ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<checkForOption>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L39
  mov    %rdi,%r12
  mov    %rdx,%r14
  movslq %esi,%rbp
  mov    $0x1,%ebx
  jmp    L19
  nopl   0x0(%rax)
L12:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L39
L19:
  mov    (%r14,%rbx,8),%rsi
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <strmatch@plt>
  test   %rax,%rax
  je     L12
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L39:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int checkForOption(char *key, int argc, char *argv[]) {
  int ii = 1;
  while (ii < argc) {
    if (strmatch(key, argv[ii]))
      return (ii);
    ++ii;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xfb8(%rbp)
  mov    $0x3e8,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3e8,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xfac(%rbp)
  movl   $0x2,-0xfc0(%rbp)
  jmp    L65
L79:
  mov    -0xfc0(%rbp),%eax
  cltq
  movl   $0x1,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfc0(%rbp)
L65:
  cmpl   $0x3e8,-0xfc0(%rbp)
  jle    L79
  movl   $0x2,-0xfc0(%rbp)
  jmp    L76
L60:
  movl   $0x2,-0xfbc(%rbp)
  jmp    L14
L40:
  mov    -0xfc0(%rbp),%eax
  imul   -0xfbc(%rbp),%eax
  cltq
  movl   $0x0,-0xfb0(%rbp,%rax,4)
  addl   $0x1,-0xfbc(%rbp)
L14:
  mov    $0x3e8,%eax
  cltd
  idivl  -0xfc0(%rbp)
  cmp    %eax,-0xfbc(%rbp)
  jle    L40
  addl   $0x1,-0xfc0(%rbp)
L76:
  cmpl   $0x1f4,-0xfc0(%rbp)
  jle    L60
  movl   $0x1,-0xfc0(%rbp)
  jmp    L10
L20:
  mov    -0xfc0(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L27
  mov    -0xfc0(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L27:
  addl   $0x1,-0xfc0(%rbp)
L10:
  cmpl   $0x3e8,-0xfc0(%rbp)
  jle    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D22
type_guessed: string

tool: D2: Program that prints all prime numbers
 below %d


tool: D6: 

Prime Numbers below %d: 

tool: D22: %4d

assistant: ```c
int main(void) {
  long int sum = 0;
  int i, j, a[1000 + 1];
  printf("Program that prints all prime numbers\n "
         "below %d\n",
         1000);
  printf("\n\nPrime Numbers below %d: ", 1000);
  for (a[1] = 0, i = 2; i <= 1000; i++)
    a[i] = 1;
  for (i = 2; i <= 1000 / 2; i++)
    for (j = 2; j <= 1000 / i; j++)
      a[i * j] = 0;
  for (i = 1; i <= 1000; i++) {
    if (a[i])
      printf("%4d", i);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    $0x3e8,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x3e8,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,0x4(%rsp)
  lea    0x8(%rsp),%rax
  lea    0xfa4(%rsp),%rdx
L3:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L3
  lea    0x10(%rsp),%r9
  mov    $0x8,%esi
  mov    $0x2,%r8d
  mov    $0x3e8,%r10d
  jmp    L68
L47:
  movl   $0x0,(%rcx)
  add    $0x1,%edx
  add    %rsi,%rcx
  cmp    %edi,%edx
  jne    L47
L96:
  add    $0x1,%r8d
  add    $0x8,%r9
  add    $0x4,%rsi
  cmp    $0x1f5,%r8d
  je     L12
L68:
  mov    %r10d,%eax
  cltd
  idiv   %r8d
  lea    0x1(%rax),%edi
  mov    %r9,%rcx
  mov    $0x2,%edx
  cmp    $0x1,%eax
  jg     L47
  jmp    L96
L12:
  mov    $0x1,%ebx
  lea    D21(%rip),%rbp
  jmp    L48
L98:
  add    $0x1,%rbx
  cmp    $0x3e9,%rbx
  je     L106
L48:
  mov    %ebx,%esi
  cmpl   $0x0,(%rsp,%rbx,4)
  je     L98
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L98
L106:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0xfb8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
data_type: string
name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D21
data_type: string

tool: D27: Program that prints all prime numbers
 below %d


tool: D12: 

