ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<parse_highlights>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <alloc_array@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L1:
  mov    %rsp,%r14
  lea    D10(%rip),%r13
  lea    D6(%rip),%r15
  jmp    L64
L16:
  lea    D19(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
L38:
  mov    (%rsp),%rax
  movb   $0x1,(%rbx,%rax,1)
L64:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L31
  cmp    %r12,(%rsp)
  jb     L38
  mov    %r15,%rdi
  call   <perror@plt>
  jmp    L38
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string

tool: D10: %zd

tool: D6: at least one of the lines specified in the given file is out of bound


tool: D19: can't malloc


assistant: ```c
char *parse_highlights(FILE *highlight_fstream, size_t height) {
  size_t num;
  char *highlights = (char *)alloc_array(height, sizeof(char));
  if (highlights == NULL) {
    perror("can't malloc\n");
    exit(1);
  }
  while (fscanf(highlight_fstream, "%zd", &num) == 1) {
    if (num >= height) {
      perror("at least one of the lines specified in the given file is out of bound\n");
    }
    highlights[num] = 1;
  }
  return highlights;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_highlights>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <alloc_array@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
L17:
  mov    %rsp,%r14
  lea    D15(%rip),%r13
  lea    D17(%rip),%r15
  jmp    L35
L55:
  movb   $0x1,(%r12,%rax,1)
L35:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L0
  mov    (%rsp),%rax
  cmp    %rbp,%rax
  jb     L55
  mov    %r15,%rdi
  call   <perror@plt>
  mov    (%rsp),%rax
  jmp    L55
  nop
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  lea    D29(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L17
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D29
type_infered: string

tool: D15: %zd

tool: D17: at least one of the lines specified in the given file is out of bound


tool: D29: can't malloc


assistant: ```c
char *parse_highlights(FILE *highlight_fstream, size_t height) {
  size_t num;
  char *highlights = (char *)alloc_array(height, sizeof(char));
  if (highlights == NULL) {
    perror("can't malloc\n");
    exit(1);
  }
  while (fscanf(highlight_fstream, "%zd", &num) == 1) {
    if (num >= height) {
      perror("at least one of the lines specified in the given file is out of bound\n");
    }
    highlights[num] = 1;
  }
  return highlights;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_highlights>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <alloc_array@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L27:
  mov    %rsp,%r14
  lea    D15(%rip),%r13
  lea    D4(%rip),%r15
  jmp    L54
L37:
  movb   $0x1,(%r12,%rax,1)
L54:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L63
  mov    (%rsp),%rax
  cmp    %rbp,%rax
  jb     L37
  mov    %r15,%rdi
  call   <perror@plt>
  mov    (%rsp),%rax
  jmp    L37
  nop
L63:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L27
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D3
type: string

tool: D15: %zd

tool: D4: at least one of the lines specified in the given file is out of bound


tool: D3: can't malloc


assistant: ```c
char *parse_highlights(FILE *highlight_fstream, size_t height) {
  size_t num;
  char *highlights = (char *)alloc_array(height, sizeof(char));
  if (highlights == NULL) {
    perror("can't malloc\n");
    exit(1);
  }
  while (fscanf(highlight_fstream, "%zd", &num) == 1) {
    if (num >= height) {
      perror("at least one of the lines specified in the given file is out of bound\n");
    }
    highlights[num] = 1;
  }
  return highlights;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninit_fgetc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninit_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uninit_fgetc>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <fgetc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninit_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uninit_fgetc>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <fgetc@plt>
```

assistant: ```c
void uninit_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<uninit_fgetc>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <fgetc@plt>
```

assistant: ```c
void uninit_fgetc(void) {
  FILE *fp;
  (void)fgetc(fp);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_int_1D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy_int_1D(int length, int *from, int *to) {
  int i;
  for (i = 0; i < length; i++) {
    to[i] = from[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copy_int_1D>:
  endbr64
  test   %edi,%edi
  jle    L6
  mov    %edi,%edi
  mov    $0x0,%eax
L2:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L2
L6:
  ret
```

assistant: ```c
void copy_int_1D(int length, int *from, int *to) {
  int i;
  for (i = 0; i < length; i++) {
    to[i] = from[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_int_1D>:
  endbr64
  test   %edi,%edi
  jle    L9
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L14:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L14
L9:
  ret
```

