ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zjisti>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  lea    D28(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L72
  nopl   0x0(%rax)
L38:
  mov    %r12d,%edx
  lea    0x1(%rbx),%ebp
  sub    %ebx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ebx,%eax
  cmp    %eax,%ebx
  cmove  %ebp,%eax
L16:
  mov    %ebx,%r15d
  mov    %eax,%ebx
L72:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r15d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  cmp    %r12d,%ebp
  jg     L51
  je     L74
  mov    %ebx,%edi
  call   <vstup@plt>
  test   %rax,%rax
  jne    L38
  mov    %ebx,%eax
  sub    %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %ebx,%eax
  sar    %edx
  sub    %edx,%eax
  cmp    %eax,%ebx
  sete   %cl
  cmp    $0x4,%eax
  setle  %dl
  test   %dl,%cl
  je     L5
  cmp    %ebp,%ebx
  je     L5
  sub    $0x1,%eax
  mov    %ebx,%r12d
  jmp    L16
L5:
  mov    %ebx,%r12d
  jmp    L16
  nopl   (%rax)
L51:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L74:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D28
data_type: string
name: disassemble_data
arguments: data_label: D4
data_type: string
name: disassemble_data
arguments: data_label: D16
data_type: string

tool: D28:                                 %d cislo, %d min, %d max, %d odl


tool: D4:                                 -------------------------------------

tool: D16:   Heureka!

assistant: ```c
int zjisti(int cislo, int min, int max, int old) {
  int zjisteno = 0;
  printf("                                -------------------------------------\n");
  printf("                                %d cislo, %d min, %d max, %d odl\n", cislo, min, max, old);
  printf("                                -------------------------------------\n");
  if (min > max) {
    return 0;
  }
  if (min == max) {
    printf("  Heureka!\n");
    return cislo;
  }
  old = cislo;
  if (vstup(cislo)) {
    min = cislo + 1;
    cislo += (max - cislo) / 2;
    if (cislo == old) {
      cislo++;
    }
    zjisteno = zjisti(cislo, min, max, old);
  } else {
    max = cislo;
    cislo -= (cislo - min) / 2;
    if (cislo == old && cislo < 5 && min != max) {
      cislo--;
    }
    zjisteno = zjisti(cislo, min, max, old);
  }
  return zjisteno;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zjisti>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  jmp    L75
  nopl   0x0(%rax)
L77:
  mov    %r12d,%edx
  lea    0x1(%rbx),%ebp
  sub    %ebx,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  add    %ebx,%eax
  cmp    %eax,%ebx
  cmove  %ebp,%eax
L48:
  mov    %ebx,%r15d
  mov    %eax,%ebx
L75:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r15d,%r8d
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  cmp    %r12d,%ebp
  jg     L20
  je     L33
  mov    %ebx,%edi
  call   <vstup@plt>
  test   %rax,%rax
  jne    L77
  mov    %ebx,%eax
  sub    %ebp,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %ebx,%eax
  sar    %edx
  sub    %edx,%eax
  cmp    %eax,%ebx
  sete   %cl
  cmp    $0x4,%eax
  setle  %dl
  test   %dl,%cl
  je     L18
  cmp    %ebp,%ebx
  je     L18
  sub    $0x1,%eax
  mov    %ebx,%r12d
  jmp    L48
L18:
  mov    %ebx,%r12d
  jmp    L48
  nopl   (%rax)
L20:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L33:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D26
type_guessed: string

tool: D13:                                 %d cislo, %d min, %d max, %d odl


tool: D6:                                 -------------------------------------

tool: D26:   Heureka!

assistant: ```c
int zjisti(int cislo, int min, int max, int old) {
  int zjisteno = 0;
  printf("                                -------------------------------------\n");
  printf("                                %d cislo, %d min, %d max, %d odl\n", cislo, min, max, old);
  printf("                                -------------------------------------\n");
  if (min > max) {
    return 0;
  }
  if (min == max) {
    printf("  Heureka!\n");
    return cislo;
  }
  old = cislo;
  if (vstup(cislo)) {
    min = cislo + 1;
    cislo += (max - cislo) / 2;
    if (cislo == old) {
      cislo++;
    }
    zjisteno = zjisti(cislo, min, max, old);
  } else {
    max = cislo;
    cislo -= (cislo - min) / 2;
    if (cislo == old && cislo < 5 && min != max) {
      cislo--;
    }
    zjisteno = zjisti(cislo, min, max, old);
  }
  return zjisteno;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6:  %d %d %d 


