user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x1d0(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x1c0(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L61:
  cmp    %rdx,%rsp
  je     L27
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L61
L27:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L52
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L52:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x1b8(%rbp)
  lea    -0x1b0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x1cc(%rbp)
L16:
  lea    -0x1d0(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1d0(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L16
  mov    -0x1d0(%rbp),%eax
  cmp    $0xc8,%eax
  jg     L16
  movl   $0x0,-0x1c4(%rbp)
  jmp    L109
L36:
  mov    -0x1c4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1b8(%rbp),%rax
  mov    -0x1c4(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  cmp    $0x64,%eax
  jg     L148
  mov    -0x1b8(%rbp),%rax
  mov    -0x1c4(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1b0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jg     L148
  mov    -0x1b8(%rbp),%rax
  mov    -0x1c4(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x1b0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x1b0(%rbp,%rax,4)
  movl   $0x1,-0x1cc(%rbp)
L148:
  cmpl   $0x0,-0x1cc(%rbp)
  je     L36
  movl   $0x0,-0x1cc(%rbp)
  addl   $0x1,-0x1c4(%rbp)
L109:
  mov    -0x1d0(%rbp),%eax
  cmp    %eax,-0x1c4(%rbp)
  jl     L36
  movl   $0x0,-0x1c4(%rbp)
  jmp    L24
L33:
  mov    -0x1c4(%rbp),%eax
  cltq
  mov    -0x1b0(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L141
  mov    -0x1c4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c8(%rbp)
  jmp    L146
L141:
  addl   $0x1,-0x1c4(%rbp)
L24:
  cmpl   $0x63,-0x1c4(%rbp)
  jle    L33
L146:
  mov    -0x1c8(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
data_type: string
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: D29: %d

tool: D18: Rudolf is: %d 


assistant: ```c
int main() {
  int n;
  int deers[n];
  int s[100] = {0};
  int k = 0, Rudolf, i;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n >= 201);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &deers[i]);
      if ((deers[i] - 1) < 100) {
        if (s[deers[i] - 1] < 2) {
          s[deers[i] - 1]++;
          k = 1;
        }
      }
    } while (k == 0);
    k = 0;
  }
  for (i = 0; i < 100; i++) {
    if (s[i] == 1) {
      Rudolf = i + 1;
      break;
    }
  }
  printf("Rudolf is: %d \n", Rudolf);
  return 0;
}
```