ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<equal_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L39
  addl   $0x1,-0x4(%rbp)
  jmp    L8
L39:
  mov    $0x0,%eax
  jmp    L16
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L88
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L88
  mov    $0x1,%eax
  jmp    L16
L88:
  mov    $0x0,%eax
L16:
  pop    %rbp
  ret
```

assistant: ```c
int equal_char(char *src, char *comp) {
  int i;
  i = 0;
  while (src[i] && comp[i]) {
    if (src[i] == comp[i])
      i++;
    else
      return (0);
  }
  if (src[i] == '\0' && comp[i] == '\0')
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<equal_char>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L9
L12:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L30
  cmp    %dl,%cl
  jne    L7
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L12
L9:
  cmpb   $0x0,(%rsi,%rax,1)
  sete   %al
  movzbl %al,%eax
  ret
L30:
  test   %dl,%dl
  je     L9
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int equal_char(char *src, char *comp) {
  int i;
  i = 0;
  while (src[i] && comp[i]) {
    if (src[i] == comp[i])
      i++;
    else
      return (0);
  }
  if (src[i] == '\0' && comp[i] == '\0')
    return (1);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<equal_char>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L18
  jmp    L21
  nop
L4:
  cmp    %dl,%cl
  jne    L38
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L17
L18:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L4
L38:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  add    %rax,%rsi
L21:
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  sete   %al
  ret
```

assistant: ```c
int equal_char(char *src, char *comp) {
  int i;
  i = 0;
  while (src[i] && comp[i]) {
    if (src[i] == comp[i])
      i++;
    else
      return (0);
  }
  if (src[i] == '\0' && comp[i] == '\0')
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<equal_char>:
  endbr64
  movzbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  jne    L41
  jmp    L37
  nop
L7:
  cmp    %dl,%cl
  jne    L26
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L11
L41:
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  jne    L7
L26:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  add    %rax,%rsi
L37:
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  sete   %al
  ret
```

assistant: ```c
int equal_char(char *src, char *comp) {
  int i;
  i = 0;
  while (src[i] && comp[i]) {
    if (src[i] == comp[i])
      i++;
    else
      return (0);
  }
  if (src[i] == '\0' && comp[i] == '\0')
    return (1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rsi
  lea    D41(%rip),%rdi
  call   <printf@plt>
L6:
  mov    %r12d,%r15d
  mov    $0x0,%ebx
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D26(%rip),%r14
  test   %r12d,%r12d
  jne    L53
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L28
L90:
  mov    0x4(%rsp),%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L83:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%r13,%rbx,4),%eax
  lea    -0x20(%rax),%edx
  cmp    $0x5f,%edx
  mov    $0x2e,%edx
  cmovae %edx,%eax
  mov    %ebp,%edx
  mov    %al,0x10(%rsp,%rdx,1)
  add    $0x1,%ebp
  mov    %ebp,%ebp
  movb   $0x0,0x10(%rsp,%rbp,1)
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L13
L53:
  mov    %ebx,0x4(%rsp)
  mov    %ebx,%ebp
  and    $0xf,%ebp
  jne    L83
  test   %ebx,%ebx
  je     L90
  mov    0x8(%rsp),%rsi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L90
L13:
  test   $0xf,%r12b
  je     L74
  lea    D47(%rip),%rbx
L92:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12d
  test   $0xf,%r12b
  jne    L92
L74:
  lea    0x10(%rsp),%rsi
  lea    D42(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D41
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D45
datatype: string
name: parse_data
arguments: data_label: D42
datatype: string
name: parse_data
arguments: data_label: D47
datatype: string

tool: D41: %s:


tool: D26:  %02x

tool: D14:   ZERO LENGTH

tool: D45:   %04x 

tool: D42:   %s


tool: D47:    

assistant: ```c
void hexdump(const char *desc, const void *addr, unsigned int len) {
  unsigned int i;
