ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<voltea_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L25
L7:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  movl   $0x0,-0x14(%rbp)
L26:
  addl   $0x1,-0x18(%rbp)
  subq   $0x1,-0x10(%rbp)
L25:
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *voltea_string(char *s) {
  char *p;
  p = malloc(strlen(s) + 1);
  int i = 0;
  int flag = 1;
  char *len = s + strlen(s) - 1;
  while (flag) {
    *(p + i) = *len;
    if (*(s + i) == '\0')
      flag = 0;
    i++;
    len--;
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<voltea_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  mov    $0x0,%eax
  jmp    L14
L3:
  sub    $0x1,%rdx
L14:
  movzbl (%rdx),%ecx
  mov    %cl,0x0(%rbp,%rax,1)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L3
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *voltea_string(char *s) {
  char *p;
  p = malloc(strlen(s) + 1);
  int i = 0;
  int flag = 1;
  char *len = s + strlen(s) - 1;
  while (flag) {
    *(p + i) = *len;
    if (*(s + i) == '\0')
      flag = 0;
    i++;
    len--;
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<voltea_string>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  mov    %al,(%r12)
  cmpb   $0x0,(%rbx)
  je     L15
  mov    $0x1,%eax
  xchg   %ax,%ax
L3:
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L3
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *voltea_string(char *s) {
  char *p;
  p = malloc(strlen(s) + 1);
  int i = 0;
  int flag = 1;
  char *len = s + strlen(s) - 1;
  while (flag) {
    *(p + i) = *len;
    if (*(s + i) == '\0')
      flag = 0;
    i++;
    len--;
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<voltea_string>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  mov    %al,(%r12)
  cmpb   $0x0,(%rbx)
  je     L3
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  mov    %cl,(%r12,%rax,1)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rbx,%rax,1)
  jne    L2
L3:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *voltea_string(char *s) {
  char *p;
  p = malloc(strlen(s) + 1);
  int i = 0;
  int flag = 1;
  char *len = s + strlen(s) - 1;
  while (flag) {
    *(p + i) = *len;
    if (*(s + i) == '\0')
      flag = 0;
    i++;
    len--;
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L0
L19:
  mov    -0x18(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   *%rdx
  test   %eax,%eax
  jns    L22
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x18(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <swap@plt>
L22:
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jbe    L19
  mov    -0x10(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x40(%rbp),%rax
  imul   -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <swap@plt>
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t partition(void *base, size_t size, int (*compar)(const void *, const void *), size_t low, size_t high) {
  size_t i, j;
  void *item;
  item = base + low * size;
  j = low;
  for (i = low + 1; i <= high; i++) {
    if (compar(base + i * size, item) < 0) {
      j++;
      swap(base + i * size, base + j * size, size);
    }
  }
  swap(base + low * size, base + j * size, size);
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<partition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r12
  mov    %rcx,%rbx
  imul   %rsi,%rbx
  lea    (%rdi,%rbx,1),%r15
  lea    0x1(%rcx),%rbp
  cmp    %r8,%rbp
  ja     L24
  mov    %rdx,%r14
  mov    %r8,%r13
