ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ln_get_uranus_disk>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  call   <ln_get_earth_solar_dist@plt>
  movsd  %xmm0,0x8(%rsp)
  movq   %rbx,%xmm0
  call   <ln_get_uranus_solar_dist@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm0
  call   <ln_get_uranus_earth_dist@plt>
  movapd %xmm0,%xmm2
  movq   %r14,%xmm3
  movq   %r14,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm4
  mulsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
  mulsd  D3(%rip),%xmm3
  movapd %xmm3,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: f64

tool: D3: 4

assistant: ```c
double ln_get_uranus_disk(double JD) {
  double r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_uranus_solar_dist(JD);
  delta = ln_get_uranus_earth_dist(JD);
  return (((r + delta) * (r + delta)) - R * R) / (4.0 * r * delta);
}
```
user: What is the c source code of the assembly code below:

```asm
<ln_get_uranus_disk>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ln_get_earth_solar_dist@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <ln_get_uranus_solar_dist@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <ln_get_uranus_earth_dist@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm3,%xmm3
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  mulsd  D8(%rip),%xmm2
  add    $0x28,%rsp
  mulsd  %xmm1,%xmm1
  mulsd  %xmm4,%xmm2
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: f64

tool: D8: 4

assistant: ```c
double ln_get_uranus_disk(double JD) {
  double r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_uranus_solar_dist(JD);
  delta = ln_get_uranus_earth_dist(JD);
  return (((r + delta) * (r + delta)) - R * R) / (4.0 * r * delta);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ln_get_uranus_disk>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <ln_get_earth_solar_dist@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  call   <ln_get_uranus_solar_dist@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <ln_get_uranus_earth_dist@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm3
  movapd %xmm0,%xmm4
  mulsd  %xmm3,%xmm3
  movapd %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  mulsd  D0(%rip),%xmm2
  add    $0x28,%rsp
  mulsd  %xmm1,%xmm1
  mulsd  %xmm4,%xmm2
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: f64

