ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<line_message>:
  endbr64
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  call   <do_msg@plt>
  test   %rax,%rax
  jne    L7
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %r14d,%r14d
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %rbp,%rdi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  call   <msg_primitive@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  cmp    $0x1,%ebx
  jle    L9
  xor    %eax,%eax
  call   <record_error@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void line_message(int severity, const char *fname, int line, const char *fmt, ...) {
  if (do_msg(severity)) {
    va_list ap;
    va_start(ap, fmt);
    msg_primitive(fname, line, fmt, ap);
    va_end(ap);
    if (severity >= 2)
      record_error();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <test_start@plt>
  mov    $0x0,%eax
  call   <test_successful@plt>
  mov    $0x0,%eax
  call   <test_failure@plt>
  mov    $0x0,%eax
  call   <test_abort@plt>
  mov    $0x0,%eax
  call   <test_finished@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_start(argc, argv);
  test_successful();
  test_failure();
  test_abort();
  test_finished();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test_start@plt>
  mov    $0x0,%eax
  call   <test_successful@plt>
  mov    $0x0,%eax
  call   <test_failure@plt>
  mov    $0x0,%eax
  call   <test_abort@plt>
  mov    $0x0,%eax
  call   <test_finished@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_start(argc, argv);
  test_successful();
  test_failure();
  test_abort();
  test_finished();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test_start@plt>
  xor    %eax,%eax
  call   <test_successful@plt>
  xor    %eax,%eax
  call   <test_failure@plt>
  xor    %eax,%eax
  call   <test_abort@plt>
  xor    %eax,%eax
  call   <test_finished@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_start(argc, argv);
  test_successful();
  test_failure();
  test_abort();
  test_finished();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <test_start@plt>
  xor    %eax,%eax
  call   <test_successful@plt>
  xor    %eax,%eax
  call   <test_failure@plt>
  xor    %eax,%eax
  call   <test_abort@plt>
  xor    %eax,%eax
  call   <test_finished@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  test_start(argc, argv);
  test_successful();
  test_failure();
  test_abort();
  test_finished();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L34
L10:
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x34(%rbp)
L34:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L10
  mov    -0x38(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L15
L21:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L15:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D38
data_type: string
name: unpack_data
arguments: data_label: D20
data_type: string
name: unpack_data
arguments: data_label: D45
data_type: string
name: unpack_data
arguments: data_label: D28
data_type: string

tool: D38: ENTER THE SIZE 

tool: D20: %d

tool: D45: ENTER THE ARRAY 

tool: D28: %d 

assistant: ```c
int main() {
  int array[10];
  int size;
  printf("ENTER THE SIZE \n");
  scanf("%d", &size);
  printf("ENTER THE ARRAY \n");
  int i;
  for (i = 0; i < size; ++i) {
    scanf("%d", &array[i]);
  }
  merge_sort(array, 0, size - 1);
  for (i = 0; i < size; ++i) {
    printf("%d ", array[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  lea    D42(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L43
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L17:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jg     L17
L43:
  sub    $0x1,%edx
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <merge_sort@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L19
  mov    $0x0,%ebx
  lea    D30(%rip),%rbp
L2:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L2
L19:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D33
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D42
datatype: string
name: unpack_data
arguments: data_label: D30
datatype: string

tool: D33: ENTER THE SIZE 

tool: D7: %d

tool: D42: ENTER THE ARRAY 

tool: D30: %d 

assistant: ```c
int main() {
  int array[10];
  int size;
  printf("ENTER THE SIZE \n");
  scanf("%d", &size);
  printf("ENTER THE ARRAY \n");
  int i;
  for (i = 0; i < size; ++i) {
    scanf("%d", &array[i]);
  }
  merge_sort(array, 0, size - 1);
  for (i = 0; i < size; ++i) {
    printf("%d ", array[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D26(%rip),%rdi
  lea    D34(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  mov    %r12,%rbp
  call   <scanf@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L7
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jg     L13
L7:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <merge_sort@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %ebx,%ebx
  lea    D2(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L29
L27:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D34
datatype: string
name: retrieve_data
arguments: data_label: D39
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D26: ENTER THE SIZE 

