ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CalcConDelay>:
  endbr64
  mov    $0xa,%eax
  cmp    $0x3,%edi
  jle    L6
  mov    %edi,%eax
  imul   %edi,%eax
L6:
  ret
```

assistant: ```c
int CalcConDelay(int attempt) {
  if (attempt <= 3)
    return (10);
  return (attempt * attempt);
}
```
user: What is the c source code of the assembly code below?

```asm
<clamp_8bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xff,-0x4(%rbp)
  jle    L31
  mov    $0xff,%eax
  jmp    L36
L31:
  cmpl   $0x0,-0x4(%rbp)
  jns    L6
  mov    $0x0,%eax
  jmp    L36
L6:
  mov    -0x4(%rbp),%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t clamp_8bit(int val) {
  if (val > 255)
    return 255;
  else if (val < 0)
    return 0;
  else
    return (uint8_t)val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<clamp_8bit>:
  endbr64
  test   %edi,%edi
  mov    $0x0,%eax
  cmovns %edi,%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint8_t clamp_8bit(int val) {
  if (val > 255)
    return 255;
  else if (val < 0)
    return 0;
  else
    return (uint8_t)val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clamp_8bit>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  mov    $0xff,%edx
  cmovns %edi,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint8_t clamp_8bit(int val) {
  if (val > 255)
    return 255;
  else if (val < 0)
    return 0;
  else
    return (uint8_t)val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clamp_8bit>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  mov    $0xff,%edx
  cmovns %edi,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
```

assistant: ```c
uint8_t clamp_8bit(int val) {
  if (val > 255)
    return 255;
  else if (val < 0)
    return 0;
  else
    return (uint8_t)val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<save_bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D1: wb

assistant: ```c
void save_bin(const char *file_name, float *rst, int num) {
  FILE *fp = fopen(file_name, "wb");
  fwrite(rst, num, sizeof(float), fp);
  fclose(fp);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<save_bin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rcx
  mov    $0x4,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <fwrite@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: wb

assistant: ```c
void save_bin(const char *file_name, float *rst, int num) {
  FILE *fp = fopen(file_name, "wb");
  fwrite(rst, num, sizeof(float), fp);
  fclose(fp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<save_bin>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  lea    D2(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %r13d,%esi
  mov    $0x4,%edx
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <fclose@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2: wb

assistant: ```c
void save_bin(const char *file_name, float *rst, int num) {
  FILE *fp = fopen(file_name, "wb");
  fwrite(rst, num, sizeof(float), fp);
  fclose(fp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<save_bin>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  mov    %r12,%rdi
  mov    %r13d,%esi
  mov    $0x4,%edx
  mov    %rax,%rbp
  mov    %rax,%rcx
  call   <fwrite@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <fclose@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D3: wb

assistant: ```c
void save_bin(const char *file_name, float *rst, int num) {
  FILE *fp = fopen(file_name, "wb");
  fwrite(rst, num, sizeof(float), fp);
  fclose(fp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Hardware_Init@plt>
  mov    $0x0,%eax
  call   <Library_Init@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  Hardware_Init();
  Library_Init();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Hardware_Init@plt>
  mov    $0x0,%eax
  call   <Library_Init@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  Hardware_Init();
  Library_Init();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Hardware_Init@plt>
  xor    %eax,%eax
  call   <Library_Init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  Hardware_Init();
  Library_Init();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Hardware_Init@plt>
  xor    %eax,%eax
  call   <Library_Init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  Hardware_Init();
  Library_Init();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: _POSIX_CPUTIME unsupported


assistant: ```c
int main(void) {
  printf("_POSIX_CPUTIME unsupported\n");
  return 4;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: _POSIX_CPUTIME unsupported


assistant: ```c
int main(void) {
  printf("_POSIX_CPUTIME unsupported\n");
  return 4;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_infered: string

tool: D5: _POSIX_CPUTIME unsupported


assistant: ```c
int main(void) {
  printf("_POSIX_CPUTIME unsupported\n");
  return 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: _POSIX_CPUTIME unsupported


assistant: ```c
int main(void) {
  printf("_POSIX_CPUTIME unsupported\n");
  return 4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x30(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x30(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x15180,-0x28(%rbp)
  movl   $0xe10,-0x24(%rbp)
  movl   $0x3c,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x28(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <time_conv@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x24(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <time_conv@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    -0x20(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <time_conv@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D8
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D0: %ld

tool: D8: There are %d days %d hours %d minutes and %d seconds

tool: D2:  left before Fall Break!!!

