ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<password_cache_save>:
  endbr64
  ret
```

assistant: ```c
void password_cache_save(const char *keygrip, const char *password) {
  (void)keygrip;
  (void)password;
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<msr_encode_float32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L80
  mov    $0x0,%eax
  jmp    L86
L80:
  cmpq   $0x0,-0x18(%rbp)
  je     L89
  cmpq   $0x0,-0x28(%rbp)
  je     L89
  cmpl   $0x0,-0x20(%rbp)
  jg     L29
L89:
  mov    $0xffffffff,%eax
  jmp    L86
L29:
  movl   $0x0,-0x4(%rbp)
  jmp    L77
L42:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  cmpl   $0x0,-0x2c(%rbp)
  je     L44
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <ms_gswap4a@plt>
L44:
  mov    -0x20(%rbp),%eax
  sub    $0x4,%eax
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x4(%rbp)
L77:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L33
  cmpl   $0x3,-0x20(%rbp)
  jg     L42
L33:
  cmpl   $0x0,-0x20(%rbp)
  je     L52
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
L52:
  mov    -0x4(%rbp),%eax
L86:
  leave
  ret
```

assistant: ```c
int msr_encode_float32(float *input, int samplecount, float *output, int outputlength, int swapflag) {
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(float); idx++) {
    output[idx] = input[idx];
    if (swapflag)
      ms_gswap4a(&output[idx]);
    outputlength -= sizeof(float);
  }
  if (outputlength)
    memset(&output[idx], 0, outputlength);
  return idx;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<msr_encode_float32>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  test   %esi,%esi
  jle    L76
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %rdx,%r12
  mov    %ecx,%ebp
  mov    %r8d,%r15d
  test   %rdx,%rdx
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L40
  test   %rdi,%rdi
  je     L40
  cmp    $0x3,%ecx
  jle    L83
  mov    $0x1,%ebx
  jmp    L28
L78:
  sub    $0x4,%ebp
  mov    %ebx,0x4(%rsp)
  cmp    %ebx,%r13d
  setg   %dl
  cmp    $0x3,%ebp
  setg   %al
  add    $0x1,%rbx
  add    $0x4,%r12
  test   %al,%dl
  je     L13
L28:
  movss  -0x4(%r14,%rbx,4),%xmm0
  movss  %xmm0,(%r12)
  test   %r15d,%r15d
  je     L78
  mov    %r12,%rdi
  call   <ms_gswap4a@plt>
  jmp    L78
L13:
  test   %ebp,%ebp
  jne    L81
L76:
  mov    0x4(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L83:
  movl   $0x0,0x4(%rsp)
L81:
  movslq 0x4(%rsp),%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,4),%rdi
  mov    %ebp,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  jmp    L76
L40:
  movl   $0xffffffff,0x4(%rsp)
  jmp    L76
```

assistant: ```c
int msr_encode_float32(float *input, int samplecount, float *output, int outputlength, int swapflag) {
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(float); idx++) {
    output[idx] = input[idx];
    if (swapflag)
      ms_gswap4a(&output[idx]);
    outputlength -= sizeof(float);
  }
  if (outputlength)
    memset(&output[idx], 0, outputlength);
  return idx;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<msr_encode_float32>:
  endbr64
  push   %r15
  xor    %r9d,%r9d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  test   %esi,%esi
  jle    L85
  test   %rdx,%rdx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L64
  mov    %rdi,%r15
  test   %rdi,%rdi
  je     L64
  cmp    $0x3,%ecx
  jle    L56
  mov    %esi,%r14d
  mov    %r8d,%r13d
  mov    $0x1,%ebx
  jmp    L105
  nopl   0x0(%rax)
L101:
  sub    $0x4,%r12d
  cmp    %ebx,%r14d
  mov    %ebx,%r9d
  setg   %dl
  cmp    $0x3,%r12d
  setg   %al
  add    $0x1,%rbx
  add    $0x4,%rbp
  test   %al,%dl
  je     L44
L105:
  movss  -0x4(%r15,%rbx,4),%xmm0
  movss  %xmm0,0x0(%rbp)
  test   %r13d,%r13d
  je     L101
  mov    %rbp,%rdi
  call   <ms_gswap4a@plt>
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L44:
  test   %r12d,%r12d
  jne    L102
L85:
  add    $0x18,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L102:
  mov    (%rsp),%rcx
  movslq %r9d,%rax
