ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <enter_string@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  mov    %rbp,%rdi
  call   <delete_string@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x70,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string

tool: D0: do %d


tool: D19: %c

assistant: ```c
void main() {
  extern enter_string(char str[80]);
  extern delete_string(char str[], char ch);
  extern print_string(char str[]);
  char c;
  char str[80];
  printf("do %d\n", enter_string(str));
  scanf("%c", &c);
  delete_string(str, c);
  print_string(str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <enter_string@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    0xf(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xf(%rsp),%esi
  mov    %rbp,%rdi
  call   <delete_string@plt>
  mov    %rbp,%rdi
  call   <print_string@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x70,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string
name: disassemble_data
arguments: label: D15
type: string

tool: D1: do %d


tool: D15: %c

assistant: ```c
void main() {
  extern enter_string(char str[80]);
  extern delete_string(char str[], char ch);
  extern print_string(char str[]);
  char c;
  char str[80];
  printf("do %d\n", enter_string(str));
  scanf("%c", &c);
  delete_string(str, c);
  print_string(str);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getMoveFromLine2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x5,%eax
  jg     L129
  mov    $0xffffffff,%eax
  jmp    L58
L129:
  lea    D1(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L53
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L53
  mov    $0xfffffffe,%eax
  jmp    L58
L53:
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  cmp    $0x5d,%al
  je     L30
  mov    $0xfffffffd,%eax
  jmp    L58
L30:
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L86
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x24(%rbp),%edx
  add    $0x60,%edx
  cmp    %edx,%eax
  jle    L16
L86:
  mov    $0xfffffffc,%eax
  jmp    L58
L16:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L101
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x24(%rbp),%edx
  add    $0x60,%edx
  cmp    %edx,%eax
  jle    L71
L101:
  mov    $0xfffffffb,%eax
  jmp    L58
L71:
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x4(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L58:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D11
type_guessed: string

