ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <unlink@plt>
  lea    D0(%rip),%rbx
  mov    %rbx,%rsi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D28(%rip),%rsi
  lea    D5(%rip),%rdi
  call   <link@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <link@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D29
type: string
name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D48
type: string
name: disassemble_data
arguments: label: D28
type: string
name: disassemble_data
arguments: label: D5
type: string

tool: D29: malloc.c

tool: D0: sysmalloc.c

tool: D48: Using memory allocation package: %s


tool: D28: mallocwrapper.c

tool: D5: plainwrapper.c

assistant: ```c
int main() {
  unlink("malloc.c");
  printf("Using memory allocation package: %s\n", "sysmalloc.c");
  link("plainwrapper.c", "mallocwrapper.c");
  link("sysmalloc.c", "malloc.c");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D34(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D3(%rip),%rbp
  sub    $0x8,%rsp
  call   <unlink@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <link@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <link@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D3
type: string
name: read_data
arguments: data_tag: D16
type: string
name: read_data
arguments: data_tag: D41
type: string
name: read_data
arguments: data_tag: D14
type: string

tool: D34: malloc.c

tool: D3: sysmalloc.c

tool: D16: Using memory allocation package: %s


tool: D41: mallocwrapper.c

tool: D14: plainwrapper.c

assistant: ```c
int main() {
  unlink("malloc.c");
  printf("Using memory allocation package: %s\n", "sysmalloc.c");
  link("plainwrapper.c", "mallocwrapper.c");
  link("sysmalloc.c", "malloc.c");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D44(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D35(%rip),%rbp
  sub    $0x8,%rsp
  call   <unlink@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rsi
  lea    D46(%rip),%rdi
  call   <link@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <link@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D44
type_infered: string
name: disassemble_data
arguments: tag: D35
type_infered: string
name: disassemble_data
arguments: tag: D31
type_infered: string
name: disassemble_data
arguments: tag: D49
type_infered: string
name: disassemble_data
arguments: tag: D46
type_infered: string

