ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<data_valid>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L12
L30:
  cmp    %edx,(%rdi)
  je     L25
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int data_valid(int *data, int size, int value) {
  int i;
  for (i = 0; i < size; i++) {
    if (data[i] != value) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tm_diffcalendardays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  sub    $0x8,%rsp
  push   0x20(%rbp)
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <tm_getrepresentation@plt>
  add    $0x20,%rsp
  mov    %rax,%rbx
  sub    $0x8,%rsp
  push   0x38(%rbp)
  push   0x30(%rbp)
  push   0x28(%rbp)
  call   <tm_getrepresentation@plt>
  add    $0x20,%rsp
  cmp    %rax,%rbx
  je     L46
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L21
L46:
  movl   $0x1,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  mov    0x28(%rbp),%rdx
  mov    0x10(%rbp),%rax
  cmp    %rax,%rdx
  jge    L4
  mov    0x10(%rbp),%rax
  mov    0x18(%rbp),%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    0x20(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    0x28(%rbp),%rax
  mov    0x30(%rbp),%rdx
  mov    %rax,0x10(%rbp)
  mov    %rdx,0x18(%rbp)
  mov    0x38(%rbp),%rax
  mov    %rax,0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,0x28(%rbp)
  mov    %rdx,0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,0x38(%rbp)
  movl   $0xffffffff,-0x38(%rbp)
L4:
  mov    0x30(%rbp),%eax
  mov    0x18(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  movl   $0xb,0x1c(%rbp)
  movl   $0x1f,0x20(%rbp)
  jmp    L48
L40:
  lea    0x10(%rbp),%rdi
  call   <tm_normalize@plt>
  mov    0x18(%rbp),%eax
  add    $0x1,%eax
  add    %eax,-0x34(%rbp)
  mov    0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,0x10(%rbp)
L48:
  mov    0x10(%rbp),%rdx
  mov    0x28(%rbp),%rax
  cmp    %rax,%rdx
  jl     L40
  mov    -0x38(%rbp),%eax
  imul   -0x34(%rbp),%eax
L21:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int tm_diffcalendardays(struct tm debut, struct tm fin) {
  if (tm_getrepresentation(debut) != tm_getrepresentation(fin)) {
    errno = EINVAL;
    return 0;
  }
  int coeff = 1;
  int ret = 0;
  if (fin.tm_year < debut.tm_year) {
    struct tm tmp = debut;
    debut = fin;
    fin = tmp;
    coeff = -1;
  }
  ret = fin.tm_yday - debut.tm_yday;
  debut.tm_mon = 11;
  debut.tm_mday = 31;
  for (; debut.tm_year < fin.tm_year; debut.tm_year++) {
    tm_normalize(&debut);
    ret += debut.tm_yday + 1;
  }
  return coeff * ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<tm_diffcalendardays>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%rbp
  mov    0x40(%rsp),%ebx
  sub    $0x8,%rsp
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <tm_getrepresentation@plt>
  mov    %rax,%r12
  add    $0x18,%rsp
  push   0x50(%rsp)
  push   0x50(%rsp)
  push   0x50(%rsp)
  call   <tm_getrepresentation@plt>
  add    $0x20,%rsp
  cmp    %rax,%r12
  je     L22
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    0x20(%rsp),%rax
  mov    $0x1,%r12d
  cmp    %rbp,%rax
  jle    L35
  mov    0x28(%rsp),%ebx
  movdqu 0x38(%rsp),%xmm0
  movups %xmm0,0x20(%rsp)
  mov    0x48(%rsp),%rdx
  mov    %rdx,0x30(%rsp)
  mov    %rax,%rbp
  mov    $0xffffffff,%r12d
L35:
  sub    0x28(%rsp),%ebx
  movl   $0xb,0x2c(%rsp)
  movl   $0x1f,0x30(%rsp)
  cmp    0x20(%rsp),%rbp
  jle    L14
L20:
  lea    0x20(%rsp),%rdi
  call   <tm_normalize@plt>
  mov    0x28(%rsp),%edx
  lea    0x1(%rbx,%rdx,1),%ebx
  mov    0x20(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x20(%rsp)
  cmp    %rbp,%rax
  jl     L20
L14:
  mov    %r12d,%eax
  imul   %ebx,%eax
  jmp    L33
```

assistant: ```c
int tm_diffcalendardays(struct tm debut, struct tm fin) {
  if (tm_getrepresentation(debut) != tm_getrepresentation(fin)) {
    errno = EINVAL;
    return 0;
  }
  int coeff = 1;
  int ret = 0;
  if (fin.tm_year < debut.tm_year) {
    struct tm tmp = debut;
    debut = fin;
    fin = tmp;
    coeff = -1;
  }
  ret = fin.tm_yday - debut.tm_yday;
  debut.tm_mon = 11;
  debut.tm_mday = 31;
  for (; debut.tm_year < fin.tm_year; debut.tm_year++) {
    tm_normalize(&debut);
    ret += debut.tm_yday + 1;
  }
  return coeff * ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tm_diffcalendardays>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%rbp
  mov    0x40(%rsp),%ebx
  sub    $0x8,%rsp
  push   0x38(%rsp)
  push   0x38(%rsp)
  push   0x38(%rsp)
  call   <tm_getrepresentation@plt>
  add    $0x18,%rsp
  push   0x50(%rsp)
  mov    %rax,%r12
  push   0x50(%rsp)
  push   0x50(%rsp)
  call   <tm_getrepresentation@plt>
  add    $0x20,%rsp
  cmp    %rax,%r12
  je     L49
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    0x20(%rsp),%rax
  cmp    %rbp,%rax
  jle    L2
  movdqu 0x38(%rsp),%xmm0
  mov    0x48(%rsp),%rdx
  mov    %rax,%rbp
  movabs $0x1f0000000b,%rcx
  mov    0x28(%rsp),%ebx
  mov    $0xffffffff,%r12d
  movups %xmm0,0x20(%rsp)
  sub    0x28(%rsp),%ebx
  mov    %rdx,0x30(%rsp)
  mov    %rcx,0x2c(%rsp)
  nop
L17:
  lea    0x20(%rsp),%rdi
  call   <tm_normalize@plt>
  mov    0x28(%rsp),%eax
  lea    0x1(%rbx,%rax,1),%ebx
  mov    0x20(%rsp),%rax
  add    $0x1,%rax
  mov    %rax,0x20(%rsp)
  cmp    %rbp,%rax
  jl     L17
L16:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
L2:
  movabs $0x1f0000000b,%rsi
  sub    0x28(%rsp),%ebx
  mov    $0x1,%r12d
  mov    %rsi,0x2c(%rsp)
  cmp    %rbp,%rax
  jl     L17
  jmp    L16
```

