ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mdbm_strlcpy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    -0x1(%r13),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  cmp    %r13,%rax
  cmovb  %rax,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t mdbm_strlcpy(char *dst, const char *src, size_t dstlen) {
  size_t srclen = strlen(src);
  if (srclen >= dstlen) {
    srclen = dstlen - 1;
  }
  memcpy(dst, src, srclen);
  dst[srclen] = 0;
  return srclen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mdbm_strlcpy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    -0x1(%r13),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  cmp    %r13,%rax
  cmovb  %rax,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t mdbm_strlcpy(char *dst, const char *src, size_t dstlen) {
  size_t srclen = strlen(src);
  if (srclen >= dstlen) {
    srclen = dstlen - 1;
  }
  memcpy(dst, src, srclen);
  dst[srclen] = 0;
  return srclen;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<L1pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    $0x0,%ebx
  jmp    L6
L9:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  add    $0x1,%ebx
L6:
  mov    -0x34(%rbp),%eax
  imul   -0x38(%rbp),%eax
  cmp    %eax,%ebx
  jl     L9
  movsd  -0x10(%rbp),%xmm0
  divsd  -0x40(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double L1pos(const double *x, const double *pr, const double eps, const int nx, const int ny, const double flux) {
  register int i;
  double L1l = 0;
  for (i = 0; i < nx * ny; ++i) {
    L1l += x[i];
  }
  return L1l / flux;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<L1pos>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L27
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L1:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L1
L0:
  divsd  %xmm1,%xmm0
  ret
L27:
  pxor   %xmm0,%xmm0
  jmp    L0
```

assistant: ```c
double L1pos(const double *x, const double *pr, const double eps, const int nx, const int ny, const double flux) {
  register int i;
  double L1l = 0;
  for (i = 0; i < nx * ny; ++i) {
    L1l += x[i];
  }
  return L1l / flux;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<L1pos>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L17
  lea    -0x1(%rdx),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L12:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L12
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double L1pos(const double *x, const double *pr, const double eps, const int nx, const int ny, const double flux) {
  register int i;
  double L1l = 0;
  for (i = 0; i < nx * ny; ++i) {
    L1l += x[i];
  }
  return L1l / flux;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<L1pos>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L22
  cmp    $0x1,%edx
  je     L32
  mov    %edx,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L47:
  movsd  (%rax),%xmm2
  add    $0x10,%rax
  addsd  %xmm2,%xmm0
  movsd  -0x8(%rax),%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L47
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L12
L29:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
L12:
  divsd  %xmm1,%xmm0
  ret
L22:
  pxor   %xmm0,%xmm0
  divsd  %xmm1,%xmm0
  ret
L32:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
double L1pos(const double *x, const double *pr, const double eps, const int nx, const int ny, const double flux) {
  register int i;
  double L1l = 0;
  for (i = 0; i < nx * ny; ++i) {
    L1l += x[i];
  }
  return L1l / flux;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isoperator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x3d,-0x4(%rbp)
  je     L18
  cmpb   $0xa,-0x4(%rbp)
  je     L18
  mov    D0(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x4(%rbp)
  je     L18
  cmpb   $0x25,-0x4(%rbp)
  je     L18
  cmpb   $0x2b,-0x4(%rbp)
  je     L18
  cmpb   $0x2d,-0x4(%rbp)
  je     L18
  cmpb   $0x2a,-0x4(%rbp)
  je     L18
  cmpb   $0x2f,-0x4(%rbp)
  jne    L88
L18:
  mov    $0x1,%eax
  jmp    L33
L88:
  mov    $0x0,%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
unsigned short int isoperator(char c) {
  if (c == '=' || c == '\n' || c == EOF || c == '%' || c == '+' || c == '-' || c == '*' || c == '/') {
    return 1;
  } else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isoperator>:
  endbr64
  cmp    $0x3d,%dil
  je     L27
  cmp    $0xa,%dil
  je     L27
  mov    $0x1,%eax
  mov    D7(%rip),%rdx
  cmp    %dil,(%rdx)
  je     L31
  cmp    $0x2f,%dil
  ja     L38
  movabs $0xac2000000000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L27:
  mov    $0x1,%eax
  ret
L38:
  mov    $0x0,%eax
L31:
  ret
```

assistant: ```c
unsigned short int isoperator(char c) {
  if (c == '=' || c == '\n' || c == EOF || c == '%' || c == '+' || c == '-' || c == '*' || c == '/') {
    return 1;
  } else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isoperator>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3d,%dil
  je     L31
  cmp    $0xa,%dil
  je     L31
  mov    D5(%rip),%rdx
  cmp    %dil,(%rdx)
  je     L2
  cmp    $0x2f,%dil
  ja     L34
  movabs $0xac2000000000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
L2:
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  ret
```

assistant: ```c
unsigned short int isoperator(char c) {
  if (c == '=' || c == '\n' || c == EOF || c == '%' || c == '+' || c == '-' || c == '*' || c == '/') {
    return 1;
  } else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isoperator>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3d,%dil
  je     L39
  cmp    $0xa,%dil
  je     L39
  mov    D2(%rip),%rdx
  cmp    %dil,(%rdx)
  je     L4
  cmp    $0x2f,%dil
  ja     L37
  movabs $0xac2000000000,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %eax,%eax
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  ret
```

