ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<assert>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  je     L0
  ret
L0:
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rdx
  mov    $0x1,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string

tool: D7: %d test failed: %s


assistant: ```c
int assert(int testresult, char error_message[]) {
  static int test_number = 1;
  int result = 1;
  if (!testresult) {
    printf("%d test failed: %s\n", test_number, error_message);
    result = 0;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<assert>:
  endbr64
  test   %edi,%edi
  je     L4
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L4:
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D3(%rip),%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type: string

tool: D3: %d test failed: %s


assistant: ```c
int assert(int testresult, char error_message[]) {
  static int test_number = 1;
  int result = 1;
  if (!testresult) {
    printf("%d test failed: %s\n", test_number, error_message);
    result = 0;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<assert>:
  endbr64
  test   %edi,%edi
  je     L0
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L0:
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D9(%rip),%rdi
  mov    $0x1,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: %d test failed: %s


assistant: ```c
int assert(int testresult, char error_message[]) {
  static int test_number = 1;
  int result = 1;
  if (!testresult) {
    printf("%d test failed: %s\n", test_number, error_message);
    result = 0;
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %edi,-0x224(%rbp)
  mov    %rsi,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x214(%rbp)
  jmp    L17
L0:
  mov    -0x214(%rbp),%eax
  cltq
  movl   $0x0,-0x210(%rbp,%rax,4)
  addl   $0x1,-0x214(%rbp)
L17:
  cmpl   $0x80,-0x214(%rbp)
  jle    L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int arr[128];
  int i;
  for (i = 0; i < 129; i++)
    arr[i] = 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x81,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int arr[128];
  int i;
  for (i = 0; i < 129; i++)
    arr[i] = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int arr[128];
  int i;
  for (i = 0; i < 129; i++)
    arr[i] = 0;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int arr[128];
  int i;
  for (i = 0; i < 129; i++)
    arr[i] = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D0: Usage: %s [OPTIONS]


tool: D25: -p, --port     The port to listen for messags on.

tool: D7: -h, --help     Print this help message.

tool: D8: -v, --verbose  Print more debugging information.

assistant: ```c
void print_usage(const char *program) {
  printf("Usage: %s [OPTIONS]\n", program);
  printf("-p, --port     The port to listen for messags on.\n");
  printf("-h, --help     Print this help message.\n");
  printf("-v, --verbose  Print more debugging information.\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D39
type: string
name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D29
type: string
name: read_data
arguments: tag: D35
type: string

tool: D39: Usage: %s [OPTIONS]


tool: D13: -p, --port     The port to listen for messags on.

tool: D29: -h, --help     Print this help message.

tool: D35: -v, --verbose  Print more debugging information.

assistant: ```c
void print_usage(const char *program) {
  printf("Usage: %s [OPTIONS]\n", program);
  printf("-p, --port     The port to listen for messags on.\n");
  printf("-h, --help     Print this help message.\n");
  printf("-v, --verbose  Print more debugging information.\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D35
type: string
name: read_data
arguments: label: D10
type: string
name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D4
type: string

tool: D35: Usage: %s [OPTIONS]


tool: D10: -p, --port     The port to listen for messags on.

tool: D25: -h, --help     Print this help message.

tool: D4: -v, --verbose  Print more debugging information.

assistant: ```c
void print_usage(const char *program) {
  printf("Usage: %s [OPTIONS]\n", program);
  printf("-p, --port     The port to listen for messags on.\n");
  printf("-h, --help     Print this help message.\n");
  printf("-v, --verbose  Print more debugging information.\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string
name: extract_symbolic_data
arguments: label: D38
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string
name: extract_symbolic_data
arguments: label: D10
data_type: string

tool: D3: Usage: %s [OPTIONS]


tool: D38: -p, --port     The port to listen for messags on.

tool: D26: -h, --help     Print this help message.

tool: D10: -v, --verbose  Print more debugging information.

assistant: ```c
void print_usage(const char *program) {
  printf("Usage: %s [OPTIONS]\n", program);
  printf("-p, --port     The port to listen for messags on.\n");
  printf("-h, --help     Print this help message.\n");
  printf("-v, --verbose  Print more debugging information.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<nrf24_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <nrf24_setupPins@plt>
  mov    $0x0,%edi
  call   <nrf24_ce_digitalWrite@plt>
  mov    $0x1,%edi
  call   <nrf24_csn_digitalWrite@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nrf24_init() {
  nrf24_setupPins();
  nrf24_ce_digitalWrite(0);
  nrf24_csn_digitalWrite(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nrf24_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <nrf24_setupPins@plt>
  mov    $0x0,%edi
  call   <nrf24_ce_digitalWrite@plt>
  mov    $0x1,%edi
  call   <nrf24_csn_digitalWrite@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void nrf24_init() {
  nrf24_setupPins();
  nrf24_ce_digitalWrite(0);
  nrf24_csn_digitalWrite(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<nrf24_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nrf24_setupPins@plt>
  xor    %edi,%edi
  call   <nrf24_ce_digitalWrite@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1080 <nrf24_csn_digitalWrite@plt>
```

assistant: ```c
void nrf24_init() {
  nrf24_setupPins();
  nrf24_ce_digitalWrite(0);
  nrf24_csn_digitalWrite(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nrf24_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <nrf24_setupPins@plt>
  xor    %edi,%edi
  call   <nrf24_ce_digitalWrite@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1080 <nrf24_csn_digitalWrite@plt>
```

