ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<fdt_nodename_eq_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fdt_get_name@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L89
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x30(%rbp)
  jle    L42
L89:
  mov    $0x0,%eax
  jmp    L30
L42:
  mov    -0x30(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  jmp    L30
L9:
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L69
  mov    $0x1,%eax
  jmp    L30
L69:
  mov    -0x30(%rbp),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  test   %eax,%eax
  jne    L36
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jne    L36
  mov    $0x1,%eax
  jmp    L30
L36:
  mov    $0x0,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int fdt_nodename_eq_(const void *fdt, int offset, const char *s, int len) {
  int olen;
  const char *p = fdt_get_name(fdt, offset, &olen);
  if (!p || olen < len)
    return 0;
  if (memcmp(p, s, len) != 0)
    return 0;
  if (p[len] == '\0')
    return 1;
  else if (!memchr(s, '@', len) && (p[len] == '@'))
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fdt_nodename_eq_>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <fdt_get_name@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbx
  mov    $0x0,%eax
  cmp    %ebp,0x4(%rsp)
  jge    L20
L45:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L45
  movslq %ebp,%rax
  add    %rax,%rbx
  mov    $0x1,%eax
  cmpb   $0x0,(%rbx)
  je     L45
  mov    %ebp,%edx
  mov    $0x40,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L45
  cmpb   $0x40,(%rbx)
  sete   %al
  movzbl %al,%eax
  jmp    L45
L4:
  mov    $0x0,%eax
  jmp    L45
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_nodename_eq_(const void *fdt, int offset, const char *s, int len) {
  int olen;
  const char *p = fdt_get_name(fdt, offset, &olen);
  if (!p || olen < len)
    return 0;
  if (memcmp(p, s, len) != 0)
    return 0;
  if (p[len] == '\0')
    return 1;
  else if (!memchr(s, '@', len) && (p[len] == '@'))
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fdt_nodename_eq_>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <fdt_get_name@plt>
  test   %rax,%rax
  je     L58
  cmp    %r12d,0x4(%rsp)
  jge    L40
L58:
  xor    %eax,%eax
L64:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L58
  movslq %r12d,%rax
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L59
L21:
  mov    $0x1,%eax
  jmp    L64
L59:
  mov    %r12d,%edx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %eax,%eax
  jne    L58
  cmpb   $0x40,(%rbx)
  jne    L58
  jmp    L21
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_nodename_eq_(const void *fdt, int offset, const char *s, int len) {
  int olen;
  const char *p = fdt_get_name(fdt, offset, &olen);
  if (!p || olen < len)
    return 0;
  if (memcmp(p, s, len) != 0)
    return 0;
  if (p[len] == '\0')
    return 1;
  else if (!memchr(s, '@', len) && (p[len] == '@'))
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fdt_nodename_eq_>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <fdt_get_name@plt>
  test   %rax,%rax
  je     L45
  cmp    %r12d,0x4(%rsp)
  jge    L83
L45:
  xor    %eax,%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L83:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L45
  movslq %r12d,%rax
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  jne    L81
L88:
  mov    $0x1,%eax
  jmp    L1
L81:
  mov    %r12d,%edx
  mov    $0x40,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %eax,%eax
  jne    L45
  cmpb   $0x40,(%rbx)
  jne    L45
  jmp    L88
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_nodename_eq_(const void *fdt, int offset, const char *s, int len) {
  int olen;
  const char *p = fdt_get_name(fdt, offset, &olen);
  if (!p || olen < len)
    return 0;
  if (memcmp(p, s, len) != 0)
    return 0;
  if (p[len] == '\0')
    return 1;
  else if (!memchr(s, '@', len) && (p[len] == '@'))
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_compare_with_null_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  cmpq   $0x0,-0x20(%rbp)
  je     L49
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x28(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L89
  mov    $0x1,%eax
  jmp    L56
L89:
  cmpl   $0x0,-0x4(%rbp)
  jns    L27
  mov    $0xffffffff,%eax
  jmp    L56
L27:
  mov    $0x0,%eax
  jmp    L56
L49:
  mov    $0x1,%eax
  jmp    L56
L19:
  cmpq   $0x0,-0x20(%rbp)
  je     L63
  mov    $0xffffffff,%eax
  jmp    L56
L63:
  mov    $0x0,%eax
L56:
  leave
  ret
```

assistant: ```c
int str_compare_with_null_check(const char *first, const char *second, int (*compare_func)(const char *, const char *)) {
  if (first != NULL) {
    if (second != NULL) {
      const int result = compare_func(first, second);
      if (result > 0)
        return +1;
      if (result < 0)
        return -1;
      return 0;
    } else {
      return +1;
    }
  } else {
    if (second != NULL) {
      return -1;
    } else {
      return 0;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<str_compare_with_null_check>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  je     L2
  sub    $0x8,%rsp
  call   *%rdx
  cltd
  test   %eax,%eax
  mov    $0x1,%eax
  cmovle %edx,%eax
  add    $0x8,%rsp
  ret
L10:
  neg    %rsi
  sbb    %eax,%eax
  ret
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int str_compare_with_null_check(const char *first, const char *second, int (*compare_func)(const char *, const char *)) {
  if (first != NULL) {
    if (second != NULL) {
      const int result = compare_func(first, second);
      if (result > 0)
        return +1;
      if (result < 0)
        return -1;
      return 0;
    } else {
      return +1;
    }
  } else {
    if (second != NULL) {
      return -1;
    } else {
      return 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_compare_with_null_check>:
  endbr64
  test   %rdi,%rdi
  je     L23
  test   %rsi,%rsi
  je     L7
  sub    $0x8,%rsp
  call   *%rdx
  test   %eax,%eax
  jg     L3
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
  nopl   (%rax)
L3:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  neg    %rsi
  sbb    %eax,%eax
  ret
  xchg   %ax,%ax
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int str_compare_with_null_check(const char *first, const char *second, int (*compare_func)(const char *, const char *)) {
  if (first != NULL) {
    if (second != NULL) {
      const int result = compare_func(first, second);
      if (result > 0)
        return +1;
      if (result < 0)
        return -1;
      return 0;
    } else {
      return +1;
    }
  } else {
    if (second != NULL) {
      return -1;
    } else {
      return 0;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_compare_with_null_check>:
  endbr64
  test   %rdi,%rdi
  je     L14
  test   %rsi,%rsi
  je     L17
  sub    $0x8,%rsp
  call   *%rdx
  test   %eax,%eax
  jg     L5
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  neg    %eax
  ret
  nopl   (%rax)
L5:
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  neg    %rsi
  sbb    %eax,%eax
  ret
  xchg   %ax,%ax
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int str_compare_with_null_check(const char *first, const char *second, int (*compare_func)(const char *, const char *)) {
  if (first != NULL) {
    if (second != NULL) {
      const int result = compare_func(first, second);
      if (result > 0)
        return +1;
      if (result < 0)
        return -1;
      return 0;
    } else {
      return +1;
    }
  } else {
    if (second != NULL) {
      return -1;
    } else {
      return 0;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0xa,-0x8(%rbp)
  jne    L24
  cmpl   $0x0,-0x4(%rbp)
  jns    L24
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    $0x1,%ecx
  mov    %rax,%rdi
  call   <xtoa@plt>
  jmp    L18
L24:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rsi
  call   <xtoa@plt>
L18:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *itoa(int val, char *buf, int radix) {
  if (radix == 10 && val < 0)
    xtoa((unsigned long)val, buf, radix, 1);
  else
    xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0xa,%edx
  jne    L15
  test   %edi,%edi
  jns    L15
  movslq %edi,%rdi
  mov    $0x1,%ecx
  call   <xtoa@plt>
L21:
  mov    %rbx,%rax
  pop    %rbx
  ret
L15:
  mov    %edi,%edi
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  call   <xtoa@plt>
  jmp    L21
```

