user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L75:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L75
  sub    $0x928,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <fastRead@plt>
  mov    %rsp,%rcx
  mov    %eax,%ebx
  lea    0x1(%rax),%eax
  cltq
  lea    0xf(,%rax,4),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rcx
  and    $0xfffffffffffffff0,%rax
  cmp    %rcx,%rsp
  je     L126
L164:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L164
L126:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L197
L39:
  mov    %rsp,-0x3d0950(%rbp)
  mov    $0x1,%r12d
  test   %ebx,%ebx
  jle    L72
L195:
  xor    %eax,%eax
  call   <fastRead@plt>
  mov    -0x3d0950(%rbp),%rdi
  mov    %eax,(%rdi,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%ebx
  jge    L195
L72:
  xor    %eax,%eax
  call   <fastRead@plt>
  movl   $0x1,-0x3d0944(%rbp)
  mov    %eax,-0x3d0948(%rbp)
  test   %eax,%eax
  jle    L7
L0:
  xor    %eax,%eax
  call   <fastRead@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <fastRead@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <fastRead@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <fastRead@plt>
  mov    %eax,%r15d
  cmp    %eax,%r13d
  jg     L186
  mov    $0x1,%r14d
  nopl   0x0(%rax)
L104:
  mov    %r13d,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L14
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %r13d,-0x3d0940(%rbp,%rax,4)
L14:
  add    $0x1,%r13d
  cmp    %r13d,%r15d
  jge    L104
  cmp    $0x1,%r14d
  je     L186
  lea    -0x2(%r14),%eax
  movslq %ebx,%rdx
  xor    %r9d,%r9d
  mov    -0x3d0950(%rbp),%rdi
  lea    -0x3d0938(%rbp,%rax,4),%r14
  mov    %r12d,%eax
  lea    -0x3d093c(%rbp),%r11
  sub    %ebx,%eax
  lea    (%rdi,%rdx,4),%r15
  add    %rdx,%rax
  lea    0x4(%rdi,%rax,4),%r10
  nopl   0x0(%rax,%rax,1)
L52:
  cmp    %r12d,%ebx
  jg     L57
  mov    (%r11),%esi
  mov    %r15,%r8
  nopl   0x0(%rax,%rax,1)
L90:
  mov    (%r8),%ecx
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,%edi
  test   %edx,%edx
  jne    L177
  xchg   %ax,%ax
L129:
  mov    %ecx,%eax
  add    $0x1,%edi
  cltd
  idiv   %esi
  cltd
  mov    %eax,%ecx
  idiv   %esi
  test   %edx,%edx
  je     L129
  add    %edi,%r9d
L177:
  add    $0x4,%r8
  cmp    %r8,%r10
  jne    L90
L57:
  add    $0x4,%r11
  cmp    %r14,%r11
  jne    L52
L149:
  mov    %r9d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  addl   $0x1,-0x3d0944(%rbp)
  mov    -0x3d0944(%rbp),%eax
  cmp    %eax,-0x3d0948(%rbp)
  jge    L0
L7:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L186:
  xor    %r9d,%r9d
  jmp    L149
L197:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L39
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %d


assistant: ```c
int main() {
  int N, Q, i, j, k, sum, number, exponent;
  int l, r, x, y, b_len;
  N = fastRead();
  int a[N + 1];
  int b[1000001];
  for (i = 1; i <= N; i++) {
    a[i] = fastRead();
  }
  Q = fastRead();
  for (i = 1; i <= Q; i++) {
    l = fastRead();
    r = fastRead();
    x = fastRead();
    y = fastRead();
    sum = 0;
    b_len = 1;
    for (j = x; j <= y; j++) {
      if (isPrime(j))
        b[b_len++] = j;
    }
    for (j = 1; j < b_len; j++) {
      for (k = l; k <= r; k++) {
        number = a[k];
        exponent = 0;
        while (number % b[j] == 0) {
          exponent += 1;
          number /= b[j];
        }
        sum += exponent;
      }
    }
    printf("%d\n", sum);
  }
  return 0;
}
```