ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <simple@plt>
  mov    $0x0,%eax
  call   <loop@plt>
  mov    $0x0,%eax
  call   <undef@plt>
  mov    $0x0,%eax
  call   <cond_incl@plt>
  mov    $0x0,%eax
  call   <const_expr@plt>
  mov    $0x0,%eax
  call   <defined@plt>
  mov    $0x0,%eax
  call   <ifdef@plt>
  mov    $0x0,%eax
  call   <funclike@plt>
  mov    $0x0,%eax
  call   <empty@plt>
  mov    $0x0,%eax
  call   <noarg@plt>
  mov    $0x0,%eax
  call   <null@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  simple();
  loop();
  undef();
  cond_incl();
  const_expr();
  defined();
  ifdef();
  funclike();
  empty();
  noarg();
  null();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <simple@plt>
  xor    %eax,%eax
  call   <loop@plt>
  xor    %eax,%eax
  call   <undef@plt>
  xor    %eax,%eax
  call   <cond_incl@plt>
  xor    %eax,%eax
  call   <const_expr@plt>
  xor    %eax,%eax
  call   <defined@plt>
  xor    %eax,%eax
  call   <ifdef@plt>
  xor    %eax,%eax
  call   <funclike@plt>
  xor    %eax,%eax
  call   <empty@plt>
  xor    %eax,%eax
  call   <noarg@plt>
  xor    %eax,%eax
  call   <null@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  simple();
  loop();
  undef();
  cond_incl();
  const_expr();
  defined();
  ifdef();
  funclike();
  empty();
  noarg();
  null();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <simple@plt>
  xor    %eax,%eax
  call   <loop@plt>
  xor    %eax,%eax
  call   <undef@plt>
  xor    %eax,%eax
  call   <cond_incl@plt>
  xor    %eax,%eax
  call   <const_expr@plt>
  xor    %eax,%eax
  call   <defined@plt>
  xor    %eax,%eax
  call   <ifdef@plt>
  xor    %eax,%eax
  call   <funclike@plt>
  xor    %eax,%eax
  call   <empty@plt>
  xor    %eax,%eax
  call   <noarg@plt>
  xor    %eax,%eax
  call   <null@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  simple();
  loop();
  undef();
  cond_incl();
  const_expr();
  defined();
  ifdef();
  funclike();
  empty();
  noarg();
  null();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CPAtEndOfFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L2
L12:
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int CPAtEndOfFile(FILE *fileRef) {
  if (feof(fileRef))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CPAtEndOfFile>:
  endbr64
  sub    $0x8,%rsp
  call   <feof@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CPAtEndOfFile(FILE *fileRef) {
  if (feof(fileRef))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CPAtEndOfFile>:
  endbr64
  sub    $0x8,%rsp
  call   <feof@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int CPAtEndOfFile(FILE *fileRef) {
  if (feof(fileRef))
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CPAtEndOfFile>:
  endbr64
  sub    $0x8,%rsp
  call   <feof@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int CPAtEndOfFile(FILE *fileRef) {
  if (feof(fileRef))
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x7fff,-0x4(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bar(double *a, double *b) {
  int i;
#pragma omp simd aligned(a, b : 32)
  for (i = 0; i < 32768; i++)
    a[i] += b[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  mov    $0x0,%eax
L1:
  movsd  (%rdi,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x40000,%rax
  jne    L1
  ret
```

assistant: ```c
void bar(double *a, double *b) {
  int i;
#pragma omp simd aligned(a, b : 32)
  for (i = 0; i < 32768; i++)
    a[i] += b[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bar>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  movsd  (%rdi,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x40000,%rax
  jne    L8
  ret
```

assistant: ```c
void bar(double *a, double *b) {
  int i;
#pragma omp simd aligned(a, b : 32)
  for (i = 0; i < 32768; i++)
    a[i] += b[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bar>:
  endbr64
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  mov    $0x0,%eax
  je     L9
  nopw   0x0(%rax,%rax,1)
L20:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rsi,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    $0x40000,%rax
  jne    L20
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movsd  (%rdi,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x40000,%rax
  jne    L9
  ret
```

assistant: ```c
void bar(double *a, double *b) {
