ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<curve25519>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x150,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %rdx,-0x148(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x124(%rbp)
  jmp    L24
L1:
  mov    -0x124(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x140(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x124(%rbp),%eax
  cltq
  mov    %dl,-0x30(%rbp,%rax,1)
  addl   $0x1,-0x124(%rbp)
L24:
  cmpl   $0x1f,-0x124(%rbp)
  jle    L1
  movzbl -0x30(%rbp),%eax
  and    $0xfffffff8,%eax
  mov    %al,-0x30(%rbp)
  movzbl -0x11(%rbp),%eax
  and    $0x7f,%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x11(%rbp),%eax
  or     $0x40,%eax
  mov    %al,-0x11(%rbp)
  mov    $0x0,%eax
  call   <crypto_smult_curve25519_athlon_init@plt>
  mov    -0x148(%rbp),%rdx
  lea    -0x120(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_smult_curve25519_athlon_todouble@plt>
  lea    -0x30(%rbp),%rdx
  lea    -0x120(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_smult_curve25519_athlon_mainloop@plt>
  lea    -0x120(%rbp),%rdx
  add    $0x50,%rdx
  lea    -0x120(%rbp),%rax
  add    $0x50,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crypto_smult_curve25519_athlon_recip@plt>
  lea    -0x120(%rbp),%rdx
  add    $0x50,%rdx
  lea    -0x120(%rbp),%rax
  add    $0xa0,%rax
  lea    -0x120(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <crypto_smult_curve25519_athlon_mult@plt>
  lea    -0x120(%rbp),%rax
  add    $0xa0,%rax
  mov    -0x138(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <crypto_smult_curve25519_athlon_fromdouble@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  double work[30];
  unsigned char e[32];
  int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  crypto_smult_curve25519_athlon_init();
  crypto_smult_curve25519_athlon_todouble(work, p);
  crypto_smult_curve25519_athlon_mainloop(work, e);
  crypto_smult_curve25519_athlon_recip(work + 10, work + 10);
  crypto_smult_curve25519_athlon_mult(work + 20, work, work + 10);
  crypto_smult_curve25519_athlon_fromdouble(q, work + 20);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<curve25519>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
L9:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,0xf0(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x20,%rax
  jne    L9
  andb   $0xf8,0xf0(%rsp)
  movzbl 0x10f(%rsp),%eax
  and    $0x7f,%eax
  or     $0x40,%eax
  mov    %al,0x10f(%rsp)
  mov    $0x0,%eax
  call   <crypto_smult_curve25519_athlon_init@plt>
  mov    %rsp,%r12
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <crypto_smult_curve25519_athlon_todouble@plt>
  lea    0xf0(%rsp),%rsi
  mov    %r12,%rdi
  call   <crypto_smult_curve25519_athlon_mainloop@plt>
  lea    0x50(%rsp),%rbp
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <crypto_smult_curve25519_athlon_recip@plt>
  lea    0xa0(%rsp),%r13
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <crypto_smult_curve25519_athlon_mult@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <crypto_smult_curve25519_athlon_fromdouble@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  double work[30];
  unsigned char e[32];
  int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  crypto_smult_curve25519_athlon_init();
  crypto_smult_curve25519_athlon_todouble(work, p);
  crypto_smult_curve25519_athlon_mainloop(work, e);
  crypto_smult_curve25519_athlon_recip(work + 10, work + 10);
  crypto_smult_curve25519_athlon_mult(work + 20, work, work + 10);
  crypto_smult_curve25519_athlon_fromdouble(q, work + 20);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<curve25519>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x128,%rsp
  movdqu 0x10(%rsi),%xmm1
