ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<qromb>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x2d8,%rsp
  movsd  %xmm0,0x8(%rsp)
  lea    0x8(%rsp),%r15
  lea    0x18(%rsp),%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x2c8(%rsp)
  xor    %eax,%eax
  mov    D41(%rip),%rax
  movsd  %xmm1,(%rsp)
  lea    0x158(%rsp),%rbp
  lea    0x10(%rsp),%r13
  mov    %rax,0x178(%rsp)
  call   <trapzd@plt>
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x28(%rsp)
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x8,%rbp
  add    $0x8,%r15
L15:
  movsd  D12(%rip),%xmm0
  mulsd  0x20(%rbp),%xmm0
  add    $0x1,%ebx
  movsd  %xmm0,0x28(%rbp)
  cmp    $0x29,%ebx
  je     L52
  movsd  0x8(%rsp),%xmm0
  mov    %ebx,%esi
  mov    %r12,%rdi
  movsd  %xmm1,(%rsp)
  call   <trapzd@plt>
  cmp    $0x4,%ebx
  movsd  (%rsp),%xmm1
  movsd  %xmm0,0x28(%r15)
  jle    L26
  pxor   %xmm0,%xmm0
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    $0x5,%edx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  movsd  %xmm1,(%rsp)
  call   <polint@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm0
  andpd  D32(%rip),%xmm0
  movsd  (%rsp),%xmm1
  movapd %xmm3,%xmm2
  andpd  D32(%rip),%xmm2
  mulsd  D37(%rip),%xmm2
  comisd %xmm0,%xmm2
  jb     L26
L32:
  mov    0x2c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x2d8,%rsp
  movapd %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  lea    D50(%rip),%rdi
  call   <nrerror@plt>
  pxor   %xmm3,%xmm3
  jmp    L32
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D41
datatype: f64
name: read_data
arguments: data_label: D12
datatype: f64
name: read_data
arguments: data_label: D32
datatype: qword[2]
name: read_data
arguments: data_label: D37
datatype: byte[8]
name: read_data
arguments: data_label: D50
datatype: string

tool: D41: 1

tool: D12: 0.25

tool: {"D32": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D37": [0x3a,0x8c,0x30,0xe2,0x8e,0x79,0x45,0x3e]}

tool: D50: Too many steps in routine qromb

assistant: ```c
double qromb(double (*func)(double), double a, double b) {
  void polint(double xa[], double ya[], int n, double x, double *y, double *dy);
  double trapzd(double (*func)(double), double a, double b, int n);
  void nrerror(char error_text[]);
  double ss, dss;
  double s[(40 + 1)], h[(40 + 1) + 1];
  int j;
  h[1] = 1.0;
  for (j = 1; j <= 40; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) <= 1.0e-8 * fabs(ss))
        return ss;
    }
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine qromb");
  return 0.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<numberOfBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L57
  mov    $0x0,%eax
  jmp    L32
L57:
  movl   $0x1f,-0x4(%rbp)
  jmp    L7
L1:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L55
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  jmp    L32
L55:
  subl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    $0x1,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int numberOfBits(unsigned int src) {
  unsigned int b;
  if (src == 0)
    return 0;
  for (b = (sizeof(unsigned int) * 8) - 1; b > 0; --b)
    if ((((src) & (1U << (b))) != 0))
      return b + 1;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<numberOfBits>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L34
  js     L35
  mov    $0x1e,%eax
L6:
  bt     %eax,%edi
  jb     L10
  sub    $0x1,%eax
  jne    L6
  mov    $0x1,%eax
L34:
  ret
L35:
  mov    $0x1f,%eax
L10:
  add    $0x1,%eax
  ret
```

assistant: ```c
unsigned int numberOfBits(unsigned int src) {
  unsigned int b;
  if (src == 0)
    return 0;
  for (b = (sizeof(unsigned int) * 8) - 1; b > 0; --b)
    if ((((src) & (1U << (b))) != 0))
      return b + 1;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<numberOfBits>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L35
  mov    $0x1f,%eax
  jmp    L30
  nopl   0x0(%rax)
L23:
  sub    $0x1,%eax
  je     L33
L30:
  bt     %eax,%edi
  jae    L23
  add    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    $0x1,%eax
L35:
  ret
```

