ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getGroupIDList>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsi)
  lea    0x10(%rsp),%rsi
  movq   $0x0,(%rdx)
  movq   $0x0,0x10(%rsp)
  call   <getPW@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L68
  mov    0x10(%rsp),%rdi
  test   %rdi,%rdi
  je     L0
L72:
  call   <free@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L68:
  mov    0x10(%rsp),%r14
  lea    0xc(%rsp),%r15
  xor    %edx,%edx
  mov    %rbp,%rdi
  movl   $0x0,0xc(%rsp)
  mov    %r15,%rcx
  mov    (%r14),%esi
  call   <getgrouplist@plt>
  test   %rax,%rax
  js     L59
L29:
  mov    0x10(%rsp),%rdi
  jmp    L72
  xchg   %ax,%ax
L59:
  mov    0xc(%rsp),%edi
  mov    %edi,(%rbx)
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    %rax,%rdx
  test   %rax,%rax
  je     L49
  mov    (%r14),%esi
  mov    %r15,%rcx
  mov    %rbp,%rdi
  call   <getgrouplist@plt>
  test   %rax,%rax
  jns    L29
  movl   $0x0,(%rbx)
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x0(%r13),%rdi
  call   <free@plt>
  mov    D9(%rip),%rax
  movq   $0x0,0x0(%r13)
  mov    (%rax),%r12d
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L49:
  movl   $0x0,(%rbx)
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%r12d
  jmp    L0
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getGroupIDList(const char *user, int *ngroups, gid_t **groups) {
  int getPW(const char *user, char **pwbuf);
  *ngroups = 0;
  char *pwbuf = NULL;
  *groups = NULL;
  int error = getPW(user, &pwbuf);
  if (error != 0) {
    if (pwbuf != NULL) {
      free(pwbuf);
    }
    return error;
  }
  struct passwd *pw = (struct passwd *)pwbuf;
  int ng = 0;
  if (getgrouplist(user, pw->pw_gid, NULL, &ng) < 0) {
    *ngroups = ng;
    *groups = (gid_t *)malloc(ng * sizeof(gid_t));
    if (!*groups) {
      *ngroups = 0;
      free(pwbuf);
      return ENOMEM;
    }
    if (getgrouplist(user, pw->pw_gid, *groups, &ng) < 0) {
      *ngroups = 0;
      free(pwbuf);
      free(*groups);
      *groups = NULL;
      return ENOENT;
    }
  }
  free(pwbuf);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<octalValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0xd(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L31:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <isOctalDigit@plt>
  test   %rax,%rax
  je     L22
  shll   $0x3,-0xc(%rbp)
  movsbl -0xd(%rbp),%eax
  mov    %eax,%edi
  call   <digitValue@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L31
  jmp    L27
L22:
  nop
L27:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int octalValue(char const *octalString) {
  int numberValue = 0;
  int i = 0, siz = 0;
  char digit = 0;
  siz = strlen(octalString);
  for (i = 0; i < siz; i++) {
    digit = octalString[i];
    if (isOctalDigit(digit)) {
      numberValue <<= 3;
      numberValue += digitValue(digit);
    } else {
      break;
    }
  }
  return numberValue;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<octalValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%r13
  mov    $0x0,%r12d
L5:
  movsbl (%rbx),%ebp
  mov    %ebp,%edi
  call   <isOctalDigit@plt>
  test   %rax,%rax
  je     L34
  mov    %ebp,%edi
  call   <digitValue@plt>
  lea    (%rax,%r12,8),%r12d
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L5
L34:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    $0x0,%r12d
  jmp    L34
```

assistant: ```c
int octalValue(char const *octalString) {
  int numberValue = 0;
  int i = 0, siz = 0;
  char digit = 0;
  siz = strlen(octalString);
  for (i = 0; i < siz; i++) {
    digit = octalString[i];
    if (isOctalDigit(digit)) {
      numberValue <<= 3;
      numberValue += digitValue(digit);
    } else {
      break;
    }
  }
  return numberValue;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<octalValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L32
  sub    $0x1,%eax
  xor    %r12d,%r12d
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <digitValue@plt>
  lea    (%rax,%r12,8),%r12d
  cmp    %r13,%rbx
  je     L0
L40:
  movsbl (%rbx),%ebp
  mov    %ebp,%edi
  call   <isOctalDigit@plt>
  test   %rax,%rax
  jne    L5
L0:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  xor    %r12d,%r12d
  jmp    L0
```

