ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_nontemporal>:
  endbr64
  ret
```

assistant: ```c
void test_nontemporal() {
  int i;
#pragma omp distribute simd nontemporal(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int x, y;
#pragma omp distribute simd nontemporal(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd private(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y : 0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) lastprivate(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd lastprivate(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd order
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(none
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(concurrent
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(concurrent)
  for (int i = 0; i < 10; ++i)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_nontemporal>:
  endbr64
  ret
```

assistant: ```c
void test_nontemporal() {
  int i;
#pragma omp distribute simd nontemporal(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int x, y;
#pragma omp distribute simd nontemporal(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd private(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y : 0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) lastprivate(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd lastprivate(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd order
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(none
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(concurrent
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(concurrent)
  for (int i = 0; i < 10; ++i)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_nontemporal>:
  endbr64
  ret
```

assistant: ```c
void test_nontemporal() {
  int i;
#pragma omp distribute simd nontemporal(
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(,
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal()
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(int)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y, z)
  for (i = 0; i < 16; ++i)
    ;
  int x, y;
#pragma omp distribute simd nontemporal(x:)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x:, )
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd private(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) private(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x, y : 0)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd nontemporal(x) lastprivate(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd lastprivate(x) nontemporal(x)
  for (i = 0; i < 16; ++i)
    ;
#pragma omp distribute simd order
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(none
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(concurrent
  for (int i = 0; i < 10; ++i)
    ;
#pragma omp distribute simd order(concurrent)
  for (int i = 0; i < 10; ++i)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
L9:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %s


assistant: ```c
void fatal(int assert, const char message[], int status) {
  if (assert) {
    printf("%s\n", message);
    exit(status);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fatal>:
  endbr64
  test   %edi,%edi
  jne    L7
  ret
L7:
  push   %rbx
  mov    %edx,%ebx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %s


assistant: ```c
void fatal(int assert, const char message[], int status) {
  if (assert) {
    printf("%s\n", message);
    exit(status);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<fatal>:
  endbr64
  test   %edi,%edi
  jne    L8
  ret
  nopl   0x0(%rax)
L8:
  push   %rbp
  lea    D3(%rip),%rdi
  mov    %edx,%ebp
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string

tool: D3: %s


assistant: ```c
void fatal(int assert, const char message[], int status) {
  if (assert) {
    printf("%s\n", message);
    exit(status);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fatal>:
  endbr64
  test   %edi,%edi
  jne    L9
  ret
  nopl   0x0(%rax)
L9:
  push   %rbp
  lea    D6(%rip),%rdi
  mov    %edx,%ebp
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_guessed: string

tool: D6: %s


assistant: ```c
void fatal(int assert, const char message[], int status) {
  if (assert) {
    printf("%s\n", message);
    exit(status);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <main_args@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <icarus@plt>
  test   %eax,%eax
  jne    L15
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L15:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D1
data_type: string

tool: D7: main: option parsing failed

tool: D1: main: call to icarus failed

assistant: ```c
int main(int argc, char **argv) {
  struct ic_opts *opts = 0;
  opts = main_args(argc, argv);
  if (!opts) {
    puts("main: option parsing failed");
    exit(1);
  }
  if (!icarus(opts)) {
    puts("main: call to icarus failed");
    exit(1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  call   <main_args@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L30
L5:
  mov    %rbx,%rdi
  call   <icarus@plt>
  test   %eax,%eax
  je     L0
L31:
  mov    $0x0,%eax
  pop    %rbx
  ret
L30:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
L0:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L31
```

tool_calls: name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D16: main: option parsing failed

tool: D7: main: call to icarus failed

assistant: ```c
int main(int argc, char **argv) {
  struct ic_opts *opts = 0;
  opts = main_args(argc, argv);
  if (!opts) {
    puts("main: option parsing failed");
    exit(1);
  }
  if (!icarus(opts)) {
    puts("main: call to icarus failed");
    exit(1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  call   <main_args@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
L10:
  mov    %rbp,%rdi
  call   <icarus@plt>
  test   %eax,%eax
  je     L1
L35:
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L35
L7:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D8
data_type: string

