ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<executable>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int executable(char *filepath) {
  if (access(filepath, X_OK) != -1) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sort_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x1d000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0x4e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x7530,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x1d4d4(%rbp)
  jmp    L5
L33:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x1d4d4(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x1d4d0(%rbp,%rdx,4)
  addl   $0x1,-0x1d4d4(%rbp)
L5:
  cmpl   $0x752f,-0x1d4d4(%rbp)
  jle    L33
  lea    -0x1d4d0(%rbp),%rax
  mov    $0x7530,%esi
  mov    %rax,%rdi
  call   <bubble_sort@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
data_type: string

tool: D0: Bubble sorting array of %d elements


assistant: ```c
void sort_array() {
  printf("Bubble sorting array of %d elements\n", 30000);
  int data[30000], i;
  for (i = 0; i < 30000; ++i) {
    data[i] = rand();
  }
  bubble_sort(data, 30000);
}
```
user: What is the c source code of the assembly code below?

```asm
<sort_array>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x1d000(%rsp),%r11
L19:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L19
  sub    $0x4d8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d4c8(%rsp)
  xor    %eax,%eax
  mov    $0x7530,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  lea    0x1d4c0(%rsp),%rbp
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L3
  mov    %rsp,%rdi
  mov    $0x7530,%esi
  call   <bubble_sort@plt>
  mov    0x1d4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x1d4d8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: Bubble sorting array of %d elements


assistant: ```c
void sort_array() {
  printf("Bubble sorting array of %d elements\n", 30000);
  int data[30000], i;
  for (i = 0; i < 30000; ++i) {
    data[i] = rand();
  }
  bubble_sort(data, 30000);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1d000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0x4d0,%rsp
  mov    $0x7530,%esi
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1d4c8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1d4c0(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L27
  mov    $0x7530,%esi
  mov    %r12,%rdi
  call   <bubble_sort@plt>
  mov    0x1d4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1d4d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string

tool: D2: Bubble sorting array of %d elements


assistant: ```c
void sort_array() {
  printf("Bubble sorting array of %d elements\n", 30000);
  int data[30000], i;
  for (i = 0; i < 30000; ++i) {
    data[i] = rand();
  }
  bubble_sort(data, 30000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sort_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1d000(%rsp),%r11
L20:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L20
  sub    $0x4d0,%rsp
  mov    $0x7530,%esi
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1d4c8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1d4c0(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rbx
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L18
  mov    $0x7530,%esi
  mov    %r12,%rdi
  call   <bubble_sort@plt>
  mov    0x1d4c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x1d4d0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D1: Bubble sorting array of %d elements


assistant: ```c
void sort_array() {
  printf("Bubble sorting array of %d elements\n", 30000);
  int data[30000], i;
  for (i = 0; i < 30000; ++i) {
    data[i] = rand();
  }
  bubble_sort(data, 30000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_isspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jne    L81
  mov    $0x1,%eax
  jmp    L52
L81:
  cmpl   $0xb,-0x4(%rbp)
  je     L0
  cmpl   $0xc,-0x4(%rbp)
  je     L0
  cmpl   $0xd,-0x4(%rbp)
  jne    L82
L0:
  mov    $0x2,%eax
  jmp    L52
L82:
  cmpl   $0x9,-0x4(%rbp)
  je     L20
  cmpl   $0xa,-0x4(%rbp)
  jne    L57
L20:
  mov    $0x3,%eax
  jmp    L52
L57:
  mov    $0x0,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isspace(int c) {
  if (c == ' ')
    return (1);
  if (c == '\v' || c == '\f' || c == '\r')
    return (2);
  if (c == '\t' || c == '\n')
    return (3);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isspace>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x20,%edi
  je     L10
  lea    -0xb(%rdi),%edx
  mov    $0x2,%eax
  cmp    $0x2,%edx
  jbe    L10
  sub    $0x9,%edi
  cmp    $0x2,%edi
  sbb    %eax,%eax
  and    $0x3,%eax
L10:
  ret
```

assistant: ```c
int ft_isspace(int c) {
  if (c == ' ')
    return (1);
  if (c == '\v' || c == '\f' || c == '\r')
    return (2);
  if (c == '\t' || c == '\n')
    return (3);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_isspace>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x20,%edi
  je     L9
  lea    -0xb(%rdi),%edx
  mov    $0x2,%eax
  cmp    $0x2,%edx
  jbe    L9
  sub    $0x9,%edi
  cmp    $0x2,%edi
  sbb    %eax,%eax
  and    $0x3,%eax
L9:
  ret
```

