ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<i2cWriteWord>:
  endbr64
  sub    $0x8,%rsp
  movzwl %dx,%edx
  movzbl %sil,%esi
  call   <i2c_smbus_write_word_data@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int i2cWriteWord(int i2cAdapter, unsigned char address, unsigned short word) {
  if (i2c_smbus_write_word_data(i2cAdapter, address, word)) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Strcpy3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L12
L4:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Strcpy3(char *t, char *s) {
  while (*s = *t) {
    s++;
    t++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Strcpy3>:
  endbr64
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %al,%al
  je     L0
  mov    $0x1,%eax
L8:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L8
L0:
  ret
```

assistant: ```c
void Strcpy3(char *t, char *s) {
  while (*s = *t) {
    s++;
    t++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Strcpy3>:
  endbr64
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %al,%al
  je     L14
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L12
L14:
  ret
```

assistant: ```c
void Strcpy3(char *t, char *s) {
  while (*s = *t) {
    s++;
    t++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Strcpy3>:
  endbr64
  movzbl (%rdi),%eax
  mov    %al,(%rsi)
  test   %al,%al
  je     L5
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L9
L5:
  ret
```

assistant: ```c
void Strcpy3(char *t, char *s) {
  while (*s = *t) {
    s++;
    t++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op0x37>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x10,%edi
  call   <set_flag@plt>
  mov    $0x40,%edi
  call   <reset_flag@plt>
  mov    $0x20,%edi
  call   <reset_flag@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op0x37(void) {
  set_flag(0x10);
  reset_flag(0x40);
  reset_flag(0x20);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<op0x37>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%edi
  call   <set_flag@plt>
  mov    $0x40,%edi
  call   <reset_flag@plt>
  mov    $0x20,%edi
  call   <reset_flag@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op0x37(void) {
  set_flag(0x10);
  reset_flag(0x40);
  reset_flag(0x20);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<op0x37>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%edi
  call   <set_flag@plt>
  mov    $0x40,%edi
  call   <reset_flag@plt>
  mov    $0x20,%edi
  add    $0x8,%rsp
  jmp    1070 <reset_flag@plt>
```

assistant: ```c
void op0x37(void) {
  set_flag(0x10);
  reset_flag(0x40);
  reset_flag(0x20);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<op0x37>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%edi
  call   <set_flag@plt>
  mov    $0x40,%edi
  call   <reset_flag@plt>
  mov    $0x20,%edi
  add    $0x8,%rsp
  jmp    1070 <reset_flag@plt>
```

assistant: ```c
void op0x37(void) {
  set_flag(0x10);
  reset_flag(0x40);
  reset_flag(0x20);
}
```
user: Translate the below assembly code into C programming language:

```asm
<setRHS2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L27
L24:
  movl   $0x1,-0x14(%rbp)
  jmp    L29
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    -0x18(%rbp),%ecx
  movslq %ecx,%rcx
  lea    0x0(,%rcx,8),%rsi
  mov    -0x28(%rbp),%rcx
  add    %rsi,%rcx
  mov    (%rcx),%rsi
  mov    -0x14(%rbp),%ecx
  movslq %ecx,%rcx
  shl    $0x3,%rcx
  lea    (%rsi,%rcx,1),%rbx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <f@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L29:
  mov    -0x40(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L5
  addl   $0x1,-0x18(%rbp)
L27:
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L24
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double **setRHS2D(double **array2D, double dx, double dy, int nX, int nY) {
  int i, j;
  for (i = 1; i < nX - 1; i++) {
    for (j = 1; j < nY - 1; j++) {
      array2D[i][j] = f(i * dx, j * dy);
    }
  }
  return array2D;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setRHS2D>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x28(%rsp)
  movsd  %xmm0,0x20(%rsp)
  movsd  %xmm1,0x8(%rsp)
  mov    %edx,0x18(%rsp)
  cmp    $0x2,%esi
  jle    L54
  lea    0x8(%rdi),%r13
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  movl   $0x1,0x14(%rsp)
