ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  sar    $0x5,%eax
  mov    %eax,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x14(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x1f,%eax
  mov    %eax,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
foo(unsigned n) {
  int i = n;
  put_unsigned(n >> 5);
  putchar('\n');
  put_unsigned(i >> 5);
  putchar('\n');
  put_unsigned(i << 5);
  putchar('\n');
  put_unsigned(n >> 31);
  putchar('\n');
  put_unsigned(i >> 31);
  putchar('\n');
  put_unsigned(i << 31);
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  sar    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shr    $0x1f,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  sar    $0x1f,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  shl    $0x1f,%ebx
  mov    %ebx,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  ret
```

assistant: ```c
foo(unsigned n) {
  int i = n;
  put_unsigned(n >> 5);
  putchar('\n');
  put_unsigned(i >> 5);
  putchar('\n');
  put_unsigned(i << 5);
  putchar('\n');
  put_unsigned(n >> 31);
  putchar('\n');
  put_unsigned(i >> 31);
  putchar('\n');
  put_unsigned(i << 31);
  putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  sar    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shr    $0x1f,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x1f,%ebx
  sar    $0x1f,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  pop    %rbx
  jmp    1060 <putchar@plt>
```

assistant: ```c
foo(unsigned n) {
  int i = n;
  put_unsigned(n >> 5);
  putchar('\n');
  put_unsigned(i >> 5);
  putchar('\n');
  put_unsigned(i << 5);
  putchar('\n');
  put_unsigned(n >> 31);
  putchar('\n');
  put_unsigned(i >> 31);
  putchar('\n');
  put_unsigned(i << 31);
  putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  shr    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  sar    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x5,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shr    $0x1f,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  shl    $0x1f,%ebx
  sar    $0x1f,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%edi
  call   <put_unsigned@plt>
  mov    $0xa,%edi
  pop    %rbx
  jmp    1060 <putchar@plt>
```

assistant: ```c
foo(unsigned n) {
  int i = n;
  put_unsigned(n >> 5);
  putchar('\n');
  put_unsigned(i >> 5);
  putchar('\n');
  put_unsigned(i << 5);
  putchar('\n');
  put_unsigned(n >> 31);
  putchar('\n');
  put_unsigned(i >> 31);
  putchar('\n');
  put_unsigned(i << 31);
  putchar('\n');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cc_user_signal_handle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigaction@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void cc_user_signal_handle() {
  struct sigaction sigact;
  sigact.sa_handler = SIG_IGN;
  sigaction(SIGPIPE, &sigact, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cc_user_signal_handle>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <sigaction@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cc_user_signal_handle() {
  struct sigaction sigact;
  sigact.sa_handler = SIG_IGN;
  sigaction(SIGPIPE, &sigact, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cc_user_signal_handle>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D16(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <sigaction@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cc_user_signal_handle() {
  struct sigaction sigact;
  sigact.sa_handler = SIG_IGN;
  sigaction(SIGPIPE, &sigact, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cc_user_signal_handle>:
  endbr64
  sub    $0x18,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D3(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <sigaction@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cc_user_signal_handle() {
  struct sigaction sigact;
  sigact.sa_handler = SIG_IGN;
  sigaction(SIGPIPE, &sigact, NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_ii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L1:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_ii(int nb) {
  int i;
  i = 0;
  while (nb) {
    nb = nb / 10;
    i++;
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_ii>:
  endbr64
  test   %edi,%edi
  je     L14
  mov    $0x0,%edx
L3:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  add    $0x1,%edx
  test   %eax,%eax
  jne    L3
L4:
  mov    %edx,%eax
  ret
L14:
  mov    %edi,%edx
  jmp    L4
```

