ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<niggli_reduce>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <initialize@plt>
  mov    $0x0,%eax
  call   <step0@plt>
  mov    $0xa,%ebx
  jmp    L57
L60:
  sub    $0x1,%ebx
  je     L64
L57:
  mov    $0x0,%eax
  call   <step1@plt>
  mov    $0x0,%eax
  call   <step2@plt>
  test   %rax,%rax
  jne    L60
  call   <step3@plt>
  mov    $0x0,%eax
  call   <step4@plt>
  mov    $0x0,%eax
  call   <step5@plt>
  test   %rax,%rax
  jne    L60
  call   <step6@plt>
  test   %rax,%rax
  jne    L60
  call   <step7@plt>
  test   %rax,%rax
  jne    L60
  call   <step8@plt>
  test   %rax,%rax
  jne    L60
L64:
  mov    %rbp,%rdi
  call   <finalize@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void niggli_reduce(double *lattice_, const double eps_) {
  int i;
  initialize(lattice_, eps_);
  step0();
  for (i = 0; i < 10; i++) {
    if (step1()) {
      ;
      ;
      ;
    }
    if (step2()) {
      ;
      ;
      ;
      continue;
    }
    if (step3()) {
      ;
      ;
      ;
    }
    if (step4()) {
      ;
      ;
      ;
    }
    if (step5()) {
      ;
      ;
      ;
      continue;
    }
    if (step6()) {
      ;
      ;
      ;
      continue;
    }
    if (step7()) {
      ;
      ;
      ;
      continue;
    }
    if (step8()) {
      ;
      ;
      ;
      continue;
    }
    break;
  }
  finalize(lattice_);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<niggli_reduce>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  call   <initialize@plt>
  xor    %eax,%eax
  call   <step0@plt>
  xchg   %ax,%ax
L57:
  xor    %eax,%eax
  call   <step1@plt>
  xor    %eax,%eax
  call   <step2@plt>
  test   %rax,%rax
  jne    L36
  xor    %eax,%eax
  call   <step3@plt>
  xor    %eax,%eax
  call   <step4@plt>
  xor    %eax,%eax
  call   <step5@plt>
  test   %rax,%rax
  jne    L36
  call   <step6@plt>
  test   %rax,%rax
  jne    L36
  call   <step7@plt>
  test   %rax,%rax
  je     L35
  nopl   0x0(%rax)
L36:
  sub    $0x1,%ebx
  jne    L57
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1160 <finalize@plt>
  nopl   0x0(%rax,%rax,1)
L35:
  call   <step8@plt>
  test   %rax,%rax
  jne    L36
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1160 <finalize@plt>
```

assistant: ```c
void niggli_reduce(double *lattice_, const double eps_) {
  int i;
  initialize(lattice_, eps_);
  step0();
  for (i = 0; i < 10; i++) {
    if (step1()) {
      ;
      ;
      ;
    }
    if (step2()) {
      ;
      ;
      ;
      continue;
    }
    if (step3()) {
      ;
      ;
      ;
    }
    if (step4()) {
      ;
      ;
      ;
    }
    if (step5()) {
      ;
      ;
      ;
      continue;
    }
    if (step6()) {
      ;
      ;
      ;
      continue;
    }
    if (step7()) {
      ;
      ;
      ;
      continue;
    }
    if (step8()) {
      ;
      ;
      ;
      continue;
    }
    break;
  }
  finalize(lattice_);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<niggli_reduce>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  call   <initialize@plt>
  xor    %eax,%eax
  call   <step0@plt>
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  call   <step1@plt>
  xor    %eax,%eax
  call   <step2@plt>
  test   %rax,%rax
  jne    L40
  xor    %eax,%eax
  call   <step3@plt>
  xor    %eax,%eax
  call   <step4@plt>
  xor    %eax,%eax
  call   <step5@plt>
  test   %rax,%rax
  jne    L40
  call   <step6@plt>
  test   %rax,%rax
  jne    L40
  call   <step7@plt>
  test   %rax,%rax
  je     L12
  nopl   0x0(%rax)
L40:
  sub    $0x1,%ebx
  jne    L0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1160 <finalize@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  call   <step8@plt>
  test   %rax,%rax
  jne    L40
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1160 <finalize@plt>
```

