ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<count_columns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <column_skip_spaces@plt>
  mov    %rax,-0x428(%rbp)
  jmp    L20
L27:
  addl   $0x1,-0x414(%rbp)
  mov    -0x428(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <column_fill_characters@plt>
  mov    %rax,-0x428(%rbp)
  mov    -0x428(%rbp),%rax
  mov    %rax,%rdi
  call   <column_skip_spaces@plt>
  mov    %rax,-0x428(%rbp)
L20:
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    -0x414(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int count_columns(char *string) {
  char put_here[1024];
  int this_column;
  this_column = 0;
  string = column_skip_spaces(string);
  while (*string) {
    this_column++;
    string = column_fill_characters(put_here, string);
    string = column_skip_spaces(string);
  }
  return this_column;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_columns>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <column_skip_spaces@plt>
  cmpb   $0x0,(%rax)
  je     L3
  mov    %rax,%rsi
  mov    $0x0,%ebx
  mov    %rsp,%rbp
L39:
  add    $0x1,%ebx
  mov    %rbp,%rdi
  call   <column_fill_characters@plt>
  mov    %rax,%rdi
  call   <column_skip_spaces@plt>
  mov    %rax,%rsi
  cmpb   $0x0,(%rax)
  jne    L39
L16:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %ebx,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x0,%ebx
  jmp    L16
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_columns(char *string) {
  char put_here[1024];
  int this_column;
  this_column = 0;
  string = column_skip_spaces(string);
  while (*string) {
    this_column++;
    string = column_fill_characters(put_here, string);
    string = column_skip_spaces(string);
  }
  return this_column;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count_columns>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <column_skip_spaces@plt>
  cmpb   $0x0,(%rax)
  je     L24
  mov    %rax,%rsi
  xor    %r12d,%r12d
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L39:
  mov    %rbx,%rdi
  add    $0x1,%r12d
  call   <column_fill_characters@plt>
  mov    %rax,%rdi
  call   <column_skip_spaces@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rsi
  jne    L39
L18:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L24:
  xor    %r12d,%r12d
  jmp    L18
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_columns(char *string) {
  char put_here[1024];
  int this_column;
  this_column = 0;
  string = column_skip_spaces(string);
  while (*string) {
    this_column++;
    string = column_fill_characters(put_here, string);
    string = column_skip_spaces(string);
  }
  return this_column;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_columns>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <column_skip_spaces@plt>
  cmpb   $0x0,(%rax)
  je     L31
  mov    %rax,%rsi
  xor    %r12d,%r12d
  mov    %rsp,%rbx
  nopl   0x0(%rax)
L13:
  mov    %rbx,%rdi
  add    $0x1,%r12d
  call   <column_fill_characters@plt>
  mov    %rax,%rdi
  call   <column_skip_spaces@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rsi
  jne    L13
L4:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x418,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L31:
  xor    %r12d,%r12d
  jmp    L4
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int count_columns(char *string) {
  char put_here[1024];
  int this_column;
  this_column = 0;
  string = column_skip_spaces(string);
  while (*string) {
    this_column++;
    string = column_fill_characters(put_here, string);
    string = column_skip_spaces(string);
  }
  return this_column;
}
```
user: What is the c source code of the assembly code below:

```asm
<string_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int string_cmp(const void *litem, const void *ritem) {
  char *lstring = (char *)litem;
  char *rstring = (char *)ritem;
  return strcmp(lstring, rstring);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<string_cmp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int string_cmp(const void *litem, const void *ritem) {
  char *lstring = (char *)litem;
  char *rstring = (char *)ritem;
  return strcmp(lstring, rstring);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_cmp>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int string_cmp(const void *litem, const void *ritem) {
  char *lstring = (char *)litem;
  char *rstring = (char *)ritem;
  return strcmp(lstring, rstring);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<string_cmp>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int string_cmp(const void *litem, const void *ritem) {
  char *lstring = (char *)litem;
  char *rstring = (char *)ritem;
  return strcmp(lstring, rstring);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L13
L1:
  cmpl   $0x0,-0x4(%rbp)
  jle    L29
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L29:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L13:
  cmpl   $0x0,-0x8(%rbp)
  jg     L1
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int q, y;
  q = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (q > 0) {
    if (y > 0) {
      q = q - y - 1;
    } else {
      q = q + y - 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jg     L37
L30:
  mov    $0x0,%eax
  pop    %rbx
  ret
L35:
  sub    %eax,%ebx
  sub    $0x1,%ebx
L2:
  test   %ebx,%ebx
  jle    L30
L37:
  test   %eax,%eax
  jg     L35
  lea    -0x1(%rax,%rbx,1),%ebx
  jmp    L2
```

assistant: ```c
int main() {
  int q, y;
  q = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (q > 0) {
    if (y > 0) {
      q = q - y - 1;
    } else {
      q = q + y - 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
L12:
  test   %ebx,%ebx
  jle    L34
L23:
  test   %eax,%eax
  jle    L37
  sub    %eax,%ebx
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jg     L23
L34:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  lea    -0x1(%rax,%rbx,1),%ebx
  jmp    L12
```