tool: D18: main: call to icarus failed

tool: D8: main: option parsing failed

assistant: ```c
int main(int argc, char **argv) {
  struct ic_opts *opts = 0;
  opts = main_args(argc, argv);
  if (!opts) {
    puts("main: option parsing failed");
    exit(1);
  }
  if (!icarus(opts)) {
    puts("main: call to icarus failed");
    exit(1);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  call   <main_args@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L12
L19:
  mov    %rbp,%rdi
  call   <icarus@plt>
  test   %eax,%eax
  je     L32
L39:
  xor    %eax,%eax
  pop    %rbp
  ret
L32:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L39
L12:
  lea    D10(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D10
data_type: string

tool: D1: main: call to icarus failed

tool: D10: main: option parsing failed

assistant: ```c
int main(int argc, char **argv) {
  struct ic_opts *opts = 0;
  opts = main_args(argc, argv);
  if (!opts) {
    puts("main: option parsing failed");
    exit(1);
  }
  if (!icarus(opts)) {
    puts("main: call to icarus failed");
    exit(1);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parseline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  jmp    L61
L44:
  addq   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L92
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L44
L92:
  movl   $0x0,-0x18(%rbp)
  jmp    L62
L28:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L88
L86:
  addq   $0x1,-0x10(%rbp)
L88:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L62
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L86
L62:
  mov    -0x10(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  cmpl   $0x0,-0x18(%rbp)
  jne    L37
  mov    $0x1,%eax
  jmp    L32
L37:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x26,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L69
  subl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L69:
  mov    -0x14(%rbp),%eax
L32:
  leave
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0)
    argv[--argc] = NULL;
  return bg;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parseline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdi,%rsi
  lea    D1(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx),%rdx
  movb   $0x20,(%rax,%rdx,1)
  cmpb   $0x20,D1(%rip)
  jne    L76
L1:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L1
L76:
  mov    $0x0,%ebp
  jmp    L86
L69:
  add    $0x1,%rbp
L86:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L17
  mov    %rbx,(%r12,%rbp,8)
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbx
  cmpb   $0x20,0x1(%rax)
  jne    L69
L10:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L10
  jmp    L69
L17:
  movslq %ebp,%rax
  lea    0x0(,%rax,8),%rdx
  movq   $0x0,(%r12,%rax,8)
  mov    $0x1,%eax
  test   %ebp,%ebp
  je     L46
  mov    -0x8(%r12,%rdx,1),%rdx
  mov    $0x0,%eax
  cmpb   $0x26,(%rdx)
  je     L60
L46:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L60:
  lea    -0x1(%rbp),%eax
  cltq
  movq   $0x0,(%r12,%rax,8)
  mov    $0x1,%eax
  jmp    L46
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0)
    argv[--argc] = NULL;
  return bg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parseline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,-0x1(%rax,%rbx,1)
  cmpb   $0x20,D5(%rip)
  jne    L70
  nopl   0x0(%rax)
L10:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L10
L70:
  mov    %r12,%r14
  xor    %ebp,%ebp
  xchg   %ax,%ax
L75:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  lea    0x0(,%rbp,8),%rdx
  test   %rax,%rax
  je     L44
  mov    %rbx,(%r14)
  cmpb   $0x20,0x1(%rax)
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  jne    L69
  nopw   0x0(%rax,%rax,1)
L53:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L53
L69:
  add    $0x1,%rbp
  add    $0x8,%r14
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L44:
  movq   $0x0,(%r14)
  mov    $0x1,%eax
  test   %ebp,%ebp
  je     L6
  mov    -0x8(%r12,%rdx,1),%rdx
  xor    %eax,%eax
  cmpb   $0x26,(%rdx)
  je     L4
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  lea    -0x1(%rbp),%eax
  pop    %rbx
  pop    %rbp
  cltq
  movq   $0x0,(%r12,%rax,8)
  pop    %r12
  mov    $0x1,%eax
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0)
    argv[--argc] = NULL;
  return bg;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseline>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,-0x1(%rax,%rbx,1)
  cmpb   $0x20,D19(%rip)
  jne    L45
  nopl   0x0(%rax)
L9:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L9
L45:
  mov    %r12,%r14
  xor    %ebp,%ebp
  xchg   %ax,%ax
L67:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  lea    0x0(,%rbp,8),%rdx
  test   %rax,%rax
  je     L38
  mov    %rbx,(%r14)
  cmpb   $0x20,0x1(%rax)
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  jne    L7
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L43
L7:
  add    $0x1,%rbp
  add    $0x8,%r14
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L38:
  movq   $0x0,(%r14)
  mov    $0x1,%eax
  test   %ebp,%ebp
  je     L6
  mov    -0x8(%r12,%rdx,1),%rdx
  xor    %eax,%eax
  cmpb   $0x26,(%rdx)
  je     L50
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L50:
  lea    -0x1(%rbp),%eax
  pop    %rbx
  pop    %rbp
  cltq
  movq   $0x0,(%r12,%rax,8)
  pop    %r12
  mov    $0x1,%eax
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  int bg;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' '))
    buf++;
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  if ((bg = (*argv[argc - 1] == '&')) != 0)
    argv[--argc] = NULL;
  return bg;
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L6
L12:
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrtfcn@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  movss  -0x8(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D14(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L6:
  movss  D29(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  ja     L12
  movss  -0x8(%rbp),%xmm1
  movss  D28(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
datatype: f32
name: disassemble_data
arguments: tag: D29
datatype: f32
name: disassemble_data
arguments: tag: D28
datatype: byte[4]

