ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<str2mac>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x6,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbp,%rdi
  lea    0x12(%rbx),%rsi
  jmp    L47
L84:
  lea    -0x41(%rdx),%eax
  cmp    $0x5,%al
  ja     L112
  lea    -0x37(%rdx),%eax
  jmp    L1
L73:
  lea    -0x41(%rcx),%edx
  cmp    $0x5,%dl
  ja     L91
  lea    -0x37(%rcx),%edx
L103:
  or     (%rdi),%al
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %al,(%rdi)
  add    $0x3,%rbx
  add    $0x1,%rdi
  cmp    %rsi,%rbx
  je     L100
L47:
  movzbl 0x1(%rbx),%ecx
  movzbl (%rbx),%edx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L1
  lea    -0x61(%rdx),%eax
  cmp    $0x5,%al
  ja     L84
  lea    -0x57(%rdx),%eax
L1:
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L103
  lea    -0x61(%rcx),%edx
  cmp    $0x5,%dl
  ja     L73
  lea    -0x57(%rcx),%edx
  jmp    L103
L100:
  mov    $0x1,%eax
L106:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L112:
  mov    $0x0,%eax
  jmp    L106
L91:
  mov    $0x0,%eax
  jmp    L106
```

assistant: ```c
int str2mac(unsigned char *mac_addr, char *str) {
  int i;
  char high, low;
  char *ptr = str;
  memset(mac_addr, 0, 6);
  for (i = 0; i < 6; i++) {
    high = *ptr;
    low = *(ptr + 1);
    if (high >= 48 && high <= 57)
      high -= 48;
    else if (high >= 97 && high <= 102)
      high -= 87;
    else if (high >= 65 && high <= 70)
      high -= 55;
    else
      return 0;
    if (low >= 48 && low <= 57)
      low -= 48;
    else if (low >= 97 && low <= 102)
      low -= 87;
    else if (low >= 65 && low <= 70)
      low -= 55;
    else
      return 0;
    mac_addr[i] |= high;
    mac_addr[i] = mac_addr[i] << 4;
    mac_addr[i] |= low;
    ptr = ptr + 3;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str2mac>:
  endbr64
  push   %rbp
  mov    $0x6,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    %rbp,%rdi
  lea    0x12(%rbx),%rsi
  jmp    L88
  nopl   (%rax)
L27:
  lea    -0x57(%rdx),%eax
L102:
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L70
  lea    -0x61(%rcx),%edx
  cmp    $0x5,%dl
  ja     L44
  lea    -0x57(%rcx),%edx
L70:
  or     (%rdi),%al
  add    $0x3,%rbx
  add    $0x1,%rdi
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %al,-0x1(%rdi)
  cmp    %rbx,%rsi
  je     L53
L88:
  movzbl (%rbx),%edx
  movzbl 0x1(%rbx),%ecx
  lea    -0x30(%rdx),%eax
  cmp    $0x9,%al
  jbe    L102
  lea    -0x61(%rdx),%eax
  cmp    $0x5,%al
  jbe    L27
  lea    -0x41(%rdx),%eax
  cmp    $0x5,%al
  ja     L12
  lea    -0x37(%rdx),%eax
  jmp    L102
  cs nopw 0x0(%rax,%rax,1)
L44:
  lea    -0x41(%rcx),%edx
  cmp    $0x5,%dl
  ja     L12
  lea    -0x37(%rcx),%edx
  jmp    L70
  nopl   (%rax)
L53:
  mov    $0x1,%eax
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  jmp    L67
```

assistant: ```c
int str2mac(unsigned char *mac_addr, char *str) {
  int i;
  char high, low;
  char *ptr = str;
  memset(mac_addr, 0, 6);
  for (i = 0; i < 6; i++) {
    high = *ptr;
    low = *(ptr + 1);
    if (high >= 48 && high <= 57)
      high -= 48;
    else if (high >= 97 && high <= 102)
      high -= 87;
    else if (high >= 65 && high <= 70)
      high -= 55;
    else
      return 0;
    if (low >= 48 && low <= 57)
      low -= 48;
    else if (low >= 97 && low <= 102)
      low -= 87;
    else if (low >= 65 && low <= 70)
      low -= 55;
    else
      return 0;
    mac_addr[i] |= high;
    mac_addr[i] = mac_addr[i] << 4;
    mac_addr[i] |= low;
    ptr = ptr + 3;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %eax,-0x8(%rbp)
  movl   $0x8badf553,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: oiee

assistant: ```c
void main() {
  int z = "oiee";
  int a = 2343433555;
  printf(z);
  getch();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  movslq %edi,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D5: oiee

