ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <Bar6@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: main: res = %d


assistant: ```c
int main() {
  int res;
  res = Bar6(1, 2);
  printf("main: res = %d\n", res);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <Bar6@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string

tool: D6: main: res = %d


assistant: ```c
int main() {
  int res;
  res = Bar6(1, 2);
  printf("main: res = %d\n", res);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<output_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <output_with_tab@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  nop
  leave
  ret
```

assistant: ```c
void output_line(char ptr[]) {
  output_with_tab(ptr);
  newline();
}
```
user: Translate the below assembly code into C programming language:

```asm
<output_line>:
  endbr64
  sub    $0x8,%rsp
  call   <output_with_tab@plt>
  mov    $0x0,%eax
  call   <newline@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void output_line(char ptr[]) {
  output_with_tab(ptr);
  newline();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_line>:
  endbr64
  sub    $0x8,%rsp
  call   <output_with_tab@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <newline@plt>
```

assistant: ```c
void output_line(char ptr[]) {
  output_with_tab(ptr);
  newline();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<output_line>:
  endbr64
  sub    $0x8,%rsp
  call   <output_with_tab@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <newline@plt>
```

assistant: ```c
void output_line(char ptr[]) {
  output_with_tab(ptr);
  newline();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_eight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <print_check@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <back_square@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rdi
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <hrt@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type_guessed: f64
name: parse_data
arguments: label: D18
type_guessed: string

tool: D19: 0.5

tool: D18: 8

assistant: ```c
void print_eight(double x, double y) {
  print_check(x, y + 0.5);
  back_square(x, y);
  hrt(x, y, "8");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_eight>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbx
  movq   %xmm1,%rbp
  addsd  D19(%rip),%xmm1
  call   <print_check@plt>
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <back_square@plt>
  lea    D4(%rip),%rdi
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <hrt@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: f64
name: disassemble_data
arguments: tag: D4
data_type: string

tool: D19: 0.5

tool: D4: 8

assistant: ```c
void print_eight(double x, double y) {
  print_check(x, y + 0.5);
  back_square(x, y);
  hrt(x, y, "8");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_eight>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  addsd  D10(%rip),%xmm1
  movsd  %xmm0,(%rsp)
  call   <print_check@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm0
  movapd %xmm2,%xmm1
  call   <back_square@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  lea    D18(%rip),%rdi
  movapd %xmm2,%xmm1
  jmp    1080 <hrt@plt>
```

tool_calls: name: read_data
arguments: tag: D10
datatype: f64
name: read_data
arguments: tag: D18
datatype: string

tool: D10: 0.5

tool: D18: 8

assistant: ```c
void print_eight(double x, double y) {
  print_check(x, y + 0.5);
  back_square(x, y);
  hrt(x, y, "8");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_eight>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm1,0x8(%rsp)
  addsd  D6(%rip),%xmm1
  movsd  %xmm0,(%rsp)
  call   <print_check@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm0
  movapd %xmm2,%xmm1
  call   <back_square@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  lea    D9(%rip),%rdi
  movapd %xmm2,%xmm1
  jmp    1080 <hrt@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: f64
name: parse_data
arguments: data_tag: D9
type: string

