ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<hash_value>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  xor    %eax,%eax
  nopl   (%rax)
L11:
  mov    %eax,%ecx
  add    $0x1,%rdi
  shl    $0x5,%ecx
  sub    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L11
  mov    %eax,%edx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x21,%rdx
  lea    (%rdx,%rdx,8),%edx
  sub    %edx,%eax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int hash_value(char *s) {
  unsigned int h;
  for (h = 0; *s != '\0'; s++)
    h = *s + 31 * h;
  return (h % (10 - 1)) + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L3
L10:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <insert@plt>
L3:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jne    L10
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <preorder_iterative@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <destroy_tree@plt>
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
datatype: string

tool: D19: %d

assistant: ```c
int main(int argc, char *argv[]) {
  struct node *root = NULL;
  int n;
  int input;
  scanf("%d", &n);
  while (n--) {
    scanf("%d", &input);
    insert(input, &root);
  }
  preorder_iterative(root);
  destroy_tree(root);
  root = NULL;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  lea    0x8(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L12
  lea    D4(%rip),%rbx
L9:
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    0xc(%rsp),%edi
  call   <insert@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L9
L12:
  mov    0x10(%rsp),%rdi
  call   <preorder_iterative@plt>
  mov    0x10(%rsp),%rdi
  call   <destroy_tree@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: string

tool: D4: %d

assistant: ```c
int main(int argc, char *argv[]) {
  struct node *root = NULL;
  int n;
  int input;
  scanf("%d", &n);
  while (n--) {
    scanf("%d", &input);
    insert(input, &root);
  }
  preorder_iterative(root);
  destroy_tree(root);
  root = NULL;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L17
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <insert@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L24
L17:
  mov    0x10(%rsp),%rdi
  call   <preorder_iterative@plt>
  mov    0x10(%rsp),%rdi
  call   <destroy_tree@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3: %d

assistant: ```c
int main(int argc, char *argv[]) {
  struct node *root = NULL;
  int n;
  int input;
  scanf("%d", &n);
  while (n--) {
    scanf("%d", &input);
    insert(input, &root);
  }
  preorder_iterative(root);
  destroy_tree(root);
  root = NULL;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  movq   $0x0,0x10(%rsp)
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L24
  lea    0xc(%rsp),%r12
  lea    0x10(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rsi
  call   <insert@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L14
L24:
  mov    0x10(%rsp),%rdi
  call   <preorder_iterative@plt>
  mov    0x10(%rsp),%rdi
  call   <destroy_tree@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string

tool: D4: %d

assistant: ```c
int main(int argc, char *argv[]) {
  struct node *root = NULL;
  int n;
  int input;
  scanf("%d", &n);
  while (n--) {
    scanf("%d", &input);
    insert(input, &root);
  }
  preorder_iterative(root);
  destroy_tree(root);
  root = NULL;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__wrd_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <__short_int_memset@plt>
  nop
  leave
  ret
```

assistant: ```c
void __wrd_memset(void *__restrict s, int c, size_t n) {
  int sc = ((c << 8) + (char)c);
  __short_int_memset(s, sc, n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__wrd_memset>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  shl    $0x8,%eax
  movsbl %sil,%esi
  add    %eax,%esi
  call   <__short_int_memset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __wrd_memset(void *__restrict s, int c, size_t n) {
  int sc = ((c << 8) + (char)c);
  __short_int_memset(s, sc, n);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__wrd_memset>:
  endbr64
  mov    %esi,%eax
  movsbl %sil,%esi
  shl    $0x8,%eax
  add    %eax,%esi
  jmp    1050 <__short_int_memset@plt>
```

assistant: ```c
void __wrd_memset(void *__restrict s, int c, size_t n) {
  int sc = ((c << 8) + (char)c);
  __short_int_memset(s, sc, n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__wrd_memset>:
  endbr64
  mov    %esi,%eax
  movsbl %sil,%esi
  shl    $0x8,%eax
  add    %eax,%esi
  jmp    1050 <__short_int_memset@plt>
```

assistant: ```c
void __wrd_memset(void *__restrict s, int c, size_t n) {
  int sc = ((c << 8) + (char)c);
  __short_int_memset(s, sc, n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trimmed_getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L46:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jge    L55
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0x20,-0x4(%rbp)
  je     L55
  cmpl   $0x9,-0x4(%rbp)
  je     L55
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L55:
  addl   $0x1,-0xc(%rbp)
L10:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L64
  cmpl   $0xa,-0x4(%rbp)
  jne    L46
L64:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L37
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L37:
  cmpl   $0xa,-0x4(%rbp)
  jne    L44
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L44:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int trimmed_getline(char s[], int lim) {
  int c, i, l;
  for (i = 0, l = 0; (c = getchar()) != EOF && c != '\n'; i++) {
    if (i < lim - 1) {
      s[i] = c;
      if (c != ' ' && c != '\t') {
        l = i;
      }
    }
  }
  if (i > l + 1) {
    i = l;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<trimmed_getline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  lea    -0x1(%rsi),%r12d
  jmp    L75
L63:
  add    $0x1,%rbx
L75:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L64
  cmp    $0xa,%eax
  je     L64
  cmp    %ebx,%r12d
  jle    L63
  mov    %al,(%r14,%rbx,1)
  cmp    $0x20,%eax
  je     L63
  cmp    $0x9,%eax
  cmovne %ebp,%r13d
  jmp    L63
L64:
  lea    0x1(%r13),%edx
  cmp    %ebp,%edx
  cmovl  %r13d,%ebp
  cmp    $0xa,%eax
  je     L43
L58:
  movslq %ebp,%rax
  movb   $0x0,(%r14,%rax,1)
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  movslq %ebp,%rax
  movb   $0xa,(%r14,%rax,1)
  add    $0x1,%ebp
  jmp    L58
```

