ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mat_mult>:
  endbr64
  test   %ecx,%ecx
  jle    L62
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  test   %r8d,%r8d
  jle    L81
  mov    %r8d,%eax
  mov    %rdi,%rbp
  lea    -0x1(%r8),%r15d
  mov    %rsi,%r12
  shr    %eax
  mov    %rdx,%r13
  movslq %ecx,%r14
  xor    %edi,%edi
  lea    -0x1(%rax),%r9d
  mov    %r8d,%eax
  mov    %r8d,%r8d
  and    $0xfffffffe,%eax
  add    $0x1,%r9
  mov    %eax,-0xc(%rsp)
  shl    $0x4,%r9
  shl    $0x3,%rax
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    (%r12,%rdi,8),%rsi
  mov    0x0(%r13,%rdi,8),%rdx
  mov    0x0(%rbp,%rdi,8),%rcx
  lea    0x8(%rsi),%r10
  cmp    %r10,%rdx
  lea    0x8(%rcx),%r10
  setne  %r11b
  cmp    %r10,%rdx
  setne  %r10b
  test   %r10b,%r11b
  je     L11
  xor    %r10d,%r10d
  cmp    $0x1,%r15d
  jbe    L11
  nopw   0x0(%rax,%rax,1)
L49:
  movupd (%rcx,%r10,1),%xmm0
  movupd (%rsi,%r10,1),%xmm1
  mulpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%r10,1)
  add    $0x10,%r10
  cmp    %r9,%r10
  jne    L49
  cmp    -0xc(%rsp),%ebx
  je     L13
  movsd  (%rcx,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
L13:
  add    $0x1,%rdi
  cmp    %r14,%rdi
  jne    L22
L81:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L11:
  xor    %r10d,%r10d
  nopl   0x0(%rax,%rax,1)
L0:
  movsd  (%rsi,%r10,8),%xmm0
  mulsd  (%rcx,%r10,8),%xmm0
  movsd  %xmm0,(%rdx,%r10,8)
  add    $0x1,%r10
  cmp    %r10,%r8
  jne    L0
  jmp    L13
L62:
  ret
```

assistant: ```c
void mat_mult(double **src1, double **src2, double **dest, int m, int n) {
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      dest[i][j] = src1[i][j] * src2[i][j];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bit_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L29
L19:
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bit_get@plt>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bit_get@plt>
  cmp    %rax,%rbx
  je     L9
  mov    -0x14(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bit_set@plt>
  jmp    L11
L9:
  mov    -0x14(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <bit_set@plt>
L11:
  addl   $0x1,-0x14(%rbp)
L29:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L19
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void bit_xor(const unsigned char *bits1, const unsigned char *bits2, unsigned char *bitsx, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (bit_get(bits1, i) != bit_get(bits2, i))
      bit_set(bitsx, i, 1);
    else
      bit_set(bitsx, i, 0);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bit_xor>:
  endbr64
  test   %ecx,%ecx
  jle    L14
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    %ecx,%r12d
  mov    $0x0,%ebx
  jmp    L35
L32:
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <bit_set@plt>
L25:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L11
L35:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <bit_get@plt>
  mov    %rax,%rbp
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <bit_get@plt>
  cmp    %rax,%rbp
  je     L32
  mov    $0x1,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <bit_set@plt>
  jmp    L25
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  ret
```

assistant: ```c
void bit_xor(const unsigned char *bits1, const unsigned char *bits2, unsigned char *bitsx, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (bit_get(bits1, i) != bit_get(bits2, i))
      bit_set(bitsx, i, 1);
    else
      bit_set(bitsx, i, 0);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bit_xor>:
  endbr64
  test   %ecx,%ecx
  jle    L41
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <bit_set@plt>
  cmp    %ebx,%r12d
  je     L19
L8:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <bit_get@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <bit_get@plt>
  cmp    %rax,%rbp
  jne    L17
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <bit_set@plt>
  cmp    %ebx,%r12d
  jne    L8
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  ret
```

assistant: ```c
void bit_xor(const unsigned char *bits1, const unsigned char *bits2, unsigned char *bitsx, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (bit_get(bits1, i) != bit_get(bits2, i))
      bit_set(bitsx, i, 1);
    else
      bit_set(bitsx, i, 0);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bit_xor>:
  endbr64
  test   %ecx,%ecx
  jle    L32
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%esi
  mov    $0x1,%edx
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <bit_set@plt>
  cmp    %ebx,%r12d
  je     L36
L13:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <bit_get@plt>
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    %rax,%rbp
  call   <bit_get@plt>
  cmp    %rax,%rbp
  jne    L26
  mov    %ebx,%esi
  xor    %edx,%edx
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <bit_set@plt>
  cmp    %ebx,%r12d
  jne    L13
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  ret
```

