ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<my_randomize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  shr    $0x2,%rax
  and    $0x3,%r12d
  test   %eax,%eax
  jle    L10
  mov    %eax,%r14d
  mov    %rdi,%rbx
  lea    -0x1(%rax),%eax
  lea    0x4(%rdi,%rax,4),%rbp
L53:
  mov    $0x0,%eax
  call   <my_rand@plt>
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L53
L56:
  test   %r12d,%r12d
  jg     L17
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %r13,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  mov    $0x0,%r14d
  jmp    L56
L17:
  mov    $0x0,%eax
  call   <my_rand@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  movslq %r14d,%r14
  lea    0x0(%r13,%r14,4),%rdi
  mov    %r12d,%edx
  call   <memcpy@plt>
  jmp    L47
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *my_randomize(char *buf, int len) {
  unsigned int x, *p;
  int i, total = len / sizeof(int);
  int left = len % sizeof(int);
  for (i = 0; i < total; i++) {
    p = (unsigned int *)(buf + i * sizeof(int));
    *p = my_rand();
  }
  if (left > 0) {
    x = my_rand();
    memcpy(buf + i * sizeof(int), &x, left);
  }
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_randomize>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  and    $0x3,%r12d
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  shr    $0x2,%rax
  test   %eax,%eax
  jle    L27
  movslq %eax,%r14
  sub    $0x1,%eax
  mov    %rdi,%rbx
  lea    0x4(%rdi,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <my_rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L4
L18:
  test   %r12d,%r12d
  jne    L39
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  xor    %eax,%eax
  call   <my_rand@plt>
  lea    0x4(%rsp),%rsi
  lea    0x0(%r13,%r14,4),%rdi
  mov    %r12d,%edx
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  jmp    L53
  nop
L27:
  xor    %r14d,%r14d
  jmp    L18
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *my_randomize(char *buf, int len) {
  unsigned int x, *p;
  int i, total = len / sizeof(int);
  int left = len % sizeof(int);
  for (i = 0; i < total; i++) {
    p = (unsigned int *)(buf + i * sizeof(int));
    *p = my_rand();
  }
  if (left > 0) {
    x = my_rand();
    memcpy(buf + i * sizeof(int), &x, left);
  }
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<my_randomize>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  and    $0x3,%r12d
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %esi,%rax
  shr    $0x2,%rax
  test   %eax,%eax
  jle    L24
  movslq %eax,%r14
  sub    $0x1,%eax
  mov    %rdi,%rbx
  lea    0x4(%rdi,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L51:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <my_rand@plt>
  mov    %eax,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L51
L52:
  test   %r12d,%r12d
  jne    L39
L34:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  xor    %eax,%eax
  call   <my_rand@plt>
  lea    0x4(%rsp),%rsi
  lea    0x0(%r13,%r14,4),%rdi
  mov    %r12d,%edx
  mov    %eax,0x4(%rsp)
  call   <memcpy@plt>
  jmp    L34
  nop
L24:
  xor    %r14d,%r14d
  jmp    L52
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *my_randomize(char *buf, int len) {
  unsigned int x, *p;
  int i, total = len / sizeof(int);
  int left = len % sizeof(int);
  for (i = 0; i < total; i++) {
    p = (unsigned int *)(buf + i * sizeof(int));
    *p = my_rand();
  }
  if (left > 0) {
    x = my_rand();
    memcpy(buf + i * sizeof(int), &x, left);
  }
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<adts_set_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  and    $0xfffffffc,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  sar    $0xb,%eax
  and    $0x3,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    -0xc(%rbp),%edx
  sar    $0x3,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  and    $0x1f,%dl
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  or     %ecx,%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void adts_set_length(uint8_t *p_adts, uint16_t i_length) {
  p_adts[3] &= ~0x03;
  p_adts[3] |= (i_length >> 11) & 0x03;
  p_adts[4] = i_length >> 3;
  p_adts[5] &= ~0xe0;
  p_adts[5] |= (i_length << 5) & 0xe0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<adts_set_length>:
  endbr64
  mov    0xc(%rdi),%eax
  and    $0xfffffffc,%eax
  mov    %esi,%edx
  sar    $0xb,%edx
  and    $0x3,%edx
  or     %edx,%eax
  mov    %eax,0xc(%rdi)
  mov    %esi,%eax
  sar    $0x3,%eax
  mov    %eax,0x10(%rdi)
  mov    0x14(%rdi),%eax
  and    $0x1f,%al
  shl    $0x5,%esi
  movzbl %sil,%esi
  or     %esi,%eax
  mov    %eax,0x14(%rdi)
  ret
```

assistant: ```c
void adts_set_length(uint8_t *p_adts, uint16_t i_length) {
  p_adts[3] &= ~0x03;
  p_adts[3] |= (i_length >> 11) & 0x03;
  p_adts[4] = i_length >> 3;
  p_adts[5] &= ~0xe0;
  p_adts[5] |= (i_length << 5) & 0xe0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<adts_set_length>:
  endbr64
  mov    0xc(%rdi),%eax
  mov    %esi,%edx
  sar    $0xb,%edx
  and    $0xfffffffc,%eax
  and    $0x3,%edx
  or     %edx,%eax
  mov    %eax,0xc(%rdi)
  mov    %esi,%eax
  shl    $0x5,%esi
  sar    $0x3,%eax
  movzbl %sil,%esi
  mov    %eax,0x10(%rdi)
  mov    0x14(%rdi),%eax
  and    $0x1f,%al
  or     %esi,%eax
  mov    %eax,0x14(%rdi)
  ret
```

