ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<ast_args>:
  endbr64
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm5
  movapd %xmm0,%xmm3
  push   %r14
  mulsd  %xmm0,%xmm4
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  lea    D50(%rip),%rbx
  lea    0xc8(%rbx),%rbp
  mulsd  %xmm4,%xmm5
  sub    $0x28,%rsp
  movsd  D2(%rip),%xmm1
  movsd  D56(%rip),%xmm2
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm4,0x8(%rsp)
  mulsd  %xmm5,%xmm3
  movsd  %xmm5,0x10(%rsp)
  movq   %xmm3,%r14
L7:
  mulsd  D9(%rip),%xmm2
  add    $0x28,%rbx
  add    $0x8,%r12
  movsd  0x8(%rsp),%xmm0
  mulsd  0x18(%rsp),%xmm1
  mov    D40(%rip),%rax
  movsd  %xmm2,-0x8(%r12)
  mulsd  -0x18(%rbx),%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rsp),%xmm1
  mulsd  -0x10(%rbx),%xmm1
  addsd  %xmm1,%xmm0
  movq   %r14,%xmm1
  mulsd  -0x8(%rbx),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D35(%rip),%xmm0
  movq   %rax,%xmm1
  call   <fmod@plt>
  movsd  %xmm0,-0x8(%r12)
  cmp    %rbx,%rbp
  je     L13
  movsd  (%rbx),%xmm2
  movsd  0x8(%rbx),%xmm1
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D50
type_infered: f64
name: parse_data
arguments: data_label: D2
type_infered: f64
name: parse_data
arguments: data_label: D56
type_infered: f64
name: parse_data
arguments: data_label: D9
type_infered: f64
name: parse_data
arguments: data_label: D40
type_infered: byte[8]
name: parse_data
arguments: data_label: D35
type_infered: byte[8]

tool: D50: 134.96340251

tool: D2: 1717915923.2178

tool: D56: 134.96340251

tool: D9: 3600

tool: {"D40": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D35": [0x9d,0x8f,0xff,0xb2,0xa5,0x55,0xd4,0x3e]}

assistant: ```c
void ast_args(double t, double *f) {
  static const double fc[][5] = {{134.96340251, 1717915923.2178, 31.8792, 0.051635, -0.00024470}, {357.52910918, 129596581.0481, -0.5532, 0.000136, -0.00001149}, {93.27209062, 1739527262.8478, -12.7512, -0.001037, 0.00000417}, {297.85019547, 1602961601.2090, -6.3706, 0.006593, -0.00003169}, {125.04455501, -6962890.2665, 7.4722, 0.007702 - 0.00005939}};
  double tt[4];
  int i, j;
  for (tt[0] = t, i = 1; i < 4; i++)
    tt[i] = tt[i - 1] * t;
  for (i = 0; i < 5; i++) {
    f[i] = fc[i][0] * 3600.0;
    for (j = 0; j < 4; j++)
      f[i] += fc[i][j + 1] * tt[j];
    f[i] = fmod(f[i] * ((3.1415926535897932 / 180.0) / 3600.0), 2.0 * 3.1415926535897932);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ast_args>:
  endbr64
  movapd %xmm0,%xmm3
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm2
  push   %r14
  mulsd  %xmm0,%xmm3
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    D28(%rip),%rbx
  lea    0xc8(%rbx),%r12
  mulsd  %xmm3,%xmm4
  sub    $0x28,%rsp
  movsd  %xmm0,0x18(%rsp)
  movsd  %xmm3,0x8(%rsp)
  mulsd  %xmm4,%xmm2
  movsd  %xmm4,0x10(%rsp)
  movq   %xmm2,%r14
L3:
  movsd  D2(%rip),%xmm0
  mulsd  (%rbx),%xmm0
  add    $0x28,%rbx
  add    $0x8,%rbp
  movsd  0x18(%rsp),%xmm1
  mulsd  -0x20(%rbx),%xmm1
  mov    D6(%rip),%rax
  addsd  %xmm1,%xmm0
  movsd  0x8(%rsp),%xmm1
  mulsd  -0x18(%rbx),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x10(%rsp),%xmm1
  mulsd  -0x10(%rbx),%xmm1
  addsd  %xmm1,%xmm0
  movq   %r14,%xmm1
  mulsd  -0x8(%rbx),%xmm1
  addsd  %xmm1,%xmm0
  mulsd  D22(%rip),%xmm0
  movq   %rax,%xmm1
  call   <fmod@plt>
  movsd  %xmm0,-0x8(%rbp)
  cmp    %rbx,%r12
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
data_type: f64
name: disassemble_data
arguments: data_tag: D2
data_type: f64
name: disassemble_data
arguments: data_tag: D6
data_type: byte[8]
name: disassemble_data
arguments: data_tag: D22
data_type: byte[8]

