ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getLine>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L19
  nop
L0:
  mov    D0(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L9
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x3e8,%rbx
  je     L5
L19:
  xor    %eax,%eax
  mov    %ebx,%r12d
  call   <getchar@plt>
  lea    0x0(%rbp,%rbx,1),%rdx
  cmp    $0xa,%eax
  jne    L0
  movb   $0xa,(%rdx)
  add    $0x1,%r12d
  movslq %r12d,%rbx
L9:
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0x3e8,%r12d
  movb   $0x0,0x0(%rbp,%rbx,1)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getLine(char line[]) {
  int c, i = 0;
  while (i < 1000 && (c = getchar()) != '\n' && c != EOF)
    line[i++] = c;
  if (c == '\n')
    line[i++] = c;
  line[i] = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_to_long_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L18
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <print_error@plt>
L18:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D5: %Lu

tool: D2: Unexpected input from vnstat

assistant: ```c
unsigned long long str_to_long_long(char *str) {
  unsigned long long result;
  if (sscanf(str, "%Lu", &result) == 0)
    print_error("Unexpected input from vnstat");
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_to_long_long>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L12
L23:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L12:
  lea    D1(%rip),%rdi
  call   <print_error@plt>
  jmp    L23
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D1
type_guessed: string

tool: D9: %Lu

tool: D1: Unexpected input from vnstat

assistant: ```c
unsigned long long str_to_long_long(char *str) {
  unsigned long long result;
  if (sscanf(str, "%Lu", &result) == 0)
    print_error("Unexpected input from vnstat");
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_to_long_long>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sscanf@plt>
  test   %rax,%rax
  je     L29
L20:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L29:
  lea    D15(%rip),%rdi
  call   <print_error@plt>
  jmp    L20
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D15
datatype: string

tool: D17: %Lu

tool: D15: Unexpected input from vnstat

assistant: ```c
unsigned long long str_to_long_long(char *str) {
  unsigned long long result;
  if (sscanf(str, "%Lu", &result) == 0)
    print_error("Unexpected input from vnstat");
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_to_long_long>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <sscanf@plt>
  test   %rax,%rax
  je     L16
L27:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L16:
  lea    D3(%rip),%rdi
  call   <print_error@plt>
  jmp    L27
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D3
datatype: string

tool: D11: %Lu

tool: D3: Unexpected input from vnstat

assistant: ```c
unsigned long long str_to_long_long(char *str) {
  unsigned long long result;
  if (sscanf(str, "%Lu", &result) == 0)
    print_error("Unexpected input from vnstat");
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fill_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L15:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fill_run(char string[], int start, int len, int first) {
  int i;
  for (i = 0; i < len; i++)
    string[start + i] = first + i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fill_run>:
  endbr64
  test   %edx,%edx
  jle    L10
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%r8
  lea    0x1(%rdi,%rsi,1),%rsi
  lea    -0x1(%rdx),%eax
  add    %rax,%rsi
  mov    %r8,%rax
  sub    %r8d,%ecx
L19:
  lea    (%rcx,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L19
L10:
  ret
```

assistant: ```c
void fill_run(char string[], int start, int len, int first) {
  int i;
  for (i = 0; i < len; i++)
    string[start + i] = first + i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fill_run>:
  endbr64
  test   %edx,%edx
  jle    L5
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  lea    0x1(%rdi,%rsi,1),%r8
  add    %rax,%r8
  lea    (%rdi,%rsi,1),%rax
  sub    %eax,%ecx
  nopl   0x0(%rax)
L2:
  lea    (%rcx,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %r8,%rax
  jne    L2
L5:
  ret
```

