user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<build_chunked_response>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %rsi,%rbp
  mov    %edi,%eax
  sar    $0x4,%eax
  lea    0x100(%rdi,%rax,1),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    D38(%rip),%rdx
  mov    %r15d,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    %eax,0x0(%rbp)
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %r14d,%esi
  mov    %rax,%rdi
  call   <build_content@plt>
  test   %r14d,%r14d
  jle    L19
  mov    $0x0,%r12d
L13:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x5254e78f,%rdx,%rdx
  sar    $0x26,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xc7,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%r12,%rax,1),%ecx
  mov    %r14d,%edx
  sub    %r12d,%edx
  add    $0x1,%eax
  cmp    %r14d,%ecx
  mov    %edx,%ebx
  cmovle %eax,%ebx
  mov    0x0(%rbp),%edi
  mov    %r15d,%esi
  sub    %edi,%esi
  movslq %edi,%rdi
  add    %r13,%rdi
  mov    %ebx,%ecx
  lea    D33(%rip),%rdx
  mov    $0x0,%eax
  call   <snprintf@plt>
  add    0x0(%rbp),%eax
  mov    %eax,0x0(%rbp)
  movslq %r12d,%rsi
  add    0x8(%rsp),%rsi
  cltq
  lea    0x0(%r13,%rax,1),%rdi
  mov    %ebx,%edx
  call   <memcpy@plt>
  mov    %ebx,%eax
  add    0x0(%rbp),%eax
  add    %ebx,%r12d
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%rbp)
  cltq
  movb   $0xd,0x0(%r13,%rax,1)
  mov    0x0(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,0x0(%rbp)
  cltq
  movb   $0xa,0x0(%r13,%rax,1)
  cmp    %r12d,%r14d
  jg     L13
L19:
  movslq 0x0(%rbp),%rdi
  add    %r13,%rdi
  mov    $0x3,%edx
  lea    D36(%rip),%rsi
  call   <memcpy@plt>
  addl   $0x3,0x0(%rbp)
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r14d,%ecx
  mov    %r15d,%edx
  mov    0x0(%rbp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D38
type_infered: string
name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string

tool: D38: HTTP/1.1 200 OK
Content-Type: text/plain
Transfer-Encoding: chunked



tool: D33: %x


tool: D36: 0


tool: D17: resp_length=%d buffer_length=%d content_length=%d


assistant: ```c
char *build_chunked_response(int content_length, int *response_len) {
  char *response_buffer;
  char *content_buffer;
  int buffer_length;
  int i, n;
  buffer_length = 256 + content_length + (content_length >> 4);
  response_buffer = malloc(buffer_length);
  *response_len = snprintf(response_buffer, buffer_length,
                           "HTTP/1.1 200 OK\r\n"
                           "Content-Type: text/plain\r\n"
                           "Transfer-Encoding: chunked\r\n"
                           "\r\n");
  content_buffer = malloc(content_length);
  build_content(content_buffer, content_length);
  i = 0;
  while (i < content_length) {
    n = (rand() % 199) + 1;
    if (i + n > content_length) {
      n = content_length - i;
    }
    *response_len += snprintf(response_buffer + *response_len, buffer_length - *response_len, "%x\r\n", n);
    memcpy(response_buffer + *response_len, content_buffer + i, n);
    *response_len += n;
    i += n;
    response_buffer[(*response_len)++] = '\r';
    response_buffer[(*response_len)++] = '\n';
  }
  memcpy(response_buffer + *response_len, "0\r\n", 3);
  *response_len += 3;
  free(content_buffer);
  printf("resp_length=%d buffer_length=%d content_length=%d\n", *response_len, buffer_length, content_length);
  return response_buffer;
}
```