ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printwrap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%esi
  mov    $0x0,%r14d
  cmpb   $0x0,(%rdi)
  jne    L99
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L142:
  mov    %edi,%r13d
L83:
  add    $0x1,%eax
  add    $0x1,%rcx
  cmp    $0x19,%eax
  je     L21
L130:
  lea    (%rsi,%rax,1),%edi
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L21
  cmp    $0x20,%dl
  je     L142
  cmp    $0x9,%dl
  jne    L83
  jmp    L142
L21:
  test   %r13d,%r13d
  jne    L139
  lea    (%rax,%rsi,1),%ebx
  cmp    %esi,%ebx
  jle    L63
L29:
  movsbl (%r12,%rbp,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbp
  cmp    %ebp,%ebx
  jg     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%esi
  test   %r13d,%r13d
  je     L113
L44:
  lea    0x1(%rbx),%esi
L113:
  movslq %esi,%rax
  cmpb   $0x0,(%r12,%rax,1)
  je     L36
L99:
  movslq %esi,%rbp
  lea    (%r12,%rbp,1),%rcx
  mov    %r14d,%r13d
  mov    $0x0,%eax
  jmp    L130
L139:
  mov    %r13d,%ebx
  cmp    %esi,%r13d
  jg     L29
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%ebx
  jmp    L44
L63:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebx,%esi
  jmp    L113
```

assistant: ```c
void printwrap(char line[]) {
  int i, lastbreak, start, stop;
  i = 0;
  lastbreak = 0;
  start = 0;
  while (line[start] != '\0') {
    lastbreak = 0;
    for (i = 0; i < 25 && line[start + i] != '\0'; i++) {
      if (line[start + i] == ' ' || line[start + i] == '\t')
        lastbreak = start + i;
    }
    if (!lastbreak) {
      stop = start + i;
    } else {
      stop = lastbreak;
    }
    for (i = start; i < stop; i++) {
      putchar(line[i]);
    }
    putchar('\n');
    start = stop;
    if (lastbreak)
      start++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printwrap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L129
  nop
L113:
  movslq %ebx,%rsi
  mov    %edi,%edx
  xor    %eax,%eax
  xor    %r12d,%r12d
  add    %rbp,%rsi
  jmp    L5
  nop
L85:
  add    $0x1,%rax
  cmp    $0x19,%rax
  je     L8
L31:
  movzbl (%rsi,%rax,1),%edx
L5:
  mov    %eax,%ecx
  mov    %eax,%r13d
  test   %dl,%dl
  je     L75
  cmp    $0x20,%dl
  je     L119
  cmp    $0x9,%dl
  jne    L85
L119:
  add    $0x1,%rax
  lea    (%rbx,%rcx,1),%r12d
  cmp    $0x19,%rax
  jne    L31
L8:
  mov    $0x19,%r13d
L75:
  test   %r12d,%r12d
  jne    L63
  add    %ebx,%r13d
  cmp    %ebx,%r13d
  jle    L2
L77:
  add    $0x1,%ebx
  movslq %ebx,%rbx
  jmp    L83
  nopw   0x0(%rax,%rax,1)
L64:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
L83:
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jg     L64
  mov    $0xa,%edi
  mov    %r13d,%ebx
  call   <putchar@plt>
  test   %r12d,%r12d
  je     L59
L138:
  lea    0x1(%r13),%ebx
L59:
  movslq %ebx,%rax
  movsbl 0x0(%rbp,%rax,1),%edi
  test   %dil,%dil
  jne    L113
L129:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L63:
  mov    %r12d,%r13d
  cmp    %ebx,%r12d
  jg     L77
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L138
L2:
  mov    $0xa,%edi
  mov    %r13d,%ebx
  call   <putchar@plt>
  jmp    L59
```

assistant: ```c
void printwrap(char line[]) {
  int i, lastbreak, start, stop;
  i = 0;
  lastbreak = 0;
  start = 0;
  while (line[start] != '\0') {
    lastbreak = 0;
    for (i = 0; i < 25 && line[start + i] != '\0'; i++) {
      if (line[start + i] == ' ' || line[start + i] == '\t')
        lastbreak = start + i;
    }
    if (!lastbreak) {
      stop = start + i;
    } else {
      stop = lastbreak;
    }
    for (i = start; i < stop; i++) {
      putchar(line[i]);
    }
    putchar('\n');
    start = stop;
    if (lastbreak)
      start++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printwrap>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L107
  push   %r14
  xor    %esi,%esi
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  nopl   0x0(%rax)
L58:
  xor    %eax,%eax
  xor    %r13d,%r13d
  lea    (%r12,%rsi,1),%r8
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x1,%rax
  cmp    $0x19,%rax
  je     L131
L76:
  movzbl (%r8,%rax,1),%edx
  mov    %eax,%edi
  lea    0x0(%rbp,%rax,1),%ecx
  mov    %rsi,%rbx
  test   %dl,%dl
  je     L102
  cmp    $0x20,%dl
  je     L138
  cmp    $0x9,%dl
  jne    L47
L138:
  add    $0x1,%rax
  mov    %ecx,%r13d
  cmp    $0x19,%rax
  jne    L76
L131:
  mov    $0x19,%edi
L102:
  test   %r13d,%r13d
  jne    L129
  lea    (%rdi,%rbp,1),%r14d
  cmp    %ebp,%r14d
  jle    L126
  mov    %r14d,%ebp
  nopl   0x0(%rax)
L140:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jg     L140
  mov    $0xa,%edi
  call   <putchar@plt>
