user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D101(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D66(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D43(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D109(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D35(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D104(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D43(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movss  -0xc(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D101
type: string
name: extract_symbolic_data
arguments: data_label: D66
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D34
type: string
name: extract_symbolic_data
arguments: data_label: D43
type: f64
name: extract_symbolic_data
arguments: data_label: D109
type: string
name: extract_symbolic_data
arguments: data_label: D35
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D92
type: string
name: extract_symbolic_data
arguments: data_label: D104
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D94
type: string
name: extract_symbolic_data
arguments: data_label: D26
type: string

tool: D101: %f%f

tool: {"D66": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x19,0x40]}

tool: D34: C1=%.2f


tool: D43: 3.14

tool: D109: Sa=%.2f


tool: {"D35": [0x1f,0x85,0xeb,0x51,0xb8,0x1e,0x29,0x40]}

tool: D92: Sb=%.2f


tool: {"D104": [0xbf,0x58,0xf2,0x8b,0x25,0xbf,0x10,0x40]}

tool: D94: Va=%.2f


tool: D26: Vb=%.2f


assistant: ```c
int main(int argc, const char *argv[]) {
  float r, h;
  scanf("%f%f", &r, &h);
  printf("C1=%.2f\n", 2 * 3.14 * r);
  printf("Sa=%.2f\n", 3.14 * r * r);
  printf("Sb=%.2f\n", 4 * 3.14 * r * r);
  printf("Va=%.2f\n", 3.14 * 4.0 / 3.0 * r * r * r);
  printf("Vb=%.2f\n", 3.14 * r * r * h);
  return 0;
}
```