ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D61(%rip),%rdi
  call   <printf@plt>
  lea    D125(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D119(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D111(%rip),%rdi
  call   <printf@plt>
  lea    D88(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D61
type_guessed: string
name: unpack_data
arguments: data_tag: D125
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D33
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D119
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D84
type_guessed: string
name: unpack_data
arguments: data_tag: D54
type_guessed: string
name: unpack_data
arguments: data_tag: D41
type_guessed: string
name: unpack_data
arguments: data_tag: D111
type_guessed: string
name: unpack_data
arguments: data_tag: D88
type_guessed: string

tool: D61: 

Usage: 
	rtw_simple_config 	-i<ifname> -c<wpa_cfgfile> -n<dev_name> -p <pincode> -t <timeout>
				-m <phone_mac> [-dD] [-v]

tool: D125: 

OPTIONS:
	

tool: D23: -i = interface name
	

tool: D15: -c = the path of wpa_supplicant config file
	

tool: D33: -p = pincode
	

tool: D13: -d = enable debug message, -D = more message.
	

tool: D119: -n = device name
	

tool: D1: -t = timeout (seconds)
	

tool: D84: -m = filtering MAC, only accept the configuration frame which's from this MAC address
	

tool: D54: -v = version	



tool: D41: example:
	

tool: D111: rtw_simple_config -i wlan0 -c ./wpa_conf -D
	

tool: D88: rtw_simple_config -i wlan0 -c ./wpa_conf -p 14825903 -t 120 -n RTKSC_SAMPLE -d



assistant: ```c
void print_usage(void) {
  printf("\n\nUsage: \n\trtw_simple_config \t-i<ifname> -c<wpa_cfgfile> -n<dev_name> -p <pincode> -t <timeout>\n\t\t\t\t-m <phone_mac> [-dD] [-v]");
  printf("\n\nOPTIONS:\n\t");
  printf("-i = interface name\n\t");
  printf("-c = the path of wpa_supplicant config file\n\t");
  printf("-p = pincode\n\t");
  printf("-d = enable debug message, -D = more message.\n\t");
  printf("-n = device name\n\t");
  printf("-t = timeout (seconds)\n\t");
  printf("-m = filtering MAC, only accept the configuration frame which's from this MAC address\n\t");
  printf("-v = version\t\n\n");
  printf("example:\n\t");
  printf("rtw_simple_config -i wlan0 -c ./wpa_conf -D\n\t");
  printf("rtw_simple_config -i wlan0 -c ./wpa_conf -p 14825903 -t 120 -n RTKSC_SAMPLE -d\n\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D110(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D108(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D99(%rip),%rdi
  call   <printf@plt>
  lea    D113(%rip),%rdi
  call   <printf@plt>
  lea    D85(%rip),%rdi
  call   <printf@plt>
  lea    D105(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D37
type_guessed: string
name: unpack_data
arguments: data_tag: D110
type_guessed: string
name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D32
type_guessed: string
name: unpack_data
arguments: data_tag: D108
type_guessed: string
name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D46
type_guessed: string
name: unpack_data
arguments: data_tag: D99
type_guessed: string
name: unpack_data
arguments: data_tag: D113
type_guessed: string
name: unpack_data
arguments: data_tag: D85
type_guessed: string
name: unpack_data
arguments: data_tag: D105
type_guessed: string

tool: D19: 

Usage: 
	rtw_simple_config 	-i<ifname> -c<wpa_cfgfile> -n<dev_name> -p <pincode> -t <timeout>
				-m <phone_mac> [-dD] [-v]

tool: D37: 

OPTIONS:
	

tool: D110: -i = interface name
	

tool: D30: -c = the path of wpa_supplicant config file
	

tool: D3: -p = pincode
	

tool: D32: -d = enable debug message, -D = more message.
	

