ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4d2,%edi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: Output:%s


assistant: ```c
int main(void) {
  char s[100];
  itoa(1234, s);
  printf("Output:%s\n", s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4d2,%edi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: Output:%s


assistant: ```c
int main(void) {
  char s[100];
  itoa(1234, s);
  printf("Output:%s\n", s);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: Hello filesystem.



assistant: ```c
int main() {
  printf("Hello filesystem.\n\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
datatype: string

tool: D0: Hello filesystem.



assistant: ```c
int main() {
  printf("Hello filesystem.\n\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: Hello filesystem.



assistant: ```c
int main() {
  printf("Hello filesystem.\n\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: Hello filesystem.



assistant: ```c
int main() {
  printf("Hello filesystem.\n\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L16
  cmpb   $0x5a,-0x4(%rbp)
  jg     L16
  movzbl -0x4(%rbp),%eax
  add    $0x20,%eax
  jmp    L18
L16:
  movzbl -0x4(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
char tolower(char c) {
  if (c >= 'A' && c <= 'Z')
    return (c + 32);
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char tolower(char c) {
  if (c >= 'A' && c <= 'Z')
    return (c + 32);
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char tolower(char c) {
  if (c >= 'A' && c <= 'Z')
    return (c + 32);
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%edx
  lea    0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
char tolower(char c) {
  if (c >= 'A' && c <= 'Z')
    return (c + 32);
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _read(int file __attribute__((unused)), char *ptr __attribute__((unused)), int len __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_read>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _read(int file __attribute__((unused)), char *ptr __attribute__((unused)), int len __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_read>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _read(int file __attribute__((unused)), char *ptr __attribute__((unused)), int len __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_read>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _read(int file __attribute__((unused)), char *ptr __attribute__((unused)), int len __attribute__((unused))) {
  errno = ENOSYS;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<JV_PBKDF1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %rdi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%r15
  mov    %r8,%r12
  mov    %r9d,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  movq   $0x0,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  lea    0xa0(%rsp),%rdi
  mov    $0x2a,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0xa0(%rsp),%r14
  mov    %r14,%rdi
  call   <memcpy@plt>
  lea    (%r14,%rbx,4),%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%r12,1),%rdx
  lea    0x50(%rsp),%rdi
  mov    %r14,%rsi
  call   <JV_SHA1@plt>
  cmp    $0x1,%ebp
  jle    L2
  mov    $0x1,%ebx
  mov    %rsp,%r12
  jmp    L75
L36:
  lea    0x50(%rsp),%rdi
  mov    $0x14,%edx
  mov    %r12,%rsi
  call   <JV_SHA1@plt>
L32:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L78
L75:
  test   $0x1,%bl
  je     L36
  lea    0x50(%rsp),%rsi
  mov    $0x14,%edx
  mov    %r12,%rdi
  call   <JV_SHA1@plt>
  jmp    L32
L78:
  test   $0x1,%bl
  jne    L2
  mov    %rsp,%rsi
  mov    $0x14,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  jmp    L40
L2:
  lea    0x50(%rsp),%rsi
  mov    $0x14,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
L40:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %r13,%rax
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t *JV_PBKDF1(uint8_t *dkey, const uint8_t password[], const size_t pwlen, const uint8_t salt[], const size_t saltlen, const uint32_t itercount) {
  uint8_t mid_odd[20] = {0}, mid_even[20] = {0};
  uint8_t kickoff[84] = {0};
  int i = 1;
  memcpy(kickoff, password, pwlen);
  memcpy(kickoff + pwlen, salt, saltlen);
  JV_SHA1(mid_even, kickoff, pwlen + saltlen);
  for (i = 1; i < itercount; i++) {
    if (i % 2) {
      JV_SHA1(mid_odd, mid_even, 20);
    } else {
      JV_SHA1(mid_even, mid_odd, 20);
    }
  }
  if (i % 2) {
    memcpy(dkey, mid_even, 20);
  } else {
    memcpy(dkey, mid_odd, 20);
  }
  return dkey;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<JV_PBKDF1>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  mov    $0x2a,%ecx
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0xa0(%rsp),%r13
  lea    0xa0(%rsp),%rdi
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rdi
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,4),%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%r12,1),%rdx
  lea    0x50(%rsp),%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x1,%ebx
  mov    %rsp,%r13
  call   <JV_SHA1@plt>
  cmp    $0x1,%ebp
  jg     L76
  jmp    L62
  nopl   (%rax)
L66:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <JV_SHA1@plt>
  cmp    %ebx,%ebp
  je     L54
L76:
  mov    $0x14,%edx
  test   $0x1,%bl
  jne    L66
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <JV_SHA1@plt>
  cmp    %ebx,%ebp
  jne    L76
L54:
  and    $0x1,%ebp
  jne    L62
  mov    $0x14,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
L23:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x208,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  mov    $0x14,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L23
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t *JV_PBKDF1(uint8_t *dkey, const uint8_t password[], const size_t pwlen, const uint8_t salt[], const size_t saltlen, const uint32_t itercount) {
  uint8_t mid_odd[20] = {0}, mid_even[20] = {0};
  uint8_t kickoff[84] = {0};
  int i = 1;
  memcpy(kickoff, password, pwlen);
  memcpy(kickoff + pwlen, salt, saltlen);
  JV_SHA1(mid_even, kickoff, pwlen + saltlen);
  for (i = 1; i < itercount; i++) {
    if (i % 2) {
      JV_SHA1(mid_odd, mid_even, 20);
    } else {
      JV_SHA1(mid_even, mid_odd, 20);
    }
  }
  if (i % 2) {
    memcpy(dkey, mid_even, 20);
  } else {
    memcpy(dkey, mid_odd, 20);
  }
  return dkey;
}
```
user: Translate the below assembly code into C programming language:

