ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<output_set_destructor>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  lea    D28(%rip),%rsi
  mov    $0x0,%eax
  call   <outputf@plt>
  mov    %r12d,%edx
  lea    D27(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <outputf@plt>
  mov    %rbp,%rcx
  lea    D47(%rip),%rdx
  lea    D37(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <outputf@plt>
  lea    D56(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <outputf@plt>
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <outputf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D27
type_guessed: string
name: read_data
arguments: tag: D47
type_guessed: string
name: read_data
arguments: tag: D37
type_guessed: string
name: read_data
arguments: tag: D56
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string

tool: D28: 	/* Set the destructor */


tool: D27: 	duk_dup(ctx, %d);


tool: D47: dukky

tool: D37: 	duk_push_c_function(ctx, %s_%s___destructor, 1);


tool: D56: 	duk_set_finalizer(ctx, -2);


tool: D7: 	duk_pop(ctx);



assistant: ```c
int output_set_destructor(struct opctx *outc, char *class_name, int idx) {
  outputf(outc, "\t/* Set the destructor */\n");
  outputf(outc, "\tduk_dup(ctx, %d);\n", idx);
  outputf(outc, "\tduk_push_c_function(ctx, %s_%s___destructor, 1);\n", "dukky", class_name);
  outputf(outc, "\tduk_set_finalizer(ctx, -2);\n");
  outputf(outc, "\tduk_pop(ctx);\n\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<output_set_destructor>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  lea    D24(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  call   <outputf@plt>
  mov    %r13d,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  call   <outputf@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D31(%rip),%rdx
  lea    D23(%rip),%rsi
  call   <outputf@plt>
  mov    %rbp,%rdi
  lea    D32(%rip),%rsi
  xor    %eax,%eax
  call   <outputf@plt>
  mov    %rbp,%rdi
  lea    D36(%rip),%rsi
  xor    %eax,%eax
  call   <outputf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D31
data_type: string
name: retrieve_data
arguments: label: D23
data_type: string
name: retrieve_data
arguments: label: D32
data_type: string
name: retrieve_data
arguments: label: D36
data_type: string

tool: D24: 	/* Set the destructor */


tool: D15: 	duk_dup(ctx, %d);


tool: D31: dukky

tool: D23: 	duk_push_c_function(ctx, %s_%s___destructor, 1);


tool: D32: 	duk_set_finalizer(ctx, -2);


tool: D36: 	duk_pop(ctx);



assistant: ```c
int output_set_destructor(struct opctx *outc, char *class_name, int idx) {
  outputf(outc, "\t/* Set the destructor */\n");
  outputf(outc, "\tduk_dup(ctx, %d);\n", idx);
  outputf(outc, "\tduk_push_c_function(ctx, %s_%s___destructor, 1);\n", "dukky", class_name);
  outputf(outc, "\tduk_set_finalizer(ctx, -2);\n");
  outputf(outc, "\tduk_pop(ctx);\n\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_set_destructor>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  call   <outputf@plt>
  mov    %r13d,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D23(%rip),%rsi
  call   <outputf@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D37(%rip),%rdx
  lea    D14(%rip),%rsi
  call   <outputf@plt>
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  xor    %eax,%eax
  call   <outputf@plt>
  mov    %rbp,%rdi
  lea    D42(%rip),%rsi
  xor    %eax,%eax
  call   <outputf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string
name: disassemble_data
arguments: label: D23
type: string
name: disassemble_data
arguments: label: D37
type: string
name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D42
type: string

tool: D4: 	/* Set the destructor */


tool: D23: 	duk_dup(ctx, %d);


tool: D37: dukky

tool: D14: 	duk_push_c_function(ctx, %s_%s___destructor, 1);


tool: D0: 	duk_set_finalizer(ctx, -2);


tool: D42: 	duk_pop(ctx);



assistant: ```c
int output_set_destructor(struct opctx *outc, char *class_name, int idx) {
  outputf(outc, "\t/* Set the destructor */\n");
  outputf(outc, "\tduk_dup(ctx, %d);\n", idx);
  outputf(outc, "\tduk_push_c_function(ctx, %s_%s___destructor, 1);\n", "dukky", class_name);
  outputf(outc, "\tduk_set_finalizer(ctx, -2);\n");
  outputf(outc, "\tduk_pop(ctx);\n\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int test5(int x) {
  int y = INT_MIN;
  return x + y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test5>:
  endbr64
  mov    D0(%rip),%rax
  add    (%rax),%edi
  mov    %edi,%eax
  ret
```

assistant: ```c
int test5(int x) {
  int y = INT_MIN;
  return x + y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test5>:
  endbr64
  mov    D7(%rip),%rax
  add    (%rax),%edi
  mov    %edi,%eax
  ret
```

