ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chdtrcf>:
  endbr64
  pxor   %xmm3,%xmm3
  comiss %xmm1,%xmm3
  ja     L18
  movss  D19(%rip),%xmm2
  comiss %xmm0,%xmm2
  ja     L18
  movsd  D13(%rip),%xmm2
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  jmp    1070 <igamcf@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <mtherrf@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D19
data_type: f32
name: read_data
arguments: tag: D13
data_type: f64
name: read_data
arguments: tag: D5
data_type: string

tool: D19: 1

tool: D13: 0.5

tool: D5: chdtrcf

assistant: ```c
float chdtrcf(float dff, float xx) {
  float df, x;
  df = dff;
  x = xx;
  if ((x < 0.0) || (df < 1.0)) {
    mtherrf("chdtrcf", 1);
    return (0.0);
  }
  return (igamcf(0.5 * df, 0.5 * x));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chdtrcf>:
  endbr64
  pxor   %xmm3,%xmm3
  comiss %xmm1,%xmm3
  ja     L14
  movss  D14(%rip),%xmm2
  comiss %xmm0,%xmm2
  ja     L14
  movsd  D19(%rip),%xmm2
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  jmp    1070 <igamcf@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  call   <mtherrf@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type: f32
name: disassemble_data
arguments: data_label: D19
type: f64
name: disassemble_data
arguments: data_label: D18
type: string

tool: D14: 1

tool: D19: 0.5

tool: D18: chdtrcf

assistant: ```c
float chdtrcf(float dff, float xx) {
  float df, x;
  df = dff;
  x = xx;
  if ((x < 0.0) || (df < 1.0)) {
    mtherrf("chdtrcf", 1);
    return (0.0);
  }
  return (igamcf(0.5 * df, 0.5 * x));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D27(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L29:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L33
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L33:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  cmpl   $0x1,-0xc(%rbp)
  jg     L14
  mov    $0x2e,%edi
  call   <putchar@plt>
L14:
  addl   $0x1,-0xc(%rbp)
L38:
  cmpl   $0x2,-0xc(%rbp)
  jle    L29
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type: string
name: extract_symbolic_data
arguments: data_tag: D20
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string

tool: D27: 000102

tool: D20: gln_index, version 

tool: D16:  by Scott Vokes

assistant: ```c
void version() {
  int i;
  char *v = "000102";
  printf("gln_index, version ");
  for (i = 0; i < 3; i++) {
    if (v[2 * i] != '0')
      printf("%c", v[2 * i]);
    printf("%c", v[2 * i + 1]);
    if (i < 2)
      printf(".");
  }
  printf(" by Scott Vokes\n");
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<version>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rbx
  mov    $0x1,%ebp
  jmp    L11
L0:
  add    $0x2,%rbx
  add    $0x1,%ebp
L11:
  mov    %rbx,%r12
  movsbl 0x1(%rbx),%edi
  call   <putchar@plt>
  lea    -0x1(%rbp),%eax
  cmp    $0x1,%eax
  jg     L20
  mov    $0x2e,%edi
  call   <putchar@plt>
L8:
  movzbl 0x2(%r12),%edi
  cmp    $0x30,%dil
  je     L0
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L0
L20:
  cmp    $0x2,%ebp
  jle    L8
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string
name: retrieve_data
arguments: label: D20
type_infered: string
name: retrieve_data
arguments: label: D23
type_infered: string

tool: D5: gln_index, version 

tool: D20: 000102

tool: D23:  by Scott Vokes

assistant: ```c
void version() {
  int i;
  char *v = "000102";
  printf("gln_index, version ");
  for (i = 0; i < 3; i++) {
    if (v[2 * i] != '0')
      printf("%c", v[2 * i]);
    printf("%c", v[2 * i + 1]);
    if (i < 2)
      printf(".");
  }
  printf(" by Scott Vokes\n");
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x32,%edi
  call   <putchar@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D9
type: string

tool: D4: gln_index, version 

tool: D9:  by Scott Vokes

assistant: ```c
void version() {
  int i;
  char *v = "000102";
  printf("gln_index, version ");
  for (i = 0; i < 3; i++) {
    if (v[2 * i] != '0')
      printf("%c", v[2 * i]);
    printf("%c", v[2 * i + 1]);
    if (i < 2)
      printf(".");
  }
  printf(" by Scott Vokes\n");
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<version>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    $0x2e,%edi
  call   <putchar@plt>
  mov    $0x32,%edi
  call   <putchar@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D5
type: string

