ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<sub_eax_imm32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2d,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void sub_eax_imm32(unsigned int imm32) {
  put8(0x2D);
  put32(imm32);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sub_eax_imm32>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x2d,%edi
  call   <put8@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void sub_eax_imm32(unsigned int imm32) {
  put8(0x2D);
  put32(imm32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sub_eax_imm32>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x2d,%edi
  call   <put8@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void sub_eax_imm32(unsigned int imm32) {
  put8(0x2D);
  put32(imm32);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<deen_leaf_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x2,%rax
  mov    %rax,%rdi
  call   <deen_emalloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  lea    D19(%rip),%rcx
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D1
type_infered: string

tool: D19: /

tool: D1: %s%s%s

assistant: ```c
char *deen_leaf_path(const char *root_dir, const char *leafname) {
  char *result = (char *)deen_emalloc(strlen(root_dir) + strlen(leafname) + 2);
  sprintf(result, "%s%s%s", root_dir, "/", leafname);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<deen_leaf_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%rdi
  call   <deen_emalloc@plt>
  mov    %rax,%rbx
  mov    %r12,%r8
  lea    D16(%rip),%rcx
  mov    %rbp,%rdx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D16: /

tool: D7: %s%s%s

assistant: ```c
char *deen_leaf_path(const char *root_dir, const char *leafname) {
  char *result = (char *)deen_emalloc(strlen(root_dir) + strlen(leafname) + 2);
  sprintf(result, "%s%s%s", root_dir, "/", leafname);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<deen_leaf_path>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <deen_emalloc@plt>
  mov    %rbx,%r8
  mov    %r13,%rdx
  lea    D16(%rip),%rcx
  mov    %rax,%r12
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D16: /

tool: D14: %s%s%s

assistant: ```c
char *deen_leaf_path(const char *root_dir, const char *leafname) {
  char *result = (char *)deen_emalloc(strlen(root_dir) + strlen(leafname) + 2);
  sprintf(result, "%s%s%s", root_dir, "/", leafname);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<deen_leaf_path>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <deen_emalloc@plt>
  mov    %rbx,%r8
  mov    %r13,%rdx
  lea    D2(%rip),%rcx
  mov    %rax,%r12
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string

tool: D2: /

tool: D3: %s%s%s

assistant: ```c
char *deen_leaf_path(const char *root_dir, const char *leafname) {
  char *result = (char *)deen_emalloc(strlen(root_dir) + strlen(leafname) + 2);
  sprintf(result, "%s%s%s", root_dir, "/", leafname);
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<isLogLevel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <regmatchInsensitive@plt>
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L0
L12:
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: ^logLevel=[1-9]+$

assistant: ```c
int isLogLevel(char *string) {
  if (regmatchInsensitive(string, "^logLevel=[1-9]+$")) {
    return (1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isLogLevel>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <regmatchInsensitive@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D1: ^logLevel=[1-9]+$

assistant: ```c
int isLogLevel(char *string) {
  if (regmatchInsensitive(string, "^logLevel=[1-9]+$")) {
    return (1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isLogLevel>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rsi
  call   <regmatchInsensitive@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: ^logLevel=[1-9]+$

assistant: ```c
int isLogLevel(char *string) {
  if (regmatchInsensitive(string, "^logLevel=[1-9]+$")) {
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<isLogLevel>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  call   <regmatchInsensitive@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: ^logLevel=[1-9]+$

assistant: ```c
int isLogLevel(char *string) {
  if (regmatchInsensitive(string, "^logLevel=[1-9]+$")) {
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<utl_strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L15:
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L21:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *utl_strncat(char *dst, char *str, int n) {
  int dst_it;
  int str_it;
  dst_it = 0;
  while (dst[dst_it] != '\0')
    dst_it++;
  str_it = 0;
  while (str_it < n) {
    dst[dst_it] = str[str_it];
    dst_it++;
    str_it++;
  }
  dst[dst_it] = '\0';
  return (dst);
}
```
user: Translate the below assembly code into C programming language:

```asm
<utl_strncat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L2
  mov    $0x1,%ecx
L21:
  mov    %ecx,%edi
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rax,%rcx,1)
  jne    L21
L27:
  test   %edx,%edx
  jle    L18
  mov    %edx,%r10d
  mov    $0x0,%ecx
  movslq %edi,%r9
  add    %rax,%r9
L41:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    %r10,%rcx
  jne    L41
  add    %edx,%edi
L18:
  movslq %edi,%rdi
  movb   $0x0,(%rax,%rdi,1)
  ret
L2:
  mov    $0x0,%edi
  jmp    L27
```

assistant: ```c
char *utl_strncat(char *dst, char *str, int n) {
  int dst_it;
  int str_it;
  dst_it = 0;
  while (dst[dst_it] != '\0')
    dst_it++;
  str_it = 0;
  while (str_it < n) {
    dst[dst_it] = str[str_it];
    dst_it++;
    str_it++;
  }
  dst[dst_it] = '\0';
  return (dst);
}
```
user: Translate the below assembly code into C programming language:

```asm
<utl_strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r10
  je     L29
  mov    %edi,%r8d
  lea    0x1(%rdi),%rax
  neg    %r8d
  cs nopw 0x0(%rax,%rax,1)
L36:
  lea    (%r8,%rax,1),%edi
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L36
L41:
  test   %edx,%edx
  jle    L15
  movslq %edi,%r8
  movslq %edx,%r9
  xor    %eax,%eax
  add    %r10,%r8
L4:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L4
  add    %edx,%edi
  movslq %edi,%rdi
  lea    (%r10,%rdi,1),%rcx
L15:
  movb   $0x0,(%rcx)
  mov    %r10,%rax
  ret
  nopl   0x0(%rax)
L29:
  mov    %rdi,%rcx
  xor    %edi,%edi
  jmp    L41
```