```asm
<JV_PBKDF1>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  mov    $0x2a,%ecx
  pxor   %xmm0,%xmm0
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  lea    0xa0(%rsp),%r13
  lea    0xa0(%rsp),%rdi
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r13,%rdi
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  call   <memcpy@plt>
  lea    0x0(%r13,%rbx,4),%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <memcpy@plt>
  lea    (%rbx,%r12,1),%rdx
  lea    0x50(%rsp),%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x1,%ebx
  mov    %rsp,%r13
  call   <JV_SHA1@plt>
  cmp    $0x1,%ebp
  jg     L72
  jmp    L23
  nopl   (%rax)
L10:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <JV_SHA1@plt>
  cmp    %ebx,%ebp
  je     L14
L72:
  mov    $0x14,%edx
  test   $0x1,%bl
  jne    L10
  mov    %r13,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <JV_SHA1@plt>
  cmp    %ebx,%ebp
  jne    L72
L14:
  and    $0x1,%ebp
  jne    L23
  mov    $0x14,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
L57:
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x208,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x14,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L57
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint8_t *JV_PBKDF1(uint8_t *dkey, const uint8_t password[], const size_t pwlen, const uint8_t salt[], const size_t saltlen, const uint32_t itercount) {
  uint8_t mid_odd[20] = {0}, mid_even[20] = {0};
  uint8_t kickoff[84] = {0};
  int i = 1;
  memcpy(kickoff, password, pwlen);
  memcpy(kickoff + pwlen, salt, saltlen);
  JV_SHA1(mid_even, kickoff, pwlen + saltlen);
  for (i = 1; i < itercount; i++) {
    if (i % 2) {
      JV_SHA1(mid_odd, mid_even, 20);
    } else {
      JV_SHA1(mid_even, mid_odd, 20);
    }
  }
  if (i % 2) {
    memcpy(dkey, mid_even, 20);
  } else {
    memcpy(dkey, mid_odd, 20);
  }
  return dkey;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<killpg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int killpg(__pid_t pgrp, int sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<killpg>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int killpg(__pid_t pgrp, int sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<killpg>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int killpg(__pid_t pgrp, int sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<killpg>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int killpg(__pid_t pgrp, int sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mpi_muluu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x80,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  mov    %rax,-0x8(%rbp)
L32:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  imul   %ecx,%eax
  add    %eax,-0x20(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L32
  mov    -0x20(%rbp),%eax
  movzwl %ax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,%rdx
  mov    %rdx,(%rax)
  shrl   $0x10,-0x20(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L16
  movl   $0x7f,-0x1c(%rbp)
  subq   $0x8,-0x38(%rbp)
  subl   $0x1,-0x18(%rbp)
L2:
  subl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addq   $0x8,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L30:
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%rax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  imul   %ecx,%eax