tool: D108: -n = device name
	

tool: D9: -t = timeout (seconds)
	

tool: D46: -m = filtering MAC, only accept the configuration frame which's from this MAC address
	

tool: D99: -v = version	



tool: D113: example:
	

tool: D85: rtw_simple_config -i wlan0 -c ./wpa_conf -D
	

tool: D105: rtw_simple_config -i wlan0 -c ./wpa_conf -p 14825903 -t 120 -n RTKSC_SAMPLE -d



assistant: ```c
void print_usage(void) {
  printf("\n\nUsage: \n\trtw_simple_config \t-i<ifname> -c<wpa_cfgfile> -n<dev_name> -p <pincode> -t <timeout>\n\t\t\t\t-m <phone_mac> [-dD] [-v]");
  printf("\n\nOPTIONS:\n\t");
  printf("-i = interface name\n\t");
  printf("-c = the path of wpa_supplicant config file\n\t");
  printf("-p = pincode\n\t");
  printf("-d = enable debug message, -D = more message.\n\t");
  printf("-n = device name\n\t");
  printf("-t = timeout (seconds)\n\t");
  printf("-m = filtering MAC, only accept the configuration frame which's from this MAC address\n\t");
  printf("-v = version\t\n\n");
  printf("example:\n\t");
  printf("rtw_simple_config -i wlan0 -c ./wpa_conf -D\n\t");
  printf("rtw_simple_config -i wlan0 -c ./wpa_conf -p 14825903 -t 120 -n RTKSC_SAMPLE -d\n\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<smtp_header_value_validate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L51:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x1f,-0x9(%rbp)
  jbe    L46
  cmpb   $0x7e,-0x9(%rbp)
  jbe    L12
L46:
  cmpb   $0x9,-0x9(%rbp)
  je     L12
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  js     L12
  mov    $0xffffffff,%eax
  jmp    L53
L12:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int smtp_header_value_validate(const char *const value) {
  size_t i;
  unsigned char uc;
  for (i = 0; value[i]; i++) {
    uc = (unsigned char)value[i];
    if ((uc < ' ' || uc > 126) && uc != '\t' && uc < 0x80) {
      return -1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<smtp_header_value_validate>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L48
  add    $0x1,%rdi
  jmp    L22
L21:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L11
L22:
  cmp    $0x9,%al
  setne  %cl
  mov    %eax,%edx
  not    %edx
  shr    $0x7,%dl
  test   %dl,%cl
  je     L21
  sub    $0x20,%eax
  cmp    $0x5e,%al
  jbe    L21
  mov    $0xffffffff,%eax
  ret
L11:
  mov    $0x0,%eax
  ret
L48:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int smtp_header_value_validate(const char *const value) {
  size_t i;
  unsigned char uc;
  for (i = 0; value[i]; i++) {
    uc = (unsigned char)value[i];
    if ((uc < ' ' || uc > 126) && uc != '\t' && uc < 0x80) {
      return -1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<smtp_header_value_validate>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L20
  add    $0x1,%rdi
  nop
L31:
  mov    %eax,%edx
  cmp    $0x9,%al
  not    %edx
  setne  %cl
  shr    $0x7,%dl
  test   %dl,%cl
  je     L13
  sub    $0x20,%eax
  cmp    $0x5e,%al
  ja     L11
L13:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L31
L20:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L11:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int smtp_header_value_validate(const char *const value) {
  size_t i;
  unsigned char uc;
  for (i = 0; value[i]; i++) {
    uc = (unsigned char)value[i];
    if ((uc < ' ' || uc > 126) && uc != '\t' && uc < 0x80) {
      return -1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<smtp_header_value_validate>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  add    $0x1,%rdi
  nop
L10:
  mov    %eax,%edx
  cmp    $0x9,%al
  not    %edx
  setne  %cl
  shr    $0x7,%dl
  test   %dl,%cl
  je     L11
  sub    $0x20,%eax
  cmp    $0x5e,%al
  ja     L17
L11:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L10
L6:
  xor    %eax,%eax
  ret
  nopl   (%rax)
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int smtp_header_value_validate(const char *const value) {
  size_t i;
  unsigned char uc;
  for (i = 0; value[i]; i++) {
    uc = (unsigned char)value[i];
    if ((uc < ' ' || uc > 126) && uc != '\t' && uc < 0x80) {
      return -1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GetInputLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L17
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0xa,-0xd(%rbp)
  jne    L9
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *GetInputLine(void) {
  char *line;
  char tmp;
  int count = 0;
  line = (char *)malloc(4096);
  while ((tmp = getchar()) != '\n') {
    line[count] = tmp;
    count++;
  }
  line[count + 1] = '\0';
  return line;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetInputLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  jmp    L13
L18:
  mov    %al,-0x1(%rbp,%rbx,1)
L13:
  mov    %ebx,%r12d
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L18
  movslq %r12d,%r12
  movb   $0x0,0x1(%rbp,%r12,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *GetInputLine(void) {
  char *line;
  char tmp;
  int count = 0;
  line = (char *)malloc(4096);
  while ((tmp = getchar()) != '\n') {
    line[count] = tmp;
    count++;
  }
  line[count + 1] = '\0';
  return line;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GetInputLine>:
  endbr64
  push   %r12
  mov    $0x1000,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L10
  nopl   0x0(%rax)
L2:
  mov    %al,-0x1(%r12,%rbx,1)
L10:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L2
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *GetInputLine(void) {
  char *line;
  char tmp;
  int count = 0;
  line = (char *)malloc(4096);
  while ((tmp = getchar()) != '\n') {
    line[count] = tmp;
    count++;
  }
  line[count + 1] = '\0';
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetInputLine>:
  endbr64
  push   %r12
  mov    $0x1000,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L10
  nopl   0x0(%rax)
L19:
  mov    %al,-0x1(%r12,%rbx,1)
L10:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L19
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *GetInputLine(void) {
  char *line;
  char tmp;
  int count = 0;
  line = (char *)malloc(4096);
  while ((tmp = getchar()) != '\n') {
    line[count] = tmp;
    count++;
  }
  line[count + 1] = '\0';
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetTickCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
unsigned long GetTickCount() {
  struct timeval tv;
  gettimeofday(&tv, (struct timezone *)NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: What is the c source code of the assembly code below:

```asm
<GetTickCount>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%eax
  mov    0x4(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  cltq
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long GetTickCount() {
  struct timeval tv;
  gettimeofday(&tv, (struct timezone *)NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GetTickCount>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  cltq
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long GetTickCount() {
  struct timeval tv;
  gettimeofday(&tv, (struct timezone *)NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GetTickCount>:
  endbr64
  sub    $0x18,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x4(%rsp),%rdx
  imul   $0x3e8,(%rsp),%eax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  cltq
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long GetTickCount() {
  struct timeval tv;
  gettimeofday(&tv, (struct timezone *)NULL);
  return (tv.tv_sec * 1000) + (tv.tv_usec / 1000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L4
  nop
  leave
  ret
```

