ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<sonos_location_string>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: 
LOCATION: http://%s:1400/xml/device_description.xml


assistant: ```c
char *sonos_location_string(char *ip) {
  char *temp;
  asprintf(&temp, "\r\nLOCATION: http://%s:1400/xml/device_description.xml\r\n", ip);
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sonos_location_string>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  lea    D1(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <asprintf@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: 
LOCATION: http://%s:1400/xml/device_description.xml


assistant: ```c
char *sonos_location_string(char *ip) {
  char *temp;
  asprintf(&temp, "\r\nLOCATION: http://%s:1400/xml/device_description.xml\r\n", ip);
  return temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cubic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L66
L32:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L58
L21:
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L38
L53:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L53
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L19
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L19:
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L21
  addl   $0x1,-0x18(%rbp)
L66:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L32
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string

tool: D7: tot = %d


assistant: ```c
int cubic(int *A, int n) {
  int i, j, k, tot, best;
  tot = 0;
  best = A[1];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      int sum = 0;
      for (k = i; k <= j; k++) {
        sum += A[k];
        tot++;
      }
      if (sum > best)
        best = sum;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cubic>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x4(%rdi),%ebx
  test   %esi,%esi
  jle    L81
  mov    %rdi,%r9
  mov    %esi,%r14d
  mov    %esi,%r10d
  add    $0x4,%r9
  lea    0x1(%rsi),%r15d
  mov    $0x1,%r13d
  mov    $0x0,%r8d
  mov    $0x0,%r11d
  jmp    L50
L52:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L52
  lea    0x1(%r8,%rsi,1),%r8d
L31:
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  add    $0x1,%esi
  add    $0x4,%rcx
  cmp    %r10d,%esi
  je     L24
L85:
  lea    (%rsi,%r12,1),%edi
  mov    %r9,%rax
  mov    %r11d,%edx
  cmp    %ebp,%edi
  jge    L52
  jmp    L31
L24:
  sub    $0x1,%r10d
  add    $0x4,%r9
  add    $0x1,%r13
  cmp    %r15,%r13
  je     L71
L50:
  mov    %r13d,%r12d
  mov    %r13d,%ebp
  cmp    %r13d,%r14d
  jl     L24
  lea    0x4(%r9),%rcx
  mov    $0x0,%esi
  jmp    L85
L81:
  mov    $0x0,%r8d
L71:
  mov    %r8d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5: tot = %d


assistant: ```c
int cubic(int *A, int n) {
  int i, j, k, tot, best;
  tot = 0;
  best = A[1];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      int sum = 0;
      for (k = i; k <= j; k++) {
        sum += A[k];
        tot++;
      }
      if (sum > best)
        best = sum;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cubic>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x4(%rdi),%r12d
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rbx
  mov    %esi,%r11d
  lea    0x1(%rsi),%ebp
  mov    $0x1,%r9d
  add    $0x4,%rbx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%r10
  add    $0x4,%rbx
  mov    %r9d,%esi
  xor    %edi,%edi
  mov    %rbx,%rcx
  nop
L20:
  mov    %r10,%rax
  xor    %edx,%edx
  cmp    %r9d,%esi
  jl     L31
  nopw   0x0(%rax,%rax,1)
L2:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L2
  lea    0x1(%r8,%rdi,1),%r8d
L31:
  cmp    %edx,%r12d
  cmovl  %edx,%r12d
  add    $0x1,%esi
  add    $0x1,%edi
  add    $0x4,%rcx
  cmp    %esi,%r11d
  jge    L20
  add    $0x1,%r9
  cmp    %rbp,%r9
  jne    L11
L8:
  mov    %r8d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  xor    %r8d,%r8d
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: tot = %d


