ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L21:
  test   %dl,%dl
  je     L1
  cmp    %dl,%cl
  jl     L43
  add    $0x1,%rax
  cmp    %dl,%cl
  jg     L1
L23:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  test   %cl,%cl
  jne    L21
  neg    %dl
  sbb    %eax,%eax
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L43:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (c1 < c2)
      return -1;
    else if (c1 > c2)
      return 1;
  }
  if (*s2)
    return -1;
  else if (*s1)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcmp>:
  endbr64
  xor    %eax,%eax
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L18:
  test   %dl,%dl
  je     L19
  cmp    %dl,%cl
  jl     L22
  add    $0x1,%rax
  cmp    %dl,%cl
  jg     L19
L6:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rsi,%rax,1),%edx
  test   %cl,%cl
  jne    L18
  neg    %dl
  sbb    %eax,%eax
  ret
  nopl   0x0(%rax)
L19:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int strcmp(const char *s1, const char *s2) {
  while (*s1 && *s2) {
    char c1 = *s1++;
    char c2 = *s2++;
    if (c1 < c2)
      return -1;
    else if (c1 > c2)
      return 1;
  }
  if (*s2)
    return -1;
  else if (*s1)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mat4f_rotateEuler_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  movss  %xmm0,-0x3c(%rbp)
  movss  %xmm1,-0x40(%rbp)
  movss  %xmm2,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rcx
  movss  -0x44(%rbp),%xmm1
  movss  -0x40(%rbp),%xmm0
  mov    -0x3c(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %edx,%xmm0
  mov    %rax,%rdi
  call   <mat3f_rotateEuler_new@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mat4f_from_mat3f@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void mat4f_rotateEuler_new(float result[16], float a1_degrees, float a2_degrees, float a3_degrees, const char order[3]) {
  float tmpMat[9];
  mat3f_rotateEuler_new(tmpMat, a1_degrees, a2_degrees, a3_degrees, order);
  mat4f_from_mat3f(result, tmpMat);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mat4f_rotateEuler_new>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <mat3f_rotateEuler_new@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mat4f_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4f_rotateEuler_new(float result[16], float a1_degrees, float a2_degrees, float a3_degrees, const char order[3]) {
  float tmpMat[9];
  mat3f_rotateEuler_new(tmpMat, a1_degrees, a2_degrees, a3_degrees, order);
  mat4f_from_mat3f(result, tmpMat);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mat4f_rotateEuler_new>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <mat3f_rotateEuler_new@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mat4f_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4f_rotateEuler_new(float result[16], float a1_degrees, float a2_degrees, float a3_degrees, const char order[3]) {
  float tmpMat[9];
  mat3f_rotateEuler_new(tmpMat, a1_degrees, a2_degrees, a3_degrees, order);
  mat4f_from_mat3f(result, tmpMat);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mat4f_rotateEuler_new>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <mat3f_rotateEuler_new@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mat4f_from_mat3f@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mat4f_rotateEuler_new(float result[16], float a1_degrees, float a2_degrees, float a3_degrees, const char order[3]) {
  float tmpMat[9];
  mat3f_rotateEuler_new(tmpMat, a1_degrees, a2_degrees, a3_degrees, order);
  mat4f_from_mat3f(result, tmpMat);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string
name: parse_data
arguments: data_label: D31
datatype: string
name: parse_data
arguments: data_label: D29
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string

tool: D0: -------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------





tool: D31: Enter a string: 

tool: D29: %255s

tool: D21: Copied string: %s


assistant: ```c
int main() {
  char *str = malloc(256);
  printf("-------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------\n\n\n\n\n");
  printf("Enter a string: ");
  scanf("%255s", str);
  char *dest = malloc(256);
  strcpy(str, dest);
  printf("Copied string: %s\n", dest);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D31
type_infered: string
name: disassemble_data
arguments: tag: D39
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D35
type_infered: string

tool: D31: -------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------





tool: D39: Enter a string: 

tool: D1: %255s

tool: D35: Copied string: %s


assistant: ```c
int main() {
  char *str = malloc(256);
  printf("-------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------\n\n\n\n\n");
  printf("Enter a string: ");
  scanf("%255s", str);
  char *dest = malloc(256);
  strcpy(str, dest);
  printf("Copied string: %s\n", dest);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D10(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D23
datatype: string

