ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r9d
  mov    %rsi,%r11
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  lea    0x4(%rsp),%r10
  xor    %edi,%edi
  shr    $0x3,%eax
  or     $0x61bab5,%eax
  mov    %eax,0x4(%rsp)
  test   %r9d,%r9d
  je     L40
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %edi,%eax
  lea    (%r10,%rax,4),%rdx
  xor    %eax,%eax
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L27:
  movzwl 0x1(%rdx),%ecx
  add    $0x2,%eax
  mov    %r8b,0x2(%rdx)
  mov    %cx,(%rdx)
  cmp    %eax,%r9d
  jbe    L16
L17:
  movzwl (%rdx),%ecx
  mov    %edi,%esi
  movzbl (%rdx),%r8d
  and    %eax,%esi
  rol    $0x8,%cx
  cmp    %esi,0x4(%rsp)
  ja     L27
  add    $0x2,%eax
  mov    %cx,(%rdx)
  rolw   $0x8,0x6(%rsp)
  cmp    %eax,%r9d
  ja     L17
L16:
  add    $0x2,%edi
  cmp    %r9d,%edi
  jb     L54
  mov    0x4(%rsp),%eax
L40:
  and    $0x369937ec,%eax
  mov    %eax,(%r11)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > (local2 & local1)) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy12;
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 916010988UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r9d
  mov    %rsi,%r11
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  lea    0x4(%rsp),%r10
  xor    %edi,%edi
  shr    $0x3,%eax
  or     $0x61bab5,%eax
  mov    %eax,0x4(%rsp)
  test   %r9d,%r9d
  je     L68
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %edi,%eax
  lea    (%r10,%rax,4),%rdx
  xor    %eax,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L15:
  movzwl 0x1(%rdx),%ecx
  add    $0x2,%eax
  mov    %r8b,0x2(%rdx)
  mov    %cx,(%rdx)
  cmp    %eax,%r9d
  jbe    L37
L48:
  movzwl (%rdx),%ecx
  mov    %edi,%esi
  movzbl (%rdx),%r8d
  and    %eax,%esi
  rol    $0x8,%cx
  cmp    %esi,0x4(%rsp)
  ja     L15
  add    $0x2,%eax
  mov    %cx,(%rdx)
  rolw   $0x8,0x6(%rsp)
  cmp    %eax,%r9d
  ja     L48
L37:
  add    $0x2,%edi
  cmp    %r9d,%edi
  jb     L40
  mov    0x4(%rsp),%eax
L68:
  and    $0x369937ec,%eax
  mov    %eax,(%r11)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  ret
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  char copy11;
  char copy12;
  char copy13;
  char copy14;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> 3U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] > (local2 & local1)) {
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
          copy12 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy12;
          copy12 = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy12;
        } else {
          copy13 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy13;
          copy14 = *((char *)(&state[0UL]) + 2);
          *((char *)(&state[0UL]) + 2) = *((char *)(&state[0UL]) + 3);
          *((char *)(&state[0UL]) + 3) = copy14;
        }
        local2 += 2UL;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] & 916010988UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<HTS_mglsadf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L6:
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movsd  -0x30(%rbp),%xmm0
  mov    -0x24(%rbp),%esi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  mov    %rcx,%rdi
  movq   %rax,%xmm0
  call   <HTS_mglsadff@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L6
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double HTS_mglsadf(double x, double *b, const int m, const double a, int n, double *d) {
  int i;
  for (i = 0; i < n; i++)
    x = HTS_mglsadff(x, b, m, a, &d[i * (m + 1)]);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HTS_mglsadf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  test   %edx,%edx
  jle    L10
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    %edx,%r12d
  movslq %esi,%rax
  lea    0x8(,%rax,8),%r15
  mov    %rcx,%rbx
  mov    $0x0,%ebp
L7:
  mov    %rbx,%rdx
  movsd  0x8(%rsp),%xmm1
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <HTS_mglsadff@plt>
  add    $0x1,%ebp
  add    %r15,%rbx
  cmp    %ebp,%r12d
  jne    L7
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double HTS_mglsadf(double x, double *b, const int m, const double a, int n, double *d) {
  int i;
  for (i = 0; i < n; i++)
    x = HTS_mglsadff(x, b, m, a, &d[i * (m + 1)]);
