ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gameresource_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  lea    D0(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <initGameResource_test@plt>
  mov    $0x0,%eax
  call   <initGameResourceFromDir_test@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D0: /home/kichikuou

tool: D6: HOME

assistant: ```c
void gameresource_test(void) {
  setenv("HOME", "/home/kichikuou", 1);
  initGameResource_test();
  initGameResourceFromDir_test();
}
```
user: Translate the below assembly code into C programming language:

```asm
<gameresource_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  lea    D0(%rip),%rsi
  lea    D18(%rip),%rdi
  call   <setenv@plt>
  xor    %eax,%eax
  call   <initGameResource_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <initGameResourceFromDir_test@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string

tool: D0: /home/kichikuou

tool: D18: HOME

assistant: ```c
void gameresource_test(void) {
  setenv("HOME", "/home/kichikuou", 1);
  initGameResource_test();
  initGameResourceFromDir_test();
}
```
user: What is the c source code of the assembly code below?

```asm
<gameresource_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  lea    D12(%rip),%rsi
  lea    D19(%rip),%rdi
  call   <setenv@plt>
  xor    %eax,%eax
  call   <initGameResource_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <initGameResourceFromDir_test@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D19
datatype: string

tool: D12: /home/kichikuou

tool: D19: HOME

assistant: ```c
void gameresource_test(void) {
  setenv("HOME", "/home/kichikuou", 1);
  initGameResource_test();
  initGameResourceFromDir_test();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  jmp    L34
L19:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L58
  mov    $0xffffffff,%ebx
  jmp    L41
L58:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L43
  sub    $0x1,%ebx
L34:
  test   %ebx,%ebx
  jns    L19
  jmp    L41
L43:
  nop
L41:
  test   %ebx,%ebx
  jns    L5
  mov    -0x20(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L71
L5:
  movslq %ebx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L71:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string

tool: D0: .

assistant: ```c
void get_path(char *str, char *path) {
  register int i;
  strcpy(path, str);
  for (i = strlen(path) - 1; i > -1; --i) {
    if (str[i] == '\\') {
      i = -1;
      break;
    }
    if (str[i] == '.')
      break;
  }
  if (i < 0)
    strcat(path, ".");
  else
    path[i + 1] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_path>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L41
  cltq
L21:
  movzbl (%rbx,%rax,1),%edx
  cmp    $0x5c,%dl
  je     L41
  cmp    $0x2e,%dl
  je     L47
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L21
L41:
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  jmp    L40
L47:
  test   %eax,%eax
  js     L41
  movslq %eax,%rcx
  movb   $0x0,0x1(%rbp,%rcx,1)
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: .

assistant: ```c
void get_path(char *str, char *path) {
  register int i;
  strcpy(path, str);
  for (i = strlen(path) - 1; i > -1; --i) {
    if (str[i] == '\\') {
      i = -1;
      break;
    }
    if (str[i] == '.')
      break;
  }
  if (i < 0)
    strcat(path, ".");
  else
    path[i + 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_path>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L26
  cltq
  jmp    L19
  nopl   0x0(%rax)
L2:
  cmp    $0x2e,%dl
  je     L14
  sub    $0x1,%rax
  test   %eax,%eax
  js     L26
L19:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%ecx
  cmp    $0x5c,%dl
  jne    L2
L26:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1090 <strcat@plt>
  nopl   (%rax)
L14:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movb   $0x0,0x0(%rbp,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: .

assistant: ```c
void get_path(char *str, char *path) {
  register int i;
  strcpy(path, str);
  for (i = strlen(path) - 1; i > -1; --i) {
    if (str[i] == '\\') {
      i = -1;
      break;
    }
    if (str[i] == '.')
      break;
  }
  if (i < 0)
    strcat(path, ".");
  else
    path[i + 1] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_path>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L43
  cltq
  jmp    L20
  nopl   0x0(%rax)
L23:
  cmp    $0x2e,%dl
  je     L0
  sub    $0x1,%rax
  test   %eax,%eax
  js     L43
L20:
  movzbl (%rbx,%rax,1),%edx
  mov    %eax,%ecx
  cmp    $0x5c,%dl
  jne    L23
L43:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1090 <strcat@plt>
  nopl   (%rax)
L0:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  movb   $0x0,0x0(%rbp,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: .