tool: D10: -------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------





tool: D37: Enter a string: 

tool: D2: %255s

tool: D23: Copied string: %s


assistant: ```c
int main() {
  char *str = malloc(256);
  printf("-------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------\n\n\n\n\n");
  printf("Enter a string: ");
  scanf("%255s", str);
  char *dest = malloc(256);
  strcpy(str, dest);
  printf("Copied string: %s\n", dest);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x100,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D24(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string

tool: D24: -------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------





tool: D17: Enter a string: 

tool: D10: %255s

tool: D12: Copied string: %s


assistant: ```c
int main() {
  char *str = malloc(256);
  printf("-------------------PROGRAM THAT COPIES A STRING TO A LOCATION-------------------\n\n\n\n\n");
  printf("Enter a string: ");
  scanf("%255s", str);
  char *dest = malloc(256);
  strcpy(str, dest);
  printf("Copied string: %s\n", dest);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<AddRoundKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    $0x4,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%esi
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    $0xc,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  xor    %ecx,%esi
  mov    %esi,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x3,-0x4(%rbp)
  jle    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AddRoundKey(unsigned char state[16], unsigned long key[4]) {
  int i, j;
  unsigned char temp;
  for (i = 0; i < 4; i++) {
    state[i] ^= key[0] >> (24 - i * 8);
    state[4 + i] ^= key[1] >> (24 - i * 8);
    state[8 + i] ^= key[2] >> (24 - i * 8);
    state[12 + i] ^= key[3] >> (24 - i * 8);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<AddRoundKey>:
  endbr64
  mov    $0x18,%ecx
L8:
  mov    (%rsi),%rax
  shr    %cl,%rax
  xor    %al,(%rdi)
  mov    0x8(%rsi),%rax
  shr    %cl,%rax
  xor    %al,0x4(%rdi)
  mov    0x10(%rsi),%rax
  shr    %cl,%rax
  xor    %al,0x8(%rdi)
  mov    0x18(%rsi),%rax
  shr    %cl,%rax
  xor    %al,0xc(%rdi)
  add    $0x1,%rdi
  sub    $0x8,%ecx
  cmp    $0xfffffff8,%ecx
  jne    L8
  ret
```

assistant: ```c
void AddRoundKey(unsigned char state[16], unsigned long key[4]) {
  int i, j;
  unsigned char temp;
  for (i = 0; i < 4; i++) {
    state[i] ^= key[0] >> (24 - i * 8);
    state[4 + i] ^= key[1] >> (24 - i * 8);
    state[8 + i] ^= key[2] >> (24 - i * 8);
    state[12 + i] ^= key[3] >> (24 - i * 8);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<AddRoundKey>:
  endbr64
  mov    $0x18,%ecx
L1:
  mov    (%rsi),%rax
  shr    %cl,%rax
  xor    %al,(%rdi)
  mov    0x8(%rsi),%rax
  shr    %cl,%rax
  xor    %al,0x4(%rdi)
  mov    0x10(%rsi),%rax
  shr    %cl,%rax
  xor    %al,0x8(%rdi)
  mov    0x18(%rsi),%rax
  shr    %cl,%rax
  sub    $0x8,%ecx
  xor    %al,0xc(%rdi)
  add    $0x1,%rdi
  cmp    $0xfffffff8,%ecx
  jne    L1
  ret
```

