ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L25
  movaps %xmm0,%xmm3
  maxss  0x14(%rsp),%xmm3
L3:
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  pxor   %xmm2,%xmm2
  cvtss2sd 0x14(%rsp),%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D17(%rip),%rdi
  mov    $0x4,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L25:
  movaps %xmm1,%xmm3
  maxss  0x14(%rsp),%xmm3
  jmp    L3
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D29
type: string
name: disassemble_data
arguments: data_label: D15
type: string
name: disassemble_data
arguments: data_label: D17
type: string

tool: D29: Enter three numbers: 

tool: D15: %f %f %f

tool: D17: Greatest of %.2f, %.2f and %.2f = %.2f


assistant: ```c
int main() {
  float num1, num2, num3, greatest;
  printf("Enter three numbers: ");
  scanf("%f %f %f", &num1, &num2, &num3);
  num1 > num2 ? (num1 > num3 ? (greatest = num1) : (greatest = num3)) : (num2 > num3 ? (greatest = num2) : (greatest = num3));
  printf("Greatest of %.2f, %.2f and %.2f = %.2f\n", num1, num2, num3, greatest);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L15
  movaps %xmm0,%xmm3
  maxss  0x14(%rsp),%xmm3
L10:
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm1,%xmm1
  lea    D20(%rip),%rdi
  mov    $0x4,%eax
  cvtss2sd 0x14(%rsp),%xmm2
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L15:
  movaps %xmm1,%xmm3
  maxss  0x14(%rsp),%xmm3
  jmp    L10
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string
name: extract_symbolic_data
arguments: tag: D20
datatype: string

tool: D16: Enter three numbers: 

tool: D13: %f %f %f

tool: D20: Greatest of %.2f, %.2f and %.2f = %.2f


assistant: ```c
int main() {
  float num1, num2, num3, greatest;
  printf("Enter three numbers: ");
  scanf("%f %f %f", &num1, &num2, &num3);
  num1 > num2 ? (num1 > num3 ? (greatest = num1) : (greatest = num3)) : (num2 > num3 ? (greatest = num2) : (greatest = num3));
  printf("Greatest of %.2f, %.2f and %.2f = %.2f\n", num1, num2, num3, greatest);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L14
  movaps %xmm0,%xmm3
  maxss  0x14(%rsp),%xmm3
L3:
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm1,%xmm1
  lea    D26(%rip),%rdi
  mov    $0x4,%eax
  cvtss2sd 0x14(%rsp),%xmm2
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L14:
  movaps %xmm1,%xmm3
  maxss  0x14(%rsp),%xmm3
  jmp    L3
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string

tool: D13: Enter three numbers: 

