ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sudokuSolve>:
  endbr64
  push   %r15
  mov    $0x195,%ecx
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xcb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xca8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x24(%rsp),%rdx
  mov    %r14,%rdi
  rep stos %rax,%es:(%rdi)
  lea    0x168(%rsp),%rcx
  cs nopw 0x0(%rax,%rax,1)
L135:
  lea    -0x24(%rdx),%rax
  nopl   0x0(%rax)
L4:
  movl   $0x9,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
  lea    0x24(%rax),%rdx
  cmp    %rcx,%rdx
  jne    L135
  mov    %r13,%r15
  xor    %r12d,%r12d
  mov    $0x51,%ebp
  nopl   0x0(%rax,%rax,1)
L115:
  xor    %ebx,%ebx
  jmp    L98
  nopl   0x0(%rax)
L112:
  add    $0x1,%rbx
  cmp    $0x9,%rbx
  je     L73
L98:
  mov    (%r15,%rbx,4),%r8d
  mov    %ebx,%ecx
  test   %r8d,%r8d
  je     L112
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  sub    $0x1,%ebp
  call   <exclude@plt>
  test   %eax,%eax
  je     L112
  lea    D4(%rip),%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x9,%rbx
  jne    L98
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x1,%r12d
  add    $0x24,%r15
  cmp    $0x9,%r12d
  jne    L115
  lea    -0x1(%rbp),%ebx
  test   %ebp,%ebp
  jle    L107
L10:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <groupDetermine@plt>
  test   %eax,%eax
  je     L30
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <uniCandidate@plt>
  test   %eax,%eax
  je     L30
  lea    D9(%rip),%rdi
  call   <printf@plt>
L107:
  mov    %r13,%rdi
  call   <printSudoku@plt>
  mov    0xca8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L132
  add    $0xcb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L30:
  mov    %ebx,%eax
  sub    $0x1,%ebx
  test   %eax,%eax
  jne    L10
  jmp    L107
L132:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D4: I think your sudoku is somewhere incorrect.


tool: D9: Unique Candidate fails, try next, ??.


assistant: ```c
int sudokuSolve(int sudoku[9][9]) {
  int aux[10][9][9] = {{{0}}};
  int blanks = 81;
  int i, j, flag, sudokuType;
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      aux[0][i][j] = 9;
    }
  }
  for (i = 0; i < 9; i++) {
    for (j = 0; j < 9; j++) {
      if (0 != sudoku[i][j]) {
        blanks--;
        sudokuType = exclude(sudoku, aux, i, j, sudoku[i][j]);
        if (0 != sudokuType) {
          printf("I think your sudoku is somewhere incorrect.\n");
        }
      }
    }
  }
  while (blanks > 0) {
    flag = groupDetermine(sudoku, aux);
    if (0 == flag) {
      blanks--;
      continue;
    } else {
    }
    flag = uniCandidate(sudoku, aux);
    if (0 == flag) {
      blanks--;
      continue;
    } else {
      printf("Unique Candidate fails, try next, ??.\n");
      blanks = 0;
    }
  }
  printSudoku(sudoku);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<randperm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L33:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x1c(%rbp),%edx
  mov    %edx,%ecx
  sub    -0xc(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L12
  cmpl   $0x0,-0x8(%rbp)
  js     L12
  mov    $0x1,%eax
  jmp    L1
L12:
  mov    $0x0,%eax
L1:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L33
  nop
  nop
  leave
  ret
```

assistant: ```c
void randperm(int *input, int len) {
  for (int i = 0; i < len - 1; i++) {
    int rnd_idx = rand() % (len - i) + i;
    assert(rnd_idx < len && rnd_idx >= 0);
    int tmp = input[i];
    input[i] = input[rnd_idx];
    input[rnd_idx] = tmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<randperm>:
  endbr64
  cmp    $0x1,%esi
  jle    L4
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  lea    -0x2(%rsi),%r14d
  mov    $0x0,%ebp
L16:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %r13d,%ecx
  sub    %ebp,%ecx
  cltd
  idiv   %ecx
  lea    (%rdx,%rbp,1),%ebx
  cmp    %ebx,%r13d
  setg   %al
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    (%r12,%rbp,4),%edx
  movslq %ebx,%rbx
  lea    (%r12,%rbx,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,(%r12,%rbp,4)
  mov    %edx,(%rax)
  mov    %rbp,%rax
  add    $0x1,%rbp
  cmp    %r14,%rax
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  ret
```

