user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  lea    0x20(%rsp),%rbx
  call   <pipe@plt>
  lea    0x14(%rsp),%rdi
  call   <pipe@plt>
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  je     L38
  lea    D7(%rip),%r15
  lea    D75(%rip),%r14
  lea    D37(%rip),%r13
  lea    0x1e(%rsp),%rbp
  lea    D82(%rip),%r12
  nop
L22:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    0x18(%rsp),%edi
  mov    %rbx,%rsi
  mov    %eax,%edx
  call   <write@plt>
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edi
  mov    $0x2,%edx
  mov    %rbp,%rsi
  call   <read@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  cmpb   $0x71,0x1e(%rsp)
  jne    L22
L39:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  mov    0x14(%rsp),%edi
  mov    $0x50,%edx
  mov    %rbx,%rsi
  lea    D86(%rip),%r14
  lea    D23(%rip),%r13
  lea    D66(%rip),%r12
  mov    $0x9,%ebp
  call   <read@plt>
  mov    %r14,%rdi
  lea    D47(%rip),%r15
  mov    %eax,%esi
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  mov    0x10(%rsp),%edi
  mov    $0x1,%edx
  mov    %r15,%rsi
  call   <write@plt>
  mov    0x14(%rsp),%edi
  mov    $0x50,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L2
  mov    0x10(%rsp),%edi
  mov    $0x1,%edx
  lea    D44(%rip),%rsi
  call   <write@plt>
  jmp    L39
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D75
type: string
name: parse_data
arguments: tag: D37
type: string
name: parse_data
arguments: tag: D82
type: string
name: parse_data
arguments: tag: D86
type: string
name: parse_data
arguments: tag: D23
type: string
name: parse_data
arguments: tag: D66
type: string
name: parse_data
arguments: tag: D47
type: string
name: parse_data
arguments: tag: D44
type: string

tool: D7: %s

tool: D75: Parent:Message: <<%s>> sent to child


tool: D37: Parent:Waiting for confirmation

tool: D82: Parent:confirmation recieved from child %s


tool: D86: Child:%d Bytes recieved from parent.


tool: D23: Child:Msg:	%s


tool: D66: Child:	Remaining:%i


tool: D47: l

tool: D44: q

assistant: ```c
void main(int args, char *argv[]) {
  int hp[2], ph[2];
  char pa_buf[2], ch_buf[80];
  pipe(hp);
  pipe(ph);
  pid_t pid = fork();
  if (pid == 0) {
    int n_rec = 0;
    while (n_rec < 10) {
      int by_re = read(ph[0], ch_buf, 80);
      ch_buf[by_re] = '\0';
      printf("Child:%d Bytes recieved from parent.\n", by_re);
      printf("Child:Msg:\t%s\n", ch_buf);
      printf("Child:\tRemaining:%i\n", 10 - n_rec);
      if (n_rec < 9)
        write(hp[1], "l", 1);
      else
        write(hp[1], "q", 1);
      n_rec++;
    }
  } else {
    int exit = 0;
    while (!exit) {
      char input[80];
      scanf("%s", input);
      write(ph[1], input, strlen(input));
      printf("Parent:Message: <<%s>> sent to child\n", input);
      printf("Parent:Waiting for confirmation\n");
      read(hp[0], pa_buf, 2);
      printf("Parent:confirmation recieved from child %s\n", pa_buf);
      if (pa_buf[0] == 'q')
        exit = 1;
    }
  }
}
```