ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<getMinTransformOp>:
  endbr64
  xor    %eax,%eax
  test   %ecx,%esi
  js     L35
  push   %r15
  lea    0x1(%rcx),%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  test   %esi,%esi
  js     L0
  lea    0x1(%rsi),%eax
  test   %ecx,%ecx
  js     L0
  movslq %esi,%r9
  movslq %ecx,%r15
  imul   $0xfa0,%r9,%rbx
  add    %r8,%rbx
  mov    (%rbx,%r15,4),%eax
  test   %eax,%eax
  js     L29
L0:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  ret
  nopl   0x0(%rax)
L29:
  lea    -0x1(%rsi),%r10d
  lea    -0x1(%rcx),%ecx
  mov    %rdi,%r13
  mov    %rdx,%r14
  mov    %r10d,%esi
  mov    %r10d,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %ecx,0x1c(%rsp)
  call   <getMinTransformOp>
  mov    0x10(%rsp),%r9
  mov    0x1c(%rsp),%ecx
  mov    %ebp,%esi
  mov    %eax,%r11d
  movzbl (%r14,%r15,1),%eax
  mov    0x8(%rsp),%r8
  mov    %r14,%rdx
  cmp    %al,0x0(%r13,%r9,1)
  mov    %r13,%rdi
  setne  %al
  movzbl %al,%eax
  add    %eax,%r11d
  mov    %r11d,0x10(%rsp)
  call   <getMinTransformOp>
  mov    0x8(%rsp),%r8
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    0x18(%rsp),%esi
  mov    %r13,%rdi
  mov    %eax,%ebp
  add    $0x1,%ebp
  call   <getMinTransformOp>
  mov    0x10(%rsp),%r11d
  add    $0x1,%eax
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  mov    %r11d,%eax
  cmp    %r11d,%ebp
  cmovle %ebp,%eax
  mov    %eax,(%rbx,%r15,4)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int getMinTransformOp(char strX[], int indX, char strY[], int indY, int memoTable[][1000]) {
  if (indX < 0 && indY < 0)
    return 0;
  if (indX < 0)
    return indY + 1;
  if (indY < 0)
    return indX + 1;
  if (memoTable[indX][indY] >= 0)
    return memoTable[indX][indY];
  int minOp = 0, op;
  minOp = getMinTransformOp(strX, indX - 1, strY, indY - 1, memoTable);
  if (strX[indX] != strY[indY])
    minOp += 1;
  op = 1 + getMinTransformOp(strX, indX, strY, indY - 1, memoTable);
  if (op < minOp)
    minOp = op;
  op = 1 + getMinTransformOp(strX, indX - 1, strY, indY, memoTable);
  if (op < minOp)
    minOp = op;
  memoTable[indX][indY] = minOp;
  return minOp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getMinTransformOp>:
  endbr64
  xor    %eax,%eax
  test   %ecx,%esi
  js     L4
  push   %r15
  lea    0x1(%rcx),%eax
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  test   %esi,%esi
  js     L36
  lea    0x1(%rsi),%eax
  test   %ecx,%ecx
  js     L36
  movslq %esi,%r9
  movslq %ecx,%r15
  imul   $0xfa0,%r9,%rbx
  add    %r8,%rbx
  mov    (%rbx,%r15,4),%eax
  test   %eax,%eax
  js     L3
L36:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  ret
  nopl   0x0(%rax)
L3:
  lea    -0x1(%rsi),%r10d
  lea    -0x1(%rcx),%ecx
  mov    %rdi,%r13
  mov    %rdx,%r14
  mov    %r10d,%esi
  mov    %r10d,0x18(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %r8,0x8(%rsp)
  mov    %ecx,0x1c(%rsp)
  call   <getMinTransformOp>
  mov    0x10(%rsp),%r9
  mov    0x1c(%rsp),%ecx
  mov    %ebp,%esi
  mov    %eax,%r11d
  movzbl (%r14,%r15,1),%eax
  mov    0x8(%rsp),%r8
  mov    %r14,%rdx
  cmp    %al,0x0(%r13,%r9,1)
  mov    %r13,%rdi
  setne  %al
