ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  mov    $0x0,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <nd_int@plt>
  test   %rax,%rax
  cmove  %rbx,%rbp
  cmovne %rbx,%r12
  xor    %eax,%eax
  call   <nd_int@plt>
  test   %rax,%rax
  je     L12
  movl   $0x5,(%r12)
L3:
  mov    (%rbx),%eax
  xor    %edi,%edi
  cmp    $0x4,%eax
  setg   %dil
  call   <__CRAB_assert@plt>
  mov    (%rbx),%eax
  xor    %edi,%edi
  cmp    $0xa,%eax
  setle  %dil
  call   <__CRAB_assert@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L12:
  movl   $0xa,0x0(%rbp)
  jmp    L3
```

assistant: ```c
int main() {
  volatile int *a = (int *)malloc(sizeof(int));
  volatile int *p, *q;
  if (nd_int()) {
    p = a;
  } else {
    q = a;
  }
  if (nd_int()) {
    *p = 5;
  } else {
    *q = 10;
  }
  __CRAB_assert(*a >= 5);
  __CRAB_assert(*a <= 10);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fibonacci_improved>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L46
L45:
  cmpl   $0x1,-0x24(%rbp)
  ja     L21
  mov    $0x1,%eax
  jmp    L46
L21:
  movq   $0x0,-0x18(%rbp)
  movq   $0x1,-0x10(%rbp)
  movl   $0x2,-0x1c(%rbp)
  jmp    L30
L27:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L30:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jae    L27
  mov    -0x8(%rbp),%rax
L46:
  pop    %rbp
  ret
```

assistant: ```c
long long fibonacci_improved(unsigned int n) {
  if (n <= 0) {
    return 0;
  }
  if (n < 2) {
    return 1;
  }
  long long fibFirst = 0;
  long long fibSecond = 1;
  long long fibResult;
  for (int i = 2; i <= n; ++i) {
    fibResult = fibFirst + fibSecond;
    fibFirst = fibSecond;
    fibSecond = fibResult;
  }
  return fibResult;
}
```
user: What is the c source code of the assembly code below?

```asm
<fibonacci_improved>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  je     L29
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L29
  add    $0x1,%edi
  mov    $0x2,%edx
  mov    $0x0,%ecx
L28:
  mov    %rax,%rsi
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %rsi,%rcx
  cmp    %edx,%edi
  jne    L28
L29:
  ret
```

assistant: ```c
long long fibonacci_improved(unsigned int n) {
  if (n <= 0) {
    return 0;
  }
  if (n < 2) {
    return 1;
  }
  long long fibFirst = 0;
  long long fibSecond = 1;
  long long fibResult;
  for (int i = 2; i <= n; ++i) {
    fibResult = fibFirst + fibSecond;
    fibFirst = fibSecond;
    fibSecond = fibResult;
  }
  return fibResult;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fibonacci_improved>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L3
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L3
  mov    $0x2,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %rax,%rsi
  add    $0x1,%edx
  add    %rcx,%rax
  mov    %rsi,%rcx
  cmp    %edi,%edx
  jbe    L16
L3:
  ret
```

assistant: ```c
long long fibonacci_improved(unsigned int n) {
  if (n <= 0) {
    return 0;
  }
  if (n < 2) {
    return 1;
  }
  long long fibFirst = 0;
  long long fibSecond = 1;
  long long fibResult;
  for (int i = 2; i <= n; ++i) {
    fibResult = fibFirst + fibSecond;
    fibFirst = fibSecond;
    fibSecond = fibResult;
  }
  return fibResult;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fibonacci_improved>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L23
  mov    $0x1,%eax
  cmp    $0x1,%edi
  je     L23
  mov    $0x2,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rax,%rsi
  add    $0x1,%edx
  add    %rcx,%rax
  mov    %rsi,%rcx
  cmp    %edi,%edx
  jbe    L6
L23:
  ret
```

assistant: ```c
long long fibonacci_improved(unsigned int n) {
  if (n <= 0) {
    return 0;
  }
  if (n < 2) {
    return 1;
  }
  long long fibFirst = 0;
  long long fibSecond = 1;
  long long fibResult;
  for (int i = 2; i <= n; ++i) {
    fibResult = fibFirst + fibSecond;
    fibFirst = fibSecond;
    fibSecond = fibResult;
  }
  return fibResult;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L11:
  shlq   -0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long power2(int power) {
  unsigned long integer = 1;
  int i;
  for (i = 0; i < power; i++) {
    integer *= 2;
  }
  return integer;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power2>:
  endbr64
  test   %edi,%edi
  jle    L11
  mov    $0x0,%eax
  mov    $0x1,%edx
L5:
  add    %rdx,%rdx
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L5
L16:
  mov    %rdx,%rax
  ret
L11:
  mov    $0x1,%edx
  jmp    L16
```