  lea    (%rcx,%rax,4),%rax
  mov    %rax,(%rsp)
L56:
  mov    (%rsp),%rdi
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %r9d,0xc(%rsp)
  call   <memset@plt>
  mov    0xc(%rsp),%r9d
  jmp    L85
L64:
  mov    $0xffffffff,%r9d
  jmp    L85
```

assistant: ```c
int msr_encode_float32(float *input, int samplecount, float *output, int outputlength, int swapflag) {
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(float); idx++) {
    output[idx] = input[idx];
    if (swapflag)
      ms_gswap4a(&output[idx]);
    outputlength -= sizeof(float);
  }
  if (outputlength)
    memset(&output[idx], 0, outputlength);
  return idx;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<msr_encode_float32>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L42
  test   %rdx,%rdx
  mov    %rdx,%r14
  mov    %ecx,%r12d
  sete   %al
  test   %ecx,%ecx
  setle  %dl
  or     %dl,%al
  jne    L77
  mov    %rdi,%r13
  test   %rdi,%rdi
  je     L77
  cmp    $0x3,%ecx
  jle    L61
  mov    %esi,%ebp
  test   %r8d,%r8d
  jne    L23
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L29:
  sub    $0x4,%r12d
  cmp    %eax,%ebp
  movss  -0x4(%r13,%rax,4),%xmm0
  mov    %eax,%r15d
  setg   %cl
  cmp    $0x3,%r12d
  setg   %dl
  movss  %xmm0,-0x4(%r14,%rax,4)
  add    $0x1,%rax
  test   %dl,%cl
  jne    L29
  test   %r12d,%r12d
  jne    L49
L42:
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r14,%rdx
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rdx,%rdi
  mov    %rdx,0x8(%rsp)
  sub    $0x4,%r12d
  mov    %ebx,%r15d
  movss  -0x4(%r13,%rbx,4),%xmm0
  movss  %xmm0,(%rdx)
  call   <ms_gswap4a@plt>
  cmp    %ebx,%ebp
  mov    0x8(%rsp),%rdx
  setg   %cl
  cmp    $0x3,%r12d
  setg   %al
  add    $0x1,%rbx
  add    $0x4,%rdx
  test   %al,%cl
  jne    L18
  test   %r12d,%r12d
  je     L42
L49:
  movslq %r15d,%rax
  lea    (%r14,%rax,4),%r14
L61:
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  jmp    L42
L77:
  mov    $0xffffffff,%r15d
  jmp    L42
```

assistant: ```c
int msr_encode_float32(float *input, int samplecount, float *output, int outputlength, int swapflag) {
  int idx;
  if (samplecount <= 0)
    return 0;
  if (!input || !output || outputlength <= 0)
    return -1;
  for (idx = 0; idx < samplecount && outputlength >= (int)sizeof(float); idx++) {
    output[idx] = input[idx];
    if (swapflag)
      ms_gswap4a(&output[idx]);
    outputlength -= sizeof(float);
  }
  if (outputlength)
    memset(&output[idx], 0, outputlength);
  return idx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_spawn_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L198
  mov    $0x0,%eax
  jmp    L116
L198:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L173
  mov    $0x0,%eax
  jmp    L116
L173:
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L24:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  addl   $0x1,-0x14(%rbp)
  jmp    L30
L39:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L24
  addl   $0x1,-0x14(%rbp)
  jmp    L160
L140:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
L160:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L140
L11:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  jmp    L30
L31:
  nop
L30:
  mov    -0x14(%rbp),%eax
  add    $0x8,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L61
L23:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
L189:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L189
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L35
L164:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
L35:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L164
  jmp    L144
L16:
  nop
L144:
  addl   $0x1,-0x18(%rbp)
L61:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L116:
  leave
  ret
```

assistant: ```c
char **parse_spawn_command(char *cmdline) {
  char **argv;
  char *p = cmdline;
  int i, argc = 0;
  if (p == NULL)
    return NULL;
  if (*p == '\0')
    return NULL;
  argc = 0;
  while (*p != '\0') {
    while (!isspace(*p)) {
