ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<getDelimOrCommand>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  movb   $0x0,(%rdi)
  mov    $0x5c,%edi
  call   <ungetTexChar@plt>
  xor    %eax,%eax
  call   <getSimpleCommand@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  je     L13
L68:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L35
  lea    D59(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L37
L73:
  movb   $0x7b,0x0(%rbp)
L41:
  mov    (%rbx),%rdi
  lea    D53(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L103
L128:
  movb   $0x7d,0x0(%rbp)
L19:
  mov    (%rbx),%rdi
  lea    D41(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L118
  movb   $0x7c,0x0(%rbp)
L118:
  mov    (%rbx),%rdi
  lea    D6(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L55
  movb   $0x3c,0x0(%rbp)
L55:
  mov    (%rbx),%rdi
  lea    D28(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L30
  movb   $0x3e,0x0(%rbp)
L115:
  mov    (%rbx),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  cmpb   $0x0,0x0(%rbp)
  jne    L115
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movb   $0x5c,(%rax)
  xor    %eax,%eax
  mov    (%rbx),%r12
  call   <getTexChar@plt>
  mov    %al,0x1(%r12)
  mov    (%rbx),%rax
  movb   $0x0,0x2(%rax)
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rbx),%rdi
  lea    D47(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L73
  jmp    L41
  nopl   (%rax)
L103:
  mov    (%rbx),%rdi
  lea    D32(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L128
  jmp    L19
```

tool_calls: name: parse_data
arguments: label: D59
datatype: string
name: parse_data
arguments: label: D53
datatype: string
name: parse_data
arguments: label: D41
datatype: string
name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D28
datatype: string
name: parse_data
arguments: label: D47
datatype: string
name: parse_data
arguments: label: D32
datatype: string

tool: D59: \{

tool: D53: \}

tool: D41: \bracevert

tool: D6: \langle

tool: D28: \rangle

tool: D47: \lbrace

tool: D32: \rbrace

assistant: ```c
void getDelimOrCommand(char *delim, char **s) {
  *delim = '\0';
  ungetTexChar('\\');
  *s = getSimpleCommand();
  if (strlen(*s) == 1) {
    free(*s);
    *s = (char *)malloc(3 * sizeof(char));
    (*s)[0] = '\\';
    (*s)[1] = getTexChar();
    (*s)[2] = '\0';
  }
  if (*s) {
    if (strcmp(*s, "\\{") == 0 || strcmp(*s, "\\lbrace") == 0)
      *delim = '{';
    if (strcmp(*s, "\\}") == 0 || strcmp(*s, "\\rbrace") == 0)
      *delim = '}';
    if (strcmp(*s, "\\bracevert") == 0)
      *delim = '|';
    if (strcmp(*s, "\\langle") == 0)
      *delim = '<';
    if (strcmp(*s, "\\rangle") == 0) {
      *delim = '>';
    }
    if (*delim) {
      free(*s);
      *s = NULL;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Utils_clean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void Utils_clean(char *string) {
  char *temp = &string[strlen(string) - 1];
  temp[0] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Utils_clean>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void Utils_clean(char *string) {
  char *temp = &string[strlen(string) - 1];
  temp[0] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Utils_clean>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void Utils_clean(char *string) {
  char *temp = &string[strlen(string) - 1];
  temp[0] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Utils_clean>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void Utils_clean(char *string) {
  char *temp = &string[strlen(string) - 1];
  temp[0] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xc,-0xc(%rbp)
  movl   $0xd,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, b, a;
  a = 12;
  b = 13;
  i = b = a + a + b + b * a;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0xc1,%eax
  ret
```

assistant: ```c
int main() {
  int i, b, a;
  a = 12;
  b = 13;
  i = b = a + a + b + b * a;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0xc1,%eax
  ret
```

assistant: ```c
int main() {
  int i, b, a;
  a = 12;
  b = 13;
  i = b = a + a + b + b * a;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0xc1,%eax
  ret
```

