ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_endian_swap_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movswl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <short_endian_swap@plt>
  mov    %ax,-0xa(%rbp)
  lea    -0xa(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void write_endian_swap_short(int socket, short num) {
  short len_for_send = short_endian_swap(num);
  write(socket, &(len_for_send), 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_endian_swap_short>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movswl %si,%edi
  call   <short_endian_swap@plt>
  mov    %ax,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %ebx,%edi
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_endian_swap_short(int socket, short num) {
  short len_for_send = short_endian_swap(num);
  write(socket, &(len_for_send), 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_endian_swap_short>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  movswl %si,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <short_endian_swap@plt>
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %ebp,%edi
  mov    %ax,0x6(%rsp)
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_endian_swap_short(int socket, short num) {
  short len_for_send = short_endian_swap(num);
  write(socket, &(len_for_send), 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_endian_swap_short>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  movswl %si,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <short_endian_swap@plt>
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %ebp,%edi
  mov    %ax,0x6(%rsp)
  call   <write@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void write_endian_swap_short(int socket, short num) {
  short len_for_send = short_endian_swap(num);
  write(socket, &(len_for_send), 2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L31
L39:
  cmpl   $0x1,-0x84(%rbp)
  jne    L4
  jmp    L31
L4:
  mov    -0x84(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x80(%rbp),%rax
  mov    %rax,%rdi
  call   <trimstr@plt>
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  lea    -0x80(%rbp),%rax
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <readln@plt>
  mov    %eax,-0x84(%rbp)
  cmpl   $0x0,-0x84(%rbp)
  jne    L39
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: string
name: read_data
arguments: label: D11
datatype: string

tool: D0: len=%d


tool: D11: TRIMMED:%s

assistant: ```c
int main() {
  int len;
  char s[120];
  while ((len = readln(s, 120)) != 0) {
    if (len == 1)
      continue;
    printf("len=%d\n", len);
    printf("TRIMMED:%s", trimstr(s));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D5(%rip),%r12
  lea    D17(%rip),%rbp
L7:
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <readln@plt>
  test   %eax,%eax
  je     L23
  cmp    $0x1,%eax
  je     L7
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <trimstr@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L23:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D5: len=%d


tool: D17: TRIMMED:%s

assistant: ```c
int main() {
  int len;
  char s[120];
  while ((len = readln(s, 120)) != 0) {
    if (len == 1)
      continue;
    printf("len=%d\n", len);
    printf("TRIMMED:%s", trimstr(s));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   (%rax)
L0:
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <readln@plt>
  mov    %eax,%esi
  test   %eax,%eax
  je     L37
  cmp    $0x1,%esi
  je     L0
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <trimstr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
  nopl   0x0(%rax)
L37:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D18: len=%d


tool: D5: TRIMMED:%s

assistant: ```c
int main() {
  int len;
  char s[120];
  while ((len = readln(s, 120)) != 0) {
    if (len == 1)
      continue;
    printf("len=%d\n", len);
    printf("TRIMMED:%s", trimstr(s));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopl   (%rax)
L11:
  mov    $0x78,%esi
  mov    %rbx,%rdi
  call   <readln@plt>
  mov    %eax,%esi
  test   %eax,%eax
  je     L30
  cmp    $0x1,%esi
  je     L11
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <trimstr@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
  nopl   0x0(%rax)
L30:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D15
type_guessed: string
name: read_data
arguments: tag: D8
type_guessed: string

