ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L3
L4:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <randint@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void shuf(int *a, int n) {
  int i, j, t;
  for (i = 0; i < n - 1; i++) {
    j = i + randint(n - i);
    t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shuf>:
  endbr64
  cmp    $0x1,%esi
  jle    L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    -0x2(%rsi),%r13d
  mov    $0x0,%ebx
L17:
  mov    %r12d,%edi
  sub    %ebx,%edi
  call   <randint@plt>
  mov    0x0(%rbp,%rbx,4),%edx
  add    %ebx,%eax
  cltq
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%rbp,%rbx,4)
  mov    %edx,(%rax)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %r13,%rax
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  ret
```

assistant: ```c
void shuf(int *a, int n) {
  int i, j, t;
  for (i = 0; i < n - 1; i++) {
    j = i + randint(n - i);
    t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shuf>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x2(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L19:
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <randint@plt>
  mov    0x0(%r13,%rbx,4),%edx
  add    %ebx,%eax
  cltq
  lea    0x0(%r13,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%r13,%rbx,4)
  mov    %edx,(%rax)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %r12,%rax
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void shuf(int *a, int n) {
  int i, j, t;
  for (i = 0; i < n - 1; i++) {
    j = i + randint(n - i);
    t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shuf>:
  endbr64
  cmp    $0x1,%esi
  jle    L17
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    -0x2(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L1:
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <randint@plt>
  mov    0x0(%r13,%rbx,4),%edx
  add    %ebx,%eax
  cltq
  lea    0x0(%r13,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %ecx,0x0(%r13,%rbx,4)
  mov    %edx,(%rax)
  mov    %rbx,%rax
  add    $0x1,%rbx
  cmp    %r12,%rax
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
```

assistant: ```c
void shuf(int *a, int n) {
  int i, j, t;
  for (i = 0; i < n - 1; i++) {
    j = i + randint(n - i);
    t = a[i];
    a[i] = a[j];
    a[j] = t;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0xa,-0x24(%rbp)
  movl   $0x1,-0x1c(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L10
L49:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,0x8(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x20(%rbp)
L10:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L49
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x20(%rbp)
  jmp    L43
L20:
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x20(%rbp)
L43:
  cmpl   $0x9,-0x20(%rbp)
  jle    L20
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L65
L79:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L28
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
  subl   $0x1,-0x24(%rbp)
L28:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x18(%rbp)
L65:
  cmpl   $0x1,-0x24(%rbp)
  jg     L79
  movl   $0x0,-0x20(%rbp)
  jmp    L21
L11:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L62
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L62:
  addl   $0x1,-0x20(%rbp)
L21:
  cmpl   $0x9,-0x20(%rbp)
  jle    L11
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string

tool: D6: %d

assistant: ```c
int main() {
  struct ber {
    int num;
    struct ber *next;
  };
  int n = 10, m, k = 1;
  struct ber *p, *q, *head;
  head = q = malloc(sizeof(struct ber));
  for (m = 0; m < n - 1; m++) {
    p = malloc(sizeof(struct ber));
    q->next = p;
    q = p;
  }
  p->next = head;
  p = head;
  for (m = 1; m < 10; m++) {
    p->num = 1;
    p = p->next;
  }
  p = head;
  while (n > 1) {
    if (k % 3 == 0) {
      p->num = 0;
      n--;
    }
    k++;
    p = p->next;
  }
  for (m = 0; m < 10; m++) {
    if (p->num != 0)
      printf("%d", p->num);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x9,%ebp
L85:
  mov    %rax,%r12
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%r12)
  sub    $0x1,%ebp
  jne    L85
  mov    %rbx,0x8(%rax)
  mov    %rbx,%rdx
  mov    $0x9,%eax
L9:
  movl   $0x1,(%rdx)
  mov    0x8(%rdx),%rdx
  sub    $0x1,%eax
  jne    L9
  mov    $0x1,%edx
  mov    $0xa,%ecx
  jmp    L17
L39:
  movl   $0x0,(%rbx)
  sub    $0x1,%ecx
L17:
  add    $0x1,%edx
  mov    0x8(%rbx),%rbx
  cmp    $0x1,%ecx
  jle    L84
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edx
  je     L39
  jmp    L17
L84:
  mov    $0xa,%ebp
  lea    D9(%rip),%r12
  jmp    L40
L95:
  sub    $0x1,%ebp
  je     L98
L40:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L95
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L95
L98:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  struct ber {
    int num;
    struct ber *next;
  };
  int n = 10, m, k = 1;
  struct ber *p, *q, *head;
  head = q = malloc(sizeof(struct ber));
  for (m = 0; m < n - 1; m++) {
    p = malloc(sizeof(struct ber));
    q->next = p;
    q = p;
  }
  p->next = head;
  p = head;
  for (m = 1; m < 10; m++) {
    p->num = 1;
    p = p->next;
  }
  p = head;
  while (n > 1) {
    if (k % 3 == 0) {
      p->num = 0;
      n--;
    }
    k++;
    p = p->next;
  }
  for (m = 0; m < 10; m++) {
    if (p->num != 0)
      printf("%d", p->num);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x10,%edi
  push   %rbp
  mov    $0x9,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  nopw   0x0(%rax,%rax,1)
L83:
  mov    $0x10,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,0x8(%r12)
  sub    $0x1,%ebp
  jne    L83
  mov    %rbx,0x8(%rax)
  mov    %rbx,%rdx
  mov    $0x9,%eax
  nopl   0x0(%rax,%rax,1)
L52:
  movl   $0x1,(%rdx)
  mov    0x8(%rdx),%rdx
  sub    $0x1,%eax
  jne    L52
  mov    $0x1,%eax
  mov    $0xa,%edx
L45:
  mov    0x8(%rbx),%rbx
  add    $0x1,%eax
  cmp    $0x1,%edx
  je     L68
L36:
  imul   $0xaaaaaaab,%eax,%ecx
  cmp    $0x55555555,%ecx
  ja     L45
  sub    $0x1,%edx
  movl   $0x0,(%rbx)
  add    $0x1,%eax
  mov    0x8(%rbx),%rbx
  cmp    $0x1,%edx
  jne    L36
L68:
  mov    $0xa,%ebp
  lea    D1(%rip),%r12
  jmp    L24
  xchg   %ax,%ax
L11:
  sub    $0x1,%ebp
  je     L76
L24:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L11
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L24
L76:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
data_type: string

