ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  jmp    L101
L88:
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x28(%rbp),%eax
  cltq
  mov    %rdx,-0x20(%rbp,%rax,8)
  movl   $0x0,-0x24(%rbp)
  jmp    L81
L92:
  mov    -0x28(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x24(%rbp)
L81:
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x24(%rbp)
  jle    L92
  addl   $0x1,-0x28(%rbp)
L101:
  cmpl   $0x2,-0x28(%rbp)
  jle    L88
  movl   $0x0,-0x28(%rbp)
  jmp    L44
L103:
  movl   $0x0,-0x24(%rbp)
  jmp    L0
L4:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L0:
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x24(%rbp)
  jle    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x28(%rbp)
L44:
  cmpl   $0x2,-0x28(%rbp)
  jle    L103
  movl   $0x0,-0x28(%rbp)
  jmp    L43
L10:
  mov    -0x28(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x28(%rbp)
L43:
  cmpl   $0x2,-0x28(%rbp)
  jle    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %4d

assistant: ```c
int main() {
  int *p[3];
  int i, j;
  for (i = 0; i < 3; i++) {
    p[i] = (int *)malloc(sizeof(int) * (2 * i + 1));
    for (j = 0; j < i * 2 + 1; j++)
      p[i][j] = 10 * i + j;
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2 * i + 1; j++)
      printf("%4d", p[i][j]);
    putchar('\n');
  }
  for (i = 0; i < 3; i++)
    free(p[i]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L22:
  lea    0x4(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,(%rsp,%rbp,8)
  test   $0x40000000,%ebp
  jne    L7
  lea    0x0(%rbp,%rbp,4),%edx
  add    %edx,%edx
L35:
  mov    %edx,(%rax)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %ebx,%edx
  jne    L35
L7:
  add    $0x1,%rbp
  add    $0xc,%ebx
  cmp    $0x25,%ebx
  jne    L22
  mov    %rsp,%r12
  mov    $0x4,%ebp
  mov    $0x0,%r14d
  lea    D6(%rip),%r13
L40:
  mov    $0x0,%ebx
  test   %r14d,%r14d
  js     L15
L59:
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L59
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x2,%r14d
  add    $0x8,%r12
  add    $0x8,%rbp
  cmp    $0x1c,%rbp
  jne    L40
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type: string

tool: D6: %4d

assistant: ```c
int main() {
  int *p[3];
  int i, j;
  for (i = 0; i < 3; i++) {
    p[i] = (int *)malloc(sizeof(int) * (2 * i + 1));
    for (j = 0; j < i * 2 + 1; j++)
      p[i][j] = 10 * i + j;
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2 * i + 1; j++)
      printf("%4d", p[i][j]);
    putchar('\n');
  }
  for (i = 0; i < 3; i++)
    free(p[i]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%r13
  sub    %ebp,%ebx
L22:
  lea    (%rbx,%r13,1),%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  mov    %rax,0x0(%r13)
L17:
  mov    %edx,(%rax)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %r12d,%edx
  jne    L17
  add    $0x8,%r13
  add    $0xa,%r14d
  lea    0xc(%rdx),%r12d
  cmp    $0x19,%edx
  jne    L22
  xor    %r14d,%r14d
  lea    D7(%rip),%r13
L37:
  mov    0x0(%rbp,%r14,1),%rbx
  lea    0x4(%rbx,%r14,1),%r12
  nopl   0x0(%rax)
L42:
  mov    (%rbx),%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L42
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    $0x18,%r14
  jne    L37
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %4d