Prime Numbers below %d: 

tool: D21: %4d

assistant: ```c
int main(void) {
  long int sum = 0;
  int i, j, a[1000 + 1];
  printf("Program that prints all prime numbers\n "
         "below %d\n",
         1000);
  printf("\n\nPrime Numbers below %d: ", 1000);
  for (a[1] = 0, i = 2; i <= 1000; i++)
    a[i] = 1;
  for (i = 2; i <= 1000 / 2; i++)
    for (j = 2; j <= 1000 / i; j++)
      a[i * j] = 0;
  for (i = 1; i <= 1000; i++) {
    if (a[i])
      printf("%4d", i);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3e8,%esi
  lea    D5(%rip),%rdi
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3e8,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x8(%rsp),%rax
  lea    0xfa4(%rsp),%rdx
  nopl   0x0(%rax)
L48:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L48
  lea    0x10(%rsp),%r8
  mov    $0x8,%esi
  mov    $0x2,%edi
  mov    $0x3e8,%r9d
  nopl   0x0(%rax)
L41:
  mov    %r9d,%eax
  mov    %r8,%rcx
  cltd
  idiv   %edi
  mov    $0x2,%edx
  add    $0x1,%eax
  nopl   0x0(%rax)
L46:
  add    $0x1,%edx
  movl   $0x0,(%rcx)
  add    %rsi,%rcx
  cmp    %eax,%edx
  jne    L46
  add    $0x1,%edi
  add    $0x8,%r8
  add    $0x4,%rsi
  cmp    $0x1f5,%edi
  jne    L41
  mov    $0x2,%ebx
  lea    D11(%rip),%rbp
  jmp    L17
  nopl   0x0(%rax)
L12:
  mov    (%rsp,%rbx,4),%eax
  test   %eax,%eax
  je     L34
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L34:
  add    $0x1,%rbx
L17:
  mov    %ebx,%esi
  cmp    $0x3e9,%rbx
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0xfb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: string

tool: D5: Program that prints all prime numbers
 below %d


tool: D13: 

Prime Numbers below %d: 

tool: D11: %4d

assistant: ```c
int main(void) {
  long int sum = 0;
  int i, j, a[1000 + 1];
  printf("Program that prints all prime numbers\n "
         "below %d\n",
         1000);
  printf("\n\nPrime Numbers below %d: ", 1000);
  for (a[1] = 0, i = 2; i <= 1000; i++)
    a[i] = 1;
  for (i = 2; i <= 1000 / 2; i++)
    for (j = 2; j <= 1000 / i; j++)
      a[i * j] = 0;
  for (i = 1; i <= 1000; i++) {
    if (a[i])
      printf("%4d", i);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3e8,%esi
  lea    D30(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3e8,%esi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movdqa D7(%rip),%xmm0
  lea    0x8(%rsp),%rax
  lea    0xf98(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L52:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L52
  lea    0x10(%rsp),%r8
  mov    $0x8,%esi
  mov    $0x2,%edi
  mov    D7(%rip),%rax
  movl   $0x1,0xfa0(%rsp)
  mov    $0x3e8,%r9d
  mov    %rax,0xf98(%rsp)
L9:
  mov    %r9d,%eax
  mov    %r8,%rcx
  cltd
  idiv   %edi
  mov    $0x2,%edx
  add    $0x1,%eax
  nopl   0x0(%rax)
L35:
  add    $0x1,%edx
  movl   $0x0,(%rcx)
  add    %rsi,%rcx
  cmp    %edx,%eax
  jne    L35
  add    $0x1,%edi
  add    $0x8,%r8
  add    $0x4,%rsi
  cmp    $0x1f5,%edi
  jne    L9
  mov    $0x2,%ebx
  mov    %rsp,%rbp
  lea    D11(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L42:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%esi
  test   %eax,%eax
  je     L51
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L51:
  add    $0x1,%rbx
  cmp    $0x3e9,%rbx
  jne    L42
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D30
type: string
name: extract_symbolic_data
arguments: label: D41
type: string
name: extract_symbolic_data
arguments: label: D7
type: byte[16]
name: extract_symbolic_data
arguments: label: D11
type: string

tool: D30: Program that prints all prime numbers
 below %d


tool: D41: 

