ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x8,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0xa,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  mov    %rsp,%rax
  mov    %rax,%rcx
  lea    0x28(%rsp),%rdx
L12:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L18
  mov    (%rax),%esi
  cmp    %esi,(%rcx)
  cmovl  %rax,%rcx
  jmp    L12
L18:
  mov    %rsp,%rax
  mov    %rcx,%rdx
  sub    %rax,%rdx
  sar    $0x2,%rdx
  mov    (%rcx),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: max is %d
it is at %d


assistant: ```c
int main() {
  int a[10] = {1, 9, 8, 4, 5, 6, 3, 10, 2, 7}, *p, *q;
  for (p = q = a; p < a + 10; p++)
    if (*q < *p)
      q = p;
  printf("max is %d\nit is at %d\n", *q, q - a);
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000001,%rax
  mov    %rsp,%r8
  lea    0x28(%rsp),%rdi
  mov    %r8,%rdx
  mov    %rax,(%rsp)
  movabs $0x400000008,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xa00000003,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000002,%rax
  mov    %rax,0x20(%rsp)
  mov    %r8,%rax
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L20
L22:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jle    L11
  mov    %rax,%rdx
  add    $0x4,%rax
  mov    %ecx,%esi
  cmp    %rdi,%rax
  jne    L22
L20:
  sub    %r8,%rdx
  lea    D1(%rip),%rdi
  sar    $0x2,%rdx
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: max is %d
it is at %d


assistant: ```c
int main() {
  int a[10] = {1, 9, 8, 4, 5, 6, 3, 10, 2, 7}, *p, *q;
  for (p = q = a; p < a + 10; p++)
    if (*q < *p)
      q = p;
  printf("max is %d\nit is at %d\n", *q, q - a);
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%edx
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string

tool: D0: max is %d
it is at %d


assistant: ```c
int main() {
  int a[10] = {1, 9, 8, 4, 5, 6, 3, 10, 2, 7}, *p, *q;
  for (p = q = a; p < a + 10; p++)
    if (*q < *p)
      q = p;
  printf("max is %d\nit is at %d\n", *q, q - a);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<add_ab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void add_ab(int x) {
  int abc[3];
  abc[2] = abc[0] + abc[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add_ab>:
  endbr64
  ret
```

assistant: ```c
void add_ab(int x) {
  int abc[3];
  abc[2] = abc[0] + abc[1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add_ab>:
  endbr64
  ret
```

