user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0xc(%rbp)
  addl   $0x3,-0xc(%rbp)
  subl   $0x3,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  add    %edx,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x3,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L28
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L28
  mov    $0x1,%eax
  jmp    L46
L28:
  mov    $0x0,%eax
L46:
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L18
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L52
L18:
  mov    $0x1,%eax
  jmp    L11
L52:
  mov    $0x0,%eax
L11:
  mov    %eax,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x6,%esi
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xfffffffc,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D97
data_type: string
name: retrieve_data
arguments: data_label: D54
data_type: string

tool: D20: %d 
 


tool: D97: %d %d 


tool: D54: %d 


assistant: ```c
int main() {
  int a = 3;
  a = a + 3;
  a = a - 3;
  a = a * 3;
  a = a / 3;
  a = a % 3;
  printf("%d \n \n", a);
  int x = 3, y = 2;
  printf("%d %d \n", x == y, x != y);
  printf("%d %d \n", x > y, x <= y);
  printf("%d \n", (x > y) && (x <= y));
  printf("%d \n", (x > y) || (x <= y));
  printf("%d \n \n", !(x > y));
  printf("%d %d \n", 3 & 1, 3 | 1);
  printf("%d \n", 3 ^ 1);
  printf("%d %d \n", 3 << 1, 3 >> 1);
  printf("%d \n", ~3);
  return 0;
}
```