ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<drukujspacja>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %edi,%ecx
  xor    %edi,%edi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L54
L77:
  movslq %ecx,%rax
  mov    %ecx,%esi
  mov    %edi,%r12d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  lea    0x1(%rdi),%edi
  sar    $0x22,%rax
  sub    %esi,%eax
  mov    %eax,%ecx
  jne    L77
  movslq %edi,%rdi
  mov    %rsp,%rsi
  shl    $0x2,%rdi
  lea    0xf(%rdi),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L22
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L68
L22:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L104
L91:
  lea    0x3(%rsp),%r13
  mov    %r13,%r8
  and    $0xfffffffffffffffc,%r13
  shr    $0x2,%r8
  lea    -0x4(%r13,%rdi,1),%rdi
  xchg   %ax,%ax
L96:
  movslq %edx,%rax
  mov    %edx,%ecx
  sub    $0x4,%rdi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  mov    %ecx,%edx
  sub    %esi,%eax
  mov    %eax,0x4(%rdi)
  test   %eax,%eax
  jne    L96
  lea    D9(%rip),%r14
  mov    0x0(,%r8,4),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  je     L54
  lea    -0x1(%r12),%eax
  lea    0x4(%r13),%rbx
  mov    $0x1,%r12d
  lea    0x8(%r13,%rax,4),%r13
  nopl   (%rax)
L70:
  mov    (%rbx),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x3,%r12d
  je     L43
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L70
L54:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   (%rax)
L43:
  mov    $0x20,%edi
  add    $0x4,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  je     L54
  xor    %r12d,%r12d
  jmp    L70
L104:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L91
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: %d

assistant: ```c
void drukujspacja(int liczba) {
  int ilecyfr = 0;
  int kopia = liczba;
  while (kopia != 0) {
    kopia /= 10;
    ilecyfr++;
  }
  kopia = liczba;
  int tab[ilecyfr];
  int ilecyfrkopia = ilecyfr;
  ilecyfr--;
  while (kopia != 0) {
    kopia = liczba % 10;
    tab[ilecyfr] = kopia;
    liczba /= 10;
    ilecyfr--;
  }
  int i, licznik = 0;
  for (i = 0; i < ilecyfrkopia; i++) {
    printf("%d", tab[i]);
    licznik++;
    if (licznik == 3) {
      licznik = 0;
      printf(" ");
    }
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ToggleOff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <LockToggled@plt>
  test   %rax,%rax
  je     L6
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <xModifierMask@plt>
  mov    %eax,%edi
  call   <xUnlockModifier@plt>
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ToggleOff(int lock) {
  int result;
  if (LockToggled(lock)) {
    result = xUnlockModifier(xModifierMask(lock));
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ToggleOff>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  call   <LockToggled@plt>
  test   %rax,%rax
  jne    L7
L1:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  mov    %ebx,%edi
  call   <xModifierMask@plt>
  mov    %eax,%edi
  call   <xUnlockModifier@plt>
  mov    %eax,%ebp
  jmp    L1
```

assistant: ```c
int ToggleOff(int lock) {
  int result;
  if (LockToggled(lock)) {
    result = xUnlockModifier(xModifierMask(lock));
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ToggleOff>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <LockToggled@plt>
  test   %rax,%rax
  jne    L1
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L1:
  mov    %ebp,%edi
  call   <xModifierMask@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    1080 <xUnlockModifier@plt>
```

assistant: ```c
int ToggleOff(int lock) {
  int result;
  if (LockToggled(lock)) {
    result = xUnlockModifier(xModifierMask(lock));
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ToggleOff>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <LockToggled@plt>
  test   %rax,%rax
  jne    L7
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L7:
  mov    %ebp,%edi
  call   <xModifierMask@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    1080 <xUnlockModifier@plt>
```

assistant: ```c
int ToggleOff(int lock) {
  int result;
  if (LockToggled(lock)) {
    result = xUnlockModifier(xModifierMask(lock));
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ResetISR>:
  endbr64
  mov    $0xe000ed88,%edx
  mov    (%rdx),%eax
  or     $0xf00000,%eax
  mov    %eax,(%rdx)
  xor    %eax,%eax
  jmp    1050 <__iar_program_start@plt>
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__bitmap_or>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  add    $0x3f,%rax
  shr    $0x6,%rax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L4
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  or     %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __bitmap_or(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, int bits) {
  int k;
  int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] | bitmap2[k];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__bitmap_or>:
  endbr64
  movslq %ecx,%rcx
  add    $0x3f,%rcx
  shr    $0x6,%rcx
  test   %ecx,%ecx
  jle    L13
  lea    -0x1(%rcx),%r8d
  mov    $0x0,%eax
L5:
  mov    (%rsi,%rax,8),%rcx
  or     (%rdx,%rax,8),%rcx
  mov    %rcx,(%rdi,%rax,8)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r8,%rcx
  jne    L5
L13:
  ret
```

