ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<FatalError>:
  endbr64
  push   %rbx
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rsi
  lea    D43(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D35
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string
name: parse_data
arguments: label: D43
type_infered: string

tool: D11: 


tool: D35:  ***   Fatal Error!!!   *** 


tool: D19:  *** Processing Stopped *** 


tool: D18: w

tool: D43: _die_

assistant: ```c
void FatalError(void) {
  FILE *fd;
  printf("\n");
  printf(" ***   Fatal Error!!!   *** \n");
  printf(" *** Processing Stopped *** \n");
  printf("\n");
  fd = fopen("_die_", "w");
  fclose(fd);
  exit(2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FatalError>:
  endbr64
  push   %rbp
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rsi
  lea    D32(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x2,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D32
type_infered: string

tool: D20: 


tool: D15:  ***   Fatal Error!!!   *** 


tool: D5:  *** Processing Stopped *** 


tool: D7: w

tool: D32: _die_

assistant: ```c
void FatalError(void) {
  FILE *fd;
  printf("\n");
  printf(" ***   Fatal Error!!!   *** \n");
  printf(" *** Processing Stopped *** \n");
  printf("\n");
  fd = fopen("_die_", "w");
  fclose(fd);
  exit(2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<FatalError>:
  endbr64
  push   %rbp
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x2,%edi
  pop    %rbp
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string
name: retrieve_data
arguments: label: D23
datatype: string
name: retrieve_data
arguments: label: D39
datatype: string
name: retrieve_data
arguments: label: D15
datatype: string

tool: D26: 


