ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<smf2low>:
  endbr64
  test   %esi,%esi
  jle    L16
  push   %r15
  movslq %esi,%rax
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L8:
  movss  D16(%rip),%xmm1
  subss  (%r15,%rbx,4),%xmm1
  mulss  D3(%rip),%xmm1
  movss  0x0(%rbp,%rbx,4),%xmm0
  movss  %xmm1,0x4(%rsp)
  call   <smff2w_2@plt>
  movss  (%r14,%rbx,4),%xmm0
  movss  0x4(%rsp),%xmm1
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <smf2lowv@plt>
  movss  %xmm0,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: byte[4]
name: parse_data
arguments: tag: D3
type_guessed: byte[4]

tool: {"D16": [0x00,0x00,0x80,0x3f]}

tool: {"D3": [0xf3,0x04,0xb5,0x3f]}

assistant: ```c
void smf2low(float *u, int n, float *y, float *x, float *f, float *r) {
  int i;
  for (i = 0; i < n; i++) {
    y[i] = smf2lowv(u, x[i], smff2w_2(f[i]), 1.414213562373095f * (1 - r[i]));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smf2low>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r15
  movslq %esi,%rax
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L1:
  movss  D16(%rip),%xmm1
  subss  (%r15,%rbx,4),%xmm1
  mulss  D2(%rip),%xmm1
  movss  0x0(%rbp,%rbx,4),%xmm0
  movss  %xmm1,0x4(%rsp)
  call   <smff2w_2@plt>
  movss  (%r14,%rbx,4),%xmm0
  movss  0x4(%rsp),%xmm1
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <smf2lowv@plt>
  movss  %xmm0,0x0(%r13,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jne    L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
datatype: byte[4]
name: disassemble_data
arguments: data_tag: D2
datatype: byte[4]

tool: {"D16": [0x00,0x00,0x80,0x3f]}

tool: {"D2": [0xf3,0x04,0xb5,0x3f]}

assistant: ```c
void smf2low(float *u, int n, float *y, float *x, float *f, float *r) {
  int i;
  for (i = 0; i < n; i++) {
    y[i] = smf2lowv(u, x[i], smff2w_2(f[i]), 1.414213562373095f * (1 - r[i]));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m_eye>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <m_set0@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L3:
  mov    -0x4(%rbp),%eax
  imul   -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: f64

tool: D5: 1

assistant: ```c
void m_eye(double *A, int nrow, int ncol) {
  int i;
  m_set0(A, nrow, ncol);
  for (i = 0; i < nrow; i++)
    *(A + i * ncol + i) = 1.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<m_eye>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  call   <m_set0@plt>
  test   %ebp,%ebp
  jle    L19
  movslq %r12d,%r12
  lea    0x8(,%r12,8),%rcx
  mov    %rbx,%rax
  mov    $0x0,%edx
  movsd  D1(%rip),%xmm0
L15:
  movsd  %xmm0,(%rax)
  add    $0x1,%edx
  add    %rcx,%rax
  cmp    %edx,%ebp
  jne    L15
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
void m_eye(double *A, int nrow, int ncol) {
  int i;
  m_set0(A, nrow, ncol);
  for (i = 0; i < nrow; i++)
    *(A + i * ncol + i) = 1.0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<m_eye>:
  endbr64
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %r12d,%edx
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <m_set0@plt>
  test   %ebp,%ebp
  jle    L10
  movsd  D6(%rip),%xmm0
  lea    0x8(,%r12,8),%rdx
  mov    %rbx,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  add    $0x1,%eax
  movsd  %xmm0,(%rdi)
  add    %rdx,%rdi
  cmp    %eax,%ebp
  jne    L8
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: f64

tool: D6: 1

assistant: ```c
void m_eye(double *A, int nrow, int ncol) {
  int i;
  m_set0(A, nrow, ncol);
  for (i = 0; i < nrow; i++)
    *(A + i * ncol + i) = 1.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<m_eye>:
  endbr64
  push   %r12
  movslq %edx,%r12
  push   %rbp
  mov    %r12d,%edx
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <m_set0@plt>
  test   %ebp,%ebp
  jle    L19
  movsd  D5(%rip),%xmm0
  lea    0x8(,%r12,8),%rdx
  mov    %rbx,%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L16:
  add    $0x1,%eax
  movsd  %xmm0,(%rdi)
  add    %rdx,%rdi
  cmp    %eax,%ebp
  jne    L16
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: f64

