ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%ebx
L16:
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%ecx
  cmp    %cl,%dl
  jne    L19
  mov    %rax,%rbx
L19:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L16
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *strrchr(register const char *s, int c) {
  register const char *p;
  p = 0;
  do {
    if (*s == (char)c) {
      p = s;
    }
  } while (*s++);
  return (char *)p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strrchr>:
  endbr64
  mov    $0x0,%edx
L1:
  movzbl (%rdi),%eax
  cmp    %sil,%al
  cmove  %rdi,%rdx
  add    $0x1,%rdi
  test   %al,%al
  jne    L1
  mov    %rdx,%rax
  ret
```

assistant: ```c
char *strrchr(register const char *s, int c) {
  register const char *p;
  p = 0;
  do {
    if (*s == (char)c) {
      p = s;
    }
  } while (*s++);
  return (char *)p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strrchr>:
  endbr64
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%rdi),%eax
  cmp    %sil,%al
  cmove  %rdi,%r8
  add    $0x1,%rdi
  test   %al,%al
  jne    L9
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strrchr(register const char *s, int c) {
  register const char *p;
  p = 0;
  do {
    if (*s == (char)c) {
      p = s;
    }
  } while (*s++);
  return (char *)p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strrchr>:
  endbr64
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl (%rdi),%eax
  cmp    %al,%sil
  je     L36
  add    $0x1,%rdi
  test   %al,%al
  jne    L38
L13:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L36:
  lea    0x1(%rdi),%rax
  mov    %rdi,%r8
  test   %sil,%sil
  je     L13
  mov    %rax,%rdi
  jmp    L38
```

assistant: ```c
char *strrchr(register const char *s, int c) {
  register const char *p;
  p = 0;
  do {
    if (*s == (char)c) {
      p = s;
    }
  } while (*s++);
  return (char *)p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <generate_key@plt>
  mov    $0x0,%eax
  call   <free_all_publickey@plt>
  mov    $0x0,%eax
  call   <free_all_privatekey@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  generate_key();
  free_all_publickey();
  free_all_privatekey();
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <generate_key@plt>
  mov    $0x0,%eax
  call   <free_all_publickey@plt>
  mov    $0x0,%eax
  call   <free_all_privatekey@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  generate_key();
  free_all_publickey();
  free_all_privatekey();
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <generate_key@plt>
  xor    %eax,%eax
  call   <free_all_publickey@plt>
  xor    %eax,%eax
  call   <free_all_privatekey@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  generate_key();
  free_all_publickey();
  free_all_privatekey();
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <generate_key@plt>
  xor    %eax,%eax
  call   <free_all_publickey@plt>
  xor    %eax,%eax
  call   <free_all_privatekey@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  generate_key();
  free_all_publickey();
  free_all_privatekey();
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<scmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L23
L21:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L21
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int scmp(char *s1, char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return (*s1 - *s2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<scmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L17:
  cmp    %al,(%rsi)
  jne    L3
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L17
L3:
  movsbl %al,%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int scmp(char *s1, char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return (*s1 - *s2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scmp>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L24
  jmp    L5
  nopl   (%rax)
L29:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L38
  mov    %rdx,%rsi
L24:
  movsbl (%rsi),%edx
  cmp    %al,%dl
  je     L29
L19:
  sub    %edx,%eax
  ret
  nopl   (%rax)
L38:
  movsbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L5:
  movsbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L19
```

assistant: ```c
int scmp(char *s1, char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return (*s1 - *s2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scmp>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L26
  jmp    L44
  nopl   (%rax)
L32:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  lea    0x1(%rsi),%rdx
  test   %al,%al
  je     L38
  mov    %rdx,%rsi
L26:
  movsbl (%rsi),%edx
  cmp    %al,%dl
  je     L32
L30:
  sub    %edx,%eax
  ret
  nopl   (%rax)
L38:
  movsbl 0x1(%rsi),%edx
  xor    %eax,%eax
  sub    %edx,%eax
  ret
L44:
  movsbl (%rsi),%edx
  xor    %eax,%eax
  jmp    L30
```

