user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xf4000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x270,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xf4268(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xf4258(%rbp)
  jmp    L13
L72:
  cmpl   $0x0,-0xf4258(%rbp)
  jle    L40
  mov    $0xa,%edi
  call   <putchar@plt>
L40:
  lea    -0xf4264(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xf4254(%rbp)
  jmp    L116
L45:
  lea    -0xf425c(%rbp),%rdx
  lea    -0xf4260(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xf4260(%rbp),%eax
  mov    %eax,%edx
  mov    -0xf425c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0xf4254(%rbp),%eax
  cltq
  mov    %dl,-0xf4250(%rbp,%rax,1)
  addl   $0x1,-0xf4254(%rbp)
L116:
  mov    -0xf4264(%rbp),%eax
  cmp    %eax,-0xf4254(%rbp)
  jl     L45
  mov    -0xf4264(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xf4254(%rbp)
  jmp    L17
L69:
  mov    -0xf4254(%rbp),%eax
  cltq
  movzbl -0xf4250(%rbp,%rax,1),%eax
  cmp    $0x9,%al
  jle    L119
  mov    -0xf4254(%rbp),%eax
  cltq
  movzbl -0xf4250(%rbp,%rax,1),%eax
  sub    $0xa,%eax
  mov    %eax,%edx
  mov    -0xf4254(%rbp),%eax
  cltq
  mov    %dl,-0xf4250(%rbp,%rax,1)
  mov    -0xf4254(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  movzbl -0xf4250(%rbp,%rdx,1),%edx
  add    $0x1,%edx
  cltq
  mov    %dl,-0xf4250(%rbp,%rax,1)
L119:
  subl   $0x1,-0xf4254(%rbp)
L17:
  cmpl   $0x0,-0xf4254(%rbp)
  jns    L69
  movl   $0x0,-0xf4254(%rbp)
  jmp    L67
L70:
  mov    -0xf4254(%rbp),%eax
  cltq
  movzbl -0xf4250(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xf4254(%rbp)
L67:
  mov    -0xf4264(%rbp),%eax
  cmp    %eax,-0xf4254(%rbp)
  jl     L70
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xf4258(%rbp)
L13:
  mov    -0xf4268(%rbp),%eax
  cmp    %eax,-0xf4258(%rbp)
  jl     L72
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L101
  call   <__stack_chk_fail@plt>
L101:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D35
type_guessed: string
name: parse_data
arguments: label: D25
type_guessed: string
name: parse_data
arguments: label: D28
type_guessed: string

tool: D35: %d


tool: D25: %d %d


tool: D28: %d

assistant: ```c
int main() {
  int num_cases, num_digits;
  int op1, op2;
  char sum[1000000];
  int i, j;
  scanf("%d\n", &num_cases);
  for (i = 0; i < num_cases; i++) {
    if (i > 0) {
      printf("\n");
    }
    scanf("%d\n", &num_digits);
    for (j = 0; j < num_digits; j++) {
      scanf("%d %d\n", &op1, &op2);
      sum[j] = op1 + op2;
    }
    for (j = num_digits - 1; j >= 0; j--) {
      if (sum[j] >= 10) {
        sum[j] -= 10;
        sum[j - 1]++;
      }
    }
    for (j = 0; j < num_digits; j++) {
      printf("%d", sum[j]);
    }
    printf("\n");
  }
  return 0;
}
```