ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_magic>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  movabs $0xcccccccccccccccd,%r14
  jmp    L15
L48:
  mov    $0x1,%ebp
L43:
  mov    %rbp,%r12
L15:
  movsbl 0x0(%r13,%r12,1),%edi
  call   <char_value@plt>
  mov    %eax,%ebx
  movsbl 0x5(%r13,%r12,1),%edi
  call   <char_value@plt>
  add    %eax,%ebx
  lea    0x1(%r12),%rbp
  mov    %rbp,%rax
  mul    %r14
  mov    %rdx,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdx
  add    %rax,%rdx
  mov    %rbp,%rax
  sub    %rdx,%rax
  movsbl 0x5(%r13,%rax,1),%edi
  call   <char_value@plt>
  add    %eax,%ebx
  mov    %ebx,-0x4(%rsp,%rbp,4)
  test   %r12,%r12
  je     L48
  cmp    -0x8(%rsp,%rbp,4),%ebx
  jne    L21
  cmp    $0x4,%rbp
  jbe    L43
  mov    $0x1,%eax
L26:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  mov    $0x0,%eax
  jmp    L26
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_magic(const char *digits) {
  int sums[5];
  for (size_t i = 0; i < 5; i++) {
    sums[i] = char_value(digits[i]) + char_value(digits[i + 5]) + char_value(digits[((i + 1) % 5) + 5]);
    if (i > 0 && sums[i] != sums[i - 1])
      return false;
  }
  return true;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_magic>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  movabs $0xcccccccccccccccd,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L47:
  movsbl 0x0(%rbp,%r13,1),%edi
  lea    0x1(%r13),%r14
  call   <char_value@plt>
  movsbl 0x5(%rbp,%r13,1),%edi
  mov    %eax,%ebx
  call   <char_value@plt>
  add    %eax,%ebx
  mov    %r14,%rax
  mul    %r12
  mov    %rdx,%rax
  and    $0xfffffffffffffffc,%rdx
  shr    $0x2,%rax
  add    %rax,%rdx
  mov    %r14,%rax
  sub    %rdx,%rax
  movsbl 0x5(%rbp,%rax,1),%edi
  call   <char_value@plt>
  add    %eax,%ebx
  mov    %ebx,(%rsp,%r13,4)
  test   %r13,%r13
  je     L56
  cmp    -0x4(%rsp,%r13,4),%ebx
  jne    L45
  cmp    $0x5,%r14
  je     L44
  mov    %r14,%r13
  jmp    L47
  nop
L56:
  mov    $0x1,%r13d
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L44:
  mov    $0x1,%eax
L51:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  jmp    L51
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_magic(const char *digits) {
  int sums[5];
  for (size_t i = 0; i < 5; i++) {
    sums[i] = char_value(digits[i]) + char_value(digits[i + 5]) + char_value(digits[((i + 1) % 5) + 5]);
    if (i > 0 && sums[i] != sums[i - 1])
      return false;
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_magic>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  movabs $0xcccccccccccccccd,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
L5:
  movsbl 0x0(%rbp,%r13,1),%edi
  lea    0x1(%r13),%r14
  call   <char_value@plt>
  movsbl 0x5(%rbp,%r13,1),%edi
  mov    %eax,%ebx
  call   <char_value@plt>
  add    %eax,%ebx
  mov    %r14,%rax
  mul    %r12
  mov    %rdx,%rax
  and    $0xfffffffffffffffc,%rdx
  shr    $0x2,%rax
  add    %rax,%rdx
  mov    %r14,%rax
  sub    %rdx,%rax
  movsbl 0x5(%rbp,%rax,1),%edi
  call   <char_value@plt>
  add    %eax,%ebx
  mov    %ebx,(%rsp,%r13,4)
  test   %r13,%r13
  je     L15
  cmp    -0x4(%rsp,%r13,4),%ebx
  jne    L69
  cmp    $0x5,%r14
  je     L9
  mov    %r14,%r13
  jmp    L5
  nop
L15:
  mov    $0x1,%r13d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  jmp    L22
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_magic(const char *digits) {
  int sums[5];
  for (size_t i = 0; i < 5; i++) {
    sums[i] = char_value(digits[i]) + char_value(digits[i + 5]) + char_value(digits[((i + 1) % 5) + 5]);
    if (i > 0 && sums[i] != sums[i - 1])
      return false;
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sqlUbyteArrayToString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <newDyString@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L24
L29:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <dyStringPrintf@plt>
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L29
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <dyStringCannibalize@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %u,

