ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<yahoo_f01_40>:
  endbr64
  sub    $0x8,%rsp
  imul   $0x511537cb,%edi,%edi
  add    $0x7135,%edi
  call   <yahoo_M1Common@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int yahoo_f01_40(int Salt, int Parameter) {
  unsigned b = Salt * 0x511537CB + 0x7135;
  return yahoo_M1Common(b, Parameter);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yahoo_f01_40>:
  endbr64
  imul   $0x511537cb,%edi,%edi
  add    $0x7135,%edi
  jmp    1050 <yahoo_M1Common@plt>
```

assistant: ```c
int yahoo_f01_40(int Salt, int Parameter) {
  unsigned b = Salt * 0x511537CB + 0x7135;
  return yahoo_M1Common(b, Parameter);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yahoo_f01_40>:
  endbr64
  imul   $0x511537cb,%edi,%edi
  add    $0x7135,%edi
  jmp    1050 <yahoo_M1Common@plt>
```

assistant: ```c
int yahoo_f01_40(int Salt, int Parameter) {
  unsigned b = Salt * 0x511537CB + 0x7135;
  return yahoo_M1Common(b, Parameter);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %ecx,-0x8c(%rbp)
  mov    %r8d,-0x90(%rbp)
  mov    %r9,-0x98(%rbp)
  mov    0x10(%rbp),%eax
  mov    %al,-0x9c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x6c(%rbp)
  movl   $0x10,-0x68(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x68(%rbp),%edx
  mov    -0x78(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x68(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  movl   $0x4,-0x68(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x68(%rbp),%edx
  mov    -0x80(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x68(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8c(%rbp),%edx
  mov    -0x88(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8c(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  movl   $0x4,-0x68(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x68(%rbp),%edx
  mov    -0x90(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <h2net@plt>
  mov    -0x68(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  movl   $0x10,-0x68(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x6c(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x68(%rbp),%edx
  mov    -0x78(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x68(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  cmpb   $0x1,-0x9c(%rbp)
  jne    L15
  movl   $0x2,-0x64(%rbp)
  jmp    L7
L15:
  movl   $0x5,-0x64(%rbp)
L7:
  mov    -0x98(%rbp),%rdx
  mov    -0x6c(%rbp),%ecx
  lea    -0x60(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <md5_sum@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void hash(unsigned char *pwd, unsigned char *id, unsigned char *chaldata, int chlen, unsigned int seq, unsigned char *mda, unsigned char md) {
  unsigned char pbuf[80];
  int blen, n, i;
  blen = 0;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  n = 4;
  memcpy(&pbuf[blen], id, n);
  blen += n;
  memcpy(&pbuf[blen], chaldata, chlen);
  blen += chlen;
  n = 4;
  h2net(seq, &pbuf[blen], n);
  blen += n;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  if (md == 0x01)
    i = 2;
  else
    i = 5;
  md5_sum(pbuf, blen, mda);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r15
  mov    %rdx,%r14
  mov    %ecx,%ebx
  mov    %r8d,%r13d
  mov    %r9,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    $0x10,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x4,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  lea    0x24(%rsp),%rdi
  mov    %ebx,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  lea    0x14(%rbx),%esi
  movslq %esi,%rsi
  add    %rbp,%rsi
  mov    $0x4,%edx
  mov    %r13d,%edi
  call   <h2net@plt>
  lea    0x18(%rbx),%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  lea    0x28(%rbx),%esi
  mov    0x8(%rsp),%rdx
  mov    %rbp,%rdi
  call   <md5_sum@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hash(unsigned char *pwd, unsigned char *id, unsigned char *chaldata, int chlen, unsigned int seq, unsigned char *mda, unsigned char md) {
  unsigned char pbuf[80];
  int blen, n, i;
  blen = 0;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  n = 4;
  memcpy(&pbuf[blen], id, n);
  blen += n;
  memcpy(&pbuf[blen], chaldata, chlen);
  blen += chlen;
  n = 4;
  h2net(seq, &pbuf[blen], n);
  blen += n;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  if (md == 0x01)
    i = 2;
  else
    i = 5;
  md5_sum(pbuf, blen, mda);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    $0x10,%edx
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x78,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rdi,%rsi