assistant: ```c
void fill_run(char string[], int start, int len, int first) {
  int i;
  for (i = 0; i < len; i++)
    string[start + i] = first + i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L21:
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L22
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L22:
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L38
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort(int a[], int len) {
  int i, j, temp;
  for (i = 0; i < len - 1; i++) {
    for (j = 0; j < len - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L44
  lea    0x4(%rdi),%r9
  jmp    L28
L34:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L53
L3:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L34
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L34
L53:
  sub    $0x1,%r8d
  je     L44
L28:
  test   %r8d,%r8d
  jle    L53
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L3
L44:
  ret
```

assistant: ```c
void bubble_sort(int a[], int len) {
  int i, j, temp;
  for (i = 0; i < len - 1; i++) {
    for (j = 0; j < len - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L35
  lea    0x4(%rdi),%r9
  nop
L4:
  sub    $0x1,%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rsi
  nopl   (%rax)
L39:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L26
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L26:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L39
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L4
L35:
  ret
```

assistant: ```c
void bubble_sort(int a[], int len) {
  int i, j, temp;
  for (i = 0; i < len - 1; i++) {
    for (j = 0; j < len - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L12
  lea    0x4(%rdi),%r9
  nop
L3:
  sub    $0x1,%eax
  mov    %rdi,%rdx
  mov    %rax,%r8
  lea    (%r9,%rax,4),%rsi
  nopl   (%rax)
L32:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L27
  movq   %xmm1,(%rdx)
L27:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L32
  mov    %r8d,%eax
  test   %r8d,%r8d
  jne    L3
L12:
  ret
```

assistant: ```c
void bubble_sort(int a[], int len) {
  int i, j, temp;
  for (i = 0; i < len - 1; i++) {
    for (j = 0; j < len - i - 1; j++)
      if (a[j] > a[j + 1]) {
        temp = a[j];
        a[j] = a[j + 1];
        a[j + 1] = temp;
      }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<jumpSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L45
L33:
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <min@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L56
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L108
L56:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
L45:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L121
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L33
  jmp    L121
L108:
  nop
L121:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L120
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L105
L120:
  mov    $0xffffffff,%eax
  jmp    L127
L105:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <min@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L18
L102:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L70
  mov    -0x8(%rbp),%eax
  jmp    L127
L70:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L99
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L102
L99:
  mov    $0xffffffff,%eax
L127:
  leave
  ret
```