tool: D44: malloc.c

tool: D35: sysmalloc.c

tool: D31: Using memory allocation package: %s


tool: D49: mallocwrapper.c

tool: D46: plainwrapper.c

assistant: ```c
int main() {
  unlink("malloc.c");
  printf("Using memory allocation package: %s\n", "sysmalloc.c");
  link("plainwrapper.c", "mallocwrapper.c");
  link("sysmalloc.c", "malloc.c");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getParamValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L22:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L2
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L22
  jmp    L50
L2:
  nop
L50:
  addl   $0x1,-0xc(%rbp)
  jmp    L12
L44:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L44
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getParamValue(char *target, const char *str) {
  unsigned int i;
  unsigned int size;
  size = strlen(str);
  unsigned int destSize = 0;
  for (i = 0; i < size; i++) {
    if (str[i] == '=')
      break;
  }
  i++;
  for (; i < size; i++) {
    target[destSize] = str[i];
    destSize++;
  }
  target[destSize] = 0;
  return target;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getParamValue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L18
  mov    %rbp,%rdx
  mov    $0x0,%ecx
L27:
  cmpb   $0x3d,(%rdx)
  je     L0
  add    $0x1,%ecx
  add    $0x1,%rdx
  cmp    %ecx,%eax
  jne    L27
  mov    %eax,%ecx
L0:
  lea    0x1(%rcx),%esi
  cmp    %esi,%eax
  jbe    L19
  lea    -0x2(%rax),%r8d
  sub    %ecx,%r8d
  mov    $0x0,%edx
  mov    %esi,%esi
  add    %rsi,%rbp
L8:
  movzbl 0x0(%rbp,%rdx,1),%edi
  mov    %edx,%esi
  mov    %dil,(%rbx,%rsi,1)
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmp    %r8,%rsi
  jne    L8
  sub    $0x1,%eax
  sub    %ecx,%eax
L18:
  mov    %eax,%eax
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%eax
  jmp    L18
```

assistant: ```c
char *getParamValue(char *target, const char *str) {
  unsigned int i;
  unsigned int size;
  size = strlen(str);
  unsigned int destSize = 0;
  for (i = 0; i < size; i++) {
    if (str[i] == '=')
      break;
  }
  i++;
  for (; i < size; i++) {
    target[destSize] = str[i];
    destSize++;
  }
  target[destSize] = 0;
  return target;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getParamValue>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L15
  mov    %rbx,%rcx
  xor    %edx,%edx
  jmp    L60
  nopl   0x0(%rax)
L31:
  add    $0x1,%rcx
  cmp    %edx,%eax
  je     L34
L60:
  cmpb   $0x3d,(%rcx)
  mov    %edx,%edi
  lea    0x1(%rdx),%edx
  jne    L31
L52:
  lea    0x1(%rdi),%ecx
  cmp    %ecx,%eax
  jbe    L15
  lea    -0x2(%rax),%r8d
  xor    %edx,%edx
  lea    (%rbx,%rcx,1),%rsi
  sub    %edi,%r8d
  xchg   %ax,%ax
L9:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %r8,%rcx
  jne    L9
  sub    $0x1,%eax
  sub    %edi,%eax
  add    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %eax,%edi
  jmp    L52
  nopl   0x0(%rax)
L15:
  mov    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *getParamValue(char *target, const char *str) {
  unsigned int i;
  unsigned int size;
  size = strlen(str);
  unsigned int destSize = 0;
  for (i = 0; i < size; i++) {
    if (str[i] == '=')
      break;
  }
  i++;
  for (; i < size; i++) {
    target[destSize] = str[i];
    destSize++;
  }
  target[destSize] = 0;
  return target;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getParamValue>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L4
  mov    %rbx,%rcx
  xor    %edx,%edx
  jmp    L30
  nopl   0x0(%rax)
L58:
  add    $0x1,%rcx
  cmp    %edx,%eax
  je     L3
L30:
  cmpb   $0x3d,(%rcx)
  mov    %edx,%edi
  lea    0x1(%rdx),%edx
  jne    L58
L55:
  lea    0x1(%rdi),%ecx
  cmp    %ecx,%eax
  jbe    L4
  lea    -0x2(%rax),%r8d
  xor    %edx,%edx
  lea    (%rbx,%rcx,1),%rsi
  sub    %edi,%r8d
  xchg   %ax,%ax
L14:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%r12,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%r8
  jne    L14
  sub    $0x1,%eax
  sub    %edi,%eax
  add    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %eax,%edi
  jmp    L55
  nopl   0x0(%rax)
L4:
  mov    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *getParamValue(char *target, const char *str) {
  unsigned int i;
  unsigned int size;
  size = strlen(str);
  unsigned int destSize = 0;
  for (i = 0; i < size; i++) {
    if (str[i] == '=')
      break;
  }
  i++;
  for (; i < size; i++) {
    target[destSize] = str[i];
    destSize++;
  }
  target[destSize] = 0;
  return target;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L26
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  jmp    L58
L26:
  mov    $0x0,%eax
L58:
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0x28(%rbp)
  je     L10
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L41
L10:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  cmpl   $0x0,-0x28(%rbp)
  je     L100
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  jmp    L49
L100:
  mov    $0x0,%eax
L49:
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L40
L78:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0x28(%rbp)
  je     L2
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L40
L2:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L40:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L78
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Rotate(int R[], int C[], int N, int Neg) {
  int Idx, Jdx;
  Jdx = Neg ? 0 : N - 1;
  for (Idx = 0; Idx < N; Neg ? Jdx++ : Jdx--)
    C[Idx++] = R[Jdx];
  Jdx = Neg ? N - 1 : 0;
  for (Idx = 0; Idx < N; Neg ? Jdx-- : Jdx++)
    R[C[Idx++]] = Jdx;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Rotate>:
  endbr64
  mov    %rsi,%r9
  mov    %edx,%r10d
  lea    -0x1(%rdx),%eax
  test   %ecx,%ecx
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %r10d,%r10d
  jle    L14
  mov    %rsi,%rdx
  lea    -0x1(%r10),%esi
  lea    0x4(%r9,%rsi,4),%r8
L9:
  movslq %eax,%rsi
  mov    (%rdi,%rsi,4),%esi
  mov    %esi,(%rdx)
  lea    0x1(%rax),%esi
  sub    $0x1,%eax
  test   %ecx,%ecx
  cmovne %esi,%eax
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L9
  mov    %ecx,%eax
  test   %ecx,%ecx
  je     L43
L35:
  lea    -0x1(%r10),%eax
  test   %r10d,%r10d
  jle    L24
L43:
  mov    %r9,%rdx
  lea    -0x1(%r10),%esi
  lea    0x4(%r9,%rsi,4),%r8
L20:
  movslq (%rdx),%rsi
  mov    %eax,(%rdi,%rsi,4)
  lea    -0x1(%rax),%esi
  add    $0x1,%eax
  test   %ecx,%ecx
  cmovne %esi,%eax
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L20
  ret
L14:
  test   %ecx,%ecx
  jne    L35
  ret
L24:
  ret
```