assistant: ```c
void __bitmap_or(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, int bits) {
  int k;
  int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] | bitmap2[k];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__bitmap_or>:
  endbr64
  movslq %ecx,%rcx
  add    $0x3f,%rcx
  shr    $0x6,%rcx
  test   %ecx,%ecx
  jle    L12
  lea    -0x1(%rcx),%r8d
  xor    %eax,%eax
  nopl   0x0(%rax)
L13:
  mov    (%rsi,%rax,8),%rcx
  or     (%rdx,%rax,8),%rcx
  mov    %rcx,(%rdi,%rax,8)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r8,%rcx
  jne    L13
L12:
  ret
```

assistant: ```c
void __bitmap_or(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, int bits) {
  int k;
  int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] | bitmap2[k];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__bitmap_or>:
  endbr64
  movslq %ecx,%rcx
  mov    %rdx,%r8
  add    $0x3f,%rcx
  shr    $0x6,%rcx
  test   %ecx,%ecx
  jle    L28
  lea    0x8(%rdx),%rdx
  lea    -0x1(%rcx),%eax
  cmp    %rdx,%rdi
  lea    0x8(%rsi),%rdx
  setne  %r9b
  cmp    %rdx,%rdi
  setne  %dl
  test   %dl,%r9b
  je     L23
  cmp    $0x1,%eax
  jbe    L23
  mov    %ecx,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  cs nopw 0x0(%rax,%rax,1)
L0:
  movdqu (%rsi,%rax,1),%xmm0
  movdqu (%r8,%rax,1),%xmm1
  por    %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L0
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L28
  cltq
  mov    (%rsi,%rax,8),%rdx
  or     (%r8,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  ret
  nopl   (%rax)
L23:
  mov    %eax,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  mov    (%rsi,%rax,8),%rdx
  or     (%r8,%rax,8),%rdx
  mov    %rdx,(%rdi,%rax,8)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L4
L28:
  ret
```

assistant: ```c
void __bitmap_or(unsigned long *dst, const unsigned long *bitmap1, const unsigned long *bitmap2, int bits) {
  int k;
  int nr = (((bits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long)));
  for (k = 0; k < nr; k++)
    dst[k] = bitmap1[k] | bitmap2[k];
}
```
user: Translate the below assembly code into C programming language:

```asm
<fail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

assistant: ```c
void fail(const char *message) {
  fputs(message, stderr);
  fputc('\n', stderr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fail>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputs@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <fputc@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fail(const char *message) {
  fputs(message, stderr);
  fputc('\n', stderr);
}
```
user: What is the c source code of the assembly code below?

```asm
<fail>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputs@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  pop    %rbx
  jmp    1070 <fputc@plt>
```

assistant: ```c
void fail(const char *message) {
  fputs(message, stderr);
  fputc('\n', stderr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fail>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputs@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  pop    %rbx
  jmp    1070 <fputc@plt>
```

