ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<byte_copyr>:
  endbr64
  mov    %esi,%eax
  add    %rax,%rdi
  add    %rax,%rdx
  test   %esi,%esi
  je     L13
  movzbl -0x1(%rdx),%eax
  mov    %al,-0x1(%rdi)
  cmp    $0x1,%esi
  je     L13
  movzbl -0x2(%rdx),%eax
  mov    %al,-0x2(%rdi)
  cmp    $0x2,%esi
  je     L13
  movzbl -0x3(%rdx),%eax
  mov    %al,-0x3(%rdi)
  cmp    $0x3,%esi
  jne    L58
  jmp    L53
  cs nopw 0x0(%rax,%rax,1)
L67:
  movzbl -0x1(%rdx),%eax
  mov    %al,-0x1(%rdi)
  cmp    $0x1,%esi
  je     L13
  movzbl -0x2(%rdx),%eax
  mov    %al,-0x2(%rdi)
  cmp    $0x2,%esi
  je     L13
  movzbl -0x3(%rdx),%eax
  mov    %al,-0x3(%rdi)
  cmp    $0x3,%esi
  je     L13
L58:
  movzbl -0x4(%rdx),%eax
  sub    $0x4,%rdx
  sub    $0x4,%rdi
  mov    %al,(%rdi)
  sub    $0x4,%esi
  jne    L67
L13:
  ret
L53:
  ret
```

assistant: ```c
void byte_copyr(void *To, unsigned int n, const void *From) {
  char *to = (char *)To + n;
  const char *from = (char *)From + n;
  for (;;) {
    if (!n)
      return;
    *--to = *--from;
    --n;
    if (!n)
      return;
    *--to = *--from;
    --n;
    if (!n)
      return;
    *--to = *--from;
    --n;
    if (!n)
      return;
    *--to = *--from;
    --n;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<byte_copyr>:
  endbr64
  mov    %esi,%eax
  add    %rax,%rdi
  add    %rax,%rdx
  test   %esi,%esi
  je     L1
  movzbl -0x1(%rdx),%eax
  mov    %al,-0x1(%rdi)
  cmp    $0x1,%esi
  je     L1
  movzbl -0x2(%rdx),%eax
  mov    %al,-0x2(%rdi)
  cmp    $0x2,%esi
  je     L1
  movzbl -0x3(%rdx),%eax
  mov    %al,-0x3(%rdi)
  cmp    $0x3,%esi
  jne    L80
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L11:
  movzbl -0x1(%rdx),%eax
  mov    %al,-0x1(%rdi)
  cmp    $0x1,%esi
  je     L1
  movzbl -0x2(%rdx),%eax
  mov    %al,-0x2(%rdi)
  cmp    $0x2,%esi
  je     L1
  movzbl -0x3(%rdx),%eax
  mov    %al,-0x3(%rdi)
  cmp    $0x3,%esi
  je     L1
L80:
  movzbl -0x4(%rdx),%eax
  sub    $0x4,%rdx
  sub    $0x4,%rdi
  mov    %al,(%rdi)
  sub    $0x4,%esi
  jne    L11
L1:
  ret
L23:
  ret
```

assistant: ```c
void byte_copyr(void *To, unsigned int n, const void *From) {
  char *to = (char *)To + n;
  const char *from = (char *)From + n;
  for (;;) {
    if (!n)
      return;
    *--to = *--from;
    --n;
    if (!n)
      return;
    *--to = *--from;
    --n;
    if (!n)
      return;
    *--to = *--from;
    --n;
    if (!n)
      return;
    *--to = *--from;
    --n;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<incVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void incVector(double *vector, int size, double inc) {
  int i;
  for (i = 0; i < size; i++) {
    vector[i] += inc;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<incVector>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L8:
  movapd %xmm0,%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L8
L3:
  ret
```

assistant: ```c
void incVector(double *vector, int size, double inc) {
  int i;
  for (i = 0; i < size; i++) {
    vector[i] += inc;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<incVector>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L14:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L14
L5:
  ret
```

