ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<MD5_Final>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x30(%rsi),%rbp
  mov    (%rsi),%rax
  mov    D3(%rip),%r12
  movb   $0x80,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  mov    (%r12),%edx
  lea    0x0(%rbp,%rax,1),%rdi
  mov    %eax,%esi
  lea    -0x8(%rdx),%ecx
  movslq %ecx,%rcx
  cmp    %rax,%rcx
  jb     L10
L3:
  sub    %esi,%edx
  xor    %esi,%esi
  sub    $0x8,%edx
  call   <memset@plt>
  movslq (%r12),%rax
  mov    0x8(%rbx),%edx
  mov    %rbx,%rdi
  lea    -0x8(%rbp,%rax,1),%rax
  mov    %edx,(%rax)
  mov    0xc(%rbx),%edx
  lea    0x8(%rax),%rbp
  mov    %edx,0x4(%rax)
  movslq (%r12),%rax
  mov    $0x1,%edx
  sub    %rax,%rbp
  mov    %rbp,%rsi
  call   <md5_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  movq   $0x0,(%rbx)
  call   <memset@plt>
  movdqu 0x10(%rbx),%xmm0
  movdqu 0x20(%rbx),%xmm1
  mov    $0x1,%eax
  shufps $0x88,%xmm1,%xmm0
  movups %xmm0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L10:
  sub    %eax,%edx
  xor    %esi,%esi
  call   <memset@plt>
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <md5_block_data_order@plt>
  mov    (%r12),%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  jmp    L3
```

assistant: ```c
int MD5_Final(unsigned char *md, MD5_CTX *c) {
  unsigned char *p = (unsigned char *)c->data;
  size_t n = c->num;
  p[n] = 0x80;
  n++;
  if (n > (MD5_CBLOCK - 8)) {
    memset(p + n, 0, MD5_CBLOCK - n);
    n = 0;
    md5_block_data_order(c, p, 1);
  }
  memset(p + n, 0, MD5_CBLOCK - 8 - n);
  p += MD5_CBLOCK - 8;
  (*((unsigned int *)(p)) = (c->Nl), (p) += 4);
  (*((unsigned int *)(p)) = (c->Nh), (p) += 4);
  p -= MD5_CBLOCK;
  md5_block_data_order(c, p, 1);
  c->num = 0;
  memset(p, 0, MD5_CBLOCK);
  do {
    unsigned long ll;
    ll = (c)->A;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->B;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->C;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
    ll = (c)->D;
    (void)(*((unsigned int *)((md))) = (ll), ((md)) += 4);
  } while (0);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D29
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string
name: disassemble_data
arguments: data_tag: D37
datatype: string

tool: D2: Don't be a fool!

tool: D29: %s


tool: D4: mesg = %s; &mesg = %p; value = %p


tool: D37: copy = %s; &copy = %p; value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool!";
  const char *copy;
  copy = mesg;
  printf("%s\n", copy);
  printf("mesg = %s; &mesg = %p; value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s; &copy = %p; value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rsi
  mov    %rsi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rdx
  mov    %rsi,%rcx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  mov    %rsi,%rcx
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type_guessed: string
name: retrieve_data
arguments: data_label: D10
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D28
type_guessed: string

tool: D27: Don't be a fool!

tool: D10: %s


tool: D9: mesg = %s; &mesg = %p; value = %p


tool: D28: copy = %s; &copy = %p; value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool!";
  const char *copy;
  copy = mesg;
  printf("%s\n", copy);
  printf("mesg = %s; &mesg = %p; value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s; &copy = %p; value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rsi
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    D6(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: string
name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D37
type: string
name: disassemble_data
arguments: data_label: D6
type: string

tool: D2: Don't be a fool!

tool: D13: %s


tool: D37: mesg = %s; &mesg = %p; value = %p


tool: D6: copy = %s; &copy = %p; value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool!";
  const char *copy;
  copy = mesg;
  printf("%s\n", copy);
  printf("mesg = %s; &mesg = %p; value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s; &copy = %p; value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D24(%rip),%rsi
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    D22(%rip),%rdi
  mov    %rsi,%rcx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D7
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string

tool: D24: Don't be a fool!

tool: D7: %s


tool: D29: mesg = %s; &mesg = %p; value = %p


tool: D22: copy = %s; &copy = %p; value = %p


assistant: ```c
int main(void) {
  const char *mesg = "Don't be a fool!";
  const char *copy;
  copy = mesg;
  printf("%s\n", copy);
  printf("mesg = %s; &mesg = %p; value = %p\n", mesg, &mesg, mesg);
  printf("copy = %s; &copy = %p; value = %p\n", copy, &copy, copy);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Test6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x320(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int Test6() {
  int B[200];
  return B[4];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Test6>:
  endbr64
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    0x10(%rsp),%eax
  mov    0x328(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x338,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Test6() {
  int B[200];
  return B[4];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Test6>:
  endbr64
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  mov    0x10(%rsp),%eax
  mov    0x328(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x338,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Test6() {
  int B[200];
  return B[4];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Test6>:
  endbr64
  sub    $0x338,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  mov    0x10(%rsp),%eax
  mov    0x328(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x338,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Test6() {
  int B[200];
  return B[4];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Printfloat8>:
  endbr64
  movq   %xmm0,%rdx
  movd   %xmm0,%ecx
  movq   %xmm0,%rax
  shr    $0x20,%rax
  mov    %eax,%esi
  test   %edx,%edx
  sete   %dl
  cmp    $0x7f800000,%rax
  jne    L4
  test   %dl,%dl
  jne    L72
L4:
  cmp    $0xff800000,%eax
  jne    L0
  test   %dl,%dl
  jne    L59
L0:
  sub    $0x8,%rsp
  and    $0xfff00000,%eax
  cmp    $0x7ff00000,%eax
  je     L87
  cmp    $0xfff00000,%eax
  je     L53
  ucomisd D17(%rip),%xmm0
  jp     L105
  jne    L105
  movl   $0x302e30,(%rdi)
  mov    $0x3,%eax
L108:
  add    $0x8,%rsp
  ret
L72:
  movabs $0x38463720464e492b,%rax
  movabs $0x3030203030303030,%rdx
  mov    %rax,(%rdi)
  mov    %rdx,0x8(%rdi)
  movl   $0x30303030,0x10(%rdi)
  movw   $0x3030,0x14(%rdi)
  movb   $0x0,0x16(%rdi)
  mov    $0x16,%eax
  ret
L59:
  movabs $0x38464620464e492d,%rax
  movabs $0x3030203030303030,%rdx
  mov    %rax,(%rdi)
  mov    %rdx,0x8(%rdi)
  movl   $0x30303030,0x10(%rdi)
  movw   $0x3030,0x14(%rdi)
  movb   $0x0,0x16(%rdi)
  mov    $0x16,%eax
  ret
L87:
  mov    %esi,%edx
