ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sortColors>:
  endbr64
  test   %esi,%esi
  jle    L41
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  xor    %esi,%esi
  xor    %r9d,%r9d
  lea    0x4(%rdi,%rdx,4),%r8
  xor    %edx,%edx
  jmp    L111
L12:
  movslq %edx,%rcx
  add    $0x1,%edx
  movl   $0x0,(%rdi,%rcx,4)
L27:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L194
L111:
  mov    (%rax),%ecx
  test   %ecx,%ecx
  je     L12
  cmp    $0x1,%ecx
  je     L117
  add    $0x4,%rax
  add    $0x1,%esi
  cmp    %r8,%rax
  jne    L111
L194:
  lea    -0x1(%r9),%r10d
  test   %r9d,%r9d
  je     L109
  cmp    $0x2,%r10d
  jbe    L73
  movslq %edx,%rax
  movdqa D2(%rip),%xmm0
  lea    (%rdi,%rax,4),%rcx
  mov    %r9d,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%r8d
  lea    0x10(%rcx),%rax
  shl    $0x4,%r8
  add    %rax,%r8
  jmp    L96
  xchg   %ax,%ax
L152:
  add    $0x10,%rax
L96:
  movups %xmm0,(%rcx)
  mov    %rax,%rcx
  cmp    %rax,%r8
  jne    L152
  mov    %r9d,%ecx
  mov    %r10d,%r8d
  and    $0xfffffffc,%ecx
  lea    (%rdx,%rcx,1),%eax
  sub    %ecx,%r8d
  cmp    %ecx,%r9d
  je     L68
L63:
  cltq
  movl   $0x1,(%rdi,%rax,4)
  lea    0x0(,%rax,4),%rcx
  test   %r8d,%r8d
  jle    L68
  movl   $0x1,0x4(%rdi,%rcx,1)
  cmp    $0x1,%r8d
  jle    L68
  movl   $0x1,0x8(%rdi,%rcx,1)
L68:
  lea    0x1(%rdx,%r10,1),%edx
L109:
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  je     L41
  cmp    $0x2,%r8d
  jbe    L183
  mov    %esi,%ecx
  movslq %edx,%rax
  movdqa D13(%rip),%xmm0
  shr    $0x2,%ecx
  lea    (%rdi,%rax,4),%rax
  shl    $0x4,%rcx
  add    %rax,%rcx
  nopl   (%rax)
L179:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L179
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  add    %eax,%edx
  sub    %eax,%r8d
  cmp    %esi,%eax
  je     L41
L183:
  movslq %edx,%rdx
  movl   $0x2,(%rdi,%rdx,4)
  lea    0x0(,%rdx,4),%rax
  test   %r8d,%r8d
  jle    L41
  movl   $0x2,0x4(%rdi,%rax,1)
  cmp    $0x1,%r8d
  jle    L41
  movl   $0x2,0x8(%rdi,%rax,1)
L41:
  ret
  nopl   0x0(%rax,%rax,1)
L117:
  add    $0x1,%r9d
  jmp    L27
L73:
  mov    %r10d,%r8d
  mov    %edx,%eax
  jmp    L63
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: byte[16]
name: parse_data
arguments: data_label: D13
type_infered: byte[16]

tool: {"D2": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D13": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int white = 0, blue = 0;
  int j = 0;
  for (int i = 0; i < numsSize; i++) {
    if (nums[i] == 0) {
      nums[j++] = 0;
    } else if (nums[i] == 1) {
      white++;
    } else {
      blue++;
    }
  }
  while (white-- > 0) {
    nums[j++] = 1;
  }
  while (blue-- > 0) {
    nums[j++] = 2;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Mmm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x38(%rbp)
  mov    $0x0,%ebx
  jmp    L5
L11:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%r8
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    (%rdx,%rax,1),%rcx
  movsd  D3(%rip),%xmm0
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rdi
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  mov    %r8,%r9
  movapd %xmm0,%xmm1
  mov    %rcx,%r8
  mov    0x10(%rbp),%ecx
  movq   %rdi,%xmm0
  mov    %eax,%edi
  mov    $0x2,%eax
  call   <Mvm@plt>
  add    $0x1,%ebx
L5:
  cmp    -0x14(%rbp),%ebx
  jl     L11
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: f64