  char buff[17] = "";
  uint8_t *pc = (uint8_t *)addr;
  if (desc != NULL)
    printf("%s:\n", desc);
  if (len == 0) {
    printf("  ZERO LENGTH\n");
    return;
  }
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i != 0)
        printf("  %s\n", buff);
      printf("  %04x ", i);
    }
    printf(" %02x", (unsigned int)pc[i]);
    if ((pc[i] < 0x20) || (pc[i] > 0x7e))
      buff[i % 16] = '.';
    else
      buff[i % 16] = (char)pc[i];
    buff[(i % 16) + 1] = '\0';
  }
  while ((i % 16) != 0) {
    printf("   ");
    i++;
  }
  printf("  %s\n", buff);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hexdump>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  test   %rdi,%rdi
  je     L26
  mov    %rdi,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
L26:
  mov    %ebp,%eax
  xor    %r14d,%r14d
  lea    D42(%rip),%r13
  mov    %rax,0x8(%rsp)
  lea    0x20(%rsp),%rax
  lea    D18(%rip),%r15
  mov    %rax,0x10(%rsp)
  test   %ebp,%ebp
  je     L3
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r14d,%ebx
  mov    %r14d,%r8d
  and    $0xf,%ebx
  jne    L29
  test   %r14d,%r14d
  je     L76
  mov    0x10(%rsp),%rsi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  mov    %r14d,0x1c(%rsp)
  call   <printf@plt>
  mov    0x1c(%rsp),%r8d
L76:
  mov    %r8d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L29:
  mov    (%r12,%r14,4),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  mov    (%r12,%r14,4),%eax
  lea    -0x20(%rax),%ecx
  cmp    $0x5f,%ecx
  mov    $0x2e,%ecx
  cmovae %ecx,%eax
  mov    %ebx,%ecx
  add    $0x1,%ebx
  add    $0x1,%r14
  mov    %al,0x20(%rsp,%rcx,1)
  movb   $0x0,0x20(%rsp,%rbx,1)
  cmp    0x8(%rsp),%r14
  jne    L10
  lea    D28(%rip),%rbx
  test   $0xf,%bpl
  je     L33
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  test   $0xf,%bpl
  jne    L46
L33:
  mov    0x10(%rsp),%rsi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L75:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L3:
  lea    D32(%rip),%rdi
  call   <puts@plt>
  jmp    L75
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
datatype: string
name: retrieve_data
arguments: tag: D42
datatype: string
name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D45
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string
name: retrieve_data
arguments: tag: D32
datatype: string

tool: D19: %s:


tool: D42:  %02x

tool: D18:   %04x 

tool: D45:   %s


tool: D28:    

tool: D32:   ZERO LENGTH

assistant: ```c
void hexdump(const char *desc, const void *addr, unsigned int len) {
  unsigned int i;
  char buff[17] = "";
  uint8_t *pc = (uint8_t *)addr;
  if (desc != NULL)
    printf("%s:\n", desc);
  if (len == 0) {
    printf("  ZERO LENGTH\n");
    return;
  }
  for (i = 0; i < len; i++) {
    if ((i % 16) == 0) {
      if (i != 0)
        printf("  %s\n", buff);
      printf("  %04x ", i);
    }
    printf(" %02x", (unsigned int)pc[i]);
    if ((pc[i] < 0x20) || (pc[i] > 0x7e))
      buff[i % 16] = '.';
    else
      buff[i % 16] = (char)pc[i];
    buff[(i % 16) + 1] = '\0';
  }
  while ((i % 16) != 0) {
    printf("   ");
    i++;
  }
  printf("  %s\n", buff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0x14,-0x2c(%rbp)
  movl   $0x1e,-0x28(%rbp)
  movl   $0x28,-0x24(%rbp)
  movl   $0x32,-0x20(%rbp)
  movl   $0x3c,-0x1c(%rbp)
  movl   $0x46,-0x18(%rbp)
  movl   $0x50,-0x14(%rbp)
  movl   $0x5a,-0x10(%rbp)
  movl   $0x64,-0xc(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L0
L49:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x3c(%rbp),%eax
  cmp    %eax,%edx
  jne    L36
  addl   $0x1,-0x34(%rbp)
L36:
  addl   $0x1,-0x38(%rbp)
L0:
  cmpl   $0x9,-0x38(%rbp)
  jle    L49
  cmpl   $0x0,-0x34(%rbp)
  jle    L12
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L33
L12:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L33:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
datatype: string
name: extract_symbolic_data
arguments: tag: D38
datatype: string
name: extract_symbolic_data
arguments: tag: D35
datatype: string
name: extract_symbolic_data
arguments: tag: D34
datatype: string

tool: D30: Por favor, digite um numero: 

tool: D38:  %d

tool: D35: Encontra-se no vetor.