tool: D6: 0.5

tool: D9: 8

assistant: ```c
void print_eight(double x, double y) {
  print_check(x, y + 0.5);
  back_square(x, y);
  hrt(x, y, "8");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_digit_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x41,%edi
  call   <char_to_digit@plt>
  cmp    $0xa,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x33,%edi
  call   <char_to_digit@plt>
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x23,%edi
  call   <digit_to_char@plt>
  cmp    $0x5a,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <digit_to_char@plt>
  cmp    $0x41,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_digit_char(void) {
  assert(char_to_digit('A') == 10);
  assert(char_to_digit('3') == 3);
  assert(digit_to_char(35) == 'Z');
  assert(digit_to_char(10) == 'A');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_digit_char>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <char_to_digit@plt>
  cmp    $0xa,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x33,%edi
  call   <char_to_digit@plt>
  cmp    $0x3,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x23,%edi
  call   <digit_to_char@plt>
  cmp    $0x5a,%al
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0xa,%edi
  call   <digit_to_char@plt>
  cmp    $0x41,%al
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_digit_char(void) {
  assert(char_to_digit('A') == 10);
  assert(char_to_digit('3') == 3);
  assert(digit_to_char(35) == 'Z');
  assert(digit_to_char(10) == 'A');
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_digit_char>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <char_to_digit@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x33,%edi
  call   <char_to_digit@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x23,%edi
  call   <digit_to_char@plt>
  xor    %edi,%edi
  cmp    $0x5a,%al
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <digit_to_char@plt>
  xor    %edi,%edi
  cmp    $0x41,%al
  sete   %dil
  add    $0x8,%rsp
  jmp    1080 <assert@plt>
```

assistant: ```c
void test_digit_char(void) {
  assert(char_to_digit('A') == 10);
  assert(char_to_digit('3') == 3);
  assert(digit_to_char(35) == 'Z');
  assert(digit_to_char(10) == 'A');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_digit_char>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x41,%edi
  call   <char_to_digit@plt>
  xor    %edi,%edi
  cmp    $0xa,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x33,%edi
  call   <char_to_digit@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    $0x23,%edi
  call   <digit_to_char@plt>
  xor    %edi,%edi
  cmp    $0x5a,%al
  sete   %dil
  call   <assert@plt>
  mov    $0xa,%edi
  call   <digit_to_char@plt>
  xor    %edi,%edi
  cmp    $0x41,%al
  sete   %dil
  add    $0x8,%rsp
  jmp    1080 <assert@plt>
```