assistant: ```c
void get_path(char *str, char *path) {
  register int i;
  strcpy(path, str);
  for (i = strlen(path) - 1; i > -1; --i) {
    if (str[i] == '\\') {
      i = -1;
      break;
    }
    if (str[i] == '.')
      break;
  }
  if (i < 0)
    strcat(path, ".");
  else
    path[i + 1] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<hsv>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdx,%r10
  mov    %ecx,%edx
  movslq %ecx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x5,%eax
  sar    $0x1f,%ecx
  mov    %eax,%ebp
  sub    %ecx,%ebp
  imul   $0x3c,%ebp,%r11d
  sub    %r11d,%edx
  mov    %edx,%ebp
  mov    %r8d,%r11d
  imul   %r9d,%r11d
  movslq %r11d,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %r11d,%edx
  sar    $0x7,%edx
  mov    %r11d,%ebx
  sar    $0x1f,%ebx
  sub    %edx,%ebx
  add    %r9d,%ebx
  mov    %r11d,%edx
  imul   %ebp,%edx
  movslq %edx,%r8
  imul   $0x22d915d5,%r8,%r8
  sar    $0x2b,%r8
  sar    $0x1f,%edx
  sub    %r8d,%edx
  add    %r9d,%edx
  mov    $0x3b,%r8d
  sub    %ebp,%r8d
  imul   %r11d,%r8d
  movslq %r8d,%r11
  imul   $0x22d915d5,%r11,%r11
  sar    $0x2b,%r11
  sar    $0x1f,%r8d
  sub    %r11d,%r8d
  add    %r9d,%r8d
  sub    %ecx,%eax
  movslq %eax,%rcx
  imul   $0x2aaaaaab,%rcx,%rcx
  shr    $0x20,%rcx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%ecx
  lea    (%rcx,%rcx,2),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  cmp    $0x5,%eax
  ja     L34
  mov    %eax,%eax
  lea    D9(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  mov    %r9d,(%rdi)
  mov    %r8d,(%rsi)
  mov    %ebx,(%r10)
L34:
  pop    %rbx
  pop    %rbp
  ret
  mov    %edx,(%rdi)
  mov    %r9d,(%rsi)
  mov    %ebx,(%r10)
  jmp    L34
  mov    %ebx,(%rdi)
  mov    %r9d,(%rsi)
  mov    %r8d,(%r10)
  jmp    L34
  mov    %ebx,(%rdi)
  mov    %edx,(%rsi)
  mov    %r9d,(%r10)
  jmp    L34
  mov    %r8d,(%rdi)
  mov    %ebx,(%rsi)
  mov    %r9d,(%r10)
  jmp    L34
  mov    %r9d,(%rdi)
  mov    %ebx,(%rsi)
  mov    %edx,(%r10)
  jmp    L34
```

assistant: ```c
void hsv(uint8_t *r, uint8_t *g, uint8_t *b, uint16_t h, uint8_t s, uint8_t v) {
  uint8_t i, f, p, q, t;
  i = h / 60;
  f = h % 60;
  p = v - ((uint16_t)v * s) / 255;
  q = v - ((uint32_t)v * s * f) / (255 * 59);
  t = v - ((uint32_t)v * s * (59 - f)) / (255 * 59);
  switch (i % 6) {
  case 0:
    *r = v;
    *g = t;
    *b = p;
    break;
  case 1:
    *r = q;
    *g = v;
    *b = p;
    break;
  case 2:
    *r = p;
    *g = v;
    *b = t;
    break;
  case 3:
    *r = p;
    *g = q;
    *b = v;
    break;
  case 4:
    *r = t;
    *g = p;
    *b = v;
    break;
  case 5:
    *r = v;
    *g = p;
    *b = q;
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nrf_powerup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <nrf_powerup_nodelay@plt>
  mov    $0x2,%edi
  call   <delay_ms@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nrf_powerup() {
  nrf_powerup_nodelay();
  delay_ms(2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nrf_powerup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nrf_powerup_nodelay@plt>
  mov    $0x2,%edi
  call   <delay_ms@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nrf_powerup() {
  nrf_powerup_nodelay();
  delay_ms(2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nrf_powerup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nrf_powerup_nodelay@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <delay_ms@plt>
```