assistant: ```c
int ft_isspace(int c) {
  if (c == ' ')
    return (1);
  if (c == '\v' || c == '\f' || c == '\r')
    return (2);
  if (c == '\t' || c == '\n')
    return (3);
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_isspace>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x20,%edi
  je     L19
  lea    -0xb(%rdi),%edx
  mov    $0x2,%eax
  cmp    $0x2,%edx
  jbe    L19
  sub    $0x9,%edi
  cmp    $0x2,%edi
  sbb    %eax,%eax
  and    $0x3,%eax
L19:
  ret
```

assistant: ```c
int ft_isspace(int c) {
  if (c == ' ')
    return (1);
  if (c == '\v' || c == '\f' || c == '\r')
    return (2);
  if (c == '\t' || c == '\n')
    return (3);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bcd_div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %edx,%r14d
  mov    %rcx,%rbx
  mov    %r9,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  cmpb   $0x31,(%rsi)
  je     L1
L90:
  mov    %r14d,%ecx
  mov    $0x0,%eax
  test   %r14d,%r14d
  jle    L109
L37:
  movzbl (%r15,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L37
L109:
  mov    $0x0,%r13d
  jmp    L50
L1:
  cmpb   $0x30,0x1(%rsi)
  jne    L90
  mov    $0xffffffff,%eax
  jmp    L13
L102:
  mov    %rbx,%rcx
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <bcd_sub@plt>
  add    $0x1,%r13d
L50:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <bcd_gt@plt>
  cmp    $0x1,%eax
  je     L102
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <bcd_eq@plt>
  cmp    $0x1,%eax
  je     L102
  mov    %rbx,%rdx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <bcd_encode@plt>
  movslq %r14d,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L104:
  cmp    %rdx,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L104
L31:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L21
  orq    $0x0,-0x8(%rsp,%rax,1)
L21:
  mov    %rsp,%rcx
  mov    %r14d,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <bcd_mul@plt>
  mov    -0x48(%rbp),%rcx
  mov    %r14d,%edx
  mov    %rsp,%rsi
  mov    %r15,%rdi
  call   <bcd_sub@plt>
  mov    $0x0,%eax
L13:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcd_div(char *s, char *t, int n, char *u, int m, char *v) {
  if ((t[0] - 48) == 1 && (t[1] - 48) == 0) {
    return -1;
  }
  int i;
  for (i = 0; i < n; i++) {
    u[i] = s[i];
  }
  int j;
  j = 0;
  while (bcd_gt(u, t) == 1 || bcd_eq(u, t) == 1) {
    bcd_sub(u, t, n, u);
    j++;
  }
  bcd_encode(j, n, u);
  char tmp[n];
  bcd_mul(t, u, n, tmp);
  bcd_sub(s, tmp, n, v);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bcd_div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %r9,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  cmpb   $0x31,(%rsi)
  je     L70
L18:
  movslq %r13d,%rax
  mov    %rax,-0x48(%rbp)
  xor    %eax,%eax
  test   %r13d,%r13d
  jle    L54
  nopl   0x0(%rax,%rax,1)
L92:
  movzbl (%r14,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    -0x48(%rbp),%rax
  jne    L92
L54:
  xor    %r12d,%r12d
  jmp    L119
  nopw   0x0(%rax,%rax,1)
L107:
  mov    %rbx,%rcx
  mov    %r13d,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <bcd_sub@plt>
  add    $0x1,%r12d
L119:
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <bcd_gt@plt>
  cmp    $0x1,%eax
  je     L107
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <bcd_eq@plt>
  cmp    $0x1,%eax
  je     L107
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <bcd_encode@plt>
  mov    -0x48(%rbp),%rdx
  add    $0xf,%rdx
  mov    %rdx,%rcx
  mov    %rdx,%rax
  mov    %rsp,%rdx
  and    $0xfffffffffffff000,%rcx
  and    $0xfffffffffffffff0,%rax
  sub    %rcx,%rdx
  cmp    %rdx,%rsp
  je     L91
L1:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdx,%rsp
  jne    L1
L91:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L108
L32:
  mov    %rsp,%rcx
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <bcd_mul@plt>
  mov    -0x50(%rbp),%rcx
  mov    %r13d,%edx
  mov    %rsp,%rsi
  mov    %r14,%rdi
  call   <bcd_sub@plt>
  xor    %eax,%eax
L64:
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L83
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L70:
  cmpb   $0x30,0x1(%rsi)
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L64
  nopl   0x0(%rax)
L108:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L32
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bcd_div(char *s, char *t, int n, char *u, int m, char *v) {
  if ((t[0] - 48) == 1 && (t[1] - 48) == 0) {
    return -1;
  }
  int i;
  for (i = 0; i < n; i++) {
    u[i] = s[i];
  }
  int j;
  j = 0;
  while (bcd_gt(u, t) == 1 || bcd_eq(u, t) == 1) {
    bcd_sub(u, t, n, u);
    j++;
  }
  bcd_encode(j, n, u);
  char tmp[n];
  bcd_mul(t, u, n, tmp);
  bcd_sub(s, tmp, n, v);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cross_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cross_product(double a[3], double b[3], double c[3]) {
  c[0] = a[1] * b[2] - a[2] * b[1];
  c[1] = a[2] * b[0] - a[0] * b[2];
  c[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cross_product>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  mulsd  0x10(%rsi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  mulsd  0x8(%rsi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross_product(double a[3], double b[3], double c[3]) {
  c[0] = a[1] * b[2] - a[2] * b[1];
  c[1] = a[2] * b[0] - a[0] * b[2];
  c[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cross_product>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross_product(double a[3], double b[3], double c[3]) {
  c[0] = a[1] * b[2] - a[2] * b[1];
  c[1] = a[2] * b[0] - a[0] * b[2];
  c[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cross_product>:
  endbr64
  movsd  0x8(%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  (%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x10(%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm0
  mulsd  (%rsi),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void cross_product(double a[3], double b[3], double c[3]) {
  c[0] = a[1] * b[2] - a[2] * b[1];
  c[1] = a[2] * b[0] - a[0] * b[2];
  c[2] = a[0] * b[1] - a[1] * b[0];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_ebml_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <ebml_int_size@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x2c(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    $0x8,%eax
  sub    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %esi,%eax
  movzbl %al,%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  subq   $0x1,-0x10(%rbp)
  jmp    L6
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  subq   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_ebml_int(FILE *file, uint64_t i) {
  int size = ebml_int_size(i);
  unsigned char *p_first = (char *)&i;
  unsigned char *p_current = p_first + (size - 1);
  fputc(*p_current | 1 << (8 - size), file);
  for (p_current--; p_current >= p_first; p_current--) {
    fputc(*p_current, file);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_ebml_int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,%edi
  mov    %esi,0xc(%rsp)
  call   <ebml_int_size@plt>
  movslq %eax,%rdx
  lea    0xb(%rsp,%rdx,1),%rbx
  mov    $0x8,%ecx
  sub    %eax,%ecx
  mov    $0x1,%edi
  shl    %cl,%edi
  or     (%rbx),%dil
  movzbl %dil,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  sub    $0x1,%rbx
  lea    0xc(%rsp),%rax
  cmp    %rax,%rbx
  jb     L13
  lea    0xb(%rsp),%r12
L19:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L19
L13:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void write_ebml_int(FILE *file, uint64_t i) {
  int size = ebml_int_size(i);
  unsigned char *p_first = (char *)&i;
  unsigned char *p_current = p_first + (size - 1);
  fputc(*p_current | 1 << (8 - size), file);
  for (p_current--; p_current >= p_first; p_current--) {
    fputc(*p_current, file);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<write_ebml_int>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <ebml_int_size@plt>
  mov    $0x8,%ecx
  mov    $0x1,%edi
  mov    %rbp,%rsi
  movslq %eax,%rdx
  sub    %eax,%ecx
  lea    0xb(%rsp,%rdx,1),%rbx
  shl    %cl,%edi
  or     (%rbx),%dil
  sub    $0x1,%rbx
  movzbl %dil,%edi
  call   <fputc@plt>
  lea    0xc(%rsp),%rax
  cmp    %rax,%rbx
  jb     L1
  lea    0xb(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  sub    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r12,%rbx
  jne    L7
L1:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void write_ebml_int(FILE *file, uint64_t i) {
  int size = ebml_int_size(i);
  unsigned char *p_first = (char *)&i;
  unsigned char *p_current = p_first + (size - 1);
  fputc(*p_current | 1 << (8 - size), file);
  for (p_current--; p_current >= p_first; p_current--) {
    fputc(*p_current, file);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_ebml_int>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,0xc(%rsp)
  call   <ebml_int_size@plt>
  mov    $0x8,%ecx
  mov    $0x1,%edi
  mov    %rbp,%rsi
  movslq %eax,%rdx
  sub    %eax,%ecx
  lea    0xb(%rsp,%rdx,1),%rbx
  shl    %cl,%edi
  or     (%rbx),%dil
  sub    $0x1,%rbx
  movzbl %dil,%edi
  call   <fputc@plt>
  lea    0xc(%rsp),%rax
  cmp    %rax,%rbx
  jb     L6
  lea    0xb(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%rbx),%edi
  mov    %rbp,%rsi
  sub    $0x1,%rbx
  call   <fputc@plt>
  cmp    %r12,%rbx
  jne    L14
L6:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void write_ebml_int(FILE *file, uint64_t i) {
  int size = ebml_int_size(i);
  unsigned char *p_first = (char *)&i;
  unsigned char *p_current = p_first + (size - 1);
  fputc(*p_current | 1 << (8 - size), file);
  for (p_current--; p_current >= p_first; p_current--) {
    fputc(*p_current, file);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L62:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L56
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L27
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  jmp    L27
L56:
  nop
L27:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L41
  cmpl   $0x0,-0x4(%rbp)
  jns    L16
  mov    $0xffffffff,%eax
  jmp    L82
L16:
  mov    $0x0,%eax
  jmp    L82
L41:
  mov    $0x1,%eax
L82:
  pop    %rbp
  ret
```