assistant: ```c
char *itoa(int val, char *buf, int radix) {
  if (radix == 10 && val < 0)
    xtoa((unsigned long)val, buf, radix, 1);
  else
    xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  cmp    $0xa,%edx
  jne    L9
  test   %edi,%edi
  jns    L9
  movslq %edi,%rdi
  mov    $0x1,%ecx
  call   <xtoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L9:
  mov    %r12,%rsi
  mov    %edi,%edi
  xor    %ecx,%ecx
  call   <xtoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *itoa(int val, char *buf, int radix) {
  if (radix == 10 && val < 0)
    xtoa((unsigned long)val, buf, radix, 1);
  else
    xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<itoa>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  cmp    $0xa,%edx
  jne    L14
  test   %edi,%edi
  jns    L14
  movslq %edi,%rdi
  mov    $0x1,%ecx
  call   <xtoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   (%rax)
L14:
  mov    %r12,%rsi
  mov    %edi,%edi
  xor    %ecx,%ecx
  call   <xtoa@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *itoa(int val, char *buf, int radix) {
  if (radix == 10 && val < 0)
    xtoa((unsigned long)val, buf, radix, 1);
  else
    xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_match_keywords>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x8000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  lea    D60(%rip),%r13
  mov    %r13,%rdx
  lea    D45(%rip),%r12
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    0x4000(%rsp),%rbx
  lea    D33(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <match_keywords@plt>
  cmp    $0x2,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D12(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <match_keywords@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D34(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <match_keywords@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <match_keywords@plt>
  cmp    $0x6,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x8018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D60
type: string
name: parse_data
arguments: label: D45
type: string
name: parse_data
arguments: label: D33
type: string
name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D34
type: string
name: parse_data
arguments: label: D21
type: string