assistant: ```c
int jumpSearch(int arr[], int n, int val) {
  int jump = (int)sqrt(n);
  int left = 0;
  int right = 0;
  while (left < n && arr[left] <= val) {
    right = min(n - 1, left + jump);
    if (arr[left] <= val && arr[right] >= val) {
      break;
    }
    left += jump;
  }
  if (left >= n || arr[left] > val) {
    return -1;
  }
  right = min(n - 1, right);
  int i;
  for (i = left; i <= right && arr[i] <= val; ++i) {
    if (arr[i] == val) {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<jumpSearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %edx,%ebx
  mov    %esi,%edi
  call   <sqrt@plt>
  mov    %eax,0x4(%rsp)
  test   %r14d,%r14d
  jle    L157
  cltq
  shl    $0x2,%rax
  mov    %rax,0x8(%rsp)
  mov    %r13,%rbp
  movl   $0x0,(%rsp)
  lea    -0x1(%r14),%r15d
  jmp    L131
L33:
  add    0x8(%rsp),%rbp
  cmp    %r14d,%r12d
  jge    L157
  mov    %r12d,(%rsp)
L131:
  cmp    %ebx,0x0(%rbp)
  jg     L105
  mov    0x4(%rsp),%r12d
  add    (%rsp),%r12d
  mov    %r12d,%esi
  mov    %r15d,%edi
  call   <min@plt>
  cmp    %ebx,0x0(%rbp)
  jg     L33
  movslq %eax,%rdx
  cmp    %ebx,0x0(%r13,%rdx,4)
  jl     L33
  cmp    (%rsp),%r14d
  jle    L15
  mov    %eax,%esi
  mov    %r15d,%edi
  call   <min@plt>
  mov    (%rsp),%edi
  cmp    %edi,%eax
  jl     L111
  movslq %edi,%rdx
L4:
  mov    %edx,%esi
  mov    0x0(%r13,%rdx,4),%ecx
  cmp    %ebx,%ecx
  jg     L70
  je     L109
  add    $0x1,%rdx
  cmp    %edx,%eax
  jge    L4
  mov    $0xffffffff,%esi
  jmp    L109
L105:
  mov    $0xffffffff,%esi
L109:
  mov    %esi,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  mov    $0xffffffff,%esi
  jmp    L109
L111:
  mov    $0xffffffff,%esi
  jmp    L109
L15:
  mov    $0xffffffff,%esi
  jmp    L109
L157:
  mov    $0xffffffff,%esi
  jmp    L109
```

assistant: ```c
int jumpSearch(int arr[], int n, int val) {
  int jump = (int)sqrt(n);
  int left = 0;
  int right = 0;
  while (left < n && arr[left] <= val) {
    right = min(n - 1, left + jump);
    if (arr[left] <= val && arr[right] >= val) {
      break;
    }
    left += jump;
  }
  if (left >= n || arr[left] > val) {
    return -1;
  }
  right = min(n - 1, right);
  int i;
  for (i = left; i <= right && arr[i] <= val; ++i) {
    if (arr[i] == val) {
      return i;
    }
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jumpSearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  call   <sqrt@plt>
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  jle    L95
  cltq
  mov    %ebx,%ecx
  mov    %r13,%rbp
  xor    %ebx,%ebx
  shl    $0x2,%rax
  lea    -0x1(%rcx),%r15d
  mov    %rax,0x8(%rsp)
  jmp    L46
  nopl   0x0(%rax)
L73:
  mov    (%rsp),%eax
  mov    %r15d,%edi
  lea    (%rbx,%rax,1),%r14d
  mov    %r14d,%esi
  call   <min@plt>
  cmp    %r12d,0x0(%rbp)
  jg     L37
  movslq %eax,%rsi
  cmp    %r12d,0x0(%r13,%rsi,4)
  jge    L58
L37:
  add    0x8(%rsp),%rbp
  cmp    0x4(%rsp),%r14d
  jge    L95
  mov    %r14d,%ebx
L46:
  cmp    %r12d,0x0(%rbp)
  jle    L73
L95:
  mov    $0xffffffff,%r8d
L30:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %eax,%esi
  mov    %r15d,%edi
  call   <min@plt>
  cmp    %eax,%ebx
  jg     L95
  movslq %ebx,%rdx
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L50:
  je     L30
  add    $0x1,%rdx
  cmp    %edx,%eax
  jl     L95
L11:
  mov    %edx,%r8d
  cmp    %r12d,0x0(%r13,%rdx,4)
  jle    L50
  jmp    L95
```

