ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  andl   $0x7fffffff,-0x30(%rbp)
  cmpl   $0x3fe921fb,-0x30(%rbp)
  jg     L9
  mov    -0x38(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  movsd  -0x28(%rbp),%xmm0
  mov    %rdx,%rsi
  mov    $0x1,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__kernel_tan@plt>
  jmp    L45
L9:
  cmpl   $0x7fefffff,-0x30(%rbp)
  jle    L10
  movsd  -0x38(%rbp),%xmm0
  movsd  -0x38(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L45
L10:
  mov    -0x38(%rbp),%rax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <__ieee754_rem_pio2@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  and    $0x2,%eax
  mov    $0x1,%edx
  mov    %edx,%ecx
  sub    %eax,%ecx
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %ecx,%edi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <__kernel_tan@plt>
  nop
L45:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void tan(double x, double *result) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    __kernel_tan(x, z, 1, result);
    return;
  } else if (ix >= 0x7ff00000) {
    *result = x - x;
    return;
  } else {
    n = __ieee754_rem_pio2(x, y);
    __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1), result);
    return;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<tan>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3fe921fb,%eax
  jle    L9
  cmp    $0x7fefffff,%eax
  jle    L38
  subsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
L37:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  mov    %rdi,%rsi
  mov    $0x1,%edi
  pxor   %xmm1,%xmm1
  call   <__kernel_tan@plt>
  jmp    L37
L38:
  mov    %rsp,%rdi
  call   <__ieee754_rem_pio2@plt>
  add    %eax,%eax
  and    $0x2,%eax
  mov    $0x1,%edi
  sub    %eax,%edi
  mov    %rbx,%rsi
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  call   <__kernel_tan@plt>
  jmp    L37
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tan(double x, double *result) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    __kernel_tan(x, z, 1, result);
    return;
  } else if (ix >= 0x7ff00000) {
    *result = x - x;
    return;
  } else {
    n = __ieee754_rem_pio2(x, y);
    __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1), result);
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tan>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3fe921fb,%eax
  jle    L10
  cmp    $0x7fefffff,%eax
  jle    L7
  subsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x20,%rsp
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rsp,%rdi
  call   <__ieee754_rem_pio2@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %rbp,%rsi
  add    %eax,%eax
  mov    $0x1,%edi
  and    $0x2,%eax
  sub    %eax,%edi
  call   <__kernel_tan@plt>
  jmp    L14
  nopl   0x0(%rax)
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x20,%rsp
  mov    %rdi,%rsi
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <__kernel_tan@plt>
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tan(double x, double *result) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    __kernel_tan(x, z, 1, result);
    return;
  } else if (ix >= 0x7ff00000) {
    *result = x - x;
    return;
  } else {
    n = __ieee754_rem_pio2(x, y);
    __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1), result);
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tan>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3fe921fb,%eax
  jle    L18
  cmp    $0x7fefffff,%eax
  jle    L0
  subsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi)
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x20,%rsp
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rsp,%rdi
  call   <__ieee754_rem_pio2@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm0
  mov    %rbp,%rsi
  add    %eax,%eax
  mov    $0x1,%edi
  and    $0x2,%eax
  sub    %eax,%edi
  call   <__kernel_tan@plt>
  jmp    L24
  nopl   0x0(%rax)
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x20,%rsp
  mov    %rdi,%rsi
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  pop    %rbp
  jmp    1070 <__kernel_tan@plt>
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tan(double x, double *result) {
  double y[2], z = 0.0;
  int n, ix;
  ix = *(1 + (int *)&x);
  ix &= 0x7fffffff;
  if (ix <= 0x3fe921fb) {
    __kernel_tan(x, z, 1, result);
    return;
  } else if (ix >= 0x7ff00000) {
    *result = x - x;
    return;
  } else {
    n = __ieee754_rem_pio2(x, y);
    __kernel_tan(y[0], y[1], 1 - ((n & 1) << 1), result);
    return;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kbuffer_ptr_delta>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read_4@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ts4host@plt>
  leave
  ret
```

assistant: ```c
unsigned int kbuffer_ptr_delta(struct kbuffer *kbuf, void *ptr) {
  unsigned int type_len_ts;
  type_len_ts = read_4(kbuf, ptr);
  return ts4host(kbuf, type_len_ts);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kbuffer_ptr_delta>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <read_4@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <ts4host@plt>
  pop    %rbx
  ret
```

