ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
type_guessed: string
name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D15: To jest testowy program do tesowania gita


tool: D1: Tutaj jeszcze cos dopiesze 


assistant: ```c
int main(void) {
  printf("To jest testowy program do tesowania gita\n");
  printf("Tutaj jeszcze cos dopiesze \n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
datatype: string
name: read_data
arguments: data_label: D14
datatype: string

tool: D16: To jest testowy program do tesowania gita


tool: D14: Tutaj jeszcze cos dopiesze 


assistant: ```c
int main(void) {
  printf("To jest testowy program do tesowania gita\n");
  printf("Tutaj jeszcze cos dopiesze \n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string
name: retrieve_data
arguments: label: D11
type: string

tool: D1: To jest testowy program do tesowania gita


tool: D11: Tutaj jeszcze cos dopiesze 


assistant: ```c
int main(void) {
  printf("To jest testowy program do tesowania gita\n");
  printf("Tutaj jeszcze cos dopiesze \n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string

tool: D1: %d

tool: D15: %d! = %d


assistant: ```c
int main(void) {
  int n, f;
  scanf("%d", &n);
  f = fact(n);
  printf("%d! = %d\n", n, f);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fact@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
datatype: string
name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D13: %d

tool: D7: %d! = %d


assistant: ```c
int main(void) {
  int n, f;
  scanf("%d", &n);
  f = fact(n);
  printf("%d! = %d\n", n, f);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fact@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D4
type: string

tool: D17: %d

tool: D4: %d! = %d


assistant: ```c
int main(void) {
  int n, f;
  scanf("%d", &n);
  f = fact(n);
  printf("%d! = %d\n", n, f);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fact@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string

tool: D9: %d

tool: D2: %d! = %d


assistant: ```c
int main(void) {
  int n, f;
  scanf("%d", &n);
  f = fact(n);
  printf("%d! = %d\n", n, f);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_stubs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x138,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x12c(%rbp)
  movl   $0x14,-0x130(%rbp)
  mov    -0x130(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x140(%rbp),%rdx
  mov    %rax,(%rdx)
  jmp    L14
L10:
  mov    -0x12c(%rbp),%eax
  cmp    -0x130(%rbp),%eax
  jne    L18
  addl   $0x14,-0x130(%rbp)
  mov    -0x130(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x140(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x140(%rbp),%rdx
  mov    %rax,(%rdx)
L18:
  lea    -0x120(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x128(%rbp)
  mov    -0x140(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x12c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x12c(%rbp)
  cltq
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x128(%rbp)
  mov    -0x140(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x12c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x12c(%rbp)
  cltq
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
L14:
  mov    -0x138(%rbp),%rdx
  lea    -0x120(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x12c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x140(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x140(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x12c(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
data_type: string

tool: D12:  

assistant: ```c
int read_stubs(FILE *filein, unsigned int **S) {
  int size, K;
  char buff[256];
  char *ptr;
  K = 0;
  size = 20;
  *S = malloc(size * sizeof(unsigned int));
  while (fgets(buff, 256, filein)) {
    if (K == size) {
      size += 20;
      *S = realloc(*S, size * sizeof(unsigned int));
    }
    ptr = strtok(buff, " ");
    (*S)[K++] = atoi(ptr);
    ptr = strtok(NULL, " ");
    (*S)[K++] = atoi(ptr);
  }
  *S = realloc(*S, K * sizeof(unsigned int));
  return K;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_stubs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    $0x50,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x14,%r15d
  lea    D9(%rip),%r13
  jmp    L2
L18:
  lea    0x10(%rsp),%rdi
  mov    %r13,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  mov    %rbx,%r14
  add    (%r12),%r14
  call   <atoi@plt>
  mov    %eax,(%r14)
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  add    $0x2,%ebp
  mov    (%r12),%rax
  lea    0x4(%rax,%rbx,1),%r14
  call   <atoi@plt>
  mov    %eax,(%r14)
  add    $0x8,%rbx
L2:
  lea    0x10(%rsp),%rdi
  mov    0x8(%rsp),%rdx
  mov    $0x100,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L38
  cmp    %ebp,%r15d
  jne    L18
  add    $0x14,%r15d
  lea    0x0(,%r15,4),%esi
  mov    (%r12),%rdi
  call   <realloc@plt>
  mov    %rax,(%r12)
  jmp    L18
L38:
  lea    0x0(,%rbp,4),%esi
  mov    (%r12),%rdi
  call   <realloc@plt>
  mov    %rax,(%r12)
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %ebp,%eax
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
data_type: string

