ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ccrandom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x18(%rbp),%xmm1
  movsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x425,%eax,%eax
  add    $0x36195,%eax
  cltd
  shr    $0xc,%edx
  add    %edx,%eax
  and    $0xfffff,%eax
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  D10(%rip),%xmm1
  divss  %xmm1,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type_infered: f64
name: extract_symbolic_data
arguments: label: D10
type_infered: byte[4]

tool: D11: 1048576

tool: {"D10": [0x00,0x00,0x80,0x49]}

assistant: ```c
float ccrandom(x)
float x;
{
  int n;
  n = x * 1048576.;
  return ((float)((1061 * n + 221589) % 1048576) / 1048576.);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ccrandom>:
  endbr64
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  imul   $0x425,%eax,%eax
  add    $0x36195,%eax
  cltd
  shr    $0xc,%edx
  add    %edx,%eax
  and    $0xfffff,%eax
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  D0(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
datatype: f64
name: unpack_data
arguments: data_label: D0
datatype: byte[4]

tool: D19: 1048576

tool: {"D0": [0x00,0x00,0x80,0x35]}

assistant: ```c
float ccrandom(x)
float x;
{
  int n;
  n = x * 1048576.;
  return ((float)((1061 * n + 221589) % 1048576) / 1048576.);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ccrandom>:
  endbr64
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D14(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  imul   $0x425,%eax,%eax
  add    $0x36195,%eax
  cltd
  shr    $0xc,%edx
  add    %edx,%eax
  and    $0xfffff,%eax
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm0
  mulss  D12(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
type_infered: f64
name: parse_data
arguments: tag: D12
type_infered: byte[4]

tool: D14: 1048576

tool: {"D12": [0x00,0x00,0x80,0x35]}

assistant: ```c
float ccrandom(x)
float x;
{
  int n;
  n = x * 1048576.;
  return ((float)((1061 * n + 221589) % 1048576) / 1048576.);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ccrandom>:
  endbr64
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  D11(%rip),%xmm0
  cvttsd2si %xmm0,%eax
  pxor   %xmm0,%xmm0
  imul   $0x425,%eax,%eax
  add    $0x36195,%eax
  cltd
  shr    $0xc,%edx
  add    %edx,%eax
  and    $0xfffff,%eax
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm0
  mulss  D13(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: f64
name: extract_symbolic_data
arguments: label: D13
data_type: byte[4]

tool: D11: 1048576

tool: {"D13": [0x00,0x00,0x80,0x35]}

assistant: ```c
float ccrandom(x)
float x;
{
  int n;
  n = x * 1048576.;
  return ((float)((1061 * n + 221589) % 1048576) / 1048576.);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<alignof_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%eax
  pop    %rbp
  ret
```

assistant: ```c
int alignof_float() {
  struct s {
    char x;
    float y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(float)));
}
```
user: What is the c source code of the assembly code below?

```asm
<alignof_float>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int alignof_float() {
  struct s {
    char x;
    float y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(float)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<alignof_float>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int alignof_float() {
  struct s {
    char x;
    float y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(float)));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<alignof_float>:
  endbr64
  mov    $0x4,%eax
  ret
```

