ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<heaviestCharacter>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x68(%rsp),%rdx
L56:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L56
  mov    $0x0,%ebp
  jmp    L62
L58:
  add    $0x1,%rbp
L62:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L40
  movzbl (%rbx,%rbp,1),%eax
  mov    %eax,%ecx
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L58
  lea    -0x41(%rax),%edx
  add    $0x20,%ecx
  cmp    $0x1a,%dl
  cmovb  %ecx,%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  jmp    L58
L40:
  mov    $0x0,%edx
  mov    $0x0,%eax
L7:
  movslq %eax,%rcx
  mov    (%rsp,%rcx,4),%esi
  cmp    %esi,(%rsp,%rdx,4)
  cmovg  %edx,%eax
  add    $0x1,%rdx
  cmp    $0x1a,%rdx
  jne    L7
  add    $0x61,%eax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char heaviestCharacter(const char *string) {
  int characterCount[26];
  int i = 0;
  int maximum = 0;
  char temp;
  for (i = 0; i < 26; i++)
    characterCount[i] = 0;
  for (i = 0; i < strlen(string); i++) {
    temp = string[i];
    if ((temp >= 'A' && temp <= 'Z') || (temp >= 'a' && temp <= 'z')) {
      if (temp >= 'A' && temp <= 'Z')
        temp = temp + 32;
      characterCount[temp - 97]++;
    }
  }
  for (i = 0; i < 26; i++) {
    if (characterCount[i] > characterCount[maximum])
      maximum = i;
  }
  return (maximum + 97);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<heaviestCharacter>:
  endbr64
  push   %r12
  mov    $0xd,%ecx
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L25
  nopl   0x0(%rax)
L3:
  movzbl (%r12,%rbx,1),%eax
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L12
  lea    -0x41(%rax),%ecx
  lea    0x20(%rax),%edx
  cmp    $0x1a,%cl
  cmovb  %edx,%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
L12:
  add    $0x1,%rbx
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L3
  xor    %edx,%edx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L47:
  movslq %eax,%rcx
  mov    (%rsp,%rcx,4),%esi
  cmp    %esi,0x0(%rbp,%rdx,4)
  cmovg  %edx,%eax
  add    $0x1,%rdx
  cmp    $0x1a,%rdx
  jne    L47
  add    $0x61,%eax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char heaviestCharacter(const char *string) {
  int characterCount[26];
  int i = 0;
  int maximum = 0;
  char temp;
  for (i = 0; i < 26; i++)
    characterCount[i] = 0;
  for (i = 0; i < strlen(string); i++) {
    temp = string[i];
    if ((temp >= 'A' && temp <= 'Z') || (temp >= 'a' && temp <= 'z')) {
      if (temp >= 'A' && temp <= 'Z')
        temp = temp + 32;
      characterCount[temp - 97]++;
    }
  }
  for (i = 0; i < 26; i++) {
    if (characterCount[i] > characterCount[maximum])
      maximum = i;
  }
  return (maximum + 97);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<heaviestCharacter>:
  endbr64
  push   %r12
  mov    $0xd,%ecx
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  jmp    L26
  nopl   0x0(%rax)
L12:
  movzbl (%r12,%rbx,1),%eax
  mov    %eax,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  ja     L23
  lea    -0x41(%rax),%ecx
  lea    0x20(%rax),%edx
  cmp    $0x1a,%cl
  cmovb  %edx,%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
L23:
  add    $0x1,%rbx
L26:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
  mov    (%rsp),%esi
  xor    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L25:
  mov    0x0(%rbp,%rdx,4),%ecx
  cmp    %ecx,%esi
  jge    L29
  mov    %ecx,%esi
  mov    %edx,%eax
L29:
  add    $0x1,%rdx
  cmp    $0x1a,%rdx
  jne    L25
  add    $0x61,%eax
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char heaviestCharacter(const char *string) {
  int characterCount[26];
  int i = 0;
  int maximum = 0;
  char temp;
  for (i = 0; i < 26; i++)
    characterCount[i] = 0;
  for (i = 0; i < strlen(string); i++) {
    temp = string[i];
    if ((temp >= 'A' && temp <= 'Z') || (temp >= 'a' && temp <= 'z')) {
      if (temp >= 'A' && temp <= 'Z')
        temp = temp + 32;
      characterCount[temp - 97]++;
    }
  }
  for (i = 0; i < 26; i++) {
    if (characterCount[i] > characterCount[maximum])
      maximum = i;
  }
  return (maximum + 97);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D74(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  D42(%rip),%xmm1
  movss  0x10(%rsp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,0x10(%rsp)
  test   %eax,%eax
  jle    L17
  mov    $0x0,%ebx
  lea    D60(%rip),%rbp
L25:
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2ss %ebx,%xmm2
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  subss  D35(%rip),%xmm0
  divss  %xmm1,%xmm0
  mulss  0x14(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x10(%rsp),%xmm1
  addsd  D24(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L25
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D57
type_infered: string
name: extract_symbolic_data
arguments: tag: D74
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D42
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D60
type_infered: string
name: extract_symbolic_data
arguments: tag: D35
type_infered: f32
name: extract_symbolic_data
arguments: tag: D24
type_infered: byte[8]

