ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D14(%rip),%rdi
  lea    D42(%rip),%r14
  push   %r13
  lea    D48(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  call   <puts@plt>
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %r14,%rdi
  call   <puts@plt>
L39:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  test   %edi,%edi
  jle    L32
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L32
  call   <gcd@plt>
  lea    D31(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D42
type_guessed: string
name: read_data
arguments: tag: D48
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D31
type_guessed: string

tool: D14: -- The GCD Finder --

tool: D42: 
Wrong input!

tool: D48: Enter two positive numbers: 

tool: D19: %d %d

tool: D31: The GCD of given numbers is: %d


assistant: ```c
int main() {
  int a, b;
  printf("-- The GCD Finder --\n");
  while (1) {
    printf("Enter two positive numbers: ");
    scanf("%d %d", &a, &b);
    if (a >= 1 && b >= 1)
      break;
    else
      printf("\nWrong input!\n");
  }
  printf("The GCD of given numbers is: %d\n", gcd(a, b));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rapl_dram_available>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rapl_get_cpu_model@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2a,-0x4(%rbp)
  je     L20
  cmpl   $0x3a,-0x4(%rbp)
  jne    L8
L20:
  mov    $0x0,%eax
  jmp    L26
L8:
  mov    $0x1,%eax
L26:
  leave
  ret
```

assistant: ```c
char rapl_dram_available() {
  int cpu_id = rapl_get_cpu_model();
  if (cpu_id == 0x2a || cpu_id == 0x3a)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rapl_dram_available>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rapl_get_cpu_model@plt>
  and    $0xffffffef,%eax
  cmp    $0x2a,%eax
  setne  %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char rapl_dram_available() {
  int cpu_id = rapl_get_cpu_model();
  if (cpu_id == 0x2a || cpu_id == 0x3a)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rapl_dram_available>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rapl_get_cpu_model@plt>
  and    $0xffffffef,%eax
  cmp    $0x2a,%eax
  setne  %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char rapl_dram_available() {
  int cpu_id = rapl_get_cpu_model();
  if (cpu_id == 0x2a || cpu_id == 0x3a)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rapl_dram_available>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rapl_get_cpu_model@plt>
  and    $0xffffffef,%eax
  cmp    $0x2a,%eax
  setne  %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char rapl_dram_available() {
  int cpu_id = rapl_get_cpu_model();
  if (cpu_id == 0x2a || cpu_id == 0x3a)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x5,-0x8(%rbp)
  jmp    L15
L6:
  cmpl   $0x5,-0x8(%rbp)
  jne    L15
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <f@plt>
L15:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int i = 1;
  int x = 5;
  while (i--) {
    int hello;
    if (x == 5) {
      int pad = 0;
      f();
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i = 1;
  int x = 5;
  while (i--) {
    int hello;
    if (x == 5) {
      int pad = 0;
      f();
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i = 1;
  int x = 5;
  while (i--) {
    int hello;
    if (x == 5) {
      int pad = 0;
      f();
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i = 1;
  int x = 5;
  while (i--) {
    int hello;
    if (x == 5) {
      int pad = 0;
      f();
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <getchar@plt>
  sub    $0xa,%eax
  cmp    $0x2f,%eax
  ja     L22
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D4(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D4(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  call   <sign>
  jmp    L22
  mov    $0x0,%eax
  call   <fraction@plt>
  jmp    L22
  mov    $0x0,%eax
  call   <integer@plt>
  jmp    L22
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L22:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D27
datatype: string

tool: D27: Rejected by method 1


assistant: ```c
void sign(void) {
  switch (getchar()) {
  case '+':
  case '-':
    sign();
    return;
  case '.':
    fraction();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    integer();