      p++;
      if (*p == '\0') {
        argc++;
        goto END_OF_LINE;
      }
    }
    argc++;
    while (isspace(*p)) {
      p++;
      if (*p == '\0')
        goto END_OF_LINE;
    }
  }
END_OF_LINE:
  argv = malloc(argc + 1 * sizeof(argv[0]));
  for (p = cmdline, i = 0; i < argc; i++) {
    argv[i] = p;
    while (!isspace(*(++p)))
      ;
    p[0] = '\0';
    while (isspace(*(++p)))
      if (p[0] == '\0')
        break;
  }
  argv[argc] = NULL;
  return argv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_spawn_command>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L101
  cmpb   $0x0,(%rdi)
  je     L121
  mov    %rdi,%rbp
  mov    $0x0,%r12d
L140:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L143
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L140
  add    $0x1,%r12d
L29:
  lea    0x8(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L73
  mov    %rax,%rbp
  lea    -0x1(%r12),%eax
  lea    0x8(%r14,%rax,8),%r13
  jmp    L172
L143:
  add    $0x1,%r12d
L92:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L14
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L92
  jmp    L29
L14:
  cmpb   $0x0,0x0(%rbp)
  jne    L140
  jmp    L29
L177:
  add    $0x8,%rbp
  cmp    %r13,%rbp
  je     L73
L172:
  mov    %rbx,0x0(%rbp)
L100:
  add    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L100
  movb   $0x0,(%rbx)
L4:
  add    $0x1,%rbx
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L177
  cmpb   $0x0,(%rbx)
  jne    L4
  jmp    L177
L73:
  movslq %r12d,%r12
  movq   $0x0,(%r14,%r12,8)
L31:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L101:
  mov    %rdi,%r14
  jmp    L31
L121:
  mov    $0x0,%r14d
  jmp    L31
```

assistant: ```c
char **parse_spawn_command(char *cmdline) {
  char **argv;
  char *p = cmdline;
  int i, argc = 0;
  if (p == NULL)
    return NULL;
  if (*p == '\0')
    return NULL;
  argc = 0;
  while (*p != '\0') {
    while (!isspace(*p)) {
      p++;
      if (*p == '\0') {
        argc++;
        goto END_OF_LINE;
      }
    }
    argc++;
    while (isspace(*p)) {
      p++;
      if (*p == '\0')
        goto END_OF_LINE;
    }
  }
END_OF_LINE:
  argv = malloc(argc + 1 * sizeof(argv[0]));
  for (p = cmdline, i = 0; i < argc; i++) {
    argv[i] = p;
    while (!isspace(*(++p)))
      ;
    p[0] = '\0';
    while (isspace(*(++p)))
      if (p[0] == '\0')
        break;
  }
  argv[argc] = NULL;
  return argv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_spawn_command>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L33
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L33
  mov    %rbx,%rbp
  xor    %r13d,%r13d
  jmp    L49
  nopl   0x0(%rax)
L130:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L102
L49:
  call   <isspace@plt>
  test   %rax,%rax
  je     L130
  movsbl 0x0(%rbp),%edi
  add    $0x1,%r13d
  jmp    L28
  nopl   (%rax)
L56:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L21
L28:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L49
  nopl   0x0(%rax,%rax,1)
L21:
  lea    0x8(%r13),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rbp
  lea    -0x1(%r13),%eax
  lea    0x8(%r14,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L148:
  mov    %rbx,0x0(%rbp)
  nopl   0x0(%rax)
L45:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  je     L45
  movb   $0x0,(%rbx)
  jmp    L128
  nop
L101:
  cmpb   $0x0,(%rbx)
  je     L2
L128:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L101
L2:
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L148
  movslq %r13d,%r13
  mov    %r14,%rax
  movq   $0x0,(%r14,%r13,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L102:
  add    $0x1,%r13d
  jmp    L21
L33:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **parse_spawn_command(char *cmdline) {
  char **argv;
  char *p = cmdline;
  int i, argc = 0;
  if (p == NULL)
    return NULL;
  if (*p == '\0')
    return NULL;
  argc = 0;
  while (*p != '\0') {
    while (!isspace(*p)) {
      p++;
      if (*p == '\0') {
