ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <debug_ol@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <ol@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D18: ; inc

tool: D9: addd	#1

assistant: ```c
inc() {
  debug_ol("; inc");
  ol("addd	#1");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inc>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <debug_ol@plt>
  lea    D3(%rip),%rdi
  call   <ol@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D3
type_infered: string

tool: D10: ; inc

tool: D3: addd	#1

assistant: ```c
inc() {
  debug_ol("; inc");
  ol("addd	#1");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inc>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <debug_ol@plt>
  lea    D16(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <ol@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D8: ; inc

tool: D16: addd	#1

assistant: ```c
inc() {
  debug_ol("; inc");
  ol("addd	#1");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inc>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <debug_ol@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <ol@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string

tool: D17: ; inc

tool: D10: addd	#1

assistant: ```c
inc() {
  debug_ol("; inc");
  ol("addd	#1");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  shr    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  jmp    L16
L17:
  mov    -0x8(%rbp),%rdx
  lea    0x8(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  mov    (%rdx),%rdx
  mov    %rdx,(%rax)
L16:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L17
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy4(void *dest, const void *src, size_t count) {
  unsigned long *tmp = (unsigned long *)dest;
  unsigned long *s = (unsigned long *)src;
  count = count / 4;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy4>:
  endbr64
  mov    %rdi,%rax
  mov    %rdx,%rdi
  shr    $0x2,%rdi
  cmp    $0x3,%rdx
  jbe    L2
  mov    $0x0,%edx
L15:
  mov    (%rsi,%rdx,8),%rcx
  mov    %rcx,(%rax,%rdx,8)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L15
L2:
  ret
```

assistant: ```c
void *memcpy4(void *dest, const void *src, size_t count) {
  unsigned long *tmp = (unsigned long *)dest;
  unsigned long *s = (unsigned long *)src;
  count = count / 4;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy4>:
  endbr64
  shr    $0x2,%rdx
  mov    %rdi,%rax
  je     L8
  xor    %ecx,%ecx
  nop
L17:
  mov    (%rsi,%rcx,8),%r8
  mov    %r8,(%rax,%rcx,8)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L17
L8:
  ret
```

assistant: ```c
void *memcpy4(void *dest, const void *src, size_t count) {
  unsigned long *tmp = (unsigned long *)dest;
  unsigned long *s = (unsigned long *)src;
  count = count / 4;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memcpy4>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  shr    $0x2,%rdi
  lea    -0x1(%rdi),%rax
  je     L36
  lea    0x8(%rsi),%rcx
  cmp    %rcx,%r8
  je     L29
  cmp    $0x2,%rax
  jbe    L29
  shr    $0x3,%rdx
  xor    %eax,%eax
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L10:
  movdqu (%rsi,%rax,1),%xmm0
  add    $0x1,%rcx
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rdx
  jne    L10
  lea    (%rdx,%rdx,1),%rax
  shl    $0x4,%rdx
  lea    (%r8,%rdx,1),%rcx
  add    %rsi,%rdx
  cmp    %rax,%rdi
  je     L36
  mov    (%rdx),%rax
  mov    %rax,(%rcx)
L36:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L29:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rsi,%rax,8),%rdx
  mov    %rdx,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L2
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memcpy4(void *dest, const void *src, size_t count) {
  unsigned long *tmp = (unsigned long *)dest;
  unsigned long *s = (unsigned long *)src;
  count = count / 4;
  while (count--)
    *tmp++ = *s++;
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x22,-0x44(%rbp)
  movb   $0x61,-0x49(%rbp)
  jmp    L12
L40:
  movsbl -0x49(%rbp),%eax
  sub    $0x61,%eax
  cltq
  movzbl -0x49(%rbp),%edx
  mov    %dl,-0x30(%rbp,%rax,1)
  movsbl -0x49(%rbp),%eax
  sub    $0x61,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl -0x49(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x49(%rbp)
L12:
  cmpb   $0x79,-0x49(%rbp)
  jle    L40
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff88888889,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x3,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x4,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    -0x30(%rbp),%rdx
  add    %rdx,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L13
L51:
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x40(%rbp)
  addl   $0x1,-0x48(%rbp)
L13:
  cmpl   $0x4,-0x48(%rbp)
  jle    L51
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x44(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L58
L68:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x4,-0x38(%rbp)
  addl   $0x1,-0x48(%rbp)
L58:
  cmpl   $0x4,-0x48(%rbp)
  jle    L68
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D33
type: string