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x8(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x24(%rsp),%rdi
  mov    %ebx,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  lea    0x14(%rbx),%esi
  mov    $0x4,%edx
  mov    %r14d,%edi
  movslq %esi,%rsi
  add    %r12,%rsi
  call   <h2net@plt>
  lea    0x18(%rbx),%edi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  movslq %edi,%rdi
  add    %r12,%rdi
  call   <memcpy@plt>
  lea    0x28(%rbx),%esi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <md5_sum@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hash(unsigned char *pwd, unsigned char *id, unsigned char *chaldata, int chlen, unsigned int seq, unsigned char *mda, unsigned char md) {
  unsigned char pbuf[80];
  int blen, n, i;
  blen = 0;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  n = 4;
  memcpy(&pbuf[blen], id, n);
  blen += n;
  memcpy(&pbuf[blen], chaldata, chlen);
  blen += chlen;
  n = 4;
  h2net(seq, &pbuf[blen], n);
  blen += n;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  if (md == 0x01)
    i = 2;
  else
    i = 5;
  md5_sum(pbuf, blen, mda);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    $0x10,%edx
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %r9,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x78,%rsp
  mov    %rsi,0x8(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rdi,%rsi
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x8(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  lea    0x24(%rsp),%rdi
  mov    %ebx,%edx
  mov    %r15,%rsi
  call   <memcpy@plt>
  lea    0x14(%rbx),%esi
  mov    $0x4,%edx
  mov    %r14d,%edi
  movslq %esi,%rsi
  add    %r12,%rsi
  call   <h2net@plt>
  lea    0x18(%rbx),%edi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  movslq %edi,%rdi
  add    %r12,%rdi
  call   <memcpy@plt>
  lea    0x28(%rbx),%esi
  mov    %r13,%rdx
  mov    %r12,%rdi
  call   <md5_sum@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void hash(unsigned char *pwd, unsigned char *id, unsigned char *chaldata, int chlen, unsigned int seq, unsigned char *mda, unsigned char md) {
  unsigned char pbuf[80];
  int blen, n, i;
  blen = 0;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  n = 4;
  memcpy(&pbuf[blen], id, n);
  blen += n;
  memcpy(&pbuf[blen], chaldata, chlen);
  blen += chlen;
  n = 4;
  h2net(seq, &pbuf[blen], n);
  blen += n;
  n = 16;
  memcpy(&pbuf[blen], pwd, n);
  blen += n;
  if (md == 0x01)
    i = 2;
  else
    i = 5;
  md5_sum(pbuf, blen, mda);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getTamVetorY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x9,%eax
  jle    L20
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x28,%eax
  jg     L20
  addl   $0x1,-0x8(%rbp)
L20:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getTamVetorY(int vetor[], int tam_vetor) {
  int cont = 0, i;
  for (i = 0; i < tam_vetor; i++) {
    if (vetor[i] >= 10 && vetor[i] <= 40) {
      cont++;
    }
  }
  return cont;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getTamVetorY>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rsi
  mov    $0x0,%ecx
L15:
  mov    (%rax),%edi
  lea    -0xa(%rdi),%edx
  cmp    $0x1f,%edx
  adc    $0x0,%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L15
L0:
  mov    %ecx,%eax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L0
```

assistant: ```c
int getTamVetorY(int vetor[], int tam_vetor) {
  int cont = 0, i;
  for (i = 0; i < tam_vetor; i++) {
    if (vetor[i] >= 10 && vetor[i] <= 40) {
      cont++;
    }
  }
  return cont;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getTamVetorY>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rdx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rdi),%eax
  sub    $0xa,%eax
  cmp    $0x1f,%eax
  adc    $0x0,%r8d
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L16
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getTamVetorY(int vetor[], int tam_vetor) {
  int cont = 0, i;
  for (i = 0; i < tam_vetor; i++) {
    if (vetor[i] >= 10 && vetor[i] <= 40) {
      cont++;
    }
  }
  return cont;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getTamVetorY>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L26
  mov    %esi,%ecx
  movdqa D19(%rip),%xmm3
  pxor   %xmm1,%xmm1
  movdqa D15(%rip),%xmm2
  shr    $0x2,%ecx
  movdqa D3(%rip),%xmm5
  mov    %rdi,%rax
  movdqa %xmm1,%xmm4
  sub    $0x1,%ecx
  psubd  %xmm3,%xmm2
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L23:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddd  %xmm5,%xmm0
  psubd  %xmm3,%xmm0
  pcmpgtd %xmm2,%xmm0
  pcmpeqd %xmm4,%xmm0
  psubd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L23
