user: 这段汇编代码用C语言表示是什么样的：

```asm
<display_byte>:
  endbr64
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    %rsi,%rdi
  jb     L157
  jmp    L75
  xchg   %ax,%ax
L132:
  movzbl %bpl,%esi
  mov    $0x20,%edx
  add    $0x1,%r12
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    %bpl,0x10(%rsp,%r13,1)
  call   <printf@plt>
  mov    %r12,%rax
  xor    %edx,%edx
  div    %rbx
  mov    %rdx,%rbp
  test   %rdx,%rdx
  je     L88
  cmp    %r12,0x8(%rsp)
  je     L128
L157:
  mov    %r12,%rdi
  call   <rd_byte@plt>
  xor    %edx,%edx
  mov    %eax,%ebp
  mov    %r12,%rax
  div    %rbx
  mov    %rdx,%r13
  test   %rdx,%rdx
  jne    L132
  mov    %r12,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L132
  nopl   0x0(%rax)
L88:
  mov    $0x20,%edi
  lea    0x10(%rsp),%r14
  mov    $0x2e,%r13d
  call   <putchar@plt>
  lea    (%r14,%rbx,1),%rax
  mov    %rax,(%rsp)
  test   %rbx,%rbx
  je     L147
  nopw   0x0(%rax,%rax,1)
L83:
  movzbl (%r14),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5f,%al
  cmovae %r13d,%edi
  add    $0x1,%r14
  call   <putchar@plt>
  cmp    %r14,(%rsp)
  jne    L83
L147:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12,0x8(%rsp)
  jne    L157
  nopl   0x0(%rax)
L128:
  test   %rbp,%rbp
  je     L26
  mov    %rbx,%rax
  xor    %r12d,%r12d
  sub    %rbp,%rax
  lea    (%rax,%rax,2),%r13
  cmp    %rbx,%rbp
  je     L92
  nopl   0x0(%rax,%rax,1)
L71:
  mov    $0x20,%edi
  add    $0x1,%r12
  call   <putchar@plt>
  cmp    %r13,%r12
  jb     L71
L92:
  mov    $0x20,%edi
  lea    0x10(%rsp),%rbx
  mov    $0x2e,%r12d
  call   <putchar@plt>
  add    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L57:
  movzbl (%rbx),%edi
  lea    -0x20(%rdi),%eax
  cmp    $0x5f,%al
  cmovae %r12d,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L57
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    %rdi,%rax
  xor    %edx,%edx
  div    %rbx
  mov    %rdx,%rbp
  jmp    L128
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string
name: extract_symbolic_data
arguments: tag: D11
datatype: string

tool: D7: %02X%c

tool: D11: %06lX: 

assistant: ```c
void display_byte(unsigned long start, unsigned long endaddr, unsigned long width) {
  int index;
  unsigned char r;
  char pc[16];
  for (;;) {
    if (start < endaddr) {
      r = rd_byte((unsigned char *)start);
      if ((start % width) == 0)
        printf("%06lX: ", start);
      pc[start % width] = r;
      start++;
      printf("%02X%c", r, ' ');
      if ((start % width) == 0) {
        printf(" ");
        for (index = 0; (index < width); index++) {
          r = pc[index];
          printf("%c", ((r >= 0x20) && (r <= 0x7E)) ? r : '.');
        }
        printf("\n");
      }
    } else {
      if (start % width) {
        for (index = 0; (index < (3 * (width - start % width))); index++)
          printf(" ");
        printf(" ");
        for (index = 0; (index < (start % width)); index++) {
          r = pc[index];
          printf("%c", ((r >= 0x20) && (r <= 0x7E)) ? r : '.');
        }
        printf("\n");
      }
      goto endbyte;
    }
  }
endbyte:
  return;
}
```