assistant: ```c
int main() {
  int q, y;
  q = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (q > 0) {
    if (y > 0) {
      q = q - y - 1;
    } else {
      q = q + y - 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %ebx,%ebx
  jle    L52
  test   %eax,%eax
  jle    L18
  nopl   (%rax)
L6:
  sub    $0x1,%ebx
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L6
L52:
  xor    %eax,%eax
  pop    %rbx
  ret
L18:
  lea    -0x1(%rbx,%rax,1),%ebx
  test   %ebx,%ebx
  jle    L52
  lea    -0x1(%rbx,%rax,1),%ebx
  test   %ebx,%ebx
  jg     L18
  jmp    L52
```

assistant: ```c
int main() {
  int q, y;
  q = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (q > 0) {
    if (y > 0) {
      q = q - y - 1;
    } else {
      q = q + y - 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wr_hashfun_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1f,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L16
L18:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L38
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x10(%rbp)
  jmp    L9
L38:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x14(%rbp)
L9:
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  shll   $0x5,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int wr_hashfun_str(const char *s) {
  int even, odd;
  int i = 0;
  int mask = 0x1F;
  int ret;
  even = odd = 0;
  while (*s != '\0') {
    if (i & 1)
      odd ^= *s;
    else
      even ^= *s;
    ++s;
    ++i;
  }
  ret = even & mask;
  ret <<= 5;
  ret += (odd & mask);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wr_hashfun_str>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L20
  mov    $0x0,%ecx
  mov    $0x0,%eax
  mov    $0x0,%esi
  jmp    L16
L22:
  movsbl %dl,%edx
  xor    %edx,%esi
L40:
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  je     L30
L16:
  test   $0x1,%cl
  je     L22
  movsbl %dl,%edx
  xor    %edx,%eax
  jmp    L40
L20:
  mov    $0x0,%eax
  mov    $0x0,%esi
L30:
  shl    $0x5,%esi
  and    $0x3e0,%esi
  and    $0x1f,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int wr_hashfun_str(const char *s) {
  int even, odd;
  int i = 0;
  int mask = 0x1F;
  int ret;
  even = odd = 0;
  while (*s != '\0') {
    if (i & 1)
      odd ^= *s;
    else
      even ^= *s;
    ++s;
    ++i;
  }
  ret = even & mask;
  ret <<= 5;
  ret += (odd & mask);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wr_hashfun_str>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L13
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rcx
  xor    %edx,%esi
  movsbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  je     L30
L4:
  test   $0x1,%cl
  jne    L15
  add    $0x1,%rcx
  xor    %edx,%eax
  movsbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  jne    L4
L30:
  shl    $0x5,%eax
  and    $0x1f,%esi
  and    $0x3e0,%eax
  or     %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int wr_hashfun_str(const char *s) {
  int even, odd;
  int i = 0;
  int mask = 0x1F;
  int ret;
  even = odd = 0;
  while (*s != '\0') {
    if (i & 1)
      odd ^= *s;
    else
      even ^= *s;
    ++s;
    ++i;
  }
  ret = even & mask;
  ret <<= 5;
  ret += (odd & mask);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<wr_hashfun_str>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L23
  xor    %ecx,%ecx
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rcx
  xor    %edx,%esi
  movsbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  je     L21
L0:
  test   $0x1,%cl
  jne    L22
  add    $0x1,%rcx
  xor    %edx,%eax
  movsbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  jne    L0
L21:
  shl    $0x5,%eax
  and    $0x1f,%esi
  and    $0x3e0,%eax
  or     %esi,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int wr_hashfun_str(const char *s) {
  int even, odd;
  int i = 0;
  int mask = 0x1F;
  int ret;
  even = odd = 0;
  while (*s != '\0') {
    if (i & 1)
      odd ^= *s;
    else
      even ^= *s;
    ++s;
    ++i;
  }
  ret = even & mask;
  ret <<= 5;
  ret += (odd & mask);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<singlecharopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jne    L6
  mov    $0x1,%eax
  jmp    L2
L6:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int singlecharopt(const char *str) {
  if (strlen(str) == 1)
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<singlecharopt>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int singlecharopt(const char *str) {
  if (strlen(str) == 1)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<singlecharopt>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int singlecharopt(const char *str) {
  if (strlen(str) == 1)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<singlecharopt>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int singlecharopt(const char *str) {
  if (strlen(str) == 1)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: Hello world!


assistant: ```c
int foo() {
  printf("Hello world!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Hello world!


assistant: ```c
int foo() {
  printf("Hello world!\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: Hello world!


assistant: ```c
int foo() {
  printf("Hello world!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: Hello world!


assistant: ```c
int foo() {
  printf("Hello world!\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<changed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  cmpq   $0x0,-0x10(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L7
L24:
  cmpq   $0x0,-0x8(%rbp)
  je     L61
  cmpq   $0x0,-0x10(%rbp)
  je     L61
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
  mov    $0x0,%eax
  jmp    L7
L61:
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
int changed(char *a, char *b) {
  if (a == 0 && b == 0)
    return 0;
  if (a != 0 && b != 0 && strcmp(a, b) == 0)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<changed>:
  endbr64
  mov    $0x0,%eax
  mov    %rdi,%rdx
  or     %rsi,%rdx
  je     L16
  test   %rdi,%rdi
  je     L8
  test   %rsi,%rsi
  jne    L29
L8:
  mov    $0x1,%eax
  ret
L29:
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L16:
  ret
```

