ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stbi_write_bmp>:
  endbr64
  mov    %esi,%r10d
  lea    0x0(,%rsi,4),%eax
  mov    %ecx,%r9d
  mov    %esi,%ecx
  and    $0x3,%esi
  sub    %eax,%ecx
  sub    $0x10,%rsp
  mov    %esi,%eax
  push   $0x0
  sub    %ecx,%eax
  push   $0x0
  mov    %r10d,%ecx
  imul   %edx,%eax
  push   $0x0
  push   $0x0
  push   $0x0
  add    $0x36,%eax
  push   $0x0
  push   $0x18
  push   $0x1
  push   %rdx
  push   %r10
  push   $0x28
  push   $0x36
  push   $0x0
  push   $0x0
  push   %rax
  lea    D6(%rip),%rax
  push   $0x4d
  push   $0x42
  push   %rax
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile@plt>
  add    $0xb8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: 11 4 22 44 44 22 444444

assistant: ```c
int stbi_write_bmp(char const *filename, int x, int y, int comp, void *data) {
  int pad = (-x * 3) & 3;
  return outfile(filename, -1, -1, x, y, comp, data, 0, pad,
                 (char *)"11 4 22 4"
                         "4 44 22 444444",
                 'B', 'M', 14 + 40 + (x * 3 + pad) * y, 0, 0, 14 + 40, 40, x, y, 1, 24, 0, 0, 0, 0, 0, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0xa,-0x14(%rbp)
  movl   $0x14,-0x10(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x1e,-0xc(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L30
L60:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  add    %eax,-0x2c(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%edx
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L30:
  mov    -0x28(%rbp),%eax
  cmp    $0x2,%eax
  jbe    L60
  movl   $0x0,-0x24(%rbp)
  jmp    L12
L4:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x24(%rbp)
L12:
  mov    -0x24(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L4
  movl   $0x0,-0x20(%rbp)
  jmp    L50
L11:
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0x1c(%rbp,%rax,4),%eax
  add    %eax,-0x2c(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0x1c(%rbp,%rax,4),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L50:
  mov    -0x20(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L11
  mov    -0x2c(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D45
type_guessed: string
name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D42
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string

tool: D45: arr[%d] = %d


tool: D28: 
Enter a integer: 

tool: D13: %d

tool: D42: b[%d] = %d


tool: D19: 
Total: %d


assistant: ```c
int main() {
  int arr[3] = {10, 20}, total = 0;
  arr[2] = 30;
  for (int i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
    total += arr[i];
    printf("arr[%d] = %d\n", i, arr[i]);
  }
  int b[2];
  for (int i = 0; i < sizeof(b) / sizeof(2); i++) {
    printf("\nEnter a integer: ");
    scanf("%d", &b[i]);
  }
  for (int i = 0; i < sizeof(b) / sizeof(b[0]); i++) {
    total += b[i];
    printf("b[%d] = %d\n", i, b[i]);
  }
  printf("\nTotal: %d\n", total);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xa,0xc(%rsp)
  movl   $0x14,0x10(%rsp)
  movl   $0x1e,0x14(%rsp)
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D38(%rip),%r12
L16:
  mov    0xc(%rsp,%rbx,4),%edx
  add    %edx,%ebp
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L16
  lea    D41(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  add    %edx,%ebp
  mov    $0x0,%esi
  lea    D26(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%ebx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D38
datatype: string
name: parse_data
arguments: data_label: D41
datatype: string
name: parse_data
arguments: data_label: D42
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string

tool: D38: arr[%d] = %d


tool: D41: 
Enter a integer: 

