ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<list_alloc_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x24(%rbp),%eax
  cmp    $0x7,%eax
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
  mov    -0x24(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L26
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L48
L14:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
L48:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L14
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L26:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L35
L6:
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
L35:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_alloc_aux>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x1,%edi
  call   <assert@plt>
  cmp    $0x7,%ebp
  seta   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L28
L40:
  mov    (%r12),%rax
  mov    %rax,(%rbx)
L58:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    %ebp,%edi
  shl    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L50
  mov    %ebp,%edx
  shl    $0x5,%edx
  sub    %ebp,%edx
  movslq %edx,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rax
  jae    L17
  movslq %ebp,%rbp
L2:
  mov    %rax,%rcx
  add    %rbp,%rax
  mov    %rax,(%rcx)
  cmp    %rax,%rdx
  ja     L2
L17:
  movq   $0x0,(%rdx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L61
L50:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  jmp    L58
L61:
  mov    %rax,%r12
  jmp    L40
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: What is the c source code of the assembly code below:

```asm
<list_alloc_aux>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  seta   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L58
L18:
  mov    (%r12),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L58:
  mov    %ebp,%r13d
  shl    $0x5,%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L27
  sub    %ebp,%r13d
  movslq %r13d,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rax
  jae    L2
  nopl   (%rax)
L38:
  mov    %rax,%rcx
  add    %rbp,%rax
  mov    %rax,(%rcx)
  cmp    %rdx,%rax
  jb     L38
L2:
  movq   $0x0,(%rdx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L10
L27:
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %rax,%r12
  jmp    L18
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: What is the c source code of the assembly code below?

```asm
<list_alloc_aux>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  mov    $0x1,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <assert@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebp
  seta   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    (%rbx),%r12
  test   %r12,%r12
  je     L8
L24:
  mov    (%r12),%rax
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  mov    %ebp,%r13d
  shl    $0x5,%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L13
  sub    %ebp,%r13d
  movslq %r13d,%rdx
  add    %rax,%rdx
  cmp    %rdx,%rax
  jae    L56
  nopl   (%rax)
L46:
  mov    %rax,%rcx
  add    %rbp,%rax
  mov    %rax,(%rcx)
  cmp    %rdx,%rax
  jb     L46
L56:
  movq   $0x0,(%rdx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L59
L13:
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L59:
  mov    %rax,%r12
  jmp    L24
```

assistant: ```c
void *list_alloc_aux(int size, void *pfreelist) {
  void **px;
  void **pfree = pfreelist;
  void **plast;
  assert(sizeof(char) == 1);
  assert(size >= sizeof(void *));
  assert(pfreelist != NULL);
  assert(32 > 0);
  ;
  if (!*pfree) {
    if ((*pfree = malloc(32 * size))) {
      px = *pfree;
      plast = (void **)((char *)*pfree + ((32 - 1) * size));
      while (px < plast)
        *px = (char *)px + size, px = *px;
      *plast = NULL;
    }
  }
  if ((px = *pfree))
    *pfree = *px;
  else
    errno = ENOMEM;
  ;
  return (px);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mov_m16_reg16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  or     $0x5,%eax
  mov    %eax,%edi
  call   <put8@plt>
  mov    -0x8(%rbp),%rax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void mov_m16_reg16(unsigned short *m16, int reg16) {
  put8(0x66);
  put8(0x89);
  put8((reg16 << 3) | 5);
  put32((unsigned int)(m16));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mov_m16_reg16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x66,%edi
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x5(,%rbp,8),%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mov_m16_reg16(unsigned short *m16, int reg16) {
  put8(0x66);
  put8(0x89);
  put8((reg16 << 3) | 5);
  put32((unsigned int)(m16));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mov_m16_reg16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x66,%edi
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x5(,%rbp,8),%edi
  call   <put8@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_m16_reg16(unsigned short *m16, int reg16) {
  put8(0x66);
  put8(0x89);
  put8((reg16 << 3) | 5);
  put32((unsigned int)(m16));
}
```
user: What is the c source code of the assembly code below?