  add    %rsi,%rbx
  add    %rdi,%rbx
  mov    %rcx,(%rsp)
  jmp    L35
L46:
  add    $0x1,%rbp
  add    %r12,%rbx
  cmp    %rbp,%r13
  jb     L22
L35:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   *%r14
  test   %eax,%eax
  jns    L46
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  mov    %rax,%rsi
  imul   %r12,%rsi
  add    0x8(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L46
L24:
  mov    %rcx,(%rsp)
L22:
  mov    (%rsp),%rbx
  mov    %rbx,%rax
  imul   %r12,%rax
  mov    0x8(%rsp),%rsi
  add    %rax,%rsi
  mov    %r12,%rdx
  mov    %r15,%rdi
  call   <swap@plt>
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
size_t partition(void *base, size_t size, int (*compar)(const void *, const void *), size_t low, size_t high) {
  size_t i, j;
  void *item;
  item = base + low * size;
  j = low;
  for (i = low + 1; i <= high; i++) {
    if (compar(base + i * size, item) < 0) {
      j++;
      swap(base + i * size, base + j * size, size);
    }
  }
  swap(base + low * size, base + j * size, size);
  return j;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<partition>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rcx,%rdi
  imul   %rsi,%rdi
  mov    %r8,(%rsp)
  lea    (%rax,%rdi,1),%r14
  cmp    %r8,%rbx
  ja     L10
  add    %rsi,%rdi
  mov    %rdx,%rbp
  lea    (%rax,%rdi,1),%r15
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rbx
  add    %r12,%r15
  cmp    %rbx,(%rsp)
  jb     L13
L18:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   *%rbp
  test   %eax,%eax
  jns    L6
  add    $0x1,%r13
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %r12,%rdx
  imul   %r13,%rsi
  add    0x8(%rsp),%rsi
  add    $0x1,%rbx
  add    %r12,%r15
  call   <swap@plt>
  cmp    %rbx,(%rsp)
  jae    L18
L13:
  mov    %r13,%rax
  mov    0x8(%rsp),%rsi
  imul   %r12,%rax
  add    %rax,%rsi
L3:
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <swap@plt>
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L10:
  mov    %r14,%rsi
  jmp    L3
```

assistant: ```c
size_t partition(void *base, size_t size, int (*compar)(const void *, const void *), size_t low, size_t high) {
  size_t i, j;
  void *item;
  item = base + low * size;
  j = low;
  for (i = low + 1; i <= high; i++) {
    if (compar(base + i * size, item) < 0) {
      j++;
      swap(base + i * size, base + j * size, size);
    }
  }
  swap(base + low * size, base + j * size, size);
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partition>:
  endbr64
  push   %r15
  mov    %rdi,%rax
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  lea    0x1(%rcx),%rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rcx,%rdi
  imul   %rsi,%rdi
  mov    %r8,(%rsp)
  lea    (%rax,%rdi,1),%r14
  cmp    %r8,%rbx
  ja     L4
  add    %rsi,%rdi
  mov    %rdx,%rbp
  lea    (%rax,%rdi,1),%r15
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rbx
  add    %r12,%r15
  cmp    %rbx,(%rsp)
  jb     L7
L15:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   *%rbp
  test   %eax,%eax
  jns    L22
  add    $0x1,%r13
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    %r12,%rdx
  imul   %r13,%rsi
  add    0x8(%rsp),%rsi
  add    $0x1,%rbx
  add    %r12,%r15
  call   <swap@plt>
  cmp    %rbx,(%rsp)
  jae    L15
L7:
  mov    %r13,%rax
  mov    0x8(%rsp),%rsi
  imul   %r12,%rax
  add    %rax,%rsi
L29:
  mov    %r12,%rdx
  mov    %r14,%rdi
  call   <swap@plt>
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L4:
  mov    %r14,%rsi
  jmp    L29
```