  movzbl %al,%eax
  add    %eax,%r11d
  mov    %r11d,0x10(%rsp)
  call   <getMinTransformOp>
  mov    0x8(%rsp),%r8
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    0x18(%rsp),%esi
  mov    %r13,%rdi
  mov    %eax,%ebp
  add    $0x1,%ebp
  call   <getMinTransformOp>
  mov    0x10(%rsp),%r11d
  add    $0x1,%eax
  cmp    %eax,%ebp
  cmovg  %eax,%ebp
  mov    %r11d,%eax
  cmp    %r11d,%ebp
  cmovle %ebp,%eax
  mov    %eax,(%rbx,%r15,4)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int getMinTransformOp(char strX[], int indX, char strY[], int indY, int memoTable[][1000]) {
  if (indX < 0 && indY < 0)
    return 0;
  if (indX < 0)
    return indY + 1;
  if (indY < 0)
    return indX + 1;
  if (memoTable[indX][indY] >= 0)
    return memoTable[indX][indY];
  int minOp = 0, op;
  minOp = getMinTransformOp(strX, indX - 1, strY, indY - 1, memoTable);
  if (strX[indX] != strY[indY])
    minOp += 1;
  op = 1 + getMinTransformOp(strX, indX, strY, indY - 1, memoTable);
  if (op < minOp)
    minOp = op;
  op = 1 + getMinTransformOp(strX, indX - 1, strY, indY, memoTable);
  if (op < minOp)
    minOp = op;
  memoTable[indX][indY] = minOp;
  return minOp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nanodelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int nanodelay(int sec, int nsec) {
  struct timespec t;
  t.tv_sec = sec;
  t.tv_nsec = nsec;
  return nanosleep(&t, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nanodelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nanodelay(int sec, int nsec) {
  struct timespec t;
  t.tv_sec = sec;
  t.tv_nsec = nsec;
  return nanosleep(&t, NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<nanodelay>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  mov    %esi,0x4(%rsp)
  xor    %esi,%esi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nanodelay(int sec, int nsec) {
  struct timespec t;
  t.tv_sec = sec;
  t.tv_nsec = nsec;
  return nanosleep(&t, NULL);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nanodelay>:
  endbr64
  sub    $0x18,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rdi
  movq   %xmm0,(%rsp)
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int nanodelay(int sec, int nsec) {
  struct timespec t;
  t.tv_sec = sec;
  t.tv_nsec = nsec;
  return nanosleep(&t, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lzrestore_tek0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    $0x0,%eax
  call   <getnum_s8@plt>
  mov    %eax,-0x18(%rbp)
  mov    $0x2,%edi
  call   <getbc@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x1,%edi
  call   <getbc@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x2,%edi
  call   <getbc@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x2,%edi
  call   <getbc@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x30(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <getnum_l0a@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L35
L90:
  mov    $0x8,%edi
  call   <getbc@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  js     L83
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L90
  jmp    L118
L83:
  nop
L118:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <getnum_l0a@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L46