assistant: ```c
void incVector(double *vector, int size, double inc) {
  int i;
  for (i = 0; i < size; i++) {
    vector[i] += inc;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<incVector>:
  endbr64
  test   %esi,%esi
  jle    L44
  cmp    $0x1,%esi
  je     L27
  mov    %esi,%edx
  movapd %xmm0,%xmm2
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L48:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  addpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L48
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L17
L1:
  cltq
  lea    (%rdi,%rax,8),%rax
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L44:
  ret
  xchg   %ax,%ax
L17:
  ret
L27:
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
void incVector(double *vector, int size, double inc) {
  int i;
  for (i = 0; i < size; i++) {
    vector[i] += inc;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x41,%edi
  call   <lower@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: %c


assistant: ```c
int main(void) {
  printf("%c\n", lower('A'));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <lower@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: %c


assistant: ```c
int main(void) {
  printf("%c\n", lower('A'));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <lower@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %c


assistant: ```c
int main(void) {
  printf("%c\n", lower('A'));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <lower@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: %c


assistant: ```c
int main(void) {
  printf("%c\n", lower('A'));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<PrintArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L3:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L39
  lea    D23(%rip),%rax
  jmp    L17
L39:
  lea    D22(%rip),%rax
L17:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%ecx
  mov    %rax,%rdx
  mov    %ecx,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string

tool: 

tool: D22: , 

tool: D17: %d%s

assistant: ```c
void PrintArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d%s", a[i], (i == n - 1) ? "" : ", ");
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PrintArray>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L12
  mov    %rdi,%r12
  mov    %esi,%r15d
  mov    $0x0,%ebx
  lea    -0x1(%rsi),%ebp
  lea    D29(%rip),%r14
  lea    D28(%rip),%r13
L18:
  cmp    %ebx,%ebp
  mov    %r13,%rdx
  cmove  %r14,%rdx
  mov    (%r12,%rbx,4),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L18
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_infered: string
name: disassemble_data
arguments: data_tag: D28
type_infered: string
name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: 

tool: D28: , 

tool: D8: %d%s

assistant: ```c
void PrintArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d%s", a[i], (i == n - 1) ? "" : ", ");
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrintArray>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r15
  movslq %esi,%rax
  lea    -0x1(%rsi),%r15d
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax)
L11:
  cmp    %ebx,%r15d
  mov    %r12,%rdx
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r14,%rdi
  cmovne %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    0x8(%rsp),%rbx
  jne    L11
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D21
type: string

tool: D0: %d%s

tool: D25: , 

tool: 

assistant: ```c
void PrintArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d%s", a[i], (i == n - 1) ? "" : ", ");
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<PrintArray>:
  endbr64
  test   %esi,%esi
  jle    L32
  push   %r15
  mov    %rdi,%r15
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  lea    -0x1(%rsi),%r13d
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L30
L1:
  mov    (%r15,%rbx,4),%esi
  mov    %r14,%rdx
  cmp    %ebx,%r13d
  jne    L31
  lea    D10(%rip),%rdx
  jmp    L31
L30:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L32:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D28
type_infered: string
name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D28: , 

tool: D25: %d%s

tool: 