  int i;
#pragma omp simd aligned(a, b : 32)
  for (i = 0; i < 32768; i++)
    a[i] += b[i];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<prom_claim_chunk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0xfffff,%eax
  mov    %eax,%eax
  and    $0xfff00000,%eax
  mov    %rax,-0x10(%rbp)
  jmp    L8
L7:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <prom_claim@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  jmp    L3
L27:
  mov    -0x10(%rbp),%rax
  add    $0x100000,%eax
  mov    %eax,%eax
  mov    %rax,-0x10(%rbp)
L8:
  cmpq   $0x10000000,-0x10(%rbp)
  jbe    L7
  mov    $0xffffffffffffffff,%rax
L3:
  leave
  ret
```

assistant: ```c
void *prom_claim_chunk(void *virt, unsigned int size) {
  void *found, *addr;
  for (addr = (void *)((((unsigned)virt) + (0x100000) - 1) & (~((0x100000) - 1))); addr <= (void *)(0x10000000); addr = (void *)((unsigned)addr + 0x100000)) {
    found = prom_claim(addr, size);
    if (found != (void *)-1) {
      return found;
    }
  }
  return (void *)-1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prom_claim_chunk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  lea    0xfffff(%rdi),%ebx
  and    $0xfff00000,%ebx
  cmp    $0x10000000,%rbx
  ja     L17
L36:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <prom_claim@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L29
  lea    0x100000(%rbx),%ebx
  cmp    $0x10000000,%rbx
  jbe    L36
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0xffffffffffffffff,%rax
  jmp    L29
```

assistant: ```c
void *prom_claim_chunk(void *virt, unsigned int size) {
  void *found, *addr;
  for (addr = (void *)((((unsigned)virt) + (0x100000) - 1) & (~((0x100000) - 1))); addr <= (void *)(0x10000000); addr = (void *)((unsigned)addr + 0x100000)) {
    found = prom_claim(addr, size);
    if (found != (void *)-1) {
      return found;
    }
  }
  return (void *)-1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prom_claim_chunk>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0xfffff(%rdi),%ebx
  and    $0xfff00000,%ebx
  sub    $0x8,%rsp
  cmp    $0x10000000,%rbx
  jg     L38
  mov    %esi,%ebp
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x100000,%ebx
  cmp    $0x10000000,%rbx
  jg     L38
L24:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <prom_claim@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L38:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *prom_claim_chunk(void *virt, unsigned int size) {
  void *found, *addr;
  for (addr = (void *)((((unsigned)virt) + (0x100000) - 1) & (~((0x100000) - 1))); addr <= (void *)(0x10000000); addr = (void *)((unsigned)addr + 0x100000)) {
    found = prom_claim(addr, size);
    if (found != (void *)-1) {
      return found;
    }
  }
  return (void *)-1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prom_claim_chunk>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0xfffff(%rdi),%ebx
  and    $0xfff00000,%ebx
  sub    $0x8,%rsp
  cmp    $0x10000000,%rbx
  jg     L17
  mov    %esi,%ebp
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x100000,%ebx
  cmp    $0x10000000,%rbx
  jg     L17
L12:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <prom_claim@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L17:
  add    $0x8,%rsp
  mov    $0xffffffffffffffff,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *prom_claim_chunk(void *virt, unsigned int size) {
  void *found, *addr;
  for (addr = (void *)((((unsigned)virt) + (0x100000) - 1) & (~((0x100000) - 1))); addr <= (void *)(0x10000000); addr = (void *)((unsigned)addr + 0x100000)) {
    found = prom_claim(addr, size);
    if (found != (void *)-1) {
      return found;
    }
  }
  return (void *)-1;
}
```
user: What is the c source code of the assembly code below:

```asm
<UI_dup_verify_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x34(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L16
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <UIerr@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L16:
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%r8
  mov    -0x24(%rbp),%edi
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   0x10(%rbp)
  mov    -0x34(%rbp),%ecx
  push   %rcx
  mov    -0x28(%rbp),%ecx
  push   %rcx
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <general_allocate_string@plt>
