ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<datawrite>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L2
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r14
  lea    0x7(%rsp),%r12
  jmp    L3
L7:
  mov    %r12,%rdi
  call   <_strupr@plt>
  mov    %rax,%rdi
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  call   <fwrite@plt>
  movsbw 0x7(%rsp),%ax
  movsbw 0x8(%rsp),%dx
  add    %edx,%eax
  add    %ax,0x0(%rbp)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L2
L3:
  movzbl (%rbx),%edi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <_itoa@plt>
  cmpb   $0x0,0x8(%rsp)
  jne    L7
  movzbl 0x7(%rsp),%eax
  mov    %al,0x8(%rsp)
  movb   $0x30,0x7(%rsp)
  jmp    L7
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void datawrite(unsigned char *buf, int len, FILE *fp, unsigned short *chk) {
  int i, n;
  char charbuffer[1];
  char *charbufferp;
  for (i = 0; i < len; i++) {
    n = (unsigned char)buf[i];
    _itoa(n, charbuffer, 16);
    if (charbuffer[1] == 0) {
      charbuffer[1] = charbuffer[0];
      charbuffer[0] = '0';
    }
    charbufferp = _strupr(charbuffer);
    fwrite(charbufferp, 2, 1, fp);
    *chk += charbuffer[0];
    *chk += charbuffer[1];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<datawrite>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rax,1),%r14
  lea    0x7(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L11:
  movzbl (%rbx),%edi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <_itoa@plt>
  cmpb   $0x0,0x8(%rsp)
  jne    L32
  movzbl 0x7(%rsp),%eax
  movb   $0x30,0x7(%rsp)
  mov    %al,0x8(%rsp)
L32:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <_strupr@plt>
  mov    $0x1,%edx
  mov    %r13,%rcx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  movsbw 0x8(%rsp),%dx
  movsbw 0x7(%rsp),%ax
  add    %edx,%eax
  add    %ax,0x0(%rbp)
  cmp    %r14,%rbx
  jne    L11
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void datawrite(unsigned char *buf, int len, FILE *fp, unsigned short *chk) {
  int i, n;
  char charbuffer[1];
  char *charbufferp;
  for (i = 0; i < len; i++) {
    n = (unsigned char)buf[i];
    _itoa(n, charbuffer, 16);
    if (charbuffer[1] == 0) {
      charbuffer[1] = charbuffer[0];
      charbuffer[0] = '0';
    }
    charbufferp = _strupr(charbuffer);
    fwrite(charbufferp, 2, 1, fp);
    *chk += charbuffer[0];
    *chk += charbuffer[1];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<datawrite>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  mov    %rdx,%r13
  mov    %rcx,%rbp
  mov    %rdi,%rbx
  lea    0x1(%rdi,%rax,1),%r14
  lea    0x7(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L29:
  movzbl (%rbx),%edi
  mov    $0x10,%edx
  mov    %r12,%rsi
  call   <_itoa@plt>
  cmpb   $0x0,0x8(%rsp)
  jne    L52
  movzbl 0x7(%rsp),%eax
  mov    %r12,%rdi
  movb   $0x30,0x7(%rsp)
  add    $0x1,%rbx
  mov    %al,0x8(%rsp)
  call   <_strupr@plt>
  mov    $0x1,%edx
  mov    %r13,%rcx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  movsbw 0x8(%rsp),%dx
  movsbw 0x7(%rsp),%ax
  add    %edx,%eax
  add    %ax,0x0(%rbp)
  cmp    %rbx,%r14
  jne    L29
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <_strupr@plt>
  mov    $0x1,%edx
  mov    %r13,%rcx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  movsbw 0x8(%rsp),%dx
  movsbw 0x7(%rsp),%ax
  add    %edx,%eax
  add    %ax,0x0(%rbp)
  cmp    %r14,%rbx
  jne    L29
  jmp    L9
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void datawrite(unsigned char *buf, int len, FILE *fp, unsigned short *chk) {
  int i, n;
  char charbuffer[1];
  char *charbufferp;
  for (i = 0; i < len; i++) {
    n = (unsigned char)buf[i];
    _itoa(n, charbuffer, 16);
    if (charbuffer[1] == 0) {
      charbuffer[1] = charbuffer[0];
      charbuffer[0] = '0';
    }
    charbufferp = _strupr(charbuffer);
    fwrite(charbufferp, 2, 1, fp);
    *chk += charbuffer[0];
    *chk += charbuffer[1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pl_strisalnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L7
  mov    -0x4(%rbp),%eax
  jmp    L28
L7:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    $0xffffffff,%eax
L28:
  leave
  ret
```

assistant: ```c
int pl_strisalnum(const char *s) {
  for (int i = 0; s[i] != '\0'; ++i) {
    if (isalnum(s[i])) {
      return i;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<pl_strisalnum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L23
  mov    $0x0,%ebx
L36:
  mov    %ebx,%r12d
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L29
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L36
  mov    $0xffffffff,%r12d
L29:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%r12d
  jmp    L29
```

