ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<mutt_concatn_path>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L72
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%rbp
  mov    %r8,%r13
  mov    %r9,%r12
  lea    (%rcx,%r9,1),%rdx
  test   %rcx,%rcx
  je     L93
  test   %r9,%r9
  je     L93
  add    $0x2,%rdx
  cmp    %rdx,%rax
  jb     L44
  mov    %rcx,%rdx
  call   <memcpy@plt>
  movb   $0x2f,(%rbx,%rbp,1)
  lea    0x1(%rbp),%rbp
L75:
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  call   <memcpy@plt>
  add    %r12,%rbp
  jmp    L92
L93:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jb     L44
  test   %rbp,%rbp
  jne    L1
L59:
  test   %r12,%r12
  jne    L75
L92:
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  movb   $0x0,(%rbx)
  mov    $0x0,%eax
  jmp    L80
L72:
  mov    $0x0,%eax
  ret
L1:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  jmp    L59
```

assistant: ```c
char *mutt_concatn_path(char *dst, size_t dstlen, const char *dir, size_t dirlen, const char *fname, size_t fnamelen) {
  size_t req;
  size_t offset = 0;
  if (dstlen == 0)
    return NULL;
  req = dirlen + fnamelen + 1;
  if (dirlen && fnamelen)
    req++;
  if (req > dstlen) {
    dst[0] = 0;
    return NULL;
  }
  if (dirlen) {
    memcpy(dst, dir, dirlen);
    offset = dirlen;
    if (fnamelen)
      dst[offset++] = '/';
  }
  if (fnamelen) {
    memcpy(dst + offset, fname, fnamelen);
    offset += fnamelen;
  }
  dst[offset] = 0;
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mutt_concatn_path>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L74
  push   %rbp
  mov    %rdx,%rsi
  lea    (%rcx,%r9,1),%rdx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  test   %rcx,%rcx
  je     L87
  test   %r9,%r9
  je     L87
  add    $0x2,%rdx
  cmp    %rdx,%rax
  jb     L1
  mov    %rcx,%rdx
  mov    %r9,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
  mov    0x18(%rsp),%r9
  mov    0x10(%rsp),%r8
  movb   $0x2f,(%rbx,%rcx,1)
  lea    0x1(%rcx),%rax
  mov    %r9,%rdx
  lea    (%r9,%rax,1),%rbp
  lea    (%rbx,%rax,1),%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%rbp,1),%rax
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L87:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jb     L1
  test   %rcx,%rcx
  jne    L75
  mov    %rbx,%rax
  test   %r9,%r9
  jne    L58
L49:
  movb   $0x0,(%rax)
  add    $0x28,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  movb   $0x0,(%rbx)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L58:
  mov    %r9,%rbp
  mov    %rbx,%rdi
  mov    %r9,%rdx
  mov    %r8,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%rbp,1),%rax
  jmp    L49
L75:
  mov    %rcx,%rdx
  mov    %rbx,%rdi
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
  lea    (%rbx,%rcx,1),%rax
  jmp    L49
```

