ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<emit_gap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L1:
  mov    $0x1,%edi
  call   <emit_bit@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x63,-0x4(%rbp)
  jle    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void emit_gap() {
  int i;
  for (i = 0; i < 100; i++)
    emit_bit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_gap>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
L0:
  mov    $0x1,%edi
  call   <emit_bit@plt>
  sub    $0x1,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void emit_gap() {
  int i;
  for (i = 0; i < 100; i++)
    emit_bit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<emit_gap>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%edi
  call   <emit_bit@plt>
  sub    $0x1,%ebx
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
void emit_gap() {
  int i;
  for (i = 0; i < 100; i++)
    emit_bit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_gap>:
  endbr64
  push   %rbx
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%edi
  call   <emit_bit@plt>
  sub    $0x1,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void emit_gap() {
  int i;
  for (i = 0; i < 100; i++)
    emit_bit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<syscon_multprec_size_limit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x25b,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_multprec_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(603, &k, szl, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<syscon_multprec_size_limit>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x25b,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_multprec_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(603, &k, szl, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<syscon_multprec_size_limit>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x25b,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_multprec_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(603, &k, szl, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<syscon_multprec_size_limit>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x25b,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int syscon_multprec_size_limit(int k, int *szl) {
  int fail;
  double *c;
  fail = _ada_use_c2phc(603, &k, szl, c);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L3:
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
  jmp    L7
L32:
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L32
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_putline(int line_size) {
  int i;
  i = 0;
  while (i < line_size) {
    ft_putchar(' ');
    i++;
  }
  ft_putchar('/');
  while (i < line_size - 2) {
    ft_putchar('*');
    i++;
  }
  ft_putchar('\\');
  ft_putchar('\n');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_putline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  test   %edi,%edi
  jle    L10
  mov    $0x0,%ebx
L36:
  mov    $0x20,%edi
  call   <ft_putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L36
  mov    %ebp,%ebx
L40:
  mov    $0x2f,%edi
  call   <ft_putchar@plt>
  sub    $0x2,%ebp
  cmp    %ebx,%ebp
  jg     L29
L17:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x0,%ebx
  jmp    L40
L29:
  mov    $0x2a,%edi
  call   <ft_putchar@plt>
  jmp    L17
```

assistant: ```c
void ft_putline(int line_size) {
  int i;
  i = 0;
  while (i < line_size) {
    ft_putchar(' ');
    i++;
  }
  ft_putchar('/');
  while (i < line_size - 2) {
    ft_putchar('*');
    i++;
  }
  ft_putchar('\\');
  ft_putchar('\n');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putline>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L32
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  jne    L5
  mov    %ebp,%ebx
L32:
  mov    $0x2f,%edi
  sub    $0x2,%ebp
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  jle    L16
  nopl   0x0(%rax)
L38:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebp,%ebx
  jne    L38
L16:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_putline(int line_size) {
  int i;
  i = 0;
  while (i < line_size) {
    ft_putchar(' ');
    i++;
  }
  ft_putchar('/');
  while (i < line_size - 2) {
    ft_putchar('*');
    i++;
  }
  ft_putchar('\\');
  ft_putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putline>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L37
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  jne    L3
  mov    %ebp,%ebx
L37:
  mov    $0x2f,%edi
  sub    $0x2,%ebp
  call   <ft_putchar@plt>
  cmp    %ebx,%ebp
  jle    L20
  nopl   0x0(%rax)
L17:
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <ft_putchar@plt>
  cmp    %ebp,%ebx
  jne    L17
L20:
  mov    $0x5c,%edi
  call   <ft_putchar@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ft_putchar@plt>
```

