user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x6000(%rsp),%r11
L75:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L75
  sub    $0x930,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x6928(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
  jmp    L68
L132:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L26
L58:
  mov    (%r12,%rbx,4),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jge    L58
L117:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  add    $0x148,%r12
  cmp    %r13d,0xc(%rsp)
  jl     L136
L131:
  mov    $0x1,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L58
  jmp    L117
L82:
  mov    0x6928(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L172
  mov    $0x0,%eax
  add    $0x6930,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L93:
  cmp    $0x1,%r12d
  je     L29
  movl   $0x20,0x15c(%rsp)
  movslq %r12d,%r12
  imul   $0x148,%r12,%rax
  movl   $0x20,0x14(%rsp,%rax,1)
  movl   $0x20,0x158(%rsp,%r12,4)
  imul   $0x14c,%r12,%r12
  movl   $0x20,0x10(%rsp,%r12,1)
L136:
  mov    $0x0,%ebx
L68:
  lea    0xb(%rsp),%rcx
  lea    0xa(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x3,%eax
  jne    L82
  cmp    $0x1,%ebx
  jne    L132
L26:
  mov    0xc(%rsp),%r12d
  test   %r12d,%r12d
  jle    L93
  movzbl 0xb(%rsp),%r14d
  movzbl 0xa(%rsp),%r13d
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  add    $0x1,%eax
  cltq
  imul   $0x14c,%rax,%rdx
  lea    0x10(%rsp,%rdx,1),%rbx
  imul   $0xfffffffffffffeb8,%rax,%r10
  add    $0x1,%rax
  lea    (%rax,%rax,4),%rcx
  lea    (%rax,%rcx,8),%r8
  shl    $0x3,%r8
  lea    0x14(%rsp,%rdx,1),%r9
  mov    $0x1,%edi
  mov    $0x1,%r11d
L88:
  mov    %r11d,%edx
  shr    $0x1f,%edx
  lea    (%r11,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  mov    %r13d,%edx
  cmovne %r14d,%edx
  test   %edi,%edi
  jle    L164
  mov    %rbx,%rax
  mov    %rbx,%rcx
  movsbl %dl,%edx
L133:
  mov    %edx,(%rcx)
  mov    %edx,(%rax)
  lea    (%rax,%r10,1),%rsi
  mov    %edx,-0x148(%rsi,%r8,1)
  mov    %edx,-0x4(%rcx,%rdi,4)
  add    $0x148,%rcx
  add    $0x4,%rax
  cmp    %r9,%rax
  jne    L133
L164:
  add    $0x1,%r11d
  sub    $0x14c,%rbx
  add    $0x148,%r10
  add    $0x148,%r8
  add    $0x2,%rdi
  sub    $0x144,%r9
  cmp    %edi,%r12d
  jge    L88
  cmp    $0x1,%r12d
  je     L29
  movl   $0x20,0x15c(%rsp)
  movslq %r12d,%rax
  lea    (%rax,%rax,4),%rdx
  lea    (%rax,%rdx,8),%rdx
  movl   $0x20,0x14(%rsp,%rdx,8)
  movl   $0x20,0x158(%rsp,%rax,4)
  imul   $0x14c,%rax,%rax
  movl   $0x20,0x10(%rsp,%rax,1)
  test   %r12d,%r12d
  jle    L136
L29:
  lea    0x158(%rsp),%r12
  mov    $0x1,%r13d
  jmp    L131
L172:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %d %c %c

assistant: ```c
int main() {
  int outPutBuf[82][82], n, i, j, k, x, y, firstCase;
  char a, b, c;
  firstCase = 1;
  while (scanf("%d %c %c", &n, &a, &b) == 3) {
    if (firstCase == 1)
      firstCase = 0;
    else
      printf("\n");
    for (i = 1, j = 1; i <= n; i += 2, j++) {
      x = n / 2 + 1;
      y = x;
      x -= j - 1;
      y -= j - 1;
      c = j % 2 == 1 ? a : b;
      for (k = 1; k <= i; k++) {
        outPutBuf[x + k - 1][y] = c;
        outPutBuf[x][y + k - 1] = c;
        outPutBuf[x + i - 1][y + k - 1] = c;
        outPutBuf[x + k - 1][y + i - 1] = c;
      }
    }
    if (n != 1) {
      outPutBuf[1][1] = ' ';
      outPutBuf[n][1] = ' ';
      outPutBuf[1][n] = ' ';
      outPutBuf[n][n] = ' ';
    }
    for (i = 1; i <= n; i++) {
      for (j = 1; j <= n; j++) {
        printf("%c", outPutBuf[i][j]);
      }
      printf("\n");
    }
  }
  return 0;
}
```