tool: D1: %c 

tool: D33: pause

assistant: ```c
int main1() {
  char c, arr['z' - 'a'], *pChar;
  int i, *pInt;
  int matr = 34;
  for (c = 'a'; c < 'z'; c++) {
    arr[c - 'a'] = c;
    printf("%c ", arr[c - 'a']);
  }
  printf("\n");
  pChar = arr + matr % 15;
  for (i = 0; i < 5; i++) {
    printf("%c ", *pChar);
    pChar++;
  }
  printf("\n");
  pInt = (int *)arr + matr % 2;
  for (i = 0; i < 5; i++) {
    pChar = (char *)pInt;
    printf("%c ", *pChar);
    pInt++;
  }
  system("pause");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x61,%ebx
  lea    D17(%rip),%rbp
L0:
  mov    %bl,-0x61(%rsp,%rbx,1)
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x7a,%rbx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x4(%rsp),%rbx
  lea    D17(%rip),%rbp
L25:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  lea    0x9(%rsp),%rax
  cmp    %rax,%rbx
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rbx
  lea    D17(%rip),%rbp
L15:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  lea    0x14(%rsp),%rax
  cmp    %rax,%rbx
  jne    L15
  lea    D14(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
datatype: string
name: parse_data
arguments: tag: D14
datatype: string

tool: D17: %c 

tool: D14: pause

assistant: ```c
int main1() {
  char c, arr['z' - 'a'], *pChar;
  int i, *pInt;
  int matr = 34;
  for (c = 'a'; c < 'z'; c++) {
    arr[c - 'a'] = c;
    printf("%c ", arr[c - 'a']);
  }
  printf("\n");
  pChar = arr + matr % 15;
  for (i = 0; i < 5; i++) {
    printf("%c ", *pChar);
    pChar++;
  }
  printf("\n");
  pInt = (int *)arr + matr % 2;
  for (i = 0; i < 5; i++) {
    pChar = (char *)pInt;
    printf("%c ", *pChar);
    pInt++;
  }
  system("pause");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main1>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x61,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x61(%rsp),%r12
  nopl   (%rax)
L31:
  mov    %bl,(%r12,%rbx,1)
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x7a,%rbx
  jne    L31
  mov    $0xa,%edi
  lea    0x4(%rsp),%rbx
  lea    0x9(%rsp),%r12
  call   <putchar@plt>
L13:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
  mov    $0xa,%edi
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  call   <putchar@plt>
L29:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L29
  lea    D17(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D2: %c 

tool: D17: pause

assistant: ```c
int main1() {
  char c, arr['z' - 'a'], *pChar;
  int i, *pInt;
  int matr = 34;
  for (c = 'a'; c < 'z'; c++) {
    arr[c - 'a'] = c;
    printf("%c ", arr[c - 'a']);
  }
  printf("\n");
  pChar = arr + matr % 15;
  for (i = 0; i < 5; i++) {
    printf("%c ", *pChar);
    pChar++;
  }
  printf("\n");
  pInt = (int *)arr + matr % 2;
  for (i = 0; i < 5; i++) {
    pChar = (char *)pInt;
    printf("%c ", *pChar);
    pInt++;
  }
  system("pause");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main1>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  mov    $0x61,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    -0x61(%rsp),%r12
  nopl   (%rax)
L24:
  mov    %bl,(%r12,%rbx,1)
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x7a,%rbx
  jne    L24
  mov    $0xa,%edi
  lea    0x4(%rsp),%rbx
  lea    0x9(%rsp),%r12
  call   <putchar@plt>
L12:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
  mov    $0xa,%edi
  mov    %rsp,%rbx
  lea    0x14(%rsp),%r12
  call   <putchar@plt>
L39:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L39
  lea    D1(%rip),%rdi
  call   <system@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D1
type_guessed: string