  lea    D16(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    $0x1a,%eax
  jmp    L108
L53:
  mov    %esi,%edx
  lea    D1(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    $0x1a,%eax
  jmp    L108
L105:
  lea    D13(%rip),%rsi
  mov    $0x1,%eax
  call   <sprintf@plt>
  jmp    L108
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: f64
name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string

tool: D17: 0

tool: D16: +NAN 0x%08X 0x%08X

tool: D1: -NAN 0x%08X 0x%08X

tool: D13: %#.16lg

assistant: ```c
int Printfloat8(char *s, double d) {
  int k;
  unsigned int lod, hid;
  lod = ((unsigned int *)&d)[0];
  hid = ((unsigned int *)&d)[1];
  if (lod == 0 && hid == 0x7F800000L)
    k = sprintf(s, "+INF 7F800000 00000000");
  else if (lod == 0 && hid == 0xFF800000L)
    k = sprintf(s, "-INF FF800000 00000000");
  else if ((hid & 0xFFF00000L) == 0x7FF00000)
    k = sprintf(s,
                "+NAN "
                "0x%08X"
                " "
                "0x%08X",
                hid, lod);
  else if ((hid & 0xFFF00000L) == 0xFFF00000)
    k = sprintf(s,
                "-NAN "
                "0x%08X"
                " "
                "0x%08X",
                hid, lod);
  else if (d == 0.0)
    k = sprintf(s, "0.0");
  else
    k = sprintf(s, "%#.16lg", d);
  return k;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Printfloat8>:
  endbr64
  movq   %xmm0,%rdx
  movq   %xmm0,%rax
  movd   %xmm0,%ecx
  shr    $0x20,%rax
  test   %edx,%edx
  mov    %eax,%r8d
  sete   %dl
  cmp    $0x7f800000,%rax
  jne    L17
  test   %dl,%dl
  jne    L67
L17:
  cmp    $0xff800000,%eax
  jne    L77
  test   %dl,%dl
  je     L77
  movdqa D26(%rip),%xmm0
L101:
  mov    $0x3030,%eax
  movl   $0x30303030,0x10(%rdi)
  mov    %ax,0x14(%rdi)
  mov    $0x16,%eax
  movb   $0x0,0x16(%rdi)
  movups %xmm0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  movdqa D32(%rip),%xmm0
  jmp    L101
  nopw   0x0(%rax,%rax,1)
L77:
  and    $0xfff00000,%eax
  sub    $0x8,%rsp
  cmp    $0x7ff00000,%eax
  je     L65
  cmp    $0xfff00000,%eax
  je     L25
  ucomisd D57(%rip),%xmm0
  jp     L97
  jne    L97
  movl   $0x302e30,(%rdi)
  mov    $0x3,%eax
L103:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L97:
  lea    D6(%rip),%rsi
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L65:
  mov    %r8d,%edx
  lea    D52(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    $0x1a,%eax
  jmp    L103
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r8d,%edx
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    $0x1a,%eax
  jmp    L103
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type: byte[16]
name: unpack_data
arguments: data_tag: D32
type: byte[16]
name: unpack_data
arguments: data_tag: D57
type: f64
name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D52
type: string
name: unpack_data
arguments: data_tag: D8
type: string

tool: {"D26": [0x2d,0x49,0x4e,0x46,0x20,0x46,0x46,0x38,0x30,0x30,0x30,0x30,0x30,0x20,0x30,0x30]}

tool: {"D32": [0x2b,0x49,0x4e,0x46,0x20,0x37,0x46,0x38,0x30,0x30,0x30,0x30,0x30,0x20,0x30,0x30]}

tool: D57: 0

tool: D6: %#.16lg

tool: D52: +NAN 0x%08X 0x%08X

tool: D8: -NAN 0x%08X 0x%08X

assistant: ```c
int Printfloat8(char *s, double d) {
  int k;
  unsigned int lod, hid;
  lod = ((unsigned int *)&d)[0];
  hid = ((unsigned int *)&d)[1];
  if (lod == 0 && hid == 0x7F800000L)
    k = sprintf(s, "+INF 7F800000 00000000");
  else if (lod == 0 && hid == 0xFF800000L)
    k = sprintf(s, "-INF FF800000 00000000");
  else if ((hid & 0xFFF00000L) == 0x7FF00000)
    k = sprintf(s,
                "+NAN "
                "0x%08X"
                " "
                "0x%08X",
                hid, lod);
  else if ((hid & 0xFFF00000L) == 0xFFF00000)
    k = sprintf(s,
                "-NAN "
                "0x%08X"
                " "
                "0x%08X",
                hid, lod);
  else if (d == 0.0)
    k = sprintf(s, "0.0");
  else
    k = sprintf(s, "%#.16lg", d);
  return k;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Printfloat8>:
  endbr64
  movq   %xmm0,%rdx
  movq   %xmm0,%rax
  movd   %xmm0,%ecx
  shr    $0x20,%rax
  test   %edx,%edx
  mov    %eax,%r8d
  sete   %dl
  cmp    $0x7f800000,%rax
  jne    L69
  test   %dl,%dl
  jne    L76
L69:
  cmp    $0xff800000,%eax
  jne    L82
  test   %dl,%dl
  je     L82
  movdqa D23(%rip),%xmm0
L83:
  mov    $0x3030,%eax
  movl   $0x30303030,0x10(%rdi)
  mov    %ax,0x14(%rdi)
  mov    $0x16,%eax
  movb   $0x0,0x16(%rdi)
  movups %xmm0,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L76:
  movdqa D15(%rip),%xmm0
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L82:
  and    $0xfff00000,%eax
  sub    $0x8,%rsp
  cmp    $0x7ff00000,%eax
  je     L47
  cmp    $0xfff00000,%eax
  je     L10
  ucomisd D29(%rip),%xmm0
  jp     L63
  jne    L63
  movl   $0x302e30,(%rdi)
  mov    $0x3,%eax
L45:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  lea    D59(%rip),%rsi
  mov    $0x1,%eax
  add    $0x8,%rsp
  jmp    1050 <sprintf@plt>
  nopl   (%rax)
L47:
  mov    %r8d,%edx
  lea    D43(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    $0x1a,%eax
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r8d,%edx
  lea    D41(%rip),%rsi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    $0x1a,%eax
  jmp    L45
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: byte[16]
name: disassemble_data
arguments: label: D15
data_type: byte[16]
name: disassemble_data
arguments: label: D29
data_type: f64
name: disassemble_data
arguments: label: D59
data_type: string
name: disassemble_data
arguments: label: D43
data_type: string
name: disassemble_data
arguments: label: D41
data_type: string

tool: {"D23": [0x2d,0x49,0x4e,0x46,0x20,0x46,0x46,0x38,0x30,0x30,0x30,0x30,0x30,0x20,0x30,0x30]}

tool: {"D15": [0x2b,0x49,0x4e,0x46,0x20,0x37,0x46,0x38,0x30,0x30,0x30,0x30,0x30,0x20,0x30,0x30]}

tool: D29: 0

tool: D59: %#.16lg

tool: D43: +NAN 0x%08X 0x%08X

tool: D41: -NAN 0x%08X 0x%08X

assistant: ```c
int Printfloat8(char *s, double d) {
  int k;
  unsigned int lod, hid;
  lod = ((unsigned int *)&d)[0];
  hid = ((unsigned int *)&d)[1];
  if (lod == 0 && hid == 0x7F800000L)
    k = sprintf(s, "+INF 7F800000 00000000");
  else if (lod == 0 && hid == 0xFF800000L)
    k = sprintf(s, "-INF FF800000 00000000");
  else if ((hid & 0xFFF00000L) == 0x7FF00000)
    k = sprintf(s,
                "+NAN "
                "0x%08X"
                " "
                "0x%08X",
                hid, lod);
  else if ((hid & 0xFFF00000L) == 0xFFF00000)
    k = sprintf(s,
                "-NAN "
                "0x%08X"
                " "
                "0x%08X",
                hid, lod);
  else if (d == 0.0)
    k = sprintf(s, "0.0");
  else
    k = sprintf(s, "%#.16lg", d);
  return k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printAt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ubrk_following@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ubrk_previous@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printTextRange@plt>
  nop
  leave
  ret
```

