ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x19c6cdeb,(%rsp)
  movl   $0xdf4709f,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x4,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  je     L10
L24:
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    %rdi,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L25
L68:
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rdi,%rsi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L54
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L10:
  call   <abort@plt>
  jmp    L24
L25:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L68
L54:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int val1 = 432459243;
  int val2 = 234123423;
  if (memcmp(&val1, &val2, sizeof(int) / sizeof(char)) == 0) {
    abort();
  }
  if (memcmp(&val1, &val1, sizeof(int) / sizeof(char)) != 0) {
    abort();
  }
  if (memcmp(&val2, &val2, sizeof(int) / sizeof(char)) != 0) {
    abort();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rsp,%r12
  movl   $0x19c6cdeb,(%rsp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0xdf4709f,0x4(%rsp)
  call   <memcmp@plt>
  test   %rax,%rax
  je     L45
L33:
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L60
L53:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L41
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L45:
  call   <abort@plt>
  jmp    L33
L41:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L13
L60:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L53
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int val1 = 432459243;
  int val2 = 234123423;
  if (memcmp(&val1, &val2, sizeof(int) / sizeof(char)) == 0) {
    abort();
  }
  if (memcmp(&val1, &val1, sizeof(int) / sizeof(char)) != 0) {
    abort();
  }
  if (memcmp(&val2, &val2, sizeof(int) / sizeof(char)) != 0) {
    abort();
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edx
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rsp,%r12
  movl   $0x19c6cdeb,(%rsp)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movl   $0xdf4709f,0x4(%rsp)
  call   <memcmp@plt>
  test   %rax,%rax
  je     L9
L57:
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L7
L3:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L52
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <abort@plt>
  jmp    L57
L52:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L14
L7:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L3
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int val1 = 432459243;
  int val2 = 234123423;
  if (memcmp(&val1, &val2, sizeof(int) / sizeof(char)) == 0) {
    abort();
  }
  if (memcmp(&val1, &val1, sizeof(int) / sizeof(char)) != 0) {
    abort();
  }
  if (memcmp(&val2, &val2, sizeof(int) / sizeof(char)) != 0) {
    abort();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testQuarterround@plt>
  mov    $0x0,%eax
  call   <testChacha20@plt>
  mov    $0x0,%eax
  call   <testUniform@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  testQuarterround();
  testChacha20();
  testUniform();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testQuarterround@plt>
  mov    $0x0,%eax
  call   <testChacha20@plt>
  mov    $0x0,%eax
  call   <testUniform@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testQuarterround();
  testChacha20();
  testUniform();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testQuarterround@plt>
  xor    %eax,%eax
  call   <testChacha20@plt>
  xor    %eax,%eax
  call   <testUniform@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testQuarterround();
  testChacha20();
  testUniform();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testQuarterround@plt>
  xor    %eax,%eax
  call   <testChacha20@plt>
  xor    %eax,%eax
  call   <testUniform@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testQuarterround();
  testChacha20();
  testUniform();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <gmtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    0x14(%rax),%esi
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%r8d
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%edi
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x8,%rsp
  push   %rsi
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string
name: extract_symbolic_data
arguments: label: D11
type: string

tool: D1: ctime is %d


tool: D11: Now is %d,%d,%d %d : %d : %d


assistant: ```c
int main() {
  time_t ctime;
  struct tm *tm;
  ctime = time(NULL);
  tm = gmtime(&ctime);
  printf("ctime is %d\n", ctime);
  printf("Now is %d,%d,%d %d : %d : %d\n", tm->tm_year, tm->tm_mon, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <gmtime@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rbx),%r9d
  mov    0xc(%rbx),%r8d
  mov    0x8(%rbx),%ecx
  mov    0x4(%rbx),%edx
  sub    $0x8,%rsp
  mov    0x14(%rbx),%eax
  push   %rax
  mov    (%rbx),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x10,%rsp
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D19: ctime is %d


tool: D3: Now is %d,%d,%d %d : %d : %d


assistant: ```c
int main() {
  time_t ctime;
  struct tm *tm;
  ctime = time(NULL);
  tm = gmtime(&ctime);
  printf("ctime is %d\n", ctime);
  printf("Now is %d,%d,%d %d : %d : %d\n", tm->tm_year, tm->tm_mon, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rbx),%eax
  sub    $0x8,%rsp
  mov    0x4(%rbx),%edx
  mov    0x10(%rbx),%r9d
  mov    0xc(%rbx),%r8d
  lea    D13(%rip),%rdi
  mov    0x8(%rbx),%ecx
  push   %rax
  xor    %eax,%eax
  mov    (%rbx),%esi
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D13
datatype: string

tool: D3: ctime is %d


tool: D13: Now is %d,%d,%d %d : %d : %d


assistant: ```c
int main() {
  time_t ctime;
  struct tm *tm;
  ctime = time(NULL);
  tm = gmtime(&ctime);
  printf("ctime is %d\n", ctime);
  printf("Now is %d,%d,%d %d : %d : %d\n", tm->tm_year, tm->tm_mon, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <gmtime@plt>
  mov    0x4(%rsp),%esi
  lea    D6(%rip),%rdi
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rbx),%eax
  sub    $0x8,%rsp
  mov    0x4(%rbx),%edx
  mov    0x10(%rbx),%r9d
  mov    0xc(%rbx),%r8d
  lea    D0(%rip),%rdi
  mov    0x8(%rbx),%ecx
  push   %rax
  xor    %eax,%eax
  mov    (%rbx),%esi
  call   <printf@plt>
  pop    %rax
  pop    %rdx
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D6: ctime is %d


