ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<test_manypaths>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <read_standard_target_system@plt>
  mov    $0x0,%eax
  call   <read_standard_start_system@plt>
  mov    $0x0,%eax
  call   <copy_start_solutions_to_container@plt>
  lea    0x4(%rsp),%rdi
  call   <solcon_number_of_standard_solutions@plt>
  mov    0x4(%rsp),%esi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  movsd  D39(%rip),%xmm0
  mov    $0x1,%edi
  call   <ade_manypaths_d@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D39
type_infered: f64
name: extract_symbolic_data
arguments: tag: D36
type_infered: string

tool: D13: 
Tracking many solution paths ...

tool: D10: The solution container has size %d.


tool: D39: 1

tool: D36: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_standard_target_system();
  fail = read_standard_start_system();
  fail = copy_start_solutions_to_container();
  fail = solcon_number_of_standard_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_d(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_standard_solutions();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_manypaths>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %eax,%eax
  call   <read_standard_target_system@plt>
  xor    %eax,%eax
  call   <read_standard_start_system@plt>
  xor    %eax,%eax
  call   <copy_start_solutions_to_container@plt>
  lea    0x4(%rsp),%rdi
  call   <solcon_number_of_standard_solutions@plt>
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  movsd  D5(%rip),%xmm0
  call   <ade_manypaths_d@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D3
data_type: string
name: parse_data
arguments: label: D5
data_type: f64
name: parse_data
arguments: label: D1
data_type: string

tool: D13: 
Tracking many solution paths ...

tool: D3: The solution container has size %d.


tool: D5: 1

tool: D1: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_standard_target_system();
  fail = read_standard_start_system();
  fail = copy_start_solutions_to_container();
  fail = solcon_number_of_standard_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_d(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_standard_solutions();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_manypaths>:
  endbr64
  sub    $0x18,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  xor    %eax,%eax
  call   <read_standard_target_system@plt>
  xor    %eax,%eax
  call   <read_standard_start_system@plt>
  xor    %eax,%eax
  call   <copy_start_solutions_to_container@plt>
  lea    0x4(%rsp),%rdi
  call   <solcon_number_of_standard_solutions@plt>
  mov    0x4(%rsp),%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  mov    $0x1,%edi
  movsd  D16(%rip),%xmm0
  call   <ade_manypaths_d@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <solcon_write_standard_solutions@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D20
datatype: string
name: read_data
arguments: tag: D26
datatype: string
name: read_data
arguments: tag: D16
datatype: f64
name: read_data
arguments: tag: D9
datatype: string

tool: D20: 
Tracking many solution paths ...

tool: D26: The solution container has size %d.


tool: D16: 1

tool: D9: The solutions after Newton's method :

assistant: ```c
void test_manypaths(void) {
  int fail, len;
  printf("\nTracking many solution paths ...\n");
  fail = read_standard_target_system();
  fail = read_standard_start_system();
  fail = copy_start_solutions_to_container();
  fail = solcon_number_of_standard_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_manypaths_d(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_standard_solutions();
}
```
user: What is the c source code of the assembly code below:

```asm
<display_dvector_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  je     L44
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L44:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L46:
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L16:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jle    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void display_dvector_number(double *v, long nl, long nh, char *format, char *name) {
  long i;
  if (name != NULL)
    printf("%s\n", name);
  for (i = nl; i <= nh; i++) {
    printf(format, i);
  }
  putchar('\n');
  for (i = nl; i <= nh; i++) {
    printf(format, v[i]);
  }
  putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<display_dvector_number>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  test   %r8,%r8
  je     L29
  mov    %r8,%rdi
  call   <puts@plt>
L29:
  cmp    %r12,%rbx
  jg     L15
  mov    %rbx,%rbp
L17:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %rbp,%r12
  jge    L17
  mov    $0xa,%edi
  call   <putchar@plt>
L11:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jge    L11
L46:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L46
```

assistant: ```c
void display_dvector_number(double *v, long nl, long nh, char *format, char *name) {
  long i;
  if (name != NULL)
    printf("%s\n", name);
  for (i = nl; i <= nh; i++) {
    printf(format, i);
  }
  putchar('\n');
  for (i = nl; i <= nh; i++) {
    printf(format, v[i]);
  }
  putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<display_dvector_number>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %r8,%r8
  je     L42
  mov    %r8,%rdi
  call   <puts@plt>
L42:
  cmp    %r12,%rbx
  jg     L14
  mov    %rbx,%rbp
  nopl   (%rax)
L16:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jge    L16
  mov    $0xa,%edi
  call   <putchar@plt>
L20:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jge    L20
L27:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
  xchg   %ax,%ax
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L27
```

