ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<kepler>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsd  (%rdi),%xmm0
  movsd  0x10(%rdi),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movsd  D1(%rip),%xmm1
  call   <pow@plt>
  mov    %eax,%edi
  call   <sqrt@plt>
  movsd  0x8(%rbx),%xmm1
  movq   D9(%rip),%xmm2
  movsd  %xmm1,0x0(%rbp)
  movsd  (%rbx),%xmm1
  xorpd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rbp)
  movsd  0x18(%rbx),%xmm1
  movsd  %xmm1,0x10(%rbp)
  movsd  0x10(%rbx),%xmm1
  xorpd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: f64
name: parse_data
arguments: data_label: D9
data_type: f32[2]

tool: D1: 3

tool: {"D9": [0.0,-0.0]}

assistant: ```c
void kepler(double t, double *u, double *up) {
  double r3 = sqrt(pow(u[0] * u[0] + u[2] * u[2], 3.0));
  up[0] = u[1];
  up[1] = -u[0] / r3;
  up[2] = u[3];
  up[3] = -u[2] / r3;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RemoveCmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int RemoveCmd(pcmd, argv)
char **pcmd;
char *argv[];
{ return 0; }
```
user: Translate the below assembly code into C programming language:

```asm
<RemoveCmd>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int RemoveCmd(pcmd, argv)
char **pcmd;
char *argv[];
{ return 0; }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RemoveCmd>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int RemoveCmd(pcmd, argv)
char **pcmd;
char *argv[];
{ return 0; }
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<RemoveCmd>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int RemoveCmd(pcmd, argv)
char **pcmd;
char *argv[];
{ return 0; }
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <t21@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: completed successfully


assistant: ```c
int main(int argc, char *const argv[]) {
  t21();
  printf("completed successfully\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <t21@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D4: completed successfully


assistant: ```c
int main(int argc, char *const argv[]) {
  t21();
  printf("completed successfully\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <t21@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D3: completed successfully


assistant: ```c
int main(int argc, char *const argv[]) {
  t21();
  printf("completed successfully\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <t21@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: completed successfully


assistant: ```c
int main(int argc, char *const argv[]) {
  t21();
  printf("completed successfully\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_to_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
L9:
  mov    -0x28(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L9
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
int write_to_fd(int fd, char *buf, size_t count) {
  ssize_t pos = 0;
  ssize_t rv = 0;
  do {
    rv = write(fd, buf + pos, count - pos);
    if (rv < 0)
      return -errno;
    pos += rv;
  } while (count > pos);
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_to_fd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L4:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  call   <write@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L4
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_to_fd(int fd, char *buf, size_t count) {
  ssize_t pos = 0;
  ssize_t rv = 0;
  do {
    rv = write(fd, buf + pos, count - pos);
    if (rv < 0)
      return -errno;
    pos += rv;
  } while (count > pos);
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_to_fd>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  sub    %rbx,%rdx
  call   <write@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L1
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_to_fd(int fd, char *buf, size_t count) {
  ssize_t pos = 0;
  ssize_t rv = 0;
  do {
    rv = write(fd, buf + pos, count - pos);
    if (rv < 0)
      return -errno;
    pos += rv;
  } while (count > pos);
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_to_fd>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  sub    %rbx,%rdx
  call   <write@plt>
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L2
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_to_fd(int fd, char *buf, size_t count) {
  ssize_t pos = 0;
  ssize_t rv = 0;
  do {
    rv = write(fd, buf + pos, count - pos);
    if (rv < 0)
      return -errno;
    pos += rv;
  } while (count > pos);
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readdip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <write_max@plt>
  mov    $0x2,%edi
  call   <read_max@plt>
  pop    %rbp
  ret
```

assistant: ```c
unsigned char readdip() {
  write_max(0x4, 0x00);
  return read_max(0x2);
}
```
user: What is the c source code of the assembly code below?

```asm
<readdip>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <write_max@plt>
  mov    $0x2,%edi
  call   <read_max@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned char readdip() {
  write_max(0x4, 0x00);
  return read_max(0x2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<readdip>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  xor    %esi,%esi
  call   <write_max@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1060 <read_max@plt>
```

