ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<twoSum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0x8,%edi
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L42
  lea    -0x2(%rbx),%r9d
  add    $0x2,%r9
  mov    $0x1,%r8d
L34:
  lea    -0x1(%r8),%r10d
  cmp    %r8d,%ebx
  jle    L17
  mov    -0x4(%rbp,%r8,4),%esi
  mov    %r8,%rdx
L28:
  mov    %esi,%ecx
  add    0x0(%rbp,%rdx,4),%ecx
  cmp    %r12d,%ecx
  je     L27
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L28
L17:
  add    $0x1,%r8
  cmp    %r9,%r8
  jne    L34
  jmp    L42
L27:
  mov    %r10d,(%rax)
  mov    %edx,0x4(%rax)
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *indices = (int *)malloc(sizeof(int) * 2);
  for (int indice1 = 0; indice1 < numsSize - 1; indice1++) {
    for (int indice2 = indice1 + 1; indice2 < numsSize; indice2++) {
      if (nums[indice1] + nums[indice2] == target) {
        indices[0] = indice1;
        indices[1] = indice2;
        return indices;
      }
    }
  }
  return indices;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L27
  lea    -0x2(%rbx),%r8d
  mov    $0x1,%edi
  add    $0x2,%r8
L0:
  lea    -0x1(%rdi),%r9d
  cmp    %edi,%ebx
  jle    L39
  mov    -0x4(%rbp,%rdi,4),%edx
  mov    %rdi,%rcx
  jmp    L24
  nopl   (%rax)
L51:
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jle    L39
L24:
  mov    0x0(%rbp,%rcx,4),%esi
  add    %edx,%esi
  cmp    %r12d,%esi
  jne    L51
  mov    %r9d,(%rax)
  mov    %ecx,0x4(%rax)
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L39:
  add    $0x1,%rdi
  cmp    %rdi,%r8
  jne    L0
  jmp    L27
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *indices = (int *)malloc(sizeof(int) * 2);
  for (int indice1 = 0; indice1 < numsSize - 1; indice1++) {
    for (int indice2 = indice1 + 1; indice2 < numsSize; indice2++) {
      if (nums[indice1] + nums[indice2] == target) {
        indices[0] = indice1;
        indices[1] = indice2;
        return indices;
      }
    }
  }
  return indices;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x8,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <malloc@plt>
  cmp    $0x1,%ebx
  jle    L22
  lea    -0x2(%rbx),%r10d
  mov    $0x1,%r8d
  add    $0x2,%r10
L57:
  lea    -0x1(%r8),%r9d
  cmp    %r8d,%ebx
  jle    L19
  mov    -0x4(%rbp,%r8,4),%edx
  mov    %r8,%rcx
  jmp    L20
L56:
  add    $0x1,%rcx
  cmp    %ecx,%ebx
  jle    L19
L20:
  mov    0x0(%rbp,%rcx,4),%esi
  add    %edx,%esi
  cmp    %r12d,%esi
  jne    L56
  movd   %r9d,%xmm0
  movd   %ecx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rax)
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  add    $0x1,%r8
  cmp    %r8,%r10
  jne    L57
  jmp    L22
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *indices = (int *)malloc(sizeof(int) * 2);
  for (int indice1 = 0; indice1 < numsSize - 1; indice1++) {
    for (int indice2 = indice1 + 1; indice2 < numsSize; indice2++) {
      if (nums[indice1] + nums[indice2] == target) {
        indices[0] = indice1;
        indices[1] = indice2;
        return indices;
      }
    }
  }
  return indices;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rsc_enc_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  and    -0x30(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <parity_counter@plt>
  xor    -0x2c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  sub    $0x1,%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x1,-0x20(%rbp)
  jmp    L17
L12:
  mov    -0x1c(%rbp),%eax
  lea    (%rax,%rax,1),%ebx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  and    -0x14(%rbp),%eax
  mov    -0x3c(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <parity_counter@plt>
  add    %ebx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%eax
  cmp    -0x40(%rbp),%eax
  jl     L12
  mov    -0x14(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i, out_, a_k;
  out_ = input;
  a_k = input ^ parity_counter(g[0] & state_in, KK);
  state = (a_k << (KK - 1)) ^ state_in;
  for (i = 1; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rsc_enc_bit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%ebp
  mov    %esi,0xc(%rsp)
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    %r8d,%r12d
  mov    %r9d,%r14d
  mov    %edx,%edi
  and    (%rcx),%edi
  mov    %r8d,%esi
  call   <parity_counter@plt>
  mov    %ebp,%edx
  xor    %ebp,%eax
  mov    %eax,%ebp
  lea    -0x1(%r12),%ecx
  shl    %cl,%ebp
  xor    %ebx,%ebp
  cmp    $0x1,%r14d
  jle    L29
  lea    0x4(%r13),%rbx
  lea    -0x2(%r14),%eax
  lea    0x8(%r13,%rax,4),%r13
  mov    %edx,%eax
L4:
  lea    (%rax,%rax,1),%r14d
  mov    %ebp,%edi
  and    (%rbx),%edi
  mov    %r12d,%esi
  call   <parity_counter@plt>
  add    %r14d,%eax
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L4
L6:
  sar    %ebp
  mov    %ebp,(%r15)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    0xc(%rsp),%eax
  jmp    L6
```

assistant: ```c
int rsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i, out_, a_k;
  out_ = input;
  a_k = input ^ parity_counter(g[0] & state_in, KK);
  state = (a_k << (KK - 1)) ^ state_in;
  for (i = 1; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rsc_enc_bit>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %r8d,%esi
  sub    $0x18,%rsp
  mov    (%rcx),%edi
  mov    %r9d,0xc(%rsp)
  and    %edx,%edi
  call   <parity_counter@plt>
  lea    -0x1(%r12),%ecx
  mov    0xc(%rsp),%r9d
  xor    %ebx,%eax
  mov    %eax,%ebp
  shl    %cl,%ebp
  xor    %r15d,%ebp
  cmp    $0x1,%r9d
  jle    L29
  lea    -0x2(%r9),%eax
  lea    0x4(%r13),%r15
  lea    0x8(%r13,%rax,4),%r13
  mov    %ebx,%eax
  nopl   0x0(%rax)
L13:
  mov    (%r15),%edi
  mov    %r12d,%esi
  lea    (%rax,%rax,1),%ebx
  add    $0x4,%r15
  and    %ebp,%edi
  call   <parity_counter@plt>
  add    %ebx,%eax
  cmp    %r13,%r15
  jne    L13
L11:
  sar    %ebp
  mov    %ebp,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L29:
  mov    %ebx,%eax
  jmp    L11
```

