ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<BsplnWght2>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdi,%xmm1
  subsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  andpd  D38(%rip),%xmm1
  movsd  D25(%rip),%xmm2
  comisd %xmm1,%xmm2
  ja     L24
  movsd  D32(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L3
  pxor   %xmm1,%xmm1
L7:
  movapd %xmm1,%xmm0
  ret
L24:
  mulsd  %xmm0,%xmm0
  movsd  D17(%rip),%xmm1
  subsd  %xmm0,%xmm1
  jmp    L7
L3:
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  mulsd  D25(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: label: D38
data_type: qword[2]
name: extract_symbolic_data
arguments: label: D25
data_type: f64
name: extract_symbolic_data
arguments: label: D32
data_type: f64
name: extract_symbolic_data
arguments: label: D17
data_type: f64

tool: {"D38": [0x7fffffffffffffff,0x0000000000000000]}

tool: D25: 0.5

tool: D32: 1.5

tool: D17: 0.75

assistant: ```c
double BsplnWght2(long i, double x) {
  x = fabs(x - (double)i);
  if (x < 0.5)
    return (0.75 - x * x);
  if (x < 1.5) {
    x -= 1.5;
    return (0.5 * x * x);
  }
  return (0.0);
}
```
user: What is the c source code of the assembly code below?

```asm
<BsplnWght2>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdi,%xmm1
  subsd  %xmm1,%xmm0
  movsd  D18(%rip),%xmm1
  movapd %xmm0,%xmm2
  andpd  D21(%rip),%xmm2
  comisd %xmm2,%xmm1
  ja     L15
  movsd  D28(%rip),%xmm0
  comisd %xmm2,%xmm0
  ja     L19
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  subsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L15:
  mulsd  %xmm0,%xmm0
  movsd  D6(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: f64
name: unpack_data
arguments: label: D21
type_guessed: qword[2]
name: unpack_data
arguments: label: D28
type_guessed: f64
name: unpack_data
arguments: label: D6
type_guessed: f64

tool: D18: 0.5

tool: {"D21": [0x7fffffffffffffff,0x0000000000000000]}

tool: D28: 1.5

tool: D6: 0.75

assistant: ```c
double BsplnWght2(long i, double x) {
  x = fabs(x - (double)i);
  if (x < 0.5)
    return (0.75 - x * x);
  if (x < 1.5) {
    x -= 1.5;
    return (0.5 * x * x);
  }
  return (0.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<BsplnWght2>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %rdi,%xmm1
  subsd  %xmm1,%xmm0
  movsd  D16(%rip),%xmm1
  movapd %xmm0,%xmm2
  andpd  D3(%rip),%xmm2
  comisd %xmm2,%xmm1
  ja     L19
  movsd  D26(%rip),%xmm0
  comisd %xmm2,%xmm0
  ja     L0
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  subsd  %xmm0,%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  mulsd  %xmm0,%xmm0
  movsd  D17(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: f64
name: read_data
arguments: label: D3
datatype: qword[2]
name: read_data
arguments: label: D26
datatype: f64
name: read_data
arguments: label: D17
datatype: f64

