ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<digits_only>:
  endbr64
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L18:
  sub    $0x30,%eax
  add    $0x1,%rdi
  cmp    $0x9,%eax
  ja     L2
L15:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L18
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int digits_only(const char *s) {
  while (*s)
    if (!isdigit(*s++))
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<digits_only>:
  endbr64
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L23:
  sub    $0x30,%eax
  add    $0x1,%rdi
  cmp    $0x9,%eax
  ja     L11
L25:
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L23
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int digits_only(const char *s) {
  while (*s)
    if (!isdigit(*s++))
      return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_inode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L57
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
L57:
  lea    D14(%rip),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L47
L10:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L79
  addq   $0x1,-0x20(%rbp)
L47:
  jmp    L79
L59:
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <ilookup_name@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L23
  mov    $0xffffffff,%eax
  jmp    L55
L23:
  mov    -0x20(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L79
  addq   $0x1,-0x20(%rbp)
L79:
  cmpq   $0x0,-0x20(%rbp)
  jne    L59
  mov    -0x4(%rbp),%eax
L55:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D14
data_type: string

tool: D13: /

tool: D14: .

assistant: ```c
int find_inode(struct minix_fs_dat *fs, const char *path) {
  int inode = 1;
  if (!strcmp(path, "/") || path[0] == 0) {
    path = ".";
  } else if (path[0] == '/')
    ++path;
  while (path) {
    inode = ilookup_name(fs, inode, path, NULL, NULL);
    if (inode == -1)
      return -1;
    path = strchr(path, '/');
    if (path)
      path++;
  }
  return inode;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_inode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L58
  movzbl (%rbx),%eax
  test   %al,%al
  je     L24
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  jmp    L6
L58:
  lea    D17(%rip),%rbx
L6:
  mov    $0x1,%ebp
L34:
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <ilookup_name@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L59
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L59
  lea    0x1(%rax),%rbx
  jmp    L34
L24:
  lea    D17(%rip),%rbx
  jmp    L6
L59:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D17
type: string

tool: D7: /

tool: D17: .

assistant: ```c
int find_inode(struct minix_fs_dat *fs, const char *path) {
  int inode = 1;
  if (!strcmp(path, "/") || path[0] == 0) {
    path = ".";
  } else if (path[0] == '/')
    ++path;
  while (path) {
    inode = ilookup_name(fs, inode, path, NULL, NULL);
    if (inode == -1)
      return -1;
    path = strchr(path, '/');
    if (path)
      path++;
  }
  return inode;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_inode>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmpb   $0x2f,(%rsi)
  mov    %rdi,%rbx
  jne    L36
  cmpb   $0x0,0x1(%rsi)
  jne    L36
L43:
  lea    D1(%rip),%rbp
L34:
  mov    $0x1,%r12d
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    %r12d,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <ilookup_name@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L47
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L47
  lea    0x1(%rax),%rbp
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L36:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L43
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  jmp    L34
  nopl   (%rax)
L47:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_guessed: string

tool: D1: .

assistant: ```c
int find_inode(struct minix_fs_dat *fs, const char *path) {
  int inode = 1;
  if (!strcmp(path, "/") || path[0] == 0) {
    path = ".";
  } else if (path[0] == '/')
    ++path;
  while (path) {
    inode = ilookup_name(fs, inode, path, NULL, NULL);
    if (inode == -1)
      return -1;
    path = strchr(path, '/');
    if (path)
      path++;
  }
  return inode;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_inode>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cmpb   $0x2f,(%rsi)
  mov    %rdi,%rbx
  jne    L22
  cmpb   $0x0,0x1(%rsi)
  jne    L22
L66:
  lea    D9(%rip),%rbp
L12:
  mov    $0x1,%r12d
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %r12d,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <ilookup_name@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L45
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L45
  lea    0x1(%rax),%rbp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L22:
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L66
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbp
  jmp    L12
  nopl   (%rax)
L45:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: .

