ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_libco_opts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D3
type: string
name: retrieve_data
arguments: tag: D11
type: string

tool: D0: PPC32 

tool: D3: FP 

tool: D11: 


assistant: ```c
void print_libco_opts(void) {
  printf("PPC32 ");
  printf("FP ");
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_libco_opts>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D2: PPC32 

tool: D8: FP 

tool: D6: 


assistant: ```c
void print_libco_opts(void) {
  printf("PPC32 ");
  printf("FP ");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_libco_opts>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D28
type: string
name: retrieve_data
arguments: tag: D14
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D28: PPC32 

tool: D14: FP 

tool: D1: 


assistant: ```c
void print_libco_opts(void) {
  printf("PPC32 ");
  printf("FP ");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_libco_opts>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string
name: retrieve_data
arguments: tag: D5
type_guessed: string
name: retrieve_data
arguments: tag: D20
type_guessed: string

tool: D7: PPC32 

tool: D5: FP 

tool: D20: 


assistant: ```c
void print_libco_opts(void) {
  printf("PPC32 ");
  printf("FP ");
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  movsd  %xmm0,-0x48(%rbp)
  movsd  %xmm1,-0x50(%rbp)
  movsd  %xmm2,-0x58(%rbp)
  movsd  %xmm3,-0x60(%rbp)
  movsd  -0x50(%rbp),%xmm0
  subsd  -0x60(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x48(%rbp),%xmm0
  subsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x38(%rbp),%xmm0
  jp     L35
  pxor   %xmm0,%xmm0
  ucomisd -0x38(%rbp),%xmm0
  jne    L35
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jp     L35
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jne    L35
  pxor   %xmm0,%xmm0
  jmp    L34
L35:
  movsd  -0x30(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x38(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x68(%rbp)
  mov    -0x48(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  %xmm0,-0x70(%rbp)
  mov    -0x58(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x70(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  -0x68(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  D7(%rip),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L32
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <asin@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  jmp    L2
L32:
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  call   <asin@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x40(%rbp)
L2:
  movsd  -0x40(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
L34:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D7
datatype: f64
name: extract_symbolic_data
arguments: label: D3
datatype: f64

