ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<test2>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  shl    %cl,%edx
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x20,%r12d
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: i %d: %u


assistant: ```c
void test2() {
  int i = 0;
  for (i = 0; i < 32; i++) {
    printf("i %d: %u\n", i, 0x1 << i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test2>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  shl    %cl,%edx
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x20,%r12d
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D1: i %d: %u


assistant: ```c
void test2() {
  int i = 0;
  for (i = 0; i < 32; i++) {
    printf("i %d: %u\n", i, 0x1 << i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<merge_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D13
type: string

tool: D12: mid = %i


tool: D13: wip

assistant: ```c
void merge_sort(int *a, int len) {
  int mid = len / 2;
  printf("mid = %i\n", mid);
  printf("wip\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge_sort>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  shr    $0x1f,%eax
  lea    (%rax,%rsi,1),%esi
  sar    %esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string

tool: D2: mid = %i


tool: D13: wip

assistant: ```c
void merge_sort(int *a, int len) {
  int mid = len / 2;
  printf("mid = %i\n", mid);
  printf("wip\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<merge_sort>:
  endbr64
  mov    %esi,%eax
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  shr    $0x1f,%eax
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D10
datatype: string

tool: D18: mid = %i


tool: D10: wip

assistant: ```c
void merge_sort(int *a, int len) {
  int mid = len / 2;
  printf("mid = %i\n", mid);
  printf("wip\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<merge_sort>:
  endbr64
  mov    %esi,%eax
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  shr    $0x1f,%eax
  add    %eax,%esi
  xor    %eax,%eax
  sar    %esi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D3: mid = %i


tool: D9: wip

assistant: ```c
void merge_sort(int *a, int len) {
  int mid = len / 2;
  printf("mid = %i\n", mid);
  printf("wip\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_directory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L2
  mov    -0x40(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L2
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L2
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D24(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L32
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L37
L32:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L2:
  mov    $0x0,%eax
L37:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string

tool: D15: ..

tool: D1: .

tool: D24: %s/%s

assistant: ```c
int is_directory(char *relpath, char *dirname) {
  if (strcmp(dirname, "..") != 0 && strcmp(dirname, ".") != 0) {
    int len = strlen(relpath) + strlen(dirname) + 1;
    char *path = malloc(len + 1);
    if (path != NULL) {
      snprintf(path, len + 1, "%s/%s", relpath, dirname);
      DIR *dirp = opendir(path);
      if (dirp != NULL) {
        closedir(dirp);
        free(path);
        return 1;
      } else
        free(path);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_directory>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L51
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L39
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%eax
  test   %r12,%r12
  je     L39
  mov    %rbx,%r8
  mov    %rbp,%rcx
  lea    D15(%rip),%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdi
  call   <opendir@plt>
  test   %rax,%rax
  je     L46
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L39
L46:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L39
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D15
data_type: string

tool: D9: ..

tool: D11: .

