ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubble_sort>:
  endbr64
  test   %esi,%esi
  jle    L20
  lea    -0x2(%rsi),%eax
  xor    %r9d,%r9d
  lea    0x4(%rdi,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%rax
  cmp    $0x1,%esi
  je     L29
L40:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L31
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L31:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L40
L29:
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jne    L19
L20:
  ret
```

assistant: ```c
void bubble_sort(int *data, int length) {
  int i, j;
  for (i = 0; i < length; i++)
    for (j = 0; j < length - 1; j++)
      if (data[j] > data[j + 1]) {
        int tmp = data[j];
        data[j] = data[j + 1];
        data[j + 1] = tmp;
      }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bubble_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L35
  lea    -0x2(%rsi),%eax
  xor    %r9d,%r9d
  lea    0x4(%rdi,%rax,4),%r8
  nopl   0x0(%rax)
L13:
  mov    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L12
  movq   %xmm1,(%rdx)
L12:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L4
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jne    L13
L35:
  ret
```

assistant: ```c
void bubble_sort(int *data, int length) {
  int i, j;
  for (i = 0; i < length; i++)
    for (j = 0; j < length - 1; j++)
      if (data[j] > data[j + 1]) {
        int tmp = data[j];
        data[j] = data[j + 1];
        data[j + 1] = tmp;
      }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rcycle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L10:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L13
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  shl    $0x3,%edx
  mov    %edx,(%rax)
L13:
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L10
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *rcycle(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] << 3;
    }
  }
  return block;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rcycle>:
  endbr64
  mov    %rdi,%r8
  mov    $0xffffffff,%ecx
  jmp    L20
L25:
  add    $0x1,%ecx
  add    $0x4,%r8
  cmp    $0x3f,%ecx
  je     L30
L20:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L25
  shll   $0x3,(%r8)
  jmp    L25
L30:
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *rcycle(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] << 3;
    }
  }
  return block;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rcycle>:
  endbr64
  mov    %rdi,%r9
  mov    %rdi,%r8
  mov    $0xffffffff,%ecx
  nop
L8:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L7
  shll   $0x3,(%r8)
L7:
  add    $0x1,%ecx
  add    $0x4,%r8
  cmp    $0x3f,%ecx
  jne    L8
  mov    %r9,%rax
  ret
```

assistant: ```c
int *rcycle(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] << 3;
    }
  }
  return block;
}
```
user: What is the c source code of the assembly code below?

```asm
<rcycle>:
  endbr64
  mov    %rdi,%r9
  mov    %rdi,%r8
  mov    $0xffffffff,%ecx
  nop
L14:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L15
  shll   $0x3,(%r8)
L15:
  add    $0x1,%ecx
  add    $0x4,%r8
  cmp    $0x3f,%ecx
  jne    L14
  mov    %r9,%rax
  ret
```

assistant: ```c
int *rcycle(int *block, int n) {
  int i;
  for (i = 0; i < 64; i++) {
    if ((i - 1) % n == 0) {
      block[i] = block[i] << 3;
    }
  }
  return block;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<luaO_int2fb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L19:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  shr    %eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0xf,-0x14(%rbp)
  ja     L19
  cmpl   $0x7,-0x14(%rbp)
  ja     L21
  mov    -0x14(%rbp),%eax
  jmp    L20
L21:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x14(%rbp),%eax
  sub    $0x8,%eax
  or     %edx,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<luaO_int2fb>:
  endbr64
  cmp    $0xf,%edi
  jbe    L9
  mov    $0x0,%edx
L12:
  lea    0x1(%rdi),%eax
  mov    %eax,%edi
  shr    %edi
  add    $0x1,%edx
  cmp    $0x1f,%eax
  ja     L12
L0:
  cmp    $0x7,%edi
  ja     L22
  mov    %edi,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L0
L22:
  lea    0x8(,%rdx,8),%eax
  sub    $0x8,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<luaO_int2fb>:
  endbr64
  mov    %edi,%eax
  xor    %ecx,%ecx
  cmp    $0xf,%edi
