ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<HeatTransferCoef>:
  endbr64
  mulsd  D0(%rip),%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: f64

tool: D0: 0.25

assistant: ```c
double HeatTransferCoef(double Nusselt, double Height) {
  double HeatTrans;
  HeatTrans = (Nusselt * (0.25)) / Height;
  return HeatTrans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<suffixname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L23
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L23:
  lea    D18(%rip),%rax
  jmp    L37
L17:
  mov    -0x10(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L57
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L41
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
L57:
  lea    D18(%rip),%rax
  jmp    L37
L41:
  mov    -0x8(%rbp),%rax
L37:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type_infered: string

tool: 

assistant: ```c
char *suffixname(const char *full_name) {
  char *base;
  char *p;
  base = basename((char *)full_name);
  if (base == NULL || base[0] == '\0')
    return "";
  p = strrchr(base, '.');
  if (p == NULL || (p[0] == '.' && p[1] == '\0'))
    return "";
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<suffixname>:
  endbr64
  sub    $0x8,%rsp
  call   <basename@plt>
  mov    %rax,%rdi
  lea    D19(%rip),%rax
  test   %rdi,%rdi
  je     L30
  cmpb   $0x0,(%rdi)
  jne    L3
L30:
  add    $0x8,%rsp
  ret
L3:
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L9
  cmpb   $0x2e,(%rax)
  jne    L30
  cmpb   $0x0,0x1(%rax)
  jne    L30
  lea    D19(%rip),%rax
  jmp    L30
L9:
  lea    D19(%rip),%rax
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
data_type: string

tool: 

assistant: ```c
char *suffixname(const char *full_name) {
  char *base;
  char *p;
  base = basename((char *)full_name);
  if (base == NULL || base[0] == '\0')
    return "";
  p = strrchr(base, '.');
  if (p == NULL || (p[0] == '.' && p[1] == '\0'))
    return "";
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<suffixname>:
  endbr64
  sub    $0x8,%rsp
  call   <basename@plt>
  test   %rax,%rax
  je     L0
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L27
L0:
  lea    D1(%rip),%rax
L1:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L0
  cmpb   $0x2e,(%rax)
  jne    L1
  cmpb   $0x0,0x1(%rax)
  jne    L1
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: 

assistant: ```c
char *suffixname(const char *full_name) {
  char *base;
  char *p;
  base = basename((char *)full_name);
  if (base == NULL || base[0] == '\0')
    return "";
  p = strrchr(base, '.');
  if (p == NULL || (p[0] == '.' && p[1] == '\0'))
    return "";
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<suffixname>:
  endbr64
  sub    $0x8,%rsp
  call   <basename@plt>
  test   %rax,%rax
  je     L31
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L57
L31:
  lea    D3(%rip),%rax
L3:
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L31
  cmpb   $0x2e,(%rax)
  jne    L3
  cmpb   $0x0,0x1(%rax)
  jne    L3
  jmp    L31
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string

tool: 

assistant: ```c
char *suffixname(const char *full_name) {
  char *base;
  char *p;
  base = basename((char *)full_name);
  if (base == NULL || base[0] == '\0')
    return "";
  p = strrchr(base, '.');
  if (p == NULL || (p[0] == '.' && p[1] == '\0'))
    return "";
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<testReadFixedInt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%rbp
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fiolSReadFixedInt@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  mov    0x4(%rsp),%esi
  mov    $0x1,%ebp
  cmp    $0xffffee77,%esi
  jne    L67
L61:
  lea    0x4(%rsp),%rdx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fiolSReadFixedInt@plt>
  cltq
  add    %rax,%rbx
  mov    0x4(%rsp),%esi
  cmp    $0x1c,%esi
  jne    L0
  lea    0x4(%rsp),%rdx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fiolSReadFixedInt@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  jne    L46
  cmp    $0x1,%bpl
  jne    L2
  lea    D38(%rip),%rdi
  call   <puts@plt>
  jmp    L2
L67:
  mov    $0xffffee77,%edx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebp
  jmp    L61
L0:
  mov    $0x1c,%edx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fiolSReadFixedInt@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  je     L2
L46:
  mov    $0x2a,%edx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D24
data_type: string
name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D38
data_type: string
name: read_data
arguments: tag: D17
data_type: string

tool: D27: Testing fiolSReadFixedInt...

tool: D24: -448928+42

tool: D0: 	("%s")


tool: D38: 		Passed!

