ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pthread_attr_getdetachstate>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x4,%esi
  call   <_pthread_get_state@plt>
  mov    %eax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int pthread_attr_getdetachstate(pthread_attr_t *a, int *flag) {
  *flag = _pthread_get_state(a, 0x04);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<string_vscanf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_empty@plt>
  test   %eax,%eax
  jne    L16
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsscanf@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L5
L16:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
size_t string_vscanf(const char *string, const char *format, va_list vargs) {
  if (!string_empty(string)) {
    ssize_t result;
    if ((result = vsscanf(string, format, vargs)) < 0)
      result = 0;
    return result;
  } else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<string_vscanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <string_empty@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L10
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsscanf@plt>
  jmp    L2
```

assistant: ```c
size_t string_vscanf(const char *string, const char *format, va_list vargs) {
  if (!string_empty(string)) {
    ssize_t result;
    if ((result = vsscanf(string, format, vargs)) < 0)
      result = 0;
    return result;
  } else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_vscanf>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <string_empty@plt>
  test   %eax,%eax
  je     L9
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <vsscanf@plt>
```

assistant: ```c
size_t string_vscanf(const char *string, const char *format, va_list vargs) {
  if (!string_empty(string)) {
    ssize_t result;
    if ((result = vsscanf(string, format, vargs)) < 0)
      result = 0;
    return result;
  } else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<string_vscanf>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <string_empty@plt>
  test   %eax,%eax
  je     L5
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <vsscanf@plt>
```

assistant: ```c
size_t string_vscanf(const char *string, const char *format, va_list vargs) {
  if (!string_empty(string)) {
    ssize_t result;
    if ((result = vsscanf(string, format, vargs)) < 0)
      result = 0;
    return result;
  } else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<leftshift_onebit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0xf,-0x4(%rbp)
  jmp    L9
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  add    %edx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x5(%rbp),%al
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  mov    %al,-0x5(%rbp)
  subl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x0,-0x4(%rbp)
  jns    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void leftshift_onebit(unsigned char *input, unsigned char *output) {
  int i;
  unsigned char overflow = 0;
  for (i = 15; i >= 0; i--) {
    output[i] = input[i] << 1;
    output[i] |= overflow;
    overflow = (input[i] & 0x80) ? 1 : 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<leftshift_onebit>:
  endbr64
  mov    $0xf,%eax
  mov    $0x0,%ecx
L7:
  movzbl (%rdi,%rax,1),%edx
  add    %edx,%edx
  or     %ecx,%edx
  mov    %dl,(%rsi,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  shr    $0x7,%cl
  sub    $0x1,%rax
  cmp    $0xffffffffffffffff,%rax
  jne    L7
  ret
```

