ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__atomic_cas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  lock cmpxchg %rdx,(%rcx)
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long __atomic_cas(volatile long *p, long test, long set) {
  asm volatile("lock; cmpxchg %3, %1" : "=a"(test), "=m"(*p) : "a"(test), "r"(set) : "memory");
  return test;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__atomic_cas>:
  endbr64
  mov    %rsi,%rax
  lock cmpxchg %rdx,(%rdi)
  ret
```

assistant: ```c
long __atomic_cas(volatile long *p, long test, long set) {
  asm volatile("lock; cmpxchg %3, %1" : "=a"(test), "=m"(*p) : "a"(test), "r"(set) : "memory");
  return test;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__atomic_cas>:
  endbr64
  mov    %rsi,%rax
  lock cmpxchg %rdx,(%rdi)
  ret
```

assistant: ```c
long __atomic_cas(volatile long *p, long test, long set) {
  asm volatile("lock; cmpxchg %3, %1" : "=a"(test), "=m"(*p) : "a"(test), "r"(set) : "memory");
  return test;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__atomic_cas>:
  endbr64
  mov    %rsi,%rax
  lock cmpxchg %rdx,(%rdi)
  ret
```

assistant: ```c
long __atomic_cas(volatile long *p, long test, long set) {
  asm volatile("lock; cmpxchg %3, %1" : "=a"(test), "=m"(*p) : "a"(test), "r"(set) : "memory");
  return test;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,-0x48(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x1,-0x3c(%rbp)
  movl   $0x2,-0x38(%rbp)
  movl   $0x3,-0x34(%rbp)
  movl   $0x4,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x8,-0x18(%rbp)
  lea    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <check_cursor_pos@plt>
  mov    %eax,-0x4c(%rbp)
  mov    $0x0,%eax
  call   <lou_free@plt>
  mov    -0x4c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string

tool: D9: greetings  

tool: D0: compress.cti,en-us-g2.ctb

assistant: ```c
int main(int argc, char **argv) {
  const char *str2 = "greetings  ";
  const int expected_pos2[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 7, 8};
  int result = check_cursor_pos("compress.cti,en-us-g2.ctb", str2, expected_pos2);
  lou_free();
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  movl   $0x8,0x28(%rsp)
  mov    %rsp,%rdx
  lea    D9(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <check_cursor_pos@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <lou_free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %ebx,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string

tool: D9: greetings  

tool: D3: compress.cti,en-us-g2.ctb

assistant: ```c
int main(int argc, char **argv) {
  const char *str2 = "greetings  ";
  const int expected_pos2[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 7, 8};
  int result = check_cursor_pos("compress.cti,en-us-g2.ctb", str2, expected_pos2);
  lou_free();
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rsi
  lea    D7(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x100000000,%rax
  mov    %rsp,%rdx
  movl   $0x8,0x28(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  add    $0x2,%rax
  mov    %rax,0x20(%rsp)
  call   <check_cursor_pos@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <lou_free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D17
type: string
name: unpack_data
arguments: data_label: D7
type: string

tool: D17: greetings  

tool: D7: compress.cti,en-us-g2.ctb

assistant: ```c
int main(int argc, char **argv) {
  const char *str2 = "greetings  ";
  const int expected_pos2[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 7, 8};
  int result = check_cursor_pos("compress.cti,en-us-g2.ctb", str2, expected_pos2);
  lou_free();
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rsi
  lea    D1(%rip),%rdi
  sub    $0x40,%rsp
  movdqa D5(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D42(%rip),%rax
  mov    %rsp,%rdx
  movl   $0x8,0x28(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D41(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <check_cursor_pos@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <lou_free@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x40,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: byte[16]
name: parse_data
arguments: data_label: D42
type_infered: byte[8]
name: parse_data
arguments: data_label: D41
type_infered: byte[16]

tool: D14: greetings  

tool: D1: compress.cti,en-us-g2.ctb

tool: {"D5": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D42": [0x08,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D41": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char **argv) {
  const char *str2 = "greetings  ";