L68:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <getnum_df@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L5
  mov    $0x0,%eax
  call   <getnum_l1a@plt>
  mov    %eax,-0x20(%rbp)
  jmp    L38
L5:
  mov    $0x0,%eax
  call   <getnum_l1b@plt>
  mov    %eax,-0x20(%rbp)
L38:
  cmpl   $0x0,-0x20(%rbp)
  js     L1
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
L63:
  mov    -0x30(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x30(%rbp)
  subl   $0x1,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L63
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L68
  jmp    L14
L1:
  nop
  jmp    L14
L35:
  nop
  jmp    L58
L46:
  nop
L58:
  mov    -0x30(%rbp),%eax
  leave
  ret
```

assistant: ```c
int lzrestore_tek0(unsigned char *buf, int k, int i, int outlimit) {
  int len, distance, j, z0, z1;
  unsigned int dis_s, l_ofs, method;
  dis_s = getnum_s8();
  l_ofs = getbc(2);
  method = getbc(1);
  z0 = getbc(2);
  z1 = getbc(2);
  i = 0;
  for (;;) {
    j = getnum_l0a(z0);
    if (j < 0)
      break;
    do {
      len = getbc(8);
      if (len < 0)
        break;
      buf[i++] = len;
    } while (--j);
    j = getnum_l0a(z1);
    if (j < 0)
      break;
    do {
      distance = getnum_df(dis_s);
      if (method == 0) {
        len = getnum_l1a();
      } else {
        len = getnum_l1b();
      }
      if (len < 0)
        break;
      len += l_ofs;
      do {
        buf[i] = buf[i + distance];
        i++;
      } while (--len);
    } while (--j);
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lzrestore_tek0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    $0x0,%eax
  call   <getnum_s8@plt>
  mov    %eax,%r14d
  mov    $0x2,%edi
  call   <getbc@plt>
  mov    %eax,0x14(%rsp)
  mov    $0x1,%edi
  call   <getbc@plt>
  mov    %eax,%r13d
  mov    $0x2,%edi
  call   <getbc@plt>
  mov    %eax,0x18(%rsp)
  mov    $0x2,%edi
  call   <getbc@plt>
  mov    %eax,0x1c(%rsp)
  mov    $0x0,%ebp
  lea    0x1(%r12),%rax
  mov    %rax,0x8(%rsp)
L75:
  mov    0x18(%rsp),%edi
  call   <getnum_l0a@plt>
  test   %eax,%eax
  js     L66
  movslq %ebp,%rdx
  lea    (%r12,%rdx,1),%rbx
  add    0x8(%rsp),%rdx
  lea    -0x1(%rax),%eax
  lea    (%rdx,%rax,1),%r15
L2:
  mov    $0x8,%edi
  call   <getbc@plt>
  test   %eax,%eax
  js     L0
  add    $0x1,%ebp
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r15,%rbx
  jne    L2
L0:
  mov    0x1c(%rsp),%edi
  call   <getnum_l0a@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jns    L5
L66:
  mov    %ebp,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  mov    $0x0,%eax
  call   <getnum_l1b@plt>
L42:
  test   %eax,%eax
  js     L75
  add    0x14(%rsp),%eax
  movslq %ebp,%rsi
  lea    (%r12,%rsi,1),%rdx
  add    0x8(%rsp),%rsi
  lea    -0x1(%rax),%ecx
  add    %rcx,%rsi
  movslq %ebx,%rbx
L23:
  movzbl (%rdx,%rbx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L23
  lea    (%rax,%rbp,1),%ebp
  sub    $0x1,%r15d
  je     L75
L5:
  mov    %r14d,%edi
  call   <getnum_df@plt>
  mov    %eax,%ebx
  test   %r13d,%r13d
  jne    L59
  mov    $0x0,%eax
  call   <getnum_l1a@plt>
  jmp    L42
```