tool: D0: 4

assistant: ```c
double ln_get_uranus_disk(double JD) {
  double r, delta, R;
  R = ln_get_earth_solar_dist(JD);
  r = ln_get_uranus_solar_dist(JD);
  delta = ln_get_uranus_earth_dist(JD);
  return (((r + delta) * (r + delta)) - R * R) / (4.0 * r * delta);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  leave
  ret
```

assistant: ```c
void crash(struct context *context_unused, void *data_unused, size_t id_unused) {
  (void)context_unused;
  (void)data_unused;
  (void)id_unused;
  abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crash>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void crash(struct context *context_unused, void *data_unused, size_t id_unused) {
  (void)context_unused;
  (void)data_unused;
  (void)id_unused;
  abort();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crash>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void crash(struct context *context_unused, void *data_unused, size_t id_unused) {
  (void)context_unused;
  (void)data_unused;
  (void)id_unused;
  abort();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crash>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void crash(struct context *context_unused, void *data_unused, size_t id_unused) {
  (void)context_unused;
  (void)data_unused;
  (void)id_unused;
  abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<maxscore>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x1e,%ecx
  rep stos %rax,%es:(%rdi)
  movss  0x0(%rbp),%xmm5
  movss  %xmm5,0xc(%rsp)
  test   %esi,%esi
  jle    L71
  mov    %edx,%esi
  mov    %rbp,%r11
  mov    $0x0,%edx
  jmp    L142
L2:
  movss  0xc(%rsp),%xmm4
  ucomiss %xmm4,%xmm0
  jp     L1
  jne    L1
  movslq %ecx,%r10
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  movss  %xmm0,0x10(%rsp,%r10,8)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,0x14(%rsp,%r10,8)
  add    $0x1,%ecx
L1:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L14
L16:
  movss  (%r8,%rax,4),%xmm0
  comiss 0xc(%rsp),%xmm0
  jbe    L2
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  movss  %xmm1,0x10(%rsp)
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x14(%rsp)
  movss  %xmm0,0xc(%rsp)
  mov    $0x1,%ecx
  jmp    L1
L14:
  add    $0x1,%edx
  add    $0x14,%r11
  cmp    %edx,%r9d
  je     L71
L142:
  mov    %r11,%r8
  mov    $0x0,%eax
  test   %esi,%esi
  jg     L16
  jmp    L14
L71:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbx
  lea    0x100(%rsp),%r12
  lea    D8(%rip),%r13
  jmp    L9
L103:
  add    $0x8,%rbx
  cmp    %rbx,%r12
  je     L159
L9:
  cvttss2si (%rbx),%esi
  cvttss2si 0x4(%rbx),%ecx
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rax
  movslq %ecx,%rdx
  movss  0xc(%rsp),%xmm2
  ucomiss (%rax,%rdx,4),%xmm2
  jp     L103
  jne    L103
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mov    %ecx,%edx
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L103
L159:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D14: 
All of the max score is:

tool: D8: i=%d j=%d max=%6.3f


assistant: ```c
void maxscore(float num[][5], int rows, int cols) {
  float stu[30][2] = {0};
  float max = num[0][0];
  int i, j, k = 0;
  int index1, index2;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      if (num[i][j] > max) {
        max = num[i][j];
        k = 0;
        stu[k][0] = i;
        stu[k][1] = j;
        k++;
      } else if (num[i][j] == max) {
        stu[k][0] = i;
        stu[k][1] = j;
        k++;
      }
    }
  }
  printf("\nAll of the max score is:\n");
  for (i = 0; i < 30; i++) {
    index1 = stu[i][0];
    index2 = stu[i][1];
    if (num[index1][index2] == max) {
      printf("i=%d j=%d max=%6.3f\n", index1, index2, max);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<maxscore>:
  endbr64
  push   %r13
  mov    $0x1e,%ecx
  pxor   %xmm0,%xmm0
  mov    %esi,%r9d
  push   %r12
  mov    %rdi,%r12
  movaps %xmm0,%xmm2
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  movss  (%r12),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  rep stos %rax,%es:(%rdi)
  test   %esi,%esi
  jle    L82
  mov    %edx,%r8d
  xor    %esi,%esi
  mov    %r12,%rdx
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  test   %r8d,%r8d
  jg     L47
  jmp    L4
  nopl   0x0(%rax)
L67:
  pxor   %xmm1,%xmm1
  mov    $0x1,%esi
  cvtsi2ss %ecx,%xmm1
  movss  %xmm1,0x10(%rsp)
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0x14(%rsp)
  movaps %xmm0,%xmm1
L88:
  add    $0x1,%rax
  cmp    %eax,%r8d
  jle    L4
L47:
  movss  (%rdx,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  ja     L67
  ucomiss %xmm1,%xmm0
  jp     L88
  jne    L88
  pxor   %xmm0,%xmm0
  movslq %esi,%r10
  add    $0x1,%esi
  cvtsi2ss %ecx,%xmm0
  movss  %xmm0,0x10(%rsp,%r10,8)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  add    $0x1,%rax
  movss  %xmm0,0x14(%rsp,%r10,8)
  cmp    %eax,%r8d
  jg     L47
L4:
  add    $0x1,%ecx
  add    $0x14,%rdx
  cmp    %ecx,%r9d
  jne    L11
  movss  0x10(%rsp),%xmm2
  movss  0x14(%rsp),%xmm0
L82:
  lea    D15(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  lea    0x18(%rsp),%rbx
  movss  %xmm2,0x8(%rsp)
  lea    0x100(%rsp),%r13
