ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<draw>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  movsd  D69(%rip),%xmm0
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm1
  call   <glScalef@plt>
  movsd  D107(%rip),%xmm4
  pxor   %xmm3,%xmm3
  movsd  D106(%rip),%xmm0
  movapd %xmm3,%xmm2
  movapd %xmm4,%xmm1
  call   <glRotatef@plt>
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  movsd  D53(%rip),%xmm5
  pxor   %xmm2,%xmm2
  movsd  D113(%rip),%xmm1
  movapd %xmm5,%xmm0
  call   <glTranslatef@plt>
  mov    D107(%rip),%rax
  pxor   %xmm3,%xmm3
  movsd  D51(%rip),%xmm0
  movapd %xmm3,%xmm2
  movq   %rax,%xmm1
  call   <glRotatef@plt>
  mov    $0x2,%edi
  call   <glCallList@plt>
  xor    %eax,%eax
  call   <glPopMatrix@plt>
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  mov    D53(%rip),%rax
  pxor   %xmm2,%xmm2
  movsd  D110(%rip),%xmm1
  movq   %rax,%xmm0
  call   <glTranslatef@plt>
  mov    D107(%rip),%rax
  pxor   %xmm3,%xmm3
  movsd  D65(%rip),%xmm0
  movapd %xmm3,%xmm2
  movq   %rax,%xmm1
  call   <glRotatef@plt>
  mov    $0x1,%edi
  call   <glCallList@plt>
  xor    %eax,%eax
  call   <glPopMatrix@plt>
  xor    %eax,%eax
  call   <glPushMatrix@plt>
  movsd  D85(%rip),%xmm2
  pxor   %xmm1,%xmm1
  movsd  D70(%rip),%xmm0
  call   <glTranslatef@plt>
  mov    $0x3,%edi
  call   <glCallList@plt>
  xor    %eax,%eax
  call   <glPopMatrix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10c0 <glPopMatrix@plt>
```

tool_calls: name: read_data
arguments: label: D69
data_type: f64
name: read_data
arguments: label: D107
data_type: f64
name: read_data
arguments: label: D106
data_type: f64
name: read_data
arguments: label: D53
data_type: f32[2]
name: read_data
arguments: label: D113
data_type: f32[2]
name: read_data
arguments: label: D51
data_type: f64
name: read_data
arguments: label: D110
data_type: f64
name: read_data
arguments: label: D65
data_type: f64
name: read_data
arguments: label: D85
data_type: f32[2]
name: read_data
arguments: label: D70
data_type: f64

tool: D69: 1.3

tool: D107: 1

tool: D106: 23

tool: {"D53": [0.0,-1.8125]}

tool: {"D113": [0.0,-1.75]}

tool: D51: 270

tool: D110: 0.5

tool: D65: 90

tool: {"D85": [0.0,-1.875]}

tool: D70: 0.75

assistant: ```c
void draw(void) {
  glPushMatrix();
  glScalef(1.3, 1.3, 1.3);
  glRotatef(23.0, 1.0, 0.0, 0.0);
  glPushMatrix();
  glTranslatef(-0.75, -0.5, 0.0);
  glRotatef(270.0, 1.0, 0.0, 0.0);
  glCallList(2);
  glPopMatrix();
  glPushMatrix();
  glTranslatef(-0.75, 0.5, 0.0);
  glRotatef(90.0, 1.0, 0.0, 0.0);
  glCallList(1);
  glPopMatrix();
  glPushMatrix();
  glTranslatef(0.75, 0.0, -1.0);
  glCallList(3);
  glPopMatrix();
  glPopMatrix();
}
```
user: What is the c source code of the assembly code below?

