ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<strnlen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  const char *p = (const char *)memchr(s, 0, maxlen);
  return p ? p - s : maxlen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strnlen>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  cmovne %rdx,%r12
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t strnlen(const char *s, size_t maxlen) {
  const char *p = (const char *)memchr(s, 0, maxlen);
  return p ? p - s : maxlen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jdns_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <jdns_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *jdns_strdup(const char *s) {
  char *p;
  int len;
  len = strlen(s) + 1;
  p = (char *)jdns_alloc(len);
  memcpy(p, s, len);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jdns_strdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r12d
  mov    %r12d,%edi
  call   <jdns_alloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *jdns_strdup(const char *s) {
  char *p;
  int len;
  len = strlen(s) + 1;
  p = (char *)jdns_alloc(len);
  memcpy(p, s, len);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jdns_strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <jdns_alloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *jdns_strdup(const char *s) {
  char *p;
  int len;
  len = strlen(s) + 1;
  p = (char *)jdns_alloc(len);
  memcpy(p, s, len);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jdns_strdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  mov    %r13d,%edi
  call   <jdns_alloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *jdns_strdup(const char *s) {
  char *p;
  int len;
  len = strlen(s) + 1;
  p = (char *)jdns_alloc(len);
  memcpy(p, s, len);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<crunch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  jmp    L26
L5:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L9:
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L9
L26:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void crunch(int usecs) {
  int i;
  while (usecs-- > 0) {
    for (i = 0; i < 1000; i++)
      ;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crunch>:
  endbr64
  lea    -0x1(%rdi),%edx
  test   %edi,%edi
  jle    L13
L26:
  mov    $0x3e8,%eax
L27:
  sub    $0x1,%eax
  jne    L27
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  jne    L26
  ret
L13:
  ret
```

assistant: ```c
void crunch(int usecs) {
  int i;
  while (usecs-- > 0) {
    for (i = 0; i < 1000; i++)
      ;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crunch>:
  endbr64
  ret
```

assistant: ```c
void crunch(int usecs) {
  int i;
  while (usecs-- > 0) {
    for (i = 0; i < 1000; i++)
      ;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crunch>:
  endbr64
  ret
```

assistant: ```c
void crunch(int usecs) {
  int i;
  while (usecs-- > 0) {
    for (i = 0; i < 1000; i++)
      ;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_basic_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L59:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D1(%rip),%rax
  mov    (%rdx,%rax,1),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L5
  mov    $0x0,%eax
  jmp    L34
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L28
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L63
  mov    $0x1,%eax
  jmp    L34
L28:
  nop
L63:
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    $0x8,%eax
  jbe    L59
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int is_basic_type(char *s) {
  static char *keywds[] = {
      "char", "double", "enum", "extern", "float", "int", "long", "short", "static",
  };
  int j, s0 = s[0], k0;
  char *k;
  for (j = 0; j < sizeof(keywds) / sizeof(char *); ++j) {
    k = keywds[j];
    k0 = k[0];
    if (k0 > s0)
      return 0;
    if (k0 < s0)
      continue;
    if (strcmp(s, k) == 0)
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_basic_type>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  movsbl (%rdi),%ebp
  lea    D6(%rip),%rbx
  lea    0x48(%rbx),%r13
  jmp    L37
L10:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L18
L37:
  mov    (%rbx),%rsi
  movsbl (%rsi),%eax
  cmp    %eax,%ebp
  jl     L21
  jg     L10
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x1,%eax
  jmp    L42
L18:
  mov    $0x0,%eax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  mov    $0x0,%eax
  jmp    L42
```

assistant: ```c
int is_basic_type(char *s) {
  static char *keywds[] = {
      "char", "double", "enum", "extern", "float", "int", "long", "short", "static",
  };
  int j, s0 = s[0], k0;
  char *k;
  for (j = 0; j < sizeof(keywds) / sizeof(char *); ++j) {
    k = keywds[j];
    k0 = k[0];
    if (k0 > s0)
      return 0;
    if (k0 < s0)
      continue;
    if (strcmp(s, k) == 0)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_basic_type>:
  endbr64
  push   %r13
  mov    $0x63,%eax
  mov    %rdi,%r13
  lea    D10(%rip),%rsi
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  lea    0x40(%rbx),%r12
  sub    $0x8,%rsp
  movsbl (%rdi),%ebp
  jmp    L6
  nopl   (%rax)
L35:
  mov    (%rbx),%rsi
  add    $0x8,%rbx
  movsbl (%rsi),%eax
L6:
  cmp    %eax,%ebp
  jl     L30
  jg     L25
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L26
L25:
  cmp    %r12,%rbx
  jne    L35
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L26:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_infered: string

