ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_add_timeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x14,-0x14(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <timeval_add@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1e,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x20(%rbp)
  movl   $0xf423f,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <timeval_add@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x20(%rbp)
  movl   $0xf423f,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0xf423f,-0x14(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <timeval_add@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0xf423e,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void test_add_timeval(void) {
  struct timeval a;
  struct timeval b;
  struct timeval c;
  a.tv_sec = 1;
  a.tv_usec = 10;
  ;
  b.tv_sec = 2;
  b.tv_usec = 20;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 30);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 2;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 1);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 999999;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 999998);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_add_timeval>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x14,0xc(%rsp)
  lea    0x8(%rsp),%r12
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <timeval_add@plt>
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1e,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x1,(%rsp)
  movl   $0xf423f,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <timeval_add@plt>
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x1,(%rsp)
  movl   $0xf423f,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0xf423f,0xc(%rsp)
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <timeval_add@plt>
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0xf423e,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_add_timeval(void) {
  struct timeval a;
  struct timeval b;
  struct timeval c;
  a.tv_sec = 1;
  a.tv_usec = 10;
  ;
  b.tv_sec = 2;
  b.tv_usec = 20;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 30);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 2;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 1);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 999999;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 999998);
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_add_timeval>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movabs $0xf423f00000001,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000001,%rax
  lea    0x8(%rsp),%r13
  mov    %rsp,%r12
  lea    0x10(%rsp),%rbp
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x1400000002,%rax
  mov    %rax,0x8(%rsp)
  call   <timeval_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1e,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movabs $0x200000001,%rax
  mov    %rbx,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <timeval_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbx,(%rsp)
  mov    %rbx,0x8(%rsp)
  call   <timeval_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0xf423e,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_add_timeval(void) {
  struct timeval a;
  struct timeval b;
  struct timeval c;
  a.tv_sec = 1;
  a.tv_usec = 10;
  ;
  b.tv_sec = 2;
  b.tv_usec = 20;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 30);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 2;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 1);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 999999;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 999998);
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_add_timeval>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  mov    %rsp,%r12
  lea    0x10(%rsp),%rbp
  mov    D28(%rip),%rax
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  mov    D16(%rip),%rax
  mov    %rax,0x8(%rsp)
  call   <timeval_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1e,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    D27(%rip),%rbx
  mov    D39(%rip),%rax
  mov    %rbx,(%rsp)
  mov    %rax,0x8(%rsp)
  call   <timeval_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbx,(%rsp)
  mov    %rbx,0x8(%rsp)
  call   <timeval_add@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0xf423e,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D28
datatype: byte[8]
name: read_data
arguments: label: D16
datatype: byte[8]
name: read_data
arguments: label: D27
datatype: byte[8]
name: read_data
arguments: label: D39
datatype: byte[8]

tool: {"D28": [0x01,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D16": [0x02,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: {"D27": [0x01,0x00,0x00,0x00,0x3f,0x42,0x0f,0x00]}

tool: {"D39": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
void test_add_timeval(void) {
  struct timeval a;
  struct timeval b;
  struct timeval c;
  a.tv_sec = 1;
  a.tv_usec = 10;
  ;
  b.tv_sec = 2;
  b.tv_usec = 20;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 30);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 2;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 1);
  ;
  a.tv_sec = 1;
  a.tv_usec = 999999;
  ;
  b.tv_sec = 1;
  b.tv_usec = 999999;
  ;
  timeval_add(&c, &a, &b);
  assert(c.tv_sec == 3);
  assert(c.tv_usec == 999998);
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L56
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <single_file@plt>
  jmp    L12
L56:
  mov    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jne    L12
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiple_file@plt>
L12:
  mov    -0x18(%rbp),%eax
  cmp    $0x9,%eax
  jne    L70
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jne    L70
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L70
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L70
  mov    $0x0,%eax
  call   <beauty@plt>
L70:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D29
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D27
type_guessed: string
name: read_data
arguments: tag: D32
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string

tool: D29: clear

tool: D25: Enter the INFECT CODE :

tool: D27: %d%d%d

tool: D32: 


YOU HAD JUST ENTERED 9 1 1
	THIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM

ARE YOU SURE TO CONTINUE??

