ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  cmpl   $0x0,-0xc(%rbp)
  jne    L20
  cmpl   $0x0,-0x8(%rbp)
  jle    L20
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L20
  mov    $0x1,%eax
  jmp    L41
L20:
  mov    $0x0,%eax
L41:
  mov    %eax,%edi
  call   <assume@plt>
  jmp    L43
L57:
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L43:
  cmpl   $0x0,-0x8(%rbp)
  jg     L57
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int low;
  int mid;
  int high;
  assume(low == 0 && mid >= 1 && high == 2 * mid);
  while (mid > 0) {
    low = low + 1;
    high = high - 1;
    mid = mid - 1;
  }
  assert(low == high);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <assume@plt>
  mov    $0x0,%eax
  cmp    %ebx,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int low;
  int mid;
  int high;
  assume(low == 0 && mid >= 1 && high == 2 * mid);
  while (mid > 0) {
    low = low + 1;
    high = high - 1;
    mid = mid - 1;
  }
  assert(low == high);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <assume@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int low;
  int mid;
  int high;
  assume(low == 0 && mid >= 1 && high == 2 * mid);
  while (mid > 0) {
    low = low + 1;
    high = high - 1;
    mid = mid - 1;
  }
  assert(low == high);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <assume@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  sete   %dil
  call   <assert@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int low;
  int mid;
  int high;
  assume(low == 0 && mid >= 1 && high == 2 * mid);
  while (mid > 0) {
    low = low + 1;
    high = high - 1;
    mid = mid - 1;
  }
  assert(low == high);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pvSendSerialCommandEx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %edi,%ecx
  mov    %cl,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %ax,-0xc(%rbp)
  mov    %edx,%eax
  mov    %al,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: f

assistant: ```c
int pvSendSerialCommandEx(char byBoardNum, char byCommand, short wData, char bWaitForAck) {
  notify_pvcall("f");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pvSendSerialCommandEx>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <notify_pvcall@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D9: f

assistant: ```c
int pvSendSerialCommandEx(char byBoardNum, char byCommand, short wData, char bWaitForAck) {
  notify_pvcall("f");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pvSendSerialCommandEx>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: string

tool: D9: f

assistant: ```c
int pvSendSerialCommandEx(char byBoardNum, char byCommand, short wData, char bWaitForAck) {
  notify_pvcall("f");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pvSendSerialCommandEx>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <notify_pvcall@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: f

assistant: ```c
int pvSendSerialCommandEx(char byBoardNum, char byCommand, short wData, char bWaitForAck) {
  notify_pvcall("f");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %al,-0x5(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L108
  cmpl   $0x0,-0x4(%rbp)
  jne    L105
L108:
  mov    $0xffffffff,%eax
  jmp    L124
L105:
  cmpb   $0x7d,-0x5(%rbp)
  je     L121
  mov    $0x1,%eax
  jmp    L124
L121:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %al,-0x5(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L150
  cmpl   $0x0,-0x4(%rbp)
  jne    L138
L150:
  mov    $0xffffffff,%eax
  jmp    L124
L138:
  cmpb   $0xd,-0x5(%rbp)
  jne    L136
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %al,-0x5(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L148
  cmpl   $0x0,-0x4(%rbp)
  jne    L136
L148:
  mov    $0xffffffff,%eax
  jmp    L124
L136:
  cmpb   $0xa,-0x5(%rbp)
  je     L92
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <ungetc@plt>
  cmp    %eax,-0x4(%rbp)
  je     L71
  mov    $0xfffffffe,%eax
  jmp    L124
L71:
  mov    $0x1,%eax
  jmp    L124
L92:
  mov    $0x0,%eax
L124:
  leave
  ret
```

assistant: ```c
int check_end(FILE *channel) {
  char c;
  int ic;
  ic = fgetc(channel);
  c = (char)ic;
  if ((ic == EOF) || (!ic))
    return (-1);
  if (c != '}')
    return (1);
  else {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c == '\r') {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c != '\n') {
    if (ic != ungetc(ic, channel))
      return (-2);
    return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_end>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <fgetc@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L5
  test   %eax,%eax
  je     L5
  mov    $0x1,%edx
  cmp    $0x7d,%al
  je     L75
L21:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L75:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L80
  test   %eax,%eax
  je     L80
  cmp    $0xd,%al
  je     L36
L50:
  mov    $0x0,%edx
  cmp    $0xa,%al
  je     L21
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <ungetc@plt>
  cmp    %ebp,%eax
  sete   %dl
  movzbl %dl,%edx
  lea    -0x2(%rdx,%rdx,2),%edx
  jmp    L21
L36:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebp
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L112
  test   %eax,%eax
  jne    L50
L112:
  mov    $0xffffffff,%edx
  jmp    L21
L5:
  mov    $0xffffffff,%edx
  jmp    L21
L80:
  mov    $0xffffffff,%edx
  jmp    L21
```

