ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<convert_time>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  sub    $0x38,%rsp
  mov    %edi,0xc(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <localtime_r@plt>
  mov    0x10(%rsp),%eax
  mov    %ebp,%esi
  mov    %r12,%rdi
  lea    D4(%rip),%rdx
  lea    0x76c(%rax),%ecx
  mov    0x20(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  mov    0x28(%rsp),%r9d
  lea    0x1(%rax),%r8d
  call   <snprintf@plt>
  pop    %rax
  pop    %rdx
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: %d-%02d-%02d %02d:%02d

assistant: ```c
char *convert_time(const time_t t, char *out_buf, int out_buf_size) {
  struct tm tm;
  localtime_r(&t, &tm);
  snprintf(out_buf, out_buf_size, "%d-%02d-%02d %02d:%02d", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min);
  return out_buf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str_trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L11
L19:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jle    L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L19
  jmp    L17
L10:
  addq   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jle    L50
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L10
L50:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_trim(char *s) {
  char *t;
  t = s + str_len(s);
  *t-- = '\0';
  while ((*t > 0 && *t < 33) ? 1 : 0)
    *t-- = '\0';
  while ((*s > 0 && *s < 33) ? 1 : 0)
    s++;
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<str_trim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <str_len@plt>
  cltq
  add    %rbx,%rax
  lea    -0x1(%rax),%rdx
  movb   $0x0,(%rax)
  movzbl -0x1(%rax),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L10
L26:
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  movzbl (%rdx),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L26
L10:
  movzbl (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L21
L2:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L2
L21:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *str_trim(char *s) {
  char *t;
  t = s + str_len(s);
  *t-- = '\0';
  while ((*t > 0 && *t < 33) ? 1 : 0)
    *t-- = '\0';
  while ((*s > 0 && *s < 33) ? 1 : 0)
    s++;
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <str_len@plt>
  cltq
  add    %r12,%rax
  movb   $0x0,(%rax)
  lea    -0x1(%rax),%rdx
  movzbl -0x1(%rax),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L7
  nopl   (%rax)
L2:
  movzbl -0x1(%rdx),%eax
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L2
  movzbl (%r12),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L15
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12
L7:
  movzbl (%r12),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L18
L15:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *str_trim(char *s) {
  char *t;
  t = s + str_len(s);
  *t-- = '\0';
  while ((*t > 0 && *t < 33) ? 1 : 0)
    *t-- = '\0';
  while ((*s > 0 && *s < 33) ? 1 : 0)
    s++;
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <str_len@plt>
  cltq
  add    %r12,%rax
  movb   $0x0,(%rax)
  lea    -0x1(%rax),%rdx
  movzbl -0x1(%rax),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L9
  nopl   (%rax)
L28:
  movzbl -0x1(%rdx),%eax
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L28
  movzbl (%r12),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  ja     L32
  nopw   0x0(%rax,%rax,1)
L16:
  add    $0x1,%r12
L9:
  movzbl (%r12),%eax
  sub    $0x1,%eax
  cmp    $0x1f,%al
  jbe    L16
L32:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *str_trim(char *s) {
  char *t;
  t = s + str_len(s);
  *t-- = '\0';
  while ((*t > 0 && *t < 33) ? 1 : 0)
    *t-- = '\0';
  while ((*s > 0 && *s < 33) ? 1 : 0)
    s++;
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x2a,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  long hash = 42;
  int i = 0;
  while (i < strlen(word)) {
    hash = hash + word[i] * (i + 1);
    i++;
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x2a,%r12d
  jmp    L3
L11:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
  add    $0x1,%rbx
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L11
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long hash = 42;
  int i = 0;
  while (i < strlen(word)) {
    hash = hash + word[i] * (i + 1);
    i++;
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L8
  nopl   (%rax)
L12:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long hash = 42;
  int i = 0;
  while (i < strlen(word)) {
    hash = hash + word[i] * (i + 1);
    i++;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash>:
  endbr64
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L3
  nopl   (%rax)
L0:
  movsbl 0x0(%rbp,%rbx,1),%eax
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  imul   %edx,%eax
  cltq
  add    %rax,%r12
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long hash(char *word) {
  long hash = 42;
  int i = 0;
  while (i < strlen(word)) {
    hash = hash + word[i] * (i + 1);
    i++;
  }
  return hash;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_is_bit_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x82,-0x8(%rbp)
  movzbl -0x8(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_byte@plt>
  mov    %al,-0x7(%rbp)
  cmpb   $0x0,-0x7(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_byte@plt>
  mov    %al,-0x7(%rbp)
  movzbl -0x7(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzbl -0x8(%rbp),%eax
  mov    $0x7,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_byte@plt>
  mov    %al,-0x7(%rbp)
  movzbl -0x7(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  movw   $0x8000,-0x6(%rbp)
