ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<pwHelper>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L4
L1:
  pxor   %xmm2,%xmm2
  cvtsi2sd %ebx,%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm1
  addsd  D10(%rip),%xmm1
  movsd  D43(%rip),%xmm0
  call   <pow@plt>
  movsbl 0x0(%rbp,%rbx,1),%r13d
  movsbl %al,%eax
  imul   %eax,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  0x8(%rsp),%xmm1
  subsd  D41(%rip),%xmm1
  movsd  D9(%rip),%xmm0
  call   <pow@plt>
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
  add    $0x1,%rbx
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L1
  mov    %r12d,%edi
  call   <intlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  lea    D37(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12d,%edi
  call   <intlen@plt>
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D43
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D41
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D9
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D37
datatype: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D37: %d

assistant: ```c
char *pwHelper(char *pw) {
  int newPW = 0;
  int i;
  for (i = 0; i < strlen(pw); i++) {
    newPW += pow((double)-1, (double)i + 2) * pw[i] * pow((double)10, (double)strlen(pw) - i - 1);
  }
  char *numstr = malloc(sizeof(char) * (intlen(newPW) + 1));
  sprintf(numstr, "%d", newPW);
  numstr[intlen(newPW)] = '\0';
  return numstr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pwHelper>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L2:
  pxor   %xmm2,%xmm2
  movsd  D25(%rip),%xmm1
  mov    D6(%rip),%rax
  cvtsi2sd %ebx,%xmm2
  movq   %rax,%xmm0
  addsd  %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsbl 0x0(%rbp,%rbx,1),%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  movsbl %al,%eax
  imul   %eax,%r13d
  call   <strlen@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm2
  cvtsi2sd %eax,%xmm1
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  subsd  %xmm2,%xmm1
  subsd  D37(%rip),%xmm1
  call   <pow@plt>
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
  mov    %r12d,%edi
  call   <intlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  mov    %r12d,%edi
  call   <intlen@plt>
  movb   $0x0,0x0(%r13,%rax,1)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D6
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D7
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D37
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D9
datatype: string

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D9: %d

assistant: ```c
char *pwHelper(char *pw) {
  int newPW = 0;
  int i;
  for (i = 0; i < strlen(pw); i++) {
    newPW += pow((double)-1, (double)i + 2) * pw[i] * pow((double)10, (double)strlen(pw) - i - 1);
  }
  char *numstr = malloc(sizeof(char) * (intlen(newPW) + 1));
  sprintf(numstr, "%d", newPW);
  numstr[intlen(newPW)] = '\0';
  return numstr;
}
```
user: What is the c source code of the assembly code below?

```asm
<pwHelper>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L7:
  pxor   %xmm2,%xmm2
  movsd  D21(%rip),%xmm1
  mov    D5(%rip),%rax
  cvtsi2sd %ebx,%xmm2
  movq   %rax,%xmm0
  addsd  %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsbl 0x0(%rbp,%rbx,1),%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  movsbl %al,%eax
  imul   %eax,%r13d
  call   <strlen@plt>
  pxor   %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm2
  cvtsi2sd %eax,%xmm1
  mov    D36(%rip),%rax
  movq   %rax,%xmm0
  subsd  %xmm2,%xmm1
  subsd  D34(%rip),%xmm1
  call   <pow@plt>
  movsbl %al,%eax
  imul   %r13d,%eax
  add    %eax,%r12d
L1:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  mov    %r12d,%edi
  call   <intlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  mov    %r12d,%edi
  call   <intlen@plt>
  movb   $0x0,0x0(%r13,%rax,1)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D21
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D5
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D36
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D34
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D10
type_guessed: string

