ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<Media_GetMediaTime>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int Media_GetMediaTime() {
  int ptime = 0;
  return ptime;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GetPortStopSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <Termios2TncomStopSize@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
unsigned char GetPortStopSize(int PortFd) {
  struct termios PortSettings;
  tcgetattr(PortFd, &PortSettings);
  return Termios2TncomStopSize(&PortSettings);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetPortStopSize>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <tcgetattr@plt>
  mov    %rbx,%rdi
  call   <Termios2TncomStopSize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char GetPortStopSize(int PortFd) {
  struct termios PortSettings;
  tcgetattr(PortFd, &PortSettings);
  return Termios2TncomStopSize(&PortSettings);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GetPortStopSize>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <tcgetattr@plt>
  mov    %rbp,%rdi
  call   <Termios2TncomStopSize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char GetPortStopSize(int PortFd) {
  struct termios PortSettings;
  tcgetattr(PortFd, &PortSettings);
  return Termios2TncomStopSize(&PortSettings);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<GetPortStopSize>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <tcgetattr@plt>
  mov    %rbp,%rdi
  call   <Termios2TncomStopSize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char GetPortStopSize(int PortFd) {
  struct termios PortSettings;
  tcgetattr(PortFd, &PortSettings);
  return Termios2TncomStopSize(&PortSettings);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<relay_weechat_msg_add_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb0(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %al,-0x91(%rbp)
  lea    -0x91(%rbp),%rcx
  mov    -0xa8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <relay_weechat_msg_add_bytes@plt>
  movzbl -0x91(%rbp),%eax
  movzbl %al,%edx
  lea    -0x90(%rbp),%rcx
  mov    -0xa8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <relay_weechat_msg_add_bytes@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: %ld

assistant: ```c
void relay_weechat_msg_add_long(struct t_relay_weechat_msg *msg, long value) {
  char str_long[128];
  unsigned char length;
  snprintf(str_long, sizeof(str_long), "%ld", value);
  length = strlen(str_long);
  relay_weechat_msg_add_bytes(msg, &length, 1);
  relay_weechat_msg_add_bytes(msg, str_long, length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<relay_weechat_msg_add_long>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    D9(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %al,0xf(%rsp)
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <relay_weechat_msg_add_bytes@plt>
  movzbl 0xf(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <relay_weechat_msg_add_bytes@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: %ld

assistant: ```c
void relay_weechat_msg_add_long(struct t_relay_weechat_msg *msg, long value) {
  char str_long[128];
  unsigned char length;
  snprintf(str_long, sizeof(str_long), "%ld", value);
  length = strlen(str_long);
  relay_weechat_msg_add_bytes(msg, &length, 1);
  relay_weechat_msg_add_bytes(msg, str_long, length);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<relay_weechat_msg_add_long>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  lea    D5(%rip),%rdx
  mov    $0x80,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %al,0xf(%rsp)
  xor    %eax,%eax
  call   <relay_weechat_msg_add_bytes@plt>
  movzbl 0xf(%rsp),%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <relay_weechat_msg_add_bytes@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xa8,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: %ld

assistant: ```c
void relay_weechat_msg_add_long(struct t_relay_weechat_msg *msg, long value) {
  char str_long[128];
  unsigned char length;
  snprintf(str_long, sizeof(str_long), "%ld", value);
  length = strlen(str_long);
  relay_weechat_msg_add_bytes(msg, &length, 1);
  relay_weechat_msg_add_bytes(msg, str_long, length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<relay_weechat_msg_add_long>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  lea    D5(%rip),%rdx
  mov    $0x80,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0xf(%rsp),%rsi
  mov    $0x1,%edx
  mov    %rbp,%rdi
  mov    %al,0xf(%rsp)
  xor    %eax,%eax
  call   <relay_weechat_msg_add_bytes@plt>
  movzbl 0xf(%rsp),%edx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <relay_weechat_msg_add_bytes@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xa8,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: %ld

assistant: ```c
void relay_weechat_msg_add_long(struct t_relay_weechat_msg *msg, long value) {
  char str_long[128];
  unsigned char length;
  snprintf(str_long, sizeof(str_long), "%ld", value);
  length = strlen(str_long);
  relay_weechat_msg_add_bytes(msg, &length, 1);
  relay_weechat_msg_add_bytes(msg, str_long, length);
}
```
user: Translate the below assembly code into C programming language:

```asm
<removeDuplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %rdi,-0x1b8(%rbp)
  mov    %esi,-0x1bc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a8(%rbp)
  movl   $0x0,-0x1a4(%rbp)
  mov    -0x1b8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1a8(%rbp)
  mov    -0x1b8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1a4(%rbp)
  movl   $0x1,-0x1ac(%rbp)
  jmp    L0
L59:
  mov    -0x1ac(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1a8(%rbp)
  jge    L46
  mov    -0x1ac(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1a8(%rbp)
  addl   $0x1,-0x1a4(%rbp)
L46:
  addl   $0x1,-0x1ac(%rbp)
L0:
  mov    -0x1ac(%rbp),%eax
  cmp    -0x1bc(%rbp),%eax
  jl     L59
  movl   $0x0,-0x1ac(%rbp)
  jmp    L4
L11:
  mov    -0x1ac(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1ac(%rbp)
L4:
  mov    -0x1ac(%rbp),%eax
  cmp    -0x1a4(%rbp),%eax
  jl     L11
  mov    -0x1a4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int removeDuplicates(int *set, int len) {
  int temp[100], i, prev = 0, loc = 0;
  prev = set[0];
  temp[loc] = set[0];
  loc++;
  for (i = 1; i < len; i++) {
    if (set[i] > prev) {
      temp[loc] = set[i];
      prev = temp[loc];
      loc++;
    }
  }
  for (i = 0; i < loc; i++) {
    set[i] = temp[i];
  }
  return (loc);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<removeDuplicates>:
  endbr64
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%r8d
  mov    %r8d,(%rsp)
  cmp    $0x1,%esi
  jle    L28
  lea    0x4(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rsi
  mov    $0x1,%ecx
  jmp    L0
L22:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L47
L0:
  mov    (%rax),%edx
  cmp    %r8d,%edx
  jle    L22
  movslq %ecx,%r8
  mov    %edx,(%rsp,%r8,4)
  add    $0x1,%ecx
  mov    %edx,%r8d
  jmp    L22
L47:
  test   %ecx,%ecx
  jle    L8
  mov    $0x0,%eax
L51:
  mov    (%rsp,%rax,4),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L51
L8:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    %ecx,%eax
  add    $0x1a8,%rsp
  ret
L28:
  mov    (%rsp),%eax
  mov    %eax,(%rdi)
  mov    $0x1,%ecx
  jmp    L8
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int removeDuplicates(int *set, int len) {
  int temp[100], i, prev = 0, loc = 0;
  prev = set[0];
  temp[loc] = set[0];
  loc++;
  for (i = 1; i < len; i++) {
    if (set[i] > prev) {
      temp[loc] = set[i];
      prev = temp[loc];
      loc++;
    }
  }
  for (i = 0; i < loc; i++) {
    set[i] = temp[i];
  }
  return (loc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<removeDuplicates>:
  endbr64
  sub    $0x1a8,%rsp
  mov    (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  jle    L31
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  mov    %ecx,%esi
  mov    $0x1,%r8d
  lea    0x8(%rdi,%rdx,4),%r9
  nopl   0x0(%rax)
L35:
  mov    (%rax),%edx
  cmp    %esi,%edx
  jle    L2
  movslq %r8d,%rsi
  add    $0x1,%r8d
  mov    %edx,(%rsp,%rsi,4)
  mov    %edx,%esi
L2:
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L35
  lea    -0x1(%r8),%edx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  shl    $0x2,%rdx
  jmp    L20
  nopl   0x0(%rax)
L64:
  mov    (%rsi,%rax,1),%ecx
  add    $0x4,%rax
L20:
  mov    %ecx,(%rdi,%rax,1)
  cmp    %rax,%rdx
  jne    L64
L67:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %r8d,%eax
  add    $0x1a8,%rsp
  ret
  nopl   (%rax)
L31:
  mov    $0x1,%r8d
  jmp    L67
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int removeDuplicates(int *set, int len) {
  int temp[100], i, prev = 0, loc = 0;
  prev = set[0];
  temp[loc] = set[0];
  loc++;
  for (i = 1; i < len; i++) {
    if (set[i] > prev) {
      temp[loc] = set[i];
      prev = temp[loc];
      loc++;
    }
  }
  for (i = 0; i < loc; i++) {
    set[i] = temp[i];
  }
  return (loc);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<removeDuplicates>:
  endbr64
  push   %r12
  sub    $0x1a0,%rsp
  mov    (%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %ecx,(%rsp)
  cmp    $0x1,%esi
  jle    L47
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi),%rax
  mov    $0x1,%r12d
  lea    0x8(%rdi,%rdx,4),%rsi
  nopl   0x0(%rax)
L0:
  mov    (%rax),%edx
  cmp    %ecx,%edx
  jle    L23
  movslq %r12d,%rcx
