ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D2(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L54
  mov    $0x1,%r14d
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D0(%rip),%rbp
  lea    D24(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  mov    0x14(%rsp),%esi
  cmp    %esi,%eax
  jg     L13
  add    $0x1,%esi
  xor    %edx,%edx
  nopl   0x0(%rax)
L9:
  lea    (%rdx,%rax,1),%ecx
  test   $0x1,%al
  cmovne %ecx,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L9
L24:
  mov    %r14d,%esi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <printf@plt>
  cmp    %r14d,0xc(%rsp)
  jge    L3
L54:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L13:
  xor    %edx,%edx
  jmp    L24
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D24
datatype: string

tool: D2: %d

tool: D0: %d %d

tool: D24: Case %d: %d


assistant: ```c
int main() {
  int n, a, b, i, j, sum = 0;
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    scanf("%d %d", &a, &b);
    for (j = a; j <= b; j++) {
      if (j % 2 != 0)
        sum += j;
    }
    printf("Case %d: %d\n", i, sum);
    sum = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<iw_imgtype_alpha_channel_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x101,-0x4(%rbp)
  je     L7
  cmpl   $0x110,-0x4(%rbp)
  jne    L27
  mov    $0x3,%eax
  jmp    L26
L7:
  mov    $0x1,%eax
  jmp    L26
L27:
  mov    $0x0,%eax
L26:
  pop    %rbp
  ret
```

assistant: ```c
int iw_imgtype_alpha_channel_index(int t) {
  switch (t) {
  case 0x0110:
    return 3;
  case 0x0101:
    return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iw_imgtype_alpha_channel_index>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x101,%edi
  je     L4
  cmp    $0x110,%edi
  sete   %al
  movzbl %al,%eax
  lea    (%rax,%rax,2),%eax
L4:
  ret
```

assistant: ```c
int iw_imgtype_alpha_channel_index(int t) {
  switch (t) {
  case 0x0110:
    return 3;
  case 0x0101:
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<iw_imgtype_alpha_channel_index>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x101,%edi
  je     L3
  xor    %eax,%eax
  cmp    $0x110,%edi
  sete   %al
  lea    (%rax,%rax,2),%eax
L3:
  ret
```

assistant: ```c
int iw_imgtype_alpha_channel_index(int t) {
  switch (t) {
  case 0x0110:
    return 3;
  case 0x0101:
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<iw_imgtype_alpha_channel_index>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x101,%edi
  je     L4
  xor    %eax,%eax
  cmp    $0x110,%edi
  sete   %al
  lea    (%rax,%rax,2),%eax
L4:
  ret
```

