ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<I2C_Read>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  or     $0x1,%ebp
  mov    %rsi,%rbx
  call   <i2cstart@plt>
  movsbl %bpl,%edi
  call   <i2csendbyte@plt>
  xor    %eax,%eax
  call   <i2cgetack@plt>
  test   %eax,%eax
  je     L28
  lea    -0x1(%r12),%ebp
  test   %r12b,%r12b
  jne    L54
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L0:
  je     L46
L21:
  sub    $0x1,%ebp
L54:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <i2cgetbyte@plt>
  mov    %al,-0x1(%rbx)
  test   %bpl,%bpl
  jle    L0
  xor    %eax,%eax
  call   <i2csendack@plt>
  jmp    L21
  nopl   0x0(%rax)
L46:
  xor    %eax,%eax
  call   <i2cstop@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  call   <i2cstop@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char I2C_Read(char Address, char *Data, char Num) {
  i2cstart();
  i2csendbyte(Address | 0x01);
  if (!i2cgetack()) {
    i2cstop();
    return (0);
  }
  while (Num--) {
    *Data = i2cgetbyte();
    Data++;
    if (Num > 0) {
      i2csendack();
    }
  }
  i2cstop();
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<I2C_Read>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  or     $0x1,%ebp
  mov    %rsi,%rbx
  call   <i2cstart@plt>
  movsbl %bpl,%edi
  call   <i2csendbyte@plt>
  xor    %eax,%eax
  call   <i2cgetack@plt>
  test   %eax,%eax
  je     L14
  lea    -0x1(%r12),%ebp
  test   %r12b,%r12b
  jne    L19
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L44:
  je     L21
L11:
  sub    $0x1,%ebp
L19:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <i2cgetbyte@plt>
  mov    %al,-0x1(%rbx)
  test   %bpl,%bpl
  jle    L44
  xor    %eax,%eax
  call   <i2csendack@plt>
  jmp    L11
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  call   <i2cstop@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  xor    %eax,%eax
  call   <i2cstop@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char I2C_Read(char Address, char *Data, char Num) {
  i2cstart();
  i2csendbyte(Address | 0x01);
  if (!i2cgetack()) {
    i2cstop();
    return (0);
  }
  while (Num--) {
    *Data = i2cgetbyte();
    Data++;
    if (Num > 0) {
      i2csendack();
    }
  }
  i2cstop();
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<HistoryDelete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <CheckRunningInMainThread@plt>
  test   %eax,%eax
  je     L7
  mov    $0x266,%edi
  call   <CallBack0@plt>
  jmp    L13
L7:
  nop
L13:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: HistoryDelete

assistant: ```c
void HistoryDelete(void) {
  if (!CheckRunningInMainThread("HistoryDelete"))
    return;
  CallBack0(102 + 512);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HistoryDelete>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <CheckRunningInMainThread@plt>
  test   %eax,%eax
  jne    L1
L17:
  add    $0x8,%rsp
  ret
L1:
  mov    $0x266,%edi
  call   <CallBack0@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: HistoryDelete

assistant: ```c
void HistoryDelete(void) {
  if (!CheckRunningInMainThread("HistoryDelete"))
    return;
  CallBack0(102 + 512);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<HistoryDelete>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <CheckRunningInMainThread@plt>
  test   %eax,%eax
  jne    L7
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L7:
  mov    $0x266,%edi
  add    $0x8,%rsp
  jmp    1060 <CallBack0@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: HistoryDelete

assistant: ```c
void HistoryDelete(void) {
  if (!CheckRunningInMainThread("HistoryDelete"))
    return;
  CallBack0(102 + 512);
}
```
user: What is the c source code of the assembly code below:

```asm
<HistoryDelete>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <CheckRunningInMainThread@plt>
  test   %eax,%eax
  jne    L4
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L4:
  mov    $0x266,%edi
  add    $0x8,%rsp
  jmp    1060 <CallBack0@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: HistoryDelete

assistant: ```c
void HistoryDelete(void) {
  if (!CheckRunningInMainThread("HistoryDelete"))
    return;
  CallBack0(102 + 512);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L12
L21:
  cmpl   $0x0,-0x10(%rbp)
  jle    L28
  mov    -0x10(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L28
  mov    $0xa,%edi
  call   <putchar@plt>
L28:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L12:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L21
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: %02x 

assistant: ```c
void print_hex(void *in, int start, int end) {
  uint8_t *array = (uint8_t *)in;
  int i;
  for (i = start; i < end; i++) {
    if (i > 0 && i % 8 == 0) {
      printf("\n");
    }
    uint8_t foo = array[i];
    printf("%02x ", foo);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jge    L23
  mov    %rdi,%rbp
  movslq %esi,%rbx
  sub    $0x1,%edx
  sub    %esi,%edx
  lea    0x1(%rbx,%rdx,1),%r13
  lea    D8(%rip),%r12
  jmp    L17
L3:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L23
L17:
  test   %ebx,%ebx
  jle    L3
  test   $0x7,%bl
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L3
L23:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: %02x 

assistant: ```c
void print_hex(void *in, int start, int end) {
  uint8_t *array = (uint8_t *)in;
  int i;
  for (i = start; i < end; i++) {
    if (i > 0 && i % 8 == 0) {
      printf("\n");
    }
    uint8_t foo = array[i];
    printf("%02x ", foo);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_hex>:
  endbr64
  cmp    %edx,%esi
  jge    L2
  push   %r14
  sub    $0x1,%edx
  lea    D7(%rip),%r14
  push   %r13
  sub    %esi,%edx
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  lea    0x1(%rbp),%rbx
  lea    (%rdx,%rbx,1),%r12
  jmp    L8
  nopl   0x0(%rax)
L22:
  mov    0x0(%r13,%rbp,4),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %rbx,%rbp
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L17
  add    $0x1,%rbx
L8:
  test   %ebp,%ebp
  jle    L22
  test   $0x7,%bpl
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L22
  nopl   0x0(%rax)
L17:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string

tool: D7: %02x 

assistant: ```c
void print_hex(void *in, int start, int end) {
  uint8_t *array = (uint8_t *)in;
  int i;
  for (i = start; i < end; i++) {
    if (i > 0 && i % 8 == 0) {
      printf("\n");
    }
    uint8_t foo = array[i];
    printf("%02x ", foo);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_hex>:
  endbr64
  cmp    %edx,%esi
  jge    L29
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L31
  lea    D0(%rip),%r12
L57:
  movslq %ebx,%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L70:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L56
L13:
  test   $0x7,%bl
  jne    L70
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L70
  nopl   0x0(%rax)
L31:
  lea    -0x1(%rdx),%r15d
  xor    %eax,%eax
  lea    D0(%rip),%r12
  test   %r15d,%r15d
  cmovg  %eax,%r15d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L52:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r15d,%ebx
  jle    L52
  cmp    %ebx,%r14d
  jg     L57
L56:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  xchg   %ax,%ax
L29:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: %02x 

assistant: ```c
void print_hex(void *in, int start, int end) {
  uint8_t *array = (uint8_t *)in;
  int i;
  for (i = start; i < end; i++) {
    if (i > 0 && i % 8 == 0) {
      printf("\n");
    }
    uint8_t foo = array[i];
    printf("%02x ", foo);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mat3_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x14,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x1c,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x20,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mat3_add(float *dst, float *b) {
  dst[0] = dst[0] + b[0];
  dst[1] = dst[1] + b[1];
  dst[2] = dst[2] + b[2];
  dst[3] = dst[3] + b[3];
  dst[4] = dst[4] + b[4];
  dst[5] = dst[5] + b[5];
  dst[6] = dst[6] + b[6];
  dst[7] = dst[7] + b[7];
  dst[8] = dst[8] + b[8];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mat3_add>:
  endbr64
  movss  (%rdi),%xmm0
  addss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  addss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  addss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  addss  0x10(%rsi),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  addss  0x14(%rsi),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  addss  0x18(%rsi),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  addss  0x1c(%rsi),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  addss  0x20(%rsi),%xmm0
  movss  %xmm0,0x20(%rdi)
  ret
```

assistant: ```c
void mat3_add(float *dst, float *b) {
  dst[0] = dst[0] + b[0];
  dst[1] = dst[1] + b[1];
  dst[2] = dst[2] + b[2];
  dst[3] = dst[3] + b[3];
  dst[4] = dst[4] + b[4];
  dst[5] = dst[5] + b[5];
  dst[6] = dst[6] + b[6];
  dst[7] = dst[7] + b[7];
  dst[8] = dst[8] + b[8];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat3_add>:
  endbr64
  movss  (%rdi),%xmm0
  addss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  addss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  addss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  addss  0x10(%rsi),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  addss  0x14(%rsi),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  addss  0x18(%rsi),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  addss  0x1c(%rsi),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  addss  0x20(%rsi),%xmm0
  movss  %xmm0,0x20(%rdi)
  ret
```

