ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fifo_read>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <read@plt>
  mov    %rax,%rbx
  cmp    $0xffffffffffffffff,%rax
  je     L1
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D13(%rip),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <abort_report@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string

tool: 

tool: D10: daemon: Could not read from fifo

assistant: ```c
void fifo_read(int fd, void *buf, size_t len) {
  size_t z;
  if ((z = read(fd, buf, len)) == -1)
    (1 == 1) ? abort_report("daemon: Could not read from fifo", "") : abort_report("daemon: Could not read from fifo");
  ((char *)buf)[z] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<close_out_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fclose@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fclose@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void close_out_err(void) {
  fclose(stdout);
  fclose(stderr);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<close_out_err>:
  endbr64
  sub    $0x8,%rsp
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void close_out_err(void) {
  fclose(stdout);
  fclose(stderr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<close_out_err>:
  endbr64
  sub    $0x8,%rsp
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1050 <fclose@plt>
```

assistant: ```c
void close_out_err(void) {
  fclose(stdout);
  fclose(stderr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<close_out_err>:
  endbr64
  sub    $0x8,%rsp
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <fclose@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1050 <fclose@plt>
```

assistant: ```c
void close_out_err(void) {
  fclose(stdout);
  fclose(stderr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<squeeze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L9:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  shrl   $0x8,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0xf,-0x8(%rbp)
  jbe    L9
  mov    -0x18(%rbp),%rax
  add    $0x40,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x40,%rax
  mov    -0x4(%rbp),%edx
  and    $0x3,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L26:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  shrl   $0x8,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  cmpl   $0xf,-0x8(%rbp)
  jbe    L26
  mov    -0x18(%rbp),%rax
  add    $0x40,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void squeeze(unsigned int h[17]) {
  unsigned int j;
  unsigned int u;
  u = 0;
  for (j = 0; j < 16; ++j) {
    u += h[j];
    h[j] = u & 255;
    u >>= 8;
  }
  u += h[16];
  h[16] = u & 3;
  u = 5 * (u >> 2);
  for (j = 0; j < 16; ++j) {
    u += h[j];
    h[j] = u & 255;
    u >>= 8;
  }
  u += h[16];
  h[16] = u;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<squeeze>:
  endbr64
  mov    %rdi,%rdx
  lea    0x40(%rdi),%rsi
  mov    %rdi,%rcx
  mov    $0x0,%eax
L9:
  add    (%rcx),%eax
  movzbl %al,%r8d
  mov    %r8d,(%rcx)
  shr    $0x8,%eax
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L9
  add    0x40(%rdi),%eax
  mov    %eax,%ecx
  and    $0x3,%ecx
  mov    %ecx,0x40(%rdi)
  mov    %eax,%ecx
  shr    $0x2,%ecx
  and    $0xfffffffc,%eax
  add    %ecx,%eax
L0:
  add    (%rdx),%eax
  movzbl %al,%ecx
  mov    %ecx,(%rdx)
  shr    $0x8,%eax
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L0
  add    %eax,0x40(%rdi)
  ret
```

assistant: ```c
void squeeze(unsigned int h[17]) {
  unsigned int j;
  unsigned int u;
  u = 0;
  for (j = 0; j < 16; ++j) {
    u += h[j];
    h[j] = u & 255;
    u >>= 8;
  }
  u += h[16];
  h[16] = u & 3;
  u = 5 * (u >> 2);
  for (j = 0; j < 16; ++j) {
    u += h[j];
    h[j] = u & 255;
    u >>= 8;
  }
  u += h[16];
  h[16] = u;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squeeze>:
  endbr64
  mov    %rdi,%rdx
  lea    0x40(%rdi),%rsi
  mov    %rdi,%rcx
  xor    %eax,%eax
L18:
  add    (%rcx),%eax
  add    $0x4,%rcx
  movzbl %al,%r8d
  shr    $0x8,%eax
  mov    %r8d,-0x4(%rcx)
  cmp    %rsi,%rcx
  jne    L18
  add    0x40(%rdi),%eax
  mov    %eax,%ecx
  and    $0x3,%ecx
  mov    %ecx,0x40(%rdi)
  mov    %eax,%ecx
  and    $0xfffffffc,%eax
  shr    $0x2,%ecx
  add    %ecx,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  add    (%rdx),%eax
  add    $0x4,%rdx
  movzbl %al,%ecx
  shr    $0x8,%eax
  mov    %ecx,-0x4(%rdx)
  cmp    %rsi,%rdx
  jne    L7
  add    %eax,0x40(%rdi)
  ret
```

