ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<marc_findgenre>:
  endbr64
  push   %r13
  lea    D4(%rip),%rsi
  mov    $0x5a,%ecx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x2e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L28
L1:
  add    $0x1,%rbx
  cmp    $0x5a,%rbx
  je     L9
L28:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <strcasecmp@plt>
  test   %eax,%eax
  jne    L1
L38:
  mov    0x2d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x2e8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%r13d
  jmp    L38
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int marc_findgenre(char *query) {
  char *marc[] = {
      "abstract or summary", "art original", "art reproduction", "article", "atlas", "autobiography", "bibliography", "biography", "book", "calendar", "catalog", "chart", "comic or graphic novel", "comic strip", "conference publication", "database", "dictionary", "diorama", "directory", "discography", "drama", "encyclopedia", "essay", "festschrift", "fiction", "filmography", "filmstrip", "finding aid", "flash card", "folktale", "font", "game", "government publication", "graphic", "globe", "handbook", "history", "humor, satire", "hymnal", "index", "instruction", "interview", "issue", "journal", "kit", "language instruction", "law report or digest", "legal article", "legal case and case notes", "legislation", "letter", "loose-leaf", "map", "memoir", "microscope slide", "model", "motion picture", "multivolume monograph", "newspaper", "novel", "numeric data", "offprint", "online system or service", "patent", "periodical", "picture", "poetry", "programmed text", "realia", "rehearsal", "remote sensing image", "reporting", "review", "series", "short story", "slide", "sound", "speech", "standard or specification", "statistics", "survey of literature", "technical drawing", "technical report", "thesis", "toy", "transparency", "treaty", "videorecording", "web site", "yearbook",
  };
  int nmarc = sizeof(marc) / sizeof(char *);
  int i;
  for (i = 0; i < nmarc; ++i) {
    if (!strcasecmp(query, marc[i]))
      return i;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<iw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L49:
  jmp    L49
L16:
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L65:
  addl   $0x1,-0x18(%rbp)
L24:
  cmpl   $0x0,-0x8(%rbp)
  jle    L65
L8:
  cmpl   $0x0,-0x14(%rbp)
  jle    L49
  cmpl   $0x0,-0x8(%rbp)
L26:
  nop
  cmpl   $0x0,-0x1c(%rbp)
  jne    L26
  jmp    L16
```

assistant: ```c
void iw(int gu, int mq, int r2) {
  int yn = 0;
  while (gu < 1) {
    for (;;)
      ;
  bb:;
    int ay = 0;
    while (yn < 1)
      ++mq;
  }
  if (yn != 0)
    goto up;
  if (0) {
  up:
    if (r2 == 0)
      goto bb;
  }
  goto up;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iw>:
  endbr64
  test   %edi,%edi
  jg     L21
L10:
  jmp    L10
L21:
  test   %edx,%edx
  jne    L21
L5:
  jmp    L5
```

assistant: ```c
void iw(int gu, int mq, int r2) {
  int yn = 0;
  while (gu < 1) {
    for (;;)
      ;
  bb:;
    int ay = 0;
    while (yn < 1)
      ++mq;
  }
  if (yn != 0)
    goto up;
  if (0) {
  up:
    if (r2 == 0)
      goto bb;
  }
  goto up;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<iw>:
  endbr64
  test   %edi,%edi
  jg     L37
L20:
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L37:
  test   %edx,%edx
  jne    L37
L17:
  jmp    L17
```

assistant: ```c
void iw(int gu, int mq, int r2) {
  int yn = 0;
  while (gu < 1) {
    for (;;)
      ;
  bb:;
    int ay = 0;
    while (yn < 1)
      ++mq;
  }
  if (yn != 0)
    goto up;
  if (0) {
  up:
    if (r2 == 0)
      goto bb;
  }
  goto up;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<iw>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
void iw(int gu, int mq, int r2) {
  int yn = 0;
  while (gu < 1) {
    for (;;)
      ;
  bb:;
    int ay = 0;
    while (yn < 1)
      ++mq;
  }
  if (yn != 0)
    goto up;
  if (0) {
  up:
    if (r2 == 0)
      goto bb;
  }
  goto up;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<m70_setParams>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  shl    $0xe,%eax
  mov    %eax,%edi
  call   <prg16setBank0@plt>
  mov    -0x8(%rbp),%eax
  shl    $0xd,%eax
  and    $0x1e000,%eax
  mov    %eax,%edi
  call   <chr8setBank0@plt>
  nop
  leave
  ret
```

assistant: ```c
void m70_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  prg16setBank0((val >> 4) << 14);
  chr8setBank0((val & 0xF) << 13);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m70_setParams>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %esi,%edi
