ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x6,%esi
  mov    $0x3,%edi
  movdqa D11(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    %rsp,%rdx
  movaps %xmm0,(%rsp)
  movdqa D28(%rip),%xmm0
  mov    %rax,0x40(%rsp)
  movaps %xmm0,0x10(%rsp)
  movdqa D12(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D47(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <spiralPrint@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type: byte[16]
name: parse_data
arguments: data_tag: D2
type: byte[8]
name: parse_data
arguments: data_tag: D28
type: byte[16]
name: parse_data
arguments: data_tag: D12
type: byte[16]
name: parse_data
arguments: data_tag: D47
type: byte[16]

tool: {"D11": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D2": [0x11,0x00,0x00,0x00,0x12,0x00,0x00,0x00]}

tool: {"D28": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: {"D12": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00]}

tool: {"D47": [0x0d,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[3][6] = {{1, 2, 3, 4, 5, 6}, {7, 8, 9, 10, 11, 12}, {13, 14, 15, 16, 17, 18}};
  spiralPrint(3, 6, a);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    -0x14(%rbp),%rdx
  mov    %eax,%esi
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L4:
  mov    -0xc(%rbp),%eax
  lea    -0xc(%rbp),%rdx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jle    L4
  mov    -0x14(%rbp),%eax
  lea    -0x14(%rbp),%rdx
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L43
L1:
  mov    -0x10(%rbp),%eax
  lea    -0x10(%rbp),%rdx
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x6,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  lea    -0xc(%rbp),%rdx
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L43:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jle    L1
  mov    -0x14(%rbp),%eax
  lea    -0x14(%rbp),%rdx
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D46
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D20
type_guessed: string
name: unpack_data
arguments: data_tag: D42
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: string

tool: D46: 	Initially, n = %d at %p


tool: D15: 	loop 1: n = %d at %p


tool: D27: After loop 1, n = %d at %p


tool: D20: 	loop 2 index n = %d at %p


tool: D42: 	loop 2: n = %d at %p


tool: D11: After loop 2, n = %d at %p


assistant: ```c
int main() {
  int n = 8;
  printf("	Initially, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 1: n = %d at %p\n", n, &n);
  }
  printf("After loop 1, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 2 index n = %d at %p\n", n, &n);
    int n = 6;
    printf("	loop 2: n = %d at %p\n", n, &n);
    n++;
  }
  printf("After loop 2, n = %d at %p\n", n, &n);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x8,0xc(%rsp)
  lea    0xc(%rsp),%rdx
  mov    $0x8,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  movl   $0x1,0x14(%rsp)
  mov    $0x1,%esi
  lea    D18(%rip),%rbx
L25:
  lea    0x14(%rsp),%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L25
  lea    0xc(%rsp),%rdx
  mov    0xc(%rsp),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  movl   $0x1,0x10(%rsp)
  mov    $0x1,%esi
  lea    0x10(%rsp),%r13
  lea    D22(%rip),%r12
  lea    0x14(%rsp),%rbp
  lea    D20(%rip),%rbx
L3:
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <printf@plt>
  movl   $0x6,0x14(%rsp)
  mov    %rbp,%rdx
  mov    $0x6,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0x10(%rsp)
  cmp    $0x2,%esi
  jle    L3
  lea    0xc(%rsp),%rdx
  mov    0xc(%rsp),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D22
data_type: string
name: read_data
arguments: data_tag: D20
data_type: string
name: read_data
arguments: data_tag: D21
data_type: string

tool: D16: 	Initially, n = %d at %p


tool: D18: 	loop 1: n = %d at %p


tool: D9: After loop 1, n = %d at %p


tool: D22: 	loop 2 index n = %d at %p


tool: D20: 	loop 2: n = %d at %p


tool: D21: After loop 2, n = %d at %p


assistant: ```c
int main() {
  int n = 8;
  printf("	Initially, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 1: n = %d at %p\n", n, &n);
  }
  printf("After loop 1, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 2 index n = %d at %p\n", n, &n);
    int n = 6;
    printf("	loop 2: n = %d at %p\n", n, &n);
    n++;
  }
  printf("After loop 2, n = %d at %p\n", n, &n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x8,%esi
  lea    D53(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  movl   $0x8,0xc(%rsp)
  lea    0x14(%rsp),%rbx
  mov    %r13,%rdx
  call   <printf@plt>
  movl   $0x1,0x14(%rsp)
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L1
  mov    0xc(%rsp),%esi
  mov    %r13,%rdx
  lea    D25(%rip),%rdi
  lea    0x10(%rsp),%r14
  lea    D3(%rip),%r12
  lea    D22(%rip),%rbp
  call   <printf@plt>
  movl   $0x1,0x10(%rsp)
  mov    $0x1,%esi
  xchg   %ax,%ax
L8:
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  movl   $0x6,0x14(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0x10(%rsp)
  cmp    $0x2,%esi
  jle    L8
  mov    0xc(%rsp),%esi
  mov    %r13,%rdx
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D53
type_guessed: string
name: read_data
arguments: label: D27
type_guessed: string
name: read_data
arguments: label: D25
type_guessed: string
name: read_data
arguments: label: D3
type_guessed: string
name: read_data
arguments: label: D22
type_guessed: string
name: read_data
arguments: label: D45
type_guessed: string

