user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fe_mu_at>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %ecx,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L7
L13:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <ceil@plt>
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <mini@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <maxi@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%ebx
  movsd  -0x18(%rbp),%xmm0
  movsd  D13(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <ceil@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <mini@plt>
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <maxi@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x20(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D27(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <hat@plt>
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x3,%rax
  lea    -0x10(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x3,%rax
  lea    -0x10(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x24(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x1c(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D13(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <hat@plt>
  mov    -0x28(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x28(%rbp)
L7:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x28(%rbp)
  jl     L13
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
data_type: f64
name: parse_data
arguments: data_tag: D27
data_type: byte[8]

tool: D13: 0.5

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void fe_mu_at(double *mu, double *y, int N, int L) {
  int n = 1 << (L - 1);
  int t;
  int i, j;
  double yn;
  for (t = 0; t < N - 1; t++) {
    yn = y[t] * (double)n;
    i = maxi(mini(((int)ceil(yn)), n), 1);
    j = maxi(mini(((int)ceil(yn - 0.5)), n - 1), 1);
    mu[2 * i - 2] += hat(y[t] * n - i + 1) * (y[t + 1] - y[t]);
    mu[2 * j - 1] += hat(y[t] * n - j + .5) * (y[t + 1] - y[t]);
  }
}
```