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HTS_mglsadf>:
  endbr64
  test   %edx,%edx
  jle    L14
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  lea    0x1(%rsi),%ebx
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L10:
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%r15d
  movsd  %xmm1,0x8(%rsp)
  add    %rbx,%r14
  call   <HTS_mglsadff@plt>
  cmp    %r15d,%ebp
  movsd  0x8(%rsp),%xmm1
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L14:
  ret
```

assistant: ```c
double HTS_mglsadf(double x, double *b, const int m, const double a, int n, double *d) {
  int i;
  for (i = 0; i < n; i++)
    x = HTS_mglsadff(x, b, m, a, &d[i * (m + 1)]);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HTS_mglsadf>:
  endbr64
  test   %edx,%edx
  jle    L13
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  lea    0x1(%rsi),%ebx
  movslq %ebx,%rbx
  shl    $0x3,%rbx
  sub    $0x18,%rsp
  xchg   %ax,%ax
L15:
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x1,%r15d
  movsd  %xmm1,0x8(%rsp)
  add    %rbx,%r14
  call   <HTS_mglsadff@plt>
  cmp    %r15d,%ebp
  movsd  0x8(%rsp),%xmm1
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L13:
  ret
```

assistant: ```c
double HTS_mglsadf(double x, double *b, const int m, const double a, int n, double *d) {
  int i;
  for (i = 0; i < n; i++)
    x = HTS_mglsadff(x, b, m, a, &d[i * (m + 1)]);
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getLengthOfType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1b,-0x4(%rbp)
  ja     L181
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1,%eax
  jmp    L1
  mov    $0x1,%eax
  jmp    L1
  mov    $0x2,%eax
  jmp    L1
  mov    $0x2,%eax
  jmp    L1
  mov    $0x2,%eax
  jmp    L1
  mov    $0x3,%eax
  jmp    L1
  mov    $0x4,%eax
  jmp    L1
  mov    $0x4,%eax
  jmp    L1
  mov    $0x5,%eax
  jmp    L1
  mov    $0x5,%eax
  jmp    L1
  mov    $0x6,%eax
  jmp    L1
  mov    $0x6,%eax
  jmp    L1
  mov    $0x8,%eax
  jmp    L1
  mov    $0x8,%eax
  jmp    L1
  mov    $0x8,%eax
  jmp    L1
  mov    $0x9,%eax
  jmp    L1
  mov    $0xa,%eax
  jmp    L1
  mov    $0xc,%eax
  jmp    L1
  mov    $0x2,%eax
  jmp    L1
  mov    $0x4,%eax
  jmp    L1
  mov    $0x6,%eax
  jmp    L1
L181:
  mov    $0xffffffff,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int getLengthOfType(int parameterType) {
  switch (parameterType) {
  case 1:
    return 1;
  case 2:
    return 1;
  case 3:
    return 2;
  case 5:
    return 2;
  case 4:
    return 2;
  case 6:
    return 3;
  case 7:
    return 4;
  case 8:
    return 4;
  case 9:
    return 5;
  case 10:
    return 5;
  case 11:
    return 6;
  case 12:
    return 6;
  case 13:
    return 8;
  case 14:
    return 8;
  case 15:
    return 8;
  case 18:
    return 9;
  case 20:
    return 10;
  case 24:
    return 12;
  case 25:
    return 2;
  case 26:
    return 4;
  case 27:
    return 6;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getLengthOfType>:
  endbr64
  cmp    $0x1b,%edi
  ja     L2
  mov    %edi,%edi
  lea    D6(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  ret
  mov    $0x3,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x5,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x6,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x8,%eax
  ret
  mov    $0x9,%eax
  ret
  mov    $0xa,%eax
  ret
  mov    $0xc,%eax
  ret
  mov    $0x4,%eax
  ret
  mov    $0x6,%eax
  ret
L2:
  mov    $0xffffffff,%eax
  ret
  mov    $0x1,%eax
  ret
```

assistant: ```c
int getLengthOfType(int parameterType) {
  switch (parameterType) {
  case 1:
    return 1;
  case 2:
    return 1;
  case 3:
    return 2;
  case 5:
    return 2;
  case 4:
    return 2;
  case 6:
    return 3;
  case 7:
    return 4;
  case 8:
    return 4;
  case 9:
    return 5;
  case 10:
    return 5;
  case 11:
    return 6;
  case 12:
    return 6;
  case 13:
    return 8;
  case 14:
    return 8;
  case 15:
    return 8;
  case 18:
    return 9;
  case 20:
    return 10;
  case 24:
    return 12;
  case 25:
    return 2;
  case 26:
    return 4;
  case 27:
    return 6;
  }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getLengthOfType>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x1a,%edi
  ja     L1
  lea    D7(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L1:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: 