assistant: ```c
unsigned int numberOfBits(unsigned int src) {
  unsigned int b;
  if (src == 0)
    return 0;
  for (b = (sizeof(unsigned int) * 8) - 1; b > 0; --b)
    if ((((src) & (1U << (b))) != 0))
      return b + 1;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<numberOfBits>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L20
  mov    $0x1f,%eax
  jmp    L9
  nopl   0x0(%rax)
L36:
  sub    $0x1,%eax
  je     L11
L9:
  bt     %eax,%edi
  jae    L36
  add    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0x1,%eax
L20:
  ret
```

assistant: ```c
unsigned int numberOfBits(unsigned int src) {
  unsigned int b;
  if (src == 0)
    return 0;
  for (b = (sizeof(unsigned int) * 8) - 1; b > 0; --b)
    if ((((src) & (1U << (b))) != 0))
      return b + 1;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  lea    -0x14(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  sar    $0x2,%rax
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movl   $0x5,(%rax)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int arr[] = {1, 2, 3};
  int *x = arr;
  int *y = &arr[2];
  int diff = y - x;
  x += diff;
  *x = 5;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int arr[] = {1, 2, 3};
  int *x = arr;
  int *y = &arr[2];
  int diff = y - x;
  x += diff;
  *x = 5;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int arr[] = {1, 2, 3};
  int *x = arr;
  int *y = &arr[2];
  int diff = y - x;
  x += diff;
  *x = 5;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int arr[] = {1, 2, 3};
  int *x = arr;
  int *y = &arr[2];
  int diff = y - x;
  x += diff;
  *x = 5;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  nop
  mov    -0x10(%rbp),%rax
  lea    0x60f19126(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x746187bc,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  add    $0x746187bc,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy11;
      } else {
        state[0UL] = state[local1] * state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 1626444070UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<SkipChars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L88
  mov    $0x0,%eax
  jmp    L37
L88:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L72
  cmpq   $0x0,-0x10(%rbp)
  je     L72
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L72
  cmpl   $0x0,-0x14(%rbp)
  jne    L49
L72:
  mov    -0x8(%rbp),%rax
  jmp    L37
L98:
  addq   $0x1,-0x8(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L49
  subl   $0x1,-0x14(%rbp)
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L103
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  jne    L103
  cmpl   $0x0,-0x14(%rbp)
  jne    L98
L103:
  mov    -0x8(%rbp),%rax
L37:
  leave
  ret
```

assistant: ```c
const char *SkipChars(const char *szStr, const char *szChars, int count) {
  if (!szStr)
    return (0);
  if (!(*szStr) || !szChars || !(*szChars) || ((0) == count))
    return szStr;
  while ((*szStr) && ((0) == strchr(szChars, (*szStr))) && (count != 0)) {
    szStr++;
    if ((-1) != count)
      count--;
  }
  return szStr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SkipChars>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L35
  mov    %rsi,%r12
  mov    %edx,%ebp
  movzbl (%rdi),%esi
  test   %r12,%r12
  je     L35
  test   %sil,%sil
  je     L35
  cmpb   $0x0,(%r12)
  je     L35
  test   %edx,%edx
  je     L35
L67:
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %ebp,%ebp
  je     L35
  test   %eax,%eax
  jne    L35
  add    $0x1,%rbx
  cmp    $0xffffffff,%ebp
  setne  %al
  movzbl %al,%eax
  sub    %eax,%ebp
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L67
L35:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *SkipChars(const char *szStr, const char *szChars, int count) {
  if (!szStr)
    return (0);
  if (!(*szStr) || !szChars || !(*szChars) || ((0) == count))
    return szStr;
  while ((*szStr) && ((0) == strchr(szChars, (*szStr))) && (count != 0)) {
    szStr++;
    if ((-1) != count)
      count--;
  }
  return szStr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<SkipChars>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L6
  mov    %rsi,%rbp
  movsbl (%rdi),%esi
  test   %rbp,%rbp
  je     L6
  test   %sil,%sil
  je     L6
  cmpb   $0x0,0x0(%rbp)
  je     L6
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L52
  jmp    L6
  xchg   %ax,%ax
L25:
  test   %ebx,%ebx
  je     L6
  add    $0x1,%r12
  xor    %eax,%eax
  movsbl (%r12),%esi
  cmp    $0xffffffff,%ebx
  setne  %al
  sub    %eax,%ebx
  test   %sil,%sil
  je     L6
L52:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L25
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *SkipChars(const char *szStr, const char *szChars, int count) {
  if (!szStr)
    return (0);
  if (!(*szStr) || !szChars || !(*szChars) || ((0) == count))
    return szStr;
  while ((*szStr) && ((0) == strchr(szChars, (*szStr))) && (count != 0)) {
    szStr++;
    if ((-1) != count)
      count--;
  }
  return szStr;
}
```
user: What is the c source code of the assembly code below:

```asm
<SkipChars>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L65
  mov    %rsi,%rbp
  movsbl (%rdi),%esi
  test   %rbp,%rbp
  je     L65
  test   %sil,%sil
  je     L65
  cmpb   $0x0,0x0(%rbp)
  je     L65
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L87
  jmp    L65
  xchg   %ax,%ax
L25:
  test   %ebx,%ebx
  je     L65
  add    $0x1,%r12
  xor    %eax,%eax
  movsbl (%r12),%esi
  cmp    $0xffffffff,%ebx
  setne  %al
  sub    %eax,%ebx
  test   %sil,%sil
  je     L65
L87:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %eax,%eax
  je     L25
L65:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *SkipChars(const char *szStr, const char *szChars, int count) {
  if (!szStr)
    return (0);
  if (!(*szStr) || !szChars || !(*szChars) || ((0) == count))
    return szStr;
  while ((*szStr) && ((0) == strchr(szChars, (*szStr))) && (count != 0)) {
    szStr++;
    if ((-1) != count)
      count--;
  }
  return szStr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<beta_ii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D10(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D18(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
data_type: byte[8]
name: unpack_data
arguments: tag: D18
data_type: byte[8]

tool: {"D10": [0xe5,0x33,0x8f,0xb2,0x34,0xa6,0xd6,0x3e]}

tool: {"D18": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x8a,0x3e]}

assistant: ```c
double beta_ii(double p) {
  double val = 0.0;
  val = 2.0E-07 + 5.4E-06 * p;
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<beta_ii>:
  endbr64
  mulsd  D17(%rip),%xmm0
  addsd  D10(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D10
type_infered: byte[8]

tool: {"D17": [0xe5,0x33,0x8f,0xb2,0x34,0xa6,0xd6,0x3e]}

tool: {"D10": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x8a,0x3e]}

assistant: ```c
double beta_ii(double p) {
  double val = 0.0;
  val = 2.0E-07 + 5.4E-06 * p;
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<beta_ii>:
  endbr64
  mulsd  D0(%rip),%xmm0
  addsd  D3(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D3
datatype: byte[8]

tool: {"D0": [0xe5,0x33,0x8f,0xb2,0x34,0xa6,0xd6,0x3e]}

tool: {"D3": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x8a,0x3e]}

assistant: ```c
double beta_ii(double p) {
  double val = 0.0;
  val = 2.0E-07 + 5.4E-06 * p;
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<beta_ii>:
  endbr64
  mulsd  D6(%rip),%xmm0
  addsd  D16(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D16
type_guessed: byte[8]

