ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rotate_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x20,%eax
  sub    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  and    %ecx,%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotate_left>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  sete   %dl
  movzbl %dl,%edx
  lea    -0x1(%rdx),%eax
  mov    %edi,%esi
  rol    %cl,%esi
  and    %esi,%eax
  neg    %edx
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rotate_left>:
  endbr64
  xor    %edx,%edx
  test   %esi,%esi
  mov    %esi,%ecx
  mov    %edi,%esi
  sete   %dl
  rol    %cl,%esi
  lea    -0x1(%rdx),%eax
  neg    %edx
  and    %esi,%eax
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rotate_left>:
  endbr64
  xor    %edx,%edx
  test   %esi,%esi
  mov    %esi,%ecx
  mov    %edi,%esi
  sete   %dl
  rol    %cl,%esi
  lea    -0x1(%rdx),%eax
  neg    %edx
  and    %esi,%eax
  and    %edi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned rotate_left(unsigned x, unsigned n) {
  int z_mask = -!n;
  unsigned left = x << n;
  unsigned right = x >> ((sizeof(unsigned) << 3) - n);
  return (z_mask & x) | (~z_mask & (left | right));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<minmax_d>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  cmp    $0x1,%esi
  je     L112
  movsd  (%rdi),%xmm0
  movsd  0x8(%rdi),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L44
  jne    L44
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
L52:
  lea    -0x1(%r9),%eax
  cmp    $0x2,%eax
  jle    L8
  cltq
  lea    0x0(,%rax,8),%rsi
  lea    (%r8,%rsi,1),%rax
  lea    -0x10(%r8,%rsi,1),%rdi
  lea    -0x4(%r9),%esi
  shr    %esi
  mov    %esi,%esi
  shl    $0x4,%rsi
  sub    %rsi,%rdi
  jmp    L20
L112:
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
  ret
L44:
  comisd %xmm0,%xmm1
  jbe    L55
  movsd  %xmm0,(%rdx)
  movsd  0x8(%r8),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L52
L55:
  movsd  %xmm1,(%rdx)
  movsd  (%r8),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L52
L64:
  comisd (%rcx),%xmm0
  jbe    L19
  movsd  %xmm0,(%rcx)
L19:
  movsd  (%rsi),%xmm0
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L94
  movsd  %xmm0,(%rdx)
L94:
  sub    $0x10,%rax
  cmp    %rdi,%rax
  je     L8
L20:
  mov    %rax,%rsi
  movsd  (%rax),%xmm1
  movsd  -0x8(%rax),%xmm0
  comisd %xmm0,%xmm1
  jb     L64
  comisd (%rcx),%xmm1
  jbe    L97
  movsd  %xmm1,(%rcx)
L97:
  movsd  -0x8(%rsi),%xmm0
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L94
  movsd  %xmm0,(%rdx)
  jmp    L94
L8:
  test   $0x1,%r9b
  je     L131
  movsd  0x10(%r8),%xmm0
  comisd (%rcx),%xmm0
  jbe    L131
  movsd  %xmm0,(%rcx)
L131:
  movsd  0x10(%r8),%xmm0
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L26
  movsd  %xmm0,(%rdx)
L26:
  ret
```

assistant: ```c
void minmax_d(double a[], int n, double *min, double *max) {
  int i;
  if (n == 1) {
    *min = *max = a[0];
    return;
  }
  if (a[0] == a[1])
    *min = *max = a[0];
  else if (a[0] < a[1]) {
    *min = a[0];
    *max = a[1];
  } else {
    *min = a[1];
    *max = a[0];
  }
  for (i = n - 1; i > 2; i -= 2) {
    if (a[i] >= a[i - 1]) {
      if (*max < a[i])
        *max = a[i];
      if (*min > a[i - 1])
        *min = a[i - 1];
