ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L57
L53:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L64:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L29
  movl   $0x1,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x8,%eax
  cmp    %eax,-0x18(%rbp)
  jne    L42
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
  jmp    L29
L42:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L29:
  addl   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L64
  cmpl   $0x0,-0xc(%rbp)
  je     L57
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L57:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fold(char input[], int posic[]) {
  int i, j, coc, tab, pos, estado;
  i = j = estado = 0;
  while (input[i] != '\0') {
    estado = 0;
    coc = (i / 8) + 1;
    tab = 8 * coc;
    while (i < tab) {
      if (input[i] != ' ') {
        estado = 1;
        if (i == tab - 8) {
          pos = i;
          posic[j] = pos;
          ++j;
        } else
          pos = i;
      }
      ++i;
    }
    if (estado) {
      posic[j] = pos;
      ++j;
    }
  }
  return j;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fold>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L40
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%r10d
  mov    $0x0,%eax
  mov    $0x0,%ebp
  mov    $0x1,%r9d
  jmp    L12
L59:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jle    L2
L92:
  cmpb   $0x20,(%rdi,%rax,1)
  je     L59
  mov    %eax,%r8d
  mov    %r9d,%esi
  cmp    %eax,%r11d
  jne    L59
  movslq %r10d,%rsi
  mov    %eax,(%rbx,%rsi,4)
  add    $0x1,%r10d
  mov    %r9d,%esi
  jmp    L59
L2:
  mov    %ecx,%eax
  test   %esi,%esi
  je     L45
  movslq %r10d,%rax
  mov    %r8d,(%rbx,%rax,4)
  add    $0x1,%r10d
  mov    %ecx,%eax
L45:
  movslq %eax,%rdx
  cmpb   $0x0,(%rdi,%rdx,1)
  je     L38
L12:
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovns %eax,%edx
  sar    $0x3,%edx
  lea    0x8(,%rdx,8),%ecx
  cmp    %eax,%ecx
  jle    L45
  cltq
  mov    %ebp,%esi
  lea    -0x8(%rcx),%r11d
  jmp    L92
L40:
  mov    $0x0,%r10d
  mov    %r10d,%eax
  ret
L38:
  mov    %r10d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fold(char input[], int posic[]) {
  int i, j, coc, tab, pos, estado;
  i = j = estado = 0;
  while (input[i] != '\0') {
    estado = 0;
    coc = (i / 8) + 1;
    tab = 8 * coc;
    while (i < tab) {
      if (input[i] != ' ') {
        estado = 1;
        if (i == tab - 8) {
          pos = i;
          posic[j] = pos;
          ++j;
        } else
          pos = i;
      }
      ++i;
    }
    if (estado) {
      posic[j] = pos;
      ++j;
    }
  }
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fold>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L61
  push   %rbp
  xor    %r8d,%r8d
  xor    %r11d,%r11d
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %r11d,%eax
  sar    $0x3,%eax
  lea    0x8(,%rax,8),%ecx
  cmp    %r11d,%ecx
  jle    L82
  movslq %r11d,%rbp
  xor    %r9d,%r9d
  lea    -0x8(%rcx),%esi
  mov    %rbp,%rax
  jmp    L24
L97:
  movzbl (%rdi,%rax,1),%edx
L24:
  cmp    $0x20,%dl
  je     L13
  mov    %eax,%r10d
  mov    $0x1,%r9d
  cmp    %eax,%esi
  jne    L13
  movslq %r8d,%rdx
  add    $0x1,%r8d
  mov    %esi,(%rbx,%rdx,4)
L13:
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L97
  mov    %ecx,%eax
  sub    %r11d,%eax
  sub    $0x1,%eax
  lea    0x1(%rbp,%rax,1),%rax
  add    %rdi,%rax
  test   %r9d,%r9d
  je     L81
  movslq %r8d,%rdx
  add    $0x1,%r8d
  mov    %r10d,(%rbx,%rdx,4)
L81:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L16
L7:
  mov    %ecx,%r11d
  jmp    L34
  nopl   0x0(%rax)
L82:
  mov    %r11d,%ecx
  jmp    L7
  nopl   (%rax)
L16:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
L61:
  xor    %eax,%eax
  ret
```

assistant: ```c
int fold(char input[], int posic[]) {
  int i, j, coc, tab, pos, estado;
  i = j = estado = 0;
  while (input[i] != '\0') {
    estado = 0;
    coc = (i / 8) + 1;
    tab = 8 * coc;
    while (i < tab) {
      if (input[i] != ' ') {
        estado = 1;
        if (i == tab - 8) {
          pos = i;
          posic[j] = pos;
          ++j;
        } else
          pos = i;
      }
      ++i;
    }
    if (estado) {
      posic[j] = pos;
      ++j;
    }
  }
  return j;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fold>:
  endbr64
  xor    %r8d,%r8d
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rcx
  je     L65
  xor    %eax,%eax
  lea    0x8(%rax),%edx
  cmp    %eax,%edx
  jle    L63
  nopl   0x0(%rax,%rax,1)
L70:
  xor    %r9d,%r9d
  lea    -0x8(%rdx),%edi
  cs nopw 0x0(%rax,%rax,1)
L56:
  cmpb   $0x20,(%rcx,%rax,1)
  je     L9
  mov    %eax,%r10d
  mov    $0x1,%r9d
  cmp    %eax,%edi
  jne    L9
  movslq %r8d,%r11
  add    $0x1,%r8d
  mov    %edi,(%rsi,%r11,4)
L9:
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L56
  movslq %edx,%rax
  add    %rcx,%rax
  test   %r9d,%r9d
  je     L67
  movslq %r8d,%rdi
  add    $0x1,%r8d
  mov    %r10d,(%rsi,%rdi,4)
L67:
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  movslq %edx,%rax
  lea    0x8(%rax),%edx
  cmp    %eax,%edx
  jg     L70
L63:
  jmp    L63
  nop
L65:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fold(char input[], int posic[]) {
  int i, j, coc, tab, pos, estado;
  i = j = estado = 0;
  while (input[i] != '\0') {
    estado = 0;
    coc = (i / 8) + 1;
    tab = 8 * coc;
    while (i < tab) {
      if (input[i] != ' ') {
        estado = 1;
        if (i == tab - 8) {
          pos = i;
          posic[j] = pos;
          ++j;
        } else
          pos = i;
      }
      ++i;
    }
    if (estado) {
      posic[j] = pos;
      ++j;
    }
  }
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lgtd_lifx_tagging_decref>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lgtd_lifx_tagging_decref(struct lgtd_lifx_tag *tag, struct lgtd_lifx_gateway *gw) {
  (void)tag;
  (void)gw;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<lgtd_lifx_tagging_decref>:
  endbr64
  ret
```

assistant: ```c
void lgtd_lifx_tagging_decref(struct lgtd_lifx_tag *tag, struct lgtd_lifx_gateway *gw) {
  (void)tag;
  (void)gw;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lgtd_lifx_tagging_decref>:
  endbr64
  ret
```

assistant: ```c
void lgtd_lifx_tagging_decref(struct lgtd_lifx_tag *tag, struct lgtd_lifx_gateway *gw) {
  (void)tag;
  (void)gw;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lgtd_lifx_tagging_decref>:
  endbr64
  ret
```

assistant: ```c
void lgtd_lifx_tagging_decref(struct lgtd_lifx_tag *tag, struct lgtd_lifx_gateway *gw) {
  (void)tag;
  (void)gw;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <svcraw_create@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <svc_destroy@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: %d


assistant: ```c
int main(void) {
  int test_status = 1;
  SVCXPRT *svcr = NULL;
  svcr = svcraw_create();
  test_status = (svcr != NULL) ? 0 : 1;
  svc_destroy(svcr);
  printf("%d\n", test_status);
  return test_status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <svcraw_create@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  sete   %bl
  movzbl %bl,%ebx
  call   <svc_destroy@plt>
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(void) {
  int test_status = 1;
  SVCXPRT *svcr = NULL;
  svcr = svcraw_create();
  test_status = (svcr != NULL) ? 0 : 1;
  svc_destroy(svcr);
  printf("%d\n", test_status);
  return test_status;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <svcraw_create@plt>
  test   %rax,%rax
  mov    %rax,%rdi
  sete   %r12b
  call   <svc_destroy@plt>
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: %d


assistant: ```c
int main(void) {
  int test_status = 1;
  SVCXPRT *svcr = NULL;
  svcr = svcraw_create();
  test_status = (svcr != NULL) ? 0 : 1;
  svc_destroy(svcr);
  printf("%d\n", test_status);
  return test_status;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  xor    %r12d,%r12d
  call   <svcraw_create@plt>
  test   %rax,%rax
  mov    %rax,%rdi
  sete   %r12b
  call   <svc_destroy@plt>
  mov    %r12d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(void) {
  int test_status = 1;
  SVCXPRT *svcr = NULL;
  svcr = svcraw_create();
  test_status = (svcr != NULL) ? 0 : 1;
  svc_destroy(svcr);
  printf("%d\n", test_status);
  return test_status;
}
```
user: Translate the below assembly code into C programming language:

```asm
<decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movabs $0x4f445241554445,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x3c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x38(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L23
L19:
  mov    -0x40(%rbp),%eax
  cltd
  idivl  -0x38(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x40(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <from_hex@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x40(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <from_hex@plt>
  or     %eax,%ebx
  mov    %ebx,%esi
  mov    -0x34(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  mov    -0x40(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  xor    %esi,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x40(%rbp)
L23:
  mov    -0x3c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x40(%rbp)
  jl     L19
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void decrypt(void *input, void *output) {
  char key[] = "EDUARDO";
  char *pinput = (char *)input;
  char *poutput = (char *)output;
  int sinput = strlen(pinput);
  int skey = strlen(key);
  int idx;
  for (idx = 0; idx < sinput / 2; idx++) {
    int pos = idx % skey;
    poutput[idx] = ((from_hex(pinput[idx * 2]) << 4) | from_hex(pinput[idx * 2 + 1])) ^ key[pos];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<decrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x4f445241554445,%rax
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    0x10(%rsp),%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  mov    %ebx,%r14d
  shr    $0x1f,%r14d
  add    %ebx,%r14d
  sar    %r14d
  cmp    $0x1,%ebx
  jle    L8
  mov    $0x0,%ebp
L20:
  mov    %ebp,%eax
  cltd
  idivl  0xc(%rsp)
  mov    %edx,%r12d
  movsbl 0x0(%r13,%rbp,2),%edi
  call   <from_hex@plt>
  mov    %eax,%ebx
  movsbl 0x1(%r13,%rbp,2),%edi
  call   <from_hex@plt>
  shl    $0x4,%ebx
  or     %eax,%ebx
  movslq %r12d,%r12
  xor    0x10(%rsp,%r12,1),%bl
  mov    %bl,(%r15,%rbp,1)
  add    $0x1,%rbp
  cmp    %ebp,%r14d
  jg     L20
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void decrypt(void *input, void *output) {
  char key[] = "EDUARDO";
  char *pinput = (char *)input;
  char *poutput = (char *)output;
  int sinput = strlen(pinput);
  int skey = strlen(key);
  int idx;
  for (idx = 0; idx < sinput / 2; idx++) {
    int pos = idx % skey;
    poutput[idx] = ((from_hex(pinput[idx * 2]) << 4) | from_hex(pinput[idx * 2 + 1])) ^ key[pos];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decrypt>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4f445241554445,%rax
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %ebx,%r14d
  shr    $0x1f,%r14d
  mov    %eax,0xc(%rsp)
  add    %ebx,%r14d
  sar    %r14d
  cmp    $0x1,%ebx
  jle    L12
  xor    %r13d,%r13d
  nop
L19:
  mov    %r13d,%eax
  movsbl (%r12,%r13,2),%edi
  cltd
  idivl  0xc(%rsp)
  movslq %edx,%rbp
  call   <from_hex@plt>
  movsbl 0x1(%r12,%r13,2),%edi
  mov    %eax,%ebx
  call   <from_hex@plt>
  shl    $0x4,%ebx
  or     %eax,%ebx
  xor    0x10(%rsp,%rbp,1),%bl
  mov    %bl,(%r15,%r13,1)
  add    $0x1,%r13
  cmp    %r13d,%r14d
  jg     L19
L12:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void decrypt(void *input, void *output) {
  char key[] = "EDUARDO";
  char *pinput = (char *)input;
  char *poutput = (char *)output;
  int sinput = strlen(pinput);
  int skey = strlen(key);
  int idx;
  for (idx = 0; idx < sinput / 2; idx++) {
    int pos = idx % skey;
    poutput[idx] = ((from_hex(pinput[idx * 2]) << 4) | from_hex(pinput[idx * 2 + 1])) ^ key[pos];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decrypt>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x4f445241554445,%rax
  mov    %rax,0x10(%rsp)
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %ebx,%r14d
  shr    $0x1f,%r14d
  mov    %eax,0xc(%rsp)
  add    %ebx,%r14d
  sar    %r14d
  cmp    $0x1,%ebx
  jle    L15
  xor    %r13d,%r13d
  nop
L11:
  mov    %r13d,%eax
  movsbl (%r12,%r13,2),%edi
  cltd
  idivl  0xc(%rsp)
  movslq %edx,%rbp
  call   <from_hex@plt>
  movsbl 0x1(%r12,%r13,2),%edi
  mov    %eax,%ebx
  call   <from_hex@plt>
  shl    $0x4,%ebx
  or     %eax,%ebx
  xor    0x10(%rsp,%rbp,1),%bl
  mov    %bl,(%r15,%r13,1)
  add    $0x1,%r13
  cmp    %r13d,%r14d
  jg     L11
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void decrypt(void *input, void *output) {
  char key[] = "EDUARDO";
  char *pinput = (char *)input;
  char *poutput = (char *)output;
  int sinput = strlen(pinput);
  int skey = strlen(key);
  int idx;
  for (idx = 0; idx < sinput / 2; idx++) {