tool: D1: %d

assistant: ```c
int main() {
  struct ber {
    int num;
    struct ber *next;
  };
  int n = 10, m, k = 1;
  struct ber *p, *q, *head;
  head = q = malloc(sizeof(struct ber));
  for (m = 0; m < n - 1; m++) {
    p = malloc(sizeof(struct ber));
    q->next = p;
    q = p;
  }
  p->next = head;
  p = head;
  for (m = 1; m < 10; m++) {
    p->num = 1;
    p = p->next;
  }
  p = head;
  while (n > 1) {
    if (k % 3 == 0) {
      p->num = 0;
      n--;
    }
    k++;
    p = p->next;
  }
  for (m = 0; m < 10; m++) {
    if (p->num != 0)
      printf("%d", p->num);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x10,%edi
  push   %rbp
  push   %rbx
  mov    $0x9,%ebx
  call   <malloc@plt>
  mov    %rax,%r12
  nopw   0x0(%rax,%rax,1)
L108:
  mov    $0x10,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %rax,0x8(%rbp)
  sub    $0x1,%ebx
  jne    L108
  mov    %r12,0x8(%rax)
  mov    0x8(%r12),%rbx
  mov    $0xa,%edx
  movl   $0x1,(%r12)
  mov    0x8(%rbx),%rax
  movl   $0x1,(%rbx)
  movl   $0x1,(%rax)
  mov    0x8(%rax),%rax
  movl   $0x1,(%rax)
  mov    0x8(%rax),%rax
  movl   $0x1,(%rax)
  mov    0x8(%rax),%rax
  movl   $0x1,(%rax)
  mov    0x8(%rax),%rax
  movl   $0x1,(%rax)
  mov    0x8(%rax),%rax
  movl   $0x1,(%rax)
  mov    0x8(%rax),%rax
  movl   $0x1,(%rax)
  mov    $0x2,%eax
  nopl   (%rax)
L60:
  imul   $0xaaaaaaab,%eax,%ecx
  cmp    $0x55555555,%ecx
  ja     L1
  sub    $0x1,%edx
  movl   $0x0,(%rbx)
  add    $0x1,%eax
  mov    0x8(%rbx),%rbx
  cmp    $0x1,%edx
  jne    L60
L114:
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L81
L40:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    0x8(%rbx),%rbx
  add    $0x1,%eax
  cmp    $0x1,%edx
  jne    L60
  jmp    L114
  xchg   %ax,%ax
L81:
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L40
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L40
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d

assistant: ```c
int main() {
  struct ber {
    int num;
    struct ber *next;
  };
  int n = 10, m, k = 1;
  struct ber *p, *q, *head;
  head = q = malloc(sizeof(struct ber));
  for (m = 0; m < n - 1; m++) {
    p = malloc(sizeof(struct ber));
    q->next = p;
    q = p;
  }
  p->next = head;
  p = head;
  for (m = 1; m < 10; m++) {
    p->num = 1;
    p = p->next;
  }
  p = head;
  while (n > 1) {
    if (k % 3 == 0) {
      p->num = 0;
      n--;
    }
    k++;
    p = p->next;
  }
  for (m = 0; m < 10; m++) {
    if (p->num != 0)
      printf("%d", p->num);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L4
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L10
L4:
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D17
type: string

