ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ANT_SetSearchWaveform>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x14(%rbp),%eax
  mov    %al,-0xb(%rbp)
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x18,%edx
  add    %edx,%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %al,-0xa(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0xff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x8,%eax
  mov    %al,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    $0x3,%edx
  mov    %rax,%rsi
  mov    $0x49,%edi
  call   <msg_send@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned char ANT_SetSearchWaveform(unsigned char chan, ushort waveform) {
  unsigned char buf[3];
  buf[0] = chan;
  buf[1] = waveform % 256;
  buf[2] = waveform / 256;
  return msg_send(0x49, buf, 3);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ANT_SetSearchWaveform>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x5(%rsp)
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x18,%edx
  lea    (%rsi,%rdx,1),%eax
  movzbl %al,%eax
  sub    %edx,%eax
  mov    %al,0x6(%rsp)
  lea    0xff(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  movzbl %ah,%eax
  mov    %al,0x7(%rsp)
  lea    0x5(%rsp),%rsi
  mov    $0x3,%edx
  mov    $0x49,%edi
  call   <msg_send@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char ANT_SetSearchWaveform(unsigned char chan, ushort waveform) {
  unsigned char buf[3];
  buf[0] = chan;
  buf[1] = waveform % 256;
  buf[2] = waveform / 256;
  return msg_send(0x49, buf, 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ANT_SetSearchWaveform>:
  endbr64
  mov    %esi,%edx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sar    $0x1f,%edx
  mov    %dil,0x5(%rsp)
  mov    $0x49,%edi
  shr    $0x18,%edx
  lea    (%rsi,%rdx,1),%eax
  movzbl %al,%eax
  sub    %edx,%eax
  test   %esi,%esi
  mov    $0x3,%edx
  mov    %al,0x6(%rsp)
  lea    0xff(%rsi),%eax
  cmovns %esi,%eax
  lea    0x5(%rsp),%rsi
  mov    %ah,0x7(%rsp)
  call   <msg_send@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char ANT_SetSearchWaveform(unsigned char chan, ushort waveform) {
  unsigned char buf[3];
  buf[0] = chan;
  buf[1] = waveform % 256;
  buf[2] = waveform / 256;
  return msg_send(0x49, buf, 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ANT_SetSearchWaveform>:
  endbr64
  mov    %esi,%edx
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sar    $0x1f,%edx
  mov    %dil,%cl
  mov    $0x49,%edi
  shr    $0x18,%edx
  lea    (%rsi,%rdx,1),%eax
  movzbl %al,%eax
  sub    %edx,%eax
  test   %esi,%esi
  mov    $0x3,%edx
  mov    %al,%ch
  lea    0xff(%rsi),%eax
  cmovns %esi,%eax
  lea    0x4(%rsp),%rsi
  mov    %cx,0x4(%rsp)
  mov    %ah,0x6(%rsp)
  call   <msg_send@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char ANT_SetSearchWaveform(unsigned char chan, ushort waveform) {
  unsigned char buf[3];
  buf[0] = chan;
  buf[1] = waveform % 256;
  buf[2] = waveform / 256;
  return msg_send(0x49, buf, 3);
}
```
user: What is the c source code of the assembly code below:

```asm
<poll_retry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  lea    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
L24:
  mov    -0x24(%rbp),%edx
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <poll@plt>
  mov    %eax,-0x1c(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x18(%rbp),%edx
  sub    %edx,%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%edx
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x40(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0xffffffff,-0x1c(%rbp)
  jne    L35
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L35
  cmpl   $0x0,-0x24(%rbp)
  jg     L24
L35:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int poll_retry(struct pollfd *fds, nfds_t nfsd, int timeout) {
  int ret;
  int time_remain = timeout;
  int time_elapsed = 0;
  struct timeval start_time;
  struct timeval tv;
  gettimeofday(&start_time, NULL);
  do {
    ret = poll(fds, nfsd, time_remain);
    gettimeofday(&tv, NULL);
    time_elapsed = ((tv.tv_sec - start_time.tv_sec) * 1000 + (tv.tv_usec - start_time.tv_usec) / 1000);
    time_remain = timeout - time_elapsed;
  } while (ret == -1 && errno == EINTR && time_remain > 0);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<poll_retry>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    %ebp,%edx
  lea    0x10(%rsp),%r14
L35:
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <poll@plt>
  mov    %eax,%ebx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <gettimeofday@plt>
  mov    0x10(%rsp),%eax
  sub    0x8(%rsp),%eax
  imul   $0x3e8,%eax,%eax
  mov    0x14(%rsp),%ecx
  sub    0xc(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    %ebp,%edx
  sub    %eax,%edx
  cmp    $0xffffffff,%ebx
  jne    L28
  mov    D4(%rip),%rcx
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  jne    L28
  test   %edx,%edx
  jg     L35
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int poll_retry(struct pollfd *fds, nfds_t nfsd, int timeout) {
  int ret;
  int time_remain = timeout;
  int time_elapsed = 0;
  struct timeval start_time;
  struct timeval tv;
  gettimeofday(&start_time, NULL);
  do {
    ret = poll(fds, nfsd, time_remain);
    gettimeofday(&tv, NULL);
    time_elapsed = ((tv.tv_sec - start_time.tv_sec) * 1000 + (tv.tv_usec - start_time.tv_usec) / 1000);
    time_remain = timeout - time_elapsed;
  } while (ret == -1 && errno == EINTR && time_remain > 0);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<poll_retry>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r13
  call   <gettimeofday@plt>
  mov    %ebx,%edx
  jmp    L37
  nopl   0x0(%rax)
L16:
  mov    D0(%rip),%rax
  mov    D18(%rip),%rcx
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  jne    L27
  test   %edx,%edx
  jle    L27
L37:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <poll@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%ecx
  sub    0xc(%rsp),%ecx
  movslq %ecx,%rdx
  mov    0x10(%rsp),%eax
  sub    0x8(%rsp),%eax
  sar    $0x1f,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  imul   $0x3e8,%eax,%eax
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    %ebx,%edx
  sub    %eax,%edx
  cmp    $0xffffffff,%r14d
  je     L16
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x20,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int poll_retry(struct pollfd *fds, nfds_t nfsd, int timeout) {
  int ret;
  int time_remain = timeout;
  int time_elapsed = 0;
  struct timeval start_time;
  struct timeval tv;
  gettimeofday(&start_time, NULL);
  do {
    ret = poll(fds, nfsd, time_remain);
    gettimeofday(&tv, NULL);
    time_elapsed = ((tv.tv_sec - start_time.tv_sec) * 1000 + (tv.tv_usec - start_time.tv_usec) / 1000);
    time_remain = timeout - time_elapsed;
  } while (ret == -1 && errno == EINTR && time_remain > 0);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<poll_retry>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  lea    0x10(%rsp),%r13
  call   <gettimeofday@plt>
  mov    %ebx,%edx
  jmp    L38
  nopl   0x0(%rax)
L1:
  mov    D9(%rip),%rax
  mov    D18(%rip),%rcx
  mov    (%rax),%rax
  cmp    %rax,(%rcx)
  jne    L47
  test   %edx,%edx
  jle    L47
L38:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <poll@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %eax,%r14d
  call   <gettimeofday@plt>
  mov    0x14(%rsp),%ecx
  sub    0xc(%rsp),%ecx
  movslq %ecx,%rdx
  mov    0x10(%rsp),%eax
  sub    0x8(%rsp),%eax
  sar    $0x1f,%ecx
  imul   $0x10624dd3,%rdx,%rdx
  imul   $0x3e8,%eax,%eax
  sar    $0x26,%rdx
  sub    %ecx,%edx
  add    %edx,%eax
  mov    %ebx,%edx
  sub    %eax,%edx
  cmp    $0xffffffff,%r14d
  je     L1
L47:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x20,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int poll_retry(struct pollfd *fds, nfds_t nfsd, int timeout) {
  int ret;
  int time_remain = timeout;
  int time_elapsed = 0;
  struct timeval start_time;
  struct timeval tv;
  gettimeofday(&start_time, NULL);
  do {
    ret = poll(fds, nfsd, time_remain);
    gettimeofday(&tv, NULL);
    time_elapsed = ((tv.tv_sec - start_time.tv_sec) * 1000 + (tv.tv_usec - start_time.tv_usec) / 1000);
    time_remain = timeout - time_elapsed;
  } while (ret == -1 && errno == EINTR && time_remain > 0);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<findentf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vfindentf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void findentf(FILE *fd, int depth, char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfindentf(fd, depth, fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<findentf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vfindentf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void findentf(FILE *fd, int depth, char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfindentf(fd, depth, fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<findentf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vfindentf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void findentf(FILE *fd, int depth, char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfindentf(fd, depth, fmt, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findentf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vfindentf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void findentf(FILE *fd, int depth, char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfindentf(fd, depth, fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L52
L27:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D4(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D26(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <modf@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jnp    L21
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L21:
  addl   $0x1,-0x34(%rbp)
L52:
  cmpl   $0xf423f,-0x34(%rbp)
  jle    L27
L19:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  ucomisd -0x28(%rbp),%xmm0
  jnp    L32
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L32:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: f64
name: extract_symbolic_data
arguments: label: D26
type: f64
name: extract_symbolic_data
arguments: label: D33
type: string

tool: D4: 10000000

tool: D26: 5000000

tool: D33: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double iptr;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = modf(x, &iptr);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What is the c source code of the assembly code below?