assistant: ```c
int trimmed_getline(char s[], int lim) {
  int c, i, l;
  for (i = 0, l = 0; (c = getchar()) != EOF && c != '\n'; i++) {
    if (i < lim - 1) {
      s[i] = c;
      if (c != ' ' && c != '\t') {
        l = i;
      }
    }
  }
  if (i > l + 1) {
    i = l;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trimmed_getline>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbp
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L54:
  cmp    $0xa,%eax
  je     L34
  cmp    %r15d,%ebx
  jle    L37
  mov    %al,(%r14,%r15,1)
  cmp    $0x20,%eax
  je     L37
  cmp    $0x9,%eax
  cmovne %r15d,%r13d
L37:
  add    $0x1,%r15
L59:
  xor    %eax,%eax
  mov    %r15d,%r12d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L54
  lea    0x1(%r13),%edx
  cmp    %r15d,%edx
  cmovl  %r13d,%r12d
  cmp    $0xa,%eax
  je     L21
L49:
  movslq %r12d,%rax
  movb   $0x0,(%r14,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  lea    0x1(%r13),%eax
  cmp    %eax,%r15d
  jg     L74
L21:
  lea    0x1(%r12),%eax
  mov    %r12d,%r13d
L74:
  movslq %r13d,%r13
  mov    %eax,%r12d
  movb   $0xa,(%r14,%r13,1)
  jmp    L49
```

assistant: ```c
int trimmed_getline(char s[], int lim) {
  int c, i, l;
  for (i = 0, l = 0; (c = getchar()) != EOF && c != '\n'; i++) {
    if (i < lim - 1) {
      s[i] = c;
      if (c != ' ' && c != '\t') {
        l = i;
      }
    }
  }
  if (i > l + 1) {
    i = l;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<trimmed_getline>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbp
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    $0xa,%eax
  je     L43
  cmp    %r15d,%ebx
  jle    L66
  mov    %al,(%r14,%r15,1)
  cmp    $0x20,%eax
  je     L66
  cmp    $0x9,%eax
  cmovne %r15d,%r13d
L66:
  add    $0x1,%r15
L27:
  xor    %eax,%eax
  mov    %r15d,%r12d
  call   <getchar@plt>
  cmp    %eax,0x0(%rbp)
  jne    L21
  lea    0x1(%r13),%edx
  cmp    %r15d,%edx
  cmovl  %r13d,%r12d
  cmp    $0xa,%eax
  je     L67
L14:
  movslq %r12d,%rax
  movb   $0x0,(%r14,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  lea    0x1(%r13),%eax
  cmp    %eax,%r15d
  jg     L59
L67:
  lea    0x1(%r12),%eax
  mov    %r12d,%r13d
L59:
  movslq %r13d,%r13
  mov    %eax,%r12d
  movb   $0xa,(%r14,%r13,1)
  jmp    L14
```

assistant: ```c
int trimmed_getline(char s[], int lim) {
  int c, i, l;
  for (i = 0, l = 0; (c = getchar()) != EOF && c != '\n'; i++) {
    if (i < lim - 1) {
      s[i] = c;
      if (c != ' ' && c != '\t') {
        l = i;
      }
    }
  }
  if (i > l + 1) {
    i = l;
  }
  if (c == '\n') {
    s[i] = c;
    i++;
  }
  s[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<procstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdupe@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L19
L12:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <process@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x10(%rbp)
L19:
  cmpq   $0x0,-0x10(%rbp)
  jne    L12
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type_infered: string

tool: D18:  

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g;
  g = strtok(h, " ");
  while (g) {
    process(g);
    g = strtok(NULL, " ");
  }
  free(h);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<procstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strdupe@plt>
  mov    %rax,%rbp
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  lea    D4(%rip),%rbx
L9:
  call   <process@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L9
L15:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4:  