assistant: ```c
int ft_ii(int nb) {
  int i;
  i = 0;
  while (nb) {
    nb = nb / 10;
    i++;
  }
  return (i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_ii>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L16
  nopl   0x0(%rax,%rax,1)
L11:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  jne    L11
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_ii(int nb) {
  int i;
  i = 0;
  while (nb) {
    nb = nb / 10;
    i++;
  }
  return (i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_ii>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L13
  nopl   0x0(%rax,%rax,1)
L16:
  movslq %edi,%rax
  mov    %edi,%edx
  add    $0x1,%r8d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  jne    L16
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_ii(int nb) {
  int i;
  i = 0;
  while (nb) {
    nb = nb / 10;
    i++;
  }
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<A>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x9,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x7,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0xe,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void A(uint16_t *l, uint16_t *r) {
  (*l) = ((((*l)) << 9) | (((*l)) >> (16 - (9))));
  (*l) += (*r);
  (*r) = ((((*r)) << 2) | (((*r)) >> (16 - (2))));
  (*r) ^= (*l);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<A>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%eax
  shl    $0x9,%eax
  sar    $0x7,%edx
  or     %edx,%eax
  mov    %eax,(%rdi)
  add    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    (%rsi),%edx
  lea    0x0(,%rdx,4),%eax
  sar    $0xe,%edx
  or     %edx,%eax
  mov    %eax,(%rsi)
  xor    (%rdi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void A(uint16_t *l, uint16_t *r) {
  (*l) = ((((*l)) << 9) | (((*l)) >> (16 - (9))));
  (*l) += (*r);
  (*r) = ((((*r)) << 2) | (((*r)) >> (16 - (2))));
  (*r) ^= (*l);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<A>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%eax
  sar    $0x7,%edx
  shl    $0x9,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  add    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    (%rsi),%edx
  lea    0x0(,%rdx,4),%eax
  sar    $0xe,%edx
  or     %edx,%eax
  mov    %eax,(%rsi)
  xor    (%rdi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void A(uint16_t *l, uint16_t *r) {
  (*l) = ((((*l)) << 9) | (((*l)) >> (16 - (9))));
  (*l) += (*r);
  (*r) = ((((*r)) << 2) | (((*r)) >> (16 - (2))));
  (*r) ^= (*l);
}
```
user: What is the c source code of the assembly code below?

```asm
<A>:
  endbr64
  mov    (%rdi),%edx
  mov    %edx,%eax
  sar    $0x7,%edx
  shl    $0x9,%eax
  or     %edx,%eax
  mov    %eax,(%rdi)
  add    (%rsi),%eax
  mov    %eax,(%rdi)
  mov    (%rsi),%edx
  lea    0x0(,%rdx,4),%eax
  sar    $0xe,%edx
  or     %edx,%eax
  mov    %eax,(%rsi)
  xor    (%rdi),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void A(uint16_t *l, uint16_t *r) {
  (*l) = ((((*l)) << 9) | (((*l)) >> (16 - (9))));
  (*l) += (*r);
  (*r) = ((((*r)) << 2) | (((*r)) >> (16 - (2))));
  (*r) ^= (*l);
}
```
user: What is the c source code of the assembly code below:

```asm
<raw2hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L15
L9:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  cltq
  lea    D8(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movslq %ecx,%rax
  lea    D8(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
  addq   $0x2,-0x8(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L9
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: 0123456789abcdef

assistant: ```c
void raw2hex(char *dst, const unsigned char *src, size_t len) {
  size_t i, o;
  static const char hextab[] = "0123456789abcdef";
  for (i = 0, o = 0; i < len; i++, o += 2) {
    dst[o + 0] = hextab[0xf & (src[i] >> 4)];
    dst[o + 1] = hextab[0xf & src[i]];
  }
  dst[o] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<raw2hex>:
  endbr64
  test   %rdx,%rdx
  je     L11
  mov    $0x0,%eax
  lea    D8(%rip),%r8
L5:
  movzbl (%rsi,%rax,1),%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rdi,%rax,2)
  movzbl (%rsi,%rax,1),%ecx
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L5
  lea    (%rax,%rax,1),%rdx
L11:
  movb   $0x0,(%rdi,%rdx,1)
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: 0123456789abcdef