assistant: ```c
void printAt(UBreakIterator *boundary, int32_t pos, UChar *str) {
  int32_t start;
  int32_t end = ubrk_following(boundary, pos);
  start = ubrk_previous(boundary);
  printTextRange(str, start, end);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printAt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  call   <ubrk_following@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <ubrk_previous@plt>
  mov    %eax,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <printTextRange@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printAt(UBreakIterator *boundary, int32_t pos, UChar *str) {
  int32_t start;
  int32_t end = ubrk_following(boundary, pos);
  start = ubrk_previous(boundary);
  printTextRange(str, start, end);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printAt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ubrk_following@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <ubrk_previous@plt>
  pop    %rbp
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  pop    %r12
  pop    %r13
  jmp    1070 <printTextRange@plt>
```

assistant: ```c
void printAt(UBreakIterator *boundary, int32_t pos, UChar *str) {
  int32_t start;
  int32_t end = ubrk_following(boundary, pos);
  start = ubrk_previous(boundary);
  printTextRange(str, start, end);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printAt>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <ubrk_following@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <ubrk_previous@plt>
  pop    %rbp
  mov    %r13d,%edx
  mov    %r12,%rdi
  mov    %eax,%esi
  pop    %r12
  pop    %r13
  jmp    1070 <printTextRange@plt>
```

