ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  lea    D2(%rip),%rdi
  sub    $0x8,%rsp
  mov    %rdi,(%rsi)
  call   <execve@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string

tool: D2: /usr/lib/cgi-bin/cricket/mini-graph-real.cgi

assistant: ```c
int main(int argn, char **argv, char **envp) {
  argv[0] = "/usr/lib/cgi-bin/cricket/mini-graph-real.cgi";
  execve("/usr/lib/cgi-bin/cricket/mini-graph-real.cgi", argv, envp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  mov    %rdi,(%rsi)
  call   <execve@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: /usr/lib/cgi-bin/cricket/mini-graph-real.cgi

assistant: ```c
int main(int argn, char **argv, char **envp) {
  argv[0] = "/usr/lib/cgi-bin/cricket/mini-graph-real.cgi";
  execve("/usr/lib/cgi-bin/cricket/mini-graph-real.cgi", argv, envp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<now>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_attempt_open_bracket@plt>
  test   %eax,%eax
  je     L44
L33:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_has_arg@plt>
  test   %rax,%rax
  je     L8
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_pop_string@plt>
  test   %eax,%eax
  jne    L33
L8:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_attempt_close_bracket@plt>
  test   %eax,%eax
  jne    L33
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <time@plt>
  mov    %r12,%rdi
  call   <localtime@plt>
  mov    %rax,%rcx
  mov    0x8(%rsp),%rdx
  test   %rdx,%rdx
  je     L68
  lea    0x10(%rsp),%r12
  mov    $0x50,%esi
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%esi
  mov    %r12,%rdi
  call   <mb_memdup@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_push_string@plt>
  jmp    L33
L68:
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,%r12
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%esi
  mov    %r12,%rdi
  call   <mb_memdup@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <mb_push_string@plt>
  jmp    L33
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int now(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  time_t ct;
  struct tm *timeinfo = 0;
  char buf[80];
  char *arg = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  if (mb_has_arg(s, l)) {
    do {
      int __hr = (mb_pop_string(s, l, &arg));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  }
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  time(&ct);
  timeinfo = localtime(&ct);
  if (arg) {
    strftime(buf, sizeof(buf), arg, timeinfo);
    do {
      int __hr = (mb_push_string(s, l, mb_memdup(buf, (unsigned)(strlen(buf) + 1))));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  } else {
    arg = asctime(timeinfo);
    do {
      int __hr = (mb_push_string(s, l, mb_memdup(arg, (unsigned)(strlen(arg) + 1))));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<now>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  movq   $0x0,0x8(%rsp)
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_open_bracket@plt>
  test   %eax,%eax
  je     L57
L73:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x70,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L57:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_has_arg@plt>
  test   %rax,%rax
  je     L33
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_pop_string@plt>
  test   %eax,%eax
  jne    L73
L33:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_close_bracket@plt>
  test   %eax,%eax
  jne    L73
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <time@plt>
  mov    %r13,%rdi
  call   <localtime@plt>
  mov    0x8(%rsp),%rdx
  mov    %rax,%rcx
  test   %rdx,%rdx
  je     L32
  lea    0x10(%rsp),%r13
  mov    $0x50,%esi
  mov    %r13,%rdi
  call   <strftime@plt>
L51:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rax),%esi
  call   <mb_memdup@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <mb_push_string@plt>
  jmp    L73
  nopl   0x0(%rax)
L32:
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  jmp    L51
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int now(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  time_t ct;
  struct tm *timeinfo = 0;
  char buf[80];
  char *arg = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  if (mb_has_arg(s, l)) {
    do {
      int __hr = (mb_pop_string(s, l, &arg));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  }
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  time(&ct);
  timeinfo = localtime(&ct);
  if (arg) {
    strftime(buf, sizeof(buf), arg, timeinfo);
    do {
      int __hr = (mb_push_string(s, l, mb_memdup(buf, (unsigned)(strlen(buf) + 1))));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  } else {
    arg = asctime(timeinfo);
    do {
      int __hr = (mb_push_string(s, l, mb_memdup(arg, (unsigned)(strlen(arg) + 1))));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<now>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  movq   $0x0,0x8(%rsp)
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_open_bracket@plt>
  test   %eax,%eax
