ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xc0000000,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L4:
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L4
  movl   $0x0,-0x14(%rbp)
  jmp    L90
L62:
  movl   $0x1,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
L90:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L62
  movl   $0x0,-0x14(%rbp)
  jmp    L102
L112:
  movl   $0x1,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
L102:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L112
  movl   $0x0,-0x14(%rbp)
  jmp    L104
L30:
  movl   $0x1,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
L104:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L30
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L43:
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L43
  movl   $0x0,-0x14(%rbp)
  jmp    L68
L91:
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L68:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L91
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int n0 = -1073741824;
  int n1 = 1;
  int n2 = 1;
  int i = 0;
  int k = 0;
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 2;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    i++;
    k--;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int n0 = -1073741824;
  int n1 = 1;
  int n2 = 1;
  int i = 0;
  int k = 0;
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 2;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    i++;
    k--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int n0 = -1073741824;
  int n1 = 1;
  int n2 = 1;
  int i = 0;
  int k = 0;
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 2;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    i++;
    k--;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int n0 = -1073741824;
  int n1 = 1;
  int n2 = 1;
  int i = 0;
  int k = 0;
  while (i < n0) {
    i++;
    k++;
  }
  i = 0;
  while (i < n1) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 2;
  }
  i = 0;
  while (i < n2) {
    i = 1;
    k = 1;
  }
  i = 0;
  while (i < n1) {
    i++;
    k--;
  }
  i = 0;
  while (i < n0) {
    i++;
    k--;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  struct stat *buf;
  double a, m, c;
  a = (double)0;
  m = (double)0;
  c = (double)0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  struct stat *buf;
  double a, m, c;
  a = (double)0;
  m = (double)0;
  c = (double)0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct stat *buf;
  double a, m, c;
  a = (double)0;
  m = (double)0;
  c = (double)0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  struct stat *buf;
  double a, m, c;
  a = (double)0;
  m = (double)0;
  c = (double)0;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L2:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L21
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L21:
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x3e7,-0xc(%rbp)
  jle    L2
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *start(void *arg) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    void *h = malloc(13);
    if (h)
      free(h);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<start>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  jmp    L32
L3:
  sub    $0x1,%ebx
  je     L27
L32:
  mov    $0xd,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L3
L27:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *start(void *arg) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    void *h = malloc(13);
    if (h)
      free(h);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<start>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L2
  call   <free@plt>
L2:
  sub    $0x1,%ebx
  jne    L12
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *start(void *arg) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    void *h = malloc(13);
    if (h)
      free(h);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<start>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xd,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L2
  call   <free@plt>
L2:
  sub    $0x1,%ebx
  jne    L1
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *start(void *arg) {
  int i = 0;
  for (i = 0; i < 1000; i++) {
    void *h = malloc(13);
    if (h)
      free(h);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<uinttostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x34(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  mov    $0x10,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <selfn_strdup@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: %u

assistant: ```c
char *uinttostr(const unsigned val) {
  char buf[16], *str = NULL;
  memset(buf, 0, sizeof(buf));
  snprintf(buf, sizeof(buf), "%u", val);
  selfn_strdup(&str, buf);
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uinttostr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rbx
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %ebp,%ecx
  lea    D4(%rip),%rdx
  mov    $0x10,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  lea    0x8(%rsp),%rdi
  mov    %rbx,%rsi
  call   <selfn_strdup@plt>
  mov    0x8(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: %u

assistant: ```c
char *uinttostr(const unsigned val) {
  char buf[16], *str = NULL;
  memset(buf, 0, sizeof(buf));
  snprintf(buf, sizeof(buf), "%u", val);
  selfn_strdup(&str, buf);
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uinttostr>:
  endbr64
  push   %r12
  mov    $0x10,%edx
  mov    %edi,%r12d
  xor    %esi,%esi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movq   $0x0,0x8(%rsp)
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%ecx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <selfn_strdup@plt>
  mov    0x8(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %u

assistant: ```c
char *uinttostr(const unsigned val) {
  char buf[16], *str = NULL;
  memset(buf, 0, sizeof(buf));
  snprintf(buf, sizeof(buf), "%u", val);
  selfn_strdup(&str, buf);
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<uinttostr>:
  endbr64
  push   %r12
  mov    $0x10,%edx
  mov    %edi,%r12d
  xor    %esi,%esi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movq   $0x0,0x8(%rsp)
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r12d,%ecx
  mov    $0x10,%esi
  mov    %rbp,%rdi
  lea    D4(%rip),%rdx
  call   <snprintf@plt>
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rsi
  call   <selfn_strdup@plt>
  mov    0x8(%rsp),%rax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: string