assistant: ```c
void squeeze(unsigned int h[17]) {
  unsigned int j;
  unsigned int u;
  u = 0;
  for (j = 0; j < 16; ++j) {
    u += h[j];
    h[j] = u & 255;
    u >>= 8;
  }
  u += h[16];
  h[16] = u & 3;
  u = 5 * (u >> 2);
  for (j = 0; j < 16; ++j) {
    u += h[j];
    h[j] = u & 255;
    u >>= 8;
  }
  u += h[16];
  h[16] = u;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x10(%rbp)
  movl   $0x3,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x10(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <printid@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string

tool: D8: a 2 1

assistant: ```c
int main() {
  int a[2] = {2, 3};
  a[1] /= a[0];
  print("a 2 1");
  printid(a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  lea    D6(%rip),%rdi
  call   <print@plt>
  mov    %rsp,%rdi
  call   <printid@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: a 2 1

assistant: ```c
int main() {
  int a[2] = {2, 3};
  a[1] /= a[0];
  print("a 2 1");
  printid(a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,(%rsp)
  call   <print@plt>
  mov    %rsp,%rdi
  call   <printid@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: a 2 1

assistant: ```c
int main() {
  int a[2] = {2, 3};
  a[1] /= a[0];
  print("a 2 1");
  printid(a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rax,(%rsp)
  call   <print@plt>
  mov    %rsp,%rdi
  call   <printid@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string
name: read_data
arguments: data_tag: D5
data_type: byte[8]

tool: D4: a 2 1

tool: {"D5": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[2] = {2, 3};
  a[1] /= a[0];
  print("a 2 1");
  printid(a);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<pc2str644>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  and    $0xf,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x4,%rax
  and    $0xf,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  sar    $0x8,%rax
  and    $0x3f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %esi,%r8d
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: %d-%d-%d

assistant: ```c
void pc2str644(long pc, char *pcstr) {
  int a;
  int b;
  int c;
  c = pc & 0x0F;
  b = (pc >> 4) & 0x0F;
  a = (pc >> 8) & 0x3F;
  sprintf(pcstr, "%d-%d-%d", a, b, c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pc2str644>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %r8,%rcx
  sar    $0x4,%rcx
  and    $0xf,%ecx
  mov    %r8,%rdx
  sar    $0x8,%rdx
  and    $0x3f,%edx
  and    $0xf,%r8d
  lea    D8(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %d-%d-%d

assistant: ```c
void pc2str644(long pc, char *pcstr) {
  int a;
  int b;
  int c;
  c = pc & 0x0F;
  b = (pc >> 4) & 0x0F;
  a = (pc >> 8) & 0x3F;
  sprintf(pcstr, "%d-%d-%d", a, b, c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pc2str644>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  lea    D6(%rip),%rsi
  mov    %r8,%rcx
  mov    %r8,%rdx
  and    $0xf,%r8d
  sar    $0x4,%rcx
  sar    $0x8,%rdx
  and    $0xf,%ecx
  and    $0x3f,%edx
  jmp    1050 <sprintf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: %d-%d-%d

assistant: ```c
void pc2str644(long pc, char *pcstr) {
  int a;
  int b;
  int c;
  c = pc & 0x0F;
  b = (pc >> 4) & 0x0F;
  a = (pc >> 8) & 0x3F;
  sprintf(pcstr, "%d-%d-%d", a, b, c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pc2str644>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  lea    D0(%rip),%rsi
  mov    %r8,%rcx
  mov    %r8,%rdx
  and    $0xf,%r8d
  sar    $0x4,%rcx
  sar    $0x8,%rdx
  and    $0xf,%ecx
  and    $0x3f,%edx
  jmp    1050 <sprintf@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: %d-%d-%d

assistant: ```c
void pc2str644(long pc, char *pcstr) {
  int a;
  int b;
  int c;
  c = pc & 0x0F;
  b = (pc >> 4) & 0x0F;
  a = (pc >> 8) & 0x3F;
  sprintf(pcstr, "%d-%d-%d", a, b, c);
}
```
user: Translate the below assembly code into C programming language:

```asm
<findChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L35
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L36
  mov    -0x8(%rbp),%rax
  jmp    L27
L36:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
char *findChar(char *str, char c) {
  char *ptrStr = str;
  while (*ptrStr != '\0') {
    if (*ptrStr == c) {
      return ptrStr;
    }
    ptrStr++;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findChar>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
L17:
  cmp    %al,%sil
  je     L7
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L17
  mov    $0x0,%eax
  ret
L18:
  mov    $0x0,%eax
  ret
L7:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *findChar(char *str, char c) {
  char *ptrStr = str;
  while (*ptrStr != '\0') {
    if (*ptrStr == c) {
      return ptrStr;
    }
    ptrStr++;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findChar>:
  endbr64
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L15:
  cmp    %al,%sil
  je     L1
  add    $0x1,%rdi
L13:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L15
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *findChar(char *str, char c) {
  char *ptrStr = str;
  while (*ptrStr != '\0') {
    if (*ptrStr == c) {
      return ptrStr;
    }
    ptrStr++;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findChar>:
  endbr64
  jmp    L15
  cs nopw 0x0(%rax,%rax,1)
L23:
  cmp    %al,%sil
  je     L12
  add    $0x1,%rdi
L15:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *findChar(char *str, char c) {
  char *ptrStr = str;
  while (*ptrStr != '\0') {
    if (*ptrStr == c) {
      return ptrStr;
    }
    ptrStr++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RmExtraWhiteSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L31
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L36
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L55
  cmpl   $0x0,-0x18(%rbp)
  je     L55
  addq   $0x1,-0x10(%rbp)
  jmp    L36
L55:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L71
  movl   $0x0,-0x18(%rbp)
  jmp    L41
L71:
  mov    -0x10(%rbp),%rax
  movb   $0x20,(%rax)
  movl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L41:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x1c(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x1c(%rbp)
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L36:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L31:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int RmExtraWhiteSpaces(char *str) {
  char *ibuf, *obuf;
  int i, cnt;
  int wsCnt = 0;
  if (str) {
    ibuf = obuf = str;
    i = cnt = 0;
    while (*ibuf) {
      if (isspace(*ibuf) && cnt)
        ibuf++;
      else {
        if (!isspace(*ibuf))
          cnt = 0;
        else {
          *ibuf = ' ';
          cnt = 1;
          wsCnt++;
        }
        obuf[i++] = *ibuf++;
      }
    }
    obuf[i] = '\0';
  }
  return (wsCnt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RmExtraWhiteSpaces>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r15d
  test   %rdi,%rdi
  je     L60
  mov    %rdi,%r14
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L15
  lea    0x1(%r14),%rbx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  jmp    L19
L51:
  mov    %rbx,%rbp
  movsbl -0x1(%rbx),%edi
  call   <isspace@plt>
  mov    $0x0,%r13d
  test   %rax,%rax
  je     L13
  movb   $0x20,-0x1(%rbx)
  add    $0x1,%r15d
  mov    $0x1,%r13d
L13:
  movzbl -0x1(%rbp),%edx
  movslq %r12d,%rax
  mov    %dl,(%r14,%rax,1)
  lea    0x1(%r12),%r12d
L11:
  movzbl 0x0(%rbp),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L28
L19:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %r13d,%r13d
  je     L51
  mov    %rbx,%rbp
  test   %rax,%rax
  jne    L11
  jmp    L51
L15:
  mov    $0x0,%r15d
  mov    $0x0,%r12d
L28:
  movslq %r12d,%r12
  movb   $0x0,(%r14,%r12,1)
L60:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int RmExtraWhiteSpaces(char *str) {
  char *ibuf, *obuf;
  int i, cnt;
  int wsCnt = 0;
  if (str) {
    ibuf = obuf = str;
    i = cnt = 0;
    while (*ibuf) {
      if (isspace(*ibuf) && cnt)
        ibuf++;
      else {
        if (!isspace(*ibuf))
          cnt = 0;
        else {
          *ibuf = ' ';
          cnt = 1;
          wsCnt++;
        }
        obuf[i++] = *ibuf++;
      }
    }
    obuf[i] = '\0';
  }
  return (wsCnt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RmExtraWhiteSpaces>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L55
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L33
  mov    %r12,%r14
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  jmp    L43
  nopl   0x0(%rax)
L48:
  movzbl -0x1(%r14),%edx
  xor    %ebp,%ebp
L9:
  movslq %ebx,%rax
  add    $0x1,%ebx
  mov    %dl,(%r12,%rax,1)
L5:
  movsbl (%r14),%edi
  test   %dil,%dil
  je     L4
L43:
  call   <isspace@plt>
  add    $0x1,%r14
  test   %rax,%rax
  je     L7
  mov    %ebp,%eax
  mov    $0x1,%ebp
  and    $0x1,%eax
  test   %al,%al
  jne    L5
L7:
  movsbl -0x1(%r14),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L48
  movb   $0x20,-0x1(%r14)
  add    $0x1,%r13d
  mov    $0x20,%edx
  mov    $0x1,%ebp
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L4:
  movslq %ebx,%rbx
  add    %rbx,%r12
L33:
  movb   $0x0,(%r12)
L55:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int RmExtraWhiteSpaces(char *str) {
  char *ibuf, *obuf;
  int i, cnt;
  int wsCnt = 0;
  if (str) {
    ibuf = obuf = str;
    i = cnt = 0;
    while (*ibuf) {
      if (isspace(*ibuf) && cnt)
        ibuf++;
      else {
        if (!isspace(*ibuf))
          cnt = 0;
        else {
          *ibuf = ' ';
          cnt = 1;
          wsCnt++;
        }
        obuf[i++] = *ibuf++;
      }
    }
    obuf[i] = '\0';
  }
  return (wsCnt);
}
```
user: What is the c source code of the assembly code below?

