ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itob>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r9d
  mov    %rsi,%rdi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L6:
  cltd
  idiv   %r9d
  cmp    $0xa,%edx
  lea    0x37(%rdx),%r10d
  lea    0x30(%rdx),%r8d
  movslq %ecx,%rdx
  cmovge %r10d,%r8d
  mov    %r8b,-0x1(%rdi,%rcx,1)
  add    $0x1,%rcx
  test   %eax,%eax
  jg     L6
  movb   $0x0,(%rdi,%rdx,1)
  jmp    1050 <reverse@plt>
```

assistant: ```c
void itob(int n, char s[], int base) {
  int i = 0, tmp;
  do {
    tmp = n % base;
    s[i++] = tmp > 9 ? 'A' + tmp - 10 : '0' + tmp;
  } while ((n /= base) > 0);
  s[i] = '\0';
  reverse(s);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itob>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    %rsi,%rdi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L13:
  cltd
  movslq %ecx,%rsi
  idiv   %r8d
  cmp    $0x9,%edx
  jle    L6
  add    $0x37,%edx
  mov    %dl,-0x1(%rdi,%rcx,1)
  add    $0x1,%rcx
  test   %eax,%eax
  jg     L13
  movb   $0x0,(%rdi,%rsi,1)
  jmp    1050 <reverse@plt>
  nopl   0x0(%rax)
L6:
  add    $0x30,%edx
  mov    %dl,-0x1(%rdi,%rcx,1)
  add    $0x1,%rcx
  test   %eax,%eax
  jg     L13
  movb   $0x0,(%rdi,%rsi,1)
  jmp    1050 <reverse@plt>
```

assistant: ```c
void itob(int n, char s[], int base) {
  int i = 0, tmp;
  do {
    tmp = n % base;
    s[i++] = tmp > 9 ? 'A' + tmp - 10 : '0' + tmp;
  } while ((n /= base) > 0);
  s[i] = '\0';
  reverse(s);
}
```
user: What is the c source code of the assembly code below?

```asm
<strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L24
L44:
  addq   $0x1,-0x20(%rbp)
L24:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  je     L28
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
L28:
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L32
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L5
L62:
  cmpq   $0x1,-0x10(%rbp)
  je     L65
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L65:
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L5:
  leave
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz, dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlcat>:
  endbr64
  push   %rbx
  test   %rdx,%rdx
  je     L57
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
L4:
  cmpb   $0x0,(%rax)
  je     L24
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L4
  mov    %rcx,%rax
L24:
  mov    %rax,%rbx
  sub    %r8,%rbx
  sub    %rbx,%rdx
  je     L69
  movzbl (%rsi),%r8d
  mov    %rsi,%rcx
  test   %r8b,%r8b
  jne    L14
L26:
  movb   $0x0,(%rax)
  sub    %rsi,%rcx
  lea    (%rcx,%rbx,1),%rax
L27:
  pop    %rbx
  ret
L57:
  mov    %rdx,%rbx
L69:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  jmp    L27
L53:
  add    $0x1,%rcx
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L26
L14:
  cmp    $0x1,%rdx
  je     L53
  mov    %r8b,(%rax)
  sub    $0x1,%rdx
  lea    0x1(%rax),%rax
  jmp    L53
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz, dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlcat>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L104
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L106:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L30
L45:
  cmpb   $0x0,(%rax)
  jne    L106
L30:
  mov    %rax,%r12
  sub    %r8,%r12
  sub    %r12,%rdx
  je     L16
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  jne    L89
  jmp    L81
  nopl   (%rax)
L43:
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  mov    %r8,%rcx
  add    $0x1,%rax
L48:
  lea    0x1(%rcx),%r8
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L84
L89:
  cmp    $0x1,%rdx
  jne    L43
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rcx
  jne    L48
  sub    %rsi,%rcx
  add    %rcx,%r12
L81:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L84:
  sub    %rsi,%r8
  add    %r8,%r12
  jmp    L81
L104:
  xor    %r12d,%r12d
