ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<get_wordsize>:
  endbr64
  cmp    $0x1,%edi
  je     L2
  cmp    $0x2,%edi
  je     L3
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  jmp    1050 <errx@plt>
  nop
L3:
  mov    $0x40,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x20,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: Unknown machine word size.

assistant: ```c
int get_wordsize(uint8_t ei_class) {
  switch (ei_class) {
  case 1:
    return 32;
  case 2:
    return 64;
  default:
    errx(1, "Unknown machine word size.");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_wordsize>:
  endbr64
  cmp    $0x1,%edi
  je     L1
  cmp    $0x2,%edi
  je     L10
  lea    D0(%rip),%rsi
  mov    $0x1,%edi
  jmp    1050 <errx@plt>
  nop
L10:
  mov    $0x40,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x20,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: Unknown machine word size.

assistant: ```c
int get_wordsize(uint8_t ei_class) {
  switch (ei_class) {
  case 1:
    return 32;
  case 2:
    return 64;
  default:
    errx(1, "Unknown machine word size.");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x1,-0x20(%rbp)
  jne    L82
  movl   $0x0,-0x8(%rbp)
  jmp    L105
L15:
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L87:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L87
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L105:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L15
  jmp    L80
L82:
  cmpl   $0x2,-0x20(%rbp)
  jne    L80
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L106:
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L47:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movss  (%rdx,%rax,4),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L106
L80:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D21
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string

tool: D15:  %.2f 	

tool: D21: 

 The Inverse Of Matrix Is : 


tool: D13:  %.4f 	

assistant: ```c
void cout(float a[100][100], int n, int show) {
  int i, j;
  if (show == 1)
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.2f \t", a[i][j]);
      printf("\n");
    }
  else if (show == 2) {
    printf("\n\n The Inverse Of Matrix Is : \n\n");
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.4f \t", a[i][j]);
      printf("\n");
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cout>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  cmp    $0x1,%edx
  je     L43
  cmp    $0x2,%edx
  je     L82
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
  imul   $0x194,%rax,%rax
  lea    0x194(%rdi,%rax,1),%r14
  mov    %esi,%ebx
  neg    %rbx
  lea    0x0(,%rbx,4),%r13
  lea    D1(%rip),%r12
L60:
  lea    0x0(%r13,%rbp,1),%rbx
L89:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L89
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x190,%rbp
  cmp    %r14,%rbp
  jne    L60
  jmp    L7
L82:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L7
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rbp
  imul   $0x194,%rax,%rax
  lea    0x194(%r12,%rax,1),%r13
  mov    %ebx,%ebx
  neg    %rbx
  lea    0x0(,%rbx,4),%r14
  lea    D18(%rip),%r12
L57:
  lea    (%r14,%rbp,1),%rbx
L42:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L42
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x190,%rbp
  cmp    %r13,%rbp
  jne    L57
  jmp    L7
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string
name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D18
type: string

tool: D1:  %.2f 	

tool: D26: 

 The Inverse Of Matrix Is : 


tool: D18:  %.4f 	

assistant: ```c
void cout(float a[100][100], int n, int show) {
  int i, j;
  if (show == 1)
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.2f \t", a[i][j]);
      printf("\n");
    }
  else if (show == 2) {
    printf("\n\n The Inverse Of Matrix Is : \n\n");
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.4f \t", a[i][j]);
      printf("\n");
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cout>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  cmp    $0x1,%edx
  je     L64
  cmp    $0x2,%edx
  je     L44
L61:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L64:
  test   %esi,%esi
  jle    L61
  lea    -0x1(%rsi),%eax
  mov    $0xfffffffffffffffc,%r13
  lea    D8(%rip),%r12
  lea    0x0(,%rax,4),%rdx
  imul   $0x194,%rax,%rax
  lea    0x4(%rdi,%rdx,1),%rbp
  sub    %rdx,%r13
  lea    0x194(%rdi,%rax,1),%r14
  nopl   0x0(%rax)
L33:
  lea    0x0(%r13,%rbp,1),%rbx
  nopl   (%rax)
L52:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L52
  mov    $0xa,%edi
  add    $0x190,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  lea    D6(%rip),%rdi
  mov    %esi,0xc(%rsp)
  call   <puts@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L61
  lea    -0x1(%rsi),%eax
  mov    $0xfffffffffffffffc,%r13
  lea    D16(%rip),%r12
  lea    0x0(,%rax,4),%rdx
  imul   $0x194,%rax,%rax
  lea    0x4(%rbx,%rdx,1),%rbp
  sub    %rdx,%r13
  lea    0x194(%rbx,%rax,1),%r14
  xchg   %ax,%ax
L75:
  lea    0x0(%r13,%rbp,1),%rbx
  nopl   (%rax)
L10:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0xa,%edi
  add    $0x190,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L75
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string

tool: D8:  %.2f 	

tool: D6: 