assistant: ```c
void ft_putline(int line_size) {
  int i;
  i = 0;
  while (i < line_size) {
    ft_putchar(' ');
    i++;
  }
  ft_putchar('/');
  while (i < line_size - 2) {
    ft_putchar('*');
    i++;
  }
  ft_putchar('\\');
  ft_putchar('\n');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encryptstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x1(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x20(%rbp)
  jmp    L18
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1(%rbp),%al
  xor    $0xffffffa5,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void encryptstr(unsigned char *src, unsigned char *dest) {
  unsigned char last = 0;
  *dest = 0;
  dest++;
  while (*src) {
    *dest = *src ^ 0xA5 ^ last;
    last = *src;
    src++;
    dest++;
  }
  *dest = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<encryptstr>:
  endbr64
  movb   $0x0,(%rsi)
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L16
  mov    $0x0,%edx
L3:
  xor    %edx,%eax
  xor    $0xffffffa5,%eax
  mov    %al,(%rsi)
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L3
L16:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void encryptstr(unsigned char *src, unsigned char *dest) {
  unsigned char last = 0;
  *dest = 0;
  dest++;
  while (*src) {
    *dest = *src ^ 0xA5 ^ last;
    last = *src;
    src++;
    dest++;
  }
  *dest = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encryptstr>:
  endbr64
  movb   $0x0,(%rsi)
  movzbl (%rdi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L3
  xor    %edx,%edx
  nopl   0x0(%rax)
L15:
  xor    %edx,%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
  xor    $0xffffffa5,%eax
  mov    %al,-0x1(%rsi)
  movzbl -0x1(%rdi),%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
L3:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void encryptstr(unsigned char *src, unsigned char *dest) {
  unsigned char last = 0;
  *dest = 0;
  dest++;
  while (*src) {
    *dest = *src ^ 0xA5 ^ last;
    last = *src;
    src++;
    dest++;
  }
  *dest = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encryptstr>:
  endbr64
  movb   $0x0,(%rsi)
  movzbl (%rdi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L10
  xor    %edx,%edx
  nopl   0x0(%rax)
L0:
  xor    %edx,%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
  xor    $0xffffffa5,%eax
  mov    %al,-0x1(%rsi)
  movzbl -0x1(%rdi),%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L0
L10:
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void encryptstr(unsigned char *src, unsigned char *dest) {
  unsigned char last = 0;
  *dest = 0;
  dest++;
  while (*src) {
    *dest = *src ^ 0xA5 ^ last;
    last = *src;
    src++;
    dest++;
  }
  *dest = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_decimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    %edx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  add    $0x20,%rax
  mov    %rax,-0x48(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  jne    L17
  subq   $0x1,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  movb   $0x30,(%rax)
  jmp    L5
L17:
  mov    -0x58(%rbp),%rax
  mov    $0xcccccccd,%esi
  mov    %rax,%rdi
  call   <__builtin_alpha_umulh@plt>
  mov    %rax,-0x40(%rbp)
  shrq   $0x3,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x58(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x30,%eax
  subq   $0x1,-0x48(%rbp)
  mov    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  jne    L17
L5:
  mov    -0x60(%rbp),%esi
  mov    -0x5c(%rbp),%ecx
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %esi,%r8d
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <print_buf_pad@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
int print_decimal(unsigned long val, int width, int pad) {
  char buf[32];
  char *p = buf + sizeof(buf);
  if (val == 0)
    *--p = '0';
  else {
    do {
      unsigned long d, r;
      d = __builtin_alpha_umulh(val, 0xcccccccccccccccd);
      d >>= 3;
      r = val - (d * 10);
      *--p = r + '0';
      val = d;
    } while (val);
  }
  return print_buf_pad(buf, sizeof(buf), p, width, pad);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_decimal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L38
  movb   $0x30,0x1f(%rsp)
  lea    0x1f(%rsp),%rbp
L10:
  mov    %rsp,%rdi
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    $0x20,%esi
  call   <print_buf_pad@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    %rdi,%rbx
  lea    0x20(%rsp),%rbp
L7:
  mov    $0xcccccccd,%esi
  mov    %rbx,%rdi
  call   <__builtin_alpha_umulh@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  mov    %rdx,%rbx
  shr    $0x3,%rbx
  sub    $0x1,%rbp
  lea    (%rbx,%rbx,4),%rdx
  add    %rdx,%rdx
  sub    %rdx,%rax
  add    $0x30,%eax
  mov    %al,0x0(%rbp)
  test   %rbx,%rbx
  jne    L7
  jmp    L10
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int print_decimal(unsigned long val, int width, int pad) {
  char buf[32];
  char *p = buf + sizeof(buf);
  if (val == 0)
    *--p = '0';
  else {
    do {
      unsigned long d, r;
      d = __builtin_alpha_umulh(val, 0xcccccccccccccccd);
      d >>= 3;
      r = val - (d * 10);
      *--p = r + '0';
      val = d;
    } while (val);
  }
  return print_buf_pad(buf, sizeof(buf), p, width, pad);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_decimal>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L27
  movb   $0x30,0x1f(%rsp)
  lea    0x1f(%rsp),%r13
L22:
  mov    %r13,%rdx
  mov    %rsp,%rdi
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    $0x20,%esi
  call   <print_buf_pad@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rdi,%rbx
  lea    0x20(%rsp),%r13
L23:
  mov    %rbx,%rdi
  mov    $0xcccccccd,%esi
  sub    $0x1,%r13
  call   <__builtin_alpha_umulh@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  mov    %r8,%rbx
  shr    $0x3,%rbx
  lea    (%rbx,%rbx,4),%rdx
  add    %rdx,%rdx
  sub    %rdx,%rax
  add    $0x30,%eax
  mov    %al,0x0(%r13)
  test   %rbx,%rbx
  jne    L23
  jmp    L22
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int print_decimal(unsigned long val, int width, int pad) {
  char buf[32];
  char *p = buf + sizeof(buf);
  if (val == 0)
    *--p = '0';
  else {
    do {
      unsigned long d, r;
      d = __builtin_alpha_umulh(val, 0xcccccccccccccccd);
      d >>= 3;
      r = val - (d * 10);
      *--p = r + '0';
      val = d;
    } while (val);
  }
  return print_buf_pad(buf, sizeof(buf), p, width, pad);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_decimal>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  jne    L10
  movb   $0x30,0x1f(%rsp)
  lea    0x1f(%rsp),%r13
L5:
  mov    %r13,%rdx
  mov    %rsp,%rdi
  mov    %ebp,%r8d
  mov    %r12d,%ecx
  mov    $0x20,%esi
  call   <print_buf_pad@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rdi,%rbx
  lea    0x20(%rsp),%r13
L2:
  mov    %rbx,%rdi
  mov    $0xcccccccd,%esi
  sub    $0x1,%r13
  call   <__builtin_alpha_umulh@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  mov    %r8,%rbx
  shr    $0x3,%rbx
  lea    (%rbx,%rbx,4),%rdx
  add    %rdx,%rdx
  sub    %rdx,%rax
  add    $0x30,%eax
  mov    %al,0x0(%r13)
  test   %rbx,%rbx
  jne    L2
  jmp    L5
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int print_decimal(unsigned long val, int width, int pad) {
  char buf[32];
  char *p = buf + sizeof(buf);
  if (val == 0)
    *--p = '0';
  else {
    do {
      unsigned long d, r;
      d = __builtin_alpha_umulh(val, 0xcccccccccccccccd);
      d >>= 3;
      r = val - (d * 10);
      *--p = r + '0';
      val = d;
    } while (val);
  }
  return print_buf_pad(buf, sizeof(buf), p, width, pad);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rcx
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x24(%rbp),%xmm1
  movss  -0x24(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x28(%rbp),%xmm2
  movss  D33(%rip),%xmm1
  mulss  %xmm1,%xmm2
  movss  -0x20(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  D22(%rip),%xmm1
  xorps  %xmm0,%xmm1
  movss  -0x28(%rbp),%xmm0
  movaps %xmm0,%xmm2
  addss  %xmm0,%xmm2
  divss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x28(%rbp),%xmm0
  movaps %xmm0,%xmm2
  addss  %xmm0,%xmm2
  divss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x18(%rbp),%xmm0
  addss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm0
  subss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D33
type_guessed: byte[4]
name: read_data
arguments: tag: D22
type_guessed: byte[4]
name: read_data
arguments: tag: D17
type_guessed: string