assistant: ```c
int main(void) {
  time_t countdown, day, hour, minute, now;
  int val, num_days, num_hours, num_minutes, num_seconds, s;
  now = time(0);
  s = scanf("%ld", &countdown);
  countdown = countdown - now;
  day = 24 * 60 * 60;
  hour = 60 * 60;
  minute = 60;
  val = time_conv(countdown, day);
  num_days = val;
  countdown = countdown - val * day;
  val = time_conv(countdown, hour);
  num_hours = val;
  countdown = countdown - val * hour;
  val = time_conv(countdown, minute);
  num_minutes = val;
  countdown = countdown - val * minute;
  num_seconds = countdown;
  printf("There are %d days %d hours %d minutes and %d seconds", num_days, num_hours, num_minutes, num_seconds);
  printf(" left before Fall Break!!!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  sub    %ebx,%edi
  mov    %edi,0x4(%rsp)
  mov    $0x15180,%esi
  call   <time_conv@plt>
  mov    %eax,%ebx
  imul   $0xfffeae80,%eax,%edi
  add    0x4(%rsp),%edi
  mov    %edi,0x4(%rsp)
  mov    $0xe10,%esi
  call   <time_conv@plt>
  mov    %eax,%ebp
  imul   $0xfffff1f0,%eax,%edi
  add    0x4(%rsp),%edi
  mov    %edi,0x4(%rsp)
  mov    $0x3c,%esi
  call   <time_conv@plt>
  mov    %eax,%ecx
  imul   $0xffffffc4,%eax,%r8d
  add    0x4(%rsp),%r8d
  mov    %r8d,0x4(%rsp)
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D15
type_guessed: string

tool: D11: %ld

tool: D22: There are %d days %d hours %d minutes and %d seconds

tool: D15:  left before Fall Break!!!

assistant: ```c
int main(void) {
  time_t countdown, day, hour, minute, now;
  int val, num_days, num_hours, num_minutes, num_seconds, s;
  now = time(0);
  s = scanf("%ld", &countdown);
  countdown = countdown - now;
  day = 24 * 60 * 60;
  hour = 60 * 60;
  minute = 60;
  val = time_conv(countdown, day);
  num_days = val;
  countdown = countdown - val * day;
  val = time_conv(countdown, hour);
  num_hours = val;
  countdown = countdown - val * hour;
  val = time_conv(countdown, minute);
  num_minutes = val;
  countdown = countdown - val * minute;
  num_seconds = countdown;
  printf("There are %d days %d hours %d minutes and %d seconds", num_days, num_hours, num_minutes, num_seconds);
  printf(" left before Fall Break!!!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  mov    %eax,%ebp
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x15180,%esi
  sub    %ebp,%edi
  mov    %edi,0x4(%rsp)
  call   <time_conv@plt>
  mov    $0xe10,%esi
  imul   $0xfffeae80,%eax,%edi
  add    0x4(%rsp),%edi
  mov    %eax,%ebp
  mov    %edi,0x4(%rsp)
  call   <time_conv@plt>
  mov    $0x3c,%esi
  imul   $0xfffff1f0,%eax,%edi
  add    0x4(%rsp),%edi
  mov    %eax,%r12d
  mov    %edi,0x4(%rsp)
  call   <time_conv@plt>
  lea    D28(%rip),%rdi
  mov    %r12d,%edx
  mov    %ebp,%esi
  imul   $0xffffffc4,%eax,%r8d
  mov    %eax,%ecx
  add    0x4(%rsp),%r8d
  xor    %eax,%eax
  mov    %r8d,0x4(%rsp)
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string
name: retrieve_data
arguments: data_label: D28
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string

tool: D8: %ld

tool: D28: There are %d days %d hours %d minutes and %d seconds

tool: D20:  left before Fall Break!!!

