ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bsearch_more>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %r8,0x10(%rsp)
  sub    $0x1,%ebp
  js     L12
  mov    %rdi,%r13
  xor    %r15d,%r15d
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L55:
  je     L20
  lea    0x1(%r14),%r15d
  cmp    %r15d,%ebp
  jl     L60
L42:
  lea    (%r15,%rbp,1),%edx
  mov    0x10(%rsp),%rax
  mov    %r13,%rdi
  sar    %edx
  movslq %edx,%rbx
  mov    %rbx,%r14
  imul   0x8(%rsp),%rbx
  add    %r12,%rbx
  mov    %rbx,%rsi
  call   *%rax
  test   %eax,%eax
  jns    L55
  lea    -0x1(%r14),%ebp
  cmp    %r15d,%ebp
  jge    L42
L60:
  movslq %r15d,%rcx
  mov    0x18(%rsp),%r15
  xor    %eax,%eax
  sub    $0x1,%r15
  cmp    %r15,%rcx
  ja     L39
  imul   0x8(%rsp),%rcx
  lea    (%r12,%rcx,1),%rax
L39:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    0x8(%rsp),%rax
  xor    %edx,%edx
  add    %rbx,%rax
  cmp    %ebp,%r14d
  cmove  %rdx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    %rsi,%rax
  jmp    L39
```

assistant: ```c
void *bsearch_more(const void *key, const void *base, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  int l, u, idx;
  const void *p;
  int comparison;
  l = 0;
  u = nmemb - 1;
  while (l <= u) {
    idx = (l + u) / 2;
    p = (void *)(((const char *)base) + (idx * size));
    comparison = (*compar)(key, p);
    if (comparison < 0)
      u = idx - 1;
    else if (comparison > 0)
      l = idx + 1;
    else
      return (idx == u) ? NULL : (void *)(((const char *)p) + size);
  }
  return (l > nmemb - 1) ? NULL : (void *)(((const char *)base) + (l * size));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getElementName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L53
L38:
  addq   $0x1,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L62
L69:
  addl   $0x1,-0x8(%rbp)
L62:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L48
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L48
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L48
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L69
L48:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getElementName(char *pline, char *name) {
  int pos = 0, len;
  while (isspace((int)*pline))
    pline++;
  len = strlen(pline);
  while (pos < len && !isspace((int)*(pline + pos)) && *(pline + pos) != '=' && *(pline + pos) != ':')
    pos++;
  strncpy(name, pline, pos);
  name[pos] = 0;
  pline += pos;
  return (pline);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getElementName>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  jmp    L32
L41:
  add    $0x1,%rbp
L32:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jle    L73
  mov    %rbp,%rbx
  mov    $0x0,%r12d
L21:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  movzbl (%rbx),%eax
  cmp    $0x3a,%al
  je     L19
  cmp    $0x3d,%al
  je     L19
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%r14d
  jne    L21
  mov    %r14d,%r12d
L19:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %r12d,%r12
  movb   $0x0,0x0(%r13,%r12,1)
  lea    0x0(%rbp,%r12,1),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  mov    $0x0,%r12d
  jmp    L19
```

