user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x4c(%rbp),%rdx
  lea    -0x50(%rbp),%rsi
  lea    D37(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    -0x44(%rbp),%rdx
  lea    -0x48(%rbp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x3c(%rbp),%rdx
  lea    -0x40(%rbp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x40(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L109:
  cmp    %rcx,%rsp
  je     L75
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L109
L75:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L56
  orq    $0x0,-0x8(%rsp,%rax,1)
L56:
  mov    %rsp,%r14
  test   %edx,%edx
  jle    L25
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D30(%rip),%r13
L222:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x40(%rbp)
  jg     L222
L25:
  mov    -0x3c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L103:
  cmp    %rcx,%rsp
  je     L67
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L103
L67:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L107
  orq    $0x0,-0x8(%rsp,%rax,1)
L107:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L45
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D30(%rip),%r15
L196:
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x3c(%rbp),%edx
  add    $0x4,%r12
  cmp    %ebx,%edx
  jg     L196
  mov    -0x40(%rbp),%edi
  test   %edi,%edi
  jle    L225
L92:
  mov    -0x48(%rbp),%r9d
  mov    -0x50(%rbp),%r8d
  mov    -0x4c(%rbp),%r10d
  mov    $0x0,%eax
  mov    $0x0,%esi
  jmp    L220
L207:
  add    $0x1,%rax
  cmp    %eax,%edi
  jle    L98
L220:
  mov    %r9d,%ecx
  add    (%r14,%rax,4),%ecx
  cmp    %r8d,%ecx
  jl     L207
  cmp    %r10d,%ecx
  setle  %cl
  movzbl %cl,%ecx
  add    %ecx,%esi
  jmp    L207
L225:
  mov    $0x0,%esi
L98:
  test   %edx,%edx
  jle    L223
  mov    -0x44(%rbp),%r9d
  mov    -0x50(%rbp),%r8d
  mov    -0x4c(%rbp),%r10d
  mov    %r13,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%r13,%rdx,4),%rdi
  mov    $0x0,%ecx
  jmp    L201
L43:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L38
L201:
  mov    %r9d,%edx
  add    (%rax),%edx
  cmp    %r8d,%edx
  jl     L43
  cmp    %r10d,%edx
  setle  %dl
  movzbl %dl,%edx
  add    %edx,%ecx
  jmp    L43
L223:
  mov    $0x0,%ecx
L38:
  mov    %ecx,%edx
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L185
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L45:
  mov    -0x40(%rbp),%edi
  mov    $0x0,%esi
  mov    $0x0,%ecx
  test   %edi,%edi
  jg     L92
  jmp    L38
L185:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D37
data_type: string
name: extract_symbolic_data
arguments: data_label: D30
data_type: string
name: extract_symbolic_data
arguments: data_label: D33
data_type: string

tool: D37: %d %d

tool: D30: %d

tool: D33: %d
%d

assistant: ```c
int main() {
  int s;
  int t;
  scanf("%d %d", &s, &t);
  int a;
  int b;
  scanf("%d %d", &a, &b);
  int m;
  int n;
  scanf("%d %d", &m, &n);
  int apple[m];
  for (int apple_i = 0; apple_i < m; apple_i++) {
    scanf("%d", &apple[apple_i]);
  }
  int orange[n];
  for (int orange_i = 0; orange_i < n; orange_i++) {
    scanf("%d", &orange[orange_i]);
  }
  int numOfApples = 0;
  int numOfOranges = 0;
  for (int i = 0; i < m; i++) {
    if ((a + apple[i]) >= s && (a + apple[i]) <= t) {
      numOfApples++;
    }
  }
  for (int i = 0; i < n; i++) {
    if ((b + orange[i]) >= s && (b + orange[i]) <= t) {
      numOfOranges++;
    }
  }
  printf("%d\n%d", numOfApples, numOfOranges);
  return 0;
}
```