ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<inet6_opt_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L27
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  je     L7
L27:
  mov    $0xffffffff,%eax
  jmp    L24
L7:
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x1c(%rbp),%eax
  sar    $0x3,%eax
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    $0x2,%eax
L24:
  pop    %rbp
  ret
```

assistant: ```c
int inet6_opt_init(void *extbuf, socklen_t extlen) {
  struct ip6_ext *ext = (struct ip6_ext *)extbuf;
  if (extlen == 0 || (extlen % 8)) {
    return (-1);
  }
  if (ext) {
    ext->ip6e_len = (extlen >> 3) - 1;
  }
  return (2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inet6_opt_init>:
  endbr64
  test   %esi,%esi
  je     L15
  test   $0x7,%sil
  jne    L17
  mov    $0x2,%eax
  test   %rdi,%rdi
  je     L5
  sar    $0x3,%esi
  sub    $0x1,%esi
  mov    %esi,(%rdi)
  ret
L15:
  mov    $0xffffffff,%eax
  ret
L17:
  mov    $0xffffffff,%eax
L5:
  ret
```

assistant: ```c
int inet6_opt_init(void *extbuf, socklen_t extlen) {
  struct ip6_ext *ext = (struct ip6_ext *)extbuf;
  if (extlen == 0 || (extlen % 8)) {
    return (-1);
  }
  if (ext) {
    ext->ip6e_len = (extlen >> 3) - 1;
  }
  return (2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inet6_opt_init>:
  endbr64
  test   %esi,%esi
  je     L19
  test   $0x7,%sil
  jne    L19
  mov    $0x2,%eax
  test   %rdi,%rdi
  je     L24
  sar    $0x3,%esi
  sub    $0x1,%esi
  mov    %esi,(%rdi)
  ret
  nopl   0x0(%rax)
L19:
  mov    $0xffffffff,%eax
L24:
  ret
```

assistant: ```c
int inet6_opt_init(void *extbuf, socklen_t extlen) {
  struct ip6_ext *ext = (struct ip6_ext *)extbuf;
  if (extlen == 0 || (extlen % 8)) {
    return (-1);
  }
  if (ext) {
    ext->ip6e_len = (extlen >> 3) - 1;
  }
  return (2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inet6_opt_init>:
  endbr64
  test   %esi,%esi
  je     L8
  test   $0x7,%sil
  jne    L8
  mov    $0x2,%eax
  test   %rdi,%rdi
  je     L6
  sar    $0x3,%esi
  sub    $0x1,%esi
  mov    %esi,(%rdi)
  ret
  nopl   0x0(%rax)
L8:
  mov    $0xffffffff,%eax
L6:
  ret
```

assistant: ```c
int inet6_opt_init(void *extbuf, socklen_t extlen) {
  struct ip6_ext *ext = (struct ip6_ext *)extbuf;
  if (extlen == 0 || (extlen % 8)) {
    return (-1);
  }
  if (ext) {
    ext->ip6e_len = (extlen >> 3) - 1;
  }
  return (2);
}
```
user: What is the c source code of the assembly code below:

```asm
<sub_pred>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L2:
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L33:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x8(%rbp)
L29:
  cmpl   $0x7,-0x8(%rbp)
  jle    L33
  addq   $0x10,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L57
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x8(%rbp)
L57:
  cmpl   $0x7,-0x8(%rbp)
  jle    L22
  addq   $0x10,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0x3,-0x4(%rbp)
  jle    L2
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sub_pred(unsigned char *pred___0, unsigned char *cur, int lx, short *blk) {
  int i;
  int j;
  {
    j = 0;
    while (j < 4) {
      i = 0;
      while (i < 8) {
        *(blk + i) = (short)((int)*(cur + i) - (int)*(pred___0 + i));
        i++;
      }
      blk += 8;
      cur += lx;
      pred___0 += lx;
      i = 0;
      while (i < 8) {
        *(blk + i) = (short)((int)*(cur + i) - (int)*(pred___0 + i));
        i++;
      }
      blk += 8;
      cur += lx;
      pred___0 += lx;
      j++;
    }
    return;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sub_pred>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rcx,%r8
  lea    0x80(%rcx),%r11
  movslq %edx,%r9
  lea    (%r9,%r9,1),%r10
L15:
  mov    $0x0,%eax
L26:
  movzbl (%rsi,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  sub    %ecx,%edx