  test   %r13d,%r13d
  je     L19
L70:
  add    $0x1,%ebp
L19:
  movslq %ebp,%rsi
  cmpb   $0x0,(%r12,%rsi,1)
  jne    L58
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L129:
  cmp    %ebp,%r13d
  jle    L61
  mov    %r13d,%ebp
  jmp    L140
L126:
  mov    $0xa,%edi
  mov    %r14d,%ebp
  call   <putchar@plt>
  jmp    L19
L61:
  mov    $0xa,%edi
  mov    %r13d,%ebp
  call   <putchar@plt>
  jmp    L70
L107:
  ret
```

assistant: ```c
void printwrap(char line[]) {
  int i, lastbreak, start, stop;
  i = 0;
  lastbreak = 0;
  start = 0;
  while (line[start] != '\0') {
    lastbreak = 0;
    for (i = 0; i < 25 && line[start + i] != '\0'; i++) {
      if (line[start + i] == ' ' || line[start + i] == '\t')
        lastbreak = start + i;
    }
    if (!lastbreak) {
      stop = start + i;
    } else {
      stop = lastbreak;
    }
    for (i = start; i < stop; i++) {
      putchar(line[i]);
    }
    putchar('\n');
    start = stop;
    if (lastbreak)
      start++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_input_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L32
  cmpl   $0x0,-0x24(%rbp)
  jle    L32
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  jmp    L43
L32:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  jne    L31
  mov    -0x24(%rbp),%eax
  jmp    L43
L31:
  mov    $0x0,%eax
L43:
  leave
  ret
```

assistant: ```c
int file_input_func(void *user_data, unsigned char *buffer, const int count) {
  FILE *fp = (FILE *)user_data;
  if (buffer && count > 0) {
    return (int)fread(buffer, 1, (size_t)count, fp);
  } else if (fseek(fp, count, SEEK_CUR) == 0) {
    return count;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<file_input_func>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %edx,%ebx
  test   %rsi,%rsi
  je     L5
  mov    %rsi,%rdi
  test   %edx,%edx
  jle    L5
  movslq %edx,%rdx
  mov    $0x1,%esi
  call   <fread@plt>
  jmp    L16
L5:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    %ebx,%esi
  mov    %rcx,%rdi
  call   <fseek@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %ebx,%eax
L16:
  pop    %rbx
  ret
```

assistant: ```c
int file_input_func(void *user_data, unsigned char *buffer, const int count) {
  FILE *fp = (FILE *)user_data;
  if (buffer && count > 0) {
    return (int)fread(buffer, 1, (size_t)count, fp);
  } else if (fseek(fp, count, SEEK_CUR) == 0) {
    return count;
  } else {
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<file_input_func>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %edx,%ebx
  test   %rsi,%rsi
  je     L2
  test   %edx,%edx
  jle    L2
  mov    %rsi,%rdi
  movslq %edx,%rdx
  mov    %r8,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    D0(%rip),%rax
  mov    %ebx,%esi
  mov    %r8,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int file_input_func(void *user_data, unsigned char *buffer, const int count) {
  FILE *fp = (FILE *)user_data;
  if (buffer && count > 0) {
    return (int)fread(buffer, 1, (size_t)count, fp);
  } else if (fseek(fp, count, SEEK_CUR) == 0) {
    return count;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_input_func>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %edx,%ebx
  test   %rsi,%rsi
  je     L9
  test   %edx,%edx
  jle    L9
  mov    %rsi,%rdi
  movslq %edx,%rdx
  mov    %r8,%rcx
  mov    $0x1,%esi
  call   <fread@plt>
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    D5(%rip),%rax
  mov    %ebx,%esi
  mov    %r8,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int file_input_func(void *user_data, unsigned char *buffer, const int count) {
  FILE *fp = (FILE *)user_data;
  if (buffer && count > 0) {
    return (int)fread(buffer, 1, (size_t)count, fp);
  } else if (fseek(fp, count, SEEK_CUR) == 0) {
    return count;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argv_get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L42
  mov    $0x0,%eax
  jmp    L66
L42:
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L57:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L31
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L57
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L43
  mov    $0x0,%eax
  jmp    L66
L43:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
L66:
  pop    %rbp
  ret
```

assistant: ```c
char *argv_get(char **argv, int idx) {
  int i;
  if (!argv)
    return NULL;
  for (i = 0; i < idx && argv[i]; i++)
    ;
  if (i < idx)
    return NULL;
  return argv[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argv_get>:
  endbr64
  test   %rdi,%rdi
  je     L1
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rdx