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D10: %d

assistant: ```c
char *pwHelper(char *pw) {
  int newPW = 0;
  int i;
  for (i = 0; i < strlen(pw); i++) {
    newPW += pow((double)-1, (double)i + 2) * pw[i] * pow((double)10, (double)strlen(pw) - i - 1);
  }
  char *numstr = malloc(sizeof(char) * (intlen(newPW) + 1));
  sprintf(numstr, "%d", newPW);
  numstr[intlen(newPW)] = '\0';
  return numstr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <foo4@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int foo5(int *a) {
  int b = 5;
  return foo4(a, &b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo5>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x5,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  call   <foo4@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo5(int *a) {
  int b = 5;
  return foo4(a, &b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo5>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x5,0x4(%rsp)
  call   <foo4@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo5(int *a) {
  int b = 5;
  return foo4(a, &b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo5>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x5,0x4(%rsp)
  call   <foo4@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int foo5(int *a) {
  int b = 5;
  return foo4(a, &b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_compar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int int_compar(const void *x, const void *y, void *context) {
  (void)context;
  return *(int *)x - *(int *)y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int_compar>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int int_compar(const void *x, const void *y, void *context) {
  (void)context;
  return *(int *)x - *(int *)y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int_compar>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int int_compar(const void *x, const void *y, void *context) {
  (void)context;
  return *(int *)x - *(int *)y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<int_compar>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int int_compar(const void *x, const void *y, void *context) {
  (void)context;
  return *(int *)x - *(int *)y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<put_etf_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  jmp    L62
L14:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  test   %eax,%eax
  jle    L62
  movss  -0x4(%rbp),%xmm0
  jmp    L72
L62:
  cmpl   $0x0,-0x14(%rbp)
  jns    L14
  jmp    L17
L45:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  test   %eax,%eax
  jle    L17
  movss  -0x8(%rbp),%xmm0
  jmp    L72
L17:
  cmpl   $0x2303,-0x14(%rbp)
  jle    L45
L72:
  pop    %rbp
  ret
```

assistant: ```c
float put_etf_value(int day, int etf_index, float **values) {
  while (day >= 0) {
    float val = values[day--][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
  while (day < 8964) {
    float val = values[day++][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put_etf_value>:
  endbr64
  movslq %esi,%rsi
  shl    $0x2,%rsi
  movslq %edi,%rdi
L24:
  mov    %edi,%eax
  test   %edi,%edi
  js     L5
  mov    (%rdx,%rdi,8),%rax
  movss  (%rax,%rsi,1),%xmm0
  sub    $0x1,%rdi
  cvttss2si %xmm0,%eax
  test   %eax,%eax
  jle    L24
L10:
  ret
L5:
  cltq
L29:
  mov    (%rdx,%rax,8),%rcx
  movss  (%rcx,%rsi,1),%xmm0
  cvttss2si %xmm0,%ecx
  test   %ecx,%ecx
  jg     L10
  add    $0x1,%rax
  cmp    $0x2303,%eax
  jle    L29
  jmp    L10
```

assistant: ```c
float put_etf_value(int day, int etf_index, float **values) {
  while (day >= 0) {
    float val = values[day--][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
  while (day < 8964) {
    float val = values[day++][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<put_etf_value>:
  endbr64
  movslq %esi,%rax
  movslq %edi,%rdi
  shl    $0x2,%rax
  jmp    L23
L28:
  sub    $0x1,%rdi
  test   %ecx,%ecx
  jg     L1
L23:
  mov    (%rdx,%rdi,8),%rcx
  mov    %edi,%esi
  movss  (%rcx,%rax,1),%xmm0
  cvttss2si %xmm0,%ecx
  test   %edi,%edi
  jns    L28
  movslq %edi,%r8
  mov    $0x2303,%edi
  sub    %esi,%edi
  lea    (%rdx,%r8,8),%rcx
  lea    (%rdi,%r8,1),%rsi
  lea    0x8(%rdx,%rsi,8),%rsi
  nopw   0x0(%rax,%rax,1)
L34:
  mov    (%rcx),%rdx
  movss  (%rdx,%rax,1),%xmm0
  cvttss2si %xmm0,%edx
  test   %edx,%edx
  jg     L1
  add    $0x8,%rcx
  cmp    %rcx,%rsi
  jne    L34
L1:
  ret
```

assistant: ```c
float put_etf_value(int day, int etf_index, float **values) {
  while (day >= 0) {
    float val = values[day--][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
  while (day < 8964) {
    float val = values[day++][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<put_etf_value>:
  endbr64
  movslq %esi,%rax
  movslq %edi,%rdi
  shl    $0x2,%rax
  jmp    L2
L25:
  sub    $0x1,%rdi
  test   %ecx,%ecx
  jg     L32
L2:
  mov    (%rdx,%rdi,8),%rcx
  mov    %edi,%esi
  movss  (%rcx,%rax,1),%xmm0
  cvttss2si %xmm0,%ecx
  test   %edi,%edi
  jns    L25
  movslq %edi,%r8
  mov    $0x2303,%edi
  sub    %esi,%edi
  lea    (%rdx,%r8,8),%rcx
  lea    (%rdi,%r8,1),%rsi
  lea    0x8(%rdx,%rsi,8),%rsi
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%rcx),%rdx
  movss  (%rdx,%rax,1),%xmm0
  cvttss2si %xmm0,%edx
  test   %edx,%edx
  jg     L32
  add    $0x8,%rcx
  cmp    %rcx,%rsi
  jne    L23
L32:
  ret
```

