ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_desktop_info>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <count_desktops@plt>
  lea    0x0(,%rax,8),%edi
  mov    %eax,%r13d
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  lea    0x1(%rbx),%rsi
  lea    D1(%rip),%rbx
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L25
  jmp    L37
  nopl   0x0(%rax)
L55:
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L37
L25:
  movzbl 0x0(%rbp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x4d,%al
  je     L55
L29:
  test   %r13d,%r13d
  je     L39
  lea    -0x1(%r13),%eax
  mov    %r14,%r15
  lea    0x8(%r14,%rax,8),%r13
  xchg   %ax,%ax
L24:
  mov    %rbp,%rdi
  add    $0x8,%r15
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,-0x8(%r15)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  cmp    %r15,%r13
  jne    L24
L39:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L37:
  xor    %ebp,%ebp
  jmp    L29
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: :

assistant: ```c
char **get_desktop_info(const char *bspwm_output) {
  unsigned int num_of_desktops = count_desktops(bspwm_output);
  char **desktop_info = malloc(sizeof(char *) * num_of_desktops);
  char *tmp = malloc(strlen(bspwm_output));
  strcpy(tmp, bspwm_output + 1);
  char *pch = strtok(tmp, ":");
  for (; pch != NULL && (pch[0] == 'M' || pch[0] == 'm'); pch = strtok(NULL, ":"))
    ;
  for (unsigned int i = 0; i < num_of_desktops; ++i, pch = strtok(NULL, ":")) {
    desktop_info[i] = malloc(strlen(pch) + 1);
    strcpy(desktop_info[i], pch);
  }
  free(tmp);
  return desktop_info;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<showItens>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L27
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x9,-0x8(%rbp)
  jle    L5
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string

tool: D2: 
%d - value: %d


assistant: ```c
void showItens(int *array, int index) {
  int i, j = 0;
  for (i = index; i < 10; i++) {
    if (array[i] != -1) {
      j++;
      printf("\n%d - value: %d\n", j, array[i]);
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<showItens>:
  endbr64
  cmp    $0x9,%esi
  jg     L35
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movslq %esi,%rdx
  lea    (%rdi,%rdx,4),%rbx
  mov    $0x9,%eax
  sub    %esi,%eax
  add    %rdx,%rax
  lea    0x4(%rdi,%rax,4),%r12
  mov    $0x0,%ebp
  lea    D3(%rip),%r13
  jmp    L19
L39:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L26
L19:
  mov    (%rbx),%edx
  cmp    $0xffffffff,%edx
  je     L39
  add    $0x1,%ebp
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L39
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: 
%d - value: %d


assistant: ```c
void showItens(int *array, int index) {
  int i, j = 0;
  for (i = index; i < 10; i++) {
    if (array[i] != -1) {
      j++;
      printf("\n%d - value: %d\n", j, array[i]);
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<showItens>:
  endbr64
  cmp    $0x9,%esi
  jg     L27
  push   %r13
  mov    $0x9,%eax
  movslq %esi,%rdx
  lea    D4(%rip),%r13
  push   %r12
  sub    %esi,%eax
  push   %rbp
  add    %rdx,%rax
  xor    %ebp,%ebp
  push   %rbx