tool: D4: gln_index, version 

tool: D5:  by Scott Vokes

assistant: ```c
void version() {
  int i;
  char *v = "000102";
  printf("gln_index, version ");
  for (i = 0; i < 3; i++) {
    if (v[2 * i] != '0')
      printf("%c", v[2 * i]);
    printf("%c", v[2 * i + 1]);
    if (i < 2)
      printf(".");
  }
  printf(" by Scott Vokes\n");
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_realloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mf__mem_realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mem_realloc(void *ptr, size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_realloc(ptr, size);
  ;
  return (r_ptr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mem_realloc>:
  endbr64
  sub    $0x8,%rsp
  call   <mf__mem_realloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *mem_realloc(void *ptr, size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_realloc(ptr, size);
  ;
  return (r_ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mem_realloc>:
  endbr64
  jmp    1050 <mf__mem_realloc@plt>
```

assistant: ```c
void *mem_realloc(void *ptr, size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_realloc(ptr, size);
  ;
  return (r_ptr);
}
```
user: What is the c source code of the assembly code below:

```asm
<mem_realloc>:
  endbr64
  jmp    1050 <mf__mem_realloc@plt>
```

assistant: ```c
void *mem_realloc(void *ptr, size_t size) {
  void *r_ptr = NULL;
  ;
  r_ptr = mf__mem_realloc(ptr, size);
  ;
  return (r_ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_mat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L5:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_vet@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D4: {

tool: D26: 
	

tool: D0: 
}


assistant: ```c
void print_mat(double **mat, int m, int n) {
  int i;
  printf("{");
  for (i = 0; i < m; i++) {
    printf("\n\t");
    print_vet(mat[i], n);
  }
  printf("\n}\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_mat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%ebp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L13
  mov    %r13,%rbx
  lea    -0x1(%r12),%eax
  lea    0x8(%r13,%rax,8),%r13
  lea    D25(%rip),%r12
L2:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    (%rbx),%rdi
  call   <print_vet@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L2
L13:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_infered: string
name: extract_symbolic_data
arguments: tag: D25
type_infered: string
name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D19: {

tool: D25: 
	

tool: D8: 
}


assistant: ```c
void print_mat(double **mat, int m, int n) {
  int i;
  printf("{");
  for (i = 0; i < m; i++) {
    printf("\n\t");
    print_vet(mat[i], n);
  }
  printf("\n}\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_mat>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L10
  lea    -0x1(%r12),%eax
  lea    D16(%rip),%r12
  lea    0x8(%rbx,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rdi
  mov    %ebp,%esi
  call   <print_vet@plt>
  cmp    %r13,%rbx
  jne    L15
L10:
  add    $0x8,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string
name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string

tool: D6: {

tool: D16: 
	

tool: D9: 
}


assistant: ```c
void print_mat(double **mat, int m, int n) {
  int i;
  printf("{");
  for (i = 0; i < m; i++) {
    printf("\n\t");
    print_vet(mat[i], n);
  }
  printf("\n}\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_mat>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L7
  lea    -0x1(%r12),%eax
  lea    D3(%rip),%r12
  lea    0x8(%rbx,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rdi
  mov    %ebp,%esi
  call   <print_vet@plt>
  cmp    %r13,%rbx
  jne    L10
L7:
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string

tool: D6: {

tool: D3: 
	

tool: D0: 
}


assistant: ```c
void print_mat(double **mat, int m, int n) {
  int i;
  printf("{");
  for (i = 0; i < m; i++) {
    printf("\n\t");
    print_vet(mat[i], n);
  }
  printf("\n}\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <settask@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x7,%esi
  mov    %eax,%edi
  call   <testtask@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <clrtask@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x7,%esi
  mov    %eax,%edi
  call   <testtask@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D26
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string
name: unpack_data
arguments: label: D35
type_guessed: string

tool: D26: set task %x


tool: D7: test task %x


tool: D35: clear task %x


assistant: ```c
int main(void) {
  unsigned int set = 0;
  settask(&set, 7);
  printf("set task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  clrtask(&set, 7);
  printf("clear task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <settask@plt>
  mov    0x4(%rsp),%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    0x4(%rsp),%edi
  call   <testtask@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  call   <clrtask@plt>
  mov    0x4(%rsp),%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    0x4(%rsp),%edi
  call   <testtask@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D29
data_type: string
name: parse_data
arguments: label: D25
data_type: string

