ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x10,%esi
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0xfffffffefffffffc,%rax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  movabs $0xfffffffb00000001,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xfffffffcfffffffc,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xfffffffe00000004,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000000,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xfffffffe00000000,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x100000003,%rax
  mov    %rax,0x40(%rsp)
  sub    $0x8,%rax
  mov    %rax,0x48(%rsp)
  call   <threeSum@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L26
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D7(%rip),%r12
  nopl   0x0(%rax)
L16:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L16
L26:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int arr[] = {-4, -2, 1, -5, -4, -4, 4, -2, 0, 4, 0, -2, 3, 1, -5, 0};
  int **r, n, i;
  r = threeSum(arr, ((sizeof(arr)) / sizeof((arr)[0])), &n);
  for (i = 0; i < n; i++) {
    printf("%d %d %d\n", r[i][0], r[i][1], r[i][2]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x10,%esi
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D41(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D40(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D6(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <threeSum@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L24
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D29(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %r12,%rdi
  add    $0x1,%rbx
  mov    0x8(%rax),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L1
L24:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D41
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D40
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D6
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D29
type_infered: string

tool: {"D9": [0xfc,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0x01,0x00,0x00,0x00,0xfb,0xff,0xff,0xff]}

tool: {"D41": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0x04,0x00,0x00,0x00,0xfe,0xff,0xff,0xff]}

tool: {"D40": [0x00,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xfe,0xff,0xff,0xff]}

tool: {"D6": [0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0xfb,0xff,0xff,0xff,0x00,0x00,0x00,0x00]}

tool: D29: %d %d %d


assistant: ```c
int main(int argc, char *argv[]) {
  int arr[] = {-4, -2, 1, -5, -4, -4, 4, -2, 0, 4, 0, -2, 3, 1, -5, 0};
  int **r, n, i;
  r = threeSum(arr, ((sizeof(arr)) / sizeof((arr)[0])), &n);
  for (i = 0; i < n; i++) {
    printf("%d %d %d\n", r[i][0], r[i][1], r[i][2]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_00>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L12
  mov    -0x10(%rbp),%eax
  jmp    L3
L12:
  mov    -0x14(%rbp),%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int test_00(const char *x, int a, int b, int c) {
  if (x[a] == 92)
    return b;
  return c;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_00>:
  endbr64
  movslq %esi,%rsi
  cmpb   $0x5c,(%rdi,%rsi,1)
  mov    %edx,%eax
  cmovne %ecx,%eax
  ret
```

assistant: ```c
int test_00(const char *x, int a, int b, int c) {
  if (x[a] == 92)
    return b;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_00>:
  endbr64
  movslq %esi,%rsi
  mov    %edx,%eax
  cmpb   $0x5c,(%rdi,%rsi,1)
  cmovne %ecx,%eax
  ret
```

assistant: ```c
int test_00(const char *x, int a, int b, int c) {
  if (x[a] == 92)
    return b;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_00>:
  endbr64
  movslq %esi,%rsi
  mov    %edx,%eax
  cmpb   $0x5c,(%rdi,%rsi,1)
  cmovne %ecx,%eax
  ret
```

assistant: ```c
int test_00(const char *x, int a, int b, int c) {
  if (x[a] == 92)
    return b;
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movq   $0x3b9aca00,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movabs $0x7fffffffffffffff,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movq   $0xffffffffffffffff,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void f(void) {
  long unsigned int n = 0;
  sink(__builtin_malloc(n));
  n = 1000 * 1000 * 1000;
  sink(__builtin_malloc(n));
  n += 1;
  sink(__builtin_malloc(n));
  n = 0x7fffffffffffffffL;
  sink(__builtin_malloc(n));
  n = 0xffffffffffffffffUL;
  sink(__builtin_malloc(n));
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3b9aca00,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3b9aca01,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movabs $0x7fffffffffffffff,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void f(void) {
  long unsigned int n = 0;
  sink(__builtin_malloc(n));
  n = 1000 * 1000 * 1000;
  sink(__builtin_malloc(n));
  n += 1;
  sink(__builtin_malloc(n));
  n = 0x7fffffffffffffffL;
  sink(__builtin_malloc(n));
  n = 0xffffffffffffffffUL;
  sink(__builtin_malloc(n));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3b9aca00,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3b9aca01,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movabs $0x7fffffffffffffff,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <__builtin_malloc@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <sink@plt>
```

