ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    $0x2,%eax
L74:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L74
  lea    0x8(%rsp),%rbx
  mov    %rbx,%r9
  mov    $0x2,%edi
  jmp    L95
L80:
  add    $0x4,%rsi
L48:
  add    $0x1,%ecx
  cmp    $0x64,%ecx
  je     L38
  cmp    %edi,%ecx
  je     L80
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  je     L80
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L80
  movl   $0x0,0x4(%rsi)
  jmp    L80
L38:
  add    $0x1,%edi
  add    $0x4,%r9
  cmp    $0x64,%edi
  je     L2
L95:
  mov    %r9,%rsi
  mov    %edi,%ecx
  cmp    $0x63,%edi
  jle    L48
  jmp    L38
L2:
  lea    0x190(%rsp),%rbp
  lea    D7(%rip),%r12
  jmp    L25
L76:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L100
L25:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L76
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L76
L100:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[100];
  for (int i = 2; i < 100; ++i) {
    nums[i] = i;
  }
  for (int i = 2; i < 100; ++i) {
    for (int j = i; j < 100; ++j) {
      if (i != j && nums[j] != 0 && (nums[j] % i == 0)) {
        nums[j] = 0;
      }
    }
  }
  for (int k = 2; k < 100; ++k) {
    if (nums[k] != 0) {
      printf("%d\n", nums[k]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  mov    $0x2,%eax
  mov    %rsp,%rdx
  nopl   0x0(%rax,%rax,1)
L55:
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L55
  lea    0x8(%rsp),%rbx
  mov    $0x2,%edi
  mov    %rbx,%r8
  nopw   0x0(%rax,%rax,1)
L73:
  mov    %r8,%rsi
  mov    %edi,%ecx
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    %edi,%ecx
  je     L24
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  je     L24
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L24
  movl   $0x0,0x4(%rsi)
L24:
  add    $0x4,%rsi
L92:
  add    $0x1,%ecx
  cmp    $0x64,%ecx
  jne    L16
  add    $0x1,%edi
  add    $0x4,%r8
  cmp    $0x64,%edi
  jne    L73
  lea    0x190(%rsp),%rbp
  lea    D9(%rip),%r12
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  je     L76
L36:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L11
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L36
L76:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string

tool: D9: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[100];
  for (int i = 2; i < 100; ++i) {
    nums[i] = i;
  }
  for (int i = 2; i < 100; ++i) {
    for (int j = i; j < 100; ++j) {
      if (i != j && nums[j] != 0 && (nums[j] % i == 0)) {
        nums[j] = 0;
      }
    }
  }
  for (int k = 2; k < 100; ++k) {
    if (nums[k] != 0) {
      printf("%d\n", nums[k]);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  movdqa D29(%rip),%xmm0
  movdqa D23(%rip),%xmm2
  lea    0x8(%rsp),%rbx
  mov    %rsp,%rbp
  lea    0x188(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rbx,%rax
  nopl   (%rax)
L89:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L89
  mov    D33(%rip),%rax
  mov    $0x2,%edi
  mov    %rbx,%r10
  mov    $0x2,%r8d
  lea    0x1(%rdi),%r9d
  mov    %rax,0x188(%rsp)
  cmp    $0x63,%edi
  je     L55
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %r10,%rsi
  mov    %r9d,%ecx
  xchg   %ax,%ax
L110:
  cmp    %r8d,%ecx
  je     L117
  mov    0x4(%rsi),%eax
  test   %eax,%eax
  je     L117
  cltd
  idiv   %edi
  test   %edx,%edx
  jne    L117
  movl   $0x0,0x4(%rsi)
L117:
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    $0x64,%ecx
  jne    L110
  mov    %r9d,%edi
  add    $0x1,%r8d
  add    $0x4,%r10
  lea    0x1(%rdi),%r9d
  cmp    $0x63,%edi
  jne    L3
L55:
  add    $0x190,%rbp
  lea    D11(%rip),%r12
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  je     L20
L26:
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L37
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L26
L20:
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D29
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D23
type: byte[16]
name: extract_symbolic_data
arguments: data_label: D33
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D11
type: string

