ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<generateDecision>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  cltq
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int generateDecision() {
  int randomDigit;
  randomDigit = (rand() % 5);
  return randomDigit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<generateDecision>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int generateDecision() {
  int randomDigit;
  randomDigit = (rand() % 5);
  return randomDigit;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<generateDecision>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  mov    %eax,%edx
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int generateDecision() {
  int randomDigit;
  randomDigit = (rand() % 5);
  return randomDigit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binomial_Coeff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jbe    L20
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L20:
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L5:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  ja     L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long int binomial_Coeff(unsigned int n, unsigned int k) {
  unsigned long int res = 1;
  int i;
  if (k > n - k)
    k = n - k;
  for (i = 0; i < k; ++i) {
    res *= (n - i);
    res /= (i + 1);
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binomial_Coeff>:
  endbr64
  mov    %edi,%eax
  sub    %esi,%eax
  cmp    %esi,%eax
  cmova  %esi,%eax
  test   %eax,%eax
  je     L12
  lea    -0x1(%rax),%esi
  add    $0x2,%rsi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  add    $0x1,%edi
L17:
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %rdx,%rax
  mov    $0x0,%edx
  div    %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L17
  ret
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long int binomial_Coeff(unsigned int n, unsigned int k) {
  unsigned long int res = 1;
  int i;
  if (k > n - k)
    k = n - k;
  for (i = 0; i < k; ++i) {
    res *= (n - i);
    res /= (i + 1);
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binomial_Coeff>:
  endbr64
  mov    %edi,%eax
  sub    %esi,%eax
  cmp    %esi,%eax
  cmova  %esi,%eax
  test   %eax,%eax
  je     L19
  lea    -0x1(%rax),%esi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  add    $0x1,%edi
  add    $0x2,%rsi
  nopl   (%rax)
L11:
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %rdx,%rax
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L11
  ret
  nop
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long int binomial_Coeff(unsigned int n, unsigned int k) {
  unsigned long int res = 1;
  int i;
  if (k > n - k)
    k = n - k;
  for (i = 0; i < k; ++i) {
    res *= (n - i);
    res /= (i + 1);
  }
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binomial_Coeff>:
  endbr64
  mov    %edi,%eax
  sub    %esi,%eax
  cmp    %esi,%eax
  cmova  %esi,%eax
  test   %eax,%eax
  je     L6
  lea    -0x1(%rax),%esi
  mov    $0x1,%ecx
  mov    $0x1,%eax
  add    $0x1,%edi
  add    $0x2,%rsi
  nopl   (%rax)
L12:
  mov    %edi,%edx
  sub    %ecx,%edx
  imul   %rdx,%rax
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L12
  ret
  nop
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long int binomial_Coeff(unsigned int n, unsigned int k) {
  unsigned long int res = 1;
  int i;
  if (k > n - k)
    k = n - k;
  for (i = 0; i < k; ++i) {
    res *= (n - i);
    res /= (i + 1);
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x16,-0x10(%rbp)
  movl   $0x2d,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L21
L8:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L8
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int sum(int *a, int n) {
  int array[2] = {22, 45};
  int i, s = 0;
  for (i = 0; i < n; i++) {
    s += a[i];
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L6
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L23:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L23
L19:
  mov    %edx,%eax
  ret
L6:
  mov    $0x0,%edx
  jmp    L19
```

assistant: ```c
int sum(int *a, int n) {
  int array[2] = {22, 45};
  int i, s = 0;
  for (i = 0; i < n; i++) {
    s += a[i];
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L17
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum(int *a, int n) {
  int array[2] = {22, 45};
  int i, s = 0;
  for (i = 0; i < n; i++) {
    s += a[i];
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L59
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L22
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L35:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L35
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L48
L44:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L40
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L40
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L59:
  xor    %eax,%eax
L40:
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  ret
L22:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L44
```

assistant: ```c
int sum(int *a, int n) {
  int array[2] = {22, 45};
  int i, s = 0;
  for (i = 0; i < n; i++) {
    s += a[i];
  }
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: ii = %d