assistant: ```c
char *sqlUbyteArrayToString(unsigned char *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sqlUbyteArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x100,%edi
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L2
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%r12
  lea    D3(%rip),%rbp
L13:
  movzbl (%rbx),%edx
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <dyStringPrintf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L13
L2:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: %u,

assistant: ```c
char *sqlUbyteArrayToString(unsigned char *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sqlUbyteArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L27
  sub    $0x1,%ebp
  mov    %rax,%rdi
  lea    D0(%rip),%r12
  add    %rbx,%rbp
  jmp    L5
  nopl   (%rax)
L11:
  mov    (%rsp),%rdi
  add    $0x1,%rbx
L5:
  movzbl (%rbx),%edx
  mov    %r12,%rsi
  call   <dyStringPrintf@plt>
  cmp    %rbp,%rbx
  jne    L11
L27:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: %u,

assistant: ```c
char *sqlUbyteArrayToString(unsigned char *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sqlUbyteArrayToString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x100,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <newDyString@plt>
  mov    %rax,(%rsp)
  test   %ebp,%ebp
  jle    L24
  sub    $0x1,%ebp
  mov    %rax,%rdi
  lea    D3(%rip),%r12
  add    %rbx,%rbp
  jmp    L26
  nopl   (%rax)
L28:
  mov    (%rsp),%rdi
  add    $0x1,%rbx
L26:
  movzbl (%rbx),%edx
  mov    %r12,%rsi
  call   <dyStringPrintf@plt>
  cmp    %rbp,%rbx
  jne    L28
L24:
  mov    %rsp,%rdi
  call   <dyStringCannibalize@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: %u,

