ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<recurse>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  jle    L13
  sub    $0x1,%rsi
  call   <recurse>
L16:
  add    $0x8,%rsp
  ret
L13:
  call   <my_readlink@plt>
  jmp    L16
```

assistant: ```c
long recurse(const char *path, long count) {
  if (count <= 0) {
    return my_readlink(path);
  } else {
    long r = recurse(path, count - 1);
    return r;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recurse>:
  endbr64
  jmp    1050 <my_readlink@plt>
```

assistant: ```c
long recurse(const char *path, long count) {
  if (count <= 0) {
    return my_readlink(path);
  } else {
    long r = recurse(path, count - 1);
    return r;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<recurse>:
  endbr64
  jmp    1050 <my_readlink@plt>
```

assistant: ```c
long recurse(const char *path, long count) {
  if (count <= 0) {
    return my_readlink(path);
  } else {
    long r = recurse(path, count - 1);
    return r;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L39
L2:
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L0:
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L39:
  cmpl   $0x4,-0x8(%rbp)
  jle    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 4; i++) {
    for (j = 1; j <= i; j++) {
      printf("%d", j % 2);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebp
  lea    D7(%rip),%r12
  jmp    L3
L13:
  mov    %ebx,%eax
  shr    $0x1f,%eax
  lea    (%rbx,%rax,1),%esi
  and    $0x1,%esi
  sub    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L13
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0x5,%ebp
  je     L8
L3:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L13
  jmp    L17
L8:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type: string

tool: D7: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 4; i++) {
    for (j = 1; j <= i; j++) {
      printf("%d", j % 2);
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
L5:
  mov    $0x1,%ebx
L6:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  and    $0x1,%esi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L6
  mov    $0xa,%edi
  lea    0x1(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0x5,%ebx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 4; i++) {
    for (j = 1; j <= i; j++) {
      printf("%d", j % 2);
    }
    printf("\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    $0x2,%ebp
  push   %rbx
L12:
  mov    $0x1,%ebx
L17:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  and    $0x1,%esi
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L17
  mov    $0xa,%edi
  lea    0x1(%rbx),%ebp
  call   <putchar@plt>
  cmp    $0x5,%ebx
  jne    L12
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4: %d

assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 4; i++) {
    for (j = 1; j <= i; j++) {
      printf("%d", j % 2);
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jl_near_rj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0x8c,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void jl_near_rj(unsigned int saut) {
  put8(0x0F);
  put8(0x8C);
  put32(saut);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jl_near_rj>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0x8c,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void jl_near_rj(unsigned int saut) {
  put8(0x0F);
  put8(0x8C);
  put32(saut);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jl_near_rj>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0x8c,%edi
  call   <put8@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void jl_near_rj(unsigned int saut) {
  put8(0x0F);
  put8(0x8C);
  put32(saut);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jl_near_rj>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0x8c,%edi
  call   <put8@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void jl_near_rj(unsigned int saut) {
  put8(0x0F);
  put8(0x8C);
  put32(saut);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<findMissing>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L31
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  movl   $0x2,-0x4(%rbp)
  jmp    L2
L36:
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L36
  mov    -0xc(%rbp),%eax
  xor    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int findMissing(int *a, int n) {
  int x0 = a[0];
  int x1 = 1;
  int i = 0;
  for (i = 1; i < n; i++) {
    x0 ^= a[i];
  }
  for (i = 2; i <= (n + 1); i++) {
    x1 ^= i;
  }
  return x0 ^ x1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findMissing>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x1,%esi