  movdqu (%rsi),%xmm0
  mov    %fs:0x28,%rdx
  mov    %rdx,0x118(%rsp)
  xor    %edx,%edx
  mov    %rsp,%r12
  lea    0xa0(%rsp),%r14
  movaps %xmm1,0x100(%rsp)
  movzbl 0x10f(%rsp),%eax
  movaps %xmm0,0xf0(%rsp)
  and    $0x7f,%eax
  andb   $0xf8,0xf0(%rsp)
  or     $0x40,%eax
  mov    %al,0x10f(%rsp)
  xor    %eax,%eax
  call   <crypto_smult_curve25519_athlon_init@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  lea    0x50(%rsp),%r13
  call   <crypto_smult_curve25519_athlon_todouble@plt>
  lea    0xf0(%rsp),%rsi
  mov    %r12,%rdi
  call   <crypto_smult_curve25519_athlon_mainloop@plt>
  mov    %r13,%rsi
  mov    %r13,%rdi
  call   <crypto_smult_curve25519_athlon_recip@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %r13,%rdx
  call   <crypto_smult_curve25519_athlon_mult@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <crypto_smult_curve25519_athlon_fromdouble@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x128,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  double work[30];
  unsigned char e[32];
  int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  crypto_smult_curve25519_athlon_init();
  crypto_smult_curve25519_athlon_todouble(work, p);
  crypto_smult_curve25519_athlon_mainloop(work, e);
  crypto_smult_curve25519_athlon_recip(work + 10, work + 10);
  crypto_smult_curve25519_athlon_mult(work + 20, work, work + 10);
  crypto_smult_curve25519_athlon_fromdouble(q, work + 20);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<curve25519>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x128,%rsp
  movdqu 0x10(%rsi),%xmm1
  movdqu (%rsi),%xmm0
  mov    %fs:0x28,%rdx
  mov    %rdx,0x118(%rsp)
  xor    %edx,%edx
  mov    %rsp,%r12
  lea    0xa0(%rsp),%r14
  movaps %xmm1,0x100(%rsp)
  movzbl 0x10f(%rsp),%eax
  movaps %xmm0,0xf0(%rsp)
  and    $0x7f,%eax
  andb   $0xf8,0xf0(%rsp)
  or     $0x40,%eax
  mov    %al,0x10f(%rsp)
  xor    %eax,%eax
  call   <crypto_smult_curve25519_athlon_init@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  lea    0x50(%rsp),%r13
  call   <crypto_smult_curve25519_athlon_todouble@plt>
  lea    0xf0(%rsp),%rsi
  mov    %r12,%rdi
  call   <crypto_smult_curve25519_athlon_mainloop@plt>
  mov    %r13,%rsi
  mov    %r13,%rdi
  call   <crypto_smult_curve25519_athlon_recip@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %r13,%rdx
  call   <crypto_smult_curve25519_athlon_mult@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <crypto_smult_curve25519_athlon_fromdouble@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x128,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int curve25519(unsigned char *q, const unsigned char *n, const unsigned char *p) {
  double work[30];
  unsigned char e[32];
  int i;
  for (i = 0; i < 32; ++i)
    e[i] = n[i];
  e[0] &= 248;
  e[31] &= 127;
  e[31] |= 64;
  crypto_smult_curve25519_athlon_init();
  crypto_smult_curve25519_athlon_todouble(work, p);
  crypto_smult_curve25519_athlon_mainloop(work, e);
  crypto_smult_curve25519_athlon_recip(work + 10, work + 10);
  crypto_smult_curve25519_athlon_mult(work + 20, work, work + 10);
  crypto_smult_curve25519_athlon_fromdouble(q, work + 20);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kiss_encapsulate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xc0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L46:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xc0,%al
  jne    L28
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xdb,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xdc,(%rax)
  jmp    L0
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xdb,%al
  jne    L44
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xdb,(%rax)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xdd,(%rax)
  jmp    L0