assistant: ```c
int main() {
  int *p[3];
  int i, j;
  for (i = 0; i < 3; i++) {
    p[i] = (int *)malloc(sizeof(int) * (2 * i + 1));
    for (j = 0; j < i * 2 + 1; j++)
      p[i][j] = 10 * i + j;
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2 * i + 1; j++)
      printf("%4d", p[i][j]);
    putchar('\n');
  }
  for (i = 0; i < 3; i++)
    free(p[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x4,%edi
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    $0xc,%edi
  movl   $0x0,(%rax)
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  call   <malloc@plt>
  mov    $0x14,%edi
  mov    %rax,%r14
  mov    %rax,0x18(%rsp)
  mov    D23(%rip),%rax
  movl   $0xc,0x8(%r14)
  mov    %rax,(%r14)
  call   <malloc@plt>
  movdqa D18(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  mov    %rax,%r13
  movl   $0x18,0x10(%rax)
  movups %xmm0,(%rax)
  lea    0x10(%rsp),%rax
  mov    %rax,(%rsp)
L27:
  mov    (%rsp),%rax
  mov    (%rax,%r12,1),%r15
  lea    0x4(%r15,%r12,1),%rbx
  nopl   0x0(%rax)
L14:
  mov    (%r15),%esi
  mov    %rbp,%rdi
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L14
  mov    $0xa,%edi
  add    $0x8,%r12
  call   <putchar@plt>
  cmp    $0x18,%r12
  jne    L27
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D18
type_guessed: byte[16]

tool: D12: %4d

tool: {"D23": [0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D18": [0x14,0x00,0x00,0x00,0x15,0x00,0x00,0x00,0x16,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int *p[3];
  int i, j;
  for (i = 0; i < 3; i++) {
    p[i] = (int *)malloc(sizeof(int) * (2 * i + 1));
    for (j = 0; j < i * 2 + 1; j++)
      p[i][j] = 10 * i + j;
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 2 * i + 1; j++)
      printf("%4d", p[i][j]);
    putchar('\n');
  }
  for (i = 0; i < 3; i++)
    free(p[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_voidQueue@plt>
  mov    $0x0,%eax
  call   <test_resetQueue@plt>
  mov    $0x0,%eax
  call   <test_peekQueue@plt>
  mov    $0x0,%eax
  call   <test_popQueue@plt>
  mov    $0x0,%eax
  call   <test_lengthQueue@plt>
  mov    $0x0,%eax
  call   <test_general@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidQueue();
  test_resetQueue();
  test_peekQueue();
  test_popQueue();
  test_lengthQueue();
  test_general();
  return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_voidQueue@plt>
  mov    $0x0,%eax
  call   <test_resetQueue@plt>
  mov    $0x0,%eax
  call   <test_peekQueue@plt>
  mov    $0x0,%eax
  call   <test_popQueue@plt>
  mov    $0x0,%eax
  call   <test_lengthQueue@plt>
  mov    $0x0,%eax
  call   <test_general@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidQueue();
  test_resetQueue();
  test_peekQueue();
  test_popQueue();
  test_lengthQueue();
  test_general();
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_voidQueue@plt>
  xor    %eax,%eax
  call   <test_resetQueue@plt>
  xor    %eax,%eax
  call   <test_peekQueue@plt>
  xor    %eax,%eax
  call   <test_popQueue@plt>
  xor    %eax,%eax
  call   <test_lengthQueue@plt>
  xor    %eax,%eax
  call   <test_general@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidQueue();
  test_resetQueue();
  test_peekQueue();
  test_popQueue();
  test_lengthQueue();
  test_general();
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_voidQueue@plt>
  xor    %eax,%eax
  call   <test_resetQueue@plt>
  xor    %eax,%eax
  call   <test_peekQueue@plt>
  xor    %eax,%eax
  call   <test_popQueue@plt>
  xor    %eax,%eax
  call   <test_lengthQueue@plt>
  xor    %eax,%eax
  call   <test_general@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_voidQueue();
  test_resetQueue();
  test_peekQueue();
  test_popQueue();
  test_lengthQueue();
  test_general();
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<warterm_initscr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string

tool: D9: XYZZY

assistant: ```c
int warterm_initscr() {
  puts("XYZZY");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<warterm_initscr>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: XYZZY