assistant: ```c
int tm_diffcalendardays(struct tm debut, struct tm fin) {
  if (tm_getrepresentation(debut) != tm_getrepresentation(fin)) {
    errno = EINVAL;
    return 0;
  }
  int coeff = 1;
  int ret = 0;
  if (fin.tm_year < debut.tm_year) {
    struct tm tmp = debut;
    debut = fin;
    fin = tmp;
    coeff = -1;
  }
  ret = fin.tm_yday - debut.tm_yday;
  debut.tm_mon = 11;
  debut.tm_mday = 31;
  for (; debut.tm_year < fin.tm_year; debut.tm_year++) {
    tm_normalize(&debut);
    ret += debut.tm_yday + 1;
  }
  return coeff * ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ah_update_keys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  xor    -0x1c(%rbp),%eax
  cltq
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x8,%rax
  xor    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  imul   $0x8088405,%rax,%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  add    $0x1,%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  shr    $0x18,%rax
  mov    %eax,%ebx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  xor    %ebx,%eax
  cltq
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  shr    $0x8,%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  xor    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int ah_update_keys(unsigned long *pkeys, const unsigned long *pcrc_32_tab, int c) {
  (*(pkeys + 0)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 0))) ^ (c)) & 0xff))) ^ (((*(pkeys + 0))) >> 8));
  (*(pkeys + 1)) += (*(pkeys + 0)) & 0xff;
  (*(pkeys + 1)) = (*(pkeys + 1)) * 134775813L + 1;
  {
    register int keyshift = (int)((*(pkeys + 1)) >> 24);
    (*(pkeys + 2)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 2))) ^ (keyshift)) & 0xff))) ^ (((*(pkeys + 2))) >> 8));
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ah_update_keys>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  mov    %edx,%esi
  mov    (%rcx),%rax
  xor    %eax,%edx
  movzbl %dl,%edx
  shr    $0x8,%rax
  xor    (%rdi,%rdx,8),%rax
  mov    %rax,(%rcx)
  movzbl %al,%eax
  add    0x8(%rcx),%rax
  imul   $0x8088405,%rax,%rax
  add    $0x1,%rax
  mov    %rax,0x8(%rcx)
  mov    0x10(%rcx),%rdx
  shr    $0x18,%rax
  xor    %edx,%eax
  movzbl %al,%eax
  shr    $0x8,%rdx
  xor    (%rdi,%rax,8),%rdx
  mov    %rdx,0x10(%rcx)
  mov    %esi,%eax
  ret
```

assistant: ```c
int ah_update_keys(unsigned long *pkeys, const unsigned long *pcrc_32_tab, int c) {
  (*(pkeys + 0)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 0))) ^ (c)) & 0xff))) ^ (((*(pkeys + 0))) >> 8));
  (*(pkeys + 1)) += (*(pkeys + 0)) & 0xff;
  (*(pkeys + 1)) = (*(pkeys + 1)) * 134775813L + 1;
  {
    register int keyshift = (int)((*(pkeys + 1)) >> 24);
    (*(pkeys + 2)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 2))) ^ (keyshift)) & 0xff))) ^ (((*(pkeys + 2))) >> 8));
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ah_update_keys>:
  endbr64
  mov    (%rdi),%rax
  mov    %edx,%r8d
  xor    %eax,%edx
  shr    $0x8,%rax
  movzbl %dl,%edx
  xor    (%rsi,%rdx,8),%rax
  mov    0x10(%rdi),%rdx
  mov    %rax,(%rdi)
  movzbl %al,%eax
  add    0x8(%rdi),%rax
  imul   $0x8088405,%rax,%rax
  add    $0x1,%rax
  mov    %rax,0x8(%rdi)
  shr    $0x18,%rax
  xor    %edx,%eax
  shr    $0x8,%rdx
  movzbl %al,%eax
  xor    (%rsi,%rax,8),%rdx
  mov    %r8d,%eax
  mov    %rdx,0x10(%rdi)
  ret
```

