ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<scale_array>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L44
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L9
  mov    %esi,%ecx
  movaps %xmm0,%xmm2
  mov    %rdi,%rax
  shr    $0x2,%ecx
  shufps $0x0,%xmm2,%xmm2
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  xchg   %ax,%ax
L12:
  movups (%rax),%xmm1
  add    $0x10,%rax
  mulps  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L12
  mov    %esi,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%esi
  je     L42
L15:
  sub    %ecx,%esi
  cmp    $0x1,%esi
  je     L43
  lea    (%rdx,%rcx,4),%rcx
  movaps %xmm0,%xmm2
  movq   (%rcx),%xmm1
  shufps $0xe0,%xmm2,%xmm2
  mulps  %xmm2,%xmm1
  movlps %xmm1,(%rcx)
  mov    %esi,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%esi
  je     L44
L43:
  cltq
  lea    (%rdx,%rax,4),%rax
  mulss  (%rax),%xmm0
  movss  %xmm0,(%rax)
L44:
  ret
  nopl   0x0(%rax)
L42:
  ret
L9:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L15
```

assistant: ```c
void scale_array(float *a, int n, float s) {
  int i;
  for (i = 0; i < n; ++i) {
    a[i] *= s;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <leapYear@plt>
  test   %rax,%rax
  je     L1
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L26
L1:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L26:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D57
data_type: string
name: parse_data
arguments: label: D37
data_type: string
name: parse_data
arguments: label: D42
data_type: string
name: parse_data
arguments: label: D22
data_type: string

tool: D57: Enter a year: 

tool: D37: %d

tool: D42:  is a leap year.

tool: D22:  is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Enter a year: ");
  scanf("%d", &year);
  if (leapYear(year)) {
    printf("%d", year);
    printf(" is a leap year.\n");
  } else {
    printf("%d", year);
    printf(" is not a leap year.\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D55(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <leapYear@plt>
  test   %rax,%rax
  je     L29
  mov    0x4(%rsp),%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L29:
  mov    0x4(%rsp),%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  jmp    L8
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D58
data_type: string
name: unpack_data
arguments: label: D55
data_type: string
name: unpack_data
arguments: label: D26
data_type: string
name: unpack_data
arguments: label: D44
data_type: string

tool: D58: Enter a year: 

tool: D55: %d

tool: D26:  is a leap year.

tool: D44:  is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Enter a year: ");
  scanf("%d", &year);
  if (leapYear(year)) {
    printf("%d", year);
    printf(" is a leap year.\n");
  } else {
    printf("%d", year);
    printf(" is not a leap year.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rdi
  lea    D30(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <leapYear@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  test   %rax,%rax
  mov    $0x0,%eax
  je     L24
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  jmp    L12
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D33
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D36
type_guessed: string

tool: D33: Enter a year: 

tool: D30: %d

tool: D23:  is a leap year.

tool: D36:  is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Enter a year: ");
  scanf("%d", &year);
  if (leapYear(year)) {
    printf("%d", year);
    printf(" is a leap year.\n");
  } else {
    printf("%d", year);
    printf(" is not a leap year.\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  lea    D3(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <leapYear@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  test   %rax,%rax
  mov    $0x0,%eax
  je     L6
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L26
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D1: Enter a year: 

tool: D3: %d

tool: D24:  is a leap year.

tool: D6:  is not a leap year.