tool: D28: 134.96340251

tool: D2: 3600

tool: {"D6": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D22": [0x9d,0x8f,0xff,0xb2,0xa5,0x55,0xd4,0x3e]}

assistant: ```c
void ast_args(double t, double *f) {
  static const double fc[][5] = {{134.96340251, 1717915923.2178, 31.8792, 0.051635, -0.00024470}, {357.52910918, 129596581.0481, -0.5532, 0.000136, -0.00001149}, {93.27209062, 1739527262.8478, -12.7512, -0.001037, 0.00000417}, {297.85019547, 1602961601.2090, -6.3706, 0.006593, -0.00003169}, {125.04455501, -6962890.2665, 7.4722, 0.007702 - 0.00005939}};
  double tt[4];
  int i, j;
  for (tt[0] = t, i = 1; i < 4; i++)
    tt[i] = tt[i - 1] * t;
  for (i = 0; i < 5; i++) {
    f[i] = fc[i][0] * 3600.0;
    for (j = 0; j < 4; j++)
      f[i] += fc[i][j + 1] * tt[j];
    f[i] = fmod(f[i] * ((3.1415926535897932 / 180.0) / 3600.0), 2.0 * 3.1415926535897932);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solcon_number_of_standard_solutions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x20,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int solcon_number_of_standard_solutions(int *length) {
  int *a, fail;
  double *c;
  fail = _ada_use_c2phc(32, a, length, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<solcon_number_of_standard_solutions>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    $0x20,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int solcon_number_of_standard_solutions(int *length) {
  int *a, fail;
  double *c;
  fail = _ada_use_c2phc(32, a, length, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<solcon_number_of_standard_solutions>:
  endbr64
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0x20,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int solcon_number_of_standard_solutions(int *length) {
  int *a, fail;
  double *c;
  fail = _ada_use_c2phc(32, a, length, c);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solcon_number_of_standard_solutions>:
  endbr64
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    $0x20,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int solcon_number_of_standard_solutions(int *length) {
  int *a, fail;
  double *c;
  fail = _ada_use_c2phc(32, a, length, c);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writemsg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %edi,-0xa4(%rbp)
  mov    %esi,-0xa8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0xa0(%rbp),%rax
  mov    $0x7f,%edx
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <mlreply@plt>
  mov    %eax,%ebx
  cmp    $0x1,%ebx
  je     L7
  mov    %ebx,%eax
  jmp    L17
L7:
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <makelit@plt>
  lea    -0xa0(%rbp),%rax
  mov    %rax,%rdi
  call   <mlforce@plt>
  mov    $0x1,%eax
L17:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: Message to write: 

assistant: ```c
writemsg(int f, int n) {
  register int status;
  char buf[128];
  if ((status = mlreply("Message to write: ", buf, 128 - 1)) != 1)
    return (status);
  makelit(buf);
  mlforce(buf);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writemsg>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x7f,%edx
  lea    D6(%rip),%rdi
  call   <mlreply@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  je     L28
L25:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <makelit@plt>
  mov    %rbp,%rdi
  call   <mlforce@plt>
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Message to write: 

assistant: ```c
writemsg(int f, int n) {
  register int status;
  char buf[128];
  if ((status = mlreply("Message to write: ", buf, 128 - 1)) != 1)
    return (status);
  makelit(buf);
  mlforce(buf);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writemsg>:
  endbr64
  push   %r12
  mov    $0x7f,%edx
  lea    D5(%rip),%rdi
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <mlreply@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  je     L25
L9:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x98,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  mov    %rbp,%rdi
  call   <makelit@plt>
  mov    %rbp,%rdi
  call   <mlforce@plt>
  jmp    L9
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: Message to write: 

assistant: ```c
writemsg(int f, int n) {
  register int status;
  char buf[128];
  if ((status = mlreply("Message to write: ", buf, 128 - 1)) != 1)
    return (status);
  makelit(buf);
  mlforce(buf);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writemsg>:
  endbr64
  push   %r12
  mov    $0x7f,%edx
  lea    D3(%rip),%rdi
  push   %rbp
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <mlreply@plt>
  mov    %eax,%r12d
  cmp    $0x1,%eax
  je     L2
L0:
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x98,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdi
  call   <makelit@plt>
  mov    %rbp,%rdi
  call   <mlforce@plt>
  jmp    L0
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: Message to write: 