tool: D34: Nao se encontra no vetor.

assistant: ```c
main() {
  int i, verifica, resposta = 0, vet[10] = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};
  printf("Por favor, digite um numero: ");
  scanf(" %d", &verifica);
  for (i = 0; i <= 9; i++) {
    if (vet[i] == verifica)
      resposta++;
  }
  if (resposta >= 1) {
    printf("Encontra-se no vetor.");
  } else {
    printf("Nao se encontra no vetor.");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x10(%rsp)
  movl   $0x14,0x14(%rsp)
  movl   $0x1e,0x18(%rsp)
  movl   $0x28,0x1c(%rsp)
  movl   $0x32,0x20(%rsp)
  movl   $0x3c,0x24(%rsp)
  movl   $0x46,0x28(%rsp)
  movl   $0x50,0x2c(%rsp)
  movl   $0x5a,0x30(%rsp)
  movl   $0x64,0x34(%rsp)
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  lea    0x10(%rsp),%rax
  lea    0x38(%rsp),%rsi
  mov    $0x0,%edx
L36:
  cmp    %edi,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L36
  test   %edx,%edx
  jle    L11
  lea    D22(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L11:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
type_infered: string
name: retrieve_data
arguments: data_tag: D33
type_infered: string
name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D21
type_infered: string

tool: D39: Por favor, digite um numero: 

tool: D33:  %d

tool: D22: Encontra-se no vetor.

tool: D21: Nao se encontra no vetor.

assistant: ```c
main() {
  int i, verifica, resposta = 0, vet[10] = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};
  printf("Por favor, digite um numero: ");
  scanf(" %d", &verifica);
  for (i = 0; i <= 9; i++) {
    if (vet[i] == verifica)
      resposta++;
  }
  if (resposta >= 1) {
    printf("Encontra-se no vetor.");
  } else {
    printf("Nao se encontra no vetor.");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x14,0x14(%rsp)
  movabs $0x280000001e,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3c00000032,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x5000000046,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x640000005a,%rax
  mov    %rax,0x30(%rsp)
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  lea    0x14(%rsp),%rax
  xor    %edx,%edx
  lea    0x38(%rsp),%rsi
  mov    $0xa,%ecx
  jmp    L19
L48:
  mov    (%rax),%ecx
  add    $0x4,%rax
L19:
  cmp    %ecx,%edi
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L48
  test   %edx,%edx
  je     L45
  lea    D9(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L45:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D9
type: string
name: extract_symbolic_data
arguments: tag: D15
type: string

tool: D17: Por favor, digite um numero: 

tool: D33:  %d

tool: D9: Encontra-se no vetor.

tool: D15: Nao se encontra no vetor.

assistant: ```c
main() {
  int i, verifica, resposta = 0, vet[10] = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};
  printf("Por favor, digite um numero: ");
  scanf(" %d", &verifica);
  for (i = 0; i <= 9; i++) {
    if (vet[i] == verifica)
      resposta++;
  }
  if (resposta >= 1) {
    printf("Encontra-se no vetor.");
  } else {
    printf("Nao se encontra no vetor.");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movd   %edx,%xmm2
  pshufd $0x0,%xmm2,%xmm1
  movdqa %xmm1,%xmm0
  pcmpeqd D18(%rip),%xmm1
  pcmpeqd D13(%rip),%xmm0
  pand   D61(%rip),%xmm0
  psubd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  cmp    $0x5a,%edx
  je     L35
  cmp    $0x64,%edx
  jne    L49
L35:
  lea    D48(%rip),%rdi
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L49:
  movd   %xmm0,%eax
  test   %eax,%eax
  jne    L35
  lea    D59(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: byte[16]
name: parse_data
arguments: data_tag: D13
datatype: byte[16]
name: parse_data
arguments: data_tag: D61
datatype: byte[16]
name: parse_data
arguments: data_tag: D48
datatype: string
name: parse_data
arguments: data_tag: D59
datatype: string

tool: D5: Por favor, digite um numero: 

tool: D32:  %d

tool: {"D18": [0x0a,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x28,0x00,0x00,0x00]}

tool: {"D13": [0x32,0x00,0x00,0x00,0x3c,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x50,0x00,0x00,0x00]}

tool: {"D61": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D48: Encontra-se no vetor.

