ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebx
  lea    D1(%rip),%rbp
L21:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L4
  movslq %ebx,%rax
  imul   $0x51eb851f,%rax,%rsi
  sar    $0x25,%rsi
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x64,%esi,%eax
  mov    %ebx,%edi
  sub    %eax,%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  mov    %esi,%ecx
  imul   %esi,%ecx
  imul   %esi,%ecx
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  add    %ecx,%edx
  mov    %eax,%ecx
  imul   %eax,%ecx
  imul   %ecx,%eax
  add    %edx,%eax
  cmp    %ebx,%eax
  jne    L21
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L21
L4:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string

tool: D1: %d


assistant: ```c
int main() {
  int x, y, z;
  int i;
  for (i = 100; i < 1000; i++) {
    x = i / 100;
    y = (i / 10) % 10;
    z = (i % 100) % 10;
    if ((x * x * x + y * y * y + z * z * z) == i) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  lea    D6(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  je     L28
L3:
  mov    %r12d,%eax
  mov    %r12d,%edi
  imul   $0x51eb851f,%rax,%rsi
  imul   %rbp,%rax
  shr    $0x25,%rsi
  shr    $0x23,%rax
  mov    %eax,%edx
  imul   %rbp,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x64,%esi,%eax
  sub    %eax,%edi
  mov    %edi,%eax
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %edi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %esi,%ecx
  imul   %esi,%ecx
  imul   %esi,%ecx
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  add    %ecx,%edx
  mov    %eax,%ecx
  imul   %eax,%ecx
  imul   %ecx,%eax
  add    %edx,%eax
  cmp    %r12d,%eax
  jne    L22
  mov    %r12d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x3e8,%r12d
  jne    L3
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main() {
  int x, y, z;
  int i;
  for (i = 100; i < 1000; i++) {
    x = i / 100;
    y = (i / 10) % 10;
    z = (i % 100) % 10;
    if ((x * x * x + y * y * y + z * z * z) == i) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x65,%r12d
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  lea    D3(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r12d,%eax
  mov    %r12d,%edi
  imul   $0x51eb851f,%rax,%rsi
  imul   %rbp,%rax
  shr    $0x25,%rsi
  shr    $0x23,%rax
  mov    %eax,%edx
  imul   %rbp,%rdx
  shr    $0x23,%rdx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0x64,%esi,%eax
  sub    %eax,%edi
  mov    %edi,%eax
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  mov    %edi,%eax
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %esi,%ecx
  imul   %esi,%ecx
  imul   %esi,%ecx
  mov    %edx,%esi
  imul   %edx,%esi
  imul   %esi,%edx
  add    %ecx,%edx
  mov    %eax,%ecx
  imul   %eax,%ecx
  imul   %ecx,%eax
  add    %edx,%eax
  cmp    %r12d,%eax
  je     L39
  add    $0x1,%r12d
  cmp    $0x3e8,%r12d
  jne    L24
L31:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x3e8,%r12d
  jne    L24
  jmp    L31
```

tool_calls: name: disassemble_data
arguments: tag: D3
data_type: string

tool: D3: %d


assistant: ```c
int main() {
  int x, y, z;
  int i;
  for (i = 100; i < 1000; i++) {
    x = i / 100;
    y = (i / 10) % 10;
    z = (i % 100) % 10;
    if ((x * x * x + y * y * y + z * z * z) == i) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<newLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L19:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: 


assistant: ```c
newLine(int qtd) {
  int i = 0;
  for (i = 0; i < qtd; i++)
    printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<newLine>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L7:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: 


assistant: ```c
newLine(int qtd) {
  int i = 0;
  for (i = 0; i < qtd; i++)
    printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<newLine>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D9: 


assistant: ```c
newLine(int qtd) {
  int i = 0;
  for (i = 0; i < qtd; i++)
    printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<newLine>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: 


assistant: ```c
newLine(int qtd) {
  int i = 0;
  for (i = 0; i < qtd; i++)
    printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x8,-0xc(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L35
L9:
  movl   $0x0,-0x24(%rbp)
  jmp    L0
L38:
  mov    -0x28(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L0:
  cmpl   $0x1,-0x24(%rbp)
  jle    L38
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x28(%rbp)
L35:
  cmpl   $0x2,-0x28(%rbp)
  jle    L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6: %d	

assistant: ```c
int main() {
  int test[3][2] = {{1, 4}, {2, 5}, {2, 8}};
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      printf("%d\t", *(*(test + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x4,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x8,0x14(%rsp)
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  lea    D8(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L2
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %d	

assistant: ```c
int main() {
  int test[3][2] = {{1, 4}, {2, 5}, {2, 8}};
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      printf("%d\t", *(*(test + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%esi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x400000001,%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  mov    %rax,(%rsp)
  movabs $0x500000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x800000002,%rax
  mov    %rax,0x10(%rsp)
L22:
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r12
  je     L13
  mov    (%rbx),%esi
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d	

assistant: ```c
int main() {
  int test[3][2] = {{1, 4}, {2, 5}, {2, 8}};
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      printf("%d\t", *(*(test + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  movdqa D24(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r12
  jne    L5
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: byte[8]

tool: D4: %d	

tool: {"D24": [0x01,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D16": [0x02,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int test[3][2] = {{1, 4}, {2, 5}, {2, 8}};
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2; j++) {
      printf("%d\t", *(*(test + i) + j));
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<so_pipeok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  movzbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <so_needign@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x0,%eax
  jmp    L6
L8:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L6:
  leave
  ret
```