assistant: ```c
void main() {
  int z = "oiee";
  int a = 2343433555;
  printf(z);
  getch();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  lea    D2(%rip),%rdi
  sub    $0x8,%rsp
  xor    %eax,%eax
  movslq %edi,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getch@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_infered: string

tool: D2: oiee

assistant: ```c
void main() {
  int z = "oiee";
  int a = 2343433555;
  printf(z);
  getch();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  lea    D3(%rip),%rdi
  sub    $0x8,%rsp
  xor    %eax,%eax
  movslq %edi,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getch@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string

tool: D3: oiee

assistant: ```c
void main() {
  int z = "oiee";
  int a = 2343433555;
  printf(z);
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<testRotateMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <buildMat123@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <outMat@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <rotateMat@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <outMat@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <deleteMat@plt>
  nop
  leave
  ret
```

assistant: ```c
void testRotateMat() {
  int size = 4;
  int **xs = buildMat123(size, size);
  outMat(xs, size, size);
  rotateMat(xs, size);
  outMat(xs, size, size);
  deleteMat(xs, size);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<testRotateMat>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <buildMat123@plt>
  mov    %rax,%rbx
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <outMat@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <rotateMat@plt>
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <outMat@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <deleteMat@plt>
  pop    %rbx
  ret
```

assistant: ```c
void testRotateMat() {
  int size = 4;
  int **xs = buildMat123(size, size);
  outMat(xs, size, size);
  rotateMat(xs, size);
  outMat(xs, size, size);
  deleteMat(xs, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testRotateMat>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <buildMat123@plt>
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <outMat@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <rotateMat@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  mov    $0x4,%edx
  call   <outMat@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  pop    %rbp
  jmp    10a0 <deleteMat@plt>
```

assistant: ```c
void testRotateMat() {
  int size = 4;
  int **xs = buildMat123(size, size);
  outMat(xs, size, size);
  rotateMat(xs, size);
  outMat(xs, size, size);
  deleteMat(xs, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testRotateMat>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  mov    $0x4,%edi
  call   <buildMat123@plt>
  mov    $0x4,%edx
  mov    $0x4,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <outMat@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <rotateMat@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  mov    $0x4,%edx
  call   <outMat@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  pop    %rbp
  jmp    10a0 <deleteMat@plt>
```

assistant: ```c
void testRotateMat() {
  int size = 4;
  int **xs = buildMat123(size, size);
  outMat(xs, size, size);
  rotateMat(xs, size);
  outMat(xs, size, size);
  deleteMat(xs, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L76
L14:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L44
L25:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L44:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L25
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L82
L37:
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L62
L84:
  mov    -0x1c(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L62:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L84
  mov    -0x14(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
L82:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L37
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L2
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x24(%rbp)
L76:
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%eax
  cmp    %eax,%edx
  jle    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L74
  call   <__stack_chk_fail@plt>
L74:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D18
data_type: string
name: disassemble_data
arguments: label: D6
data_type: string

tool: D18: %d %d

tool: D6: %d 

assistant: ```c
int main() {
  int a, b, i, n, j, digit, digitCnt, pow, x;
  scanf("%d %d", &i, &n);
  while (i <= n) {
    a = i;
    digit = 0;
    while (a > 0) {
      a /= 10;
      digit++;
    }
    int sum = 0;
    a = i;
    while (a > 0) {
      for (pow = 1, x = 0; x < digit; x++) {
        pow *= a % 10;
      }
      sum += pow;
      a /= 10;
    }
    if (sum == i) {
      printf("%d ", i);
    }
    i++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%r11d
  lea    D12(%rip),%rbx
  cmp    0x4(%rsp),%r11d
  jle    L82
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L98:
  movslq %r8d,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%eax
  add    %eax,%eax
  mov    %r8d,%ecx
  sub    %eax,%ecx
  mov    $0x0,%eax
  mov    $0x1,%edx
L10:
  imul   %ecx,%edx
  mov    %eax,%esi
  add    $0x1,%eax
  cmp    %esi,%edi
  jg     L10
L24:
  add    %edx,%r10d
  movslq %r8d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %r8d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  cmp    $0x9,%r8d
  jle    L29
  mov    %eax,%r8d
L48:
  mov    $0x1,%edx
  test   %r9d,%r9d
  jg     L98
  jmp    L24
L29:
  cmp    %r10d,%r11d
  je     L56
L95:
  mov    (%rsp),%eax
  lea    0x1(%rax),%r11d
  mov    %r11d,(%rsp)
  cmp    0x4(%rsp),%r11d
  jg     L34
L82:
  mov    %r11d,%edx
  mov    $0x0,%r9d
  mov    $0x0,%r10d
  test   %r11d,%r11d
  jle    L29
L39:
  mov    %edx,%ecx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  mov    %r9d,%edi
  add    $0x1,%r9d
  cmp    $0x9,%ecx
  jg     L39
  mov    %r11d,%r8d
  mov    $0x0,%r10d
  jmp    L48
L56:
  mov    %r11d,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L95
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D12
data_type: string

