ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<search_l>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <hash@plt>
  cltq
  mov    0x0(%rbp,%rax,4),%edx
  mov    $0x3e8,%eax
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x1,%eax
  je     L5
L20:
  cmp    %ebx,%edx
  jne    L0
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int search_l(int *HASH_MAP, int num) {
  int probe = hash(num);
  int i;
  for (i = 0; i < 1000; i++) {
    if (HASH_MAP[probe] == num) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<search_l>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <hash@plt>
  cltq
  cmp    %ebx,0x0(%rbp,%rax,4)
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int search_l(int *HASH_MAP, int num) {
  int probe = hash(num);
  int i;
  for (i = 0; i < 1000; i++) {
    if (HASH_MAP[probe] == num) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<atoh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L82
L18:
  shlq   $0x4,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L11
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L11
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  or     %rax,-0x8(%rbp)
  jmp    L38
L11:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x5f,%eax
  cmp    $0x40,%eax
  jle    L48
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x5f,%eax
  cmp    $0x46,%eax
  jg     L48
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x5f,%eax
  sub    $0x37,%eax
  cltq
  or     %rax,-0x8(%rbp)
  jmp    L38
L48:
  movq   $0xffffffffffffffff,-0x8(%rbp)
  jmp    L49
L38:
  addl   $0x1,-0xc(%rbp)
L82:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  nop
L49:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long atoh(char *cp) {
  unsigned long n = 0;
  int i = 2;
  while (cp[i]) {
    n <<= 4;
    if (cp[i] >= '0' && cp[i] <= '9')
      n |= cp[i] - '0';
    else if ((cp[i] & 0x5f) >= 'A' && (cp[i] & 0x5f) <= 'F')
      n |= (cp[i] & 0x5f) - 'A' + 10;
    else {
      n = -1;
      goto error;
    }
    i++;
  }
error:
  return (n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<atoh>:
  endbr64
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  je     L6
  add    $0x3,%rdi
  mov    $0x0,%eax
  jmp    L8
L5:
  mov    %edx,%ecx
  and    $0x5f,%ecx
  and    $0x5f,%edx
  sub    $0x41,%edx
  cmp    $0x5,%edx
  ja     L14
  sub    $0x37,%ecx
  movsbq %cl,%rcx
  or     %rcx,%rax
L18:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L37
L8:
  shl    $0x4,%rax
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L5
  movsbl %dl,%edx
  sub    $0x30,%edx
  movslq %edx,%rdx
  or     %rdx,%rax
  jmp    L18
L37:
  ret
L6:
  mov    $0x0,%eax
  ret
L14:
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
unsigned long atoh(char *cp) {
  unsigned long n = 0;
  int i = 2;
  while (cp[i]) {
    n <<= 4;
    if (cp[i] >= '0' && cp[i] <= '9')
      n |= cp[i] - '0';
    else if ((cp[i] & 0x5f) >= 'A' && (cp[i] & 0x5f) <= 'F')
      n |= (cp[i] & 0x5f) - 'A' + 10;
    else {
      n = -1;
      goto error;
    }
    i++;
  }
error:
  return (n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<atoh>:
  endbr64
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  je     L9
  add    $0x3,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L30:
  lea    -0x30(%rdx),%ecx
  shl    $0x4,%rax
  cmp    $0x9,%cl
  jbe    L0
  mov    %edx,%ecx
  and    $0x5f,%edx
  sub    $0x41,%edx
  and    $0x5f,%ecx
  cmp    $0x5,%edx
  ja     L17
  sub    $0x37,%ecx
L0:
  movzbl (%rdi),%edx
  movsbq %cl,%rcx
  add    $0x1,%rdi
  or     %rcx,%rax
  test   %dl,%dl
  jne    L30
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0xffffffffffffffff,%rax
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long atoh(char *cp) {
  unsigned long n = 0;
  int i = 2;
  while (cp[i]) {
    n <<= 4;
    if (cp[i] >= '0' && cp[i] <= '9')
      n |= cp[i] - '0';
    else if ((cp[i] & 0x5f) >= 'A' && (cp[i] & 0x5f) <= 'F')
      n |= (cp[i] & 0x5f) - 'A' + 10;
    else {
      n = -1;
      goto error;
    }
    i++;
  }
error:
  return (n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<atoh>:
  endbr64
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  je     L34
  add    $0x3,%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  lea    -0x30(%rdx),%ecx
  shl    $0x4,%rax
  cmp    $0x9,%cl
  jbe    L38
  mov    %edx,%ecx
  and    $0x5f,%edx
  sub    $0x41,%edx
  and    $0x5f,%ecx
  cmp    $0x5,%edx
  ja     L39
  sub    $0x37,%ecx
L38:
  movzbl (%rdi),%edx
  movsbq %cl,%rcx
  add    $0x1,%rdi
  or     %rcx,%rax
  test   %dl,%dl
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0xffffffffffffffff,%rax