assistant: ```c
void nrf_powerup() {
  nrf_powerup_nodelay();
  delay_ms(2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nrf_powerup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nrf_powerup_nodelay@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <delay_ms@plt>
```

assistant: ```c
void nrf_powerup() {
  nrf_powerup_nodelay();
  delay_ms(2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L4
L2:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cmp    $0x14,%eax
  seta   %dl
  test   %dl,%dl
  jne    L4
  mov    $0x104111,%edx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L4
  addl   $0x1,-0x8(%rbp)
  nop
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L2
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D13: Enter a sentence: 

tool: D11: That sentence contains %d vowels.


assistant: ```c
int main(void) {
  int count = 0;
  int vowel;
  printf("Enter a sentence: ");
  while ((vowel = getchar()) != '\n') {
    switch (toupper(vowel)) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      count++;
      break;
    }
  }
  printf("That sentence contains %d vowels.\n", count);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  mov    $0x104111,%ebp
L23:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L14
  call   <toupper@plt>
  lea    -0x41(%rax),%ecx
  cmp    $0x14,%ecx
  ja     L23
  mov    %rbp,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  add    %eax,%ebx
  jmp    L23
L14:
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D1: Enter a sentence: 

tool: D9: That sentence contains %d vowels.


assistant: ```c
int main(void) {
  int count = 0;
  int vowel;
  printf("Enter a sentence: ");
  while ((vowel = getchar()) != '\n') {
    switch (toupper(vowel)) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      count++;
      break;
    }
  }
  printf("That sentence contains %d vowels.\n", count);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x104111,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L16:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L19
L26:
  call   <toupper@plt>
  lea    -0x41(%rax),%ecx
  cmp    $0x14,%ecx
  ja     L16
  mov    %rbx,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    $0xffffffff,%ebp
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  jne    L26
L19:
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D0: Enter a sentence: 

tool: D3: That sentence contains %d vowels.


assistant: ```c
int main(void) {
  int count = 0;
  int vowel;
  printf("Enter a sentence: ");
  while ((vowel = getchar()) != '\n') {
    switch (toupper(vowel)) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      count++;
      break;
    }
  }
  printf("That sentence contains %d vowels.\n", count);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x104111,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L14
L25:
  call   <toupper@plt>
  lea    -0x41(%rax),%ecx
  cmp    $0x14,%ecx
  ja     L17
  mov    %rbx,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x1,%al
  sbb    $0xffffffff,%ebp
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  jne    L25
L14:
  mov    %ebp,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string

tool: D13: Enter a sentence: 

tool: D16: That sentence contains %d vowels.


assistant: ```c
int main(void) {
  int count = 0;
  int vowel;
  printf("Enter a sentence: ");
  while ((vowel = getchar()) != '\n') {
    switch (toupper(vowel)) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      count++;
      break;
    }
  }