assistant: ```c
int ah_update_keys(unsigned long *pkeys, const unsigned long *pcrc_32_tab, int c) {
  (*(pkeys + 0)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 0))) ^ (c)) & 0xff))) ^ (((*(pkeys + 0))) >> 8));
  (*(pkeys + 1)) += (*(pkeys + 0)) & 0xff;
  (*(pkeys + 1)) = (*(pkeys + 1)) * 134775813L + 1;
  {
    register int keyshift = (int)((*(pkeys + 1)) >> 24);
    (*(pkeys + 2)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 2))) ^ (keyshift)) & 0xff))) ^ (((*(pkeys + 2))) >> 8));
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ah_update_keys>:
  endbr64
  mov    %edx,%r8d
  mov    (%rdi),%rdx
  mov    %r8d,%eax
  xor    %edx,%eax
  shr    $0x8,%rdx
  movzbl %al,%eax
  xor    (%rsi,%rax,8),%rdx
  movzbl %dl,%eax
  add    0x8(%rdi),%rax
  movq   %rdx,%xmm0
  mov    0x10(%rdi),%rdx
  imul   $0x8088405,%rax,%rax
  add    $0x1,%rax
  movq   %rax,%xmm1
  shr    $0x18,%rax
  xor    %edx,%eax
  punpcklqdq %xmm1,%xmm0
  shr    $0x8,%rdx
  movzbl %al,%eax
  movups %xmm0,(%rdi)
  xor    (%rsi,%rax,8),%rdx
  mov    %r8d,%eax
  mov    %rdx,0x10(%rdi)
  ret
```

assistant: ```c
int ah_update_keys(unsigned long *pkeys, const unsigned long *pcrc_32_tab, int c) {
  (*(pkeys + 0)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 0))) ^ (c)) & 0xff))) ^ (((*(pkeys + 0))) >> 8));
  (*(pkeys + 1)) += (*(pkeys + 0)) & 0xff;
  (*(pkeys + 1)) = (*(pkeys + 1)) * 134775813L + 1;
  {
    register int keyshift = (int)((*(pkeys + 1)) >> 24);
    (*(pkeys + 2)) = ((*(pcrc_32_tab + (((int)((*(pkeys + 2))) ^ (keyshift)) & 0xff))) ^ (((*(pkeys + 2))) >> 8));
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mean_sd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L29
L22:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addl   $0x1,-0x24(%rbp)
L29:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L22
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x3c(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L37
L13:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x24(%rbp)
L37:
  mov    -0x24(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L13
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x3c(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    -0x50(%rbp),%rdx
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void mean_sd(double *x, int n, double *mean, double *sd) {
  double ave, var, diff, error;
  int i;
  ave = 0.0;
  for (i = 0; i < n; i++)
    ave += x[i];
  ave /= n;
  diff = var = 0.0;
  for (i = 0; i < n; i++) {
    diff = x[i] - ave;
    error += diff;
    var += diff * diff;
  }
  var = (var - error * error / n) / (n - 1);
  *mean = ave;
  *sd = sqrt(var);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mean_sd>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  test   %esi,%esi
  jle    L5
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x8(%rdi,%rcx,8),%rcx
  pxor   %xmm2,%xmm2
L0:
  addsd  (%rdi),%xmm2
  add    $0x8,%rdi
  cmp    %rcx,%rdi
  jne    L0
  pxor   %xmm4,%xmm4
  cvtsi2sd %esi,%xmm4
  divsd  %xmm4,%xmm2
  pxor   %xmm0,%xmm0
L48:
  movsd  (%rax),%xmm1
  subsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm3
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L48
L26:
  mulsd  %xmm3,%xmm3
  divsd  %xmm4,%xmm3
  subsd  %xmm3,%xmm0
  sub    $0x1,%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm2,(%rdx)
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L55
  sqrtsd %xmm0,%xmm0
L1:
  movsd  %xmm0,(%rbx)
  pop    %rbx
  ret
L55:
  call   <sqrt@plt>
  jmp    L1
L5:
  pxor   %xmm4,%xmm4
  cvtsi2sd %esi,%xmm4
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm2
  divsd  %xmm4,%xmm2
  jmp    L26
```

