ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isprime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  js     L38
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movq   %xmm1,%rax
  jmp    L61
L38:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  movq   %xmm0,%rax
L61:
  movq   %rax,%xmm0
  call   <sqrt@plt>
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L13
  mov    -0x28(%rbp),%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  mov    %rax,%rdx
  add    %rdx,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L80
L13:
  mov    $0x0,%eax
  jmp    L82
L80:
  movq   $0x5,-0x10(%rbp)
  movq   $0x5,-0x18(%rbp)
  jmp    L67
L46:
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  jmp    L82
L8:
  cmpq   $0x1,-0x10(%rbp)
  jne    L7
  addq   $0x4,-0x18(%rbp)
  jmp    L91
L7:
  addq   $0x2,-0x18(%rbp)
L91:
  mov    -0x18(%rbp),%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x2,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,-0x10(%rbp)
L67:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L46
  mov    $0x1,%eax
L82:
  leave
  ret
```

assistant: ```c
int isprime(unsigned long int n) {
  unsigned long int sqrt_n, i, residue;
  sqrt_n = (unsigned long int)sqrt((double)n) + 1;
  if ((n & 0x1) == 0 || n % 3 == 0)
    return 0;
  residue = 5;
  for (i = 5; i <= sqrt_n;) {
    if (n % i == 0)
      return 0;
    if (residue == 1)
      i += 4;
    else
      i += 2;
    residue = i % 6;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isprime>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  js     L27
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L82:
  call   <sqrt@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   $0x1,%bl
  je     L68
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rbx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    %rax
  and    $0xfffffffffffffffe,%rdx
  add    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%rbx
  je     L68
  add    $0x1,%rdi
  cmp    $0x4,%rdi
  jbe    L109
  movabs $0xcccccccccccccccd,%rdx
  mov    %rbx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rbx
  je     L7
  mov    $0x5,%esi
  mov    $0x5,%ecx
  movabs $0xaaaaaaaaaaaaaaab,%r8
L66:
  lea    0x4(%rcx),%rax
  add    $0x2,%rcx
  cmp    $0x1,%rsi
  cmove  %rax,%rcx
  mov    %rcx,%rax
  mul    %r8
  mov    %rdx,%rsi
  shr    $0x2,%rsi
  lea    (%rsi,%rsi,2),%rdx
  add    %rdx,%rdx
  mov    %rcx,%rsi
  sub    %rdx,%rsi
  cmp    %rdi,%rcx
  ja     L38
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  test   %rdx,%rdx
  jne    L66
  mov    $0x0,%eax
  jmp    L68
L27:
  mov    %rdi,%rax
  shr    %rax
  mov    %rdi,%rdx
  and    $0x1,%edx
  or     %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L82
L38:
  mov    $0x1,%eax
L68:
  pop    %rbx
  ret
L109:
  mov    $0x1,%eax
  jmp    L68
L7:
  mov    $0x0,%eax
  jmp    L68
```

