ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<applyfuncmap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  cmpq   $0x0,(%rdi)
  je     L14
  lea    0x8(%rdi),%rax
  mov    $0x0,%ebp
L28:
  mov    %ebp,%edx
  add    $0x1,%ebp
  add    $0x8,%rax
  cmpq   $0x0,-0x8(%rax)
  jne    L28
  lea    0x10(,%rdx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L63:
  test   %ebp,%ebp
  jle    L16
  mov    %ebp,%r14d
  mov    $0x0,%ebx
L4:
  call   *0x0(%r13,%rbx,8)
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jne    L4
L26:
  movslq %ebp,%rbp
  movq   $0x0,(%r12,%rbp,8)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  mov    $0x0,%ebp
L17:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    $0x0,%r12d
  jmp    L63
L16:
  mov    $0x0,%ebp
  jmp    L26
L14:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L47
  mov    $0x0,%ebp
  jmp    L26
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: malloc

assistant: ```c
char **applyfuncmap(char *(*fmap[])(void)) {
  int i;
  int sz = 0;
  char **ret;
  while (fmap[sz] != NULL)
    ++sz;
  ret = malloc((sz + 1) * sizeof(char *));
  if (ret == NULL) {
    perror("malloc");
    exit(1);
  }
  for (i = 0; i < sz; i++)
    ret[i] = fmap[i]();
  ret[i] = 0;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<applyfuncmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L5
  mov    %rdi,%r13
  lea    0x8(%rdi),%rax
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L60:
  add    $0x8,%rax
  mov    %ebp,%edx
  add    $0x1,%ebp
  cmpq   $0x0,-0x8(%rax)
  jne    L60
  lea    0x10(,%rdx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
L57:
  xor    %ebx,%ebx
  xchg   %ax,%ax
L33:
  call   *0x0(%r13,%rbx,8)
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L33
  movslq %ebp,%rbp
  lea    (%r12,%rbp,8),%rax
L23:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L1:
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L23
  lea    D10(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  jmp    L23
```

tool_calls: name: read_data
arguments: tag: D10
data_type: string

tool: D10: malloc

assistant: ```c
char **applyfuncmap(char *(*fmap[])(void)) {
  int i;
  int sz = 0;
  char **ret;
  while (fmap[sz] != NULL)
    ++sz;
  ret = malloc((sz + 1) * sizeof(char *));
  if (ret == NULL) {
    perror("malloc");
    exit(1);
  }
  for (i = 0; i < sz; i++)
    ret[i] = fmap[i]();
  ret[i] = 0;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<applyfuncmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpq   $0x0,(%rdi)
  je     L40
  mov    %rdi,%r13
  lea    0x8(%rdi),%rax
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L27:
  add    $0x8,%rax
  mov    %ebp,%edx
  add    $0x1,%ebp
  cmpq   $0x0,-0x8(%rax)
  jne    L27
  lea    0x10(,%rdx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
L8:
  xor    %ebx,%ebx
  xchg   %ax,%ax
L44:
  call   *0x0(%r13,%rbx,8)
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L44
  movslq %ebp,%rbp
  lea    (%r12,%rbp,8),%rax
L17:
  movq   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L39:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L40:
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L17
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  xor    %eax,%eax
  jmp    L17
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: malloc

assistant: ```c
char **applyfuncmap(char *(*fmap[])(void)) {
  int i;
  int sz = 0;
  char **ret;
  while (fmap[sz] != NULL)
    ++sz;
  ret = malloc((sz + 1) * sizeof(char *));
  if (ret == NULL) {
    perror("malloc");
    exit(1);
  }
  for (i = 0; i < sz; i++)
    ret[i] = fmap[i]();
  ret[i] = 0;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  D28(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D13(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  mov    -0xc(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <remainingAngle@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D28
datatype: f32
name: read_data
arguments: label: D13
datatype: f32
name: read_data
arguments: label: D7
datatype: string

tool: D28: 30

tool: D13: 60

tool: D7: The third angle is %.1f.


