ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<random_decreasing>:
  endbr64
  test   %esi,%esi
  jle    L11
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  movslq %esi,%rbx
  mov    $0x0,%ebp
L14:
  mov    $0x0,%eax
  call   <random@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%ebp
  mov    %ebp,-0x4(%r12,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  ret
```

assistant: ```c
void random_decreasing(uint32_t *a, uint32_t n) {
  uint32_t x;
  x = 0;
  while (n > 0) {
    n--;
    x += ((uint32_t)random()) % 4;
    a[n] = x;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<random_decreasing>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L7:
  xor    %eax,%eax
  call   <random@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%r12d
  mov    %r12d,-0x4(%rbx,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L1:
  ret
```

assistant: ```c
void random_decreasing(uint32_t *a, uint32_t n) {
  uint32_t x;
  x = 0;
  while (n > 0) {
    n--;
    x += ((uint32_t)random()) % 4;
    a[n] = x;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<random_decreasing>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L1:
  xor    %eax,%eax
  call   <random@plt>
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  add    %eax,%r12d
  mov    %r12d,-0x4(%rbx,%rbp,4)
  sub    $0x1,%rbp
  test   %ebp,%ebp
  jg     L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L9:
  ret
```

assistant: ```c
void random_decreasing(uint32_t *a, uint32_t n) {
  uint32_t x;
  x = 0;
  while (n > 0) {
    n--;
    x += ((uint32_t)random()) % 4;
    a[n] = x;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L5
L2:
  addq   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strip(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L17
L5:
  add    $0x1,%rbx
L17:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strip(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12
L5:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L0
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r12
L17:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strip(char *str) {
  while (isspace(*str))
    ++str;
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calc_csum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  jmp    L36
L17:
  mov    -0x18(%rbp),%rax
  movzwl %ax,%edx
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  test   %rax,%rax
  jne    L17
  mov    -0x18(%rbp),%rax
  not    %rax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t calc_csum(unsigned long sum, const uint16_t *data, int num_words) {
  int i;
  for (i = 0; i < num_words; i++)
    sum += data[i];
  while (sum >> 16)
    sum = (sum & 0xffff) + (sum >> 16);
  return ~sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calc_csum>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L23
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
L26:
  add    (%rcx),%rax
  add    $0x8,%rcx
  cmp    %rdx,%rcx
  jne    L26
L23:
  mov    %rax,%rdx
  shr    $0x10,%rdx
  je     L37
L39:
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  jne    L39
L37:
  not    %rax
  ret
```

assistant: ```c
uint16_t calc_csum(unsigned long sum, const uint16_t *data, int num_words) {
  int i;
  for (i = 0; i < num_words; i++)
    sum += data[i];
  while (sum >> 16)
    sum = (sum & 0xffff) + (sum >> 16);
  return ~sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc_csum>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L18
  sub    $0x1,%edx
  lea    0x8(%rsi,%rdx,8),%rdx
  nopl   0x0(%rax,%rax,1)
L27:
  add    (%rsi),%rax
  add    $0x8,%rsi
  cmp    %rdx,%rsi
  jne    L27
  mov    %rax,%rdx
  shr    $0x10,%rdx
  je     L14
  nopl   (%rax)
L6:
  movzwl %ax,%eax
  add    %rdx,%rax
L18:
  mov    %rax,%rdx
  shr    $0x10,%rdx
  jne    L6
L14:
  not    %rax
  ret
```

assistant: ```c
uint16_t calc_csum(unsigned long sum, const uint16_t *data, int num_words) {
  int i;
  for (i = 0; i < num_words; i++)
    sum += data[i];
  while (sum >> 16)
    sum = (sum & 0xffff) + (sum >> 16);
  return ~sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calc_csum>:
  endbr64
  mov    %rdi,%rax
  mov    %edx,%edi
  test   %edx,%edx
  jle    L21
  cmp    $0x1,%edx
  je     L11
  shr    %edx
  mov    %rsi,%rcx
  pxor   %xmm0,%xmm0
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L30:
  movdqu (%rcx),%xmm2
  add    $0x10,%rcx
  paddq  %xmm2,%xmm0
  cmp    %rcx,%rdx
  jne    L30
