ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L8
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L8:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0xe9972899994bd208,%rax
  cmp    %rax,%rsi
  je     L37
L3:
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L37:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L3
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string

tool: D24: Call this program with %i arguments


tool: D15: %lu


tool: D11: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 16831966772487508488UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L16
  lea    D16(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L16:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0xe9972899994bd208,%rax
  cmp    %rax,%rsi
  je     L17
L26:
  xor    %eax,%eax
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L26
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string

tool: D16: Call this program with %i arguments


tool: D20: %lu


tool: D9: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 16831966772487508488UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dci_format2B_sizeof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  %xmm1,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <srslte_ra_type0_P@plt>
  movss  -0x1c(%rbp),%xmm1
  divss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <ceilf@plt>
  add    $0x16,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x14(%rbp)
  jle    L1
  addl   $0x1,-0x4(%rbp)
  jmp    L1
L28:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_ambiguous_size@plt>
  test   %rax,%rax
  jne    L28
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t dci_format2B_sizeof(uint32_t nof_prb, uint32_t nof_ports) {
  uint32_t n = (uint32_t)ceilf((float)nof_prb / srslte_ra_type0_P(nof_prb)) + 2 + 3 + 1 + 2 * (5 + 1 + 2);
  if (nof_prb > 10) {
    n++;
  }
  while (is_ambiguous_size(n)) {
    n++;
  }
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dci_format2B_sizeof>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <srslte_ra_type0_P@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  divss  %xmm1,%xmm0
  call   <ceilf@plt>
  cmp    $0xa,%ebx
  setg   %bl
  movzbl %bl,%ebx
  lea    0x16(%rbx,%rax,1),%ebx
  jmp    L9
L18:
  add    $0x1,%ebx
L9:
  mov    %ebx,%edi
  call   <is_ambiguous_size@plt>
  test   %rax,%rax
  jne    L18
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t dci_format2B_sizeof(uint32_t nof_prb, uint32_t nof_ports) {
  uint32_t n = (uint32_t)ceilf((float)nof_prb / srslte_ra_type0_P(nof_prb)) + 2 + 3 + 1 + 2 * (5 + 1 + 2);
  if (nof_prb > 10) {
    n++;
  }
  while (is_ambiguous_size(n)) {
    n++;
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dci_format2B_sizeof>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <srslte_ra_type0_P@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  call   <ceilf@plt>
  cmp    $0xa,%r12d
  setg   %r12b
  movzbl %r12b,%r12d
  lea    0x16(%r12,%rax,1),%r12d
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12d
L8:
  mov    %r12d,%edi
  call   <is_ambiguous_size@plt>
  test   %rax,%rax
  jne    L19
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
uint32_t dci_format2B_sizeof(uint32_t nof_prb, uint32_t nof_ports) {
  uint32_t n = (uint32_t)ceilf((float)nof_prb / srslte_ra_type0_P(nof_prb)) + 2 + 3 + 1 + 2 * (5 + 1 + 2);
  if (nof_prb > 10) {
    n++;
  }
  while (is_ambiguous_size(n)) {
    n++;
  }
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dci_format2B_sizeof>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  call   <srslte_ra_type0_P@plt>
  movaps %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %r12d,%xmm0
  divss  %xmm1,%xmm0
  call   <ceilf@plt>
  cmp    $0xa,%r12d
  setg   %r12b
  movzbl %r12b,%r12d
  lea    0x16(%r12,%rax,1),%r12d
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12d
L6:
  mov    %r12d,%edi
  call   <is_ambiguous_size@plt>
  test   %rax,%rax
  jne    L19
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
uint32_t dci_format2B_sizeof(uint32_t nof_prb, uint32_t nof_ports) {
  uint32_t n = (uint32_t)ceilf((float)nof_prb / srslte_ra_type0_P(nof_prb)) + 2 + 3 + 1 + 2 * (5 + 1 + 2);
  if (nof_prb > 10) {
    n++;
  }
  while (is_ambiguous_size(n)) {
    n++;
  }
  return n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<libkeccak_hmac_fast_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <libkeccak_hmac_fast_destroy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void libkeccak_hmac_fast_free(struct libkeccak_hmac_state *restrict state) {
  libkeccak_hmac_fast_destroy(state);
  free(state);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<libkeccak_hmac_fast_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <libkeccak_hmac_fast_destroy@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void libkeccak_hmac_fast_free(struct libkeccak_hmac_state *restrict state) {
  libkeccak_hmac_fast_destroy(state);
  free(state);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<libkeccak_hmac_fast_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <libkeccak_hmac_fast_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void libkeccak_hmac_fast_free(struct libkeccak_hmac_state *restrict state) {
  libkeccak_hmac_fast_destroy(state);
  free(state);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<libkeccak_hmac_fast_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <libkeccak_hmac_fast_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void libkeccak_hmac_fast_free(struct libkeccak_hmac_state *restrict state) {
  libkeccak_hmac_fast_destroy(state);
  free(state);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_splitted>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x4000,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L10:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L13
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L19
  mov    -0x4(%rbp),%eax
  jmp    L21
L19:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L20:
  cmpl   $0x0,-0x18(%rbp)
  jne    L10
  mov    -0x8(%rbp),%eax
L21:
  leave
  ret
```

assistant: ```c
int write_splitted(int sockfd, char *buf, int size) {
  int chunk = 0x4000;
  int done = 0;
  int res;
  while (size) {
    if (size < chunk)
      chunk = size;
    res = write(sockfd, buf, chunk);
    if (res <= 0) {
      return res;
    }
    done += res;
    buf += res;
    size -= res;
  }
  return done;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_splitted>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  je     L17
  mov    %edi,%r14d
  mov    %rsi,%r12
  mov    $0x0,%r13d
  mov    $0x4000,%ebp
L25:
  cmp    %ebx,%ebp
  cmovg  %ebx,%ebp
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L3
  add    %eax,%r13d
  movslq %eax,%rdx
  add    %rdx,%r12
  sub    %eax,%ebx
  jne    L25
  mov    %r13d,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  mov    %edx,%eax
  jmp    L3
```

