ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    -0x1579f698(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy13;
        copy14 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 360314520UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x1613eb53,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy13;
        copy14 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 360314520UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x1613eb53,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy13;
        copy14 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 360314520UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  sub    $0x1613eb53,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] > local1) {
        state[0UL] += state[0UL];
      } else {
        state[local1] = state[0UL] + state[0UL];
        state[0UL] += state[local1];
      }
      if (state[0UL] != local1) {
        state[local1] = state[0UL] + state[local1];
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy12;
      } else {
        copy13 = *((unsigned short *)(&state[0UL]) + 2);
        *((unsigned short *)(&state[0UL]) + 2) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy13;
        copy14 = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] - 360314520UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<solcon_replace_quaddobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x18b,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int solcon_replace_quaddobl_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(395, &k, b, sol);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_replace_quaddobl_solution>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x10(%rsp)
  mov    %edx,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x18b,%edi
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_replace_quaddobl_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(395, &k, b, sol);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<solcon_replace_quaddobl_solution>:
  endbr64
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x10(%rsp)
  mov    $0x18b,%edi
  mov    %edx,0x14(%rsp)
  lea    0x10(%rsp),%rdx
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_replace_quaddobl_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(395, &k, b, sol);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<solcon_replace_quaddobl_solution>:
  endbr64
  sub    $0x28,%rsp
  movd   %edi,%xmm0
  movd   %edx,%xmm1
  mov    $0x18b,%edi
  mov    %esi,0xc(%rsp)
  punpckldq %xmm1,%xmm0
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_replace_quaddobl_solution(int n, int k, int m, double *sol) {
  int b[2], fail;
  b[0] = n;
  b[1] = m;
  fail = _ada_use_c2phc(395, &k, b, sol);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mkdir_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L29:
  cmp    %rdx,%rsp
  je     L68
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L29
L68:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L41
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L41:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x68(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x40(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x50(%rbp)
  jmp    L98
L82:
  mov    -0x50(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    $0x1ff,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    %eax,-0x54(%rbp)
  cmpl   $0x0,-0x54(%rbp)
  jns    L55
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L55
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L16
L55:
  mov    -0x50(%rbp),%rax
  movb   $0x2f,(%rax)
  mov    -0x50(%rbp),%rax
  add    $0x1,%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x50(%rbp)
L98:
  cmpq   $0x0,-0x50(%rbp)
  je     L33
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L82
L33:
  mov    $0x0,%eax
L16:
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int mkdir_p(const char *path) {
  char *p;
  char t[strlen(path) + 1];
  assert(path);
  strcpy(t, path);
  for (p = strchr(t, '/'); p && *p; p = strchr(p + 1, '/')) {
    int r;
    *p = 0;
    r = mkdir(t, 0777);
    if (r < 0 && errno != EEXIST)
      return -errno;
    *p = '/';
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mkdir_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L44:
  cmp    %rdx,%rsp
  je     L107
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L44
L107:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L50
  orq    $0x0,-0x8(%rsp,%rax,1)
L50:
  mov    %rsp,%r12
  mov    %rbx,%rdi
  call   <assert@plt>
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rsp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  jne    L12
  jmp    L113
L114:
  movb   $0x2f,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L34
L12:
  cmpb   $0x0,(%rbx)
  je     L80
  movb   $0x0,(%rbx)
  mov    $0x1ff,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  test   %eax,%eax
  jns    L114
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    D4(%rip),%rdx
  cmp    (%rdx),%eax
  je     L114
  neg    %eax
  jmp    L113
L80:
  mov    $0x0,%eax
L113:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L34:
  mov    $0x0,%eax
  jmp    L113
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mkdir_p(const char *path) {
  char *p;
  char t[strlen(path) + 1];
  assert(path);
  strcpy(t, path);
  for (p = strchr(t, '/'); p && *p; p = strchr(p + 1, '/')) {
    int r;
    *p = 0;
    r = mkdir(t, 0777);
    if (r < 0 && errno != EEXIST)
      return -errno;
    *p = '/';
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mkdir_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L33
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L16
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L93:
  mov    %r13,%rdi
  mov    %rsp,%r12
  call   <assert@plt>
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rsp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L49
  jmp    L114
  nopl   (%rax)
L31:
  movb   $0x0,(%rbx)
  mov    $0x1ff,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  test   %eax,%eax
  jns    L102
  mov    D12(%rip),%rax
  mov    D1(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  jne    L34
L102:
  movb   $0x2f,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L114
L49:
  cmpb   $0x0,(%rbx)
  jne    L31
L114:
  xor    %eax,%eax
L43:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L97
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  neg    %eax
  jmp    L43
  nopl   0x0(%rax)
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L93
L97:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mkdir_p(const char *path) {
  char *p;
  char t[strlen(path) + 1];
  assert(path);
  strcpy(t, path);
  for (p = strchr(t, '/'); p && *p; p = strchr(p + 1, '/')) {
    int r;
    *p = 0;
    r = mkdir(t, 0777);
    if (r < 0 && errno != EEXIST)
      return -errno;
    *p = '/';
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mkdir_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L1
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L1:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L7
L83:
  mov    %r13,%rdi
  mov    %rsp,%r12
  call   <assert@plt>
  mov    %r13,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    $0x2f,%esi
  mov    %rsp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L72
  jmp    L53
  nopl   (%rax)
L27:
  movb   $0x0,(%rbx)
  mov    $0x1ff,%esi
  mov    %r12,%rdi
  call   <mkdir@plt>
  test   %eax,%eax
  jns    L59
  mov    D15(%rip),%rax
  mov    D0(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  jne    L39
L59:
  movb   $0x2f,(%rbx)
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L53
L72:
  cmpb   $0x0,(%rbx)
  jne    L27
L53:
  xor    %eax,%eax
L76:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L70
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  neg    %eax
  jmp    L76
  nopl   0x0(%rax)
L7:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L83
L70:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mkdir_p(const char *path) {
  char *p;
  char t[strlen(path) + 1];
  assert(path);
  strcpy(t, path);
  for (p = strchr(t, '/'); p && *p; p = strchr(p + 1, '/')) {
    int r;
    *p = 0;
    r = mkdir(t, 0777);
    if (r < 0 && errno != EEXIST)
      return -errno;
    *p = '/';
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <options_print@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: Usage: clQueue [options]