  movdqa %xmm0,%xmm1
  mov    %edi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffe,%edx
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rcx
  add    %rcx,%rax
  and    $0x1,%edi
  je     L21
L26:
  movslq %edx,%rdx
  add    (%rsi,%rdx,8),%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  je     L59
L58:
  movzwl %ax,%eax
  add    %rdx,%rax
L21:
  mov    %rax,%rdx
  shr    $0x10,%rdx
  jne    L58
L59:
  not    %rax
  ret
L11:
  xor    %edx,%edx
  jmp    L26
```

assistant: ```c
uint16_t calc_csum(unsigned long sum, const uint16_t *data, int num_words) {
  int i;
  for (i = 0; i < num_words; i++)
    sum += data[i];
  while (sum >> 16)
    sum = (sum & 0xffff) + (sum >> 16);
  return ~sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <SetupWall@plt>
  jmp    L19
L6:
  mov    $0x0,%eax
  call   <PrintSpace@plt>
  mov    $0x0,%eax
  call   <PrintWall@plt>
  mov    $0x0,%eax
  call   <PrintBat@plt>
  mov    $0x0,%eax
  call   <PrintBall@plt>
  mov    $0x0,%eax
  call   <MoveBall@plt>
  mov    $0x0,%eax
  call   <MoveBat@plt>
  mov    $0x0,%eax
  call   <Draw@plt>
  mov    $0x0,%eax
  call   <SlowDown@plt>
L19:
  mov    $0x0,%eax
  call   <Ended@plt>
  test   %eax,%eax
  je     L6
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  SetupWall();
  while (!Ended()) {
    PrintSpace();
    PrintWall();
    PrintBat();
    PrintBall();
    MoveBall();
    MoveBat();
    Draw();
    SlowDown();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SetupWall@plt>
  jmp    L10
L2:
  mov    $0x0,%eax
  call   <PrintSpace@plt>
  mov    $0x0,%eax
  call   <PrintWall@plt>
  mov    $0x0,%eax
  call   <PrintBat@plt>
  mov    $0x0,%eax
  call   <PrintBall@plt>
  mov    $0x0,%eax
  call   <MoveBall@plt>
  mov    $0x0,%eax
  call   <MoveBat@plt>
  mov    $0x0,%eax
  call   <Draw@plt>
  mov    $0x0,%eax
  call   <SlowDown@plt>
L10:
  mov    $0x0,%eax
  call   <Ended@plt>
  test   %eax,%eax
  je     L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  SetupWall();
  while (!Ended()) {
    PrintSpace();
    PrintWall();
    PrintBat();
    PrintBall();
    MoveBall();
    MoveBat();
    Draw();
    SlowDown();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SetupWall@plt>
  jmp    L9
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <PrintSpace@plt>
  xor    %eax,%eax
  call   <PrintWall@plt>
  xor    %eax,%eax
  call   <PrintBat@plt>
  xor    %eax,%eax
  call   <PrintBall@plt>
  xor    %eax,%eax
  call   <MoveBall@plt>
  xor    %eax,%eax
  call   <MoveBat@plt>
  xor    %eax,%eax
  call   <Draw@plt>
  xor    %eax,%eax
  call   <SlowDown@plt>
L9:
  xor    %eax,%eax
  call   <Ended@plt>
  test   %eax,%eax
  je     L0
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  SetupWall();
  while (!Ended()) {
    PrintSpace();
    PrintWall();
    PrintBat();
    PrintBall();
    MoveBall();
    MoveBat();
    Draw();
    SlowDown();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SetupWall@plt>
  jmp    L9
  nopl   0x0(%rax)
L12:
  xor    %eax,%eax
  call   <PrintSpace@plt>
  xor    %eax,%eax
  call   <PrintWall@plt>
  xor    %eax,%eax
  call   <PrintBat@plt>
  xor    %eax,%eax
  call   <PrintBall@plt>
  xor    %eax,%eax
  call   <MoveBall@plt>
  xor    %eax,%eax
  call   <MoveBat@plt>
  xor    %eax,%eax
  call   <Draw@plt>
  xor    %eax,%eax
  call   <SlowDown@plt>
L9:
  xor    %eax,%eax
  call   <Ended@plt>
  test   %eax,%eax
  je     L12
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  SetupWall();
  while (!Ended()) {
    PrintSpace();
    PrintWall();
    PrintBat();
    PrintBall();
    MoveBall();
    MoveBat();
    Draw();
    SlowDown();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_numbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L47
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L49
L30:
  mov    $0x0,%eax
  jmp    L24
L49:
  addq   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    $0x1,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int all_numbers(char *input) {
  for (; input[0] != 0; input++) {
    if (input[0] < '0' || input[0] > '9') {
      return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<all_numbers>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
L27:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L9
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L27
  mov    $0x1,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int all_numbers(char *input) {