  mov    %dx,(%r8,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L26
  mov    %rsi,%rbp
  add    %r9,%rsi
  mov    %rdi,%rbx
  add    %r9,%rdi
  mov    $0x0,%eax
L10:
  movzbl (%rsi,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  sub    %ecx,%edx
  mov    %dx,0x10(%r8,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L10
  add    $0x20,%r8
  lea    0x0(%rbp,%r10,1),%rsi
  lea    (%rbx,%r10,1),%rdi
  cmp    %r8,%r11
  jne    L15
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sub_pred(unsigned char *pred___0, unsigned char *cur, int lx, short *blk) {
  int i;
  int j;
  {
    j = 0;
    while (j < 4) {
      i = 0;
      while (i < 8) {
        *(blk + i) = (short)((int)*(cur + i) - (int)*(pred___0 + i));
        i++;
      }
      blk += 8;
      cur += lx;
      pred___0 += lx;
      i = 0;
      while (i < 8) {
        *(blk + i) = (short)((int)*(cur + i) - (int)*(pred___0 + i));
        i++;
      }
      blk += 8;
      cur += lx;
      pred___0 += lx;
      j++;
    }
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sub_pred>:
  endbr64
  movslq %edx,%r10
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbx
  lea    (%r10,%r10,1),%r11
  lea    0x80(%rcx),%rbx
L9:
  xor    %eax,%eax
  nopl   0x0(%rax)
L22:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%r8,%rax,1),%esi
  sub    %esi,%edx
  mov    %dx,(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L22
  lea    (%rdi,%r10,1),%rbp
  lea    (%r8,%r10,1),%r9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl 0x0(%rbp,%rax,1),%edx
  movzbl (%r9,%rax,1),%esi
  sub    %esi,%edx
  mov    %dx,0x10(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L27
  add    $0x20,%rcx
  add    %r11,%rdi
  add    %r11,%r8
  cmp    %rbx,%rcx
  jne    L9
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sub_pred(unsigned char *pred___0, unsigned char *cur, int lx, short *blk) {
  int i;
  int j;
  {
    j = 0;
    while (j < 4) {
      i = 0;
      while (i < 8) {
        *(blk + i) = (short)((int)*(cur + i) - (int)*(pred___0 + i));
        i++;
      }
      blk += 8;
      cur += lx;
      pred___0 += lx;
      i = 0;
      while (i < 8) {
        *(blk + i) = (short)((int)*(cur + i) - (int)*(pred___0 + i));
        i++;
      }
      blk += 8;
      cur += lx;
      pred___0 += lx;
      j++;
    }
    return;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mulmp>:
  endbr64
  mov    %rdi,%rax
  movss  (%rdx),%xmm0
  movss  0x4(%rdx),%xmm5
  movss  0x8(%rdx),%xmm4
  movaps %xmm0,%xmm3
  mulss  (%rsi),%xmm3
  movaps %xmm5,%xmm1
  mulss  0x10(%rsi),%xmm1
  addss  %xmm1,%xmm3
  movaps %xmm4,%xmm1
  mulss  0x20(%rsi),%xmm1
  addss  %xmm1,%xmm3
  addss  0x30(%rsi),%xmm3
  movaps %xmm0,%xmm2
  mulss  0x4(%rsi),%xmm2
  movaps %xmm5,%xmm1
  mulss  0x14(%rsi),%xmm1
  addss  %xmm1,%xmm2
  movaps %xmm4,%xmm1
  mulss  0x24(%rsi),%xmm1
  addss  %xmm1,%xmm2
  addss  0x34(%rsi),%xmm2
  movaps %xmm0,%xmm1
  mulss  0x8(%rsi),%xmm1
  movaps %xmm5,%xmm6
  mulss  0x18(%rsi),%xmm6
  addss  %xmm6,%xmm1
  movaps %xmm4,%xmm6
  mulss  0x28(%rsi),%xmm6
  addss  %xmm6,%xmm1
  addss  0x38(%rsi),%xmm1
  mulss  0xc(%rsi),%xmm0
  mulss  0x1c(%rsi),%xmm5
  addss  %xmm5,%xmm0
  mulss  0x2c(%rsi),%xmm4
  addss  %xmm4,%xmm0
  addss  0x3c(%rsi),%xmm0
  ucomiss D15(%rip),%xmm0
  jp     L3
  jne    L3
L29:
  movss  %xmm3,(%rax)
  movss  %xmm2,0x4(%rax)
  movss  %xmm1,0x8(%rax)
  ret
L3:
  cvtss2sd %xmm0,%xmm0
  movsd  D8(%rip),%xmm4
  divsd  %xmm0,%xmm4
  cvtss2sd %xmm3,%xmm3
  mulsd  %xmm4,%xmm3
  cvtsd2ss %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm2
  mulsd  %xmm4,%xmm2
  cvtsd2ss %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  mulsd  %xmm4,%xmm1
  cvtsd2ss %xmm1,%xmm1
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_label: D15
