ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgets2>:
  endbr64
  push   %r13
  lea    (%rsi,%rdx,1),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L23
  nopl   (%rax)
L27:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L17
  mov    %al,(%rbx)
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    $0xa,%eax
  je     L12
L23:
  cmp    %r13,%rbx
  jne    L27
L12:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L17:
  add    $0x8,%rsp
  mov    $0xffffffff,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fgets2(FILE *in, char *buf, size_t n) {
  int count = 0, c;
  while (n-- > 0) {
    if ((c = fgetc(in)) == EOF)
      return -1;
    buf[count++] = (char)c;
    if (c == '\n')
      return count;
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eddyViscosity_2D_Update>:
  endbr64
  test   %edi,%edi
  jle    L8
  mov    %edi,%edi
  shl    $0x5,%rdi
  mov    $0x0,%eax
L10:
  movsd  (%rsi),%xmm0
  addsd  %xmm0,%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  movsd  0x18(%rdx,%rax,1),%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx,%rax,1)
  movsd  0x10(%r8,%rax,1),%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,0x10(%r8,%rax,1)
  movsd  (%rcx,%rax,1),%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  movsd  (%rsi),%xmm0
  addsd  %xmm0,%xmm0
  addsd  0x18(%rcx,%rax,1),%xmm0
  movsd  %xmm0,0x18(%rcx,%rax,1)
  movsd  0x8(%r9,%rax,1),%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,0x8(%r9,%rax,1)
  add    $0x8,%rsi
  add    $0x20,%rax
  cmp    %rdi,%rax
  jne    L10
L8:
  ret
```

assistant: ```c
void eddyViscosity_2D_Update(const int nPoints, const double *nu_t, double *mom_u_diff_ten, double *mom_v_diff_ten, double *mom_uv_diff_ten, double *mom_vu_diff_ten) {
  int i;
  for (i = 0; i < nPoints; i++) {
    mom_u_diff_ten[i * 4 + 0] += 2.0 * nu_t[i];
    mom_u_diff_ten[i * 4 + 3] += nu_t[i];
    mom_uv_diff_ten[i * 4 + 2] += nu_t[i];
    mom_v_diff_ten[i * 4 + 0] += nu_t[i];
    mom_v_diff_ten[i * 4 + 3] += 2.0 * nu_t[i];
    mom_vu_diff_ten[i * 4 + 1] += nu_t[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eddyViscosity_2D_Update>:
  endbr64
  test   %edi,%edi
  jle    L18
  movslq %edi,%rdi
  xor    %eax,%eax
  shl    $0x5,%rdi
  nopl   (%rax)
L7:
  movsd  (%rsi),%xmm0
  add    $0x8,%rsi
  addsd  %xmm0,%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  movsd  0x18(%rdx,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx,%rax,1)
  movsd  0x10(%r8,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%r8,%rax,1)
  movsd  (%rcx,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  movsd  -0x8(%rsi),%xmm0
  addsd  %xmm0,%xmm0
  addsd  0x18(%rcx,%rax,1),%xmm0
  movsd  %xmm0,0x18(%rcx,%rax,1)
  movsd  0x8(%r9,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%r9,%rax,1)
  add    $0x20,%rax
  cmp    %rax,%rdi
  jne    L7
L18:
  ret
```

assistant: ```c
void eddyViscosity_2D_Update(const int nPoints, const double *nu_t, double *mom_u_diff_ten, double *mom_v_diff_ten, double *mom_uv_diff_ten, double *mom_vu_diff_ten) {
  int i;
  for (i = 0; i < nPoints; i++) {
    mom_u_diff_ten[i * 4 + 0] += 2.0 * nu_t[i];
    mom_u_diff_ten[i * 4 + 3] += nu_t[i];
    mom_uv_diff_ten[i * 4 + 2] += nu_t[i];
    mom_v_diff_ten[i * 4 + 0] += nu_t[i];
    mom_v_diff_ten[i * 4 + 3] += 2.0 * nu_t[i];
    mom_vu_diff_ten[i * 4 + 1] += nu_t[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<eddyViscosity_2D_Update>:
  endbr64
  test   %edi,%edi
  jle    L8
  movslq %edi,%rdi
  xor    %eax,%eax
  shl    $0x5,%rdi
  nopl   (%rax)
L15:
  movsd  (%rsi),%xmm0
  add    $0x8,%rsi
  addsd  %xmm0,%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  movsd  0x18(%rdx,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,0x18(%rdx,%rax,1)
  movsd  0x10(%r8,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,0x10(%r8,%rax,1)
  movsd  (%rcx,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,(%rcx,%rax,1)
  movsd  -0x8(%rsi),%xmm0
  addsd  %xmm0,%xmm0
  addsd  0x18(%rcx,%rax,1),%xmm0
  movsd  %xmm0,0x18(%rcx,%rax,1)
  movsd  0x8(%r9,%rax,1),%xmm0
  addsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,0x8(%r9,%rax,1)
