ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<multiply144>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L8
L10:
  movl   $0x0,-0x3c(%rbp)
  jmp    L30
L13:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L30:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L13
  addl   $0x1,-0x40(%rbp)
L8:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L10
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply144(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply144>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L29:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L3:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L3
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  ret
```

assistant: ```c
void multiply144(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<multiply144>:
  endbr64
  test   %edi,%edi
  jle    L28
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L21
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L1
  pop    %rbx
  ret
L28:
  ret
```

assistant: ```c
void multiply144(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply144>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L44
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L65:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L97
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L97
  nopl   0x0(%rax)
L94:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L94
  cmp    -0x24(%rsp),%r11d
  je     L8
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L8
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L8
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L8:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L65
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L97:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L57:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L57
  mov    -0x18(%rsp),%r8
  jmp    L8
```

assistant: ```c
void multiply144(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0xc(%rbp)
  jmp    L26
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D14
data_type: string

tool: D17: %d

tool: D14: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 2; i <= 2 * n; i += 2)
    printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    $0x1,%eax
  jle    L23
  mov    $0x2,%ebx
  lea    D11(%rip),%rbp
L15:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x2,%ebx
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jge    L15
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D19: %d

tool: D11: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 2; i <= 2 * n; i += 2)
    printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    $0x1,%eax
  jle    L17
  mov    $0x2,%ebx
  lea    D9(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jge    L6
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string

tool: D2: %d

tool: D9: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 2; i <= 2 * n; i += 2)
    printf("%d\n", i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    $0x1,%eax
  jle    L24
  mov    $0x2,%ebx
  lea    D19(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    %eax,%eax
  cmp    %ebx,%eax
  jge    L4
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D17: %d

tool: D19: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 2; i <= 2 * n; i += 2)
    printf("%d\n", i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sk_atomic_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int32_t sk_atomic_add(int32_t *addr, int32_t inc) {
  int32_t value = *addr;
  *addr = value + inc;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sk_atomic_add>:
  endbr64
  mov    (%rdi),%rax
  add    %rax,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
int32_t sk_atomic_add(int32_t *addr, int32_t inc) {
  int32_t value = *addr;
  *addr = value + inc;
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sk_atomic_add>:
  endbr64
  mov    (%rdi),%rax
  add    %rax,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
int32_t sk_atomic_add(int32_t *addr, int32_t inc) {
  int32_t value = *addr;
  *addr = value + inc;
  return value;
}
```
user: What is the c source code of the assembly code below?

```asm
<sk_atomic_add>:
  endbr64
  mov    (%rdi),%rax
  add    %rax,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
int32_t sk_atomic_add(int32_t *addr, int32_t inc) {
  int32_t value = *addr;
  *addr = value + inc;
  return value;
}
```
user: What is the c source code of the assembly code below?

```asm
<liste_referentiel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <creation_fichier_liste@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ajout_info_liste@plt>
  jmp    L5
L19:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ecriture_s@plt>
L5:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <lecture@plt>
  cmp    $0x1,%eax
  je     L19
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: liste_ref

assistant: ```c
void liste_referentiel(int ta_socket) {
  int liste_ref = creation_fichier_liste("liste_ref");
  ajout_info_liste(liste_ref);
  while (lecture("liste_ref") == 1)
    ecriture_s(ta_socket);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<liste_referentiel>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    D0(%rip),%rdi
  call   <creation_fichier_liste@plt>
  mov    %eax,%edi
  call   <ajout_info_liste@plt>
  lea    D0(%rip),%rbp
  jmp    L4
L7:
  mov    %ebx,%edi
  call   <ecriture_s@plt>
L4:
  mov    %rbp,%rdi
  call   <lecture@plt>
  cmp    $0x1,%eax
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0: liste_ref

assistant: ```c
void liste_referentiel(int ta_socket) {
  int liste_ref = creation_fichier_liste("liste_ref");
  ajout_info_liste(liste_ref);
  while (lecture("liste_ref") == 1)
    ecriture_s(ta_socket);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<liste_referentiel>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <creation_fichier_liste@plt>
  mov    %eax,%edi
  call   <ajout_info_liste@plt>
  jmp    L13
  nopl   0x0(%rax)
L8:
  mov    %ebp,%edi
  call   <ecriture_s@plt>
L13:
  mov    %rbx,%rdi
  call   <lecture@plt>
  cmp    $0x1,%eax
  je     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: liste_ref

assistant: ```c
void liste_referentiel(int ta_socket) {
  int liste_ref = creation_fichier_liste("liste_ref");
  ajout_info_liste(liste_ref);
  while (lecture("liste_ref") == 1)
    ecriture_s(ta_socket);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<liste_referentiel>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <creation_fichier_liste@plt>
  mov    %eax,%edi
  call   <ajout_info_liste@plt>
  jmp    L19
  nopl   0x0(%rax)
L12:
  mov    %ebp,%edi
  call   <ecriture_s@plt>
L19:
  mov    %rbx,%rdi
  call   <lecture@plt>
  cmp    $0x1,%eax
  je     L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: liste_ref

assistant: ```c
void liste_referentiel(int ta_socket) {
  int liste_ref = creation_fichier_liste("liste_ref");
  ajout_info_liste(liste_ref);
  while (lecture("liste_ref") == 1)
    ecriture_s(ta_socket);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b1_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    %eax,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  nop
  leave
  ret
```