assistant: ```c
void copy_int_1D(int length, int *from, int *to) {
  int i;
  for (i = 0; i < length; i++) {
    to[i] = from[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_int_1D>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L27
  lea    0x4(%rsi),%rsi
  mov    %rdx,%rax
  sub    %rsi,%rax
  cmp    $0x8,%rax
  jbe    L34
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L34
  shr    $0x2,%edi
  xor    %eax,%eax
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L75:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L75
  mov    %r9d,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%r9b
  je     L27
  mov    %eax,%r8d
  mov    (%rcx,%r8,4),%esi
  lea    0x0(,%r8,4),%rdi
  mov    %esi,(%rdx,%r8,4)
  lea    0x1(%rax),%esi
  cmp    %esi,%r9d
  jle    L27
  mov    0x4(%rcx,%rdi,1),%esi
  add    $0x2,%eax
  mov    %esi,0x4(%rdx,%rdi,1)
  cmp    %eax,%r9d
  jle    L27
  mov    0x8(%rcx,%rdi,1),%eax
  mov    %eax,0x8(%rdx,%rdi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %r9d,%esi
  xor    %eax,%eax
  nopl   (%rax)
L48:
  mov    (%rcx,%rax,4),%edi
  mov    %edi,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L48
L27:
  ret
```

assistant: ```c
void copy_int_1D(int length, int *from, int *to) {
  int i;
  for (i = 0; i < length; i++) {
    to[i] = from[i];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__get_array_size@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__get_array_size@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L43
  mov    $0x0,%eax
  jmp    L45
L43:
  cmpl   $0x0,-0xc(%rbp)
  js     L34
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L32
L34:
  jmp    L34
L32:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
L45:
  leave
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int size1, size2;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  size1 = __get_array_size(s1);
  size2 = __get_array_size(s2);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size1)
    while (1)
      ;
  return (void *)s1 + offset;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strpbrk>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <__get_array_size@plt>
  mov    %eax,%r14d
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <__get_array_size@plt>
  test   %r12d,%r12d
  jne    L15
  test   %ebx,%ebx
  js     L35
  cmp    %r14d,%ebx
  setge  %dl
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rax
  test   %dl,%dl
  jne    L35
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  jmp    L35
L15:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int size1, size2;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  size1 = __get_array_size(s1);
  size2 = __get_array_size(s2);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size1)
    while (1)
      ;
  return (void *)s1 + offset;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strpbrk>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <__infer_nondet_int@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  xor    %eax,%eax
  call   <__get_array_size@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <__get_array_size@plt>
  test   %r12d,%r12d
  jne    L8
  test   %ebx,%ebx
  js     L26
  cmp    %r14d,%ebx
  lea    0x0(%rbp,%rbx,1),%rax
  setge  %dl
  test   %dl,%dl
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  jmp    L26
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int size1, size2;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  size1 = __get_array_size(s1);
  size2 = __get_array_size(s2);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size1)
    while (1)
      ;
  return (void *)s1 + offset;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strpbrk>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <__infer_nondet_int@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <__infer_nondet_int@plt>
  mov    %rbp,%rdi
  movslq %eax,%rbx
  xor    %eax,%eax
  call   <__get_array_size@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  xor    %eax,%eax
  call   <__get_array_size@plt>
  test   %r12d,%r12d
  jne    L10
  test   %ebx,%ebx
  js     L20
  cmp    %r14d,%ebx
  lea    0x0(%rbp,%rbx,1),%rax
  setge  %dl
  test   %dl,%dl
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  jmp    L20
L10:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  int size1, size2;
  int nondet;
  int offset;
  nondet = __infer_nondet_int();
  offset = __infer_nondet_int();
  size1 = __get_array_size(s1);
  size2 = __get_array_size(s2);
  if (nondet)
    return 0;
  if (offset < 0 || offset >= size1)
    while (1)
      ;
  return (void *)s1 + offset;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_isprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ft_isdigit@plt>
  test   %rax,%rax
  jne    L0
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <ft_isalpha@plt>
  test   %rax,%rax
  jne    L0
  cmpl   $0x1f,-0x4(%rbp)
  jle    L7
  cmpl   $0x7e,-0x4(%rbp)
  jg     L7
L0:
  mov    $0x1,%eax
  jmp    L35
L7:
  mov    $0x0,%eax
L35:
  leave
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (ft_isdigit(c) || ft_isalpha(c) || (c >= 32 && c <= 126))
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_isprint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <ft_isdigit@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L17
L27:
  pop    %rbx
  ret
L17:
  mov    %ebx,%edi
  call   <ft_isalpha@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L27
  sub    $0x20,%ebx
  cmp    $0x5e,%ebx
  setbe  %al
  movzbl %al,%eax
  jmp    L27
```

