ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  or     $0x80,%al
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    $0x2,%ecx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <spi_comms@plt>
  test   %rax,%rax
  je     L16
  mov    $0xffffffff,%eax
  jmp    L9
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int read_byte(uint8_t reg, uint8_t *value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg | 0x80;
  tx_buf[0] = shift_reg;
  if (spi_comms(tx_buf, 2, rx_buf, 2) != 0) {
    return -1;
  }
  *value = rx_buf[1];
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<read_byte>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movq   $0x0,0x10(%rsp)
  or     $0x80,%dil
  mov    %edi,0x8(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rdi
  mov    $0x2,%ecx
  mov    $0x2,%esi
  call   <spi_comms@plt>
  test   %rax,%rax
  jne    L6
  mov    0x14(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x0,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L24
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_byte(uint8_t reg, uint8_t *value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg | 0x80;
  tx_buf[0] = shift_reg;
  if (spi_comms(tx_buf, 2, rx_buf, 2) != 0) {
    return -1;
  }
  *value = rx_buf[1];
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_byte>:
  endbr64
  push   %rbx
  or     $0x80,%dil
  mov    %rsi,%rbx
  mov    $0x2,%ecx
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    %edi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  movl   $0x0,0xc(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <spi_comms@plt>
  test   %rax,%rax
  jne    L15
  mov    0x14(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L26:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L15:
  mov    $0xffffffff,%eax
  jmp    L26
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_byte(uint8_t reg, uint8_t *value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg | 0x80;
  tx_buf[0] = shift_reg;
  if (spi_comms(tx_buf, 2, rx_buf, 2) != 0) {
    return -1;
  }
  *value = rx_buf[1];
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<read_byte>:
  endbr64
  push   %rbx
  or     $0x80,%dil
  mov    %rsi,%rbx
  mov    $0x2,%ecx
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    %edi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  movl   $0x0,0xc(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <spi_comms@plt>
  test   %rax,%rax
  jne    L26
  mov    0x14(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L26:
  mov    $0xffffffff,%eax
  jmp    L21
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_byte(uint8_t reg, uint8_t *value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg | 0x80;
  tx_buf[0] = shift_reg;
  if (spi_comms(tx_buf, 2, rx_buf, 2) != 0) {
    return -1;
  }
  *value = rx_buf[1];
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ROL>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,%eax
  mov    %al,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movzbl -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_shiftL@plt>
  movzbl -0x34(%rbp),%eax
  mov    $0x40,%edx
  sub    %eax,%edx
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_shiftR@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_or@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void ROL(unsigned char ans[8], unsigned char x[8], unsigned char r) {
  unsigned char r1[8];
  unsigned char r2[8];
  _shiftL(r1, x, r);
  _shiftR(r2, x, 64 - r);
  _or(ans, r1, r2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ROL>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl %dl,%ebp
  lea    0x8(%rsp),%r13
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <_shiftL@plt>
  mov    $0x40,%edx
  sub    %ebp,%edx
  lea    0x10(%rsp),%rbp
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <_shiftR@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <_or@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ROL(unsigned char ans[8], unsigned char x[8], unsigned char r) {
  unsigned char r1[8];
  unsigned char r2[8];
  _shiftL(r1, x, r);
  _shiftR(r2, x, 64 - r);
  _or(ans, r1, r2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ROL>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dl,%ebx
  mov    %ebx,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r14
  mov    %r13,%rdi
  call   <_shiftL@plt>
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  sub    %ebx,%edx
  call   <_shiftR@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <_or@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ROL(unsigned char ans[8], unsigned char x[8], unsigned char r) {
  unsigned char r1[8];
  unsigned char r2[8];
  _shiftL(r1, x, r);
  _shiftR(r2, x, 64 - r);
  _or(ans, r1, r2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ROL>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dl,%ebx
  mov    %ebx,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x10(%rsp),%r14
  mov    %r13,%rdi
  call   <_shiftL@plt>
  mov    $0x40,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  sub    %ebx,%edx
  call   <_shiftR@plt>
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <_or@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ROL(unsigned char ans[8], unsigned char x[8], unsigned char r) {
  unsigned char r1[8];
  unsigned char r2[8];
  _shiftL(r1, x, r);
  _shiftR(r2, x, 64 - r);
  _or(ans, r1, r2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getMicomTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  imul   $0x15180,%eax,%eax
  add    $0x2efbbf80,%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0xe10,%eax,%edx
  mov    -0x10(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  add    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%edi
  mov    -0x10(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string