type: byte[4]
name: unpack_data
arguments: data_label: D8
type: byte[8]

tool: {"D15": [0x00,0x00,0x80,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void mulmp(float *result, const float *s1, const float *s2) {
  const float x = s1[(0 + (0 << 2))] * s2[0] + s1[(0 + (1 << 2))] * s2[1] + s1[(0 + (2 << 2))] * s2[2] + s1[(0 + (3 << 2))];
  const float y = s1[(1 + (0 << 2))] * s2[0] + s1[(1 + (1 << 2))] * s2[1] + s1[(1 + (2 << 2))] * s2[2] + s1[(1 + (3 << 2))];
  const float z = s1[(2 + (0 << 2))] * s2[0] + s1[(2 + (1 << 2))] * s2[1] + s1[(2 + (2 << 2))] * s2[2] + s1[(2 + (3 << 2))];
  const float w = s1[(3 + (0 << 2))] * s2[0] + s1[(3 + (1 << 2))] * s2[1] + s1[(3 + (2 << 2))] * s2[2] + s1[(3 + (3 << 2))];
  if (w != 1) {
    const double l = 1 / (double)w;
    result[0] = (float)(x * l);
    result[1] = (float)(y * l);
    result[2] = (float)(z * l);
  } else {
    result[0] = x;
    result[1] = y;
    result[2] = z;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mulmp>:
  endbr64
  movss  (%rdx),%xmm0
  movss  0x4(%rdx),%xmm5
  mov    %rdi,%rax
  movss  (%rsi),%xmm3
  movss  0x10(%rsi),%xmm1
  movss  0x8(%rdx),%xmm4
  movss  0x4(%rsi),%xmm2
  mulss  %xmm5,%xmm1
  movss  0x18(%rsi),%xmm6
  mulss  %xmm0,%xmm3
  mulss  %xmm0,%xmm2
  mulss  %xmm5,%xmm6
  addss  %xmm1,%xmm3
  movss  0x20(%rsi),%xmm1
  mulss  %xmm4,%xmm1
  addss  %xmm1,%xmm3
  movss  0x14(%rsi),%xmm1
  addss  0x30(%rsi),%xmm3
  mulss  %xmm5,%xmm1
  mulss  0x1c(%rsi),%xmm5
  addss  %xmm1,%xmm2
  movss  0x24(%rsi),%xmm1
  mulss  %xmm4,%xmm1
  addss  %xmm1,%xmm2
  movss  0x8(%rsi),%xmm1
  addss  0x34(%rsi),%xmm2
  mulss  %xmm0,%xmm1
  mulss  0xc(%rsi),%xmm0
  addss  %xmm6,%xmm1
  movss  0x28(%rsi),%xmm6
  addss  %xmm5,%xmm0
  mulss  %xmm4,%xmm6
  mulss  0x2c(%rsi),%xmm4
  addss  %xmm6,%xmm1
  addss  0x38(%rsi),%xmm1
  addss  %xmm4,%xmm0
  addss  0x3c(%rsi),%xmm0
  ucomiss D11(%rip),%xmm0
  jp     L11
  jne    L11
  movss  %xmm3,(%rax)
  movss  %xmm2,0x4(%rax)
  movss  %xmm1,0x8(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm3
  cvtss2sd %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm1
  movsd  D14(%rip),%xmm4
  divsd  %xmm0,%xmm4
  mulsd  %xmm4,%xmm3
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm1
  cvtsd2ss %xmm3,%xmm3
  movss  %xmm3,(%rax)
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,0x4(%rax)
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0x8(%rax)
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
type_infered: byte[4]
name: read_data
arguments: data_label: D14
type_infered: byte[8]

tool: {"D11": [0x00,0x00,0x80,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void mulmp(float *result, const float *s1, const float *s2) {
  const float x = s1[(0 + (0 << 2))] * s2[0] + s1[(0 + (1 << 2))] * s2[1] + s1[(0 + (2 << 2))] * s2[2] + s1[(0 + (3 << 2))];
  const float y = s1[(1 + (0 << 2))] * s2[0] + s1[(1 + (1 << 2))] * s2[1] + s1[(1 + (2 << 2))] * s2[2] + s1[(1 + (3 << 2))];
  const float z = s1[(2 + (0 << 2))] * s2[0] + s1[(2 + (1 << 2))] * s2[1] + s1[(2 + (2 << 2))] * s2[2] + s1[(2 + (3 << 2))];
  const float w = s1[(3 + (0 << 2))] * s2[0] + s1[(3 + (1 << 2))] * s2[1] + s1[(3 + (2 << 2))] * s2[2] + s1[(3 + (3 << 2))];
  if (w != 1) {
    const double l = 1 / (double)w;
    result[0] = (float)(x * l);
    result[1] = (float)(y * l);
    result[2] = (float)(z * l);
  } else {
    result[0] = x;
    result[1] = y;
    result[2] = z;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mulmp>:
  endbr64
  movq   (%rdx),%xmm2
  movq   (%rsi),%xmm0
  mov    %rdi,%rcx
  movss  0x8(%rdx),%xmm3
  movaps %xmm2,%xmm5
  movaps %xmm2,%xmm1
  movaps %xmm2,%xmm6
  shufps $0xe5,%xmm2,%xmm2
  shufps $0xe0,%xmm5,%xmm5
  mulps  %xmm5,%xmm0
  movq   0x10(%rsi),%xmm5
  shufps $0xe5,%xmm6,%xmm6
  movaps %xmm6,%xmm4
  mulps  %xmm2,%xmm5
