ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_int>:
  endbr64
  mov    $0x0,%eax
  test   %esi,%esi
  jns    L8
  ret
L8:
  sub    $0x8,%rsp
  call   <get_str@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L10
  call   <atoi@plt>
L10:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_int(char *line, int column_number) {
  if (column_number >= 0) {
    const char *s = get_str(line, column_number);
    return s ? atoi(s) : 0;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_int>:
  endbr64
  test   %esi,%esi
  jns    L10
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  sub    $0x8,%rsp
  call   <get_str@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L11
  add    $0x8,%rsp
  jmp    1070 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_int(char *line, int column_number) {
  if (column_number >= 0) {
    const char *s = get_str(line, column_number);
    return s ? atoi(s) : 0;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_int>:
  endbr64
  test   %esi,%esi
  jns    L5
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  sub    $0x8,%rsp
  call   <get_str@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L7
  add    $0x8,%rsp
  jmp    1070 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int get_int(char *line, int column_number) {
  if (column_number >= 0) {
    const char *s = get_str(line, column_number);
    return s ? atoi(s) : 0;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lacf_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L3:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L24
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
L24:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,%rdx
  cmova  %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void lacf_strlcpy(char *restrict dest, const char *restrict src, size_t cap) {
  size_t l;
  (void)(cap != 0);
  for (l = 0; l + 1 < cap && src[l] != '\0'; l++)
    ;
  memcpy(dest, src, ((cap - 1) < (l + 1) ? (cap - 1) : (l + 1)));
  dest[cap - 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lacf_strlcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%edx
L9:
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jae    L4
  cmpb   $0x0,-0x1(%rsi,%rdx,1)
  jne    L9
L4:
  lea    -0x1(%rbx),%rax
  cmp    %rax,%rdx
  cmova  %rax,%rdx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lacf_strlcpy(char *restrict dest, const char *restrict src, size_t cap) {
  size_t l;
  (void)(cap != 0);
  for (l = 0; l + 1 < cap && src[l] != '\0'; l++)
    ;
  memcpy(dest, src, ((cap - 1) < (l + 1) ? (cap - 1) : (l + 1)));
  dest[cap - 1] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lacf_strlcpy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  xor    %edx,%edx
  sub    $0x8,%rsp
  jmp    L28
  nopl   0x0(%rax)
L3:
  cmpb   $0x0,-0x1(%rsi,%rdx,1)
  je     L26
L28:
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jb     L3
L26:
  lea    -0x1(%rbx),%rax
  mov    %rbp,%rdi
  cmp    %rax,%rdx
  cmova  %rax,%rdx
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lacf_strlcpy(char *restrict dest, const char *restrict src, size_t cap) {
  size_t l;
  (void)(cap != 0);
  for (l = 0; l + 1 < cap && src[l] != '\0'; l++)
    ;
  memcpy(dest, src, ((cap - 1) < (l + 1) ? (cap - 1) : (l + 1)));
  dest[cap - 1] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<lacf_strlcpy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  xor    %edx,%edx
  sub    $0x8,%rsp
  jmp    L9
  nopl   0x0(%rax)
L25:
  cmpb   $0x0,-0x1(%rsi,%rdx,1)
  je     L11
L9:
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jb     L25
L11:
  lea    -0x1(%rbx),%rax
  mov    %rbp,%rdi
  cmp    %rax,%rdx
  cmova  %rax,%rdx
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lacf_strlcpy(char *restrict dest, const char *restrict src, size_t cap) {
  size_t l;
  (void)(cap != 0);
  for (l = 0; l + 1 < cap && src[l] != '\0'; l++)
    ;
  memcpy(dest, src, ((cap - 1) < (l + 1) ? (cap - 1) : (l + 1)));
  dest[cap - 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2SRxFIFOLimitGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x80c,%rax
  mov    (%rax),%rax
  and    $0xfffe,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long I2SRxFIFOLimitGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x0000080C))) & 0xFFFE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2SRxFIFOLimitGet>:
  endbr64
  mov    0x80c(%rdi),%rax
  and    $0xfffe,%eax
  ret
```

assistant: ```c
unsigned long I2SRxFIFOLimitGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x0000080C))) & 0xFFFE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<I2SRxFIFOLimitGet>:
  endbr64
  mov    0x80c(%rdi),%rax
  and    $0xfffe,%eax
  ret
```

assistant: ```c
unsigned long I2SRxFIFOLimitGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x0000080C))) & 0xFFFE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<I2SRxFIFOLimitGet>:
  endbr64
  mov    0x80c(%rdi),%rax
  and    $0xfffe,%eax
  ret
```

assistant: ```c
unsigned long I2SRxFIFOLimitGet(unsigned long ulBase) {
  ;
  return ((*((volatile unsigned long *)(ulBase + 0x0000080C))) & 0xFFFE);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_cpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L5:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  jle    L2
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L2:
  cmpl   $0x1f,-0x4(%rbp)
  jg     L5
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void str_cpy(char *to, const char *from) {
  int c;
  do {
    c = *from++;
    if (c >= ' ')
      *to++ = c;
  } while (c >= ' ');
  *to = '\0';
}
```
user: What is the c source code of the assembly code below?

