ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_simpson>:
  endbr64
  push   %r14
  movq   %xmm1,%r14
  movapd %xmm0,%xmm1
  push   %rbx
  addsd  %xmm2,%xmm1
  movq   %r14,%xmm7
  sub    $0x28,%rsp
  comisd %xmm1,%xmm7
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  jbe    L6
  mov    $0x1,%ebx
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L19:
  call   <funcao_x@plt>
  movsd  0x10(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
L27:
  addsd  0x8(%rsp),%xmm1
  movq   %r14,%xmm4
  add    $0x1,%ebx
  comisd %xmm1,%xmm4
  jbe    L6
L18:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  test   $0x1,%bl
  je     L19
  call   <funcao_x@plt>
  mulsd  D2(%rip),%xmm0
  movsd  0x10(%rsp),%xmm1
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L6:
  movq   %r14,%xmm0
  call   <funcao_x@plt>
  movsd  %xmm0,0x10(%rsp)
  movsd  0x18(%rsp),%xmm0
  call   <funcao_x@plt>
  addsd  0x10(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  mulsd  0x8(%rsp),%xmm0
  divsd  D7(%rip),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f64
name: disassemble_data
arguments: tag: D7
type_guessed: f64

tool: D2: 4

tool: D7: 3

assistant: ```c
double n_simpson(double intervalo_min, double intervalo_max, double h) {
  double xk = intervalo_min + h;
  double soma;
  int i = 1;
  while (xk < intervalo_max) {
    if (i % 2 == 0)
      soma += 2.0 * funcao_x(xk);
    else
      soma += 4.0 * funcao_x(xk);
    xk += h;
    i++;
  }
  soma = h * (funcao_x(intervalo_max) + funcao_x(intervalo_min) + soma) / 3.0;
  return soma;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<six_f3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %edx,-0x5c(%rbp)
  mov    %ecx,-0x60(%rbp)
  mov    -0x58(%rbp),%edx
  mov    -0x54(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x5c(%rbp),%edx
  mov    -0x54(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x60(%rbp),%edx
  mov    -0x54(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x5c(%rbp),%edx
  mov    -0x58(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x60(%rbp),%edx
  mov    -0x58(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%edx
  mov    -0x5c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <probability@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  D2(%rip),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D2(%rip),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D2(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x40(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x38(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x38(%rbp),%xmm2
  movsd  -0x8(%rbp),%xmm0
  addsd  -0x30(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: f64

tool: D2: 1

assistant: ```c
double six_f3(int a, int b, int c, int d) {
  double ab, ac, ad, bc, bd, cb, cd, db, dc;
  ab = probability(a, b);
  ac = probability(a, c);
  ad = probability(a, d);
  bc = probability(b, c);
  bd = probability(b, d);
  cd = probability(c, d);
  cb = 1.0 - bc;
  db = 1.0 - bd;
  dc = 1.0 - cd;
  return (ab * ac * (cd + bd) + ac * ad * (db + cb) + ab * ad * (dc + bc));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<six_f3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %ecx,%ebp
  call   <probability@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <probability@plt>
  movq   %xmm0,%r14
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <probability@plt>
  movsd  %xmm0,0x10(%rsp)
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <probability@plt>
  movsd  %xmm0,0x18(%rsp)
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <probability@plt>
  movq   %xmm0,%r12
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <probability@plt>
  movapd %xmm0,%xmm4
  movsd  D7(%rip),%xmm1
  movapd %xmm1,%xmm3
  movsd  0x18(%rsp),%xmm8
  subsd  %xmm8,%xmm3
  movapd %xmm3,%xmm0
  movapd %xmm1,%xmm2
  movq   %r12,%xmm6
  subsd  %xmm6,%xmm2
  addsd  %xmm2,%xmm0
  movq   %r14,%xmm5
  movq   %r14,%xmm2
  movsd  0x10(%rsp),%xmm9
  mulsd  %xmm9,%xmm2
  mulsd  %xmm2,%xmm0
  movsd  0x8(%rsp),%xmm7
  mulsd  %xmm7,%xmm5
  movapd %xmm5,%xmm2
  movq   %r12,%xmm3
  addsd  %xmm4,%xmm3
  mulsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  subsd  %xmm4,%xmm1
  addsd  %xmm8,%xmm1
  mulsd  %xmm9,%xmm7
  mulsd  %xmm7,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: f64

tool: D7: 1

assistant: ```c
double six_f3(int a, int b, int c, int d) {
  double ab, ac, ad, bc, bd, cb, cd, db, dc;
  ab = probability(a, b);
  ac = probability(a, c);
  ad = probability(a, d);
  bc = probability(b, c);
  bd = probability(b, d);
  cd = probability(c, d);
  cb = 1.0 - bc;
  db = 1.0 - bd;
  dc = 1.0 - cd;
  return (ab * ac * (cd + bd) + ac * ad * (db + cb) + ab * ad * (dc + bc));
}
```
user: What is the c source code of the assembly code below:

```asm
<six_f3>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x38,%rsp
  call   <probability@plt>
  mov    %ebp,%esi
  mov    %r14d,%edi
  movsd  %xmm0,0x28(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  movsd  %xmm0,0x20(%rsp)
  call   <probability@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x18(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x10(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <probability@plt>
  movsd  D1(%rip),%xmm1
  movsd  0x10(%rsp),%xmm6
  movsd  0x8(%rsp),%xmm4
  movapd %xmm0,%xmm7
  movsd  0x20(%rsp),%xmm2
  movapd %xmm1,%xmm0
  movapd %xmm1,%xmm8
  subsd  %xmm7,%xmm1
  movsd  0x18(%rsp),%xmm5
  subsd  %xmm4,%xmm8
  subsd  %xmm6,%xmm0
  movsd  0x28(%rsp),%xmm3
  add    $0x38,%rsp
  addsd  %xmm7,%xmm4
  pop    %rbp
  pop    %r12
  addsd  %xmm6,%xmm1
  pop    %r13
  pop    %r14
  addsd  %xmm8,%xmm0
  movapd %xmm2,%xmm8
  mulsd  %xmm5,%xmm8
  mulsd  %xmm3,%xmm2
  mulsd  %xmm5,%xmm3
  mulsd  %xmm8,%xmm0
  mulsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: f64

tool: D1: 1

assistant: ```c
double six_f3(int a, int b, int c, int d) {
  double ab, ac, ad, bc, bd, cb, cd, db, dc;
  ab = probability(a, b);
  ac = probability(a, c);
  ad = probability(a, d);
  bc = probability(b, c);
  bd = probability(b, d);
  cd = probability(c, d);
  cb = 1.0 - bc;
  db = 1.0 - bd;
  dc = 1.0 - cd;
  return (ab * ac * (cd + bd) + ac * ad * (db + cb) + ab * ad * (dc + bc));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<six_f3>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x38,%rsp
  call   <probability@plt>
  mov    %ebp,%esi
  mov    %r14d,%edi
  movsd  %xmm0,0x28(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %r14d,%edi
  movsd  %xmm0,0x20(%rsp)
  call   <probability@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x18(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %r13d,%edi
  movsd  %xmm0,0x10(%rsp)
  call   <probability@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <probability@plt>
  movsd  D1(%rip),%xmm1
  movsd  0x10(%rsp),%xmm6
  movsd  0x8(%rsp),%xmm4
  movapd %xmm0,%xmm7
  movsd  0x20(%rsp),%xmm2
  movapd %xmm1,%xmm0
  movapd %xmm1,%xmm8
  subsd  %xmm7,%xmm1
  movsd  0x18(%rsp),%xmm5
  subsd  %xmm4,%xmm8
  subsd  %xmm6,%xmm0
  movsd  0x28(%rsp),%xmm3
  add    $0x38,%rsp
  addsd  %xmm7,%xmm4
  pop    %rbp
  pop    %r12
  addsd  %xmm6,%xmm1
  pop    %r13
  pop    %r14
  addsd  %xmm8,%xmm0
  movapd %xmm2,%xmm8
  mulsd  %xmm5,%xmm8
  mulsd  %xmm3,%xmm2
  mulsd  %xmm5,%xmm3
  mulsd  %xmm8,%xmm0
  mulsd  %xmm4,%xmm2
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
double six_f3(int a, int b, int c, int d) {
  double ab, ac, ad, bc, bd, cb, cd, db, dc;
  ab = probability(a, b);
  ac = probability(a, c);
  ad = probability(a, d);
  bc = probability(b, c);
  bd = probability(b, d);
  cd = probability(c, d);
  cb = 1.0 - bc;
  db = 1.0 - bd;
  dc = 1.0 - cd;
  return (ab * ac * (cd + bd) + ac * ad * (db + cb) + ab * ad * (dc + bc));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uspi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L13
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x14(%rbp),%edx
  lea    0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,-0x4(%rbp)
  jmp    L14
L13:
  movl   $0x0,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,%edi
  call   <usleep@plt>
  nop
  leave
  ret
```

assistant: ```c
void uspi(int R) {
  int cas = 0;
  if (R != 0) {
    cas = (rand() % (R + 1));
  } else {
    cas = 0;
  }
  usleep(cas * 1000);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uspi>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L0
L5:
  imul   $0x3e8,%ebx,%edi
  call   <usleep@plt>
  pop    %rbx
  ret
L0:
  mov    $0x0,%eax
  call   <rand@plt>
  lea    0x1(%rbx),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%ebx
  jmp    L5
```