tool: D1: ;B[

tool: D11: ;W[

assistant: ```c
int getMoveFromLine2(char *line, char *move, int boardSize) {
  if (strlen(line) < 6) {
    return -1;
  }
  char *szB = ";B[";
  char *szW = ";W[";
  if (strncmp(line, szB, 3) && strncmp(line, szW, 3)) {
    return -2;
  }
  if (line[5] != ']') {
    return -3;
  }
  if (line[3] < 97 || line[3] > 97 + boardSize - 1) {
    return -4;
  }
  if (line[4] < 97 || line[4] > 97 + boardSize - 1) {
    return -5;
  }
  move[0] = line[3];
  move[1] = line[4];
  move[2] = '\0';
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getMoveFromLine2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L91
  mov    $0x3,%edx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L106
L45:
  cmpb   $0x5d,0x5(%rbx)
  jne    L125
  movzbl 0x3(%rbx),%ecx
  cmp    $0x60,%cl
  jle    L122
  lea    0x60(%r12),%eax
  movsbl %cl,%edx
  cmp    %eax,%edx
  jg     L18
  movzbl 0x4(%rbx),%edx
  cmp    $0x60,%dl
  jle    L36
  movsbl %dl,%edx
  cmp    %edx,%eax
  jl     L2
  mov    %cl,0x0(%rbp)
  movzbl 0x4(%rbx),%eax
  mov    %al,0x1(%rbp)
  movb   $0x0,0x2(%rbp)
  mov    $0x0,%eax
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L106:
  mov    $0x3,%edx
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L45
  mov    $0xfffffffe,%eax
  jmp    L32
L91:
  mov    $0xffffffff,%eax
  jmp    L32
L125:
  mov    $0xfffffffd,%eax
  jmp    L32
L122:
  mov    $0xfffffffc,%eax
  jmp    L32
L18:
  mov    $0xfffffffc,%eax
  jmp    L32
L36:
  mov    $0xfffffffb,%eax
  jmp    L32
L2:
  mov    $0xfffffffb,%eax
  jmp    L32
```

tool_calls: name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string

tool: D11: ;B[

tool: D18: ;W[

assistant: ```c
int getMoveFromLine2(char *line, char *move, int boardSize) {
  if (strlen(line) < 6) {
    return -1;
  }
  char *szB = ";B[";
  char *szW = ";W[";
  if (strncmp(line, szB, 3) && strncmp(line, szW, 3)) {
    return -2;
  }
  if (line[5] != ']') {
    return -3;
  }
  if (line[3] < 97 || line[3] > 97 + boardSize - 1) {
    return -4;
  }
  if (line[4] < 97 || line[4] > 97 + boardSize - 1) {
    return -5;
  }
  move[0] = line[3];
  move[1] = line[4];
  move[2] = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getMoveFromLine2>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L76
  mov    $0x3,%edx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L128
L29:
  cmpb   $0x5d,0x5(%rbx)
  jne    L124
  movzbl 0x3(%rbx),%ecx
  cmp    $0x60,%cl
  jle    L86
  lea    0x60(%r12),%eax
  movsbl %cl,%edx
  cmp    %eax,%edx
  jg     L86
  movsbl 0x4(%rbx),%edx
  cmp    $0x60,%dl
  jle    L98
  cmp    %edx,%eax
  jl     L98
  mov    %cl,0x0(%rbp)
  movzbl 0x4(%rbx),%eax
  movb   $0x0,0x2(%rbp)
  mov    %al,0x1(%rbp)
  xor    %eax,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L128:
  mov    $0x3,%edx
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L29
  mov    $0xfffffffe,%eax
  jmp    L11
L76:
  mov    $0xffffffff,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L86:
  mov    $0xfffffffc,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L124:
  mov    $0xfffffffd,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L98:
  mov    $0xfffffffb,%eax
  jmp    L11
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string

tool: D9: ;B[

tool: D3: ;W[

assistant: ```c
int getMoveFromLine2(char *line, char *move, int boardSize) {
  if (strlen(line) < 6) {
    return -1;
  }
  char *szB = ";B[";
  char *szW = ";W[";
  if (strncmp(line, szB, 3) && strncmp(line, szW, 3)) {
    return -2;
  }
  if (line[5] != ']') {
    return -3;
  }
  if (line[3] < 97 || line[3] > 97 + boardSize - 1) {
    return -4;
  }
  if (line[4] < 97 || line[4] > 97 + boardSize - 1) {
    return -5;
  }
  move[0] = line[3];
  move[1] = line[4];
  move[2] = '\0';
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getMoveFromLine2>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x5,%eax
  jle    L3
  mov    $0x3,%edx
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L44
L36:
  cmpb   $0x5d,0x5(%rbx)
  jne    L78
  movzbl 0x3(%rbx),%ecx
  cmp    $0x60,%cl
  jle    L89
  lea    0x60(%r12),%eax
  movsbl %cl,%edx
  cmp    %eax,%edx
  jg     L89
  movsbl 0x4(%rbx),%edx
  cmp    $0x60,%dl
  jle    L52
  cmp    %edx,%eax
  jl     L52
  mov    %cl,0x0(%rbp)
  movzbl 0x4(%rbx),%eax
  movb   $0x0,0x2(%rbp)
  mov    %al,0x1(%rbp)
  xor    %eax,%eax
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L44:
  mov    $0x3,%edx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L36
  mov    $0xfffffffe,%eax
  jmp    L43
L3:
  mov    $0xffffffff,%eax
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L89:
  mov    $0xfffffffc,%eax
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L78:
  mov    $0xfffffffd,%eax
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L52:
  mov    $0xfffffffb,%eax
  jmp    L43
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D17: ;B[

tool: D4: ;W[

assistant: ```c
int getMoveFromLine2(char *line, char *move, int boardSize) {
  if (strlen(line) < 6) {
    return -1;
  }
  char *szB = ";B[";
  char *szW = ";W[";
  if (strncmp(line, szB, 3) && strncmp(line, szW, 3)) {
    return -2;
  }
  if (line[5] != ']') {
    return -3;
  }
  if (line[3] < 97 || line[3] > 97 + boardSize - 1) {
    return -4;
  }
  if (line[4] < 97 || line[4] > 97 + boardSize - 1) {
    return -5;
  }
  move[0] = line[3];
  move[1] = line[4];
  move[2] = '\0';
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<draw_line>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%eax
  mov    %ecx,%r10d
  sub    %esi,%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  mov    %r8d,%r11d
  sub    %eax,%r11d
  mov    %r11d,%ecx
  neg    %ecx
  cmovs  %r11d,%ecx
  cmp    %r10d,%esi
  setle  %r11b
  movzbl %r11b,%r11d
  lea    -0x1(%r11,%r11,1),%r11d
  cmp    %r8d,%eax
  setle  %r10b
  movzbl %r10b,%r10d
  lea    -0x1(%r10,%r10,1),%r10d
  cmp    %ecx,%edx
  jl     L69
  lea    (%rcx,%rcx,1),%ebx
  mov    %ebx,%r8d
  sub    %edx,%r8d
  sub    %edx,%ecx
  lea    (%rcx,%rcx,1),%ebp
  movslq %r11d,%r11
  movslq %esi,%rsi
  lea    0x1(%rdx),%r12d
  mov    $0x0,%ecx
  jmp    L15
L58:
  add    %r10d,%eax
  add    %ebp,%r8d
L33:
  add    $0x1,%ecx
  add    %r11,%rsi
  cmp    %r12d,%ecx
  je     L39
L15:
  mov    %r9d,%edx
  imul   %eax,%edx
  movslq %edx,%rdx
