ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<send_mail>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %r9,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r9,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  mov    0x50(%rsp),%r13
  call   <strlen@plt>
  mov    0x8(%rsp),%rcx
  mov    %rbp,%rdi
  mov    %rbx,%r8
  lea    0x7d0(%rax),%r9
  mov    %r15,%rdx
  mov    %r14,%rsi
  call   <smtp_start_mail@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L40
L23:
  test   %rbx,%rbx
  je     L18
  xor    %eax,%eax
  call   <lp_from_address@plt>
  lea    D5(%rip),%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <smtp_write@plt>
  lea    D3(%rip),%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <smtp_write@plt>
L18:
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <smtp_write_data@plt>
  test   %r13,%r13
  je     L20
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <smtp_write_data@plt>
L20:
  mov    %ebp,%edi
  call   <smtp_end_mail@plt>
  cmp    $0xffffffff,%eax
  je     L1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  call   <smtp_error@plt>
  mov    %eax,%edi
  call   <fatal@plt>
  jmp    L23
L1:
  xor    %eax,%eax
  call   <smtp_error@plt>
  add    $0x18,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1130 <fatal@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D3
type: string

tool: D5: X-Loop: %s


tool: D3: 


assistant: ```c
void send_mail(char *from, char *to, char *cc, char *bcc, char *subject, char *body, char *sig) {
  int fd;
  fd = smtp_start_mail(from, to, cc, bcc, subject, strlen(body) + 2000);
  if (fd == -1)
    fatal(smtp_error());
  if (subject) {
    smtp_write(fd, "X-Loop: %s\n", lp_from_address());
    smtp_write(fd, "\n");
  }
  smtp_write_data(fd, body);
  if (sig)
    smtp_write_data(fd, sig);
  if (smtp_end_mail(fd) == -1)
    fatal(smtp_error());
}
```
user: Translate the below assembly code into C programming language:

