ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<Read_Thermal_Status_CPU>:
  endbr64
  push   %r13
  xor    %ecx,%ecx
  mov    $0x3f,%edx
  mov    $0x19c,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%r8
  call   <get_msr_value@plt>
  mov    $0x10,%edx
  mov    $0x17,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <Get_Bits_Value@plt>
  mov    %r12,%rdi
  mov    $0x1f,%edx
  mov    $0x20,%esi
  mov    %eax,%ebx
  call   <Get_Bits_Value@plt>
  xor    %ecx,%ecx
  mov    $0x3f,%edx
  mov    %ebp,%edi
  mov    $0x1a2,%esi
  mov    %r13,%r8
  mov    %eax,%r12d
  call   <get_msr_value@plt>
  mov    $0x10,%edx
  mov    $0x17,%esi
  mov    %rax,%rdi
  call   <Get_Bits_Value@plt>
  test   %r12d,%r12d
  je     L11
  sub    %ebx,%eax
L0:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L11:
  mov    $0xffffffff,%eax
  jmp    L0
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Read_Thermal_Status_CPU(int cpu_num) {
  int error_indx;
  unsigned long val = get_msr_value(cpu_num, 0x19C, 63, 0, &error_indx);
  int digital_readout = Get_Bits_Value(val, 23, 16);
  int thermal_status = Get_Bits_Value(val, 32, 31);
  val = get_msr_value(cpu_num, 0x1a2, 63, 0, &error_indx);
  int PROCHOT_temp = Get_Bits_Value(val, 23, 16);
  if (thermal_status)
    return (PROCHOT_temp - digital_readout);
  else
    return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
L9:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,0x80(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L9
  movslq %ebp,%rbp
  movb   $0x0,0x80(%rsp,%rbp,1)
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
L18:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,0x10(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L18
  movslq %ebp,%rbp
  movb   $0x0,0x10(%rsp,%rbp,1)
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%r12
  mov    %r12,%rsi
  lea    D59(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  lea    0x80(%rsp),%rbx
  mov    0x8(%rsp),%edx
  mov    %rbx,%rdi
  call   <ins_string@plt>
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <delnchars@plt>
  mov    %rbx,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
type: string
name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D20
type: string
name: unpack_data
arguments: tag: D59
type: string
name: unpack_data
arguments: tag: D26
type: string
name: unpack_data
arguments: tag: D12
type: string
name: unpack_data
arguments: tag: D2
type: string

tool: D29: Enter the main string: 

tool: D0: Enter the sub-string: 

tool: D20: Enter the position to insert sub-string to main string: 

tool: D59: %d

tool: D26: The main string is now:
%s


tool: D12: Enter the number of characters and the position to delete from in the above string: 

tool: D2: The string is now:
%s


assistant: ```c
int main() {
  char str1[2 * 100], str2[100];
  int i, x, n;
  printf("Enter the main string: ");
  i = 0;
  while ((str1[i++] = getchar()) != '\n')
    ;
  str1[i - 1] = '\0';
  printf("Enter the sub-string: ");
  i = 0;
  while ((str2[i++] = getchar()) != '\n')
    ;
  str2[i - 1] = '\0';
  printf("Enter the position to insert sub-string to main string: ");
  scanf("%d", &x);
  ins_string(str1, str2, x);
  printf("The main string is now:\n%s\n", str1);
  printf("Enter the number of characters and the position to delete from in the above string: ");
  scanf("%d", &n);
  scanf("%d", &x);
  delnchars(str1, n, x);
  printf("The string is now:\n%s\n", str1);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tea_decode_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x416554214b704e,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%esi
  mov    -0x24(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%edi
  sar    $0x1f,%edi
  mov    %edx,%ecx
  sub    %edi,%ecx
  mov    %ecx,%edx
  shl    $0x8,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  xor    %eax,%esi
  mov    %esi,%edx
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x10(%rbp,%rax,1),%eax
  xor    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void tea_decode_byte(char *v, int *k, int p) {
  char y[] = "NpK!TeA";
  *v = *v ^ (char)(k[p % 4] % 0xFF) ^ y[p];
}
```
user: Translate the below assembly code into C programming language:

```asm
<tea_decode_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movabs $0x416554214b704e,%rax
  mov    %rax,(%rsp)
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x3,%eax
  sub    %ecx,%eax
  cltq
  mov    (%rsi,%rax,4),%ecx
  movslq %ecx,%rax
  imul   $0xffffffff80808081,%rax,%rax
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x7,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  sub    %eax,%esi
  sub    %esi,%ecx
  movslq %edx,%rdx
  movzbl (%rdi),%eax
  xor    (%rsp,%rdx,1),%al
  xor    %ecx,%eax
  mov    %al,(%rdi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tea_decode_byte(char *v, int *k, int p) {
  char y[] = "NpK!TeA";
  *v = *v ^ (char)(k[p % 4] % 0xFF) ^ y[p];
}
```
user: Translate the below assembly code into C programming language:

```asm
<tea_decode_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x416554214b704e,%rax
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  mov    %rax,(%rsp)
  lea    (%rdx,%rcx,1),%eax
  movslq %edx,%rdx
  and    $0x3,%eax
  sub    %ecx,%eax
  cltq
  movslq (%rsi,%rax,4),%rax
  mov    %rax,%rcx
  imul   $0xffffffff80808081,%rax,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x7,%eax
  sub    %esi,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  sub    %eax,%esi
  movzbl (%rdi),%eax
  xor    (%rsp,%rdx,1),%al
  sub    %esi,%ecx
  xor    %ecx,%eax
  mov    %al,(%rdi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tea_decode_byte(char *v, int *k, int p) {
  char y[] = "NpK!TeA";
  *v = *v ^ (char)(k[p % 4] % 0xFF) ^ y[p];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tea_decode_byte>:
  endbr64
  sub    $0x18,%rsp
  mov    %edx,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x416554214b704e,%rax
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  mov    %rax,(%rsp)
  lea    (%rdx,%rcx,1),%eax
  movslq %edx,%rdx
  and    $0x3,%eax
  sub    %ecx,%eax
  cltq
  movslq (%rsi,%rax,4),%rax
  mov    %rax,%rcx
  imul   $0xffffffff80808081,%rax,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x7,%eax
  sub    %esi,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  sub    %eax,%esi
  movzbl (%rdi),%eax
  xor    (%rsp,%rdx,1),%al
  sub    %esi,%ecx
  xor    %ecx,%eax
  mov    %al,(%rdi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void tea_decode_byte(char *v, int *k, int p) {
  char y[] = "NpK!TeA";
  *v = *v ^ (char)(k[p % 4] % 0xFF) ^ y[p];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findMaxSub>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    %edx,%esi
  je     L8
  mov    %edx,%eax
  sub    %esi,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  add    %esi,%edi
  call   <floor@plt>
  mov    %eax,%r14d
  mov    %rsp,%rcx
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <findMaxSub>
  lea    0xc(%rsp),%rcx
  lea    0x1(%r14),%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <findMaxSub>
  lea    0x18(%rsp),%r8
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <findMaxCrossMid@plt>
  mov    0x8(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  setg   %al
  movzbl %al,%eax
  setg   %dl
  movzbl %dl,%edx
  lea    (%rdx,%rdx,2),%rdx
  mov    0x8(%rsp,%rdx,4),%ebx
  cmp    %ebx,0x20(%rsp)
  mov    $0x2,%edx
  cmovg  %edx,%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    (%rsp,%rcx,4),%ecx
  mov    %ecx,(%r12)
  lea    (%rdx,%rax,1),%rcx
  mov    0x4(%rsp,%rcx,4),%ecx
  mov    %ecx,0x4(%r12)
  add    %rax,%rdx
  mov    0x8(%rsp,%rdx,4),%eax
L6:
  mov    %eax,0x8(%r12)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    %esi,(%r12)
  mov    %edx,0x4(%r12)
  movslq %esi,%rbx
  mov    (%rdi,%rbx,4),%eax
  jmp    L6
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void findMaxSub(int *A, int p, int q, int *rret) {
  if (p == q) {
    rret[0] = p;
    rret[1] = q;
    rret[2] = A[p];
    return;
  }
  int ret[3][3];
  int mid = floor(p + (q - p) / 2);
  findMaxSub(A, p, mid, ret[0]);
  findMaxSub(A, mid + 1, q, ret[1]);
  findMaxCrossMid(A, p, mid, q, ret[2]);
  int flag = 0;
  if (ret[1][2] > ret[flag][2]) {
    flag = 1;
  }
  if (ret[2][2] > ret[flag][2]) {
    flag = 2;
  }
  rret[0] = ret[flag][0];
  rret[1] = ret[flag][1];
  rret[2] = ret[flag][2];
}
```
user: Translate the below assembly code into C programming language:

```asm
<findMaxSub>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    %edx,%ebp
  je     L41
  mov    %edx,%eax
  mov    %edx,%r12d
  sub    %ebp,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  add    %ebp,%edi
  call   <floor@plt>
  mov    %rsp,%rcx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%r14d
  mov    %eax,%edx
  call   <findMaxSub>
  lea    0xc(%rsp),%rcx
  mov    %r12d,%edx
  mov    %r13,%rdi
  lea    0x1(%r14),%esi
  call   <findMaxSub>
  mov    %r12d,%ecx
  mov    %r14d,%edx
  lea    0x18(%rsp),%r8
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <findMaxCrossMid@plt>
  mov    0x8(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  setg   %al
  mov    0x20(%rsp),%edx
  movzbl %al,%eax
  lea    (%rax,%rax,2),%rcx
  mov    0x8(%rsp,%rcx,4),%ecx
  cmp    %ecx,%edx
  jg     L36
  mov    %ecx,%edx
L34:
  lea    (%rax,%rax,2),%rax
  mov    (%rsp,%rax,4),%rax
  mov    %rax,(%rbx)
L19:
  mov    %edx,0x8(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L36:
  mov    $0x2,%eax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %ebp,(%rcx)
  mov    %ebp,0x4(%rcx)
  mov    (%rdi,%rbp,4),%edx
  jmp    L19
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void findMaxSub(int *A, int p, int q, int *rret) {
  if (p == q) {
    rret[0] = p;
    rret[1] = q;
    rret[2] = A[p];
    return;
  }
  int ret[3][3];
  int mid = floor(p + (q - p) / 2);
  findMaxSub(A, p, mid, ret[0]);
  findMaxSub(A, mid + 1, q, ret[1]);
  findMaxCrossMid(A, p, mid, q, ret[2]);
  int flag = 0;
  if (ret[1][2] > ret[flag][2]) {
    flag = 1;
  }
  if (ret[2][2] > ret[flag][2]) {
    flag = 2;
  }
  rret[0] = ret[flag][0];
  rret[1] = ret[flag][1];
  rret[2] = ret[flag][2];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<findMaxSub>:
  endbr64
  push   %r14
  movd   %edx,%xmm1
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  movd   %ebp,%xmm0
  mov    %rcx,%rbx
  punpckldq %xmm1,%xmm0
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    %edx,%ebp
  je     L31
  mov    %edx,%eax
  mov    %edx,%r12d
  sub    %ebp,%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  add    %ebp,%edi
  call   <floor@plt>
  mov    %rsp,%rcx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    %eax,%r14d
  mov    %eax,%edx
  call   <findMaxSub>
  lea    0xc(%rsp),%rcx
  mov    %r12d,%edx
  mov    %r13,%rdi
  lea    0x1(%r14),%esi
  call   <findMaxSub>
  mov    %r12d,%ecx
  mov    %r14d,%edx
  lea    0x18(%rsp),%r8
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <findMaxCrossMid@plt>
  mov    0x8(%rsp),%eax
  cmp    %eax,0x14(%rsp)
  setg   %al
  mov    0x20(%rsp),%edx
  movzbl %al,%eax
  lea    (%rax,%rax,2),%rcx
  mov    0x8(%rsp,%rcx,4),%ecx
  cmp    %ecx,%edx
  jg     L17
  mov    %ecx,%edx
L26:
  lea    (%rax,%rax,2),%rax
  mov    (%rsp,%rax,4),%rax
  mov    %rax,(%rbx)
L2:
  mov    %edx,0x8(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x2,%eax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L31:
  movq   %xmm0,(%rcx)
  mov    (%rdi,%rbp,4),%edx
  jmp    L2
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void findMaxSub(int *A, int p, int q, int *rret) {
  if (p == q) {
    rret[0] = p;
    rret[1] = q;
    rret[2] = A[p];
    return;
  }
  int ret[3][3];
  int mid = floor(p + (q - p) / 2);
  findMaxSub(A, p, mid, ret[0]);
  findMaxSub(A, mid + 1, q, ret[1]);
  findMaxCrossMid(A, p, mid, q, ret[2]);
  int flag = 0;
  if (ret[1][2] > ret[flag][2]) {
    flag = 1;
  }
  if (ret[2][2] > ret[flag][2]) {
    flag = 2;
  }
  rret[0] = ret[flag][0];
  rret[1] = ret[flag][1];
  rret[2] = ret[flag][2];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(char s[], int i, int j) {
  char temp = s[j];
  s[j] = s[i];
  s[i] = temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swap>:
  endbr64
  movslq %edx,%rdx
  add    %rdi,%rdx
  movzbl (%rdx),%eax
  movslq %esi,%rsi
  add    %rsi,%rdi
  movzbl (%rdi),%ecx
  mov    %cl,(%rdx)
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void swap(char s[], int i, int j) {
  char temp = s[j];
  s[j] = s[i];
  s[i] = temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap>:
  endbr64
  movslq %edx,%rdx
  movslq %esi,%rsi
  add    %rdi,%rdx
  add    %rsi,%rdi
  movzbl (%rdx),%eax
  movzbl (%rdi),%ecx
  mov    %cl,(%rdx)
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void swap(char s[], int i, int j) {
  char temp = s[j];
  s[j] = s[i];
  s[i] = temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap>:
  endbr64
  movslq %edx,%rdx
  movslq %esi,%rsi
  add    %rdi,%rdx
  add    %rsi,%rdi
  movzbl (%rdx),%eax
  movzbl (%rdi),%ecx
  mov    %cl,(%rdx)
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void swap(char s[], int i, int j) {
  char temp = s[j];
  s[j] = s[i];
  s[i] = temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cs_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clr_avails@plt>
  mov    $0x0,%eax
  call   <clr_entities@plt>
  mov    $0x0,%eax
  call   <clr_stack@plt>
  mov    $0x0,%eax
  call   <start_valnum@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cs_clear() {
  clr_avails();
  clr_entities();
  clr_stack();
  start_valnum();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cs_clear>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clr_avails@plt>
  mov    $0x0,%eax
  call   <clr_entities@plt>
  mov    $0x0,%eax
  call   <clr_stack@plt>
  mov    $0x0,%eax
  call   <start_valnum@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cs_clear() {
  clr_avails();
  clr_entities();
  clr_stack();
  start_valnum();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cs_clear>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clr_avails@plt>
  xor    %eax,%eax
  call   <clr_entities@plt>
  xor    %eax,%eax
  call   <clr_stack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <start_valnum@plt>
```

assistant: ```c
void cs_clear() {
  clr_avails();
  clr_entities();
  clr_stack();
  start_valnum();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cs_clear>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clr_avails@plt>
  xor    %eax,%eax
  call   <clr_entities@plt>
  xor    %eax,%eax
  call   <clr_stack@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <start_valnum@plt>
```