assistant: ```c
char *getElementName(char *pline, char *name) {
  int pos = 0, len;
  while (isspace((int)*pline))
    pline++;
  len = strlen(pline);
  while (pos < len && !isspace((int)*(pline + pos)) && *(pline + pos) != '=' && *(pline + pos) != ':')
    pos++;
  strncpy(name, pline, pos);
  name[pos] = 0;
  pline += pos;
  return (pline);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getElementName>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  jmp    L85
  nopl   0x0(%rax)
L5:
  add    $0x1,%r12
L85:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12,%rdi
  mov    %r12,%rbp
  xor    %ebx,%ebx
  call   <strlen@plt>
  movslq %eax,%r15
  test   %eax,%eax
  jg     L60
  jmp    L18
  nopl   0x0(%rax)
L79:
  movzbl 0x0(%rbp),%eax
  cmp    $0x3a,%al
  je     L55
  cmp    $0x3d,%al
  je     L55
  add    $0x1,%rbx
  add    $0x1,%r14d
  lea    0x1(%r13),%rbp
  cmp    %r15,%rbx
  je     L46
L60:
  movsbl 0x0(%rbp),%edi
  mov    %ebx,%r14d
  mov    %rbp,%r13
  call   <isspace@plt>
  test   %rax,%rax
  je     L79
L55:
  add    0x8(%rsp),%rbx
L73:
  mov    0x8(%rsp),%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%rbx)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L46:
  mov    0x8(%rsp),%rax
  movslq %r14d,%r13
  lea    (%rax,%r13,1),%rbx
  add    %r12,%r13
  jmp    L73
L18:
  mov    0x8(%rsp),%rbx
  mov    %r12,%r13
  xor    %r14d,%r14d
  jmp    L73
```

assistant: ```c
char *getElementName(char *pline, char *name) {
  int pos = 0, len;
  while (isspace((int)*pline))
    pline++;
  len = strlen(pline);
  while (pos < len && !isspace((int)*(pline + pos)) && *(pline + pos) != '=' && *(pline + pos) != ':')
    pos++;
  strncpy(name, pline, pos);
  name[pos] = 0;
  pline += pos;
  return (pline);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getElementName>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  jmp    L55
  nopl   0x0(%rax)
L10:
  add    $0x1,%r12
L55:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
  mov    %r12,%rdi
  mov    %r12,%rbp
  xor    %ebx,%ebx
  call   <strlen@plt>
  movslq %eax,%r15
  test   %eax,%eax
  jg     L25
  jmp    L23
  nopl   0x0(%rax)
L74:
  movzbl 0x0(%rbp),%eax
  cmp    $0x3a,%al
  je     L86
  cmp    $0x3d,%al
  je     L86
  add    $0x1,%rbx
  add    $0x1,%r14d
  lea    0x1(%r13),%rbp
  cmp    %r15,%rbx
  je     L83
L25:
  movsbl 0x0(%rbp),%edi
  mov    %ebx,%r14d
  mov    %rbp,%r13
  call   <isspace@plt>
  test   %rax,%rax
  je     L74
L86:
  add    0x8(%rsp),%rbx
L52:
  mov    0x8(%rsp),%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%rbx)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L83:
  mov    0x8(%rsp),%rax
  movslq %r14d,%r13
  lea    (%rax,%r13,1),%rbx
  add    %r12,%r13
  jmp    L52
L23:
  mov    0x8(%rsp),%rbx
  mov    %r12,%r13
  xor    %r14d,%r14d
  jmp    L52
```

assistant: ```c
char *getElementName(char *pline, char *name) {
  int pos = 0, len;
  while (isspace((int)*pline))
    pline++;
  len = strlen(pline);
  while (pos < len && !isspace((int)*(pline + pos)) && *(pline + pos) != '=' && *(pline + pos) != ':')
    pos++;
  strncpy(name, pline, pos);
  name[pos] = 0;
  pline += pos;
  return (pline);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x1c(%rsp)
  jle    L69
  movl   $0x0,0xc(%rsp)
  lea    D7(%rip),%r15
  jmp    L7
L18:
  mov    %ebx,%r12d
  mov    $0x0,%r14d
L127:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x18(%rsp)
  jle    L129
L63:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  add    %eax,%r13d
  movslq %r12d,%rdx
  mov    0x20(%rsp,%rdx,4),%edx
  cmp    %edx,%eax
  jg     L18
  cmp    %r12d,%ebx
  je     L127
  cmp    %edx,%eax
  mov    $0x1,%eax
  cmove  %eax,%r14d
  jmp    L127
L129:
  test   %r14d,%r14d
  jne    L119
L13:
  movslq %r12d,%rdx
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %r13d,%eax
  sar    %eax
  cmp    %eax,0x20(%rsp,%rdx,4)
  jle    L71
  lea    0x1(%r12),%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L22:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jle    L69
L7:
  lea    0x18(%rsp),%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x18(%rsp)
  jle    L103
  lea    0x20(%rsp),%rbp
  mov    $0x0,%r14d
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  jmp    L63
L119:
  lea    D42(%rip),%rdi
  call   <puts@plt>
  jmp    L22
L103:
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L13
L71:
  lea    0x1(%r12),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L69:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D37
type: string
name: retrieve_data
arguments: tag: D42
type: string
name: retrieve_data
arguments: tag: D22
type: string