  printf("That sentence contains %d vowels.\n", count);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yyx_calc_posterior>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  movq   %xmm0,%r13
  movsd  0x10(%rdi),%xmm0
  movapd %xmm0,%xmm2
  addsd  0x10(%rsi),%xmm2
  movq   %xmm2,%r15
  movsd  (%rdi),%xmm0
  addsd  (%rsi),%xmm0
  movapd %xmm0,%xmm1
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm2,%xmm0
  call   <log10_add_pow10@plt>
  movsd  0x8(%r12),%xmm1
  addsd  0x8(%rbp),%xmm1
  movsd  %xmm1,0x18(%rsp)
  call   <log10_add_pow10@plt>
  movq   %xmm0,%r14
  movsd  0x18(%r12),%xmm0
  addsd  0x18(%rbp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movq   %r13,%xmm0
  call   <log10@plt>
  movapd %xmm0,%xmm4
  addsd  0x8(%rsp),%xmm4
  movq   %xmm4,%rbp
  movapd %xmm4,%xmm1
  movq   %r14,%xmm0
  call   <log10_add_pow10@plt>
  movsd  0x10(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rbx)
  movsd  0x18(%rsp),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbx)
  movq   %r15,%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rbx)
  movq   %rbp,%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rbx)
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double *yyx_calc_posterior(const double *log10_prior_vec, const double *log10_likelihood_vec, double *tmp_four_double_vec, double base_change_relative_rate) {
  double alt_hom_log10_posterior = log10_prior_vec[2] + log10_likelihood_vec[2];
  double ref_hom_log10_posterior = log10_prior_vec[0] + log10_likelihood_vec[0];
  double log10_posterior_normalization_constant = log10_add_pow10(alt_hom_log10_posterior, ref_hom_log10_posterior);
  double het_log10_posterior = log10_prior_vec[1] + log10_likelihood_vec[1];
  log10_posterior_normalization_constant = log10_add_pow10(log10_posterior_normalization_constant, het_log10_posterior);
  double mosaic_log10_posterior = log10_prior_vec[3] + log10_likelihood_vec[3] + log10(base_change_relative_rate);
  log10_posterior_normalization_constant = log10_add_pow10(log10_posterior_normalization_constant, mosaic_log10_posterior);
  tmp_four_double_vec[0] = ref_hom_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[1] = het_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[2] = alt_hom_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[3] = mosaic_log10_posterior - log10_posterior_normalization_constant;
  return tmp_four_double_vec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yyx_calc_posterior>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x30,%rsp
  movsd  0x10(%rdi),%xmm2
  movsd  (%rdi),%xmm4
  addsd  0x10(%rsi),%xmm2
  addsd  (%rsi),%xmm4
  movsd  %xmm0,0x28(%rsp)
  movapd %xmm4,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm4,0x20(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <log10_add_pow10@plt>
  movsd  0x8(%rbp),%xmm3
  addsd  0x8(%rbx),%xmm3
  movapd %xmm3,%xmm1
  movsd  %xmm3,0x10(%rsp)
  call   <log10_add_pow10@plt>
  movsd  0x28(%rsp),%xmm6
  movsd  %xmm0,0x8(%rsp)
  movsd  0x18(%rbp),%xmm0
  addsd  0x18(%rbx),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm6,%xmm0
  call   <log10@plt>
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm5
  addsd  %xmm0,%xmm1
  movapd %xmm5,%xmm0
  movsd  %xmm1,(%rsp)
  call   <log10_add_pow10@plt>
  movsd  0x20(%rsp),%xmm4
  movsd  0x10(%rsp),%xmm3
  mov    %r12,%rax
  movsd  0x18(%rsp),%xmm2
  movsd  (%rsp),%xmm1
  subsd  %xmm0,%xmm4
  subsd  %xmm0,%xmm3
  subsd  %xmm0,%xmm2
  subsd  %xmm0,%xmm1
  movsd  %xmm4,(%r12)
  movsd  %xmm3,0x8(%r12)
  movsd  %xmm2,0x10(%r12)