assistant: ```c
void add_ab(int x) {
  int abc[3];
  abc[2] = abc[0] + abc[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_ab>:
  endbr64
  ret
```

assistant: ```c
void add_ab(int x) {
  int abc[3];
  abc[2] = abc[0] + abc[1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<audit_encode_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L50
  mov    $0x0,%eax
  jmp    L36
L50:
  cmpq   $0x0,-0x30(%rbp)
  jne    L35
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  jmp    L36
L35:
  movl   $0x0,-0x14(%rbp)
  jmp    L31
L6:
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sar    $0x4,%eax
  cltq
  and    $0xf,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  and    $0xf,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L6
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
L36:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: 0123456789ABCDEF

assistant: ```c
char *audit_encode_value(char *final, const char *buf, unsigned int size) {
  unsigned int i;
  char *ptr = final;
  const char *hex = "0123456789ABCDEF";
  if (final == NULL)
    return NULL;
  if (buf == NULL) {
    *final = 0;
    return final;
  }
  for (i = 0; i < size; i++) {
    *ptr++ = hex[(buf[i] & 0xF0) >> 4];
    *ptr++ = hex[buf[i] & 0x0F];
  }
  *ptr = 0;
  return final;
}
```
user: What is the c source code of the assembly code below:

```asm
<audit_encode_value>:
  endbr64
  mov    %rdi,%rcx
  test   %rdi,%rdi
  je     L38
  test   %rsi,%rsi
  je     L1
  mov    %edx,%r8d
  mov    $0x0,%eax
  lea    D7(%rip),%rdi
  test   %edx,%edx
  je     L59
L8:
  movsbl (%rsi,%rax,1),%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  movzbl (%rdi,%rdx,1),%edx
  mov    %dl,(%rcx,%rax,2)
  movzbl (%rsi,%rax,1),%edx
  and    $0xf,%edx
  movzbl (%rdi,%rdx,1),%edx
  mov    %dl,0x1(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L8
  lea    (%rcx,%r8,2),%rax
L35:
  movb   $0x0,(%rax)
L38:
  mov    %rcx,%rax
  ret
L59:
  mov    %rcx,%rax
  jmp    L35
L1:
  movb   $0x0,(%rdi)
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: 0123456789ABCDEF

assistant: ```c
char *audit_encode_value(char *final, const char *buf, unsigned int size) {
  unsigned int i;
  char *ptr = final;
  const char *hex = "0123456789ABCDEF";
  if (final == NULL)
    return NULL;
  if (buf == NULL) {
    *final = 0;
    return final;
  }
  for (i = 0; i < size; i++) {
    *ptr++ = hex[(buf[i] & 0xF0) >> 4];
    *ptr++ = hex[buf[i] & 0x0F];
  }
  *ptr = 0;
  return final;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<audit_encode_value>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  je     L24
  test   %rsi,%rsi
  je     L21
  mov    %edx,%edi
  xor    %eax,%eax
  lea    D9(%rip),%rcx
  test   %edx,%edx
  je     L8
L47:
  movsbl (%rsi,%rax,1),%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r8,%rax,2)
  movzbl (%rsi,%rax,1),%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,0x1(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L47
  lea    (%r8,%rdi,2),%rax
L37:
  movb   $0x0,(%rax)
L24:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  movb   $0x0,(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r8,%rax
  jmp    L37
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: 0123456789ABCDEF

assistant: ```c
char *audit_encode_value(char *final, const char *buf, unsigned int size) {
  unsigned int i;
  char *ptr = final;
  const char *hex = "0123456789ABCDEF";
  if (final == NULL)
    return NULL;
  if (buf == NULL) {
    *final = 0;
    return final;
  }
  for (i = 0; i < size; i++) {
    *ptr++ = hex[(buf[i] & 0xF0) >> 4];
    *ptr++ = hex[buf[i] & 0x0F];
  }
  *ptr = 0;
  return final;
}
```
user: What is the c source code of the assembly code below?

```asm
<audit_encode_value>:
  endbr64
  mov    %rdi,%r8
  test   %rdi,%rdi
  je     L0
  test   %rsi,%rsi
  je     L34
  mov    %edx,%edi
  xor    %eax,%eax
  lea    D0(%rip),%rcx
  test   %edx,%edx
  je     L2
L17:
  movsbl (%rsi,%rax,1),%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%r8,%rax,2)
  movzbl (%rsi,%rax,1),%edx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,0x1(%r8,%rax,2)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L17
  lea    (%r8,%rax,2),%rax
L11:
  movb   $0x0,(%rax)
L0:
  mov    %r8,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  movb   $0x0,(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r8,%rax
  jmp    L11
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: 0123456789ABCDEF

assistant: ```c
char *audit_encode_value(char *final, const char *buf, unsigned int size) {
  unsigned int i;
  char *ptr = final;
  const char *hex = "0123456789ABCDEF";
  if (final == NULL)
    return NULL;
  if (buf == NULL) {
    *final = 0;
    return final;
  }
  for (i = 0; i < size; i++) {
    *ptr++ = hex[(buf[i] & 0xF0) >> 4];
    *ptr++ = hex[buf[i] & 0x0F];
  }
  *ptr = 0;
  return final;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <splitpath@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char *basename(char *path) {