assistant: ```c
int alignof_float() {
  struct s {
    char x;
    float y;
  };
  return sizeof(char) + (sizeof(struct s) - (sizeof(char) + sizeof(float)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<__futimes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __futimes(int fd, const struct timeval tvp[2]) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__futimes>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __futimes(int fd, const struct timeval tvp[2]) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__futimes>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __futimes(int fd, const struct timeval tvp[2]) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__futimes>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __futimes(int fd, const struct timeval tvp[2]) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  je     L25
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x3d0900,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x3d0900,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L28
L10:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L23
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  jmp    L38
L23:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L38
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x20(%rbp)
L38:
  addl   $0x1,-0x18(%rbp)
L28:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L10
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quick>
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quick>
  jmp    L43
L25:
  nop
L43:
  leave
  ret
```

assistant: ```c
quick(int *arr, int size) {
  if (size == 0)
    return;
  int pvt = *(arr);
  int *y = malloc(sizeof(int) * 1000000), *z = malloc(sizeof(int) * 1000000);
  int size_y = 0, size_z = 0;
  int i;
  for (i = 1; i < size; i++) {
    if (*(arr + i) > pvt) {
      *(z + size_z) = *(arr + i);
      size_z++;
    } else if (*(arr + i) <= pvt) {
      *(y + size_y) = *(arr + i);
      size_y++;
    }
  }
  quick(y, size_y);
  quick(z, size_z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quick>:
  endbr64
  test   %esi,%esi
  jne    L9
  ret
L9:
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %esi,%ebx
  mov    (%rdi),%ebp
  mov    $0x3d0900,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x3d0900,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  cmp    $0x1,%ebx
  jle    L45
  lea    0x4(%r14),%rax
  lea    -0x2(%rbx),%edx
  lea    0x8(%r14,%rdx,4),%rcx
  mov    $0x0,%ebx
  mov    $0x0,%esi
  jmp    L29
L13:
  movslq %esi,%rdi
  mov    %edx,0x0(%r13,%rdi,4)
  add    $0x1,%esi
L18:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L24
L29:
  mov    (%rax),%edx
  cmp    %ebp,%edx
  jle    L13
  movslq %ebx,%rdi
  mov    %edx,(%r12,%rdi,4)
  add    $0x1,%ebx
  jmp    L18
L45:
  mov    $0x0,%ebx
  mov    $0x0,%esi
L24:
  mov    %r13,%rdi
  call   <quick>
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <quick>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
quick(int *arr, int size) {
  if (size == 0)
    return;
  int pvt = *(arr);
  int *y = malloc(sizeof(int) * 1000000), *z = malloc(sizeof(int) * 1000000);
  int size_y = 0, size_z = 0;
  int i;
  for (i = 1; i < size; i++) {
    if (*(arr + i) > pvt) {
      *(z + size_z) = *(arr + i);
      size_z++;
    } else if (*(arr + i) <= pvt) {
      *(y + size_y) = *(arr + i);
      size_y++;
    }
  }
  quick(y, size_y);
  quick(z, size_z);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quick>:
  endbr64
  test   %esi,%esi
  je     L33
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  nopl   0x0(%rax)
L24:
  mov    $0x3d0900,%edi
  mov    0x0(%rbp),%r13d
  mov    %rbp,%r12
  call   <malloc@plt>
  mov    $0x3d0900,%edi
  mov    %rax,%r14
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    $0x1,%ebx
  jle    L58
  lea    -0x2(%rbx),%edx
  lea    0x4(%r12),%rax
  xor    %ebx,%ebx
  xor    %esi,%esi
  lea    0x8(%r12,%rdx,4),%rcx
  jmp    L28
  nopl   0x0(%rax)
L55:
  movslq %ebx,%rdi
  add    $0x4,%rax
  add    $0x1,%ebx
  mov    %edx,0x0(%rbp,%rdi,4)
  cmp    %rax,%rcx
  je     L31
L28:
  mov    (%rax),%edx
  cmp    %r13d,%edx
  jg     L55
  movslq %esi,%rdi
  add    $0x4,%rax
  add    $0x1,%esi
  mov    %edx,(%r14,%rdi,4)
  cmp    %rax,%rcx
  jne    L28
L31:
  mov    %r14,%rdi
  call   <quick>
  test   %ebx,%ebx
  jne    L24
L58:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
quick(int *arr, int size) {
  if (size == 0)
    return;
  int pvt = *(arr);
  int *y = malloc(sizeof(int) * 1000000), *z = malloc(sizeof(int) * 1000000);
  int size_y = 0, size_z = 0;
  int i;
  for (i = 1; i < size; i++) {
    if (*(arr + i) > pvt) {
      *(z + size_z) = *(arr + i);
      size_z++;
    } else if (*(arr + i) <= pvt) {
      *(y + size_y) = *(arr + i);
      size_y++;
    }
  }
  quick(y, size_y);
  quick(z, size_z);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UWerr_dsum_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  cmpq   $0x0,-0x20(%rbp)
  je     L15
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L38:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L38
L15:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double UWerr_dsum_int(int *v, double *w, int len) {
  int i;
  double s = 0;
  if (v && w)
    for (i = 0; i < len; ++i)
      s += v[i] * w[i];
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UWerr_dsum_int>:
  endbr64
  test   %rdi,%rdi
  je     L21
  test   %rsi,%rsi
  je     L21
  test   %edx,%edx
  jle    L55
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L32:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L32
  jmp    L54
L21:
  pxor   %xmm1,%xmm1
L54:
  movapd %xmm1,%xmm0
  ret
L55:
  pxor   %xmm1,%xmm1
  jmp    L54
```

