ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<modOfPower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L0:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L0
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int modOfPower(int value, int power, int modulus) {
  int x = 1;
  for (int i = 0; i < power; i++) {
    x = (x * value) % modulus;
  }
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<modOfPower>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L28
  mov    $0x0,%ecx
  mov    $0x1,%edx
L19:
  mov    %edx,%eax
  imul   %edi,%eax
  cltd
  idiv   %r8d
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L19
L16:
  mov    %edx,%eax
  ret
L28:
  mov    $0x1,%edx
  jmp    L16
```

assistant: ```c
int modOfPower(int value, int power, int modulus) {
  int x = 1;
  for (int i = 0; i < power; i++) {
    x = (x * value) % modulus;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<modOfPower>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L7
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %edx,%eax
  add    $0x1,%ecx
  imul   %edi,%eax
  cltd
  idiv   %r8d
  cmp    %ecx,%esi
  jne    L13
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int modOfPower(int value, int power, int modulus) {
  int x = 1;
  for (int i = 0; i < power; i++) {
    x = (x * value) % modulus;
  }
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modOfPower>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L18
  xor    %ecx,%ecx
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %edx,%eax
  add    $0x1,%ecx
  imul   %edi,%eax
  cltd
  idiv   %r8d
  cmp    %ecx,%esi
  jne    L19
  mov    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int modOfPower(int value, int power, int modulus) {
  int x = 1;
  for (int i = 0; i < power; i++) {
    x = (x * value) % modulus;
  }
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L3
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(int *arr, int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
    mergeSort(arr, low, mid);
    mergeSort(arr, mid + 1, high);
    merge(arr, low, mid, high);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L9
  ret
L9:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mergeSort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <mergeSort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void mergeSort(int *arr, int low, int high) {
  int mid;
  if (low < high) {
    mid = (low + high) / 2;
    mergeSort(arr, low, mid);
    mergeSort(arr, mid + 1, high);
    merge(arr, low, mid, high);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<float_le>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <f2u@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <f2u@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L10
  cmpl   $0x0,-0x4(%rbp)
  je     L9
L10:
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  test   %eax,%eax
  jne    L57
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  test   %eax,%eax
  je     L9
L57:
  cmpl   $0x0,-0x8(%rbp)
  jne    L16
  cmpl   $0x0,-0x4(%rbp)
  jne    L16
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jbe    L9
L16:
  cmpl   $0x0,-0x8(%rbp)
  je     L46
  cmpl   $0x0,-0x4(%rbp)
  je     L46
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jb     L46
L9:
  mov    $0x1,%eax
  jmp    L56
L46:
  mov    $0x0,%eax
L56:
  leave
  ret
```