tool: D42: %d

tool: D26: b[%d] = %d


tool: D5: 
Total: %d


assistant: ```c
int main() {
  int arr[3] = {10, 20}, total = 0;
  arr[2] = 30;
  for (int i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
    total += arr[i];
    printf("arr[%d] = %d\n", i, arr[i]);
  }
  int b[2];
  for (int i = 0; i < sizeof(b) / sizeof(2); i++) {
    printf("\nEnter a integer: ");
    scanf("%d", &b[i]);
  }
  for (int i = 0; i < sizeof(b) / sizeof(b[0]); i++) {
    total += b[i];
    printf("b[%d] = %d\n", i, b[i]);
  }
  printf("\nTotal: %d\n", total);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%edx
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1e00000014,%rax
  mov    %rax,0x10(%rsp)
L12:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  add    %edx,%ebp
  call   <printf@plt>
  cmp    $0x3,%rbx
  je     L4
  mov    0xc(%rsp,%rbx,4),%edx
  jmp    L12
  nopl   0x0(%rax)
L4:
  lea    D2(%rip),%r13
  lea    D7(%rip),%r12
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  lea    0x8(%rsp),%rsi
  lea    D39(%rip),%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %edx,%ebp
  call   <printf@plt>
  mov    0x8(%rsp),%ebx
  mov    $0x1,%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    %ebx,%edx
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,1),%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_guessed: string
name: retrieve_data
arguments: data_label: D2
type_guessed: string
name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D46
type_guessed: string

tool: D21: arr[%d] = %d


tool: D2: 
Enter a integer: 

tool: D7: %d

tool: D39: b[%d] = %d


tool: D46: 
Total: %d


assistant: ```c
int main() {
  int arr[3] = {10, 20}, total = 0;
  arr[2] = 30;
  for (int i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
    total += arr[i];
    printf("arr[%d] = %d\n", i, arr[i]);
  }
  int b[2];
  for (int i = 0; i < sizeof(b) / sizeof(2); i++) {
    printf("\nEnter a integer: ");
    scanf("%d", &b[i]);
  }
  for (int i = 0; i < sizeof(b) / sizeof(b[0]); i++) {
    total += b[i];
    printf("b[%d] = %d\n", i, b[i]);
  }
  printf("\nTotal: %d\n", total);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D32(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  movl   $0x1e,0x10(%rsp)
  lea    0x8(%rsp),%r13
  mov    %rax,0x8(%rsp)
L5:
  mov    0x0(%r13,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  add    %edx,%ebp
  call   <printf@plt>
  cmp    $0x3,%rbx
  jne    L5
  lea    D8(%rip),%r13
  lea    D42(%rip),%r12
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%r12
  call   <scanf@plt>
  mov    (%rsp),%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %edx,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  mov    $0x1,%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  mov    %ebx,%edx
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,1),%esi
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D32
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: byte[8]
name: disassemble_data
arguments: tag: D8
datatype: string
name: disassemble_data
arguments: tag: D42
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D57
datatype: string

tool: D32: arr[%d] = %d


tool: {"D0": [0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: D8: 
Enter a integer: 