tool: {"D29": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D23": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D33": [0x62,0x00,0x00,0x00,0x63,0x00,0x00,0x00]}

tool: D11: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[100];
  for (int i = 2; i < 100; ++i) {
    nums[i] = i;
  }
  for (int i = 2; i < 100; ++i) {
    for (int j = i; j < 100; ++j) {
      if (i != j && nums[j] != 0 && (nums[j] % i == 0)) {
        nums[j] = 0;
      }
    }
  }
  for (int k = 2; k < 100; ++k) {
    if (nums[k] != 0) {
      printf("%d\n", nums[k]);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<set_audio_driver_from_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_audio_driver_from_str(const char *tmp) {
  (void)tmp;
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_audio_driver_from_str>:
  endbr64
  ret
```

assistant: ```c
void set_audio_driver_from_str(const char *tmp) {
  (void)tmp;
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_audio_driver_from_str>:
  endbr64
  ret
```

assistant: ```c
void set_audio_driver_from_str(const char *tmp) {
  (void)tmp;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_audio_driver_from_str>:
  endbr64
  ret
```

assistant: ```c
void set_audio_driver_from_str(const char *tmp) {
  (void)tmp;
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<execv_perf_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <prepare_perf_cmd@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <execvp@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: perf

assistant: ```c
int execv_perf_cmd(const char **argv) {
  const char **nargv = prepare_perf_cmd(argv);
  execvp("perf", (char **)nargv);
  free(nargv);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<execv_perf_cmd>:
  endbr64
  push   %rbx
  call   <prepare_perf_cmd@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D8(%rip),%rdi
  call   <execvp@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string

tool: D8: perf

assistant: ```c
int execv_perf_cmd(const char **argv) {
  const char **nargv = prepare_perf_cmd(argv);
  execvp("perf", (char **)nargv);
  free(nargv);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<execv_perf_cmd>:
  endbr64
  push   %rbp
  call   <prepare_perf_cmd@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <execvp@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: perf

assistant: ```c
int execv_perf_cmd(const char **argv) {
  const char **nargv = prepare_perf_cmd(argv);
  execvp("perf", (char **)nargv);
  free(nargv);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<execv_perf_cmd>:
  endbr64
  push   %rbp
  call   <prepare_perf_cmd@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <execvp@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: perf

assistant: ```c
int execv_perf_cmd(const char **argv) {
  const char **nargv = prepare_perf_cmd(argv);
  execvp("perf", (char **)nargv);
  free(nargv);
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L21
L3:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x64(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <send@plt>
  lea    -0x60(%rbp),%rax
  mov    $0x50,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L21:
  lea    -0x60(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x50,%edx
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <recv@plt>
  mov    %eax,-0x64(%rbp)
  cmpl   $0x0,-0x64(%rbp)
  jne    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: child received: %s

assistant: ```c
int main() {
  char buffer[80];
  int rc;
  while (rc = recv(3, buffer, sizeof(buffer), 0)) {
    printf("child received: %s", buffer);
    send(3, buffer, rc, 0);
    memset(buffer, 0, sizeof(buffer));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%r12
  jmp    L21
L16:
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <send@plt>
  mov    $0x50,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
L21:
  mov    %rsp,%rsi
  mov    $0x0,%ecx
  mov    $0x50,%edx
  mov    $0x3,%edi
  call   <recv@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L16
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string

tool: D1: child received: %s

assistant: ```c
int main() {
  char buffer[80];
  int rc;
  while (rc = recv(3, buffer, sizeof(buffer), 0)) {
    printf("child received: %s", buffer);
    send(3, buffer, rc, 0);
    memset(buffer, 0, sizeof(buffer));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  xor    %ecx,%ecx
  call   <send@plt>
  mov    $0x50,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
L14:
  xor    %ecx,%ecx
  mov    $0x50,%edx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <recv@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L19
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: child received: %s

assistant: ```c
int main() {
  char buffer[80];
  int rc;
  while (rc = recv(3, buffer, sizeof(buffer), 0)) {
    printf("child received: %s", buffer);
    send(3, buffer, rc, 0);
    memset(buffer, 0, sizeof(buffer));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  xor    %ecx,%ecx
  call   <send@plt>
  mov    $0x50,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
L2:
  xor    %ecx,%ecx
  mov    $0x50,%edx
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <recv@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L21
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D2: child received: %s

assistant: ```c
int main() {
  char buffer[80];
  int rc;
  while (rc = recv(3, buffer, sizeof(buffer), 0)) {
    printf("child received: %s", buffer);
    send(3, buffer, rc, 0);
    memset(buffer, 0, sizeof(buffer));
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <drawlogin@plt>
  mov    $0x0,%eax
  call   <destroy@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  init();
  drawlogin();
  destroy();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x0,%eax
  call   <drawlogin@plt>
  mov    $0x0,%eax
  call   <destroy@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  drawlogin();
  destroy();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <drawlogin@plt>
  xor    %eax,%eax
  call   <destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  drawlogin();
  destroy();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init@plt>
  xor    %eax,%eax
  call   <drawlogin@plt>
  xor    %eax,%eax
  call   <destroy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  init();
  drawlogin();
  destroy();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L5:
  mov    $0x3e8,%edi
  call   <mdelay@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L5
  nop
  nop
  leave
  ret
```