  movzwl -0x6(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_word@plt>
  mov    %al,-0x7(%rbp)
  cmpb   $0x0,-0x7(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movzwl -0x6(%rbp),%eax
  mov    $0xf,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_word@plt>
  mov    %al,-0x7(%rbp)
  movzbl -0x7(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x80000001,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_dword@plt>
  mov    %al,-0x7(%rbp)
  movzbl -0x7(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    $0xf,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_dword@plt>
  mov    %al,-0x7(%rbp)
  cmpb   $0x0,-0x7(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1f,%esi
  mov    %eax,%edi
  call   <memory_get_bit_from_dword@plt>
  mov    %al,-0x7(%rbp)
  movzbl -0x7(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_is_bit_set(void) {
  unsigned char test_case = (unsigned char)0b10000010;
  unsigned char is_bit_set = memory_get_bit_from_byte(test_case, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 1);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 7);
  assert(is_bit_set);
  unsigned short instruction = 0b1000000000000000;
  is_bit_set = memory_get_bit_from_word(instruction, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_word(instruction, 15);
  assert(is_bit_set);
  unsigned int instruction32 = 0b10000000000000000000000000000001;
  is_bit_set = memory_get_bit_from_dword(instruction32, 0);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 15);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 31);
  assert(is_bit_set);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_is_bit_set>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  test   %al,%al
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0x7,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0x0,%esi
  mov    $0x8000,%edi
  call   <memory_get_bit_from_word@plt>
  test   %al,%al
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xf,%esi
  mov    $0x8000,%edi
  call   <memory_get_bit_from_word@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0x0,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0xf,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  test   %al,%al
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1f,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  movzbl %al,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_is_bit_set(void) {
  unsigned char test_case = (unsigned char)0b10000010;
  unsigned char is_bit_set = memory_get_bit_from_byte(test_case, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 1);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 7);
  assert(is_bit_set);
  unsigned short instruction = 0b1000000000000000;
  is_bit_set = memory_get_bit_from_word(instruction, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_word(instruction, 15);
  assert(is_bit_set);
  unsigned int instruction32 = 0b10000000000000000000000000000001;
  is_bit_set = memory_get_bit_from_dword(instruction32, 0);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 15);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 31);
  assert(is_bit_set);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_is_bit_set>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  xor    %edi,%edi
  test   %al,%al
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0x7,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  movzbl %al,%edi
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0x8000,%edi
  call   <memory_get_bit_from_word@plt>
  xor    %edi,%edi
  test   %al,%al
  sete   %dil
  call   <assert@plt>
  mov    $0xf,%esi
  mov    $0x8000,%edi
  call   <memory_get_bit_from_word@plt>
  movzbl %al,%edi
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0xf,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  xor    %edi,%edi
  test   %al,%al
  sete   %dil
  call   <assert@plt>
  mov    $0x80000001,%edi
  mov    $0x1f,%esi
  call   <memory_get_bit_from_dword@plt>
  add    $0x8,%rsp
  movzbl %al,%edi
  jmp    1090 <assert@plt>
```

assistant: ```c
void test_is_bit_set(void) {
  unsigned char test_case = (unsigned char)0b10000010;
  unsigned char is_bit_set = memory_get_bit_from_byte(test_case, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 1);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 7);
  assert(is_bit_set);
  unsigned short instruction = 0b1000000000000000;
  is_bit_set = memory_get_bit_from_word(instruction, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_word(instruction, 15);
  assert(is_bit_set);
  unsigned int instruction32 = 0b10000000000000000000000000000001;
  is_bit_set = memory_get_bit_from_dword(instruction32, 0);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 15);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 31);
  assert(is_bit_set);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_is_bit_set>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  xor    %edi,%edi
  test   %al,%al
  sete   %dil
  call   <assert@plt>
  mov    $0x1,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0x7,%esi
  mov    $0x82,%edi
  call   <memory_get_bit_from_byte@plt>
  movzbl %al,%edi
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0x8000,%edi
  call   <memory_get_bit_from_word@plt>
  xor    %edi,%edi
  test   %al,%al
  sete   %dil
  call   <assert@plt>
  mov    $0xf,%esi
  mov    $0x8000,%edi
  call   <memory_get_bit_from_word@plt>
  movzbl %al,%edi
  call   <assert@plt>
  xor    %esi,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  movzbl %al,%edi
  call   <assert@plt>
