ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x74(%rsp),%r15
  mov    %rbp,%rbx
  call   <printf@plt>
L28:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x14,%rbx
  call   <scanf@plt>
  cmp    %r15,%rbx
  jne    L28
  movl   $0x4,0xc(%rsp)
  lea    0x50(%rbp),%r12
  lea    0x80(%rsp),%r13
L58:
  mov    %rbp,%rbx
L36:
  mov    %rbx,%r14
  add    $0x14,%rbx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L56
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
L56:
  cmp    %r12,%rbx
  jne    L36
  subl   $0x1,0xc(%rsp)
  jne    L58
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  lea    D1(%rip),%rbx
  call   <printf@plt>
L52:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x14,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L52
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D7
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D9: 
Enter any five strings: 

tool: D2: %s

tool: D7: 
Strings in order are: 

tool: D1: 
%s

assistant: ```c
void main() {
  char s[5][20], t[20];
  int i, j;
  printf("\nEnter any five strings: ");
  for (i = 0; i < 5; i++) {
    scanf("%s", s[i]);
  }
  for (i = 1; i < 5; i++) {
    for (j = 1; j < 5; j++) {
      if (strcmp(s[j - 1], s[j]) > 0) {
        strcpy(t, s[j - 1]);
        strcpy(s[j - 1], s[j]);
        strcpy(s[j], t);
      }
    }
  }
  printf("\nStrings in order are: ");
  for (i = 0; i < 5; i++) {
    printf("\n%s", s[i]);
  }
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x74(%rsp),%r15
  mov    %rbp,%rbx
  call   <printf@plt>
L57:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x14,%rbx
  call   <scanf@plt>
  cmp    %r15,%rbx
  jne    L57
  movl   $0x4,0xc(%rsp)
  lea    0x50(%rbp),%r12
  lea    0x80(%rsp),%r13
L18:
  mov    %rbp,%rbx
L3:
  mov    %rbx,%r14
  add    $0x14,%rbx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L55
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
L55:
  cmp    %r12,%rbx
  jne    L3
  subl   $0x1,0xc(%rsp)
  jne    L18
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  lea    D4(%rip),%rbx
  call   <printf@plt>
L35:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x14,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L35
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D38
datatype: string
name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D28: 
Enter any five strings: 

tool: D19: %s

tool: D38: 
Strings in order are: 

