ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,%rdx
  rol    $0x10,%eax
  shr    $0x20,%rdx
  movd   %eax,%xmm1
  movd   %edx,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,%rdx
  imul   $0xe3600c9,%rdx,%rax
  movabs $0x6e800000001d584d,%rdx
  or     %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local2;
  unsigned long local1;
  unsigned short copy11;
  unsigned int copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((unsigned short *)(&state[local2]) + 0);
        *((unsigned short *)(&state[local2]) + 0) = *((unsigned short *)(&state[local2]) + 1);
        *((unsigned short *)(&state[local2]) + 1) = copy11;
        copy12 = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = copy12;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] * 238420169UL | 7962364141192960077UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<code>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void code(char *s) {
  while (*s) {
    (*s)++;
    s++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<code>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
L2:
  add    $0x1,%eax
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
L10:
  ret
```

assistant: ```c
void code(char *s) {
  while (*s) {
    (*s)++;
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<code>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L7:
  add    $0x1,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
  ret
```

assistant: ```c
void code(char *s) {
  while (*s) {
    (*s)++;
    s++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<code>:
  endbr64
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L10:
  add    $0x1,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
L2:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L10
  ret
```

assistant: ```c
void code(char *s) {
  while (*s) {
    (*s)++;
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<construct_piece_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    -0x3c(%rbp),%eax
  add    $0xd,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    0x9(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x7,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x38(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x9(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    0xd(%rax),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *construct_piece_message(int piece_index, int blockoffset, int piece_len, char *piece) {
  char *msg = malloc(13 + piece_len);
  int *msgLen = malloc(4);
  *msgLen = 9 + piece_len;
  int *piece_id = malloc(4);
  int *block_off = malloc(4);
  char *msgID = malloc(1);
  *msgID = 7;
  *piece_id = piece_index;
  *block_off = blockoffset;
  memcpy(msg, msgLen, 4);
  memcpy(msg + 4, msgID, 1);
  memcpy(msg + 5, piece_id, 4);
  memcpy(msg + 9, block_off, 4);
  memcpy(msg + 13, piece, piece_len);
  free(msgLen);
  free(msgID);
  free(piece_id);
  free(block_off);
  return msg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<construct_piece_message>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %rcx,%r12
  lea    0xd(%rdx),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0x9(%rbp),%eax
  mov    %eax,(%rbx)
  movb   $0x7,0x4(%rbx)
  mov    %r14d,0x5(%rbx)
  mov    %r13d,0x9(%rbx)
  lea    0xd(%rbx),%rdi
  movslq %ebp,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *construct_piece_message(int piece_index, int blockoffset, int piece_len, char *piece) {
  char *msg = malloc(13 + piece_len);
  int *msgLen = malloc(4);
  *msgLen = 9 + piece_len;
  int *piece_id = malloc(4);
  int *block_off = malloc(4);
  char *msgID = malloc(1);
  *msgID = 7;
  *piece_id = piece_index;
  *block_off = blockoffset;
  memcpy(msg, msgLen, 4);
  memcpy(msg + 4, msgID, 1);
  memcpy(msg + 5, piece_id, 4);
  memcpy(msg + 9, block_off, 4);
  memcpy(msg + 13, piece, piece_len);
  free(msgLen);
  free(msgID);
  free(piece_id);
  free(block_off);
  return msg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<construct_piece_message>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  lea    0xd(%rdx),%edi
  push   %r13
  movslq %edi,%rdi
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <malloc@plt>
  movslq %ebx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  lea    0x9(%rbx),%eax
  lea    0xd(%r12),%rdi
  mov    %r14d,0x5(%r12)
  mov    %r13d,0x9(%r12)
  mov    %eax,(%r12)
  movb   $0x7,0x4(%r12)
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *construct_piece_message(int piece_index, int blockoffset, int piece_len, char *piece) {
  char *msg = malloc(13 + piece_len);
  int *msgLen = malloc(4);
  *msgLen = 9 + piece_len;
  int *piece_id = malloc(4);
  int *block_off = malloc(4);
  char *msgID = malloc(1);
  *msgID = 7;
  *piece_id = piece_index;
  *block_off = blockoffset;
  memcpy(msg, msgLen, 4);
  memcpy(msg + 4, msgID, 1);
  memcpy(msg + 5, piece_id, 4);
  memcpy(msg + 9, block_off, 4);
