ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<A2C128_A>:
  endbr64
  mov    (%rdi),%rcx
  lea    -0x80(%rsi),%eax
  cmp    $0x7,%al
  ja     L60
  movzbl %al,%eax
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x64,%eax
  jmp    L1
  mov    $0x66,%eax
  jmp    L1
  mov    $0x61,%eax
  jmp    L1
  mov    $0x60,%eax
  jmp    L1
  mov    $0x63,%eax
  jmp    L1
  mov    $0x62,%eax
  jmp    L1
L60:
  lea    -0x20(%rsi),%eax
  add    $0x40,%esi
  cmp    $0x3f,%al
  cmova  %esi,%eax
  jmp    L1
  mov    $0x65,%eax
L1:
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
```

assistant: ```c
void A2C128_A(unsigned char **ppOutPos, unsigned char c) {
  unsigned char *pOutPos = *ppOutPos;
  switch (c) {
  case (unsigned char)(133):
    *pOutPos = 100;
    break;
  case (unsigned char)(131):
    *pOutPos = 101;
    break;
  case (unsigned char)(128):
    *pOutPos = 102;
    break;
  case (unsigned char)(129):
    *pOutPos = 97;
    break;
  case (unsigned char)(130):
    *pOutPos = 96;
    break;
  case (unsigned char)(134):
    *pOutPos = 99;
    break;
  case (unsigned char)(135):
    *pOutPos = 98;
    break;
  default:
    if (c >= ' ' && c <= '_')
      *pOutPos = (unsigned char)(c - ' ');
    else
      *pOutPos = (unsigned char)(c + 64);
    break;
  }
  (*ppOutPos)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<A2C128_A>:
  endbr64
  lea    -0x80(%rsi),%eax
  mov    (%rdi),%rcx
  cmp    $0x7,%al
  ja     L7
  lea    D8(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  cs nopw 0x0(%rax,%rax,1)
  mov    $0x65,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x64,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x63,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x62,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x66,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x61,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x60,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
L7:
  lea    -0x20(%rsi),%eax
  add    $0x40,%esi
  cmp    $0x3f,%al
  cmova  %esi,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
```

assistant: ```c
void A2C128_A(unsigned char **ppOutPos, unsigned char c) {
  unsigned char *pOutPos = *ppOutPos;
  switch (c) {
  case (unsigned char)(133):
    *pOutPos = 100;
    break;
  case (unsigned char)(131):
    *pOutPos = 101;
    break;
  case (unsigned char)(128):
    *pOutPos = 102;
    break;
  case (unsigned char)(129):
    *pOutPos = 97;
    break;
  case (unsigned char)(130):
    *pOutPos = 96;
    break;
  case (unsigned char)(134):
    *pOutPos = 99;
    break;
  case (unsigned char)(135):
    *pOutPos = 98;
    break;
  default:
    if (c >= ' ' && c <= '_')
      *pOutPos = (unsigned char)(c - ' ');
    else
      *pOutPos = (unsigned char)(c + 64);
    break;
  }
  (*ppOutPos)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<A2C128_A>:
  endbr64
  lea    -0x80(%rsi),%eax
  mov    (%rdi),%rcx
  cmp    $0x7,%al
  ja     L8
  lea    D2(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  cs nopw 0x0(%rax,%rax,1)
  mov    $0x65,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x64,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x63,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x62,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x66,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x61,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
  mov    $0x60,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
  nopl   0x0(%rax)
L8:
  lea    -0x20(%rsi),%eax
  add    $0x40,%esi
  cmp    $0x3f,%al
  cmova  %esi,%eax
  mov    %al,(%rcx)
  addq   $0x1,(%rdi)
  ret
```

assistant: ```c
void A2C128_A(unsigned char **ppOutPos, unsigned char c) {
  unsigned char *pOutPos = *ppOutPos;
  switch (c) {
  case (unsigned char)(133):
    *pOutPos = 100;
    break;
  case (unsigned char)(131):
    *pOutPos = 101;
    break;
  case (unsigned char)(128):
    *pOutPos = 102;
    break;
  case (unsigned char)(129):
    *pOutPos = 97;
    break;
  case (unsigned char)(130):
    *pOutPos = 96;
    break;
  case (unsigned char)(134):
    *pOutPos = 99;
    break;
  case (unsigned char)(135):
    *pOutPos = 98;
    break;
  default:
    if (c >= ' ' && c <= '_')
      *pOutPos = (unsigned char)(c - ' ');
    else
      *pOutPos = (unsigned char)(c + 64);
    break;
  }
  (*ppOutPos)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<outInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xfffffffd,%edi
  call   <exit@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D0
datatype: string

tool: D8: wb

tool: D0: could not open output file

assistant: ```c
FILE *outInit(const char *name) {
  FILE *temp;