tool: D15: %s: Testing clock()


tool: D17: clock

assistant: ```c
int _clock(char const *progname) {
  clock_t c;
  printf("%s: Testing clock()\n", progname);
  if ((c = clock()) == (clock_t)-1) {
    perror("clock");
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<_clock>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <clock@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    $0x0,%ebx
L2:
  mov    %ebx,%eax
  pop    %rbx
  ret
L9:
  mov    %eax,%ebx
  lea    D10(%rip),%rdi
  call   <perror@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: string
name: read_data
arguments: data_tag: D10
type_infered: string

tool: D11: %s: Testing clock()


tool: D10: clock

assistant: ```c
int _clock(char const *progname) {
  clock_t c;
  printf("%s: Testing clock()\n", progname);
  if ((c = clock()) == (clock_t)-1) {
    perror("clock");
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_clock>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <clock@plt>
  cmp    $0xffffffff,%eax
  je     L12
  xor    %r12d,%r12d
L6:
  mov    %r12d,%eax
  pop    %r12
  ret
L12:
  lea    D3(%rip),%rdi
  mov    %eax,%r12d
  call   <perror@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D3
type: string

tool: D1: %s: Testing clock()


tool: D3: clock

assistant: ```c
int _clock(char const *progname) {
  clock_t c;
  printf("%s: Testing clock()\n", progname);
  if ((c = clock()) == (clock_t)-1) {
    perror("clock");
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_clock>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <clock@plt>
  cmp    $0xffffffff,%eax
  je     L1
  xor    %r12d,%r12d
L10:
  mov    %r12d,%eax
  pop    %r12
  ret
L1:
  lea    D4(%rip),%rdi
  mov    %eax,%r12d
  call   <perror@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string

tool: D8: %s: Testing clock()


tool: D4: clock

assistant: ```c
int _clock(char const *progname) {
  clock_t c;
  printf("%s: Testing clock()\n", progname);
  if ((c = clock()) == (clock_t)-1) {
    perror("clock");
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sort_shift_down>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L21
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L21
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L51
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L46
  jmp    L29
L51:
  nop
L29:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_shift_down(int key, int num[], int root, int last) {
  int bigger = 2 * root;
  while (bigger <= last) {
    if (bigger < last)
      if (num[bigger + 1] > num[bigger])
        bigger++;
    if (key >= num[bigger])
      break;
    num[root] = num[bigger];
    root = bigger;
    bigger = 2 * root;
  }
  num[root] = key;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sort_shift_down>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rdi
  lea    (%rdx,%rdx,1),%eax
  cmp    %ecx,%eax
  jle    L27
  jmp    L34
L26:
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%eax
  cmp    %r9d,%eax
  jle    L34
  movslq %edx,%rdx
  mov    %eax,(%rdi,%rdx,4)
  lea    (%rsi,%rsi,1),%eax
  cmp    %eax,%ecx
  jl     L53
  mov    %esi,%edx
L27:
  mov    %eax,%esi
  cmp    %eax,%ecx
  jle    L26
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r10d
  cmp    %r10d,0x4(%rdi,%r8,4)
  jle    L26
  lea    0x1(%rax),%esi
  jmp    L26
L53:
  mov    %esi,%edx
L34:
  movslq %edx,%rdx
  mov    %r9d,(%rdi,%rdx,4)
  ret
```

assistant: ```c
void sort_shift_down(int key, int num[], int root, int last) {
  int bigger = 2 * root;
  while (bigger <= last) {
    if (bigger < last)
      if (num[bigger + 1] > num[bigger])
        bigger++;
    if (key >= num[bigger])
      break;
    num[root] = num[bigger];
    root = bigger;
    bigger = 2 * root;
  }
  num[root] = key;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort_shift_down>:
  endbr64
  mov    %edi,%r10d
  lea    (%rdx,%rdx,1),%edi
  mov    %rsi,%r9
  cmp    %ecx,%edi
  jle    L44
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L53:
  lea    (%rsi,%rsi,1),%edi
  mov    %r8d,(%rax)
  cmp    %edi,%ecx
  jl     L7
  mov    %esi,%edx
L44:
  movslq %edi,%rax
  mov    %edi,%esi
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%r11
  mov    (%r11),%r8d
  cmp    %edi,%ecx
  jle    L67
  lea    0x4(%r9,%rax,1),%rax
  mov    (%rax),%edi
  cmp    %r8d,%edi
  jle    L67
  add    $0x1,%esi
  mov    %edi,%r8d
  mov    %rax,%r11
L67:
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rax
  cmp    %r8d,%r10d
  jl     L53
L39:
  mov    %r10d,(%rax)
  ret
  nopl   (%rax)
L7:
  mov    %r11,%rax
  mov    %r10d,(%rax)
  ret
L50:
  movslq %edx,%rdx
  lea    (%rsi,%rdx,4),%rax
  jmp    L39
```