assistant: ```c
int test5(int x) {
  int y = INT_MIN;
  return x + y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hidpp_cpu_to_be_u16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%edx
  lea    -0xc(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <hidpp_set_unaligned_be_u16@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
uint16_t hidpp_cpu_to_be_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_be_u16((uint8_t *)&result, data);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hidpp_cpu_to_be_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <hidpp_set_unaligned_be_u16@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t hidpp_cpu_to_be_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_be_u16((uint8_t *)&result, data);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hidpp_cpu_to_be_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <hidpp_set_unaligned_be_u16@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t hidpp_cpu_to_be_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_be_u16((uint8_t *)&result, data);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hidpp_cpu_to_be_u16>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <hidpp_set_unaligned_be_u16@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint16_t hidpp_cpu_to_be_u16(uint16_t data) {
  uint16_t result;
  hidpp_set_unaligned_be_u16((uint8_t *)&result, data);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<humanize_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  movl   $0x0,-0x14(%rbp)
  fldt   0x10(%rbp)
  fstpt  -0x10(%rbp)
  jmp    L22
L7:
  addl   $0x1,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %rax,-0x48(%rbp)
  fildll -0x48(%rbp)
  fldt   -0x10(%rbp)
  fdivp  %st,%st(1)
  fstpt  -0x10(%rbp)
L22:
  mov    -0x24(%rbp),%eax
  mov    %rax,-0x48(%rbp)
  fildll -0x48(%rbp)
  fldt   -0x10(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jb     L10
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jb     L7
L10:
  mov    -0x38(%rbp),%rax
  fldt   -0x10(%rbp)
  fstpt  (%rax)
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void humanize_value(uint64_t x, unsigned int ratio, const char *const units[], unsigned int num_units, long double *result, const char **unit) {
  unsigned int unit_exp = 0;
  long double i;
  for (i = x; i >= ratio && unit_exp < num_units; i /= ratio) {
    unit_exp++;
  }
  *result = i;
  *unit = units[unit_exp];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<humanize_value>:
  endbr64
  fldt   0x8(%rsp)
  mov    %edi,%eax
  mov    %rax,-0x10(%rsp)
  fildll -0x10(%rsp)
  test   %edx,%edx
  je     L27
  fxch   %st(1)
  fcomi  %st(1),%st
  jb     L39
  mov    $0x0,%eax
L57:
  add    $0x1,%eax
  fdiv   %st(1),%st
  cmp    %eax,%edx
  jbe    L20
  fcomi  %st(1),%st
  jae    L57
  fstp   %st(1)
  jmp    L0
L20:
  fstp   %st(1)
L0:
  fstpt  (%rcx)
  mov    %eax,%eax
  mov    (%rsi,%rax,8),%rax
  mov    %rax,(%r8)
  ret
L27:
  fstp   %st(0)
  jmp    L43
L39:
  fstp   %st(1)
L43:
  mov    $0x0,%eax
  jmp    L0
```

assistant: ```c
void humanize_value(uint64_t x, unsigned int ratio, const char *const units[], unsigned int num_units, long double *result, const char **unit) {
  unsigned int unit_exp = 0;
  long double i;
  for (i = x; i >= ratio && unit_exp < num_units; i /= ratio) {
    unit_exp++;
  }
  *result = i;
  *unit = units[unit_exp];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<humanize_value>:
  endbr64
  fldt   0x8(%rsp)
  mov    %edi,%edi
  mov    %rdi,-0x10(%rsp)
  fildll -0x10(%rsp)
  test   %edx,%edx
  je     L13
  fxch   %st(1)
  fcomi  %st(1),%st
  jb     L60
  xor    %eax,%eax
  jmp    L55
  nopl   0x0(%rax)
L6:
  fcomi  %st(1),%st
  jb     L39
L55:
  fdiv   %st(1),%st
  add    $0x1,%eax
  cmp    %eax,%edx
  ja     L6
  fstp   %st(1)
  jmp    L58
  nopl   0x0(%rax)
L39:
  fstp   %st(1)
L58:
  lea    (%rsi,%rax,8),%rsi
  jmp    L48
L13:
  fstp   %st(0)
  jmp    L48
L60:
  fstp   %st(1)
L48:
  mov    (%rsi),%rax
  fstpt  (%rcx)
  mov    %rax,(%r8)
  ret
```