assistant: ```c
int write_splitted(int sockfd, char *buf, int size) {
  int chunk = 0x4000;
  int done = 0;
  int res;
  while (size) {
    if (size < chunk)
      chunk = size;
    res = write(sockfd, buf, chunk);
    if (res <= 0) {
      return res;
    }
    done += res;
    buf += res;
    size -= res;
  }
  return done;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_splitted>:
  endbr64
  test   %edx,%edx
  je     L34
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x4000,%ebp
  push   %rbx
  mov    %edx,%ebx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L37:
  movslq %eax,%rdx
  add    %eax,%r13d
  add    %rdx,%r14
  sub    %eax,%ebx
  je     L15
L8:
  cmp    %ebx,%ebp
  mov    %r14,%rsi
  mov    %r12d,%edi
  cmovg  %ebx,%ebp
  mov    %ebp,%edx
  call   <write@plt>
  test   %eax,%eax
  jg     L37
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  xor    %eax,%eax
  ret
```

assistant: ```c
int write_splitted(int sockfd, char *buf, int size) {
  int chunk = 0x4000;
  int done = 0;
  int res;
  while (size) {
    if (size < chunk)
      chunk = size;
    res = write(sockfd, buf, chunk);
    if (res <= 0) {
      return res;
    }
    done += res;
    buf += res;
    size -= res;
  }
  return done;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_splitted>:
  endbr64
  test   %edx,%edx
  je     L0
  push   %r14
  mov    %rsi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x4000,%ebp
  push   %rbx
  mov    %edx,%ebx
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L29:
  movslq %eax,%rdx
  add    %eax,%r13d
  add    %rdx,%r14
  sub    %eax,%ebx
  je     L2
L20:
  cmp    %ebx,%ebp
  mov    %r14,%rsi
  mov    %r12d,%edi
  cmovg  %ebx,%ebp
  mov    %ebp,%edx
  call   <write@plt>
  test   %eax,%eax
  jg     L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L2:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int write_splitted(int sockfd, char *buf, int size) {
  int chunk = 0x4000;
  int done = 0;
  int res;
  while (size) {
    if (size < chunk)
      chunk = size;
    res = write(sockfd, buf, chunk);
    if (res <= 0) {
      return res;
    }
    done += res;
    buf += res;
    size -= res;
  }
  return done;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inv_fifo_protocol_helper_decode_heart_rate_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <FifoProtocol_memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  D1(%rip),%xmm1
  divss  %xmm1,%xmm0
  mov    -0x28(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x43]}

assistant: ```c
void inv_fifo_protocol_helper_decode_heart_rate_data(const void *in, uint16_t len, float *bpm) {
  uint16_t tmp;
  FifoProtocol_memcpy((&tmp), (in), (sizeof(tmp)));
  tmp = tmp;
  *bpm = ((float)(uint16_t)(tmp) / (float)(1ULL << (7)));
  (void)len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inv_fifo_protocol_helper_decode_heart_rate_data>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rsi
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x8,%edx
  call   <FifoProtocol_memcpy@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsp),%xmm0
  mulss  D6(%rip),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: byte[4]

tool: {"D6": [0x00,0x00,0x00,0x3c]}

assistant: ```c
void inv_fifo_protocol_helper_decode_heart_rate_data(const void *in, uint16_t len, float *bpm) {
  uint16_t tmp;
  FifoProtocol_memcpy((&tmp), (in), (sizeof(tmp)));
  tmp = tmp;
  *bpm = ((float)(uint16_t)(tmp) / (float)(1ULL << (7)));
  (void)len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inv_fifo_protocol_helper_decode_heart_rate_data>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdx,%rbx
  mov    $0x8,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <FifoProtocol_memcpy@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsp),%xmm0
  mulss  D2(%rip),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3c]}

assistant: ```c
void inv_fifo_protocol_helper_decode_heart_rate_data(const void *in, uint16_t len, float *bpm) {
  uint16_t tmp;
  FifoProtocol_memcpy((&tmp), (in), (sizeof(tmp)));
  tmp = tmp;
  *bpm = ((float)(uint16_t)(tmp) / (float)(1ULL << (7)));
  (void)len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inv_fifo_protocol_helper_decode_heart_rate_data>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    %rdx,%rbx
  mov    $0x8,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <FifoProtocol_memcpy@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsp),%xmm0
  mulss  D2(%rip),%xmm0
  movss  %xmm0,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3c]}

assistant: ```c
void inv_fifo_protocol_helper_decode_heart_rate_data(const void *in, uint16_t len, float *bpm) {
  uint16_t tmp;
  FifoProtocol_memcpy((&tmp), (in), (sizeof(tmp)));
  tmp = tmp;
  *bpm = ((float)(uint16_t)(tmp) / (float)(1ULL << (7)));