assistant: ```c
size_t partition(void *base, size_t size, int (*compar)(const void *, const void *), size_t low, size_t high) {
  size_t i, j;
  void *item;
  item = base + low * size;
  j = low;
  for (i = low + 1; i <= high; i++) {
    if (compar(base + i * size, item) < 0) {
      j++;
      swap(base + i * size, base + j * size, size);
    }
  }
  swap(base + low * size, base + j * size, size);
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4150(%rbp),%rax
  mov    $0x4141,%edx
  mov    %rax,%rsi
  mov    $0x4242,%edi
  call   <read@plt>
  lea    -0x4150(%rbp),%rdx
  mov    $0x0,%eax
  call   *%rdx
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void main() {
  char buf[0x4141];
  read(0x4242, buf, 0x4141);
  ((void (*)())buf)();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  lea    -0x4000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x4141,%edx
  mov    %rbx,%rsi
  mov    $0x4242,%edi
  call   <read@plt>
  mov    $0x0,%eax
  call   *%rbx
  mov    0x4148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x4150,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char buf[0x4141];
  read(0x4242, buf, 0x4141);
  ((void (*)())buf)();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    -0x4000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x150,%rsp
  mov    $0x4141,%edx
  mov    $0x4242,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x4148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <read@plt>
  xor    %eax,%eax
  call   *%rbx
  mov    0x4148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x4150,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char buf[0x4141];
  read(0x4242, buf, 0x4141);
  ((void (*)())buf)();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    -0x4000(%rsp),%r11
L15:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L15
  sub    $0x150,%rsp
  mov    $0x4141,%edx
  mov    $0x4242,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x4148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <read@plt>
  xor    %eax,%eax
  call   *%rbx
  mov    0x4148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x4150,%rsp
  pop    %rbx
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char buf[0x4141];
  read(0x4242, buf, 0x4141);
  ((void (*)())buf)();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<acu_malloc_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc_t@plt>
  mov    %rax,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <acu_new_unique@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *acu_malloc_t(size_t s) {
  void *p = malloc_t(s);
  (void)acu_new_unique(p, free);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<acu_malloc_t>:
  endbr64
  push   %rbx
  call   <malloc_t@plt>
  mov    %rax,%rbx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <acu_new_unique@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *acu_malloc_t(size_t s) {
  void *p = malloc_t(s);
  (void)acu_new_unique(p, free);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<acu_malloc_t>:
  endbr64
  push   %r12
  call   <malloc_t@plt>
  mov    %rax,%r12
  mov    D9(%rip),%rax
  mov    %r12,%rdi
  mov    (%rax),%esi
  call   <acu_new_unique@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *acu_malloc_t(size_t s) {
  void *p = malloc_t(s);
  (void)acu_new_unique(p, free);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<acu_malloc_t>:
  endbr64
  push   %r12
  call   <malloc_t@plt>
  mov    %rax,%r12
  mov    D2(%rip),%rax
  mov    %r12,%rdi
  mov    (%rax),%esi
  call   <acu_new_unique@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *acu_malloc_t(size_t s) {
  void *p = malloc_t(s);
  (void)acu_new_unique(p, free);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Warning>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <MapErrorWindow@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <PrintErrorMessage@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: W A R N I N G