assistant: ```c
int octalValue(char const *octalString) {
  int numberValue = 0;
  int i = 0, siz = 0;
  char digit = 0;
  siz = strlen(octalString);
  for (i = 0; i < siz; i++) {
    digit = octalString[i];
    if (isOctalDigit(digit)) {
      numberValue <<= 3;
      numberValue += digitValue(digit);
    } else {
      break;
    }
  }
  return numberValue;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<octalValue>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L5
  sub    $0x1,%eax
  xor    %r12d,%r12d
  lea    0x1(%rbx,%rax,1),%r13
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %ebp,%edi
  add    $0x1,%rbx
  call   <digitValue@plt>
  lea    (%rax,%r12,8),%r12d
  cmp    %r13,%rbx
  je     L16
L40:
  movsbl (%rbx),%ebp
  mov    %ebp,%edi
  call   <isOctalDigit@plt>
  test   %rax,%rax
  jne    L31
L16:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  xor    %r12d,%r12d
  jmp    L16
```

assistant: ```c
int octalValue(char const *octalString) {
  int numberValue = 0;
  int i = 0, siz = 0;
  char digit = 0;
  siz = strlen(octalString);
  for (i = 0; i < siz; i++) {
    digit = octalString[i];
    if (isOctalDigit(digit)) {
      numberValue <<= 3;
      numberValue += digitValue(digit);
    } else {
      break;
    }
  }
  return numberValue;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L46
L8:
  addq   $0x1,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_is_wht_spc@plt>
  test   %rax,%rax
  jne    L8
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L6
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L78
L6:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L87
  mov    $0xffffffff,%eax
  jmp    L4
L87:
  mov    $0x1,%eax
L4:
  mov    %eax,-0x4(%rbp)
  jmp    L78
L27:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
L78:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L27
L12:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int sign;
  nb = 0;
  while (ft_is_wht_spc(*str))
    str++;
  sign = 1;
  if (*str == '-' || *str == '+')
    sign = (*(str++) == '-') ? -1 : 1;
  while (*str && ft_isdigit(*str))
    nb = nb * 10 + *(str++) - '0';
  return (sign * nb);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L19
L69:
  add    $0x1,%rbx
L19:
  movsbl (%rbx),%edi
  call   <ft_is_wht_spc@plt>
  test   %rax,%rax
  jne    L69
  movzbl (%rbx),%eax
  lea    -0x2b(%rax),%edx
  mov    $0x1,%r12d
  test   $0xfd,%dl
  jne    L12
  add    $0x1,%rbx
  cmp    $0x2d,%al
  setne  %r12b
  movzbl %r12b,%r12d
  lea    -0x1(%r12,%r12,1),%r12d
L12:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L37
  mov    $0x0,%ebp
L22:
  movsbl %dil,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L34
  add    $0x1,%rbx
  lea    0x0(%rbp,%rbp,4),%edx
  movsbl -0x1(%rbx),%eax
  lea    -0x30(%rax,%rdx,2),%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L22
L34:
  mov    %r12d,%eax
  imul   %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0x0,%ebp
  jmp    L34
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int sign;
  nb = 0;
  while (ft_is_wht_spc(*str))
    str++;
  sign = 1;
  if (*str == '-' || *str == '+')
    sign = (*(str++) == '-') ? -1 : 1;
  while (*str && ft_isdigit(*str))
    nb = nb * 10 + *(str++) - '0';
  return (sign * nb);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L3
  nopl   (%rax)
L28:
  add    $0x1,%rbx
L3:
  movsbl (%rbx),%edi
  call   <ft_is_wht_spc@plt>
  test   %rax,%rax
  jne    L28
  movsbl (%rbx),%edi
  mov    $0x1,%r12d
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L99
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  cmp    $0x2d,%dil
  mov    %rax,%rbx
  movsbl %dl,%edi
  je     L26
L99:
  test   %dil,%dil
  je     L6
  xor    %ebp,%ebp
  jmp    L40
  xchg   %ax,%ax
L66:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
  test   %dil,%dil
  je     L62
L40:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L66
  mov    %r12d,%eax
  imul   %ebp,%eax
L30:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L62:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0xffffffff,%r12d
  jmp    L99
L6:
  xor    %eax,%eax
  jmp    L30
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int sign;
  nb = 0;
  while (ft_is_wht_spc(*str))
    str++;
  sign = 1;
  if (*str == '-' || *str == '+')
    sign = (*(str++) == '-') ? -1 : 1;
  while (*str && ft_isdigit(*str))
    nb = nb * 10 + *(str++) - '0';
  return (sign * nb);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_atoi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L57
  nopl   (%rax)
L33:
  add    $0x1,%rbx
L57:
  movsbl (%rbx),%edi
  call   <ft_is_wht_spc@plt>
  test   %rax,%rax
  jne    L33
  movsbl (%rbx),%edi
  mov    $0x1,%r12d
  lea    -0x2b(%rdi),%eax
  test   $0xfd,%al
  jne    L26
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  cmp    $0x2d,%dil
  mov    %rax,%rbx
  movsbl %dl,%edi
  je     L47
L26:
  test   %dil,%dil
  je     L56
  xor    %ebp,%ebp
  jmp    L74
  xchg   %ax,%ax
L90:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  lea    0x0(%rbp,%rbp,4),%edx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%ebp
  test   %dil,%dil
  je     L39
L74:
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L90
  mov    %r12d,%eax
  imul   %ebp,%eax
L83:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L39:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  imul   %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0xffffffff,%r12d
  jmp    L26
L56:
  xor    %eax,%eax
  jmp    L83
```