assistant: ```c
void niggli_reduce(double *lattice_, const double eps_) {
  int i;
  initialize(lattice_, eps_);
  step0();
  for (i = 0; i < 10; i++) {
    if (step1()) {
      ;
      ;
      ;
    }
    if (step2()) {
      ;
      ;
      ;
      continue;
    }
    if (step3()) {
      ;
      ;
      ;
    }
    if (step4()) {
      ;
      ;
      ;
    }
    if (step5()) {
      ;
      ;
      ;
      continue;
    }
    if (step6()) {
      ;
      ;
      ;
      continue;
    }
    if (step7()) {
      ;
      ;
      ;
      continue;
    }
    if (step8()) {
      ;
      ;
      ;
      continue;
    }
    break;
  }
  finalize(lattice_);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toStringEUC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_set_buffer@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_shift2euc@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <_replace_buffer@plt>
  leave
  ret
```

assistant: ```c
char *toStringEUC(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _shift2euc((unsigned char *)str, buf);
  return (char *)_replace_buffer(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<toStringEUC>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_set_buffer@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <_shift2euc@plt>
  mov    %rbx,%rdi
  call   <_replace_buffer@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *toStringEUC(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _shift2euc((unsigned char *)str, buf);
  return (char *)_replace_buffer(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<toStringEUC>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_set_buffer@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <_shift2euc@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <_replace_buffer@plt>
```

assistant: ```c
char *toStringEUC(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _shift2euc((unsigned char *)str, buf);
  return (char *)_replace_buffer(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toStringEUC>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_set_buffer@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <_shift2euc@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <_replace_buffer@plt>
```

assistant: ```c
char *toStringEUC(char *str) {
  unsigned char *buf;
  buf = _set_buffer(str);
  _shift2euc((unsigned char *)str, buf);
  return (char *)_replace_buffer(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_cmd_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L1
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: ./

assistant: ```c
char *parse_cmd_args(int argc, char **argv) {
  char *path = "./";
  if (argc > 1) {
    path = argv[1];
  }
  return path;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_cmd_args>:
  endbr64
  lea    D7(%rip),%rax
  cmp    $0x1,%edi
  jle    L7
  mov    0x8(%rsi),%rax
L7:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: ./

assistant: ```c
char *parse_cmd_args(int argc, char **argv) {
  char *path = "./";
  if (argc > 1) {
    path = argv[1];
  }
  return path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_cmd_args>:
  endbr64
  lea    D4(%rip),%rax
  cmp    $0x1,%edi
  jle    L9
  mov    0x8(%rsi),%rax
L9:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: ./

assistant: ```c
char *parse_cmd_args(int argc, char **argv) {
  char *path = "./";
  if (argc > 1) {
    path = argv[1];
  }
  return path;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_cmd_args>:
  endbr64
  lea    D3(%rip),%rax
  cmp    $0x1,%edi
  jle    L8
  mov    0x8(%rsi),%rax
L8:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D3: ./

assistant: ```c
char *parse_cmd_args(int argc, char **argv) {
  char *path = "./";
  if (argc > 1) {
    path = argv[1];
  }
  return path;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ten_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L5:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ten_power(int expon) {
  int i;
  int valOut;
  valOut = 1;
  for (i = 0; i < expon; i++)
    valOut = valOut * 10;
  return valOut;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ten_power>:
  endbr64
  test   %edi,%edi
  jle    L14
  mov    $0x1,%eax
  mov    $0x0,%edx
L0:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L0
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ten_power(int expon) {
  int i;
  int valOut;
  valOut = 1;
  for (i = 0; i < expon; i++)
    valOut = valOut * 10;
  return valOut;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ten_power>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jle    L6
  xor    %edx,%edx
  nop
L19:
  lea    (%rax,%rax,4),%eax
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %edx,%edi
  jne    L19
  ret
  nopl   (%rax)
L6:
  ret
```

assistant: ```c
int ten_power(int expon) {
  int i;
  int valOut;
  valOut = 1;
  for (i = 0; i < expon; i++)
    valOut = valOut * 10;
  return valOut;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ten_power>:
  endbr64
  test   %edi,%edi
  jle    L5
  cmp    $0x1,%edi
  je     L3
  movq   D8(%rip),%xmm0
  mov    %edi,%edx
  xor    %eax,%eax
  shr    %edx
  nopl   0x0(%rax,%rax,1)
L21:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L21
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%edx
  imul   %edx,%eax
  and    $0x1,%edi
  je     L22
L8:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L22:
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x1,%eax
  ret
L3:
  mov    $0x1,%eax
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: byte[8]

