ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<build_post>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rcx
  call   <build_post_bin@plt>
  test   %rbx,%rbx
  je     L4
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %rax,(%rbx)
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void build_post(uint8_t **post, size_t *post_len, char *newchar, size_t *content_len) {
  build_post_bin(post, post_len, (uint8_t *)newchar, strlen(newchar));
  if (content_len) {
    *content_len += strlen(newchar);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  lea    -0xc8(%rbp),%rax
  mov    %rax,-0xb8(%rbp)
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <print@plt>
  leave
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  int *varg = (int *)(char *)(&format);
  return print(0, varg);
}
```
user: What is the c source code of the assembly code below:

```asm
<printf>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  mov    $0x0,%edi
  call   <print@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  int *varg = (int *)(char *)(&format);
  return print(0, varg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printf>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  xor    %edi,%edi
  call   <print@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  int *varg = (int *)(char *)(&format);
  return print(0, varg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rsi
  xor    %edi,%edi
  call   <print@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int printf(const char *format, ...) {
  int *varg = (int *)(char *)(&format);
  return print(0, varg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testComma@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  testComma();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testComma@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  testComma();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testComma@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  testComma();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testComma@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  testComma();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_118_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x1c(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x18(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  not    %eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_118_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_118_0_0>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%esi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %esi,%eax
  mov    %edi,%edx
  not    %edx
  and    %edx,%eax
  or     $0xff,%al
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_118_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xrop3_118_0_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  or     %esi,%eax
  not    %edx
  and    %edx,%eax
  or     $0xff,%al
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_118_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_118_0_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  mov    %edi,%edx
  or     %esi,%eax
  not    %edx
  and    %edx,%eax
  or     $0xff,%al
  xor    %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_118_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  unsigned stk4;
  stk4 = ~S;
  stk3 = T & stk4;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<so3_roty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  movsd  %xmm0,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x58(%rbp),%rsi
  lea    -0x60(%rbp),%rdi
  mov    -0x70(%rbp),%rax
  mov    $0x2a,%r8d
  lea    D23(%rip),%rdx
  mov    %rdx,%rcx
  lea    D15(%rip),%rdx
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <_fsincos@plt>
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0x60(%rbp),%xmm0
  movq   D20(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x60(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x50(%rbp),%rcx
  mov    -0x68(%rbp),%rax
  mov    $0x48,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type: string
name: retrieve_data
arguments: data_tag: D15
type: string
name: retrieve_data
arguments: data_tag: D20
type: byte[8]
name: retrieve_data
arguments: data_tag: D9
type: byte[8]

tool: D23: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h

tool: D15: so3_roty

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void so3_roty(double Ry[9], const double theta) {
  double s, c;
  _fsincos(theta, &s, &c, __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h", 42);
  const double data[] = {c, 0, -s, 0, 1, 0, s, 0, c};
  memcpy(Ry, data, 9 * sizeof(double));
}
```
user: What is the c source code of the assembly code below?

```asm
<so3_roty>:
  endbr64
  push   %rbx
  sub    $0x60,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x2a,%r8d
  lea    D36(%rip),%rcx
  lea    D34(%rip),%rdx
  mov    $0x1,%eax
  call   <_fsincos@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm2
  xorpd  D25(%rip),%xmm2
  movsd  %xmm2,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    D31(%rip),%rax
  mov    %rax,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movsd  %xmm1,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movsd  %xmm0,0x50(%rsp)
  movdqa 0x10(%rsp),%xmm3
  movups %xmm3,(%rbx)
  movdqa 0x20(%rsp),%xmm4
  movups %xmm4,0x10(%rbx)
  movdqa 0x30(%rsp),%xmm5
  movups %xmm5,0x20(%rbx)
  movdqa 0x40(%rsp),%xmm6
  movups %xmm6,0x30(%rbx)
  mov    0x50(%rsp),%rax
  mov    %rax,0x40(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x60,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D36
data_type: string
name: extract_symbolic_data
arguments: label: D34
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D31
data_type: byte[8]

