user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L138
L71:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x2,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L138:
  mov    -0x20(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L71
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L64
L37:
  addl   $0x2,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L64:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L37
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L96
L41:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L96:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L41
  mov    $0x2a,%edi
  call   <putchar@plt>
  subl   $0x1,-0x18(%rbp)
  jmp    L87
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0xffffffff,-0x14(%rbp)
  jmp    L25
L72:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L25:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L72
  mov    $0x2a,%edi
  call   <putchar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L102:
  mov    $0x23,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L102
  addl   $0x2,-0xc(%rbp)
  mov    $0x2a,%edi
  call   <putchar@plt>
  subl   $0x1,-0x18(%rbp)
L87:
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L31
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L135
L0:
  mov    $0x2a,%edi
  call   <putchar@plt>
  addl   $0x1,-0x14(%rbp)
L135:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %d

assistant: ```c
int main() {
  int empty = 0, row, k, i = 0, j = 1, hashes = 1;
  scanf("%d", &row);
  for (i = 0; i < row - 2; i++) {
    hashes = hashes + j;
    j = j + 2;
  }
  hashes--;
  printf("%d", hashes);
  hashes = 1;
  for (i = 0; i < row; i++) {
    empty = empty + 2;
  }
  empty--;
  k = empty / 2 - 1;
  printf("\n");
  for (i = -1; i < k; i++) {
    printf(" ");
  }
  printf("*");
  k--;
  while (k != -1) {
    printf("\n");
    for (i = -1; i < k; i++) {
      printf(" ");
    }
    printf("*");
    for (i = 0; i < hashes; i++) {
      printf("#");
    }
    hashes = hashes + 2;
    printf("*");
    k--;
  }
  printf("\n");
  for (i = 0; i < empty; i++) {
    printf("*");
  }
  return 0;
}
```