assistant: ```c
int cubic(int *A, int n) {
  int i, j, k, tot, best;
  tot = 0;
  best = A[1];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      int sum = 0;
      for (k = i; k <= j; k++) {
        sum += A[k];
        tot++;
      }
      if (sum > best)
        best = sum;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: What is the c source code of the assembly code below:

```asm
<cubic>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x4(%rdi),%r12d
  test   %esi,%esi
  jle    L11
  lea    0x1(%rsi),%eax
  mov    %rdi,%r11
  mov    %esi,%r13d
  xor    %ebp,%ebp
  mov    %eax,0xc(%rsp)
  lea    0x4(%rdi),%rbx
  mov    $0x1,%r8d
  mov    $0x1,%r15d
  nopl   (%rax)
L9:
  mov    %r8d,%edx
  xor    %esi,%esi
  lea    0x10(%rbx),%r14
  nopl   0x0(%rax)
L27:
  mov    %esi,%r9d
  mov    %r15d,%edi
  add    $0x1,%esi
  cmp    %r8d,%edx
  cmovge %esi,%edi
  cmp    $0x2,%r9d
  jbe    L100
  cmp    %r8d,%edx
  jl     L100
  mov    %edi,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  lea    -0x1(%rax),%ecx
  mov    %rbx,%rax
  shl    $0x4,%rcx
  add    %r14,%rcx
  nopl   0x0(%rax,%rax,1)
L38:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L38
  movdqa %xmm0,%xmm1
  mov    %edi,%r10d
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%r10d
  paddd  %xmm1,%xmm0
  lea    (%r10,%r8,1),%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edi,%r10d
  je     L29
L23:
  movslq %ecx,%r10
  lea    0x0(,%r10,4),%rdi
  add    (%r11,%r10,4),%eax
  lea    0x1(%rcx),%r10d
  cmp    %r10d,%edx
  jl     L29
  add    $0x2,%ecx
  add    0x4(%r11,%rdi,1),%eax
  cmp    %ecx,%edx
  jl     L29
  add    0x8(%r11,%rdi,1),%eax
L29:
  cmp    %eax,%r12d
  lea    0x1(%rbp,%r9,1),%ebp
  cmovl  %eax,%r12d
  add    $0x1,%edx
  cmp    %edx,%r13d
  jge    L27
  add    $0x1,%r8d
  add    $0x4,%rbx
  cmp    0xc(%rsp),%r8d
  jne    L9
L106:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L100:
  mov    %r8d,%ecx
  xor    %eax,%eax
  jmp    L23
L11:
  xor    %ebp,%ebp
  jmp    L106
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: tot = %d


assistant: ```c
int cubic(int *A, int n) {
  int i, j, k, tot, best;
  tot = 0;
  best = A[1];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      int sum = 0;
      for (k = i; k <= j; k++) {
        sum += A[k];
        tot++;
      }
      if (sum > best)
        best = sum;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L42
L49:
  cmpb   $0x20,-0x5(%rbp)
  jne    L7
  cmpl   $0x0,-0x4(%rbp)
  jne    L42
  movl   $0x1,-0x4(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L42
L7:
  movl   $0x0,-0x4(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L42:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L49
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  char c;
  int blank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (!blank) {
        blank = 1;
        putchar(c);
      }
    } else {
      blank = 0;
      putchar(c);
    }
  }
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L31
L46:
  movsbl %al,%edi
  call   <putchar@plt>
  mov    %ebp,%ebx
L31:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D0(%rip),%rdx
  cmp    %al,(%rdx)
  je     L11
  cmp    $0x20,%al
  jne    L46
  test   %ebx,%ebx
  jne    L31
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    $0x1,%ebx
  jmp    L31
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char c;
  int blank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (!blank) {
        blank = 1;
        putchar(c);
      }
    } else {
      blank = 0;
      putchar(c);
    }
  }
  getchar();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D5(%rip),%rbx
L87:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  je     L104
  cmp    $0x20,%al
  jne    L67
  test   %ebp,%ebp
  jne    L7
L35:
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  je     L104
  cmp    $0x20,%al
  jne    L67
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  je     L104
  cmp    $0x20,%al
  jne    L67
L7:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  je     L104
  mov    $0x1,%ebp
  cmp    $0x20,%al
  je     L87
  nopw   0x0(%rax,%rax,1)
L67:
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  je     L104
  cmp    $0x20,%al
  je     L35
  jmp    L67
  nopl   0x0(%rax)
L104:
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char c;
  int blank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (!blank) {
        blank = 1;
        putchar(c);
      }
    } else {
      blank = 0;
      putchar(c);
    }
  }
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbx
L73:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  je     L63
  cmp    $0x20,%al
  jne    L57
  test   %ebp,%ebp
  jne    L111
L100:
  mov    $0x20,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  je     L63
  cmp    $0x20,%al
  jne    L57
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  je     L63
  cmp    $0x20,%al
  jne    L57
L111:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  je     L63
  mov    $0x1,%ebp
  cmp    $0x20,%al
  je     L73
  nopw   0x0(%rax,%rax,1)
L57:
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    (%rbx),%al
  je     L63
  cmp    $0x20,%al
  je     L100
  jmp    L57
  nopl   0x0(%rax)
L63:
  xor    %eax,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  char c;
  int blank = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      if (!blank) {
        blank = 1;
        putchar(c);
      }
    } else {
      blank = 0;
      putchar(c);
    }
  }
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L4
L15:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L15
L1:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while ((*s1 != '\0') && (tolower(*(unsigned char *)s1) == tolower(*(unsigned char *)s2))) {
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L13
L3:
  movzbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  jne    L13
  add    $0x1,%rbp
  add    $0x1,%r12
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L3
L13:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while ((*s1 != '\0') && (tolower(*(unsigned char *)s1) == tolower(*(unsigned char *)s2))) {