assistant: ```c
int main() {
  int i, b, a;
  a = 12;
  b = 13;
  i = b = a + a + b + b * a;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<range_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L126
  addq   $0x1,-0x18(%rbp)
  jmp    L126
L12:
  cmpb   $0x0,-0xa(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L96
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L101
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  je     L101
  cmpb   $0x5d,-0x9(%rbp)
  je     L101
  movsbl -0xa(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L124
  movsbl -0x9(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L124
  movl   $0x1,-0x8(%rbp)
L124:
  addq   $0x2,-0x18(%rbp)
  jmp    L126
L101:
  movsbl -0xa(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L126
  movl   $0x1,-0x8(%rbp)
L126:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  cmpb   $0x5d,-0xa(%rbp)
  jne    L12
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L100
  mov    -0x18(%rbp),%rax
  jmp    L96
L100:
  mov    $0x0,%eax
L96:
  pop    %rbp
  ret
```

assistant: ```c
char *range_match(char *pattern, int test) {
  char c;
  char c2;
  int negate;
  int ok = 0;
  if ((negate = (*pattern == '!')) != 0)
    ++pattern;
  while ((c = *pattern++) != ']') {
    if (c == '\0')
      return (NULL);
    if ((*pattern == '-') && ((c2 = pattern[1]) != '\0') && (c2 != ']')) {
      if ((c <= test) && (test <= c2))
        ok = 1;
      pattern += 2;
    } else if (c == test)
      ok = 1;
  }
  return (ok == negate ? NULL : pattern);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<range_match>:
  endbr64
  movzbl (%rdi),%r10d
  cmp    $0x21,%r10b
  je     L129
  lea    0x1(%rdi),%rdx
  mov    %r10d,%eax
  cmp    $0x5d,%r10b
  je     L9
L47:
  mov    $0x0,%ecx
  mov    $0x1,%r9d
  jmp    L46
L129:
  lea    0x1(%rdi),%rcx
  lea    0x2(%rdi),%rdx
  movzbl 0x1(%rdi),%eax
  cmp    $0x5d,%al
  je     L38
  mov    %rcx,%rdi
  jmp    L47
L112:
  movsbl %al,%eax
  mov    %rdx,%rdi
  cmp    %esi,%eax
  cmove  %r9d,%ecx
L101:
  lea    0x1(%rdi),%rdx
  movzbl (%rdi),%eax
  cmp    $0x5d,%al
  je     L49
L46:
  test   %al,%al
  je     L130
  cmpb   $0x2d,0x1(%rdi)
  jne    L112
  movzbl 0x2(%rdi),%r8d
  cmp    $0x5d,%r8b
  je     L112
  test   %r8b,%r8b
  je     L112
  movsbl %al,%eax
  cmp    %esi,%eax
  jg     L77
  movsbl %r8b,%r8d
  cmp    %esi,%r8d
  cmovge %r9d,%ecx
L77:
  add    $0x3,%rdi
  jmp    L101
L49:
  cmp    $0x21,%r10b
  sete   %al
  movzbl %al,%eax
  cmp    %eax,%ecx
  mov    $0x0,%eax
  cmove  %rax,%rdx
  jmp    L38
L130:
  mov    $0x0,%edx
L38:
  mov    %rdx,%rax
  ret
L9:
  mov    $0x0,%edx
  jmp    L38
```

