ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<peripheralClockFrequency>:
  endbr64
  push   %rbx
  movabs 0xe01fc100,%al
  and    $0x3,%eax
  mov    $0x1,%ebx
  cmp    $0x1,%al
  je     L16
  mov    $0x2,%ebx
  cmp    $0x2,%al
  je     L16
  test   %al,%al
  sete   %bl
  movzbl %bl,%ebx
  shl    $0x2,%ebx
L16:
  mov    $0x0,%eax
  call   <processorClockFrequency@plt>
  mov    $0x0,%edx
  div    %ebx
  pop    %rbx
  ret
```

assistant: ```c
unsigned int peripheralClockFrequency(void) {
  unsigned int divider = 0;
  switch ((*((volatile unsigned char *)0xE01FC100)) & 3) {
  case 0:
    divider = 4;
    break;
  case 1:
    divider = 1;
    break;
  case 2:
    divider = 2;
    break;
  }
  return processorClockFrequency() / divider;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<peripheralClockFrequency>:
  endbr64
  push   %rbx
  movabs 0xe01fc100,%al
  and    $0x3,%eax
  cmp    $0x3,%al
  je     1060 <peripheralClockFrequency.cold>
  lea    D8(%rip),%rdx
  movzbl %al,%eax
  mov    (%rdx,%rax,4),%ebx
  xor    %eax,%eax
  call   <processorClockFrequency@plt>
  xor    %edx,%edx
  div    %ebx
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: 

assistant: ```c
unsigned int peripheralClockFrequency(void) {
  unsigned int divider = 0;
  switch ((*((volatile unsigned char *)0xE01FC100)) & 3) {
  case 0:
    divider = 4;
    break;
  case 1:
    divider = 1;
    break;
  case 2:
    divider = 2;
    break;
  }
  return processorClockFrequency() / divider;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<peripheralClockFrequency>:
  endbr64
  push   %rbx
  movabs 0xe01fc100,%al
  and    $0x3,%eax
  cmp    $0x3,%al
  je     1060 <peripheralClockFrequency.cold>
  lea    D6(%rip),%rdx
  movzbl %al,%eax
  mov    (%rdx,%rax,4),%ebx
  xor    %eax,%eax
  call   <processorClockFrequency@plt>
  xor    %edx,%edx
  div    %ebx
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: 

assistant: ```c
unsigned int peripheralClockFrequency(void) {
  unsigned int divider = 0;
  switch ((*((volatile unsigned char *)0xE01FC100)) & 3) {
  case 0:
    divider = 4;
    break;
  case 1:
    divider = 1;
    break;
  case 2:
    divider = 2;
    break;
  }
  return processorClockFrequency() / divider;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<msx_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <msx_readval@plt>
  test   %rax,%rax
  je     L29
  mov    -0xc(%rbp),%eax
  jmp    L4
L29:
  mov    $0xffffffff,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int msx_read(char *fn) {
  int val;
  return (msx_readval(fn, &val) ? val : -1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msx_read>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <msx_readval@plt>
  test   %rax,%rax
  je     L1
  mov    0x4(%rsp),%eax
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L20
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int msx_read(char *fn) {
  int val;
  return (msx_readval(fn, &val) ? val : -1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<msx_read>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <msx_readval@plt>
  test   %rax,%rax
  je     L12
  mov    0x4(%rsp),%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x18,%rsp
  ret
L12:
  mov    $0xffffffff,%eax
  jmp    L1
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int msx_read(char *fn) {
  int val;
  return (msx_readval(fn, &val) ? val : -1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msx_read>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <msx_readval@plt>
  test   %rax,%rax
  je     L29
  mov    0x4(%rsp),%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L29:
  mov    $0xffffffff,%eax
  jmp    L11
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int msx_read(char *fn) {
  int val;
  return (msx_readval(fn, &val) ? val : -1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L8
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *src, char *dst) {
  while (src < dst) {
    char tmp;
    tmp = *src;
    *src = *dst;
    *dst = tmp;
    src++;
    dst--;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  cmp    %rsi,%rdi
  jae    L0
L5:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  mov    %dl,(%rdi)
  mov    %al,(%rsi)
  add    $0x1,%rdi
  sub    $0x1,%rsi
  cmp    %rsi,%rdi
  jb     L5
L0:
  ret
```

