ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_lb>:
  endbr64
  cmpb   $0x20,(%rdi)
  jne    L1
  push   %rbp
  lea    0x1(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L9:
  movslq %eax,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  cmpb   $0x20,(%rbx)
  jne    L29
L34:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L9
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

assistant: ```c
void remove_lb(char *s) {
  int i, l;
  char *p;
  while (*s == ' ') {
    l = strlen(s);
    if (l <= 0)
      return;
    for (i = 0, p = s; i < l; i++, p++)
      *p = *(p + 1);
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L20
L16:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L9
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  sub    %eax,-0xc(%rbp)
  jmp    L20
L9:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L20:
  cmpl   $0x0,-0xc(%rbp)
  jg     L16
  mov    -0x1c(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bsage(int *a, int first, int last, int val) {
  int it, step, cnt = last - first;
  while (cnt > 0) {
    step = cnt / 2;
    it = first + step;
    if (a[it] < val) {
      first = it + 1;
      cnt -= step + 1;
    } else
      cnt = step;
  }
  return first;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bsage>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%eax
  sub    %esi,%edx
L21:
  test   %edx,%edx
  jle    L24
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  lea    (%rax,%rdi,1),%r8d
  movslq %r8d,%r9
  cmp    %ecx,(%r10,%r9,4)
  jl     L31
  mov    %edi,%edx
  jmp    L21
L31:
  lea    0x1(%r8),%eax
  add    $0x1,%edi
  sub    %edi,%edx
  jmp    L21
L24:
  ret
```

assistant: ```c
int bsage(int *a, int first, int last, int val) {
  int it, step, cnt = last - first;
  while (cnt > 0) {
    step = cnt / 2;
    it = first + step;
    if (a[it] < val) {
      first = it + 1;
      cnt -= step + 1;
    } else
      cnt = step;
  }
  return first;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bsage>:
  endbr64
  mov    %esi,%eax
  sub    %esi,%edx
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %edx,%r8d
  sar    %r8d
  lea    (%rax,%r8,1),%r9d
  movslq %r9d,%r10
  cmp    %ecx,(%rdi,%r10,4)
  jl     L30
  mov    %r8d,%edx
L17:
  test   %edx,%edx
  jg     L7
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x1,%r8d
  lea    0x1(%r9),%eax
  sub    %r8d,%edx
  jmp    L17
```

assistant: ```c
int bsage(int *a, int first, int last, int val) {
  int it, step, cnt = last - first;
  while (cnt > 0) {
    step = cnt / 2;
    it = first + step;
    if (a[it] < val) {
      first = it + 1;
      cnt -= step + 1;
    } else
      cnt = step;
  }
  return first;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bsage>:
  endbr64
  mov    %esi,%eax
  sub    %esi,%edx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %edx,%r8d
  sar    %r8d
  lea    (%rax,%r8,1),%r9d
  movslq %r9d,%r10
  cmp    %ecx,(%rdi,%r10,4)
  jl     L20
  mov    %r8d,%edx
L29:
  test   %edx,%edx
  jg     L5
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%r8d
  lea    0x1(%r9),%eax
  sub    %r8d,%edx
  jmp    L29
```

assistant: ```c
int bsage(int *a, int first, int last, int val) {
  int it, step, cnt = last - first;
  while (cnt > 0) {
    step = cnt / 2;
    it = first + step;
    if (a[it] < val) {
      first = it + 1;
      cnt -= step + 1;
    } else
      cnt = step;
  }
  return first;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parsestandard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L37
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <parseonestd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L2
  mov    $0xffffffff,%eax
  jmp    L33
L2:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L37:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
L33:
  leave
  ret
```

assistant: ```c
int parsestandard(int argc, char **argv) {
  int i;
  int dt = 0;
  int tdt;
  for (i = 0; i < argc; i++) {
    tdt = parseonestd(argv[i]);
    if (tdt == -1)
      return -1;
    dt += tdt;
  }
  return dt;
}
```
user: What is the c source code of the assembly code below:

```asm
<parsestandard>:
  endbr64
  test   %edi,%edi
  jle    L6
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  mov    $0x0,%ebp
L17:
  mov    (%rbx),%rdi
  call   <parseonestd@plt>
  cmp    $0xffffffff,%eax
  je     L22
  add    %eax,%ebp
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L17
  mov    %ebp,%eax
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int parsestandard(int argc, char **argv) {
  int i;
  int dt = 0;
  int tdt;
  for (i = 0; i < argc; i++) {
    tdt = parseonestd(argv[i]);
    if (tdt == -1)
      return -1;
    dt += tdt;
  }
  return dt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parsestandard>:
  endbr64
  test   %edi,%edi
  jle    L20
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x8,%rbx
  add    %eax,%ebp
  cmp    %r12,%rbx
  je     L8
L38:
  mov    (%rbx),%rdi
  call   <parseonestd@plt>
  cmp    $0xffffffff,%eax
  jne    L36
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int parsestandard(int argc, char **argv) {
  int i;
  int dt = 0;
  int tdt;
  for (i = 0; i < argc; i++) {
    tdt = parseonestd(argv[i]);
    if (tdt == -1)
      return -1;
    dt += tdt;
  }
  return dt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parsestandard>:
  endbr64
  test   %edi,%edi
  jle    L33
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L34:
  add    $0x8,%rbx
  add    %eax,%ebp
  cmp    %r12,%rbx
  je     L7
L19:
  mov    (%rbx),%rdi
  call   <parseonestd@plt>
  cmp    $0xffffffff,%eax
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L7:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int parsestandard(int argc, char **argv) {
  int i;
  int dt = 0;
  int tdt;
  for (i = 0; i < argc; i++) {
    tdt = parseonestd(argv[i]);
    if (tdt == -1)
      return -1;
    dt += tdt;
  }
  return dt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L9:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy2(char *dest, const char *src) {
  char *rval = dest;
  while ((*dest++ = *src++) != 0)
    ;
  return rval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy2>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L3:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L3
  ret
```

assistant: ```c
char *strcpy2(char *dest, const char *src) {
  char *rval = dest;
  while ((*dest++ = *src++) != 0)
    ;
  return rval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strcpy2>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L2:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L2
  ret
```

assistant: ```c
char *strcpy2(char *dest, const char *src) {
  char *rval = dest;
  while ((*dest++ = *src++) != 0)
    ;
  return rval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy2>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L4:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L4
  ret
```

assistant: ```c
char *strcpy2(char *dest, const char *src) {
  char *rval = dest;
  while ((*dest++ = *src++) != 0)
    ;
  return rval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stdinout_reopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stdinout_open@plt>
  nop
  leave
  ret
```

assistant: ```c
void stdinout_reopen(int fd, char *path, int flags) {
  assert(!close(fd));
  stdinout_open(fd, path, flags);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stdinout_reopen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <close@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <stdinout_open@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void stdinout_reopen(int fd, char *path, int flags) {
  assert(!close(fd));
  stdinout_open(fd, path, flags);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stdinout_reopen>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <close@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <stdinout_open@plt>
```

assistant: ```c
void stdinout_reopen(int fd, char *path, int flags) {
  assert(!close(fd));
  stdinout_open(fd, path, flags);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stdinout_reopen>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  call   <close@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <stdinout_open@plt>
```

assistant: ```c
void stdinout_reopen(int fd, char *path, int flags) {
  assert(!close(fd));
  stdinout_open(fd, path, flags);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <init_address_table@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  init_address_table();
  char c = getchar();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_address_table@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init_address_table();
  char c = getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_address_table@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init_address_table();
  char c = getchar();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_address_table@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init_address_table();
  char c = getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<legal_hostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <check_name@plt>
  test   %eax,%eax
  jne    L130
  mov    $0x0,%eax
  jmp    L63
L130:
  movl   $0x1,-0x4(%rbp)
  jmp    L95
L17:
  cmpb   $0x40,-0x5(%rbp)
  jle    L37
  cmpb   $0x5a,-0x5(%rbp)
  jle    L8
L37:
  cmpb   $0x60,-0x5(%rbp)
  jle    L5
  cmpb   $0x7a,-0x5(%rbp)
  jle    L8
L5:
  cmpb   $0x2f,-0x5(%rbp)
  jle    L139
  cmpb   $0x39,-0x5(%rbp)
  jle    L8
L139:
  cmpl   $0x0,-0x4(%rbp)
  jne    L151
  cmpb   $0x2d,-0x5(%rbp)
  je     L150
  cmpb   $0x5f,-0x5(%rbp)
  je     L150
L151:
  cmpb   $0x2e,-0x5(%rbp)
  jne    L58
  mov    $0x1,%eax
  jmp    L63
L58:
  mov    $0x0,%eax
  jmp    L63
L8:
  nop
  jmp    L59
L150:
  nop
L59:
  addq   $0x1,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L95:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x0,-0x5(%rbp)
  jne    L17
  mov    $0x1,%eax
L63:
  leave
  ret
```

assistant: ```c
int legal_hostname(char *name) {
  char c;
  int first;
  if (!check_name(name))
    return 0;
  for (first = 1; (c = *name); name++, first = 0) {
    if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9'))
      continue;
    if (!first && (c == '-' || c == '_'))
      continue;
    if (c == '.')
      return 1;
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<legal_hostname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <check_name@plt>
  test   %eax,%eax
  jne    L109
L101:
  pop    %rbx
  ret
L109:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L40
  mov    $0x1,%ecx
  mov    $0x0,%esi
  jmp    L116
L64:
  cmp    $0x2d,%al
  je     L65
  cmp    $0x5f,%al
  jne    L42
L65:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  mov    %esi,%ecx
  test   %al,%al
  je     L81
L116:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L65
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L65
  test   %ecx,%ecx
  je     L64
L42:
  cmp    $0x2e,%al
  sete   %al
  movzbl %al,%eax
  jmp    L101
L81:
  mov    $0x1,%eax
  jmp    L101
L40:
  mov    $0x1,%eax
  jmp    L101
```

