ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  sar    $0x1f,%eax
  not    %eax
  cmp    $0xffffffff,%edi
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  mov    $0xfffffffe,%edx
  mov    %edx,%ecx
  sub    %edi,%ecx
  and    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,%esi
  sar    $0x1f,%esi
  cmp    $0x2,%edx
  setbe  %dl
  movzbl %dl,%edx
  sub    %edx,%esi
  mov    $0xfffffffb,%edx
  sub    %eax,%edx
  and    %edx,%esi
  add    $0x3,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: MinMax result %d


assistant: ```c
void test(int param1) {
  int g1;
  g1 = -2 - (-2 - param1 & -1 - (param1 >> 31) + ((unsigned int)-2 < (unsigned int)param1));
  printf("MinMax result %d\n", (g1 - 3 & (g1 >> 31) - ((unsigned int)g1 < 3)) + 3);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test>:
  endbr64
  mov    %edi,%eax
  xor    %edx,%edx
  sar    $0x1f,%eax
  cmp    $0xffffffff,%edi
  sete   %dl
  not    %eax
  add    %edx,%eax
  mov    $0xfffffffe,%edx
  mov    %edx,%ecx
  sub    %edi,%ecx
  lea    D5(%rip),%rdi
  and    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,%esi
  sar    $0x1f,%esi
  cmp    $0x2,%edx
  setbe  %dl
  movzbl %dl,%edx
  sub    %edx,%esi
  mov    $0xfffffffb,%edx
  sub    %eax,%edx
  and    %edx,%esi
  add    $0x3,%esi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: MinMax result %d


assistant: ```c
void test(int param1) {
  int g1;
  g1 = -2 - (-2 - param1 & -1 - (param1 >> 31) + ((unsigned int)-2 < (unsigned int)param1));
  printf("MinMax result %d\n", (g1 - 3 & (g1 >> 31) - ((unsigned int)g1 < 3)) + 3);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test>:
  endbr64
  mov    %edi,%eax
  xor    %edx,%edx
  sar    $0x1f,%eax
  cmp    $0xffffffff,%edi
  sete   %dl
  not    %eax
  add    %edx,%eax
  mov    $0xfffffffe,%edx
  mov    %edx,%ecx
  sub    %edi,%ecx
  lea    D3(%rip),%rdi
  and    %ecx,%eax
  sub    %eax,%edx
  mov    %edx,%esi
  sar    $0x1f,%esi
  cmp    $0x2,%edx
  setbe  %dl
  movzbl %dl,%edx
  sub    %edx,%esi
  mov    $0xfffffffb,%edx
  sub    %eax,%edx
  and    %edx,%esi
  add    $0x3,%esi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: D3: MinMax result %d


assistant: ```c
void test(int param1) {
  int g1;
  g1 = -2 - (-2 - param1 & -1 - (param1 >> 31) + ((unsigned int)-2 < (unsigned int)param1));
  printf("MinMax result %d\n", (g1 - 3 & (g1 >> 31) - ((unsigned int)g1 < 3)) + 3);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<grep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L3:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L3
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <execv@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
data_type: string

tool: D11: /bin/grep

assistant: ```c
int grep(char *grep_args[]) {
  int i;
  char **new_args;
  new_args = (char **)malloc(sizeof(char *) * (sizeof(grep_args) + 1));
  new_args[0] = strdup("/bin/grep");
  for (i = 0; grep_args[i]; i++)
    new_args[i + 1] = grep_args[i];
  new_args[i + 1] = NULL;
  execv("/bin/grep", new_args);
  free(new_args);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<grep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D11(%rip),%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L26
  lea    0x8(%rbp),%rcx
  mov    $0x1,%eax
L5:
  mov    %rdx,(%rcx)
  mov    (%rbx,%rax,8),%rdx
  mov    %rax,%rsi
  add    $0x1,%rax
  add    $0x8,%rcx
  test   %rdx,%rdx
  jne    L5
L15:
  movq   $0x0,0x8(%rbp,%rsi,8)
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <execv@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    $0x0,%esi
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string