assistant: ```c
int rev(char str[]) {
  char temp;
  int j = strlen(str) - 1;
  int i = 0;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rev>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L1
  cltq
  mov    $0x0,%edx
L19:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  mov    %cl,(%rbx,%rax,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L19
L1:
  pop    %rbx
  ret
```

assistant: ```c
int rev(char str[]) {
  char temp;
  int j = strlen(str) - 1;
  int i = 0;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rev>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L10
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L7
L10:
  pop    %rbx
  ret
```

assistant: ```c
int rev(char str[]) {
  char temp;
  int j = strlen(str) - 1;
  int i = 0;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rev>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L7
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rbx,%rdx,1),%ecx
  movzbl (%rbx,%rax,1),%esi
  mov    %sil,(%rbx,%rdx,1)
  add    $0x1,%rdx
  mov    %cl,(%rbx,%rax,1)
  sub    $0x1,%rax
  cmp    %edx,%eax
  jg     L13
L7:
  pop    %rbx
  ret
```

assistant: ```c
int rev(char str[]) {
  char temp;
  int j = strlen(str) - 1;
  int i = 0;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  lea    -0x2c(%rbp),%rax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L84
L103:
  cmpb   $0x25,-0x11(%rbp)
  jne    L62
  addq   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x64,-0x11(%rbp)
  jne    L54
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__print_int@plt>
  jmp    L87
L54:
  cmpb   $0x63,-0x11(%rbp)
  jne    L123
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__print_char@plt>
  jmp    L87
L123:
  cmpb   $0x73,-0x11(%rbp)
  jne    L18
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__print_string@plt>
  jmp    L87
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L145
  movl   $0x1,-0x10(%rbp)
  jmp    L137
L145:
  movl   $0x0,-0x10(%rbp)
  jmp    L116
L107:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L116:
  cmpl   $0x0,-0xc(%rbp)
  jne    L107
L137:
  mov    $0x4,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L115
L24:
  mov    $0x30,%edi
  mov    $0x0,%eax
  call   <__print_char@plt>
  subl   $0x1,-0x10(%rbp)
L115:
  cmpl   $0x0,-0x10(%rbp)
  jne    L24
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__print_int@plt>
  addq   $0x2,-0x28(%rbp)
L87:
  addq   $0x4,-0x8(%rbp)
  jmp    L39
L62:
  movsbl -0x11(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <__print_char@plt>
L39:
  addq   $0x1,-0x28(%rbp)
L84:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L103
  nop
  leave
  ret
```

