ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pbhypotenuse_distance>:
  endbr64
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm1
  subsd  %xmm2,%xmm0
  movsd  D9(%rip),%xmm3
  pxor   %xmm2,%xmm2
  mulsd  %xmm3,%xmm4
  mulsd  %xmm3,%xmm1
  mulsd  %xmm3,%xmm0
  cvtsd2ss %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  movapd %xmm4,%xmm0
  jmp    1050 <CalcDistance@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: f64

tool: D9: 3600

assistant: ```c
double pbhypotenuse_distance(double lng1, double lat1, double lng2, double lat2) {
  double latitude = lat1 * 3600;
  float delta_lon = (lng1 - lng2) * 3600;
  float delta_lat = (lat1 - lat2) * 3600;
  return CalcDistance(latitude, delta_lon, delta_lat);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hexci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L7
  cmpb   $0x39,-0x4(%rbp)
  jg     L7
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L59
L7:
  cmpb   $0x40,-0x4(%rbp)
  jle    L36
  cmpb   $0x46,-0x4(%rbp)
  jg     L36
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L59
L36:
  cmpb   $0x60,-0x4(%rbp)
  jle    L77
  cmpb   $0x66,-0x4(%rbp)
  jg     L77
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L59
L77:
  mov    $0xffffffff,%eax
L59:
  pop    %rbp
  ret
```

assistant: ```c
int hexci(char c) {
  if ((c >= '0') && (c <= '9'))
    return (c - '0');
  if ((c >= 'A') && (c <= 'F'))
    return (10 + (c - 'A'));
  if ((c >= 'a') && (c <= 'f'))
    return (10 + (c - 'a'));
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexci>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L12
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L18
  lea    -0x61(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x57,%eax
  cmp    $0x6,%dl
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
L12:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L18:
  movsbl %dil,%edi
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
int hexci(char c) {
  if ((c >= '0') && (c <= '9'))
    return (c - '0');
  if ((c >= 'A') && (c <= 'F'))
    return (10 + (c - 'A'));
  if ((c >= 'a') && (c <= 'f'))
    return (10 + (c - 'a'));
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<hexci>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L15
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L12
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hexci(char c) {
  if ((c >= '0') && (c <= '9'))
    return (c - '0');
  if ((c >= 'A') && (c <= 'F'))
    return (10 + (c - 'A'));
  if ((c >= 'a') && (c <= 'f'))
    return (10 + (c - 'a'));
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexci>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L2
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L12
  lea    -0x61(%rdi),%edx
  lea    -0x57(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0xffffffff,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  sub    $0x37,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hexci(char c) {
  if ((c >= '0') && (c <= '9'))
    return (c - '0');
  if ((c >= 'A') && (c <= 'F'))
    return (10 + (c - 'A'));
  if ((c >= 'a') && (c <= 'f'))
    return (10 + (c - 'a'));
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L118
L130:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L72
L2:
  movl   $0x0,-0x8(%rbp)
  jmp    L96
L42:
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1450,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  test   %al,%al
  je     L3
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1450,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  test   %al,%al
  jne    L21
  movl   $0x1,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  jmp    L13
L21:
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1450,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1450,%rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl (%rcx,%rax,1),%eax
  cmp    %al,%dl
  jl     L90
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1450,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1450,%rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl (%rcx,%rax,1),%eax
  cmp    %al,%dl
  jle    L33
  movl   $0x1,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  jmp    L13
L33:
  addl   $0x1,-0x8(%rbp)
L96:
  cmpl   $0x31,-0x8(%rbp)
  jle    L42
  jmp    L13
L3:
  nop
  jmp    L13
L90:
  nop
L13:
  addl   $0x1,-0x4(%rbp)
L72:
  cmpl   $0x1429,-0x4(%rbp)
  jle    L2
L118:
  cmpl   $0x0,-0xc(%rbp)
  jne    L130
  nop
  nop
  leave
  ret
```