tool: {"D6": [0xe5,0x33,0x8f,0xb2,0x34,0xa6,0xd6,0x3e]}

tool: {"D16": [0x48,0xaf,0xbc,0x9a,0xf2,0xd7,0x8a,0x3e]}

assistant: ```c
double beta_ii(double p) {
  double val = 0.0;
  val = 2.0E-07 + 5.4E-06 * p;
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L35:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  ja     L40
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
L40:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jae    L22
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L22:
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jb     L35
  mov    -0xc(%rbp),%eax
  lea    0x50edd68c(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] < local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x3f60a4d,%eax
  mov    0x4(%rdi),%edi
  test   %edi,%edi
  je     L15
  mov    $0x0,%edx
L7:
  lea    (%rax,%rax,1),%ecx
  cmp    %eax,%edx
  cmovbe %ecx,%eax
  lea    (%rax,%rax,1),%ecx
  cmp    %edx,%eax
  cmova  %ecx,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L7
L15:
  add    $0x50edd68c,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] < local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edi
  sub    $0x3f60a4d,%eax
  test   %edi,%edi
  je     L17
  xor    %edx,%edx
  nopl   0x0(%rax)
L11:
  cmp    %eax,%edx
  lea    (%rax,%rax,1),%ecx
  cmovbe %ecx,%eax
  cmp    %edx,%eax
  lea    (%rax,%rax,1),%ecx
  cmova  %ecx,%eax
  add    $0x1,%edx
  cmp    %edi,%edx
  jne    L11
L17:
  add    $0x50edd68c,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] < local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%ecx
  sub    $0x3f60a4d,%eax
  test   %ecx,%ecx
  je     L16
  xor    %edx,%edx
  nopl   0x0(%rax)
L24:
  cmp    %edx,%eax
  jb     L5
  add    %eax,%eax
  lea    (%rax,%rax,1),%edi
  cmp    %edx,%eax
  cmova  %edi,%eax
L5:
  add    $0x1,%edx
  cmp    %ecx,%edx
  jne    L24
L16:
  add    $0x50edd68c,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (!(state[0UL] < local1)) {
        state[local1] += state[0UL];
      }
      if (state[0UL] > local1) {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L18
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <usb_reset@plt>
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *usb_device;
  int ret = 0;
  int idx = 1;
  for (idx = 1; idx < argc; idx++) {
    usb_device = argv[idx];
    ret = usb_reset(usb_device);
  }
  return (ret);
  if (argc == 2) {
    usb_device = argv[1];
    ret = usb_reset(usb_device);
    return (ret);
  }
  if (argc == 3) {
    while (1) {
      usleep(10000L);
      printf(".\b");
    }
    return (ret);
  }
  hu_log(3, "hu_uti", __func__, "1");
  sleep(1);
  hu_log(3, "hu_uti", __func__, "2");
  sleep(1);
  hu_log(3, "hu_uti", __func__, "3");
  sleep(1);
  unsigned long this_ms = 0;
  unsigned long sleep_val = 1L;
  unsigned long last_ms = ms_get();
  for (sleep_val = 64L; sleep_val <= 10000L; sleep_val += 64L) {
    ms_sleep(sleep_val);
    this_ms = ms_get();
    hu_log(3, "hu_uti", __func__, "Done ms_sleep (%6.6ld)  ms: %16ld\n", sleep_val, this_ms - last_ms);
    last_ms = this_ms;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L10
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
L7:
  mov    (%rbx),%rdi
  mov    $0x0,%eax
  call   <usb_reset@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *usb_device;
  int ret = 0;
  int idx = 1;
  for (idx = 1; idx < argc; idx++) {
    usb_device = argv[idx];
    ret = usb_reset(usb_device);
  }
  return (ret);
  if (argc == 2) {
    usb_device = argv[1];
    ret = usb_reset(usb_device);
    return (ret);
  }
  if (argc == 3) {
    while (1) {
      usleep(10000L);
      printf(".\b");
    }
    return (ret);
  }
  hu_log(3, "hu_uti", __func__, "1");
  sleep(1);
  hu_log(3, "hu_uti", __func__, "2");
  sleep(1);
  hu_log(3, "hu_uti", __func__, "3");
  sleep(1);
  unsigned long this_ms = 0;
  unsigned long sleep_val = 1L;
  unsigned long last_ms = ms_get();
  for (sleep_val = 64L; sleep_val <= 10000L; sleep_val += 64L) {
    ms_sleep(sleep_val);
    this_ms = ms_get();
    hu_log(3, "hu_uti", __func__, "Done ms_sleep (%6.6ld)  ms: %16ld\n", sleep_val, this_ms - last_ms);
    last_ms = this_ms;
  }
  return (0);
}
```