assistant: ```c
void b1_reset(unsigned int base) {
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
  b1outp(base, 0x10, 1);
  mdelay(55 * 2);
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<b1_reset>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    $0x10,%esi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    $0x1,%edx
  mov    $0x10,%esi
  mov    %ebx,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    %ebx,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  pop    %rbx
  ret
```

assistant: ```c
void b1_reset(unsigned int base) {
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
  b1outp(base, 0x10, 1);
  mdelay(55 * 2);
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
}
```
user: What is the c source code of the assembly code below:

```asm
<b1_reset>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x10,%esi
  mov    %edi,%ebp
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    $0x1,%edx
  mov    $0x10,%esi
  mov    %ebp,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    %ebp,%edi
  xor    %edx,%edx
  mov    $0x10,%esi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  pop    %rbp
  jmp    1060 <mdelay@plt>
```

assistant: ```c
void b1_reset(unsigned int base) {
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
  b1outp(base, 0x10, 1);
  mdelay(55 * 2);
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<b1_reset>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    $0x10,%esi
  mov    %edi,%ebp
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    $0x1,%edx
  mov    $0x10,%esi
  mov    %ebp,%edi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  call   <mdelay@plt>
  mov    %ebp,%edi
  xor    %edx,%edx
  mov    $0x10,%esi
  call   <b1outp@plt>
  mov    $0x6e,%edi
  pop    %rbp
  jmp    1060 <mdelay@plt>
```

assistant: ```c
void b1_reset(unsigned int base) {
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
  b1outp(base, 0x10, 1);
  mdelay(55 * 2);
  b1outp(base, 0x10, 0);
  mdelay(55 * 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<listSheet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L15:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L52
L54:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L52
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L38
  jmp    L52
L38:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L52:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L54
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D38
datatype: string
name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D25
datatype: string

tool: D12: listSheet: %s

tool: D38: Available cheatsheets:

tool: D15: .

tool: D25: ..

assistant: ```c
void listSheet(char *dr) {
  DIR *d;
  struct dirent *dir;
  d = opendir(dr);
  if (!d)
    err(1, "listSheet: %s", dr);
  printf("Available cheatsheets:\n");
  while ((dir = readdir(d)) != NULL)
    if (!strcmp(dir->d_name, ".") || !(strcmp(dir->d_name, "..")))
      continue;
    else
      printf("%s\n", dir->d_name);
  (void)closedir(d);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<listSheet>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L50
L24:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%r12
  lea    D22(%rip),%r13
L8:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L43
  mov    (%rax),%rbx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L8
L50:
  mov    %rbx,%rdx
  lea    D7(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L24
L43:
  mov    %rbp,%rdi
  call   <closedir@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
datatype: string
name: extract_symbolic_data
arguments: label: D4
datatype: string
name: extract_symbolic_data
arguments: label: D22
datatype: string
name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D27: Available cheatsheets:

tool: D4: .

tool: D22: ..

tool: D7: listSheet: %s

assistant: ```c
void listSheet(char *dr) {
  DIR *d;
  struct dirent *dir;
  d = opendir(dr);
  if (!d)
    err(1, "listSheet: %s", dr);
  printf("Available cheatsheets:\n");
  while ((dir = readdir(d)) != NULL)
    if (!strcmp(dir->d_name, ".") || !(strcmp(dir->d_name, "..")))
      continue;
    else
      printf("%s\n", dir->d_name);
  (void)closedir(d);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<listSheet>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L60
L9:
  lea    D8(%rip),%rdi
  call   <puts@plt>
L8:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L80
L70:
  mov    (%rax),%rdi
  cmpb   $0x2e,(%rdi)
  jne    L24
  cmpb   $0x0,0x1(%rdi)
  je     L8
L24:
  cmpb   $0x2e,(%rdi)
  jne    L20
  cmpb   $0x2e,0x1(%rdi)
  jne    L20
  cmpb   $0x0,0x2(%rdi)
  je     L8
  nopl   0x0(%rax,%rax,1)
L20:
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L70
L80:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <closedir@plt>
  nopl   0x0(%rax)
L60:
  mov    %r12,%rdx
  lea    D14(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string

tool: D8: Available cheatsheets:

tool: D14: listSheet: %s

assistant: ```c
void listSheet(char *dr) {
  DIR *d;
  struct dirent *dir;
  d = opendir(dr);
  if (!d)
    err(1, "listSheet: %s", dr);
  printf("Available cheatsheets:\n");
  while ((dir = readdir(d)) != NULL)
    if (!strcmp(dir->d_name, ".") || !(strcmp(dir->d_name, "..")))
      continue;
    else
      printf("%s\n", dir->d_name);
  (void)closedir(d);
  return;
}
```