```asm
<str_cpy>:
  endbr64
  jmp    L14
L9:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
L14:
  movzbl (%rsi),%eax
  cmp    $0x1f,%al
  jg     L9
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void str_cpy(char *to, const char *from) {
  int c;
  do {
    c = *from++;
    if (c >= ' ')
      *to++ = c;
  } while (c >= ' ');
  *to = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_cpy>:
  endbr64
  movzbl (%rsi),%edx
  cmp    $0x1f,%dl
  jle    L7
  lea    0x1(%rsi),%rax
L19:
  add    $0x1,%rax
  mov    %dl,(%rdi)
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jg     L19
L7:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void str_cpy(char *to, const char *from) {
  int c;
  do {
    c = *from++;
    if (c >= ' ')
      *to++ = c;
  } while (c >= ' ');
  *to = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_cpy>:
  endbr64
  movzbl (%rsi),%edx
  cmp    $0x1f,%dl
  jle    L0
  lea    0x1(%rsi),%rax
L6:
  add    $0x1,%rax
  mov    %dl,(%rdi)
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jg     L6
L0:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void str_cpy(char *to, const char *from) {
  int c;
  do {
    c = *from++;
    if (c >= ' ')
      *to++ = c;
  } while (c >= ' ');
  *to = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<x_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <add_alloc@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *x_malloc(char *file, int lineno, size_t bytes) {
  void *t;
  t = malloc(bytes);
  add_alloc(t, bytes, file, lineno);
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<x_malloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <add_alloc@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *x_malloc(char *file, int lineno, size_t bytes) {
  void *t;
  t = malloc(bytes);
  add_alloc(t, bytes, file, lineno);
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<x_malloc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <add_alloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *x_malloc(char *file, int lineno, size_t bytes) {
  void *t;
  t = malloc(bytes);
  add_alloc(t, bytes, file, lineno);
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<x_malloc>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <add_alloc@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *x_malloc(char *file, int lineno, size_t bytes) {
  void *t;
  t = malloc(bytes);
  add_alloc(t, bytes, file, lineno);
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d

assistant: ```c
void input(int array[], int length) {
  int i = 0;
  for (i = 0; i < length; i++) {
    scanf("%d", &array[i]);
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<input>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D7(%rip),%rbp
L12:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: %d

assistant: ```c
void input(int array[], int length) {
  int i = 0;
  for (i = 0; i < length; i++) {
    scanf("%d", &array[i]);
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<input>:
  endbr64
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L8:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L19:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: %d

assistant: ```c
void input(int array[], int length) {
  int i = 0;
  for (i = 0; i < length; i++) {
    scanf("%d", &array[i]);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<input>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: %d

assistant: ```c
void input(int array[], int length) {
  int i = 0;
  for (i = 0; i < length; i++) {
    scanf("%d", &array[i]);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<invalidate_id_status>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x0,-0x28(%rbp)
  jle    L31
  cmpq   $0x0,-0x38(%rbp)
  je     L55
  movl   $0x0,-0x10(%rbp)
  jmp    L54
L19:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movl   $0xffffffff,(%rax)
  addl   $0x1,-0x10(%rbp)
L54:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L19
  lea    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <nc_inq_varid@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nc_put_var_int@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L55:
  cmpq   $0x0,-0x30(%rbp)
  je     L31
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L65:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L65
  lea    -0x14(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <nc_inq_varid@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x14(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <nc_put_var_int@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L31:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
void invalidate_id_status(int exoid, const char *var_stat, const char *var_id, int count, int *ids) {
  int status;
  int i;
  int id_var, stat_var;
  if (count > 0) {
    if (var_id != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = -1;
      }
      status = nc_inq_varid(exoid, var_id, &id_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, id_var, ids);
      assert(status == 0);