assistant: ```c
unsigned long power2(int power) {
  unsigned long integer = 1;
  int i;
  for (i = 0; i < power; i++) {
    integer *= 2;
  }
  return integer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<power2>:
  endbr64
  test   %edi,%edi
  jle    L9
  xor    %eax,%eax
  mov    $0x1,%r8d
L16:
  add    $0x1,%eax
  add    %r8,%r8
  cmp    %eax,%edi
  jne    L16
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L9:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long power2(int power) {
  unsigned long integer = 1;
  int i;
  for (i = 0; i < power; i++) {
    integer *= 2;
  }
  return integer;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<power2>:
  endbr64
  test   %edi,%edi
  jle    L3
  xor    %eax,%eax
  mov    $0x1,%r8d
L13:
  add    $0x1,%eax
  add    %r8,%r8
  cmp    %eax,%edi
  jne    L13
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L3:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long power2(int power) {
  unsigned long integer = 1;
  int i;
  for (i = 0; i < power; i++) {
    integer *= 2;
  }
  return integer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movabs $0xef34ca9f65fb16,%rdx
  imul   %rdx,%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L18
L14:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jbe    L7
  lea    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x1a(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  lea    -0x10(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzwl -0x1a(%rbp),%edx
  mov    %dx,(%rax)
  jmp    L13
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
L13:
  addq   $0x1,-0x18(%rbp)
L18:
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x10(%rbp),%rax
  imul   $0x1aae2792,%rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] * 447621010UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  imul   $0x355c4f24,%rax,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] * 447621010UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  imul   $0x355c4f24,%rax,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] * 447621010UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movabs $0xef34ca9f65fb16,%rax
  imul   (%rdi),%rax
  movabs $0xdf61e99ee5b9fd1c,%rdx
  add    %rdx,%rax
  imul   $0x355c4f24,%rax,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) * 67330564296145686UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 3);
        *((unsigned short *)(&state[0UL]) + 3) = copy11;
      } else {
        state[local1] = state[0UL] + state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] * 447621010UL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getDirectionString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L54
  cmpl   $0x3,-0x4(%rbp)
  jg     L5
  cmpl   $0x2,-0x4(%rbp)
  je     L21
  cmpl   $0x2,-0x4(%rbp)
  jg     L5
  cmpl   $0x0,-0x4(%rbp)
  je     L23
  cmpl   $0x1,-0x4(%rbp)
  je     L88
  jmp    L5
L23:
  lea    D30(%rip),%rax
  jmp    L62
L88:
  lea    D0(%rip),%rax
  jmp    L62
L21:
  lea    D43(%rip),%rax
  jmp    L62
L54:
  lea    D5(%rip),%rax
  jmp    L62
L5:
  lea    D19(%rip),%rax
L62:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D43
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string

tool: D30: Left

tool: D0: Right

tool: D43: Up

tool: D5: Down

tool: 

assistant: ```c
char *getDirectionString(int num) {
  switch (num) {
  case 0:
    return "Left";
  case 1:
    return "Right";
  case 2:
    return "Up";
  case 3:
    return "Down";
  default:
    return "";
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getDirectionString>:
  endbr64
  lea    D9(%rip),%rax
  cmp    $0x2,%edi
  je     L15
  jg     L9
  lea    D8(%rip),%rax
  test   %edi,%edi
  je     L15
  cmp    $0x1,%edi
  lea    D36(%rip),%rax
  lea    D47(%rip),%rdx
  cmove  %rdx,%rax
  ret
L9:
  cmp    $0x3,%edi
  lea    D36(%rip),%rax
  lea    D19(%rip),%rdx
  cmove  %rdx,%rax
L15:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D8
type_guessed: string
name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D47
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string

tool: D9: Up

tool: D8: Left

tool: 

tool: D47: Right

tool: D19: Down

assistant: ```c
char *getDirectionString(int num) {
  switch (num) {
  case 0:
    return "Left";
  case 1:
    return "Right";
  case 2:
    return "Up";
  case 3:
    return "Down";
  default:
    return "";
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getDirectionString>:
  endbr64
  lea    D52(%rip),%rax
  cmp    $0x2,%edi
  je     L8
  jg     L1
  lea    D35(%rip),%rax
  test   %edi,%edi
  je     L8
  cmp    $0x1,%edi
  lea    D56(%rip),%rdx
  lea    D17(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    $0x3,%edi
  lea    D17(%rip),%rax
  lea    D14(%rip),%rdx
  cmove  %rdx,%rax
L8:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D52
type: string
name: parse_data
arguments: data_label: D35
type: string
name: parse_data
arguments: data_label: D56
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D14
type: string

tool: D52: Up

tool: D35: Left

tool: D56: Right

tool: 

