ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<deallocateStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L6:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L6
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void deallocateStrings(char **array) {
  char **element = array;
  while (*element)
    free(*element++);
  free(array);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<deallocateStrings>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  mov    %rbp,%rbx
L13:
  add    $0x8,%rbx
  call   <free@plt>
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L13
L4:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void deallocateStrings(char **array) {
  char **element = array;
  while (*element)
    free(*element++);
  free(array);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<deallocateStrings>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L19
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L10:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L10
L19:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void deallocateStrings(char **array) {
  char **element = array;
  while (*element)
    free(*element++);
  free(array);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deallocateStrings>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L13:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L13
L9:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void deallocateStrings(char **array) {
  char **element = array;
  while (*element)
    free(*element++);
  free(array);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dicho_si_leaf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <binomial_d@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%eax
  and    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <log2@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double dicho_si_leaf(int m, int t, int l) {
  unsigned long u;
  u = binomial_d(1 << m, t);
  u &= (((unsigned)-1) << l);
  return log2(u);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dicho_si_leaf>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  mov    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  mov    %eax,%edi
  call   <binomial_d@plt>
  mov    $0xffffffff,%edi
  mov    %ebx,%ecx
  shl    %cl,%edi
  and    %rax,%rdi
  call   <log2@plt>
  pop    %rbx
  ret
```

assistant: ```c
double dicho_si_leaf(int m, int t, int l) {
  unsigned long u;
  u = binomial_d(1 << m, t);
  u &= (((unsigned)-1) << l);
  return log2(u);
}
```
user: What is the c source code of the assembly code below?

```asm
<dicho_si_leaf>:
  endbr64
  mov    %edi,%ecx
  push   %rbx
  mov    $0x1,%eax
  mov    %edx,%ebx
  shl    %cl,%eax
  mov    %eax,%edi
  call   <binomial_d@plt>
  mov    %ebx,%ecx
  mov    $0xffffffff,%edi
  pop    %rbx
  shl    %cl,%edi
  and    %rax,%rdi
  jmp    1070 <log2@plt>
```

assistant: ```c
double dicho_si_leaf(int m, int t, int l) {
  unsigned long u;
  u = binomial_d(1 << m, t);
  u &= (((unsigned)-1) << l);
  return log2(u);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dicho_si_leaf>:
  endbr64
  mov    %edi,%ecx
  push   %rbx
  mov    $0x1,%eax
  mov    %edx,%ebx
  shl    %cl,%eax
  mov    %eax,%edi
  call   <binomial_d@plt>
  mov    %ebx,%ecx
  mov    $0xffffffff,%edi
  pop    %rbx
  shl    %cl,%edi
  and    %rax,%rdi
  jmp    1070 <log2@plt>
```

assistant: ```c
double dicho_si_leaf(int m, int t, int l) {
  unsigned long u;
  u = binomial_d(1 << m, t);
  u &= (((unsigned)-1) << l);
  return log2(u);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xil_fpo_flttoflt_flt_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <xip_fpo_flttoflt_flt_d@plt>
  movss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
float xil_fpo_flttoflt_flt_d(double a) {
  float res_flt;
  xip_fpo_flttoflt_flt_d(&res_flt, a);
  return res_flt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xil_fpo_flttoflt_flt_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <xip_fpo_flttoflt_flt_d@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float xil_fpo_flttoflt_flt_d(double a) {
