ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<glmGenerateRandomVector3f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  D31(%rip),%xmm1
  movss  D2(%rip),%xmm0
  call   <glmRandomNumberf@plt>
  movsd  D25(%rip),%xmm1
  movss  %xmm0,0x8(%rbx)
  pxor   %xmm0,%xmm0
  call   <glmRandomNumberf@plt>
  movss  D37(%rip),%xmm2
  movss  %xmm0,0xc(%rsp)
  movss  0x8(%rbx),%xmm0
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,(%rbx)
  movaps %xmm1,%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D31
type_guessed: byte[8]
name: unpack_data
arguments: data_label: D2
type_guessed: byte[4]
name: unpack_data
arguments: data_label: D25
type_guessed: f64
name: unpack_data
arguments: data_label: D37
type_guessed: byte[4]

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D2": [0x00,0x00,0x80,0xbf]}

tool: D25: 6.283185307179586

tool: {"D37": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmGenerateRandomVector3f(float v[3]) {
  float a, r;
  v[2] = glmRandomNumberf(-1.0f, 1.0f);
  a = glmRandomNumberf(0.0f, 6.283185307179586476925286766559);
  r = sqrt(1.0f - v[2] * v[2]);
  v[0] = r * cos(a);
  v[1] = r * sin(a);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<glmGenerateRandomVector3f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  D2(%rip),%xmm1
  movss  D27(%rip),%xmm0
  call   <glmRandomNumberf@plt>
  movsd  D18(%rip),%xmm1
  movss  %xmm0,0x8(%rbx)
  pxor   %xmm0,%xmm0
  call   <glmRandomNumberf@plt>
  movss  D36(%rip),%xmm2
  movss  %xmm0,0xc(%rsp)
  movss  0x8(%rbx),%xmm0
  mulss  %xmm0,%xmm0
  subss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  call   <sqrt@plt>
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,(%rbx)
  movaps %xmm1,%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x4(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: byte[8]
name: extract_symbolic_data
arguments: data_tag: D27
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D18
datatype: f64
name: extract_symbolic_data
arguments: data_tag: D36
datatype: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D27": [0x00,0x00,0x80,0xbf]}

tool: D18: 6.283185307179586

tool: {"D36": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void glmGenerateRandomVector3f(float v[3]) {
  float a, r;
  v[2] = glmRandomNumberf(-1.0f, 1.0f);
  a = glmRandomNumberf(0.0f, 6.283185307179586476925286766559);
  r = sqrt(1.0f - v[2] * v[2]);
  v[0] = r * cos(a);
  v[1] = r * sin(a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convertAsn1ToTimestamp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <convertAsn1ToString@plt>
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strptime@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D8(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string

tool: D7: %b %d %H:%M:%S %Y

tool: D8: %s

assistant: ```c
int convertAsn1ToTimestamp(ASN1_TIME *notAfter, char buffer[]) {
  convertAsn1ToString(notAfter, buffer);
  struct tm timestruct;
  memset(&timestruct, 0, sizeof(struct tm));
  strptime(buffer, "%b %d %H:%M:%S %Y", &timestruct);
  strftime(buffer, 128, "%s", &timestruct);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convertAsn1ToTimestamp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <convertAsn1ToString@plt>
  lea    0x4(%rsp),%rbp
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rdx
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <strptime@plt>
  mov    %rbp,%rcx
  lea    D9(%rip),%rdx
  mov    $0x80,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D19: %b %d %H:%M:%S %Y

tool: D9: %s

assistant: ```c
int convertAsn1ToTimestamp(ASN1_TIME *notAfter, char buffer[]) {
  convertAsn1ToString(notAfter, buffer);
  struct tm timestruct;
  memset(&timestruct, 0, sizeof(struct tm));
  strptime(buffer, "%b %d %H:%M:%S %Y", &timestruct);
  strftime(buffer, 128, "%s", &timestruct);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convertAsn1ToTimestamp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <convertAsn1ToString@plt>
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strptime@plt>
  mov    %r12,%rcx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  lea    D4(%rip),%rdx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
type: string
name: parse_data
arguments: data_tag: D4
type: string

