ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<roxml_is_number>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <roxml_strtonum@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L28
  movsbl (%rax),%edi
  call   <roxml_is_separator@plt>
  test   %rax,%rax
  je     L13
L28:
  mov    $0x1,%eax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L13:
  mov    (%rsp),%rax
  movzbl (%rax),%ecx
  xor    %eax,%eax
  cmp    $0x27,%cl
  ja     L15
  movabs $0xffffff7bfffffffe,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  jmp    L15
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int roxml_is_number(char *input) {
  char *end;
  int is_number = 0;
  roxml_strtonum(input, &end);
  if ((end == NULL) || (roxml_is_separator(end[0])) || (end[0] == '"') || (end[0] == '\'') || (end[0] == '\0')) {
    is_number = 1;
  }
  return is_number;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<roxml_is_number>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <roxml_strtonum@plt>
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L18
  movsbl (%rax),%edi
  call   <roxml_is_separator@plt>
  test   %rax,%rax
  je     L4
L18:
  mov    $0x1,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L4:
  mov    (%rsp),%rax
  movzbl (%rax),%ecx
  xor    %eax,%eax
  cmp    $0x27,%cl
  ja     L5
  movabs $0xffffff7bfffffffe,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  jmp    L5
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int roxml_is_number(char *input) {
  char *end;
  int is_number = 0;
  roxml_strtonum(input, &end);
  if ((end == NULL) || (roxml_is_separator(end[0])) || (end[0] == '"') || (end[0] == '\'') || (end[0] == '\0')) {
    is_number = 1;
  }
  return is_number;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<testequal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <maxBall@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L2
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: Error. Expected %d but got %d


assistant: ```c
void testequal(int v0, int exp) {
  int act = maxBall(v0);
  if (act != exp)
    printf("Error. Expected %d but got %d\n", exp, act);
  assert(exp == act);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<testequal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  call   <maxBall@plt>
  mov    %eax,%ebp
  cmp    %ebx,%eax
  jne    L13
L16:
  cmp    %ebx,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: Error. Expected %d but got %d


assistant: ```c
void testequal(int v0, int exp) {
  int act = maxBall(v0);
  if (act != exp)
    printf("Error. Expected %d but got %d\n", exp, act);
  assert(exp == act);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testequal>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <maxBall@plt>
  mov    %eax,%ebp
  cmp    %ebx,%eax
  je     L0
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
L0:
  xor    %edi,%edi
  cmp    %ebx,%ebp
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <assert@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: Error. Expected %d but got %d


assistant: ```c
void testequal(int v0, int exp) {
  int act = maxBall(v0);
  if (act != exp)
    printf("Error. Expected %d but got %d\n", exp, act);
  assert(exp == act);
}
```
user: Translate the below assembly code into C programming language:

```asm
<testequal>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <maxBall@plt>
  mov    %eax,%ebp
  cmp    %ebx,%eax
  je     L8
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
L8:
  xor    %edi,%edi
  cmp    %ebx,%ebp
  sete   %dil
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <assert@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: Error. Expected %d but got %d


assistant: ```c
void testequal(int v0, int exp) {
  int act = maxBall(v0);
  if (act != exp)
    printf("Error. Expected %d but got %d\n", exp, act);
  assert(exp == act);
}
```
user: What is the c source code of the assembly code below?

```asm
<xp_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L10
  mov    $0x0,%eax
  jmp    L21
L10:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L10
  mov    -0xc(%rbp),%eax
  cltq
L21:
  leave
  ret
```

assistant: ```c
long xp_random(int n) {
  double f = 0;
  int ret;
  if (n < 2)
    return (0);
  do {
    f = (double)rand() / (double)(RAND_MAX + 1);
    ret = (int)(n * f);
  } while (ret == n);
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xp_random>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L5
L15:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %eax,%ebx
  je     L15
  cltq
L5:
  pop    %rbx
  ret
```