tool: D34: %d

tool: D39: ENTER THE ARRAY 

tool: D2: %d 

assistant: ```c
int main() {
  int array[10];
  int size;
  printf("ENTER THE SIZE \n");
  scanf("%d", &size);
  printf("ENTER THE ARRAY \n");
  int i;
  for (i = 0; i < size; ++i) {
    scanf("%d", &array[i]);
  }
  merge_sort(array, 0, size - 1);
  for (i = 0; i < size; ++i) {
    printf("%d ", array[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  lea    D33(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r13,%rdi
  mov    %r12,%rbp
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  test   %edx,%edx
  jle    L27
  nopl   0x0(%rax)
L47:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  cmp    %ebx,%edx
  jg     L47
L27:
  sub    $0x1,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <merge_sort@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %ebx,%ebx
  lea    D7(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L10
L0:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string
name: read_data
arguments: data_label: D33
data_type: string
name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D7
data_type: string

tool: D3: ENTER THE SIZE 

tool: D33: %d

tool: D11: ENTER THE ARRAY 

tool: D7: %d 

assistant: ```c
int main() {
  int array[10];
  int size;
  printf("ENTER THE SIZE \n");
  scanf("%d", &size);
  printf("ENTER THE ARRAY \n");
  int i;
  for (i = 0; i < size; ++i) {
    scanf("%d", &array[i]);
  }
  merge_sort(array, 0, size - 1);
  for (i = 0; i < size; ++i) {
    printf("%d ", array[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fprint_anl_not_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  je     L5
  mov    -0xc(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  and    $0xf8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L3
L5:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L3:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D2: ANL   C, /0x%02X.%X                

tool: D1: ANL   C, /0x%02X                  

assistant: ```c
void fprint_anl_not_bit(FILE *stream, uint8_t bit) {
  if (bit & 0x80)
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            ".%X                ",
            bit & 0xF8, bit & 0x07);
  else
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            "                  ",
            bit);
}
```
user: What is the c source code of the assembly code below?

```asm
<fprint_anl_not_bit>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  test   $0x80,%sil
  je     L4
  mov    %esi,%ecx
  and    $0x7,%ecx
  and    $0xf8,%edx
  lea    D14(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
L12:
  add    $0x8,%rsp
  ret
L4:
  lea    D9(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string

tool: D14: ANL   C, /0x%02X.%X                

tool: D9: ANL   C, /0x%02X                  

assistant: ```c
void fprint_anl_not_bit(FILE *stream, uint8_t bit) {
  if (bit & 0x80)
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            ".%X                ",
            bit & 0xF8, bit & 0x07);
  else
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            "                  ",
            bit);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fprint_anl_not_bit>:
  endbr64
  mov    %esi,%edx
  test   $0x80,%sil
  je     L4
  mov    %esi,%ecx
  and    $0xf8,%edx
  lea    D5(%rip),%rsi
  xor    %eax,%eax
  and    $0x7,%ecx
  jmp    1050 <fprintf@plt>
  nopl   (%rax)
L4:
  lea    D8(%rip),%rsi
  xor    %eax,%eax
  jmp    1050 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D8
type: string

tool: D5: ANL   C, /0x%02X.%X                

tool: D8: ANL   C, /0x%02X                  

assistant: ```c
void fprint_anl_not_bit(FILE *stream, uint8_t bit) {
  if (bit & 0x80)
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            ".%X                ",
            bit & 0xF8, bit & 0x07);
  else
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            "                  ",
            bit);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fprint_anl_not_bit>:
  endbr64
  mov    %esi,%edx
  test   $0x80,%sil
  je     L7
  mov    %esi,%ecx
  and    $0xf8,%edx
  lea    D2(%rip),%rsi
  xor    %eax,%eax
  and    $0x7,%ecx
  jmp    1050 <fprintf@plt>
  nopl   (%rax)
L7:
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  jmp    1050 <fprintf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string

