ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L19:
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  nop
L18:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  char *s = dest;
  while (*dest) {
    dest++;
  }
  while ((*dest++ = *src++))
    ;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L24
  mov    %rdi,%rcx
L9:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L9
L20:
  mov    $0x0,%edx
L29:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L29
  ret
L24:
  mov    %rdi,%rcx
  jmp    L20
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  char *s = dest;
  while (*dest) {
    dest++;
  }
  while ((*dest++ = *src++))
    ;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  je     L25
  nop
L18:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L18
L25:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L3
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  char *s = dest;
  while (*dest) {
    dest++;
  }
  while ((*dest++ = *src++))
    ;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  je     L20
  nop
L14:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L14
L20:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rsi,%rdx,1),%r8d
  mov    %r8b,(%rcx,%rdx,1)
  add    $0x1,%rdx
  test   %r8b,%r8b
  jne    L12
  ret
```

assistant: ```c
char *strcat(char *dest, const char *src) {
  char *s = dest;
  while (*dest) {
    dest++;
  }
  while ((*dest++ = *src++))
    ;
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_is_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L35
L28:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  test   %eax,%eax
  je     L35
  mov    $0x1,%eax
  jmp    L15
L35:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L28
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t mem_is_zero(uint8_t *src, uint16_t len) {
  while (len--) {
    if (*src++) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_is_zero>:
  endbr64
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
L0:
  cmp    %rax,%rdi
  je     L10
  add    $0x4,%rdi
  cmpl   $0x0,-0x4(%rdi)
  je     L0
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint8_t mem_is_zero(uint8_t *src, uint16_t len) {
  while (len--) {
    if (*src++) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_is_zero>:
  endbr64
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  jmp    L3
  nopl   0x0(%rax)
L23:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  test   %edx,%edx
  jne    L18
L3:
  cmp    %rax,%rdi
  jne    L23
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint8_t mem_is_zero(uint8_t *src, uint16_t len) {
  while (len--) {
    if (*src++) {
      return 1;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mem_is_zero>:
  endbr64
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rax
  jmp    L9
  nopl   0x0(%rax)
L2:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  test   %edx,%edx
  jne    L10
L9:
  cmp    %rax,%rdi
  jne    L2
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint8_t mem_is_zero(uint8_t *src, uint16_t len) {
  while (len--) {
    if (*src++) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L42
L41:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L50
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L29
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L30
L29:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L30
L50:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shl    $0x2,%eax
  cltq
  lea    D14(%rip),%rdx
  add    %rdx,%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L30:
  addl   $0x1,-0x4(%rbp)
L42:
  cmpl   $0x64,-0x4(%rbp)
  jle    L41
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
type: string
name: unpack_data
arguments: tag: D27
type: string
name: unpack_data
arguments: tag: D14
type: string

tool: D18: %d


tool: D27: Fizz

tool: D14: FizzBuzz


assistant: ```c
int main() {
  for (int i = 1; i <= 100; i++) {
    if (i % 5) {
      if (i % 3) {
        printf("%d\n", i);
      } else {
        printf("Fizz\n");
      }
    } else {
      printf("FizzBuzz\n" + i * i % 3 * 4);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D3(%rip),%r13
  lea    D18(%rip),%r12
  lea    D13(%rip),%rbp
  jmp    L15
L42:
  mov    %r12,%rdi
  call   <puts@plt>
L47:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L13
L15:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  je     L1
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L42
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L1:
  mov    %ebx,%edi
  imul   %ebx,%edi
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edi
  shl    $0x2,%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L47
L13:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: string

tool: D3: FizzBuzz


tool: D18: Fizz

tool: D13: %d


assistant: ```c
int main() {
  for (int i = 1; i <= 100; i++) {
    if (i % 5) {
      if (i % 3) {
        printf("%d\n", i);
      } else {
        printf("Fizz\n");
      }
    } else {
      printf("FizzBuzz\n" + i * i % 3 * 4);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xaaaaaaab,%r14d
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L0
  xchg   %ax,%ax
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L19:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L37
L0:
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  jbe    L6
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  ja     L8
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L0
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  mov    %ebx,%edi
  imul   %ebx,%edi
  mov    %edi,%eax
  imul   %r14,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edi
  xor    %eax,%eax
  shl    $0x2,%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: unpack_data
arguments: data_label: D18
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D1
type: string

tool: D18: FizzBuzz


tool: D15: Fizz

tool: D1: %d


assistant: ```c
int main() {
  for (int i = 1; i <= 100; i++) {
    if (i % 5) {
      if (i % 3) {
        printf("%d\n", i);
      } else {
        printf("Fizz\n");
      }
    } else {
      printf("FizzBuzz\n" + i * i % 3 * 4);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xaaaaaaab,%r14d
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L39
  xchg   %ax,%ax
L33:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L46:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L56
L39:
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  jbe    L53
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  ja     L33
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L39
L56:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L53:
  mov    %ebx,%edi
  imul   %ebx,%edi
  mov    %edi,%eax
  imul   %r14,%rax
  shr    $0x21,%rax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%edi
  xor    %eax,%eax
  shl    $0x2,%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  call   <printf@plt>
  jmp    L46
```

