ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    D48(%rip),%rax
  mov    (%rax),%ebx
  add    $0x200,%ebx
  movslq %ebx,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L22:
  cmp    %rdx,%rsp
  je     L30
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L22
L30:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L49
  orq    $0x0,-0x8(%rsp,%rax,1)
L49:
  mov    %rsp,%r12
  mov    %rsp,-0x20(%rbp)
  mov    (%rdi),%eax
  mov    %eax,-0x24(%rbp)
  lea    -0x20(%rbp),%rsi
  mov    %ebx,%edx
  mov    D51(%rip),%rax
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  js     L39
L10:
  mov    -0x20(%rbp),%rdi
  call   <basename@plt>
  mov    %rax,%rsi
  mov    D48(%rip),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%edi
  call   <strncpy@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <utmpname@plt>
  test   %rax,%rax
  je     L78
L69:
  mov    -0x20(%rbp),%rdi
  cmp    %r12,%rdi
  je     L65
  call   <free@plt>
  jmp    L65
L39:
  lea    -0x20(%rbp),%rsi
  mov    %ebx,%edx
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  jns    L10
  lea    -0x20(%rbp),%rsi
  mov    %ebx,%edx
  mov    D66(%rip),%rax
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  jns    L10
L65:
  lea    -0x24(%rbp),%rsi
  mov    D43(%rip),%rax
  mov    (%rax),%edi
  call   <updwtmp@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L78:
  call   <setutent@plt>
  lea    -0x24(%rbp),%rdi
  call   <pututline@plt>
  mov    $0x0,%eax
  call   <endutent@plt>
  jmp    L69
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void login(const struct utmp *ut) {
  char _tty[512 + UT_LINESIZE];
  char *tty = _tty;
  int found_tty;
  const char *ttyp;
  struct utmp copy = *ut;
  found_tty = tty_name(STDIN_FILENO, &tty, sizeof(_tty));
  if (found_tty < 0)
    found_tty = tty_name(STDOUT_FILENO, &tty, sizeof(_tty));
  if (found_tty < 0)
    found_tty = tty_name(STDERR_FILENO, &tty, sizeof(_tty));
  if (found_tty >= 0) {
    ttyp = basename(tty);
    strncpy(copy.ut_line, ttyp, UT_LINESIZE);
    if (utmpname(_PATH_UTMP) == 0) {
      setutent();
      pututline(&copy);
      endutent();
    }
    if (tty != _tty)
      free(tty);
  }
  updwtmp(_PATH_WTMP, &copy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    D15(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  mov    (%rbx),%eax
  lea    0x200(%rax),%r12d
  movslq %r12d,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L68
L5:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L5
L68:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L100
L28:
  mov    (%rdi),%eax
  lea    -0x30(%rbp),%r14
  mov    %r12d,%edx
  mov    %rsp,-0x30(%rbp)
  mov    %r14,%rsi
  mov    %rsp,%r13
  mov    %eax,-0x34(%rbp)
  mov    D44(%rip),%rax
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  js     L6
L18:
  mov    -0x30(%rbp),%rdi
  lea    -0x34(%rbp),%r12
  call   <basename@plt>
  mov    (%rbx),%edx
  mov    -0x34(%rbp),%edi
  mov    %rax,%rsi
  call   <strncpy@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <utmpname@plt>
  test   %rax,%rax
  je     L9
L20:
  mov    -0x30(%rbp),%rdi
  cmp    %r13,%rdi
  je     L71
  call   <free@plt>
L71:
  mov    D51(%rip),%rax
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <updwtmp@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L6:
  mov    D49(%rip),%rax
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  jns    L18
  mov    D25(%rip),%rax
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  jns    L18
  lea    -0x34(%rbp),%r12
  jmp    L71
  xchg   %ax,%ax
L100:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  lea    -0x34(%rbp),%r12
  call   <setutent@plt>
  mov    %r12,%rdi
  call   <pututline@plt>
  xor    %eax,%eax
  call   <endutent@plt>
  jmp    L20
L97:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void login(const struct utmp *ut) {
  char _tty[512 + UT_LINESIZE];
  char *tty = _tty;
  int found_tty;
  const char *ttyp;
  struct utmp copy = *ut;
  found_tty = tty_name(STDIN_FILENO, &tty, sizeof(_tty));
  if (found_tty < 0)
    found_tty = tty_name(STDOUT_FILENO, &tty, sizeof(_tty));
  if (found_tty < 0)
    found_tty = tty_name(STDERR_FILENO, &tty, sizeof(_tty));
  if (found_tty >= 0) {
    ttyp = basename(tty);
    strncpy(copy.ut_line, ttyp, UT_LINESIZE);
    if (utmpname(_PATH_UTMP) == 0) {
      setutent();
      pututline(&copy);
      endutent();
    }
    if (tty != _tty)
      free(tty);
  }
  updwtmp(_PATH_WTMP, &copy);
}
```
user: Translate the below assembly code into C programming language:

```asm
<login>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    D9(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  mov    (%rbx),%eax
  lea    0x200(%rax),%r12d
  movslq %r12d,%rax
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L60
L113:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L113
L60:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L54
L32:
  mov    (%rdi),%eax
  lea    -0x30(%rbp),%r14
  mov    %r12d,%edx
  mov    %rsp,-0x30(%rbp)
  mov    %r14,%rsi
  mov    %rsp,%r13
  mov    %eax,-0x34(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  js     L103
L81:
  mov    -0x30(%rbp),%rdi
  lea    -0x34(%rbp),%r12
  call   <basename@plt>
  mov    (%rbx),%edx
  mov    -0x34(%rbp),%edi
  mov    %rax,%rsi
  call   <strncpy@plt>
  mov    D56(%rip),%rax
  mov    (%rax),%edi
  call   <utmpname@plt>
  test   %rax,%rax
  je     L102
L41:
  mov    -0x30(%rbp),%rdi
  cmp    %r13,%rdi
  je     L96
  call   <free@plt>
L96:
  mov    D31(%rip),%rax
  mov    %r12,%rsi
  mov    (%rax),%edi
  call   <updwtmp@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L103:
  mov    D16(%rip),%rax
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  jns    L81
  mov    D33(%rip),%rax
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    (%rax),%edi
  call   <tty_name@plt>
  test   %eax,%eax
  jns    L81
  lea    -0x34(%rbp),%r12
  jmp    L96
  xchg   %ax,%ax
L54:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L102:
  xor    %eax,%eax
  lea    -0x34(%rbp),%r12
  call   <setutent@plt>
  mov    %r12,%rdi
  call   <pututline@plt>
  xor    %eax,%eax
  call   <endutent@plt>
  jmp    L41
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void login(const struct utmp *ut) {
  char _tty[512 + UT_LINESIZE];
  char *tty = _tty;
  int found_tty;
  const char *ttyp;
  struct utmp copy = *ut;
  found_tty = tty_name(STDIN_FILENO, &tty, sizeof(_tty));
  if (found_tty < 0)
    found_tty = tty_name(STDOUT_FILENO, &tty, sizeof(_tty));
  if (found_tty < 0)
    found_tty = tty_name(STDERR_FILENO, &tty, sizeof(_tty));
  if (found_tty >= 0) {
    ttyp = basename(tty);
    strncpy(copy.ut_line, ttyp, UT_LINESIZE);
    if (utmpname(_PATH_UTMP) == 0) {
      setutent();
      pututline(&copy);
      endutent();
    }
    if (tty != _tty)
      free(tty);
  }
  updwtmp(_PATH_WTMP, &copy);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L6:
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  je     L29
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L26
L29:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
L26:
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x3e7,-0x8(%rbp)
  jle    L6
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: %d


assistant: ```c
int main(void) {
  int i, total = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      total += i;
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L25
L8:
  add    %edx,%esi
L19:
  add    $0x1,%edx
  cmp    $0x3e8,%edx
  je     L32
L25:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edx
  je     L8
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%edx
  jne    L19
  jmp    L8
L32:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(void) {
  int i, total = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      total += i;
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  imul   $0xaaaaaaab,%eax,%edx
  cmp    $0x55555555,%edx
  jbe    L20
  imul   $0xcccccccd,%eax,%edx
  cmp    $0x33333333,%edx
  ja     L14
L20:
  add    %eax,%esi
L14:
  add    $0x1,%eax
  cmp    $0x3e8,%eax
  jne    L8
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: %d


