ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<prepare_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x54(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    -0x54(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x17(%rax),%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1e,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x54(%rbp),%ecx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x50(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x30(%rbp),%rax
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x2(%rax),%edx
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x34(%rbp)
  jmp    L26
L35:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L34
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
L34:
  addl   $0x1,-0x34(%rbp)
L26:
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L35
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_infered: string
name: disassemble_data
arguments: label: D5
type_infered: string

tool: D15: %d

tool: D5: %d:CONTENT_LENGTH
%d
SCGI
1
,

assistant: ```c
void prepare_header(char **header, int *header_length, int body_length) {
  char tmp[30];
  assert(header);
  assert(header_length);
  assert(body_length >= 0);
  *header_length = 23 + sprintf(tmp, "%d", body_length);
  *header = xmalloc(*header_length + 30);
  sprintf(*header, "%d:CONTENT_LENGTH\n%d\nSCGI\n1\n,", *header_length, body_length);
  *header_length += 2 + sprintf(tmp, "%d", *header_length);
  for (int i = 0; i < *header_length; ++i)
    if ((*header)[i] == '\n')
      (*header)[i] = '\x00';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prepare_header>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <assert@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %r12d,%edi
  not    %edi
  shr    $0x1f,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %rsp,%r13
  mov    %r12d,%edx
  lea    D12(%rip),%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0x17(%rax),%edx
  mov    %edx,(%rbx)
  lea    0x35(%rax),%edi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  movslq %eax,%rdi
  mov    %rdi,0x0(%rbp)
  mov    %r12d,%ecx
  mov    (%rbx),%edx
  lea    D6(%rip),%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    (%rbx),%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    (%rbx),%edx
  lea    0x2(%rdx,%rax,1),%eax
  mov    %eax,(%rbx)
  test   %eax,%eax
  jle    L47
  mov    $0x0,%eax
  jmp    L41
L54:
  add    $0x1,%rax
  cmp    %eax,(%rbx)
  jle    L47
L41:
  mov    %rax,%rdx
  add    0x0(%rbp),%rdx
  cmpb   $0xa,(%rdx)
  jne    L54
  movb   $0x0,(%rdx)
  jmp    L54
L47:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D6
type: string

tool: D12: %d

tool: D6: %d:CONTENT_LENGTH
%d
SCGI
1
,

assistant: ```c
void prepare_header(char **header, int *header_length, int body_length) {
  char tmp[30];
  assert(header);
  assert(header_length);
  assert(body_length >= 0);
  *header_length = 23 + sprintf(tmp, "%d", body_length);
  *header = xmalloc(*header_length + 30);
  sprintf(*header, "%d:CONTENT_LENGTH\n%d\nSCGI\n1\n,", *header_length, body_length);
  *header_length += 2 + sprintf(tmp, "%d", *header_length);
  for (int i = 0; i < *header_length; ++i)
    if ((*header)[i] == '\n')
      (*header)[i] = '\x00';
}
```
user: Translate the below assembly code into C programming language:

```asm
<prepare_header>:
  endbr64
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r12d,%edi
  xor    %eax,%eax
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %r14,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  lea    0x17(%rax),%edx
  lea    0x35(%rax),%edi
  xor    %eax,%eax
  mov    %edx,(%rbx)
  call   <xmalloc@plt>
  mov    (%rbx),%edx
  mov    %r12d,%ecx
  lea    D1(%rip),%rsi
  movslq %eax,%rdi
  xor    %eax,%eax
  mov    %rdi,0x0(%rbp)
  call   <sprintf@plt>
  mov    (%rbx),%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    (%rbx),%edx
  lea    0x2(%rdx,%rax,1),%eax
  mov    %eax,(%rbx)
  test   %eax,%eax
  jle    L16
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L30:
  mov    0x0(%rbp),%rdx
  add    %rax,%rdx
  cmpb   $0xa,(%rdx)
  jne    L9
  movb   $0x0,(%rdx)
L9:
  add    $0x1,%rax
  cmp    %eax,(%rbx)
  jg     L30
L16:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D1
type: string