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <len@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int sum(char *a) {
  int l = len(a);
  int i;
  int _sum = 0;
  for (i = 0; i < l; i++)
    _sum += a[i];
  return _sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <len@plt>
  test   %eax,%eax
  jle    L21
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L5:
  movsbl (%rdx),%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L5
L28:
  pop    %rbx
  ret
L21:
  mov    $0x0,%eax
  jmp    L28
```

assistant: ```c
int sum(char *a) {
  int l = len(a);
  int i;
  int _sum = 0;
  for (i = 0; i < l; i++)
    _sum += a[i];
  return _sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <len@plt>
  test   %eax,%eax
  jle    L9
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L13:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L13
  pop    %rbx
  ret
L9:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int sum(char *a) {
  int l = len(a);
  int i;
  int _sum = 0;
  for (i = 0; i < l; i++)
    _sum += a[i];
  return _sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sum>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <len@plt>
  test   %eax,%eax
  jle    L174
  mov    %eax,%edx
  lea    -0x1(%rax),%eax
  cmp    $0xe,%eax
  jbe    L59
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  pxor   %xmm6,%xmm6
  mov    %rbx,%rax
  shr    $0x4,%ecx
  pxor   %xmm4,%xmm4
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rbx,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L11:
  movdqu (%rax),%xmm0
  movdqa %xmm6,%xmm3
  add    $0x10,%rax
  pcmpgtb %xmm0,%xmm3
  movdqa %xmm0,%xmm2
  punpcklbw %xmm3,%xmm2
  punpckhbw %xmm3,%xmm0
  movdqa %xmm4,%xmm3
  pcmpgtw %xmm2,%xmm3
  movdqa %xmm2,%xmm5
  punpcklwd %xmm3,%xmm5
  punpckhwd %xmm3,%xmm2
  movdqa %xmm0,%xmm3
  paddd  %xmm5,%xmm1
  paddd  %xmm2,%xmm1
  movdqa %xmm4,%xmm2
  pcmpgtw %xmm0,%xmm2
  punpcklwd %xmm2,%xmm3
  punpckhwd %xmm2,%xmm0
  paddd  %xmm3,%xmm1
  paddd  %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L11
  movdqa %xmm1,%xmm0
  mov    %edx,%ecx
  psrldq $0x8,%xmm0
  and    $0xfffffff0,%ecx
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0xf,%dl
  je     L84
L94:
  movslq %ecx,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x2(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x3(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x4(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x5(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x6(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x7(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x8(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0x9(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0xa(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0xb(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0xc(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  lea    0xd(%rcx),%esi
  cmp    %esi,%edx
  jle    L84
  movslq %esi,%rsi
  add    $0xe,%ecx
  movsbl (%rbx,%rsi,1),%esi
  add    %esi,%eax
  cmp    %ecx,%edx
  jle    L84
  movslq %ecx,%rcx
  movsbl (%rbx,%rcx,1),%edx
  add    %edx,%eax
L84:
  pop    %rbx
  ret
L174:
  xor    %eax,%eax
  pop    %rbx
  ret
L59:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L94
```

assistant: ```c
int sum(char *a) {
  int l = len(a);
  int i;
  int _sum = 0;
  for (i = 0; i < l; i++)
    _sum += a[i];
  return _sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <MyLibraryFunctionToTest@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string

tool: D9: Test 1 for MyLibrary:


assistant: ```c
int main() {
  printf("Test 1 for MyLibrary:\n");
  MyLibraryFunctionToTest();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <MyLibraryFunctionToTest@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: Test 1 for MyLibrary:


assistant: ```c
int main() {
  printf("Test 1 for MyLibrary:\n");
  MyLibraryFunctionToTest();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <MyLibraryFunctionToTest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: Test 1 for MyLibrary:


assistant: ```c
int main() {
  printf("Test 1 for MyLibrary:\n");
  MyLibraryFunctionToTest();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <MyLibraryFunctionToTest@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D8: Test 1 for MyLibrary:


assistant: ```c
int main() {
  printf("Test 1 for MyLibrary:\n");
  MyLibraryFunctionToTest();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L14
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  jmp    L37
L4:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  mov    $0x0,%eax
L37:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s) {
    if (*s == c) {
      return (char *)s;
    }
    ++s;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L28
L17:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L21
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L17
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L21:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s) {
    if (*s == c) {
      return (char *)s;
    }
    ++s;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strchr>:
  endbr64
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L3:
  cmp    %esi,%edx
  je     L20
  add    $0x1,%rdi
L4:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L3
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s) {
    if (*s == c) {
      return (char *)s;
    }
    ++s;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strchr>:
  endbr64
  jmp    L27
  cs nopw 0x0(%rax,%rax,1)
L5:
  cmp    %esi,%edx
  je     L29
  add    $0x1,%rdi
L27:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L5
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  while (*s) {
    if (*s == c) {
      return (char *)s;
    }
    ++s;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <findNumOfDec@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
type_guessed: string

tool: D7: %f has %d decimals


assistant: ```c
void test(double x) {
  int num = findNumOfDec(x);
  printf("%f has %d decimals\n", x, num);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  call   <findNumOfDec@plt>
  mov    %eax,%esi
  movq   %rbx,%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string

