user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D73(%rip),%r14
  push   %r13
  lea    D69(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  lea    D37(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  call   <printf@plt>
  nopl   (%rax)
L51:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L12
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L34
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L51
  nop
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L34
  movss  (%rsp),%xmm0
  pxor   %xmm1,%xmm1
  mov    0x4(%rsp),%edi
  cvtss2sd %xmm0,%xmm1
  comisd D7(%rip),%xmm1
  jbe    L132
  movsd  D21(%rip),%xmm2
  comisd %xmm1,%xmm2
  jbe    L132
  test   %edi,%edi
  jne    L113
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L89
L132:
  test   %edi,%edi
  jg     L9
  jne    L48
  lea    D64(%rip),%rdi
  call   <puts@plt>
L89:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <my_power@plt>
  lea    D72(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L89
L48:
  neg    %edi
  mov    %edi,0x4(%rsp)
  call   <my_power@plt>
  lea    D72(%rip),%rdi
  mov    %eax,%r8d
  mov    $0x1,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L89
L113:
  lea    D95(%rip),%rdi
  call   <puts@plt>
  jmp    L89
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D73
type_infered: string
name: parse_data
arguments: data_label: D69
type_infered: string
name: parse_data
arguments: data_label: D37
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: byte[16]
name: parse_data
arguments: data_label: D21
type_infered: byte[8]
name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D64
type_infered: string
name: parse_data
arguments: data_label: D72
type_infered: string
name: parse_data
arguments: data_label: D95
type_infered: string

tool: D73: input invalid!

tool: D69: Pls input the base and power number(e.g. 3.14, 2):

tool: D37: %f,%d

tool: {"D7": [0xe4,0x78,0xaa,0x9d,0xfb,0x38,0x0b,0xb8,0xe4,0x78,0xaa,0x9d,0xfb,0x38,0x0b,0x38]}

tool: {"D21": [0xe4,0x78,0xaa,0x9d,0xfb,0x38,0x0b,0x38]}

tool: D22: forbiden!

tool: D64: answer: 1

tool: D72: answer: %.6f


tool: D95: answer: 0

assistant: ```c
int main(void) {
  float num;
  int pow;
  printf("Pls input the base and power number(e.g. 3.14, 2):");
  while (scanf("%f,%d", &num, &pow) != 2 || getchar() != '\n') {
    while (getchar() != '\n')
      ;
    printf("input invalid!\n");
    printf("Pls input the base and power number(e.g. 3.14, 2):");
  }
  if (num > -1e-38 && num < 1e-38) {
    if (pow == 0)
      printf("forbiden!\n");
    else
      printf("answer: 0\n");
  } else {
    if (pow > 0)
      printf("answer: %.6f\n", my_power(num, pow));
    else if (pow == 0)
      printf("answer: 1\n");
    else {
      pow *= -1;
      printf("answer: %.6f\n", 1 / my_power(num, pow));
    }
  }
  return 0;
}
```