tool: D11: /bin/grep

assistant: ```c
int grep(char *grep_args[]) {
  int i;
  char **new_args;
  new_args = (char **)malloc(sizeof(char *) * (sizeof(grep_args) + 1));
  new_args[0] = strdup("/bin/grep");
  for (i = 0; grep_args[i]; i++)
    new_args[i + 1] = grep_args[i];
  new_args[i + 1] = NULL;
  execv("/bin/grep", new_args);
  free(new_args);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<grep>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L11
  lea    0x8(%rbp),%rcx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L13:
  mov    %rdx,(%rcx)
  mov    (%rbx,%rax,8),%rdx
  add    $0x8,%rcx
  add    $0x1,%rax
  test   %rdx,%rdx
  jne    L13
  shl    $0x3,%rax
L10:
  movq   $0x0,0x0(%rbp,%rax,1)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <execv@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0x8,%eax
  jmp    L10
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string

tool: D6: /bin/grep

assistant: ```c
int grep(char *grep_args[]) {
  int i;
  char **new_args;
  new_args = (char **)malloc(sizeof(char *) * (sizeof(grep_args) + 1));
  new_args[0] = strdup("/bin/grep");
  for (i = 0; grep_args[i]; i++)
    new_args[i + 1] = grep_args[i];
  new_args[i + 1] = NULL;
  execv("/bin/grep", new_args);
  free(new_args);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<grep>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L6
  lea    0x8(%rbp),%rcx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L22:
  mov    %rdx,(%rcx)
  mov    (%rbx,%rax,8),%rdx
  add    $0x8,%rcx
  add    $0x1,%rax
  test   %rdx,%rdx
  jne    L22
  shl    $0x3,%rax
L3:
  movq   $0x0,0x0(%rbp,%rax,1)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <execv@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x8,%eax
  jmp    L3
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: /bin/grep

assistant: ```c
int grep(char *grep_args[]) {
  int i;
  char **new_args;
  new_args = (char **)malloc(sizeof(char *) * (sizeof(grep_args) + 1));
  new_args[0] = strdup("/bin/grep");
  for (i = 0; grep_args[i]; i++)
    new_args[i + 1] = grep_args[i];
  new_args[i + 1] = NULL;
  execv("/bin/grep", new_args);
  free(new_args);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fl_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L17
  mov    $0x0,%eax
  jmp    L7
L17:
  mov    $0x1,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int fl_(int *const l) {

  if ((*l))
    return (0);
  else
    return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fl_>:
  endbr64
  cmpl   $0x0,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int fl_(int *const l) {

  if ((*l))
    return (0);
  else
    return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fl_>:
  endbr64
  mov    (%rdi),%edx
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  ret
```

assistant: ```c
int fl_(int *const l) {

  if ((*l))
    return (0);
  else
    return (1);
}
```
user: What is the c source code of the assembly code below?

```asm
<fl_>:
  endbr64
  mov    (%rdi),%edx
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  ret
```

assistant: ```c
int fl_(int *const l) {

  if ((*l))
    return (0);
  else
    return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<configure>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <load_if@plt>
  mov    $0x0,%eax
  call   <load_db@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void configure(void) {
  load_if();
  load_db();
}
```
user: Translate the below assembly code into C programming language:

```asm
<configure>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <load_if@plt>
  mov    $0x0,%eax
  call   <load_db@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void configure(void) {
  load_if();
  load_db();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<configure>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <load_if@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <load_db@plt>
```

assistant: ```c
void configure(void) {
  load_if();
  load_db();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<more_params>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ignore_ws@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int more_params(char **c) {
  ignore_ws(c);
  return (**c) != 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<more_params>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ignore_ws@plt>
  mov    (%rbx),%rax
  cmpb   $0x0,(%rax)
  setne  %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int more_params(char **c) {
  ignore_ws(c);
  return (**c) != 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<more_params>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ignore_ws@plt>
  mov    (%rbx),%rax
  pop    %rbx
  cmpb   $0x0,(%rax)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int more_params(char **c) {
  ignore_ws(c);
  return (**c) != 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<more_params>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ignore_ws@plt>
  mov    (%rbx),%rax
  pop    %rbx
  cmpb   $0x0,(%rax)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int more_params(char **c) {
  ignore_ws(c);
  return (**c) != 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L4:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L29
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L21
L29:
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl %al,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L17:
  cmpl   $0x1f,-0x14(%rbp)
  jle    L4
  mov    -0x10(%rbp),%rax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D8: %02x

tool: D9: hash parsing error


assistant: ```c
uint8_t *parse_hash(const char *input) {
  uint8_t *r = (uint8_t *)malloc(sizeof(uint8_t) * 32);
  for (int i = 0; i < 32; i++) {
    unsigned tmp;
    if (sscanf(input + 2 * i, "%02x", &tmp) != 1) {
      printf("hash parsing error\n");
      return NULL;
    }
    r[i] = tmp & 0xff;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_hash>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x80,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %r12,%rbx
  mov    %rax,%rbp
  add    $0x40,%r12
  lea    D19(%rip),%r13
L25:
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L22
  movzbl 0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  add    $0x2,%rbx
  add    $0x4,%rbp
  cmp    %r12,%rbx
  jne    L25
  jmp    L14
L22:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%r14d
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    %r14,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D3
data_type: string

tool: D19: %02x

tool: D3: hash parsing error


assistant: ```c
uint8_t *parse_hash(const char *input) {
  uint8_t *r = (uint8_t *)malloc(sizeof(uint8_t) * 32);
  for (int i = 0; i < 32; i++) {
    unsigned tmp;
    if (sscanf(input + 2 * i, "%02x", &tmp) != 1) {
      printf("hash parsing error\n");
      return NULL;
    }
    r[i] = tmp & 0xff;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_hash>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x80,%edi
  lea    0x40(%rbx),%r15
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rbp
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L24:
  movzbl 0x4(%rsp),%eax
  add    $0x2,%rbx
  add    $0x4,%rbp
  mov    %eax,-0x4(%rbp)
  cmp    %r15,%rbx
  je     L25
L30:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L24
  lea    D11(%rip),%rdi
  xor    %r14d,%r14d
  call   <printf@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D11
type_guessed: string

tool: D2: %02x

tool: D11: hash parsing error


assistant: ```c
uint8_t *parse_hash(const char *input) {
  uint8_t *r = (uint8_t *)malloc(sizeof(uint8_t) * 32);
  for (int i = 0; i < 32; i++) {
    unsigned tmp;
    if (sscanf(input + 2 * i, "%02x", &tmp) != 1) {
      printf("hash parsing error\n");
      return NULL;
    }
    r[i] = tmp & 0xff;
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parse_hash>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x80,%edi
  lea    0x40(%rbx),%r15
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rax,%rbp
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl 0x4(%rsp),%eax
  add    $0x2,%rbx
  add    $0x4,%rbp
  mov    %eax,-0x4(%rbp)
  cmp    %r15,%rbx
  je     L10
L26:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L12
