ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <develop@plt>
  mov    %eax,-0x4(%rbp)
L23:
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L6:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  addl   $0x1,-0x8(%rbp)
L11:
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L6
  jmp    L23
```

tool_calls: name: read_data
arguments: data_tag: D10
data_type: string
name: read_data
arguments: data_tag: D16
data_type: string

tool: D10:  >>>>>start main function>>>>>> 

tool: D16: this is a test program : %d 


assistant: ```c
int main(void) {
  int i;
  int result;
  printf(" >>>>>start main function>>>>>> \n");
  result = develop();
  while (1) {
    for (i = 0; i < 1000; i++) {
      printf("this is a test program : %d \n", i);
      sleep(1);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <develop@plt>
  lea    D18(%rip),%rbp
L0:
  mov    $0x0,%ebx
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  add    $0x1,%ebx
  cmp    $0x3e8,%ebx
  jne    L1
  jmp    L0
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D6:  >>>>>start main function>>>>>> 

tool: D18: this is a test program : %d 


assistant: ```c
int main(void) {
  int i;
  int result;
  printf(" >>>>>start main function>>>>>> \n");
  result = develop();
  while (1) {
    for (i = 0; i < 1000; i++) {
      printf("this is a test program : %d \n", i);
      sleep(1);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  xor    %eax,%eax
  call   <develop@plt>
  nopl   0x0(%rax)
L11:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x3e8,%ebx
  jne    L4
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D10:  >>>>>start main function>>>>>> 

tool: D8: this is a test program : %d 


assistant: ```c
int main(void) {
  int i;
  int result;
  printf(" >>>>>start main function>>>>>> \n");
  result = develop();
  while (1) {
    for (i = 0; i < 1000; i++) {
      printf("this is a test program : %d \n", i);
      sleep(1);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  xor    %eax,%eax
  call   <develop@plt>
  nopl   0x0(%rax)
L3:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x3e8,%ebx
  jne    L4
  jmp    L3
```

tool_calls: name: unpack_data
arguments: tag: D11
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string

tool: D11:  >>>>>start main function>>>>>> 

tool: D6: this is a test program : %d 


assistant: ```c
int main(void) {
  int i;
  int result;
  printf(" >>>>>start main function>>>>>> \n");
  result = develop();
  while (1) {
    for (i = 0; i < 1000; i++) {
      printf("this is a test program : %d \n", i);
      sleep(1);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string

tool: D8: %d


assistant: ```c
int main() {
  printf("%d\n", foo(3, 4));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %d


assistant: ```c
int main() {
  printf("%d\n", foo(3, 4));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
int main() {
  printf("%d\n", foo(3, 4));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <foo@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_infered: string

tool: D8: %d


assistant: ```c
int main() {
  printf("%d\n", foo(3, 4));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printMatrixt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L18:
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L33:
  cmpl   $0x9,-0x4(%rbp)
  jle    L15
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x9,-0x8(%rbp)
  jle    L18
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string

tool: D3:  %d 

tool: D19: 


assistant: ```c
void printMatrixt(int m[10][10]) {
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 10; ++j) {
      printf(" %d ", m[i][j]);
    }
    printf("\n\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printMatrixt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x28(%rdi),%rbp
  lea    0x1b8(%rdi),%r13
  lea    D10(%rip),%r12
  lea    D17(%rip),%r14
L14:
  lea    -0x28(%rbp),%rbx
L1:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L1
  mov    %r14,%rdi
  call   <puts@plt>
  add    $0x28,%rbp
  cmp    %r13,%rbp
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D10:  %d 

tool: D17: 


assistant: ```c
void printMatrixt(int m[10][10]) {
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 10; ++j) {
      printf(" %d ", m[i][j]);
    }
    printf("\n\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printMatrixt>:
  endbr64
  push   %r14
  lea    D5(%rip),%r14
  push   %r13
  lea    0x1b8(%rdi),%r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  lea    0x28(%rdi),%rbp
  push   %rbx
  nopl   (%rax)
L14:
  lea    -0x28(%rbp),%rbx
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L0
  mov    %r14,%rdi
  lea    0x28(%rbx),%rbp
  call   <puts@plt>
  cmp    %r13,%rbp
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string

tool: D5: 