assistant: ```c
void fail(const char *message) {
  fputs(message, stderr);
  fputc('\n', stderr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <flash_eeprom_write_uint32@plt>
  jmp    L1
L9:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <flash_eeprom_read_uint32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <flash_eeprom_write_uint32@plt>
  mov    -0xc(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,%edi
  call   <flash_eeprom_read_uint32@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x4,%eax
  sub    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x4,%eax
  sub    -0x8(%rbp),%eax
  shl    $0x3,%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x4(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <flash_eeprom_write_uint32@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void write_uint32(uint32_t offset, uint32_t value) {
  uint32_t base_offset = offset & ~3;
  uint32_t byte_offset = offset & 3;
  if (byte_offset == 0) {
    flash_eeprom_write_uint32(offset, value);
  } else {
    uint32_t base_word = flash_eeprom_read_uint32(base_offset);
    base_word &= ~(0xFFFFFFFF << (byte_offset * 8));
    base_word |= (value << (byte_offset * 8));
    flash_eeprom_write_uint32(base_offset, base_word);
    base_word = flash_eeprom_read_uint32(base_offset + 4);
    base_word &= ~(0xFFFFFFFF >> (8 * (4 - byte_offset)));
    base_word |= (value >> (8 * (4 - byte_offset)));
    flash_eeprom_write_uint32(base_offset + 4, base_word);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_uint32>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edi,%r13d
  and    $0x3,%r13d
  jne    L13
  call   <flash_eeprom_write_uint32@plt>
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    %edi,%ebx
  and    $0xfffffffc,%ebx
  mov    %ebx,%edi
  call   <flash_eeprom_read_uint32@plt>
  mov    %eax,%edx
  lea    0x0(,%r13,8),%ecx
  mov    $0xffffffff,%r12d
  mov    %r12d,%eax
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %ebp,%esi
  shl    %cl,%esi
  or     %eax,%esi
  mov    %ebx,%edi
  call   <flash_eeprom_write_uint32@plt>
  add    $0x4,%ebx
  mov    %ebx,%edi
  call   <flash_eeprom_read_uint32@plt>
  mov    $0x4,%ecx
  sub    %r13d,%ecx
  shl    $0x3,%ecx
  shr    %cl,%r12d
  not    %r12d
  and    %eax,%r12d
  mov    %ebp,%esi
  sar    %cl,%esi
  or     %r12d,%esi
  mov    %ebx,%edi
  call   <flash_eeprom_write_uint32@plt>
  jmp    L18
```

assistant: ```c
void write_uint32(uint32_t offset, uint32_t value) {
  uint32_t base_offset = offset & ~3;
  uint32_t byte_offset = offset & 3;
  if (byte_offset == 0) {
    flash_eeprom_write_uint32(offset, value);
  } else {
    uint32_t base_word = flash_eeprom_read_uint32(base_offset);
    base_word &= ~(0xFFFFFFFF << (byte_offset * 8));
    base_word |= (value << (byte_offset * 8));
    flash_eeprom_write_uint32(base_offset, base_word);
    base_word = flash_eeprom_read_uint32(base_offset + 4);
    base_word &= ~(0xFFFFFFFF >> (8 * (4 - byte_offset)));
    base_word |= (value >> (8 * (4 - byte_offset)));
    flash_eeprom_write_uint32(base_offset + 4, base_word);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_uint32>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  and    $0x3,%r14d
  je     L9
  and    $0xfffffffc,%edi
  mov    $0xffffffff,%r13d
  mov    %edi,%ebp
  call   <flash_eeprom_read_uint32@plt>
  lea    0x0(,%r14,8),%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r8d
  mov    %r13d,%eax
  shl    %cl,%esi
  add    $0x4,%ebp
  shl    %cl,%eax
  not    %eax
  and    %r8d,%eax
  or     %eax,%esi
  call   <flash_eeprom_write_uint32@plt>
  mov    %ebp,%edi
  call   <flash_eeprom_read_uint32@plt>
  mov    $0x4,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  sub    %r14d,%ecx
  shl    $0x3,%ecx
  shr    %cl,%r13d
  sar    %cl,%esi
  not    %r13d
  and    %eax,%r13d
  or     %r13d,%esi
L9:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <flash_eeprom_write_uint32@plt>
```