L44:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L0:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L46
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0xc0,(%rax)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int kiss_encapsulate(unsigned char *in, int ilen, unsigned char *out) {
  int olen;
  int j;
  olen = 0;
  out[olen++] = 0xC0;
  for (j = 0; j < ilen; j++) {
    if (in[j] == 0xC0) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDC;
    } else if (in[j] == 0xDB) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDD;
    } else {
      out[olen++] = in[j];
    }
  }
  out[olen++] = 0xC0;
  return (olen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kiss_encapsulate>:
  endbr64
  mov    %rdx,%r8
  movb   $0xc0,(%rdx)
  test   %esi,%esi
  jle    L35
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x1,%eax
  jmp    L58
L36:
  lea    0x1(%rax),%ecx
  movslq %eax,%rdi
  movb   $0xdb,(%r8,%rdi,1)
  add    $0x2,%eax
  movslq %ecx,%rcx
  movb   $0xdc,(%r8,%rcx,1)
L63:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L28
L58:
  movzbl (%rdx),%ecx
  cmp    $0xc0,%cl
  je     L36
  cmp    $0xdb,%cl
  je     L56
  movslq %eax,%rdi
  mov    %cl,(%r8,%rdi,1)
  lea    0x1(%rax),%eax
  jmp    L63
L56:
  lea    0x1(%rax),%ecx
  movslq %eax,%rdi
  movb   $0xdb,(%r8,%rdi,1)
  add    $0x2,%eax
  movslq %ecx,%rcx
  movb   $0xdd,(%r8,%rcx,1)
  jmp    L63
L35:
  mov    $0x1,%eax
L28:
  movslq %eax,%rdx
  movb   $0xc0,(%r8,%rdx,1)
  add    $0x1,%eax
  ret
```

assistant: ```c
int kiss_encapsulate(unsigned char *in, int ilen, unsigned char *out) {
  int olen;
  int j;
  olen = 0;
  out[olen++] = 0xC0;
  for (j = 0; j < ilen; j++) {
    if (in[j] == 0xC0) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDC;
    } else if (in[j] == 0xDB) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDD;
    } else {
      out[olen++] = in[j];
    }
  }
  out[olen++] = 0xC0;
  return (olen);
}
```
user: What is the c source code of the assembly code below?

```asm
<kiss_encapsulate>:
  endbr64
  movb   $0xc0,(%rdx)
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r10
  mov    $0x1,%eax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L53:
  cmp    $0xdb,%r8b
  je     L69
  mov    %r8b,(%rcx)
  mov    %r9d,%eax
L58:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  je     L21
L19:
  lea    0x1(%rax),%r9d
  movzbl (%rdi),%r8d
  movslq %r9d,%rcx
  lea    (%rdx,%rcx,1),%rsi
  movslq %eax,%rcx
  add    %rdx,%rcx
  cmp    $0xc0,%r8b
  jne    L53
  add    $0x1,%rdi
  movb   $0xdb,(%rcx)
  add    $0x2,%eax
  movb   $0xdc,(%rsi)
  cmp    %r10,%rdi
  jne    L19
L21:
  movslq %eax,%rcx
  add    $0x1,%eax
  movb   $0xc0,(%rdx,%rcx,1)
  ret
  nopl   (%rax)
L69:
  movb   $0xdb,(%rcx)
  add    $0x2,%eax
  movb   $0xdd,(%rsi)
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x1,%ecx
  mov    $0x2,%eax
  movb   $0xc0,(%rdx,%rcx,1)
  ret
```

assistant: ```c
int kiss_encapsulate(unsigned char *in, int ilen, unsigned char *out) {
  int olen;
  int j;
  olen = 0;
  out[olen++] = 0xC0;
  for (j = 0; j < ilen; j++) {
    if (in[j] == 0xC0) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDC;
    } else if (in[j] == 0xDB) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDD;
    } else {
      out[olen++] = in[j];
    }
  }
  out[olen++] = 0xC0;
  return (olen);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<kiss_encapsulate>:
  endbr64
  movb   $0xc0,(%rdx)
  test   %esi,%esi
  jle    L27
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r10
  mov    $0x1,%eax
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L20:
  cmp    $0xdb,%r8b
  je     L7
  mov    %r8b,(%rcx)
  mov    %r9d,%eax
L35:
  add    $0x1,%rdi
  cmp    %rdi,%r10
  je     L9
L10:
  lea    0x1(%rax),%r9d