 The Inverse Of Matrix Is : 


tool: D16:  %.4f 	

assistant: ```c
void cout(float a[100][100], int n, int show) {
  int i, j;
  if (show == 1)
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.2f \t", a[i][j]);
      printf("\n");
    }
  else if (show == 2) {
    printf("\n\n The Inverse Of Matrix Is : \n\n");
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.4f \t", a[i][j]);
      printf("\n");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cout>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  cmp    $0x1,%edx
  je     L50
  cmp    $0x2,%edx
  je     L46
L70:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L50:
  test   %esi,%esi
  jle    L70
  lea    -0x1(%rsi),%eax
  mov    $0xfffffffffffffffc,%r13
  lea    D24(%rip),%r12
  lea    0x0(,%rax,4),%rdx
  imul   $0x194,%rax,%rax
  lea    0x4(%rdi,%rdx,1),%rbp
  sub    %rdx,%r13
  lea    0x194(%rdi,%rax,1),%r14
  nopl   0x0(%rax)
L53:
  lea    0x0(%r13,%rbp,1),%rbx
  nopl   (%rax)
L3:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L3
  mov    $0xa,%edi
  add    $0x190,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L53
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  lea    D5(%rip),%rdi
  mov    %esi,0xc(%rsp)
  call   <puts@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L70
  lea    -0x1(%rsi),%eax
  mov    $0xfffffffffffffffc,%r13
  lea    D7(%rip),%r12
  lea    0x0(,%rax,4),%rdx
  imul   $0x194,%rax,%rax
  lea    0x4(%rbx,%rdx,1),%rbp
  sub    %rdx,%r13
  lea    0x194(%rbx,%rax,1),%r14
  xchg   %ax,%ax
L66:
  lea    0x0(%r13,%rbp,1),%rbx
  nopl   (%rax)
L76:
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x4,%rbx
  cvtss2sd -0x4(%rbx),%xmm0
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L76
  mov    $0xa,%edi
  add    $0x190,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L66
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D5
type_infered: string
name: read_data
arguments: label: D7
type_infered: string

tool: D24:  %.2f 	

tool: D5: 

 The Inverse Of Matrix Is : 


tool: D7:  %.4f 	

assistant: ```c
void cout(float a[100][100], int n, int show) {
  int i, j;
  if (show == 1)
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.2f \t", a[i][j]);
      printf("\n");
    }
  else if (show == 2) {
    printf("\n\n The Inverse Of Matrix Is : \n\n");
    for (i = 0; i < n; i++) {
      for (j = 0; j < n; j++)
        printf(" %.4f \t", a[i][j]);
      printf("\n");
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<stringToUnsignedInteger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L15
L17:
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  subl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L6
L2:
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <charToInt@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <fastUnsignedPower10@plt>
  imul   %ebx,%eax
  add    %eax,-0x20(%rbp)
  subl   $0x1,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L2
  mov    -0x20(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int stringToUnsignedInteger(char *str) {
  unsigned int len, c, i, j;
  len = c = 0;
  while (str[c] != '\0') {
    c++;
  }
  j = c;
  c = c - 1;
  for (i = 0; i < j; ++i) {
    len += ((unsigned int)charToInt(str[c])) * fastUnsignedPower10(i);
    c--;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringToUnsignedInteger>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L6
  mov    %rdi,%r12
  mov    $0x0,%ebx
L5:
  mov    %ebx,%r13d
  add    $0x1,%ebx
  mov    %ebx,%eax
  cmpb   $0x0,(%r12,%rax,1)
  jne    L5
  test   %ebx,%ebx
  je     L28
  mov    %r13d,%ebp
  mov    $0x0,%ebx
L30:
  mov    %r13d,%r15d
  sub    %ebp,%r15d
  mov    %ebp,%eax
  movsbl (%r12,%rax,1),%edi
  call   <charToInt@plt>
  mov    %rax,%r14
  mov    %r15d,%edi
  call   <fastUnsignedPower10@plt>
  imul   %r14d,%eax
  add    %eax,%ebx
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L30
L28:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    $0x0,%ebx
  jmp    L28
```

assistant: ```c
unsigned int stringToUnsignedInteger(char *str) {
  unsigned int len, c, i, j;
  len = c = 0;
  while (str[c] != '\0') {
    c++;
  }
  j = c;
  c = c - 1;
  for (i = 0; i < j; ++i) {
    len += ((unsigned int)charToInt(str[c])) * fastUnsignedPower10(i);
    c--;
  }
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stringToUnsignedInteger>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L21
  mov    %rdi,%r14
  xor    %r12d,%r12d
  nopl   (%rax)
L22:
  lea    0x1(%r12),%eax
  mov    %r12d,%r13d
  cmpb   $0x0,(%r14,%rax,1)
  mov    %rax,%r12
  jne    L22
  test   %eax,%eax
  je     L49
  mov    %r13d,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L36:
  mov    %ebx,%eax
  mov    %r13d,%r15d
  movsbl (%r14,%rax,1),%edi
  sub    %ebx,%r15d
  call   <charToInt@plt>
  mov    %r15d,%edi
  mov    %rax,%rbp
  call   <fastUnsignedPower10@plt>
  imul   %ebp,%eax
  add    %eax,%r12d
  sub    $0x1,%ebx
  jae    L36
L49:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %r12d,%r12d
  jmp    L49
```