  movdqa %xmm1,%xmm0
  mov    %edx,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%ecx
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%dl
  je     L54
L17:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  sub    $0xa,%esi
  cmp    $0x1f,%esi
  lea    0x1(%rcx),%esi
  adc    $0x0,%eax
  cmp    %edx,%esi
  jge    L4
  mov    0x4(%rdi,%r8,1),%esi
  sub    $0xa,%esi
  cmp    $0x1f,%esi
  adc    $0x0,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jle    L4
  mov    0x8(%rdi,%r8,1),%edx
  sub    $0xa,%edx
  cmp    $0x1f,%edx
  adc    $0x0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
L4:
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  ret
L26:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L17
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D15
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D3
type_guessed: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80]}

tool: {"D15": [0x1e,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1e,0x00,0x00,0x00]}

tool: {"D3": [0xf6,0xff,0xff,0xff,0xf6,0xff,0xff,0xff,0xf6,0xff,0xff,0xff,0xf6,0xff,0xff,0xff]}

assistant: ```c
int getTamVetorY(int vetor[], int tam_vetor) {
  int cont = 0, i;
  for (i = 0; i < tam_vetor; i++) {
    if (vetor[i] >= 10 && vetor[i] <= 40) {
      cont++;
    }
  }
  return cont;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<prefetch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  prefetcht0 (%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) void prefetch(const void *x) {
  asm volatile("661:\n\t"
               "prefetcht0 (%1)"
               "\n662:\n"
               ".section .altinstructions,\"a\"\n"
               " "
               ".balign 8"
               " "
               "\n"
               " "
               ".quad"
               " "
               "661b\n"
               " "
               ".quad"
               " "
               "663f\n"
               "	 .byte "
               "(0*32+25)"
               "\n"
               "	 .byte 662b-661b\n"
               "	 .byte 664f-663f\n"
               ".previous\n"
               ".section .altinstr_replacement, \"ax\"\n"
               "663:\n\t"
               "prefetchnta (%1)"
               "\n664:\n"
               ".previous"
               :
               : "i"(0), "r"(x));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<prefetch>:
  endbr64
  prefetcht0 (%rdi)
  ret
```

assistant: ```c
__attribute__((always_)) void prefetch(const void *x) {
  asm volatile("661:\n\t"
               "prefetcht0 (%1)"
               "\n662:\n"
               ".section .altinstructions,\"a\"\n"
               " "
               ".balign 8"
               " "
               "\n"
               " "
               ".quad"
               " "
               "661b\n"
               " "
               ".quad"
               " "
               "663f\n"
               "	 .byte "
               "(0*32+25)"
               "\n"
               "	 .byte 662b-661b\n"
               "	 .byte 664f-663f\n"
               ".previous\n"
               ".section .altinstr_replacement, \"ax\"\n"
               "663:\n\t"
               "prefetchnta (%1)"
               "\n664:\n"
               ".previous"
               :
               : "i"(0), "r"(x));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prefetch>:
  endbr64
  prefetcht0 (%rdi)
  ret
```

assistant: ```c
__attribute__((always_)) void prefetch(const void *x) {
  asm volatile("661:\n\t"
               "prefetcht0 (%1)"
               "\n662:\n"
               ".section .altinstructions,\"a\"\n"
               " "
               ".balign 8"
               " "
               "\n"
               " "
               ".quad"
               " "
               "661b\n"
               " "
               ".quad"
               " "
               "663f\n"
               "	 .byte "
               "(0*32+25)"
               "\n"
               "	 .byte 662b-661b\n"
               "	 .byte 664f-663f\n"
               ".previous\n"
               ".section .altinstr_replacement, \"ax\"\n"
               "663:\n\t"
               "prefetchnta (%1)"
               "\n664:\n"
               ".previous"
               :
               : "i"(0), "r"(x));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<new_double2DFss>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x14(%rbp),%eax
  cltq
  mov    $0x8,%ecx
  mov    %rax,%rdx
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D10
datatype: string

tool: D10: new_double2D(): calloc(%ld,%ld) failed

assistant: ```c
double **new_double2DFss(int n) {