assistant: ```c
void randperm(int *input, int len) {
  for (int i = 0; i < len - 1; i++) {
    int rnd_idx = rand() % (len - i) + i;
    assert(rnd_idx < len && rnd_idx >= 0);
    int tmp = input[i];
    input[i] = input[rnd_idx];
    input[rnd_idx] = tmp;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<randperm>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    -0x2(%rsi),%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   (%rax)
L5:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12d,%ecx
  sub    %ebp,%ecx
  cltd
  idiv   %ecx
  lea    (%rdx,%rbp,1),%ebx
  mov    %ebx,%edi
  cmp    %ebx,%r12d
  movslq %ebx,%rbx
  not    %edi
  setg   %al
  shr    $0x1f,%edi
  and    %eax,%edi
  call   <assert@plt>
  lea    (%r14,%rbx,4),%rax
  mov    (%r14,%rbp,4),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%r14,%rbp,4)
  mov    %edx,(%rax)
  mov    %rbp,%rax
  add    $0x1,%rbp
  cmp    %r13,%rax
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L0:
  ret
```

assistant: ```c
void randperm(int *input, int len) {
  for (int i = 0; i < len - 1; i++) {
    int rnd_idx = rand() % (len - i) + i;
    assert(rnd_idx < len && rnd_idx >= 0);
    int tmp = input[i];
    input[i] = input[rnd_idx];
    input[rnd_idx] = tmp;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<randperm>:
  endbr64
  cmp    $0x1,%esi
  jle    L4
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    -0x2(%rsi),%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   (%rax)
L0:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12d,%ecx
  sub    %ebp,%ecx
  cltd
  idiv   %ecx
  lea    (%rdx,%rbp,1),%ebx
  mov    %ebx,%edi
  cmp    %ebx,%r12d
  movslq %ebx,%rbx
  not    %edi
  setg   %al
  shr    $0x1f,%edi
  and    %eax,%edi
  call   <assert@plt>
  lea    (%r14,%rbx,4),%rax
  mov    (%r14,%rbp,4),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%r14,%rbp,4)
  mov    %edx,(%rax)
  mov    %rbp,%rax
  add    $0x1,%rbp
  cmp    %r13,%rax
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void randperm(int *input, int len) {
  for (int i = 0; i < len - 1; i++) {
    int rnd_idx = rand() % (len - i) + i;
    assert(rnd_idx < len && rnd_idx >= 0);
    int tmp = input[i];
    input[i] = input[rnd_idx];
    input[rnd_idx] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lst_remove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <lst_size@plt>
  mov    %eax,-0x1c(%rbp)
  movl   $0x1,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L33
  cmpq   $0x0,-0x30(%rbp)
  jne    L2
L33:
  mov    $0x0,%eax
  jmp    L45
L2:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x10(%rbp)
L36:
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  jbe    L44
  addl   $0x1,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L36
L44:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  jne    L46
  mov    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L46:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
L45:
  leave
  ret
```

assistant: ```c
int lst_remove(void *lst, size_t pos) {
  int size = lst_size(lst), count = 1;
  if (pos > size || pos <= 0)
    return 0;
  void *remov;
  void *aux = lst;
  void *tail = lst + sizeof(void *);
LOOP:
  if (count < pos) {
    count++;
    aux = *(void **)aux;
    goto LOOP;
  }
  if (pos == size)
    *(void **)tail = aux;
  remov = *(void **)aux;
  *(void **)aux = *(void **)remov;
  free(remov);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lst_remove>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <lst_size@plt>
  cltq
  lea    -0x1(%rbx),%rcx
  mov    $0x0,%edx
  cmp    %rcx,%rax
  ja     L20
L56:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  cmp    $0x1,%rbx
  jbe    L64
  mov    %ebx,%esi
  mov    %rbp,%rcx
  mov    $0x1,%edx
L47:
  add    $0x1,%edx
  mov    (%rcx),%rcx
  cmp    %esi,%edx
  jne    L47
L39:
  cmp    %rbx,%rax
  je     L12
L51:
  mov    (%rcx),%rdi
  mov    (%rdi),%rax
  mov    %rax,(%rcx)
  call   <free@plt>
  mov    $0x1,%edx
  jmp    L56
L64:
  mov    %rbp,%rcx
  jmp    L39
L12:
  mov    %rcx,0x8(%rbp)
  jmp    L51
```

assistant: ```c
int lst_remove(void *lst, size_t pos) {
  int size = lst_size(lst), count = 1;
  if (pos > size || pos <= 0)
    return 0;
  void *remov;
  void *aux = lst;
  void *tail = lst + sizeof(void *);
LOOP:
  if (count < pos) {
    count++;
    aux = *(void **)aux;
    goto LOOP;
  }
  if (pos == size)
    *(void **)tail = aux;
  remov = *(void **)aux;
  *(void **)aux = *(void **)remov;
  free(remov);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lst_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <lst_size@plt>
  lea    -0x1(%rbx),%rdx
  xor    %r8d,%r8d
  cltq
  cmp    %rdx,%rax
  ja     L27
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L27:
  cmp    $0x1,%rbx
  jbe    L6
  mov    %ebx,%esi
  mov    %rbp,%rcx
  mov    $0x1,%edx
L21:
  add    $0x1,%edx
  mov    (%rcx),%rcx
  cmp    %esi,%edx
  jne    L21
L49:
  cmp    %rbx,%rax
  jne    L29
  mov    %rcx,0x8(%rbp)
L29:
  mov    (%rcx),%rdi
  mov    (%rdi),%rax
  mov    %rax,(%rcx)
  call   <free@plt>
  add    $0x8,%rsp
  mov    $0x1,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  mov    %rbp,%rcx
  jmp    L49
```

