ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_186_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%edx
  not    %edx
  and    %esi,%edx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  mov    %edx,%ecx
  or     $0xff,%cl
  and    %ecx,%eax
  movzbl %dl,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_186_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_186_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  not    %edx
  or     %eax,%esi
  and    %esi,%edx
  mov    %esi,%eax
  mov    %edx,%ecx
  not    %eax
  movzbl %dl,%edx
  or     %edi,%eax
  or     $0xff,%cl
  and    %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_186_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_186_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  not    %edx
  or     %eax,%esi
  and    %esi,%edx
  mov    %esi,%eax
  mov    %edx,%ecx
  not    %eax
  movzbl %dl,%edx
  or     %edi,%eax
  or     $0xff,%cl
  and    %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_186_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allocChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *allocChar(int maxLen) {
  char *string = (char *)malloc(sizeof(char) * maxLen);
  return string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<allocChar>:
  endbr64
  sub    $0x8,%rsp
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *allocChar(int maxLen) {
  char *string = (char *)malloc(sizeof(char) * maxLen);
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<allocChar>:
  endbr64
  jmp    1050 <malloc@plt>
```

assistant: ```c
char *allocChar(int maxLen) {
  char *string = (char *)malloc(sizeof(char) * maxLen);
  return string;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_num_month>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rcx
  lea    -0xd(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x9(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x5(%rax),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0xe(%rbp)
  lea    -0xd(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  imul   $0x64,%eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int get_num_month(char *date) {
  char year[5];
  char month[3];
  int iyear, imonth;
  strncpy(year, date, 4);
  year[4] = '\0';
  strncpy(month, date + 5, 2);
  month[2] = '\0';
  iyear = atoi(year);
  imonth = atoi(month);
  return (iyear * 100 + imonth);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_num_month>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  mov    $0x4,%edx
  mov    %rdi,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x7(%rsp)
  lea    0x5(%rbx),%rsi
  mov    %rsp,%rbp
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x2(%rsp)
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <atoi@plt>
  imul   $0x64,%ebx,%ebx
  add    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_num_month(char *date) {
  char year[5];
  char month[3];
  int iyear, imonth;
  strncpy(year, date, 4);
  year[4] = '\0';
  strncpy(month, date + 5, 2);
  month[2] = '\0';
  iyear = atoi(year);
  imonth = atoi(month);
  return (iyear * 100 + imonth);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_num_month>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x4,%edx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  mov    %rsp,%rbp
  mov    %r12,%rdi
  call   <strncpy@plt>
  lea    0x5(%rbx),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strncpy@plt>
  mov    %r12,%rdi
  movb   $0x0,0x2(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  imul   $0x64,%ebx,%ebx
  add    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_num_month(char *date) {
  char year[5];
  char month[3];
  int iyear, imonth;
  strncpy(year, date, 4);
  year[4] = '\0';
  strncpy(month, date + 5, 2);
  month[2] = '\0';
  iyear = atoi(year);
  imonth = atoi(month);
  return (iyear * 100 + imonth);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_num_month>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x4,%edx
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rsp),%r12
  mov    %rsp,%rbp
  mov    %r12,%rdi
  call   <strncpy@plt>
  lea    0x5(%rbx),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strncpy@plt>
  mov    %r12,%rdi
  movb   $0x0,0x2(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <atoi@plt>
  imul   $0x64,%ebx,%ebx
  add    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_num_month(char *date) {
  char year[5];
  char month[3];
  int iyear, imonth;
  strncpy(year, date, 4);
  year[4] = '\0';
  strncpy(month, date + 5, 2);
  month[2] = '\0';
  iyear = atoi(year);
  imonth = atoi(month);
  return (iyear * 100 + imonth);
}
```
user: Translate the below assembly code into C programming language:

```asm
<page_getfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <validptr@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L11
  mov    -0x4(%rbp),%eax
  jmp    L36
L11:
  addl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L15
  mov    $0xffffffff,%eax
L36:
  leave
  ret
```