tool: D20: %f %f %f

tool: D26: Greatest of %.2f, %.2f and %.2f = %.2f


assistant: ```c
int main() {
  float num1, num2, num3, greatest;
  printf("Enter three numbers: ");
  scanf("%f %f %f", &num1, &num2, &num3);
  num1 > num2 ? (num1 > num3 ? (greatest = num1) : (greatest = num3)) : (num2 > num3 ? (greatest = num2) : (greatest = num3));
  printf("Greatest of %.2f, %.2f and %.2f = %.2f\n", num1, num2, num3, greatest);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_splitter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,%eax
  mov    %al,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7e5f2d212e3b2c20,%rax
  movabs $0x282a265e25242340,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x7c5d5b7d7b3d2b29,%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x90a,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L26
L41:
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    %al,-0x44(%rbp)
  jne    L22
  mov    $0x1,%eax
  jmp    L33
L22:
  addl   $0x1,-0x34(%rbp)
L26:
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L41
  mov    $0x0,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int is_splitter(char ch) {
  char splitters[] = " ,;.!-_~@#$%^&*()+={}[]|\n\t";
  for (int i = 0; splitters[i] != '\0'; ++i)
    if (ch == splitters[i])
      return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_splitter>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x7e5f2d212e3b2c20,%rax
  movabs $0x282a265e25242340,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x7c5d5b7d7b3d2b29,%rax
  mov    %rax,0x10(%rsp)
  movw   $0x90a,0x18(%rsp)
  movb   $0x0,0x1a(%rsp)
  mov    $0x20,%eax
  lea    0x1(%rsp),%rdx
L20:
  cmp    %al,%dil
  je     L33
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L20
  mov    $0x0,%eax
  jmp    L6
L33:
  mov    $0x1,%eax
L6:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x38,%rsp
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_splitter(char ch) {
  char splitters[] = " ,;.!-_~@#$%^&*()+={}[]|\n\t";
  for (int i = 0; splitters[i] != '\0'; ++i)
    if (ch == splitters[i])
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_splitter>:
  endbr64
  sub    $0x38,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rdx
  movb   $0x0,0x1a(%rsp)
  movabs $0x7c5d5b7d7b3d2b29,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x90a,%eax
  mov    %ax,0x18(%rsp)
  mov    $0x20,%eax
  movaps %xmm0,(%rsp)
  jmp    L5
  xchg   %ax,%ax
L33:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L22
L5:
  cmp    %al,%dil
  jne    L33
  mov    $0x1,%eax
L30:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  jmp    L30
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: byte[16]

tool: {"D8": [0x20,0x2c,0x3b,0x2e,0x21,0x2d,0x5f,0x7e,0x40,0x23,0x24,0x25,0x5e,0x26,0x2a,0x28]}

assistant: ```c
int is_splitter(char ch) {
  char splitters[] = " ,;.!-_~@#$%^&*()+={}[]|\n\t";
  for (int i = 0; splitters[i] != '\0'; ++i)
    if (ch == splitters[i])
      return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_splitter>:
  endbr64
  sub    $0x38,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rdx
  movb   $0x0,0x1a(%rsp)
  movabs $0x7c5d5b7d7b3d2b29,%rax
  mov    %rax,0x10(%rsp)
  mov    $0x90a,%eax
  mov    %ax,0x18(%rsp)
  mov    $0x20,%eax
  movaps %xmm0,(%rsp)
  jmp    L1
  xchg   %ax,%ax
L23:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L32
L1:
  cmp    %al,%dil
  jne    L23
  mov    $0x1,%eax
L20:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x38,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  jmp    L20
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: byte[16]

tool: {"D7": [0x20,0x2c,0x3b,0x2e,0x21,0x2d,0x5f,0x7e,0x40,0x23,0x24,0x25,0x5e,0x26,0x2a,0x28]}

