ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<extract7bit_dates>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movl   $0xffffffff,(%rsi)
  movl   $0xffffffff,(%rdx)
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L156
  cs nopw 0x0(%rax,%rax,1)
L93:
  mov    %r15,%rbp
  jmp    L136
  nopl   (%rax)
L73:
  movzbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L118
L136:
  call   <isdigit@plt>
  test   %rax,%rax
  je     L73
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L156
  mov    %rbp,%r15
  xor    %r14d,%r14d
  jmp    L97
  nopl   0x0(%rax)
L51:
  movzbl 0x1(%r15),%edi
  add    $0x1,%r15
  add    $0x1,%r14d
  test   %dil,%dil
  je     L130
L97:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L51
L130:
  cmp    $0x4,%r14d
  jne    L79
  test   %r12d,%r12d
  jne    L79
  mov    %rbp,%rdi
  call   <atoi@plt>
L188:
  mov    (%rbx),%edx
  cmp    %eax,%edx
  jg     L38
  test   %edx,%edx
  jns    L32
L38:
  mov    %eax,(%rbx)
L32:
  xor    %edx,%edx
  test   %eax,%eax
  cmovns %eax,%edx
  cmp    %edx,0x0(%r13)
  jge    L124
  mov    %eax,0x0(%r13)
L124:
  movzbl (%r15),%edi
  test   %dil,%dil
  jne    L93
L156:
  mov    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  lea    -0x4(%r14),%eax
  cmp    $0x4,%eax
  ja     L124
  test   %r12d,%r12d
  je     L124
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    $0x4,%r14d
  jne    L188
  imul   $0x2710,%eax,%eax
  jmp    L188
  nopl   0x0(%rax)
L118:
  mov    %rbp,%r15
  jmp    L124
```

assistant: ```c
int extract7bit_dates(const char *buf, int *first, int *last, int longdate) {
  *first = -1;
  *last = -1;
  while (*buf) {
    const char *e;
    int len;
    while (*buf && !isdigit(*(unsigned char *)buf))
      buf++;
    len = 0;
    for (e = buf; *e && isdigit(*(unsigned char *)e); e++)
      len++;
    if ((len == 4 && !longdate) || (longdate && len >= 4 && len <= 8)) {
      int value = atoi(buf);
      if (longdate && len == 4)
        value *= 10000;
      if (*first < 0 || value < *first)
        *first = value;
      if (*last < 0 || value > *last)
        *last = value;
    }
    buf = e;
  }
  return *first;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_parse_enum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L26
L0:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L39
  mov    -0x8(%rbp),%rax
  jmp    L18
L39:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L0
  mov    $0xffffffff,%eax
L18:
  leave
  ret
```