tool: D9:  

assistant: ```c
int read_stubs(FILE *filein, unsigned int **S) {
  int size, K;
  char buff[256];
  char *ptr;
  K = 0;
  size = 20;
  *S = malloc(size * sizeof(unsigned int));
  while (fgets(buff, 256, filein)) {
    if (K == size) {
      size += 20;
      *S = realloc(*S, size * sizeof(unsigned int));
    }
    ptr = strtok(buff, " ");
    (*S)[K++] = atoi(ptr);
    ptr = strtok(NULL, " ");
    (*S)[K++] = atoi(ptr);
  }
  *S = realloc(*S, K * sizeof(unsigned int));
  return K;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_stubs>:
  endbr64
  push   %r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x128,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x50,%edi
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movl   $0x14,0x4(%rsp)
  mov    %rax,0x0(%rbp)
  jmp    L20
  nopl   0x0(%rax)
L2:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x2,%r12d
  call   <strtok@plt>
  mov    0x0(%rbp),%r15
  mov    %rax,%rdi
  call   <atoi@plt>
  add    %rbx,%r15
  mov    %r14,%rsi
  xor    %edi,%edi
  mov    %eax,(%r15)
  call   <strtok@plt>
  mov    %rax,%rdi
  mov    0x0(%rbp),%rax
  lea    0x4(%rax,%rbx,1),%r15
  add    $0x8,%rbx
  call   <atoi@plt>
  mov    %eax,(%r15)
L20:
  mov    0x8(%rsp),%rdx
  mov    $0x100,%esi
  mov    %r13,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L47
  cmp    %r12d,0x4(%rsp)
  jne    L2
  addl   $0x14,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    0x0(%rbp),%rdi
  lea    0x0(,%rax,4),%esi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  jmp    L2
L47:
  mov    0x0(%rbp),%rdi
  lea    0x0(,%r12,4),%esi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x128,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3:  

assistant: ```c
int read_stubs(FILE *filein, unsigned int **S) {
  int size, K;
  char buff[256];
  char *ptr;
  K = 0;
  size = 20;
  *S = malloc(size * sizeof(unsigned int));
  while (fgets(buff, 256, filein)) {
    if (K == size) {
      size += 20;
      *S = realloc(*S, size * sizeof(unsigned int));
    }
    ptr = strtok(buff, " ");
    (*S)[K++] = atoi(ptr);
    ptr = strtok(NULL, " ");
    (*S)[K++] = atoi(ptr);
  }
  *S = realloc(*S, K * sizeof(unsigned int));
  return K;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_stubs>:
  endbr64
  push   %r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x128,%rsp
  mov    %rdi,0x8(%rsp)
  mov    $0x50,%edi
  lea    0x10(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movl   $0x14,0x4(%rsp)
  mov    %rax,0x0(%rbp)
  jmp    L23
  nopl   0x0(%rax)
L25:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x2,%r12d
  call   <strtok@plt>
  mov    0x0(%rbp),%r15
  mov    %rax,%rdi
  call   <atoi@plt>
  add    %rbx,%r15
  mov    %r14,%rsi
  xor    %edi,%edi
  mov    %eax,(%r15)
  call   <strtok@plt>
  mov    %rax,%rdi
  mov    0x0(%rbp),%rax
  lea    0x4(%rax,%rbx,1),%r15
  add    $0x8,%rbx
  call   <atoi@plt>
  mov    %eax,(%r15)
L23:
  mov    0x8(%rsp),%rdx
  mov    $0x100,%esi
  mov    %r13,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L42
  cmp    %r12d,0x4(%rsp)
  jne    L25
  addl   $0x14,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    0x0(%rbp),%rdi
  lea    0x0(,%rax,4),%esi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  jmp    L25
L42:
  mov    0x0(%rbp),%rdi
  lea    0x0(,%r12,4),%esi
  call   <realloc@plt>
  mov    %rax,0x0(%rbp)
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x128,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3:  

