ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<Msystem>:
  endbr64
  test   %edi,%edi
  jle    L0
  movslq (%rsi),%rdi
  jmp    1070 <system@plt>
L0:
  sub    $0x8,%rsp
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Msystem(int nargs, int *argsv) {
  if (nargs < 1) {
    eset(21);
    return -1;
  }
  char *cmd = (char *)argsv[0];
  return system(cmd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f_acc_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f_acc_data(void) {
#pragma acc data
  {
    int i;
#pragma omp atomic write
    i = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f_acc_data>:
  endbr64
  ret
```

assistant: ```c
void f_acc_data(void) {
#pragma acc data
  {
    int i;
#pragma omp atomic write
    i = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f_acc_data>:
  endbr64
  ret
```

assistant: ```c
void f_acc_data(void) {
#pragma acc data
  {
    int i;
#pragma omp atomic write
    i = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f_acc_data>:
  endbr64
  ret
```

assistant: ```c
void f_acc_data(void) {
#pragma acc data
  {
    int i;
#pragma omp atomic write
    i = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string

tool: D6: Hello, World.


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  i++;
  printf("Hello, World.\n");
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: Hello, World.


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  i++;
  printf("Hello, World.\n");
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: string

tool: D8: Hello, World.


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  i++;
  printf("Hello, World.\n");
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: Hello, World.


assistant: ```c
int main(int argc, char **argv) {
  int i = 0;
  i++;
  printf("Hello, World.\n");
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitPrint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <btostr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: %s 

assistant: ```c
void bitPrint(unsigned int n, int numBits) {
  char *tmp;
  printf("%s ", tmp = btostr(n, numBits));
  free(tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitPrint>:
  endbr64
  push   %rbx
  call   <btostr@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type: string

tool: D0: %s 

assistant: ```c
void bitPrint(unsigned int n, int numBits) {
  char *tmp;
  printf("%s ", tmp = btostr(n, numBits));
  free(tmp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitPrint>:
  endbr64
  push   %rbp
  call   <btostr@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
datatype: string

tool: D0: %s 

assistant: ```c
void bitPrint(unsigned int n, int numBits) {
  char *tmp;
  printf("%s ", tmp = btostr(n, numBits));
  free(tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitPrint>:
  endbr64
  push   %rbp
  call   <btostr@plt>
  lea    D8(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string

tool: D8: %s 

assistant: ```c
void bitPrint(unsigned int n, int numBits) {
  char *tmp;
  printf("%s ", tmp = btostr(n, numBits));
  free(tmp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L1
L9:
  mov    -0x8(%rbp),%rax
  movl   $0x2,(%rax)
L1:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int f() {
  int x = 1;
  int *p = (int *)malloc(sizeof(int));
  if (x > 0) {
    *p = x;
  } else {
    *p = 2;
  }
  return *p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f() {
  int x = 1;
  int *p = (int *)malloc(sizeof(int));
  if (x > 0) {
    *p = x;
  } else {
    *p = 2;
  }
  return *p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f() {
  int x = 1;
  int *p = (int *)malloc(sizeof(int));
  if (x > 0) {
    *p = x;
  } else {
    *p = 2;
  }
  return *p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f() {
  int x = 1;
  int *p = (int *)malloc(sizeof(int));
  if (x > 0) {
    *p = x;
  } else {
    *p = 2;
  }
  return *p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L26:
  addl   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *_strcat(char *dest, char *src) {
  int i, j;
  for (i = 0; dest[i]; i++)
    ;
  for (j = 0; src[j]; j++, i++)
    dest[i] = src[j];
  dest[i] = '\0';
  return (dest);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_strcat>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%edx
L24:
  mov    %edx,%r8d
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rax,%rdx,1)
  jne    L24
L29:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L32
  lea    0x1(%r8),%edx
  movslq %edx,%rdx
  movslq %r8d,%r8
  sub    %r8,%rsi
L13:
  mov    %cl,-0x1(%rax,%rdx,1)
  mov    %edx,%r8d
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L13
L32:
  movslq %r8d,%r8
  movb   $0x0,(%rax,%r8,1)
  ret
L9:
  mov    $0x0,%r8d
  jmp    L29
```

assistant: ```c
char *_strcat(char *dest, char *src) {
  int i, j;
  for (i = 0; dest[i]; i++)
    ;
  for (j = 0; src[j]; j++, i++)
    dest[i] = src[j];
  dest[i] = '\0';
  return (dest);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L9
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L7:
  lea    (%rcx,%rdx,1),%edi
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L7
L16:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L18
  lea    0x1(%rdi),%edx
  movslq %edi,%rdi
  movslq %edx,%rdx
  sub    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%r8
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L45
  add    %rax,%r8
L18:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L9:
  mov    %rdi,%r8
  xor    %edi,%edi
  jmp    L16
```

assistant: ```c
char *_strcat(char *dest, char *src) {
  int i, j;
  for (i = 0; dest[i]; i++)
    ;
  for (j = 0; src[j]; j++, i++)
    dest[i] = src[j];
  dest[i] = '\0';
  return (dest);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L27
  mov    %edi,%ecx
  lea    0x1(%rdi),%rdx
  neg    %ecx
  nopl   0x0(%rax)
L40:
  lea    (%rcx,%rdx,1),%edi
  mov    %rdx,%r8
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L40
L30:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L34
  lea    0x1(%rdi),%edx
  movslq %edi,%rdi
  movslq %edx,%rdx
  sub    %rdi,%rsi
  nopl   0x0(%rax,%rax,1)
L48:
  mov    %cl,-0x1(%rax,%rdx,1)
  movslq %edx,%r8
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  test   %cl,%cl
  jne    L48
  add    %rax,%r8
L34:
  movb   $0x0,(%r8)
  ret
  nopl   0x0(%rax)
L27:
  mov    %rdi,%r8
  xor    %edi,%edi
  jmp    L30
```