    } else {
      if (*max < a[i - 1])
        *max = a[i - 1];
      if (*min > a[i])
        *min = a[i];
    }
  }
  if (n % 2)
    if (*max < a[2])
      *max = a[2];
  if (*min > a[2])
    *min = a[2];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minmax_d>:
  endbr64
  movsd  (%rdi),%xmm0
  mov    %esi,%r8d
  cmp    $0x1,%esi
  je     L105
  movsd  0x8(%rdi),%xmm1
  ucomisd %xmm0,%xmm1
  jp     L104
  jne    L104
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
L178:
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jle    L116
  cltq
  lea    -0x4(%r8),%r9d
  lea    0x0(,%rax,8),%rsi
  shr    %r9d
  lea    (%rdi,%rsi,1),%rax
  shl    $0x4,%r9
  lea    -0x10(%rdi,%rsi,1),%rsi
  sub    %r9,%rsi
  jmp    L129
  nopl   0x0(%rax)
L136:
  comisd %xmm2,%xmm0
  jbe    L134
  movsd  %xmm0,(%rcx)
  movsd  -0x8(%rax),%xmm1
L134:
  movsd  (%rdx),%xmm0
  comisd %xmm1,%xmm0
  jbe    L74
  movsd  %xmm1,(%rdx)
L74:
  sub    $0x10,%rax
  cmp    %rax,%rsi
  je     L116
L129:
  movsd  (%rax),%xmm0
  movsd  -0x8(%rax),%xmm1
  movsd  (%rcx),%xmm2
  comisd %xmm1,%xmm0
  jae    L136
  comisd %xmm2,%xmm1
  jbe    L180
  movsd  %xmm1,(%rcx)
  movsd  (%rax),%xmm0
L180:
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L74
  sub    $0x10,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L129
L116:
  and    $0x1,%r8d
  movsd  0x10(%rdi),%xmm0
  je     L11
  comisd (%rcx),%xmm0
  ja     L151
L11:
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L53
  movsd  %xmm0,(%rdx)
L53:
  ret
  cs nopw 0x0(%rax,%rax,1)
L104:
  comisd %xmm0,%xmm1
  jbe    L110
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L178
  nopl   0x0(%rax,%rax,1)
L105:
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax)
L151:
  movsd  %xmm0,(%rcx)
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L110:
  movsd  %xmm1,(%rdx)
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L178
```

assistant: ```c
void minmax_d(double a[], int n, double *min, double *max) {
  int i;
  if (n == 1) {
    *min = *max = a[0];
    return;
  }
  if (a[0] == a[1])
    *min = *max = a[0];
  else if (a[0] < a[1]) {
    *min = a[0];
    *max = a[1];
  } else {
    *min = a[1];
    *max = a[0];
  }
  for (i = n - 1; i > 2; i -= 2) {
    if (a[i] >= a[i - 1]) {
      if (*max < a[i])
        *max = a[i];
      if (*min > a[i - 1])
        *min = a[i - 1];
    } else {
      if (*max < a[i - 1])
        *max = a[i - 1];
      if (*min > a[i])
        *min = a[i];
    }
  }
  if (n % 2)
    if (*max < a[2])
      *max = a[2];
  if (*min > a[2])
    *min = a[2];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minmax_d>:
  endbr64
  movsd  (%rdi),%xmm0
  mov    %esi,%r8d
  cmp    $0x1,%esi
  je     L45
  movsd  0x8(%rdi),%xmm1
  ucomisd %xmm0,%xmm1
  jp     L102
  jne    L102
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
L15:
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jle    L149
  cltq
  lea    -0x4(%r8),%r9d
  lea    0x0(,%rax,8),%rsi
  shr    %r9d
  lea    (%rdi,%rsi,1),%rax
  shl    $0x4,%r9
  lea    -0x10(%rdi,%rsi,1),%rsi
  sub    %r9,%rsi
  jmp    L176
  nopl   0x0(%rax)
L127:
  comisd %xmm2,%xmm0
  jbe    L109
  movsd  %xmm0,(%rcx)
  movsd  -0x8(%rax),%xmm1
L109:
  movsd  (%rdx),%xmm0
  comisd %xmm1,%xmm0