tool: D5: 1

assistant: ```c
void m_eye(double *A, int nrow, int ncol) {
  int i;
  m_set0(A, nrow, ncol);
  for (i = 0; i < nrow; i++)
    *(A + i * ncol + i) = 1.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findMin1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jne    L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  jmp    L53
L0:
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L54:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  je     L41
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L2
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L62
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L1
L62:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L54
  jmp    L43
L41:
  nop
L43:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int findMin1(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int l = 0, r = size - 1, m = 0;
  while (nums[l] >= nums[r]) {
    m = (l + r) >> 1;
    if (r - l == 1)
      break;
    if (nums[m] > nums[l])
      l = m;
    else if (nums[m] < nums[l])
      r = m;
    else
      l++;
  }
  return nums[l] > nums[r] ? nums[r] : nums[l];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findMin1>:
  endbr64
  lea    -0x1(%rsi),%r8d
  mov    $0x0,%ecx
  cmp    $0x1,%esi
  je     L14
L59:
  movslq %r8d,%rax
  mov    (%rdi,%rax,4),%r9d
L30:
  movslq %ecx,%rax
  mov    (%rdi,%rax,4),%eax
  cmp    %r9d,%eax
  jl     L39
  lea    (%r8,%rcx,1),%edx
  sar    %edx
  mov    %r8d,%esi
  sub    %ecx,%esi
  cmp    $0x1,%esi
  je     L39
  movslq %edx,%rsi
  mov    (%rdi,%rsi,4),%esi
  cmp    %eax,%esi
  jle    L24
  mov    %edx,%ecx
  jmp    L30
L14:
  mov    (%rdi),%eax
  ret
L24:
  jge    L44
  mov    %edx,%r8d
  jmp    L59
L44:
  add    $0x1,%ecx
  jmp    L59
L39:
  cmp    %r9d,%eax
  cmovg  %r9d,%eax
  ret
```

assistant: ```c
int findMin1(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int l = 0, r = size - 1, m = 0;
  while (nums[l] >= nums[r]) {
    m = (l + r) >> 1;
    if (r - l == 1)
      break;
    if (nums[m] > nums[l])
      l = m;
    else if (nums[m] < nums[l])
      r = m;
    else
      l++;
  }
  return nums[l] > nums[r] ? nums[r] : nums[l];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findMin1>:
  endbr64
  cmp    $0x1,%esi
  je     L31
  sub    $0x1,%esi
  xor    %r8d,%r8d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%eax
L15:
  movslq %r8d,%rdx
  mov    (%rdi,%rdx,4),%ecx
  jmp    L68
  nopl   (%rax)
L38:
  mov    %esi,%r9d
  lea    (%rsi,%r8,1),%edx
  sub    %r8d,%r9d
  sar    %edx
  cmp    $0x1,%r9d
  je     L19
  movslq %edx,%r9
  mov    (%rdi,%r9,4),%r9d
  cmp    %ecx,%r9d
  jle    L9
  mov    %r9d,%ecx
  mov    %edx,%r8d
L68:
  cmp    %ecx,%eax
  jle    L38
L19:
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  ret
  xchg   %ax,%ax
L9:
  jge    L79
  mov    %r9d,%eax
  mov    %edx,%esi
  jmp    L68
  nopl   0x0(%rax)
L31:
  mov    (%rdi),%eax
  ret
L79:
  add    $0x1,%r8d
  jmp    L15
```

assistant: ```c
int findMin1(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int l = 0, r = size - 1, m = 0;
  while (nums[l] >= nums[r]) {
    m = (l + r) >> 1;
    if (r - l == 1)
      break;
    if (nums[m] > nums[l])
      l = m;
    else if (nums[m] < nums[l])
      r = m;
    else
      l++;
  }
  return nums[l] > nums[r] ? nums[r] : nums[l];
}
```
user: What is the c source code of the assembly code below?