assistant: ```c
int scmp(char *s1, char *s2) {
  while (*s1 != '\0' && *s1 == *s2) {
    s1++;
    s2++;
  }
  return (*s1 - *s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_cmd_line>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rdx
  lea    D10(%rip),%rsi
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L36
  mov    %rax,%rdi
  call   <process_cmd@plt>
  lea    D10(%rip),%rbx
  jmp    L20
L37:
  call   <process_cmd@plt>
L20:
  mov    %rsp,%rdx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L37
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_infered: string

tool: D10: ;

assistant: ```c
void process_cmd_line(char *cmd_line) {
  static const char *delim = ";";
  char *saveptr = NULL;
  char *next_tok;
  if ((next_tok = strtok_r(cmd_line, delim, &saveptr)) == NULL) {
    return;
  }
  process_cmd(next_tok);
  while ((next_tok = strtok_r(NULL, delim, &saveptr)) != NULL) {
    process_cmd(next_tok);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<process_cmd_line>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movq   $0x0,(%rsp)
  mov    %rbx,%rdx
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L34
  mov    %rax,%rdi
  call   <process_cmd@plt>
  jmp    L18
  cs nopw 0x0(%rax,%rax,1)
L30:
  call   <process_cmd@plt>
L18:
  xor    %edi,%edi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L30
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: ;

assistant: ```c
void process_cmd_line(char *cmd_line) {
  static const char *delim = ";";
  char *saveptr = NULL;
  char *next_tok;
  if ((next_tok = strtok_r(cmd_line, delim, &saveptr)) == NULL) {
    return;
  }
  process_cmd(next_tok);
  while ((next_tok = strtok_r(NULL, delim, &saveptr)) != NULL) {
    process_cmd(next_tok);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<process_cmd_line>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movq   $0x0,(%rsp)
  mov    %rbx,%rdx
  call   <strtok_r@plt>
  test   %rax,%rax
  je     L1
  mov    %rax,%rdi
  call   <process_cmd@plt>
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L7:
  call   <process_cmd@plt>
L2:
  xor    %edi,%edi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <strtok_r@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L7
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: ;

assistant: ```c
void process_cmd_line(char *cmd_line) {
  static const char *delim = ";";
  char *saveptr = NULL;
  char *next_tok;
  if ((next_tok = strtok_r(cmd_line, delim, &saveptr)) == NULL) {
    return;
  }
  process_cmd(next_tok);
  while ((next_tok = strtok_r(NULL, delim, &saveptr)) != NULL) {
    process_cmd(next_tok);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <leeNumero@plt>
  mov    %eax,-0xc(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <leeNumero@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <potencia@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D26
data_type: string

tool: D6: Introduzca la base:

tool: D27: Introduzca el exponente:

tool: D26: El resultado de %d elevado a %d es %d.


assistant: ```c
int main() {
  int base;
  int exponente;
  int resultado;
  printf("Introduzca la base:");
  base = leeNumero();
  printf("Introduzca el exponente:");
  exponente = leeNumero();
  resultado = potencia(base, exponente);
  printf("El resultado de %d elevado a %d es %d.\n", base, exponente, resultado);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <leeNumero@plt>
  mov    %eax,%ebx
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <leeNumero@plt>
  mov    %eax,%ebp
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <potencia@plt>
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D21
data_type: string

tool: D28: Introduzca la base:

tool: D24: Introduzca el exponente:

tool: D21: El resultado de %d elevado a %d es %d.


assistant: ```c
int main() {
  int base;
  int exponente;
  int resultado;
  printf("Introduzca la base:");
  base = leeNumero();
  printf("Introduzca el exponente:");
  exponente = leeNumero();
  resultado = potencia(base, exponente);
  printf("El resultado de %d elevado a %d es %d.\n", base, exponente, resultado);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <leeNumero@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <leeNumero@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <potencia@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type: string
name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string

tool: D8: Introduzca la base:

tool: D6: Introduzca el exponente:

tool: D24: El resultado de %d elevado a %d es %d.


assistant: ```c
int main() {
  int base;
  int exponente;
  int resultado;
  printf("Introduzca la base:");
  base = leeNumero();
  printf("Introduzca el exponente:");
  exponente = leeNumero();
  resultado = potencia(base, exponente);
  printf("El resultado de %d elevado a %d es %d.\n", base, exponente, resultado);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <leeNumero@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <leeNumero@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  mov    %eax,%r12d
  call   <potencia@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D29(%rip),%rdi
  mov    %eax,%ecx
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string

tool: D15: Introduzca la base:

tool: D13: Introduzca el exponente:

tool: D29: El resultado de %d elevado a %d es %d.