assistant: ```c
int so_pipeok(struct socket *so, _Bool rdonly) {
  if (!so_needign(so, rdonly))
    return 0;
  return EOPNOTSUPP;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<so_pipeok>:
  endbr64
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <so_needign@plt>
  test   %eax,%eax
  je     L8
  mov    D3(%rip),%rax
  mov    (%rax),%eax
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int so_pipeok(struct socket *so, _Bool rdonly) {
  if (!so_needign(so, rdonly))
    return 0;
  return EOPNOTSUPP;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<so_pipeok>:
  endbr64
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <so_needign@plt>
  test   %eax,%eax
  je     L5
  mov    D7(%rip),%rax
  mov    (%rax),%eax
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int so_pipeok(struct socket *so, _Bool rdonly) {
  if (!so_needign(so, rdonly))
    return 0;
  return EOPNOTSUPP;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<so_pipeok>:
  endbr64
  sub    $0x8,%rsp
  movzbl %sil,%esi
  call   <so_needign@plt>
  test   %eax,%eax
  je     L7
  mov    D1(%rip),%rax
  mov    (%rax),%eax
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int so_pipeok(struct socket *so, _Bool rdonly) {
  if (!so_needign(so, rdonly))
    return 0;
  return EOPNOTSUPP;
}
```
user: Translate the below assembly code into C programming language:

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L16
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L14
L16:
  mov    -0x8(%rbp),%rax
L14:
  pop    %rbp
  ret
```

assistant: ```c
long abs(long v) {
  if (v < 0)
    return (-1) * v;
  return v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<abs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long abs(long v) {
  if (v < 0)
    return (-1) * v;
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<abs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long abs(long v) {
  if (v < 0)
    return (-1) * v;
  return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<abs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long abs(long v) {
  if (v < 0)
    return (-1) * v;
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L13:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L39:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x40,-0x4(%rbp)
L32:
  cmpl   $0x3f,-0x8(%rbp)
  jle    L39
  addl   $0x1,-0x10(%rbp)
  addl   $0x40,-0xc(%rbp)
L19:
  cmpl   $0x3f,-0x10(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose(uint8_t *const dst, const uint8_t *const src) {
  for (int y = 0, y_off = 0; y < 64; y++, y_off += 64)
    for (int x = 0, x_off = 0; x < 64; x++, x_off += 64)
      dst[x_off + y] = src[y_off + x];
}
```
user: Translate the below assembly code into C programming language:

```asm
<transpose>:
  endbr64
  mov    %rsi,%r8
  lea    0x4000(%rdi),%rsi
  mov    $0x0,%edi
L16:
  lea    -0x4000(%rsi),%rax
  mov    %r8,%rdx
L6:
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  add    $0x4,%rdx
  add    $0x100,%rax
  cmp    %rsi,%rax
  jne    L6
  add    $0x1,%edi
  add    $0x100,%r8
  add    $0x4,%rsi
  cmp    $0x40,%edi
  jne    L16
  ret
```

assistant: ```c
void transpose(uint8_t *const dst, const uint8_t *const src) {
  for (int y = 0, y_off = 0; y < 64; y++, y_off += 64)
    for (int x = 0, x_off = 0; x < 64; x++, x_off += 64)
      dst[x_off + y] = src[y_off + x];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<transpose>:
  endbr64
  mov    %rsi,%r8
  lea    0x4000(%rdi),%rsi
  xor    %edi,%edi
L10:
  lea    -0x4000(%rsi),%rax
  mov    %r8,%rdx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    (%rdx),%ecx
  add    $0x100,%rax
  add    $0x4,%rdx
  mov    %ecx,-0x100(%rax)
  cmp    %rsi,%rax
  jne    L11
  add    $0x1,%edi
  add    $0x100,%r8
  lea    0x4(%rax),%rsi
  cmp    $0x40,%edi
  jne    L10
  ret
```

assistant: ```c
void transpose(uint8_t *const dst, const uint8_t *const src) {
  for (int y = 0, y_off = 0; y < 64; y++, y_off += 64)
    for (int x = 0, x_off = 0; x < 64; x++, x_off += 64)
      dst[x_off + y] = src[y_off + x];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetFileType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: GBZ|GZ