  lea    D10(%rip),%rdi
  xor    %r14d,%r14d
  call   <printf@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D19
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string

tool: D19: %02x

tool: D10: hash parsing error


assistant: ```c
uint8_t *parse_hash(const char *input) {
  uint8_t *r = (uint8_t *)malloc(sizeof(uint8_t) * 32);
  for (int i = 0; i < 32; i++) {
    unsigned tmp;
    if (sscanf(input + 2 * i, "%02x", &tmp) != 1) {
      printf("hash parsing error\n");
      return NULL;
    }
    r[i] = tmp & 0xff;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<count_bitarray_AND4_SSE2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    %edx,%eax
  mov    %eax,%edi
  call   <bitcount_SSE2@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x7ffff,-0x4(%rbp)
  jle    L1
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t count_bitarray_AND4_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C, uint32_t *restrict D) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  D = __builtin_assume_aligned(D, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i] & D[i]);
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<count_bitarray_AND4_SSE2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    $0x10,%esi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r15
  mov    $0x10,%esi
  mov    %r12,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r14
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r13
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L4:
  mov    (%r15,%rbx,1),%edi
  and    (%r14,%rbx,1),%edi
  and    0x0(%r13,%rbx,1),%edi
  and    (%r12,%rbx,1),%edi
  call   <bitcount_SSE2@plt>
  add    %eax,%ebp
  add    $0x4,%rbx
  cmp    $0x200000,%rbx
  jne    L4
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint32_t count_bitarray_AND4_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C, uint32_t *restrict D) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  D = __builtin_assume_aligned(D, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i] & D[i]);
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count_bitarray_AND4_SSE2>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0x10,%esi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <__builtin_assume_aligned@plt>
  mov    %r13,%rdi
  mov    $0x10,%esi
  mov    %rax,%r14
  call   <__builtin_assume_aligned@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  mov    %rax,%r13
  call   <__builtin_assume_aligned@plt>
  mov    %r12,%rdi
  mov    $0x10,%esi
  xor    %r12d,%r12d
  mov    %rax,%rbp
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbx
  xchg   %ax,%ax
L8:
  mov    (%r14,%r15,1),%edi
  and    0x0(%r13,%r15,1),%edi
  and    0x0(%rbp,%r15,1),%edi
  and    (%rbx,%r15,1),%edi
  add    $0x4,%r15
  call   <bitcount_SSE2@plt>
  add    %eax,%r12d
  cmp    $0x200000,%r15
  jne    L8
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint32_t count_bitarray_AND4_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C, uint32_t *restrict D) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  D = __builtin_assume_aligned(D, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i] & D[i]);
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<count_bitarray_AND4_SSE2>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    $0x10,%esi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <__builtin_assume_aligned@plt>
  mov    %r13,%rdi
  mov    $0x10,%esi
  mov    %rax,%r14
  call   <__builtin_assume_aligned@plt>
  mov    %rbp,%rdi
  mov    $0x10,%esi
  mov    %rax,%r13
  call   <__builtin_assume_aligned@plt>
  mov    %r12,%rdi
  mov    $0x10,%esi
  xor    %r12d,%r12d
  mov    %rax,%rbp
  call   <__builtin_assume_aligned@plt>
  mov    %rax,%rbx
  xchg   %ax,%ax
L9:
  mov    (%r14,%r15,1),%edi
  and    0x0(%r13,%r15,1),%edi
  and    0x0(%rbp,%r15,1),%edi
  and    (%rbx,%r15,1),%edi
  add    $0x4,%r15
  call   <bitcount_SSE2@plt>
  add    %eax,%r12d
  cmp    $0x200000,%r15
  jne    L9
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint32_t count_bitarray_AND4_SSE2(uint32_t *restrict A, uint32_t *restrict B, uint32_t *restrict C, uint32_t *restrict D) {
  A = __builtin_assume_aligned(A, 16);
  B = __builtin_assume_aligned(B, 16);
  C = __builtin_assume_aligned(C, 16);
  D = __builtin_assume_aligned(D, 16);
  uint32_t count = 0;
  for (uint32_t i = 0; i < (1 << 19); i++) {
    count += bitcount_SSE2(A[i] & B[i] & C[i] & D[i]);
  }
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CLOCK_SYS_GetCrcFreq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <CLOCK_SYS_GetBusClockFreq@plt>
  leave
  ret
```

assistant: ```c
uint32_t CLOCK_SYS_GetCrcFreq(uint32_t instance) {
  (void)instance;
  return CLOCK_SYS_GetBusClockFreq();
}
```