user: 下面的汇编指令对应的C源代码是什么:

```asm
<qstat_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x4c(%rbp),%eax
  add    $0x6,%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x38(%rbp)
  cmpl   $0x0,-0x38(%rbp)
  jg     L13
  mov    -0x4c(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <LOG_wrk@plt>
  mov    %rbx,%rsp
  jmp    L18
L13:
  mov    -0x38(%rbp),%eax
  imul   $0x52,%eax,%eax
  add    $0x14,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L74:
  cmp    %rdx,%rsp
  je     L51
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L74
L51:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L7
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L7:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x30(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,-0x30(%rbp)
  movl   $0x0,-0x3c(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x40(%rbp)
  jmp    L80
L82:
  mov    -0x30(%rbp),%rax
  mov    $0x5,%edx
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x5,-0x30(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    0x7(%rax),%edx
  mov    -0x4c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min_i@plt>
  mov    %eax,-0x34(%rbp)
  jmp    L94
L22:
  mov    -0x3c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <enc11@plt>
  addq   $0xb,-0x30(%rbp)
  addl   $0x1,-0x3c(%rbp)
L94:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L22
  addl   $0x1,-0x40(%rbp)
L80:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L82
  mov    -0x30(%rbp),%rax
  movb   $0x21,(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  movb   $0xa,(%rax)
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %rbx,%rsp
L18:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D14
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string

tool: D14: BUG: qstat_dump: n=%d

tool: D4: Q_^_Sc%d

tool: D25: 
Q_^<

assistant: ```c
void qstat_dump(const double *v, int n) {
  int i, j, k, n7 = (n + 6) / 7;
  if (n7 < 1)
    return LOG_wrk("BUG: qstat_dump: n=%d", n);
  char buf[82 * n7 + 20], *q = buf;
  q += sprintf(q, "Q_^_Sc%d", n);
  for (i = j = 0; i < n7; i++) {
    memcpy(q, "\nQ_^<", 5);
    q += 5;
    for (k = min_i(n, j + 7); j < k; j++)
      enc11(q, v[j]), q += 11;
  }
  q[0] = '!';
  q[1] = 10;
  write(1, buf, q + 2 - buf);
}
```