ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<sendplane_rand_z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %al,-0x14(%rbp)
  movb   $0x10,-0x3(%rbp)
  mov    $0x0,%edi
  call   <fill@plt>
  movzbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <setplane_z@plt>
  jmp    L8
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %al,-0x2(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x1(%rbp),%ecx
  movzbl -0x2(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <getvoxel@plt>
  test   %rax,%rax
  je     L8
  movzbl -0x14(%rbp),%edx
  movzbl -0x1(%rbp),%esi
  movzbl -0x2(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  mov    %eax,%edi
  call   <sendvoxel_z@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <delay_ms@plt>
  movzbl -0x3(%rbp),%eax
  sub    $0x1,%eax
  mov    %al,-0x3(%rbp)
L8:
  cmpb   $0x0,-0x3(%rbp)
  jne    L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void sendplane_rand_z(unsigned char z, int delay, int wait) {
  unsigned char loop = 16;
  unsigned char x, y;
  fill(0x00);
  setplane_z(z);
  while (loop) {
    x = rand() % 4;
    y = rand() % 4;
    if (getvoxel(x, y, z)) {
      sendvoxel_z(x, y, z, delay);
      delay_ms(wait);
      loop--;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sendplane_rand_z>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r15d
  mov    %edx,%r14d
  mov    $0x0,%edi
  call   <fill@plt>
  movzbl %r12b,%r12d
  mov    %r12d,%edi
  call   <setplane_z@plt>
  mov    $0x10,%r13d
L22:
  test   %r13b,%r13b
  je     L21
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x3,%ebp
  sub    %edx,%ebp
  movzbl %bpl,%ebp
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%ebx
  and    $0x3,%ebx
  sub    %eax,%ebx
  movzbl %bl,%ebx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <getvoxel@plt>
  test   %rax,%rax
  je     L22
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <sendvoxel_z@plt>
  mov    %r14d,%edi
  call   <delay_ms@plt>
  sub    $0x1,%r13d
  jmp    L22
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sendplane_rand_z(unsigned char z, int delay, int wait) {
  unsigned char loop = 16;
  unsigned char x, y;
  fill(0x00);
  setplane_z(z);
  while (loop) {
    x = rand() % 4;
    y = rand() % 4;
    if (getvoxel(x, y, z)) {
      sendvoxel_z(x, y, z, delay);
      delay_ms(wait);
      loop--;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendplane_rand_z>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  mov    $0x10,%r13d
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  movzbl %r12b,%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fill@plt>
  mov    %r12d,%edi
  call   <setplane_z@plt>
  jmp    L9
  nopl   (%rax)
L6:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  lea    (%rax,%rdx,1),%esi
  mov    %ebp,%eax
  sar    $0x1f,%eax
  and    $0x3,%esi
  shr    $0x1e,%eax
  sub    %edx,%esi
  mov    %r12d,%edx
  add    %eax,%ebp
  movzbl %sil,%r14d
  and    $0x3,%ebp
  mov    %r14d,%esi
  sub    %eax,%ebp
  movzbl %bpl,%ebp
  mov    %ebp,%edi
  call   <getvoxel@plt>
  test   %rax,%rax
  jne    L14
L9:
  test   %r13b,%r13b
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %ebp,%edi
  call   <sendvoxel_z@plt>
  mov    %ebx,%edi
  sub    $0x1,%r13d
  call   <delay_ms@plt>
  jmp    L9
```

assistant: ```c
void sendplane_rand_z(unsigned char z, int delay, int wait) {
  unsigned char loop = 16;
  unsigned char x, y;
  fill(0x00);
  setplane_z(z);
  while (loop) {
    x = rand() % 4;
    y = rand() % 4;
    if (getvoxel(x, y, z)) {
      sendvoxel_z(x, y, z, delay);
      delay_ms(wait);
      loop--;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sendplane_rand_z>:
  endbr64
  push   %r15
  mov    $0x10,%r15d
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  mov    %edi,%r12d
  xor    %edi,%edi
  push   %rbp
  movzbl %r12b,%r12d
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <fill@plt>
  mov    %r12d,%edi
  call   <setplane_z@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  shr    $0x1e,%edx
  lea    (%rax,%rdx,1),%esi
  mov    %ebp,%eax
  sar    $0x1f,%eax
  and    $0x3,%esi
  shr    $0x1e,%eax
  sub    %edx,%esi
  mov    %r12d,%edx
  add    %eax,%ebp
  movzbl %sil,%r13d
  and    $0x3,%ebp
  mov    %r13d,%esi
  sub    %eax,%ebp
  movzbl %bpl,%ebp
  mov    %ebp,%edi
  call   <getvoxel@plt>
  test   %rax,%rax
  je     L16
  mov    %ebp,%edi
  mov    %r14d,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  call   <sendvoxel_z@plt>
  mov    %ebx,%edi
  call   <delay_ms@plt>
  sub    $0x1,%r15b
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sendplane_rand_z(unsigned char z, int delay, int wait) {
  unsigned char loop = 16;
  unsigned char x, y;
  fill(0x00);
  setplane_z(z);
  while (loop) {
    x = rand() % 4;
    y = rand() % 4;
    if (getvoxel(x, y, z)) {
      sendvoxel_z(x, y, z, delay);
      delay_ms(wait);
      loop--;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jg     L139
  cmpl   $0x0,-0x14(%rbp)
  js     L139
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jg     L139
  cmpl   $0xffffffff,-0x10(%rbp)
  jl     L139
  mov    $0x1,%eax
  jmp    L117
L139:
  mov    $0x0,%eax
L117:
  mov    %eax,%edi
  call   <__ESBMC_assume@plt>
  jmp    L66
L79:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L66:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L79
  movl   $0x0,-0x14(%rbp)
  jmp    L54
L123:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L54:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L123