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L38
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L34:
  movzbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  test   %dil,%dil
  je     L19
L38:
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L34
L19:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while ((*s1 != '\0') && (tolower(*(unsigned char *)s1) == tolower(*(unsigned char *)s2))) {
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L33
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L34:
  movzbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  test   %dil,%dil
  je     L2
L33:
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L34
L2:
  movzbl 0x0(%rbp),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while ((*s1 != '\0') && (tolower(*(unsigned char *)s1) == tolower(*(unsigned char *)s2))) {
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uni>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %ecx,%ebp
  test   %esi,%esi
  jle    L51
  mov    %rdi,%r12
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  shl    $0x2,%rax
  mov    %rax,0x8(%rsp)
  lea    0x4(%rdi,%rax,1),%rdi
  lea    -0x1(%rcx),%eax
  lea    0x4(%r13,%rax,4),%rcx
  mov    $0x0,%esi
  jmp    L135
L134:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L89
L162:
  mov    (%rax),%r8d
  cmp    %r8d,(%rdx)
  jne    L134
  movl   $0x0,(%rax)
  add    $0x1,%esi
  jmp    L134
L89:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L5
L135:
  mov    %r13,%rax
  test   %ebp,%ebp
  jg     L162
  jmp    L89
L109:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L130
L103:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L109
  movslq %ebx,%rsi
  mov    %edx,(%r14,%rsi,4)
  add    $0x1,%ebx
  jmp    L109
L130:
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <sort@plt>
  test   %r15d,%r15d
  jle    L57
  mov    %r14,%rbx
  lea    -0x1(%r15),%eax
  lea    0x4(%r14,%rax,4),%r12
  lea    D2(%rip),%rbp
L107:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L107
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  lea    (%rbx,%rbp,1),%r15d
  sub    %esi,%r15d
  lea    0x0(,%r15,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    0x8(%rsp),%rax
  lea    0x4(%r14,%rax,1),%rcx
  mov    %r14,%rax
  sub    %r14,%r12
L104:
  mov    (%r12,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L104
L106:
  test   %ebp,%ebp
  jle    L130
  mov    %r13,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%r13,%rdx,4),%rcx
  jmp    L103
L51:
  lea    (%rsi,%rcx,1),%r15d
  lea    0x0(,%r15,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x0,%ebx
  jmp    L106
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: %d 

assistant: ```c
void uni(int *p1, int n1, int *p2, int n2) {
  int i, j, count = 0, *arr;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (*(p1 + i) == *(p2 + j)) {
        *(p2 + j) = 0;
        count++;
      }
    }
  }
  arr = (int *)malloc((n1 + n2 - count) * sizeof(int));
  for (i = 0; i < n1; i++)
    arr[i] = *(p1 + i);
  for (j = 0; j < n2; j++)
    if (*(p2 + j) != 0) {
      arr[i] = (*(p2 + j));
      i++;
    }
  sort(arr, n1 + n2 - count);
  for (i = 0; i < (n1 + n2 - count); i++)
    printf("%d ", arr[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uni>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  lea    (%rsi,%rcx,1),%r13d
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L89
  lea    -0x1(%rsi),%r8d
  lea    -0x1(%rcx),%eax
  mov    %rdi,%r14
  mov    %esi,%r12d
  shl    $0x2,%r8
  mov    %rdi,%rdx
  lea    0x4(%rbp,%rax,4),%rcx
  xor    %esi,%esi
  lea    0x4(%rdi,%r8,1),%rdi
  nopl   0x0(%rax)
L29:
  mov    %rbp,%rax
  test   %r15d,%r15d
  jle    L116
L83:
  mov    (%rax),%ebx
  cmp    %ebx,(%rdx)
  jne    L77
  movl   $0x0,(%rax)
  add    $0x1,%esi
L77:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L83
L116:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L29
  sub    %esi,%r13d
  mov    %r8,0x8(%rsp)
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%r8
  mov    %rax,%rbx
  sub    %rax,%r14
  lea    0x4(%rax,%r8,1),%rcx
  cs nopw 0x0(%rax,%rax,1)
L67:
  mov    (%r14,%rax,1),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L67
L25:
  test   %r15d,%r15d
  jle    L61
  lea    -0x1(%r15),%edx
  mov    %rbp,%rax
  lea    0x4(%rbp,%rdx,4),%rcx
  nopl   0x0(%rax)
L42:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L19
  movslq %r12d,%rsi
  add    $0x1,%r12d
  mov    %edx,(%rbx,%rsi,4)
L19:
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L42
L61:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <sort@plt>
  test   %r13d,%r13d
  jle    L52
  lea    -0x1(%r13),%eax
  lea    D7(%rip),%rbp
  lea    0x4(%rbx,%rax,4),%r12
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L0
L52:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L89:
  lea    0x0(,%r13,4),%edi
  xor    %r12d,%r12d
  call   <malloc@plt>
  mov    %rax,%rbx
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d 

assistant: ```c
void uni(int *p1, int n1, int *p2, int n2) {
  int i, j, count = 0, *arr;
  for (i = 0; i < n1; i++) {
    for (j = 0; j < n2; j++) {
      if (*(p1 + i) == *(p2 + j)) {
        *(p2 + j) = 0;
        count++;
      }
    }
  }
  arr = (int *)malloc((n1 + n2 - count) * sizeof(int));
  for (i = 0; i < n1; i++)
    arr[i] = *(p1 + i);
  for (j = 0; j < n2; j++)
    if (*(p2 + j) != 0) {
      arr[i] = (*(p2 + j));
      i++;
    }
  sort(arr, n1 + n2 - count);
  for (i = 0; i < (n1 + n2 - count); i++)
    printf("%d ", arr[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L5:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *p = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L5:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L5
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *p = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L1:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L1
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *p = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *dest, const char *src) {
  char *p = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return p;
}
```