ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<Mx1_is_wrap>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L45
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L24:
  add    $0x14,%rbx
  cmpb   $0x0,(%rbx)
  je     L57
L26:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L24
  cmpb   $0x0,(%rbx)
  je     L57
  mov    $0x1,%eax
  test   %r12,%r12
  je     L11
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  xor    %eax,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Mx1_is_wrap(struct Mx1 *m, char wraps[][20], char *start, char **found, int flag) {
  int i;
  for (i = 0; wraps[i][0] != 0; i++)
    if (strncmp(start, wraps[i], strlen(wraps[i])) == 0)
      break;
  if (wraps[i][0] != 0) {
    if (found != NULL)
      *found = wraps[i];
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<UsefulBufUtil_CopyFloatToUint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
uint32_t UsefulBufUtil_CopyFloatToUint32(float f) {
  uint32_t u32;
  memcpy(&u32, &f, sizeof(uint32_t));
  return u32;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UsefulBufUtil_CopyFloatToUint32>:
  endbr64
  sub    $0x28,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t UsefulBufUtil_CopyFloatToUint32(float f) {
  uint32_t u32;
  memcpy(&u32, &f, sizeof(uint32_t));
  return u32;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UsefulBufUtil_CopyFloatToUint32>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  movss  %xmm0,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t UsefulBufUtil_CopyFloatToUint32(float f) {
  uint32_t u32;
  memcpy(&u32, &f, sizeof(uint32_t));
  return u32;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UsefulBufUtil_CopyFloatToUint32>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edx
  movss  %xmm0,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t UsefulBufUtil_CopyFloatToUint32(float f) {
  uint32_t u32;
  memcpy(&u32, &f, sizeof(uint32_t));
  return u32;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L68
L67:
  cmpl   $0x20,-0x4(%rbp)
  je     L53
  cmpl   $0xa,-0x4(%rbp)
  je     L53
  cmpl   $0x9,-0x4(%rbp)
  jne    L31
L53:
  cmpl   $0x1,-0x8(%rbp)
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
L20:
  movl   $0x0,-0x8(%rbp)
  jmp    L68
L31:
  movl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L68:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L67
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int c, state;
  state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\n' || c == '\t') {
      if (state == 1)
        putchar('\n');
      state = 0;
    } else {
      state = 1;
      putchar(c);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L38
L63:
  cmp    $0x1,%ebx
  je     L4
L38:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D3(%rip),%rax
  cmp    %edi,(%rax)
  je     L37
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L63
  cmp    $0x20,%edi
  je     L63
  call   <putchar@plt>
  mov    $0x1,%ebx
  jmp    L38
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%ebx
  jmp    L38
L37:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int c, state;
  state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\n' || c == '\t') {
      if (state == 1)
        putchar('\n');
      state = 0;
    } else {
      state = 1;
      putchar(c);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  je     L59
L23:
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L46
  cmp    $0x20,%edi
  jne    L22
L46:
  cmp    $0x1,%ebx
  jne    L18
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  jne    L23
L59:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  call   <putchar@plt>
  mov    $0x1,%ebx
  jmp    L18
```

assistant: ```c
main() {
  int c, state;
  state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\n' || c == '\t') {
      if (state == 1)
        putchar('\n');
      state = 0;
    } else {
      state = 1;
      putchar(c);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  je     L35
L21:
  lea    -0x9(%rdi),%eax
  cmp    $0x1,%eax
  jbe    L7
  cmp    $0x20,%edi
  jne    L12
L7:
  cmp    $0x1,%ebx
  jne    L18
  mov    $0xa,%edi
  xor    %ebx,%ebx
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    %eax,0x0(%rbp)
  jne    L21
L35:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  call   <putchar@plt>
  mov    $0x1,%ebx
  jmp    L18
```

assistant: ```c
main() {
  int c, state;