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L94:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L94
  movl   $0x0,-0x14(%rbp)
  jmp    L40
L155:
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L40:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L155
  movl   $0x0,-0x14(%rbp)
  jmp    L156
L19:
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L156:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L19
  movl   $0x0,-0x14(%rbp)
  jmp    L108
L36:
  cmpl   $0x0,-0x10(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L108:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L36
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n0, n1, n2;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i + k + 2 > n0 && i >= 0 && i + 2 > n0 && k + 2 > 0);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  mov    $0x0,%eax
  test   %eax,%eax
  jle    L1
  mov    %eax,%ebx
  mov    %eax,%ebp
  sub    %eax,%ebp
L12:
  test   %ebx,%ebx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L12
L1:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n0, n1, n2;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i + k + 2 > n0 && i >= 0 && i + 2 > n0 && k + 2 > 0);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n0, n1, n2;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i + k + 2 > n0 && i >= 0 && i + 2 > n0 && k + 2 > 0);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__ESBMC_assume@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n0, n1, n2;
  int i = 0;
  int k = 0;
  __ESBMC_assume(i + k + 2 > n0 && i >= 0 && i + 2 > n0 && k + 2 > 0);
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k++;
  }
  i = 0;
  while (i < n2) {
    i++;
    k--;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    assert(k > 0);
    i++;
    k--;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x5(%rbp)
  jmp    L6
L10:
  cmpl   $0x20,-0x4(%rbp)
  jne    L1
  cmpb   $0x0,-0x5(%rbp)
  jne    L6
  mov    $0x20,%edi
  call   <putchar@plt>
  movb   $0x1,-0x5(%rbp)
  jmp    L6
L1:
  movb   $0x0,-0x5(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  nop
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L10
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char space = 0;
  int c;
  while ((c = getchar()) != EOF) {
    switch (c) {
    case ' ':
      if (!space) {
        putchar(' ');
        space = 1;
      }
      break;
    default:
      space = 0;
      putchar(c);
      break;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x1,%ebp
  jmp    L3
L10:
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D1(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L47
  cmp    $0x20,%eax
  jne    L10
  test   %bl,%bl
  jne    L3
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    %ebp,%ebx
  jmp    L3
L47:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char space = 0;
  int c;
  while ((c = getchar()) != EOF) {
    switch (c) {
    case ' ':
      if (!space) {
        putchar(' ');
        space = 1;
      }
      break;
    default:
      space = 0;
      putchar(c);
      break;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%rbx
L115:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L102
  cmp    $0x20,%edi
  jne    L109
  test   %bpl,%bpl
  jne    L62
L40:
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L102
  cmp    $0x20,%eax
  jne    L109
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L102
  cmp    $0x20,%eax
  jne    L109
L62:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L102
  mov    $0x1,%ebp
  cmp    $0x20,%eax
  je     L115
  nop
L109:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L102
  cmp    $0x20,%eax
  je     L40
  jmp    L109
  nopl   0x0(%rax)
L102:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char space = 0;
  int c;
  while ((c = getchar()) != EOF) {
    switch (c) {
    case ' ':
      if (!space) {
        putchar(' ');
        space = 1;
      }
      break;
    default:
      space = 0;
      putchar(c);
      break;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbx
L78:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L45
  cmp    $0x20,%edi
  jne    L103
  test   %bpl,%bpl
  jne    L22
L39:
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L45
  cmp    $0x20,%eax
  jne    L103
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L45
  cmp    $0x20,%eax
  jne    L103
L22:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L45
  mov    $0x1,%ebp
  cmp    $0x20,%eax
  je     L78
  nop
L103:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    (%rbx),%eax
  je     L45
  cmp    $0x20,%eax
  je     L39
  jmp    L103
  nopl   0x0(%rax)
L45:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char space = 0;
  int c;
  while ((c = getchar()) != EOF) {
    switch (c) {
    case ' ':
      if (!space) {
        putchar(' ');
        space = 1;
      }
      break;
    default:
      space = 0;
      putchar(c);
      break;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<compute_BMI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   %eax,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D2(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: f32[2]

tool: {"D2": [0.0,4.1865234375]}

assistant: ```c
double compute_BMI(double weight, int height) {
  double value = 0.0;
  value = (weight / (height * height)) * 703;
  return value;
}
```
user: What is the c source code of the assembly code below?