```asm
<number_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L8
L16:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_number_char@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int number_size(const char *s) {
  int result = 1;
  s++;
  while (is_number_char(*(s++)))
    result++;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<number_size>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0x1,%rdi
  mov    %rdi,%rbx
  mov    $0x1,%ebp
  sub    %edi,%ebp
L5:
  lea    0x0(%rbp,%rbx,1),%r12d
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  call   <is_number_char@plt>
  test   %rax,%rax
  jne    L5
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int number_size(const char *s) {
  int result = 1;
  s++;
  while (is_number_char(*(s++)))
    result++;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<number_size>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  neg    %ebp
  lea    0x1(%rdi),%rbx
L2:
  lea    0x0(%rbp,%rbx,1),%r12d
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <is_number_char@plt>
  test   %rax,%rax
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int number_size(const char *s) {
  int result = 1;
  s++;
  while (is_number_char(*(s++)))
    result++;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<number_size>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  neg    %ebp
  lea    0x1(%rdi),%rbx
L8:
  lea    0x0(%rbp,%rbx,1),%r12d
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <is_number_char@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int number_size(const char *s) {
  int result = 1;
  s++;
  while (is_number_char(*(s++)))
    result++;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<html_cvt_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  je     L16
  lea    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  jne    L16
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  jmp    L26
L16:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int html_cvt_long(const char *data, int len, void *dst, void *closure) {
  if (data) {
    char *e;
    long val;
    val = strtol(data, &e, 0);
    if (data + len == e) {
      long *d = dst;
      *d = val;
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<html_cvt_long>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L8
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %rsp,%rsi
  mov    $0x0,%edx
  call   <strtol@plt>
  mov    %rax,%rcx
  movslq %ebp,%rdx
  add    %rdx,%rbx
  mov    $0x0,%eax
  cmp    %rbx,(%rsp)
  je     L20
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  mov    %rcx,(%r12)
  mov    $0x1,%eax
  jmp    L8
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int html_cvt_long(const char *data, int len, void *dst, void *closure) {
  if (data) {
    char *e;
    long val;
    val = strtol(data, &e, 0);
    if (data + len == e) {
      long *d = dst;
      *d = val;
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<html_cvt_long>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L39
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %rsp,%rsi
  xor    %edx,%edx
  mov    %rdi,%rbx
  call   <strtol@plt>
  movslq %ebp,%rsi
  add    %rsi,%rbx
  cmp    %rbx,(%rsp)
  je     L7
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rax,(%r12)
  mov    $0x1,%r13d
  jmp    L39
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int html_cvt_long(const char *data, int len, void *dst, void *closure) {
  if (data) {
    char *e;
    long val;
    val = strtol(data, &e, 0);
    if (data + len == e) {
      long *d = dst;
      *d = val;
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<html_cvt_long>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L5
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %rsp,%rsi
  xor    %edx,%edx
  mov    %rdi,%rbx
  call   <strtol@plt>
  movslq %ebp,%rsi
  add    %rsi,%rbx
  cmp    %rbx,(%rsp)
  je     L20
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rax,(%r12)
  mov    $0x1,%r13d
  jmp    L5
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int html_cvt_long(const char *data, int len, void *dst, void *closure) {
  if (data) {
    char *e;
    long val;
    val = strtol(data, &e, 0);
    if (data + len == e) {
      long *d = dst;
      *d = val;
      return 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mix_scale_stereo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L36
L18:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x24(%rbp),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L18
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  -0x24(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mix_scale_stereo(const float *l1, const float *r1, float scale, float *l2, float *r2, int len) {
  for (int i = 0; i < len; i++) {
    l2[i] += scale * l1[i];
  }
  for (int i = 0; i < len; i++) {
    r2[i] += scale * r1[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mix_scale_stereo>:
  endbr64
  test   %r8d,%r8d
  jle    L9
  mov    %r8d,%r8d
  mov    $0x0,%eax
L5:
  movaps %xmm0,%xmm1
  mulss  (%rdi,%rax,4),%xmm1
  addss  (%rdx,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L5
  mov    $0x0,%eax
L4:
  movaps %xmm0,%xmm1
  mulss  (%rsi,%rax,4),%xmm1
  addss  (%rcx,%rax,4),%xmm1
  movss  %xmm1,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L4
L9:
  ret
```

assistant: ```c
void mix_scale_stereo(const float *l1, const float *r1, float scale, float *l2, float *r2, int len) {
  for (int i = 0; i < len; i++) {
    l2[i] += scale * l1[i];
  }
  for (int i = 0; i < len; i++) {
    r2[i] += scale * r1[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mix_scale_stereo>:
  endbr64
  test   %r8d,%r8d
  jle    L6
  movslq %r8d,%r8
  xor    %eax,%eax
  xchg   %ax,%ax
L12:
  movss  (%rdi,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  addss  (%rdx,%rax,4),%xmm1
  movss  %xmm1,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L12
  xor    %eax,%eax
  xchg   %ax,%ax
L25:
  movss  (%rsi,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  addss  (%rcx,%rax,4),%xmm1
  movss  %xmm1,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L25
L6:
  ret
```

assistant: ```c
void mix_scale_stereo(const float *l1, const float *r1, float scale, float *l2, float *r2, int len) {
  for (int i = 0; i < len; i++) {
    l2[i] += scale * l1[i];
  }
  for (int i = 0; i < len; i++) {
    r2[i] += scale * r1[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f4(void) {
  int w;
#pragma unused((w))
}
```
user: What is the c source code of the assembly code below:

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void) {
  int w;
#pragma unused((w))
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void) {
  int w;
#pragma unused((w))
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void) {
  int w;
#pragma unused((w))
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<AscToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x9,-0x4(%rbp)
  ja     L2
  addb   $0x30,-0x4(%rbp)
  jmp    L47
L2:
  cmpb   $0x9,-0x4(%rbp)
  jbe    L17
  cmpb   $0xf,-0x4(%rbp)
  ja     L17
  addb   $0x37,-0x4(%rbp)
  jmp    L47
L17:
  movb   $0xff,-0x4(%rbp)
L47:
  movzbl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char AscToHex(unsigned char aHex) {
  if ((aHex >= 0) && (aHex <= 9))
    aHex += 0x30;
  else if ((aHex >= 10) && (aHex <= 15))
    aHex += 0x37;
  else
    aHex = 0xff;
  return aHex;
}
```
user: What is the c source code of the assembly code below:

```asm
<AscToHex>:
  endbr64
  cmp    $0x9,%dil
  ja     L6
  lea    0x30(%rdi),%eax
  ret
L6:
  lea    -0xa(%rdi),%eax
  add    $0x37,%edi
  cmp    $0x6,%al
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
  ret
```