assistant: ```c
main() {
  int i = 10;
  printf(" %d %d %d \n", ++i, i++, ++i);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%ecx
  mov    $0xb,%edx
  mov    $0xd,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7:  %d %d %d 


assistant: ```c
main() {
  int i = 10;
  printf(" %d %d %d \n", ++i, i++, ++i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%ecx
  mov    $0xb,%edx
  mov    $0xd,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D7:  %d %d %d 


assistant: ```c
main() {
  int i = 10;
  printf(" %d %d %d \n", ++i, i++, ++i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd,%ecx
  mov    $0xb,%edx
  mov    $0xd,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5:  %d %d %d 


assistant: ```c
main() {
  int i = 10;
  printf(" %d %d %d \n", ++i, i++, ++i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Quaternion_Conjugate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  D14(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  D14(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  D14(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: byte[4]

tool: {"D14": [0x00,0x00,0x00,0x80]}

assistant: ```c
void Quaternion_Conjugate(float *r, float *a) {
  r[0] = a[0];
  r[1] = -a[1];
  r[2] = -a[2];
  r[3] = -a[3];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Quaternion_Conjugate>:
  endbr64
  movss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  movss  D2(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x80]}

assistant: ```c
void Quaternion_Conjugate(float *r, float *a) {
  r[0] = a[0];
  r[1] = -a[1];
  r[2] = -a[2];
  r[3] = -a[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Quaternion_Conjugate>:
  endbr64
  movss  (%rsi),%xmm0
  movss  D2(%rip),%xmm1
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_infered: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x80]}

assistant: ```c
void Quaternion_Conjugate(float *r, float *a) {
  r[0] = a[0];
  r[1] = -a[1];
  r[2] = -a[2];
  r[3] = -a[3];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Quaternion_Conjugate>:
  endbr64
  movss  (%rsi),%xmm0
  movss  D3(%rip),%xmm1
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x80]}

assistant: ```c
void Quaternion_Conjugate(float *r, float *a) {
  r[0] = a[0];
  r[1] = -a[1];
  r[2] = -a[2];
  r[3] = -a[3];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__max_path_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    %r9d,-0x44(%rbp)
  mov    -0x40(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jne    L76
  movl   $0x0,-0x10(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L77
L34:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
L77:
  cmpl   $0x0,-0x14(%rbp)
  jne    L34
  mov    -0x10(%rbp),%eax
  jmp    L23
L76:
  movl   $0xffffffff,-0xc(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L71
L50:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L5
  mov    -0x40(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L5
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x40(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x44(%rbp),%r8d
  mov    -0x8(%rbp),%edi
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <__max_path_sum>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L63
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L63:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L5:
  addl   $0x1,-0x8(%rbp)
L71:
  mov    -0x8(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L50
  mov    -0xc(%rbp),%eax
L23:
  leave
  ret
```

assistant: ```c
int __max_path_sum(int **m, int *visited, int *path, int n, int s, int t) {
  if (s == t) {
    int i, cost;
    cost = 0;
    i = t;
    while (i != 0) {
      cost += m[path[i]][i];
      i = path[i];
    }
    return cost;
  } else {
    int max, tmp, i;
    max = -1;
    tmp = -1;
    for (i = 0; i < n; i++) {
      if (visited[i] == 0 && m[s][i] > 0) {
        visited[i] = 1;
        path[i] = s;
        tmp = __max_path_sum(m, visited, path, n, i, t);
        if (tmp > max) {
          max = tmp;
        }
        visited[i] = 0;
      }
    }
    return max;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__max_path_sum>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rdx,%r15
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x18(%rsp)
  mov    %r9d,%ebx
  cmp    %r9d,%r8d
  je     L45
  mov    %rsi,%r13
  mov    $0xffffffff,%r12d
  test   %ecx,%ecx
  jle    L69
  movslq 0x18(%rsp),%rax
  lea    (%rdi,%rax,8),%rax
  mov    0xc(%rsp),%esi
  mov    $0x0,%ebp
  mov    $0xffffffff,%r12d
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%r14
  mov    %r9d,0x1c(%rsp)
  mov    %rax,%rbx
  jmp    L58
L45:
  test   %r9d,%r9d
  je     L71
  mov    $0x0,%r12d
L22:
  movslq %ebx,%rax
  mov    (%r15,%rax,4),%ebx
  movslq %ebx,%rdx
  mov    (%r14,%rdx,8),%rdx
  add    (%rdx,%rax,4),%r12d
  test   %ebx,%ebx
  jne    L22
L69:
  mov    %r12d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  add    $0x1,%rbp
  cmp    %r14,%rbp
  je     L69
L58:
  mov    %ebp,%r8d
  cmpl   $0x0,0x0(%r13,%rbp,4)
  jne    L19
  mov    (%rbx),%rax
  cmpl   $0x0,(%rax,%rbp,4)
  jle    L19
  movl   $0x1,0x0(%r13,%rbp,4)
  mov    0x18(%rsp),%eax
  mov    %eax,(%r15,%rbp,4)
  mov    0x1c(%rsp),%r9d
  mov    0xc(%rsp),%ecx
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    0x10(%rsp),%rdi
  call   <__max_path_sum>
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  movl   $0x0,0x0(%r13,%rbp,4)
  jmp    L19
L71:
  mov    %r9d,%r12d
  jmp    L69
```