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long atoh(char *cp) {
  unsigned long n = 0;
  int i = 2;
  while (cp[i]) {
    n <<= 4;
    if (cp[i] >= '0' && cp[i] <= '9')
      n |= cp[i] - '0';
    else if ((cp[i] & 0x5f) >= 'A' && (cp[i] & 0x5f) <= 'F')
      n |= (cp[i] & 0x5f) - 'A' + 10;
    else {
      n = -1;
      goto error;
    }
    i++;
  }
error:
  return (n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    (%rdi,%rdi,2),%eax
  cltq
  shl    $0x3,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L157:
  cmp    %rcx,%rsp
  je     L8
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L157
L8:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L16
  orq    $0x0,-0x8(%rsp,%rdx,1)
L16:
  mov    %rsp,%rbx
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L151:
  cmp    %rcx,%rsp
  je     L90
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L151
L90:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L140
  orq    $0x0,-0x8(%rsp,%rdx,1)
L140:
  mov    %rsp,%r12
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L23:
  cmp    %rcx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L18:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L97
  orq    $0x0,-0x8(%rsp,%rdx,1)
L97:
  mov    %rsp,%r13
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L120:
  cmp    %rcx,%rsp
  je     L153
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L120
L153:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L124
  orq    $0x0,-0x8(%rsp,%rax,1)
L124:
  mov    %rsp,%r15
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fn1@plt>
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <fn1@plt>
  test   %r14d,%r14d
  jle    L85
  mov    %r14d,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L48:
  movsd  (%rbx,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm0
  addsd  0x0(%r13,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L48
L72:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L123
  movapd %xmm1,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L85:
  pxor   %xmm1,%xmm1
  jmp    L72
L123:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double fn3(int x) {
  double s = 0;
  double b[3 * x], c[3 * x], d[3 * x], e[3 * x];
  int i;
  fn1(b, c, x);
  fn1(e, d, x);
#pragma omp target map(tofrom : s)
#pragma omp parallel for reduction(+ : s)
  for (i = 0; i < x; i++)
    s += b[i] * c[i] + d[i];
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    (%rdi,%rdi,2),%eax
  mov    %rsp,%rsi
  cltq
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rcx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L83
L19:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L19
L83:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L143
L31:
  mov    %rax,%rdi
  mov    %rsp,%rsi
  mov    %rax,%rcx
  mov    %rsp,%rbx
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rcx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L14
L38:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L38
L14:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L52
L66:
  mov    %rax,%rdi
  mov    %rsp,%rsi
  mov    %rax,%rcx
  mov    %rsp,%r12
  and    $0xfffffffffffff000,%rdi
  and    $0xfffffffffffffff0,%rcx
  sub    %rdi,%rsi
  cmp    %rsi,%rsp
  je     L97
L131:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L131
L97:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L72
  orq    $0x0,-0x8(%rsp,%rcx,1)
L72:
  mov    %rax,%rcx
  mov    %rsp,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%r13
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L60
L55:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L55
L60:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L172
  orq    $0x0,-0x8(%rsp,%rax,1)
L172:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    %edx,-0x34(%rbp)
  mov    %rsp,%r14
  call   <fn1@plt>
  mov    -0x34(%rbp),%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <fn1@plt>
  movslq -0x34(%rbp),%rdx
  test   %edx,%edx
  jle    L84
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L1:
  movsd  (%rbx,%rax,8),%xmm0
  mulsd  (%r12,%rax,8),%xmm0
  addsd  0x0(%r13,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L1
L70:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L141
  lea    -0x20(%rbp),%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L143:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L31
L52:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L66
L84:
  pxor   %xmm1,%xmm1
  jmp    L70
L141:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double fn3(int x) {
  double s = 0;
  double b[3 * x], c[3 * x], d[3 * x], e[3 * x];