```asm
<findMin1>:
  endbr64
  cmp    $0x1,%esi
  je     L11
  sub    $0x1,%esi
  xor    %r8d,%r8d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%eax
L34:
  movslq %r8d,%rdx
  mov    (%rdi,%rdx,4),%ecx
  jmp    L61
  nopl   (%rax)
L79:
  mov    %esi,%r9d
  lea    (%rsi,%r8,1),%edx
  sub    %r8d,%r9d
  sar    %edx
  cmp    $0x1,%r9d
  je     L68
  movslq %edx,%r9
  mov    (%rdi,%r9,4),%r9d
  cmp    %ecx,%r9d
  jle    L62
  mov    %r9d,%ecx
  mov    %edx,%r8d
L61:
  cmp    %ecx,%eax
  jle    L79
L68:
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  ret
  xchg   %ax,%ax
L62:
  jge    L13
  mov    %r9d,%eax
  mov    %edx,%esi
  jmp    L61
  nopl   0x0(%rax)
L11:
  mov    (%rdi),%eax
  ret
L13:
  add    $0x1,%r8d
  jmp    L34
```

assistant: ```c
int findMin1(int *nums, int size) {
  if (size == 1)
    return nums[0];
  int l = 0, r = size - 1, m = 0;
  while (nums[l] >= nums[r]) {
    m = (l + r) >> 1;
    if (r - l == 1)
      break;
    if (nums[m] > nums[l])
      l = m;
    else if (nums[m] < nums[l])
      r = m;
    else
      l++;
  }
  return nums[l] > nums[r] ? nums[r] : nums[l];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fill_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L17:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <int_to_string@plt>
  mov    %rax,%rdi
  call   <print@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <readStr@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <str_to_int@plt>
  mov    %eax,(%rbx)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  addl   $0x1,-0x14(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string
name: extract_symbolic_data
arguments: data_label: D23
type: string
name: extract_symbolic_data
arguments: data_label: D11
type: string

tool: D1: ARR[

tool: D23: ]: 

tool: D11: 


assistant: ```c
void fill_array(int arr[], int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    print("ARR[");
    print(int_to_string(i));
    print("]: ");
    arr[i] = str_to_int(readStr());
    print("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fill_array>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D2(%rip),%r15
  lea    D16(%rip),%r14
  lea    D27(%rip),%r13
L3:
  mov    %r15,%rdi
  call   <print@plt>
  mov    %ebx,%edi
  call   <int_to_string@plt>
  mov    %rax,%rdi
  call   <print@plt>
  mov    %r14,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  call   <readStr@plt>
  mov    %eax,%edi
  call   <str_to_int@plt>
  mov    %eax,(%r12,%rbx,4)
  mov    %r13,%rdi
  call   <print@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D27
datatype: string

tool: D2: ARR[

tool: D16: ]: 

tool: D27: 


assistant: ```c
void fill_array(int arr[], int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    print("ARR[");
    print(int_to_string(i));
    print("]: ");
    arr[i] = str_to_int(readStr());
    print("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fill_array>:
  endbr64
  test   %esi,%esi
  jle    L2
  push   %r15
  lea    D3(%rip),%r15
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r15,%rdi
  call   <print@plt>
  mov    %ebx,%edi
  call   <int_to_string@plt>
  mov    %rax,%rdi
  call   <print@plt>
  mov    %r14,%rdi
  call   <print@plt>
  xor    %eax,%eax
  call   <readStr@plt>
  mov    %eax,%edi
  call   <str_to_int@plt>
  mov    %r13,%rdi
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  call   <print@plt>
  cmp    %rbp,%rbx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L2:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string

tool: D3: ARR[

tool: D13: ]: 

tool: D11: 


assistant: ```c
void fill_array(int arr[], int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    print("ARR[");
    print(int_to_string(i));
    print("]: ");
    arr[i] = str_to_int(readStr());
    print("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fill_array>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r15
  lea    D17(%rip),%r15
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r15,%rdi
  call   <print@plt>
  mov    %ebx,%edi
  call   <int_to_string@plt>
  mov    %rax,%rdi
  call   <print@plt>
  mov    %r14,%rdi
  call   <print@plt>
  xor    %eax,%eax
  call   <readStr@plt>
  mov    %eax,%edi
  call   <str_to_int@plt>
  mov    %r13,%rdi
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  call   <print@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D19
type_infered: string
name: disassemble_data
arguments: label: D18
type_infered: string

tool: D17: ARR[

tool: D19: ]: 

tool: D18: 


assistant: ```c
void fill_array(int arr[], int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    print("ARR[");
