ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<get3array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%eax
  lea    0x0(,%rax,8),%edi
  call   <c_malloc@plt>
  mov    %rax,%r15
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L31
  mov    0x4(%r12),%eax
  mov    %r15,%r13
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L40:
  lea    0x0(,%rax,8),%edi
  call   <c_malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%r12),%eax
  test   %eax,%eax
  jle    L49
  mov    0x8(%r12),%ebx
  xor    %ebp,%ebp
L37:
  lea    0x0(,%rbx,8),%edi
  call   <c_malloc@plt>
  mov    0x8(%r12),%ebx
  mov    %rax,%rdi
  mov    0x0(%r13),%rax
  mov    %rdi,(%rax,%rbp,8)
  test   %ebx,%ebx
  jle    L39
  movslq %ebx,%rdx
  xor    %esi,%esi
  shl    $0x3,%rdx
  call   <memset@plt>
L39:
  mov    0x4(%r12),%eax
  add    $0x1,%rbp
  cmp    %ebp,%eax
  jg     L37
L49:
  add    $0x1,%r14
  add    $0x8,%r13
  cmp    %r14d,(%r12)
  jg     L40
L31:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double ***get3array(int *d) {
  int i[3];
  double ***p = NULL;
  p = (double ***)c_malloc(d[0] * sizeof(double **));
  for (i[0] = 0; i[0] < d[0]; i[0]++) {
    p[i[0]] = (double **)c_malloc(d[1] * sizeof(double *));
    for (i[1] = 0; i[1] < d[1]; i[1]++) {
      p[i[0]][i[1]] = (double *)c_malloc(d[2] * sizeof(double));
      for (i[2] = 0; i[2] < d[2]; i[2]++)
        p[i[0]][i[1]][i[2]] = 0.0;
    }
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_putstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L4
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_putchar@plt>
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_putstr(char const *str) {
  while (*str) {
    ft_putchar(*str);
    str++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L3
L0:
  movsbl %dil,%edi
  call   <ft_putchar@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L3:
  pop    %rbx
  ret
```

assistant: ```c
void ft_putstr(char const *str) {
  while (*str) {
    ft_putchar(*str);
    str++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L1:
  call   <ft_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L2:
  pop    %rbx
  ret
```

assistant: ```c
void ft_putstr(char const *str) {
  while (*str) {
    ft_putchar(*str);
    str++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L14:
  call   <ft_putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L14
L8:
  pop    %rbx
  ret
```

assistant: ```c
void ft_putstr(char const *str) {
  while (*str) {
    ft_putchar(*str);
    str++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_grab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test_grab(int fd) {
  int rc;
  rc = ioctl(fd, EVIOCGRAB, (void *)1);
  if (!rc) {
    ioctl(fd, EVIOCGRAB, (void *)0);
  }
  return rc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_grab>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x1,%edx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L13
L14:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0x0,%edx
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    %ebp,%edi
  call   <ioctl@plt>
  jmp    L14
```

assistant: ```c
int test_grab(int fd) {
  int rc;
  rc = ioctl(fd, EVIOCGRAB, (void *)1);
  if (!rc) {
    ioctl(fd, EVIOCGRAB, (void *)0);
  }
  return rc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_grab>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    D8(%rip),%rbx
  mov    (%rbx),%esi
  call   <ioctl@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L7
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  xor    %edx,%edx
  call   <ioctl@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int test_grab(int fd) {
  int rc;
  rc = ioctl(fd, EVIOCGRAB, (void *)1);
  if (!rc) {
    ioctl(fd, EVIOCGRAB, (void *)0);
  }
  return rc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_grab>:
  endbr64
  push   %r12
  mov    $0x1,%edx
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    D9(%rip),%rbx
  mov    (%rbx),%esi
  call   <ioctl@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L9
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  xor    %edx,%edx
  call   <ioctl@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int test_grab(int fd) {
  int rc;
  rc = ioctl(fd, EVIOCGRAB, (void *)1);
  if (!rc) {
    ioctl(fd, EVIOCGRAB, (void *)0);
  }
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_begin_end_dates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4c0,%rsp
  mov    %rdi,-0x4a8(%rbp)
  mov    %rsi,-0x4b0(%rbp)
  mov    %rdx,-0x4b8(%rbp)
  mov    %rcx,-0x4c0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4c0(%rbp),%rcx
  mov    -0x4b8(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x498(%rbp)
  mov    -0x498(%rbp),%rdx
  lea    -0x490(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  je     L15
  lea    -0x490(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x4a8(%rbp),%rax
  mov    %rdx,(%rax)
L15:
  mov    -0x498(%rbp),%rdx
  lea    -0x490(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  je     L0
  lea    -0x490(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rdx
  mov    -0x4b0(%rbp),%rax
  mov    %rdx,(%rax)
L0:
  mov    -0x498(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D14
datatype: string