assistant: ```c
int rsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i, out_, a_k;
  out_ = input;
  a_k = input ^ parity_counter(g[0] & state_in, KK);
  state = (a_k << (KK - 1)) ^ state_in;
  for (i = 1; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rsc_enc_bit>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %r8d,%esi
  sub    $0x18,%rsp
  mov    (%rcx),%edi
  mov    %r9d,0xc(%rsp)
  and    %edx,%edi
  call   <parity_counter@plt>
  lea    -0x1(%r12),%ecx
  mov    0xc(%rsp),%r9d
  xor    %ebx,%eax
  mov    %eax,%ebp
  shl    %cl,%ebp
  xor    %r15d,%ebp
  cmp    $0x1,%r9d
  jle    L25
  lea    -0x2(%r9),%eax
  lea    0x4(%r13),%r15
  lea    0x8(%r13,%rax,4),%r13
  mov    %ebx,%eax
  nopl   0x0(%rax)
L9:
  mov    (%r15),%edi
  mov    %r12d,%esi
  lea    (%rax,%rax,1),%ebx
  add    $0x4,%r15
  and    %ebp,%edi
  call   <parity_counter@plt>
  add    %ebx,%eax
  cmp    %r13,%r15
  jne    L9
L4:
  sar    %ebp
  mov    %ebp,(%r14)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L25:
  mov    %ebx,%eax
  jmp    L4
```

assistant: ```c
int rsc_enc_bit(int state_out_p[], int input, int state_in, int g[], int KK, int nn) {
  int state, i, out_, a_k;
  out_ = input;
  a_k = input ^ parity_counter(g[0] & state_in, KK);
  state = (a_k << (KK - 1)) ^ state_in;
  for (i = 1; i < nn; i++) {
    out_ = (out_ << 1) + parity_counter(state & g[i], KK);
  }
  state_out_p[0] = state >> 1;
  return (out_);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Decode_Bitstream>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
L11:
  mov    $0x0,%eax
  call   <Headers@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L29
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <video_sequence@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L11
L29:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
signed int Decode_Bitstream(void) {
  signed int ret;
  signed int Bitstream_Framenum = 0;
  do {
    ret = Headers();
    if (ret == 1)
      ret = video_sequence(&Bitstream_Framenum);
    else
      return ret;
  } while ((_Bool)1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Decode_Bitstream>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbx
  jmp    L4
L18:
  mov    %rbx,%rdi
  call   <video_sequence@plt>
L4:
  mov    $0x0,%eax
  call   <Headers@plt>
  cmp    $0x1,%eax
  je     L18
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed int Decode_Bitstream(void) {
  signed int ret;
  signed int Bitstream_Framenum = 0;
  do {
    ret = Headers();
    if (ret == 1)
      ret = video_sequence(&Bitstream_Framenum);
    else
      return ret;
  } while ((_Bool)1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Decode_Bitstream>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x0,0x4(%rsp)
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbx,%rdi
  call   <video_sequence@plt>
L11:
  xor    %eax,%eax
  call   <Headers@plt>
  cmp    $0x1,%eax
  je     L17
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed int Decode_Bitstream(void) {
  signed int ret;
  signed int Bitstream_Framenum = 0;
  do {
    ret = Headers();
    if (ret == 1)
      ret = video_sequence(&Bitstream_Framenum);
    else
      return ret;
  } while ((_Bool)1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Decode_Bitstream>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  movl   $0x0,0x4(%rsp)
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbx,%rdi
  call   <video_sequence@plt>
L6:
  xor    %eax,%eax
  call   <Headers@plt>
  cmp    $0x1,%eax
  je     L27
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed int Decode_Bitstream(void) {
  signed int ret;
  signed int Bitstream_Framenum = 0;
  do {
    ret = Headers();
    if (ret == 1)
      ret = video_sequence(&Bitstream_Framenum);
    else
      return ret;
  } while ((_Bool)1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parityb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L4
  mov    $0x0,%eax
  call   <partab_init@plt>
L4:
  movzbl -0x4(%rbp),%edx
  mov    D6(%rip),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  leave
  ret
```