tool: D49:  ***   Fatal Error!!!   *** 


tool: D23:  *** Processing Stopped *** 


tool: D39: w

tool: D15: _die_

assistant: ```c
void FatalError(void) {
  FILE *fd;
  printf("\n");
  printf(" ***   Fatal Error!!!   *** \n");
  printf(" *** Processing Stopped *** \n");
  printf("\n");
  fd = fopen("_die_", "w");
  fclose(fd);
  exit(2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_label>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <init_buffer@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <in_nonblank@plt>
  mov    %eax,-0x14(%rbp)
  jmp    L54
L10:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <add_then_next@plt>
  mov    %eax,-0x14(%rbp)
L54:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  je     L23
  cmpl   $0xa,-0x14(%rbp)
  je     L23
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <ISBLANK@plt>
  test   %eax,%eax
  jne    L23
  cmpl   $0x3b,-0x14(%rbp)
  je     L23
  cmpl   $0x7d,-0x14(%rbp)
  je     L23
  cmpl   $0x23,-0x14(%rbp)
  jne    L10
L23:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <savchar@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <add1_buffer@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <get_buffer@plt>
  mov    %eax,%edi
  call   <ck_strdup@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free_buffer@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *read_label(void) {
  struct buffer *b;
  int ch;
  char *ret;
  b = init_buffer();
  ch = in_nonblank();
  while (ch != EOF && ch != '\n' && !ISBLANK(ch) && ch != ';' && ch != '}' && ch != '#')
    ch = add_then_next(b, ch);
  savchar(ch);
  add1_buffer(b, '\0');
  ret = ck_strdup(get_buffer(b));
  free_buffer(b);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_label>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_buffer@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <in_nonblank@plt>
  mov    %eax,%ebx
  mov    D6(%rip),%rax
  cmp    %ebx,(%rax)
  je     L12
  cmp    $0xa,%ebx
  je     L12
L10:
  mov    %ebx,%edi
  call   <ISBLANK@plt>
  test   %eax,%eax
  jne    L12
  cmp    $0x3b,%ebx
  setne  %dl
  cmp    $0x7d,%ebx
  setne  %al
  test   %al,%dl
  je     L12
  cmp    $0x23,%ebx
  je     L12
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <add_then_next@plt>
  mov    %eax,%ebx
  mov    D6(%rip),%rax
  cmp    %ebx,(%rax)
  je     L12
  cmp    $0xa,%ebx
  jne    L10
L12:
  mov    %ebx,%edi
  call   <savchar@plt>
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <add1_buffer@plt>
  mov    %rbp,%rdi
  call   <get_buffer@plt>
  mov    %eax,%edi
  call   <ck_strdup@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <free_buffer@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *read_label(void) {
  struct buffer *b;
  int ch;
  char *ret;
  b = init_buffer();
  ch = in_nonblank();
  while (ch != EOF && ch != '\n' && !ISBLANK(ch) && ch != ';' && ch != '}' && ch != '#')
    ch = add_then_next(b, ch);
  savchar(ch);
  add1_buffer(b, '\0');
  ret = ck_strdup(get_buffer(b));
  free_buffer(b);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_label>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <init_buffer@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <in_nonblank@plt>
  mov    D2(%rip),%rbx
  mov    %eax,%ebp
  cmp    (%rbx),%eax
  jne    L15
  jmp    L12
  xchg   %ax,%ax
L79:
  mov    %ebp,%edi
  call   <ISBLANK@plt>
  test   %eax,%eax
  jne    L12
  cmp    $0x3b,%ebp
  je     L12
  cmp    $0x7d,%ebp
  je     L12
  cmp    $0x23,%ebp
  je     L12
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <add_then_next@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  je     L12
L15:
  cmp    $0xa,%ebp
  jne    L79
  mov    $0xa,%ebp
L12:
  mov    %ebp,%edi
  call   <savchar@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <add1_buffer@plt>
  mov    %r12,%rdi
  call   <get_buffer@plt>
  mov    %eax,%edi
  call   <ck_strdup@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free_buffer@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *read_label(void) {
  struct buffer *b;
  int ch;
  char *ret;
  b = init_buffer();
  ch = in_nonblank();
  while (ch != EOF && ch != '\n' && !ISBLANK(ch) && ch != ';' && ch != '}' && ch != '#')
    ch = add_then_next(b, ch);
  savchar(ch);
  add1_buffer(b, '\0');
  ret = ck_strdup(get_buffer(b));
  free_buffer(b);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_label>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <init_buffer@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <in_nonblank@plt>
  mov    D0(%rip),%rbx
  mov    %eax,%ebp
  cmp    (%rbx),%eax
  jne    L61
  jmp    L27
  xchg   %ax,%ax
L20:
  mov    %ebp,%edi
  call   <ISBLANK@plt>
  test   %eax,%eax
  jne    L27
  cmp    $0x3b,%ebp
  je     L27
  cmp    $0x7d,%ebp