tool: D11: %b %d %H:%M:%S %Y

tool: D4: %s

assistant: ```c
int convertAsn1ToTimestamp(ASN1_TIME *notAfter, char buffer[]) {
  convertAsn1ToString(notAfter, buffer);
  struct tm timestruct;
  memset(&timestruct, 0, sizeof(struct tm));
  strptime(buffer, "%b %d %H:%M:%S %Y", &timestruct);
  strftime(buffer, 128, "%s", &timestruct);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convertAsn1ToTimestamp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <convertAsn1ToString@plt>
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rdx
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <strptime@plt>
  mov    %r12,%rcx
  mov    $0x80,%esi
  mov    %rbp,%rdi
  lea    D4(%rip),%rdx
  call   <strftime@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D4
data_type: string

tool: D14: %b %d %H:%M:%S %Y

tool: D4: %s

assistant: ```c
int convertAsn1ToTimestamp(ASN1_TIME *notAfter, char buffer[]) {
  convertAsn1ToString(notAfter, buffer);
  struct tm timestruct;
  memset(&timestruct, 0, sizeof(struct tm));
  strptime(buffer, "%b %d %H:%M:%S %Y", &timestruct);
  strftime(buffer, 128, "%s", &timestruct);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  cmpl   $0x1,-0x28(%rbp)
  jle    L69
  cmpl   $0x24,-0x28(%rbp)
  jle    L60
L69:
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  jmp    L10
L60:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L65:
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x28(%rbp)
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movslq %ecx,%rdx
  lea    D9(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  cmpl   $0x0,-0x24(%rbp)
  jne    L65
  cmpl   $0x0,-0x14(%rbp)
  jns    L14
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2d,(%rax)
L14:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  jmp    L31
L1:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x15(%rbp),%edx
  mov    %dl,(%rax)
L31:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L1
  mov    -0x30(%rbp),%rax
L10:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[(tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0)
    *ptr++ = '-';
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<itoa>:
  endbr64
  mov    %rsi,%r10
  mov    %edx,%ecx
  lea    -0x2(%rdx),%eax
  lea    D6(%rip),%r11
  cmp    $0x22,%eax
  ja     L28
  push   %rbx
L55:
  mov    %edi,%r8d
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r9d
  mov    %eax,%edi
  mov    %rsi,%rbx
  add    $0x1,%rsi
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  movslq %edx,%rdx
  movzbl (%r11,%rdx,1),%eax
  mov    %al,-0x1(%rsi)
  test   %r9d,%r9d
  jne    L55
  test   %r8d,%r8d
  js     L50
L9:
  lea    -0x1(%rsi),%rax
  movb   $0x0,(%rsi)
  cmp    %rax,%r10
  jae    L48
  mov    %r10,%rdx
L54:
  movzbl (%rax),%ecx
  sub    $0x1,%rax
  movzbl (%rdx),%esi
  mov    %sil,0x1(%rax)
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rax
  ja     L54
L48:
  mov    %r10,%rax
  pop    %rbx
  ret
L28:
  movb   $0x0,(%rsi)
  mov    %rsi,%rax
  ret
L50:
  movb   $0x2d,(%rsi)
  lea    0x2(%rbx),%rsi
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
datatype: string

tool: D6: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[(tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0)
    *ptr++ = '-';
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itoa>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%edi
  lea    -0x2(%rdx),%edx
  mov    %rsi,%r9
  lea    D0(%rip),%r8
  cmp    $0x22,%edx
  ja     L7
  nopw   0x0(%rax,%rax,1)
L43:
  cltd
  mov    %eax,%r10d
  mov    %rsi,%rcx
  add    $0x1,%rsi
  idiv   %edi
  movslq %edx,%rdx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jne    L43
  test   %r10d,%r10d
  js     L33
L44:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  cmp    %r9,%rcx
  jbe    L16
  nopl   0x0(%rax)
L3:
  movzbl (%rcx),%edx
  movzbl (%rax),%esi
  sub    $0x1,%rcx
  add    $0x1,%rax
  mov    %sil,0x1(%rcx)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  ja     L3
L16:
  mov    %r9,%rax
  ret
  xchg   %ax,%ax
L33:
  lea    0x2(%rcx),%rax
  movb   $0x2d,(%rsi)
  mov    %rsi,%rcx
  mov    %rax,%rsi
  jmp    L44
  nop
L7:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[(tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0)
    *ptr++ = '-';
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%edi
  lea    -0x2(%rdx),%edx
  mov    %rsi,%r9
  lea    D8(%rip),%r8
  cmp    $0x22,%edx
  ja     L2
  nopw   0x0(%rax,%rax,1)
L35:
  cltd
  mov    %eax,%r10d
  mov    %rsi,%rcx
  add    $0x1,%rsi
  idiv   %edi
  movslq %edx,%rdx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,-0x1(%rsi)
  test   %eax,%eax
  jne    L35
  test   %r10d,%r10d
  js     L7
L41:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  cmp    %r9,%rcx
  jbe    L23
  nopl   0x0(%rax)
L1:
  movzbl (%rcx),%edx
  movzbl (%rax),%esi
  sub    $0x1,%rcx
  add    $0x1,%rax
  mov    %sil,0x1(%rcx)
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  ja     L1
L23:
  mov    %r9,%rax
  ret
  xchg   %ax,%ax
L7:
  lea    0x2(%rcx),%rax
  movb   $0x2d,(%rsi)
  mov    %rsi,%rcx
  mov    %rax,%rsi
  jmp    L41
  nop
L2:
  movb   $0x0,(%rsi)
  mov    %r9,%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string