tool: D13: %d

tool: D1: %d:CONTENT_LENGTH
%d
SCGI
1
,

assistant: ```c
void prepare_header(char **header, int *header_length, int body_length) {
  char tmp[30];
  assert(header);
  assert(header_length);
  assert(body_length >= 0);
  *header_length = 23 + sprintf(tmp, "%d", body_length);
  *header = xmalloc(*header_length + 30);
  sprintf(*header, "%d:CONTENT_LENGTH\n%d\nSCGI\n1\n,", *header_length, body_length);
  *header_length += 2 + sprintf(tmp, "%d", *header_length);
  for (int i = 0; i < *header_length; ++i)
    if ((*header)[i] == '\n')
      (*header)[i] = '\x00';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prepare_header>:
  endbr64
  push   %r14
  lea    D6(%rip),%r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <assert@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <assert@plt>
  mov    %r12d,%edi
  xor    %eax,%eax
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %r14,%rsi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  lea    0x17(%rax),%edx
  lea    0x35(%rax),%edi
  xor    %eax,%eax
  mov    %edx,(%rbx)
  call   <xmalloc@plt>
  mov    (%rbx),%edx
  mov    %r12d,%ecx
  lea    D8(%rip),%rsi
  movslq %eax,%rdi
  xor    %eax,%eax
  mov    %rdi,0x0(%rbp)
  call   <sprintf@plt>
  mov    (%rbx),%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    (%rbx),%edx
  lea    0x2(%rdx,%rax,1),%ecx
  mov    %ecx,(%rbx)
  test   %ecx,%ecx
  jle    L52
  xor    %eax,%eax
L41:
  mov    0x0(%rbp),%rsi
L21:
  lea    (%rsi,%rax,1),%rdx
  cmpb   $0xa,(%rdx)
  je     L14
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L21
L52:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rdx)
  mov    (%rbx),%ecx
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L41
  jmp    L52
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D6: %d

tool: D8: %d:CONTENT_LENGTH
%d
SCGI
1
,

assistant: ```c
void prepare_header(char **header, int *header_length, int body_length) {
  char tmp[30];
  assert(header);
  assert(header_length);
  assert(body_length >= 0);
  *header_length = 23 + sprintf(tmp, "%d", body_length);
  *header = xmalloc(*header_length + 30);
  sprintf(*header, "%d:CONTENT_LENGTH\n%d\nSCGI\n1\n,", *header_length, body_length);
  *header_length += 2 + sprintf(tmp, "%d", *header_length);
  for (int i = 0; i < *header_length; ++i)
    if ((*header)[i] == '\n')
      (*header)[i] = '\x00';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<subtract_array_dbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L2:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  cvtss2sd %xmm1,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
  addq   $0x4,-0x18(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subtract_array_dbl(float *ptr, int n, void *target) {
  double *t = (double *)target;
  int i;
  for (i = 0; i < n; i++, ptr++)
    t[i] -= (double)(*ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<subtract_array_dbl>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    %esi,%esi
  mov    $0x0,%eax
L2:
  pxor   %xmm1,%xmm1
  cvtss2sd (%rdi,%rax,4),%xmm1
  movsd  (%rdx,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
L18:
  ret
```

assistant: ```c
void subtract_array_dbl(float *ptr, int n, void *target) {
  double *t = (double *)target;
  int i;
  for (i = 0; i < n; i++, ptr++)
    t[i] -= (double)(*ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<subtract_array_dbl>:
  endbr64
  test   %esi,%esi
  jle    L8
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   (%rax)
L16:
  movsd  (%rdx,%rax,8),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rdi,%rax,4),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L16
L8:
  ret
```