assistant: ```c
char *mutt_concatn_path(char *dst, size_t dstlen, const char *dir, size_t dirlen, const char *fname, size_t fnamelen) {
  size_t req;
  size_t offset = 0;
  if (dstlen == 0)
    return NULL;
  req = dirlen + fnamelen + 1;
  if (dirlen && fnamelen)
    req++;
  if (req > dstlen) {
    dst[0] = 0;
    return NULL;
  }
  if (dirlen) {
    memcpy(dst, dir, dirlen);
    offset = dirlen;
    if (fnamelen)
      dst[offset++] = '/';
  }
  if (fnamelen) {
    memcpy(dst + offset, fname, fnamelen);
    offset += fnamelen;
  }
  dst[offset] = 0;
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mutt_concatn_path>:
  endbr64
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L71
  push   %rbp
  mov    %rdx,%rsi
  lea    (%rcx,%r9,1),%rdx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  test   %rcx,%rcx
  je     L44
  test   %r9,%r9
  je     L44
  add    $0x2,%rdx
  cmp    %rdx,%rax
  jb     L48
  mov    %rcx,%rdx
  mov    %r9,0x18(%rsp)
  mov    %r8,0x10(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
  mov    0x18(%rsp),%r9
  mov    0x10(%rsp),%r8
  movb   $0x2f,(%rbx,%rcx,1)
  lea    0x1(%rcx),%rax
  mov    %r9,%rdx
  lea    (%r9,%rax,1),%rbp
  lea    (%rbx,%rax,1),%rdi
  mov    %r8,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%rbp,1),%rax
  jmp    L91
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jb     L48
  test   %rcx,%rcx
  jne    L31
  mov    %rbx,%rax
  test   %r9,%r9
  jne    L87
L91:
  movb   $0x0,(%rax)
  add    $0x28,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L71:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  movb   $0x0,(%rbx)
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L87:
  mov    %r9,%rbp
  mov    %rbx,%rdi
  mov    %r9,%rdx
  mov    %r8,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%rbp,1),%rax
  jmp    L91
L31:
  mov    %rcx,%rdx
  mov    %rbx,%rdi
  mov    %rcx,0x8(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rcx
  lea    (%rbx,%rcx,1),%rax
  jmp    L91
```

assistant: ```c
char *mutt_concatn_path(char *dst, size_t dstlen, const char *dir, size_t dirlen, const char *fname, size_t fnamelen) {
  size_t req;
  size_t offset = 0;
  if (dstlen == 0)
    return NULL;
  req = dirlen + fnamelen + 1;
  if (dirlen && fnamelen)
    req++;
  if (req > dstlen) {
    dst[0] = 0;
    return NULL;
  }
  if (dirlen) {
    memcpy(dst, dir, dirlen);
    offset = dirlen;
    if (fnamelen)
      dst[offset++] = '/';
  }
  if (fnamelen) {
    memcpy(dst + offset, fname, fnamelen);
    offset += fnamelen;
  }
  dst[offset] = 0;
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <list_passwd@plt>
  mov    $0x0,%edi
  call   <user_by_uid@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <user_by_name@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
datatype: string
name: read_data
arguments: data_tag: D15
datatype: string

tool: D12: games

tool: D15: pwd ok


assistant: ```c
int main(int argc, char *argv[]) {
  list_passwd();
  user_by_uid(0);
  user_by_name("games");
  printf("pwd ok\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <list_passwd@plt>
  mov    $0x0,%edi
  call   <user_by_uid@plt>
  lea    D8(%rip),%rdi
  call   <user_by_name@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string

tool: D8: games

tool: D12: pwd ok


assistant: ```c
int main(int argc, char *argv[]) {
  list_passwd();
  user_by_uid(0);
  user_by_name("games");
  printf("pwd ok\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <list_passwd@plt>
  xor    %edi,%edi
  call   <user_by_uid@plt>
  lea    D9(%rip),%rdi
  call   <user_by_name@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string
name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D9: games

tool: D3: pwd ok


assistant: ```c
int main(int argc, char *argv[]) {
  list_passwd();
  user_by_uid(0);
  user_by_name("games");
  printf("pwd ok\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <list_passwd@plt>
  xor    %edi,%edi
  call   <user_by_uid@plt>
  lea    D15(%rip),%rdi
  call   <user_by_name@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D19
type: string

tool: D15: games

tool: D19: pwd ok


assistant: ```c
int main(int argc, char *argv[]) {
  list_passwd();
  user_by_uid(0);
  user_by_name("games");
  printf("pwd ok\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<re_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <alloc@plt>
  cltq
  mov    %rax,%r13
  cmpl   $0x0,-0x2c(%rbp)
  je     L18
  mov    %r13,%r12
  mov    -0x28(%rbp),%rbx
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jbe    L6
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  jmp    L6
L5:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L6:
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x30(%rbp)
  test   %eax,%eax
  jne    L5
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L18:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *re_alloc(ptr, oldsize, newsize)
char *ptr;
unsigned oldsize;
unsigned newsize;
{
  register char *pmem;
  register char *c1, *c2;
  pmem = alloc(newsize, 0);
  if (oldsize) {
    c1 = pmem;
    c2 = ptr;
    if (newsize > oldsize) {
      newsize = oldsize;
    }
    while (newsize--) {
      *c1++ = *c2++;
    }
    free(ptr);
  }
  return pmem;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<re_alloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    $0x0,%esi
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <alloc@plt>
  movslq %eax,%r12
  test   %r13d,%r13d
  je     L18
  cmp    %r13d,%ebx
  cmova  %r13d,%ebx
  lea    -0x1(%rbx),%edx
  test   %ebx,%ebx
  je     L22
  mov    %edx,%edx
  lea    0x1(%r12,%rdx,1),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  sub    %r12,%rsi
L10:
  mov    %rdx,%rax
  add    $0x1,%rdx
  movzbl -0x1(%rdx,%rsi,1),%ecx
  mov    %cl,(%rax)
  cmp    %rdi,%rdx
  jne    L10
L22:
  mov    %rbp,%rdi
  call   <free@plt>
L18:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *re_alloc(ptr, oldsize, newsize)
char *ptr;
unsigned oldsize;
unsigned newsize;
{
  register char *pmem;
  register char *c1, *c2;
  pmem = alloc(newsize, 0);
  if (oldsize) {
    c1 = pmem;
    c2 = ptr;
    if (newsize > oldsize) {
      newsize = oldsize;
    }
    while (newsize--) {
      *c1++ = *c2++;
    }
    free(ptr);
  }
  return pmem;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<re_alloc>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <alloc@plt>
  movslq %eax,%r12
  test   %r13d,%r13d
  je     L5
  cmp    %r13d,%ebx
  cmova  %r13,%rbx
  test   %ebx,%ebx
  je     L26
  mov    %rbp,%rax
  lea    (%rbx,%r12,1),%rcx
  mov    %r12,%rdx
  sub    %r12,%rax
  nopl   0x0(%rax)
L3:
  mov    %rdx,%rsi
  movzbl (%rdx,%rax,1),%edi
  add    $0x1,%rdx
  mov    %dil,(%rsi)
  cmp    %rcx,%rdx
  jne    L3
L26:
  mov    %rbp,%rdi
  call   <free@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *re_alloc(ptr, oldsize, newsize)
char *ptr;
unsigned oldsize;
unsigned newsize;
{
  register char *pmem;
  register char *c1, *c2;
  pmem = alloc(newsize, 0);
  if (oldsize) {
    c1 = pmem;
    c2 = ptr;
    if (newsize > oldsize) {
      newsize = oldsize;
    }
    while (newsize--) {
      *c1++ = *c2++;
    }
    free(ptr);
  }
  return pmem;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<re_alloc>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ebp,%edi
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x8,%rsp
  call   <alloc@plt>
  movslq %eax,%r12
  test   %ebx,%ebx
  je     L68
  cmp    %ebx,%ebp
  mov    %ebx,%eax
  cmovbe %rbp,%rax
  lea    -0x1(%rax),%ecx
  test   %eax,%eax
  je     L26
  lea    0x1(%r13),%rdi
  mov    %r12,%rsi
  mov    %r12,%rdx
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L177
  cmp    $0x6,%ecx
  jbe    L177
  cmp    $0xe,%ecx
  jbe    L104
  mov    %eax,%esi
  mov    %r13,%rdi
  shr    $0x4,%esi
  sub    %r12,%rdi
  shl    $0x4,%rsi
  add    %r12,%rsi
  nopl   0x0(%rax)
L153:
  movdqu (%rdx,%rdi,1),%xmm0
  add    $0x10,%rdx
  movups %xmm0,-0x10(%rdx)
  cmp    %rsi,%rdx
  jne    L153
  mov    %eax,%r8d
  and    $0xfffffff0,%r8d
  mov    %r8d,%edi
  sub    %r8d,%ecx
  lea    (%r12,%rdi,1),%rdx
  lea    0x0(%r13,%rdi,1),%rsi
  cmp    %r8d,%eax
  je     L26
  sub    %r8d,%eax
  lea    -0x1(%rax),%r8d
  cmp    $0x6,%r8d
  jbe    L96
L46:
  mov    0x0(%r13,%rdi,1),%r8
  mov    %r8,(%r12,%rdi,1)
  mov    %eax,%edi
  and    $0xfffffff8,%edi
  mov    %edi,%r8d
  sub    %edi,%ecx
  add    %r8,%rdx
  add    %r8,%rsi
  cmp    %edi,%eax
  je     L26
L96:
  movzbl (%rsi),%eax
  mov    %al,(%rdx)
  test   %ecx,%ecx
  je     L26
  movzbl 0x1(%rsi),%eax
  mov    %al,0x1(%rdx)
  cmp    $0x1,%ecx
  je     L26
  movzbl 0x2(%rsi),%eax
  mov    %al,0x2(%rdx)
  cmp    $0x2,%ecx
  je     L26
  movzbl 0x3(%rsi),%eax
  mov    %al,0x3(%rdx)
  cmp    $0x3,%ecx
  je     L26
  movzbl 0x4(%rsi),%eax
  mov    %al,0x4(%rdx)
  cmp    $0x4,%ecx
  je     L26
  movzbl 0x5(%rsi),%eax
  mov    %al,0x5(%rdx)
  cmp    $0x5,%ecx
  je     L26
  movzbl 0x6(%rsi),%eax
  mov    %al,0x6(%rdx)
L26:
  mov    %r13,%rdi
  call   <free@plt>
L68:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L177:
  mov    %r13,%rdi
  add    %r12,%rax
  mov    %r12,%rdx
  sub    %r12,%rdi
  nopl   0x0(%rax)
L172:
  mov    %rdx,%rcx
  movzbl (%rdx,%rdi,1),%esi
  add    $0x1,%rdx
  mov    %sil,(%rcx)
  cmp    %rax,%rdx
  jne    L172
  jmp    L26
L104:
  mov    %r13,%rsi
  xor    %edi,%edi
  jmp    L46
```