L16:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz, dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlcat>:
  endbr64
  push   %r12
  test   %rdx,%rdx
  je     L25
  mov    %rdi,%r8
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rax
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L19
L64:
  cmpb   $0x0,(%rax)
  jne    L50
L19:
  mov    %rax,%r12
  sub    %r8,%r12
  sub    %r12,%rdx
  je     L99
  movzbl (%rsi),%ecx
  mov    %rsi,%r8
  test   %cl,%cl
  jne    L44
  jmp    L104
  nopl   (%rax)
L74:
  mov    %cl,(%rax)
  sub    $0x1,%rdx
  mov    %r8,%rcx
  add    $0x1,%rax
L4:
  lea    0x1(%rcx),%r8
  movzbl 0x1(%rcx),%ecx
  test   %cl,%cl
  je     L62
L44:
  cmp    $0x1,%rdx
  jne    L74
  cmpb   $0x0,0x1(%r8)
  lea    0x1(%r8),%rcx
  jne    L4
  sub    %rsi,%rcx
  add    %rcx,%r12
L104:
  movb   $0x0,(%rax)
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L62:
  sub    %rsi,%r8
  add    %r8,%r12
  jmp    L104
L25:
  xor    %r12d,%r12d
L99:
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
size_t strlcat(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz, dlen;
  while (n-- != 0 && *d != '\0')
    d++;
  dlen = d - dst;
  n = siz - dlen;
  if (n == 0)
    return (dlen + strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dlen + (s - src));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<h_u32_to_be>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void h_u32_to_be(uint8_t *buf, int val) {
  buf[0] = (uint8_t)(val >> 24);
  buf[1] = (uint8_t)(val >> 16);
  buf[2] = (uint8_t)(val >> 8);
  buf[3] = (uint8_t)(val >> 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<h_u32_to_be>:
  endbr64
  mov    %esi,%eax
  sar    $0x18,%eax
  cltq
  mov    %rax,(%rdi)
  mov    %esi,%eax
  sar    $0x10,%eax
  cltq
  mov    %rax,0x8(%rdi)
  mov    %esi,%eax
  sar    $0x8,%eax
  cltq
  mov    %rax,0x10(%rdi)
  movslq %esi,%rsi
  mov    %rsi,0x18(%rdi)
  ret
```

assistant: ```c
void h_u32_to_be(uint8_t *buf, int val) {
  buf[0] = (uint8_t)(val >> 24);
  buf[1] = (uint8_t)(val >> 16);
  buf[2] = (uint8_t)(val >> 8);
  buf[3] = (uint8_t)(val >> 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<h_u32_to_be>:
  endbr64
  mov    %esi,%eax
  sar    $0x18,%eax
  cltq
  mov    %rax,(%rdi)
  mov    %esi,%eax
  sar    $0x10,%eax
  cltq
  mov    %rax,0x8(%rdi)
  mov    %esi,%eax
  movslq %esi,%rsi
  sar    $0x8,%eax
  mov    %rsi,0x18(%rdi)
  cltq
  mov    %rax,0x10(%rdi)
  ret
```

assistant: ```c
void h_u32_to_be(uint8_t *buf, int val) {
  buf[0] = (uint8_t)(val >> 24);
  buf[1] = (uint8_t)(val >> 16);
  buf[2] = (uint8_t)(val >> 8);
  buf[3] = (uint8_t)(val >> 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<h_u32_to_be>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  movd   %esi,%xmm3
  sar    $0x18,%eax
  sar    $0x8,%edx
  movd   %eax,%xmm0
  mov    %esi,%eax
  movd   %edx,%xmm1
  sar    $0x10,%eax
  punpckldq %xmm3,%xmm1
  movd   %eax,%xmm4
  punpckldq %xmm4,%xmm0
  punpcklqdq %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  punpckldq %xmm1,%xmm2
  punpckhdq %xmm1,%xmm0
  movups %xmm2,(%rdi)
  movups %xmm0,0x10(%rdi)
  ret
```

assistant: ```c
void h_u32_to_be(uint8_t *buf, int val) {
  buf[0] = (uint8_t)(val >> 24);
  buf[1] = (uint8_t)(val >> 16);
  buf[2] = (uint8_t)(val >> 8);
  buf[3] = (uint8_t)(val >> 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<symbolic_index2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L16
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x10(%rbp,%rax,4),%eax
  jmp    L28
L16:
  mov    $0x0,%eax
L28:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
int symbolic_index2(int a) {
  int x[2] = {1, 2};
  if (a < 0) {
    return x[a];
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<symbolic_index2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  test   %edi,%edi
  js     L20
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L20:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  jmp    L29