  movq   0x20(%rsi),%xmm2
  mulss  0x1c(%rsi),%xmm4
  addps  %xmm5,%xmm0
  movaps %xmm3,%xmm5
  shufps $0xe0,%xmm5,%xmm5
  mulps  %xmm5,%xmm2
  movss  0x18(%rsi),%xmm5
  mulss  %xmm6,%xmm5
  addps  %xmm2,%xmm0
  movq   0x30(%rsi),%xmm2
  addps  %xmm2,%xmm0
  movss  0x8(%rsi),%xmm2
  mulss  %xmm1,%xmm2
  mulss  0xc(%rsi),%xmm1
  addss  %xmm5,%xmm2
  movss  0x28(%rsi),%xmm5
  addss  %xmm4,%xmm1
  mulss  %xmm3,%xmm5
  mulss  0x2c(%rsi),%xmm3
  addss  %xmm5,%xmm2
  addss  0x38(%rsi),%xmm2
  addss  %xmm3,%xmm1
  addss  0x3c(%rsi),%xmm1
  ucomiss D5(%rip),%xmm1
  jp     L14
  jne    L14
  movlps %xmm0,(%rcx)
  movss  %xmm2,0x8(%rcx)
  ret
  nopl   0x0(%rax)
L14:
  movsd  D7(%rip),%xmm3
  cvtss2sd %xmm1,%xmm1
  cvtps2pd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  divsd  %xmm1,%xmm3
  mulsd  %xmm3,%xmm2
  movapd %xmm3,%xmm1
  unpcklpd %xmm1,%xmm1
  mulpd  %xmm1,%xmm0
  cvtsd2ss %xmm2,%xmm2
  movss  %xmm2,0x8(%rcx)
  cvtpd2ps %xmm0,%xmm0
  movlps %xmm0,(%rcx)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
type_guessed: byte[4]
name: extract_symbolic_data
arguments: label: D7
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void mulmp(float *result, const float *s1, const float *s2) {
  const float x = s1[(0 + (0 << 2))] * s2[0] + s1[(0 + (1 << 2))] * s2[1] + s1[(0 + (2 << 2))] * s2[2] + s1[(0 + (3 << 2))];
  const float y = s1[(1 + (0 << 2))] * s2[0] + s1[(1 + (1 << 2))] * s2[1] + s1[(1 + (2 << 2))] * s2[2] + s1[(1 + (3 << 2))];
  const float z = s1[(2 + (0 << 2))] * s2[0] + s1[(2 + (1 << 2))] * s2[1] + s1[(2 + (2 << 2))] * s2[2] + s1[(2 + (3 << 2))];
  const float w = s1[(3 + (0 << 2))] * s2[0] + s1[(3 + (1 << 2))] * s2[1] + s1[(3 + (2 << 2))] * s2[2] + s1[(3 + (3 << 2))];
  if (w != 1) {
    const double l = 1 / (double)w;
    result[0] = (float)(x * l);
    result[1] = (float)(y * l);
    result[2] = (float)(z * l);
  } else {
    result[0] = x;
    result[1] = y;
    result[2] = z;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L19
L21:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jg     L20
  mov    $0xffffffff,%eax
  jmp    L29
L20:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x10(%rbp)
L19:
  cmpl   $0x0,-0x10(%rbp)
  jg     L21
  mov    -0x18(%rbp),%eax
L29:
  leave
  ret
```

assistant: ```c
int read_socket(int client_fd, void *buf, int buf_size) {
  int ecode, to_read = buf_size;
  uint8_t *ptr = (uint8_t *)buf;
  while (to_read > 0) {
    ecode = read(client_fd, ptr, to_read);
    if (ecode <= 0)
      return -1;
    ptr += ecode;
    to_read -= ecode;
  }
  return buf_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_socket>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L16
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
L10:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L28
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,4),%rbp
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L10
  jmp    L16
L28:
  mov    $0xffffffff,%r13d
L16:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_socket(int client_fd, void *buf, int buf_size) {
  int ecode, to_read = buf_size;
  uint8_t *ptr = (uint8_t *)buf;
  while (to_read > 0) {
    ecode = read(client_fd, ptr, to_read);
    if (ecode <= 0)
      return -1;
    ptr += ecode;
    to_read -= ecode;
  }
  return buf_size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_socket>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L33
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L8
  nop
L22:
  movslq %eax,%rdx
  sub    %eax,%ebx
  lea    0x0(%rbp,%rdx,4),%rbp
  test   %ebx,%ebx
  jle    L33
L8:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L22
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L33:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_socket(int client_fd, void *buf, int buf_size) {