assistant: ```c
void leftshift_onebit(unsigned char *input, unsigned char *output) {
  int i;
  unsigned char overflow = 0;
  for (i = 15; i >= 0; i--) {
    output[i] = input[i] << 1;
    output[i] |= overflow;
    overflow = (input[i] & 0x80) ? 1 : 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<leftshift_onebit>:
  endbr64
  mov    $0xf,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%rdi,%rax,1),%edx
  add    %edx,%edx
  or     %ecx,%edx
  mov    %dl,(%rsi,%rax,1)
  movzbl (%rdi,%rax,1),%ecx
  shr    $0x7,%cl
  sub    $0x1,%rax
  jae    L3
  ret
```

assistant: ```c
void leftshift_onebit(unsigned char *input, unsigned char *output) {
  int i;
  unsigned char overflow = 0;
  for (i = 15; i >= 0; i--) {
    output[i] = input[i] << 1;
    output[i] |= overflow;
    overflow = (input[i] & 0x80) ? 1 : 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<leftshift_onebit>:
  endbr64
  mov    %rdi,%rax
  movzbl 0xf(%rdi),%edi
  mov    %rsi,%rdx
  lea    (%rdi,%rdi,1),%ecx
  mov    %cl,0xf(%rsi)
  movzbl 0xe(%rax),%edi
  movzbl 0xf(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0xe(%rdx)
  movzbl 0xd(%rax),%edi
  movzbl 0xe(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0xd(%rdx)
  movzbl 0xc(%rax),%edi
  movzbl 0xd(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0xc(%rdx)
  movzbl 0xb(%rax),%edi
  movzbl 0xc(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0xb(%rdx)
  movzbl 0xa(%rax),%edi
  movzbl 0xb(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0xa(%rdx)
  movzbl 0x9(%rax),%edi
  movzbl 0xa(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x9(%rdx)
  movzbl 0x8(%rax),%edi
  movzbl 0x9(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x8(%rdx)
  movzbl 0x7(%rax),%edi
  movzbl 0x8(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x7(%rdx)
  movzbl 0x6(%rax),%edi
  movzbl 0x7(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x6(%rdx)
  movzbl 0x5(%rax),%edi
  movzbl 0x6(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x5(%rdx)
  movzbl 0x5(%rax),%ecx
  movzbl 0x4(%rax),%edi
  shr    $0x7,%cl
  lea    (%rdi,%rdi,1),%esi
  or     %esi,%ecx
  mov    %cl,0x4(%rdx)
  movzbl 0x3(%rax),%edi
  movzbl 0x4(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x3(%rdx)
  movzbl 0x2(%rax),%edi
  movzbl 0x3(%rax),%ecx
  lea    (%rdi,%rdi,1),%esi
  shr    $0x7,%cl
  or     %esi,%ecx
  mov    %cl,0x2(%rdx)
  movzbl 0x2(%rax),%ecx
  movzbl 0x1(%rax),%esi
  shr    $0x7,%cl
  add    %esi,%esi
  or     %esi,%ecx
  mov    %cl,0x1(%rdx)
  movzbl (%rax),%edi
  movzbl 0x1(%rax),%eax
  lea    (%rdi,%rdi,1),%ecx
  shr    $0x7,%al
  or     %ecx,%eax
  mov    %al,(%rdx)
  ret
```

assistant: ```c
void leftshift_onebit(unsigned char *input, unsigned char *output) {
  int i;
  unsigned char overflow = 0;
  for (i = 15; i >= 0; i--) {
    output[i] = input[i] << 1;
    output[i] |= overflow;
    overflow = (input[i] & 0x80) ? 1 : 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GenPostIncDecLocal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0xa,-0x4(%rbp)
  cmpl   $0x51,-0x20(%rbp)
  je     L8
  movl   $0xb,-0x4(%rbp)
L8:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <GenReadLocal@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%r9d
  mov    $0x80,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <GenPrintInstr2Operands@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <GenWriteLocal@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0xffffffff,%r9d
  mov    $0x80,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <GenPrintInstr2Operands@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <GenExtendRegIfNeeded@plt>
  nop
  leave
  ret
```

assistant: ```c
void GenPostIncDecLocal(int regDst, int opSz, int ofs, int tok) {
  int instr = 0x0A;
  if (tok != 'Q')
    instr = 0x0B;
  GenReadLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, 1);
  GenWriteLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, -1);
  GenExtendRegIfNeeded(regDst, opSz);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GenPostIncDecLocal>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r13d
  cmp    $0x51,%ecx
  setne  %r12b
  movzbl %r12b,%r12d
  add    $0xa,%r12d
  call   <GenReadLocal@plt>
  mov    $0x1,%r9d
  mov    $0x80,%r8d
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <GenPrintInstr2Operands@plt>
  mov    %r13d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <GenWriteLocal@plt>
  mov    $0xffffffff,%r9d
  mov    $0x80,%r8d
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <GenPrintInstr2Operands@plt>
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <GenExtendRegIfNeeded@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void GenPostIncDecLocal(int regDst, int opSz, int ofs, int tok) {
  int instr = 0x0A;
  if (tok != 'Q')
    instr = 0x0B;
  GenReadLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, 1);
  GenWriteLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, -1);
  GenExtendRegIfNeeded(regDst, opSz);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GenPostIncDecLocal>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  cmp    $0x51,%ecx
  setne  %r13b
  call   <GenReadLocal@plt>
  add    $0xa,%r13d
  xor    %ecx,%ecx
  mov    %ebp,%edx
  mov    $0x1,%r9d
  mov    $0x80,%r8d
  mov    %r13d,%edi
  xor    %esi,%esi
  call   <GenPrintInstr2Operands@plt>
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <GenWriteLocal@plt>
  mov    %r13d,%edi
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%r9d
  mov    $0x80,%r8d
  xor    %ecx,%ecx
  call   <GenPrintInstr2Operands@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <GenExtendRegIfNeeded@plt>
```