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
  mov    %rsp,%rbp
L31:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D12(%rip),%xmm0
  subsd  D25(%rip),%xmm0
  mov    %rbp,%rdi
  call   <modf@plt>
  ucomisd %xmm0,%xmm0
  jp     L19
  sub    $0x1,%ebx
  jne    L31
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L30
L19:
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  movq   %rbx,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: f64
name: retrieve_data
arguments: label: D25
type_infered: f64
name: retrieve_data
arguments: label: D16
type_infered: string

tool: D12: 10000000

tool: D25: 5000000

tool: D16: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double iptr;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = modf(x, &iptr);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L8
  nopl   0x0(%rax)
L45:
  sub    $0x1,%ebx
  je     L6
L8:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D9(%rip),%xmm0
  mov    %rbp,%rdi
  subsd  D7(%rip),%xmm0
  call   <modf@plt>
  ucomisd %xmm0,%xmm0
  jnp    L45
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  jmp    L17
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: f64
name: retrieve_data
arguments: label: D7
type_guessed: f64
name: retrieve_data
arguments: label: D29
type_guessed: string

tool: D9: 10000000

tool: D7: 5000000

tool: D29: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double iptr;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = modf(x, &iptr);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  jmp    L12
  nopl   0x0(%rax)
L1:
  sub    $0x1,%ebx
  je     L35
L12:
  xor    %eax,%eax
  call   <rand_double@plt>
  mulsd  D18(%rip),%xmm0
  mov    %rbp,%rdi
  subsd  D3(%rip),%xmm0
  call   <modf@plt>
  ucomisd %xmm0,%xmm0
  jnp    L1
  lea    D25(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  jmp    L38
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: f64
name: parse_data
arguments: data_tag: D3
datatype: f64
name: parse_data
arguments: data_tag: D25
datatype: string

tool: D18: 10000000

tool: D3: 5000000

tool: D25: should not return NaN


assistant: ```c
double benchmark() {
  double elapsed;
  double iptr;
  double x;
  double y;
  double t;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (1.0e7 * rand_double()) - 5.0e6;
    y = modf(x, &iptr);
    if (y != y) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y != y) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <uart_puts@plt>
  mov    $0x4000000,%edi
  call   <load_kernel@plt>
L7:
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D5
type_guessed: string

tool: D13: [D] 

tool: D5: Now running in C


assistant: ```c
int main(void) {
  do {
    uart_puts("[D] ");
    uart_puts("Now running in C\n");
  } while (0);
  load_kernel((void *)0x04000000);
  while (1) {
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <uart_puts@plt>
  lea    D8(%rip),%rdi
  call   <uart_puts@plt>
  mov    $0x4000000,%edi
  call   <load_kernel@plt>
L3:
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D13: [D] 

tool: D8: Now running in C


assistant: ```c
int main(void) {
  do {
    uart_puts("[D] ");
    uart_puts("Now running in C\n");
  } while (0);
  load_kernel((void *)0x04000000);
  while (1) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <uart_puts@plt>
  lea    D0(%rip),%rdi
  call   <uart_puts@plt>
  mov    $0x4000000,%edi
  call   <load_kernel@plt>
L3:
  jmp    L3
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D0
type: string

tool: D2: [D] 

tool: D0: Now running in C


assistant: ```c
int main(void) {
  do {
    uart_puts("[D] ");
    uart_puts("Now running in C\n");
  } while (0);
  load_kernel((void *)0x04000000);
  while (1) {
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <uart_puts@plt>
  lea    D15(%rip),%rdi
  call   <uart_puts@plt>
  mov    $0x4000000,%edi
  call   <load_kernel@plt>
L1:
  jmp    L1
```

tool_calls: name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D15
datatype: string

tool: D12: [D] 

tool: D15: Now running in C


assistant: ```c
int main(void) {
  do {
    uart_puts("[D] ");
    uart_puts("Now running in C\n");
  } while (0);
  load_kernel((void *)0x04000000);
  while (1) {
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<merc_reload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <read_merc_db@plt>
  mov    $0x0,%eax
  call   <read_merc_skilldb@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void merc_reload(void) {
  read_merc_db();
  read_merc_skilldb();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<merc_reload>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <read_merc_db@plt>
  mov    $0x0,%eax
  call   <read_merc_skilldb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void merc_reload(void) {
  read_merc_db();
  read_merc_skilldb();
}
```