ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<partion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L77
L35:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L48
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L35
  jmp    L43
L48:
  nop
  jmp    L43
L106:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  je     L93
  subl   $0x1,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L106
  jmp    L60
L93:
  nop
L60:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L77
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L77
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L77:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L33
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L118
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L118:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int partion(int *elements, int low, int high) {
  int l = low + 1;
  int h = high;
  int pivot = low;
  while (h > l) {
    while (elements[l] <= elements[pivot]) {
      if (l == high)
        break;
      l++;
    }
    while (elements[h] >= elements[pivot]) {
      if (h == low)
        break;
      h--;
    }
    if (elements[l] >= elements[h] && l < h) {
      swap(&elements[l], &elements[h]);
    }
  }
  if (elements[low] > elements[h]) {
    swap(&elements[low], &elements[h]);
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<partion>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %esi,%r12d
  mov    %edx,%r13d
  lea    0x1(%rsi),%ebp
  cmp    %edx,%ebp
  jge    L130
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r15
  mov    %edx,%ebx
  jmp    L118
L91:
  cmp    %ebx,%ebp
  jge    L138
L118:
  movslq %ebp,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdi
  mov    (%rdi),%edx
  mov    (%r15),%esi
  cmp    %ebp,%r13d
  je     L20
  lea    0x4(%r14,%rax,1),%rax
  cmp    %esi,%edx
  jg     L20
L132:
  add    $0x1,%ebp
  mov    %rax,%rdi
  mov    (%rax),%edx
  add    $0x4,%rax
  cmp    %ebp,%r13d
  je     L20
  cmp    %esi,%edx
  jle    L132
L20:
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%r8
  mov    (%r8),%ecx
  cmp    %ebx,%r12d
  je     L135
  cmp    %esi,%ecx
  jl     L135
  lea    -0x4(%r14,%rax,4),%rax
L63:
  sub    $0x1,%ebx
  mov    %rax,%r8
  mov    (%rax),%ecx
  sub    $0x4,%rax
  cmp    %ebx,%r12d
  je     L135
  cmp    %esi,%ecx
  jge    L63
L135:
  cmp    %ebx,%ebp
  jge    L91
  cmp    %ecx,%edx
  jl     L91
  mov    %r8,%rsi
  call   <swap@plt>
  jmp    L118
L130:
  mov    %edx,%ebx
L138:
  movslq %r12d,%r12
  lea    (%r14,%r12,4),%rdi
  movslq %ebx,%rax
  lea    (%r14,%rax,4),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jg     L45
L131:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <swap@plt>
  jmp    L131
```

assistant: ```c
int partion(int *elements, int low, int high) {
  int l = low + 1;
  int h = high;
  int pivot = low;
  while (h > l) {
    while (elements[l] <= elements[pivot]) {
      if (l == high)
        break;
      l++;
    }
    while (elements[h] >= elements[pivot]) {
      if (h == low)
        break;
      h--;
    }
    if (elements[l] >= elements[h] && l < h) {
      swap(&elements[l], &elements[h]);
    }
  }
  if (elements[low] > elements[h]) {
    swap(&elements[low], &elements[h]);
  }
  return h;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<partion>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  lea    (%rdi,%rax,4),%r15
  mov    %rdi,%r14
  push   %r13
  mov    %rax,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  lea    0x1(%rax),%ebx
  sub    $0x8,%rsp
  mov    (%r15),%esi
  cmp    %edx,%ebx
  jge    L105
  nopw   0x0(%rax,%rax,1)
L108:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdi
  mov    (%rdi),%ecx
  cmp    %ebx,%ebp
  je     L64
  lea    0x4(%r14,%rax,1),%rax
  cmp    %esi,%ecx
  jle    L59
  jmp    L64
  nopl   0x0(%rax)