  movzbl (%rdi),%r8d
  movslq %r9d,%rcx
  lea    (%rdx,%rcx,1),%rsi
  movslq %eax,%rcx
  add    %rdx,%rcx
  cmp    $0xc0,%r8b
  jne    L20
  add    $0x1,%rdi
  movb   $0xdb,(%rcx)
  add    $0x2,%eax
  movb   $0xdc,(%rsi)
  cmp    %rdi,%r10
  jne    L10
L9:
  movslq %eax,%rcx
  add    $0x1,%eax
  movb   $0xc0,(%rdx,%rcx,1)
  ret
  nopl   (%rax)
L7:
  movb   $0xdb,(%rcx)
  add    $0x2,%eax
  movb   $0xdd,(%rsi)
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%ecx
  mov    $0x2,%eax
  movb   $0xc0,(%rdx,%rcx,1)
  ret
```

assistant: ```c
int kiss_encapsulate(unsigned char *in, int ilen, unsigned char *out) {
  int olen;
  int j;
  olen = 0;
  out[olen++] = 0xC0;
  for (j = 0; j < ilen; j++) {
    if (in[j] == 0xC0) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDC;
    } else if (in[j] == 0xDB) {
      out[olen++] = 0xDB;
      out[olen++] = 0xDD;
    } else {
      out[olen++] = in[j];
    }
  }
  out[olen++] = 0xC0;
  return (olen);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_float_neg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <u2f@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  movss  D8(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <isnan@plt>
  test   %rax,%rax
  je     L10
  mov    -0x14(%rbp),%eax
  jmp    L5
L10:
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <f2u@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x80]}

assistant: ```c
unsigned test_float_neg(unsigned uf) {
  float f = u2f(uf);
  float nf = -f;
  if (isnan(f))
    return uf;
  else
    return f2u(nf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_float_neg>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  call   <u2f@plt>
  movss  %xmm0,0xc(%rsp)
  call   <isnan@plt>
  test   %rax,%rax
  je     L10
L19:
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L10:
  movss  0xc(%rsp),%xmm0
  xorps  D3(%rip),%xmm0
  call   <f2u@plt>
  mov    %eax,%ebx
  jmp    L19
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
unsigned test_float_neg(unsigned uf) {
  float f = u2f(uf);
  float nf = -f;
  if (isnan(f))
    return uf;
  else
    return f2u(nf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_float_neg>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  sub    $0x10,%rsp
  call   <u2f@plt>
  movss  %xmm0,0xc(%rsp)
  call   <isnan@plt>
  movss  0xc(%rsp),%xmm0
  test   %rax,%rax
  je     L5
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xorps  D1(%rip),%xmm0
  add    $0x10,%rsp
  pop    %r12
  jmp    1090 <f2u@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
unsigned test_float_neg(unsigned uf) {
  float f = u2f(uf);
  float nf = -f;
  if (isnan(f))
    return uf;
  else
    return f2u(nf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_float_neg>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  sub    $0x10,%rsp
  call   <u2f@plt>
  movss  %xmm0,0xc(%rsp)
  call   <isnan@plt>
  movss  0xc(%rsp),%xmm0
  test   %rax,%rax
  je     L0
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xorps  D1(%rip),%xmm0
  add    $0x10,%rsp
  pop    %r12
  jmp    1090 <f2u@plt>
```

tool_calls: name: read_data
arguments: tag: D1
data_type: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
unsigned test_float_neg(unsigned uf) {
  float f = u2f(uf);
  float nf = -f;
  if (isnan(f))
    return uf;
  else
    return f2u(nf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  jns    L3
  mov    $0x6f,%eax
  jmp    L7
L3:
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) < 0)
    return 111;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  sar    $0x3f,%rax
  and    $0x6f,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) < 0)
    return 111;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  sar    $0x3f,%rax