assistant: ```c
void AddRoundKey(unsigned char state[16], unsigned long key[4]) {
  int i, j;
  unsigned char temp;
  for (i = 0; i < 4; i++) {
    state[i] ^= key[0] >> (24 - i * 8);
    state[4 + i] ^= key[1] >> (24 - i * 8);
    state[8 + i] ^= key[2] >> (24 - i * 8);
    state[12 + i] ^= key[3] >> (24 - i * 8);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AddRoundKey>:
  endbr64
  movzbl 0x3(%rsi),%ecx
  xor    %cl,(%rdi)
  movzbl 0xb(%rsi),%ecx
  xor    %cl,0x4(%rdi)
  movzbl 0x13(%rsi),%ecx
  xor    %cl,0x8(%rdi)
  movzbl 0x1b(%rsi),%ecx
  xor    %cl,0xc(%rdi)
  movzbl 0x2(%rsi),%ecx
  xor    %cl,0x1(%rdi)
  movzbl 0xa(%rsi),%ecx
  xor    %cl,0x5(%rdi)
  movzbl 0x12(%rsi),%ecx
  xor    %cl,0x9(%rdi)
  movzbl 0x1a(%rsi),%ecx
  xor    %cl,0xd(%rdi)
  movzbl 0x1(%rsi),%ecx
  xor    %cl,0x2(%rdi)
  movzbl 0x9(%rsi),%ecx
  xor    %cl,0x6(%rdi)
  movzbl 0x11(%rsi),%ecx
  xor    %cl,0xa(%rdi)
  movzbl 0x19(%rsi),%ecx
  xor    %cl,0xe(%rdi)
  mov    (%rsi),%rcx
  xor    %cl,0x3(%rdi)
  mov    0x8(%rsi),%rcx
  xor    %cl,0x7(%rdi)
  mov    0x10(%rsi),%rcx
  xor    %cl,0xb(%rdi)
  mov    0x18(%rsi),%rdx
  xor    %dl,0xf(%rdi)
  ret
```

assistant: ```c
void AddRoundKey(unsigned char state[16], unsigned long key[4]) {
  int i, j;
  unsigned char temp;
  for (i = 0; i < 4; i++) {
    state[i] ^= key[0] >> (24 - i * 8);
    state[4 + i] ^= key[1] >> (24 - i * 8);
    state[8 + i] ^= key[2] >> (24 - i * 8);
    state[12 + i] ^= key[3] >> (24 - i * 8);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xrop3_140_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_140_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xrop3_140_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_140_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrop3_140_1_1>:
  endbr64
  or     %edi,%esi
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned xrop3_140_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L29
  cmpl   $0x1000,-0xc(%rbp)
  jle    L12
L29:
  movl   $0x1000,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L43
  mov    $0x1,%edi
  call   <exit@plt>
L43:
  movl   $0x0,-0x10(%rbp)
  jmp    L49
L27:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L27
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char *p;
  int i;
  int n = argc * (argc + 1);
  if (n <= 0 || n > 4096)
    n = 4096;
  p = malloc(n);
  if (!p) {
    exit(1);
  }
  for (i = 0; i <= n; i++) {
    putchar(p[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%ebp
  imul   %edi,%ebp
  lea    -0x1(%rbp),%eax
  cmp    $0xfff,%eax
  ja     L23
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L34
L61:
  mov    $0x0,%ebx
L49:
  movsbl (%r12,%rbx,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L49
L65:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    $0x1000,%ebp
L34:
  mov    $0x1,%edi
  call   <exit@plt>
  test   %ebp,%ebp
  js     L65
  mov    $0x0,%r12d
  jmp    L61
L23:
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L20
  mov    $0x1000,%ebp
  jmp    L61
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char *p;
  int i;
  int n = argc * (argc + 1);
  if (n <= 0 || n > 4096)
    n = 4096;
  p = malloc(n);
  if (!p) {
    exit(1);
  }
  for (i = 0; i <= n; i++) {
    putchar(p[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%ebp
  imul   %edi,%ebp
  push   %rbx
  lea    -0x1(%rbp),%eax
  sub    $0x8,%rsp
  cmp    $0x1000,%eax
  mov    $0x1000,%eax
  cmovae %eax,%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
L21:
  movslq %ebp,%rbp
  lea    0x1(%rbx,%rbp,1),%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L21
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char *p;
  int i;
  int n = argc * (argc + 1);
  if (n <= 0 || n > 4096)
    n = 4096;
  p = malloc(n);
  if (!p) {
    exit(1);
  }
  for (i = 0; i <= n; i++) {
    putchar(p[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    0x1(%rdi),%ebp
  imul   %edi,%ebp
  push   %rbx
  lea    -0x1(%rbp),%eax
  sub    $0x8,%rsp
  cmp    $0x1000,%eax
  mov    $0x1000,%eax
  cmovae %eax,%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L28:
  movslq %ebp,%rbp
  lea    0x1(%rbx,%rbp,1),%rbp
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L27
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L28
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char *p;
  int i;
  int n = argc * (argc + 1);
  if (n <= 0 || n > 4096)
    n = 4096;
  p = malloc(n);
  if (!p) {
    exit(1);
  }
  for (i = 0; i <= n; i++) {
    putchar(p[i]);
  }
}
```