  jle    L30
  lea    0x4(%rdi),%rdx
  lea    -0x2(%rsi),%ecx
  lea    0x8(%rdi,%rcx,4),%rcx
L32:
  xor    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L32
  mov    $0x2,%edx
  mov    $0x1,%ecx
L15:
  xor    %edx,%ecx
  mov    %edx,%edi
  add    $0x1,%edx
  cmp    %edi,%esi
  jge    L15
L0:
  xor    %ecx,%eax
  ret
L30:
  test   %esi,%esi
  setg   %cl
  movzbl %cl,%ecx
  lea    0x1(%rcx,%rcx,1),%ecx
  jmp    L0
```

assistant: ```c
int findMissing(int *a, int n) {
  int x0 = a[0];
  int x1 = 1;
  int i = 0;
  for (i = 1; i < n; i++) {
    x0 ^= a[i];
  }
  for (i = 2; i <= (n + 1); i++) {
    x1 ^= i;
  }
  return x0 ^ x1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findMissing>:
  endbr64
  mov    (%rdi),%eax
  lea    0x1(%rsi),%edx
  cmp    $0x1,%esi
  jle    L11
  lea    -0x2(%rsi),%ecx
  lea    0x4(%rdi),%rdx
  lea    0x8(%rdi,%rcx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L16:
  xor    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L16
L31:
  mov    $0x2,%edx
  mov    $0x1,%ecx
  nopl   (%rax)
L36:
  mov    %edx,%edi
  xor    %edx,%ecx
  add    $0x1,%edx
  cmp    %edi,%esi
  jge    L36
  xor    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  cmp    $0x1,%edx
  jg     L31
  mov    $0x1,%ecx
  xor    %ecx,%eax
  ret
```

assistant: ```c
int findMissing(int *a, int n) {
  int x0 = a[0];
  int x1 = 1;
  int i = 0;
  for (i = 1; i < n; i++) {
    x0 ^= a[i];
  }
  for (i = 2; i <= (n + 1); i++) {
    x1 ^= i;
  }
  return x0 ^ x1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<findMissing>:
  endbr64
  mov    (%rdi),%eax
  mov    %esi,%ecx
  lea    0x1(%rsi),%r8d
  cmp    $0x1,%esi
  jle    L181
  lea    -0x2(%rsi),%edx
  lea    -0x1(%rsi),%r9d
  cmp    $0x2,%edx
  jbe    L151
  mov    %r9d,%esi
  lea    0x4(%rdi),%rdx
  pxor   %xmm0,%xmm0
  shr    $0x2,%esi
  sub    $0x1,%esi
  shl    $0x4,%rsi
  lea    0x14(%rdi,%rsi,1),%rsi
  nop
L112:
  movdqu (%rdx),%xmm4
  add    $0x10,%rdx
  pxor   %xmm4,%xmm0
  cmp    %rdx,%rsi
  jne    L112
  movdqa %xmm0,%xmm1
  mov    %r9d,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%edx
  xor    %edx,%eax
  lea    0x1(%rsi),%edx
  cmp    %esi,%r9d
  je     L53
L4:
  movslq %edx,%rsi
  lea    0x0(,%rsi,4),%r9
  xor    (%rdi,%rsi,4),%eax
  lea    0x1(%rdx),%esi
  cmp    %esi,%ecx
  jle    L53
  add    $0x2,%edx
  xor    0x4(%rdi,%r9,1),%eax
  cmp    %edx,%ecx
  jle    L53
  xor    0x8(%rdi,%r9,1),%eax
L53:
  test   %ecx,%ecx
  mov    $0x1,%edi
  cmovg  %ecx,%edi
  cmp    $0xa,%ecx
  jle    L79
  mov    %edi,%esi
  movdqa D17(%rip),%xmm1
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  movdqa D2(%rip),%xmm3
  shr    $0x2,%esi
  nopl   0x0(%rax,%rax,1)
L145:
  movdqa %xmm1,%xmm2
  add    $0x1,%edx
  paddd  %xmm3,%xmm1
  pxor   %xmm2,%xmm0
  cmp    %edx,%esi
  jne    L145
  movdqa %xmm0,%xmm1
  mov    %edi,%r9d
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%r9d
  pxor   %xmm1,%xmm0
  lea    0x2(%r9),%esi
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%edx
  xor    $0x1,%edx
  cmp    %edi,%r9d
  je     L107
L122:
  xor    %esi,%edx
  lea    0x1(%rsi),%edi
  cmp    %ecx,%esi
  jg     L107
  lea    0x2(%rsi),%ecx
  xor    %edi,%edx
  cmp    %r8d,%ecx
  jg     L107
  xor    %ecx,%edx
  lea    0x3(%rsi),%ecx
  cmp    %r8d,%ecx
  jg     L107
  xor    %ecx,%edx
  lea    0x4(%rsi),%ecx
  cmp    %r8d,%ecx
  jg     L107
  xor    %ecx,%edx
  lea    0x5(%rsi),%ecx
  cmp    %ecx,%r8d
  jl     L107
  xor    %ecx,%edx
  lea    0x6(%rsi),%ecx
  cmp    %ecx,%r8d
  jl     L107
  xor    %ecx,%edx
  lea    0x7(%rsi),%ecx
  cmp    %ecx,%r8d
  jl     L107
  xor    %ecx,%edx
  lea    0x8(%rsi),%ecx
  cmp    %ecx,%r8d
  jl     L107
  xor    %ecx,%edx
  add    $0x9,%esi
  mov    %edx,%ecx
  xor    %esi,%ecx
  cmp    %esi,%r8d
  cmovge %ecx,%edx
L107:
  xor    %edx,%eax
  ret
  nopl   (%rax)
L181:
  cmp    $0x1,%r8d
  jg     L79
  mov    $0x1,%edx
  xor    %edx,%eax
  ret
L151:
  mov    $0x1,%edx
  jmp    L4
L79:
  mov    $0x2,%esi
  mov    $0x1,%edx
  jmp    L122
```

tool_calls: name: unpack_data
arguments: tag: D17
type: byte[16]
name: unpack_data
arguments: tag: D2
type: byte[16]

tool: {"D17": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D2": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int findMissing(int *a, int n) {
  int x0 = a[0];
  int x1 = 1;
  int i = 0;
  for (i = 1; i < n; i++) {
    x0 ^= a[i];
  }
  for (i = 2; i <= (n + 1); i++) {
    x1 ^= i;
  }
