ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<DrawDisk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    $0x0,%eax
  call   <glPushMatrix@plt>
  mov    $0x0,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <glTranslatef@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x5a,%edi
  call   <glRotatef@plt>
  mov    %ebx,%edi
  call   <glCallList@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void DrawDisk(int xcenter, int ycenter, int size) {
  glPushMatrix();
  {
    glTranslatef(xcenter, ycenter, 0);
    glRotatef(90, 1, 0, 0);
    glCallList(size);
  }
  glPopMatrix();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<DrawDisk>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  call   <glPushMatrix@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  xor    %edx,%edx
  call   <glTranslatef@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x5a,%edi
  call   <glRotatef@plt>
  mov    %ebp,%edi
  call   <glCallList@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glPopMatrix@plt>
```

assistant: ```c
void DrawDisk(int xcenter, int ycenter, int size) {
  glPushMatrix();
  {
    glTranslatef(xcenter, ycenter, 0);
    glRotatef(90, 1, 0, 0);
    glCallList(size);
  }
  glPopMatrix();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<DrawDisk>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  call   <glPushMatrix@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  xor    %edx,%edx
  call   <glTranslatef@plt>
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x5a,%edi
  call   <glRotatef@plt>
  mov    %ebp,%edi
  call   <glCallList@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glPopMatrix@plt>
```

assistant: ```c
void DrawDisk(int xcenter, int ycenter, int size) {
  glPushMatrix();
  {
    glTranslatef(xcenter, ycenter, 0);
    glRotatef(90, 1, 0, 0);
    glCallList(size);
  }
  glPopMatrix();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xdebug_hash_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x1505,-0x10(%rbp)
  jmp    L8
L10:
  mov    -0x10(%rbp),%rax
  shl    $0x5,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rax,-0x10(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L10
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long xdebug_hash_str(const char *key, unsigned int key_length) {
  char *p = (char *)key;
  char *end = (char *)key + key_length;
  unsigned long h = 5381;
  while (p < end) {
    h += h << 5;
    h ^= (unsigned long)*p++;
  }
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xdebug_hash_str>:
  endbr64
  mov    %esi,%esi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L17
  mov    $0x1505,%eax
L10:
  mov    %rax,%rdx
  shl    $0x5,%rdx
  add    %rdx,%rax
  add    $0x1,%rdi
  movsbq -0x1(%rdi),%rdx
  xor    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L10
  ret
L17:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned long xdebug_hash_str(const char *key, unsigned int key_length) {
  char *p = (char *)key;
  char *end = (char *)key + key_length;
  unsigned long h = 5381;
  while (p < end) {
    h += h << 5;
    h ^= (unsigned long)*p++;
  }
  return h;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xdebug_hash_str>:
  endbr64
  mov    %esi,%esi
  mov    $0x1505,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L13
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  xor    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L4
  ret
  nopl   0x0(%rax)
L13:
  ret
```

assistant: ```c
unsigned long xdebug_hash_str(const char *key, unsigned int key_length) {
  char *p = (char *)key;
  char *end = (char *)key + key_length;
  unsigned long h = 5381;
  while (p < end) {
    h += h << 5;
    h ^= (unsigned long)*p++;
  }
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xdebug_hash_str>:
  endbr64
  mov    %esi,%esi
  mov    $0x1505,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L1
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rax,%rdx
  add    $0x1,%rdi
  shl    $0x5,%rdx
  add    %rdx,%rax
  movsbq -0x1(%rdi),%rdx
  xor    %rdx,%rax
  cmp    %rdi,%rsi
  jne    L6
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
unsigned long xdebug_hash_str(const char *key, unsigned int key_length) {
  char *p = (char *)key;
  char *end = (char *)key + key_length;
  unsigned long h = 5381;
  while (p < end) {
    h += h << 5;
    h ^= (unsigned long)*p++;
  }
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xa0008820,%eax
  movl   $0x1111,(%rax)
  movl   $0x0,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    $0xa0008824,%eax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <delay@plt>
  cmpl   $0x3,-0x4(%rbp)
  jle    L10
  movl   $0x0,-0x4(%rbp)
  jmp    L10
```

assistant: ```c
int main(void) {
  *((volatile unsigned int *)(0xA0008820)) = 0x1111;
  int i = 0;
  while (1) {
