ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sockutil_a6_eq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L38
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L38
  mov    $0x0,%eax
  jmp    L55
L38:
  mov    -0x14(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  jne    L113
  mov    -0x10(%rbp),%rax
  lea    0x18(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L113
  mov    $0x0,%eax
  jmp    L55
L113:
  mov    -0x14(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L117
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  je     L117
  mov    $0x0,%eax
  jmp    L55
L117:
  mov    -0x14(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  jne    L100
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  cmp    %rax,%rdx
  je     L100
  mov    $0x0,%eax
  jmp    L55
L100:
  mov    $0x1,%eax
L55:
  leave
  ret
```

assistant: ```c
int sockutil_a6_eq(struct sockaddr_in6 *a, struct sockaddr_in6 *b, unsigned ignore) {
  if (!(ignore & 0x2) && (a->sin6_port != b->sin6_port)) {
    return 0;
  }
  if (!(ignore & 0x4) && memcmp(&a->sin6_addr, &b->sin6_addr, sizeof(struct in6_addr))) {
    return 0;
  }
  if (!(ignore & 0x8) && (a->sin6_flowinfo != b->sin6_flowinfo)) {
    return 0;
  }
  if (!(ignore & 0x10) && (a->sin6_scope_id != b->sin6_scope_id)) {
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sockutil_a6_eq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  test   $0x2,%dl
  jne    L40
  mov    $0x0,%eax
  mov    (%rsi),%rcx
  cmp    %rcx,(%rdi)
  jne    L76
L40:
  test   $0x4,%bl
  je     L77
L27:
  test   $0x8,%bl
  jne    L19
  mov    $0x0,%eax
  mov    0x8(%rbp),%rcx
  cmp    %rcx,0x8(%r12)
  jne    L76
L19:
  mov    $0x1,%eax
  test   $0x10,%bl
  jne    L76
  mov    0x10(%rbp),%rax
  cmp    %rax,0x10(%r12)
  sete   %al
  movzbl %al,%eax
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L77:
  lea    0x18(%rbp),%rsi
  lea    0x18(%r12),%rdi
  mov    $0x4,%edx
  call   <memcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L27
  jmp    L76
```

assistant: ```c
int sockutil_a6_eq(struct sockaddr_in6 *a, struct sockaddr_in6 *b, unsigned ignore) {
  if (!(ignore & 0x2) && (a->sin6_port != b->sin6_port)) {
    return 0;
  }
  if (!(ignore & 0x4) && memcmp(&a->sin6_addr, &b->sin6_addr, sizeof(struct in6_addr))) {
    return 0;
  }
  if (!(ignore & 0x8) && (a->sin6_flowinfo != b->sin6_flowinfo)) {
    return 0;
  }
  if (!(ignore & 0x10) && (a->sin6_scope_id != b->sin6_scope_id)) {
    return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sockutil_a6_eq>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  and    $0x2,%edx
  jne    L17
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  je     L17
L3:
  xor    %eax,%eax
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  test   $0x4,%bl
  je     L68
L21:
  test   $0x8,%bl
  je     L14
L59:
  and    $0x10,%ebx
  mov    $0x1,%eax
  jne    L43
  mov    0x10(%rbp),%rax
  cmp    %rax,0x10(%r12)
  sete   %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  ret
L14:
  mov    0x8(%rbp),%rax
  cmp    %rax,0x8(%r12)
  jne    L3
  jmp    L59
  nopl   (%rax)
L68:
  lea    0x18(%rbp),%rsi
  lea    0x18(%r12),%rdi
  mov    $0x4,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  je     L21
  jmp    L3
```

assistant: ```c
int sockutil_a6_eq(struct sockaddr_in6 *a, struct sockaddr_in6 *b, unsigned ignore) {
  if (!(ignore & 0x2) && (a->sin6_port != b->sin6_port)) {
    return 0;
  }
  if (!(ignore & 0x4) && memcmp(&a->sin6_addr, &b->sin6_addr, sizeof(struct in6_addr))) {
    return 0;
  }
  if (!(ignore & 0x8) && (a->sin6_flowinfo != b->sin6_flowinfo)) {
    return 0;
  }
  if (!(ignore & 0x10) && (a->sin6_scope_id != b->sin6_scope_id)) {
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sockutil_a6_eq>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  and    $0x2,%edx
  jne    L65
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  je     L65
L80:
  xor    %eax,%eax
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L65:
  test   $0x4,%bl
  je     L32
L13:
  test   $0x8,%bl
  je     L71
L17:
  and    $0x10,%ebx
  mov    $0x1,%eax
  jne    L35
  mov    0x10(%rbp),%rax
  cmp    %rax,0x10(%r12)
  sete   %al
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  pop    %r12
  ret
L71:
  mov    0x8(%rbp),%rax
  cmp    %rax,0x8(%r12)
  jne    L80
  jmp    L17
  nopl   (%rax)
L32:
  lea    0x18(%rbp),%rsi
  lea    0x18(%r12),%rdi
  mov    $0x4,%edx
  call   <memcmp@plt>
  test   %rax,%rax
  je     L13
  jmp    L80
```