  int i;
  fn1(b, c, x);
  fn1(e, d, x);
#pragma omp target map(tofrom : s)
#pragma omp parallel for reduction(+ : s)
  for (i = 0; i < x; i++)
    s += b[i] * c[i] + d[i];
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lseek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int lseek(int _fd, off_t offset, int whence) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lseek>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lseek(int _fd, off_t offset, int whence) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lseek>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lseek(int _fd, off_t offset, int whence) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lseek>:
  endbr64
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lseek(int _fd, off_t offset, int whence) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test18_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D23(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D6(%rip)
  mov    D6(%rip),%eax
  cmp    $0x1,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  jmp    L4
L2:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
void *test18_malloc(size_t n) {
  static int invoke_count = 0;
  switch (++invoke_count) {
  case 1:
    return malloc(n);
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test18_malloc>:
  endbr64
  mov    D9(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D1(%rip)
  mov    $0x0,%eax
  cmp    $0x1,%edx
  je     L7
  ret
L7:
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *test18_malloc(size_t n) {
  static int invoke_count = 0;
  switch (++invoke_count) {
  case 1:
    return malloc(n);
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test18_malloc>:
  endbr64
  mov    D2(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D1(%rip)
  cmp    $0x1,%eax
  je     L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *test18_malloc(size_t n) {
  static int invoke_count = 0;
  switch (++invoke_count) {
  case 1:
    return malloc(n);
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test18_malloc>:
  endbr64
  mov    D19(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D9(%rip)
  cmp    $0x1,%eax
  je     L9
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  jmp    1050 <malloc@plt>
```

assistant: ```c
void *test18_malloc(size_t n) {
  static int invoke_count = 0;
  switch (++invoke_count) {
  case 1:
    return malloc(n);
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: Usage:
	%s [serial [-u|-l] host port frequency]

or pass a packet in on stdin



assistant: ```c
void usage(char *name) {
  printf("Usage:\n"
         "\t%s [serial [-u|-l] host port frequency]\n"
         "\n"
         "or pass a packet in on stdin\n\n",
         name);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: Usage:
	%s [serial [-u|-l] host port frequency]

or pass a packet in on stdin



assistant: ```c
void usage(char *name) {
  printf("Usage:\n"
         "\t%s [serial [-u|-l] host port frequency]\n"
         "\n"
         "or pass a packet in on stdin\n\n",
         name);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string

tool: D9: Usage:
	%s [serial [-u|-l] host port frequency]

or pass a packet in on stdin



assistant: ```c
void usage(char *name) {
  printf("Usage:\n"
         "\t%s [serial [-u|-l] host port frequency]\n"
         "\n"
         "or pass a packet in on stdin\n\n",
         name);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: Usage:
	%s [serial [-u|-l] host port frequency]

or pass a packet in on stdin



assistant: ```c
void usage(char *name) {
  printf("Usage:\n"
         "\t%s [serial [-u|-l] host port frequency]\n"
         "\n"
         "or pass a packet in on stdin\n\n",
         name);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmp_diff_length_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D15(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D15: 123

tool: D3: 12345

assistant: ```c
void strcmp_diff_length_3() {
  char *x = "123";
  char *y = "12345";
  clang_analyzer_eval(strcmp(x, y) == -1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strcmp_diff_length_3>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <clang_analyzer_eval@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void strcmp_diff_length_3() {
  char *x = "123";
  char *y = "12345";
  clang_analyzer_eval(strcmp(x, y) == -1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp_diff_length_3>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <clang_analyzer_eval@plt>
```

assistant: ```c
void strcmp_diff_length_3() {
  char *x = "123";
  char *y = "12345";