tool: D4: %u

assistant: ```c
char *uinttostr(const unsigned val) {
  char buf[16], *str = NULL;
  memset(buf, 0, sizeof(buf));
  snprintf(buf, sizeof(buf), "%u", val);
  selfn_strdup(&str, buf);
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bdecrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  je     L42
  mov    $0xffffffff,%eax
  jmp    L27
L42:
  lea    -0x14(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DES_set_key_checked@plt>
  lea    -0x10(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DES_set_key_checked@plt>
  cmpq   $0x0,-0x50(%rbp)
  jne    L24
  movl   $0x0,-0xc(%rbp)
  jmp    L50
L33:
  mov    D19(%rip),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    %rax,%rdx
  call   <DES_ecb2_encrypt@plt>
  addl   $0x8,-0xc(%rbp)
L50:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  ja     L33
  jmp    L63
L24:
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  mov    -0x50(%rbp),%r9
  lea    -0x10(%rbp),%r8
  lea    -0x14(%rbp),%rcx
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  sub    $0x8,%rsp
  push   %rdi
  mov    %rax,%rdi
  call   <DES_ede2_cbc_encrypt@plt>
  add    $0x10,%rsp
L63:
  mov    $0x0,%eax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int bdecrypt(unsigned char *input, unsigned char *output, unsigned int len, DES_cblock *k1, DES_cblock *k2, DES_cblock *iv) {
  DES_key_schedule s1, s2;
  int i;
  if (len % 8 != 0) {
    return -1;
  }
  DES_set_key_checked(k1, &s1);
  DES_set_key_checked(k2, &s2);
  if (iv == NULL) {
    for (i = 0; i < len; i += 8) {
      DES_ecb2_encrypt(input + i, output + i, &s1, &s2, DES_DECRYPT);
    }
  } else {
    DES_ede2_cbc_encrypt(input, output, len, &s1, &s2, iv, DES_DECRYPT);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bdecrypt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   $0x7,%dl
  jne    L18
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %rcx,%rdi
  mov    %r8,%r14
  mov    %r9,%rbp
  mov    %rsp,%rsi
  call   <DES_set_key_checked@plt>
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  call   <DES_set_key_checked@plt>
  test   %rbp,%rbp
  je     L77
  mov    %rsp,%rcx
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  push   %rax
  mov    %rbp,%r9
  lea    0x14(%rsp),%r8
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <DES_ede2_cbc_encrypt@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  test   %r12d,%r12d
  je     L5
  mov    %r13,%rbp
  sub    $0x1,%r12d
  shr    $0x3,%r12d
  mov    %r12d,%r12d
  lea    0x8(%r13,%r12,8),%r13
  mov    D2(%rip),%r12
L63:
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  mov    (%r12),%r8d
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <DES_ecb2_encrypt@plt>
  add    $0x8,%rbp
  add    $0x8,%rbx
  cmp    %r13,%rbp
  jne    L63
  mov    $0x0,%eax
  jmp    L16
L18:
  mov    $0xffffffff,%eax
  jmp    L16
L5:
  mov    $0x0,%eax
  jmp    L16
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bdecrypt(unsigned char *input, unsigned char *output, unsigned int len, DES_cblock *k1, DES_cblock *k2, DES_cblock *iv) {
  DES_key_schedule s1, s2;
  int i;
  if (len % 8 != 0) {
    return -1;
  }
  DES_set_key_checked(k1, &s1);
  DES_set_key_checked(k2, &s2);
  if (iv == NULL) {
    for (i = 0; i < len; i += 8) {
      DES_ecb2_encrypt(input + i, output + i, &s1, &s2, DES_DECRYPT);
    }
  } else {
    DES_ede2_cbc_encrypt(input, output, len, &s1, &s2, iv, DES_DECRYPT);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bdecrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   $0x7,%dl
  jne    L0
  lea    0x10(%rsp),%r14
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rcx,%rdi
  mov    %r14,%rsi
  mov    %r9,%rbx
  lea    0x14(%rsp),%r15
  mov    %edx,%r13d
  call   <DES_set_key_checked@plt>
  mov    0x8(%rsp),%rdi
  mov    %r15,%rsi
  call   <DES_set_key_checked@plt>
  test   %rbx,%rbx
  je     L64
  mov    D5(%rip),%rax
  mov    %r13d,%edx
  mov    %rbx,%r9
  mov    %r15,%r8
  sub    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%eax
  push   %rax
  call   <DES_ede2_cbc_encrypt@plt>
  pop    %rax
  pop    %rdx
L33:
  xor    %eax,%eax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  test   %r13d,%r13d
  je     L33
  sub    $0x1,%r13d
  mov    %rbp,%rbx
  mov    %r12,%rbp
  mov    D5(%rip),%r12
  shr    $0x3,%r13d
  lea    0x8(%rbx,%r13,8),%r13
  nop
L34:
  mov    (%r12),%r8d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r15,%rcx
  mov    %r14,%rdx
  add    $0x8,%rbx
  add    $0x8,%rbp
  call   <DES_ecb2_encrypt@plt>
  cmp    %r13,%rbx
  jne    L34
  jmp    L33
L0:
  mov    $0xffffffff,%eax
  jmp    L4
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bdecrypt(unsigned char *input, unsigned char *output, unsigned int len, DES_cblock *k1, DES_cblock *k2, DES_cblock *iv) {