  add    %rsi,%rdx
  movw   $0xfff,(%rdi,%rdx,2)
  test   %r8d,%r8d
  jg     L58
  add    %ebx,%r8d
  jmp    L33
L69:
  lea    (%rdx,%rdx,1),%ebx
  mov    %ebx,%r8d
  sub    %ecx,%r8d
  sub    %ecx,%edx
  lea    (%rdx,%rdx,1),%ebp
  imul   %r9d,%r10d
  movslq %r10d,%r10
  imul   %r9d,%eax
  movslq %eax,%r9
  add    $0x1,%ecx
  mov    $0x0,%edx
  jmp    L59
L70:
  add    %r11d,%esi
  add    %ebp,%r8d
L4:
  add    $0x1,%edx
  add    %r10,%r9
  cmp    %ecx,%edx
  je     L39
L59:
  movslq %esi,%rax
  add    %r9,%rax
  movw   $0xfff,(%rdi,%rax,2)
  test   %r8d,%r8d
  jg     L70
  add    %ebx,%r8d
  jmp    L4
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void draw_line(short int *dst, int x1, int y1, int x2, int y2, int ncol) {
  int i, e, dx, dy, ix = 1, iy = 1;
  int x = x1, y = y1;
  dx = (((x2 - x1) > 0) ? ((x2 - x1)) : (-(x2 - x1)));
  dy = (((y2 - y1) > 0) ? ((y2 - y1)) : (-(y2 - y1)));
  if (x2 < x1)
    ix = -1;
  if (y2 < y1)
    iy = -1;
  if (dx >= dy) {
    e = 2 * dy - dx;
    for (i = 0; i <= dx; ++i) {
      *(dst + ncol * y + x) = 4096 - 1;
      if (e > 0) {
        y += iy;
        e += 2 * (dy - dx);
      } else
        e += 2 * dy;
      x += ix;
    }
  } else {
    e = 2 * dx - dy;
    for (i = 0; i <= dy; ++i) {
      *(dst + ncol * y + x) = 4096 - 1;
      if (e > 0) {
        x += ix;
        e += 2 * (dx - dy);
      } else
        e += 2 * dx;
      y += iy;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<draw_line>:
  endbr64
  mov    %ecx,%r10d
  sub    %esi,%ecx
  mov    %edx,%eax
  mov    %r8d,%r11d
  mov    %ecx,%edx
  push   %r12
  neg    %edx
  push   %rbp
  cmovs  %ecx,%edx
  sub    %eax,%r11d
  push   %rbx
  mov    %r11d,%ecx
  neg    %ecx
  cmovs  %r11d,%ecx
  xor    %r11d,%r11d
  cmp    %r10d,%esi
  setle  %r11b
  xor    %r10d,%r10d
  cmp    %r8d,%eax
  setle  %r10b
  lea    -0x1(%r11,%r11,1),%r11d
  lea    -0x1(%r10,%r10,1),%r10d
  cmp    %ecx,%edx
  jl     L7
  lea    (%rcx,%rcx,1),%ebx
  sub    %edx,%ecx
  movslq %r11d,%r11
  movslq %esi,%rsi
  mov    %ebx,%r8d
  lea    (%rcx,%rcx,1),%ebp
  lea    0x1(%rdx),%r12d
  xor    %ecx,%ecx
  sub    %edx,%r8d
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x1,%ecx
  add    %r10d,%eax
  add    %ebp,%r8d
  add    %r11,%rsi
  cmp    %r12d,%ecx
  je     L61
L22:
  mov    %r9d,%edx
  imul   %eax,%edx
  movslq %edx,%rdx
  add    %rsi,%rdx
  movw   $0xfff,(%rdi,%rdx,2)
  test   %r8d,%r8d
  jg     L24
  add    $0x1,%ecx
  add    %ebx,%r8d
  add    %r11,%rsi
  cmp    %r12d,%ecx
  jne    L22
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  imul   %r9d,%r10d
  lea    (%rdx,%rdx,1),%ebx
  sub    %ecx,%edx
  imul   %r9d,%eax
  mov    %ebx,%r8d
  lea    (%rdx,%rdx,1),%ebp
  xor    %edx,%edx
  sub    %ecx,%r8d
  add    $0x1,%ecx
  movslq %r10d,%r10
  movslq %eax,%r9
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L63:
  add    %r11d,%esi
  add    %ebp,%r8d
L71:
  add    $0x1,%edx
  add    %r10,%r9
  cmp    %edx,%ecx
  je     L61
L76:
  movslq %esi,%rax
  mov    $0xfff,%r12d
  add    %r9,%rax
  mov    %r12w,(%rdi,%rax,2)
  test   %r8d,%r8d
  jg     L63
  add    %ebx,%r8d
  jmp    L71
```

