ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<simple_strtoul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L160
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %edx,%r12d
  cmpb   $0x30,(%rdi)
  je     L90
  test   %edx,%edx
  mov    $0xa,%eax
  cmove  %eax,%r12d
L17:
  mov    $0x0,%ebp
  mov    %r12d,%r12d
  jmp    L112
L90:
  lea    0x1(%rdi),%rbp
  cmpb   $0x78,0x1(%rdi)
  je     L46
L42:
  test   %r12d,%r12d
  je     L30
L154:
  mov    %rbp,%rbx
  jmp    L17
L46:
  movsbl 0x2(%rdi),%edi
  call   <_isxdigit@plt>
  test   %rax,%rax
  je     L42
  lea    0x2(%rbx),%rbp
  mov    $0x10,%r12d
  jmp    L154
L30:
  mov    %rbp,%rbx
  mov    $0x8,%r12d
  jmp    L17
L48:
  movsbl (%rbx),%edi
  call   <_islower@plt>
  test   %rax,%rax
  jne    L89
  movsbl (%rbx),%eax
  sub    $0x37,%eax
  cltq
L57:
  cmp    %rax,%r12
  jbe    L116
  imul   %r12,%rbp
  add    %rax,%rbp
  add    $0x1,%rbx
L112:
  movsbl (%rbx),%edi
  call   <_isxdigit@plt>
  test   %rax,%rax
  je     L116
  movsbl (%rbx),%edi
  call   <_isdigit@plt>
  test   %rax,%rax
  je     L48
  movsbl (%rbx),%eax
  sub    $0x30,%eax
  cltq
  jmp    L57
L89:
  movsbl (%rbx),%edi
  call   <_toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L57
L116:
  test   %r13,%r13
  je     L135
  mov    %rbx,0x0(%r13)
L135:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L160:
  mov    $0x0,%ebp
  jmp    L135
```

assistant: ```c
unsigned long simple_strtoul(const char *cp, char **endp, unsigned int base) {
  unsigned long result = 0, value;
  if (!cp)
    return 0;
  if (*cp == '0') {
    cp++;
    if ((*cp == 'x') && _isxdigit(cp[1])) {
      base = 16;
      cp++;
    }
    if (!base) {
      base = 8;
    }
  }
  if (!base) {
    base = 10;
  }
  while (_isxdigit(*cp) && (value = _isdigit(*cp) ? *cp - '0' : (_islower(*cp) ? _toupper(*cp) : *cp) - 'A' + 10) < base) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (char *)cp;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<simple_strtoul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L44
  mov    %rdi,%r13
  movsbl (%rdi),%edi
  mov    %rsi,%rbp
  cmp    $0x30,%dil
  je     L107
  test   %edx,%edx
  mov    $0xa,%eax
  cmove  %eax,%edx
L124:
  xor    %r12d,%r12d
  mov    %edx,%ebx
  jmp    L122
  nopl   0x0(%rax,%rax,1)
L76:
  movsbl 0x0(%r13),%eax
  sub    $0x30,%eax
  cltq
L12:
  cmp    %rax,%rbx
  jbe    L83
L110:
  imul   %rbx,%r12
  movsbl 0x1(%r13),%edi
  add    $0x1,%r13
  add    %rax,%r12
L122:
  call   <_isxdigit@plt>
  test   %rax,%rax
  je     L83
  movsbl 0x0(%r13),%edi
  call   <_isdigit@plt>
  test   %rax,%rax
  jne    L76
  movsbl 0x0(%r13),%edi
  call   <_islower@plt>
  test   %rax,%rax
  jne    L71
  movsbl 0x0(%r13),%eax
  sub    $0x37,%eax
  cltq
  cmp    %rax,%rbx
  ja     L110
  cs nopw 0x0(%rax,%rax,1)
L83:
  test   %rbp,%rbp
  je     L7
  mov    %r13,0x0(%rbp)
L7:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  movsbl 0x0(%r13),%edi
  call   <_toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L107:
  cmpb   $0x78,0x1(%r13)
  lea    0x1(%r13),%r12
  je     L50
L103:
  movsbl 0x1(%r13),%edi
  mov    %r12,%r13
  test   %edx,%edx
  jne    L124
  mov    $0x8,%edx
  jmp    L124
  nopl   (%rax)
L44:
  add    $0x18,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  movsbl 0x2(%r13),%edi
  mov    %edx,0xc(%rsp)
  call   <_isxdigit@plt>
  mov    0xc(%rsp),%edx
  test   %rax,%rax
  je     L103
  movsbl 0x2(%r13),%edi
  mov    $0x10,%edx
  add    $0x2,%r13
