ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<intlog2>:
  endbr64
  mov    $0xffffffff,%eax
  test   %edi,%edi
  je     L17
  nopl   (%rax)
L14:
  add    $0x1,%eax
  shr    %edi
  jne    L14
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
int intlog2(unsigned int val) {
  int ret = -1;
  while (val != 0) {
    val >>= 1;
    ret++;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intlog2>:
  endbr64
  mov    $0xffffffff,%eax
  test   %edi,%edi
  je     L9
  nopl   (%rax)
L18:
  add    $0x1,%eax
  shr    %edi
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
int intlog2(unsigned int val) {
  int ret = -1;
  while (val != 0) {
    val >>= 1;
    ret++;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  or     $0x61bab5,%rax
  test   $0x8,%dl
  je     L17
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  jmp    L3
L17:
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
L3:
  shr    $0x5,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  unsigned short copy15;
  unsigned int copy16;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if (state[0UL] & 1UL) {
          state[0UL] >>= (state[0UL] & 7UL) | 1UL;
          state[0UL] <<= (state[0UL] & 7UL) | 1UL;
        } else {
          state[0UL] <<= (state[0UL] & 7UL) | 1UL;
          copy11 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        }
      } else if ((state[0UL] >> 4UL) & 1UL) {
        state[0UL] >>= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      } else {
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] >>= (state[0UL] & 7UL) | 1UL;
    } else {
      copy15 = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = copy15;
      copy16 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy16;
    }
    output[0UL] = state[0UL] >> 5UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  or     $0x61bab5,%rax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  and    $0x8,%edx
  je     L3
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L3:
  shr    $0x5,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  unsigned short copy15;
  unsigned int copy16;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if (state[0UL] & 1UL) {
          state[0UL] >>= (state[0UL] & 7UL) | 1UL;
          state[0UL] <<= (state[0UL] & 7UL) | 1UL;
        } else {
          state[0UL] <<= (state[0UL] & 7UL) | 1UL;
          copy11 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        }
      } else if ((state[0UL] >> 4UL) & 1UL) {
        state[0UL] >>= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      } else {
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] >>= (state[0UL] & 7UL) | 1UL;
    } else {
      copy15 = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = copy15;
      copy16 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy16;
    }
    output[0UL] = state[0UL] >> 5UL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  or     $0x61bab5,%rax
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  and    $0x8,%edx
  je     L7
  mov    %eax,%ecx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L7:
  shr    $0x5,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned short copy11;
  unsigned short copy15;
  unsigned int copy16;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3UL;
    if ((state[0UL] >> 3UL) & 1UL) {
      if ((state[0UL] >> 4UL) & 1UL) {
        if (state[0UL] & 1UL) {
          state[0UL] >>= (state[0UL] & 7UL) | 1UL;
          state[0UL] <<= (state[0UL] & 7UL) | 1UL;
        } else {
          state[0UL] <<= (state[0UL] & 7UL) | 1UL;
          copy11 = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        }
      } else if ((state[0UL] >> 4UL) & 1UL) {
        state[0UL] >>= ((state[0UL] >> 1UL) & 7UL) | 1UL;
      } else {
        state[0UL] >>= (state[0UL] & 7UL) | 1UL;
      }
    } else if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] >>= (state[0UL] & 7UL) | 1UL;
    } else {
      copy15 = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = copy15;
      copy16 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy16;
    }
    output[0UL] = state[0UL] >> 5UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<code_conv_u2g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L23
L58:
  mov    -0x18(%rbp),%rax
  add    %rax,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L23
L21:
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <code_conv@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L42
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L23
L42:
  mov    -0x8(%rbp),%rax
L23:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string

tool: D1: gb2312

tool: D10: utf-8

assistant: ```c
char *code_conv_u2g(char *inbuf) {
  size_t inlen;
  size_t outlen;
  char *outbuf;
  int ret;
  inlen = strlen(inbuf);
  if (inlen == 0)
    return NULL;
  outlen = inlen * 2 + 1;
  outbuf = calloc(1, outlen);
  if (outbuf == NULL)
    return NULL;
  ret = code_conv("utf-8", "gb2312", inbuf, inlen, outbuf, outlen);
  if (ret == -1) {
    free(outbuf);
    return NULL;
  }
  return outbuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<code_conv_u2g>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L1
  mov    %rax,%rbp
  lea    0x1(%rax,%rax,1),%r13
  mov    %r13,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %r13,%r9
  mov    %rax,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  lea    D11(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <code_conv@plt>
  cmp    $0xffffffff,%eax
  je     L15
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%ebx
  jmp    L1
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D6
datatype: string