assistant: ```c
void PrintArray(int a[], int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d%s", a[i], (i == n - 1) ? "" : ", ");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<filt_u_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x238(%rbp)
  mov    %rsi,-0x240(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rax
  mov    %rax,-0x228(%rbp)
  mov    -0x238(%rbp),%rax
  mov    $0x3e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x220(%rbp)
  mov    -0x238(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x220(%rbp)
  je     L25
  cmpq   $0x0,-0x218(%rbp)
  je     L25
  addq   $0x1,-0x220(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,-0x218(%rbp)
  mov    -0x228(%rbp),%rax
  lea    D43(%rip),%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %eax,-0x22c(%rbp)
  mov    -0x22c(%rbp),%eax
  cltq
  add    %rax,-0x228(%rbp)
  mov    -0x220(%rbp),%rcx
  mov    -0x228(%rbp),%rax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x10,-0x228(%rbp)
  lea    -0x210(%rbp),%rax
  add    $0x200,%rax
  sub    -0x228(%rbp),%rax
  mov    %eax,%esi
  mov    -0x218(%rbp),%rdx
  mov    -0x228(%rbp),%rax
  mov    %rdx,%rcx
  lea    D39(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  lea    -0x210(%rbp),%rcx
  mov    -0x238(%rbp),%rax
  mov    $0x200,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x238(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L25:
  nop
L7:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D43
type_infered: string
name: disassemble_data
arguments: label: D39
type_infered: string
name: disassemble_data
arguments: label: D44
type_infered: string

tool: D5: Product:

tool: D43: <SYS>	

tool: D39:  Find USB device: %s

tool: D44: msg:%s


assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char dst[512];
  char *cur = &dst[0];
  char *p1, *p3;
  int n;
  p1 = strchr(msg, '>');
  p3 = strstr(msg, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p3 += strlen("Product:");
  n = snprintf(cur, 512, "<SYS>\t");
  cur = cur + n;
  memcpy(cur, p1, sizeof("Dec  8 11:12:58 ") - 1);
  cur = cur + (sizeof("Dec  8 11:12:58 ") - 1);
  snprintf(cur, (&dst[0]) + 512 - cur, " Find USB device: %s", p3);
  strncpy(msg, dst, 512);
  printf("msg:%s\n", msg);
}
```
user: What is the c source code of the assembly code below:

```asm
<filt_u_message>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x3e,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rbp,%rbp
  je     L26
  mov    %rax,%r12
  test   %rax,%rax
  je     L26
  lea    D7(%rip),%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%r12
  mov    %rsp,%r14
  lea    D28(%rip),%rdx
  mov    $0x200,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  movslq %eax,%r13
  add    %r14,%r13
  lea    0x1(%rbp),%rsi
  mov    $0x10,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  lea    0x10(%r13),%rdi
  lea    0x200(%rsp),%rsi
  mov    %r12,%rcx
  lea    D15(%rip),%rdx
  sub    %edi,%esi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    $0x200,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D1
type: string

tool: D7: Product:

tool: D28: <SYS>	

tool: D15:  Find USB device: %s

tool: D1: msg:%s


assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char dst[512];
  char *cur = &dst[0];
  char *p1, *p3;
  int n;
  p1 = strchr(msg, '>');
  p3 = strstr(msg, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p3 += strlen("Product:");
  n = snprintf(cur, 512, "<SYS>\t");
  cur = cur + n;
  memcpy(cur, p1, sizeof("Dec  8 11:12:58 ") - 1);
  cur = cur + (sizeof("Dec  8 11:12:58 ") - 1);
  snprintf(cur, (&dst[0]) + 512 - cur, " Find USB device: %s", p3);
  strncpy(msg, dst, 512);
  printf("msg:%s\n", msg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<filt_u_message>:
  endbr64
  push   %r14
  mov    $0x3e,%esi
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strstr@plt>
  test   %rbx,%rbx
  je     L10
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
  mov    %r13,%rdi
  mov    %rsp,%r14
  call   <strlen@plt>
  lea    D39(%rip),%rdx
  mov    $0x200,%esi
  mov    %r14,%rdi
  cltq
  add    %rax,%r12
  xor    %eax,%eax
  call   <snprintf@plt>
  lea    0x1(%rbx),%rsi
  mov    $0x10,%edx
  movslq %eax,%rdi
  lea    (%r14,%rdi,1),%r13
  mov    %r13,%rdi
  call   <memcpy@plt>
  lea    0x10(%r13),%rdi
  mov    %r12,%rcx
  xor    %eax,%eax
  lea    0x200(%rsp),%rsi
  lea    D11(%rip),%rdx
  sub    %edi,%esi
  call   <snprintf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    $0x200,%edx
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
L10:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D39
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string