tool: D8: 0123456789abcdefghijklmnopqrstuvwxyz

assistant: ```c
char *itoa(int value, char *result, int base) {
  if (base < 2 || base > 36) {
    *result = '\0';
    return result;
  }
  char *ptr = result, *ptr1 = result, tmp_char;
  int tmp_value;
  do {
    tmp_value = value;
    value /= base;
    *ptr++ = "0123456789abcdefghijklmnopqrstuvwxyz"[(tmp_value - value * base)];
  } while (value);
  if (tmp_value < 0)
    *ptr++ = '-';
  *ptr-- = '\0';
  while (ptr1 < ptr) {
    tmp_char = *ptr;
    *ptr-- = *ptr1;
    *ptr1++ = tmp_char;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qh_pointdist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L18
L13:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jne    L13
  cmpl   $0x0,-0x34(%rbp)
  jle    L37
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  jmp    L9
L37:
  mov    -0x10(%rbp),%rax
L9:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double qh_pointdist(double *point1, double *point2, int dim) {
  double dist, diff;
  int k;
  dist = 0.0;
  for (k = (dim > 0 ? dim : -dim); k--;) {
    diff = *point1++ - *point2++;
    dist += diff * diff;
  }
  if (dim > 0)
    return (sqrt(dist));
  return dist;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qh_pointdist>:
  endbr64
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  test   %edx,%edx
  je     L18
  lea    -0x1(%rax),%r8d
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L48:
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r8,%rcx
  jne    L48
  test   %edx,%edx
  jg     L36
L25:
  movapd %xmm1,%xmm0
  ret
L36:
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L53
  sqrtsd %xmm1,%xmm1
  jmp    L25
L53:
  sub    $0x8,%rsp
  movapd %xmm1,%xmm0
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
L18:
  pxor   %xmm1,%xmm1
  jmp    L25
```

assistant: ```c
double qh_pointdist(double *point1, double *point2, int dim) {
  double dist, diff;
  int k;
  dist = 0.0;
  for (k = (dim > 0 ? dim : -dim); k--;) {
    diff = *point1++ - *point2++;
    dist += diff * diff;
  }
  if (dim > 0)
    return (sqrt(dist));
  return dist;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<qh_pointdist>:
  endbr64
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  test   %edx,%edx
  je     L35
  lea    -0x1(%rax),%r8d
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%rcx
  add    $0x1,%rax
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %r8,%rcx
  jne    L10
  test   %edx,%edx
  jg     L39
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  pxor   %xmm2,%xmm2
  ucomisd %xmm1,%xmm2
  ja     L22
  sqrtsd %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
L22:
  movapd %xmm1,%xmm0
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double qh_pointdist(double *point1, double *point2, int dim) {
  double dist, diff;
  int k;
  dist = 0.0;
  for (k = (dim > 0 ? dim : -dim); k--;) {
    diff = *point1++ - *point2++;
    dist += diff * diff;
  }
  if (dim > 0)
    return (sqrt(dist));
  return dist;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qh_pointdist>:
  endbr64
  mov    %edx,%r8d
  mov    %rsi,%rcx
  neg    %r8d
  cmovs  %edx,%r8d
  test   %edx,%edx
  je     L28
  cmp    $0x1,%r8d
  je     L21
  mov    %r8d,%esi
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  shr    %esi
  movapd %xmm3,%xmm0
  shl    $0x4,%rsi
  cs nopw 0x0(%rax,%rax,1)
L64:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm4
  add    $0x10,%rax
  subpd  %xmm4,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L64
  mov    %r8d,%esi
  and    $0xfffffffe,%esi