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g;
  g = strtok(h, " ");
  while (g) {
    process(g);
    g = strtok(NULL, " ");
  }
  free(h);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<procstr>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D1(%rip),%rbx
  sub    $0x8,%rsp
  call   <strdupe@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strtok@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rdi
  nopl   0x0(%rax)
L11:
  call   <process@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
L18:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1080 <free@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D1:  

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g;
  g = strtok(h, " ");
  while (g) {
    process(g);
    g = strtok(NULL, " ");
  }
  free(h);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<procstr>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x8,%rsp
  call   <strdupe@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strtok@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  nopl   0x0(%rax)
L6:
  call   <process@plt>
  xor    %edi,%edi
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L6
L12:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1080 <free@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6:  

assistant: ```c
void procstr(char *s) {
  char *h = strdupe(s);
  char *g;
  g = strtok(h, " ");
  while (g) {
    process(g);
    g = strtok(NULL, " ");
  }
  free(h);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L12:
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L30
  mov    -0x8(%rbp),%rcx
  movabs $0x5555555555555556,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rsi
  sar    $0x3f,%rsi
  mov    %rdx,%rax
  sub    %rsi,%rax
  mov    %rax,%rdx
  add    %rdx,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L30
  mov    -0x8(%rbp),%rcx
  movabs $0x4924924924924925,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    %rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x3,%rdx
  sub    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L30
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  addq   $0x1,-0x8(%rbp)
L4:
  cmpq   $0x752f,-0x8(%rbp)
  jle    L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %ld


assistant: ```c
int main() {
  long int number;
  for (number = 0; number < 30000; number++) {
    if (number % 2 != 0) {
      if (number % 3 == 0 && number % 7 == 0) {
        printf("%ld\n", number);
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  movabs $0x5555555555555556,%r12
  movabs $0x4924924924924925,%rbp
  lea    D3(%rip),%r13
L38:
  add    $0x1,%rbx
  cmp    $0x7530,%rbx
  je     L32
  test   $0x1,%bl
  je     L38
  mov    %rbx,%rax
  imul   %r12
  mov    %rbx,%rcx
  sar    $0x3f,%rcx
  sub    %rcx,%rdx
  lea    (%rdx,%rdx,2),%rax
  mov    %rbx,%rsi
  sub    %rax,%rsi
  mov    %rbx,%rax
  imul   %rbp
  sar    %rdx
  sub    %rcx,%rdx
  lea    0x0(,%rdx,8),%rax
  sub    %rdx,%rax
  mov    %rbx,%rdx
  sub    %rax,%rdx
  or     %rsi,%rdx
  jne    L38
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L38
L32:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: %ld


assistant: ```c
int main() {
  long int number;
  for (number = 0; number < 30000; number++) {
    if (number % 2 != 0) {
      if (number % 3 == 0 && number % 7 == 0) {
        printf("%ld\n", number);
      }
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  movabs $0xaaaaaaaaaaaaaaab,%r13
  push   %r12
  movabs $0x4924924924924925,%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rbx
  cmp    $0x7530,%rbx
  je     L32
L33:
  test   $0x1,%bl
  je     L38
  mov    %rbx,%rax
  mov    %rbx,%rcx
  mul    %r13
  mov    %rdx,%rax
  and    $0xfffffffffffffffe,%rdx
  shr    %rax
  add    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rcx
  imul   %r12
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  lea    0x0(,%rdx,8),%rax
  sub    %rdx,%rax
  mov    %rbx,%rdx
  sub    %rax,%rdx
  or     %rcx,%rdx
  jne    L38
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7530,%rbx
  jne    L33
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: %ld


assistant: ```c
int main() {
  long int number;
  for (number = 0; number < 30000; number++) {
    if (number % 2 != 0) {
      if (number % 3 == 0 && number % 7 == 0) {
        printf("%ld\n", number);
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  movabs $0xaaaaaaaaaaaaaaab,%r13
  push   %r12
  movabs $0x4924924924924925,%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L31
L17:
  add    $0x1,%rbx
  cmp    $0x7530,%rbx
  je     L30
L31:
  test   $0x1,%bl
  je     L17
  mov    %rbx,%rax
  mov    %rbx,%rcx
  mul    %r13
  mov    %rdx,%rax
  and    $0xfffffffffffffffe,%rdx
  shr    %rax
  add    %rax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rcx
  imul   %r12
  mov    %rbx,%rax
  sar    $0x3f,%rax
  sar    %rdx
  sub    %rax,%rdx
  lea    0x0(,%rdx,8),%rax
  sub    %rdx,%rax
  mov    %rbx,%rdx
  sub    %rax,%rdx
  or     %rcx,%rdx
  jne    L17
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7530,%rbx
  jne    L31
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: %ld


assistant: ```c
int main() {
  long int number;
  for (number = 0; number < 30000; number++) {
    if (number % 2 != 0) {
      if (number % 3 == 0 && number % 7 == 0) {
        printf("%ld\n", number);
      }
    }
  }
  return 0;
}
```