  temp = fopen(name, "wb");
  if (temp == NULL) {
    perror("could not open output file");
    exit(-3);
  }
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<outInit>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0xfffffffd,%edi
  call   <exit@plt>
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string

tool: D0: wb

tool: D7: could not open output file

assistant: ```c
FILE *outInit(const char *name) {
  FILE *temp;
  temp = fopen(name, "wb");
  if (temp == NULL) {
    perror("could not open output file");
    exit(-3);
  }
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<outInit>:
  endbr64
  push   %r12
  lea    D18(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %r12,%rax
  pop    %r12
  ret
L6:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0xfffffffd,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_guessed: string
name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D18: wb

tool: D5: could not open output file

assistant: ```c
FILE *outInit(const char *name) {
  FILE *temp;
  temp = fopen(name, "wb");
  if (temp == NULL) {
    perror("could not open output file");
    exit(-3);
  }
  return temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<outInit>:
  endbr64
  push   %r12
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0xfffffffd,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D1: wb

tool: D9: could not open output file

assistant: ```c
FILE *outInit(const char *name) {
  FILE *temp;
  temp = fopen(name, "wb");
  if (temp == NULL) {
    perror("could not open output file");
    exit(-3);
  }
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rd_round>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L62
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  jmp    L12
L62:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0xc(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
L12:
  movsd  %xmm0,-0x8(%rbp)
  movsd  D10(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L32
  mov    -0xc(%rbp),%eax
  jmp    L73
L32:
  movsd  -0x8(%rbp),%xmm0
  comisd D10(%rip),%xmm0
  jbe    L89
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L16
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L73
L16:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  jmp    L73
L89:
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L56
  mov    -0xc(%rbp),%eax
  jmp    L73
L56:
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L101
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L73
L101:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
L73:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D10
datatype: f64

tool: D10: 0.5

assistant: ```c
int rd_round(double n) {
  const int floor = (int)n;
  const double rem = n >= 0 ? n - floor : floor - n;
  if (rem < 0.5) {
    return floor;
  } else if (rem > 0.5) {
    return n > 0 ? floor + 1 : floor - 1;
  } else if (floor % 2 == 0) {
    return floor;
  }
  return n > 0 ? floor + 1 : floor - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rd_round>:
  endbr64
  cvttsd2si %xmm0,%eax
  comisd D7(%rip),%xmm0
  jb     L22
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
L10:
  movsd  D20(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L4
  comisd %xmm2,%xmm1
  ja     L37
  test   $0x1,%al
  je     L4
  lea    -0x1(%rax),%edx
  add    $0x1,%eax
  comisd D7(%rip),%xmm0
  cmovbe %edx,%eax
L4:
  ret
L22:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm0,%xmm1
  jmp    L10
L37:
  lea    -0x1(%rax),%edx
  add    $0x1,%eax
  comisd D7(%rip),%xmm0
  cmovbe %edx,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
data_type: byte[16]
name: retrieve_data
arguments: tag: D20
data_type: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D20: 0.5

assistant: ```c
int rd_round(double n) {
  const int floor = (int)n;
  const double rem = n >= 0 ? n - floor : floor - n;
  if (rem < 0.5) {
    return floor;
  } else if (rem > 0.5) {
    return n > 0 ? floor + 1 : floor - 1;
  } else if (floor % 2 == 0) {
    return floor;
  }
  return n > 0 ? floor + 1 : floor - 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rd_round>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  comisd %xmm3,%xmm0
  cvtsi2sd %eax,%xmm1
  jb     L20
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
L48:
  movsd  D3(%rip),%xmm1
  comisd %xmm2,%xmm1
  ja     L49
  comisd %xmm1,%xmm2
  ja     L19
  test   $0x1,%al
  je     L49
L19:
  lea    -0x1(%rax),%edx
  add    $0x1,%eax
  comisd %xmm3,%xmm0
  cmovbe %edx,%eax
L49:
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  movapd %xmm1,%xmm2
  subsd  %xmm0,%xmm2
  jmp    L48
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: f64