tool: D14: Down

assistant: ```c
char *getDirectionString(int num) {
  switch (num) {
  case 0:
    return "Left";
  case 1:
    return "Right";
  case 2:
    return "Up";
  case 3:
    return "Down";
  default:
    return "";
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getDirectionString>:
  endbr64
  lea    D38(%rip),%rax
  cmp    $0x2,%edi
  je     L23
  jg     L1
  lea    D22(%rip),%rax
  test   %edi,%edi
  je     L23
  cmp    $0x1,%edi
  lea    D35(%rip),%rdx
  lea    D14(%rip),%rax
  cmove  %rdx,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  cmp    $0x3,%edi
  lea    D14(%rip),%rax
  lea    D11(%rip),%rdx
  cmove  %rdx,%rax
L23:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D38
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D35
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string
name: retrieve_data
arguments: tag: D11
type_guessed: string

tool: D38: Up

tool: D22: Left

tool: D35: Right

tool: 

tool: D11: Down

assistant: ```c
char *getDirectionString(int num) {
  switch (num) {
  case 0:
    return "Left";
  case 1:
    return "Right";
  case 2:
    return "Up";
  case 3:
    return "Down";
  default:
    return "";
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D73(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D67
type_infered: string
name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D73
type_infered: string
name: read_data
arguments: data_label: D77
type_infered: string
name: read_data
arguments: data_label: D33
type_infered: string
name: read_data
arguments: data_label: D48
type_infered: string
name: read_data
arguments: data_label: D22
type_infered: string

tool: D67: 
Usage:


tool: D21: ------


tool: D0: lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.


tool: D73: lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.



tool: D77: Examples:


tool: D33: ---------


tool: D48: lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.


tool: D22: lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.



assistant: ```c
void help() {
  printf("\nUsage:\n");
  printf("------\n");
  printf("lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.\n");
  printf("lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.\n\n");
  printf("Examples:\n");
  printf("---------\n");
  printf("lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.\n");
  printf("lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D64(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D64
datatype: string
name: extract_symbolic_data
arguments: data_label: D73
datatype: string
name: extract_symbolic_data
arguments: data_label: D59
datatype: string
name: extract_symbolic_data
arguments: data_label: D45
datatype: string
name: extract_symbolic_data
arguments: data_label: D31
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D61
datatype: string

tool: D64: 
Usage:


tool: D73: ------


tool: D59: lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.


tool: D45: lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.



tool: D31: Examples:


tool: D28: ---------


tool: D3: lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.


tool: D61: lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.



assistant: ```c
void help() {
  printf("\nUsage:\n");
  printf("------\n");
  printf("lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.\n");
  printf("lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.\n\n");
  printf("Examples:\n");
  printf("---------\n");
  printf("lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.\n");
  printf("lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.\n\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D71(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D39
data_type: string
name: disassemble_data
arguments: tag: D42
data_type: string
name: disassemble_data
arguments: tag: D30
data_type: string
name: disassemble_data
arguments: tag: D11
data_type: string
name: disassemble_data
arguments: tag: D73
data_type: string
name: disassemble_data
arguments: tag: D24
data_type: string
name: disassemble_data
arguments: tag: D71
data_type: string
name: disassemble_data
arguments: tag: D67
data_type: string

tool: D39: 
Usage:


tool: D42: ------


tool: D30: lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.


tool: D11: lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.



tool: D73: Examples:


tool: D24: ---------


tool: D71: lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.


tool: D67: lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.



assistant: ```c
void help() {
  printf("\nUsage:\n");
  printf("------\n");
  printf("lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.\n");
  printf("lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.\n\n");
  printf("Examples:\n");
  printf("---------\n");
  printf("lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.\n");
  printf("lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.\n\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D25
type_guessed: string
name: read_data
arguments: tag: D48
type_guessed: string
name: read_data
arguments: tag: D77
type_guessed: string
name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D35
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D22
type_guessed: string

tool: D3: 
Usage:


tool: D25: ------


tool: D48: lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.


tool: D77: lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.



tool: D4: Examples:


tool: D35: ---------


tool: D13: lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.


tool: D22: lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.



assistant: ```c
void help() {
  printf("\nUsage:\n");
  printf("------\n");
  printf("lexperm N -- N is the order of the permutation. Generates all the permutations of the given order.\n");
  printf("lexperm PERMUTATION -- PERMUTATION is a permutation of n order with its digits space separated. Generates the next lexicographic permutation.\n\n");
  printf("Examples:\n");
  printf("---------\n");
  printf("lexperm 4 -- Generates all the permutations of order 4 in lexicographic order. The number of the permutations is n! so beware of the N.\n");
  printf("lexperm 2 4 1 3 -- Generates the next permutation in lexicographic order.\n\n");
}
```