  char *dir, *base;
  splitpath(path, &dir, &base);
  return base;
}
```
user: What is the c source code of the assembly code below:

```asm
<basename>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <splitpath@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *basename(char *path) {
  char *dir, *base;
  splitpath(path, &dir, &base);
  return base;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basename>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <splitpath@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *basename(char *path) {
  char *dir, *base;
  splitpath(path, &dir, &base);
  return base;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<basename>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <splitpath@plt>
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *basename(char *path) {
  char *dir, *base;
  splitpath(path, &dir, &base);
  return base;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_lib_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L20
  mov    $0x1,%eax
  jmp    L36
L20:
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L23
  mov    $0x1,%eax
  jmp    L36
L23:
  mov    $0x0,%eax
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: string
name: read_data
arguments: label: D4
data_type: string

tool: D3: printf

tool: D4: scanf

assistant: ```c
int is_lib_func(char *str) {
  if (!strcmp(str, "printf"))
    return 1;
  else if (!strcmp(str, "scanf"))
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_lib_func>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D12(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L6
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L6:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D12: printf

tool: D0: scanf

assistant: ```c
int is_lib_func(char *str) {
  if (!strcmp(str, "printf"))
    return 1;
  else if (!strcmp(str, "scanf"))
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_lib_func>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L7
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L7:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D7
type: string

tool: D15: printf

tool: D7: scanf

assistant: ```c
int is_lib_func(char *str) {
  if (!strcmp(str, "printf"))
    return 1;
  else if (!strcmp(str, "scanf"))
    return 1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_lib_func>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L6
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L6:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D15: printf

tool: D14: scanf

assistant: ```c
int is_lib_func(char *str) {
  if (!strcmp(str, "printf"))
    return 1;
  else if (!strcmp(str, "scanf"))
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<svc_stop_service>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: Stopping %s... 


assistant: ```c
int svc_stop_service(const char *service_name) {
  printf("Stopping %s... \n", service_name);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<svc_stop_service>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: Stopping %s... 


assistant: ```c
int svc_stop_service(const char *service_name) {
  printf("Stopping %s... \n", service_name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<svc_stop_service>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: Stopping %s... 


assistant: ```c
int svc_stop_service(const char *service_name) {
  printf("Stopping %s... \n", service_name);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<svc_stop_service>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D7: Stopping %s... 


assistant: ```c
int svc_stop_service(const char *service_name) {
  printf("Stopping %s... \n", service_name);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_switch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <do_a@plt>
  mov    $0x0,%eax
  call   <test_condition@plt>
  cmp    $0x23,%eax
  je     L28
  cmp    $0x23,%eax
  jg     L25
  cmp    $0xd,%eax
  je     L20
  cmp    $0x1b,%eax
  jne    L25
L20:
  mov    $0x0,%eax
  call   <do_b@plt>
  jmp    L45
L28:
  mov    $0x0,%eax
  call   <do_c@plt>
  jmp    L45
L25:
  mov    $0x0,%eax
  call   <do_d@plt>
  nop
L45:
  mov    $0x0,%eax
  call   <do_e@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_switch() {
  do_a();
  switch (test_condition()) {
  case 13:
  case 27:
    do_b();
    break;
  case 35:
    do_c();
    break;
  default:
    do_d();
    break;
  }
  do_e();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_switch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <do_a@plt>
  mov    $0x0,%eax
  call   <test_condition@plt>
  cmp    $0x1b,%eax
  je     L48
  cmp    $0x23,%eax
  je     L30
  cmp    $0xd,%eax
  je     L48
  mov    $0x0,%eax
  call   <do_d@plt>
  jmp    L16
L48:
  mov    $0x0,%eax
  call   <do_b@plt>
L16:
  mov    $0x0,%eax
  call   <do_e@plt>
  add    $0x8,%rsp
  ret
L30:
  mov    $0x0,%eax
  call   <do_c@plt>
  jmp    L16
```

