user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L93:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L93
  sub    $0xaa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61a98(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L101
  lea    0x8(%rsp),%r14
  lea    D18(%rip),%r12
  lea    D37(%rip),%r15
  jmp    L97
L3:
  lea    0x10(%rsp),%rdi
  call   <maxsubarray@plt>
  mov    %eax,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L98
  lea    -0x1(%rax),%eax
  lea    (%rbx,%rax,4),%rcx
  mov    $0x0,%esi
L142:
  mov    0x0(%r13),%eax
  lea    (%rsi,%rax,1),%edx
  test   %eax,%eax
  cmovg  %edx,%esi
  add    $0x4,%r13
  cmp    %rcx,%r13
  jne    L142
L125:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
L124:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L101
L97:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  test   %esi,%esi
  jle    L85
  lea    0x10(%rsp),%r13
  mov    %r13,%rbp
  mov    $0x0,%ebx
L78:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x8(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L78
  test   %esi,%esi
  jle    L85
  lea    0x4(%r13),%rbx
  lea    -0x1(%rsi),%eax
  lea    (%rbx,%rax,4),%rcx
  mov    %r13,%rax
  mov    $0x0,%edx
L165:
  cmpl   $0x80000000,(%rax)
  sbb    $0xffffffff,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L165
  cmp    %edx,%esi
  jg     L3
  jne    L124
  mov    0x10(%rsp),%edx
L159:
  lea    0x10(%rsp),%rax
  lea    -0x1(%rsi),%ecx
  lea    0x14(%rsp,%rcx,4),%rsi
L143:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L143
L164:
  mov    %edx,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L124
L98:
  mov    $0x0,%esi
  jmp    L125
L101:
  mov    0x61a98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L161
  mov    $0x0,%eax
  add    $0x61aa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L85:
  test   %esi,%esi
  jne    L124
  mov    0x10(%rsp),%edx
  jle    L164
  jmp    L159
L161:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
data_type: string
name: disassemble_data
arguments: data_label: D37
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D18: %d

tool: D37: %d 

tool: D0: %d %d


assistant: ```c
int main() {
  int i, j, k, n, t, sum, sum1, count = 0, max;
  int arr[100000];
  scanf("%d", &t);
  while (t--) {
    count = 0;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
      scanf("%d", &arr[i]);
    for (i = 0; i < n; i++) {
      if (arr[i] < 0)
        count++;
    }
    if (count < n) {
      sum1 = maxsubarray(arr, n);
      printf("%d ", sum1);
      sum = 0;
      for (i = 0; i < n; i++) {
        if (arr[i] > 0)
          sum = sum + arr[i];
      }
      printf("%d", sum);
      printf("\n");
    } else if (count == n) {
      max = arr[0];
      for (i = 0; i < n; i++) {
        if (max < arr[i])
          max = arr[i];
      }
      printf("%d %d\n", max, max);
    }
  }
  return 0;
}
```