tool: D7: cr10_parse "%s" "%s" y

tool: D14: r

assistant: ```c
void parse_begin_end_dates(char **begin_date_string, char **end_date_string, char *filename, char *station) {
  char sys_string[1024];
  FILE *input_pipe;
  char input_buffer[128];
  sprintf(sys_string, "cr10_parse \"%s\" \"%s\" y", filename, station);
  input_pipe = popen(sys_string, "r");
  if (get_line(input_buffer, input_pipe)) {
    *begin_date_string = strdup(input_buffer);
  }
  if (get_line(input_buffer, input_pipe)) {
    *end_date_string = strdup(input_buffer);
  }
  pclose(input_pipe);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_begin_end_dates>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x490,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x488(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbx
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <popen@plt>
  mov    %rax,%rbx
  mov    %rsp,%rdi
  mov    %rax,%rsi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L45
L11:
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L34
L31:
  mov    %rbx,%rdi
  call   <pclose@plt>
  mov    0x488(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x490,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  jmp    L11
L34:
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    %rax,0x0(%rbp)
  jmp    L31
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type: string
name: disassemble_data
arguments: data_tag: D8
type: string

tool: D10: cr10_parse "%s" "%s" y

tool: D8: r

assistant: ```c
void parse_begin_end_dates(char **begin_date_string, char **end_date_string, char *filename, char *station) {
  char sys_string[1024];
  FILE *input_pipe;
  char input_buffer[128];
  sprintf(sys_string, "cr10_parse \"%s\" \"%s\" y", filename, station);
  input_pipe = popen(sys_string, "r");
  if (get_line(input_buffer, input_pipe)) {
    *begin_date_string = strdup(input_buffer);
  }
  if (get_line(input_buffer, input_pipe)) {
    *end_date_string = strdup(input_buffer);
  }
  pclose(input_pipe);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_begin_end_dates>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D3(%rip),%rsi
  sub    $0x498,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x488(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbp
  mov    %rsp,%r13
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    D10(%rip),%rsi
  call   <popen@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <get_line@plt>
  test   %rax,%rax
  jne    L25
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L29
L44:
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    0x488(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x498,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L25:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,(%r12)
  call   <get_line@plt>
  test   %rax,%rax
  je     L44
L29:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L44
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D10
type: string

tool: D3: cr10_parse "%s" "%s" y

tool: D10: r

assistant: ```c
void parse_begin_end_dates(char **begin_date_string, char **end_date_string, char *filename, char *station) {
  char sys_string[1024];
  FILE *input_pipe;
  char input_buffer[128];
  sprintf(sys_string, "cr10_parse \"%s\" \"%s\" y", filename, station);
  input_pipe = popen(sys_string, "r");
  if (get_line(input_buffer, input_pipe)) {
    *begin_date_string = strdup(input_buffer);
  }
  if (get_line(input_buffer, input_pipe)) {
    *end_date_string = strdup(input_buffer);
  }
  pclose(input_pipe);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_begin_end_dates>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  sub    $0x498,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x488(%rsp)
  xor    %eax,%eax
  lea    0x80(%rsp),%rbp
  mov    %rsp,%r13
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  lea    D16(%rip),%rsi
  call   <popen@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <get_line@plt>
  test   %rax,%rax
  jne    L4
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L42
L35:
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    0x488(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x498,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L4:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,(%r12)
  call   <get_line@plt>
  test   %rax,%rax
  je     L35
L42:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L35
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D16
type: string

