ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wmemcpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x0(,%rbx,4),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
wchar_t *wmemcpy(wchar_t *d, const wchar_t *s, size_t n) {
  assert(d != NULL);
  assert(s != NULL);
  return (wchar_t *)memcpy(d, s, n * sizeof(wchar_t));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wmemcpy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  test   %rbp,%rbp
  mov    %rdx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  lea    0x0(,%rbx,4),%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <memcpy@plt>
```

assistant: ```c
wchar_t *wmemcpy(wchar_t *d, const wchar_t *s, size_t n) {
  assert(d != NULL);
  assert(s != NULL);
  return (wchar_t *)memcpy(d, s, n * sizeof(wchar_t));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wmemcpy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  test   %rbp,%rbp
  mov    %rdx,%rbx
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  lea    0x0(,%rbx,4),%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <memcpy@plt>
```

assistant: ```c
wchar_t *wmemcpy(wchar_t *d, const wchar_t *s, size_t n) {
  assert(d != NULL);
  assert(s != NULL);
  return (wchar_t *)memcpy(d, s, n * sizeof(wchar_t));
}
```
user: Translate the below assembly code into C programming language:

```asm
<pgm_copystring_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %esi,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movb   $0x0,-0x2(%rbp)
  jmp    L23
L37:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x20,-0x1(%rbp)
  jne    L23
  movzbl -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x1c(%rbp)
L23:
  cmpb   $0x0,-0x1c(%rbp)
  jne    L37
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  jmp    L22
L59:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
L22:
  cmpb   $0x20,-0x1(%rbp)
  je     L12
  movzbl -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dl,-0x20(%rbp)
  test   %al,%al
  jne    L59
L12:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  movzbl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char pgm_copystring_test(const char *p, unsigned char i, char *b, unsigned char l) {
  unsigned char ret, c;
  ret = 0;
  while (i) {
    c = *p++;
    if (c == ' ')
      i--;
  }
  c = *p++;
  while (c != ' ' && l--) {
    *b++ = c;
    ret++;
    c = *p++;
  }
  *b = 0;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pgm_copystring_test>:
  endbr64
  mov    %esi,%r8d
  test   %sil,%sil
  je     L9
L30:
  add    $0x1,%rdi
  cmpb   $0x20,-0x1(%rdi)
  sete   %sil
  sub    %sil,%r8b
  jne    L30
L9:
  movzbl (%rdi),%esi
  cmp    $0x20,%sil
  je     L0
  lea    -0x1(%rcx),%r8d
  test   %cl,%cl
  je     L4
  movzbl %r8b,%r8d
  add    $0x2,%r8
  mov    $0x1,%eax
L5:
  add    $0x1,%rdx
  mov    %sil,-0x1(%rdx)
  mov    %eax,%ecx
  movzbl (%rdi,%rax,1),%esi
  cmp    $0x20,%sil
  je     L4
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L5
L4:
  movb   $0x0,(%rdx)
  mov    %ecx,%eax
  ret
L0:
  mov    $0x0,%ecx
  jmp    L4
```

assistant: ```c
unsigned char pgm_copystring_test(const char *p, unsigned char i, char *b, unsigned char l) {
  unsigned char ret, c;
  ret = 0;
  while (i) {
    c = *p++;
    if (c == ' ')
      i--;
  }
  c = *p++;
  while (c != ' ' && l--) {
    *b++ = c;
    ret++;
    c = *p++;
  }
  *b = 0;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pgm_copystring_test>:
  endbr64
  mov    %esi,%eax
  test   %sil,%sil
  je     L37
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%rdi
  cmpb   $0x20,-0x1(%rdi)
  jne    L39
  sub    $0x1,%al
  jne    L39
L37:
  movzbl (%rdi),%esi
  cmp    $0x20,%sil
  je     L74
  lea    -0x1(%rcx),%eax
  test   %cl,%cl
  je     L74
  movzbl %al,%ecx
  mov    $0x1,%eax
  add    $0x2,%rcx
  jmp    L5
  nopl   0x0(%rax)
L44:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L34
L5:
  mov    %sil,(%rdx)
  movzbl (%rdi,%rax,1),%esi
  add    $0x1,%rdx
  mov    %eax,%r8d
  cmp    $0x20,%sil
  jne    L44
L34:
  movb   $0x0,(%rdx)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L74:
  xor    %r8d,%r8d
  movb   $0x0,(%rdx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char pgm_copystring_test(const char *p, unsigned char i, char *b, unsigned char l) {
  unsigned char ret, c;
  ret = 0;
  while (i) {
    c = *p++;
    if (c == ' ')
      i--;
  }
  c = *p++;
  while (c != ' ' && l--) {
    *b++ = c;
    ret++;
    c = *p++;
  }
  *b = 0;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pgm_copystring_test>:
  endbr64
  mov    %esi,%eax
  test   %sil,%sil
  je     L62
  nopl   0x0(%rax,%rax,1)
L69:
  add    $0x1,%rdi
  cmpb   $0x20,-0x1(%rdi)
  jne    L69
  sub    $0x1,%al
  jne    L69
L62:
  movzbl (%rdi),%esi
  cmp    $0x20,%sil
  je     L66
  lea    -0x1(%rcx),%eax
  test   %cl,%cl
  je     L66
  movzbl %al,%ecx
  mov    $0x1,%eax
  add    $0x2,%rcx
  jmp    L35
  nopl   0x0(%rax)
L10:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L38
L35:
  mov    %sil,(%rdx)
  movzbl (%rdi,%rax,1),%esi
  add    $0x1,%rdx
  mov    %eax,%r8d
  cmp    $0x20,%sil
  jne    L10
L38:
  movb   $0x0,(%rdx)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L66:
  xor    %r8d,%r8d
  movb   $0x0,(%rdx)
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned char pgm_copystring_test(const char *p, unsigned char i, char *b, unsigned char l) {
  unsigned char ret, c;
  ret = 0;
  while (i) {
    c = *p++;
    if (c == ' ')
      i--;
  }
  c = *p++;
  while (c != ' ' && l--) {
    *b++ = c;
    ret++;
    c = *p++;
  }
  *b = 0;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<heron_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <heron_setmem@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *heron_calloc(size_t num, size_t size) {
  void *p = calloc(num, size);
  heron_setmem(p, num * size);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<heron_calloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <calloc@plt>
  mov    %rax,%rbp
  imul   %r12,%rbx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <heron_setmem@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *heron_calloc(size_t num, size_t size) {
  void *p = calloc(num, size);
  heron_setmem(p, num * size);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heron_calloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  imul   %rbp,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <heron_setmem@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *heron_calloc(size_t num, size_t size) {
  void *p = calloc(num, size);
  heron_setmem(p, num * size);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<heron_calloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  imul   %rbp,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <heron_setmem@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *heron_calloc(size_t num, size_t size) {
  void *p = calloc(num, size);
  heron_setmem(p, num * size);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<summiere_int_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int summiere_int_array(const int array[], int laenge) {
  int summe = 0;
  for (int i = 0; i < laenge; i++)
    summe += array[i];
  return summe;
}
```
user: What is the c source code of the assembly code below:

```asm
<summiere_int_array>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L14:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L14
L20:
  mov    %edx,%eax
  ret
L6:
  mov    $0x0,%edx
  jmp    L20
```

