ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_writev>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %edx,%edx
  jle    L17
  mov    %rsi,%rbx
  mov    %edx,%r15d
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  mov    $0x0,%r13d
L76:
  add    (%rax),%r13d
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L76
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L75
L18:
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L19:
  mov    0x8(%rbx),%esi
  lea    (%r14,%r12,1),%rdi
  mov    (%rbx),%rdx
  call   <memcpy@plt>
  add    (%rbx),%r12
  add    $0x1,%ebp
  add    $0x10,%rbx
  cmp    %ebp,%r15d
  jg     L19
L29:
  mov    %r13d,%edx
  mov    %r14,%rsi
  mov    0xc(%rsp),%edi
  call   <write@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L37
L79:
  mov    %r14,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  lea    D20(%rip),%rdi
  call   <exitErr@plt>
  jmp    L79
L17:
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x0,%r13d
  test   %rax,%rax
  jne    L29
  lea    D9(%rip),%rdi
  call   <exitErr@plt>
  jmp    L29
L75:
  lea    D9(%rip),%rdi
  call   <exitErr@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: label: D20
data_type: string
name: read_data
arguments: label: D9
data_type: string

tool: D20: write

tool: D9: malloc

assistant: ```c
ssize_t _writev(int fd, const struct iovec *iov, int iovcnt) {
  int i;
  size_t bytesCopied = 0;
  ssize_t bytesWritten, bytesRequired = 0;
  void *buf;
  for (i = 0; i < iovcnt; ++i) {
    bytesRequired += iov[i].iov_len;
  }
  buf = malloc(bytesRequired);
  if (buf == NULL)
    exitErr("malloc");
  for (i = 0; i < iovcnt; ++i) {
    memcpy(buf + bytesCopied, iov[i].iov_base, iov[i].iov_len);
    bytesCopied += iov[i].iov_len;
  }
  bytesWritten = write(fd, buf, bytesRequired);
  if (bytesWritten == -1)
    exitErr("write");
  free(buf);
  return bytesWritten;
}
```
user: What is the c source code of the assembly code below:

```asm
<_writev>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %edx,%edx
  jle    L65
  mov    %edx,%r13d
  lea    -0x1(%rdx),%edx
  mov    %rsi,%rbx
  mov    %rsi,%rax
  shl    $0x4,%rdx
  xor    %r12d,%r12d
  lea    0x10(%rsi,%rdx,1),%rdx
  cs nopw 0x0(%rax,%rax,1)
L30:
  add    (%rax),%r12d
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L30
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L32
L17:
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L36:
  mov    0x8(%rbx),%esi
  mov    (%rbx),%rdx
  lea    (%r14,%r15,1),%rdi
  add    $0x1,%ebp
  add    $0x10,%rbx
  call   <memcpy@plt>
  add    -0x10(%rbx),%r15
  cmp    %ebp,%r13d
  jg     L36
L39:
  mov    0xc(%rsp),%edi
  mov    %r12d,%edx
  mov    %r14,%rsi
  call   <write@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L33
L86:
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  lea    D2(%rip),%rdi
  call   <exitErr@plt>
  jmp    L86
  xchg   %ax,%ax
L32:
  lea    D18(%rip),%rdi
  call   <exitErr@plt>
  jmp    L17
  nopl   0x0(%rax)
L65:
  xor    %edi,%edi
  xor    %r12d,%r12d
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L39
  lea    D18(%rip),%rdi
  call   <exitErr@plt>
  jmp    L39
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D18
type_guessed: string