tool: D15: %s/%s

assistant: ```c
int is_directory(char *relpath, char *dirname) {
  if (strcmp(dirname, "..") != 0 && strcmp(dirname, ".") != 0) {
    int len = strlen(relpath) + strlen(dirname) + 1;
    char *path = malloc(len + 1);
    if (path != NULL) {
      snprintf(path, len + 1, "%s/%s", relpath, dirname);
      DIR *dirp = opendir(path);
      if (dirp != NULL) {
        closedir(dirp);
        free(path);
        return 1;
      } else
        free(path);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_directory>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D20(%rip),%rsi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
L28:
  xor    %eax,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L1:
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L28
  mov    %rbx,%r8
  mov    %r12,%rcx
  lea    D10(%rip),%rdx
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L31
  call   <closedir@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L28
```

tool_calls: name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D20: ..

tool: D18: .

tool: D10: %s/%s

assistant: ```c
int is_directory(char *relpath, char *dirname) {
  if (strcmp(dirname, "..") != 0 && strcmp(dirname, ".") != 0) {
    int len = strlen(relpath) + strlen(dirname) + 1;
    char *path = malloc(len + 1);
    if (path != NULL) {
      snprintf(path, len + 1, "%s/%s", relpath, dirname);
      DIR *dirp = opendir(path);
      if (dirp != NULL) {
        closedir(dirp);
        free(path);
        return 1;
      } else
        free(path);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_directory>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L19
L48:
  xor    %eax,%eax
L57:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L19:
  lea    D25(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L48
  mov    %rbx,%r8
  mov    %r12,%rcx
  lea    D5(%rip),%rdx
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <opendir@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L51
  call   <closedir@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L48
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D25
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D0: ..

tool: D25: .

tool: D5: %s/%s

assistant: ```c
int is_directory(char *relpath, char *dirname) {
  if (strcmp(dirname, "..") != 0 && strcmp(dirname, ".") != 0) {
    int len = strlen(relpath) + strlen(dirname) + 1;
    char *path = malloc(len + 1);
    if (path != NULL) {
      snprintf(path, len + 1, "%s/%s", relpath, dirname);
      DIR *dirp = opendir(path);
      if (dirp != NULL) {
        closedir(dirp);
        free(path);
        return 1;
      } else
        free(path);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<inet_pton4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L199
L87:
  mov    -0x28(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L74
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  lea    D5(%rip),%rdx
  mov    -0x18(%rbp),%rax
  sub    %rdx,%rax
  add    %ecx,%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L14
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    $0x0,%eax
  jmp    L162
L14:
  cmpl   $0xff,-0x24(%rbp)
  jbe    L102
  mov    $0x0,%eax
  jmp    L162
L102:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  cmpl   $0x0,-0x30(%rbp)
  jne    L199
  addl   $0x1,-0x2c(%rbp)
  cmpl   $0x4,-0x2c(%rbp)
  jle    L73
  mov    $0x0,%eax
  jmp    L162
L73:
  movl   $0x1,-0x30(%rbp)
  jmp    L199
L74:
  cmpl   $0x2e,-0x28(%rbp)
  jne    L11
  cmpl   $0x0,-0x30(%rbp)
  je     L11
  cmpl   $0x4,-0x2c(%rbp)
  jne    L15
  mov    $0x0,%eax
  jmp    L162
L15:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x30(%rbp)
  jmp    L199
L11:
  mov    $0x0,%eax
  jmp    L162
L199:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jne    L87
  cmpl   $0x3,-0x2c(%rbp)
  jg     L147
  mov    $0x0,%eax
  jmp    L162
L147:
  lea    -0xc(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x1,%eax
L162:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: 0123456789