tool: D3: 0.5

assistant: ```c
int rd_round(double n) {
  const int floor = (int)n;
  const double rem = n >= 0 ? n - floor : floor - n;
  if (rem < 0.5) {
    return floor;
  } else if (rem > 0.5) {
    return n > 0 ? floor + 1 : floor - 1;
  } else if (floor % 2 == 0) {
    return floor;
  }
  return n > 0 ? floor + 1 : floor - 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rd_round>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  comisd %xmm3,%xmm0
  cvtsi2sd %eax,%xmm1
  jb     L26
  movapd %xmm0,%xmm2
  subsd  %xmm1,%xmm2
L35:
  movsd  D6(%rip),%xmm1
  comisd %xmm2,%xmm1
  ja     L17
  comisd %xmm1,%xmm2
  ja     L45
  test   $0x1,%al
  je     L17
L45:
  lea    -0x1(%rax),%edx
  add    $0x1,%eax
  comisd %xmm3,%xmm0
  cmovbe %edx,%eax
L17:
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movapd %xmm1,%xmm2
  subsd  %xmm0,%xmm2
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: f64

tool: D6: 0.5

assistant: ```c
int rd_round(double n) {
  const int floor = (int)n;
  const double rem = n >= 0 ? n - floor : floor - n;
  if (rem < 0.5) {
    return floor;
  } else if (rem > 0.5) {
    return n > 0 ? floor + 1 : floor - 1;
  } else if (floor % 2 == 0) {
    return floor;
  }
  return n > 0 ? floor + 1 : floor - 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<overflow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void overflow(char *recv_buff) {
  char buffer[10];
  strcpy(buffer, recv_buff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<overflow>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void overflow(char *recv_buff) {
  char buffer[10];
  strcpy(buffer, recv_buff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<overflow>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void overflow(char *recv_buff) {
  char buffer[10];
  strcpy(buffer, recv_buff);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<overflow>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rdi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void overflow(char *recv_buff) {
  char buffer[10];
  strcpy(buffer, recv_buff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cleanup_pcap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cleanup_pcap_rw@plt>
  mov    $0x0,%eax
  call   <cleanup_pcap_sg@plt>
  mov    $0x0,%eax
  call   <cleanup_pcap_mmap@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cleanup_pcap(void) {
  cleanup_pcap_rw();
  cleanup_pcap_sg();
  cleanup_pcap_mmap();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cleanup_pcap>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cleanup_pcap_rw@plt>
  mov    $0x0,%eax
  call   <cleanup_pcap_sg@plt>
  mov    $0x0,%eax
  call   <cleanup_pcap_mmap@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cleanup_pcap(void) {
  cleanup_pcap_rw();
  cleanup_pcap_sg();
  cleanup_pcap_mmap();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cleanup_pcap>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanup_pcap_rw@plt>
  xor    %eax,%eax
  call   <cleanup_pcap_sg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cleanup_pcap_mmap@plt>
```

assistant: ```c
void cleanup_pcap(void) {
  cleanup_pcap_rw();
  cleanup_pcap_sg();
  cleanup_pcap_mmap();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cleanup_pcap>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cleanup_pcap_rw@plt>
  xor    %eax,%eax
  call   <cleanup_pcap_sg@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <cleanup_pcap_mmap@plt>
```

assistant: ```c
void cleanup_pcap(void) {
  cleanup_pcap_rw();
  cleanup_pcap_sg();
  cleanup_pcap_mmap();
}
```
user: Translate the below assembly code into C programming language:

```asm
<aes_enc_128>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x8(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0xc(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x10(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x14(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x18(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x1c(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x20(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x24(%rbp),%esi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,%edi
  mov    %eax,(%rbx)
  mov    0x28(%rbp),%esi
  call   <_mm_aesenclast_si128@plt>
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void aes_enc_128(__m128i *state, __m128i *key) {
  *state = _mm_xor_si128(*state, key[0]);
  *state = _mm_aesenc_si128(*state, key[1]);
  *state = _mm_aesenc_si128(*state, key[2]);
  *state = _mm_aesenc_si128(*state, key[3]);
  *state = _mm_aesenc_si128(*state, key[4]);
  *state = _mm_aesenc_si128(*state, key[5]);