```asm
<mov_m16_reg16>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x66,%edi
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0x89,%edi
  call   <put8@plt>
  lea    0x5(,%rbp,8),%edi
  call   <put8@plt>
  add    $0x8,%rsp
  mov    %ebx,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void mov_m16_reg16(unsigned short *m16, int reg16) {
  put8(0x66);
  put8(0x89);
  put8((reg16 << 3) | 5);
  put32((unsigned int)(m16));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inotify_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int inotify_init(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inotify_init>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int inotify_init(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inotify_init>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int inotify_init(void) {
  errno = ENOSYS;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<inotify_init>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int inotify_init(void) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_rstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L0
  movq   $0x0,-0x10(%rbp)
  jmp    L32
L26:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L32:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  mov    -0x10(%rbp),%rax
  jmp    L17
L0:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
char *str_rstr(char *haystack, const char *needle) {
  if (*haystack) {
    char *p, *q;
    for (q = NULL; (p = strstr(haystack, needle)); q = p, haystack = p + 1)
      ;
    return q;
  } else
    return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_rstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  cmpb   $0x0,(%rdi)
  jne    L12
  jmp    L28
L0:
  lea    0x1(%rax),%rdi
  mov    %rax,%rbp
L12:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L0
L28:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *str_rstr(char *haystack, const char *needle) {
  if (*haystack) {
    char *p, *q;
    for (q = NULL; (p = strstr(haystack, needle)); q = p, haystack = p + 1)
      ;
    return q;
  } else
    return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_rstr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L15
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L11:
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
L15:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L11
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_rstr(char *haystack, const char *needle) {
  if (*haystack) {
    char *p, *q;
    for (q = NULL; (p = strstr(haystack, needle)); q = p, haystack = p + 1)
      ;
    return q;
  } else
    return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_rstr>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  jne    L8
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L24:
  lea    0x1(%rax),%rdi
  mov    %rax,%r12
L8:
  mov    %rbx,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L24
L25:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *str_rstr(char *haystack, const char *needle) {
  if (*haystack) {
    char *p, *q;
    for (q = NULL; (p = strstr(haystack, needle)); q = p, haystack = p + 1)
      ;
    return q;
  } else
    return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_fabsf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float my_fabsf(float x) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  u.i &= 0x7fffffff;
  return u.f;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_fabsf>:
  endbr64
  movd   %xmm0,%eax
  and    $0x7fffffff,%eax
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float my_fabsf(float x) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  u.i &= 0x7fffffff;
  return u.f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_fabsf>:
  endbr64
  movd   %xmm0,%eax
  and    $0x7fffffff,%eax
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float my_fabsf(float x) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  u.i &= 0x7fffffff;
  return u.f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_fabsf>:
  endbr64
  movd   %xmm0,%eax
  and    $0x7fffffff,%eax
  movd   %eax,%xmm0
  ret
```

assistant: ```c
float my_fabsf(float x) {
  union {
    float f;
    uint32_t i;
  } u = {x};
  u.i &= 0x7fffffff;
  return u.f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  subl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_imatrix(int **m, int num_row) {
  int i;
  for (i = num_row - 1; i >= 0; i--)
    free(m[i]);
  free(m);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<free_imatrix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  sub    $0x1,%esi
  js     L0
  movslq %esi,%rbx
L14:
  mov    0x0(%rbp,%rbx,8),%rdi
  call   <free@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L14
L0:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free_imatrix(int **m, int num_row) {
  int i;
  for (i = num_row - 1; i >= 0; i--)
    free(m[i]);
  free(m);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_imatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%esi
  js     L8
  movslq %esi,%rbx
  nopl   (%rax)
L5:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <free@plt>
  test   %ebx,%ebx
  jns    L5
L8:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_imatrix(int **m, int num_row) {
