ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fdt_subnode_offset_namelen>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fdt_check_header@plt>
  test   %eax,%eax
  jne    L13
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%r12
  test   %ebp,%ebp
  js     L31
  nopl   (%rax)
L20:
  mov    %ebp,%esi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <fdt_next_node@plt>
  mov    %eax,%ebp
  mov    0x4(%rsp),%eax
  mov    %eax,%ecx
  or     %ebp,%ecx
  js     L28
  cmp    $0x1,%eax
  jne    L20
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <_fdt_nodename_eq@plt>
  test   %rax,%rax
  je     L20
  nopl   0x0(%rax,%rax,1)
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L28:
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovs  %eax,%ebp
  jmp    L31
  nopl   0x0(%rax)
L13:
  mov    %eax,%ebp
  jmp    L31
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fdt_subnode_offset_namelen(const void *fdt, int offset, const char *name, int namelen) {
  int depth;
  {
    int __err;
    if ((__err = fdt_check_header(fdt)) != 0)
      return __err;
  };
  for (depth = 0; (offset >= 0) && (depth >= 0); offset = fdt_next_node(fdt, offset, &depth))
    if ((depth == 1) && _fdt_nodename_eq(fdt, offset, name, namelen))
      return offset;
  if (depth < 0)
    return -1;
  return offset;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imprimirError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L28
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L28:
  cmpl   $0x2,-0x4(%rbp)
  jne    L8
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D35
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string

tool: D7: El archivo especificado no existe

tool: D35: %s


tool: D19: El archivo especificado debe tener extension .xx

assistant: ```c
void imprimirError(int codigo) {
  if (codigo == 1) {
    printf("%s\n", "El archivo especificado no existe");
  } else if (codigo == 2) {
    printf("%s\n", "El archivo especificado debe tener extension .xx");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imprimirError>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L12
  cmp    $0x2,%edi
  je     L13
L35:
  add    $0x8,%rsp
  ret
L12:
  lea    D18(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L13:
  lea    D33(%rip),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L35
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D33
data_type: string

tool: D18: El archivo especificado no existe

tool: D4: %s


tool: D33: El archivo especificado debe tener extension .xx

assistant: ```c
void imprimirError(int codigo) {
  if (codigo == 1) {
    printf("%s\n", "El archivo especificado no existe");
  } else if (codigo == 2) {
    printf("%s\n", "El archivo especificado debe tener extension .xx");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<imprimirError>:
  endbr64
  cmp    $0x1,%edi
  je     L11
  cmp    $0x2,%edi
  je     L0
  ret
  nop
L11:
  lea    D15(%rip),%rsi
  lea    D20(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  lea    D24(%rip),%rsi
  lea    D20(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D24
type_infered: string

tool: D15: El archivo especificado no existe

tool: D20: %s


tool: D24: El archivo especificado debe tener extension .xx

assistant: ```c
void imprimirError(int codigo) {
  if (codigo == 1) {
    printf("%s\n", "El archivo especificado no existe");
  } else if (codigo == 2) {
    printf("%s\n", "El archivo especificado debe tener extension .xx");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<imprimirError>:
  endbr64
  cmp    $0x1,%edi
  je     L8
  cmp    $0x2,%edi
  je     L15
  ret
  nop
L8:
  lea    D6(%rip),%rsi
  lea    D39(%rip),%rdi
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L15:
  lea    D13(%rip),%rsi
  lea    D39(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D13
datatype: string