  add    $0x1,%r12d
  mov    %edx,(%rsp,%rcx,4)
  mov    %edx,%ecx
L23:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L0
  movslq %r12d,%rdx
  mov    %rsp,%rsi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L48:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x1a0,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x1,%r12d
  jmp    L48
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int removeDuplicates(int *set, int len) {
  int temp[100], i, prev = 0, loc = 0;
  prev = set[0];
  temp[loc] = set[0];
  loc++;
  for (i = 1; i < len; i++) {
    if (set[i] > prev) {
      temp[loc] = set[i];
      prev = temp[loc];
      loc++;
    }
  }
  for (i = 0; i < loc; i++) {
    set[i] = temp[i];
  }
  return (loc);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mc_conv_utf8_to_unicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L31
L44:
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mc_utf8_to_unicode@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L33
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movslq %ecx,%rdx
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L31:
  cmpl   $0x0,-0x18(%rbp)
  jg     L44
  jmp    L36
L33:
  nop
L36:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sar    $0x3,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int mc_conv_utf8_to_unicode(const char *utf8str, wchar_t *wcstr) {
  int len = (int)strlen(utf8str);
  wchar_t *ptr = wcstr;
  int ch, n;
  while (len > 0) {
    n = mc_utf8_to_unicode(utf8str, &ch);
    if (n <= 0) {
      break;
    }
    *ptr++ = (wchar_t)ch;
    utf8str += n;
    len -= n;
  }
  return (int)(ptr - wcstr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mc_conv_utf8_to_unicode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  mov    %eax,%r12d
  mov    %r14,%rbx
  lea    0x4(%rsp),%r13
L14:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <mc_utf8_to_unicode@plt>
  test   %eax,%eax
  jle    L13
  add    $0x8,%rbx
  movslq 0x4(%rsp),%rdx
  mov    %rdx,-0x8(%rbx)
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%r12d
  test   %r12d,%r12d
  jg     L14
L13:
  sub    %r14,%rbx
  sar    $0x3,%rbx
  mov    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  mov    %r14,%rbx
  jmp    L13
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mc_conv_utf8_to_unicode(const char *utf8str, wchar_t *wcstr) {
  int len = (int)strlen(utf8str);
  wchar_t *ptr = wcstr;
  int ch, n;
  while (len > 0) {
    n = mc_utf8_to_unicode(utf8str, &ch);
    if (n <= 0) {
      break;
    }
    *ptr++ = (wchar_t)ch;
    utf8str += n;
    len -= n;
  }
  return (int)(ptr - wcstr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mc_conv_utf8_to_unicode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jle    L39
  mov    %eax,%r14d
  mov    %rbp,%rbx
  lea    0x4(%rsp),%r13
  jmp    L22
  nopl   0x0(%rax)
L19:
  movslq 0x4(%rsp),%rdx
  sub    %eax,%r14d
  add    $0x8,%rbx
  mov    %rdx,-0x8(%rbx)
  movslq %eax,%rdx
  add    %rdx,%r12
  test   %r14d,%r14d
  jle    L25
L22:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mc_utf8_to_unicode@plt>
  test   %eax,%eax
  jg     L19
L25:
  mov    %rbx,%rax
  sub    %rbp,%rax
  sar    $0x3,%rax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  xor    %eax,%eax
  jmp    L26
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mc_conv_utf8_to_unicode(const char *utf8str, wchar_t *wcstr) {
  int len = (int)strlen(utf8str);
  wchar_t *ptr = wcstr;
  int ch, n;
  while (len > 0) {
    n = mc_utf8_to_unicode(utf8str, &ch);
    if (n <= 0) {
      break;
    }
    *ptr++ = (wchar_t)ch;
    utf8str += n;
    len -= n;
  }
  return (int)(ptr - wcstr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mc_conv_utf8_to_unicode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  test   %eax,%eax
  jle    L24
  mov    %eax,%r14d
  mov    %rbp,%rbx
  lea    0x4(%rsp),%r13
  jmp    L42
  nopl   0x0(%rax)
L32:
  movslq 0x4(%rsp),%rdx
  sub    %eax,%r14d
  add    $0x8,%rbx
  mov    %rdx,-0x8(%rbx)
  movslq %eax,%rdx
  add    %rdx,%r12
  test   %r14d,%r14d
  jle    L3
L42:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <mc_utf8_to_unicode@plt>
  test   %eax,%eax
  jg     L32
L3:
  mov    %rbx,%rax
  sub    %rbp,%rax