  const int expected_pos2[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 7, 8};
  int result = check_cursor_pos("compress.cti,en-us-g2.ctb", str2, expected_pos2);
  lou_free();
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<seq_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x1(%rdx),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: the seq is :%d


assistant: ```c
int seq_random() {
  int i;
  i = rand() % 100 + 1;
  printf("the seq is :%d\n", i);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<seq_random>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%ebx
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: the seq is :%d


assistant: ```c
int seq_random() {
  int i;
  i = rand() % 100 + 1;
  printf("the seq is :%d\n", i);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<seq_random>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  lea    D2(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: the seq is :%d


assistant: ```c
int seq_random() {
  int i;
  i = rand() % 100 + 1;
  printf("the seq is :%d\n", i);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<seq_random>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  lea    D9(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: the seq is :%d


assistant: ```c
int seq_random() {
  int i;
  i = rand() % 100 + 1;
  printf("the seq is :%d\n", i);
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L12
L1:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,%rcx
  movabs $0x346dc5d63886594b,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0xb,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0x2710,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jne    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D19: %lld


tool: D5: %lld

assistant: ```c
int main() {
  long long int n;
  while (scanf("%lld", &n), n) {
    printf("%lld\n", n * (n - 1) / 2 % 10000);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D14(%rip),%rbx
  movabs $0x346dc5d63886594b,%r13
  lea    D15(%rip),%r12
  jmp    L27
L16:
  lea    -0x1(%rdx),%rax
  imul   %rdx,%rax
  mov    %rax,%rcx
  shr    $0x3f,%rcx
  add    %rax,%rcx
  mov    %rcx,%rsi
  sar    %rsi
  mov    %rsi,%rax
  imul   %r13
  sar    $0xb,%rdx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  imul   $0x2710,%rdx,%rdx
  sub    %rdx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L27:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jne    L16
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string

tool: D14: %lld

tool: D15: %lld


assistant: ```c
int main() {
  long long int n;
  while (scanf("%lld", &n), n) {
    printf("%lld\n", n * (n - 1) / 2 % 10000);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  movabs $0x346dc5d63886594b,%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D12(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rdx),%rax
  mov    %r12,%rdi
  imul   %rdx,%rax
  mov    %rax,%rcx
  shr    $0x3f,%rcx
  add    %rax,%rcx
  mov    %rcx,%rsi
  sar    $0x3f,%rcx
  sar    %rsi
  mov    %rsi,%rax
  imul   %r13
  sar    $0xb,%rdx
  sub    %rcx,%rdx
  imul   $0x2710,%rdx,%rdx
  sub    %rdx,%rsi
  call   <printf@plt>
L4:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jne    L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string
name: unpack_data
arguments: label: D12
data_type: string

tool: D4: %lld


tool: D12: %lld

assistant: ```c
int main() {
  long long int n;
  while (scanf("%lld", &n), n) {
    printf("%lld\n", n * (n - 1) / 2 % 10000);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  movabs $0x346dc5d63886594b,%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L5:
  lea    -0x1(%rdx),%rax
  mov    %r12,%rdi
  imul   %rdx,%rax
  mov    %rax,%rcx
  shr    $0x3f,%rcx
  add    %rax,%rcx
  mov    %rcx,%rsi
  sar    $0x3f,%rcx
  sar    %rsi
  mov    %rsi,%rax
  imul   %r13
  sar    $0xb,%rdx
  sub    %rcx,%rdx
  imul   $0x2710,%rdx,%rdx
  sub    %rdx,%rsi
  call   <printf@plt>
L11:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  jne    L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D18: %lld


tool: D2: %lld

assistant: ```c
int main() {
  long long int n;
  while (scanf("%lld", &n), n) {
    printf("%lld\n", n * (n - 1) / 2 % 10000);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RemoveHotmail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  cmpq   $0x0,-0x18(%rbp)
  jne    L3
  mov    $0xffffffff,%eax
  jmp    L0
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L1
L31:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L1:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: @hotmail.com

assistant: ```c
int RemoveHotmail(const char *src, char **dst) {
