ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<setreuid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L7
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <setuid@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L27
L7:
  cmpl   $0xffffffff,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <seteuid@plt>
  cmp    $0xffffffff,%eax
  jne    L27
  mov    $0xffffffff,%eax
  jmp    L27
L27:
  leave
  ret
```

assistant: ```c
int setreuid(int ruid, int euid) {
  if (ruid != -1)
    if (setuid(ruid) == -1)
      return (-1);
  if (euid != -1)
    if (seteuid(euid) == -1)
      return (-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setreuid>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  cmp    $0xffffffff,%edi
  jne    L8
L30:
  cmp    $0xffffffff,%ebx
  jne    L34
L35:
  pop    %rbx
  ret
L8:
  call   <setuid@plt>
  cmp    $0xffffffff,%eax
  jne    L30
L1:
  mov    $0xffffffff,%eax
  jmp    L35
L34:
  mov    %ebx,%edi
  call   <seteuid@plt>
  cmp    $0xffffffff,%eax
  jne    L35
  jmp    L1
```

assistant: ```c
int setreuid(int ruid, int euid) {
  if (ruid != -1)
    if (setuid(ruid) == -1)
      return (-1);
  if (euid != -1)
    if (seteuid(euid) == -1)
      return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setreuid>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  cmp    $0xffffffff,%edi
  jne    L26
L5:
  cmp    $0xffffffff,%ebp
  jne    L4
L1:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%edi
  call   <seteuid@plt>
  cmp    $0xffffffff,%eax
  jne    L1
  mov    $0xffffffff,%eax
L41:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  call   <setuid@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  mov    $0xffffffff,%eax
  jmp    L41
```

assistant: ```c
int setreuid(int ruid, int euid) {
  if (ruid != -1)
    if (setuid(ruid) == -1)
      return (-1);
  if (euid != -1)
    if (seteuid(euid) == -1)
      return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setreuid>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  cmp    $0xffffffff,%edi
  jne    L3
L35:
  cmp    $0xffffffff,%ebp
  jne    L25
L46:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %ebp,%edi
  call   <seteuid@plt>
  cmp    $0xffffffff,%eax
  jne    L46
  mov    $0xffffffff,%eax
L42:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  call   <setuid@plt>
  cmp    $0xffffffff,%eax
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L42
```

assistant: ```c
int setreuid(int ruid, int euid) {
  if (ruid != -1)
    if (setuid(ruid) == -1)
      return (-1);
  if (euid != -1)
    if (seteuid(euid) == -1)
      return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<block_iter_move_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L0
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <block_iter_eat_line@plt>
L0:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void block_iter_move_down(struct block_iter *bi, int count) {
  while (count--)
    block_iter_eat_line(bi);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<block_iter_move_down>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  test   %esi,%esi
  je     L17
L2:
  mov    %rbp,%rdi
  call   <block_iter_eat_line@plt>
  sub    $0x1,%ebx
  jne    L2
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void block_iter_move_down(struct block_iter *bi, int count) {
  while (count--)
    block_iter_eat_line(bi);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<block_iter_move_down>:
  endbr64
  test   %esi,%esi
  je     L8
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rdi
  call   <block_iter_eat_line@plt>
  sub    $0x1,%ebx
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void block_iter_move_down(struct block_iter *bi, int count) {
  while (count--)
    block_iter_eat_line(bi);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<block_iter_move_down>:
  endbr64
  test   %esi,%esi
  je     L6
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  call   <block_iter_eat_line@plt>
  sub    $0x1,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
void block_iter_move_down(struct block_iter *bi, int count) {
  while (count--)
    block_iter_eat_line(bi);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xa,%edi
  call   <indexArray@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L2:
  cmpl   $0x9,-0xc(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *ip;
  ip = indexArray(10);
  for (int i = 0; i < 10; i++) {
    printf("%d ", *(ip + i));
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xa,%edi
  call   <indexArray@plt>
  mov    %rax,%rbx
  lea    0x28(%rax),%r12
  lea    D9(%rip),%rbp
L3:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D9: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *ip;
  ip = indexArray(10);
  for (int i = 0; i < 10; i++) {
    printf("%d ", *(ip + i));
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  call   <indexArray@plt>
  mov    %rax,%rbx
  lea    0x28(%rax),%r12
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D1
datatype: string

tool: D1: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *ip;
  ip = indexArray(10);
  for (int i = 0; i < 10; i++) {
    printf("%d ", *(ip + i));
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  call   <indexArray@plt>
  mov    %rax,%rbx
  lea    0x28(%rax),%r12
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int *ip;
  ip = indexArray(10);
  for (int i = 0; i < 10; i++) {
    printf("%d ", *(ip + i));
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L18
L12:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <stop_at_ten@plt>
L18:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L12
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string