tool: D11: gb2312

tool: D6: utf-8

assistant: ```c
char *code_conv_u2g(char *inbuf) {
  size_t inlen;
  size_t outlen;
  char *outbuf;
  int ret;
  inlen = strlen(inbuf);
  if (inlen == 0)
    return NULL;
  outlen = inlen * 2 + 1;
  outbuf = calloc(1, outlen);
  if (outbuf == NULL)
    return NULL;
  ret = code_conv("utf-8", "gb2312", inbuf, inlen, outbuf, outlen);
  if (ret == -1) {
    free(outbuf);
    return NULL;
  }
  return outbuf;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<code_conv_u2g>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L2
  lea    0x1(%rax,%rax,1),%rbx
  mov    $0x1,%edi
  mov    %rax,%r12
  mov    %rbx,%rsi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L2
  mov    %rbx,%r9
  mov    %rax,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  lea    D0(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <code_conv@plt>
  cmp    $0xffffffff,%eax
  je     L24
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  mov    %r13,%rdi
  call   <free@plt>
L2:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D0: gb2312

tool: D13: utf-8

assistant: ```c
char *code_conv_u2g(char *inbuf) {
  size_t inlen;
  size_t outlen;
  char *outbuf;
  int ret;
  inlen = strlen(inbuf);
  if (inlen == 0)
    return NULL;
  outlen = inlen * 2 + 1;
  outbuf = calloc(1, outlen);
  if (outbuf == NULL)
    return NULL;
  ret = code_conv("utf-8", "gb2312", inbuf, inlen, outbuf, outlen);
  if (ret == -1) {
    free(outbuf);
    return NULL;
  }
  return outbuf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<code_conv_u2g>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L24
  lea    0x1(%rax,%rax,1),%rbx
  mov    $0x1,%edi
  mov    %rax,%r12
  mov    %rbx,%rsi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L24
  mov    %rbx,%r9
  mov    %rax,%r8
  mov    %r12,%rcx
  mov    %r14,%rdx
  lea    D6(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <code_conv@plt>
  cmp    $0xffffffff,%eax
  je     L2
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  mov    %r13,%rdi
  call   <free@plt>
L24:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D6: gb2312