  jmp    L124
```

assistant: ```c
unsigned long simple_strtoul(const char *cp, char **endp, unsigned int base) {
  unsigned long result = 0, value;
  if (!cp)
    return 0;
  if (*cp == '0') {
    cp++;
    if ((*cp == 'x') && _isxdigit(cp[1])) {
      base = 16;
      cp++;
    }
    if (!base) {
      base = 8;
    }
  }
  if (!base) {
    base = 10;
  }
  while (_isxdigit(*cp) && (value = _isdigit(*cp) ? *cp - '0' : (_islower(*cp) ? _toupper(*cp) : *cp) - 'A' + 10) < base) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (char *)cp;
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<simple_strtoul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L121
  cmpb   $0x30,(%rdi)
  mov    %rdi,%r13
  mov    %rsi,%rbp
  je     L104
  test   %edx,%edx
  mov    $0xa,%eax
  cmove  %eax,%edx
L35:
  xor    %r12d,%r12d
  mov    %edx,%ebx
  jmp    L60
  nopw   0x0(%rax,%rax,1)
L48:
  movsbl 0x0(%r13),%eax
  sub    $0x30,%eax
  cltq
L11:
  cmp    %rax,%rbx
  jbe    L67
L124:
  imul   %rbx,%r12
  add    $0x1,%r13
  add    %rax,%r12
L60:
  movsbl 0x0(%r13),%edi
  call   <_isxdigit@plt>
  test   %rax,%rax
  je     L67
  movsbl 0x0(%r13),%edi
  call   <_isdigit@plt>
  test   %rax,%rax
  jne    L48
  movsbl 0x0(%r13),%edi
  call   <_islower@plt>
  test   %rax,%rax
  jne    L98
  movsbl 0x0(%r13),%eax
  sub    $0x37,%eax
  cltq
  cmp    %rax,%rbx
  ja     L124
  cs nopw 0x0(%rax,%rax,1)
L67:
  test   %rbp,%rbp
  je     L69
  mov    %r13,0x0(%rbp)
L69:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L98:
  movsbl 0x0(%r13),%edi
  call   <_toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L104:
  cmpb   $0x78,0x1(%rdi)
  lea    0x1(%rdi),%r12
  je     L106
L74:
  test   %edx,%edx
  mov    $0x8,%eax
  mov    %r12,%r13
  cmove  %eax,%edx
  jmp    L35
  nopl   0x0(%rax)
L121:
  add    $0x18,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L106:
  movsbl 0x2(%rdi),%edi
  mov    %edx,0xc(%rsp)
  call   <_isxdigit@plt>
  mov    0xc(%rsp),%edx
  test   %rax,%rax
  je     L74
  add    $0x2,%r13
  mov    $0x10,%edx
  jmp    L35
```

assistant: ```c
unsigned long simple_strtoul(const char *cp, char **endp, unsigned int base) {
  unsigned long result = 0, value;
  if (!cp)
    return 0;
  if (*cp == '0') {
    cp++;
    if ((*cp == 'x') && _isxdigit(cp[1])) {
      base = 16;
      cp++;
    }
    if (!base) {
      base = 8;
    }
  }
  if (!base) {
    base = 10;
  }
  while (_isxdigit(*cp) && (value = _isdigit(*cp) ? *cp - '0' : (_islower(*cp) ? _toupper(*cp) : *cp) - 'A' + 10) < base) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (char *)cp;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L9
  mov    $0x1,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L9:
  movl   $0x0,-0x14(%rbp)
  jmp    L65
L24:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %ax,-0x16(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzwl -0x16(%rbp),%edx
  mov    %dx,-0xc(%rbp,%rax,2)
  addl   $0x1,-0x14(%rbp)
L65:
  cmpl   $0x0,-0x14(%rbp)
  jle    L24
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzwl -0xa(%rbp),%eax
  cmp    $0x1ad0,%ax
  jne    L28
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L28:
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L41:
  mov    -0x10(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L33:
  cmpl   $0x0,-0x10(%rbp)
  jle    L41
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D28
type: string

tool: D8: Call this program with %i arguments


tool: D20: You win!