  clang_analyzer_eval(strcmp(x, y) == -1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcmp_diff_length_3>:
  endbr64
  mov    $0x1,%edi
  jmp    1050 <clang_analyzer_eval@plt>
```

assistant: ```c
void strcmp_diff_length_3() {
  char *x = "123";
  char *y = "12345";
  clang_analyzer_eval(strcmp(x, y) == -1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<waitfor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  nop
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    %al,-0x4(%rbp)
  jne    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void waitfor(char c) {
  while (getchar() != c) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<waitfor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
L7:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    %bl,%al
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void waitfor(char c) {
  while (getchar() != c) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<waitfor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %bl,%al
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void waitfor(char c) {
  while (getchar() != c) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<waitfor>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %bl,%al
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void waitfor(char c) {
  while (getchar() != c) {
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<dbchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,-0x8(%rbp)
  andl   $0xff,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L31
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x7e,(%rax)
  andl   $0x7f,-0x14(%rbp)
L31:
  cmpl   $0x1f,-0x14(%rbp)
  jg     L20
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x5e,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  xor    $0x40,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L21
L20:
  cmpl   $0x7f,-0x14(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x5e,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x3f,(%rax)
  jmp    L21
L5:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %dl,(%rax)
L21:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D12(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *dbchr(c)
int c;
{
  static char s[8];
  char *cp = s;
  c &= 0xff;
  if (c & 0x80) {
    *cp++ = '~';
    c &= 0x7f;
  }
  if (c < 32) {
    *cp++ = '^';
    *cp++ = (char)(((c) ^ 64) & 0xFF);
  } else if (c == 127) {
    *cp++ = '^';
    *cp++ = '?';
  } else {
    *cp++ = (char)c;
  }
  *cp = '\0';
  cp = s;
  return (cp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dbchr>:
  endbr64
  test   $0x80,%dil
  jne    L27
  movzbl %dil,%edi
  lea    D34(%rip),%rax
  jmp    L21
L27:
  movb   $0x7e,D34(%rip)
  and    $0x7f,%edi
  lea    D3(%rip),%rax
L21:
  cmp    $0x1f,%edi
  jg     L12
  movb   $0x5e,(%rax)
  lea    0x2(%rax),%rdx
  xor    $0x40,%edi
  mov    %dil,0x1(%rax)
L30:
  movb   $0x0,(%rdx)
  lea    D34(%rip),%rax
  ret
L12:
  cmp    $0x7f,%edi
  je     L51
  lea    0x1(%rax),%rdx
  mov    %dil,(%rax)
  jmp    L30
L51:
  movb   $0x5e,(%rax)
  lea    0x2(%rax),%rdx
  movb   $0x3f,0x1(%rax)
  jmp    L30
```

assistant: ```c
char *dbchr(c)
int c;
{
  static char s[8];
  char *cp = s;
  c &= 0xff;
  if (c & 0x80) {
    *cp++ = '~';
    c &= 0x7f;
  }
  if (c < 32) {
    *cp++ = '^';
    *cp++ = (char)(((c) ^ 64) & 0xFF);
  } else if (c == 127) {
    *cp++ = '^';
    *cp++ = '?';
  } else {
    *cp++ = (char)c;
  }
  *cp = '\0';
  cp = s;
  return (cp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dbchr>:
  endbr64
  test   $0x80,%dil
  jne    L27
  lea    D18(%rip),%r8
  movzbl %dil,%edi
  mov    %r8,%rax
  cmp    $0x1f,%edi
  jg     L1
L16:
  lea    0x2(%rax),%rdx
  xor    $0x40,%edi
  movb   $0x5e,(%rax)
  mov    %dil,0x1(%rax)
  mov    %r8,%rax
  movb   $0x0,(%rdx)
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  lea    D27(%rip),%rax
  and    $0x7f,%edi
  movb   $0x7e,D18(%rip)
  lea    -0x1(%rax),%r8
  cmp    $0x1f,%edi
  jle    L16
L1:
  cmp    $0x7f,%edi
  je     L14
  lea    0x1(%rax),%rdx
  mov    %dil,(%rax)
  mov    %r8,%rax
  movb   $0x0,(%rdx)
  ret
  nopl   (%rax)
L14:
  lea    0x2(%rax),%rdx
  mov    $0x3f5e,%ecx
  mov    %cx,(%rax)
  mov    %r8,%rax
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *dbchr(c)
int c;
{
  static char s[8];
  char *cp = s;
  c &= 0xff;
  if (c & 0x80) {
    *cp++ = '~';
    c &= 0x7f;
  }
  if (c < 32) {
    *cp++ = '^';
    *cp++ = (char)(((c) ^ 64) & 0xFF);
  } else if (c == 127) {
    *cp++ = '^';
    *cp++ = '?';
  } else {
    *cp++ = (char)c;
  }
  *cp = '\0';
  cp = s;
  return (cp);
}
```