tool: D14: 100

tool: D29: 10000

tool: {"D28": [0x00,0x50,0xc3,0x47]}

assistant: ```c
int benchmark() {
  float i = 0.0;
  volatile float accum = 0.0;
  for (i = 0.0; i < 10000.; i += 100.)
    accum += sqrtfcn(i);
  return (int)(accum * 100000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<benchmark>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,0xc(%rsp)
  mov    $0x64,%ebp
  mov    D28(%rip),%ebx
L0:
  movd   %ebx,%xmm0
  call   <sqrtfcn@plt>
  movss  0xc(%rsp),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,0xc(%rsp)
  movd   %ebx,%xmm2
  addss  D18(%rip),%xmm2
  movd   %xmm2,%ebx
  sub    $0x1,%ebp
  jne    L0
  movss  0xc(%rsp),%xmm0
  mulss  D0(%rip),%xmm0
  cvttss2si %xmm0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D28
type: f32
name: disassemble_data
arguments: tag: D18
type: f32
name: disassemble_data
arguments: tag: D0
type: byte[4]

tool: D28: 0

tool: D18: 100

tool: {"D0": [0x00,0x50,0xc3,0x47]}

assistant: ```c
int benchmark() {
  float i = 0.0;
  volatile float accum = 0.0;
  for (i = 0.0; i < 10000.; i += 100.)
    accum += sqrtfcn(i);
  return (int)(accum * 100000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<benchmark>:
  endbr64
  push   %rbx
  pxor   %xmm1,%xmm1
  mov    $0x64,%ebx
  sub    $0x20,%rsp
  movl   $0x0,0x1c(%rsp)
  nopw   0x0(%rax,%rax,1)
L2:
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <sqrtfcn@plt>
  pxor   %xmm0,%xmm0
  movss  0x1c(%rsp),%xmm2
  movss  0xc(%rsp),%xmm1
  cvtsi2ss %rax,%xmm0
  addss  D17(%rip),%xmm1
  addss  %xmm2,%xmm0
  movss  %xmm0,0x1c(%rsp)
  sub    $0x1,%ebx
  jne    L2
  movss  0x1c(%rsp),%xmm0
  mulss  D19(%rip),%xmm0
  add    $0x20,%rsp
  pop    %rbx
  cvttss2si %xmm0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type: f32
name: extract_symbolic_data
arguments: label: D19
type: byte[4]

tool: D17: 100

tool: {"D19": [0x00,0x50,0xc3,0x47]}

assistant: ```c
int benchmark() {
  float i = 0.0;
  volatile float accum = 0.0;
  for (i = 0.0; i < 10000.; i += 100.)
    accum += sqrtfcn(i);
  return (int)(accum * 100000);
}
```