assistant: ```c
int add(int ii) {
  ii++;
  printf("ii = %d\n", ii);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add>:
  endbr64
  sub    $0x8,%rsp
  lea    0x1(%rdi),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: ii = %d


assistant: ```c
int add(int ii) {
  ii++;
  printf("ii = %d\n", ii);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add>:
  endbr64
  lea    0x1(%rdi),%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: string

tool: D2: ii = %d


assistant: ```c
int add(int ii) {
  ii++;
  printf("ii = %d\n", ii);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add>:
  endbr64
  lea    0x1(%rdi),%esi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: ii = %d


assistant: ```c
int add(int ii) {
  ii++;
  printf("ii = %d\n", ii);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x74636e7566737964,%rax
  mov    %rax,-0x15(%rbp)
  movl   $0x6c6e6f69,-0xd(%rbp)
  movb   $0x0,-0x9(%rbp)
  movl   $0x6e7566,-0x19(%rbp)
  lea    -0x19(%rbp),%rdx
  lea    -0x15(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L17
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L17:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: I found the fun in dysfunctionl!

assistant: ```c
int main() {
  char s0[] = "dysfunctionl";
  char s1[] = "fun";
  if (strstr(s0, s1)) {
    puts("I found the fun in dysfunctionl!");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x74636e7566737964,%rax
  mov    %rax,0xb(%rsp)
  movl   $0x6c6e6f69,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  movl   $0x6e7566,0x7(%rsp)
  lea    0x7(%rsp),%rsi
  lea    0xb(%rsp),%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L24
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L24:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L22
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D2: I found the fun in dysfunctionl!

assistant: ```c
int main() {
  char s0[] = "dysfunctionl";
  char s1[] = "fun";
  if (strstr(s0, s1)) {
    puts("I found the fun in dysfunctionl!");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x74636e7566737964,%rax
  lea    0x7(%rsp),%rsi
  lea    0xb(%rsp),%rdi
  movl   $0x6c6e6f69,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  movl   $0x6e7566,0x7(%rsp)
  mov    %rax,0xb(%rsp)
  call   <strstr@plt>
  test   %rax,%rax
  jne    L20
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L20:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L16
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: I found the fun in dysfunctionl!

assistant: ```c
int main() {
  char s0[] = "dysfunctionl";
  char s1[] = "fun";
  if (strstr(s0, s1)) {
    puts("I found the fun in dysfunctionl!");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x74636e7566737964,%rax
  lea    0x7(%rsp),%rsi
  lea    0xb(%rsp),%rdi
  movl   $0x6c6e6f69,0x13(%rsp)
  movb   $0x0,0x17(%rsp)
  movl   $0x6e7566,0x7(%rsp)
  mov    %rax,0xb(%rsp)
  call   <strstr@plt>
  test   %rax,%rax
  jne    L14
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L14:
  lea    D6(%rip),%rdi
  call   <puts@plt>
  jmp    L1
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: I found the fun in dysfunctionl!

assistant: ```c
int main() {
  char s0[] = "dysfunctionl";
  char s1[] = "fun";
  if (strstr(s0, s1)) {
    puts("I found the fun in dysfunctionl!");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<psvec2_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vec2_add@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_add(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_add((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<psvec2_add>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec2_add@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_add(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_add((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<psvec2_add>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2_add@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_add(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_add((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<psvec2_add>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec2_add@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec2 *psvec2_add(struct vec2 *result, struct vec2 *a, struct vec2 *b) {
  vec2_add((float *)result, (float *)a, (float *)b);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subparserColprintCompareLines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L9
  mov    -0x24(%rbp),%eax
  jmp    L16
L9:
  mov    -0x38(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
L16:
  leave
  ret
```

assistant: ```c
int subparserColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_name = colprintLineGetColumn(a, 0);
  const char *b_name = colprintLineGetColumn(b, 0);
  int r;
  r = strcmp(a_name, b_name);
  if (r != 0)
    return r;
  const char *a_baseparser = colprintLineGetColumn(a, 1);
  const char *b_baseparser = colprintLineGetColumn(b, 1);
  return strcmp(a_baseparser, b_baseparser);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<subparserColprintCompareLines>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%esi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%r12
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L1
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%rbp
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <colprintLineGetColumn@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  jmp    L16
```