assistant: ```c
void sort(char arr[50][5200]) {
  int swaps_bool = 1;
  int i, j;
  while (swaps_bool) {
    swaps_bool = 0;
    for (j = 0; j < 5162; j++)
      for (i = 0; i < 50; i++) {
        if (arr[i][j] == '\0')
          break;
        if (arr[i][j + 1] == '\0') {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
        if (arr[i][j] < arr[i][j + 1])
          break;
        if (arr[i][j] > arr[i][j + 1]) {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
      }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%r14d
  mov    $0x1,%r13d
  jmp    L78
L56:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %r13d,%esi
L60:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    $0x142a,%ebp
  je     L31
L11:
  lea    -0x3f7a0(%rbx),%rax
L16:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L60
  movzbl 0x1(%rax),%ecx
  test   %cl,%cl
  je     L56
  cmp    %cl,%dl
  jl     L60
  jg     L79
  add    $0x1450,%rax
  cmp    %rbx,%rax
  jne    L16
  jmp    L60
L79:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %r13d,%esi
  jmp    L60
L31:
  test   %esi,%esi
  je     L4
L78:
  lea    0x3f7a0(%r12),%rbx
  mov    $0x0,%ebp
  mov    %r14d,%esi
  jmp    L11
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void sort(char arr[50][5200]) {
  int swaps_bool = 1;
  int i, j;
  while (swaps_bool) {
    swaps_bool = 0;
    for (j = 0; j < 5162; j++)
      for (i = 0; i < 50; i++) {
        if (arr[i][j] == '\0')
          break;
        if (arr[i][j + 1] == '\0') {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
        if (arr[i][j] < arr[i][j + 1])
          break;
        if (arr[i][j] > arr[i][j + 1]) {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
      }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    0x3f7a0(%rdi),%rbp
  push   %rbx
L82:
  mov    %rbp,%r13
  mov    $0x1,%r12d
  xor    %ebx,%ebx
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %ebx,%esi
  lea    (%r14,%rbx,1),%rax
  jmp    L59
L28:
  mov    %rax,%rcx
  sub    %rbx,%rcx
  movzbl (%rcx,%r12,1),%ecx
  test   %cl,%cl
  je     L12
  cmp    %cl,%dl
  jl     L23
  jg     L12
  add    $0x1450,%rax
  cmp    %r13,%rax
  je     L23
L59:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L28
L23:
  add    $0x1,%rbx
  add    $0x1,%r13
  add    $0x1,%r12
  cmp    $0x142a,%rbx
  jne    L27
  test   %edi,%edi
  jne    L82
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L12:
  mov    %r14,%rdi
  call   <swap@plt>
  mov    $0x1,%edi
  jmp    L23
```

assistant: ```c
void sort(char arr[50][5200]) {
  int swaps_bool = 1;
  int i, j;
  while (swaps_bool) {
    swaps_bool = 0;
    for (j = 0; j < 5162; j++)
      for (i = 0; i < 50; i++) {
        if (arr[i][j] == '\0')
          break;
        if (arr[i][j + 1] == '\0') {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
        if (arr[i][j] < arr[i][j + 1])
          break;
        if (arr[i][j] > arr[i][j + 1]) {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
      }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    0x3f7a0(%rdi),%rbp
  push   %rbx
L25:
  mov    %rbp,%r13
  mov    $0x1,%r12d
  xor    %ebx,%ebx
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %ebx,%esi
  lea    (%r14,%rbx,1),%rax
  jmp    L33
L32:
  mov    %rax,%rcx
  sub    %rbx,%rcx
  movzbl (%rcx,%r12,1),%ecx
  test   %cl,%cl
  je     L76
  cmp    %cl,%dl
  jl     L74
  jg     L76
  add    $0x1450,%rax
  cmp    %r13,%rax
  je     L74
L33:
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L32
L74:
  add    $0x1,%rbx
  add    $0x1,%r13
  add    $0x1,%r12
  cmp    $0x142a,%rbx
  jne    L17
  test   %edi,%edi
  jne    L25
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L76:
  mov    %r14,%rdi
  call   <swap@plt>
  mov    $0x1,%edi
  jmp    L74
```

assistant: ```c
void sort(char arr[50][5200]) {
  int swaps_bool = 1;
  int i, j;
  while (swaps_bool) {
    swaps_bool = 0;
    for (j = 0; j < 5162; j++)
      for (i = 0; i < 50; i++) {
        if (arr[i][j] == '\0')
          break;
        if (arr[i][j + 1] == '\0') {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
        if (arr[i][j] < arr[i][j + 1])
          break;
        if (arr[i][j] > arr[i][j + 1]) {
          swaps_bool = 1;
          swap(arr, j);
          break;
        }
      }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x6,%eax
  int    $0x82
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Physical memory usage data:


assistant: ```c
int main(void) {
  puts("Physical memory usage data:\n");
  __asm__("int $0x82" ::"a"(0x06));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%eax
  int    $0x82
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: Physical memory usage data:


assistant: ```c
int main(void) {
  puts("Physical memory usage data:\n");
  __asm__("int $0x82" ::"a"(0x06));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%eax
  int    $0x82
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: Physical memory usage data:


assistant: ```c
int main(void) {
  puts("Physical memory usage data:\n");
  __asm__("int $0x82" ::"a"(0x06));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x6,%eax
  int    $0x82
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: Physical memory usage data:


assistant: ```c
int main(void) {
  puts("Physical memory usage data:\n");
  __asm__("int $0x82" ::"a"(0x06));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L27
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L27:
  cmpl   $0x2,-0x14(%rbp)
  je     L10
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L10:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D13(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L7
L29:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <findWords@plt>
L7:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D26
datatype: string
name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D34
datatype: string
name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D26: Memoria insuficient!

tool: D6: %s

tool: D34: Utilitzacio: %s <nom fitxer>


tool: D18: r

tool: D13: Ha succeit un problema al obrir obrir el fitxer!

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char *line = malloc(sizeof(char) * 100);
  if (line == NULL) {
    printf("%s", "Memoria insuficient!");
    exit(1);
  }
  if (argc != 2) {
    printf("Utilitzacio: %s <nom fitxer>\n", argv[0]);
    exit(2);
  }
  fp = fopen(argv[1], "r");
  if (!fp) {
    printf("%s", "Ha succeit un problema al obrir obrir el fitxer!");
    exit(3);
  }
  while (fgets(line, 100, fp) != NULL)
    findWords(line);
  fclose(fp);
  free(line);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L45
L54:
  cmp    $0x2,%r12d
  jne    L29
L64:
  mov    0x8(%rbp),%rdi
  lea    D55(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L24
  lea    D53(%rip),%rsi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L24
L45:
  lea    D32(%rip),%rsi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L54
L29:
  mov    0x0(%rbp),%rsi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  jmp    L64
L10:
  mov    %rbx,%rdi
  call   <findWords@plt>
L24:
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D55
type: string
name: disassemble_data
arguments: data_label: D53
type: string
name: disassemble_data
arguments: data_label: D40
type: string
name: disassemble_data
arguments: data_label: D32
type: string
name: disassemble_data
arguments: data_label: D20
type: string

tool: D55: r

tool: D53: Ha succeit un problema al obrir obrir el fitxer!

tool: D40: %s

tool: D32: Memoria insuficient!

tool: D20: Utilitzacio: %s <nom fitxer>


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char *line = malloc(sizeof(char) * 100);
  if (line == NULL) {
    printf("%s", "Memoria insuficient!");
    exit(1);
  }
  if (argc != 2) {
    printf("Utilitzacio: %s <nom fitxer>\n", argv[0]);
    exit(2);
  }
  fp = fopen(argv[1], "r");
  if (!fp) {
    printf("%s", "Ha succeit un problema al obrir obrir el fitxer!");
    exit(3);
  }
  while (fgets(line, 100, fp) != NULL)
    findWords(line);
  fclose(fp);
  free(line);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L45
L10:
  cmp    $0x2,%ebx
  je     L7
  mov    (%r12),%rsi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L7:
  mov    0x8(%r12),%rdi
  lea    D20(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L33
  jmp    L64
  nopl   0x0(%rax)
L44:
  mov    %rbp,%rdi
  call   <findWords@plt>
L33:
  mov    %r12,%rdx
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L44
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L45:
  lea    D17(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
L64:
  lea    D0(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L33
```

tool_calls: name: retrieve_data
arguments: label: D32
type: string
name: retrieve_data
arguments: label: D20
type: string
name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D3
type: string
name: retrieve_data
arguments: label: D0
type: string

tool: D32: Utilitzacio: %s <nom fitxer>


tool: D20: r

tool: D17: Memoria insuficient!

tool: D3: %s

tool: D0: Ha succeit un problema al obrir obrir el fitxer!

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char *line = malloc(sizeof(char) * 100);
  if (line == NULL) {
    printf("%s", "Memoria insuficient!");
    exit(1);
  }
  if (argc != 2) {
    printf("Utilitzacio: %s <nom fitxer>\n", argv[0]);
    exit(2);
  }
  fp = fopen(argv[1], "r");
  if (!fp) {
    printf("%s", "Ha succeit un problema al obrir obrir el fitxer!");
    exit(3);
  }
  while (fgets(line, 100, fp) != NULL)
    findWords(line);
  fclose(fp);
  free(line);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L53
L14:
  cmp    $0x2,%ebx
  je     L13
  mov    (%r12),%rsi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%edi
  call   <exit@plt>
L13:
  mov    0x8(%r12),%rdi
  lea    D23(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L38
  jmp    L39
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  call   <findWords@plt>
L38:
  mov    %r12,%rdx
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L1
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L53:
  lea    D24(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L14
L39:
  lea    D16(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%edi
  call   <exit@plt>
  jmp    L38
```