tool: D17: 		failed, returned %d instead of %d


assistant: ```c
void testReadFixedInt() {
  char str[255];
  char *msg = &str;
  char passed = 0;
  char signedChar;
  signed int signedInt;
  printf("Testing fiolSReadFixedInt...\r\n");
  msg = "-448928+42";
  passed = 1;
  printf("\t(\"%s\")\r\n", msg);
  msg += fiolSReadFixedInt(msg, 5, &signedInt);
  if (signedInt != -4489) {
    printf("\t\tfailed, returned %d instead of %d\r\n", signedInt, -4489);
    passed = 0;
  }
  msg += fiolSReadFixedInt(msg, 3, &signedInt);
  if (signedInt != 28) {
    printf("\t\tfailed, returned %d instead of %d\r\n", signedInt, 28);
    passed = 0;
  }
  msg += fiolSReadFixedInt(msg, 3, &signedInt);
  if (signedInt != +42) {
    printf("\t\tfailed, returned %d instead of %d\r\n", signedInt, +42);
    passed = 0;
  }
  if (passed == 1)
    printf("\t\tPassed!\r\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<testReadFixedInt>:
  endbr64
  push   %r13
  lea    D54(%rip),%rdi
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  lea    D49(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  xor    %eax,%eax
  call   <fiolSReadFixedInt@plt>
  mov    0x4(%rsp),%esi
  movslq %eax,%rbx
  add    %rbx,%rbp
  cmp    $0xffffee77,%esi
  je     L14
  lea    D28(%rip),%r13
  mov    $0xffffee77,%edx
  xor    %eax,%eax
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <printf@plt>
L14:
  mov    $0x3,%esi
  mov    %rbp,%rdi
  mov    %r12,%rdx
  xor    %eax,%eax
  call   <fiolSReadFixedInt@plt>
  mov    0x4(%rsp),%esi
  cltq
  add    %rax,%rbp
  cmp    $0x1c,%esi
  jne    L57
  mov    $0x3,%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fiolSReadFixedInt@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  jne    L7
  cmp    $0x1,%r13b
  jne    L70
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L70
  nopl   0x0(%rax)
L7:
  lea    D28(%rip),%r13
L60:
  mov    $0x2a,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L70:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L57:
  lea    D28(%rip),%r13
  mov    $0x1c,%edx
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fiolSReadFixedInt@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2a,%esi
  je     L70
  jmp    L60
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D54
data_type: string
name: unpack_data
arguments: label: D49
data_type: string
name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D28
data_type: string
name: unpack_data
arguments: label: D23
data_type: string

tool: D54: Testing fiolSReadFixedInt...

tool: D49: -448928+42

tool: D6: 	("%s")


tool: D28: 		failed, returned %d instead of %d


tool: D23: 		Passed!

assistant: ```c
void testReadFixedInt() {
  char str[255];
  char *msg = &str;
  char passed = 0;
  char signedChar;
  signed int signedInt;
  printf("Testing fiolSReadFixedInt...\r\n");
  msg = "-448928+42";
  passed = 1;
  printf("\t(\"%s\")\r\n", msg);
  msg += fiolSReadFixedInt(msg, 5, &signedInt);
  if (signedInt != -4489) {
    printf("\t\tfailed, returned %d instead of %d\r\n", signedInt, -4489);
    passed = 0;
  }
  msg += fiolSReadFixedInt(msg, 3, &signedInt);
  if (signedInt != 28) {
    printf("\t\tfailed, returned %d instead of %d\r\n", signedInt, 28);
    passed = 0;
  }
  msg += fiolSReadFixedInt(msg, 3, &signedInt);
  if (signedInt != +42) {
    printf("\t\tfailed, returned %d instead of %d\r\n", signedInt, +42);
    passed = 0;
  }
  if (passed == 1)
    printf("\t\tPassed!\r\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <run_lisp@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  run_lisp(argc, argv);
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <run_lisp@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  run_lisp(argc, argv);
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <run_lisp@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  run_lisp(argc, argv);
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <run_lisp@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  run_lisp(argc, argv);
  return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fun>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %d


assistant: ```c
void fun() {
  int a;
  printf("%d\n", a);
  static int b;
  printf("%d\n", b);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fun>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
void fun() {
  int a;
  printf("%d\n", a);
  static int b;
  printf("%d\n", b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fun>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: %d


assistant: ```c
void fun() {
  int a;
  printf("%d\n", a);
  static int b;
  printf("%d\n", b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L13:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D74(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D77(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L29
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D74(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D68(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x41,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L57
L29:
  cmpl   $0x1,-0xc(%rbp)
  jne    L16
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D74(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D68(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x61,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L57
L16:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D74(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D32(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L57:
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L13
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D74
datatype: byte[8]
name: parse_data
arguments: data_tag: D77
datatype: byte[8]
name: parse_data
arguments: data_tag: D68
datatype: byte[8]
name: parse_data
arguments: data_tag: D32
datatype: byte[8]

tool: {"D74": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x41]}

tool: {"D77": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D68": [0x00,0x00,0x00,0x00,0x00,0x00,0x3a,0x40]}