tool: D16: 0.5

tool: {"D3": [0x7fffffffffffffff,0x0000000000000000]}

tool: D26: 1.5

tool: D17: 0.75

assistant: ```c
double BsplnWght2(long i, double x) {
  x = fabs(x - (double)i);
  if (x < 0.5)
    return (0.75 - x * x);
  if (x < 1.5) {
    x -= 1.5;
    return (0.5 * x * x);
  }
  return (0.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L6:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L11
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
L11:
  cmpl   $0x0,-0x4(%rbp)
  jns    L44
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L3
L44:
  cmpl   $0x0,-0x4(%rbp)
  jle    L3
  movl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(const char *dest, const char *src) {
  int ret = 0;
  while (!(ret = *(unsigned char *)src - *(unsigned char *)dest) && *dest) {
    ++src;
    ++dest;
  }
  if (ret < 0) {
    ret = -1;
  } else if (ret > 0) {
    ret = 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%eax
  movzbl %dl,%ecx
  sub    %ecx,%eax
  test   %dl,%dl
  je     L8
  test   %eax,%eax
  jne    L8
  mov    $0x1,%edx
L36:
  movzbl (%rdi,%rdx,1),%ecx
  movzbl (%rsi,%rdx,1),%eax
  movzbl %cl,%r8d
  sub    %r8d,%eax
  add    $0x1,%rdx
  test   %cl,%cl
  je     L8
  test   %eax,%eax
  je     L36
L8:
  test   %eax,%eax
  mov    $0x1,%edx
  cmovg  %edx,%eax
  test   %eax,%eax
  mov    $0xffffffff,%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *dest, const char *src) {
  int ret = 0;
  while (!(ret = *(unsigned char *)src - *(unsigned char *)dest) && *dest) {
    ++src;
    ++dest;
  }
  if (ret < 0) {
    ret = -1;
  } else if (ret > 0) {
    ret = 1;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%eax
  mov    $0x1,%ecx
  sub    %edx,%eax
  mov    %edx,%r8d
  mov    %eax,%edx
  je     L28
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L34:
  movzbl (%rdi,%rcx,1),%r9d
  movzbl (%rsi,%rcx,1),%edx
  add    $0x1,%rcx
  mov    %r9d,%r8d
  sub    %r9d,%edx
  jne    L22
L28:
  test   %r8b,%r8b
  jne    L34
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  setne  %al
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *dest, const char *src) {
  int ret = 0;
  while (!(ret = *(unsigned char *)src - *(unsigned char *)dest) && *dest) {
    ++src;
    ++dest;
  }
  if (ret < 0) {
    ret = -1;
  } else if (ret > 0) {
    ret = 1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%eax
  mov    $0x1,%ecx
  sub    %edx,%eax
  mov    %edx,%r8d
  mov    %eax,%edx
  je     L32
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L6:
  movzbl (%rdi,%rcx,1),%r9d
  movzbl (%rsi,%rcx,1),%edx
  add    $0x1,%rcx
  mov    %r9d,%r8d
  sub    %r9d,%edx
  jne    L26
L32:
  test   %r8b,%r8b
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  setne  %al
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int strcmp(const char *dest, const char *src) {
  int ret = 0;
  while (!(ret = *(unsigned char *)src - *(unsigned char *)dest) && *dest) {
    ++src;
    ++dest;
  }
  if (ret < 0) {
    ret = -1;
  } else if (ret > 0) {
    ret = 1;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ShiftRows>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl 0x1(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x5(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x5(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x9(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x9(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xd(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xd(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x2(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xa(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xa(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0x6(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x6(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xe(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xe(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  movzbl 0xf(%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0xf(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0xb(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0xb(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x7(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x7(%rax),%rdx
  mov    -0x18(%rbp),%rax
  movzbl 0x3(%rax),%eax
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ShiftRows(unsigned char *state) {
  unsigned char temp;
  temp = state[1 + 0 * 4];