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D7: 1

tool: D3: 6378.137

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2) {
  double dlon = lon1 - lon2;
  double dlat = lat1 - lat2;
  double a1, a2, a, sa, c, d;
  if (dlon == 0 && dlat == 0)
    return 0;
  a1 = sin(dlat / 2);
  a2 = sin(dlon / 2);
  a = (a1 * a1) + cos(lat1) * cos(lat2) * a2 * a2;
  sa = sqrt(a);
  if (sa <= 1.0) {
    c = 2 * asin(sa);
  } else {
    c = 2 * asin(1.0);
  }
  d = 6378.137 * c;
  return (d);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<distance>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  movq   %xmm2,%r14
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm4
  movsd  %xmm4,(%rsp)
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  ucomisd D18(%rip),%xmm4
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  je     L16
  ucomisd D18(%rip),%xmm1
  setnp  %al
  cmovne %edx,%eax
  pxor   %xmm0,%xmm0
  test   %al,%al
  je     L16
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
L16:
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <sin@plt>
  movsd  %xmm0,0x8(%rsp)
  movsd  D13(%rip),%xmm6
  mulsd  (%rsp),%xmm6
  movapd %xmm6,%xmm0
  call   <sin@plt>
  movsd  %xmm0,(%rsp)
  movq   %rbx,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rbx
  movq   %r14,%xmm0
  call   <cos@plt>
  movq   %rbx,%xmm6
  mulsd  %xmm6,%xmm0
  movsd  (%rsp),%xmm7
  mulsd  %xmm7,%xmm0
  mulsd  %xmm7,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L21
  sqrtsd %xmm0,%xmm0
L18:
  movsd  D63(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L37
  movsd  D63(%rip),%xmm0
  call   <asin@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L62:
  mulsd  D67(%rip),%xmm0
  jmp    L38
L21:
  call   <sqrt@plt>
  jmp    L18
L37:
  call   <asin@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L62
```

tool_calls: name: retrieve_data
arguments: label: D18
datatype: byte[8]
name: retrieve_data
arguments: label: D13
datatype: byte[8]
name: retrieve_data
arguments: label: D63
datatype: f64
name: retrieve_data
arguments: label: D67
datatype: f64

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D63: 1

tool: D67: 6378.137

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2) {
  double dlon = lon1 - lon2;
  double dlat = lat1 - lat2;
  double a1, a2, a, sa, c, d;
  if (dlon == 0 && dlat == 0)
    return 0;
  a1 = sin(dlat / 2);
  a2 = sin(dlon / 2);
  a = (a1 * a1) + cos(lat1) * cos(lat2) * a2 * a2;
  sa = sqrt(a);
  if (sa <= 1.0) {
    c = 2 * asin(sa);
  } else {
    c = 2 * asin(1.0);
  }
  d = 6378.137 * c;
  return (d);
}
```
user: What is the c source code of the assembly code below:

```asm
<distance>:
  endbr64
  subsd  %xmm3,%xmm1
  pxor   %xmm3,%xmm3
  mov    $0x0,%edx
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm4
  subsd  %xmm2,%xmm5
  ucomisd %xmm3,%xmm1
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L33
  ucomisd %xmm3,%xmm5
  movapd %xmm3,%xmm0
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L33
  ret
  xchg   %ax,%ax
L33:
  sub    $0x38,%rsp
  movsd  D11(%rip),%xmm0
  movsd  %xmm2,0x28(%rsp)
  mulsd  %xmm5,%xmm0
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x18(%rsp)
  movsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <sin@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm4,%xmm0
  call   <cos@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <cos@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  movsd  0x18(%rsp),%xmm5
  mulsd  %xmm5,%xmm5
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm5,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L46
  sqrtsd %xmm0,%xmm0
L41:
  movsd  D20(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L19
  movapd %xmm1,%xmm0
L19:
  call   <asin@plt>
  pxor   %xmm0,%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D2(%rip),%xmm0
  add    $0x38,%rsp
  ret
L46:
  call   <sqrt@plt>
  jmp    L41
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: byte[8]
name: read_data
arguments: label: D20
type_guessed: f64
name: read_data
arguments: label: D2
type_guessed: f64

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D20: 1

tool: D2: 6378.137

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2) {
  double dlon = lon1 - lon2;
  double dlat = lat1 - lat2;
  double a1, a2, a, sa, c, d;
  if (dlon == 0 && dlat == 0)
    return 0;
  a1 = sin(dlat / 2);
  a2 = sin(dlon / 2);
  a = (a1 * a1) + cos(lat1) * cos(lat2) * a2 * a2;
  sa = sqrt(a);
  if (sa <= 1.0) {
    c = 2 * asin(sa);
  } else {
    c = 2 * asin(1.0);
  }
  d = 6378.137 * c;
  return (d);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<distance>:
  endbr64
  subsd  %xmm3,%xmm1
  pxor   %xmm3,%xmm3
  mov    $0x0,%edx
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm4
  subsd  %xmm2,%xmm5
  ucomisd %xmm3,%xmm1
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L35
  ucomisd %xmm3,%xmm5
  movapd %xmm3,%xmm0
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L35
  ret
  xchg   %ax,%ax
L35:
  sub    $0x38,%rsp
  movsd  D35(%rip),%xmm0
  movsd  %xmm2,0x28(%rsp)
  mulsd  %xmm5,%xmm0
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x18(%rsp)
  movsd  D35(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  call   <sin@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm4,%xmm0
  call   <cos@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <cos@plt>
  mulsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  pxor   %xmm3,%xmm3
  movsd  0x18(%rsp),%xmm5
  mulsd  %xmm5,%xmm5
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm5,%xmm0
  ucomisd %xmm0,%xmm3
  ja     L20
  sqrtsd %xmm0,%xmm0
L44:
  movsd  D21(%rip),%xmm1
  comisd %xmm0,%xmm1
  jae    L39
  movapd %xmm1,%xmm0
L39:
  call   <asin@plt>
  pxor   %xmm0,%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D11(%rip),%xmm0
  add    $0x38,%rsp
  ret
L20:
  call   <sqrt@plt>
  jmp    L44
```

tool_calls: name: unpack_data
arguments: data_label: D35
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D21
type_guessed: f64
name: unpack_data
arguments: data_label: D11
type_guessed: f64

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D21: 1

tool: D11: 6378.137

assistant: ```c
double distance(double lat1, double lon1, double lat2, double lon2) {
  double dlon = lon1 - lon2;
  double dlat = lat1 - lat2;
  double a1, a2, a, sa, c, d;
  if (dlon == 0 && dlat == 0)
    return 0;
  a1 = sin(dlat / 2);
  a2 = sin(dlon / 2);
  a = (a1 * a1) + cos(lat1) * cos(lat2) * a2 * a2;
  sa = sqrt(a);
  if (sa <= 1.0) {
    c = 2 * asin(sa);
  } else {
    c = 2 * asin(1.0);
  }
  d = 6378.137 * c;
  return (d);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x1852324,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L3
L0:
  mov    -0x8(%rbp),%rax
  imul   %rax,%rax
  sub    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L3:
  cmpq   $0x64,-0x8(%rbp)
  jle    L0
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: %ld


assistant: ```c
int main(void) {
  long sum = 101 * 50 * 101 * 50;
  long i;
  for (i = 1; i <= 100; i++)
    sum -= i * i;
  printf("%ld\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%eax
L1:
  sub    $0x1,%rax
  jne    L1
  mov    $0x17ff976,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %ld


assistant: ```c
int main(void) {
  long sum = 101 * 50 * 101 * 50;
  long i;
  for (i = 1; i <= 100; i++)
    sum -= i * i;
  printf("%ld\n", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17ff976,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: %ld


