ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DS2480Detect>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    %ebp,%edi
  call   <DS2480Try@plt>
  cmp    $0x1,%eax
  je     L3
  sub    $0x1,%ebx
  jne    L12
  xor    %eax,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DS2480Detect(int portnum) {
  int retry = 0;
  while (retry++ < 10) {
    if (DS2480Try(portnum) == 1)
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split_n_sort>:
  endbr64
  cmp    $0x1,%rsi
  je     L3
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  mov    %rdi,%rbx
  add    %esi,%ebp
  sar    %ebp
  sub    $0x18,%rsp
  movslq %ebp,%r12
  lea    0x0(,%rbp,4),%r13d
  cmp    $0x2,%rsi
  je     L22
  and    $0x1,%esi
  jne    L37
  mov    %r12,%rsi
  lea    (%rbx,%r12,4),%r15
  call   <split_n_sort>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <split_n_sort>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %ebp,%esi
L25:
  mov    %r12,%rdi
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <merge@plt>
  nopl   0x0(%rax,%rax,1)
L37:
  lea    0x1(%rbp),%r15d
  movslq %r15d,%r14
  mov    %r14,%rsi
  call   <split_n_sort>
  lea    (%rbx,%r14,4),%r8
  mov    %r12,%rsi
  lea    0x4(%r13),%r14d
  mov    %r8,%rdi
  mov    %r8,0x8(%rsp)
  call   <split_n_sort>
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%edx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %r15d,%esi
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L3:
  ret
  nopl   0x0(%rax)
L22:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  lea    (%rbx,%r12,4),%rsi
  mov    %r13d,%edx
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r15,%rdx
  mov    %ebp,%esi
  mov    %r14,%rdi
  jmp    L18
```

assistant: ```c
void split_n_sort(int array[], size_t count) {
  if (count == 1)
    return;
  int c2 = (int)count / 2;
  if (count == 2) {
    int *t1 = malloc(c2 * sizeof(*array));
    memcpy(t1, array, c2 * sizeof(*array));
    int *t2 = malloc(c2 * sizeof(*array));
    memcpy(t2, array + c2, c2 * sizeof(*array));
    merge(t1, c2, t2, c2, array);
  } else {
    if (count % 2) {
      split_n_sort(array, c2 + 1);
      split_n_sort(array + c2 + 1, c2);
      int *t1 = malloc((c2 + 1) * sizeof(*array));
      memcpy(t1, array, (c2 + 1) * sizeof(*array));
      int *t2 = malloc(c2 * sizeof(*array));
      memcpy(t2, array + c2 + 1, c2 * sizeof(*array));
      merge(t1, c2 + 1, t2, c2, array);
    } else {
      split_n_sort(array, c2);
      split_n_sort(array + c2, c2);
      int *t1 = malloc(c2 * sizeof(*array));
      memcpy(t1, array, c2 * sizeof(*array));
      int *t2 = malloc(c2 * sizeof(*array));
      memcpy(t2, array + c2, c2 * sizeof(*array));
      merge(t1, c2, t2, c2, array);
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<split_n_sort>:
  endbr64
  cmp    $0x1,%rsi
  je     L39
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  mov    %rdi,%rbx
  add    %esi,%ebp
  sar    %ebp
  sub    $0x18,%rsp
  movslq %ebp,%r12
  lea    0x0(,%rbp,4),%r13d
  cmp    $0x2,%rsi
  je     L25
  and    $0x1,%esi
  jne    L42
  mov    %r12,%rsi
  lea    (%rbx,%r12,4),%r15
  call   <split_n_sort>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <split_n_sort>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %ebp,%esi
L10:
  mov    %r12,%rdi
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <merge@plt>
  nopl   0x0(%rax,%rax,1)
L42:
  lea    0x1(%rbp),%r15d
  movslq %r15d,%r14
  mov    %r14,%rsi
  call   <split_n_sort>
  lea    (%rbx,%r14,4),%r8
  mov    %r12,%rsi
  lea    0x4(%r13),%r14d
  mov    %r8,%rdi
  mov    %r8,0x8(%rsp)
  call   <split_n_sort>
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memcpy@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13d,%edx
  mov    %rax,%r14
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %r15d,%esi
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L39:
  ret
  nopl   0x0(%rax)
L25:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  lea    (%rbx,%r12,4),%rsi
  mov    %r13d,%edx
  mov    %rax,%r15
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%r8
  mov    %ebp,%ecx
  mov    %r15,%rdx
  mov    %ebp,%esi
  mov    %r14,%rdi
  jmp    L22
```