tool: D6: El archivo especificado no existe

tool: D39: %s


tool: D13: El archivo especificado debe tener extension .xx

assistant: ```c
void imprimirError(int codigo) {
  if (codigo == 1) {
    printf("%s\n", "El archivo especificado no existe");
  } else if (codigo == 2) {
    printf("%s\n", "El archivo especificado debe tener extension .xx");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x6a,%eax
  xor    $0xb,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  add    $0x1aae2792,%rax
  mov    $0xff,%edx
  mov    %edx,%ecx
  shr    %cl,%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= (state[local1] & (unsigned char)31) << 4UL;
      state[0UL] -= state[local1];
      local1++;
    }
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      local1++;
    }
    output[0UL] = ((state[0UL] + 447621010UL) << (unsigned char)9) | ((state[0UL] + 447621010UL) >> (unsigned char)255);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= (state[local1] & (unsigned char)31) << 4UL;
      state[0UL] -= state[local1];
      local1++;
    }
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      local1++;
    }
    output[0UL] = ((state[0UL] + 447621010UL) << (unsigned char)9) | ((state[0UL] + 447621010UL) >> (unsigned char)255);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= (state[local1] & (unsigned char)31) << 4UL;
      state[0UL] -= state[local1];
      local1++;
    }
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      local1++;
    }
    output[0UL] = ((state[0UL] + 447621010UL) << (unsigned char)9) | ((state[0UL] + 447621010UL) >> (unsigned char)255);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movb   $0x0,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned char)11;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= (state[local1] & (unsigned char)31) << 4UL;
      state[0UL] -= state[local1];
      local1++;
    }
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      state[local1] |= ((state[0UL] + state[local1]) & (unsigned char)15) << 2UL;
      state[0UL] |= (state[0UL] & (unsigned char)15) << 3UL;
      local1++;
    }
    output[0UL] = ((state[0UL] + 447621010UL) << (unsigned char)9) | ((state[0UL] + 447621010UL) >> (unsigned char)255);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dosub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%eax
  cmp    $0x4,%eax
  jg     L20
  mov    $0x200,%r12d
  jmp    L42
L20:
  lea    0x20(%rbx),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%r12d
L42:
  mov    0x10(%rbx),%r13
  lea    0x18(%rbx),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  cltq
  lea    0x0(%r13,%rax,1),%rbx
  cmp    %r13,%rbx
  jb     L70
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %r13,%rax
  cmp    %rax,%rbx
  jae    L70
  movslq %r12d,%r13
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %rax,%r13
  jae    L10
  movslq %r12d,%rax
  sub    $0x1,%rax
  jmp    L14
L10:
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%rax
L14:
  lea    (%rbx,%rax,1),%r12
  jmp    L58
L16:
  movzbl (%r12),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <putback@plt>
  sub    $0x1,%r12
L58:
  cmp    %rbx,%r12
  jae    L16
L70:
  nop
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
void dosub(argv, argc) register char *argv[];
register int argc;
{
  register char *ap, *fc, *k;
  register int nc;
  if (argc < 5)
    nc = 512;
  else
    nc = atoi(argv[4]);
  ap = argv[2];
  fc = ap + atoi(argv[3]);
  if (fc >= ap && fc < ap + strlen(ap))
    for (k = fc + ((nc) < (strlen(fc)) ? (nc) : (strlen(fc))) - 1; k >= fc; k--)
      putback(*k);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dosub>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x200,%r12d
  cmp    $0x4,%esi
  jg     L40
L33:
  mov    0x10(%rbp),%rbx
  mov    0x18(%rbp),%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  movslq %eax,%rbp
  add    %rbx,%rbp
  jb     L18
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jae    L18
  movslq %r12d,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%r12),%rdx
  lea    -0x1(%rax),%rbx
  cmp    %rax,%r12
  cmovb  %rdx,%rbx
  add    %rbp,%rbx
  jb     L18
L29:
  movsbl (%rbx),%edi
  mov    $0x0,%eax
  call   <putback@plt>
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L29
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  mov    0x20(%rdi),%rdi
  mov    $0x0,%eax
  call   <atoi@plt>
  mov    %eax,%r12d
  jmp    L33
```

assistant: ```c
void dosub(argv, argc) register char *argv[];
register int argc;
{
  register char *ap, *fc, *k;
  register int nc;
  if (argc < 5)
    nc = 512;
  else
    nc = atoi(argv[4]);
  ap = argv[2];
  fc = ap + atoi(argv[3]);
  if (fc >= ap && fc < ap + strlen(ap))
    for (k = fc + ((nc) < (strlen(fc)) ? (nc) : (strlen(fc))) - 1; k >= fc; k--)
      putback(*k);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dosub>:
  endbr64
  push   %r12
  mov    $0x200,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    $0x4,%esi
  jg     L48
L34:
  mov    0x18(%rbp),%rdi
  xor    %eax,%eax
  mov    0x10(%rbp),%rbx
  call   <atoi@plt>
  movslq %eax,%rbp
  add    %rbx,%rbp
  jb     L30
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jae    L30
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%r12),%rdx
  lea    -0x1(%rax),%rbx
  cmp    %rax,%r12
  cmovb  %rdx,%rbx
  add    %rbp,%rbx
  jb     L30
  nopw   0x0(%rax,%rax,1)
L2:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <putback@plt>
  cmp    %rbx,%rbp
  jbe    L2
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    0x20(%rdi),%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  movslq %eax,%r12
  jmp    L34
```