  mov    $0x0,%eax
L52:
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  je     L58
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %eax,%esi
  jne    L52
L22:
  mov    %esi,%eax
L69:
  cltq
  mov    (%rdi,%rax,8),%rcx
L68:
  mov    %rcx,%rax
  ret
L58:
  cmp    %eax,%esi
  jle    L69
  jmp    L68
L1:
  mov    %rdi,%rcx
  jmp    L68
L10:
  mov    $0x0,%esi
  jmp    L22
```

assistant: ```c
char *argv_get(char **argv, int idx) {
  int i;
  if (!argv)
    return NULL;
  for (i = 0; i < idx && argv[i]; i++)
    ;
  if (i < idx)
    return NULL;
  return argv[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<argv_get>:
  endbr64
  test   %rdi,%rdi
  je     L1
  lea    0x1(%rsi),%ecx
  mov    $0x1,%eax
  test   %esi,%esi
  jg     L42
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L59:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L37
L42:
  mov    -0x8(%rdi,%rax,8),%r8
  test   %r8,%r8
  jne    L59
L5:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  lea    (%rdi,%rdx,8),%rdi
L55:
  mov    (%rdi),%r8
  mov    %r8,%rax
  ret
L1:
  xor    %r8d,%r8d
  jmp    L5
```

assistant: ```c
char *argv_get(char **argv, int idx) {
  int i;
  if (!argv)
    return NULL;
  for (i = 0; i < idx && argv[i]; i++)
    ;
  if (i < idx)
    return NULL;
  return argv[i];
}
```
user: What is the c source code of the assembly code below?

```asm
<argv_get>:
  endbr64
  test   %rdi,%rdi
  je     L26
  lea    0x1(%rsi),%ecx
  mov    $0x1,%eax
  test   %esi,%esi
  jg     L12
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L55:
  movslq %eax,%rdx
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L3
L12:
  mov    -0x8(%rdi,%rax,8),%r8
  test   %r8,%r8
  jne    L55
L34:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  lea    (%rdi,%rdx,8),%rdi
L28:
  mov    (%rdi),%r8
  mov    %r8,%rax
  ret
L26:
  xor    %r8d,%r8d
  jmp    L34
```

assistant: ```c
char *argv_get(char **argv, int idx) {
  int i;
  if (!argv)
    return NULL;
  for (i = 0; i < idx && argv[i]; i++)
    ;
  if (i < idx)
    return NULL;
  return argv[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_init@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_inc_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_inc_16@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_dec_16@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_nop@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_ld_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_ldi@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_dec_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_add_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_sub_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_and@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_xor@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_or@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: All tests passed


assistant: ```c
int main() {
  test_init();
  test_reset();
  test_op_inc_8();
  test_reset();
  test_op_inc_16();
  test_reset();
  test_op_dec_16();
  test_reset();
  test_op_nop();
  test_reset();
  test_op_ld_8();
  test_reset();
  test_op_ldi();
  test_reset();
  test_op_dec_8();
  test_reset();
  test_op_add_8();
  test_reset();
  test_op_sub_8();
  test_reset();
  test_op_and();
  test_reset();
  test_op_xor();
  test_reset();
  test_op_or();
  printf("All tests passed\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_init@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_inc_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_inc_16@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_dec_16@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_nop@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_ld_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_ldi@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_dec_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_add_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_sub_8@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_and@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_xor@plt>
  mov    $0x0,%eax
  call   <test_reset@plt>
  mov    $0x0,%eax
  call   <test_op_or@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: All tests passed


assistant: ```c
int main() {
  test_init();
  test_reset();
  test_op_inc_8();
  test_reset();
  test_op_inc_16();
  test_reset();
  test_op_dec_16();
  test_reset();
  test_op_nop();
  test_reset();
  test_op_ld_8();
  test_reset();
  test_op_ldi();
  test_reset();
  test_op_dec_8();
  test_reset();
  test_op_add_8();
  test_reset();
  test_op_sub_8();
  test_reset();
