ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<retrieve_solutions_on_grid>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x31,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int retrieve_solutions_on_grid(int i) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(49, &i, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L23
L19:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D7
type: string

tool: D8: %llu


tool: D7: %llu

assistant: ```c
int main(int argc, char **argv) {
  long long unsigned int x;
  while (scanf("%llu", &x) == 1) {
    printf("%llu\n", x);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D3(%rip),%rbx
  lea    D10(%rip),%r12
  jmp    L0
L20:
  mov    (%rsp),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L20
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string

tool: D3: %llu

tool: D10: %llu


assistant: ```c
int main(int argc, char **argv) {
  long long unsigned int x;
  while (scanf("%llu", &x) == 1) {
    printf("%llu\n", x);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L6
  nop
L24:
  mov    (%rsp),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L24
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D6: %llu


tool: D8: %llu

assistant: ```c
int main(int argc, char **argv) {
  long long unsigned int x;
  while (scanf("%llu", &x) == 1) {
    printf("%llu\n", x);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L14
  nop
L21:
  mov    (%rsp),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L14:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L21
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string

tool: D8: %llu


tool: D3: %llu

assistant: ```c
int main(int argc, char **argv) {
  long long unsigned int x;
  while (scanf("%llu", &x) == 1) {
    printf("%llu\n", x);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__irmodl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fldt   0x10(%rbp)
  fstpt  -0x10(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x80000000,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x14,%eax
  and    $0x7ff,%eax
  sub    $0x3ff,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x52,-0x14(%rbp)
  jg     L25
  cmpl   $0x0,-0x14(%rbp)
  jns    L50
L25:
  mov    $0x0,%eax
  jmp    L13
L50:
  cmpl   $0x33,-0x14(%rbp)
  jle    L49
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  sub    $0x34,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L26
L49:
  mov    -0xc(%rbp),%eax
  and    $0xfffff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  or     $0x100000,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    $0x34,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  mov    %eax,%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L26:
  cmpl   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x1c(%rbp),%eax
  neg    %eax
  jmp    L13
L8:
  mov    -0x1c(%rbp),%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int __irmodl(long double x) {
  union {
    long double f;
    long i;
    struct {
      int i0, i1;
    };
  } u = {x};
  int sig = u.i1 & 0x80000000;
  int exp = ((u.i1 >> 20) & 0x7FF) - 1023;
  int res;
  if (exp >= 83 || exp < 0)
    return 0;
  if (exp >= 52)
    res = (u.i0 << (exp - 52)) & INT_MAX;
  else {
    u.i1 &= 0x000FFFFF;
    u.i1 |= 0x00100000;
    res = (u.i >> (52 - exp)) & INT_MAX;
  }
  return sig ? -res : res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__irmodl>:
  endbr64
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%edi
  mov    %rsi,-0x18(%rsp)
  mov    %edi,-0x10(%rsp)
  mov    %rsi,%rcx
  mov    %rsi,%r8
  sar    $0x20,%r8
  sar    $0x34,%rcx
  and    $0x7ff,%ecx
  lea    -0x3ff(%rcx),%edx
  mov    $0x0,%eax
  cmp    $0x52,%edx
  ja     L13
  cmp    $0x33,%edx
  jle    L1
  sub    $0x433,%ecx
  shl    %cl,%esi
  mov    D17(%rip),%rax
  and    (%rax),%esi
  mov    %esi,%eax
L26:
  mov    %eax,%edx
  neg    %edx
  test   %r8d,%r8d
  cmovs  %edx,%eax
L13:
  ret
L1:
  mov    %r8d,%eax
  and    $0xfffff,%eax
  or     $0x100000,%eax
  mov    %eax,-0x14(%rsp)
  mov    $0x34,%ecx
  sub    %edx,%ecx
  mov    -0x18(%rsp),%rax
  sar    %cl,%rax
  mov    D17(%rip),%rdx
  and    (%rdx),%eax
  jmp    L26
```

assistant: ```c
int __irmodl(long double x) {
  union {
    long double f;
    long i;
    struct {
      int i0, i1;
    };
  } u = {x};
  int sig = u.i1 & 0x80000000;
  int exp = ((u.i1 >> 20) & 0x7FF) - 1023;
  int res;
  if (exp >= 83 || exp < 0)
    return 0;
  if (exp >= 52)
    res = (u.i0 << (exp - 52)) & INT_MAX;
  else {
    u.i1 &= 0x000FFFFF;
    u.i1 |= 0x00100000;
    res = (u.i >> (52 - exp)) & INT_MAX;
  }
  return sig ? -res : res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__irmodl>:
  endbr64
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%edx
  xor    %r8d,%r8d
  mov    %rax,%rdi
  mov    %edx,-0x10(%rsp)
  mov    %rax,%rsi
  sar    $0x34,%rdi
  mov    %rax,-0x18(%rsp)
  sar    $0x20,%rsi
  mov    %rdi,%rcx
  and    $0x7ff,%ecx
  lea    -0x3ff(%rcx),%edx
  cmp    $0x52,%edx
  ja     L6
  mov    D4(%rip),%rdi
  mov    (%rdi),%r8d
  cmp    $0x33,%edx
  jg     L11
  mov    %esi,%eax
  mov    $0x34,%ecx
  and    $0xfffff,%eax
  sub    %edx,%ecx
  or     $0x100000,%eax
  mov    %eax,-0x14(%rsp)
  mov    -0x18(%rsp),%rax
  sar    %cl,%rax
  and    %eax,%r8d
L25:
  mov    %r8d,%eax
  neg    %eax
  test   %esi,%esi
  cmovs  %eax,%r8d
L6:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  sub    $0x433,%ecx
  shl    %cl,%eax
  and    %eax,%r8d
  jmp    L25
```