assistant: ```c
writemsg(int f, int n) {
  register int status;
  char buf[128];
  if ((status = mlreply("Message to write: ", buf, 128 - 1)) != 1)
    return (status);
  makelit(buf);
  mlforce(buf);
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mult3drm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L14
L2:
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addq   $0x4,-0x10(%rbp)
  addq   $0x4,-0x8(%rbp)
  addl   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mult3drm(float *array1, float *array2, int Ntot) {
  int i;
  float tmp, *pt1, *pt2;
  pt1 = array1;
  pt2 = array2;
  for (i = 0; i < Ntot; i++) {
    tmp = *pt1 * *pt2;
    *pt1 = tmp;
    pt1++;
    pt2++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mult3drm>:
  endbr64
  test   %edx,%edx
  jle    L16
  mov    %edx,%edx
  mov    $0x0,%eax
L5:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L5
L16:
  ret
```

assistant: ```c
void mult3drm(float *array1, float *array2, int Ntot) {
  int i;
  float tmp, *pt1, *pt2;
  pt1 = array1;
  pt2 = array2;
  for (i = 0; i < Ntot; i++) {
    tmp = *pt1 * *pt2;
    *pt1 = tmp;
    pt1++;
    pt2++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mult3drm>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L0:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L0
L1:
  ret
```

assistant: ```c
void mult3drm(float *array1, float *array2, int Ntot) {
  int i;
  float tmp, *pt1, *pt2;
  pt1 = array1;
  pt2 = array2;
  for (i = 0; i < Ntot; i++) {
    tmp = *pt1 * *pt2;
    *pt1 = tmp;
    pt1++;
    pt2++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mult3drm>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L17
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L53
  cmp    $0x1,%edx
  je     L53
  lea    -0x1(%rdx),%eax
  mov    %edx,%r8d
  cmp    $0x2,%eax
  jbe    L98
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L28:
  movups (%rcx,%rax,1),%xmm0
  movups (%rsi,%rax,1),%xmm2
  mulps  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L28
  mov    %edx,%r10d
  and    $0xfffffffc,%r10d
  mov    %r10d,%r9d
  lea    0x0(,%r9,4),%rdi
  lea    (%rcx,%rdi,1),%rax
  add    %rsi,%rdi
  cmp    %r10d,%edx
  je     L17
  sub    %r10d,%edx
  mov    %edx,%r8d
  cmp    $0x1,%edx
  je     L63
L68:
  lea    (%rcx,%r9,4),%rdx
  movq   (%rsi,%r9,4),%xmm0
  mov    %r8d,%ecx
  movq   (%rdx),%xmm1
  and    $0xfffffffe,%ecx
  mulps  %xmm1,%xmm0
  movlps %xmm0,(%rdx)
  mov    %ecx,%edx
  shl    $0x2,%rdx
  add    %rdx,%rax
  add    %rdx,%rdi
  cmp    %ecx,%r8d
  je     L17
L63:
  movss  (%rax),%xmm0
  mulss  (%rdi),%xmm0
  movss  %xmm0,(%rax)
  ret
  nopl   0x0(%rax)
L53:
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L92:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L92
L17:
  ret
L98:
  mov    %rsi,%rdi
  mov    %rcx,%rax
  xor    %r9d,%r9d
  jmp    L68
```

assistant: ```c
void mult3drm(float *array1, float *array2, int Ntot) {
  int i;
  float tmp, *pt1, *pt2;
  pt1 = array1;
  pt2 = array2;
  for (i = 0; i < Ntot; i++) {
    tmp = *pt1 * *pt2;
    *pt1 = tmp;
    pt1++;
    pt2++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<stat_per_interval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x3e7,-0xc(%rbp)
  jg     L4
  movl   $0x3e8,-0xc(%rbp)
L4:
  pxor   %xmm0,%xmm0
  cvtsi2sdq -0x8(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sdl -0xc(%rbp),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double stat_per_interval(uint32_t value, int32_t dur) {
  if (dur < 1000)
    dur = 1000;
  return ((double)value / dur) * 1000000;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stat_per_interval>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdi,%xmm0
  mov    $0x3e8,%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D5(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double stat_per_interval(uint32_t value, int32_t dur) {
  if (dur < 1000)
    dur = 1000;
  return ((double)value / dur) * 1000000;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stat_per_interval>:
  endbr64
  mov    $0x3e8,%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cmp    %eax,%esi
  cvtsi2sd %rdi,%xmm0
  cmovl  %eax,%esi
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D5(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double stat_per_interval(uint32_t value, int32_t dur) {
  if (dur < 1000)
    dur = 1000;
  return ((double)value / dur) * 1000000;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<stat_per_interval>:
  endbr64
  mov    $0x3e8,%eax
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cmp    %eax,%esi
  cvtsi2sd %rdi,%xmm0
  cmovl  %eax,%esi
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  mulsd  D9(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

assistant: ```c
double stat_per_interval(uint32_t value, int32_t dur) {
  if (dur < 1000)
    dur = 1000;
  return ((double)value / dur) * 1000000;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    %ebx,%r12d
  jle    L6
  movslq %r12d,%rax
  movslq %ebx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <STRCMP@plt>
  jmp    L17
L6:
  mov    $0xffffffff,%eax
L17:
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int Suffix(myword, suffix)
char *myword;
char *suffix;
{
  register int i;
  register int j;
  i = strlen(myword);
  j = strlen(suffix);
  if (i > j) {
    return (STRCMP((myword + i - j), suffix));
  } else {
    return (-1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Suffix>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L2
  movslq %ebx,%rbx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  mov    $0x0,%eax
  call   <STRCMP@plt>
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L17
```

