user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<merge_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %esi,-0x5c(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x5c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x44(%rbp)
  jmp    L128
L6:
  movl   $0x0,-0x40(%rbp)
  jmp    L16
L113:
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x44(%rbp),%eax
  add    %eax,%edx
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <min@plt>
  mov    %eax,-0x28(%rbp)
  mov    -0x40(%rbp),%edx
  mov    -0x44(%rbp),%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %eax,%edx
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <min@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L127
L80:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L72
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L99
L72:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
L99:
  mov    -0x3c(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x3c(%rbp)
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,(%rdx)
L127:
  mov    -0x38(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L4
  mov    -0x34(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L80
  jmp    L4
L26:
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L4:
  mov    -0x38(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L26
  jmp    L0
L44:
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L0:
  mov    -0x34(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  mov    -0x44(%rbp),%eax
  add    %eax,%eax
  add    %eax,-0x40(%rbp)
L16:
  mov    -0x40(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L113
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  shll   -0x44(%rbp)
L128:
  mov    -0x44(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L6
  mov    -0x18(%rbp),%rax
  cmp    -0x58(%rbp),%rax
  je     L115
  movl   $0x0,-0x30(%rbp)
  jmp    L75
L101:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x30(%rbp)
L75:
  mov    -0x30(%rbp),%eax
  cmp    -0x5c(%rbp),%eax
  jl     L101
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L115:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void merge_sort(int arr[], int len) {
  int *a = arr;
  int *b = (int *)malloc(len * sizeof(int));
  int seg, start;
  for (seg = 1; seg < len; seg += seg) {
    for (start = 0; start < len; start += (seg + seg)) {
      int low = start, mid = min(start + seg, len), high = min(start + seg + seg, len);
      int k = low;
      int start1 = low, end1 = mid;
      int start2 = mid, end2 = high;
      while (start1 < end1 && start2 < end2)
        b[k++] = a[start1] < a[start2] ? a[start1++] : a[start2++];
      while (start1 < end1)
        b[k++] = a[start1++];
      while (start2 < end2)
        b[k++] = a[start2++];
    }
    int *temp = a;
    a = b;
    b = temp;
  }
  if (a != arr) {
    int i;
    for (i = 0; i < len; i++)
      b[i] = a[i];
    b = a;
  }
  free(b);
}
```