assistant: ```c
int main() {
  int base;
  int exponente;
  int resultado;
  printf("Introduzca la base:");
  base = leeNumero();
  printf("Introduzca el exponente:");
  exponente = leeNumero();
  resultado = potencia(base, exponente);
  printf("El resultado de %d elevado a %d es %d.\n", base, exponente, resultado);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gothic_hall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  movsd  %xmm3,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    $0x0,%eax
  call   <diff@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D49(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D35(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <xlate@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  D49(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  movsd  -0x10(%rbp),%xmm1
  movsd  D30(%rip),%xmm0
  movapd %xmm1,%xmm3
  mulsd  %xmm0,%xmm3
  movsd  -0x8(%rbp),%xmm1
  movsd  D30(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  mov    $0x1,%edi
  movapd %xmm3,%xmm1
  movq   %rax,%xmm0
  call   <cube@plt>
  mov    $0x0,%eax
  call   <endxlate@plt>
  movsd  -0x28(%rbp),%xmm1
  movsd  D31(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <xlate@plt>
  movsd  -0x28(%rbp),%xmm2
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm2,%xmm3
  mov    %ecx,%esi
  mov    %edx,%edi
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <gothic_matrix@plt>
  mov    $0x0,%eax
  call   <endxlate@plt>
  mov    $0x0,%eax
  call   <enddiff@plt>
  cmpl   $0x0,-0x2c(%rbp)
  je     L9
  movsd  -0x18(%rbp),%xmm1
  movsd  D49(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <xlate@plt>
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fancy_roof@plt>
  mov    $0x0,%eax
  call   <endxlate@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D49
type_guessed: f64
name: parse_data
arguments: data_label: D35
type_guessed: f64
name: parse_data
arguments: data_label: D30
type_guessed: f64
name: parse_data
arguments: data_label: D31
type_guessed: f64

tool: D49: 1.05

tool: D35: 2

tool: D30: 0.97

tool: D31: 1.5

assistant: ```c
void gothic_hall(double length, double width, double height, int larches, int warches, double border_thickness, int with_roof) {
  diff();
  xlate(0, 0, (height * 1.05) / 2.0 + border_thickness);
  cube(length * 0.97, width * 0.97, height * 1.05 + border_thickness * 2.0, 1);
  endxlate();
  xlate(0, 0, 1.5 * border_thickness);
  gothic_matrix(length, width, height, larches, warches, border_thickness);
  endxlate();
  enddiff();
  if (with_roof) {
    xlate(0, 0, height * 1.05 + border_thickness * 2.0);
    fancy_roof(width, length, height * 2.0);
    endxlate();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gothic_hall>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  movq   %xmm2,%rbx
  mov    %edi,%r12d
  mov    %esi,%r13d
  movsd  %xmm3,(%rsp)
  mov    %edx,%ebp
  mov    $0x0,%eax
  call   <diff@plt>
  movq   %rbx,%xmm5
  mulsd  D1(%rip),%xmm5
  movsd  %xmm5,0x18(%rsp)
  movapd %xmm5,%xmm0
  mulsd  D6(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <xlate@plt>
  movsd  (%rsp),%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm4,%xmm0
  movapd %xmm0,%xmm6
  addsd  0x18(%rsp),%xmm6
  movq   %xmm6,%r14
  movsd  D14(%rip),%xmm1
  movsd  0x8(%rsp),%xmm7
  mulsd  %xmm1,%xmm7
  movapd %xmm7,%xmm0
  mov    $0x1,%edi
  movapd %xmm6,%xmm2
  mulsd  0x10(%rsp),%xmm1
  call   <cube@plt>
  mov    $0x0,%eax
  call   <endxlate@plt>
  movsd  (%rsp),%xmm0
  mulsd  D31(%rip),%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <xlate@plt>
  movsd  (%rsp),%xmm3
  mov    %r13d,%esi
  mov    %r12d,%edi
  movq   %rbx,%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <gothic_matrix@plt>
  mov    $0x0,%eax
  call   <endxlate@plt>
  mov    $0x0,%eax
  call   <enddiff@plt>
  test   %ebp,%ebp
  jne    L10
L11:
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  movq   %r14,%xmm0
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <xlate@plt>
  movq   %rbx,%xmm2
  addsd  %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  call   <fancy_roof@plt>
  mov    $0x0,%eax
  call   <endxlate@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: f64
name: disassemble_data
arguments: data_tag: D6
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D14
type_guessed: f64
name: disassemble_data
arguments: data_tag: D31
type_guessed: f64

