ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<udcFastReadString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  call   <udcRead@plt>
  test   %eax,%eax
  je     L12
  movzbl 0x7(%rsp),%r12d
  movzbl %r12b,%edx
  test   %edx,%edx
  jg     L35
L20:
  movzbl %r12b,%r12d
  movb   $0x0,0x0(%rbp,%r12,1)
  mov    $0x1,%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <udcMustRead@plt>
  jmp    L20
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udcFastReadString(struct udcFile *f, char buf[256]) {
  unsigned char bLen;
  int len;
  if (!udcRead(f, &(bLen), sizeof(bLen)))
    return 0;
  if ((len = bLen) > 0)
    udcMustRead(f, buf, len);
  buf[len] = 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<udcFastReadString>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <udcRead@plt>
  test   %eax,%eax
  je     L33
  movzbl 0x7(%rsp),%edx
  mov    %rdx,%r12
  test   %edx,%edx
  jne    L35
L39:
  movb   $0x0,(%rbx,%r12,1)
  mov    $0x1,%eax
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L35:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <udcMustRead@plt>
  jmp    L39
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udcFastReadString(struct udcFile *f, char buf[256]) {
  unsigned char bLen;
  int len;
  if (!udcRead(f, &(bLen), sizeof(bLen)))
    return 0;
  if ((len = bLen) > 0)
    udcMustRead(f, buf, len);
  buf[len] = 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<udcFastReadString>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <udcRead@plt>
  test   %eax,%eax
  je     L26
  movzbl 0x7(%rsp),%edx
  mov    %rdx,%r12
  test   %edx,%edx
  jne    L5
L13:
  movb   $0x0,(%rbx,%r12,1)
  mov    $0x1,%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <udcMustRead@plt>
  jmp    L13
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udcFastReadString(struct udcFile *f, char buf[256]) {
  unsigned char bLen;
  int len;
  if (!udcRead(f, &(bLen), sizeof(bLen)))
    return 0;
  if ((len = bLen) > 0)
    udcMustRead(f, buf, len);
  buf[len] = 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L40:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L49
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L49
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L28
L49:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
L28:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L40
L50:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hex2dec(char *a) {
  int result = 0;
  int i;
  for (i = 0; (a[i] != '\0') && (a[i] != '\n'); i++)
    if (a[i] >= 'A' && a[i] <= 'F')
      result = (16 * result) + (a[i] - 'A' + 10);
    else
      result = (16 * result) + (a[i] - '0');
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hex2dec>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
  cmp    $0xa,%dl
  je     L2
  add    $0x1,%rdi
  mov    $0x0,%eax
  jmp    L16
L4:
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x30(%rax,%rdx,1),%eax
L26:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  je     L36
  cmp    $0xa,%dl
  je     L66
L16:
  lea    -0x41(%rdx),%ecx
  cmp    $0x5,%cl
  ja     L4
  shl    $0x4,%eax
  movsbl %dl,%edx
  lea    -0x37(%rax,%rdx,1),%eax
  jmp    L26
L66:
  ret
L2:
  mov    $0x0,%eax
L36:
  ret
```

assistant: ```c
int hex2dec(char *a) {
  int result = 0;
  int i;
  for (i = 0; (a[i] != '\0') && (a[i] != '\n'); i++)
    if (a[i] >= 'A' && a[i] <= 'F')
      result = (16 * result) + (a[i] - 'A' + 10);
    else
      result = (16 * result) + (a[i] - '0');
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hex2dec>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L31
  cmp    $0xa,%dl
  je     L31
  add    $0x1,%rdi
  xor    %eax,%eax
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L37:
  sub    $0x37,%edx
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L3
L24:
  cmp    $0xa,%dl
  je     L6
L62:
  lea    -0x41(%rdx),%ecx
  shl    $0x4,%eax
  cmp    $0x5,%cl
  jbe    L37
  lea    -0x30(%rax,%rdx,1),%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L24
L3:
  ret
  nopl   0x0(%rax)
L6:
  ret
  nopl   0x0(%rax)
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hex2dec(char *a) {
  int result = 0;
  int i;
  for (i = 0; (a[i] != '\0') && (a[i] != '\n'); i++)
    if (a[i] >= 'A' && a[i] <= 'F')
      result = (16 * result) + (a[i] - 'A' + 10);
    else
      result = (16 * result) + (a[i] - '0');
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex2dec>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L26
  cmp    $0xa,%dl
  je     L26
  add    $0x1,%rdi
  xor    %eax,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L55:
  sub    $0x37,%edx
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L40
L0:
  cmp    $0xa,%dl
  je     L53
L10:
  lea    -0x41(%rdx),%ecx
  shl    $0x4,%eax
  cmp    $0x5,%cl
  jbe    L55
  lea    -0x30(%rax,%rdx,1),%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L0
L40:
  ret
  nopl   0x0(%rax)
L53:
  ret
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hex2dec(char *a) {
  int result = 0;
  int i;
  for (i = 0; (a[i] != '\0') && (a[i] != '\n'); i++)
    if (a[i] >= 'A' && a[i] <= 'F')
      result = (16 * result) + (a[i] - 'A' + 10);
    else
      result = (16 * result) + (a[i] - '0');
