ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<scale_YCoCg>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movzbl 0x2(%rsi),%eax
  lea    -0x80(%rax),%edi
  movzbl %dil,%edi
  call   <abs@plt>
  mov    %eax,%ebp
  movzbl 0x1(%r13),%eax
  lea    -0x80(%rax),%edi
  movzbl %dil,%edi
  call   <abs@plt>
  mov    %eax,%r15d
  movzbl 0x2(%r12),%eax
  lea    -0x80(%rax),%edi
  movzbl %dil,%edi
  call   <abs@plt>
  mov    %eax,%r14d
  movzbl 0x1(%r12),%eax
  lea    -0x80(%rax),%edi
  movzbl %dil,%edi
  call   <abs@plt>
  cmp    %r15d,%ebp
  cmovl  %r15d,%ebp
  cmp    %r14d,%ebp
  cmovl  %r14d,%ebp
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  xor    %eax,%eax
  cmp    $0x3f,%ebp
  setle  %al
  xor    %edx,%edx
  cmp    $0x1f,%ebp
  setle  %dl
  lea    0x1(%rax,%rdx,2),%edx
  movzbl 0x2(%r13),%eax
  lea    -0x8(,%rdx,8),%esi
  mov    %edx,%ecx
  add    $0xffffff80,%eax
  mov    %sil,0x0(%r13)
  imul   %edx,%eax
  add    $0xffffff80,%eax
  mov    %al,0x2(%r13)
  movzbl 0x1(%r13),%eax
  add    $0xffffff80,%eax
  imul   %edx,%eax
  add    $0xffffff80,%eax
  mov    %al,0x1(%r13)
  movzbl 0x2(%r12),%eax
  mov    %sil,(%r12)
  lea    0x41(%rbx),%rsi
  add    $0xffffff80,%eax
  imul   %edx,%eax
  add    $0xffffff80,%eax
  mov    %al,0x2(%r12)
  movzbl 0x1(%r12),%eax
  add    $0xffffff80,%eax
  imul   %edx,%eax
  lea    0x1(%rbx),%rdx
  add    $0xffffff80,%eax
  mov    %al,0x1(%r12)
  nopl   0x0(%rax)
L4:
  movzbl 0x1(%rdx),%eax
  add    $0x4,%rdx
  add    $0xffffff80,%eax
  imul   %ecx,%eax
  add    $0xffffff80,%eax
  mov    %al,-0x3(%rdx)
  movzbl -0x4(%rdx),%eax
  add    $0xffffff80,%eax
  imul   %ecx,%eax
  add    $0xffffff80,%eax
  mov    %al,-0x4(%rdx)
  cmp    %rdx,%rsi
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void scale_YCoCg(unsigned char *block, unsigned char *mincolor, unsigned char *maxcolor) {
  const int s0 = 128 / 2 - 1;
  const int s1 = 128 / 4 - 1;
  int m0, m1, m2, m3;
  int mask0, mask1, scale;
  int i;
  m0 = abs(mincolor[2] - 128);
  m1 = abs(mincolor[1] - 128);
  m2 = abs(maxcolor[2] - 128);
  m3 = abs(maxcolor[1] - 128);
  if (m1 > m0)
    m0 = m1;
  if (m3 > m2)
    m2 = m3;
  if (m2 > m0)
    m0 = m2;
  mask0 = -(m0 <= s0);
  mask1 = -(m0 <= s1);
  scale = 1 + (1 & mask0) + (2 & mask1);
  mincolor[2] = (mincolor[2] - 128) * scale + 128;
  mincolor[1] = (mincolor[1] - 128) * scale + 128;
  mincolor[0] = (scale - 1) << 3;
  maxcolor[2] = (maxcolor[2] - 128) * scale + 128;
  maxcolor[1] = (maxcolor[1] - 128) * scale + 128;
  maxcolor[0] = (scale - 1) << 3;
  for (i = 0; i < 16; ++i) {
    block[i * 4 + 2] = (block[i * 4 + 2] - 128) * scale + 128;
    block[i * 4 + 1] = (block[i * 4 + 1] - 128) * scale + 128;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<helloWorld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: Hello World.


assistant: ```c
int helloWorld(int argc, char **argv) {
  printf("Hello World.\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<helloWorld>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: Hello World.


assistant: ```c
int helloWorld(int argc, char **argv) {
  printf("Hello World.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<helloWorld>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: Hello World.


assistant: ```c
int helloWorld(int argc, char **argv) {
  printf("Hello World.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<helloWorld>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: D4: Hello World.


