ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D82(%rip),%r15
  push   %r14
  lea    D55(%rip),%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  lea    D92(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D78(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L113:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L123
L137:
  mov    (%rsp),%rax
  test   %rax,%rax
  js     L129
  cmp    $0x7,%rax
  jle    L3
  sub    $0x8,%rax
  cmp    $0x5,%rax
  ja     L132
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L113
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L113
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L113
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L113
  lea    D73(%rip),%rdi
  call   <printf@plt>
  jmp    L113
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L113
  nopw   0x0(%rax,%rax,1)
L129:
  test   $0x1,%al
  je     L3
L132:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L137
L123:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L113
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D82
type: string
name: unpack_data
arguments: label: D55
type: string
name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D78
type: string
name: unpack_data
arguments: label: D50
type: string
name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D73
type: string
name: unpack_data
arguments: label: D80
type: string

tool: D82: 6227020800


tool: D55: 479001600


tool: D2: Overflow!


tool: D78: %lld

tool: D50: 39916800


tool: D6: 3628800


tool: D18: 362880


tool: D73: 40320


tool: D80: Underflow!


assistant: ```c
int main() {
  long long n;
  while (scanf("%lld", &n) == 1) {
    if (n < 0 && n % 2 == 0)
      printf("Underflow!\n");
    else if (n < 0 && n % 2 != 0)
      printf("Overflow!\n");
    else if (n == 0 || n <= 7)
      printf("Underflow!\n");
    else if (n == 8)
      printf("40320\n");
    else if (n == 9)
      printf("362880\n");
    else if (n == 10)
      printf("3628800\n");
    else if (n == 11)
      printf("39916800\n");
    else if (n == 12)
      printf("479001600\n");
    else if (n == 13)
      printf("6227020800\n");
    else if (n > 13)
      printf("Overflow!\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%r15
  push   %r14
  lea    D33(%rip),%r14
  push   %r13
  lea    D70(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D74(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L19
L60:
  mov    (%rsp),%rax
  test   %rax,%rax
  js     L121
  cmp    $0x7,%rax
  jle    L131
  sub    $0x8,%rax
  cmp    $0x5,%rax
  ja     L72
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L44
  lea    D60(%rip),%rdi
  call   <printf@plt>
  jmp    L44
  lea    D89(%rip),%rdi
  call   <printf@plt>
  jmp    L44
  lea    D72(%rip),%rdi
  call   <printf@plt>
  jmp    L44
  lea    D91(%rip),%rdi
  call   <printf@plt>
  jmp    L44
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L121:
  test   $0x1,%al
  je     L131
L72:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L60
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L131:
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L44
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D33
datatype: string
name: unpack_data
arguments: label: D70
datatype: string
name: unpack_data
arguments: label: D74
datatype: string
name: unpack_data
arguments: label: D60
datatype: string
name: unpack_data
arguments: label: D89
datatype: string
name: unpack_data
arguments: label: D72
datatype: string
name: unpack_data
arguments: label: D91
datatype: string
name: unpack_data
arguments: label: D80
datatype: string

tool: D4: 6227020800


tool: D33: 479001600


tool: D70: Overflow!


tool: D74: %lld

tool: D60: 39916800


tool: D89: 3628800


tool: D72: 362880


tool: D91: 40320


tool: D80: Underflow!