assistant: ```c
float put_etf_value(int day, int etf_index, float **values) {
  while (day >= 0) {
    float val = values[day--][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
  while (day < 8964) {
    float val = values[day++][etf_index];
    if ((int)val > 0) {
      return val;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<baz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *__attribute__((no)) baz(void **lab) {
  asm volatile("" : "+r"(lab));
  return *lab;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<baz>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
void *__attribute__((no)) baz(void **lab) {
  asm volatile("" : "+r"(lab));
  return *lab;
}
```
user: What is the c source code of the assembly code below?

```asm
<baz>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
void *__attribute__((no)) baz(void **lab) {
  asm volatile("" : "+r"(lab));
  return *lab;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<baz>:
  endbr64
  mov    (%rdi),%rax
  ret
```

assistant: ```c
void *__attribute__((no)) baz(void **lab) {
  asm volatile("" : "+r"(lab));
  return *lab;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<docall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <lcall@plt>
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <report@plt>
  leave
  ret
```

assistant: ```c
int docall(int status) {
  if (status == 0)
    status = lcall(0, 1);
  return report(status);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<docall>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L17
L9:
  call   <report@plt>
  add    $0x8,%rsp
  ret
L17:
  mov    $0x1,%esi
  call   <lcall@plt>
  mov    %eax,%edi
  jmp    L9
```

assistant: ```c
int docall(int status) {
  if (status == 0)
    status = lcall(0, 1);
  return report(status);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<docall>:
  endbr64
  test   %edi,%edi
  je     L6
  jmp    1070 <report@plt>
  nopl   (%rax)
L6:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <lcall@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <report@plt>
```