  int i;
  for (i = num_row - 1; i >= 0; i--)
    free(m[i]);
  free(m);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_imatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  sub    $0x1,%esi
  js     L5
  movslq %esi,%rbx
  nopl   (%rax)
L9:
  mov    0x0(%rbp,%rbx,8),%rdi
  sub    $0x1,%rbx
  call   <free@plt>
  test   %ebx,%ebx
  jns    L9
L5:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_imatrix(int **m, int num_row) {
  int i;
  for (i = num_row - 1; i >= 0; i--)
    free(m[i]);
  free(m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<store24bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  sar    $0x8,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  sar    $0x10,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  sar    $0x18,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void store24bit(void *data, int pos, uint32_t expanded_value) {
  ((uint8_t *)data)[3 * pos] = expanded_value >> 8;
  ((uint8_t *)data)[3 * pos + 1] = expanded_value >> 16;
  ((uint8_t *)data)[3 * pos + 2] = expanded_value >> 24;
}
```
user: Translate the below assembly code into C programming language:

```asm
<store24bit>:
  endbr64
  lea    (%rsi,%rsi,2),%eax
  cltq
  mov    %edx,%ecx
  sar    $0x8,%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  mov    %edx,%ecx
  sar    $0x10,%ecx
  mov    %ecx,(%rdi,%rax,4)
  sar    $0x18,%edx
  mov    %edx,0x4(%rdi,%rax,4)
  ret
```

assistant: ```c
void store24bit(void *data, int pos, uint32_t expanded_value) {
  ((uint8_t *)data)[3 * pos] = expanded_value >> 8;
  ((uint8_t *)data)[3 * pos + 1] = expanded_value >> 16;
  ((uint8_t *)data)[3 * pos + 2] = expanded_value >> 24;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store24bit>:
  endbr64
  mov    %edx,%ecx
  lea    (%rsi,%rsi,2),%eax
  cltq
  sar    $0x8,%ecx
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,%ecx
  add    $0x1,%rax
  sar    $0x18,%edx
  sar    $0x10,%ecx
  mov    %edx,0x4(%rdi,%rax,4)
  mov    %ecx,(%rdi,%rax,4)
  ret
```

assistant: ```c
void store24bit(void *data, int pos, uint32_t expanded_value) {
  ((uint8_t *)data)[3 * pos] = expanded_value >> 8;
  ((uint8_t *)data)[3 * pos + 1] = expanded_value >> 16;
  ((uint8_t *)data)[3 * pos + 2] = expanded_value >> 24;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<store24bit>:
  endbr64
  mov    %edx,%ecx
  lea    (%rsi,%rsi,2),%eax
  sar    $0x8,%ecx
  cltq
  movd   %ecx,%xmm0
  mov    %edx,%ecx
  sar    $0x18,%edx
  sar    $0x10,%ecx
  mov    %edx,0x8(%rdi,%rax,4)
  movd   %ecx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rdi,%rax,4)
  ret
```

assistant: ```c
void store24bit(void *data, int pos, uint32_t expanded_value) {
  ((uint8_t *)data)[3 * pos] = expanded_value >> 8;
  ((uint8_t *)data)[3 * pos + 1] = expanded_value >> 16;
  ((uint8_t *)data)[3 * pos + 2] = expanded_value >> 24;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hr20GetTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x150,%rsp
  mov    %edi,-0x144(%rbp)
  mov    %esi,-0x148(%rbp)
  mov    %rdx,-0x150(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x148(%rbp),%ecx
  mov    -0x144(%rbp),%edx
  lea    -0x130(%rbp),%rax
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
L25:
  lea    -0x110(%rbp),%rdx
  lea    -0x130(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <serialCommand@plt>
  movzbl -0x110(%rbp),%eax
  cmp    $0x52,%al
  je     L26
  mov    $0x3e8,%edi
  call   <usleep@plt>
  jmp    L25
L26:
  nop
  lea    -0x110(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x138(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x138(%rbp)
  mov    -0x138(%rbp),%rdx
  mov    -0x150(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D1: R%d%d

tool: D11: =

assistant: ```c
void hr20GetTimer(int day, int slot, char *value) {
  char buffer[20];
  char response[255];
  char *result;
  sprintf(buffer, "\rR%d%d\r", day, slot);
  while (1) {
    serialCommand(buffer, response);
    if (response[0] == 'R')
      break;
    usleep(1000);
  }
  result = strtok(response, "=");
  result = strtok(NULL, "=");
  strcpy(value, result);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hr20GetTimer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %esi,%ecx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %edi,%edx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    0x20(%rsp),%rbx
  jmp    L21
L4:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L21:
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <serialCommand@plt>
  cmpb   $0x52,0x20(%rsp)
  jne    L4
  lea    0x20(%rsp),%rdi
  lea    D0(%rip),%rbx
  mov    %rbx,%rsi
  call   <strtok@plt>
  mov    %rbx,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x138,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string
name: retrieve_data
arguments: data_tag: D0
type: string

tool: D2: R%d%d

tool: D0: =

assistant: ```c
void hr20GetTimer(int day, int slot, char *value) {
  char buffer[20];
  char response[255];
  char *result;
  sprintf(buffer, "\rR%d%d\r", day, slot);
  while (1) {
    serialCommand(buffer, response);
    if (response[0] == 'R')
      break;
    usleep(1000);
  }
  result = strtok(response, "=");
  result = strtok(NULL, "=");
  strcpy(value, result);
}
```