user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D73(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  -0x20(%rbp),%xmm0
  movss  %xmm0,-0x24(%rbp)
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x24(%rbp),%xmm1
  movss  -0x20(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x24(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L70
  movss  -0x24(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
  jmp    L53
L70:
  movss  -0x20(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x1c(%rbp)
L53:
  pxor   %xmm3,%xmm3
  cvtss2sd -0x1c(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x24(%rbp),%xmm1
  movss  -0x20(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x24(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L28
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  je     L30
L28:
  movss  -0x20(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L99
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jne    L99
L30:
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L35
L99:
  movss  -0x24(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L71
  movss  -0x24(%rbp),%xmm0
  movss  -0x20(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm5,%xmm5
  cvtss2sd -0x14(%rbp),%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L35
L71:
  movss  -0x20(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm6,%xmm6
  cvtss2sd -0x14(%rbp),%xmm6
  movq   %xmm6,%rax
  movq   %rax,%xmm0
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L35:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L92
  call   <__stack_chk_fail@plt>
L92:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D73
type_infered: byte[4]
name: retrieve_data
arguments: tag: D60
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string
name: retrieve_data
arguments: tag: D33
type_infered: string
name: retrieve_data
arguments: tag: D89
type_infered: string
name: retrieve_data
arguments: tag: D25
type_infered: string
name: retrieve_data
arguments: tag: D9
type_infered: string
name: retrieve_data
arguments: tag: D39
type_infered: string
name: retrieve_data
arguments: tag: D85
type_infered: string

tool: {"D73": [0x5c,0xff,0x79,0xc4]}

tool: D60: Please provide a number for the first float: 

tool: D11:  %f

tool: D33: Please provide a number for the second float: 

tool: D89: The number for the sum of the two floats is %.2f



tool: D25: The number for the difference of the two float is %.2f



tool: D9: The number for the product of the two float is %.2f



tool: D39: 
You cannot any number divide by zero because it produces a non-real result. Any zero dived by any integer is equal to zero.


tool: D85: The number for the quotient of the two float is %.2f



assistant: ```c
int main() {
  float a1, a2, intSum, intDiff, intProd, intQuot, intMod;
  a1 = a2 = intSum = intDiff = intProd = intQuot = intMod = -999.99;
  printf("Please provide a number for the first float: \n");
  scanf(" %f", &a1);
  printf("Please provide a number for the second float: \n");
  scanf(" %f", &a2);
  intSum = a1 + a2;
  printf("The number for the sum of the two floats is %.2f\n\n", intSum);
  if (a1 > a2) {
    intDiff = a1 - a2;
  } else {
    intDiff = a2 - a1;
  }
  printf("The number for the difference of the two float is %.2f\n\n", intDiff);
  intProd = a1 * a2;
  printf("The number for the product of the two float is %.2f\n\n", intProd);
  if (a1 == 0 || a2 == 0) {
    printf("\nYou cannot any number divide by zero because it produces a non-real result. Any zero dived by any integer is equal to zero.\n\n");
  } else if (a1 > a2) {
    intQuot = a1 / a2;
    printf("The number for the quotient of the two float is %.2f\n\n", intQuot);
  } else {
    intQuot = a2 / a1;
    printf("The number for the quotient of the two float is %.2f\n\n", intQuot);
  }
  return 0;
}
```