ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L32:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x2,%eax
  cmp    $0x12,%eax
  ja     L32
  xor    %r12d,%r12d
  lea    D30(%rip),%rbp
  lea    D28(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L33:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L6
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L33
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D28
type_guessed: string

tool: D12: Inserisci lato tra 2 e 20: 

tool: D14: %d

tool: D30: *

tool: D28: 


assistant: ```c
int main() {
  int n;
  int i;
  int k;
  do {
    printf("Inserisci lato tra 2 e 20: ");
    scanf("%d", &n);
  } while ((n < 2) || (n > 20));
  for (i = 0; i < n; i++) {
    for (k = 0; k < n; k++) {
      printf("*");
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D35(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax)
L9:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x2,%eax
  cmp    $0x12,%eax
  ja     L9
  xor    %r12d,%r12d
  lea    D23(%rip),%rbp
  lea    D0(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L33:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L13
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L33
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D35
type_infered: string
name: parse_data
arguments: data_label: D23
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D9: Inserisci lato tra 2 e 20: 

tool: D35: %d

tool: D23: *

tool: D0: 


assistant: ```c
int main() {
  int n;
  int i;
  int k;
  do {
    printf("Inserisci lato tra 2 e 20: ");
    scanf("%d", &n);
  } while ((n < 2) || (n > 20));
  for (i = 0; i < n; i++) {
    for (k = 0; k < n; k++) {
      printf("*");
    }
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L11
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
L11:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L48
L15:
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L48
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
L48:
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D25
data_type: string
name: parse_data
arguments: data_label: D35
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string
name: parse_data
arguments: data_label: D30
data_type: string

tool: D25: Enter a positive integer: 

tool: D35: %d

tool: D4: ERROR: Out of bounds

tool: D30: The positive integer %d has %d digit(s).

assistant: ```c
int main() {
  int num = 0, digit = 0, temp = 0, done = 0;
  printf("Enter a positive integer: ");
  scanf("%d", &num);
  if (num < 0)
    printf("ERROR: Out of bounds");
  else {
    temp = num;
    while (!done) {
      digit++;
      temp /= 10;
      if (temp == 0)
        done = !done;
    }
    printf("The positive integer %d has %d digit(s).", num, digit);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%edx
  mov    $0x0,%ecx
  test   %esi,%esi
  js     L28
L18:
  add    $0x1,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  jne    L18
  mov    %ecx,%edx
  lea    D39(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L28:
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L26
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D21
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D39
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string

tool: D21: Enter a positive integer: 

tool: D12: %d

tool: D39: The positive integer %d has %d digit(s).

tool: D7: ERROR: Out of bounds

assistant: ```c
int main() {
  int num = 0, digit = 0, temp = 0, done = 0;
  printf("Enter a positive integer: ");
  scanf("%d", &num);
  if (num < 0)
    printf("ERROR: Out of bounds");
  else {
    temp = num;
    while (!done) {
      digit++;
      temp /= 10;
      if (temp == 0)
        done = !done;
    }
    printf("The positive integer %d has %d digit(s).", num, digit);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D33(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %edx,%edx
  mov    $0xcccccccd,%ecx
  mov    %esi,%eax
  test   %esi,%esi
  js     L39
  xchg   %ax,%ax
L6:
  mov    %eax,%eax
  add    $0x1,%edx
  imul   %rcx,%rax
  shr    $0x23,%rax
  test   %eax,%eax
  jne    L6
  lea    D10(%rip),%rdi
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L39:
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D33
type: string
name: parse_data
arguments: data_label: D12
type: string
name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D30
type: string

tool: D33: Enter a positive integer: 

tool: D12: %d

tool: D10: The positive integer %d has %d digit(s).

tool: D30: ERROR: Out of bounds

assistant: ```c
int main() {
  int num = 0, digit = 0, temp = 0, done = 0;
  printf("Enter a positive integer: ");
  scanf("%d", &num);
  if (num < 0)
    printf("ERROR: Out of bounds");
  else {
    temp = num;
    while (!done) {
      digit++;
      temp /= 10;
      if (temp == 0)
        done = !done;
    }
    printf("The positive integer %d has %d digit(s).", num, digit);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %edx,%edx
  mov    $0xcccccccd,%ecx
  mov    %esi,%eax
  test   %esi,%esi
  js     L0
  xchg   %ax,%ax
L25:
  mov    %eax,%eax
  add    $0x1,%edx
  imul   %rcx,%rax
  shr    $0x23,%rax
  test   %eax,%eax
  jne    L25
  lea    D11(%rip),%rdi
  call   <printf@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D11
type_guessed: string
name: unpack_data
arguments: tag: D33
type_guessed: string

tool: D25: Enter a positive integer: 

tool: D6: %d

tool: D11: The positive integer %d has %d digit(s).