assistant: ```c
void printAt(UBreakIterator *boundary, int32_t pos, UChar *str) {
  int32_t start;
  int32_t end = ubrk_following(boundary, pos);
  start = ubrk_previous(boundary);
  printTextRange(str, start, end);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pvUseLibrary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %al,-0x4(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: f

assistant: ```c
int pvUseLibrary(char byBoardNum, char *szLibName) {
  notify_pvcall("f");
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pvUseLibrary>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: f

assistant: ```c
int pvUseLibrary(char byBoardNum, char *szLibName) {
  notify_pvcall("f");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pvUseLibrary>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string

tool: D7: f

assistant: ```c
int pvUseLibrary(char byBoardNum, char *szLibName) {
  notify_pvcall("f");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pvUseLibrary>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type: string

tool: D0: f

assistant: ```c
int pvUseLibrary(char byBoardNum, char *szLibName) {
  notify_pvcall("f");
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L49
L37:
  cmpl   $0x9,-0x4(%rbp)
  jne    L68
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L49
L68:
  cmpl   $0x8,-0x4(%rbp)
  jne    L18
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L49
L18:
  cmpl   $0x5c,-0x4(%rbp)
  jne    L11
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
  jmp    L49
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L49:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L37
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\t') {
      putchar('\\');
      putchar('t');
    } else if (c == '\b') {
      putchar('\\');
      putchar('b');
    } else if (c == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(c);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L8
L65:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x74,%edi
  call   <putchar@plt>
  jmp    L8
L0:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x62,%edi
  call   <putchar@plt>
  jmp    L8
L45:
  mov    $0x5c,%edi
  call   <putchar@plt>
  mov    $0x5c,%edi
  call   <putchar@plt>
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D5(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L59
  cmp    $0x9,%eax
  je     L65
  cmp    $0x8,%eax
  je     L0
  cmp    $0x5c,%eax
  je     L45
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L8
L59:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int c = 0;
  while ((c = getchar()) != EOF) {
    if (c == '\t') {
      putchar('\\');
      putchar('t');
    } else if (c == '\b') {
      putchar('\\');
      putchar('b');
    } else if (c == '\\') {
      putchar('\\');
      putchar('\\');
    } else {
      putchar(c);
    }
  }
}
```