assistant: ```c
int subparserColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_name = colprintLineGetColumn(a, 0);
  const char *b_name = colprintLineGetColumn(b, 0);
  int r;
  r = strcmp(a_name, b_name);
  if (r != 0)
    return r;
  const char *a_baseparser = colprintLineGetColumn(a, 1);
  const char *b_baseparser = colprintLineGetColumn(b, 1);
  return strcmp(a_baseparser, b_baseparser);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<subparserColprintCompareLines>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <colprintLineGetColumn@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <colprintLineGetColumn@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L6
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <colprintLineGetColumn@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  mov    %rax,%r12
  call   <colprintLineGetColumn@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %rax,%rsi
  pop    %r13
  jmp    1060 <strcmp@plt>
```

assistant: ```c
int subparserColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_name = colprintLineGetColumn(a, 0);
  const char *b_name = colprintLineGetColumn(b, 0);
  int r;
  r = strcmp(a_name, b_name);
  if (r != 0)
    return r;
  const char *a_baseparser = colprintLineGetColumn(a, 1);
  const char *b_baseparser = colprintLineGetColumn(b, 1);
  return strcmp(a_baseparser, b_baseparser);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<subparserColprintCompareLines>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  call   <colprintLineGetColumn@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <colprintLineGetColumn@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L0
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %r12,%rdi
  mov    $0x1,%esi
  call   <colprintLineGetColumn@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  mov    %rax,%r12
  call   <colprintLineGetColumn@plt>
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  mov    %rax,%rsi
  pop    %r13
  jmp    1060 <strcmp@plt>
```

assistant: ```c
int subparserColprintCompareLines(struct colprintLine *a, struct colprintLine *b) {
  const char *a_name = colprintLineGetColumn(a, 0);
  const char *b_name = colprintLineGetColumn(b, 0);
  int r;
  r = strcmp(a_name, b_name);
  if (r != 0)
    return r;
  const char *a_baseparser = colprintLineGetColumn(a, 1);
  const char *b_baseparser = colprintLineGetColumn(b, 1);
  return strcmp(a_baseparser, b_baseparser);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timer_sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0xf4240,%edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L39
L11:
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L39
  mov    $0x0,%eax
  jmp    L20
L39:
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L11
  mov    $0x1,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int timer_sleep(int interval) {
  struct timespec ts;
  ts.tv_sec = interval / 1000;
  ts.tv_nsec = (interval % 1000) * 1000000;
  while (nanosleep(&ts, &ts) == -1) {
    if (errno != EINTR)
      return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timer_sleep>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rbx
L11:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  jne    L5
  mov    D12(%rip),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L11
  mov    $0x0,%eax
  jmp    L7
L5:
  mov    $0x1,%eax
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int timer_sleep(int interval) {
  struct timespec ts;
  ts.tv_sec = interval / 1000;
  ts.tv_nsec = (interval % 1000) * 1000000;
  while (nanosleep(&ts, &ts) == -1) {
    if (errno != EINTR)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timer_sleep>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rbx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L31:
  mov    D6(%rip),%rax
  mov    D19(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L48
L27:
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <nanosleep@plt>
  cmp    $0xffffffff,%eax
  je     L31
  mov    $0x1,%eax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L48:
  xor    %eax,%eax
  jmp    L23
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int timer_sleep(int interval) {
  struct timespec ts;
  ts.tv_sec = interval / 1000;
  ts.tv_nsec = (interval % 1000) * 1000000;
  while (nanosleep(&ts, &ts) == -1) {
    if (errno != EINTR)
      return 0;
  }
  return 1;
}
```