    int pos = idx % skey;
    poutput[idx] = ((from_hex(pinput[idx * 2]) << 4) | from_hex(pinput[idx * 2 + 1])) ^ key[pos];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa8(%rbp)
  jmp    L74
L113:
  movl   $0x0,-0xa4(%rbp)
  jmp    L158
L17:
  mov    -0xa4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xa8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  add    %rcx,%rax
  sub    $0x70,%rax
  movb   $0x6c,(%rax)
  addl   $0x1,-0xa4(%rbp)
L158:
  cmpl   $0x9,-0xa4(%rbp)
  jle    L17
  addl   $0x1,-0xa8(%rbp)
L74:
  cmpl   $0x9,-0xa8(%rbp)
  jle    L113
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,-0x88(%rbp)
  movl   $0x0,-0xa0(%rbp)
  jmp    L111
L167:
  mov    -0xa0(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x88(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movl   $0x0,-0x9c(%rbp)
  jmp    L105
L23:
  mov    -0x88(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xa0(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x9c(%rbp),%eax
  cltq
  add    %rcx,%rax
  add    %rdx,%rax
  movb   $0x61,(%rax)
  addl   $0x1,-0x9c(%rbp)
L105:
  cmpl   $0x9,-0x9c(%rbp)
  jle    L23
  addl   $0x1,-0xa0(%rbp)
L111:
  cmpl   $0x9,-0xa0(%rbp)
  jle    L167
  movl   $0x0,-0x98(%rbp)
  jmp    L86
L103:
  movl   $0x0,-0x94(%rbp)
  jmp    L77
L99:
  mov    -0x94(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x98(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  add    %rcx,%rax
  sub    $0x70,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x94(%rbp)
L77:
  cmpl   $0x9,-0x94(%rbp)
  jle    L99
  addl   $0x1,-0x98(%rbp)
L86:
  cmpl   $0x9,-0x98(%rbp)
  jle    L103
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x90(%rbp)
  jmp    L32
L65:
  movl   $0x0,-0x8c(%rbp)
  jmp    L21
L56:
  mov    -0x88(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x90(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8c(%rbp),%eax
  cltq
  add    %rcx,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8c(%rbp)
L21:
  cmpl   $0x9,-0x8c(%rbp)
  jle    L56
  addl   $0x1,-0x90(%rbp)
L32:
  cmpl   $0x9,-0x90(%rbp)
  jle    L65
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L132
  call   <__stack_chk_fail@plt>
L132:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main() {
  char mat[10][10];
  for (int i = 0; i < 10; i++)
    for (int j = 0; j < 10; j++)
      mat[i][j] = 'l';
  char **pont = malloc(sizeof(char **) * 10);
  for (int i = 0; i < 10; i++) {
    *(pont + i) = malloc(sizeof(char *) * 10);
    for (int j = 0; j < 10; j++) {
      *((*pont + i) + j) = 'a';
    }
  }
  for (int i = 0; i < 10; i++)
    for (int j = 0; j < 10; j++)
      printf("%c", mat[i][j]);
  printf("\n");
  for (int i = 0; i < 10; i++)
    for (int j = 0; j < 10; j++)
      printf("%c", *((*pont + i) + j));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xa(%rsp),%r12
  lea    0x6e(%rsp),%r13
  mov    %r12,%rdx
L31:
  lea    -0xa(%rdx),%rax
L4:
  movb   $0x6c,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L4
  add    $0xa,%rdx
  cmp    %r13,%rdx
  jne    L31
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0xa,%ebx
L47:
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,-0x50(%rbp,%rbx,8)
  lea    -0xa(%rbx),%rax
L86:
  mov    0x0(%rbp),%rdx
  movb   $0x61,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L86
  add    $0x1,%rbx
  cmp    $0x14,%rbx
  jne    L47
L8:
  lea    -0xa(%r12),%rbx
L52:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L52
  add    $0xa,%r12
  cmp    %r13,%r12
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0xa,%r12d
L57:
  lea    -0xa(%r12),%rbx
L75:
  mov    0x0(%rbp),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L75
  add    $0x1,%r12
  cmp    $0x14,%r12
  jne    L57
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char mat[10][10];
  for (int i = 0; i < 10; i++)
    for (int j = 0; j < 10; j++)
      mat[i][j] = 'l';
  char **pont = malloc(sizeof(char **) * 10);
  for (int i = 0; i < 10; i++) {
    *(pont + i) = malloc(sizeof(char *) * 10);
    for (int j = 0; j < 10; j++) {
      *((*pont + i) + j) = 'a';
    }
  }
  for (int i = 0; i < 10; i++)
    for (int j = 0; j < 10; j++)
      printf("%c", mat[i][j]);
  printf("\n");
  for (int i = 0; i < 10; i++)
    for (int j = 0; j < 10; j++)
      printf("%c", *((*pont + i) + j));
  return 0;
}
```