assistant: ```c
unsigned int kbuffer_ptr_delta(struct kbuffer *kbuf, void *ptr) {
  unsigned int type_len_ts;
  type_len_ts = read_4(kbuf, ptr);
  return ts4host(kbuf, type_len_ts);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kbuffer_ptr_delta>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <read_4@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <ts4host@plt>
```

assistant: ```c
unsigned int kbuffer_ptr_delta(struct kbuffer *kbuf, void *ptr) {
  unsigned int type_len_ts;
  type_len_ts = read_4(kbuf, ptr);
  return ts4host(kbuf, type_len_ts);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<kbuffer_ptr_delta>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <read_4@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1060 <ts4host@plt>
```

assistant: ```c
unsigned int kbuffer_ptr_delta(struct kbuffer *kbuf, void *ptr) {
  unsigned int type_len_ts;
  type_len_ts = read_4(kbuf, ptr);
  return ts4host(kbuf, type_len_ts);
}
```
user: What is the c source code of the assembly code below:

```asm
<SDL_imageFilterConvolveKernel9x9ShiftRight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    %r9d,%eax
  mov    %al,-0x24(%rbp)
  cmpl   $0x8,-0x18(%rbp)
  jle    L4
  cmpl   $0x8,-0x14(%rbp)
  jle    L4
  cmpb   $0x7,-0x24(%rbp)
  jbe    L45
L4:
  mov    $0xffffffff,%eax
  jmp    L26
L45:
  mov    $0x0,%eax
  call   <SDL_imageFilterMMXdetect@plt>
  test   %rax,%rax
  je     L52
  mov    $0x0,%eax
  jmp    L26
L52:
  mov    $0xffffffff,%eax
L26:
  leave
  ret
```

assistant: ```c
int SDL_imageFilterConvolveKernel9x9ShiftRight(unsigned char *Src, unsigned char *Dest, int rows, int columns, signed short *Kernel, unsigned char NRightShift) {
  if ((columns < 9) || (rows < 9) || (NRightShift > 7))
    return (-1);
  if ((SDL_imageFilterMMXdetect())) {
    return (0);
  } else {
    return (-1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SDL_imageFilterConvolveKernel9x9ShiftRight>:
  endbr64
  cmp    $0x8,%edx
  setle  %al
  cmp    $0x7,%r9b
  seta   %dl
  or     %dl,%al
  jne    L8
  cmp    $0x8,%ecx
  jle    L8
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SDL_imageFilterMMXdetect@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterConvolveKernel9x9ShiftRight(unsigned char *Src, unsigned char *Dest, int rows, int columns, signed short *Kernel, unsigned char NRightShift) {
  if ((columns < 9) || (rows < 9) || (NRightShift > 7))
    return (-1);
  if ((SDL_imageFilterMMXdetect())) {
    return (0);
  } else {
    return (-1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SDL_imageFilterConvolveKernel9x9ShiftRight>:
  endbr64
  cmp    $0x8,%edx
  setle  %al
  cmp    $0x7,%r9b
  seta   %dl
  or     %dl,%al
  jne    L6
  cmp    $0x8,%ecx
  jle    L6
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SDL_imageFilterMMXdetect@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterConvolveKernel9x9ShiftRight(unsigned char *Src, unsigned char *Dest, int rows, int columns, signed short *Kernel, unsigned char NRightShift) {
  if ((columns < 9) || (rows < 9) || (NRightShift > 7))
    return (-1);
  if ((SDL_imageFilterMMXdetect())) {
    return (0);
  } else {
    return (-1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SDL_imageFilterConvolveKernel9x9ShiftRight>:
  endbr64
  cmp    $0x8,%edx
  setle  %al
  cmp    $0x7,%r9b
  seta   %dl
  or     %dl,%al
  jne    L4
  cmp    $0x8,%ecx
  jle    L4
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SDL_imageFilterMMXdetect@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterConvolveKernel9x9ShiftRight(unsigned char *Src, unsigned char *Dest, int rows, int columns, signed short *Kernel, unsigned char NRightShift) {
  if ((columns < 9) || (rows < 9) || (NRightShift > 7))
    return (-1);
  if ((SDL_imageFilterMMXdetect())) {
    return (0);
  } else {
    return (-1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x17,-0x14(%rbp)
  movl   $0x73736148,-0xf(%rbp)
  movw   $0x6e61,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    $0x17,%edx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  lea    -0xf(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x14,-0x14(%rbp)
  lea    -0xf(%rbp),%rax
  lea    D31(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x14(%rbp),%edx
  lea    -0xf(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D21
type_infered: string
name: parse_data
arguments: tag: D33
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D22
type_infered: string

tool: D21: Hassan

tool: D33: %s is %d 


tool: D31: Khaled

tool: D22: %s is %d


assistant: ```c
int main() {
  int age = 23;
  char name[] = "Hassan";
  printf("%s is %d \n", "Hassan", 23);
  printf("%s is %d \n", name, age);
  age = 20;
  strcpy(name, "Khaled");
  printf("%s is %d\n", name, age);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x73736148,0x1(%rsp)
  movw   $0x6e61,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  mov    $0x17,%edx
  lea    D25(%rip),%rsi
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x1(%rsp),%rbx
  mov    $0x17,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    $0x14,%edx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_infered: string
name: extract_symbolic_data
arguments: data_label: D29
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D14
type_infered: string

tool: D25: Hassan

tool: D29: %s is %d 


tool: D20: Khaled

tool: D14: %s is %d


assistant: ```c
int main() {
  int age = 23;
  char name[] = "Hassan";
  printf("%s is %d \n", "Hassan", 23);
  printf("%s is %d \n", name, age);
  age = 20;
  strcpy(name, "Khaled");
  printf("%s is %d\n", name, age);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D31(%rip),%r12
  mov    $0x17,%edx
  lea    D0(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    $0x6e61,%eax
  movl   $0x73736148,0x1(%rsp)
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <printf@plt>
  mov    $0x17,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x14,%edx
  mov    %rbp,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D31
data_type: string
name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D22
data_type: string

tool: D31: %s is %d 


tool: D0: Hassan

tool: D19: Khaled

tool: D22: %s is %d


assistant: ```c
int main() {
  int age = 23;
  char name[] = "Hassan";
  printf("%s is %d \n", "Hassan", 23);
  printf("%s is %d \n", name, age);
  age = 20;
  strcpy(name, "Khaled");
  printf("%s is %d\n", name, age);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  mov    $0x17,%edx
  lea    D30(%rip),%rsi
  push   %rbp
  mov    %r12,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    $0x6e61,%eax
  movl   $0x73736148,0x1(%rsp)
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <printf@plt>
  mov    $0x17,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x14,%edx
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D30
datatype: string
name: read_data
arguments: tag: D20
datatype: string
name: read_data
arguments: tag: D34
datatype: string

tool: D0: %s is %d 


tool: D30: Hassan

tool: D20: Khaled

tool: D34: %s is %d


assistant: ```c
int main() {
  int age = 23;
  char name[] = "Hassan";
  printf("%s is %d \n", "Hassan", 23);
  printf("%s is %d \n", name, age);
  age = 20;
  strcpy(name, "Khaled");
  printf("%s is %d\n", name, age);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<long_asc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L2
L5:
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L2:
  cmpq   $0x9,-0x18(%rbp)
  jg     L5
  mov    -0x18(%rbp),%rax
  lea    0x30(%rax),%ecx
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L21
L16:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
L21:
  cmpl   $0x0,-0xc(%rbp)
  jne    L16
  nop
  pop    %rbp
  ret
```

