ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L12
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L11
L12:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L4
  movl   $0x1,-0x4(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <run_file@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string

tool: D7: Usage: %s input-file


tool: D1: DEBUG

assistant: ```c
int main(int argc, char **argv) {
  int dump_registers = 0;
  if (argc < 2) {
    printf("Usage: %s input-file\n", argv[0]);
    return 0;
  }
  if (getenv("DEBUG") != NULL)
    dump_registers = 1;
  return (run_file(argv[1], dump_registers));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L10
  lea    D4(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  setne  %sil
  movzbl %sil,%esi
  mov    0x8(%rbx),%rdi
  call   <run_file@plt>
L15:
  pop    %rbx
  ret
L10:
  mov    (%rsi),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L15
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D14
datatype: string

tool: D4: DEBUG

tool: D14: Usage: %s input-file


assistant: ```c
int main(int argc, char **argv) {
  int dump_registers = 0;
  if (argc < 2) {
    printf("Usage: %s input-file\n", argv[0]);
    return 0;
  }
  if (getenv("DEBUG") != NULL)
    dump_registers = 1;
  return (run_file(argv[1], dump_registers));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L2
  lea    D15(%rip),%rdi
  call   <getenv@plt>
  xor    %esi,%esi
  mov    0x8(%rbx),%rdi
  pop    %rbx
  test   %rax,%rax
  setne  %sil
  jmp    1080 <run_file@plt>
L2:
  mov    (%rsi),%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string

tool: D15: DEBUG

tool: D19: Usage: %s input-file


assistant: ```c
int main(int argc, char **argv) {
  int dump_registers = 0;
  if (argc < 2) {
    printf("Usage: %s input-file\n", argv[0]);
    return 0;
  }
  if (getenv("DEBUG") != NULL)
    dump_registers = 1;
  return (run_file(argv[1], dump_registers));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L0
  lea    D9(%rip),%rdi
  call   <getenv@plt>
  xor    %esi,%esi
  mov    0x8(%rbx),%rdi
  pop    %rbx
  test   %rax,%rax
  setne  %sil
  jmp    1080 <run_file@plt>
L0:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string
name: read_data
arguments: data_label: D1
datatype: string

tool: D9: DEBUG

tool: D1: Usage: %s input-file


assistant: ```c
int main(int argc, char **argv) {
  int dump_registers = 0;
  if (argc < 2) {
    printf("Usage: %s input-file\n", argv[0]);
    return 0;
  }
  if (getenv("DEBUG") != NULL)
    dump_registers = 1;
  return (run_file(argv[1], dump_registers));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x3e8,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L30
L23:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L36
  addl   $0x1,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L36
  mov    -0x18(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L36:
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L23
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string
name: disassemble_data
arguments: tag: D4
data_type: string

tool: D9: The sum of %3d primes in [2, %3d] is %5d which is also prime


tool: D4: There are %d summerized primes in [%d, %d)


assistant: ```c
int main() {
  const int start = 1;
  const int stop = 1000;
  int sum = 0;
  int count = 0;
  int sc = 0;
  int p;
  for (p = start; p < stop; p++) {
    if (is_prime(p)) {
      count++;
      sum += p;
      if (is_prime(sum)) {
        printf("The sum of %3d primes in [2, %3d] is %5d which is also prime\n", count, p, sum);
        sc++;
      }
    }
  }
  printf("There are %d summerized primes in [%d, %d)\n", sc, start, stop);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D0(%rip),%r14
  jmp    L19
L45:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L4
L19:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L45
  add    $0x1,%r12d
  add    %ebx,%ebp
  mov    %ebp,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L45
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  jmp    L45
L4:
  mov    $0x3e8,%ecx
  mov    $0x1,%edx
  mov    %r13d,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D18
type_guessed: string

tool: D0: The sum of %3d primes in [2, %3d] is %5d which is also prime


tool: D18: There are %d summerized primes in [%d, %d)


assistant: ```c
int main() {
  const int start = 1;
  const int stop = 1000;
  int sum = 0;
  int count = 0;
  int sc = 0;
  int p;
  for (p = start; p < stop; p++) {
    if (is_prime(p)) {
      count++;
      sum += p;
      if (is_prime(sum)) {
        printf("The sum of %3d primes in [2, %3d] is %5d which is also prime\n", count, p, sum);
        sc++;
      }
    }
  }
  printf("There are %d summerized primes in [%d, %d)\n", sc, start, stop);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L39:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L29
L26:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L39
  add    %ebx,%ebp
  add    $0x1,%r12d
  mov    %ebp,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L39
  mov    %ebx,%edx
  mov    %ebp,%ecx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%r13d
  cmp    $0x3e8,%ebx
  jne    L26
L29:
  mov    %r13d,%esi
  mov    $0x3e8,%ecx
  mov    $0x1,%edx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D1
type: string