tool: D7: %d

tool: D37: majority winner %d


tool: D42: no winner

tool: D22: minority winner %d


assistant: ```c
int main() {
  int i, j, c, t, n, tot, win, tie;
  int votes[10];
  for (i = 0, scanf("%d", &t); i < t; i++) {
    for (j = tot = win = tie = 0, scanf("%d", &c); j < c; j++) {
      scanf("%d", &votes[j]);
      tot += votes[j];
      if (votes[j] > votes[win]) {
        win = j;
        tie = 0;
      } else if (votes[j] == votes[win] && j != win) {
        tie = 1;
      }
    }
    if (tie) {
      printf("no winner\n");
    } else if (votes[win] > tot / 2)
      printf("majority winner %d\n", win + 1);
    else
      printf("minority winner %d\n", win + 1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D33(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  lea    0x18(%rsp),%rax
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  test   %edx,%edx
  jle    L11
  nopl   0x0(%rax)
L135:
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L39
  lea    0x20(%rsp),%r13
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L88:
  cmp    %r15d,%r14d
  je     L106
  cmp    %esi,%eax
  mov    $0x1,%eax
  cmove  %eax,%ebp
L106:
  add    $0x1,%r14d
  add    $0x4,%r13
  cmp    %r14d,0x18(%rsp)
  jle    L113
L48:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq %r15d,%rsi
  mov    0x0(%r13),%eax
  mov    0x20(%rsp,%rsi,4),%esi
  add    %eax,%ebx
  cmp    %esi,%eax
  jle    L88
  mov    %r14d,%r15d
  xor    %ebp,%ebp
  add    $0x1,%r14d
  add    $0x4,%r13
  cmp    %r14d,0x18(%rsp)
  jg     L48
L113:
  test   %ebp,%ebp
  jne    L98
  mov    %ebx,%eax
  lea    0x1(%r15),%esi
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
L102:
  movslq %r15d,%r8
  cmp    %eax,0x20(%rsp,%r8,4)
  jle    L79
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L64:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jg     L135
L11:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L79:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L98:
  lea    D19(%rip),%rdi
  call   <puts@plt>
  jmp    L64
  xchg   %ax,%ax
L39:
  mov    $0x1,%esi
  xor    %eax,%eax
  xor    %r15d,%r15d
  jmp    L102
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D33
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D34
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D33: %d

tool: D34: majority winner %d


tool: D4: minority winner %d


tool: D19: no winner

assistant: ```c
int main() {
  int i, j, c, t, n, tot, win, tie;
  int votes[10];
  for (i = 0, scanf("%d", &t); i < t; i++) {
    for (j = tot = win = tie = 0, scanf("%d", &c); j < c; j++) {
      scanf("%d", &votes[j]);
      tot += votes[j];
      if (votes[j] > votes[win]) {
        win = j;
        tie = 0;
      } else if (votes[j] == votes[win] && j != win) {
        tie = 1;
      }
    }
    if (tie) {
      printf("no winner\n");
    } else if (votes[win] > tot / 2)
      printf("majority winner %d\n", win + 1);
    else
      printf("minority winner %d\n", win + 1);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D32(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  lea    0x18(%rsp),%rax
  movl   $0x0,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  test   %edx,%edx
  jle    L53
  nopl   0x0(%rax)
L8:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L155
  lea    0x20(%rsp),%r14
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  jmp    L129
  nopw   0x0(%rax,%rax,1)
L144:
  cmp    %ebx,%r15d
  je     L92
  cmp    %esi,%eax
  jne    L92
  mov    %esi,%eax
  mov    $0x1,%r12d
L22:
  add    $0x1,%r15d
  add    $0x4,%r14
  cmp    %r15d,0x18(%rsp)
  jle    L90
L129:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  movslq %ebx,%rsi
  mov    (%r14),%eax
  mov    0x20(%rsp,%rsi,4),%esi
  add    %eax,%ebp
  cmp    %esi,%eax
  jle    L144
  mov    %r15d,%ebx
  xor    %r12d,%r12d
  add    $0x1,%r15d
  add    $0x4,%r14
  cmp    %r15d,0x18(%rsp)
  jg     L129
L90:
  test   %r12d,%r12d
  jne    L6
  mov    %ebp,%edx
  lea    0x1(%rbx),%esi
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
L44:
  cmp    %eax,%edx
  jge    L142
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L127:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jg     L8
L53:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L134
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L92:
  mov    %esi,%eax
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L142:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L127
L6:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L127
  xchg   %ax,%ax
L155:
  mov    0x20(%rsp),%eax
  mov    $0x1,%esi
  xor    %edx,%edx
  jmp    L44
L134:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string

tool: D32: %d

tool: D28: majority winner %d


tool: D3: minority winner %d


tool: D24: no winner

assistant: ```c
int main() {
  int i, j, c, t, n, tot, win, tie;
  int votes[10];
  for (i = 0, scanf("%d", &t); i < t; i++) {
    for (j = tot = win = tie = 0, scanf("%d", &c); j < c; j++) {
      scanf("%d", &votes[j]);
      tot += votes[j];
      if (votes[j] > votes[win]) {
        win = j;
        tie = 0;
      } else if (votes[j] == votes[win] && j != win) {
        tie = 1;
      }
    }
    if (tie) {
      printf("no winner\n");
    } else if (votes[win] > tot / 2)
      printf("majority winner %d\n", win + 1);
    else
      printf("minority winner %d\n", win + 1);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int j = foo(1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int j = foo(1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int j = foo(1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int j = foo(1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Plain_LinkCheck>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Plain_LinkCheck(void) {
  ;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Plain_LinkCheck>:
  endbr64
  ret
```

assistant: ```c
void Plain_LinkCheck(void) {
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Plain_LinkCheck>:
  endbr64
  ret
```