  add    $0x20,%rax
  cmp    %rax,%rdi
  jne    L15
L8:
  ret
```

assistant: ```c
void eddyViscosity_2D_Update(const int nPoints, const double *nu_t, double *mom_u_diff_ten, double *mom_v_diff_ten, double *mom_uv_diff_ten, double *mom_vu_diff_ten) {
  int i;
  for (i = 0; i < nPoints; i++) {
    mom_u_diff_ten[i * 4 + 0] += 2.0 * nu_t[i];
    mom_u_diff_ten[i * 4 + 3] += nu_t[i];
    mom_uv_diff_ten[i * 4 + 2] += nu_t[i];
    mom_v_diff_ten[i * 4 + 0] += nu_t[i];
    mom_v_diff_ten[i * 4 + 3] += 2.0 * nu_t[i];
    mom_vu_diff_ten[i * 4 + 1] += nu_t[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movb   $0xf6,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xf6,%al
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void foo(void) {
  int i;
  char *p;
  p = (char *)&i;
  *p = -10;
  if (*(unsigned char *)p != 0x100 - 10)
    abort();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  int i;
  char *p;
  p = (char *)&i;
  *p = -10;
  if (*(unsigned char *)p != 0x100 - 10)
    abort();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  int i;
  char *p;
  p = (char *)&i;
  *p = -10;
  if (*(unsigned char *)p != 0x100 - 10)
    abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  int i;
  char *p;
  p = (char *)&i;
  *p = -10;
  if (*(unsigned char *)p != 0x100 - 10)
    abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L78:
  addl   $0x1,-0xc(%rbp)
L35:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jge    L25
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L78
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L4
L58:
  subl   $0x1,-0x8(%rbp)
L4:
  cmpl   $0x0,-0x8(%rbp)
  js     L26
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L58
L26:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L33
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void strip(char *string, char *string2) {
  int i, j, k;
  for (i = 0; i < strlen(string) && string[i] == ' '; i++)
    ;
  for (j = strlen(string) - 1; j >= 0 && string[j] == ' '; j--)
    ;
  for (k = i; k <= j; k++)
    string2[k - i] = string[k];
  string2[j - i + 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L29:
  mov    %ebx,%r12d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L67
  add    $0x1,%rbx
  cmpb   $0x20,-0x1(%r13,%rbx,1)
  je     L29
L67:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L59
  movslq %eax,%rdx
  add    %r13,%rdx
L44:
  cmpb   $0x20,(%rdx)
  jne    L59
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L44
L59:
  cmp    %eax,%r12d
  jg     L60
  movslq %r12d,%rcx
  mov    %rcx,%rdx
  mov    %rbp,%rsi
  sub    %rcx,%rsi
L33:
  movzbl 0x0(%r13,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jge    L33
L60:
  sub    %r12d,%eax
  cltq
  movb   $0x0,0x1(%rbp,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strip(char *string, char *string2) {
  int i, j, k;
  for (i = 0; i < strlen(string) && string[i] == ' '; i++)
    ;
  for (j = strlen(string) - 1; j >= 0 && string[j] == ' '; j--)
    ;
  for (k = i; k <= j; k++)
    string2[k - i] = string[k];
  string2[j - i + 1] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rbx
  cmpb   $0x20,-0x1(%r13,%rbx,1)
  jne    L59
L78:
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
L59:
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  movslq %eax,%rdx
  add    %r13,%rdx
  test   %eax,%eax
  jns    L30
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L2:
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L61
L30:
  cmpb   $0x20,(%rdx)
  je     L2
  cmp    %eax,%r12d
  jg     L61
  movslq %r12d,%rdx
  mov    %rbp,%rsi
  sub    %rdx,%rsi
  nopw   0x0(%rax,%rax,1)
L29:
  movzbl 0x0(%r13,%rdx,1),%ecx
  mov    %cl,(%rsi,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jge    L29
L61:
  sub    %r12d,%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strip(char *string, char *string2) {
  int i, j, k;
  for (i = 0; i < strlen(string) && string[i] == ' '; i++)
    ;
  for (j = strlen(string) - 1; j >= 0 && string[j] == ' '; j--)
    ;
  for (k = i; k <= j; k++)
    string2[k - i] = string[k];
  string2[j - i + 1] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int array[], int pos1, int pos2) {