assistant: ```c
char *utl_strncat(char *dst, char *str, int n) {
  int dst_it;
  int str_it;
  dst_it = 0;
  while (dst[dst_it] != '\0')
    dst_it++;
  str_it = 0;
  while (str_it < n) {
    dst[dst_it] = str[str_it];
    dst_it++;
    str_it++;
  }
  dst[dst_it] = '\0';
  return (dst);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utl_strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rsi,%rcx
  mov    %rdi,%r8
  mov    %edx,%esi
  je     L3
  mov    %edi,%r9d
  lea    0x1(%rdi),%rax
  neg    %r9d
  nop
L49:
  lea    (%r9,%rax,1),%edx
  mov    %rax,%rdi
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L49
L51:
  test   %esi,%esi
  jle    L58
  movslq %edx,%rdi
  lea    0x1(%rcx),%r10
  lea    -0x1(%rsi),%eax
  add    %r8,%rdi
  mov    %rdi,%r9
  sub    %r10,%r9
  cmp    $0xe,%r9
  jbe    L34
  cmp    $0x6,%eax
  jbe    L34
  push   %rbx
  cmp    $0xe,%eax
  jbe    L148
  mov    %esi,%r9d
  xor    %eax,%eax
  shr    $0x4,%r9d
  shl    $0x4,%r9
  cs nopw 0x0(%rax,%rax,1)
L57:
  movdqu (%rcx,%rax,1),%xmm1
  movups %xmm1,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %r9,%rax
  jne    L57
  mov    %esi,%eax
  and    $0xfffffff0,%eax
  mov    %eax,%r9d
  lea    (%rdx,%rax,1),%r10d
  cmp    %eax,%esi
  je     L36
  mov    %esi,%r11d
  sub    %eax,%r11d
  lea    -0x1(%r11),%ebx
  cmp    $0x6,%ebx
  jbe    L113
L178:
  movq   (%rcx,%rax,1),%xmm0
  movq   %xmm0,(%rdi,%rax,1)
  mov    %r11d,%eax
  and    $0xfffffff8,%eax
  add    %eax,%r10d
  add    %eax,%r9d
  cmp    %eax,%r11d
  je     L36
L113:
  movslq %r9d,%rax
  movzbl (%rcx,%rax,1),%edi
  movslq %r10d,%rax
  mov    %dil,(%r8,%rax,1)
  lea    0x1(%r9),%eax
  lea    0x1(%r10),%edi
  cmp    %eax,%esi
  jle    L36
  cltq
  movslq %edi,%rdi
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rdi,1)
  lea    0x2(%r9),%eax
  lea    0x2(%r10),%edi
  cmp    %eax,%esi
  jle    L36
  cltq
  movslq %edi,%rdi
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rdi,1)
  lea    0x3(%r9),%eax
  lea    0x3(%r10),%edi
  cmp    %eax,%esi
  jle    L36
  cltq
  movslq %edi,%rdi
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rdi,1)
  lea    0x4(%r9),%eax
  lea    0x4(%r10),%edi
  cmp    %eax,%esi
  jle    L36
  cltq
  movslq %edi,%rdi
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rdi,1)
  lea    0x5(%r9),%eax
  lea    0x5(%r10),%edi
  cmp    %eax,%esi
  jle    L36
  cltq
  movslq %edi,%rdi
  add    $0x6,%r9d
  add    $0x6,%r10d
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r8,%rdi,1)
  cmp    %r9d,%esi
  jle    L36
  movslq %r9d,%r9
  movslq %r10d,%r10
  movzbl (%rcx,%r9,1),%eax
  mov    %al,(%r8,%r10,1)
L36:
  add    %esi,%edx
  mov    %r8,%rax
  movslq %edx,%rdx
  lea    (%r8,%rdx,1),%rdi
  movb   $0x0,(%rdi)
  pop    %rbx
  ret
L34:
  mov    %esi,%r10d
  xor    %eax,%eax
  nopl   (%rax)
L48:
  movzbl (%rcx,%rax,1),%r9d
  mov    %r9b,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L48
  add    %esi,%edx
  movslq %edx,%rdx
  lea    (%r8,%rdx,1),%rdi
L58:
  movb   $0x0,(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %edx,%edx
  jmp    L51
L148:
  mov    %esi,%r11d
  mov    %edx,%r10d
  xor    %eax,%eax
  xor    %r9d,%r9d
  jmp    L178
```

assistant: ```c
char *utl_strncat(char *dst, char *str, int n) {
  int dst_it;
  int str_it;
  dst_it = 0;
  while (dst[dst_it] != '\0')
    dst_it++;
  str_it = 0;
  while (str_it < n) {
    dst[dst_it] = str[str_it];
    dst_it++;
    str_it++;
  }
  dst[dst_it] = '\0';
  return (dst);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tsd2dt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <ts2dt@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double tsd2dt(tsec)
double tsec;
{
  double date, time;
  ts2dt(tsec, &date, &time);
  return (time);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tsd2dt>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%eax
  call   <ts2dt@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double tsd2dt(tsec)
double tsec;
{
  double date, time;
  ts2dt(tsec, &date, &time);
  return (time);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tsd2dt>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%eax
  call   <ts2dt@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double tsd2dt(tsec)
double tsec;
{
  double date, time;
  ts2dt(tsec, &date, &time);
  return (time);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tsd2dt>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%eax
  call   <ts2dt@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double tsd2dt(tsec)
double tsec;
{
  double date, time;
  ts2dt(tsec, &date, &time);
  return (time);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_ops>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  cmp    $0x7,%eax
  je     L7
  mov    $0x5,%edi
  call   <print_fatal_error@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void check_ops(char *ops) {
  if (my_strlen(ops) != 7)
    print_fatal_error(5);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_ops>:
  endbr64
  sub    $0x8,%rsp
  call   <my_strlen@plt>
  cmp    $0x7,%eax
  jne    L5
L15:
  add    $0x8,%rsp
  ret
L5:
  mov    $0x5,%edi
  call   <print_fatal_error@plt>
  jmp    L15
```