assistant: ```c
void delay(unsigned secs) {
  unsigned i;
  for (i = 0; i < secs; i++) {
    mdelay(1000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<delay>:
  endbr64
  test   %edi,%edi
  je     L4
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L9:
  mov    $0x3e8,%edi
  call   <mdelay@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
```

assistant: ```c
void delay(unsigned secs) {
  unsigned i;
  for (i = 0; i < secs; i++) {
    mdelay(1000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delay>:
  endbr64
  test   %edi,%edi
  je     L1
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x3e8,%edi
  add    $0x1,%ebx
  call   <mdelay@plt>
  cmp    %ebx,%ebp
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  ret
```

assistant: ```c
void delay(unsigned secs) {
  unsigned i;
  for (i = 0; i < secs; i++) {
    mdelay(1000);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<delay>:
  endbr64
  test   %edi,%edi
  je     L15
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x3e8,%edi
  add    $0x1,%ebx
  call   <mdelay@plt>
  cmp    %ebx,%ebp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
```

assistant: ```c
void delay(unsigned secs) {
  unsigned i;
  for (i = 0; i < secs; i++) {
    mdelay(1000);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uc0_rdphalf_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <RDP_E@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <RDP@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: uc0:rdphalf_1 - IGNORED


assistant: ```c
void uc0_rdphalf_1() {
  RDP_E("uc0:rdphalf_1 - IGNORED\n");
  RDP("uc0:rdphalf_1 - IGNORED\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uc0_rdphalf_1>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <RDP_E@plt>
  mov    %rbx,%rdi
  call   <RDP@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: uc0:rdphalf_1 - IGNORED


assistant: ```c
void uc0_rdphalf_1() {
  RDP_E("uc0:rdphalf_1 - IGNORED\n");
  RDP("uc0:rdphalf_1 - IGNORED\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uc0_rdphalf_1>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <RDP_E@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <RDP@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: uc0:rdphalf_1 - IGNORED


assistant: ```c
void uc0_rdphalf_1() {
  RDP_E("uc0:rdphalf_1 - IGNORED\n");
  RDP("uc0:rdphalf_1 - IGNORED\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uc0_rdphalf_1>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <RDP_E@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <RDP@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: uc0:rdphalf_1 - IGNORED


assistant: ```c
void uc0_rdphalf_1() {
  RDP_E("uc0:rdphalf_1 - IGNORED\n");
  RDP("uc0:rdphalf_1 - IGNORED\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ffiTestFloats7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  %xmm3,-0x10(%rbp)
  movss  %xmm4,-0x14(%rbp)
  movss  %xmm5,-0x18(%rbp)
  movss  %xmm6,-0x1c(%rbp)
  movss  -0x4(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  addss  -0xc(%rbp),%xmm0
  addss  -0x10(%rbp),%xmm0
  addss  -0x14(%rbp),%xmm0
  addss  -0x18(%rbp),%xmm0
  addss  -0x1c(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float ffiTestFloats7(float f1, float f2, float f3, float f4, float f5, float f6, float f7) {
  ;
  return (float)(f1 + f2 + f3 + f4 + f5 + f6 + f7);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ffiTestFloats7>:
  endbr64
  addss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  addss  %xmm3,%xmm0
  addss  %xmm4,%xmm0
  addss  %xmm5,%xmm0
  addss  %xmm6,%xmm0
  ret
```