assistant: ```c
unsigned short int isoperator(char c) {
  if (c == '=' || c == '\n' || c == EOF || c == '%' || c == '+' || c == '-' || c == '*' || c == '/') {
    return 1;
  } else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <alocar@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L26
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L26:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ler@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <imprimir@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <liberar@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D15: Informe a quantidade: 

tool: D23: %d

tool: D6: Memoria insuficiente!


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, i;
  int *p;
  printf("Informe a quantidade: ");
  scanf("%d", &n);
  p = alocar(n);
  if (p == NULL) {
    printf("Memoria insuficiente!\n");
  } else {
    ler(p, n);
    imprimir(p, n);
    liberar(p);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <alocar@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbx
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  call   <ler@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  call   <imprimir@plt>
  mov    %rbx,%rdi
  call   <liberar@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D10
type_infered: string

tool: D6: Informe a quantidade: 

tool: D17: %d

tool: D10: Memoria insuficiente!


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, i;
  int *p;
  printf("Informe a quantidade: ");
  scanf("%d", &n);
  p = alocar(n);
  if (p == NULL) {
    printf("Memoria insuficiente!\n");
  } else {
    ler(p, n);
    imprimir(p, n);
    liberar(p);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D28(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <alocar@plt>
  test   %rax,%rax
  je     L9
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <ler@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <imprimir@plt>
  mov    %rbp,%rdi
  call   <liberar@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D28
type_infered: string
name: read_data
arguments: data_tag: D22
type_infered: string

tool: D4: Informe a quantidade: 

tool: D28: %d

tool: D22: Memoria insuficiente!


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, i;
  int *p;
  printf("Informe a quantidade: ");
  scanf("%d", &n);
  p = alocar(n);
  if (p == NULL) {
    printf("Memoria insuficiente!\n");
  } else {
    ler(p, n);
    imprimir(p, n);
    liberar(p);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <alocar@plt>
  test   %rax,%rax
  je     L23
  mov    0x4(%rsp),%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <ler@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <imprimir@plt>
  mov    %rbp,%rdi
  call   <liberar@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D20
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D20: Informe a quantidade: 

tool: D13: %d

tool: D26: Memoria insuficiente!