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int symbolic_index2(int a) {
  int x[2] = {1, 2};
  if (a < 0) {
    return x[a];
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<symbolic_index2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L14
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
  nop
L14:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  jmp    L1
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int symbolic_index2(int a) {
  int x[2] = {1, 2};
  if (a < 0) {
    return x[a];
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<symbolic_index2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rax,(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L1
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L1:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  jmp    L17
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
datatype: byte[8]

tool: {"D4": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int symbolic_index2(int a) {
  int x[2] = {1, 2};
  if (a < 0) {
    return x[a];
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generePQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L4
L12:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <estPremier@plt>
  cmp    $0x1,%eax
  jne    L33
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L33:
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,-0x8(%rbp)
L4:
  cmpl   $0x0,-0xc(%rbp)
  jne    L12
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long generePQ() {
  long p = random_numberC(100);
  int boolean = 1;
  while (boolean) {
    if (estPremier(p) == 1) {
      boolean = 0;
    } else {
      p = random_numberC(100);
    }
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<generePQ>:
  endbr64
  push   %rbx
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,%rbx
  jmp    L14
L12:
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,%rbx
L14:
  mov    %rbx,%rdi
  call   <estPremier@plt>
  cmp    $0x1,%eax
  jne    L12
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
long generePQ() {
  long p = random_numberC(100);
  int boolean = 1;
  while (boolean) {
    if (estPremier(p) == 1) {
      boolean = 0;
    } else {
      p = random_numberC(100);
    }
  }
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generePQ>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,%r12
  jmp    L9
  nopl   (%rax)
L4:
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,%r12
L9:
  mov    %r12,%rdi
  call   <estPremier@plt>
  cmp    $0x1,%eax
  jne    L4
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long generePQ() {
  long p = random_numberC(100);
  int boolean = 1;
  while (boolean) {
    if (estPremier(p) == 1) {
      boolean = 0;
    } else {
      p = random_numberC(100);
    }
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generePQ>:
  endbr64
  push   %r12
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,%r12
  jmp    L17
  nopl   (%rax)
L10:
  mov    $0x64,%edi
  call   <random_numberC@plt>
  mov    %rax,%r12
L17:
  mov    %r12,%rdi
  call   <estPremier@plt>
  cmp    $0x1,%eax
  jne    L10
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
long generePQ() {
  long p = random_numberC(100);
  int boolean = 1;
  while (boolean) {
    if (estPremier(p) == 1) {
      boolean = 0;
    } else {
      p = random_numberC(100);
    }
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<buildymd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <month2num@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  add    $0x30,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7: %04d%02d%02d

assistant: ```c
void buildymd(const char *dia, const char *mes, const char *ano, char *wdata) {
  int nmes;
  nmes = month2num(mes);
  sprintf(wdata, "%04d%02d%02d", atoi(ano), nmes + 1, atoi(dia));
}
```
user: What is the c source code of the assembly code below?