assistant: ```c
int main(int argc, const char *argv[]) {
  float angleA = 30.0;
  float angleB = 60.0;
  float angleC = remainingAngle(angleA, angleB);
  printf("The third angle is %.1f.\n", angleC);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D0(%rip),%xmm1
  movss  D16(%rip),%xmm0
  call   <remainingAngle@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: f32
name: disassemble_data
arguments: tag: D16
datatype: f32
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D0: 60

tool: D16: 30

tool: D14: The third angle is %.1f.


assistant: ```c
int main(int argc, const char *argv[]) {
  float angleA = 30.0;
  float angleB = 60.0;
  float angleC = remainingAngle(angleA, angleB);
  printf("The third angle is %.1f.\n", angleC);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D6(%rip),%xmm1
  movss  D13(%rip),%xmm0
  call   <remainingAngle@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type: f32
name: read_data
arguments: tag: D13
type: f32
name: read_data
arguments: tag: D20
type: string

tool: D6: 60

tool: D13: 30

tool: D20: The third angle is %.1f.


assistant: ```c
int main(int argc, const char *argv[]) {
  float angleA = 30.0;
  float angleB = 60.0;
  float angleC = remainingAngle(angleA, angleB);
  printf("The third angle is %.1f.\n", angleC);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D2(%rip),%xmm1
  movss  D29(%rip),%xmm0
  call   <remainingAngle@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: f32
name: retrieve_data
arguments: label: D29
type_infered: f32
name: retrieve_data
arguments: label: D18
type_infered: string

tool: D2: 60

tool: D29: 30

tool: D18: The third angle is %.1f.


assistant: ```c
int main(int argc, const char *argv[]) {
  float angleA = 30.0;
  float angleB = 60.0;
  float angleC = remainingAngle(angleA, angleB);
  printf("The third angle is %.1f.\n", angleC);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<num_perfeito>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L9
L26:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L3
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L35
  movl   $0x1,-0x4(%rbp)
  jmp    L5
L35:
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L26
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: num: %d	soma: %d


assistant: ```c
int num_perfeito(int num) {
  int i, sum = 0, flg = 0;
  for (i = 1; i <= num; i++) {
    if (num % i == 0) {
      sum += i;
      printf("num: %d\tsoma: %d\n", i, sum);
    }
    if (sum == num) {
      flg = 1;
      break;
    }
  }
  return flg;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<num_perfeito>:
  endbr64
  test   %edi,%edi
  jle    L31
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D2(%rip),%r13
  jmp    L52
L39:
  cmp    %ebp,%r12d
  je     L63
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L47
L52:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L39
  add    %ebx,%r12d
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L39
L47:
  mov    $0x0,%eax
  jmp    L41
L31:
  mov    $0x0,%eax
  ret
L63:
  mov    $0x1,%eax
L41:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D2: num: %d	soma: %d


assistant: ```c
int num_perfeito(int num) {
  int i, sum = 0, flg = 0;
  for (i = 1; i <= num; i++) {
    if (num % i == 0) {
      sum += i;
      printf("num: %d\tsoma: %d\n", i, sum);
    }
    if (sum == num) {
      flg = 1;
      break;
    }
  }
  return flg;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_perfeito>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L31
  nopl   (%rax)
L39:
  cmp    %ebp,%r12d
  je     L44
L48:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L49
L31:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L39
  add    %ebx,%r12d
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %r12d,%edx
  call   <printf@plt>
  cmp    %ebp,%r12d
  jne    L48
L44:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string

tool: D5: num: %d	soma: %d


assistant: ```c
int num_perfeito(int num) {
  int i, sum = 0, flg = 0;
  for (i = 1; i <= num; i++) {
    if (num % i == 0) {
      sum += i;
      printf("num: %d\tsoma: %d\n", i, sum);
    }
    if (sum == num) {
      flg = 1;
      break;
    }
  }
  return flg;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<num_perfeito>:
  endbr64
  test   %edi,%edi
  jle    L45
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   (%rax)
L46:
  cmp    %ebp,%r12d