tool: D4: a=%f,b=%f,c=%f

tool: {"D33": [0x00,0x00,0x80,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x80]}

tool: D17: x1=%5.2f
x2=%5.2f


assistant: ```c
void main() {
  float a, b, c, disc, x1, x2, p, q;
  scanf("a=%f,b=%f,c=%f", &a, &b, &c);
  disc = b * b - 4 * a * c;
  p = -b / (2 * a);
  q = sqrt(disc) / (2 * a);
  x1 = p + q;
  x2 = p - q;
  printf("x1=%5.2f\nx2=%5.2f\n", x1, x2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  movss  0x20(%rsp),%xmm0
  movss  0x1c(%rsp),%xmm1
  movaps %xmm0,%xmm3
  xorps  D2(%rip),%xmm3
  movaps %xmm1,%xmm2
  addss  %xmm1,%xmm2
  divss  %xmm2,%xmm3
  movss  %xmm3,0xc(%rsp)
  mulss  %xmm0,%xmm0
  mulss  D13(%rip),%xmm1
  mulss  0x24(%rsp),%xmm1
  subss  %xmm1,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  0x1c(%rsp),%xmm1
  addss  %xmm1,%xmm1
  divss  %xmm1,%xmm0
  movss  0xc(%rsp),%xmm4
  movaps %xmm4,%xmm2
  addss  %xmm0,%xmm2
  subss  %xmm0,%xmm4
  movaps %xmm4,%xmm1
  movaps %xmm2,%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D2
data_type: byte[16]
name: unpack_data
arguments: tag: D13
data_type: byte[4]
name: unpack_data
arguments: tag: D5
data_type: string