tool: D10: The sum of %3d primes in [2, %3d] is %5d which is also prime


tool: D1: There are %d summerized primes in [%d, %d)


assistant: ```c
int main() {
  const int start = 1;
  const int stop = 1000;
  int sum = 0;
  int count = 0;
  int sc = 0;
  int p;
  for (p = start; p < stop; p++) {
    if (is_prime(p)) {
      count++;
      sum += p;
      if (is_prime(sum)) {
        printf("The sum of %3d primes in [2, %3d] is %5d which is also prime\n", count, p, sum);
        sc++;
      }
    }
  }
  printf("There are %d summerized primes in [%d, %d)\n", sc, start, stop);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  je     L31
L35:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L30
  add    %ebx,%ebp
  add    $0x1,%r12d
  mov    %ebp,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L30
  mov    %ebx,%edx
  mov    %ebp,%ecx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x1,%r13d
  cmp    $0x3e8,%ebx
  jne    L35
L31:
  mov    %r13d,%esi
  mov    $0x3e8,%ecx
  mov    $0x1,%edx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D16: The sum of %3d primes in [2, %3d] is %5d which is also prime


tool: D4: There are %d summerized primes in [%d, %d)


assistant: ```c
int main() {
  const int start = 1;
  const int stop = 1000;
  int sum = 0;
  int count = 0;
  int sc = 0;
  int p;
  for (p = start; p < stop; p++) {
    if (is_prime(p)) {
      count++;
      sum += p;
      if (is_prime(sum)) {
        printf("The sum of %3d primes in [2, %3d] is %5d which is also prime\n", count, p, sum);
        sc++;
      }
    }
  }
  printf("There are %d summerized primes in [%d, %d)\n", sc, start, stop);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L19:
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  subss  -0x1c(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  subss  -0x1c(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  ja     L19
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %d * %f Euro


assistant: ```c
void chance(float *money, float chance) {
  int count = 0;
  while (*money - chance > 0) {
    *money = *money - chance;
    count++;
  }
  printf("%d * %f Euro\n", count, chance);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<chance>:
  endbr64
  sub    $0x8,%rsp
  movss  (%rdi),%xmm1
  subss  %xmm0,%xmm1
  mov    $0x0,%esi
  pxor   %xmm2,%xmm2
  comiss %xmm2,%xmm1
  jbe    L21
L9:
  add    $0x1,%esi
  movaps %xmm1,%xmm3
  subss  %xmm0,%xmm1
  comiss %xmm2,%xmm1
  ja     L9
  movss  %xmm3,(%rdi)
L0:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L21:
  mov    $0x0,%esi
  jmp    L0
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d * %f Euro


assistant: ```c
void chance(float *money, float chance) {
  int count = 0;
  while (*money - chance > 0) {
    *money = *money - chance;
    count++;
  }
  printf("%d * %f Euro\n", count, chance);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chance>:
  endbr64
  movss  (%rdi),%xmm1
  pxor   %xmm2,%xmm2
  xor    %esi,%esi
  subss  %xmm0,%xmm1
  comiss %xmm2,%xmm1
  jbe    L1
  nopw   0x0(%rax,%rax,1)
L5:
  movaps %xmm1,%xmm3
  subss  %xmm0,%xmm1
  add    $0x1,%esi
  comiss %xmm2,%xmm1
  ja     L5
  movss  %xmm3,(%rdi)
L1:
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: string

tool: D0: %d * %f Euro


assistant: ```c
void chance(float *money, float chance) {
  int count = 0;
  while (*money - chance > 0) {
    *money = *money - chance;
    count++;
  }
  printf("%d * %f Euro\n", count, chance);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chance>:
  endbr64
  movss  (%rdi),%xmm1
  pxor   %xmm2,%xmm2
  xor    %esi,%esi
  subss  %xmm0,%xmm1
  comiss %xmm2,%xmm1
  jbe    L8
  nopw   0x0(%rax,%rax,1)
L7:
  movaps %xmm1,%xmm3
  subss  %xmm0,%xmm1
  add    $0x1,%esi
  comiss %xmm2,%xmm1
  ja     L7
  movss  %xmm3,(%rdi)
L8:
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: %d * %f Euro


