ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D21(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  nopl   0x0(%rax)
L43:
  mov    %r13,%rbx
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L53
  mov    0x10(%rsp),%r8d
  mov    0x14(%rsp),%esi
  mov    0x18(%rsp),%edx
  mov    0x1c(%rsp),%ecx
  lea    (%r8,%rsi,1),%eax
  mov    0x20(%rsp),%edi
  mov    0x24(%rsp),%r9d
  add    %edx,%eax
  add    %ecx,%eax
  add    %edi,%eax
  add    %r9d,%eax
  je     L50
  lea    (%rdi,%r9,1),%r10d
  mov    %edx,%r11d
  lea    0x6(%rdx),%eax
  add    %ecx,%r10d
  add    $0x3,%r11d
  cmovns %r11d,%eax
  mov    %edx,%r11d
  sar    $0x1f,%r11d
  shr    $0x1e,%r11d
  sar    $0x2,%eax
  add    %eax,%r10d
  lea    (%rdx,%r11,1),%eax
  and    $0x3,%eax
  sub    %r11d,%eax
  lea    (%rcx,%rcx,4),%r11d
  cltq
  add    (%rsp,%rax,4),%r11d
  mov    %r11d,%eax
  cmp    %r11d,%esi
  jle    L57
  mov    %esi,%r11d
  sub    %eax,%r11d
  lea    0x8(%r11),%eax
  imul   $0x38e38e39,%rax,%rax
  shr    $0x21,%rax
  add    %eax,%r10d
L57:
  imul   $0xffffffe7,%edi,%edi
  mov    %r10d,%eax
  shl    $0x4,%ecx
  lea    (%rdx,%rdx,8),%edx
  sub    %r9d,%eax
  shl    $0x2,%esi
  lea    (%rax,%rax,8),%eax
  lea    (%rdi,%rax,4),%eax
  sub    %ecx,%eax
  sub    %edx,%eax
  sub    %esi,%eax
  cmp    %eax,%r8d
  jle    L15
  sub    %eax,%r8d
  lea    0x23(%r8),%eax
  imul   $0x38e38e39,%rax,%rax
  shr    $0x23,%rax
  add    %eax,%r10d
L15:
  mov    %r10d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L50:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: byte[16]

tool: D0: %d


tool: D7: %d

tool: {"D21": [0x00,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void main() {
  int a[6];
  int b[4] = {0, 5, 3, 1};
  int i, count, x2, x1;
  while (1) {
    for (i = 0; i < 6; i++)
      scanf("%d", &a[i]);
    if (a[0] + a[1] + a[2] + a[3] + a[4] + a[5] == 0)
      break;
    count = 0;
    count = a[5] + a[4] + a[3] + (a[2] + 3) / 4;
    x2 = a[3] * 5 + b[a[2] % 4];
    if (x2 < a[1])
      count += (a[1] - x2 + 8) / 9;
    x1 = count * 36 - a[5] * 36 - a[4] * 25 - a[3] * 16 - a[2] * 9 - a[1] * 4;
    if (a[0] > x1)
      count += (a[0] - x1 + 35) / 36;
    printf("%d\n", count);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rdi
  mov    $0x0,%eax
  mov    $0xffffffff,%edx
  mov    %edx,%ecx
  repnz scas %es:(%rdi),%al
  dec    %edi
L1:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L1
  mov    %ecx,%edx
  mov    %esi,-0x10(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) char *strcat(char *dest, const char *src) {
  int d0, d1, d2, d3;
  __asm__ __volatile__("repne\n\t"
                       "scasb\n\t"
                       "decl %1\n"
                       "1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2), "=&c"(d3)
                       : "0"(src), "1"(dest), "2"(0), "3"(0xffffffffu)
                       : "memory");
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcat>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x0,%eax
  mov    $0xffffffff,%ecx
  repnz scas %es:(%rdi),%al
  dec    %edi
L2:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L2
  mov    %rdx,%rax
  ret
```

assistant: ```c
__attribute__((always_)) char *strcat(char *dest, const char *src) {
  int d0, d1, d2, d3;
  __asm__ __volatile__("repne\n\t"
                       "scasb\n\t"
                       "decl %1\n"
                       "1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2), "=&c"(d3)
                       : "0"(src), "1"(dest), "2"(0), "3"(0xffffffffu)
                       : "memory");
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  mov    %rdi,%r8
  xor    %eax,%eax
  mov    $0xffffffff,%ecx
  repnz scas %es:(%rdi),%al
  dec    %edi
L6:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L6
  mov    %r8,%rax
  ret
```