assistant: ```c
int summiere_int_array(const int array[], int laenge) {
  int summe = 0;
  for (int i = 0; i < laenge; i++)
    summe += array[i];
  return summe;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<summiere_int_array>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L16
  ret
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int summiere_int_array(const int array[], int laenge) {
  int summe = 0;
  for (int i = 0; i < laenge; i++)
    summe += array[i];
  return summe;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<summiere_int_array>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L60
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L55
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L13:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L13
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L35
L12:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L22
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L22
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L60:
  xor    %eax,%eax
L22:
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  ret
L55:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L12
```

assistant: ```c
int summiere_int_array(const int array[], int laenge) {
  int summe = 0;
  for (int i = 0; i < laenge; i++)
    summe += array[i];
  return summe;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<additional_decryption_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %eax,-0x4(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,-0x4(%rbp)
  je     L4
  cmpl   $0x80,-0x4(%rbp)
  jne    L26
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L4:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L26:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L5:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %eax,%edi
  call   <pub_algs@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <fingerprint@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string

tool: D12: 		Class - 

tool: D5: Strong request

tool: D11: Normal

tool: D27: Unknown class(%02x)

assistant: ```c
extern void additional_decryption_key(int len) {
  int c = Getc();
  printf("\t\tClass - ");
  switch (c) {
  case 0x80:
    printf("Strong request");
    break;
  case 0x0:
    printf("Normal");
    break;
  default:
    printf("Unknown class(%02x)", c);
    break;
  }
  printf("\n");
  printf("\t");
  pub_algs(Getc());
  printf("\t");
  fingerprint();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<additional_decryption_key>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %eax,%ebx
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L31
  cmp    $0x80,%ebx
  jne    L8
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <Getc@plt>
  mov    %eax,%edi
  call   <pub_algs@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <fingerprint@plt>
  pop    %rbx
  ret
L31:
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L8:
  mov    %ebx,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D20
data_type: string
name: extract_symbolic_data
arguments: data_label: D38
data_type: string
name: extract_symbolic_data
arguments: data_label: D24
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string

tool: D20: 		Class - 

tool: D38: Strong request

tool: D24: Normal

tool: D11: Unknown class(%02x)

assistant: ```c
extern void additional_decryption_key(int len) {
  int c = Getc();
  printf("\t\tClass - ");
  switch (c) {
  case 0x80:
    printf("Strong request");
    break;
  case 0x0:
    printf("Normal");
    break;
  default:
    printf("Unknown class(%02x)", c);
    break;
  }
  printf("\n");
  printf("\t");
  pub_algs(Getc());
  printf("\t");
  fingerprint();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<additional_decryption_key>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <Getc@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L39
  cmp    $0x80,%ebp
  jne    L33
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %eax,%edi
  call   <pub_algs@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10c0 <fingerprint@plt>
  nopw   0x0(%rax,%rax,1)
L39:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L7
L33:
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string
name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D11: 		Class - 

tool: D15: Strong request

tool: D10: Normal

tool: D3: Unknown class(%02x)

assistant: ```c
extern void additional_decryption_key(int len) {
  int c = Getc();
  printf("\t\tClass - ");
  switch (c) {
  case 0x80:
    printf("Strong request");
    break;
  case 0x0:
    printf("Normal");
    break;
  default:
    printf("Unknown class(%02x)", c);
    break;
  }
  printf("\n");
  printf("\t");
  pub_algs(Getc());
  printf("\t");
  fingerprint();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<additional_decryption_key>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <Getc@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L38
  cmp    $0x80,%ebp
  jne    L36
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L27:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <Getc@plt>
  mov    %eax,%edi
  call   <pub_algs@plt>
  mov    $0x9,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    10c0 <fingerprint@plt>
  nopw   0x0(%rax,%rax,1)
L38:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
L36:
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
```