assistant: ```c
void Rotate(int R[], int C[], int N, int Neg) {
  int Idx, Jdx;
  Jdx = Neg ? 0 : N - 1;
  for (Idx = 0; Idx < N; Neg ? Jdx++ : Jdx--)
    C[Idx++] = R[Jdx];
  Jdx = Neg ? N - 1 : 0;
  for (Idx = 0; Idx < N; Neg ? Jdx-- : Jdx++)
    R[C[Idx++]] = Jdx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Rotate>:
  endbr64
  xor    %eax,%eax
  lea    -0x1(%rdx),%r10d
  test   %ecx,%ecx
  cmove  %r10d,%eax
  test   %edx,%edx
  jle    L3
  mov    %r10d,%r8d
  lea    0x4(%rsi),%r11
  mov    %rsi,%rdx
  lea    (%r11,%r8,4),%r9
  nopw   0x0(%rax,%rax,1)
L19:
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  mov    %r8d,(%rdx)
  lea    0x1(%rax),%r8d
  sub    $0x1,%eax
  test   %ecx,%ecx
  cmovne %r8d,%eax
  add    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L19
  xor    %eax,%eax
  test   %ecx,%ecx
  lea    (%r11,%r10,4),%r8
  mov    %rsi,%rdx
  cmovne %r10d,%eax
  nopw   0x0(%rax,%rax,1)
L1:
  movslq (%rdx),%rsi
  mov    %eax,(%rdi,%rsi,4)
  lea    -0x1(%rax),%esi
  add    $0x1,%eax
  test   %ecx,%ecx
  cmovne %esi,%eax
  add    $0x4,%rdx
  cmp    %rdx,%r8
  jne    L1
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void Rotate(int R[], int C[], int N, int Neg) {
  int Idx, Jdx;
  Jdx = Neg ? 0 : N - 1;
  for (Idx = 0; Idx < N; Neg ? Jdx++ : Jdx--)
    C[Idx++] = R[Jdx];
  Jdx = Neg ? N - 1 : 0;
  for (Idx = 0; Idx < N; Neg ? Jdx-- : Jdx++)
    R[C[Idx++]] = Jdx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<saslc__crypto_md5_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x18(%rbp)
  je     L8
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void saslc__crypto_md5_hash(const char *buf, size_t buflen, unsigned char *digest) {
  assert(digest != NULL);
  if (digest != NULL)
    (void)MD5((const unsigned char *)buf, buflen, digest);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<saslc__crypto_md5_hash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  test   %rdx,%rdx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L1
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <MD5@plt>
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void saslc__crypto_md5_hash(const char *buf, size_t buflen, unsigned char *digest) {
  assert(digest != NULL);
  if (digest != NULL)
    (void)MD5((const unsigned char *)buf, buflen, digest);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<saslc__crypto_md5_hash>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rdx,%rdx
  setne  %dil
  call   <assert@plt>
  test   %r12,%r12
  je     L0
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <MD5@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void saslc__crypto_md5_hash(const char *buf, size_t buflen, unsigned char *digest) {
  assert(digest != NULL);
  if (digest != NULL)
    (void)MD5((const unsigned char *)buf, buflen, digest);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<saslc__crypto_md5_hash>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rdx,%rdx
  setne  %dil
  call   <assert@plt>
  test   %r12,%r12
  je     L6
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <MD5@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void saslc__crypto_md5_hash(const char *buf, size_t buflen, unsigned char *digest) {
  assert(digest != NULL);
  if (digest != NULL)
    (void)MD5((const unsigned char *)buf, buflen, digest);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mvtlolevelirqinstall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <locore_readtbr@plt>
  and    $0xfffff000,%eax
  lea    0x100(%rax),%edx
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  add    %edx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L2
  cmpl   $0xe,-0x14(%rbp)
  jle    L12
L2:
  mov    $0x0,%eax
  jmp    L11
L12:
  mov    -0x10(%rbp),%rax
  shr    $0xa,%rax
  and    $0x3fffff,%eax
  or     $0x29000000,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  and    $0x3ff,%eax
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    $0x81c52000,%edx
  or     %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movq   $0x1000000,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movq   $0x1000000,(%rax)
  mov    $0x1,%eax
L11:
  leave
  ret
```

assistant: ```c
int mvtlolevelirqinstall(int irqnr, void (*handler)()) {
  unsigned long h = (unsigned long)handler;
  unsigned long *addr = (unsigned long *)((locore_readtbr() & ~0xFFF) + 0x100 + (16 * irqnr));
  if (irqnr == 0 || irqnr >= 15) {
    return 0;
  }
  addr[0] = ((h >> 10) & 0x3fffff) | 0x29000000;
  addr[1] = ((h)&0x3ff) | 0x81c52000;
  addr[2] = 0x01000000;
  addr[3] = 0x01000000;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mvtlolevelirqinstall>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <locore_readtbr@plt>
  test   %ebp,%ebp
  je     L19
  cmp    $0xe,%ebp
  jg     L19
  and    $0xfffff000,%eax
  shl    $0x4,%ebp
  lea    0x100(%rax,%rbp,1),%eax
  cltq
  mov    %rbx,%rdx
  shr    $0xa,%rdx
  and    $0x3fffff,%edx
  or     $0x29000000,%rdx
  mov    %rdx,(%rax)
  and    $0x3ff,%ebx
  mov    $0x81c52000,%edx
  or     %rdx,%rbx
  mov    %rbx,0x8(%rax)
  movq   $0x1000000,0x10(%rax)
  movq   $0x1000000,0x18(%rax)
  mov    $0x1,%eax
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%eax
  jmp    L16
```