assistant: ```c
int float_le(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return (sx && !sy) || ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && !sy && ux <= uy) || (sx && sy && ux >= uy);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<float_le>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <f2u@plt>
  mov    %eax,%ebx
  movss  0xc(%rsp),%xmm0
  call   <f2u@plt>
  mov    %ebx,%edi
  shr    $0x1f,%edi
  setne  %sil
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  jne    L44
  mov    $0x1,%edx
  test   %sil,%sil
  je     L44
L47:
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L44:
  mov    %eax,%r8d
  or     %ebx,%r8d
  mov    $0x1,%edx
  add    %r8d,%r8d
  je     L47
  or     %ecx,%edi
  jne    L1
  cmp    %eax,%ebx
  jbe    L47
L1:
  cmp    %eax,%ebx
  setae  %dl
  and    %esi,%ecx
  and    %ecx,%edx
  jmp    L47
```

assistant: ```c
int float_le(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return (sx && !sy) || ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && !sy && ux <= uy) || (sx && sy && ux >= uy);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<float_le>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <f2u@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <f2u@plt>
  mov    %ebx,%edx
  mov    $0x1,%r8d
  mov    %eax,%ecx
  shr    $0x1f,%edx
  shr    $0x1f,%ecx
  mov    %ecx,%esi
  xor    $0x1,%esi
  test   %edx,%esi
  jne    L20
  mov    %eax,%esi
  or     %ebx,%esi
  add    %esi,%esi
  jne    L27
L20:
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L27:
  mov    %edx,%edi
  or     %ecx,%edi
  jne    L23
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  setbe  %r8b
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  cmp    %eax,%ebx
  setae  %r8b
  and    %ecx,%edx
  add    $0x10,%rsp
  and    %edx,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int float_le(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return (sx && !sy) || ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && !sy && ux <= uy) || (sx && sy && ux >= uy);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<float_le>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <f2u@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <f2u@plt>
  mov    %ebx,%edx
  mov    $0x1,%r8d
  mov    %eax,%ecx
  shr    $0x1f,%edx
  shr    $0x1f,%ecx
  mov    %ecx,%esi
  xor    $0x1,%esi
  test   %edx,%esi
  jne    L13
  mov    %eax,%esi
  or     %ebx,%esi
  add    %esi,%esi
  jne    L5
L13:
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  xchg   %ax,%ax
L5:
  mov    %edx,%edi
  or     %ecx,%edi
  jne    L24
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  setbe  %r8b
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  cmp    %eax,%ebx
  setae  %r8b
  and    %ecx,%edx
  add    $0x10,%rsp
  and    %edx,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int float_le(float x, float y) {
  unsigned ux = f2u(x);
  unsigned uy = f2u(y);
  unsigned sx = ux >> 31;
  unsigned sy = uy >> 31;
  return (sx && !sy) || ((ux << 1) == 0 && (uy << 1) == 0) || (!sx && !sy && ux <= uy) || (sx && sy && ux >= uy);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initmac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <defmac@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <defmac@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <defmac@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D24
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string

tool: D3: cpm	1

tool: D24: Z80	1

tool: D10: smallc	1

assistant: ```c
void initmac(void) {
  defmac("cpm\t1");
  defmac("Z80\t1");
  defmac("smallc\t1");
}
```
user: What is the c source code of the assembly code below?

```asm
<initmac>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <defmac@plt>
  lea    D15(%rip),%rdi
  call   <defmac@plt>
  lea    D4(%rip),%rdi
  call   <defmac@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type: string
name: retrieve_data
arguments: tag: D15
type: string
name: retrieve_data
arguments: tag: D4
type: string

tool: D13: cpm	1

tool: D15: Z80	1

tool: D4: smallc	1

assistant: ```c
void initmac(void) {
  defmac("cpm\t1");
  defmac("Z80\t1");
  defmac("smallc\t1");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<initmac>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <defmac@plt>
  lea    D6(%rip),%rdi
  call   <defmac@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <defmac@plt>
```

tool_calls: name: disassemble_data
arguments: label: D28
type: string
name: disassemble_data
arguments: label: D6
type: string
name: disassemble_data
arguments: label: D10
type: string

tool: D28: cpm	1

tool: D6: Z80	1

tool: D10: smallc	1

assistant: ```c
void initmac(void) {
  defmac("cpm\t1");
  defmac("Z80\t1");
  defmac("smallc\t1");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initmac>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <defmac@plt>
  lea    D6(%rip),%rdi
  call   <defmac@plt>
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <defmac@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string