assistant: ```c
long_asc(char buf[], int width, long num) {
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<long_asc>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rcx
  movslq %esi,%rax
  movb   $0x0,(%rdi,%rax,1)
  cmp    $0x9,%rdx
  jle    L4
  lea    -0x1(%rsi),%esi
  movslq %esi,%rsi
  movabs $0x6666666666666667,%r10
L30:
  mov    %esi,%r8d
  mov    %rcx,%rax
  imul   %r10
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%r9
  add    %r9,%r9
  mov    %rcx,%rax
  sub    %r9,%rax
  add    $0x30,%eax
  mov    %al,(%rdi,%rsi,1)
  mov    %rcx,%rax
  mov    %rdx,%rcx
  sub    $0x1,%rsi
  cmp    $0x63,%rax
  jg     L30
L4:
  lea    -0x1(%r8),%edx
  movslq %edx,%rax
  add    %rdi,%rax
  add    $0x30,%ecx
  mov    %cl,(%rax)
  test   %edx,%edx
  je     L13
  movslq %r8d,%rdx
  lea    -0x2(%rdi,%rdx,1),%rdx
  lea    -0x2(%r8),%ecx
  sub    %rcx,%rdx
L11:
  movb   $0x20,-0x1(%rax)
  sub    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
L13:
  ret
```

assistant: ```c
long_asc(char buf[], int width, long num) {
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<long_asc>:
  endbr64
  movslq %esi,%rax
  mov    %rdx,%rcx
  movb   $0x0,(%rdi,%rax,1)
  mov    %rax,%r9
  cmp    $0x9,%rdx
  jle    L24
  movabs $0xcccccccccccccccd,%r10
  lea    -0x1(%rax),%esi
  movslq %esi,%rsi
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rcx,%rax
  mov    %esi,%r9d
  mul    %r10
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%r8
  add    %r8,%r8
  sub    %r8,%rax
  add    $0x30,%eax
  mov    %al,(%rdi,%rsi,1)
  mov    %rcx,%rax
  sub    $0x1,%rsi
  mov    %rdx,%rcx
  cmp    $0x63,%rax
  jg     L26
L24:
  lea    -0x1(%r9),%edx
  add    $0x30,%ecx
  movslq %edx,%rax
  mov    %cl,(%rdi,%rax,1)
  test   %edx,%edx
  je     L29
  lea    -0x2(%r9),%edx
  sub    $0x1,%rax
  sub    $0x8,%rsp
  mov    $0x20,%esi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %rax,%rdi
  mov    %r8,%rdx
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L29:
  ret
```