assistant: ```c
int warterm_initscr() {
  puts("XYZZY");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<warterm_initscr>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: XYZZY

assistant: ```c
int warterm_initscr() {
  puts("XYZZY");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<warterm_initscr>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: XYZZY

assistant: ```c
int warterm_initscr() {
  puts("XYZZY");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isValidOperator>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L20
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D34(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L51
  mov    %rbp,%rsi
  lea    D23(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L115
  mov    %rbx,%rsi
  lea    D92(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L55
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L55
L20:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  mov    %rbx,%rsi
  lea    D92(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L20
L55:
  mov    $0x1,%eax
  jmp    L20
L115:
  mov    %rbp,%rsi
  lea    D91(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L20
  lea    D92(%rip),%rax
  mov    %rax,(%rsp)
  lea    D90(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D37(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D69(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D79(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    %rsp,%rbp
  lea    0x28(%rsp),%r12
L67:
  mov    %rbx,%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L74
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L67
  mov    $0x0,%eax
  jmp    L20
L74:
  mov    $0x1,%eax
  jmp    L20
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D34
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string
name: unpack_data
arguments: data_label: D92
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D91
data_type: string
name: unpack_data
arguments: data_label: D90
data_type: string
name: unpack_data
arguments: data_label: D37
data_type: string
name: unpack_data
arguments: data_label: D69
data_type: string
name: unpack_data
arguments: data_label: D79
data_type: string

tool: D34: ID

tool: D23: NAME

tool: D92: EQ

tool: D29: ~

tool: D91: DATE

tool: D90: LT

tool: D37: LE

tool: D69: GT

tool: D79: GE

assistant: ```c
bool isValidOperator(char *op, char *attr) {
  int i;
  if (op == NULL)
    return false;
  if (strcmp("ID", attr) == 0) {
    char *operators[1] = {"EQ"};
    for (i = 0; i < 1; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  } else if (strcmp("NAME", attr) == 0) {
    char *operators[2] = {"EQ", "~"};
    for (i = 0; i < 2; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  } else if (strcmp("DATE", attr) == 0) {
    char *operators[5] = {"EQ", "LT", "LE", "GT", "GE"};
    for (i = 0; i < 5; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<isValidOperator>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L59
  mov    %rdi,%rbp
  lea    D55(%rip),%rdi
  mov    %rsi,%r12
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L71
  mov    %rbp,%rsi
  lea    D90(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L100
  nopw   0x0(%rax,%rax,1)
L71:
  mov    %r12,%rsi
  lea    D49(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L52
  mov    %rbp,%rsi
  lea    D90(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L58
  mov    %rbp,%rsi
  lea    D67(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L58
L59:
  xor    %eax,%eax
L100:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r12,%rsi
  lea    D94(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L59
  lea    D7(%rip),%rax
  lea    D90(%rip),%rdi
  mov    %rbp,%rsi
  mov    %rsp,%r12
  mov    %rax,0x8(%rsp)
  lea    D101(%rip),%rax
  lea    0x28(%rsp),%rbx
  mov    %rax,0x10(%rsp)
  lea    D24(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D46(%rip),%rax
  mov    %rax,0x20(%rsp)
  call   <strcmp@plt>
  test   %rax,%rax
  je     L58
L47:
  add    $0x8,%r12
  cmp    %r12,%rbx
  je     L59
  mov    (%r12),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
L58:
  mov    $0x1,%eax
  jmp    L100
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D55
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D90
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D49
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D94
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D101
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D46
type_guessed: string