tool: D9: cpm	1

tool: D6: Z80	1

tool: D19: smallc	1

assistant: ```c
void initmac(void) {
  defmac("cpm\t1");
  defmac("Z80\t1");
  defmac("smallc\t1");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__strtok_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L143
L7:
  nop
L37:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L135
L1:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L135
  jmp    L37
L135:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  cmpl   $0x0,-0x18(%rbp)
  jne    L72
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L143
L72:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L82:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L115
  cmpl   $0x0,-0x18(%rbp)
  jne    L83
  movq   $0x0,-0x28(%rbp)
  jmp    L19
L83:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,(%rax)
L19:
  mov    -0x38(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L143
L115:
  cmpl   $0x0,-0x14(%rbp)
  jne    L30
  jmp    L82
L143:
  pop    %rbp
  ret
```

assistant: ```c
char *__strtok_r(char *s, const char *delim, char **last) {
  char *spanp, *tok;
  int c, sc;
  if (s == NULL && (s = *last) == NULL) {
    return (NULL);
  }
cont:
  c = *s++;
  for (spanp = (char *)delim; (sc = *spanp++) != 0;) {
    if (c == sc) {
      goto cont;
    }
  }
  if (c == 0) {
    *last = NULL;
    return (NULL);
  }
  tok = s - 1;
  for (;;) {
    c = *s++;
    spanp = (char *)delim;
    do {
      if ((sc = *spanp++) == c) {
        if (c == 0) {
          s = NULL;
        } else {
          s[-1] = '\0';
        }
        *last = s;
        return (tok);
      }
    } while (sc != 0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__strtok_r>:
  endbr64
  test   %rdi,%rdi
  jne    L83
  mov    (%rdx),%rdi
  test   %rdi,%rdi
  jne    L83
  mov    %rdi,%rax
  ret
L68:
  mov    %rax,%rdi
L83:
  lea    0x1(%rdi),%rax
  movsbl (%rdi),%r9d
  mov    %rsi,%rcx
L58:
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%r8d
  test   %r8d,%r8d
  je     L26
  cmp    %r8d,%r9d
  jne    L58
  jmp    L68
L26:
  test   %r9d,%r9d
  je     L34
L82:
  add    $0x1,%rax
  movsbl -0x1(%rax),%r9d
  mov    %rsi,%rcx
L76:
  add    $0x1,%rcx
  movsbl -0x1(%rcx),%r8d
  cmp    %r8d,%r9d
  je     L73
  test   %r8d,%r8d
  jne    L76
  jmp    L82
L34:
  movq   $0x0,(%rdx)
  mov    $0x0,%eax
  ret
L73:
  test   %r9d,%r9d
  je     L12
  movb   $0x0,-0x1(%rax)
  jmp    L74
L12:
  mov    $0x0,%eax
L74:
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *__strtok_r(char *s, const char *delim, char **last) {
  char *spanp, *tok;
  int c, sc;
  if (s == NULL && (s = *last) == NULL) {
    return (NULL);
  }
cont:
  c = *s++;
  for (spanp = (char *)delim; (sc = *spanp++) != 0;) {
    if (c == sc) {
      goto cont;
    }
  }
  if (c == 0) {
    *last = NULL;
    return (NULL);
  }
  tok = s - 1;
  for (;;) {
    c = *s++;
    spanp = (char *)delim;
    do {
      if ((sc = *spanp++) == c) {
        if (c == 0) {
          s = NULL;
        } else {
          s[-1] = '\0';
        }
        *last = s;
        return (tok);
      }
    } while (sc != 0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__strtok_r>:
  endbr64
  test   %rdi,%rdi
  je     L9
L48:
  movsbl (%rdi),%r9d
  lea    0x1(%rdi),%rax
  mov    %rsi,%rcx
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L20:
  cmp    %r8d,%r9d
  je     L64
L25:
  movsbl (%rcx),%r8d
  add    $0x1,%rcx
  test   %r8d,%r8d
  jne    L20
  test   %r9d,%r9d
  je     L38
L108:
  add    $0x1,%rax
  mov    %rsi,%rcx
  movsbl -0x1(%rax),%r9d
  jmp    L102
  nopl   (%rax)
L65:
  test   %r8d,%r8d
  je     L108
L102:
  movsbl (%rcx),%r8d
  add    $0x1,%rcx
  cmp    %r8d,%r9d
  jne    L65
  test   %r9d,%r9d
  je     L103
  movb   $0x0,-0x1(%rax)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %rax,%rdi
  jmp    L48
  nopl   (%rax)
L103:
  xor    %eax,%eax
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L9:
  mov    (%rdx),%rdi
  test   %rdi,%rdi
  jne    L48
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *__strtok_r(char *s, const char *delim, char **last) {
  char *spanp, *tok;
  int c, sc;
  if (s == NULL && (s = *last) == NULL) {
    return (NULL);
  }
cont:
  c = *s++;
  for (spanp = (char *)delim; (sc = *spanp++) != 0;) {
    if (c == sc) {
      goto cont;
    }
  }
  if (c == 0) {
    *last = NULL;
    return (NULL);
  }
  tok = s - 1;
  for (;;) {
    c = *s++;
    spanp = (char *)delim;
    do {
      if ((sc = *spanp++) == c) {
        if (c == 0) {
          s = NULL;
        } else {
          s[-1] = '\0';
        }
        *last = s;