assistant: ```c
int iw_imgtype_alpha_channel_index(int t) {
  switch (t) {
  case 0x0110:
    return 3;
  case 0x0101:
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<entab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L95
L98:
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  sub    %eax,-0x10(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L98
  jmp    L92
L44:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x10(%rbp)
L92:
  cmpl   $0x0,-0x10(%rbp)
  jne    L44
  cmpl   $0x20,-0x4(%rbp)
  je     L18
  cmpl   $0x9,-0x4(%rbp)
  jne    L27
L18:
  cmpl   $0x20,-0x4(%rbp)
  jne    L75
  addl   $0x1,-0x8(%rbp)
  jmp    L65
L75:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0x8(%rbp)
L65:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L95
  mov    $0x9,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  add    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L95
L93:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L27:
  cmpl   $0x0,-0x8(%rbp)
  jne    L93
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  cmpl   $0xa,-0x4(%rbp)
  jne    L63
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L95
L63:
  addl   $0x1,-0xc(%rbp)
L95:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void entab(int m, int n) {
  int start, column, blanks, c;
  start = m;
  column = 1;
  blanks = 0;
  while ((c = getchar()) != EOF) {
    while (start >= n - (column - 1) % n) {
      putchar('\t');
      column += n - (column - 1) % n;
      start -= n - (column - 1) % n;
    }
    while (start) {
      putchar(' ');
      column++;
      start--;
    }
    if (c == ' ' || c == '\t') {
      if (c == ' ')
        blanks++;
      else
        blanks += n - (blanks + column - 1) % n;
      if (blanks == n - (column - 1) % n) {
        putchar('\t');
        column += n - (column - 1) % n;
        blanks = 0;
      }
    } else {
      while (blanks) {
        putchar(' ');
        column++;
        blanks--;
      }
      putchar(c);
      if (c == '\n') {
        start = m;
        column = 1;
      } else
        column++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<entab>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%ebp
  mov    %edi,%r13d
  mov    $0x0,%r15d
  mov    $0x1,%r12d
  jmp    L90
L96:
  cmp    $0x20,%r14d
  je     L89
  lea    -0x1(%r15,%r12,1),%eax
  cltd
  idiv   %ebp
  mov    %ebp,%eax
  sub    %edx,%eax
  add    %eax,%r15d
L142:
  lea    -0x1(%r12),%eax
  cltd
  idiv   %ebp
  mov    %ebp,%eax
  sub    %edx,%eax
  mov    $0x0,%r13d
  cmp    %r15d,%eax
  je     L22
L90:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%r14d
  mov    D8(%rip),%rax
  cmp    %r14d,(%rax)
  je     L38
  lea    -0x1(%r12),%eax
  cltd
  idiv   %ebp
  mov    %ebp,%ebx
  sub    %edx,%ebx
  cmp    %ebx,%r13d
  jl     L163
L153:
  mov    $0x9,%edi
  call   <putchar@plt>
  add    %ebx,%r12d
  lea    -0x1(%r12),%eax
  cltd
  idiv   %ebp
  mov    %ebp,%ebx
  sub    %edx,%ebx
  sub    %ebx,%r13d
  cmp    %r13d,%ebx
  jle    L153
L163:
  test   %r13d,%r13d
  je     L27
  mov    %r13d,%ebx
L21:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L21
  lea    (%r12,%r13,1),%r12d
L27:
  cmp    $0x20,%r14d
  je     L96
  cmp    $0x9,%r14d
  je     L96
  mov    %r15d,%ebx
  test   %r15d,%r15d
  je     L143
L151:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L151
  lea    (%r15,%r12,1),%r12d
L143:
  mov    %r14d,%edi
  call   <putchar@plt>
  cmp    $0xa,%r14d
  je     L79
  add    $0x1,%r12d
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  jmp    L90
L89:
  add    $0x1,%r15d
  jmp    L142
L22:
  mov    $0x9,%edi
  call   <putchar@plt>
  add    %r15d,%r12d
  mov    $0x0,%r15d
  jmp    L90
L79:
  mov    0xc(%rsp),%r13d
  mov    $0x0,%r15d
  mov    $0x1,%r12d
  jmp    L90
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void entab(int m, int n) {
  int start, column, blanks, c;
  start = m;
  column = 1;
  blanks = 0;
  while ((c = getchar()) != EOF) {
    while (start >= n - (column - 1) % n) {
      putchar('\t');
      column += n - (column - 1) % n;
      start -= n - (column - 1) % n;
    }
    while (start) {
      putchar(' ');
      column++;
      start--;
    }
    if (c == ' ' || c == '\t') {
      if (c == ' ')
        blanks++;
      else
        blanks += n - (blanks + column - 1) % n;
      if (blanks == n - (column - 1) % n) {
        putchar('\t');
        column += n - (column - 1) % n;
        blanks = 0;
      }
    } else {
      while (blanks) {
        putchar(' ');
        column++;
        blanks--;
      }
      putchar(c);
      if (c == '\n') {
        start = m;
        column = 1;
      } else
        column++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<entab>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L91:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r14d
  mov    D3(%rip),%rax
  cmp    %r14d,(%rax)
  je     L78
  lea    -0x1(%rbp),%eax
  mov    %ebx,%r13d
  cltd
  idiv   %ebx
  sub    %edx,%r13d
  cmp    %r13d,%r12d
  jl     L70
  nopl   0x0(%rax,%rax,1)
L61:
  add    %r13d,%ebp
  mov    $0x9,%edi
  mov    %ebx,%r13d
  call   <putchar@plt>
  lea    -0x1(%rbp),%eax
  cltd
  idiv   %ebx
  sub    %edx,%r13d
  sub    %r13d,%r12d
  cmp    %r12d,%r13d
  jle    L61
L70:
  test   %r12d,%r12d
  je     L49
  mov    %r12d,%r13d
  nopl   0x0(%rax)
L63:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  jne    L63
  add    %r12d,%ebp
L49:
  cmp    $0x20,%r14d
  je     L57
  cmp    $0x9,%r14d
  jne    L58
  cmp    $0x20,%r14d
  je     L57
  lea    -0x1(%r15,%rbp,1),%eax
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    %eax,%r15d
L89:
  lea    -0x1(%rbp),%eax
  xor    %r12d,%r12d
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    %r15d,%eax
  jne    L91
  mov    $0x9,%edi
  add    %r15d,%ebp
  xor    %r15d,%r15d
  call   <putchar@plt>
  jmp    L91
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %r15d,%r12d
  test   %r15d,%r15d
  je     L101
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  jne    L47
  add    %r15d,%ebp
L101:
  mov    %r14d,%edi
  call   <putchar@plt>
  cmp    $0xa,%r14d
  je     L26
  add    $0x1,%ebp
  xor    %r15d,%r15d
  xor    %r12d,%r12d
  jmp    L91
  nop
L57:
  add    $0x1,%r15d
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L78:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L26:
  mov    0xc(%rsp),%r12d
  xor    %r15d,%r15d
  mov    $0x1,%ebp
  jmp    L91
```

assistant: ```c
void entab(int m, int n) {
  int start, column, blanks, c;
  start = m;
  column = 1;
  blanks = 0;
  while ((c = getchar()) != EOF) {
    while (start >= n - (column - 1) % n) {
      putchar('\t');
      column += n - (column - 1) % n;
      start -= n - (column - 1) % n;
    }
    while (start) {
      putchar(' ');
      column++;
      start--;
    }
    if (c == ' ' || c == '\t') {
      if (c == ' ')
        blanks++;
      else
        blanks += n - (blanks + column - 1) % n;
      if (blanks == n - (column - 1) % n) {
        putchar('\t');
        column += n - (column - 1) % n;
        blanks = 0;
      }
    } else {
      while (blanks) {
        putchar(' ');
        column++;
        blanks--;
      }
      putchar(c);
      if (c == '\n') {
        start = m;
        column = 1;
      } else
        column++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<entab>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r14d
  mov    D2(%rip),%rax
  cmp    %r14d,(%rax)
  je     L19
  lea    -0x1(%r12),%ecx
  mov    %ebx,%r13d
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  sub    %edx,%r13d
  cmp    %r13d,%ebp
  jl     L92
  nopw   0x0(%rax,%rax,1)
L98:
  add    %r13d,%r12d
  mov    $0x9,%edi
  mov    %ebx,%r13d
  call   <putchar@plt>
  lea    -0x1(%r12),%ecx
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  sub    %edx,%r13d
  sub    %r13d,%ebp
  cmp    %ebp,%r13d
  jle    L98
L92:
  test   %ebp,%ebp
  je     L127
  mov    %ebp,%r13d
  nopl   0x0(%rax)
L0:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%r13d
  jne    L0
  lea    -0x1(%r12,%rbp,1),%ecx
  add    %ebp,%r12d
L127:
  cmp    $0x20,%r14d
  je     L57
  cmp    $0x9,%r14d
  jne    L151
  cmp    $0x20,%r14d
  je     L57
  lea    -0x1(%r15,%r12,1),%eax
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    %eax,%r15d
L148:
  mov    %ecx,%eax
  xor    %ebp,%ebp
  cltd
  idiv   %ebx
  mov    %ebx,%eax
  sub    %edx,%eax
  cmp    %r15d,%eax
  jne    L64
  mov    $0x9,%edi
  add    %r15d,%r12d
  xor    %r15d,%r15d
  call   <putchar@plt>
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L151:
  mov    %r15d,%ebp
  test   %r15d,%r15d
  je     L120
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebp
  jne    L36
  add    %r15d,%r12d
L120:
  mov    %r14d,%edi
  call   <putchar@plt>
  cmp    $0xa,%r14d
  je     L48
  add    $0x1,%r12d
  xor    %r15d,%r15d
  xor    %ebp,%ebp
  jmp    L64
  xchg   %ax,%ax
L57:
  add    $0x1,%r15d
  jmp    L148
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L48:
  mov    0xc(%rsp),%ebp
  xor    %r15d,%r15d
  mov    $0x1,%r12d
  jmp    L64
```