assistant: ```c
int page_getfree(int pages[]) {
  int i;
  int rv;
  int rv2;
  for (i = 0; i < 1000; i++) {
    validptr(pages + i);
    if (pages[i] == 0) {
      return i;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<page_getfree>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L15:
  mov    %rbx,%rdi
  call   <validptr@plt>
  cmpl   $0x0,(%rbx)
  je     L18
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    $0x3e8,%ebp
  jne    L15
  mov    $0xffffffff,%ebp
L18:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int page_getfree(int pages[]) {
  int i;
  int rv;
  int rv2;
  for (i = 0; i < 1000; i++) {
    validptr(pages + i);
    if (pages[i] == 0) {
      return i;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<page_getfree>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    $0x3e8,%r12d
  je     L6
L23:
  mov    %rbx,%rdi
  call   <validptr@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L18
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int page_getfree(int pages[]) {
  int i;
  int rv;
  int rv2;
  for (i = 0; i < 1000; i++) {
    validptr(pages + i);
    if (pages[i] == 0) {
      return i;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<page_getfree>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12d
  add    $0x4,%rbx
  cmp    $0x3e8,%r12d
  je     L0
L9:
  mov    %rbx,%rdi
  call   <validptr@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L19
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int page_getfree(int pages[]) {
  int i;
  int rv;
  int rv2;
  for (i = 0; i < 1000; i++) {
    validptr(pages + i);
    if (pages[i] == 0) {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<expVecTimesPlusAccum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x30(%rbp),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  addsd  %xmm2,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void expVecTimesPlusAccum(int dim, double p1, const double *restrict v1, double p2, const double *restrict v2, double *restrict pacc, double *restrict vacc) {
  *pacc += p1 * p2;
  for (int i = 0; i < dim; ++i) {
    vacc[i] += (p2 * v1[i]) + (p1 * v2[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expVecTimesPlusAccum>:
  endbr64
  mov    %edi,%eax
  mov    %rdx,%rdi
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  (%rcx),%xmm2
  movsd  %xmm2,(%rcx)
  test   %eax,%eax
  jle    L0
  mov    %eax,%edx
  mov    $0x0,%eax
L3:
  movapd %xmm1,%xmm2
  mulsd  (%rsi,%rax,8),%xmm2
  movapd %xmm0,%xmm3
  mulsd  (%rdi,%rax,8),%xmm3
  addsd  %xmm3,%xmm2
  addsd  (%r8,%rax,8),%xmm2
  movsd  %xmm2,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L3
L0:
  ret
```

assistant: ```c
void expVecTimesPlusAccum(int dim, double p1, const double *restrict v1, double p2, const double *restrict v2, double *restrict pacc, double *restrict vacc) {
  *pacc += p1 * p2;
  for (int i = 0; i < dim; ++i) {
    vacc[i] += (p2 * v1[i]) + (p1 * v2[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<expVecTimesPlusAccum>:
  endbr64
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  addsd  (%rcx),%xmm2
  movsd  %xmm2,(%rcx)
  test   %edi,%edi
  jle    L14
  movslq %edi,%rcx
  xor    %eax,%eax
  nopl   (%rax)
L13:
  movsd  (%rsi,%rax,8),%xmm2
  movsd  (%rdx,%rax,8),%xmm3
  mulsd  %xmm1,%xmm2
  mulsd  %xmm0,%xmm3
  addsd  %xmm3,%xmm2
  addsd  (%r8,%rax,8),%xmm2
  movsd  %xmm2,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L13
L14:
  ret
```

