ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<wait_busy>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <_c2_addr_read@plt>
  test   $0x2,%al
  jne    L0
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_busy(void) {
  while (_c2_addr_read() & (1 << 1))
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wait_busy>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <_c2_addr_read@plt>
  test   $0x2,%al
  jne    L7
  add    $0x8,%rsp
  ret
```

assistant: ```c
void wait_busy(void) {
  while (_c2_addr_read() & (1 << 1))
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dmm_destruct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <dmm_make_snapshot@plt>
  mov    $0x0,%eax
  call   <stdlib_release@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: DMM exiting...


assistant: ```c
void __attribute__((destructor)) dmm_destruct(void) {
  printf("DMM exiting...\n");
  dmm_make_snapshot(0);
  stdlib_release();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dmm_destruct>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <dmm_make_snapshot@plt>
  mov    $0x0,%eax
  call   <stdlib_release@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: DMM exiting...


assistant: ```c
void __attribute__((destructor)) dmm_destruct(void) {
  printf("DMM exiting...\n");
  dmm_make_snapshot(0);
  stdlib_release();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dmm_destruct>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <dmm_make_snapshot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <stdlib_release@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: DMM exiting...


assistant: ```c
void __attribute__((destructor)) dmm_destruct(void) {
  printf("DMM exiting...\n");
  dmm_make_snapshot(0);
  stdlib_release();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dmm_destruct>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  call   <dmm_make_snapshot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <stdlib_release@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: DMM exiting...


assistant: ```c
void __attribute__((destructor)) dmm_destruct(void) {
  printf("DMM exiting...\n");
  dmm_make_snapshot(0);
  stdlib_release();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 2;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 2;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 2;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x2,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 2;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lcd_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L119
L96:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0xd,%eax
  je     L101
  cmp    $0xd,%eax
  jg     L68
  cmp    $0x9,%eax
  je     L41
  cmp    $0xa,%eax
  jne    L68
  mov    $0xffffffc0,%esi
  mov    $0x0,%edi
  call   <lcd_write@plt>
  jmp    L54
L101:
  mov    $0xffffff80,%esi
  mov    $0x0,%edi
  call   <lcd_write@plt>
  jmp    L54
L41:
  mov    $0x0,%edi
  call   <lcd_read@plt>
  and    $0x7f,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L3
L55:
  mov    $0x20,%esi
  mov    $0x1,%edi
  call   <lcd_write@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L55
  cmpl   $0xf,-0x4(%rbp)
  jle    L26
  mov    $0xffffffc0,%esi
  mov    $0x0,%edi
  call   <lcd_write@plt>
  jmp    L26
L68:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <lcd_write@plt>
  jmp    L54
L26:
  nop
L54:
  addq   $0x1,-0x18(%rbp)
L119:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L96
  nop
  nop
  leave
  ret
```

assistant: ```c
void lcd_puts(char *s) {
  int c;
  for (; *s; s++) {
    switch (*s) {
    case '\n':
      lcd_write(0, (0x40) | 0x80);
      break;
    case '\r':
      lcd_write(0, (0) | 0x80);
      break;
    case '\t':
      c = (lcd_read(0) & 0x7F);
      while (c & 7) {
        lcd_write(1, (' '));
        c++;
      }
      if (c > 15)
        lcd_write(0, (0x40) | 0x80);
      break;
    default:
      lcd_write(1, (*s));
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lcd_puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%esi
  test   %sil,%sil
  jne    L5
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0xffffffc0,%esi
  mov    $0x0,%edi
  call   <lcd_write@plt>
L86:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L50
L5:
  cmp    $0xa,%sil
  je     L3
  cmp    $0xd,%sil
  je     L11
  cmp    $0x9,%sil
  je     L20
  movsbl %sil,%esi