tool: D13:  %d 

assistant: ```c
void printMatrixt(int m[10][10]) {
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 10; ++j) {
      printf(" %d ", m[i][j]);
    }
    printf("\n\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printMatrixt>:
  endbr64
  push   %r14
  lea    D11(%rip),%r14
  push   %r13
  lea    0x1b8(%rdi),%r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  lea    0x28(%rdi),%rbp
  push   %rbx
  nopl   (%rax)
L12:
  lea    -0x28(%rbp),%rbx
  nopl   0x0(%rax)
L18:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L18
  mov    %r14,%rdi
  lea    0x28(%rbx),%rbp
  call   <puts@plt>
  cmp    %r13,%rbp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string

tool: D11: 


tool: D16:  %d 

assistant: ```c
void printMatrixt(int m[10][10]) {
  for (int i = 0; i < 10; ++i) {
    for (int j = 0; j < 10; ++j) {
      printf(" %d ", m[i][j]);
    }
    printf("\n\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypt_luksDump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <_crypt_init@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L8
  mov    -0x14(%rbp),%eax
  jmp    L10
L8:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <crypt_dump@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <crypt_free@plt>
  mov    $0x0,%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: LUKS1

assistant: ```c
int crypt_luksDump(struct crypt_options *options) {
  struct crypt_device *cd = NULL;
  int r;
  r = _crypt_init(&cd, "LUKS1", options, 1, 0);
  if (r < 0)
    return r;
  r = crypt_dump(cd);
  crypt_free(cd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crypt_luksDump>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%r8d
  mov    $0x1,%ecx
  lea    D2(%rip),%rsi
  call   <_crypt_init@plt>
  test   %eax,%eax
  js     L3
  mov    (%rsp),%rdi
  call   <crypt_dump@plt>
  mov    (%rsp),%rdi
  call   <crypt_free@plt>
  mov    $0x0,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: LUKS1

assistant: ```c
int crypt_luksDump(struct crypt_options *options) {
  struct crypt_device *cd = NULL;
  int r;
  r = _crypt_init(&cd, "LUKS1", options, 1, 0);
  if (r < 0)
    return r;
  r = crypt_dump(cd);
  crypt_free(cd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crypt_luksDump>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D3(%rip),%rsi
  movq   $0x0,(%rsp)
  call   <_crypt_init@plt>
  test   %eax,%eax
  js     L2
  mov    (%rsp),%rdi
  call   <crypt_dump@plt>
  mov    (%rsp),%rdi
  call   <crypt_free@plt>
  xor    %eax,%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D3: LUKS1

assistant: ```c
int crypt_luksDump(struct crypt_options *options) {
  struct crypt_device *cd = NULL;
  int r;
  r = _crypt_init(&cd, "LUKS1", options, 1, 0);
  if (r < 0)
    return r;
  r = crypt_dump(cd);
  crypt_free(cd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crypt_luksDump>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  mov    $0x1,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D2(%rip),%rsi
  movq   $0x0,(%rsp)
  call   <_crypt_init@plt>
  test   %eax,%eax
  js     L5
  mov    (%rsp),%rdi
  call   <crypt_dump@plt>
  mov    (%rsp),%rdi
  call   <crypt_free@plt>
  xor    %eax,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: LUKS1

assistant: ```c
int crypt_luksDump(struct crypt_options *options) {
  struct crypt_device *cd = NULL;
  int r;
  r = _crypt_init(&cd, "LUKS1", options, 1, 0);
  if (r < 0)
    return r;
  r = crypt_dump(cd);
  crypt_free(cd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fz_softlight_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x7f,-0x18(%rbp)
  jg     L9
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  mov    $0xff,%edx
  sub    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    $0xff,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    $0xff,%eax
  sub    -0x14(%rbp),%eax
  sar    $0x7,%eax
  add    %ecx,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  jmp    L1
L9:
  cmpl   $0x3f,-0x14(%rbp)
  jg     L38
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  lea    -0xc(%rax),%edx
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  lea    0x4(%rax),%edx
  mov    -0x14(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L38:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  D6(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  lea    -0xff(%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sub    -0x14(%rbp),%eax
  sar    $0x7,%eax
  add    %ecx,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: byte[4]