  for (; input[0] != 0; input++) {
    if (input[0] < '0' || input[0] > '9') {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<all_numbers>:
  endbr64
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L18:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L15
  add    $0x1,%rdi
L14:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int all_numbers(char *input) {
  for (; input[0] != 0; input++) {
    if (input[0] < '0' || input[0] > '9') {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<all_numbers>:
  endbr64
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L14:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L17
  add    $0x1,%rdi
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L14
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int all_numbers(char *input) {
  for (; input[0] != 0; input++) {
    if (input[0] < '0' || input[0] > '9') {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writeI2C_asFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  movzbl -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x18(%rbp),%eax
  cmp    -0x1(%rbp),%al
  je     L14
  mov    $0xffffffff,%eax
  jmp    L15
L14:
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
int writeI2C_asFile(int i2c_fd, unsigned char writebuffer[], unsigned char bytes) {
  unsigned char bytesWritten = write(i2c_fd, writebuffer, bytes);
  if (bytes != bytesWritten)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<writeI2C_asFile>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  movzbl %dl,%edx
  call   <write@plt>
  cmp    %bl,%al
  setne  %al
  movzbl %al,%eax
  neg    %eax
  pop    %rbx
  ret
```

assistant: ```c
int writeI2C_asFile(int i2c_fd, unsigned char writebuffer[], unsigned char bytes) {
  unsigned char bytesWritten = write(i2c_fd, writebuffer, bytes);
  if (bytes != bytesWritten)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<writeI2C_asFile>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  movzbl %dl,%edx
  call   <write@plt>
  cmp    %bl,%al
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int writeI2C_asFile(int i2c_fd, unsigned char writebuffer[], unsigned char bytes) {
  unsigned char bytesWritten = write(i2c_fd, writebuffer, bytes);
  if (bytes != bytesWritten)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<writeI2C_asFile>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  movzbl %dl,%edx
  call   <write@plt>
  cmp    %bl,%al
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int writeI2C_asFile(int i2c_fd, unsigned char writebuffer[], unsigned char bytes) {
  unsigned char bytesWritten = write(i2c_fd, writebuffer, bytes);
  if (bytes != bytesWritten)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checkGCCAsmRValueOutput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %eax,-0x4(%rbp)
  mov    %eax,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void checkGCCAsmRValueOutput() {
  int arg;
  __asm__("" : "=r"((int)arg));
  __asm__("" : "=r"(arg));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkGCCAsmRValueOutput>:
  endbr64
  ret
```

assistant: ```c
void checkGCCAsmRValueOutput() {
  int arg;
  __asm__("" : "=r"((int)arg));
  __asm__("" : "=r"(arg));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checkGCCAsmRValueOutput>:
  endbr64
  ret
```

assistant: ```c
void checkGCCAsmRValueOutput() {
  int arg;
  __asm__("" : "=r"((int)arg));
  __asm__("" : "=r"(arg));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  jmp    L8
L9:
  lea    D20(%rip),%rax
L8:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <rt_kprintf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <rt_kprintf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string

tool: D20: NULL

tool: D4: %s = %s


tool: D5: 


assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; i++) {
    rt_kprintf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  rt_kprintf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<callback>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L9
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D24(%rip),%r15
  lea    D9(%rip),%r14
L10:
  mov    (%r12,%rbx,8),%rdx
  test   %rdx,%rdx
  cmove  %r15,%rdx
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <rt_kprintf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
L9:
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <rt_kprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D24
