ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<draw_arc>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int draw_arc(long x_0, long y_0, long w, long h, int th1, int th2, int mode) {
  x_0 = x_0;
  y_0 = y_0;
  w = w;
  h = h;
  th1 = th1;
  th2 = th2;
  mode = mode;
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<draw_arc>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int draw_arc(long x_0, long y_0, long w, long h, int th1, int th2, int mode) {
  x_0 = x_0;
  y_0 = y_0;
  w = w;
  h = h;
  th1 = th1;
  th2 = th2;
  mode = mode;
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main() {
  int var1 = 1;
  int var2 = 2;
  foo(var1);
  return var2;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int var1 = 1;
  int var2 = 2;
  foo(var1);
  return var2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int var1 = 1;
  int var2 = 2;
  foo(var1);
  return var2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x2,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int var1 = 1;
  int var2 = 2;
  foo(var1);
  return var2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<scramble_ata_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void scramble_ata_string(char *str, int size) {
  int i;
  char tmp;
  for (i = 0; i < size; i += 2) {
    tmp = str[i];
    str[i] = str[i + 1];
    str[i + 1] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<scramble_ata_string>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rax
  sub    $0x1,%esi
  shr    %esi
  mov    %esi,%esi
  lea    0x2(%rdi,%rsi,2),%rsi
L13:
  movzbl (%rax),%edx
  movzbl 0x1(%rax),%ecx
  mov    %cl,(%rax)
  mov    %dl,0x1(%rax)
  add    $0x2,%rax
  cmp    %rsi,%rax
  jne    L13
L17:
  ret
```

assistant: ```c
void scramble_ata_string(char *str, int size) {
  int i;
  char tmp;
  for (i = 0; i < size; i += 2) {
    tmp = str[i];
    str[i] = str[i + 1];
    str[i + 1] = tmp;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<scramble_ata_string>:
  endbr64
  test   %esi,%esi
  jle    L5
  sub    $0x1,%esi
  shr    %esi
  lea    0x2(%rdi,%rsi,2),%rcx
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  add    $0x2,%rdi
  mov    %dl,-0x2(%rdi)
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%rdi
  jne    L9
L5:
  ret
```

assistant: ```c
void scramble_ata_string(char *str, int size) {
  int i;
  char tmp;
  for (i = 0; i < size; i += 2) {
    tmp = str[i];
    str[i] = str[i + 1];
    str[i + 1] = tmp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<triggerDivZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <retZero@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x5,%eax
  cltd
  idivl  -0x4(%rbp)
  leave
  ret
```

assistant: ```c
int triggerDivZero() {
  int y = retZero();
  return 5 / y;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<triggerDivZero>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <retZero@plt>
  mov    %eax,%ecx
  mov    $0x5,%eax
  cltd
  idiv   %ecx
  add    $0x8,%rsp
  ret
```

assistant: ```c
int triggerDivZero() {
  int y = retZero();
  return 5 / y;
}
```
user: What is the c source code of the assembly code below:

```asm
<triggerDivZero>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <retZero@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    $0x5,%eax
  cltd
  idiv   %r8d
  ret
```

assistant: ```c
int triggerDivZero() {
  int y = retZero();
  return 5 / y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<triggerDivZero>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <retZero@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    $0x5,%eax
  cltd
  idiv   %r8d
  ret
```

assistant: ```c
int triggerDivZero() {
  int y = retZero();
  return 5 / y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<complete_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %esi,-0xe8(%rbp)
  mov    %rdx,-0xf0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xe4(%rbp),%eax
  mov    %eax,-0xe0(%rbp)
  mov    -0xe8(%rbp),%eax
  mov    %eax,-0xdc(%rbp)
  mov    -0xe0(%rbp),%edx
  mov    -0xdc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  D8(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xd8(%rbp)
  mov    -0xe4(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <format_iso8601@plt>
  mov    %eax,-0xd4(%rbp)
  cmpl   $0x0,-0xd4(%rbp)
  je     L5
  mov    -0xd4(%rbp),%eax
  jmp    L21
L5:
  mov    -0xd8(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <make_message@plt>
  mov    -0xf0(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x1,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type_guessed: f64
name: disassemble_data
arguments: data_label: D18
type_guessed: string

