ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <exact_square@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string

tool: D25: Number=

tool: D0: %d

tool: D21: %d


assistant: ```c
int main() {
  int num;
  printf("Number=");
  scanf("%d", &num);
  printf("%d\n", exact_square(num));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L16
L14:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x64,-0x14(%rbp)
  jmp    L49
L67:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L49:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L67
  mov    -0x1c(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jle    L9
  mov    -0x1c(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  jmp    L40
L9:
  mov    $0xffffffff,%eax
L40:
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L16:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D6
type_infered: string

tool: D7: %d

tool: D14: %d%d

tool: D6: %d


assistant: ```c
int main() {
  int t, n, x, a, m, i, s;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d", &n, &x);
    for (i = s = 0, m = 100; i < n; ++i)
      scanf("%d", &a), m = a < m ? a : m, s += a;
    printf("%d\n", (s % x >= m) ? -1 : (s / x));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L57
  lea    0x10(%rsp),%r15
  lea    D19(%rip),%r14
  lea    D20(%rip),%r13
  jmp    L77
L57:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  mov    0x10(%rsp),%ecx
  mov    $0x0,%r12d
L28:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
L18:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L57
L77:
  lea    0xc(%rsp),%rsi
  mov    %r15,%rdx
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L79
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  mov    $0x64,%ebx
L58:
  lea    0x14(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  add    %eax,%r12d
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jg     L58
  mov    0x10(%rsp),%ecx
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  mov    $0xffffffff,%esi
  cmp    %ebx,%edx
  jge    L18
  jmp    L28
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D20: %d

tool: D19: %d%d

tool: D15: %d


assistant: ```c
int main() {
  int t, n, x, a, m, i, s;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d", &n, &x);
    for (i = s = 0, m = 100; i < n; ++i)
      scanf("%d", &a), m = a < m ? a : m, s += a;
    printf("%d\n", (s % x >= m) ? -1 : (s / x));
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  lea    0x20(%rsp),%r15
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    0x1c(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L58
  nopl   0x0(%rax,%rax,1)
L53:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L42
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  lea    0x24(%rsp),%rbp
  mov    $0x64,%r13d
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  add    %eax,%ebx
  add    $0x1,%r14d
  cmp    %r14d,0x1c(%rsp)
  jg     L28
  mov    %ebx,%eax
  cltd
  idivl  0x20(%rsp)
  cmp    %r13d,%edx
  mov    $0xffffffff,%edx
  cmovl  %eax,%edx
  mov    %edx,%esi
L51:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L53
L58:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %esi,%esi
  jmp    L51
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D23
data_type: string
name: disassemble_data
arguments: data_tag: D4
data_type: string

tool: D11: %d

tool: D23: %d%d

tool: D4: %d


assistant: ```c
int main() {
  int t, n, x, a, m, i, s;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d", &n, &x);
    for (i = s = 0, m = 100; i < n; ++i)
      scanf("%d", &a), m = a < m ? a : m, s += a;
    printf("%d\n", (s % x >= m) ? -1 : (s / x));
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  lea    0x20(%rsp),%r15
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    0x1c(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L50
  nopl   0x0(%rax,%rax,1)
L14:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L1
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  lea    0x24(%rsp),%rbp
  mov    $0x64,%r13d
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  add    %eax,%ebx
  add    $0x1,%r14d
  cmp    %r14d,0x1c(%rsp)
  jg     L55
  mov    %ebx,%eax
  cltd
  idivl  0x20(%rsp)
  cmp    %r13d,%edx
  mov    $0xffffffff,%edx
  cmovl  %eax,%edx
  mov    %edx,%esi
L19:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L14
L50:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %esi,%esi
  jmp    L19
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D1: %d

tool: D26: %d%d

tool: D12: %d


assistant: ```c
int main() {
  int t, n, x, a, m, i, s;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d", &n, &x);
    for (i = s = 0, m = 100; i < n; ++i)
      scanf("%d", &a), m = a < m ? a : m, s += a;
    printf("%d\n", (s % x >= m) ? -1 : (s / x));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x4(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <signal_type_alarm@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D16
type: string
name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D33
type: string