assistant: ```c
int jumpSearch(int arr[], int n, int val) {
  int jump = (int)sqrt(n);
  int left = 0;
  int right = 0;
  while (left < n && arr[left] <= val) {
    right = min(n - 1, left + jump);
    if (arr[left] <= val && arr[right] >= val) {
      break;
    }
    left += jump;
  }
  if (left >= n || arr[left] > val) {
    return -1;
  }
  right = min(n - 1, right);
  int i;
  for (i = left; i <= right && arr[i] <= val; ++i) {
    if (arr[i] == val) {
      return i;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jumpSearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  call   <sqrt@plt>
  mov    %eax,(%rsp)
  test   %ebx,%ebx
  jle    L50
  cltq
  mov    %ebx,%ecx
  mov    %r13,%rbp
  xor    %ebx,%ebx
  shl    $0x2,%rax
  lea    -0x1(%rcx),%r15d
  mov    %rax,0x8(%rsp)
  jmp    L80
  nopl   0x0(%rax)
L48:
  mov    (%rsp),%eax
  mov    %r15d,%edi
  lea    (%rbx,%rax,1),%r14d
  mov    %r14d,%esi
  call   <min@plt>
  cmp    %r12d,0x0(%rbp)
  jg     L71
  movslq %eax,%rsi
  cmp    %r12d,0x0(%r13,%rsi,4)
  jge    L78
L71:
  add    0x8(%rsp),%rbp
  cmp    0x4(%rsp),%r14d
  jge    L50
  mov    %r14d,%ebx
L80:
  cmp    %r12d,0x0(%rbp)
  jle    L48
L50:
  mov    $0xffffffff,%r8d
L66:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L78:
  mov    %eax,%esi
  mov    %r15d,%edi
  call   <min@plt>
  cmp    %eax,%ebx
  jg     L50
  movslq %ebx,%rdx
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L116:
  je     L66
  add    $0x1,%rdx
  cmp    %edx,%eax
  jl     L50
L68:
  mov    %edx,%r8d
  cmp    %r12d,0x0(%r13,%rdx,4)
  jle    L116
  jmp    L50
```

assistant: ```c
int jumpSearch(int arr[], int n, int val) {
  int jump = (int)sqrt(n);
  int left = 0;
  int right = 0;
  while (left < n && arr[left] <= val) {
    right = min(n - 1, left + jump);
    if (arr[left] <= val && arr[right] >= val) {
      break;
    }
    left += jump;
  }
  if (left >= n || arr[left] > val) {
    return -1;
  }
  right = min(n - 1, right);
  int i;
  for (i = left; i <= right && arr[i] <= val; ++i) {
    if (arr[i] == val) {
      return i;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strDate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%edi
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%esi
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x8,%rsp
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  lea    D15(%rip),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
datatype: string

tool: D29: 20%02x-%02x-%02x %02x:%02x

assistant: ```c
char *strDate(char *ptrDate) {
  static char stringDate[17];
  sprintf(stringDate, "20%02x-%02x-%02x %02x:%02x", ptrDate[0], ptrDate[1], ptrDate[2], ptrDate[3], ptrDate[4]);
  return stringDate;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strDate>:
  endbr64
  push   %rbx
  movsbl 0x1(%rdi),%ecx
  movsbl (%rdi),%edx
  sub    $0x8,%rsp
  movsbl 0x4(%rdi),%eax
  push   %rax
  movsbl 0x3(%rdi),%r9d
  movsbl 0x2(%rdi),%r8d
  lea    D16(%rip),%rsi
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  add    $0x10,%rsp
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type_guessed: string

tool: D16: 20%02x-%02x-%02x %02x:%02x

assistant: ```c
char *strDate(char *ptrDate) {
  static char stringDate[17];
  sprintf(stringDate, "20%02x-%02x-%02x %02x:%02x", ptrDate[0], ptrDate[1], ptrDate[2], ptrDate[3], ptrDate[4]);
  return stringDate;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strDate>:
  endbr64
  push   %r12
  movsbl 0x4(%rdi),%eax
  lea    D13(%rip),%r12
  lea    D16(%rip),%rsi
  movsbl (%rdi),%edx
  movsbl 0x1(%rdi),%ecx
  sub    $0x8,%rsp
  push   %rax
  movsbl 0x3(%rdi),%r9d
  movsbl 0x2(%rdi),%r8d
  mov    %r12,%rdi
  call   <sprintf@plt>
  pop    %rax
  mov    %r12,%rax
  pop    %rdx
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D16: 20%02x-%02x-%02x %02x:%02x

assistant: ```c
char *strDate(char *ptrDate) {
  static char stringDate[17];
  sprintf(stringDate, "20%02x-%02x-%02x %02x:%02x", ptrDate[0], ptrDate[1], ptrDate[2], ptrDate[3], ptrDate[4]);
  return stringDate;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strDate>:
  endbr64
  push   %r12
  movsbl 0x4(%rdi),%eax
  lea    D9(%rip),%r12
  lea    D11(%rip),%rsi
  movsbl (%rdi),%edx
  movsbl 0x1(%rdi),%ecx
  sub    $0x8,%rsp
  push   %rax
  movsbl 0x3(%rdi),%r9d
  movsbl 0x2(%rdi),%r8d
  mov    %r12,%rdi
  call   <sprintf@plt>
  pop    %rax
  mov    %r12,%rax
  pop    %rdx
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
datatype: string

tool: D11: 20%02x-%02x-%02x %02x:%02x

assistant: ```c
char *strDate(char *ptrDate) {
  static char stringDate[17];
  sprintf(stringDate, "20%02x-%02x-%02x %02x:%02x", ptrDate[0], ptrDate[1], ptrDate[2], ptrDate[3], ptrDate[4]);
  return stringDate;
}
```