assistant: ```c
void write_uint32(uint32_t offset, uint32_t value) {
  uint32_t base_offset = offset & ~3;
  uint32_t byte_offset = offset & 3;
  if (byte_offset == 0) {
    flash_eeprom_write_uint32(offset, value);
  } else {
    uint32_t base_word = flash_eeprom_read_uint32(base_offset);
    base_word &= ~(0xFFFFFFFF << (byte_offset * 8));
    base_word |= (value << (byte_offset * 8));
    flash_eeprom_write_uint32(base_offset, base_word);
    base_word = flash_eeprom_read_uint32(base_offset + 4);
    base_word &= ~(0xFFFFFFFF >> (8 * (4 - byte_offset)));
    base_word |= (value >> (8 * (4 - byte_offset)));
    flash_eeprom_write_uint32(base_offset + 4, base_word);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_uint32>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  sub    $0x8,%rsp
  and    $0x3,%r14d
  je     L1
  and    $0xfffffffc,%edi
  mov    $0xffffffff,%r13d
  mov    %edi,%ebp
  call   <flash_eeprom_read_uint32@plt>
  lea    0x0(,%r14,8),%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r8d
  mov    %r13d,%eax
  shl    %cl,%esi
  add    $0x4,%ebp
  shl    %cl,%eax
  not    %eax
  and    %r8d,%eax
  or     %eax,%esi
  call   <flash_eeprom_write_uint32@plt>
  mov    %ebp,%edi
  call   <flash_eeprom_read_uint32@plt>
  mov    $0x4,%ecx
  mov    %r12d,%esi
  mov    %ebp,%edi
  sub    %r14d,%ecx
  shl    $0x3,%ecx
  shr    %cl,%r13d
  sar    %cl,%esi
  not    %r13d
  and    %eax,%r13d
  or     %r13d,%esi
L1:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <flash_eeprom_write_uint32@plt>
```

assistant: ```c
void write_uint32(uint32_t offset, uint32_t value) {
  uint32_t base_offset = offset & ~3;
  uint32_t byte_offset = offset & 3;
  if (byte_offset == 0) {
    flash_eeprom_write_uint32(offset, value);
  } else {
    uint32_t base_word = flash_eeprom_read_uint32(base_offset);
    base_word &= ~(0xFFFFFFFF << (byte_offset * 8));
    base_word |= (value << (byte_offset * 8));
    flash_eeprom_write_uint32(base_offset, base_word);
    base_word = flash_eeprom_read_uint32(base_offset + 4);
    base_word &= ~(0xFFFFFFFF >> (8 * (4 - byte_offset)));
    base_word |= (value >> (8 * (4 - byte_offset)));
    flash_eeprom_write_uint32(base_offset + 4, base_word);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<testV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  D22(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: byte[8]
name: retrieve_data
arguments: label: D2
type_infered: byte[8]
name: retrieve_data
arguments: label: D22
type_infered: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D2": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0x3f]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0xc0]}

assistant: ```c
void testV(double *src) {
  src[0] = 1;
  src[1] = .6;
  src[2] = -4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<testV>:
  endbr64
  mov    D7(%rip),%rax
  mov    %rax,(%rdi)
  mov    D27(%rip),%rax
  mov    %rax,0x8(%rdi)
  mov    D23(%rip),%rax
  mov    %rax,0x10(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: byte[8]
name: read_data
arguments: data_tag: D27
type_guessed: byte[8]
name: read_data
arguments: data_tag: D23
type_guessed: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D27": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0x3f]}

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0xc0]}

assistant: ```c
void testV(double *src) {
  src[0] = 1;
  src[1] = .6;
  src[2] = -4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<testV>:
  endbr64
  mov    D12(%rip),%rax
  mov    %rax,(%rdi)
  mov    D28(%rip),%rax
  mov    %rax,0x8(%rdi)
  mov    D18(%rip),%rax
  mov    %rax,0x10(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D28
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D18
type_infered: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D28": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0xc0]}

assistant: ```c
void testV(double *src) {
  src[0] = 1;
  src[1] = .6;
  src[2] = -4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testV>:
  endbr64
  movapd D7(%rip),%xmm0
  mov    D18(%rip),%rax
  movups %xmm0,(%rdi)
  mov    %rax,0x10(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D18
data_type: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0xc0]}

assistant: ```c
void testV(double *src) {
  src[0] = 1;
  src[1] = .6;
  src[2] = -4;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jl     L37
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L8
L37:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jle    L28
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L8
L28:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L8:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L55
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D0
type: string

tool: D1: %d
%d
%d

tool: D0: %d
%d
%d


assistant: ```c
int main() {
  int aux, a, b, c;
  scanf("%d\n%d\n%d", &a, &b, &c);
  if (a < b || a < c) {
    if (b > c) {
      aux = a;
      a = b;
      b = aux;
    } else {
      aux = a;
      a = c;
      c = aux;
    }
  }
  if (b < c) {
    aux = b;
    b = c;
    c = aux;
  }
  printf("%d\n%d\n%d\n", a, b, c);
  return 0;
}
```