assistant: ```c
void humanize_value(uint64_t x, unsigned int ratio, const char *const units[], unsigned int num_units, long double *result, const char **unit) {
  unsigned int unit_exp = 0;
  long double i;
  for (i = x; i >= ratio && unit_exp < num_units; i /= ratio) {
    unit_exp++;
  }
  *result = i;
  *unit = units[unit_exp];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<humanize_value>:
  endbr64
  fldt   0x8(%rsp)
  mov    %edi,%edi
  mov    %rdi,-0x10(%rsp)
  fildll -0x10(%rsp)
  test   %edx,%edx
  je     L76
  fxch   %st(1)
  fcomi  %st(1),%st
  jb     L49
  xor    %eax,%eax
  jmp    L78
  nopl   0x0(%rax)
L10:
  fcomi  %st(1),%st
  jb     L73
L78:
  fdiv   %st(1),%st
  add    $0x1,%eax
  cmp    %eax,%edx
  ja     L10
  fstp   %st(1)
  jmp    L79
  nopl   0x0(%rax)
L73:
  fstp   %st(1)
L79:
  lea    (%rsi,%rax,8),%rsi
  jmp    L74
L76:
  fstp   %st(0)
  jmp    L74
L49:
  fstp   %st(1)
L74:
  mov    (%rsi),%rax
  fstpt  (%rcx)
  mov    %rax,(%r8)
  ret
```

assistant: ```c
void humanize_value(uint64_t x, unsigned int ratio, const char *const units[], unsigned int num_units, long double *result, const char **unit) {
  unsigned int unit_exp = 0;
  long double i;
  for (i = x; i >= ratio && unit_exp < num_units; i /= ratio) {
    unit_exp++;
  }
  *result = i;
  *unit = units[unit_exp];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_mounts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x10(%rbp),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x30(%rbp),%rax
  mov    0x10(%rbp),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L7
L47:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
L7:
  leave
  ret
```

assistant: ```c
int check_mounts(char *ft_name, char *ft_dir, char *ft_type, char *mt_name, char *mt_dir, char *mt_type, char *type) {
  if (((strcmp(ft_type, type)) == 0) && (strcmp(mt_type, type) == 0)) {
    if (((strcmp(ft_name, mt_name)) == 0) && (strcmp(ft_dir, mt_dir) == 0)) {
      return (EXIT_SUCCESS);
    }
  }
  return (EXIT_FAILURE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_mounts>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rdi
  mov    %rcx,%r12
  mov    %r8,%r14
  mov    %r9,%rbx
  mov    0x30(%rsp),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
L14:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    0x30(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  jmp    L37
```

assistant: ```c
int check_mounts(char *ft_name, char *ft_dir, char *ft_type, char *mt_name, char *mt_dir, char *mt_type, char *type) {
  if (((strcmp(ft_type, type)) == 0) && (strcmp(mt_type, type) == 0)) {
    if (((strcmp(ft_name, mt_name)) == 0) && (strcmp(ft_dir, mt_dir) == 0)) {
      return (EXIT_SUCCESS);
    }
  }
  return (EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_mounts>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%rbx
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
L42:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L34:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L42
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  jmp    L4
```