assistant: ```c
int helloWorld(int argc, char **argv) {
  printf("Hello World.\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L10
L28:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L59:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L20
  mov    -0x18(%rbp),%rax
  jmp    L2
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  while (*s != '\0') {
    const char *a = accept;
    while (*a != '\0')
      if (*a++ == *s)
        return (char *)s;
    ++s;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strpbrk>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L2
L16:
  mov    %rsi,%rdx
L43:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L49
  add    $0x1,%rdx
  cmp    %r8b,%cl
  jne    L43
L40:
  ret
L2:
  mov    $0x0,%eax
  ret
L49:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L16
  mov    $0x0,%eax
  jmp    L40
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  while (*s != '\0') {
    const char *a = accept;
    while (*a != '\0')
      if (*a++ == *s)
        return (char *)s;
    ++s;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L32
L48:
  mov    %rsi,%rdx
  jmp    L46
  nopl   (%rax)
L17:
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L3
L46:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L17
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L48
L32:
  xor    %eax,%eax
L3:
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  while (*s != '\0') {
    const char *a = accept;
    while (*a != '\0')
      if (*a++ == *s)
        return (char *)s;
    ++s;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L10
L17:
  mov    %rsi,%rdx
  jmp    L36
  nopl   (%rax)
L30:
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L34
L36:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L30
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L17
L10:
  xor    %eax,%eax
L34:
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  while (*s != '\0') {
    const char *a = accept;
    while (*a != '\0')
      if (*a++ == *s)
        return (char *)s;
    ++s;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strsep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L4
L14:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  movb   $0x0,(%rax)
L0:
  mov    -0x8(%rbp),%rax
L4:
  leave
  ret
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *ret = *stringp;
  if (ret == NULL)
    return (NULL);
  if ((*stringp = strpbrk(*stringp, delim)) != NULL) {
    *((*stringp)++) = '\0';
  }
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strsep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  test   %rbp,%rbp
  je     L1
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L5
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
L1:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  movq   $0x0,(%rbx)
  jmp    L1
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *ret = *stringp;
  if (ret == NULL)
    return (NULL);
  if ((*stringp = strpbrk(*stringp, delim)) != NULL) {
    *((*stringp)++) = '\0';
  }
  return (ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strsep>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  test   %r12,%r12
  je     L15
  mov    %rdi,%rbx
  mov    %r12,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L13
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  movq   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *ret = *stringp;
  if (ret == NULL)
    return (NULL);
  if ((*stringp = strpbrk(*stringp, delim)) != NULL) {
    *((*stringp)++) = '\0';
  }
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strsep>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  test   %r12,%r12
  je     L12
  mov    %rdi,%rbx
  mov    %r12,%rdi
  call   <strpbrk@plt>
  test   %rax,%rax
  je     L5
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rbx)
  movb   $0x0,(%rax)
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  movq   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strsep(char **stringp, const char *delim) {
  char *ret = *stringp;
  if (ret == NULL)
    return (NULL);
  if ((*stringp = strpbrk(*stringp, delim)) != NULL) {
    *((*stringp)++) = '\0';
  }
  return (ret);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<VIM_MAPI_EnableSyncGen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movq   $0x190,-0x8(%rbp)
  mov    $0x0,%eax
  call   <VIM_JPEG_GetFrameCount@plt>
  mov    %ax,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <VIM_SIF_EnableSyncGen@plt>
  cmpb   $0x0,-0x14(%rbp)
