ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<TI_CC_SPIWriteBurstReg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %ecx,%eax
  mov    %esi,%edx
  mov    %dl,-0x38(%rbp)
  mov    %al,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movsbl -0x44(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L27:
  cmp    %rdx,%rsp
  je     L32
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L32:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L22
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L22:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movb   $0x0,-0x29(%rbp)
  movzbl -0x38(%rbp),%eax
  or     $0x40,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L15
L18:
  movsbq -0x29(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsbl -0x29(%rbp),%edx
  lea    0x1(%rdx),%esi
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rdx
  movslq %esi,%rax
  mov    %cl,(%rdx,%rax,1)
  movzbl -0x29(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x29(%rbp)
L15:
  movzbl -0x29(%rbp),%eax
  cmp    -0x44(%rbp),%al
  jl     L18
  movzbl -0x44(%rbp),%eax
  add    $0x1,%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <CC_SPI_Transfer@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void TI_CC_SPIWriteBurstReg(int fd, char addr, char *buffer, char count) {
  uint8_t buf[count + 1];
  uint8_t i = 0;
  buf[0] = (addr | 0x40);
  while (i < count) {
    buf[i + 1] = buffer[i];
    i++;
  }
  CC_SPI_Transfer(fd, buf, 0, count + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<TI_CC_SPIWriteBurstReg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%r8d
  mov    %esi,%r9d
  mov    %rdx,%rsi
  mov    %ecx,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsbl %cl,%eax
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L7:
  cmp    %rdx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L44:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L45
  orq    $0x0,-0x8(%rsp,%rax,1)
L45:
  mov    %rsp,%rdi
  or     $0x40,%r9d
  mov    %r9b,(%rsp)
  test   %cl,%cl
  jle    L30
  mov    $0x0,%eax
L52:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,0x1(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %al,%r10b
  jg     L52
L30:
  add    $0x1,%ecx
  movsbl %cl,%ecx
  mov    $0x0,%edx
  mov    %rdi,%rsi
  mov    %r8d,%edi
  call   <CC_SPI_Transfer@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  leave
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void TI_CC_SPIWriteBurstReg(int fd, char addr, char *buffer, char count) {
  uint8_t buf[count + 1];
  uint8_t i = 0;
  buf[0] = (addr | 0x40);
  while (i < count) {
    buf[i + 1] = buffer[i];
    i++;
  }
  CC_SPI_Transfer(fd, buf, 0, count + 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<TI_CC_SPIWriteBurstReg>:
  endbr64
  push   %rbp
  mov    %edi,%r8d
  mov    %esi,%edi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsbl %cl,%eax
  mov    %rsp,%r9
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r9
  and    $0xfffffffffffffff0,%rcx
  cmp    %r9,%rsp
  je     L121
L76:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r9,%rsp
  jne    L76
L121:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L79
L110:
  or     $0x40,%edi
  mov    %rsp,%r9
  mov    %dil,(%rsp)
  test   %dl,%dl
  jle    L68
  movsbq %dl,%rax
  lea    0x1(%rsp),%rcx
  cmp    $0x8,%eax
  jae    L122
  test   $0x4,%al
  jne    L36
  test   %eax,%eax
  je     L68
  movzbl (%rsi),%edi
  mov    %dil,(%rcx)
  test   $0x2,%al
  jne    L64
  nopw   0x0(%rax,%rax,1)
L68:
  lea    0x1(%rdx),%ecx
  mov    %r9,%rsi
  xor    %edx,%edx
  mov    %r8d,%edi
  movsbl %cl,%ecx
  call   <CC_SPI_Transfer@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L117
  leave
  ret
  nopl   0x0(%rax)
L122:
  mov    (%rsi),%rdi
  mov    %rdi,0x1(%rsp)
  mov    %eax,%edi
  mov    -0x8(%rsi,%rdi,1),%r10
  mov    %r10,-0x8(%rcx,%rdi,1)
  lea    0x8(%rsp),%rdi
  sub    %rdi,%rcx
  sub    %rcx,%rsi
  add    %eax,%ecx
  mov    %ecx,%eax
  shr    $0x3,%eax
  mov    %eax,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L68
  nopl   (%rax)
L79:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L110
L64:
  mov    %eax,%eax
  movzwl -0x2(%rsi,%rax,1),%esi
  mov    %si,-0x2(%rcx,%rax,1)
  jmp    L68
L36:
  mov    (%rsi),%edi
  mov    %eax,%eax
  mov    %edi,(%rcx)
  mov    -0x4(%rsi,%rax,1),%esi
  mov    %esi,-0x4(%rcx,%rax,1)
  jmp    L68