assistant: ```c
int find_inode(struct minix_fs_dat *fs, const char *path) {
  int inode = 1;
  if (!strcmp(path, "/") || path[0] == 0) {
    path = ".";
  } else if (path[0] == '/')
    ++path;
  while (path) {
    inode = ilookup_name(fs, inode, path, NULL, NULL);
    if (inode == -1)
      return -1;
    path = strchr(path, '/');
    if (path)
      path++;
  }
  return inode;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test@plt>
  jmp    L7
L2:
  addq   $0x8,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L7:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L2
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test();
  while (--argc)
    puts(*++argv);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <test@plt>
  cmp    $0x1,%ebp
  je     L9
  lea    -0x1(%rbp),%eax
  lea    (%rbx,%rax,8),%rbp
L11:
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L11
L9:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test();
  while (--argc)
    puts(*++argv);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <test@plt>
  cmp    $0x1,%ebp
  je     L11
  lea    -0x1(%rbp),%eax
  lea    (%rbx,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L3
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test();
  while (--argc)
    puts(*++argv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <test@plt>
  cmp    $0x1,%ebp
  je     L3
  lea    -0x1(%rbp),%eax
  lea    (%rbx,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L6:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L6
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test();
  while (--argc)
    puts(*++argv);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x40(%rbp)
  movl   $0x3,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0xc,-0x18(%rbp)
  movl   $0xb,-0x48(%rbp)
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sortByFrequency@plt>
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    %eax,-0x44(%rbp)
  mov    -0x48(%rbp),%eax
  sub    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: %d

assistant: ```c
int main() {
  int p;
  int arr[] = {2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12};
  int n = sizeof(arr) / sizeof(arr[0]);
  sortByFrequency(arr, n);
  p = printArray(arr, n);
  printf("%d", (n - p));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0xc,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x3,0x24(%rsp)
  movl   $0xc,0x28(%rsp)
  mov    %rsp,%rbx
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <sortByFrequency@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <printArray@plt>
  mov    $0xb,%esi
  sub    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: %d

assistant: ```c
int main() {
  int p;
  int arr[] = {2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12};
  int n = sizeof(arr) / sizeof(arr[0]);
  sortByFrequency(arr, n);
  p = printArray(arr, n);
  printf("%d", (n - p));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  movabs $0x400000002,%rdx
  push   %rbp
  mov    $0xb,%esi
  movabs $0xc00000005,%rcx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x300000002,%rax
  mov    %rsp,%rbp
  mov    %rdx,0x8(%rsp)
  mov    %rbp,%rdi
  mov    %rcx,0x10(%rsp)
  movl   $0xc,0x28(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x18(%rsp)
  add    $0x1,%rax
  mov    %rax,0x20(%rsp)
  call   <sortByFrequency@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xb,%esi
  lea    D3(%rip),%rdi
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: %d

assistant: ```c
int main() {
  int p;
  int arr[] = {2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12};
  int n = sizeof(arr) / sizeof(arr[0]);
  sortByFrequency(arr, n);
  p = printArray(arr, n);
  printf("%d", (n - p));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xb,%esi
  sub    $0x40,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D34(%rip),%rax
  movl   $0xc,0x28(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D37(%rip),%xmm0
  mov    %rbp,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <sortByFrequency@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  call   <printArray@plt>
  mov    $0xb,%esi
  lea    D12(%rip),%rdi
  sub    %eax,%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: byte[16]
name: unpack_data
arguments: data_label: D34
data_type: byte[8]
name: unpack_data
arguments: data_label: D37
data_type: byte[16]
name: unpack_data
arguments: data_label: D12
data_type: string

tool: {"D6": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D34": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D37": [0x05,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D12: %d