assistant: ```c
int main(int argc, char const *argv[]) {
  int n, i;
  int *p;
  printf("Informe a quantidade: ");
  scanf("%d", &n);
  p = alocar(n);
  if (p == NULL) {
    printf("Memoria insuficiente!\n");
  } else {
    ler(p, n);
    imprimir(p, n);
    liberar(p);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<numbtrop_standard_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %rdx,-0x60(%rbp)
  mov    %rcx,-0x68(%rbp)
  mov    %r8,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x58(%rbp),%eax
  add    $0x1,%eax
  imul   -0x54(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x40(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L39:
  cmp    %rdx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L39
L54:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L61
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L61:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x54(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x58(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L25
L76:
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x38(%rbp),%rax
  mov    -0x48(%rbp),%edx
  movslq %edx,%rdx
  movsd  %xmm0,(%rax,%rdx,8)
  addl   $0x1,-0x48(%rbp)
L25:
  mov    -0x54(%rbp),%eax
  imul   -0x58(%rbp),%eax
  cmp    %eax,-0x48(%rbp)
  jl     L76
  movl   $0x0,-0x48(%rbp)
  jmp    L48
L59:
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x70(%rbp),%rax
  add    %rax,%rdx
  mov    -0x54(%rbp),%eax
  imul   -0x58(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x48(%rbp),%eax
  add    %eax,%ecx
  movsd  (%rdx),%xmm0
  mov    -0x38(%rbp),%rax
  movslq %ecx,%rdx
  movsd  %xmm0,(%rax,%rdx,8)
  addl   $0x1,-0x48(%rbp)
L48:
  mov    -0x48(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L59
  mov    -0x38(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2c7,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int numbtrop_standard_initialize(int nbt, int dim, int *wnd, double *dir, double *err) {
  int fail, k;
  int nd[2];
  double cff[nbt * (dim + 1)];
  nd[0] = nbt;
  nd[1] = dim;
  for (k = 0; k < nbt * dim; k++)
    cff[k] = dir[k];
  for (k = 0; k < nbt; k++)
    cff[nbt * dim + k] = err[k];
  fail = _ada_use_c2phc(711, nd, wnd, cff);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<numbtrop_standard_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdx,%r10
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x1(%rsi),%r9d
  imul   %edi,%r9d
  movslq %r9d,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%r11
  and    $0xfffffffffffffff0,%r11
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L69:
  cmp    %rcx,%rsp
  je     L3
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L69
L3:
  mov    %r11,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L75
  orq    $0x0,-0x8(%rsp,%rax,1)
L75:
  mov    %rsp,%rcx
  mov    %edi,-0x10(%rbp)
  mov    %esi,-0xc(%rbp)
  sub    %edi,%r9d
  test   %r9d,%r9d
  jle    L67
  mov    %r9d,%esi
  mov    $0x0,%eax
L2:
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
L67:
  test   %edi,%edi
  jle    L61
  mov    %edi,%edx
  movslq %r9d,%r9
  lea    (%rcx,%r9,8),%rsi
  mov    $0x0,%eax
L55:
  movsd  (%r8,%rax,8),%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L55
L61:
  lea    -0x10(%rbp),%rsi
  mov    %r10,%rdx
  mov    $0x2c7,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  leave
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numbtrop_standard_initialize(int nbt, int dim, int *wnd, double *dir, double *err) {
  int fail, k;
  int nd[2];
  double cff[nbt * (dim + 1)];
  nd[0] = nbt;
  nd[1] = dim;
  for (k = 0; k < nbt * dim; k++)
    cff[k] = dir[k];
  for (k = 0; k < nbt; k++)
    cff[nbt * dim + k] = err[k];
  fail = _ada_use_c2phc(711, nd, wnd, cff);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<numbtrop_standard_initialize>:
  endbr64
  push   %rbp
  mov    %rcx,%r9
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbx
  imul   %edi,%r12d
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %r12d,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L55
L66:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L66
L55:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L40
L36:
  sub    %ebx,%r12d
  mov    %ebx,-0x40(%rbp)
  mov    %rsp,%r15
  mov    %esi,-0x3c(%rbp)
  test   %r12d,%r12d
  jle    L6
  movslq %r12d,%rdx
  mov    %r9,%rsi
  mov    %r15,%rdi
  shl    $0x3,%rdx
  call   <memcpy@plt>
L6:
  test   %ebx,%ebx
  jle    L14
  movslq %r12d,%r12
  movslq %ebx,%rdx
  mov    %r14,%rsi
  lea    (%r15,%r12,8),%rdi
  shl    $0x3,%rdx
  call   <memcpy@plt>
L14:
  mov    %r13,%rdx
  lea    -0x40(%rbp),%rsi
  mov    %r15,%rcx
  mov    $0x2c7,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L40:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L36
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numbtrop_standard_initialize(int nbt, int dim, int *wnd, double *dir, double *err) {
  int fail, k;
  int nd[2];
  double cff[nbt * (dim + 1)];
  nd[0] = nbt;
  nd[1] = dim;
  for (k = 0; k < nbt * dim; k++)
    cff[k] = dir[k];
  for (k = 0; k < nbt; k++)
    cff[nbt * dim + k] = err[k];
  fail = _ada_use_c2phc(711, nd, wnd, cff);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numbtrop_standard_initialize>:
  endbr64
  push   %rbp
  mov    %rcx,%r9
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  lea    0x1(%rsi),%r12d
  push   %rbx
  imul   %edi,%r12d
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %r12d,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L12
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L16
L12:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L33
L38:
  movd   %ebx,%xmm0
  movd   %esi,%xmm1
  sub    %ebx,%r12d
  mov    %rsp,%r15
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x40(%rbp)
  test   %r12d,%r12d
  jle    L31
  movslq %r12d,%rdx
  mov    %r9,%rsi
  mov    %r15,%rdi
  shl    $0x3,%rdx
  call   <memcpy@plt>
L31:
  test   %ebx,%ebx
  jle    L67
  movslq %r12d,%r12
  movslq %ebx,%rdx
  mov    %r14,%rsi
  lea    (%r15,%r12,8),%rdi
  shl    $0x3,%rdx
  call   <memcpy@plt>
L67:
  mov    %r13,%rdx
  lea    -0x40(%rbp),%rsi
  mov    %r15,%rcx
  mov    $0x2c7,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L38
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numbtrop_standard_initialize(int nbt, int dim, int *wnd, double *dir, double *err) {
  int fail, k;
  int nd[2];
  double cff[nbt * (dim + 1)];
  nd[0] = nbt;
  nd[1] = dim;
  for (k = 0; k < nbt * dim; k++)
    cff[k] = dir[k];
  for (k = 0; k < nbt; k++)
    cff[nbt * dim + k] = err[k];
  fail = _ada_use_c2phc(711, nd, wnd, cff);
  return fail;
}
```