assistant: ```c
int main(void) {
  int i, total = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      total += i;
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  pxor   %xmm12,%xmm12
  movdqa D2(%rip),%xmm7
  xor    %eax,%eax
  movdqa %xmm12,%xmm14
  movdqa %xmm12,%xmm13
  movdqa D29(%rip),%xmm8
  movdqa D14(%rip),%xmm11
  pcmpgtd %xmm7,%xmm13
  movdqa %xmm12,%xmm9
  pcmpgtd %xmm8,%xmm14
  nopw   0x0(%rax,%rax,1)
L1:
  movdqa %xmm11,%xmm3
  movdqa %xmm9,%xmm5
  movdqa %xmm14,%xmm2
  add    $0x1,%eax
  movdqa %xmm3,%xmm0
  movdqa %xmm9,%xmm4
  movdqa %xmm14,%xmm15
  paddd  D47(%rip),%xmm11
  punpckldq %xmm3,%xmm0
  pcmpgtd %xmm0,%xmm5
  pmuludq %xmm0,%xmm2
  movdqa %xmm0,%xmm6
  pmuludq %xmm8,%xmm6
  movdqa %xmm5,%xmm1
  pmuludq %xmm7,%xmm5
  pmuludq %xmm8,%xmm1
  paddq  %xmm2,%xmm1
  movdqa %xmm3,%xmm2
  punpckhdq %xmm3,%xmm2
  psllq  $0x20,%xmm1
  pcmpgtd %xmm2,%xmm4
  paddq  %xmm1,%xmm6
  movdqa %xmm2,%xmm10
  pmuludq %xmm2,%xmm15
  pmuludq %xmm8,%xmm10
  movdqa %xmm4,%xmm1
  pmuludq %xmm7,%xmm4
  pmuludq %xmm8,%xmm1
  paddq  %xmm15,%xmm1
  psllq  $0x20,%xmm1
  paddq  %xmm10,%xmm1
  shufps $0xdd,%xmm1,%xmm6
  psrad  $0x1,%xmm6
  movdqa %xmm6,%xmm1
  pslld  $0x2,%xmm1
  paddd  %xmm6,%xmm1
  movdqa %xmm13,%xmm6
  pmuludq %xmm0,%xmm6
  pmuludq %xmm7,%xmm0
  pcmpeqd %xmm3,%xmm1
  pcmpeqd %xmm9,%xmm1
  paddq  %xmm6,%xmm5
  psllq  $0x20,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm13,%xmm5
  pmuludq %xmm2,%xmm5
  pmuludq %xmm7,%xmm2
  paddq  %xmm5,%xmm4
  psllq  $0x20,%xmm4
  paddq  %xmm4,%xmm2
  shufps $0xdd,%xmm2,%xmm0
  movdqa %xmm0,%xmm2
  pslld  $0x1,%xmm2
  paddd  %xmm2,%xmm0
  pcmpeqd %xmm3,%xmm0
  pcmpeqd %xmm9,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm3,%xmm1
  paddd  %xmm1,%xmm12
  cmp    $0xfa,%eax
  jne    L1
  movdqa %xmm12,%xmm0
  lea    D16(%rip),%rdi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm12
  movdqa %xmm12,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm12
  movd   %xmm12,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D29
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D14
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D47
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D16
type_infered: string

tool: {"D2": [0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55,0x56,0x55,0x55,0x55]}

tool: {"D29": [0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66,0x67,0x66,0x66,0x66]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D47": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D16: %d


assistant: ```c
int main(void) {
  int i, total = 0;
  for (i = 0; i < 1000; i++) {
    if (i % 3 == 0 || i % 5 == 0) {
      total += i;
    }
  }
  printf("%d\n", total);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  movb   $0x0,-0x32(%rbp)
  movb   $0x0,-0x31(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L47
L26:
  mov    -0x18(%rbp),%rdx
  lea    -0x32(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    -0x31(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x28(%rbp)
  cmpl   $0x0,-0x2c(%rbp)
  jne    L32
  cmpl   $0x0,-0x28(%rbp)
  je     L83
L32:
  movzbl -0x32(%rbp),%edx
  movzbl -0x31(%rbp),%eax
  cmp    %al,%dl
  jne    L0
  lea    D12(%rip),%rax
  jmp    L89
L0:
  lea    D45(%rip),%rax
L89:
  movzbl -0x31(%rbp),%edx
  movzbl %dl,%ecx
  movzbl -0x32(%rbp),%edx
  movzbl %dl,%edx
  mov    -0x30(%rbp),%esi
  mov    %rax,%r8
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x30(%rbp)
L47:
  cmpl   $0x0,-0x2c(%rbp)
  je     L59
  cmpl   $0x0,-0x28(%rbp)
  jne    L26
  jmp    L59
L83:
  nop
L59:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D37
type_infered: string
name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D45
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string

tool: D3: rb

tool: D29: bnk1.bnk

tool: D37: bnk2.bnk

tool: 

tool: D45:  <- NOT SAME!!!