  je     L37
L50:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x70,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L37:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_has_arg@plt>
  test   %rax,%rax
  je     L36
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_pop_string@plt>
  test   %eax,%eax
  jne    L50
L36:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <mb_attempt_close_bracket@plt>
  test   %eax,%eax
  jne    L50
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <time@plt>
  mov    %r13,%rdi
  call   <localtime@plt>
  mov    0x8(%rsp),%rdx
  mov    %rax,%rcx
  test   %rdx,%rdx
  je     L58
  lea    0x10(%rsp),%r13
  mov    $0x50,%esi
  mov    %r13,%rdi
  call   <strftime@plt>
L43:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    0x1(%rax),%esi
  call   <mb_memdup@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <mb_push_string@plt>
  jmp    L50
  nopl   0x0(%rax)
L58:
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %rax,0x8(%rsp)
  mov    %rax,%r13
  jmp    L43
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int now(struct mb_interpreter_t *s, void **l) {
  int result = 0;
  time_t ct;
  struct tm *timeinfo = 0;
  char buf[80];
  char *arg = 0;
  do {
    ((void)(s && l));
    assert(s && l);
  } while (0);
  do {
    int __hr = (mb_attempt_open_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  if (mb_has_arg(s, l)) {
    do {
      int __hr = (mb_pop_string(s, l, &arg));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  }
  do {
    int __hr = (mb_attempt_close_bracket(s, l));
    if ((__hr) != 0) {
      return (__hr);
    }
  } while (0);
  time(&ct);
  timeinfo = localtime(&ct);
  if (arg) {
    strftime(buf, sizeof(buf), arg, timeinfo);
    do {
      int __hr = (mb_push_string(s, l, mb_memdup(buf, (unsigned)(strlen(buf) + 1))));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  } else {
    arg = asctime(timeinfo);
    do {
      int __hr = (mb_push_string(s, l, mb_memdup(arg, (unsigned)(strlen(arg) + 1))));
      if ((__hr) != 0) {
        return (__hr);
      }
    } while (0);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b_disk_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    %rsi,%rdi
  call   *0x100070
  mov    %rcx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long b_disk_read(unsigned long start, unsigned long num, unsigned long disknum, void *dest) {
  unsigned long tlong;
  asm volatile("call *0x00100070" : "=c"(tlong) : "a"(start), "c"(num), "d"(disknum), "D"(dest));
  return tlong;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<b_disk_read>:
  endbr64
  mov    %rdi,%rax
  mov    %rcx,%rdi
  mov    %rsi,%rcx
  call   *0x100070
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_disk_read(unsigned long start, unsigned long num, unsigned long disknum, void *dest) {
  unsigned long tlong;
  asm volatile("call *0x00100070" : "=c"(tlong) : "a"(start), "c"(num), "d"(disknum), "D"(dest));
  return tlong;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<b_disk_read>:
  endbr64
  mov    %rdi,%rax
  mov    %rcx,%rdi
  mov    %rsi,%rcx
  call   *0x100070
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_disk_read(unsigned long start, unsigned long num, unsigned long disknum, void *dest) {
  unsigned long tlong;
  asm volatile("call *0x00100070" : "=c"(tlong) : "a"(start), "c"(num), "d"(disknum), "D"(dest));
  return tlong;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b_disk_read>:
  endbr64
  mov    %rdi,%rax
  mov    %rcx,%rdi
  mov    %rsi,%rcx
  call   *0x100070
  mov    %rcx,%rax
  ret
```

assistant: ```c
unsigned long b_disk_read(unsigned long start, unsigned long num, unsigned long disknum, void *dest) {
  unsigned long tlong;
  asm volatile("call *0x00100070" : "=c"(tlong) : "a"(start), "c"(num), "d"(disknum), "D"(dest));
  return tlong;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compare_ints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_ints(const void *addr1, const void *addr2) {
  int num1 = *(int *)addr1;
  int num2 = *(int *)addr2;
  return num1 - num2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compare_ints>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int compare_ints(const void *addr1, const void *addr2) {
  int num1 = *(int *)addr1;
  int num2 = *(int *)addr2;
  return num1 - num2;
}
```
user: What is the c source code of the assembly code below:

```asm
<compare_ints>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int compare_ints(const void *addr1, const void *addr2) {
  int num1 = *(int *)addr1;
  int num2 = *(int *)addr2;
  return num1 - num2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compare_ints>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int compare_ints(const void *addr1, const void *addr2) {
  int num1 = *(int *)addr1;
  int num2 = *(int *)addr2;
  return num1 - num2;
}
```
user: What is the c source code of the assembly code below?

```asm
<stripnl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  nop
  leave
  ret
```