  lea    -0x1(%rdx),%r15d
  jmp    L7
L14:
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm0
  mulsd  0x20(%rsp),%xmm0
  cvttsd2si %xmm0,%r14d
  mov    $0x8,%ebp
  mov    $0x1,%ebx
L8:
  mov    %rbp,%r12
  add    0x0(%r13),%r12
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%esi
  mov    %r14d,%edi
  call   <f@plt>
  movsd  %xmm0,(%r12)
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r15d
  jne    L8
L38:
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  add    $0x8,%r13
  cmp    0x1c(%rsp),%eax
  je     L54
L7:
  cmpl   $0x2,0x18(%rsp)
  jg     L14
  jmp    L38
L54:
  mov    0x28(%rsp),%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **setRHS2D(double **array2D, double dx, double dy, int nX, int nY) {
  int i, j;
  for (i = 1; i < nX - 1; i++) {
    for (j = 1; j < nY - 1; j++) {
      array2D[i][j] = f(i * dx, j * dy);
    }
  }
  return array2D;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<setRHS2D>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %eax,0xc(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,(%rsp)
  cmp    $0x1,%eax
  jle    L17
  movl   $0x1,0x8(%rsp)
  lea    -0x1(%rdx),%ebp
  lea    0x8(%rdi),%rbx
  nopl   0x0(%rax)
L2:
  cmp    $0x1,%ebp
  jle    L13
  pxor   %xmm0,%xmm0
  mov    $0x8,%r14d
  mov    $0x1,%r15d
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%r12d
  xchg   %ax,%ax
L31:
  pxor   %xmm0,%xmm0
  mov    (%rbx),%r13
  mov    %r12d,%edi
  cvtsi2sd %r15d,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x1,%r15d
  add    %r14,%r13
  add    $0x8,%r14
  cvttsd2si %xmm0,%esi
  call   <f@plt>
  movsd  %xmm0,0x0(%r13)
  cmp    %r15d,%ebp
  jne    L31
L13:
  addl   $0x1,0x8(%rsp)
  add    $0x8,%rbx
  mov    0x8(%rsp),%eax
  cmp    0xc(%rsp),%eax
  jne    L2
L17:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **setRHS2D(double **array2D, double dx, double dy, int nX, int nY) {
  int i, j;
  for (i = 1; i < nX - 1; i++) {
    for (j = 1; j < nY - 1; j++) {
      array2D[i][j] = f(i * dx, j * dy);
    }
  }
  return array2D;
}
```
user: What is the c source code of the assembly code below?

```asm
<setRHS2D>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %eax,0xc(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,(%rsp)
  cmp    $0x1,%eax
  jle    L37
  lea    -0x1(%rdx),%r12d
  cmp    $0x1,%r12d
  jle    L37
  movl   $0x1,0x8(%rsp)
  lea    0x8(%rdi),%rbx
  nopl   0x0(%rax,%rax,1)
L25:
  pxor   %xmm0,%xmm0
  mov    $0x8,%r14d
  mov    $0x1,%r15d
  cvtsi2sdl 0x8(%rsp),%xmm0
  mulsd  0x10(%rsp),%xmm0
  cvttsd2si %xmm0,%ebp
L6:
  pxor   %xmm0,%xmm0
  mov    (%rbx),%r13
  mov    %ebp,%edi
  cvtsi2sd %r15d,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x1,%r15d
  add    %r14,%r13
  add    $0x8,%r14
  cvttsd2si %xmm0,%esi
  call   <f@plt>
  movsd  %xmm0,0x0(%r13)
  cmp    %r12d,%r15d
  jne    L6
  addl   $0x1,0x8(%rsp)
  add    $0x8,%rbx
  mov    0x8(%rsp),%eax
  cmp    0xc(%rsp),%eax
  jne    L25
L37:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **setRHS2D(double **array2D, double dx, double dy, int nX, int nY) {
  int i, j;
  for (i = 1; i < nX - 1; i++) {
    for (j = 1; j < nY - 1; j++) {
      array2D[i][j] = f(i * dx, j * dy);
    }
  }
  return array2D;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  lea    -0x2(%rdx,%rdx,1),%r14d
  lea    0x1(%r14),%eax
  mov    %eax,0xc(%rsp)
  test   $0x1,%dl
  jne    L167
  lea    -0x2(%rdx),%eax
  lea    -0x2(%r14),%esi
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  imul   %eax,%esi
L119:
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L18
  mov    0xc(%rsp),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%r12d
  mov    $0x0,%ebp
  add    $0x1,%r14d
  jmp    L107
L167:
  lea    -0x3(%rdx),%eax
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  lea    -0x4(%r14),%edx
  imul   %edx,%eax
  lea    -0x3(%r14,%rax,1),%esi
  jmp    L119
L129:
  mov    $0x2a,%edi
  call   <putchar@plt>
  jmp    L154
L131:
  mov    $0x2a,%edi
  call   <putchar@plt>
L154:
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  je     L81
L21:
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  je     L129
  cmp    %r13d,%ebx
  je     L131
  cmp    %r12d,%ebx
  je     L131
  jle    L104
  cmp    %r15d,%ebx
  jl     L78
L104:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L154
L78:
  mov    $0x23,%edi
  call   <putchar@plt>
  jmp    L154
L81:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  sub    $0x1,%r12d
  add    $0x1,%r13d
  cmp    %ebp,0x14(%rsp)
  jle    L18
L107:
  mov    $0x0,%ebx
  mov    %r13d,%r15d
  cmpl   $0x0,0xc(%rsp)
  jg     L21
  jmp    L81
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L133
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L133:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D18: %d

tool: D8: %d


assistant: ```c
int main() {
  int h, base, count;
  scanf("%d", &h);
  base = 1 + (h - 1) * 2;
  int base_hash = base - 4;
  int h_hash = h - 2;
  if (h_hash % 2 == 0)
    count = (base_hash + 1) * (h_hash / 2);
  else
    count = (base_hash - 1) * ((h_hash - 1) / 2) + base_hash;
  printf("%d\n", count);
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < base; j++) {
      if (i == h - 1)
        printf("*");
      else if (j == (base / 2) + i || j == (base / 2) - i)
        printf("*");
      else if (j < (base / 2) + i && j > (base / 2) - i)
        printf("#");
      else
        printf(" ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    -0x2(%rdx,%rdx,1),%r13d
  lea    0x1(%r13),%r15d
  test   $0x1,%dl
  jne    L126
  lea    -0x2(%rdx),%eax
  mov    $0x2,%ecx
  lea    -0x2(%r13),%esi
  cltd
  idiv   %ecx
  imul   %eax,%esi
L86:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L103
  mov    %r15d,%r14d
  xor    %ebp,%ebp
  sar    %r14d
  mov    %r14d,%r12d
  nopl   0x0(%rax)
L49:
  xor    %ebx,%ebx
  test   %r15d,%r15d
  jg     L105
  jmp    L73
  nopl   0x0(%rax)
L116:
  jle    L124
  cmp    %r12d,%ebx
  jl     L68
L124:
  mov    $0x20,%edi
  call   <putchar@plt>
L122:
  lea    0x1(%rbx),%eax
  cmp    %ebx,%r13d
  je     L73
L148:
  mov    %eax,%ebx
L105:
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  je     L135
  cmp    %r12d,%ebx
  je     L135
  cmp    %r14d,%ebx
  jne    L116
L135:
  mov    $0x2a,%edi
  call   <putchar@plt>
  lea    0x1(%rbx),%eax
  cmp    %ebx,%r13d
  jne    L148
L73:
  mov    $0xa,%edi
  add    $0x1,%ebp
  sub    $0x1,%r14d
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %ebp,0x4(%rsp)
  jg     L49
L103:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L68:
  mov    $0x23,%edi
  call   <putchar@plt>
  jmp    L122
L126:
  lea    -0x3(%rdx),%eax
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  lea    -0x4(%r13),%edx
  imul   %edx,%eax
  lea    -0x3(%r13,%rax,1),%esi
  jmp    L86
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
datatype: string
name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D14: %d

tool: D6: %d


assistant: ```c
int main() {
  int h, base, count;
  scanf("%d", &h);
  base = 1 + (h - 1) * 2;
  int base_hash = base - 4;
  int h_hash = h - 2;
  if (h_hash % 2 == 0)
    count = (base_hash + 1) * (h_hash / 2);
  else
    count = (base_hash - 1) * ((h_hash - 1) / 2) + base_hash;
  printf("%d\n", count);
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < base; j++) {
      if (i == h - 1)
        printf("*");
      else if (j == (base / 2) + i || j == (base / 2) - i)
        printf("*");
      else if (j < (base / 2) + i && j > (base / 2) - i)
        printf("#");
      else
        printf(" ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    -0x2(%rdx,%rdx,1),%r13d
  lea    0x1(%r13),%r15d
  test   $0x1,%dl
  jne    L71
  lea    -0x2(%rdx),%eax
  mov    $0x2,%ecx
  lea    -0x2(%r13),%esi
  cltd
  idiv   %ecx
  imul   %eax,%esi
L109:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L52
  mov    %r15d,%r14d
  xor    %ebp,%ebp
  sar    %r14d
  mov    %r14d,%r12d
  nopl   0x0(%rax)
L53:
  xor    %ebx,%ebx
  test   %r15d,%r15d
  jg     L35
  jmp    L34
  nopl   0x0(%rax)
L2:
  jle    L129
  cmp    %ebx,%r12d
  jg     L114
L129:
  mov    $0x20,%edi
  call   <putchar@plt>
L142:
  lea    0x1(%rbx),%edx
  cmp    %ebx,%r13d
  je     L34
L19:
  mov    0x4(%rsp),%eax
  mov    %edx,%ebx
L35:
  sub    $0x1,%eax
  cmp    %ebp,%eax
  je     L31
  cmp    %ebx,%r12d
  je     L31
  cmp    %r14d,%ebx
  jne    L2
L31:
  mov    $0x2a,%edi
  call   <putchar@plt>
  lea    0x1(%rbx),%edx
  cmp    %ebx,%r13d
  jne    L19
L34:
  mov    $0xa,%edi
  add    $0x1,%ebp
  sub    $0x1,%r14d
  add    $0x1,%r12d
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jg     L53
