user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D36(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D29(%rip),%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  movl   $0xffffffff,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0xffffffff,0x14(%rsp)
  nop
L68:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%ecx
  test   %ecx,%ecx
  jle    L68
  lea    D4(%rip),%r12
  lea    0xc(%rsp),%rbp
  nopl   0x0(%rax)
L29:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L29
  lea    D6(%rip),%r12
  lea    0x10(%rsp),%rbp
  nopl   0x0(%rax)
L28:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L28
  lea    D5(%rip),%r12
  lea    0x14(%rsp),%rbp
  nopl   0x0(%rax)
L54:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jle    L54
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  xor    %r8d,%r8d
  mov    0x8(%rsp),%edi
  call   <cut_one@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %r8d,%r8d
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %eax,%ebx
  call   <cut_one@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    $0x1,%r8d
  cmp    %eax,%ebx
  jle    L57
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <cut_one@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %r8d,%r8d
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
L22:
  call   <cut_one@plt>
  lea    D37(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <cut_one@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  xor    %r8d,%r8d
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%edi
  jmp    L22
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D36
data_type: string
name: unpack_data
arguments: data_tag: D29
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D37
data_type: string

tool: D36: X: 

tool: D29: %d

tool: D4: Y: 

tool: D6: W: 

tool: D5: H: 

tool: D37: 
Number of tiles: %d


assistant: ```c
int main() {
  int x = -1, y = -1, w = -1, h = -1;
  do {
    printf("X: ");
    scanf("%d", &x);
  } while (x <= 0);
  do {
    printf("Y: ");
    scanf("%d", &y);
  } while (y <= 0);
  do {
    printf("W: ");
    scanf("%d", &w);
  } while (w <= 0);
  do {
    printf("H: ");
    scanf("%d", &h);
  } while (h <= 0);
  if (cut_one(x, y, w, h, 0) > cut_one(y, x, w, h, 0)) {
    cut_one(x, y, w, h, 1);
    printf("\nNumber of tiles: %d\n", cut_one(x, y, w, h, 0));
  } else {
    cut_one(y, x, w, h, 1);
    printf("\nNumber of tiles: %d\n", cut_one(y, x, w, h, 0));
  }
  return 0;
}
```