ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L65:
  cmp    %rdx,%rsp
  je     L50
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L65
L50:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L97
  orq    $0x0,-0x8(%rsp,%rax,1)
L97:
  mov    %rsp,%r12
  test   %r13d,%r13d
  jle    L90
  mov    %r13d,%edx
  mov    $0x0,%eax
L57:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L57
L90:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r14d,%r14d
  jle    L73
  mov    $0x0,%ebx
L2:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <stdlib_strided_sminsorted@plt>
  ucomiss %xmm0,%xmm0
  jp     L76
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jne    L2
L73:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L58:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L76:
  lea    D1(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L58
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = i;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_sminsorted(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<benchmark>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rsp,%rbp
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdx,4),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L6
L83:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L83
L6:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L68
L89:
  mov    %rsp,%r12
  test   %r13d,%r13d
  jle    L2
  xor    %eax,%eax
  nopl   0x0(%rax)
L57:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L57
L2:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x38(%rbp)
  test   %r14d,%r14d
  jle    L20
  xor    %ebx,%ebx
  jmp    L97
  nopl   0x0(%rax)
L74:
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  je     L20
L97:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <stdlib_strided_sminsorted@plt>
  ucomiss %xmm0,%xmm0
  jnp    L74
  lea    D7(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x38(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x38(%rbp)
  call   <printf@plt>
  movsd  -0x38(%rbp),%xmm0
L23:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L107
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x38(%rbp),%xmm0
  jmp    L23
  xchg   %ax,%ax
L68:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L89
L107:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  float x[len];
  float v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = i;
  }
  v = 0.0f;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_sminsorted(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hex2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L3
L23:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L42
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L42
  mov    $0xffffffff,%eax
  jmp    L17
L42:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <cval@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <cval@plt>
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  lea    (%rbx,%rcx,1),%edx
  mov    %dl,(%rax)
  addl   $0x2,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
L29:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
L17:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int hex2bin(char *str, unsigned char *out) {
  int i;
  for (i = 0; str[i] && str[i + 1]; i += 2) {
    if (!isxdigit(str[i]) && !isxdigit(str[i + 1]))
      return -1;
    out[i / 2] = (cval(str[i]) << 4) + cval(str[i + 1]);
  }
  return i / 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2bin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  movzbl (%rdi),%edi
  mov    $0x0,%r12d
  test   %dil,%dil
  jne    L2
L11:
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
L42:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  movsbl 0x0(%rbp),%edi
  call   <cval@plt>
  mov    %eax,%ebx
  movsbl 0x1(%rbp),%edi
  call   <cval@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  shr    $0x1f,%eax
  add    %r12d,%eax
  sar    %eax
  cltq
  shl    $0x4,%ebx
  add    %edx,%ebx
  mov    %bl,0x0(%r13,%rax,1)
  add    $0x2,%r12d
  add    $0x2,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L11
L2:
  cmpb   $0x0,0x1(%rbp)
  je     L11
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L26
  movsbl 0x1(%rbp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L26
  mov    $0xffffffff,%eax
  jmp    L42
```

assistant: ```c
int hex2bin(char *str, unsigned char *out) {
  int i;
  for (i = 0; str[i] && str[i + 1]; i += 2) {
    if (!isxdigit(str[i]) && !isxdigit(str[i + 1]))
      return -1;
    out[i / 2] = (cval(str[i]) << 4) + cval(str[i + 1]);
  }
  return i / 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex2bin>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L38
  mov    %rsi,%r13
  xor    %r12d,%r12d
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L37:
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L51
  movsbl 0x1(%rbp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L41
L51:
  movsbl 0x0(%rbp),%edi
  add    $0x2,%rbp
  call   <cval@plt>
  movsbl -0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <cval@plt>
  shl    $0x4,%ebx
  mov    %eax,%r8d
  mov    %r12d,%eax
  add    $0x2,%r12d
  sar    %eax
  add    %r8d,%ebx
  cltq
  mov    %bl,0x0(%r13,%rax,1)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L27
L18:
  cmpb   $0x0,0x1(%rbp)
  jne    L37
L27:
  mov    %r12d,%eax
  sar    %eax
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L41:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hex2bin(char *str, unsigned char *out) {
  int i;
  for (i = 0; str[i] && str[i + 1]; i += 2) {
    if (!isxdigit(str[i]) && !isxdigit(str[i + 1]))
      return -1;
    out[i / 2] = (cval(str[i]) << 4) + cval(str[i + 1]);
  }
  return i / 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hex2bin>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L3
  mov    %rsi,%r13
  xor    %r12d,%r12d
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L5:
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L50
  movsbl 0x1(%rbp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L31
L50:
  movsbl 0x0(%rbp),%edi
  add    $0x2,%rbp
  call   <cval@plt>
  movsbl -0x1(%rbp),%edi
  mov    %eax,%ebx
  call   <cval@plt>
  shl    $0x4,%ebx
  mov    %eax,%r8d
  mov    %r12d,%eax
  add    $0x2,%r12d
  sar    %eax
  add    %r8d,%ebx
  cltq
  mov    %bl,0x0(%r13,%rax,1)
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L15
L8:
  cmpb   $0x0,0x1(%rbp)
  jne    L5
L15:
  mov    %r12d,%eax