assistant: ```c
int main() {
  int year;
  printf("Enter a year: ");
  scanf("%d", &year);
  if (leapYear(year)) {
    printf("%d", year);
    printf(" is a leap year.\n");
  } else {
    printf("%d", year);
    printf(" is not a leap year.\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<combination_next>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L6
  cmpl   $0x0,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L2
L17:
  subl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
  jmp    L21
L6:
  addl   $0x1,-0x8(%rbp)
  jmp    L42
L40:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L40
  mov    $0x1,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int combination_next(int r, int n, int *c) {
  int i = r - 1;
  int h = n;
recurse:
  ++c[i];
  if (c[i] >= h) {
    if (i == 0)
      return 0;
    --i;
    --h;
    goto recurse;
  }
  ++i;
  while (i < r) {
    c[i] = c[i - 1] + 1;
    ++i;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<combination_next>:
  endbr64
  mov    %edi,%r10d
  mov    %rdx,%rcx
  lea    -0x1(%rdi),%r8d
  movslq %r8d,%rax
  lea    (%rdx,%rax,4),%rdx
  mov    (%rdx),%eax
  add    $0x1,%eax
  mov    %eax,(%rdx)
  cmp    %eax,%esi
  jg     L7
  test   %r8d,%r8d
  je     L42
  lea    -0x2(%rdi),%edx
  movslq %edx,%rax
  movslq %edi,%r9
  sub    $0x3,%r9
  mov    %edx,%edx
  sub    %rdx,%r9
  add    $0x1,%esi
  sub    %edi,%esi
L38:
  mov    %eax,%r8d
  mov    (%rcx,%rax,4),%edi
  lea    0x1(%rdi),%edx
  mov    %edx,(%rcx,%rax,4)
  lea    (%rsi,%rax,1),%edi
  cmp    %edi,%edx
  jl     L7
  sub    $0x1,%rax
  cmp    %r9,%rax
  jne    L38
  mov    $0x0,%r8d
  jmp    L42
L7:
  lea    0x1(%r8),%eax
  cmp    %eax,%r10d
  jle    L68
  cltq
  lea    (%rcx,%rax,4),%rax
  sub    $0x2,%r10d
  sub    %r8d,%r10d
  movslq %r8d,%r8
  add    %r8,%r10
  lea    0x8(%rcx,%r10,4),%rcx
L49:
  mov    -0x4(%rax),%esi
  lea    0x1(%rsi),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L49
  mov    $0x1,%r8d
L42:
  mov    %r8d,%eax
  ret
L68:
  mov    $0x1,%r8d
  jmp    L42
```

assistant: ```c
__attribute__((always_)) int combination_next(int r, int n, int *c) {
  int i = r - 1;
  int h = n;
recurse:
  ++c[i];
  if (c[i] >= h) {
    if (i == 0)
      return 0;
    --i;
    --h;
    goto recurse;
  }
  ++i;
  while (i < r) {
    c[i] = c[i - 1] + 1;
    ++i;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<combination_next>:
  endbr64
  lea    -0x1(%rdi),%r10d
  movslq %r10d,%rax
  lea    (%rdx,%rax,4),%r8
  mov    (%r8),%ecx
  add    $0x1,%ecx
  mov    %ecx,(%r8)
  cmp    %ecx,%esi
  jg     L4
  sub    %edi,%esi
  test   %r10d,%r10d
  jne    L28
  jmp    L62
  nopl   (%rax)
L61:
  sub    $0x1,%rax
  test   %eax,%eax
  je     L62
L28:
  mov    -0x4(%rdx,%rax,4),%ecx
  lea    (%rsi,%rax,1),%r8d
  movslq %eax,%r9
  add    $0x1,%ecx
  mov    %ecx,-0x4(%rdx,%rax,4)
  cmp    %r8d,%ecx
  jge    L61
  cmp    %r9d,%edi
  jle    L4
  sub    %eax,%r10d
  lea    (%rdx,%r9,4),%rcx
  add    %r9,%r10
  lea    0x4(%rdx,%r10,4),%rdx
  nopl   0x0(%rax,%rax,1)
L36:
  mov    -0x4(%rcx),%eax
  add    $0x4,%rcx
  add    $0x1,%eax
  mov    %eax,-0x4(%rcx)
  cmp    %rcx,%rdx
  jne    L36
L4:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int combination_next(int r, int n, int *c) {
  int i = r - 1;
  int h = n;
recurse:
  ++c[i];
  if (c[i] >= h) {
    if (i == 0)
      return 0;
    --i;
    --h;
    goto recurse;
  }
  ++i;
  while (i < r) {
    c[i] = c[i - 1] + 1;
    ++i;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<combination_next>:
  endbr64
  lea    -0x1(%rdi),%r10d
  mov    %rdx,%rcx
  movslq %r10d,%rax
  lea    (%rdx,%rax,4),%r8
  mov    (%r8),%edx
  add    $0x1,%edx
  mov    %edx,(%r8)
  cmp    %edx,%esi
  jg     L59
  sub    %edi,%esi
  test   %r10d,%r10d
  jne    L68
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L39:
  sub    $0x1,%rax
  test   %eax,%eax
  je     L27
L68:
  mov    -0x4(%rcx,%rax,4),%edx
  lea    (%rsi,%rax,1),%r8d
  movslq %eax,%r9
  add    $0x1,%edx
  mov    %edx,-0x4(%rcx,%rax,4)
  cmp    %r8d,%edx
  jge    L39
  cmp    %r9d,%edi
  jle    L59
  sub    %eax,%r10d
  lea    (%rcx,%r9,4),%rdx
  add    %r9,%r10
  mov    -0x4(%rdx),%esi
  lea    0x4(%rcx,%r10,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L57:
  add    $0x1,%esi