assistant: ```c
void entab(int m, int n) {
  int start, column, blanks, c;
  start = m;
  column = 1;
  blanks = 0;
  while ((c = getchar()) != EOF) {
    while (start >= n - (column - 1) % n) {
      putchar('\t');
      column += n - (column - 1) % n;
      start -= n - (column - 1) % n;
    }
    while (start) {
      putchar(' ');
      column++;
      start--;
    }
    if (c == ' ' || c == '\t') {
      if (c == ' ')
        blanks++;
      else
        blanks += n - (blanks + column - 1) % n;
      if (blanks == n - (column - 1) % n) {
        putchar('\t');
        column += n - (column - 1) % n;
        blanks = 0;
      }
    } else {
      while (blanks) {
        putchar(' ');
        column++;
        blanks--;
      }
      putchar(c);
      if (c == '\n') {
        start = m;
        column = 1;
      } else
        column++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copyAndSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L62
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  movl   $0x1,-0x8(%rbp)
  jmp    L69
L47:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L54:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L21:
  cmpl   $0x0,-0x4(%rbp)
  jle    L38
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jg     L54
L38:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L69:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L47
  jmp    L67
L62:
  nop
L67:
  pop    %rbp
  ret
```

assistant: ```c
void copyAndSort(uint64_t *source, uint64_t *dest, int length) {
  if (length == 0)
    return;
  dest[0] = source[0];
  for (uint64_t i = 1; i < length; i++) {
    uint64_t j = i;
    while (j > 0 && dest[j - 1] > source[i]) {
      dest[j] = dest[j - 1];
      j--;
    }
    dest[j] = source[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<copyAndSort>:
  endbr64
  test   %edx,%edx
  je     L27
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  cmp    $0x1,%edx
  jle    L27
  lea    0x4(%rdi),%r8
  lea    0x4(%rsi),%r10
  mov    $0x1,%r9d
  jmp    L54
L13:
  mov    (%r8),%eax
  movslq %ecx,%rcx
  mov    %eax,(%rsi,%rcx,4)
  add    $0x1,%r9d
  add    $0x4,%r8
  add    $0x4,%r10
  cmp    %r9d,%edx
  je     L27
L54:
  mov    %r10,%rax
  mov    %r9d,%ecx
  test   %r9d,%r9d
  jle    L13
L0:
  mov    -0x4(%rax),%edi
  cmp    (%r8),%edi
  jle    L13
  mov    %edi,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%ecx
  jne    L0
  jmp    L13
L27:
  ret
```