  memcpy(msg + 13, piece, piece_len);
  free(msgLen);
  free(msgID);
  free(piece_id);
  free(block_off);
  return msg;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<construct_piece_message>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    0xd(%rdx),%edi
  push   %rbx
  movslq %edi,%rdi
  mov    %edx,%ebx
  call   <malloc@plt>
  movd   %r13d,%xmm1
  movslq %ebx,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  movd   %ebp,%xmm0
  lea    0x9(%rbx),%eax
  punpckldq %xmm1,%xmm0
  lea    0xd(%r12),%rdi
  mov    %eax,(%r12)
  movb   $0x7,0x4(%r12)
  movq   %xmm0,0x5(%r12)
  call   <memcpy@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *construct_piece_message(int piece_index, int blockoffset, int piece_len, char *piece) {
  char *msg = malloc(13 + piece_len);
  int *msgLen = malloc(4);
  *msgLen = 9 + piece_len;
  int *piece_id = malloc(4);
  int *block_off = malloc(4);
  char *msgID = malloc(1);
  *msgID = 7;
  *piece_id = piece_index;
  *block_off = blockoffset;
  memcpy(msg, msgLen, 4);
  memcpy(msg + 4, msgID, 1);
  memcpy(msg + 5, piece_id, 4);
  memcpy(msg + 9, block_off, 4);
  memcpy(msg + 13, piece, piece_len);
  free(msgLen);
  free(msgID);
  free(piece_id);
  free(block_off);
  return msg;
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  xor    $0x1cdb,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L2
L16:
  lea    -0xa(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  lea    -0xa(%rbp),%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xd(%rbp),%edx
  mov    %dl,(%rax)
  addw   $0x2,-0xc(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L16
  movw   $0x0,-0xc(%rbp)
  jmp    L34
L45:
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rdx,%rax
  movzwl -0xc(%rbp),%edx
  lea    -0xa(%rbp),%rcx
  movslq %edx,%rdx
  add    %rdx,%rdx
  add    %rcx,%rdx
  add    $0x1,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  lea    -0xa(%rbp),%rdx
  cltq
  add    %rax,%rax
  add    %rax,%rdx
  movzbl -0xe(%rbp),%eax
  mov    %al,(%rdx)
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L34:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L45
  movzwl -0xa(%rbp),%eax
  xor    $0x537d,%ax
  or     $0x6e22,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy12 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy12;
      local1++;
    }
    output[0UL] = (state[0UL] ^ 255873917UL) | (unsigned short)28194;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  xor    $0x1cdb,%ax
  mov    %ax,0x6(%rsp)
  movzwl 0x2(%rdi),%edx
  test   %dx,%dx
  je     L34
  mov    $0x0,%eax
L22:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L22
  lea    0x6(%rsp),%rax
  sub    $0x1,%edx
  movzwl %dx,%edx
  lea    0x8(%rsp,%rdx,2),%rdi
L18:
  movzbl 0x1(%rax),%edx
  movzbl (%rax),%ecx
  mov    %cl,0x1(%rax)
  mov    %dl,(%rax)
  add    $0x2,%rax
  cmp    %rdi,%rax
  jne    L18
L34:
  movzwl 0x6(%rsp),%eax
  xor    $0x537d,%ax
  or     $0x6e22,%ax
  mov    %ax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy12 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy12;
      local1++;
    }
    output[0UL] = (state[0UL] ^ 255873917UL) | (unsigned short)28194;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  movzwl 0x2(%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzwl (%rdi),%eax
  xor    $0x1cdb,%ax
  mov    %ax,0x6(%rsp)
  test   %dx,%dx
  je     L2
  xor    %eax,%eax
  nop
L24:
  add    $0x2,%eax
  cmp    %dx,%ax
  jb     L24
  sub    $0x1,%edx
  lea    0x6(%rsp),%rax
  movzwl %dx,%edx
  lea    0x8(%rsp,%rdx,2),%rdi
  nopl   0x0(%rax,%rax,1)
L31:
  movzbl 0x1(%rax),%edx
  movzbl (%rax),%ecx
  add    $0x2,%rax
  mov    %cl,-0x1(%rax)
  mov    %dl,-0x2(%rax)
  cmp    %rdi,%rax
  jne    L31
  movzwl 0x6(%rsp),%eax
L2:
  xor    $0x537d,%ax
  or     $0x6e22,%ax
  mov    %ax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  char copy12;
  {
    state[0UL] = input[0UL] ^ (unsigned short)7387;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy11 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy11;
      copy11 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy11;
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      copy12 = *((char *)(&state[local1]) + 1);
      *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
      *((char *)(&state[local1]) + 0) = copy12;
      local1++;
    }
    output[0UL] = (state[0UL] ^ 255873917UL) | (unsigned short)28194;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L40
L81:
  addq   $0x1,-0x18(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L81
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L81
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L81
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L81
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xc,%al
  je     L81
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xb,%al
  je     L81
  jmp    L28