assistant: ```c
void split_n_sort(int array[], size_t count) {
  if (count == 1)
    return;
  int c2 = (int)count / 2;
  if (count == 2) {
    int *t1 = malloc(c2 * sizeof(*array));
    memcpy(t1, array, c2 * sizeof(*array));
    int *t2 = malloc(c2 * sizeof(*array));
    memcpy(t2, array + c2, c2 * sizeof(*array));
    merge(t1, c2, t2, c2, array);
  } else {
    if (count % 2) {
      split_n_sort(array, c2 + 1);
      split_n_sort(array + c2 + 1, c2);
      int *t1 = malloc((c2 + 1) * sizeof(*array));
      memcpy(t1, array, (c2 + 1) * sizeof(*array));
      int *t2 = malloc(c2 * sizeof(*array));
      memcpy(t2, array + c2 + 1, c2 * sizeof(*array));
      merge(t1, c2 + 1, t2, c2, array);
    } else {
      split_n_sort(array, c2);
      split_n_sort(array + c2, c2);
      int *t1 = malloc(c2 * sizeof(*array));
      memcpy(t1, array, c2 * sizeof(*array));
      int *t2 = malloc(c2 * sizeof(*array));
      memcpy(t2, array + c2, c2 * sizeof(*array));
      merge(t1, c2, t2, c2, array);
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6464614d,-0x71(%rbp)
  movw   $0x6569,-0x6d(%rbp)
  movb   $0x0,-0x6b(%rbp)
  movl   $0x72646e41,-0x6a(%rbp)
  movw   $0x7765,-0x66(%rbp)
  movb   $0x0,-0x64(%rbp)
  movl   $0x6d746142,-0x63(%rbp)
  movw   $0x6e61,-0x5f(%rbp)
  movb   $0x0,-0x5d(%rbp)
  movabs $0x616d726564697053,%rax
  mov    $0x6e,%edx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movw   $0x0,-0x10(%rbp)
  movb   $0x4b,-0x5c(%rbp)
  movb   $0x61,-0x5b(%rbp)
  movb   $0x74,-0x5a(%rbp)
  movb   $0x69,-0x59(%rbp)
  movb   $0x65,-0x58(%rbp)
  movb   $0x0,-0x57(%rbp)
  lea    -0x50(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x63(%rbp),%rdx
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  lea    -0x71(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0x6a(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D13
datatype: string

tool: D12: The Incredible Hulk

tool: D13: %s's favorite hero is %s. 


assistant: ```c
main() {
  char Kid1[12];
  char Kid2[] = "Maddie";
  char Kid3[7] = "Andrew";
  char Hero1[] = "Batman";
  char Hero2[34] = "Spiderman";
  char Hero3[25];
  Kid1[0] = 'K';
  Kid1[1] = 'a';
  Kid1[2] = 't';
  Kid1[3] = 'i';
  Kid1[4] = 'e';
  Kid1[5] = '\0';
  strcpy(Hero3, "The Incredible Hulk");
  printf("%s\'s favorite hero is %s. \n", Kid1, Hero1);
  printf("%s\'s favorite hero is %s. \n", Kid2, Hero2);
  printf("%s\'s favorite hero is %s. \n", Kid3, Hero3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movl   $0x6464614d,0xf(%rsp)
  movw   $0x6569,0x13(%rsp)
  movb   $0x0,0x15(%rsp)
  movl   $0x72646e41,0x16(%rsp)
  movw   $0x7765,0x1a(%rsp)
  movb   $0x0,0x1c(%rsp)
  movl   $0x6d746142,0x1d(%rsp)
  movw   $0x6e61,0x21(%rsp)
  movb   $0x0,0x23(%rsp)
  movabs $0x616d726564697053,%rax
  mov    $0x6e,%edx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movw   $0x0,0x70(%rsp)
  movb   $0x4b,0x24(%rsp)
  movb   $0x61,0x25(%rsp)
  movb   $0x74,0x26(%rsp)
  movb   $0x69,0x27(%rsp)
  movb   $0x65,0x28(%rsp)
  movb   $0x0,0x29(%rsp)
  lea    0x30(%rsp),%rbp
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    0x1d(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x50(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x16(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D17
type_infered: string