assistant: ```c
int mvtlolevelirqinstall(int irqnr, void (*handler)()) {
  unsigned long h = (unsigned long)handler;
  unsigned long *addr = (unsigned long *)((locore_readtbr() & ~0xFFF) + 0x100 + (16 * irqnr));
  if (irqnr == 0 || irqnr >= 15) {
    return 0;
  }
  addr[0] = ((h >> 10) & 0x3fffff) | 0x29000000;
  addr[1] = ((h)&0x3ff) | 0x81c52000;
  addr[2] = 0x01000000;
  addr[3] = 0x01000000;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mvtlolevelirqinstall>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <locore_readtbr@plt>
  test   %ebp,%ebp
  je     L16
  cmp    $0xe,%ebp
  jg     L16
  mov    %rbx,%rdx
  shl    $0x4,%ebp
  and    $0xfffff000,%eax
  and    $0x3ff,%ebx
  shr    $0xa,%rdx
  lea    0x100(%rax,%rbp,1),%eax
  and    $0x3fffff,%edx
  cltq
  or     $0x29000000,%rdx
  movq   $0x1000000,0x10(%rax)
  mov    %rdx,(%rax)
  mov    $0x81c52000,%edx
  or     %rdx,%rbx
  movq   $0x1000000,0x18(%rax)
  mov    %rbx,0x8(%rax)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mvtlolevelirqinstall(int irqnr, void (*handler)()) {
  unsigned long h = (unsigned long)handler;
  unsigned long *addr = (unsigned long *)((locore_readtbr() & ~0xFFF) + 0x100 + (16 * irqnr));
  if (irqnr == 0 || irqnr >= 15) {
    return 0;
  }
  addr[0] = ((h >> 10) & 0x3fffff) | 0x29000000;
  addr[1] = ((h)&0x3ff) | 0x81c52000;
  addr[2] = 0x01000000;
  addr[3] = 0x01000000;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mvtlolevelirqinstall>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <locore_readtbr@plt>
  test   %ebp,%ebp
  je     L7
  cmp    $0xe,%ebp
  jg     L7
  mov    %rbx,%rdx
  shl    $0x4,%ebp
  and    $0xfffff000,%eax
  movdqa D1(%rip),%xmm0
  shr    $0xa,%rdx
  lea    0x100(%rax,%rbp,1),%eax
  and    $0x3ff,%ebx
  and    $0x3fffff,%edx
  cltq
  or     $0x29000000,%rdx
  movaps %xmm0,0x10(%rax)
  mov    %rdx,(%rax)
  mov    $0x81c52000,%edx
  or     %rdx,%rbx
  mov    %rbx,0x8(%rax)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: byte[16]