  return x0 ^ x1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<warn_mempcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  lea    -0x5(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x6,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <mempcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    D9(%rip),%rax
  lea    0x1(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mempcpy@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x5,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <mempcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
void warn_mempcpy(const void *s) {
  extern char pcpy_a5[5];
  char *p = pcpy_a5;
  p = mempcpy(p, s, 5);
  sink(p);
  mempcpy(p - 5, s, 6);
  sink(p);
  p = pcpy_a5;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p, s, 3);
  sink(p);
  p = pcpy_a5 + 1;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p - 1, s, 5);
  sink(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<warn_mempcpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5,%edx
  mov    %rdi,%rsi
  mov    D9(%rip),%r12
  mov    %r12,%rdi
  call   <mempcpy@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <sink@plt>
  lea    -0x5(%rbp),%rdi
  mov    $0x6,%edx
  mov    %rbx,%rsi
  call   <mempcpy@plt>
  mov    %rbp,%rdi
  call   <sink@plt>
  mov    $0x3,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <mempcpy@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <sink@plt>
  mov    $0x3,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mempcpy@plt>
  mov    %rbp,%rdi
  call   <sink@plt>
  mov    $0x3,%edx
  mov    %rbx,%rsi
  lea    0x1(%r12),%rdi
  call   <mempcpy@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <sink@plt>
  lea    -0x1(%rbp),%rdi
  mov    $0x5,%edx
  mov    %rbx,%rsi
  call   <mempcpy@plt>
  mov    %rbp,%rdi
  call   <sink@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void warn_mempcpy(const void *s) {
  extern char pcpy_a5[5];
  char *p = pcpy_a5;
  p = mempcpy(p, s, 5);
  sink(p);
  mempcpy(p - 5, s, 6);
  sink(p);
  p = pcpy_a5;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p, s, 3);
  sink(p);
  p = pcpy_a5 + 1;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p - 1, s, 5);
  sink(p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<warn_mempcpy>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x5,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <mempcpy@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  lea    -0x5(%r12),%rdi
  mov    $0x6,%edx
  call   <mempcpy@plt>
  mov    %r12,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <mempcpy@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edx
  mov    %r12,%rdi
  call   <mempcpy@plt>
  mov    %r12,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edx
  lea    0x1(%rbx),%rdi
  call   <mempcpy@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  lea    -0x1(%r12),%rdi
  mov    %rbp,%rsi
  mov    $0x5,%edx
  call   <mempcpy@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <sink@plt>
```

assistant: ```c
void warn_mempcpy(const void *s) {
  extern char pcpy_a5[5];
  char *p = pcpy_a5;
  p = mempcpy(p, s, 5);
  sink(p);
  mempcpy(p - 5, s, 6);
  sink(p);
  p = pcpy_a5;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p, s, 3);
  sink(p);
  p = pcpy_a5 + 1;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p - 1, s, 5);
  sink(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<warn_mempcpy>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x5,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <mempcpy@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  lea    -0x5(%r12),%rdi
  mov    $0x6,%edx
  call   <mempcpy@plt>
  mov    %r12,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edx
  mov    %rbx,%rdi
  call   <mempcpy@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edx
  mov    %r12,%rdi
  call   <mempcpy@plt>
  mov    %r12,%rdi
  call   <sink@plt>
  mov    %rbp,%rsi
  mov    $0x3,%edx
  lea    0x1(%rbx),%rdi
  call   <mempcpy@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sink@plt>
  lea    -0x1(%r12),%rdi
  mov    %rbp,%rsi
  mov    $0x5,%edx
  call   <mempcpy@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <sink@plt>
```

assistant: ```c
void warn_mempcpy(const void *s) {
  extern char pcpy_a5[5];
  char *p = pcpy_a5;
  p = mempcpy(p, s, 5);
  sink(p);
  mempcpy(p - 5, s, 6);
  sink(p);
  p = pcpy_a5;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p, s, 3);
  sink(p);
  p = pcpy_a5 + 1;
  p = mempcpy(p, s, 3);
  sink(p);
  mempcpy(p - 1, s, 5);
  sink(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *ptr;
  unsigned long dst;
  unsigned long src = ~0;
  ptr = __builtin_memcpy(&dst, &src, sizeof(dst));