assistant: ```c
int isprime(unsigned long int n) {
  unsigned long int sqrt_n, i, residue;
  sqrt_n = (unsigned long int)sqrt((double)n) + 1;
  if ((n & 0x1) == 0 || n % 3 == 0)
    return 0;
  residue = 5;
  for (i = 5; i <= sqrt_n;) {
    if (n % i == 0)
      return 0;
    if (residue == 1)
      i += 4;
    else
      i += 2;
    residue = i % 6;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isprime>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  js     L42
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L37:
  call   <sqrt@plt>
  xor    %r9d,%r9d
  test   $0x1,%bl
  je     L60
  movabs $0xaaaaaaaaaaaaaaab,%r8
  mov    %rbx,%rcx
  movabs $0x5555555555555555,%rdx
  imul   %r8,%rcx
  cmp    %rdx,%rcx
  jbe    L60
  lea    0x1(%rax),%rdi
  cmp    $0x4,%rdi
  jbe    L34
  movabs $0xcccccccccccccccd,%rax
  movabs $0x3333333333333333,%rdx
  imul   %rbx,%rax
  cmp    %rdx,%rax
  jbe    L60
  mov    $0x5,%esi
  mov    $0x5,%ecx
  jmp    L17
  xchg   %ax,%ax
L50:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rcx
  test   %rdx,%rdx
  je     L23
L17:
  lea    0x4(%rcx),%rax
  add    $0x2,%rcx
  cmp    $0x1,%rsi
  cmove  %rax,%rcx
  mov    %rcx,%rax
  mul    %r8
  mov    %rdx,%rsi
  shr    $0x2,%rsi
  lea    (%rsi,%rsi,2),%rdx
  mov    %rcx,%rsi
  add    %rdx,%rdx
  sub    %rdx,%rsi
  cmp    %rdi,%rcx
  jbe    L50
L34:
  mov    $0x1,%r9d
L60:
  mov    %r9d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %rdi,%rax
  mov    %rdi,%rdx
  pxor   %xmm0,%xmm0
  shr    %rax
  and    $0x1,%edx
  or     %rdx,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L37
  nopl   0x0(%rax)
L23:
  xor    %r9d,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
```

assistant: ```c
int isprime(unsigned long int n) {
  unsigned long int sqrt_n, i, residue;
  sqrt_n = (unsigned long int)sqrt((double)n) + 1;
  if ((n & 0x1) == 0 || n % 3 == 0)
    return 0;
  residue = 5;
  for (i = 5; i <= sqrt_n;) {
    if (n % i == 0)
      return 0;
    if (residue == 1)
      i += 4;
    else
      i += 2;
    residue = i % 6;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isprime>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  js     L50
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
L13:
  call   <sqrt@plt>
  xor    %r9d,%r9d
  test   $0x1,%bl
  je     L20
  movabs $0xaaaaaaaaaaaaaaab,%r8
  mov    %rbx,%rcx
  movabs $0x5555555555555555,%rdx
  imul   %r8,%rcx
  cmp    %rdx,%rcx
  jbe    L20
  lea    0x1(%rax),%rdi
  cmp    $0x4,%rdi
  jbe    L9
  movabs $0xcccccccccccccccd,%rax
  movabs $0x3333333333333333,%rdx
  imul   %rbx,%rax
  cmp    %rdx,%rax
  jbe    L20
  mov    $0x5,%esi
  mov    $0x5,%ecx
  jmp    L8
  xchg   %ax,%ax
L72:
  mov    %rbx,%rax
  xor    %edx,%edx
  div    %rcx
  test   %rdx,%rdx
  je     L44
L8:
  lea    0x4(%rcx),%rax
  add    $0x2,%rcx
  cmp    $0x1,%rsi
  cmove  %rax,%rcx
  mov    %rcx,%rax
  mul    %r8
  mov    %rdx,%rsi
  shr    $0x2,%rsi
  lea    (%rsi,%rsi,2),%rdx
  mov    %rcx,%rsi
  add    %rdx,%rdx
  sub    %rdx,%rsi
  cmp    %rdi,%rcx
  jbe    L72
L9:
  mov    $0x1,%r9d
L20:
  mov    %r9d,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %rdi,%rax
  mov    %rdi,%rdx
  pxor   %xmm0,%xmm0
  shr    %rax
  and    $0x1,%edx
  or     %rdx,%rax
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L13
  nopl   0x0(%rax)
L44:
  xor    %r9d,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
```

assistant: ```c
int isprime(unsigned long int n) {
  unsigned long int sqrt_n, i, residue;
  sqrt_n = (unsigned long int)sqrt((double)n) + 1;
  if ((n & 0x1) == 0 || n % 3 == 0)
    return 0;
  residue = 5;
  for (i = 5; i <= sqrt_n;) {
    if (n % i == 0)
      return 0;
    if (residue == 1)
      i += 4;
    else
      i += 2;
    residue = i % 6;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%esi
  mov    $0x2a,%edi
  call   <max@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  max(42, 3);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2a,%edi
  call   <max@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  max(42, 3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2a,%edi
  call   <max@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  max(42, 3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%esi
  mov    $0x2a,%edi
  call   <max@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  max(42, 3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<umf4zsnum_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %rdx,-0xe8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xe0(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xd0(%rbp),%rdx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <make_filename@plt>
  mov    -0xd8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xd0(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <umfpack_zi_save_numeric@plt>
  mov    -0xe8(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: n

assistant: ```c
void umf4zsnum_(void **Numeric, long *filenum, long *status) {
  char filename[200];
  make_filename(*filenum, "n", filename);
  *status = umfpack_zi_save_numeric(*Numeric, filename);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<umf4zsnum_>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rax
  mov    %rdx,%rbx
  mov    %fs:0x28,%rdx
  mov    %rdx,0xc8(%rsp)
  xor    %edx,%edx
  mov    %rsp,%rbp
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  mov    (%rax),%rdi
  call   <make_filename@plt>
  mov    %rbp,%rsi
  mov    (%r12),%rdi
  call   <umfpack_zi_save_numeric@plt>
  mov    %rax,(%rbx)
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: n

assistant: ```c
void umf4zsnum_(void **Numeric, long *filenum, long *status) {
  char filename[200];
  make_filename(*filenum, "n", filename);
  *status = umfpack_zi_save_numeric(*Numeric, filename);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<umf4zsnum_>:
  endbr64
  push   %r12
  mov    %rsi,%r8
  lea    D0(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0xd0,%rsp
  mov    (%r8),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdx
  call   <make_filename@plt>
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  call   <umfpack_zi_save_numeric@plt>
  mov    %rax,(%rbx)
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: n

