user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x10,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L119:
  movq   $0x0,-0x58(%rbp)
  movl   $0x0,-0x60(%rbp)
  jmp    L81
L141:
  nop
L222:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  lea    0x1(%rax),%edx
  mov    -0x60(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  and    -0x58(%rbp),%rax
  test   %rax,%rax
  jne    L222
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  or     %rax,-0x58(%rbp)
  addl   $0x1,-0x60(%rbp)
L81:
  cmpl   $0xf,-0x60(%rbp)
  jle    L141
  movl   $0x0,-0x5c(%rbp)
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L16:
  mov    $0x9,%edi
  call   <putchar@plt>
  movl   $0x10,-0x60(%rbp)
  jmp    L160
L124:
  subl   $0x1,-0x60(%rbp)
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L160:
  cmpl   $0x0,-0x60(%rbp)
  jg     L124
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x64(%rbp),%rax
  mov    %rax,%rsi
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x64(%rbp),%eax
  cmp    $0x1,%eax
  jle    L147
  mov    -0x64(%rbp),%eax
  cmp    $0x10,%eax
  jg     L147
  movl   $0x0,-0x60(%rbp)
  jmp    L101
L203:
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x64(%rbp),%eax
  sub    -0x60(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  xor    %eax,%edx
  mov    -0x60(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  mov    -0x64(%rbp),%eax
  sub    -0x60(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%ecx
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x64(%rbp),%eax
  sub    -0x60(%rbp),%eax
  sub    $0x1,%eax
  xor    %ecx,%edx
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x64(%rbp),%eax
  sub    -0x60(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  xor    %eax,%edx
  mov    -0x60(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  addl   $0x1,-0x60(%rbp)
L101:
  mov    -0x64(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x60(%rbp)
  jl     L203
  addl   $0x1,-0x5c(%rbp)
  jmp    L186
L147:
  mov    -0x64(%rbp),%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L186:
  movl   $0x0,-0x60(%rbp)
  jmp    L62
L80:
  addl   $0x1,-0x60(%rbp)
L62:
  cmpl   $0xe,-0x60(%rbp)
  jg     L215
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x60(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jg     L80
L215:
  mov    -0x64(%rbp),%eax
  test   %eax,%eax
  je     L42
  cmpl   $0xe,-0x60(%rbp)
  jle    L16
L42:
  mov    -0x64(%rbp),%eax
  test   %eax,%eax
  je     L109
  mov    $0x9,%edi
  call   <putchar@plt>
  movl   $0x10,-0x60(%rbp)
  jmp    L166
L199:
  subl   $0x1,-0x60(%rbp)
  mov    -0x60(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L166:
  cmpl   $0x0,-0x60(%rbp)
  jg     L199
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  lea    D138(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x1d,-0x5c(%rbp)
  jle    L72
  mov    $0x1d,%esi
  lea    D128(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L72:
  cmpl   $0x10,-0x5c(%rbp)
  jg     L109
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L109:
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L137:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x65(%rbp)
  movsbl -0x65(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L137
  cmpb   $0x79,-0x65(%rbp)
  je     L119
  lea    D121(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    D97(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L112
  call   <__stack_chk_fail@plt>
L112:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D63
data_type: string
name: disassemble_data
arguments: label: D60
data_type: string
name: disassemble_data
arguments: label: D62
data_type: string
name: disassemble_data
arguments: label: D51
data_type: string
name: disassemble_data
arguments: label: D79
data_type: string
name: disassemble_data
arguments: label: D43
data_type: string
name: disassemble_data
arguments: label: D138
data_type: string
name: disassemble_data
arguments: label: D128
data_type: string
name: disassemble_data
arguments: label: D25
data_type: string
name: disassemble_data
arguments: label: D55
data_type: string
name: disassemble_data
arguments: label: D121
data_type: string
name: disassemble_data
arguments: label: D26
data_type: string
name: disassemble_data
arguments: label: D97
data_type: string

tool: D63: Reverse
-------

This is the game of Reverse. To win all you have to do is arrange a list
of numbers (1 through %d) in numerical order left to right.
To move, you input how many numbers from the right you want to reverse.
You will no doubt like this game but, if you want to quit just input '0'
as your move.



tool: D60: Here we go...


tool: D62: %2d 

tool: D51: 	? 

tool: D79: %d

tool: D43: You can not reverse %d. Try again.


tool: D138: 

You ordered the list in %d moves.


tool: D128: But it shouldn't have taken more than %d moves.


tool: D25: Wow, you are either extremely good, or extremely lucky.

tool: D55: 
Would you like to try another? (y/n) : 

tool: D121: 







	Cymon's Games

	http://WWW.CYMONSGAMES.COM


   This game and its code is a 2008 Cymon's Games game.
   If you have enjoyed this game or would just like to have a new game
   each week please visit:
   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs
   for everyone, beginners and advanced users alike.



tool: D26: 
	Press ENTER to continue...






tool: D97: Good bye for now then!

assistant: ```c
int main(void) {
  int list[16], c, d, turns;
  long mask;
  char yn;
  srand(time(NULL));
  printf("Reverse\n-------\n\n"
         "This is the game of Reverse. To win all you have to do is arrange a list\n"
         "of numbers (1 through %d) in numerical order left to right.\n"
         "To move, you input how many numbers from the right you want to reverse.\n"
         "You will no doubt like this game but, if you want to quit just input '0'\n"
         "as your move.\n\n",
         16);
  do {
    mask = 0;
    for (c = 0; c < 16; c++) {
      while (1 << (list[c] = rand() % 16 + 1) & mask)
        ;
      mask |= 1 << list[c];
    }
    turns = 0;
    puts("Here we go...\n");
    do {
      putchar('\t');
      for (c = 16; c > 0;)
        printf("%2d ", list[--c]);
      printf("\t? ");
      scanf("%d", &d);
      if (d > 1 && d <= 16) {
        for (c = 0; c < (d / 2); c++) {
          list[c] ^= list[d - c - 1];
          list[d - c - 1] ^= list[c];
          list[c] ^= list[d - c - 1];
        }
        turns++;
      } else
        printf("You can not reverse %d. Try again.\n", d);
      for (c = 0; c < 16 - 1 && list[c] > list[c + 1]; c++)
        ;
    } while (d && c < 16 - 1);
    if (d) {
      putchar('\t');
      for (c = 16; c > 0;)
        printf("%2d ", list[--c]);
      printf("\n\nYou ordered the list in %d moves.\n", turns);
      if (turns > 16 * 2 - 3)
        printf("But it shouldn't have taken more than %d moves.\n", 16 * 2 - 3);
      if (turns <= 16)
        puts("Wow, you are either extremely good, or extremely lucky.");
    }
    printf("\nWould you like to try another? (y/n) : ");
    while (!isalpha(yn = getchar()))
      ;
  } while (yn == 'y');
  puts("\n\n\n\n\n\n\n\n\tCymon's Games\n\n\thttp://WWW.CYMONSGAMES.COM\n\n\n"
       "   This game and its code is a 2008 Cymon's Games game.\n"
       "   If you have enjoyed this game or would just like to have a new game\n"
       "   each week please visit:\n"
       "   http://WWW.CYMONSGAMES.COM for C/C++ programming resources and programs\n"
       "   for everyone, beginners and advanced users alike.\n\n");
  printf("\n\tPress ENTER to continue...\n\n\n\n\n\n");
  getchar();
  getchar();
  puts("Good bye for now then!");
  exit(0);
}
```