assistant: ```c
int inet_pton4(const char *src, unsigned char *dst) {
  static const char digits[] = "0123456789";
  int saw_digit, octets, ch;
  unsigned char tmp[4], *tp;
  saw_digit = 0;
  octets = 0;
  tp = tmp;
  *tp = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    if ((pch = strchr(digits, ch)) != 0) {
      unsigned int val = *tp * 10 + (unsigned int)(pch - digits);
      if (saw_digit && *tp == 0)
        return (0);
      if (val > 255)
        return (0);
      *tp = (unsigned char)val;
      if (!saw_digit) {
        if (++octets > 4)
          return (0);
        saw_digit = 1;
      }
    } else if (ch == '.' && saw_digit) {
      if (octets == 4)
        return (0);
      *++tp = 0;
      saw_digit = 0;
    } else
      return (0);
  }
  if (octets < 4)
    return (0);
  memcpy(dst, tmp, 4);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inet_pton4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x14(%rsp)
  movsbl (%rdi),%ebx
  test   %ebx,%ebx
  je     L14
  lea    0x1(%rdi),%rbp
  lea    0x14(%rsp),%r12
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    D6(%rip),%r14
  jmp    L81
L85:
  cmp    $0x2e,%ebx
  sete   %al
  test   %r13b,%al
  je     L123
  cmp    $0x4,%r15d
  je     L123
  movb   $0x0,0x1(%r12)
  lea    0x1(%r12),%r12
  mov    $0x0,%r13d
L82:
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%ebx
  test   %ebx,%ebx
  je     L156
L81:
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L85
  movzbl (%r12),%edx
  movzbl %dl,%ecx
  lea    (%rcx,%rcx,4),%ecx
  sub    %r14,%rax
  lea    (%rax,%rcx,2),%eax
  test   %dl,%dl
  jne    L168
  test   %r13d,%r13d
  jne    L119
L168:
  cmp    $0xff,%eax
  ja     L162
  mov    %al,(%r12)
  test   %r13d,%r13d
  jne    L82
  add    $0x1,%r15d
  cmp    $0x4,%r15d
  jg     L174
  mov    $0x1,%r13d
  jmp    L82
L156:
  cmp    $0x3,%r15d
  jle    L14
  lea    0x14(%rsp),%rsi
  mov    $0x4,%edx
  mov    0x8(%rsp),%rdi
  call   <memcpy@plt>
  mov    $0x1,%ebx
  jmp    L14
L119:
  mov    $0x0,%ebx
  jmp    L14
L162:
  mov    $0x0,%ebx
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L174:
  mov    %r13d,%ebx
  jmp    L14
L123:
  mov    $0x0,%ebx
  jmp    L14
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: 0123456789

assistant: ```c
int inet_pton4(const char *src, unsigned char *dst) {
  static const char digits[] = "0123456789";
  int saw_digit, octets, ch;
  unsigned char tmp[4], *tp;
  saw_digit = 0;
  octets = 0;
  tp = tmp;
  *tp = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    if ((pch = strchr(digits, ch)) != 0) {
      unsigned int val = *tp * 10 + (unsigned int)(pch - digits);
      if (saw_digit && *tp == 0)
        return (0);
      if (val > 255)
        return (0);
      *tp = (unsigned char)val;
      if (!saw_digit) {
        if (++octets > 4)
          return (0);
        saw_digit = 1;
      }
    } else if (ch == '.' && saw_digit) {
      if (octets == 4)
        return (0);
      *++tp = 0;
      saw_digit = 0;
    } else
      return (0);
  }
  if (octets < 4)
    return (0);
  memcpy(dst, tmp, 4);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet_pton4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsbl (%rdi),%r14d
  mov    %rsi,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x14(%rsp)
  test   %r14d,%r14d
  je     L94
  lea    0x14(%rsp),%rax
  lea    0x1(%rdi),%r15
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  lea    D4(%rip),%r12
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L32:
  cmp    $0xff,%eax
  ja     L94
  test   %sil,%sil
  je     L94
  mov    %al,0x0(%r13)
L13:
  movsbl (%r15),%r14d
  add    $0x1,%r15
  test   %r14d,%r14d
  je     L17
L43:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L159
  movzbl 0x0(%r13),%ecx
  sub    %r12,%rax
  mov    %ecx,%esi
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rax,%rcx,2),%eax
  test   %ebx,%ebx
  jne    L32
  cmp    $0xff,%eax
  ja     L94
  add    $0x1,%ebp
  mov    %al,0x0(%r13)
  cmp    $0x4,%ebp
  jg     L94
  movsbl (%r15),%r14d
  add    $0x1,%r15
  mov    $0x1,%ebx