tool: D0: cr10_parse "%s" "%s" y

tool: D16: r

assistant: ```c
void parse_begin_end_dates(char **begin_date_string, char **end_date_string, char *filename, char *station) {
  char sys_string[1024];
  FILE *input_pipe;
  char input_buffer[128];
  sprintf(sys_string, "cr10_parse \"%s\" \"%s\" y", filename, station);
  input_pipe = popen(sys_string, "r");
  if (get_line(input_buffer, input_pipe)) {
    *begin_date_string = strdup(input_buffer);
  }
  if (get_line(input_buffer, input_pipe)) {
    *end_date_string = strdup(input_buffer);
  }
  pclose(input_pipe);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_insstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L14
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <insstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L17
L14:
  nop
L17:
  leave
  ret
```

assistant: ```c
void cmd_insstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(insstr(args[0]));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_insstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L0
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <insstr@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L0:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_insstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(insstr(args[0]));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmd_insstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L1
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <insstr@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
  nopl   0x0(%rax)
L1:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_insstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(insstr(args[0]));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cmd_insstr>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L1
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%rdi
  call   <insstr@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
  nopl   0x0(%rax)
L1:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_insstr(int nargs, char **args) {
  if (check_arg_count(nargs, 1) == 1)
    return;
  report_count(1);
  report_return(insstr(args[0]));
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x80000000,-0x14(%rbp)
  jne    L48
  mov    -0x18(%rbp),%eax
  mov    $0xb,%edx
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L6
L48:
  cmpl   $0x0,-0x14(%rbp)
  jns    L28
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  negl   -0x14(%rbp)
L28:
  cmpl   $0x9,-0x14(%rbp)
  jle    L21
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ft_putnbr_fd>
L21:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x9(%rbp)
  lea    -0x9(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
L6:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D3
type: string

tool: D2: -2147483648

tool: D3: -

assistant: ```c
void ft_putnbr_fd(int nb, int fd) {
  char c;
  if (nb == -2147483648) {
    write(fd, "-2147483648", 11);
    return;
  }
  if (nb < 0) {
    write(fd, "-", 1);
    nb = 0 - nb;
  }
  if (nb >= 10)
    ft_putnbr_fd(nb / 10, fd);
  c = '0' + nb % 10;
  write(fd, &c, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x80000000,%edi
  je     L33
  mov    %edi,%ebx
  test   %edi,%edi
  js     L14
L60:
  cmp    $0x9,%ebx
  jg     L6
L9:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <write@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  mov    $0xb,%edx
  lea    D4(%rip),%rsi
  mov    %ebp,%edi
  call   <write@plt>
  jmp    L10
L14:
  mov    $0x1,%edx
  lea    D13(%rip),%rsi
  mov    %ebp,%edi
  call   <write@plt>
  neg    %ebx
  jmp    L60
L6:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  mov    %ebp,%esi
  call   <ft_putnbr_fd>
  jmp    L9
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string
name: parse_data
arguments: tag: D13
type_infered: string

tool: D4: -2147483648

tool: D13: -

assistant: ```c
void ft_putnbr_fd(int nb, int fd) {
  char c;
  if (nb == -2147483648) {
    write(fd, "-2147483648", 11);
    return;
  }
  if (nb < 0) {
    write(fd, "-", 1);
    nb = 0 - nb;
  }
  if (nb >= 10)
    ft_putnbr_fd(nb / 10, fd);
  c = '0' + nb % 10;
  write(fd, &c, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x80000000,%edi
  je     L17
  mov    %edi,%ebx
  test   %edi,%edi
  js     L27
L64:
  mov    %ebx,%ebp
  cmp    $0x9,%ebx
  jg     L29
L24:
  mov    $0xcccccccd,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    %r12d,%edi
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x7(%rsp)
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L29:
  mov    $0xcccccccd,%edi
  mov    %r12d,%esi
  imul   %rbp,%rdi
  shr    $0x23,%rdi
  call   <ft_putnbr_fd>
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%edx
  lea    D14(%rip),%rsi
  mov    %r12d,%edi
  neg    %ebx
  call   <write@plt>
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  mov    %r12d,%edi
  mov    $0xb,%edx
  pop    %rbx
  lea    D6(%rip),%rsi
  pop    %rbp
  pop    %r12
  jmp    1060 <write@plt>
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type: string
name: extract_symbolic_data
arguments: label: D6
type: string

tool: D14: -

tool: D6: -2147483648

assistant: ```c
void ft_putnbr_fd(int nb, int fd) {
  char c;
  if (nb == -2147483648) {
    write(fd, "-2147483648", 11);
    return;
  }
  if (nb < 0) {
    write(fd, "-", 1);
    nb = 0 - nb;
  }
  if (nb >= 10)
    ft_putnbr_fd(nb / 10, fd);
  c = '0' + nb % 10;
  write(fd, &c, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x80000000,%edi
  je     L16
  mov    %edi,%ebx
  test   %edi,%edi
  js     L70
L66:
  cmp    $0x9,%ebx
  jg     L63
  lea    0x7(%rsp),%r12
  mov    %ebx,%r13d
L62:
  mov    $0xcccccccd,%eax
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  imul   %r13,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    $0x30,%ebx
  mov    %bl,0x7(%rsp)
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  mov    %ebx,%r13d
  mov    $0xcccccccd,%edi
  mov    %r13,%r12
  imul   %rdi,%r12
  shr    $0x23,%r12
  mov    %r12d,%r14d
  cmp    $0x63,%ebx
  jg     L55
L25:
  mov    $0xcccccccd,%eax
  mov    $0x1,%edx
  mov    %ebp,%edi
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  add    $0x30,%r12d
  mov    %r12b,0x7(%rsp)
  lea    0x7(%rsp),%r12
  mov    %r12,%rsi
  call   <write@plt>
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L70:
  mov    $0x1,%edx
  lea    D14(%rip),%rsi
  mov    %ebp,%edi
  neg    %ebx
  call   <write@plt>
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L55:
  imul   %r14,%rdi
  mov    %ebp,%esi
  shr    $0x23,%rdi
  call   <ft_putnbr_fd>
  jmp    L25
  nopl   0x0(%rax)
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  mov    %ebp,%edi
  mov    $0xb,%edx
  pop    %rbx
  lea    D19(%rip),%rsi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <write@plt>
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string

tool: D14: -

tool: D19: -2147483648

assistant: ```c
void ft_putnbr_fd(int nb, int fd) {
  char c;
  if (nb == -2147483648) {
    write(fd, "-2147483648", 11);
    return;
  }
  if (nb < 0) {
    write(fd, "-", 1);
    nb = 0 - nb;
  }
  if (nb >= 10)
    ft_putnbr_fd(nb / 10, fd);
  c = '0' + nb % 10;
  write(fd, &c, 1);
}
```