assistant: ```c
char *range_match(char *pattern, int test) {
  char c;
  char c2;
  int negate;
  int ok = 0;
  if ((negate = (*pattern == '!')) != 0)
    ++pattern;
  while ((c = *pattern++) != ']') {
    if (c == '\0')
      return (NULL);
    if ((*pattern == '-') && ((c2 = pattern[1]) != '\0') && (c2 != ']')) {
      if ((c <= test) && (test <= c2))
        ok = 1;
      pattern += 2;
    } else if (c == test)
      ok = 1;
  }
  return (ok == negate ? NULL : pattern);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<range_match>:
  endbr64
  movzbl (%rdi),%r10d
  lea    0x1(%rdi),%r8
  cmp    $0x21,%r10b
  je     L9
  movsbl %r10b,%eax
  cmp    $0x5d,%r10b
  je     L115
L58:
  xor    %edx,%edx
  mov    $0x1,%r9d
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r8,%rdi
  cmp    %eax,%esi
  movsbl (%rdi),%eax
  cmove  %r9d,%edx
  lea    0x1(%rdi),%r8
  cmp    $0x5d,%al
  je     L129
L39:
  test   %al,%al
  je     L115
  cmpb   $0x2d,0x1(%rdi)
  jne    L27
  movsbl 0x2(%rdi),%ecx
  cmp    $0x5d,%cl
  je     L27
  test   %cl,%cl
  je     L27
  cmp    %eax,%esi
  jl     L107
  cmp    %esi,%ecx
  cmovge %r9d,%edx
L107:
  movsbl 0x3(%rdi),%eax
  add    $0x3,%rdi
  lea    0x1(%rdi),%r8
  cmp    $0x5d,%al
  jne    L39
L129:
  xor    %eax,%eax
  cmp    $0x21,%r10b
  sete   %al
  cmp    %eax,%edx
  mov    $0x0,%eax
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
  nopl   (%rax)
L115:
  xor    %r8d,%r8d
L89:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movsbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rdx
  cmp    $0x5d,%al
  je     L88
  mov    %r8,%rdi
  mov    %rdx,%r8
  jmp    L58
L88:
  mov    %rdx,%r8
  jmp    L89
```

assistant: ```c
char *range_match(char *pattern, int test) {
  char c;
  char c2;
  int negate;
  int ok = 0;
  if ((negate = (*pattern == '!')) != 0)
    ++pattern;
  while ((c = *pattern++) != ']') {
    if (c == '\0')
      return (NULL);
    if ((*pattern == '-') && ((c2 = pattern[1]) != '\0') && (c2 != ']')) {
      if ((c <= test) && (test <= c2))
        ok = 1;
      pattern += 2;
    } else if (c == test)
      ok = 1;
  }
  return (ok == negate ? NULL : pattern);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<range_match>:
  endbr64
  movzbl (%rdi),%r10d
  lea    0x1(%rdi),%r8
  cmp    $0x21,%r10b
  je     L36
  movsbl %r10b,%eax
  cmp    $0x5d,%r10b
  je     L80
L68:
  xor    %edx,%edx
  mov    $0x1,%r9d
  jmp    L117
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %r8,%rdi
  cmp    %eax,%esi
  movsbl (%rdi),%eax
  cmove  %r9d,%edx
  lea    0x1(%rdi),%r8
  cmp    $0x5d,%al
  je     L121
L117:
  test   %al,%al
  je     L80
  cmpb   $0x2d,0x1(%rdi)
  jne    L62
  movsbl 0x2(%rdi),%ecx
  cmp    $0x5d,%cl
  je     L62
  test   %cl,%cl
  je     L62
  cmp    %eax,%esi
  jl     L127
  cmp    %esi,%ecx
  cmovge %r9d,%edx
L127:
  movsbl 0x3(%rdi),%eax
  add    $0x3,%rdi
  lea    0x1(%rdi),%r8
  cmp    $0x5d,%al
  jne    L117
L121:
  xor    %eax,%eax
  cmp    $0x21,%r10b
  sete   %al
  cmp    %eax,%edx
  mov    $0x0,%eax
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
  nopl   (%rax)
L80:
  xor    %r8d,%r8d
L7:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  movsbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rdx
  cmp    $0x5d,%al
  je     L104
  mov    %r8,%rdi
  mov    %rdx,%r8
  jmp    L68
L104:
  mov    %rdx,%r8
  jmp    L7
```

assistant: ```c
char *range_match(char *pattern, int test) {
  char c;
  char c2;
  int negate;
  int ok = 0;
  if ((negate = (*pattern == '!')) != 0)
    ++pattern;
  while ((c = *pattern++) != ']') {
    if (c == '\0')
      return (NULL);
    if ((*pattern == '-') && ((c2 = pattern[1]) != '\0') && (c2 != ']')) {
      if ((c <= test) && (test <= c2))
        ok = 1;
      pattern += 2;
    } else if (c == test)
      ok = 1;
  }
  return (ok == negate ? NULL : pattern);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<word>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x114(%rbp)
  jmp    L47
L6:
  mov    -0x128(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x128(%rbp)
  mov    -0x114(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x114(%rbp)
  movzbl (%rax),%ecx
  movslq %edx,%rax
  mov    %cl,-0x110(%rbp,%rax,1)
L47:
  mov    -0x128(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L6
  mov    -0x114(%rbp),%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  cmpl   $0x0,-0x114(%rbp)
  jle    L35
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %eax,%edx
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <strcpy@plt>
  mov    -0x130(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L38
L35:
  mov    -0x130(%rbp),%rax
  movq   $0x0,(%rax)
L38:
  mov    -0x128(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
char *word(char *p, char **s) {
  char buf[256];
  int i = 0;
  while (*p > ' ')
    buf[i++] = *p++;
  buf[i] = '\0';
  if (i > 0)
    *s = strcpy(xmalloc(strlen(buf) + 1), (buf));
  else
    *s = NULL;
  return (p);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<word>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  jle    L9
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rsi
L38:
  add    $0x1,%rbx
  mov    %eax,%ecx
  mov    %dl,(%rsi,%rax,1)
  movzbl (%rbx),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jg     L38
  movslq %ecx,%rax
  movb   $0x0,(%rsp,%rax,1)
  test   %ecx,%ecx
  jg     L22
L9:
  mov    %rbx,%rax
  mov    $0x0,%edx
L20:
  mov    %rdx,0x0(%rbp)
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %eax,%edi
  mov    %r12,%rsi
  call   <strcpy@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  jmp    L20
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *word(char *p, char **s) {
  char buf[256];
  int i = 0;
  while (*p > ' ')
    buf[i++] = *p++;
  buf[i] = '\0';
  if (i > 0)
    *s = strcpy(xmalloc(strlen(buf) + 1), (buf));
  else
    *s = NULL;
  return (p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<word>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x110,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%dl
  jle    L17
  mov    $0x1,%eax
  mov    %rsp,%rbp
  lea    -0x1(%rsp),%rsi
  nopl   (%rax)
L34:
  add    $0x1,%r12
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl (%r12),%edx
  cmp    $0x20,%dl
  jg     L34
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcpy@plt>
L27:
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  jmp    L27
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *word(char *p, char **s) {
  char buf[256];
  int i = 0;
  while (*p > ' ')
    buf[i++] = *p++;
  buf[i] = '\0';
  if (i > 0)
    *s = strcpy(xmalloc(strlen(buf) + 1), (buf));
  else
    *s = NULL;
  return (p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<word>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x110,%rsp
  movzbl (%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%dl
  jle    L32
  mov    $0x1,%eax
  mov    %rsp,%rbp
  lea    -0x1(%rsp),%rsi
  nopl   (%rax)
L26:
  add    $0x1,%r12
  mov    %dl,(%rsi,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl (%r12),%edx
  cmp    $0x20,%dl
  jg     L26
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rcx,1)
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <xmalloc@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <strcpy@plt>
L9:
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  jmp    L9
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *word(char *p, char **s) {
  char buf[256];
  int i = 0;
  while (*p > ' ')
    buf[i++] = *p++;
  buf[i] = '\0';
  if (i > 0)
    *s = strcpy(xmalloc(strlen(buf) + 1), (buf));
  else
    *s = NULL;
  return (p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <bi_input@plt>
  mov    %eax,-0x68(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <bi_input@plt>
  mov    %eax,-0x64(%rbp)
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x6c(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x6c(%rbp),%edx
  mov    -0x70(%rbp),%esi
  mov    -0x64(%rbp),%ecx
  mov    -0x68(%rbp),%eax
  mov    %eax,%edi
  call   <setbit@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x6c(%rbp),%edx
  mov    -0x70(%rbp),%esi
  mov    -0x64(%rbp),%ecx
  mov    -0x68(%rbp),%eax
  mov    %eax,%edi
  call   <setbit@plt>
  mov    %eax,%edx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <to2@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D21
type: string
name: unpack_data
arguments: data_tag: D8
type: string
name: unpack_data
arguments: data_tag: D41
type: string
name: unpack_data
arguments: data_tag: D4
type: string
name: unpack_data
arguments: data_tag: D18
type: string
name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D57
type: string