  test   %r14d,%r14d
  jne    L43
L17:
  cmp    $0x3,%ebp
  jle    L94
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    $0x1,%eax
  jmp    L59
  nopl   (%rax)
L159:
  cmp    $0x2e,%r14d
  sete   %al
  test   %bl,%al
  je     L94
  cmp    $0x4,%ebp
  je     L94
  movb   $0x0,0x1(%r13)
  xor    %ebx,%ebx
  add    $0x1,%r13
  jmp    L13
L94:
  xor    %eax,%eax
L59:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: 0123456789

assistant: ```c
int inet_pton4(const char *src, unsigned char *dst) {
  static const char digits[] = "0123456789";
  int saw_digit, octets, ch;
  unsigned char tmp[4], *tp;
  saw_digit = 0;
  octets = 0;
  tp = tmp;
  *tp = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    if ((pch = strchr(digits, ch)) != 0) {
      unsigned int val = *tp * 10 + (unsigned int)(pch - digits);
      if (saw_digit && *tp == 0)
        return (0);
      if (val > 255)
        return (0);
      *tp = (unsigned char)val;
      if (!saw_digit) {
        if (++octets > 4)
          return (0);
        saw_digit = 1;
      }
    } else if (ch == '.' && saw_digit) {
      if (octets == 4)
        return (0);
      *++tp = 0;
      saw_digit = 0;
    } else
      return (0);
  }
  if (octets < 4)
    return (0);
  memcpy(dst, tmp, 4);
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inet_pton4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsbl (%rdi),%r14d
  mov    %rsi,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x14(%rsp)
  test   %r14d,%r14d
  je     L58
  lea    0x14(%rsp),%rax
  lea    0x1(%rdi),%r15
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  lea    D9(%rip),%r12
  jmp    L34
  cs nopw 0x0(%rax,%rax,1)
L48:
  cmp    $0xff,%eax
  ja     L58
  test   %sil,%sil
  je     L58
  mov    %al,0x0(%r13)
L59:
  movsbl (%r15),%r14d
  add    $0x1,%r15
  test   %r14d,%r14d
  je     L2
L34:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L135
  movzbl 0x0(%r13),%ecx
  sub    %r12,%rax
  mov    %ecx,%esi
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rax,%rcx,2),%eax
  test   %ebx,%ebx
  jne    L48
  cmp    $0xff,%eax
  ja     L58
  add    $0x1,%ebp
  mov    %al,0x0(%r13)
  cmp    $0x4,%ebp
  jg     L58
  movsbl (%r15),%r14d
  add    $0x1,%r15
  mov    $0x1,%ebx
  test   %r14d,%r14d
  jne    L34
L2:
  cmp    $0x3,%ebp
  jle    L58
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    $0x1,%eax
  jmp    L113
  nopl   (%rax)
L135:
  cmp    $0x2e,%r14d
  sete   %al
  test   %bl,%al
  je     L58
  cmp    $0x4,%ebp
  je     L58
  movb   $0x0,0x1(%r13)
  xor    %ebx,%ebx
  add    $0x1,%r13
  jmp    L59
L58:
  xor    %eax,%eax
L113:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D9: 0123456789

assistant: ```c
int inet_pton4(const char *src, unsigned char *dst) {
  static const char digits[] = "0123456789";
  int saw_digit, octets, ch;
  unsigned char tmp[4], *tp;
  saw_digit = 0;
  octets = 0;
  tp = tmp;
  *tp = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    if ((pch = strchr(digits, ch)) != 0) {
      unsigned int val = *tp * 10 + (unsigned int)(pch - digits);
      if (saw_digit && *tp == 0)
        return (0);
      if (val > 255)
        return (0);
      *tp = (unsigned char)val;
      if (!saw_digit) {
        if (++octets > 4)
          return (0);
        saw_digit = 1;
      }
    } else if (ch == '.' && saw_digit) {
      if (octets == 4)
        return (0);
      *++tp = 0;
      saw_digit = 0;
    } else
      return (0);
  }
  if (octets < 4)
    return (0);
  memcpy(dst, tmp, 4);
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<outl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0x7,%rax
  ja     L9
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fatal@plt>
L9:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string

tool: D1: out of space to store resource

assistant: ```c
char *outl(p, l, maxl)
char *p;
long l;
long *maxl;
{
  long *q = (long *)p;
  if (*maxl < sizeof(long))
    fatal("out of space to store resource");
  *maxl = *maxl - sizeof(long);
  *q++ = l;
  return (char *)q;
}
```