    *((volatile unsigned int *)(0xA0008824)) = ~(1 << i++);
    delay();
    if (i > 3)
      i = 0;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa0008820,%eax
  movl   $0x1111,(%rax)
  lea    0x4(%rax),%rax
  movl   $0xfffffffe,(%rax)
  mov    $0x0,%eax
  call   <delay@plt>
  mov    $0x1,%ecx
  mov    $0xa0008824,%ebp
L8:
  lea    0x1(%rcx),%ebx
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x0,%eax
  call   <delay@plt>
  cmp    $0x4,%ebx
  mov    $0x0,%ecx
  cmovl  %ebx,%ecx
  jmp    L8
```

assistant: ```c
int main(void) {
  *((volatile unsigned int *)(0xA0008820)) = 0x1111;
  int i = 0;
  while (1) {
    *((volatile unsigned int *)(0xA0008824)) = ~(1 << i++);
    delay();
    if (i > 3)
      i = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa0008820,%eax
  xor    %ecx,%ecx
  mov    $0xa0008824,%ebp
  push   %rbx
  sub    $0x8,%rsp
  movl   $0x1111,(%rax)
  nopl   0x0(%rax)
L4:
  mov    $0xfffffffe,%eax
  lea    0x1(%rcx),%ebx
  rol    %cl,%eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <delay@plt>
  xor    %ecx,%ecx
  cmp    $0x4,%ebx
  cmovne %ebx,%ecx
  jmp    L4
```

assistant: ```c
int main(void) {
  *((volatile unsigned int *)(0xA0008820)) = 0x1111;
  int i = 0;
  while (1) {
    *((volatile unsigned int *)(0xA0008824)) = ~(1 << i++);
    delay();
    if (i > 3)
      i = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa0008820,%eax
  xor    %ecx,%ecx
  mov    $0xa0008824,%ebp
  push   %rbx
  sub    $0x8,%rsp
  movl   $0x1111,(%rax)
  nopl   0x0(%rax)
L3:
  mov    $0xfffffffe,%eax
  lea    0x1(%rcx),%ebx
  rol    %cl,%eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <delay@plt>
  xor    %ecx,%ecx
  cmp    $0x4,%ebx
  cmovne %ebx,%ecx
  jmp    L3
```

assistant: ```c
int main(void) {
  *((volatile unsigned int *)(0xA0008820)) = 0x1111;
  int i = 0;
  while (1) {
    *((volatile unsigned int *)(0xA0008824)) = ~(1 << i++);
    delay();
    if (i > 3)
      i = 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ylog_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fnmatch@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x1,%eax
  jmp    L68
L6:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L76
L79:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L32
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L32
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fnmatch@plt>
  test   %eax,%eax
  jne    L32
  mov    $0x1,%eax
  jmp    L68
L32:
  addq   $0x1,-0x8(%rbp)
L76:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L79
  mov    $0x0,%eax
L68:
  leave
  ret
```

assistant: ```c
int ylog_match(const char *pat, const char *fn) {
  const char *f;
  if (!fnmatch(pat, fn, 0))
    return 1;
  for (f = fn; *f; f++)
    if (*f == '/' && f[1] != '/' && !fnmatch(pat, f + 1, 0))
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<ylog_match>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%edx
  call   <fnmatch@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L61
  movzbl (%rbx),%eax
  test   %al,%al
  je     L81
  add    $0x1,%rbx
  jmp    L17
L50:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L78
L17:
  cmp    $0x2f,%al
  jne    L50
  cmpb   $0x2f,(%rbx)
  je     L50
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fnmatch@plt>
  test   %eax,%eax
  jne    L50
  mov    $0x1,%eax
  jmp    L61
L78:
  mov    $0x0,%eax
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L81:
  mov    $0x0,%eax
  jmp    L61
```

assistant: ```c
int ylog_match(const char *pat, const char *fn) {
  const char *f;
  if (!fnmatch(pat, fn, 0))
    return 1;
  for (f = fn; *f; f++)
    if (*f == '/' && f[1] != '/' && !fnmatch(pat, f + 1, 0))
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ylog_match>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <fnmatch@plt>
  test   %eax,%eax
  je     L40
L6:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L19
L50:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x2f,%al
  je     L29
  mov    %edx,%eax
  test   %al,%al
  jne    L50
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L42:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
L29:
  cmp    $0x2f,%dl
  je     L42
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fnmatch@plt>
  test   %eax,%eax
  jne    L6
L40:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ylog_match(const char *pat, const char *fn) {
  const char *f;
  if (!fnmatch(pat, fn, 0))
    return 1;
  for (f = fn; *f; f++)
    if (*f == '/' && f[1] != '/' && !fnmatch(pat, f + 1, 0))
      return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ylog_match>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <fnmatch@plt>
  test   %eax,%eax
  je     L7
L15:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L26
L2:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x2f,%al
  je     L18
  mov    %edx,%eax
  test   %al,%al