assistant: ```c
void display_dvector_number(double *v, long nl, long nh, char *format, char *name) {
  long i;
  if (name != NULL)
    printf("%s\n", name);
  for (i = nl; i <= nh; i++) {
    printf(format, i);
  }
  putchar('\n');
  for (i = nl; i <= nh; i++) {
    printf(format, v[i]);
  }
  putchar('\n');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<display_dvector_number>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %r8,%r8
  je     L19
  mov    %r8,%rdi
  call   <puts@plt>
L19:
  cmp    %r12,%rbx
  jg     L36
  mov    %rbx,%rbp
  nopl   (%rax)
L12:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %rbp,%r12
  jge    L12
  mov    $0xa,%edi
  call   <putchar@plt>
L2:
  movsd  (%r14,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jge    L2
L31:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
  xchg   %ax,%ax
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L31
```

assistant: ```c
void display_dvector_number(double *v, long nl, long nh, char *format, char *name) {
  long i;
  if (name != NULL)
    printf("%s\n", name);
  for (i = nl; i <= nh; i++) {
    printf(format, i);
  }
  putchar('\n');
  for (i = nl; i <= nh; i++) {
    printf(format, v[i]);
  }
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: I am thread %d with thread id %X


assistant: ```c
void *run(void *ptr) {
  printf("I am thread %d with thread id %X\n", *(int *)ptr, (unsigned int)pthread_self());
  pthread_exit(NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<run>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <pthread_self@plt>
  mov    %eax,%edx
  mov    (%rbx),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <pthread_exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: I am thread %d with thread id %X


assistant: ```c
void *run(void *ptr) {
  printf("I am thread %d with thread id %X\n", *(int *)ptr, (unsigned int)pthread_self());
  pthread_exit(NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<run>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <pthread_self@plt>
  mov    (%rbx),%esi
  lea    D7(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: I am thread %d with thread id %X


assistant: ```c
void *run(void *ptr) {
  printf("I am thread %d with thread id %X\n", *(int *)ptr, (unsigned int)pthread_self());
  pthread_exit(NULL);
}
```
user: What is the c source code of the assembly code below:

```asm
<run>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  call   <pthread_self@plt>
  mov    (%rbx),%esi
  lea    D3(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: D3: I am thread %d with thread id %X


assistant: ```c
void *run(void *ptr) {
  printf("I am thread %d with thread id %X\n", *(int *)ptr, (unsigned int)pthread_self());
  pthread_exit(NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Is_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L0
L15:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int Is_empty(struct list_node_s *head_p) {
  if (head_p == NULL)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Is_empty>:
  endbr64
  test   %rdi,%rdi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int Is_empty(struct list_node_s *head_p) {
  if (head_p == NULL)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Is_empty>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
```