tool: D10: char

assistant: ```c
int is_basic_type(char *s) {
  static char *keywds[] = {
      "char", "double", "enum", "extern", "float", "int", "long", "short", "static",
  };
  int j, s0 = s[0], k0;
  char *k;
  for (j = 0; j < sizeof(keywds) / sizeof(char *); ++j) {
    k = keywds[j];
    k0 = k[0];
    if (k0 > s0)
      return 0;
    if (k0 < s0)
      continue;
    if (strcmp(s, k) == 0)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_basic_type>:
  endbr64
  movsbl (%rdi),%eax
  cmp    $0x62,%eax
  jle    L72
  sub    $0x18,%rsp
  cmp    $0x63,%eax
  je     L3
  cmp    $0x64,%eax
  je     L143
  cmp    $0x65,%eax
  jne    L193
  lea    D83(%rip),%rsi
  mov    %rdi,0x8(%rsp)
  call   <strcmp@plt>
  mov    0x8(%rsp),%rdi
  test   %rax,%rax
  je     L238
  lea    D73(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L238
L44:
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L193:
  cmp    $0x66,%eax
  je     L234
  cmp    $0x68,%eax
  jle    L44
  cmp    $0x69,%eax
  je     L1
  cmp    $0x6b,%eax
  jle    L44
  cmp    $0x6c,%eax
  je     L167
  cmp    $0x72,%eax
  jle    L44
  cmp    $0x73,%eax
  jne    L44
  lea    D60(%rip),%rsi
  mov    %rdi,0x8(%rsp)
  call   <strcmp@plt>
  mov    0x8(%rsp),%rdi
  test   %rax,%rax
  je     L238
  lea    D19(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
L238:
  mov    $0x1,%eax
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L3:
  lea    D29(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  jmp    L238
  nop
L143:
  lea    D1(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  jmp    L238
  nopw   0x0(%rax,%rax,1)
L234:
  lea    D13(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  jmp    L238
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D69(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  jmp    L238
  nopw   0x0(%rax,%rax,1)
L167:
  lea    D30(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L44
  jmp    L238
L72:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D83
type_guessed: string
name: parse_data
arguments: tag: D73
type_guessed: string
name: parse_data
arguments: tag: D60
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D29
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D69
type_guessed: string
name: parse_data
arguments: tag: D30
type_guessed: string

tool: D83: enum

tool: D73: extern

tool: D60: short

tool: D19: static

tool: D29: char

tool: D1: double

tool: D13: float

tool: D69: int

tool: D30: long

assistant: ```c
int is_basic_type(char *s) {
  static char *keywds[] = {
      "char", "double", "enum", "extern", "float", "int", "long", "short", "static",
  };
  int j, s0 = s[0], k0;
  char *k;
  for (j = 0; j < sizeof(keywds) / sizeof(char *); ++j) {
    k = keywds[j];
    k0 = k[0];
    if (k0 > s0)
      return 0;
    if (k0 < s0)
      continue;
    if (strcmp(s, k) == 0)
      return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gb_int2ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *gb_int2ptr(const int i) {
  union {
    void *p;
    int i;
  } x = {NULL};
  x.i = i;
  return x.p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gb_int2ptr>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
void *gb_int2ptr(const int i) {
  union {
    void *p;
    int i;
  } x = {NULL};
  x.i = i;
  return x.p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gb_int2ptr>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
void *gb_int2ptr(const int i) {
  union {
    void *p;
    int i;
  } x = {NULL};
  x.i = i;
  return x.p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L9:
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    -0x90(%rbp),%rax
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x90(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: thread3

assistant: ```c
void *thread4(void *arg) {
  while (1) {
    sleep(1);
    char szBuf[128];
    memset(szBuf, 0, sizeof(szBuf));
    strcpy(szBuf, "thread3");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread4>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rbp
L4:
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    %rsp,%rbx
  mov    $0x80,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: thread3