  add    %eax,-0x20(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L30
  mov    -0x20(%rbp),%eax
  movzwl %ax,%ecx
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,%rdx
  mov    %rdx,(%rax)
  shrl   $0x10,-0x20(%rbp)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L2
  mov    -0x20(%rbp),%eax
  movzwl %ax,%eax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mpi_muluu(uint16_t *c, const uint16_t *a, const uint16_t *b) {
  uint64_t mcarry = 0;
  uint8_t count = 128;
  uint8_t niter2 = 1;
  uint8_t count2;
  const uint16_t *aa;
  const uint16_t *bb;
  do {
    count2 = niter2++;
    aa = a;
    bb = b++;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  count = 128 - 1;
  b--;
  niter2--;
  do {
    count2 = --niter2;
    aa = ++a;
    bb = b;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  *c = (uint16_t)(mcarry & 0xFFFF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mpi_muluu>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%r9
  mov    %rdx,%rbp
  lea    0x8(%rsi),%rdi
  mov    %rdx,%rbx
  mov    %r8,%r11
  mov    $0x1,%r10d
  mov    $0x0,%eax
L16:
  add    $0x1,%r10d
  mov    %rbx,%rsi
  add    $0x8,%rbx
  mov    %r9,%rdx
L24:
  add    $0x8,%rdx
  sub    $0x8,%rsi
  mov    0x8(%rsi),%rcx
  imul   -0x8(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L24
  add    $0x8,%r11
  movzwl %ax,%edx
  mov    %edx,%esi
  mov    %rsi,-0x8(%r11)
  shr    $0x10,%eax
  add    $0x8,%rdi
  cmp    $0x81,%r10d
  jne    L16
  lea    0x3f8(%rbp),%rbx
  lea    0x400(%r8),%r10
  mov    $0x7f,%r11d
  lea    0x800(%r8),%rbp
L26:
  mov    %r9,%rdi
  add    $0x8,%r9
  mov    %rbp,%rdx
  sub    %r10,%rdx
  add    %rdx,%rdi
  mov    %rbx,%rsi
  mov    %r9,%rdx
L18:
  add    $0x8,%rdx
  sub    $0x8,%rsi
  mov    0x8(%rsi),%rcx
  imul   -0x8(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L18
  add    $0x8,%r10
  movzwl %ax,%edx
  mov    %edx,%edi
  mov    %rdi,-0x8(%r10)
  shr    $0x10,%eax
  sub    $0x1,%r11d
  jne    L26
  mov    %eax,%eax
  mov    %rax,0x7f8(%r8)
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void mpi_muluu(uint16_t *c, const uint16_t *a, const uint16_t *b) {
  uint64_t mcarry = 0;
  uint8_t count = 128;
  uint8_t niter2 = 1;
  uint8_t count2;
  const uint16_t *aa;
  const uint16_t *bb;
  do {
    count2 = niter2++;
    aa = a;
    bb = b++;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  count = 128 - 1;
  b--;
  niter2--;
  do {
    count2 = --niter2;
    aa = ++a;
    bb = b;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  *c = (uint16_t)(mcarry & 0xFFFF);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mpi_muluu>:
  endbr64
  mov    %rdi,%r8
  lea    0x8(%rsi),%r10
  push   %r12
  mov    %rsi,%r9
  push   %rbp
  mov    %rdx,%r12
  mov    %r10,%rdi
  mov    %rdx,%rbp
  push   %rbx
  mov    $0x1,%r11d
  mov    %r8,%rbx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %rbp,%rsi
  add    $0x1,%r11d
  add    $0x8,%rbp
  mov    %r9,%rdx
  xchg   %ax,%ax
L19:
  add    $0x8,%rdx
  mov    (%rsi),%rcx
  sub    $0x8,%rsi
  imul   -0x8(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L19
  movzwl %ax,%edi
  add    $0x8,%rbx
  shr    $0x10,%eax
  mov    %rdi,-0x8(%rbx)
  lea    0x8(%rdx),%rdi
  cmp    $0x81,%r11d
  jne    L31
  lea    0x3f8(%r12),%rbp
  lea    0x400(%r8),%r11
  mov    $0x7f,%ebx
  lea    0x800(%r8),%r12
  nopl   0x0(%rax)