assistant: ```c
char *re_alloc(ptr, oldsize, newsize)
char *ptr;
unsigned oldsize;
unsigned newsize;
{
  register char *pmem;
  register char *c1, *c2;
  pmem = alloc(newsize, 0);
  if (oldsize) {
    c1 = pmem;
    c2 = ptr;
    if (newsize > oldsize) {
      newsize = oldsize;
    }
    while (newsize--) {
      *c1++ = *c2++;
    }
    free(ptr);
  }
  return pmem;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_ram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xff,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <sysctlbyname@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%eax
  jmp    L4
L8:
  mov    -0x14(%rbp),%eax
  lea    0x3fffffff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x1e,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  lea    D10(%rip),%rax
  mov    %rax,%rdx
  mov    $0xff,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    D30(%rip),%rax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D10
data_type: string

tool: D7: hw.memsize

tool: D10: %lld GiB

assistant: ```c
char const *get_ram(void) {
  static char ret[255];
  int64_t mem;
  size_t len = 255;
  if (sysctlbyname("hw.memsize", &mem, &len, NULL, 0))
    return NULL;
  mem = mem / 1024 / 1024 / 1024;
  snprintf(ret, 255, "%lld GiB", mem);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_ram>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0xff,0x10(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  lea    D18(%rip),%rdi
  call   <sysctlbyname@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L2
  mov    0xc(%rsp),%eax
  lea    0x3fffffff(%rax),%ecx
  test   %eax,%eax
  cmovns %eax,%ecx
  sar    $0x1e,%ecx
  mov    %ecx,0xc(%rsp)
  lea    D8(%rip),%rdx
  mov    $0xff,%esi
  lea    D26(%rip),%rbx
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
L2:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
type_guessed: string
name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D18: hw.memsize

tool: D8: %lld GiB

assistant: ```c
char const *get_ram(void) {
  static char ret[255];
  int64_t mem;
  size_t len = 255;
  if (sysctlbyname("hw.memsize", &mem, &len, NULL, 0))
    return NULL;
  mem = mem / 1024 / 1024 / 1024;
  snprintf(ret, 255, "%lld GiB", mem);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_ram>:
  endbr64
  push   %rbx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  lea    D14(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movq   $0xff,0x10(%rsp)
  call   <sysctlbyname@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L0
  mov    0xc(%rsp),%eax
  lea    D23(%rip),%rbx
  mov    $0xff,%esi
  lea    D18(%rip),%rdx
  mov    %rbx,%rdi
  test   %eax,%eax
  lea    0x3fffffff(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x1e,%ecx
  mov    %ecx,0xc(%rsp)
  call   <snprintf@plt>
  mov    %rbx,%rax
L0:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string

