user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D89(%rip),%xmm0
  movsd  %xmm0,-0x98(%rbp)
  movsd  D10(%rip),%xmm0
  movsd  %xmm0,-0x90(%rbp)
  movsd  D59(%rip),%xmm0
  movsd  %xmm0,-0x88(%rbp)
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0xa8(%rbp)
  jmp    L21
L10:
  mov    -0xa8(%rbp),%eax
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  -0x98(%rbp),%xmm0
  movsd  %xmm0,-0xa0(%rbp)
  jmp    L30
L15:
  movsd  -0xa0(%rbp),%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xa4(%rbp)
  lea    -0x40(%rbp),%rdx
  mov    -0xa4(%rbp),%eax
  mov    %rdx,%rdi
  movd   %eax,%xmm0
  call   <CalcLon@plt>
  lea    -0x80(%rbp),%rdx
  mov    -0xa8(%rbp),%esi
  lea    -0x40(%rbp),%rcx
  mov    -0xa4(%rbp),%eax
  mov    %rcx,%rdi
  movd   %eax,%xmm0
  call   <CalcTass17Elem@plt>
  movsd  -0x58(%rbp),%xmm5
  movsd  -0x60(%rbp),%xmm4
  movsd  -0x68(%rbp),%xmm3
  movsd  -0x70(%rbp),%xmm2
  movsd  -0x78(%rbp),%xmm1
  movsd  -0x80(%rbp),%xmm0
  mov    -0xa0(%rbp),%rax
  movapd %xmm5,%xmm6
  movapd %xmm4,%xmm5
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x7,%eax
  call   <printf@plt>
  movsd  -0xa0(%rbp),%xmm0
  addsd  -0x88(%rbp),%xmm0
  movsd  %xmm0,-0xa0(%rbp)
L30:
  movsd  -0x90(%rbp),%xmm0
  comisd -0xa0(%rbp),%xmm0
  ja     L15
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0xa8(%rbp)
L21:
  cmpl   $0x7,-0xa8(%rbp)
  jle    L10
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D89
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D10
datatype: f64
name: extract_symbolic_data
arguments: data_label: D59
datatype: f64
name: extract_symbolic_data
arguments: data_label: D77
datatype: string
name: extract_symbolic_data
arguments: data_label: D49
datatype: string
name: extract_symbolic_data
arguments: data_label: D8
datatype: f64
name: extract_symbolic_data
arguments: data_label: D45
datatype: string
name: extract_symbolic_data
arguments: data_label: D31
datatype: string
name: extract_symbolic_data
arguments: data_label: D86
datatype: string

tool: {"D89": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D10: 20000

tool: D59: 225

tool: D77: {

tool: D49: 	"%d": [


tool: D8: 7305

tool: D45: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: D31: 	],

tool: D86: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[7];
  double lon[7];
  printf("{\n");
  for (body = 0; body < 8; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float time = jd2k + 7305.0;
      CalcLon(time, lon);
      CalcTass17Elem(time, lon, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```