  add    $0x4,%rdx
  mov    %esi,-0x4(%rdx)
  cmp    %rdx,%rax
  jne    L57
L59:
  mov    $0x1,%eax
  ret
  nopl   (%rax)
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
__attribute__((always_)) int combination_next(int r, int n, int *c) {
  int i = r - 1;
  int h = n;
recurse:
  ++c[i];
  if (c[i] >= h) {
    if (i == 0)
      return 0;
    --i;
    --h;
    goto recurse;
  }
  ++i;
  while (i < r) {
    c[i] = c[i - 1] + 1;
    ++i;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<receivemsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: Received: 

assistant: ```c
void receivemsg(char *msg, int lenmsg) {
  printf("Received: ");
  printf("%s\n", msg);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<receivemsg>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: Received: 

assistant: ```c
void receivemsg(char *msg, int lenmsg) {
  printf("Received: ");
  printf("%s\n", msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<receivemsg>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: Received: 

assistant: ```c
void receivemsg(char *msg, int lenmsg) {
  printf("Received: ");
  printf("%s\n", msg);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<receivemsg>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: Received: 

assistant: ```c
void receivemsg(char *msg, int lenmsg) {
  printf("Received: ");
  printf("%s\n", msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HashStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x400,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    -0x30(%rbp),%eax
  cltq
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x30(%rbp),%eax
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L38:
  cmp    %rdx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L38
L23:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L13
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L13:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  lea    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <SHA1_Init@plt>
  jmp    L41
L43:
  mov    -0x2c(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  lea    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <SHA1_Update@plt>
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x34(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    %eax,-0x54(%rbp)
L41:
  cmpl   $0x0,-0x54(%rbp)
  jle    L31
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jae    L83
  mov    -0x54(%rbp),%eax
  jmp    L29
L83:
  mov    -0x30(%rbp),%eax
L29:
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rdi
  mov    %rdx,%rcx
  mov    %eax,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L43
L31:
  lea    -0x38(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <SHA1_Final@plt>
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int HashStream(FILE *fp, unsigned char *hash, int bytes_to_read) {
  SHA_CTX ctx;
  const int CHUNK_SIZE = 1 * 1024;
  unsigned char chunk[CHUNK_SIZE];
  int bytes_read;
  int total_read = 0;
  SHA1_Init(&ctx);
  while (bytes_to_read > 0 && (bytes_read = fread(chunk, sizeof(char), ((bytes_to_read) < (sizeof(chunk)) ? bytes_to_read : sizeof(chunk)), fp)) != 0) {
    SHA1_Update(&ctx, chunk, bytes_read);
    total_read += bytes_read;
    bytes_to_read -= bytes_read;
  }
  SHA1_Final(hash, &ctx);
  return total_read;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HashStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
L21:
  cmp    %rax,%rsp
  je     L27
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L21
L27:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  mov    %rsp,%r14
  lea    -0x3c(%rbp),%rdi
  call   <SHA1_Init@plt>
  mov    $0x0,%r13d
  mov    $0x400,%r15d
  test   %r12d,%r12d
  jle    L39
L30:
  movslq %r12d,%rax
  cmp    $0x3ff,%rax
  mov    %r15d,%edx
  cmovbe %r12d,%edx
  mov    -0x48(%rbp),%rcx
  mov    $0x1,%esi
  mov    %r14,%rdi
  call   <fread@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L39
  lea    -0x3c(%rbp),%rdi
  mov    %ebx,%edx
  mov    %r14,%rsi
  call   <SHA1_Update@plt>
  add    %ebx,%r13d
  sub    %ebx,%r12d
  test   %r12d,%r12d
  jg     L30
L39:
  lea    -0x3c(%rbp),%rsi
  mov    -0x50(%rbp),%rdi
  call   <SHA1_Final@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    %r13d,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int HashStream(FILE *fp, unsigned char *hash, int bytes_to_read) {