tool: D14: hw.memsize

tool: D18: %lld GiB

assistant: ```c
char const *get_ram(void) {
  static char ret[255];
  int64_t mem;
  size_t len = 255;
  if (sysctlbyname("hw.memsize", &mem, &len, NULL, 0))
    return NULL;
  mem = mem / 1024 / 1024 / 1024;
  snprintf(ret, 255, "%lld GiB", mem);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_ram>:
  endbr64
  push   %rbx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  lea    D16(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  movq   $0xff,0x10(%rsp)
  call   <sysctlbyname@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L8
  mov    0xc(%rsp),%eax
  lea    D25(%rip),%rbx
  mov    $0xff,%esi
  lea    D1(%rip),%rdx
  mov    %rbx,%rdi
  test   %eax,%eax
  lea    0x3fffffff(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x1e,%ecx
  mov    %ecx,0xc(%rsp)
  call   <snprintf@plt>
  mov    %rbx,%rax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string

tool: D16: hw.memsize

tool: D1: %lld GiB

assistant: ```c
char const *get_ram(void) {
  static char ret[255];
  int64_t mem;
  size_t len = 255;
  if (sysctlbyname("hw.memsize", &mem, &len, NULL, 0))
    return NULL;
  mem = mem / 1024 / 1024 / 1024;
  snprintf(ret, 255, "%lld GiB", mem);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  cmpl   $0x4,-0x8(%rbp)
  jle    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(char t[4]) {
  int i;
  int sum = 0;
  for (i = 0; i < 5; i++) {
    sum += t[i];
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum>:
  endbr64
  lea    0x5(%rdi),%rcx
  mov    $0x0,%eax
L8:
  movsbl (%rdi),%edx
  add    %edx,%eax
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L8
  ret
```

assistant: ```c
int sum(char t[4]) {
  int i;
  int sum = 0;
  for (i = 0; i < 5; i++) {
    sum += t[i];
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sum>:
  endbr64
  lea    0x5(%rdi),%rcx
  xor    %eax,%eax
L5:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L5
  ret
```

assistant: ```c
int sum(char t[4]) {
  int i;
  int sum = 0;
  for (i = 0; i < 5; i++) {
    sum += t[i];
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sum>:
  endbr64
  movsbl 0x1(%rdi),%eax
  movsbl (%rdi),%edx
  add    %eax,%edx
  movsbl 0x2(%rdi),%eax
  add    %edx,%eax
  movsbl 0x3(%rdi),%edx
  add    %eax,%edx
  movsbl 0x4(%rdi),%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int sum(char t[4]) {
  int i;
  int sum = 0;
  for (i = 0; i < 5; i++) {
    sum += t[i];
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<power10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L22
  mov    $0xa,%eax
  jmp    L1
L22:
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L2
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  shr    %eax
  mov    %eax,%edi
  call   <power10>
  mov    %eax,%edi
  call   <sq@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  jmp    L1
L2:
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edi
  call   <power10>
  mov    %eax,%edi
  call   <sq@plt>
L1:
  leave
  ret
```

assistant: ```c
unsigned int power10(unsigned int n) {
  if (n == 1)
    return 10;
  if (n % 2)
    return 10 * sq(power10((n - 1) / 2));
  return sq(power10(n / 2));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<power10>:
  endbr64
  cmp    $0x1,%edi
  je     L27
  sub    $0x8,%rsp
  test   $0x1,%dil
  jne    L22
  shr    %edi
  call   <power10>
  mov    %eax,%edi
  call   <sq@plt>
L6:
  add    $0x8,%rsp
  ret
L22:
  sub    $0x1,%edi
  shr    %edi
  call   <power10>
  mov    %eax,%edi
  call   <sq@plt>
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  jmp    L6
L27:
  mov    $0xa,%eax
  ret
```

assistant: ```c
unsigned int power10(unsigned int n) {
  if (n == 1)
    return 10;
  if (n % 2)
    return 10 * sq(power10((n - 1) / 2));
  return sq(power10(n / 2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<power10>:
  endbr64
  cmp    $0x1,%edi
  je     L14
  sub    $0x8,%rsp
  test   $0x1,%dil
  jne    L0
  shr    %edi
  call   <power10>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1050 <sq@plt>
  nopl   (%rax)
L0:
  sub    $0x1,%edi
  shr    %edi
  call   <power10>
  mov    %eax,%edi
  call   <sq@plt>
  add    $0x8,%rsp
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0xa,%eax
  ret
```

assistant: ```c
unsigned int power10(unsigned int n) {
  if (n == 1)
    return 10;
  if (n % 2)
    return 10 * sq(power10((n - 1) / 2));
  return sq(power10(n / 2));
}
```