ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  lea    D26(%rip),%r15
  push   %r14
  lea    D17(%rip),%r14
  push   %r13
  lea    D42(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movl   $0xa,0xc(%rsp)
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %rbp,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  movl   $0x14,0xc(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  lea    D41(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D42
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D36
datatype: string
name: retrieve_data
arguments: data_label: D41
datatype: string

tool: D26: &a: %p



tool: D17: p: %p


tool: D42: *p: %d


tool: D29: a: %d


tool: D36: &p: %p



tool: D41: &p: %p


assistant: ```c
int main() {
  int a, *p;
  a = 10;
  printf("a: %d\n", a);
  printf("&a: %p\n\n", &a);
  p = &a;
  printf("p: %p\n", p);
  printf("*p: %d\n", *p);
  printf("&p: %p\n\n", &p);
  a = 20;
  printf("a: %d\n", a);
  printf("&a: %p\n\n", &a);
  printf("p: %p\n", p);
  printf("*p: %d\n", *p);
  printf("&p: %p\n", &p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xa,%esi
  lea    D36(%rip),%r15
  push   %r14
  lea    D33(%rip),%r14
  push   %r13
  lea    D30(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D44(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movl   $0xa,0xc(%rsp)
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %rbp,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  movl   $0x14,0xc(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %r12,%rsi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D33
datatype: string
name: disassemble_data
arguments: label: D30
datatype: string
name: disassemble_data
arguments: label: D44
datatype: string
name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string

tool: D36: &a: %p



tool: D33: p: %p


tool: D30: *p: %d


tool: D44: a: %d


tool: D8: &p: %p



tool: D23: &p: %p


assistant: ```c
int main() {
  int a, *p;
  a = 10;
  printf("a: %d\n", a);
  printf("&a: %p\n\n", &a);
  p = &a;
  printf("p: %p\n", p);
  printf("*p: %d\n", *p);
  printf("&p: %p\n\n", &p);
  a = 20;
  printf("a: %d\n", a);
  printf("&a: %p\n\n", &a);
  printf("p: %p\n", p);
  printf("*p: %d\n", *p);
  printf("&p: %p\n", &p);
}
```
user: What is the c source code of the assembly code below:

```asm
<candidates>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movslq %esi,%r12
  imul   $0x38e38e39,%r12,%r12
  sar    $0x21,%r12
  mov    %esi,%eax
  sar    $0x1f,%eax
  sub    %eax,%r12d
  mov    %r12d,%r13d
  lea    (%r12,%r12,8),%eax
  mov    %esi,%r12d
  sub    %eax,%r12d
  movslq %r12d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r12d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  mov    %eax,0xc(%rsp)
  movslq %r13d,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %r13d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r14d
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  mov    $0x0,%ebx
L54:
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <getAt@plt>
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <getAt@plt>
  addl   $0x1,0x10(%rsp,%rax,4)
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%r14,1),%edx
  lea    (%rax,%rax,2),%eax
  mov    %ebx,%esi
  sub    %eax,%esi
  add    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <getAt@plt>
  addl   $0x1,0x10(%rsp,%rax,4)
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L54
  mov    $0x1,%eax
  mov    $0x0,%esi
  jmp    L27
L38:
  add    $0x1,%rax
  cmp    $0xa,%rax
  je     L58
L27:
  mov    0x10(%rsp,%rax,4),%edx
  test   %edx,%edx
  jne    L38
  test   %esi,%esi
  jg     L56
  mov    %eax,%esi
  jmp    L38
L58:
  movslq %r15d,%r15
  mov    %esi,0x0(%rbp,%r15,4)
  test   %esi,%esi
  setg   %dl
  movzbl %dl,%edx
L56:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %edx,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int candidates(int *grid, int index) {
  int boxN = 9 / 3;
  int x = index % 9;
  int y = index / 9;
  int boxX = x - (x % boxN);
  int boxY = y - (y % boxN);
  int i;
  int counts[9 + 1] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int candidate = 0;
  for (i = 0; i < 9; i++) {
    counts[getAt(grid, i, y)]++;
    counts[getAt(grid, x, i)]++;
    counts[getAt(grid, boxX + (int)(i % boxN), boxY + (int)(i / boxN))]++;
  }
  for (i = 1; i <= 9; i++) {
    if (*(counts + i) == 0) {
      if (candidate > 0) {
        return 0;
      }
      candidate = i;
    }
  }
  grid[index] = candidate;
  return candidate > 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<candidates>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  movaps %xmm0,0x10(%rsp)
  imul   $0x38e38e39,%rax,%rbp
  mov    %rax,0x8(%rsp)
  mov    %esi,%eax
  sar    $0x1f,%eax
  movaps %xmm0,0x20(%rsp)
  movq   $0x0,0x30(%rsp)
  sar    $0x21,%rbp
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,8),%eax
  mov    %ebp,%r12d
  sub    %eax,%esi
  movslq %esi,%rax
  mov    %rax,%rbp
  imul   $0x55555556,%rax,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  shr    $0x20,%rax
  sub    %edx,%eax
  mov    %r12d,%edx
  lea    (%rax,%rax,2),%r14d
  movslq %r12d,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%r13d
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %r15d,%esi
  mov    %r12d,%edx
  mov    %rbx,%rdi
  call   <getAt@plt>
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  addl   $0x1,0x10(%rsp,%rax,4)
  call   <getAt@plt>
  mov    $0xaaaaaaab,%ecx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  addl   $0x1,0x10(%rsp,%rax,4)
  mov    %r15d,%eax
  add    $0x1,%r15d
  imul   %rcx,%rax
  shr    $0x21,%rax
  lea    (%rax,%r13,1),%edx
  lea    (%rax,%rax,2),%eax
  sub    %eax,%esi
  add    %r14d,%esi
  call   <getAt@plt>
  addl   $0x1,0x10(%rsp,%rax,4)
  cmp    $0x9,%r15d
  jne    L35
  mov    $0x1,%eax
  xor    %edx,%edx
  lea    0x10(%rsp),%rcx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rcx,%rax,4),%r8d
  test   %r8d,%r8d
  jne    L0
  test   %edx,%edx
  jne    L25
  mov    %eax,%edx
L0:
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L13
  mov    0x8(%rsp),%rax
  xor    %r8d,%r8d
  test   %edx,%edx
  setg   %r8b
  mov    %edx,(%rbx,%rax,4)
L25:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x48,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int candidates(int *grid, int index) {
  int boxN = 9 / 3;
  int x = index % 9;
  int y = index / 9;
  int boxX = x - (x % boxN);
  int boxY = y - (y % boxN);
  int i;
  int counts[9 + 1] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
  int candidate = 0;
  for (i = 0; i < 9; i++) {
    counts[getAt(grid, i, y)]++;
    counts[getAt(grid, x, i)]++;
    counts[getAt(grid, boxX + (int)(i % boxN), boxY + (int)(i / boxN))]++;
  }
  for (i = 1; i <= 9; i++) {
    if (*(counts + i) == 0) {
      if (candidate > 0) {
        return 0;
      }
      candidate = i;
    }
  }
  grid[index] = candidate;
  return candidate > 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gencoef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    D21(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D19(%rip)
  test   %eax,%eax
  jne    L18
  mov    $0x0,%eax
  call   <dct_coef_addr@plt>
  mov    %rax,-0x18(%rbp)
  movsd  D19(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x10,-0x24(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L12
L4:
  movl   $0x0,-0x28(%rbp)
  jmp    L42
L13:
  mov    -0x24(%rbp),%eax
  shl    $0x2,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  D13(%rip),%xmm1
  divsd  %xmm0,%xmm1
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x28(%rbp)
  addl   $0x1,-0x1c(%rbp)
L42:
  mov    -0x28(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  addl   $0x1,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x24(%rbp)
L12:
  cmpl   $0x4,-0x20(%rbp)
  jle    L4
L18:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D19
datatype: byte[8]
name: read_data
arguments: tag: D13
datatype: f64