tool: D4: 
%s

assistant: ```c
void main() {
  char s[5][20], t[20];
  int i, j;
  printf("\nEnter any five strings: ");
  for (i = 0; i < 5; i++) {
    scanf("%s", s[i]);
  }
  for (i = 1; i < 5; i++) {
    for (j = 1; j < 5; j++) {
      if (strcmp(s[j - 1], s[j]) > 0) {
        strcpy(t, s[j - 1]);
        strcpy(s[j - 1], s[j]);
        strcpy(s[j], t);
      }
    }
  }
  printf("\nStrings in order are: ");
  for (i = 0; i < 5; i++) {
    printf("\n%s", s[i]);
  }
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<romanToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L5
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <valueOfSymbol@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L4
L27:
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
L4:
  subq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x28(%rbp)
  jne    L24
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int romanToInt(char *s) {
  char *c;
  int current_value = 0;
  int big_value = 0;
  int result = 0;
  for (c = s + strlen(s) - 1; c + 1 != s; c--) {
    current_value = valueOfSymbol(*c);
    if (current_value >= big_value) {
      result += current_value;
      big_value = current_value;
    } else {
      result -= current_value;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<romanToInt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  test   %rax,%rax
  je     L37
  mov    $0x0,%ebp
  mov    $0x0,%r13d
  jmp    L6
L16:
  sub    %eax,%ebp
L31:
  sub    $0x1,%rbx
  lea    0x1(%rbx),%rax
  cmp    %rax,%r12
  je     L0
L6:
  movsbl (%rbx),%edi
  call   <valueOfSymbol@plt>
  cmp    %r13d,%eax
  jl     L16
  add    %eax,%ebp
  mov    %eax,%r13d
  jmp    L31
L37:
  mov    $0x0,%ebp
L0:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int romanToInt(char *s) {
  char *c;
  int current_value = 0;
  int big_value = 0;
  int result = 0;
  for (c = s + strlen(s) - 1; c + 1 != s; c--) {
    current_value = valueOfSymbol(*c);
    if (current_value >= big_value) {
      result += current_value;
      big_value = current_value;
    } else {
      result -= current_value;
    }
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<romanToInt>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  test   %rax,%rax
  je     L17
  xor    %r13d,%r13d
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L12:
  sub    $0x1,%rbx
  add    %eax,%r12d
  mov    %eax,%r13d
  lea    0x1(%rbx),%rax
  cmp    %rax,%rbp
  je     L17
L42:
  movsbl (%rbx),%edi
  call   <valueOfSymbol@plt>
  cmp    %r13d,%eax
  jge    L12
  sub    $0x1,%rbx
  sub    %eax,%r12d
  lea    0x1(%rbx),%rax
  cmp    %rax,%rbp
  jne    L42
L17:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int romanToInt(char *s) {
  char *c;
  int current_value = 0;
  int big_value = 0;
  int result = 0;
  for (c = s + strlen(s) - 1; c + 1 != s; c--) {
    current_value = valueOfSymbol(*c);
    if (current_value >= big_value) {
      result += current_value;
      big_value = current_value;
    } else {
      result -= current_value;
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<romanToInt>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  test   %rax,%rax
  je     L47
  xor    %r13d,%r13d
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L43:
  sub    $0x1,%rbx
  add    %eax,%r12d
  mov    %eax,%r13d
  lea    0x1(%rbx),%rax
  cmp    %rax,%rbp
  je     L47
L46:
  movsbl (%rbx),%edi
  call   <valueOfSymbol@plt>
  cmp    %r13d,%eax
  jge    L43
  sub    $0x1,%rbx
  sub    %eax,%r12d
  lea    0x1(%rbx),%rax
  cmp    %rax,%rbp
  jne    L46
L47:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int romanToInt(char *s) {
  char *c;
  int current_value = 0;
  int big_value = 0;
  int result = 0;
  for (c = s + strlen(s) - 1; c + 1 != s; c--) {
    current_value = valueOfSymbol(*c);
    if (current_value >= big_value) {
      result += current_value;
      big_value = current_value;
    } else {
      result -= current_value;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__rawmemchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  mov    %al,-0x31(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  jmp    L25
L58:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L108
  mov    -0x30(%rbp),%rax
  jmp    L94
L108:
  addq   $0x1,-0x30(%rbp)
L25:
  mov    -0x30(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  jne    L58
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movq   $0xffffffffffffffff,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movabs $0x8080808080808081,%rdx
  mul    %rdx
  shr    $0x7,%rdx
  mov    %rdx,%rax
  shl    $0x7,%rax
  sub    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  movabs $0x7ffffffffffffffe,%rax
  and    %rdx,%rax
  or     $0x1,%rax
  mov    %rax,-0x20(%rbp)
  movzbl -0x31(%rbp),%edx
  movzbl -0x31(%rbp),%eax
  shl    $0x8,%eax
  or     %edx,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  or     %rax,-0x18(%rbp)
L71:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  xor    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  xor    -0x10(%rbp),%rax
  or     -0x20(%rbp),%rax
  cmp    $0xffffffffffffffff,%rax
  je     L71
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L102
  mov    -0x8(%rbp),%rax
  jmp    L94
L102:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L86
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L94
L86:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L12
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  jmp    L94
L12:
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x31(%rbp)
  jne    L71
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
L94:
  pop    %rbp
  ret
```

assistant: ```c
void *__rawmemchr(const void *s, int c_in) {
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  magic_bits = -1;
  magic_bits = magic_bits / 0xff * 0xfe << 1 >> 1 | 1;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  je     L44
L106:
  cmp    %cl,(%rax)
  je     L65
  add    $0x1,%rax
  test   $0x7,%al
  jne    L106
L44:
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%r9
  shl    $0x10,%r9
  or     %rdx,%r9
  movabs $0x7efefefefefefeff,%rdi
L49:
  mov    %rax,%r8
  add    $0x8,%rax
  mov    %r9,%rsi
  xor    -0x8(%rax),%rsi
  lea    (%rsi,%rdi,1),%rdx
  xor    %rsi,%rdx
  or     %rdi,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L49
  cmp    %cl,-0x8(%rax)
  je     L10
  cmp    %cl,-0x7(%rax)
  je     L29
  cmp    %cl,-0x6(%rax)
  je     L27
  cmp    %cl,-0x5(%rax)
  jne    L49
  add    $0x3,%r8
  jmp    L10
L29:
  add    $0x1,%r8
  jmp    L10
L27:
  add    $0x2,%r8
  jmp    L10
L65:
  mov    %rax,%r8
L10:
  mov    %r8,%rax
  ret
```