tool: {"D8": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int ten_power(int expon) {
  int i;
  int valOut;
  valOut = 1;
  for (i = 0; i < expon; i++)
    valOut = valOut * 10;
  return valOut;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fake_gmtime_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x0,%eax
  jmp    L11
L0:
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
struct tm *fake_gmtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = gmtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fake_gmtime_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <gmtime@plt>
  mov    %rax,%rbx
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L17
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %rbp,%rbx
L6:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  jmp    L6
```

assistant: ```c
struct tm *fake_gmtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = gmtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<fake_gmtime_r>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <gmtime@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    $0x4,%edx
  test   %r12,%r12
  je     L3
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbp,%r12
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct tm *fake_gmtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = gmtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fake_gmtime_r>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <gmtime@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    $0x4,%edx
  test   %r12,%r12
  je     L2
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rbp,%r12
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct tm *fake_gmtime_r(const time_t *time, struct tm *result) {
  const struct tm *static_result = gmtime(time);
  assert(result != NULL);
  if (static_result == NULL) {
    memset(result, 0, sizeof(*result));
    return NULL;
  } else {
    memcpy(result, static_result, sizeof(*result));
    return result;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<pressAnyKeyToContinue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edi
  call   <nnewline@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: Press any key to continue . . .

assistant: ```c
void pressAnyKeyToContinue() {
  nnewline(3);
  printf("Press any key to continue . . .");
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pressAnyKeyToContinue>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <nnewline@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: Press any key to continue . . .

assistant: ```c
void pressAnyKeyToContinue() {
  nnewline(3);
  printf("Press any key to continue . . .");
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<pressAnyKeyToContinue>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <nnewline@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <getchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Press any key to continue . . .

assistant: ```c
void pressAnyKeyToContinue() {
  nnewline(3);
  printf("Press any key to continue . . .");
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pressAnyKeyToContinue>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <nnewline@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <getchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: Press any key to continue . . .

assistant: ```c
void pressAnyKeyToContinue() {
  nnewline(3);
  printf("Press any key to continue . . .");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<polygon_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L6
  mov    $0xffffffff,%eax
  jmp    L36
L6:
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <polygon_area@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L1
  mov    $0x2,%eax
  jmp    L36
L1:
  mov    $0x0,%eax
L36:
  leave
  ret
```

assistant: ```c
int polygon_check(int n, const double *v) {
  double area = 0;
  if (n < 3) {
    return -1;
  }
  area = polygon_area(n, v);
  if (area < 0) {
    return 2;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<polygon_check>:
  endbr64
  cmp    $0x2,%edi
  jle    L7
  sub    $0x8,%rsp
  call   <polygon_area@plt>
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  add    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int polygon_check(int n, const double *v) {
  double area = 0;
  if (n < 3) {
    return -1;
  }
  area = polygon_area(n, v);
  if (area < 0) {
    return 2;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<polygon_check>:
  endbr64
  cmp    $0x2,%edi
  jle    L3
  sub    $0x8,%rsp
  call   <polygon_area@plt>
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  add    $0x8,%rsp
  add    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int polygon_check(int n, const double *v) {
  double area = 0;
  if (n < 3) {
    return -1;
  }
  area = polygon_area(n, v);
  if (area < 0) {
    return 2;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<polygon_check>:
  endbr64
  cmp    $0x2,%edi
  jle    L0
  sub    $0x8,%rsp
  call   <polygon_area@plt>
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  add    $0x8,%rsp
  add    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int polygon_check(int n, const double *v) {
  double area = 0;
  if (n < 3) {
    return -1;
  }
  area = polygon_area(n, v);
  if (area < 0) {
    return 2;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VM_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x140,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L31
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L31:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  lea    -0x120(%rbp),%rax
  mov    %rax,-0x128(%rbp)
  mov    -0x138(%rbp),%rdx
  mov    -0x12c(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x12c(%rbp),%ecx
  mov    -0x138(%rbp),%rdx
  lea    -0x120(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  jmp    L37
L34:
  mov    -0x128(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x128(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <VM_putchar@plt>
L37:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x12c(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void VM_printf(const char *fmt, ...) {
  char buf[100], *p = buf;
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof(buf), fmt, ap);
  while (*p != '\0')
    VM_putchar(*p++);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<VM_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    $0x64,%esi
  call   <vsnprintf@plt>
  movzbl (%rsp),%edi
  test   %dil,%dil
  je     L19
  mov    %rsp,%rbx
L8:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <VM_putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L8
L19:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void VM_printf(const char *fmt, ...) {
  char buf[100], *p = buf;
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof(buf), fmt, ap);
  while (*p != '\0')
    VM_putchar(*p++);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VM_printf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %r12d,%edi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <va_start@plt>
  mov    %rbx,%rdi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    $0x64,%esi
  call   <vsnprintf@plt>
  movsbl (%rsp),%edi
  test   %dil,%dil
  je     L0
  nopl   (%rax)
L1:
  call   <VM_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L0:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x70,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void VM_printf(const char *fmt, ...) {
  char buf[100], *p = buf;
  va_list ap;
  va_start(ap, fmt);
  vsnprintf(buf, sizeof(buf), fmt, ap);
  while (*p != '\0')
    VM_putchar(*p++);
  va_end(ap);
}
```