assistant: ```c
void copyAndSort(uint64_t *source, uint64_t *dest, int length) {
  if (length == 0)
    return;
  dest[0] = source[0];
  for (uint64_t i = 1; i < length; i++) {
    uint64_t j = i;
    while (j > 0 && dest[j - 1] > source[i]) {
      dest[j] = dest[j - 1];
      j--;
    }
    dest[j] = source[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copyAndSort>:
  endbr64
  test   %edx,%edx
  je     L46
  push   %rbx
  mov    (%rdi),%ecx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %ecx,(%rbx)
  cmp    $0x1,%edx
  jle    L23
  lea    0x4(%rbx),%r10
  lea    0x4(%rdi),%r9
  mov    $0x1,%edx
  mov    %r10,%r11
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r11,%rax
  jmp    L15
  nopl   (%rax)
L64:
  mov    -0x8(%rax),%ecx
  sub    $0x4,%rax
L15:
  mov    (%r9),%edi
  mov    %rax,%r8
  cmp    %ecx,%edi
  jge    L44
  mov    %ecx,(%rax)
  cmp    %r10,%r8
  jne    L64
  mov    (%r9),%edi
  mov    %rbx,%r8
L44:
  add    $0x1,%edx
  mov    %edi,(%r8)
  add    $0x4,%r9
  cmp    %edx,%esi
  je     L23
  mov    (%r11),%ecx
  add    $0x4,%r11
  jmp    L39
  nopl   (%rax)
L23:
  pop    %rbx
  ret
L46:
  ret
```

assistant: ```c
void copyAndSort(uint64_t *source, uint64_t *dest, int length) {
  if (length == 0)
    return;
  dest[0] = source[0];
  for (uint64_t i = 1; i < length; i++) {
    uint64_t j = i;
    while (j > 0 && dest[j - 1] > source[i]) {
      dest[j] = dest[j - 1];
      j--;
    }
    dest[j] = source[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copyAndSort>:
  endbr64
  test   %edx,%edx
  je     L47
  mov    (%rdi),%eax
  mov    %eax,(%rsi)
  cmp    $0x1,%edx
  jle    L47
  lea    0x4(%rsi),%r11
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  nop
L11:
  mov    %r11,%rax
  nopl   0x0(%rax,%rax,1)
L49:
  mov    -0x4(%rax),%ecx
  mov    (%r9),%edi
  mov    %rax,%r8
  cmp    %edi,%ecx
  jle    L6
  mov    %ecx,(%rax)
  lea    -0x4(%r8),%rax
  cmp    %rsi,%rax
  jne    L49
  mov    (%r9),%edi
  mov    %rsi,%r8
L6:
  add    $0x1,%r10d
  mov    %edi,(%r8)
  add    $0x4,%r11
  add    $0x4,%r9
  cmp    %r10d,%edx
  jne    L11
L47:
  ret
```