  je     L27
  cmp    $0x23,%ebp
  je     L27
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <add_then_next@plt>
  mov    %eax,%ebp
  cmp    %eax,(%rbx)
  je     L27
L61:
  cmp    $0xa,%ebp
  jne    L20
  mov    $0xa,%ebp
L27:
  mov    %ebp,%edi
  call   <savchar@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <add1_buffer@plt>
  mov    %r12,%rdi
  call   <get_buffer@plt>
  mov    %eax,%edi
  call   <ck_strdup@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <free_buffer@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *read_label(void) {
  struct buffer *b;
  int ch;
  char *ret;
  b = init_buffer();
  ch = in_nonblank();
  while (ch != EOF && ch != '\n' && !ISBLANK(ch) && ch != ';' && ch != '}' && ch != '#')
    ch = add_then_next(b, ch);
  savchar(ch);
  add1_buffer(b, '\0');
  ret = ck_strdup(get_buffer(b));
  free_buffer(b);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo() {
  static int v4;
  {
    static int v5;
#pragma omp threadprivate(v4, v5)
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  static int v4;
  {
    static int v5;
#pragma omp threadprivate(v4, v5)
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  static int v4;
  {
    static int v5;
#pragma omp threadprivate(v4, v5)
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inv_mix_columns>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbx
  movl   $0x0,0x8(%rsp)
L2:
  mov    $0x0,%eax
  mov    %rbx,%rbp
L3:
  mov    (%rbx,%rax,1),%edx
  mov    %edx,0x10(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L3
  mov    0x10(%rsp),%r12d
  mov    $0xe,%esi
  mov    %r12d,%edi
  call   <gmul@plt>
  mov    %eax,%r13d
  mov    0x1c(%rsp),%r15d
  mov    $0x9,%esi
  mov    %r15d,%edi
  call   <gmul@plt>
  xor    %eax,%r13d
  mov    0x18(%rsp),%r14d
  mov    $0xd,%esi
  mov    %r14d,%edi
  call   <gmul@plt>
  xor    %eax,%r13d
  mov    %r13d,0xc(%rsp)
  mov    0x14(%rsp),%r13d
  mov    $0xb,%esi
  mov    %r13d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0x0(%rbp)
  mov    $0xe,%esi
  mov    %r13d,%edi
  call   <gmul@plt>
  mov    %eax,0xc(%rsp)
  mov    $0x9,%esi
  mov    %r12d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    $0xd,%esi
  mov    %r15d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    $0xb,%esi
  mov    %r14d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0x4(%rbp)
  mov    $0xe,%esi
  mov    %r14d,%edi
  call   <gmul@plt>
  mov    %eax,0xc(%rsp)
  mov    $0x9,%esi
  mov    %r13d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    $0xd,%esi
  mov    %r12d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0xc(%rsp)
  mov    $0xb,%esi
  mov    %r15d,%edi
  call   <gmul@plt>
  xor    0xc(%rsp),%eax
  mov    %eax,0x8(%rbp)
  mov    $0xe,%esi
  mov    %r15d,%edi
  call   <gmul@plt>
  mov    %eax,%r15d
  mov    $0x9,%esi
  mov    %r14d,%edi
  call   <gmul@plt>
  xor    %eax,%r15d
  mov    $0xd,%esi
  mov    %r13d,%edi
  call   <gmul@plt>
  xor    %eax,%r15d
  mov    %r15d,%r13d
  mov    $0xb,%esi
  mov    %r12d,%edi
  call   <gmul@plt>
  xor    %eax,%r13d
  mov    %r13d,0xc(%rbp)
  add    $0x10,%rbx
  addl   $0x4,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    $0x10,%eax
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void inv_mix_columns(uint8_t *state) {
  uint8_t a[4];
  for (uint8_t k = 0; k < 4; k++) {
    for (uint8_t i = 0; i < 4; i++) {
      a[i] = state[i + 4 * k];
    }
    state[4 * k] = gmul(a[0], 14) ^ gmul(a[3], 9) ^ gmul(a[2], 13) ^ gmul(a[1], 11);
    state[1 + 4 * k] = gmul(a[1], 14) ^ gmul(a[0], 9) ^ gmul(a[3], 13) ^ gmul(a[2], 11);
    state[2 + 4 * k] = gmul(a[2], 14) ^ gmul(a[1], 9) ^ gmul(a[0], 13) ^ gmul(a[3], 11);
    state[3 + 4 * k] = gmul(a[3], 14) ^ gmul(a[2], 9) ^ gmul(a[1], 13) ^ gmul(a[0], 11);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inv_mix_columns>:
  endbr64
  push   %r15
  xor    %edx,%edx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r8
L26:
  xor    %eax,%eax
L17:
  mov    (%rbx,%rax,1),%ecx
  mov    %ecx,(%r8,%rax,1)
  add    $0x4,%rax
  cmp    $0x10,%rax
  jne    L17
  mov    0x10(%rsp),%r12d
  mov    $0xe,%esi
  mov    %edx,0x4(%rsp)
  add    $0x10,%rbx
  mov    %r8,0x8(%rsp)
  mov    %r12d,%edi
  call   <gmul@plt>
  mov    0x1c(%rsp),%r15d
  mov    $0x9,%esi
  mov    %eax,%ebp
  mov    %r15d,%edi
  call   <gmul@plt>
  mov    0x18(%rsp),%r14d
  mov    $0xd,%esi
  xor    %eax,%ebp
  mov    %r14d,%edi
  call   <gmul@plt>
  mov    0x14(%rsp),%r13d
  mov    $0xb,%esi
  xor    %eax,%ebp
  mov    %r13d,%edi
  call   <gmul@plt>
  mov    $0xe,%esi
  mov    %r13d,%edi
  xor    %eax,%ebp
  mov    %ebp,-0x10(%rbx)
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r15d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r14d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xe,%esi