assistant: ```c
int main() {
  int p;
  int arr[] = {2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12};
  int n = sizeof(arr) / sizeof(arr[0]);
  sortByFrequency(arr, n);
  p = printArray(arr, n);
  printf("%d", (n - p));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fget32_@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void get_uint32(FILE *fp, int *next_offset, uint32_t *val) {
  *val = fget32_(fp);
  *next_offset = *next_offset + 4;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_uint32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  call   <fget32_@plt>
  mov    %eax,0x0(%rbp)
  addl   $0x4,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void get_uint32(FILE *fp, int *next_offset, uint32_t *val) {
  *val = fget32_(fp);
  *next_offset = *next_offset + 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_uint32>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <fget32_@plt>
  mov    %eax,0x0(%rbp)
  addl   $0x4,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void get_uint32(FILE *fp, int *next_offset, uint32_t *val) {
  *val = fget32_(fp);
  *next_offset = *next_offset + 4;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_uint32>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <fget32_@plt>
  mov    %eax,0x0(%rbp)
  addl   $0x4,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void get_uint32(FILE *fp, int *next_offset, uint32_t *val) {
  *val = fget32_(fp);
  *next_offset = *next_offset + 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<round_f_inverse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  lea    0x4(%rdi),%r14
  lea    0x4(%rsi),%r15
  mov    (%rsi),%r12d
  mov    %r12d,%edi
  call   <rot32l8@plt>
  mov    %eax,0x8(%rsp)
  mov    0x0(%rbp),%edi
  call   <rot32r8@plt>
  xor    (%rbx),%r12d
  xor    0x8(%rsp),%r12d
  xor    %eax,%r12d
  mov    %r12d,(%rbx)
  lea    0x2c(%r13),%r12
  lea    0x20(%r13),%rax
  mov    %rax,0x8(%rsp)
L35:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  sub    $0x4,%r12
  cmp    0x8(%rsp),%r12
  jne    L35
  lea    0x20(%r13),%r12
  lea    0x14(%r13),%rax
  mov    %rax,0x8(%rsp)
L26:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  sub    $0x4,%r12
  cmp    0x8(%rsp),%r12
  jne    L26
  mov    (%rbx),%r12d
  mov    %r12d,%edi
  call   <rot32l8@plt>
  mov    %eax,0x8(%rsp)
  mov    (%rbx),%edi
  call   <rot32r8@plt>
  xor    0x0(%rbp),%r12d
  xor    0x8(%rsp),%r12d
  xor    %eax,%r12d
  mov    %r12d,0x0(%rbp)
  lea    0x14(%r13),%r12
  lea    0x8(%r13),%rax
  mov    %rax,0x8(%rsp)
L33:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  sub    $0x4,%r12
  cmp    0x8(%rsp),%r12
  jne    L33
  lea    0x8(%r13),%rbp
L25:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <speckey_inverse@plt>
  mov    0x0(%rbp),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,(%rbx)
  mov    %rbp,%rax
  sub    $0x4,%rbp
  cmp    %r13,%rax
  jne    L25
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void round_f_inverse(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  int8_t i;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  *left ^= *right ^ rot32l8(*right) ^ rot32r8(*right);
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b0_l, b0_r);
    *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 9]);
  }
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b1_l, b1_r);
    *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 6]);
  }
  *right ^= *left ^ rot32l8(*left) ^ rot32r8(*left);
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b1_l, b1_r);
    *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 3]);
  }
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b0_l, b0_r);
    *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<round_f_inverse>:
  endbr64
  push   %r15
  lea    0x4(%rsi),%r15
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%r12d
  mov    %rdx,(%rsp)
  mov    %r12d,%edi
  call   <rot32l8@plt>
  mov    0x0(%r13),%edi
  mov    %eax,%ebx
  call   <rot32r8@plt>
  xor    0x0(%rbp),%r12d
  xor    %ebx,%r12d
  xor    %eax,%r12d
  mov    (%rsp),%rax
  mov    %r12d,0x0(%rbp)
  lea    0x2c(%rax),%rbx
  lea    0x20(%rax),%r12
L19:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  sub    $0x4,%rbx
  call   <speckey_inverse@plt>
  mov    0x4(%rbx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  cmp    %r12,%rbx
