ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<strstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmpb   $0x0,(%rbx)
  je     L36
  mov    %eax,%esi
  nop
L39:
  xor    %edx,%edx
  jmp    L17
  nopl   0x0(%rax)
L37:
  lea    0x1(%rdx),%ecx
  lea    0x1(%rdx),%rdi
  cmp    %rsi,%rdx
  je     L38
  mov    %rdi,%rdx
L17:
  movzbl 0x0(%rbp,%rdx,1),%edi
  mov    %edx,%ecx
  cmp    %dil,(%rbx,%rdx,1)
  je     L37
L38:
  cmp    %eax,%ecx
  je     L12
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L39
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L12:
  add    $0x8,%rsp
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strstr(const char *src, const char *search) {
  unsigned len = strlen(search);
  while (*src) {
    unsigned i = 0;
    while (src[i] == search[i] && i++ < len)
      ;
    if (i == len)
      return (char *)src;
    else
      src++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L20
L18:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L38
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  cmpl   $0x7,-0x8(%rbp)
  jle    L18
  jmp    L30
L38:
  nop
L30:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_run(int byte, int start_bit, int desired_val) {
  int count = 0;
  int i;
  for (i = start_bit; i < 8; i++) {
    int bit = (byte >> i) & 1;
    if (bit == desired_val)
      count++;
    else
      break;
  }
  return (count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_run>:
  endbr64
  mov    %edi,%r9d
  cmp    $0x7,%esi
  jg     L9
  mov    %edi,%eax
  mov    %esi,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  cmp    %eax,%edx
  jne    L0
  mov    $0x8,%eax
  sub    %esi,%eax
  mov    $0x0,%edi
L30:
  add    $0x1,%edi
  lea    (%rdi,%rsi,1),%ecx
  cmp    %eax,%edi
  je     L34
  mov    %r9d,%r8d
  sar    %cl,%r8d
  and    $0x1,%r8d
  cmp    %edx,%r8d
  je     L30
  mov    %edi,%eax
  ret
L34:
  ret
L9:
  mov    $0x0,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int count_run(int byte, int start_bit, int desired_val) {
  int count = 0;
  int i;
  for (i = start_bit; i < 8; i++) {
    int bit = (byte >> i) & 1;
    if (bit == desired_val)
      count++;
    else
      break;
  }
  return (count);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<count_run>:
  endbr64
  mov    %edi,%r9d
  cmp    $0x7,%esi
  jg     L19
  mov    %edi,%eax
  mov    %esi,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  cmp    %eax,%edx
  jne    L19
  mov    $0x8,%eax
  xor    %edi,%edi
  sub    %esi,%eax
  jmp    L10
  nopl   0x0(%rax)
L32:
  mov    %r9d,%r8d
  sar    %cl,%r8d
  and    $0x1,%r8d
  cmp    %edx,%r8d
  jne    L28
L10:
  add    $0x1,%edi
  lea    (%rdi,%rsi,1),%ecx
  cmp    %eax,%edi
  jne    L32
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count_run(int byte, int start_bit, int desired_val) {
  int count = 0;
  int i;
  for (i = start_bit; i < 8; i++) {
    int bit = (byte >> i) & 1;
    if (bit == desired_val)
      count++;
    else
      break;
  }
  return (count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_run>:
  endbr64
  mov    %edi,%r9d
  cmp    $0x7,%esi
  jg     L15
  mov    %edi,%eax
  mov    %esi,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  cmp    %eax,%edx
  jne    L15
  mov    $0x8,%eax
  xor    %edi,%edi
  sub    %esi,%eax
  jmp    L31
  nopl   0x0(%rax)
L21:
  mov    %r9d,%r8d
  sar    %cl,%r8d
  and    $0x1,%r8d
  cmp    %edx,%r8d
  jne    L43
L31:
  add    $0x1,%edi
  lea    (%rdi,%rsi,1),%ecx
  cmp    %eax,%edi
  jne    L21
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int count_run(int byte, int start_bit, int desired_val) {
  int count = 0;
  int i;
  for (i = start_bit; i < 8; i++) {
    int bit = (byte >> i) & 1;
    if (bit == desired_val)
      count++;
    else
      break;
  }
  return (count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L24
L13:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L67
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x14(%rbp)
  jmp    L22
L67:
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x10(%rbp)
L22:
  addl   $0x1,-0x18(%rbp)
L24:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L13
  mov    -0x10(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x9,-0xc(%rbp)
  jg     L63
  cmpl   $0xfffffff7,-0xc(%rbp)
  jl     L63
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L41
L63:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L41:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D16: %d