assistant: ```c
void cs_clear() {
  clr_avails();
  clr_entities();
  clr_stack();
  start_valnum();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prvocislo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L93
  cmpl   $0x2,-0x14(%rbp)
  je     L24
  jmp    L34
L93:
  mov    $0x0,%eax
  jmp    L72
L24:
  mov    $0x1,%eax
  jmp    L72
L34:
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L48
L74:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L41
  addl   $0x1,-0x4(%rbp)
L41:
  addl   $0x1,-0x8(%rbp)
L48:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jg     L74
  cmpl   $0x1,-0x4(%rbp)
  jne    L76
  mov    $0x1,%eax
  jmp    L72
L76:
  mov    $0x0,%eax
L72:
  pop    %rbp
  ret
```

assistant: ```c
int prvocislo(int vstup) {
  switch (vstup) {
  case 1:
    return 0;
    break;
  case 2:
    return 1;
    break;
  default: {
    int i;
    int pom = 0;
    for (i = 1; i * i < vstup; i++) {
      if (vstup % i == 0)
        pom++;
    }
    if (pom == 1)
      return 1;
    else
      return 0;
  }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prvocislo>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  je     L42
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L42
  cmp    $0x1,%edi
  jle    L11
  mov    $0x0,%esi
  mov    $0x1,%ecx
L4:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jl     L4
L39:
  cmp    $0x1,%esi
  sete   %al
  movzbl %al,%eax
L42:
  ret
L11:
  mov    $0x0,%esi
  jmp    L39
```