assistant: ```c
void nrf24_init() {
  nrf24_setupPins();
  nrf24_ce_digitalWrite(0);
  nrf24_csn_digitalWrite(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<__mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x118(%rbp)
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    $0x2f,%al
  jne    L26
  mov    -0x118(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,-0x110(%rbp,%rax,1)
L26:
  lea    -0x110(%rbp),%rax
  mov    %rax,-0x120(%rbp)
  jmp    L4
L21:
  mov    -0x120(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L79
  mov    -0x120(%rbp),%rax
  movb   $0x0,(%rax)
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  test   %rax,%rax
  je     L34
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
L34:
  mov    -0x120(%rbp),%rax
  movb   $0x2f,(%rax)
L79:
  addq   $0x1,-0x120(%rbp)
L4:
  mov    -0x120(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <access@plt>
  test   %rax,%rax
  je     L66
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  lea    -0x110(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  jmp    L71
L66:
  mov    $0xffffffff,%eax
L71:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
unsigned int __mkdir(const char *path) {
  char opath[256];
  char *p;
  size_t len;
  strncpy(opath, path, sizeof(opath));
  len = strlen(opath);
  if (opath[len - 1] == '/')
    opath[len - 1] = '\0';
  for (p = opath; *p; p++)
    if (*p == '/') {
      *p = '\0';
      if (access(opath, F_OK))
        mkdir(opath, S_IRWXU);
      *p = '/';
    }
  if (access(opath, F_OK))
    return mkdir(opath, S_IRWXU);
  else
    return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x100,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  je     L8
L13:
  movzbl (%rsp),%eax
  test   %al,%al
  je     L94
  mov    %rsp,%rbx
  mov    %rsp,%rbp
  jmp    L84
L8:
  movb   $0x0,-0x1(%rsp,%rax,1)
  jmp    L13
L72:
  movb   $0x2f,(%rbx)
L29:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L94
L84:
  cmp    $0x2f,%al
  jne    L29
  movb   $0x0,(%rbx)
  mov    D34(%rip),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  je     L72
  mov    D26(%rip),%rax
  mov    (%rax),%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L72
L94:
  mov    %rsp,%rdi
  mov    D34(%rip),%rax
  mov    (%rax),%esi
  call   <access@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  jne    L65
L68:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L65:
  mov    %rsp,%rdi
  mov    D26(%rip),%rax
  mov    (%rax),%esi
  call   <mkdir@plt>
  jmp    L68
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int __mkdir(const char *path) {
  char opath[256];
  char *p;
  size_t len;
  strncpy(opath, path, sizeof(opath));
  len = strlen(opath);
  if (opath[len - 1] == '/')
    opath[len - 1] = '\0';
  for (p = opath; *p; p++)
    if (*p == '/') {
      *p = '\0';
      if (access(opath, F_OK))
        mkdir(opath, S_IRWXU);
      *p = '/';
    }
  if (access(opath, F_OK))
    return mkdir(opath, S_IRWXU);
  else
    return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__mkdir>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x100,%edx
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  jne    L53
  movb   $0x0,-0x1(%rsp,%rax,1)
L53:
  movzbl (%rsp),%eax
  test   %al,%al
  je     L36
  mov    D36(%rip),%r12
  mov    %rbp,%rbx
  jmp    L62
  nopl   0x0(%rax)
L85:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L19
L62:
  cmp    $0x2f,%al
  jne    L85
  movb   $0x0,(%rbx)
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L64
L97:
  movb   $0x2f,(%rbx)
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L62
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L32
  mov    $0xffffffff,%eax
L77:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L64:
  mov    D8(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <mkdir@plt>
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L32:
  mov    D8(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <mkdir@plt>
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L36:
  mov    D36(%rip),%r12
  jmp    L19
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int __mkdir(const char *path) {
  char opath[256];
  char *p;
  size_t len;
  strncpy(opath, path, sizeof(opath));
  len = strlen(opath);
  if (opath[len - 1] == '/')
    opath[len - 1] = '\0';
  for (p = opath; *p; p++)
    if (*p == '/') {
      *p = '\0';
      if (access(opath, F_OK))
        mkdir(opath, S_IRWXU);
      *p = '/';
    }
  if (access(opath, F_OK))
    return mkdir(opath, S_IRWXU);
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__mkdir>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x100,%edx
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmpb   $0x2f,-0x1(%rsp,%rax,1)
  jne    L119
  movb   $0x0,-0x1(%rsp,%rax,1)
L119:
  movzbl (%rsp),%eax
  test   %al,%al
  je     L4
  mov    D14(%rip),%r12
  mov    %rbp,%rbx
  jmp    L9
  nopl   0x0(%rax)
L37:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L104
L9:
  cmp    $0x2f,%al
  jne    L37
  movb   $0x0,(%rbx)
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L71
L83:
  movb   $0x2f,(%rbx)
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L9
  nopl   0x0(%rax,%rax,1)
L104:
  mov    (%r12),%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  jne    L19
  mov    $0xffffffff,%eax
L97:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L109
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L71:
  mov    D24(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <mkdir@plt>
  jmp    L83
  nopl   0x0(%rax,%rax,1)
L19:
  mov    D24(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <mkdir@plt>
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L4:
  mov    D14(%rip),%r12
  jmp    L104
L109:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int __mkdir(const char *path) {
  char opath[256];
  char *p;
  size_t len;
  strncpy(opath, path, sizeof(opath));
  len = strlen(opath);
  if (opath[len - 1] == '/')
    opath[len - 1] = '\0';
  for (p = opath; *p; p++)
    if (*p == '/') {
      *p = '\0';
      if (access(opath, F_OK))
        mkdir(opath, S_IRWXU);
      *p = '/';
    }
  if (access(opath, F_OK))
    return mkdir(opath, S_IRWXU);
  else
    return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L2:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L3
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  jmp    L45
L3:
  mov    -0x10(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rax
  movsd  D59(%rip),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  D23(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D61(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0xc(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  movsd  D30(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movsd  D31(%rip),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L45:
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D59
datatype: byte[8]
name: read_data
arguments: data_label: D23
datatype: f64
name: read_data
arguments: data_label: D61
datatype: byte[8]
name: read_data
arguments: data_label: D30
datatype: byte[8]
name: read_data
arguments: data_label: D31
datatype: byte[8]
name: read_data
arguments: data_label: D54
datatype: string

