ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<token_decode>:
  endbr64
  mov    $0xffffffff,%eax
  cmpb   $0x0,(%rdi)
  je     L65
  cmpb   $0x0,0x1(%rdi)
  je     L65
  cmpb   $0x0,0x2(%rdi)
  je     L65
  cmpb   $0x0,0x3(%rdi)
  je     L65
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x4(%rdi),%rbx
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L10
L20:
  add    $0x1,%r12d
L34:
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  je     L9
L10:
  shl    $0x6,%r13d
  movzbl 0x0(%rbp),%edi
  cmp    $0x3d,%dil
  je     L20
  test   %r12d,%r12d
  jg     L88
  movsbl %dil,%edi
  call   <pos@plt>
  add    %eax,%r13d
  jmp    L34
L9:
  mov    %r12d,%eax
  shl    $0x18,%eax
  or     %r13d,%eax
  cmp    $0x3,%r12d
  mov    $0xffffffff,%edx
  cmovge %edx,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L88:
  mov    $0xffffffff,%eax
  jmp    L25
L65:
  ret
```

assistant: ```c
unsigned int token_decode(const char *token) {
  int i;
  unsigned int val = 0;
  int marker = 0;
  if (!token[0] || !token[1] || !token[2] || !token[3])
    return 0xffffffff;
  for (i = 0; i < 4; i++) {
    val *= 64;
    if (token[i] == '=')
      marker++;
    else if (marker > 0)
      return 0xffffffff;
    else
      val += pos(token[i]);
  }
  if (marker > 2)
    return 0xffffffff;
  return (marker << 24) | val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<token_decode>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  cmpb   $0x0,0x1(%rdi)
  je     L15
  cmpb   $0x0,0x2(%rdi)
  je     L15
  cmpb   $0x0,0x3(%rdi)
  je     L15
  push   %r13
  lea    0x1(%rdi),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  shl    $0x6,%r12d
  xor    %ebp,%ebp
  push   %rbx
  lea    0x4(%rdi),%rbx
  sub    $0x8,%rsp
  cmp    $0x3d,%dl
  je     L13
L94:
  test   %ebp,%ebp
  jne    L5
  movsbl %dl,%edi
  call   <pos@plt>
  add    %eax,%r12d
  cmp    %rbx,%r13
  je     L69
L43:
  movzbl 0x0(%r13),%edx
  shl    $0x6,%r12d
  add    $0x1,%r13
  cmp    $0x3d,%dl
  jne    L94
L13:
  add    $0x1,%ebp
  cmp    %rbx,%r13
  jne    L43
L69:
  cmp    $0x2,%ebp
  jg     L5
  mov    %ebp,%eax
  add    $0x8,%rsp
  shl    $0x18,%eax
  pop    %rbx
  pop    %rbp
  or     %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nop
L5:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int token_decode(const char *token) {
  int i;
  unsigned int val = 0;
  int marker = 0;
  if (!token[0] || !token[1] || !token[2] || !token[3])
    return 0xffffffff;
  for (i = 0; i < 4; i++) {
    val *= 64;
    if (token[i] == '=')
      marker++;
    else if (marker > 0)
      return 0xffffffff;
    else
      val += pos(token[i]);
  }
  if (marker > 2)
    return 0xffffffff;
  return (marker << 24) | val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<token_decode>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L31
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,0x1(%rdi)
  je     L0
  cmpb   $0x0,0x2(%rdi)
  je     L0
  cmpb   $0x0,0x3(%rdi)
  je     L0
  lea    0x4(%rdi),%r13
  xor    %ebp,%ebp
  xor    %r12d,%r12d
L50:
  movsbl (%rbx),%edi
  shl    $0x6,%r12d
  cmp    $0x3d,%dil
  je     L54
  test   %ebp,%ebp
  jne    L0
  call   <pos@plt>
  add    %eax,%r12d
L68:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L50
  cmp    $0x2,%ebp
  jg     L0
  mov    %ebp,%eax
  add    $0x8,%rsp
  shl    $0x18,%eax
  pop    %rbx
  pop    %rbp
  or     %r12d,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  add    $0x1,%ebp
  jmp    L68
  nopl   (%rax)
L31:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned int token_decode(const char *token) {
  int i;
  unsigned int val = 0;
  int marker = 0;
  if (!token[0] || !token[1] || !token[2] || !token[3])
    return 0xffffffff;
  for (i = 0; i < 4; i++) {
    val *= 64;
    if (token[i] == '=')
      marker++;