tool: D8: %f has %d decimals


assistant: ```c
void test(double x) {
  int num = findNumOfDec(x);
  printf("%f has %d decimals\n", x, num);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <findNumOfDec@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: %f has %d decimals


assistant: ```c
void test(double x) {
  int num = findNumOfDec(x);
  printf("%f has %d decimals\n", x, num);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <findNumOfDec@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string

tool: D1: %f has %d decimals


assistant: ```c
void test(double x) {
  int num = findNumOfDec(x);
  printf("%f has %d decimals\n", x, num);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmp3_sum_f_bands>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xmp3_sum_f_bands(float a[], float b[], int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] += b[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmp3_sum_f_bands>:
  endbr64
  test   %edx,%edx
  jle    L19
  mov    %edx,%edx
  mov    $0x0,%eax
L15:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
L19:
  ret
```

assistant: ```c
void xmp3_sum_f_bands(float a[], float b[], int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] += b[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmp3_sum_f_bands>:
  endbr64
  test   %edx,%edx
  jle    L5
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L4:
  movss  (%rdi,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L4
L5:
  ret
```

assistant: ```c
void xmp3_sum_f_bands(float a[], float b[], int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] += b[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xmp3_sum_f_bands>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L33
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L53
  cmp    $0x1,%edx
  je     L53
  lea    -0x1(%rdx),%eax
  mov    %edx,%r8d
  cmp    $0x2,%eax
  jbe    L66
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L34:
  movups (%rcx,%rax,1),%xmm0
  movups (%rsi,%rax,1),%xmm2
  addps  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L34
  mov    %edx,%edi
  and    $0xfffffffc,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L33
  sub    %edi,%edx
  mov    %edx,%r8d
  cmp    $0x1,%edx
  je     L47
L8:
  lea    (%rcx,%rdi,4),%rdx
  movq   (%rsi,%rdi,4),%xmm0
  movq   (%rdx),%xmm1
  addps  %xmm1,%xmm0
  movlps %xmm0,(%rdx)
  mov    %r8d,%edx
  and    $0xfffffffe,%edx
  add    %edx,%eax
  cmp    %edx,%r8d
  je     L33
L47:
  cltq
  lea    (%rcx,%rax,4),%rdx
  movss  (%rdx),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax)
L53:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L42:
  movss  (%rcx,%rax,4),%xmm0
  addss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L42
L33:
  ret
L66:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L8
```

assistant: ```c
void xmp3_sum_f_bands(float a[], float b[], int n) {
  int i;
  for (i = 0; i < n; i++)
    a[i] += b[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sentenumeric>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L89
  cmpb   $0x5a,-0x4(%rbp)
  jg     L89
  mov    $0x1,%eax
  jmp    L63
L89:
  cmpb   $0x60,-0x4(%rbp)
  jle    L93
  cmpb   $0x7a,-0x4(%rbp)
  jg     L93
  mov    $0x1,%eax
  jmp    L63
L93:
  cmpb   $0x2f,-0x4(%rbp)
  jle    L70
  cmpb   $0x39,-0x4(%rbp)
  jg     L70
  mov    $0x1,%eax
  jmp    L63
L70:
  cmpb   $0x5f,-0x4(%rbp)
  je     L33
  cmpb   $0x24,-0x4(%rbp)
  jne    L115
L33:
  mov    $0x1,%eax
  jmp    L63
L115:
  mov    $0x0,%eax
L63:
  pop    %rbp
  ret
```

assistant: ```c
char sentenumeric(char input) {
  if ((input >= 'A') && (input <= 'Z'))
    return 1;
  if ((input >= 'a') && (input <= 'z'))
    return 1;
  if ((input >= '0') && (input <= '9'))
    return 1;
  if ((input == '_') || (input == '$'))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sentenumeric>:
  endbr64
  mov    %edi,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  mov    $0x1,%eax
  cmp    $0x19,%dl
  jbe    L1
  lea    -0x24(%rdi),%ecx
  cmp    $0x3b,%cl
  ja     L18
  movabs $0x8000000003ff001,%rax
  shr    %cl,%rax
  xor    $0x1,%rax
  and    $0x1,%eax
L18:
  xor    $0x1,%eax
L1:
  ret
```

assistant: ```c
char sentenumeric(char input) {
  if ((input >= 'A') && (input <= 'Z'))
    return 1;
  if ((input >= 'a') && (input <= 'z'))
    return 1;
  if ((input >= '0') && (input <= '9'))
    return 1;
  if ((input == '_') || (input == '$'))
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sentenumeric>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L13
  lea    -0x24(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x3b,%cl
  ja     L13
  movabs $0xf7ffffffffc00ffe,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
L13:
  ret
```

