ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<heap_sort>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  push   %r12
  mov    %rdi,%r12
  cltq
  push   %rbp
  lea    (%rdi,%rax,4),%rbp
  push   %rbx
  mov    %esi,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <build_heap_tree@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  sub    $0x4,%rbp
  call   <swap@plt>
  sub    $0x1,%ebx
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void heap_sort(int *array, int n) {
  for (int i = 0; i < n; i++) {
    build_heap_tree(array, n - i);
    swap(&array[0], &array[n - 1 - i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shortenstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L17
  mov    -0x18(%rbp),%rax
  jmp    L10
L17:
  mov    -0x4(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x2b,(%rax)
  mov    -0x18(%rbp),%rax
L10:
  leave
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  str += (slen - len);
  str[0] = '+';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shortenstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  mov    %rbx,%rdx
  cmp    %ebp,%eax
  jle    L4
  sub    %ebp,%eax
  cltq
  lea    (%rbx,%rax,1),%rdx
  movb   $0x2b,(%rdx)
L4:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  str += (slen - len);
  str[0] = '+';
  return str;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shortenstr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  cmp    %ebp,%edx
  jle    L0
  sub    %ebp,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  movb   $0x2b,(%rax)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  str += (slen - len);
  str[0] = '+';
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shortenstr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  cmp    %ebp,%edx
  jle    L2
  sub    %ebp,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  movb   $0x2b,(%rax)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  str += (slen - len);
  str[0] = '+';
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sig_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D1: Interrupted by SIGALRM


tool: D5: Test PASSED: main blocked on barrier init


assistant: ```c
void sig_handler() {
  printf("Interrupted by SIGALRM\n");
  printf("Test PASSED: main blocked on barrier init\n");
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string

tool: D9: Interrupted by SIGALRM


tool: D13: Test PASSED: main blocked on barrier init


assistant: ```c
void sig_handler() {
  printf("Interrupted by SIGALRM\n");
  printf("Test PASSED: main blocked on barrier init\n");
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string

tool: D12: Interrupted by SIGALRM


tool: D3: Test PASSED: main blocked on barrier init


assistant: ```c
void sig_handler() {
  printf("Interrupted by SIGALRM\n");
  printf("Test PASSED: main blocked on barrier init\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sig_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D7: Interrupted by SIGALRM


tool: D6: Test PASSED: main blocked on barrier init


assistant: ```c
void sig_handler() {
  printf("Interrupted by SIGALRM\n");
  printf("Test PASSED: main blocked on barrier init\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<floats_mat44_inv_rotate_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <floats_mat44_inv@plt>
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <floats_mat44_rotate_vector@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void floats_mat44_inv_rotate_vector(const float M[16], const float in[3], float out[3]) {
  float T[16];
  floats_mat44_inv(M, T);
  floats_mat44_rotate_vector(T, in, out);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<floats_mat44_inv_rotate_vector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <floats_mat44_inv@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <floats_mat44_rotate_vector@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_mat44_inv_rotate_vector(const float M[16], const float in[3], float out[3]) {
  float T[16];
  floats_mat44_inv(M, T);
  floats_mat44_rotate_vector(T, in, out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<floats_mat44_inv_rotate_vector>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <floats_mat44_inv@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <floats_mat44_rotate_vector@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_mat44_inv_rotate_vector(const float M[16], const float in[3], float out[3]) {
  float T[16];
  floats_mat44_inv(M, T);
  floats_mat44_rotate_vector(T, in, out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<floats_mat44_inv_rotate_vector>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rsi
  call   <floats_mat44_inv@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <floats_mat44_rotate_vector@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_mat44_inv_rotate_vector(const float M[16], const float in[3], float out[3]) {
  float T[16];
  floats_mat44_inv(M, T);
  floats_mat44_rotate_vector(T, in, out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L23
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L8
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x14(%rbp)
L23:
  cmpl   $0x0,-0x14(%rbp)
  jg     L24
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int u, int v) {
  int temp;
  while (u > 0) {
    if (u < v) {
      temp = u;
      u = v;
      v = temp;
    }
    u = u % v;
  }
  return v;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jg     L35
L17:
  mov    %esi,%eax
  ret
L34:
  cltd
  idiv   %esi
  mov    %edx,%eax
  test   %edx,%edx
  jle    L17
L35:
  cmp    %esi,%eax
  jge    L34
  mov    %eax,%edx
  mov    %esi,%eax
  mov    %edx,%esi
  jmp    L34
```

assistant: ```c
int gcd(int u, int v) {
  int temp;
  while (u > 0) {
    if (u < v) {
      temp = u;
      u = v;
      v = temp;
    }
    u = u % v;
  }
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gcd>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  jle    L23
  nopl   0x0(%rax,%rax,1)
L12:
  cmp    %r8d,%edi
  jge    L26
  mov    %edi,%eax
  mov    %r8d,%edi
  mov    %eax,%r8d
L26:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  mov    %edx,%edi
  test   %edx,%edx
  jg     L12
L23:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int u, int v) {
  int temp;
  while (u > 0) {
    if (u < v) {
      temp = u;
      u = v;
      v = temp;
    }
    u = u % v;
  }
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  mov    %esi,%r8d
  test   %edi,%edi
  jle    L4
  nopl   0x0(%rax,%rax,1)
L29:
  cmp    %r8d,%edi
  jge    L17
  mov    %edi,%eax
  mov    %r8d,%edi
  mov    %eax,%r8d
L17:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  mov    %edx,%edi
  test   %edx,%edx
  jg     L29
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int u, int v) {
  int temp;
  while (u > 0) {
    if (u < v) {
      temp = u;
      u = v;
      v = temp;
    }
    u = u % v;
  }
  return v;
}
```
user: What is the c source code of the assembly code below:

```asm
<lookup_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L46:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L6
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L6
  mov    -0x4(%rbp),%eax
  jmp    L44
L6:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L46
  mov    $0xffffffff,%eax
L44:
  leave
  ret
```