tool: D1: MJD = %d epoch = %ld, time = %02d:%02d:%02d


assistant: ```c
unsigned long getMicomTime(char *micomTimeString) {
  unsigned int mjd = ((micomTimeString[1] & 0xFF) * 256) + (micomTimeString[2] & 0xFF);
  unsigned long epoch = ((mjd - 40587) * 86400);
  unsigned int hour = micomTimeString[3] & 0xFF;
  unsigned int min = micomTimeString[4] & 0xFF;
  unsigned int sec = micomTimeString[5] & 0xFF;
  epoch += (hour * 3600 + min * 60 + sec);
  printf("MJD = %d epoch = %ld, time = %02d:%02d:%02d\n", mjd, epoch, hour, min, sec);
  return epoch;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getMicomTime>:
  endbr64
  push   %rbx
  movzbl 0x1(%rdi),%esi
  shl    $0x8,%esi
  movzbl 0x2(%rdi),%eax
  add    %eax,%esi
  imul   $0x15180,%esi,%eax
  add    $0x2efbbf80,%eax
  mov    %eax,%eax
  movzbl 0x3(%rdi),%ecx
  movzbl 0x4(%rdi),%r8d
  movzbl 0x5(%rdi),%r9d
  imul   $0xe10,%ecx,%ebx
  imul   $0x3c,%r8d,%edx
  add    %edx,%ebx
  add    %r9d,%ebx
  mov    %ebx,%ebx
  add    %rax,%rbx
  mov    %rbx,%rdx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string

tool: D8: MJD = %d epoch = %ld, time = %02d:%02d:%02d


assistant: ```c
unsigned long getMicomTime(char *micomTimeString) {
  unsigned int mjd = ((micomTimeString[1] & 0xFF) * 256) + (micomTimeString[2] & 0xFF);
  unsigned long epoch = ((mjd - 40587) * 86400);
  unsigned int hour = micomTimeString[3] & 0xFF;
  unsigned int min = micomTimeString[4] & 0xFF;
  unsigned int sec = micomTimeString[5] & 0xFF;
  epoch += (hour * 3600 + min * 60 + sec);
  printf("MJD = %d epoch = %ld, time = %02d:%02d:%02d\n", mjd, epoch, hour, min, sec);
  return epoch;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getMicomTime>:
  endbr64
  push   %r12
  movzbl 0x1(%rdi),%esi
  movzbl 0x2(%rdi),%eax
  movzbl 0x3(%rdi),%ecx
  movzbl 0x4(%rdi),%r8d
  shl    $0x8,%esi
  movzbl 0x5(%rdi),%r9d
  lea    D5(%rip),%rdi
  imul   $0xe10,%ecx,%r12d
  add    %eax,%esi
  imul   $0x3c,%r8d,%edx
  imul   $0x15180,%esi,%eax
  add    %edx,%r12d
  add    $0x2efbbf80,%eax
  add    %r9d,%r12d
  add    %rax,%r12
  mov    %r12,%rdx
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: MJD = %d epoch = %ld, time = %02d:%02d:%02d


assistant: ```c
unsigned long getMicomTime(char *micomTimeString) {
  unsigned int mjd = ((micomTimeString[1] & 0xFF) * 256) + (micomTimeString[2] & 0xFF);
  unsigned long epoch = ((mjd - 40587) * 86400);
  unsigned int hour = micomTimeString[3] & 0xFF;
  unsigned int min = micomTimeString[4] & 0xFF;
  unsigned int sec = micomTimeString[5] & 0xFF;
  epoch += (hour * 3600 + min * 60 + sec);
  printf("MJD = %d epoch = %ld, time = %02d:%02d:%02d\n", mjd, epoch, hour, min, sec);
  return epoch;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getMicomTime>:
  endbr64
  push   %r12
  movzbl 0x1(%rdi),%esi
  movzbl 0x2(%rdi),%eax
  movzbl 0x3(%rdi),%ecx
  movzbl 0x4(%rdi),%r8d
  shl    $0x8,%esi
  movzbl 0x5(%rdi),%r9d
  lea    D9(%rip),%rdi
  imul   $0xe10,%ecx,%r12d
  add    %eax,%esi
  imul   $0x3c,%r8d,%edx
  imul   $0x15180,%esi,%eax
  add    %edx,%r12d
  add    $0x2efbbf80,%eax
  add    %r9d,%r12d
  add    %rax,%r12
  mov    %r12,%rdx
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: MJD = %d epoch = %ld, time = %02d:%02d:%02d