assistant: ```c
int Is_empty(struct list_node_s *head_p) {
  if (head_p == NULL)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Is_empty>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  sete   %al
  ret
```

assistant: ```c
int Is_empty(struct list_node_s *head_p) {
  if (head_p == NULL)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x20,-0x1c(%rbp)
  movl   $0xffffffc0,-0x18(%rbp)
  movl   $0xa,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <go_south_east@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string
name: extract_symbolic_data
arguments: data_label: D31
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string

tool: D5: Avast! Now at: [%i, %i]


tool: D6: c %p


tool: D31: %p


tool: D14: x %p


tool: D9: %i


assistant: ```c
int main() {
  int latitude = 32;
  int longitude = -64;
  int x = 10;
  int *ConTro = &x;
  go_south_east(&latitude, &longitude);
  printf("Avast! Now at: [%i, %i]\n", latitude, longitude);
  printf("c %p\n", ConTro);
  printf("%p\n", &ConTro);
  printf("x %p\n", &x);
  printf("%i\n", x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x20,0x4(%rsp)
  movl   $0xffffffc0,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  mov    %rbx,0x10(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <go_south_east@plt>
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  lea    D41(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D43
type_infered: string
name: read_data
arguments: data_label: D41
type_infered: string

tool: D1: Avast! Now at: [%i, %i]


tool: D3: c %p


tool: D19: %p


tool: D43: x %p


tool: D41: %i


assistant: ```c
int main() {
  int latitude = 32;
  int longitude = -64;
  int x = 10;
  int *ConTro = &x;
  go_south_east(&latitude, &longitude);
  printf("Avast! Now at: [%i, %i]\n", latitude, longitude);
  printf("c %p\n", ConTro);
  printf("%p\n", &ConTro);
  printf("x %p\n", &x);
  printf("%i\n", x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x8(%rsp),%rsi
  movl   $0x20,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  movl   $0xffffffc0,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  mov    %rbp,0x10(%rsp)
  call   <go_south_east@plt>
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D38
type_infered: string
name: retrieve_data
arguments: data_label: D29
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D44
type_infered: string

tool: D38: Avast! Now at: [%i, %i]


tool: D29: c %p


tool: D12: %p


tool: D10: x %p


tool: D44: %i


assistant: ```c
int main() {
  int latitude = 32;
  int longitude = -64;
  int x = 10;
  int *ConTro = &x;
  go_south_east(&latitude, &longitude);
  printf("Avast! Now at: [%i, %i]\n", latitude, longitude);
  printf("c %p\n", ConTro);
  printf("%p\n", &ConTro);
  printf("x %p\n", &x);
  printf("%i\n", x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x8(%rsp),%rsi
  movl   $0x20,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  movl   $0xffffffc0,0x8(%rsp)
  movl   $0xa,0xc(%rsp)
  mov    %rbp,0x10(%rsp)
  call   <go_south_east@plt>
  mov    0x8(%rsp),%edx
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%esi
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D40
data_type: string
name: unpack_data
arguments: data_label: D30
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D46
data_type: string
name: unpack_data
arguments: data_label: D27
data_type: string

tool: D40: Avast! Now at: [%i, %i]


tool: D30: c %p


tool: D29: %p


tool: D46: x %p


tool: D27: %i


assistant: ```c
int main() {
  int latitude = 32;
  int longitude = -64;
  int x = 10;
  int *ConTro = &x;
  go_south_east(&latitude, &longitude);
  printf("Avast! Now at: [%i, %i]\n", latitude, longitude);
  printf("c %p\n", ConTro);
  printf("%p\n", &ConTro);
  printf("x %p\n", &x);
  printf("%i\n", x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x44(%rbp)
  movl   $0x9,-0x40(%rbp)
  movl   $0xa,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0x8,-0x34(%rbp)
  movl   $0x5,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x16,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <bubble_loop@plt>
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <quick_loop@plt>
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quick_rec@plt>
  mov    -0x1c(%rbp),%r10d
  mov    -0x20(%rbp),%r9d
  mov    -0x24(%rbp),%r8d
  mov    -0x28(%rbp),%edi
  mov    -0x2c(%rbp),%ebx
  mov    -0x30(%rbp),%r11d
  mov    -0x34(%rbp),%ecx
  mov    -0x38(%rbp),%edx
  mov    -0x3c(%rbp),%esi
  mov    -0x40(%rbp),%eax
  push   %r10
  push   %r9
  push   %r8
  push   %rdi
  mov    %ebx,%r9d
  mov    %r11d,%r8d
  mov    %eax,%edi
  call   <check_stack@plt>
  add    $0x20,%rsp
  mov    $0x2775,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int main() {
  int len = 10;
  int A[] = {9, 10, 7, 8, 5, 0, 3, 22, 1, 6};
  bubble_loop(len);
  quick_loop(len);
  quick_rec(A, 0, len - 1);
  check_stack(A[0], A[1], A[2], A[3], A[4], A[5], A[6], A[7], A[8], A[9]);
  return 10101;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x9,(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x16,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x6,0x24(%rsp)
  mov    $0xa,%edi
  call   <bubble_loop@plt>
  mov    $0xa,%edi
  call   <quick_loop@plt>
  mov    %rsp,%rdi
  mov    $0x9,%edx
  mov    $0x0,%esi
  call   <quick_rec@plt>
  mov    0x24(%rsp),%eax
  push   %rax
  mov    0x28(%rsp),%eax
  push   %rax
  mov    0x2c(%rsp),%eax
  push   %rax
  mov    0x30(%rsp),%eax
  push   %rax
  mov    0x34(%rsp),%r9d
  mov    0x30(%rsp),%r8d
  mov    0x2c(%rsp),%ecx
  mov    0x28(%rsp),%edx
  mov    0x24(%rsp),%esi
  mov    0x20(%rsp),%edi
  call   <check_stack@plt>
  add    $0x20,%rsp
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x2775,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int len = 10;
  int A[] = {9, 10, 7, 8, 5, 0, 3, 22, 1, 6};
  bubble_loop(len);
  quick_loop(len);
  quick_rec(A, 0, len - 1);
  check_stack(A[0], A[1], A[2], A[3], A[4], A[5], A[6], A[7], A[8], A[9]);
  return 10101;
}
```