assistant: ```c
int _parse_enum(char const **strings, char const *string) {
  size_t i;
  for (i = 0; strings[i] != NULL; i++)
    if (strcasecmp(strings[i], string) == 0)
      return i;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_parse_enum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L0
  mov    %rsi,%r12
  mov    $0x0,%ebx
L3:
  mov    %r12,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  jne    L3
  mov    $0xffffffff,%eax
  jmp    L34
L17:
  mov    %ebx,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    $0xffffffff,%eax
  jmp    L34
```

assistant: ```c
int _parse_enum(char const **strings, char const *string) {
  size_t i;
  for (i = 0; strings[i] != NULL; i++)
    if (strcasecmp(strings[i], string) == 0)
      return i;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_parse_enum>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L33
  mov    %rsi,%r12
  xor    %ebx,%ebx
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L33
L14:
  mov    %r12,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L27
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _parse_enum(char const **strings, char const *string) {
  size_t i;
  for (i = 0; strings[i] != NULL; i++)
    if (strcasecmp(strings[i], string) == 0)
      return i;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_parse_enum>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L22
  mov    %rsi,%r12
  xor    %ebx,%ebx
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdi
  test   %rdi,%rdi
  je     L22
L2:
  mov    %r12,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L5
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int _parse_enum(char const **strings, char const *string) {
  size_t i;
  for (i = 0; strings[i] != NULL; i++)
    if (strcasecmp(strings[i], string) == 0)
      return i;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D15: foo%n


tool: D6: %d


assistant: ```c
int main() {
  int written = 0;
  printf("foo%n\n", &written);
  assert(written != 0);
  printf("%d\n", written);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string

tool: D13: foo%n


tool: D8: %d


assistant: ```c
int main() {
  int written = 0;
  printf("foo%n\n", &written);
  assert(written != 0);
  printf("%d\n", written);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  setne  %dil
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string
name: disassemble_data
arguments: label: D6
data_type: string

tool: D3: foo%n


tool: D6: %d


assistant: ```c
int main() {
  int written = 0;
  printf("foo%n\n", &written);
  assert(written != 0);
  printf("%d\n", written);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  xor    %edi,%edi
  test   %eax,%eax
  setne  %dil
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D13: foo%n


tool: D3: %d


assistant: ```c
int main() {
  int written = 0;
  printf("foo%n\n", &written);
  assert(written != 0);
  printf("%d\n", written);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<C2Flongv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L4:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jl     L4
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void C2Flongv(long size, int *A, long *B) {
  long i;
  for (i = 0; i < size; i++)
    A[i] = B[i];
  free(B);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<C2Flongv>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %rdx,%rdi
  test   %r8,%r8
  jle    L3
  mov    $0x0,%eax
L17:
  mov    (%rdi,%rax,8),%rcx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L17
L3:
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void C2Flongv(long size, int *A, long *B) {
  long i;
  for (i = 0; i < size; i++)
    A[i] = B[i];
  free(B);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<C2Flongv>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  test   %r8,%r8
  jle    L16
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  mov    (%rdi,%rax,8),%rcx
  mov    %ecx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L3
L16:
  jmp    1050 <free@plt>
```