  jne    L19
  mov    (%rsp),%rax
  lea    0x14(%rax),%r12
L38:
  mov    %r15,%rsi
  mov    %r13,%rdi
  sub    $0x4,%rbx
  call   <speckey_inverse@plt>
  mov    0x4(%rbx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%r13)
  cmp    %r12,%rbx
  jne    L38
  mov    0x0(%rbp),%edx
  mov    %edx,%edi
  mov    %edx,0xc(%rsp)
  call   <rot32l8@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%r12d
  call   <rot32r8@plt>
  mov    0xc(%rsp),%edx
  xor    0x0(%r13),%edx
  xor    %r12d,%edx
  xor    %eax,%edx
  mov    (%rsp),%rax
  mov    %edx,0x0(%r13)
  lea    0x8(%rax),%r12
L7:
  mov    %r15,%rsi
  mov    %r13,%rdi
  sub    $0x4,%rbx
  call   <speckey_inverse@plt>
  mov    0x4(%rbx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%r13)
  cmp    %rbx,%r12
  jne    L7
L14:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r12,%rax
  sub    $0x4,%r12
  cmp    (%rsp),%rax
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void round_f_inverse(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  int8_t i;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  *left ^= *right ^ rot32l8(*right) ^ rot32r8(*right);
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b0_l, b0_r);
    *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 9]);
  }
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b1_l, b1_r);
    *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 6]);
  }
  *right ^= *left ^ rot32l8(*left) ^ rot32r8(*left);
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b1_l, b1_r);
    *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 3]);
  }
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b0_l, b0_r);
    *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<round_f_inverse>:
  endbr64
  push   %r15
  lea    0x4(%rsi),%r15
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%r12d
  mov    %rdx,(%rsp)
  mov    %r12d,%edi
  call   <rot32l8@plt>
  mov    0x0(%r13),%edi
  mov    %eax,%ebx
  call   <rot32r8@plt>
  xor    0x0(%rbp),%r12d
  xor    %ebx,%r12d
  xor    %eax,%r12d
  mov    (%rsp),%rax
  mov    %r12d,0x0(%rbp)
  lea    0x2c(%rax),%rbx
  lea    0x20(%rax),%r12
L36:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  sub    $0x4,%rbx
  call   <speckey_inverse@plt>
  mov    0x4(%rbx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  cmp    %r12,%rbx
  jne    L36
  mov    (%rsp),%rax
  lea    0x14(%rax),%r12
L19:
  mov    %r15,%rsi
  mov    %r13,%rdi
  sub    $0x4,%rbx
  call   <speckey_inverse@plt>
  mov    0x4(%rbx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%r13)
  cmp    %r12,%rbx
  jne    L19
  mov    0x0(%rbp),%edx
  mov    %edx,%edi
  mov    %edx,0xc(%rsp)
  call   <rot32l8@plt>
  mov    0x0(%rbp),%edi
  mov    %eax,%r12d
  call   <rot32r8@plt>
  mov    0xc(%rsp),%edx
  xor    0x0(%r13),%edx
  xor    %r12d,%edx
  xor    %eax,%edx
  mov    (%rsp),%rax
  mov    %edx,0x0(%r13)
  lea    0x8(%rax),%r12
L10:
  mov    %r15,%rsi
  mov    %r13,%rdi
  sub    $0x4,%rbx
  call   <speckey_inverse@plt>
  mov    0x4(%rbx),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%r13)
  cmp    %rbx,%r12
  jne    L10
L8:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <speckey_inverse@plt>
  mov    (%r12),%edi
  call   <READ_ROUND_KEY_DOUBLE_WORD@plt>
  xor    %eax,0x0(%rbp)
  mov    %r12,%rax
  sub    $0x4,%r12
  cmp    (%rsp),%rax
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void round_f_inverse(uint32_t *left, uint32_t *right, uint32_t *roundKeys) {
  int8_t i;
  uint16_t *b0_l = (uint16_t *)left;
  uint16_t *b0_r = (uint16_t *)left + 1;
  uint16_t *b1_l = (uint16_t *)right;
  uint16_t *b1_r = (uint16_t *)right + 1;
  *left ^= *right ^ rot32l8(*right) ^ rot32r8(*right);
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b0_l, b0_r);
    *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 9]);
  }
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b1_l, b1_r);
    *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 6]);
  }
  *right ^= *left ^ rot32l8(*left) ^ rot32r8(*left);
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b1_l, b1_r);
    *right ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i + 3]);
  }
  for (i = 2; i >= 0; i--) {
    speckey_inverse(b0_l, b0_r);
    *left ^= READ_ROUND_KEY_DOUBLE_WORD(roundKeys[i]);
  }
}
```