Prime Numbers below %d: 

tool: {"D7": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D11: %4d

assistant: ```c
int main(void) {
  long int sum = 0;
  int i, j, a[1000 + 1];
  printf("Program that prints all prime numbers\n "
         "below %d\n",
         1000);
  printf("\n\nPrime Numbers below %d: ", 1000);
  for (a[1] = 0, i = 2; i <= 1000; i++)
    a[i] = 1;
  for (i = 2; i <= 1000 / 2; i++)
    for (j = 2; j <= 1000 / i; j++)
      a[i * j] = 0;
  for (i = 1; i <= 1000; i++) {
    if (a[i])
      printf("%4d", i);
  }
  printf("\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_REQUIRE_not_null_failed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  mov    $0x0,%edi
  call   <_get_color_lassert@plt>
  mov    %rax,%rbx
  mov    $0x3,%edi
  call   <_get_color_lassert@plt>
  mov    %rax,%rsi
  mov    -0x18(%rbp),%rdx
  mov    -0x1c(%rbp),%eax
  mov    %rbx,%r8
  mov    %rdx,%rcx
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <_failed_test_case@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: 
%sFailed to allocate outside a test case line %d :
	%s %s


assistant: ```c
void _REQUIRE_not_null_failed(char *statement, int line) {
  if (statement)
    printf("\n%sFailed to allocate outside a test case line %d :\n\t%s %s\n", _get_color_lassert(3), line, statement, _get_color_lassert(0));
  _failed_test_case(1, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_REQUIRE_not_null_failed>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <_get_color_lassert@plt>
  mov    %rax,%r12
  mov    $0x3,%edi
  call   <_get_color_lassert@plt>
  mov    %rax,%rsi
  mov    %r12,%r8
  mov    %rbx,%rcx
  mov    %ebp,%edx
  lea    D8(%rip),%rdi
  call   <printf@plt>
L3:
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <_failed_test_case@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string

tool: D8: 
%sFailed to allocate outside a test case line %d :
	%s %s


assistant: ```c
void _REQUIRE_not_null_failed(char *statement, int line) {
  if (statement)
    printf("\n%sFailed to allocate outside a test case line %d :\n\t%s %s\n", _get_color_lassert(3), line, statement, _get_color_lassert(0));
  _failed_test_case(1, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_REQUIRE_not_null_failed>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbx
  call   <_get_color_lassert@plt>
  mov    $0x3,%edi
  mov    %rax,%rbx
  call   <_get_color_lassert@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %rax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %esi,%esi
  pop    %r12
  mov    $0x1,%edi
  pop    %r13
  jmp    1090 <_failed_test_case@plt>
  nopl   0x0(%rax)
L0:
  xor    %esi,%esi
  mov    $0x1,%edi
  jmp    1090 <_failed_test_case@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 
%sFailed to allocate outside a test case line %d :
	%s %s


assistant: ```c
void _REQUIRE_not_null_failed(char *statement, int line) {
  if (statement)
    printf("\n%sFailed to allocate outside a test case line %d :\n\t%s %s\n", _get_color_lassert(3), line, statement, _get_color_lassert(0));
  _failed_test_case(1, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_REQUIRE_not_null_failed>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbx
  call   <_get_color_lassert@plt>
  mov    $0x3,%edi
  mov    %rax,%rbx
  call   <_get_color_lassert@plt>
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13d,%edx
  mov    %rax,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %esi,%esi
  pop    %r12
  mov    $0x1,%edi
  pop    %r13
  jmp    1090 <_failed_test_case@plt>
  nopl   0x0(%rax)
L2:
  xor    %esi,%esi
  mov    $0x1,%edi
  jmp    1090 <_failed_test_case@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: 
%sFailed to allocate outside a test case line %d :
	%s %s