tool: D2: write

tool: D18: malloc

assistant: ```c
ssize_t _writev(int fd, const struct iovec *iov, int iovcnt) {
  int i;
  size_t bytesCopied = 0;
  ssize_t bytesWritten, bytesRequired = 0;
  void *buf;
  for (i = 0; i < iovcnt; ++i) {
    bytesRequired += iov[i].iov_len;
  }
  buf = malloc(bytesRequired);
  if (buf == NULL)
    exitErr("malloc");
  for (i = 0; i < iovcnt; ++i) {
    memcpy(buf + bytesCopied, iov[i].iov_base, iov[i].iov_len);
    bytesCopied += iov[i].iov_len;
  }
  bytesWritten = write(fd, buf, bytesRequired);
  if (bytesWritten == -1)
    exitErr("write");
  free(buf);
  return bytesWritten;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_writev>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  test   %edx,%edx
  jle    L31
  mov    %edx,%ebp
  lea    -0x1(%rdx),%edx
  mov    %rsi,%rbx
  cmp    $0x3,%edx
  jbe    L66
  mov    %edx,%ecx
  mov    %rsi,%rax
  pxor   %xmm2,%xmm2
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x6,%rcx
  lea    0x40(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L134:
  movdqu (%rax),%xmm0
  movdqu 0x10(%rax),%xmm3
  add    $0x40,%rax
  movdqu -0x20(%rax),%xmm1
  movdqu -0x10(%rax),%xmm4
  punpcklqdq %xmm3,%xmm0
  punpcklqdq %xmm4,%xmm1
  shufps $0x88,%xmm1,%xmm0
  paddd  %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L134
  movdqa %xmm2,%xmm0
  mov    %edx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%r12d
L132:
  movslq %eax,%rdx
  lea    0x1(%rax),%ecx
  shl    $0x4,%rdx
  add    (%rbx,%rdx,1),%r12d
  cmp    %ebp,%ecx
  jge    L128
  lea    0x2(%rax),%ecx
  add    0x10(%rbx,%rdx,1),%r12d
  cmp    %ecx,%ebp
  jle    L128
  add    $0x3,%eax
  add    0x20(%rbx,%rdx,1),%r12d
  cmp    %eax,%ebp
  jle    L128
  add    0x30(%rbx,%rdx,1),%r12d
L128:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L18
L125:
  xor    %r13d,%r13d
  xor    %r15d,%r15d
  nopl   (%rax)
L121:
  mov    0x8(%rbx),%esi
  mov    (%rbx),%rdx
  lea    (%r14,%r13,1),%rdi
  add    $0x1,%r15d
  add    $0x10,%rbx
  call   <memcpy@plt>
  add    -0x10(%rbx),%r13
  cmp    %r15d,%ebp
  jg     L121
L8:
  mov    0xc(%rsp),%edi
  mov    %r12d,%edx
  mov    %r14,%rsi
  call   <write@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L112
L16:
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L112:
  lea    D13(%rip),%rdi
  call   <exitErr@plt>
  jmp    L16
  xchg   %ax,%ax
L18:
  lea    D3(%rip),%rdi
  call   <exitErr@plt>
  jmp    L125
  xchg   %ax,%ax
L31:
  xor    %edi,%edi
  xor    %r12d,%r12d
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L8
  lea    D3(%rip),%rdi
  call   <exitErr@plt>
  jmp    L8
L66:
  xor    %r12d,%r12d
  xor    %eax,%eax
  jmp    L132
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D13: write