assistant: ```c
char *_strcat(char *dest, char *src) {
  int i, j;
  for (i = 0; dest[i]; i++)
    ;
  for (j = 0; src[j]; j++, i++)
    dest[i] = src[j];
  dest[i] = '\0';
  return (dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GenJumpIfNotZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf2@plt>
  mov    -0x4(%rbp),%eax
  push   %rax
  push   $0x82
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0x22,%edi
  call   <GenPrintInstr3Operands@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1:  # JumpIfNotZero


assistant: ```c
void GenJumpIfNotZero(int label) {
  printf2(" # JumpIfNotZero\n");
  GenPrintInstr3Operands(0x22, 0, 0x02, 0, 0x00, 0, 0x82, label);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GenJumpIfNotZero>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D7(%rip),%rdi
  call   <printf2@plt>
  push   %rbx
  push   $0x82
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0x22,%edi
  call   <GenPrintInstr3Operands@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7:  # JumpIfNotZero


assistant: ```c
void GenJumpIfNotZero(int label) {
  printf2(" # JumpIfNotZero\n");
  GenPrintInstr3Operands(0x22, 0, 0x02, 0, 0x00, 0, 0x82, label);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GenJumpIfNotZero>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D0(%rip),%rdi
  call   <printf2@plt>
  push   %rbx
  mov    $0x2,%edx
  xor    %r9d,%r9d
  push   $0x82
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0x22,%edi
  call   <GenPrintInstr3Operands@plt>
  pop    %rax
  pop    %rdx
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0:  # JumpIfNotZero


assistant: ```c
void GenJumpIfNotZero(int label) {
  printf2(" # JumpIfNotZero\n");
  GenPrintInstr3Operands(0x22, 0, 0x02, 0, 0x00, 0, 0x82, label);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<GenJumpIfNotZero>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D9(%rip),%rdi
  call   <printf2@plt>
  push   %rbx
  mov    $0x2,%edx
  xor    %r9d,%r9d
  push   $0x82
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0x22,%edi
  call   <GenPrintInstr3Operands@plt>
  pop    %rax
  pop    %rdx
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9:  # JumpIfNotZero


assistant: ```c
void GenJumpIfNotZero(int label) {
  printf2(" # JumpIfNotZero\n");
  GenPrintInstr3Operands(0x22, 0, 0x02, 0, 0x00, 0, 0x82, label);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<zfile_put_contents>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L69
L100:
  nop
L69:
  mov    D79(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1ff,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L12
  mov    D63(%rip),%rax
  mov    (%rax),%edx
  mov    D83(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L100
L12:
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L6
  mov    $0xffffffff,%eax
  jmp    L49
L35:
  mov    -0x24(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0xc(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L90
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  jmp    L6
L90:
  mov    D63(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    D63(%rip),%rax
  mov    (%rax),%edx
  mov    D83(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L88
  jmp    L6
L88:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    D63(%rip),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L49
L6:
  mov    -0x24(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L35
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x1,%eax
L49:
  leave
  ret
```

assistant: ```c
int zfile_put_contents(const char *pathname, const void *data, int len) {
  int fd;
  int ret;
  int wlen = 0;
  int errno2;
  while (((fd = open(pathname, O_CREAT | O_RDWR | O_TRUNC, 0777)) == -1) && (errno == EINTR)) {
    continue;
  }
  if (fd == -1) {
    return -1;
  }
  while (len > wlen) {
    ret = write(fd, (const char *)data + wlen, len - wlen);
    if (ret > -1) {
      wlen += ret;
      continue;
    }
    errno2 = errno;
    if (errno == EINTR) {
      continue;
    }
    close(fd);
    errno = errno2;
    return -1;
  }
  close(fd);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zfile_put_contents>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    D17(%rip),%r14
L42:
  mov    (%r14),%esi
  mov    D40(%rip),%rax
  or     (%rax),%esi
  mov    D0(%rip),%rax
  or     (%rax),%esi
  mov    $0x1ff,%edx
  mov    %r13,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L45
  mov    D53(%rip),%rdx
  mov    D68(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  je     L42
L67:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L45:
  test   %ebp,%ebp
  jle    L63
  mov    $0x0,%r13d
  jmp    L18
L30:
  add    %eax,%r13d
L15:
  cmp    %ebp,%r13d
  jge    L63
L18:
  mov    %ebp,%edx
  sub    %r13d,%edx
  movslq %r13d,%rsi
  add    %r12,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L30
  mov    D53(%rip),%rax
  mov    (%rax),%r14d
  mov    D68(%rip),%rax
  cmp    %r14d,(%rax)
  je     L15
  mov    %ebx,%edi
  call   <close@plt>
  mov    D53(%rip),%rax
  mov    %r14d,(%rax)
  mov    $0xffffffff,%ebx
  jmp    L67
L63:
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x1,%ebx
  jmp    L67
```