assistant: ```c
void *__rawmemchr(const void *s, int c_in) {
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  magic_bits = -1;
  magic_bits = magic_bits / 0xff * 0xfe << 1 >> 1 | 1;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  jne    L61
  jmp    L16
  nop
L46:
  add    $0x1,%rax
  test   $0x7,%al
  je     L16
L61:
  cmp    %cl,(%rax)
  jne    L46
  mov    %rax,%r8
L85:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  movabs $0x7efefefefefefeff,%rdi
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%r9
  shl    $0x10,%r9
  or     %rdx,%r9
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rax,%r8
  lea    0x8(%rax),%rax
  mov    (%r8),%rsi
  xor    %r9,%rsi
  lea    (%rsi,%rdi,1),%rdx
  xor    %rsi,%rdx
  or     %rdi,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L10
  cmp    %cl,-0x8(%rax)
  je     L85
  cmp    %cl,-0x7(%rax)
  je     L18
  cmp    %cl,-0x6(%rax)
  je     L73
  cmp    %cl,-0x5(%rax)
  jne    L10
  add    $0x3,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L18:
  add    $0x1,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  add    $0x2,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
void *__rawmemchr(const void *s, int c_in) {
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  magic_bits = -1;
  magic_bits = magic_bits / 0xff * 0xfe << 1 >> 1 | 1;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__rawmemchr>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  test   $0x7,%al
  jne    L47
  jmp    L20
  nop
L57:
  add    $0x1,%rax
  test   $0x7,%al
  je     L20
L47:
  cmp    %cl,(%rax)
  jne    L57
  mov    %rax,%r8
L73:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  movabs $0x7efefefefefefeff,%rdi
  movzbl %sil,%esi
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  movslq %edx,%rdx
  mov    %rdx,%r9
  shl    $0x10,%r9
  or     %rdx,%r9
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %rax,%r8
  lea    0x8(%rax),%rax
  mov    (%r8),%rsi
  xor    %r9,%rsi
  lea    (%rsi,%rdi,1),%rdx
  xor    %rsi,%rdx
  or     %rdi,%rdx
  cmp    $0xffffffffffffffff,%rdx
  je     L25
  cmp    %cl,-0x8(%rax)
  je     L73
  cmp    %cl,-0x7(%rax)
  je     L15
  cmp    %cl,-0x6(%rax)
  je     L77
  cmp    %cl,-0x5(%rax)
  jne    L25
  add    $0x3,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L15:
  add    $0x1,%r8
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L77:
  add    $0x2,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
void *__rawmemchr(const void *s, int c_in) {
  const unsigned char *char_ptr;
  const unsigned long int *longword_ptr;
  unsigned long int longword, magic_bits, charmask;
  unsigned char c;
  c = (unsigned char)c_in;
  for (char_ptr = (const unsigned char *)s; ((unsigned long int)char_ptr & (sizeof(longword) - 1)) != 0; ++char_ptr)
    if (*char_ptr == c)
      return (void *)char_ptr;
  longword_ptr = (unsigned long int *)char_ptr;
  magic_bits = -1;
  magic_bits = magic_bits / 0xff * 0xfe << 1 >> 1 | 1;
  charmask = c | (c << 8);
  charmask |= charmask << 16;
  while (1) {
    longword = *longword_ptr++ ^ charmask;
    if ((((longword + magic_bits) ^ ~longword) & ~magic_bits) != 0) {
      const unsigned char *cp = (const unsigned char *)(longword_ptr - 1);
      if (cp[0] == c)
        return (void *)cp;
      if (cp[1] == c)
        return (void *)&cp[1];
      if (cp[2] == c)
        return (void *)&cp[2];
      if (cp[3] == c)
        return (void *)&cp[3];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<stdlib_strided_dnanvarianceyc>:
  endbr64
  movapd %xmm0,%xmm8
  test   %edi,%edi
  jle    L85
  cmp    $0x1,%edi
  je     L138
  test   %edx,%edx
  je     L138
  mov    $0x0,%ecx
  js     L63
L131:
  pxor   %xmm4,%xmm4
  cvtsi2sd %edi,%xmm4
  movslq %edx,%rdi
  shl    $0x3,%rdi
  movslq %ecx,%rax
  lea    (%rsi,%rax,8),%rax
  pxor   %xmm0,%xmm0
  movsd  D0(%rip),%xmm1
L60:
  movsd  (%rax),%xmm2
  ucomisd %xmm2,%xmm2
  jnp    L159
  add    %edx,%ecx
  addsd  %xmm1,%xmm0
  add    %rdi,%rax
  comisd %xmm0,%xmm4
  ja     L60
L159:
  ucomisd %xmm0,%xmm4
  jp     L99
  je     L0
L99:
  add    %edx,%ecx
  addsd  D0(%rip),%xmm0
  comisd %xmm0,%xmm4
  jbe    L121
  movslq %edx,%rdx
  shl    $0x3,%rdx
  movslq %ecx,%rcx
  lea    (%rsi,%rcx,8),%rax
  pxor   %xmm3,%xmm3
  movsd  D0(%rip),%xmm5
  movapd %xmm5,%xmm9
  movapd %xmm5,%xmm10
  jmp    L75
L85:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  ret
L138:
  movsd  (%rsi),%xmm0
  ucomisd %xmm0,%xmm0
  jp     L146
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  subsd  %xmm8,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm0,%xmm1
  ja     L69
L146:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  ret
L63:
  mov    $0x1,%ecx
  sub    %edi,%ecx
  imul   %edx,%ecx
  jmp    L131
L0:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  ret
L151:
  addsd  %xmm10,%xmm0
  add    %rdx,%rax
  comisd %xmm0,%xmm4
  jbe    L42
L75:
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm1
  jp     L151
  addsd  %xmm9,%xmm5
  addsd  %xmm1,%xmm2
  mulsd  %xmm5,%xmm1
  subsd  %xmm2,%xmm1
  movapd %xmm5,%xmm7
  subsd  %xmm9,%xmm7
  mulsd  %xmm5,%xmm7
  movapd %xmm9,%xmm6
  divsd  %xmm7,%xmm6
  mulsd  %xmm1,%xmm6
  mulsd  %xmm6,%xmm1
  addsd  %xmm1,%xmm3
  jmp    L151
L121:
  pxor   %xmm3,%xmm3
  movsd  D0(%rip),%xmm5
L42:
  subsd  %xmm8,%xmm5
  pxor   %xmm0,%xmm0
  comisd %xmm5,%xmm0
  jae    L123
  divsd  %xmm5,%xmm3
  movapd %xmm3,%xmm0
L69:
  ret
L123:
  divsd  %xmm0,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: f64