L19:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L92
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L19
L92:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int atoi(const char *str) {
  int result = 0;
  while (((*str) == ' ' || (*str) == '\t' || (*str) == '\r' || (*str) == '\n' || (*str) == '\f' || (*str) == '\v'))
    str++;
  while (((*str) >= '0' && (*str) <= '9'))
    result = (result * 10) + (*(str++) - '0');
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L4
  cmp    $0x20,%al
  jne    L5
L4:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L4
  cmp    $0x20,%al
  je     L4
L5:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L11
  mov    $0x0,%edx
L47:
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L47
L29:
  mov    %edx,%eax
  ret
L11:
  mov    $0x0,%edx
  jmp    L29
```

assistant: ```c
int atoi(const char *str) {
  int result = 0;
  while (((*str) == ' ' || (*str) == '\t' || (*str) == '\r' || (*str) == '\n' || (*str) == '\f' || (*str) == '\v'))
    str++;
  while (((*str) >= '0' && (*str) <= '9'))
    result = (result * 10) + (*(str++) - '0');
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoi>:
  endbr64
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L16:
  add    $0x1,%rdi
L19:
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L16
  cmp    $0x20,%al
  je     L16
  lea    -0x30(%rax),%edx
  xor    %r8d,%r8d
  cmp    $0x9,%dl
  ja     L17
  xchg   %ax,%ax
L22:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L22
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(const char *str) {
  int result = 0;
  while (((*str) == ' ' || (*str) == '\t' || (*str) == '\r' || (*str) == '\n' || (*str) == '\f' || (*str) == '\v'))
    str++;
  while (((*str) >= '0' && (*str) <= '9'))
    result = (result * 10) + (*(str++) - '0');
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atoi>:
  endbr64
  jmp    L37
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%rdi
L37:
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x4,%dl
  jbe    L0
  cmp    $0x20,%al
  je     L0
  lea    -0x30(%rax),%edx
  xor    %r8d,%r8d
  cmp    $0x9,%dl
  ja     L35
  xchg   %ax,%ax
L46:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L46
L35:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(const char *str) {
  int result = 0;
  while (((*str) == ' ' || (*str) == '\t' || (*str) == '\r' || (*str) == '\n' || (*str) == '\f' || (*str) == '\v'))
    str++;
  while (((*str) >= '0' && (*str) <= '9'))
    result = (result * 10) + (*(str++) - '0');
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_pmac_test_vectors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x480,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x3f0(%rbp)
  movq   $0x0,-0x3e8(%rbp)
  lea    -0x3e0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7b,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x0,-0x470(%rbp)
  movq   $0x0,-0x468(%rbp)
  movb   $0x1,-0x461(%rbp)
  movl   $0x0,-0x474(%rbp)
  jmp    L26
L37:
  mov    -0x474(%rbp),%eax
  mov    %eax,%edx
  mov    -0x474(%rbp),%eax
  cltq
  mov    %dl,-0x450(%rbp,%rax,1)
  addl   $0x1,-0x474(%rbp)
L26:
  cmpl   $0x1f,-0x474(%rbp)
  jle    L37
  movl   $0x0,-0x474(%rbp)
  jmp    L45
L9:
  mov    -0x474(%rbp),%eax
  mov    %eax,%edx
  mov    -0x474(%rbp),%eax
  cltq
  mov    %dl,-0x430(%rbp,%rax,1)
  addl   $0x1,-0x474(%rbp)
L45:
  cmpl   $0x21,-0x474(%rbp)
  jle    L9
  lea    -0x460(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <print_pmac_test_case@plt>
  lea    -0x460(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <print_pmac_test_case@plt>
  lea    -0x460(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x10,%edi
  call   <print_pmac_test_case@plt>
  lea    -0x460(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x14,%edi
  call   <print_pmac_test_case@plt>
  lea    -0x460(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <print_pmac_test_case@plt>
  lea    -0x460(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x22,%edi
  call   <print_pmac_test_case@plt>
  lea    -0x460(%rbp),%rcx
  lea    -0x3f0(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3e8,%edi
  call   <print_pmac_test_case@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: 


assistant: ```c
int print_pmac_test_vectors(void) {
  char z[1000] =
      {
          0,
      },
       key[32], pt[50], ct[1000],
       nonce[16] =
           {
               0,
           },
       tag[16];
  int i;
  nonce[15] = 1;
  for (i = 0; i < 32; i++) {
    key[i] = i;
  }
  for (i = 0; i < 34; i++) {
    pt[i] = i;
  }
  print_pmac_test_case(0, key, pt, tag);
  print_pmac_test_case(3, key, pt, tag);
  print_pmac_test_case(16, key, pt, tag);
  print_pmac_test_case(20, key, pt, tag);
  print_pmac_test_case(32, key, pt, tag);
  print_pmac_test_case(34, key, pt, tag);
  print_pmac_test_case(1000, key, z, tag);
  printf("\n");
  return 0;
}
```