tool: D16: input x:

tool: D21: %s

tool: D8: input y:

tool: D41: input is %d(%s)


tool: D4: p=? n=?

tool: D18: %d %d

tool: D22: The result is %d


tool: D57: result in binumber:

assistant: ```c
main() {
  char s[20];
  char c[20];
  char d[20];
  int x, y;
  int p, n;
  printf("input x:");
  scanf("%s", s);
  x = bi_input(s);
  printf("input y:");
  scanf("%s", c);
  y = bi_input(c);
  printf("input is %d(%s)\n", x, s);
  printf("input is %d(%s)\n", y, c);
  printf("p=? n=?\n");
  scanf("%d %d", &p, &n);
  printf("The result is %d\n", setbit(x, p, n, y));
  printf("result in binumber:");
  to2(setbit(x, p, n, y), d);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%r13
  mov    %r13,%rsi
  lea    D76(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rdi
  call   <bi_input@plt>
  mov    %eax,%ebx
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x30(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r12,%rdi
  call   <bi_input@plt>
  mov    %eax,%ebp
  mov    %r13,%rdx
  mov    %ebx,%esi
  lea    D28(%rip),%r13
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D72(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %ebp,%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %ebx,%edi
  call   <setbit@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D61(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %ebx,%edi
  call   <setbit@plt>
  mov    %eax,%edi
  lea    0x50(%rsp),%rsi
  call   <to2@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D12
type_guessed: string
name: read_data
arguments: tag: D76
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D72
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D61
type_guessed: string

tool: D12: input x:

tool: D76: %s

tool: D16: input y:

tool: D28: input is %d(%s)


tool: D23: p=? n=?

tool: D72: %d %d

tool: D19: The result is %d


tool: D61: result in binumber:

assistant: ```c
main() {
  char s[20];
  char c[20];
  char d[20];
  int x, y;
  int p, n;
  printf("input x:");
  scanf("%s", s);
  x = bi_input(s);
  printf("input y:");
  scanf("%s", c);
  y = bi_input(c);
  printf("input is %d(%s)\n", x, s);
  printf("input is %d(%s)\n", y, c);
  printf("p=? n=?\n");
  scanf("%d %d", &p, &n);
  printf("The result is %d\n", setbit(x, p, n, y));
  printf("result in binumber:");
  to2(setbit(x, p, n, y), d);
}
```