assistant: ```c
void C2Flongv(long size, int *A, long *B) {
  long i;
  for (i = 0; i < size; i++)
    A[i] = B[i];
  free(B);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<C2Flongv>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  mov    %rdx,%rdi
  test   %r8,%r8
  jle    L22
  lea    -0x1(%r8),%rax
  cmp    $0x2,%rax
  jbe    L64
  mov    %r8,%rdx
  xor    %eax,%eax
  shr    $0x2,%rdx
  shl    $0x4,%rdx
  nopl   (%rax)
L26:
  movdqu (%rdi,%rax,2),%xmm0
  movdqu 0x10(%rdi,%rax,2),%xmm1
  shufps $0x88,%xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L26
  mov    %r8,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%r8b
  je     L22
L55:
  mov    (%rdi,%rax,8),%r9
  lea    0x0(,%rax,8),%rsi
  lea    0x0(,%rax,4),%rdx
  mov    %r9d,(%rcx,%rax,4)
  lea    0x1(%rax),%r9
  cmp    %r9,%r8
  jle    L22
  mov    0x8(%rdi,%rsi,1),%r9
  add    $0x2,%rax
  mov    %r9d,0x4(%rcx,%rdx,1)
  cmp    %rax,%r8
  jle    L22
  mov    0x10(%rdi,%rsi,1),%rax
  mov    %eax,0x8(%rcx,%rdx,1)
L22:
  jmp    1050 <free@plt>
L64:
  xor    %eax,%eax
  jmp    L55
```

assistant: ```c
void C2Flongv(long size, int *A, long *B) {
  long i;
  for (i = 0; i < size; i++)
    A[i] = B[i];
  free(B);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L60:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  je     L38
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  jne    L35
L38:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x20(%rbp)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L60
  jmp    L10
L35:
  nop
L10:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_strings(const char *l, char *r) {
  char *str = (char *)l;
  int i = 0;
  while (*str && *r) {
    if ((*str != *r) && (*str != '?') && (*r != '?'))
      break;
    str++;
    r++;
    i++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compare_strings>:
  endbr64
  movzbl (%rdi),%ecx
  mov    $0x0,%eax
  mov    $0x0,%r8d
  test   %cl,%cl
  jne    L7
  jmp    L35
L25:
  lea    0x1(%r9),%r8d
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L35
L7:
  mov    %eax,%r9d
  mov    %eax,%r8d
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L35
  cmp    %cl,%dl
  setne  %r10b
  cmp    $0x3f,%dl
  setne  %dl
  test   %dl,%r10b
  je     L25
  cmp    $0x3f,%cl
  je     L25
L35:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int compare_strings(const char *l, char *r) {
  char *str = (char *)l;
  int i = 0;
  while (*str && *r) {
    if ((*str != *r) && (*str != '?') && (*r != '?'))
      break;
    str++;
    r++;
    i++;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compare_strings>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %eax,%eax
  xor    %r8d,%r8d
  test   %cl,%cl
  jne    L29
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L19:
  cmp    %cl,%dl
  setne  %r10b
  cmp    $0x3f,%dl
  setne  %dl
  test   %dl,%r10b
  je     L54
  cmp    $0x3f,%cl
  jne    L39
L54:
  add    $0x1,%rax
  lea    0x1(%r9),%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L39
L29:
  movzbl (%rsi,%rax,1),%edx
  mov    %eax,%r9d
  mov    %eax,%r8d
  test   %dl,%dl
  jne    L19
L39:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int compare_strings(const char *l, char *r) {
  char *str = (char *)l;
  int i = 0;
  while (*str && *r) {
    if ((*str != *r) && (*str != '?') && (*r != '?'))
      break;
    str++;
    r++;
    i++;
  }
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<compare_strings>:
  endbr64
  movzbl (%rdi),%ecx
  xor    %eax,%eax
  xor    %r8d,%r8d
  test   %cl,%cl
  jne    L40
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L38:
  cmp    %cl,%dl
  setne  %r10b
  cmp    $0x3f,%dl
  setne  %dl
  test   %dl,%r10b
  je     L57
  cmp    $0x3f,%cl
  jne    L47
L57:
  add    $0x1,%rax
  lea    0x1(%r9),%r8d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L47
L40:
  movzbl (%rsi,%rax,1),%edx
  mov    %eax,%r9d
  mov    %eax,%r8d
  test   %dl,%dl
  jne    L38
L47:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int compare_strings(const char *l, char *r) {
  char *str = (char *)l;
  int i = 0;
  while (*str && *r) {
    if ((*str != *r) && (*str != '?') && (*r != '?'))
      break;
    str++;
    r++;
    i++;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str2int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L13:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L13
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int str2int(char a[], int pos, int len) {
  int i;
  int ret = 0;
  int rate = 1;
  for (i = 0; i < len; ++i, rate *= 10)
    ret += rate * (a[i + pos] - '0');
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<str2int>:
  endbr64
  test   %edx,%edx
  jle    L22
  movslq %esi,%rsi
  lea    (%rdi,%rsi,1),%rcx
  lea    0x1(%rdi,%rsi,1),%rdi
  lea    -0x1(%rdx),%eax
  add    %rax,%rdi
  mov    $0x1,%eax
  mov    $0x0,%esi
L26:
  movsbl (%rcx),%edx
  sub    $0x30,%edx
  imul   %eax,%edx
  add    %edx,%esi
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L26
L2:
  mov    %esi,%eax
  ret
L22:
  mov    $0x0,%esi
  jmp    L2
```