assistant: ```c
int lst_remove(void *lst, size_t pos) {
  int size = lst_size(lst), count = 1;
  if (pos > size || pos <= 0)
    return 0;
  void *remov;
  void *aux = lst;
  void *tail = lst + sizeof(void *);
LOOP:
  if (count < pos) {
    count++;
    aux = *(void **)aux;
    goto LOOP;
  }
  if (pos == size)
    *(void **)tail = aux;
  remov = *(void **)aux;
  *(void **)aux = *(void **)remov;
  free(remov);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lst_remove>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <lst_size@plt>
  lea    -0x1(%rbx),%rdx
  xor    %r8d,%r8d
  cltq
  cmp    %rdx,%rax
  ja     L2
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  cmp    $0x1,%rbx
  jbe    L48
  mov    %ebx,%esi
  mov    %rbp,%rcx
  mov    $0x1,%edx
L29:
  add    $0x1,%edx
  mov    (%rcx),%rcx
  cmp    %esi,%edx
  jne    L29
L31:
  cmp    %rbx,%rax
  jne    L8
  mov    %rcx,0x8(%rbp)
L8:
  mov    (%rcx),%rdi
  mov    (%rdi),%rax
  mov    %rax,(%rcx)
  call   <free@plt>
  add    $0x8,%rsp
  mov    $0x1,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    %rbp,%rcx
  jmp    L31
```

assistant: ```c
int lst_remove(void *lst, size_t pos) {
  int size = lst_size(lst), count = 1;
  if (pos > size || pos <= 0)
    return 0;
  void *remov;
  void *aux = lst;
  void *tail = lst + sizeof(void *);
LOOP:
  if (count < pos) {
    count++;
    aux = *(void **)aux;
    goto LOOP;
  }
  if (pos == size)
    *(void **)tail = aux;
  remov = *(void **)aux;
  *(void **)aux = *(void **)remov;
  free(remov);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x4,0x80(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: %d


assistant: ```c
int main() {
  int arr[4] = {0, 1, 2, 3};
  arr[40] = 4;
  printf("%d\n", arr[0]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: string

tool: D6: %d


assistant: ```c
int main() {
  int arr[4] = {0, 1, 2, 3};
  arr[40] = 4;
  printf("%d\n", arr[0]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main() {
  int arr[4] = {0, 1, 2, 3};
  arr[40] = 4;
  printf("%d\n", arr[0]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main() {
  int arr[4] = {0, 1, 2, 3};
  arr[40] = 4;
  printf("%d\n", arr[0]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lw_server_get_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D15(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <get_argument_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
datatype: string
name: disassemble_data
arguments: tag: D9
datatype: string

tool: 

tool: D9: log

assistant: ```c
char *lw_server_get_log() {
  char *result = "";
  result = get_argument_str("log");
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lw_server_get_log>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <get_argument_str@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: log

assistant: ```c
char *lw_server_get_log() {
  char *result = "";
  result = get_argument_str("log");
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lw_server_get_log>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <get_argument_str@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: log

assistant: ```c
char *lw_server_get_log() {
  char *result = "";
  result = get_argument_str("log");
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lw_server_get_log>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <get_argument_str@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: log

assistant: ```c
char *lw_server_get_log() {
  char *result = "";
  result = get_argument_str("log");
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<EPINonBlockingReadCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x28(%rax),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EPINonBlockingReadCount>:
  endbr64
  shl    $0x4,%esi
  lea    0x28(%rsi,%rdi,1),%eax
  cltq
  mov    (%rax),%eax
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<EPINonBlockingReadCount>:
  endbr64
  shl    $0x4,%esi
  lea    0x28(%rsi,%rdi,1),%eax
  cltq
  mov    (%rax),%eax
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EPINonBlockingReadCount>:
  endbr64
  shl    $0x4,%esi
  lea    0x28(%rsi,%rdi,1),%eax
  cltq
  mov    (%rax),%eax
  ret
```