assistant: ```c
int ft_atoi(const char *str) {
  int nb;
  int sign;
  nb = 0;
  while (ft_is_wht_spc(*str))
    str++;
  sign = 1;
  if (*str == '-' || *str == '+')
    sign = (*(str++) == '-') ? -1 : 1;
  while (*str && ft_isdigit(*str))
    nb = nb * 10 + *(str++) - '0';
  return (sign * nb);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_objc_ivar_symbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t is_objc_ivar_symbol(const char *__attribute__((nonnull)) const symbol, const uint64_t first) {
  if (first != 6217605503174987615) {
    return 0;
  }
  const uint32_t second = *(const uint32_t *)(symbol + 8);
  if (second != 610226753) {
    return 0;
  }
  if (symbol[12] != '_') {
    return 0;
  }
  return 12;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_objc_ivar_symbol>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
uint64_t is_objc_ivar_symbol(const char *__attribute__((nonnull)) const symbol, const uint64_t first) {
  if (first != 6217605503174987615) {
    return 0;
  }
  const uint32_t second = *(const uint32_t *)(symbol + 8);
  if (second != 610226753) {
    return 0;
  }
  if (symbol[12] != '_') {
    return 0;
  }
  return 12;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_objc_ivar_symbol>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t is_objc_ivar_symbol(const char *__attribute__((nonnull)) const symbol, const uint64_t first) {
  if (first != 6217605503174987615) {
    return 0;
  }
  const uint32_t second = *(const uint32_t *)(symbol + 8);
  if (second != 610226753) {
    return 0;
  }
  if (symbol[12] != '_') {
    return 0;
  }
  return 12;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_objc_ivar_symbol>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t is_objc_ivar_symbol(const char *__attribute__((nonnull)) const symbol, const uint64_t first) {
  if (first != 6217605503174987615) {
    return 0;
  }
  const uint32_t second = *(const uint32_t *)(symbol + 8);
  if (second != 610226753) {
    return 0;
  }
  if (symbol[12] != '_') {
    return 0;
  }
  return 12;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo() {
  enum xpto;
  enum xpto;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  enum xpto;
  enum xpto;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo() {
  enum xpto;
  enum xpto;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readgb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L23:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <readrecord@plt>
  add    %eax,-0xc(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L23
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
unsigned int readgb(FILE *f) {
  unsigned int nErrors = 0;
  int atEnd = 0;
  while (atEnd == 0) {
    nErrors += readrecord(f, &atEnd);
    if (atEnd == 0) {
    }
  }
  return nErrors;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readgb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r12
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <readrecord@plt>
  add    %eax,%ebx
  cmpl   $0x0,0x4(%rsp)
  je     L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int readgb(FILE *f) {
  unsigned int nErrors = 0;
  int atEnd = 0;
  while (atEnd == 0) {
    nErrors += readrecord(f, &atEnd);
    if (atEnd == 0) {
    }
  }
  return nErrors;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readgb>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  nop
L5:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readrecord@plt>
  add    %eax,%r12d
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int readgb(FILE *f) {
  unsigned int nErrors = 0;
  int atEnd = 0;
  while (atEnd == 0) {
    nErrors += readrecord(f, &atEnd);
    if (atEnd == 0) {
    }
  }
  return nErrors;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readgb>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  nop
L9:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <readrecord@plt>
  add    %eax,%r12d
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L9
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int readgb(FILE *f) {
  unsigned int nErrors = 0;
  int atEnd = 0;
  while (atEnd == 0) {
    nErrors += readrecord(f, &atEnd);
    if (atEnd == 0) {
    }
  }
  return nErrors;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<poly_area_no_adjust>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %edx,%edx
  jle    L35
  mov    %rdi,%r13
  mov    %rsi,%r15
  mov    %edx,%r12d
  lea    0x1(%rdx),%r14d
  mov    $0x1,%ebx
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L6
L13:
  call   <cos@plt>
  movq   %xmm0,%rbp
  movsd  0x18(%rsp),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm0
  subsd  %xmm1,%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x10(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
L0:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L56
L6:
  mov    %ebx,%eax
  cltd
  idiv   %r12d
  movslq %edx,%rdx
  movsd  0x0(%r13,%rdx,8),%xmm0
  subsd  -0x8(%r13,%rbx,8),%xmm0
  movsd  %xmm0,(%rsp)
  pxor   %xmm4,%xmm4
  ucomisd %xmm4,%xmm0
  jp     L55
  je     L0
L55:
  movsd  (%r15,%rdx,8),%xmm0
  movsd  -0x8(%r15,%rbx,8),%xmm3
  movsd  %xmm3,0x18(%rsp)
  movapd %xmm0,%xmm2
  subsd  %xmm3,%xmm2
  movsd  %xmm2,0x10(%rsp)
  movapd %xmm2,%xmm1
  andpd  D0(%rip),%xmm1
  movsd  D36(%rip),%xmm5
  comisd %xmm1,%xmm5
  jbe    L13
  addsd  %xmm3,%xmm0
  mulsd  D8(%rip),%xmm0
  call   <sin@plt>
  mulsd  (%rsp),%xmm0
  movsd  0x8(%rsp),%xmm6
  subsd  %xmm0,%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L0
L35:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
L56:
  movsd  D11(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: qword[2]
name: unpack_data
arguments: tag: D36
datatype: byte[8]
name: unpack_data
arguments: tag: D8
datatype: f64
name: unpack_data
arguments: tag: D11
datatype: f64