  *state = _mm_aesenc_si128(*state, key[6]);
  *state = _mm_aesenc_si128(*state, key[7]);
  *state = _mm_aesenc_si128(*state, key[8]);
  *state = _mm_aesenc_si128(*state, key[9]);
  *state = _mm_aesenclast_si128(*state, key[10]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aes_enc_128>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x8(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0xc(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x10(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x14(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x18(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x1c(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x20(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x24(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x28(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenclast_si128@plt>
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void aes_enc_128(__m128i *state, __m128i *key) {
  *state = _mm_xor_si128(*state, key[0]);
  *state = _mm_aesenc_si128(*state, key[1]);
  *state = _mm_aesenc_si128(*state, key[2]);
  *state = _mm_aesenc_si128(*state, key[3]);
  *state = _mm_aesenc_si128(*state, key[4]);
  *state = _mm_aesenc_si128(*state, key[5]);
  *state = _mm_aesenc_si128(*state, key[6]);
  *state = _mm_aesenc_si128(*state, key[7]);
  *state = _mm_aesenc_si128(*state, key[8]);
  *state = _mm_aesenc_si128(*state, key[9]);
  *state = _mm_aesenclast_si128(*state, key[10]);
}
```
user: What is the c source code of the assembly code below:

```asm
<aes_enc_128>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%esi
  mov    (%rdi),%edi
  call   <_mm_xor_si128@plt>
  mov    %eax,(%rbx)
  mov    0x4(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x8(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0xc(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x10(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x14(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x18(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x1c(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x20(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x24(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenc_si128@plt>
  mov    %eax,(%rbx)
  mov    0x28(%rbp),%esi
  mov    %eax,%edi
  call   <_mm_aesenclast_si128@plt>
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void aes_enc_128(__m128i *state, __m128i *key) {
  *state = _mm_xor_si128(*state, key[0]);
  *state = _mm_aesenc_si128(*state, key[1]);
  *state = _mm_aesenc_si128(*state, key[2]);
  *state = _mm_aesenc_si128(*state, key[3]);
  *state = _mm_aesenc_si128(*state, key[4]);
  *state = _mm_aesenc_si128(*state, key[5]);
  *state = _mm_aesenc_si128(*state, key[6]);
  *state = _mm_aesenc_si128(*state, key[7]);
  *state = _mm_aesenc_si128(*state, key[8]);
  *state = _mm_aesenc_si128(*state, key[9]);
  *state = _mm_aesenclast_si128(*state, key[10]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<numlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L6:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned numlen(unsigned num) {
  unsigned result = 1;
  while (num /= 10)
    ++result;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<numlen>:
  endbr64
  mov    %edi,%eax
  mov    $0xcccccccd,%edx
  imul   %rdx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jbe    L20
  mov    $0x1,%edx
  mov    $0xcccccccd,%esi
L8:
  add    $0x1,%edx
  mov    %eax,%ecx
  mov    %eax,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  cmp    $0x9,%ecx
  ja     L8
L7:
  mov    %edx,%eax
  ret
L20:
  mov    $0x1,%edx
  jmp    L7
```

assistant: ```c
unsigned numlen(unsigned num) {
  unsigned result = 1;
  while (num /= 10)
    ++result;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<numlen>:
  endbr64
  mov    %edi,%eax
  mov    $0xcccccccd,%ecx
  mov    $0x1,%r8d
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jbe    L11
  xchg   %ax,%ax
L8:
  mov    %eax,%eax
  add    $0x1,%r8d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  ja     L8
L11:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned numlen(unsigned num) {
  unsigned result = 1;
  while (num /= 10)
    ++result;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<numlen>:
  endbr64
  mov    %edi,%eax
  mov    $0xcccccccd,%ecx
  mov    $0x1,%r8d
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  jbe    L10
  xchg   %ax,%ax
L16:
  mov    %eax,%eax
  add    $0x1,%r8d
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edx
  ja     L16
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned numlen(unsigned num) {
  unsigned result = 1;
  while (num /= 10)
    ++result;
  return result;
}
```