ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<operands_fix_8bit_rex_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jbe    L18
  cmpl   $0x7,-0x4(%rbp)
  ja     L18
  mov    -0x4(%rbp),%eax
  add    $0x3c,%eax
  jmp    L27
L18:
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
unsigned int operands_fix_8bit_rex_base(unsigned int reg) {
  if ((reg >= 4) && (reg < 8))
    return reg + (64) - 4;
  return reg + (48);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<operands_fix_8bit_rex_base>:
  endbr64
  lea    -0x4(%rdi),%edx
  lea    0x3c(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x3,%edx
  cmova  %edi,%eax
  ret
```

assistant: ```c
unsigned int operands_fix_8bit_rex_base(unsigned int reg) {
  if ((reg >= 4) && (reg < 8))
    return reg + (64) - 4;
  return reg + (48);
}
```
user: What is the c source code of the assembly code below?

```asm
<operands_fix_8bit_rex_base>:
  endbr64
  lea    -0x4(%rdi),%edx
  lea    0x3c(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x3,%edx
  cmova  %edi,%eax
  ret
```

assistant: ```c
unsigned int operands_fix_8bit_rex_base(unsigned int reg) {
  if ((reg >= 4) && (reg < 8))
    return reg + (64) - 4;
  return reg + (48);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<operands_fix_8bit_rex_base>:
  endbr64
  lea    -0x4(%rdi),%edx
  lea    0x3c(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x3,%edx
  cmova  %edi,%eax
  ret
```

assistant: ```c
unsigned int operands_fix_8bit_rex_base(unsigned int reg) {
  if ((reg >= 4) && (reg < 8))
    return reg + (64) - 4;
  return reg + (48);
}
```
user: Translate the below assembly code into C programming language:

```asm
<javacall_os_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <javacall_logging_initialize@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void javacall_os_initialize(void) {
  javacall_logging_initialize();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<javacall_os_initialize>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <javacall_logging_initialize@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void javacall_os_initialize(void) {
  javacall_logging_initialize();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<javacall_os_initialize>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <javacall_logging_initialize@plt>
```

assistant: ```c
void javacall_os_initialize(void) {
  javacall_logging_initialize();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<javacall_os_initialize>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <javacall_logging_initialize@plt>
```

assistant: ```c
void javacall_os_initialize(void) {
  javacall_logging_initialize();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<gfx_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ILI948x_drv_init@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gfx_init(void) {
  ILI948x_drv_init();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gfx_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ILI948x_drv_init@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gfx_init(void) {
  ILI948x_drv_init();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gfx_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ILI948x_drv_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gfx_init(void) {
  ILI948x_drv_init();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<gfx_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ILI948x_drv_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gfx_init(void) {
  ILI948x_drv_init();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pickHighest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L6
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L6:
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x2,-0x4(%rbp)
  jle    L16
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pickHighest(int a[]) {
  int highest = a[0];
  int i = 1;
  for (; i < 3; i++)
    if (highest < a[i])
      highest = a[i];
  return highest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pickHighest>:
  endbr64
  mov    0x8(%rdi),%eax
  mov    0x4(%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    (%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int pickHighest(int a[]) {
  int highest = a[0];
  int i = 1;
  for (; i < 3; i++)
    if (highest < a[i])
      highest = a[i];
  return highest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pickHighest>:
  endbr64
  mov    0x4(%rdi),%edx
  mov    (%rdi),%eax
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    0x8(%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int pickHighest(int a[]) {
  int highest = a[0];
  int i = 1;
  for (; i < 3; i++)
    if (highest < a[i])
      highest = a[i];
  return highest;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pickHighest>:
  endbr64
  mov    0x4(%rdi),%edx
  mov    (%rdi),%eax
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    0x8(%rdi),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int pickHighest(int a[]) {
  int highest = a[0];
  int i = 1;
  for (; i < 3; i++)
    if (highest < a[i])
      highest = a[i];
  return highest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<append_hex_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xb0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x3,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movl   $0xb3,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movl   $0xcd,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movl   $0x80,(%rax)
  mov    $0x6,%eax
  pop    %rbp
  ret
```

assistant: ```c
size_t append_hex_in(uint8_t *dst) {
  dst[0] = 0xb0;
  dst[1] = 0x03;
  dst[2] = 0xb3;
  dst[3] = 0x00;
  dst[4] = 0xcd;
  dst[5] = 0x80;
  return 6;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_hex_in>:
  endbr64
  movl   $0xb0,(%rdi)
  movl   $0x3,0x4(%rdi)
  movl   $0xb3,0x8(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0xcd,0x10(%rdi)
  movl   $0x80,0x14(%rdi)
  mov    $0x6,%eax
  ret
```

assistant: ```c
size_t append_hex_in(uint8_t *dst) {
  dst[0] = 0xb0;
  dst[1] = 0x03;
  dst[2] = 0xb3;
  dst[3] = 0x00;
  dst[4] = 0xcd;
  dst[5] = 0x80;
  return 6;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_hex_in>:
  endbr64
  movabs $0x3000000b0,%rax
  movq   $0xb3,0x8(%rdi)
  mov    %rax,(%rdi)
  movabs $0x80000000cd,%rax
  mov    %rax,0x10(%rdi)
  mov    $0x6,%eax
  ret
```