assistant: ```c
void f(void) {
  long unsigned int n = 0;
  sink(__builtin_malloc(n));
  n = 1000 * 1000 * 1000;
  sink(__builtin_malloc(n));
  n += 1;
  sink(__builtin_malloc(n));
  n = 0x7fffffffffffffffL;
  sink(__builtin_malloc(n));
  n = 0xffffffffffffffffUL;
  sink(__builtin_malloc(n));
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3b9aca00,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0x3b9aca01,%edi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  movabs $0x7fffffffffffffff,%rdi
  call   <__builtin_malloc@plt>
  mov    %eax,%edi
  call   <sink@plt>
  mov    $0xffffffffffffffff,%rdi
  call   <__builtin_malloc@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <sink@plt>
```

assistant: ```c
void f(void) {
  long unsigned int n = 0;
  sink(__builtin_malloc(n));
  n = 1000 * 1000 * 1000;
  sink(__builtin_malloc(n));
  n += 1;
  sink(__builtin_malloc(n));
  n = 0x7fffffffffffffffL;
  sink(__builtin_malloc(n));
  n = 0xffffffffffffffffUL;
  sink(__builtin_malloc(n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D96(%rip),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  D23(%rip),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  D79(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D37(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  D44(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D88(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movl   $0x4,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  mov    -0x5c(%rbp),%edx
  lea    -0x50(%rbp),%rsi
  mov    D37(%rip),%rcx
  mov    -0x60(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%edi
  call   <stdlib_strided_dapxsumkbn2@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D96
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D10
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D23
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D79
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D37
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D12
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D44
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D88
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D90
type_guessed: string

tool: D96: 1

tool: D10: 2

tool: D23: 3

tool: D79: 4

tool: D37: 5

tool: D12: 6

tool: D44: 7

tool: D88: 8

tool: D90: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dapxsumkbn2(N, 5.0, x, stride);
  printf("sum: %lf\n", v);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D74(%rip),%rax
  mov    %rax,(%rsp)
  mov    D1(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D20(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D41(%rip),%rax
  mov    %rax,0x18(%rsp)
  movsd  D6(%rip),%xmm0
  movsd  %xmm0,0x20(%rsp)
  mov    D58(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D34(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D7(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edx
  mov    $0x4,%edi
  call   <stdlib_strided_dapxsumkbn2@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D74
type_guessed: f64
name: disassemble_data
arguments: tag: D1
type_guessed: f64
name: disassemble_data
arguments: tag: D20
type_guessed: f64
name: disassemble_data
arguments: tag: D41
type_guessed: f64
name: disassemble_data
arguments: tag: D6
type_guessed: f64
name: disassemble_data
arguments: tag: D58
type_guessed: f64
name: disassemble_data
arguments: tag: D34
type_guessed: f64
name: disassemble_data
arguments: tag: D7
type_guessed: f64
name: disassemble_data
arguments: tag: D32
type_guessed: string

tool: D74: 1

tool: D1: 2

tool: D20: 3

tool: D41: 4

tool: D6: 5

tool: D58: 6

tool: D34: 7

tool: D7: 8

tool: D32: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dapxsumkbn2(N, 5.0, x, stride);
  printf("sum: %lf\n", v);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x4,%edi
  mov    $0x2,%edx
  movsd  D65(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D89(%rip),%rax
  mov    %rsp,%rsi
  movsd  %xmm0,0x20(%rsp)
  mov    %rax,(%rsp)
  mov    D7(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D6(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D70(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D45(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D2(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D16(%rip),%rax
  mov    %rax,0x38(%rsp)
  call   <stdlib_strided_dapxsumkbn2@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D65
data_type: f64
name: unpack_data
arguments: tag: D89
data_type: f64
name: unpack_data
arguments: tag: D7
data_type: f64
name: unpack_data
arguments: tag: D6
data_type: f64
name: unpack_data
arguments: tag: D70
data_type: f64
name: unpack_data
arguments: tag: D45
data_type: f64
name: unpack_data
arguments: tag: D2
data_type: f64
name: unpack_data
arguments: tag: D16
data_type: f64
name: unpack_data
arguments: tag: D24
data_type: string

tool: D65: 5

tool: D89: 1

tool: D7: 2

tool: D6: 3

tool: D70: 4

tool: D45: 6

tool: D2: 7

tool: D16: 8

tool: D24: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dapxsumkbn2(N, 5.0, x, stride);
  printf("sum: %lf\n", v);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x4,%edi
  mov    $0x2,%edx
  movapd D49(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movapd D48(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movapd D22(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movapd D59(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movsd  D22(%rip),%xmm0
  call   <stdlib_strided_dapxsumkbn2@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D49
type_infered: f64[2]
name: parse_data
arguments: tag: D48
type_infered: f64[2]
name: parse_data
arguments: tag: D22
type_infered: f64[2]
name: parse_data
arguments: tag: D59
type_infered: f64[2]
name: parse_data
arguments: tag: D29
type_infered: string

tool: {"D49": [1.0,2.0]}

tool: {"D48": [3.0,4.0]}

tool: {"D22": [5.0,6.0]}

tool: {"D59": [7.0,8.0]}

tool: D29: sum: %lf


assistant: ```c
int main() {
  double x[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0};
  int64_t N = 4;
  int64_t stride = 2;
  double v = stdlib_strided_dapxsumkbn2(N, 5.0, x, stride);
  printf("sum: %lf\n", v);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_tthread_timespec_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x2c(%rbp)
  je     L14
  mov    $0x0,%eax
  jmp    L10
L14:
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x2c(%rbp),%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int _tthread_timespec_get(struct timespec *ts, int base) {
  struct timeval tv;
  if (base != 1) {
    return 0;
  }
  gettimeofday(&tv, (void *)0);
  ts->tv_sec = (time_t)tv.tv_sec;
  ts->tv_nsec = 1000L * (long)tv.tv_usec;
  return base;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_tthread_timespec_get>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L7
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rax
  mov    %rax,0x8(%rbp)
  imul   $0x3e8,(%rsp),%rax
  mov    %rax,0x0(%rbp)
  mov    %ebx,%eax
  jmp    L14
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _tthread_timespec_get(struct timespec *ts, int base) {
  struct timeval tv;
  if (base != 1) {
    return 0;
  }
  gettimeofday(&tv, (void *)0);
  ts->tv_sec = (time_t)tv.tv_sec;
  ts->tv_nsec = 1000L * (long)tv.tv_usec;
  return base;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_tthread_timespec_get>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L29
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L29:
  mov    %rdi,%rbx
  xor    %esi,%esi
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rax
  mov    %rax,0x8(%rbx)
  imul   $0x3e8,(%rsp),%rax
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L10
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _tthread_timespec_get(struct timespec *ts, int base) {
  struct timeval tv;
  if (base != 1) {
    return 0;
  }
  gettimeofday(&tv, (void *)0);
  ts->tv_sec = (time_t)tv.tv_sec;
  ts->tv_nsec = 1000L * (long)tv.tv_usec;
  return base;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_tthread_timespec_get>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%esi
  je     L7
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L7:
  mov    %rdi,%rbx
  xor    %esi,%esi
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  movhps 0x8(%rsp),%xmm0
  movups %xmm0,(%rbx)
  jmp    L9
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _tthread_timespec_get(struct timespec *ts, int base) {
  struct timeval tv;
  if (base != 1) {
    return 0;
  }
  gettimeofday(&tv, (void *)0);
  ts->tv_sec = (time_t)tv.tv_sec;
  ts->tv_nsec = 1000L * (long)tv.tv_usec;
  return base;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<spawn_type_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  mov    $0x0,%eax
  jmp    L9
L1:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    $0x1,%eax
  jmp    L9
L12:
  mov    -0x8(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L53
  mov    $0x2,%eax
  jmp    L9
L53:
  mov    $0xffffffff,%eax
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D7: player

tool: D14: bldhnd

tool: D17: zombie

assistant: ```c
unsigned int spawn_type_id(const char *name) {
  if (strcmp(name, "player") == 0) {
    return 0x00000000;
  } else if (strcmp(name, "bldhnd") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "zombie") == 0) {
    return 0x00000002;
  }
  return 0xFFFFFFFF;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<spawn_type_id>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D28(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L2
L11:
  pop    %rbx
  ret
L2:
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L11
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x3,%eax
  sub    $0x1,%eax
  jmp    L11
```