tool: D10: %c 

tool: D1: pause

assistant: ```c
int main1() {
  char c, arr['z' - 'a'], *pChar;
  int i, *pInt;
  int matr = 34;
  for (c = 'a'; c < 'z'; c++) {
    arr[c - 'a'] = c;
    printf("%c ", arr[c - 'a']);
  }
  printf("\n");
  pChar = arr + matr % 15;
  for (i = 0; i < 5; i++) {
    printf("%c ", *pChar);
    pChar++;
  }
  printf("\n");
  pInt = (int *)arr + matr % 2;
  for (i = 0; i < 5; i++) {
    pChar = (char *)pInt;
    printf("%c ", *pChar);
    pInt++;
  }
  system("pause");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<swizzle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L5:
  mov    -0x4(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  shrl   -0x14(%rbp)
  shrl   -0x18(%rbp)
L13:
  cmpl   $0x0,-0x18(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned swizzle(unsigned in, unsigned limit) {
  unsigned out = 0;
  while (limit) {
    out = (out << 1) | (in & 1);
    in >>= 1;
    limit >>= 1;
  }
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<swizzle>:
  endbr64
  test   %esi,%esi
  je     L17
  mov    $0x0,%eax
L13:
  add    %eax,%eax
  mov    %edi,%edx
  and    $0x1,%edx
  or     %edx,%eax
  shr    %edi
  shr    %esi
  jne    L13
  ret
L17:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned swizzle(unsigned in, unsigned limit) {
  unsigned out = 0;
  while (limit) {
    out = (out << 1) | (in & 1);
    in >>= 1;
    limit >>= 1;
  }
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swizzle>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L7
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %edi,%edx
  add    %eax,%eax
  shr    %edi
  and    $0x1,%edx
  or     %edx,%eax
  shr    %esi
  jne    L6
  ret
L7:
  ret
```

assistant: ```c
unsigned swizzle(unsigned in, unsigned limit) {
  unsigned out = 0;
  while (limit) {
    out = (out << 1) | (in & 1);
    in >>= 1;
    limit >>= 1;
  }
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swizzle>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L16
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %edi,%edx
  add    %eax,%eax
  shr    %edi
  and    $0x1,%edx
  or     %edx,%eax
  shr    %esi
  jne    L4
  ret
L16:
  ret
```