assistant: ```c
int main(void) {
  time_t countdown, day, hour, minute, now;
  int val, num_days, num_hours, num_minutes, num_seconds, s;
  now = time(0);
  s = scanf("%ld", &countdown);
  countdown = countdown - now;
  day = 24 * 60 * 60;
  hour = 60 * 60;
  minute = 60;
  val = time_conv(countdown, day);
  num_days = val;
  countdown = countdown - val * day;
  val = time_conv(countdown, hour);
  num_hours = val;
  countdown = countdown - val * hour;
  val = time_conv(countdown, minute);
  num_minutes = val;
  countdown = countdown - val * minute;
  num_seconds = countdown;
  printf("There are %d days %d hours %d minutes and %d seconds", num_days, num_hours, num_minutes, num_seconds);
  printf(" left before Fall Break!!!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  mov    %eax,%ebp
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x15180,%esi
  sub    %ebp,%edi
  mov    %edi,0x4(%rsp)
  call   <time_conv@plt>
  mov    $0xe10,%esi
  imul   $0xfffeae80,%eax,%edi
  add    0x4(%rsp),%edi
  mov    %eax,%ebp
  mov    %edi,0x4(%rsp)
  call   <time_conv@plt>
  mov    $0x3c,%esi
  imul   $0xfffff1f0,%eax,%edi
  add    0x4(%rsp),%edi
  mov    %eax,%r12d
  mov    %edi,0x4(%rsp)
  call   <time_conv@plt>
  lea    D0(%rip),%rdi
  mov    %r12d,%edx
  mov    %ebp,%esi
  imul   $0xffffffc4,%eax,%r8d
  mov    %eax,%ecx
  add    0x4(%rsp),%r8d
  xor    %eax,%eax
  mov    %r8d,0x4(%rsp)
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D0
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string

tool: D25: %ld

tool: D0: There are %d days %d hours %d minutes and %d seconds

tool: D10:  left before Fall Break!!!