assistant: ```c
void subtract_array_dbl(float *ptr, int n, void *target) {
  double *t = (double *)target;
  int i;
  for (i = 0; i < n; i++, ptr++)
    t[i] -= (double)(*ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<subtract_array_dbl>:
  endbr64
  mov    %esi,%ecx
  mov    %rdx,%rsi
  test   %ecx,%ecx
  jle    L55
  lea    -0x1(%rcx),%eax
  cmp    $0x2,%eax
  jbe    L16
  mov    %ecx,%r8d
  mov    %rdx,%rax
  mov    %rdi,%rdx
  shr    $0x2,%r8d
  sub    $0x1,%r8d
  shl    $0x5,%r8
  lea    0x20(%rsi,%r8,1),%r8
  nopw   0x0(%rax,%rax,1)
L64:
  movupd 0x10(%rax),%xmm1
  movupd (%rax),%xmm2
  movlps 0x8(%rdx),%xmm3
  add    $0x20,%rax
  cvtps2pd %xmm3,%xmm0
  subpd  %xmm0,%xmm1
  cvtps2pd (%rdx),%xmm0
  subpd  %xmm0,%xmm2
  add    $0x10,%rdx
  movups %xmm2,-0x20(%rax)
  movups %xmm1,-0x10(%rax)
  cmp    %r8,%rax
  jne    L64
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %eax,%ecx
  je     L46
L62:
  movslq %eax,%rdx
  pxor   %xmm1,%xmm1
  shl    $0x3,%rdx
  cvtss2sd (%rdi),%xmm1
  lea    (%rsi,%rdx,1),%r8
  movsd  (%r8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8)
  lea    0x1(%rax),%r8d
  cmp    %r8d,%ecx
  jle    L55
  lea    0x8(%rsi,%rdx,1),%r8
  pxor   %xmm1,%xmm1
  add    $0x2,%eax
  movsd  (%r8),%xmm0
  cvtss2sd 0x4(%rdi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8)
  cmp    %eax,%ecx
  jle    L55
  lea    0x10(%rsi,%rdx,1),%rax
  pxor   %xmm1,%xmm1
  movsd  (%rax),%xmm0
  cvtss2sd 0x8(%rdi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
L55:
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  ret
L16:
  xor    %eax,%eax
  jmp    L62
```

assistant: ```c
void subtract_array_dbl(float *ptr, int n, void *target) {
  double *t = (double *)target;
  int i;
  for (i = 0; i < n; i++, ptr++)
    t[i] -= (double)(*ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<matrix4RotateXf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x3c,%rax
  movss  D7(%rip),%xmm0
  movss  %xmm0,(%rax)
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rdx
  add    $0x34,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rdx
  add    $0x2c,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rdx
  add    $0x1c,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rdx
  add    $0xc,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rdx
  add    $0x4,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rdx
  add    $0x14,%rdx
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x24,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  movss  %xmm0,(%rax)
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movss  D13(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: byte[4]
name: read_data
arguments: data_label: D13
datatype: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3f]}

tool: {"D13": [0x00,0x00,0x00,0x80]}

assistant: ```c
void matrix4RotateXf(float *mat, float rot) {
  mat[0] = mat[15] = 1;
  mat[1] = mat[2] = mat[3] = mat[4] = mat[7] = mat[8] = mat[11] = mat[12] = mat[13] = mat[14] = 0;
  mat[5] = mat[10] = (float)cos(rot);
  mat[6] = -(mat[9] = (float)sin(rot));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix4RotateXf>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  movaps %xmm0,%xmm1
  movss  D3(%rip),%xmm0
  movss  %xmm0,0x3c(%rdi)
  movss  %xmm0,(%rdi)
  movl   $0x0,0x38(%rdi)
  movl   $0x0,0x34(%rdi)
  movl   $0x0,0x30(%rdi)
  movl   $0x0,0x2c(%rdi)
  movl   $0x0,0x20(%rdi)
  movl   $0x0,0x1c(%rdi)
  movl   $0x0,0x10(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0x4(%rdi)
  movss  %xmm1,0xc(%rsp)
  movaps %xmm1,%xmm0
  call   <cos@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x28(%rbx)
  movss  %xmm0,0x14(%rbx)
  movss  0xc(%rsp),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x24(%rbx)
  xorps  D0(%rip),%xmm0
  movss  %xmm0,0x18(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: byte[4]
name: disassemble_data
arguments: data_tag: D0
type_infered: byte[16]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

tool: {"D0": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void matrix4RotateXf(float *mat, float rot) {
  mat[0] = mat[15] = 1;
  mat[1] = mat[2] = mat[3] = mat[4] = mat[7] = mat[8] = mat[11] = mat[12] = mat[13] = mat[14] = 0;
  mat[5] = mat[10] = (float)cos(rot);
  mat[6] = -(mat[9] = (float)sin(rot));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix4RotateXf>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movq   $0x0,0x2c(%rdi)
  movq   $0x0,0x34(%rdi)
  movl   $0x3f800000,0x3c(%rdi)
  movq   $0x0,0x1c(%rdi)
  movq   $0x3f800000,(%rdi)
  movq   $0x0,0x8(%rdi)
  movl   $0x0,0x10(%rdi)
  movss  %xmm0,0xc(%rsp)
  call   <cos@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  movss  %xmm1,0x28(%rbx)
  movss  %xmm1,0x14(%rbx)
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x24(%rbx)
  xorps  D5(%rip),%xmm0
  movss  %xmm0,0x18(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: byte[16]

tool: {"D5": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void matrix4RotateXf(float *mat, float rot) {
  mat[0] = mat[15] = 1;
  mat[1] = mat[2] = mat[3] = mat[4] = mat[7] = mat[8] = mat[11] = mat[12] = mat[13] = mat[14] = 0;
  mat[5] = mat[10] = (float)cos(rot);
  mat[6] = -(mat[9] = (float)sin(rot));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrix4RotateXf>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movl   $0x3f800000,0x3c(%rdi)
  movq   $0x0,0x1c(%rdi)
  movl   $0x0,0x10(%rdi)
  movups %xmm1,0x2c(%rdi)
  movss  D13(%rip),%xmm1
  movups %xmm1,(%rdi)
  movss  %xmm0,0xc(%rsp)
  call   <cos@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  movss  %xmm1,0x28(%rbx)
  movss  %xmm1,0x14(%rbx)
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x24(%rbx)
  xorps  D18(%rip),%xmm0
  movss  %xmm0,0x18(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type_infered: byte[4]
name: parse_data
arguments: tag: D18
type_infered: byte[16]

tool: {"D13": [0x00,0x00,0x80,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void matrix4RotateXf(float *mat, float rot) {
  mat[0] = mat[15] = 1;
  mat[1] = mat[2] = mat[3] = mat[4] = mat[7] = mat[8] = mat[11] = mat[12] = mat[13] = mat[14] = 0;
  mat[5] = mat[10] = (float)cos(rot);
  mat[6] = -(mat[9] = (float)sin(rot));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L32
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <p>
  jmp    L14
L32:
  cmpl   $0x0,-0x8(%rbp)
  jle    L9
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <p>
  jmp    L14
L9:
  mov    -0x4(%rbp),%eax
L14:
  leave
  ret
```