L117:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void TI_CC_SPIWriteBurstReg(int fd, char addr, char *buffer, char count) {
  uint8_t buf[count + 1];
  uint8_t i = 0;
  buf[0] = (addr | 0x40);
  while (i < count) {
    buf[i + 1] = buffer[i];
    i++;
  }
  CC_SPI_Transfer(fd, buf, 0, count + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<TI_CC_SPIWriteBurstReg>:
  endbr64
  push   %rbp
  mov    %edi,%r8d
  mov    %esi,%edi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsbl %cl,%eax
  mov    %rsp,%r9
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r9
  and    $0xfffffffffffffff0,%rcx
  cmp    %r9,%rsp
  je     L108
L15:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r9,%rsp
  jne    L15
L108:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L46
L120:
  or     $0x40,%edi
  mov    %rsp,%r9
  mov    %dil,(%rsp)
  test   %dl,%dl
  jle    L94
  movsbq %dl,%rax
  lea    0x1(%rsp),%rcx
  cmp    $0x8,%eax
  jae    L89
  test   $0x4,%al
  jne    L64
  test   %eax,%eax
  je     L94
  movzbl (%rsi),%edi
  mov    %dil,(%rcx)
  test   $0x2,%al
  jne    L58
  nopw   0x0(%rax,%rax,1)
L94:
  lea    0x1(%rdx),%ecx
  mov    %r9,%rsi
  xor    %edx,%edx
  mov    %r8d,%edi
  movsbl %cl,%ecx
  call   <CC_SPI_Transfer@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  leave
  ret
  nopl   0x0(%rax)
L89:
  mov    (%rsi),%rdi
  mov    %rdi,0x1(%rsp)
  mov    %eax,%edi
  mov    -0x8(%rsi,%rdi,1),%r10
  mov    %r10,-0x8(%rcx,%rdi,1)
  lea    0x8(%rsp),%rdi
  sub    %rdi,%rcx
  sub    %rcx,%rsi
  add    %eax,%ecx
  mov    %ecx,%eax
  shr    $0x3,%eax
  mov    %eax,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L94
  nopl   (%rax)
L46:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L120
L58:
  mov    %eax,%eax
  movzwl -0x2(%rsi,%rax,1),%esi
  mov    %si,-0x2(%rcx,%rax,1)
  jmp    L94
L64:
  mov    (%rsi),%edi
  mov    %eax,%eax
  mov    %edi,(%rcx)
  mov    -0x4(%rsi,%rax,1),%esi
  mov    %esi,-0x4(%rcx,%rax,1)
  jmp    L94
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void TI_CC_SPIWriteBurstReg(int fd, char addr, char *buffer, char count) {
  uint8_t buf[count + 1];
  uint8_t i = 0;
  buf[0] = (addr | 0x40);
  while (i < count) {
    buf[i + 1] = buffer[i];
    i++;
  }
  CC_SPI_Transfer(fd, buf, 0, count + 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8to16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t utf8to16(const char *unicode8, u_int16_t *buf, size_t buflen) {
  size_t len = 0;
  char *pstr;
  errno = EIO;
  return -1;
  if (!unicode8 || !buf || !buflen)
    return 0;
  pstr = (char *)malloc(strlen(unicode8) + 1);
  if (!pstr)
    return -1;
  len = *pstr;
  free(pstr);
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8to16>:
  endbr64
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
size_t utf8to16(const char *unicode8, u_int16_t *buf, size_t buflen) {
  size_t len = 0;
  char *pstr;
  errno = EIO;
  return -1;
  if (!unicode8 || !buf || !buflen)
    return 0;
  pstr = (char *)malloc(strlen(unicode8) + 1);
  if (!pstr)
    return -1;
  len = *pstr;
  free(pstr);
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<utf8to16>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
size_t utf8to16(const char *unicode8, u_int16_t *buf, size_t buflen) {
  size_t len = 0;
  char *pstr;
  errno = EIO;
  return -1;
  if (!unicode8 || !buf || !buflen)
    return 0;
  pstr = (char *)malloc(strlen(unicode8) + 1);
  if (!pstr)
    return -1;
  len = *pstr;
  free(pstr);
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<utf8to16>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
  ret
```

assistant: ```c
size_t utf8to16(const char *unicode8, u_int16_t *buf, size_t buflen) {
  size_t len = 0;
  char *pstr;
  errno = EIO;
  return -1;
  if (!unicode8 || !buf || !buflen)
    return 0;
  pstr = (char *)malloc(strlen(unicode8) + 1);
  if (!pstr)
    return -1;
  len = *pstr;
  free(pstr);
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<window>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void window(float input[], float win_cof[], float output[], int npts) {
  int i;
  for (i = 0; i < npts; i++)
    output[i] = win_cof[i] * input[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<window>:
  endbr64
  test   %ecx,%ecx
  jle    L0
  mov    %ecx,%ecx
  mov    $0x0,%eax
L17:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L17
L0:
  ret
```