assistant: ```c
int read_stubs(FILE *filein, unsigned int **S) {
  int size, K;
  char buff[256];
  char *ptr;
  K = 0;
  size = 20;
  *S = malloc(size * sizeof(unsigned int));
  while (fgets(buff, 256, filein)) {
    if (K == size) {
      size += 20;
      *S = realloc(*S, size * sizeof(unsigned int));
    }
    ptr = strtok(buff, " ");
    (*S)[K++] = atoi(ptr);
    ptr = strtok(NULL, " ");
    (*S)[K++] = atoi(ptr);
  }
  *S = realloc(*S, K * sizeof(unsigned int));
  return K;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<resume>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: Resume: %s


assistant: ```c
void resume(void *m) {
  char *msg = m;
  printf("Resume: %s\n", msg);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<resume>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: Resume: %s


assistant: ```c
void resume(void *m) {
  char *msg = m;
  printf("Resume: %s\n", msg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resume>:
  endbr64
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: Resume: %s


assistant: ```c
void resume(void *m) {
  char *msg = m;
  printf("Resume: %s\n", msg);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<resume>:
  endbr64
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type: string

tool: D5: Resume: %s


assistant: ```c
void resume(void *m) {
  char *msg = m;
  printf("Resume: %s\n", msg);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isLeapYear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L34
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L35
L34:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L16
L35:
  mov    $0x1,%eax
  jmp    L21
L16:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int isLeapYear(const int year) {
  if (((year % 100 == 0) && (year % 4 == 0)) || year % 400 == 0) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isLeapYear>:
  endbr64
  mov    %edi,%ecx
  and    $0x3,%ecx
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  imul   $0x64,%eax,%eax
  mov    %edi,%esi
  sub    %eax,%esi
  mov    $0x1,%eax
  or     %esi,%ecx
  je     L3
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edi
  sete   %al
  movzbl %al,%eax
L3:
  ret
```

assistant: ```c
int isLeapYear(const int year) {
  if (((year % 100 == 0) && (year % 4 == 0)) || year % 400 == 0) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<isLeapYear>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edi,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%ecx
  and    $0x3,%edx
  sar    $0x25,%rax
  sub    %ecx,%eax
  mov    %edi,%ecx
  imul   $0x64,%eax,%eax
  sub    %eax,%ecx
  mov    $0x1,%eax
  or     %ecx,%edx
  je     L2
  imul   $0xc28f5c29,%edi,%edi
  xor    %eax,%eax
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70a,%edi
  setbe  %al
L2:
  ret
```