assistant: ```c
void *thread4(void *arg) {
  while (1) {
    sleep(1);
    char szBuf[128];
    memset(szBuf, 0, sizeof(szBuf));
    strcpy(szBuf, "thread3");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<thread4>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    $0x80,%edx
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L7
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: thread3

assistant: ```c
void *thread4(void *arg) {
  while (1) {
    sleep(1);
    char szBuf[128];
    memset(szBuf, 0, sizeof(szBuf));
    strcpy(szBuf, "thread3");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread4>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    $0x80,%edx
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: label: D8
type_infered: string

tool: D8: thread3

assistant: ```c
void *thread4(void *arg) {
  while (1) {
    sleep(1);
    char szBuf[128];
    memset(szBuf, 0, sizeof(szBuf));
    strcpy(szBuf, "thread3");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <_inttypes@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
  jmp    L18
L10:
  mov    $0x2,%eax
L18:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_inttypes(argv[0]) == 0) ? 0 : 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_inttypes@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_inttypes(argv[0]) == 0) ? 0 : 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_inttypes@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_inttypes(argv[0]) == 0) ? 0 : 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <_inttypes@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  (void)argc;
  return (_inttypes(argv[0]) == 0) ? 0 : 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<newstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *newstr(char *s, int len) {
  char *rv = (char *)malloc(len + 1);
  rv[len] = '\0';
  strncpy(rv, s, len);
  return rv;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<newstr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movslq %ebp,%rax
  movb   $0x0,(%rbx,%rax,1)
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *newstr(char *s, int len) {
  char *rv = (char *)malloc(len + 1);
  rv[len] = '\0';
  strncpy(rv, s, len);
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<newstr>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *newstr(char *s, int len) {
  char *rv = (char *)malloc(len + 1);
  rv[len] = '\0';
  strncpy(rv, s, len);
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<newstr>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r12
  movslq %r13d,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *newstr(char *s, int len) {
  char *rv = (char *)malloc(len + 1);
  rv[len] = '\0';
  strncpy(rv, s, len);
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gen_swap_first>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl -0x20(%rbp),%edx
  mov    %dl,(%rax)
L6:
  nop
  leave
  ret
```

assistant: ```c
void gen_swap_first(char **line, char target, char dest) {
  char *holder = NULL;
  holder = strchr(*line, target);
  if (holder != NULL)
    *holder = dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<gen_swap_first>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  movsbl %sil,%esi
  mov    (%rdi),%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  mov    %bl,(%rax)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void gen_swap_first(char **line, char target, char dest) {
  char *holder = NULL;
  holder = strchr(*line, target);
  if (holder != NULL)
    *holder = dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_swap_first>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdi
  movsbl %sil,%esi
  mov    %edx,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  mov    %bl,(%rax)
L5:
  pop    %rbx
  ret
```

assistant: ```c
void gen_swap_first(char **line, char target, char dest) {
  char *holder = NULL;
  holder = strchr(*line, target);
  if (holder != NULL)
    *holder = dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_swap_first>:
  endbr64
  push   %rbx
  mov    (%rdi),%rdi
  movsbl %sil,%esi
  mov    %edx,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L3
  mov    %bl,(%rax)
L3:
  pop    %rbx
  ret
```

assistant: ```c
void gen_swap_first(char **line, char target, char dest) {
  char *holder = NULL;
  holder = strchr(*line, target);
  if (holder != NULL)
    *holder = dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<exec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: Thread


assistant: ```c
void *exec(void *t) {
  printf("Thread\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<exec>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string

tool: D8: Thread


assistant: ```c
void *exec(void *t) {
  printf("Thread\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<exec>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: Thread


assistant: ```c
void *exec(void *t) {
  printf("Thread\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<exec>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Thread


assistant: ```c
void *exec(void *t) {
  printf("Thread\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    $0xffffffff,%eax
  jmp    L45
L4:
  movl   $0x0,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L26
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L37
L26:
  mov    $0xffffffff,%eax
  jmp    L45
L37:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int parse_fd(const char *s) {
  if (!*s) {
    return -1;
  }
  int val = 0;
  do {
    if (*s < '0' || *s > '9') {
      return -1;
    }
    int digit = *s++ - '0';
    val = val * 10 + digit;
  } while (*s);
  return val;
}
```