tool: D9: Product:

tool: D39: <SYS>	

tool: D11:  Find USB device: %s

tool: D24: msg:%s


assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char dst[512];
  char *cur = &dst[0];
  char *p1, *p3;
  int n;
  p1 = strchr(msg, '>');
  p3 = strstr(msg, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p3 += strlen("Product:");
  n = snprintf(cur, 512, "<SYS>\t");
  cur = cur + n;
  memcpy(cur, p1, sizeof("Dec  8 11:12:58 ") - 1);
  cur = cur + (sizeof("Dec  8 11:12:58 ") - 1);
  snprintf(cur, (&dst[0]) + 512 - cur, " Find USB device: %s", p3);
  strncpy(msg, dst, 512);
  printf("msg:%s\n", msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filt_u_message>:
  endbr64
  push   %r14
  mov    $0x3e,%esi
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  call   <strchr@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strstr@plt>
  test   %rbx,%rbx
  je     L0
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %r13,%rdi
  mov    %rsp,%r14
  call   <strlen@plt>
  lea    D0(%rip),%rdx
  mov    $0x200,%esi
  mov    %r14,%rdi
  cltq
  add    %rax,%r12
  xor    %eax,%eax
  call   <snprintf@plt>
  lea    0x1(%rbx),%rsi
  mov    $0x10,%edx
  movslq %eax,%rdi
  lea    (%r14,%rdi,1),%r13
  mov    %r13,%rdi
  call   <memcpy@plt>
  lea    0x10(%r13),%rdi
  mov    %r12,%rcx
  xor    %eax,%eax
  lea    0x200(%rsp),%rsi
  lea    D3(%rip),%rdx
  sub    %edi,%esi
  call   <snprintf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    $0x200,%edx
  call   <strncpy@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string

tool: D23: Product:

tool: D0: <SYS>	

tool: D3:  Find USB device: %s

tool: D19: msg:%s


assistant: ```c
void filt_u_message(char *msg, char *keycat) {
  char dst[512];
  char *cur = &dst[0];
  char *p1, *p3;
  int n;
  p1 = strchr(msg, '>');
  p3 = strstr(msg, "Product:");
  if (!p1 || !p3)
    return;
  p1 += 1;
  p3 += strlen("Product:");
  n = snprintf(cur, 512, "<SYS>\t");
  cur = cur + n;
  memcpy(cur, p1, sizeof("Dec  8 11:12:58 ") - 1);
  cur = cur + (sizeof("Dec  8 11:12:58 ") - 1);
  snprintf(cur, (&dst[0]) + 512 - cur, " Find USB device: %s", p3);
  strncpy(msg, dst, 512);
  printf("msg:%s\n", msg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L68:
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L5
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L5
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L5
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  jmp    L10
L5:
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <game@plt>
  jmp    L68
L10:
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: %d %d %d %d

assistant: ```c
int main() {
  while (1) {
    int s0, r0, s1, r1;
    scanf("%d %d %d %d", &s0, &r0, &s1, &r1);
    if (!s0 && !r0 && !s1 && !r1)
      break;
    game(s0, r0, s1, r1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rbx
  jmp    L14
L0:
  call   <game@plt>
L14:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  mov    %edi,%eax
  or     %esi,%eax
  or     %edx,%eax
  or     %ecx,%eax
  jne    L0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: %d %d %d %d

assistant: ```c
int main() {
  while (1) {
    int s0, r0, s1, r1;
    scanf("%d %d %d %d", &s0, &r0, &s1, &r1);
    if (!s0 && !r0 && !s1 && !r1)
      break;
    game(s0, r0, s1, r1);
  }
  return 0;
}
```