tool: D57: Enter amount of loan:

tool: D74: %f

tool: D13: Enter interest rate:

tool: D10: Enter payment times:

tool: D1: %d

tool: {"D42": [0x00,0x00,0xc8,0x42]}

tool: D60: loan remain:%.2f


tool: D35: 1

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int main() {
  int i, times;
  float rate, loan, remainder;
  printf("Enter amount of loan:");
  scanf("%f", &loan);
  printf("Enter interest rate:");
  scanf("%f", &rate);
  printf("Enter payment times:");
  scanf("%d", &times);
  rate /= (float)times * 100;
  for (i = 0; i < times; i++) {
    remainder = (loan * (((float)times - i - 1) / (float)times)) * (1.0 + rate);
    printf("loan remain:%.2f\n", remainder);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D82(%rip),%rdi
  lea    D89(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  pxor   %xmm2,%xmm2
  movss  D33(%rip),%xmm0
  movss  0x10(%rsp),%xmm1
  cvtsi2ss %eax,%xmm2
  mulss  %xmm2,%xmm0
  divss  %xmm0,%xmm1
  movss  %xmm1,0x10(%rsp)
  test   %eax,%eax
  jle    L16
  xor    %ebp,%ebp
  lea    D8(%rip),%rbx
  jmp    L6
  nopl   0x0(%rax)
L18:
  pxor   %xmm2,%xmm2
  movss  0x10(%rsp),%xmm1
  cvtsi2ss %eax,%xmm2
L6:
  pxor   %xmm3,%xmm3
  movaps %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    %rbx,%rdi
  cvtsi2ss %ebp,%xmm3
  addsd  D37(%rip),%xmm1
  mov    $0x1,%eax
  add    $0x1,%ebp
  subss  %xmm3,%xmm0
  subss  D49(%rip),%xmm0
  divss  %xmm2,%xmm0
  mulss  0x14(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebp,%eax
  jg     L18
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D82
datatype: string
name: read_data
arguments: data_tag: D89
datatype: string
name: read_data
arguments: data_tag: D31
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string
name: read_data
arguments: data_tag: D33
datatype: byte[4]
name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D37
datatype: f64
name: read_data
arguments: data_tag: D49
datatype: byte[4]

tool: D82: Enter amount of loan:

tool: D89: %f

tool: D31: Enter interest rate:

tool: D21: Enter payment times:

tool: D14: %d

tool: {"D33": [0x00,0x00,0xc8,0x42]}

tool: D8: loan remain:%.2f


tool: D37: 1

tool: {"D49": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int main() {
  int i, times;
  float rate, loan, remainder;
  printf("Enter amount of loan:");
  scanf("%f", &loan);
  printf("Enter interest rate:");
  scanf("%f", &rate);
  printf("Enter payment times:");
  scanf("%d", &times);
  rate /= (float)times * 100;
  for (i = 0; i < times; i++) {
    remainder = (loan * (((float)times - i - 1) / (float)times)) * (1.0 + rate);
    printf("loan remain:%.2f\n", remainder);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D54(%rip),%rdi
  lea    D34(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D78(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  pxor   %xmm2,%xmm2
  movss  D48(%rip),%xmm0
  movss  0x10(%rsp),%xmm1
  cvtsi2ss %eax,%xmm2
  mulss  %xmm2,%xmm0
  divss  %xmm0,%xmm1
  movss  %xmm1,0x10(%rsp)
  test   %eax,%eax
  jle    L27
  xor    %ebp,%ebp
  lea    D84(%rip),%rbx
  jmp    L14
  nopl   0x0(%rax)
L39:
  pxor   %xmm2,%xmm2
  movss  0x10(%rsp),%xmm1
  cvtsi2ss %eax,%xmm2
L14:
  pxor   %xmm3,%xmm3
  movaps %xmm2,%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    %rbx,%rdi
  cvtsi2ss %ebp,%xmm3
  addsd  D85(%rip),%xmm1
  mov    $0x1,%eax
  add    $0x1,%ebp
  subss  %xmm3,%xmm0
  subss  D66(%rip),%xmm0
  divss  %xmm2,%xmm0
  mulss  0x14(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebp,%eax
  jg     L39
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D54
datatype: string
name: extract_symbolic_data
arguments: data_tag: D34
datatype: string
name: extract_symbolic_data
arguments: data_tag: D78
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D46
datatype: string
name: extract_symbolic_data
arguments: data_tag: D48
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D84
datatype: string
name: extract_symbolic_data
arguments: data_tag: D85
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D66
datatype: byte[4]