assistant: ```c
int p(int m, int n, int r) {
  if (r > 0) {
    return p(m, r - 1, n);
  } else {
    if (n > 0) {
      return p(r, n - 1, m);
    } else {
      return m;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<p>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r8d
  mov    %esi,%ecx
  mov    %edx,%edi
  test   %edx,%edx
  jg     L10
  mov    %r8d,%eax
  test   %esi,%esi
  jg     L0
L35:
  add    $0x8,%rsp
  ret
L10:
  lea    -0x1(%rdx),%esi
  mov    %ecx,%edx
  mov    %r8d,%edi
  call   <p>
  jmp    L35
L0:
  lea    -0x1(%rsi),%esi
  mov    %r8d,%edx
  call   <p>
  jmp    L35
```

assistant: ```c
int p(int m, int n, int r) {
  if (r > 0) {
    return p(m, r - 1, n);
  } else {
    if (n > 0) {
      return p(r, n - 1, m);
    } else {
      return m;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<p>:
  endbr64
  mov    %edi,%eax
  cs nopw 0x0(%rax,%rax,1)
L26:
  test   %edx,%edx
  jle    L11
L30:
  lea    -0x1(%rdx),%ecx
  mov    %esi,%edx
  mov    %ecx,%esi
  test   %edx,%edx
  jg     L30
L11:
  test   %esi,%esi
  jle    L21
  mov    %eax,%ecx
  sub    $0x1,%esi
  mov    %edx,%eax
  mov    %ecx,%edx
  jmp    L26
  xchg   %ax,%ax
L21:
  ret
```

assistant: ```c
int p(int m, int n, int r) {
  if (r > 0) {
    return p(m, r - 1, n);
  } else {
    if (n > 0) {
      return p(r, n - 1, m);
    } else {
      return m;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<p>:
  endbr64
  mov    %edi,%eax
  cs nopw 0x0(%rax,%rax,1)
L18:
  test   %edx,%edx
  jle    L14
L27:
  lea    -0x1(%rdx),%ecx
  mov    %esi,%edx
  mov    %ecx,%esi
  test   %edx,%edx
  jg     L27
L14:
  test   %esi,%esi
  jle    L16
  mov    %eax,%ecx
  sub    $0x1,%esi
  mov    %edx,%eax
  mov    %ecx,%edx
  jmp    L18
  xchg   %ax,%ax
L16:
  ret
```

assistant: ```c
int p(int m, int n, int r) {
  if (r > 0) {
    return p(m, r - 1, n);
  } else {
    if (n > 0) {
      return p(r, n - 1, m);
    } else {
      return m;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ruspma_setup_symbols>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ruspma_setup_symbol_constants@plt>
  mov    $0x0,%eax
  call   <ruspma_setup_default_symbols@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ruspma_setup_symbols() {
  ruspma_setup_symbol_constants();
  ruspma_setup_default_symbols();
}
```
user: Translate the below assembly code into C programming language:

```asm
<ruspma_setup_symbols>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ruspma_setup_symbol_constants@plt>
  mov    $0x0,%eax
  call   <ruspma_setup_default_symbols@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ruspma_setup_symbols() {
  ruspma_setup_symbol_constants();
  ruspma_setup_default_symbols();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ruspma_setup_symbols>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ruspma_setup_symbol_constants@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ruspma_setup_default_symbols@plt>
```

assistant: ```c
void ruspma_setup_symbols() {
  ruspma_setup_symbol_constants();
  ruspma_setup_default_symbols();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ruspma_setup_symbols>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ruspma_setup_symbol_constants@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ruspma_setup_default_symbols@plt>
```

assistant: ```c
void ruspma_setup_symbols() {
  ruspma_setup_symbol_constants();
  ruspma_setup_default_symbols();
}
```