ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_in_str_list>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strdup@plt>
  mov    %rax,%r14
  movq   $0x0,(%rsp)
  mov    %rax,%rbx
  mov    %rsp,%r13
L6:
  movsbl %bpl,%esi
  mov    %r13,%rdx
  mov    %rbx,%rdi
  call   <split_and_get@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L6
L28:
  mov    %r14,%rdi
  call   <free@plt>
  test   %rbx,%rbx
  setne  %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_in_str_list(const char list[], char separator, const char needle[]) {
  char *list_copy = strdup(list);
  char *item = list_copy, *state = NULL;
  while ((item = split_and_get(item, separator, &state)) != NULL) {
    if (strcasecmp(item, needle) == 0) {
      break;
    }
  }
  free(list_copy);
  return (item != NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_in_str_list>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  movsbl %bl,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <strdup@plt>
  movq   $0x0,(%rsp)
  mov    %rax,%r14
  mov    %rax,%rbp
  jmp    L31
L42:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L33
L31:
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %ebx,%esi
  call   <split_and_get@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L42
  xor    %r12d,%r12d
L3:
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  mov    $0x1,%r12d
  jmp    L3
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_in_str_list(const char list[], char separator, const char needle[]) {
  char *list_copy = strdup(list);
  char *item = list_copy, *state = NULL;
  while ((item = split_and_get(item, separator, &state)) != NULL) {
    if (strcasecmp(item, needle) == 0) {
      break;
    }
  }
  free(list_copy);
  return (item != NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_in_str_list>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  movsbl %bl,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <strdup@plt>
  movq   $0x0,(%rsp)
  mov    %rax,%r14
  mov    %rax,%rbp
  jmp    L21
L14:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L15
L21:
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %ebx,%esi
  call   <split_and_get@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L14
  xor    %r12d,%r12d
L36:
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0x1,%r12d
  jmp    L36
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_in_str_list(const char list[], char separator, const char needle[]) {
  char *list_copy = strdup(list);
  char *item = list_copy, *state = NULL;
  while ((item = split_and_get(item, separator, &state)) != NULL) {
    if (strcasecmp(item, needle) == 0) {
      break;
    }
  }
  free(list_copy);
  return (item != NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compute_CRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffff,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L17:
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  shll   $0x8,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x10(%rbp)
  shll   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x10(%rbp)
  shll   $0x7,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t compute_CRC(unsigned char *message, int length) {
  uint16_t crc = 0x0ffff, temp, quick;
  int i;
  for (i = 0; i < length; i++) {
    temp = (crc >> 8) ^ message[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compute_CRC>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffff,%eax
L8:
  mov    %eax,%ecx
  sar    $0x8,%ecx
  movzbl (%r8),%edx
  xor    %edx,%ecx
  shl    $0x8,%eax
  mov    %ecx,%edx
  sar    $0x4,%edx
  xor    %ecx,%edx
  xor    %edx,%eax
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %ecx,%eax
  shl    $0xc,%edx
  xor    %edx,%eax
  add    $0x1,%r8
  cmp    %rsi,%r8
  jne    L8
  ret
L3:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
uint16_t compute_CRC(unsigned char *message, int length) {
  uint16_t crc = 0x0ffff, temp, quick;
  int i;
  for (i = 0; i < length; i++) {
    temp = (crc >> 8) ^ message[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compute_CRC>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffff,%eax
  nopl   (%rax)
L8:
  movzbl (%rdi),%edx
  mov    %eax,%ecx
  shl    $0x8,%eax
  add    $0x1,%rdi
  sar    $0x8,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x4,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  xor    %edx,%eax
  shl    $0xc,%edx
  shl    $0x5,%ecx
  xor    %ecx,%eax
  xor    %edx,%eax
  cmp    %rdi,%rsi
  jne    L8
  ret
  nopl   0x0(%rax)
L3:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
uint16_t compute_CRC(unsigned char *message, int length) {
  uint16_t crc = 0x0ffff, temp, quick;
  int i;
  for (i = 0; i < length; i++) {
    temp = (crc >> 8) ^ message[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compute_CRC>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffff,%eax
  nopl   (%rax)
L7:
  movzbl (%rdi),%edx
  mov    %eax,%ecx
  shl    $0x8,%eax
  add    $0x1,%rdi
  sar    $0x8,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x4,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  xor    %edx,%eax
  shl    $0xc,%edx
  shl    $0x5,%ecx
  xor    %ecx,%eax
  xor    %edx,%eax
  cmp    %rdi,%rsi
  jne    L7
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
uint16_t compute_CRC(unsigned char *message, int length) {
  uint16_t crc = 0x0ffff, temp, quick;
  int i;
  for (i = 0; i < length; i++) {
    temp = (crc >> 8) ^ message[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L27
L11:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L10
  movl   $0x1,-0x8(%rbp)
L10:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int prime(int n) {
  int l = 0, j;
  for (j = 2; j < n; j++) {
    if (n % j == 0)
      l = 1;
  }
  return l;
}
```
user: What is the c source code of the assembly code below?