assistant: ```c
int printf(char *fmt, int pos) {
  char *arg, ch;
  int len, x;
  arg = (int)&pos;
  while ((ch = *fmt)) {
    if (ch == '%') {
      ch = *(++fmt);
      if (ch == 'd')
        __print_int(*(int *)arg);
      else if (ch == 'c')
        __print_char(*(char *)arg);
      else if (ch == 's')
        __print_string(*(char **)arg);
      else {
        x = *(int *)arg;
        if (!x)
          len = 1;
        else
          for (len = 0; x; x /= 10, len++)
            ;
        len = 4 - len;
        while (len)
          __print_char('0'), len--;
        __print_int(*(int *)arg);
        fmt += 2;
      }
      arg += 4;
    } else
      __print_char(ch);
    fmt++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<printf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,0xc(%rsp)
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L151
  lea    0xc(%rsp),%r12
  movslq %r12d,%r12
  mov    $0x4,%r13d
  jmp    L15
L65:
  mov    (%r12),%edi
  mov    $0x0,%eax
  call   <__print_int@plt>
  jmp    L50
L126:
  movsbl (%r12),%edi
  mov    $0x0,%eax
  call   <__print_char@plt>
  jmp    L50
L110:
  mov    (%r12),%rdi
  mov    $0x0,%eax
  call   <__print_string@plt>
  jmp    L50
L34:
  mov    $0x30,%edi
  mov    $0x0,%eax
  call   <__print_char@plt>
  sub    $0x1,%ebx
  jne    L34
L154:
  mov    %r14d,%edi
  mov    $0x0,%eax
  call   <__print_int@plt>
  lea    0x3(%rbp),%rbx
L50:
  add    $0x4,%r12
L41:
  lea    0x1(%rbx),%rbp
  movzbl 0x1(%rbx),%edi
  test   %dil,%dil
  je     L151
L15:
  cmp    $0x25,%dil
  jne    L113
  lea    0x1(%rbp),%rbx
  movzbl 0x1(%rbp),%eax
  cmp    $0x64,%al
  je     L65
  cmp    $0x63,%al
  je     L126
  cmp    $0x73,%al
  je     L110
  mov    (%r12),%r14d
  mov    $0x3,%ebx
  test   %r14d,%r14d
  je     L34
  mov    %r14d,%edx
  mov    $0x0,%ecx
L39:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  add    $0x1,%ecx
  test   %eax,%eax
  jne    L39
  mov    %r13d,%ebx
  sub    %ecx,%ebx
  jne    L34
  jmp    L154
L113:
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <__print_char@plt>
  mov    %rbp,%rbx
  jmp    L41
L151:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int printf(char *fmt, int pos) {
  char *arg, ch;
  int len, x;
  arg = (int)&pos;
  while ((ch = *fmt)) {
    if (ch == '%') {
      ch = *(++fmt);
      if (ch == 'd')
        __print_int(*(int *)arg);
      else if (ch == 'c')
        __print_char(*(char *)arg);
      else if (ch == 's')
        __print_string(*(char **)arg);
      else {
        x = *(int *)arg;
        if (!x)
          len = 1;
        else
          for (len = 0; x; x /= 10, len++)
            ;
        len = 4 - len;
        while (len)
          __print_char('0'), len--;
        __print_int(*(int *)arg);
        fmt += 2;
      }
      arg += 4;
    } else
      __print_char(ch);
    fmt++;
  }
}
```