ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_channel_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L27:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x20(%rbp),%eax
  mov    $0xef,%ecx
  mov    %eax,%edi
  call   <write_frame@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
  addl   $0x1,-0x8(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L26
  cmpl   $0x4,-0x8(%rbp)
  jle    L27
L26:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int handle_channel_data(unsigned char *buf, int len, int channel) {
  int written = 0;
  int i = 0;
  int last = 0;
  while (written != len && i < 5) {
    last = write_frame(channel, buf + written, len - written, 0xEF);
    written += last;
    if (last == 0)
      i++;
  }
  return (len - written);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<handle_channel_data>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  test   %esi,%esi
  je     L50
  mov    %rdi,%r13
  mov    %edx,%r14d
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L37
L24:
  add    $0x1,%r12d
L56:
  cmp    %ebp,%ebx
  je     L21
  cmp    $0x4,%r12d
  jg     L21
L37:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    $0xef,%ecx
  mov    %r14d,%edi
  call   <write_frame@plt>
  test   %eax,%eax
  je     L24
  add    %eax,%ebx
  jmp    L56
L50:
  mov    %esi,%ebx
L21:
  mov    %ebp,%eax
  sub    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int handle_channel_data(unsigned char *buf, int len, int channel) {
  int written = 0;
  int i = 0;
  int last = 0;
  while (written != len && i < 5) {
    last = write_frame(channel, buf + written, len - written, 0xEF);
    written += last;
    if (last == 0)
      i++;
  }
  return (len - written);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<handle_channel_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L39
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    %edx,%r13d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  jmp    L44
  nopl   (%rax)
L12:
  add    %eax,%ebx
  mov    %r14d,%r15d
  sub    %ebx,%r15d
  cmp    %ebx,%r14d
  je     L1
L10:
  cmp    $0x4,%ebp
  jg     L1
L44:
  mov    %r14d,%r15d
  movslq %ebx,%rsi
  mov    $0xef,%ecx
  mov    %r13d,%edi
  sub    %ebx,%r15d
  add    %r12,%rsi
  mov    %r15d,%edx
  call   <write_frame@plt>
  test   %eax,%eax
  jne    L12
  add    $0x1,%ebp
  cmp    %ebx,%r14d
  jne    L10
L1:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L39:
  xor    %r15d,%r15d
  jmp    L1
```

assistant: ```c
int handle_channel_data(unsigned char *buf, int len, int channel) {
  int written = 0;
  int i = 0;
  int last = 0;
  while (written != len && i < 5) {
    last = write_frame(channel, buf + written, len - written, 0xEF);
    written += last;
    if (last == 0)
      i++;
  }
  return (len - written);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<handle_channel_data>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L56
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    %edx,%r13d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  jmp    L54
  nopl   (%rax)
L62:
  add    %eax,%ebx
  mov    %r14d,%r15d
  sub    %ebx,%r15d
  cmp    %ebx,%r14d
  je     L47
L40:
  cmp    $0x4,%ebp
  jg     L47
L54:
  mov    %r14d,%r15d
  movslq %ebx,%rsi
  mov    $0xef,%ecx
  mov    %r13d,%edi
  sub    %ebx,%r15d
  add    %r12,%rsi
  mov    %r15d,%edx
  call   <write_frame@plt>
  test   %eax,%eax
  jne    L62
  add    $0x1,%ebp
  cmp    %ebx,%r14d
  jne    L40
L47:
  add    $0x8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L56:
  xor    %r15d,%r15d
  jmp    L47
```

assistant: ```c
int handle_channel_data(unsigned char *buf, int len, int channel) {
  int written = 0;
  int i = 0;
  int last = 0;
  while (written != len && i < 5) {
    last = write_frame(channel, buf + written, len - written, 0xEF);
    written += last;
    if (last == 0)
      i++;
  }
  return (len - written);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L13:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L3:
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L3
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D26
data_type: string

tool: D15: [ 

tool: D24: %.8f 

tool: D26: ]

assistant: ```c
void printMat(double *A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    printf("[ ");
    for (j = 0; j < m; j++) {
      printf("%.8f ", A[i + j * n]);
    }
    printf("]\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printMat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %esi,%esi
  jle    L33
  mov    %edx,%r12d
  mov    %esi,%eax
  mov    %rax,(%rsp)
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%r13
  mov    $0x0,%r15d
  lea    D9(%rip),%r14
L14:
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L16
  mov    0x8(%rsp),%rax
  lea    (%rax,%r15,8),%rbp
  mov    $0x0,%ebx
L37:
  movsd  0x0(%rbp),%xmm0
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13,%rbp
  cmp    %ebx,%r12d
  jne    L37
L16:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r15
  cmp    (%rsp),%r15
  jne    L14
L33:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D7
data_type: string