  mov    $0x1,%edi
  call   <lcd_write@plt>
  jmp    L86
L11:
  mov    $0xffffff80,%esi
  mov    $0x0,%edi
  call   <lcd_write@plt>
  jmp    L86
L20:
  mov    $0x0,%edi
  call   <lcd_read@plt>
  mov    %eax,%ebx
  and    $0x7f,%ebx
  test   $0x7,%al
  je     L58
L57:
  mov    $0x20,%esi
  mov    $0x1,%edi
  call   <lcd_write@plt>
  add    $0x1,%ebx
  test   $0x7,%bl
  jne    L57
L58:
  cmp    $0xf,%ebx
  jle    L86
  mov    $0xffffffc0,%esi
  mov    $0x0,%edi
  call   <lcd_write@plt>
  jmp    L86
```

assistant: ```c
void lcd_puts(char *s) {
  int c;
  for (; *s; s++) {
    switch (*s) {
    case '\n':
      lcd_write(0, (0x40) | 0x80);
      break;
    case '\r':
      lcd_write(0, (0) | 0x80);
      break;
    case '\t':
      c = (lcd_read(0) & 0x7F);
      while (c & 7) {
        lcd_write(1, (' '));
        c++;
      }
      if (c > 15)
        lcd_write(0, (0x40) | 0x80);
      break;
    default:
      lcd_write(1, (*s));
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<lcd_puts>:
  endbr64
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L52
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L54:
  cmp    $0x9,%sil
  je     L109
  mov    $0x1,%edi
  call   <lcd_write@plt>
L23:
  movsbl 0x1(%rbp),%esi
  add    $0x1,%rbp
  test   %sil,%sil
  je     L105
L65:
  cmp    $0xa,%sil
  je     L1
  cmp    $0xd,%sil
  jne    L54
  mov    $0xffffff80,%esi
  xor    %edi,%edi
  add    $0x1,%rbp
  call   <lcd_write@plt>
  movsbl 0x0(%rbp),%esi
  test   %sil,%sil
  jne    L65
L105:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L109:
  xor    %edi,%edi
  call   <lcd_read@plt>
  mov    %eax,%ebx
  and    $0x7f,%ebx
  test   $0x7,%al
  je     L46
L44:
  mov    $0x20,%esi
  mov    $0x1,%edi
  add    $0x1,%ebx
  call   <lcd_write@plt>
  test   $0x7,%bl
  jne    L44
L46:
  cmp    $0xf,%ebx
  jle    L23
L1:
  mov    $0xffffffc0,%esi
  xor    %edi,%edi
  call   <lcd_write@plt>
  jmp    L23
L52:
  ret
```

assistant: ```c
void lcd_puts(char *s) {
  int c;
  for (; *s; s++) {
    switch (*s) {
    case '\n':
      lcd_write(0, (0x40) | 0x80);
      break;
    case '\r':
      lcd_write(0, (0) | 0x80);
      break;
    case '\t':
      c = (lcd_read(0) & 0x7F);
      while (c & 7) {
        lcd_write(1, (' '));
        c++;
      }
      if (c > 15)
        lcd_write(0, (0x40) | 0x80);
      break;
    default:
      lcd_write(1, (*s));
      break;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<lcd_puts>:
  endbr64
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L30
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L76:
  cmp    $0x9,%sil
  je     L0
  mov    $0x1,%edi
  call   <lcd_write@plt>
L62:
  movsbl 0x1(%rbp),%esi
  add    $0x1,%rbp
  test   %sil,%sil
  je     L10
L53:
  cmp    $0xa,%sil
  je     L39
  cmp    $0xd,%sil
  jne    L76
  mov    $0xffffff80,%esi
  xor    %edi,%edi
  add    $0x1,%rbp
  call   <lcd_write@plt>
  movsbl 0x0(%rbp),%esi
  test   %sil,%sil
  jne    L53
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  xor    %edi,%edi
  call   <lcd_read@plt>
  mov    %eax,%ebx
  and    $0x7f,%ebx
  test   $0x7,%al
  je     L79
L40:
  mov    $0x20,%esi
  mov    $0x1,%edi
  add    $0x1,%ebx
  call   <lcd_write@plt>
  test   $0x7,%bl
  jne    L40
L79:
  cmp    $0xf,%ebx
  jle    L62
L39:
  mov    $0xffffffc0,%esi
  xor    %edi,%edi
  call   <lcd_write@plt>
  jmp    L62
L30:
  ret
```

assistant: ```c
void lcd_puts(char *s) {
  int c;
  for (; *s; s++) {
    switch (*s) {
    case '\n':
      lcd_write(0, (0x40) | 0x80);
      break;
    case '\r':
      lcd_write(0, (0) | 0x80);
      break;
    case '\t':
      c = (lcd_read(0) & 0x7F);
      while (c & 7) {
        lcd_write(1, (' '));
        c++;
      }
      if (c > 15)
        lcd_write(0, (0x40) | 0x80);
      break;
    default:
      lcd_write(1, (*s));
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_opt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jle    L23
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L38
L23:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L38:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x6d,%al
  jne    L28
  mov    $0x1,%eax
  jmp    L36
L28:
  mov    $0x0,%eax
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: USAGE: hash -t|-m nom [,nom]*

assistant: ```c
int parse_opt(int argc, char *argv[]) {
  if (argc < 3 || argv[1][0] != '-') {
    puts("USAGE: hash -t|-m nom [,nom]*");