assistant: ```c
unsigned char readdip() {
  write_max(0x4, 0x00);
  return read_max(0x2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readdip>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  xor    %esi,%esi
  call   <write_max@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1060 <read_max@plt>
```

assistant: ```c
unsigned char readdip() {
  write_max(0x4, 0x00);
  return read_max(0x2);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1e,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string

tool: D9: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", foo(0, 10));
  printf("%d\n", foo(30, 100));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%esi
  mov    $0x0,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1e,%edi
  call   <foo@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", foo(0, 10));
  printf("%d\n", foo(30, 100));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  xor    %edi,%edi
  lea    D0(%rip),%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1e,%edi
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", foo(0, 10));
  printf("%d\n", foo(30, 100));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  xor    %edi,%edi
  lea    D4(%rip),%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x64,%esi
  mov    $0x1e,%edi
  call   <foo@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: %d


assistant: ```c
int main(int argc, char **argv) {
  printf("%d\n", foo(0, 10));
  printf("%d\n", foo(30, 100));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xb,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0xd,-0x28(%rbp)
  movl   $0xe,-0x24(%rbp)
  movl   $0xf,-0x20(%rbp)
  movl   $0x10,-0x1c(%rbp)
  movl   $0x11,-0x18(%rbp)
  movl   $0x12,-0x14(%rbp)
  movl   $0x13,-0x10(%rbp)
  movl   $0x14,-0xc(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x1,-0x38(%rbp)
  jmp    L59
L0:
  movl   $0x0,-0x3c(%rbp)
  addl   $0x1,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L53
L20:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%ecx
  mov    -0x38(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L40
  addl   $0x1,-0x3c(%rbp)
L40:
  addl   $0x1,-0x34(%rbp)
L53:
  cmpl   $0x9,-0x34(%rbp)
  jle    L20
L59:
  cmpl   $0xa,-0x3c(%rbp)
  jne    L0
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: The number is: %d


assistant: ```c
int main() {
  int arr[] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20};
  int found = 0;
  int number = 1;
  int i;
  while (found != 10) {
    found = 0;
    number++;
    for (i = 0; i < 10; i++) {
      if (number % arr[i] == 0)
        found += 1;
    }
  };
  printf("The number is: %d\n", number);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xb,(%rsp)
  movl   $0xc,0x4(%rsp)
  movl   $0xd,0x8(%rsp)
  movl   $0xe,0xc(%rsp)
  movl   $0xf,0x10(%rsp)
  movl   $0x10,0x14(%rsp)
  movl   $0x11,0x18(%rsp)
  movl   $0x12,0x1c(%rsp)
  movl   $0x13,0x20(%rsp)
  movl   $0x14,0x24(%rsp)
  mov    $0x1,%esi
  lea    0x28(%rsp),%r8
L15:
  add    $0x1,%esi
  mov    %rsp,%rcx
  mov    $0x0,%edi
L11:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  cmp    $0x1,%edx
  adc    $0x0,%edi
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L11
  cmp    $0xa,%edi
  jne    L15
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: The number is: %d


assistant: ```c
int main() {
  int arr[] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20};
  int found = 0;
  int number = 1;
  int i;
  while (found != 10) {
    found = 0;
    number++;
    for (i = 0; i < 10; i++) {
      if (number % arr[i] == 0)
        found += 1;
    }
  };
  printf("The number is: %d\n", number);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x1,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xc,0x4(%rsp)
  lea    0x4(%rsp),%r10
  movabs $0xe0000000d,%rax
  mov    %rax,0x8(%rsp)
  lea    0x28(%rsp),%r9
  movabs $0x100000000f,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1200000011,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x1400000013,%rax
  mov    %rax,0x20(%rsp)
  nopl   0x0(%rax)
L37:
  add    $0x1,%r8d
  mov    %r10,%rcx
  mov    $0xb,%esi
  xor    %edi,%edi
  jmp    L35
L22:
  mov    (%rcx),%esi
  add    $0x4,%rcx
L35:
  mov    %r8d,%eax
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  adc    $0x0,%edi
  cmp    %r9,%rcx
  jne    L22
  cmp    $0xa,%edi
  jne    L37
  mov    %r8d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D1: The number is: %d


assistant: ```c
int main() {
  int arr[] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20};
  int found = 0;
  int number = 1;
  int i;
  while (found != 10) {
    found = 0;
    number++;
    for (i = 0; i < 10; i++) {
      if (number % arr[i] == 0)
        found += 1;
    }
  };
  printf("The number is: %d\n", number);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  xor    %eax,%eax
  nop
L26:
  imul   $0xc4ec4ec5,%esi,%edx
  cmp    $0x13b13b14,%edx
  adc    $0x0,%eax
  imul   $0xb6db6db7,%esi,%edx
  ror    %edx
  cmp    $0x12492493,%edx
  adc    $0x0,%eax
  imul   $0xeeeeeeef,%esi,%edx
  cmp    $0x11111112,%edx
  mov    %esi,%edx
  adc    $0x0,%eax
  and    $0xf,%edx
  cmp    $0x1,%edx
  adc    $0x0,%eax
  imul   $0xf0f0f0f1,%esi,%edx
  cmp    $0xf0f0f10,%edx
  adc    $0x0,%eax
  imul   $0x38e38e39,%esi,%edx