assistant: ```c
void check_ops(char *ops) {
  if (my_strlen(ops) != 7)
    print_fatal_error(5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_ops>:
  endbr64
  sub    $0x8,%rsp
  call   <my_strlen@plt>
  cmp    $0x7,%eax
  jne    L6
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0x5,%edi
  add    $0x8,%rsp
  jmp    1060 <print_fatal_error@plt>
```

assistant: ```c
void check_ops(char *ops) {
  if (my_strlen(ops) != 7)
    print_fatal_error(5);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_ops>:
  endbr64
  sub    $0x8,%rsp
  call   <my_strlen@plt>
  cmp    $0x7,%eax
  jne    L5
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x5,%edi
  add    $0x8,%rsp
  jmp    1060 <print_fatal_error@plt>
```

assistant: ```c
void check_ops(char *ops) {
  if (my_strlen(ops) != 7)
    print_fatal_error(5);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<text_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <text_length@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *text_copy(char *text) {
  int size = text_length(text);
  char *copied_text = (char *)malloc(sizeof(char) * (size + 1));
  strcpy(copied_text, text);
  return copied_text;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<text_copy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <text_length@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *text_copy(char *text) {
  int size = text_length(text);
  char *copied_text = (char *)malloc(sizeof(char) * (size + 1));
  strcpy(copied_text, text);
  return copied_text;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<text_copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <text_length@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *text_copy(char *text) {
  int size = text_length(text);
  char *copied_text = (char *)malloc(sizeof(char) * (size + 1));
  strcpy(copied_text, text);
  return copied_text;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<text_copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <text_length@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *text_copy(char *text) {
  int size = text_length(text);
  char *copied_text = (char *)malloc(sizeof(char) * (size + 1));
  strcpy(copied_text, text);
  return copied_text;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<min_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L26:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L30
L0:
  mov    -0x30(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <search@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L37
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L37:
  addl   $0x1,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L0
  addl   $0x1,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L26
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *min_pos(int *v, int vsize, int n) {
  int *pos = malloc(n * sizeof(int));
  memset(pos, -1, n * sizeof(int));
  int i, j, min;
  for (i = 0; i < n; i++) {
    min = INT_MAX;
    for (j = 0; j < vsize; j++) {
      if (!search(j, pos, n) && v[j] < min) {
        pos[i] = j;
        min = v[j];
      }
    }
  }
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<min_pos>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %esi,0x14(%rsp)
  mov    %edx,%r14d
  mov    %edx,0x10(%rsp)
  lea    0x0(,%rdx,4),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebx,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %r14d,%r14d
  jle    L33
  mov    %r13,0x8(%rsp)
  mov    %r14d,%eax
  lea    0x0(%r13,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  jmp    L48
L55:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L68
L21:
  mov    0x10(%rsp),%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <search@plt>
  test   %eax,%eax
  jne    L55
  cmp    %r14d,(%r15,%rbx,4)
  jge    L55
  mov    0x8(%rsp),%rax
  mov    %ebx,(%rax)
  mov    (%r15,%rbx,4),%r14d
  jmp    L55
L68:
  addq   $0x4,0x8(%rsp)
  mov    0x8(%rsp),%rax
  cmp    0x18(%rsp),%rax
  je     L33
L48:
  mov    D3(%rip),%rax
  mov    (%rax),%r14d
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L68
  mov    %eax,%r12d
  mov    $0x0,%ebx
  jmp    L21
L33:
  mov    %r13,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int *min_pos(int *v, int vsize, int n) {
  int *pos = malloc(n * sizeof(int));
  memset(pos, -1, n * sizeof(int));
  int i, j, min;
  for (i = 0; i < n; i++) {
    min = INT_MAX;
    for (j = 0; j < vsize; j++) {
      if (!search(j, pos, n) && v[j] < min) {
        pos[i] = j;
        min = v[j];
      }
    }
  }
  return pos;
}
```