tool_calls: name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D25
data_type: string
name: retrieve_data
arguments: tag: D26
data_type: string

tool: D11: FizzBuzz


tool: D25: Fizz

tool: D26: %d


assistant: ```c
int main() {
  for (int i = 1; i <= 100; i++) {
    if (i % 5) {
      if (i % 3) {
        printf("%d\n", i);
      } else {
        printf("Fizz\n");
      }
    } else {
      printf("FizzBuzz\n" + i * i % 3 * 4);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fbitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L28
L35:
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L26:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L26
  mov    -0x4(%rbp),%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int fbitcount(int x) {
  int b;
  if (!x)
    return 0;
  for (b = 1; x &= (x - 1); b++)
    ;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fbitcount>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  je     L12
  lea    -0x1(%rdi),%eax
  and    %eax,%edi
  je     L22
  mov    $0x1,%edx
L18:
  add    $0x1,%edx
  lea    -0x1(%rdi),%eax
  and    %eax,%edi
  jne    L18
L12:
  mov    %edx,%eax
  ret
L22:
  mov    $0x1,%edx
  jmp    L12
```

assistant: ```c
int fbitcount(int x) {
  int b;
  if (!x)
    return 0;
  for (b = 1; x &= (x - 1); b++)
    ;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fbitcount>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L14
  lea    -0x1(%rdi),%eax
  mov    $0x1,%r8d
  and    %eax,%edi
  je     L14
  nopl   0x0(%rax,%rax,1)
L27:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L27
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fbitcount(int x) {
  int b;
  if (!x)
    return 0;
  for (b = 1; x &= (x - 1); b++)
    ;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fbitcount>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L22
  lea    -0x1(%rdi),%eax
  mov    $0x1,%r8d
  and    %eax,%edi
  je     L22
  nopl   0x0(%rax,%rax,1)
L0:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L0
L22:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fbitcount(int x) {
  int b;
  if (!x)
    return 0;
  for (b = 1; x &= (x - 1); b++)
    ;
  return b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<SwapWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SwapWord(char *binary, int len) {
  char tmp;
  int i, j;
  for (i = 0, j = len - 1; i < j; ++i, --j) {
    tmp = binary[i];
    binary[i] = binary[j];
    binary[j] = tmp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SwapWord>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L19
  movslq %esi,%rsi
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L5
L19:
  ret
```

assistant: ```c
void SwapWord(char *binary, int len) {
  char tmp;
  int i, j;
  for (i = 0, j = len - 1; i < j; ++i, --j) {
    tmp = binary[i];
    binary[i] = binary[j];
    binary[j] = tmp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SwapWord>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L13
  movslq %esi,%rsi
  xor    %eax,%eax
L8:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L8
L13:
  ret
```

assistant: ```c
void SwapWord(char *binary, int len) {
  char tmp;
  int i, j;
  for (i = 0, j = len - 1; i < j; ++i, --j) {
    tmp = binary[i];
    binary[i] = binary[j];
    binary[j] = tmp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SwapWord>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L11
  movslq %esi,%rsi
  xor    %eax,%eax
L2:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L2
L11:
  ret
```

assistant: ```c
void SwapWord(char *binary, int len) {
  char tmp;
  int i, j;
  for (i = 0, j = len - 1; i < j; ++i, --j) {
    tmp = binary[i];
    binary[i] = binary[j];
    binary[j] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  movl   $0x7b,-0x2c(%rbp)
  movl   $0x2d,-0x28(%rbp)
  movl   $0x64,-0x24(%rbp)
  movl   $0x23f,-0x20(%rbp)
  movl   $0xf0,-0x1c(%rbp)
  movl   $0x31f,-0x18(%rbp)
  movl   $0x2c6,-0x14(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x5a,-0xc(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x40(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  movl   $0xa,-0x34(%rbp)
  mov    $0x28,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L7
L11:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x40(%rbp)
  jge    L3
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x40(%rbp)
L3:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x3c(%rbp)
  jle    L10
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x3c(%rbp)
L10:
  addl   $0x1,-0x38(%rbp)
L7:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L11
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D16
datatype: string