assistant: ```c
int f_strcmp(const char *s1, const char *s2) {
  int ret = 0;
  int i;
  for (i = 0; s1[i] != '\0' && s2[i] != '\0'; i++)
    if (s1[i] != s2[i])
      break;
  ret = s1[i] - s2[i];
  return (ret > 0) ? 1 : (ret < 0) ? -1 : 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<f_strcmp>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L24
L20:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  jne    L24
  test   %cl,%cl
  je     L24
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L20
L24:
  movsbl %dl,%edx
  movsbl (%rsi,%rax,1),%eax
  sub    %eax,%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  test   %edx,%edx
  mov    $0x1,%edx
  cmovg  %edx,%eax
  ret
```

assistant: ```c
int f_strcmp(const char *s1, const char *s2) {
  int ret = 0;
  int i;
  for (i = 0; s1[i] != '\0' && s2[i] != '\0'; i++)
    if (s1[i] != s2[i])
      break;
  ret = s1[i] - s2[i];
  return (ret > 0) ? 1 : (ret < 0) ? -1 : 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f_strcmp>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L10
  jmp    L16
  nop
L60:
  test   %cl,%cl
  je     L58
  add    $0x1,%rax
  movsbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L45
L10:
  movsbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  je     L60
L58:
  xor    %eax,%eax
  sub    %ecx,%edx
  setne  %al
  neg    %eax
  test   %edx,%edx
  mov    $0x1,%edx
  cmovg  %edx,%eax
  ret
  nopl   0x0(%rax)
L45:
  movsbl (%rsi,%rax,1),%ecx
  xor    %edx,%edx
  jmp    L58
L16:
  movsbl (%rsi),%ecx
  xor    %edx,%edx
  jmp    L58
```