  add    $0x20,%rsp
L25:
  leave
  ret
```

assistant: ```c
int UI_dup_verify_string(UI *ui, const char *prompt, int flags, char *result_buf, int minsize, int maxsize, const char *test_buf) {
  char *prompt_copy = NULL;
  if (prompt) {
    prompt_copy = strdup(prompt);
    if (prompt_copy == NULL) {
      UIerr(UI_F_UI_DUP_VERIFY_STRING, ERR_R_MALLOC_FAILURE);
      return -1;
    }
  }
  return general_allocate_string(ui, prompt_copy, 1, UIT_VERIFY, flags, result_buf, minsize, maxsize, test_buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<UI_dup_verify_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%ebp
  mov    %rcx,%r12
  mov    %r8d,%r13d
  mov    %r9d,%r14d
  test   %rsi,%rsi
  je     L6
  mov    %rsi,%rdi
  call   <strdup@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L3
L6:
  sub    $0x8,%rsp
  push   0x38(%rsp)
  push   %r14
  push   %r13
  mov    %r12,%r9
  mov    %ebp,%r8d
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x1,%edx
  mov    %rbx,%rdi
  call   <general_allocate_string@plt>
  add    $0x20,%rsp
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  mov    $0xffffffff,%eax
  jmp    L15
```

assistant: ```c
int UI_dup_verify_string(UI *ui, const char *prompt, int flags, char *result_buf, int minsize, int maxsize, const char *test_buf) {
  char *prompt_copy = NULL;
  if (prompt) {
    prompt_copy = strdup(prompt);
    if (prompt_copy == NULL) {
      UIerr(UI_F_UI_DUP_VERIFY_STRING, ERR_R_MALLOC_FAILURE);
      return -1;
    }
  }
  return general_allocate_string(ui, prompt_copy, 1, UIT_VERIFY, flags, result_buf, minsize, maxsize, test_buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UI_dup_verify_string>:
  endbr64
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  test   %rsi,%rsi
  je     L3
  mov    %rsi,%rdi
  call   <strdup@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L28
L3:
  sub    $0x8,%rsp
  mov    %r12,%r9
  mov    %ebx,%r8d
  mov    $0x1,%edx
  mov    D23(%rip),%rax
  push   0x38(%rsp)
  mov    %rbp,%rdi
  push   %r14
  push   %r13
  mov    (%rax),%ecx
  call   <general_allocate_string@plt>
  add    $0x20,%rsp
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    D26(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  or     $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int UI_dup_verify_string(UI *ui, const char *prompt, int flags, char *result_buf, int minsize, int maxsize, const char *test_buf) {
  char *prompt_copy = NULL;
  if (prompt) {
    prompt_copy = strdup(prompt);
    if (prompt_copy == NULL) {
      UIerr(UI_F_UI_DUP_VERIFY_STRING, ERR_R_MALLOC_FAILURE);
      return -1;
    }
  }
  return general_allocate_string(ui, prompt_copy, 1, UIT_VERIFY, flags, result_buf, minsize, maxsize, test_buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UI_dup_verify_string>:
  endbr64
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  test   %rsi,%rsi
  je     L18
  mov    %rsi,%rdi
  call   <strdup@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L9
L18:
  sub    $0x8,%rsp
  mov    %r12,%r9
  mov    %ebx,%r8d
  mov    $0x1,%edx
  mov    D17(%rip),%rax
  push   0x38(%rsp)
  mov    %rbp,%rdi
  push   %r14
  push   %r13
  mov    (%rax),%ecx
  call   <general_allocate_string@plt>
  add    $0x20,%rsp
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    D25(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  or     $0xffffffff,%eax
  jmp    L7
```

assistant: ```c
int UI_dup_verify_string(UI *ui, const char *prompt, int flags, char *result_buf, int minsize, int maxsize, const char *test_buf) {
  char *prompt_copy = NULL;
  if (prompt) {
    prompt_copy = strdup(prompt);
    if (prompt_copy == NULL) {
      UIerr(UI_F_UI_DUP_VERIFY_STRING, ERR_R_MALLOC_FAILURE);
      return -1;
    }
  }
  return general_allocate_string(ui, prompt_copy, 1, UIT_VERIFY, flags, result_buf, minsize, maxsize, test_buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PIC16F1939_stop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <serial_close@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PIC16F1939_stop(void) {
  serial_close(0);
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PIC16F1939_stop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <serial_close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void PIC16F1939_stop(void) {