assistant: ```c
void GenPostIncDecLocal(int regDst, int opSz, int ofs, int tok) {
  int instr = 0x0A;
  if (tok != 'Q')
    instr = 0x0B;
  GenReadLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, 1);
  GenWriteLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, -1);
  GenExtendRegIfNeeded(regDst, opSz);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GenPostIncDecLocal>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  cmp    $0x51,%ecx
  setne  %r13b
  call   <GenReadLocal@plt>
  add    $0xa,%r13d
  xor    %ecx,%ecx
  mov    %ebp,%edx
  mov    $0x1,%r9d
  mov    $0x80,%r8d
  mov    %r13d,%edi
  xor    %esi,%esi
  call   <GenPrintInstr2Operands@plt>
  mov    %r14d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <GenWriteLocal@plt>
  mov    %r13d,%edi
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%r9d
  mov    $0x80,%r8d
  xor    %ecx,%ecx
  call   <GenPrintInstr2Operands@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <GenExtendRegIfNeeded@plt>
```

assistant: ```c
void GenPostIncDecLocal(int regDst, int opSz, int ofs, int tok) {
  int instr = 0x0A;
  if (tok != 'Q')
    instr = 0x0B;
  GenReadLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, 1);
  GenWriteLocal(regDst, opSz, ofs);
  GenPrintInstr2Operands(instr, 0, regDst, 0, 0x80, -1);
  GenExtendRegIfNeeded(regDst, opSz);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allocIobuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x828,%esi
  mov    $0xcaff,%edi
  call   <svcAlloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x828,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <IOSMCPPAYLOAD_memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *allocIobuf() {
  void *ptr = svcAlloc(0xCAFF, 0x828);
  IOSMCPPAYLOAD_memset(ptr, 0x00, 0x828);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<allocIobuf>:
  endbr64
  push   %rbx
  mov    $0x828,%esi
  mov    $0xcaff,%edi
  call   <svcAlloc@plt>
  mov    %rax,%rbx
  mov    $0x828,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <IOSMCPPAYLOAD_memset@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *allocIobuf() {
  void *ptr = svcAlloc(0xCAFF, 0x828);
  IOSMCPPAYLOAD_memset(ptr, 0x00, 0x828);
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<allocIobuf>:
  endbr64
  push   %r12
  mov    $0x828,%esi
  mov    $0xcaff,%edi
  call   <svcAlloc@plt>
  mov    $0x828,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <IOSMCPPAYLOAD_memset@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *allocIobuf() {
  void *ptr = svcAlloc(0xCAFF, 0x828);
  IOSMCPPAYLOAD_memset(ptr, 0x00, 0x828);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<allocIobuf>:
  endbr64
  push   %r12
  mov    $0x828,%esi
  mov    $0xcaff,%edi
  call   <svcAlloc@plt>
  mov    $0x828,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <IOSMCPPAYLOAD_memset@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *allocIobuf() {
  void *ptr = svcAlloc(0xCAFF, 0x828);
  IOSMCPPAYLOAD_memset(ptr, 0x00, 0x828);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m68k_op_cpgen_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <m68ki_exception_1111@plt>
  pop    %rbp
  ret
```

assistant: ```c
void m68k_op_cpgen_32(void) {
  if (0) {

    ;
    return;
  }
  m68ki_exception_1111();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<m68k_op_cpgen_32>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <m68ki_exception_1111@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void m68k_op_cpgen_32(void) {
  if (0) {