L34:
  cmp    %esi,%ecx
  jg     L64
L59:
  add    $0x1,%ebx
  mov    (%rax),%ecx
  mov    %rax,%rdi
  add    $0x4,%rax
  cmp    %ebx,%ebp
  jne    L34
L64:
  movslq %r12d,%rax
  lea    (%r14,%rax,4),%r8
  mov    (%r8),%edx
  cmp    %esi,%edx
  jl     L102
  cmp    %r12d,%r13d
  je     L102
  lea    -0x4(%r14,%rax,4),%rax
  jmp    L164
  cs nopw 0x0(%rax,%rax,1)
L85:
  cmp    %r12d,%r13d
  je     L102
L164:
  mov    (%rax),%edx
  mov    %rax,%r8
  sub    $0x1,%r12d
  sub    $0x4,%rax
  cmp    %esi,%edx
  jge    L85
L102:
  cmp    %r12d,%ebx
  jge    L168
  cmp    %edx,%ecx
  jge    L147
  cmp    %r12d,%ebx
  jl     L108
  nopl   0x0(%rax)
L168:
  cmp    %esi,(%r8)
  jl     L146
L158:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L147:
  mov    %r8,%rsi
  call   <swap@plt>
  mov    (%r15),%esi
  jmp    L108
L146:
  mov    %r8,%rsi
  mov    %r15,%rdi
  call   <swap@plt>
  jmp    L158
L105:
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r8
  jmp    L168
```

assistant: ```c
int partion(int *elements, int low, int high) {
  int l = low + 1;
  int h = high;
  int pivot = low;
  while (h > l) {
    while (elements[l] <= elements[pivot]) {
      if (l == high)
        break;
      l++;
    }
    while (elements[h] >= elements[pivot]) {
      if (h == low)
        break;
      h--;
    }
    if (elements[l] >= elements[h] && l < h) {
      swap(&elements[l], &elements[h]);
    }
  }
  if (elements[low] > elements[h]) {
    swap(&elements[low], &elements[h]);
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<partion>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  lea    (%rdi,%rax,4),%r15
  mov    %rdi,%r14
  push   %r13
  mov    %rax,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  lea    0x1(%rax),%ebx
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r8
  sub    $0x18,%rsp
  mov    (%r15),%esi
  mov    (%r8),%ecx
  cmp    %edx,%ebx
  jge    L55
  nopl   0x0(%rax)
L9:
  movslq %ebx,%rax
  shl    $0x2,%rax
  lea    (%r14,%rax,1),%rdi
  mov    (%rdi),%edx
  cmp    %ebx,%ebp
  je     L158
  lea    0x4(%r14,%rax,1),%rax
  cmp    %esi,%edx
  jle    L170
  jmp    L158
  nopl   0x0(%rax)
L57:
  cmp    %esi,%edx
  jg     L158
L170:
  add    $0x1,%ebx
  mov    (%rax),%edx
  mov    %rax,%rdi
  add    $0x4,%rax
  cmp    %ebx,%ebp
  jne    L57
L158:
  movslq %r12d,%rax
  cmp    %ecx,%esi
  jg     L11
  cmp    %r12d,%r13d
  je     L11
  lea    -0x4(%r14,%rax,4),%rax
  jmp    L131
  nopw   0x0(%rax,%rax,1)
L71:
  cmp    %r12d,%r13d
  je     L80
L131:
  mov    (%rax),%ecx
  mov    %rax,%r8
  sub    $0x1,%r12d
  sub    $0x4,%rax
  cmp    %esi,%ecx
  jge    L71
L80:
  cmp    %r12d,%ebx
  jge    L55
  cmp    %ecx,%edx
  jge    L93
  cmp    %r12d,%ebx
  jl     L9
  nopl   0x0(%rax)
L55:
  cmp    %ecx,%esi
  jg     L108
L121:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L93:
  mov    %r8,%rsi
  mov    %r8,0x8(%rsp)
  call   <swap@plt>
  mov    0x8(%rsp),%r8
  mov    (%r15),%esi
  mov    (%r8),%ecx
  jmp    L9
  nopl   (%rax)
L11:
  lea    (%r14,%rax,4),%r8
  jmp    L80
L108:
  mov    %r8,%rsi
  mov    %r15,%rdi
  call   <swap@plt>
  jmp    L121
```

assistant: ```c
int partion(int *elements, int low, int high) {
  int l = low + 1;
  int h = high;
  int pivot = low;
  while (h > l) {
    while (elements[l] <= elements[pivot]) {
      if (l == high)
        break;
      l++;
    }
    while (elements[h] >= elements[pivot]) {
      if (h == low)
        break;
      h--;
    }
    if (elements[l] >= elements[h] && l < h) {
      swap(&elements[l], &elements[h]);
    }
  }
  if (elements[low] > elements[h]) {
    swap(&elements[low], &elements[h]);
  }