assistant: ```c
int pl_strisalnum(const char *s) {
  for (int i = 0; s[i] != '\0'; ++i) {
    if (isalnum(s[i])) {
      return i;
    }
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pl_strisalnum>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L38
  xor    %ebx,%ebx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L38
L7:
  mov    %ebx,%r12d
  call   <isalnum@plt>
  test   %rax,%rax
  je     L11
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int pl_strisalnum(const char *s) {
  for (int i = 0; s[i] != '\0'; ++i) {
    if (isalnum(s[i])) {
      return i;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pl_strisalnum>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L1
  xor    %ebx,%ebx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L1
L2:
  mov    %ebx,%r12d
  call   <isalnum@plt>
  test   %rax,%rax
  je     L4
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int pl_strisalnum(const char *s) {
  for (int i = 0; s[i] != '\0'; ++i) {
    if (isalnum(s[i])) {
      return i;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<sendmsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sendmsg(int sockfd, const struct msghdr *msg, int flags) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sendmsg>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sendmsg(int sockfd, const struct msghdr *msg, int flags) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sendmsg>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sendmsg(int sockfd, const struct msghdr *msg, int flags) {
  errno = ENOSYS;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendmsg>:
  endbr64
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int sendmsg(int sockfd, const struct msghdr *msg, int flags) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  movl   $0x4,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x3,%ecx
  mov    $0xd,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getfirstocc@plt>
  mov    %eax,-0x38(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x3,%ecx
  mov    $0xd,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getlastocc@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d%d

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 3, 3, 3, 3, 3, 3, 4, 5, 5, 5, 5};
  int i = getfirstocc(a, 0, 13, 3);
  int j = getlastocc(a, 0, 13, 3);
  printf("%d%d", i, j);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x3,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0x4,0x24(%rsp)
  mov    %rsp,%rbp
  mov    $0x3,%ecx
  mov    $0xd,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <getfirstocc@plt>
  mov    %eax,%ebx
  mov    $0x3,%ecx
  mov    $0xd,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <getlastocc@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: %d%d

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 3, 3, 3, 3, 3, 3, 4, 5, 5, 5, 5};
  int i = getfirstocc(a, 0, 13, 3);
  int j = getlastocc(a, 0, 13, 3);
  printf("%d%d", i, j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x3,%ecx
  mov    $0xd,%edx
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%r12
  mov    %r12,%rdi
  mov    %rax,(%rsp)
  movabs $0x300000003,%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x20(%rsp)
  call   <getfirstocc@plt>
  xor    %esi,%esi
  mov    $0xd,%edx
  mov    %r12,%rdi
  mov    $0x3,%ecx
  mov    %eax,%ebp
  call   <getlastocc@plt>
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: %d%d

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 3, 3, 3, 3, 3, 3, 4, 5, 5, 5, 5};
  int i = getfirstocc(a, 0, 13, 3);
  int j = getlastocc(a, 0, 13, 3);
  printf("%d%d", i, j);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x3,%ecx
  mov    $0xd,%edx
  push   %rbp
  sub    $0x38,%rsp
  movdqa D39(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    D20(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D12(%rip),%xmm0
  mov    %r12,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <getfirstocc@plt>
  xor    %esi,%esi
  mov    $0xd,%edx
  mov    %r12,%rdi
  mov    $0x3,%ecx
  mov    %eax,%ebp
  call   <getlastocc@plt>
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D39
data_type: byte[16]
name: parse_data
arguments: label: D20
data_type: byte[8]
name: parse_data
arguments: label: D12
data_type: byte[16]
name: parse_data
arguments: label: D6
data_type: string

tool: {"D39": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D20": [0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D12": [0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D6: %d%d

assistant: ```c
int main(void) {
  int a[10] = {1, 2, 3, 3, 3, 3, 3, 3, 3, 4, 5, 5, 5, 5};
  int i = getfirstocc(a, 0, 13, 3);
  int j = getlastocc(a, 0, 13, 3);
  printf("%d%d", i, j);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gaussian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L10
L1:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L1
  movsd  -0x8(%rbp),%xmm0
  movq   D0(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x38(%rbp),%xmm2
  divsd  %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: f32[2]