    else if (marker > 0)
      return 0xffffffff;
    else
      val += pos(token[i]);
  }
  if (marker > 2)
    return 0xffffffff;
  return (marker << 24) | val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <sbrk@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x1000,%edi
  call   <sbrk@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L7
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L22
L7:
  mov    $0x0,%edi
  call   <sbrk@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1000(%rax),%edx
  mov    -0x8(%rbp),%rax
  cmp    %eax,%edx
  je     L42
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L22
L42:
  mov    $0xfffff000,%edi
  call   <sbrk@plt>
  mov    $0x0,%edi
  call   <sbrk@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L28
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L22
L28:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string
name: disassemble_data
arguments: data_tag: D37
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D39
type_infered: string

tool: D5: testing sbrk


tool: D37: sbrk failed on increment


tool: D9: sbrk failed on increment a PAGE_SIZE


tool: D7: sbrk failed on decrement a PAGE_SIZE


tool: D39: Test passed OK


assistant: ```c
int main() {
  printf("testing sbrk\n");
  void *addr, *addr_new;
  addr = sbrk(0);
  addr_new = sbrk(0x1000);
  if (addr != addr_new) {
    printf("sbrk failed on increment\n");
    return 1;
  }
  addr_new = sbrk(0);
  if ((unsigned int)addr + 0x1000 != (unsigned int)addr_new) {
    printf("sbrk failed on increment a PAGE_SIZE\n");
    return 1;
  }
  sbrk(-0x1000);
  addr_new = sbrk(0);
  if (addr != addr_new) {
    printf("sbrk failed on decrement a PAGE_SIZE\n");
    return 1;
  }
  printf("Test passed OK\n");
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <sbrk@plt>
  mov    %rax,%rbx
  mov    $0x1000,%edi
  call   <sbrk@plt>
  cmp    %rax,%rbx
  je     L50
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L48:
  pop    %rbx
  ret
L50:
  mov    $0x0,%edi
  call   <sbrk@plt>
  lea    0x1000(%rbx),%edx
  cmp    %eax,%edx
  je     L34
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L48
L34:
  mov    $0xfffff000,%edi
  call   <sbrk@plt>
  mov    $0x0,%edi
  call   <sbrk@plt>
  cmp    %rax,%rbx
  je     L19
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L48
L19:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  jmp    L48
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D37
datatype: string
name: extract_symbolic_data
arguments: tag: D24
datatype: string
name: extract_symbolic_data
arguments: tag: D28
datatype: string

tool: D13: testing sbrk


tool: D3: sbrk failed on increment


tool: D37: sbrk failed on increment a PAGE_SIZE


tool: D24: sbrk failed on decrement a PAGE_SIZE


tool: D28: Test passed OK


assistant: ```c
int main() {
  printf("testing sbrk\n");
  void *addr, *addr_new;
  addr = sbrk(0);
  addr_new = sbrk(0x1000);
  if (addr != addr_new) {
    printf("sbrk failed on increment\n");
    return 1;
  }
  addr_new = sbrk(0);
  if ((unsigned int)addr + 0x1000 != (unsigned int)addr_new) {
    printf("sbrk failed on increment a PAGE_SIZE\n");
    return 1;
  }
  sbrk(-0x1000);
  addr_new = sbrk(0);
  if (addr != addr_new) {
    printf("sbrk failed on decrement a PAGE_SIZE\n");
    return 1;
  }
  printf("Test passed OK\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <sbrk@plt>
  mov    $0x1000,%edi
  mov    %rax,%rbx
  call   <sbrk@plt>
  cmp    %rax,%rbx
  je     L17
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
L17:
  xor    %edi,%edi
  call   <sbrk@plt>
  lea    0x1000(%rbx),%edx
  cmp    %eax,%edx
  je     L23
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
L23:
  mov    $0xfffff000,%edi
  call   <sbrk@plt>
  xor    %edi,%edi
  call   <sbrk@plt>
  cmp    %rax,%rbx