assistant: ```c
void window(float input[], float win_cof[], float output[], int npts) {
  int i;
  for (i = 0; i < npts; i++)
    output[i] = win_cof[i] * input[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<window>:
  endbr64
  test   %ecx,%ecx
  jle    L4
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L0:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L0
L4:
  ret
```

assistant: ```c
void window(float input[], float win_cof[], float output[], int npts) {
  int i;
  for (i = 0; i < npts; i++)
    output[i] = win_cof[i] * input[i];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<window>:
  endbr64
  test   %ecx,%ecx
  jle    L52
  lea    0x4(%rdi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  seta   %r8b
  cmp    $0x1,%ecx
  setne  %al
  test   %al,%r8b
  je     L96
  lea    0x4(%rsi),%r8
  mov    %rdx,%rax
  sub    %r8,%rax
  cmp    $0x8,%rax
  jbe    L96
  lea    -0x1(%rcx),%eax
  mov    %ecx,%r9d
  cmp    $0x2,%eax
  jbe    L37
  mov    %ecx,%r8d
  xor    %eax,%eax
  shr    $0x2,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L61:
  movups (%rsi,%rax,1),%xmm0
  movups (%rdi,%rax,1),%xmm2
  mulps  %xmm2,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L61
  mov    %ecx,%r8d
  and    $0xfffffffc,%r8d
  mov    %r8d,%eax
  cmp    %r8d,%ecx
  je     L52
  sub    %r8d,%ecx
  mov    %ecx,%r9d
  cmp    $0x1,%ecx
  je     L21
L33:
  mov    %r8d,%ecx
  movq   (%rsi,%rcx,4),%xmm0
  movq   (%rdi,%rcx,4),%xmm1
  mulps  %xmm1,%xmm0
  movlps %xmm0,(%rdx,%rcx,4)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%r9d
  je     L52
L21:
  cltq
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  ret
  nopl   (%rax)
L96:
  movslq %ecx,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L30:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  movss  %xmm0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L30
L52:
  ret
L37:
  xor    %r8d,%r8d
  xor    %eax,%eax
  jmp    L33
```