tool: D36: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h

tool: D34: so3_roty

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void so3_roty(double Ry[9], const double theta) {
  double s, c;
  _fsincos(theta, &s, &c, __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h", 42);
  const double data[] = {c, 0, -s, 0, 1, 0, s, 0, c};
  memcpy(Ry, data, 9 * sizeof(double));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<so3_roty>:
  endbr64
  push   %rbx
  mov    $0x2a,%r8d
  mov    %rdi,%rbx
  lea    D8(%rip),%rcx
  lea    D10(%rip),%rdx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x1,%eax
  call   <_fsincos@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  (%rsp),%xmm1
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    D5(%rip),%rax
  movapd %xmm1,%xmm2
  movsd  %xmm0,0x50(%rsp)
  xorpd  D39(%rip),%xmm2
  mov    %rax,0x30(%rsp)
  mov    0x50(%rsp),%rax
  movq   $0x0,0x38(%rsp)
  movdqa 0x30(%rsp),%xmm5
  movq   $0x0,0x48(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movdqa 0x10(%rsp),%xmm3
  movsd  %xmm2,0x20(%rsp)
  movdqa 0x20(%rsp),%xmm4
  movsd  %xmm1,0x40(%rsp)
  movdqa 0x40(%rsp),%xmm6
  mov    %rax,0x40(%rbx)
  movups %xmm3,(%rbx)
  movups %xmm4,0x10(%rbx)
  movups %xmm5,0x20(%rbx)
  movups %xmm6,0x30(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x60,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D10
type: string
name: extract_symbolic_data
arguments: label: D5
type: byte[8]
name: extract_symbolic_data
arguments: label: D39
type: byte[16]

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h

tool: D10: so3_roty

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void so3_roty(double Ry[9], const double theta) {
  double s, c;
  _fsincos(theta, &s, &c, __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h", 42);
  const double data[] = {c, 0, -s, 0, 1, 0, s, 0, c};
  memcpy(Ry, data, 9 * sizeof(double));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<so3_roty>:
  endbr64
  push   %rbx
  mov    $0x2a,%r8d
  mov    %rdi,%rbx
  lea    D22(%rip),%rcx
  lea    D31(%rip),%rdx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x1,%eax
  call   <_fsincos@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  (%rsp),%xmm1
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    D0(%rip),%rax
  movapd %xmm1,%xmm2
  movsd  %xmm0,0x50(%rsp)
  xorpd  D16(%rip),%xmm2
  mov    %rax,0x30(%rsp)
  mov    0x50(%rsp),%rax
  movq   $0x0,0x38(%rsp)
  movdqa 0x30(%rsp),%xmm5
  movq   $0x0,0x48(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movdqa 0x10(%rsp),%xmm3
  movsd  %xmm2,0x20(%rsp)
  movdqa 0x20(%rsp),%xmm4
  movsd  %xmm1,0x40(%rsp)
  movdqa 0x40(%rsp),%xmm6
  mov    %rax,0x40(%rbx)
  movups %xmm3,(%rbx)
  movups %xmm4,0x10(%rbx)
  movups %xmm5,0x20(%rbx)
  movups %xmm6,0x30(%rbx)
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x60,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D31
data_type: string
name: disassemble_data
arguments: data_tag: D0
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D16
data_type: byte[16]

