user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<factorial>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D75(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%ecx
  cmp    $0x1,%ecx
  jbe    L6
  lea    -0x2(%rcx),%edx
  lea    -0x1(%rcx),%eax
  cmp    $0xd5,%edx
  jbe    L33
  movd   %ecx,%xmm6
  mov    %eax,%esi
  movdqa D37(%rip),%xmm1
  xor    %edx,%edx
  pshufd $0x0,%xmm6,%xmm2
  movdqa D54(%rip),%xmm5
  shr    $0x2,%esi
  pcmpeqd %xmm4,%xmm4
  paddd  D39(%rip),%xmm2
  nopw   0x0(%rax,%rax,1)
L22:
  movdqa %xmm2,%xmm0
  add    $0x1,%edx
  paddd  %xmm5,%xmm2
  paddd  %xmm4,%xmm0
  movdqa %xmm0,%xmm3
  psrlq  $0x20,%xmm0
  pmuludq %xmm1,%xmm3
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm3,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  cmp    %esi,%edx
  jne    L22
  movdqa %xmm1,%xmm0
  mov    %eax,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  movdqa %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  pmuludq %xmm1,%xmm0
  movd   %xmm0,%esi
  imul   %ecx,%esi
  sub    %edx,%ecx
  cmp    %edx,%eax
  je     L80
  lea    -0x1(%rcx),%eax
  jmp    L73
L82:
  sub    $0x1,%eax
L73:
  imul   %eax,%esi
  cmp    $0x1,%eax
  jne    L82
L80:
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,0x4(%rsp)
  call   <printf@plt>
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  jmp    L46
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %ecx,%esi
  jmp    L73
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D26
type: string
name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D75
type: string
name: unpack_data
arguments: data_label: D37
type: byte[16]
name: unpack_data
arguments: data_label: D54
type: byte[16]
name: unpack_data
arguments: data_label: D39
type: byte[16]
name: unpack_data
arguments: data_label: D44
type: string
name: unpack_data
arguments: data_label: D46
type: string

tool: D26: 


tool: D12: Enter a positive decimal number: 

tool: D75: %d

tool: {"D37": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D54": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D39": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

tool: D44: Result: %d



tool: D46: Result: 1


assistant: ```c
void factorial(void) {
  int count = 0, fact = 0;
  printf("\n\n");
  printf("Enter a positive decimal number: ");
  scanf("%d", &fact);
  printf("\n\n");
  if ((fact == 0) || (fact == 1)) {
    printf("Result: 1\n\n");
  } else {
    count = fact;
    while (count != 1) {
      count--;
      fact = fact * count;
    }
    printf("Result: %d\n\n", fact);
  }
}
```