assistant: ```c
void Plain_LinkCheck(void) {
  ;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Plain_LinkCheck>:
  endbr64
  ret
```

assistant: ```c
void Plain_LinkCheck(void) {
  ;
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gfarm_hash_default>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L8:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0xf0000000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L14
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x8(%rbp)
L14:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gfarm_hash_default(const void *key, int keylen) {
  int i;
  unsigned int hash = 0, g;
  for (i = 0; i < keylen; i++) {
    hash = (hash << 4) + ((unsigned char *)key)[i];
    if ((g = hash & 0xf0000000) != 0) {
      hash ^= g >> 24;
      hash ^= g;
    }
  }
  return (hash);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gfarm_hash_default>:
  endbr64
  test   %esi,%esi
  jle    L37
  movzbl (%rdi),%eax
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%ecx
  add    %rcx,%rdi
  jmp    L25
L37:
  mov    $0x0,%eax
  ret
L35:
  add    $0x1,%rdx
L25:
  cmp    %rdi,%rdx
  je     L31
  shl    $0x4,%eax
  movzbl 0x1(%rdx),%ecx
  add    %ecx,%eax
  mov    %eax,%ecx
  and    $0xf0000000,%ecx
  je     L35
  and    $0xfffffff,%eax
  shr    $0x18,%ecx
  xor    %ecx,%eax
  jmp    L35
L31:
  ret
```

assistant: ```c
int gfarm_hash_default(const void *key, int keylen) {
  int i;
  unsigned int hash = 0, g;
  for (i = 0; i < keylen; i++) {
    hash = (hash << 4) + ((unsigned char *)key)[i];
    if ((g = hash & 0xf0000000) != 0) {
      hash ^= g >> 24;
      hash ^= g;
    }
  }
  return (hash);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gfarm_hash_default>:
  endbr64
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%ecx
  movzbl (%rdi),%eax
  add    %rdi,%rcx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl 0x1(%rdi),%edx
  shl    $0x4,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xf0000000,%edx
  je     L29
  and    $0xfffffff,%eax
  shr    $0x18,%edx
  xor    %edx,%eax
L29:
  add    $0x1,%rdi
L9:
  cmp    %rcx,%rdi
  jne    L14
  ret
  nop
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int gfarm_hash_default(const void *key, int keylen) {
  int i;
  unsigned int hash = 0, g;
  for (i = 0; i < keylen; i++) {
    hash = (hash << 4) + ((unsigned char *)key)[i];
    if ((g = hash & 0xf0000000) != 0) {
      hash ^= g >> 24;
      hash ^= g;
    }
  }
  return (hash);
}
```
user: What is the c source code of the assembly code below:

```asm
<gfarm_hash_default>:
  endbr64
  test   %esi,%esi
  jle    L39
  movzbl (%rdi),%eax
  cmp    $0x1,%esi
  je     L6
  lea    -0x2(%rsi),%ecx
  lea    0x1(%rdi),%rdx
  lea    0x2(%rdi,%rcx,1),%rsi
  nopl   0x0(%rax)
L17:
  movzbl (%rdx),%ecx
  shl    $0x4,%eax
  add    %ecx,%eax
  mov    %eax,%ecx
  and    $0xf0000000,%ecx
  je     L21
  and    $0xfffffff,%eax
  shr    $0x18,%ecx
  xor    %ecx,%eax
L21:
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L17
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int gfarm_hash_default(const void *key, int keylen) {
  int i;
  unsigned int hash = 0, g;
  for (i = 0; i < keylen; i++) {
    hash = (hash << 4) + ((unsigned char *)key)[i];
    if ((g = hash & 0xf0000000) != 0) {
      hash ^= g >> 24;
      hash ^= g;
    }
  }
  return (hash);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wchars_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xd7ff,-0x4(%rbp)
  jle    L96
  cmpl   $0xdfff,-0x4(%rbp)
  jg     L96
  mov    $0xffffffff,%edi
  call   <exit@plt>
L96:
  cmpl   $0x7f,-0x4(%rbp)
  jg     L37
  mov    $0x1,%eax
  jmp    L8
L37:
  cmpl   $0x7ff,-0x4(%rbp)
  jg     L90
  mov    $0x2,%eax
  jmp    L8
L90:
  cmpl   $0xffff,-0x4(%rbp)
  jg     L2
  mov    $0x3,%eax
  jmp    L8
L2:
  cmpl   $0x10ffff,-0x4(%rbp)
  jg     L24
  mov    $0x4,%eax
  jmp    L8
L24:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int wchars_size(wchar_t c) {
  if (c > 55295 && c < 57344)
    exit(-1);
  if (c < 128)
    return (1);
  else if (c < 2048)
    return (2);
  else if (c < 65536)
    return (3);
  else if (c < 1114112)
    return (4);
  else
    exit(-1);
  return (0);
}
```