  int tmp = array[pos1];
  array[pos1] = array[pos2];
  array[pos2] = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int array[], int pos1, int pos2) {
  int tmp = array[pos1];
  array[pos1] = array[pos2];
  array[pos2] = tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int array[], int pos1, int pos2) {
  int tmp = array[pos1];
  array[pos1] = array[pos2];
  array[pos2] = tmp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int array[], int pos1, int pos2) {
  int tmp = array[pos1];
  array[pos1] = array[pos2];
  array[pos2] = tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mtransp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    -0x54(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L27
L34:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    0x8(%rdx),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x44(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x40(%rbp)
  jmp    L12
L24:
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x30(%rbp)
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0x40(%rbp)
L12:
  mov    -0x40(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jl     L24
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x44(%rbp)
L27:
  mov    -0x54(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x44(%rbp)
  jl     L34
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mtransp(n, A, T) int n;
double *A, *T;
{
  int i, j, np1;
  double *pAc, *pAr, *pTc, *pTr, *pA0, *pT0;
  double x;
  np1 = n + 1;
  pA0 = A;
  pT0 = T;
  for (i = 0; i < n - 1; i++) {
    pAc = pA0;
    pAr = pAc + n;
    pTc = pT0;
    pTr = pTc + n;
    *pTc++ = *pAc++;
    for (j = i + 1; j < n; j++) {
      x = *pAr;
      *pTr = *pAc++;
      *pTc++ = x;
      pAr += n;
      pTr += n;
    }
    pA0 += np1;
    pT0 += np1;
  }
  *pT0 = *pA0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mtransp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r13
  mov    %rdx,%r14
  cmp    $0x1,%edi
  jle    L21
  mov    %edi,%r12d
  movslq %edi,%rdi
  shl    $0x3,%rdi
  lea    0x8(%rdi),%rbx
  lea    -0x1(%r12),%ebp
  mov    %rdx,%rsi
  mov    %r13,%rcx
  mov    $0x0,%r11d
L10:
  lea    (%rcx,%rdi,1),%r8
  lea    (%rsi,%rdi,1),%r9
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rsi)
  add    $0x1,%r11d
  cmp    %r11d,%r12d
  jle    L29
  mov    %ebp,%eax
  sub    %r11d,%eax
  lea    0x10(,%rax,8),%r10
  mov    $0x8,%eax
  mov    $0x0,%edx
L6:
  movsd  (%r8,%rdx,1),%xmm0
  movsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%r9,%rdx,1)
  movsd  %xmm0,(%rsi,%rax,1)
  add    %rdi,%rdx
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L6
L29:
  add    %rbx,%rcx
  add    %rbx,%rsi
  cmp    %ebp,%r11d
  jne    L10
  lea    -0x2(%r12),%eax
  add    $0x1,%rax
  imul   %rbx,%rax
  add    %rax,%r13
  add    %rax,%r14
L21:
  movsd  0x0(%r13),%xmm0
  movsd  %xmm0,(%r14)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mtransp(n, A, T) int n;
double *A, *T;
{
  int i, j, np1;
  double *pAc, *pAr, *pTc, *pTr, *pA0, *pT0;
  double x;
  np1 = n + 1;
  pA0 = A;
  pT0 = T;
  for (i = 0; i < n - 1; i++) {
    pAc = pA0;
    pAr = pAc + n;
    pTc = pT0;
    pTr = pTc + n;
    *pTc++ = *pAc++;
    for (j = i + 1; j < n; j++) {
      x = *pAr;
      *pTr = *pAc++;
      *pTc++ = x;
      pAr += n;
      pTr += n;
    }
    pA0 += np1;
    pT0 += np1;
  }
  *pT0 = *pA0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mtransp>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rdi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L0
  mov    %edi,%r12d
  movslq %edi,%rdi
  mov    %rdx,%rsi
  mov    %r13,%rcx
  shl    $0x3,%rdi
  xor    %r11d,%r11d
  lea    0x8(%rdi),%rbx
  nopl   0x0(%rax)
L23:
  movsd  (%rcx),%xmm0
  add    $0x1,%r11d
  lea    (%rcx,%rdi,1),%r8
  lea    (%rsi,%rdi,1),%r9
  movsd  %xmm0,(%rsi)
  cmp    %r11d,%r12d
  jle    L28
  mov    %ebp,%eax
  xor    %edx,%edx
  sub    %r11d,%eax
  lea    0x10(,%rax,8),%r10
  mov    $0x8,%eax
  nopl   (%rax)
L33:
  movsd  (%r8,%rdx,1),%xmm0
  movsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%r9,%rdx,1)
