ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<cuberp>:
  endbr64
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movsd  D69(%rip),%xmm2
  movsd  %xmm2,0x20(%rsp)
  movsd  D68(%rip),%xmm1
  movsd  %xmm1,0x28(%rsp)
  mov    D5(%rip),%rax
  mov    %rax,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movsd  %xmm1,0x40(%rsp)
  mov    D0(%rip),%rax
  mov    %rax,0x48(%rsp)
  movsd  D54(%rip),%xmm4
  movsd  %xmm4,0x50(%rsp)
  movsd  D47(%rip),%xmm3
  movsd  %xmm3,0x58(%rsp)
  movsd  %xmm4,0x60(%rsp)
  movsd  %xmm1,0x68(%rsp)
  mov    D55(%rip),%rax
  mov    %rax,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movsd  %xmm3,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movsd  %xmm2,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rsp,%rcx
  lea    0xa0(%rsp),%rdx
  lea    0x20(%rsp),%r8
L23:
  mov    %rcx,%rsi
  movsd  (%rcx),%xmm1
  movsd  (%rdi),%xmm3
  lea    -0x80(%rdx),%rax
L15:
  movapd %xmm3,%xmm2
  mulsd  (%rax),%xmm2
  addsd  %xmm2,%xmm1
  add    $0x20,%rax
  cmp    %rdx,%rax
  jne    L15
  movsd  %xmm1,(%rsi)
  add    $0x8,%rcx
  add    $0x8,%rdi
  add    $0x8,%rdx
  cmp    %r8,%rcx
  jne    L23
  movapd %xmm0,%xmm1
  mulsd  (%rsp),%xmm1
  addsd  0x8(%rsp),%xmm1
  mulsd  %xmm0,%xmm1
  addsd  0x10(%rsp),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  0x18(%rsp),%xmm0
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0xb8,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D69
type_guessed: f32[2]
name: parse_data
arguments: data_label: D68
type_guessed: f64
name: parse_data
arguments: data_label: D5
type_guessed: f32[2]
name: parse_data
arguments: data_label: D0
type_guessed: f32[2]
name: parse_data
arguments: data_label: D54
type_guessed: f32[2]
name: parse_data
arguments: data_label: D47
type_guessed: f64
name: parse_data
arguments: data_label: D55
type_guessed: f64

tool: {"D69": [0.0,-1.875]}

tool: D68: 3

tool: {"D5": [0.0,-2.0]}

tool: {"D0": [0.0,-2.375]}

tool: {"D54": [0.0,-2.125]}

tool: D47: 1

tool: D55: 6

assistant: ```c
double cuberp(double x, double *f) {
  double M[4][4] = {{-1.0, 3.0, -2.0, 0.0}, {3.0, -6.0, -3.0, 1.0}, {-3.0, 3.0, 6.0, 0.0}, {1.0, 0.0, -1.0, 0.0}};
  double coeff[4] = {0.0, 0.0, 0.0, 0.0};
  int i, j;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      coeff[i] += f[i] * M[j][i];
    }
  }
  return coeff[3] + x * (coeff[2] + x * (coeff[1] + x * coeff[0]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cuberp>:
  endbr64
  sub    $0xb8,%rsp
  movsd  D54(%rip),%xmm1
  movsd  D31(%rip),%xmm2
  movapd %xmm0,%xmm3
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    D28(%rip),%rax
  mov    %rsp,%rdx
  lea    0x40(%rsp),%rcx
  movsd  D1(%rip),%xmm0
  movsd  %xmm1,0x58(%rsp)
  mov    %rax,0x30(%rsp)
  mov    D59(%rip),%rax
  movsd  %xmm1,0x80(%rsp)
  movsd  D3(%rip),%xmm1
  mov    %rax,0x48(%rsp)
  mov    D19(%rip),%rax
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rax,0x70(%rsp)
  lea    0x20(%rsp),%rax
  movsd  %xmm0,0x28(%rsp)
  movsd  %xmm0,0x40(%rsp)
  movsd  %xmm0,0x68(%rsp)
  pxor   %xmm0,%xmm0
  movsd  %xmm2,0x50(%rsp)
  movsd  %xmm2,0x60(%rsp)
  movsd  %xmm1,0x90(%rsp)
L6:
  movsd  (%rdi),%xmm2
  add    $0x8,%rax
  add    $0x8,%rdi
  add    $0x8,%rdx
  mulsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x18(%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x38(%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  0x58(%rax),%xmm2
  addsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,-0x8(%rdx)
  cmp    %rax,%rcx
  je     L11
  movsd  (%rdx),%xmm0
  movsd  (%rax),%xmm1
  jmp    L6
  nopl   0x0(%rax)
L11:
  movsd  (%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  0x8(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  0x10(%rsp),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  0x18(%rsp),%xmm0
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xb8,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D54
type_infered: f64
name: unpack_data
arguments: tag: D31
type_infered: f32[2]
name: unpack_data
arguments: tag: D28
type_infered: f32[2]
name: unpack_data
arguments: tag: D1
type_infered: f64
name: unpack_data
arguments: tag: D59
type_infered: f32[2]
name: unpack_data
arguments: tag: D3
type_infered: f32[2]
name: unpack_data
arguments: tag: D19
type_infered: f64