tool: D8: 0.5

tool: D18: %s--PT%dS

assistant: ```c
int complete_name(int64_t start, int64_t end, char **result) {
  time_t start_time = (time_t)start;
  time_t end_time = (time_t)end;
  int duration = (int)(difftime(end_time, start_time) + 0.5);
  char start_str[200];
  int ret = format_iso8601(start_str, sizeof(start_str), start);
  if (ret)
    return ret;
  *result = make_message("%s--PT%dS", start_str, duration);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<complete_name>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %edi,%ebx
  mov    %esi,%edi
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <difftime@plt>
  mov    %rax,%r12
  mov    %rsp,%rdi
  mov    %ebx,%edx
  mov    $0xc8,%esi
  call   <format_iso8601@plt>
  test   %eax,%eax
  je     L13
L17:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12,%xmm0
  addsd  D0(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <make_message@plt>
  mov    %rax,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L17
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: f64
name: read_data
arguments: tag: D17
datatype: string

tool: D0: 0.5

tool: D17: %s--PT%dS

assistant: ```c
int complete_name(int64_t start, int64_t end, char **result) {
  time_t start_time = (time_t)start;
  time_t end_time = (time_t)end;
  int duration = (int)(difftime(end_time, start_time) + 0.5);
  char start_str[200];
  int ret = format_iso8601(start_str, sizeof(start_str), start);
  if (ret)
    return ret;
  *result = make_message("%s--PT%dS", start_str, duration);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<complete_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  mov    %r12d,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <difftime@plt>
  mov    %r12d,%edx
  mov    $0xc8,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <format_iso8601@plt>
  test   %eax,%eax
  jne    L17
  pxor   %xmm0,%xmm0
  mov    %r13,%rsi
  lea    D13(%rip),%rdi
  cvtsi2sd %rbp,%xmm0
  addsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  call   <make_message@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L17:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: f64

tool: D13: %s--PT%dS

tool: D19: 0.5

assistant: ```c
int complete_name(int64_t start, int64_t end, char **result) {
  time_t start_time = (time_t)start;
  time_t end_time = (time_t)end;
  int duration = (int)(difftime(end_time, start_time) + 0.5);
  char start_str[200];
  int ret = format_iso8601(start_str, sizeof(start_str), start);
  if (ret)
    return ret;
  *result = make_message("%s--PT%dS", start_str, duration);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<complete_name>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %esi,%edi
  push   %rbp
  mov    %r12d,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <difftime@plt>
  mov    %r12d,%edx
  mov    $0xc8,%esi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <format_iso8601@plt>
  test   %eax,%eax
  jne    L11
  pxor   %xmm0,%xmm0
  mov    %r13,%rsi
  lea    D9(%rip),%rdi
  cvtsi2sd %rbp,%xmm0
  addsd  D8(%rip),%xmm0
  cvttsd2si %xmm0,%edx
  call   <make_message@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L11:
  mov    0xc8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D8
type_infered: f64

tool: D9: %s--PT%dS

tool: D8: 0.5

assistant: ```c
int complete_name(int64_t start, int64_t end, char **result) {
  time_t start_time = (time_t)start;
  time_t end_time = (time_t)end;
  int duration = (int)(difftime(end_time, start_time) + 0.5);
  char start_str[200];
  int ret = format_iso8601(start_str, sizeof(start_str), start);
  if (ret)
    return ret;
  *result = make_message("%s--PT%dS", start_str, duration);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UPnPConnectionManager_PrepareForConnection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x28(%rbp),%rsi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x61a8,%ecx
  mov    $0x61a8,%edx
  mov    $0x61a8,%esi
  mov    %rax,%rdi
  call   <UPnPResponse_ConnectionManager_PrepareForConnection@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);