assistant: ```c
int sockutil_a6_eq(struct sockaddr_in6 *a, struct sockaddr_in6 *b, unsigned ignore) {
  if (!(ignore & 0x2) && (a->sin6_port != b->sin6_port)) {
    return 0;
  }
  if (!(ignore & 0x4) && memcmp(&a->sin6_addr, &b->sin6_addr, sizeof(struct in6_addr))) {
    return 0;
  }
  if (!(ignore & 0x8) && (a->sin6_flowinfo != b->sin6_flowinfo)) {
    return 0;
  }
  if (!(ignore & 0x10) && (a->sin6_scope_id != b->sin6_scope_id)) {
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]

  FILENAME is a Scheme source file, or '-' to read from standard input.
  OPTION may be one of the following:

    -L, --lib-path PATHNAME  add PATHNAME to the library search paths
    -h, --help               display this text and exit
        --version            display version and exit


assistant: ```c
_Noreturn void usage(const char *name, int status) {
  printf("usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]\n\n  FILENAME is a Scheme source file, or '-' to read from standard input.\n  OPTION may be one of the following:\n\n    -L, --lib-path PATHNAME  add PATHNAME to the library search paths\n    -h, --help               display this text and exit\n        --version            display version and exit\n", name);
  exit(status);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]

  FILENAME is a Scheme source file, or '-' to read from standard input.
  OPTION may be one of the following:

    -L, --lib-path PATHNAME  add PATHNAME to the library search paths
    -h, --help               display this text and exit
        --version            display version and exit


assistant: ```c
_Noreturn void usage(const char *name, int status) {
  printf("usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]\n\n  FILENAME is a Scheme source file, or '-' to read from standard input.\n  OPTION may be one of the following:\n\n    -L, --lib-path PATHNAME  add PATHNAME to the library search paths\n    -h, --help               display this text and exit\n        --version            display version and exit\n", name);
  exit(status);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]

  FILENAME is a Scheme source file, or '-' to read from standard input.
  OPTION may be one of the following:

    -L, --lib-path PATHNAME  add PATHNAME to the library search paths
    -h, --help               display this text and exit
        --version            display version and exit


assistant: ```c
_Noreturn void usage(const char *name, int status) {
  printf("usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]\n\n  FILENAME is a Scheme source file, or '-' to read from standard input.\n  OPTION may be one of the following:\n\n    -L, --lib-path PATHNAME  add PATHNAME to the library search paths\n    -h, --help               display this text and exit\n        --version            display version and exit\n", name);
  exit(status);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D6: usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]

  FILENAME is a Scheme source file, or '-' to read from standard input.
  OPTION may be one of the following:

    -L, --lib-path PATHNAME  add PATHNAME to the library search paths
    -h, --help               display this text and exit
        --version            display version and exit


assistant: ```c
_Noreturn void usage(const char *name, int status) {
  printf("usage: %s [OPTION ...] [FILENAME [ARGUMENT ...]]\n\n  FILENAME is a Scheme source file, or '-' to read from standard input.\n  OPTION may be one of the following:\n\n    -L, --lib-path PATHNAME  add PATHNAME to the library search paths\n    -h, --help               display this text and exit\n        --version            display version and exit\n", name);
  exit(status);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_nb_cpus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xffffffff,-0x1c(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L36
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L11
  movl   $0xfffffffe,-0x1c(%rbp)
  jmp    L47
L21:
  mov    -0x10(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L47
  mov    -0x10(%rbp),%rax
  mov    $0x3a,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x1c(%rbp)
L47:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L21
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L11:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L36:
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D25
type: string
name: extract_symbolic_data
arguments: data_label: D19
type: string