tool: D54: 1

tool: {"D31": [0.0,-2.125]}

tool: {"D28": [0.0,-2.0]}

tool: D1: 3

tool: {"D59": [0.0,-2.375]}

tool: {"D3": [0.0,-1.875]}

tool: D19: 6

assistant: ```c
double cuberp(double x, double *f) {
  double M[4][4] = {{-1.0, 3.0, -2.0, 0.0}, {3.0, -6.0, -3.0, 1.0}, {-3.0, 3.0, 6.0, 0.0}, {1.0, 0.0, -1.0, 0.0}};
  double coeff[4] = {0.0, 0.0, 0.0, 0.0};
  int i, j;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      coeff[i] += f[i] * M[j][i];
    }
  }
  return coeff[3] + x * (coeff[2] + x * (coeff[1] + x * coeff[0]));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cuberp>:
  endbr64
  movapd %xmm0,%xmm3
  movapd D59(%rip),%xmm2
  movupd (%rdi),%xmm0
  pxor   %xmm4,%xmm4
  movapd D31(%rip),%xmm1
  mulpd  %xmm0,%xmm2
  mulpd  %xmm0,%xmm1
  addpd  %xmm4,%xmm2
  addpd  %xmm1,%xmm2
  movapd D72(%rip),%xmm1
  mulpd  %xmm0,%xmm1
  mulpd  D39(%rip),%xmm0
  addpd  %xmm1,%xmm2
  movq   D9(%rip),%xmm1
  addpd  %xmm0,%xmm2
  movupd 0x10(%rdi),%xmm0
  mulpd  %xmm0,%xmm1
  addpd  %xmm4,%xmm1
  movapd D5(%rip),%xmm4
  mulpd  %xmm0,%xmm4
  addpd  %xmm4,%xmm1
  movq   D25(%rip),%xmm4
  mulpd  %xmm0,%xmm4
  mulpd  D44(%rip),%xmm0
  addpd  %xmm4,%xmm1
  addpd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  unpckhpd %xmm2,%xmm2
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D59
type_guessed: f32[4]
name: retrieve_data
arguments: data_label: D31
type_guessed: f64[2]
name: retrieve_data
arguments: data_label: D72
type_guessed: f32[4]
name: retrieve_data
arguments: data_label: D39
type_guessed: f64[2]
name: retrieve_data
arguments: data_label: D9
type_guessed: f32[2]
name: retrieve_data
arguments: data_label: D5
type_guessed: f32[4]
name: retrieve_data
arguments: data_label: D25
type_guessed: f64
name: retrieve_data
arguments: data_label: D44
type_guessed: f32[4]

tool: {"D59": [0.0,-1.875,0.0,2.125]}

tool: {"D31": [3.0,-6.0]}

tool: {"D72": [0.0,-2.125,0.0,2.125]}

tool: {"D39": [1.0,0.0]}

tool: {"D9": [0.0,-2.0]}

tool: {"D5": [0.0,-2.125,0.0,1.875]}

tool: D25: 6

tool: {"D44": [0.0,-1.875,0.0,0.0]}

assistant: ```c
double cuberp(double x, double *f) {
  double M[4][4] = {{-1.0, 3.0, -2.0, 0.0}, {3.0, -6.0, -3.0, 1.0}, {-3.0, 3.0, 6.0, 0.0}, {1.0, 0.0, -1.0, 0.0}};
  double coeff[4] = {0.0, 0.0, 0.0, 0.0};
  int i, j;
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++) {
      coeff[i] += f[i] * M[j][i];
    }
  }
  return coeff[3] + x * (coeff[2] + x * (coeff[1] + x * coeff[0]));
}
```
user: Translate the below assembly code into C programming language:

```asm
<mainTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <convertToRPN@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <convertToRPN@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <convertToRPN@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string

tool: D28: (a+(b*c))

tool: D9: a*b+c

tool: D23: ((a+t)*((b+(a+c))^(c+d)))

assistant: ```c
void mainTest(int argc, char **argv) {
  convertToRPN("(a+(b*c))");
  convertToRPN("a*b+c");
  convertToRPN("((a+t)*((b+(a+c))^(c+d)))");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mainTest>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <convertToRPN@plt>
  lea    D25(%rip),%rdi
  call   <convertToRPN@plt>
  lea    D17(%rip),%rdi
  call   <convertToRPN@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D25
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string

tool: D6: (a+(b*c))

tool: D25: a*b+c

tool: D17: ((a+t)*((b+(a+c))^(c+d)))

assistant: ```c
void mainTest(int argc, char **argv) {
  convertToRPN("(a+(b*c))");
  convertToRPN("a*b+c");
  convertToRPN("((a+t)*((b+(a+c))^(c+d)))");
}
```
user: Translate the below assembly code into C programming language:

```asm
<mainTest>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <convertToRPN@plt>
  lea    D11(%rip),%rdi
  call   <convertToRPN@plt>
  lea    D28(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <convertToRPN@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string

tool: D19: (a+(b*c))

tool: D11: a*b+c

tool: D28: ((a+t)*((b+(a+c))^(c+d)))

assistant: ```c
void mainTest(int argc, char **argv) {
  convertToRPN("(a+(b*c))");
  convertToRPN("a*b+c");
  convertToRPN("((a+t)*((b+(a+c))^(c+d)))");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mainTest>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <convertToRPN@plt>
  lea    D13(%rip),%rdi
  call   <convertToRPN@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <convertToRPN@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D4
type: string

tool: D12: (a+(b*c))

tool: D13: a*b+c

tool: D4: ((a+t)*((b+(a+c))^(c+d)))

assistant: ```c
void mainTest(int argc, char **argv) {
  convertToRPN("(a+(b*c))");
  convertToRPN("a*b+c");
  convertToRPN("((a+t)*((b+(a+c))^(c+d)))");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<qromo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %rdi,%r15
  movss  %xmm0,0x10(%rsp)
  movss  %xmm1,0x14(%rsp)
  mov    %rsi,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,0x34(%rsp)
  mov    $0x1,%esi
  call   *%r14
  movss  %xmm0,0x74(%rsp)
  lea    0x24(%rsp),%r12
  lea    0x64(%rsp),%rbx
  mov    $0x1,%ebp
  lea    0x2c(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L51
L17:
  add    $0x4,%r12
  add    $0x4,%rbx
L51:
  add    $0x1,%ebp
  mov    %rbx,%r13
  movss  0x10(%rbx),%xmm0
  movss  %xmm0,0x14(%rbx)
  mov    %r12,0x8(%rsp)
  movss  0x10(%r12),%xmm0
  divss  D14(%rip),%xmm0
  movss  %xmm0,0x14(%r12)
  cmp    $0xf,%ebp
  je     L21
  mov    %ebp,%esi
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  mov    %r15,%rdi
  call   *%r14
  movss  %xmm0,0x14(%rbx)
  cmp    $0x4,%ebp
  jle    L17
  lea    0x28(%rsp),%rcx
  mov    0x18(%rsp),%r8
  pxor   %xmm0,%xmm0
  mov    $0x5,%edx
  mov    %r13,%rsi
  mov    0x8(%rsp),%rdi
  call   <polint@plt>
  movss  0x2c(%rsp),%xmm0
  call   <fabs@plt>
  movq   %xmm0,%r13
  movss  0x28(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D13(%rip),%xmm0
  movq   %r13,%xmm2
  comisd %xmm2,%xmm0
  jbe    L17
  movss  0x28(%rsp),%xmm0
  jmp    L4
L21:
  lea    D25(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L4:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
type_infered: f32
name: disassemble_data
arguments: label: D13
type_infered: byte[8]
name: disassemble_data
arguments: label: D25
type_infered: string