tool: D42: %d

tool: D16: b[%d] = %d


tool: D57: 
Total: %d


assistant: ```c
int main() {
  int arr[3] = {10, 20}, total = 0;
  arr[2] = 30;
  for (int i = 0; i < sizeof(arr) / sizeof(arr[0]); i++) {
    total += arr[i];
    printf("arr[%d] = %d\n", i, arr[i]);
  }
  int b[2];
  for (int i = 0; i < sizeof(b) / sizeof(2); i++) {
    printf("\nEnter a integer: ");
    scanf("%d", &b[i]);
  }
  for (int i = 0; i < sizeof(b) / sizeof(b[0]); i++) {
    total += b[i];
    printf("b[%d] = %d\n", i, b[i]);
  }
  printf("\nTotal: %d\n", total);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getkey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r14
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x54(%rbp)
  mov    %rcx,%rbx
  mov    %rcx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <BN_CTX_new@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <BN_num_bytes@plt>
  lea    -0x1(%rax),%r13d
  movslq %r13d,%r13
  mov    %r13,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    D9(%rip),%rax
  movslq (%rax),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L57:
  cmp    %rdx,%rsp
  je     L39
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L57
L39:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L0
  orq    $0x0,-0x8(%rsp,%rax,1)
L0:
  mov    %rsp,%r15
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    -0x54(%rbp),%esi
  mov    -0x50(%rbp),%rdi
  call   <fdh@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <BN_bin2bn@plt>
  jmp    L11
L50:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %r13,%rcx
  mov    %rbx,%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    %r15,%rdi
  call   <fdh@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <BN_bin2bn@plt>
L11:
  mov    %r12,%rdx
  mov    -0x48(%rbp),%rsi
  mov    %r14,%rdi
  call   <BN_kronecker@plt>
  cmp    $0x1,%eax
  jne    L50
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <BN_CTX_free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getkey(BIGNUM *a, const uint8_t *id, int len, const BIGNUM *N) {
  uint8_t *tmp;
  BN_CTX *ctx = BN_CTX_new();
  const size_t num_bytes = BN_num_bytes(N) - 1;
  uint8_t *buf = (uint8_t *)malloc(num_bytes);
  uint8_t hash[RIPEMD160_DIGEST_LENGTH];
  fdh(id, len, buf, num_bytes);
  BN_bin2bn(hash, num_bytes, a);
  while (BN_kronecker(a, N, ctx) != 1) {
    memcpy(hash, buf, RIPEMD160_DIGEST_LENGTH);
    fdh(hash, RIPEMD160_DIGEST_LENGTH, buf, num_bytes);
    BN_bin2bn(buf, num_bytes, a);
  }
  free(buf);
  BN_CTX_free(ctx);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getkey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  mov    %edx,-0x54(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <BN_CTX_new@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   <BN_num_bytes@plt>
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rsp,%rcx
  mov    %rax,%r12
  mov    D27(%rip),%rax
  movslq (%rax),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L23
L44:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L44
L23:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L46
L17:
  mov    -0x54(%rbp),%esi
  mov    -0x50(%rbp),%rdi
  mov    %r12,%rdx
  mov    %rsp,%r14
  mov    %rbx,%rcx
  call   <fdh@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <BN_bin2bn@plt>
  jmp    L5
  nopl   0x0(%rax)
L1:
  mov    D27(%rip),%rax
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    %rbx,%rcx
  mov    D27(%rip),%rax
  mov    (%rax),%esi
  call   <fdh@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <BN_bin2bn@plt>
L5:
  mov    -0x48(%rbp),%rsi
  mov    %r15,%rdx
  mov    %r13,%rdi
  call   <BN_kronecker@plt>
  cmp    $0x1,%eax
  jne    L1
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <BN_CTX_free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L46:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L17
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getkey(BIGNUM *a, const uint8_t *id, int len, const BIGNUM *N) {
  uint8_t *tmp;
  BN_CTX *ctx = BN_CTX_new();
  const size_t num_bytes = BN_num_bytes(N) - 1;
  uint8_t *buf = (uint8_t *)malloc(num_bytes);
  uint8_t hash[RIPEMD160_DIGEST_LENGTH];
  fdh(id, len, buf, num_bytes);
  BN_bin2bn(hash, num_bytes, a);
  while (BN_kronecker(a, N, ctx) != 1) {
    memcpy(hash, buf, RIPEMD160_DIGEST_LENGTH);
    fdh(hash, RIPEMD160_DIGEST_LENGTH, buf, num_bytes);
    BN_bin2bn(buf, num_bytes, a);
  }
  free(buf);
  BN_CTX_free(ctx);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getkey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x38,%rsp
  mov    %edx,-0x54(%rbp)
  mov    %rcx,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <BN_CTX_new@plt>
  mov    %rbx,%rdi
  mov    %rax,%r15
  call   <BN_num_bytes@plt>
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rsp,%rcx
  mov    %rax,%r12
  mov    D3(%rip),%rax
  movslq (%rax),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L2
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L22
L2:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L44
L69:
  mov    -0x54(%rbp),%esi
  mov    -0x50(%rbp),%rdi
  mov    %r12,%rdx
  mov    %rsp,%r14
  mov    %rbx,%rcx
  call   <fdh@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <BN_bin2bn@plt>
  jmp    L38
  nopl   0x0(%rax)
L0:
  mov    D3(%rip),%rax
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %r14,%rdi
  mov    %rbx,%rcx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <fdh@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <BN_bin2bn@plt>
L38:
  mov    -0x48(%rbp),%rsi
  mov    %r15,%rdx
  mov    %r13,%rdi
  call   <BN_kronecker@plt>
  cmp    $0x1,%eax
  jne    L0
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <BN_CTX_free@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L44:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L69
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getkey(BIGNUM *a, const uint8_t *id, int len, const BIGNUM *N) {
  uint8_t *tmp;
  BN_CTX *ctx = BN_CTX_new();
  const size_t num_bytes = BN_num_bytes(N) - 1;
  uint8_t *buf = (uint8_t *)malloc(num_bytes);
  uint8_t hash[RIPEMD160_DIGEST_LENGTH];
  fdh(id, len, buf, num_bytes);
  BN_bin2bn(hash, num_bytes, a);
  while (BN_kronecker(a, N, ctx) != 1) {
    memcpy(hash, buf, RIPEMD160_DIGEST_LENGTH);
    fdh(hash, RIPEMD160_DIGEST_LENGTH, buf, num_bytes);
    BN_bin2bn(buf, num_bytes, a);
  }
  free(buf);
  BN_CTX_free(ctx);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ehnlc_strcspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L43
L30:
  cmpq   $0x0,-0x30(%rbp)
  jne    L36
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ehnlc_strlen@plt>
  jmp    L43
L36:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ehnlc_strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L99
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ehnlc_strlen@plt>
  jmp    L43
L99:
  movq   $0x0,-0x20(%rbp)
  jmp    L110
L46:
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L120
L100:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L115
  mov    -0x20(%rbp),%rax
  jmp    L43
L115:
  addq   $0x1,-0x18(%rbp)
L120:
  cmpq   $0x0,-0x8(%rbp)
  jne    L45
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L100
L45:
  addq   $0x1,-0x20(%rbp)
L110:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    -0x20(%rbp),%rax
L43:
  leave
  ret
```

assistant: ```c
size_t ehnlc_strcspn(const char *s, const char *reject) {
  size_t i, j, found, len;
  if (!s) {
    return 0;
  }
  if (!reject) {
    return ehnlc_strlen(s);
  }
  len = ehnlc_strlen(reject);
  if (!len) {
    return ehnlc_strlen(s);
  }
  for (i = 0; s[i]; ++i) {
    found = 0;
    for (j = 0; !found && j < len; ++j) {
      if (s[i] == reject[j]) {
        return i;
      }
    }
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<ehnlc_strcspn>:
  endbr64
  test   %rdi,%rdi
  je     L82
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L29
  mov    %rsi,%rdi
  call   <ehnlc_strlen@plt>
  test   %rax,%rax
  je     L54
  movzbl 0x0(%rbp),%esi
  mov    $0x0,%edi
  lea    (%rax,%rbx,1),%rcx
  test   %sil,%sil
  je     L48
L12:
  mov    %rbx,%rdx
L52:
  cmp    %sil,(%rdx)
  je     L48
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L52
  add    $0x1,%rdi
  movzbl 0x0(%rbp,%rdi,1),%esi
  test   %sil,%sil
  jne    L12
  jmp    L48
L29:
  call   <ehnlc_strlen@plt>
  mov    %rax,%rdi
L48:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L54:
  mov    %rbp,%rdi
  call   <ehnlc_strlen@plt>
  mov    %rax,%rdi
  jmp    L48
L82:
  mov    $0x0,%edi
  mov    %rdi,%rax
  ret
```