assistant: ```c
unsigned long getMicomTime(char *micomTimeString) {
  unsigned int mjd = ((micomTimeString[1] & 0xFF) * 256) + (micomTimeString[2] & 0xFF);
  unsigned long epoch = ((mjd - 40587) * 86400);
  unsigned int hour = micomTimeString[3] & 0xFF;
  unsigned int min = micomTimeString[4] & 0xFF;
  unsigned int sec = micomTimeString[5] & 0xFF;
  epoch += (hour * 3600 + min * 60 + sec);
  printf("MJD = %d epoch = %ld, time = %02d:%02d:%02d\n", mjd, epoch, hour, min, sec);
  return epoch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *m_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  mem_list_add(ptr);
  return ptr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<m_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *m_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  mem_list_add(ptr);
  return ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *m_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  mem_list_add(ptr);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<m_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <mem_list_add@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *m_malloc(size_t size) {
  void *ptr;
  ptr = malloc(size);
  mem_list_add(ptr);
  return ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  cltq
  mov    %rax,%rcx
  mov    $0x0,%ebx
  lea    -0x19(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void foo(void) {
  char a[1];
  int t = 1;
  ((char(*)[t])a)[0][0] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  char a[1];
  int t = 1;
  ((char(*)[t])a)[0][0] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  char a[1];
  int t = 1;
  ((char(*)[t])a)[0][0] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  ret
```

assistant: ```c
void foo(void) {
  char a[1];
  int t = 1;
  ((char(*)[t])a)[0][0] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<http_arg_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L28
L17:
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L28
L8:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L7
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  jmp    L28
L7:
  addq   $0x10,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  mov    -0x8(%rbp),%rax
L28:
  leave
  ret
```

assistant: ```c
char *http_arg_val(char **args, char *key) {
  char *val = NULL;
  if (!args)
    return (NULL);
  if (!key)
    return (NULL);
  while (*args) {
    if (strcmp(key, *args) == 0)
      return (*(args + 1));
    args += 2;
  }
  return (val);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<http_arg_val>:
  endbr64
  test   %rsi,%rsi
  je     L37
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L25
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L9
L6:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L10
  add    $0x10,%rbx
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L6
  jmp    L9
L10:
  mov    0x8(%rbx),%rsi
L9:
  mov    %rsi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0x0,%esi
  jmp    L9
L37:
  mov    $0x0,%esi
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *http_arg_val(char **args, char *key) {
  char *val = NULL;
  if (!args)
    return (NULL);
  if (!key)
    return (NULL);
  while (*args) {
    if (strcmp(key, *args) == 0)
      return (*(args + 1));
    args += 2;
  }
  return (val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<http_arg_val>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%rbp
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  jne    L52
  jmp    L8
  nopl   0x0(%rax)
L18:
  mov    0x10(%rbx),%rsi
  add    $0x10,%rbx
  test   %rsi,%rsi
  je     L8
L52:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
  mov    0x8(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *http_arg_val(char **args, char *key) {
  char *val = NULL;
  if (!args)
    return (NULL);
  if (!key)
    return (NULL);
  while (*args) {
    if (strcmp(key, *args) == 0)
      return (*(args + 1));
    args += 2;
  }
  return (val);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<http_arg_val>:
  endbr64
  test   %rsi,%rsi
  je     L53
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L8
  mov    %rsi,%rbp
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  jne    L31
  jmp    L8
  nopl   0x0(%rax)
L55:
  mov    0x10(%rbx),%rsi
  add    $0x10,%rbx
  test   %rsi,%rsi
  je     L8
L31:
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L55
  mov    0x8(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L53:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *http_arg_val(char **args, char *key) {
  char *val = NULL;
  if (!args)
    return (NULL);
  if (!key)
    return (NULL);
  while (*args) {
    if (strcmp(key, *args) == 0)
      return (*(args + 1));
    args += 2;
  }
  return (val);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getText>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L13:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x14(%rbp)
  jl     L13
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %[^!]

assistant: ```c
void getText(char a[]) {
  scanf("%[^!]", a);
  int i;
  for (i = 0; i < strlen(a); i++)
    a[i] = toupper(a[i]);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getText>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  jmp    L5
L19:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_infered: string

tool: D1: %[^!]

assistant: ```c
void getText(char a[]) {
  scanf("%[^!]", a);
  int i;
  for (i = 0; i < strlen(a); i++)
    a[i] = toupper(a[i]);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getText>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <scanf@plt>
  jmp    L9
L16:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: %[^!]

assistant: ```c
void getText(char a[]) {
  scanf("%[^!]", a);
  int i;
  for (i = 0; i < strlen(a); i++)
    a[i] = toupper(a[i]);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getText>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <scanf@plt>
  jmp    L8
L12:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %[^!]

assistant: ```c
void getText(char a[]) {
  scanf("%[^!]", a);
  int i;
  for (i = 0; i < strlen(a); i++)
    a[i] = toupper(a[i]);
  return;
}
```