tool: D16: test_match_keywords...

tool: D60: the, cat, sat, on, the, mat

tool: D45: %s

tool: D33: cat, mat

tool: D12: badger, antelope

tool: D34: badger, the, antelope

tool: D21: Ok


assistant: ```c
void test_match_keywords() {
  char keywords1[(4096 * 4)];
  char keywords2[(4096 * 4)];
  printf("test_match_keywords...");
  sprintf(keywords1, "%s", "the, cat, sat, on, the, mat");
  sprintf(keywords2, "%s", "cat, mat");
  assert(match_keywords(keywords2, keywords1) == 2);
  sprintf(keywords2, "%s", "badger, antelope");
  assert(match_keywords(keywords2, keywords1) == 0);
  sprintf(keywords2, "%s", "badger, the, antelope");
  assert(match_keywords(keywords2, keywords1) == 1);
  sprintf(keywords2, "%s", "the, cat, sat, on, the, mat");
  assert(match_keywords(keywords2, keywords1) == 6);
  printf("Ok\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_match_keywords>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x8000(%rsp),%r11
L7:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L7
  sub    $0x18,%rsp
  lea    D12(%rip),%r13
  lea    D16(%rip),%rdi
  lea    D69(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4000(%rsp),%rbp
  call   <printf@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  lea    D44(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  lea    D34(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    D59(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x8018,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D69
type_guessed: string
name: unpack_data
arguments: tag: D44
type_guessed: string
name: unpack_data
arguments: tag: D34
type_guessed: string
name: unpack_data
arguments: tag: D59
type_guessed: string
name: unpack_data
arguments: tag: D46
type_guessed: string

tool: D12: %s

tool: D16: test_match_keywords...

