ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<c2_write_sfr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  movzbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <c2_write_ar@plt>
  movzbl -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <c2_write_dr@plt>
  test   %rax,%rax
  jns    L10
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L5
L10:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int c2_write_sfr(struct c2interface *c2if, unsigned char sfr, unsigned char data) {
  c2_write_ar(c2if, sfr);
  if (c2_write_dr(c2if, data) < 0)
    return -EIO;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c2_write_sfr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %edx,%ebx
  movzbl %sil,%esi
  call   <c2_write_ar@plt>
  movzbl %bl,%esi
  mov    %rbp,%rdi
  call   <c2_write_dr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L0
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L13
```

assistant: ```c
int c2_write_sfr(struct c2interface *c2if, unsigned char sfr, unsigned char data) {
  c2_write_ar(c2if, sfr);
  if (c2_write_dr(c2if, data) < 0)
    return -EIO;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<c2_write_sfr>:
  endbr64
  push   %rbp
  movzbl %sil,%esi
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <c2_write_ar@plt>
  movzbl %bl,%esi
  mov    %rbp,%rdi
  call   <c2_write_dr@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  neg    %eax
  ret
```

assistant: ```c
int c2_write_sfr(struct c2interface *c2if, unsigned char sfr, unsigned char data) {
  c2_write_ar(c2if, sfr);
  if (c2_write_dr(c2if, data) < 0)
    return -EIO;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c2_write_sfr>:
  endbr64
  push   %rbp
  movzbl %sil,%esi
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <c2_write_ar@plt>
  movzbl %bl,%esi
  mov    %rbp,%rdi
  call   <c2_write_dr@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  neg    %eax
  ret
```

assistant: ```c
int c2_write_sfr(struct c2interface *c2if, unsigned char sfr, unsigned char data) {
  c2_write_ar(c2if, sfr);
  if (c2_write_dr(c2if, data) < 0)
    return -EIO;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<star>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edx,%r10d
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%r8
  and    $0xfffffffffffffff0,%r8
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L88:
  cmp    %rcx,%rsp
  je     L62
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L88
L62:
  mov    %r8,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L72
  orq    $0x0,-0x8(%rsp,%rdx,1)
L72:
  mov    %rsp,%r13
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L33:
  cmp    %rdx,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L55:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L8
  orq    $0x0,-0x8(%rsp,%rax,1)
L8:
  mov    %rsp,%r14
  mov    %r12d,%r9d
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r10d,%edx
  call   <_pointCircle@plt>
  test   %r12d,%r12d
  jle    L27
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  mov    %eax,-0x44(%rbp)
  mov    %r12d,%r15d
  mov    $0x0,%ebx
L56:
  mov    -0x44(%rbp),%eax
  add    %ebx,%eax
  cltd
  idiv   %r12d
  movslq %edx,%rdx
  mov    (%r14,%rdx,4),%ecx
  mov    0x0(%r13,%rdx,4),%edx
  mov    (%r14,%rbx,4),%esi
  mov    0x0(%r13,%rbx,4),%edi
  call   <line@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L56
L27:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void star(int xCenter, int yCenter, int radius, int npts) {
  int xPts[npts], yPts[npts];
  _pointCircle(xCenter, yCenter, radius, xPts, yPts, npts);
  int i, to;
  for (i = 0; i < npts; ++i) {
    to = (i + npts / 2) % npts;
    line(xPts[i], yPts[i], xPts[to], yPts[to]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<star>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  mov    %rsp,%r8
  mov    %rax,-0x48(%rbp)
  lea    0xf(,%rax,4),%rax
  mov    %rax,%r9
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%r9
  and    $0xfffffffffffffff0,%rcx
  sub    %r9,%r8
  cmp    %r8,%rsp
  je     L81
L40:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L40
L81:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L89
L93:
  mov    %rax,%rcx
  mov    %rsp,%r8
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%r15
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rcx
  cmp    %r8,%rsp
  je     L13
L106:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L106
L13:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L43
L101:
  mov    %rsp,%r13
  mov    %r12d,%r9d
  mov    %r15,%rcx
  mov    %r13,%r8
  call   <_pointCircle@plt>
  test   %r12d,%r12d
  jle    L18
  mov    %r12d,%r14d
  xor    %ebx,%ebx
  sar    %r14d
  nopl   (%rax)
L82:
  lea    (%r14,%rbx,1),%eax
  mov    0x0(%r13,%rbx,4),%esi
  mov    (%r15,%rbx,4),%edi
  add    $0x1,%rbx
  cltd
  idiv   %r12d
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,4),%ecx
  mov    (%r15,%rdx,4),%edx
  call   <line@plt>
  cmp    -0x48(%rbp),%rbx
  jne    L82
L18:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L93
L43:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L101