tool: {"D19": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x09,0x40]}

tool: D13: 0.5

assistant: ```c
void gencoef() {
  static int iOnceOnly = 0;
  int p, n, i, k;
  double t, pi;
  float *coef32;
  if (!iOnceOnly++) {
    coef32 = dct_coef_addr();
    pi = 4.0 * atan(1.0);
    n = 16;
    k = 0;
    for (i = 0; i < 5; i++, n = n / 2) {
      for (p = 0; p < n; p++, k++) {
        t = (pi / (4 * n)) * (2 * p + 1);
        coef32[k] = (float)(0.50 / cos(t));
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<gencoef>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D15(%rip),%r14d
  lea    0x1(%r14),%eax
  mov    %eax,D22(%rip)
  test   %r14d,%r14d
  je     L33
L36:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  mov    $0x0,%eax
  call   <dct_coef_addr@plt>
  mov    %rax,0x18(%rsp)
  mov    $0x5,%r15d
  mov    $0x10,%r13d
L32:
  test   %r13d,%r13d
  jle    L7
  lea    0x0(,%r13,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D22(%rip),%xmm3
  divsd  %xmm0,%xmm3
  movsd  %xmm3,0x8(%rsp)
  movslq %r14d,%rax
  mov    0x18(%rsp),%rdx
  lea    (%rdx,%rax,4),%rbp
  mov    %r13d,0x14(%rsp)
  lea    0x1(%r13,%r13,1),%r12d
  mov    $0x1,%ebx
L39:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  0x8(%rsp),%xmm0
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  D6(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x0(%rbp)
  add    $0x2,%ebx
  add    $0x4,%rbp
  cmp    %r12d,%ebx
  jne    L39
  add    0x14(%rsp),%r14d
L7:
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    %r13d,%eax
  sar    %eax
  mov    %eax,%r13d
  sub    $0x1,%r15d
  jne    L32
  jmp    L36
```

tool_calls: name: read_data
arguments: label: D22
type_infered: byte[8]
name: read_data
arguments: label: D6
type_infered: f64

tool: {"D22": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x09,0x40]}

tool: D6: 0.5

assistant: ```c
void gencoef() {
  static int iOnceOnly = 0;
  int p, n, i, k;
  double t, pi;
  float *coef32;
  if (!iOnceOnly++) {
    coef32 = dct_coef_addr();
    pi = 4.0 * atan(1.0);
    n = 16;
    k = 0;
    for (i = 0; i < 5; i++, n = n / 2) {
      for (p = 0; p < n; p++, k++) {
        t = (pi / (4 * n)) * (2 * p + 1);
        coef32[k] = (float)(0.50 / cos(t));
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gencoef>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D8(%rip),%r13d
  lea    0x1(%r13),%eax
  mov    %eax,D34(%rip)
  test   %r13d,%r13d
  je     L19
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  mov    $0x5,%r14d
  mov    $0x10,%r12d
  call   <dct_coef_addr@plt>
  mov    %rax,0x8(%rsp)
L14:
  test   %r12d,%r12d
  jle    L20
  pxor   %xmm0,%xmm0
  mov    0x8(%rsp),%rdx
  lea    0x1(%r12,%r12,1),%ebp
  lea    0x0(,%r12,4),%eax
  cvtsi2sd %eax,%xmm0
  movsd  D34(%rip),%xmm3
  movslq %r13d,%rax
  mov    $0x1,%ebx
  lea    (%rdx,%rax,4),%r15
  divsd  %xmm0,%xmm3
  movsd  %xmm3,(%rsp)
  nopl   0x0(%rax)
L3:
  pxor   %xmm0,%xmm0
  add    $0x4,%r15
  cvtsi2sd %ebx,%xmm0
  mulsd  (%rsp),%xmm0
  add    $0x2,%ebx
  call   <cos@plt>
  movapd %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%r15)
  cmp    %ebp,%ebx
  jne    L3
  add    %r12d,%r13d
L20:
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  mov    %eax,%r12d
  sub    $0x1,%r14d
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D34
type_infered: byte[8]
name: unpack_data
arguments: data_label: D15
type_infered: f64

tool: {"D34": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x09,0x40]}

tool: D15: 0.5

assistant: ```c
void gencoef() {
  static int iOnceOnly = 0;
  int p, n, i, k;
  double t, pi;
  float *coef32;
  if (!iOnceOnly++) {
    coef32 = dct_coef_addr();
    pi = 4.0 * atan(1.0);
    n = 16;
    k = 0;
    for (i = 0; i < 5; i++, n = n / 2) {
      for (p = 0; p < n; p++, k++) {
        t = (pi / (4 * n)) * (2 * p + 1);
        coef32[k] = (float)(0.50 / cos(t));
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bitmap_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <__builtin_constant_p@plt>
  test   %rax,%rax
  je     L2
  cmpl   $0x40,-0x24(%rbp)
  jg     L2
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L12
L2:
  mov    -0x24(%rbp),%eax
  cltq
  add    $0x3f,%rax
  shr    $0x6,%rax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
L12:
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %edx,%edi
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%ebx
  jg     L0
  test   %rax,%rax
  je     L0
  mov    (%r12),%rax
  mov    %rax,0x0(%rbp)
  jmp    L3
L0:
  movslq %ebx,%rdx
  add    $0x3f,%rdx
  shr    $0x6,%rdx
  shl    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmap_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%ebx
  jg     L8
  test   %rax,%rax
  je     L8
  mov    (%r12),%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L8:
  movslq %ebx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  add    $0x3f,%rdx
  pop    %rbp
  pop    %r12
  shr    $0x6,%rdx
  shl    $0x3,%edx
  jmp    1060 <memcpy@plt>
```