  float res_flt;
  xip_fpo_flttoflt_flt_d(&res_flt, a);
  return res_flt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xil_fpo_flttoflt_flt_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <xip_fpo_flttoflt_flt_d@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float xil_fpo_flttoflt_flt_d(double a) {
  float res_flt;
  xip_fpo_flttoflt_flt_d(&res_flt, a);
  return res_flt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xil_fpo_flttoflt_flt_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <xip_fpo_flttoflt_flt_d@plt>
  movss  0x4(%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
float xil_fpo_flttoflt_flt_d(double a) {
  float res_flt;
  xip_fpo_flttoflt_flt_d(&res_flt, a);
  return res_flt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_spc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L2
L13:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_out@plt>
L2:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jg     L13
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4:  

assistant: ```c
_spc(x) int x;
{
  while (x-- > 0)
    _out(" ");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_spc>:
  endbr64
  test   %edi,%edi
  jle    L12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rdi),%ebx
  lea    D6(%rip),%rbp
L17:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <_out@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6:  

assistant: ```c
_spc(x) int x;
{
  while (x-- > 0)
    _out(" ");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_spc>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <_out@plt>
  sub    $0x1,%ebx
  jae    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D5:  

assistant: ```c
_spc(x) int x;
{
  while (x-- > 0)
    _out(" ");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_spc>:
  endbr64
  test   %edi,%edi
  jle    L17
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  lea    -0x1(%rdi),%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <_out@plt>
  sub    $0x1,%ebx
  jae    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4:  

assistant: ```c
_spc(x) int x;
{
  while (x-- > 0)
    _out(" ");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jle    L19
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  jmp    L29
L19:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_infered: string
name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D23: 
 Enter Number: 

tool: D0: %d

tool: D26: 
 -1 

assistant: ```c
int main() {
  int num;
  printf("\n Enter Number: ");
  scanf("%d", &num);
  if (num > 1)
    is_prime(num);
  else
    printf("\n -1 ");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x1,%edi
  jle    L3
  call   <is_prime@plt>
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L13
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D26
type: string
name: unpack_data
arguments: data_label: D13
type: string

tool: D9: 
 Enter Number: 

tool: D26: %d

tool: D13: 
 -1 

assistant: ```c
int main() {
  int num;
  printf("\n Enter Number: ");
  scanf("%d", &num);
  if (num > 1)
    is_prime(num);
  else
    printf("\n -1 ");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x1,%edi
  jle    L7
  call   <is_prime@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D12
datatype: string

tool: D17: 
 Enter Number: 

tool: D1: %d

tool: D12: 
 -1 

assistant: ```c
int main() {
  int num;
  printf("\n Enter Number: ");
  scanf("%d", &num);
  if (num > 1)
    is_prime(num);
  else
    printf("\n -1 ");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  cmp    $0x1,%edi
  jle    L19
  call   <is_prime@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D11
type: string

tool: D10: 
 Enter Number: 

tool: D15: %d

tool: D11: 
 -1 

assistant: ```c
int main() {
  int num;
  printf("\n Enter Number: ");
  scanf("%d", &num);
  if (num > 1)
    is_prime(num);
  else
    printf("\n -1 ");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L32