tool: D69: the, cat, sat, on, the, mat

tool: D44: cat, mat

tool: D34: badger, antelope

tool: D59: badger, the, antelope

tool: D46: Ok


assistant: ```c
void test_match_keywords() {
  char keywords1[(4096 * 4)];
  char keywords2[(4096 * 4)];
  printf("test_match_keywords...");
  sprintf(keywords1, "%s", "the, cat, sat, on, the, mat");
  sprintf(keywords2, "%s", "cat, mat");
  assert(match_keywords(keywords2, keywords1) == 2);
  sprintf(keywords2, "%s", "badger, antelope");
  assert(match_keywords(keywords2, keywords1) == 0);
  sprintf(keywords2, "%s", "badger, the, antelope");
  assert(match_keywords(keywords2, keywords1) == 1);
  sprintf(keywords2, "%s", "the, cat, sat, on, the, mat");
  assert(match_keywords(keywords2, keywords1) == 6);
  printf("Ok\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_match_keywords>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x8000(%rsp),%r11
L5:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L5
  sub    $0x18,%rsp
  lea    D52(%rip),%r13
  lea    D68(%rip),%rdi
  lea    D33(%rip),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4000(%rsp),%rbp
  call   <printf@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  lea    D30(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  cmp    $0x2,%eax
  sete   %dil
  call   <assert@plt>
  lea    D69(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  lea    D46(%rip),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <match_keywords@plt>
  xor    %edi,%edi
  cmp    $0x6,%eax
  sete   %dil
  call   <assert@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x8018,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D52
type_infered: string
name: unpack_data
arguments: data_tag: D68
type_infered: string
name: unpack_data
arguments: data_tag: D33
type_infered: string
name: unpack_data
arguments: data_tag: D30
type_infered: string
name: unpack_data
arguments: data_tag: D69
type_infered: string
name: unpack_data
arguments: data_tag: D46
type_infered: string
name: unpack_data
arguments: data_tag: D55
type_infered: string

tool: D52: %s

tool: D68: test_match_keywords...

tool: D33: the, cat, sat, on, the, mat

tool: D30: cat, mat

tool: D69: badger, antelope

tool: D46: badger, the, antelope

tool: D55: Ok


assistant: ```c
void test_match_keywords() {
  char keywords1[(4096 * 4)];
  char keywords2[(4096 * 4)];
  printf("test_match_keywords...");
  sprintf(keywords1, "%s", "the, cat, sat, on, the, mat");
  sprintf(keywords2, "%s", "cat, mat");
  assert(match_keywords(keywords2, keywords1) == 2);
  sprintf(keywords2, "%s", "badger, antelope");
  assert(match_keywords(keywords2, keywords1) == 0);
  sprintf(keywords2, "%s", "badger, the, antelope");
  assert(match_keywords(keywords2, keywords1) == 1);
  sprintf(keywords2, "%s", "the, cat, sat, on, the, mat");
  assert(match_keywords(keywords2, keywords1) == 6);
  printf("Ok\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <insertfunctionhere@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  insertfunctionhere(100, 1000);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <insertfunctionhere@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  insertfunctionhere(100, 1000);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <insertfunctionhere@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  insertfunctionhere(100, 1000);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <insertfunctionhere@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  insertfunctionhere(100, 1000);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  fldt   0xe9e(%rip)        # 2010 <_fini+0xdf8>
  fstpt  -0x30(%rbp)
  fldt   0xe95(%rip)        # 2010 <_fini+0xdf8>
  fstpt  -0x20(%rbp)
  fldt   -0x20(%rbp)
  fadd   %st(0),%st
  fldt   -0x30(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <cov_log@plt>
  add    $0x10,%rsp
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cov_check@plt>
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  push   -0x28(%rbp)
  push   -0x30(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string

tool: D17: result

tool: D14: %1.15Le


assistant: ```c
int main(int argc, char *argv[]) {
  long double a = 2.2L;
  long double b = 2.2L;
  long double c = b + b + a;
  cov_log(c, "result", argv[2]);
  cov_check(argv[2], argv[1], argv[3]);
  printf("%1.15Le\n", c);
  printf("%1.15Le\n", (long double)a);
  return 0;
}
```