  lea    0x4(%rdi,%rax,4),%r12
  lea    (%rdi,%rdx,4),%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%edx
  cmp    $0xffffffff,%edx
  je     L0
  add    $0x1,%ebp
  mov    %r13,%rdi
  mov    %ebp,%esi
  call   <printf@plt>
L0:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: 
%d - value: %d


assistant: ```c
void showItens(int *array, int index) {
  int i, j = 0;
  for (i = index; i < 10; i++) {
    if (array[i] != -1) {
      j++;
      printf("\n%d - value: %d\n", j, array[i]);
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<showItens>:
  endbr64
  cmp    $0x9,%esi
  jg     L21
  push   %r13
  mov    $0x9,%eax
  movslq %esi,%rdx
  lea    D6(%rip),%r13
  push   %r12
  sub    %esi,%eax
  push   %rbp
  add    %rdx,%rax
  xor    %ebp,%ebp
  push   %rbx
  lea    0x4(%rdi,%rax,4),%r12
  lea    (%rdi,%rdx,4),%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%edx
  cmp    $0xffffffff,%edx
  je     L1
  add    $0x1,%ebp
  mov    %r13,%rdi
  mov    %ebp,%esi
  call   <printf@plt>
L1:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: 
%d - value: %d


assistant: ```c
void showItens(int *array, int index) {
  int i, j = 0;
  for (i = index; i < 10; i++) {
    if (array[i] != -1) {
      j++;
      printf("\n%d - value: %d\n", j, array[i]);
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<move_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9d,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L86
  mov    -0x20(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L86
  mov    -0x20(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L75
L86:
  mov    $0x0,%eax
  jmp    L125
L75:
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L126
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jne    L126
  mov    $0x1,%eax
  jmp    L125
L126:
  mov    -0x20(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L80
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%r8d
  mov    -0x20(%rbp),%edi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %edi,%r9d
  mov    %eax,%edi
  call   <move_mem>
  test   %eax,%eax
  je     L104
  mov    $0x1,%eax
  jmp    L125
L104:
  mov    -0x20(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
L80:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L96
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%r8d
  mov    -0x1c(%rbp),%edi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%esi
  mov    -0x4(%rbp),%eax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <move_mem>
  test   %eax,%eax
  je     L96
  mov    $0x1,%eax
  jmp    L125
L96:
  mov    $0x0,%eax
L125:
  leave
  ret
```

assistant: ```c
int move_mem(int r, int c, int *grid, int *mem, int x, int y) {
  if (x >= c || y >= r || !grid[y * c + x])
    return 0;
  if (x == (c - 1) && y == (r - 1))
    return 1;
  if (!mem[y * c + x + 1]) {
    if (move_mem(r, c, grid, mem, x + 1, y))
      return 1;
    mem[y * c + x + 1] = 1;
  }
  if (!mem[(y + 1) * c + x]) {
    if (move_mem(r, c, grid, mem, x, y + 1))
      return 1;
    mem[(y + 1) * c + x] == 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<move_mem>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebx
  mov    %rdx,(%rsp)
  cmp    %esi,%r8d
  jge    L89