tool: D13: set task %x


tool: D29: test task %x


tool: D25: clear task %x


assistant: ```c
int main(void) {
  unsigned int set = 0;
  settask(&set, 7);
  printf("set task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  clrtask(&set, 7);
  printf("clear task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  lea    D13(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  movl   $0x0,0x4(%rsp)
  mov    %r12,%rdi
  call   <settask@plt>
  mov    0x4(%rsp),%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x7,%esi
  call   <testtask@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %r12,%rdi
  call   <clrtask@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x7,%esi
  call   <testtask@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D18
datatype: string
name: parse_data
arguments: tag: D27
datatype: string

tool: D13: test task %x


tool: D18: set task %x


tool: D27: clear task %x


assistant: ```c
int main(void) {
  unsigned int set = 0;
  settask(&set, 7);
  printf("set task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  clrtask(&set, 7);
  printf("clear task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7,%esi
  push   %rbp
  lea    D22(%rip),%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  movl   $0x0,0x4(%rsp)
  mov    %r12,%rdi
  call   <settask@plt>
  mov    0x4(%rsp),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x7,%esi
  call   <testtask@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %r12,%rdi
  call   <clrtask@plt>
  mov    0x4(%rsp),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  mov    $0x7,%esi
  call   <testtask@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D26
type_guessed: string
name: retrieve_data
arguments: tag: D21
type_guessed: string

tool: D22: test task %x


tool: D26: set task %x


tool: D21: clear task %x


assistant: ```c
int main(void) {
  unsigned int set = 0;
  settask(&set, 7);
  printf("set task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  clrtask(&set, 7);
  printf("clear task %x\n", set);
  printf("test task %x\n", testtask(set, 7));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<func_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L10
L2:
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L10:
  cmpl   $0x7,-0x34(%rbp)
  jle    L2
  mov    $0x1,%edi
  call   <step_hash@plt>
  mov    -0x2c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
signed char func_1(void) {
  int l_2[8];
  int i;
  for (i = 0; i < 8; i++)
    l_2[i] = 0L;
  step_hash(1);
  return l_2[1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func_1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <step_hash@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed char func_1(void) {
  int l_2[8];
  int i;
  for (i = 0; i < 8; i++)
    l_2[i] = 0L;
  step_hash(1);
  return l_2[1];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func_1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <step_hash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed char func_1(void) {
  int l_2[8];
  int i;
  for (i = 0; i < 8; i++)
    l_2[i] = 0L;
  step_hash(1);
  return l_2[1];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func_1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <step_hash@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed char func_1(void) {
  int l_2[8];
  int i;
  for (i = 0; i < 8; i++)
    l_2[i] = 0L;
  step_hash(1);
  return l_2[1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mat_mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L32:
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L0
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mat_mult(double **src1, double **src2, double **dest, int m, int n) {
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      dest[i][j] = src1[i][j] * src2[i][j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mat_mult>:
  endbr64
  test   %ecx,%ecx
  jle    L8
  push   %rbx
  mov    %r8d,%ebx
  mov    %rsi,%r8
  mov    %rdx,%r9
  lea    -0x1(%rcx),%edx
  lea    0x8(%rdi,%rdx,8),%r11
  lea    -0x1(%rbx),%eax
  lea    0x8(,%rax,8),%r10
  jmp    L39
L16:
  mov    (%r9),%rdx
  mov    (%rdi),%rsi
  mov    (%r8),%rcx
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rcx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %r10,%rax
  jne    L16
L27:
  add    $0x8,%rdi
  add    $0x8,%r8
  add    $0x8,%r9
  cmp    %r11,%rdi
  je     L55
L39:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L16
  jmp    L27
L55:
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void mat_mult(double **src1, double **src2, double **dest, int m, int n) {
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      dest[i][j] = src1[i][j] * src2[i][j];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mat_mult>:
  endbr64
  test   %ecx,%ecx
  jle    L11
  push   %rbp
  mov    %rdi,%r11
  mov    %rdx,%rbp
  movslq %ecx,%r10
  push   %rbx
  xor    %r9d,%r9d
  mov    %rsi,%rbx
  movslq %r8d,%rdi
  nopl   0x0(%rax)
L39:
  test   %r8d,%r8d
  jle    L21
  mov    (%r11,%r9,8),%rsi
  mov    (%rbx,%r9,8),%rcx
  xor    %eax,%eax
  mov    0x0(%rbp,%r9,8),%rdx
  nopl   0x0(%rax)
L20:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L20
L21:
  add    $0x1,%r9
  cmp    %r10,%r9
  jne    L39
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

assistant: ```c
void mat_mult(double **src1, double **src2, double **dest, int m, int n) {
  int i;
  int j;
  for (i = 0; i < m; i++)
    for (j = 0; j < n; j++)
      dest[i][j] = src1[i][j] * src2[i][j];
}
```