tool: D1: 1.05

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D14: 0.97

tool: D31: 1.5

assistant: ```c
void gothic_hall(double length, double width, double height, int larches, int warches, double border_thickness, int with_roof) {
  diff();
  xlate(0, 0, (height * 1.05) / 2.0 + border_thickness);
  cube(length * 0.97, width * 0.97, height * 1.05 + border_thickness * 2.0, 1);
  endxlate();
  xlate(0, 0, 1.5 * border_thickness);
  gothic_matrix(length, width, height, larches, warches, border_thickness);
  endxlate();
  enddiff();
  if (with_roof) {
    xlate(0, 0, height * 1.05 + border_thickness * 2.0);
    fancy_roof(width, length, height * 2.0);
    endxlate();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gothic_hall>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x30,%rsp
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x20(%rsp)
  movsd  %xmm0,0x10(%rsp)
  call   <diff@plt>
  movsd  0x20(%rsp),%xmm7
  xor    %esi,%esi
  xor    %edi,%edi
  mulsd  D31(%rip),%xmm7
  movsd  0x8(%rsp),%xmm0
  movapd %xmm7,%xmm5
  movsd  %xmm7,0x28(%rsp)
  mulsd  D26(%rip),%xmm5
  addsd  %xmm5,%xmm0
  call   <xlate@plt>
  movsd  0x8(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm1
  mov    $0x1,%edi
  movsd  0x10(%rsp),%xmm6
  movapd %xmm5,%xmm4
  addsd  %xmm5,%xmm4
  addsd  %xmm1,%xmm4
  movsd  D4(%rip),%xmm1
  mulsd  %xmm1,%xmm6
  mulsd  0x18(%rsp),%xmm1
  movapd %xmm4,%xmm2
  movsd  %xmm4,0x28(%rsp)
  movapd %xmm6,%xmm0
  call   <cube@plt>
  xor    %eax,%eax
  call   <endxlate@plt>
  movsd  0x8(%rsp),%xmm6
  xor    %esi,%esi
  xor    %edi,%edi
  mulsd  D18(%rip),%xmm6
  movapd %xmm6,%xmm0
  call   <xlate@plt>
  movsd  0x8(%rsp),%xmm3
  mov    %r12d,%esi
  mov    %ebp,%edi
  movsd  0x20(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  call   <gothic_matrix@plt>
  xor    %eax,%eax
  call   <endxlate@plt>
  xor    %eax,%eax
  call   <enddiff@plt>
  test   %ebx,%ebx
  movsd  0x28(%rsp),%xmm4
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  movapd %xmm4,%xmm0
  xor    %esi,%esi
  xor    %edi,%edi
  call   <xlate@plt>
  movsd  0x20(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm0
  addsd  %xmm2,%xmm2
  call   <fancy_roof@plt>
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10e0 <endxlate@plt>
```

tool_calls: name: unpack_data
arguments: label: D31
type_infered: f64
name: unpack_data
arguments: label: D26
type_infered: byte[8]
name: unpack_data
arguments: label: D4
type_infered: f64
name: unpack_data
arguments: label: D18
type_infered: f64

tool: D31: 1.05

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D4: 0.97

tool: D18: 1.5

assistant: ```c
void gothic_hall(double length, double width, double height, int larches, int warches, double border_thickness, int with_roof) {
  diff();
  xlate(0, 0, (height * 1.05) / 2.0 + border_thickness);
  cube(length * 0.97, width * 0.97, height * 1.05 + border_thickness * 2.0, 1);
  endxlate();
  xlate(0, 0, 1.5 * border_thickness);
  gothic_matrix(length, width, height, larches, warches, border_thickness);
  endxlate();
  enddiff();
  if (with_roof) {
    xlate(0, 0, height * 1.05 + border_thickness * 2.0);
    fancy_roof(width, length, height * 2.0);
    endxlate();
  }
}
```