  je     L7
L6:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L27
L8:
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L46
  add    %ebx,%r12d
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %r12d,%edx
  call   <printf@plt>
  cmp    %ebp,%r12d
  jne    L6
L7:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: num: %d	soma: %d


assistant: ```c
int num_perfeito(int num) {
  int i, sum = 0, flg = 0;
  for (i = 1; i <= num; i++) {
    if (num % i == 0) {
      sum += i;
      printf("num: %d\tsoma: %d\n", i, sum);
    }
    if (sum == num) {
      flg = 1;
      break;
    }
  }
  return flg;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_mosquitto_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *_mosquitto_strdup(const char *s) {
  char *str = strdup(s);
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_mosquitto_strdup>:
  endbr64
  sub    $0x8,%rsp
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *_mosquitto_strdup(const char *s) {
  char *str = strdup(s);
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_mosquitto_strdup>:
  endbr64
  jmp    1050 <strdup@plt>
```

assistant: ```c
char *_mosquitto_strdup(const char *s) {
  char *str = strdup(s);
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_mosquitto_strdup>:
  endbr64
  jmp    1050 <strdup@plt>
```

assistant: ```c
char *_mosquitto_strdup(const char *s) {
  char *str = strdup(s);
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compareStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int compareStrings(void *value1, void *value2) {
  char *charPtr1, *charPtr2;
  charPtr1 = (char *)value1;
  charPtr2 = (char *)value2;
  return strcmp(charPtr1, charPtr2);
}
```
user: What is the c source code of the assembly code below?

```asm
<compareStrings>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int compareStrings(void *value1, void *value2) {
  char *charPtr1, *charPtr2;
  charPtr1 = (char *)value1;
  charPtr2 = (char *)value2;
  return strcmp(charPtr1, charPtr2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compareStrings>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int compareStrings(void *value1, void *value2) {
  char *charPtr1, *charPtr2;
  charPtr1 = (char *)value1;
  charPtr2 = (char *)value2;
  return strcmp(charPtr1, charPtr2);
}
```
user: What is the c source code of the assembly code below?

```asm
<compareStrings>:
  endbr64
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int compareStrings(void *value1, void *value2) {
  char *charPtr1, *charPtr2;
  charPtr1 = (char *)value1;
  charPtr2 = (char *)value2;
  return strcmp(charPtr1, charPtr2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hull_in_4d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x130(%rbp),%rdx
  mov    -0x124(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <convex_hull@plt>
  mov    %eax,-0x114(%rbp)
  lea    -0x120(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <number_of_facets@plt>
  mov    %eax,-0x114(%rbp)
  mov    -0x120(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L11:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x11c(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x11c(%rbp),%eax
  test   %eax,%eax
  js     L19
  mov    -0x11c(%rbp),%eax
  lea    -0x110(%rbp),%rcx
  lea    -0x118(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <retrieve_facet@plt>
  mov    %eax,-0x114(%rbp)
  mov    -0x11c(%rbp),%eax
  lea    -0x110(%rbp),%rdx
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x11c(%rbp),%eax
  test   %eax,%eax
  jns    L11
  jmp    L10
L19:
  nop
L10:
  mov    -0x114(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D13
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D30
data_type: string

tool: D15: Number of facets : %d


tool: D13: Give a facet number (-1 to exit) : 

tool: D26: %d

tool: D30: The representation of facet %d :
 %s


assistant: ```c
int hull_in_4d(int nbc_pts, char *pts) {
  int fail, nbr, fcn, ncp;
  char rep[256];
  fail = convex_hull(nbc_pts, pts);
  fail = number_of_facets(4, &nbr);
  printf("Number of facets : %d\n", nbr);
  do {
    printf("Give a facet number (-1 to exit) : ");
    scanf("%d", &fcn);
    if (fcn < 0)
      break;
    fail = retrieve_facet(4, fcn, &ncp, rep);
    printf("The representation of facet %d :\n %s\n", fcn, rep);