tool: D0: r

tool: D25: /proc/cpuinfo

tool: D19: processor

assistant: ```c
int get_nb_cpus() {
  char *s, *pos;
  FILE *f;
  int number = -1;
  f = fopen("/proc/cpuinfo", "r");
  if (f != NULL) {
    s = (char *)calloc(1, 81);
    if (s != NULL) {
      number = -2;
      while (fgets(s, 80, f) != NULL) {
        pos = strstr(s, "processor");
        if (pos == s) {
          pos = strchr(s, ':');
          number = atoi(pos + 1);
        }
      }
      ++number;
      free(s);
    }
    fclose(f);
  }
  return number;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_nb_cpus>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D18(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rbp
  mov    $0x51,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rbx
  mov    $0xffffffff,%r13d
  test   %rax,%rax
  je     L17
  mov    $0xfffffffe,%r13d
  lea    D10(%rip),%r12
L34:
  mov    %rbp,%rdx
  mov    $0x50,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L44
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  cmp    %rax,%rbx
  jne    L34
  mov    $0x3a,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  jmp    L34
L44:
  add    $0x1,%r13d
  mov    %rbx,%rdi
  call   <free@plt>
L17:
  mov    %rbp,%rdi
  call   <fclose@plt>
L57:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    $0xffffffff,%r13d
  jmp    L57
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D0: r

tool: D18: /proc/cpuinfo

tool: D10: processor

assistant: ```c
int get_nb_cpus() {
  char *s, *pos;
  FILE *f;
  int number = -1;
  f = fopen("/proc/cpuinfo", "r");
  if (f != NULL) {
    s = (char *)calloc(1, 81);
    if (s != NULL) {
      number = -2;
      while (fgets(s, 80, f) != NULL) {
        pos = strstr(s, "processor");
        if (pos == s) {
          pos = strchr(s, ':');
          number = atoi(pos + 1);
        }
      }
      ++number;
      free(s);
    }
    fclose(f);
  }
  return number;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_nb_cpus>:
  endbr64
  push   %r13
  lea    D25(%rip),%rsi
  lea    D1(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L33
  mov    $0x51,%esi
  mov    $0x1,%edi
  mov    %rax,%r12
  mov    $0xffffffff,%r13d
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L65
  mov    $0xfffffffe,%r13d
  lea    D23(%rip),%rbx
  jmp    L2
  nopl   0x0(%rax)
L41:
  mov    $0x9,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L38
L2:
  mov    %r12,%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L41
  mov    %rbp,%rdi
  add    $0x1,%r13d
  call   <free@plt>
L65:
  mov    %r12,%rdi
  call   <fclose@plt>
L16:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  jmp    L2
L33:
  mov    $0xffffffff,%r13d
  jmp    L16
```

tool_calls: name: parse_data
arguments: data_label: D25
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D23
datatype: string

tool: D25: r

tool: D1: /proc/cpuinfo

tool: D23: processor

assistant: ```c
int get_nb_cpus() {
  char *s, *pos;
  FILE *f;
  int number = -1;
  f = fopen("/proc/cpuinfo", "r");
  if (f != NULL) {
    s = (char *)calloc(1, 81);
    if (s != NULL) {
      number = -2;
      while (fgets(s, 80, f) != NULL) {
        pos = strstr(s, "processor");
        if (pos == s) {
          pos = strchr(s, ':');
          number = atoi(pos + 1);
        }
      }
      ++number;
      free(s);
    }
    fclose(f);
  }
  return number;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_nb_cpus>:
  endbr64
  push   %r13
  lea    D6(%rip),%rsi
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <fopen@plt>
  test   %rax,%rax
  je     L46
  mov    $0x51,%esi
  mov    $0x1,%edi
  mov    %rax,%r12
  mov    $0xffffffff,%r13d
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L57
  mov    $0xfffffffe,%r13d
  lea    D15(%rip),%rbx
  jmp    L40
  nopl   0x0(%rax)
L8:
  mov    $0x9,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L18
L40:
  mov    %r12,%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  add    $0x1,%r13d
  call   <free@plt>
L57:
  mov    %r12,%rdi
  call   <fclose@plt>
L9:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x3a,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r13d
  jmp    L40
L46:
  mov    $0xffffffff,%r13d
  jmp    L9
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string

tool: D6: r

tool: D2: /proc/cpuinfo

tool: D15: processor

assistant: ```c
int get_nb_cpus() {
  char *s, *pos;
  FILE *f;
  int number = -1;
  f = fopen("/proc/cpuinfo", "r");
  if (f != NULL) {
    s = (char *)calloc(1, 81);
    if (s != NULL) {
      number = -2;
      while (fgets(s, 80, f) != NULL) {
        pos = strstr(s, "processor");
        if (pos == s) {
          pos = strchr(s, ':');
          number = atoi(pos + 1);
        }
      }
      ++number;
      free(s);
    }
    fclose(f);
  }
  return number;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MINIMUM_32b_AUTOTEST>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
L10:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x18,%edx
  lea    (%rax,%rdx,1),%ebp
  movzbl %bpl,%ebp
  sub    %edx,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x18,%edx
  lea    (%rax,%rdx,1),%ebx
  movzbl %bl,%ebx
  sub    %edx,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <instr_min@plt>
  mov    %eax,%r13d
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <instr_min@plt>
  mov    %eax,%r14d
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <prog_min@plt>
  mov    %eax,%r15d
  cmp    %r14d,%r13d
  jne    L20
  cmp    %eax,%r13d
  jne    L20
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L10
  lea    D52(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D5(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r15d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L12
```