assistant: ```c
void umf4zsnum_(void **Numeric, long *filenum, long *status) {
  char filename[200];
  make_filename(*filenum, "n", filename);
  *status = umfpack_zi_save_numeric(*Numeric, filename);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<umf4zsnum_>:
  endbr64
  push   %r12
  mov    %rsi,%r8
  lea    D6(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0xd0,%rsp
  mov    (%r8),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdx
  call   <make_filename@plt>
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  call   <umfpack_zi_save_numeric@plt>
  mov    %rax,(%rbx)
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6: n

assistant: ```c
void umf4zsnum_(void **Numeric, long *filenum, long *status) {
  char filename[200];
  make_filename(*filenum, "n", filename);
  *status = umfpack_zi_save_numeric(*Numeric, filename);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_tab_rm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x8000,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L7
L42:
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L23
  mov    $0x0,%eax
  jmp    L7
L23:
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L43
  mov    $0x0,%eax
  jmp    L7
L43:
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  lea    D13(%rip),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string
name: read_data
arguments: data_label: D13
type: string

tool: D3: rm

tool: D13:  

assistant: ```c
char **init_tab_rm() {
  char **tab5;
  if ((tab5 = malloc(sizeof(char *) * 4096)) == NULL)
    return (0);
  if ((tab5[0] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[0] = "rm";
  if ((tab5[1] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[1] = " ";
  return (tab5);
}
```
user: What is the c source code of the assembly code below:

```asm
<init_tab_rm>:
  endbr64
  push   %rbx
  mov    $0x8000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    $0x1000,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L20
  lea    D10(%rip),%rax
  mov    %rax,(%rbx)
  mov    $0x1000,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L30
  lea    D17(%rip),%rax
  mov    %rax,0x8(%rbx)
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
L20:
  movq   $0x0,(%rbx)
  mov    %rax,%rbx
  jmp    L5
L30:
  movq   $0x0,0x8(%rbx)
  mov    %rax,%rbx
  jmp    L5
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D17
type: string

tool: D10: rm

tool: D17:  

assistant: ```c
char **init_tab_rm() {
  char **tab5;
  if ((tab5 = malloc(sizeof(char *) * 4096)) == NULL)
    return (0);
  if ((tab5[0] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[0] = "rm";
  if ((tab5[1] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[1] = " ";
  return (tab5);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_tab_rm>:
  endbr64
  push   %r12
  mov    $0x8000,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L19
  mov    $0x1000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  test   %rax,%rax
  je     L36
  lea    D2(%rip),%rax
  mov    $0x1000,%edi
  mov    %rax,(%r12)
  call   <malloc@plt>
  test   %rax,%rax
  je     L4
  lea    D16(%rip),%rax
  mov    %rax,0x8(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  movq   $0x0,(%r12)
L19:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L4:
  movq   $0x0,0x8(%r12)
  jmp    L19
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D16
datatype: string

tool: D2: rm

tool: D16:  

assistant: ```c
char **init_tab_rm() {
  char **tab5;
  if ((tab5 = malloc(sizeof(char *) * 4096)) == NULL)
    return (0);
  if ((tab5[0] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[0] = "rm";
  if ((tab5[1] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[1] = " ";
  return (tab5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_tab_rm>:
  endbr64
  push   %r12
  mov    $0x8000,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1000,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  test   %rax,%rax
  je     L11
  lea    D10(%rip),%rax
  mov    $0x1000,%edi
  mov    %rax,(%r12)
  call   <malloc@plt>
  test   %rax,%rax
  je     L38
  lea    D7(%rip),%rax
  mov    %rax,0x8(%r12)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movq   $0x0,(%r12)
L7:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L38:
  movq   $0x0,0x8(%r12)
  jmp    L7
```

tool_calls: name: read_data
arguments: label: D10
type: string
name: read_data
arguments: label: D7
type: string

tool: D10: rm

tool: D7:  

assistant: ```c
char **init_tab_rm() {
  char **tab5;
  if ((tab5 = malloc(sizeof(char *) * 4096)) == NULL)
    return (0);
  if ((tab5[0] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[0] = "rm";
  if ((tab5[1] = malloc(sizeof(char) * 4096)) == NULL)
    return (0);
  tab5[1] = " ";
  return (tab5);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L29:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L22
  mov    D0(%rip),%rax
  mov    (%rax),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L34
  mov    $0xffffffff,%eax
  jmp    L7
L22:
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  jmp    L9
L34:
  nop
L9:
  cmpq   $0x0,-0x10(%rbp)
  jne    L29
  mov    -0x38(%rbp),%rax
L7:
  leave
  ret
```