assistant: ```c
char *sqlUbyteArrayToString(unsigned char *array, int arraySize) {
  int i;
  struct dyString *string = newDyString(256);
  for (i = 0; i < arraySize; i++) {
    dyStringPrintf(string, "%u,", array[i]);
  }
  return dyStringCannibalize(&string);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L23:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  nop
L11:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L34
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  jne    L11
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  jmp    L18
L19:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const char *t;
  t = s;
  while (*t++ != '\0')
    ;
  while (--t != s && *t != (char)c)
    ;
  if (*t == (char)c)
    return (char *)t;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strrchr>:
  endbr64
  mov    %rdi,%rax
L16:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L16
L36:
  sub    $0x1,%rax
  cmp    %rax,%rdi
  je     L39
  cmp    %sil,(%rax)
  jne    L36
  ret
L39:
  cmp    %sil,(%rax)
  je     L10
  mov    $0x0,%eax
L10:
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const char *t;
  t = s;
  while (*t++ != '\0')
    ;
  while (--t != s && *t != (char)c)
    ;
  if (*t == (char)c)
    return (char *)t;
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strrchr>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L23:
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L23
  mov    %esi,%ecx
  jmp    L0
  nop
L28:
  cmp    %cl,%dl
  je     L33
  movzbl -0x1(%rax),%edx
L0:
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L28
  cmp    %sil,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
L33:
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const char *t;
  t = s;
  while (*t++ != '\0')
    ;
  while (--t != s && *t != (char)c)
    ;
  if (*t == (char)c)
    return (char *)t;
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strrchr>:
  endbr64
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  jne    L19
  mov    %esi,%ecx
  jmp    L12
  nop
L29:
  cmp    %dl,%cl
  je     L31
  movzbl -0x1(%rax),%edx
L12:
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jne    L29
  cmp    %sil,%dl
  mov    $0x0,%edx
  cmovne %rdx,%rax
L31:
  ret
```

assistant: ```c
char *strrchr(const char *s, int c) {
  const char *t;
  t = s;
  while (*t++ != '\0')
    ;
  while (--t != s && *t != (char)c)
    ;
  if (*t == (char)c)
    return (char *)t;
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<GF_vectmulX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfefefefe,-0x38(%rbp)
  movl   $0xfefefefe,-0x34(%rbp)
  movl   $0x80808080,-0x30(%rbp)
  movl   $0x80808080,-0x2c(%rbp)
  movl   $0x1d1d1d1d,-0x28(%rbp)
  movl   $0x1d1d1d1d,-0x24(%rbp)
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  mov    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_cmpgt_epi8@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  mov    %rax,-0x48(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <_mm_slli_epi16@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_mm_xor_si128@plt>
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
__m128i GF_vectmulX(__m128i v) {
  __m128i v1;
  __m128i mask;
  __m128i res;
  __m128i low_bit_mask = {0xfefefefefefefefe, 0xfefefefefefefefe};
  __m128i high_bit_mask = {0x8080808080808080, 0x8080808080808080};
  __m128i modulo_mask = {0x1d1d1d1d1d1d1d1d, 0x1d1d1d1d1d1d1d1d};
  unsigned char A[16] __attribute__((aligned(16)));
  int i;
  mask = _mm_setzero_si128();
  v1 = _mm_and_si128(v, high_bit_mask);
  mask = _mm_cmpgt_epi8(mask, v1);
  mask = _mm_and_si128(mask, modulo_mask);
  res = v;
  res = _mm_slli_epi16(res, 1);
  res = _mm_and_si128(res, low_bit_mask);
  res = _mm_xor_si128(res, mask);
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<GF_vectmulX>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <_mm_setzero_si128@plt>
  mov    %rax,%rbx
  movabs $0x8080808080808080,%rsi
  mov    %rbp,%rdi
  call   <_mm_and_si128@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <_mm_cmpgt_epi8@plt>
  movabs $0x1d1d1d1d1d1d1d1d,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  mov    %rax,%rbx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <_mm_slli_epi16@plt>
  movabs $0xfefefefefefefefe,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <_mm_xor_si128@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__m128i GF_vectmulX(__m128i v) {
  __m128i v1;
  __m128i mask;
  __m128i res;
  __m128i low_bit_mask = {0xfefefefefefefefe, 0xfefefefefefefefe};
  __m128i high_bit_mask = {0x8080808080808080, 0x8080808080808080};
  __m128i modulo_mask = {0x1d1d1d1d1d1d1d1d, 0x1d1d1d1d1d1d1d1d};
  unsigned char A[16] __attribute__((aligned(16)));
  int i;
  mask = _mm_setzero_si128();
  v1 = _mm_and_si128(v, high_bit_mask);
  mask = _mm_cmpgt_epi8(mask, v1);
  mask = _mm_and_si128(mask, modulo_mask);
  res = v;
  res = _mm_slli_epi16(res, 1);
  res = _mm_and_si128(res, low_bit_mask);
  res = _mm_xor_si128(res, mask);
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GF_vectmulX>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <_mm_setzero_si128@plt>
  mov    %r12,%rdi
  movabs $0x8080808080808080,%rsi
  mov    %rax,%rbp
  call   <_mm_and_si128@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <_mm_cmpgt_epi8@plt>
  movabs $0x1d1d1d1d1d1d1d1d,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  mov    %r12,%rdi
  mov    $0x1,%esi
  mov    %rax,%rbp
  call   <_mm_slli_epi16@plt>
  movabs $0xfefefefefefefefe,%rsi
  mov    %rax,%rdi
  call   <_mm_and_si128@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i GF_vectmulX(__m128i v) {
  __m128i v1;
  __m128i mask;
  __m128i res;
  __m128i low_bit_mask = {0xfefefefefefefefe, 0xfefefefefefefefe};
  __m128i high_bit_mask = {0x8080808080808080, 0x8080808080808080};
  __m128i modulo_mask = {0x1d1d1d1d1d1d1d1d, 0x1d1d1d1d1d1d1d1d};
  unsigned char A[16] __attribute__((aligned(16)));
  int i;
  mask = _mm_setzero_si128();
  v1 = _mm_and_si128(v, high_bit_mask);
  mask = _mm_cmpgt_epi8(mask, v1);
  mask = _mm_and_si128(mask, modulo_mask);
  res = v;
  res = _mm_slli_epi16(res, 1);
  res = _mm_and_si128(res, low_bit_mask);
  res = _mm_xor_si128(res, mask);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode_packchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jg     L6
  mov    $0x1b,%eax
  jmp    L15
L6:
  cmpl   $0x60,-0x4(%rbp)
  jle    L27
  mov    -0x4(%rbp),%eax
  sub    $0x60,%eax
  jmp    L15
L27:
  mov    -0x4(%rbp),%eax
  sub    $0x40,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
uint32_t encode_packchar(int c) {
  if (c < 'A') {
    return 27;
  }
  if (c >= 'a') {
    return (uint32_t)(c - 'a' + 1);
  }
  return (uint32_t)(c - 'A' + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encode_packchar>:
  endbr64
  mov    $0x1b,%eax
  cmp    $0x40,%edi
  jle    L5
  lea    -0x60(%rdi),%edx
  lea    -0x40(%rdi),%eax
  cmp    $0x61,%edi
  cmovge %edx,%eax
L5:
  ret
```