tool: D3: 1

assistant: ```c
void Mmm(m, n, p, alpha, A, Aj0, B, Bj0, C, Cj0) int m, n, p;
double alpha;
double **A, **B, **C;
int Aj0, Bj0, Cj0;
{
  register int i, j, k;
  for (i = 0; i < m; i++)
    Mvm(p, n, alpha, B, Bj0, &(A[i][Aj0]), 1.0, &(C[i][Cj0]));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Mmm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  movsd  %xmm0,0x8(%rsp)
  mov    0x58(%rsp),%rdx
  test   %edi,%edi
  jle    L15
  mov    %rcx,%rbp
  mov    %r9,%r13
  movslq 0x60(%rsp),%r14
  shl    $0x3,%r14
  movslq %r8d,%r8
  lea    0x0(,%r8,8),%r12
  mov    %rdx,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rdx,%rax,8),%r15
L6:
  mov    %r14,%r9
  add    (%rbx),%r9
  mov    D1(%rip),%rax
  movq   %rax,%xmm1
  mov    %r12,%r8
  add    0x0(%rbp),%r8
  mov    0x50(%rsp),%ecx
  mov    %r13,%rdx
  movsd  0x8(%rsp),%xmm0
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  mov    $0x2,%eax
  call   <Mvm@plt>
  add    $0x8,%rbx
  add    $0x8,%rbp
  cmp    %r15,%rbx
  jne    L6
L15:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: f64

tool: D1: 1

assistant: ```c
void Mmm(m, n, p, alpha, A, Aj0, B, Bj0, C, Cj0) int m, n, p;
double alpha;
double **A, **B, **C;
int Aj0, Bj0, Cj0;
{
  register int i, j, k;
  for (i = 0; i < m; i++)
    Mvm(p, n, alpha, B, Bj0, &(A[i][Aj0]), 1.0, &(C[i][Cj0]));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Mmm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r15d
  movsd  %xmm0,(%rsp)
  test   %edi,%edi
  jle    L16
  movslq 0x70(%rsp),%r14
  mov    0x68(%rsp),%rbx
  mov    %edi,%eax
  movslq %r8d,%r8
  sub    $0x1,%eax
  mov    %edx,%r12d
  mov    %rcx,%r11
  lea    0x0(,%r14,8),%rdx
  lea    0x8(%rbx,%rax,8),%rax
  mov    %r12d,%r13d
  mov    %r11,%rbp
  lea    0x0(,%r8,8),%rcx
  mov    %rdx,0x8(%rsp)
  mov    %esi,%r12d
  mov    %r9,%r14
  mov    %rcx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L3:
  mov    D9(%rip),%rax
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r12d,%esi
  movsd  (%rsp),%xmm0
  mov    %r13d,%edi
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    0x8(%rsp),%r9
  mov    0x10(%rsp),%r8
  movq   %rax,%xmm1
  mov    $0x2,%eax
  add    -0x8(%rbx),%r9
  add    -0x8(%rbp),%r8
  call   <Mvm@plt>
  cmp    0x18(%rsp),%rbx
  jne    L3
L16:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: f64