tool_calls: name: parse_data
arguments: tag: D48
type_guessed: string
name: parse_data
arguments: tag: D52
type_guessed: string
name: parse_data
arguments: tag: D59
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D35
type_guessed: string

tool: D48: LAUNCHING THE (MINIMUM) RESOURCE TEST...

tool: D52: - TEST OF THE (MINIMUM) RESOURCE => OK

tool: D59: - TEST OF THE MINIMUM_32b RESOURCE => FAILED !

tool: D19:   + %d COMPUTATION BEFORE ERROR... !


tool: D5:   + INSTRUCTION RESULT (%d l %d) => %d


tool: D35:   + C CODE RESULT      (%d l %d) => %d


assistant: ```c
int MINIMUM_32b_AUTOTEST() {
  int i, j;
  printf("LAUNCHING THE (MINIMUM) RESOURCE TEST...\n");
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 256;
    int op2 = rand() % 256;
    int res1 = instr_min(op1, op2);
    int res2 = instr_min(op2, op1);
    int res3 = prog_min(op1, op2);
    if ((res1 != res2) || (res1 != res3)) {
      printf("- TEST OF THE MINIMUM_32b RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op1, op2, res1);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op2, op1, res2);
      printf("  + C CODE RESULT      (%d l %d) => %d\n", op2, op1, res3);
      return 0;
    }
  }
  printf("- TEST OF THE (MINIMUM) RESOURCE => OK\n");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<MINIMUM_32b_AUTOTEST>:
  endbr64
  push   %r15
  lea    D14(%rip),%rdi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  shr    $0x18,%edx
  lea    (%rax,%rdx,1),%r12d
  xor    %eax,%eax
  movzbl %r12b,%r12d
  sub    %edx,%r12d
  call   <rand@plt>
  mov    %r12d,%edi
  cltd
  shr    $0x18,%edx
  lea    (%rax,%rdx,1),%ebp
  movzbl %bpl,%ebp
  sub    %edx,%ebp
  mov    %ebp,%esi
  call   <instr_min@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%r13d
  call   <instr_min@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r15d
  call   <prog_min@plt>
  mov    %eax,%ebx
  cmp    %r15d,%r13d
  jne    L20
  cmp    %eax,%r13d
  jne    L20
  add    $0x1,%r14d
  cmp    $0xa,%r14d
  jne    L6
  lea    D29(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L20:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %r14d,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  lea    D7(%rip),%r13
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r15d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D29
datatype: string
name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D56
datatype: string
name: unpack_data
arguments: label: D7
datatype: string
name: unpack_data
arguments: label: D43
datatype: string

tool: D14: LAUNCHING THE (MINIMUM) RESOURCE TEST...

tool: D29: - TEST OF THE (MINIMUM) RESOURCE => OK

tool: D5: - TEST OF THE MINIMUM_32b RESOURCE => FAILED !

tool: D56:   + %d COMPUTATION BEFORE ERROR... !


tool: D7:   + INSTRUCTION RESULT (%d l %d) => %d


tool: D43:   + C CODE RESULT      (%d l %d) => %d


assistant: ```c
int MINIMUM_32b_AUTOTEST() {
  int i, j;
  printf("LAUNCHING THE (MINIMUM) RESOURCE TEST...\n");
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 256;
    int op2 = rand() % 256;
    int res1 = instr_min(op1, op2);
    int res2 = instr_min(op2, op1);
    int res3 = prog_min(op1, op2);
    if ((res1 != res2) || (res1 != res3)) {
      printf("- TEST OF THE MINIMUM_32b RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op1, op2, res1);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op2, op1, res2);
      printf("  + C CODE RESULT      (%d l %d) => %d\n", op2, op1, res3);
      return 0;
    }
  }
  printf("- TEST OF THE (MINIMUM) RESOURCE => OK\n");
  return 1;
}
```