    exit(1);
  }
  if (argv[1][1] == 'm')
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_opt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jle    L8
  mov    0x8(%rsi),%rax
  cmpb   $0x2d,(%rax)
  je     L17
L8:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L17:
  mov    0x8(%rbx),%rax
  cmpb   $0x6d,0x1(%rax)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: USAGE: hash -t|-m nom [,nom]*

assistant: ```c
int parse_opt(int argc, char *argv[]) {
  if (argc < 3 || argv[1][0] != '-') {
    puts("USAGE: hash -t|-m nom [,nom]*");
    exit(1);
  }
  if (argv[1][1] == 'm')
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_opt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jle    L8
  mov    0x8(%rsi),%rax
  cmpb   $0x2d,(%rax)
  je     L5
L8:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    0x8(%rbx),%rax
L5:
  cmpb   $0x6d,0x1(%rax)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type_guessed: string

tool: D9: USAGE: hash -t|-m nom [,nom]*

assistant: ```c
int parse_opt(int argc, char *argv[]) {
  if (argc < 3 || argv[1][0] != '-') {
    puts("USAGE: hash -t|-m nom [,nom]*");
    exit(1);
  }
  if (argv[1][1] == 'm')
    return 1;
  else
    return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<parse_opt>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x2,%edi
  jle    L16
  mov    0x8(%rsi),%rax
  cmpb   $0x2d,(%rax)
  je     L12
L16:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    0x8(%rbx),%rax
L12:
  cmpb   $0x6d,0x1(%rax)
  pop    %rbx
  sete   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: string

tool: D2: USAGE: hash -t|-m nom [,nom]*

assistant: ```c
int parse_opt(int argc, char *argv[]) {
  if (argc < 3 || argv[1][0] != '-') {
    puts("USAGE: hash -t|-m nom [,nom]*");
    exit(1);
  }
  if (argv[1][1] == 'm')
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: Place Holder Main function...


assistant: ```c
int main(int argc, char **argv) {
  printf("Place Holder Main function...\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: Place Holder Main function...


assistant: ```c
int main(int argc, char **argv) {
  printf("Place Holder Main function...\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: Place Holder Main function...


assistant: ```c
int main(int argc, char **argv) {
  printf("Place Holder Main function...\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: Place Holder Main function...


assistant: ```c
int main(int argc, char **argv) {
  printf("Place Holder Main function...\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L29
  mov    $0x0,%eax
  jmp    L22
L29:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L45
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
L0:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L45:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L23
  mov    $0x1,%eax
L22:
  leave
  ret
```

assistant: ```c
int get_line(FILE *file, char *buf, int size) {
  char *ptmp;
  int length;
  int i;
  ptmp = fgets(buf, (size - 1), file);
  if (ptmp == (char *)NULL) {
    if (0 >= 10)
      (void)printf("get_line EOF\n");
    return 0;
  }
  if (0 >= 10)
    (void)printf("before strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  length = strlen(ptmp);
  for (i = 0; i < length; i++) {
    if (*ptmp == '\n')
      *ptmp = ' ';
    ptmp++;
  }
  if (0 >= 10)
    (void)printf("after strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%esi
  mov    %rax,%rdx
  call   <fgets@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L32
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L30
  mov    %eax,%eax
  add    %rbx,%rax
  jmp    L45
L63:
  add    $0x1,%rbx
  cmp    %rax,%rbx
  je     L7
L45:
  cmpb   $0xa,(%rbx)
  jne    L63
  movb   $0x20,(%rbx)
  jmp    L63
L7:
  mov    $0x1,%eax
L32:
  pop    %rbx
  ret
L30:
  mov    $0x1,%eax
  jmp    L32
```

assistant: ```c
int get_line(FILE *file, char *buf, int size) {
  char *ptmp;
  int length;
  int i;
  ptmp = fgets(buf, (size - 1), file);
  if (ptmp == (char *)NULL) {
    if (0 >= 10)
      (void)printf("get_line EOF\n");
    return 0;
  }
  if (0 >= 10)
    (void)printf("before strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  length = strlen(ptmp);
  for (i = 0; i < length; i++) {
    if (*ptmp == '\n')
      *ptmp = ' ';
    ptmp++;
  }
  if (0 >= 10)