assistant: ```c
int changed(char *a, char *b) {
  if (a == 0 && b == 0)
    return 0;
  if (a != 0 && b != 0 && strcmp(a, b) == 0)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<changed>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  or     %rsi,%rdx
  je     L25
  test   %rdi,%rdi
  je     L24
  test   %rsi,%rsi
  je     L24
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nop
L25:
  ret
  nopl   0x0(%rax)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int changed(char *a, char *b) {
  if (a == 0 && b == 0)
    return 0;
  if (a != 0 && b != 0 && strcmp(a, b) == 0)
    return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<changed>:
  endbr64
  mov    %rdi,%rdx
  xor    %eax,%eax
  or     %rsi,%rdx
  je     L14
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  je     L10
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nop
L14:
  ret
  nopl   0x0(%rax)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int changed(char *a, char *b) {
  if (a == 0 && b == 0)
    return 0;
  if (a != 0 && b != 0 && strcmp(a, b) == 0)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cprop_result5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L8
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0xa,(%rax)
  jmp    L13
L8:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movl   $0xf,(%rax)
L13:
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movl   $0x1a,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cprop_result5(int *data) {
  if (data[0])
    data[1] = 10;
  else
    data[2] = 15;
  data[3] = 26;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cprop_result5>:
  endbr64
  cmpl   $0x0,(%rdi)
  je     L12
  movl   $0xa,0x4(%rdi)
L17:
  movl   $0x1a,0xc(%rdi)
  ret
L12:
  movl   $0xf,0x8(%rdi)
  jmp    L17
```

assistant: ```c
void cprop_result5(int *data) {
  if (data[0])
    data[1] = 10;
  else
    data[2] = 15;
  data[3] = 26;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cprop_result5>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L8
  movl   $0xa,0x4(%rdi)
  movl   $0x1a,0xc(%rdi)
  ret
  nopl   0x0(%rax)
L8:
  movl   $0xf,0x8(%rdi)
  movl   $0x1a,0xc(%rdi)
  ret
```

assistant: ```c
void cprop_result5(int *data) {
  if (data[0])
    data[1] = 10;
  else
    data[2] = 15;
  data[3] = 26;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cprop_result5>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L0
  movl   $0xa,0x4(%rdi)
  movl   $0x1a,0xc(%rdi)
  ret
  nopl   0x0(%rax)
L0:
  movl   $0xf,0x8(%rdi)
  movl   $0x1a,0xc(%rdi)
  ret
```

assistant: ```c
void cprop_result5(int *data) {
  if (data[0])
    data[1] = 10;
  else
    data[2] = 15;
  data[3] = 26;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L5:
  mov    $0x0,%eax
  call   <foo@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x5f5e0ff,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 100000000; i++)
    foo();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
L2:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 100000000; i++)
    foo();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L7
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 100000000; i++)
    foo();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L1
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0; i < 100000000; i++)
    foo();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<validate_sources>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L30
L16:
  movq   $0x0,-0x8(%rbp)
  jmp    L39
L45:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <validate_source@plt>
  cmp    $0xffffffff,%eax
  jne    L21
  mov    $0xffffffff,%eax
  jmp    L30
L21:
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L45
  mov    $0x0,%eax
L30:
  leave
  ret
```

assistant: ```c
int validate_sources(const char *sources[], const size_t length) {
  size_t i;
  if (sources == NULL) {
    return -1;
  }
  for (i = 0; i < length; i++) {
    if (validate_source(sources[i]) == -1) {
      return -1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<validate_sources>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L49
  mov    $0x0,%ebx
L27:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <validate_source@plt>
  cmp    $0xffffffff,%eax
  je     L25
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L27
  mov    $0x0,%eax
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    $0xffffffff,%eax
  ret
L49:
  mov    $0x0,%eax
  jmp    L25
```

assistant: ```c
int validate_sources(const char *sources[], const size_t length) {
  size_t i;
  if (sources == NULL) {
    return -1;
  }
  for (i = 0; i < length; i++) {
    if (validate_source(sources[i]) == -1) {
      return -1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<validate_sources>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  test   %rsi,%rsi
  jne    L30
  jmp    L17
  nopl   0x0(%rax)
L36:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L17
L30:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <validate_source@plt>
  cmp    $0xffffffff,%eax
  jne    L36
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int validate_sources(const char *sources[], const size_t length) {
  size_t i;
  if (sources == NULL) {
    return -1;
  }
  for (i = 0; i < length; i++) {
    if (validate_source(sources[i]) == -1) {
      return -1;
    }
  }
  return 0;
}
```