ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L59
  mov    $0x0,%ebp
  lea    D5(%rip),%r13
  mov    $0x3c009,%ebx
  lea    D28(%rip),%r12
  jmp    L50
L70:
  bt     %rcx,%rbx
  jae    L58
  add    $0x1,%esi
L15:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L37
L13:
  lea    -0x41(%rax),%ecx
  cmp    $0x11,%cl
  jbe    L70
L58:
  lea    0x2(%rsi),%ecx
  cmp    $0x42,%al
  cmove  %ecx,%esi
  jmp    L15
L21:
  mov    $0x0,%esi
L37:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jle    L59
L50:
  lea    0x10(%rsp),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L21
  lea    0x10(%rsp),%rdx
  mov    $0x0,%esi
  jmp    L13
L59:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string
name: extract_symbolic_data
arguments: data_label: D28
data_type: string

tool: D1: %d

tool: D5: %s

tool: D28: %d


assistant: ```c
int main() {
  int cases, char_count;
  register int i;
  char text[100], *c;
  scanf("%d", &cases);
  for (i = 0; i < cases; i++) {
    scanf("%s", &text);
    c = &text[0];
    char_count = 0;
    while (*c != '\0') {
      if (*c == 'A' || *c == 'D' || *c == 'O' || *c == 'P' || *c == 'Q' || *c == 'R')
        char_count++;
      else if (*c == 'B')
        char_count += 2;
      c++;
    }
    printf("%d\n", char_count);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L34
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D28(%rip),%r13
  mov    $0xfffffffffffc3ff6,%r14
  lea    D16(%rip),%r12
  nopl   (%rax)
L0:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L97
  mov    %rbp,%rdx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L69:
  lea    -0x41(%rax),%ecx
  cmp    $0x11,%cl
  ja     L90
  bt     %rcx,%r14
  jb     L40
  add    $0x1,%esi
L90:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L69
L26:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L0
L34:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L40:
  cmp    $0x42,%al
  jne    L90
  add    $0x2,%esi
  jmp    L90
  nopl   0x0(%rax)
L97:
  xor    %esi,%esi
  jmp    L26
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D29: %d

tool: D28: %s

tool: D16: %d


assistant: ```c
int main() {
  int cases, char_count;
  register int i;
  char text[100], *c;
  scanf("%d", &cases);
  for (i = 0; i < cases; i++) {
    scanf("%s", &text);
    c = &text[0];
    char_count = 0;
    while (*c != '\0') {
      if (*c == 'A' || *c == 'D' || *c == 'O' || *c == 'P' || *c == 'Q' || *c == 'R')
        char_count++;
      else if (*c == 'B')
        char_count += 2;
      c++;
    }
    printf("%d\n", char_count);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L14
  xor    %ebx,%ebx
  lea    0x10(%rsp),%rbp
  lea    D21(%rip),%r13
  mov    $0xfffffffffffc3ff6,%r14
  lea    D5(%rip),%r12
  nopl   (%rax)
L25:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L45
  mov    %rbp,%rdx
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L91:
  lea    -0x41(%rax),%ecx
  cmp    $0x11,%cl
  ja     L46
  bt     %rcx,%r14
  jb     L8
  add    $0x1,%esi
L46:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L91
L30:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L25
L14:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L8:
  cmp    $0x42,%al
  jne    L46
  add    $0x2,%esi
  jmp    L46
  nopl   0x0(%rax)
L45:
  xor    %esi,%esi
  jmp    L30
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type_guessed: string
name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D29: %d

tool: D21: %s

tool: D5: %d


assistant: ```c
int main() {
  int cases, char_count;
  register int i;
  char text[100], *c;
  scanf("%d", &cases);
  for (i = 0; i < cases; i++) {
    scanf("%s", &text);
    c = &text[0];
    char_count = 0;
    while (*c != '\0') {
      if (*c == 'A' || *c == 'D' || *c == 'O' || *c == 'P' || *c == 'Q' || *c == 'R')
        char_count++;
      else if (*c == 'B')
        char_count += 2;
      c++;
    }
    printf("%d\n", char_count);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L16
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: %d 

assistant: ```c
void print_arr(int *arr, int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d ", arr[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_arr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L3
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D0(%rip),%rbp
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L2
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string

tool: D0: %d 

assistant: ```c
void print_arr(int *arr, int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d ", arr[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: %d 

assistant: ```c
void print_arr(int *arr, int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d ", arr[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L10:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L10
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %d 