assistant: ```c
void _REQUIRE_not_null_failed(char *statement, int line) {
  if (statement)
    printf("\n%sFailed to allocate outside a test case line %d :\n\t%s %s\n", _get_color_lassert(3), line, statement, _get_color_lassert(0));
  _failed_test_case(1, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<getFileSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %rax,-0x10(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    D37(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %rax,-0x8(%rbp)
  mov    D25(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long int getFileSize(int fp) {
  long int save_pos, size_of_file;
  save_pos = lseek(fp, 0, SEEK_CUR);
  lseek(fp, 0L, SEEK_SET);
  size_of_file = lseek(fp, 0L, SEEK_END);
  lseek(fp, save_pos, SEEK_SET);
  return (size_of_file);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getFileSize>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <lseek@plt>
  mov    %rax,%r12
  mov    D20(%rip),%r13
  mov    0x0(%r13),%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <lseek@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <lseek@plt>
  mov    %rax,%rbp
  mov    0x0(%r13),%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <lseek@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long int getFileSize(int fp) {
  long int save_pos, size_of_file;
  save_pos = lseek(fp, 0, SEEK_CUR);
  lseek(fp, 0L, SEEK_SET);
  size_of_file = lseek(fp, 0L, SEEK_END);
  lseek(fp, save_pos, SEEK_SET);
  return (size_of_file);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getFileSize>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    D17(%rip),%rbx
  mov    %ebp,%edi
  xor    %esi,%esi
  mov    %rax,%r13
  mov    (%rbx),%edx
  call   <lseek@plt>
  mov    D15(%rip),%rax
  mov    %ebp,%edi
  xor    %esi,%esi
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    (%rbx),%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <lseek@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long int getFileSize(int fp) {
  long int save_pos, size_of_file;
  save_pos = lseek(fp, 0, SEEK_CUR);
  lseek(fp, 0L, SEEK_SET);
  size_of_file = lseek(fp, 0L, SEEK_END);
  lseek(fp, save_pos, SEEK_SET);
  return (size_of_file);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getFileSize>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    D2(%rip),%rbx
  mov    %ebp,%edi
  xor    %esi,%esi
  mov    %rax,%r13
  mov    (%rbx),%edx
  call   <lseek@plt>
  mov    D20(%rip),%rax
  mov    %ebp,%edi
  xor    %esi,%esi
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    (%rbx),%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <lseek@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long int getFileSize(int fp) {
  long int save_pos, size_of_file;
  save_pos = lseek(fp, 0, SEEK_CUR);
  lseek(fp, 0L, SEEK_SET);
  size_of_file = lseek(fp, 0L, SEEK_END);
  lseek(fp, save_pos, SEEK_SET);
  return (size_of_file);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mercLat>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  xorpd  D23(%rip),%xmm0
  divsd  D60(%rip),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x8(%rsp)
  call   <atan@plt>
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  D22(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  mov    $0x0,%ebx
L17:
  movsd  (%rsp),%xmm0
  call   <sin@plt>
  movsd  D2(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D44(%rip),%xmm3
  subsd  %xmm1,%xmm3
  movapd %xmm3,%xmm0
  addsd  D44(%rip),%xmm1
  divsd  %xmm1,%xmm0
  mov    D15(%rip),%rax
  movq   %rax,%xmm1
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <atan@plt>
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D22(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  (%rsp),%xmm2
  subsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm2
  movsd  %xmm2,(%rsp)
  add    $0x1,%ebx
  andpd  D20(%rip),%xmm0
  comisd D25(%rip),%xmm0
  jbe    L7
  cmp    $0xe,%ebx
  jle    L17
L7:
  movsd  (%rsp),%xmm0
  call   <radDeg@plt>
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D23
type_guessed: byte[16]
name: extract_symbolic_data
arguments: data_label: D60
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D22
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D44
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: qword[2]
name: extract_symbolic_data
arguments: data_label: D25
type_guessed: f64