assistant: ```c
void mat3_add(float *dst, float *b) {
  dst[0] = dst[0] + b[0];
  dst[1] = dst[1] + b[1];
  dst[2] = dst[2] + b[2];
  dst[3] = dst[3] + b[3];
  dst[4] = dst[4] + b[4];
  dst[5] = dst[5] + b[5];
  dst[6] = dst[6] + b[6];
  dst[7] = dst[7] + b[7];
  dst[8] = dst[8] + b[8];
}
```
user: What is the c source code of the assembly code below?

```asm
<mat3_add>:
  endbr64
  movss  (%rdi),%xmm0
  addss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  addss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  addss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdi),%xmm0
  addss  0xc(%rsi),%xmm0
  movss  %xmm0,0xc(%rdi)
  movss  0x10(%rdi),%xmm0
  addss  0x10(%rsi),%xmm0
  movss  %xmm0,0x10(%rdi)
  movss  0x14(%rdi),%xmm0
  addss  0x14(%rsi),%xmm0
  movss  %xmm0,0x14(%rdi)
  movss  0x18(%rdi),%xmm0
  addss  0x18(%rsi),%xmm0
  movss  %xmm0,0x18(%rdi)
  movss  0x1c(%rdi),%xmm0
  addss  0x1c(%rsi),%xmm0
  movss  %xmm0,0x1c(%rdi)
  movss  0x20(%rdi),%xmm0
  addss  0x20(%rsi),%xmm0
  movss  %xmm0,0x20(%rdi)
  ret
```

assistant: ```c
void mat3_add(float *dst, float *b) {
  dst[0] = dst[0] + b[0];
  dst[1] = dst[1] + b[1];
  dst[2] = dst[2] + b[2];
  dst[3] = dst[3] + b[3];
  dst[4] = dst[4] + b[4];
  dst[5] = dst[5] + b[5];
  dst[6] = dst[6] + b[6];
  dst[7] = dst[7] + b[7];
  dst[8] = dst[8] + b[8];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strsplit7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x10(%rbp)
  movsbl -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void strsplit7(char *string, char sep, char **first, char **second) {
  char *copy = strdup(string);
  char *sep_ptr = strchr(copy, sep);
  *sep_ptr = '\0';
  *first = copy;
  *second = sep_ptr + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strsplit7>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %rcx,%r12
  call   <strdup@plt>
  mov    %rax,%rbp
  movsbl %bl,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  movb   $0x0,(%rax)
  mov    %rbp,0x0(%r13)
  add    $0x1,%rax
  mov    %rax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strsplit7(char *string, char sep, char **first, char **second) {
  char *copy = strdup(string);
  char *sep_ptr = strchr(copy, sep);
  *sep_ptr = '\0';
  *first = copy;
  *second = sep_ptr + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strsplit7>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strdup@plt>
  movsbl %bl,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strchr@plt>
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rbp,0x0(%r13)
  mov    %rax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strsplit7(char *string, char sep, char **first, char **second) {
  char *copy = strdup(string);
  char *sep_ptr = strchr(copy, sep);
  *sep_ptr = '\0';
  *first = copy;
  *second = sep_ptr + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strsplit7>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strdup@plt>
  movsbl %bl,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strchr@plt>
  movb   $0x0,(%rax)
  add    $0x1,%rax
  mov    %rbp,0x0(%r13)
  mov    %rax,(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strsplit7(char *string, char sep, char **first, char **second) {
  char *copy = strdup(string);
  char *sep_ptr = strchr(copy, sep);
  *sep_ptr = '\0';
  *first = copy;
  *second = sep_ptr + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<series2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L24
L52:
  mov    $0x28,%edi
