user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L71:
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x4,%eax
  jne    L65
  mov    $0xa,%edi
  call   <putchar@plt>
L65:
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x31,-0x4(%rbp)
  jle    L71
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <genrand@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L16
L82:
  mov    $0x0,%eax
  call   <genrand@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x3e6,-0x4(%rbp)
  jle    L82
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L110
L0:
  mov    $0x0,%eax
  call   <genrand@plt>
  addl   $0x1,-0x4(%rbp)
L110:
  cmpl   $0x1386,-0x4(%rbp)
  jle    L0
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L86
L44:
  mov    $0x0,%eax
  call   <genrand@plt>
  addl   $0x1,-0x4(%rbp)
L86:
  cmpl   $0x270e,-0x4(%rbp)
  jle    L44
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L43
L106:
  mov    $0x0,%eax
  call   <genrand@plt>
  addl   $0x1,-0x4(%rbp)
L43:
  cmpl   $0x4e1e,-0x4(%rbp)
  jle    L106
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
  jmp    L37
L22:
  mov    $0x0,%eax
  call   <genrand@plt>
  addl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0x752e,-0x4(%rbp)
  jle    L22
  mov    $0x0,%eax
  call   <genrand@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D56
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string
name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D30
type_infered: string
name: retrieve_data
arguments: data_label: D29
type_infered: string

tool: D56: %12lu 

tool: D10:  1000: %08lx


tool: D2:  5000: %08lx


tool: D17: 10000: %08lx


tool: D30: 20000: %08lx


tool: D29: 30000: %08lx


assistant: ```c
int main() {
  int j;
  for (j = 0; j < 50; j++) {
    printf("%12lu ", genrand());
    if (j % 5 == 4)
      printf("\n");
  }
  printf("\n");
  genrand();
  for (++j; j < 999; j++) {
    genrand();
  }
  printf(" 1000: %08lx\n", genrand());
  for (++j; j < 4999; j++) {
    genrand();
  }
  printf(" 5000: %08lx\n", genrand());
  for (++j; j < 9999; j++) {
    genrand();
  }
  printf("10000: %08lx\n", genrand());
  for (++j; j < 19999; j++) {
    genrand();
  }
  printf("20000: %08lx\n", genrand());
  for (++j; j < 29999; j++) {
    genrand();
  }
  printf("30000: %08lx\n", genrand());
  return (0);
}
```