    }
    if (var_stat != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = 0;
      }
      status = nc_inq_varid(exoid, var_stat, &stat_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, stat_var, ids);
      assert(status == 0);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<invalidate_id_status>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L0
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rsi
  mov    %ecx,%ebp
  mov    %r8,%rbx
  test   %rdx,%rdx
  je     L32
  mov    %r8,%rax
  lea    -0x1(%rcx),%edx
  lea    0x4(%r8,%rdx,4),%rdx
L41:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L41
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <nc_inq_varid@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    (%rsp),%esi
  mov    %r12d,%edi
  call   <nc_put_var_int@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L32:
  test   %r13,%r13
  je     L0
  mov    %rbx,%rax
  lea    -0x1(%rbp),%edx
  lea    0x4(%rbx,%rdx,4),%rdx
L5:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <nc_inq_varid@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdx
  mov    0x4(%rsp),%esi
  mov    %r12d,%edi
  call   <nc_put_var_int@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void invalidate_id_status(int exoid, const char *var_stat, const char *var_id, int count, int *ids) {
  int status;
  int i;
  int id_var, stat_var;
  if (count > 0) {
    if (var_id != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = -1;
      }
      status = nc_inq_varid(exoid, var_id, &id_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, id_var, ids);
      assert(status == 0);
    }
    if (var_stat != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = 0;
      }
      status = nc_inq_varid(exoid, var_stat, &stat_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, stat_var, ids);
      assert(status == 0);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<invalidate_id_status>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L27
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %ecx,%ebx
  mov    %r8,%r12
  test   %rdx,%rdx
  je     L8
  movslq %ecx,%rdx
  mov    %r8,%rdi
  mov    $0xff,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rsp,%rdx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <nc_inq_varid@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    (%rsp),%esi
  mov    %ebp,%edi
  mov    %r12,%rdx
  call   <nc_put_var_int@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
L8:
  test   %r13,%r13
  je     L27
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <nc_inq_varid@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  mov    %ebp,%edi
  mov    %r12,%rdx
  call   <nc_put_var_int@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void invalidate_id_status(int exoid, const char *var_stat, const char *var_id, int count, int *ids) {
  int status;
  int i;
  int id_var, stat_var;
  if (count > 0) {
    if (var_id != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = -1;
      }
      status = nc_inq_varid(exoid, var_id, &id_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, id_var, ids);
      assert(status == 0);
    }
    if (var_stat != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = 0;
      }
      status = nc_inq_varid(exoid, var_stat, &stat_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, stat_var, ids);
      assert(status == 0);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<invalidate_id_status>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L1
  mov    %edi,%ebp
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %ecx,%ebx
  mov    %r8,%r12
  test   %rdx,%rdx
  je     L20
  movslq %ecx,%rdx
  mov    %r8,%rdi
  mov    $0xff,%esi
  shl    $0x2,%rdx
  call   <memset@plt>
  mov    %rsp,%rdx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <nc_inq_varid@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    (%rsp),%esi
  mov    %ebp,%edi
  mov    %r12,%rdx
  call   <nc_put_var_int@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
L20:
  test   %r13,%r13
  je     L1
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
  lea    0x4(%rsp),%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <nc_inq_varid@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  mov    %ebp,%edi
  mov    %r12,%rdx
  call   <nc_put_var_int@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void invalidate_id_status(int exoid, const char *var_stat, const char *var_id, int count, int *ids) {
  int status;
  int i;
  int id_var, stat_var;
  if (count > 0) {
    if (var_id != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = -1;
      }
      status = nc_inq_varid(exoid, var_id, &id_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, id_var, ids);
      assert(status == 0);
    }
    if (var_stat != 0) {
      for (i = 0; i < count; i++) {
        ids[i] = 0;
      }
      status = nc_inq_varid(exoid, var_stat, &stat_var);
      assert(status == 0);
      status = nc_put_var_int(exoid, stat_var, ids);
      assert(status == 0);
    }
  }
}
```