assistant: ```c
void bit_xor(const unsigned char *bits1, const unsigned char *bits2, unsigned char *bitsx, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (bit_get(bits1, i) != bit_get(bits2, i))
      bit_set(bitsx, i, 1);
    else
      bit_set(bitsx, i, 0);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_trans>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L35
L2:
  mov    -0x20(%rbp),%eax
  imul   -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L24
L19:
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x8,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L19
  addl   $0x1,-0x20(%rbp)
L35:
  mov    -0x20(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_trans(const int n, double *__restrict__ z) {
  int i, j;
  double *row, *col, tmp;
  for (i = 0; i < n; i++) {
    row = z + i * n;
    col = z + i;
    for (j = 0; j < i; j++) {
      tmp = (*row);
      (*row) = (*col);
      (*col) = tmp;
      ++row;
      col += n;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copy_trans>:
  endbr64
  test   %edi,%edi
  jle    L13
  movslq %edi,%r8
  shl    $0x3,%r8
  lea    (%rsi,%r8,1),%r10
  lea    0x8(%rsi),%r9
  lea    0x8(%r8),%r11
  lea    (%rsi,%r11,1),%rcx
  mov    $0x0,%esi
  jmp    L31
L0:
  mov    %r10,%rax
  mov    %r9,%rdx
  test   %esi,%esi
  jle    L17
L24:
  movsd  (%rax),%xmm0
  movsd  (%rdx),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L24
L17:
  add    %r8,%r10
  add    $0x8,%r9
  add    %r11,%rcx
L31:
  add    $0x1,%esi
  cmp    %esi,%edi
  jne    L0
L13:
  ret
```

assistant: ```c
void copy_trans(const int n, double *__restrict__ z) {
  int i, j;
  double *row, *col, tmp;
  for (i = 0; i < n; i++) {
    row = z + i * n;
    col = z + i;
    for (j = 0; j < i; j++) {
      tmp = (*row);
      (*row) = (*col);
      (*col) = tmp;
      ++row;
      col += n;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_trans>:
  endbr64
  test   %edi,%edi
  jle    L39
  movslq %edi,%r8
  lea    0x8(%rsi),%r9
  shl    $0x3,%r8
  lea    0x8(%r8),%r11
  lea    (%rsi,%r8,1),%r10
  lea    (%rsi,%r11,1),%rcx
  xor    %esi,%esi
  add    $0x1,%esi
  cmp    %esi,%edi
  je     L39
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %r10,%rax
  mov    %r9,%rdx
  cs nopw 0x0(%rax,%rax,1)
L17:
  movsd  (%rdx),%xmm1
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,(%rdx)
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L17
  add    $0x1,%esi
  add    %r8,%r10
  add    $0x8,%r9
  add    %r11,%rcx
  cmp    %esi,%edi
  jne    L26
L39:
  ret
```