L46:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L46
  addq   $0x1,-0x20(%rbp)
L32:
  cmpq   $0x0,-0x18(%rbp)
  je     L26
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L26
  cmpq   $0x0,-0x20(%rbp)
  je     L26
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
L26:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strspn(const char *cs, const char *ct) {
  size_t i = 0;
  for (; cs && *cs && ct && *ct; ct++)
    for (; *ct == *cs; i++, cs++)
      ;
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<strspn>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L47
  lea    0x1(%rsi),%r8
  mov    $0x0,%eax
  jmp    L3
L32:
  lea    (%rdx,%rsi,1),%rax
  add    $0x1,%rdx
  cmp    %cl,(%rdx)
  je     L32
  mov    %rdx,%rdi
L40:
  add    $0x1,%r8
  cmpb   $0x0,(%rdi)
  je     L38
L3:
  movzbl -0x1(%r8),%ecx
  test   %cl,%cl
  je     L38
  mov    %rdi,%rdx
  lea    0x1(%rax),%rsi
  sub    %rdi,%rsi
  cmp    (%rdi),%cl
  je     L32
  jmp    L40
L47:
  mov    $0x0,%eax
L38:
  ret
```

assistant: ```c
size_t strspn(const char *cs, const char *ct) {
  size_t i = 0;
  for (; cs && *cs && ct && *ct; ct++)
    for (; *ct == *cs; i++, cs++)
      ;
  return (i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strspn>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L12
  nopl   0x0(%rax,%rax,1)
L5:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L0
  movzbl (%rdi),%ecx
  lea    0x1(%rax),%r9
  mov    %rdi,%rdx
  sub    %rdi,%r9
  cmp    %cl,%r8b
  jne    L8
  nopl   0x0(%rax,%rax,1)
L25:
  lea    (%rdx,%r9,1),%rax
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L25
  mov    %rdx,%rdi
L8:
  add    $0x1,%rsi
  test   %cl,%cl
  jne    L5
L0:
  ret
L12:
  ret
```

assistant: ```c
size_t strspn(const char *cs, const char *ct) {
  size_t i = 0;
  for (; cs && *cs && ct && *ct; ct++)
    for (; *ct == *cs; i++, cs++)
      ;
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strspn>:
  endbr64
  movzbl (%rdi),%r8d
  xor    %eax,%eax
  test   %r8b,%r8b
  je     L29
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L38
  cs nopw 0x0(%rax,%rax,1)
L3:
  lea    0x1(%rax),%rcx
  sub    %rdi,%rcx
  cmp    %r8b,%dl
  jne    L20
  nopl   0x0(%rax)
L25:
  lea    (%rdi,%rcx,1),%rax
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  cmp    %r8b,%dl
  je     L25
  add    $0x1,%rsi
  test   %dl,%dl
  je     L38
L8:
  mov    %edx,%r8d
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L3
L38:
  ret
  nopl   0x0(%rax)
L20:
  add    $0x1,%rsi
  mov    %r8d,%edx
  jmp    L8
L29:
  ret
```

assistant: ```c
size_t strspn(const char *cs, const char *ct) {
  size_t i = 0;
  for (; cs && *cs && ct && *ct; ct++)
    for (; *ct == *cs; i++, cs++)
      ;
  return (i);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<numDistinct0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L15
L8:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  addl   $0x1,-0x24(%rbp)
L15:
  mov    -0x24(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L8
  movl   $0x1,-0x20(%rbp)
  jmp    L60
L0:
  movl   $0x1,-0x1c(%rbp)
  jmp    L51
L6:
  mov    -0x20(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L23
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L12
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L12:
  addl   $0x1,-0x1c(%rbp)
L51:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L6
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x20(%rbp)
L60:
  mov    -0x20(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L0
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int numDistinct0(char *s, char *t) {
  int sLen = strlen(s), tLen = strlen(t);
  int *pre = (int *)malloc(sizeof(int) * (sLen + 1));
  int *cur = (int *)malloc(sizeof(int) * (sLen + 1));
  for (int i = 0; i <= sLen; i++)
    pre[i] = 1;
  for (int i = 1; i <= tLen; i++) {
    for (int j = 1; j <= sLen; j++) {
      if (t[i - 1] != s[j - 1])
        cur[j] = cur[j - 1];
      else
        cur[j] = cur[j - 1] + pre[j - 1];