assistant: ```c
int main(void) {
  time_t countdown, day, hour, minute, now;
  int val, num_days, num_hours, num_minutes, num_seconds, s;
  now = time(0);
  s = scanf("%ld", &countdown);
  countdown = countdown - now;
  day = 24 * 60 * 60;
  hour = 60 * 60;
  minute = 60;
  val = time_conv(countdown, day);
  num_days = val;
  countdown = countdown - val * day;
  val = time_conv(countdown, hour);
  num_hours = val;
  countdown = countdown - val * hour;
  val = time_conv(countdown, minute);
  num_minutes = val;
  countdown = countdown - val * minute;
  num_seconds = countdown;
  printf("There are %d days %d hours %d minutes and %d seconds", num_days, num_hours, num_minutes, num_seconds);
  printf(" left before Fall Break!!!\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getroot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  call   <prepare_kernel_cred@plt>
  mov    %eax,%edi
  call   <commit_creds@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __attribute__((regparm(3))) getroot(void *file, void *vma) {
  commit_creds(prepare_kernel_cred(0));
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getroot>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <prepare_kernel_cred@plt>
  mov    %eax,%edi
  call   <commit_creds@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __attribute__((regparm(3))) getroot(void *file, void *vma) {
  commit_creds(prepare_kernel_cred(0));
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getroot>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <prepare_kernel_cred@plt>
  mov    %eax,%edi
  call   <commit_creds@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __attribute__((regparm(3))) getroot(void *file, void *vma) {
  commit_creds(prepare_kernel_cred(0));
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getroot>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <prepare_kernel_cred@plt>
  mov    %eax,%edi
  call   <commit_creds@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __attribute__((regparm(3))) getroot(void *file, void *vma) {
  commit_creds(prepare_kernel_cred(0));
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <hextrlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L34
L62:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  sub    $0xa,%eax
  cmp    $0x5,%eax
  ja     L89
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D17(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D17(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x41,(%rax)
  jmp    L95
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x42,(%rax)
  jmp    L95
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x43,(%rax)
  jmp    L95
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x44,(%rax)
  jmp    L95
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x45,(%rax)
  jmp    L95
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x46,(%rax)
  jmp    L95
L89:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  nop
L95:
  addl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x14(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L62
  movl   $0x0,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L80
L86:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L69
  mov    $0xffffffff,%eax
  jmp    L97
L69:
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L80:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jge    L86
  mov    -0x14(%rbp),%eax
L97:
  leave
  ret
```

assistant: ```c
int isPalindrome(int num, char *hex) {
  int len = hextrlen(num);
  for (int i = 0; i < len; i++, num /= 16)
    switch (num % 16) {
    case 10:
      hex[i] = 'A';
      break;
    case 11:
      hex[i] = 'A' + 1;
      break;
    case 12:
      hex[i] = 'A' + 2;
      break;
    case 13:
      hex[i] = 'A' + 3;
      break;
    case 14:
      hex[i] = 'A' + 4;
      break;
    case 15:
      hex[i] = 'A' + 5;
      break;
    default:
      hex[i] = (num % 16) + 48;
      break;
    }
  for (int i = 0, j = len - 1; j >= len / 2; i++, j--) {
    if (hex[i] != hex[j])
      return -1;
  }
  return num;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  call   <hextrlen@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  jle    L52
  mov    %rbx,%rsi
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%r9
  mov    %ebp,%eax
  lea    D6(%rip),%rdi
  jmp    L73
  movb   $0x41,(%rsi)
L31:
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  add    $0x1,%rsi
  cmp    %r9,%rsi
  je     L71
L73:
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1c,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0xf,%edx
  sub    %ecx,%edx
  lea    -0xa(%rdx),%ecx
  cmp    $0x5,%ecx
  ja     L70
  mov    %ecx,%ecx
  movslq (%rdi,%rcx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  movb   $0x42,(%rsi)
  jmp    L31
  movb   $0x43,(%rsi)
  jmp    L31
  movb   $0x44,(%rsi)
  jmp    L31
  movb   $0x45,(%rsi)
  jmp    L31
  movb   $0x46,(%rsi)
  jmp    L31
L70:
  add    $0x30,%edx
  mov    %dl,(%rsi)
  jmp    L31
L52:
  mov    %ebp,%eax
L71:
  lea    -0x1(%r8),%edx
  mov    %r8d,%esi
  shr    $0x1f,%esi
  add    %r8d,%esi
  sar    %esi
  cmp    %esi,%edx
  jl     L139
  movslq %edx,%rdx
  mov    %rbx,%rcx
L53:
  movzbl (%rbx,%rdx,1),%edi
  cmp    %dil,(%rcx)
  jne    L26
  sub    $0x1,%rdx
  add    $0x1,%rcx
  cmp    %edx,%esi
  jle    L53
  jmp    L139
L26:
  mov    $0xffffffff,%eax
L139:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int isPalindrome(int num, char *hex) {
  int len = hextrlen(num);
  for (int i = 0; i < len; i++, num /= 16)
    switch (num % 16) {
    case 10:
      hex[i] = 'A';
      break;
    case 11:
      hex[i] = 'A' + 1;
      break;
    case 12:
      hex[i] = 'A' + 2;
      break;
    case 13:
      hex[i] = 'A' + 3;
      break;
    case 14:
      hex[i] = 'A' + 4;
      break;
    case 15:
      hex[i] = 'A' + 5;
      break;
    default:
      hex[i] = (num % 16) + 48;
      break;
    }
  for (int i = 0, j = len - 1; j >= len / 2; i++, j--) {
    if (hex[i] != hex[j])
      return -1;
  }
  return num;
}
```