assistant: ```c
void UPnPConnectionManager_PrepareForConnection(void *upnptoken, char *RemoteProtocolInfo, char *PeerConnectionManager, int PeerConnectionID, char *Direction) {
  printf("Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);\r\n", RemoteProtocolInfo, PeerConnectionManager, PeerConnectionID, Direction);
  UPnPResponse_ConnectionManager_PrepareForConnection(upnptoken, 25000, 25000, 25000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UPnPConnectionManager_PrepareForConnection>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x61a8,%ecx
  mov    $0x61a8,%edx
  mov    $0x61a8,%esi
  mov    %rbx,%rdi
  call   <UPnPResponse_ConnectionManager_PrepareForConnection@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_infered: string

tool: D3: Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);


assistant: ```c
void UPnPConnectionManager_PrepareForConnection(void *upnptoken, char *RemoteProtocolInfo, char *PeerConnectionManager, int PeerConnectionID, char *Direction) {
  printf("Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);\r\n", RemoteProtocolInfo, PeerConnectionManager, PeerConnectionID, Direction);
  UPnPResponse_ConnectionManager_PrepareForConnection(upnptoken, 25000, 25000, 25000);
}
```
user: What is the c source code of the assembly code below:

```asm
<UPnPConnectionManager_PrepareForConnection>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x61a8,%ecx
  pop    %rbp
  mov    $0x61a8,%edx
  mov    $0x61a8,%esi
  jmp    1070 <UPnPResponse_ConnectionManager_PrepareForConnection@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);


assistant: ```c
void UPnPConnectionManager_PrepareForConnection(void *upnptoken, char *RemoteProtocolInfo, char *PeerConnectionManager, int PeerConnectionID, char *Direction) {
  printf("Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);\r\n", RemoteProtocolInfo, PeerConnectionManager, PeerConnectionID, Direction);
  UPnPResponse_ConnectionManager_PrepareForConnection(upnptoken, 25000, 25000, 25000);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UPnPConnectionManager_PrepareForConnection>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x61a8,%ecx
  pop    %rbp
  mov    $0x61a8,%edx
  mov    $0x61a8,%esi
  jmp    1070 <UPnPResponse_ConnectionManager_PrepareForConnection@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);


assistant: ```c
void UPnPConnectionManager_PrepareForConnection(void *upnptoken, char *RemoteProtocolInfo, char *PeerConnectionManager, int PeerConnectionID, char *Direction) {
  printf("Invoke: UPnPConnectionManager_PrepareForConnection(%s,%s,%d,%s);\r\n", RemoteProtocolInfo, PeerConnectionManager, PeerConnectionID, Direction);
  UPnPResponse_ConnectionManager_PrepareForConnection(upnptoken, 25000, 25000, 25000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcsncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L48
L8:
  addq   $0x8,-0x8(%rbp)
  addq   $0x8,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L48:
  cmpq   $0x0,-0x18(%rbp)
  je     L34
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L34
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L8
L34:
  cmpq   $0x0,-0x18(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L21
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *ws1, const wchar_t *ws2, size_t n) {
  while (n && *ws1 && *ws1 == *ws2) {
    ++ws1;
    ++ws2;
    --n;
  }
  if (n == 0) {
    return 0;
  }
  return *ws1 - *ws2;
}
```
user: What is the c source code of the assembly code below?