  sar    $0x4,%edi
  shl    $0xe,%edi
  call   <prg16setBank0@plt>
  shl    $0xd,%ebx
  mov    %ebx,%edi
  and    $0x1e000,%edi
  call   <chr8setBank0@plt>
  pop    %rbx
  ret
```

assistant: ```c
void m70_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  prg16setBank0((val >> 4) << 14);
  chr8setBank0((val & 0xF) << 13);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<m70_setParams>:
  endbr64
  push   %rbx
  mov    %esi,%edi
  mov    %esi,%ebx
  sar    $0x4,%edi
  shl    $0xd,%ebx
  shl    $0xe,%edi
  call   <prg16setBank0@plt>
  mov    %ebx,%edi
  pop    %rbx
  and    $0x1e000,%edi
  jmp    1060 <chr8setBank0@plt>
```

assistant: ```c
void m70_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  prg16setBank0((val >> 4) << 14);
  chr8setBank0((val & 0xF) << 13);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<m70_setParams>:
  endbr64
  push   %rbx
  mov    %esi,%edi
  mov    %esi,%ebx
  sar    $0x4,%edi
  shl    $0xd,%ebx
  shl    $0xe,%edi
  call   <prg16setBank0@plt>
  mov    %ebx,%edi
  pop    %rbx
  and    $0x1e000,%edi
  jmp    1060 <chr8setBank0@plt>
```

assistant: ```c
void m70_setParams(uint16_t addr, uint8_t val) {
  (void)addr;
  prg16setBank0((val >> 4) << 14);
  chr8setBank0((val & 0xF) << 13);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_calloc_w>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <exit_msg@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: Failed to allocate memory in %s() %s:%d

assistant: ```c
void *_calloc_w(size_t size, const char *caller, const char *file, int line) {
  void *buffer;
  buffer = calloc(1, size);
  if (!buffer)
    exit_msg("Failed to allocate memory in %s() %s:%d", caller, file, line);
  ;
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_calloc_w>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %rdi,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L7
L2:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <exit_msg@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: Failed to allocate memory in %s() %s:%d

assistant: ```c
void *_calloc_w(size_t size, const char *caller, const char *file, int line) {
  void *buffer;
  buffer = calloc(1, size);
  if (!buffer)
    exit_msg("Failed to allocate memory in %s() %s:%d", caller, file, line);
  ;
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_calloc_w>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  mov    %r14d,%ecx
  mov    %r13,%rdx
  lea    D2(%rip),%rdi
  mov    %rbp,%rsi
  call   <exit_msg@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string

tool: D2: Failed to allocate memory in %s() %s:%d

assistant: ```c
void *_calloc_w(size_t size, const char *caller, const char *file, int line) {
  void *buffer;
  buffer = calloc(1, size);
  if (!buffer)
    exit_msg("Failed to allocate memory in %s() %s:%d", caller, file, line);
  ;
  return buffer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_calloc_w>:
  endbr64
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  mov    %r14d,%ecx
  mov    %r13,%rdx
  lea    D9(%rip),%rdi
  mov    %rbp,%rsi
  call   <exit_msg@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: Failed to allocate memory in %s() %s:%d

assistant: ```c
void *_calloc_w(size_t size, const char *caller, const char *file, int line) {
  void *buffer;
  buffer = calloc(1, size);
  if (!buffer)
    exit_msg("Failed to allocate memory in %s() %s:%d", caller, file, line);
  ;
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<plt_validateMonoTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L17
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  jns    L10
  mov    $0xffffffff,%eax
  jmp    L7
L10:
  mov    D15(%rip),%rax
  mov    (%rax),%rax
  imul   $0xf4240,%rax,%rcx
  mov    D15(%rip),%rax
  mov    0x8(%rax),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,%rdx
  mov    D39(%rip),%rax
  mov    %rdx,(%rax)
  mov    D42(%rip),%rax
  movl   $0x1,(%rax)
L17:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int plt_validateMonoTime() {
  extern int plt_monoValid;
  extern struct timespec plt_monoRef;
  extern uint32_t plt_monoTimeUS;
  if (!plt_monoValid) {
    if (clock_gettime(CLOCK_MONOTONIC, &plt_monoRef) < 0)
      return -1;
    plt_monoTimeUS = (uint32_t)((plt_monoRef.tv_sec * 1000000ul) + (plt_monoRef.tv_nsec / 1000));
    plt_monoValid = 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<plt_validateMonoTime>:
  endbr64
  push   %rbx
  mov    D37(%rip),%rax