  jne    L2
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L51:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
L18:
  cmp    $0x2f,%dl
  je     L51
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fnmatch@plt>
  test   %eax,%eax
  jne    L15
L7:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ylog_match(const char *pat, const char *fn) {
  const char *f;
  if (!fnmatch(pat, fn, 0))
    return 1;
  for (f = fn; *f; f++)
    if (*f == '/' && f[1] != '/' && !fnmatch(pat, f + 1, 0))
      return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rot13_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,-0x490(%rbp)
  mov    %rdx,-0x488(%rbp)
  movabs $0x5857565554535251,%rax
  movabs $0x6665646362615a59,%rdx
  mov    %rax,-0x480(%rbp)
  mov    %rdx,-0x478(%rbp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x767574737271706f,%rdx
  mov    %rax,-0x470(%rbp)
  mov    %rdx,-0x468(%rbp)
  movl   $0x7a797877,-0x460(%rbp)
  movb   $0x0,-0x45c(%rbp)
  movabs $0x5554535251504f4e,%rax
  movabs $0x4342415a59585756,%rdx
  mov    %rax,-0x450(%rbp)
  mov    %rdx,-0x448(%rbp)
  movabs $0x4b4a494847464544,%rax
  movabs $0x737271706f6e4d4c,%rdx
  mov    %rax,-0x440(%rbp)
  mov    %rdx,-0x438(%rbp)
  movabs $0x617a797877767574,%rax
  movabs $0x6968676665646362,%rdx
  mov    %rax,-0x430(%rbp)
  mov    %rdx,-0x428(%rbp)
  movl   $0x6d6c6b6a,-0x420(%rbp)
  movb   $0x0,-0x41c(%rbp)
  movl   $0x1,-0x494(%rbp)
  lea    -0x490(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <rot13@plt>
  cmpl   $0x0,-0x494(%rbp)
  je     L3
  lea    -0x410(%rbp),%rdx
  lea    -0x450(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x1,%eax
  jmp    L1
L3:
  mov    $0x0,%eax
L1:
  mov    %eax,-0x494(%rbp)
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <rot13@plt>
  cmpl   $0x0,-0x494(%rbp)
  je     L39
  lea    -0x410(%rbp),%rdx
  lea    -0x490(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L39
  mov    $0x1,%eax
  jmp    L5
L39:
  mov    $0x0,%eax
L5:
  mov    %eax,-0x494(%rbp)
  mov    -0x494(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int rot13_test() {
  char text[] = {"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"};
  char code[] = {"NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm"};
  char buf[1024];
  int pass = 1;
  strcpy(buf, text);
  rot13(buf);
  pass = pass && !strcmp(code, buf);
  rot13(buf);
  pass = pass && !strcmp(text, buf);
  return (pass);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rot13_test>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x498,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x488(%rsp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x5857565554535251,%rax
  movabs $0x6665646362615a59,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movabs $0x767574737271706f,%rdx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movl   $0x7a797877,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  movabs $0x5554535251504f4e,%rax
  movabs $0x4342415a59585756,%rdx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movabs $0x4b4a494847464544,%rax
  movabs $0x737271706f6e4d4c,%rdx
  mov    %rax,0x50(%rsp)
  mov    %rdx,0x58(%rsp)
  movabs $0x617a797877767574,%rax
  movabs $0x6968676665646362,%rdx
  mov    %rax,0x60(%rsp)
  mov    %rdx,0x68(%rsp)
  movl   $0x6d6c6b6a,0x70(%rsp)
  movb   $0x0,0x74(%rsp)
  mov    %rsp,%rsi
  lea    0x80(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <rot13@plt>
  lea    0x40(%rsp),%rdi
  mov    %rbx,%rsi
  call   <strcmp@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <rot13@plt>
  mov    $0x0,%eax
  test   %ebp,%ebp
  jne    L10
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L10:
  mov    0x488(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x498,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rot13_test() {
  char text[] = {"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"};
  char code[] = {"NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm"};
  char buf[1024];
  int pass = 1;
  strcpy(buf, text);
  rot13(buf);
  pass = pass && !strcmp(code, buf);
  rot13(buf);
  pass = pass && !strcmp(text, buf);
  return (pass);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rot13_test>:
  endbr64
  movabs $0x504f4e4d4c4b4a49,%rdx
  push   %rbp
  sub    $0x490,%rsp
  movdqa D59(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x488(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbp
  mov    %rdx,0x88(%rsp)
  movabs $0x4847464544434241,%rax
  movaps %xmm0,(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %rbp,%rdi
  movabs $0x6665646362615a59,%rdx
  mov    %rax,0x80(%rsp)
  movabs $0x5857565554535251,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D14(%rip),%xmm0
  mov    %rax,0x90(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movaps %xmm0,0x20(%rsp)
  movdqa D0(%rip),%xmm0
