ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<memcopy>:
  endbr64
  push   %r13
  movslq %esi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
L2:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <fatal@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: out of dynamic memory

assistant: ```c
void *memcopy(void *p, int len) {
  ;
  char *q = malloc(len);
  if (!q)
    fatal("out of dynamic memory");
  memcpy(q, p, len);
  return (q);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<silf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <get_random@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x96,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mod6@plt>
  cmp    %rax,%rbx
  jge    L5
  mov    -0x20(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <add_status@plt>
L5:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void silf(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 150))
    add_status(target, 12);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<silf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x64,%esi
  mov    $0x0,%edi
  call   <get_random@plt>
  mov    %rax,%rbp
  mov    $0x96,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <mod6@plt>
  cmp    %rax,%rbp
  jl     L17
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0xc,%esi
  mov    %rbx,%rdi
  call   <add_status@plt>
  jmp    L6
```

assistant: ```c
void silf(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 150))
    add_status(target, 12);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<silf>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x64,%esi
  push   %rbx
  call   <get_random@plt>
  mov    $0x96,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <mod6@plt>
  cmp    %rax,%rbx
  jl     L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0xc,%esi
  pop    %rbp
  pop    %r12
  jmp    1080 <add_status@plt>
```

assistant: ```c
void silf(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 150))
    add_status(target, 12);
}
```
user: What is the c source code of the assembly code below:

```asm
<silf>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x64,%esi
  push   %rbx
  call   <get_random@plt>
  mov    $0x96,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <mod6@plt>
  cmp    %rax,%rbx
  jl     L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  pop    %rbx
  mov    %rbp,%rdi
  mov    $0xc,%esi
  pop    %rbp
  pop    %r12
  jmp    1080 <add_status@plt>
```

assistant: ```c
void silf(struct battle_char *origin, struct battle_char *target) {
  if (get_random(0, 100) < mod6(origin, target, 150))
    add_status(target, 12);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<evtag_unmarshal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <evtag_unmarshal_header@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L23
  mov    $0xffffffff,%eax
  jmp    L30
L23:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <evbuffer_pullup@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <evbuffer_add@plt>
  cmp    $0xffffffff,%eax
  jne    L19
  mov    $0xffffffff,%eax
  jmp    L30
L19:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <evbuffer_drain@plt>
  mov    -0x4(%rbp),%eax
L30:
  leave
  ret
```

assistant: ```c
int evtag_unmarshal(struct evbuffer *src, unsigned long *ptag, struct evbuffer *dst) {
  int len;
  if ((len = evtag_unmarshal_header(src, ptag)) == -1)
    return (-1);
  if (evbuffer_add(dst, evbuffer_pullup(src, len), len) == -1)
    return (-1);
  evbuffer_drain(src, len);
  return (len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<evtag_unmarshal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  call   <evtag_unmarshal_header@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L0
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <evbuffer_pullup@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <evbuffer_add@plt>
  cmp    $0xffffffff,%eax
  je     L1
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <evbuffer_drain@plt>
L0:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %eax,%ebx
  jmp    L0
```

assistant: ```c
int evtag_unmarshal(struct evbuffer *src, unsigned long *ptag, struct evbuffer *dst) {
  int len;
  if ((len = evtag_unmarshal_header(src, ptag)) == -1)
    return (-1);
  if (evbuffer_add(dst, evbuffer_pullup(src, len), len) == -1)
    return (-1);
  evbuffer_drain(src, len);
  return (len);
}
```
user: What is the c source code of the assembly code below?

```asm
<evtag_unmarshal>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <evtag_unmarshal_header@plt>
  cmp    $0xffffffff,%eax
  je     L22
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <evbuffer_pullup@plt>
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <evbuffer_add@plt>
  cmp    $0xffffffff,%eax
  je     L22
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <evbuffer_drain@plt>
L6:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  mov    $0xffffffff,%r12d
  jmp    L6
```

assistant: ```c
int evtag_unmarshal(struct evbuffer *src, unsigned long *ptag, struct evbuffer *dst) {
  int len;
  if ((len = evtag_unmarshal_header(src, ptag)) == -1)
    return (-1);
  if (evbuffer_add(dst, evbuffer_pullup(src, len), len) == -1)
    return (-1);
  evbuffer_drain(src, len);
  return (len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<evtag_unmarshal>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <evtag_unmarshal_header@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <evbuffer_pullup@plt>
  mov    %r12d,%edx
  mov    %r13,%rdi
  mov    %eax,%esi
  call   <evbuffer_add@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <evbuffer_drain@plt>
L7:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    $0xffffffff,%r12d
  jmp    L7
```

assistant: ```c
int evtag_unmarshal(struct evbuffer *src, unsigned long *ptag, struct evbuffer *dst) {
  int len;
  if ((len = evtag_unmarshal_header(src, ptag)) == -1)
    return (-1);
  if (evbuffer_add(dst, evbuffer_pullup(src, len), len) == -1)
    return (-1);
  evbuffer_drain(src, len);
  return (len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tdd_whilefixer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L5:
  subl   $0x1,-0x4(%rbp)
  jmp    L5
```