assistant: ```c
int ft_isprint(int c) {
  if (ft_isdigit(c) || ft_isalpha(c) || (c >= 32 && c <= 126))
    return (1);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_isprint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L6
L9:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%edi
  call   <ft_isalpha@plt>
  test   %rax,%rax
  jne    L9
  sub    $0x20,%ebx
  xor    %eax,%eax
  cmp    $0x5e,%ebx
  pop    %rbx
  setbe  %al
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (ft_isdigit(c) || ft_isalpha(c) || (c >= 32 && c <= 126))
    return (1);
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_isprint>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <ft_isdigit@plt>
  test   %rax,%rax
  je     L12
L18:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%edi
  call   <ft_isalpha@plt>
  test   %rax,%rax
  jne    L18
  sub    $0x20,%ebx
  xor    %eax,%eax
  cmp    $0x5e,%ebx
  pop    %rbx
  setbe  %al
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (ft_isdigit(c) || ft_isalpha(c) || (c >= 32 && c <= 126))
    return (1);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<timeval_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  jmp    L6
L14:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0xf4240(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  js     L14
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cltq
  imul   $0xf4240,%rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long long timeval_diff(struct timeval *end_time, struct timeval *start_time) {
  struct timeval *difference;
  difference->tv_sec = end_time->tv_sec - start_time->tv_sec;
  difference->tv_usec = end_time->tv_usec - start_time->tv_usec;
  while (difference->tv_usec < 0) {
    difference->tv_usec += 1000000;
    difference->tv_sec -= 1;
  }
  return (1000000LL * difference->tv_sec + difference->tv_usec);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<timeval_diff>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  mov    $0x0,%r8d
  mov    %eax,(%r8)
  mov    0x8(%rdi),%rdx
  sub    0x8(%rsi),%rdx
  mov    %rdx,0x8(%r8)
  jns    L6
  sub    $0x1,%eax
L1:
  mov    %eax,%ecx
  sub    $0x1,%eax
  add    $0xf4240,%rdx
  js     L1
  mov    $0x0,%r8d
  mov    %rdx,0x8(%r8)
  mov    %ecx,(%r8)
L6:
  movslq 0x0,%rax
  imul   $0xf4240,%rax,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
long long timeval_diff(struct timeval *end_time, struct timeval *start_time) {
  struct timeval *difference;
  difference->tv_sec = end_time->tv_sec - start_time->tv_sec;
  difference->tv_usec = end_time->tv_usec - start_time->tv_usec;
  while (difference->tv_usec < 0) {
    difference->tv_usec += 1000000;
    difference->tv_sec -= 1;
  }
  return (1000000LL * difference->tv_sec + difference->tv_usec);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<timeval_diff>:
  endbr64
  mov    (%rdi),%eax
  xor    %r8d,%r8d
  sub    (%rsi),%eax
  mov    0x8(%rdi),%rdx
  sub    0x8(%rsi),%rdx
  mov    %eax,(%r8)
  mov    %rdx,0x8(%r8)
  jns    L9
  sub    $0x1,%eax
  nop
L5:
  mov    %eax,%ecx
  sub    $0x1,%eax
  add    $0xf4240,%rdx
  js     L5
  xor    %r8d,%r8d
  mov    %rdx,0x8(%r8)
  mov    %ecx,(%r8)
L9:
  movslq 0x0,%rax
  imul   $0xf4240,%rax,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
long long timeval_diff(struct timeval *end_time, struct timeval *start_time) {
  struct timeval *difference;
  difference->tv_sec = end_time->tv_sec - start_time->tv_sec;
  difference->tv_usec = end_time->tv_usec - start_time->tv_usec;
  while (difference->tv_usec < 0) {
    difference->tv_usec += 1000000;
    difference->tv_sec -= 1;
  }
  return (1000000LL * difference->tv_sec + difference->tv_usec);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<timeval_diff>:
  endbr64
  mov    %rsi,%rax
  mov    (%rdi),%r8d
  xor    %edx,%edx
  sub    (%rsi),%r8d
  mov    0x8(%rdi),%rsi
  sub    0x8(%rax),%rsi
  mov    %r8d,(%rdx)
  mov    %rsi,0x8(%rdx)
  jns    L80
  movabs $0x431bde82d7b634db,%rcx
  mov    %rsi,%rdx
  not    %rdx
  mov    %rdx,%rax
  mul    %rcx
  shr    $0x12,%rdx
  add    $0x1,%rdx
  cmp    $0xffffffffffa4727f,%rsi
  ja     L24
  lea    0xf4240(%rsi),%rax
  movd   %r8d,%xmm5
  movq   %rsi,%xmm3
  mov    %rdx,%rcx
  movq   %rax,%xmm4
  pshufd $0x0,%xmm5,%xmm2
  shr    $0x2,%rcx
  xor    %eax,%eax
  paddd  D11(%rip),%xmm2
  movdqa D6(%rip),%xmm7
  punpcklqdq %xmm4,%xmm3
  pcmpeqd %xmm4,%xmm4
  movdqa D19(%rip),%xmm6
  movdqa D38(%rip),%xmm5
  nopl   0x0(%rax,%rax,1)
L86:
  movdqa %xmm2,%xmm0
  movdqa %xmm3,%xmm1
  paddd  %xmm7,%xmm2
  add    $0x1,%eax
  paddq  %xmm6,%xmm3
  paddq  %xmm5,%xmm1
  paddd  %xmm4,%xmm0
  cmp    %ecx,%eax
  jne    L86
  mov    %rdx,%rdi
  pshufd $0xff,%xmm0,%xmm0
  movhlps %xmm1,%xmm6
  and    $0xfffffffffffffffc,%rdi
  movd   %xmm0,%eax
  movq   %xmm6,%rcx
  imul   $0xf4240,%rdi,%r9
  sub    %edi,%r8d
  add    %r9,%rsi
  cmp    %rdi,%rdx
  je     L95
L24:
  mov    %rsi,%rcx
  lea    -0x1(%r8),%eax
  add    $0xf4240,%rcx
  jns    L95
  mov    %rsi,%rcx
  lea    -0x2(%r8),%eax
  add    $0x1e8480,%rcx
  jns    L95
  mov    %rsi,%rcx
  lea    -0x3(%r8),%eax
  add    $0x2dc6c0,%rcx
  jns    L95
  mov    %rsi,%rcx
  lea    -0x4(%r8),%eax
  add    $0x3d0900,%rcx
  jns    L95
  mov    %rsi,%rcx
  lea    -0x5(%r8),%eax
  add    $0x4c4b40,%rcx
  jns    L95
  lea    0x5b8d80(%rsi),%rcx
  lea    -0x6(%r8),%eax
L95:
  xor    %edx,%edx
  mov    %rcx,0x8(%rdx)
  mov    %eax,(%rdx)
L19:
  movslq 0x0,%rax
  imul   $0xf4240,%rax,%rax
  add    %rcx,%rax
  ret
  nop
L80:
  mov    %rsi,%rcx
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: byte[16]