assistant: ```c
int __irmodl(long double x) {
  union {
    long double f;
    long i;
    struct {
      int i0, i1;
    };
  } u = {x};
  int sig = u.i1 & 0x80000000;
  int exp = ((u.i1 >> 20) & 0x7FF) - 1023;
  int res;
  if (exp >= 83 || exp < 0)
    return 0;
  if (exp >= 52)
    res = (u.i0 << (exp - 52)) & INT_MAX;
  else {
    u.i1 &= 0x000FFFFF;
    u.i1 |= 0x00100000;
    res = (u.i >> (52 - exp)) & INT_MAX;
  }
  return sig ? -res : res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__irmodl>:
  endbr64
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%edx
  xor    %r8d,%r8d
  mov    %rax,%rdi
  mov    %edx,-0x10(%rsp)
  mov    %rax,%rsi
  sar    $0x34,%rdi
  mov    %rax,-0x18(%rsp)
  sar    $0x20,%rsi
  mov    %rdi,%rcx
  and    $0x7ff,%ecx
  lea    -0x3ff(%rcx),%edx
  cmp    $0x52,%edx
  ja     L14
  mov    D7(%rip),%rdi
  mov    (%rdi),%r8d
  cmp    $0x33,%edx
  jg     L17
  mov    %esi,%eax
  mov    $0x34,%ecx
  and    $0xfffff,%eax
  sub    %edx,%ecx
  or     $0x100000,%eax
  mov    %eax,-0x14(%rsp)
  mov    -0x18(%rsp),%rax
  sar    %cl,%rax
  and    %eax,%r8d
L6:
  mov    %r8d,%eax
  neg    %eax
  test   %esi,%esi
  cmovs  %eax,%r8d
L14:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  sub    $0x433,%ecx
  shl    %cl,%eax
  and    %eax,%r8d
  jmp    L6
```

assistant: ```c
int __irmodl(long double x) {
  union {
    long double f;
    long i;
    struct {
      int i0, i1;
    };
  } u = {x};
  int sig = u.i1 & 0x80000000;
  int exp = ((u.i1 >> 20) & 0x7FF) - 1023;
  int res;
  if (exp >= 83 || exp < 0)
    return 0;
  if (exp >= 52)
    res = (u.i0 << (exp - 52)) & INT_MAX;
  else {
    u.i1 &= 0x000FFFFF;
    u.i1 |= 0x00100000;
    res = (u.i >> (52 - exp)) & INT_MAX;
  }
  return sig ? -res : res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  {
#pragma omp declare reduction(fun : struct SSS : omp_out = omp_in) initializer(init(&omp_priv, omp_orig))
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_broadcast_ether_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  and    %edx,%eax
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_broadcast_ether_addr(const void *addr) {
  const __u16 *_addr = addr;
  return (_addr[0] & _addr[1] & _addr[2]) == 0xffff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_broadcast_ether_addr>:
  endbr64
  mov    (%rdi),%eax
  and    0x4(%rdi),%eax
  and    0x8(%rdi),%eax
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_broadcast_ether_addr(const void *addr) {
  const __u16 *_addr = addr;
  return (_addr[0] & _addr[1] & _addr[2]) == 0xffff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_broadcast_ether_addr>:
  endbr64
  mov    (%rdi),%eax
  and    0x4(%rdi),%eax
  and    0x8(%rdi),%eax
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_broadcast_ether_addr(const void *addr) {
  const __u16 *_addr = addr;
  return (_addr[0] & _addr[1] & _addr[2]) == 0xffff;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_broadcast_ether_addr>:
  endbr64
  mov    (%rdi),%eax
  and    0x4(%rdi),%eax
  and    0x8(%rdi),%eax
  cmp    $0xffff,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_broadcast_ether_addr(const void *addr) {
  const __u16 *_addr = addr;
  return (_addr[0] & _addr[1] & _addr[2]) == 0xffff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scale>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,%rcx
  mov    $0x0,%ebx
  movq   $0x0,-0x28(%rbp)
  jmp    L28
L4:
  movq   $0x0,-0x20(%rbp)
  jmp    L24
L35:
  mov    %rax,%rdx
  imul   -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x20(%rbp),%rdx
  movsd  (%rcx,%rdx,8),%xmm0
  mov    %rax,%rdx
  imul   -0x28(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x48(%rbp),%rdx
  add    %rdx,%rcx
  mulsd  -0x50(%rbp),%xmm0
  mov    -0x20(%rbp),%rdx
  movsd  %xmm0,(%rcx,%rdx,8)
  addq   $0x1,-0x20(%rbp)
L24:
  mov    -0x20(%rbp),%rdx
  cmp    -0x40(%rbp),%rdx
  jb     L35
  addq   $0x1,-0x28(%rbp)
L28:
  mov    -0x28(%rbp),%rdx
  cmp    -0x38(%rbp),%rdx
  jb     L4
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void scale(size_t r, size_t c, double X[r][c], double s) {
  size_t i, j;
  for (i = 0; i < r; i++) {
    for (j = 0; j < c; j++)
      X[i][j] *= s;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<scale>:
  endbr64
  test   %rdi,%rdi
  je     L51
  lea    0x0(,%rsi,8),%r9
  mov    $0x0,%r8d
  jmp    L59
L37:
  movapd %xmm0,%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L37
L19:
  add    $0x1,%r8
  add    %r9,%rdx
  cmp    %r8,%rdi
  je     L51
L59:
  mov    %rdx,%rcx
  mov    $0x0,%eax
  test   %rsi,%rsi
  jne    L37
  jmp    L19
L51:
  ret
```