  (void)ptr;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *ptr;
  unsigned long dst;
  unsigned long src = ~0;
  ptr = __builtin_memcpy(&dst, &src, sizeof(dst));
  (void)ptr;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *ptr;
  unsigned long dst;
  unsigned long src = ~0;
  ptr = __builtin_memcpy(&dst, &src, sizeof(dst));
  (void)ptr;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  void *ptr;
  unsigned long dst;
  unsigned long src = ~0;
  ptr = __builtin_memcpy(&dst, &src, sizeof(dst));
  (void)ptr;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BSVM2_NatCall_SigGetRet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x28,%al
  jne    L45
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L15
L51:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BSVM2_NatCall_SigNext@plt>
  mov    %rax,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L51
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x29,%al
  jne    L67
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  jmp    L20
L67:
  mov    $0x0,%eax
  jmp    L20
L45:
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
char *BSVM2_NatCall_SigGetRet(char *sig) {
  char *s;
  if (*sig == '(') {
    s = sig + 1;
    while (*s && (*s != ')')) {
      s = BSVM2_NatCall_SigNext(s);
    }
    if (*s == ')')
      return (s + 1);
    return (NULL);
  }
  return (NULL);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BSVM2_NatCall_SigGetRet>:
  endbr64
  mov    $0x0,%eax
  cmpb   $0x28,(%rdi)
  jne    L27
  mov    %rdi,%rdx
  lea    0x1(%rdi),%rdi
  movzbl 0x1(%rdx),%edx
  test   %dl,%dl
  je     L2
  cmp    $0x29,%dl
  je     L2
  sub    $0x8,%rsp
L19:
  call   <BSVM2_NatCall_SigNext@plt>
  mov    %rax,%rdi
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L1
  cmp    $0x29,%dl
  jne    L19
L1:
  lea    0x1(%rdi),%rax
  cmp    $0x29,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
  add    $0x8,%rsp
  ret
L2:
  lea    0x1(%rdi),%rax
  cmp    $0x29,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
  ret
L27:
  ret
```

assistant: ```c
char *BSVM2_NatCall_SigGetRet(char *sig) {
  char *s;
  if (*sig == '(') {
    s = sig + 1;
    while (*s && (*s != ')')) {
      s = BSVM2_NatCall_SigNext(s);
    }
    if (*s == ')')
      return (s + 1);
    return (NULL);
  }
  return (NULL);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BSVM2_NatCall_SigGetRet>:
  endbr64
  cmpb   $0x28,(%rdi)
  jne    L32
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L19
  cmp    $0x29,%al
  je     L55
  sub    $0x8,%rsp
L21:
  call   <BSVM2_NatCall_SigNext@plt>
  mov    %rax,%rdi
  movzbl (%rax),%eax
  test   %al,%al
  je     L58
  cmp    $0x29,%al
  jne    L21
L25:
  lea    0x1(%rdi),%rax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L58:
  cmp    $0x29,%al
  je     L25
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L19:
  cmp    $0x29,%al
  jne    L32
L55:
  lea    0x1(%rdi),%rax
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *BSVM2_NatCall_SigGetRet(char *sig) {
  char *s;
  if (*sig == '(') {
    s = sig + 1;
    while (*s && (*s != ')')) {
      s = BSVM2_NatCall_SigNext(s);
    }
    if (*s == ')')
      return (s + 1);
    return (NULL);
  }
  return (NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BSVM2_NatCall_SigGetRet>:
  endbr64
  cmpb   $0x28,(%rdi)
  jne    L18
  mov    %rdi,%rax
  lea    0x1(%rdi),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L15
  cmp    $0x29,%al
  je     L67
  sub    $0x8,%rsp
L12:
  call   <BSVM2_NatCall_SigNext@plt>
  mov    %rax,%rdi
  movzbl (%rax),%eax
  test   %al,%al
  je     L54
  cmp    $0x29,%al
  jne    L12
L28:
  lea    0x1(%rdi),%rax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L54:
  cmp    $0x29,%al
  je     L28
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L15:
  cmp    $0x29,%al
  jne    L18
L67:
  lea    0x1(%rdi),%rax
  ret
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *BSVM2_NatCall_SigGetRet(char *sig) {
  char *s;
  if (*sig == '(') {
    s = sig + 1;
    while (*s && (*s != ')')) {
      s = BSVM2_NatCall_SigNext(s);
    }
    if (*s == ')')
      return (s + 1);
    return (NULL);
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<excess>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rcx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <decimalToBinary@plt>
  nop
  leave
  ret
```

assistant: ```c
void excess(long n, int size, char result[size + 1]) {
  long bias = (long)pow(2, size - 1) - 1;
  n += bias;
  result[size] = '\0';
  decimalToBinary(n, 0, size, result);
}
```