assistant: ```c
void dosub(argv, argc) register char *argv[];
register int argc;
{
  register char *ap, *fc, *k;
  register int nc;
  if (argc < 5)
    nc = 512;
  else
    nc = atoi(argv[4]);
  ap = argv[2];
  fc = ap + atoi(argv[3]);
  if (fc >= ap && fc < ap + strlen(ap))
    for (k = fc + ((nc) < (strlen(fc)) ? (nc) : (strlen(fc))) - 1; k >= fc; k--)
      putback(*k);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dosub>:
  endbr64
  push   %r12
  mov    $0x200,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmp    $0x4,%esi
  jg     L7
L14:
  mov    0x18(%rbp),%rdi
  xor    %eax,%eax
  mov    0x10(%rbp),%rbx
  call   <atoi@plt>
  movslq %eax,%rbp
  add    %rbx,%rbp
  jb     L59
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jae    L59
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%r12),%rdx
  lea    -0x1(%rax),%rbx
  cmp    %rax,%r12
  cmovb  %rdx,%rbx
  add    %rbp,%rbx
  jb     L59
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  sub    $0x1,%rbx
  call   <putback@plt>
  cmp    %rbx,%rbp
  jbe    L11
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x20(%rdi),%rdi
  xor    %eax,%eax
  call   <atoi@plt>
  movslq %eax,%r12
  jmp    L14
```

assistant: ```c
void dosub(argv, argc) register char *argv[];
register int argc;
{
  register char *ap, *fc, *k;
  register int nc;
  if (argc < 5)
    nc = 512;
  else
    nc = atoi(argv[4]);
  ap = argv[2];
  fc = ap + atoi(argv[3]);
  if (fc >= ap && fc < ap + strlen(ap))
    for (k = fc + ((nc) < (strlen(fc)) ? (nc) : (strlen(fc))) - 1; k >= fc; k--)
      putback(*k);
}
```
user: What is the c source code of the assembly code below:

```asm
<randvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L8:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *randvec(int m, double c) {
  srand(time(NULL));
  double *X;
  int i;
  int j;
  X = (double *)malloc(m * sizeof(double));
  for (i = 0; i < m; i++)
    X[i] = ((double)rand()) / ((double)RAND_MAX) * c;
  return X;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<randvec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L3
  mov    %rax,%rbx
  mov    %ebp,%ebp
  lea    (%rax,%rbp,8),%rbp
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D9(%rip),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rax),%xmm1
  divsd  %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L6
L3:
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *randvec(int m, double c) {
  srand(time(NULL));
  double *X;
  int i;
  int j;
  X = (double *)malloc(m * sizeof(double));
  for (i = 0; i < m; i++)
    X[i] = ((double)rand()) / ((double)RAND_MAX) * c;
  return X;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<randvec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L5
  lea    (%rax,%rbx,8),%rbp
  mov    D2(%rip),%rbx
  mov    %rax,%r13
  nopl   (%rax)
L12:
  xor    %eax,%eax
  add    $0x8,%r13
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rbx),%xmm1
  cvtsi2sd %rax,%xmm0
  divsd  %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,-0x8(%r13)
  cmp    %rbp,%r13
  jne    L12
L5:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double *randvec(int m, double c) {
  srand(time(NULL));
  double *X;
  int i;
  int j;
  X = (double *)malloc(m * sizeof(double));
  for (i = 0; i < m; i++)
    X[i] = ((double)rand()) / ((double)RAND_MAX) * c;
  return X;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<randvec>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L6
  lea    (%rax,%rbx,8),%rbp
  mov    D2(%rip),%rbx
  mov    %rax,%r13
  nopl   (%rax)
L2:
  xor    %eax,%eax
  add    $0x8,%r13
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdq (%rbx),%xmm1
  cvtsi2sd %rax,%xmm0
  divsd  %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  movsd  %xmm0,-0x8(%r13)
  cmp    %rbp,%r13
  jne    L2
L6:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double *randvec(int m, double c) {
  srand(time(NULL));
  double *X;
  int i;
  int j;
  X = (double *)malloc(m * sizeof(double));
  for (i = 0; i < m; i++)
    X[i] = ((double)rand()) / ((double)RAND_MAX) * c;
  return X;
}
```
user: What is the c source code of the assembly code below?

```asm
<phistar>:
  endbr64
  movapd %xmm0,%xmm2
  mulsd  D26(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D15(%rip),%xmm0
  subsd  %xmm1,%xmm0
  comisd D27(%rip),%xmm0
  ja     L4
  pxor   %xmm0,%xmm0
  ret
L4:
  sub    $0x8,%rsp
  call   <exp@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D26
datatype: f32[2]
name: read_data
arguments: label: D15
datatype: f64
name: read_data
arguments: label: D27
datatype: f32

tool: {"D26": [0.0,-1.75]}

tool: D15: 0.9189385332046728

tool: D27: 0

assistant: ```c
double phistar(double x, double y) {
  double arg, tem;
  static double xlow = -87.0, sq2p = 0.91893853320467274;
  tem = 0.;
  arg = -0.5 * x * x - sq2p - y;
  if (arg > xlow)
    tem = exp(arg);
  return tem;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<phistar>:
  endbr64
  movapd %xmm0,%xmm2
  movsd  D4(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D21(%rip),%xmm0
  subsd  %xmm1,%xmm0
  comisd D15(%rip),%xmm0
  ja     L6
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  jmp    1050 <exp@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: f32[2]
name: read_data
arguments: tag: D21
datatype: f64
name: read_data
arguments: tag: D15
datatype: f32

tool: {"D4": [0.0,-1.75]}

tool: D21: 0.9189385332046728

tool: D15: 0

assistant: ```c
double phistar(double x, double y) {
  double arg, tem;
  static double xlow = -87.0, sq2p = 0.91893853320467274;
  tem = 0.;
  arg = -0.5 * x * x - sq2p - y;
  if (arg > xlow)
    tem = exp(arg);
  return tem;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<phistar>:
  endbr64
  movapd %xmm0,%xmm2
  movsd  D11(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D0(%rip),%xmm0
  subsd  %xmm1,%xmm0
  comisd D25(%rip),%xmm0
  ja     L2
  pxor   %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  jmp    1050 <exp@plt>
```