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
char *gen(int len, char *token) {
  char *pt = token;
  while (len--) {
    int choose = (0) + (long)((double)((double)(2) - (0) + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    if (choose == 0) {
      *pt = ('A') + (long)((double)((double)('Z') - ('A') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else if (choose == 1) {
      *pt = ('a') + (long)((double)((double)('z') - ('a') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else {
      *pt = ('0') + (long)((double)((double)('9') - ('0') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    }
    pt++;
  }
  *pt = 0;
  return token;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  test   %edi,%edi
  je     L51
  lea    -0x1(%rdi),%r13d
  mov    %edi,%edi
  lea    (%rsi,%rdi,1),%rbp
  mov    %rsi,%rbx
  jmp    L28
L26:
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D11(%rip),%xmm0
  mulsd  D30(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x41,%eax
L77:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L35
L28:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D11(%rip),%xmm0
  mulsd  D59(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  test   %eax,%eax
  je     L26
  cmp    $0x1,%eax
  je     L19
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D11(%rip),%xmm0
  mulsd  D27(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x30,%eax
  jmp    L77
L19:
  mov    $0x0,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D11(%rip),%xmm0
  mulsd  D30(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x61,%eax
  jmp    L77
L35:
  mov    %r13d,%r13d
  lea    0x1(%r12,%r13,1),%rax
L48:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  mov    %rsi,%rax
  jmp    L48
```

tool_calls: name: retrieve_data
arguments: tag: D11
type: byte[8]
name: retrieve_data
arguments: tag: D30
type: byte[8]
name: retrieve_data
arguments: tag: D59
type: byte[8]
name: retrieve_data
arguments: tag: D27
type: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x3a,0x40]}

tool: {"D59": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
char *gen(int len, char *token) {
  char *pt = token;
  while (len--) {
    int choose = (0) + (long)((double)((double)(2) - (0) + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    if (choose == 0) {
      *pt = ('A') + (long)((double)((double)('Z') - ('A') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else if (choose == 1) {
      *pt = ('a') + (long)((double)((double)('z') - ('a') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else {
      *pt = ('0') + (long)((double)((double)('9') - ('0') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    }
    pt++;
  }
  *pt = 0;
  return token;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L7
  mov    %edi,%edi
  mov    %rsi,%rbx
  lea    (%rsi,%rdi,1),%rbp
  jmp    L34
  xchg   %ax,%ax
L49:
  cmp    $0x1,%eax
  mov    $0x0,%eax
  je     L55
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D10(%rip),%xmm0
  mulsd  D64(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x30,%eax
L69:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L61
L34:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D10(%rip),%xmm0
  mulsd  D73(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  test   %eax,%eax
  jne    L49
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  add    $0x1,%rbx
  cvtsi2sd %eax,%xmm0
  mulsd  D10(%rip),%xmm0
  mulsd  D57(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x41,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L34
L61:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L55:
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D10(%rip),%xmm0
  mulsd  D57(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x61,%eax
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rsi,%rbp
  mov    %r12,%rax
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type: byte[8]
name: read_data
arguments: data_tag: D64
type: byte[8]
name: read_data
arguments: data_tag: D73
type: byte[8]
name: read_data
arguments: data_tag: D57
type: byte[8]

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e]}

tool: {"D64": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D73": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x00,0x3a,0x40]}

assistant: ```c
char *gen(int len, char *token) {
  char *pt = token;
  while (len--) {
    int choose = (0) + (long)((double)((double)(2) - (0) + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    if (choose == 0) {
      *pt = ('A') + (long)((double)((double)('Z') - ('A') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else if (choose == 1) {
      *pt = ('a') + (long)((double)((double)('z') - ('a') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else {
      *pt = ('0') + (long)((double)((double)('9') - ('0') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    }
    pt++;
  }
  *pt = 0;
  return token;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L42
  mov    %edi,%edi
  mov    %rsi,%rbx
  lea    (%rsi,%rdi,1),%rbp
  jmp    L49
  xchg   %ax,%ax
L69:
  cmp    $0x1,%eax
  mov    $0x0,%eax
  je     L58
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D56(%rip),%xmm0
  mulsd  D64(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x30,%eax
L30:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L15
L49:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D56(%rip),%xmm0
  mulsd  D44(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  test   %eax,%eax
  jne    L69
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  add    $0x1,%rbx
  cvtsi2sd %eax,%xmm0
  mulsd  D56(%rip),%xmm0
  mulsd  D42(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x41,%eax
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L49
L15:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D56(%rip),%xmm0
  mulsd  D42(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x61,%eax
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %rsi,%rbp
  mov    %r12,%rax
  movb   $0x0,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D56
datatype: byte[8]
name: parse_data
arguments: data_label: D64
datatype: byte[8]
name: parse_data
arguments: data_label: D44
datatype: byte[8]
name: parse_data
arguments: data_label: D42
datatype: byte[8]

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e]}

tool: {"D64": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x3a,0x40]}

assistant: ```c
char *gen(int len, char *token) {
  char *pt = token;
  while (len--) {
    int choose = (0) + (long)((double)((double)(2) - (0) + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    if (choose == 0) {
      *pt = ('A') + (long)((double)((double)('Z') - ('A') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else if (choose == 1) {
      *pt = ('a') + (long)((double)((double)('z') - ('a') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    } else {
      *pt = ('0') + (long)((double)((double)('9') - ('0') + 1.0) * ((rand()) / ((2147483647) + 1.0)));
    }
    pt++;
  }
  *pt = 0;
  return token;
}
```