tool: D53: 	Initially, n = %d at %p


tool: D27: 	loop 1: n = %d at %p


tool: D25: After loop 1, n = %d at %p


tool: D3: 	loop 2 index n = %d at %p


tool: D22: 	loop 2: n = %d at %p


tool: D45: After loop 2, n = %d at %p


assistant: ```c
int main() {
  int n = 8;
  printf("	Initially, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 1: n = %d at %p\n", n, &n);
  }
  printf("After loop 1, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 2 index n = %d at %p\n", n, &n);
    int n = 6;
    printf("	loop 2: n = %d at %p\n", n, &n);
    n++;
  }
  printf("After loop 2, n = %d at %p\n", n, &n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x8,%esi
  lea    D18(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  movl   $0x8,0xc(%rsp)
  lea    0x14(%rsp),%rbx
  mov    %r13,%rdx
  call   <printf@plt>
  movl   $0x1,0x14(%rsp)
  mov    $0x1,%esi
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0x14(%rsp)
  cmp    $0x2,%esi
  jle    L5
  mov    0xc(%rsp),%esi
  mov    %r13,%rdx
  lea    D3(%rip),%rdi
  lea    0x10(%rsp),%r14
  lea    D5(%rip),%r12
  lea    D19(%rip),%rbp
  call   <printf@plt>
  movl   $0x1,0x10(%rsp)
  mov    $0x1,%esi
  xchg   %ax,%ax
L3:
  mov    %r14,%rdx
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x6,%esi
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  movl   $0x6,0x14(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%eax
  lea    0x1(%rax),%esi
  mov    %esi,0x10(%rsp)
  cmp    $0x2,%esi
  jle    L3
  mov    0xc(%rsp),%esi
  mov    %r13,%rdx
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D26
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D44
type_guessed: string

tool: D18: 	Initially, n = %d at %p


tool: D26: 	loop 1: n = %d at %p


tool: D3: After loop 1, n = %d at %p


tool: D5: 	loop 2 index n = %d at %p


tool: D19: 	loop 2: n = %d at %p


tool: D44: After loop 2, n = %d at %p


assistant: ```c
int main() {
  int n = 8;
  printf("	Initially, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 1: n = %d at %p\n", n, &n);
  }
  printf("After loop 1, n = %d at %p\n", n, &n);
  for (int n = 1; n < 3; n++) {
    printf("	loop 2 index n = %d at %p\n", n, &n);
    int n = 6;
    printf("	loop 2: n = %d at %p\n", n, &n);
    n++;
  }
  printf("After loop 2, n = %d at %p\n", n, &n);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_zap_trailing_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L16:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L24:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L3
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
L3:
  nop
  leave
  ret
```

assistant: ```c
void _zap_trailing_whitespace(char *s) {
  char *p = s + strlen(s) - 1;
  while (p >= s && isspace(*p))
    *p-- = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_zap_trailing_whitespace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L2
L29:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L2
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  jbe    L29
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void _zap_trailing_whitespace(char *s) {
  char *p = s + strlen(s) - 1;
  while (p >= s && isspace(*p))
    *p-- = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_zap_trailing_whitespace>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jbe    L38
  jmp    L35
L21:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  ja     L35
L38:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void _zap_trailing_whitespace(char *s) {
  char *p = s + strlen(s) - 1;
  while (p >= s && isspace(*p))
    *p-- = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_zap_trailing_whitespace>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jbe    L10
  jmp    L36
L21:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  ja     L36
L10:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void _zap_trailing_whitespace(char *s) {
  char *p = s + strlen(s) - 1;
  while (p >= s && isspace(*p))
    *p-- = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gameplay_update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gameplay_fire_update@plt>
  mov    $0x0,%eax
  call   <gameplay_players_update@plt>
  mov    $0x0,%eax
  call   <gameplay_bombs_update@plt>
  mov    $0x0,%eax
  call   <gameplay_players_ai_update@plt>
  mov    $0x0,%eax
  call   <gameplay_items_item_update@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gameplay_update(void) {
  gameplay_fire_update();
  gameplay_players_update();
  gameplay_bombs_update();
  gameplay_players_ai_update();
  gameplay_items_item_update();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gameplay_update>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gameplay_fire_update@plt>
  mov    $0x0,%eax
  call   <gameplay_players_update@plt>
  mov    $0x0,%eax
  call   <gameplay_bombs_update@plt>
  mov    $0x0,%eax
  call   <gameplay_players_ai_update@plt>
  mov    $0x0,%eax
  call   <gameplay_items_item_update@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gameplay_update(void) {
  gameplay_fire_update();
  gameplay_players_update();
  gameplay_bombs_update();
  gameplay_players_ai_update();
  gameplay_items_item_update();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gameplay_update>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gameplay_fire_update@plt>
  xor    %eax,%eax
  call   <gameplay_players_update@plt>
  xor    %eax,%eax
  call   <gameplay_bombs_update@plt>
  xor    %eax,%eax
  call   <gameplay_players_ai_update@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <gameplay_items_item_update@plt>
```

assistant: ```c
void gameplay_update(void) {
  gameplay_fire_update();
  gameplay_players_update();
  gameplay_bombs_update();
  gameplay_players_ai_update();
  gameplay_items_item_update();
}
```
user: Translate the below assembly code into C programming language:

```asm
<gameplay_update>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gameplay_fire_update@plt>
  xor    %eax,%eax
  call   <gameplay_players_update@plt>
  xor    %eax,%eax
  call   <gameplay_bombs_update@plt>
  xor    %eax,%eax
  call   <gameplay_players_ai_update@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <gameplay_items_item_update@plt>
```

assistant: ```c
void gameplay_update(void) {
  gameplay_fire_update();
  gameplay_players_update();
  gameplay_bombs_update();
  gameplay_players_ai_update();
  gameplay_items_item_update();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_data_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L21:
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L2
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D0
type: string

tool: D10: %d 

tool: D0: %d

assistant: ```c
void print_data_int(int *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%d ", dat[i * M + j]);
    }
    printf("%d", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_data_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,0x20(%rsp)
  mov    %edx,0xc(%rsp)
  test   %esi,%esi
  jle    L43
  movslq %edx,%rax
  shl    $0x2,%rax
  mov    %rax,0x10(%rsp)
  mov    %rdi,%r14
  add    %rax,%r14
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    -0x2(%rdx),%eax
  mov    %eax,0x24(%rsp)
  lea    0x4(%rdi),%rax
  mov    %rax,0x28(%rsp)
  lea    D10(%rip),%r12
  jmp    L13
L35:
  movslq %r15d,%rdx
  mov    0x18(%rsp),%rax
  lea    (%rax,%rdx,4),%rbx
  mov    0x24(%rsp),%eax
  add    %rdx,%rax
  mov    0x28(%rsp),%rcx
  lea    (%rcx,%rax,4),%rbp
L15:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L15
L20:
  mov    -0x4(%r14),%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    0x10(%rsp),%r14
  add    0xc(%rsp),%r15d
  cmp    %r13d,0x20(%rsp)
  je     L43
L13:
  cmpl   $0x1,0xc(%rsp)
  jg     L35
  jmp    L20
L43:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: string

tool: D10: %d 

tool: D4: %d

assistant: ```c
void print_data_int(int *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%d ", dat[i * M + j]);
    }
    printf("%d", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_data_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  test   %esi,%esi
  jle    L29
  movslq %edx,%r15
  mov    %rdi,%r12
  lea    D4(%rip),%rbp
  xor    %r13d,%r13d
  lea    0x0(,%r15,4),%rcx
  mov    %r15,%rax
  mov    %rcx,0x8(%rsp)
  sub    $0x2,%eax
  lea    0x4(%rdi,%rax,4),%rbx
  nopl   0x0(%rax)
L1:
  cmpl   $0x1,0x4(%rsp)
  mov    %r12,%r14
  jle    L13
  nopw   0x0(%rax,%rax,1)
L35:
  mov    (%r14),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L35
L13:
  mov    -0x4(%r12,%r15,4),%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  add    %rax,%r12
  add    %rax,%rbx
  cmp    %r13d,(%rsp)
  jne    L1
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D4: %d 

tool: D16: %d

assistant: ```c
void print_data_int(int *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%d ", dat[i * M + j]);
    }
    printf("%d", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_data_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  test   %esi,%esi
  jle    L23
  movslq %edx,%r15
  mov    %rdi,%r12
  lea    D3(%rip),%rbp
  xor    %r13d,%r13d
  lea    0x0(,%r15,4),%rcx
  mov    %r15,%rax
  mov    %rcx,0x8(%rsp)
  sub    $0x2,%eax
  lea    0x4(%rdi,%rax,4),%rbx
  nopl   0x0(%rax)
L0:
  cmpl   $0x1,0x4(%rsp)
  mov    %r12,%r14
  jle    L13
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%r14),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r14
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L5
L13:
  mov    -0x4(%r12,%r15,4),%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  add    %rax,%r12
  add    %rax,%rbx
  cmp    %r13d,(%rsp)
  jne    L0
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D11
type: string

tool: D3: %d 

tool: D11: %d

assistant: ```c
void print_data_int(int *dat, int N, int M) {
  int i, j;
  for (i = 0; i < N; i++) {
    for (j = 0; j < M - 1; j++) {
      printf("%d ", dat[i * M + j]);
    }
    printf("%d", dat[i * M + (M - 1)]);
    printf("\n");
  }
}
```