tool: D2: %d

assistant: ```c
int main(void) {
  int i;
  while (scanf("%d", &i) != 0)
    stop_at_ten(i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rbx
  jmp    L0
L20:
  mov    0x4(%rsp),%edi
  call   <stop_at_ten@plt>
L0:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L20
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: %d

assistant: ```c
int main(void) {
  int i;
  while (scanf("%d", &i) != 0)
    stop_at_ten(i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x4(%rsp),%edi
  call   <stop_at_ten@plt>
L29:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: %d

assistant: ```c
int main(void) {
  int i;
  while (scanf("%d", &i) != 0)
    stop_at_ten(i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D7(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L21:
  mov    0x4(%rsp),%edi
  call   <stop_at_ten@plt>
L18:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L21
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: %d

assistant: ```c
int main(void) {
  int i;
  while (scanf("%d", &i) != 0)
    stop_at_ten(i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x342a332b3231,%rax
  mov    $0x0,%edx
  mov    %rax,-0x90(%rbp)
  mov    %rdx,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movsd  D13(%rip),%xmm0
  movsd  %xmm0,-0xa0(%rbp)
  lea    -0x90(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <calc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  subsd  -0xa0(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  jle    L15
  mov    $0xffffffff,%eax
  jmp    L43
L15:
  movq   $0x322d2a33,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x98(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <replace_minus@plt>
  lea    -0x50(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <calc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  subsd  -0x98(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  jle    L25
  mov    $0xffffffff,%eax
  jmp    L43
L25:
  mov    $0x0,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: f64
name: disassemble_data
arguments: label: D17
type_guessed: byte[8]

tool: D13: 24

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0xc0]}

assistant: ```c
int main(void) {
  char formula1[64] = "12+3*4";
  double result1 = 24;
  if (1e-10 < fabs(calc(formula1, 0) - result1)) {
    return (-1);
  }
  char formula2[64] = "3*-2";
  double result2 = -6;
  replace_minus(formula2);
  if (1e-10 < fabs(calc(formula2, 0) - result2)) {
    return (-1);
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movabs $0x342a332b3231,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <calc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  subsd  D2(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  jg     L20
  movq   $0x322d2a33,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rdi
  call   <replace_minus@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <calc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D6(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  neg    %eax
L21:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x90,%rsp
  pop    %rbx
  ret
L20:
  mov    $0xffffffff,%eax
  jmp    L21
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: f64
name: disassemble_data
arguments: data_tag: D6
data_type: f64

tool: D2: 24

tool: D6: 6

assistant: ```c
int main(void) {
  char formula1[64] = "12+3*4";
  double result1 = 24;
  if (1e-10 < fabs(calc(formula1, 0) - result1)) {
    return (-1);
  }
  char formula2[64] = "3*-2";
  double result2 = -6;
  replace_minus(formula2);
  if (1e-10 < fabs(calc(formula2, 0) - result2)) {
    return (-1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  xor    %esi,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x342a332b3231,%rax
  mov    %rsp,%rdi
  mov    %rdx,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  mov    %rax,(%rsp)
  call   <calc@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  D13(%rip),%xmm1
  cvttsd2si %xmm1,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  jg     L12
  lea    0x40(%rsp),%rbp
  pxor   %xmm0,%xmm0
  movq   $0x322d2a33,0x40(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movq   $0x0,0x48(%rsp)
  call   <replace_minus@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <calc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  neg    %eax
L4:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x90,%rsp
  pop    %rbp
  ret
L12:
  or     $0xffffffff,%eax
  jmp    L4
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: f64
name: extract_symbolic_data
arguments: tag: D19
type: f64

tool: D13: 24

tool: D19: 6

assistant: ```c
int main(void) {
  char formula1[64] = "12+3*4";
  double result1 = 24;
  if (1e-10 < fabs(calc(formula1, 0) - result1)) {
    return (-1);
  }
  char formula2[64] = "3*-2";
  double result2 = -6;
  replace_minus(formula2);
  if (1e-10 < fabs(calc(formula2, 0) - result2)) {
    return (-1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  xor    %esi,%esi
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x342a332b3231,%rax
  mov    %rsp,%rdi
  mov    %rdx,0x8(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  mov    %rax,(%rsp)
  call   <calc@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  subsd  D4(%rip),%xmm1
  cvttsd2si %xmm1,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  jg     L2
  lea    0x40(%rsp),%rbp
  pxor   %xmm0,%xmm0
  movq   $0x322d2a33,0x40(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movq   $0x0,0x48(%rsp)
  call   <replace_minus@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <calc@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%rdi
  call   <fabs@plt>
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  neg    %eax
L21:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x90,%rsp
  pop    %rbp
  ret
L2:
  or     $0xffffffff,%eax
  jmp    L21
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: f64
name: parse_data
arguments: label: D13
type: f64

