user: What would the C source look like for the assembly code provided here:

```asm
<question_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x64,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%ecx
  mov    $0x0,%edx
  div    %rcx
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L36:
  cmp    %rdx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L23:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L21
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L21:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insere_lista_auto@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mostra_lista@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cont_elemt_par@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cont_elemt_impar@plt>
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <media_maior_50@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x2c(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x2c(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bubblesort_inverso@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mostra_lista@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D34
type: string
name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D3
type: string
name: retrieve_data
arguments: tag: D17
type: string

tool: D29: 
------------- Questao 1 -------------

tool: D34: Lista incial:

tool: D9: par: %d
impar: %d


tool: D3: media: %.2f



tool: D17: lista ordenada: 

assistant: ```c
void question_one() {
  int tam_vetor = 100;
  int vetor[tam_vetor];
  printf("\n------------- Questao 1 -------------\n");
  insere_lista_auto(vetor, tam_vetor);
  printf("Lista incial:\n");
  mostra_lista(vetor, tam_vetor);
  int numPar = cont_elemt_par(vetor, tam_vetor);
  int numImpar = cont_elemt_impar(vetor, tam_vetor);
  printf("par: %d\nimpar: %d\n", numPar, numImpar);
  float media = media_maior_50(vetor, tam_vetor);
  printf("media: %.2f\n\n", media);
  bubblesort_inverso(vetor, tam_vetor);
  printf("lista ordenada: \n");
  mostra_lista(vetor, tam_vetor);
}
```