assistant: ```c
void chance(float *money, float chance) {
  int count = 0;
  while (*money - chance > 0) {
    *money = *money - chance;
    count++;
  }
  printf("%d * %f Euro\n", count, chance);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetField37SunCal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x17(%rbp),%rax
  mov    $0xf,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x17(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <AddYearToDate@plt>
  mov    -0x30(%rbp),%rdx
  lea    -0x17(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <juliancal_to_suncal@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void GetField37SunCal(char *field7, char *buf) {
  char curtime[15];
  memset(curtime, 0, 15);
  AddYearToDate(field7, curtime);
  juliancal_to_suncal(curtime, buf);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetField37SunCal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbx
  mov    $0xf,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <AddYearToDate@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <juliancal_to_suncal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void GetField37SunCal(char *field7, char *buf) {
  char curtime[15];
  memset(curtime, 0, 15);
  AddYearToDate(field7, curtime);
  juliancal_to_suncal(curtime, buf);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<GetField37SunCal>:
  endbr64
  push   %r13
  mov    $0xf,%edx
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <AddYearToDate@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <juliancal_to_suncal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void GetField37SunCal(char *field7, char *buf) {
  char curtime[15];
  memset(curtime, 0, 15);
  AddYearToDate(field7, curtime);
  juliancal_to_suncal(curtime, buf);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetField37SunCal>:
  endbr64
  push   %r13
  mov    $0xf,%edx
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x9(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <AddYearToDate@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <juliancal_to_suncal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void GetField37SunCal(char *field7, char *buf) {
  char curtime[15];
  memset(curtime, 0, 15);
  AddYearToDate(field7, curtime);
  juliancal_to_suncal(curtime, buf);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mpfraddd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  movq   %rsi,%xmm0
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpfr_add_d@plt>
  nop
  leave
  ret
```

assistant: ```c
void mpfraddd(mpfr_t r2, mpfr_t r1, double *d, mpfr_rnd_t *irnd) {
  double d1;
  int n1;
  d1 = *d;
  n1 = *irnd;
  mpfr_add_d(r2, r1, d1, n1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mpfraddd>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdx,%rax
  mov    (%rcx),%edx
  movsd  (%rax),%xmm0
  call   <mpfr_add_d@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void mpfraddd(mpfr_t r2, mpfr_t r1, double *d, mpfr_rnd_t *irnd) {
  double d1;
  int n1;
  d1 = *d;
  n1 = *irnd;
  mpfr_add_d(r2, r1, d1, n1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mpfraddd>:
  endbr64
  mov    %rdx,%r8
  mov    (%rcx),%edx
  movsd  (%r8),%xmm0
  jmp    1050 <mpfr_add_d@plt>
```

assistant: ```c
void mpfraddd(mpfr_t r2, mpfr_t r1, double *d, mpfr_rnd_t *irnd) {
  double d1;
  int n1;
  d1 = *d;
  n1 = *irnd;
  mpfr_add_d(r2, r1, d1, n1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mpfraddd>:
  endbr64
  mov    %rdx,%r8
  mov    (%rcx),%edx
  movsd  (%r8),%xmm0
  jmp    1050 <mpfr_add_d@plt>
```

assistant: ```c
void mpfraddd(mpfr_t r2, mpfr_t r1, double *d, mpfr_rnd_t *irnd) {
  double d1;
  int n1;
  d1 = *d;
  n1 = *irnd;
  mpfr_add_d(r2, r1, d1, n1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<kernel4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L16
L11:
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movss  (%rax),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  -0x8(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x24(%rbp)
L16:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void kernel4(int L, float *ai, float *ef) {
  float *p2 = ef;
  float *p1 = ai;
  double mag, t;
  int i;
  for (i = 0; i < L; i++) {
    t = *p2++;
    mag = t * t;
    t = *p2++;
    mag += t * t;
    *p1++ += mag;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel4>:
  endbr64
  test   %edi,%edi
  jle    L16
  mov    %edi,%edi
  lea    (%rdx,%rdi,8),%rax
L18:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdx),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  add    $0x8,%rdx
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rdx),%xmm0
  add    $0x4,%rsi
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rsi)
  cmp    %rdx,%rax
  jne    L18
L16:
  ret
```

assistant: ```c
void kernel4(int L, float *ai, float *ef) {
  float *p2 = ef;
  float *p1 = ai;
  double mag, t;
  int i;
  for (i = 0; i < L; i++) {
    t = *p2++;
    mag = t * t;
    t = *p2++;
    mag += t * t;
    *p1++ += mag;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kernel4>:
  endbr64
  test   %edi,%edi
  jle    L5
  movslq %edi,%rdi
  lea    (%rdx,%rdi,8),%rax
  nop
L15:
  pxor   %xmm0,%xmm0
  add    $0x8,%rdx
  add    $0x4,%rsi
  cvtss2sd -0x8(%rdx),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rdx),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rsi)
  cmp    %rax,%rdx
  jne    L15
L5:
  ret
```

assistant: ```c
void kernel4(int L, float *ai, float *ef) {
  float *p2 = ef;
  float *p1 = ai;
  double mag, t;
  int i;
  for (i = 0; i < L; i++) {
    t = *p2++;
    mag = t * t;
    t = *p2++;
    mag += t * t;
    *p1++ += mag;
  }
}
```