assistant: ```c
int docall(int status) {
  if (status == 0)
    status = lcall(0, 1);
  return report(status);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<docall>:
  endbr64
  test   %edi,%edi
  je     L1
  jmp    1070 <report@plt>
  nopl   (%rax)
L1:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <lcall@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1070 <report@plt>
```

assistant: ```c
int docall(int status) {
  if (status == 0)
    status = lcall(0, 1);
  return report(status);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_latitude_longitude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <timlib_latitude_longitude_degrees_minutes_to_decimal@plt>
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <timlib_latitude_longitude_degrees_minutes_to_decimal@plt>
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <timlib_latitude_longitude_degrees_decimal_to_minutes@plt>
  mov    %rax,%rsi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <timlib_latitude_longitude_degrees_decimal_to_minutes@plt>
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D49
data_type: string
name: disassemble_data
arguments: label: D13
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D50
data_type: string
name: disassemble_data
arguments: label: D11
data_type: string
name: disassemble_data
arguments: label: D19
data_type: string

tool: D6: 25 33.14

tool: D4: Latitude to decimal: should be 25.55233 is %.5lf


tool: D49: -81 12.61

tool: D13: Longitude to decimal: should be -81.21017 is %.5lf


tool: D10: 25.55233

tool: D50: Latitude to minutes: should be 25 33.14 is %s


tool: D11: -81.21017

tool: D19: Latitude to minutes: should be -81 12.61 is %s


assistant: ```c
void test_latitude_longitude(void) {
  printf("Latitude to decimal: should be 25.55233 is %.5lf\n", timlib_latitude_longitude_degrees_minutes_to_decimal("25 33.14"));
  printf("Longitude to decimal: should be -81.21017 is %.5lf\n", timlib_latitude_longitude_degrees_minutes_to_decimal("-81 12.61"));
  printf("Latitude to minutes: should be 25 33.14 is %s\n", timlib_latitude_longitude_degrees_decimal_to_minutes("25.55233"));
  printf("Latitude to minutes: should be -81 12.61 is %s\n", timlib_latitude_longitude_degrees_decimal_to_minutes("-81.21017"));
}
```
user: What is the c source code of the assembly code below:

```asm
<test_latitude_longitude>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_minutes_to_decimal@plt>
  mov    %rax,%rsi
  lea    D65(%rip),%rdi
  call   <printf@plt>
  lea    D72(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_minutes_to_decimal@plt>
  mov    %rax,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_decimal_to_minutes@plt>
  mov    %rax,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_decimal_to_minutes@plt>
  mov    %rax,%rsi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
type_guessed: string
name: unpack_data
arguments: tag: D65
type_guessed: string
name: unpack_data
arguments: tag: D72
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D63
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D45
type_guessed: string

tool: D28: 25 33.14

tool: D65: Latitude to decimal: should be 25.55233 is %.5lf


tool: D72: -81 12.61

tool: D13: Longitude to decimal: should be -81.21017 is %.5lf


tool: D63: 25.55233

tool: D19: Latitude to minutes: should be 25 33.14 is %s


tool: D3: -81.21017

tool: D45: Latitude to minutes: should be -81 12.61 is %s


assistant: ```c
void test_latitude_longitude(void) {
  printf("Latitude to decimal: should be 25.55233 is %.5lf\n", timlib_latitude_longitude_degrees_minutes_to_decimal("25 33.14"));
  printf("Longitude to decimal: should be -81.21017 is %.5lf\n", timlib_latitude_longitude_degrees_minutes_to_decimal("-81 12.61"));
  printf("Latitude to minutes: should be 25 33.14 is %s\n", timlib_latitude_longitude_degrees_decimal_to_minutes("25.55233"));
  printf("Latitude to minutes: should be -81 12.61 is %s\n", timlib_latitude_longitude_degrees_decimal_to_minutes("-81.21017"));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_latitude_longitude>:
  endbr64
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_minutes_to_decimal@plt>
  lea    D50(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_minutes_to_decimal@plt>
  lea    D32(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D78(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_decimal_to_minutes@plt>
  lea    D4(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <timlib_latitude_longitude_degrees_decimal_to_minutes@plt>
  lea    D51(%rip),%rdi
  add    $0x8,%rsp
  mov    %rax,%rsi
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D28
type: string
name: parse_data
arguments: label: D50
type: string
name: parse_data
arguments: label: D73
type: string
name: parse_data
arguments: label: D32
type: string
name: parse_data
arguments: label: D78
type: string
name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D65
type: string
name: parse_data
arguments: label: D51
type: string

tool: D28: 25 33.14

tool: D50: Latitude to decimal: should be 25.55233 is %.5lf


tool: D73: -81 12.61

tool: D32: Longitude to decimal: should be -81.21017 is %.5lf


tool: D78: 25.55233

tool: D4: Latitude to minutes: should be 25 33.14 is %s


tool: D65: -81.21017

tool: D51: Latitude to minutes: should be -81 12.61 is %s


assistant: ```c
void test_latitude_longitude(void) {
  printf("Latitude to decimal: should be 25.55233 is %.5lf\n", timlib_latitude_longitude_degrees_minutes_to_decimal("25 33.14"));
  printf("Longitude to decimal: should be -81.21017 is %.5lf\n", timlib_latitude_longitude_degrees_minutes_to_decimal("-81 12.61"));
  printf("Latitude to minutes: should be 25 33.14 is %s\n", timlib_latitude_longitude_degrees_decimal_to_minutes("25.55233"));
  printf("Latitude to minutes: should be -81 12.61 is %s\n", timlib_latitude_longitude_degrees_decimal_to_minutes("-81.21017"));
}
```