assistant: ```c
int parityb(unsigned char x) {
  extern uint8_t partab[256];
  extern bool p_init;
  if (!p_init)
    partab_init();
  return partab[x];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parityb>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D0(%rip),%rax
  cmpl   $0x0,(%rax)
  je     L5
L12:
  movzbl %bl,%ebx
  mov    D1(%rip),%rax
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
L5:
  mov    $0x0,%eax
  call   <partab_init@plt>
  jmp    L12
```

assistant: ```c
int parityb(unsigned char x) {
  extern uint8_t partab[256];
  extern bool p_init;
  if (!p_init)
    partab_init();
  return partab[x];
}
```
user: What is the c source code of the assembly code below:

```asm
<parityb>:
  endbr64
  mov    D7(%rip),%rax
  push   %rbx
  mov    %edi,%ebx
  mov    (%rax),%eax
  test   %eax,%eax
  je     L2
  mov    D1(%rip),%rax
  movzbl %bl,%ebx
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  movzbl %bl,%ebx
  call   <partab_init@plt>
  mov    D1(%rip),%rax
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
```

assistant: ```c
int parityb(unsigned char x) {
  extern uint8_t partab[256];
  extern bool p_init;
  if (!p_init)
    partab_init();
  return partab[x];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parityb>:
  endbr64
  mov    D26(%rip),%rax
  push   %rbx
  mov    %edi,%ebx
  mov    (%rax),%eax
  test   %eax,%eax
  je     L5
  mov    D27(%rip),%rax
  movzbl %bl,%ebx
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  movzbl %bl,%ebx
  call   <partab_init@plt>
  mov    D27(%rip),%rax
  mov    (%rax,%rbx,4),%eax
  pop    %rbx
  ret
```

assistant: ```c
int parityb(unsigned char x) {
  extern uint8_t partab[256];
  extern bool p_init;
  if (!p_init)
    partab_init();
  return partab[x];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x78,0x4(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  struct base {
    int basic;
  };
  struct derived {
    struct base common;
    char extra;
  };
  struct base *bp;
  bp = (struct base *)malloc(sizeof(struct base));
  ;
  bp->basic = 10;
  ((struct derived *)bp)->extra = 'x';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0xa,(%rax)
  movb   $0x78,0x4(%rax)
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct base {
    int basic;
  };
  struct derived {
    struct base common;
    char extra;
  };
  struct base *bp;
  bp = (struct base *)malloc(sizeof(struct base));
  ;
  bp->basic = 10;
  ((struct derived *)bp)->extra = 'x';
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <malloc@plt>
  movl   $0xa,(%rax)
  movb   $0x78,0x4(%rax)
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  struct base {
    int basic;
  };
  struct derived {
    struct base common;
    char extra;
  };
  struct base *bp;
  bp = (struct base *)malloc(sizeof(struct base));
  ;
  bp->basic = 10;
  ((struct derived *)bp)->extra = 'x';
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strclr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L34
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <ft_strclr>
  jmp    L33
L34:
  nop
  jmp    L16
L33:
  nop
L16:
  leave
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  if (*s) {
    *s = '\0';
    ft_strclr(s + 1);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  je     L8
  cmpb   $0x0,(%rdi)
  jne    L0
L8:
  ret
L0:
  sub    $0x8,%rsp
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
  call   <ft_strclr>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  if (*s) {
    *s = '\0';
    ft_strclr(s + 1);
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  jne    L22
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L5:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L22:
  cmpb   $0x0,(%rdi)
  jne    L5
L27:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  if (*s) {
    *s = '\0';
    ft_strclr(s + 1);
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strclr>:
  endbr64
  test   %rdi,%rdi
  jne    L8
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L13:
  movb   $0x0,(%rdi)
  add    $0x1,%rdi
L8:
  cmpb   $0x0,(%rdi)
  jne    L13
L18:
  ret
```