L108:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void star(int xCenter, int yCenter, int radius, int npts) {
  int xPts[npts], yPts[npts];
  _pointCircle(xCenter, yCenter, radius, xPts, yPts, npts);
  int i, to;
  for (i = 0; i < npts; ++i) {
    to = (i + npts / 2) % npts;
    line(xPts[i], yPts[i], xPts[to], yPts[to]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<star>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %ecx,%rax
  mov    %rsp,%r8
  mov    %rax,-0x48(%rbp)
  lea    0xf(,%rax,4),%rax
  mov    %rax,%r9
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%r9
  and    $0xfffffffffffffff0,%rcx
  sub    %r9,%r8
  cmp    %r8,%rsp
  je     L42
L92:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L92
L42:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L12
L109:
  mov    %rax,%rcx
  mov    %rsp,%r8
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%r15
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rcx
  cmp    %r8,%rsp
  je     L33
L26:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L26
L33:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L7
L46:
  mov    %rsp,%r13
  mov    %r12d,%r9d
  mov    %r15,%rcx
  mov    %r13,%r8
  call   <_pointCircle@plt>
  test   %r12d,%r12d
  jle    L107
  mov    %r12d,%r14d
  xor    %ebx,%ebx
  sar    %r14d
  nopl   (%rax)
L2:
  lea    (%r14,%rbx,1),%eax
  mov    0x0(%r13,%rbx,4),%esi
  mov    (%r15,%rbx,4),%edi
  add    $0x1,%rbx
  cltd
  idiv   %r12d
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,4),%ecx
  mov    (%r15,%rdx,4),%edx
  call   <line@plt>
  cmp    -0x48(%rbp),%rbx
  jne    L2
L107:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L109
L7:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L46
L90:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void star(int xCenter, int yCenter, int radius, int npts) {
  int xPts[npts], yPts[npts];
  _pointCircle(xCenter, yCenter, radius, xPts, yPts, npts);
  int i, to;
  for (i = 0; i < npts; ++i) {
    to = (i + npts / 2) % npts;
    line(xPts[i], yPts[i], xPts[to], yPts[to]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<solutionA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L88
L43:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L88:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L43
  movl   $0x0,-0x18(%rbp)
  jmp    L42
L15:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L78
L37:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,%edx
  jne    L62
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x24(%rbp),%eax
  lea    (%rcx,%rax,1),%edi
  mov    -0x10(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %rax,%rsi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L62
  addl   $0x1,-0x20(%rbp)
L62:
  addl   $0x1,-0x14(%rbp)
L78:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L37
  addl   $0x1,-0x18(%rbp)
L42:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L15
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D16: %d %d

tool: D14: %d

assistant: ```c
void solutionA() {
  int n, d;
  scanf("%d %d", &n, &d);
  int *arr = (int *)malloc(sizeof(int) * n);
  int count = 0;
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (arr[j] - arr[i] == 2 * d) {
        if (binarySearch(arr[i] + d, arr, 0, n - 1)) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<solutionA>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  cmpl   $0x0,0x10(%rsp)
  jle    L57
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D20(%rip),%r12
L2:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x10(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L2
  test   %eax,%eax
  jle    L78
  mov    0x8(%rsp),%rax
  lea    0x4(%rax),%r14
  mov    $0x0,%r13d
  mov    $0x0,%r15d
  jmp    L7
L86:
  sub    $0x1,%ecx
  add    %edx,%edi
  mov    $0x0,%edx
  mov    0x8(%rsp),%rsi
  call   <binarySearch@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r15d
L61:
  add    $0x1,%ebx
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jle    L22
L44:
  mov    (%r12),%edi
  mov    0x14(%rsp),%edx
  mov    0x0(%rbp),%eax
  sub    %edi,%eax
  lea    (%rdx,%rdx,1),%esi
  cmp    %esi,%eax
  jne    L61
  jmp    L86
L22:
  add    $0x4,%r14
  cmp    %r13d,%ecx
  jle    L51
L7:
  add    $0x1,%r13d
  mov    0x10(%rsp),%ecx
  cmp    %ecx,%r13d
  jge    L51
  lea    -0x4(%r14),%r12
  mov    %r14,%rbp
  mov    %r13d,%ebx
  jmp    L44
L57:
  mov    $0x0,%r15d
L51:
  mov    %r15d,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L77
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L78:
  mov    $0x0,%r15d
  jmp    L51
L77:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D20
type_guessed: string

tool: D3: %d %d

tool: D20: %d

assistant: ```c
void solutionA() {
  int n, d;
  scanf("%d %d", &n, &d);
  int *arr = (int *)malloc(sizeof(int) * n);
  int count = 0;
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (arr[j] - arr[i] == 2 * d) {
        if (binarySearch(arr[i] + d, arr, 0, n - 1)) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: What is the c source code of the assembly code below?