assistant: ```c
void sort_shift_down(int key, int num[], int root, int last) {
  int bigger = 2 * root;
  while (bigger <= last) {
    if (bigger < last)
      if (num[bigger + 1] > num[bigger])
        bigger++;
    if (key >= num[bigger])
      break;
    num[root] = num[bigger];
    root = bigger;
    bigger = 2 * root;
  }
  num[root] = key;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sort_shift_down>:
  endbr64
  mov    %edi,%r10d
  lea    (%rdx,%rdx,1),%edi
  mov    %rsi,%r9
  cmp    %ecx,%edi
  jle    L1
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L41:
  lea    (%rsi,%rsi,1),%edi
  mov    %r8d,(%rax)
  cmp    %edi,%ecx
  jl     L66
  mov    %esi,%edx
L1:
  movslq %edi,%rax
  mov    %edi,%esi
  shl    $0x2,%rax
  lea    (%r9,%rax,1),%r11
  mov    (%r11),%r8d
  cmp    %edi,%ecx
  jle    L38
  lea    0x4(%r9,%rax,1),%rax
  mov    (%rax),%edi
  cmp    %r8d,%edi
  jle    L38
  add    $0x1,%esi
  mov    %edi,%r8d
  mov    %rax,%r11
L38:
  movslq %edx,%rdx
  lea    (%r9,%rdx,4),%rax
  cmp    %r8d,%r10d
  jl     L41
L8:
  mov    %r10d,(%rax)
  ret
  nopl   (%rax)
L66:
  mov    %r11,%rax
  mov    %r10d,(%rax)
  ret
L12:
  movslq %edx,%rdx
  lea    (%rsi,%rdx,4),%rax
  jmp    L8
```

assistant: ```c
void sort_shift_down(int key, int num[], int root, int last) {
  int bigger = 2 * root;
  while (bigger <= last) {
    if (bigger < last)
      if (num[bigger + 1] > num[bigger])
        bigger++;
    if (key >= num[bigger])
      break;
    num[root] = num[bigger];
    root = bigger;
    bigger = 2 * root;
  }
  num[root] = key;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sysfs_get_two>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sysfs_get_fd@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L16
  mov    $0xffffffff,%eax
  jmp    L14
L16:
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sysfs_fd_get_two@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x4(%rbp),%eax
L14:
  leave
  ret
```

assistant: ```c
int sysfs_get_two(struct mdinfo *sra, struct mdinfo *dev, char *name, unsigned long long *v1, unsigned long long *v2) {
  int n;
  int fd;
  fd = sysfs_get_fd(sra, dev, name);
  if (fd < 0)
    return -1;
  n = sysfs_fd_get_two(fd, v1, v2);
  close(fd);
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sysfs_get_two>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbp
  mov    %r8,%r12
  call   <sysfs_get_fd@plt>
  test   %eax,%eax
  js     L1
  mov    %eax,%ebx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <sysfs_fd_get_two@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <close@plt>
L4:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    $0xffffffff,%ebp
  jmp    L4
```

assistant: ```c
int sysfs_get_two(struct mdinfo *sra, struct mdinfo *dev, char *name, unsigned long long *v1, unsigned long long *v2) {
  int n;
  int fd;
  fd = sysfs_get_fd(sra, dev, name);
  if (fd < 0)
    return -1;
  n = sysfs_fd_get_two(fd, v1, v2);
  close(fd);
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sysfs_get_two>:
  endbr64
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  call   <sysfs_get_fd@plt>
  test   %eax,%eax
  js     L10
  mov    %eax,%ebp
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    %r13,%rdx
  call   <sysfs_fd_get_two@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <close@plt>
L16:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%r12d
  jmp    L16
```

assistant: ```c
int sysfs_get_two(struct mdinfo *sra, struct mdinfo *dev, char *name, unsigned long long *v1, unsigned long long *v2) {
  int n;
  int fd;
  fd = sysfs_get_fd(sra, dev, name);
  if (fd < 0)
    return -1;
  n = sysfs_fd_get_two(fd, v1, v2);
  close(fd);
  return n;
}
```