tool: {"D11": [0x00,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0xfe,0xff,0xff,0xff,0xfd,0xff,0xff,0xff]}

tool: {"D6": [0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff,0xfc,0xff,0xff,0xff]}

tool: {"D19": [0x00,0x09,0x3d,0x00,0x00,0x00,0x00,0x00,0x00,0x09,0x3d,0x00,0x00,0x00,0x00,0x00]}

tool: {"D38": [0xc0,0xc6,0x2d,0x00,0x00,0x00,0x00,0x00,0xc0,0xc6,0x2d,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
long long timeval_diff(struct timeval *end_time, struct timeval *start_time) {
  struct timeval *difference;
  difference->tv_sec = end_time->tv_sec - start_time->tv_sec;
  difference->tv_usec = end_time->tv_usec - start_time->tv_usec;
  while (difference->tv_usec < 0) {
    difference->tv_usec += 1000000;
    difference->tv_sec -= 1;
  }
  return (1000000LL * difference->tv_sec + difference->tv_usec);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<BuildIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movw   $0x1,-0x2(%rbp)
  jmp    L3
L4:
  movswq -0x2(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movswl -0x2(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L3:
  movswl -0x2(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jg     L4
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D23
type: string
name: disassemble_data
arguments: tag: D2
type: string

tool: D15: %s:


tool: D23: 	argv[%d] = %s


tool: D2: BuildIndex 

assistant: ```c
int BuildIndex(int argc, char **argv) {
  short k;
  printf("%s:\n", argv[0]);
  for (k = 1; k < argc; ++k)
    printf("\targv[%d] = %s\n", k, argv[k]);
  printf("BuildIndex \n");
  return (0);
}
```