tool: D8: The two sums are close

tool: D11: The two sums are far

assistant: ```c
int main() {
  int difference, i, n = 0, number = 0;
  int sum_odd_positions = 0, sum_even_positions = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%d", &number);
    if (i % 2) {
      sum_odd_positions += number;
    } else {
      sum_even_positions += number;
    }
  }
  difference = sum_even_positions - sum_odd_positions;
  if (difference < 10 && difference > -10) {
    printf("The two sums are close");
  } else {
    printf("The two sums are far");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L65
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  mov    $0x1,%ebx
  lea    D7(%rip),%r13
  jmp    L38
L39:
  add    0x4(%rsp),%ebp
L72:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L55
L38:
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  test   $0x1,%bl
  je     L39
  add    0x4(%rsp),%r12d
  jmp    L72
L55:
  sub    %r12d,%ebp
  add    $0x9,%ebp
  cmp    $0x12,%ebp
  jbe    L65
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L65:
  lea    D14(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D14
type: string

tool: D7: %d

tool: D13: The two sums are far

tool: D14: The two sums are close

assistant: ```c
int main() {
  int difference, i, n = 0, number = 0;
  int sum_odd_positions = 0, sum_even_positions = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%d", &number);
    if (i % 2) {
      sum_odd_positions += number;
    } else {
      sum_even_positions += number;
    }
  }
  difference = sum_even_positions - sum_odd_positions;
  if (difference < 10 && difference > -10) {
    printf("The two sums are close");
  } else {
    printf("The two sums are far");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L26
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  lea    0x4(%rsp),%r14
  mov    $0x1,%ebx
  jmp    L76
  nopl   0x0(%rax)
L55:
  add    0x4(%rsp),%r13d
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L50
L76:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   $0x1,%bl
  jne    L55
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L76
L50:
  sub    %r13d,%ebp
  add    $0x9,%ebp
  cmp    $0x12,%ebp
  jbe    L26
  lea    D16(%rip),%rdi
  call   <printf@plt>
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L47
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string

tool: D15: %d

tool: D16: The two sums are far

tool: D23: The two sums are close

assistant: ```c
int main() {
  int difference, i, n = 0, number = 0;
  int sum_odd_positions = 0, sum_even_positions = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%d", &number);
    if (i % 2) {
      sum_odd_positions += number;
    } else {
      sum_even_positions += number;
    }
  }
  difference = sum_even_positions - sum_odd_positions;
  if (difference < 10 && difference > -10) {
    printf("The two sums are close");
  } else {
    printf("The two sums are far");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L13
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  lea    0x4(%rsp),%r14
  mov    $0x1,%ebx
  jmp    L60
  nopl   0x0(%rax)
L21:
  add    0x4(%rsp),%r13d
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L6
L60:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   $0x1,%bl
  jne    L21
  add    0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L60
L6:
  sub    %r13d,%ebp
  add    $0x9,%ebp
  cmp    $0x12,%ebp
  jbe    L13
  lea    D17(%rip),%rdi
  call   <printf@plt>
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D14: %d