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<splice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fh_str_slice@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fh_str_slice@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fh_str_concat@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fh_str_concat@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *splice(char *str, char *rep, int start, int end) {
  char *front, *back, *tmp, *new;
  front = fh_str_slice(str, 0, start);
  back = fh_str_slice(str, end, strlen(str));
  tmp = fh_str_concat(front, rep);
  new = fh_str_concat(tmp, back);
  free(front);
  free(back);
  free(tmp);
  return new;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<splice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %ecx,%ebp
  mov    $0x0,%esi
  call   <fh_str_slice@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <fh_str_slice@plt>
  mov    %rax,%rbp
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fh_str_concat@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <fh_str_concat@plt>
  mov    %rax,%r13
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *splice(char *str, char *rep, int start, int end) {
  char *front, *back, *tmp, *new;
  front = fh_str_slice(str, 0, start);
  back = fh_str_slice(str, end, strlen(str));
  tmp = fh_str_concat(front, rep);
  new = fh_str_concat(tmp, back);
  free(front);
  free(back);
  free(tmp);
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<splice>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fh_str_slice@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <fh_str_slice@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <fh_str_concat@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fh_str_concat@plt>
  mov    %r13,%rdi
  mov    %rax,%r14
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *splice(char *str, char *rep, int start, int end) {
  char *front, *back, *tmp, *new;
  front = fh_str_slice(str, 0, start);
  back = fh_str_slice(str, end, strlen(str));
  tmp = fh_str_concat(front, rep);
  new = fh_str_concat(tmp, back);
  free(front);
  free(back);
  free(tmp);
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<splice>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fh_str_slice@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <fh_str_slice@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <fh_str_concat@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fh_str_concat@plt>
  mov    %r13,%rdi
  mov    %rax,%r14
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *splice(char *str, char *rep, int start, int end) {
  char *front, *back, *tmp, *new;
  front = fh_str_slice(str, 0, start);
  back = fh_str_slice(str, end, strlen(str));
  tmp = fh_str_concat(front, rep);
  new = fh_str_concat(tmp, back);
  free(front);
  free(back);
  free(tmp);
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__msgwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __msgwrite(int sock, void *data, size_t cnt) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__msgwrite>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __msgwrite(int sock, void *data, size_t cnt) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__msgwrite>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __msgwrite(int sock, void *data, size_t cnt) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__msgwrite>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __msgwrite(int sock, void *data, size_t cnt) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_results>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D24(%rip),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D24
datatype: f64
name: read_data
arguments: label: D48
datatype: string
name: read_data
arguments: label: D40
datatype: string
name: read_data
arguments: label: D42
datatype: string
name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D58
datatype: string

tool: D24: 100

tool: D48:   ---

tool: D40:   iterations: %d


tool: D42:   elapsed: %0.9f


tool: D11:   rate: %0.9f


tool: D58:   ...