  state = 0;
  while ((c = getchar()) != EOF) {
    if (c == ' ' || c == '\n' || c == '\t') {
      if (state == 1)
        putchar('\n');
      state = 0;
    } else {
      state = 1;
      putchar(c);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_backward>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  test   %ecx,%ecx
  jle    L57
  lea    -0x1(%r8),%edx
  imul   %ecx,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  lea    -0x1(%rcx),%ecx
  add    %rcx,%rdx
  lea    0x8(%rdi,%rdx,8),%rcx
  mov    %rax,%rdx
  pxor   %xmm1,%xmm1
  movsd  D6(%rip),%xmm0
L45:
  movsd  %xmm0,(%rdx)
  addsd  %xmm0,%xmm1
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L45
L116:
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L116
L57:
  sub    $0x2,%r14d
  js     L15
  mov    %r14d,%ebp
  imul   %r13d,%ebp
  movslq %r13d,%rbx
  shl    $0x3,%rbx
  lea    -0x1(%r13),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x8(%rdi),%r15
  mov    %r13d,%eax
  mov    %rax,-0x8(%rsp)
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm3
  jmp    L0
L67:
  movsd  (%r9),%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%r9)
  add    $0x8,%r9
  cmp    %r10,%r9
  jne    L67
L6:
  sub    $0x1,%r14d
  sub    %r13d,%ebp
  cmp    $0xffffffff,%r14d
  je     L15
L0:
  test   %r13d,%r13d
  jle    L6
  movslq %ebp,%rcx
  lea    (%rdi,%rcx,8),%r9
  lea    0x0(%rbp,%r13,1),%eax
  cltq
  mov    %rax,%rdx
  neg    %rdx
  lea    (%r12,%rdx,8),%rdx
  add    -0x10(%rsp),%rcx
  lea    (%r15,%rcx,8),%r10
  lea    0x0(,%rax,8),%r11
  add    -0x8(%rsp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    %r9,%r8
  pxor   %xmm2,%xmm2
L78:
  mov    %r11,%rax
  pxor   %xmm1,%xmm1
L12:
  movsd  (%rdx,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L12
  movsd  %xmm1,(%r8)
  addsd  %xmm1,%xmm2
  add    $0x8,%r8
  add    %rbx,%rdx
  cmp    %r10,%r8
  jne    L78
  ucomisd %xmm4,%xmm2
  jp     L67
  ucomisd %xmm3,%xmm2
  je     L6
  jmp    L67
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_infered: f64

tool: D6: 1

assistant: ```c
void _backward(double *beta, const double *A, const double *pobs, int N, int T) {
  int i, j, t;
  double sum, scaling;
  scaling = 0.0;
  for (i = 0; i < N; i++) {
    beta[(T - 1) * N + i] = 1.0;
    scaling += beta[(T - 1) * N + i];
  }
  for (i = 0; i < N; i++)
    beta[(T - 1) * N + i] /= scaling;
  for (t = T - 2; t >= 0; t--) {
    scaling = 0.0;
    for (i = 0; i < N; i++) {
      sum = 0.0;
      for (j = 0; j < N; j++) {
        sum += A[i * N + j] * pobs[(t + 1) * N + j] * beta[(t + 1) * N + j];
      }
      beta[t * N + i] = sum;
      scaling += sum;
    }
    if (scaling != 0)
      for (j = 0; j < N; j++)
        beta[t * N + j] /= scaling;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_backward>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,-0x10(%rsp)
  mov    %rdx,%rsi
  test   %ecx,%ecx
  jle    L14
  lea    -0x1(%r8),%edx
  movsd  D5(%rip),%xmm0
  pxor   %xmm1,%xmm1
  imul   %ecx,%edx
  lea    -0x1(%rcx),%ecx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  add    %rcx,%rdx
  lea    0x8(%rdi,%rdx,8),%rcx
  mov    %rax,%rdx
  nopl   0x0(%rax,%rax,1)
L45:
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  addsd  %xmm0,%xmm1
  cmp    %rcx,%rdx
  jne    L45
  nopl   0x0(%rax)
L100:
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L100
L14:
  sub    $0x2,%r13d
  js     L50
  lea    -0x1(%r12),%r14d
  mov    %r13d,%ebp
  lea    0x8(%rdi),%r15
  movslq %r12d,%rbx
  imul   %r12d,%ebp
  lea    0x1(%r14),%rax
  pxor   %xmm3,%xmm3
  shl    $0x3,%rbx
  mov    %rax,-0x8(%rsp)
  nopl   0x0(%rax)
L73:
  test   %r12d,%r12d
  jle    L90
  lea    (%r12,%rbp,1),%eax
  movslq %ebp,%rcx
  mov    -0x10(%rsp),%rdx
  movapd %xmm3,%xmm2
  cltq
  lea    (%rdi,%rcx,8),%r10
  add    %r14,%rcx
  mov    %rax,%r9
  add    -0x8(%rsp),%rax
  lea    (%r15,%rcx,8),%r11
  mov    %r10,%r8
  neg    %r9
  lea    0x0(,%rax,8),%rcx
  shl    $0x3,%r9
  add    %r9,%rdx
  neg    %r9
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %r9,%rax
  movapd %xmm3,%xmm1
  nopw   0x0(%rax,%rax,1)
L74:
  movsd  (%rdx,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L74
  movsd  %xmm1,(%r8)
  add    $0x8,%r8
  addsd  %xmm1,%xmm2
  add    %rbx,%rdx
  cmp    %r8,%r11
  jne    L46
  ucomisd %xmm3,%xmm2
  jp     L115
  jne    L115
L90:
  sub    $0x1,%r13d
  sub    %r12d,%ebp
  cmp    $0xffffffff,%r13d