  mov    %edi,%r13d
  mov    %rdx,%rsi
  mov    %rcx,%r15
  mov    %r8d,%ebp
  mov    %r9d,%r12d
  cmp    %edi,%r9d
  jge    L89
  mov    %ebx,%r14d
  imul   %r9d,%r14d
  lea    (%r14,%r8,1),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    (%rsi,%rax,4),%eax
  test   %eax,%eax
  je     L68
  lea    -0x1(%rbx),%eax
  cmp    %r8d,%eax
  je     L76
L52:
  lea    0x4(%r15,%rdx,1),%rax
  mov    %rax,0x8(%rsp)
  cmpl   $0x0,(%rax)
  je     L3
L41:
  lea    0x1(%r12),%r9d
  add    %ebx,%r14d
  add    %ebp,%r14d
  movslq %r14d,%r14
  mov    $0x0,%eax
  cmpl   $0x0,(%r15,%r14,4)
  jne    L68
  mov    %ebp,%r8d
  mov    %r15,%rcx
  mov    (%rsp),%rdx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <move_mem>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L68
L76:
  lea    -0x1(%rdi),%ecx
  mov    $0x1,%eax
  cmp    %r9d,%ecx
  jne    L52
  jmp    L68
L3:
  mov    %r12d,%r9d
  lea    0x1(%rbp),%r8d
  mov    %r15,%rcx
  mov    (%rsp),%rdx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <move_mem>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L68
  mov    0x8(%rsp),%rax
  movl   $0x1,(%rax)
  jmp    L41
L89:
  mov    $0x0,%eax
L68:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int move_mem(int r, int c, int *grid, int *mem, int x, int y) {
  if (x >= c || y >= r || !grid[y * c + x])
    return 0;
  if (x == (c - 1) && y == (r - 1))
    return 1;
  if (!mem[y * c + x + 1]) {
    if (move_mem(r, c, grid, mem, x + 1, y))
      return 1;
    mem[y * c + x + 1] = 1;
  }
  if (!mem[(y + 1) * c + x]) {
    if (move_mem(r, c, grid, mem, x, y + 1))
      return 1;
    mem[(y + 1) * c + x] == 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<move_mem>:
  endbr64
  cmp    %esi,%r8d
  jge    L51
  cmp    %edi,%r9d
  jge    L51
  push   %r15
  mov    %rdx,%r15
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  imul   %r9d,%ebp
  push   %rbx
  mov    %r8d,%ebx
  lea    0x0(%rbp,%r8,1),%eax
  sub    $0x28,%rsp
  cltq
  mov    (%r15,%rax,4),%r8d
  lea    0x0(,%rax,4),%rdx
  test   %r8d,%r8d
  je     L94
  lea    -0x1(%rsi),%eax
  cmp    %ebx,%eax
  je     L37
L92:
  lea    0x4(%rcx,%rdx,1),%r12
  mov    (%r12),%edx
  test   %edx,%edx
  je     L98
L58:
  lea    0x0(%rbp,%rsi,1),%eax
  add    $0x1,%r9d
  add    %ebx,%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  test   %eax,%eax
  je     L43
L94:
  xor    %eax,%eax
L40:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %ebx,%r8d
  mov    %r15,%rdx
  call   <move_mem>
  test   %eax,%eax
  setne  %al
  add    $0x28,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r15
  ret
  xchg   %ax,%ax
L51:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  lea    -0x1(%rdi),%eax
  cmp    %r9d,%eax
  jne    L92
L44:
  mov    $0x1,%eax
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L98:
  lea    0x1(%rbx),%r8d
  mov    %r15,%rdx
  mov    %r9d,0x1c(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %esi,0x18(%rsp)
  mov    %edi,0xc(%rsp)
  call   <move_mem>
  test   %eax,%eax
  jne    L44
  mov    0x18(%rsp),%esi
  mov    0xc(%rsp),%edi
  movl   $0x1,(%r12)
  mov    0x1c(%rsp),%r9d
  mov    0x10(%rsp),%rcx
  jmp    L58
```

assistant: ```c
