user: What would the C source look like for the assembly code provided here?

```asm
<PartitionDispositionRipetitionR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rdx,%r15
  lea    0x0(,%r8,8),%rdx
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %r9,-0x58(%rbp)
  mov    %rsp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rsi
  cmp    %rdi,%rsp
  je     L203
L245:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L245
L203:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L104
L1:
  mov    %rsp,%rdi
  test   %r14,%r14
  je     L171
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rdi
  cmp    %r13,%rbx
  jb     L138
  test   %r13,%r13
  je     L113
L5:
  mov    %r15,%rax
  lea    (%r15,%r13,4),%rsi
  nopl   0x0(%rax)
L240:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addq   $0x1,(%rdi,%rdx,8)
  cmp    %rsi,%rax
  jne    L240
  test   %r14,%r14
  je     L64
L113:
  xor    %ebx,%ebx
  jmp    L144
  xchg   %ax,%ax
L154:
  lea    0x1(%rbx),%rax
  cmp    %rax,%r14
  je     L185
  mov    %rax,%rbx
L144:
  cmpq   $0x0,(%rdi,%rbx,8)
  jne    L154
L11:
  mov    -0x58(%rbp),%r9
L239:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L214
  lea    -0x28(%rbp),%rsp
  mov    %r9,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L138:
  lea    (%r15,%rbx,4),%rax
  mov    -0x58(%rbp),%r9
  mov    %rax,-0x48(%rbp)
  lea    0x1(%rbx),%rax
  xor    %ebx,%ebx
  mov    %rax,-0x50(%rbp)
L27:
  mov    -0x48(%rbp),%rax
  mov    -0x50(%rbp),%rdi
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %ebx,(%rax)
  add    $0x1,%rbx
  call   <PartitionDispositionRipetitionR>
  mov    %rax,%r9
  cmp    %rbx,%r14
  jne    L27
  jmp    L239
  nop
L185:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  xor    %r14d,%r14d
  call   <printf@plt>
  nopl   0x0(%rax)
L243:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edx,%edx
  test   %r13,%r13
  jne    L242
  jmp    L12
  nop
L126:
  add    $0x1,%rdx
  cmp    %rdx,%r13
  je     L12
L242:
  movslq (%r15,%rdx,4),%rax
  cmp    %r14,%rax
  jne    L126
  mov    (%r12,%rdx,4),%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  mov    %rdx,-0x48(%rbp)
  call   <printf@plt>
  mov    -0x48(%rbp),%rdx
  add    $0x1,%rdx
  cmp    %rdx,%r13
  jne    L242
  nopl   (%rax)
L12:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r14),%rax
  cmp    %r14,%rbx
  je     L86
  mov    %rax,%r14
  jmp    L243
L171:
  cmp    %r13,%rbx
  jb     L11
  test   %r13,%r13
  jne    L5
L64:
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L86:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x58(%rbp),%r9
  add    $0x1,%r9
  jmp    L239
L104:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L1
L214:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D41
type_infered: string
name: disassemble_data
arguments: data_tag: D39
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D41: partition: 

tool: D39: { 

tool: D17: %d 

tool: D7: }  

assistant: ```c
size_t PartitionDispositionRipetitionR(size_t pos, int *val, int *sol, size_t n, size_t k, size_t count) {
  size_t i, j, occ[k];
  for (i = 0; i < k; i++)
    occ[i] = 0;
  if (pos >= n) {
    for (i = 0; i < n; i++)
      occ[sol[i]]++;
    for (i = 0; i < k; i++)
      if (occ[i] == 0)
        return (count);
    printf("partition: ");
    for (i = 0; i < k; i++) {
      printf("{ ");
      for (j = 0; j < n; j++) {
        if (sol[j] == i)
          printf("%d ", val[j]);
      }
      printf("}  ");
    }
    printf("\n");
    return (count + 1);
  }
  for (i = 0; i < k; i++) {
    sol[pos] = i;
    count = PartitionDispositionRipetitionR(pos + 1, val, sol, n, k, count);
  }
  return (count);
}
```