  jne    L73
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L115:
  movsd  (%r10),%xmm0
  add    $0x8,%r10
  divsd  %xmm2,%xmm0
  movsd  %xmm0,-0x8(%r10)
  cmp    %r10,%r11
  jne    L115
  jmp    L90
```

tool_calls: name: read_data
arguments: data_label: D5
type: f64

tool: D5: 1

assistant: ```c
void _backward(double *beta, const double *A, const double *pobs, int N, int T) {
  int i, j, t;
  double sum, scaling;
  scaling = 0.0;
  for (i = 0; i < N; i++) {
    beta[(T - 1) * N + i] = 1.0;
    scaling += beta[(T - 1) * N + i];
  }
  for (i = 0; i < N; i++)
    beta[(T - 1) * N + i] /= scaling;
  for (t = T - 2; t >= 0; t--) {
    scaling = 0.0;
    for (i = 0; i < N; i++) {
      sum = 0.0;
      for (j = 0; j < N; j++) {
        sum += A[i * N + j] * pobs[(t + 1) * N + j] * beta[(t + 1) * N + j];
      }
      beta[t * N + i] = sum;
      scaling += sum;
    }
    if (scaling != 0)
      for (j = 0; j < N; j++)
        beta[t * N + j] /= scaling;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipWhitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L36
L25:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L39
  mov    -0x8(%rbp),%rax
  jmp    L12
L39:
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L25
  mov    -0x20(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
size_t skipWhitespace(const char *cmd, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (!isspace((unsigned char)cmd[i])) {
      return i;
    }
  }
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<skipWhitespace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L23
  mov    %rdi,%r12
  mov    $0x0,%ebx
L10:
  movzbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L33
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L10
  jmp    L23
L33:
  mov    %rbx,%rbp
L23:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t skipWhitespace(const char *cmd, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (!isspace((unsigned char)cmd[i])) {
      return i;
    }
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skipWhitespace>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L31
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L31
L19:
  movzbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L29
  mov    %rbx,%r12
L31:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t skipWhitespace(const char *cmd, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (!isspace((unsigned char)cmd[i])) {
      return i;
    }
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<skipWhitespace>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L10
  mov    %rdi,%rbp
  xor    %ebx,%ebx
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L10
L34:
  movzbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L1
  mov    %rbx,%r12
L10:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t skipWhitespace(const char *cmd, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    if (!isspace((unsigned char)cmd[i])) {
      return i;
    }
  }
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xfb8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xfb4(%rbp)
  lea    -0xfc4(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L5
L24:
  lea    -0xfc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xfb8(%rbp)
  movl   $0x0,-0xfbc(%rbp)
  jmp    L56
L21:
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfbc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  add    %eax,-0xfb8(%rbp)
  addl   $0x1,-0xfbc(%rbp)
L56:
  mov    -0xfc0(%rbp),%eax
  cmp    %eax,-0xfbc(%rbp)
  jl     L21
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xfb8(%rbp),%xmm0
  mov    -0xfc0(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xfb4(%rbp)
  movl   $0x0,-0xfb8(%rbp)
  movl   $0x0,-0xfbc(%rbp)
  jmp    L49
L41:
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  comiss -0xfb4(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  add    %eax,-0xfb8(%rbp)
  addl   $0x1,-0xfbc(%rbp)
L49:
  mov    -0xfc0(%rbp),%eax
  cmp    %eax,-0xfbc(%rbp)
  jl     L41
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0xfb8(%rbp),%xmm1
  movss  D17(%rip),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0xfc0(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    -0xfc4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xfc4(%rbp)
  test   %eax,%eax
  jne    L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: byte[4]
name: unpack_data