press
1 for yes
0 for no

:

tool: D22: %d

assistant: ```c
int main(void) {
  int c1, c2, c3, d;
  system("clear");
  printf("Enter the INFECT CODE :");
  scanf("%d%d%d", &c1, &c2, &c3);
  if (c1 == 0)
    single_file(c2, c3);
  else if (c1 == 1)
    multiple_file(c2, c3);
  if (c1 == 9 && c2 == 1 && c3 == 1) {
    printf("\n\n\nYOU HAD JUST ENTERED 9 1 1\n\tTHIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM\n\nARE YOU SURE TO CONTINUE??\n\npress\n1 for yes\n0 for no\n\n:");
    scanf("%d", &d);
    if (d == 1) {
      beauty();
    }
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <system@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L48
  cmp    $0x1,%eax
  je     L22
L98:
  cmpl   $0x9,0x8(%rsp)
  je     L34
L87:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L48:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <single_file@plt>
  jmp    L98
L22:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <multiple_file@plt>
  jmp    L98
L34:
  cmpl   $0x1,0xc(%rsp)
  jne    L87
  cmpl   $0x1,0x10(%rsp)
  jne    L87
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jne    L87
  mov    $0x0,%eax
  call   <beauty@plt>
  jmp    L87
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D41
data_type: string
name: extract_symbolic_data
arguments: data_label: D47
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string

tool: D10: clear

tool: D41: Enter the INFECT CODE :

tool: D47: %d%d%d

tool: D2: 


YOU HAD JUST ENTERED 9 1 1
	THIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM

ARE YOU SURE TO CONTINUE??

press
1 for yes
0 for no

:

tool: D15: %d

assistant: ```c
int main(void) {
  int c1, c2, c3, d;
  system("clear");
  printf("Enter the INFECT CODE :");
  scanf("%d%d%d", &c1, &c2, &c3);
  if (c1 == 0)
    single_file(c2, c3);
  else if (c1 == 1)
    multiple_file(c2, c3);
  if (c1 == 9 && c2 == 1 && c3 == 1) {
    printf("\n\n\nYOU HAD JUST ENTERED 9 1 1\n\tTHIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM\n\nARE YOU SURE TO CONTINUE??\n\npress\n1 for yes\n0 for no\n\n:");
    scanf("%d", &d);
    if (d == 1) {
      beauty();
    }
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L76
  cmp    $0x1,%eax
  je     L71
L99:
  cmpl   $0x9,0x8(%rsp)
  je     L8
L97:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  cmpl   $0x1,0xc(%rsp)
  jne    L97
  cmpl   $0x1,0x10(%rsp)
  jne    L97
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jne    L97
  xor    %eax,%eax
  call   <beauty@plt>
  jmp    L97
L76:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <single_file@plt>
  jmp    L99
L71:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <multiple_file@plt>
  jmp    L99
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D13
data_type: string
name: parse_data
arguments: data_label: D44
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D41
data_type: string

tool: D13: clear

tool: D44: Enter the INFECT CODE :

tool: D20: %d%d%d

tool: D12: 


YOU HAD JUST ENTERED 9 1 1
	THIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM

ARE YOU SURE TO CONTINUE??

press
1 for yes
0 for no

:

tool: D41: %d

assistant: ```c
int main(void) {
  int c1, c2, c3, d;
  system("clear");
  printf("Enter the INFECT CODE :");
  scanf("%d%d%d", &c1, &c2, &c3);
  if (c1 == 0)
    single_file(c2, c3);
  else if (c1 == 1)
    multiple_file(c2, c3);
  if (c1 == 9 && c2 == 1 && c3 == 1) {
    printf("\n\n\nYOU HAD JUST ENTERED 9 1 1\n\tTHIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM\n\nARE YOU SURE TO CONTINUE??\n\npress\n1 for yes\n0 for no\n\n:");
    scanf("%d", &d);
    if (d == 1) {
      beauty();
    }
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <system@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L64
  cmp    $0x1,%eax
  je     L72
L46:
  cmpl   $0x9,0x8(%rsp)
  je     L99
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L99:
  cmpl   $0x1,0xc(%rsp)
  jne    L20
  cmpl   $0x1,0x10(%rsp)
  jne    L20
  lea    D28(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jne    L20
  xor    %eax,%eax
  call   <beauty@plt>
  jmp    L20
L64:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <single_file@plt>
  jmp    L46
L72:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <multiple_file@plt>
  jmp    L46
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string
name: extract_symbolic_data
arguments: tag: D39
type: string

tool: D14: clear

tool: D1: Enter the INFECT CODE :

tool: D9: %d%d%d

tool: D28: 


YOU HAD JUST ENTERED 9 1 1
	THIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM

ARE YOU SURE TO CONTINUE??