assistant: ```c
void reverse(char *src, char *dst) {
  while (src < dst) {
    char tmp;
    tmp = *src;
    *src = *dst;
    *dst = tmp;
    src++;
    dst--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reverse>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L0:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  add    $0x1,%rdi
  sub    $0x1,%rsi
  mov    %dl,-0x1(%rdi)
  mov    %al,0x1(%rsi)
L7:
  cmp    %rsi,%rdi
  jb     L0
  ret
```

assistant: ```c
void reverse(char *src, char *dst) {
  while (src < dst) {
    char tmp;
    tmp = *src;
    *src = *dst;
    *dst = tmp;
    src++;
    dst--;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  add    $0x1,%rdi
  sub    $0x1,%rsi
  mov    %dl,-0x1(%rdi)
  mov    %al,0x1(%rsi)
L17:
  cmp    %rsi,%rdi
  jb     L4
  ret
```

assistant: ```c
void reverse(char *src, char *dst) {
  while (src < dst) {
    char tmp;
    tmp = *src;
    *src = *dst;
    *dst = tmp;
    src++;
    dst--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L10
  movsd  -0x8(%rbp),%xmm0
  jmp    L4
L10:
  movsd  -0x8(%rbp),%xmm0
  movq   D0(%rip),%xmm1
  xorpd  %xmm1,%xmm0
L4:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double Abs(double Nbr) {
  if (Nbr >= 0)
    return Nbr;
  else
    return -Nbr;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<android_atomic_acquire_store>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <android_memory_barrier@plt>
  nop
  leave
  ret
```

assistant: ```c
extern void android_atomic_acquire_store(int32_t value, volatile int32_t *ptr) {
  *ptr = value;
  android_memory_barrier();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<android_atomic_acquire_store>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,(%rsi)
  mov    $0x0,%eax
  call   <android_memory_barrier@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern void android_atomic_acquire_store(int32_t value, volatile int32_t *ptr) {
  *ptr = value;
  android_memory_barrier();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<android_atomic_acquire_store>:
  endbr64
  mov    %edi,(%rsi)
  xor    %eax,%eax
  jmp    1050 <android_memory_barrier@plt>
```