assistant: ```c
void expVecTimesPlusAccum(int dim, double p1, const double *restrict v1, double p2, const double *restrict v2, double *restrict pacc, double *restrict vacc) {
  *pacc += p1 * p2;
  for (int i = 0; i < dim; ++i) {
    vacc[i] += (p2 * v1[i]) + (p1 * v2[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<expVecTimesPlusAccum>:
  endbr64
  movapd %xmm0,%xmm2
  mov    %edi,%r9d
  mov    %rdx,%rdi
  mulsd  %xmm1,%xmm2
  addsd  (%rcx),%xmm2
  movsd  %xmm2,(%rcx)
  test   %r9d,%r9d
  jle    L10
  cmp    $0x1,%r9d
  je     L25
  mov    %r9d,%edx
  movapd %xmm1,%xmm5
  movapd %xmm0,%xmm4
  xor    %eax,%eax
  shr    %edx
  unpcklpd %xmm5,%xmm5
  unpcklpd %xmm4,%xmm4
  shl    $0x4,%rdx
L16:
  movupd (%rsi,%rax,1),%xmm2
  movupd (%rdi,%rax,1),%xmm3
  movupd (%r8,%rax,1),%xmm6
  mulpd  %xmm5,%xmm2
  mulpd  %xmm4,%xmm3
  addpd  %xmm3,%xmm2
  addpd  %xmm6,%xmm2
  movups %xmm2,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L16
  mov    %r9d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r9d
  je     L42
L29:
  cltq
  mulsd  (%rdi,%rax,8),%xmm0
  lea    (%r8,%rax,8),%rdx
  mulsd  (%rsi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
L10:
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  ret
L25:
  xor    %eax,%eax
  jmp    L29
```

assistant: ```c
void expVecTimesPlusAccum(int dim, double p1, const double *restrict v1, double p2, const double *restrict v2, double *restrict pacc, double *restrict vacc) {
  *pacc += p1 * p2;
  for (int i = 0; i < dim; ++i) {
    vacc[i] += (p2 * v1[i]) + (p1 * v2[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  movslq %edx,%rbp
  test   %edx,%edx
  js     L100
L81:
  add    %rbx,%rbp
  cmp    %rbp,%rbx
  jae    L118
  lea    D56(%rip),%r15
  lea    D83(%rip),%r14
  lea    D70(%rip),%r12
  jmp    L102
L100:
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%rbp
  jmp    L81
  lea    D12(%rip),%rsi
  jmp    L107
  lea    D78(%rip),%rsi
L107:
  movzbl (%rbx),%edx
  mov    %r13,%rdi
  call   <fprintf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L118
L102:
  movzbl (%rbx),%edi
  lea    -0x7(%rdi),%eax
  cmp    $0x1b,%al
  ja     L17
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  lea    D34(%rip),%rsi
  jmp    L107
  lea    D102(%rip),%rsi
  jmp    L107
  lea    D58(%rip),%rsi
  jmp    L107
  lea    D80(%rip),%rsi
  jmp    L107
  lea    D55(%rip),%rsi
  jmp    L107
L17:
  movsbl %dil,%edi
  call   <isprint@plt>
  test   %eax,%eax
  mov    %r14,%rsi
  cmovne %r15,%rsi
  jmp    L107
  lea    D99(%rip),%rsi
  jmp    L107
L118:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D56
type_guessed: string
name: retrieve_data
arguments: data_label: D83
type_guessed: string
name: retrieve_data
arguments: data_label: D70
type_guessed: string
name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D78
type_guessed: string
name: retrieve_data
arguments: data_label: D34
type_guessed: string
name: retrieve_data
arguments: data_label: D102
type_guessed: string
name: retrieve_data
arguments: data_label: D58
type_guessed: string
name: retrieve_data
arguments: data_label: D80
type_guessed: string
name: retrieve_data
arguments: data_label: D55
type_guessed: string
name: retrieve_data
arguments: data_label: D99
type_guessed: string

tool: D56: %c

tool: D83: \x%02x

tool: 

tool: D12: \b

tool: D78: \f

tool: D34: \n

tool: D102: \r

tool: D58: \t

tool: D80: \v

tool: D55: \"

tool: D99: \a

assistant: ```c
void print_string(FILE *file, const char *s, int len) {
  const char *end = s + (len < 0 ? (int)strlen(s) : len);
  const char *p;
  for (p = s; p < end; ++p) {
    const char *format;
    switch (*p) {
    case '\a':
      format = "\\a";
      break;
    case '\b':
      format = "\\b";
      break;
    case '\f':
      format = "\\f";
      break;
    case '\n':
      format = "\\n";
      break;
    case '\r':
      format = "\\r";
      break;
    case '\t':
      format = "\\t";
      break;
    case '\v':
      format = "\\v";
      break;
    case '\"':
      format = "\\\"";
      break;
    default:
      format = isprint(*p) ? "%c" : "\\x%02x";
      break;
    }
    fprintf(file, format, ((unsigned)*p) & 0xff);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jns    L120
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
L120:
  add    %r13,%rbx
  lea    D86(%rip),%r15
  lea    D29(%rip),%r14
  lea    D85(%rip),%rbp
  cmp    %rbx,%r13
  jae    L1
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%r13),%edx
  lea    -0x7(%rdx),%eax
  cmp    $0x1b,%al
  ja     L6
  movzbl %al,%eax
  movslq 0x0(%rbp,%rax,4),%rax
  add    %rbp,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl %dl,%edi
  call   <isprint@plt>
  movzbl 0x0(%r13),%edx
  mov    %r14,%rsi
  test   %eax,%eax
  jne    L62
  mov    %r15,%rsi
  nopw   0x0(%rax,%rax,1)
L62:
  movzbl %dl,%edx
  mov    %r12,%rdi
  add    $0x1,%r13
  call   <fprintf@plt>
  cmp    %r13,%rbx
  jne    L8
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D63(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D1(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D30(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D104(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D3(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D91(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D100(%rip),%rsi
  jmp    L62
  nopl   0x0(%rax)
  lea    D60(%rip),%rsi
  jmp    L62
```

tool_calls: name: parse_data
arguments: data_tag: D86
type: string
name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D63
type: string
name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D30
type: string
name: parse_data
arguments: data_tag: D104
type: string
name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D91
type: string
name: parse_data
arguments: data_tag: D100
type: string
name: parse_data
arguments: data_tag: D60
type: string

tool: D86: \x%02x

tool: D29: %c

tool: D63: \"

tool: D1: \r

tool: D30: \f

tool: D104: \v

tool: D3: \n

tool: D91: \t

tool: D100: \a

tool: D60: \b

assistant: ```c
void print_string(FILE *file, const char *s, int len) {
  const char *end = s + (len < 0 ? (int)strlen(s) : len);
  const char *p;
  for (p = s; p < end; ++p) {
    const char *format;
    switch (*p) {
    case '\a':
      format = "\\a";
      break;
    case '\b':
      format = "\\b";
      break;
    case '\f':
      format = "\\f";
      break;
    case '\n':
      format = "\\n";
      break;
    case '\r':
      format = "\\r";
      break;
    case '\t':
      format = "\\t";
      break;
    case '\v':
      format = "\\v";
      break;
    case '\"':
      format = "\\\"";
      break;
    default:
      format = isprint(*p) ? "%c" : "\\x%02x";
      break;
    }
    fprintf(file, format, ((unsigned)*p) & 0xff);
  }
}
```