assistant: ```c
int prvocislo(int vstup) {
  switch (vstup) {
  case 1:
    return 0;
    break;
  case 2:
    return 1;
    break;
  default: {
    int i;
    int pom = 0;
    for (i = 1; i * i < vstup; i++) {
      if (vstup % i == 0)
        pom++;
    }
    if (pom == 1)
      return 1;
    else
      return 0;
  }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prvocislo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L14
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L14
  cmp    $0x1,%edi
  jle    L36
  xor    %esi,%esi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L3:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jl     L3
  xor    %eax,%eax
  cmp    $0x1,%esi
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %eax,%eax
L14:
  ret
```

assistant: ```c
int prvocislo(int vstup) {
  switch (vstup) {
  case 1:
    return 0;
    break;
  case 2:
    return 1;
    break;
  default: {
    int i;
    int pom = 0;
    for (i = 1; i * i < vstup; i++) {
      if (vstup % i == 0)
        pom++;
    }
    if (pom == 1)
      return 1;
    else
      return 0;
  }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prvocislo>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L35
  mov    $0x1,%eax
  cmp    $0x2,%edi
  je     L35
  cmp    $0x1,%edi
  jle    L5
  xor    %esi,%esi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L10:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %eax,%edi
  jg     L10
  xor    %eax,%eax
  cmp    $0x1,%esi
  sete   %al
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
L35:
  ret
```

assistant: ```c
int prvocislo(int vstup) {
  switch (vstup) {
  case 1:
    return 0;
    break;
  case 2:
    return 1;
    break;
  default: {
    int i;
    int pom = 0;
    for (i = 1; i * i < vstup; i++) {
      if (vstup % i == 0)
        pom++;
    }
    if (pom == 1)
      return 1;
    else
      return 0;
  }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <max@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type: string

tool: D6: %d


assistant: ```c
main() {
  int printf();
  printf("%d\n", max(1, 2));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <max@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %d


assistant: ```c
main() {
  int printf();
  printf("%d\n", max(1, 2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <max@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: %d


assistant: ```c
main() {
  int printf();
  printf("%d\n", max(1, 2));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <max@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string

tool: D3: %d


assistant: ```c
main() {
  int printf();
  printf("%d\n", max(1, 2));
  return 0;
}
```