assistant: ```c
void copy_trans(const int n, double *__restrict__ z) {
  int i, j;
  double *row, *col, tmp;
  for (i = 0; i < n; i++) {
    row = z + i * n;
    col = z + i;
    for (j = 0; j < i; j++) {
      tmp = (*row);
      (*row) = (*col);
      (*col) = tmp;
      ++row;
      col += n;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_trans>:
  endbr64
  test   %edi,%edi
  jle    L34
  movslq %edi,%r8
  shl    $0x3,%r8
  cmp    $0x1,%edi
  je     L34
  lea    0x8(%r8),%r11
  lea    (%rsi,%r8,1),%r10
  lea    0x8(%rsi),%r9
  lea    (%rsi,%r11,1),%rcx
  mov    $0x1,%esi
  nopl   0x0(%rax)
L0:
  mov    %r10,%rax
  mov    %r9,%rdx
  cs nopw 0x0(%rax,%rax,1)
L35:
  movsd  (%rdx),%xmm1
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,(%rdx)
  add    %r8,%rdx
  cmp    %rcx,%rax
  jne    L35
  add    $0x1,%esi
  add    %r8,%r10
  add    $0x8,%r9
  add    %r11,%rcx
  cmp    %esi,%edi
  jne    L0
L34:
  ret
```

assistant: ```c
void copy_trans(const int n, double *__restrict__ z) {
  int i, j;
  double *row, *col, tmp;
  for (i = 0; i < n; i++) {
    row = z + i * n;
    col = z + i;
    for (j = 0; j < i; j++) {
      tmp = (*row);
      (*row) = (*col);
      (*col) = tmp;
      ++row;
      col += n;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xec(%rbp)
  lea    -0xe0(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x70(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpl   $0x0,-0xec(%rbp)
  je     L14
  lea    -0xe0(%rbp),%rax
  jmp    L2
L14:
  lea    -0x70(%rbp),%rax
L2:
  mov    %rax,-0xe8(%rbp)
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xec(%rbp)
  cmpl   $0x3,-0xec(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string
name: extract_symbolic_data
arguments: label: D19
type_infered: string

tool: D2: asdasd

tool: D19: asd

assistant: ```c
int main() {
  char a[100], b[100], *p;
  unsigned int i;
  i = strlen("asdasd");
  strcpy(a, "asd");
  strcpy(b, "asd");
  p = i ? a : b;
  i = strlen(p);
  assert(i == 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rsp,%rdi
  lea    D16(%rip),%rbp
  mov    %rbp,%rsi
  call   <strcpy@plt>
  lea    0x70(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  lea    0x70(%rsp),%rax
  mov    %rsp,%rdi
  test   %ebx,%ebx
  cmove  %rax,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D16
type: string

tool: D5: asdasd

tool: D16: asd

assistant: ```c
int main() {
  char a[100], b[100], *p;
  unsigned int i;
  i = strlen("asdasd");
  strcpy(a, "asd");
  strcpy(b, "asd");
  p = i ? a : b;
  i = strlen(p);
  assert(i == 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%rdi
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x70(%rsp),%r12
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %ebp,%ebp
  mov    %r12,%rdi
  cmovne %rbx,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D6: asdasd

tool: D3: asd

assistant: ```c
int main() {
  char a[100], b[100], *p;
  unsigned int i;
  i = strlen("asdasd");
  strcpy(a, "asd");
  strcpy(b, "asd");
  p = i ? a : b;
  i = strlen(p);
  assert(i == 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  lea    D18(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x70(%rsp),%r12
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %ebp,%ebp
  mov    %r12,%rdi
  cmovne %rbx,%rdi
  call   <strlen@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string

tool: D0: asdasd

tool: D18: asd

assistant: ```c
int main() {
  char a[100], b[100], *p;
  unsigned int i;
  i = strlen("asdasd");
  strcpy(a, "asd");
  strcpy(b, "asd");
  p = i ? a : b;
  i = strlen(p);
  assert(i == 3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sendBloqueCompleto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x6,-0x10(%rbp)
  lea    -0x10(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x8,%edx
  mov    %eax,%edi
  call   <msgsnd@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int sendBloqueCompleto(int queue) {
  long tipo = 6;
  return msgsnd(queue, &tipo, sizeof(long), 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sendBloqueCompleto>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x6,(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%ecx
  mov    $0x8,%edx
  call   <msgsnd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sendBloqueCompleto(int queue) {
  long tipo = 6;
  return msgsnd(queue, &tipo, sizeof(long), 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sendBloqueCompleto>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x6,(%rsp)
  call   <msgsnd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sendBloqueCompleto(int queue) {
  long tipo = 6;
  return msgsnd(queue, &tipo, sizeof(long), 0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sendBloqueCompleto>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x6,(%rsp)
  call   <msgsnd@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sendBloqueCompleto(int queue) {
  long tipo = 6;
  return msgsnd(queue, &tipo, sizeof(long), 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<magic_comment_encoding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <comment_at_top@plt>
  test   %eax,%eax
  je     L18
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parser_set_encode@plt>
  jmp    L2
L18:
  nop
L2:
  leave
  ret
```

assistant: ```c
void magic_comment_encoding(struct parser_params *parser, const char *name, const char *val) {
  if (!comment_at_top(parser)) {
    return;
  }
  parser_set_encode(parser, val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<magic_comment_encoding>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  call   <comment_at_top@plt>
  test   %eax,%eax
  jne    L5
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <parser_set_encode@plt>
  jmp    L13
```

assistant: ```c
void magic_comment_encoding(struct parser_params *parser, const char *name, const char *val) {
  if (!comment_at_top(parser)) {
    return;
  }
  parser_set_encode(parser, val);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<magic_comment_encoding>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <comment_at_top@plt>
  test   %eax,%eax
  jne    L3
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <parser_set_encode@plt>
```

assistant: ```c
void magic_comment_encoding(struct parser_params *parser, const char *name, const char *val) {
  if (!comment_at_top(parser)) {
    return;
  }
  parser_set_encode(parser, val);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<magic_comment_encoding>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <comment_at_top@plt>
  test   %eax,%eax
  jne    L0
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <parser_set_encode@plt>
```

assistant: ```c
void magic_comment_encoding(struct parser_params *parser, const char *name, const char *val) {
  if (!comment_at_top(parser)) {
    return;
  }
  parser_set_encode(parser, val);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L80
L65:
  movl   $0x1,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  mov    -0x24(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L58
L83:
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  mov    -0x24(%rbp),%edx
  sub    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  je     L37
  mov    -0x24(%rbp),%eax
  mov    -0x28(%rbp),%edx
  sub    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  je     L37
  movl   $0x0,-0x10(%rbp)
L37:
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L83
  cmpl   $0x1,-0x10(%rbp)
  jne    L7
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L62
L7:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L62:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  je     L70
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L70:
  addl   $0x1,-0x18(%rbp)
L80:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L65
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D51
type_infered: string
name: disassemble_data
arguments: data_label: D44
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D25: %d

tool: D51: %d %d

tool: D44: yes


tool: D28: no


tool: D4: 


assistant: ```c
int main(void) {
  int i, j, a, b, n, m, t, y;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    y = 1;
    scanf("%d", &m);
    scanf("%d %d", &a, &b);
    t = a - b;
    for (j = 0; j < m - 1; j++) {
      scanf("%d %d", &a, &b);
      if (t != a - b && t != b - a)
        y = 0;
    }
    if (y == 1)
      printf("yes\n");
    else
      printf("no\n");
    if (i != n - 1)
      printf("\n");
  }
  return 0;
}
```