assistant: ```c
char sentenumeric(char input) {
  if ((input >= 'A') && (input <= 'Z'))
    return 1;
  if ((input >= 'a') && (input <= 'z'))
    return 1;
  if ((input >= '0') && (input <= '9'))
    return 1;
  if ((input == '_') || (input == '$'))
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sentenumeric>:
  endbr64
  mov    %edi,%edx
  mov    $0x1,%eax
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x19,%dl
  jbe    L3
  lea    -0x24(%rdi),%ecx
  xor    %eax,%eax
  cmp    $0x3b,%cl
  ja     L3
  movabs $0xf7ffffffffc00ffe,%rax
  sar    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
L3:
  ret
```

assistant: ```c
char sentenumeric(char input) {
  if ((input >= 'A') && (input <= 'Z'))
    return 1;
  if ((input >= 'a') && (input <= 'z'))
    return 1;
  if ((input >= '0') && (input <= '9'))
    return 1;
  if ((input == '_') || (input == '$'))
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hctoc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x2f,-0x1(%rbp)
  jbe    L44
  cmpb   $0x39,-0x1(%rbp)
  ja     L44
  subb   $0x30,-0x1(%rbp)
  jmp    L17
L44:
  cmpb   $0x60,-0x1(%rbp)
  jbe    L39
  cmpb   $0x66,-0x1(%rbp)
  ja     L39
  subb   $0x57,-0x1(%rbp)
  jmp    L17
L39:
  cmpb   $0x40,-0x1(%rbp)
  jbe    L17
  cmpb   $0x46,-0x1(%rbp)
  ja     L17
  subb   $0x37,-0x1(%rbp)
L17:
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char hctoc(const char hc) {
  unsigned char c = hc;
  if ((c >= '0') && (c <= '9'))
    c -= '0';
  else if ((c >= 'a') && (c <= 'f'))
    c -= ('a' - 10);
  else if ((c >= 'A') && (c <= 'F'))
    c -= ('A' - 10);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hctoc>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L19
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  ja     L15
  lea    -0x57(%rdi),%eax
  ret
L15:
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  cmovae %edi,%eax
L19:
  ret
```

assistant: ```c
unsigned char hctoc(const char hc) {
  unsigned char c = hc;
  if ((c >= '0') && (c <= '9'))
    c -= '0';
  else if ((c >= 'a') && (c <= 'f'))
    c -= ('a' - 10);
  else if ((c >= 'A') && (c <= 'F'))
    c -= ('A' - 10);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hctoc>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L5
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  ja     L15
  lea    -0x57(%rdi),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  cmovae %edi,%eax
L5:
  ret
```

assistant: ```c
unsigned char hctoc(const char hc) {
  unsigned char c = hc;
  if ((c >= '0') && (c <= '9'))
    c -= '0';
  else if ((c >= 'a') && (c <= 'f'))
    c -= ('a' - 10);
  else if ((c >= 'A') && (c <= 'F'))
    c -= ('A' - 10);
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hctoc>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L14
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  ja     L6
  lea    -0x57(%rdi),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  cmovae %edi,%eax
L14:
  ret
```

assistant: ```c
unsigned char hctoc(const char hc) {
  unsigned char c = hc;
  if ((c >= '0') && (c <= '9'))
    c -= '0';
  else if ((c >= 'a') && (c <= 'f'))
    c -= ('a' - 10);
  else if ((c >= 'A') && (c <= 'F'))
    c -= ('A' - 10);
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solcon_quaddobl_multi_affinization>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x393,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int solcon_quaddobl_multi_affinization(int n, int m, int *z) {
  int fail;
  int pars[2];
  double c;
  pars[0] = n;
  pars[1] = m;
  fail = _ada_use_c2phc4c(915, pars, z, &c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<solcon_quaddobl_multi_affinization>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0x10(%rsp)
  mov    %esi,0x14(%rsp)
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x393,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_quaddobl_multi_affinization(int n, int m, int *z) {
  int fail;
  int pars[2];
  double c;
  pars[0] = n;
  pars[1] = m;
  fail = _ada_use_c2phc4c(915, pars, z, &c, 0);
  return fail;
}
```