tool: D3: malloc

assistant: ```c
ssize_t _writev(int fd, const struct iovec *iov, int iovcnt) {
  int i;
  size_t bytesCopied = 0;
  ssize_t bytesWritten, bytesRequired = 0;
  void *buf;
  for (i = 0; i < iovcnt; ++i) {
    bytesRequired += iov[i].iov_len;
  }
  buf = malloc(bytesRequired);
  if (buf == NULL)
    exitErr("malloc");
  for (i = 0; i < iovcnt; ++i) {
    memcpy(buf + bytesCopied, iov[i].iov_base, iov[i].iov_len);
    bytesCopied += iov[i].iov_len;
  }
  bytesWritten = write(fd, buf, bytesRequired);
  if (bytesWritten == -1)
    exitErr("write");
  free(buf);
  return bytesWritten;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<u1_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x840,%rsp
  mov    %rdi,-0x838(%rbp)
  mov    %rsi,-0x840(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x838(%rbp),%rax
  mov    %rax,-0x818(%rbp)
  cmpq   $0x1f,-0x840(%rbp)
  jg     L25
  mov    -0x840(%rbp),%rdx
  mov    -0x838(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <u1_ins_sort@plt>
  jmp    L71
L25:
  lea    -0x810(%rbp),%rax
  mov    $0x800,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movq   $0x0,-0x820(%rbp)
  jmp    L2
L9:
  mov    -0x820(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x838(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x810(%rbp,%rdx,8),%rdx
  add    $0x1,%rdx
  cltq
  mov    %rdx,-0x810(%rbp,%rax,8)
  addq   $0x1,-0x820(%rbp)
L2:
  mov    -0x820(%rbp),%rax
  cmp    -0x840(%rbp),%rax
  jl     L9
  movq   $0x0,-0x828(%rbp)
  jmp    L22
L65:
  mov    -0x828(%rbp),%rax
  mov    %eax,%edx
  mov    -0x818(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x4,-0x818(%rbp)
L35:
  mov    -0x828(%rbp),%rax
  mov    -0x810(%rbp,%rax,8),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x828(%rbp),%rdx
  mov    %rcx,-0x810(%rbp,%rdx,8)
  test   %rax,%rax
  jg     L65
  addq   $0x1,-0x828(%rbp)
L22:
  cmpq   $0xff,-0x828(%rbp)
  jle    L35
L71:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void u1_sort(int *a, const long sz) {
  long j;
  long n;
  int *writer = a;
  long b0[256];
  if (sz < 32) {
    return u1_ins_sort(a, sz);
  }
  memset(b0, 0, 256 * sizeof(long));
  for (n = 0; n < sz; n++) {
    b0[a[n]]++;
  }
  for (j = 0; j < 256; j++) {
    while (b0[j]-- > 0) {
      *writer = j;
      writer++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<u1_sort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  cmp    $0x1f,%rsi
  jle    L72
  mov    %rsp,%rdi
  mov    $0x800,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbx,%rax
  lea    (%rbx,%rbp,4),%rcx
L42:
  movslq (%rax),%rdx
  addq   $0x1,(%rsp,%rdx,8)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L42
  mov    %rsp,%rdi
  mov    $0x0,%esi
  jmp    L45
L72:
  call   <u1_ins_sort@plt>
L74:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    %esi,(%rbx)
  add    $0x4,%rbx
  mov    %rax,%rdx
  sub    $0x1,%rax
  lea    0x1(%rdx),%rcx
  test   %rcx,%rcx
  jg     L27
  mov    %rdx,(%r8)
L1:
  add    $0x1,%rsi
  add    $0x8,%rdi
  cmp    $0x100,%rsi
  je     L74
L45:
  mov    %rdi,%r8
  mov    (%rdi),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,(%rdi)
  lea    -0x2(%rdx),%rax
  test   %rdx,%rdx
  jg     L27
  jmp    L1
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void u1_sort(int *a, const long sz) {
  long j;
  long n;
  int *writer = a;
  long b0[256];
  if (sz < 32) {
    return u1_ins_sort(a, sz);
  }
  memset(b0, 0, 256 * sizeof(long));
  for (n = 0; n < sz; n++) {
    b0[a[n]]++;
  }
  for (j = 0; j < 256; j++) {
    while (b0[j]-- > 0) {
      *writer = j;
      writer++;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<u1_sort>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  cmp    $0x1f,%rsi
  jle    L41
  mov    %rsp,%rbx
  mov    $0x800,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbp,%rax
  lea    0x0(%rbp,%r12,4),%rcx
L36:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addq   $0x1,(%rsp,%rdx,8)
  cmp    %rcx,%rax
  jne    L36
  mov    %rbx,%rsi
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rsi),%rdx
  mov    %edi,%ecx
  lea    -0x1(%rdx),%rax
  mov    %rax,(%rsi)
  xor    %eax,%eax
  test   %rdx,%rdx
  jle    L21
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L42
  movq   $0xffffffffffffffff,(%rsi)
  lea    0x0(%rbp,%rax,4),%rbp
L21:
  add    $0x1,%rdi
  add    $0x8,%rsi
  cmp    $0x100,%rdi
  jne    L7
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <u1_ins_sort@plt>
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void u1_sort(int *a, const long sz) {
  long j;
  long n;
  int *writer = a;
  long b0[256];
  if (sz < 32) {
    return u1_ins_sort(a, sz);
  }
  memset(b0, 0, 256 * sizeof(long));
  for (n = 0; n < sz; n++) {
    b0[a[n]]++;
  }
  for (j = 0; j < 256; j++) {
    while (b0[j]-- > 0) {
      *writer = j;
      writer++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<u1_sort>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  cmp    $0x1f,%rsi
  jle    L70
  mov    %rsp,%rbx
  mov    $0x800,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbp,%rax
  lea    0x0(%rbp,%r12,4),%rcx
L47:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addq   $0x1,(%rsp,%rdx,8)
  cmp    %rcx,%rax
  jne    L47
  mov    %rbx,%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L35:
  mov    (%r8),%rcx
  lea    -0x1(%rcx),%rsi
  mov    %rsi,(%r8)
  test   %rcx,%rcx
  jle    L43
  mov    %r9d,%r10d
  cmp    $0x2,%rsi
  jbe    L34
  mov    %rcx,%rdi
  movd   %r9d,%xmm1
  xor    %eax,%eax
  shr    $0x2,%rdi
  pshufd $0x0,%xmm1,%xmm0
  nopw   0x0(%rax,%rax,1)
L103:
  mov    %rax,%rdx
  add    $0x1,%rax
  shl    $0x4,%rdx
  movups %xmm0,0x0(%rbp,%rdx,1)
  cmp    %rax,%rdi
  jne    L103
  mov    %rcx,%rax
  and    $0xfffffffffffffffc,%rax
  lea    0x0(%rbp,%rax,4),%rdx
  sub    %rax,%rsi
  cmp    %rcx,%rax
  je     L93
L15:
  mov    %r10d,(%rdx)
  test   %rsi,%rsi
  jle    L93
  mov    %r10d,0x4(%rdx)
  cmp    $0x1,%rsi
  jle    L93
  mov    %r10d,0x8(%rdx)
L93:
  movq   $0xffffffffffffffff,(%r8)
  lea    0x0(%rbp,%rcx,4),%rbp
L43:
  add    $0x1,%r9
  add    $0x8,%r8
  cmp    $0x100,%r9
  jne    L35
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    %rbp,%rdx
  jmp    L15
L70:
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  add    $0x810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1090 <u1_ins_sort@plt>
L105:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void u1_sort(int *a, const long sz) {
  long j;
  long n;
  int *writer = a;
  long b0[256];
  if (sz < 32) {
    return u1_ins_sort(a, sz);
  }
  memset(b0, 0, 256 * sizeof(long));
  for (n = 0; n < sz; n++) {
    b0[a[n]]++;
  }
  for (j = 0; j < 256; j++) {
    while (b0[j]-- > 0) {
      *writer = j;
      writer++;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  movsd  %xmm1,-0x18(%rbp)
  movsd  %xmm2,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  cmpl   $0x5,-0x24(%rbp)
  je     L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void foo(char *name, double d, double e, double f, int g) {
  if (g != 5)
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  cmp    $0x5,%esi
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo(char *name, double d, double e, double f, int g) {
  if (g != 5)
    abort();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  cmp    $0x5,%esi
  jne    L5
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void foo(char *name, double d, double e, double f, int g) {
  if (g != 5)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  cmp    $0x5,%esi
  jne    L7
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void foo(char *name, double d, double e, double f, int g) {
  if (g != 5)
    abort();
}
```
user: What is the c source code of the assembly code below:

```asm
<sig_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <sigfillset@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int sig_exit(void) {
  sigset_t mask;
  sigfillset(&mask);
  sigprocmask(SIG_UNBLOCK, &mask, NULL);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sig_exit>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <sigfillset@plt>
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sig_exit(void) {
  sigset_t mask;
  sigfillset(&mask);
  sigprocmask(SIG_UNBLOCK, &mask, NULL);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sig_exit>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigfillset@plt>
  mov    D8(%rip),%rax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sig_exit(void) {
  sigset_t mask;
  sigfillset(&mask);
  sigprocmask(SIG_UNBLOCK, &mask, NULL);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sig_exit>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigfillset@plt>
  mov    D9(%rip),%rax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sig_exit(void) {
  sigset_t mask;
  sigfillset(&mask);
  sigprocmask(SIG_UNBLOCK, &mask, NULL);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<slprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vslprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int slprintf(char *buf, int buflen, char *fmt, ...) {
  va_list args;
  int n;
  va_start(args, fmt);
  n = vslprintf(buf, buflen, fmt, args);
  va_end(args);
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<slprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vslprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int slprintf(char *buf, int buflen, char *fmt, ...) {
  va_list args;
  int n;
  va_start(args, fmt);
  n = vslprintf(buf, buflen, fmt, args);
  va_end(args);
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<slprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vslprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int slprintf(char *buf, int buflen, char *fmt, ...) {
  va_list args;
  int n;
  va_start(args, fmt);
  n = vslprintf(buf, buflen, fmt, args);
  va_end(args);
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<slprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vslprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int slprintf(char *buf, int buflen, char *fmt, ...) {
  va_list args;
  int n;
  va_start(args, fmt);
  n = vslprintf(buf, buflen, fmt, args);
  va_end(args);
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<rarch_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void rarch_sleep(unsigned msec) {
  struct timespec tv = {0};
  tv.tv_sec = msec / 1000;
  tv.tv_nsec = (msec % 1000) * 1000000;
  nanosleep(&tv, NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rarch_sleep>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  mov    %edi,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,0xc(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x10(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void rarch_sleep(unsigned msec) {
  struct timespec tv = {0};
  tv.tv_sec = msec / 1000;
  tv.tv_nsec = (msec % 1000) * 1000000;
  nanosleep(&tv, NULL);
}
```