  jbe    L3
  nopl   (%rax)
L26:
  lea    0x1(%rax),%edx
  add    $0x1,%ecx
  mov    %edx,%eax
  shr    %eax
  cmp    $0x1f,%edx
  ja     L26
L3:
  cmp    $0x7,%eax
  jbe    L17
  lea    0x8(,%rcx,8),%edx
  sub    $0x8,%eax
  or     %edx,%eax
L17:
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<luaO_int2fb>:
  endbr64
  mov    %edi,%eax
  xor    %ecx,%ecx
  cmp    $0xf,%edi
  jbe    L3
  nopl   (%rax)
L28:
  lea    0x1(%rax),%edx
  add    $0x1,%ecx
  mov    %edx,%eax
  shr    %eax
  cmp    $0x1f,%edx
  ja     L28
L3:
  cmp    $0x7,%eax
  jbe    L11
  lea    0x8(,%rcx,8),%edx
  sub    $0x8,%eax
  or     %edx,%eax
L11:
  ret
```

assistant: ```c
int luaO_int2fb(unsigned int x) {
  int e = 0;
  while (x >= 16) {
    x = (x + 1) >> 1;
    e++;
  }
  if (x < 8)
    return x;
  else
    return ((e + 1) << 3) | (((int)((x))) - 8);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x90(%rbp)
  movl   $0x0,-0x8c(%rbp)
  movl   $0x0,-0x88(%rbp)
  movl   $0x0,-0x84(%rbp)
  movl   $0x0,-0x80(%rbp)
  movl   $0x5,-0xa0(%rbp)
  mov    -0xa0(%rbp),%edx
  lea    -0x90(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_max_consecutive_ones@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x70(%rbp)
  movl   $0x1,-0x6c(%rbp)
  movl   $0x1,-0x68(%rbp)
  movl   $0x1,-0x64(%rbp)
  movl   $0x1,-0x60(%rbp)
  movl   $0x5,-0x9c(%rbp)
  mov    -0x9c(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_max_consecutive_ones@plt>
  cmp    %eax,-0x9c(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x50(%rbp)
  movl   $0x1,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x1,-0x44(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x6,-0x98(%rbp)
  mov    -0x98(%rbp),%edx
  lea    -0x50(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_max_consecutive_ones@plt>
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x7,-0x94(%rbp)
  mov    -0x94(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_max_consecutive_ones@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main() {
  int array0[] = {0, 0, 0, 0, 0};
  int len0 = sizeof(array0) / sizeof(int);
  assert(0 == find_max_consecutive_ones(array0, len0));
  int array1[] = {1, 1, 1, 1, 1};
  int len1 = sizeof(array1) / sizeof(int);
  assert(len1 == find_max_consecutive_ones(array1, len1));
  int array2[] = {1, 1, 0, 1, 1, 1};
  int len2 = sizeof(array2) / sizeof(int);
  assert(3 == find_max_consecutive_ones(array2, len2));
  int array3[] = {1, 0, 1, 0, 1, 0, 1};
  int len3 = sizeof(array3) / sizeof(int);
  assert(1 == find_max_consecutive_ones(array3, len3));
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <find_max_consecutive_ones@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x1,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x1,0x28(%rsp)
  movl   $0x1,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  lea    0x20(%rsp),%rdi
  mov    $0x5,%esi
  call   <find_max_consecutive_ones@plt>
  cmp    $0x5,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x1,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0x0,0x48(%rsp)
  movl   $0x1,0x4c(%rsp)
  movl   $0x1,0x50(%rsp)
  movl   $0x1,0x54(%rsp)
  lea    0x40(%rsp),%rdi
  mov    $0x6,%esi
  call   <find_max_consecutive_ones@plt>
  cmp    $0x3,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x1,0x60(%rsp)
  movl   $0x0,0x64(%rsp)
  movl   $0x1,0x68(%rsp)
  movl   $0x0,0x6c(%rsp)
  movl   $0x1,0x70(%rsp)
  movl   $0x0,0x74(%rsp)
  movl   $0x1,0x78(%rsp)
  lea    0x60(%rsp),%rdi
  mov    $0x7,%esi
  call   <find_max_consecutive_ones@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x98,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array0[] = {0, 0, 0, 0, 0};
  int len0 = sizeof(array0) / sizeof(int);
  assert(0 == find_max_consecutive_ones(array0, len0));
  int array1[] = {1, 1, 1, 1, 1};
  int len1 = sizeof(array1) / sizeof(int);
  assert(len1 == find_max_consecutive_ones(array1, len1));
  int array2[] = {1, 1, 0, 1, 1, 1};
  int len2 = sizeof(array2) / sizeof(int);
  assert(3 == find_max_consecutive_ones(array2, len2));
  int array3[] = {1, 0, 1, 0, 1, 0, 1};
  int len3 = sizeof(array3) / sizeof(int);
  assert(1 == find_max_consecutive_ones(array3, len3));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5,%esi
  movabs $0x100000001,%rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%esi
  lea    0x20(%rsp),%rdi