tool: D14: 9

tool: {"D13": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D25: Too many steps in routing qromo

assistant: ```c
float qromo(float (*func)(float), float a, float b, float (*choose)(float (*)(float), float, float, int)) {
  void polint(float xa[], float ya[], int n, float x, float *y, float *dy);
  void nrerror(char error_text[]);
  int j;
  float ss, dss, h[(14 + 1) + 1], s[(14 + 1) + 1];
  h[1] = 1.0;
  for (j = 1; j <= 14; j++) {
    s[j] = (*choose)(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 1.0e-6 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = h[j] / 9.0;
  }
  nrerror("Too many steps in routing qromo");
  return 0.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<qromo>:
  endbr64
  push   %r15
  movd   %xmm0,%r15d
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movss  %xmm1,(%rsp)
  lea    0x14(%rsp),%r14
  lea    0x54(%rsp),%r12
  movl   $0x3f800000,0x24(%rsp)
  call   *%rbx
  movss  (%rsp),%xmm1
  movss  %xmm0,0x64(%rsp)
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L12:
  movss  %xmm1,(%rsp)
  mov    %r13d,%esi
  movd   %r15d,%xmm0
  mov    %rbp,%rdi
  call   *%rbx
  cmp    $0x4,%r13d
  movss  (%rsp),%xmm1
  movss  %xmm0,0x14(%r12)
  jle    L58
  lea    0x18(%rsp),%rcx
  lea    0x1c(%rsp),%r8
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    $0x5,%edx
  pxor   %xmm0,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <polint@plt>
  movss  0x1c(%rsp),%xmm0
  call   <fabs@plt>
  movsd  %xmm0,(%rsp)
  movss  0x18(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D22(%rip),%xmm0
  comisd (%rsp),%xmm0
  ja     L49
  movss  0x14(%r12),%xmm0
  movss  0xc(%rsp),%xmm1
L58:
  add    $0x4,%r14
  add    $0x4,%r12
L4:
  add    $0x1,%r13d
  movss  %xmm0,0x14(%r12)
  movss  0x10(%r14),%xmm0
  divss  D16(%rip),%xmm0
  movss  %xmm0,0x14(%r14)
  cmp    $0xf,%r13d
  jne    L12
  lea    D7(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L59:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L49:
  movss  0x18(%rsp),%xmm0
  jmp    L59
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D16
type_guessed: f32
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: {"D22": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D16: 9

tool: D7: Too many steps in routing qromo

assistant: ```c
float qromo(float (*func)(float), float a, float b, float (*choose)(float (*)(float), float, float, int)) {
  void polint(float xa[], float ya[], int n, float x, float *y, float *dy);
  void nrerror(char error_text[]);
  int j;
  float ss, dss, h[(14 + 1) + 1], s[(14 + 1) + 1];
  h[1] = 1.0;
  for (j = 1; j <= 14; j++) {
    s[j] = (*choose)(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 1.0e-6 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = h[j] / 9.0;
  }
  nrerror("Too many steps in routing qromo");
  return 0.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<qromo>:
  endbr64
  push   %r15
  movd   %xmm0,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  mov    $0x1,%esi
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movss  %xmm1,(%rsp)
  lea    0x14(%rsp),%r12
  lea    0x54(%rsp),%rbx
  movl   $0x3f800000,0x24(%rsp)
  call   *%r13
  movss  (%rsp),%xmm1
  movss  %xmm0,0x64(%rsp)
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L47:
  movss  %xmm1,(%rsp)
  mov    %ebp,%esi
  movd   %r15d,%xmm0
  mov    %r14,%rdi
  call   *%r13
  cmp    $0x4,%ebp
  movss  (%rsp),%xmm1
  movss  %xmm0,0x14(%rbx)
  jle    L44
  lea    0x18(%rsp),%rcx
  lea    0x1c(%rsp),%r8
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x5,%edx
  pxor   %xmm0,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <polint@plt>
  movss  0x1c(%rsp),%xmm0
  call   <fabs@plt>
  movsd  %xmm0,(%rsp)
  movss  0x18(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D20(%rip),%xmm0
  movss  0xc(%rsp),%xmm1
  comisd (%rsp),%xmm0
  ja     L37
L44:
  add    $0x4,%r12
  add    $0x4,%rbx
L52:
  movss  0x10(%rbx),%xmm0
  add    $0x1,%ebp
  movss  %xmm0,0x14(%rbx)
  movss  0x10(%r12),%xmm0
  divss  D15(%rip),%xmm0
  movss  %xmm0,0x14(%r12)
  cmp    $0xf,%ebp
  jne    L47
  lea    D3(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm0,%xmm0
L21:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L37:
  movss  0x18(%rsp),%xmm0
  jmp    L21
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D20
datatype: byte[8]
name: read_data
arguments: label: D15
datatype: f32
name: read_data
arguments: label: D3
datatype: string