assistant: ```c
int is_splitter(char ch) {
  char splitters[] = " ,;.!-_~@#$%^&*()+={}[]|\n\t";
  for (int i = 0; splitters[i] != '\0'; ++i)
    if (ch == splitters[i])
      return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<i2d_EC_PUBKEY>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L6
L25:
  mov    $0x0,%eax
  call   <EVP_PKEY_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ASN1error@plt>
  mov    $0x0,%eax
  jmp    L6
L9:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_set1_EC_KEY@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <i2d_PUBKEY@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_free@plt>
  mov    -0xc(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int i2d_EC_PUBKEY(EC_KEY *a, unsigned char **pp) {
  EVP_PKEY *pktmp;
  int ret;
  if (!a)
    return (0);
  if ((pktmp = EVP_PKEY_new()) == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (0);
  }
  EVP_PKEY_set1_EC_KEY(pktmp, a);
  ret = i2d_PUBKEY(pktmp, pp);
  EVP_PKEY_free(pktmp);
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<i2d_EC_PUBKEY>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    $0x0,%eax
  call   <EVP_PKEY_new@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L16
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_set1_EC_KEY@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <i2d_PUBKEY@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <EVP_PKEY_free@plt>
L10:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L10
```

assistant: ```c
int i2d_EC_PUBKEY(EC_KEY *a, unsigned char **pp) {
  EVP_PKEY *pktmp;
  int ret;
  if (!a)
    return (0);
  if ((pktmp = EVP_PKEY_new()) == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (0);
  }
  EVP_PKEY_set1_EC_KEY(pktmp, a);
  ret = i2d_PUBKEY(pktmp, pp);
  EVP_PKEY_free(pktmp);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<i2d_EC_PUBKEY>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L4
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r14
  call   <EVP_PKEY_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_set1_EC_KEY@plt>
  mov    %r12,%rdi
  mov    %r14,%rsi
  call   <i2d_PUBKEY@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <EVP_PKEY_free@plt>
L4:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int i2d_EC_PUBKEY(EC_KEY *a, unsigned char **pp) {
  EVP_PKEY *pktmp;
  int ret;
  if (!a)
    return (0);
  if ((pktmp = EVP_PKEY_new()) == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (0);
  }
  EVP_PKEY_set1_EC_KEY(pktmp, a);
  ret = i2d_PUBKEY(pktmp, pp);
  EVP_PKEY_free(pktmp);
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i2d_EC_PUBKEY>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L13
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r14
  call   <EVP_PKEY_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_set1_EC_KEY@plt>
  mov    %r12,%rdi
  mov    %r14,%rsi
  call   <i2d_PUBKEY@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <EVP_PKEY_free@plt>
L13:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int i2d_EC_PUBKEY(EC_KEY *a, unsigned char **pp) {
  EVP_PKEY *pktmp;
  int ret;
  if (!a)
    return (0);
  if ((pktmp = EVP_PKEY_new()) == NULL) {
    ASN1error(ERR_R_MALLOC_FAILURE);
    return (0);
  }
  EVP_PKEY_set1_EC_KEY(pktmp, a);
  ret = i2d_PUBKEY(pktmp, pp);
  EVP_PKEY_free(pktmp);
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L7:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uart_write@plt>
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_print(char *msg) {
  while (*msg != 0)
    uart_write(*msg++);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uart_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L9
L5:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <uart_write@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L9:
  pop    %rbx
  ret
```

assistant: ```c
void uart_print(char *msg) {
  while (*msg != 0)
    uart_write(*msg++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uart_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L12
L9:
  call   <uart_write@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L9
L12:
  pop    %rbx
  ret
```

assistant: ```c
void uart_print(char *msg) {
  while (*msg != 0)
    uart_write(*msg++);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uart_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L13:
  call   <uart_write@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
L14:
  pop    %rbx
  ret
```

assistant: ```c
void uart_print(char *msg) {
  while (*msg != 0)
    uart_write(*msg++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getCellIdRight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L9
  mov    $0xffffffff,%eax
  jmp    L11
L9:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int getCellIdRight(int cellId) {
  if ((cellId + 1) % 8 == 0)
    return -1;
  return cellId + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getCellIdRight>:
  endbr64
  lea    0x1(%rdi),%eax
  test   $0x7,%al
  mov    $0xffffffff,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int getCellIdRight(int cellId) {
  if ((cellId + 1) % 8 == 0)
    return -1;
  return cellId + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getCellIdRight>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    $0xffffffff,%edx
  test   $0x7,%al
  cmove  %edx,%eax
  ret
```

assistant: ```c
int getCellIdRight(int cellId) {
  if ((cellId + 1) % 8 == 0)
    return -1;
  return cellId + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getCellIdRight>:
  endbr64
  lea    0x1(%rdi),%eax
  mov    $0xffffffff,%edx
  test   $0x7,%al
  cmove  %edx,%eax
  ret
```

assistant: ```c
int getCellIdRight(int cellId) {
  if ((cellId + 1) % 8 == 0)
    return -1;
  return cellId + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x31,-0x10(%rbp)
  movl   $0x7,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <euclidean_gcd_recursive@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <euclidean_gcd@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D4: GCD of %d and %d is : %d by recursive algo.


tool: D6: GCD of %d and %d is : %d by iterative algo.