  je     L25
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
L25:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D26
data_type: string
name: unpack_data
arguments: data_label: D49
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string
name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D36
data_type: string

tool: D26: testing sbrk


tool: D49: sbrk failed on increment


tool: D0: sbrk failed on increment a PAGE_SIZE


tool: D7: sbrk failed on decrement a PAGE_SIZE


tool: D36: Test passed OK


assistant: ```c
int main() {
  printf("testing sbrk\n");
  void *addr, *addr_new;
  addr = sbrk(0);
  addr_new = sbrk(0x1000);
  if (addr != addr_new) {
    printf("sbrk failed on increment\n");
    return 1;
  }
  addr_new = sbrk(0);
  if ((unsigned int)addr + 0x1000 != (unsigned int)addr_new) {
    printf("sbrk failed on increment a PAGE_SIZE\n");
    return 1;
  }
  sbrk(-0x1000);
  addr_new = sbrk(0);
  if (addr != addr_new) {
    printf("sbrk failed on decrement a PAGE_SIZE\n");
    return 1;
  }
  printf("Test passed OK\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D29(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <sbrk@plt>
  mov    $0x1000,%edi
  mov    %rax,%rbx
  call   <sbrk@plt>
  cmp    %rax,%rbx
  je     L26
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
L26:
  xor    %edi,%edi
  call   <sbrk@plt>
  lea    0x1000(%rbx),%edx
  cmp    %eax,%edx
  je     L17
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
L17:
  mov    $0xfffff000,%edi
  call   <sbrk@plt>
  xor    %edi,%edi
  call   <sbrk@plt>
  cmp    %rax,%rbx
  je     L28
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
L28:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D21
type: string
name: parse_data
arguments: data_tag: D49
type: string
name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D29: testing sbrk


tool: D21: sbrk failed on increment


tool: D49: sbrk failed on increment a PAGE_SIZE


tool: D7: sbrk failed on decrement a PAGE_SIZE


tool: D17: Test passed OK


assistant: ```c
int main() {
  printf("testing sbrk\n");
  void *addr, *addr_new;
  addr = sbrk(0);
  addr_new = sbrk(0x1000);
  if (addr != addr_new) {
    printf("sbrk failed on increment\n");
    return 1;
  }
  addr_new = sbrk(0);
  if ((unsigned int)addr + 0x1000 != (unsigned int)addr_new) {
    printf("sbrk failed on increment a PAGE_SIZE\n");
    return 1;
  }
  sbrk(-0x1000);
  addr_new = sbrk(0);
  if (addr != addr_new) {
    printf("sbrk failed on decrement a PAGE_SIZE\n");
    return 1;
  }
  printf("Test passed OK\n");
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rbx
  lea    D36(%rip),%rbp
  lea    D23(%rip),%r12
  lea    D16(%rip),%r13
  jmp    L55
L80:
  mov    %r12,%rdi
  call   <printf@plt>
L55:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L9
  mov    0x4(%rsp),%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%esi
  je     L80
  cmp    $0x1,%eax
  je     L101
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L55
L101:
  test   %esi,%esi
  je     L117
  mov    $0x0,%r14d
L126:
  lea    (%r14,%r14,4),%ecx
  movslq %esi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  lea    (%rsi,%rcx,2),%r14d
  mov    %eax,%esi
  test   %eax,%eax
  jne    L126
L5:
  mov    %r14d,%edi
  call   <check_prime@plt>
  cmp    $0x1,%eax
  jne    L8
  mov    0x4(%rsp),%esi
  cmp    %r14d,%esi
  jne    L112
L8:
  mov    0x4(%rsp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L55
L117:
  mov    %esi,%r14d
  jmp    L5
L112:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L55
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D36
type_guessed: string
name: unpack_data
arguments: label: D23
type_guessed: string
name: unpack_data
arguments: label: D16
type_guessed: string

tool: D11: %d

tool: D36: %d is not prime.