tool: {"D1": [0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00]}

assistant: ```c
int mvtlolevelirqinstall(int irqnr, void (*handler)()) {
  unsigned long h = (unsigned long)handler;
  unsigned long *addr = (unsigned long *)((locore_readtbr() & ~0xFFF) + 0x100 + (16 * irqnr));
  if (irqnr == 0 || irqnr >= 15) {
    return 0;
  }
  addr[0] = ((h >> 10) & 0x3fffff) | 0x29000000;
  addr[1] = ((h)&0x3ff) | 0x81c52000;
  addr[2] = 0x01000000;
  addr[3] = 0x01000000;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D6
data_type: string

tool: D15: author ltw:4/12/2008 d/m/Y


tool: D6: Usage:
	ltwbase64 -s string -t e
	ltwbase64 -s string -t d


assistant: ```c
void help() {
  printf("author ltw:4/12/2008 d/m/Y\n");
  printf("Usage:\n\tltwbase64 -s string -t e\n\tltwbase64 -s string -t d\n");
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string
name: read_data
arguments: label: D7
type: string

tool: D0: author ltw:4/12/2008 d/m/Y


tool: D7: Usage:
	ltwbase64 -s string -t e
	ltwbase64 -s string -t d


assistant: ```c
void help() {
  printf("author ltw:4/12/2008 d/m/Y\n");
  printf("Usage:\n\tltwbase64 -s string -t e\n\tltwbase64 -s string -t d\n");
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D10: author ltw:4/12/2008 d/m/Y


tool: D4: Usage:
	ltwbase64 -s string -t e
	ltwbase64 -s string -t d


assistant: ```c
void help() {
  printf("author ltw:4/12/2008 d/m/Y\n");
  printf("Usage:\n\tltwbase64 -s string -t e\n\tltwbase64 -s string -t d\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<help>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string

tool: D16: author ltw:4/12/2008 d/m/Y


tool: D1: Usage:
	ltwbase64 -s string -t e
	ltwbase64 -s string -t d


assistant: ```c
void help() {
  printf("author ltw:4/12/2008 d/m/Y\n");
  printf("Usage:\n\tltwbase64 -s string -t e\n\tltwbase64 -s string -t d\n");
  exit(0);
}
```