assistant: ```c
void adts_set_length(uint8_t *p_adts, uint16_t i_length) {
  p_adts[3] &= ~0x03;
  p_adts[3] |= (i_length >> 11) & 0x03;
  p_adts[4] = i_length >> 3;
  p_adts[5] &= ~0xe0;
  p_adts[5] |= (i_length << 5) & 0xe0;
}
```
user: What is the c source code of the assembly code below?

```asm
<adts_set_length>:
  endbr64
  mov    0xc(%rdi),%eax
  mov    %esi,%edx
  sar    $0xb,%edx
  and    $0x3,%edx
  and    $0xfffffffc,%eax
  or     %edx,%eax
  mov    %esi,%edx
  shl    $0x5,%esi
  movd   %eax,%xmm0
  mov    0x14(%rdi),%eax
  sar    $0x3,%edx
  movzbl %sil,%esi
  movd   %edx,%xmm1
  and    $0x1f,%al
  punpckldq %xmm1,%xmm0
  or     %esi,%eax
  movq   %xmm0,0xc(%rdi)
  mov    %eax,0x14(%rdi)
  ret
```

assistant: ```c
void adts_set_length(uint8_t *p_adts, uint16_t i_length) {
  p_adts[3] &= ~0x03;
  p_adts[3] |= (i_length >> 11) & 0x03;
  p_adts[4] = i_length >> 3;
  p_adts[5] &= ~0xe0;
  p_adts[5] |= (i_length << 5) & 0xe0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <tipo2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  tipo2();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tipo2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  tipo2();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tipo2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  tipo2();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tipo2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  tipo2();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sigemptyset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: sigemptyset: not implemented

assistant: ```c
int sigemptyset(sigset_t *set) {
  (void)set;
  puts("sigemptyset: not implemented");
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sigemptyset>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: sigemptyset: not implemented

assistant: ```c
int sigemptyset(sigset_t *set) {
  (void)set;
  puts("sigemptyset: not implemented");
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sigemptyset>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: sigemptyset: not implemented

assistant: ```c
int sigemptyset(sigset_t *set) {
  (void)set;
  puts("sigemptyset: not implemented");
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sigemptyset>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: sigemptyset: not implemented

assistant: ```c
int sigemptyset(sigset_t *set) {
  (void)set;
  puts("sigemptyset: not implemented");
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L16
L19:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f1(const char *x, char *y) {
  while (*x != 0) {
    *y++ = *x++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<f1>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L7
  mov    $0x0,%eax
L19:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L19
L7:
  ret
```