assistant: ```c
int getLengthOfType(int parameterType) {
  switch (parameterType) {
  case 1:
    return 1;
  case 2:
    return 1;
  case 3:
    return 2;
  case 5:
    return 2;
  case 4:
    return 2;
  case 6:
    return 3;
  case 7:
    return 4;
  case 8:
    return 4;
  case 9:
    return 5;
  case 10:
    return 5;
  case 11:
    return 6;
  case 12:
    return 6;
  case 13:
    return 8;
  case 14:
    return 8;
  case 15:
    return 8;
  case 18:
    return 9;
  case 20:
    return 10;
  case 24:
    return 12;
  case 25:
    return 2;
  case 26:
    return 4;
  case 27:
    return 6;
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getLengthOfType>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x1a,%edi
  ja     L4
  lea    D0(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L4:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: 

assistant: ```c
int getLengthOfType(int parameterType) {
  switch (parameterType) {
  case 1:
    return 1;
  case 2:
    return 1;
  case 3:
    return 2;
  case 5:
    return 2;
  case 4:
    return 2;
  case 6:
    return 3;
  case 7:
    return 4;
  case 8:
    return 4;
  case 9:
    return 5;
  case 10:
    return 5;
  case 11:
    return 6;
  case 12:
    return 6;
  case 13:
    return 8;
  case 14:
    return 8;
  case 15:
    return 8;
  case 18:
    return 9;
  case 20:
    return 10;
  case 24:
    return 12;
  case 25:
    return 2;
  case 26:
    return 4;
  case 27:
    return 6;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stringadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L16
L17:
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L52
  addq   $0x1,-0x28(%rbp)
L52:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L26
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L26:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%eax
  add    %ebx,%eax
  add    $0x7,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x40(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L56
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L18
L56:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    (%rdx,%rax,1),%rdi
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    %rax,%rcx
  lea    D15(%rip),%rax
  mov    %rax,%rdx
  call   <snprintf@plt>
  mov    -0x48(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x48(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x0,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%eax
L16:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D15
datatype: string

tool: D17: realloc

tool: D15: <%s>"%s"</%s>

assistant: ```c
int stringadd(char *p, int offset, char *keyword, char **s0, int *s0len) {
  int retval = -1;
  int slen;
  if (p == NULL)
    return 0;
  p += offset;
  if (p[0] == '\"')
    p++;
  if (p[strlen(p) - 1] == '\"')
    p[strlen(p) - 1] = '\0';
  slen = strlen(p) + 2 * strlen(keyword) + 5 + 2;
  if ((*s0 = realloc(*s0, *s0len + slen + 1)) == NULL) {
    perror("realloc");
    goto done;
  }
  snprintf(*s0 + *s0len, slen + 1, "<%s>\"%s\"</%s>", keyword, p, keyword);
  *s0len += slen;
  retval = 0;
done:
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stringadd>:
  endbr64
  test   %rdi,%rdi
  je     L42
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%rbp
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rbx
  cmpb   $0x22,(%rbx)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,-0x1(%rbx,%rax,1)
  je     L17
L41:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    (%r14,%rax,2),%r14d
  lea    0x7(%r14),%r15d
  mov    %r15d,%esi
  add    0x0(%rbp),%esi
  add    $0x1,%esi
  mov    0x0(%r13),%rdi
  call   <realloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L11
  lea    0x8(%r14),%esi
  movslq 0x0(%rbp),%rdx
  lea    (%rax,%rdx,1),%rdi
  mov    %r12,%r9
  mov    %rbx,%r8
  mov    %r12,%rcx
  lea    D0(%rip),%rdx
  call   <snprintf@plt>
  add    %r15d,0x0(%rbp)
  mov    $0x0,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L41
L11:
  lea    D14(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L42:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D0: <%s>"%s"</%s>

tool: D14: realloc

assistant: ```c
int stringadd(char *p, int offset, char *keyword, char **s0, int *s0len) {