  jne    L1
  jmp    L47
L11:
  mov    $0x0,%eax
  call   <VIM_JPEG_GetFrameCount@plt>
  mov    %ax,-0xa(%rbp)
  movzwl -0xa(%rbp),%eax
  movzwl -0xc(%rbp),%edx
  sub    %edx,%eax
  cmp    $0x1,%eax
  jg     L25
  mov    $0x1,%edi
  call   <VIM_USER_DelayMs@plt>
L47:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L11
  jmp    L1
L25:
  nop
L1:
  nop
  leave
  ret
```

assistant: ```c
void VIM_MAPI_EnableSyncGen(unsigned char bEnable) {
  unsigned long i = 400;
  unsigned short iCurrentFrame, iStartFram;
  iStartFram = VIM_JPEG_GetFrameCount();
  VIM_SIF_EnableSyncGen(bEnable);
  if (bEnable == 0) {
    while (i--) {
      iCurrentFrame = VIM_JPEG_GetFrameCount();
      if ((iCurrentFrame - iStartFram) > 1)
        break;
      VIM_USER_DelayMs(1);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<VIM_MAPI_EnableSyncGen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <VIM_JPEG_GetFrameCount@plt>
  mov    %eax,%ebp
  movzbl %bl,%edi
  call   <VIM_SIF_EnableSyncGen@plt>
  test   %bl,%bl
  jne    L29
  mov    $0x190,%ebx
  movzwl %bp,%ebp
L3:
  mov    $0x0,%eax
  call   <VIM_JPEG_GetFrameCount@plt>
  movzwl %ax,%eax
  sub    %ebp,%eax
  cmp    $0x1,%eax
  jg     L29
  mov    $0x1,%edi
  call   <VIM_USER_DelayMs@plt>
  sub    $0x1,%rbx
  jne    L3
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void VIM_MAPI_EnableSyncGen(unsigned char bEnable) {
  unsigned long i = 400;
  unsigned short iCurrentFrame, iStartFram;
  iStartFram = VIM_JPEG_GetFrameCount();
  VIM_SIF_EnableSyncGen(bEnable);
  if (bEnable == 0) {
    while (i--) {
      iCurrentFrame = VIM_JPEG_GetFrameCount();
      if ((iCurrentFrame - iStartFram) > 1)
        break;
      VIM_USER_DelayMs(1);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<VIM_MAPI_EnableSyncGen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <VIM_JPEG_GetFrameCount@plt>
  movzbl %bl,%edi
  movzwl %ax,%ebp
  call   <VIM_SIF_EnableSyncGen@plt>
  test   %bl,%bl
  jne    L3
  mov    $0x190,%ebx
  jmp    L0
  nopl   0x0(%rax)
L13:
  mov    $0x1,%edi
  call   <VIM_USER_DelayMs@plt>
  sub    $0x1,%rbx
  je     L3
L0:
  xor    %eax,%eax
  call   <VIM_JPEG_GetFrameCount@plt>
  movzwl %ax,%eax
  sub    %ebp,%eax
  cmp    $0x1,%eax
  jle    L13
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void VIM_MAPI_EnableSyncGen(unsigned char bEnable) {
  unsigned long i = 400;
  unsigned short iCurrentFrame, iStartFram;
  iStartFram = VIM_JPEG_GetFrameCount();
  VIM_SIF_EnableSyncGen(bEnable);
  if (bEnable == 0) {
    while (i--) {
      iCurrentFrame = VIM_JPEG_GetFrameCount();
      if ((iCurrentFrame - iStartFram) > 1)
        break;
      VIM_USER_DelayMs(1);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<VIM_MAPI_EnableSyncGen>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <VIM_JPEG_GetFrameCount@plt>
  movzbl %bl,%edi
  movzwl %ax,%ebp
  call   <VIM_SIF_EnableSyncGen@plt>
  test   %bl,%bl
  jne    L29
  mov    $0x190,%ebx
  jmp    L5
  nopl   0x0(%rax)
L32:
  mov    $0x1,%edi
  call   <VIM_USER_DelayMs@plt>
  sub    $0x1,%rbx
  je     L29
L5:
  xor    %eax,%eax
  call   <VIM_JPEG_GetFrameCount@plt>
  movzwl %ax,%eax
  sub    %ebp,%eax
  cmp    $0x1,%eax
  jle    L32
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void VIM_MAPI_EnableSyncGen(unsigned char bEnable) {
  unsigned long i = 400;
  unsigned short iCurrentFrame, iStartFram;
  iStartFram = VIM_JPEG_GetFrameCount();
  VIM_SIF_EnableSyncGen(bEnable);
  if (bEnable == 0) {
    while (i--) {
      iCurrentFrame = VIM_JPEG_GetFrameCount();
      if ((iCurrentFrame - iStartFram) > 1)
        break;
      VIM_USER_DelayMs(1);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x4,%rax
  lea    -0x30(%rbp),%rdx
  movl   $0xfa1e0ff3,(%rax)
  movw   $0xbb49,0x4(%rax)
  lea    -0xa0(%rip),%rcx        # 1159 <f2.0>
  mov    %rcx,0x6(%rax)
  movw   $0xba49,0xe(%rax)
  mov    %rdx,0x10(%rax)
  movl   $0x90e3ff49,0x18(%rax)
  mov    $0x0,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <f0@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: in f1 %d


assistant: ```c
int f1(void) {
  int i = 0;
  printf("in f1 %d\n", i);
  int f2(int *p) {
    printf("in f2 %d\n", i);
    i = 1;
    printf("in f2 %d\n", i);
    return *p + 1;
  }
  printf("in f1 %d\n", i);
  return f0(f2, &i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rax
  mov    %rax,0x20(%rsp)
  mov    %rsp,%rbx
  lea    0x4(%rsp),%r12
  movl   $0xfa1e0ff3,0x4(%rsp)
  movw   $0xbb49,0x8(%rsp)
  lea    -0x8c(%rip),%rax        # 1159 <f2.0>
