user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L146
L22:
  mov    $0x0,%eax
  call   <clrscr@plt>
  mov    $0x0,%eax
  call   <divider@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <divider@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  call   <rollDice@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x7,-0x14(%rbp)
  je     L23
  cmpl   $0xb,-0x14(%rbp)
  jne    L84
L23:
  addl   $0x1,-0x10(%rbp)
  mov    $0x0,%eax
  call   <divider@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L28
L84:
  cmpl   $0x2,-0x14(%rbp)
  je     L114
  cmpl   $0x3,-0x14(%rbp)
  je     L114
  cmpl   $0xc,-0x14(%rbp)
  jne    L45
L114:
  subl   $0x1,-0x10(%rbp)
  mov    $0x0,%eax
  call   <divider@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L28
L45:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L72
L47:
  mov    $0x0,%eax
  call   <rollDice@plt>
  mov    %eax,-0x14(%rbp)
L72:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L95
  cmpl   $0x7,-0x14(%rbp)
  jne    L47
L95:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L76
  addl   $0x1,-0x10(%rbp)
  mov    $0x0,%eax
  call   <divider@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L28
L76:
  subl   $0x1,-0x10(%rbp)
  mov    $0x0,%eax
  call   <divider@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L28:
  mov    $0x0,%eax
  call   <divider@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <divider@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L146:
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  je     L22
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D47
datatype: string
name: parse_data
arguments: label: D65
datatype: string
name: parse_data
arguments: label: D71
datatype: string
name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D74
datatype: string

tool: D10: Bet: $1

tool: D47: You win!

tool: D65: You lose.

tool: D71: Winnings: $%d


tool: D5: Would you like to continue? (1 = yes, 0 = no) 

tool: D74: %d

assistant: ```c
void main() {
  int cont = 1;
  int points, roll;
  int winnings = 0;
  while (cont == 1) {
    clrscr();
    divider();
    printf("Bet: $1\n");
    divider();
    sleep((unsigned int)1);
    roll = rollDice();
    if ((roll == 7) || (roll == 11)) {
      winnings += 1;
      divider();
      printf("You win!\n");
    } else if ((roll == 2) || (roll == 3) || (roll == 12)) {
      winnings -= 1;
      divider();
      printf("You lose.\n");
    } else {
      points = roll;
      roll = 0;
      while ((roll != points) && (roll != 7)) {
        roll = rollDice();
      }
      if (roll == points) {
        winnings += 1;
        divider();
        printf("You win!\n");
      } else {
        winnings -= 1;
        divider();
        printf("You lose.\n");
      }
    }
    divider();
    sleep((unsigned int)1);
    printf("Winnings: $%d\n", winnings);
    divider();
    sleep((unsigned int)1);
    printf("Would you like to continue? (1 = yes, 0 = no) ");
    scanf("%d", &cont);
  }
}
```