assistant: ```c
void tdd_whilefixer(void) {
  int whilecounter;
  int counter;
  while (1)
    whilecounter--;
  while (1)
    whilecounter++;
  while (1) {
    counter++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tdd_whilefixer>:
  endbr64
L0:
  jmp    L0
```

assistant: ```c
void tdd_whilefixer(void) {
  int whilecounter;
  int counter;
  while (1)
    whilecounter--;
  while (1)
    whilecounter++;
  while (1) {
    counter++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tdd_whilefixer>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void tdd_whilefixer(void) {
  int whilecounter;
  int counter;
  while (1)
    whilecounter--;
  while (1)
    whilecounter++;
  while (1) {
    counter++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tdd_whilefixer>:
  endbr64
  nopl   0x0(%rax)
L0:
  jmp    L0
```

assistant: ```c
void tdd_whilefixer(void) {
  int whilecounter;
  int counter;
  while (1)
    whilecounter--;
  while (1)
    whilecounter++;
  while (1) {
    counter++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<readLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x33,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L3
L9:
  mov    -0x8(%rbp),%rax
  mov    $0x32,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jle    L26
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L3
L26:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L3:
  leave
  ret
```

assistant: ```c
char *readLine() {
  ssize_t ret;
  char *buff;
  if ((buff = malloc(sizeof(*buff) * (50 + 1))) == NULL)
    return (NULL);
  if ((ret = read(0, buff, 50)) > 1) {
    buff[ret - 1] = '\0';
    return (buff);
  }
  buff[0] = '\0';
  return (buff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readLine>:
  endbr64
  push   %rbx
  mov    $0x33,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    $0x32,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jg     L0
  movb   $0x0,(%rbx)
L8:
  mov    %rbx,%rax
  pop    %rbx
  ret
L0:
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L8
```

assistant: ```c
char *readLine() {
  ssize_t ret;
  char *buff;
  if ((buff = malloc(sizeof(*buff) * (50 + 1))) == NULL)
    return (NULL);
  if ((ret = read(0, buff, 50)) > 1) {
    buff[ret - 1] = '\0';
    return (buff);
  }
  buff[0] = '\0';
  return (buff);
}
```
user: What is the c source code of the assembly code below?

```asm
<readLine>:
  endbr64
  push   %r12
  mov    $0x33,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  xor    %edi,%edi
  mov    $0x32,%edx
  mov    %rax,%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  jg     L6
  movb   $0x0,(%r12)
L2:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *readLine() {
  ssize_t ret;
  char *buff;
  if ((buff = malloc(sizeof(*buff) * (50 + 1))) == NULL)
    return (NULL);
  if ((ret = read(0, buff, 50)) > 1) {
    buff[ret - 1] = '\0';
    return (buff);
  }
  buff[0] = '\0';
  return (buff);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readLine>:
  endbr64
  push   %r12
  mov    $0x33,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
  xor    %edi,%edi
  mov    $0x32,%edx
  mov    %rax,%rsi
  call   <read@plt>
  cmp    $0x1,%eax
  jg     L17
  movb   $0x0,(%r12)
L18:
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *readLine() {
  ssize_t ret;
  char *buff;
  if ((buff = malloc(sizeof(*buff) * (50 + 1))) == NULL)
    return (NULL);
  if ((ret = read(0, buff, 50)) > 1) {
    buff[ret - 1] = '\0';
    return (buff);
  }
  buff[0] = '\0';
  return (buff);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_help_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: dnat options:
 --to-dst address       : MAC address to map destination to
 --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE


assistant: ```c
void print_help_d() {
  printf("dnat options:\n"
         " --to-dst address       : MAC address to map destination to\n"
         " --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_help_d>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: dnat options:
 --to-dst address       : MAC address to map destination to
 --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE


assistant: ```c
void print_help_d() {
  printf("dnat options:\n"
         " --to-dst address       : MAC address to map destination to\n"
         " --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_help_d>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: dnat options:
 --to-dst address       : MAC address to map destination to
 --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE


assistant: ```c
void print_help_d() {
  printf("dnat options:\n"
         " --to-dst address       : MAC address to map destination to\n"
         " --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_help_d>:
  endbr64
  lea    D3(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: dnat options:
 --to-dst address       : MAC address to map destination to
 --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE


assistant: ```c
void print_help_d() {
  printf("dnat options:\n"
         " --to-dst address       : MAC address to map destination to\n"
         " --dnat-target target   : ACCEPT, DROP, RETURN or CONTINUE\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ExecuteAInstruction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <OpCodGetValue@plt>
  sub    $0xa,%eax
  cmp    $0x21,%eax
  ja     L39
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D2(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <Read@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Write@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Load@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Store@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Add@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Subtract@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Divide@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Multiply@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <Branch@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <BranchNeg@plt>
  jmp    L39
  mov    $0x0,%eax
  call   <BranchZero@plt>
  jmp    L39
  nop
L39:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ExecuteAInstruction(void) {
  switch (OpCodGetValue()) {
  case 10:
    Read();
    break;
  case 11:
    Write();
    break;
  case 20:
    Load();
    break;
  case 21:
    Store();
    break;
  case 30:
    Add();
    break;
  case 31:
    Subtract();
    break;
  case 32:
    Divide();
    break;
  case 33:
    Multiply();
    break;
  case 40:
    Branch();
    break;
  case 41:
    BranchNeg();
    break;
  case 42:
    BranchZero();
    break;
  case 43:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ExecuteAInstruction>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <OpCodGetValue@plt>
  sub    $0xa,%eax
  cmp    $0x20,%eax
  ja     L36
  mov    %eax,%eax
  lea    D7(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <Read@plt>
L36:
  add    $0x8,%rsp
  ret
  mov    $0x0,%eax
  call   <Write@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Load@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Store@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Add@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Subtract@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Divide@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Multiply@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <Branch@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <BranchNeg@plt>
  jmp    L36
  mov    $0x0,%eax
  call   <BranchZero@plt>
  jmp    L36
```

assistant: ```c
void ExecuteAInstruction(void) {
  switch (OpCodGetValue()) {
  case 10:
    Read();
    break;
  case 11:
    Write();
    break;
  case 20:
    Load();
    break;
  case 21:
    Store();
    break;
  case 30:
    Add();
    break;
  case 31:
    Subtract();
    break;
  case 32:
    Divide();
    break;
  case 33:
    Multiply();
    break;
  case 40:
    Branch();
    break;
  case 41:
    BranchNeg();
    break;
  case 42:
    BranchZero();
    break;
  case 43:
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ExecuteAInstruction>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <OpCodGetValue@plt>
  sub    $0xa,%eax
  cmp    $0x20,%eax
  ja     L1
  lea    D4(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1140 <Read@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1130 <Write@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11a0 <Load@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1110 <Store@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1150 <Add@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1100 <Subtract@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1170 <Divide@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1120 <Multiply@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1190 <Branch@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11b0 <BranchNeg@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1160 <BranchZero@plt>
```

assistant: ```c
void ExecuteAInstruction(void) {
  switch (OpCodGetValue()) {
  case 10:
    Read();
    break;
  case 11:
    Write();
    break;
  case 20:
    Load();
    break;
  case 21:
    Store();
    break;
  case 30:
    Add();
    break;
  case 31:
    Subtract();
    break;
  case 32:
    Divide();
    break;
  case 33:
    Multiply();
    break;
  case 40:
    Branch();
    break;
  case 41:
    BranchNeg();
    break;
  case 42:
    BranchZero();
    break;
  case 43:
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ExecuteAInstruction>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <OpCodGetValue@plt>
  sub    $0xa,%eax
  cmp    $0x20,%eax
  ja     L7
  lea    D1(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1140 <Read@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1130 <Write@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11a0 <Load@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1110 <Store@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1150 <Add@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1100 <Subtract@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1170 <Divide@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1120 <Multiply@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1190 <Branch@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11b0 <BranchNeg@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1160 <BranchZero@plt>
```

assistant: ```c
void ExecuteAInstruction(void) {
  switch (OpCodGetValue()) {
  case 10:
    Read();
    break;
  case 11:
    Write();
    break;
  case 20:
    Load();
    break;
  case 21:
    Store();
    break;
  case 30:
    Add();
    break;
  case 31:
    Subtract();
    break;
  case 32:
    Divide();
    break;
  case 33:
    Multiply();
    break;
  case 40:
    Branch();
    break;
  case 41:
    BranchNeg();
    break;
  case 42:
    BranchZero();
    break;
  case 43:
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ipfw_append>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <add_command@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <ipfw_init@plt>
  mov    D7(%rip),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int ipfw_append(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0010U, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<ipfw_append>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x0,%edx
  mov    $0x10,%esi
  call   <add_command@plt>
  mov    $0x0,%r8d
  mov    %r12,%rcx
  mov    0x4(%rsp),%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <ipfw_init@plt>
  mov    D3(%rip),%rax
  movq   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipfw_append(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0010U, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ipfw_append>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  xor    %edx,%edx
  push   %r12
  mov    %rsi,%r12
  mov    $0x10,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  movl   $0x0,0x4(%rsp)
  call   <add_command@plt>
  mov    0x4(%rsp),%edx
  xor    %r8d,%r8d
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <ipfw_init@plt>
  mov    D9(%rip),%rax
  movq   $0x0,(%rax)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ipfw_append(int args, char **arglist, const char *chain) {
  unsigned int command = 0;
  add_command(&command, 0x0010U, 0x0000U);
  ipfw_init(args, arglist, command, chain, 0);
  optind = 0;
  return (0);
}
```