assistant: ```c
__attribute__((always_)) char *strcat(char *dest, const char *src) {
  int d0, d1, d2, d3;
  __asm__ __volatile__("repne\n\t"
                       "scasb\n\t"
                       "decl %1\n"
                       "1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2), "=&c"(d3)
                       : "0"(src), "1"(dest), "2"(0), "3"(0xffffffffu)
                       : "memory");
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcat>:
  endbr64
  mov    %rdi,%r8
  xor    %eax,%eax
  mov    $0xffffffff,%ecx
  repnz scas %es:(%rdi),%al
  dec    %edi
L0:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L0
  mov    %r8,%rax
  ret
```

assistant: ```c
__attribute__((always_)) char *strcat(char *dest, const char *src) {
  int d0, d1, d2, d3;
  __asm__ __volatile__("repne\n\t"
                       "scasb\n\t"
                       "decl %1\n"
                       "1:\tlodsb\n\t"
                       "stosb\n\t"
                       "testb %%al,%%al\n\t"
                       "jne 1b"
                       : "=&S"(d0), "=&D"(d1), "=&a"(d2), "=&c"(d3)
                       : "0"(src), "1"(dest), "2"(0), "3"(0xffffffffu)
                       : "memory");
  return dest;
}
```
user: What is the c source code of the assembly code below?

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L9
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <at91_serial_putc@plt>
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int puts(const char *str) {
  while (*str != 0) {
    at91_serial_putc(*str);
    str++;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L15:
  movsbl %dil,%edi
  call   <at91_serial_putc@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
L7:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *str) {
  while (*str != 0) {
    at91_serial_putc(*str);
    str++;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
L12:
  call   <at91_serial_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L12
L16:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *str) {
  while (*str != 0) {
    at91_serial_putc(*str);
    str++;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L7:
  call   <at91_serial_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L7
L2:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int puts(const char *str) {
  while (*str != 0) {
    at91_serial_putc(*str);
    str++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<recv_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <report@plt>
  nop
L2:
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L2
  mov    -0x4(%rbp),%eax
  and    $0x1e,%eax
  test   %eax,%eax
  je     L34
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L34
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  mov    -0x4(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L46
  mov    $0x99,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fail@plt>
L46:
  mov    $0x9c000000,%edi
  call   <getreg@plt>
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsbl -0x5(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  je     L45
  mov    $0x9c,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fail@plt>
L45:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D3: LSR7 (0x%02x) ERR @ recv_char


tool: D22: ?

tool: D4: expected %02x, read %02x


assistant: ```c
void recv_char(int ch) {
  unsigned x;
  char r;
  report(ch);
  while (!((x = getreg(((0x9c000000) + 5))) & (0x01)))
    ;
  if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
    printf("LSR7 (0x%02x) ERR @ recv_char\n", x);
  ((!(x & (0x80))) ? 1 : fail("?", 153));
  printf("expected %02x, read %02x\n", ch, r = getreg(((0x9c000000) + 0)));
  ((r == ch) ? 1 : fail("?", 156));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recv_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <report@plt>
L51:
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  test   $0x1,%al
  je     L51
  test   $0x1e,%al
  je     L55
  test   $0x80,%al
  je     L27
L0:
  mov    $0x99,%esi
  lea    D33(%rip),%rdi
  call   <fail@plt>
  jmp    L21
L27:
  mov    %eax,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L21
L55:
  test   $0x80,%al
  jne    L0
L21:
  mov    $0x9c000000,%edi
  call   <getreg@plt>
  movsbl %al,%ebx
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L59
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L59:
  mov    $0x9c,%esi
  lea    D33(%rip),%rdi
  call   <fail@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_tag: D33
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string

tool: D33: ?

tool: D17: LSR7 (0x%02x) ERR @ recv_char


tool: D10: expected %02x, read %02x


assistant: ```c
void recv_char(int ch) {
  unsigned x;
  char r;
  report(ch);
  while (!((x = getreg(((0x9c000000) + 5))) & (0x01)))
    ;
  if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
    printf("LSR7 (0x%02x) ERR @ recv_char\n", x);
  ((!(x & (0x80))) ? 1 : fail("?", 153));
  printf("expected %02x, read %02x\n", ch, r = getreg(((0x9c000000) + 0)));
  ((r == ch) ? 1 : fail("?", 156));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recv_char>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <report@plt>
  nopl   0x0(%rax)
L17:
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,%esi
  test   $0x1,%al
  je     L17
  and    $0x80,%eax
  test   $0x1e,%sil
  je     L43
  test   %eax,%eax
  je     L50
L34:
  mov    $0x99,%esi
  lea    D4(%rip),%rdi
  call   <fail@plt>
  jmp    L66
  nopw   0x0(%rax,%rax,1)
L43:
  test   %eax,%eax
  jne    L34
L66:
  mov    $0x9c000000,%edi
  call   <getreg@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  movsbl %al,%ebx
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L14:
  add    $0x8,%rsp
  mov    $0x9c,%esi
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1080 <fail@plt>
  nopw   0x0(%rax,%rax,1)
L50:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L66
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D4: ?