assistant: ```c
int str2int(char a[], int pos, int len) {
  int i;
  int ret = 0;
  int rate = 1;
  for (i = 0; i < len; ++i, rate *= 10)
    ret += rate * (a[i + pos] - '0');
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str2int>:
  endbr64
  test   %edx,%edx
  jle    L19
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,1),%rcx
  lea    0x1(%rdi,%rsi,1),%rsi
  add    %rax,%rsi
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl (%rcx),%edx
  add    $0x1,%rcx
  sub    $0x30,%edx
  imul   %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %edx,%r8d
  cmp    %rsi,%rcx
  jne    L6
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str2int(char a[], int pos, int len) {
  int i;
  int ret = 0;
  int rate = 1;
  for (i = 0; i < len; ++i, rate *= 10)
    ret += rate * (a[i + pos] - '0');
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str2int>:
  endbr64
  test   %edx,%edx
  jle    L7
  movslq %esi,%rsi
  lea    -0x1(%rdx),%eax
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,1),%rcx
  lea    0x1(%rdi,%rsi,1),%rsi
  add    %rax,%rsi
  mov    $0x1,%eax
  nopw   0x0(%rax,%rax,1)
L10:
  movsbl (%rcx),%edx
  add    $0x1,%rcx
  sub    $0x30,%edx
  imul   %eax,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %edx,%r8d
  cmp    %rcx,%rsi
  jne    L10
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int str2int(char a[], int pos, int len) {
  int i;
  int ret = 0;
  int rate = 1;
  for (i = 0; i < len; ++i, rate *= 10)
    ret += rate * (a[i + pos] - '0');
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movss  D30(%rip),%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  D35(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <f1@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L7
L17:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  movd   %eax,%xmm0
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L7:
  cmpl   $0x9,-0x34(%rbp)
  jle    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D30
type_infered: f32
name: extract_symbolic_data
arguments: label: D9
type_infered: f32
name: extract_symbolic_data
arguments: label: D35
type_infered: f32
name: extract_symbolic_data
arguments: label: D24
type_infered: string

tool: D30: 1734.4371

tool: D9: 172.432

tool: D35: 172.213

tool: D24: %.3f 

assistant: ```c
int main() {
  float niz[10] = {1734.4371, 172.432, 172.213};
  f1(niz, 10);
  int i;
  for (i = 0; i < 10; i++)
    printf("%.3f ", niz[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x44d8cdfd,(%rsp)
  movl   $0x432c6e98,0x4(%rsp)
  movl   $0x432c3687,0x8(%rsp)
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <f1@plt>
  lea    0x28(%rsp),%r12
  lea    D8(%rip),%rbp
L17:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: %.3f 

assistant: ```c
int main() {
  float niz[10] = {1734.4371, 172.432, 172.213};
  f1(niz, 10);
  int i;
  for (i = 0; i < 10; i++)
    printf("%.3f ", niz[i]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0xa,%esi
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movups %xmm0,0x8(%rsp)
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdi
  movl   $0x44d8cdfd,(%rsp)
  movl   $0x432c6e98,0x4(%rsp)
  movl   $0x432c3687,0x8(%rsp)
  movups %xmm0,0x18(%rsp)
  call   <f1@plt>
  nopl   (%rax)
L6:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: %.3f 

assistant: ```c
int main() {
  float niz[10] = {1734.4371, 172.432, 172.213};
  f1(niz, 10);
  int i;
  for (i = 0; i < 10; i++)
    printf("%.3f ", niz[i]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    $0xa,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movups %xmm0,0x8(%rsp)
  lea    0x28(%rsp),%r12
  mov    D1(%rip),%rax
  mov    %rbx,%rdi
  movups %xmm0,0x18(%rsp)
  movl   $0x432c3687,0x8(%rsp)
  mov    %rax,(%rsp)
  call   <f1@plt>
  nopl   0x0(%rax)
L11:
  movss  (%rbx),%xmm0
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string
name: extract_symbolic_data
arguments: tag: D1
type: f32[2]

tool: D6: %.3f 

tool: {"D1": [1734.4371337890625,172.4320068359375]}

assistant: ```c
int main() {
  float niz[10] = {1734.4371, 172.432, 172.213};
  f1(niz, 10);
  int i;
  for (i = 0; i < 10; i++)
    printf("%.3f ", niz[i]);
  return 0;
}
```