tool: D10: %d %d

tool: D12: %d 

assistant: ```c
int main() {
  int a, b, i, n, j, digit, digitCnt, pow, x;
  scanf("%d %d", &i, &n);
  while (i <= n) {
    a = i;
    digit = 0;
    while (a > 0) {
      a /= 10;
      digit++;
    }
    int sum = 0;
    a = i;
    while (a > 0) {
      for (pow = 1, x = 0; x < digit; x++) {
        pow *= a % 10;
      }
      sum += pow;
      a /= 10;
    }
    if (sum == i) {
      printf("%d ", i);
    }
    i++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0xcccccccd,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%r9d
  cmp    %r9d,0x4(%rsp)
  jl     L81
  nopl   0x0(%rax)
L53:
  mov    %r9d,%eax
  xor    %ecx,%ecx
  xor    %r11d,%r11d
  test   %r9d,%r9d
  jle    L55
  nopl   (%rax)
L8:
  mov    %eax,%eax
  mov    %ecx,%edi
  lea    0x1(%rcx),%ecx
  mov    %rax,%rdx
  imul   %rbx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  jg     L8
  mov    %r9d,%r10d
  xor    %r11d,%r11d
  nopl   (%rax)
L41:
  mov    %r10d,%r8d
  mov    $0x1,%edx
  mov    %r8,%rsi
  imul   %rbx,%rsi
  shr    $0x23,%rsi
  lea    (%rsi,%rsi,4),%eax
  mov    %r10d,%esi
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  nop
L93:
  mov    %eax,%ecx
  imul   %esi,%edx
  add    $0x1,%eax
  cmp    %ecx,%edi
  jne    L93
  imul   %rbx,%r8
  add    %edx,%r11d
  shr    $0x23,%r8
  cmp    $0x9,%r10d
  jle    L55
  mov    %r8d,%r10d
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L55:
  cmp    %r11d,%r9d
  je     L86
L75:
  mov    (%rsp),%eax
  lea    0x1(%rax),%r9d
  mov    %r9d,(%rsp)
  cmp    0x4(%rsp),%r9d
  jle    L53
L81:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L86:
  mov    %r9d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L75
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D10: %d %d

tool: D5: %d 

assistant: ```c
int main() {
  int a, b, i, n, j, digit, digitCnt, pow, x;
  scanf("%d %d", &i, &n);
  while (i <= n) {
    a = i;
    digit = 0;
    while (a > 0) {
      a /= 10;
      digit++;
    }
    int sum = 0;
    a = i;
    while (a > 0) {
      for (pow = 1, x = 0; x < digit; x++) {
        pow *= a % 10;
      }
      sum += pow;
      a /= 10;
    }
    if (sum == i) {
      printf("%d ", i);
    }
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    $0xcccccccd,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%r9d
  mov    0x4(%rsp),%r10d
  cmp    %r9d,%r10d
  jl     L65
  xchg   %ax,%ax
L101:
  mov    %r9d,%eax
  xor    %ecx,%ecx
  xor    %r12d,%r12d
  test   %r9d,%r9d
  jle    L18
  nopl   (%rax)
L29:
  mov    %eax,%eax
  mov    %ecx,%edi
  lea    0x1(%rcx),%ecx
  mov    %rax,%rdx
  imul   %rbx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  jg     L29
  mov    %r9d,%r11d
  xor    %r12d,%r12d
  nopl   (%rax)
L22:
  mov    %r11d,%r8d
  mov    $0x1,%edx
  mov    %r8,%rsi
  imul   %rbx,%rsi
  shr    $0x23,%rsi
  lea    (%rsi,%rsi,4),%eax
  mov    %r11d,%esi
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  nop
L35:
  mov    %eax,%ecx
  imul   %esi,%edx
  add    $0x1,%eax
  cmp    %ecx,%edi
  jne    L35
  imul   %rbx,%r8
  add    %edx,%r12d
  shr    $0x23,%r8
  cmp    $0x9,%r11d
  jle    L18
  mov    %r8d,%r11d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L18:
  cmp    %r12d,%r9d
  je     L79
  add    $0x1,%r9d
  mov    %r9d,(%rsp)
  cmp    %r10d,%r9d
  jle    L101
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L79:
  mov    %r9d,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%r10d
  lea    0x1(%rax),%r9d
  mov    %r9d,(%rsp)
  cmp    %r9d,%r10d
  jge    L101
  jmp    L65
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D17: %d %d

