ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getbits>:
  endbr64
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L59:
  movsbl 0x0(%rbp,%rbx,1),%esi
  test   %sil,%sil
  je     L32
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L66
  test   %ebx,%ebx
  je     L14
  test   %r13d,%r13d
  je     L66
L14:
  sub    %r14,%rax
  lea    0x0(%r13,%r13,4),%edx
  add    $0x1,%rbx
  lea    (%rax,%rdx,2),%r13d
  cmp    $0x80,%r13d
  jle    L59
L66:
  xor    %eax,%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  test   %ebx,%ebx
  je     L66
  mov    %r13d,(%r12)
  mov    $0x1,%eax
  jmp    L37
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: 0123456789

assistant: ```c
int getbits(const char *src, int *bitsp) {
  static const char digits[] = "0123456789";
  int n;
  int val;
  char ch;
  val = 0;
  n = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    pch = strchr(digits, ch);
    if (pch != NULL) {
      if (n++ != 0 && val == 0)
        return (0);
      val *= 10;
      val += (pch - digits);
      if (val > 128)
        return (0);
      continue;
    }
    return (0);
  }
  if (n == 0)
    return (0);
  *bitsp = val;
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getbits>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L17:
  movsbl 0x0(%rbp,%rbx,1),%esi
  test   %sil,%sil
  je     L48
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L69
  test   %ebx,%ebx
  je     L43
  test   %r13d,%r13d
  je     L69
L43:
  sub    %r14,%rax
  lea    0x0(%r13,%r13,4),%edx
  add    $0x1,%rbx
  lea    (%rax,%rdx,2),%r13d
  cmp    $0x80,%r13d
  jle    L17
L69:
  xor    %eax,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  test   %ebx,%ebx
  je     L69
  mov    %r13d,(%r12)
  mov    $0x1,%eax
  jmp    L45
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: 0123456789

assistant: ```c
int getbits(const char *src, int *bitsp) {
  static const char digits[] = "0123456789";
  int n;
  int val;
  char ch;
  val = 0;
  n = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    pch = strchr(digits, ch);
    if (pch != NULL) {
      if (n++ != 0 && val == 0)
        return (0);
      val *= 10;
      val += (pch - digits);
      if (val > 128)
        return (0);
      continue;
    }
    return (0);
  }
  if (n == 0)
    return (0);
  *bitsp = val;
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ExtMcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x4(%rbp),%eax
  jmp    L7
L17:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ExtMcd>
L7:
  leave
  ret
```

assistant: ```c
int ExtMcd(int num1, int num2) {
  if (num2 % num1 == 0)
    return num1;
  else
    return ExtMcd(num2 % num1, num1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ExtMcd>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L1
  mov    %edi,%eax
  ret
L1:
  sub    $0x8,%rsp
  mov    %edi,%esi
  mov    %edx,%edi
  call   <ExtMcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ExtMcd(int num1, int num2) {
  if (num2 % num1 == 0)
    return num1;
  else
    return ExtMcd(num2 % num1, num1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ExtMcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edx,%r8d
L8:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L3
  ret
```

assistant: ```c
int ExtMcd(int num1, int num2) {
  if (num2 % num1 == 0)
    return num1;
  else
    return ExtMcd(num2 % num1, num1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ExtMcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edx,%r8d
L12:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L2
  ret
```

assistant: ```c
int ExtMcd(int num1, int num2) {
  if (num2 % num1 == 0)
    return num1;
  else
    return ExtMcd(num2 % num1, num1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_instruction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readbits@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L106
  movl   $0x0,-0x8(%rbp)
  jmp    L74
L106:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readbits@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L65
  movl   $0x1,-0x8(%rbp)
  jmp    L74
L65:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readbits@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L121
  movl   $0x2,-0x8(%rbp)
  jmp    L74
L121:
  cmpl   $0x1,-0x4(%rbp)
  jne    L11
  movl   $0x3,-0x8(%rbp)
  jmp    L74
L11:
  cmpl   $0x2,-0x4(%rbp)
  jne    L49
  movl   $0x4,-0x8(%rbp)
  jmp    L74
L49:
  cmpl   $0x3,-0x4(%rbp)
  jne    L74
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <readbits@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L52
  movl   $0x5,-0x8(%rbp)
  jmp    L74
L52:
  movl   $0x6,-0x8(%rbp)
L74:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_instruction(unsigned char **ptr, int *bitptr) {
  int instr = -1;
  unsigned int bits = readbits(ptr, bitptr, 1);
  if (bits)
    instr = 0;
  else {
    bits = readbits(ptr, bitptr, 1);
    if (!bits)
      instr = 1;
    else {
      bits = readbits(ptr, bitptr, 2);
      if (bits == 0)
        instr = 2;
      else if (bits == 1)
        instr = 3;
      else if (bits == 2)
        instr = 4;
      else if (bits == 3) {
        bits = readbits(ptr, bitptr, 1);
        if (bits == 0)
          instr = 5;
        else
          instr = 6;
      }
    }
  }
  return instr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_instruction>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x1,%edx
  call   <readbits@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L62
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L62:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readbits@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L9
  mov    $0x2,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readbits@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L9
  mov    $0x3,%eax
  cmp    $0x1,%edx
  je     L9
  mov    $0x4,%eax
  cmp    $0x2,%edx
  je     L9
  cmp    $0x3,%edx
  jne    L19
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readbits@plt>
  cmp    $0x1,%eax
  mov    $0x5,%eax
  sbb    $0xffffffff,%eax
  jmp    L9
L19:
  mov    $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int read_instruction(unsigned char **ptr, int *bitptr) {
  int instr = -1;
  unsigned int bits = readbits(ptr, bitptr, 1);
  if (bits)
    instr = 0;
  else {
    bits = readbits(ptr, bitptr, 1);
    if (!bits)
      instr = 1;
    else {
      bits = readbits(ptr, bitptr, 2);
      if (bits == 0)
        instr = 2;
      else if (bits == 1)
        instr = 3;
      else if (bits == 2)
        instr = 4;
      else if (bits == 3) {
        bits = readbits(ptr, bitptr, 1);
        if (bits == 0)
          instr = 5;
        else
          instr = 6;
      }
    }
  }
  return instr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_instruction>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <readbits@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L36
L14:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L36:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readbits@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L14
  mov    $0x2,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readbits@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L14
  mov    $0x3,%eax
  cmp    $0x1,%edx
  je     L14
  mov    $0x4,%eax
  cmp    $0x2,%edx
  je     L14
  cmp    $0x3,%edx
  jne    L58
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readbits@plt>
  cmp    $0x1,%eax
  mov    $0x5,%eax
  sbb    $0xffffffff,%eax
  jmp    L14
L58:
  mov    $0xffffffff,%eax
  jmp    L14
```