  int retval = -1;
  int slen;
  if (p == NULL)
    return 0;
  p += offset;
  if (p[0] == '\"')
    p++;
  if (p[strlen(p) - 1] == '\"')
    p[strlen(p) - 1] = '\0';
  slen = strlen(p) + 2 * strlen(keyword) + 5 + 2;
  if ((*s0 = realloc(*s0, *s0len + slen + 1)) == NULL) {
    perror("realloc");
    goto done;
  }
  snprintf(*s0 + *s0len, slen + 1, "<%s>\"%s\"</%s>", keyword, p, keyword);
  *s0len += slen;
  retval = 0;
done:
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stringadd>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %r15
  movslq %esi,%rsi
  xor    %eax,%eax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  lea    (%rdi,%rsi,1),%rbx
  sub    $0x8,%rsp
  cmpb   $0x22,(%rbx)
  sete   %al
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,-0x1(%rbx,%rax,1)
  je     L37
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    0x0(%rbp),%esi
  mov    (%r12),%rdi
  lea    0x0(%r13,%rax,2),%r15d
  lea    0x7(%r15),%r13d
  add    %r13d,%esi
  add    $0x1,%esi
  call   <realloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L7
  movslq 0x0(%rbp),%rdx
  lea    0x8(%r15),%esi
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    (%rax,%rdx,1),%rdi
  lea    D8(%rip),%rdx
  call   <snprintf@plt>
  add    %r13d,0x0(%rbp)
  xor    %eax,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L12
L7:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D8: <%s>"%s"</%s>

tool: D9: realloc

assistant: ```c
int stringadd(char *p, int offset, char *keyword, char **s0, int *s0len) {
  int retval = -1;
  int slen;
  if (p == NULL)
    return 0;
  p += offset;
  if (p[0] == '\"')
    p++;
  if (p[strlen(p) - 1] == '\"')
    p[strlen(p) - 1] = '\0';
  slen = strlen(p) + 2 * strlen(keyword) + 5 + 2;
  if ((*s0 = realloc(*s0, *s0len + slen + 1)) == NULL) {
    perror("realloc");
    goto done;
  }
  snprintf(*s0 + *s0len, slen + 1, "<%s>\"%s\"</%s>", keyword, p, keyword);
  *s0len += slen;
  retval = 0;
done:
  return retval;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stringadd>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %r15
  movslq %esi,%rsi
  xor    %eax,%eax
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  lea    (%rdi,%rsi,1),%rbx
  sub    $0x8,%rsp
  cmpb   $0x22,(%rbx)
  sete   %al
  add    %rax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x22,-0x1(%rbx,%rax,1)
  je     L46
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    0x0(%rbp),%esi
  mov    (%r12),%rdi
  lea    0x0(%r13,%rax,2),%r15d
  lea    0x7(%r15),%r13d
  add    %r13d,%esi
  add    $0x1,%esi
  call   <realloc@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L2
  movslq 0x0(%rbp),%rdx
  lea    0x8(%r15),%esi
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    (%rax,%rdx,1),%rdi
  lea    D9(%rip),%rdx
  call   <snprintf@plt>
  add    %r13d,0x0(%rbp)
  xor    %eax,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L8
L2:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L22
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D7
data_type: string

tool: D9: <%s>"%s"</%s>

tool: D7: realloc

assistant: ```c
int stringadd(char *p, int offset, char *keyword, char **s0, int *s0len) {
  int retval = -1;
  int slen;
  if (p == NULL)
    return 0;
  p += offset;
  if (p[0] == '\"')
    p++;
  if (p[strlen(p) - 1] == '\"')
    p[strlen(p) - 1] = '\0';
  slen = strlen(p) + 2 * strlen(keyword) + 5 + 2;
  if ((*s0 = realloc(*s0, *s0len + slen + 1)) == NULL) {
    perror("realloc");
    goto done;
  }
  snprintf(*s0 + *s0len, slen + 1, "<%s>\"%s\"</%s>", keyword, p, keyword);
  *s0len += slen;
  retval = 0;
done:
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_split_whitespaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <write_in_memory@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **ft_split_whitespaces(char *str) {
  char **result;
  int from;
  int to;
  from = 0;
  to = 0;
  result = write_in_memory(str, to, from);
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_split_whitespaces>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <write_in_memory@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char **ft_split_whitespaces(char *str) {
  char **result;
  int from;
  int to;
  from = 0;
  to = 0;
  result = write_in_memory(str, to, from);
  return (result);
}
```