assistant: ```c
void raw2hex(char *dst, const unsigned char *src, size_t len) {
  size_t i, o;
  static const char hextab[] = "0123456789abcdef";
  for (i = 0, o = 0; i < len; i++, o += 2) {
    dst[o + 0] = hextab[0xf & (src[i] >> 4)];
    dst[o + 1] = hextab[0xf & src[i]];
  }
  dst[o] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<raw2hex>:
  endbr64
  test   %rdx,%rdx
  je     L0
  xor    %eax,%eax
  lea    D2(%rip),%r8
  nopw   0x0(%rax,%rax,1)
L6:
  movzbl (%rsi,%rax,1),%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rdi,%rax,2)
  movzbl (%rsi,%rax,1),%ecx
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L6
  lea    (%rdi,%rdx,2),%rdi
L0:
  movb   $0x0,(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string

tool: D2: 0123456789abcdef

assistant: ```c
void raw2hex(char *dst, const unsigned char *src, size_t len) {
  size_t i, o;
  static const char hextab[] = "0123456789abcdef";
  for (i = 0, o = 0; i < len; i++, o += 2) {
    dst[o + 0] = hextab[0xf & (src[i] >> 4)];
    dst[o + 1] = hextab[0xf & src[i]];
  }
  dst[o] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<raw2hex>:
  endbr64
  test   %rdx,%rdx
  je     L11
  xor    %eax,%eax
  lea    D2(%rip),%r8
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%rsi,%rax,1),%ecx
  shr    $0x4,%cl
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,(%rdi,%rax,2)
  movzbl (%rsi,%rax,1),%ecx
  and    $0xf,%ecx
  movzbl (%r8,%rcx,1),%ecx
  mov    %cl,0x1(%rdi,%rax,2)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L14
  lea    (%rdi,%rdx,2),%rdi
L11:
  movb   $0x0,(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: 0123456789abcdef