assistant: ```c
int legal_hostname(char *name) {
  char c;
  int first;
  if (!check_name(name))
    return 0;
  for (first = 1; (c = *name); name++, first = 0) {
    if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9'))
      continue;
    if (!first && (c == '-' || c == '_'))
      continue;
    if (c == '.')
      return 1;
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<legal_hostname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <check_name@plt>
  test   %eax,%eax
  jne    L12
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L57
  mov    $0x1,%ecx
L14:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L52
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L52
  test   %ecx,%ecx
  je     L7
L30:
  cmp    $0x2e,%al
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
L7:
  cmp    $0x2d,%al
  je     L52
  cmp    $0x5f,%al
  jne    L30
  nop
L52:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  xor    %ecx,%ecx
  test   %al,%al
  jne    L14
L57:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int legal_hostname(char *name) {
  char c;
  int first;
  if (!check_name(name))
    return 0;
  for (first = 1; (c = *name); name++, first = 0) {
    if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9'))
      continue;
    if (!first && (c == '-' || c == '_'))
      continue;
    if (c == '.')
      return 1;
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<legal_hostname>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <check_name@plt>
  test   %eax,%eax
  jne    L50
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L33
  mov    $0x1,%ecx
L14:
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L26
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L26
  test   %ecx,%ecx
  je     L24
L36:
  cmp    $0x2e,%al
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
L24:
  cmp    $0x2d,%al
  je     L26
  cmp    $0x5f,%al
  jne    L36
  nop
L26:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  xor    %ecx,%ecx
  test   %al,%al
  jne    L14
L33:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int legal_hostname(char *name) {
  char c;
  int first;
  if (!check_name(name))
    return 0;
  for (first = 1; (c = *name); name++, first = 0) {
    if ((c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z') || (c >= '0' && c <= '9'))
      continue;
    if (!first && (c == '-' || c == '_'))
      continue;
    if (c == '.')
      return 1;
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L30
  mov    -0xc(%rbp),%eax
  cmp    $0x8,%eax
  jne    L30
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L38
L30:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L38:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string
name: unpack_data
arguments: data_label: D27
data_type: string

tool: D1: %d%d

tool: D6: 0

tool: D27: 1

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  if (a == 2 && b == 8)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x2,(%rsp)
  jne    L35
  cmpl   $0x8,0x4(%rsp)
  je     L37
L35:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L37:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D8
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D5: %d%d

tool: D8: 1

tool: D2: 0

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  if (a == 2 && b == 8)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  cmpl   $0x2,(%rsp)
  jne    L17
  cmpl   $0x8,0x4(%rsp)
  je     L32
L17:
  lea    D21(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L32:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D3: %d%d

tool: D21: 1

tool: D9: 0

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  if (a == 2 && b == 8)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  cmpl   $0x2,(%rsp)
  jne    L36
  cmpl   $0x8,0x4(%rsp)
  je     L8
L36:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
datatype: string
name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string

tool: D15: %d%d

tool: D5: 1

tool: D11: 0

assistant: ```c
int main() {
  int a, b;
  scanf("%d%d", &a, &b);
  if (a == 2 && b == 8)
    printf("0");
  else
    printf("1");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<normalize3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm2
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D4(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
data_type: f64

tool: D4: 1

assistant: ```c
void normalize3d(float *out, const float *in) {
  float r = 1. / sqrtf(in[0] * in[0] + in[1] * in[1] + in[2] * in[2]);
  out[0] = in[0] * r;
  out[1] = in[1] * r;
  out[2] = in[2] * r;
}
```