    return;
  case '\n':
    printf("Rejected by method 1\n");
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sign>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  sub    $0xa,%eax
  cmp    $0x2f,%eax
  ja     L25
  mov    %eax,%eax
  lea    D1(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  call   <sign>
L25:
  add    $0x8,%rsp
  ret
  mov    $0x0,%eax
  call   <fraction@plt>
  jmp    L25
  mov    $0x0,%eax
  call   <integer@plt>
  jmp    L25
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: Rejected by method 1


assistant: ```c
void sign(void) {
  switch (getchar()) {
  case '+':
  case '-':
    sign();
    return;
  case '.':
    fraction();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    integer();
    return;
  case '\n':
    printf("Rejected by method 1\n");
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sign>:
  endbr64
  push   %rbx
  lea    D15(%rip),%rbx
  xor    %eax,%eax
  call   <getchar@plt>
  sub    $0xa,%eax
  cmp    $0x2f,%eax
  ja     L0
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L0:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <integer@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  pop    %rbx
  jmp    10a0 <fraction@plt>
  nopl   0x0(%rax,%rax,1)
  lea    D0(%rip),%rdi
  pop    %rbx
  jmp    1090 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: Rejected by method 1


assistant: ```c
void sign(void) {
  switch (getchar()) {
  case '+':
  case '-':
    sign();
    return;
  case '.':
    fraction();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    integer();
    return;
  case '\n':
    printf("Rejected by method 1\n");
    return;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sign>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rbx
  xor    %eax,%eax
  call   <getchar@plt>
  sub    $0xa,%eax
  cmp    $0x2f,%eax
  ja     L3
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   (%rax)
L3:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  pop    %rbx
  jmp    1080 <integer@plt>
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  pop    %rbx
  jmp    10a0 <fraction@plt>
  nopl   0x0(%rax,%rax,1)
  lea    D5(%rip),%rdi
  pop    %rbx
  jmp    1090 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: Rejected by method 1


assistant: ```c
void sign(void) {
  switch (getchar()) {
  case '+':
  case '-':
    sign();
    return;
  case '.':
    fraction();
    return;
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
    integer();
    return;
  case '\n':
    printf("Rejected by method 1\n");
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<M408_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D14: M408_f(const char *s) is not yet implemented!


tool: D10: %s


assistant: ```c
int M408_f(char *s) {
  debug("M408_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<M408_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D1
type: string

tool: D14: M408_f(const char *s) is not yet implemented!


tool: D1: %s


assistant: ```c
int M408_f(char *s) {
  debug("M408_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<M408_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D19
type_guessed: string

tool: D1: M408_f(const char *s) is not yet implemented!


tool: D19: %s


assistant: ```c
int M408_f(char *s) {
  debug("M408_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<M408_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D3: M408_f(const char *s) is not yet implemented!


tool: D13: %s


assistant: ```c
int M408_f(char *s) {
  debug("M408_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L13
  addl   $0x1,-0x8(%rbp)
L13:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L22
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count(int a[], int size, int n) {
  int counter = 0;
  for (int i = 0; i < size; i++) {
    if (a[i] == n)
      counter++;
  }
  return counter;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x4(%rdi,%rcx,4),%rdi
  mov    $0x0,%ecx
L5:
  cmp    %edx,(%rax)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ecx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L5
L27:
  mov    %ecx,%eax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L27
```