assistant: ```c
void f1(const char *x, char *y) {
  while (*x != 0) {
    *y++ = *x++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<f1>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L18
  xor    %eax,%eax
  nopl   (%rax)
L8:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L8
L18:
  ret
```

assistant: ```c
void f1(const char *x, char *y) {
  while (*x != 0) {
    *y++ = *x++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f1>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L0
  xor    %eax,%eax
  nopl   (%rax)
L17:
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L17
L0:
  ret
```

assistant: ```c
void f1(const char *x, char *y) {
  while (*x != 0) {
    *y++ = *x++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x124(%rbp)
  jle    L2
  mov    -0x130(%rbp),%rax
  mov    %rax,-0x118(%rbp)
  jmp    L32
L39:
  mov    -0x118(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <factor@plt>
  addq   $0x8,-0x118(%rbp)
L32:
  mov    -0x118(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L39
  jmp    L24
L2:
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <gets_s@plt>
  test   %rax,%rax
  je     L55
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <factor@plt>
  jmp    L2
L55:
  nop
L24:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1) {
    char **ss;
    for (ss = argv; *ss; ss++)
      factor(*ss);
  } else
    for (;;) {
      char s[256];
      if (NULL == gets_s(s, 256))
        break;
      factor(s);
    }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  cmp    $0x1,%edi
  jle    L21
  mov    %rsi,%rbx
  mov    (%rsi),%rdi
  test   %rdi,%rdi
  je     L37
L18:
  call   <factor@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L18
L37:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  ret
L21:
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <gets_s@plt>
  test   %rax,%rax
  je     L37
  mov    %rbx,%rdi
  call   <factor@plt>
  jmp    L21
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1) {
    char **ss;
    for (ss = argv; *ss; ss++)
      factor(*ss);
  } else
    for (;;) {
      char s[256];
      if (NULL == gets_s(s, 256))
        break;
      factor(s);
    }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  cmp    $0x1,%edi
  jle    L5
  mov    (%rsi),%rdi
  mov    %rsi,%rbx
  test   %rdi,%rdi
  je     L2
  nopw   0x0(%rax,%rax,1)
L7:
  call   <factor@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L7
L2:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rbx,%rdi
  call   <factor@plt>
L5:
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <gets_s@plt>
  test   %rax,%rax
  jne    L23
  jmp    L2
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1) {
    char **ss;
    for (ss = argv; *ss; ss++)
      factor(*ss);
  } else
    for (;;) {
      char s[256];
      if (NULL == gets_s(s, 256))
        break;
      factor(s);
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  cmp    $0x1,%edi
  jle    L2
  mov    (%rsi),%rdi
  mov    %rsi,%rbx
  test   %rdi,%rdi
  je     L43
  nopw   0x0(%rax,%rax,1)
L8:
  call   <factor@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L8
L43:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %rbx,%rdi
  call   <factor@plt>
L2:
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <gets_s@plt>
  test   %rax,%rax
  jne    L39
  jmp    L43
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1) {
    char **ss;
    for (ss = argv; *ss; ss++)
      factor(*ss);
  } else
    for (;;) {
      char s[256];
      if (NULL == gets_s(s, 256))
        break;
      factor(s);
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xf,-0x4(%rbp)
  ja     L162
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x30,%eax
  jmp    L71
  mov    $0x31,%eax
  jmp    L71
  mov    $0x32,%eax
  jmp    L71
  mov    $0x33,%eax
  jmp    L71
  mov    $0x34,%eax
  jmp    L71
  mov    $0x35,%eax
  jmp    L71
  mov    $0x36,%eax
  jmp    L71
  mov    $0x37,%eax
  jmp    L71
  mov    $0x38,%eax
  jmp    L71
  mov    $0x39,%eax
  jmp    L71
  mov    $0x41,%eax
  jmp    L71
  mov    $0x42,%eax
  jmp    L71
  mov    $0x43,%eax
  jmp    L71
  mov    $0x44,%eax
  jmp    L71
  mov    $0x45,%eax
  jmp    L71
  mov    $0x46,%eax
  jmp    L71
L162:
  mov    $0x2d,%eax
L71:
  pop    %rbp
  ret
```

assistant: ```c
char get_char(int get_from) {
  switch (get_from) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_char>:
  endbr64
  cmp    $0xf,%edi
  ja     L2
  mov    %edi,%edi
  lea    D6(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x31,%eax
  ret
  mov    $0x32,%eax
  ret
  mov    $0x33,%eax
  ret
  mov    $0x34,%eax
  ret
  mov    $0x35,%eax
  ret
  mov    $0x36,%eax
  ret
  mov    $0x37,%eax
  ret
  mov    $0x38,%eax
  ret
  mov    $0x39,%eax
  ret
  mov    $0x41,%eax
  ret
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
L2:
  mov    $0x2d,%eax
  ret
  mov    $0x30,%eax
  ret
```