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_quaddobl_Laurent_container_to_start_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x30b,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_quaddobl_Laurent_container_to_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(779, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_quaddobl_Laurent_container_to_start_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x30b,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_quaddobl_Laurent_container_to_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(779, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_quaddobl_Laurent_container_to_start_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x30b,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int copy_quaddobl_Laurent_container_to_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(779, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_quaddobl_Laurent_container_to_start_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x30b,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int copy_quaddobl_Laurent_container_to_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(779, a, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printCPUNiceInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <output@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: CPU Nice Load	0	100	%%


assistant: ```c
void printCPUNiceInfo(const char *cmd) {
  (void)cmd;
  output("CPU Nice Load\t0\t100\t%%\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printCPUNiceInfo>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <output@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: CPU Nice Load	0	100	%%


assistant: ```c
void printCPUNiceInfo(const char *cmd) {
  (void)cmd;
  output("CPU Nice Load\t0\t100\t%%\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printCPUNiceInfo>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <output@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: CPU Nice Load	0	100	%%


assistant: ```c
void printCPUNiceInfo(const char *cmd) {
  (void)cmd;
  output("CPU Nice Load\t0\t100\t%%\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printCPUNiceInfo>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <output@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: CPU Nice Load	0	100	%%


assistant: ```c
void printCPUNiceInfo(const char *cmd) {
  (void)cmd;
  output("CPU Nice Load\t0\t100\t%%\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<_string_append_with_format_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x34(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <string_append@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void _string_append_with_format_list(const char *format, char **original, va_list arguments) {
  va_list copy_arguments;
  va_copy(copy_arguments, arguments);
  size_t buffer_size = vsnprintf(NULL, 0, format, copy_arguments) + 1;
  va_end(copy_arguments);
  char *temporal = malloc(buffer_size);
  va_copy(copy_arguments, arguments);
  vsnprintf(temporal, buffer_size, format, arguments);
  va_end(copy_arguments);
  string_append(original, temporal);
  free(temporal);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_string_append_with_format_list>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %edx,%r13d
  mov    %edx,%esi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_copy@plt>
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  lea    0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <va_copy@plt>
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <string_append@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void _string_append_with_format_list(const char *format, char **original, va_list arguments) {
  va_list copy_arguments;
  va_copy(copy_arguments, arguments);
  size_t buffer_size = vsnprintf(NULL, 0, format, copy_arguments) + 1;
  va_end(copy_arguments);
  char *temporal = malloc(buffer_size);
  va_copy(copy_arguments, arguments);
  vsnprintf(temporal, buffer_size, format, arguments);
  va_end(copy_arguments);
  string_append(original, temporal);
  free(temporal);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_string_append_with_format_list>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %r13d,%edi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  sub    $0x8,%rsp
  call   <va_copy@plt>
  mov    %r13d,%ecx
  mov    %r15,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  lea    0x1(%rax),%ebp
  call   <va_end@plt>
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  mov    %r12,%rsi
  call   <string_append@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
```

assistant: ```c
void _string_append_with_format_list(const char *format, char **original, va_list arguments) {
  va_list copy_arguments;
  va_copy(copy_arguments, arguments);
  size_t buffer_size = vsnprintf(NULL, 0, format, copy_arguments) + 1;
  va_end(copy_arguments);
  char *temporal = malloc(buffer_size);
  va_copy(copy_arguments, arguments);
  vsnprintf(temporal, buffer_size, format, arguments);
  va_end(copy_arguments);
  string_append(original, temporal);
  free(temporal);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_string_append_with_format_list>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %r13d,%edi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  sub    $0x8,%rsp
  call   <va_copy@plt>
  mov    %r13d,%ecx
  mov    %r15,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  lea    0x1(%rax),%ebp
  call   <va_end@plt>
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %r15,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  mov    %r12,%rsi
  call   <string_append@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