assistant: ```c
float ffiTestFloats7(float f1, float f2, float f3, float f4, float f5, float f6, float f7) {
  ;
  return (float)(f1 + f2 + f3 + f4 + f5 + f6 + f7);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ffiTestFloats7>:
  endbr64
  addss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  addss  %xmm3,%xmm0
  addss  %xmm4,%xmm0
  addss  %xmm5,%xmm0
  addss  %xmm6,%xmm0
  ret
```

assistant: ```c
float ffiTestFloats7(float f1, float f2, float f3, float f4, float f5, float f6, float f7) {
  ;
  return (float)(f1 + f2 + f3 + f4 + f5 + f6 + f7);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ffiTestFloats7>:
  endbr64
  addss  %xmm1,%xmm0
  addss  %xmm2,%xmm0
  addss  %xmm3,%xmm0
  addss  %xmm4,%xmm0
  addss  %xmm5,%xmm0
  addss  %xmm6,%xmm0
  ret
```

assistant: ```c
float ffiTestFloats7(float f1, float f2, float f3, float f4, float f5, float f6, float f7) {
  ;
  return (float)(f1 + f2 + f3 + f4 + f5 + f6 + f7);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_EmptyMethod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _EmptyMethod(unsigned char bEnable) {
  ;
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_EmptyMethod>:
  endbr64
  ret
```

assistant: ```c
void _EmptyMethod(unsigned char bEnable) {
  ;
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_EmptyMethod>:
  endbr64
  ret
```

assistant: ```c
void _EmptyMethod(unsigned char bEnable) {
  ;
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_EmptyMethod>:
  endbr64
  ret
```

assistant: ```c
void _EmptyMethod(unsigned char bEnable) {
  ;
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<emergency>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  jmp    L21
L27:
  addl   $0x1,-0x74(%rbp)
L21:
  cmpl   $0x3,-0x74(%rbp)
  jle    L27
  mov    -0x84(%rbp),%eax
  mov    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <signal@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void emergency(int signo) {
  int i;
  char message[100];
  for (i = 0; i < 4; i++) {
  }
  signal(signo, emergency);
}
```
user: What is the c source code of the assembly code below:

```asm
<emergency>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rsi
  call   <signal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void emergency(int signo) {
  int i;
  char message[100];
  for (i = 0; i < 4; i++) {
  }
  signal(signo, emergency);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emergency>:
  endbr64
  mov    D4(%rip),%rsi
  jmp    1050 <signal@plt>
```

assistant: ```c
void emergency(int signo) {
  int i;
  char message[100];
  for (i = 0; i < 4; i++) {
  }
  signal(signo, emergency);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<emergency>:
  endbr64
  mov    D5(%rip),%rsi
  jmp    1050 <signal@plt>
```

assistant: ```c
void emergency(int signo) {
  int i;
  char message[100];
  for (i = 0; i < 4; i++) {
  }
  signal(signo, emergency);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x80000000,-0x4(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L10
L7:
  mov    -0x4(%rbp),%eax
  neg    %eax
L10:
  pop    %rbp
  ret
```

assistant: ```c
int g(int n) {
  if ((unsigned)n == (1u << 31))
    return -1;
  else
    return -n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  cmp    $0x80000000,%edi
  je     L9
  mov    %edi,%eax
  neg    %eax
  ret
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int g(int n) {
  if ((unsigned)n == (1u << 31))
    return -1;
  else
    return -n;
}
```