assistant: ```c
void uspi(int R) {
  int cas = 0;
  if (R != 0) {
    cas = (rand() % (R + 1));
  } else {
    cas = 0;
  }
  usleep(cas * 1000);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uspi>:
  endbr64
  test   %edi,%edi
  jne    L4
  jmp    1070 <usleep@plt>
  nopl   (%rax)
L4:
  push   %rbp
  xor    %eax,%eax
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  call   <rand@plt>
  mov    0xc(%rsp),%edi
  add    $0x10,%rsp
  cltd
  lea    0x1(%rdi),%ebp
  idiv   %ebp
  pop    %rbp
  imul   $0x3e8,%edx,%edi
  jmp    1070 <usleep@plt>
```

assistant: ```c
void uspi(int R) {
  int cas = 0;
  if (R != 0) {
    cas = (rand() % (R + 1));
  } else {
    cas = 0;
  }
  usleep(cas * 1000);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uspi>:
  endbr64
  test   %edi,%edi
  jne    L8
  jmp    1070 <usleep@plt>
  nopl   (%rax)
L8:
  push   %rbp
  xor    %eax,%eax
  sub    $0x10,%rsp
  mov    %edi,0xc(%rsp)
  call   <rand@plt>
  mov    0xc(%rsp),%edi
  add    $0x10,%rsp
  cltd
  lea    0x1(%rdi),%ebp
  idiv   %ebp
  pop    %rbp
  imul   $0x3e8,%edx,%edi
  jmp    1070 <usleep@plt>
```

assistant: ```c
void uspi(int R) {
  int cas = 0;
  if (R != 0) {
    cas = (rand() % (R + 1));
  } else {
    cas = 0;
  }
  usleep(cas * 1000);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ini_lskip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L62
L51:
  addq   $0x1,-0x18(%rbp)
L62:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  jle    L65
  cmpl   $0xd,-0x4(%rbp)
  jle    L36
L65:
  cmpl   $0x20,-0x4(%rbp)
  jne    L5
L36:
  mov    $0x1,%eax
  jmp    L58
L5:
  mov    $0x0,%eax
L58:
  test   %eax,%eax
  jne    L51
L50:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ini_lskip(char *s) {
  while (*s && ({
    int c = (*s);
    !!((c >= '\t' && c <= '\r') || c == ' ');
  }))
    s++;
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ini_lskip>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L21
  ret
L28:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L32
L21:
  movsbl %cl,%edx
  sub    $0x9,%edx
  cmp    $0x4,%edx
  jbe    L28
  cmp    $0x20,%cl
  je     L28
L32:
  ret
```

assistant: ```c
char *ini_lskip(char *s) {
  while (*s && ({
    int c = (*s);
    !!((c >= '\t' && c <= '\r') || c == ' ');
  }))
    s++;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ini_lskip>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  jne    L28
  jmp    L32
L39:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L47
L28:
  movsbl %cl,%edx
  sub    $0x9,%edx
  cmp    $0x4,%edx
  jbe    L39
  cmp    $0x20,%cl
  je     L39
L47:
  ret
L32:
  ret
```

assistant: ```c
char *ini_lskip(char *s) {
  while (*s && ({
    int c = (*s);
    !!((c >= '\t' && c <= '\r') || c == ' ');
  }))
    s++;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ini_lskip>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  jne    L2
  jmp    L23
L7:
  movzbl 0x1(%rax),%ecx
  add    $0x1,%rax
  test   %cl,%cl
  je     L48
L2:
  movsbl %cl,%edx
  sub    $0x9,%edx
  cmp    $0x4,%edx
  jbe    L7
  cmp    $0x20,%cl
  je     L7
L48:
  ret
L23:
  ret
```

assistant: ```c
char *ini_lskip(char *s) {
  while (*s && ({
    int c = (*s);
    !!((c >= '\t' && c <= '\r') || c == ' ');
  }))
    s++;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<intakeIn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xffffff81,%esi
  mov    $0x5,%edi
  call   <motorSet@plt>
  mov    $0x7f,%esi
  mov    $0x6,%edi
  call   <motorSet@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void intakeIn() {
  motorSet(5, -127);
  motorSet(6, 127);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<intakeIn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff81,%esi
  mov    $0x5,%edi
  call   <motorSet@plt>
  mov    $0x7f,%esi
  mov    $0x6,%edi
  call   <motorSet@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void intakeIn() {
  motorSet(5, -127);
  motorSet(6, 127);
}
```
user: What is the c source code of the assembly code below:

```asm
<intakeIn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff81,%esi
  mov    $0x5,%edi
  call   <motorSet@plt>
  mov    $0x7f,%esi
  mov    $0x6,%edi
  add    $0x8,%rsp
  jmp    1050 <motorSet@plt>
```