  state[1 + 0 * 4] = state[1 + 1 * 4];
  state[1 + 1 * 4] = state[1 + 2 * 4];
  state[1 + 2 * 4] = state[1 + 3 * 4];
  state[1 + 3 * 4] = temp;
  temp = state[2 + 0 * 4];
  state[2 + 0 * 4] = state[2 + 2 * 4];
  state[2 + 2 * 4] = temp;
  temp = state[2 + 1 * 4];
  state[2 + 1 * 4] = state[2 + 3 * 4];
  state[2 + 3 * 4] = temp;
  temp = state[3 + 3 * 4];
  state[3 + 3 * 4] = state[3 + 2 * 4];
  state[3 + 2 * 4] = state[3 + 1 * 4];
  state[3 + 1 * 4] = state[3 + 0 * 4];
  state[3 + 0 * 4] = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ShiftRows>:
  endbr64
  movzbl 0x1(%rdi),%eax
  movzbl 0x5(%rdi),%edx
  mov    %dl,0x1(%rdi)
  movzbl 0x9(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0xd(%rdi),%edx
  mov    %dl,0x9(%rdi)
  mov    %al,0xd(%rdi)
  movzbl 0x2(%rdi),%eax
  movzbl 0xa(%rdi),%edx
  mov    %dl,0x2(%rdi)
  mov    %al,0xa(%rdi)
  movzbl 0x6(%rdi),%eax
  movzbl 0xe(%rdi),%edx
  mov    %dl,0x6(%rdi)
  mov    %al,0xe(%rdi)
  movzbl 0xf(%rdi),%eax
  movzbl 0xb(%rdi),%edx
  mov    %dl,0xf(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %dl,0xb(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %dl,0x7(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void ShiftRows(unsigned char *state) {
  unsigned char temp;
  temp = state[1 + 0 * 4];
  state[1 + 0 * 4] = state[1 + 1 * 4];
  state[1 + 1 * 4] = state[1 + 2 * 4];
  state[1 + 2 * 4] = state[1 + 3 * 4];
  state[1 + 3 * 4] = temp;
  temp = state[2 + 0 * 4];
  state[2 + 0 * 4] = state[2 + 2 * 4];
  state[2 + 2 * 4] = temp;
  temp = state[2 + 1 * 4];
  state[2 + 1 * 4] = state[2 + 3 * 4];
  state[2 + 3 * 4] = temp;
  temp = state[3 + 3 * 4];
  state[3 + 3 * 4] = state[3 + 2 * 4];
  state[3 + 2 * 4] = state[3 + 1 * 4];
  state[3 + 1 * 4] = state[3 + 0 * 4];
  state[3 + 0 * 4] = temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ShiftRows>:
  endbr64
  movzbl 0x5(%rdi),%edx
  movzbl 0x1(%rdi),%eax
  mov    %dl,0x1(%rdi)
  movzbl 0x9(%rdi),%edx
  mov    %dl,0x5(%rdi)
  movzbl 0xd(%rdi),%edx
  mov    %al,0xd(%rdi)
  movzbl 0x2(%rdi),%eax
  mov    %dl,0x9(%rdi)
  movzbl 0xa(%rdi),%edx
  mov    %al,0xa(%rdi)
  movzbl 0x6(%rdi),%eax
  mov    %dl,0x2(%rdi)
  movzbl 0xe(%rdi),%edx
  mov    %al,0xe(%rdi)
  movzbl 0xf(%rdi),%eax
  mov    %dl,0x6(%rdi)
  movzbl 0xb(%rdi),%edx
  mov    %dl,0xf(%rdi)
  movzbl 0x7(%rdi),%edx
  mov    %dl,0xb(%rdi)
  movzbl 0x3(%rdi),%edx
  mov    %al,0x3(%rdi)
  mov    %dl,0x7(%rdi)
  ret
```

assistant: ```c
void ShiftRows(unsigned char *state) {
  unsigned char temp;
  temp = state[1 + 0 * 4];
  state[1 + 0 * 4] = state[1 + 1 * 4];
  state[1 + 1 * 4] = state[1 + 2 * 4];
  state[1 + 2 * 4] = state[1 + 3 * 4];
  state[1 + 3 * 4] = temp;
  temp = state[2 + 0 * 4];
  state[2 + 0 * 4] = state[2 + 2 * 4];
  state[2 + 2 * 4] = temp;
  temp = state[2 + 1 * 4];
  state[2 + 1 * 4] = state[2 + 3 * 4];
  state[2 + 3 * 4] = temp;
  temp = state[3 + 3 * 4];
  state[3 + 3 * 4] = state[3 + 2 * 4];
  state[3 + 2 * 4] = state[3 + 1 * 4];
  state[3 + 1 * 4] = state[3 + 0 * 4];
  state[3 + 0 * 4] = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<runcontext_capturevar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
const char *runcontext_capturevar(const char *restrict env_var, char *restrict *slot) {
  *slot = malloc(strlen(env_var) + 1);
  strcpy(*slot, env_var);
  return *slot;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<runcontext_capturevar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  mov    %rbp,%rsi
  call   <strcpy@plt>
  mov    (%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *runcontext_capturevar(const char *restrict env_var, char *restrict *slot) {
  *slot = malloc(strlen(env_var) + 1);
  strcpy(*slot, env_var);
  return *slot;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<runcontext_capturevar>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *runcontext_capturevar(const char *restrict env_var, char *restrict *slot) {
  *slot = malloc(strlen(env_var) + 1);
  strcpy(*slot, env_var);
  return *slot;
}
```
user: Translate the below assembly code into C programming language:

```asm
<runcontext_capturevar>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    (%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *runcontext_capturevar(const char *restrict env_var, char *restrict *slot) {
  *slot = malloc(strlen(env_var) + 1);
  strcpy(*slot, env_var);