  mov    %rdx,0x98(%rsp)
  movabs $0x767574737271706f,%rdx
  movaps %xmm0,0x40(%rsp)
  movdqa D27(%rip),%xmm0
  mov    %rax,0xa0(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x50(%rsp)
  movdqa D20(%rip),%xmm0
  mov    %rdx,0xa8(%rsp)
  movaps %xmm0,0x60(%rsp)
  movl   $0x7a797877,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  movl   $0x6d6c6b6a,0x70(%rsp)
  movb   $0x0,0x74(%rsp)
  movl   $0x7a797877,0xb0(%rsp)
  movb   $0x0,0xb4(%rsp)
  call   <rot13@plt>
  lea    0x40(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  jne    L8
  call   <rot13@plt>
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L16:
  mov    0x488(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x490,%rsp
  pop    %rbp
  ret
  nop
L8:
  xor    %eax,%eax
  call   <rot13@plt>
  xor    %eax,%eax
  jmp    L16
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D59
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D26
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D14
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D0
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D27
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D20
data_type: byte[16]

tool: {"D59": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D26": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D14": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D0": [0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x41,0x42,0x43]}

tool: {"D27": [0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x6e,0x6f,0x70,0x71,0x72,0x73]}

tool: {"D20": [0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69]}

assistant: ```c
int rot13_test() {
  char text[] = {"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"};
  char code[] = {"NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm"};
  char buf[1024];
  int pass = 1;
  strcpy(buf, text);
  rot13(buf);
  pass = pass && !strcmp(code, buf);
  rot13(buf);
  pass = pass && !strcmp(text, buf);
  return (pass);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rot13_test>:
  endbr64
  movabs $0x504f4e4d4c4b4a49,%rdx
  push   %rbp
  sub    $0x490,%rsp
  movdqa D31(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x488(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbp
  mov    %rdx,0x88(%rsp)
  movabs $0x4847464544434241,%rax
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %rbp,%rdi
  movabs $0x6665646362615a59,%rdx
  mov    %rax,0x80(%rsp)
  movabs $0x5857565554535251,%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D0(%rip),%xmm0
  mov    %rax,0x90(%rsp)
  movabs $0x6e6d6c6b6a696867,%rax
  movaps %xmm0,0x20(%rsp)
  movdqa D32(%rip),%xmm0
  mov    %rdx,0x98(%rsp)
  movabs $0x767574737271706f,%rdx
  movaps %xmm0,0x40(%rsp)
  movdqa D4(%rip),%xmm0
  mov    %rax,0xa0(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x50(%rsp)
  movdqa D24(%rip),%xmm0
  mov    %rdx,0xa8(%rsp)
  movaps %xmm0,0x60(%rsp)
  movl   $0x7a797877,0x30(%rsp)
  movb   $0x0,0x34(%rsp)
  movl   $0x6d6c6b6a,0x70(%rsp)
  movb   $0x0,0x74(%rsp)
  movl   $0x7a797877,0xb0(%rsp)
  movb   $0x0,0xb4(%rsp)
  call   <rot13@plt>
  lea    0x40(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    %rbp,%rdi
  test   %eax,%eax
  jne    L25
  call   <rot13@plt>
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L0:
  mov    0x488(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x490,%rsp
  pop    %rbp
  ret
  nop
L25:
  xor    %eax,%eax
  call   <rot13@plt>
  xor    %eax,%eax
  jmp    L0
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D31
type_guessed: byte[16]
name: unpack_data
arguments: label: D5
type_guessed: byte[16]
name: unpack_data
arguments: label: D0
type_guessed: byte[16]
name: unpack_data
arguments: label: D32
type_guessed: byte[16]
name: unpack_data
arguments: label: D4
type_guessed: byte[16]
name: unpack_data
arguments: label: D24
type_guessed: byte[16]

tool: {"D31": [0x41,0x42,0x43,0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x4e,0x4f,0x50]}

tool: {"D5": [0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x61,0x62,0x63,0x64,0x65,0x66]}

tool: {"D0": [0x67,0x68,0x69,0x6a,0x6b,0x6c,0x6d,0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76]}

tool: {"D32": [0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x41,0x42,0x43]}

tool: {"D4": [0x44,0x45,0x46,0x47,0x48,0x49,0x4a,0x4b,0x4c,0x4d,0x6e,0x6f,0x70,0x71,0x72,0x73]}

tool: {"D24": [0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x61,0x62,0x63,0x64,0x65,0x66,0x67,0x68,0x69]}

assistant: ```c
int rot13_test() {
  char text[] = {"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"};
  char code[] = {"NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm"};
  char buf[1024];
  int pass = 1;
  strcpy(buf, text);
  rot13(buf);
  pass = pass && !strcmp(code, buf);
  rot13(buf);
  pass = pass && !strcmp(text, buf);
  return (pass);
}
```