press
1 for yes
0 for no

:

tool: D39: %d

assistant: ```c
int main(void) {
  int c1, c2, c3, d;
  system("clear");
  printf("Enter the INFECT CODE :");
  scanf("%d%d%d", &c1, &c2, &c3);
  if (c1 == 0)
    single_file(c2, c3);
  else if (c1 == 1)
    multiple_file(c2, c3);
  if (c1 == 9 && c2 == 1 && c3 == 1) {
    printf("\n\n\nYOU HAD JUST ENTERED 9 1 1\n\tTHIS IS THE MOST DESTRUCTIVE COMMAND TO THIS PROGRAM\n\nARE YOU SURE TO CONTINUE??\n\npress\n1 for yes\n0 for no\n\n:");
    scanf("%d", &d);
    if (d == 1) {
      beauty();
    }
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<LSKeyframeAnimationFunctionEaseInOutQuint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  %xmm3,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movsd  D33(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D21(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L18
  movsd  -0x18(%rbp),%xmm0
  movsd  D33(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  jmp    L19
L18:
  movsd  -0x18(%rbp),%xmm0
  movsd  D33(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x8(%rbp),%xmm0
  movsd  D33(%rip),%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movsd  D33(%rip),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  -0x10(%rbp),%xmm0
L19:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
data_type: byte[8]
name: extract_symbolic_data
arguments: tag: D21
data_type: byte[8]

tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double LSKeyframeAnimationFunctionEaseInOutQuint(double t, double b, double c, double d) {
  if ((t /= d / 2) < 1)
    return c / 2 * t * t * t * t * t + b;
  return c / 2 * ((t -= 2) * t * t * t * t + 2) + b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LSKeyframeAnimationFunctionEaseInOutQuint>:
  endbr64
  mulsd  D26(%rip),%xmm3
  movapd %xmm0,%xmm4
  divsd  %xmm3,%xmm4
  movsd  D21(%rip),%xmm0
  comisd %xmm4,%xmm0
  ja     L2
  movsd  D7(%rip),%xmm0
  subsd  %xmm0,%xmm4
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm4
  mulsd  %xmm4,%xmm3
  addsd  %xmm0,%xmm3
  mulsd  D26(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  ret
L2:
  mulsd  D26(%rip),%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
datatype: byte[8]
name: parse_data
arguments: data_tag: D21
datatype: byte[8]
name: parse_data
arguments: data_tag: D7
datatype: byte[8]

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double LSKeyframeAnimationFunctionEaseInOutQuint(double t, double b, double c, double d) {
  if ((t /= d / 2) < 1)
    return c / 2 * t * t * t * t * t + b;
  return c / 2 * ((t -= 2) * t * t * t * t + 2) + b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LSKeyframeAnimationFunctionEaseInOutQuint>:
  endbr64
  movsd  D13(%rip),%xmm4
  mulsd  %xmm4,%xmm3
  mulsd  %xmm2,%xmm4
  movsd  D9(%rip),%xmm2
  divsd  %xmm3,%xmm0
  comisd %xmm0,%xmm2
  ja     L5
  movsd  D24(%rip),%xmm5
  movapd %xmm0,%xmm3
  subsd  %xmm5,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm5,%xmm2
  mulsd  %xmm4,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mulsd  %xmm0,%xmm4
  movapd %xmm4,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: byte[8]
name: unpack_data
arguments: tag: D9
data_type: byte[8]
name: unpack_data
arguments: tag: D24
data_type: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double LSKeyframeAnimationFunctionEaseInOutQuint(double t, double b, double c, double d) {
  if ((t /= d / 2) < 1)
    return c / 2 * t * t * t * t * t + b;
  return c / 2 * ((t -= 2) * t * t * t * t + 2) + b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LSKeyframeAnimationFunctionEaseInOutQuint>:
  endbr64
  movsd  D2(%rip),%xmm4
  mulsd  %xmm4,%xmm3
  mulsd  %xmm2,%xmm4
  movsd  D29(%rip),%xmm2
  divsd  %xmm3,%xmm0
  comisd %xmm0,%xmm2
  ja     L5
  movsd  D3(%rip),%xmm5
  movapd %xmm0,%xmm3
  subsd  %xmm5,%xmm3
  movapd %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  mulsd  %xmm3,%xmm2
  addsd  %xmm5,%xmm2
  mulsd  %xmm4,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mulsd  %xmm0,%xmm4
  movapd %xmm4,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D29
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D3
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double LSKeyframeAnimationFunctionEaseInOutQuint(double t, double b, double c, double d) {
  if ((t /= d / 2) < 1)
    return c / 2 * t * t * t * t * t + b;
  return c / 2 * ((t -= 2) * t * t * t * t + 2) + b;
}
```