assistant: ```c
extern void android_atomic_acquire_store(int32_t value, volatile int32_t *ptr) {
  *ptr = value;
  android_memory_barrier();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MakeLinearString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L15
L47:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L47
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L7:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L7
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L28
L11:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L11
  movl   $0x0,-0x1c(%rbp)
  jmp    L33
L71:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x1c(%rbp)
L33:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L71
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *MakeLinearString(const int nHeader, const char *const header[], const int nLine, const char *const line[]) {
  int l;
  size_t ptr = 0, totalSize = 0;
  char *buf;
  for (l = 0; l < nHeader; ++l) {
    totalSize += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    totalSize += strlen(line[l]);
  }
  buf = (char *)malloc(totalSize + 1);
  for (l = 0; l < nHeader; ++l) {
    strcpy(buf + ptr, header[l]);
    ptr += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    strcpy(buf + ptr, line[l]);
    ptr += strlen(line[l]);
  }
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<MakeLinearString>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %rcx,0x8(%rsp)
  test   %edi,%edi
  jle    L8
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r15
  mov    $0x0,%ebx
L24:
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  add    $0x8,%rbp
  cmp    %r15,%rbp
  jne    L24
L102:
  test   %r13d,%r13d
  jle    L79
  mov    0x8(%rsp),%rdx
  mov    %rdx,%rbp
  lea    -0x1(%r13),%eax
  lea    0x8(%rdx,%rax,8),%r15
L108:
  mov    0x0(%rbp),%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  add    $0x8,%rbp
  cmp    %r15,%rbp
  jne    L108
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L40
L89:
  mov    %r14,%rbx
  lea    -0x1(%r12),%eax
  lea    0x8(%r14,%rax,8),%r14
  mov    $0x0,%r12d
L63:
  lea    0x0(%rbp,%r12,1),%rdi
  mov    (%rbx),%rsi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  call   <strlen@plt>
  add    %rax,%r12
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L63
  test   %r13d,%r13d
  jle    L98
L110:
  mov    0x8(%rsp),%rcx
  mov    %rcx,%rbx
  lea    -0x1(%r13),%eax
  lea    0x8(%rcx,%rax,8),%r13
L77:
  lea    0x0(%rbp,%r12,1),%rdi
  mov    (%rbx),%rsi
  call   <strcpy@plt>
  mov    (%rbx),%rdi
  call   <strlen@plt>
  add    %rax,%r12
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L77
L98:
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    $0x0,%ebx
  jmp    L102
L79:
  lea    0x1(%rbx),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jg     L89
  jmp    L98
L40:
  mov    $0x0,%r12d
  jmp    L110
```

assistant: ```c
char *MakeLinearString(const int nHeader, const char *const header[], const int nLine, const char *const line[]) {
  int l;
  size_t ptr = 0, totalSize = 0;
  char *buf;
  for (l = 0; l < nHeader; ++l) {
    totalSize += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    totalSize += strlen(line[l]);
  }
  buf = (char *)malloc(totalSize + 1);
  for (l = 0; l < nHeader; ++l) {
    strcpy(buf + ptr, header[l]);
    ptr += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    strcpy(buf + ptr, line[l]);
    ptr += strlen(line[l]);
  }
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MakeLinearString>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  test   %edi,%edi
  jle    L37
  lea    -0x1(%rdi),%eax
  mov    %rsi,%r15
  xor    %ebp,%ebp
  lea    0x8(%rsi,%rax,8),%r12
  nopl   (%rax)
L90:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r12,%r15
  jne    L90
  test   %r14d,%r14d
  jle    L50
L91:
  lea    -0x1(%r14),%eax
  lea    0x8(%rbx),%rdx
  mov    %rbx,%r15
  mov    %eax,0xc(%rsp)
  lea    (%rdx,%rax,8),%r12
  mov    %rdx,0x10(%rsp)
  nopl   (%rax)
L26:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r12,%r15
  jne    L26
  lea    0x1(%rbp),%rdi
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L103
L21:
  mov    0x18(%rsp),%r15
  lea    -0x1(%r13),%eax
  xor    %ebp,%ebp
  lea    0x8(%r15,%rax,8),%r13
  nopw   0x0(%rax,%rax,1)
L76:
  mov    (%r15),%rsi
  lea    (%r12,%rbp,1),%rdi
  add    $0x8,%r15
  call   <strcpy@plt>
  mov    -0x8(%r15),%rdi
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r15,%r13
  jne    L76
  test   %r14d,%r14d
  jle    L72
  lea    -0x1(%r14),%eax
  mov    %eax,0xc(%rsp)
  lea    0x8(%rbx),%rax
  mov    %rax,0x10(%rsp)
L103:
  mov    0xc(%rsp),%eax
  mov    0x10(%rsp),%rcx
  lea    (%rcx,%rax,8),%r13
  nopl   0x0(%rax)
L88:
  mov    (%rbx),%rsi
  lea    (%r12,%rbp,1),%rdi
  add    $0x8,%rbx
  call   <strcpy@plt>
  mov    -0x8(%rbx),%rdi
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %rbx,%r13
  jne    L88
L72:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %ebp,%ebp
  test   %r14d,%r14d
  jg     L91
  nopl   0x0(%rax,%rax,1)
L50:
  lea    0x1(%rbp),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jg     L21
  jmp    L72
```