assistant: ```c
int zfile_put_contents(const char *pathname, const void *data, int len) {
  int fd;
  int ret;
  int wlen = 0;
  int errno2;
  while (((fd = open(pathname, O_CREAT | O_RDWR | O_TRUNC, 0777)) == -1) && (errno == EINTR)) {
    continue;
  }
  if (fd == -1) {
    return -1;
  }
  while (len > wlen) {
    ret = write(fd, (const char *)data + wlen, len - wlen);
    if (ret > -1) {
      wlen += ret;
      continue;
    }
    errno2 = errno;
    if (errno == EINTR) {
      continue;
    }
    close(fd);
    errno = errno2;
    return -1;
  }
  close(fd);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zfile_put_contents>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  mov    D30(%rip),%r15
  mov    D23(%rip),%r14
L66:
  mov    D32(%rip),%rax
  mov    (%r15),%esi
  mov    $0x1ff,%edx
  mov    %r13,%rdi
  or     (%r14),%esi
  or     (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  jne    L16
  mov    D38(%rip),%rax
  mov    D17(%rip),%rdx
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  je     L66
L7:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r13d,%r13d
  test   %ebx,%ebx
  jle    L75
  nop
L68:
  mov    %ebx,%edx
  movslq %r13d,%rsi
  mov    %r12d,%edi
  sub    %r13d,%edx
  add    %rbp,%rsi
  call   <write@plt>
  test   %eax,%eax
  jns    L51
  mov    D17(%rip),%r14
  mov    D38(%rip),%rax
  mov    (%r14),%r15d
  cmp    %r15d,(%rax)
  je     L35
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  mov    %r15d,(%r14)
  jmp    L7
L51:
  add    %eax,%r13d
L35:
  cmp    %ebx,%r13d
  jl     L68
L75:
  mov    %r12d,%edi
  mov    $0x1,%r12d
  call   <close@plt>
  jmp    L7
```

assistant: ```c
int zfile_put_contents(const char *pathname, const void *data, int len) {
  int fd;
  int ret;
  int wlen = 0;
  int errno2;
  while (((fd = open(pathname, O_CREAT | O_RDWR | O_TRUNC, 0777)) == -1) && (errno == EINTR)) {
    continue;
  }
  if (fd == -1) {
    return -1;
  }
  while (len > wlen) {
    ret = write(fd, (const char *)data + wlen, len - wlen);
    if (ret > -1) {
      wlen += ret;
      continue;
    }
    errno2 = errno;
    if (errno == EINTR) {
      continue;
    }
    close(fd);
    errno = errno2;
    return -1;
  }
  close(fd);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zfile_put_contents>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  mov    D4(%rip),%r15
  mov    D52(%rip),%r14
L47:
  mov    D10(%rip),%rax
  mov    (%r15),%esi
  mov    $0x1ff,%edx
  mov    %r13,%rdi
  or     (%r14),%esi
  or     (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  jne    L71
  mov    D37(%rip),%rax
  mov    D2(%rip),%rdx
  mov    (%rax),%eax
  cmp    %eax,(%rdx)
  je     L47
L49:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  xor    %r13d,%r13d
  test   %ebx,%ebx
  jle    L48
  nop
L13:
  mov    %ebx,%edx
  movslq %r13d,%rsi
  mov    %r12d,%edi
  sub    %r13d,%edx
  add    %rbp,%rsi
  call   <write@plt>
  test   %eax,%eax
  jns    L67
  mov    D2(%rip),%r14
  mov    D37(%rip),%rax
  mov    (%r14),%r15d
  cmp    %r15d,(%rax)
  je     L12
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  mov    %r15d,(%r14)
  jmp    L49
L67:
  add    %eax,%r13d
L12:
  cmp    %ebx,%r13d
  jl     L13
L48:
  mov    %r12d,%edi
  mov    $0x1,%r12d
  call   <close@plt>
  jmp    L49
```

assistant: ```c
int zfile_put_contents(const char *pathname, const void *data, int len) {
  int fd;
  int ret;
  int wlen = 0;
  int errno2;
  while (((fd = open(pathname, O_CREAT | O_RDWR | O_TRUNC, 0777)) == -1) && (errno == EINTR)) {
    continue;
  }
  if (fd == -1) {
    return -1;
  }
  while (len > wlen) {
    ret = write(fd, (const char *)data + wlen, len - wlen);
    if (ret > -1) {
      wlen += ret;
      continue;
    }
    errno2 = errno;
    if (errno == EINTR) {
      continue;
    }
    close(fd);
    errno = errno2;
    return -1;
  }
  close(fd);
  return 1;
}
```