assistant: ```c
void mean_sd(double *x, int n, double *mean, double *sd) {
  double ave, var, diff, error;
  int i;
  ave = 0.0;
  for (i = 0; i < n; i++)
    ave += x[i];
  ave /= n;
  diff = var = 0.0;
  for (i = 0; i < n; i++) {
    diff = x[i] - ave;
    error += diff;
    var += diff * diff;
  }
  var = (var - error * error / n) / (n - 1);
  *mean = ave;
  *sd = sqrt(var);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mean_sd>:
  endbr64
  pxor   %xmm5,%xmm5
  cvtsi2sd %esi,%xmm5
  test   %esi,%esi
  jle    L30
  lea    -0x1(%rsi),%eax
  pxor   %xmm4,%xmm4
  mov    %rax,%rsi
  lea    0x8(%rdi,%rax,8),%r8
  movapd %xmm4,%xmm2
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L32:
  addsd  (%rax),%xmm2
  add    $0x8,%rax
  cmp    %rax,%r8
  jne    L32
  divsd  %xmm5,%xmm2
  movapd %xmm4,%xmm0
  nopl   (%rax)
L41:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  subsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm3
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdi,%r8
  jne    L41
L5:
  mulsd  %xmm3,%xmm3
  pxor   %xmm1,%xmm1
  movsd  %xmm2,(%rdx)
  cvtsi2sd %esi,%xmm1
  divsd  %xmm5,%xmm3
  subsd  %xmm3,%xmm0
  divsd  %xmm1,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L49
  sqrtsd %xmm0,%xmm0
  movsd  %xmm0,(%rcx)
  ret
L30:
  pxor   %xmm4,%xmm4
  sub    $0x1,%esi
  movapd %xmm4,%xmm2
  movapd %xmm4,%xmm0
  divsd  %xmm5,%xmm2
  jmp    L5
L49:
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x8(%rsp),%rcx
  movsd  %xmm0,(%rcx)
  add    $0x18,%rsp
  ret
```

assistant: ```c
void mean_sd(double *x, int n, double *mean, double *sd) {
  double ave, var, diff, error;
  int i;
  ave = 0.0;
  for (i = 0; i < n; i++)
    ave += x[i];
  ave /= n;
  diff = var = 0.0;
  for (i = 0; i < n; i++) {
    diff = x[i] - ave;
    error += diff;
    var += diff * diff;
  }
  var = (var - error * error / n) / (n - 1);
  *mean = ave;
  *sd = sqrt(var);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mean_sd>:
  endbr64
  pxor   %xmm5,%xmm5
  push   %rbx
  mov    %rdi,%rax
  mov    %rcx,%rbx
  cvtsi2sd %esi,%xmm5
  mov    %rdx,%rdi
  test   %esi,%esi
  jle    L5
  cmp    $0x1,%esi
  je     L48
  mov    %esi,%ecx
  lea    0x10(%rax),%r8
  pxor   %xmm6,%xmm6
  mov    %rax,%rdx
  shr    %ecx
  movapd %xmm6,%xmm0
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  add    %r8,%rcx
  nopl   0x0(%rax)
L58:
  movsd  (%rdx),%xmm1
  add    $0x10,%rdx
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rcx
  jne    L58
  mov    %esi,%edx
  and    $0xfffffffe,%edx
  cmp    %esi,%edx
  je     L14
L90:
  movslq %edx,%rdx
  addsd  (%rax,%rdx,8),%xmm0
  divsd  %xmm5,%xmm0
  cmp    $0x1,%esi
  je     L92
  lea    0x10(%rax),%r8
L3:
  mov    %esi,%ecx
  movapd %xmm0,%xmm7
  movapd %xmm6,%xmm3
  mov    %rax,%rdx
  shr    %ecx
  unpcklpd %xmm7,%xmm7
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  add    %r8,%rcx
  nopl   (%rax)
L6:
  movupd (%rdx),%xmm1
  add    $0x10,%rdx
  subpd  %xmm7,%xmm1
  movapd %xmm1,%xmm4
  addsd  %xmm2,%xmm4
  movapd %xmm1,%xmm2
  mulpd  %xmm1,%xmm1
  unpckhpd %xmm2,%xmm2
  addsd  %xmm4,%xmm2
  addsd  %xmm1,%xmm3
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm3
  cmp    %rdx,%rcx
  jne    L6
  mov    %esi,%edx
  and    $0xfffffffe,%edx
  test   $0x1,%sil
  je     L55
L105:
  movslq %edx,%rdx
  movsd  (%rax,%rdx,8),%xmm1
  subsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm2
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm3
L55:
  mulsd  %xmm2,%xmm2
  sub    $0x1,%esi
  pxor   %xmm1,%xmm1
  movsd  %xmm0,(%rdi)
  cvtsi2sd %esi,%xmm1
  divsd  %xmm5,%xmm2
  subsd  %xmm2,%xmm3
  divsd  %xmm1,%xmm3
  ucomisd %xmm3,%xmm6
  ja     L94
  sqrtsd %xmm3,%xmm3
L96:
  movsd  %xmm3,(%rbx)
  pop    %rbx
  ret
  nop
L92:
  xor    %edx,%edx
  movapd %xmm6,%xmm3
  jmp    L105
  nopl   0x0(%rax,%rax,1)
L14:
  divsd  %xmm5,%xmm0
  jmp    L3
  nopl   0x0(%rax)
L5:
  pxor   %xmm6,%xmm6
  movapd %xmm6,%xmm0
  movapd %xmm6,%xmm3
  divsd  %xmm5,%xmm0
  jmp    L55
L48:
  pxor   %xmm6,%xmm6
  xor    %edx,%edx
  movapd %xmm6,%xmm0
  jmp    L90
L94:
  movapd %xmm3,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm3
  jmp    L96
```