  mov    (%rax),%ebx
  test   %ebx,%ebx
  je     L36
  mov    $0x0,%ebx
L4:
  mov    %ebx,%eax
  pop    %rbx
  ret
L36:
  mov    D33(%rip),%rsi
  mov    D38(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  js     L16
  mov    D33(%rip),%rax
  imul   $0xf4240,(%rax),%rcx
  mov    0x8(%rax),%edx
  movslq %edx,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  cltq
  add    %rcx,%rax
  mov    D6(%rip),%rdx
  mov    %rax,(%rdx)
  mov    D37(%rip),%rax
  movl   $0x1,(%rax)
  jmp    L4
L16:
  mov    $0xffffffff,%ebx
  jmp    L4
```

assistant: ```c
int plt_validateMonoTime() {
  extern int plt_monoValid;
  extern struct timespec plt_monoRef;
  extern uint32_t plt_monoTimeUS;
  if (!plt_monoValid) {
    if (clock_gettime(CLOCK_MONOTONIC, &plt_monoRef) < 0)
      return -1;
    plt_monoTimeUS = (uint32_t)((plt_monoRef.tv_sec * 1000000ul) + (plt_monoRef.tv_nsec / 1000));
    plt_monoValid = 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<plt_validateMonoTime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D12(%rip),%rbx
  mov    (%rbx),%r12d
  test   %r12d,%r12d
  je     L22
  xor    %r12d,%r12d
L29:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    D4(%rip),%rax
  mov    D32(%rip),%rbp
  mov    (%rax),%edi
  mov    %rbp,%rsi
  call   <clock_gettime@plt>
  test   %rax,%rax
  js     L5
  movslq 0x8(%rbp),%rax
  imul   $0xf4240,0x0(%rbp),%rcx
  movl   $0x1,(%rbx)
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    D9(%rip),%rdx
  cltq
  add    %rcx,%rax
  mov    %rax,(%rdx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0xffffffff,%r12d
  jmp    L29
```

assistant: ```c
int plt_validateMonoTime() {
  extern int plt_monoValid;
  extern struct timespec plt_monoRef;
  extern uint32_t plt_monoTimeUS;
  if (!plt_monoValid) {
    if (clock_gettime(CLOCK_MONOTONIC, &plt_monoRef) < 0)
      return -1;
    plt_monoTimeUS = (uint32_t)((plt_monoRef.tv_sec * 1000000ul) + (plt_monoRef.tv_nsec / 1000));
    plt_monoValid = 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<plt_validateMonoTime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    D2(%rip),%rbx
  mov    (%rbx),%r12d
  test   %r12d,%r12d
  je     L14
  xor    %r12d,%r12d
L0:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    D18(%rip),%rax
  mov    D29(%rip),%rbp
  mov    (%rax),%edi
  mov    %rbp,%rsi
  call   <clock_gettime@plt>
  test   %rax,%rax
  js     L23
  movslq 0x8(%rbp),%rax
  imul   $0xf4240,0x0(%rbp),%rcx
  movl   $0x1,(%rbx)
  mov    %rax,%rdx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    D22(%rip),%rdx
  cltq
  add    %rcx,%rax
  mov    %rax,(%rdx)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0xffffffff,%r12d
  jmp    L0
```

assistant: ```c
int plt_validateMonoTime() {
  extern int plt_monoValid;
  extern struct timespec plt_monoRef;
  extern uint32_t plt_monoTimeUS;
  if (!plt_monoValid) {
    if (clock_gettime(CLOCK_MONOTONIC, &plt_monoRef) < 0)
      return -1;
    plt_monoTimeUS = (uint32_t)((plt_monoRef.tv_sec * 1000000ul) + (plt_monoRef.tv_nsec / 1000));
    plt_monoValid = 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mem_alloc_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mem_alloc_str(const char *orig) {
  int len = strlen(orig);
  char *ptr = malloc(len + 1);
  strcpy(ptr, orig);
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mem_alloc_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mem_alloc_str(const char *orig) {
  int len = strlen(orig);
  char *ptr = malloc(len + 1);
  strcpy(ptr, orig);
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_alloc_str>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mem_alloc_str(const char *orig) {
  int len = strlen(orig);
  char *ptr = malloc(len + 1);
  strcpy(ptr, orig);
  return ptr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mem_alloc_str>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mem_alloc_str(const char *orig) {
  int len = strlen(orig);
  char *ptr = malloc(len + 1);
  strcpy(ptr, orig);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<emit_shrsr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_shrimm@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_shrimm@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_adc@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_shrsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_shrimm(t, 1, t);
  emit_adc(sr, sr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_shrsr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %esi,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <emit_shrimm@plt>