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D25
datatype: string

tool: D24: NULL

tool: D9: %s = %s


tool: D25: 


assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; i++) {
    rt_kprintf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  rt_kprintf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<callback>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L2
  mov    %rdx,%r12
  mov    %rcx,%r15
  movslq %esi,%rbp
  xor    %ebx,%ebx
  lea    D15(%rip),%r14
  lea    D1(%rip),%r13
  nop
L13:
  mov    (%r12,%rbx,8),%rdx
  mov    (%r15,%rbx,8),%rsi
  mov    %r14,%rdi
  test   %rdx,%rdx
  cmove  %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rt_kprintf@plt>
  cmp    %rbp,%rbx
  jne    L13
L2:
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <rt_kprintf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string

tool: D15: %s = %s


tool: D1: NULL

tool: D4: 


assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; i++) {
    rt_kprintf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  rt_kprintf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<callback>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L8
  mov    %rdx,%r12
  mov    %rcx,%r15
  movslq %esi,%rbp
  xor    %ebx,%ebx
  lea    D26(%rip),%r13
  lea    D5(%rip),%r14
  jmp    L25
  nopl   0x0(%rax)
L42:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rt_kprintf@plt>
  cmp    %rbp,%rbx
  je     L8
L25:
  mov    (%r12,%rbx,8),%rdx
  mov    (%r15,%rbx,8),%rsi
  test   %rdx,%rdx
  jne    L42
  mov    %r14,%rdx
  jmp    L42
  nopl   (%rax)
L8:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <rt_kprintf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D26
type_guessed: string
name: unpack_data
arguments: data_label: D5
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D26: %s = %s


tool: D5: NULL

tool: D2: 


assistant: ```c
int callback(void *NotUsed, int argc, char **argv, char **azColName) {
  int i;
  for (i = 0; i < argc; i++) {
    rt_kprintf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");
  }
  rt_kprintf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<NC_check_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L122
  mov    $0xffffffc5,%eax
  jmp    L117
L59:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L11
  cmpl   $0x5f,-0xc(%rbp)
  je     L11
  cmpl   $0x2d,-0xc(%rbp)
  je     L11
  cmpl   $0x2b,-0xc(%rbp)
  je     L11
  cmpl   $0x2e,-0xc(%rbp)
  je     L11
  cmpl   $0x3a,-0xc(%rbp)
  je     L11
  cmpl   $0x40,-0xc(%rbp)
  je     L11
  cmpl   $0x28,-0xc(%rbp)
  je     L11
  cmpl   $0x29,-0xc(%rbp)
  je     L11
  mov    $0xffffffc5,%eax
  jmp    L117
L11:
  addq   $0x1,-0x8(%rbp)
L122:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  cmp    $0x100,%rax
  jle    L29
  mov    $0xffffffcb,%eax
  jmp    L117
L29:
  mov    $0x0,%eax
L117:
  leave
  ret
```

assistant: ```c
int NC_check_name(const char *name) {
  const char *cp = name;
  assert(name != NULL);
  if (*name == 0)
    return (-59);
  for (; *cp != 0; cp++) {
    int ch = *cp;
    if (!isalnum(ch)) {
      if (ch != '_' && ch != '-' && ch != '+' && ch != '.' && ch != ':' && ch != '@' && ch != '(' && ch != ')')
        return (-59);
    }
  }
  if (cp - name > 256)
    return (-53);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<NC_check_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%r12),%ebx
  test   %bl,%bl
  je     L82
  mov    %r12,%rbp
  movabs $0x8000000104006b,%r13
  jmp    L19
L74:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%ebx
  test   %bl,%bl
  je     L25
L19:
  movsbl %bl,%edi
  call   <isalnum@plt>
  test   %eax,%eax
  jne    L74
  sub    $0x28,%ebx
  cmp    $0x37,%bl
  ja     L89
  bt     %rbx,%r13
  jb     L74
  mov    $0xffffffc5,%eax
  jmp    L67
L25:
  sub    %r12,%rbp
  cmp    $0x101,%rbp
  mov    $0x0,%eax
  mov    $0xffffffcb,%edx
  cmovge %edx,%eax
L67:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L82:
  mov    $0xffffffc5,%eax
  jmp    L67
L89:
  mov    $0xffffffc5,%eax
  jmp    L67
```

assistant: ```c
int NC_check_name(const char *name) {
  const char *cp = name;
  assert(name != NULL);
  if (*name == 0)
    return (-59);
  for (; *cp != 0; cp++) {
    int ch = *cp;
    if (!isalnum(ch)) {
      if (ch != '_' && ch != '-' && ch != '+' && ch != '.' && ch != ':' && ch != '@' && ch != '(' && ch != ')')
        return (-59);
    }
  }
  if (cp - name > 256)
    return (-53);
  return 0;
}
```