L12:
  mov    %r12,%rdx
  mov    %r9,%rdi
  mov    %rbp,%rsi
  mov    %r10,%r9
  sub    %r11,%rdx
  add    %rdx,%rdi
  mov    %r10,%rdx
  nopl   (%rax)
L28:
  add    $0x8,%rdx
  mov    (%rsi),%rcx
  sub    $0x8,%rsi
  imul   -0x8(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L28
  movzwl %ax,%edi
  add    $0x8,%r11
  shr    $0x10,%eax
  mov    %rdi,-0x8(%r11)
  sub    $0x1,%ebx
  je     L41
  add    $0x8,%r10
  jmp    L12
L41:
  pop    %rbx
  pop    %rbp
  mov    %rax,0x7f8(%r8)
  pop    %r12
  ret
```

assistant: ```c
void mpi_muluu(uint16_t *c, const uint16_t *a, const uint16_t *b) {
  uint64_t mcarry = 0;
  uint8_t count = 128;
  uint8_t niter2 = 1;
  uint8_t count2;
  const uint16_t *aa;
  const uint16_t *bb;
  do {
    count2 = niter2++;
    aa = a;
    bb = b++;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  count = 128 - 1;
  b--;
  niter2--;
  do {
    count2 = --niter2;
    aa = ++a;
    bb = b;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  *c = (uint16_t)(mcarry & 0xFFFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mpi_muluu>:
  endbr64
  mov    %rdi,%r8
  lea    0x8(%rsi),%r10
  push   %r12
  mov    %rsi,%r9
  push   %rbp
  mov    %rdx,%r12
  mov    %r10,%rdi
  mov    %rdx,%rbp
  push   %rbx
  mov    $0x1,%r11d
  mov    %r8,%rbx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %rbp,%rsi
  add    $0x1,%r11d
  add    $0x8,%rbp
  mov    %r9,%rdx
  xchg   %ax,%ax
L21:
  add    $0x8,%rdx
  mov    (%rsi),%rcx
  sub    $0x8,%rsi
  imul   -0x8(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L21
  movzwl %ax,%edi
  add    $0x8,%rbx
  shr    $0x10,%eax
  mov    %rdi,-0x8(%rbx)
  lea    0x8(%rdx),%rdi
  cmp    $0x81,%r11d
  jne    L24
  lea    0x3f8(%r12),%rbp
  lea    0x400(%r8),%r11
  mov    $0x80,%ebx
  lea    0x800(%r8),%r12
  nopl   0x0(%rax)
L41:
  mov    %r12,%rdx
  mov    %r9,%rdi
  sub    $0x1,%ebx
  mov    %r10,%r9
  sub    %r11,%rdx
  mov    %rbp,%rsi
  add    %rdx,%rdi
  mov    %r10,%rdx
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x8,%rdx
  mov    (%rsi),%rcx
  sub    $0x8,%rsi
  imul   -0x8(%rdx),%ecx
  add    %ecx,%eax
  cmp    %rdi,%rdx
  jne    L30
  movzwl %ax,%edi
  add    $0x8,%r11
  shr    $0x10,%eax
  mov    %rdi,-0x8(%r11)
  cmp    $0x1,%ebx
  je     L40
  add    $0x8,%r10
  jmp    L41
L40:
  pop    %rbx
  pop    %rbp
  mov    %rax,0x7f8(%r8)
  pop    %r12
  ret
```

assistant: ```c
void mpi_muluu(uint16_t *c, const uint16_t *a, const uint16_t *b) {
  uint64_t mcarry = 0;
  uint8_t count = 128;
  uint8_t niter2 = 1;
  uint8_t count2;
  const uint16_t *aa;
  const uint16_t *bb;
  do {
    count2 = niter2++;
    aa = a;
    bb = b++;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  count = 128 - 1;
  b--;
  niter2--;
  do {
    count2 = --niter2;
    aa = ++a;
    bb = b;
    do {
      mcarry += (unsigned)*aa++ * (unsigned)*bb--;
    } while (--count2);
    *c++ = (uint16_t)(mcarry & 0xFFFF);
    mcarry >>= 16;
  } while (--count);
  *c = (uint16_t)(mcarry & 0xFFFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  lea    D11(%rip),%rax
  mov    %rax,%rdx
  mov    $0x20,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    D13(%rip),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string

tool: D11: %d

assistant: ```c
char *_itoa(int n) {
  static char buf[32];
  snprintf(buf, 32, "%d", n);
  return buf;
}
```