tool: D33: ERROR: Out of bounds

assistant: ```c
int main() {
  int num = 0, digit = 0, temp = 0, done = 0;
  printf("Enter a positive integer: ");
  scanf("%d", &num);
  if (num < 0)
    printf("ERROR: Out of bounds");
  else {
    temp = num;
    while (!done) {
      digit++;
      temp /= 10;
      if (temp == 0)
        done = !done;
    }
    printf("The positive integer %d has %d digit(s).", num, digit);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__wrap_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb8(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <dll_vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __wrap_printf(const char *format, ...) {
  int res;
  va_list va;
  va_start(va, format);
  res = dll_vfprintf(stdout, format, va);
  va_end(va);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__wrap_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <dll_vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int __wrap_printf(const char *format, ...) {
  int res;
  va_list va;
  va_start(va, format);
  res = dll_vfprintf(stdout, format, va);
  va_end(va);
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<__wrap_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <dll_vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __wrap_printf(const char *format, ...) {
  int res;
  va_list va;
  va_start(va, format);
  res = dll_vfprintf(stdout, format, va);
  va_end(va);
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__wrap_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <dll_vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int __wrap_printf(const char *format, ...) {
  int res;
  va_list va;
  va_start(va, format);
  res = dll_vfprintf(stdout, format, va);
  va_end(va);
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yyLineAtPos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
yyLineAtPos(pos) long pos;
{
  long l;
  l = pos / 1000L;
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<yyLineAtPos>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x7,%rdx
  sar    $0x3f,%rdi
  mov    %edx,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
yyLineAtPos(pos) long pos;
{
  long l;
  l = pos / 1000L;
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yyLineAtPos>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rdi
  imul   %rdx
  sar    $0x7,%rdx
  mov    %edx,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
yyLineAtPos(pos) long pos;
{
  long l;
  l = pos / 1000L;
  return l;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yyLineAtPos>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rdi
  imul   %rdx
  sar    $0x7,%rdx
  mov    %edx,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
yyLineAtPos(pos) long pos;
{
  long l;
  l = pos / 1000L;
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<TGM_TrimSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L19
L4:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L89
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L89
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L99
L89:
  addq   $0x1,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L4
L99:
  movl   $0x0,-0x1c(%rbp)
  jmp    L117
L109:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L41
L38:
  subq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x1c(%rbp)
L117:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L109
L41:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L67
  mov    $0x0,%eax
  jmp    L70
L67:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
L70:
  leave
  ret
```

assistant: ```c
unsigned int TGM_TrimSpaces(char *str) {
  int length = strlen(str);
  const char *start = str;
  const char *end = str + length - 1;
  int count = 0;
  while (count != length) {
    if (*start == ' ' || *start == '\t' || *start == '\n')
      ++start;
    else
      break;
    ++count;
  }
  count = 0;
  while (count != length) {
    if (*end == ' ' || *end == '\t' || *end == '\n')
      --end;
    else
      break;
    ++count;
  }
  if (end <= start)
    return 0;
  unsigned strLen = end - start + 1;
  memmove(str, start, strLen);
  str[strLen] = '\0';
  return strLen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TGM_TrimSpaces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  test   %eax,%eax
  je     L83
  lea    -0x1(%rax),%r8d
  mov    %eax,%eax
  lea    (%rbx,%rax,1),%rdi
  mov    %rbx,%rsi
  jmp    L32
L52:
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  je     L58
L32:
  movzbl (%rsi),%eax
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L52
  cmp    $0x20,%al
  je     L52
L58:
  mov    %r8,%rdi
  not    %rdi
  add    %rdx,%rdi
  jmp    L69
L10:
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L3
L69:
  movzbl (%rdx),%eax
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L10
  cmp    $0x20,%al
  je     L10
  mov    %rdx,%rdi
L3:
  mov    $0x0,%ebp
  cmp    %rsi,%rdi
  ja     L119
L5:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L83:
  mov    %rbx,%rsi
  mov    %rdx,%rdi
  jmp    L3
L119:
  sub    %rsi,%rdi
  lea    0x1(%rdi),%ebp
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <memmove@plt>
  mov    %ebp,%eax
  movb   $0x0,(%rbx,%rax,1)
  jmp    L5
```