assistant: ```c
int main(void) {
  long sum = 101 * 50 * 101 * 50;
  long i;
  for (i = 1; i <= 100; i++)
    sum -= i * i;
  printf("%ld\n", sum);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17ff976,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: D4: %ld


assistant: ```c
int main(void) {
  long sum = 101 * 50 * 101 * 50;
  long i;
  for (i = 1; i <= 100; i++)
    sum -= i * i;
  printf("%ld\n", sum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xrop3_165_1_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0xff,-0x10(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  movzbl -0x18(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_165_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T ^ D;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_165_1_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  or     %esi,%eax
  shl    $0x8,%edi
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_165_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T ^ D;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xrop3_165_1_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  shl    $0x8,%edi
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_165_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T ^ D;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_165_1_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  shl    $0x8,%edi
  or     %esi,%eax
  or     %edi,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_165_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  stk1 = T ^ D;
  stk1 = ~stk1;
  return (stk1 & (~S)) | (D & S);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%rdi
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <__quick_sort@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(void *base, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *buf = (char *)calloc(1, size);
  assert(buf != NULL);
  __quick_sort(base, nmemb, size, buf, cmp);
  free(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick_sort>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    %rcx,%r14
  mov    %rdx,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r14,%r8
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <__quick_sort@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void quick_sort(void *base, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *buf = (char *)calloc(1, size);
  assert(buf != NULL);
  __quick_sort(base, nmemb, size, buf, cmp);
  free(buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quick_sort>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  mov    $0x1,%edi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <calloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdi
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <__quick_sort@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free@plt>
```

assistant: ```c
void quick_sort(void *base, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *buf = (char *)calloc(1, size);
  assert(buf != NULL);
  __quick_sort(base, nmemb, size, buf, cmp);
  free(buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quick_sort>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  mov    $0x1,%edi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <calloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r13,%rdi
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <__quick_sort@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <free@plt>
```

assistant: ```c
void quick_sort(void *base, size_t nmemb, size_t size, int (*cmp)(const void *, const void *)) {
  char *buf = (char *)calloc(1, size);
  assert(buf != NULL);
  __quick_sort(base, nmemb, size, buf, cmp);
  free(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<T>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <P@plt>
  mov    %eax,%edi
  call   <Rt@plt>
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: T->PRt


assistant: ```c
int T() {
  printf("T->PRt\n");
  return Rt(P());
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<T>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <P@plt>
  mov    %eax,%edi
  call   <Rt@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: T->PRt


assistant: ```c
int T() {
  printf("T->PRt\n");
  return Rt(P());
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<T>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <P@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <Rt@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: T->PRt


assistant: ```c
int T() {
  printf("T->PRt\n");
  return Rt(P());
}
```
user: What is the c source code of the assembly code below?

```asm
<T>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <P@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1090 <Rt@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: T->PRt


assistant: ```c
int T() {
  printf("T->PRt\n");
  return Rt(P());
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<old_time_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rax
  lea    D30(%rip),%rdx
  mov    $0xf0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L6
L13:
  cmpq   $0xffffffffffffffff,-0x10(%rbp)
  jne    L25
  mov    -0x8(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    $0xf0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L6
L25:
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jns    L59
  movq   $0x0,-0x10(%rbp)
L59:
  cmpq   $0x270f,-0x10(%rbp)
  jbe    L66
  mov    -0x10(%rbp),%rax
  shr    $0x2,%rax
  movabs $0x28f5c28f5c28f5c3,%rdx
  mul    %rdx
  shr    $0x2,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    $0xf0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L6
L66:
  mov    -0x10(%rbp),%rax
  mov    %eax,%ecx
  mov    %ecx,%eax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  shr    $0x5,%eax
  imul   $0x64,%eax,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    -0x10(%rbp),%rdx
  mov    %edx,%edx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  shr    $0x5,%edx
  mov    -0x8(%rbp),%rdi
  mov    %eax,%r8d
  mov    %edx,%ecx
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0xf0,%esi
  mov    $0x0,%eax
  call   <snprintf@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D30
data_type: string
name: parse_data
arguments: tag: D28
data_type: string
name: parse_data
arguments: tag: D3
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D30:     -

tool: D28:    xx

tool: D3: %5Lu

tool: D4: %2u.%02u

assistant: ```c
int old_time_helper(char *dst, unsigned long long t, unsigned long long rel) {
  if (!t)
    return snprintf(dst, 240, "    -");
  if (t == ~0ULL)
    return snprintf(dst, 240, "   xx");
  if ((long long)(t -= rel) < 0)
    t = 0ULL;
  if (t > 9999ULL)
    return snprintf(dst, 240, "%5Lu", t / 100ULL);
  else
    return snprintf(dst, 240, "%2u.%02u", (unsigned)t / 100U, (unsigned)t % 100U);
}
```