assistant: ```c
unsigned char AscToHex(unsigned char aHex) {
  if ((aHex >= 0) && (aHex <= 9))
    aHex += 0x30;
  else if ((aHex >= 10) && (aHex <= 15))
    aHex += 0x37;
  else
    aHex = 0xff;
  return aHex;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AscToHex>:
  endbr64
  cmp    $0x9,%dil
  ja     L2
  lea    0x30(%rdi),%eax
  ret
  xchg   %ax,%ax
L2:
  lea    -0xa(%rdi),%eax
  add    $0x37,%edi
  cmp    $0x6,%al
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
  ret
```

assistant: ```c
unsigned char AscToHex(unsigned char aHex) {
  if ((aHex >= 0) && (aHex <= 9))
    aHex += 0x30;
  else if ((aHex >= 10) && (aHex <= 15))
    aHex += 0x37;
  else
    aHex = 0xff;
  return aHex;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AscToHex>:
  endbr64
  cmp    $0x9,%dil
  ja     L0
  lea    0x30(%rdi),%eax
  ret
  xchg   %ax,%ax
L0:
  lea    -0xa(%rdi),%eax
  add    $0x37,%edi
  cmp    $0x6,%al
  mov    $0xffffffff,%eax
  cmovb  %edi,%eax
  ret
```

assistant: ```c
unsigned char AscToHex(unsigned char aHex) {
  if ((aHex >= 0) && (aHex <= 9))
    aHex += 0x30;
  else if ((aHex >= 10) && (aHex <= 15))
    aHex += 0x37;
  else
    aHex = 0xff;
  return aHex;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x8,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L50
  mov    $0xffffffff,%eax
  jmp    L57
L50:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L54:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L6
  mov    $0x1,%eax
  jmp    L57
L6:
  addl   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L54
  mov    $0x0,%eax
L57:
  leave
  ret
```

assistant: ```c
int main() {
  int *a;
  int k = 8;
  int i;
  if (k <= 0)
    return -1;
  a = malloc((k - 1) * sizeof(int));
  assert(a != 0);
  for (i = 0; i < k; i++) {
    assert(a + i != 0);
    if (a[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1c,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rbx
  add    $0x20,%rbp
L20:
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L9
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L20
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    $0x1,%eax
  jmp    L17
```

assistant: ```c
int main() {
  int *a;
  int k = 8;
  int i;
  if (k <= 0)
    return -1;
  a = malloc((k - 1) * sizeof(int));
  assert(a != 0);
  for (i = 0; i < k; i++) {
    assert(a + i != 0);
    if (a[i])
      return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1c,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  lea    0x20(%rbx),%rbp
  call   <assert@plt>
  nopl   0x0(%rax)
L3:
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L19
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L3
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x1,%eax
  jmp    L17
```

assistant: ```c
int main() {
  int *a;
  int k = 8;
  int i;
  if (k <= 0)
    return -1;
  a = malloc((k - 1) * sizeof(int));
  assert(a != 0);
  for (i = 0; i < k; i++) {
    assert(a + i != 0);
    if (a[i])
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1c,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  setne  %dil
  lea    0x20(%rbx),%rbp
  call   <assert@plt>
  nopl   0x0(%rax)
L15:
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L10
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L15
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x1,%eax
  jmp    L26
```