  ror    %edx
  cmp    $0xe38e38f,%edx
  adc    $0x0,%eax
  imul   $0x286bca1b,%esi,%edx
  cmp    $0xd79435e,%edx
  ja     L37
  imul   $0xcccccccd,%esi,%edx
  ror    $0x2,%edx
  cmp    $0xccccccc,%edx
  ja     L37
  cmp    $0x8,%eax
  jne    L37
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L37:
  add    $0x1,%esi
  imul   $0xba2e8ba3,%esi,%eax
  cmp    $0x1745d174,%eax
  setbe  %al
  imul   $0xaaaaaaab,%esi,%edx
  movzbl %al,%eax
  ror    $0x2,%edx
  cmp    $0x15555556,%edx
  adc    $0x0,%eax
  jmp    L26
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: The number is: %d


assistant: ```c
int main() {
  int arr[] = {11, 12, 13, 14, 15, 16, 17, 18, 19, 20};
  int found = 0;
  int number = 1;
  int i;
  while (found != 10) {
    found = 0;
    number++;
    for (i = 0; i < 10; i++) {
      if (number % arr[i] == 0)
        found += 1;
    }
  };
  printf("The number is: %d\n", number);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dotest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <consecKprimes@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <list2String@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  je     L4
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: Expected %d, got %d


assistant: ```c
void dotest(int k, struct list *l, int expr) {
  int act = consecKprimes(k, l);
  char *s = list2String(l);
  if (act != expr)
    printf("Expected %d, got %d\n", expr, act);
  assert(act == expr);
  free(s);
  s = NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dotest>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%ebx
  call   <consecKprimes@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <list2String@plt>
  mov    %rax,%r12
  cmp    %ebx,%ebp
  jne    L0
L4:
  cmp    %ebx,%ebp
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_infered: string

tool: D1: Expected %d, got %d


assistant: ```c
void dotest(int k, struct list *l, int expr) {
  int act = consecKprimes(k, l);
  char *s = list2String(l);
  if (act != expr)
    printf("Expected %d, got %d\n", expr, act);
  assert(act == expr);
  free(s);
  s = NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dotest>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <consecKprimes@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <list2String@plt>
  mov    %rax,%r12
  cmp    %ebx,%ebp
  je     L4
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
L4:
  xor    %edi,%edi
  cmp    %ebx,%ebp
  sete   %dil
  call   <assert@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: Expected %d, got %d


assistant: ```c
void dotest(int k, struct list *l, int expr) {
  int act = consecKprimes(k, l);
  char *s = list2String(l);
  if (act != expr)
    printf("Expected %d, got %d\n", expr, act);
  assert(act == expr);
  free(s);
  s = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dotest>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  call   <consecKprimes@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <list2String@plt>
  mov    %rax,%r12
  cmp    %ebx,%ebp
  je     L3
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
L3:
  xor    %edi,%edi
  cmp    %ebx,%ebp
  sete   %dil
  call   <assert@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string

tool: D7: Expected %d, got %d


assistant: ```c
void dotest(int k, struct list *l, int expr) {
  int act = consecKprimes(k, l);
  char *s = list2String(l);
  if (act != expr)
    printf("Expected %d, got %d\n", expr, act);
  assert(act == expr);
  free(s);
  s = NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x2b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x2a0(%rbp)
  movq   $0x1,-0x298(%rbp)
  movq   $0x2,-0x2a8(%rbp)
  jmp    L0
L7:
  mov    -0x2a8(%rbp),%rax
  sub    $0x1,%rax
  mov    -0x2a0(%rbp,%rax,8),%rdx
  mov    -0x2a8(%rbp),%rax
  sub    $0x2,%rax
  mov    -0x2a0(%rbp,%rax,8),%rax
  add    %rax,%rdx
  mov    -0x2a8(%rbp),%rax
  mov    %rdx,-0x2a0(%rbp,%rax,8)
  addq   $0x1,-0x2a8(%rbp)
L0:
  cmpq   $0x51,-0x2a8(%rbp)
  jle    L7
  lea    -0x2b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x0,-0x2a8(%rbp)
  jmp    L5
L43:
  mov    -0x2a8(%rbp),%rax
  mov    -0x2a0(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x2a8(%rbp)
L5:
  mov    -0x2b0(%rbp),%rax
  cmp    %rax,-0x2a8(%rbp)
  jle    L43
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x2b0(%rbp),%rax
  mov    -0x2a0(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2b0(%rbp),%rax
  add    $0x1,%rax
  mov    -0x2a0(%rbp,%rax,8),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D11
type_infered: string
name: read_data
arguments: label: D26
type_infered: string
name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D27
type_infered: string

tool: D25: %lld

tool: D11: %lld 

tool: D26: 


tool: D18: %lld



tool: D27: %lld


assistant: ```c
int main() {
  long long int i, j, n;
  long long int arrayForFiboStore[82];
  arrayForFiboStore[0] = 0;
  arrayForFiboStore[1] = 1;
  for (i = 2; i <= 81; i++) {
    arrayForFiboStore[i] = arrayForFiboStore[i - 1] + arrayForFiboStore[i - 2];
  }
  scanf("%lld", &n);
  for (i = 0; i <= n; i++) {
    printf("%lld ", arrayForFiboStore[i]);
  }
  printf("\n\n");
  printf("%lld\n\n", arrayForFiboStore[n]);
  printf("%lld\n", arrayForFiboStore[n + 1]);
  return 0;
}
```