  sar    %eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L31:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int hex2bin(char *str, unsigned char *out) {
  int i;
  for (i = 0; str[i] && str[i + 1]; i += 2) {
    if (!isxdigit(str[i]) && !isxdigit(str[i + 1]))
      return -1;
    out[i / 2] = (cval(str[i]) << 4) + cval(str[i + 1]);
  }
  return i / 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L26
L18:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  jmp    L13
L24:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  while (*dst)
    dst++;
  while (*src) {
    *dst++ = *src++;
  }
  *dst = 0;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcat>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L13
L27:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L27
L13:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L39
L25:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L25
L39:
  movb   $0x0,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  while (*dst)
    dst++;
  while (*src) {
    *dst++ = *src++;
  }
  *dst = 0;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcat>:
  endbr64
  jmp    L32
  cs nopw 0x0(%rax,%rax,1)
L37:
  add    $0x1,%rdi
L32:
  cmpb   $0x0,(%rdi)
  jne    L37
  movzbl (%rsi),%eax
  test   %al,%al
  je     L1
L0:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L0
L1:
  movb   $0x0,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  while (*dst)
    dst++;
  while (*src) {
    *dst++ = *src++;
  }
  *dst = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcat>:
  endbr64
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdi
L17:
  cmpb   $0x0,(%rdi)
  jne    L8
  movzbl (%rsi),%eax
  test   %al,%al
  je     L18
L24:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L24
L18:
  movb   $0x0,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strcat(char *dst, const char *src) {
  while (*dst)
    dst++;
  while (*src) {
    *dst++ = *src++;
  }
  *dst = 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<second>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
```

assistant: ```c
int second(char *x) {
  asm("second_label: .globl second_label");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<second>:
  endbr64
```

assistant: ```c
int second(char *x) {
  asm("second_label: .globl second_label");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<second>:
  endbr64
```

assistant: ```c
int second(char *x) {
  asm("second_label: .globl second_label");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<second>:
  endbr64
```

assistant: ```c
int second(char *x) {
  asm("second_label: .globl second_label");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x4,-0x48(%rbp)
  addq   $0x8,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L9
L46:
  movl   $0x0,-0x4c(%rbp)
  mov    -0x50(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  jmp    L16
L29:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x50(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x4c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4c(%rbp)
L16:
  cmpl   $0x1,-0x4c(%rbp)
  jle    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x50(%rbp)
L9:
  cmpl   $0x4,-0x50(%rbp)
  jle    L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D33
type_guessed: string

tool: D29: 
 %ul %ul

tool: D33: %d 

assistant: ```c
main() {
  int array[][2] = {{1, 2}, {3, 4}, {5, 6}, {7, 8}, {9, 10}};
  int *p;
  int *poi;
  int(*q)[2];
  p = (int *)array;
  q = array;
  printf("\n %ul %ul", p, q);
  p++;
  q++;
  printf("\n %ul %ul", p, q);
  int i = 0, j = 0;
  while (i < 5) {
    j = 0;
    poi = q + i;
    while (j < 2) {
      printf("%d ", *(poi + j));
      printf("%d ", *(p + i * 2 + j));
      j++;
    }
    printf("\n");
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x28(%rsp),%r12
  lea    D1(%rip),%rbp
L1:
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
type_infered: string
name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D19: 
 %ul %ul

tool: D1: %d 

assistant: ```c
main() {
  int array[][2] = {{1, 2}, {3, 4}, {5, 6}, {7, 8}, {9, 10}};
  int *p;
  int *poi;
  int(*q)[2];
  p = (int *)array;
  q = array;
  printf("\n %ul %ul", p, q);
  p++;
  q++;
  printf("\n %ul %ul", p, q);
  int i = 0, j = 0;
  while (i < 5) {
    j = 0;
    poi = q + i;
    while (j < 2) {
      printf("%d ", *(poi + j));
      printf("%d ", *(p + i * 2 + j));
      j++;
    }
    printf("\n");
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rbp
  call   <printf@plt>
L9:
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r12
  jne    L9
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D13
type_guessed: string

tool: D12: 
 %ul %ul

tool: D13: %d 

assistant: ```c
main() {
  int array[][2] = {{1, 2}, {3, 4}, {5, 6}, {7, 8}, {9, 10}};
  int *p;
  int *poi;
  int(*q)[2];
  p = (int *)array;
  q = array;
  printf("\n %ul %ul", p, q);
  p++;
  q++;
  printf("\n %ul %ul", p, q);
  int i = 0, j = 0;
  while (i < 5) {
    j = 0;
    poi = q + i;
    while (j < 2) {
      printf("%d ", *(poi + j));
      printf("%d ", *(p + i * 2 + j));
      j++;
    }
    printf("\n");
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D24(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x30,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D34(%rip),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D19(%rip),%xmm0
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rbp
  call   <printf@plt>
L10:
  mov    0x8(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r12
  jne    L10
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type: string
name: retrieve_data
arguments: data_tag: D1
type: byte[16]
name: retrieve_data
arguments: data_tag: D34
type: byte[8]
name: retrieve_data
arguments: data_tag: D19
type: byte[16]
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D24: 
 %ul %ul

tool: {"D1": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D34": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D19": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D15: %d 

assistant: ```c
main() {
  int array[][2] = {{1, 2}, {3, 4}, {5, 6}, {7, 8}, {9, 10}};
  int *p;
  int *poi;
  int(*q)[2];
  p = (int *)array;
  q = array;
  printf("\n %ul %ul", p, q);
  p++;
  q++;
  printf("\n %ul %ul", p, q);
  int i = 0, j = 0;
  while (i < 5) {
    j = 0;
    poi = q + i;
    while (j < 2) {
      printf("%d ", *(poi + j));
      printf("%d ", *(p + i * 2 + j));
      j++;
    }
    printf("\n");
    i++;
  }
}
```