assistant: ```c
int main() {
  int *a;
  int k = 8;
  int i;
  if (k <= 0)
    return -1;
  a = malloc((k - 1) * sizeof(int));
  assert(a != 0);
  for (i = 0; i < k; i++) {
    assert(a + i != 0);
    if (a[i])
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<imc_fits_mkstrg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %rdi,-0x1f8(%rbp)
  mov    %rsi,-0x200(%rbp)
  mov    %rdx,-0x208(%rbp)
  mov    %rcx,-0x210(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xb0(%rbp),%rdx
  mov    -0x208(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <imc_fits_mkstrg_val@plt>
  lea    -0xb0(%rbp),%rcx
  mov    -0x200(%rbp),%rdx
  lea    -0x1f0(%rbp),%rax
  lea    D27(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x210(%rbp),%rcx
  lea    -0x1f0(%rbp),%rdx
  lea    -0x150(%rbp),%rax
  lea    D23(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x150(%rbp),%rdx
  mov    -0x1f8(%rbp),%rax
  lea    D28(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D28
type_guessed: string

tool: D27: %-8.8s= %s 

tool: D23: %-30.80s / %-47.47s

tool: D28: %80.80s

assistant: ```c
void imc_fits_mkstrg(char *line, char *key, char *strg, char *com) {
  char tmp[2 * 80];
  char tmp2[2 * 80];
  char tmp3[161];
  imc_fits_mkstrg_val(strg, tmp3);
  sprintf(tmp, "%-8.8s= %s ", key, tmp3);
  sprintf(tmp2, "%-30.80s / %-47.47s", tmp, com);
  sprintf(line, "%80.80s", tmp2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<imc_fits_mkstrg>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1f0,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rdi
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  lea    0x140(%rsp),%r14
  mov    %r14,%rsi
  call   <imc_fits_mkstrg_val@plt>
  mov    %rsp,%r13
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D12(%rip),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    0xa0(%rsp),%r12
  mov    %rbp,%rcx
  mov    %r13,%rdx
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    0x1e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x1f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
datatype: string
name: parse_data
arguments: label: D3
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D12: %-8.8s= %s 

tool: D3: %-30.80s / %-47.47s

tool: D6: %80.80s

assistant: ```c
void imc_fits_mkstrg(char *line, char *key, char *strg, char *com) {
  char tmp[2 * 80];
  char tmp2[2 * 80];
  char tmp3[161];
  imc_fits_mkstrg_val(strg, tmp3);
  sprintf(tmp, "%-8.8s= %s ", key, tmp3);
  sprintf(tmp2, "%-30.80s / %-47.47s", tmp, com);
  sprintf(line, "%80.80s", tmp2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imc_fits_mkstrg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x1f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  lea    0x140(%rsp),%r15
  mov    %rsp,%r14
  mov    %r15,%rsi
  call   <imc_fits_mkstrg_val@plt>
  mov    %r13,%rdx
  mov    %r15,%rcx
  mov    %r14,%rdi
  lea    D18(%rip),%rsi
  xor    %eax,%eax
  lea    0xa0(%rsp),%r13
  call   <sprintf@plt>
  mov    %r14,%rdx
  mov    %r13,%rdi
  xor    %eax,%eax
  lea    D26(%rip),%rsi
  mov    %r12,%rcx
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %r13,%rdx
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <sprintf@plt>
  mov    0x1e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x1f0,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D26
type_infered: string
name: disassemble_data
arguments: data_tag: D15
type_infered: string

tool: D18: %-8.8s= %s 

tool: D26: %-30.80s / %-47.47s

tool: D15: %80.80s

assistant: ```c
void imc_fits_mkstrg(char *line, char *key, char *strg, char *com) {
  char tmp[2 * 80];
  char tmp2[2 * 80];
  char tmp3[161];
  imc_fits_mkstrg_val(strg, tmp3);
  sprintf(tmp, "%-8.8s= %s ", key, tmp3);
  sprintf(tmp2, "%-30.80s / %-47.47s", tmp, com);
  sprintf(line, "%80.80s", tmp2);
}
```