  jbe    L29
  movsd  %xmm1,(%rdx)
L29:
  sub    $0x10,%rax
  cmp    %rax,%rsi
  je     L149
L176:
  movsd  (%rax),%xmm0
  movsd  -0x8(%rax),%xmm1
  movsd  (%rcx),%xmm2
  comisd %xmm1,%xmm0
  jae    L127
  comisd %xmm2,%xmm1
  jbe    L75
  movsd  %xmm1,(%rcx)
  movsd  (%rax),%xmm0
L75:
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L29
  sub    $0x10,%rax
  movsd  %xmm0,(%rdx)
  cmp    %rax,%rsi
  jne    L176
L149:
  and    $0x1,%r8d
  movsd  0x10(%rdi),%xmm0
  je     L95
  comisd (%rcx),%xmm0
  ja     L44
L95:
  movsd  (%rdx),%xmm1
  comisd %xmm0,%xmm1
  jbe    L136
  movsd  %xmm0,(%rdx)
L136:
  ret
  cs nopw 0x0(%rax,%rax,1)
L102:
  comisd %xmm0,%xmm1
  jbe    L133
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
  ret
  nopl   0x0(%rax)
L44:
  movsd  %xmm0,(%rcx)
  jmp    L95
  cs nopw 0x0(%rax,%rax,1)
L133:
  movsd  %xmm1,(%rdx)
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L15
```

assistant: ```c
void minmax_d(double a[], int n, double *min, double *max) {
  int i;
  if (n == 1) {
    *min = *max = a[0];
    return;
  }
  if (a[0] == a[1])
    *min = *max = a[0];
  else if (a[0] < a[1]) {
    *min = a[0];
    *max = a[1];
  } else {
    *min = a[1];
    *max = a[0];
  }
  for (i = n - 1; i > 2; i -= 2) {
    if (a[i] >= a[i - 1]) {
      if (*max < a[i])
        *max = a[i];
      if (*min > a[i - 1])
        *min = a[i - 1];
    } else {
      if (*max < a[i - 1])
        *max = a[i - 1];
      if (*min > a[i])
        *min = a[i];
    }
  }
  if (n % 2)
    if (*max < a[2])
      *max = a[2];
  if (*min > a[2])
    *min = a[2];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__ffs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  xor    %eax,%eax
  bsf    -0x14(%rbp),%edx
  je     L6
  lea    0x1(%edx),%eax
L6:
  mov    %eax,-0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("xorl %0,%0\n"
      "bsfl %2,%1\n"
      "jz 1f\n"
      "leal 1(%1),%0\n"
      "1:"
      : "=&a"(cnt), "=r"(tmp)
      : "rm"(x));
  return cnt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__ffs>:
  endbr64
  xor    %eax,%eax
  bsf    %edi,%edi
  je     L6
  lea    0x1(%edi),%eax
L6:
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("xorl %0,%0\n"
      "bsfl %2,%1\n"
      "jz 1f\n"
      "leal 1(%1),%0\n"
      "1:"
      : "=&a"(cnt), "=r"(tmp)
      : "rm"(x));
  return cnt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__ffs>:
  endbr64
  xor    %eax,%eax
  bsf    %edi,%edi
  je     L2
  lea    0x1(%edi),%eax
L2:
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("xorl %0,%0\n"
      "bsfl %2,%1\n"
      "jz 1f\n"
      "leal 1(%1),%0\n"
      "1:"
      : "=&a"(cnt), "=r"(tmp)
      : "rm"(x));
  return cnt;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__ffs>:
  endbr64
  xor    %eax,%eax
  bsf    %edi,%edi
  je     L7
  lea    0x1(%edi),%eax
L7:
  ret
```

assistant: ```c
int __ffs(x)
int x;
{
  int cnt;
  int tmp;
  asm("xorl %0,%0\n"
      "bsfl %2,%1\n"
      "jz 1f\n"
      "leal 1(%1),%0\n"
      "1:"
      : "=&a"(cnt), "=r"(tmp)
      : "rm"(x));
  return cnt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<inv_fast_sqrt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  mov    $0x0,%ebx
  test   %rdi,%rdi
  jle    L50