tool: D17: The two sums are far

tool: D3: The two sums are close

assistant: ```c
int main() {
  int difference, i, n = 0, number = 0;
  int sum_odd_positions = 0, sum_even_positions = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%d", &number);
    if (i % 2) {
      sum_odd_positions += number;
    } else {
      sum_even_positions += number;
    }
  }
  difference = sum_even_positions - sum_odd_positions;
  if (difference < 10 && difference > -10) {
    printf("The two sums are close");
  } else {
    printf("The two sums are far");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stripOutEmailAddress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0xffffffff,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L95
L86:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L32
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L32
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L16
L32:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L76
  subl   $0x1,-0x1c(%rbp)
  jmp    L124
L76:
  cmpl   $0x0,-0x1c(%rbp)
  je     L16
  addl   $0x1,-0x1c(%rbp)
L16:
  addl   $0x1,-0x14(%rbp)
L95:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  ja     L86
L124:
  cmpl   $0x0,-0x1c(%rbp)
  je     L108
  cmpl   $0x0,-0x18(%rbp)
  je     L108
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L26
L99:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L99
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L75
L108:
  mov    $0x0,%eax
L75:
  leave
  ret
```

assistant: ```c
char *stripOutEmailAddress(char *line) {
  int length_needed = 0;
  int start = -1;
  int i;
  size_t len = strlen(line);
  for (i = 0; i < len; i++) {
    if (line[i] == '<' && start == -1) {
      start = i + 1;
      length_needed = 1;
    } else if (line[i] == '>') {
      length_needed--;
      break;
    } else if (length_needed)
      length_needed++;
  }
  if (length_needed && start) {
    char *output = malloc(length_needed);
    for (i = 0; i < length_needed; i++)
      output[i] = line[start + i];
    output[length_needed] = '\0';
    return output;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stripOutEmailAddress>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %rax,%rax
  je     L101
  mov    $0x1,%edx
  mov    $0xffffffff,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ecx
  jmp    L5
L47:
  cmp    $0x3e,%cl
  je     L44
  cmp    $0x1,%ebx
  sbb    $0xffffffff,%ebx
L88:
  lea    0x1(%rdx),%rsi
  mov    %rdx,%rcx
  cmp    %rdx,%rax
  je     L108
  mov    %rsi,%rdx
L5:
  movzbl 0x0(%rbp,%rcx,1),%ecx
  cmp    $0xffffffff,%r12d
  jne    L47
  cmp    $0x3c,%cl
  jne    L47
  mov    %edx,%r12d
  mov    $0x1,%ebx
  jmp    L88
L44:
  sub    $0x1,%ebx
L108:
  test   %ebx,%ebx
  je     L55
  test   %r12d,%r12d
  je     L55
  mov    %ebx,%edi
  call   <malloc@plt>
  test   %ebx,%ebx
  jle    L113
  mov    %ebx,%esi
  mov    $0x0,%edx
  movslq %r12d,%r12
  add    %r12,%rbp
L115:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L115
L113:
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  jmp    L127
L101:
  mov    $0x0,%eax
  jmp    L127
L55:
  mov    $0x0,%eax
L127:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *stripOutEmailAddress(char *line) {
  int length_needed = 0;
  int start = -1;
  int i;
  size_t len = strlen(line);
  for (i = 0; i < len; i++) {
    if (line[i] == '<' && start == -1) {
      start = i + 1;
      length_needed = 1;
    } else if (line[i] == '>') {
      length_needed--;
      break;
    } else if (length_needed)
      length_needed++;
  }
  if (length_needed && start) {
    char *output = malloc(length_needed);
    for (i = 0; i < length_needed; i++)
      output[i] = line[start + i];
    output[length_needed] = '\0';
    return output;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stripOutEmailAddress>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L82
  mov    $0x1,%edx
  mov    $0xffffffffffffffff,%r12
  xor    %ebx,%ebx
  xor    %ecx,%ecx
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L88:
  cmp    $0x3e,%cl
  je     L15
L63:
  cmp    $0x1,%ebx
  movslq %edx,%rcx
  sbb    $0xffffffff,%ebx
  add    $0x1,%edx
  cmp    %rax,%rcx
  jae    L52
L9:
  movzbl 0x0(%rbp,%rcx,1),%ecx
  cmp    $0x3c,%cl
  jne    L88
  cmp    $0xffffffff,%r12d
  jne    L63
  movslq %edx,%rcx
  movslq %edx,%r12
  mov    $0x1,%ebx
  add    $0x1,%edx
  cmp    %rax,%rcx
  jb     L9
  nopl   (%rax)
L52:
  test   %ebx,%ebx
  je     L82
  test   %r12d,%r12d
  je     L82
  mov    %ebx,%edi
  add    %r12,%rbp
  call   <malloc@plt>
  movslq %ebx,%rsi
  xor    %edx,%edx
  test   %ebx,%ebx
  jle    L106
  nopl   0x0(%rax)
L43:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L43
L106:
  movb   $0x0,(%rax,%rsi,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  sub    $0x1,%ebx
  jmp    L52
```