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %ebp,%edi
  call   <emit_shrimm@plt>
  mov    %ebx,%esi
  mov    %ebx,%edi
  call   <emit_adc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void emit_shrsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_shrimm(t, 1, t);
  emit_adc(sr, sr);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<emit_shrsr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <emit_shrimm@plt>
  mov    %r12d,%edi
  mov    %r12d,%edx
  mov    $0x1,%esi
  call   <emit_shrimm@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <emit_adc@plt>
```

assistant: ```c
void emit_shrsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_shrimm(t, 1, t);
  emit_adc(sr, sr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<emit_shrsr>:
  endbr64
  push   %r12
  mov    %esi,%edx
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <emit_shrimm@plt>
  mov    %r12d,%edi
  mov    %r12d,%edx
  mov    $0x1,%esi
  call   <emit_shrimm@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <emit_adc@plt>
```

assistant: ```c
void emit_shrsr(int t, int sr) {
  emit_shrimm(sr, 1, sr);
  emit_shrimm(t, 1, t);
  emit_adc(sr, sr);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L40
L43:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L45
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L26
L45:
  movl   $0x0,-0x14(%rbp)
L26:
  addq   $0x1,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L13
  cmpl   $0x0,-0x14(%rbp)
  je     L13
  subq   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *basename(char const *name) {
  char const *base = name += 0;
  int all_slashes = 1;
  char const *p;
  for (p = name; *p; p++) {
    if (((*p) == '/')) {
      base = p + 1;
    } else {
      all_slashes = 0;
    }
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes) {
    --base;
  }
  return (char *)base;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<basename>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L24
  lea    0x1(%rdi),%rcx
  mov    %r8d,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
L2:
  cmp    $0x2f,%dl
  cmove  %rcx,%rax
  cmovne %edi,%esi
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L2
  cmpb   $0x0,(%rax)
  je     L25
L24:
  ret
L25:
  test   %esi,%esi
  je     L24
  cmp    $0x2f,%r8b
  sete   %dl
  cmp    $0x1,%dl
  adc    $0xffffffffffffffff,%rax
  jmp    L24
```

assistant: ```c
char *basename(char const *name) {
  char const *base = name += 0;
  int all_slashes = 1;
  char const *p;
  for (p = name; *p; p++) {
    if (((*p) == '/')) {
      base = p + 1;
    } else {
      all_slashes = 0;
    }
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes) {
    --base;
  }
  return (char *)base;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<basename>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%r8
  test   %sil,%sil
  je     L8
  mov    %esi,%eax
  mov    $0x1,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  movzbl (%rdi),%eax
  cmove  %rdi,%r8
  cmovne %ecx,%edx
  test   %al,%al
  jne    L21
  cmpb   $0x0,(%r8)
  je     L33
L8:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L33:
  cmp    $0x2f,%sil
  jne    L8
  and    $0x1,%edx
  cmp    $0x1,%dl
  adc    $0xffffffffffffffff,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *basename(char const *name) {
  char const *base = name += 0;
  int all_slashes = 1;
  char const *p;
  for (p = name; *p; p++) {
    if (((*p) == '/')) {
      base = p + 1;
    } else {
      all_slashes = 0;
    }
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes) {
    --base;
  }
  return (char *)base;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basename>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%r8
  test   %sil,%sil
  je     L13
  mov    %esi,%eax
  mov    $0x1,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  movzbl (%rdi),%eax
  cmove  %rdi,%r8
  cmovne %ecx,%edx
  test   %al,%al
  jne    L10
  cmpb   $0x0,(%r8)
  je     L16
L13:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L16:
  cmp    $0x2f,%sil
  jne    L13
  and    $0x1,%edx
  cmp    $0x1,%dl
  adc    $0xffffffffffffffff,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *basename(char const *name) {
  char const *base = name += 0;
  int all_slashes = 1;
  char const *p;
  for (p = name; *p; p++) {
    if (((*p) == '/')) {
      base = p + 1;
    } else {
      all_slashes = 0;
    }
  }
  if (*base == '\0' && ((*name) == '/') && all_slashes) {
    --base;
  }
  return (char *)base;
}
```