assistant: ```c
__attribute__((always_)) void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitmap_copy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  mov    %edx,%ebx
  call   <__builtin_constant_p@plt>
  cmp    $0x40,%ebx
  jg     L2
  test   %rax,%rax
  je     L2
  mov    (%r12),%rax
  pop    %rbx
  mov    %rax,0x0(%rbp)
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  movslq %ebx,%rdx
  mov    %r12,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  add    $0x3f,%rdx
  pop    %rbp
  pop    %r12
  shr    $0x6,%rdx
  shl    $0x3,%edx
  jmp    1060 <memcpy@plt>
```

assistant: ```c
__attribute__((always_)) void bitmap_copy(unsigned long *dst, const unsigned long *src, int nbits) {
  if ((__builtin_constant_p(nbits) && (nbits) <= 64))
    *dst = *src;
  else {
    int len = (((nbits) + (8 * sizeof(long)) - 1) / (8 * sizeof(long))) * sizeof(unsigned long);
    memcpy(dst, src, len);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<qh_minabsval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L51:
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L34
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L27
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L27:
  addq   $0x8,-0x8(%rbp)
L39:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L51
  movsd  -0x18(%rbp),%xmm0
  movq   D9(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L58
  movsd  -0x18(%rbp),%xmm0
  movq   D9(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  jmp    L28
L58:
  movsd  -0x10(%rbp),%xmm0
L28:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: f32[2]

tool: {"D9": [0.0,-0.0]}

assistant: ```c
double qh_minabsval(double *normal, int dim) {
  double minval = 0;
  double maxval = 0;
  double *colp;
  int k;
  for (k = dim, colp = normal; k--; colp++) {
    {
      if ((maxval) < (*colp))
        (maxval) = (*colp);
    };
    {
      if ((minval) > (*colp))
        (minval) = (*colp);
    };
  }
  return ((maxval) < (-minval) ? (-minval) : (maxval));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qh_minabsval>:
  endbr64
  test   %esi,%esi
  je     L7
  mov    %esi,%esi
  lea    (%rdi,%rsi,8),%rax
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm2
L20:
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm3
  maxsd  %xmm1,%xmm3
  movapd %xmm3,%xmm1
  minsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L20
  xorpd  D3(%rip),%xmm2
  maxsd  %xmm3,%xmm2
  movapd %xmm2,%xmm1
L23:
  movapd %xmm1,%xmm0
  ret
L7:
  pxor   %xmm1,%xmm1
  jmp    L23
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: f32[4]

tool: {"D3": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double qh_minabsval(double *normal, int dim) {
  double minval = 0;
  double maxval = 0;
  double *colp;
  int k;
  for (k = dim, colp = normal; k--; colp++) {
    {
      if ((maxval) < (*colp))
        (maxval) = (*colp);
    };
    {
      if ((minval) > (*colp))
        (minval) = (*colp);
    };
  }
  return ((maxval) < (-minval) ? (-minval) : (maxval));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<qh_minabsval>:
  endbr64
  test   %esi,%esi
  je     L10
  mov    %esi,%esi
  pxor   %xmm1,%xmm1
  lea    (%rdi,%rsi,8),%rax
  movapd %xmm1,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L3:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  movapd %xmm0,%xmm3
  minsd  %xmm2,%xmm0
  maxsd  %xmm1,%xmm3
  movapd %xmm0,%xmm2
  movapd %xmm3,%xmm1
  cmp    %rdi,%rax
  jne    L3
  xorpd  D9(%rip),%xmm2
  maxsd  %xmm3,%xmm2
  movapd %xmm2,%xmm1
  movapd %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: f32[4]

tool: {"D9": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double qh_minabsval(double *normal, int dim) {
  double minval = 0;
  double maxval = 0;
  double *colp;
  int k;
  for (k = dim, colp = normal; k--; colp++) {
    {
      if ((maxval) < (*colp))
        (maxval) = (*colp);
    };
    {
      if ((minval) > (*colp))
        (minval) = (*colp);
    };
  }
  return ((maxval) < (-minval) ? (-minval) : (maxval));
}
```