tool: {"D0": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D36": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

tool: D8: 0.5

tool: D11: 6371000

assistant: ```c
double poly_area_no_adjust(const double x[], const double y[], int n) {
  double area = 0.0;
  int i;
  for (i = 0; i < n; i++) {
    int ip = (i + 1) % n;
    double dx = (x[ip] - x[i]);
    double lat1, lat2;
    lat1 = y[ip];
    lat2 = y[i];
    if (dx == 0.0)
      continue;
    if (fabs(lat1 - lat2) < (1.e-10))
      area -= dx * sin(0.5 * (lat1 + lat2));
    else
      area += dx * (cos(lat1) - cos(lat2)) / (lat1 - lat2);
  }
  return area * (6371000.) * (6371000.);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<poly_area_no_adjust>:
  endbr64
  test   %edx,%edx
  jle    L2
  push   %r14
  pxor   %xmm3,%xmm3
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x30,%rsp
  jmp    L21
  nop
L32:
  addsd  %xmm4,%xmm0
  mulsd  D27(%rip),%xmm0
  movsd  %xmm1,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <sin@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm3
  mulsd  %xmm1,%xmm0
  subsd  %xmm0,%xmm3
L20:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L6
L21:
  mov    %ebx,%eax
  pxor   %xmm6,%xmm6
  cltd
  idiv   %ebp
  movslq %edx,%rdx
  movsd  0x0(%r13,%rdx,8),%xmm1
  subsd  -0x8(%r13,%rbx,8),%xmm1
  ucomisd %xmm6,%xmm1
  jp     L48
  je     L20
L48:
  movsd  (%r14,%rdx,8),%xmm0
  movsd  -0x8(%r14,%rbx,8),%xmm4
  movsd  D4(%rip),%xmm7
  movapd %xmm0,%xmm5
  subsd  %xmm4,%xmm5
  movapd %xmm5,%xmm2
  andpd  D16(%rip),%xmm2
  comisd %xmm2,%xmm7
  ja     L32
  movsd  %xmm1,0x20(%rsp)
  add    $0x1,%rbx
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm4,0x28(%rsp)
  call   <cos@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm4,%xmm0
  call   <cos@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  0x20(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm5
  movsd  0x18(%rsp),%xmm3
  subsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  divsd  %xmm5,%xmm0
  addsd  %xmm0,%xmm3
  cmp    %rbx,%r12
  jne    L21
L6:
  movsd  D13(%rip),%xmm1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  mulsd  %xmm1,%xmm3
  pop    %r12
  pop    %r13
  pop    %r14
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  ret
  nop
L2:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D27
data_type: f64
name: parse_data
arguments: data_tag: D4
data_type: byte[8]
name: parse_data
arguments: data_tag: D16
data_type: qword[2]
name: parse_data
arguments: data_tag: D13
data_type: f64

tool: D27: 0.5

tool: {"D4": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d]}

tool: {"D16": [0x7fffffffffffffff,0x0000000000000000]}

tool: D13: 6371000

assistant: ```c
double poly_area_no_adjust(const double x[], const double y[], int n) {
  double area = 0.0;
  int i;
  for (i = 0; i < n; i++) {
    int ip = (i + 1) % n;
    double dx = (x[ip] - x[i]);
    double lat1, lat2;
    lat1 = y[ip];
    lat2 = y[i];
    if (dx == 0.0)
      continue;
    if (fabs(lat1 - lat2) < (1.e-10))
      area -= dx * sin(0.5 * (lat1 + lat2));
    else
      area += dx * (cos(lat1) - cos(lat2)) / (lat1 - lat2);
  }
  return area * (6371000.) * (6371000.);
}
```