user: 这段汇编代码用C语言表示是什么样的：

```asm
<fmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L21
L11:
  addl   $0x1,-0x10(%rbp)
  cmpl   $0x2,-0x10(%rbp)
  jle    L85
  mov    -0x10(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
L85:
  cmpl   $0x3,-0x10(%rbp)
  jne    L29
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x3(%rdx),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x2(%rdx),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2e,(%rax)
  addl   $0x1,-0x8(%rbp)
L29:
  cmpl   $0x0,-0xc(%rbp)
  je     L45
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L45
  cmpl   $0x0,-0x14(%rbp)
  je     L45
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2c,(%rax)
  addl   $0x1,-0x8(%rbp)
L45:
  subl   $0x1,-0x14(%rbp)
L21:
  cmpl   $0x0,-0x14(%rbp)
  jns    L11
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x1,-0x4(%rbp)
  jne    L66
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L66:
  cmpl   $0x2,-0x4(%rbp)
  jne    L59
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
L59:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string
name: retrieve_data
arguments: label: D15
datatype: string

tool: D8: 0.0%c

tool: D15: 0.%c%c

assistant: ```c
void fmt(char *dst, char const *src) {
  int l = strlen(src);
  int i, j = 0, k = 0, n = 0;
  strncpy(dst, src, l);
  for (i = l - 1; i >= 0; i--) {
    j++;
    if (j > 2)
      k = j - 2;
    if (j == 3) {
      dst[i + 3] = dst[i + 2];
      dst[i + 2] = dst[i + 1];
      dst[i + 1] = '.';
      n++;
    }
    if (k != 0 && k % 3 == 0 && i != 0) {
      memmove(&dst[i + 1], &dst[i], j + n);
      dst[i] = ',';
      n++;
    }
  }
  dst[l + n] = '\0';
  if (l == 1)
    sprintf(dst, "0.0%c", src[0]);
  if (l == 2)
    sprintf(dst, "0.%c%c", src[0], src[1]);
}
```