user: 请从给定的汇编指令推导出C源代码：

```asm
<dictionary>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc70,%rsp
  mov    %esi,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xc68(%rsp)
  xor    %eax,%eax
  lea    0x238(%rsp),%rdx
  lea    0xcc8(%rsp),%rsi
  mov    $0x0,%ecx
L122:
  movl   $0x0,0x10(%rsp,%rcx,1)
  movl   $0x0,0x80(%rsp,%rcx,1)
  movl   $0x0,0xf0(%rsp,%rcx,1)
  movl   $0x0,0x160(%rsp,%rcx,1)
  lea    -0x68(%rdx),%rax
L105:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L105
  add    $0x68,%rdx
  add    $0x4,%rcx
  cmp    %rsi,%rdx
  jne    L122
  cmp    $0x1,%r8d
  jle    L202
  mov    %rdi,%rbp
  lea    -0x2(%r8),%eax
  lea    0x8(%rdi,%rax,8),%r12
  jmp    L28
L204:
  mov    %rax,%rdx
L154:
  mov    %rdx,%r8
  movzbl (%rdx),%eax
  movzbl (%rcx),%esi
  cmp    %sil,%al
  jne    L39
  lea    0x1(%rdx),%rax
  add    $0x1,%rcx
  cmp    %rdi,%rdx
  jne    L204
  jmp    L168
L39:
  movsbl %sil,%edx
  sub    $0x61,%edx
  movslq %edx,%rdx
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  lea    (%rax,%rax,2),%rcx
  lea    (%rax,%rcx,4),%rax
  lea    (%rdx,%rax,2),%rax
  movl   $0x1,0x1d0(%rsp,%rax,4)
  movsbl (%r8),%eax
  sub    $0x61,%eax
  cltq
  movl   $0x1,0x10(%rsp,%rax,4)
L168:
  add    $0x8,%rbp
  cmp    %r12,%rbp
  je     L202
L28:
  mov    0x0(%rbp),%r13
  mov    0x8(%rbp),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %r14d,%esi
  call   <min@plt>
  test   %eax,%eax
  jle    L168
  mov    %r13,%rdx
  mov    %rbx,%rcx
  lea    -0x1(%rax),%eax
  lea    0x0(%r13,%rax,1),%rdi
  jmp    L154
L202:
  movl   $0x0,0xc(%rsp)
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rbp
  jmp    L92
L186:
  add    $0x1,%rbx
  cmp    $0x1a,%rbx
  je     L139
L92:
  mov    %ebx,%r8d
  cmpl   $0x0,0x0(%rbp,%rbx,4)
  je     L186
  cmpl   $0x0,0x80(%rsp,%rbx,4)
  jne    L186
  lea    0xf0(%rsp),%rdx
  lea    0x80(%rsp),%rsi
  lea    0x1d0(%rsp),%rdi
  lea    0xc(%rsp),%r9
  mov    %rbp,%rcx
  call   <dfs@plt>
  jmp    L186
L139:
  lea    0xf0(%rsp),%rsi
  lea    0x154(%rsp),%rax
  lea    0x160(%rsp),%rdx
L85:
  mov    (%rax),%ecx
  mov    %ecx,(%rdx)
  mov    %rax,%rcx
  sub    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rsi,%rcx
  jne    L85
  mov    $0x1,%r9d
  lea    0x10(%rsp),%rcx
  jmp    L10
L136:
  add    $0x1,%rax
  cmp    $0x19,%eax
  jg     L180
L53:
  cmpl   $0x0,(%rcx,%rax,4)
  je     L136
  movslq 0x160(%rsp,%r8,4),%rsi
  movslq 0x160(%rsp,%rax,4),%rdx
  lea    (%rdx,%rdx,2),%rdi
  lea    (%rdx,%rdi,4),%rdx
  lea    (%rsi,%rdx,2),%rdx
  cmpl   $0x1,0x1d0(%rsp,%rdx,4)
  jne    L136
  lea    D4(%rip),%rdi
  call   <printf@plt>
L228:
  mov    0xc68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0xc70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L180:
  add    $0x1,%r9
  cmp    $0x1a,%r9
  je     L228
L10:
  lea    -0x1(%r9),%r8d
  mov    %r9,%rax
  movslq %r8d,%r8
  jmp    L53
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string

tool: D4: invalid

assistant: ```c
void dictionary(char **words, int count) {
  int i = 0, j = 0;
  int graph[26][26];
  int counter[26];
  int visited[26];
  int result[26];
  int reverse_result[26];
  for (i = 0; i < 26; i++) {
    counter[i] = 0;
    visited[i] = 0;
    result[i] = 0;
    reverse_result[i] = 0;
    for (j = 0; j < 26; j++) {
      graph[i][j] = 0;
    }
  }
  for (i = 0; i < count - 1; i++) {
    char *w1 = words[i];
    char *w2 = words[i + 1];
    int len = min(strlen(w1), strlen(w2));
    for (j = 0; j < len; j++) {
      if (w1[j] != w2[j]) {
        graph[w1[j] - 'a'][w2[j] - 'a'] = 1;
        counter[w1[j] - 'a'] = 1;
        break;
      }
    }
  }
  int result_idx = 0;
  for (i = 0; i < 26; i++) {
    if (counter[i] && !visited[i]) {
      dfs(graph, visited, result, counter, i, &result_idx);
    }
  }
  for (i = 0; i < 26; i++) {
    reverse_result[i] = result[25 - i];
  }
  for (i = 0; i < 26; i++) {
    for (j = i + 1; j < 26; j++) {
      if (counter[j] && graph[reverse_result[j]][reverse_result[i]] == 1) {
        printf("invalid");
        return;
      }
    }
  }
}
```