assistant: ```c
void intakeIn() {
  motorSet(5, -127);
  motorSet(6, 127);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intakeIn>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffff81,%esi
  mov    $0x5,%edi
  call   <motorSet@plt>
  mov    $0x7f,%esi
  mov    $0x6,%edi
  add    $0x8,%rsp
  jmp    1050 <motorSet@plt>
```

assistant: ```c
void intakeIn() {
  motorSet(5, -127);
  motorSet(6, 127);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L6
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Quicksort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Quicksort>
L6:
  nop
  leave
  ret
```

assistant: ```c
void Quicksort(int A[], int p, int r) {
  if (p < r) {
    int q = Partition(A, p, r);
    Quicksort(A, p, q - 1);
    Quicksort(A, q + 1, r);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Quicksort>:
  endbr64
  cmp    %edx,%esi
  jl     L6
  ret
L6:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <Partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <Quicksort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <Quicksort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void Quicksort(int A[], int p, int r) {
  if (p < r) {
    int q = Partition(A, p, r);
    Quicksort(A, p, q - 1);
    Quicksort(A, q + 1, r);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x18(%rbp)
  jmp    L33
L18:
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L57
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L21
L57:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    -0x28(%rbp),%rcx
  cqto
  idiv   %rcx
  mov    %rax,-0x10(%rbp)
  cmpq   $0x1a,-0x10(%rbp)
  jle    L65
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L65:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  addq   $0x1,-0x18(%rbp)
L33:
  lea    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L18
  jmp    L8
L21:
  nop
L8:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D20
datatype: string

tool: D11: Case %lld: impossible


tool: D18: Case %lld: %lld


tool: D20: %lld %lld

assistant: ```c
int main() {
  long long int n, r, temp, i = 1;
  while (scanf("%lld %lld", &r, &n) == 2) {
    if (r == 0 && n == 0)
      break;
    temp = (r - 1) / n;
    if (temp > 26)
      printf("Case %lld: impossible\n", i);
    else
      printf("Case %lld: %lld\n", i, temp);
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    0x8(%rsp),%r12
  lea    D0(%rip),%rbp
  lea    D10(%rip),%r14
  lea    D26(%rip),%r13
  jmp    L28
L55:
  sub    $0x1,%rax
  cqto
  idivq  0x8(%rsp)
  mov    %rax,%rcx
  cmp    $0x1a,%rax
  jle    L52
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  add    $0x1,%rbx
L28:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L11
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  jne    L55
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  je     L11
  mov    $0xffffffffffffffff,%rax
  cqto
  idiv   %rcx
  mov    %rax,%rcx
L52:
  mov    %rcx,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string
name: extract_symbolic_data
arguments: data_tag: D26
type: string

tool: D0: %lld %lld

tool: D10: Case %lld: %lld


tool: D26: Case %lld: impossible


assistant: ```c
int main() {
  long long int n, r, temp, i = 1;
  while (scanf("%lld %lld", &r, &n) == 2) {
    if (r == 0 && n == 0)
      break;
    temp = (r - 1) / n;
    if (temp > 26)
      printf("Case %lld: impossible\n", i);
    else
      printf("Case %lld: %lld\n", i, temp);
    i++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%r15
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D23(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r12
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L57:
  test   %rcx,%rcx
  je     L55
  mov    $0xffffffffffffffff,%rax
  cqto
  idiv   %rcx
L33:
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  add    $0x1,%rbx
L2:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L55
  mov    0x10(%rsp),%rax
  mov    0x8(%rsp),%rcx
  test   %rax,%rax
  je     L57
  sub    $0x1,%rax
  cqto
  idiv   %rcx
  cmp    $0x1a,%rax
  jle    L33
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
  nopl   (%rax)
L55:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D12
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D23
type_guessed: string

tool: D12: Case %lld: %lld


tool: D16: Case %lld: impossible


tool: D23: %lld %lld

assistant: ```c
int main() {
  long long int n, r, temp, i = 1;
  while (scanf("%lld %lld", &r, &n) == 2) {
    if (r == 0 && n == 0)
      break;
    temp = (r - 1) / n;
    if (temp > 26)
      printf("Case %lld: impossible\n", i);
    else
      printf("Case %lld: %lld\n", i, temp);
    i++;
  }
  return 0;
}
```