assistant: ```c
unsigned int stringToUnsignedInteger(char *str) {
  unsigned int len, c, i, j;
  len = c = 0;
  while (str[c] != '\0') {
    c++;
  }
  j = c;
  c = c - 1;
  for (i = 0; i < j; ++i) {
    len += ((unsigned int)charToInt(str[c])) * fastUnsignedPower10(i);
    c--;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stringToUnsignedInteger>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  mov    %rdi,%r15
  xor    %r12d,%r12d
  nop
L56:
  mov    %r12d,%ebp
  add    $0x1,%r12d
  movsbl %al,%edi
  mov    %r12d,%eax
  movzbl (%r15,%rax,1),%eax
  test   %al,%al
  jne    L56
  test   %r12d,%r12d
  je     L28
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  lea    -0x1(%rbp),%r13d
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L40:
  movsbl (%r15,%rax,1),%edi
  mov    %edx,%ebx
L15:
  call   <charToInt@plt>
  mov    %ebx,%edi
  mov    %rax,%r14
  call   <fastUnsignedPower10@plt>
  lea    0x1(%rbx),%edx
  imul   %r14d,%eax
  add    %eax,%r12d
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    %ebx,%ebp
  jne    L40
L28:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %r12d,%r12d
  jmp    L28
```

assistant: ```c
unsigned int stringToUnsignedInteger(char *str) {
  unsigned int len, c, i, j;
  len = c = 0;
  while (str[c] != '\0') {
    c++;
  }
  j = c;
  c = c - 1;
  for (i = 0; i < j; ++i) {
    len += ((unsigned int)charToInt(str[c])) * fastUnsignedPower10(i);
    c--;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compact_arguments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L46
L3:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L58
L53:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L58:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L53
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L36:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L24
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
L24:
  addl   $0x1,-0x8(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L36
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void compact_arguments(int *argc, char ***argv) {
  for (int i = 0; i < *argc; i++) {
    while (i < *argc && !(*argv)[i]) {
      for (int n = i; n < *argc; n++)
        (*argv)[n] = (*argv)[n + 1];
      (*argc)--;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compact_arguments>:
  endbr64
  mov    %rsi,%r8
  mov    $0x8,%r10d
  mov    $0x0,%r9d
  cmpl   $0x0,(%rdi)
  jg     L61
  ret
L1:
  mov    (%r8),%rcx
  mov    (%rcx,%rax,1),%rsi
  mov    %rsi,-0x8(%rcx,%rax,1)
  add    $0x1,%edx
  mov    (%rdi),%ecx
  add    $0x8,%rax
  cmp    %edx,%ecx
  jg     L1
L48:
  sub    $0x1,%ecx
  mov    %ecx,(%rdi)
  cmp    %r9d,%ecx
  jle    L8
L55:
  mov    (%r8),%rax
  cmpq   $0x0,(%rax,%r11,1)
  jne    L8
  mov    (%rdi),%ecx
  mov    %r10,%rax
  mov    %r9d,%edx
  cmp    %r9d,%ecx
  jg     L1
  jmp    L48
L8:
  add    $0x1,%r9d
  add    $0x8,%r10
  cmp    %r9d,(%rdi)
  jle    L85
L61:
  cmp    %r9d,(%rdi)
  jle    L8
  lea    -0x8(%r10),%r11
  jmp    L55
L85:
  ret
```