assistant: ```c
int lzrestore_tek0(unsigned char *buf, int k, int i, int outlimit) {
  int len, distance, j, z0, z1;
  unsigned int dis_s, l_ofs, method;
  dis_s = getnum_s8();
  l_ofs = getbc(2);
  method = getbc(1);
  z0 = getbc(2);
  z1 = getbc(2);
  i = 0;
  for (;;) {
    j = getnum_l0a(z0);
    if (j < 0)
      break;
    do {
      len = getbc(8);
      if (len < 0)
        break;
      buf[i++] = len;
    } while (--j);
    j = getnum_l0a(z1);
    if (j < 0)
      break;
    do {
      distance = getnum_df(dis_s);
      if (method == 0) {
        len = getnum_l1a();
      } else {
        len = getnum_l1b();
      }
      if (len < 0)
        break;
      len += l_ofs;
      do {
        buf[i] = buf[i + distance];
        i++;
      } while (--len);
    } while (--j);
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lzrestore_tek0>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x1(%r13),%r14
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <getnum_s8@plt>
  mov    $0x2,%edi
  mov    %eax,%r15d
  call   <getbc@plt>
  mov    $0x1,%edi
  mov    %eax,0x4(%rsp)
  call   <getbc@plt>
  mov    $0x2,%edi
  mov    %eax,(%rsp)
  call   <getbc@plt>
  mov    $0x2,%edi
  mov    %eax,0x8(%rsp)
  call   <getbc@plt>
  mov    %eax,0xc(%rsp)
  nopl   (%rax)
L37:
  mov    0x8(%rsp),%edi
  call   <getnum_l0a@plt>
  test   %eax,%eax
  js     L43
  movslq %r12d,%rdx
  sub    $0x1,%eax
  lea    0x0(%r13,%rdx,1),%rbp
  add    %r14,%rdx
  lea    (%rdx,%rax,1),%rbx
  jmp    L44
  nopl   (%rax)
L75:
  mov    %al,0x0(%rbp)
  add    $0x1,%rbp
  add    $0x1,%r12d
  cmp    %rbx,%rbp
  je     L11
L44:
  mov    $0x8,%edi
  call   <getbc@plt>
  test   %eax,%eax
  jns    L75
L11:
  mov    0xc(%rsp),%edi
  call   <getnum_l0a@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L43
  nopl   (%rax)
L45:
  mov    %r15d,%edi
  call   <getnum_df@plt>
  mov    (%rsp),%edx
  movslq %eax,%rbx
  xor    %eax,%eax
  test   %edx,%edx
  jne    L35
  call   <getnum_l1a@plt>
L14:
  test   %eax,%eax
  js     L37
  mov    0x4(%rsp),%edi
  movslq %r12d,%rcx
  lea    0x0(%r13,%rcx,1),%rdx
  add    %r14,%rcx
  lea    -0x1(%rax,%rdi,1),%eax
  mov    %rax,%rsi
  add    %rax,%rcx
  xchg   %ax,%ax
L69:
  movzbl (%rdx,%rbx,1),%eax
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rdx
  jne    L69
  lea    0x1(%r12,%rsi,1),%r12d
  sub    $0x1,%ebp
  jne    L45
  jmp    L37
  nop
L35:
  call   <getnum_l1b@plt>
  jmp    L14
L43:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int lzrestore_tek0(unsigned char *buf, int k, int i, int outlimit) {
  int len, distance, j, z0, z1;
  unsigned int dis_s, l_ofs, method;
  dis_s = getnum_s8();
  l_ofs = getbc(2);
  method = getbc(1);
  z0 = getbc(2);
  z1 = getbc(2);
  i = 0;
  for (;;) {
    j = getnum_l0a(z0);
    if (j < 0)
      break;
    do {
      len = getbc(8);
      if (len < 0)
        break;
      buf[i++] = len;
    } while (--j);
    j = getnum_l0a(z1);
    if (j < 0)
      break;
    do {
      distance = getnum_df(dis_s);
      if (method == 0) {
        len = getnum_l1a();
      } else {
        len = getnum_l1b();
      }
      if (len < 0)
        break;
      len += l_ofs;
      do {
        buf[i] = buf[i + distance];
        i++;
      } while (--len);
    } while (--j);
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm2
  movss  0x14(%rsp),%xmm0
  movaps %xmm1,%xmm3
  addss  %xmm2,%xmm3
  comiss %xmm3,%xmm0
  jae    L10
  movaps %xmm1,%xmm3
  addss  %xmm0,%xmm3
  comiss %xmm3,%xmm2
  jae    L10
  movaps %xmm2,%xmm3
  addss  %xmm0,%xmm3
  comiss %xmm3,%xmm1
  jb     L80
L10:
  lea    D67(%rip),%rdi
  call   <puts@plt>
L65:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L80:
  comiss %xmm2,%xmm1
  jb     L36
  movss  %xmm2,0xc(%rsp)
  movss  %xmm1,0x10(%rsp)
L36:
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  jb     L98
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x14(%rsp)
L98:
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jb     L53
  movss  %xmm1,0x10(%rsp)
  movss  %xmm0,0x14(%rsp)
L53:
  movss  0x14(%rsp),%xmm1
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm2
  mulss  %xmm1,%xmm1
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  addss  %xmm2,%xmm0
  ucomiss %xmm0,%xmm1
  jp     L60
  jne    L60
  lea    D63(%rip),%rdi
  call   <puts@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm0
  mulss  D66(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D6(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L65
L60:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L65
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D67
type_guessed: string
name: disassemble_data
arguments: tag: D63
type_guessed: string
name: disassemble_data
arguments: tag: D66
type_guessed: byte[4]
name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D18
type_guessed: string

