ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  lea    D4(%rip),%rdi
  lea    D34(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D41(%rip),%rbp
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x20(%rsp),%r13
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r14,%rdi
  lea    0x40(%rsp),%r14
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmpi@plt>
  test   %rax,%rax
  jne    L37
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <strcmpi@plt>
  test   %rax,%rax
  je     L22
L37:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L24:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcmpi@plt>
  test   %rax,%rax
  jne    L37
  lea    D43(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L24
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D34
type_guessed: string
name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D43
type_guessed: string

tool: D4: Please enter a string that is less than 20 characters: 

tool: D34: Please enter another string that is less than 20 characters: 

tool: D41: %s

tool: D14: One, Two, or All of the string(s) you entered are not equal!


tool: D43: All three strings you entered are equal!!


assistant: ```c
int main(void) {
  char stringOne[21], stringTwo[21], stringThree[21];
  printf("Please enter a string that is less than 20 characters: ");
  scanf("%s", stringOne);
  printf("Please enter another string that is less than 20 characters: ");
  scanf("%s", stringTwo);
  printf("Please enter another string that is less than 20 characters: ");
  scanf("%s", stringThree);
  if ((strcmpi(stringOne, stringTwo) != 0) || (strcmpi(stringOne, stringThree) != 0) || (strcmpi(stringTwo, stringThree) != 0)) {
    printf("One, Two, or All of the string(s) you entered are not equal!\n");
    return 1;
  }
  printf("All three strings you entered are equal!!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<transfer_RGB888_to_RGBA16161616>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0xc,%rax
  movl   $0xffff,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_RGB888_to_RGBA16161616(uint16_t *(*output), unsigned char *input) {
  (*output)[0] = (input[0] << 8) | input[0];
  (*output)[1] = (input[1] << 8) | input[1];
  (*output)[2] = (input[2] << 8) | input[2];
  (*output)[3] = 0xffff;
  (*output) += 4;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<transfer_RGB888_to_RGBA16161616>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rsi),%ecx
  mov    (%rdi),%rdi
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,(%rdi)
  movzbl 0x1(%rsi),%ecx
  mov    (%rax),%rdi
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,0x4(%rdi)
  movzbl 0x2(%rsi),%ecx
  mov    (%rax),%rsi
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,0x8(%rsi)
  mov    (%rax),%rdx
  movl   $0xffff,0xc(%rdx)
  addq   $0x10,(%rax)
  ret
```

assistant: ```c
void transfer_RGB888_to_RGBA16161616(uint16_t *(*output), unsigned char *input) {
  (*output)[0] = (input[0] << 8) | input[0];
  (*output)[1] = (input[1] << 8) | input[1];
  (*output)[2] = (input[2] << 8) | input[2];
  (*output)[3] = 0xffff;
  (*output) += 4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<transfer_RGB888_to_RGBA16161616>:
  endbr64
  movzbl (%rsi),%ecx
  mov    (%rdi),%rax
  mov    %ecx,%edx
  add    $0x10,%rax
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,-0x10(%rax)
  movzbl 0x1(%rsi),%ecx
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,-0xc(%rax)
  movzbl 0x2(%rsi),%ecx
  movl   $0xffff,-0x4(%rax)
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,-0x8(%rax)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void transfer_RGB888_to_RGBA16161616(uint16_t *(*output), unsigned char *input) {
  (*output)[0] = (input[0] << 8) | input[0];
  (*output)[1] = (input[1] << 8) | input[1];
  (*output)[2] = (input[2] << 8) | input[2];
  (*output)[3] = 0xffff;
  (*output) += 4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transfer_RGB888_to_RGBA16161616>:
  endbr64
  movzbl (%rsi),%ecx
  mov    (%rdi),%rax
  mov    %ecx,%edx
  add    $0x10,%rax
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,-0x10(%rax)
  movzbl 0x1(%rsi),%ecx
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,-0xc(%rax)
  movzbl 0x2(%rsi),%ecx
  movl   $0xffff,-0x4(%rax)
  mov    %ecx,%edx
  shl    $0x8,%edx
  or     %ecx,%edx
  mov    %edx,-0x8(%rax)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void transfer_RGB888_to_RGBA16161616(uint16_t *(*output), unsigned char *input) {
  (*output)[0] = (input[0] << 8) | input[0];
  (*output)[1] = (input[1] << 8) | input[1];
  (*output)[2] = (input[2] << 8) | input[2];
  (*output)[3] = 0xffff;
  (*output) += 4;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <facttail@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: result is %d


assistant: ```c
int main() {
  int n = 4;
  int a = 1;
  printf("result is %d\n", facttail(n, a));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <facttail@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: result is %d


assistant: ```c
int main() {
  int n = 4;
  int a = 1;
  printf("result is %d\n", facttail(n, a));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <facttail@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: result is %d


assistant: ```c
int main() {
  int n = 4;
  int a = 1;