assistant: ```c
size_t append_hex_in(uint8_t *dst) {
  dst[0] = 0xb0;
  dst[1] = 0x03;
  dst[2] = 0xb3;
  dst[3] = 0x00;
  dst[4] = 0xcd;
  dst[5] = 0x80;
  return 6;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<append_hex_in>:
  endbr64
  mov    D8(%rip),%rax
  movdqa D13(%rip),%xmm0
  mov    %rax,0x10(%rdi)
  mov    $0x6,%eax
  movups %xmm0,(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D13
type_infered: byte[16]

tool: {"D8": [0xcd,0x00,0x00,0x00,0x80,0x00,0x00,0x00]}

tool: {"D13": [0xb0,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0xb3,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
size_t append_hex_in(uint8_t *dst) {
  dst[0] = 0xb0;
  dst[1] = 0x03;
  dst[2] = 0xb3;
  dst[3] = 0x00;
  dst[4] = 0xcd;
  dst[5] = 0x80;
  return 6;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: %s


assistant: ```c
int main(int argc, char **argv) {
  char *path = malloc(256);
  printf("%s\n", getcwd(path, 256));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x100,%esi
  call   <getcwd@plt>
  mov    %rax,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: %s


assistant: ```c
int main(int argc, char **argv) {
  char *path = malloc(256);
  printf("%s\n", getcwd(path, 256));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: %s


assistant: ```c
int main(int argc, char **argv) {
  char *path = malloc(256);
  printf("%s\n", getcwd(path, 256));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: %s


assistant: ```c
int main(int argc, char **argv) {
  char *path = malloc(256);
  printf("%s\n", getcwd(path, 256));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
pid_t _wait(int *status) {
  assert(0);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_wait>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
pid_t _wait(int *status) {
  assert(0);
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<_wait>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
pid_t _wait(int *status) {
  assert(0);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_wait>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assert@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
pid_t _wait(int *status) {
  assert(0);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wcsstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L59
L58:
  movq   $0x0,-0x8(%rbp)
  jmp    L21
L31:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L31
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L57
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L17
L57:
  addq   $0x1,-0x10(%rbp)
L59:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L58
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
wchar_t *wcsstr(const wchar_t *haystack, const wchar_t *needle) {
  size_t i, j;
  for (i = 0; haystack[i]; ++i) {
    for (j = 0; haystack[i + j] == needle[j]; ++j)
      ;
    if (!needle[j])
      return (wchar_t *)haystack + i;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wcsstr>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L11
  mov    (%rsi),%rcx
  jmp    L36
L37:
  add    $0x1,%rax
  mov    (%rsi,%rax,8),%rdx
  cmp    %rdx,(%rdi,%rax,8)
  je     L37
L8:
  test   %rdx,%rdx
  je     L43
  add    $0x8,%rdi
  cmpq   $0x0,(%rdi)
  je     L57
L36:
  mov    $0x0,%eax
  mov    %rcx,%rdx
  cmp    %rcx,(%rdi)
  je     L37
  jmp    L8
L11:
  mov    $0x0,%edi
  jmp    L43
L57:
  mov    $0x0,%edi
L43:
  mov    %rdi,%rax
  ret
```

assistant: ```c
wchar_t *wcsstr(const wchar_t *haystack, const wchar_t *needle) {
  size_t i, j;
  for (i = 0; haystack[i]; ++i) {
    for (j = 0; haystack[i + j] == needle[j]; ++j)
      ;
    if (!needle[j])
      return (wchar_t *)haystack + i;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<wcsstr>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rdi,%r8
  test   %rdx,%rdx
  je     L18
  mov    (%rsi),%rcx
  nopw   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
  cmp    %rdx,%rcx
  jne    L15
  nop
L37:
  add    $0x1,%rax
  mov    (%rsi,%rax,8),%rdx
  cmp    %rdx,(%r8,%rax,8)
  je     L37
L34:
  test   %rdx,%rdx
  je     L40
  mov    0x8(%r8),%rdx
  add    $0x8,%r8
  test   %rdx,%rdx
  jne    L59
L18:
  xor    %r8d,%r8d
L40:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rcx,%rdx
  jmp    L34
```