assistant: ```c
int lookup_value(const char **names, int size, const char *name) {
  int value;
  for (value = 0; value < size; value++)
    if (names[value] && strcasecmp(names[value], name) == 0) {
      return value;
    }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lookup_value>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L47
  mov    %rdi,%r12
  mov    %rdx,%r14
  mov    %esi,%ebp
  mov    $0x0,%ebx
  jmp    L66
L45:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L19
L66:
  mov    %ebx,%r13d
  mov    (%r12,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L45
  mov    %r14,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L45
  jmp    L65
L19:
  mov    $0xffffffff,%r13d
L65:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L47:
  mov    $0xffffffff,%r13d
  jmp    L65
```

assistant: ```c
int lookup_value(const char **names, int size, const char *name) {
  int value;
  for (value = 0; value < size; value++)
    if (names[value] && strcasecmp(names[value], name) == 0) {
      return value;
    }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<lookup_value>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L25
  mov    %rdi,%r12
  mov    %rdx,%r14
  movslq %esi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    (%r12,%rbx,8),%rdi
  mov    %ebx,%r13d
  test   %rdi,%rdi
  je     L19
  mov    %r14,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L38
L19:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
L25:
  mov    $0xffffffff,%r13d
L38:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int lookup_value(const char **names, int size, const char *name) {
  int value;
  for (value = 0; value < size; value++)
    if (names[value] && strcasecmp(names[value], name) == 0) {
      return value;
    }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lookup_value>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L28
  mov    %rdi,%r12
  mov    %rdx,%r14
  movslq %esi,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L30:
  mov    (%r12,%rbx,8),%rdi
  mov    %ebx,%r13d
  test   %rdi,%rdi
  je     L36
  mov    %r14,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L11
L36:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L30
L28:
  mov    $0xffffffff,%r13d
L11:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int lookup_value(const char **names, int size, const char *name) {
  int value;
  for (value = 0; value < size; value++)
    if (names[value] && strcasecmp(names[value], name) == 0) {
      return value;
    }
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<updateAllParameters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initMotorStuff@plt>
  mov    $0x0,%eax
  call   <initPIDs@plt>
  mov    $0x0,%eax
  call   <initIMU@plt>
  mov    $0x0,%eax
  call   <initSensorOrientation@plt>
  mov    $0x0,%eax
  call   <initRCPins@plt>
  mov    $0x0,%eax
  call   <initRC@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void updateAllParameters() {
  initMotorStuff();
  initPIDs();
  initIMU();
  initSensorOrientation();
  initRCPins();
  initRC();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<updateAllParameters>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initMotorStuff@plt>
  mov    $0x0,%eax
  call   <initPIDs@plt>
  mov    $0x0,%eax
  call   <initIMU@plt>
  mov    $0x0,%eax
  call   <initSensorOrientation@plt>
  mov    $0x0,%eax
  call   <initRCPins@plt>
  mov    $0x0,%eax
  call   <initRC@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void updateAllParameters() {
  initMotorStuff();
  initPIDs();
  initIMU();
  initSensorOrientation();
  initRCPins();
  initRC();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<updateAllParameters>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initMotorStuff@plt>
  xor    %eax,%eax
  call   <initPIDs@plt>
  xor    %eax,%eax
  call   <initIMU@plt>
  xor    %eax,%eax
  call   <initSensorOrientation@plt>
  xor    %eax,%eax
  call   <initRCPins@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <initRC@plt>
```

