ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L2
  movq   $0x65757274,0x8(%rsp)
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  movabs $0x65736c6166,%rax
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <removeDuplicateLetters@plt>
  mov    0x8(%rbx),%rdi
  movslq %eax,%r12
  xor    %eax,%eax
  call   <removeDuplicateLetters2@plt>
  mov    %r12,%rdi
  movslq %eax,%rbp
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  lea    (%rsp,%rax,8),%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L6
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string

tool: D5: %s	%s	Equal=%s


tool: D0: removeDuplicateLetters <string>

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("removeDuplicateLetters <string>\n");
    return 0;
  }
  char boolStr[][8] = {"false", "true"};
  char *r = removeDuplicateLetters(argv[1]);
  char *r2 = removeDuplicateLetters2(argv[1]);
  printf("%s\t%s\tEqual=%s\n", r, r2, boolStr[!strcmp(r, r2)]);
  free(r);
  free(r2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L12
  movdqa D22(%rip),%xmm0
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <removeDuplicateLetters@plt>
  mov    0x8(%rbx),%rdi
  movslq %eax,%r12
  xor    %eax,%eax
  call   <removeDuplicateLetters2@plt>
  mov    %r12,%rdi
  movslq %eax,%rbp
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    %rbp,%rdx
  mov    %r12,%rsi
  lea    D16(%rip),%rdi
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  lea    (%rsp,%rax,8),%rcx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  lea    D26(%rip),%rdi
  call   <puts@plt>
  jmp    L0
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D22
data_type: byte[16]
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string

tool: {"D22": [0x66,0x61,0x6c,0x73,0x65,0x00,0x00,0x00,0x74,0x72,0x75,0x65,0x00,0x00,0x00,0x00]}

tool: D16: %s	%s	Equal=%s


tool: D26: removeDuplicateLetters <string>

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("removeDuplicateLetters <string>\n");
    return 0;
  }
  char boolStr[][8] = {"false", "true"};
  char *r = removeDuplicateLetters(argv[1]);
  char *r2 = removeDuplicateLetters2(argv[1]);
  printf("%s\t%s\tEqual=%s\n", r, r2, boolStr[!strcmp(r, r2)]);
  free(r);
  free(r2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <regcomp@plt>
  test   %rax,%rax
  je     L18
  mov    $0x0,%eax
  jmp    L21
L18:
  mov    -0x18(%rbp),%rsi
  lea    -0x10(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <regexec@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <regfree@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L41
  mov    $0x0,%eax
  jmp    L21
L41:
  mov    $0x1,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int match(const char *source, const char *regex) {
  int status;
  regex_t re;
  if (regcomp(&re, regex, REG_EXTENDED | REG_NOSUB) != 0) {
    return 0;
  }
  status = regexec(&re, source, (size_t)0, NULL, 0);
  regfree(&re);
  if (status != 0) {
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<match>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  or     (%rax),%edx
  lea    0x4(%rsp),%rdi
  call   <regcomp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L5
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    0x4(%rsp),%rbp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <regexec@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <regfree@plt>
  test   %ebx,%ebx
  sete   %al
  movzbl %al,%eax
  jmp    L14
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match(const char *source, const char *regex) {
  int status;
  regex_t re;
  if (regcomp(&re, regex, REG_EXTENDED | REG_NOSUB) != 0) {
    return 0;
  }
  status = regexec(&re, source, (size_t)0, NULL, 0);
  regfree(&re);
  if (status != 0) {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<match>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D8(%rip),%rax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  or     (%rax),%edx
  call   <regcomp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L18
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <regexec@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <regfree@plt>
  xor    %eax,%eax
  test   %ebp,%ebp
  sete   %al
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match(const char *source, const char *regex) {
  int status;
  regex_t re;
  if (regcomp(&re, regex, REG_EXTENDED | REG_NOSUB) != 0) {
    return 0;
  }
  status = regexec(&re, source, (size_t)0, NULL, 0);
  regfree(&re);
  if (status != 0) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<match>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D16(%rip),%rax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  or     (%rax),%edx
  call   <regcomp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <regexec@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <regfree@plt>
  xor    %eax,%eax
  test   %ebp,%ebp
  sete   %al
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match(const char *source, const char *regex) {
  int status;
  regex_t re;
  if (regcomp(&re, regex, REG_EXTENDED | REG_NOSUB) != 0) {
    return 0;
  }
  status = regexec(&re, source, (size_t)0, NULL, 0);
  regfree(&re);
  if (status != 0) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stnline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void stnline(char *str) {
  int length;
  length = strlen(str);
  str[length - 1] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stnline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void stnline(char *str) {
  int length;
  length = strlen(str);
  str[length - 1] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<stnline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void stnline(char *str) {
  int length;
  length = strlen(str);
  str[length - 1] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<stnline>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void stnline(char *str) {
  int length;
  length = strlen(str);
  str[length - 1] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L15
L2:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L15:
  cmpl   $0x14,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
data_type: string