  printf("result is %d\n", facttail(n, a));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <facttail@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: result is %d


assistant: ```c
int main() {
  int n = 4;
  int a = 1;
  printf("result is %d\n", facttail(n, a));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cat_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L29:
  lea    -0x110(%rbp),%rcx
  mov    -0x124(%rbp),%eax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0x0,-0x114(%rbp)
  jle    L6
  mov    -0x114(%rbp),%edx
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0x0,-0x114(%rbp)
  jle    L30
  jmp    L29
L6:
  nop
  jmp    L2
L30:
  nop
L2:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
void cat_fd(int fd) {
  char buffer[0x100];
  int r;
  while (1) {
    r = read(fd, buffer, sizeof buffer);
    if (r <= 0)
      break;
    r = write(1, buffer, r);
    if (r <= 0)
      break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cat_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
L7:
  mov    $0x100,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jle    L4
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L7
L4:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cat_fd(int fd) {
  char buffer[0x100];
  int r;
  while (1) {
    r = read(fd, buffer, sizeof buffer);
    if (r <= 0)
      break;
    r = write(1, buffer, r);
    if (r <= 0)
      break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cat_fd>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L19
L39:
  mov    $0x100,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L0
L19:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cat_fd(int fd) {
  char buffer[0x100];
  int r;
  while (1) {
    r = read(fd, buffer, sizeof buffer);
    if (r <= 0)
      break;
    r = write(1, buffer, r);
    if (r <= 0)
      break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cat_fd>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L35
L23:
  mov    $0x100,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jg     L19
L35:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void cat_fd(int fd) {
  char buffer[0x100];
  int r;
  while (1) {
    r = read(fd, buffer, sizeof buffer);
    if (r <= 0)
      break;
    r = write(1, buffer, r);
    if (r <= 0)
      break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<MinHeapCreat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  jmp    L14
L7:
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <MinHeapify@plt>
  subl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void MinHeapCreat(uint32_t *array, uint32_t heapSize) {
  int i = 0;
  for (i = heapSize / 2; i >= 0; i--) {
    MinHeapify(array, heapSize, i);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MinHeapCreat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0xffffffff,%esi
  jl     L17
L2:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <MinHeapify@plt>
  sub    $0x1,%ebx
  jns    L2
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void MinHeapCreat(uint32_t *array, uint32_t heapSize) {
  int i = 0;
  for (i = heapSize / 2; i >= 0; i--) {
    MinHeapify(array, heapSize, i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<MinHeapCreat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0xffffffff,%esi
  jl     L10
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <MinHeapify@plt>
  sub    $0x1,%ebx
  jae    L3
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void MinHeapCreat(uint32_t *array, uint32_t heapSize) {
  int i = 0;
  for (i = heapSize / 2; i >= 0; i--) {
    MinHeapify(array, heapSize, i);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<MinHeapCreat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0xffffffff,%esi
  jl     L4
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <MinHeapify@plt>
  sub    $0x1,%ebx
  jae    L6
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void MinHeapCreat(uint32_t *array, uint32_t heapSize) {
  int i = 0;
  for (i = heapSize / 2; i >= 0; i--) {
    MinHeapify(array, heapSize, i);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setRates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D15(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
datatype: f64
name: read_data
arguments: data_label: D17
datatype: f64

tool: D15: 0.5

tool: D17: 1

assistant: ```c
void setRates(double *r, int rates) {
  int i;
  for (i = 0; i < rates - 1; i++)
    r[i] = 0.5;
  r[rates - 1] = 1.0;
}
```
user: What is the c source code of the assembly code below:

```asm
<setRates>:
  endbr64
  cmp    $0x1,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  movsd  D4(%rip),%xmm0
L1:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L1
L4:
  movslq %esi,%rsi
  mov    D18(%rip),%rax
  mov    %rax,-0x8(%rdi,%rsi,8)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: f64
name: retrieve_data
arguments: data_label: D18
data_type: f64

tool: D4: 0.5

tool: D18: 1

assistant: ```c
void setRates(double *r, int rates) {
  int i;
  for (i = 0; i < rates - 1; i++)
    r[i] = 0.5;
  r[rates - 1] = 1.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setRates>:
  endbr64
  cmp    $0x1,%esi
  jle    L7
  lea    -0x2(%rsi),%edx
  movsd  D11(%rip),%xmm0
  mov    %rdi,%rax
  lea    0x8(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L19:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
L7:
  mov    D2(%rip),%rax
  movslq %esi,%rsi
  mov    %rax,-0x8(%rdi,%rsi,8)
  ret
```

