ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prntB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L25:
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
L5:
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L25
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D0: %d	

assistant: ```c
void prntB(int *matrix, int nx, int ny) {
  int i;
  for (i = 1; i <= nx * ny; i++) {
    int b_i = (i - 1) / nx, b_j = (i - 1) % nx;
    printf("%d\t", matrix[i - 1]);
    if (i % nx == 0)
      printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prntB>:
  endbr64
  imul   %esi,%edx
  test   %edx,%edx
  jle    L33
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    $0x1,%ebx
  lea    D9(%rip),%r14
  jmp    L32
L6:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L16
L32:
  mov    -0x4(%r13,%rbx,4),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L6
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d	

assistant: ```c
void prntB(int *matrix, int nx, int ny) {
  int i;
  for (i = 1; i <= nx * ny; i++) {
    int b_i = (i - 1) / nx, b_j = (i - 1) % nx;
    printf("%d\t", matrix[i - 1]);
    if (i % nx == 0)
      printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prntB>:
  endbr64
  imul   %esi,%edx
  test   %edx,%edx
  jle    L45
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L34
  nopl   0x0(%rax)
L42:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L23
L34:
  mov    -0x4(%r13,%rbx,4),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L42
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L34
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L45:
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: %d	

assistant: ```c
void prntB(int *matrix, int nx, int ny) {
  int i;
  for (i = 1; i <= nx * ny; i++) {
    int b_i = (i - 1) / nx, b_j = (i - 1) % nx;
    printf("%d\t", matrix[i - 1]);
    if (i % nx == 0)
      printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prntB>:
  endbr64
  imul   %esi,%edx
  test   %edx,%edx
  jle    L42
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L24
  nopl   0x0(%rax)
L4:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L23
L24:
  mov    -0x4(%r13,%rbx,4),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L4
  mov    $0xa,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jge    L24
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L42:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: %d	

assistant: ```c
void prntB(int *matrix, int nx, int ny) {
  int i;
  for (i = 1; i <= nx * ny; i++) {
    int b_i = (i - 1) / nx, b_j = (i - 1) % nx;
    printf("%d\t", matrix[i - 1]);
    if (i % nx == 0)
      printf("\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<dummy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  call   *%rax
L7:
  nop
  leave
  ret
```

assistant: ```c
void dummy(void (*foo)(void)) {
  if (foo)
    (*foo)();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dummy>:
  endbr64
  test   %rdi,%rdi
  je     L6
  sub    $0x8,%rsp
  call   *%rdi
  add    $0x8,%rsp
  ret
L6:
  ret
```

assistant: ```c
void dummy(void (*foo)(void)) {
  if (foo)
    (*foo)();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dummy>:
  endbr64
  test   %rdi,%rdi
  je     L5
  jmp    *%rdi
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void dummy(void (*foo)(void)) {
  if (foo)
    (*foo)();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dummy>:
  endbr64
  test   %rdi,%rdi
  je     L8
  jmp    *%rdi
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void dummy(void (*foo)(void)) {
  if (foo)
    (*foo)();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ch2ind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x39,-0x4(%rbp)
  jg     L48
  movsbl -0x4(%rbp),%eax
  add    $0x4,%eax
  jmp    L0
L48:
  cmpb   $0x5a,-0x4(%rbp)
  jg     L38
  movsbl -0x4(%rbp),%eax
  sub    $0x27,%eax
  jmp    L0
L38:
  cmpb   $0x7a,-0x4(%rbp)
  jg     L56
  movsbl -0x4(%rbp),%eax
  sub    $0x61,%eax
  jmp    L0
L56:
  mov    $0x0,%edi
  call   <assert@plt>
L0:
  leave
  ret
```

assistant: ```c
int ch2ind(char c) {
  if (c <= '9')
    return (int)c + 52 - '0';
  if (c <= 'Z')
    return (int)c + 26 - 'A';
  if (c <= 'z')
    return (int)c - 'a';
  assert(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ch2ind>:
  endbr64
  cmp    $0x39,%dil
  jle    L18
  cmp    $0x5a,%dil
  jle    L8
  cmp    $0x7a,%dil
  jg     L11
  movsbl %dil,%edi
  lea    -0x61(%rdi),%eax
  ret
L18:
  movsbl %dil,%edi
  lea    0x4(%rdi),%eax
  ret
L8:
  movsbl %dil,%edi
  lea    -0x27(%rdi),%eax
  ret
L11:
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ch2ind(char c) {
  if (c <= '9')
    return (int)c + 52 - '0';
  if (c <= 'Z')
    return (int)c + 26 - 'A';
  if (c <= 'z')
    return (int)c - 'a';
  assert(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ch2ind>:
  endbr64
  cmp    $0x39,%dil
  jle    L29
  cmp    $0x5a,%dil
  jle    L27
  cmp    $0x7a,%dil
  jg     L24
  sub    $0x61,%edi
  movsbl %dil,%eax
  ret
  xchg   %ax,%ax
L27:
  sub    $0x27,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x4,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %edi,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
int ch2ind(char c) {
  if (c <= '9')
    return (int)c + 52 - '0';
  if (c <= 'Z')
    return (int)c + 26 - 'A';
  if (c <= 'z')
    return (int)c - 'a';
  assert(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ch2ind>:
  endbr64
  cmp    $0x39,%dil
  jle    L7
  cmp    $0x5a,%dil
  jle    L9
  cmp    $0x7a,%dil
  jg     L3
  sub    $0x61,%edi
  movsbl %dil,%eax
  ret
  xchg   %ax,%ax
L9:
  sub    $0x27,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x4,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %edi,%edi
  jmp    1050 <assert@plt>
```

