ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x270,%rsp
  mov    %edi,-0x264(%rbp)
  mov    %rsi,-0x270(%rbp)
  mov    %edx,-0x268(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x268(%rbp)
  jg     L19
  mov    $0x0,%eax
  jmp    L61
L19:
  mov    -0x270(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x264(%rbp),%edx
  lea    -0x250(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x210(%rbp),%rcx
  lea    -0x250(%rbp),%rax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <f_read_string@plt>
  cmp    $0x4,%eax
  jle    L38
  lea    -0x210(%rbp),%rax
  mov    $0x29,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x258(%rbp)
  cmpq   $0x0,-0x258(%rbp)
  je     L38
  mov    -0x258(%rbp),%rax
  movb   $0x0,(%rax)
  lea    -0x210(%rbp),%rax
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x258(%rbp)
  cmpq   $0x0,-0x258(%rbp)
  je     L38
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  cmp    %eax,-0x264(%rbp)
  jne    L38
  mov    -0x258(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x268(%rbp),%edx
  mov    -0x270(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
L38:
  mov    -0x270(%rbp),%rax
L61:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: /proc/%d/stat

assistant: ```c
char *psname(int pid, char *buffer, int maxlen) {
  char buf[512];
  char path[64];
  char *p;
  if (maxlen <= 0)
    return NULL;
  *buffer = 0;
  sprintf(path, "/proc/%d/stat", pid);
  if ((f_read_string(path, buf, sizeof(buf)) > 4) && ((p = strrchr(buf, ')')) != NULL)) {
    *p = 0;
    if (((p = strchr(buf, '(')) != NULL) && (atoi(buf) == pid)) {
      strlcpy(buffer, p + 1, maxlen);
    }
  }
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<psname>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x258,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x248(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  test   %edx,%edx
  jle    L58
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %edx,%ebp
  movb   $0x0,(%rsi)
  mov    %rsp,%r12
  mov    %edi,%edx
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  lea    0x40(%rsp),%rsi
  mov    $0x200,%edx
  mov    %r12,%rdi
  call   <f_read_string@plt>
  cmp    $0x4,%eax
  jg     L48
L58:
  mov    0x248(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %rbx,%rax
  add    $0x258,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  lea    0x40(%rsp),%rdi
  mov    $0x29,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L58
  movb   $0x0,(%rax)
  lea    0x40(%rsp),%rdi
  mov    $0x28,%esi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L58
  lea    0x40(%rsp),%rdi
  call   <atoi@plt>
  cmp    %r13d,%eax
  jne    L58
  lea    0x1(%r12),%rsi
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
  jmp    L58
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: D2: /proc/%d/stat

assistant: ```c
char *psname(int pid, char *buffer, int maxlen) {
  char buf[512];
  char path[64];
  char *p;
  if (maxlen <= 0)
    return NULL;
  *buffer = 0;
  sprintf(path, "/proc/%d/stat", pid);
  if ((f_read_string(path, buf, sizeof(buf)) > 4) && ((p = strrchr(buf, ')')) != NULL)) {
    *p = 0;
    if (((p = strchr(buf, '(')) != NULL) && (atoi(buf) == pid)) {
      strlcpy(buffer, p + 1, maxlen);
    }
  }
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x250,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x248(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L27
  movb   $0x0,(%rsi)
  mov    %rsp,%r13
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  lea    D8(%rip),%rsi
  lea    0x40(%rsp),%r14
  mov    %edi,%edx
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    $0x200,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <f_read_string@plt>
  cmp    $0x4,%eax
  jg     L55
L59:
  mov    %rbx,%rax
L27:
  mov    0x248(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x250,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L55:
  mov    $0x29,%esi
  mov    %r14,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L59
  movb   $0x0,(%rax)
  mov    $0x28,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L59
  mov    %r14,%rdi
  call   <atoi@plt>
  cmp    %ebp,%eax
  jne    L59
  lea    0x1(%r13),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
  jmp    L59
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: /proc/%d/stat

assistant: ```c
char *psname(int pid, char *buffer, int maxlen) {
  char buf[512];
  char path[64];
  char *p;
  if (maxlen <= 0)
    return NULL;
  *buffer = 0;
  sprintf(path, "/proc/%d/stat", pid);
  if ((f_read_string(path, buf, sizeof(buf)) > 4) && ((p = strrchr(buf, ')')) != NULL)) {
    *p = 0;
    if (((p = strchr(buf, '(')) != NULL) && (atoi(buf) == pid)) {
      strlcpy(buffer, p + 1, maxlen);
    }
  }
  return buffer;
}
```
user: What is the c source code of the assembly code below?

