ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ParseAddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x6,%edx
  mov    $0x0,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L25
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L15
  addl   $0x1,-0x10(%rbp)
  cmpl   $0x6,-0x10(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L174
L45:
  movl   $0x0,-0xc(%rbp)
  jmp    L143
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L104
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x57,%eax
  jmp    L85
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
L85:
  mov    %eax,-0x14(%rbp)
  cmpl   $0x9,-0x14(%rbp)
  jbe    L50
  cmpl   $0xf,-0x14(%rbp)
  jbe    L104
L50:
  mov    $0x0,%eax
  jmp    L174
L104:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  je     L159
  cmpl   $0x2,-0xc(%rbp)
  jle    L69
  mov    $0x0,%eax
  jmp    L174
L69:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D20(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D20(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
L159:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D20(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  or     -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D20(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
L143:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  cmpl   $0x5,-0x10(%rbp)
  je     L67
  mov    $0x0,%eax
  jmp    L174
L67:
  lea    D20(%rip),%rax
L174:
  leave
  ret
```

assistant: ```c
u_int8_t *ParseAddr(char *str) {
  static u_int8_t addr[6];
  char *cp;
  unsigned i;
  int part, subpart;
  memset((char *)&addr[0], 0, 6);
  part = subpart = 0;
  for (cp = str; *cp; cp++) {
    if (*cp == ':') {
      if (++part == 6)
        return (NULL);
      subpart = 0;
      continue;
    }
    if (isdigit(*cp))
      i = *cp - '0';
    else {
      i = (isupper(*cp) ? tolower(*cp) : *cp) - 'a' + 10;
      if (i < 10 || i > 15)
        return (NULL);
    }
    if (subpart++) {
      if (subpart > 2)
        return (NULL);
      addr[part] <<= 4;
    }
    addr[part] |= i;
  }
  if (part != (6 - 1))
    return (NULL);
  return (&addr[0]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ParseAddr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x6,%edx
  mov    $0x0,%esi
  lea    D21(%rip),%rdi
  call   <memset@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L18
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D21(%rip),%r13
  jmp    L141
L26:
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L0
  movsbl (%rbx),%eax
  sub    $0x30,%eax
L48:
  lea    0x1(%r12),%ecx
  test   %r12d,%r12d
  je     L142
  cmp    $0x2,%ecx
  jg     L89
  movslq %ebp,%rdx
  shll   $0x4,0x0(%r13,%rdx,4)
L142:
  movslq %ebp,%rdx
  or     %eax,0x0(%r13,%rdx,4)
  mov    %ecx,%r12d
L14:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L149
L141:
  cmp    $0x3a,%dil
  jne    L26
  add    $0x1,%ebp
  cmp    $0x6,%ebp
  je     L11
  mov    $0x0,%r12d
  jmp    L14
L0:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L29
  movsbl (%rbx),%eax
  sub    $0x57,%eax
L59:
  lea    -0xa(%rax),%edx
  cmp    $0x5,%edx
  jbe    L48
  mov    $0x0,%eax
  jmp    L22
L29:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x57,%eax
  jmp    L59
L149:
  cmp    $0x5,%ebp
  lea    D21(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
  jmp    L22
L18:
  mov    $0x0,%eax
  jmp    L22
L11:
  mov    $0x0,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  mov    $0x0,%eax
  jmp    L22
```