assistant: ```c
size_t ehnlc_strcspn(const char *s, const char *reject) {
  size_t i, j, found, len;
  if (!s) {
    return 0;
  }
  if (!reject) {
    return ehnlc_strlen(s);
  }
  len = ehnlc_strlen(reject);
  if (!len) {
    return ehnlc_strlen(s);
  }
  for (i = 0; s[i]; ++i) {
    found = 0;
    for (j = 0; !found && j < len; ++j) {
      if (s[i] == reject[j]) {
        return i;
      }
    }
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<ehnlc_strcspn>:
  endbr64
  test   %rdi,%rdi
  je     L48
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L2
  mov    %rsi,%rdi
  call   <ehnlc_strlen@plt>
  test   %rax,%rax
  je     L2
  movzbl 0x0(%rbp),%edx
  xor    %r8d,%r8d
  lea    (%rax,%rbx,1),%rcx
  test   %dl,%dl
  je     L21
L38:
  mov    %rbx,%rax
  nopl   0x0(%rax)
L66:
  cmp    %dl,(%rax)
  je     L17
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L66
  add    $0x1,%r8
  movzbl 0x0(%rbp,%r8,1),%edx
  test   %dl,%dl
  jne    L38
L17:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <ehnlc_strlen@plt>
L21:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t ehnlc_strcspn(const char *s, const char *reject) {
  size_t i, j, found, len;
  if (!s) {
    return 0;
  }
  if (!reject) {
    return ehnlc_strlen(s);
  }
  len = ehnlc_strlen(reject);
  if (!len) {
    return ehnlc_strlen(s);
  }
  for (i = 0; s[i]; ++i) {
    found = 0;
    for (j = 0; !found && j < len; ++j) {
      if (s[i] == reject[j]) {
        return i;
      }
    }
  }
  return i;
}
```