assistant: ```c
int check_end(FILE *channel) {
  char c;
  int ic;
  ic = fgetc(channel);
  c = (char)ic;
  if ((ic == EOF) || (!ic))
    return (-1);
  if (c != '}')
    return (1);
  else {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c == '\r') {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c != '\n') {
    if (ic != ungetc(ic, channel))
      return (-2);
    return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_end>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fgetc@plt>
  mov    D3(%rip),%r12
  cmp    %eax,(%r12)
  je     L99
  test   %eax,%eax
  je     L99
  cmp    $0x7d,%al
  je     L94
L38:
  mov    $0x1,%eax
L101:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L94:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  cmp    %eax,(%r12)
  je     L99
  test   %eax,%eax
  je     L99
  cmp    $0xd,%al
  je     L110
L21:
  xor    %eax,%eax
  cmp    $0xa,%dl
  je     L101
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <ungetc@plt>
  cmp    %ebx,%eax
  je     L38
  mov    $0xfffffffe,%eax
  jmp    L101
  cs nopw 0x0(%rax,%rax,1)
L110:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  cmp    %eax,(%r12)
  je     L99
  test   %eax,%eax
  jne    L21
  cs nopw 0x0(%rax,%rax,1)
L99:
  mov    $0xffffffff,%eax
  jmp    L101
```

assistant: ```c
int check_end(FILE *channel) {
  char c;
  int ic;
  ic = fgetc(channel);
  c = (char)ic;
  if ((ic == EOF) || (!ic))
    return (-1);
  if (c != '}')
    return (1);
  else {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c == '\r') {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c != '\n') {
    if (ic != ungetc(ic, channel))
      return (-2);
    return (1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_end>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <fgetc@plt>
  mov    D5(%rip),%r12
  cmp    %eax,(%r12)
  je     L58
  test   %eax,%eax
  je     L58
  cmp    $0x7d,%al
  je     L5
L110:
  mov    $0x1,%eax
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L5:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  cmp    %eax,(%r12)
  je     L58
  test   %eax,%eax
  je     L58
  cmp    $0xd,%al
  je     L10
L75:
  xor    %eax,%eax
  cmp    $0xa,%dl
  je     L31
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <ungetc@plt>
  cmp    %ebx,%eax
  je     L110
  mov    $0xfffffffe,%eax
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  cmp    %eax,(%r12)
  je     L58
  test   %eax,%eax
  jne    L75
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    $0xffffffff,%eax
  jmp    L31
```

assistant: ```c
int check_end(FILE *channel) {
  char c;
  int ic;
  ic = fgetc(channel);
  c = (char)ic;
  if ((ic == EOF) || (!ic))
    return (-1);
  if (c != '}')
    return (1);
  else {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c == '\r') {
    ic = fgetc(channel);
    c = (char)ic;
    if ((ic == EOF) || (!ic))
      return (-1);
  }
  if (c != '\n') {
    if (ic != ungetc(ic, channel))
      return (-2);
    return (1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tt_complex_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tt_complex_sub(double *out, const double *in1, const double *in2) {
  out[0] = in1[0] - in2[0];
  out[1] = in1[1] - in2[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tt_complex_sub>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void tt_complex_sub(double *out, const double *in1, const double *in2) {
  out[0] = in1[0] - in2[0];
  out[1] = in1[1] - in2[1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tt_complex_sub>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void tt_complex_sub(double *out, const double *in1, const double *in2) {
  out[0] = in1[0] - in2[0];
  out[1] = in1[1] - in2[1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tt_complex_sub>:
  endbr64
  movsd  (%rsi),%xmm0
  subsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  subsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
void tt_complex_sub(double *out, const double *in1, const double *in2) {
  out[0] = in1[0] - in2[0];
  out[1] = in1[1] - in2[1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  cmpb   $0x0,-0xa(%rbp)
  je     L26
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L47
  mov    $0x0,%eax
  jmp    L38
L47:
  movzbl -0x9(%rbp),%eax
  cmp    -0xa(%rbp),%al
  jne    L18
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L18
  subq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != '\0') {
    len = strlen(find);
    do {
      do {
        if ((sc = *s++) == '\0') {
          return (NULL);
        }
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rsi),%r12d
  test   %r12b,%r12b
  je     L31
  lea    0x1(%rsi),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  lea    0x1(%rbp),%rbx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L59
  mov    $0x0,%ebp
  jmp    L31
L57:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L29
L59:
  lea    -0x1(%rbx),%rbp
  cmp    %al,%r12b
  jne    L57
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L57
  jmp    L31
L29:
  mov    $0x0,%ebp
L31:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != '\0') {
    len = strlen(find);
    do {
      do {
        if ((sc = *s++) == '\0') {
          return (NULL);
        }
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  je     L3
  lea    0x1(%rsi),%r13
  lea    0x1(%r12),%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  movzbl (%r12),%eax
  test   %al,%al
  jne    L36
  nopl   0x0(%rax)
L43:
  xor    %r12d,%r12d
L3:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L3
  nopl   0x0(%rax,%rax,1)
L35:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L43
L36:
  lea    -0x1(%rbx),%r12
  cmp    %al,%bpl
  jne    L35
  jmp    L28
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != '\0') {
    len = strlen(find);
    do {
      do {
        if ((sc = *s++) == '\0') {
          return (NULL);
        }
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: What is the c source code of the assembly code below:

```asm
<strstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  je     L3
  lea    0x1(%rsi),%r13
  lea    0x1(%r12),%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  movzbl (%r12),%eax
  test   %al,%al
  jne    L12
  nopl   0x0(%rax)
L47:
  xor    %r12d,%r12d
L3:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L3
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L47
L12:
  lea    -0x1(%rbx),%r12
  cmp    %al,%bpl
  jne    L7
  jmp    L40
```