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L121
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L114:
  mov    $0x23,%edi
  call   <putchar@plt>
  jmp    L142
L71:
  lea    -0x3(%rdx),%eax
  mov    $0x2,%ecx
  cltd
  idiv   %ecx
  lea    -0x4(%r13),%edx
  imul   %edx,%eax
  lea    -0x3(%r13,%rax,1),%esi
  jmp    L109
L121:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D13: %d

tool: D3: %d


assistant: ```c
int main() {
  int h, base, count;
  scanf("%d", &h);
  base = 1 + (h - 1) * 2;
  int base_hash = base - 4;
  int h_hash = h - 2;
  if (h_hash % 2 == 0)
    count = (base_hash + 1) * (h_hash / 2);
  else
    count = (base_hash - 1) * ((h_hash - 1) / 2) + base_hash;
  printf("%d\n", count);
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < base; j++) {
      if (i == h - 1)
        printf("*");
      else if (j == (base / 2) + i || j == (base / 2) - i)
        printf("*");
      else if (j < (base / 2) + i && j > (base / 2) - i)
        printf("#");
      else
        printf(" ");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_atoi_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L4:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L4
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_atoi_printf(char *str) {
  int result;
  int sign;
  int i;
  i = 0;
  result = 0;
  sign = 1;
  while (ft_isdigit(str[i])) {
    result = (result * 10) + (str[i] - '0');
    ++i;
  }
  return (result * sign);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_atoi_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L1
L16:
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  add    $0x1,%rbx
L1:
  movsbl (%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L16
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_atoi_printf(char *str) {
  int result;
  int sign;
  int i;
  i = 0;
  result = 0;
  sign = 1;
  while (ft_isdigit(str[i])) {
    result = (result * 10) + (str[i] - '0');
    ++i;
  }
  return (result * sign);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_atoi_printf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L8:
  movsbl (%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int ft_atoi_printf(char *str) {
  int result;
  int sign;
  int i;
  i = 0;
  result = 0;
  sign = 1;
  while (ft_isdigit(str[i])) {
    result = (result * 10) + (str[i] - '0');
    ++i;
  }
  return (result * sign);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_atoi_printf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rbx),%eax
  lea    (%r12,%r12,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12d
L4:
  movsbl (%rbx),%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int ft_atoi_printf(char *str) {
  int result;
  int sign;
  int i;
  i = 0;
  result = 0;
  sign = 1;
  while (ft_isdigit(str[i])) {
    result = (result * 10) + (str[i] - '0');
    ++i;
  }
  return (result * sign);
}
```
user: What is the c source code of the assembly code below?

```asm
<digitalWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void digitalWrite(int pin, int value) {
  (void)pin;
  (void)value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<digitalWrite>:
  endbr64
  ret
```

assistant: ```c
void digitalWrite(int pin, int value) {
  (void)pin;
  (void)value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<digitalWrite>:
  endbr64
  ret
```

assistant: ```c
void digitalWrite(int pin, int value) {
  (void)pin;
  (void)value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<digitalWrite>:
  endbr64
  ret
```

assistant: ```c
void digitalWrite(int pin, int value) {
  (void)pin;
  (void)value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<orderRow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L16:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x24(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,%ecx
  jge    L41
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L41:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <swapRow@plt>
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void orderRow(int matriz[4][5], int fils, int cols, int colSwap) {
  int i, j, minor, n;
  for (i = 0; i < fils; i++) {
    minor = i;
    for (j = (i + 1); j < fils; j++) {
      if (matriz[j][colSwap] < matriz[minor][colSwap]) {
        minor = j;
      }
    }
    swapRow(matriz, i, minor, cols);
  }
}
```