tool: D15: len=%d


tool: D8: TRIMMED:%s

assistant: ```c
int main() {
  int len;
  char s[120];
  while ((len = readln(s, 120)) != 0) {
    if (len == 1)
      continue;
    printf("len=%d\n", len);
    printf("TRIMMED:%s", trimstr(s));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<next_column>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  jmp    L10
L3:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int next_column(int position, int tabsize) {
  if (tabsize == 0) {
    return 0;
  }
  return tabsize - (position % tabsize);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<next_column>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  test   %esi,%esi
  je     L1
  cltd
  idiv   %esi
  sub    %edx,%ecx
L1:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int next_column(int position, int tabsize) {
  if (tabsize == 0) {
    return 0;
  }
  return tabsize - (position % tabsize);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<next_column>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L4
  cltd
  idiv   %esi
  sub    %edx,%esi
  mov    %esi,%r8d
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int next_column(int position, int tabsize) {
  if (tabsize == 0) {
    return 0;
  }
  return tabsize - (position % tabsize);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<next_column>:
  endbr64
  mov    %edi,%eax
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L0
  cltd
  idiv   %esi
  sub    %edx,%esi
  mov    %esi,%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int next_column(int position, int tabsize) {
  if (tabsize == 0) {
    return 0;
  }
  return tabsize - (position % tabsize);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dot_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L9
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dot_product(double *vec1, double *vec2, int K) {
  double sum = 0;
  for (int k = 0; k < K; k++) {
    sum += vec1[k] * vec2[k];
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dot_product>:
  endbr64
  test   %edx,%edx
  jle    L14
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L27:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L27
L1:
  movapd %xmm1,%xmm0
  ret
L14:
  pxor   %xmm1,%xmm1
  jmp    L1
```

assistant: ```c
double dot_product(double *vec1, double *vec2, int K) {
  double sum = 0;
  for (int k = 0; k < K; k++) {
    sum += vec1[k] * vec2[k];
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dot_product>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L8:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L8
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L14:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double dot_product(double *vec1, double *vec2, int K) {
  double sum = 0;
  for (int k = 0; k < K; k++) {
    sum += vec1[k] * vec2[k];
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dot_product>:
  endbr64
  test   %edx,%edx
  jle    L28
  cmp    $0x1,%edx
  je     L42
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L13:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L13
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L38
L2:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L38:
  ret
  nopl   0x0(%rax)
L28:
  pxor   %xmm0,%xmm0
  ret
L42:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L2
```