```asm
<RmExtraWhiteSpaces>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L22
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L74
  mov    %r12,%r14
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  jmp    L36
  nopl   0x0(%rax)
L60:
  movzbl -0x1(%r14),%edx
  xor    %ebp,%ebp
L46:
  movslq %ebx,%rax
  add    $0x1,%ebx
  mov    %dl,(%r12,%rax,1)
L75:
  movsbl (%r14),%edi
  test   %dil,%dil
  je     L5
L36:
  call   <isspace@plt>
  add    $0x1,%r14
  test   %rax,%rax
  je     L38
  mov    %ebp,%eax
  mov    $0x1,%ebp
  and    $0x1,%eax
  test   %al,%al
  jne    L75
L38:
  movsbl -0x1(%r14),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L60
  movb   $0x20,-0x1(%r14)
  add    $0x1,%r13d
  mov    $0x20,%edx
  mov    $0x1,%ebp
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L5:
  movslq %ebx,%rbx
  add    %rbx,%r12
L74:
  movb   $0x0,(%r12)
L22:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int RmExtraWhiteSpaces(char *str) {
  char *ibuf, *obuf;
  int i, cnt;
  int wsCnt = 0;
  if (str) {
    ibuf = obuf = str;
    i = cnt = 0;
    while (*ibuf) {
      if (isspace(*ibuf) && cnt)
        ibuf++;
      else {
        if (!isspace(*ibuf))
          cnt = 0;
        else {
          *ibuf = ' ';
          cnt = 1;
          wsCnt++;
        }
        obuf[i++] = *ibuf++;
      }
    }
    obuf[i] = '\0';
  }
  return (wsCnt);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<costforstudent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L4
L26:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L25
L0:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <lookforcourse@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <lookforcourse@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <distancecost@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x1c(%rbp)
L25:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L0
  addl   $0x1,-0x20(%rbp)
L4:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L26
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double costforstudent(int *student, struct courseintb **timetable, int timeslots) {
  double studentcost = 0.0;
  int temp = 0, temp2 = 0, distance = 0, distance2 = 0, i = 0, j = 0;
  while (student[i] != 0) {
    temp = student[i];
    j = i;
    while (student[j + 1] != 0) {
      temp2 = student[j + 1];
      distance = lookforcourse(temp, timetable, timeslots);
      distance2 = lookforcourse(temp2, timetable, timeslots);
      studentcost += distancecost(distance, distance2);
      j++;
    }
    i++;
  }
  return studentcost;
}
```