tool: D23: %d is prime.


tool: D16: %d is emirp.


assistant: ```c
int main() {
  int i, n, result;
  int p, num1, num2, num;
  while (scanf("%d", &n) == 1) {
    result = check_prime(n);
    if (n == 1) {
      printf("%d is prime.\n", n);
    } else if (result == 1) {
      num1 = n;
      num2 = 0;
      while (num1 != 0) {
        p = num1 % 10;
        num2 = p + num2 * 10;
        num1 = num1 / 10;
      }
      num = check_prime(num2);
      if (num == 1 && num2 != n) {
        printf("%d is emirp.\n", n);
      } else {
        printf("%d is prime.\n", n);
      }
    } else {
      printf("%d is not prime.\n", n);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D24(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L39:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L88
L76:
  mov    0x4(%rsp),%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%esi
  je     L106
  cmp    $0x1,%eax
  je     L107
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L76
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L107:
  xor    %r15d,%r15d
  test   %esi,%esi
  je     L103
  nopw   0x0(%rax,%rax,1)
L92:
  movslq %esi,%rax
  mov    %esi,%edx
  lea    (%r15,%r15,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  lea    (%rsi,%rcx,2),%r15d
  mov    %eax,%esi
  test   %eax,%eax
  jne    L92
L103:
  mov    %r15d,%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%eax
  jne    L106
  cmp    %r15d,%esi
  jne    L83
L106:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L39
L83:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L39
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D18
type: string
name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D24
type: string

tool: D7: %d is emirp.


tool: D18: %d is prime.


tool: D26: %d is not prime.


tool: D24: %d

assistant: ```c
int main() {
  int i, n, result;
  int p, num1, num2, num;
  while (scanf("%d", &n) == 1) {
    result = check_prime(n);
    if (n == 1) {
      printf("%d is prime.\n", n);
    } else if (result == 1) {
      num1 = n;
      num2 = 0;
      while (num1 != 0) {
        p = num1 % 10;
        num2 = p + num2 * 10;
        num1 = num1 / 10;
      }
      num = check_prime(num2);
      if (num == 1 && num2 != n) {
        printf("%d is emirp.\n", n);
      } else {
        printf("%d is prime.\n", n);
      }
    } else {
      printf("%d is not prime.\n", n);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D27(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D21(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
L55:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L77
L1:
  mov    0x4(%rsp),%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%esi
  je     L72
  cmp    $0x1,%eax
  je     L70
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L1
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L108
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  xor    %r15d,%r15d
  test   %esi,%esi
  je     L47
  nopw   0x0(%rax,%rax,1)
L49:
  movslq %esi,%rax
  mov    %esi,%edx
  lea    (%r15,%r15,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  lea    (%rsi,%rcx,2),%r15d
  mov    %eax,%esi
  test   %eax,%eax
  jne    L49
L47:
  mov    %r15d,%edi
  call   <check_prime@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x1,%eax
  jne    L72
  cmp    %r15d,%esi
  jne    L18
L72:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L55
L18:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L55
L108:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D27
type_guessed: string
name: disassemble_data
arguments: data_label: D0
type_guessed: string
name: disassemble_data
arguments: data_label: D21
type_guessed: string

tool: D16: %d is emirp.


