user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %rbp,%rbx
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  sub    %ebp,%edx
  cmp    %eax,%edx
  jge    L300
L16:
  movzbl (%rbx),%eax
  cmp    $0x43,%al
  je     L281
  cmp    $0x4c,%al
  je     L4
  cmp    $0x58,%al
  jne    L38
  cmpb   $0x49,-0x1(%rbx)
  je     L187
  add    $0xa,%r12d
  nopw   0x0(%rax,%rax,1)
L168:
  add    $0x1,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %ebx,%edx
  sub    %ebp,%edx
  cmp    %eax,%edx
  jl     L16
L300:
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  cmp    $0x56,%al
  jne    L53
  cmpb   $0x49,-0x1(%rbx)
  je     L78
  add    $0x5,%r12d
  jmp    L168
  cs nopw 0x0(%rax,%rax,1)
L4:
  cmpb   $0x49,-0x1(%rbx)
  je     L256
  add    $0x32,%r12d
  jmp    L168
  nopl   0x0(%rax)
L281:
  cmpb   $0x49,-0x1(%rbx)
  je     L42
  add    $0x64,%r12d
  jmp    L168
L53:
  cmp    $0x49,%al
  jne    L168
  movzbl 0x1(%rbx),%eax
  test   %al,%al
  jne    L145
  cmpb   $0x49,-0x1(%rbx)
  je     L168
  add    $0x1,%r12d
  jmp    L168
L145:
  cmp    $0x49,%al
  jne    L168
  cmpb   $0x49,-0x1(%rbx)
  movzbl 0x2(%rbx),%eax
  je     L186
  test   %al,%al
  jne    L186
  add    $0x2,%r12d
  jmp    L168
L42:
  add    $0x63,%r12d
  jmp    L168
L256:
  cmpb   $0x49,-0x2(%rbx)
  je     L168
  add    $0x31,%r12d
  jmp    L168
L78:
  add    $0x4,%r12d
  jmp    L168
L187:
  cmpb   $0x49,-0x2(%rbx)
  je     L229
  add    $0x9,%r12d
  jmp    L168
L186:
  cmp    $0x49,%al
  jne    L168
  cmpb   $0x0,0x3(%rbx)
  jne    L168
  add    $0x3,%r12d
  jmp    L168
L229:
  add    $0x8,%r12d
  jmp    L168
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
type_infered: string
name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D17: %s

tool: D1: Desetichno = %d


assistant: ```c
int main() {
  char rome[5];
  int j, fin = 0;
  int C = 100, L = 50, X = 10, V = 5, I = 1, Null = 0;
  scanf("%s", rome);
  for (j = 0; j < strlen(rome); j++) {
    if (rome[j] == 'C') {
      if (rome[j - 1] != 'I')
        fin = fin + C;
      else if (rome[j - 1] == 'I')
        fin = fin + (C - I);
    }
    if (rome[j] == 'L') {
      if (rome[j - 1] != 'I')
        fin = fin + L;
      else if (rome[j - 1] == 'I') {
        if (rome[j - 2] != 'I')
          fin = fin + (L - I);
      }
    }
    if (rome[j] == 'X') {
      if (rome[j - 1] != 'I')
        fin = fin + X;
      else if (rome[j - 1] == 'I') {
        if (rome[j - 2] != 'I')
          fin = fin + (X - I);
        else if (rome[j - 2] == 'I')
          fin = fin + (X - (I + I));
      }
    }
    if (rome[j] == 'V') {
      if (rome[j - 1] != 'I')
        fin = fin + V;
      else if (rome[j - 1] == 'I')
        fin = fin + (V - I);
    }
    if (rome[j] == 'I') {
      if (rome[j + 1] == Null) {
        if (rome[j - 1] != 'I')
          fin = fin + I;
      }
      if (rome[j + 1] == 'I') {
        if (rome[j - 1] != 'I')
          if (rome[j + 2] == Null)
            fin = fin + 2 * I;
      }
      if (rome[j + 1] == 'I') {
        if (rome[j + 2] == 'I')
          if (rome[j + 3] == Null)
            fin = fin + 3 * I;
      }
    }
  }
  printf("Desetichno = %d\n", fin);
  return 0;
}
```