assistant: ```c
long xp_random(int n) {
  double f = 0;
  int ret;
  if (n < 2)
    return (0);
  do {
    f = (double)rand() / (double)(RAND_MAX + 1);
    ret = (int)(n * f);
  } while (ret == n);
  return (ret);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xp_random>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  pxor   %xmm3,%xmm3
  push   %rbp
  cvtsi2sd %edi,%xmm3
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    D4(%rip),%rbp
  movsd  %xmm3,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm0
  mov    0x0(%rbp),%rax
  add    $0x1,%rax
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %eax,%ebx
  je     L5
  add    $0x18,%rsp
  cltq
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
long xp_random(int n) {
  double f = 0;
  int ret;
  if (n < 2)
    return (0);
  do {
    f = (double)rand() / (double)(RAND_MAX + 1);
    ret = (int)(n * f);
  } while (ret == n);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xp_random>:
  endbr64
  cmp    $0x1,%edi
  jle    L8
  pxor   %xmm3,%xmm3
  push   %rbp
  cvtsi2sd %edi,%xmm3
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    D5(%rip),%rbp
  movsd  %xmm3,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm0
  mov    0x0(%rbp),%rax
  add    $0x1,%rax
  cvtsi2sd %rax,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %eax,%ebx
  je     L12
  add    $0x18,%rsp
  cltq
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
long xp_random(int n) {
  double f = 0;
  int ret;
  if (n < 2)
    return (0);
  do {
    f = (double)rand() / (double)(RAND_MAX + 1);
    ret = (int)(n * f);
  } while (ret == n);
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D13: x value:     %d


tool: D14: x address:   %p


assistant: ```c
int main() {
  int x;
  printf("x value:     %d\n", x);
  printf("x address:   %p\n", &x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D11: x value:     %d


tool: D17: x address:   %p


assistant: ```c
int main() {
  int x;
  printf("x value:     %d\n", x);
  printf("x address:   %p\n", &x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D2: x value:     %d


tool: D10: x address:   %p


assistant: ```c
int main() {
  int x;
  printf("x value:     %d\n", x);
  printf("x address:   %p\n", &x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x4(%rsp),%esi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D6: x value:     %d


tool: D16: x address:   %p


assistant: ```c
int main() {
  int x;
  printf("x value:     %d\n", x);
  printf("x address:   %p\n", &x);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L18:
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned h = 0;
  while (*str)
    h = (h << 1) + *str++;
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L27
  mov    $0x0,%edx
L7:
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
L22:
  mov    %edx,%eax
  ret
L27:
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned h = 0;
  while (*str)
    h = (h << 1) + *str++;
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L2
  xchg   %ax,%ax
L5:
  add    $0x1,%rdi
  lea    (%rax,%r8,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L5
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned h = 0;
  while (*str)
    h = (h << 1) + *str++;
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  xchg   %ax,%ax
L4:
  add    $0x1,%rdi
  lea    (%rax,%r8,2),%r8d
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L4
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned hash(const char *str) {
  unsigned h = 0;
  while (*str)
    h = (h << 1) + *str++;
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x3,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <find@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: is find_result null? %d


assistant: ```c
int main() {
  int arr[3] = {5, 4, 2};
  int *find_result = find(arr, 3, 3);
  printf("is find_result null? %d\n", find_result == NULL);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x5,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x3,%edx
  mov    $0x3,%esi
  call   <find@plt>
  test   %rax,%rax
  sete   %sil
  movzbl %sil,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: is find_result null? %d


assistant: ```c
int main() {
  int arr[3] = {5, 4, 2};
  int *find_result = find(arr, 3, 3);
  printf("is find_result null? %d\n", find_result == NULL);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    $0x3,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000005,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x2,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <find@plt>
  xor    %esi,%esi
  lea    D7(%rip),%rdi
  test   %rax,%rax
  sete   %sil
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
datatype: string

tool: D7: is find_result null? %d


assistant: ```c
int main() {
  int arr[3] = {5, 4, 2};
  int *find_result = find(arr, 3, 3);
  printf("is find_result null? %d\n", find_result == NULL);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3,%esi
  mov    $0x3,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x2,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <find@plt>
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  test   %rax,%rax
  sete   %sil
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: byte[8]
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: {"D7": [0x05,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D8: is find_result null? %d


assistant: ```c
int main() {
  int arr[3] = {5, 4, 2};
  int *find_result = find(arr, 3, 3);
  printf("is find_result null? %d\n", find_result == NULL);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<deleteList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L19
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <deleteNode@plt>
  mov    %rax,-0x8(%rbp)
L19:
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct ListNode *deleteList(struct ListNode *head) {
  while (head != NULL) {
    head = deleteNode(head);
  }
  return head;
}
```
user: What is the c source code of the assembly code below?