tool: D22: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h

tool: D31: so3_roty

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void so3_roty(double Ry[9], const double theta) {
  double s, c;
  _fsincos(theta, &s, &c, __func__, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/arpit15/OnlineCalibration/refs/heads/master/src/common/so3.h", 42);
  const double data[] = {c, 0, -s, 0, 1, 0, s, 0, c};
  memcpy(Ry, data, 9 * sizeof(double));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pos_in_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L14:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L28
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  jmp    L17
L28:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L14
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
unsigned int pos_in_mem(const unsigned char *haystack, const unsigned int haystack_size, const unsigned char *needle, const unsigned int needle_size) {
  unsigned int i;
  for (i = 0; i < haystack_size; i++)
    if (memcmp(&haystack[i], needle, needle_size) == 0)
      return (i + needle_size);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pos_in_mem>:
  endbr64
  test   %esi,%esi
  je     L27
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rdx,%r14
  mov    %ecx,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
L22:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %ebp,%edx
  mov    %r14,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L18
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L22
  mov    $0x0,%eax
  jmp    L33
L18:
  lea    0x0(%rbp,%rbx,1),%eax
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int pos_in_mem(const unsigned char *haystack, const unsigned int haystack_size, const unsigned char *needle, const unsigned int needle_size) {
  unsigned int i;
  for (i = 0; i < haystack_size; i++)
    if (memcmp(&haystack[i], needle, needle_size) == 0)
      return (i + needle_size);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pos_in_mem>:
  endbr64
  test   %esi,%esi
  je     L18
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   (%rax)
L6:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L14
L4:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %ebp,%edx
  mov    %r14,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L6
  add    $0x8,%rsp
  lea    0x0(%rbp,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int pos_in_mem(const unsigned char *haystack, const unsigned int haystack_size, const unsigned char *needle, const unsigned int needle_size) {
  unsigned int i;
  for (i = 0; i < haystack_size; i++)
    if (memcmp(&haystack[i], needle, needle_size) == 0)
      return (i + needle_size);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pos_in_mem>:
  endbr64
  test   %esi,%esi
  je     L39
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L36
  nopl   (%rax)
L25:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L4
L36:
  lea    0x0(%r13,%rbx,1),%rdi
  mov    %ebp,%edx
  mov    %r14,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L25
  add    $0x8,%rsp
  lea    0x0(%rbp,%rbx,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int pos_in_mem(const unsigned char *haystack, const unsigned int haystack_size, const unsigned char *needle, const unsigned int needle_size) {
  unsigned int i;
  for (i = 0; i < haystack_size; i++)
    if (memcmp(&haystack[i], needle, needle_size) == 0)
      return (i + needle_size);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <epoll_ctl@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void add_event(int epollfd, int fd, int state) {
  struct epoll_event ev;
  ev.events = state;
  ev.data.fd = fd;
  epoll_ctl(epollfd, EPOLL_CTL_ADD, fd, &ev);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_event>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edx,(%rsp)
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rcx
  mov    %esi,%edx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <epoll_ctl@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_event(int epollfd, int fd, int state) {
  struct epoll_event ev;
  ev.events = state;
  ev.data.fd = fd;
  epoll_ctl(epollfd, EPOLL_CTL_ADD, fd, &ev);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add_event>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %edx,(%rsp)
  mov    %esi,%edx
  mov    %esi,0x4(%rsp)
  mov    %rsp,%rcx
  mov    (%rax),%esi
  call   <epoll_ctl@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_event(int epollfd, int fd, int state) {
  struct epoll_event ev;
  ev.events = state;
  ev.data.fd = fd;
  epoll_ctl(epollfd, EPOLL_CTL_ADD, fd, &ev);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_event>:
  endbr64
  sub    $0x18,%rsp
  movd   %edx,%xmm0
  movd   %esi,%xmm1
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rcx
  movq   %xmm0,(%rsp)
  mov    (%rax),%esi
  call   <epoll_ctl@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_event(int epollfd, int fd, int state) {
  struct epoll_event ev;
  ev.events = state;
  ev.data.fd = fd;
  epoll_ctl(epollfd, EPOLL_CTL_ADD, fd, &ev);
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L9
L6:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rcx
  movabs $0x446f86562d9faee5,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  shr    %rax
  add    %rdx,%rax
  shr    $0x6,%rax
  mov    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rsi
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_key(char *key) {
  unsigned long hash = 5381;
  int c;
  while ((c = *key++) != 0) {
    hash = ((hash << 5) + hash) + c;
  }
  return hash % 101;
}
```