assistant: ```c
ssize_t write_all(int fd, const void *buf, size_t n) {
  size_t left = n;
  const char *ptr = buf;
  do {
    int res;
    res = write(fd, ptr, left);
    if (res == -1) {
      if (errno == EINTR)
        continue;
      return -1;
    }
    left -= res;
    ptr += res;
  } while (left != 0);
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rdx,%rbx
  jmp    L15
L7:
  cltq
  sub    %rax,%rbx
  add    %rax,%rbp
L41:
  test   %rbx,%rbx
  je     L44
L15:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  mov    D8(%rip),%rcx
  mov    D7(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L41
  jmp    L49
L44:
  mov    %r13d,%eax
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_all(int fd, const void *buf, size_t n) {
  size_t left = n;
  const char *ptr = buf;
  do {
    int res;
    res = write(fd, ptr, left);
    if (res == -1) {
      if (errno == EINTR)
        continue;
      return -1;
    }
    left -= res;
    ptr += res;
  } while (left != 0);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<write_all>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L18:
  cltq
  sub    %rax,%rbx
  add    %rax,%r13
L21:
  test   %rbx,%rbx
  je     L16
L12:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L18
  mov    D14(%rip),%rdx
  mov    D1(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L21
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_all(int fd, const void *buf, size_t n) {
  size_t left = n;
  const char *ptr = buf;
  do {
    int res;
    res = write(fd, ptr, left);
    if (res == -1) {
      if (errno == EINTR)
        continue;
      return -1;
    }
    left -= res;
    ptr += res;
  } while (left != 0);
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_all>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L0:
  cltq
  sub    %rax,%rbx
  add    %rax,%r13
L37:
  test   %rbx,%rbx
  je     L38
L3:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L0
  mov    D0(%rip),%rdx
  mov    D12(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L37
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_all(int fd, const void *buf, size_t n) {
  size_t left = n;
  const char *ptr = buf;
  do {
    int res;
    res = write(fd, ptr, left);
    if (res == -1) {
      if (errno == EINTR)
        continue;
      return -1;
    }
    left -= res;
    ptr += res;
  } while (left != 0);
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  cmpl   $0xffff,-0x14(%rbp)
  jle    L24
  subl   $0x10,-0x4(%rbp)
  sarl   $0x10,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  and    $0xff00,%eax
  test   %eax,%eax
  je     L1
  subl   $0x8,-0x4(%rbp)
  sarl   $0x8,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  and    $0xf0,%eax
  test   %eax,%eax
  je     L23
  subl   $0x4,-0x4(%rbp)
  sarl   $0x4,-0x14(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    %edx,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: 

assistant: ```c
uint8_t clz(uint32_t x) {
  static const uint8_t bval[] = {0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4};
  unsigned int r = 32;
  if (x >= 0x10000) {
    r -= 16;
    x >>= 16;
  }
  if (x & 0xFF00) {
    r -= 8;
    x >>= 8;
  }
  if (x & 0xF0) {
    r -= 4;
    x >>= 4;
  }
  return r - bval[x];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<clz>:
  endbr64
  mov    $0x20,%eax
  cmp    $0xffff,%edi
  jle    L24
  sar    $0x10,%edi
  mov    $0x10,%eax
L24:
  test   $0xff00,%edi
  je     L12
  sub    $0x8,%eax
  sar    $0x8,%edi
L12:
  test   $0xf0,%dil
  je     L6
  sub    $0x4,%eax
  sar    $0x4,%edi
L6:
  movslq %edi,%rdi
  lea    D1(%rip),%rdx
  sub    (%rdx,%rdi,4),%eax
  ret
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: 

assistant: ```c
uint8_t clz(uint32_t x) {
  static const uint8_t bval[] = {0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4};
  unsigned int r = 32;
  if (x >= 0x10000) {
    r -= 16;
    x >>= 16;
  }
  if (x & 0xFF00) {
    r -= 8;
    x >>= 8;
  }
  if (x & 0xF0) {
    r -= 4;
    x >>= 4;
  }
  return r - bval[x];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clz>:
  endbr64
  mov    $0x20,%eax
  cmp    $0xffff,%edi
  jle    L26
  sar    $0x10,%edi
  mov    $0x10,%eax
L26:
  test   $0xff00,%edi
  je     L27
  sub    $0x8,%eax
  sar    $0x8,%edi
L27:
  test   $0xf0,%dil
  je     L7
  sub    $0x4,%eax
  sar    $0x4,%edi
L7:
  movslq %edi,%rdi
  lea    D0(%rip),%rdx
  sub    (%rdx,%rdi,4),%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: 

assistant: ```c
uint8_t clz(uint32_t x) {
  static const uint8_t bval[] = {0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4};
  unsigned int r = 32;
  if (x >= 0x10000) {
    r -= 16;
    x >>= 16;
  }
  if (x & 0xFF00) {
    r -= 8;
    x >>= 8;
  }
  if (x & 0xF0) {
    r -= 4;
    x >>= 4;
  }
  return r - bval[x];
}
```