```asm
<prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L1
  mov    $0x2,%ecx
  mov    $0x0,%esi
  mov    $0x1,%r8d
L2:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %r8d,%esi
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L2
L3:
  mov    %esi,%eax
  ret
L1:
  mov    $0x0,%esi
  jmp    L3
```

assistant: ```c
int prime(int n) {
  int l = 0, j;
  for (j = 2; j < n; j++) {
    if (n % j == 0)
      l = 1;
  }
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L0
  mov    $0x2,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%esi
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %esi,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L16
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int prime(int n) {
  int l = 0, j;
  for (j = 2; j < n; j++) {
    if (n % j == 0)
      l = 1;
  }
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prime>:
  endbr64
  cmp    $0x2,%edi
  jle    L7
  mov    $0x2,%ecx
  xor    %r8d,%r8d
  mov    $0x1,%esi
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %esi,%r8d
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L17
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int prime(int n) {
  int l = 0, j;
  for (j = 2; j < n; j++) {
    if (n % j == 0)
      l = 1;
  }
  return l;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_ftrace_files>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <read_copy_size4@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L14
  mov    $0xffffffff,%eax
  jmp    L13
L14:
  movl   $0x0,-0x10(%rbp)
  jmp    L26
L22:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <read_copy_size8@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <read_copy_data@plt>
  test   %rax,%rax
  jns    L17
  mov    $0xffffffff,%eax
  jmp    L13
L17:
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L22
  mov    $0x0,%eax
L13:
  leave
  ret
```

assistant: ```c
int copy_ftrace_files(struct tracecmd_input *handle, int fd) {
  unsigned long long size;
  int count;
  int i;
  count = read_copy_size4(handle, fd);
  if (count < 0)
    return -1;
  for (i = 0; i < count; i++) {
    size = read_copy_size8(handle, fd);
    if (size < 0)
      return -1;
    if (read_copy_data(handle, size, fd) < 0)
      return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy_ftrace_files>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  call   <read_copy_size4@plt>
  test   %eax,%eax
  js     L31
  mov    %eax,%r13d
  jle    L32
  mov    $0x0,%ebx
L9:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <read_copy_size8@plt>
  mov    %rax,%rsi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <read_copy_data@plt>
  test   %rax,%rax
  js     L21
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L9
  mov    $0x0,%eax
  jmp    L67
L31:
  mov    $0xffffffff,%eax
  jmp    L67
L32:
  mov    $0x0,%eax
  jmp    L67
L21:
  mov    $0xffffffff,%eax
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copy_ftrace_files(struct tracecmd_input *handle, int fd) {
  unsigned long long size;
  int count;
  int i;
  count = read_copy_size4(handle, fd);
  if (count < 0)
    return -1;
  for (i = 0; i < count; i++) {
    size = read_copy_size8(handle, fd);
    if (size < 0)
      return -1;
    if (read_copy_data(handle, size, fd) < 0)
      return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_ftrace_files>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <read_copy_size4@plt>
  test   %eax,%eax
  js     L1
  mov    %eax,%r13d
  mov    $0x0,%ebx
  jne    L21
  jmp    L25
  nopl   0x0(%rax)
L3:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  je     L25
L21:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <read_copy_size8@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <read_copy_data@plt>
  test   %rax,%rax
  jns    L3
L1:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copy_ftrace_files(struct tracecmd_input *handle, int fd) {
  unsigned long long size;
  int count;
  int i;
  count = read_copy_size4(handle, fd);
  if (count < 0)
    return -1;
  for (i = 0; i < count; i++) {
    size = read_copy_size8(handle, fd);
    if (size < 0)
      return -1;
    if (read_copy_data(handle, size, fd) < 0)
      return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<copy_ftrace_files>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <read_copy_size4@plt>
  test   %eax,%eax
  js     L34
  mov    %eax,%r13d
  mov    $0x0,%ebx
  jne    L32
  jmp    L31
  nopl   0x0(%rax)
L14:
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  je     L31
L32:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <read_copy_size8@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <read_copy_data@plt>
  test   %rax,%rax
  jns    L14
L34:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int copy_ftrace_files(struct tracecmd_input *handle, int fd) {
  unsigned long long size;
  int count;
  int i;
  count = read_copy_size4(handle, fd);
  if (count < 0)
    return -1;
  for (i = 0; i < count; i++) {
    size = read_copy_size8(handle, fd);
    if (size < 0)
      return -1;
    if (read_copy_data(handle, size, fd) < 0)
      return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  lea    D57(%rip),%r14
  lea    D9(%rip),%r13
L0:
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb2,%ebx
  movsd  D46(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  lea    0x10(%rsp),%r12
L29:
  lea    0x30(%rsp),%rsi
  movsd  D7(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    %r12,%rdx
  mov    %ebp,%edi
  call   <GetMarsSatCoor@plt>
  movsd  0x20(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  movsd  0x40(%rsp),%xmm3
  movsd  0x38(%rsp),%xmm2
  movsd  0x30(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %r13,%rdi
  mov    $0x7,%eax
  call   <printf@plt>
  movsd  D22(%rip),%xmm1
  addsd  0x8(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L29
  lea    D66(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  jne    L0
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D42
datatype: string
name: parse_data
arguments: data_tag: D57
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D46
datatype: byte[8]
name: parse_data
arguments: data_tag: D7
datatype: f64
name: parse_data
arguments: data_tag: D22
datatype: f64
name: parse_data
arguments: data_tag: D66
datatype: string
name: parse_data
arguments: data_tag: D29
datatype: string