assistant: ```c
int main() {
  long long n;
  while (scanf("%lld", &n) == 1) {
    if (n < 0 && n % 2 == 0)
      printf("Underflow!\n");
    else if (n < 0 && n % 2 != 0)
      printf("Overflow!\n");
    else if (n == 0 || n <= 7)
      printf("Underflow!\n");
    else if (n == 8)
      printf("40320\n");
    else if (n == 9)
      printf("362880\n");
    else if (n == 10)
      printf("3628800\n");
    else if (n == 11)
      printf("39916800\n");
    else if (n == 12)
      printf("479001600\n");
    else if (n == 13)
      printf("6227020800\n");
    else if (n > 13)
      printf("Overflow!\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gendep_getenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %rsi,-0x420(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x5f5045444e4547,%rax
  mov    $0x0,%edx
  mov    %rax,-0x410(%rbp)
  mov    %rdx,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x420(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    -0x418(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x418(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int gendep_getenv(char **dest, char *what) {
  char var[1024] = "GENDEP_";
  strcat(var, what);
  *dest = getenv(var);
  return !!(*dest);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gendep_getenv>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movabs $0x5f5045444e4547,%rax
  mov    $0x0,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <getenv@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  setne  %al
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gendep_getenv(char **dest, char *what) {
  char var[1024] = "GENDEP_";
  strcat(var, what);
  *dest = getenv(var);
  return !!(*dest);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gendep_getenv>:
  endbr64
  push   %rbp
  mov    $0x7e,%ecx
  xor    %edx,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  movabs $0x5f5045444e4547,%rax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  mov    %rdx,0x8(%rsp)
  mov    %rax,(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <getenv@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  setne  %al
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x418,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gendep_getenv(char **dest, char *what) {
  char var[1024] = "GENDEP_";
  strcat(var, what);
  *dest = getenv(var);
  return !!(*dest);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gendep_getenv>:
  endbr64
  push   %rbp
  mov    $0x7e,%ecx
  xor    %edx,%edx
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  movabs $0x5f5045444e4547,%rax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  mov    %rdx,0x8(%rsp)
  mov    %rax,(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <getenv@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  setne  %al
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x418,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gendep_getenv(char **dest, char *what) {
  char var[1024] = "GENDEP_";
  strcat(var, what);
  *dest = getenv(var);
  return !!(*dest);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitmap_snlistprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L39
L16:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <find_first_bit@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L56
L43:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_next_bit@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L24
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L56
L24:
  mov    -0x10(%rbp),%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <bsnl_emit@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L56:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L43
  mov    -0x10(%rbp),%eax
L39:
  leave
  ret
```

assistant: ```c
int bitmap_snlistprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int len = 0;
  int cur, rbot, rtop;
  if (buflen == 0)
    return 0;
  buf[0] = 0;
  rbot = cur = find_first_bit(maskp, nmaskbits);
  while (cur < nmaskbits) {
    rtop = cur;
    cur = find_next_bit(maskp, nmaskbits, cur + 1);
    if (cur >= nmaskbits || cur > rtop + 1) {
      len = bsnl_emit(buf, buflen, rbot, rtop, len);
      rbot = cur;
    }
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitmap_snlistprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  mov    $0x0,%r12d
  test   %esi,%esi
  jne    L57
L15:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  mov    %rdx,%r15
  mov    %ecx,%ebp
  movb   $0x0,(%rdi)
  mov    %ecx,%esi
  mov    %rdx,%rdi
  call   <find_first_bit@plt>
  mov    %eax,%r13d
  cmp    %eax,%ebp
  jle    L37
  mov    %eax,0x8(%rsp)
  jmp    L20
L32:
  mov    %r12d,%r8d
  mov    %r13d,%ecx
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    (%rsp),%rdi
  call   <bsnl_emit@plt>
  mov    %eax,%r12d
  cmp    %ebx,%ebp
  jle    L15
  mov    %ebx,0x8(%rsp)
L36:
  mov    %ebx,%r13d
L20:
  lea    0x1(%r13),%r14d
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  call   <find_next_bit@plt>
  mov    %eax,%ebx
  cmp    %eax,%r14d
  jl     L32
  cmp    %eax,%ebp
  jg     L36
  jmp    L32
L37:
  mov    $0x0,%r12d
  jmp    L15
```