assistant: ```c
u_int8_t *ParseAddr(char *str) {
  static u_int8_t addr[6];
  char *cp;
  unsigned i;
  int part, subpart;
  memset((char *)&addr[0], 0, 6);
  part = subpart = 0;
  for (cp = str; *cp; cp++) {
    if (*cp == ':') {
      if (++part == 6)
        return (NULL);
      subpart = 0;
      continue;
    }
    if (isdigit(*cp))
      i = *cp - '0';
    else {
      i = (isupper(*cp) ? tolower(*cp) : *cp) - 'a' + 10;
      if (i < 10 || i > 15)
        return (NULL);
    }
    if (subpart++) {
      if (subpart > 2)
        return (NULL);
      addr[part] <<= 4;
    }
    addr[part] |= i;
  }
  if (part != (6 - 1))
    return (NULL);
  return (&addr[0]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ParseAddr>:
  endbr64
  push   %r13
  mov    $0x6,%edx
  xor    %esi,%esi
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L110
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L129:
  add    $0x1,%r12d
  cmp    $0x6,%r12d
  je     L110
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  xor    %r13d,%r13d
  test   %dil,%dil
  je     L7
L45:
  cmp    $0x3a,%dil
  je     L129
  call   <isdigit@plt>
  test   %rax,%rax
  je     L147
  movsbl (%rbx),%eax
  sub    $0x30,%eax
L135:
  lea    0x1(%r13),%esi
  test   %r13d,%r13d
  jne    L59
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
L61:
  or     %ecx,%eax
  add    $0x1,%rbx
  mov    %esi,%r13d
  mov    %eax,0x0(%rbp,%rdx,4)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L45
L7:
  lea    D4(%rip),%rax
  cmp    $0x5,%r12d
  je     L9
  nopw   0x0(%rax,%rax,1)
L110:
  xor    %eax,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L59:
  cmp    $0x2,%esi
  jne    L110
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  shl    $0x4,%ecx
  jmp    L61
  nopl   0x0(%rax)
L147:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L122
  movsbl (%rbx),%eax
  sub    $0x57,%eax
L11:
  lea    -0xa(%rax),%edx
  cmp    $0x5,%edx
  jbe    L135
  jmp    L110
  nopl   (%rax)
L122:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x57,%eax
  jmp    L11
```

assistant: ```c
u_int8_t *ParseAddr(char *str) {
  static u_int8_t addr[6];
  char *cp;
  unsigned i;
  int part, subpart;
  memset((char *)&addr[0], 0, 6);
  part = subpart = 0;
  for (cp = str; *cp; cp++) {
    if (*cp == ':') {
      if (++part == 6)
        return (NULL);
      subpart = 0;
      continue;
    }
    if (isdigit(*cp))
      i = *cp - '0';
    else {
      i = (isupper(*cp) ? tolower(*cp) : *cp) - 'a' + 10;
      if (i < 10 || i > 15)
        return (NULL);
    }
    if (subpart++) {
      if (subpart > 2)
        return (NULL);
      addr[part] <<= 4;
    }
    addr[part] |= i;
  }
  if (part != (6 - 1))
    return (NULL);
  return (&addr[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ParseAddr>:
  endbr64
  push   %r13
  mov    $0x6,%edx
  xor    %esi,%esi
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <memset@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L63
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x1,%r12d
  cmp    $0x6,%r12d
  je     L63
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  xor    %r13d,%r13d
  test   %dil,%dil
  je     L17
L55:
  cmp    $0x3a,%dil
  je     L29
  call   <isdigit@plt>
  test   %rax,%rax
  je     L88
  movsbl (%rbx),%eax
  sub    $0x30,%eax
L37:
  lea    0x1(%r13),%esi
  test   %r13d,%r13d
  jne    L144
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
L128:
  or     %ecx,%eax
  add    $0x1,%rbx
  mov    %esi,%r13d
  mov    %eax,0x0(%rbp,%rdx,4)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L55
L17:
  lea    D16(%rip),%rax
  cmp    $0x5,%r12d
  je     L44
  nopw   0x0(%rax,%rax,1)
L63:
  xor    %eax,%eax
L44:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L144:
  cmp    $0x2,%esi
  jne    L63
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  shl    $0x4,%ecx
  jmp    L128
  nopl   0x0(%rax)
L88:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L98
  movsbl (%rbx),%eax
  sub    $0x57,%eax
L133:
  lea    -0xa(%rax),%edx
  cmp    $0x5,%edx
  jbe    L37
  jmp    L63
  nopl   (%rax)
L98:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x57,%eax
  jmp    L133
```