int move_mem(int r, int c, int *grid, int *mem, int x, int y) {
  if (x >= c || y >= r || !grid[y * c + x])
    return 0;
  if (x == (c - 1) && y == (r - 1))
    return 1;
  if (!mem[y * c + x + 1]) {
    if (move_mem(r, c, grid, mem, x + 1, y))
      return 1;
    mem[y * c + x + 1] = 1;
  }
  if (!mem[(y + 1) * c + x]) {
    if (move_mem(r, c, grid, mem, x, y + 1))
      return 1;
    mem[(y + 1) * c + x] == 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<move_mem>:
  endbr64
  cmp    %esi,%r8d
  jge    L60
  cmp    %edi,%r9d
  jge    L60
  push   %r15
  mov    %rdx,%r15
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  imul   %r9d,%ebp
  push   %rbx
  mov    %r8d,%ebx
  lea    0x0(%rbp,%r8,1),%eax
  sub    $0x28,%rsp
  cltq
  mov    (%r15,%rax,4),%r8d
  lea    0x0(,%rax,4),%rdx
  test   %r8d,%r8d
  je     L61
  lea    -0x1(%rsi),%eax
  cmp    %ebx,%eax
  je     L58
L31:
  lea    0x4(%rcx,%rdx,1),%r12
  mov    (%r12),%edx
  test   %edx,%edx
  je     L70
L57:
  lea    0x0(%rbp,%rsi,1),%eax
  add    $0x1,%r9d
  add    %ebx,%eax
  cltq
  mov    (%rcx,%rax,4),%eax
  test   %eax,%eax
  je     L16
L61:
  xor    %eax,%eax
L93:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%r8d
  mov    %r15,%rdx
  call   <move_mem>
  test   %eax,%eax
  setne  %al
  add    $0x28,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r15
  ret
  xchg   %ax,%ax
L60:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  lea    -0x1(%rdi),%eax
  cmp    %r9d,%eax
  jne    L31
L91:
  mov    $0x1,%eax
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L70:
  lea    0x1(%rbx),%r8d
  mov    %r15,%rdx
  mov    %r9d,0x1c(%rsp)
  mov    %rcx,0x10(%rsp)
  mov    %esi,0x18(%rsp)
  mov    %edi,0xc(%rsp)
  call   <move_mem>
  test   %eax,%eax
  jne    L91
  mov    0x18(%rsp),%esi
  mov    0xc(%rsp),%edi
  movl   $0x1,(%r12)
  mov    0x1c(%rsp),%r9d
  mov    0x10(%rsp),%rcx
  jmp    L57
```

assistant: ```c
int move_mem(int r, int c, int *grid, int *mem, int x, int y) {
  if (x >= c || y >= r || !grid[y * c + x])
    return 0;
  if (x == (c - 1) && y == (r - 1))
    return 1;
  if (!mem[y * c + x + 1]) {
    if (move_mem(r, c, grid, mem, x + 1, y))
      return 1;
    mem[y * c + x + 1] = 1;
  }
  if (!mem[(y + 1) * c + x]) {
    if (move_mem(r, c, grid, mem, x, y + 1))
      return 1;
    mem[(y + 1) * c + x] == 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D37(%rip),%eax
  mov    %eax,%edi
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L7
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <first@plt>
  jmp    L8
L7:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <alloc_err_handler@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <alloc_err@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D25: main


tool: D0: finishing


assistant: ```c
int main() {
  static jmp_buf buf;
  if (!setjmp(buf)) {
    first(&buf);
  } else {
    printf("main\n");
  }
  alloc_err_handler(&buf);
  alloc_err(&buf);
  printf("finishing\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    D20(%rip),%edi
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L6
  lea    D20(%rip),%rdi
  call   <first@plt>
L4:
  lea    D20(%rip),%rbx
  mov    %rbx,%rdi
  call   <alloc_err_handler@plt>