assistant: ```c
int __max_path_sum(int **m, int *visited, int *path, int n, int s, int t) {
  if (s == t) {
    int i, cost;
    cost = 0;
    i = t;
    while (i != 0) {
      cost += m[path[i]][i];
      i = path[i];
    }
    return cost;
  } else {
    int max, tmp, i;
    max = -1;
    tmp = -1;
    for (i = 0; i < n; i++) {
      if (visited[i] == 0 && m[s][i] > 0) {
        visited[i] = 1;
        path[i] = s;
        tmp = __max_path_sum(m, visited, path, n, i, t);
        if (tmp > max) {
          max = tmp;
        }
        visited[i] = 0;
      }
    }
    return max;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__max_path_sum>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmp    %r9d,%r8d
  je     L77
  mov    $0xffffffff,%r12d
  test   %ecx,%ecx
  jle    L34
  movslq %r8d,%rax
  mov    %r8d,0xc(%rsp)
  movslq %ecx,%r10
  mov    %rsi,%r13
  lea    (%rdi,%rax,8),%r11
  xor    %ebx,%ebx
  mov    $0xffffffff,%r12d
  mov    %r10,%rbp
  mov    %r11,%r14
L9:
  mov    0x0(%r13,%rbx,4),%edx
  test   %edx,%edx
  jne    L45
  mov    (%r14),%rax
  mov    (%rax,%rbx,4),%eax
  test   %eax,%eax
  jle    L45
  mov    0xc(%rsp),%eax
  mov    %ebx,%r8d
  mov    %r15,%rdx
  mov    %r13,%rsi
  movl   $0x1,0x0(%r13,%rbx,4)
  mov    %eax,(%r15,%rbx,4)
  mov    %r9d,0x1c(%rsp)
  mov    %ecx,0x18(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <__max_path_sum>
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  movl   $0x0,0x0(%r13,%rbx,4)
  cmp    %eax,%r12d
  mov    0x10(%rsp),%rdi
  cmovl  %eax,%r12d
L45:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L9
L34:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L77:
  xor    %r12d,%r12d
  test   %r8d,%r8d
  je     L34
  movslq %r8d,%r8
  nopl   0x0(%rax,%rax,1)
L41:
  lea    0x0(,%r8,4),%rdx
  movslq (%r15,%r8,4),%r8
  mov    (%r14,%r8,8),%rcx
  add    (%rcx,%rdx,1),%r12d
  test   %r8d,%r8d
  jne    L41
  jmp    L34
```

assistant: ```c
int __max_path_sum(int **m, int *visited, int *path, int n, int s, int t) {
  if (s == t) {
    int i, cost;
    cost = 0;
    i = t;
    while (i != 0) {
      cost += m[path[i]][i];
      i = path[i];
    }
    return cost;
  } else {
    int max, tmp, i;
    max = -1;
    tmp = -1;
    for (i = 0; i < n; i++) {
      if (visited[i] == 0 && m[s][i] > 0) {
        visited[i] = 1;
        path[i] = s;
        tmp = __max_path_sum(m, visited, path, n, i, t);
        if (tmp > max) {
          max = tmp;
        }
        visited[i] = 0;
      }
    }
    return max;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<__max_path_sum>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmp    %r9d,%r8d
  je     L72
  mov    $0xffffffff,%r12d
  test   %ecx,%ecx
  jle    L69
  movslq %r8d,%rax
  mov    %r8d,0xc(%rsp)
  movslq %ecx,%r10
  mov    %rsi,%r13
  lea    (%rdi,%rax,8),%r11
  xor    %ebx,%ebx
  mov    $0xffffffff,%r12d
  mov    %r10,%rbp
  mov    %r11,%r14
L7:
  mov    0x0(%r13,%rbx,4),%edx
  test   %edx,%edx
  jne    L23
  mov    (%r14),%rax
  mov    (%rax,%rbx,4),%eax
  test   %eax,%eax
  jle    L23
  mov    0xc(%rsp),%eax
  mov    %ebx,%r8d
  mov    %r15,%rdx
  mov    %r13,%rsi
  movl   $0x1,0x0(%r13,%rbx,4)
  mov    %eax,(%r15,%rbx,4)
  mov    %r9d,0x1c(%rsp)
  mov    %ecx,0x18(%rsp)
  mov    %rdi,0x10(%rsp)
  call   <__max_path_sum>
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  movl   $0x0,0x0(%r13,%rbx,4)
  cmp    %eax,%r12d
  mov    0x10(%rsp),%rdi
  cmovl  %eax,%r12d
L23:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L7
L69:
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  xor    %r12d,%r12d
  test   %r8d,%r8d
  je     L69
  movslq %r8d,%r8
  nopl   0x0(%rax,%rax,1)
L42:
  lea    0x0(,%r8,4),%rdx
  movslq (%r15,%r8,4),%r8
  mov    (%r14,%r8,8),%rcx
  add    (%rcx,%rdx,1),%r12d
  test   %r8d,%r8d
  jne    L42
  jmp    L69
```