    ;
    return;
  }
  m68ki_exception_1111();
}
```
user: Translate the below assembly code into C programming language:

```asm
<m68k_op_cpgen_32>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <m68ki_exception_1111@plt>
```

assistant: ```c
void m68k_op_cpgen_32(void) {
  if (0) {

    ;
    return;
  }
  m68ki_exception_1111();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<m68k_op_cpgen_32>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <m68ki_exception_1111@plt>
```

assistant: ```c
void m68k_op_cpgen_32(void) {
  if (0) {

    ;
    return;
  }
  m68ki_exception_1111();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<daynumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jle    L68
  cmpl   $0xc,-0x18(%rbp)
  jle    L5
L68:
  mov    $0xffffffff,%eax
  jmp    L63
L5:
  cmpl   $0x76b,-0x14(%rbp)
  jle    L64
  subl   $0x76c,-0x14(%rbp)
L64:
  mov    D5(%rip),%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L9
  mov    $0xffffffff,%eax
  jmp    L63
L9:
  mov    -0x8(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  sub    %eax,-0x8(%rbp)
  mov    D13(%rip),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    D27(%rip),%eax
  imul   -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D24(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  add    %edx,%eax
  add    %eax,-0xc(%rbp)
  cmpl   $0x3,-0x8(%rbp)
  jne    L21
  cmpl   $0x2,-0x18(%rbp)
  jle    L21
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
L63:
  pop    %rbp
  ret
```

assistant: ```c
int daynumber(int year, int month, int day) {
  int ndays;
  static int year0 = 73, days4yrs = 1461, days1yr = 365;
  static int modays[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365};
  int nyears, nfouryrs;
  if (month < 1 || month > 12)
    return (-1);
  if (year >= 1900)
    year -= 1900;
  nyears = year - year0;
  if (nyears < 0)
    return (-1);
  nfouryrs = nyears / 4;
  nyears -= (4 * nfouryrs);
  ndays = (days4yrs * nfouryrs) + (days1yr * nyears);
  ndays += (modays[month - 1] + (day - 1));
  if (nyears == 3) {
    if (month > 2)
      ndays++;
  }
  return ((int)(ndays));
}
```
user: What is the c source code of the assembly code below:

```asm
<daynumber>:
  endbr64
  mov    %edx,%r8d
  lea    -0x1(%rsi),%eax
  cmp    $0xb,%eax
  ja     L22
  lea    -0x76c(%rdi),%eax
  cmp    $0x76b,%edi
  cmovg  %eax,%edi
  sub    $0x49,%edi
  js     L19
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rdi,%rax,1),%ecx
  and    $0x3,%ecx
  sub    %eax,%ecx
  lea    0x3(%rdi),%edx
  test   %edi,%edi
  cmovns %edi,%edx
  sar    $0x2,%edx
  imul   $0x5b5,%edx,%edx
  imul   $0x16d,%ecx,%eax
  add    %eax,%edx
  lea    -0x1(%rsi),%eax
  cltq
  lea    D2(%rip),%rdi
  mov    (%rdi,%rax,4),%eax
  lea    -0x1(%r8,%rax,1),%eax
  add    %edx,%eax
  cmp    $0x2,%esi
  jle    L28
  cmp    $0x3,%ecx
  sete   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%eax
  ret
L22:
  mov    $0xffffffff,%eax
  ret
L19:
  mov    $0xffffffff,%eax
L28:
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type: string

tool: 

assistant: ```c
int daynumber(int year, int month, int day) {
  int ndays;
  static int year0 = 73, days4yrs = 1461, days1yr = 365;