assistant: ```c
void test_digit_char(void) {
  assert(char_to_digit('A') == 10);
  assert(char_to_digit('3') == 3);
  assert(digit_to_char(35) == 'Z');
  assert(digit_to_char(10) == 'A');
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ksprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    $0x200,%edi
  call   <oak_malloc@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ksprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  char *buf = oak_malloc(512);
  vsnprintf(buf, 512, fmt, args);
  va_end(args);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ksprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    $0x200,%edi
  call   <oak_malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ksprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  char *buf = oak_malloc(512);
  vsnprintf(buf, 512, fmt, args);
  va_end(args);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ksprintf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x200,%edi
  call   <oak_malloc@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ksprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  char *buf = oak_malloc(512);
  vsnprintf(buf, 512, fmt, args);
  va_end(args);
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<ksprintf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    $0x200,%edi
  call   <oak_malloc@plt>
  mov    %ebp,%ecx
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ksprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  char *buf = oak_malloc(512);
  vsnprintf(buf, 512, fmt, args);
  va_end(args);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_wait_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x20(%rbp)
  cmpl   $0x4,-0x20(%rbp)
  je     L22
  cmpl   $0x6,-0x20(%rbp)
  je     L22
  mov    $0xffffffff,%eax
  jmp    L21
L22:
  mov    -0x38(%rbp),%rcx
  lea    -0x11(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0xf(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x2(%rax),%rcx
  lea    -0xe(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0xc(%rbp)
  lea    -0x11(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  cmpl   $0x4,-0x20(%rbp)
  jle    L28
  mov    -0x38(%rbp),%rax
  lea    0x4(%rax),%rcx
  lea    -0xb(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x24(%rbp)
L28:
  cmpl   $0x0,-0x1c(%rbp)
  js     L50
  cmpl   $0x63,-0x1c(%rbp)
  jle    L130
L50:
  mov    $0xffffffff,%eax
  jmp    L21
L130:
  cmpl   $0x0,-0x18(%rbp)
  js     L46
  cmpl   $0x3b,-0x18(%rbp)
  jle    L74
L46:
  mov    $0xffffffff,%eax
  jmp    L21
L74:
  cmpl   $0x0,-0x24(%rbp)
  js     L36
  cmpl   $0x3b,-0x24(%rbp)
  jle    L75
L36:
  mov    $0xffffffff,%eax
  jmp    L21
L75:
  mov    $0x0,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L91
  call   <__stack_chk_fail@plt>
L91:
  leave
  ret
```

assistant: ```c
int check_wait_time(char *data) {
  int size, i_hour, i_min, i_sec;
  char hour[3], min[3], sec[3];
  size = strlen(data);
  if (size == 4 || size == 6) {
  } else {
    return -1;
  }
  strncpy(hour, data, 2);
  hour[2] = '\0';
  strncpy(min, (data + 2), 2);
  min[2] = '\0';
  i_hour = atoi(hour);
  i_min = atoi(min);
  i_sec = 0;
  if (size > 4) {
    strncpy(sec, (data + 4), 2);
    sec[2] = '\0';
    i_sec = atoi(sec);
  }
  if (i_hour < 0 || i_hour > 99) {
    return -1;
  }
  if (i_min < 0 || i_min > 59) {
    return -1;
  }
  if (i_sec < 0 || i_sec > 59) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check_wait_time>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebp
  and    $0xfffffffd,%eax
  cmp    $0x4,%eax
  jne    L57
  lea    0xf(%rsp),%r12
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x11(%rsp)
  lea    0x2(%rbx),%rsi
  lea    0x12(%rsp),%r13
  mov    $0x2,%edx
  mov    %r13,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x14(%rsp)
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  cmp    $0x4,%ebp
  jg     L80
L76:
  cmp    $0x63,%r12d
  ja     L66
  cmp    $0x3b,%r13d
  ja     L17
  cmp    $0x3b,%eax
  seta   %al
  movzbl %al,%eax
  neg    %eax
L75:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L84
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L80:
  lea    0x4(%rbx),%rsi
  lea    0x15(%rsp),%rbx
  mov    $0x2,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x17(%rsp)
  mov    %rbx,%rdi
  call   <atoi@plt>
  jmp    L76
L57:
  mov    $0xffffffff,%eax
  jmp    L75
L66:
  mov    $0xffffffff,%eax
  jmp    L75
L17:
  mov    $0xffffffff,%eax
  jmp    L75
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_wait_time(char *data) {
  int size, i_hour, i_min, i_sec;
  char hour[3], min[3], sec[3];
  size = strlen(data);
  if (size == 4 || size == 6) {
  } else {
    return -1;
  }
  strncpy(hour, data, 2);
  hour[2] = '\0';
  strncpy(min, (data + 2), 2);
  min[2] = '\0';
  i_hour = atoi(hour);
  i_min = atoi(min);
  i_sec = 0;
  if (size > 4) {
    strncpy(sec, (data + 4), 2);
    sec[2] = '\0';
    i_sec = atoi(sec);
  }
  if (i_hour < 0 || i_hour > 99) {
    return -1;
  }
  if (i_min < 0 || i_min > 59) {
    return -1;
  }
  if (i_sec < 0 || i_sec > 59) {