assistant: ```c
char get_char(int get_from) {
  switch (get_from) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_char>:
  endbr64
  mov    $0x2d,%eax
  cmp    $0xf,%edi
  ja     L1
  mov    %edi,%edi
  lea    D0(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L1:
  ret
```

assistant: ```c
char get_char(int get_from) {
  switch (get_from) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_char>:
  endbr64
  mov    $0x2d,%eax
  cmp    $0xf,%edi
  ja     L7
  mov    %edi,%edi
  lea    D4(%rip),%rax
  movzbl (%rax,%rdi,1),%eax
L7:
  ret
```

assistant: ```c
char get_char(int get_from) {
  switch (get_from) {
  case 0:
    return '0';
    break;
  case 1:
    return '1';
    break;
  case 2:
    return '2';
    break;
  case 3:
    return '3';
    break;
  case 4:
    return '4';
    break;
  case 5:
    return '5';
    break;
  case 6:
    return '6';
    break;
  case 7:
    return '7';
    break;
  case 8:
    return '8';
    break;
  case 9:
    return '9';
    break;
  case 10:
    return 'A';
    break;
  case 11:
    return 'B';
    break;
  case 12:
    return 'C';
    break;
  case 13:
    return 'D';
    break;
  case 14:
    return 'E';
    break;
  case 15:
    return 'F';
    break;
  default:
    return '-';
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L57
  cmpl   $0x0,-0x14(%rbp)
  jle    L57
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L21
L17:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L25
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L17
  jmp    L40
L57:
  nop
L40:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: %d 

assistant: ```c
void print_prime(int n1, int n2) {
  int i;
  if ((n2 >= n1) && (n1 > 0)) {
    for (i = n1; i <= n2; i++) {
      if (check_prime(i))
        printf("%d ", i);
    }
  } else
    return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_prime>:
  endbr64
  cmp    %edi,%esi
  jl     L13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   %edi,%edi
  jle    L18
  lea    D5(%rip),%r12
  jmp    L34
L56:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L18
L34:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L56
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L56
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: %d 

assistant: ```c
void print_prime(int n1, int n2) {
  int i;
  if ((n2 >= n1) && (n1 > 0)) {
    for (i = n1; i <= n2; i++) {
      if (check_prime(i))
        printf("%d ", i);
    }
  } else
    return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_prime>:
  endbr64
  cmp    %edi,%esi
  jl     L54
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L20
  mov    %esi,%ebp
  lea    D2(%rip),%r12
  jmp    L30
  nopl   (%rax)
L36:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jl     L20
L30:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %rax,%rax
  je     L36
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L30
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L54:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
void print_prime(int n1, int n2) {
  int i;
  if ((n2 >= n1) && (n1 > 0)) {
    for (i = n1; i <= n2; i++) {
      if (check_prime(i))
        printf("%d ", i);
    }
  } else
    return;
}
```