tool: D42: {

tool: D57: 	"%d": [


tool: D9: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D46": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D7: 2451545

tool: D22: 225

tool: D66: 	],

tool: D29: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double xyzdot[3];
  double xyz[3];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float jd = jd2k + 2451545.0;
      GetMarsSatCoor(jd, body, xyz, xyzdot);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, xyz[0], xyz[1], xyz[2], xyzdot[0], xyzdot[1], xyzdot[2]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D52(%rip),%rdi
  lea    D78(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D77(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x30(%rsp),%r13
  call   <puts@plt>
L1:
  mov    %ebp,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0xb2,%ebx
  call   <printf@plt>
  mov    D33(%rip),%rax
  movq   %rax,%xmm7
  nopl   (%rax)
L4:
  movsd  D51(%rip),%xmm0
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  movsd  %xmm7,0x8(%rsp)
  addsd  %xmm7,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <GetMarsSatCoor@plt>
  movsd  0x8(%rsp),%xmm7
  movsd  0x20(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  mov    %r12,%rdi
  mov    $0x7,%eax
  movsd  0x40(%rsp),%xmm3
  movsd  0x38(%rsp),%xmm2
  movapd %xmm7,%xmm0
  movsd  0x30(%rsp),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm7
  addsd  D10(%rip),%xmm7
  sub    $0x1,%ebx
  jne    L4
  lea    D3(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  jne    L19
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  mov    $0x1,%ebp
  jmp    L1
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D52
type_guessed: string
name: extract_symbolic_data
arguments: label: D78
type_guessed: string
name: extract_symbolic_data
arguments: label: D77
type_guessed: string
name: extract_symbolic_data
arguments: label: D33
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D51
type_guessed: f64
name: extract_symbolic_data
arguments: label: D10
type_guessed: f64
name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D52: {

tool: D78: 	"%d": [


tool: D77: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D33": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D51: 2451545

tool: D10: 225

tool: D3: 	],

tool: D19: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double xyzdot[3];
  double xyz[3];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float jd = jd2k + 2451545.0;
      GetMarsSatCoor(jd, body, xyz, xyzdot);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, xyz[0], xyz[1], xyz[2], xyzdot[0], xyzdot[1], xyzdot[2]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D66(%rip),%rdi
  lea    D13(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D68(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  lea    0x30(%rsp),%r13
  call   <puts@plt>
L2:
  mov    %ebp,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0xb2,%ebx
  call   <printf@plt>
  mov    D15(%rip),%rax
  movq   %rax,%xmm7
  nopl   (%rax)
L11:
  movsd  D72(%rip),%xmm0
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  movsd  %xmm7,0x8(%rsp)
  addsd  %xmm7,%xmm0
  cvtsd2ss %xmm0,%xmm0
  call   <GetMarsSatCoor@plt>
  movsd  0x8(%rsp),%xmm7
  movsd  0x20(%rsp),%xmm6
  movsd  0x18(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  mov    %r12,%rdi
  mov    $0x7,%eax
  movsd  0x40(%rsp),%xmm3
  movsd  0x38(%rsp),%xmm2
  movapd %xmm7,%xmm0
  movsd  0x30(%rsp),%xmm1
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm7
  addsd  D55(%rip),%xmm7
  sub    $0x1,%ebx
  jne    L11
  lea    D44(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%ebp
  jne    L15
  lea    D61(%rip),%rdi
  call   <puts@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    $0x1,%ebp
  jmp    L2
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D66
type: string
name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D68
type: string
name: unpack_data
arguments: tag: D15
type: byte[8]
name: unpack_data
arguments: tag: D72
type: f64
name: unpack_data
arguments: tag: D55
type: f64
name: unpack_data
arguments: tag: D44
type: string
name: unpack_data
arguments: tag: D61
type: string

tool: D66: {

tool: D13: 	"%d": [


tool: D68: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D72: 2451545

tool: D55: 225

tool: D44: 	],

tool: D61: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double xyzdot[3];
  double xyz[3];
  printf("{\n");
  for (body = 0; body < 2; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float jd = jd2k + 2451545.0;
      GetMarsSatCoor(jd, body, xyz, xyzdot);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, xyz[0], xyz[1], xyz[2], xyzdot[0], xyzdot[1], xyzdot[2]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```