tool: {"D6": [0x00,0x00,0x7f,0x43]}

assistant: ```c
int fz_softlight_byte(int bd, int s) {
  if (s < 128) {
    return bd - (((((((255 - (s << 1))) * ((bd) + ((bd) >> 7))) >> 8)) * ((255 - bd) + ((255 - bd) >> 7))) >> 8);
  } else {
    int dbd;
    if (bd < 64)
      dbd = (((((((bd << 4) - 12) * ((bd) + ((bd) >> 7))) >> 8) + 4) * ((bd) + ((bd) >> 7))) >> 8);
    else
      dbd = (int)sqrtf(255.0f * bd);
    return bd + (((((s << 1) - 255)) * (((dbd - bd)) + (((dbd - bd)) >> 7))) >> 8);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fz_softlight_byte>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x7f,%esi
  jg     L19
  mov    $0xff,%eax
  mov    %eax,%ecx
  sub    %edi,%ecx
  add    %ebp,%ebp
  sub    %ebp,%eax
  mov    %eax,%edx
  mov    %edi,%eax
  sar    $0x7,%eax
  add    %edi,%eax
  imul   %eax,%edx
  sar    $0x8,%edx
  mov    %ecx,%eax
  sar    $0x7,%eax
  add    %ecx,%eax
  imul   %eax,%edx
  sar    $0x8,%edx
  mov    %edi,%eax
  sub    %edx,%eax
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  cmp    $0x3f,%edi
  jg     L35
  mov    %edi,%edx
  sar    $0x7,%edx
  add    %edi,%edx
  mov    %edi,%eax
  shl    $0x4,%eax
  sub    $0xc,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  add    $0x4,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
L9:
  sub    %ebx,%eax
  lea    -0xff(%rbp,%rbp,1),%edx
  mov    %eax,%ecx
  sar    $0x7,%ecx
  add    %ecx,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  add    %ebx,%eax
  jmp    L29
L35:
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  mulss  D2(%rip),%xmm0
  call   <sqrtf@plt>
  jmp    L9
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x7f,0x43]}

assistant: ```c
int fz_softlight_byte(int bd, int s) {
  if (s < 128) {
    return bd - (((((((255 - (s << 1))) * ((bd) + ((bd) >> 7))) >> 8)) * ((255 - bd) + ((255 - bd) >> 7))) >> 8);
  } else {
    int dbd;
    if (bd < 64)
      dbd = (((((((bd << 4) - 12) * ((bd) + ((bd) >> 7))) >> 8) + 4) * ((bd) + ((bd) >> 7))) >> 8);
    else
      dbd = (int)sqrtf(255.0f * bd);
    return bd + (((((s << 1) - 255)) * (((dbd - bd)) + (((dbd - bd)) >> 7))) >> 8);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fz_softlight_byte>:
  endbr64
  push   %rbp
  lea    (%rsi,%rsi,1),%ebp
  sub    $0x10,%rsp
  cmp    $0x7f,%esi
  jg     L0
  mov    %edi,%edx
  mov    $0xff,%eax
  add    $0x10,%rsp
  sar    $0x7,%edx
  mov    %eax,%ecx
  sub    %ebp,%eax
  pop    %rbp
  add    %edi,%edx
  sub    %edi,%ecx
  imul   %eax,%edx
  mov    %ecx,%eax
  sar    $0x7,%eax
  add    %ecx,%eax
  sar    $0x8,%edx
  imul   %eax,%edx
  mov    %edi,%eax
  sar    $0x8,%edx
  sub    %edx,%eax
  ret
L0:
  cmp    $0x3f,%edi
  jg     L6
  mov    %edi,%edx
  mov    %edi,%eax
  sar    $0x7,%edx
  shl    $0x4,%eax
  add    %edi,%edx
  sub    $0xc,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  add    $0x4,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
L13:
  sub    %edi,%eax
  sub    $0xff,%ebp
  add    $0x10,%rsp
  mov    %eax,%edx
  sar    $0x7,%edx
  add    %edx,%eax
  imul   %ebp,%eax
  pop    %rbp
  sar    $0x8,%eax
  add    %edi,%eax
  ret
L6:
  pxor   %xmm0,%xmm0
  mov    %edi,0xc(%rsp)
  cvtsi2ss %edi,%xmm0
  mulss  D6(%rip),%xmm0
  call   <sqrtf@plt>
  mov    0xc(%rsp),%edi
  jmp    L13
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x7f,0x43]}

