ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<printErrMsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <strerror@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: %s:%s


assistant: ```c
void printErrMsg(char *str, int err) {
  printf("%s:%s\n", str, strerror(err));
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printErrMsg>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  call   <strerror@plt>
  mov    %rax,%rdx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: %s:%s


assistant: ```c
void printErrMsg(char *str, int err) {
  printf("%s:%s\n", str, strerror(err));
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printErrMsg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <strerror@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1080 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: %s:%s


assistant: ```c
void printErrMsg(char *str, int err) {
  printf("%s:%s\n", str, strerror(err));
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printErrMsg>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <strerror@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  mov    %rax,%rdx
  call   <printf@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1080 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: %s:%s


assistant: ```c
void printErrMsg(char *str, int err) {
  printf("%s:%s\n", str, strerror(err));
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x7,%esi
  mov    $0x1,%edi
  call   <function_A@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = function_A(1, 7);
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x1,%edi
  call   <function_A@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = function_A(1, 7);
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x7,%esi
  mov    $0x1,%edi
  jmp    1050 <function_A@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = function_A(1, 7);
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x7,%esi
  mov    $0x1,%edi
  jmp    1050 <function_A@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = function_A(1, 7);
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L9
L20:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L9:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L20
  movl   $0x0,-0x18(%rbp)
  jmp    L37
L32:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L37:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L32
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D0: %d

tool: D2: address: %p, value: %d


assistant: ```c
int main() {
  int lim = 3;
  int *p = (int *)malloc(sizeof(int) * lim);
  int i;
  int d;
  for (i = 0; i < lim; i++) {
    scanf("%d", &d);
    *(p + i) = d;
  }
  for (i = 0; i < lim; i++) {
    printf("address: %p, value: %d\n", (p + i), *(p + i));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0xc(%rax),%r12
  mov    %rax,%rbp
  lea    D14(%rip),%r13
L2:
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L2
  lea    D1(%rip),%rbp
L14:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D1
data_type: string

tool: D14: %d

tool: D1: address: %p, value: %d


assistant: ```c
int main() {
  int lim = 3;
  int *p = (int *)malloc(sizeof(int) * lim);
  int i;
  int d;
  for (i = 0; i < lim; i++) {
    scanf("%d", &d);
    *(p + i) = d;
  }
  for (i = 0; i < lim; i++) {
    printf("address: %p, value: %d\n", (p + i), *(p + i));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xc,%edi
  push   %r13
  lea    D16(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0xc(%rax),%r12
  mov    %rax,%rbp
L25:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L25
  lea    D12(%rip),%rbp
L22:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L22
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D16
datatype: string
name: read_data
arguments: tag: D12
datatype: string

tool: D16: %d

tool: D12: address: %p, value: %d


assistant: ```c
int main() {
  int lim = 3;
  int *p = (int *)malloc(sizeof(int) * lim);
  int i;
  int d;
  for (i = 0; i < lim; i++) {
    scanf("%d", &d);
    *(p + i) = d;
  }
  for (i = 0; i < lim; i++) {
    printf("address: %p, value: %d\n", (p + i), *(p + i));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0xc,%edi
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    0xc(%rax),%r12
  mov    %rax,%rbp
L1:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  mov    %eax,-0x4(%rbp)
  cmp    %r12,%rbp
  jne    L1
  lea    D4(%rip),%rbp
L0:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D18: %d

tool: D4: address: %p, value: %d


assistant: ```c
int main() {
  int lim = 3;
  int *p = (int *)malloc(sizeof(int) * lim);
  int i;
  int d;
  for (i = 0; i < lim; i++) {
    scanf("%d", &d);
    *(p + i) = d;
  }
  for (i = 0; i < lim; i++) {
    printf("address: %p, value: %d\n", (p + i), *(p + i));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<I2CMasterEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <I2CMasterBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x20,%rdx
  or     $0x10,%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void I2CMasterEnable(unsigned long ulBase) {
  DEBUG_ASSERT(I2CMasterBaseValid(ulBase));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= 0x00000010;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<I2CMasterEnable>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <I2CMasterBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x20(%rbx),%rax
  or     $0x10,%rax
  mov    %rax,0x20(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void I2CMasterEnable(unsigned long ulBase) {
  DEBUG_ASSERT(I2CMasterBaseValid(ulBase));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= 0x00000010;
}
```
user: Translate the below assembly code into C programming language:

```asm
<I2CMasterEnable>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <I2CMasterBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x20(%rbx),%rax
  or     $0x10,%rax
  mov    %rax,0x20(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void I2CMasterEnable(unsigned long ulBase) {
  DEBUG_ASSERT(I2CMasterBaseValid(ulBase));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= 0x00000010;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<I2CMasterEnable>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <I2CMasterBaseValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    0x20(%rbx),%rax
  or     $0x10,%rax
  mov    %rax,0x20(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void I2CMasterEnable(unsigned long ulBase) {
  DEBUG_ASSERT(I2CMasterBaseValid(ulBase));
  (*((volatile unsigned long *)(ulBase + 0x00000020))) |= 0x00000010;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<level1_saturation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm2
  movsd  D4(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: f64

tool: D4: 0.5

assistant: ```c
double level1_saturation(double x1, double x2, double x3, double c1, double c2) {
  double T1 = x1 - x3;
  return c2 * (x2 - x3 - c1 - T1 * 0.5) * T1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<level1_saturation>:
  endbr64
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  movapd %xmm0,%xmm2
  mulsd  D8(%rip),%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: f64

tool: D8: 0.5

assistant: ```c
double level1_saturation(double x1, double x2, double x3, double c1, double c2) {
  double T1 = x1 - x3;
  return c2 * (x2 - x3 - c1 - T1 * 0.5) * T1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<level1_saturation>:
  endbr64
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  movsd  D9(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm3,%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: f64

tool: D9: 0.5

assistant: ```c
double level1_saturation(double x1, double x2, double x3, double c1, double c2) {
  double T1 = x1 - x3;
  return c2 * (x2 - x3 - c1 - T1 * 0.5) * T1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<level1_saturation>:
  endbr64
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  movsd  D4(%rip),%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm3,%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: f64

tool: D4: 0.5

assistant: ```c
double level1_saturation(double x1, double x2, double x3, double c1, double c2) {
  double T1 = x1 - x3;
  return c2 * (x2 - x3 - c1 - T1 * 0.5) * T1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <who_am_i@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void main() {
  unsigned int who_am_i();
  who_am_i();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <who_am_i@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  unsigned int who_am_i();
  who_am_i();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <who_am_i@plt>
```

assistant: ```c
void main() {
  unsigned int who_am_i();
  who_am_i();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <who_am_i@plt>
```

assistant: ```c
void main() {
  unsigned int who_am_i();
  who_am_i();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mystery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  jmp    L7
L3:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mystery>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
L7:
  leave
  ret
```

assistant: ```c
int mystery(int a, int b) {
  if (1 == b) {
    return a;
  } else {
    return a + mystery(a, b - 1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mystery>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%esi
  jne    L0
L5:
  mov    %ebx,%eax
  pop    %rbx
  ret
L0:
  sub    $0x1,%esi
  call   <mystery>
  add    %eax,%ebx
  jmp    L5
```

assistant: ```c
int mystery(int a, int b) {
  if (1 == b) {
    return a;
  } else {
    return a + mystery(a, b - 1);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystery>:
  endbr64
  cmp    $0x1,%esi
  je     L8
  sub    $0x2,%esi
  imul   %edi,%esi
  lea    (%rsi,%rdi,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %edi,%eax
  ret
```

assistant: ```c
int mystery(int a, int b) {
  if (1 == b) {
    return a;
  } else {
    return a + mystery(a, b - 1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mystery>:
  endbr64
  cmp    $0x1,%esi
  je     L2
  sub    $0x2,%esi
  imul   %edi,%esi
  lea    (%rsi,%rdi,2),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edi,%eax
  ret
```

