user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  call   <getop@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <assert@plt>
  lea    D76(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getop@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <assert@plt>
  lea    D71(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getop@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <assert@plt>
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getop@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    $0x0,%esi
  lea    D75(%rip),%rbp
  mov    %rbp,%rdi
  call   <getop@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <assert@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getop@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <assert@plt>
  lea    D74(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getop@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <assert@plt>
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getop@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D76
datatype: string
name: read_data
arguments: label: D71
datatype: string
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D75
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D74
datatype: string
name: read_data
arguments: label: D17
datatype: string

tool: D26: 12.3 4.5 +


tool: D76: 12.3

tool: D71: 4.5

tool: D7: +

tool: D75:  a b c 


tool: D3: a

tool: D74: b

tool: D17: c

assistant: ```c
int main(int argc, char *argv[]) {
  char *s = "12.3 4.5 +\n";
  char t[100];
  int i = 0;
  assert(i = getop(s, i, t));
  assert(!strcmp(t, "12.3"));
  assert(i = getop(s, i, t));
  assert(!strcmp(t, "4.5"));
  assert(i = getop(s, i, t));
  assert(!strcmp(t, "+"));
  assert(getop(s, i, t) == -1);
  s = " a b c \n";
  i = 0;
  assert(i = getop(s, i, t));
  assert(!strcmp(t, "a"));
  assert(i = getop(s, i, t));
  assert(!strcmp(t, "b"));
  assert(i = getop(s, i, t));
  assert(!strcmp(t, "c"));
  assert(getop(s, i, t) == -1);
}
```