tool: D2: ANL   C, /0x%02X.%X                

tool: D19: ANL   C, /0x%02X                  

assistant: ```c
void fprint_anl_not_bit(FILE *stream, uint8_t bit) {
  if (bit & 0x80)
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            ".%X                ",
            bit & 0xF8, bit & 0x07);
  else
    fprintf(stream,
            "ANL   C, /"
            "0x%02X"
            "                  ",
            bit);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L5:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L9:
  cmpl   $0x0,-0x14(%rbp)
  jg     L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reverse(int n) {
  int r = 0;
  while (n > 0) {
    r = 10 * r + n % 10;
    n = n / 10;
  }
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse>:
  endbr64
  test   %edi,%edi
  jle    L29
  mov    $0x0,%edx
L27:
  lea    (%rdx,%rdx,4),%esi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  mov    %edi,%ecx
  sub    %edx,%ecx
  lea    (%rcx,%rsi,2),%edx
  mov    %edi,%ecx
  mov    %eax,%edi
  cmp    $0x9,%ecx
  jg     L27
L4:
  mov    %edx,%eax
  ret
L29:
  mov    $0x0,%edx
  jmp    L4
```

assistant: ```c
int reverse(int n) {
  int r = 0;
  while (n > 0) {
    r = 10 * r + n % 10;
    n = n / 10;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L14
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L5:
  mov    %edi,%eax
  mov    %edi,%ecx
  lea    (%r8,%r8,4),%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  lea    (%rcx,%rsi,2),%r8d
  cmp    $0x9,%edx
  jg     L5
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int n) {
  int r = 0;
  while (n > 0) {
    r = 10 * r + n % 10;
    n = n / 10;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  jle    L10
  mov    $0xcccccccd,%r9d
  nopl   0x0(%rax)
L16:
  mov    %edi,%eax
  mov    %edi,%ecx
  lea    (%r8,%r8,4),%esi
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  mov    %edi,%edx
  mov    %eax,%edi
  lea    (%rcx,%rsi,2),%r8d
  cmp    $0x9,%edx
  jg     L16
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverse(int n) {
  int r = 0;
  while (n > 0) {
    r = 10 * r + n % 10;
    n = n / 10;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<revcomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L21:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L14
  mov    -0x1c(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L4
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L4:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void revcomp(unsigned char *seq, int n, int *c_nt) {
  unsigned char tmp;
  int i, ni;
  for (i = 0, ni = n - 1; i < n / 2; i++, ni--) {
    tmp = c_nt[seq[i]];
    seq[i] = c_nt[seq[ni]];
    seq[ni] = tmp;
  }
  if ((n % 2) == 1) {
    i = n / 2;
    seq[i] = c_nt[seq[i]];
  }
  seq[n] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<revcomp>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%r10d
  mov    %rdx,%rsi
  lea    -0x1(%r10),%edx
  mov    %r10d,%r9d
  shr    $0x1f,%r9d
  add    %r10d,%r9d
  sar    %r9d
  cmp    $0x1,%r10d
  jle    L12
  movslq %edx,%rdx
  add    %rdi,%rdx
  mov    $0x0,%eax
L4:
  movzbl (%rcx,%rax,1),%edi
  mov    (%rsi,%rdi,4),%edi
  movzbl (%rdx),%r8d
  mov    (%rsi,%r8,4),%r8d
  mov    %r8b,(%rcx,%rax,1)
  mov    %dil,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%r9d
  jg     L4
L12:
  mov    %r10d,%edx
  shr    $0x1f,%edx
  lea    (%r10,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L9
L37:
  movslq %r10d,%r10
  movb   $0x0,(%rcx,%r10,1)
  ret
L9:
  movslq %r9d,%r9
  add    %rcx,%r9
  movzbl (%r9),%eax
  mov    (%rsi,%rax,4),%eax
  mov    %al,(%r9)
  jmp    L37
```