tool: D29: =====================test mask=================


tool: D16: =====================test Action=================


tool: D0: =====================test USER1=================


tool: D33: =====================test ALARM=================


assistant: ```c
int main(void) {
  int ret = -1;
  printf("=====================test mask=================\n");
  if (ret < 0) {
  }
  printf("=====================test Action=================\n");
  if (ret < 0) {
  }
  printf("=====================test USER1=================\n");
  if (ret < 0) {
  }
  printf("=====================test ALARM=================\n");
  ret = signal_type_alarm();
  if (ret < 0) {
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <signal_type_alarm@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D29: =====================test mask=================


tool: D11: =====================test Action=================


tool: D14: =====================test USER1=================


tool: D12: =====================test ALARM=================


assistant: ```c
int main(void) {
  int ret = -1;
  printf("=====================test mask=================\n");
  if (ret < 0) {
  }
  printf("=====================test Action=================\n");
  if (ret < 0) {
  }
  printf("=====================test USER1=================\n");
  if (ret < 0) {
  }
  printf("=====================test ALARM=================\n");
  ret = signal_type_alarm();
  if (ret < 0) {
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <signal_type_alarm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
type: string
name: disassemble_data
arguments: tag: D36
type: string
name: disassemble_data
arguments: tag: D34
type: string
name: disassemble_data
arguments: tag: D7
type: string

tool: D22: =====================test mask=================


tool: D36: =====================test Action=================


tool: D34: =====================test USER1=================


tool: D7: =====================test ALARM=================


assistant: ```c
int main(void) {
  int ret = -1;
  printf("=====================test mask=================\n");
  if (ret < 0) {
  }
  printf("=====================test Action=================\n");
  if (ret < 0) {
  }
  printf("=====================test USER1=================\n");
  if (ret < 0) {
  }
  printf("=====================test ALARM=================\n");
  ret = signal_type_alarm();
  if (ret < 0) {
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <signal_type_alarm@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D36
data_type: string
name: unpack_data
arguments: data_tag: D34
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string
name: unpack_data
arguments: data_tag: D11
data_type: string

tool: D36: =====================test mask=================


tool: D34: =====================test Action=================


tool: D2: =====================test USER1=================


tool: D11: =====================test ALARM=================


assistant: ```c
int main(void) {
  int ret = -1;
  printf("=====================test mask=================\n");
  if (ret < 0) {
  }
  printf("=====================test Action=================\n");
  if (ret < 0) {
  }
  printf("=====================test USER1=================\n");
  if (ret < 0) {
  }
  printf("=====================test ALARM=================\n");
  ret = signal_type_alarm();
  if (ret < 0) {
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
type: string
name: disassemble_data
arguments: data_tag: D33
type: string
name: disassemble_data
arguments: data_tag: D35
type: string
name: disassemble_data
arguments: data_tag: D48
type: string

tool: D27: Ingrese un numero:

tool: D33: %d

tool: D35: Ingrese otro:

tool: D48: La suma es: %d


assistant: ```c
int main() {
  int a, b, c;
  printf("Ingrese un numero:");
  scanf("%d", &a);
  printf("Ingrese otro:");
  scanf("%d", &b);
  c = a + b;
  printf("La suma es: %d\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D32(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  add    (%rsp),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D37
datatype: string
name: unpack_data
arguments: data_label: D32
datatype: string
name: unpack_data
arguments: data_label: D36
datatype: string
name: unpack_data
arguments: data_label: D8
datatype: string

tool: D37: Ingrese un numero:

tool: D32: %d

tool: D36: Ingrese otro:

tool: D8: La suma es: %d


assistant: ```c
int main() {
  int a, b, c;
  printf("Ingrese un numero:");
  scanf("%d", &a);
  printf("Ingrese otro:");
  scanf("%d", &b);
  c = a + b;
  printf("La suma es: %d\n", c);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D0(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D0
data_type: string
name: retrieve_data
arguments: tag: D39
data_type: string
name: retrieve_data
arguments: tag: D32
data_type: string

tool: D15: Ingrese un numero:

tool: D0: %d

tool: D39: Ingrese otro:

tool: D32: La suma es: %d


assistant: ```c
int main() {
  int a, b, c;
  printf("Ingrese un numero:");
  scanf("%d", &a);
  printf("Ingrese otro:");
  scanf("%d", &b);
  c = a + b;
  printf("La suma es: %d\n", c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D13(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  add    (%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string