```asm
<psname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x250,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x248(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L27
  movb   $0x0,(%rsi)
  mov    %rsp,%r13
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  lea    D2(%rip),%rsi
  lea    0x40(%rsp),%r14
  mov    %edi,%edx
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    $0x200,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <f_read_string@plt>
  cmp    $0x4,%eax
  jg     L17
L43:
  mov    %rbx,%rax
L27:
  mov    0x248(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x250,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x29,%esi
  mov    %r14,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L43
  movb   $0x0,(%rax)
  mov    $0x28,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L43
  mov    %r14,%rdi
  call   <atoi@plt>
  cmp    %ebp,%eax
  jne    L43
  lea    0x1(%r13),%rsi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
  jmp    L43
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string

tool: D2: /proc/%d/stat

assistant: ```c
char *psname(int pid, char *buffer, int maxlen) {
  char buf[512];
  char path[64];
  char *p;
  if (maxlen <= 0)
    return NULL;
  *buffer = 0;
  sprintf(path, "/proc/%d/stat", pid);
  if ((f_read_string(path, buf, sizeof(buf)) > 4) && ((p = strrchr(buf, ')')) != NULL)) {
    *p = 0;
    if (((p = strchr(buf, '(')) != NULL) && (atoi(buf) == pid)) {
      strlcpy(buffer, p + 1, maxlen);
    }
  }
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D47(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D47(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L23
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L23:
  cmpl   $0x1,-0x14(%rbp)
  jne    L6
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L31
L6:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D47
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D43
type_infered: string

tool: D47: asdf

tool: D9: true


tool: D17: false


tool: D43: not a damn clue


assistant: ```c
int main(void) {
  char *a = "asdf";
  char *b = "asdf";
  int ret = 0;
  ret = strcmp(a, b);
  if (ret == 0) {
    printf("true\n");
  } else if (ret == 1) {
    printf("false\n");
  } else {
    printf("not a damn clue\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: true


assistant: ```c
int main(void) {
  char *a = "asdf";
  char *b = "asdf";
  int ret = 0;
  ret = strcmp(a, b);
  if (ret == 0) {
    printf("true\n");
  } else if (ret == 1) {
    printf("false\n");
  } else {
    printf("not a damn clue\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: true


assistant: ```c
int main(void) {
  char *a = "asdf";
  char *b = "asdf";
  int ret = 0;
  ret = strcmp(a, b);
  if (ret == 0) {
    printf("true\n");
  } else if (ret == 1) {
    printf("false\n");
  } else {
    printf("not a damn clue\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: true


assistant: ```c
int main(void) {
  char *a = "asdf";
  char *b = "asdf";
  int ret = 0;
  ret = strcmp(a, b);
  if (ret == 0) {
    printf("true\n");
  } else if (ret == 1) {
    printf("false\n");
  } else {
    printf("not a damn clue\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<blob_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *blob_alloc(unsigned long size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr != NULL)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<blob_alloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *blob_alloc(unsigned long size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr != NULL)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<blob_alloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *blob_alloc(unsigned long size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr != NULL)
    memset(ptr, 0, size);
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<blob_alloc>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *blob_alloc(unsigned long size) {
  void *ptr;
  ptr = malloc(size);
  if (ptr != NULL)
    memset(ptr, 0, size);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_slope>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  subsd  -0x18(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double compute_slope(double x_1, double y_1, double x_2, double y_2) {
  double slope = 0.0;
  slope = (y_2 - y_1) / (x_2 - x_1);
  return slope;
}
```
user: What is the c source code of the assembly code below:

```asm
<compute_slope>:
  endbr64
  subsd  %xmm1,%xmm3
  subsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double compute_slope(double x_1, double y_1, double x_2, double y_2) {
  double slope = 0.0;
  slope = (y_2 - y_1) / (x_2 - x_1);
  return slope;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_slope>:
  endbr64
  subsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm3
  divsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double compute_slope(double x_1, double y_1, double x_2, double y_2) {
  double slope = 0.0;
  slope = (y_2 - y_1) / (x_2 - x_1);
  return slope;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_slope>:
  endbr64
  subsd  %xmm0,%xmm2
  subsd  %xmm1,%xmm3
  divsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  ret
```

assistant: ```c
double compute_slope(double x_1, double y_1, double x_2, double y_2) {
  double slope = 0.0;
  slope = (y_2 - y_1) / (x_2 - x_1);
  return slope;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ispan>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <reset@plt>
  test   %ebx,%ebx
  je     L24
L23:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  cmpl   $0x0,(%rsp,%rdx,4)
  jne    L72
  movl   $0x1,(%rsp,%rdx,4)
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ebx
  sub    %ebx,%eax
  mov    %eax,%ebx
  jne    L23
L24:
  test   %ebp,%ebp
  je     L107
L94:
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  cmpl   $0x0,(%rsp,%rdx,4)
  jne    L72
  movl   $0x1,(%rsp,%rdx,4)
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ebp
  sub    %ebp,%eax
  mov    %eax,%ebp
  jne    L94
L107:
  test   %r12d,%r12d
  je     L48
L88:
  movslq %r12d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %r12d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  cmpl   $0x0,(%rsp,%rdx,4)
  jne    L72
  movl   $0x1,(%rsp,%rdx,4)
  movslq %r12d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%r12d
  sub    %r12d,%eax
  mov    %eax,%r12d
  jne    L88
L48:
  mov    %rsp,%rax
L65:
  add    $0x4,%rax
  cmpl   $0x0,-0x4(%rax)
  jne    L65
L72:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L80:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ispan(int a, int b, int c) {
  int i;
  int pan[10];
  reset(pan);
  while (a != 0) {
    if (pan[a % 10])
      return 0;
    pan[a % 10] = 1;
    a /= 10;
  }
  while (b != 0) {
    if (pan[b % 10])
      return 0;
    pan[b % 10] = 1;
    b /= 10;
  }
  while (c != 0) {
    if (pan[c % 10])
      return 0;
    pan[c % 10] = 1;
    c /= 10;
  }
  for (i = 0; i < 11; i++)
    if (!pan[i])
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ispan>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <reset@plt>
  test   %ebx,%ebx
  jne    L41
  jmp    L0
  nopl   0x0(%rax)
L95:
  movl   $0x1,(%rsp,%rax,4)
  mov    %ecx,%ebx
  test   %ecx,%ecx
  je     L0
L41:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  mov    %ebx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%edi
  test   %edi,%edi
  je     L95
L61:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L71:
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  mov    %ebp,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%esi
  test   %esi,%esi
  jne    L61
  movl   $0x1,(%rsp,%rax,4)
  mov    %ecx,%ebp
L0:
  test   %ebp,%ebp
  jne    L71
  test   %r12d,%r12d
  je     L61
  nopl   0x0(%rax,%rax,1)
L21:
  movslq %r12d,%rax
  mov    %r12d,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  mov    %r12d,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%edx
  test   %edx,%edx
  jne    L61
  mov    %ecx,%r12d
  movl   $0x1,(%rsp,%rax,4)
  test   %r12d,%r12d
  jne    L21
  jmp    L61
L87:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ispan(int a, int b, int c) {
  int i;
  int pan[10];
  reset(pan);
  while (a != 0) {
    if (pan[a % 10])
      return 0;
    pan[a % 10] = 1;
    a /= 10;
  }
  while (b != 0) {
    if (pan[b % 10])
      return 0;
    pan[b % 10] = 1;
    b /= 10;
  }
  while (c != 0) {
    if (pan[c % 10])
      return 0;
    pan[c % 10] = 1;
    c /= 10;
  }
  for (i = 0; i < 11; i++)
    if (!pan[i])
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ispan>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <reset@plt>
  test   %ebx,%ebx
  jne    L28
  jmp    L31
  nopl   0x0(%rax)
L92:
  movl   $0x1,(%rsp,%rax,4)
  mov    %ecx,%ebx
  test   %ecx,%ecx
  je     L31
L28:
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  mov    %ebx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%edi
  test   %edi,%edi
  je     L92
L52:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L46:
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  mov    %ebp,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%esi
  test   %esi,%esi
  jne    L52
  movl   $0x1,(%rsp,%rax,4)
  mov    %ecx,%ebp
L31:
  test   %ebp,%ebp
  jne    L46
  test   %r12d,%r12d
  je     L52
  nopl   0x0(%rax,%rax,1)
L24:
  movslq %r12d,%rax
  mov    %r12d,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%ecx
  mov    %r12d,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,4),%edx
  test   %edx,%edx
  jne    L52
  mov    %ecx,%r12d
  movl   $0x1,(%rsp,%rax,4)
  test   %r12d,%r12d
  jne    L24
  jmp    L52
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ispan(int a, int b, int c) {
  int i;
  int pan[10];
  reset(pan);
  while (a != 0) {
    if (pan[a % 10])
      return 0;
    pan[a % 10] = 1;
    a /= 10;
  }
  while (b != 0) {
    if (pan[b % 10])
      return 0;
    pan[b % 10] = 1;
    b /= 10;
  }
  while (c != 0) {
    if (pan[c % 10])
      return 0;
    pan[c % 10] = 1;
    c /= 10;
  }
  for (i = 0; i < 11; i++)
    if (!pan[i])
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<PyThread_set_key_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <pthread_setspecific@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    $0xffffffff,%eax
  jmp    L1
L2:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int PyThread_set_key_value(int key, void *value) {
  int fail;
  fail = pthread_setspecific(key, value);
  return fail ? -1 : 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PyThread_set_key_value>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_setspecific@plt>
  neg    %eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int PyThread_set_key_value(int key, void *value) {
  int fail;
  fail = pthread_setspecific(key, value);
  return fail ? -1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PyThread_set_key_value>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_setspecific@plt>
  neg    %eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int PyThread_set_key_value(int key, void *value) {
  int fail;
  fail = pthread_setspecific(key, value);
  return fail ? -1 : 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<PyThread_set_key_value>:
  endbr64
  sub    $0x8,%rsp
  call   <pthread_setspecific@plt>
  neg    %eax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int PyThread_set_key_value(int key, void *value) {
  int fail;
  fail = pthread_setspecific(key, value);
  return fail ? -1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D15: 1.234567801232

tool: D3: %.10lf


assistant: ```c
int main(void) {
  double d = 1.234567801232;
  printf("%.10lf\n", d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D2(%rip),%xmm0
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: f64
name: retrieve_data
arguments: tag: D3
datatype: string

tool: D2: 1.234567801232

tool: D3: %.10lf


assistant: ```c
int main(void) {
  double d = 1.234567801232;
  printf("%.10lf\n", d);
}
```