assistant: ```c
void usage() {
  printf("Usage: clQueue [options]\n");
  options_print();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <options_print@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: Usage: clQueue [options]


assistant: ```c
void usage() {
  printf("Usage: clQueue [options]\n");
  options_print();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <options_print@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: Usage: clQueue [options]


assistant: ```c
void usage() {
  printf("Usage: clQueue [options]\n");
  options_print();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <options_print@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
data_type: string

tool: D9: Usage: clQueue [options]


assistant: ```c
void usage() {
  printf("Usage: clQueue [options]\n");
  options_print();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<internal_fiat_poly1305_carry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x8,%esi
  mov    %ebp,%edi
  call   <_br2_load@plt>
  mov    %rax,%r12
  lea    0x8(%rbp),%edi
  mov    $0x8,%esi
  call   <_br2_load@plt>
  mov    %rax,%r13
  lea    0x10(%rbp),%edi
  mov    $0x8,%esi
  call   <_br2_load@plt>
  mov    %rax,%rcx
  mov    %r12,%rdx
  shr    $0x2c,%rdx
  add    %r13,%rdx
  mov    %rdx,%rax
  shr    $0x2b,%rax
  add    %rcx,%rax
  mov    %rax,%rcx
  shr    $0x2b,%rcx
  lea    (%rcx,%rcx,4),%rsi
  movabs $0xfffffffffff,%rcx
  and    %rcx,%r12
  add    %r12,%rsi
  mov    %rsi,%rbp
  shr    $0x2c,%rbp
  movabs $0x7ffffffffff,%r12
  and    %r12,%rdx
  add    %rdx,%rbp
  mov    %rbp,%r13
  shr    $0x2b,%r13
  and    %r12,%rax
  add    %rax,%r13
  and    %rcx,%rsi
  mov    $0x8,%edx
  mov    %ebx,%edi
  call   <_br2_store@plt>
  mov    %rbp,%rsi
  and    %r12,%rsi
  lea    0x8(%rbx),%edi
  mov    $0x8,%edx
  call   <_br2_store@plt>
  lea    0x10(%rbx),%edi
  mov    $0x8,%edx
  mov    %r13,%rsi
  call   <_br2_store@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void internal_fiat_poly1305_carry(uintptr_t out0, uintptr_t in0) {
  uintptr_t x0, x1, x2, x3, x4, x6, x7, x5, x8, x9, x10, x11, x12, x13;
  x0 = _br2_load((in0) + ((uintptr_t)0ULL), sizeof(uintptr_t));
  x1 = _br2_load((in0) + ((uintptr_t)8ULL), sizeof(uintptr_t));
  x2 = _br2_load((in0) + ((uintptr_t)16ULL), sizeof(uintptr_t));
  x3 = x0;
  x4 = ((x3) >> ((uintptr_t)44ULL)) + (x1);
  x5 = ((x4) >> ((uintptr_t)43ULL)) + (x2);
  x6 = ((x3) & ((uintptr_t)17592186044415ULL)) + (((x5) >> ((uintptr_t)43ULL)) * ((uintptr_t)5ULL));
  x7 = ((x6) >> ((uintptr_t)44ULL)) + ((x4) & ((uintptr_t)8796093022207ULL));