assistant: ```c
int GetFileType(char *pname) {
  if (pname != NULL) {
    strcpy(pname, "GBZ|GZ");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GetFileType>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <strcpy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_infered: string

tool: D0: GBZ|GZ

assistant: ```c
int GetFileType(char *pname) {
  if (pname != NULL) {
    strcpy(pname, "GBZ|GZ");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GetFileType>:
  endbr64
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L8:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: GBZ|GZ

assistant: ```c
int GetFileType(char *pname) {
  if (pname != NULL) {
    strcpy(pname, "GBZ|GZ");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GetFileType>:
  endbr64
  test   %rdi,%rdi
  je     L7
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  call   <strcpy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L7:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: GBZ|GZ

assistant: ```c
int GetFileType(char *pname) {
  if (pname != NULL) {
    strcpy(pname, "GBZ|GZ");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movswl %ax,%edx
  mov    -0x18(%rbp),%eax
  cwtl
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L11
  mov    $0xa,%eax
  jmp    L2
L11:
  mov    -0x4(%rbp),%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int f(int b, int c) {
  int a = (short)b * (short)c;
  if (!a)
    return 10;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  movswl %di,%eax
  movswl %si,%esi
  imul   %esi,%eax
  test   %eax,%eax
  mov    $0xa,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
int f(int b, int c) {
  int a = (short)b * (short)c;
  if (!a)
    return 10;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  movswl %di,%eax
  movswl %si,%esi
  mov    $0xa,%edx
  imul   %esi,%eax
  test   %eax,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int f(int b, int c) {
  int a = (short)b * (short)c;
  if (!a)
    return 10;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  movswl %di,%eax
  movswl %si,%esi
  mov    $0xa,%edx
  imul   %esi,%eax
  test   %eax,%eax
  cmove  %edx,%eax
  ret
```

assistant: ```c
int f(int b, int c) {
  int a = (short)b * (short)c;
  if (!a)
    return 10;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x4,%eax
  pop    %rbp
  ret
```

assistant: ```c
int g(void) {
  f();
  return 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <f@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int g(void) {
  f();
  return 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int g(void) {
  f();
  return 4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<g>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <f@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int g(void) {
  f();
  return 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bfin_coreb_stop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <bfin_read_SYSCR@plt>
  or     $0x20,%eax
  mov    %eax,%edi
  call   <bfin_write_SYSCR@plt>
  mov    $0x0,%eax
  call   <bfin_read_SICB_SYSCR@plt>
  or     $0x80,%al
  mov    %eax,%edi
  call   <bfin_write_SICB_SYSCR@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bfin_coreb_stop(void) {
  bfin_write_SYSCR(bfin_read_SYSCR() | 0x0020);
  bfin_write_SICB_SYSCR(bfin_read_SICB_SYSCR() | 0x0080);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bfin_coreb_stop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bfin_read_SYSCR@plt>
  or     $0x20,%eax
  mov    %eax,%edi
  call   <bfin_write_SYSCR@plt>
  mov    $0x0,%eax
  call   <bfin_read_SICB_SYSCR@plt>
  or     $0x80,%al
  mov    %eax,%edi
  call   <bfin_write_SICB_SYSCR@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bfin_coreb_stop(void) {
  bfin_write_SYSCR(bfin_read_SYSCR() | 0x0020);
  bfin_write_SICB_SYSCR(bfin_read_SICB_SYSCR() | 0x0080);
}
```
user: What is the c source code of the assembly code below?

```asm
<bfin_coreb_stop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bfin_read_SYSCR@plt>
  or     $0x20,%eax
  mov    %eax,%edi
  call   <bfin_write_SYSCR@plt>
  xor    %eax,%eax
  call   <bfin_read_SICB_SYSCR@plt>
  add    $0x8,%rsp
  or     $0x80,%al
  mov    %eax,%edi
  jmp    10b0 <bfin_write_SICB_SYSCR@plt>
```

assistant: ```c
void bfin_coreb_stop(void) {
  bfin_write_SYSCR(bfin_read_SYSCR() | 0x0020);
  bfin_write_SICB_SYSCR(bfin_read_SICB_SYSCR() | 0x0080);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bfin_coreb_stop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bfin_read_SYSCR@plt>
  or     $0x20,%eax
  mov    %eax,%edi
  call   <bfin_write_SYSCR@plt>
  xor    %eax,%eax
  call   <bfin_read_SICB_SYSCR@plt>
  add    $0x8,%rsp
  or     $0x80,%al
  mov    %eax,%edi
  jmp    10b0 <bfin_write_SICB_SYSCR@plt>
```

assistant: ```c
void bfin_coreb_stop(void) {
  bfin_write_SYSCR(bfin_read_SYSCR() | 0x0020);
  bfin_write_SICB_SYSCR(bfin_read_SICB_SYSCR() | 0x0080);
}
```