  mov    %r14d,%edi
  xor    %eax,%ebp
  mov    %ebp,-0xc(%rbx)
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r12d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r15d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xe,%esi
  mov    %r15d,%edi
  xor    %eax,%ebp
  mov    %ebp,-0x8(%rbx)
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r14d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r13d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r12d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%r8
  xor    %eax,%ebp
  add    $0x4,%edx
  mov    %ebp,-0x4(%rbx)
  cmp    $0x10,%edx
  jne    L26
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void inv_mix_columns(uint8_t *state) {
  uint8_t a[4];
  for (uint8_t k = 0; k < 4; k++) {
    for (uint8_t i = 0; i < 4; i++) {
      a[i] = state[i + 4 * k];
    }
    state[4 * k] = gmul(a[0], 14) ^ gmul(a[3], 9) ^ gmul(a[2], 13) ^ gmul(a[1], 11);
    state[1 + 4 * k] = gmul(a[1], 14) ^ gmul(a[0], 9) ^ gmul(a[3], 13) ^ gmul(a[2], 11);
    state[2 + 4 * k] = gmul(a[2], 14) ^ gmul(a[1], 9) ^ gmul(a[0], 13) ^ gmul(a[3], 11);
    state[3 + 4 * k] = gmul(a[3], 14) ^ gmul(a[2], 9) ^ gmul(a[1], 13) ^ gmul(a[0], 11);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<inv_mix_columns>:
  endbr64
  push   %r15
  lea    0x40(%rdi),%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
L9:
  mov    (%rbx),%r12d
  mov    0xc(%rbx),%r15d
  mov    $0xe,%esi
  add    $0x10,%rbx
  mov    -0x8(%rbx),%r14d
  mov    -0xc(%rbx),%r13d
  mov    %r12d,%edi
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r15d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r14d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r13d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xe,%esi
  mov    %r13d,%edi
  xor    %eax,%ebp
  mov    %ebp,-0x10(%rbx)
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r15d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r14d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xe,%esi
  mov    %r14d,%edi
  xor    %eax,%ebp
  mov    %ebp,-0xc(%rbx)
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r13d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r12d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r15d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xe,%esi
  mov    %r15d,%edi
  xor    %eax,%ebp
  mov    %ebp,-0x8(%rbx)
  call   <gmul@plt>
  mov    $0x9,%esi
  mov    %r14d,%edi
  mov    %eax,%ebp
  call   <gmul@plt>
  mov    $0xd,%esi
  mov    %r13d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  mov    $0xb,%esi
  mov    %r12d,%edi
  xor    %eax,%ebp
  call   <gmul@plt>
  xor    %eax,%ebp
  mov    %ebp,-0x4(%rbx)
  cmp    %rbx,0x8(%rsp)
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void inv_mix_columns(uint8_t *state) {
  uint8_t a[4];
  for (uint8_t k = 0; k < 4; k++) {
    for (uint8_t i = 0; i < 4; i++) {
      a[i] = state[i + 4 * k];
    }
    state[4 * k] = gmul(a[0], 14) ^ gmul(a[3], 9) ^ gmul(a[2], 13) ^ gmul(a[1], 11);
    state[1 + 4 * k] = gmul(a[1], 14) ^ gmul(a[0], 9) ^ gmul(a[3], 13) ^ gmul(a[2], 11);
    state[2 + 4 * k] = gmul(a[2], 14) ^ gmul(a[1], 9) ^ gmul(a[0], 13) ^ gmul(a[3], 11);
    state[3 + 4 * k] = gmul(a[3], 14) ^ gmul(a[2], 9) ^ gmul(a[1], 13) ^ gmul(a[0], 11);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_rest_of_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L6:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L6
L23:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <talloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *copy_rest_of_line(char *p) {
  char *s;
  for (s = p; *s && *s != '\n'; s++)
    ;
  *s = '\0';
  s = talloc(strlen(p) + 1);
  strcpy(s, p);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_rest_of_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  cmp    $0xa,%al
  je     L24
  mov    %rdi,%rax
L34:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L6
  cmp    $0xa,%dl
  jne    L34
L6:
  movb   $0x0,(%rax)
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <talloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    %rbx,%rax
  jmp    L6
```

assistant: ```c
char *copy_rest_of_line(char *p) {
  char *s;
  for (s = p; *s && *s != '\n'; s++)
    ;
  *s = '\0';
  s = talloc(strlen(p) + 1);
  strcpy(s, p);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_rest_of_line>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L39
  cmp    $0xa,%al
  je     L39
  mov    %rdi,%rax
  nopl   0x0(%rax)
L45:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L2
  cmp    $0xa,%dl
  jne    L45
L2:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <talloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L39:
  mov    %rbp,%rax
  jmp    L2
```