  char *temp;
  char *ptr;
  *dst = NULL;
  if (src == NULL)
    return -1;
  temp = strdup(src);
  ptr = strstr(temp, "@hotmail.com");
  if (ptr == NULL)
    *dst = strdup(src);
  else {
    *ptr = '\0';
    *dst = strdup(temp);
  }
  free(temp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RemoveHotmail>:
  endbr64
  movq   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strdup@plt>
  mov    %rax,%rbx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L14
  movb   $0x0,(%rax)
  mov    %rbx,%rdi
  call   <strdup@plt>
L22:
  mov    %rax,(%r12)
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %rbp,%rdi
  call   <strdup@plt>
  jmp    L22
L1:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: @hotmail.com

assistant: ```c
int RemoveHotmail(const char *src, char **dst) {
  char *temp;
  char *ptr;
  *dst = NULL;
  if (src == NULL)
    return -1;
  temp = strdup(src);
  ptr = strstr(temp, "@hotmail.com");
  if (ptr == NULL)
    *dst = strdup(src);
  else {
    *ptr = '\0';
    *dst = strdup(temp);
  }
  free(temp);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RemoveHotmail>:
  endbr64
  movq   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L16
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strdup@plt>
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strstr@plt>
  test   %rax,%rax
  je     L25
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strdup@plt>
L13:
  mov    %rax,(%rbx)
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %r12,%rdi
  call   <strdup@plt>
  jmp    L13
L16:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: @hotmail.com

assistant: ```c
int RemoveHotmail(const char *src, char **dst) {
  char *temp;
  char *ptr;
  *dst = NULL;
  if (src == NULL)
    return -1;
  temp = strdup(src);
  ptr = strstr(temp, "@hotmail.com");
  if (ptr == NULL)
    *dst = strdup(src);
  else {
    *ptr = '\0';
    *dst = strdup(temp);
  }
  free(temp);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RemoveHotmail>:
  endbr64
  movq   $0x0,(%rsi)
  test   %rdi,%rdi
  je     L0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <strdup@plt>
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strstr@plt>
  test   %rax,%rax
  je     L10
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strdup@plt>
L23:
  mov    %rax,(%rbx)
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rdi
  call   <strdup@plt>
  jmp    L23
L0:
  mov    $0xffffffff,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string

tool: D7: @hotmail.com

assistant: ```c
int RemoveHotmail(const char *src, char **dst) {
  char *temp;
  char *ptr;
  *dst = NULL;
  if (src == NULL)
    return -1;
  temp = strdup(src);
  ptr = strstr(temp, "@hotmail.com");
  if (ptr == NULL)
    *dst = strdup(src);
  else {
    *ptr = '\0';
    *dst = strdup(temp);
  }
  free(temp);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pad_spaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L6
L1:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L1
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void pad_spaces(char *str, size_t len) {
  size_t x;
  for (x = strlen(str); x < len - 1; x++) {
    str[x] = ' ';
  }
  str[len - 1] = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pad_spaces>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  lea    -0x1(%rbp),%rdx
  cmp    %rdx,%rax
  jae    L12
  add    %rbx,%rax
  add    %rbx,%rdx
L17:
  movb   $0x20,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L12:
  movb   $0x0,-0x1(%rbx,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pad_spaces(char *str, size_t len) {
  size_t x;
  for (x = strlen(str); x < len - 1; x++) {
    str[x] = ' ';
  }
  str[len - 1] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pad_spaces>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    -0x1(%rbp),%rdx
  cmp    %rdx,%rax
  jae    L6
  sub    %rax,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x20,%esi
  call   <memset@plt>
L6:
  movb   $0x0,-0x1(%rbx,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pad_spaces(char *str, size_t len) {
  size_t x;
  for (x = strlen(str); x < len - 1; x++) {
    str[x] = ' ';
  }
  str[len - 1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pad_spaces>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    -0x1(%rbp),%rdx
  cmp    %rdx,%rax
  jae    L8
  sub    %rax,%rdx
  lea    (%rbx,%rax,1),%rdi
  mov    $0x20,%esi
  call   <memset@plt>
L8:
  movb   $0x0,-0x1(%rbx,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void pad_spaces(char *str, size_t len) {
  size_t x;
  for (x = strlen(str); x < len - 1; x++) {
    str[x] = ' ';
  }
  str[len - 1] = 0;
}
```