assistant: ```c
void stripnl(char *str) {
  if (*str != '\0') {
    size_t len = strlen(str);
    if (str[len - 1] == '\n') {
      str[len - 1] = '\0';
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stripnl>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L19
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L17
L11:
  pop    %rbx
  ret
L17:
  movb   $0x0,(%rax)
  jmp    L11
L19:
  ret
```

assistant: ```c
void stripnl(char *str) {
  if (*str != '\0') {
    size_t len = strlen(str);
    if (str[len - 1] == '\n') {
      str[len - 1] = '\0';
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<stripnl>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L8
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L19
  pop    %rbx
  ret
  xchg   %ax,%ax
L8:
  ret
  nopl   0x0(%rax)
L19:
  movb   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void stripnl(char *str) {
  if (*str != '\0') {
    size_t len = strlen(str);
    if (str[len - 1] == '\n') {
      str[len - 1] = '\0';
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<stripnl>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rbx,%rax,1),%rax
  cmpb   $0xa,(%rax)
  je     L16
  pop    %rbx
  ret
  xchg   %ax,%ax
L5:
  ret
  nopl   0x0(%rax)
L16:
  movb   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void stripnl(char *str) {
  if (*str != '\0') {
    size_t len = strlen(str);
    if (str[len - 1] == '\n') {
      str[len - 1] = '\0';
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<populateNeighborList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rdx
  mov    %rdx,%rcx
  shl    $0x7,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rcx
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %edx,(%rcx,%rax,4)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  cmpl   $0x1f,-0x8(%rbp)
  jle    L4
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int populateNeighborList(int currDist[32], int currList[32], const int i, int NL[32][32]) {
  int idx, validPairs, distanceIter, neighborIter;
  idx = 0;
  validPairs = 0;
  for (neighborIter = 0; neighborIter < 32; neighborIter++) {
    NL[i][neighborIter] = currList[neighborIter];
    validPairs++;
  }
  return validPairs;
}
```
user: Translate the below assembly code into C programming language:

```asm
<populateNeighborList>:
  endbr64
  movslq %edx,%rdx
  shl    $0x7,%rdx
  add    %rdx,%rcx
  mov    $0x0,%eax
L1:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x80,%rax
  jne    L1
  mov    $0x20,%eax
  ret
```

assistant: ```c
int populateNeighborList(int currDist[32], int currList[32], const int i, int NL[32][32]) {
  int idx, validPairs, distanceIter, neighborIter;
  idx = 0;
  validPairs = 0;
  for (neighborIter = 0; neighborIter < 32; neighborIter++) {
    NL[i][neighborIter] = currList[neighborIter];
    validPairs++;
  }
  return validPairs;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<populateNeighborList>:
  endbr64
  movslq %edx,%rdx
  xor    %eax,%eax
  shl    $0x7,%rdx
  add    %rdx,%rcx
L0:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x80,%rax
  jne    L0
  mov    $0x20,%eax
  ret
```

assistant: ```c
int populateNeighborList(int currDist[32], int currList[32], const int i, int NL[32][32]) {
  int idx, validPairs, distanceIter, neighborIter;
  idx = 0;
  validPairs = 0;
  for (neighborIter = 0; neighborIter < 32; neighborIter++) {
    NL[i][neighborIter] = currList[neighborIter];
    validPairs++;
  }
  return validPairs;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<populateNeighborList>:
  endbr64
  movslq %edx,%rdx
  shl    $0x7,%rdx
  add    %rdx,%rcx
  lea    0x4(%rsi),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L12
  movdqu (%rsi),%xmm0
  mov    $0x20,%eax
  movups %xmm0,(%rcx)
  movdqu 0x10(%rsi),%xmm1
  movups %xmm1,0x10(%rcx)
  movdqu 0x20(%rsi),%xmm2
  movups %xmm2,0x20(%rcx)
  movdqu 0x30(%rsi),%xmm3
  movups %xmm3,0x30(%rcx)
  movdqu 0x40(%rsi),%xmm4
  movups %xmm4,0x40(%rcx)
  movdqu 0x50(%rsi),%xmm5
  movups %xmm5,0x50(%rcx)
  movdqu 0x60(%rsi),%xmm6
  movups %xmm6,0x60(%rcx)
  movdqu 0x70(%rsi),%xmm7
  movups %xmm7,0x70(%rcx)
  ret
L12:
  xor    %eax,%eax
  nopl   0x0(%rax)
L0:
  mov    (%rsi,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    $0x80,%rax
  jne    L0
  mov    $0x20,%eax
  ret
```