tool: D9: %.8f 

tool: D20: [ 

tool: D7: ]

assistant: ```c
void printMat(double *A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    printf("[ ");
    for (j = 0; j < m; j++) {
      printf("%.8f ", A[i + j * n]);
    }
    printf("]\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printMat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %esi,%esi
  jle    L39
  movslq %esi,%rax
  mov    %edx,%ebx
  lea    D10(%rip),%rbp
  xor    %r13d,%r13d
  mov    %rax,(%rsp)
  lea    0x0(,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L36
  mov    0x8(%rsp),%rax
  xor    %r14d,%r14d
  lea    (%rax,%r13,8),%r15
  xchg   %ax,%ax
L2:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%r14d
  add    %r12,%r15
  call   <printf@plt>
  cmp    %r14d,%ebx
  jne    L2
L36:
  lea    D7(%rip),%rdi
  add    $0x1,%r13
  call   <puts@plt>
  cmp    (%rsp),%r13
  jne    L23
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
datatype: string
name: read_data
arguments: data_label: D18
datatype: string
name: read_data
arguments: data_label: D7
datatype: string

tool: D10: %.8f 

tool: D18: [ 

tool: D7: ]

assistant: ```c
void printMat(double *A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    printf("[ ");
    for (j = 0; j < m; j++) {
      printf("%.8f ", A[i + j * n]);
    }
    printf("]\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printMat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %esi,%esi
  jle    L28
  movslq %esi,%rax
  mov    %edx,%ebx
  lea    D0(%rip),%rbp
  xor    %r13d,%r13d
  mov    %rax,(%rsp)
  lea    0x0(,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L3
  mov    0x8(%rsp),%rax
  xor    %r14d,%r14d
  lea    (%rax,%r13,8),%r15
  xchg   %ax,%ax
L23:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%r14d
  add    %r12,%r15
  call   <printf@plt>
  cmp    %r14d,%ebx
  jne    L23
L3:
  lea    D25(%rip),%rdi
  add    $0x1,%r13
  call   <puts@plt>
  cmp    %r13,(%rsp)
  jne    L14
L28:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string
name: unpack_data
arguments: data_tag: D10
data_type: string
name: unpack_data
arguments: data_tag: D25
data_type: string

tool: D0: %.8f 

tool: D10: [ 

tool: D25: ]

assistant: ```c
void printMat(double *A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++) {
    printf("[ ");
    for (j = 0; j < m; j++) {
      printf("%.8f ", A[i + j * n]);
    }
    printf("]\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x1,-0x18(%rbp)
  jmp    L40
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  movq   $0x1,-0x10(%rbp)
  jmp    L22
L5:
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jbe    L5
  addq   $0x1,-0x18(%rbp)
L40:
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jbe    L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D44
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string
name: extract_symbolic_data
arguments: tag: D15
type_infered: string

tool: D44: Enter the nember of *row*:

tool: D29: %d

tool: D20: Enter the number of *column*:

tool: D15:   %lu  

assistant: ```c
int main(int argc, char const *argv[]) {
  int row = 1, column = 1;
  printf("Enter the nember of *row*:");
  scanf("%d", &row);
  printf("Enter the number of *column*:");
  scanf("%d", &column);
  for (size_t i = 1; i <= row; i++) {
    printf("\n");
    for (size_t j = 1; j <= column; j++) {
      printf("  %lu  ", i * j);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  je     L45
  mov    $0x1,%r12d
  lea    D21(%rip),%r13
L9:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x0,0x4(%rsp)
  je     L39
  mov    %r12,%rbp
  mov    $0x1,%ebx
L7:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  add    %r12,%rbp
  movslq 0x4(%rsp),%rax
  cmp    %rbx,%rax
  jae    L7
L39:
  add    $0x1,%r12
  movslq (%rsp),%rax
  cmp    %r12,%rax
  jae    L9
L45:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D1
type: string
name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D21
type: string

tool: D0: Enter the nember of *row*:

tool: D1: %d

tool: D14: Enter the number of *column*:

tool: D21:   %lu  

assistant: ```c
int main(int argc, char const *argv[]) {
  int row = 1, column = 1;
  printf("Enter the nember of *row*:");
  scanf("%d", &row);
  printf("Enter the number of *column*:");
  scanf("%d", &column);
  for (size_t i = 1; i <= row; i++) {
    printf("\n");
    for (size_t j = 1; j <= column; j++) {
      printf("  %lu  ", i * j);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  je     L37
  mov    $0x1,%r12d
  lea    D11(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L43:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L30
  mov    %r12,%rbp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  add    %r12,%rbp
  cmp    %rbx,%rax
  jae    L22
L30:
  movslq (%rsp),%rax
  add    $0x1,%r12
  cmp    %r12,%rax
  jae    L43
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string
name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D11
type_infered: string

tool: D25: Enter the nember of *row*:

tool: D3: %d

tool: D7: Enter the number of *column*:

tool: D11:   %lu  

assistant: ```c
int main(int argc, char const *argv[]) {
  int row = 1, column = 1;
  printf("Enter the nember of *row*:");
  scanf("%d", &row);
  printf("Enter the number of *column*:");
  scanf("%d", &column);
  for (size_t i = 1; i <= row; i++) {
    printf("\n");
    for (size_t j = 1; j <= column; j++) {
      printf("  %lu  ", i * j);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D12(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D32(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  je     L16
  mov    $0x1,%r12d
  lea    D7(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L45
  mov    %r12,%rbp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  movslq 0x4(%rsp),%rax
  add    %r12,%rbp
  cmp    %rbx,%rax
  jae    L36
L45:
  movslq (%rsp),%rax
  add    $0x1,%r12
  cmp    %r12,%rax
  jae    L2
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
datatype: string
name: disassemble_data
arguments: label: D32
datatype: string
name: disassemble_data
arguments: label: D10
datatype: string
name: disassemble_data
arguments: label: D7
datatype: string

tool: D12: Enter the nember of *row*:

tool: D32: %d

tool: D10: Enter the number of *column*:

tool: D7:   %lu  

assistant: ```c
int main(int argc, char const *argv[]) {
  int row = 1, column = 1;
  printf("Enter the nember of *row*:");
  scanf("%d", &row);
  printf("Enter the number of *column*:");
  scanf("%d", &column);
  for (size_t i = 1; i <= row; i++) {
    printf("\n");
    for (size_t j = 1; j <= column; j++) {
      printf("  %lu  ", i * j);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<build_total_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: /

assistant: ```c
char *build_total_path(char *infix, char *path) {
  char *final_path = malloc(strlen(infix) + strlen(path) + 2);
  strcpy(final_path, infix);
  strcat(final_path, "/");
  strcat(final_path, path);
  return final_path;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<build_total_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: /

assistant: ```c
char *build_total_path(char *infix, char *path) {
  char *final_path = malloc(strlen(infix) + strlen(path) + 2);
  strcpy(final_path, infix);
  strcat(final_path, "/");
  strcat(final_path, path);
  return final_path;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<build_total_path>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D8(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: /

assistant: ```c
char *build_total_path(char *infix, char *path) {
  char *final_path = malloc(strlen(infix) + strlen(path) + 2);
  strcpy(final_path, infix);
  strcat(final_path, "/");
  strcat(final_path, path);
  return final_path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<build_total_path>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  lea    D9(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: /

assistant: ```c
char *build_total_path(char *infix, char *path) {
  char *final_path = malloc(strlen(infix) + strlen(path) + 2);
  strcpy(final_path, infix);
  strcat(final_path, "/");
  strcat(final_path, path);
  return final_path;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x154(%rbp)
L2:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x154(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x154(%rbp),%eax
  test   %eax,%eax
  jle    L2
  mov    -0x154(%rbp),%eax
  cmp    $0x4f,%eax
  jg     L2
  mov    -0x154(%rbp),%edx
  lea    -0x150(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <leVETOR@plt>
  mov    -0x154(%rbp),%edx
  lea    -0x150(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quadradoVETOR@plt>
  mov    -0x154(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x150(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string

tool: D10: Introduza o n de inteiros a ler: 

tool: D12: %d

tool: D5: %d


assistant: ```c
int main() {
  int vetor[80], n = 0;
  do {
    printf("Introduza o n de inteiros a ler: ");
    scanf("%d", &n);
  } while (n < 1 || n >= 80);
  leVETOR(vetor, n);
  quadradoVETOR(vetor, n);
  printf("%d\n", vetor[n - 1]);
  return 0;
}
```