  static char s[170];
  double **p = (double **)calloc((unsigned)n, sizeof(double *));
  if (p == NULL) {
    sprintf(s, "new_double2D(): calloc(%ld,%ld) failed", (long)n, (long)sizeof(double *));
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<new_double2DFss>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  movslq %ebp,%rdx
  mov    $0x8,%ecx
  lea    D13(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <sprintf@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type: string

tool: D13: new_double2D(): calloc(%ld,%ld) failed

assistant: ```c
double **new_double2DFss(int n) {
  static char s[170];
  double **p = (double **)calloc((unsigned)n, sizeof(double *));
  if (p == NULL) {
    sprintf(s, "new_double2D(): calloc(%ld,%ld) failed", (long)n, (long)sizeof(double *));
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<new_double2DFss>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movslq %ebx,%rdx
  mov    $0x8,%ecx
  lea    D10(%rip),%rsi
  lea    D9(%rip),%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D10: new_double2D(): calloc(%ld,%ld) failed

assistant: ```c
double **new_double2DFss(int n) {
  static char s[170];
  double **p = (double **)calloc((unsigned)n, sizeof(double *));
  if (p == NULL) {
    sprintf(s, "new_double2D(): calloc(%ld,%ld) failed", (long)n, (long)sizeof(double *));
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<new_double2DFss>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %ebx,%rdx
  mov    $0x8,%ecx
  lea    D8(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: new_double2D(): calloc(%ld,%ld) failed

assistant: ```c
double **new_double2DFss(int n) {
  static char s[170];
  double **p = (double **)calloc((unsigned)n, sizeof(double *));
  if (p == NULL) {
    sprintf(s, "new_double2D(): calloc(%ld,%ld) failed", (long)n, (long)sizeof(double *));
  }
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_count_set_bits_with_four>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <count_set_bits@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L7
  mov    $0x21,%ecx
  lea    D16(%rip),%rax
  mov    %rax,%rdx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__test_fail@plt>
L7:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
type_guessed: string
name: read_data
arguments: label: D21
type_guessed: string
name: read_data
arguments: label: D13
type_guessed: string

tool: D16: test_count_set_bits_with_four

tool: D21: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_count_set_bits.c

tool: D13: count == 1

assistant: ```c
void test_count_set_bits_with_four(void) {
  unsigned int number = 4;
  unsigned int count = count_set_bits(number);
  ((void)((count == 1) ? ((void)0) : __test_fail("count == 1", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_count_set_bits.c", __FUNCTION__, 33)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_count_set_bits_with_four>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <count_set_bits@plt>
  cmp    $0x1,%eax
  jne    L8
L3:
  add    $0x8,%rsp
  ret
L8:
  mov    $0x21,%ecx
  lea    D7(%rip),%rdx
  lea    D27(%rip),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <__test_fail@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D27
type: string
name: disassemble_data
arguments: tag: D19
type: string

tool: D7: test_count_set_bits_with_four

tool: D27: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_count_set_bits.c

tool: D19: count == 1

assistant: ```c
void test_count_set_bits_with_four(void) {
  unsigned int number = 4;
  unsigned int count = count_set_bits(number);
  ((void)((count == 1) ? ((void)0) : __test_fail("count == 1", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_count_set_bits.c", __FUNCTION__, 33)));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_count_set_bits_with_four>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <count_set_bits@plt>
  cmp    $0x1,%eax
  jne    L8
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L8:
  mov    $0x21,%ecx
  lea    D0(%rip),%rdx
  xor    %eax,%eax
  add    $0x8,%rsp
  lea    D25(%rip),%rsi
  lea    D2(%rip),%rdi
  jmp    1060 <__test_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D0: test_count_set_bits_with_four

tool: D25: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_count_set_bits.c

tool: D2: count == 1

assistant: ```c
void test_count_set_bits_with_four(void) {
  unsigned int number = 4;
  unsigned int count = count_set_bits(number);
  ((void)((count == 1) ? ((void)0) : __test_fail("count == 1", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_count_set_bits.c", __FUNCTION__, 33)));
}
```