user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D2(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x678,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x668(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%ecx
  mov    0x1c(%rsp),%eax
  test   %ecx,%ecx
  jle    L30
  lea    0x74(%rsp),%rdi
  mov    $0x1,%ebp
  lea    D41(%rip),%r14
  mov    %rdi,0x8(%rsp)
  nopl   0x0(%rax)
L68:
  mov    0x8(%rsp),%rbx
  mov    $0x1,%r15d
  test   %eax,%eax
  jle    L164
  nop
L102:
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  add    $0x4,%rbx
  cmp    %r15d,%eax
  jge    L102
  mov    0x18(%rsp),%ecx
L164:
  add    $0x1,%ebp
  addq   $0x50,0x8(%rsp)
  cmp    %ebp,%ecx
  jge    L68
  add    $0x1,%eax
  js     L180
L57:
  lea    0x1(%rcx),%edx
  lea    0x20(%rsp),%r14
  movslq %edx,%rdx
  lea    (%rdx,%rdx,4),%rsi
  xor    %edx,%edx
  shl    $0x4,%rsi
  add    %r14,%rsi
  nopl   0x0(%rax)
L96:
  movl   $0xffffffff,(%r14,%rdx,4)
  movl   $0xffffffff,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jge    L96
L180:
  test   %ecx,%ecx
  jle    L10
  lea    -0x1(%rcx),%esi
  lea    0x70(%rsp),%r12
  cltq
  lea    (%rsi,%rsi,4),%rsi
  mov    %r12,%rdx
  shl    $0x4,%rsi
  lea    0xc0(%rsp,%rsi,1),%rsi
  nopl   0x0(%rax)
L86:
  movl   $0xffffffff,(%rdx)
  movl   $0xffffffff,(%rdx,%rax,4)
  add    $0x50,%rdx
  cmp    %rsi,%rdx
  jne    L86
  mov    %r12,%r15
  mov    $0x1,%ebp
  lea    0x20(%rsp),%r14
  nopl   0x0(%rax,%rax,1)
L110:
  mov    0x1c(%rsp),%edx
  mov    $0x1,%ebx
  test   %edx,%edx
  jle    L32
  nopl   (%rax)
L85:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <find_position@plt>
  cmp    $0x1,%eax
  jne    L141
  add    $0x1,%r13d
  mov    %r13d,(%r15,%rbx,4)
L141:
  add    $0x1,%rbx
  cmp    %ebx,0x1c(%rsp)
  jge    L85
  mov    0x18(%rsp),%ecx
L32:
  add    $0x1,%ebp
  add    $0x50,%r15
  cmp    %ebp,%ecx
  jge    L110
  test   %ecx,%ecx
  jle    L10
  mov    $0x1,%r13d
  lea    D35(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L127:
  mov    0x1c(%rsp),%eax
  mov    $0x1,%ebx
  test   %eax,%eax
  jle    L73
  nopl   (%rax)
L44:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x1c(%rsp)
  jge    L44
L73:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    $0x50,%r12
  call   <putchar@plt>
  cmp    %r13d,0x18(%rsp)
  jge    L127
L10:
  mov    0x668(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L117
  add    $0x678,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  add    $0x1,%eax
  jns    L57
  jmp    L10
L117:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D48
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string
name: retrieve_data
arguments: tag: D41
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string

tool: D2: Digite quantidade de linhas: 

tool: D48: %d

tool: D9: 
Digite a quantidade de colunas: 

tool: D41: Digite o elemento MATRIZ[%d][%d]: 

tool: D35: %d	

assistant: ```c
int main(int argc, const char *arqv[]) {
  int mat[20][20], line, col;
  int i, j, cont;
  printf("Digite quantidade de linhas: ");
  scanf("%d", &line);
  printf("\nDigite a quantidade de colunas: ");
  scanf("%d", &col);
  for (i = 1; i <= line; i++) {
    for (j = 1; j <= col; j++) {
      printf("Digite o elemento MATRIZ[%d][%d]: ", i, j);
      scanf("%d", &mat[i][j]);
    }
  }
  for (j = 0; j <= col + 1; j++) {
    mat[0][j] = -1;
    mat[line + 1][j] = -1;
  }
  for (i = 1; i <= line; i++) {
    mat[i][0] = -1;
    mat[i][col + 1] = -1;
  }
  for (i = 1; i <= line; i++) {
    for (j = 1; j <= col; j++) {
      if (find_position(mat, i, j) == 1) {
        cont++;
        mat[i][j] = cont;
      }
    }
  }
  for (i = 1; i <= line; i++) {
    for (j = 1; j <= col; j++) {
      printf("%d\t", mat[i][j]);
    }
    printf("\n");
  }
}
```