  test_op_and();
  test_reset();
  test_op_xor();
  test_reset();
  test_op_or();
  printf("All tests passed\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_init@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_inc_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_inc_16@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_dec_16@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_nop@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_ld_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_ldi@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_dec_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_add_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_sub_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_and@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_xor@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_or@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: All tests passed


assistant: ```c
int main() {
  test_init();
  test_reset();
  test_op_inc_8();
  test_reset();
  test_op_inc_16();
  test_reset();
  test_op_dec_16();
  test_reset();
  test_op_nop();
  test_reset();
  test_op_ld_8();
  test_reset();
  test_op_ldi();
  test_reset();
  test_op_dec_8();
  test_reset();
  test_op_add_8();
  test_reset();
  test_op_sub_8();
  test_reset();
  test_op_and();
  test_reset();
  test_op_xor();
  test_reset();
  test_op_or();
  printf("All tests passed\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_init@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_inc_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_inc_16@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_dec_16@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_nop@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_ld_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_ldi@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_dec_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_add_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_sub_8@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_and@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_xor@plt>
  xor    %eax,%eax
  call   <test_reset@plt>
  xor    %eax,%eax
  call   <test_op_or@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: All tests passed


assistant: ```c
int main() {
  test_init();
  test_reset();
  test_op_inc_8();
  test_reset();
  test_op_inc_16();
  test_reset();
  test_op_dec_16();
  test_reset();
  test_op_nop();
  test_reset();
  test_op_ld_8();
  test_reset();
  test_op_ldi();
  test_reset();
  test_op_dec_8();
  test_reset();
  test_op_add_8();
  test_reset();
  test_op_sub_8();
  test_reset();
  test_op_and();
  test_reset();
  test_op_xor();
  test_reset();
  test_op_or();
  printf("All tests passed\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_num_and_caps_lights>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L9
  mov    $0x20,%ecx
  jmp    L3
L9:
  mov    $0x2d,%ecx
L3:
  mov    -0x34(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L32
  mov    $0x20,%edx
  jmp    L15
L32:
  mov    $0x2d,%edx
L15:
  lea    -0x30(%rbp),%rax
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: xset %cled 2 %cled 1

assistant: ```c
void set_num_and_caps_lights(int lights) {
  char command[32];
  sprintf(command, "xset %cled 2 %cled 1", (lights & 2) ? ' ' : '-', (lights & 1) ? ' ' : '-');
  system(command);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_num_and_caps_lights>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %ecx,%ecx
  and    $0xd,%ecx
  add    $0x20,%ecx
  and    $0x2,%edi
  cmp    $0x1,%edi
  sbb    %edx,%edx
  and    $0xd,%edx
  add    $0x20,%edx
  mov    %rsp,%rbx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: xset %cled 2 %cled 1

assistant: ```c
void set_num_and_caps_lights(int lights) {
  char command[32];
  sprintf(command, "xset %cled 2 %cled 1", (lights & 2) ? ' ' : '-', (lights & 1) ? ' ' : '-');
  system(command);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_num_and_caps_lights>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  mov    %edi,%eax
  mov    %rsp,%rbp
  and    $0x1,%eax
  cmp    $0x1,%eax
  sbb    %ecx,%ecx
  and    $0x2,%edi
  and    $0xd,%ecx
  add    $0x20,%ecx
  cmp    $0x1,%edi
  mov    %rbp,%rdi
  sbb    %edx,%edx
  and    $0xd,%edx
  add    $0x20,%edx
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: xset %cled 2 %cled 1

assistant: ```c
void set_num_and_caps_lights(int lights) {
  char command[32];
  sprintf(command, "xset %cled 2 %cled 1", (lights & 2) ? ' ' : '-', (lights & 1) ? ' ' : '-');
  system(command);
}
```