tool_calls: name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D23
type_guessed: string
name: retrieve_data
arguments: data_label: D24
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D36: Utilitzacio: %s <nom fitxer>


tool: D23: r

tool: D24: Memoria insuficient!

tool: D12: %s

tool: D16: Ha succeit un problema al obrir obrir el fitxer!

assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char *line = malloc(sizeof(char) * 100);
  if (line == NULL) {
    printf("%s", "Memoria insuficient!");
    exit(1);
  }
  if (argc != 2) {
    printf("Utilitzacio: %s <nom fitxer>\n", argv[0]);
    exit(2);
  }
  fp = fopen(argv[1], "r");
  if (!fp) {
    printf("%s", "Ha succeit un problema al obrir obrir el fitxer!");
    exit(3);
  }
  while (fgets(line, 100, fp) != NULL)
    findWords(line);
  fclose(fp);
  free(line);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strsplit_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  movl   $0x3,(%rdx)
  mov    $0x3,%eax
L83:
  cltq
  movl   $0x0,(%rbx,%rax,4)
  mov    (%rbx),%eax
  sub    $0x1,%eax
  mov    %eax,(%rbx)
  jne    L83
  lea    0x1(%rcx),%rdx
  movzbl 0x1(%rdi,%rcx,1),%eax
  test   %al,%al
  jne    L20
L133:
  mov    0x8(%rbx),%eax
  lea    0x2(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    0xc(%rbx),%eax
  lea    0x1(%rax),%edx
  mov    %edx,0xc(%rbx)
  cmp    0x8(%rbx),%eax
  jg     L113
L128:
  mov    0x4(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  movslq 0xc(%rbx),%rax
  mov    %rdx,-0x8(%rbp,%rax,8)
  mov    0xc(%rbx),%eax
  lea    0x1(%rax),%edx
  mov    %edx,0xc(%rbx)
  cmp    0x8(%rbx),%eax
  jle    L128
L113:
  movl   $0x3,(%rbx)
  mov    $0x3,%eax
L8:
  cltq
  movl   $0xffffffff,(%rbx,%rax,4)
  mov    (%rbx),%eax
  sub    $0x1,%eax
  mov    %eax,(%rbx)
  jne    L8
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L129:
  mov    (%rbx),%eax
  cmp    0x4(%rbx),%eax
  jle    L141
  mov    %eax,0x4(%rbx)
L141:
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L133
L20:
  cmp    %al,%sil
  je     L129
  mov    0x8(%rbx),%eax
  add    $0x1,%eax
  mov    %eax,0x8(%rbx)
  je     L129
  movzbl (%rdi,%rdx,1),%eax
  cmp    %al,%sil
  je     L129
  test   %al,%al
  je     L129
L16:
  mov    (%rbx),%eax
  add    $0x1,%eax
  mov    %eax,(%rbx)
  je     L129
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  cmp    %sil,%al
  je     L129
  test   %al,%al
  jne    L16
  jmp    L129
```

assistant: ```c
char **ft_strsplit_init(char const *s, char c, int *v, size_t i) {
  char **av;
  v[0] = 4;
  while (--v[0])
    v[v[0]] = 0;
  while (s[++i]) {
    if (s[i] != c && (v[2] = v[2] + 1))
      while (s[i] && s[i] != c && (v[0] = v[0] + 1))
        i++;
    if ((v[0] > v[1]) && (v[1] = v[0]))
      ;
  }
  av = (char **)malloc(sizeof(char *) * v[2] + 2);
  while ((++v[3] - 1) <= v[2])
    av[v[3] - 1] = (char *)malloc(sizeof(char) * v[1]);
  v[0] = 4;
  while (--v[0])
    v[v[0]] = -1;
  return (av);
}
```