assistant: ```c
int bitmap_snlistprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int len = 0;
  int cur, rbot, rtop;
  if (buflen == 0)
    return 0;
  buf[0] = 0;
  rbot = cur = find_first_bit(maskp, nmaskbits);
  while (cur < nmaskbits) {
    rtop = cur;
    cur = find_next_bit(maskp, nmaskbits, cur + 1);
    if (cur >= nmaskbits || cur > rtop + 1) {
      len = bsnl_emit(buf, buflen, rbot, rtop, len);
      rbot = cur;
    }
  }
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<bitmap_snlistprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jne    L16
L59:
  xor    %r14d,%r14d
L48:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  movb   $0x0,(%rdi)
  mov    %ecx,%esi
  mov    %rdx,%rdi
  mov    %rdx,%r12
  mov    %ecx,%ebp
  call   <find_first_bit@plt>
  mov    %eax,%r13d
  cmp    %eax,%ebp
  jle    L59
  mov    %eax,0x8(%rsp)
  xor    %r14d,%r14d
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L67:
  mov    %ebx,0x8(%rsp)
L12:
  mov    %ebx,%r13d
L33:
  lea    0x1(%r13),%r15d
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %r15d,%edx
  call   <find_next_bit@plt>
  mov    %eax,%ebx
  cmp    %eax,%r15d
  jl     L45
  cmp    %eax,%ebp
  jg     L12
L45:
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    (%rsp),%rdi
  call   <bsnl_emit@plt>
  mov    %eax,%r14d
  cmp    %ebx,%ebp
  jg     L67
  jmp    L48
```

assistant: ```c
int bitmap_snlistprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int len = 0;
  int cur, rbot, rtop;
  if (buflen == 0)
    return 0;
  buf[0] = 0;
  rbot = cur = find_first_bit(maskp, nmaskbits);
  while (cur < nmaskbits) {
    rtop = cur;
    cur = find_next_bit(maskp, nmaskbits, cur + 1);
    if (cur >= nmaskbits || cur > rtop + 1) {
      len = bsnl_emit(buf, buflen, rbot, rtop, len);
      rbot = cur;
    }
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitmap_snlistprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  jne    L22
L17:
  xor    %r14d,%r14d
L33:
  add    $0x18,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  movb   $0x0,(%rdi)
  mov    %ecx,%esi
  mov    %rdx,%rdi
  mov    %rdx,%r12
  mov    %ecx,%ebp
  call   <find_first_bit@plt>
  mov    %eax,%r13d
  cmp    %eax,%ebp
  jle    L17
  mov    %eax,0x8(%rsp)
  xor    %r14d,%r14d
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %ebx,0x8(%rsp)
L15:
  mov    %ebx,%r13d
L46:
  lea    0x1(%r13),%r15d
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %r15d,%edx
  call   <find_next_bit@plt>
  mov    %eax,%ebx
  cmp    %eax,%r15d
  jl     L25
  cmp    %eax,%ebp
  jg     L15
L25:
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    (%rsp),%rdi
  call   <bsnl_emit@plt>
  mov    %eax,%r14d
  cmp    %ebx,%ebp
  jg     L32
  jmp    L33
```

assistant: ```c
int bitmap_snlistprintf(char *buf, unsigned int buflen, const unsigned long *maskp, int nmaskbits) {
  int len = 0;
  int cur, rbot, rtop;
  if (buflen == 0)
    return 0;
  buf[0] = 0;
  rbot = cur = find_first_bit(maskp, nmaskbits);
  while (cur < nmaskbits) {
    rtop = cur;
    cur = find_next_bit(maskp, nmaskbits, cur + 1);
    if (cur >= nmaskbits || cur > rtop + 1) {
      len = bsnl_emit(buf, buflen, rbot, rtop, len);
      rbot = cur;
    }
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_runtime_h>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <read_runtime@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
  lea    D0(%rip),%rax
  jmp    L12
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  movq   %xmm0,%rax
  movsd  D21(%rip),%xmm0
  movq   %rax,%xmm1
  divsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D35(%rip),%rax
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string
name: disassemble_data
arguments: data_tag: D21
data_type: f64
name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: D0: NULL

tool: D21: 3600

tool: D19: %06.1f

assistant: ```c
const char *const read_runtime_h(void) {
  static char cache[20];
  const char *result;
  result = read_runtime();
  if (strcmp(result, "NULL") == 0)
    return "NULL";
  sprintf(cache, "%06.1f", atoi(result) / 3600.0);
  return cache;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_runtime_h>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <read_runtime@plt>
  mov    %rax,%rbx
  lea    D43(%rip),%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  lea    D43(%rip),%rax
  test   %rdx,%rdx
  jne    L19
L11:
  pop    %rbx
  ret
L19:
  mov    %rbx,%rdi
  call   <atoi@plt>
  divsd  D2(%rip),%xmm0
  lea    D31(%rip),%rsi
  lea    D16(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D43
type: string
name: disassemble_data
arguments: data_tag: D2
type: f64
name: disassemble_data
arguments: data_tag: D31
type: string