tool: D28: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6864) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L23
L3:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %ax,0x4(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpw   $0x1ad0,0x6(%rsp)
  je     L28
L4:
  movzwl 0x6(%rsp),%esi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    $0x1,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L3
L28:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_infered: string
name: extract_symbolic_data
arguments: tag: D24
type_infered: string
name: extract_symbolic_data
arguments: tag: D22
type_infered: string

tool: D16: %u


tool: D24: Call this program with %i arguments


tool: D22: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6864) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L34
  lea    D3(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L34:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0x1ad0,%si
  je     L37
L22:
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L37:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L22
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string
name: unpack_data
arguments: data_tag: D26
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string

tool: D3: Call this program with %i arguments


tool: D26: %u


tool: D25: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6864) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L28
  lea    D21(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L28:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0x1ad0,%si
  je     L29
L16:
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L29:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L16
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D21
data_type: string
name: disassemble_data
arguments: data_label: D9
data_type: string
name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D21: Call this program with %i arguments


tool: D9: %u


tool: D2: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 6864) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Crypto_Exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ERR_free_strings@plt>
  mov    $0x0,%edi
  call   <ERR_remove_state@plt>
  mov    $0x0,%eax
  call   <EVP_cleanup@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Crypto_Exit() {
  ERR_free_strings();
  ERR_remove_state(0);
  EVP_cleanup();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Crypto_Exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ERR_free_strings@plt>
  mov    $0x0,%edi
  call   <ERR_remove_state@plt>
  mov    $0x0,%eax
  call   <EVP_cleanup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Crypto_Exit() {
  ERR_free_strings();
  ERR_remove_state(0);
  EVP_cleanup();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Crypto_Exit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ERR_free_strings@plt>
  xor    %edi,%edi
  call   <ERR_remove_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <EVP_cleanup@plt>
```

assistant: ```c
void Crypto_Exit() {
  ERR_free_strings();
  ERR_remove_state(0);
  EVP_cleanup();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Crypto_Exit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ERR_free_strings@plt>
  xor    %edi,%edi
  call   <ERR_remove_state@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <EVP_cleanup@plt>
```

assistant: ```c
void Crypto_Exit() {
  ERR_free_strings();
  ERR_remove_state(0);
  EVP_cleanup();
}
```
user: Translate the below assembly code into C programming language:

```asm
<debug_step_03>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int debug_step_03(int y) {
  int x = y;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<debug_step_03>:
  endbr64
  lea    0xa(%rdi),%eax
  ret
```

assistant: ```c
int debug_step_03(int y) {
  int x = y;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<debug_step_03>:
  endbr64
  lea    0xa(%rdi),%eax
  ret
```

assistant: ```c
int debug_step_03(int y) {
  int x = y;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<debug_step_03>:
  endbr64
  lea    0xa(%rdi),%eax
  ret
```

assistant: ```c
int debug_step_03(int y) {