```asm
<wcsncmp>:
  endbr64
  test   %rdx,%rdx
  je     L42
L39:
  mov    (%rdi),%rax
  test   %rax,%rax
  je     L26
  cmp    (%rsi),%rax
  jne    L26
  add    $0x8,%rdi
  add    $0x8,%rsi
  sub    $0x1,%rdx
  jne    L39
  mov    $0x0,%eax
  ret
L42:
  mov    $0x0,%eax
  ret
L26:
  test   %rdx,%rdx
  je     L31
  mov    (%rdi),%rax
  sub    (%rsi),%eax
  ret
L31:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *ws1, const wchar_t *ws2, size_t n) {
  while (n && *ws1 && *ws1 == *ws2) {
    ++ws1;
    ++ws2;
    --n;
  }
  if (n == 0) {
    return 0;
  }
  return *ws1 - *ws2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wcsncmp>:
  endbr64
  xor    %ecx,%ecx
  test   %rdx,%rdx
  jne    L44
  jmp    L23
  nopl   (%rax)
L6:
  cmp    %r8,%rax
  jne    L18
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L23
L44:
  mov    (%rdi,%rcx,8),%rax
  mov    (%rsi,%rcx,8),%r8
  test   %rax,%rax
  jne    L6
L18:
  sub    %r8d,%eax
  ret
  nop
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *ws1, const wchar_t *ws2, size_t n) {
  while (n && *ws1 && *ws1 == *ws2) {
    ++ws1;
    ++ws2;
    --n;
  }
  if (n == 0) {
    return 0;
  }
  return *ws1 - *ws2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcsncmp>:
  endbr64
  xor    %ecx,%ecx
  test   %rdx,%rdx
  jne    L2
  jmp    L40
  nopl   (%rax)
L36:
  cmp    %r8,%rax
  jne    L13
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L40
L2:
  mov    (%rdi,%rcx,8),%rax
  mov    (%rsi,%rcx,8),%r8
  test   %rax,%rax
  jne    L36
L13:
  sub    %r8d,%eax
  ret
  nop
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
int wcsncmp(const wchar_t *ws1, const wchar_t *ws2, size_t n) {
  while (n && *ws1 && *ws1 == *ws2) {
    ++ws1;
    ++ws2;
    --n;
  }
  if (n == 0) {
    return 0;
  }
  return *ws1 - *ws2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<job>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <sleep@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D26
type_infered: string

tool: D29: job

tool: D13: %10s(): starting number %d


tool: D26: %10s(): completed number %d


assistant: ```c
void *job(int input) {
  printf("%10s(): starting number %d\n", __FUNCTION__, input);
  sleep(1);
  printf("%10s(): completed number %d\n", __FUNCTION__, input);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<job>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %edi,%edx
  lea    D9(%rip),%rbp
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <sleep@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D13
datatype: string

tool: D9: job

tool: D14: %10s(): starting number %d


tool: D13: %10s(): completed number %d


assistant: ```c
void *job(int input) {
  printf("%10s(): starting number %d\n", __FUNCTION__, input);
  sleep(1);
  printf("%10s(): completed number %d\n", __FUNCTION__, input);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<job>:
  endbr64
  push   %r12
  mov    %edi,%edx
  mov    %edi,%r12d
  xor    %eax,%eax
  push   %rbp
  lea    D8(%rip),%rbp
  lea    D20(%rip),%rdi
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <sleep@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string

tool: D8: job

tool: D20: %10s(): starting number %d


tool: D17: %10s(): completed number %d


assistant: ```c
void *job(int input) {
  printf("%10s(): starting number %d\n", __FUNCTION__, input);
  sleep(1);
  printf("%10s(): completed number %d\n", __FUNCTION__, input);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<job>:
  endbr64
  push   %r12
  mov    %edi,%edx
  mov    %edi,%r12d
  xor    %eax,%eax
  push   %rbp
  lea    D12(%rip),%rbp
  lea    D29(%rip),%rdi
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <sleep@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D29
type_guessed: string
name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D12: job

tool: D29: %10s(): starting number %d


tool: D17: %10s(): completed number %d


assistant: ```c
void *job(int input) {
  printf("%10s(): starting number %d\n", __FUNCTION__, input);
  sleep(1);
  printf("%10s(): completed number %d\n", __FUNCTION__, input);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<agrega_el_mil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string

tool: D5: mil

assistant: ```c
int agrega_el_mil(char *buffer) {
  int len = 3;
  strncat(buffer, "mil", len);
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<agrega_el_mil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D4(%rip),%rsi
  call   <strncat@plt>
  mov    $0x3,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: mil

assistant: ```c
int agrega_el_mil(char *buffer) {
  int len = 3;
  strncat(buffer, "mil", len);
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<agrega_el_mil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D5(%rip),%rsi
  call   <strncat@plt>
  mov    $0x3,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: mil

assistant: ```c
int agrega_el_mil(char *buffer) {
  int len = 3;
  strncat(buffer, "mil", len);
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<agrega_el_mil>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  lea    D5(%rip),%rsi
  call   <strncat@plt>
  mov    $0x3,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5: mil

assistant: ```c
int agrega_el_mil(char *buffer) {
  int len = 3;
  strncat(buffer, "mil", len);
  return len;
}
```