tool: D0: expected %02x, read %02x


tool: D10: LSR7 (0x%02x) ERR @ recv_char


assistant: ```c
void recv_char(int ch) {
  unsigned x;
  char r;
  report(ch);
  while (!((x = getreg(((0x9c000000) + 5))) & (0x01)))
    ;
  if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
    printf("LSR7 (0x%02x) ERR @ recv_char\n", x);
  ((!(x & (0x80))) ? 1 : fail("?", 153));
  printf("expected %02x, read %02x\n", ch, r = getreg(((0x9c000000) + 0)));
  ((r == ch) ? 1 : fail("?", 156));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<recv_char>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <report@plt>
  nopl   0x0(%rax)
L22:
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,%esi
  test   $0x1,%al
  je     L22
  and    $0x80,%eax
  test   $0x1e,%sil
  je     L53
  test   %eax,%eax
  je     L42
L33:
  mov    $0x99,%esi
  lea    D18(%rip),%rdi
  call   <fail@plt>
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L53:
  test   %eax,%eax
  jne    L33
L31:
  mov    $0x9c000000,%edi
  call   <getreg@plt>
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  movsbl %al,%ebx
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <printf@plt>
  cmp    %ebp,%ebx
  jne    L23
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L23:
  add    $0x8,%rsp
  mov    $0x9c,%esi
  lea    D18(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1080 <fail@plt>
  nopw   0x0(%rax,%rax,1)
L42:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L31
```

tool_calls: name: read_data
arguments: data_label: D18
datatype: string
name: read_data
arguments: data_label: D5
datatype: string
name: read_data
arguments: data_label: D29
datatype: string

tool: D18: ?

tool: D5: expected %02x, read %02x


tool: D29: LSR7 (0x%02x) ERR @ recv_char


assistant: ```c
void recv_char(int ch) {
  unsigned x;
  char r;
  report(ch);
  while (!((x = getreg(((0x9c000000) + 5))) & (0x01)))
    ;
  if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
    printf("LSR7 (0x%02x) ERR @ recv_char\n", x);
  ((!(x & (0x80))) ? 1 : fail("?", 153));
  printf("expected %02x, read %02x\n", ch, r = getreg(((0x9c000000) + 0)));
  ((r == ch) ? 1 : fail("?", 156));
}
```
user: Translate the below assembly code into C programming language:

```asm
<compute_window>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x8(%rbp),%xmm1
  movsd  D26(%rip),%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0x4(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D26(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D14(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  pxor   %xmm3,%xmm3
  cvtsi2ss %rax,%xmm3
  movd   %xmm3,%eax
  movd   %eax,%xmm0
  call   <square@plt>
  movsd  D12(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rdx,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L15
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
data_type: f64
name: disassemble_data
arguments: data_tag: D14
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D12
data_type: byte[8]

tool: D26: 0.5

tool: {"D14": [0x00,0x00,0x00,0x60,0xfb,0x21,0x09,0x40]}

tool: {"D12": [0x00,0x00,0x00,0x60,0xfb,0x21,0xf9,0x3f]}

assistant: ```c
void compute_window(int n, float *window) {
  int n2 = n >> 1, i;
  for (i = 0; i < n2; ++i)
    window[i] = (float)sin(0.5 * 3.14159265358979323846264f * square((float)sin((i - 0 + 0.5) / n2 * 0.5 * 3.14159265358979323846264f)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_window>:
  endbr64
  sar    %edi
  test   %edi,%edi
  jle    L19
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbp
  mov    %edi,%r12d
  mov    $0x0,%ebx
  pxor   %xmm2,%xmm2
  cvtsi2sd %edi,%xmm2
  movsd  %xmm2,0x8(%rsp)
L2:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  addsd  D25(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  mulsd  D25(%rip),%xmm0
  mulsd  D36(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  call   <square@plt>
  mulsd  D8(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
type_guessed: f64
name: retrieve_data
arguments: tag: D36
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D8
type_guessed: byte[8]

tool: D25: 0.5

tool: {"D36": [0x00,0x00,0x00,0x60,0xfb,0x21,0x09,0x40]}

tool: {"D8": [0x00,0x00,0x00,0x60,0xfb,0x21,0xf9,0x3f]}

assistant: ```c
void compute_window(int n, float *window) {
  int n2 = n >> 1, i;
  for (i = 0; i < n2; ++i)
    window[i] = (float)sin(0.5 * 3.14159265358979323846264f * square((float)sin((i - 0 + 0.5) / n2 * 0.5 * 3.14159265358979323846264f)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compute_window>:
  endbr64
  sar    %edi
  test   %edi,%edi
  jle    L8
  pxor   %xmm2,%xmm2
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  cvtsi2sd %edi,%xmm2
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm2,0x8(%rsp)
  nopl   (%rax)
L7:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  addsd  D19(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  mulsd  D19(%rip),%xmm0
  mulsd  D4(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  call   <square@plt>
  mulsd  D31(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp,%r12,4)
  add    $0x1,%r12
  cmp    %r12,%rbx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: f64
name: retrieve_data
arguments: tag: D4
type_infered: byte[8]
name: retrieve_data
arguments: tag: D31
type_infered: byte[8]

tool: D19: 0.5

tool: {"D4": [0x00,0x00,0x00,0x60,0xfb,0x21,0x09,0x40]}

tool: {"D31": [0x00,0x00,0x00,0x60,0xfb,0x21,0xf9,0x3f]}

assistant: ```c
void compute_window(int n, float *window) {
  int n2 = n >> 1, i;
  for (i = 0; i < n2; ++i)
    window[i] = (float)sin(0.5 * 3.14159265358979323846264f * square((float)sin((i - 0 + 0.5) / n2 * 0.5 * 3.14159265358979323846264f)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<compute_window>:
  endbr64
  sar    %edi
  test   %edi,%edi
  jle    L2
  pxor   %xmm2,%xmm2
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  cvtsi2sd %edi,%xmm2
  mov    %rsi,%rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x10,%rsp
  movsd  %xmm2,0x8(%rsp)
  nopl   (%rax)
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  addsd  D28(%rip),%xmm0
  divsd  0x8(%rsp),%xmm0
  mulsd  D28(%rip),%xmm0
  mulsd  D23(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  call   <square@plt>
  mulsd  D3(%rip),%xmm0
  call   <sin@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  %xmm0,0x0(%rbp,%r12,4)
  add    $0x1,%r12
  cmp    %r12,%rbx
  jne    L5
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  ret
```