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D60: 6378137

tool: D22: 1.5707963267948966

tool: {"D2": [0xcb,0x8e,0x39,0x3d,0x1a,0xf2,0xb4,0x3f]}

tool: D44: 1

tool: {"D15": [0xcb,0x8e,0x39,0x3d,0x1a,0xf2,0xa4,0x3f]}

tool: {"D20": [0x7fffffffffffffff,0x0000000000000000]}

tool: D25: 1e-09

assistant: ```c
double mercLat(double y) {
  double ts = exp(-y / 6378137.0);
  double phi = 1.57079632679489661923132169163975144 - 2 * atan(ts);
  double dphi = 1.0;
  int i;
  for (i = 0; fabs(dphi) > 0.000000001 && i < 15; i++) {
    double con = (sqrt(1.0 - ((6356752.3142 / 6378137.0) * (6356752.3142 / 6378137.0)))) * sin(phi);
    dphi = 1.57079632679489661923132169163975144 - 2 * atan(ts * pow((1.0 - con) / (1.0 + con), (0.5 * (sqrt(1.0 - ((6356752.3142 / 6378137.0) * (6356752.3142 / 6378137.0))))))) - phi;
    phi += dphi;
  }
  return radDeg(phi);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mercLat>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  xorpd  D25(%rip),%xmm0
  divsd  D76(%rip),%xmm0
  call   <exp@plt>
  movsd  %xmm0,0x8(%rsp)
  call   <atan@plt>
  pxor   %xmm0,%xmm0
  movsd  D69(%rip),%xmm2
  add    %eax,%eax
  cvtsi2sd %eax,%xmm0
  subsd  %xmm0,%xmm2
  nopl   0x0(%rax)
L1:
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  add    $0x1,%ebx
  call   <sin@plt>
  movsd  D95(%rip),%xmm1
  mov    D2(%rip),%rax
  mulsd  %xmm0,%xmm1
  movsd  D15(%rip),%xmm0
  subsd  %xmm1,%xmm0
  addsd  D15(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %rax,%xmm1
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  call   <atan@plt>
  pxor   %xmm1,%xmm1
  movsd  (%rsp),%xmm2
  movsd  D69(%rip),%xmm0
  add    %eax,%eax
  cvtsi2sd %eax,%xmm1
  subsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm2
  andpd  D26(%rip),%xmm0
  comisd D14(%rip),%xmm0
  jbe    L8
  cmp    $0xf,%ebx
  jne    L1
L8:
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  jmp    1090 <radDeg@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D25
datatype: byte[16]
name: parse_data
arguments: data_tag: D76
datatype: f64
name: parse_data
arguments: data_tag: D69
datatype: f64
name: parse_data
arguments: data_tag: D95
datatype: byte[8]
name: parse_data
arguments: data_tag: D2
datatype: byte[8]
name: parse_data
arguments: data_tag: D15
datatype: f64
name: parse_data
arguments: data_tag: D26
datatype: qword[2]
name: parse_data
arguments: data_tag: D14
datatype: f64

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D76: 6378137

tool: D69: 1.5707963267948966

tool: {"D95": [0xcb,0x8e,0x39,0x3d,0x1a,0xf2,0xb4,0x3f]}

tool: {"D2": [0xcb,0x8e,0x39,0x3d,0x1a,0xf2,0xa4,0x3f]}

tool: D15: 1

tool: {"D26": [0x7fffffffffffffff,0x0000000000000000]}

tool: D14: 1e-09

assistant: ```c
double mercLat(double y) {
  double ts = exp(-y / 6378137.0);
  double phi = 1.57079632679489661923132169163975144 - 2 * atan(ts);
  double dphi = 1.0;
  int i;
  for (i = 0; fabs(dphi) > 0.000000001 && i < 15; i++) {
    double con = (sqrt(1.0 - ((6356752.3142 / 6378137.0) * (6356752.3142 / 6378137.0)))) * sin(phi);
    dphi = 1.57079632679489661923132169163975144 - 2 * atan(ts * pow((1.0 - con) / (1.0 + con), (0.5 * (sqrt(1.0 - ((6356752.3142 / 6378137.0) * (6356752.3142 / 6378137.0))))))) - phi;
    phi += dphi;
  }
  return radDeg(phi);
}
```