tool: D4: 24

tool: D13: 6

assistant: ```c
int main(void) {
  char formula1[64] = "12+3*4";
  double result1 = 24;
  if (1e-10 < fabs(calc(formula1, 0) - result1)) {
    return (-1);
  }
  char formula2[64] = "3*-2";
  double result2 = -6;
  replace_minus(formula2);
  if (1e-10 < fabs(calc(formula2, 0) - result2)) {
    return (-1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<scan_pm_wlan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <exists@plt>
  test   %rax,%rax
  je     L19
  lea    D3(%rip),%rax
  jmp    L13
L19:
  mov    $0x0,%eax
L13:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: /sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0

assistant: ```c
const char *scan_pm_wlan() {
  if (exists("/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0"))
    return "/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0";
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<scan_pm_wlan>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <exists@plt>
  test   %rax,%rax
  lea    D10(%rip),%rax
  mov    $0x0,%edx
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
data_type: string

tool: D10: /sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0

assistant: ```c
const char *scan_pm_wlan() {
  if (exists("/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0"))
    return "/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0";
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scan_pm_wlan>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <exists@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: /sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0

assistant: ```c
const char *scan_pm_wlan() {
  if (exists("/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0"))
    return "/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0";
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<scan_pm_wlan>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <exists@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: /sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0

assistant: ```c
const char *scan_pm_wlan() {
  if (exists("/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0"))
    return "/sys/bus/platform/drivers/gta02-pm-wlan/gta02-pm-wlan.0";
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<planeBoxOverlap>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  pxor   %xmm3,%xmm3
  jmp    L36
L33:
  movss  (%rdx,%rax,1),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  xorps  D24(%rip),%xmm0
  subss  %xmm2,%xmm0
L59:
  movss  %xmm1,(%rsp,%rax,1)
  movss  %xmm0,0xc(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0xc,%rax
  je     L6
L36:
  movss  (%rsi,%rax,1),%xmm2
  movss  (%rcx,%rax,1),%xmm0
  comiss %xmm3,%xmm0
  jbe    L33
  movss  (%rdx,%rax,1),%xmm0
  movaps %xmm0,%xmm1
  xorps  D24(%rip),%xmm1
  subss  %xmm2,%xmm1
  subss  %xmm2,%xmm0
  jmp    L59
L6:
  movss  (%rcx),%xmm0
  movss  0x4(%rcx),%xmm3
  movss  0x8(%rcx),%xmm2
  movaps %xmm0,%xmm1
  mulss  (%rsp),%xmm1
  movaps %xmm3,%xmm4
  mulss  0x4(%rsp),%xmm4
  addss  %xmm4,%xmm1
  movaps %xmm2,%xmm4
  mulss  0x8(%rsp),%xmm4
  addss  %xmm4,%xmm1
  mov    $0x0,%eax
  comiss D19(%rip),%xmm1
  ja     L37
  mulss  0xc(%rsp),%xmm0
  mulss  0x10(%rsp),%xmm3
  addss  %xmm3,%xmm0
  mulss  0x14(%rsp),%xmm2
  addss  %xmm2,%xmm0
  comiss D19(%rip),%xmm0
  setae  %al
  movzbl %al,%eax
L37:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x28,%rsp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D24
data_type: byte[16]
name: read_data
arguments: data_label: D19
data_type: byte[4]

tool: {"D24": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D19": [0x00,0x00,0x00,0x00]}

assistant: ```c
int planeBoxOverlap(float normal[3], float vert[3], float maxbox[3]) {
  int q;
  float vmin[3], vmax[3], v;
  for (q = 0; q <= 2; q++) {
    v = vert[q];
    if (normal[q] > 0.0f) {
      vmin[q] = -maxbox[q] - v;
      vmax[q] = maxbox[q] - v;
    } else {
      vmin[q] = maxbox[q] - v;
      vmax[q] = -maxbox[q] - v;
    }
  }
  if ((normal[0] * vmin[0] + normal[1] * vmin[1] + normal[2] * vmin[2]) > 0.0f)
    return 0;
  if ((normal[0] * vmax[0] + normal[1] * vmax[1] + normal[2] * vmax[2]) >= 0.0f)
    return 1;
  return 0;
}
```