tool: D54: Enter amount of loan:

tool: D34: %f

tool: D78: Enter interest rate:

tool: D15: Enter payment times:

tool: D46: %d

tool: {"D48": [0x00,0x00,0xc8,0x42]}

tool: D84: loan remain:%.2f


tool: D85: 1

tool: {"D66": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int main() {
  int i, times;
  float rate, loan, remainder;
  printf("Enter amount of loan:");
  scanf("%f", &loan);
  printf("Enter interest rate:");
  scanf("%f", &rate);
  printf("Enter payment times:");
  scanf("%d", &times);
  rate /= (float)times * 100;
  for (i = 0; i < times; i++) {
    remainder = (loan * (((float)times - i - 1) / (float)times)) * (1.0 + rate);
    printf("loan remain:%.2f\n", remainder);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L9
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <err@plt>
L9:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <read_file@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <err@plt>
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <compile@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D17: Usage: compiler-x64 <inputfile>

tool: D19: Unable to read file

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2)
    err("Usage: compiler-x64 <inputfile>");
  char *text_body = read_file(argv[1]);
  if (text_body == NULL)
    err("Unable to read file");
  compile(text_body);
  free(text_body);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jne    L27
L8:
  mov    0x8(%rbx),%rdi
  call   <read_file@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
L1:
  mov    %rbx,%rdi
  call   <compile@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L27:
  lea    D16(%rip),%rdi
  call   <err@plt>
  jmp    L8
L15:
  lea    D0(%rip),%rdi
  call   <err@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: label: D16
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D16: Usage: compiler-x64 <inputfile>

tool: D0: Unable to read file

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2)
    err("Usage: compiler-x64 <inputfile>");
  char *text_body = read_file(argv[1]);
  if (text_body == NULL)
    err("Unable to read file");
  compile(text_body);
  free(text_body);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  cmp    $0x2,%edi
  je     L6
  lea    D14(%rip),%rdi
  call   <err@plt>
L6:
  mov    0x8(%rbp),%rdi
  call   <read_file@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L9
L1:
  mov    %rbp,%rdi
  call   <compile@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  lea    D11(%rip),%rdi
  call   <err@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_guessed: string
name: disassemble_data
arguments: data_tag: D11
type_guessed: string

tool: D14: Usage: compiler-x64 <inputfile>

tool: D11: Unable to read file

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2)
    err("Usage: compiler-x64 <inputfile>");
  char *text_body = read_file(argv[1]);
  if (text_body == NULL)
    err("Unable to read file");
  compile(text_body);
  free(text_body);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  cmp    $0x2,%edi
  je     L11
  lea    D7(%rip),%rdi
  call   <err@plt>
L11:
  mov    0x8(%rbp),%rdi
  call   <read_file@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
L25:
  mov    %rbp,%rdi
  call   <compile@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  lea    D10(%rip),%rdi
  call   <err@plt>
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D10
type: string

tool: D7: Usage: compiler-x64 <inputfile>

tool: D10: Unable to read file

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2)
    err("Usage: compiler-x64 <inputfile>");
  char *text_body = read_file(argv[1]);
  if (text_body == NULL)
    err("Unable to read file");
  compile(text_body);
  free(text_body);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bez2_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  movss  %xmm3,-0x20(%rbp)
  movss  %xmm4,-0x24(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x38(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  movss  (%rax),%xmm3
  movaps %xmm0,%xmm2
  subss  %xmm3,%xmm2
  movss  D14(%rip),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm3
  movss  -0x20(%rbp),%xmm2
  movss  -0x1c(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <bezier@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x24(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm5
  comiss D1(%rip),%xmm5
  jbe    L36
  movss  -0x4(%rbp),%xmm0
  comiss -0x24(%rbp),%xmm0
  jbe    L19
  mov    -0x38(%rbp),%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  jmp    L8
L19:
  mov    -0x30(%rbp),%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
L8:
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  movss  -0x24(%rbp),%xmm3
  movss  -0x20(%rbp),%xmm2
  movss  -0x1c(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movaps %xmm3,%xmm4
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <bez2_time>
  movd   %xmm0,%eax
  jmp    L35
L36:
  mov    -0x8(%rbp),%eax
L35:
  movd   %eax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type: byte[4]
name: parse_data
arguments: data_label: D1
type: byte[4]