  mov    %rbx,0x20(%rsp)
  mov    %rbx,0x28(%rsp)
  movl   $0x1,0x30(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x6,%esi
  lea    0x40(%rsp),%rdi
  movabs $0x100000000,%rax
  mov    %rbx,0x40(%rsp)
  mov    %rax,0x48(%rsp)
  mov    %rbx,0x50(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x60(%rsp),%rdi
  mov    $0x7,%esi
  movq   $0x1,0x60(%rsp)
  movq   $0x1,0x68(%rsp)
  movq   $0x1,0x70(%rsp)
  movl   $0x1,0x78(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int array0[] = {0, 0, 0, 0, 0};
  int len0 = sizeof(array0) / sizeof(int);
  assert(0 == find_max_consecutive_ones(array0, len0));
  int array1[] = {1, 1, 1, 1, 1};
  int len1 = sizeof(array1) / sizeof(int);
  assert(len1 == find_max_consecutive_ones(array1, len1));
  int array2[] = {1, 1, 0, 1, 1, 1};
  int len2 = sizeof(array2) / sizeof(int);
  assert(3 == find_max_consecutive_ones(array2, len2));
  int array3[] = {1, 0, 1, 0, 1, 0, 1};
  int len3 = sizeof(array3) / sizeof(int);
  assert(1 == find_max_consecutive_ones(array3, len3));
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x98,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movl   $0x0,0x10(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x5,%esi
  movdqa D15(%rip),%xmm0
  lea    0x20(%rsp),%rdi
  movl   $0x1,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  cmp    $0x5,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x6,%esi
  lea    0x40(%rsp),%rdi
  movdqa D47(%rip),%xmm0
  mov    D15(%rip),%rax
  movaps %xmm0,0x40(%rsp)
  mov    %rax,0x50(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  lea    0x60(%rsp),%rdi
  mov    $0x7,%esi
  movdqa D3(%rip),%xmm0
  mov    D3(%rip),%rax
  movl   $0x1,0x78(%rsp)
  movaps %xmm0,0x60(%rsp)
  mov    %rax,0x70(%rsp)
  call   <find_max_consecutive_ones@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x98,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_infered: byte[16]
name: disassemble_data
arguments: tag: D47
type_infered: byte[16]
name: disassemble_data
arguments: tag: D3
type_infered: byte[16]

tool: {"D15": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D47": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D3": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int array0[] = {0, 0, 0, 0, 0};
  int len0 = sizeof(array0) / sizeof(int);
  assert(0 == find_max_consecutive_ones(array0, len0));
  int array1[] = {1, 1, 1, 1, 1};
  int len1 = sizeof(array1) / sizeof(int);
  assert(len1 == find_max_consecutive_ones(array1, len1));
  int array2[] = {1, 1, 0, 1, 1, 1};
  int len2 = sizeof(array2) / sizeof(int);
  assert(3 == find_max_consecutive_ones(array2, len2));
  int array3[] = {1, 0, 1, 0, 1, 0, 1};
  int len3 = sizeof(array3) / sizeof(int);
  assert(1 == find_max_consecutive_ones(array3, len3));
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<compare_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  comiss %xmm1,%xmm0
  jbe    L28
  mov    $0xffffffff,%eax
  jmp    L19
L28:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  comiss %xmm1,%xmm0
  jbe    L12
  mov    $0x1,%eax
  jmp    L19
L12:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int compare_float(const void *a, const void *b) {
  if (*(float *)a > *(float *)b)
    return -1;
  else if (*(float *)a < *(float *)b)
    return 1;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare_float>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L6
  comiss %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
L6:
  ret
```

assistant: ```c
int compare_float(const void *a, const void *b) {
  if (*(float *)a > *(float *)b)
    return -1;
  else if (*(float *)a < *(float *)b)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_float>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L2
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
L2:
  ret
```

assistant: ```c
int compare_float(const void *a, const void *b) {
  if (*(float *)a > *(float *)b)
    return -1;
  else if (*(float *)a < *(float *)b)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compare_float>:
  endbr64
  movss  (%rdi),%xmm0
  movss  (%rsi),%xmm1
  mov    $0xffffffff,%eax
  comiss %xmm1,%xmm0
  ja     L2
  xor    %eax,%eax
  comiss %xmm0,%xmm1
  seta   %al
L2:
  ret
```

assistant: ```c
int compare_float(const void *a, const void *b) {
  if (*(float *)a > *(float *)b)
    return -1;
  else if (*(float *)a < *(float *)b)