assistant: ```c
unsigned int TGM_TrimSpaces(char *str) {
  int length = strlen(str);
  const char *start = str;
  const char *end = str + length - 1;
  int count = 0;
  while (count != length) {
    if (*start == ' ' || *start == '\t' || *start == '\n')
      ++start;
    else
      break;
    ++count;
  }
  count = 0;
  while (count != length) {
    if (*end == ' ' || *end == '\t' || *end == '\n')
      --end;
    else
      break;
    ++count;
  }
  if (end <= start)
    return 0;
  unsigned strLen = end - start + 1;
  memmove(str, start, strLen);
  str[strLen] = '\0';
  return strLen;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TGM_TrimSpaces>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  test   %eax,%eax
  je     L43
  mov    %eax,%esi
  lea    -0x1(%rax),%r8d
  mov    %rbx,%rax
  add    %rbx,%rsi
  nop
L15:
  movzbl (%rax),%ecx
  lea    -0x9(%rcx),%edi
  cmp    $0x1,%dil
  jbe    L20
  cmp    $0x20,%cl
  jne    L95
L20:
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L15
L19:
  mov    %r8,%rdi
  not    %rdi
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L93:
  movzbl (%rdx),%eax
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L2
  cmp    $0x20,%al
  jne    L26
L2:
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L93
L85:
  xor    %r12d,%r12d
  cmp    %rsi,%rdi
  jbe    L22
  sub    %rsi,%rdi
  lea    0x1(%rdi),%r12d
  mov    %rbx,%rdi
  mov    %r12d,%edx
  call   <memmove@plt>
  mov    %r12d,%eax
  movb   $0x0,(%rbx,%rax,1)
L22:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  mov    %rdx,%rdi
  jmp    L85
  nopl   (%rax)
L95:
  mov    %rax,%rsi
  jmp    L19
L43:
  mov    %rbx,%rsi
  mov    %rdx,%rdi
  jmp    L85
```

assistant: ```c
unsigned int TGM_TrimSpaces(char *str) {
  int length = strlen(str);
  const char *start = str;
  const char *end = str + length - 1;
  int count = 0;
  while (count != length) {
    if (*start == ' ' || *start == '\t' || *start == '\n')
      ++start;
    else
      break;
    ++count;
  }
  count = 0;
  while (count != length) {
    if (*end == ' ' || *end == '\t' || *end == '\n')
      --end;
    else
      break;
    ++count;
  }
  if (end <= start)
    return 0;
  unsigned strLen = end - start + 1;
  memmove(str, start, strLen);
  str[strLen] = '\0';
  return strLen;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TGM_TrimSpaces>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  test   %eax,%eax
  je     L78
  mov    %eax,%esi
  lea    -0x1(%rax),%r8d
  mov    %rbx,%rax
  add    %rbx,%rsi
  nop
L103:
  movzbl (%rax),%ecx
  lea    -0x9(%rcx),%edi
  cmp    $0x1,%dil
  jbe    L61
  cmp    $0x20,%cl
  jne    L3
L61:
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L103
L13:
  mov    %r8,%rdi
  not    %rdi
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L60:
  movzbl (%rdx),%eax
  lea    -0x9(%rax),%ecx
  cmp    $0x1,%cl
  jbe    L38
  cmp    $0x20,%al
  jne    L76
L38:
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L60
L14:
  xor    %r12d,%r12d
  cmp    %rsi,%rdi
  jbe    L84
  sub    %rsi,%rdi
  lea    0x1(%rdi),%r12d
  mov    %rbx,%rdi
  mov    %r12d,%edx
  call   <memmove@plt>
  mov    %r12d,%eax
  movb   $0x0,(%rbx,%rax,1)
L84:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L76:
  mov    %rdx,%rdi
  jmp    L14
  nopl   (%rax)
L3:
  mov    %rax,%rsi
  jmp    L13
L78:
  mov    %rbx,%rsi
  mov    %rdx,%rdi
  jmp    L14
```

assistant: ```c
unsigned int TGM_TrimSpaces(char *str) {
  int length = strlen(str);
  const char *start = str;
  const char *end = str + length - 1;
  int count = 0;
  while (count != length) {
    if (*start == ' ' || *start == '\t' || *start == '\n')
      ++start;
    else
      break;
    ++count;
  }
  count = 0;
  while (count != length) {
    if (*end == ' ' || *end == '\t' || *end == '\n')
      --end;
    else
      break;
    ++count;
  }
  if (end <= start)
    return 0;
  unsigned strLen = end - start + 1;
  memmove(str, start, strLen);
  str[strLen] = '\0';
  return strLen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exit1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x17,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <nocrmode@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void exit1() {
  move(23, 0);
  refresh();
  nocrmode();
  endwin();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exit1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x17,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  mov    $0x0,%eax
  call   <nocrmode@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void exit1() {
  move(23, 0);
  refresh();
  nocrmode();
  endwin();
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exit1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17,%edi
  xor    %esi,%esi
  call   <move@plt>
  xor    %eax,%eax
  call   <refresh@plt>
  xor    %eax,%eax
  call   <nocrmode@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10c0 <exit@plt>
```

assistant: ```c
void exit1() {
  move(23, 0);
  refresh();
  nocrmode();
  endwin();
  exit(0);
}
```