tool: D11: %d 

assistant: ```c
main() {
  int a = 0, b = 1, c, count = 2;
  printf("%d ", a);
  printf("%d ", b);
  while (count != 20) {
    c = a + b;
    count++;
    printf("%d ", c);
    a = b;
    b = c;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x12,%ebp
  mov    $0x1,%ebx
  mov    $0x0,%eax
  lea    D2(%rip),%r13
L0:
  mov    %ebx,%r12d
  add    %eax,%ebx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  sub    $0x1,%ebp
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
main() {
  int a = 0, b = 1, c, count = 2;
  printf("%d ", a);
  printf("%d ", b);
  while (count != 20) {
    c = a + b;
    count++;
    printf("%d ", c);
    a = b;
    b = c;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  xor    %esi,%esi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  mov    $0x12,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%r12d
  add    %eax,%ebx
  mov    %r13,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  sub    $0x1,%ebp
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: %d 

assistant: ```c
main() {
  int a = 0, b = 1, c, count = 2;
  printf("%d ", a);
  printf("%d ", b);
  while (count != 20) {
    c = a + b;
    count++;
    printf("%d ", c);
    a = b;
    b = c;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  xor    %esi,%esi
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  mov    $0x12,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%r12d
  add    %eax,%ebx
  mov    %r13,%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  sub    $0x1,%ebp
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
datatype: string

tool: D2: %d 

assistant: ```c
main() {
  int a = 0, b = 1, c, count = 2;
  printf("%d ", a);
  printf("%d ", b);
  while (count != 20) {
    c = a + b;
    count++;
    printf("%d ", c);
    a = b;
    b = c;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GPIODMATriggerDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x534,%rax
  mov    (%rax),%rsi
  movzbl -0xc(%rbp),%eax
  not    %eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    $0x534,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  and    %rcx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GPIODMATriggerDisable(unsigned long ulPort, unsigned char ucPins) {
  ;
  (*((volatile unsigned long *)(ulPort + 0x00000534))) &= (~ucPins);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GPIODMATriggerDisable>:
  endbr64
  mov    0x534(%rdi),%rax
  movzbl %sil,%esi
  not    %esi
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    %rsi,0x534(%rdi)
  ret
```

assistant: ```c
void GPIODMATriggerDisable(unsigned long ulPort, unsigned char ucPins) {
  ;
  (*((volatile unsigned long *)(ulPort + 0x00000534))) &= (~ucPins);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GPIODMATriggerDisable>:
  endbr64
  movzbl %sil,%esi
  mov    0x534(%rdi),%rax
  not    %esi
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    %rsi,0x534(%rdi)
  ret
```

assistant: ```c
void GPIODMATriggerDisable(unsigned long ulPort, unsigned char ucPins) {
  ;
  (*((volatile unsigned long *)(ulPort + 0x00000534))) &= (~ucPins);
}
```
user: What is the c source code of the assembly code below:

```asm
<GPIODMATriggerDisable>:
  endbr64
  movzbl %sil,%esi
  mov    0x534(%rdi),%rax
  not    %esi
  movslq %esi,%rsi
  and    %rax,%rsi
  mov    %rsi,0x534(%rdi)
  ret
```

assistant: ```c
void GPIODMATriggerDisable(unsigned long ulPort, unsigned char ucPins) {
  ;
  (*((volatile unsigned long *)(ulPort + 0x00000534))) &= (~ucPins);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L8:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memset(void *b, int c, size_t len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L13
  add    %rdi,%rdx
L3:
  add    $0x1,%rdi
  mov    %sil,-0x1(%rdi)
  cmp    %rdi,%rdx
  jne    L3
L13:
  ret
```

assistant: ```c
void memset(void *b, int c, size_t len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L9
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void memset(void *b, int c, size_t len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L5
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void memset(void *b, int c, size_t len) {
  char *bp = b;
  while (len--)
    *bp++ = (unsigned char)c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<randomInteger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  cmp    $0x4,%eax
  ja     L34
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0xff1,-0x4(%rbp)
  jmp    L32
  movl   $0xfe2,-0x4(%rbp)
  jmp    L32
  movl   $0xfd3,-0x4(%rbp)
  jmp    L32
  movl   $0xfc4,-0x4(%rbp)
  jmp    L32
  movl   $0xfb5,-0x4(%rbp)
  jmp    L32
L34:
  movl   $0xff1,-0x4(%rbp)
  nop
L32:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t randomInteger(const unsigned short *globalCount) {
  uint16_t retVal = 0;
  switch (*globalCount) {
  case 0:
    retVal = 0x0FF1;
    break;
  case 1:
    retVal = 0x0FE2;
    break;
  case 2:
    retVal = 0x0FD3;
    break;
  case 3:
    retVal = 0x0FC4;
    break;
  case 4:
    retVal = 0x0FB5;
    break;
  default:
    retVal = 0x0FF1;
    break;
  }
  return retVal;
}
```
user: What is the c source code of the assembly code below?