tool: {"D14": [0x00,0x00,0x00,0x3f]}

tool: {"D1": [0x17,0xb7,0xd1,0x38]}

assistant: ```c
float bez2_time(float x0, float x1, float x2, float x3, float time, float *t0, float *t1) {
  float v, t;
  t = *t0 + (*t1 - *t0) * 0.5f;
  v = bezier(x0, x1, x2, x3, t);
  if (fabs(time - v) > .0001f) {
    if (v > time)
      *t1 = t;
    else
      *t0 = t;
    return bez2_time(x0, x1, x2, x3, time, t0, t1);
  } else
    return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<bez2_time>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movaps %xmm0,%xmm8
  movss  %xmm0,0x10(%rsp)
  movaps %xmm1,%xmm7
  movss  %xmm1,0x14(%rsp)
  movss  %xmm2,0x18(%rsp)
  movss  %xmm3,0x1c(%rsp)
  movss  %xmm4,0x8(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movss  (%rdi),%xmm1
  movss  (%rsi),%xmm0
  subss  %xmm1,%xmm0
  mulss  D0(%rip),%xmm0
  movaps %xmm0,%xmm6
  addss  %xmm1,%xmm6
  movd   %xmm6,%ebx
  movaps %xmm6,%xmm4
  movaps %xmm7,%xmm1
  movaps %xmm8,%xmm0
  call   <bezier@plt>
  movss  0x8(%rsp),%xmm5
  movss  %xmm0,0xc(%rsp)
  subss  %xmm0,%xmm5
  movaps %xmm5,%xmm0
  call   <fabs@plt>
  comiss D12(%rip),%xmm0
  jbe    L23
  movss  0xc(%rsp),%xmm6
  comiss 0x8(%rsp),%xmm6
  jbe    L1
  mov    %ebx,(%r12)
L21:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movss  0x8(%rsp),%xmm4
  movss  0x1c(%rsp),%xmm3
  movss  0x18(%rsp),%xmm2
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  call   <bez2_time>
  movd   %xmm0,%ebx
L23:
  movd   %ebx,%xmm0
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %ebx,0x0(%rbp)
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: byte[4]
name: disassemble_data
arguments: data_label: D12
data_type: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x3f]}

tool: {"D12": [0x17,0xb7,0xd1,0x38]}

assistant: ```c
float bez2_time(float x0, float x1, float x2, float x3, float time, float *t0, float *t1) {
  float v, t;
  t = *t0 + (*t1 - *t0) * 0.5f;
  v = bezier(x0, x1, x2, x3, t);
  if (fabs(time - v) > .0001f) {
    if (v > time)
      *t1 = t;
    else
      *t0 = t;
    return bez2_time(x0, x1, x2, x3, time, t0, t1);
  } else
    return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bez2_time>:
  endbr64
  push   %r14
  movd   %xmm0,%r14d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  movss  %xmm4,0x8(%rsp)
  nopl   (%rax)
L3:
  movss  0x0(%rbp),%xmm0
  movss  (%rbx),%xmm4
  movss  %xmm3,0x1c(%rsp)
  movss  %xmm2,0x18(%rsp)
  subss  %xmm0,%xmm4
  mulss  D5(%rip),%xmm4
  movss  %xmm1,0x14(%rsp)
  addss  %xmm0,%xmm4
  movd   %r14d,%xmm0
  movss  %xmm4,0xc(%rsp)
  call   <bezier@plt>
  movaps %xmm0,%xmm5
  movss  0x8(%rsp),%xmm0
  movss  %xmm5,0x10(%rsp)
  subss  %xmm5,%xmm0
  call   <fabs@plt>
  comiss D15(%rip),%xmm0
  movss  0xc(%rsp),%xmm4
  jbe    L12
  movss  0x10(%rsp),%xmm5
  comiss 0x8(%rsp),%xmm5
  movss  0x14(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  movss  0x1c(%rsp),%xmm3
  jbe    L21
  movss  %xmm4,(%rbx)
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L21:
  movss  %xmm4,0x0(%rbp)
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x20,%rsp
  movaps %xmm4,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: byte[4]
name: read_data
arguments: label: D15
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x3f]}

tool: {"D15": [0x17,0xb7,0xd1,0x38]}

assistant: ```c
float bez2_time(float x0, float x1, float x2, float x3, float time, float *t0, float *t1) {
  float v, t;
  t = *t0 + (*t1 - *t0) * 0.5f;
  v = bezier(x0, x1, x2, x3, t);
  if (fabs(time - v) > .0001f) {
    if (v > time)
      *t1 = t;
    else
      *t0 = t;
    return bez2_time(x0, x1, x2, x3, time, t0, t1);
  } else
    return t;
}
```