```asm
<deleteList>:
  endbr64
  test   %rdi,%rdi
  je     L11
  sub    $0x8,%rsp
L4:
  call   <deleteNode@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
struct ListNode *deleteList(struct ListNode *head) {
  while (head != NULL) {
    head = deleteNode(head);
  }
  return head;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<deleteList>:
  endbr64
  test   %rdi,%rdi
  je     L13
  sub    $0x8,%rsp
  nopl   (%rax)
L15:
  call   <deleteNode@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct ListNode *deleteList(struct ListNode *head) {
  while (head != NULL) {
    head = deleteNode(head);
  }
  return head;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<deleteList>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  nopl   (%rax)
L10:
  call   <deleteNode@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L10
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
struct ListNode *deleteList(struct ListNode *head) {
  while (head != NULL) {
    head = deleteNode(head);
  }
  return head;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sample>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  addl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sample(int i) {
  i += 1;
  int j = 0;
  j += 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sample>:
  endbr64
  ret
```

assistant: ```c
void sample(int i) {
  i += 1;
  int j = 0;
  j += 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sample>:
  endbr64
  ret
```

assistant: ```c
void sample(int i) {
  i += 1;
  int j = 0;
  j += 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sample>:
  endbr64
  ret
```

assistant: ```c
void sample(int i) {
  i += 1;
  int j = 0;
  j += 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_any_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L21
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L8
L21:
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int is_any_of(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      (*ofs)++;
      return (1);
    }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_any_of>:
  endbr64
  mov    (%rcx),%r9d
  movslq %r9d,%rax
  movsbl (%rdx,%rax,1),%r8d
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
L9:
  movzbl (%rax),%edx
  cmp    %r8d,%edx
  je     L19
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L9
  mov    $0x0,%eax
  ret
L19:
  add    $0x1,%r9d
  mov    %r9d,(%rcx)
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_any_of(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      (*ofs)++;
      return (1);
    }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_any_of>:
  endbr64
  movslq (%rcx),%rax
  movsbl (%rdx,%rax,1),%edx
  mov    %rax,%r8
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  jmp    L29
  nopl   0x0(%rax)
L35:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L8
L29:
  movzbl (%rdi),%eax
  cmp    %edx,%eax
  jne    L35
  add    $0x1,%r8d
  mov    $0x1,%eax
  mov    %r8d,(%rcx)
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_any_of(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      (*ofs)++;
      return (1);
    }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_any_of>:
  endbr64
  movslq (%rcx),%rax
  movsbl (%rdx,%rax,1),%edx
  mov    %rax,%r8
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  jmp    L24
  nopl   0x0(%rax)
L5:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L18
L24:
  movzbl (%rdi),%eax
  cmp    %edx,%eax
  jne    L5
  add    $0x1,%r8d
  mov    $0x1,%eax
  mov    %r8d,(%rcx)
  ret
  nopl   (%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_any_of(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      (*ofs)++;
      return (1);
    }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_cpy(int a, int b) {
  int c = a;
  a = b;
  b = c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap_cpy>:
  endbr64
  ret
```

assistant: ```c
void swap_cpy(int a, int b) {
  int c = a;
  a = b;
  b = c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_cpy>:
  endbr64
  ret
```

assistant: ```c
void swap_cpy(int a, int b) {
  int c = a;
  a = b;
  b = c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap_cpy>:
  endbr64
  ret
```

assistant: ```c
void swap_cpy(int a, int b) {
  int c = a;
  a = b;
  b = c;
}
```