tool: D6: a=%f,b=%f,c=%f

tool: {"D2": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x80,0x40]}

tool: D5: x1=%5.2f
x2=%5.2f


assistant: ```c
void main() {
  float a, b, c, disc, x1, x2, p, q;
  scanf("a=%f,b=%f,c=%f", &a, &b, &c);
  disc = b * b - 4 * a * c;
  p = -b / (2 * a);
  q = sqrt(disc) / (2 * a);
  x1 = p + q;
  x2 = p - q;
  printf("x1=%5.2f\nx2=%5.2f\n", x1, x2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  movss  0x1c(%rsp),%xmm2
  movss  0x20(%rsp),%xmm0
  movaps %xmm2,%xmm3
  movaps %xmm0,%xmm1
  xorps  D6(%rip),%xmm1
  addss  %xmm2,%xmm3
  mulss  D27(%rip),%xmm2
  mulss  0x24(%rsp),%xmm2
  mulss  %xmm0,%xmm0
  divss  %xmm3,%xmm1
  subss  %xmm2,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %eax,%xmm0
  lea    D2(%rip),%rdi
  addss  %xmm2,%xmm2
  divss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  addss  %xmm0,%xmm2
  subss  %xmm0,%xmm1
  movaps %xmm2,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D6
data_type: byte[16]
name: read_data
arguments: data_label: D27
data_type: byte[4]
name: read_data
arguments: data_label: D2
data_type: string

tool: D26: a=%f,b=%f,c=%f

tool: {"D6": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D27": [0x00,0x00,0x80,0x40]}

tool: D2: x1=%5.2f
x2=%5.2f


assistant: ```c
void main() {
  float a, b, c, disc, x1, x2, p, q;
  scanf("a=%f,b=%f,c=%f", &a, &b, &c);
  disc = b * b - 4 * a * c;
  p = -b / (2 * a);
  q = sqrt(disc) / (2 * a);
  x1 = p + q;
  x2 = p - q;
  printf("x1=%5.2f\nx2=%5.2f\n", x1, x2);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  movss  0x1c(%rsp),%xmm2
  movss  0x20(%rsp),%xmm0
  movaps %xmm2,%xmm3
  movaps %xmm0,%xmm1
  xorps  D29(%rip),%xmm1
  addss  %xmm2,%xmm3
  mulss  D20(%rip),%xmm2
  mulss  0x24(%rsp),%xmm2
  mulss  %xmm0,%xmm0
  divss  %xmm3,%xmm1
  subss  %xmm2,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <sqrt@plt>
  movss  0x1c(%rsp),%xmm2
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %eax,%xmm0
  lea    D3(%rip),%rdi
  addss  %xmm2,%xmm2
  divss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  addss  %xmm0,%xmm2
  subss  %xmm0,%xmm1
  movaps %xmm2,%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D29
type_infered: byte[16]
name: parse_data
arguments: data_label: D20
type_infered: byte[4]
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D6: a=%f,b=%f,c=%f

tool: {"D29": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D20": [0x00,0x00,0x80,0x40]}

tool: D3: x1=%5.2f
x2=%5.2f


assistant: ```c
void main() {
  float a, b, c, disc, x1, x2, p, q;
  scanf("a=%f,b=%f,c=%f", &a, &b, &c);
  disc = b * b - 4 * a * c;
  p = -b / (2 * a);
  q = sqrt(disc) / (2 * a);
  x1 = p + q;
  x2 = p - q;
  printf("x1=%5.2f\nx2=%5.2f\n", x1, x2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<be64toh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <swap_n@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
uint64_t be64toh(uint64_t in) {
  uint64_t out;
  swap_n(&in, &out, sizeof(out));
  return out;
}
```