assistant: ```c
long_asc(char buf[], int width, long num) {
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: What is the c source code of the assembly code below:

```asm
<long_asc>:
  endbr64
  movslq %esi,%rax
  mov    %rdx,%rcx
  movb   $0x0,(%rdi,%rax,1)
  mov    %rax,%r9
  cmp    $0x9,%rdx
  jle    L20
  movabs $0xcccccccccccccccd,%r10
  lea    -0x1(%rax),%esi
  movslq %esi,%rsi
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rcx,%rax
  mov    %esi,%r9d
  mul    %r10
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%r8
  add    %r8,%r8
  sub    %r8,%rax
  add    $0x30,%eax
  mov    %al,(%rdi,%rsi,1)
  mov    %rcx,%rax
  sub    $0x1,%rsi
  mov    %rdx,%rcx
  cmp    $0x63,%rax
  jg     L4
L20:
  lea    -0x1(%r9),%edx
  add    $0x30,%ecx
  movslq %edx,%rax
  mov    %cl,(%rdi,%rax,1)
  test   %edx,%edx
  je     L28
  lea    -0x2(%r9),%edx
  sub    $0x1,%rax
  sub    $0x8,%rsp
  mov    $0x20,%esi
  sub    %rdx,%rax
  lea    0x1(%rdx),%r8
  add    %rax,%rdi
  mov    %r8,%rdx
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L28:
  ret
```

assistant: ```c
long_asc(char buf[], int width, long num) {
  buf[width] = 0;
  while (num >= 10) {
    buf[--width] = (int)(num % 10L) + '0';
    num /= 10L;
  }
  buf[--width] = (int)num + '0';
  while (width != 0)
    buf[--width] = ' ';
}
```
user: Translate the below assembly code into C programming language:

```asm
<vbi_ucs2be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x62,-0x39(%rbp)
  lea    -0x39(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movw   $0x6161,-0xa(%rbp)
  lea    -0xa(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movq   $0x1,-0x20(%rbp)
  movq   $0x2,-0x18(%rbp)
  movl   $0xffffffff,-0x38(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <iconv_open@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0xffffffff,-0x34(%rbp)
  je     L56
  lea    -0x18(%rbp),%rdi
  lea    -0x28(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <iconv@plt>
  movzbl -0xa(%rbp),%eax
  test   %al,%al
  jne    L36
  movzbl -0x9(%rbp),%eax
  cmp    $0x62,%al
  jne    L36
  movl   $0x1,-0x38(%rbp)
  jmp    L55
L36:
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  jne    L55
  movzbl -0xa(%rbp),%eax
  cmp    $0x62,%al
  jne    L55
  movl   $0x0,-0x38(%rbp)
L55:
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <iconv_close@plt>
L56:
  mov    -0x38(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D12
data_type: string
name: read_data
arguments: label: D17
data_type: string

tool: D12: ISO-8859-1

tool: D17: UCS-2

assistant: ```c
int vbi_ucs2be(void) {
  iconv_t cd;
  char c = 'b', *cp = &c;
  char uc[2] = {'a', 'a'}, *up = uc;
  size_t in = sizeof(c), out = sizeof(uc);
  int endianess = -1;
  if ((cd = iconv_open("UCS-2", "ISO-8859-1")) != (iconv_t)-1) {
    iconv(cd, (void *)&cp, &in, (void *)&up, &out);
    if (uc[0] == 0 && uc[1] == 'b')
      endianess = 1;
    else if (uc[1] == 0 && uc[0] == 'b')
      endianess = 0;
    iconv_close(cd);
  }
  return endianess;
}
```