assistant: ```c
int check_mounts(char *ft_name, char *ft_dir, char *ft_type, char *mt_name, char *mt_dir, char *mt_type, char *type) {
  if (((strcmp(ft_type, type)) == 0) && (strcmp(mt_type, type) == 0)) {
    if (((strcmp(ft_name, mt_name)) == 0) && (strcmp(ft_dir, mt_dir) == 0)) {
      return (EXIT_SUCCESS);
    }
  }
  return (EXIT_FAILURE);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_mounts>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %r9,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x40(%rsp),%rbx
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L32
L22:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L32:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L22
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  jmp    L2
```

assistant: ```c
int check_mounts(char *ft_name, char *ft_dir, char *ft_type, char *mt_name, char *mt_dir, char *mt_type, char *type) {
  if (((strcmp(ft_type, type)) == 0) && (strcmp(mt_type, type) == 0)) {
    if (((strcmp(ft_name, mt_name)) == 0) && (strcmp(ft_dir, mt_dir) == 0)) {
      return (EXIT_SUCCESS);
    }
  }
  return (EXIT_FAILURE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dect_is_multiframe_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xe0,%eax
  cmp    $0x80,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf0,%eax
  cmp    $0x60,%eax
  jne    L1
  mov    $0x1,%eax
  jmp    L12
L1:
  mov    $0x0,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int dect_is_multiframe_number(unsigned char *packet) {
  if ((packet[5] & 0xe0) == 0x80) {
    if ((packet[6] & 0xf0) == 0x60) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dect_is_multiframe_number>:
  endbr64
  movzbl 0x5(%rdi),%eax
  and    $0xffffffe0,%eax
  mov    $0x0,%edx
  cmp    $0x80,%al
  je     L1
L19:
  mov    %edx,%eax
  ret
L1:
  movzbl 0x6(%rdi),%eax
  and    $0xfffffff0,%eax
  cmp    $0x60,%al
  sete   %dl
  movzbl %dl,%edx
  jmp    L19
```

assistant: ```c
int dect_is_multiframe_number(unsigned char *packet) {
  if ((packet[5] & 0xe0) == 0x80) {
    if ((packet[6] & 0xf0) == 0x60) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dect_is_multiframe_number>:
  endbr64
  movzbl 0x5(%rdi),%eax
  xor    %r8d,%r8d
  and    $0xffffffe0,%eax
  cmp    $0x80,%al
  jne    L1
  movzbl 0x6(%rdi),%eax
  xor    %r8d,%r8d
  and    $0xfffffff0,%eax
  cmp    $0x60,%al
  sete   %r8b
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int dect_is_multiframe_number(unsigned char *packet) {
  if ((packet[5] & 0xe0) == 0x80) {
    if ((packet[6] & 0xf0) == 0x60) {
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dect_is_multiframe_number>:
  endbr64
  movzbl 0x5(%rdi),%eax
  xor    %r8d,%r8d
  and    $0xffffffe0,%eax
  cmp    $0x80,%al
  jne    L4
  movzbl 0x6(%rdi),%eax
  xor    %r8d,%r8d
  and    $0xfffffff0,%eax
  cmp    $0x60,%al
  sete   %r8b
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int dect_is_multiframe_number(unsigned char *packet) {
  if ((packet[5] & 0xe0) == 0x80) {
    if ((packet[6] & 0xf0) == 0x60) {
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L42
  cmpl   $0x0,-0x1c(%rbp)
  je     L42
  mov    $0x0,%eax
  call   <_time_counter@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    -0x1c(%rbp),%ebx
  jmp    L47
L52:
  mov    $0x0,%eax
  call   <rand@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L51
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  lea    0x0(,%rax,4),%ecx
  add    %ecx,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x61(%rax),%ecx
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L23
L51:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L23:
  sub    $0x1,%ebx
L47:
  test   %ebx,%ebx
  jns    L52
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L46
L42:
  nop
L46:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void random_str(char *str, unsigned len) {
  if (!str || len <= 0)
    return;
  srand(_time_counter());
  register int i;
  for (i = len; i >= 0; --i) {
    if (rand() % 2)
      str[i] = (rand() % 25) + 97;
    else
      str[i] = (rand() % 10) + 48;
  }
  str[i] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<random_str>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  test   %esi,%esi
  je     L42
  mov    $0x0,%eax
  call   <_time_counter@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %r13d,%eax
  test   %r13d,%r13d
  js     L39
  movslq %r13d,%rbx
  add    %r12,%rbx
  lea    -0x1(%rbx),%rbp
  mov    %r13d,%r13d
  sub    %r13,%rbp
  jmp    L40
L51:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,(%rbx)
L65:
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L16
L40:
  mov    $0x0,%eax
  call   <rand@plt>
  test   $0x1,%al
  je     L51
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%eax
  add    $0x61,%eax
  mov    %al,(%rbx)
  jmp    L65
L16:
  mov    $0xffffffff,%eax
L39:
  cltq
  movb   $0x0,(%r12,%rax,1)
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  ret
```

assistant: ```c
void random_str(char *str, unsigned len) {
  if (!str || len <= 0)
    return;
  srand(_time_counter());
  register int i;
  for (i = len; i >= 0; --i) {
    if (rand() % 2)
      str[i] = (rand() % 25) + 97;
    else
      str[i] = (rand() % 10) + 48;
  }
  str[i] = '\0';
}
```