assistant: ```c
int read_instruction(unsigned char **ptr, int *bitptr) {
  int instr = -1;
  unsigned int bits = readbits(ptr, bitptr, 1);
  if (bits)
    instr = 0;
  else {
    bits = readbits(ptr, bitptr, 1);
    if (!bits)
      instr = 1;
    else {
      bits = readbits(ptr, bitptr, 2);
      if (bits == 0)
        instr = 2;
      else if (bits == 1)
        instr = 3;
      else if (bits == 2)
        instr = 4;
      else if (bits == 3) {
        bits = readbits(ptr, bitptr, 1);
        if (bits == 0)
          instr = 5;
        else
          instr = 6;
      }
    }
  }
  return instr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<read_instruction>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <readbits@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  je     L17
L50:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L17:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readbits@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L50
  mov    $0x2,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readbits@plt>
  mov    %eax,%edx
  mov    $0x2,%eax
  test   %edx,%edx
  je     L50
  mov    $0x3,%eax
  cmp    $0x1,%edx
  je     L50
  mov    $0x4,%eax
  cmp    $0x2,%edx
  je     L50
  cmp    $0x3,%edx
  jne    L26
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readbits@plt>
  cmp    $0x1,%eax
  mov    $0x5,%eax
  sbb    $0xffffffff,%eax
  jmp    L50
L26:
  mov    $0xffffffff,%eax
  jmp    L50
```

assistant: ```c
int read_instruction(unsigned char **ptr, int *bitptr) {
  int instr = -1;
  unsigned int bits = readbits(ptr, bitptr, 1);
  if (bits)
    instr = 0;
  else {
    bits = readbits(ptr, bitptr, 1);
    if (!bits)
      instr = 1;
    else {
      bits = readbits(ptr, bitptr, 2);
      if (bits == 0)
        instr = 2;
      else if (bits == 1)
        instr = 3;
      else if (bits == 2)
        instr = 4;
      else if (bits == 3) {
        bits = readbits(ptr, bitptr, 1);
        if (bits == 0)
          instr = 5;
        else
          instr = 6;
      }
    }
  }
  return instr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<look>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <binary_search@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <linear_search@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <print_from@plt>
L3:
  cmpq   $0x0,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int look(wchar_t *string, unsigned char *front, unsigned char *back) {
  front = binary_search(string, front, back);
  front = linear_search(string, front, back);
  if (front)
    print_from(string, front, back);
  return (front ? 0 : 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<look>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  call   <binary_search@plt>
  mov    %rax,%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <linear_search@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L8
  mov    %r12,%rdx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <print_from@plt>
L8:
  test   %rbx,%rbx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int look(wchar_t *string, unsigned char *front, unsigned char *back) {
  front = binary_search(string, front, back);
  front = linear_search(string, front, back);
  if (front)
    print_from(string, front, back);
  return (front ? 0 : 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<look>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <binary_search@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <linear_search@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %r12,%rdx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <print_from@plt>
L9:
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
```