tool_calls: name: read_data
arguments: tag: D11
datatype: f64
name: read_data
arguments: tag: D2
datatype: f64

tool: D11: 0.5

tool: D2: 1

assistant: ```c
void setRates(double *r, int rates) {
  int i;
  for (i = 0; i < rates - 1; i++)
    r[i] = 0.5;
  r[rates - 1] = 1.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setRates>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  lea    -0x1(%rsi),%ecx
  cmp    $0x2,%esi
  je     L47
  mov    %ecx,%edx
  movapd D12(%rip),%xmm0
  mov    %rdi,%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L3:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L3
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L0
L49:
  mov    D12(%rip),%rcx
  cltq
  mov    %rcx,(%rdi,%rax,8)
L0:
  mov    D5(%rip),%rax
  movslq %esi,%rsi
  mov    %rax,-0x8(%rdi,%rsi,8)
  ret
L47:
  xor    %eax,%eax
  jmp    L49
```

tool_calls: name: unpack_data
arguments: data_tag: D12
data_type: f64[2]
name: unpack_data
arguments: data_tag: D5
data_type: f64

tool: {"D12": [0.5,0.5]}

tool: D5: 1

assistant: ```c
void setRates(double *r, int rates) {
  int i;
  for (i = 0; i < rates - 1; i++)
    r[i] = 0.5;
  r[rates - 1] = 1.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cli_file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L46
  mov    $0x0,%eax
  jmp    L32
L46:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  jmp    L32
L10:
  mov    $0x1,%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
int cli_file_exists(const char *fpath) {
  struct stat st;
  if (stat(fpath, &st) == -1)
    return (0);
  if (!S_ISREG(st.st_mode))
    return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cli_file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L1
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cli_file_exists(const char *fpath) {
  struct stat st;
  if (stat(fpath, &st) == -1)
    return (0);
  if (!S_ISREG(st.st_mode))
    return (0);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cli_file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L7
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cli_file_exists(const char *fpath) {
  struct stat st;
  if (stat(fpath, &st) == -1)
    return (0);
  if (!S_ISREG(st.st_mode))
    return (0);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cli_file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L11
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cli_file_exists(const char *fpath) {
  struct stat st;
  if (stat(fpath, &st) == -1)
    return (0);
  if (!S_ISREG(st.st_mode))
    return (0);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <err@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: Can't dup %s

assistant: ```c
char *xstrdup(char *string) {
  char *dup = strdup(string);
  if (dup == NULL)
    err(1, "Can't dup %s", string);
  return dup;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<xstrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %rbp,%rdx
  lea    D4(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: Can't dup %s

assistant: ```c
char *xstrdup(char *string) {
  char *dup = strdup(string);
  if (dup == NULL)
    err(1, "Can't dup %s", string);
  return dup;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xstrdup>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
L14:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %r13,%rdx
  lea    D5(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Can't dup %s

assistant: ```c
char *xstrdup(char *string) {
  char *dup = strdup(string);
  if (dup == NULL)
    err(1, "Can't dup %s", string);
  return dup;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xstrdup>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
L17:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L6:
  mov    %r13,%rdx
  lea    D2(%rip),%rsi
  mov    $0x1,%edi
  call   <err@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type: string

tool: D2: Can't dup %s

assistant: ```c
char *xstrdup(char *string) {
  char *dup = strdup(string);
  if (dup == NULL)
    err(1, "Can't dup %s", string);
  return dup;
}
```