assistant: ```c
void revcomp(unsigned char *seq, int n, int *c_nt) {
  unsigned char tmp;
  int i, ni;
  for (i = 0, ni = n - 1; i < n / 2; i++, ni--) {
    tmp = c_nt[seq[i]];
    seq[i] = c_nt[seq[ni]];
    seq[ni] = tmp;
  }
  if ((n % 2) == 1) {
    i = n / 2;
    seq[i] = c_nt[seq[i]];
  }
  seq[n] = 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<revcomp>:
  endbr64
  movslq %esi,%r10
  mov    %rdi,%rcx
  mov    %rdx,%rsi
  mov    %r10d,%r9d
  lea    -0x1(%r10),%edx
  shr    $0x1f,%r9d
  add    %r10d,%r9d
  sar    %r9d
  cmp    $0x1,%r10d
  jle    L7
  movslq %edx,%rdx
  xor    %eax,%eax
  add    %rdi,%rdx
  nopl   0x0(%rax)
L2:
  movzbl (%rdx),%r8d
  movzbl (%rcx,%rax,1),%edi
  sub    $0x1,%rdx
  mov    (%rsi,%r8,4),%r8d
  mov    (%rsi,%rdi,4),%edi
  mov    %r8b,(%rcx,%rax,1)
  add    $0x1,%rax
  mov    %dil,0x1(%rdx)
  cmp    %eax,%r9d
  jg     L2
L7:
  mov    %r10d,%edx
  shr    $0x1f,%edx
  lea    (%r10,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L17
  movslq %r9d,%r9
  add    %rcx,%r9
  movzbl (%r9),%eax
  mov    (%rsi,%rax,4),%eax
  mov    %al,(%r9)
L17:
  movb   $0x0,(%rcx,%r10,1)
  ret
```

assistant: ```c
void revcomp(unsigned char *seq, int n, int *c_nt) {
  unsigned char tmp;
  int i, ni;
  for (i = 0, ni = n - 1; i < n / 2; i++, ni--) {
    tmp = c_nt[seq[i]];
    seq[i] = c_nt[seq[ni]];
    seq[ni] = tmp;
  }
  if ((n % 2) == 1) {
    i = n / 2;
    seq[i] = c_nt[seq[i]];
  }
  seq[n] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<revcomp>:
  endbr64
  movslq %esi,%r10
  mov    %rdi,%rcx
  mov    %rdx,%rsi
  mov    %r10d,%r9d
  lea    -0x1(%r10),%edx
  shr    $0x1f,%r9d
  add    %r10d,%r9d
  sar    %r9d
  cmp    $0x1,%r10d
  jle    L8
  movslq %edx,%rdx
  xor    %eax,%eax
  add    %rdi,%rdx
  nopl   0x0(%rax)
L15:
  movzbl (%rdx),%r8d
  movzbl (%rcx,%rax,1),%edi
  sub    $0x1,%rdx
  mov    (%rsi,%r8,4),%r8d
  mov    (%rsi,%rdi,4),%edi
  mov    %r8b,(%rcx,%rax,1)
  add    $0x1,%rax
  mov    %dil,0x1(%rdx)
  cmp    %eax,%r9d
  jg     L15
L8:
  mov    %r10d,%edx
  shr    $0x1f,%edx
  lea    (%r10,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L26
  movslq %r9d,%r9
  add    %rcx,%r9
  movzbl (%r9),%eax
  mov    (%rsi,%rax,4),%eax
  mov    %al,(%r9)
L26:
  movb   $0x0,(%rcx,%r10,1)
  ret
```

assistant: ```c
void revcomp(unsigned char *seq, int n, int *c_nt) {
  unsigned char tmp;
  int i, ni;
  for (i = 0, ni = n - 1; i < n / 2; i++, ni--) {
    tmp = c_nt[seq[i]];
    seq[i] = c_nt[seq[ni]];
    seq[ni] = tmp;
  }
  if ((n % 2) == 1) {
    i = n / 2;
    seq[i] = c_nt[seq[i]];
  }
  seq[n] = 0;
}
```