assistant: ```c
void window(float input[], float win_cof[], float output[], int npts) {
  int i;
  for (i = 0; i < npts; i++)
    output[i] = win_cof[i] * input[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x200000(%rsp),%r11
L3:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L3
  sub    $0x440,%rsp
  mov    %edi,-0x200434(%rbp)
  mov    %rsi,-0x200440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <iconv_open@plt>
  mov    %eax,-0x200424(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x200420(%rbp)
  movq   $0x400,-0x200418(%rbp)
  mov    -0x200420(%rbp),%rdx
  lea    -0x200010(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x200010(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x200418(%rbp),%rdi
  lea    -0x200410(%rbp),%rcx
  mov    -0x200418(%rbp),%rdx
  lea    -0x200010(%rbp),%rsi
  mov    -0x200424(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <iconv@plt>
  lea    -0x200410(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D46
type: string
name: unpack_data
arguments: data_tag: D16
type: string
name: unpack_data
arguments: data_tag: D33
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D58
type: string

tool: D46: UTF-8

tool: D16: GBK

tool: D33: r

tool: D14: iconv.txt

tool: D58: %s


assistant: ```c
int main(int argc, char **argv) {
  iconv_t cd = iconv_open("GBK", "UTF-8");
  FILE *file = fopen("iconv.txt", "r");
  char ori[2 * 1024 * 1024];
  char out[1024];
  size_t *size = 1024;
  fgets(ori, 1024, file);
  printf("%s\n", ori);
  iconv(cd, &ori, size, &out, size);
  printf("%s\n", out);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x200000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x200408(%rsp)
  xor    %eax,%eax
  lea    D35(%rip),%rsi
  lea    D17(%rip),%rdi
  call   <iconv_open@plt>
  mov    %eax,%ebx
  lea    D23(%rip),%rsi
  lea    D30(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rdx
  lea    0x400(%rsp),%rbp
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rsp,%r13
  mov    $0x400,%r8d
  mov    %r13,%rcx
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <iconv@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x200408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x200418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string
name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D35: UTF-8

tool: D17: GBK

tool: D23: r

tool: D30: iconv.txt

tool: D5: %s


assistant: ```c
int main(int argc, char **argv) {
  iconv_t cd = iconv_open("GBK", "UTF-8");
  FILE *file = fopen("iconv.txt", "r");
  char ori[2 * 1024 * 1024];
  char out[1024];
  size_t *size = 1024;
  fgets(ori, 1024, file);
  printf("%s\n", ori);
  iconv(cd, &ori, size, &out, size);
  printf("%s\n", out);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x200000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x418,%rsp
  lea    D38(%rip),%rsi
  lea    D39(%rip),%rdi
  lea    D20(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x200408(%rsp)
  xor    %eax,%eax
  lea    0x400(%rsp),%r12
  mov    %rsp,%r14
  call   <iconv_open@plt>
  lea    D3(%rip),%rsi
  lea    D44(%rip),%rdi
  mov    %eax,%ebp
  call   <fopen@plt>
  mov    $0x400,%esi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <fgets@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    $0x400,%r8d
  mov    %r14,%rcx
  mov    $0x400,%edx
  call   <iconv@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x200408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x200418,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D38
datatype: string
name: disassemble_data
arguments: tag: D39
datatype: string
name: disassemble_data
arguments: tag: D20
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D44
datatype: string

tool: D38: UTF-8

tool: D39: GBK

tool: D20: %s


tool: D3: r

tool: D44: iconv.txt

assistant: ```c
int main(int argc, char **argv) {
  iconv_t cd = iconv_open("GBK", "UTF-8");
  FILE *file = fopen("iconv.txt", "r");
  char ori[2 * 1024 * 1024];
  char out[1024];
  size_t *size = 1024;
  fgets(ori, 1024, file);
  printf("%s\n", ori);
  iconv(cd, &ori, size, &out, size);
  printf("%s\n", out);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x200000(%rsp),%r11
L12:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L12
  sub    $0x418,%rsp
  lea    D41(%rip),%rsi
  lea    D14(%rip),%rdi
  lea    D36(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x200408(%rsp)
  xor    %eax,%eax
  lea    0x400(%rsp),%r12
  mov    %rsp,%r14
  call   <iconv_open@plt>
  lea    D7(%rip),%rsi
  lea    D44(%rip),%rdi
  mov    %eax,%ebp
  call   <fopen@plt>
  mov    $0x400,%esi
  mov    %r12,%rdi
  mov    %rax,%rdx
  call   <fgets@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    $0x400,%r8d
  mov    %r14,%rcx
  mov    $0x400,%edx
  call   <iconv@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x200408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x200418,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D41
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D36
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D44
type_infered: string

tool: D41: UTF-8

tool: D14: GBK

tool: D36: %s


tool: D7: r

tool: D44: iconv.txt

assistant: ```c
int main(int argc, char **argv) {
  iconv_t cd = iconv_open("GBK", "UTF-8");
  FILE *file = fopen("iconv.txt", "r");
  char ori[2 * 1024 * 1024];
  char out[1024];
  size_t *size = 1024;
  fgets(ori, 1024, file);
  printf("%s\n", ori);
  iconv(cd, &ori, size, &out, size);
  printf("%s\n", out);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sys_err>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void sys_err(const char *str) {
  perror(str);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<sys_err>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sys_err(const char *str) {
  perror(str);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sys_err>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sys_err(const char *str) {
  perror(str);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sys_err>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sys_err(const char *str) {
  perror(str);
  exit(1);
}
```