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <test_limits_and_scale@plt>
  mov    %eax,%r12d
  mov    0x14(%rsp),%eax
  mov    $0x0,%ebp
  test   %eax,%eax
  jle    L36
  mov    %eax,%edx
  shr    $0x1f,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x1,%ebp
  sub    %edx,%ebp
L36:
  sub    %ebp,%eax
  mov    %eax,0x14(%rsp)
  mov    0x8(%rsp),%rbx
  lea    -0x40000000(%rbx),%r13
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%rbx
  cmp    $0x1,%r12d
  jg     L74
L66:
  test   %ebp,%ebp
  jne    L41
L88:
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jle    L42
  sar    %ecx
  sar    %cl,%rbx
L50:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  mov    %r13,%rsi
  sar    %rsi
  sub    $0x60000000,%rsi
  mov    %r13,%rdi
  call   <inv_q30_mult@plt>
  movslq %eax,%rsi
  mov    %r13,%rdi
  call   <inv_q30_mult@plt>
  sar    %eax
  movslq %eax,%r13
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%rbx
  cmp    $0x3,%r12d
  jne    L66
  mov    %r13,%rsi
  sar    %rsi
  sub    $0x60000000,%rsi
  mov    %r13,%rdi
  call   <inv_q30_mult@plt>
  movslq %eax,%rsi
  mov    %r13,%rdi
  call   <inv_q30_mult@plt>
  sar    %eax
  movslq %eax,%rsi
  mov    %rbx,%rdi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%rbx
  jmp    L66
L41:
  mov    $0x2d413ccd,%esi
  mov    %rbx,%rdi
  call   <inv_q30_mult@plt>
  movslq %eax,%rbx
  jmp    L88
L42:
  cmp    $0xffffffff,%ecx
  jne    L50
  mov    $0x5a82799a,%esi
  mov    %rbx,%rdi
  call   <inv_q30_mult@plt>
  movslq %eax,%rbx
  jmp    L50
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long inv_fast_sqrt(long x0) {
  long sqrt2, oneoversqrt2, one_pt5;
  long xx, cc;
  int pow2, sq2scale, nr_iters;
  if (x0 <= 0L) {
    return 0L;
  }
  sqrt2 = 1518500250L;
  oneoversqrt2 = 759250125L;
  one_pt5 = 1610612736L;
  nr_iters = test_limits_and_scale(&x0, &pow2);
  sq2scale = 0;
  if (pow2 > 0)
    sq2scale = pow2 % 2;
  pow2 = pow2 - sq2scale;
  cc = x0 - (1L << 30);
  xx = x0 - (inv_q30_mult(x0, cc) >> 1);
  if (nr_iters >= 2) {
    cc = inv_q30_mult(cc, inv_q30_mult(cc, (cc >> 1) - one_pt5)) >> 1;
    xx = xx - (inv_q30_mult(xx, cc) >> 1);
    if (nr_iters == 3) {
      cc = inv_q30_mult(cc, inv_q30_mult(cc, (cc >> 1) - one_pt5)) >> 1;
      xx = xx - (inv_q30_mult(xx, cc) >> 1);
    }
  }
  if (sq2scale)
    xx = inv_q30_mult(xx, oneoversqrt2);
  if (pow2 > 0)
    xx = (xx >> (pow2 >> 1));
  else if (pow2 == -1)
    xx = inv_q30_mult(xx, sqrt2);
  return xx;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<inv_fast_sqrt>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %rdi,%rdi
  jle    L48
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  xor    %r13d,%r13d
  call   <test_limits_and_scale@plt>
  mov    %eax,%ebx
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L112
  mov    %eax,%r13d
  and    $0x1,%r13d
  sub    %r13d,%eax
L112:
  mov    0x8(%rsp),%r12
  mov    %eax,0x14(%rsp)
  lea    -0x40000000(%r12),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%r12
  cmp    $0x1,%ebx
  jg     L46
L8:
  test   %r13d,%r13d
  jne    L12
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jle    L18
L99:
  sar    %ecx
  sar    %cl,%r12
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L110
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L46:
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  sar    %rsi
  sub    $0x60000000,%rsi
  call   <inv_q30_mult@plt>
  mov    %rbp,%rdi
  movslq %eax,%rsi
  call   <inv_q30_mult@plt>
  mov    %r12,%rdi
  sar    %eax
  movslq %eax,%rbp
  mov    %rbp,%rsi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%r12
  cmp    $0x3,%ebx
  jne    L8
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  sar    %rsi
  sub    $0x60000000,%rsi
  call   <inv_q30_mult@plt>
  mov    %rbp,%rdi
  movslq %eax,%rsi
  call   <inv_q30_mult@plt>
  mov    %r12,%rdi
  sar    %eax
  movslq %eax,%rsi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%r12
  jmp    L8
  nopl   (%rax)
L18:
  cmp    $0xffffffff,%ecx
  jne    L48
  mov    %r12,%rdi
  mov    $0x5a82799a,%esi
  call   <inv_q30_mult@plt>
  movslq %eax,%r12
  jmp    L48
  xchg   %ax,%ax
L12:
  mov    %r12,%rdi
  mov    $0x2d413ccd,%esi
  call   <inv_q30_mult@plt>
  mov    0x14(%rsp),%ecx
  movslq %eax,%r12
  test   %ecx,%ecx
  jg     L99
  jmp    L18
L110:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long inv_fast_sqrt(long x0) {
  long sqrt2, oneoversqrt2, one_pt5;
  long xx, cc;
  int pow2, sq2scale, nr_iters;
  if (x0 <= 0L) {
    return 0L;
  }
  sqrt2 = 1518500250L;
  oneoversqrt2 = 759250125L;
  one_pt5 = 1610612736L;
  nr_iters = test_limits_and_scale(&x0, &pow2);
  sq2scale = 0;
  if (pow2 > 0)
    sq2scale = pow2 % 2;
  pow2 = pow2 - sq2scale;
  cc = x0 - (1L << 30);
  xx = x0 - (inv_q30_mult(x0, cc) >> 1);
  if (nr_iters >= 2) {
    cc = inv_q30_mult(cc, inv_q30_mult(cc, (cc >> 1) - one_pt5)) >> 1;
    xx = xx - (inv_q30_mult(xx, cc) >> 1);
    if (nr_iters == 3) {
      cc = inv_q30_mult(cc, inv_q30_mult(cc, (cc >> 1) - one_pt5)) >> 1;
      xx = xx - (inv_q30_mult(xx, cc) >> 1);
    }
  }
  if (sq2scale)
    xx = inv_q30_mult(xx, oneoversqrt2);
  if (pow2 > 0)
    xx = (xx >> (pow2 >> 1));
  else if (pow2 == -1)
    xx = inv_q30_mult(xx, sqrt2);
  return xx;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inv_fast_sqrt>:
  endbr64
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %rdi,%rdi
  jle    L27
  lea    0x14(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  xor    %r13d,%r13d
  call   <test_limits_and_scale@plt>
  mov    %eax,%ebx
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L106
  mov    %eax,%r13d
  and    $0x1,%r13d
  sub    %r13d,%eax
L106:
  mov    0x8(%rsp),%r12
  mov    %eax,0x14(%rsp)
  lea    -0x40000000(%r12),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%r12
  cmp    $0x1,%ebx
  jg     L104
L22:
  test   %r13d,%r13d
  jne    L119
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  jle    L3
L100:
  sar    %ecx
  sar    %cl,%r12
L27:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L104:
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  sar    %rsi
  sub    $0x60000000,%rsi
  call   <inv_q30_mult@plt>
  mov    %rbp,%rdi
  movslq %eax,%rsi
  call   <inv_q30_mult@plt>
  mov    %r12,%rdi
  sar    %eax
  movslq %eax,%rbp
  mov    %rbp,%rsi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%r12
  cmp    $0x3,%ebx
  jne    L22
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  sar    %rsi
  sub    $0x60000000,%rsi
  call   <inv_q30_mult@plt>
  mov    %rbp,%rdi
  movslq %eax,%rsi