  } while (fcn >= 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hull_in_4d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <convex_hull@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edi
  call   <number_of_facets@plt>
  mov    %eax,%ebx
  mov    0x4(%rsp),%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D32(%rip),%r14
  lea    0x8(%rsp),%r13
  lea    D28(%rip),%r12
  lea    D37(%rip),%r15
L1:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  test   %esi,%esi
  js     L18
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rcx
  mov    $0x4,%edi
  call   <retrieve_facet@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdx
  mov    0x8(%rsp),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jns    L1
L18:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D32
type: string
name: unpack_data
arguments: label: D28
type: string
name: unpack_data
arguments: label: D37
type: string

tool: D18: Number of facets : %d


tool: D32: Give a facet number (-1 to exit) : 

tool: D28: %d

tool: D37: The representation of facet %d :
 %s


assistant: ```c
int hull_in_4d(int nbc_pts, char *pts) {
  int fail, nbr, fcn, ncp;
  char rep[256];
  fail = convex_hull(nbc_pts, pts);
  fail = number_of_facets(4, &nbr);
  printf("Number of facets : %d\n", nbr);
  do {
    printf("Give a facet number (-1 to exit) : ");
    scanf("%d", &fcn);
    if (fcn < 0)
      break;
    fail = retrieve_facet(4, fcn, &ncp, rep);
    printf("The representation of facet %d :\n %s\n", fcn, rep);
  } while (fcn >= 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hull_in_4d>:
  endbr64
  push   %r15
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D31(%rip),%rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  call   <convex_hull@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edi
  call   <number_of_facets@plt>
  mov    0x4(%rsp),%esi
  lea    D28(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L12
  nopl   (%rax)
L7:
  lea    0x10(%rsp),%r15
  lea    0xc(%rsp),%rdx
  mov    $0x4,%edi
  mov    %r15,%rcx
  call   <retrieve_facet@plt>
  mov    0x8(%rsp),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  js     L19
L12:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  test   %esi,%esi
  jns    L7
L19:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x128,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D31
type: string
name: extract_symbolic_data
arguments: tag: D28
type: string

tool: D7: The representation of facet %d :
 %s


tool: D29: Give a facet number (-1 to exit) : 

tool: D31: %d

tool: D28: Number of facets : %d


assistant: ```c
int hull_in_4d(int nbc_pts, char *pts) {
  int fail, nbr, fcn, ncp;
  char rep[256];
  fail = convex_hull(nbc_pts, pts);
  fail = number_of_facets(4, &nbr);
  printf("Number of facets : %d\n", nbr);
  do {
    printf("Give a facet number (-1 to exit) : ");
    scanf("%d", &fcn);
    if (fcn < 0)
      break;
    fail = retrieve_facet(4, fcn, &ncp, rep);
    printf("The representation of facet %d :\n %s\n", fcn, rep);
  } while (fcn >= 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hull_in_4d>:
  endbr64
  push   %r15
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  call   <convex_hull@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edi
  call   <number_of_facets@plt>
  mov    0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L20
  nopl   (%rax)
L32:
  lea    0x10(%rsp),%r15
  lea    0xc(%rsp),%rdx
  mov    $0x4,%edi
  mov    %r15,%rcx
  call   <retrieve_facet@plt>
  mov    0x8(%rsp),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  js     L10
L20:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  test   %esi,%esi
  jns    L32
L10:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x128,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D33
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D25: The representation of facet %d :
 %s


tool: D12: Give a facet number (-1 to exit) : 

tool: D33: %d

tool: D6: Number of facets : %d


assistant: ```c
int hull_in_4d(int nbc_pts, char *pts) {
  int fail, nbr, fcn, ncp;
  char rep[256];
  fail = convex_hull(nbc_pts, pts);
  fail = number_of_facets(4, &nbr);
  printf("Number of facets : %d\n", nbr);
  do {
    printf("Give a facet number (-1 to exit) : ");
    scanf("%d", &fcn);
    if (fcn < 0)
      break;
    fail = retrieve_facet(4, fcn, &ncp, rep);
    printf("The representation of facet %d :\n %s\n", fcn, rep);
  } while (fcn >= 0);
  return fail;
}
```