tool: {"D0": [0.0,-0.0]}

assistant: ```c
double gaussian(double *x, double *y, int n, double sigma) {
  int i;
  double d = 0.0;
  for (i = 0; i < n; i++)
    d += pow(x[i] - y[i], 2);
  return exp(-d / (2 * pow(sigma, 2)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gaussian>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%r14
  test   %edx,%edx
  jle    L4
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
L13:
  movsd  (%r12,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L13
L6:
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm0
  xorpd  D9(%rip),%xmm0
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  call   <exp@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L6
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: f32[4]

tool: {"D9": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double gaussian(double *x, double *y, int n, double sigma) {
  int i;
  double d = 0.0;
  for (i = 0; i < n; i++)
    d += pow(x[i] - y[i], 2);
  return exp(-d / (2 * pow(sigma, 2)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gaussian>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L9
  mov    %rdi,%r13
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L11:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  add    $0x1,%rbx
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %eax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L11
  xorpd  D15(%rip),%xmm1
  movq   %xmm1,%rbx
L24:
  movq   %r14,%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm1
  add    $0x10,%rsp
  add    %eax,%eax
  pop    %rbx
  pop    %rbp
  cvtsi2sd %eax,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  jmp    1070 <exp@plt>
  nopl   0x0(%rax)
L9:
  mov    D15(%rip),%rbx
  jmp    L24
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type_infered: f32[4]

tool: {"D15": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double gaussian(double *x, double *y, int n, double sigma) {
  int i;
  double d = 0.0;
  for (i = 0; i < n; i++)
    d += pow(x[i] - y[i], 2);
  return exp(-d / (2 * pow(sigma, 2)));
}
```
user: What is the c source code of the assembly code below:

```asm
<gaussian>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %edx,%edx
  jle    L10
  mov    %rdi,%r13
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L18:
  movsd  0x0(%r13,%rbx,8),%xmm0
  subsd  (%r12,%rbx,8),%xmm0
  add    $0x1,%rbx
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %eax,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rbp
  jne    L18
  xorpd  D15(%rip),%xmm1
  movq   %xmm1,%rbx
L27:
  movq   %r14,%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movq   %rbx,%xmm1
  add    $0x10,%rsp
  add    %eax,%eax
  pop    %rbx
  pop    %rbp
  cvtsi2sd %eax,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  divsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  jmp    1070 <exp@plt>
  nopl   0x0(%rax)
L10:
  mov    D15(%rip),%rbx
  jmp    L27
```

tool_calls: name: unpack_data
arguments: data_tag: D15
type: f32[4]

tool: {"D15": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double gaussian(double *x, double *y, int n, double sigma) {
  int i;
  double d = 0.0;
  for (i = 0; i < n; i++)
    d += pow(x[i] - y[i], 2);
  return exp(-d / (2 * pow(sigma, 2)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movb   $0x2,-0xa(%rbp)
  movzbl -0xa(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsbl -0x9(%rbp),%edx
  movsbl -0xa(%rbp),%eax
  add    %edx,%eax
  cmp    $0xa,%eax
  je     L3
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D24: Probleme d'allocation memoire !


tool: D13: Probleme de multiplication !


tool: D29: Tout va bien !


assistant: ```c
int main(void) {
  char *s = NULL;
  char a, b;
  s = malloc(10 * sizeof(char));
  a = b = 2;
  printf("Probleme d'allocation memoire !\n");
  if (a + 1 * b + 2 != 12)
    printf("Probleme de multiplication !\n");
  else
    ;
  printf("Tout va bien !\n");
  free(s);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string
name: retrieve_data
arguments: data_label: D24
datatype: string

tool: D21: Probleme d'allocation memoire !


tool: D12: Probleme de multiplication !


tool: D24: Tout va bien !


assistant: ```c
int main(void) {
  char *s = NULL;
  char a, b;
  s = malloc(10 * sizeof(char));
  a = b = 2;
  printf("Probleme d'allocation memoire !\n");
  if (a + 1 * b + 2 != 12)
    printf("Probleme de multiplication !\n");
  else
    ;
  printf("Tout va bien !\n");
  free(s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  call   <malloc@plt>
  lea    D9(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type: string
name: extract_symbolic_data
arguments: data_tag: D5
type: string
name: extract_symbolic_data
arguments: data_tag: D10
type: string

tool: D9: Probleme d'allocation memoire !


tool: D5: Probleme de multiplication !


tool: D10: Tout va bien !


assistant: ```c
int main(void) {
  char *s = NULL;
  char a, b;
  s = malloc(10 * sizeof(char));
  a = b = 2;
  printf("Probleme d'allocation memoire !\n");
  if (a + 1 * b + 2 != 12)
    printf("Probleme de multiplication !\n");
  else
    ;
  printf("Tout va bien !\n");
  free(s);
  return 0;
}
```