assistant: ```c
int f_strcmp(const char *s1, const char *s2) {
  int ret = 0;
  int i;
  for (i = 0; s1[i] != '\0' && s2[i] != '\0'; i++)
    if (s1[i] != s2[i])
      break;
  ret = s1[i] - s2[i];
  return (ret > 0) ? 1 : (ret < 0) ? -1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f_strcmp>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L1
  jmp    L30
  nop
L14:
  test   %cl,%cl
  je     L22
  add    $0x1,%rax
  movsbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L43
L1:
  movsbl (%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  je     L14
L22:
  xor    %eax,%eax
  sub    %ecx,%edx
  setne  %al
  neg    %eax
  test   %edx,%edx
  mov    $0x1,%edx
  cmovg  %edx,%eax
  ret
  nopl   0x0(%rax)
L43:
  movsbl (%rsi,%rax,1),%ecx
  xor    %edx,%edx
  jmp    L22
L30:
  movsbl (%rsi),%ecx
  xor    %edx,%edx
  jmp    L22
```

assistant: ```c
int f_strcmp(const char *s1, const char *s2) {
  int ret = 0;
  int i;
  for (i = 0; s1[i] != '\0' && s2[i] != '\0'; i++)
    if (s1[i] != s2[i])
      break;
  ret = s1[i] - s2[i];
  return (ret > 0) ? 1 : (ret < 0) ? -1 : 0;
}
```