  DES_key_schedule s1, s2;
  int i;
  if (len % 8 != 0) {
    return -1;
  }
  DES_set_key_checked(k1, &s1);
  DES_set_key_checked(k2, &s2);
  if (iv == NULL) {
    for (i = 0; i < len; i += 8) {
      DES_ecb2_encrypt(input + i, output + i, &s1, &s2, DES_DECRYPT);
    }
  } else {
    DES_ede2_cbc_encrypt(input, output, len, &s1, &s2, iv, DES_DECRYPT);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bdecrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   $0x7,%dl
  jne    L35
  lea    0x10(%rsp),%r14
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rcx,%rdi
  mov    %r14,%rsi
  mov    %r9,%rbx
  lea    0x14(%rsp),%r15
  mov    %edx,%r13d
  call   <DES_set_key_checked@plt>
  mov    0x8(%rsp),%rdi
  mov    %r15,%rsi
  call   <DES_set_key_checked@plt>
  test   %rbx,%rbx
  je     L16
  mov    D3(%rip),%rax
  mov    %r13d,%edx
  mov    %rbx,%r9
  mov    %r15,%r8
  sub    $0x8,%rsp
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%eax
  push   %rax
  call   <DES_ede2_cbc_encrypt@plt>
  pop    %rax
  pop    %rdx
L32:
  xor    %eax,%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  test   %r13d,%r13d
  je     L32
  sub    $0x1,%r13d
  mov    %rbp,%rbx
  mov    %r12,%rbp
  mov    D3(%rip),%r12
  shr    $0x3,%r13d
  lea    0x8(%rbx,%r13,8),%r13
  nop
L25:
  mov    (%r12),%r8d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r15,%rcx
  mov    %r14,%rdx
  add    $0x8,%rbx
  add    $0x8,%rbp
  call   <DES_ecb2_encrypt@plt>
  cmp    %r13,%rbx
  jne    L25
  jmp    L32
L35:
  mov    $0xffffffff,%eax
  jmp    L1
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bdecrypt(unsigned char *input, unsigned char *output, unsigned int len, DES_cblock *k1, DES_cblock *k2, DES_cblock *iv) {
  DES_key_schedule s1, s2;
  int i;
  if (len % 8 != 0) {
    return -1;
  }
  DES_set_key_checked(k1, &s1);
  DES_set_key_checked(k2, &s2);
  if (iv == NULL) {
    for (i = 0; i < len; i += 8) {
      DES_ecb2_encrypt(input + i, output + i, &s1, &s2, DES_DECRYPT);
    }
  } else {
    DES_ede2_cbc_encrypt(input, output, len, &s1, &s2, iv, DES_DECRYPT);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<regmatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L36
L28:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L42
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L36:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L28
  jmp    L26
L42:
  nop
L26:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L41
L20:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x1c(%rbp)
L41:
  mov    -0x1c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L20
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int regmatch(const regmatch_t *matchdata, const char *str, char **matches, int maxmatch) {
  int start;
  int end;
  int count;
  int i, n;
  for (i = 0; i < maxmatch; i++) {
    if (matchdata[i].rm_so == -1)
      break;
    n = matchdata[i].rm_eo - matchdata[i].rm_so;
    matches[i] = malloc(n + 1);
    strncpy(matches[i], str + matchdata[i].rm_so, n);
    matches[i][n] = 0;
  }
  count = i;
  for (; i < maxmatch; i++)
    matches[i] = NULL;
  return (count);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<regmatch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  test   %ecx,%ecx
  jle    L16
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %ecx,%r15d
  lea    -0x1(%rcx),%eax
  mov    %eax,0xc(%rsp)
  mov    %ecx,%r14d
  mov    $0x0,%ebx
L33:
  mov    %ebx,%edx
  mov    (%r12,%rbx,8),%eax
  cmp    $0xffffffff,%eax
  je     L5
  mov    0x4(%r12,%rbx,8),%ebp
  sub    %eax,%ebp
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%r13,%rbx,8)
  movslq (%r12,%rbx,8),%rsi
  add    (%rsp),%rsi
  mov    %ebp,%edx
  call   <strncpy@plt>
  movslq %ebp,%rbp
  mov    0x0(%r13,%rbx,8),%rax
  movb   $0x0,(%rax,%rbp,1)
  lea    0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L33
  jmp    L58
L5:
  cmp    %ebx,%r15d
  jle    L58
  movslq %ebx,%rsi
  lea    0x0(%r13,%rsi,8),%rax
  mov    0xc(%rsp),%ecx
  sub    %ebx,%ecx
  add    %rsi,%rcx
  lea    0x8(%r13,%rcx,8),%rcx
L59:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L59
L58:
  mov    %edx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    $0x0,%edx
  jmp    L58
```

assistant: ```c
int regmatch(const regmatch_t *matchdata, const char *str, char **matches, int maxmatch) {
  int start;
  int end;
  int count;
  int i, n;
  for (i = 0; i < maxmatch; i++) {
    if (matchdata[i].rm_so == -1)
      break;
    n = matchdata[i].rm_eo - matchdata[i].rm_so;
    matches[i] = malloc(n + 1);
    strncpy(matches[i], str + matchdata[i].rm_so, n);
    matches[i][n] = 0;
  }
  count = i;
  for (; i < maxmatch; i++)
    matches[i] = NULL;
  return (count);
}
```