tool: D0: 1

assistant: ```c
double stdlib_strided_dnanvarianceyc(const int64_t N, const double correction, const double *X, const int64_t stride) {
  double sum;
  int64_t ix;
  double nc;
  double n;
  double S;
  double v;
  double d;
  double i;
  if (N <= 0) {
    return 0.0 / 0.0;
  }
  if (N == 1 || stride == 0) {
    v = X[0];
    if (v == v && (double)N - correction > 0.0) {
      return 0.0;
    }
    return 0.0 / 0.0;
  }
  if (stride < 0) {
    ix = (1 - N) * stride;
  } else {
    ix = 0;
  }
  for (i = 0; i < N; i++) {
    v = X[ix];
    if (v == v) {
      break;
    }
    ix += stride;
  }
  if (i == N) {
    return 0.0 / 0.0;
  }
  ix += stride;
  sum = v;
  S = 0.0;
  n = 1.0;
  i += 1;
  for (; i < N; i++) {
    v = X[ix];
    if (v == v) {
      n += 1.0;
      sum += v;
      d = (n * v) - sum;
      S += (1.0 / (n * (n - 1.0))) * d * d;
    }
    ix += stride;
  }
  nc = n - correction;
  if (nc <= 0.0) {
    return 0.0 / 0.0;
  }
  return S / nc;
}
```