assistant: ```c
int main() {
  int first = 49;
  int second = 7;
  int answer_recursive = euclidean_gcd_recursive(first, second);
  int answer_iterative = euclidean_gcd(first, second);
  printf("GCD of %d and %d is : %d by recursive algo.\n", first, second, answer_recursive);
  printf("GCD of %d and %d is : %d by iterative algo.\n", first, second, answer_iterative);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x31,%edi
  call   <euclidean_gcd_recursive@plt>
  mov    %eax,%ebp
  mov    $0x7,%esi
  mov    $0x31,%edi
  call   <euclidean_gcd@plt>
  mov    %eax,%ebx
  mov    %ebp,%ecx
  mov    $0x7,%edx
  mov    $0x31,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    $0x7,%edx
  mov    $0x31,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D19
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D19: GCD of %d and %d is : %d by recursive algo.


tool: D0: GCD of %d and %d is : %d by iterative algo.


assistant: ```c
int main() {
  int first = 49;
  int second = 7;
  int answer_recursive = euclidean_gcd_recursive(first, second);
  int answer_iterative = euclidean_gcd(first, second);
  printf("GCD of %d and %d is : %d by recursive algo.\n", first, second, answer_recursive);
  printf("GCD of %d and %d is : %d by iterative algo.\n", first, second, answer_iterative);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x7,%esi
  mov    $0x31,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <euclidean_gcd_recursive@plt>
  mov    $0x7,%esi
  mov    $0x31,%edi
  mov    %eax,%r13d
  call   <euclidean_gcd@plt>
  mov    %r13d,%ecx
  mov    $0x7,%edx
  mov    $0x31,%esi
  mov    %eax,%r12d
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%ecx
  mov    $0x7,%edx
  mov    $0x31,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D4: GCD of %d and %d is : %d by recursive algo.


tool: D2: GCD of %d and %d is : %d by iterative algo.


assistant: ```c
int main() {
  int first = 49;
  int second = 7;
  int answer_recursive = euclidean_gcd_recursive(first, second);
  int answer_iterative = euclidean_gcd(first, second);
  printf("GCD of %d and %d is : %d by recursive algo.\n", first, second, answer_recursive);
  printf("GCD of %d and %d is : %d by iterative algo.\n", first, second, answer_iterative);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x7,%esi
  mov    $0x31,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <euclidean_gcd_recursive@plt>
  mov    $0x7,%esi
  mov    $0x31,%edi
  mov    %eax,%r13d
  call   <euclidean_gcd@plt>
  mov    %r13d,%ecx
  mov    $0x7,%edx
  mov    $0x31,%esi
  mov    %eax,%r12d
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%ecx
  mov    $0x7,%edx
  mov    $0x31,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D5
type_guessed: string

tool: D17: GCD of %d and %d is : %d by recursive algo.


tool: D5: GCD of %d and %d is : %d by iterative algo.


assistant: ```c
int main() {
  int first = 49;
  int second = 7;
  int answer_recursive = euclidean_gcd_recursive(first, second);
  int answer_iterative = euclidean_gcd(first, second);
  printf("GCD of %d and %d is : %d by recursive algo.\n", first, second, answer_recursive);
  printf("GCD of %d and %d is : %d by iterative algo.\n", first, second, answer_iterative);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<typecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int typecmp(const void *e1, const void *e2) {
  const char *s1 = *(const char *const *)e1;
  const char *s2 = *(const char *const *)e2;
  return strcmp(s1, s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<typecmp>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int typecmp(const void *e1, const void *e2) {
  const char *s1 = *(const char *const *)e1;
  const char *s2 = *(const char *const *)e2;
  return strcmp(s1, s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<typecmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int typecmp(const void *e1, const void *e2) {
  const char *s1 = *(const char *const *)e1;
  const char *s2 = *(const char *const *)e2;
  return strcmp(s1, s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<typecmp>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int typecmp(const void *e1, const void *e2) {
  const char *s1 = *(const char *const *)e1;
  const char *s2 = *(const char *const *)e2;
  return strcmp(s1, s2);
}
```