  x8 = (x6) & ((uintptr_t)17592186044415ULL);
  x9 = (x7) & ((uintptr_t)8796093022207ULL);
  x10 = ((x7) >> ((uintptr_t)43ULL)) + ((x5) & ((uintptr_t)8796093022207ULL));
  x11 = x8;
  x12 = x9;
  x13 = x10;
  _br2_store((out0) + ((uintptr_t)0ULL), x11, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)8ULL), x12, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)16ULL), x13, sizeof(uintptr_t));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<internal_fiat_poly1305_carry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <_br2_load@plt>
  lea    0x8(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r12
  call   <_br2_load@plt>
  lea    0x10(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r13
  call   <_br2_load@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  shr    $0x2c,%rdx
  mov    %rax,%r8
  add    %r13,%rdx
  movabs $0x7ffffffffff,%r13
  mov    %rdx,%rax
  and    %r13,%rdx
  shr    $0x2b,%rax
  add    %r8,%rax
  mov    %rax,%rcx
  and    %r13,%rax
  shr    $0x2b,%rcx
  lea    (%rcx,%rcx,4),%rsi
  movabs $0xfffffffffff,%rcx
  and    %rcx,%r12
  add    %r12,%rsi
  mov    %rsi,%rbp
  and    %rcx,%rsi
  shr    $0x2c,%rbp
  add    %rdx,%rbp
  mov    $0x8,%edx
  mov    %rbp,%r12
  shr    $0x2b,%r12
  add    %rax,%r12
  call   <_br2_store@plt>
  mov    %rbp,%rsi
  lea    0x8(%rbx),%edi
  mov    $0x8,%edx
  and    %r13,%rsi
  call   <_br2_store@plt>
  add    $0x8,%rsp
  lea    0x10(%rbx),%edi
  mov    %r12,%rsi
  pop    %rbx
  mov    $0x8,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <_br2_store@plt>
```

assistant: ```c
void internal_fiat_poly1305_carry(uintptr_t out0, uintptr_t in0) {
  uintptr_t x0, x1, x2, x3, x4, x6, x7, x5, x8, x9, x10, x11, x12, x13;
  x0 = _br2_load((in0) + ((uintptr_t)0ULL), sizeof(uintptr_t));
  x1 = _br2_load((in0) + ((uintptr_t)8ULL), sizeof(uintptr_t));
  x2 = _br2_load((in0) + ((uintptr_t)16ULL), sizeof(uintptr_t));
  x3 = x0;
  x4 = ((x3) >> ((uintptr_t)44ULL)) + (x1);
  x5 = ((x4) >> ((uintptr_t)43ULL)) + (x2);
  x6 = ((x3) & ((uintptr_t)17592186044415ULL)) + (((x5) >> ((uintptr_t)43ULL)) * ((uintptr_t)5ULL));
  x7 = ((x6) >> ((uintptr_t)44ULL)) + ((x4) & ((uintptr_t)8796093022207ULL));
  x8 = (x6) & ((uintptr_t)17592186044415ULL);
  x9 = (x7) & ((uintptr_t)8796093022207ULL);
  x10 = ((x7) >> ((uintptr_t)43ULL)) + ((x5) & ((uintptr_t)8796093022207ULL));
  x11 = x8;
  x12 = x9;
  x13 = x10;
  _br2_store((out0) + ((uintptr_t)0ULL), x11, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)8ULL), x12, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)16ULL), x13, sizeof(uintptr_t));
  return;
}
```