assistant: ```c
void scale(size_t r, size_t c, double X[r][c], double s) {
  size_t i, j;
  for (i = 0; i < r; i++) {
    for (j = 0; j < c; j++)
      X[i][j] *= s;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<scale>:
  endbr64
  test   %rdi,%rdi
  je     L36
  lea    0x0(,%rsi,8),%r8
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L39
  nop
L13:
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L13
L39:
  add    $0x1,%rcx
  add    %r8,%rdx
  cmp    %rcx,%rdi
  jne    L8
L36:
  ret
```

assistant: ```c
void scale(size_t r, size_t c, double X[r][c], double s) {
  size_t i, j;
  for (i = 0; i < r; i++) {
    for (j = 0; j < c; j++)
      X[i][j] *= s;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<scale>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  test   %rdi,%rdi
  je     L36
  test   %rsi,%rsi
  je     L36
  mov    %r8,%r10
  movapd %xmm0,%xmm2
  lea    0x0(,%rsi,8),%r11
  xor    %edi,%edi
  shr    %rsi
  and    $0xfffffffffffffffe,%r10
  unpcklpd %xmm2,%xmm2
L34:
  mov    %rdx,%rax
  xor    %ecx,%ecx
  cmp    $0x1,%r8
  je     L43
  nopl   0x0(%rax,%rax,1)
L5:
  movupd (%rax),%xmm1
  add    $0x1,%rcx
  add    $0x10,%rax
  mulpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rsi
  jne    L5
  mov    %r10,%rax
  cmp    %r10,%r8
  je     L2
L16:
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
L2:
  add    $0x1,%rdi
  add    %r11,%rdx
  cmp    %rdi,%r9
  jne    L34
L36:
  ret
L43:
  xor    %eax,%eax
  jmp    L16
```