  add    %rdi,%rdx
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L33
L28:
  add    %rbx,%rcx
  add    %rbx,%rsi
  cmp    %ebp,%r11d
  jne    L23
  lea    -0x2(%r12),%eax
  add    $0x1,%rax
  imul   %rbx,%rax
  add    %rax,%r13
  add    %rax,%r14
L0:
  movsd  0x0(%r13),%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  movsd  %xmm0,(%r14)
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mtransp(n, A, T) int n;
double *A, *T;
{
  int i, j, np1;
  double *pAc, *pAr, *pTc, *pTr, *pA0, *pT0;
  double x;
  np1 = n + 1;
  pA0 = A;
  pT0 = T;
  for (i = 0; i < n - 1; i++) {
    pAc = pA0;
    pAr = pAc + n;
    pTc = pT0;
    pTr = pTc + n;
    *pTc++ = *pAc++;
    for (j = i + 1; j < n; j++) {
      x = *pAr;
      *pTr = *pAc++;
      *pTc++ = x;
      pAr += n;
      pTr += n;
    }
    pA0 += np1;
    pT0 += np1;
  }
  *pT0 = *pA0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mtransp>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rdi),%ebp
  push   %rbx
  test   %ebp,%ebp
  jle    L8
  mov    %edi,%r12d
  movslq %edi,%rdi
  mov    %rdx,%rsi
  mov    %r13,%rcx
  shl    $0x3,%rdi
  xor    %r11d,%r11d
  lea    0x8(%rdi),%rbx
  nopl   0x0(%rax)
L4:
  movsd  (%rcx),%xmm0
  add    $0x1,%r11d
  lea    (%rcx,%rdi,1),%r8
  lea    (%rsi,%rdi,1),%r9
  movsd  %xmm0,(%rsi)
  cmp    %r11d,%r12d
  jle    L15
  mov    %ebp,%eax
  xor    %edx,%edx
  sub    %r11d,%eax
  lea    0x10(,%rax,8),%r10
  mov    $0x8,%eax
  nopl   (%rax)
L17:
  movsd  (%r8,%rdx,1),%xmm0
  movsd  (%rcx,%rax,1),%xmm1
  movsd  %xmm1,(%r9,%rdx,1)
  add    %rdi,%rdx
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L17
L15:
  add    %rbx,%rcx
  add    %rbx,%rsi
  cmp    %ebp,%r11d
  jne    L4
  lea    -0x2(%r12),%eax
  add    $0x1,%rax
  imul   %rbx,%rax
  add    %rax,%r13
  add    %rax,%r14
L8:
  movsd  0x0(%r13),%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  movsd  %xmm0,(%r14)
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void mtransp(n, A, T) int n;
double *A, *T;
{
  int i, j, np1;
  double *pAc, *pAr, *pTc, *pTr, *pA0, *pT0;
  double x;
  np1 = n + 1;
  pA0 = A;
  pT0 = T;
  for (i = 0; i < n - 1; i++) {
    pAc = pA0;
    pAr = pAc + n;
    pTc = pT0;
    pTr = pTc + n;
    *pTc++ = *pAc++;
    for (j = i + 1; j < n; j++) {
      x = *pAr;
      *pTr = *pAc++;
      *pTc++ = x;
      pAr += n;
      pTr += n;
    }
    pA0 += np1;
    pT0 += np1;
  }
  *pT0 = *pA0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L22
L8:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L22:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %eax,%ebx
  je     L8
L4:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const char *p, *q;
  p = s1;
  q = s2;
  while (*p && toupper((int)*p) == toupper((int)*q)) {
    p++, q++;
  }
  return (toupper((int)*p) - toupper((int)*q));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasecmp>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L26
L19:
  movsbl %bpl,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <toupper@plt>
  cmp    %eax,%ebx
  jne    L26
  add    $0x1,%r13
  add    $0x1,%r12
  movzbl 0x0(%r13),%ebp
  test   %bpl,%bpl
  jne    L19
L26:
  movsbl %bpl,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  movsbl (%r12),%edi
  call   <toupper@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const char *p, *q;
  p = s1;
  q = s2;
  while (*p && toupper((int)*p) == toupper((int)*q)) {
    p++, q++;
  }
  return (toupper((int)*p) - toupper((int)*q));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L39
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  test   %dil,%dil
  je     L47
L39:
  call   <toupper@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <toupper@plt>
  cmp    %eax,%ebx
  je     L6
L10:
  movsbl (%r12),%edi
  call   <toupper@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L47:
  xor    %edi,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  jmp    L10
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const char *p, *q;
  p = s1;
  q = s2;
  while (*p && toupper((int)*p) == toupper((int)*q)) {
    p++, q++;
  }
  return (toupper((int)*p) - toupper((int)*q));
}
```