tool: D11: %d 

assistant: ```c
int main() {
  int a, b, i, n, j, digit, digitCnt, pow, x;
  scanf("%d %d", &i, &n);
  while (i <= n) {
    a = i;
    digit = 0;
    while (a > 0) {
      a /= 10;
      digit++;
    }
    int sum = 0;
    a = i;
    while (a > 0) {
      for (pow = 1, x = 0; x < digit; x++) {
        pow *= a % 10;
      }
      sum += pow;
      a /= 10;
    }
    if (sum == i) {
      printf("%d ", i);
    }
    i++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_parameter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L18
  mov    $0x1,%eax
  jmp    L27
L18:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L8
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int check_parameter(char str, char *tab, int size) {
  int i = 0;
  while (i < size) {
    if (str == tab[i]) {
      return 1;
    }
    i++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<check_parameter>:
  endbr64
  test   %edx,%edx
  jle    L20
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rsi,%rdx,1),%rdx
L11:
  cmp    %dil,(%rax)
  je     L15
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
  mov    $0x0,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int check_parameter(char str, char *tab, int size) {
  int i = 0;
  while (i < size) {
    if (str == tab[i]) {
      return 1;
    }
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_parameter>:
  endbr64
  test   %edx,%edx
  jle    L18
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rax
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rsi
  cmp    %rax,%rsi
  je     L18
L22:
  cmp    %dil,(%rsi)
  jne    L14
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_parameter(char str, char *tab, int size) {
  int i = 0;
  while (i < size) {
    if (str == tab[i]) {
      return 1;
    }
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_parameter>:
  endbr64
  test   %edx,%edx
  jle    L37
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rax
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rsi
  cmp    %rax,%rsi
  je     L37
L22:
  cmp    %dil,(%rsi)
  jne    L35
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L37:
  xor    %eax,%eax
  ret
```

assistant: ```c
int check_parameter(char str, char *tab, int size) {
  int i = 0;
  while (i < size) {
    if (str == tab[i]) {
      return 1;
    }
    i++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wrenUtf8NumBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7f,-0x4(%rbp)
  jg     L42
  mov    $0x1,%eax
  jmp    L64
L42:
  cmpl   $0x7ff,-0x4(%rbp)
  jg     L35
  mov    $0x2,%eax
  jmp    L64
L35:
  cmpl   $0xffff,-0x4(%rbp)
  jg     L16
  mov    $0x3,%eax
  jmp    L64
L16:
  cmpl   $0x10ffff,-0x4(%rbp)
  jg     L61
  mov    $0x4,%eax
  jmp    L64
L61:
  mov    $0x0,%eax
L64:
  pop    %rbp
  ret
```

assistant: ```c
int wrenUtf8NumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wrenUtf8NumBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L2
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L2
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L2
  cmp    $0x10ffff,%edi
  setle  %al
  movzbl %al,%eax
  shl    $0x2,%eax
L2:
  ret
```

assistant: ```c
int wrenUtf8NumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wrenUtf8NumBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L19
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L19
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L19
  xor    %eax,%eax
  cmp    $0x10ffff,%edi
  setle  %al
  shl    $0x2,%eax
L19:
  ret
```

assistant: ```c
int wrenUtf8NumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<wrenUtf8NumBytes>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L24
  mov    $0x2,%eax
  cmp    $0x7ff,%edi
  jle    L24
  mov    $0x3,%eax
  cmp    $0xffff,%edi
  jle    L24
  xor    %eax,%eax
  cmp    $0x10ffff,%edi
  setle  %al
  shl    $0x2,%eax
L24:
  ret
```

assistant: ```c
int wrenUtf8NumBytes(int value) {
  do {
  } while (0);
  if (value <= 0x7f)
    return 1;
  if (value <= 0x7ff)
    return 2;
  if (value <= 0xffff)
    return 3;
  if (value <= 0x10ffff)
    return 4;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<freeaddrinfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L17
L10:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L17:
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void freeaddrinfo(struct addrinfo *ai) {
  while (ai != NULL) {
    struct addrinfo *next = ai->ai_next;
    free(ai);
    ai = next;
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<freeaddrinfo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L19
L10:
  mov    %rbx,%rdi
  mov    (%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L10
L19:
  pop    %rbx
  ret
```

assistant: ```c
void freeaddrinfo(struct addrinfo *ai) {
  while (ai != NULL) {
    struct addrinfo *next = ai->ai_next;
    free(ai);
    ai = next;
  };
}
```