tool: D43: NULL

tool: D2: 3600

tool: D31: %06.1f

assistant: ```c
const char *const read_runtime_h(void) {
  static char cache[20];
  const char *result;
  result = read_runtime();
  if (strcmp(result, "NULL") == 0)
    return "NULL";
  sprintf(cache, "%06.1f", atoi(result) / 3600.0);
  return cache;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_runtime_h>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  lea    D5(%rip),%rbx
  sub    $0x8,%rsp
  call   <read_runtime@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  je     L3
  mov    %rbp,%rdi
  lea    D34(%rip),%rbx
  call   <atoi@plt>
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  divsd  D14(%rip),%xmm0
  call   <sprintf@plt>
  mov    %rbx,%rax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: f64

tool: D5: NULL

tool: D26: %06.1f

tool: D14: 3600

assistant: ```c
const char *const read_runtime_h(void) {
  static char cache[20];
  const char *result;
  result = read_runtime();
  if (strcmp(result, "NULL") == 0)
    return "NULL";
  sprintf(cache, "%06.1f", atoi(result) / 3600.0);
  return cache;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_runtime_h>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  lea    D10(%rip),%rbx
  sub    $0x8,%rsp
  call   <read_runtime@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  test   %r8,%r8
  je     L7
  mov    %rbp,%rdi
  lea    D14(%rip),%rbx
  call   <atoi@plt>
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  divsd  D25(%rip),%xmm0
  call   <sprintf@plt>
  mov    %rbx,%rax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: f64

tool: D10: NULL

tool: D9: %06.1f

tool: D25: 3600

assistant: ```c
const char *const read_runtime_h(void) {
  static char cache[20];
  const char *result;
  result = read_runtime();
  if (strcmp(result, "NULL") == 0)
    return "NULL";
  sprintf(cache, "%06.1f", atoi(result) / 3600.0);
  return cache;
}
```
user: What is the c source code of the assembly code below:

```asm
<basic_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <ol_lrc_new@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L46
L13:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ol_lrc_get_item@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D56(%rip),%rax
  mov    %rax,%rdx
  mov    $0x2b,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_item_get_id@plt>
  cmp    %eax,-0x18(%rbp)
  je     L27
  lea    D55(%rip),%rax
  mov    %rax,%rdx
  mov    $0x2c,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L27:
  cmpl   $0x0,-0x18(%rbp)
  jle    L28
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_item_get_time@plt>
  cmp    %eax,-0x14(%rbp)
  jle    L28
  lea    D58(%rip),%rax
  mov    %rax,%rdx
  mov    $0x2e,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_item_get_time@plt>
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x18(%rbp)
L46:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_item_count@plt>
  cmp    %eax,-0x18(%rbp)
  jl     L13
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ol_lrc_free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D56
type_infered: string
name: unpack_data
arguments: data_tag: D35
type_infered: string
name: unpack_data
arguments: data_tag: D55
type_infered: string
name: unpack_data
arguments: data_tag: D58
type_infered: string

tool: D6: lrc_basic.lrc

tool: D56: item != NULL

tool: D35: ERROR[%d]: EXPECT %s failed


tool: D55: ol_lrc_item_get_id (item) == i

tool: D58: ol_lrc_item_get_time (item) >= lasttime

assistant: ```c
void basic_test() {
  struct OlLrc *lrc = ol_lrc_new("lrc_basic.lrc");
  int i;
  int lasttime;
  for (i = 0; i < ol_lrc_item_count(lrc); i++) {
    const struct OlLrcItem *item = ol_lrc_get_item(lrc, i);
    if (!(item != NULL)) {
      printf("ERROR[%d]: EXPECT %s failed\n", 43, "item != NULL");
    };
    if (!(ol_lrc_item_get_id(item) == i)) {
      printf("ERROR[%d]: EXPECT %s failed\n", 44, "ol_lrc_item_get_id (item) == i");
    };
    if (i > 0)
      if (!(ol_lrc_item_get_time(item) >= lasttime)) {
        printf("ERROR[%d]: EXPECT %s failed\n", 46, "ol_lrc_item_get_time (item) >= lasttime");
      };
    lasttime = ol_lrc_item_get_time(item);
  }
  ol_lrc_free(lrc);
}
```