tool: D27: %d is prime.


tool: D0: %d is not prime.


tool: D21: %d

assistant: ```c
int main() {
  int i, n, result;
  int p, num1, num2, num;
  while (scanf("%d", &n) == 1) {
    result = check_prime(n);
    if (n == 1) {
      printf("%d is prime.\n", n);
    } else if (result == 1) {
      num1 = n;
      num2 = 0;
      while (num1 != 0) {
        p = num1 % 10;
        num2 = p + num2 * 10;
        num1 = num1 / 10;
      }
      num = check_prime(num2);
      if (num == 1 && num2 != n) {
        printf("%d is emirp.\n", n);
      } else {
        printf("%d is prime.\n", n);
      }
    } else {
      printf("%d is not prime.\n", n);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f3@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  f3();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f3@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f3();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f3@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f3();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f3@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f3();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L72
L45:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  jmp    L44
L47:
  addq   $0x1,-0x18(%rbp)
L72:
  mov    -0x18(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L45
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L74
L24:
  addq   $0x8,-0x10(%rbp)
L74:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    D14(%rip),%rax
  mov    (%rax),%rsi
  mov    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  div    %rsi
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  not    %rax
  and    %rax,%rdx
  mov    %rdx,%rcx
  mov    D14(%rip),%rax
  mov    (%rax),%rdi
  mov    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  div    %rdi
  mov    %rax,%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  shr    %rax
  add    $0x1,%rax
  imul   %rdx,%rax
  and    %rcx,%rax
  test   %rax,%rax
  je     L24
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L54
L77:
  addq   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
L44:
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  const char *a = s;
  typedef size_t __attribute__((__may_alias__)) word;
  const word *w;
  for (; (uintptr_t)s % (sizeof(size_t)); s++)
    if (!*s)
      return s - a;
  for (w = (const void *)s; !((*w) - ((size_t)-1 / UCHAR_MAX) & ~(*w) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))); w++)
    ;
  s = (const void *)w;
  for (; *s; s++)
    ;
  return s - a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  mov    %rdi,%r8
  test   $0x7,%dil
  je     L47
  mov    %rdi,%rcx
L22:
  cmpb   $0x0,(%rcx)
  je     L44
  add    $0x1,%rcx
  test   $0x7,%cl
  jne    L22
L3:
  mov    (%rcx),%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%rdi
  mov    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  div    %rdi
  shr    %rdi
  add    $0x1,%rdi
  imul   %rax,%rdi
  mov    %rsi,%rdx
  sub    %rax,%rdx
  not    %rsi
  and    %rsi,%rdx
  test   %rdi,%rdx
  jne    L29
L63:
  add    $0x8,%rcx
  mov    (%rcx),%rdx
  mov    %rdx,%rsi
  sub    %rax,%rsi
  not    %rdx
  and    %rsi,%rdx
  test   %rdi,%rdx
  je     L63
L29:
  cmpb   $0x0,(%rcx)
  je     L43
L53:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L53
L43:
  mov    %rcx,%rax
  sub    %r8,%rax
  ret
L44:
  mov    %rcx,%rax
  sub    %r8,%rax
  ret
L47:
  mov    %rdi,%rcx
  jmp    L3
```

assistant: ```c
size_t strlen(const char *s) {
  const char *a = s;
  typedef size_t __attribute__((__may_alias__)) word;
  const word *w;
  for (; (uintptr_t)s % (sizeof(size_t)); s++)
    if (!*s)
      return s - a;
  for (w = (const void *)s; !((*w) - ((size_t)-1 / UCHAR_MAX) & ~(*w) & (((size_t)-1 / UCHAR_MAX) * (UCHAR_MAX / 2 + 1))); w++)
    ;
  s = (const void *)w;
  for (; *s; s++)
    ;
  return s - a;
}
```