  mov    $0xf,%esi
  mov    $0x80000001,%edi
  call   <memory_get_bit_from_dword@plt>
  xor    %edi,%edi
  test   %al,%al
  sete   %dil
  call   <assert@plt>
  mov    $0x80000001,%edi
  mov    $0x1f,%esi
  call   <memory_get_bit_from_dword@plt>
  add    $0x8,%rsp
  movzbl %al,%edi
  jmp    1090 <assert@plt>
```

assistant: ```c
void test_is_bit_set(void) {
  unsigned char test_case = (unsigned char)0b10000010;
  unsigned char is_bit_set = memory_get_bit_from_byte(test_case, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 1);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_byte(test_case, 7);
  assert(is_bit_set);
  unsigned short instruction = 0b1000000000000000;
  is_bit_set = memory_get_bit_from_word(instruction, 0);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_word(instruction, 15);
  assert(is_bit_set);
  unsigned int instruction32 = 0b10000000000000000000000000000001;
  is_bit_set = memory_get_bit_from_dword(instruction32, 0);
  assert(is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 15);
  assert(!is_bit_set);
  is_bit_set = memory_get_bit_from_dword(instruction32, 31);
  assert(is_bit_set);
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_till_prefix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L21
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L21:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgets@plt>
  cmp    %rax,-0x20(%rbp)
  je     L10
L13:
  cmpl   $0x0,-0xc(%rbp)
  jne    L49
  mov    $0xffffffff,%eax
  jmp    L47
L49:
  mov    $0x0,%eax
L47:
  leave
  ret
```

assistant: ```c
int skip_till_prefix(FILE *f, char *line, size_t line_len, char *prefix) {
  int found = 0;
  size_t prefix_len = strlen(prefix);
  do {
    if (!strncmp(prefix, line, prefix_len)) {
      found = 1;
      break;
    }
  } while (line == fgets(line, line_len, f));
  if (!found) {
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<skip_till_prefix>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
L13:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L8
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <fgets@plt>
  cmp    %rax,%rbx
  je     L13
  mov    $0x0,%eax
  jmp    L10
L8:
  mov    $0x1,%eax
L10:
  sub    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int skip_till_prefix(FILE *f, char *line, size_t line_len, char *prefix) {
  int found = 0;
  size_t prefix_len = strlen(prefix);
  do {
    if (!strncmp(prefix, line, prefix_len)) {
      found = 1;
      break;
    }
  } while (line == fgets(line, line_len, f));
  if (!found) {
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<skip_till_prefix>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rcx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  jmp    L8
  nopl   (%rax)
L3:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <fgets@plt>
  cmp    %rax,%r14
  jne    L13
L8:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int skip_till_prefix(FILE *f, char *line, size_t line_len, char *prefix) {
  int found = 0;
  size_t prefix_len = strlen(prefix);
  do {
    if (!strncmp(prefix, line, prefix_len)) {
      found = 1;
      break;
    }
  } while (line == fgets(line, line_len, f));
  if (!found) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skip_till_prefix>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  mov    %rcx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  jmp    L29
  nopl   (%rax)
L22:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <fgets@plt>
  cmp    %rax,%r14
  jne    L11
L29:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int skip_till_prefix(FILE *f, char *line, size_t line_len, char *prefix) {
  int found = 0;
  size_t prefix_len = strlen(prefix);
  do {
    if (!strncmp(prefix, line, prefix_len)) {
      found = 1;
      break;
    }
  } while (line == fgets(line, line_len, f));
  if (!found) {
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void square(int *N, double *x) {
  int n = *N;
  int i = (int)n;
  for (i = 0; i < n; ++i) {
    x[i] = x[i] * x[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<square>:
  endbr64
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L16
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
L17:
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L17
L16:
  ret
```

assistant: ```c
void square(int *N, double *x) {
  int n = *N;
  int i = (int)n;
  for (i = 0; i < n; ++i) {
    x[i] = x[i] * x[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<square>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  jle    L7
  sub    $0x1,%eax
  lea    0x8(%rsi,%rax,8),%rax
  nopw   0x0(%rax,%rax,1)
L9:
  movsd  (%rsi),%xmm0
  add    $0x8,%rsi
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rax,%rsi
  jne    L9
L7:
  ret
```

assistant: ```c
void square(int *N, double *x) {
  int n = *N;
  int i = (int)n;
  for (i = 0; i < n; ++i) {
    x[i] = x[i] * x[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<square>:
  endbr64
  mov    (%rdi),%ecx
  test   %ecx,%ecx
  jle    L41
  cmp    $0x1,%ecx
  je     L7
  mov    %ecx,%edx
  mov    %rsi,%rax
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L4:
  movupd (%rax),%xmm0
  add    $0x10,%rax
  mulpd  %xmm0,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L4
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L42
L2:
  cltq
  lea    (%rsi,%rax,8),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
L41:
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  ret
L7:
  xor    %eax,%eax
  jmp    L2
```

assistant: ```c
void square(int *N, double *x) {
  int n = *N;
  int i = (int)n;
  for (i = 0; i < n; ++i) {
    x[i] = x[i] * x[i];
  }
}
```