assistant: ```c
char *MakeLinearString(const int nHeader, const char *const header[], const int nLine, const char *const line[]) {
  int l;
  size_t ptr = 0, totalSize = 0;
  char *buf;
  for (l = 0; l < nHeader; ++l) {
    totalSize += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    totalSize += strlen(line[l]);
  }
  buf = (char *)malloc(totalSize + 1);
  for (l = 0; l < nHeader; ++l) {
    strcpy(buf + ptr, header[l]);
    ptr += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    strcpy(buf + ptr, line[l]);
    ptr += strlen(line[l]);
  }
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<MakeLinearString>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  test   %edi,%edi
  jle    L103
  lea    -0x1(%rdi),%eax
  mov    %rsi,%r15
  xor    %ebp,%ebp
  lea    0x8(%rsi,%rax,8),%r12
  nopl   (%rax)
L32:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r12,%r15
  jne    L32
  test   %r14d,%r14d
  jle    L51
L85:
  lea    -0x1(%r14),%eax
  lea    0x8(%rbx),%rdx
  mov    %rbx,%r15
  mov    %eax,0xc(%rsp)
  lea    (%rdx,%rax,8),%r12
  mov    %rdx,0x10(%rsp)
  nopl   (%rax)
L109:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r15,%r12
  jne    L109
  lea    0x1(%rbp),%rdi
  xor    %ebp,%ebp
  call   <malloc@plt>
  mov    0x10(%rsp),%rcx
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L104
L59:
  mov    0x18(%rsp),%r15
  lea    -0x1(%r13),%eax
  xor    %ebp,%ebp
  lea    0x8(%r15,%rax,8),%r13
  nopl   0x0(%rax)
L67:
  mov    (%r15),%rsi
  lea    (%r12,%rbp,1),%rdi
  add    $0x8,%r15
  call   <strcpy@plt>
  mov    -0x8(%r15),%rdi
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r15,%r13
  jne    L67
  test   %r14d,%r14d
  jle    L57
  lea    -0x1(%r14),%eax
  mov    %eax,0xc(%rsp)
  lea    0x8(%rbx),%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,%rcx
L104:
  mov    0xc(%rsp),%eax
  lea    (%rcx,%rax,8),%r13
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rbx),%rsi
  lea    (%r12,%rbp,1),%rdi
  add    $0x8,%rbx
  call   <strcpy@plt>
  mov    -0x8(%rbx),%rdi
  call   <strlen@plt>
  add    %rax,%rbp
  cmp    %r13,%rbx
  jne    L29
L57:
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L103:
  xor    %ebp,%ebp
  test   %r14d,%r14d
  jg     L85
  nopl   0x0(%rax,%rax,1)
L51:
  lea    0x1(%rbp),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jg     L59
  jmp    L57
```

assistant: ```c
char *MakeLinearString(const int nHeader, const char *const header[], const int nLine, const char *const line[]) {
  int l;
  size_t ptr = 0, totalSize = 0;
  char *buf;
  for (l = 0; l < nHeader; ++l) {
    totalSize += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    totalSize += strlen(line[l]);
  }
  buf = (char *)malloc(totalSize + 1);
  for (l = 0; l < nHeader; ++l) {
    strcpy(buf + ptr, header[l]);
    ptr += strlen(header[l]);
  }
  for (l = 0; l < nLine; ++l) {
    strcpy(buf + ptr, line[l]);
    ptr += strlen(line[l]);
  }
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    $0x14,%edi
  call   <memory_hog@plt>
  mov    $0x6,%edi
  call   <cpu_hog@plt>
  jmp    L9
```

assistant: ```c
int main() {
  while (1) {
    memory_hog(20, 1, 4, 1);
    cpu_hog(6);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    $0x14,%edi
  call   <memory_hog@plt>
  mov    $0x6,%edi
  call   <cpu_hog@plt>
  jmp    L8
```

assistant: ```c
int main() {
  while (1) {
    memory_hog(20, 1, 4, 1);
    cpu_hog(6);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    $0x14,%edi
  call   <memory_hog@plt>
  mov    $0x6,%edi
  call   <cpu_hog@plt>
  jmp    L1
```

assistant: ```c
int main() {
  while (1) {
    memory_hog(20, 1, 4, 1);
    cpu_hog(6);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    $0x14,%edi
  call   <memory_hog@plt>
  mov    $0x6,%edi
  call   <cpu_hog@plt>
  jmp    L5
```

assistant: ```c
int main() {
  while (1) {
    memory_hog(20, 1, 4, 1);
    cpu_hog(6);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <__builtin_alloca_with_align@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <useit@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo2(long unsigned int len) {
  void *p = __builtin_alloca_with_align(len, 8);
  useit(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  call   <__builtin_alloca_with_align@plt>
  mov    %rax,%rdi
  call   <useit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo2(long unsigned int len) {
  void *p = __builtin_alloca_with_align(len, 8);
  useit(p);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  call   <__builtin_alloca_with_align@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <useit@plt>
```

assistant: ```c
void foo2(long unsigned int len) {
  void *p = __builtin_alloca_with_align(len, 8);
  useit(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  call   <__builtin_alloca_with_align@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <useit@plt>
```

assistant: ```c
void foo2(long unsigned int len) {
  void *p = __builtin_alloca_with_align(len, 8);
  useit(p);
}
```