tool: D5: %d %d

tool: {"D59": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D23: 3.141592653589793

tool: {"D61": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D30": [0x65,0x73,0x2d,0x38,0x52,0xc1,0xe0,0x3f]}

tool: {"D31": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D54: %.8f


assistant: ```c
int main() {
  while (1) {
    int D, V;
    scanf("%d %d", &D, &V);
    if (!D && !V)
      break;
    printf("%.8f\n", pow((pow(D, 3) * 3.1415926535897932384626434 / 6 - V) / (3.1415926535897932384626434 / 6), 1.0 / 3));
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D57(%rip),%rbx
  jmp    L25
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D26(%rip),%xmm1
  call   <pow@plt>
  mulsd  D63(%rip),%xmm0
  divsd  D18(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  subsd  %xmm1,%xmm0
  divsd  D35(%rip),%xmm0
  movsd  D2(%rip),%xmm1
  call   <pow@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
L25:
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%ebp
  mov    %eax,%ecx
  or     %ebp,%ecx
  jne    L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D57
type_guessed: string
name: read_data
arguments: data_tag: D26
type_guessed: byte[8]
name: read_data
arguments: data_tag: D63
type_guessed: f64
name: read_data
arguments: data_tag: D18
type_guessed: byte[8]
name: read_data
arguments: data_tag: D35
type_guessed: byte[8]
name: read_data
arguments: data_tag: D2
type_guessed: byte[8]
name: read_data
arguments: data_tag: D16
type_guessed: string

tool: D57: %d %d

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D63: 3.141592653589793

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D35": [0x65,0x73,0x2d,0x38,0x52,0xc1,0xe0,0x3f]}

tool: {"D2": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D16: %.8f


assistant: ```c
int main() {
  while (1) {
    int D, V;
    scanf("%d %d", &D, &V);
    if (!D && !V)
      break;
    printf("%.8f\n", pow((pow(D, 3) * 3.1415926535897932384626434 / 6 - V) / (3.1415926535897932384626434 / 6), 1.0 / 3));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D28(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  jmp    L23
  nop
L11:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    D52(%rip),%rax
  movq   %rax,%xmm1
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  mov    D4(%rip),%rax
  cvtsi2sd %r13d,%xmm1
  mulsd  D46(%rip),%xmm0
  divsd  D41(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movq   %rax,%xmm1
  divsd  D0(%rip),%xmm0
  call   <pow@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
L23:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  mov    0x4(%rsp),%r13d
  mov    %eax,%ecx
  or     %r13d,%ecx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D28
type_guessed: string
name: retrieve_data
arguments: tag: D52
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D4
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D46
type_guessed: f64
name: retrieve_data
arguments: tag: D41
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D0
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D66
type_guessed: string

tool: D28: %d %d

tool: {"D52": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D4": [0x55,0x55,0x55,0x55,0x55,0x55,0xd5,0x3f]}

tool: D46: 3.141592653589793

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D0": [0x65,0x73,0x2d,0x38,0x52,0xc1,0xe0,0x3f]}

tool: D66: %.8f


assistant: ```c
int main() {
  while (1) {
    int D, V;
    scanf("%d %d", &D, &V);
    if (!D && !V)
      break;
    printf("%.8f\n", pow((pow(D, 3) * 3.1415926535897932384626434 / 6 - V) / (3.1415926535897932384626434 / 6), 1.0 / 3));
  }
  return 0;
}
```