  call   <putchar@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L19:
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L23
  mov    $0x2b,%edi
  call   <putchar@plt>
L23:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L19
  mov    $0x29,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L36
  mov    $0x2b,%edi
  call   <putchar@plt>
L36:
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L52
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
type: string
name: parse_data
arguments: data_label: D3
type: string

tool: D18: %d

tool: D3: 
Sum Of Above Series is %d


assistant: ```c
void series2(int n) {
  int sum = 0, i, j;
  for (i = 1; i <= n; i++) {
    printf("(");
    for (j = 1; j <= i; j++) {
      sum += j;
      printf("%d", j);
      if (j != i)
        printf("+");
    }
    printf(")");
    if (i != n)
      printf("+");
  }
  printf("\nSum Of Above Series is %d\n", sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<series2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L10
  mov    %edi,%r14d
  mov    $0x1,%ebp
  mov    $0x0,%r12d
  lea    D2(%rip),%r13
  jmp    L3
L37:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jg     L69
L55:
  add    %ebx,%r12d
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  je     L37
  mov    $0x2b,%edi
  call   <putchar@plt>
  jmp    L37
L69:
  mov    $0x29,%edi
  call   <putchar@plt>
  cmp    %ebp,%r14d
  je     L83
  mov    $0x2b,%edi
  call   <putchar@plt>
L83:
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  jl     L86
L3:
  mov    $0x28,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L69
  mov    $0x1,%ebx
  jmp    L55
L10:
  mov    $0x0,%r12d
L86:
  mov    %r12d,%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D2: %d

tool: D16: 
Sum Of Above Series is %d


assistant: ```c
void series2(int n) {
  int sum = 0, i, j;
  for (i = 1; i <= n; i++) {
    printf("(");
    for (j = 1; j <= i; j++) {
      sum += j;
      printf("%d", j);
      if (j != i)
        printf("+");
    }
    printf(")");
    if (i != n)
      printf("+");
  }
  printf("\nSum Of Above Series is %d\n", sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<series2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L9
  mov    %edi,%r14d
  mov    $0x1,%ebp
  xor    %r12d,%r12d
  lea    D5(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    $0x28,%edi
  mov    $0x1,%ebx
  call   <putchar@plt>
  nop
L39:
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    %ebx,%r12d
  call   <printf@plt>
  cmp    %ebx,%ebp
  je     L14
  mov    $0x2b,%edi
  call   <putchar@plt>
L14:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L39
  mov    $0x29,%edi
  call   <putchar@plt>
  cmp    %ebp,%r14d
  je     L11
  mov    $0x2b,%edi
  call   <putchar@plt>
L11:
  add    $0x1,%ebp
  cmp    %ebp,%r14d
  jge    L16
L30:
  pop    %rbx
  mov    %r12d,%esi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  lea    D13(%rip),%rdi
  pop    %r13
  pop    %r14
  jmp    1070 <printf@plt>
L9:
  xor    %r12d,%r12d
  jmp    L30
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string

tool: D5: %d

tool: D13: 
Sum Of Above Series is %d


assistant: ```c
void series2(int n) {
  int sum = 0, i, j;
  for (i = 1; i <= n; i++) {
    printf("(");
    for (j = 1; j <= i; j++) {
      sum += j;
      printf("%d", j);
      if (j != i)
        printf("+");
    }
    printf(")");
    if (i != n)
      printf("+");
  }
  printf("\nSum Of Above Series is %d\n", sum);
}
```