ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<coap_get_variable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L50
L17:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  je     L30
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  jne    L62
L30:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L62
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L62
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    $0x26,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L44
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L44:
  mov    -0x40(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  jmp    L72
L62:
  addq   $0x1,-0x20(%rbp)
L50:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  ja     L17
  mov    $0x0,%eax
L72:
  leave
  ret
```

assistant: ```c
int coap_get_variable(const char *buffer, size_t length, const char *name, const char **output) {
  const char *start = NULL;
  const char *end = NULL;
  const char *value_end = NULL;
  size_t name_len = 0;
  *output = 0;
  name_len = strlen(name);
  end = buffer + length;
  for (start = buffer; start + name_len < end; ++start) {
    if ((start == buffer || start[-1] == '&') && start[name_len] == '=' && strncmp(name, start, name_len) == 0) {
      start += name_len + 1;
      value_end = (const char *)memchr(start, '&', end - start);
      if (value_end == NULL) {
        value_end = end;
      }
      *output = start;
      return (value_end - start);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<coap_get_variable>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%r15
  mov    %rcx,0x8(%rsp)
  movq   $0x0,(%rcx)
  mov    %rdx,%rdi
  call   <strlen@plt>
  add    %r13,%r12
  lea    0x0(%r13,%rax,1),%rbp
  cmp    %rbp,%r12
  jbe    L47
  mov    %rax,%r14
  mov    %r13,%rbx
  jmp    L98
L38:
  cmpb   $0x3d,0x0(%rbp)
  je     L50
L89:
  add    $0x1,%rbx
  add    $0x1,%rbp
  lea    (%rbx,%r14,1),%rax
  cmp    %rax,%r12
  jbe    L96
L98:
  cmp    %rbx,%r13
  je     L38
  cmpb   $0x26,-0x1(%rbx)
  jne    L89
  jmp    L38
L50:
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L89
  lea    0x1(%rbx,%r14,1),%rbx
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    $0x26,%esi
  mov    %rbx,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  cmovne %rax,%r12
  mov    0x8(%rsp),%rax
  mov    %rbx,(%rax)
  mov    %r12d,%eax
  sub    %ebx,%eax
  jmp    L12
L96:
  mov    $0x0,%eax
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
int coap_get_variable(const char *buffer, size_t length, const char *name, const char **output) {
  const char *start = NULL;
  const char *end = NULL;
  const char *value_end = NULL;
  size_t name_len = 0;
  *output = 0;
  name_len = strlen(name);
  end = buffer + length;
  for (start = buffer; start + name_len < end; ++start) {
    if ((start == buffer || start[-1] == '&') && start[name_len] == '=' && strncmp(name, start, name_len) == 0) {
      start += name_len + 1;
      value_end = (const char *)memchr(start, '&', end - start);
      if (value_end == NULL) {
        value_end = end;
      }
      *output = start;
      return (value_end - start);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<coap_get_variable>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  add    %r14,%r12
  push   %rbx
  mov    %r14,%rbx
  sub    $0x18,%rsp
  movq   $0x0,(%rcx)
  mov    %rcx,0x8(%rsp)
  call   <strlen@plt>
  lea    (%r14,%rax,1),%rbp
  mov    %rax,%r15
  cmp    %rbp,%r12
  ja     L35
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L69:
  cmpb   $0x26,-0x1(%rbx)
  je     L60
L51:
  add    $0x1,%rbx
  add    $0x1,%rbp
  lea    (%rbx,%r15,1),%rax
  cmp    %rax,%r12
  jbe    L29
L35:
  cmp    %rbx,%r14
  jne    L69
L60:
  cmpb   $0x3d,0x0(%rbp)
  jne    L51
  mov    %r15,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L51
  lea    0x1(%rbx,%r15,1),%rbx
  mov    $0x26,%esi
  sub    %ebx,%r12d
  mov    %rbx,%rdi
  mov    %r12d,%edx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    0x8(%rsp),%rax
  cmovne %edx,%r12d
  mov    %rbx,(%rax)
  jmp    L12
  nopl   0x0(%rax)
L29:
  xor    %r12d,%r12d
L12:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int coap_get_variable(const char *buffer, size_t length, const char *name, const char **output) {
  const char *start = NULL;
  const char *end = NULL;
  const char *value_end = NULL;
  size_t name_len = 0;
  *output = 0;
  name_len = strlen(name);
  end = buffer + length;
  for (start = buffer; start + name_len < end; ++start) {
    if ((start == buffer || start[-1] == '&') && start[name_len] == '=' && strncmp(name, start, name_len) == 0) {
      start += name_len + 1;
      value_end = (const char *)memchr(start, '&', end - start);
      if (value_end == NULL) {
        value_end = end;
      }
      *output = start;
      return (value_end - start);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<coap_get_variable>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  mov    %rdx,%rdi
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  add    %r14,%r12
  push   %rbx
  mov    %r14,%rbx
  sub    $0x18,%rsp
  movq   $0x0,(%rcx)
  mov    %rcx,0x8(%rsp)
  call   <strlen@plt>
  lea    (%r14,%rax,1),%rbp
  mov    %rax,%r15
  cmp    %rbp,%r12
  ja     L70
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L33:
  cmpb   $0x26,-0x1(%rbx)
  je     L59
L25:
  add    $0x1,%rbx
  add    $0x1,%rbp
  lea    (%rbx,%r15,1),%rax
  cmp    %rax,%r12
  jbe    L68
L70:
  cmp    %rbx,%r14
  jne    L33
L59:
  cmpb   $0x3d,0x0(%rbp)
  jne    L25
  mov    %r15,%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L25
  lea    0x1(%rbx,%r15,1),%rbx
  mov    $0x26,%esi
  sub    %ebx,%r12d
  mov    %rbx,%rdi
  mov    %r12d,%edx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbx,%rdx
  test   %rax,%rax
  mov    0x8(%rsp),%rax
  cmovne %edx,%r12d
  mov    %rbx,(%rax)
  jmp    L10
  nopl   0x0(%rax)
L68:
  xor    %r12d,%r12d
L10:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int coap_get_variable(const char *buffer, size_t length, const char *name, const char **output) {
  const char *start = NULL;
  const char *end = NULL;
  const char *value_end = NULL;
  size_t name_len = 0;
  *output = 0;
  name_len = strlen(name);
  end = buffer + length;
  for (start = buffer; start + name_len < end; ++start) {
    if ((start == buffer || start[-1] == '&') && start[name_len] == '=' && strncmp(name, start, name_len) == 0) {
      start += name_len + 1;
      value_end = (const char *)memchr(start, '&', end - start);
      if (value_end == NULL) {
        value_end = end;
      }
      *output = start;
      return (value_end - start);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L39
L51:
  movw   $0x0,-0xe(%rbp)
  jmp    L40
L17:
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  movzwl -0xe(%rbp),%ecx
  movzwl -0xc(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jle    L11
  movzwl -0xe(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xf(%rbp)
  movzwl -0xe(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzwl -0xe(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xe(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  movzbl -0xf(%rbp),%eax
  mov    %al,(%rdx)
  movzwl -0xe(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xf(%rbp)
  movzwl -0xe(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl -0xe(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xe(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzbl -0xf(%rbp),%eax
  mov    %al,(%rdx)
L11:
  addw   $0x2,-0xe(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xe(%rbp)
  jb     L17
  addw   $0x2,-0xc(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L51
  movzwl -0xa(%rbp),%eax
  lea    -0x68e9(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > local2 + local1) {
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 1039116836UL) + (unsigned short)60659;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%r8d
  movzwl 0x2(%rdi),%edx
  mov    $0x0,%ecx
  test   %dx,%dx
  je     L10
L15:
  mov    $0x0,%eax
L28:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L28
  add    $0x2,%ecx
  cmp    %dx,%cx
  jb     L15
L10:
  lea    -0x5da4(%r8),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > local2 + local1) {
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 1039116836UL) + (unsigned short)60659;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl 0x2(%rdi),%edx
  movzwl (%rdi),%r8d
  xor    %ecx,%ecx
  test   %dx,%dx
  je     L4
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L21
  add    $0x2,%ecx
  cmp    %dx,%cx
  jb     L22
L4:
  lea    -0x5da4(%r8),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > local2 + local1) {
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 1039116836UL) + (unsigned short)60659;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzwl 0x2(%rdi),%edx
  movzwl (%rdi),%r8d
  xor    %ecx,%ecx
  test   %dx,%dx
  je     L3
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L27
  add    $0x2,%ecx
  cmp    %dx,%cx
  jb     L8
L3:
  lea    -0x5da4(%r8),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > local2 + local1) {
          copy11 = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = copy11;
          copy11 = *((char *)(&state[local2]) + 1);
          *((char *)(&state[local2]) + 1) = *((char *)(&state[local2]) + 0);
          *((char *)(&state[local2]) + 0) = copy11;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 1039116836UL) + (unsigned short)60659;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<command_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D18
type_guessed: string
name: read_data
arguments: label: D13
type_guessed: string

tool: D18: Usage:


tool: D13:        dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] [-su <address>] [-sf <interface>+<address>] 


assistant: ```c
void command_text() {
  printf("Usage:\n");
  printf("       dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] "
         "[-su <address>] [-sf <interface>+<address>] \n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<command_text>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string
name: retrieve_data
arguments: label: D15
datatype: string

tool: D0: Usage:


tool: D15:        dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] [-su <address>] [-sf <interface>+<address>] 


assistant: ```c
void command_text() {
  printf("Usage:\n");
  printf("       dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] "
         "[-su <address>] [-sf <interface>+<address>] \n");
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<command_text>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D13
type: string

tool: D17: Usage:


tool: D13:        dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] [-su <address>] [-sf <interface>+<address>] 


assistant: ```c
void command_text() {
  printf("Usage:\n");
  printf("       dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] "
         "[-su <address>] [-sf <interface>+<address>] \n");
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<command_text>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D16
type: string

tool: D3: Usage:


tool: D16:        dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] [-su <address>] [-sf <interface>+<address>] 


assistant: ```c
void command_text() {
  printf("Usage:\n");
  printf("       dhcp6r [-d] [-cu] [-cm <interface>] [-sm <interface>] "
         "[-su <address>] [-sf <interface>+<address>] \n");
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_farnspokel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%fs:(%edx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _farnspokel(unsigned long offset, unsigned long value) {
  __asm__ __volatile__(".byte 0x64\n"
                       "	movl %k0,(%k1)"
                       :
                       : "ri"(value), "r"(offset));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_farnspokel>:
  endbr64
  mov    %esi,%fs:(%edi)
  ret
```

assistant: ```c
void _farnspokel(unsigned long offset, unsigned long value) {
  __asm__ __volatile__(".byte 0x64\n"
                       "	movl %k0,(%k1)"
                       :
                       : "ri"(value), "r"(offset));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_farnspokel>:
  endbr64
  mov    %esi,%fs:(%edi)
  ret
```

assistant: ```c
void _farnspokel(unsigned long offset, unsigned long value) {
  __asm__ __volatile__(".byte 0x64\n"
                       "	movl %k0,(%k1)"
                       :
                       : "ri"(value), "r"(offset));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_farnspokel>:
  endbr64
  mov    %esi,%fs:(%edi)
  ret
```

assistant: ```c
void _farnspokel(unsigned long offset, unsigned long value) {
  __asm__ __volatile__(".byte 0x64\n"
                       "	movl %k0,(%k1)"
                       :
                       : "ri"(value), "r"(offset));
}
```
user: What is the c source code of the assembly code below?

```asm
<flip_sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L13
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L13:
  movl   $0xffffffff,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int flip_sign(int current_state) {
  int new_state = 0;
  if (current_state != 1) {
    new_state = 1;
  } else {
    new_state = -1;
  }
  return new_state;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flip_sign>:
  endbr64
  cmp    $0x1,%edi
  setne  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int flip_sign(int current_state) {
  int new_state = 0;
  if (current_state != 1) {
    new_state = 1;
  } else {
    new_state = -1;
  }
  return new_state;
}
```
user: Translate the below assembly code into C programming language:

```asm
<flip_sign>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  setne  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int flip_sign(int current_state) {
  int new_state = 0;
  if (current_state != 1) {
    new_state = 1;
  } else {
    new_state = -1;
  }
  return new_state;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<flip_sign>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  setne  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int flip_sign(int current_state) {
  int new_state = 0;
  if (current_state != 1) {
    new_state = 1;
  } else {
    new_state = -1;
  }
  return new_state;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strip_punct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L3
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ispunct@plt>
  test   %rax,%rax
  je     L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  jmp    L29
L0:
  nop
L29:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip_punct(char *arg) {
  int i;
  for (i = strlen(arg); --i >= 0;)
    if (ispunct(arg[i]))
      arg[i] = '\0';
    else
      break;
  return arg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strip_punct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L16
  movslq %ebx,%rbx
  add    %r12,%rbx
  movslq %eax,%rdx
  lea    -0x2(%r12,%rdx,1),%rbp
  lea    -0x1(%rax),%eax
  sub    %rax,%rbp
L6:
  movsbl (%rbx),%edi
  call   <ispunct@plt>
  test   %rax,%rax
  je     L16
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
L16:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strip_punct(char *arg) {
  int i;
  for (i = strlen(arg); --i >= 0;)
    if (ispunct(arg[i]))
      arg[i] = '\0';
    else
      break;
  return arg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_punct>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L7
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  lea    -0x2(%r12,%rax,1),%rbp
  add    %r12,%rbx
  sub    %rdx,%rbp
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L7
L30:
  movsbl (%rbx),%edi
  call   <ispunct@plt>
  test   %rax,%rax
  jne    L1
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strip_punct(char *arg) {
  int i;
  for (i = strlen(arg); --i >= 0;)
    if (ispunct(arg[i]))
      arg[i] = '\0';
    else
      break;
  return arg;
}
```