  serial_close(0);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<PIC16F1939_stop>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <serial_close@plt>
```

assistant: ```c
void PIC16F1939_stop(void) {
  serial_close(0);
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PIC16F1939_stop>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <serial_close@plt>
```

assistant: ```c
void PIC16F1939_stop(void) {
  serial_close(0);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binstrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%ebx
  jmp    L17
L41:
  mov    %rbx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L64
  mov    %rbx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L64
  mov    %rbx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L64
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <bcmp@plt>
  test   %rax,%rax
  jne    L64
  mov    %rbx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L55
L64:
  add    $0x1,%rbx
L17:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  cmp    %rax,%rbx
  jl     L41
  mov    $0x0,%eax
L55:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned char *binstrstr(unsigned char *base, unsigned char *find, long max) {
  register long i;
  for (i = 0L; i < max - (long)strlen((char *)find); i++) {
    if (base[i] == '-' && base[i + 1] == '-' && base[i] == find[0]) {
      if (bcmp((base + i), find, (int)strlen((char *)find)) == 0) {
        return (base + i);
      }
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binstrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  jmp    L4
L61:
  add    $0x1,%rbp
  add    $0x1,%rbx
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  sub    %rax,%rdx
  cmp    %rbp,%rdx
  jle    L39
  mov    %rbx,%r14
  cmpb   $0x2d,(%rbx)
  jne    L61
  cmpb   $0x2d,0x1(%rbx)
  jne    L61
  cmpb   $0x2d,(%r12)
  jne    L61
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <bcmp@plt>
  test   %rax,%rax
  jne    L61
  jmp    L48
L39:
  mov    $0x0,%r14d
L48:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *binstrstr(unsigned char *base, unsigned char *find, long max) {
  register long i;
  for (i = 0L; i < max - (long)strlen((char *)find); i++) {
    if (base[i] == '-' && base[i + 1] == '-' && base[i] == find[0]) {
      if (bcmp((base + i), find, (int)strlen((char *)find)) == 0) {
        return (base + i);
      }
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binstrstr>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x1,%r13
  add    $0x1,%rbx
L61:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  sub    %rax,%rdx
  cmp    %r13,%rdx
  jle    L34
  cmpb   $0x2d,(%rbx)
  mov    %rbx,%r14
  jne    L26
  cmpb   $0x2d,0x1(%rbx)
  jne    L26
  cmpb   $0x2d,0x0(%rbp)
  jne    L26
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bcmp@plt>
  test   %rax,%rax
  jne    L26
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %r14d,%r14d
L21:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *binstrstr(unsigned char *base, unsigned char *find, long max) {
  register long i;
  for (i = 0L; i < max - (long)strlen((char *)find); i++) {
    if (base[i] == '-' && base[i + 1] == '-' && base[i] == find[0]) {
      if (bcmp((base + i), find, (int)strlen((char *)find)) == 0) {
        return (base + i);
      }
    }
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binstrstr>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L52:
  add    $0x1,%r13
  add    $0x1,%rbx
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdx
  sub    %rax,%rdx
  cmp    %r13,%rdx
  jle    L36
  cmpb   $0x2d,(%rbx)
  mov    %rbx,%r14
  jne    L52
  cmpb   $0x2d,0x1(%rbx)
  jne    L52
  cmpb   $0x2d,0x0(%rbp)
  jne    L52
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bcmp@plt>
  test   %rax,%rax
  jne    L52
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %r14d,%r14d
L29:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char *binstrstr(unsigned char *base, unsigned char *find, long max) {
  register long i;
  for (i = 0L; i < max - (long)strlen((char *)find); i++) {
    if (base[i] == '-' && base[i + 1] == '-' && base[i] == find[0]) {
      if (bcmp((base + i), find, (int)strlen((char *)find)) == 0) {
        return (base + i);
      }
    }
  }
  return NULL;
}
```