user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gen_inputtest>:
  endbr64
  push   %r14
  lea    D31(%rip),%rdi
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D77(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
  lea    D62(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L47:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    $0x40,%ebx
  jne    L47
  xor    %ebx,%ebx
  lea    D10(%rip),%rbp
  lea    D53(%rip),%r12
  jmp    L53
  nopw   0x0(%rax,%rax,1)
L35:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    $0x40,%ebx
  je     L55
L53:
  test   $0xf,%bl
  jne    L35
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L55:
  xor    %ebx,%ebx
  lea    D65(%rip),%r14
  lea    D98(%rip),%r13
  lea    D74(%rip),%r12
  lea    D20(%rip),%rbp
  xchg   %ax,%ax
L14:
  mov    %ebx,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    $0x40,%ebx
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D31
datatype: string
name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D77
datatype: string
name: parse_data
arguments: label: D62
datatype: string
name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D53
datatype: string
name: parse_data
arguments: label: D65
datatype: string
name: parse_data
arguments: label: D98
datatype: string
name: parse_data
arguments: label: D74
datatype: string
name: parse_data
arguments: label: D20
datatype: string

tool: D31: // Input test program

tool: D4: .input I%d_L	%d


tool: D77: .input I%d_R	%d


tool: D62: #include "vu.mac"

tool: D11: .gpr VUTMP

tool: D9: .gpr TMP

tool: D10: .parm IVU%d	0		stereopeak


tool: D53: .parm G%x		0		group


tool: D65: ACC3(TMP, I%d_L, 0, 0)


tool: D98: VU(IVU%d_L, TMP)


tool: D74: ACC3(TMP, I%d_R, 0, 0)


tool: D20: VU(IVU%d_R, TMP)


assistant: ```c
void gen_inputtest(void) {
  int i;
  printf("// Input test program\n");
  printf("#include \"vu.mac\"\n");
  printf(".gpr VUTMP\n");
  printf(".gpr TMP\n");
  for (i = 0; i < 64; i += 2) {
    printf(".input I%d_L	%d\n", i, i);
    printf(".input I%d_R	%d\n", i, i + 1);
  }
  for (i = 0; i < 64; i += 2) {
    if (!(i % 16))
      printf(".parm G%x		0		group\n", i);
    printf(".parm IVU%d	0		stereopeak\n", i);
  }
  for (i = 0; i < 64; i += 2) {
    printf("ACC3(TMP, I%d_L, 0, 0)\n", i);
    printf("VU(IVU%d_L, TMP)\n", i);
    printf("ACC3(TMP, I%d_R, 0, 0)\n", i);
    printf("VU(IVU%d_R, TMP)\n", i);
  }
}
```