  SHA_CTX ctx;
  const int CHUNK_SIZE = 1 * 1024;
  unsigned char chunk[CHUNK_SIZE];
  int bytes_read;
  int total_read = 0;
  SHA1_Init(&ctx);
  while (bytes_to_read > 0 && (bytes_read = fread(chunk, sizeof(char), ((bytes_to_read) < (sizeof(chunk)) ? bytes_to_read : sizeof(chunk)), fp)) != 0) {
    SHA1_Update(&ctx, chunk, bytes_read);
    total_read += bytes_read;
    bytes_to_read -= bytes_read;
  }
  SHA1_Final(hash, &ctx);
  return total_read;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HashStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L69
L24:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L24
L69:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  xor    %r12d,%r12d
  lea    -0x3c(%rbp),%r14
  mov    %rsp,%rbx
  mov    %r14,%rdi
  call   <SHA1_Init@plt>
  test   %r15d,%r15d
  jg     L29
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  sub    %r13d,%r15d
  call   <SHA1_Update@plt>
  add    %r13d,%r12d
  test   %r15d,%r15d
  jle    L31
L29:
  mov    $0x400,%edx
  mov    -0x48(%rbp),%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  cmp    %edx,%r15d
  cmovle %r15d,%edx
  call   <fread@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jne    L22
L31:
  mov    -0x50(%rbp),%rdi
  mov    %r14,%rsi
  call   <SHA1_Final@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  lea    -0x28(%rbp),%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int HashStream(FILE *fp, unsigned char *hash, int bytes_to_read) {
  SHA_CTX ctx;
  const int CHUNK_SIZE = 1 * 1024;
  unsigned char chunk[CHUNK_SIZE];
  int bytes_read;
  int total_read = 0;
  SHA1_Init(&ctx);
  while (bytes_to_read > 0 && (bytes_read = fread(chunk, sizeof(char), ((bytes_to_read) < (sizeof(chunk)) ? bytes_to_read : sizeof(chunk)), fp)) != 0) {
    SHA1_Update(&ctx, chunk, bytes_read);
    total_read += bytes_read;
    bytes_to_read -= bytes_read;
  }
  SHA1_Final(hash, &ctx);
  return total_read;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HashStream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  mov    %rsp,%rax
  cmp    %rax,%rsp
  je     L51
L60:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rax,%rsp
  jne    L60
L51:
  sub    $0x400,%rsp
  orq    $0x0,0x3f8(%rsp)
  xor    %r12d,%r12d
  lea    -0x3c(%rbp),%r14
  mov    %rsp,%rbx
  mov    %r14,%rdi
  call   <SHA1_Init@plt>
  test   %r15d,%r15d
  jg     L40
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  sub    %r13d,%r15d
  call   <SHA1_Update@plt>
  add    %r13d,%r12d
  test   %r15d,%r15d
  jle    L35
L40:
  mov    $0x400,%edx
  mov    -0x48(%rbp),%rcx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  cmp    %edx,%r15d
  cmovle %r15d,%edx
  call   <fread@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jne    L28
L35:
  mov    -0x50(%rbp),%rdi
  mov    %r14,%rsi
  call   <SHA1_Final@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  lea    -0x28(%rbp),%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int HashStream(FILE *fp, unsigned char *hash, int bytes_to_read) {
  SHA_CTX ctx;
  const int CHUNK_SIZE = 1 * 1024;
  unsigned char chunk[CHUNK_SIZE];
  int bytes_read;
  int total_read = 0;
  SHA1_Init(&ctx);
  while (bytes_to_read > 0 && (bytes_read = fread(chunk, sizeof(char), ((bytes_to_read) < (sizeof(chunk)) ? bytes_to_read : sizeof(chunk)), fp)) != 0) {
    SHA1_Update(&ctx, chunk, bytes_read);
    total_read += bytes_read;
    bytes_to_read -= bytes_read;
  }
  SHA1_Final(hash, &ctx);
  return total_read;
}
```
user: What is the c source code of the assembly code below?

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L27
L19:
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
L27:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L19
  cmpl   $0x0,-0x1c(%rbp)
  je     L13
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rax,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short checksum(unsigned short *buffer, int size) {
  unsigned long cksum = 0;
  while (size > 1) {
    cksum += *buffer++;
    size -= sizeof(unsigned short);
  }
  if (size)
    cksum += *(unsigned char *)buffer;
  cksum = (cksum >> 16) + (cksum & 0xffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```