        argc++;
        goto END_OF_LINE;
      }
    }
    argc++;
    while (isspace(*p)) {
      p++;
      if (*p == '\0')
        goto END_OF_LINE;
    }
  }
END_OF_LINE:
  argv = malloc(argc + 1 * sizeof(argv[0]));
  for (p = cmdline, i = 0; i < argc; i++) {
    argv[i] = p;
    while (!isspace(*(++p)))
      ;
    p[0] = '\0';
    while (isspace(*(++p)))
      if (p[0] == '\0')
        break;
  }
  argv[argc] = NULL;
  return argv;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse_spawn_command>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L48
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  je     L48
  mov    %rdi,%rbp
  xor    %r13d,%r13d
  jmp    L90
  nopl   0x0(%rax)
L119:
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  je     L100
L90:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L119
  add    $0x1,%r13d
  jmp    L139
  nopw   0x0(%rax,%rax,1)
L142:
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  je     L128
L139:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L142
  cmpb   $0x0,0x0(%rbp)
  jne    L90
  cs nopw 0x0(%rax,%rax,1)
L128:
  lea    0x8(%r13),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rbp
  lea    -0x1(%r13),%eax
  lea    0x8(%r14,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbx,0x0(%rbp)
  nopl   0x0(%rax)
L83:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  je     L83
  movb   $0x0,(%rbx)
  jmp    L21
  nop
L45:
  cmpb   $0x0,(%rbx)
  je     L15
L21:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L45
L15:
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L14
  movslq %r13d,%r13
  mov    %r14,%rax
  movq   $0x0,(%r14,%r13,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L100:
  add    $0x1,%r13d
  jmp    L128
L48:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char **parse_spawn_command(char *cmdline) {
  char **argv;
  char *p = cmdline;
  int i, argc = 0;
  if (p == NULL)
    return NULL;
  if (*p == '\0')
    return NULL;
  argc = 0;
  while (*p != '\0') {
    while (!isspace(*p)) {
      p++;
      if (*p == '\0') {
        argc++;
        goto END_OF_LINE;
      }
    }
    argc++;
    while (isspace(*p)) {
      p++;
      if (*p == '\0')
        goto END_OF_LINE;
    }
  }
END_OF_LINE:
  argv = malloc(argc + 1 * sizeof(argv[0]));
  for (p = cmdline, i = 0; i < argc; i++) {
    argv[i] = p;
    while (!isspace(*(++p)))
      ;
    p[0] = '\0';
    while (isspace(*(++p)))
      if (p[0] == '\0')
        break;
  }
  argv[argc] = NULL;
  return argv;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L21
  mov    $0x1,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L21:
  movl   $0x0,-0x14(%rbp)
  jmp    L57
L52:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %ax,-0x16(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzwl -0x16(%rbp),%edx
  mov    %dx,-0xc(%rbp,%rax,2)
  addl   $0x1,-0x14(%rbp)
L57:
  cmpl   $0x0,-0x14(%rbp)
  jle    L52
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzwl -0xa(%rbp),%eax
  cmp    $0x711,%ax
  jne    L60
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L60:
  movl   $0x0,-0x10(%rbp)
  jmp    L14
L62:
  mov    -0x10(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L14:
  cmpl   $0x0,-0x10(%rbp)
  jle    L62
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D1: Call this program with %i arguments


tool: D10: You win!

tool: D4: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1809) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L6
L9:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %ax,0x4(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpw   $0x711,0x6(%rsp)
  je     L25
L13:
  movzwl 0x6(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L9
L25:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L13
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D3: %u


tool: D7: Call this program with %i arguments


tool: D6: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 1809) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```