  lea    D4(%rip),%rbp
  movss  %xmm1,0x4(%rsp)
  call   <puts@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm2
  movss  0x4(%rsp),%xmm1
  jmp    L136
  nopl   (%rax)
L118:
  cmp    %rbx,%r13
  je     L30
L79:
  movss  (%rbx),%xmm2
  movss  0x4(%rbx),%xmm0
  add    $0x8,%rbx
L136:
  cvttss2si %xmm2,%esi
  cvttss2si %xmm0,%edx
  movslq %esi,%rax
  lea    (%rax,%rax,4),%rax
  movslq %edx,%rcx
  lea    (%r12,%rax,4),%rax
  ucomiss (%rax,%rcx,4),%xmm1
  jp     L118
  jne    L118
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  movss  %xmm1,0x4(%rsp)
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  movss  0x4(%rsp),%xmm1
  cmp    %rbx,%r13
  jne    L79
L30:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string

tool: D15: 
All of the max score is:

tool: D4: i=%d j=%d max=%6.3f


assistant: ```c
void maxscore(float num[][5], int rows, int cols) {
  float stu[30][2] = {0};
  float max = num[0][0];
  int i, j, k = 0;
  int index1, index2;
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      if (num[i][j] > max) {
        max = num[i][j];
        k = 0;
        stu[k][0] = i;
        stu[k][1] = j;
        k++;
      } else if (num[i][j] == max) {
        stu[k][0] = i;
        stu[k][1] = j;
        k++;
      }
    }
  }
  printf("\nAll of the max score is:\n");
  for (i = 0; i < 30; i++) {
    index1 = stu[i][0];
    index2 = stu[i][1];
    if (num[index1][index2] == max) {
      printf("i=%d j=%d max=%6.3f\n", index1, index2, max);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_ts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int64_t __attribute__((unused)) get_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (int64_t)tv.tv_sec * 1000000LL + tv.tv_usec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ts>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t __attribute__((unused)) get_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (int64_t)tv.tv_sec * 1000000LL + tv.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_ts>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t __attribute__((unused)) get_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (int64_t)tv.tv_sec * 1000000LL + tv.tv_usec;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_ts>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int64_t __attribute__((unused)) get_ts(void) {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return (int64_t)tv.tv_sec * 1000000LL + tv.tv_usec;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findlongest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %esi,-0x42c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x414(%rbp)
  movl   $0x0,-0x420(%rbp)
  movl   $0x0,-0x41c(%rbp)
  mov    -0x428(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  movl   $0x0,-0x410(%rbp,%rax,4)
  movl   $0x1,-0x418(%rbp)
  jmp    L71
L60:
  mov    -0x418(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  cmp    $0xffffffff,%eax
  je     L10
  mov    -0x418(%rbp),%eax
  sub    -0x420(%rbp),%eax
  mov    %eax,%edx
  mov    -0x418(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x428(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L24
L10:
  addl   $0x1,-0x420(%rbp)
  jmp    L65
L24:
  mov    -0x420(%rbp),%eax
  cmp    -0x41c(%rbp),%eax
  jle    L59
  mov    -0x420(%rbp),%eax
  mov    %eax,-0x41c(%rbp)
L59:
  mov    -0x418(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%edx
  mov    -0x418(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x420(%rbp)
L65:
  mov    -0x418(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x418(%rbp),%edx
  mov    %edx,-0x410(%rbp,%rax,4)
  addl   $0x1,-0x418(%rbp)
L71:
  mov    -0x418(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jl     L60
  mov    -0x420(%rbp),%eax
  cmp    -0x41c(%rbp),%eax
  jle    L41
  mov    -0x420(%rbp),%eax
  mov    %eax,-0x41c(%rbp)
L41:
  mov    -0x41c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: Max string len is  %d

assistant: ```c
void findlongest(char a[], int len) {
  int prev_instance[256];
  memset(prev_instance, -1, sizeof(prev_instance));
  int prev = 0;
  int cur_len = 0;
  int max_len = 0;
  prev_instance[a[0]] = 0;
  for (int i = 1; i < len; i++) {
    if ((prev_instance[a[i]] == -1) || (i - cur_len > prev_instance[a[i]])) {
      cur_len++;
    } else {
      if (cur_len > max_len) {
        max_len = cur_len;
      }
      cur_len = (i - prev_instance[a[i]]);
    }
    prev_instance[a[i]] = i;
  }
  if (cur_len > max_len)
    max_len = cur_len;
  printf("Max string len is  %d", max_len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findlongest>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    $0xffffffff,%esi
  call   <memset@plt>
  movsbq (%rbx),%rax
  movl   $0x0,(%rsp,%rax,4)
  cmp    $0x1,%ebp
  jle    L66
  mov    %ebp,%r8d
  mov    $0x1,%eax
  mov    $0x0,%r9d
  mov    $0x0,%esi
  jmp    L27
L48:
  add    $0x1,%esi
L39:
  movslq %edx,%rdx
  mov    %edi,(%rsp,%rdx,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L14
L27:
  mov    %eax,%edi
  movsbl (%rbx,%rax,1),%edx
  movslq %edx,%rcx
  mov    (%rsp,%rcx,4),%ecx
  cmp    $0xffffffff,%ecx
  je     L48