tool: D9: 1

assistant: ```c
void Mmm(m, n, p, alpha, A, Aj0, B, Bj0, C, Cj0) int m, n, p;
double alpha;
double **A, **B, **C;
int Aj0, Bj0, Cj0;
{
  register int i, j, k;
  for (i = 0; i < m; i++)
    Mvm(p, n, alpha, B, Bj0, &(A[i][Aj0]), 1.0, &(C[i][Cj0]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Mmm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    0x60(%rsp),%r15d
  movsd  %xmm0,(%rsp)
  test   %edi,%edi
  jle    L9
  movslq 0x70(%rsp),%r14
  mov    0x68(%rsp),%rbx
  mov    %edi,%eax
  movslq %r8d,%r8
  sub    $0x1,%eax
  mov    %edx,%r12d
  mov    %rcx,%r11
  lea    0x0(,%r14,8),%rdx
  lea    0x8(%rbx,%rax,8),%rax
  mov    %r12d,%r13d
  mov    %r11,%rbp
  lea    0x0(,%r8,8),%rcx
  mov    %rdx,0x8(%rsp)
  mov    %esi,%r12d
  mov    %r9,%r14
  mov    %rcx,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L19:
  mov    D2(%rip),%rax
  mov    %r15d,%ecx
  mov    %r14,%rdx
  mov    %r12d,%esi
  movsd  (%rsp),%xmm0
  mov    %r13d,%edi
  add    $0x8,%rbx
  add    $0x8,%rbp
  mov    0x8(%rsp),%r9
  mov    0x10(%rsp),%r8
  movq   %rax,%xmm1
  mov    $0x2,%eax
  add    -0x8(%rbx),%r9
  add    -0x8(%rbp),%r8
  call   <Mvm@plt>
  cmp    0x18(%rsp),%rbx
  jne    L19
L9:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: f64

tool: D2: 1

assistant: ```c
void Mmm(m, n, p, alpha, A, Aj0, B, Bj0, C, Cj0) int m, n, p;
double alpha;
double **A, **B, **C;
int Aj0, Bj0, Cj0;
{
  register int i, j, k;
  for (i = 0; i < m; i++)
    Mvm(p, n, alpha, B, Bj0, &(A[i][Aj0]), 1.0, &(C[i][Cj0]));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <dhry@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  dhry();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <dhry@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dhry();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dhry@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dhry();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <dhry@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  dhry();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_page_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x50000000,-0x8(%rbp)
  mov    $0xa0000000,%eax
  mov    %rax,-0x18(%rbp)
  movq   $0x7f000000,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0xfff00000,%eax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  shr    $0x14,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  or     $0xc12,%rdx
  mov    %rdx,(%rax)
  movq   $0x50000000,-0x18(%rbp)
  movq   $0x50000000,-0x10(%rbp)
  jmp    L9
L16:
  mov    -0x10(%rbp),%rax
  and    $0xfff00000,%eax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  shr    $0x14,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  or     $0xc1e,%rdx
  mov    %rdx,(%rax)
  addq   $0x100000,-0x18(%rbp)
  addq   $0x100000,-0x10(%rbp)
L9:
  cmpq   $0x53ffffff,-0x18(%rbp)
  jbe    L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void create_page_table() {
  unsigned long vaddr, paddr;
  unsigned long *ttb = (unsigned long *)0x50000000;
  vaddr = 0xA0000000;
  paddr = 0x7f000000;
  *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10));
  vaddr = 0x50000000;
  paddr = 0x50000000;
  while (vaddr < 0x54000000) {
    *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10)) | (1 << 3) | (1 << 2);
    vaddr += 0x100000;
    paddr += 0x100000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_page_table>:
  endbr64
  movq   $0x7f000c12,0x50005000
  mov    $0x50000000,%eax
L5:
  mov    %rax,%rcx
  shr    $0x14,%rcx
  mov    %rax,%rdx
  and    $0xfff00000,%edx
  or     $0xc1e,%rdx
  mov    %rdx,0x50000000(,%rcx,8)
  add    $0x100000,%rax
  cmp    $0x54000000,%rax
  jne    L5
  ret
```

assistant: ```c
void create_page_table() {
  unsigned long vaddr, paddr;
  unsigned long *ttb = (unsigned long *)0x50000000;
  vaddr = 0xA0000000;
  paddr = 0x7f000000;
  *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10));
  vaddr = 0x50000000;
  paddr = 0x50000000;
  while (vaddr < 0x54000000) {
    *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10)) | (1 << 3) | (1 << 2);
    vaddr += 0x100000;
    paddr += 0x100000;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<create_page_table>:
  endbr64
  movq   $0x7f000c12,0x50005000
  mov    $0x50000000,%eax
  nopl   (%rax)
L5:
  mov    %rax,%rdx
  mov    %rax,%rcx
  add    $0x100000,%rax
  shr    $0x14,%rdx
  or     $0xc1e,%rcx
  mov    %rcx,0x50000000(,%rdx,8)
  cmp    $0x54000000,%rax
  jne    L5
  ret
```