assistant: ```c
char *stripOutEmailAddress(char *line) {
  int length_needed = 0;
  int start = -1;
  int i;
  size_t len = strlen(line);
  for (i = 0; i < len; i++) {
    if (line[i] == '<' && start == -1) {
      start = i + 1;
      length_needed = 1;
    } else if (line[i] == '>') {
      length_needed--;
      break;
    } else if (length_needed)
      length_needed++;
  }
  if (length_needed && start) {
    char *output = malloc(length_needed);
    for (i = 0; i < length_needed; i++)
      output[i] = line[start + i];
    output[length_needed] = '\0';
    return output;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<labname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    $0x4c,%edx
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D22(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_infered: string

tool: D12: %c%d

assistant: ```c
char *labname(int id) {
  static char name[100];
  sprintf(name, "%c%d", 'L', id);
  return name;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<labname>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  mov    $0x4c,%edx
  lea    D1(%rip),%rsi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: %c%d

assistant: ```c
char *labname(int id) {
  static char name[100];
  sprintf(name, "%c%d", 'L', id);
  return name;
}
```
user: What is the c source code of the assembly code below:

```asm
<labname>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  mov    %edi,%ecx
  mov    $0x4c,%edx
  mov    %r12,%rdi
  lea    D6(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string

tool: D6: %c%d

assistant: ```c
char *labname(int id) {
  static char name[100];
  sprintf(name, "%c%d", 'L', id);
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<labname>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  mov    %edi,%ecx
  mov    $0x4c,%edx
  mov    %r12,%rdi
  lea    D2(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string

tool: D2: %c%d

assistant: ```c
char *labname(int id) {
  static char name[100];
  sprintf(name, "%c%d", 'L', id);
  return name;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fsetpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fsetpos(FILE *stream, const fpos_t *pos) {
  errno = ESPIPE;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fsetpos>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fsetpos(FILE *stream, const fpos_t *pos) {
  errno = ESPIPE;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fsetpos>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fsetpos(FILE *stream, const fpos_t *pos) {
  errno = ESPIPE;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fsetpos>:
  endbr64
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int fsetpos(FILE *stream, const fpos_t *pos) {
  errno = ESPIPE;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L6
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L15
L6:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <myformat@plt>
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type_guessed: string
name: disassemble_data
arguments: data_label: D1
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string

tool: D15: Invalid number of arguments 

tool: D1: usage: %s diskSizeInBlockSize


tool: D12: Formatting the disk with size %lu 


assistant: ```c
int main(int argc, char **argv) {
  if (argc != 2) {
    printf("Invalid number of arguments \n");
    printf("usage: %s diskSizeInBlockSize\n", argv[0]);
    return 1;
  }
  unsigned long size = atoi(argv[1]);
  printf("Formatting the disk with size %lu \n", size);
  myformat(size);
}
```