tool: D0: Now is %d,%d,%d %d : %d : %d


assistant: ```c
int main() {
  time_t ctime;
  struct tm *tm;
  ctime = time(NULL);
  tm = gmtime(&ctime);
  printf("ctime is %d\n", ctime);
  printf("Now is %d,%d,%d %d : %d : %d\n", tm->tm_year, tm->tm_mon, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0xa,%edx
  mov    $0x0,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <strtoll@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D7
type_guessed: string

tool: D10: 1234567890123456789x

tool: D7: %lld


assistant: ```c
int main(int argc, char **argv) {
  long long l;
  l = strtoll("1234567890123456789x", NULL, 10);
  printf("%lld\n", l);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edx
  mov    $0x0,%esi
  lea    D7(%rip),%rdi
  call   <strtoll@plt>
  mov    %rax,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string
name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D7: 1234567890123456789x

tool: D2: %lld


assistant: ```c
int main(int argc, char **argv) {
  long long l;
  l = strtoll("1234567890123456789x", NULL, 10);
  printf("%lld\n", l);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edx
  xor    %esi,%esi
  lea    D18(%rip),%rdi
  call   <strtoll@plt>
  lea    D17(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D18: 1234567890123456789x

tool: D17: %lld


assistant: ```c
int main(int argc, char **argv) {
  long long l;
  l = strtoll("1234567890123456789x", NULL, 10);
  printf("%lld\n", l);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edx
  xor    %esi,%esi
  lea    D9(%rip),%rdi
  call   <strtoll@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string

tool: D9: 1234567890123456789x

tool: D5: %lld


assistant: ```c
int main(int argc, char **argv) {
  long long l;
  l = strtoll("1234567890123456789x", NULL, 10);
  printf("%lld\n", l);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fun@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D5: %f


assistant: ```c
int main(int argc, char **argv) {
  int a = 1;
  printf("%f\n", fun(a));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %f


assistant: ```c
int main(int argc, char **argv) {
  int a = 1;
  printf("%f\n", fun(a));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: %f


assistant: ```c
int main(int argc, char **argv) {
  int a = 1;
  printf("%f\n", fun(a));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <fun@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: %f


assistant: ```c
int main(int argc, char **argv) {
  int a = 1;
  printf("%f\n", fun(a));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isSupported>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %eax,%eax
  jne    L12
  mov    $0x1,%eax
  jmp    L18
L12:
  mov    $0x0,%eax
L18:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: MAP

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "MAP"))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isSupported>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D0: MAP

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "MAP"))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<isSupported>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: MAP

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "MAP"))
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isSupported>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rsi
  call   <strcasecmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: MAP

assistant: ```c
int isSupported(char *type) {
  if (!strcasecmp(type, "MAP"))
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bit_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  and    $0x1f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  shr    $0x5,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%edi
  mov    %edi,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%ecx
  mov    %edi,%eax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  and    %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bit_clear(int *tbl, int l, unsigned int bit) {
  int b;
  b = bit % 32;
  bit = bit / 32;
  tbl[bit % l] &= ~(1 << b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bit_clear>:
  endbr64
  mov    %edx,%ecx
  mov    %edx,%eax
  shr    $0x5,%eax
  mov    $0x0,%edx
  div    %esi
  mov    %edx,%edx
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  and    %eax,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void bit_clear(int *tbl, int l, unsigned int bit) {
  int b;
  b = bit % 32;
  bit = bit / 32;
  tbl[bit % l] &= ~(1 << b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bit_clear>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  xor    %edx,%edx
  shr    $0x5,%eax
  div    %esi
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  mov    %edx,%edx
  and    %eax,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void bit_clear(int *tbl, int l, unsigned int bit) {
  int b;
  b = bit % 32;
  bit = bit / 32;
  tbl[bit % l] &= ~(1 << b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bit_clear>:
  endbr64
  mov    %edx,%eax
  mov    %edx,%ecx
  xor    %edx,%edx
  shr    $0x5,%eax
  div    %esi
  mov    $0xfffffffe,%eax
  rol    %cl,%eax
  mov    %edx,%edx
  and    %eax,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void bit_clear(int *tbl, int l, unsigned int bit) {
  int b;
  b = bit % 32;
  bit = bit / 32;
  tbl[bit % l] &= ~(1 << b);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L2
L16:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <least_pf@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string

tool: D19: %lld

tool: D22: %lld


assistant: ```c
int main() {
  long long int i, t, n;
  long long int j, k;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    j = least_pf(n);
    printf("%lld\n", j);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  je     L3
  lea    0x10(%rsp),%r12
  lea    D21(%rip),%rbp
  lea    D17(%rip),%rbx
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  call   <least_pf@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  jne    L2
L3:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D17
type: string

tool: D21: %lld

tool: D17: %lld


assistant: ```c
int main() {
  long long int i, t, n;
  long long int j, k;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    j = least_pf(n);
    printf("%lld\n", j);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  je     L22
  lea    0x10(%rsp),%r12
  lea    D18(%rip),%rbp
  nop
L19:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  call   <least_pf@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  jne    L19
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D18
type: string

tool: D2: %lld

tool: D18: %lld


assistant: ```c
int main() {
  long long int i, t, n;
  long long int j, k;
  scanf("%lld", &t);
  while (t--) {
    scanf("%lld", &n);
    j = least_pf(n);
    printf("%lld\n", j);
  }
  return 0;
}
```