assistant: ```c
void draw_line(short int *dst, int x1, int y1, int x2, int y2, int ncol) {
  int i, e, dx, dy, ix = 1, iy = 1;
  int x = x1, y = y1;
  dx = (((x2 - x1) > 0) ? ((x2 - x1)) : (-(x2 - x1)));
  dy = (((y2 - y1) > 0) ? ((y2 - y1)) : (-(y2 - y1)));
  if (x2 < x1)
    ix = -1;
  if (y2 < y1)
    iy = -1;
  if (dx >= dy) {
    e = 2 * dy - dx;
    for (i = 0; i <= dx; ++i) {
      *(dst + ncol * y + x) = 4096 - 1;
      if (e > 0) {
        y += iy;
        e += 2 * (dy - dx);
      } else
        e += 2 * dy;
      x += ix;
    }
  } else {
    e = 2 * dx - dy;
    for (i = 0; i <= dy; ++i) {
      *(dst + ncol * y + x) = 4096 - 1;
      if (e > 0) {
        x += ix;
        e += 2 * (dx - dy);
      } else
        e += 2 * dx;
      y += iy;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_to_mac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0xc0(%rbp),%rax
  mov    %rax,-0xa8(%rbp)
  movl   $0x0,-0xb0(%rbp)
  jmp    L7
L14:
  lea    -0xa0(%rbp),%rdx
  mov    -0xa8(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <getnext@plt>
  mov    %eax,-0xac(%rbp)
  cmpl   $0xffffffff,-0xac(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L44
L13:
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xb8(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  lea    -0xa0(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %al,(%rbx)
  mov    -0xac(%rbp),%eax
  cltq
  add    %rax,-0xa8(%rbp)
  addl   $0x1,-0xb0(%rbp)
L7:
  cmpl   $0x4,-0xb0(%rbp)
  jle    L14
  mov    -0xb8(%rbp),%rax
  lea    0x5(%rax),%rbx
  mov    -0xa8(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %al,(%rbx)
  mov    $0x0,%eax
L44:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int str_to_mac(unsigned char *mac, char *str) {
  int len;
  char *ptr = str;
  char buf[128];
  int i;
  for (i = 0; i < 5; i++) {
    if ((len = getnext(ptr, ':', buf)) == -1) {
      return 1;
    }
    mac[i] = strtol(buf, NULL, 16);
    ptr += len;
  }
  mac[5] = strtol(ptr, NULL, 16);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_to_mac>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    0x5(%rdi),%r15
  mov    %rsp,%r13
L39:
  mov    %r13,%rdx
  mov    $0x3a,%esi
  mov    %r12,%rdi
  call   <getnext@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L9
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <strtol@plt>
  mov    %al,0x0(%rbp)
  movslq %ebx,%rbx
  add    %rbx,%r12
  add    $0x1,%rbp
  cmp    %r15,%rbp
  jne    L39
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %al,0x5(%r14)
  mov    $0x0,%eax
L30:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    $0x1,%eax
  jmp    L30
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_to_mac(unsigned char *mac, char *str) {
  int len;
  char *ptr = str;
  char buf[128];
  int i;
  for (i = 0; i < 5; i++) {
    if ((len = getnext(ptr, ':', buf)) == -1) {
      return 1;
    }
    mac[i] = strtol(buf, NULL, 16);
    ptr += len;
  }
  mac[5] = strtol(ptr, NULL, 16);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_to_mac>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  lea    0x5(%rdi),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
L1:
  mov    %r12,%rdx
  mov    $0x3a,%esi
  mov    %r15,%rdi
  call   <getnext@plt>
  movslq %eax,%rbx
  cmp    $0xffffffff,%ebx
  je     L9
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <strtol@plt>
  add    %rbx,%r15
  mov    %al,-0x1(%rbp)
  cmp    %rbp,%r14
  jne    L1
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <strtol@plt>
  mov    %al,0x5(%r13)
  xor    %eax,%eax
L30:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  jmp    L30
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_to_mac(unsigned char *mac, char *str) {
  int len;
  char *ptr = str;
  char buf[128];
  int i;
  for (i = 0; i < 5; i++) {
    if ((len = getnext(ptr, ':', buf)) == -1) {
      return 1;
    }
    mac[i] = strtol(buf, NULL, 16);
    ptr += len;
  }
  mac[5] = strtol(ptr, NULL, 16);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_to_mac>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  lea    0x5(%rdi),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
L0:
  mov    %r12,%rdx
  mov    $0x3a,%esi
  mov    %r15,%rdi
  call   <getnext@plt>
  movslq %eax,%rbx
  cmp    $0xffffffff,%ebx
  je     L12
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <strtol@plt>
  add    %rbx,%r15
  mov    %al,-0x1(%rbp)
  cmp    %rbp,%r14
  jne    L0
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r15,%rdi
  call   <strtol@plt>
  mov    %al,0x5(%r13)
  xor    %eax,%eax
L28:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0x1,%eax
  jmp    L28
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int str_to_mac(unsigned char *mac, char *str) {
  int len;
  char *ptr = str;
  char buf[128];
  int i;
  for (i = 0; i < 5; i++) {
    if ((len = getnext(ptr, ':', buf)) == -1) {
      return 1;
    }
    mac[i] = strtol(buf, NULL, 16);
    ptr += len;
  }
  mac[5] = strtol(ptr, NULL, 16);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<run_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    -0x38(%rbp),%r8
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <start_command@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    $0xffffffff,%eax
  jmp    L14
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <wait_command@plt>
L14:
  leave
  ret
```

assistant: ```c
int run_command(char *cmd, sigset_t *mask, int infd, int outfd, char *a0, char *a1, char *a2) {
  int pid;
  if ((pid = start_command(cmd, mask, infd, outfd, a0, a1, a2)) < 0)
    return (-1);
  return (wait_command(pid));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run_command>:
  endbr64
  sub    $0x10,%rsp
  push   0x18(%rsp)
  call   <start_command@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  js     L15
  mov    %eax,%edi
  call   <wait_command@plt>
L3:
  add    $0x8,%rsp
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int run_command(char *cmd, sigset_t *mask, int infd, int outfd, char *a0, char *a1, char *a2) {
  int pid;
  if ((pid = start_command(cmd, mask, infd, outfd, a0, a1, a2)) < 0)
    return (-1);
  return (wait_command(pid));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_command>:
  endbr64
  sub    $0x10,%rsp
  push   0x18(%rsp)
  call   <start_command@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L3
  mov    %eax,%edi
  add    $0x8,%rsp
  jmp    1060 <wait_command@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int run_command(char *cmd, sigset_t *mask, int infd, int outfd, char *a0, char *a1, char *a2) {
  int pid;
  if ((pid = start_command(cmd, mask, infd, outfd, a0, a1, a2)) < 0)
    return (-1);
  return (wait_command(pid));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<run_command>:
  endbr64
  sub    $0x10,%rsp
  push   0x18(%rsp)
  call   <start_command@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  js     L3
  mov    %eax,%edi
  add    $0x8,%rsp
  jmp    1060 <wait_command@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int run_command(char *cmd, sigset_t *mask, int infd, int outfd, char *a0, char *a1, char *a2) {
  int pid;
  if ((pid = start_command(cmd, mask, infd, outfd, a0, a1, a2)) < 0)
    return (-1);
  return (wait_command(pid));
}
```