tool: D14: %ld


tool: D16: The max is %d, The min is %d


assistant: ```c
void main() {
  int a[10] = {2, 123, 45, 100, 575, 240, 799, 710, 10, 90};
  int max = a[0], min = a[0];
  int i;
  int len = sizeof(a) / sizeof(int);
  printf("%ld\n", sizeof(a));
  for (i = 0; i < len; i++) {
    if (a[i] > max) {
      max = a[i];
    }
    if (a[i] < min) {
      min = a[i];
    }
  }
  printf("The max is %d, The min is %d\n", max, min);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x7b,0x4(%rsp)
  movl   $0x2d,0x8(%rsp)
  movl   $0x64,0xc(%rsp)
  movl   $0x23f,0x10(%rsp)
  movl   $0xf0,0x14(%rsp)
  movl   $0x31f,0x18(%rsp)
  movl   $0x2c6,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  movl   $0x5a,0x24(%rsp)
  mov    $0x28,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdx
  lea    0x28(%rsp),%rdi
  mov    $0x2,%ecx
  mov    $0x2,%esi
L19:
  mov    (%rdx),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    %eax,%ecx
  cmovg  %eax,%ecx
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L19
  mov    %ecx,%edx
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D9: %ld


tool: D8: The max is %d, The min is %d


assistant: ```c
void main() {
  int a[10] = {2, 123, 45, 100, 575, 240, 799, 710, 10, 90};
  int max = a[0], min = a[0];
  int i;
  int len = sizeof(a) / sizeof(int);
  printf("%ld\n", sizeof(a));
  for (i = 0; i < len; i++) {
    if (a[i] > max) {
      max = a[i];
    }
    if (a[i] < min) {
      min = a[i];
    }
  }
  printf("The max is %d, The min is %d\n", max, min);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x28,%esi
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x7b,0x4(%rsp)
  movabs $0x640000002d,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xf00000023f,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x2c60000031f,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x5a0000000a,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  lea    0x28(%rsp),%rcx
  mov    $0x2,%eax
  mov    $0x2,%r8d
  mov    $0x2,%esi
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rdx),%eax
  add    $0x4,%rdx
L11:
  cmp    %eax,%esi
  cmovl  %eax,%esi
  cmp    %eax,%r8d
  cmovg  %eax,%r8d
  cmp    %rcx,%rdx
  jne    L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %r8d,%edx
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  add    $0x38,%rsp
  jmp    1070 <printf@plt>
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D17: %ld


tool: D7: The max is %d, The min is %d


assistant: ```c
void main() {
  int a[10] = {2, 123, 45, 100, 575, 240, 799, 710, 10, 90};
  int max = a[0], min = a[0];
  int i;
  int len = sizeof(a) / sizeof(int);
  printf("%ld\n", sizeof(a));
  for (i = 0; i < len; i++) {
    if (a[i] > max) {
      max = a[i];
    }
    if (a[i] < min) {
      min = a[i];
    }
  }
  printf("The max is %d, The min is %d\n", max, min);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x28,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edx
  xor    %eax,%eax
  add    $0x8,%rsp
  mov    $0x31f,%esi
  lea    D16(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string

tool: D15: %ld


tool: D16: The max is %d, The min is %d


assistant: ```c
void main() {
  int a[10] = {2, 123, 45, 100, 575, 240, 799, 710, 10, 90};
  int max = a[0], min = a[0];
  int i;
  int len = sizeof(a) / sizeof(int);
  printf("%ld\n", sizeof(a));
  for (i = 0; i < len; i++) {
    if (a[i] > max) {
      max = a[i];
    }
    if (a[i] < min) {
      min = a[i];
    }
  }
  printf("The max is %d, The min is %d\n", max, min);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<indexof_featuremap_coeff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int indexof_featuremap_coeff(int num_detector, int detector, int pos) {
  assert(detector >= 0);
  assert(pos >= 0);
  return detector + num_detector * pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<indexof_featuremap_coeff>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %esi,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  imul   %r12d,%ebx
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int indexof_featuremap_coeff(int num_detector, int detector, int pos) {
  assert(detector >= 0);
  assert(pos >= 0);
  return detector + num_detector * pos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<indexof_featuremap_coeff>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  not    %edi
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%edi
  mov    %edx,%ebx
  call   <assert@plt>
  mov    %ebx,%edi
  imul   %r12d,%ebx
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int indexof_featuremap_coeff(int num_detector, int detector, int pos) {
  assert(detector >= 0);
  assert(pos >= 0);
  return detector + num_detector * pos;
}
```