  call   <inv_q30_mult@plt>
  mov    %r12,%rdi
  sar    %eax
  movslq %eax,%rsi
  call   <inv_q30_mult@plt>
  sar    %eax
  cltq
  sub    %rax,%r12
  jmp    L22
  nopl   (%rax)
L3:
  cmp    $0xffffffff,%ecx
  jne    L27
  mov    %r12,%rdi
  mov    $0x5a82799a,%esi
  call   <inv_q30_mult@plt>
  movslq %eax,%r12
  jmp    L27
  xchg   %ax,%ax
L119:
  mov    %r12,%rdi
  mov    $0x2d413ccd,%esi
  call   <inv_q30_mult@plt>
  mov    0x14(%rsp),%ecx
  movslq %eax,%r12
  test   %ecx,%ecx
  jg     L100
  jmp    L3
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long inv_fast_sqrt(long x0) {
  long sqrt2, oneoversqrt2, one_pt5;
  long xx, cc;
  int pow2, sq2scale, nr_iters;
  if (x0 <= 0L) {
    return 0L;
  }
  sqrt2 = 1518500250L;
  oneoversqrt2 = 759250125L;
  one_pt5 = 1610612736L;
  nr_iters = test_limits_and_scale(&x0, &pow2);
  sq2scale = 0;
  if (pow2 > 0)
    sq2scale = pow2 % 2;
  pow2 = pow2 - sq2scale;
  cc = x0 - (1L << 30);
  xx = x0 - (inv_q30_mult(x0, cc) >> 1);
  if (nr_iters >= 2) {
    cc = inv_q30_mult(cc, inv_q30_mult(cc, (cc >> 1) - one_pt5)) >> 1;
    xx = xx - (inv_q30_mult(xx, cc) >> 1);
    if (nr_iters == 3) {
      cc = inv_q30_mult(cc, inv_q30_mult(cc, (cc >> 1) - one_pt5)) >> 1;
      xx = xx - (inv_q30_mult(xx, cc) >> 1);
    }
  }
  if (sq2scale)
    xx = inv_q30_mult(xx, oneoversqrt2);
  if (pow2 > 0)
    xx = (xx >> (pow2 >> 1));
  else if (pow2 == -1)
    xx = inv_q30_mult(xx, sqrt2);
  return xx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inw>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%ax
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short value;
  __asm__ __volatile__("inw %w1, %0" : "=a"(value) : "Nd"(port));
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short value;
  __asm__ __volatile__("inw %w1, %0" : "=a"(value) : "Nd"(port));
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short value;
  __asm__ __volatile__("inw %w1, %0" : "=a"(value) : "Nd"(port));
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<inw>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%ax
  ret
```

assistant: ```c
unsigned short inw(int port) {
  unsigned short value;
  __asm__ __volatile__("inw %w1, %0" : "=a"(value) : "Nd"(port));
  return value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7c(%rbp)
  jmp    L0
L27:
  mov    -0x78(%rbp),%eax
  mov    %eax,%edx
  mov    -0x7c(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x7c(%rbp)
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x78(%rbp)
  cmpl   $0xa,-0x78(%rbp)
  jne    L27
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x74(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: %d


assistant: ```c
int main(void) {
  char str[100];
  int c, n = 0, len;
  while ((c = getchar()) != '\n') {
    str[n] = c;
    n++;
  }
  len = strlen(str);
  printf("%d\n", len);
  printf("\n");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  jmp    L26
L5:
  mov    %al,(%rbx)
  add    $0x1,%rbx
L26:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L5
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main(void) {
  char str[100];
  int c, n = 0, len;
  while ((c = getchar()) != '\n') {
    str[n] = c;
    n++;
  }
  len = strlen(str);
  printf("%d\n", len);
  printf("\n");
  return (0);
}
```