user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x360,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x354(%rbp),%rdx
  lea    -0x358(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x348(%rbp)
  jmp    L3
L86:
  lea    -0x330(%rbp),%rdx
  mov    -0x348(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x348(%rbp)
L3:
  mov    -0x358(%rbp),%eax
  cmp    %eax,-0x348(%rbp)
  jl     L86
  mov    -0x358(%rbp),%eax
  mov    %eax,-0x350(%rbp)
  jmp    L123
L91:
  mov    -0x330(%rbp),%edx
  mov    -0x350(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  movl   $0x0,-0x344(%rbp)
  jmp    L68
L155:
  mov    -0x344(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%edx
  mov    -0x344(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  sub    %eax,%edx
  mov    -0x344(%rbp),%eax
  cltq
  mov    %edx,-0x330(%rbp,%rax,4)
  addl   $0x1,-0x344(%rbp)
L68:
  mov    -0x350(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x344(%rbp)
  jl     L155
  subl   $0x1,-0x350(%rbp)
L123:
  mov    -0x350(%rbp),%edx
  lea    -0x330(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <check@plt>
  test   %eax,%eax
  je     L91
  mov    -0x350(%rbp),%eax
  mov    %eax,-0x340(%rbp)
  jmp    L34
L168:
  mov    -0x330(%rbp),%edx
  mov    -0x340(%rbp),%eax
  cltq
  mov    %edx,-0x330(%rbp,%rax,4)
  addl   $0x1,-0x340(%rbp)
L34:
  mov    -0x354(%rbp),%edx
  mov    -0x350(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x340(%rbp)
  jl     L168
  mov    -0x350(%rbp),%eax
  mov    %eax,-0x33c(%rbp)
  jmp    L28
L84:
  mov    -0x33c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x354(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    -0x330(%rbp),%rax
  lea    (%rax,%rdx,1),%rcx
  lea    -0x330(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <accumulate@plt>
  mov    %eax,%edx
  mov    -0x33c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    %eax,-0x34c(%rbp)
  mov    -0x354(%rbp),%edx
  mov    -0x33c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x338(%rbp)
  jmp    L106
L85:
  mov    -0x338(%rbp),%eax
  cltq
  mov    -0x34c(%rbp),%edx
  mov    %edx,-0x330(%rbp,%rax,4)
  cmpl   $0x0,-0x338(%rbp)
  jle    L158
  mov    -0x338(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  sub    %eax,-0x34c(%rbp)
L158:
  subl   $0x1,-0x338(%rbp)
L106:
  cmpl   $0x0,-0x338(%rbp)
  jns    L85
  addl   $0x1,-0x33c(%rbp)
L28:
  mov    -0x358(%rbp),%eax
  cmp    %eax,-0x33c(%rbp)
  jl     L84
  mov    -0x358(%rbp),%eax
  mov    %eax,-0x334(%rbp)
  jmp    L154
L15:
  mov    -0x358(%rbp),%eax
  cmp    %eax,-0x334(%rbp)
  jle    L76
  mov    $0x20,%edi
  call   <putchar@plt>
L76:
  mov    -0x334(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x334(%rbp)
L154:
  mov    -0x358(%rbp),%edx
  mov    -0x354(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x334(%rbp)
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L81
  call   <__stack_chk_fail@plt>
L81:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D26: %d %d

tool: D0: %d

assistant: ```c
int main() {
  int T, S, C, n, a[100], start[101], sum;
  scanf("%d %d", &S, &C);
  for (int i = 0; i < S; i++)
    scanf("%d", &a[i]);
  n = S;
  while (!check(a, n)) {
    start[n] = a[0];
    for (int i = 0; i < n - 1; i++)
      a[i] = a[i + 1] - a[i];
    n--;
  }
  for (int i = n; i < n + C; i++)
    a[i] = a[0];
  for (int i = n; i < S; i++) {
    sum = accumulate(a, a + i + C, 0) + start[i + 1];
    for (int j = i + C; j >= 0; j--) {
      a[j] = sum;
      if (j > 0)
        sum -= a[j - 1];
    }
  }
  for (int i = S; i < S + C; i++) {
    if (i > S)
      printf(" ");
    printf("%d", a[i]);
  }
  printf("\n");
  return 0;
}
```