user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x100000(%rsp),%r11
L37:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L37
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x100408(%rsp)
  xor    %eax,%eax
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L56
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  mov    %rax,%r13
  mov    %rax,%rbx
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    0x8(%rbp),%rax
  lea    -0x1(%rax,%r13,1),%rax
  cmpb   $0x2f,(%rax)
  je     L108
L143:
  cmp    $0x3,%r12d
  je     L95
L105:
  mov    0x8(%rbp),%r8
  mov    $0x1,%eax
  mov    $0x0,%ecx
  mov    $0x0,%edi
  mov    $0x0,%r10d
  jmp    L52
L108:
  movb   $0x0,(%rax)
  mov    0x8(%rbp),%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  jmp    L143
L95:
  mov    0x10(%rbp),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L149
  mov    %rbx,%rax
  sub    %r12,%rax
  add    0x8(%rbp),%rax
  lea    0x100001(%rsp),%rdx
  mov    %rbx,%rsi
  add    0x8(%rbp),%rsi
L48:
  movzbl (%rax),%ecx
  mov    %cl,-0x1(%rdx)
  movb   $0x0,(%rdx)
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rsi,%rax
  jne    L48
L149:
  lea    0x100000(%rsp),%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L105
  sub    $0x1,%rbx
  sub    %r12,%rbx
  jmp    L105
L22:
  add    $0x1,%rdi
  mov    %r10,%rcx
L69:
  lea    0x1(%rax),%rdx
  cmp    %rbx,%rax
  ja     L99
  mov    %rdx,%rax
L52:
  cmpb   $0x2f,-0x1(%r8,%rax,1)
  je     L22
  lea    0x1(%rcx),%rsi
  mov    %rdi,%rdx
  shl    $0xa,%rdx
  lea    0x100410(%rdx),%rdx
  add    %rsp,%rdx
  movb   $0x0,-0x10040f(%rdx,%rcx,1)
  movzbl -0x1(%r8,%rax,1),%r9d
  mov    %r9b,-0x100410(%rcx,%rdx,1)
  mov    %rsi,%rcx
  jmp    L69
L99:
  shl    $0xa,%rdi
  lea    (%rsp,%rdi,1),%rdi
  cmpb   $0x0,(%rdi)
  jne    L167
  cmpb   $0x0,(%rsp)
  je     L101
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L56:
  mov    0x100408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x100418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L101:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L56
L167:
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L56
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: /

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2)
    return 1;
  size_t len = strlen(argv[1]);
  size_t lena;
  char end[1024][1024];
  char buffer[1024];
  size_t i, c, d, e;
  i = c = d = e = 0;
  memset(end[0], 0, 1024);
  if (argv[1][len - 1] == '/') {
    argv[1][len - 1] = '\0';
    len = strlen(argv[1]);
  }
  if (argc == 3) {
    lena = strlen(argv[2]);
    while (i < lena) {
      buffer[i] = argv[1][len - lena + i];
      buffer[++i] = '\0';
    }
    if (strcmp(argv[2], buffer) == 0)
      len -= lena + 1;
  }
  while (c <= len) {
    if (argv[1][c] != '/') {
      end[d][e + 1] = '\0';
      end[d][e++] = argv[1][c++];
    } else {
      ++c;
      ++d;
      e = 0;
    }
  }
  if (strlen(end[d]) == 0) {
    if (strlen(end[0]) != 0)
      printf("%s\n", end[0]);
    else
      printf("/\n");
  } else {
    printf("%s\n", end[d]);
  }
  return (0);
}
```