assistant: ```c
int look(wchar_t *string, unsigned char *front, unsigned char *back) {
  front = binary_search(string, front, back);
  front = linear_search(string, front, back);
  if (front)
    print_from(string, front, back);
  return (front ? 0 : 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<look>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <binary_search@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <linear_search@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %r12,%rdx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <print_from@plt>
L0:
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
```

assistant: ```c
int look(wchar_t *string, unsigned char *front, unsigned char *back) {
  front = binary_search(string, front, back);
  front = linear_search(string, front, back);
  if (front)
    print_from(string, front, back);
  return (front ? 0 : 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PECIIntRegister>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x400b0000,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7b,%edi
  call   <IntRegister@plt>
  mov    $0x7b,%edi
  call   <IntEnable@plt>
  nop
  leave
  ret
```

assistant: ```c
void PECIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(pfnHandler != 0);
  IntRegister(123, pfnHandler);
  IntEnable(123);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PECIIntRegister>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x400b0000,%rdi
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %rbx,%rsi
  mov    $0x7b,%edi
  call   <IntRegister@plt>
  mov    $0x7b,%edi
  call   <IntEnable@plt>
  pop    %rbx
  ret
```

assistant: ```c
void PECIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(pfnHandler != 0);
  IntRegister(123, pfnHandler);
  IntEnable(123);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PECIIntRegister>:
  endbr64
  push   %rbp
  cmp    $0x400b0000,%rdi
  mov    %rsi,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,%rsi
  mov    $0x7b,%edi
  call   <IntRegister@plt>
  mov    $0x7b,%edi
  pop    %rbp
  jmp    1090 <IntEnable@plt>
```

assistant: ```c
void PECIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(pfnHandler != 0);
  IntRegister(123, pfnHandler);
  IntEnable(123);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<PECIIntRegister>:
  endbr64
  push   %rbp
  cmp    $0x400b0000,%rdi
  mov    %rsi,%rbp
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <DEBUG_ASSERT@plt>
  mov    %rbp,%rsi
  mov    $0x7b,%edi
  call   <IntRegister@plt>
  mov    $0x7b,%edi
  pop    %rbp
  jmp    1090 <IntEnable@plt>
```

assistant: ```c
void PECIIntRegister(unsigned long ulBase, void (*pfnHandler)(void)) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(pfnHandler != 0);
  IntRegister(123, pfnHandler);
  IntEnable(123);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x45,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  lea    -0x2e(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 343007618UL) + (unsigned char)84;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x17,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 343007618UL) + (unsigned char)84;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x17,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 343007618UL) + (unsigned char)84;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  add    $0x17,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = input[0UL] + (unsigned char)69;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      local2 = 0UL;
      while (local2 < (unsigned char)0) {
        state[0UL] = state[local1] - state[0UL];
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 343007618UL) + (unsigned char)84;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %edi,-0x154(%rbp)
  mov    %esi,-0x158(%rbp)
  mov    %rdx,-0x160(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x154(%rbp),%eax
  mov    %eax,-0x150(%rbp)
  movl   $0x0,-0x14c(%rbp)
  jmp    L27
L26:
  mov    -0x150(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x160(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14c(%rbp),%eax
  cltq
  mov    %dl,-0x140(%rbp,%rax,1)
  addl   $0x1,-0x14c(%rbp)
  addl   $0x1,-0x150(%rbp)
L27:
  mov    -0x158(%rbp),%eax
  cmp    -0x150(%rbp),%eax
  jge    L26
  lea    -0x140(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x148(%rbp)
  mov    -0x150(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x148(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x148(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
char *substr(int start, int end, char *str) {
  int i = start;
  int newStrIndex = 0;
  char newStr[300];
  for (; i < end + 1; i++) {
    newStr[newStrIndex] = str[i];
    newStrIndex++;
  }
  char *ret = strdup(newStr);
  ret[i] = '\0';
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<substr>:
  endbr64
  push   %rbx
  sub    $0x140,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  cmp    %esi,%edi
  jg     L19
  movslq %edi,%rbx
  mov    %rbx,%rax
  mov    %rsp,%rdi
  sub    %rbx,%rdi
L15:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%esi
  jge    L15
  lea    0x1(%rsi),%ebx
L19:
  mov    %rsp,%rdi
  call   <strdup@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  mov    0x138(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x140,%rsp
  pop    %rbx
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *substr(int start, int end, char *str) {
  int i = start;
  int newStrIndex = 0;
  char newStr[300];
  for (; i < end + 1; i++) {
    newStr[newStrIndex] = str[i];
    newStrIndex++;
  }
  char *ret = strdup(newStr);
  ret[i] = '\0';
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<substr>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  cmp    %esi,%ebx
  jg     L12
  mov    %esi,%r8d
  mov    %esi,%ebp
  lea    (%rdx,%rbx,1),%rsi
  mov    %rsp,%rdi
  sub    %ebx,%r8d
  lea    0x1(%rbp),%ebx
  add    $0x1,%r8
  mov    %r8,%rdx
  call   <memcpy@plt>
  mov    %rax,%rdi
L12:
  call   <strdup@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  mov    0x138(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *substr(int start, int end, char *str) {
  int i = start;
  int newStrIndex = 0;
  char newStr[300];
  for (; i < end + 1; i++) {
    newStr[newStrIndex] = str[i];
    newStrIndex++;
  }
  char *ret = strdup(newStr);
  ret[i] = '\0';
  return ret;
}
```