assistant: ```c
int isLeapYear(const int year) {
  if (((year % 100 == 0) && (year % 4 == 0)) || year % 400 == 0) {
    return 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isLeapYear>:
  endbr64
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edi,%edx
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%ecx
  and    $0x3,%edx
  sar    $0x25,%rax
  sub    %ecx,%eax
  mov    %edi,%ecx
  imul   $0x64,%eax,%eax
  sub    %eax,%ecx
  mov    $0x1,%eax
  or     %ecx,%edx
  je     L2
  imul   $0xc28f5c29,%edi,%edi
  xor    %eax,%eax
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70a,%edi
  setbe  %al
L2:
  ret
```

assistant: ```c
int isLeapYear(const int year) {
  if (((year % 100 == 0) && (year % 4 == 0)) || year % 400 == 0) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L27
L19:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  shr    $0x1e,%rax
  and    $0x3,%eax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  shlq   $0x2,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L15
  mov    -0x10(%rbp),%rax
  sub    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L15:
  addl   $0x1,-0x24(%rbp)
L27:
  cmpl   $0x1f,-0x24(%rbp)
  jle    L19
  lea    -0x20(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
void usqrt(unsigned long x, struct int_sqrt *q) {
  unsigned long a = 0L;
  unsigned long r = 0L;
  unsigned long e = 0L;
  int i;
  for (i = 0; i < 32; i++) {
    r = (r << 2) + ((x & (3L << (32 - 2))) >> (32 - 2));
    x <<= 2;
    a <<= 1;
    e = (a << 1) + 1;
    if (r >= e) {
      r -= e;
      a++;
    }
  }
  memcpy(q, &a, sizeof(long));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usqrt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x20,%esi
  mov    $0x0,%ecx
  jmp    L33
L20:
  sub    $0x1,%esi
  je     L36
L33:
  mov    %r8,%rdx
  shr    $0x1e,%rdx
  and    $0x3,%edx
  lea    (%rdx,%rax,4),%rax
  shl    $0x2,%r8
  lea    (%rcx,%rcx,1),%rdx
  lea    0x1(,%rcx,4),%r9
  mov    %rdx,%rcx
  cmp    %r9,%rax
  jb     L20
  sub    %r9,%rax
  lea    0x1(%rdx),%rcx
  jmp    L20
L36:
  mov    %rcx,(%rsp)
  mov    %rsp,%rsi
  mov    $0x8,%edx
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void usqrt(unsigned long x, struct int_sqrt *q) {
  unsigned long a = 0L;
  unsigned long r = 0L;
  unsigned long e = 0L;
  int i;
  for (i = 0; i < 32; i++) {
    r = (r << 2) + ((x & (3L << (32 - 2))) >> (32 - 2));
    x <<= 2;
    a <<= 1;
    e = (a << 1) + 1;
    if (r >= e) {
      r -= e;
      a++;
    }
  }
  memcpy(q, &a, sizeof(long));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<usqrt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  xor    %edx,%edx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x20,%esi
  nopl   (%rax)
L15:
  mov    %r8,%rcx
  shl    $0x2,%r8
  shr    $0x1e,%rcx
  and    $0x3,%ecx
  lea    (%rcx,%rdx,4),%rdx
  lea    0x1(,%rax,4),%rcx
  add    %rax,%rax
  cmp    %rcx,%rdx
  jb     L29
  sub    %rcx,%rdx
  add    $0x1,%rax
L29:
  sub    $0x1,%esi
  jne    L15
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void usqrt(unsigned long x, struct int_sqrt *q) {
  unsigned long a = 0L;
  unsigned long r = 0L;
  unsigned long e = 0L;
  int i;
  for (i = 0; i < 32; i++) {
    r = (r << 2) + ((x & (3L << (32 - 2))) >> (32 - 2));
    x <<= 2;
    a <<= 1;
    e = (a << 1) + 1;
    if (r >= e) {
      r -= e;
      a++;
    }
  }
  memcpy(q, &a, sizeof(long));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usqrt>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  xor    %edx,%edx
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x20,%esi
  nopl   (%rax)
L14:
  mov    %r8,%rcx
  shl    $0x2,%r8
  shr    $0x1e,%rcx
  and    $0x3,%ecx
  lea    (%rcx,%rdx,4),%rdx
  lea    0x1(,%rax,4),%rcx
  add    %rax,%rax
  cmp    %rdx,%rcx
  ja     L17
  sub    %rcx,%rdx
  add    $0x1,%rax
L17:
  sub    $0x1,%esi
  jne    L14
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,(%rsp)
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void usqrt(unsigned long x, struct int_sqrt *q) {
  unsigned long a = 0L;
  unsigned long r = 0L;
  unsigned long e = 0L;
  int i;
  for (i = 0; i < 32; i++) {
    r = (r << 2) + ((x & (3L << (32 - 2))) >> (32 - 2));
    x <<= 2;
    a <<= 1;
    e = (a << 1) + 1;
    if (r >= e) {
      r -= e;
      a++;
    }
  }
  memcpy(q, &a, sizeof(long));
}
```