        return (tok);
      }
    } while (sc != 0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__strtok_r>:
  endbr64
  test   %rdi,%rdi
  je     L12
L79:
  movsbl (%rdi),%r9d
  lea    0x1(%rdi),%rax
  mov    %rsi,%rcx
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L67:
  cmp    %r8d,%r9d
  je     L3
L60:
  movsbl (%rcx),%r8d
  add    $0x1,%rcx
  test   %r8d,%r8d
  jne    L67
  test   %r9d,%r9d
  je     L2
L64:
  add    $0x1,%rax
  mov    %rsi,%rcx
  movsbl -0x1(%rax),%r9d
  jmp    L97
  nopl   (%rax)
L55:
  test   %r8d,%r8d
  je     L64
L97:
  movsbl (%rcx),%r8d
  add    $0x1,%rcx
  cmp    %r8d,%r9d
  jne    L55
  test   %r9d,%r9d
  je     L69
  movb   $0x0,-0x1(%rax)
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rax,%rdi
  jmp    L79
  nopl   (%rax)
L69:
  xor    %eax,%eax
  mov    %rax,(%rdx)
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L12:
  mov    (%rdx),%rdi
  test   %rdi,%rdi
  jne    L79
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  movq   $0x0,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *__strtok_r(char *s, const char *delim, char **last) {
  char *spanp, *tok;
  int c, sc;
  if (s == NULL && (s = *last) == NULL) {
    return (NULL);
  }
cont:
  c = *s++;
  for (spanp = (char *)delim; (sc = *spanp++) != 0;) {
    if (c == sc) {
      goto cont;
    }
  }
  if (c == 0) {
    *last = NULL;
    return (NULL);
  }
  tok = s - 1;
  for (;;) {
    c = *s++;
    spanp = (char *)delim;
    do {
      if ((sc = *spanp++) == c) {
        if (c == 0) {
          s = NULL;
        } else {
          s[-1] = '\0';
        }
        *last = s;
        return (tok);
      }
    } while (sc != 0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L0
  movl   $0x4,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int tmp___0;
  {
    tmp___0 = f();
    if (!tmp___0) {
      tmp___0 = 4;
    }
    return (tmp___0);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  test   %eax,%eax
  mov    $0x4,%edx
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int tmp___0;
  {
    tmp___0 = f();
    if (!tmp___0) {
      tmp___0 = 4;
    }
    return (tmp___0);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  mov    $0x4,%edx
  test   %eax,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int tmp___0;
  {
    tmp___0 = f();
    if (!tmp___0) {
      tmp___0 = 4;
    }
    return (tmp___0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  mov    $0x4,%edx
  test   %eax,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int tmp___0;
  {
    tmp___0 = f();
    if (!tmp___0) {
      tmp___0 = 4;
    }
    return (tmp___0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<WRITE_DHCPC_FILE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  je     L4
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L4:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: Write udhcpc script file error!


assistant: ```c
void WRITE_DHCPC_FILE(int fh, unsigned char *buf) {
  if (write(fh, buf, strlen(buf)) != strlen(buf)) {
    printf("Write udhcpc script file error!\n");
    close(fh);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<WRITE_DHCPC_FILE>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    %rax,%r12
  jne    L1
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: string

tool: D6: Write udhcpc script file error!


assistant: ```c
void WRITE_DHCPC_FILE(int fh, unsigned char *buf) {
  if (write(fh, buf, strlen(buf)) != strlen(buf)) {
    printf("Write udhcpc script file error!\n");
    close(fh);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<WRITE_DHCPC_FILE>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12d,%edi
  mov    %rbp,%rsi
  mov    %rax,%rdx
  call   <write@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    10b0 <close@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: Write udhcpc script file error!


assistant: ```c
void WRITE_DHCPC_FILE(int fh, unsigned char *buf) {
  if (write(fh, buf, strlen(buf)) != strlen(buf)) {
    printf("Write udhcpc script file error!\n");
    close(fh);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<WRITE_DHCPC_FILE>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12d,%edi
  mov    %rbp,%rsi
  mov    %rax,%rdx
  call   <write@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  jmp    10b0 <close@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: Write udhcpc script file error!


assistant: ```c
void WRITE_DHCPC_FILE(int fh, unsigned char *buf) {
  if (write(fh, buf, strlen(buf)) != strlen(buf)) {
    printf("Write udhcpc script file error!\n");
    close(fh);
  }
}
```