assistant: ```c
void Warning(char *msg) {
  MapErrorWindow("W A R N I N G");
  (void)PrintErrorMessage(msg);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Warning>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  call   <MapErrorWindow@plt>
  mov    %rbx,%rdi
  call   <PrintErrorMessage@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: W A R N I N G

assistant: ```c
void Warning(char *msg) {
  MapErrorWindow("W A R N I N G");
  (void)PrintErrorMessage(msg);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Warning>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <MapErrorWindow@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <PrintErrorMessage@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: W A R N I N G

assistant: ```c
void Warning(char *msg) {
  MapErrorWindow("W A R N I N G");
  (void)PrintErrorMessage(msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Warning>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  call   <MapErrorWindow@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <PrintErrorMessage@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: W A R N I N G

assistant: ```c
void Warning(char *msg) {
  MapErrorWindow("W A R N I N G");
  (void)PrintErrorMessage(msg);
}
```
user: What is the c source code of the assembly code below?

```asm
<write_ec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    $0x66,%esi
  mov    $0x81,%edi
  call   <outb@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x62,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    -0x8(%rbp),%eax
  mov    $0x62,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  nop
  leave
  ret
```

assistant: ```c
void write_ec(const uint32_t port, const uint8_t value) {
  wait_ec(0x66, 1, 0);
  outb(0x81, 0x66);
  wait_ec(0x66, 1, 0);
  outb(port, 0x62);
  wait_ec(0x66, 1, 0);
  outb(value, 0x62);
  wait_ec(0x66, 1, 0);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_ec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    $0x66,%esi
  mov    $0x81,%edi
  call   <outb@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    $0x62,%esi
  mov    %ebp,%edi
  call   <outb@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    $0x62,%esi
  mov    %ebx,%edi
  call   <outb@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_ec(const uint32_t port, const uint8_t value) {
  wait_ec(0x66, 1, 0);
  outb(0x81, 0x66);
  wait_ec(0x66, 1, 0);
  outb(port, 0x62);
  wait_ec(0x66, 1, 0);
  outb(value, 0x62);
  wait_ec(0x66, 1, 0);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_ec>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %edi,%r12d
  mov    $0x66,%edi
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <wait_ec@plt>
  mov    $0x66,%esi
  mov    $0x81,%edi
  call   <outb@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    %r12d,%edi
  mov    $0x62,%esi
  call   <outb@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    %ebp,%edi
  mov    $0x62,%esi
  call   <outb@plt>
  add    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  pop    %rbp
  mov    $0x66,%edi
  pop    %r12
  jmp    1070 <wait_ec@plt>
```

assistant: ```c
void write_ec(const uint32_t port, const uint8_t value) {
  wait_ec(0x66, 1, 0);
  outb(0x81, 0x66);
  wait_ec(0x66, 1, 0);
  outb(port, 0x62);
  wait_ec(0x66, 1, 0);
  outb(value, 0x62);
  wait_ec(0x66, 1, 0);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_ec>:
  endbr64
  push   %r12
  xor    %edx,%edx
  mov    %edi,%r12d
  mov    $0x66,%edi
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <wait_ec@plt>
  mov    $0x66,%esi
  mov    $0x81,%edi
  call   <outb@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    %r12d,%edi
  mov    $0x62,%esi
  call   <outb@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x66,%edi
  call   <wait_ec@plt>
  mov    %ebp,%edi
  mov    $0x62,%esi
  call   <outb@plt>
  add    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  pop    %rbp
  mov    $0x66,%edi
  pop    %r12
  jmp    1070 <wait_ec@plt>
```

assistant: ```c
void write_ec(const uint32_t port, const uint8_t value) {
  wait_ec(0x66, 1, 0);
  outb(0x81, 0x66);
  wait_ec(0x66, 1, 0);
  outb(port, 0x62);
  wait_ec(0x66, 1, 0);
  outb(value, 0x62);
  wait_ec(0x66, 1, 0);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b_smp_enqueue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  call   *0x100030
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long b_smp_enqueue(void *ptr, unsigned long var) {
  unsigned long tlong;
  asm volatile("call *0x00100030" : "=a"(tlong) : "a"(ptr), "S"(var));
  return tlong;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<b_smp_enqueue>:
  endbr64
  mov    %rdi,%rax
  call   *0x100030
  ret
```

assistant: ```c
unsigned long b_smp_enqueue(void *ptr, unsigned long var) {
  unsigned long tlong;
  asm volatile("call *0x00100030" : "=a"(tlong) : "a"(ptr), "S"(var));
  return tlong;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<b_smp_enqueue>:
  endbr64
  mov    %rdi,%rax
  call   *0x100030
  ret
```

assistant: ```c
unsigned long b_smp_enqueue(void *ptr, unsigned long var) {
  unsigned long tlong;
  asm volatile("call *0x00100030" : "=a"(tlong) : "a"(ptr), "S"(var));
  return tlong;
}
```
user: What is the c source code of the assembly code below?

```asm
<b_smp_enqueue>:
  endbr64
  mov    %rdi,%rax
  call   *0x100030
  ret
```

assistant: ```c
unsigned long b_smp_enqueue(void *ptr, unsigned long var) {
  unsigned long tlong;
  asm volatile("call *0x00100030" : "=a"(tlong) : "a"(ptr), "S"(var));
  return tlong;
}
```