  movsd  %xmm1,0x18(%r12)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *yyx_calc_posterior(const double *log10_prior_vec, const double *log10_likelihood_vec, double *tmp_four_double_vec, double base_change_relative_rate) {
  double alt_hom_log10_posterior = log10_prior_vec[2] + log10_likelihood_vec[2];
  double ref_hom_log10_posterior = log10_prior_vec[0] + log10_likelihood_vec[0];
  double log10_posterior_normalization_constant = log10_add_pow10(alt_hom_log10_posterior, ref_hom_log10_posterior);
  double het_log10_posterior = log10_prior_vec[1] + log10_likelihood_vec[1];
  log10_posterior_normalization_constant = log10_add_pow10(log10_posterior_normalization_constant, het_log10_posterior);
  double mosaic_log10_posterior = log10_prior_vec[3] + log10_likelihood_vec[3] + log10(base_change_relative_rate);
  log10_posterior_normalization_constant = log10_add_pow10(log10_posterior_normalization_constant, mosaic_log10_posterior);
  tmp_four_double_vec[0] = ref_hom_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[1] = het_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[2] = alt_hom_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[3] = mosaic_log10_posterior - log10_posterior_normalization_constant;
  return tmp_four_double_vec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<yyx_calc_posterior>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x40,%rsp
  movsd  0x10(%rdi),%xmm2
  movsd  (%rdi),%xmm3
  addsd  0x10(%rsi),%xmm2
  addsd  (%rsi),%xmm3
  movsd  %xmm0,0x38(%rsp)
  movapd %xmm3,%xmm1
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x30(%rsp)
  movsd  %xmm3,(%rsp)
  call   <log10_add_pow10@plt>
  movsd  0x8(%rbp),%xmm1
  addsd  0x8(%rbx),%xmm1
  movsd  (%rsp),%xmm3
  unpcklpd %xmm1,%xmm3
  movaps %xmm3,0x20(%rsp)
  call   <log10_add_pow10@plt>
  movsd  0x38(%rsp),%xmm5
  movsd  %xmm0,0x18(%rsp)
  movsd  0x18(%rbp),%xmm0
  addsd  0x18(%rbx),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm5,%xmm0
  call   <log10@plt>
  movsd  (%rsp),%xmm1
  movsd  0x30(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm4
  addsd  %xmm0,%xmm1
  movapd %xmm4,%xmm0
  unpcklpd %xmm1,%xmm2
  movaps %xmm2,(%rsp)
  call   <log10_add_pow10@plt>
  movapd 0x20(%rsp),%xmm3
  movapd (%rsp),%xmm2
  mov    %r12,%rax
  unpcklpd %xmm0,%xmm0
  subpd  %xmm0,%xmm3
  subpd  %xmm0,%xmm2
  movups %xmm3,(%r12)
  movups %xmm2,0x10(%r12)
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *yyx_calc_posterior(const double *log10_prior_vec, const double *log10_likelihood_vec, double *tmp_four_double_vec, double base_change_relative_rate) {
  double alt_hom_log10_posterior = log10_prior_vec[2] + log10_likelihood_vec[2];
  double ref_hom_log10_posterior = log10_prior_vec[0] + log10_likelihood_vec[0];
  double log10_posterior_normalization_constant = log10_add_pow10(alt_hom_log10_posterior, ref_hom_log10_posterior);
  double het_log10_posterior = log10_prior_vec[1] + log10_likelihood_vec[1];
  log10_posterior_normalization_constant = log10_add_pow10(log10_posterior_normalization_constant, het_log10_posterior);
  double mosaic_log10_posterior = log10_prior_vec[3] + log10_likelihood_vec[3] + log10(base_change_relative_rate);
  log10_posterior_normalization_constant = log10_add_pow10(log10_posterior_normalization_constant, mosaic_log10_posterior);
  tmp_four_double_vec[0] = ref_hom_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[1] = het_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[2] = alt_hom_log10_posterior - log10_posterior_normalization_constant;
  tmp_four_double_vec[3] = mosaic_log10_posterior - log10_posterior_normalization_constant;
  return tmp_four_double_vec;
}
```