tool_calls: name: parse_data
arguments: data_label: D28
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string

tool: D28: player

tool: D9: bldhnd

tool: D15: zombie

assistant: ```c
unsigned int spawn_type_id(const char *name) {
  if (strcmp(name, "player") == 0) {
    return 0x00000000;
  } else if (strcmp(name, "bldhnd") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "zombie") == 0) {
    return 0x00000002;
  }
  return 0xFFFFFFFF;
}
```
user: Translate the below assembly code into C programming language:

```asm
<spawn_type_id>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L15
L4:
  pop    %rbp
  ret
L15:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L4
  mov    %rbp,%rdi
  lea    D12(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x3,%eax
  sub    $0x1,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string

tool: D25: player

tool: D17: bldhnd

tool: D12: zombie

assistant: ```c
unsigned int spawn_type_id(const char *name) {
  if (strcmp(name, "player") == 0) {
    return 0x00000000;
  } else if (strcmp(name, "bldhnd") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "zombie") == 0) {
    return 0x00000002;
  }
  return 0xFFFFFFFF;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<spawn_type_id>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L5
L1:
  pop    %rbp
  ret
L5:
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L1
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  call   <strcmp@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x3,%eax
  sub    $0x1,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D25
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string

tool: D18: player

tool: D25: bldhnd

tool: D1: zombie

assistant: ```c
unsigned int spawn_type_id(const char *name) {
  if (strcmp(name, "player") == 0) {
    return 0x00000000;
  } else if (strcmp(name, "bldhnd") == 0) {
    return 0x00000001;
  } else if (strcmp(name, "zombie") == 0) {
    return 0x00000002;
  }
  return 0xFFFFFFFF;
}
```