assistant: ```c
double UWerr_dsum_int(int *v, double *w, int len) {
  int i;
  double s = 0;
  if (v && w)
    for (i = 0; i < len; ++i)
      s += v[i] * w[i];
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<UWerr_dsum_int>:
  endbr64
  test   %rdi,%rdi
  je     L2
  test   %rsi,%rsi
  je     L2
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax,%rax,1)
L31:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L31
  movapd %xmm1,%xmm0
  ret
L2:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double UWerr_dsum_int(int *v, double *w, int len) {
  int i;
  double s = 0;
  if (v && w)
    for (i = 0; i < len; ++i)
      s += v[i] * w[i];
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<UWerr_dsum_int>:
  endbr64
  test   %rdi,%rdi
  je     L31
  test   %rsi,%rsi
  je     L31
  test   %edx,%edx
  jle    L31
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax,%rax,1)
L29:
  pxor   %xmm0,%xmm0
  cvtsi2sdl (%rdi,%rax,4),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L29
  movapd %xmm1,%xmm0
  ret
L31:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double UWerr_dsum_int(int *v, double *w, int len) {
  int i;
  double s = 0;
  if (v && w)
    for (i = 0; i < len; ++i)
      s += v[i] * w[i];
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<turn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <setLeft@plt>
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%edi
  call   <setRight@plt>
  nop
  leave
  ret
```

assistant: ```c
void turn(int pwr) {
  setLeft(pwr);
  setRight(-pwr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<turn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <setLeft@plt>
  neg    %ebx
  mov    %ebx,%edi
  call   <setRight@plt>
  pop    %rbx
  ret
```

assistant: ```c
void turn(int pwr) {
  setLeft(pwr);
  setRight(-pwr);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<turn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  call   <setLeft@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1070 <setRight@plt>
```

assistant: ```c
void turn(int pwr) {
  setLeft(pwr);
  setRight(-pwr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<turn>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  neg    %ebx
  call   <setLeft@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1070 <setRight@plt>
```

assistant: ```c
void turn(int pwr) {
  setLeft(pwr);
  setRight(-pwr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gen_mulx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) unsigned long long gen_mulx(unsigned a, unsigned b) {
  unsigned long long res;
  res = (unsigned long long)a * b;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gen_mulx>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%esi
  imul   %rsi,%rax
  ret
```

assistant: ```c
__attribute__((no)) unsigned long long gen_mulx(unsigned a, unsigned b) {
  unsigned long long res;
  res = (unsigned long long)a * b;
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<gen_mulx>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%esi
  imul   %rsi,%rax
  ret
```