```asm
<solutionA>:
  endbr64
  push   %r15
  lea    D5(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %edx,%edx
  jle    L75
  nopl   0x0(%rax)
L79:
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L79
  test   %ecx,%ecx
  jle    L75
  movl   $0x0,0xc(%rsp)
  lea    0x4(%r12),%rbp
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L103:
  add    $0x1,%r13d
  cmp    %r13d,%ecx
  jle    L50
  lea    -0x4(%rbp),%r14
  mov    %rbp,%r15
  mov    %r13d,%ebx
  jmp    L90
  nopl   (%rax)
L66:
  add    $0x1,%ebx
  add    $0x4,%r15
  cmp    %ebx,%ecx
  jle    L56
L90:
  mov    (%r14),%edi
  mov    0x14(%rsp),%edx
  mov    (%r15),%eax
  lea    (%rdx,%rdx,1),%esi
  sub    %edi,%eax
  cmp    %esi,%eax
  jne    L66
  add    %edx,%edi
  sub    $0x1,%ecx
  xor    %edx,%edx
  mov    %r12,%rsi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L26
  addl   $0x1,0xc(%rsp)
L26:
  mov    0x10(%rsp),%ecx
  add    $0x1,%ebx
  add    $0x4,%r15
  cmp    %ebx,%ecx
  jg     L90
L56:
  add    $0x4,%rbp
  cmp    %r13d,%ecx
  jg     L103
  nopw   0x0(%rax,%rax,1)
L50:
  mov    0xc(%rsp),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  movl   $0x0,0xc(%rsp)
  jmp    L50
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D21
datatype: string

tool: D5: %d %d

tool: D21: %d

assistant: ```c
void solutionA() {
  int n, d;
  scanf("%d %d", &n, &d);
  int *arr = (int *)malloc(sizeof(int) * n);
  int count = 0;
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (arr[j] - arr[i] == 2 * d) {
        if (binarySearch(arr[i] + d, arr, 0, n - 1)) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<solutionA>:
  endbr64
  push   %r15
  lea    D6(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%edx
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %edx,%edx
  jle    L100
  nopl   0x0(%rax)
L95:
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x10(%rsp),%ecx
  add    $0x4,%rbp
  cmp    %ebx,%ecx
  jg     L95
  test   %ecx,%ecx
  jle    L100
  movl   $0x0,0xc(%rsp)
  lea    0x4(%r12),%rbp
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L61:
  add    $0x1,%r13d
  cmp    %ecx,%r13d
  jge    L94
  lea    -0x4(%rbp),%r14
  mov    %rbp,%r15
  mov    %r13d,%ebx
  jmp    L51
  nopl   (%rax)
L59:
  add    $0x1,%ebx
  add    $0x4,%r15
  cmp    %ecx,%ebx
  jge    L76
L51:
  mov    (%r14),%edi
  mov    0x14(%rsp),%edx
  mov    (%r15),%eax
  lea    (%rdx,%rdx,1),%esi
  sub    %edi,%eax
  cmp    %esi,%eax
  jne    L59
  add    %edx,%edi
  sub    $0x1,%ecx
  xor    %edx,%edx
  mov    %r12,%rsi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L116
  addl   $0x1,0xc(%rsp)
L116:
  mov    0x10(%rsp),%ecx
  add    $0x1,%ebx
  add    $0x4,%r15
  cmp    %ecx,%ebx
  jl     L51
L76:
  add    $0x4,%rbp
  cmp    %ecx,%r13d
  jl     L61
  nopw   0x0(%rax,%rax,1)
L94:
  mov    0xc(%rsp),%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L100:
  movl   $0x0,0xc(%rsp)
  jmp    L94
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string
name: disassemble_data
arguments: tag: D12
type: string