assistant: ```c
int Suffix(myword, suffix)
char *myword;
char *suffix;
{
  register int i;
  register int j;
  i = strlen(myword);
  j = strlen(suffix);
  if (i > j) {
    return (STRCMP((myword + i - j), suffix));
  } else {
    return (-1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Suffix>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L6
  cltq
  movslq %ebx,%rbx
  mov    %r12,%rsi
  sub    %rax,%rbx
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <STRCMP@plt>
  nopl   (%rax)
L6:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Suffix(myword, suffix)
char *myword;
char *suffix;
{
  register int i;
  register int j;
  i = strlen(myword);
  j = strlen(suffix);
  if (i > j) {
    return (STRCMP((myword + i - j), suffix));
  } else {
    return (-1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Suffix>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  cmp    %eax,%ebx
  jle    L8
  cltq
  movslq %ebx,%rbx
  mov    %r12,%rsi
  sub    %rax,%rbx
  xor    %eax,%eax
  lea    0x0(%rbp,%rbx,1),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <STRCMP@plt>
  nopl   (%rax)
L8:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int Suffix(myword, suffix)
char *myword;
char *suffix;
{
  register int i;
  register int j;
  i = strlen(myword);
  j = strlen(suffix);
  if (i > j) {
    return (STRCMP((myword + i - j), suffix));
  } else {
    return (-1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<align>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xfff,%eax
  test   %eax,%eax
  je     L1
  andl   $0xfffff000,-0x4(%rbp)
  addl   $0x1000,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t align(uint64_t val) {
  if (val & 0xFFF) {
    val &= ~0xFFF;
    val += 0x1000;
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<align>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  and    $0xfffff000,%edx
  add    $0x1000,%edx
  test   $0xfff,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
uint64_t align(uint64_t val) {
  if (val & 0xFFF) {
    val &= ~0xFFF;
    val += 0x1000;
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<align>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  and    $0xfffff000,%edx
  add    $0x1000,%edx
  test   $0xfff,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
uint64_t align(uint64_t val) {
  if (val & 0xFFF) {
    val &= ~0xFFF;
    val += 0x1000;
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<align>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  and    $0xfffff000,%edx
  add    $0x1000,%edx
  test   $0xfff,%eax
  cmovne %edx,%eax
  ret
```

assistant: ```c
uint64_t align(uint64_t val) {
  if (val & 0xFFF) {
    val &= ~0xFFF;
    val += 0x1000;
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L9:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L9
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %02X 

assistant: ```c
void print_number(size_t len, unsigned char *data) {
  for (size_t i = 0; i < len; i++) {
    printf("%02X ", data[i]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L6
  mov    %rsi,%rbx
  lea    (%rsi,%rdi,1),%rbp
  lea    D3(%rip),%r12
L14:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: %02X 

assistant: ```c
void print_number(size_t len, unsigned char *data) {
  for (size_t i = 0; i < len; i++) {
    printf("%02X ", data[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_number>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    (%rsi,%rdi,1),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L18
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L2:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: %02X 

assistant: ```c
void print_number(size_t len, unsigned char *data) {
  for (size_t i = 0; i < len; i++) {
    printf("%02X ", data[i]);
  }
  printf("\n");
}
```