assistant: ```c
int count(int a[], int size, int n) {
  int counter = 0;
  for (int i = 0; i < size; i++) {
    if (a[i] == n)
      counter++;
  }
  return counter;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<count>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %ecx,%ecx
  cmp    %edx,(%rdi)
  sete   %cl
  add    $0x4,%rdi
  add    %ecx,%eax
  cmp    %rsi,%rdi
  jne    L16
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count(int a[], int size, int n) {
  int counter = 0;
  for (int i = 0; i < size; i++) {
    if (a[i] == n)
      counter++;
  }
  return counter;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L26
  shr    $0x2,%esi
  movd   %edx,%xmm3
  pxor   %xmm0,%xmm0
  mov    %rdi,%rax
  sub    $0x1,%esi
  pshufd $0x0,%xmm3,%xmm2
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   0x0(%rax)
L23:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  pcmpeqd %xmm2,%xmm1
  psubd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L23
  movdqa %xmm0,%xmm1
  mov    %ecx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%cl
  je     L30
L96:
  movslq %esi,%rdi
  lea    0x0(,%rdi,4),%r9
  cmp    %edx,(%r8,%rdi,4)
  je     L108
L109:
  lea    0x1(%rsi),%edi
  cmp    %ecx,%edi
  jge    L115
  cmp    0x4(%r8,%r9,1),%edx
  je     L113
L38:
  add    $0x2,%esi
  cmp    %esi,%ecx
  jle    L115
  cmp    0x8(%r8,%r9,1),%edx
  je     L97
L115:
  ret
  nopl   0x0(%rax,%rax,1)
L108:
  add    $0x1,%eax
  jmp    L109
  nopl   (%rax)
L113:
  add    $0x1,%eax
  jmp    L38
  nopl   (%rax)
L30:
  ret
  nopl   0x0(%rax)
L97:
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
L26:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L96
```

assistant: ```c
int count(int a[], int size, int n) {
  int counter = 0;
  for (int i = 0; i < size; i++) {
    if (a[i] == n)
      counter++;
  }
  return counter;
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_llen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L1:
  addl   $0x1,-0x4(%rbp)
  shrq   $0x7,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L1
  cmpl   $0x8,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int calc_llen(size_t len) {
  int n = 0;
  do {
    n++;
  } while (len >>= 7);
  assert(n <= (int)sizeof(len));
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<calc_llen>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L3:
  add    $0x1,%ebx
  shr    $0x7,%rdi
  jne    L3
  cmp    $0x8,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int calc_llen(size_t len) {
  int n = 0;
  do {
    n++;
  } while (len >>= 7);
  assert(n <= (int)sizeof(len));
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calc_llen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L2:
  add    $0x1,%r12d
  shr    $0x7,%rdi
  jne    L2
  xor    %edi,%edi
  cmp    $0x8,%r12d
  setle  %dil
  call   <assert@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int calc_llen(size_t len) {
  int n = 0;
  do {
    n++;
  } while (len >>= 7);
  assert(n <= (int)sizeof(len));
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calc_llen>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L0:
  add    $0x1,%r12d
  shr    $0x7,%rdi
  jne    L0
  xor    %edi,%edi
  cmp    $0x8,%r12d
  setle  %dil
  call   <assert@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int calc_llen(size_t len) {
  int n = 0;
  do {
    n++;
  } while (len >>= 7);
  assert(n <= (int)sizeof(len));
  return n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L31
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L31
L4:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  jmp    L31
L23:
  nop
L31:
  cmpq   $0x0,-0x8(%rbp)
  jne    L48
  cmpq   $0x0,-0x38(%rbp)
  je     L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L12
L3:
  nop
L12:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
L48:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      continue;
  }
  return s - src - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L54
  sub    $0x1,%rdx
  je     L33
  mov    %rsi,%rax
L66:
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%rdi)
  test   %cl,%cl
  je     L17
  sub    $0x1,%rdx
  jne    L66
  jmp    L21
L54:
  mov    %rsi,%rax
L81:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L81
L23:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L33:
  mov    %rsi,%rax
L21:
  movb   $0x0,(%rdi)
  jmp    L81
L17:
  test   %rdx,%rdx
  jne    L23
  jmp    L21
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      continue;
  }
  return s - src - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L18
  cmp    $0x1,%rdx
  je     L17
  mov    %rdi,%rcx
  nopl   (%rax)
L24:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L41
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  jne    L24
  mov    %rcx,%rdi
L17:
  movb   $0x0,(%rdi)
L18:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L18
L41:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      continue;
  }
  return s - src - 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlcpy>:
  endbr64
  mov    %rsi,%rax
  test   %rdx,%rdx
  je     L21
  cmp    $0x1,%rdx
  je     L23
  mov    %rdi,%rcx
  nopl   (%rax)
L1:
  movzbl (%rax),%r8d
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L38
  mov    %rdx,%r8
  sub    %rcx,%r8
  lea    -0x1(%rdi,%r8,1),%r8
  test   %r8,%r8
  jne    L1
  mov    %rcx,%rdi
L23:
  movb   $0x0,(%rdi)
L21:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L21
L38:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      continue;
  }
  return s - src - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gui_confirm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gui_draw_message@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <gui_wait_for_key@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <gui_delete_message@plt>
  cmpl   $0x79,-0x4(%rbp)
  je     L9
  cmpl   $0x59,-0x4(%rbp)
  jne    L5
L9:
  mov    $0x1,%eax
  jmp    L0
L5:
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: yYnN

assistant: ```c
int gui_confirm(char *msg) {
  int c;
  gui_draw_message(msg);
  c = gui_wait_for_key("yYnN");
  gui_delete_message();
  return ((c == 'y') || (c == 'Y')) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gui_confirm>:
  endbr64
  push   %rbx
  call   <gui_draw_message@plt>
  lea    D5(%rip),%rdi
  call   <gui_wait_for_key@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <gui_delete_message@plt>
  and    $0xffffffdf,%ebx
  cmp    $0x59,%ebx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: yYnN

assistant: ```c
int gui_confirm(char *msg) {
  int c;
  gui_draw_message(msg);
  c = gui_wait_for_key("yYnN");
  gui_delete_message();
  return ((c == 'y') || (c == 'Y')) ? 1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gui_confirm>:
  endbr64
  push   %rbx
  call   <gui_draw_message@plt>
  lea    D2(%rip),%rdi
  call   <gui_wait_for_key@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gui_delete_message@plt>
  and    $0xffffffdf,%ebx
  xor    %eax,%eax
  cmp    $0x59,%ebx
  pop    %rbx
  sete   %al
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: yYnN

assistant: ```c
int gui_confirm(char *msg) {
  int c;
  gui_draw_message(msg);
  c = gui_wait_for_key("yYnN");
  gui_delete_message();
  return ((c == 'y') || (c == 'Y')) ? 1 : 0;
}
```