tool: D55: ID

tool: D90: EQ

tool: D49: NAME

tool: D67: ~

tool: D94: DATE

tool: D7: LT

tool: D101: LE

tool: D24: GT

tool: D46: GE

assistant: ```c
bool isValidOperator(char *op, char *attr) {
  int i;
  if (op == NULL)
    return false;
  if (strcmp("ID", attr) == 0) {
    char *operators[1] = {"EQ"};
    for (i = 0; i < 1; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  } else if (strcmp("NAME", attr) == 0) {
    char *operators[2] = {"EQ", "~"};
    for (i = 0; i < 2; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  } else if (strcmp("DATE", attr) == 0) {
    char *operators[5] = {"EQ", "LT", "LE", "GT", "GE"};
    for (i = 0; i < 5; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isValidOperator>:
  endbr64
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  movq   %r13,%xmm1
  push   %rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D48(%rip),%rax
  movq   %rax,%xmm2
  punpcklqdq %xmm2,%xmm1
  movaps %xmm1,(%rsp)
  test   %rdi,%rdi
  je     L47
  mov    %rdi,%rbp
  lea    D5(%rip),%rdi
  mov    %rsi,%r12
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L12
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L35
  nop
L12:
  mov    %r12,%rsi
  lea    D26(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L39
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L78
  mov    %rbp,%rsi
  lea    D88(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L78
L47:
  xor    %eax,%eax
L35:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L89
  add    $0x40,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    %r12,%rsi
  lea    D65(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L47
  movdqa (%rsp),%xmm3
  lea    0x10(%rsp),%r12
  lea    0x38(%rsp),%r13
  lea    D11(%rip),%rax
  lea    D10(%rip),%rcx
  movq   %rax,%xmm4
  movq   %rcx,%xmm0
  movaps %xmm3,0x10(%rsp)
  lea    D23(%rip),%rax
  mov    %rax,0x30(%rsp)
  punpcklqdq %xmm4,%xmm0
  movaps %xmm0,0x20(%rsp)
L108:
  mov    (%r12),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L78
  add    $0x8,%r12
  cmp    %r12,%r13
  jne    L108
  jmp    L47
  nopl   0x0(%rax)
L78:
  mov    $0x1,%eax
  jmp    L35
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
datatype: string
name: extract_symbolic_data
arguments: label: D48
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: string
name: extract_symbolic_data
arguments: label: D88
datatype: string
name: extract_symbolic_data
arguments: label: D65
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string

tool: D37: EQ

tool: D48: LT

tool: D5: ID

tool: D26: NAME

tool: D88: ~

tool: D65: DATE

tool: D11: GT

tool: D10: LE

tool: D23: GE

assistant: ```c
bool isValidOperator(char *op, char *attr) {
  int i;
  if (op == NULL)
    return false;
  if (strcmp("ID", attr) == 0) {
    char *operators[1] = {"EQ"};
    for (i = 0; i < 1; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  } else if (strcmp("NAME", attr) == 0) {
    char *operators[2] = {"EQ", "~"};
    for (i = 0; i < 2; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  } else if (strcmp("DATE", attr) == 0) {
    char *operators[5] = {"EQ", "LT", "LE", "GT", "GE"};
    for (i = 0; i < 5; i++) {
      if ((strcmp(operators[i], op) == 0))
        return true;
    }
  }
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L16
L13:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x86377f7332675bb7,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x13,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4247,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x86377f7332675bb7,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x13,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4247,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movabs $0x86377f7332675bb7,%rdx
  mov    %rcx,%rax
  imul   %rdx
  lea    (%rdx,%rcx,1),%rax
  sar    $0x13,%rax
  mov    %rcx,%rdx
  sar    $0x3f,%rdx
  sub    %rdx,%rax
  imul   $0xf4247,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string

tool: D22: %lld

tool: D29: %lld


assistant: ```c
int main() {
  long long test, num, i, j, k;
  scanf("%lld", &test);
  while (test--) {
    scanf("%lld", &num);
    i = num * (num + 1);
    i = i % 1000007;
    j = ((num - 1) * (num)) / 2;
    j = j % 1000007;
    printf("%lld\n", (i + j) % 1000007);
  }
  return 0;
}
```