    (void)printf("after strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_line>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%esi
  mov    %r8,%rdx
  call   <fgets@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  je     L17
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  add    %rbx,%rdx
  test   %eax,%eax
  jle    L32
  nopw   0x0(%rax,%rax,1)
L23:
  cmpb   $0xa,(%rbx)
  jne    L8
  movb   $0x20,(%rbx)
L8:
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L23
L32:
  mov    $0x1,%eax
L17:
  pop    %rbx
  ret
```

assistant: ```c
int get_line(FILE *file, char *buf, int size) {
  char *ptmp;
  int length;
  int i;
  ptmp = fgets(buf, (size - 1), file);
  if (ptmp == (char *)NULL) {
    if (0 >= 10)
      (void)printf("get_line EOF\n");
    return 0;
  }
  if (0 >= 10)
    (void)printf("before strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  length = strlen(ptmp);
  for (i = 0; i < length; i++) {
    if (*ptmp == '\n')
      *ptmp = ' ';
    ptmp++;
  }
  if (0 >= 10)
    (void)printf("after strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_line>:
  endbr64
  push   %rbx
  mov    %rdi,%r8
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%esi
  mov    %r8,%rdx
  call   <fgets@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  je     L26
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  add    %rbx,%rdx
  test   %eax,%eax
  jle    L39
  nopw   0x0(%rax,%rax,1)
L15:
  cmpb   $0xa,(%rbx)
  jne    L37
  movb   $0x20,(%rbx)
L37:
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L15
L39:
  mov    $0x1,%eax
L26:
  pop    %rbx
  ret
```

assistant: ```c
int get_line(FILE *file, char *buf, int size) {
  char *ptmp;
  int length;
  int i;
  ptmp = fgets(buf, (size - 1), file);
  if (ptmp == (char *)NULL) {
    if (0 >= 10)
      (void)printf("get_line EOF\n");
    return 0;
  }
  if (0 >= 10)
    (void)printf("before strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  length = strlen(ptmp);
  for (i = 0; i < length; i++) {
    if (*ptmp == '\n')
      *ptmp = ' ';
    ptmp++;
  }
  if (0 >= 10)
    (void)printf("after strip:\nbuf  is <%s>\nptmp is <%s>\n", buf, ptmp);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L14
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <problem@plt>
L14:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L34
L35:
  mov    -0x30(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %rdx,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <problem@plt>
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L34:
  mov    -0x1c(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L35
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D5: allocation failure 1 in cmatrix()

tool: D2: allocation failure 2 in imatrix()

assistant: ```c
char **cmatrix(nrl, nrh, ncl, nch)
int nrl, nrh, ncl, nch;
{
  int i;
  char **m;
  m = (char **)malloc((unsigned)(nrh - nrl + 1) * sizeof(char *));
  if (!m)
    problem("allocation failure 1 in cmatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (char *)malloc((unsigned)(nch - ncl + 1) * sizeof(char));
    if (!m[i])
      problem("allocation failure 2 in imatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%r12d
  mov    %ecx,%r15d
  mov    %esi,%eax
  sub    %edi,%eax
  lea    0x1(%rax),%edi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L31
L45:
  movslq %r14d,%rbx
  lea    0x0(,%rbx,8),%rax
  sub    %rax,%rbp
  cmp    %r14d,%r13d
  jl     L22
  sub    %r12d,%r15d
  lea    0x1(%r15),%r14d
  lea    D14(%rip),%r15
  movslq %r12d,%r12
L9:
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  je     L30
L29:
  sub    %r12,0x0(%rbp,%rbx,8)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jge    L9
L22:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <problem@plt>
  jmp    L45
L30:
  mov    %r15,%rdi
  call   <problem@plt>
  jmp    L29
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D10
datatype: string

tool: D14: allocation failure 2 in imatrix()

tool: D10: allocation failure 1 in cmatrix()

assistant: ```c
char **cmatrix(nrl, nrh, ncl, nch)
int nrl, nrh, ncl, nch;
{
  int i;
  char **m;
  m = (char **)malloc((unsigned)(nrh - nrl + 1) * sizeof(char *));
  if (!m)
    problem("allocation failure 1 in cmatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (char *)malloc((unsigned)(nch - ncl + 1) * sizeof(char));
    if (!m[i])
      problem("allocation failure 2 in imatrix()");
    m[i] -= ncl;
  }
  return m;
}
```