  mov    %rax,0xa(%rsp)
  movw   $0xba49,0x12(%rsp)
  mov    %rbx,0x14(%rsp)
  movl   $0x90e3ff49,0x1c(%rsp)
  movl   $0x0,(%rsp)
  mov    $0x0,%esi
  lea    D7(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <f0@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: in f1 %d


assistant: ```c
int f1(void) {
  int i = 0;
  printf("in f1 %d\n", i);
  int f2(int *p) {
    printf("in f2 %d\n", i);
    i = 1;
    printf("in f2 %d\n", i);
    return *p + 1;
  }
  printf("in f1 %d\n", i);
  return f0(f2, &i);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f1>:
  endbr64
  push   %r13
  mov    $0xffffba49,%edx
  xor    %esi,%esi
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rax
  mov    %rsp,%rbp
  mov    %dx,0x12(%rsp)
  mov    %rax,0x20(%rsp)
  mov    $0xffffbb49,%eax
  lea    0x4(%rsp),%r13
  mov    %ax,0x8(%rsp)
  lea    -0xa6(%rip),%rax        # 1160 <f2.0>
  mov    %rax,0xa(%rsp)
  xor    %eax,%eax
  movl   $0xfa1e0ff3,0x4(%rsp)
  mov    %rbp,0x14(%rsp)
  movl   $0x90e3ff49,0x1c(%rsp)
  movl   $0x0,(%rsp)
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <f0@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: in f1 %d


assistant: ```c
int f1(void) {
  int i = 0;
  printf("in f1 %d\n", i);
  int f2(int *p) {
    printf("in f2 %d\n", i);
    i = 1;
    printf("in f2 %d\n", i);
    return *p + 1;
  }
  printf("in f1 %d\n", i);
  return f0(f2, &i);
}
```
user: What is the c source code of the assembly code below:

```asm
<f1>:
  endbr64
  push   %r13
  mov    $0xffffba49,%edx
  xor    %esi,%esi
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rax
  mov    %rsp,%rbp
  mov    %dx,0x12(%rsp)
  mov    %rax,0x20(%rsp)
  mov    $0xffffbb49,%eax
  lea    0x4(%rsp),%r13
  mov    %ax,0x8(%rsp)
  lea    -0xa6(%rip),%rax        # 1160 <f2.0>
  mov    %rax,0xa(%rsp)
  xor    %eax,%eax
  movl   $0xfa1e0ff3,0x4(%rsp)
  mov    %rbp,0x14(%rsp)
  movl   $0x90e3ff49,0x1c(%rsp)
  movl   $0x0,(%rsp)
  call   <printf@plt>
  mov    (%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <f0@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: in f1 %d


assistant: ```c
int f1(void) {
  int i = 0;
  printf("in f1 %d\n", i);
  int f2(int *p) {
    printf("in f2 %d\n", i);
    i = 1;
    printf("in f2 %d\n", i);
    return *p + 1;
  }
  printf("in f1 %d\n", i);
  return f0(f2, &i);
}
```
user: What is the c source code of the assembly code below:

```asm
<celcon_read_mixed_cell_configuration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x50,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int celcon_read_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(80, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<celcon_read_mixed_cell_configuration>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x50,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int celcon_read_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(80, a, b, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<celcon_read_mixed_cell_configuration>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x50,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int celcon_read_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(80, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<celcon_read_mixed_cell_configuration>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x50,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int celcon_read_mixed_cell_configuration(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(80, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0x18(%rbp),%rcx
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    $0x1,%eax
  jmp    L14
L15:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: %ld

assistant: ```c
int main(int argc, const char *argv[]) {
  long d;
  char *endptr;
  d = strtol(argv[1], &endptr, 8);
  if (*endptr != '\0')
    return (1);
  printf("%ld", d);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  mov    %rsp,%rsi
  mov    0x8(%rax),%rdi
  mov    $0x8,%edx
  call   <strtol@plt>
  mov    $0x1,%edx
  mov    (%rsp),%rcx
  cmpb   $0x0,(%rcx)
  je     L20
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %edx,%eax
  add    $0x18,%rsp
  ret
L20:
  mov    %rax,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edx
  jmp    L6
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: %ld

assistant: ```c
int main(int argc, const char *argv[]) {
  long d;
  char *endptr;
  d = strtol(argv[1], &endptr, 8);
  if (*endptr != '\0')
    return (1);
  printf("%ld", d);
  return (0);
}
```