assistant: ```c
u_int8_t *ParseAddr(char *str) {
  static u_int8_t addr[6];
  char *cp;
  unsigned i;
  int part, subpart;
  memset((char *)&addr[0], 0, 6);
  part = subpart = 0;
  for (cp = str; *cp; cp++) {
    if (*cp == ':') {
      if (++part == 6)
        return (NULL);
      subpart = 0;
      continue;
    }
    if (isdigit(*cp))
      i = *cp - '0';
    else {
      i = (isupper(*cp) ? tolower(*cp) : *cp) - 'a' + 10;
      if (i < 10 || i > 15)
        return (NULL);
    }
    if (subpart++) {
      if (subpart > 2)
        return (NULL);
      addr[part] <<= 4;
    }
    addr[part] |= i;
  }
  if (part != (6 - 1))
    return (NULL);
  return (&addr[0]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<nonDashCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L12:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L5
  addl   $0x1,-0x8(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int nonDashCount(char *s, int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; ++i)
    if (s[i] != '-')
      ++count;
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nonDashCount>:
  endbr64
  test   %esi,%esi
  jle    L22
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    $0x0,%edx
L1:
  cmpb   $0x2d,(%rax)
  setne  %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L1
L12:
  mov    %edx,%eax
  ret
L22:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int nonDashCount(char *s, int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; ++i)
    if (s[i] != '-')
      ++count;
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nonDashCount>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %edx,%edx
  cmpb   $0x2d,(%rdi)
  setne  %dl
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L8
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int nonDashCount(char *s, int size) {
  int count = 0;
  int i;
  for (i = 0; i < size; ++i)
    if (s[i] != '-')
      ++count;
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
L0:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L21:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L32
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x1,-0x8(%rbp)
L32:
  addl   $0x1,-0xc(%rbp)
L38:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L21
  cmpl   $0x1,-0x8(%rbp)
  je     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i = 0;
  int tmp, anySwaps;
  do {
    anySwaps = 0;
    for (i = 0; i < n - 1; i++) {
      if (number[i] > number[i + 1]) {
        tmp = number[i];
        number[i] = number[i + 1];
        number[i + 1] = tmp;
        anySwaps = 1;
      }
    }
  } while (anySwaps == 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<sort>:
  endbr64
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  mov    $0x0,%r11d
  mov    $0x1,%r10d
L1:
  cmp    $0x1,%esi
  jle    L46
  mov    %rdi,%rax
  mov    %r11d,%r9d
  jmp    L49
L16:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L18
L49:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L16
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  mov    %r10d,%r9d
  jmp    L16
L18:
  cmp    $0x1,%r9d
  je     L1
L46:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i = 0;
  int tmp, anySwaps;
  do {
    anySwaps = 0;
    for (i = 0; i < n - 1; i++) {
      if (number[i] > number[i + 1]) {
        tmp = number[i];
        number[i] = number[i + 1];
        number[i + 1] = tmp;
        anySwaps = 1;
      }
    }
  } while (anySwaps == 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sort>:
  endbr64
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  nopl   0x0(%rax)
L39:
  cmp    $0x1,%esi
  jle    L8
  mov    %rdi,%rax
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L12:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L24
  mov    %ecx,(%rax)
  mov    $0x1,%r9d
  mov    %edx,0x4(%rax)
L24:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L12
  cmp    $0x1,%r9d
  je     L39
L8:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i = 0;
  int tmp, anySwaps;
  do {
    anySwaps = 0;
    for (i = 0; i < n - 1; i++) {
      if (number[i] > number[i + 1]) {
        tmp = number[i];
        number[i] = number[i + 1];
        number[i + 1] = tmp;
        anySwaps = 1;
      }
    }
  } while (anySwaps == 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort>:
  endbr64
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  nopl   0x0(%rax)
L31:
  cmp    $0x1,%esi
  jle    L24
  mov    %rdi,%rdx
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L3:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L9
  movq   %xmm1,(%rdx)
  mov    $0x1,%r9d
L9:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L3
  cmp    $0x1,%r9d
  je     L31
L24:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int i = 0;
  int tmp, anySwaps;
  do {
    anySwaps = 0;
    for (i = 0; i < n - 1; i++) {
      if (number[i] > number[i + 1]) {
        tmp = number[i];
        number[i] = number[i + 1];
        number[i + 1] = tmp;
        anySwaps = 1;
      }
    }
  } while (anySwaps == 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slash_preceded>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L13
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  sete   %al
  movzbl %al,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int slash_preceded(const char *s) {
  if (!s) {
    return 0;
  }
  return (s[0] == '/') ? 1 : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<slash_preceded>:
  endbr64
  test   %rdi,%rdi
  je     L5
  cmpb   $0x2f,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int slash_preceded(const char *s) {
  if (!s) {
    return 0;
  }
  return (s[0] == '/') ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<slash_preceded>:
  endbr64
  test   %rdi,%rdi
  je     L0
  xor    %eax,%eax
  cmpb   $0x2f,(%rdi)
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int slash_preceded(const char *s) {
  if (!s) {
    return 0;
  }
  return (s[0] == '/') ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slash_preceded>:
  endbr64
  test   %rdi,%rdi
  je     L6
  xor    %eax,%eax
  cmpb   $0x2f,(%rdi)
  sete   %al
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int slash_preceded(const char *s) {
  if (!s) {
    return 0;
  }
  return (s[0] == '/') ? 1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x8,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x7,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0xd,-0x18(%rbp)
  movl   $0x7,-0x38(%rbp)
  mov    -0x38(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    $0xd,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <linearSearch@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  je     L8
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L10
L8:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L10:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string
name: disassemble_data
arguments: data_tag: D5
type: string