tool: D28: Vnesi dolzini na strani: 

tool: D2: %f %f %f

tool: D67: Ne moze da se konstruira triagolnik.

tool: D63: Tragolnikot e pravoagolen.

tool: {"D66": [0x00,0x00,0x00,0x3f]}

tool: D6: Ploshtinata mu e %7.3f


tool: D18: Tragolnikot NE e pravoagolen.

assistant: ```c
int main() {
  float a, b, c;
  printf("Vnesi dolzini na strani: \n");
  scanf("%f %f %f", &a, &b, &c);
  if ((a + b <= c) || (a + c <= b) || (b + c <= a))
    printf("Ne moze da se konstruira triagolnik.\n");
  else {
    if (a >= b) {
      float tmp = a;
      a = b;
      b = tmp;
    }
    if (a >= c) {
      float tmp = a;
      a = c;
      c = tmp;
    }
    if (b >= c) {
      float tmp = b;
      b = c;
      c = tmp;
    }
    if (c * c == a * a + b * b) {
      printf("Tragolnikot e pravoagolen.\n");
      printf("Ploshtinata mu e %7.3f\n", a * b / 2);
    } else {
      printf("Tragolnikot NE e pravoagolen.\n");
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm2
  movss  0x14(%rsp),%xmm1
  movaps %xmm0,%xmm3
  addss  %xmm2,%xmm3
  comiss %xmm3,%xmm1
  jae    L89
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm3,%xmm2
  jb     L107
L89:
  lea    D11(%rip),%rdi
  call   <puts@plt>
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L107:
  movaps %xmm2,%xmm3
  addss  %xmm1,%xmm3
  comiss %xmm3,%xmm0
  jae    L89
  comiss %xmm2,%xmm0
  jb     L49
  movaps %xmm0,%xmm3
  movss  %xmm2,0xc(%rsp)
  movss  %xmm0,0x10(%rsp)
  movaps %xmm2,%xmm0
  movaps %xmm3,%xmm2
L49:
  comiss %xmm1,%xmm0
  jb     L76
  movaps %xmm0,%xmm3
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x14(%rsp)
  movaps %xmm1,%xmm0
  movaps %xmm3,%xmm1
L76:
  comiss %xmm1,%xmm2
  jb     L59
  movaps %xmm2,%xmm3
  movss  %xmm1,0x10(%rsp)
  movss  %xmm2,0x14(%rsp)
  movaps %xmm1,%xmm2
  movaps %xmm3,%xmm1
L59:
  mulss  %xmm0,%xmm0
  mulss  %xmm2,%xmm2
  mulss  %xmm1,%xmm1
  addss  %xmm2,%xmm0
  ucomiss %xmm0,%xmm1
  jp     L100
  jne    L100
  lea    D29(%rip),%rdi
  call   <puts@plt>
  movss  0xc(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm0
  lea    D27(%rip),%rdi
  mulss  D26(%rip),%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L27
L100:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D31
type: string
name: retrieve_data
arguments: data_label: D11
type: string
name: retrieve_data
arguments: data_label: D29
type: string
name: retrieve_data
arguments: data_label: D27
type: string
name: retrieve_data
arguments: data_label: D26
type: byte[4]
name: retrieve_data
arguments: data_label: D22
type: string

tool: D10: Vnesi dolzini na strani: 

tool: D31: %f %f %f

tool: D11: Ne moze da se konstruira triagolnik.

tool: D29: Tragolnikot e pravoagolen.

tool: D27: Ploshtinata mu e %7.3f


tool: {"D26": [0x00,0x00,0x00,0x3f]}

tool: D22: Tragolnikot NE e pravoagolen.

assistant: ```c
int main() {
  float a, b, c;
  printf("Vnesi dolzini na strani: \n");
  scanf("%f %f %f", &a, &b, &c);
  if ((a + b <= c) || (a + c <= b) || (b + c <= a))
    printf("Ne moze da se konstruira triagolnik.\n");
  else {
    if (a >= b) {
      float tmp = a;
      a = b;
      b = tmp;
    }
    if (a >= c) {
      float tmp = a;
      a = c;
      c = tmp;
    }
    if (b >= c) {
      float tmp = b;
      b = c;
      c = tmp;
    }
    if (c * c == a * a + b * b) {
      printf("Tragolnikot e pravoagolen.\n");
      printf("Ploshtinata mu e %7.3f\n", a * b / 2);
    } else {
      printf("Tragolnikot NE e pravoagolen.\n");
    }
  }
  return 0;
}
```