assistant: ```c
void copyAndSort(uint64_t *source, uint64_t *dest, int length) {
  if (length == 0)
    return;
  dest[0] = source[0];
  for (uint64_t i = 1; i < length; i++) {
    uint64_t j = i;
    while (j > 0 && dest[j - 1] > source[i]) {
      dest[j] = dest[j - 1];
      j--;
    }
    dest[j] = source[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  return (unsigned long)buf.tms_utime + buf.tms_stime;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<clock>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  return (unsigned long)buf.tms_utime + buf.tms_stime;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clock>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  return (unsigned long)buf.tms_utime + buf.tms_stime;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clock>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
clock_t clock(void) {
  struct tms buf;
  return (unsigned long)buf.tms_utime + buf.tms_stime;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverse_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L57
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L44
  mov    -0x4(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse_string@plt>
  jmp    L47
L44:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <reverse_string@plt>
L47:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L39
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse_string@plt>
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L39:
  addl   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L63
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L0
L63:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse_string@plt>
  jmp    L17
L57:
  nop
L17:
  leave
  ret
```

assistant: ```c
void reverse_words(char line[]) {
  int len = strlen(line);
  if (len < 1) {
    return;
  }
  if (line[len - 1] == '\n') {
    reverse_string(line, 0, len - 2);
  } else {
    reverse_string(line, 0, len - 1);
  }
  int wordstart = 0, wordend = 0;
  for (; line[wordend] != '\0' && line[wordend] != '\n'; wordend++) {
    if (line[wordend] == ' ') {
      reverse_string(line, wordstart, wordend - 1);
      wordstart = wordend + 1;
    }
  }
  reverse_string(line, wordstart, wordend - 1);
}
```