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<matrixMultF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L13:
  mov    -0x2c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L42:
  mov    -0x2c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x28(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x2c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x2c(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L42
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L13
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L45
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixMultF(float *matrixA, float *matrixB, int numRowsA, int numColsA, int numColsB, float *matrixC) {
  int i, j, k;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsB; j++) {
      matrixC[numColsB * i + j] = 0;
      for (k = 0; k < numColsA; k++)
        matrixC[numColsB * i + j] = matrixC[numColsB * i + j] + matrixA[numColsA * i + k] * matrixB[numColsB * k + j];
    }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrixMultF>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x20(%rsp)
  mov    %edx,-0x24(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %edx,%edx
  jle    L25
  mov    %rdi,%rbx
  mov    %ecx,%ebp
  mov    %r8d,%r11d
  movslq %r8d,%rdi
  shl    $0x2,%rdi
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    -0x1(%rcx),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x4(%rbx),%rax
  mov    %rax,-0x8(%rsp)
  jmp    L50
L76:
  movslq %r14d,%rax
  mov    -0x18(%rsp),%rsi
  lea    (%rsi,%rax,4),%r8
  mov    -0x20(%rsp),%r10
  movslq %r15d,%rax
  lea    (%rbx,%rax,4),%r12
  add    -0x10(%rsp),%rax
  mov    -0x8(%rsp),%rsi
  lea    (%rsi,%rax,4),%rsi
  mov    $0x0,%r9d
L32:
  mov    %r8,%rcx
  movl   $0x0,(%r8)
  test   %ebp,%ebp
  jle    L17
  mov    %r10,%rdx
  mov    %r12,%rax
L26:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  addss  (%rcx),%xmm0
  movss  %xmm0,(%rcx)
  add    $0x4,%rax
  add    %rdi,%rdx
  cmp    %rsi,%rax
  jne    L26
L17:
  add    $0x1,%r9d
  add    $0x4,%r8
  add    $0x4,%r10
  cmp    %r9d,%r11d
  jne    L32
L49:
  add    $0x1,%r13d
  add    %r11d,%r14d
  add    %ebp,%r15d
  cmp    %r13d,-0x24(%rsp)
  je     L25
L50:
  test   %r11d,%r11d
  jg     L76
  jmp    L49
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixMultF(float *matrixA, float *matrixB, int numRowsA, int numColsA, int numColsB, float *matrixC) {
  int i, j, k;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsB; j++) {
      matrixC[numColsB * i + j] = 0;
      for (k = 0; k < numColsA; k++)
        matrixC[numColsB * i + j] = matrixC[numColsB * i + j] + matrixA[numColsA * i + k] * matrixB[numColsB * k + j];
    }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<matrixMultF>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x18(%rsp)
  mov    %edx,-0x1c(%rsp)
  test   %edx,%edx
  jle    L56
  mov    %rdi,%rbx
  lea    -0x1(%rcx),%eax
  movslq %r8d,%rdi
  mov    %ecx,%r11d
  mov    %rax,-0x10(%rsp)
  lea    0x4(%rbx),%rax
  mov    %r8d,%r10d
  mov    %r9,%r15
  mov    %rax,-0x8(%rsp)
  shl    $0x2,%rdi
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  pxor   %xmm2,%xmm2
L27:
  test   %r10d,%r10d
  jle    L7
  movslq %r14d,%rax
  mov    -0x8(%rsp),%rsi
  mov    -0x18(%rsp),%r9
  xor    %r8d,%r8d
  lea    (%r15,%rax,4),%rcx
  movslq %r13d,%rax
  lea    (%rbx,%rax,4),%rbp
  add    -0x10(%rsp),%rax
  lea    (%rsi,%rax,4),%rsi
  nopl   0x0(%rax)
L29:
  movl   $0x0,(%rcx)
  mov    %r9,%rdx
  mov    %rbp,%rax
  movaps %xmm2,%xmm1
  test   %r11d,%r11d
  jle    L23
  nopl   0x0(%rax)
L58:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rdi,%rdx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L58
L23:
  add    $0x1,%r8d
  add    $0x4,%rcx
  add    $0x4,%r9
  cmp    %r8d,%r10d
  jne    L29
L7:
  add    $0x1,%r12d
  add    %r11d,%r13d
  add    %r10d,%r14d
  cmp    %r12d,-0x1c(%rsp)
  jne    L27
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixMultF(float *matrixA, float *matrixB, int numRowsA, int numColsA, int numColsB, float *matrixC) {
  int i, j, k;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsB; j++) {
      matrixC[numColsB * i + j] = 0;
      for (k = 0; k < numColsA; k++)
        matrixC[numColsB * i + j] = matrixC[numColsB * i + j] + matrixA[numColsA * i + k] * matrixB[numColsB * k + j];
    }
}
```