  and    $0x6f,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) < 0)
    return 111;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  sar    $0x3f,%rax
  and    $0x6f,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) < 0)
    return 111;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<roman_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L92
L21:
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L87
L89:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x43,%eax
  cmp    $0x15,%eax
  ja     L27
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D5(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D5(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movl   $0x1,-0xc(%rbp)
  jmp    L13
  movl   $0x5,-0xc(%rbp)
  jmp    L13
  movl   $0xa,-0xc(%rbp)
  jmp    L13
  movl   $0x32,-0xc(%rbp)
  jmp    L13
  movl   $0x64,-0xc(%rbp)
  jmp    L13
  movl   $0x1f4,-0xc(%rbp)
  jmp    L13
  movl   $0x3e8,-0xc(%rbp)
  jmp    L13
L27:
  movl   $0x0,-0xc(%rbp)
  nop
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L76
  mov    -0xc(%rbp),%eax
  neg    %eax
  jmp    L54
L76:
  mov    -0xc(%rbp),%eax
L54:
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x10(%rbp)
L87:
  cmpl   $0x0,-0x10(%rbp)
  jns    L89
  mov    -0x14(%rbp),%eax
L92:
  leave
  ret
```

assistant: ```c
int roman_to_int(char *s) {
  if (!s) {
    return 0;
  }
  int num = 0, len, i, temp, last = 0;
  len = strlen(s);
  for (i = len - 1; i >= 0; --i) {
    switch (s[i]) {
    case 'I':
      temp = 1;
      break;
    case 'V':
      temp = 5;
      break;
    case 'X':
      temp = 10;
      break;
    case 'L':
      temp = 50;
      break;
    case 'C':
      temp = 100;
      break;
    case 'D':
      temp = 500;
      break;
    case 'M':
      temp = 1000;
      break;
    default:
      temp = 0;
      break;
    }
    num += (temp >= last ? temp : -1 * temp);
    last = temp;
  }
  return num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<roman_to_int>:
  endbr64
  mov    $0x0,%ecx
  test   %rdi,%rdi
  je     L4
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L1
  movslq %edx,%rdx
  add    %rbx,%rdx
  movslq %eax,%rcx
  lea    -0x2(%rbx,%rcx,1),%r8
  lea    -0x1(%rax),%eax
  sub    %rax,%r8
  mov    $0x0,%esi
  mov    $0x0,%ecx
  mov    $0x0,%r12d
  lea    D9(%rip),%rdi
  mov    $0x1,%r13d
  mov    $0x3e8,%ebp
  mov    $0x1f4,%ebx
  mov    $0x64,%r11d
  mov    $0x32,%r10d
  mov    $0xa,%r9d
  mov    $0x5,%r14d
  jmp    L20
  mov    %r14d,%eax
  jmp    L35
  mov    %r9d,%eax
L35:
  mov    %eax,%r15d
  neg    %r15d
  cmp    %esi,%eax
  mov    %r15d,%esi
  cmovge %eax,%esi
  add    %esi,%ecx
  sub    $0x1,%rdx
  cmp    %r8,%rdx
  je     L91
  mov    %eax,%esi
L20:
  movzbl (%rdx),%eax
  sub    $0x43,%eax
  cmp    $0x15,%al
  ja     L62
  movzbl %al,%eax
  movslq (%rdi,%rax,4),%rax
  add    %rdi,%rax
  notrack jmp *%rax
  mov    %r10d,%eax
  jmp    L35
  mov    %r11d,%eax
  jmp    L35
  mov    %ebx,%eax
  jmp    L35
  mov    %ebp,%eax
  jmp    L35
L62:
  mov    %r12d,%eax
  jmp    L35
  mov    %r13d,%eax
  jmp    L35
L1:
  mov    $0x0,%ecx
L91:
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int roman_to_int(char *s) {
  if (!s) {
    return 0;
  }
  int num = 0, len, i, temp, last = 0;
  len = strlen(s);
  for (i = len - 1; i >= 0; --i) {
    switch (s[i]) {
    case 'I':
      temp = 1;
      break;
    case 'V':
      temp = 5;
      break;
    case 'X':
      temp = 10;
      break;
    case 'L':
      temp = 50;
      break;
    case 'C':
      temp = 100;
      break;
    case 'D':
      temp = 500;
      break;
    case 'M':
      temp = 1000;
      break;
    default:
      temp = 0;
      break;
    }
    num += (temp >= last ? temp : -1 * temp);
    last = temp;
  }
  return num;
}
```