  static int modays[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365};
  int nyears, nfouryrs;
  if (month < 1 || month > 12)
    return (-1);
  if (year >= 1900)
    year -= 1900;
  nyears = year - year0;
  if (nyears < 0)
    return (-1);
  nfouryrs = nyears / 4;
  nyears -= (4 * nfouryrs);
  ndays = (days4yrs * nfouryrs) + (days1yr * nyears);
  ndays += (modays[month - 1] + (day - 1));
  if (nyears == 3) {
    if (month > 2)
      ndays++;
  }
  return ((int)(ndays));
}
```
user: Translate the below assembly code into C programming language:

```asm
<daynumber>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    %esi,%ecx
  cmp    $0xb,%eax
  ja     L21
  lea    -0x76c(%rdi),%esi
  cmp    $0x76b,%edi
  cmovg  %esi,%edi
  sub    $0x49,%edi
  js     L21
  mov    %edi,%esi
  sar    $0x2,%edi
  cltq
  and    $0x3,%esi
  imul   $0x5b5,%edi,%edi
  imul   $0x16d,%esi,%r8d
  add    %r8d,%edi
  lea    D2(%rip),%r8
  mov    (%r8,%rax,4),%eax
  lea    -0x1(%rdx,%rax,1),%eax
  add    %edi,%eax
  cmp    $0x3,%esi
  jne    L29
  cmp    $0x2,%ecx
  setg   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%eax
  ret
  nop
L21:
  mov    $0xffffffff,%eax
L29:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: 

assistant: ```c
int daynumber(int year, int month, int day) {
  int ndays;
  static int year0 = 73, days4yrs = 1461, days1yr = 365;
  static int modays[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365};
  int nyears, nfouryrs;
  if (month < 1 || month > 12)
    return (-1);
  if (year >= 1900)
    year -= 1900;
  nyears = year - year0;
  if (nyears < 0)
    return (-1);
  nfouryrs = nyears / 4;
  nyears -= (4 * nfouryrs);
  ndays = (days4yrs * nfouryrs) + (days1yr * nyears);
  ndays += (modays[month - 1] + (day - 1));
  if (nyears == 3) {
    if (month > 2)
      ndays++;
  }
  return ((int)(ndays));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<daynumber>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    %esi,%ecx
  cmp    $0xb,%eax
  ja     L15
  lea    -0x76c(%rdi),%esi
  cmp    $0x76b,%edi
  cmovg  %esi,%edi
  sub    $0x49,%edi
  js     L15
  mov    %edi,%esi
  sar    $0x2,%edi
  cltq
  and    $0x3,%esi
  imul   $0x5b5,%edi,%edi
  imul   $0x16d,%esi,%r8d
  add    %r8d,%edi
  lea    D4(%rip),%r8
  mov    (%r8,%rax,4),%eax
  lea    -0x1(%rdx,%rax,1),%eax
  add    %edi,%eax
  cmp    $0x3,%esi
  jne    L19
  cmp    $0x2,%ecx
  setg   %dl
  cmp    $0x1,%dl
  sbb    $0xffffffff,%eax
  ret
  nop
L15:
  mov    $0xffffffff,%eax
L19:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_guessed: string

tool: 

assistant: ```c
int daynumber(int year, int month, int day) {
  int ndays;
  static int year0 = 73, days4yrs = 1461, days1yr = 365;
  static int modays[] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365};
  int nyears, nfouryrs;
  if (month < 1 || month > 12)
    return (-1);
  if (year >= 1900)
    year -= 1900;
  nyears = year - year0;
  if (nyears < 0)
    return (-1);
  nfouryrs = nyears / 4;
  nyears -= (4 * nfouryrs);
  ndays = (days4yrs * nfouryrs) + (days1yr * nyears);
  ndays += (modays[month - 1] + (day - 1));
  if (nyears == 3) {
    if (month > 2)
      ndays++;
  }
  return ((int)(ndays));
}
```