tool: D6: %d %d

tool: D12: %d

assistant: ```c
void solutionA() {
  int n, d;
  scanf("%d %d", &n, &d);
  int *arr = (int *)malloc(sizeof(int) * n);
  int count = 0;
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = i + 1; j < n; j++) {
      if (arr[j] - arr[i] == 2 * d) {
        if (binarySearch(arr[i] + d, arr, 0, n - 1)) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<full_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L67
L6:
  mov    -0x18(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L19
  mov    D30(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L67
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L35
  jmp    L67
L35:
  mov    -0xc(%rbp),%eax
  jmp    L62
L19:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L67:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L6
  mov    -0x10(%rbp),%eax
L62:
  leave
  ret
```

assistant: ```c
int full_write(int fd, const void *vbuf, int len) {
  const unsigned char *buf = (const unsigned char *)vbuf;
  int total;
  int thistime;
  for (total = 0; total < len;) {
    thistime = write(fd, buf + total, len - total);
    if (thistime < 0) {
      if (EINTR == errno || EAGAIN == errno)
        continue;
      return thistime;
    }
    total += thistime;
  }
  return total;
}
```
user: What is the c source code of the assembly code below?

```asm
<full_write>:
  endbr64
  test   %edx,%edx
  jle    L55
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  jmp    L54
L37:
  add    %eax,%ebx
L18:
  cmp    %ebp,%ebx
  jge    L22
L54:
  mov    %ebp,%edx
  sub    %ebx,%edx
  movslq %ebx,%rsi
  add    %r13,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L37
  mov    D26(%rip),%rdx
  mov    (%rdx),%rdx
  mov    D9(%rip),%rcx
  cmp    %rdx,(%rcx)
  je     L18
  mov    D24(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L18
L57:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    %ebx,%eax
  jmp    L57
L55:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int full_write(int fd, const void *vbuf, int len) {
  const unsigned char *buf = (const unsigned char *)vbuf;
  int total;
  int thistime;
  for (total = 0; total < len;) {
    thistime = write(fd, buf + total, len - total);
    if (thistime < 0) {
      if (EINTR == errno || EAGAIN == errno)
        continue;
      return thistime;
    }
    total += thistime;
  }
  return total;
}
```
user: Translate the below assembly code into C programming language:

```asm
<full_write>:
  endbr64
  test   %edx,%edx
  jle    L38
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L14:
  mov    %r13d,%edx
  movslq %ebx,%rsi
  mov    %ebp,%edi
  sub    %ebx,%edx
  add    %r12,%rsi
  call   <write@plt>
  test   %eax,%eax
  js     L4
  add    %eax,%ebx
L35:
  cmp    %ebx,%r13d
  jg     L14
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    D23(%rip),%rdx
  mov    D21(%rip),%rcx
  mov    (%rdx),%rdx
  cmp    %rdx,(%rcx)
  je     L35
  mov    D24(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L35
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int full_write(int fd, const void *vbuf, int len) {
  const unsigned char *buf = (const unsigned char *)vbuf;
  int total;
  int thistime;
  for (total = 0; total < len;) {
    thistime = write(fd, buf + total, len - total);
    if (thistime < 0) {
      if (EINTR == errno || EAGAIN == errno)
        continue;
      return thistime;
    }
    total += thistime;
  }
  return total;
}
```