assistant: ```c
void compact_arguments(int *argc, char ***argv) {
  for (int i = 0; i < *argc; i++) {
    while (i < *argc && !(*argv)[i]) {
      for (int n = i; n < *argc; n++)
        (*argv)[n] = (*argv)[n + 1];
      (*argc)--;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<compact_arguments>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r15d
  mov    %rsi,0x8(%rsp)
  test   %r15d,%r15d
  jle    L58
  xor    %ebx,%ebx
  movq   $0x0,(%rsp)
  mov    %rdi,%r14
  xor    %ebp,%ebp
  mov    $0x8,%r12d
  cmp    %r15d,%ebx
  jge    L67
  nopl   (%rax)
L9:
  mov    0x8(%rsp),%rax
  sub    $0x1,%ebp
  mov    (%rax),%r13
  mov    (%rsp),%rax
  lea    0x0(%r13,%rax,1),%rdi
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L24:
  lea    0x0(%rbp,%r15,1),%eax
  cmp    %r15d,%ebx
  lea    0x0(%r13,%r12,1),%rsi
  lea    0x8(,%rax,8),%rdx
  mov    $0x8,%eax
  cmovge %rax,%rdx
  sub    $0x1,%r15d
  call   <memmove@plt>
  mov    %r15d,(%r14)
  mov    %rax,%rdi
  cmp    %ebx,%r15d
  je     L53
L29:
  cmpq   $0x0,(%rdi)
  je     L24
  mov    (%r14),%r15d
L53:
  add    $0x1,%ebx
  addq   $0x8,(%rsp)
  add    $0x8,%r12
  cmp    %r15d,%ebx
  jl     L9
L58:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  sub    $0x1,%ebp
  jmp    L53
```

assistant: ```c
void compact_arguments(int *argc, char ***argv) {
  for (int i = 0; i < *argc; i++) {
    while (i < *argc && !(*argv)[i]) {
      for (int n = i; n < *argc; n++)
        (*argv)[n] = (*argv)[n + 1];
      (*argc)--;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compact_arguments>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r15d
  mov    %rsi,0x8(%rsp)
  test   %r15d,%r15d
  jle    L34
  xor    %ebx,%ebx
  movq   $0x0,(%rsp)
  mov    %rdi,%r14
  xor    %ebp,%ebp
  mov    $0x8,%r12d
  cmp    %r15d,%ebx
  jge    L18
  nopl   (%rax)
L1:
  mov    0x8(%rsp),%rax
  sub    $0x1,%ebp
  mov    (%rax),%r13
  mov    (%rsp),%rax
  lea    0x0(%r13,%rax,1),%rdi
  jmp    L16
  cs nopw 0x0(%rax,%rax,1)
L59:
  lea    0x0(%rbp,%r15,1),%eax
  cmp    %r15d,%ebx
  lea    0x0(%r13,%r12,1),%rsi
  lea    0x8(,%rax,8),%rdx
  mov    $0x8,%eax
  cmovge %rax,%rdx
  sub    $0x1,%r15d
  call   <memmove@plt>
  mov    %r15d,(%r14)
  mov    %rax,%rdi
  cmp    %ebx,%r15d
  je     L67
L16:
  cmpq   $0x0,(%rdi)
  je     L59
L67:
  add    $0x1,%ebx
  addq   $0x8,(%rsp)
  add    $0x8,%r12
  cmp    %r15d,%ebx
  jl     L1
L34:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  sub    $0x1,%ebp
  jmp    L67
```

assistant: ```c
void compact_arguments(int *argc, char ***argv) {
  for (int i = 0; i < *argc; i++) {
    while (i < *argc && !(*argv)[i]) {
      for (int n = i; n < *argc; n++)
        (*argv)[n] = (*argv)[n + 1];
      (*argc)--;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_sorted_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L38:
  cmpl   $0x9,-0x4(%rbp)
  je     L4
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x9,-0x4(%rbp)
  jle    L38
  jmp    L11
L4:
  nop
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
datatype: string
name: extract_symbolic_data
arguments: tag: D25
datatype: string
name: extract_symbolic_data
arguments: tag: D28
datatype: string

tool: D21: 
Sorted Array is: [

tool: D25: %d, 

tool: D28: %d]


assistant: ```c
void print_sorted_arr(int *a) {
  int i;
  printf("\nSorted Array is: [");
  for (i = 0; i < 10; i++) {
    if (i + 1 == 10)
      break;
    printf("%d, ", a[i]);
  }
  printf("%d]\n", a[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_sorted_arr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  lea    0x24(%rbp),%r13
  lea    D27(%rip),%r12
L3:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L3
  mov    0x24(%rbp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D28: 
Sorted Array is: [

tool: D27: %d, 

tool: D3: %d]


assistant: ```c
void print_sorted_arr(int *a) {
  int i;
  printf("\nSorted Array is: [");
  for (i = 0; i < 10; i++) {
    if (i + 1 == 10)
      break;
    printf("%d, ", a[i]);
  }
  printf("%d]\n", a[i]);
}
```