assistant: ```c
void print_arr(int *arr, int n) {
  int i;
  for (i = 0; i < n; ++i)
    printf("%d ", arr[i]);
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<open>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int open(const char *pathname, int flags) {
  _exit(-1);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<open>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int open(const char *pathname, int flags) {
  _exit(-1);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<open>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int open(const char *pathname, int flags) {
  _exit(-1);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<open>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int open(const char *pathname, int flags) {
  _exit(-1);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L20
L21:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L16
  mov    -0x4(%rbp),%eax
  jmp    L26
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    $0x0,%eax
  jmp    L26
L11:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L20:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L21
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, unsigned n) {
  int a;
  while (n--) {
    a = *s1 - *s2;
    if (a)
      return a;
    if (*s1 == 0)
      return 0;
    s1++;
    s2++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  lea    -0x1(%rdx),%r9d
  test   %edx,%edx
  je     L39
  mov    %r9d,%r9d
  mov    $0x0,%edx
  jmp    L35
L30:
  mov    %rcx,%rdx
L35:
  movzbl (%rdi,%rdx,1),%r8d
  movsbl %r8b,%eax
  movsbl (%rsi,%rdx,1),%ecx
  sub    %ecx,%eax
  jne    L19
  test   %r8b,%r8b
  je     L19
  lea    0x1(%rdx),%rcx
  cmp    %r9,%rdx
  jne    L30
  ret
L39:
  mov    $0x0,%eax
L19:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, unsigned n) {
  int a;
  while (n--) {
    a = *s1 - *s2;
    if (a)
      return a;
    if (*s1 == 0)
      return 0;
    s1++;
    s2++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  je     L36
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L13
  xchg   %ax,%ax
L48:
  test   %r9b,%r9b
  je     L5
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L10
L13:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  mov    %eax,%r9d
  sub    %r8d,%eax
  je     L48
L5:
  ret
L10:
  ret
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, unsigned n) {
  int a;
  while (n--) {
    a = *s1 - *s2;
    if (a)
      return a;
    if (*s1 == 0)
      return 0;
    s1++;
    s2++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncmp>:
  endbr64
  test   %edx,%edx
  je     L33
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L18
  xchg   %ax,%ax
L34:
  test   %r9b,%r9b
  je     L48
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L7
L18:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%r8d
  mov    %eax,%r9d
  sub    %r8d,%eax
  je     L34
L48:
  ret
L7:
  ret
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, unsigned n) {
  int a;
  while (n--) {
    a = *s1 - *s2;
    if (a)
      return a;
    if (*s1 == 0)
      return 0;
    s1++;
    s2++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cipher>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <processInput@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sub@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <trans@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cipher(char *text, int lkey, int nkey) {
  int textLength = processInput(text);
  sub(text, lkey, nkey, textLength);
  trans(text, textLength);
  return textLength;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cipher>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  call   <processInput@plt>
  mov    %eax,%ebx
  mov    %eax,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <sub@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <trans@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int cipher(char *text, int lkey, int nkey) {
  int textLength = processInput(text);
  sub(text, lkey, nkey, textLength);
  trans(text, textLength);
  return textLength;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cipher>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <processInput@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  mov    %eax,%ecx
  call   <sub@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <trans@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int cipher(char *text, int lkey, int nkey) {
  int textLength = processInput(text);
  sub(text, lkey, nkey, textLength);
  trans(text, textLength);
  return textLength;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cipher>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <processInput@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  mov    %eax,%ecx
  call   <sub@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <trans@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int cipher(char *text, int lkey, int nkey) {
  int textLength = processInput(text);
  sub(text, lkey, nkey, textLength);
  trans(text, textLength);
  return textLength;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L15
  mov    -0x8(%rbp),%eax
  jmp    L10
L48:
  cmpl   $0x0,-0x4(%rbp)
  jg     L9
  mov    -0x8(%rbp),%eax
  jmp    L10
L9:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L48
  mov    -0x8(%rbp),%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  if (x <= 0) {
    return y;
  }
  while (x > y) {
    if (x <= 0) {
      return y;
    }
    y = y + x;
  }