tool: D9: Key found at position : %d 


tool: D5: Key not found 

assistant: ```c
int main() {
  int a[] = {8, 12, 3, 4, 7, 2, 13};
  int n = sizeof(a) / sizeof(a[0]);
  int pos = linearSearch(a, n, 13);
  if (pos != 1)
    printf("Key found at position : %d \n", pos);
  else
    printf("Key not found \n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x8,(%rsp)
  movl   $0xc,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x7,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0xd,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0xd,%edx
  mov    $0x7,%esi
  call   <linearSearch@plt>
  cmp    $0x1,%eax
  je     L21
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L21:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L19
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D8
data_type: string

tool: D2: Key found at position : %d 


tool: D8: Key not found 

assistant: ```c
int main() {
  int a[] = {8, 12, 3, 4, 7, 2, 13};
  int n = sizeof(a) / sizeof(a[0]);
  int pos = linearSearch(a, n, 13);
  if (pos != 1)
    printf("Key found at position : %d \n", pos);
  else
    printf("Key not found \n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xd,%edx
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xc00000008,%rax
  mov    %rsp,%rdi
  movl   $0xd,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000007,%rax
  mov    %rax,0x10(%rsp)
  call   <linearSearch@plt>
  cmp    $0x1,%eax
  je     L20
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L20:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L14
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D1: Key found at position : %d 


tool: D7: Key not found 

assistant: ```c
int main() {
  int a[] = {8, 12, 3, 4, 7, 2, 13};
  int n = sizeof(a) / sizeof(a[0]);
  int pos = linearSearch(a, n, 13);
  if (pos != 1)
    printf("Key found at position : %d \n", pos);
  else
    printf("Key not found \n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0xd,%edx
  mov    $0x7,%esi
  movdqa D23(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D20(%rip),%rax
  mov    %rsp,%rdi
  movl   $0xd,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <linearSearch@plt>
  cmp    $0x1,%eax
  je     L7
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L7:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L11
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D23
type: byte[16]
name: retrieve_data
arguments: tag: D20
type: byte[8]
name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D9
type: string

tool: {"D23": [0x08,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D20": [0x07,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D6: Key found at position : %d 


tool: D9: Key not found 

assistant: ```c
int main() {
  int a[] = {8, 12, 3, 4, 7, 2, 13};
  int n = sizeof(a) / sizeof(a[0]);
  int pos = linearSearch(a, n, 13);
  if (pos != 1)
    printf("Key found at position : %d \n", pos);
  else
    printf("Key not found \n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x61(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x60(%rbp),%rax
  lea    D26(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
  movb   $0x1,-0x61(%rbp)
L26:
  cmpb   $0x1,-0x61(%rbp)
  jne    L5
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string

tool: D9: Enter password:


tool: D26: GOODPASS

tool: D19: You win!


assistant: ```c
int main() {
  char passIsGood = 0;
  char buf[80];
  printf("Enter password:\n");
  gets(buf);
  if (strcmp(buf, "GOODPASS") == 0)
    passIsGood = 1;
  if (passIsGood == 1)
    printf("You win!\n");
}
```