tool: {"D20": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D15: 9

tool: D3: Too many steps in routing qromo

assistant: ```c
float qromo(float (*func)(float), float a, float b, float (*choose)(float (*)(float), float, float, int)) {
  void polint(float xa[], float ya[], int n, float x, float *y, float *dy);
  void nrerror(char error_text[]);
  int j;
  float ss, dss, h[(14 + 1) + 1], s[(14 + 1) + 1];
  h[1] = 1.0;
  for (j = 1; j <= 14; j++) {
    s[j] = (*choose)(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 1.0e-6 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = h[j] / 9.0;
  }
  nrerror("Too many steps in routing qromo");
  return 0.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0xa,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <rotate@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int a[7] = {1, 2, 3, 4, 5, 6, 7};
  int k = 10;
  rotate(a, 7, k);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0xa,%edx
  mov    $0x7,%esi
  call   <rotate@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[7] = {1, 2, 3, 4, 5, 6, 7};
  int k = 10;
  rotate(a, 7, k);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xa,%edx
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  movl   $0x7,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  call   <rotate@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[7] = {1, 2, 3, 4, 5, 6, 7};
  int k = 10;
  rotate(a, 7, k);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xa,%edx
  mov    $0x7,%esi
  movdqa D9(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %rsp,%rdi
  movl   $0x7,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <rotate@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D1
type_infered: byte[8]

tool: {"D9": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D1": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[7] = {1, 2, 3, 4, 5, 6, 7};
  int k = 10;
  rotate(a, 7, k);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x2e2c73696854202d,%rax
  movabs $0x706d61732061202e,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6e6972747320656c,%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x2e67,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  lea    D22(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok1@plt>
  mov    %rax,-0x38(%rbp)
  jmp    L19
L9:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok1@plt>
  mov    %rax,-0x38(%rbp)
L19:
  cmpq   $0x0,-0x38(%rbp)
  jne    L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D36
datatype: string

tool: D2: Splitting string "%s" into tokens:


tool: D22:  ,.-

tool: D36: %s


assistant: ```c
int main() {
  char str[] = "- This,.. a sample string.";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok1(str, " ,.-");
  while (pch != NULL) {
    printf("%s\n", pch);
    pch = strtok1(NULL, " ,.-");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x2e2c73696854202d,%rax
  movabs $0x706d61732061202e,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x6e6972747320656c,%rax
  mov    %rax,0x10(%rsp)
  movw   $0x2e67,0x18(%rsp)
  movb   $0x0,0x1a(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok1@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rsi
  lea    D9(%rip),%rbp
  lea    D24(%rip),%rbx
L29:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok1@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L29
L9:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D24
type_infered: string
name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D8: Splitting string "%s" into tokens:


tool: D24:  ,.-

tool: D9: %s


assistant: ```c
int main() {
  char str[] = "- This,.. a sample string.";
  char *pch;
  printf("Splitting string \"%s\" into tokens:\n", str);
  pch = strtok1(str, " ,.-");
  while (pch != NULL) {
    printf("%s\n", pch);
    pch = strtok1(NULL, " ,.-");
  }
  return 0;
}
```