assistant: ```c
uint32_t encode_packchar(int c) {
  if (c < 'A') {
    return 27;
  }
  if (c >= 'a') {
    return (uint32_t)(c - 'a' + 1);
  }
  return (uint32_t)(c - 'A' + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<encode_packchar>:
  endbr64
  mov    $0x1b,%eax
  cmp    $0x40,%edi
  jle    L6
  lea    -0x60(%rdi),%edx
  lea    -0x40(%rdi),%eax
  cmp    $0x61,%edi
  cmovge %edx,%eax
L6:
  ret
```

assistant: ```c
uint32_t encode_packchar(int c) {
  if (c < 'A') {
    return 27;
  }
  if (c >= 'a') {
    return (uint32_t)(c - 'a' + 1);
  }
  return (uint32_t)(c - 'A' + 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encode_packchar>:
  endbr64
  mov    $0x1b,%eax
  cmp    $0x40,%edi
  jle    L3
  lea    -0x60(%rdi),%edx
  lea    -0x40(%rdi),%eax
  cmp    $0x61,%edi
  cmovge %edx,%eax
L3:
  ret
```

assistant: ```c
uint32_t encode_packchar(int c) {
  if (c < 'A') {
    return 27;
  }
  if (c >= 'a') {
    return (uint32_t)(c - 'a' + 1);
  }
  return (uint32_t)(c - 'A' + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<string_concat_heap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <string_copy_heap@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <string_concat_to@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct String *string_concat_heap(struct String *a, struct String *b) {
  struct String *temp = string_copy_heap(a);
  string_concat_to(temp, b);
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<string_concat_heap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <string_copy_heap@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <string_concat_to@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct String *string_concat_heap(struct String *a, struct String *b) {
  struct String *temp = string_copy_heap(a);
  string_concat_to(temp, b);
  return temp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_concat_heap>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <string_copy_heap@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <string_concat_to@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct String *string_concat_heap(struct String *a, struct String *b) {
  struct String *temp = string_copy_heap(a);
  string_concat_to(temp, b);
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_concat_heap>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <string_copy_heap@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <string_concat_to@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct String *string_concat_heap(struct String *a, struct String *b) {
  struct String *temp = string_copy_heap(a);
  string_concat_to(temp, b);
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ln_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L88
L10:
  cmpl   $0x20,-0x4(%rbp)
  je     L111
  cmpl   $0x20,-0x4(%rbp)
  jg     L68
  cmpl   $0x9,-0x4(%rbp)
  je     L47
  cmpl   $0xa,-0x4(%rbp)
  je     L97
  jmp    L68
L111:
  addl   $0x1,-0x8(%rbp)
  jmp    L88
L47:
  addl   $0x1,-0xc(%rbp)
  jmp    L88
L97:
  addl   $0x1,-0x10(%rbp)
  jmp    L88
L68:
  nop
L88:
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7e,-0x4(%rbp)
  jne    L10
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L67
L57:
  nop
L67:
  mov    $0x0,%eax
  call   <getchar@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L57
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: Tabs = %d
Blaks = %d
Nl = %i

assistant: ```c
ln_1(void) {
  int c, nl = 1, tabs = 0, blanks = 0;
  while ((c = getchar()) != '~')
    switch (c) {
    case ' ':
      blanks++;
      break;
    case '\t':
      tabs++;
      break;
    case '\n':
      nl++;
      break;
    default:
      continue;
    }
  printf("Tabs = %d\nBlaks = %d\nNl = %i", tabs, blanks, nl);
  while (c = getchar() != '10')
    continue;
}
```
user: What is the c source code of the assembly code below:

```asm
<ln_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  mov    $0x1,%r12d
  jmp    L26
L69:
  cmp    $0x9,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
L26:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x7e,%al
  je     L8
  cmp    $0xa,%al
  je     L28
  cmp    $0x20,%al
  jne    L69
  add    $0x1,%ebp
  jmp    L26
L28:
  add    $0x1,%r12d
  jmp    L26
L8:
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L31:
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L31
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Tabs = %d
Blaks = %d
Nl = %i

assistant: ```c
ln_1(void) {
  int c, nl = 1, tabs = 0, blanks = 0;
  while ((c = getchar()) != '~')
    switch (c) {
    case ' ':
      blanks++;
      break;
    case '\t':
      tabs++;
      break;
    case '\n':
      nl++;
      break;
    default:
      continue;
    }
  printf("Tabs = %d\nBlaks = %d\nNl = %i", tabs, blanks, nl);
  while (c = getchar() != '10')
    continue;
}
```