  mov    %rbx,%rdi
  call   <alloc_err@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L6:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D38
datatype: string
name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D38: finishing


tool: D5: main


assistant: ```c
int main() {
  static jmp_buf buf;
  if (!setjmp(buf)) {
    first(&buf);
  } else {
    printf("main\n");
  }
  alloc_err_handler(&buf);
  alloc_err(&buf);
  printf("finishing\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    D46(%rip),%edi
  push   %rbp
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L18
  lea    D46(%rip),%rdi
  call   <first@plt>
L9:
  lea    D46(%rip),%rbp
  mov    %rbp,%rdi
  call   <alloc_err_handler@plt>
  mov    %rbp,%rdi
  call   <alloc_err@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L18:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string
name: retrieve_data
arguments: label: D39
type: string

tool: D9: finishing


tool: D39: main


assistant: ```c
int main() {
  static jmp_buf buf;
  if (!setjmp(buf)) {
    first(&buf);
  } else {
    printf("main\n");
  }
  alloc_err_handler(&buf);
  alloc_err(&buf);
  printf("finishing\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    D45(%rip),%edi
  push   %rbp
  call   <setjmp@plt>
  endbr64
  test   %eax,%eax
  jne    L10
  lea    D45(%rip),%rdi
  call   <first@plt>
L3:
  lea    D45(%rip),%rbp
  mov    %rbp,%rdi
  call   <alloc_err_handler@plt>
  mov    %rbp,%rdi
  call   <alloc_err@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D34
datatype: string

tool: D17: finishing


tool: D34: main


assistant: ```c
int main() {
  static jmp_buf buf;
  if (!setjmp(buf)) {
    first(&buf);
  } else {
    printf("main\n");
  }
  alloc_err_handler(&buf);
  alloc_err(&buf);
  printf("finishing\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ll_type_n2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L39:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  jmp    L23
L1:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    $0x35,%eax
  jbe    L39
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    %edx,%ecx
  lea    D1(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x20(%rbp),%rax
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: [%d]

assistant: ```c
const char *ll_type_n2a(int type, char *buf, int len) {
  static struct {
    int type;
    const char *name;
  } arphrd_names[] = {
      {0, "generic"}, {ARPHRD_ETHER, "ether"}, {ARPHRD_EETHER, "eether"}, {ARPHRD_AX25, "ax25"}, {ARPHRD_PRONET, "pronet"}, {ARPHRD_CHAOS, "chaos"}, {ARPHRD_IEEE802, "tr"}, {ARPHRD_ARCNET, "arcnet"}, {ARPHRD_APPLETLK, "atalk"}, {ARPHRD_DLCI, "dlci"}, {ARPHRD_METRICOM, "metricom"}, {ARPHRD_SLIP, "slip"}, {ARPHRD_CSLIP, "cslip"}, {ARPHRD_SLIP6, "slip6"}, {ARPHRD_CSLIP6, "cslip6"}, {ARPHRD_RSRVD, "rsrvd"}, {ARPHRD_ADAPT, "adapt"}, {ARPHRD_ROSE, "rose"}, {ARPHRD_X25, "x25"}, {ARPHRD_PPP, "ppp"}, {ARPHRD_HDLC, "hdlc"}, {ARPHRD_LAPB, "lapb"}, {ARPHRD_TUNNEL, "ipip"}, {ARPHRD_TUNNEL6, "tunnel6"}, {ARPHRD_FRAD, "frad"}, {ARPHRD_SKIP, "skip"}, {ARPHRD_LOOPBACK, "loopback"}, {ARPHRD_LOCALTLK, "ltalk"}, {ARPHRD_FDDI, "fddi"}, {ARPHRD_BIF, "bif"}, {ARPHRD_SIT, "sit"}, {ARPHRD_IPDDP, "ip/ddp"}, {ARPHRD_IPGRE, "gre"}, {ARPHRD_PIMREG, "pimreg"}, {ARPHRD_HIPPI, "hippi"}, {ARPHRD_ASH, "ash"}, {ARPHRD_ECONET, "econet"}, {ARPHRD_IRDA, "irda"}, {ARPHRD_FCPP, "fcpp"}, {ARPHRD_FCAL, "fcal"}, {ARPHRD_FCPL, "fcpl"}, {ARPHRD_FCFABRIC, "fcfb0"}, {ARPHRD_FCFABRIC + 1, "fcfb1"}, {ARPHRD_FCFABRIC + 2, "fcfb2"}, {ARPHRD_FCFABRIC + 3, "fcfb3"}, {ARPHRD_FCFABRIC + 4, "fcfb4"}, {ARPHRD_FCFABRIC + 5, "fcfb5"}, {ARPHRD_FCFABRIC + 6, "fcfb6"}, {ARPHRD_FCFABRIC + 7, "fcfb7"}, {ARPHRD_FCFABRIC + 8, "fcfb8"}, {ARPHRD_FCFABRIC + 9, "fcfb9"}, {ARPHRD_FCFABRIC + 10, "fcfb10"}, {ARPHRD_FCFABRIC + 11, "fcfb11"}, {ARPHRD_FCFABRIC + 12, "fcfb12"},
  };
  int i;
  for (i = 0; i < sizeof(arphrd_names) / sizeof(arphrd_names[0]); i++) {
    if (arphrd_names[i].type == type)
      return arphrd_names[i].name;
  }
  snprintf(buf, len, "[%d]", type);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ll_type_n2a>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  lea    D16(%rip),%r8
  mov    $0x0,%eax
L0:
  cmp    %edi,(%r8)
  je     L22
  add    $0x1,%eax
  add    $0x10,%r8
  cmp    $0x36,%eax
  jne    L0
  mov    %edi,%ecx
  lea    D10(%rip),%rdx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  jmp    L27
L22:
  cltq
  shl    $0x4,%rax
  lea    D16(%rip),%rdx
  mov    0x8(%rdx,%rax,1),%rax
L27:
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string

tool: D10: [%d]

assistant: ```c
const char *ll_type_n2a(int type, char *buf, int len) {
  static struct {
    int type;
    const char *name;
  } arphrd_names[] = {
      {0, "generic"}, {ARPHRD_ETHER, "ether"}, {ARPHRD_EETHER, "eether"}, {ARPHRD_AX25, "ax25"}, {ARPHRD_PRONET, "pronet"}, {ARPHRD_CHAOS, "chaos"}, {ARPHRD_IEEE802, "tr"}, {ARPHRD_ARCNET, "arcnet"}, {ARPHRD_APPLETLK, "atalk"}, {ARPHRD_DLCI, "dlci"}, {ARPHRD_METRICOM, "metricom"}, {ARPHRD_SLIP, "slip"}, {ARPHRD_CSLIP, "cslip"}, {ARPHRD_SLIP6, "slip6"}, {ARPHRD_CSLIP6, "cslip6"}, {ARPHRD_RSRVD, "rsrvd"}, {ARPHRD_ADAPT, "adapt"}, {ARPHRD_ROSE, "rose"}, {ARPHRD_X25, "x25"}, {ARPHRD_PPP, "ppp"}, {ARPHRD_HDLC, "hdlc"}, {ARPHRD_LAPB, "lapb"}, {ARPHRD_TUNNEL, "ipip"}, {ARPHRD_TUNNEL6, "tunnel6"}, {ARPHRD_FRAD, "frad"}, {ARPHRD_SKIP, "skip"}, {ARPHRD_LOOPBACK, "loopback"}, {ARPHRD_LOCALTLK, "ltalk"}, {ARPHRD_FDDI, "fddi"}, {ARPHRD_BIF, "bif"}, {ARPHRD_SIT, "sit"}, {ARPHRD_IPDDP, "ip/ddp"}, {ARPHRD_IPGRE, "gre"}, {ARPHRD_PIMREG, "pimreg"}, {ARPHRD_HIPPI, "hippi"}, {ARPHRD_ASH, "ash"}, {ARPHRD_ECONET, "econet"}, {ARPHRD_IRDA, "irda"}, {ARPHRD_FCPP, "fcpp"}, {ARPHRD_FCAL, "fcal"}, {ARPHRD_FCPL, "fcpl"}, {ARPHRD_FCFABRIC, "fcfb0"}, {ARPHRD_FCFABRIC + 1, "fcfb1"}, {ARPHRD_FCFABRIC + 2, "fcfb2"}, {ARPHRD_FCFABRIC + 3, "fcfb3"}, {ARPHRD_FCFABRIC + 4, "fcfb4"}, {ARPHRD_FCFABRIC + 5, "fcfb5"}, {ARPHRD_FCFABRIC + 6, "fcfb6"}, {ARPHRD_FCFABRIC + 7, "fcfb7"}, {ARPHRD_FCFABRIC + 8, "fcfb8"}, {ARPHRD_FCFABRIC + 9, "fcfb9"}, {ARPHRD_FCFABRIC + 10, "fcfb10"}, {ARPHRD_FCFABRIC + 11, "fcfb11"}, {ARPHRD_FCFABRIC + 12, "fcfb12"},
  };
  int i;
  for (i = 0; i < sizeof(arphrd_names) / sizeof(arphrd_names[0]); i++) {
    if (arphrd_names[i].type == type)
      return arphrd_names[i].name;
  }
  snprintf(buf, len, "[%d]", type);
  return buf;
}
```