tool: D10: utf-8

assistant: ```c
char *code_conv_u2g(char *inbuf) {
  size_t inlen;
  size_t outlen;
  char *outbuf;
  int ret;
  inlen = strlen(inbuf);
  if (inlen == 0)
    return NULL;
  outlen = inlen * 2 + 1;
  outbuf = calloc(1, outlen);
  if (outbuf == NULL)
    return NULL;
  ret = code_conv("utf-8", "gb2312", inbuf, inlen, outbuf, outlen);
  if (ret == -1) {
    free(outbuf);
    return NULL;
  }
  return outbuf;
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rcx
  test   %rcx,%rcx
  je     L42
  mov    %rsp,%rax
  mov    $0x0,%edx
  jmp    L28
L22:
  movzbl 0x7(%rax),%esi
  movzbl 0x6(%rax),%edi
  mov    %dil,0x7(%rax)
  mov    %sil,0x6(%rax)
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
L54:
  add    $0x2,%rdx
  add    $0x10,%rax
  cmp    %rcx,%rdx
  jae    L42
L28:
  cmp    %rdx,(%rsp)
  jae    L22
  movzbl 0x5(%rax),%esi
  movzbl 0x3(%rax),%edi
  mov    %dil,0x5(%rax)
  movzbl 0x2(%rax),%edi
  mov    %dil,0x3(%rax)
  mov    %sil,0x2(%rax)
  movzwl (%rax),%esi
  movzwl 0x6(%rax),%edi
  mov    %di,(%rax)
  mov    %si,0x6(%rax)
  jmp    L54
L42:
  mov    (%rsp),%rax
  add    $0x67fd37,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  unsigned int copy14;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        copy13 = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 6);
        *((char *)(&state[local1]) + 6) = copy13;
        copy14 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 6815031UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    0x8(%rdi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  lea    0x136ff696(%rax),%rcx
  mov    %rcx,(%rsp)
  test   %rsi,%rsi
  je     L21
  mov    %rsp,%rax
  xor    %edx,%edx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L16:
  movzbl 0x3(%rax),%edi
  movzbl 0x5(%rax),%ecx
  mov    %dil,0x5(%rax)
  movzbl 0x2(%rax),%edi
  mov    %cl,0x2(%rax)
  movzwl (%rax),%ecx
  mov    %dil,0x3(%rax)
  movzwl 0x6(%rax),%edi
  mov    %cx,0x6(%rax)
  mov    %di,(%rax)
L52:
  add    $0x2,%rdx
  mov    (%rsp),%rcx
  add    $0x10,%rax
  cmp    %rsi,%rdx
  jae    L21
L12:
  cmp    %rcx,%rdx
  ja     L16
  movzbl 0x7(%rax),%ecx
  movzbl 0x6(%rax),%edi
  mov    %cl,0x6(%rax)
  mov    %dil,0x7(%rax)
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edi
  mov    %ecx,0x4(%rsp)
  mov    %edi,(%rsp)
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x67fd37,%rcx
  mov    %rcx,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  unsigned int copy14;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        copy13 = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 6);
        *((char *)(&state[local1]) + 6) = copy13;
        copy14 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 6815031UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  lea    0x136ff696(%rax),%rdx
  mov    %rdx,(%rsp)
  test   %rdi,%rdi
  je     L51
  mov    %rsp,%rax
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    %rdx,%rcx
  jbe    L21
  movzbl 0x3(%rax),%edx
  movzbl 0x5(%rax),%r8d
  add    $0x2,%rcx
  add    $0x10,%rax
  mov    %dl,-0xb(%rax)
  xor    %edx,%edx
  mov    %r8b,%dl
  mov    -0xe(%rax),%dh
  movzwl -0xa(%rax),%r8d
  mov    %dx,-0xe(%rax)
  movzwl -0x10(%rax),%edx
  mov    %r8w,-0x10(%rax)
  mov    %dx,-0xa(%rax)
  mov    (%rsp),%rdx
  cmp    %rcx,%rdi
  ja     L1
L51:
  add    $0x67fd37,%rdx
  mov    %rdx,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %edx,%edx
  mov    0x7(%rax),%dl
  mov    0x6(%rax),%dh
  add    $0x2,%rcx
  add    $0x10,%rax
  mov    %dx,-0xa(%rax)
  movq   (%rsp),%xmm0
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rsp)
  movq   %xmm0,%rdx
  cmp    %rdi,%rcx
  jb     L1
  jmp    L51
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  unsigned int copy14;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      } else {
        copy13 = *((char *)(&state[local1]) + 7);
        *((char *)(&state[local1]) + 7) = *((char *)(&state[local1]) + 6);
        *((char *)(&state[local1]) + 6) = copy13;
        copy14 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 6815031UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<norma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x2,-0x4(%rbp)
  jle    L18
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  leave
  ret
```

assistant: ```c
float norma(float *x) {
  float norma2 = 0;
  int i;
  for (i = 0; i < 3; i++)
    norma2 += x[i] * x[i];
  return sqrt(norma2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<norma>:
  endbr64
  sub    $0x8,%rsp
  movss  (%rdi),%xmm0
  mulss  %xmm0,%xmm0
  movaps %xmm0,%xmm1
  addss  D9(%rip),%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  0x8(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: f32

tool: D9: 0

assistant: ```c
float norma(float *x) {
  float norma2 = 0;
  int i;
  for (i = 0; i < 3; i++)
    norma2 += x[i] * x[i];
  return sqrt(norma2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<norma>:
  endbr64
  movss  (%rdi),%xmm0
  pxor   %xmm1,%xmm1
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  0x8(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  jmp    1050 <sqrt@plt>
```

assistant: ```c
float norma(float *x) {
  float norma2 = 0;
  int i;
  for (i = 0; i < 3; i++)
    norma2 += x[i] * x[i];
  return sqrt(norma2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<norma>:
  endbr64
  movss  (%rdi),%xmm0
  pxor   %xmm1,%xmm1
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  movss  0x8(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  jmp    1050 <sqrt@plt>
```

assistant: ```c
float norma(float *x) {
  float norma2 = 0;
  int i;
  for (i = 0; i < 3; i++)
    norma2 += x[i] * x[i];
  return sqrt(norma2);
}
```