tool: D24: %03X: {0x%02x == 0x%02x}%s


assistant: ```c
int main() {
  FILE *f1 = fopen("bnk1.bnk", "rb");
  FILE *f2 = fopen("bnk2.bnk", "rb");
  unsigned char byte1 = 0, byte2 = 0;
  int count = 0;
  int insCount = 0;
  int dataPos = 4;
  int valid1 = 1;
  int valid2 = 1;
  int drumMode = 0;
  while (valid1 && valid2) {
    valid1 = (fread(&byte1, 1, 1, f1) != 0);
    valid2 = (fread(&byte2, 1, 1, f2) != 0);
    if (!valid1 && !valid2)
      break;
    printf("%03X: {0x%02x == 0x%02x}%s\n", count, byte1, byte2, (byte1 == byte2) ? "" : " <- NOT SAME!!!");
    count++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rbx
  mov    %rbx,%rsi
  lea    D50(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,0x8(%rsp)
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,0x10(%rsp)
  movb   $0x0,0x26(%rsp)
  movb   $0x0,0x27(%rsp)
  mov    $0x0,%ebp
  lea    0x26(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    D46(%rip),%r15
  lea    D57(%rip),%r14
L13:
  mov    0x8(%rsp),%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    0x18(%rsp),%rdi
  call   <fread@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %r12b
  lea    0x27(%rsp),%rdi
  mov    0x10(%rsp),%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  test   %rax,%rax
  setne  %r13b
  or     %rbx,%rax
  je     L34
  movzbl 0x26(%rsp),%edx
  movzbl 0x27(%rsp),%ecx
  cmp    %cl,%dl
  movzbl %cl,%ecx
  movzbl %dl,%edx
  mov    %r14,%r8
  cmove  %r15,%r8
  mov    %ebp,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  test   %r12b,%r12b
  je     L34
  test   %r13b,%r13b
  jne    L13
L34:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D50
type_guessed: string
name: extract_symbolic_data
arguments: tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: tag: D46
type_guessed: string
name: extract_symbolic_data
arguments: tag: D57
type_guessed: string
name: extract_symbolic_data
arguments: tag: D32
type_guessed: string

tool: D4: rb

tool: D50: bnk1.bnk

tool: D26: bnk2.bnk

tool: 

tool: D57:  <- NOT SAME!!!

tool: D32: %03X: {0x%02x == 0x%02x}%s


assistant: ```c
int main() {
  FILE *f1 = fopen("bnk1.bnk", "rb");
  FILE *f2 = fopen("bnk2.bnk", "rb");
  unsigned char byte1 = 0, byte2 = 0;
  int count = 0;
  int insCount = 0;
  int dataPos = 4;
  int valid1 = 1;
  int valid2 = 1;
  int drumMode = 0;
  while (valid1 && valid2) {
    valid1 = (fread(&byte1, 1, 1, f1) != 0);
    valid2 = (fread(&byte2, 1, 1, f2) != 0);
    if (!valid1 && !valid2)
      break;
    printf("%03X: {0x%02x == 0x%02x}%s\n", count, byte1, byte2, (byte1 == byte2) ? "" : " <- NOT SAME!!!");
    count++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  lea    D36(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D25(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x16(%rsp),%r15
  lea    0x17(%rsp),%r14
  call   <fopen@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  mov    %rax,%r13
  call   <fopen@plt>
  movb   $0x0,0x16(%rsp)
  movb   $0x0,0x17(%rsp)
  mov    %rax,%r12
  jmp    L28
  nopl   (%rax)
L10:
  movzbl 0x16(%rsp),%edx
  movzbl 0x17(%rsp),%ecx
  lea    D47(%rip),%rax
  lea    D21(%rip),%r8
  mov    %ebx,%esi
  lea    D15(%rip),%rdi
  cmp    %cl,%dl
  cmove  %rax,%r8
  add    $0x1,%ebx
  call   <printf@plt>
  test   %bpl,%bpl
  je     L38
  cmpb   $0x0,0xf(%rsp)
  je     L38
L28:
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r15,%rdi
  call   <fread@plt>
  mov    %r12,%rcx
  mov    $0x1,%edx
  mov    %r14,%rdi
  test   %rax,%rax
  mov    $0x1,%esi
  mov    %rax,(%rsp)
  setne  %bpl
  call   <fread@plt>
  mov    (%rsp),%r8
  test   %rax,%rax
  setne  0xf(%rsp)
  or     %rax,%r8
  jne    L10
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D36
type_guessed: string
name: retrieve_data
arguments: tag: D25
type_guessed: string
name: retrieve_data
arguments: tag: D13
type_guessed: string
name: retrieve_data
arguments: tag: D47
type_guessed: string
name: retrieve_data
arguments: tag: D21
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string

tool: D36: bnk1.bnk

tool: D25: rb

tool: D13: bnk2.bnk

tool: 

tool: D21:  <- NOT SAME!!!

tool: D15: %03X: {0x%02x == 0x%02x}%s


assistant: ```c
int main() {
  FILE *f1 = fopen("bnk1.bnk", "rb");
  FILE *f2 = fopen("bnk2.bnk", "rb");
  unsigned char byte1 = 0, byte2 = 0;
  int count = 0;
  int insCount = 0;
  int dataPos = 4;
  int valid1 = 1;
  int valid2 = 1;
  int drumMode = 0;
  while (valid1 && valid2) {
    valid1 = (fread(&byte1, 1, 1, f1) != 0);
    valid2 = (fread(&byte2, 1, 1, f2) != 0);
    if (!valid1 && !valid2)
      break;
    printf("%03X: {0x%02x == 0x%02x}%s\n", count, byte1, byte2, (byte1 == byte2) ? "" : " <- NOT SAME!!!");
    count++;
  }
}
```