assistant: ```c
void ft_strclr(char *s) {
  if (!s)
    return;
  if (*s) {
    *s = '\0';
    ft_strclr(s + 1);
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_putnchar_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L4:
  lea    -0x14(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    D7(%rip),%rdx
  mov    (%rdx),%edx
  cmp    %edx,%eax
  jne    L10
  mov    -0x4(%rbp),%eax
  jmp    L31
L10:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
L31:
  mov    %eax,-0x4(%rbp)
L24:
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  test   %rax,%rax
  jne    L4
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ft_putnchar_fd(char c, size_t n, int fd) {
  int ret;
  ret = EXIT_SUCCESS;
  while (n-- > 0)
    ret = write(fd, &c, 1) == EXIT_SUCCESS ? ret : EXIT_FAILURE;
  return (ret);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_putnchar_fd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%r13d
  test   %rsi,%rsi
  je     L23
  mov    %edx,%ebp
  lea    -0x1(%rsi),%rbx
  lea    0xc(%rsp),%r12
  jmp    L45
L46:
  sub    $0x1,%rbx
  cmp    $0xffffffffffffffff,%rbx
  je     L23
L45:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    D8(%rip),%rdx
  cmp    (%rdx),%eax
  je     L46
  mov    D15(%rip),%rax
  mov    (%rax),%r13d
  jmp    L46
L23:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ft_putnchar_fd(char c, size_t n, int fd) {
  int ret;
  ret = EXIT_SUCCESS;
  while (n-- > 0)
    ret = write(fd, &c, 1) == EXIT_SUCCESS ? ret : EXIT_FAILURE;
  return (ret);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_putnchar_fd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D18(%rip),%r12
  mov    %dil,0xc(%rsp)
  mov    (%r12),%r14d
  test   %rsi,%rsi
  je     L13
  mov    %edx,%ebp
  lea    -0x1(%rsi),%rbx
  lea    0xc(%rsp),%r13
L21:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    (%r12),%eax
  je     L27
  mov    D13(%rip),%rax
  mov    (%rax),%r14d
L27:
  sub    $0x1,%rbx
  jae    L21
L13:
  add    $0x10,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ft_putnchar_fd(char c, size_t n, int fd) {
  int ret;
  ret = EXIT_SUCCESS;
  while (n-- > 0)
    ret = write(fd, &c, 1) == EXIT_SUCCESS ? ret : EXIT_FAILURE;
  return (ret);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_putnchar_fd>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    D5(%rip),%r12
  mov    %dil,0xc(%rsp)
  mov    (%r12),%r14d
  test   %rsi,%rsi
  je     L15
  mov    %edx,%ebp
  lea    -0x1(%rsi),%rbx
  lea    0xc(%rsp),%r13
L25:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    (%r12),%eax
  je     L26
  mov    D12(%rip),%rax
  mov    (%rax),%r14d
L26:
  sub    $0x1,%rbx
  jae    L25
L15:
  add    $0x10,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ft_putnchar_fd(char c, size_t n, int fd) {
  int ret;
  ret = EXIT_SUCCESS;
  while (n-- > 0)
    ret = write(fd, &c, 1) == EXIT_SUCCESS ? ret : EXIT_FAILURE;
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L9:
  mov    -0x18(%rbp),%rdx
  mov    $0x1,%eax
  sub    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: allocation failure in lvector()

assistant: ```c
long *lvector(long nl, long nh) {
  long *v = (long *)malloc((size_t)((nh - nl + 2) * sizeof(long)));
  if (v == NULL)
    error("allocation failure in lvector()");
  return (v - nl + 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lvector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  sub    %rdi,%rsi
  lea    0x10(,%rsi,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L12:
  mov    $0x1,%eax
  sub    %rbp,%rax
  lea    (%rbx,%rax,8),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D3(%rip),%rdi
  call   <error@plt>
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_infered: string

tool: D3: allocation failure in lvector()

assistant: ```c
long *lvector(long nl, long nh) {
  long *v = (long *)malloc((size_t)((nh - nl + 2) * sizeof(long)));
  if (v == NULL)
    error("allocation failure in lvector()");
  return (v - nl + 1);
}
```