assistant: ```c
wchar_t *wcsstr(const wchar_t *haystack, const wchar_t *needle) {
  size_t i, j;
  for (i = 0; haystack[i]; ++i) {
    for (j = 0; haystack[i + j] == needle[j]; ++j)
      ;
    if (!needle[j])
      return (wchar_t *)haystack + i;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wcsstr>:
  endbr64
  cmpq   $0x0,(%rdi)
  mov    %rdi,%r8
  je     L5
  mov    (%rsi),%rcx
L24:
  xor    %eax,%eax
  mov    %rcx,%rdx
  cmp    %rcx,(%r8)
  jne    L25
  nopw   0x0(%rax,%rax,1)
L44:
  add    $0x1,%rax
  mov    (%rsi,%rax,8),%rdx
  cmp    %rdx,(%r8,%rax,8)
  je     L44
L25:
  test   %rdx,%rdx
  je     L31
  add    $0x8,%r8
  cmpq   $0x0,(%r8)
  jne    L24
L5:
  xor    %r8d,%r8d
L31:
  mov    %r8,%rax
  ret
```

assistant: ```c
wchar_t *wcsstr(const wchar_t *haystack, const wchar_t *needle) {
  size_t i, j;
  for (i = 0; haystack[i]; ++i) {
    for (j = 0; haystack[i + j] == needle[j]; ++j)
      ;
    if (!needle[j])
      return (wchar_t *)haystack + i;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<av_clip_int16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x8000,%eax
  mov    $0x0,%ax
  test   %eax,%eax
  je     L17
  mov    -0x4(%rbp),%eax
  sar    $0x1f,%eax
  xor    $0x7fff,%eax
  jmp    L3
L17:
  mov    -0x4(%rbp),%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int16_t av_clip_int16(int a) {
  if ((a + 32768) & ~65535)
    return (a >> 31) ^ 32767;
  else
    return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<av_clip_int16>:
  endbr64
  mov    %edi,%eax
  lea    0x8000(%rdi),%ecx
  cltd
  xor    $0x7fff,%edx
  test   $0xffff0000,%ecx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int16_t av_clip_int16(int a) {
  if ((a + 32768) & ~65535)
    return (a >> 31) ^ 32767;
  else
    return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<av_clip_int16>:
  endbr64
  mov    %edi,%eax
  lea    0x8000(%rdi),%ecx
  cltd
  xor    $0x7fff,%edx
  and    $0xffff0000,%ecx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int16_t av_clip_int16(int a) {
  if ((a + 32768) & ~65535)
    return (a >> 31) ^ 32767;
  else
    return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<av_clip_int16>:
  endbr64
  mov    %edi,%eax
  lea    0x8000(%rdi),%ecx
  cltd
  xor    $0x7fff,%edx
  and    $0xffff0000,%ecx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int16_t av_clip_int16(int a) {
  if ((a + 32768) & ~65535)
    return (a >> 31) ^ 32767;
  else
    return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x20,-0x28(%rbp)
  movl   $0x10,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <encrypt@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decrypt@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string

tool: D8: %08X%08X


assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t v[2] = {0x20, 0x10}, k[4] = {0x04, 0x03, 0x02, 0x01};
  printf("%08X%08X\n", v[0], v[1]);
  encrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  decrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x20,0x8(%rsp)
  movl   $0x10,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  mov    $0x10,%edx
  mov    $0x20,%esi
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <encrypt@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <decrypt@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: %08X%08X


assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t v[2] = {0x20, 0x10}, k[4] = {0x04, 0x03, 0x02, 0x01};
  printf("%08X%08X\n", v[0], v[1]);
  encrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  decrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x10,%edx
  mov    $0x20,%esi
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x1000000020,%rax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  mov    %rax,0x8(%rsp)
  movabs $0x300000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x18(%rsp)
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <encrypt@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <decrypt@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: %08X%08X


assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t v[2] = {0x20, 0x10}, k[4] = {0x04, 0x03, 0x02, 0x01};
  printf("%08X%08X\n", v[0], v[1]);
  encrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  decrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x10,%edx
  mov    $0x20,%esi
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  movdqa D28(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x10(%rsp),%r13
  lea    0x8(%rsp),%r12
  movaps %xmm0,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <encrypt@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <decrypt@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D28
type_guessed: byte[16]
name: extract_symbolic_data
arguments: tag: D5
type_guessed: byte[8]

tool: D1: %08X%08X


tool: {"D28": [0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D5": [0x20,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  uint32_t v[2] = {0x20, 0x10}, k[4] = {0x04, 0x03, 0x02, 0x01};
  printf("%08X%08X\n", v[0], v[1]);
  encrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  decrypt(v, k);
  printf("%08X%08X\n", v[0], v[1]);
  return 0;
}
```