assistant: ```c
uint32_t EPINonBlockingReadCount(uint32_t ui32Base, uint32_t ui32Channel) {
  uint32_t ui32Offset;
  ;
  ;
  ui32Offset = ui32Channel * (0x00000038 - 0x00000028);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000028 + ui32Offset))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rand_range16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  movzwl -0x18(%rbp),%eax
  movzwl -0x14(%rbp),%edx
  sub    %edx,%eax
  mov    %ax,-0x2(%rbp)
  cmpw   $0x0,-0x2(%rbp)
  jne    L13
  movzwl -0x14(%rbp),%eax
  jmp    L9
L13:
  mov    $0x0,%eax
  call   <rand@plt>
  cwtl
  movswl -0x2(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  mov    %eax,%edx
  movzwl -0x14(%rbp),%eax
  add    %edx,%eax
L9:
  leave
  ret
```

assistant: ```c
short rand_range16(short min, short max) {
  short range = (max - min);
  if (range == 0)
    return min;
  return min + (rand() % range);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rand_range16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %esi,%ebp
  sub    %di,%bp
  jne    L13
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  cwtl
  movswl %bp,%esi
  cltd
  idiv   %esi
  lea    (%rbx,%rdx,1),%eax
  jmp    L3
```

assistant: ```c
short rand_range16(short min, short max) {
  short range = (max - min);
  if (range == 0)
    return min;
  return min + (rand() % range);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand_range16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%eax
  push   %rbx
  sub    $0x8,%rsp
  sub    %di,%bp
  je     L8
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <rand@plt>
  movswl %bp,%esi
  cwtl
  cltd
  idiv   %esi
  lea    (%rbx,%rdx,1),%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
short rand_range16(short min, short max) {
  short range = (max - min);
  if (range == 0)
    return min;
  return min + (rand() % range);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rand_range16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%eax
  push   %rbx
  sub    $0x8,%rsp
  sub    %di,%bp
  je     L4
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <rand@plt>
  movswl %bp,%esi
  cwtl
  cltd
  idiv   %esi
  lea    (%rbx,%rdx,1),%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
short rand_range16(short min, short max) {
  short range = (max - min);
  if (range == 0)
    return min;
  return min + (rand() % range);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unfs_child_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L29
  mov    $0x0,%eax
  jmp    L75
L29:
  cmpl   $0x1,-0xc(%rbp)
  jne    L40
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L75
L40:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L4
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L4
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x1,%eax
  jmp    L75
L4:
  mov    $0x0,%eax
L75:
  leave
  ret
```

assistant: ```c
int unfs_child_of(const char *child, const char *parent) {
  int clen = strlen(child);
  int plen = strlen(parent);
  if (clen <= plen)
    return 0;
  if (plen == 1)
    return (strchr(child + 1, '/') == 0);
  const char *s = child + plen;
  return (*s == '/' && !strncmp(child, parent, plen) && !strchr(s + 1, '/'));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unfs_child_of>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%r12d
  jle    L8
  cmp    $0x1,%eax
  je     L51
  movslq %eax,%r12
  add    %rbx,%r12
  mov    $0x0,%edx
  cmpb   $0x2f,(%r12)
  je     L4
L8:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L8
L4:
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  mov    $0x0,%edx
  test   %eax,%eax
  jne    L8
  lea    0x1(%r12),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L8
```

assistant: ```c
int unfs_child_of(const char *child, const char *parent) {
  int clen = strlen(child);
  int plen = strlen(parent);
  if (clen <= plen)
    return 0;
  if (plen == 1)
    return (strchr(child + 1, '/') == 0);
  const char *s = child + plen;
  return (*s == '/' && !strncmp(child, parent, plen) && !strchr(s + 1, '/'));
}
```