```asm
<buildymd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%r13
  mov    %rcx,%rbp
  call   <month2num@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  lea    0x1(%rbx),%ecx
  mov    %r12d,%r8d
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: %04d%02d%02d

assistant: ```c
void buildymd(const char *dia, const char *mes, const char *ano, char *wdata) {
  int nmes;
  nmes = month2num(mes);
  sprintf(wdata, "%04d%02d%02d", atoi(ano), nmes + 1, atoi(dia));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<buildymd>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <month2num@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%ecx
  mov    %r12d,%r8d
  pop    %rbx
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  lea    D9(%rip),%rsi
  pop    %r12
  pop    %r13
  jmp    1090 <sprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: %04d%02d%02d

assistant: ```c
void buildymd(const char *dia, const char *mes, const char *ano, char *wdata) {
  int nmes;
  nmes = month2num(mes);
  sprintf(wdata, "%04d%02d%02d", atoi(ano), nmes + 1, atoi(dia));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<buildymd>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <month2num@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  add    $0x8,%rsp
  lea    0x1(%rbx),%ecx
  mov    %r12d,%r8d
  pop    %rbx
  mov    %rbp,%rdi
  mov    %eax,%edx
  pop    %rbp
  lea    D0(%rip),%rsi
  pop    %r12
  pop    %r13
  jmp    1090 <sprintf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D0: %04d%02d%02d

assistant: ```c
void buildymd(const char *dia, const char *mes, const char *ano, char *wdata) {
  int nmes;
  nmes = month2num(mes);
  sprintf(wdata, "%04d%02d%02d", atoi(ano), nmes + 1, atoi(dia));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L69
L104:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x61,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x41,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x65,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x45,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x69,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x49,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x6f,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x75,%al
  je     L31
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x55,%al
  jne    L12
L31:
  addl   $0x1,-0x78(%rbp)
L12:
  addl   $0x1,-0x7c(%rbp)
L69:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L104
  mov    -0x78(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L114
  call   <__stack_chk_fail@plt>
L114:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D15
type_infered: string

tool: D4: 
Entre com uma frase:

tool: D15: 
Esta frase possui %d vogais.

assistant: ```c
int main() {
  char frase[100];
  int tam, i, vogal = 0;
  printf("\nEntre com uma frase:");
  gets(frase);
  tam = strlen(frase);
  for (i = 0; i < tam; i++) {
    if (frase[i] == 'a' || frase[i] == 'A' || frase[i] == 'e' || frase[i] == 'E' || frase[i] == 'i' || frase[i] == 'I' || frase[i] == 'o' || frase[i] == 'O' || frase[i] == 'u' || frase[i] == 'U') {
      vogal++;
    }
  }
  printf("\nEsta frase possui %d vogais.", vogal);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L47
  mov    %rsp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rsp,%rax,1),%rdi
  mov    $0x0,%esi
  movabs $0x1041100010411,%r8
  jmp    L49
L50:
  add    $0x1,%esi
L53:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L26
L49:
  movzbl (%rdx),%eax
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  cmp    $0x41,%cl
  je     L50
  sub    $0x45,%eax
  cmp    $0x30,%al
  ja     L53
  bt     %rax,%r8
  jae    L53
  jmp    L50
L47:
  mov    $0x0,%esi
L26:
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D15
data_type: string
name: retrieve_data
arguments: tag: D13
data_type: string

tool: D15: 
Entre com uma frase:

tool: D13: 
Esta frase possui %d vogais.

assistant: ```c
int main() {
  char frase[100];
  int tam, i, vogal = 0;
  printf("\nEntre com uma frase:");
  gets(frase);
  tam = strlen(frase);
  for (i = 0; i < tam; i++) {
    if (frase[i] == 'a' || frase[i] == 'A' || frase[i] == 'e' || frase[i] == 'E' || frase[i] == 'i' || frase[i] == 'I' || frase[i] == 'o' || frase[i] == 'O' || frase[i] == 'u' || frase[i] == 'U') {
      vogal++;
    }
  }
  printf("\nEsta frase possui %d vogais.", vogal);
  return 0;
}
```