assistant: ```c
void print_results(double elapsed) {
  double rate = (double)100 / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", 100);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_results>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  D53(%rip),%xmm0
  movq   %rbx,%xmm1
  divsd  %xmm1,%xmm0
  lea    D46(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D44
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: string
name: parse_data
arguments: data_tag: D53
type_guessed: f64
name: parse_data
arguments: data_tag: D46
type_guessed: string
name: parse_data
arguments: data_tag: D45
type_guessed: string

tool: D18:   ---

tool: D44:   iterations: %d


tool: D27:   elapsed: %0.9f


tool: D53: 100

tool: D46:   rate: %0.9f


tool: D45:   ...

assistant: ```c
void print_results(double elapsed) {
  double rate = (double)100 / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", 100);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_results>:
  endbr64
  sub    $0x18,%rsp
  lea    D20(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <puts@plt>
  mov    $0x64,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  movsd  D4(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  add    $0x18,%rsp
  lea    D45(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D20
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D23
type_infered: string
name: unpack_data
arguments: tag: D14
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: f64
name: unpack_data
arguments: tag: D45
type_infered: string

tool: D20:   ---

tool: D5:   iterations: %d


tool: D23:   elapsed: %0.9f


tool: D14:   rate: %0.9f


tool: D4: 100

tool: D45:   ...

assistant: ```c
void print_results(double elapsed) {
  double rate = (double)100 / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", 100);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_results>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <puts@plt>
  mov    $0x64,%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  movsd  D43(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  add    $0x18,%rsp
  lea    D46(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D32
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D43
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D46
type_infered: string

tool: D5:   ---

tool: D32:   iterations: %d


tool: D25:   elapsed: %0.9f


tool: D17:   rate: %0.9f


tool: D43: 100

tool: D46:   ...

assistant: ```c
void print_results(double elapsed) {
  double rate = (double)100 / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", 100);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rgb16tobgr24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  shr    %eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L1
L12:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%ebx
  mov    %ebx,%ecx
  sar    $0x8,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  and    $0xf8,%ecx
  mov    %ecx,%edx
  mov    %edx,(%rax)
  mov    %ebx,%ecx
  sar    $0x3,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  and    $0xfc,%ecx
  mov    %ecx,%edx
  mov    %edx,(%rax)
  lea    0x0(,%rbx,8),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl %cl,%edx
  mov    %edx,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L12
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void rgb16tobgr24(const uint8_t *src, uint8_t *dst, unsigned int src_size) {
  const uint16_t *end;
  uint8_t *d = (uint8_t *)dst;
  const uint16_t *s = (const uint16_t *)src;
  end = s + src_size / 2;
  while (s < end) {
    register uint16_t bgr;
    bgr = *s++;
    *d++ = (bgr & 0xF800) >> 8;
    *d++ = (bgr & 0x7E0) >> 3;
    *d++ = (bgr & 0x1F) << 3;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rgb16tobgr24>:
  endbr64
  mov    %rdi,%rcx
  shr    %edx
  mov    %edx,%edx
  lea    (%rdi,%rdx,4),%rdi
  cmp    %rdi,%rcx
  jae    L13
L2:
  add    $0x4,%rcx
  mov    -0x4(%rcx),%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  and    $0xf8,%edx
  mov    %edx,(%rsi)
  mov    %eax,%edx
  sar    $0x3,%edx
  and    $0xfc,%edx
  mov    %edx,0x4(%rsi)
  add    $0xc,%rsi
  shl    $0x3,%eax
  and    $0xff,%eax
  mov    %eax,-0x4(%rsi)
  cmp    %rcx,%rdi
  ja     L2
L13:
  ret
```

assistant: ```c
void rgb16tobgr24(const uint8_t *src, uint8_t *dst, unsigned int src_size) {
  const uint16_t *end;
  uint8_t *d = (uint8_t *)dst;
  const uint16_t *s = (const uint16_t *)src;
  end = s + src_size / 2;
  while (s < end) {
    register uint16_t bgr;
    bgr = *s++;
    *d++ = (bgr & 0xF800) >> 8;
    *d++ = (bgr & 0x7E0) >> 3;
    *d++ = (bgr & 0x1F) << 3;
  }
}
```