assistant: ```c
double dot_product(double *vec1, double *vec2, int K) {
  double sum = 0;
  for (int k = 0; k < K; k++) {
    sum += vec1[k] * vec2[k];
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x4,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jle    L5
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <omp_quiesce_overhead@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int thr_num = 4;
  if (argc >= 2)
    thr_num = (atoi(argv[1]));
  omp_quiesce_overhead(thr_num);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    $0x4,%edi
  cmp    $0x1,%eax
  jg     L0
L3:
  call   <omp_quiesce_overhead@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  jmp    L3
```

assistant: ```c
int main(int argc, char *argv[]) {
  int thr_num = 4;
  if (argc >= 2)
    thr_num = (atoi(argv[1]));
  omp_quiesce_overhead(thr_num);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    $0x4,%edi
  cmp    $0x1,%r8d
  jle    L6
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
L6:
  call   <omp_quiesce_overhead@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int thr_num = 4;
  if (argc >= 2)
    thr_num = (atoi(argv[1]));
  omp_quiesce_overhead(thr_num);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    $0x4,%edi
  cmp    $0x1,%r8d
  jle    L9
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
L9:
  call   <omp_quiesce_overhead@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int thr_num = 4;
  if (argc >= 2)
    thr_num = (atoi(argv[1]));
  omp_quiesce_overhead(thr_num);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_139_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x20(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_139_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T ^ *D;
  stk2 = S | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_139_0_0>:
  endbr64
  xor    (%rdi),%dl
  or     %esi,%edx
  xor    (%rdi),%dl
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_139_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T ^ *D;
  stk2 = S | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rop3_139_0_0>:
  endbr64
  xor    (%rdi),%dl
  or     %esi,%edx
  xor    (%rdi),%dl
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_139_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T ^ *D;
  stk2 = S | stk3;
  stk1 = *D ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init_prg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <srand@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D1: Seed: %d


assistant: ```c
void init_prg(void) {
  time_t seed = time(NULL);
  printf("Seed: %d\n", (int)seed);
  srand(seed);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_prg>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rbx
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <srand@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: Seed: %d


assistant: ```c
void init_prg(void) {
  time_t seed = time(NULL);
  printf("Seed: %d\n", (int)seed);
  srand(seed);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<init_prg>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <time@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rbp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <srand@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: Seed: %d


assistant: ```c
void init_prg(void) {
  time_t seed = time(NULL);
  printf("Seed: %d\n", (int)seed);
  srand(seed);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_prg>:
  endbr64
  push   %rbp
  xor    %edi,%edi
  call   <time@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rbp
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <srand@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: Seed: %d


assistant: ```c
void init_prg(void) {
  time_t seed = time(NULL);
  printf("Seed: %d\n", (int)seed);
  srand(seed);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_field_imm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movswl %ax,%edx
  lea    -0x30(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: %d

assistant: ```c
char *get_field_imm(long instr) {
  char tmpstr[25];
  sprintf(tmpstr, "%d", (short)((instr & 0x0000FFFF) >> 0));
  return (strdup(tmpstr));
}
```
user: What is the c source code of the assembly code below:

```asm
<get_field_imm>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movswl %di,%edx
  mov    %rsp,%rbx
  lea    D1(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
data_type: string

tool: D1: %d

assistant: ```c
char *get_field_imm(long instr) {
  char tmpstr[25];
  sprintf(tmpstr, "%d", (short)((instr & 0x0000FFFF) >> 0));
  return (strdup(tmpstr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_field_imm>:
  endbr64
  push   %rbp
  movswl %di,%edx
  lea    D2(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %d

assistant: ```c
char *get_field_imm(long instr) {
  char tmpstr[25];
  sprintf(tmpstr, "%d", (short)((instr & 0x0000FFFF) >> 0));
  return (strdup(tmpstr));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_field_imm>:
  endbr64
  push   %rbp
  movswl %di,%edx
  lea    D8(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
char *get_field_imm(long instr) {
  char tmpstr[25];
  sprintf(tmpstr, "%d", (short)((instr & 0x0000FFFF) >> 0));
  return (strdup(tmpstr));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pasa_ez_komilla>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L10
L4:
  addq   $0x1,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L4
L13:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *pasa_ez_komilla(char *s) {
  while ((*s != '\42') && (*s != '\n'))
    s++;
  return (s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pasa_ez_komilla>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x22,%dl
  je     L8
  cmp    $0xa,%dl
  je     L8
L4:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x22,%dl
  je     L8
  cmp    $0xa,%dl
  jne    L4
L8:
  ret
```

assistant: ```c
char *pasa_ez_komilla(char *s) {
  while ((*s != '\42') && (*s != '\n'))
    s++;
  return (s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pasa_ez_komilla>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x22,%dl
  jne    L8
  jmp    L21
  nopl   0x0(%rax)
L31:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x22,%dl
  je     L21
L8:
  cmp    $0xa,%dl
  jne    L31
L21:
  ret
```

assistant: ```c
char *pasa_ez_komilla(char *s) {
  while ((*s != '\42') && (*s != '\n'))
    s++;
  return (s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pasa_ez_komilla>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x22,%dl
  jne    L36
  jmp    L4
  nopl   0x0(%rax)
L18:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x22,%dl
  je     L4
L36:
  cmp    $0xa,%dl
  jne    L18
L4:
  ret
```

assistant: ```c
char *pasa_ez_komilla(char *s) {
  while ((*s != '\42') && (*s != '\n'))
    s++;
  return (s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mem_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    $0x0,%eax
  jmp    L13
L6:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
L13:
  leave
  ret
```

assistant: ```c
void *mem_double(void *ptr, int size) {
  void *newptr;
  newptr = calloc(2 * size, 1);
  if (newptr == NULL)
    return NULL;
  memcpy(newptr, ptr, size);
  free(ptr);
  return newptr;
}
```