```asm
<randomInteger>:
  endbr64
  movzwl (%rdi),%edx
  cmp    $0x3,%dx
  je     L28
  ja     L10
  mov    $0xfe2,%eax
  cmp    $0x1,%dx
  je     L8
  cmp    $0x2,%dx
  mov    $0xff1,%eax
  mov    $0xfd3,%edx
  cmove  %edx,%eax
  ret
L10:
  cmp    $0x4,%dx
  mov    $0xff1,%eax
  mov    $0xfb5,%edx
  cmove  %edx,%eax
  ret
L28:
  mov    $0xfc4,%eax
L8:
  ret
```

assistant: ```c
uint16_t randomInteger(const unsigned short *globalCount) {
  uint16_t retVal = 0;
  switch (*globalCount) {
  case 0:
    retVal = 0x0FF1;
    break;
  case 1:
    retVal = 0x0FE2;
    break;
  case 2:
    retVal = 0x0FD3;
    break;
  case 3:
    retVal = 0x0FC4;
    break;
  case 4:
    retVal = 0x0FB5;
    break;
  default:
    retVal = 0x0FF1;
    break;
  }
  return retVal;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<randomInteger>:
  endbr64
  movzwl (%rdi),%eax
  mov    $0xff1,%r8d
  lea    -0x1(%rax),%edx
  cmp    $0x3,%dx
  ja     L4
  mov    %eax,%edx
  shl    $0x4,%edx
  sub    %edx,%eax
  lea    0xff1(%rax),%r8d
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint16_t randomInteger(const unsigned short *globalCount) {
  uint16_t retVal = 0;
  switch (*globalCount) {
  case 0:
    retVal = 0x0FF1;
    break;
  case 1:
    retVal = 0x0FE2;
    break;
  case 2:
    retVal = 0x0FD3;
    break;
  case 3:
    retVal = 0x0FC4;
    break;
  case 4:
    retVal = 0x0FB5;
    break;
  default:
    retVal = 0x0FF1;
    break;
  }
  return retVal;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<randomInteger>:
  endbr64
  movzwl (%rdi),%eax
  mov    $0xff1,%r8d
  lea    -0x1(%rax),%edx
  cmp    $0x3,%dx
  ja     L2
  mov    %eax,%edx
  shl    $0x4,%edx
  sub    %edx,%eax
  lea    0xff1(%rax),%r8d
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint16_t randomInteger(const unsigned short *globalCount) {
  uint16_t retVal = 0;
  switch (*globalCount) {
  case 0:
    retVal = 0x0FF1;
    break;
  case 1:
    retVal = 0x0FE2;
    break;
  case 2:
    retVal = 0x0FD3;
    break;
  case 3:
    retVal = 0x0FC4;
    break;
  case 4:
    retVal = 0x0FB5;
    break;
  default:
    retVal = 0x0FF1;
    break;
  }
  return retVal;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<intpow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L10
  negl   -0xc(%rbp)
  movsd  D7(%rip),%xmm0
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L10:
  movsd  D7(%rip),%xmm2
  movapd %xmm2,%xmm3
  jmp    L23
L24:
  movapd %xmm3,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movapd %xmm1,%xmm3
L23:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jg     L24
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: f64

tool: D7: 1

assistant: ```c
double intpow(double base, int power) {
  register double answer;
  if (power < 0) {
    power = -power;
    base = 1 / base;
  }
  answer = 1.;
  while (power-- > 0)
    answer *= base;
  return (answer);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<intpow>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  js     L35
  lea    -0x1(%rdi),%eax
  jle    L6
L18:
  movsd  D22(%rip),%xmm0
L26:
  mulsd  %xmm1,%xmm0
  mov    %eax,%edx
  sub    $0x1,%eax
  test   %edx,%edx
  jg     L26
  ret
L35:
  movsd  D22(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mov    %edi,%eax
  not    %eax
  jmp    L18
L6:
  movsd  D22(%rip),%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D22
type_infered: f64

tool: D22: 1

assistant: ```c
double intpow(double base, int power) {
  register double answer;
  if (power < 0) {
    power = -power;
    base = 1 / base;
  }
  answer = 1.;
  while (power-- > 0)
    answer *= base;
  return (answer);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<intpow>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  js     L43
  movsd  D1(%rip),%xmm0
  lea    -0x1(%rdi),%eax
  je     L0
  nopl   0x0(%rax)
L37:
  mulsd  %xmm1,%xmm0
  mov    %eax,%edx
  sub    $0x1,%eax
  test   %edx,%edx
  jg     L37
L13:
  ret
  xchg   %ax,%ax
L43:
  movsd  D1(%rip),%xmm0
  mov    %edi,%eax
  not    %eax
  movapd %xmm0,%xmm2
  mov    %eax,%edx
  sub    $0x1,%eax
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  test   %edx,%edx
  jg     L37
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: f64

tool: D1: 1

assistant: ```c
double intpow(double base, int power) {
  register double answer;
  if (power < 0) {
    power = -power;
    base = 1 / base;
  }
  answer = 1.;
  while (power-- > 0)
    answer *= base;
  return (answer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intpow>:
  endbr64
  movapd %xmm0,%xmm1
  test   %edi,%edi
  js     L27
  movsd  D16(%rip),%xmm0
  lea    -0x1(%rdi),%eax
  je     L23
  nopl   0x0(%rax)
L19:
  mulsd  %xmm1,%xmm0
  mov    %eax,%edx
  sub    $0x1,%eax
  test   %edx,%edx
  jg     L19
L42:
  ret
  xchg   %ax,%ax
L27:
  movsd  D16(%rip),%xmm0
  mov    %edi,%eax
  not    %eax
  movapd %xmm0,%xmm2
  mov    %eax,%edx
  sub    $0x1,%eax
  divsd  %xmm1,%xmm2
  movapd %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  test   %edx,%edx
  jg     L19
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L23:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: f64

tool: D16: 1

assistant: ```c
double intpow(double base, int power) {
  register double answer;
  if (power < 0) {
    power = -power;
    base = 1 / base;
  }
  answer = 1.;
  while (power-- > 0)
    answer *= base;
  return (answer);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L13:
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L13
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L13
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int len(double *list) {
  int i = 0;
  for (; list[i] != 0; i++)
    ;
  return i + 1;
}
```