assistant: ```c
int fz_softlight_byte(int bd, int s) {
  if (s < 128) {
    return bd - (((((((255 - (s << 1))) * ((bd) + ((bd) >> 7))) >> 8)) * ((255 - bd) + ((255 - bd) >> 7))) >> 8);
  } else {
    int dbd;
    if (bd < 64)
      dbd = (((((((bd << 4) - 12) * ((bd) + ((bd) >> 7))) >> 8) + 4) * ((bd) + ((bd) >> 7))) >> 8);
    else
      dbd = (int)sqrtf(255.0f * bd);
    return bd + (((((s << 1) - 255)) * (((dbd - bd)) + (((dbd - bd)) >> 7))) >> 8);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fz_softlight_byte>:
  endbr64
  push   %rbp
  lea    (%rsi,%rsi,1),%ebp
  sub    $0x10,%rsp
  cmp    $0x7f,%esi
  jg     L10
  mov    %edi,%edx
  mov    $0xff,%eax
  add    $0x10,%rsp
  sar    $0x7,%edx
  mov    %eax,%ecx
  sub    %ebp,%eax
  pop    %rbp
  add    %edi,%edx
  sub    %edi,%ecx
  imul   %eax,%edx
  mov    %ecx,%eax
  sar    $0x7,%eax
  add    %ecx,%eax
  sar    $0x8,%edx
  imul   %eax,%edx
  mov    %edi,%eax
  sar    $0x8,%edx
  sub    %edx,%eax
  ret
L10:
  cmp    $0x3f,%edi
  jg     L7
  mov    %edi,%edx
  mov    %edi,%eax
  sar    $0x7,%edx
  shl    $0x4,%eax
  add    %edi,%edx
  sub    $0xc,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  add    $0x4,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
L17:
  sub    %edi,%eax
  sub    $0xff,%ebp
  add    $0x10,%rsp
  mov    %eax,%edx
  sar    $0x7,%edx
  add    %edx,%eax
  imul   %ebp,%eax
  pop    %rbp
  sar    $0x8,%eax
  add    %edi,%eax
  ret
L7:
  pxor   %xmm0,%xmm0
  mov    %edi,0xc(%rsp)
  cvtsi2ss %edi,%xmm0
  mulss  D3(%rip),%xmm0
  call   <sqrtf@plt>
  mov    0xc(%rsp),%edi
  jmp    L17
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: byte[4]

tool: {"D3": [0x00,0x00,0x7f,0x43]}

assistant: ```c
int fz_softlight_byte(int bd, int s) {
  if (s < 128) {
    return bd - (((((((255 - (s << 1))) * ((bd) + ((bd) >> 7))) >> 8)) * ((255 - bd) + ((255 - bd) >> 7))) >> 8);
  } else {
    int dbd;
    if (bd < 64)
      dbd = (((((((bd << 4) - 12) * ((bd) + ((bd) >> 7))) >> 8) + 4) * ((bd) + ((bd) >> 7))) >> 8);
    else
      dbd = (int)sqrtf(255.0f * bd);
    return bd + (((((s << 1) - 255)) * (((dbd - bd)) + (((dbd - bd)) >> 7))) >> 8);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RSA_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    $0x0,%eax
  call   <EVP_PKEY_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_set1_RSA@plt>
  test   %eax,%eax
  jne    L21
L9:
  mov    $0x0,%eax
  jmp    L6
L21:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <EVP_PKEY_print_private@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_free@plt>
  mov    -0xc(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int RSA_print(BIO *bp, const RSA *x, int off) {
  EVP_PKEY *pk;
  int ret;
  pk = EVP_PKEY_new();
  if (!pk || !EVP_PKEY_set1_RSA(pk, (RSA *)x))
    return 0;
  ret = EVP_PKEY_print_private(bp, pk, off, NULL);
  EVP_PKEY_free(pk);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RSA_print>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    $0x0,%eax
  call   <EVP_PKEY_new@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L21
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <EVP_PKEY_set1_RSA@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L22
L21:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    $0x0,%ecx
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <EVP_PKEY_print_private@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <EVP_PKEY_free@plt>
  jmp    L21
```

assistant: ```c
int RSA_print(BIO *bp, const RSA *x, int off) {
  EVP_PKEY *pk;
  int ret;
  pk = EVP_PKEY_new();
  if (!pk || !EVP_PKEY_set1_RSA(pk, (RSA *)x))
    return 0;
  ret = EVP_PKEY_print_private(bp, pk, off, NULL);
  EVP_PKEY_free(pk);
  return ret;
}
```