tool: D59: Nao se encontra no vetor.

assistant: ```c
main() {
  int i, verifica, resposta = 0, vet[10] = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};
  printf("Por favor, digite um numero: ");
  scanf(" %d", &verifica);
  for (i = 0; i <= 9; i++) {
    if (vet[i] == verifica)
      resposta++;
  }
  if (resposta >= 1) {
    printf("Encontra-se no vetor.");
  } else {
    printf("Nao se encontra no vetor.");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D40(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm0
  addss  -0x14(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type_infered: string
name: parse_data
arguments: data_tag: D37
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: byte[8]
name: parse_data
arguments: data_tag: D40
type_infered: byte[8]
name: parse_data
arguments: data_tag: D30
type_infered: string

tool: D11: Enter the basic salary: 

tool: D37: %f

tool: {"D4": [0x9a,0x99,0x99,0x99,0x99,0x99,0xd9,0x3f]}

tool: {"D40": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

tool: D30: The gross salary is %f


assistant: ```c
int main() {
  float basic_sal, gross_sal, da, hra;
  printf("Enter the basic salary: ");
  scanf("%f", &basic_sal);
  da = basic_sal * .40;
  hra = basic_sal * .20;
  gross_sal = basic_sal + da + hra;
  printf("The gross salary is %f\n", gross_sal);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  movapd %xmm1,%xmm0
  mulsd  D18(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  addss  %xmm2,%xmm0
  mulsd  D42(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D42
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D24
type_guessed: string

tool: D7: Enter the basic salary: 

tool: D34: %f

tool: {"D18": [0x9a,0x99,0x99,0x99,0x99,0x99,0xd9,0x3f]}

tool: {"D42": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

tool: D24: The gross salary is %f


assistant: ```c
int main() {
  float basic_sal, gross_sal, da, hra;
  printf("Enter the basic salary: ");
  scanf("%f", &basic_sal);
  da = basic_sal * .40;
  hra = basic_sal * .20;
  gross_sal = basic_sal + da + hra;
  printf("The gross salary is %f\n", gross_sal);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D34(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movsd  D9(%rip),%xmm0
  lea    D49(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  D3(%rip),%xmm1
  cvtsd2ss %xmm0,%xmm0
  addss  %xmm2,%xmm0
  cvtsd2ss %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D34
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_tag: D49
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D3
type_infered: byte[8]

tool: D28: Enter the basic salary: 

tool: D34: %f

tool: {"D9": [0x9a,0x99,0x99,0x99,0x99,0x99,0xd9,0x3f]}

tool: D49: The gross salary is %f


tool: {"D3": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

assistant: ```c
int main() {
  float basic_sal, gross_sal, da, hra;
  printf("Enter the basic salary: ");
  scanf("%f", &basic_sal);
  da = basic_sal * .40;
  hra = basic_sal * .20;
  gross_sal = basic_sal + da + hra;
  printf("The gross salary is %f\n", gross_sal);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movsd  D11(%rip),%xmm0
  lea    D1(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm2,%xmm1
  mulsd  %xmm1,%xmm0
  mulsd  D39(%rip),%xmm1
  cvtsd2ss %xmm0,%xmm0
  addss  %xmm2,%xmm0
  cvtsd2ss %xmm1,%xmm1
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D38
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: byte[8]

tool: D38: Enter the basic salary: 

tool: D2: %f

tool: {"D11": [0x9a,0x99,0x99,0x99,0x99,0x99,0xd9,0x3f]}

tool: D1: The gross salary is %f


tool: {"D39": [0x9a,0x99,0x99,0x99,0x99,0x99,0xc9,0x3f]}

assistant: ```c
int main() {
  float basic_sal, gross_sal, da, hra;
  printf("Enter the basic salary: ");
  scanf("%f", &basic_sal);
  da = basic_sal * .40;
  hra = basic_sal * .20;
  gross_sal = basic_sal + da + hra;
  printf("The gross salary is %f\n", gross_sal);
  return 0;
}
```