    print(int_to_string(i));
    print("]: ");
    arr[i] = str_to_int(readStr());
    print("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sun_RA_dec>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movq   %xmm0,%rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rdi
  mov    %rdx,%rsi
  mov    $0x1,%eax
  call   <sunpos@plt>
  mov    0x0(%r13),%r15
  lea    0x18(%rsp),%r13
  lea    0x10(%rsp),%r14
  movsd  D56(%rip),%xmm0
  mulsd  0x20(%rsp),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movq   %r15,%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  %xmm1,(%rsp)
  movq   %r15,%xmm3
  mulsd  0x18(%rsp),%xmm3
  movq   %xmm3,%r15
  movq   %rbx,%xmm4
  mulsd  D43(%rip),%xmm4
  movsd  D17(%rip),%xmm0
  subsd  %xmm4,%xmm0
  mulsd  D56(%rip),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <sincos@plt>
  movq   %r15,%xmm2
  mulsd  0x10(%rsp),%xmm2
  movq   %r15,%xmm5
  mulsd  0x18(%rsp),%xmm5
  movq   %xmm5,%rbx
  movsd  (%rsp),%xmm1
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <atan2@plt>
  mulsd  D48(%rip),%xmm0
  movsd  %xmm0,(%r12)
  movsd  (%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L25
  sqrtsd %xmm1,%xmm1
L14:
  movq   %rbx,%xmm0
  call   <atan2@plt>
  mulsd  D48(%rip),%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm1
  jmp    L14
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D56
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D43
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D17
type_guessed: f64
name: disassemble_data
arguments: data_label: D48
type_guessed: byte[8]

tool: {"D56": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D43": [0xda,0xda,0xce,0xf8,0x2f,0xe9,0x97,0x3e]}

tool: D17: 23.4393

tool: {"D48": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
void sun_RA_dec(double d, double *RA, double *dec, double *r) {
  double lon, obl_ecl;
  double xs, ys, zs;
  double xe, ye, ze;
  sunpos(d, &lon, r);
  xs = *r * cos((lon) * (3.1415926535897932384 / 180.0));
  ys = *r * sin((lon) * (3.1415926535897932384 / 180.0));
  zs = 0;
  obl_ecl = 23.4393 - 3.563E-7 * d;
  xe = xs;
  ye = ys * cos((obl_ecl) * (3.1415926535897932384 / 180.0));
  ze = ys * sin((obl_ecl) * (3.1415926535897932384 / 180.0));
  *RA = ((180.0 / 3.1415926535897932384) * atan2(ye, xe));
  *dec = ((180.0 / 3.1415926535897932384) * atan2(ze, sqrt(xe * xe + ye * ye)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sun_RA_dec>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rdi
  mov    $0x1,%eax
  movsd  %xmm0,0x18(%rsp)
  call   <sunpos@plt>
  lea    0x20(%rsp),%r13
  movsd  0x0(%rbp),%xmm2
  movsd  D34(%rip),%xmm0
  mulsd  0x30(%rsp),%xmm0
  lea    0x28(%rsp),%rbp
  mov    %r13,%rsi
  mov    %rbp,%rdi
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x18(%rsp),%xmm3
  mov    %r13,%rsi
  movsd  0x8(%rsp),%xmm2
  mulsd  D32(%rip),%xmm3
  movsd  0x20(%rsp),%xmm1
  mov    %rbp,%rdi
  movsd  D18(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  0x28(%rsp),%xmm2
  subsd  %xmm3,%xmm0
  mulsd  D34(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm1
  mulsd  %xmm2,%xmm3
  mulsd  0x28(%rsp),%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm2,0x18(%rsp)
  call   <atan2@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  mulsd  D9(%rip),%xmm0
  movsd  0x18(%rsp),%xmm2
  mulsd  %xmm1,%xmm1
  mulsd  %xmm3,%xmm3
  movsd  %xmm0,(%r12)
  pxor   %xmm0,%xmm0
  addsd  %xmm3,%xmm1
  ucomisd %xmm1,%xmm0
  ja     L7
  sqrtsd %xmm1,%xmm1
L8:
  movapd %xmm2,%xmm0
  call   <atan2@plt>
  mulsd  D9(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm2
  movapd %xmm0,%xmm1
  jmp    L8
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D34
datatype: byte[8]
name: parse_data
arguments: tag: D32
datatype: byte[8]
name: parse_data
arguments: tag: D18
datatype: f64
name: parse_data
arguments: tag: D9
datatype: byte[8]

tool: {"D34": [0x39,0x9d,0x52,0xa2,0x46,0xdf,0x91,0x3f]}

tool: {"D32": [0xda,0xda,0xce,0xf8,0x2f,0xe9,0x97,0x3e]}

tool: D18: 23.4393

tool: {"D9": [0xf8,0xc1,0x63,0x1a,0xdc,0xa5,0x4c,0x40]}

assistant: ```c
void sun_RA_dec(double d, double *RA, double *dec, double *r) {
  double lon, obl_ecl;
  double xs, ys, zs;
  double xe, ye, ze;
  sunpos(d, &lon, r);
  xs = *r * cos((lon) * (3.1415926535897932384 / 180.0));
  ys = *r * sin((lon) * (3.1415926535897932384 / 180.0));
  zs = 0;
  obl_ecl = 23.4393 - 3.563E-7 * d;
  xe = xs;
  ye = ys * cos((obl_ecl) * (3.1415926535897932384 / 180.0));
  ze = ys * sin((obl_ecl) * (3.1415926535897932384 / 180.0));
  *RA = ((180.0 / 3.1415926535897932384) * atan2(ye, xe));
  *dec = ((180.0 / 3.1415926535897932384) * atan2(ze, sqrt(xe * xe + ye * ye)));
}
```