tool: D13: The Incredible Hulk

tool: D17: %s's favorite hero is %s. 


assistant: ```c
main() {
  char Kid1[12];
  char Kid2[] = "Maddie";
  char Kid3[7] = "Andrew";
  char Hero1[] = "Batman";
  char Hero2[34] = "Spiderman";
  char Hero3[25];
  Kid1[0] = 'K';
  Kid1[1] = 'a';
  Kid1[2] = 't';
  Kid1[3] = 'i';
  Kid1[4] = 'e';
  Kid1[5] = '\0';
  strcpy(Hero3, "The Incredible Hulk");
  printf("%s\'s favorite hero is %s. \n", Kid1, Hero1);
  printf("%s\'s favorite hero is %s. \n", Kid2, Hero2);
  printf("%s\'s favorite hero is %s. \n", Kid3, Hero3);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x65,%edi
  mov    $0x6e61,%ecx
  push   %rbp
  mov    $0x7765,%edx
  lea    D21(%rip),%rbp
  sub    $0x88,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r12
  mov    %si,0x70(%rsp)
  mov    $0x6569,%eax
  mov    %di,0x28(%rsp)
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  movaps %xmm0,0x50(%rsp)
  pxor   %xmm0,%xmm0
  mov    %cx,0x21(%rsp)
  movaps %xmm0,0x60(%rsp)
  mov    %dx,0x1a(%rsp)
  movl   $0x6464614d,0xf(%rsp)
  mov    %ax,0x13(%rsp)
  movb   $0x0,0x15(%rsp)
  movl   $0x72646e41,0x16(%rsp)
  movb   $0x0,0x1c(%rsp)
  movl   $0x6d746142,0x1d(%rsp)
  movb   $0x0,0x23(%rsp)
  movl   $0x6974614b,0x24(%rsp)
  call   <strcpy@plt>
  lea    0x1d(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x50(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x16(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D21
type: string
name: unpack_data
arguments: label: D12
type: byte[16]
name: unpack_data
arguments: label: D8
type: string

tool: D21: %s's favorite hero is %s. 


tool: {"D12": [0x53,0x70,0x69,0x64,0x65,0x72,0x6d,0x61,0x6e,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D8: The Incredible Hulk