```asm
<compute_BMI>:
  endbr64
  imul   %edi,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: f32[2]

tool: {"D7": [0.0,4.1865234375]}

assistant: ```c
double compute_BMI(double weight, int height) {
  double value = 0.0;
  value = (weight / (height * height)) * 703;
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compute_BMI>:
  endbr64
  imul   %edi,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: f32[2]

tool: {"D0": [0.0,4.1865234375]}

assistant: ```c
double compute_BMI(double weight, int height) {
  double value = 0.0;
  value = (weight / (height * height)) * 703;
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compute_BMI>:
  endbr64
  imul   %edi,%edi
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: f32[2]

tool: {"D7": [0.0,4.1865234375]}

assistant: ```c
double compute_BMI(double weight, int height) {
  double value = 0.0;
  value = (weight / (height * height)) * 703;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<panic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printk@plt>
L8:
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: Kernel panic: %s


assistant: ```c
void panic(const char *s) {
  printk("Kernel panic: %s\n", s);
  for (;;)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<panic>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printk@plt>
L0:
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: Kernel panic: %s


assistant: ```c
void panic(const char *s) {
  printk("Kernel panic: %s\n", s);
  for (;;)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<panic>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printk@plt>
L7:
  jmp    L7
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: Kernel panic: %s


assistant: ```c
void panic(const char *s) {
  printk("Kernel panic: %s\n", s);
  for (;;)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<panic>:
  endbr64
  mov    %rdi,%rsi
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printk@plt>
L0:
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: Kernel panic: %s


assistant: ```c
void panic(const char *s) {
  printk("Kernel panic: %s\n", s);
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L36
L39:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L11:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L38:
  addl   $0x1,-0x14(%rbp)
L36:
  cmpl   $0x2710,-0x14(%rbp)
  jle    L39
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  movss  D56(%rip),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  movss  D2(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D2(%rip),%xmm0
  subss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2710,%esi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D52
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D56
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D2
type_infered: f32
name: extract_symbolic_data
arguments: data_label: D57
type_infered: string

tool: D52: Heads	

tool: D11: Tails	

tool: {"D56": [0x00,0x40,0x1c,0x46]}

tool: D2: 100

tool: D57: Total Flips: %d
Heads: %.2f
Tails: %.2f


assistant: ```c
int main() {
  int coin, loop;
  int total_heads = 0;
  float hpercent, tpercent;
  srand((unsigned)time(NULL));
  for (loop = 0; loop <= 10000; loop++) {
    coin = rand() % 2;
    total_heads += coin;
    if (coin)
      printf("Heads\t");
    else
      printf("Tails\t");
  }
  hpercent = (float)total_heads / 10000 * 100;
  tpercent = 100.0 - hpercent;
  printf("Total Flips: %d\nHeads: %.2f\nTails: %.2f\n", 10000, hpercent, tpercent);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x2711,%ebx
  mov    $0x0,%ebp
  lea    D48(%rip),%r13
  lea    D31(%rip),%r12
  jmp    L21
L35:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  sub    $0x1,%ebx
  je     L27
L21:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x1,%edx
  sub    %ecx,%edx
  add    %edx,%ebp
  test   $0x1,%al
  je     L35
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
L27:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  divss  D32(%rip),%xmm0
  movss  D25(%rip),%xmm1
  mulss  %xmm1,%xmm0
  subss  %xmm0,%xmm1
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    $0x2710,%esi
  lea    D42(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D48
datatype: string
name: unpack_data
arguments: data_tag: D31
datatype: string
name: unpack_data
arguments: data_tag: D32
datatype: byte[4]
name: unpack_data
arguments: data_tag: D25
datatype: f32
name: unpack_data
arguments: data_tag: D42
datatype: string

tool: D48: Tails	

tool: D31: Heads	

tool: {"D32": [0x00,0x40,0x1c,0x46]}

tool: D25: 100

tool: D42: Total Flips: %d
Heads: %.2f
Tails: %.2f


assistant: ```c
int main() {
  int coin, loop;
  int total_heads = 0;
  float hpercent, tpercent;
  srand((unsigned)time(NULL));
  for (loop = 0; loop <= 10000; loop++) {
    coin = rand() % 2;
    total_heads += coin;
    if (coin)
      printf("Heads\t");
    else
      printf("Tails\t");
  }
  hpercent = (float)total_heads / 10000 * 100;
  tpercent = 100.0 - hpercent;
  printf("Total Flips: %d\nHeads: %.2f\nTails: %.2f\n", 10000, hpercent, tpercent);
  return 0;
}
```