assistant: ```c
unsigned swizzle(unsigned in, unsigned limit) {
  unsigned out = 0;
  while (limit) {
    out = (out << 1) | (in & 1);
    in >>= 1;
    limit >>= 1;
  }
  return out;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<brsupower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  mov    %edi,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <__ecm_eulerphi@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L15
L13:
  mov    -0x34(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <__ecm_gcd@plt>
  cmp    $0x1,%eax
  jne    L12
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <__ecm_gcd@plt>
  sub    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x30(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <brentsuyama@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L12:
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L13
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double brsupower(double B1, double B2, double N, double nr, int S) {
  int i, f;
  double sum;
  sum = 0;
  f = __ecm_eulerphi(S);
  for (i = 1; i < S; i++)
    if (__ecm_gcd(i, S) == 1)
      sum += brentsuyama(B1, B2, N, nr * (__ecm_gcd(i - 1, S) - 2));
  return sum / (double)f;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<brsupower>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movq   %xmm1,%r13
  movq   %xmm2,%r14
  movsd  %xmm3,0x8(%rsp)
  mov    %edi,%ebp
  call   <__ecm_eulerphi@plt>
  mov    %eax,%r15d
  cmp    $0x1,%ebp
  jle    L40
  mov    D3(%rip),%r12
  mov    $0x1,%ebx
  jmp    L46
L2:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L26
L46:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <__ecm_gcd@plt>
  cmp    $0x1,%eax
  jne    L2
  lea    -0x1(%rbx),%edi
  mov    %ebp,%esi
  call   <__ecm_gcd@plt>
  sub    $0x2,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  mulsd  0x8(%rsp),%xmm3
  movq   %r14,%xmm2
  movq   %r13,%xmm1
  movsd  (%rsp),%xmm0
  call   <brentsuyama@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movq   %r12,%xmm4
  addsd  %xmm0,%xmm4
  movq   %xmm4,%r12
  jmp    L2
L40:
  mov    D3(%rip),%r12
L26:
  pxor   %xmm1,%xmm1
  cvtsi2sd %r15d,%xmm1
  movq   %r12,%xmm0
  divsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double brsupower(double B1, double B2, double N, double nr, int S) {
  int i, f;
  double sum;
  sum = 0;
  f = __ecm_eulerphi(S);
  for (i = 1; i < S; i++)
    if (__ecm_gcd(i, S) == 1)
      sum += brentsuyama(B1, B2, N, nr * (__ecm_gcd(i - 1, S) - 2));
  return sum / (double)f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<brsupower>:
  endbr64
  push   %r15
  movq   %xmm1,%r15
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  movq   %xmm2,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm3,0x8(%rsp)
  call   <__ecm_eulerphi@plt>
  mov    %eax,%r12d
  cmp    $0x1,%ebp
  jle    L19
  pxor   %xmm6,%xmm6
  mov    $0x1,%ebx
  movsd  %xmm6,(%rsp)
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L12
L47:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <__ecm_gcd@plt>
  cmp    $0x1,%eax
  jne    L30
  lea    -0x1(%rbx),%edi
  mov    %ebp,%esi
  add    $0x1,%ebx
  call   <__ecm_gcd@plt>
  pxor   %xmm3,%xmm3
  movq   %r14,%xmm0
  movq   %r13,%xmm2
  sub    $0x2,%eax
  movq   %r15,%xmm1
  cvtsi2sd %eax,%xmm3
  mulsd  0x8(%rsp),%xmm3
  call   <brentsuyama@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    %ebx,%ebp
  jne    L47
L12:
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  cvtsi2sd %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm1,%xmm0
  ret
  nop
L19:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  jmp    L12
```

assistant: ```c
double brsupower(double B1, double B2, double N, double nr, int S) {
  int i, f;
  double sum;
  sum = 0;
  f = __ecm_eulerphi(S);
  for (i = 1; i < S; i++)
    if (__ecm_gcd(i, S) == 1)
      sum += brentsuyama(B1, B2, N, nr * (__ecm_gcd(i - 1, S) - 2));
  return sum / (double)f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<brsupower>:
  endbr64
  push   %r15
  movq   %xmm1,%r15
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  movq   %xmm2,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm3,0x8(%rsp)
  call   <__ecm_eulerphi@plt>
  mov    %eax,%r12d
  cmp    $0x1,%ebp
  jle    L7
  pxor   %xmm6,%xmm6
  mov    $0x1,%ebx
  movsd  %xmm6,(%rsp)
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L58
L26:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <__ecm_gcd@plt>
  cmp    $0x1,%eax
  jne    L34
  lea    -0x1(%rbx),%edi
  mov    %ebp,%esi
  add    $0x1,%ebx
  call   <__ecm_gcd@plt>
  pxor   %xmm3,%xmm3
  movq   %r14,%xmm0
  movq   %r13,%xmm2
  sub    $0x2,%eax
  movq   %r15,%xmm1
  cvtsi2sd %eax,%xmm3
  mulsd  0x8(%rsp),%xmm3
  call   <brentsuyama@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    %ebx,%ebp
  jne    L26
L58:
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  cvtsi2sd %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  divsd  %xmm1,%xmm0
  ret
  nop
L7:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,(%rsp)
  jmp    L58
```

assistant: ```c
double brsupower(double B1, double B2, double N, double nr, int S) {
  int i, f;
  double sum;
  sum = 0;
  f = __ecm_eulerphi(S);
  for (i = 1; i < S; i++)
    if (__ecm_gcd(i, S) == 1)
      sum += brentsuyama(B1, B2, N, nr * (__ecm_gcd(i - 1, S) - 2));
  return sum / (double)f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<onAlarm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <printBuffer@plt>
  mov    $0x1e,%edi
  call   <alarm@plt>
  nop
  leave
  ret
```

assistant: ```c
void onAlarm(int signum) {
  printBuffer();
  alarm(30);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<onAlarm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <printBuffer@plt>
  mov    $0x1e,%edi
  call   <alarm@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void onAlarm(int signum) {
  printBuffer();
  alarm(30);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<onAlarm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <printBuffer@plt>
  mov    $0x1e,%edi
  add    $0x8,%rsp
  jmp    1060 <alarm@plt>
```

assistant: ```c
void onAlarm(int signum) {
  printBuffer();
  alarm(30);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<onAlarm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <printBuffer@plt>
  mov    $0x1e,%edi
  add    $0x8,%rsp
  jmp    1060 <alarm@plt>
```

assistant: ```c
void onAlarm(int signum) {
  printBuffer();
  alarm(30);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D5(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: f32

tool: D5: 5

assistant: ```c
int main(void) {
  float x = 5;
  float *p = (float *)&x;
  *p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  float x = 5;
  float *p = (float *)&x;
  *p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  float x = 5;
  float *p = (float *)&x;
  *p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  float x = 5;
  float *p = (float *)&x;
  *p;
}
```