  (void)len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_four_digits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L10:
  mov    $0x0,%eax
  call   <get_byte@plt>
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <get_byte@plt>
  sub    $0x30,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x3,-0x4(%rbp)
  jle    L10
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint16_t parse_four_digits(void) {
  uint16_t value = 0;
  uint8_t n;
  for (n = 0; n < 4; n++) {
    get_byte();
    value *= 10;
    value += ((get_byte()) - '0');
  }
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_four_digits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x4,%ebp
  mov    $0x0,%ebx
L6:
  mov    $0x0,%eax
  call   <get_byte@plt>
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  mov    $0x0,%eax
  call   <get_byte@plt>
  lea    -0x30(%rbx,%rax,1),%ebx
  sub    $0x1,%ebp
  jne    L6
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint16_t parse_four_digits(void) {
  uint16_t value = 0;
  uint8_t n;
  for (n = 0; n < 4; n++) {
    get_byte();
    value *= 10;
    value += ((get_byte()) - '0');
  }
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_four_digits>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
L2:
  xor    %eax,%eax
  lea    (%r12,%r12,4),%ebx
  call   <get_byte@plt>
  xor    %eax,%eax
  add    %ebx,%ebx
  call   <get_byte@plt>
  lea    -0x30(%rbx,%rax,1),%r12d
  sub    $0x1,%ebp
  jne    L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint16_t parse_four_digits(void) {
  uint16_t value = 0;
  uint8_t n;
  for (n = 0; n < 4; n++) {
    get_byte();
    value *= 10;
    value += ((get_byte()) - '0');
  }
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_four_digits>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
L6:
  xor    %eax,%eax
  lea    (%r12,%r12,4),%ebx
  call   <get_byte@plt>
  xor    %eax,%eax
  add    %ebx,%ebx
  call   <get_byte@plt>
  lea    -0x30(%rbx,%rax,1),%r12d
  sub    $0x1,%ebp
  jne    L6
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint16_t parse_four_digits(void) {
  uint16_t value = 0;
  uint8_t n;
  for (n = 0; n < 4; n++) {
    get_byte();
    value *= 10;
    value += ((get_byte()) - '0');
  }
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<page32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x16,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D43
type: string
name: disassemble_data
arguments: tag: D40
type: string
name: disassemble_data
arguments: tag: D27
type: string
name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D39
type: string

tool: D43: Finally it's your big chance to prove that you're as good a troubleshooter


tool: D40: as your previous clone.  You walk briskly to mission briefing and pick up your


tool: D27: previous clone's personal effects and notepad.  After reviewing the notes you


tool: D15: know what has to be done.  You catch the purple line to Goods Distribution Hall


tool: D39: 7-beta and begin to search for the blast door.


assistant: ```c
page32() {
  printf("Finally it\'s your big chance to prove that you\'re as good a troubleshooter\n");
  printf("as your previous clone.  You walk briskly to mission briefing and pick up your\n");
  printf("previous clone\'s personal effects and notepad.  After reviewing the notes you\n");
  printf("know what has to be done.  You catch the purple line to Goods Distribution Hall\n");
  printf("7-beta and begin to search for the blast door.\n");
  return 22;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<page32>:
  endbr64
  sub    $0x8,%rsp
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x16,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D43
type_guessed: string
name: parse_data
arguments: tag: D41
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string
name: parse_data
arguments: tag: D40
type_guessed: string
name: parse_data
arguments: tag: D38
type_guessed: string

tool: D43: Finally it's your big chance to prove that you're as good a troubleshooter


tool: D41: as your previous clone.  You walk briskly to mission briefing and pick up your


tool: D36: previous clone's personal effects and notepad.  After reviewing the notes you


tool: D40: know what has to be done.  You catch the purple line to Goods Distribution Hall


tool: D38: 7-beta and begin to search for the blast door.


assistant: ```c
page32() {
  printf("Finally it\'s your big chance to prove that you\'re as good a troubleshooter\n");
  printf("as your previous clone.  You walk briskly to mission briefing and pick up your\n");
  printf("previous clone\'s personal effects and notepad.  After reviewing the notes you\n");
  printf("know what has to be done.  You catch the purple line to Goods Distribution Hall\n");
  printf("7-beta and begin to search for the blast door.\n");
  return 22;
}
```