assistant: ```c
void create_page_table() {
  unsigned long vaddr, paddr;
  unsigned long *ttb = (unsigned long *)0x50000000;
  vaddr = 0xA0000000;
  paddr = 0x7f000000;
  *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10));
  vaddr = 0x50000000;
  paddr = 0x50000000;
  while (vaddr < 0x54000000) {
    *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10)) | (1 << 3) | (1 << 2);
    vaddr += 0x100000;
    paddr += 0x100000;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<create_page_table>:
  endbr64
  movq   $0x7f000c12,0x50005000
  mov    $0x50000000,%eax
  nopl   (%rax)
L4:
  mov    %rax,%rdx
  mov    %rax,%rcx
  add    $0x100000,%rax
  shr    $0x14,%rdx
  or     $0xc1e,%rcx
  mov    %rcx,0x50000000(,%rdx,8)
  cmp    $0x54000000,%rax
  jne    L4
  ret
```

assistant: ```c
void create_page_table() {
  unsigned long vaddr, paddr;
  unsigned long *ttb = (unsigned long *)0x50000000;
  vaddr = 0xA0000000;
  paddr = 0x7f000000;
  *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10));
  vaddr = 0x50000000;
  paddr = 0x50000000;
  while (vaddr < 0x54000000) {
    *(ttb + ((vaddr) >> 20)) = (paddr & 0xfff00000) | ((2 << 0) | (1 << 4) | (0 << 5) | (3 << 10)) | (1 << 3) | (1 << 2);
    vaddr += 0x100000;
    paddr += 0x100000;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<singleNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  xor    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  int ans = 0;
  for (int i = 0; i < numsSize; i++) {
    ans ^= nums[i];
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<singleNumber>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L10:
  xor    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L10
L22:
  mov    %edx,%eax
  ret
L4:
  mov    $0x0,%edx
  jmp    L22
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  int ans = 0;
  for (int i = 0; i < numsSize; i++) {
    ans ^= nums[i];
  }
  return ans;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<singleNumber>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L17:
  xor    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L17
  ret
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  int ans = 0;
  for (int i = 0; i < numsSize; i++) {
    ans ^= nums[i];
  }
  return ans;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<singleNumber>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L62
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L27:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L27
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L41
L18:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  xor    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L37
  add    $0x2,%ecx
  xor    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L37
  xor    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
L37:
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  ret
L62:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L18
```

assistant: ```c
int singleNumber(int *nums, int numsSize) {
  int ans = 0;
  for (int i = 0; i < numsSize; i++) {
    ans ^= nums[i];
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<selt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L34
L25:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L8
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L52
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L52:
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  je     L24
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L24:
  addl   $0x1,-0x10(%rbp)
L34:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  nop
  pop    %rbp
  ret
```

assistant: ```c
void selt(x, n) int *x;
int n;
{
  int i, j, k, t;
  for (i = 1; i < n; i++) {
    k = i - 1;
    for (j = i; j < n; j++) {
      if (x[j] < x[k])
        k = j;
    }
    if (k != i - 1) {
      t = x[i - 1];
      x[i - 1] = x[k];
      x[k] = t;
    }
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<selt>:
  endbr64
  cmp    $0x1,%esi
  jle    L25
  mov    %esi,%r10d
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  jmp    L10
L33:
  add    $0x1,%r8
  add    $0x1,%r9
  cmp    %r10,%r9
  je     L25
L10:
  mov    %r8d,%edx
  cmp    %r9d,%esi
  jle    L33
  mov    %r9,%rax
L32:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L32
  cmp    %r8d,%edx
  je     L33
  mov    (%rdi,%r8,4),%ecx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r8,4)
  mov    %ecx,(%rax)
  jmp    L33
L25:
  ret
```