assistant: ```c
void raw2hex(char *dst, const unsigned char *src, size_t len) {
  size_t i, o;
  static const char hextab[] = "0123456789abcdef";
  for (i = 0, o = 0; i < len; i++, o += 2) {
    dst[o + 0] = hextab[0xf & (src[i] >> 4)];
    dst[o + 1] = hextab[0xf & src[i]];
  }
  dst[o] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_assem2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <m_cvt_hex@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <m_cvt_hex@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  jmp    L9
L3:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
unsigned long long parse_assem2(char *str) {
  int highval, lowval;
  highval = m_cvt_hex(str);
  str = strchr(str, ',');
  if (str)
    lowval = m_cvt_hex(str + 1);
  else {
    return 0;
  }
  return (unsigned long long)((highval << 16) + lowval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_assem2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <m_cvt_hex@plt>
  mov    %eax,%ebp
  mov    $0x2c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    $0x0,%edx
  test   %rax,%rax
  je     L6
  lea    0x1(%rax),%rdi
  call   <m_cvt_hex@plt>
  mov    %eax,%edx
  mov    %ebp,%eax
  shl    $0x10,%eax
  add    %edx,%eax
  movslq %eax,%rdx
L6:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long parse_assem2(char *str) {
  int highval, lowval;
  highval = m_cvt_hex(str);
  str = strchr(str, ',');
  if (str)
    lowval = m_cvt_hex(str + 1);
  else {
    return 0;
  }
  return (unsigned long long)((highval << 16) + lowval);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_assem2>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <m_cvt_hex@plt>
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L3
  lea    0x1(%rax),%rdi
  call   <m_cvt_hex@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  shl    $0x10,%eax
  add    %r8d,%eax
  movslq %eax,%r8
L3:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long parse_assem2(char *str) {
  int highval, lowval;
  highval = m_cvt_hex(str);
  str = strchr(str, ',');
  if (str)
    lowval = m_cvt_hex(str + 1);
  else {
    return 0;
  }
  return (unsigned long long)((highval << 16) + lowval);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_assem2>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <m_cvt_hex@plt>
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rdi
  call   <m_cvt_hex@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  shl    $0x10,%eax
  add    %r8d,%eax
  movslq %eax,%r8
L2:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long parse_assem2(char *str) {
  int highval, lowval;
  highval = m_cvt_hex(str);
  str = strchr(str, ',');
  if (str)
    lowval = m_cvt_hex(str + 1);
  else {
    return 0;
  }
  return (unsigned long long)((highval << 16) + lowval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bytswp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bytswp(short int *ptr1, short int *ptr2) {
  char temp, *cptr1, *cptr2;
  *ptr2 = *ptr1;
  cptr1 = ptr2;
  cptr2 = cptr1 + 1;
  temp = *cptr1;
  *cptr1 = *cptr2;
  *cptr2 = temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bytswp>:
  endbr64
  movzwl (%rdi),%eax
  movzbl %ah,%edx
  mov    %dl,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void bytswp(short int *ptr1, short int *ptr2) {
  char temp, *cptr1, *cptr2;
  *ptr2 = *ptr1;
  cptr1 = ptr2;
  cptr2 = cptr1 + 1;
  temp = *cptr1;
  *cptr1 = *cptr2;
  *cptr2 = temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bytswp>:
  endbr64
  movzwl (%rdi),%eax
  mov    %ah,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void bytswp(short int *ptr1, short int *ptr2) {
  char temp, *cptr1, *cptr2;
  *ptr2 = *ptr1;
  cptr1 = ptr2;
  cptr2 = cptr1 + 1;
  temp = *cptr1;
  *cptr1 = *cptr2;
  *cptr2 = temp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bytswp>:
  endbr64
  movzwl (%rdi),%eax
  mov    %ah,(%rsi)
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void bytswp(short int *ptr1, short int *ptr2) {
  char temp, *cptr1, *cptr2;
  *ptr2 = *ptr1;
  cptr1 = ptr2;
  cptr2 = cptr1 + 1;
  temp = *cptr1;
  *cptr1 = *cptr2;
  *cptr2 = temp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<full_fread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rdi
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  mov    -0x4(%rbp),%eax
  jmp    L67
L17:
  cmpl   $0x0,-0x4(%rbp)
  jne    L55
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L9
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L55
L9:
  mov    -0x8(%rbp),%eax
  jmp    L67
L55:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L41
  mov    -0x8(%rbp),%eax
L67:
  leave
  ret
```

assistant: ```c
int full_fread(void *buf, size_t size, size_t nmemb, FILE *fp) {
  int items_read = 0;
  int this_read = 0;
  do {
    this_read = fread(buf, size, nmemb - items_read, fp);
    if (this_read < 0) {
      return this_read;
    }
    if (this_read == 0 && (feof(fp) || ferror(fp))) {
      return items_read;
    }
    items_read += this_read;
  } while (items_read < nmemb);
  return items_read;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<full_fread>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    $0x0,%ebp
  jmp    L1
L68:
  add    %ebx,%ebp
  movslq %ebp,%rax
  cmp    %r12,%rax
  jae    L0
L1:
  movslq %ebp,%rax
  mov    %r12,%rdx
  sub    %rax,%rdx
  mov    %r13,%rcx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <fread@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L70
  jne    L68
  mov    %r13,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L28
  mov    %r13,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L68
  mov    %ebp,%ebx
  jmp    L70
L0:
  mov    %ebp,%ebx
L70:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    %ebp,%ebx
  jmp    L70
```

assistant: ```c
int full_fread(void *buf, size_t size, size_t nmemb, FILE *fp) {
  int items_read = 0;
  int this_read = 0;
  do {
    this_read = fread(buf, size, nmemb - items_read, fp);
    if (this_read < 0) {
      return this_read;
    }
    if (this_read == 0 && (feof(fp) || ferror(fp))) {
      return items_read;
    }
    items_read += this_read;
  } while (items_read < nmemb);
  return items_read;
}
```