user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x8d0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28b0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x28bc(%rbp),%rdx
  lea    -0x28c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x28b8(%rbp)
  jmp    L112
L27:
  lea    -0x2720(%rbp),%rdx
  mov    -0x28b8(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28b8(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  jne    L136
  subl   $0x1,-0x28b8(%rbp)
L136:
  addl   $0x1,-0x28b8(%rbp)
L112:
  mov    -0x28c0(%rbp),%edx
  mov    -0x28bc(%rbp),%eax
  imul   %edx,%eax
  cmp    %eax,-0x28b8(%rbp)
  jl     L27
  movl   $0x0,-0x28b4(%rbp)
  jmp    L40
L87:
  movb   $0x30,-0x28c1(%rbp)
  mov    -0x28b4(%rbp),%eax
  mov    %eax,-0x28b8(%rbp)
  jmp    L125
L43:
  mov    -0x28b8(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  cmp    %al,-0x28c1(%rbp)
  jge    L46
  mov    -0x28b8(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  mov    %al,-0x28c1(%rbp)
L46:
  mov    -0x28bc(%rbp),%eax
  add    %eax,-0x28b8(%rbp)
L125:
  mov    -0x28bc(%rbp),%edx
  mov    -0x28c0(%rbp),%eax
  imul   %edx,%eax
  cmp    %eax,-0x28b8(%rbp)
  jl     L43
  mov    -0x28b4(%rbp),%eax
  mov    %eax,-0x28b8(%rbp)
  jmp    L17
L64:
  mov    -0x28b8(%rbp),%eax
  cltq
  movzbl -0x2720(%rbp,%rax,1),%eax
  cmp    %al,-0x28c1(%rbp)
  jne    L108
  mov    -0x28bc(%rbp),%ecx
  mov    -0x28b8(%rbp),%eax
  cltd
  idiv   %ecx
  cltq
  movl   $0x1,-0x28b0(%rbp,%rax,4)
L108:
  mov    -0x28bc(%rbp),%eax
  add    %eax,-0x28b8(%rbp)
L17:
  mov    -0x28bc(%rbp),%edx
  mov    -0x28c0(%rbp),%eax
  imul   %edx,%eax
  cmp    %eax,-0x28b8(%rbp)
  jl     L64
  addl   $0x1,-0x28b4(%rbp)
L40:
  mov    -0x28bc(%rbp),%eax
  cmp    %eax,-0x28b4(%rbp)
  jl     L87
  movl   $0x0,-0x28b4(%rbp)
  movl   $0x0,-0x28b8(%rbp)
  jmp    L53
L117:
  mov    -0x28b8(%rbp),%eax
  cltq
  mov    -0x28b0(%rbp,%rax,4),%eax
  add    %eax,-0x28b4(%rbp)
  addl   $0x1,-0x28b8(%rbp)
L53:
  mov    -0x28c0(%rbp),%eax
  cmp    %eax,-0x28b8(%rbp)
  jl     L117
  mov    -0x28b4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
data_type: string
name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D17: %d%d

tool: D5: %c

tool: D8: %d

assistant: ```c
int main(void) {
  int students, mark, successful, counts, countm, stds[100] = {0};
  char marks[10001], larger;
  scanf("%d%d", &students, &mark);
  for (counts = 0; counts < students * mark; counts++) {
    scanf("%c", &marks[counts]);
    if (marks[counts] == '\n')
      counts--;
  }
  for (countm = 0; countm < mark; countm++) {
    larger = '0';
    for (counts = countm; counts < mark * students; counts += mark) {
      if (marks[counts] > larger)
        larger = marks[counts];
    }
    for (counts = countm; counts < mark * students; counts += mark) {
      if (marks[counts] == larger)
        stds[counts / mark] = 1;
    }
  }
  countm = 0;
  for (counts = 0; counts < students; counts++)
    countm += stds[counts];
  printf("%d", countm);
  return 0;
}
```