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_fun>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jle    L29
  cmp    %esi,%edi
  jle    L29
L21:
  add    %edi,%eax
  cmp    %eax,%edi
  jg     L21
L29:
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  if (x <= 0) {
    return y;
  }
  while (x > y) {
    if (x <= 0) {
      return y;
    }
    y = y + x;
  }
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_fun>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jg     L6
  jmp    L2
  nopl   0x0(%rax)
L5:
  add    %edi,%eax
L6:
  cmp    %eax,%edi
  jg     L5
L2:
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  if (x <= 0) {
    return y;
  }
  while (x > y) {
    if (x <= 0) {
      return y;
    }
    y = y + x;
  }
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_fun>:
  endbr64
  mov    %esi,%eax
  test   %edi,%edi
  jg     L7
  jmp    L24
  nopl   0x0(%rax)
L26:
  add    %edi,%eax
L7:
  cmp    %eax,%edi
  jg     L26
L24:
  ret
```

assistant: ```c
int test_fun(int x, int y) {
  if (x <= 0) {
    return y;
  }
  while (x > y) {
    if (x <= 0) {
      return y;
    }
    y = y + x;
  }
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<alloc_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L0:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string

tool: D1: alloc_string: Out of memory for malloc

assistant: ```c
void alloc_string(char **dest, unsigned long size) {
  *dest = (char *)malloc(size);
  if (*dest == NULL) {
    print_error("alloc_string: Out of memory for malloc");
    exit((1));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<alloc_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L3
L8:
  pop    %rbx
  ret
L3:
  lea    D2(%rip),%rdi
  call   <print_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: alloc_string: Out of memory for malloc

assistant: ```c
void alloc_string(char **dest, unsigned long size) {
  *dest = (char *)malloc(size);
  if (*dest == NULL) {
    print_error("alloc_string: Out of memory for malloc");
    exit((1));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<alloc_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L0
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D5(%rip),%rdi
  call   <print_error@plt>
  mov    $0x1,%edi
  pop    %rbx
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: alloc_string: Out of memory for malloc

assistant: ```c
void alloc_string(char **dest, unsigned long size) {
  *dest = (char *)malloc(size);
  if (*dest == NULL) {
    print_error("alloc_string: Out of memory for malloc");
    exit((1));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<alloc_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L6
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D8(%rip),%rdi
  call   <print_error@plt>
  mov    $0x1,%edi
  pop    %rbx
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: alloc_string: Out of memory for malloc

assistant: ```c
void alloc_string(char **dest, unsigned long size) {
  *dest = (char *)malloc(size);
  if (*dest == NULL) {
    print_error("alloc_string: Out of memory for malloc");
    exit((1));
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<R_GenerateDrawSurfs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <R_AddWorldSurfaces@plt>
  mov    $0x0,%eax
  call   <R_AddPolygonSurfaces@plt>
  mov    $0x0,%eax
  call   <R_SetupProjection@plt>
  mov    $0x0,%eax
  call   <R_AddEntitySurfaces@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void R_GenerateDrawSurfs(void) {
  R_AddWorldSurfaces();
  R_AddPolygonSurfaces();
  R_SetupProjection();
  R_AddEntitySurfaces();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<R_GenerateDrawSurfs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <R_AddWorldSurfaces@plt>
  mov    $0x0,%eax
  call   <R_AddPolygonSurfaces@plt>
  mov    $0x0,%eax
  call   <R_SetupProjection@plt>
  mov    $0x0,%eax
  call   <R_AddEntitySurfaces@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void R_GenerateDrawSurfs(void) {
  R_AddWorldSurfaces();
  R_AddPolygonSurfaces();
  R_SetupProjection();
  R_AddEntitySurfaces();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<R_GenerateDrawSurfs>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <R_AddWorldSurfaces@plt>
  xor    %eax,%eax
  call   <R_AddPolygonSurfaces@plt>
  xor    %eax,%eax
  call   <R_SetupProjection@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <R_AddEntitySurfaces@plt>
```

assistant: ```c
void R_GenerateDrawSurfs(void) {
  R_AddWorldSurfaces();
  R_AddPolygonSurfaces();
  R_SetupProjection();
  R_AddEntitySurfaces();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<R_GenerateDrawSurfs>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <R_AddWorldSurfaces@plt>
  xor    %eax,%eax
  call   <R_AddPolygonSurfaces@plt>
  xor    %eax,%eax
  call   <R_SetupProjection@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <R_AddEntitySurfaces@plt>
```

assistant: ```c
void R_GenerateDrawSurfs(void) {
  R_AddWorldSurfaces();
  R_AddPolygonSurfaces();
  R_SetupProjection();
  R_AddEntitySurfaces();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x6d,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string

tool: D2: c is [%c]


assistant: ```c
int main(void) {
  char c = 'm';
  printf("c"
         " is [%c]\n",
         c);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: c is [%c]


assistant: ```c
int main(void) {
  char c = 'm';
  printf("c"
         " is [%c]\n",
         c);
  return 0;
}
```