assistant: ```c
char *strstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != '\0') {
    len = strlen(find);
    do {
      do {
        if ((sc = *s++) == '\0') {
          return (NULL);
        }
      } while (sc != c);
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Lcd4_Shift_Right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <Lcd4_Cmd@plt>
  mov    $0xc,%edi
  call   <Lcd4_Cmd@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Lcd4_Shift_Right() {
  Lcd4_Cmd(0x01);
  Lcd4_Cmd(0x0C);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Lcd4_Shift_Right>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <Lcd4_Cmd@plt>
  mov    $0xc,%edi
  call   <Lcd4_Cmd@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Lcd4_Shift_Right() {
  Lcd4_Cmd(0x01);
  Lcd4_Cmd(0x0C);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Lcd4_Shift_Right>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <Lcd4_Cmd@plt>
  mov    $0xc,%edi
  add    $0x8,%rsp
  jmp    1050 <Lcd4_Cmd@plt>
```

assistant: ```c
void Lcd4_Shift_Right() {
  Lcd4_Cmd(0x01);
  Lcd4_Cmd(0x0C);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Lcd4_Shift_Right>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <Lcd4_Cmd@plt>
  mov    $0xc,%edi
  add    $0x8,%rsp
  jmp    1050 <Lcd4_Cmd@plt>
```

assistant: ```c
void Lcd4_Shift_Right() {
  Lcd4_Cmd(0x01);
  Lcd4_Cmd(0x0C);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<i2c_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %al,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L27
  cmpl   $0x1,-0x4(%rbp)
  je     L10
L27:
  mov    $0xffffffff,%eax
  jmp    L22
L10:
  mov    -0x4(%rbp),%eax
L22:
  leave
  ret
```

assistant: ```c
int i2c_write(int fd, unsigned char data) {
  int ret = 0;
  ret = write(fd, &data, 1);
  if ((ret == -1) || (ret != 1))
    return -1;
  else
    return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<i2c_write>:
  endbr64
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  cmp    $0x1,%eax
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int i2c_write(int fd, unsigned char data) {
  int ret = 0;
  ret = write(fd, &data, 1);
  if ((ret == -1) || (ret != 1))
    return -1;
  else
    return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<i2c_write>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  mov    $0xffffffff,%edx
  cmp    $0x1,%eax
  cmovne %edx,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int i2c_write(int fd, unsigned char data) {
  int ret = 0;
  ret = write(fd, &data, 1);
  if ((ret == -1) || (ret != 1))
    return -1;
  else
    return (ret);
}
```
user: What is the c source code of the assembly code below:

```asm
<i2c_write>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %sil,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  call   <write@plt>
  mov    $0xffffffff,%edx
  cmp    $0x1,%eax
  cmovne %edx,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int i2c_write(int fd, unsigned char data) {
  int ret = 0;
  ret = write(fd, &data, 1);
  if ((ret == -1) || (ret != 1))
    return -1;
  else
    return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L35:
  addl   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  movl   $0x0,-0x4(%rbp)
  jmp    L25
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  int i;
  int j;
  i = 0;
  while (s1[i])
    i++;
  j = 0;
  while (s2[j]) {
    s1[i + j] = s2[j];
    j++;
  }
  s1[i + j] = '\0';
  return (s1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L32
  mov    $0x1,%edx
L19:
  mov    %edx,%edi
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L19
L46:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L29
  mov    $0x1,%edx
  movslq %edi,%r8
  add    %rax,%r8
L13:
  mov    %cl,-0x1(%r8,%rdx,1)
  mov    %edx,%r9d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L13
L48:
  add    %r9d,%edi
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  ret
L32:
  mov    $0x0,%edi
  jmp    L46
L29:
  mov    $0x0,%r9d
  jmp    L48
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  int i;
  int j;
  i = 0;
  while (s1[i])
    i++;
  j = 0;
  while (s2[j]) {
    s1[i + j] = s2[j];
    j++;
  }
  s1[i + j] = '\0';
  return (s1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L26
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L2:
  lea    (%rcx,%rdx,1),%r10d
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L2
L13:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L8
  movslq %r10d,%r9
  mov    $0x1,%edx
  add    %rax,%r9
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %cl,-0x1(%r9,%rdx,1)
  mov    %edx,%r8d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L9
  add    %r10d,%r8d
  movslq %r8d,%r8
  add    %rax,%r8
L8:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rdi,%r8
  xor    %r10d,%r10d
  jmp    L13
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  int i;
  int j;
  i = 0;
  while (s1[i])
    i++;
  j = 0;
  while (s2[j]) {
    s1[i + j] = s2[j];
    j++;
  }
  s1[i + j] = '\0';
  return (s1);
}
```