assistant: ```c
void selt(x, n) int *x;
int n;
{
  int i, j, k, t;
  for (i = 1; i < n; i++) {
    k = i - 1;
    for (j = i; j < n; j++) {
      if (x[j] < x[k])
        k = j;
    }
    if (k != i - 1) {
      t = x[i - 1];
      x[i - 1] = x[k];
      x[k] = t;
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<selt>:
  endbr64
  cmp    $0x1,%esi
  jle    L35
  lea    -0x1(%rsi),%r10d
  xor    %r8d,%r8d
L38:
  mov    %r8d,%edx
  mov    %r8,%r9
  add    $0x1,%r8
  mov    %r8,%rax
  nopl   (%rax)
L4:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L4
  cmp    %r9d,%edx
  je     L16
  movslq %edx,%rdx
  mov    (%rdi,%r9,4),%ecx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r9,4)
  mov    %ecx,(%rax)
L16:
  cmp    %r10,%r8
  jne    L38
L35:
  ret
```

assistant: ```c
void selt(x, n) int *x;
int n;
{
  int i, j, k, t;
  for (i = 1; i < n; i++) {
    k = i - 1;
    for (j = i; j < n; j++) {
      if (x[j] < x[k])
        k = j;
    }
    if (k != i - 1) {
      t = x[i - 1];
      x[i - 1] = x[k];
      x[k] = t;
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<selt>:
  endbr64
  cmp    $0x1,%esi
  jle    L24
  push   %r12
  xor    %r11d,%r11d
  lea    -0x1(%rsi),%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x4(%rdi),%rdi
  nopl   0x0(%rax,%rax,1)
L44:
  mov    -0x4(%rdi),%ebp
  lea    0x1(%r11),%edx
  mov    %r11d,%r10d
  mov    %rdi,%rax
  mov    %ebp,%r8d
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L8:
  movslq %r10d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rbx,%rcx,4),%r9
  cmp    %esi,%edx
  jge    L56
L37:
  mov    (%rax),%ecx
  mov    %rax,%r9
  cmp    %r8d,%ecx
  jge    L8
  mov    %edx,%r10d
  add    $0x1,%edx
  mov    %ecx,%r8d
  add    $0x4,%rax
  cmp    %esi,%edx
  jl     L37
L56:
  cmp    %r11d,%r10d
  je     L62
  mov    %r8d,-0x4(%rdi)
  mov    %ebp,(%r9)
L62:
  add    $0x1,%r11
  add    $0x4,%rdi
  cmp    %r12,%r11
  jne    L44
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  ret
```

assistant: ```c
void selt(x, n) int *x;
int n;
{
  int i, j, k, t;
  for (i = 1; i < n; i++) {
    k = i - 1;
    for (j = i; j < n; j++) {
      if (x[j] < x[k])
        k = j;
    }
    if (k != i - 1) {
      t = x[i - 1];
      x[i - 1] = x[k];
      x[k] = t;
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L34:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <push@plt>
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L34
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L47:
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L47
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string

tool: D22: %d

tool: D19: %d 

assistant: ```c
int main() {
  int n, i, k;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &k);
    push(k);
  }
  for (i = 0; i < n; i++) {
    printf("%d ", pop());
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L17
  mov    $0x0,%ebx
  lea    D17(%rip),%rbp
L18:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <push@plt>
  add    $0x1,%ebx
  mov    (%rsp),%eax
  cmp    %ebx,%eax
  jg     L18
  test   %eax,%eax
  jle    L17
  mov    $0x0,%ebx
  lea    D0(%rip),%rbp
L23:
  mov    $0x0,%eax
  call   <pop@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L23
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D17: %d

tool: D0: %d 

assistant: ```c
int main() {
  int n, i, k;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &k);
    push(k);
  }
  for (i = 0; i < n; i++) {
    printf("%d ", pop());
  }
  return 0;
}
```