  mov    %eax,%r10d
  sub    %esi,%r10d
  cmp    %r10d,%ecx
  jl     L48
  cmp    %esi,%r9d
  cmovl  %esi,%r9d
  mov    %eax,%esi
  sub    %ecx,%esi
  jmp    L39
L66:
  mov    $0x0,%r9d
  mov    $0x0,%esi
L14:
  cmp    %r9d,%esi
  cmovl  %r9d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: Max string len is  %d

assistant: ```c
void findlongest(char a[], int len) {
  int prev_instance[256];
  memset(prev_instance, -1, sizeof(prev_instance));
  int prev = 0;
  int cur_len = 0;
  int max_len = 0;
  prev_instance[a[0]] = 0;
  for (int i = 1; i < len; i++) {
    if ((prev_instance[a[i]] == -1) || (i - cur_len > prev_instance[a[i]])) {
      cur_len++;
    } else {
      if (cur_len > max_len) {
        max_len = cur_len;
      }
      cur_len = (i - prev_instance[a[i]]);
    }
    prev_instance[a[i]] = i;
  }
  if (cur_len > max_len)
    max_len = cur_len;
  printf("Max string len is  %d", max_len);
}
```
user: What is the c source code of the assembly code below?

```asm
<findlongest>:
  endbr64
  push   %rbp
  mov    $0x400,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0xffffffff,%esi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq 0x0(%rbp),%rax
  movl   $0x0,(%rsp,%rax,4)
  cmp    $0x1,%ebx
  jle    L35
  movslq %ebx,%r8
  mov    $0x1,%eax
  xor    %r10d,%r10d
  xor    %esi,%esi
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %eax,%r9d
  sub    %esi,%r9d
  cmp    %r9d,%ecx
  jl     L41
  cmp    %esi,%r10d
  mov    %edi,(%rsp,%rdx,4)
  cmovl  %esi,%r10d
  mov    %eax,%esi
  add    $0x1,%rax
  sub    %ecx,%esi
  cmp    %rax,%r8
  je     L3
L65:
  movsbq 0x0(%rbp,%rax,1),%rdx
  mov    %eax,%edi
  mov    (%rsp,%rdx,4),%ecx
  cmp    $0xffffffff,%ecx
  jne    L36
L41:
  add    $0x1,%rax
  mov    %edi,(%rsp,%rdx,4)
  add    $0x1,%esi
  cmp    %rax,%r8
  jne    L65
L3:
  cmp    %r10d,%esi
  cmovl  %r10d,%esi
L73:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L35:
  xor    %esi,%esi
  jmp    L73
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: Max string len is  %d

assistant: ```c
void findlongest(char a[], int len) {
  int prev_instance[256];
  memset(prev_instance, -1, sizeof(prev_instance));
  int prev = 0;
  int cur_len = 0;
  int max_len = 0;
  prev_instance[a[0]] = 0;
  for (int i = 1; i < len; i++) {
    if ((prev_instance[a[i]] == -1) || (i - cur_len > prev_instance[a[i]])) {
      cur_len++;
    } else {
      if (cur_len > max_len) {
        max_len = cur_len;
      }
      cur_len = (i - prev_instance[a[i]]);
    }
    prev_instance[a[i]] = i;
  }
  if (cur_len > max_len)
    max_len = cur_len;
  printf("Max string len is  %d", max_len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findlongest>:
  endbr64
  push   %rbp
  mov    $0x400,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  mov    $0xffffffff,%esi
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  movsbq 0x0(%rbp),%rax
  movl   $0x0,(%rsp,%rax,4)
  cmp    $0x1,%ebx
  jle    L41
  movslq %ebx,%r8
  mov    $0x1,%eax
  xor    %r10d,%r10d
  xor    %esi,%esi
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %eax,%r9d
  sub    %esi,%r9d
  cmp    %r9d,%ecx
  jl     L25
  cmp    %esi,%r10d
  mov    %edi,(%rsp,%rdx,4)
  cmovl  %esi,%r10d
  mov    %eax,%esi
  add    $0x1,%rax
  sub    %ecx,%esi
  cmp    %rax,%r8
  je     L61
L47:
  movsbq 0x0(%rbp,%rax,1),%rdx
  mov    %eax,%edi
  mov    (%rsp,%rdx,4),%ecx
  cmp    $0xffffffff,%ecx
  jne    L14
L25:
  add    $0x1,%rax
  mov    %edi,(%rsp,%rdx,4)
  add    $0x1,%esi
  cmp    %rax,%r8
  jne    L47
L61:
  cmp    %r10d,%esi
  cmovl  %r10d,%esi
L45:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L41:
  xor    %esi,%esi
  jmp    L45
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: Max string len is  %d

assistant: ```c
void findlongest(char a[], int len) {
  int prev_instance[256];
  memset(prev_instance, -1, sizeof(prev_instance));
  int prev = 0;
  int cur_len = 0;
  int max_len = 0;
  prev_instance[a[0]] = 0;
  for (int i = 1; i < len; i++) {
    if ((prev_instance[a[i]] == -1) || (i - cur_len > prev_instance[a[i]])) {
      cur_len++;
    } else {
      if (cur_len > max_len) {
        max_len = cur_len;
      }
      cur_len = (i - prev_instance[a[i]]);
    }
    prev_instance[a[i]] = i;
  }
  if (cur_len > max_len)
    max_len = cur_len;
  printf("Max string len is  %d", max_len);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    $0x0,%eax
  jmp    L1
L44:
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L30
  movl   $0xffffffff,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L30
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isNumericChar@plt>
  test   %eax,%eax
  jne    L43
  mov    $0x0,%eax
  jmp    L1
L43:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x8(%rbp),%eax
  imul   -0xc(%rbp),%eax
L1:
  leave
  ret
```

assistant: ```c
int stoi(const char *str) {
  if ((*str) == 0)
    return 0;
  int res = 0;
  int sign = 1;
  int i = 0;
  if (str[0] == '-') {
    sign = -1;
    i++;
  }
  for (; str[i] != '\0'; ++i) {
    if (isNumericChar(str[i]) == false)
      return 0;
    res = res * 10 + str[i] - '0';
  }
  return sign * res;
}
```