  int ecode, to_read = buf_size;
  uint8_t *ptr = (uint8_t *)buf;
  while (to_read > 0) {
    ecode = read(client_fd, ptr, to_read);
    if (ecode <= 0)
      return -1;
    ptr += ecode;
    to_read -= ecode;
  }
  return buf_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_socket>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L34
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  jmp    L5
  nop
L22:
  movslq %eax,%rdx
  sub    %eax,%ebx
  lea    0x0(%rbp,%rdx,4),%rbp
  test   %ebx,%ebx
  jle    L34
L5:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L22
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L34:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int read_socket(int client_fd, void *buf, int buf_size) {
  int ecode, to_read = buf_size;
  uint8_t *ptr = (uint8_t *)buf;
  while (to_read > 0) {
    ecode = read(client_fd, ptr, to_read);
    if (ecode <= 0)
      return -1;
    ptr += ecode;
    to_read -= ecode;
  }
  return buf_size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<HsStrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *HsStrchr(char *s, int c) {
  char *a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HsStrchr>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *HsStrchr(char *s, int c) {
  char *a;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HsStrchr>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *HsStrchr(char *s, int c) {
  char *a;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<HsStrchr>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *HsStrchr(char *s, int c) {
  char *a;
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%eax
  call   <print_full_usage@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void usage() {
  print_version();
  print_full_usage();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%eax
  call   <print_full_usage@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void usage() {
  print_version();
  print_full_usage();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_version@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <print_full_usage@plt>
```

assistant: ```c
void usage() {
  print_version();
  print_full_usage();
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <print_version@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <print_full_usage@plt>
```

assistant: ```c
void usage() {
  print_version();
  print_full_usage();
}
```
user: Translate the below assembly code into C programming language:

```asm
<ol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  jmp    L13
L48:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x4,%edx
  je     L18
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x7,%edx
  jne    L3
L18:
  mov    $0x1,%eax
  jmp    L41
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x4(%rbp)
  jne    L48
  mov    $0x0,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
int ol(int n) {
  while (n)
    if ((n % 10 == 4) || (n % 10 == 7))
      return 1;
    else
      n /= 10;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ol>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L15
  movslq %edi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%edx
  sub    %ecx,%edx
  add    $0x9,%edx
  mov    $0x12000,%ecx
  bt     %rdx,%rcx
  jb     L28
  mov    $0x12000,%esi
L29:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    %edx,%eax
  je     L31
  movslq %edx,%rcx
  imul   $0x66666667,%rcx,%rcx
  sar    $0x22,%rcx
  mov    %edx,%edi
  sar    $0x1f,%edi
  sub    %edi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x9,%edx
  bt     %rdx,%rsi
  jae    L29
  mov    $0x1,%eax
L15:
  ret
L31:
  ret
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ol(int n) {
  while (n)
    if ((n % 10 == 4) || (n % 10 == 7))
      return 1;
    else
      n /= 10;
  return 0;
}
```