  return *slot;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xf4240,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  and    $0x1,%eax
  test   %eax,%eax
  je     L16
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xe(%rbp)
  jmp    L16
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0xc(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L17
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xe(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: %s

assistant: ```c
main() {
  char *q, temp, temp2;
  int i;
  q = malloc(1000000);
  scanf("%s", q);
  i = 0;
  if (strlen(q) % 2 != 0) {
    temp2 = *(q + (strlen(q) - 1));
  }
  while (i < strlen(q)) {
    temp = *(q + i);
    *(q + i) = *(q + (i + 1));
    *(q + (i + 1)) = temp;
    i = i + 2;
  }
  *(q + (strlen(q) - 1)) = temp2;
  printf("%s", q);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xf4240,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   $0x1,%al
  jne    L7
L28:
  mov    $0x0,%ebx
  jmp    L3
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movzbl -0x1(%rbp,%rax,1),%r12d
  jmp    L28
L20:
  movzbl 0x0(%rbp,%rbx,1),%eax
  movzbl 0x1(%rbp,%rbx,1),%edx
  mov    %dl,0x0(%rbp,%rbx,1)
  mov    %al,0x1(%rbp,%rbx,1)
  add    $0x2,%rbx
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L20
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  mov    %r12b,-0x1(%rbp,%rax,1)
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: %s

assistant: ```c
main() {
  char *q, temp, temp2;
  int i;
  q = malloc(1000000);
  scanf("%s", q);
  i = 0;
  if (strlen(q) % 2 != 0) {
    temp2 = *(q + (strlen(q) - 1));
  }
  while (i < strlen(q)) {
    temp = *(q + i);
    *(q + i) = *(q + (i + 1));
    *(q + (i + 1)) = temp;
    i = i + 2;
  }
  *(q + (strlen(q) - 1)) = temp2;
  printf("%s", q);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xf4240,%edi
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   $0x1,%al
  jne    L17
L32:
  xor    %ebx,%ebx
  jmp    L11
  nopl   (%rax)
L9:
  movzbl 0x0(%rbp,%rbx,1),%eax
  movzbl 0x1(%rbp,%rbx,1),%edx
  mov    %al,0x1(%rbp,%rbx,1)
  mov    %dl,0x0(%rbp,%rbx,1)
  add    $0x2,%rbx
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  cltq
  mov    %r12b,-0x1(%rbp,%rax,1)
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movzbl -0x1(%rbp,%rax,1),%r12d
  jmp    L32
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: %s

assistant: ```c
main() {
  char *q, temp, temp2;
  int i;
  q = malloc(1000000);
  scanf("%s", q);
  i = 0;
  if (strlen(q) % 2 != 0) {
    temp2 = *(q + (strlen(q) - 1));
  }
  while (i < strlen(q)) {
    temp = *(q + i);
    *(q + i) = *(q + (i + 1));
    *(q + (i + 1)) = temp;
    i = i + 2;
  }
  *(q + (strlen(q) - 1)) = temp2;
  printf("%s", q);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xf4240,%edi
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   $0x1,%al
  jne    L23
L14:
  xor    %ebx,%ebx
  jmp    L7
  nopl   (%rax)
L28:
  movzbl 0x0(%rbp,%rbx,1),%eax
  movzbl 0x1(%rbp,%rbx,1),%edx
  mov    %al,0x1(%rbp,%rbx,1)
  mov    %dl,0x0(%rbp,%rbx,1)
  add    $0x2,%rbx
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L28
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  cltq
  mov    %r12b,-0x1(%rbp,%rax,1)
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  movzbl -0x1(%rbp,%rax,1),%r12d
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %s

assistant: ```c
main() {
  char *q, temp, temp2;
  int i;
  q = malloc(1000000);
  scanf("%s", q);
  i = 0;
  if (strlen(q) % 2 != 0) {
    temp2 = *(q + (strlen(q) - 1));
  }
  while (i < strlen(q)) {
    temp = *(q + i);
    *(q + i) = *(q + (i + 1));
    *(q + (i + 1)) = temp;
    i = i + 2;
  }
  *(q + (strlen(q) - 1)) = temp2;
  printf("%s", q);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <prt_not_mcn@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = strtol(argv[1], NULL, 10);
  prt_not_mcn(n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%edi
  call   <prt_not_mcn@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = strtol(argv[1], NULL, 10);
  prt_not_mcn(n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %eax,%edi
  call   <prt_not_mcn@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = strtol(argv[1], NULL, 10);
  prt_not_mcn(n);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %eax,%edi
  call   <prt_not_mcn@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = strtol(argv[1], NULL, 10);
  prt_not_mcn(n);
  return 0;
}
```