assistant: ```c
int populateNeighborList(int currDist[32], int currList[32], const int i, int NL[32][32]) {
  int idx, validPairs, distanceIter, neighborIter;
  idx = 0;
  validPairs = 0;
  for (neighborIter = 0; neighborIter < 32; neighborIter++) {
    NL[i][neighborIter] = currList[neighborIter];
    validPairs++;
  }
  return validPairs;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pop_paren>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L9
  mov    $0x20,%eax
  jmp    L7
L9:
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    D43(%rip),%rax
  mov    %edx,(%rax)
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  mov    D45(%rip),%rdx
  cltq
  movzbl (%rdx,%rax,1),%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
char pop_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[--paren_stack_top];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pop_paren>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    $0x20,%edx
  test   %eax,%eax
  je     L7
  sub    $0x1,%eax
  mov    D9(%rip),%rdx
  mov    %eax,(%rdx)
  cltq
  mov    D10(%rip),%rdx
  movzbl (%rdx,%rax,1),%edx
L7:
  mov    %edx,%eax
  ret
```

assistant: ```c
char pop_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[--paren_stack_top];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop_paren>:
  endbr64
  mov    D11(%rip),%rdx
  mov    $0x20,%r8d
  mov    (%rdx),%eax
  test   %eax,%eax
  je     L3
  sub    $0x1,%eax
  mov    %eax,(%rdx)
  mov    D16(%rip),%rdx
  cltq
  movzbl (%rdx,%rax,1),%r8d
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char pop_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[--paren_stack_top];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pop_paren>:
  endbr64
  mov    D17(%rip),%rdx
  mov    $0x20,%r8d
  mov    (%rdx),%eax
  test   %eax,%eax
  je     L4
  sub    $0x1,%eax
  mov    %eax,(%rdx)
  mov    D3(%rip),%rdx
  cltq
  movzbl (%rdx,%rax,1),%r8d
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
char pop_paren() {
  extern int paren_stack_top;
  extern char paren_stack[];
  if (paren_stack_top == 0) {
    return ' ';
  } else {
    return paren_stack[--paren_stack_top];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stopB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stopB() {
  GPIOPinWrite(0x40007000, 0x00000020, 0x00);
  GPIOPinWrite(0x40007000, 0x00000010, 0xff);
  GPIOPinWrite(0x40007000, 0x00000020, 0xff);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stopB>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0x0,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stopB() {
  GPIOPinWrite(0x40007000, 0x00000020, 0x00);
  GPIOPinWrite(0x40007000, 0x00000010, 0xff);
  GPIOPinWrite(0x40007000, 0x00000020, 0xff);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
}
```
user: What is the c source code of the assembly code below:

```asm
<stopB>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  xor    %edx,%edx
  mov    $0x10,%esi
  add    $0x8,%rsp
  mov    $0x40007000,%edi
  jmp    1050 <GPIOPinWrite@plt>
```

assistant: ```c
void stopB() {
  GPIOPinWrite(0x40007000, 0x00000020, 0x00);
  GPIOPinWrite(0x40007000, 0x00000010, 0xff);
  GPIOPinWrite(0x40007000, 0x00000020, 0xff);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stopB>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x20,%esi
  mov    $0x40007000,%edi
  call   <GPIOPinWrite@plt>
  xor    %edx,%edx
  mov    $0x10,%esi
  add    $0x8,%rsp
  mov    $0x40007000,%edi
  jmp    1050 <GPIOPinWrite@plt>
```

assistant: ```c
void stopB() {
  GPIOPinWrite(0x40007000, 0x00000020, 0x00);
  GPIOPinWrite(0x40007000, 0x00000010, 0xff);
  GPIOPinWrite(0x40007000, 0x00000020, 0xff);
  GPIOPinWrite(0x40007000, 0x00000010, 0x00);
}
```