user: 请从给定的汇编指令推导出C源代码：

```asm
<gerarNumeros>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x6c000(%rsp),%r11
L15:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L15
  sub    $0x800,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x6c7f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x190(%rsp),%rbp
  call   <time@plt>
  mov    %r12,%rbx
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2d,%rdx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L46
  mov    %r12,%rdi
  mov    $0x64,%edx
  mov    %rbp,%rbx
  lea    D5(%rip),%rsi
  lea    0x1130(%rsp),%r12
  call   <salvarTXT@plt>
  nop
L2:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2d,%rdx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L2
  mov    %rbp,%rdi
  mov    $0x3e8,%edx
  mov    %r12,%rbx
  lea    D37(%rip),%rsi
  lea    0xad70(%rsp),%rbp
  call   <salvarTXT@plt>
  nop
L57:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2d,%rdx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbx)
  cmp    %rbx,%rbp
  jne    L57
  mov    %r12,%rdi
  mov    $0x2710,%edx
  mov    %rbp,%r12
  lea    D7(%rip),%rsi
  lea    0x6c7f0(%rsp),%rbx
  call   <salvarTXT@plt>
  nop
L47:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x14f8b589,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x2d,%rdx
  sub    %ecx,%edx
  imul   $0x186a0,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L47
  mov    $0x186a0,%edx
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <salvarTXT@plt>
  mov    0x6c7f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x6c800,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D37
type_infered: string
name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D5: vetorCem.txt

tool: D37: vetorMil.txt

tool: D7: vetorDezMil.txt

tool: D3: vetorCemMil.txt

assistant: ```c
void gerarNumeros() {
  int i, x;
  int vetCem[100];
  int vetMil[1000];
  int vetDezMil[10000];
  int vetCemMil[100000];
  srand((unsigned)time(NULL));
  for (i = 0; i < 100; i++) {
    x = rand() % 100000;
    vetCem[i] = x;
  }
  salvarTXT(vetCem, "vetorCem.txt", 100);
  for (i = 0; i < 1000; i++) {
    x = rand() % 100000;
    vetMil[i] = x;
  }
  salvarTXT(vetMil, "vetorMil.txt", 1000);
  for (i = 0; i < 10000; i++) {
    x = rand() % 100000;
    vetDezMil[i] = x;
  }
  salvarTXT(vetDezMil, "vetorDezMil.txt", 10000);
  for (i = 0; i < 100000; i++) {
    x = rand() % 100000;
    vetCemMil[i] = x;
  }
  salvarTXT(vetCemMil, "vetorCemMil.txt", 100000);
}
```