  int x = y;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  x++;
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L46:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L4
  mov    -0x8(%rbp),%rax
  jmp    L40
L4:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  jmp    L41
L2:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x0,(%rax)
L41:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
L40:
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  char *ret = dst;
  do {
    if (!n--) {
      return ret;
    }
  } while ((*dst++ = *src++));
  while (n--) {
    *dst++ = '\0';
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  lea    (%rsi,%rdx,1),%r10
  mov    %rdi,%r9
  jmp    L20
L5:
  mov    %rcx,%r9
L20:
  mov    %rdx,%r11
  sub    $0x1,%rdx
  cmp    %rsi,%r10
  je     L13
  add    $0x1,%rsi
  lea    0x1(%r9),%rcx
  movzbl -0x1(%rsi),%r8d
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  jne    L5
  test   %rdx,%rdx
  je     L13
  add    %r11,%r9
L40:
  add    $0x1,%rcx
  movb   $0x0,-0x1(%rcx)
  cmp    %rcx,%r9
  jne    L40
L13:
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  char *ret = dst;
  do {
    if (!n--) {
      return ret;
    }
  } while ((*dst++ = *src++));
  while (n--) {
    *dst++ = '\0';
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncpy>:
  endbr64
  push   %r12
  lea    (%rsi,%rdx,1),%rcx
  mov    %rdi,%r12
  jmp    L47
  nop
L11:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  test   %al,%al
  je     L21
L47:
  sub    $0x1,%rdx
  cmp    %rcx,%rsi
  jne    L11
L16:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L21:
  test   %rdx,%rdx
  je     L16
  xor    %esi,%esi
  call   <memset@plt>
  jmp    L16
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  char *ret = dst;
  do {
    if (!n--) {
      return ret;
    }
  } while ((*dst++ = *src++));
  while (n--) {
    *dst++ = '\0';
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncpy>:
  endbr64
  push   %r12
  lea    (%rsi,%rdx,1),%rcx
  mov    %rdi,%r12
  jmp    L15
  nop
L8:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  test   %al,%al
  je     L18
L15:
  sub    $0x1,%rdx
  cmp    %rcx,%rsi
  jne    L8
L14:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  test   %rdx,%rdx
  je     L14
  xor    %esi,%esi
  call   <memset@plt>
  jmp    L14
```

assistant: ```c
char *strncpy(char *dst, const char *src, size_t n) {
  char *ret = dst;
  do {
    if (!n--) {
      return ret;
    }
  } while ((*dst++ = *src++));
  while (n--) {
    *dst++ = '\0';
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<E_ToMinusPiPlusPi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <E_ToZeroTwoPi@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    D5(%rip),%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L15
  mov    D5(%rip),%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L12
L15:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L12:
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double E_ToMinusPiPlusPi(double input) {
  double zero_2pi;
  double res = 0.0;
  zero_2pi = E_ToZeroTwoPi(input);
  if (zero_2pi > M_PI)
    res = -(2.0 * M_PI) + zero_2pi;
  else
    res = zero_2pi;
  return res;
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<E_ToMinusPiPlusPi>:
  endbr64
  sub    $0x8,%rsp
  call   <E_ToZeroTwoPi@plt>
  mov    D4(%rip),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L8
  addsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
double E_ToMinusPiPlusPi(double input) {
  double zero_2pi;
  double res = 0.0;
  zero_2pi = E_ToZeroTwoPi(input);
  if (zero_2pi > M_PI)
    res = -(2.0 * M_PI) + zero_2pi;
  else
    res = zero_2pi;
  return res;
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<E_ToMinusPiPlusPi>:
  endbr64
  sub    $0x8,%rsp
  call   <E_ToZeroTwoPi@plt>
  mov    D2(%rip),%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L9
  addsd  %xmm1,%xmm1
  subsd  %xmm1,%xmm0
L9:
  add    $0x8,%rsp
  ret
```

assistant: ```c
double E_ToMinusPiPlusPi(double input) {
  double zero_2pi;
  double res = 0.0;
  zero_2pi = E_ToZeroTwoPi(input);
  if (zero_2pi > M_PI)
    res = -(2.0 * M_PI) + zero_2pi;
  else
    res = zero_2pi;
  return res;
  return res;
}
```