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_wait_time>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebp
  and    $0xfffffffd,%eax
  cmp    $0x4,%eax
  jne    L47
  lea    0xf(%rsp),%r12
  lea    0x12(%rsp),%r13
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  lea    0x2(%rbx),%rsi
  mov    $0x2,%edx
  mov    %r13,%rdi
  movb   $0x0,0x11(%rsp)
  call   <strncpy@plt>
  mov    %r12,%rdi
  movb   $0x0,0x14(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  cmp    $0x4,%ebp
  je     L53
  lea    0x15(%rsp),%rbp
  lea    0x4(%rbx),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  call   <atoi@plt>
L53:
  cmp    $0x63,%r12d
  ja     L47
  cmp    $0x3b,%r13d
  ja     L47
  cmp    $0x3b,%eax
  seta   %al
  movzbl %al,%eax
  neg    %eax
L14:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0xffffffff,%eax
  jmp    L14
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_wait_time(char *data) {
  int size, i_hour, i_min, i_sec;
  char hour[3], min[3], sec[3];
  size = strlen(data);
  if (size == 4 || size == 6) {
  } else {
    return -1;
  }
  strncpy(hour, data, 2);
  hour[2] = '\0';
  strncpy(min, (data + 2), 2);
  min[2] = '\0';
  i_hour = atoi(hour);
  i_min = atoi(min);
  i_sec = 0;
  if (size > 4) {
    strncpy(sec, (data + 4), 2);
    sec[2] = '\0';
    i_sec = atoi(sec);
  }
  if (i_hour < 0 || i_hour > 99) {
    return -1;
  }
  if (i_min < 0 || i_min > 59) {
    return -1;
  }
  if (i_sec < 0 || i_sec > 59) {
    return -1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_wait_time>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebp
  and    $0xfffffffd,%eax
  cmp    $0x4,%eax
  jne    L43
  lea    0xf(%rsp),%r12
  lea    0x12(%rsp),%r13
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  lea    0x2(%rbx),%rsi
  mov    $0x2,%edx
  mov    %r13,%rdi
  movb   $0x0,0x11(%rsp)
  call   <strncpy@plt>
  mov    %r12,%rdi
  movb   $0x0,0x14(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  cmp    $0x4,%ebp
  je     L31
  lea    0x15(%rsp),%rbp
  lea    0x4(%rbx),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdi
  movb   $0x0,0x17(%rsp)
  call   <atoi@plt>
L31:
  cmp    $0x63,%r12d
  ja     L43
  cmp    $0x3b,%r13d
  ja     L43
  cmp    $0x3b,%eax
  seta   %al
  movzbl %al,%eax
  neg    %eax
L23:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0xffffffff,%eax
  jmp    L23
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_wait_time(char *data) {
  int size, i_hour, i_min, i_sec;
  char hour[3], min[3], sec[3];
  size = strlen(data);
  if (size == 4 || size == 6) {
  } else {
    return -1;
  }
  strncpy(hour, data, 2);
  hour[2] = '\0';
  strncpy(min, (data + 2), 2);
  min[2] = '\0';
  i_hour = atoi(hour);
  i_min = atoi(min);
  i_sec = 0;
  if (size > 4) {
    strncpy(sec, (data + 4), 2);
    sec[2] = '\0';
    i_sec = atoi(sec);
  }
  if (i_hour < 0 || i_hour > 99) {
    return -1;
  }
  if (i_min < 0 || i_min > 59) {
    return -1;
  }
  if (i_sec < 0 || i_sec > 59) {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x8,-0x4(%rbp)
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%edi
  call   <srand@plt>
  cmpl   $0x2,-0x14(%rbp)
  je     L38
  cmpl   $0x3,-0x14(%rbp)
  jne    L4
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
L38:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
L4:
  movl   $0x1,-0xc(%rbp)
  jmp    L46
L35:
  movl   $0x1,-0x10(%rbp)
  jmp    L11
L2:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x21(%rdx),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L35
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c, l;
  int passwords = 1;
  int plength = 8;
  srand(clock());
  switch (argc) {
  case 3:
    passwords = atoi(argv[2]);
  case 2:
    plength = atoi(argv[1]);
  }
  for (l = 1; l <= passwords; l++) {
    for (c = 1; c <= plength; c++)
      printf("%c", (rand() % (126 - 32)) + 33);
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%edi
  call   <srand@plt>
  cmp    $0x2,%ebx
  je     L77
  cmp    $0x3,%ebx
  jne    L92
  mov    0x10(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
L83:
  mov    0x8(%rbp),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  test   %r13d,%r13d
  jle    L71
L37:
  mov    $0x1,%r12d
  jmp    L7
L77:
  mov    $0x1,%r13d
  jmp    L83
L70:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffffae4c415d,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x5e,%edx,%edx
  sub    %edx,%eax
  lea    0x21(%rax),%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L70
L68:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    %r13d,%r12d
  jg     L71
L7:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L70
  jmp    L68
L92:
  mov    $0x8,%ebp
  mov    $0x1,%r13d
  jmp    L37
L71:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int c, l;
  int passwords = 1;
  int plength = 8;
  srand(clock());
  switch (argc) {
  case 3:
    passwords = atoi(argv[2]);
  case 2:
    plength = atoi(argv[1]);
  }
  for (l = 1; l <= passwords; l++) {
    for (c = 1; c <= plength; c++)
      printf("%c", (rand() % (126 - 32)) + 33);
    printf("\n");
  }
  return 0;
}
```