arguments: label: D44
type_infered: string

tool: D23: %d

tool: {"D17": [0x00,0x00,0xc8,0x42]}

tool: D44: %.3f%%


assistant: ```c
int main() {
  int i, num, students;
  int data[1000];
  int sum = 0;
  float average = 0;
  scanf("%d", &num);
  while (num--) {
    scanf("%d", &students);
    sum = 0;
    for (i = 0; i < students; i++) {
      scanf("%d", &data[i]);
      sum += data[i];
    }
    average = (float)sum / students;
    sum = 0;
    for (i = 0; i < students; i++) {
      sum += data[i] > average ? 1 : 0;
    }
    printf("%.3f%%\n", 100 * (float)sum / students);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L24
  lea    0xc(%rsp),%r15
  lea    D24(%rip),%r13
  lea    D9(%rip),%r14
L60:
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    $0x0,%ebp
  mov    $0x0,%r12d
L54:
  lea    0x10(%rsp),%rbx
  lea    (%rbx,%rbp,4),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    (%rbx,%rbp,4),%r12d
  mov    0xc(%rsp),%eax
  add    $0x1,%rbp
  cmp    %ebp,%eax
  jg     L54
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12d,%xmm1
  divss  %xmm2,%xmm1
  test   %eax,%eax
  jle    L68
  lea    -0x1(%rax),%eax
  lea    0x4(%rbx,%rax,4),%rcx
  mov    $0x0,%eax
L71:
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rbx),%xmm0
  comiss %xmm1,%xmm0
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  add    $0x4,%rbx
  cmp    %rcx,%rbx
  jne    L71
L11:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  D36(%rip),%xmm0
  divss  %xmm2,%xmm0
  cvttss2si %xmm0,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L60
L24:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  mov    $0x0,%eax
  jmp    L11
L20:
  pxor   %xmm2,%xmm2
  cvtsi2ss %eax,%xmm2
  mov    $0x0,%eax
  jmp    L11
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string
name: disassemble_data
arguments: label: D36
type_guessed: byte[4]

tool: D24: %d

tool: D9: %.3f%%


tool: {"D36": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int main() {
  int i, num, students;
  int data[1000];
  int sum = 0;
  float average = 0;
  scanf("%d", &num);
  while (num--) {
    scanf("%d", &students);
    sum = 0;
    for (i = 0; i < students; i++) {
      scanf("%d", &data[i]);
      sum += data[i];
    }
    average = (float)sum / students;
    sum = 0;
    for (i = 0; i < students; i++) {
      sum += data[i] > average ? 1 : 0;
    }
    printf("%.3f%%\n", 100 * (float)sum / students);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%r15
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L12
  nopl   0x0(%rax)
L11:
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L77
  xor    %ebp,%ebp
  xor    %r14d,%r14d
  lea    0x10(%rsp),%r12
  nopl   0x0(%rax)
L34:
  lea    (%r12,%rbp,4),%rsi
  mov    %r13,%rdi
  mov    %r12,%rbx
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  add    (%r12,%rbp,4),%r14d
  add    $0x1,%rbp
  cmp    %ebp,%eax
  jg     L34
  pxor   %xmm2,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm2
  cvtsi2ss %r14d,%xmm1
  divss  %xmm2,%xmm1
  test   %eax,%eax
  jle    L7
  sub    $0x1,%eax
  lea    0x14(%rsp,%rax,4),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L66:
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  cvtsi2ssl (%rbx),%xmm0
  comiss %xmm1,%xmm0
  seta   %dl
  add    $0x4,%rbx
  add    %edx,%eax
  cmp    %rbx,%rcx
  jne    L66
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  D1(%rip),%xmm0
L22:
  divss  %xmm2,%xmm0
  lea    D19(%rip),%rdi
  cvttss2si %xmm0,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L11
L12:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L77:
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm2
  jmp    L22
L7:
  pxor   %xmm0,%xmm0
  jmp    L22
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D1
type_infered: byte[4]
name: read_data
arguments: label: D19
type_infered: string

tool: D12: %d

tool: {"D1": [0x00,0x00,0xc8,0x42]}

tool: D19: %.3f%%


assistant: ```c
int main() {
  int i, num, students;
  int data[1000];
  int sum = 0;
  float average = 0;
  scanf("%d", &num);
  while (num--) {
    scanf("%d", &students);
    sum = 0;
    for (i = 0; i < students; i++) {
      scanf("%d", &data[i]);
      sum += data[i];
    }
    average = (float)sum / students;
    sum = 0;
    for (i = 0; i < students; i++) {
      sum += data[i] > average ? 1 : 0;
    }
    printf("%.3f%%\n", 100 * (float)sum / students);
  }
  return 0;
}
```