tool_calls: name: read_data
arguments: label: D28
datatype: f64
name: read_data
arguments: label: D23
datatype: byte[8]
name: read_data
arguments: label: D3
datatype: byte[8]

tool: D28: 0.5

tool: {"D23": [0x00,0x00,0x00,0x60,0xfb,0x21,0x09,0x40]}

tool: {"D3": [0x00,0x00,0x00,0x60,0xfb,0x21,0xf9,0x3f]}

assistant: ```c
void compute_window(int n, float *window) {
  int n2 = n >> 1, i;
  for (i = 0; i < n2; ++i)
    window[i] = (float)sin(0.5 * 3.14159265358979323846264f * square((float)sin((i - 0 + 0.5) / n2 * 0.5 * 3.14159265358979323846264f)));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D102(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L17:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L17
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <preOrder@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <inOrder@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <postOrder@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D39
type: string
name: unpack_data
arguments: tag: D24
type: string
name: unpack_data
arguments: tag: D102
type: string
name: unpack_data
arguments: tag: D7
type: string
name: unpack_data
arguments: tag: D74
type: string
name: unpack_data
arguments: tag: D36
type: string
name: unpack_data
arguments: tag: D11
type: string

tool: D39: Enter the number of elements to input:


tool: D24: %d

tool: D102: Enter the elements:


tool: D7: 


tool: D74: Pre-order:


tool: D36: In-order:


tool: D11: Post-order:


assistant: ```c
int main() {
  int n, elem;
  struct node *root = NULL;
  printf("Enter the number of elements to input:\n");
  scanf("%d", &n);
  printf("Enter the elements:\n");
  for (int i = 0; i < n; i++) {
    scanf("%d", &elem);
    root = insert(root, elem);
  }
  printf("\n");
  printf("Pre-order:\n");
  preOrder(root);
  printf("\n");
  printf("In-order:\n");
  inOrder(root);
  printf("\n");
  printf("Post-order:\n");
  postOrder(root);
  printf("\n");
  return 0;
}
```