  sar    $0x3,%rax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  xor    %eax,%eax
  jmp    L34
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mc_conv_utf8_to_unicode(const char *utf8str, wchar_t *wcstr) {
  int len = (int)strlen(utf8str);
  wchar_t *ptr = wcstr;
  int ch, n;
  while (len > 0) {
    n = mc_utf8_to_unicode(utf8str, &ch);
    if (n <= 0) {
      break;
    }
    *ptr++ = (wchar_t)ch;
    utf8str += n;
    len -= n;
  }
  return (int)(ptr - wcstr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kvz_math_floor_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  jmp    L21
L16:
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jb     L37
  mov    -0x8(%rbp),%eax
  jmp    L30
L37:
  mov    $0x0,%eax
L30:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shrl   %cl,-0x14(%rbp)
  subl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0x0,-0xc(%rbp)
  jns    L16
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned kvz_math_floor_log2(unsigned value) {
  assert(value > 0);
  unsigned result = 0;
  for (int i = 4; i >= 0; --i) {
    unsigned bits = 1ull << i;
    unsigned shift = value >= (1 << bits) ? bits : 0;
    result += shift;
    value >>= shift;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kvz_math_floor_log2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x4,%eax
  mov    $0x0,%edx
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  mov    $0x0,%edi
L0:
  mov    %r9,%rsi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    %rsi,%rcx
  mov    %r8d,%esi
  shl    %cl,%esi
  cmp    %ebx,%esi
  cmova  %edi,%ecx
  add    %ecx,%edx
  shr    %cl,%ebx
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  jne    L0
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned kvz_math_floor_log2(unsigned value) {
  assert(value > 0);
  unsigned result = 0;
  for (int i = 4; i >= 0; --i) {
    unsigned bits = 1ull << i;
    unsigned shift = value >= (1 << bits) ? bits : 0;
    result += shift;
    value >>= shift;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kvz_math_floor_log2>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  test   %ebx,%ebx
  setne  %dil
  call   <assert@plt>
  mov    $0x4,%eax
  xor    %r8d,%r8d
  mov    $0x1,%edi
  mov    $0x1,%esi
L0:
  mov    %eax,%ecx
  mov    %rdi,%rdx
  shl    %cl,%rdx
  mov    %rdx,%rcx
  mov    %esi,%edx
  shl    %cl,%edx
  cmp    %ebx,%edx
  ja     L7
  add    %ecx,%r8d
  shr    %cl,%ebx
L7:
  sub    $0x1,%eax
  jae    L0
  mov    %r8d,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned kvz_math_floor_log2(unsigned value) {
  assert(value > 0);
  unsigned result = 0;
  for (int i = 4; i >= 0; --i) {
    unsigned bits = 1ull << i;
    unsigned shift = value >= (1 << bits) ? bits : 0;
    result += shift;
    value >>= shift;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<kvz_math_floor_log2>:
  endbr64
  test   %edi,%edi
  push   %rbx
  mov    %edi,%ebx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %eax,%eax
  cmp    $0xffff,%ebx
  jbe    L25
  shr    $0x10,%ebx
  mov    $0x10,%eax
L25:
  cmp    $0xff,%ebx
  jbe    L35
  add    $0x8,%eax
  shr    $0x8,%ebx
L35:
  cmp    $0xf,%ebx
  jbe    L5
  add    $0x4,%eax
  shr    $0x4,%ebx
L5:
  cmp    $0x3,%ebx
  jbe    L31
  add    $0x2,%eax
  shr    $0x2,%ebx
L31:
  cmp    $0x2,%ebx
  pop    %rbx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned kvz_math_floor_log2(unsigned value) {
  assert(value > 0);
  unsigned result = 0;
  for (int i = 4; i >= 0; --i) {
    unsigned bits = 1ull << i;
    unsigned shift = value >= (1 << bits) ? bits : 0;
    result += shift;
    value >>= shift;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<OutHips>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L9
L15:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
L9:
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cmp    %eax,%ebx
  jl     L15
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: HIPS


1

%d
%d
%d
%d
0
0
0
1
0
1

0
  0


assistant: ```c
void OutHips(char *Screen, int xmax, int ymax) {
  register uint k;
  printf("HIPS\n\n\n1\n\n%d\n%d\n%d\n%d\n0\n0\n0\n1\n0\n1\n\n0\n  0\n", ymax, xmax, ymax, xmax);
  for (k = 0; k < xmax * ymax; k++)
    putchar(Screen[k]);
}
```