```

assistant: ```c
void _string_append_with_format_list(const char *format, char **original, va_list arguments) {
  va_list copy_arguments;
  va_copy(copy_arguments, arguments);
  size_t buffer_size = vsnprintf(NULL, 0, format, copy_arguments) + 1;
  va_end(copy_arguments);
  char *temporal = malloc(buffer_size);
  va_copy(copy_arguments, arguments);
  vsnprintf(temporal, buffer_size, format, arguments);
  va_end(copy_arguments);
  string_append(original, temporal);
  free(temporal);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncat2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L22:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  subq   $0x1,-0x18(%rbp)
  jmp    L0
L23:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L0:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  cmp    %rax,-0x28(%rbp)
  ja     L23
L18:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncat2(char *s1, const char *s2, size_t n) {
  size_t i = 0;
  char *result = s1;
  while (*s1++ != '\0')
    ;
  s1--;
  while (*s2 != '\0' && i++ < n)
    *s1++ = *s2++;
  *s1 = '\0';
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncat2>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
L23:
  mov    %r8,%rcx
  add    $0x1,%r8
  cmpb   $0x0,-0x1(%r8)
  jne    L23
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L6
  test   %rdx,%rdx
  je     L6
  add    %rcx,%rdx
L45:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L6
  cmp    %rcx,%rdx
  jne    L45
  mov    %rdx,%rcx
L6:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strncat2(char *s1, const char *s2, size_t n) {
  size_t i = 0;
  char *result = s1;
  while (*s1++ != '\0')
    ;
  s1--;
  while (*s2 != '\0' && i++ < n)
    *s1++ = *s2++;
  *s1 = '\0';
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strncat2>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r8,%rcx
  lea    0x1(%r8),%r8
  cmpb   $0x0,(%rcx)
  jne    L26
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L43
  test   %rdx,%rdx
  je     L43
  add    %rcx,%rdx
  jmp    L8
  nop
L51:
  cmp    %rcx,%rdx
  je     L43
L8:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L51
L43:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strncat2(char *s1, const char *s2, size_t n) {
  size_t i = 0;
  char *result = s1;
  while (*s1++ != '\0')
    ;
  s1--;
  while (*s2 != '\0' && i++ < n)
    *s1++ = *s2++;
  *s1 = '\0';
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strncat2>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %r8,%rcx
  lea    0x1(%r8),%r8
  cmpb   $0x0,(%rcx)
  jne    L16
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L8
  test   %rdx,%rdx
  je     L8
  add    %rcx,%rdx
  jmp    L19
  nop
L17:
  cmp    %rcx,%rdx
  je     L8
L19:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L17
L8:
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *strncat2(char *s1, const char *s2, size_t n) {
  size_t i = 0;
  char *result = s1;
  while (*s1++ != '\0')
    ;
  s1--;
  while (*s2 != '\0' && i++ < n)
    *s1++ = *s2++;
  *s1 = '\0';
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L52:
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L45:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x9,-0x4(%rbp)
  jle    L45
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x9,-0x8(%rbp)
  jle    L52
  cmpl   $0xa,-0x8(%rbp)
  jne    L17
  cmpl   $0xa,-0x4(%rbp)
  je     L27
L17:
  call   <abort@plt>
L27:
  nop
  leave
  ret
```

assistant: ```c
void f4(void) {
  int i = 0, j = 0;
#pragma omp task default(shared) if (0)
  {
#pragma omp simd collapse(2) lastprivate(i, j)
    for (i = 0; i < 10; i++)
      for (j = 0; j < 10; j++)
        ;
  }
  if (i != 10 || j != 10)
    __builtin_abort();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void) {
  int i = 0, j = 0;
#pragma omp task default(shared) if (0)
  {
#pragma omp simd collapse(2) lastprivate(i, j)
    for (i = 0; i < 10; i++)
      for (j = 0; j < 10; j++)
        ;
  }
  if (i != 10 || j != 10)
    __builtin_abort();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void) {
  int i = 0, j = 0;
#pragma omp task default(shared) if (0)
  {
#pragma omp simd collapse(2) lastprivate(i, j)
    for (i = 0; i < 10; i++)
      for (j = 0; j < 10; j++)
        ;
  }
  if (i != 10 || j != 10)
    __builtin_abort();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void) {
  int i = 0, j = 0;
#pragma omp task default(shared) if (0)
  {
#pragma omp simd collapse(2) lastprivate(i, j)
    for (i = 0; i < 10; i++)
      for (j = 0; j < 10; j++)
        ;
  }
  if (i != 10 || j != 10)
    __builtin_abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<user_bill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int user_bill(int unit) {
  int total_bill;
  total_bill = unit * 2;
  return total_bill;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<user_bill>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int user_bill(int unit) {
  int total_bill;
  total_bill = unit * 2;
  return total_bill;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<user_bill>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int user_bill(int unit) {
  int total_bill;
  total_bill = unit * 2;
  return total_bill;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<user_bill>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int user_bill(int unit) {
  int total_bill;
  total_bill = unit * 2;
  return total_bill;
}
```