tool: D15: Ingrese un numero:

tool: D13: %d

tool: D16: Ingrese otro:

tool: D8: La suma es: %d


assistant: ```c
int main() {
  int a, b, c;
  printf("Ingrese un numero:");
  scanf("%d", &a);
  printf("Ingrese otro:");
  scanf("%d", &b);
  c = a + b;
  printf("La suma es: %d\n", c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Polynomial_Extrapolation_to_Zero>:
  endbr64
  mov    %rsi,%r10
  test   %ecx,%ecx
  je     L35
  push   %rbx
  mov    %rdi,%r9
  movslq %ecx,%rbx
  lea    (%rdx,%rbx,8),%r8
  pxor   %xmm1,%xmm1
  ucomisd (%r8),%xmm1
  jp     L94
  je     L117
L94:
  movsd  (%r10),%xmm3
  movsd  %xmm0,(%r10)
  test   %ecx,%ecx
  jle    L26
  mov    %r8,%rsi
  lea    0x8(%r10),%rdx
  lea    -0x1(%rcx),%eax
  lea    0x10(%r10,%rax,8),%r11
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm5
  mov    $0x0,%edi
  movapd %xmm0,%xmm8
  movapd %xmm0,%xmm6
  movapd %xmm0,%xmm7
  jmp    L58
L35:
  movsd  %xmm0,(%rsi)
  mov    %ecx,%eax
  ret
L117:
  movsd  %xmm0,(%rdi)
  mov    $0xfffffffe,%eax
  jmp    L25
L21:
  movapd %xmm2,%xmm1
  subsd  %xmm3,%xmm1
  movapd %xmm2,%xmm4
  subsd  %xmm0,%xmm4
  movsd  -0x8(%rsi),%xmm0
  divsd  (%r8),%xmm0
  movapd %xmm4,%xmm9
  subsd  %xmm1,%xmm9
  mulsd  %xmm9,%xmm0
  subsd  %xmm4,%xmm0
  ucomisd %xmm6,%xmm0
  jp     L111
  ucomisd %xmm7,%xmm0
  je     L0
L111:
  movsd  (%rcx),%xmm9
  mulsd  %xmm4,%xmm1
  divsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,(%rcx)
  sub    $0x8,%rsi
  add    $0x8,%rdx
  movapd %xmm3,%xmm0
  cmp    %r11,%rdx
  je     L26
  movapd %xmm9,%xmm3
L58:
  mov    %rdx,%rcx
  movsd  -0x8(%rdx),%xmm2
  ucomisd %xmm5,%xmm3
  setnp  %al
  cmovne %edi,%eax
  test   %al,%al
  je     L21
  ucomisd %xmm8,%xmm2
  setnp  %al
  cmovne %edi,%eax
  test   %al,%al
  je     L21
  movq   $0x0,(%r10,%rbx,8)
L26:
  movsd  (%r10,%rbx,8),%xmm0
  movsd  %xmm0,(%r9)
  mov    $0x0,%eax
L25:
  pop    %rbx
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L25
```

assistant: ```c
int Polynomial_Extrapolation_to_Zero(double *fzero, double tableau[], double x[], double f, int n) {
  double back_two_columns;
  double old_aux;
  double new_value;
  double vertical_diff;
  double backslant_diff;
  double forwardslant_diff;
  double denominator;
  int i;
  if (n == 0) {
    tableau[0] = f;
    return 0;
  }
  if (x[n] == 0.0) {
    *fzero = f;
    return -2;
  }
  back_two_columns = 0.0;
  old_aux = tableau[0];
  tableau[0] = f;
  for (i = 0; i < n; i++) {
    if (tableau[i] == 0 && old_aux == 0) {
      tableau[n] = 0.0;
      break;
    }
    vertical_diff = tableau[i] - old_aux;
    backslant_diff = tableau[i] - back_two_columns;
    forwardslant_diff = backslant_diff - vertical_diff;
    denominator = (x[n - i - 1] / x[n]) * forwardslant_diff - backslant_diff;
    if (denominator == 0.0)
      return -1;
    back_two_columns = old_aux;
    old_aux = tableau[i + 1];
    tableau[i + 1] = tableau[i] + vertical_diff * backslant_diff / denominator;
  }
  *fzero = tableau[n];
  return 0;
}
```