assistant: ```c
void scale(size_t r, size_t c, double X[r][c], double s) {
  size_t i, j;
  for (i = 0; i < r; i++) {
    for (j = 0; j < c; j++)
      X[i][j] *= s;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  jmp    L4
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <pause@plt>
  subl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x0,-0x4(%rbp)
  jg     L1
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string
name: unpack_data
arguments: tag: D18
data_type: string

tool: D3: %d


tool: D18: 
Blast Off!

assistant: ```c
int main(void) {
  int x;
  for (x = 10; x > 0; x--) {
    printf("%d\n", x);
    pause();
  }
  printf("\nBlast Off!");
  getchar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0xa,%ebx
  lea    D3(%rip),%rbp
L0:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <pause@plt>
  sub    $0x1,%ebx
  jne    L0
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D3: %d


tool: D10: 
Blast Off!

assistant: ```c
int main(void) {
  int x;
  for (x = 10; x > 0; x--) {
    printf("%d\n", x);
    pause();
  }
  printf("\nBlast Off!");
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <pause@plt>
  sub    $0x1,%ebx
  jne    L9
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D1
type_guessed: string

tool: D11: %d


tool: D1: 
Blast Off!

assistant: ```c
int main(void) {
  int x;
  for (x = 10; x > 0; x--) {
    printf("%d\n", x);
    pause();
  }
  printf("\nBlast Off!");
  getchar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <pause@plt>
  sub    $0x1,%ebx
  jne    L7
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D7
type_infered: string

tool: D10: %d


tool: D7: 
Blast Off!

assistant: ```c
int main(void) {
  int x;
  for (x = 10; x > 0; x--) {
    printf("%d\n", x);
    pause();
  }
  printf("\nBlast Off!");
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  jmp    L11
L56:
  mov    -0x3c(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x3c(%rbp)
L11:
  cmpl   $0x6,-0x3c(%rbp)
  jle    L56
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L5
L43:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x34(%rbp)
  jge    L66
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
L66:
  addl   $0x1,-0x38(%rbp)
L5:
  cmpl   $0x6,-0x38(%rbp)
  jle    L43
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L32
L39:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L81
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
L81:
  addl   $0x1,-0x38(%rbp)
L32:
  cmpl   $0x6,-0x38(%rbp)
  jle    L39
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: string
name: unpack_data
arguments: data_tag: D23
type: string
name: unpack_data
arguments: data_tag: D33
type: string
name: unpack_data
arguments: data_tag: D31
type: string

tool: D15: Enter ur value of [%d]:


tool: D23: %d

tool: D33: Maximum value is %d


tool: D31: Mini value is %d


assistant: ```c
int main() {
  int array[7];
  int i, j, search, max;
  for (i = 0; i < 7; i++) {
    printf("Enter ur value of [%d]:\n", i);
    scanf("%d", &array[i]);
  }
  max = array[0];
  for (j = 0; j < 7; j++) {
    if (max < array[j]) {
      max = array[j];
    }
  }
  printf("Maximum value is %d\n", max);
  max = array[0];
  for (j = 0; j < 7; j++) {
    if (max > array[j]) {
      max = array[j];
    }
  }
  printf("Mini value is %d\n", max);
  return (0);
}
```