assistant: ```c
void mean_sd(double *x, int n, double *mean, double *sd) {
  double ave, var, diff, error;
  int i;
  ave = 0.0;
  for (i = 0; i < n; i++)
    ave += x[i];
  ave /= n;
  diff = var = 0.0;
  for (i = 0; i < n; i++) {
    diff = x[i] - ave;
    error += diff;
    var += diff * diff;
  }
  var = (var - error * error / n) / (n - 1);
  *mean = ave;
  *sd = sqrt(var);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L0
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L15
L0:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <get_host_addr@plt>
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: USAGE: %s host_or_domain


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("USAGE: %s host_or_domain\n", argv[0]);
    return 0;
  }
  get_host_addr(argv[1]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L5
  mov    0x8(%rsi),%rdi
  call   <get_host_addr@plt>
L16:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L5:
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string

tool: D0: USAGE: %s host_or_domain


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("USAGE: %s host_or_domain\n", argv[0]);
    return 0;
  }
  get_host_addr(argv[1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L1
  mov    0x8(%rsi),%rdi
  call   <get_host_addr@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L1:
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D6: USAGE: %s host_or_domain


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("USAGE: %s host_or_domain\n", argv[0]);
    return 0;
  }
  get_host_addr(argv[1]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L10
  mov    0x8(%rsi),%rdi
  call   <get_host_addr@plt>
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L10:
  mov    (%rsi),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: USAGE: %s host_or_domain


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("USAGE: %s host_or_domain\n", argv[0]);
    return 0;
  }
  get_host_addr(argv[1]);
  return 0;
}
```