tool_calls: name: disassemble_data
arguments: tag: D29
type: string
name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D29: 		Class - 

tool: D25: Strong request

tool: D4: Normal

tool: D9: Unknown class(%02x)

assistant: ```c
extern void additional_decryption_key(int len) {
  int c = Getc();
  printf("\t\tClass - ");
  switch (c) {
  case 0x80:
    printf("Strong request");
    break;
  case 0x0:
    printf("Normal");
    break;
  default:
    printf("Unknown class(%02x)", c);
    break;
  }
  printf("\n");
  printf("\t");
  pub_algs(Getc());
  printf("\t");
  fingerprint();
}
```
user: Translate the below assembly code into C programming language:

```asm
<make16bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzwl -0xc(%rbp),%edx
  mov    %dl,(%rax)
  movzwl -0xc(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void make16bit(unsigned char *p, unsigned short i) {
  p[1] = i;
  p[0] = i >> 8;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make16bit>:
  endbr64
  mov    %esi,%eax
  mov    %sil,0x1(%rdi)
  movzbl %ah,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void make16bit(unsigned char *p, unsigned short i) {
  p[1] = i;
  p[0] = i >> 8;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<make16bit>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void make16bit(unsigned char *p, unsigned short i) {
  p[1] = i;
  p[0] = i >> 8;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<make16bit>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void make16bit(unsigned char *p, unsigned short i) {
  p[1] = i;
  p[0] = i >> 8;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L17:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  ja     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned mult(unsigned a, unsigned b) {
  unsigned s = 0;
  for (int i = 0; i < a; ++i) {
    s += b;
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mult>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L11
  mov    $0x0,%edx
L18:
  add    $0x1,%edx
  cmp    %eax,%edx
  jne    L18
  imul   %esi,%eax
L11:
  ret
```

assistant: ```c
unsigned mult(unsigned a, unsigned b) {
  unsigned s = 0;
  for (int i = 0; i < a; ++i) {
    s += b;
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mult>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
unsigned mult(unsigned a, unsigned b) {
  unsigned s = 0;
  for (int i = 0; i < a; ++i) {
    s += b;
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mult>:
  endbr64
  mov    %edi,%eax
  imul   %esi,%eax
  ret
```

assistant: ```c
unsigned mult(unsigned a, unsigned b) {
  unsigned s = 0;
  for (int i = 0; i < a; ++i) {
    s += b;
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gapped_extend_zero_stats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gapped_extend_zero_stats(void) {
  ;
  ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gapped_extend_zero_stats>:
  endbr64
  ret
```

assistant: ```c
void gapped_extend_zero_stats(void) {
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gapped_extend_zero_stats>:
  endbr64
  ret
```

assistant: ```c
void gapped_extend_zero_stats(void) {
  ;
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gapped_extend_zero_stats>:
  endbr64
  ret
```

assistant: ```c
void gapped_extend_zero_stats(void) {
  ;
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  je     L30
  cmpl   $0x0,-0x8(%rbp)
  je     L30
  mov    $0x1,%ecx
  jmp    L44
L30:
  mov    $0x0,%ecx
L44:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  cmp    %eax,%ecx
  jne    L32
  cmpl   $0x0,-0x10(%rbp)
  je     L48
L32:
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  setle  %al
  movzbl %al,%eax
  jmp    L41
L48:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
L41:
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 1, j = 6, k, l = 0;
  k = ((i + j && l) - j * 2 % j) || i ? j < j % i + 1 : j - i * -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int i = 1, j = 6, k, l = 0;
  k = ((i + j && l) - j * 2 % j) || i ? j < j % i + 1 : j - i * -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 1, j = 6, k, l = 0;
  k = ((i + j && l) - j * 2 % j) || i ? j < j % i + 1 : j - i * -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i = 1, j = 6, k, l = 0;
  k = ((i + j && l) - j * 2 % j) || i ? j < j % i + 1 : j - i * -1;
  return 0;
}
```