assistant: ```c
int __max_path_sum(int **m, int *visited, int *path, int n, int s, int t) {
  if (s == t) {
    int i, cost;
    cost = 0;
    i = t;
    while (i != 0) {
      cost += m[path[i]][i];
      i = path[i];
    }
    return cost;
  } else {
    int max, tmp, i;
    max = -1;
    tmp = -1;
    for (i = 0; i < n; i++) {
      if (visited[i] == 0 && m[s][i] > 0) {
        visited[i] = 1;
        path[i] = s;
        tmp = __max_path_sum(m, visited, path, n, i, t);
        if (tmp > max) {
          max = tmp;
        }
        visited[i] = 0;
      }
    }
    return max;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lowercase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L0:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L35
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L35
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    0x20(%rax),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L35:
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void lowercase(char *str) {
  unsigned int i, len = strlen(str);
  for (i = 0; i < len; i++)
    if (str[i] >= 65 && str[i] <= 90)
      str[i] += 32;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lowercase>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L26
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  jmp    L25
L22:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L26
L25:
  movzbl (%rdx),%eax
  lea    -0x41(%rax),%ecx
  cmp    $0x19,%cl
  ja     L22
  add    $0x20,%eax
  mov    %al,(%rdx)
  jmp    L22
L26:
  pop    %rbx
  ret
```

assistant: ```c
void lowercase(char *str) {
  unsigned int i, len = strlen(str);
  for (i = 0; i < len; i++)
    if (str[i] >= 65 && str[i] <= 90)
      str[i] += 32;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lowercase>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L19
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax)
L10:
  movzbl (%rdi),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L12
  add    $0x20,%eax
  mov    %al,(%rdi)
L12:
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L10
L19:
  pop    %rbx
  ret
```

assistant: ```c
void lowercase(char *str) {
  unsigned int i, len = strlen(str);
  for (i = 0; i < len; i++)
    if (str[i] >= 65 && str[i] <= 90)
      str[i] += 32;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lowercase>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L13
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  nopl   0x0(%rax)
L9:
  movzbl (%rdi),%eax
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L3
  add    $0x20,%eax
  mov    %al,(%rdi)
L3:
  add    $0x1,%rdi
  cmp    %rdi,%rcx
  jne    L9
L13:
  pop    %rbx
  ret
```

assistant: ```c
void lowercase(char *str) {
  unsigned int i, len = strlen(str);
  for (i = 0; i < len; i++)
    if (str[i] >= 65 && str[i] <= 90)
      str[i] += 32;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x80,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <is_power_of_2@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L6
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L6:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string

tool: D8: is_power_of_2(%d) = true 


tool: D3: is_power_of_2(%d) = False 


assistant: ```c
int main() {
  unsigned int x = 128;
  unsigned int y = 2;
  int q = is_power_of_2(x, y);
  if (q == 1) {
    printf("is_power_of_2(%d) = true \n", x);
  } else {
    printf("is_power_of_2(%d) = False \n", x);
  }
  return 0;
}
```