assistant: ```c
char *copy_rest_of_line(char *p) {
  char *s;
  for (s = p; *s && *s != '\n'; s++)
    ;
  *s = '\0';
  s = talloc(strlen(p) + 1);
  strcpy(s, p);
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_rest_of_line>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  cmp    $0xa,%al
  je     L9
  mov    %rdi,%rax
  nopl   0x0(%rax)
L25:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L24
  cmp    $0xa,%dl
  jne    L25
L24:
  movb   $0x0,(%rax)
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <talloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L9:
  mov    %rbp,%rax
  jmp    L24
```

assistant: ```c
char *copy_rest_of_line(char *p) {
  char *s;
  for (s = p; *s && *s != '\n'; s++)
    ;
  *s = '\0';
  s = talloc(strlen(p) + 1);
  strcpy(s, p);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pintar_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x14(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  add    %rax,%rax
  add    $0xb8000,%rax
  mov    %rax,D8(%rip)
  jmp    L1
L8:
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cbtw
  or     %eax,%ecx
  mov    D8(%rip),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,D13(%rip)
  mov    %ecx,%edx
  mov    %dx,(%rax)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pintar_string(char *msg, unsigned int x, unsigned int y, unsigned char color) {
  static unsigned short *p;
  p = (unsigned short *)0xb8000 + (80 * y + x);
  while (*msg) {
    *p++ = (color << 8) | *msg++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pintar_string>:
  endbr64
  lea    (%rdx,%rdx,4),%eax
  shl    $0x4,%eax
  lea    (%rax,%rsi,1),%eax
  lea    0xb8000(%rax,%rax,1),%rax
  mov    %rax,D6(%rip)
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L4
  shl    $0x8,%ecx
L10:
  add    $0x1,%rdi
  mov    %rax,%r8
  add    $0x2,%rax
  movsbw %sil,%dx
  or     %ecx,%edx
  mov    %dx,-0x2(%rax)
  movzbl (%rdi),%esi
  test   %sil,%sil
  jne    L10
  mov    %rax,D17(%rip)
  mov    %dx,(%r8)
L4:
  ret
```

assistant: ```c
void pintar_string(char *msg, unsigned int x, unsigned int y, unsigned char color) {
  static unsigned short *p;
  p = (unsigned short *)0xb8000 + (80 * y + x);
  while (*msg) {
    *p++ = (color << 8) | *msg++;
  }
}
```