assistant: ```c
main() {
  char Kid1[12];
  char Kid2[] = "Maddie";
  char Kid3[7] = "Andrew";
  char Hero1[] = "Batman";
  char Hero2[34] = "Spiderman";
  char Hero3[25];
  Kid1[0] = 'K';
  Kid1[1] = 'a';
  Kid1[2] = 't';
  Kid1[3] = 'i';
  Kid1[4] = 'e';
  Kid1[5] = '\0';
  strcpy(Hero3, "The Incredible Hulk");
  printf("%s\'s favorite hero is %s. \n", Kid1, Hero1);
  printf("%s\'s favorite hero is %s. \n", Kid2, Hero2);
  printf("%s\'s favorite hero is %s. \n", Kid3, Hero3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x65,%edi
  mov    $0x6e61,%ecx
  push   %rbp
  mov    $0x7765,%edx
  lea    D25(%rip),%rbp
  sub    $0x88,%rsp
  movdqa D19(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%r12
  mov    %si,0x70(%rsp)
  mov    $0x6569,%eax
  mov    %di,0x28(%rsp)
  lea    D1(%rip),%rsi
  mov    %r12,%rdi
  movaps %xmm0,0x50(%rsp)
  pxor   %xmm0,%xmm0
  mov    %cx,0x21(%rsp)
  movaps %xmm0,0x60(%rsp)
  mov    %dx,0x1a(%rsp)
  movl   $0x6464614d,0xf(%rsp)
  mov    %ax,0x13(%rsp)
  movb   $0x0,0x15(%rsp)
  movl   $0x72646e41,0x16(%rsp)
  movb   $0x0,0x1c(%rsp)
  movl   $0x6d746142,0x1d(%rsp)
  movb   $0x0,0x23(%rsp)
  movl   $0x6974614b,0x24(%rsp)
  call   <strcpy@plt>
  lea    0x1d(%rsp),%rdx
  lea    0x24(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x50(%rsp),%rdx
  lea    0xf(%rsp),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x16(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D25
type: string
name: disassemble_data
arguments: tag: D19
type: byte[16]
name: disassemble_data
arguments: tag: D1
type: string

tool: D25: %s's favorite hero is %s. 


tool: {"D19": [0x53,0x70,0x69,0x64,0x65,0x72,0x6d,0x61,0x6e,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D1: The Incredible Hulk

assistant: ```c
main() {
  char Kid1[12];
  char Kid2[] = "Maddie";
  char Kid3[7] = "Andrew";
  char Hero1[] = "Batman";
  char Hero2[34] = "Spiderman";
  char Hero3[25];
  Kid1[0] = 'K';
  Kid1[1] = 'a';
  Kid1[2] = 't';
  Kid1[3] = 'i';
  Kid1[4] = 'e';
  Kid1[5] = '\0';
  strcpy(Hero3, "The Incredible Hulk");
  printf("%s\'s favorite hero is %s. \n", Kid1, Hero1);
  printf("%s\'s favorite hero is %s. \n", Kid2, Hero2);
  printf("%s\'s favorite hero is %s. \n", Kid3, Hero3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<IoRegisterDeviceInterface>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L19
  nop
  mov    $0x0,%eax
  jmp    L17
L19:
  nop
  mov    $0xc0000010,%eax
L17:
  leave
  ret
```

assistant: ```c
int IoRegisterDeviceInterface(int PhysicalDeviceObject, int InterfaceClassGuid, int ReferenceString, int SymbolicLinkName) {
  {
    int tmp_ndt_5;
    tmp_ndt_5 = __VERIFIER_nondet_int();
    if (tmp_ndt_5 == 0) {
      goto switch_6_0;
    } else {
      goto switch_6_default;
      if (0) {
      switch_6_0:
        return (0);
      switch_6_default:;
        return (-1073741808);
      } else {
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<IoRegisterDeviceInterface>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L9
L7:
  add    $0x8,%rsp
  ret
L9:
  mov    $0xc0000010,%eax
  jmp    L7
```

assistant: ```c
int IoRegisterDeviceInterface(int PhysicalDeviceObject, int InterfaceClassGuid, int ReferenceString, int SymbolicLinkName) {
  {
    int tmp_ndt_5;
    tmp_ndt_5 = __VERIFIER_nondet_int();
    if (tmp_ndt_5 == 0) {
      goto switch_6_0;
    } else {
      goto switch_6_default;
      if (0) {
      switch_6_0:
        return (0);
      switch_6_default:;
        return (-1073741808);
      } else {
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IoRegisterDeviceInterface>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L18
L15:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xc0000010,%eax
  jmp    L15
```

assistant: ```c
int IoRegisterDeviceInterface(int PhysicalDeviceObject, int InterfaceClassGuid, int ReferenceString, int SymbolicLinkName) {
  {
    int tmp_ndt_5;
    tmp_ndt_5 = __VERIFIER_nondet_int();
    if (tmp_ndt_5 == 0) {
      goto switch_6_0;
    } else {
      goto switch_6_default;
      if (0) {
      switch_6_0:
        return (0);
      switch_6_default:;
        return (-1073741808);
      } else {
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<IoRegisterDeviceInterface>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L3
L13:
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xc0000010,%eax
  jmp    L13
```