assistant: ```c
__attribute__((no)) unsigned long long gen_mulx(unsigned a, unsigned b) {
  unsigned long long res;
  res = (unsigned long long)a * b;
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_mulx>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%esi
  imul   %rsi,%rax
  ret
```

assistant: ```c
__attribute__((no)) unsigned long long gen_mulx(unsigned a, unsigned b) {
  unsigned long long res;
  res = (unsigned long long)a * b;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copyArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *copyArray(int *a, int n) {
  int *x = (int *)malloc(n * (sizeof(int)));
  int i = 0;
  for (; i < n; i++) {
    x[i] = a[i];
  }
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copyArray>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L4
  mov    %ebp,%ebp
  lea    (%rax,%rbp,4),%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rsi
L16:
  mov    (%rsi,%rdx,1),%ecx
  mov    %ecx,(%rdx)
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L16
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *copyArray(int *a, int n) {
  int *x = (int *)malloc(n * (sizeof(int)));
  int i = 0;
  for (; i < n; i++) {
    x[i] = a[i];
  }
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copyArray>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rbp,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L1
  sub    %rax,%rbx
  lea    (%rax,%rbp,4),%rdi
  mov    %rax,%rdx
  mov    %rbx,%rsi
  nopl   0x0(%rax)
L11:
  mov    (%rsi,%rdx,1),%ecx
  add    $0x4,%rdx
  mov    %ecx,-0x4(%rdx)
  cmp    %rdi,%rdx
  jne    L11
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *copyArray(int *a, int n) {
  int *x = (int *)malloc(n * (sizeof(int)));
  int i = 0;
  for (; i < n; i++) {
    x[i] = a[i];
  }
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<copyArray>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L9
  lea    0x4(%rbp),%rdx
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L15
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L15
  mov    %ebx,%edx
  mov    %rbp,%rcx
  mov    %r8,%rax
  shr    $0x2,%edx
  sub    %r8,%rcx
  shl    $0x4,%rdx
  add    %r8,%rdx
L71:
  movdqu (%rax,%rcx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L71
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L9
  mov    %eax,%ecx
  mov    0x0(%rbp,%rcx,4),%esi
  lea    0x0(,%rcx,4),%rdx
  mov    %esi,(%r8,%rcx,4)
  lea    0x1(%rax),%ecx
  cmp    %ecx,%ebx
  jle    L9
  mov    0x4(%rbp,%rdx,1),%ecx
  add    $0x2,%eax
  mov    %ecx,0x4(%r8,%rdx,1)
  cmp    %eax,%ebx
  jle    L9
  mov    0x8(%rbp,%rdx,1),%eax
  mov    %eax,0x8(%r8,%rdx,1)
L9:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  lea    (%r8,%rbx,4),%rcx
  mov    %r8,%rax
  sub    %r8,%rbp
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x0(%rbp,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L24
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *copyArray(int *a, int n) {
  int *x = (int *)malloc(n * (sizeof(int)));
  int i = 0;
  for (; i < n; i++) {
    x[i] = a[i];
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MA_Calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <MA_Malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  leave
  ret
```

assistant: ```c
void *MA_Calloc(long nr_elems, long bytes_per_elem, const char *r, const char *fn, long ln) {
  long nr_bytes = nr_elems * bytes_per_elem;
  void *p = MA_Malloc(nr_bytes, r, fn, ln);
  return memset(p, 0, nr_bytes);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MA_Calloc>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  mov    %r8,%rcx
  imul   %rdi,%rbx
  mov    %rbx,%rdi
  call   <MA_Malloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *MA_Calloc(long nr_elems, long bytes_per_elem, const char *r, const char *fn, long ln) {
  long nr_bytes = nr_elems * bytes_per_elem;
  void *p = MA_Malloc(nr_bytes, r, fn, ln);
  return memset(p, 0, nr_bytes);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MA_Calloc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  imul   %rdi,%r12
  mov    %r8,%rcx
  mov    %r12,%rdi
  call   <MA_Malloc@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  pop    %r12
  mov    %rax,%rdi
  jmp    1060 <memset@plt>
```

assistant: ```c
void *MA_Calloc(long nr_elems, long bytes_per_elem, const char *r, const char *fn, long ln) {
  long nr_bytes = nr_elems * bytes_per_elem;
  void *p = MA_Malloc(nr_bytes, r, fn, ln);
  return memset(p, 0, nr_bytes);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MA_Calloc>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %rcx,%rdx
  imul   %rdi,%r12
  mov    %r8,%rcx
  mov    %r12,%rdi
  call   <MA_Malloc@plt>
  mov    %r12,%rdx
  xor    %esi,%esi
  pop    %r12
  mov    %rax,%rdi
  jmp    1060 <memset@plt>
```

assistant: ```c
void *MA_Calloc(long nr_elems, long bytes_per_elem, const char *r, const char *fn, long ln) {
  long nr_bytes = nr_elems * bytes_per_elem;
  void *p = MA_Malloc(nr_bytes, r, fn, ln);
  return memset(p, 0, nr_bytes);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xioctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
L13:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L18
  mov    D19(%rip),%rax
  mov    (%rax),%rdx
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L13
L18:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int xioctl(int fd, int request, void *arg) {
  int r;
  do {
    r = ioctl(fd, request, arg);
  } while (-1 == r && EINTR == errno);
  return r;
}
```