  mov    %esi,%eax
  shl    $0x3,%rax
  add    %rax,%rdi
  add    %rax,%rcx
  cmp    %esi,%r8d
  je     L35
L3:
  movsd  (%rdi),%xmm1
  subsd  (%rcx),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L35:
  test   %edx,%edx
  jg     L48
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  ucomisd %xmm0,%xmm3
  ja     L10
  sqrtsd %xmm0,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  pxor   %xmm0,%xmm0
  ret
L21:
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm0
  jmp    L3
L10:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double qh_pointdist(double *point1, double *point2, int dim) {
  double dist, diff;
  int k;
  dist = 0.0;
  for (k = (dim > 0 ? dim : -dim); k--;) {
    diff = *point1++ - *point2++;
    dist += diff * diff;
  }
  if (dim > 0)
    return (sqrt(dist));
  return dist;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<appendText>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %edx,%ebp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  movl   $0x0,0xc(%rsp)
  test   %r15,%r15
  je     L19
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
L19:
  mov    0xc(%rsp),%eax
  lea    (%rax,%r14,1),%ebx
  test   %r13b,%r13b
  je     L126
  add    $0x3,%ebx
  test   %r14d,%r14d
  jle    L92
  mov    %r12,%rax
  lea    -0x1(%r14),%edx
  lea    0x1(%r12,%rdx,1),%rcx
L30:
  cmp    %bpl,(%rax)
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%ebx
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L30
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <realloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L58
  movslq 0xc(%rsp),%rdx
  add    %r15,%rdx
  lea    0x1(%rdx),%rax
  mov    %r13b,(%rdx)
  mov    %r12,%rdx
  lea    -0x1(%r14),%ecx
  lea    0x1(%r12,%rcx,1),%rsi
  jmp    L66
L46:
  mov    %bpl,0x1(%rax)
  lea    0x2(%rax),%rax
L61:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L50
L66:
  movzbl (%rdx),%ecx
  mov    %cl,(%rax)
  cmp    %bpl,%cl
  je     L46
  add    $0x1,%rax
  jmp    L61
L7:
  mov    $0x0,%r15d
  jmp    L102
L58:
  mov    $0x0,%r15d
  jmp    L102
L126:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <realloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%r15d
  test   %rax,%rax
  je     L102
  mov    %rbp,%r15
  movslq 0xc(%rsp),%rdi
  add    %rbp,%rdi
  mov    %r14d,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,-0x1(%rbp,%rbx,1)
  jmp    L102
L92:
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <realloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L7
  movslq 0xc(%rsp),%rdx
  add    %r15,%rdx
  lea    0x1(%rdx),%rax
  mov    %r13b,(%rdx)
L50:
  mov    %r13b,(%rax)
  movb   $0x0,0x1(%rax)
  add    $0x2,%rax
  sub    %r15,%rax
  movslq %ebx,%rbx
  cmp    %rbx,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
L102:
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *appendText(char *zIn, char const *zAppend, char quote) {
  int len;
  int i;
  int nAppend = strlen(zAppend);
  int nIn = (zIn ? strlen(zIn) : 0);
  len = nAppend + nIn + 1;
  if (quote) {
    len += 2;
    for (i = 0; i < nAppend; i++) {
      if (zAppend[i] == quote)
        len++;
    }
  }
  zIn = (char *)realloc(zIn, len);
  if (!zIn) {
    return 0;
  }
  if (quote) {
    char *zCsr = &zIn[nIn];
    *zCsr++ = quote;
    for (i = 0; i < nAppend; i++) {
      *zCsr++ = zAppend[i];
      if (zAppend[i] == quote)
        *zCsr++ = quote;
    }
    *zCsr++ = quote;
    *zCsr++ = '\0';
    assert((zCsr - zIn) == len);
  } else {
    memcpy(&zIn[nIn], zAppend, nAppend);
    zIn[len - 1] = '\0';
  }
  return zIn;
}
```