assistant: ```c
int IoRegisterDeviceInterface(int PhysicalDeviceObject, int InterfaceClassGuid, int ReferenceString, int SymbolicLinkName) {
  {
    int tmp_ndt_5;
    tmp_ndt_5 = __VERIFIER_nondet_int();
    if (tmp_ndt_5 == 0) {
      goto switch_6_0;
    } else {
      goto switch_6_default;
      if (0) {
      switch_6_0:
        return (0);
      switch_6_default:;
        return (-1073741808);
      } else {
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fs_new_bit_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x7(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char *fs_new_bit_array(long n) {
  int extra = (n % 8) ? 1 : 0;
  size_t ms = ((n / 8) + extra) * sizeof(unsigned char);
  unsigned char *p = malloc(ms);
  memset(p, 0xFF, ms);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fs_new_bit_array>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   $0x7,%dil
  setne  %bpl
  movzbl %bpl,%ebp
  lea    0x7(%rdi),%rax
  test   %rdi,%rdi
  cmovns %rdi,%rax
  sar    $0x3,%rax
  add    %rax,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    $0xff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *fs_new_bit_array(long n) {
  int extra = (n % 8) ? 1 : 0;
  size_t ms = ((n / 8) + extra) * sizeof(unsigned char);
  unsigned char *p = malloc(ms);
  memset(p, 0xFF, ms);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fs_new_bit_array>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  lea    0x7(%rdi),%rax
  push   %r12
  sub    $0x8,%rsp
  test   $0x7,%dil
  setne  %r13b
  test   %rdi,%rdi
  cmovns %rdi,%rax
  sar    $0x3,%rax
  add    %rax,%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    $0xff,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *fs_new_bit_array(long n) {
  int extra = (n % 8) ? 1 : 0;
  size_t ms = ((n / 8) + extra) * sizeof(unsigned char);
  unsigned char *p = malloc(ms);
  memset(p, 0xFF, ms);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fs_new_bit_array>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  lea    0x7(%rdi),%rax
  push   %r12
  sub    $0x8,%rsp
  test   $0x7,%dil
  setne  %r13b
  test   %rdi,%rdi
  cmovns %rdi,%rax
  sar    $0x3,%rax
  add    %rax,%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    $0xff,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *fs_new_bit_array(long n) {
  int extra = (n % 8) ? 1 : 0;
  size_t ms = ((n / 8) + extra) * sizeof(unsigned char);
  unsigned char *p = malloc(ms);
  memset(p, 0xFF, ms);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<printMatrices>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9d,-0x24(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printMatrix@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printMatrix@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <printMatrix@plt>
  nop
  leave
  ret
```

assistant: ```c
void printMatrices(int *first, int *second, int *third, int M, int N, int K) {
  printMatrix(first, M, N);
  printMatrix(second, N, K);
  printMatrix(third, M, K);
}
```
user: What is the c source code of the assembly code below:

```asm
<printMatrices>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %ecx,%ebx
  mov    %r8d,%r12d
  mov    %r9d,%ebp
  mov    %r8d,%edx
  mov    %ecx,%esi
  call   <printMatrix@plt>
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printMatrix@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printMatrix@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void printMatrices(int *first, int *second, int *third, int M, int N, int K) {
  printMatrix(first, M, N);
  printMatrix(second, N, K);
  printMatrix(third, M, K);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printMatrices>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    %ecx,%esi
  push   %r14
  mov    %rdx,%r14
  mov    %r8d,%edx
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %r9d,%r12d
  push   %rbp
  mov    %ecx,%ebp
  call   <printMatrix@plt>
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  call   <printMatrix@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printMatrix@plt>
```

assistant: ```c
void printMatrices(int *first, int *second, int *third, int M, int N, int K) {
  printMatrix(first, M, N);
  printMatrix(second, N, K);
  printMatrix(third, M, K);
}
```