assistant: ```c
void test_switch() {
  do_a();
  switch (test_condition()) {
  case 13:
  case 27:
    do_b();
    break;
  case 35:
    do_c();
    break;
  default:
    do_d();
    break;
  }
  do_e();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_switch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_a@plt>
  xor    %eax,%eax
  call   <test_condition@plt>
  cmp    $0x1b,%eax
  je     L13
  cmp    $0x23,%eax
  je     L2
  cmp    $0xd,%eax
  je     L13
  xor    %eax,%eax
  call   <do_d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <do_e@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <do_b@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <do_e@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <do_c@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <do_e@plt>
```

assistant: ```c
void test_switch() {
  do_a();
  switch (test_condition()) {
  case 13:
  case 27:
    do_b();
    break;
  case 35:
    do_c();
    break;
  default:
    do_d();
    break;
  }
  do_e();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_switch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_a@plt>
  xor    %eax,%eax
  call   <test_condition@plt>
  cmp    $0x1b,%eax
  je     L14
  cmp    $0x23,%eax
  je     L3
  cmp    $0xd,%eax
  je     L14
  xor    %eax,%eax
  call   <do_d@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <do_e@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  call   <do_b@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <do_e@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  call   <do_c@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <do_e@plt>
```

assistant: ```c
void test_switch() {
  do_a();
  switch (test_condition()) {
  case 13:
  case 27:
    do_b();
    break;
  case 35:
    do_c();
    break;
  default:
    do_d();
    break;
  }
  do_e();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xc,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x0,-0x7c(%rbp)
  movl   $0x2,-0x78(%rbp)
  movl   $0x1,-0x74(%rbp)
  mov    -0x78(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    (%rax,%rcx,1),%rdx
  mov    -0x74(%rbp),%eax
  mov    %eax,-0x70(%rbp,%rdx,4)
  jmp    L40
L84:
  addl   $0x1,-0x74(%rbp)
  subl   $0x1,-0x7c(%rbp)
  addl   $0x1,-0x78(%rbp)
  cmpl   $0x0,-0x7c(%rbp)
  jns    L116
  cmpl   $0x4,-0x78(%rbp)
  jle    L116
  addl   $0x2,-0x7c(%rbp)
  subl   $0x1,-0x78(%rbp)
L116:
  cmpl   $0x0,-0x7c(%rbp)
  jns    L61
  movl   $0x4,-0x7c(%rbp)
L61:
  cmpl   $0x4,-0x78(%rbp)
  jle    L48
  movl   $0x0,-0x78(%rbp)
L48:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x70(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L82
  addl   $0x2,-0x7c(%rbp)
  subl   $0x1,-0x78(%rbp)
L82:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    (%rax,%rcx,1),%rdx
  mov    -0x74(%rbp),%eax
  mov    %eax,-0x70(%rbp,%rdx,4)
L40:
  cmpl   $0x18,-0x74(%rbp)
  jle    L84
  movl   $0x0,-0x7c(%rbp)
  jmp    L56
L113:
  movl   $0x0,-0x78(%rbp)
  jmp    L105
L46:
  mov    -0x78(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x70(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L105:
  cmpl   $0x4,-0x78(%rbp)
  jle    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x7c(%rbp)
L56:
  cmpl   $0x4,-0x7c(%rbp)
  jle    L113
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %3d

assistant: ```c
void main() {
  int a[5][5] = {0}, i = 0, j = 5 / 2, m = 1;
  a[i][j] = m;
  while (m < 5 * 5) {
    m++;
    i--;
    j++;
    if (i < 0 && j > 5 - 1) {
      i += 2;
      j--;
    }
    if (i < 0)
      i = 5 - 1;
    if (j > 5 - 1)
      j = 0;
    if (a[i][j] != 0) {
      i += 2;
      j--;
    }
    a[i][j] = m;
  }
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++)
      printf("%3d", a[i][j]);
    printf("\n");
  }
}
```