assistant: ```c
int mystery(int a, int b) {
  if (1 == b) {
    return a;
  } else {
    return a + mystery(a, b - 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sendLA>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x503,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0xa(%rbp)
  movzbl -0x18(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <send_frame@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
sendLA(unsigned char nr, unsigned char cr) {
  char la[] = {3, 5, 0, 0};
  la[2] = nr;
  la[3] = cr;
  send_frame(la, sizeof(la));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sendLA>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x503,0x4(%rsp)
  mov    %dil,0x6(%rsp)
  mov    %sil,0x7(%rsp)
  lea    0x4(%rsp),%rdi
  mov    $0x4,%esi
  call   <send_frame@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sendLA(unsigned char nr, unsigned char cr) {
  char la[] = {3, 5, 0, 0};
  la[2] = nr;
  la[3] = cr;
  send_frame(la, sizeof(la));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sendLA>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x503,0x4(%rsp)
  mov    %dil,0x6(%rsp)
  lea    0x4(%rsp),%rdi
  mov    %sil,0x7(%rsp)
  mov    $0x4,%esi
  call   <send_frame@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sendLA(unsigned char nr, unsigned char cr) {
  char la[] = {3, 5, 0, 0};
  la[2] = nr;
  la[3] = cr;
  send_frame(la, sizeof(la));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sendLA>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x503,0x4(%rsp)
  mov    %dil,%al
  lea    0x4(%rsp),%rdi
  mov    %dl,%ah
  mov    %ax,0x6(%rsp)
  call   <send_frame@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sendLA(unsigned char nr, unsigned char cr) {
  char la[] = {3, 5, 0, 0};
  la[2] = nr;
  la[3] = cr;
  send_frame(la, sizeof(la));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cu2axLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %ecx,-0x4c(%rbp)
  movq   $0x3,-0x20(%rbp)
  movq   $0x4,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  jmp    L1
L11:
  mov    -0x28(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4c(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <cu2ax@plt>
  mov    %eax,-0x2c(%rbp)
  addq   $0x1,-0x28(%rbp)
L1:
  mov    -0x28(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jb     L11
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int cu2axLoop(double *cu, double *ax, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, custep = 3, axstep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(custep, axstep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * custep;
    iOut = i * axstep;
    trash = cu2ax(&(cu[iIn]), &(ax[iOut]), p);
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cu2axLoop>:
  endbr64
  test   %rdx,%rdx
  je     L3
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%r14d
L19:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <cu2ax@plt>
  add    $0x1,%r14
  add    $0x18,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L19
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cu2axLoop(double *cu, double *ax, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, custep = 3, axstep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(custep, axstep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * custep;
    iOut = i * axstep;
    trash = cu2ax(&(cu[iIn]), &(ax[iOut]), p);
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cu2axLoop>:
  endbr64
  test   %rdx,%rdx
  je     L3
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L16:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  call   <cu2ax@plt>
  add    $0x18,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L16
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L3:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cu2axLoop(double *cu, double *ax, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, custep = 3, axstep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(custep, axstep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * custep;
    iOut = i * axstep;
    trash = cu2ax(&(cu[iIn]), &(ax[iOut]), p);
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cu2axLoop>:
  endbr64
  test   %rdx,%rdx
  je     L12
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
L13:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  add    $0x1,%r14
  call   <cu2ax@plt>
  add    $0x18,%rbp
  add    $0x20,%rbx
  cmp    %r14,%r12
  jne    L13
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cu2axLoop(double *cu, double *ax, unsigned long long n, int p) {
  int trash;
  unsigned long long i, iIn, iOut, custep = 3, axstep = 4;
#pragma omp parallel for default(shared) private(i, iIn, iOut, trash) firstprivate(custep, axstep) schedule(static)
  for (i = 0; i < n; i++) {
    iIn = i * custep;
    iOut = i * axstep;
    trash = cu2ax(&(cu[iIn]), &(ax[iOut]), p);
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<af2e>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xc,%edi
  call   <my_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L2
L13:
  nop
L2:
  leave
  ret
```

assistant: ```c
void af2e() {
  int *p = my_malloc(12);
  if (!p)
    return;
  free(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<af2e>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edi
  call   <my_malloc@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rdi
  call   <free@plt>
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void af2e() {
  int *p = my_malloc(12);
  if (!p)
    return;
  free(p);
}
```