assistant: ```c
void updateAllParameters() {
  initMotorStuff();
  initPIDs();
  initIMU();
  initSensorOrientation();
  initRCPins();
  initRC();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<updateAllParameters>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initMotorStuff@plt>
  xor    %eax,%eax
  call   <initPIDs@plt>
  xor    %eax,%eax
  call   <initIMU@plt>
  xor    %eax,%eax
  call   <initSensorOrientation@plt>
  xor    %eax,%eax
  call   <initRCPins@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <initRC@plt>
```

assistant: ```c
void updateAllParameters() {
  initMotorStuff();
  initPIDs();
  initIMU();
  initSensorOrientation();
  initRCPins();
  initRC();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: Usage: accelerometer [options] <device path>
  --debug         debug to stderr
  --help          print this help text



assistant: ```c
void help(void) {
  printf("Usage: accelerometer [options] <device path>\n"
         "  --debug         debug to stderr\n"
         "  --help          print this help text\n\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: Usage: accelerometer [options] <device path>
  --debug         debug to stderr
  --help          print this help text



assistant: ```c
void help(void) {
  printf("Usage: accelerometer [options] <device path>\n"
         "  --debug         debug to stderr\n"
         "  --help          print this help text\n\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<help>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: Usage: accelerometer [options] <device path>
  --debug         debug to stderr
  --help          print this help text



assistant: ```c
void help(void) {
  printf("Usage: accelerometer [options] <device path>\n"
         "  --debug         debug to stderr\n"
         "  --help          print this help text\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<help>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: Usage: accelerometer [options] <device path>
  --debug         debug to stderr
  --help          print this help text



assistant: ```c
void help(void) {
  printf("Usage: accelerometer [options] <device path>\n"
         "  --debug         debug to stderr\n"
         "  --help          print this help text\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <is_binary@plt>
  test   %eax,%eax
  je     L17
  movsbl -0x8(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <is_binary@plt>
  test   %eax,%eax
  je     L17
  mov    $0x1,%eax
  jmp    L13
L17:
  mov    $0x0,%eax
L13:
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  movzbl -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%al
  jne    L6
  mov    $0x30,%eax
  jmp    L1
L6:
  mov    $0x31,%eax
L1:
  leave
  ret
```

assistant: ```c
char xor (char a, char b) {
  assert(is_binary(a) && is_binary(b));
  if (a == b)
    return '0';
  else
    return '1';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xor>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <is_binary@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L12
L5:
  mov    $0x0,%eax
  call   <assert@plt>
  cmp    %bpl,%bl
  setne  %al
  add    $0x30,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  movsbl %bpl,%edi
  mov    $0x0,%eax
  call   <is_binary@plt>
  test   %eax,%eax
  setne  %dil
  movzbl %dil,%edi
  jmp    L5
```

assistant: ```c
char xor (char a, char b) {
  assert(is_binary(a) && is_binary(b));
  if (a == b)
    return '0';
  else
    return '1';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xor>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  sub    $0x8,%rsp
  call   <is_binary@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L10
L17:
  xor    %eax,%eax
  call   <assert@plt>
  cmp    %bpl,%bl
  setne  %al
  add    $0x8,%rsp
  add    $0x30,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  movsbl %bpl,%edi
  xor    %eax,%eax
  call   <is_binary@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setne  %dil
  jmp    L17
```

assistant: ```c
char xor (char a, char b) {
  assert(is_binary(a) && is_binary(b));
  if (a == b)
    return '0';
  else
    return '1';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xor>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  sub    $0x8,%rsp
  call   <is_binary@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L4
L19:
  xor    %eax,%eax
  call   <assert@plt>
  cmp    %bpl,%bl
  setne  %al
  add    $0x8,%rsp
  add    $0x30,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsbl %bpl,%edi
  xor    %eax,%eax
  call   <is_binary@plt>
  xor    %edi,%edi
  test   %eax,%eax
  setne  %dil
  jmp    L19
```

assistant: ```c
char xor (char a, char b) {
  assert(is_binary(a) && is_binary(b));
  if (a == b)
    return '0';
  else
    return '1';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ROR64c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,%ecx
  ror    %cl,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long ROR64c(unsigned long word, const int i) {
  asm("rorq %%cl,%0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ROR64c>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  ror    %cl,%rax
  ret
```

assistant: ```c
unsigned long ROR64c(unsigned long word, const int i) {
  asm("rorq %%cl,%0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ROR64c>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  ror    %cl,%rax
  ret
```

assistant: ```c
unsigned long ROR64c(unsigned long word, const int i) {
  asm("rorq %%cl,%0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ROR64c>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  ror    %cl,%rax
  ret
```

assistant: ```c
unsigned long ROR64c(unsigned long word, const int i) {
  asm("rorq %%cl,%0" : "=r"(word) : "0"(word), "c"(i));
  return word;
}
```