user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<llspeech_make_int_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movw   $0x3a2c,-0x1b(%rbp)
  movb   $0x0,-0x19(%rbp)
  movl   $0x0,-0x50(%rbp)
  cmpq   $0x0,-0x58(%rbp)
  jne    L101
  cmpq   $0x0,-0x60(%rbp)
  je     L80
  mov    -0x60(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L21
L80:
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x48(%rbp),%rax
  jmp    L21
L101:
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x1b(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <count_tokens_in_string@plt>
  mov    %eax,-0x4c(%rbp)
  cmpq   $0x0,-0x60(%rbp)
  je     L90
  mov    -0x60(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4c(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x48(%rbp)
  jmp    L81
L90:
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x50(%rbp)
L81:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rdx
  lea    -0x1b(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_token_from_string@plt>
  mov    %rax,-0x40(%rbp)
  jmp    L1
L70:
  mov    -0x50(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x50(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  mov    -0x30(%rbp),%rdx
  lea    -0x1b(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <get_token_from_string@plt>
  mov    %rax,-0x40(%rbp)
L1:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
  cmpq   $0x0,-0x38(%rbp)
  je     L24
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L24:
  cmpq   $0x0,-0x28(%rbp)
  je     L37
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L37:
  mov    -0x48(%rbp),%rax
L21:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *llspeech_make_int_array(const char *original, int *array_len) {
  int *int_array;
  char *copy, *copy2, *next, *token, delim[3] = ",:";
  int i = 0, len;
  if (!original) {
    if (array_len) {
      *array_len = 0;
      return NULL;
    } else {
      int_array = (int *)calloc(1, sizeof(int));
      int_array[0] = 0;
      return int_array;
    }
  }
  copy = strdup(original);
  len = count_tokens_in_string(copy, delim);
  if (array_len) {
    *array_len = len;
    int_array = (int *)calloc(len, sizeof(int));
  } else {
    int_array = (int *)calloc(len + 1, sizeof(int));
    int_array[0] = len;
    i++;
  }
  token = copy;
  copy2 = strdup(original);
  next = get_token_from_string(copy2, delim, token);
  while (strlen(token)) {
    int_array[i++] = atoi(token);
    next = get_token_from_string(next, delim, token);
  }
  if (copy)
    free(copy);
  if (copy2)
    free(copy2);
  return int_array;
}
```