    }
    memcpy(pre, cur, sizeof(int) * (sLen + 1));
  }
  return pre[sLen];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<numDistinct0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(,%r14,4),%ebx
  mov    %ebx,0x18(%rsp)
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r15
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r14d,%r14d
  js     L57
  mov    %r15,%rax
  mov    %r14d,%edx
  lea    0x4(%r15,%rdx,4),%rdx
L6:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L6
L57:
  cmpl   $0x0,0x4(%rsp)
  jle    L54
  lea    0x4(%r13),%rax
  mov    %rax,%rbx
  mov    %rax,0x10(%rsp)
  lea    -0x1(%r14),%eax
  lea    (%rbx,%rax,4),%rbp
  mov    %r12,%rdi
  mov    %r12,%rbx
  mov    %r15,%r12
  sub    %r13,%r12
  mov    $0x1,%eax
  sub    %edi,%eax
  mov    %eax,0x1c(%rsp)
  jmp    L14
L72:
  mov    (%rax),%esi
  mov    %esi,(%rcx)
L98:
  add    $0x1,%rdx
  add    $0x4,%rax
  add    $0x4,%rcx
  cmp    %rbp,%rax
  je     L49
L10:
  movzbl (%rdx),%edi
  cmp    %dil,(%rbx)
  jne    L72
  mov    (%rax),%esi
  add    (%r12,%rax,1),%esi
  mov    %esi,(%rcx)
  jmp    L98
L49:
  mov    0x18(%rsp),%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  add    $0x1,%rbx
  mov    0x1c(%rsp),%eax
  add    %ebx,%eax
  cmp    %eax,0x4(%rsp)
  jl     L54
L14:
  mov    0x8(%rsp),%rdx
  mov    0x10(%rsp),%rcx
  mov    %r13,%rax
  test   %r14d,%r14d
  jg     L10
  jmp    L49
L54:
  movslq %r14d,%r14
  mov    (%r15,%r14,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int numDistinct0(char *s, char *t) {
  int sLen = strlen(s), tLen = strlen(t);
  int *pre = (int *)malloc(sizeof(int) * (sLen + 1));
  int *cur = (int *)malloc(sizeof(int) * (sLen + 1));
  for (int i = 0; i <= sLen; i++)
    pre[i] = 1;
  for (int i = 1; i <= tLen; i++) {
    for (int j = 1; j <= sLen; j++) {
      if (t[i - 1] != s[j - 1])
        cur[j] = cur[j - 1];
      else
        cur[j] = cur[j - 1] + pre[j - 1];
    }
    memcpy(pre, cur, sizeof(int) * (sLen + 1));
  }
  return pre[sLen];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<numDistinct0>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%r14d
  mov    %eax,0x4(%rsp)
  call   <strlen@plt>
  lea    0x4(,%r14,4),%r15d
  mov    %r15d,%edi
  mov    %eax,0x10(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r14d,%r14d
  js     L35
  movslq 0x4(%rsp),%rsi
  mov    %r12,%rax
  mov    %rsi,0x18(%rsp)
  lea    0x4(%r12,%rsi,4),%rdx
  nopl   0x0(%rax,%rax,1)
L32:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L32
L39:
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  jle    L51
  mov    0x4(%rsp),%eax
  mov    %rbx,%r14
  mov    %r12,%rbx
  sub    %r13,%rbx
  sub    $0x1,%eax
  lea    0x4(%r13,%rax,4),%rbp
  mov    $0x1,%eax
  sub    %r14d,%eax
  mov    %eax,0x14(%rsp)
  nopl   0x0(%rax,%rax,1)
L14:
  mov    0x4(%rsp),%ecx
  mov    0x8(%rsp),%rdx
  mov    %r13,%rax
  test   %ecx,%ecx
  jle    L55
L43:
  mov    (%rax),%edi
  mov    %rax,%r10
  movzbl (%rdx),%ecx
  add    $0x4,%rax
  cmp    %cl,(%r14)
  jne    L72
  add    (%rbx,%r10,1),%edi
L72:
  mov    %edi,(%rax)
  add    $0x1,%rdx
  cmp    %rax,%rbp
  jne    L43
L55:
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%r14
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  add    %r14d,%eax
  cmp    0x10(%rsp),%eax
  jle    L14
L51:
  mov    0x18(%rsp),%rax
  mov    (%r12,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  movslq 0x4(%rsp),%rax
  mov    %rax,0x18(%rsp)
  jmp    L39
```

assistant: ```c
int numDistinct0(char *s, char *t) {
  int sLen = strlen(s), tLen = strlen(t);
  int *pre = (int *)malloc(sizeof(int) * (sLen + 1));
  int *cur = (int *)malloc(sizeof(int) * (sLen + 1));
  for (int i = 0; i <= sLen; i++)
    pre[i] = 1;
  for (int i = 1; i <= tLen; i++) {
    for (int j = 1; j <= sLen; j++) {
      if (t[i - 1] != s[j - 1])
        cur[j] = cur[j - 1];
      else
        cur[j] = cur[j - 1] + pre[j - 1];
    }
    memcpy(pre, cur, sizeof(int) * (sLen + 1));
  }
  return pre[sLen];
}
```