user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L62
L80:
  movl   $0x0,-0x2c(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x30(%rbp)
  jmp    L86
L23:
  mov    -0x30(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x24(%rbp)
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x30(%rbp)
  addl   $0x30,-0x24(%rbp)
  cmpl   $0x30,-0x24(%rbp)
  je     L86
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x2c(%rbp)
L86:
  cmpl   $0x0,-0x30(%rbp)
  jne    L23
  mov    -0x2c(%rbp),%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  movb   $0x0,-0x14(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  subl   $0x1,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L17
L65:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x28(%rbp),%eax
  cltq
  mov    %dl,-0x14(%rbp,%rax,1)
  subl   $0x1,-0x2c(%rbp)
  addl   $0x1,-0x28(%rbp)
L17:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L65
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x34(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L62:
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  je     L35
  mov    -0x38(%rbp),%eax
  test   %eax,%eax
  jne    L80
L35:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D2
type: string

tool: D19: %d%d

tool: D2: %s


assistant: ```c
int main() {
  int A, B, Result, Div, Cont, Mod, Cont2;
  char ForaZero[12], SemZer[12];
  scanf("%d%d", &A, &B);
  while (B != 0 && A != 0) {
    Cont = 0;
    Result = A + B;
    while (Result != 0) {
      Mod = Result % 10;
      Result = Result / 10;
      Mod = Mod + 48;
      if (Mod != 48) {
        ForaZero[Cont] = Mod;
        Cont++;
      }
    }
    ForaZero[Cont] = '\0';
    Cont = strlen(ForaZero);
    SemZer[Cont] = '\0';
    Mod = Cont;
    Cont = Cont - 1;
    for (Cont2 = 0; Cont2 < Mod; Cont2++) {
      SemZer[Cont2] = ForaZero[Cont];
      Cont--;
    }
    printf("%s\n", SemZer);
    scanf("%d%d", &A, &B);
  }
  return 0;
}
```