tool_calls: name: retrieve_data
arguments: label: D11
data_type: f32[2]
name: retrieve_data
arguments: label: D0
data_type: f64
name: retrieve_data
arguments: label: D25
data_type: f32

tool: {"D11": [0.0,-1.75]}

tool: D0: 0.9189385332046728

tool: D25: 0

assistant: ```c
double phistar(double x, double y) {
  double arg, tem;
  static double xlow = -87.0, sq2p = 0.91893853320467274;
  tem = 0.;
  arg = -0.5 * x * x - sq2p - y;
  if (arg > xlow)
    tem = exp(arg);
  return tem;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L1
  call   <foo_f5@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D3: hello

assistant: ```c
__attribute__((no_icf)) void f5(char *s) {
  char *t1 = __builtin_strstr(s, "hello");
  void foo_f5(void);
  if (t1 != s)
    foo_f5();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f5>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D7(%rip),%rsi
  call   <strstr@plt>
  cmp    %rax,%rbx
  je     L4
  call   <foo_f5@plt>
L4:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: hello

assistant: ```c
__attribute__((no_icf)) void f5(char *s) {
  char *t1 = __builtin_strstr(s, "hello");
  void foo_f5(void);
  if (t1 != s)
    foo_f5();
}
```
user: What is the c source code of the assembly code below:

```asm
<f5>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  lea    D9(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  jmp    1070 <foo_f5@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: hello

assistant: ```c
__attribute__((no_icf)) void f5(char *s) {
  char *t1 = __builtin_strstr(s, "hello");
  void foo_f5(void);
  if (t1 != s)
    foo_f5();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f5>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  lea    D7(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L9
  add    $0x8,%rsp
  jmp    1070 <foo_f5@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string

tool: D7: hello

assistant: ```c
__attribute__((no_icf)) void f5(char *s) {
  char *t1 = __builtin_strstr(s, "hello");
  void foo_f5(void);
  if (t1 != s)
    foo_f5();
}
```