assistant: ```c
int ch2ind(char c) {
  if (c <= '9')
    return (int)c + 52 - '0';
  if (c <= 'Z')
    return (int)c + 26 - 'A';
  if (c <= 'z')
    return (int)c - 'a';
  assert(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <BsiGenerateTables@plt>
  mov    $0x0,%eax
  call   <Sinc4GenerateTables@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  BsiGenerateTables();
  Sinc4GenerateTables();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <BsiGenerateTables@plt>
  mov    $0x0,%eax
  call   <Sinc4GenerateTables@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  BsiGenerateTables();
  Sinc4GenerateTables();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <BsiGenerateTables@plt>
  xor    %eax,%eax
  call   <Sinc4GenerateTables@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  BsiGenerateTables();
  Sinc4GenerateTables();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <BsiGenerateTables@plt>
  xor    %eax,%eax
  call   <Sinc4GenerateTables@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  BsiGenerateTables();
  Sinc4GenerateTables();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<closeConnection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  call   <ClearWinSock@plt>
  nop
  leave
  ret
```

assistant: ```c
void closeConnection(int socket) {
  close(socket);
  ClearWinSock();
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<closeConnection>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x0,%eax
  call   <ClearWinSock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void closeConnection(int socket) {
  close(socket);
  ClearWinSock();
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<closeConnection>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ClearWinSock@plt>
```

assistant: ```c
void closeConnection(int socket) {
  close(socket);
  ClearWinSock();
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<closeConnection>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ClearWinSock@plt>
```

assistant: ```c
void closeConnection(int socket) {
  close(socket);
  ClearWinSock();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x12,%edx
  mov    $0x1,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L5:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x9,-0xc(%rbp)
  jle    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string
name: read_data
arguments: tag: D19
data_type: string
name: read_data
arguments: tag: D39
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D5: w

tool: D19: file.txt

tool: D39: Inteiros de 0 a 9


tool: D4: %d


assistant: ```c
int main() {
  FILE *file = fopen("file.txt", "w");
  fprintf(file, "Inteiros de 0 a 9\n");
  for (int i = 0; i < 10; ++i) {
    fprintf(file, "%d\n", i);
  }
  fclose(file);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rsi
  lea    D11(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rax,%rcx
  mov    $0x12,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  call   <fwrite@plt>
  mov    $0x0,%ebx
  lea    D10(%rip),%r12
L5:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L5
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string
name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D2
type_guessed: string
name: retrieve_data
arguments: label: D10
type_guessed: string

tool: D4: w

tool: D11: file.txt

tool: D2: Inteiros de 0 a 9


tool: D10: %d


assistant: ```c
int main() {
  FILE *file = fopen("file.txt", "w");
  fprintf(file, "Inteiros de 0 a 9\n");
  for (int i = 0; i < 10; ++i) {
    fprintf(file, "%d\n", i);
  }
  fclose(file);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D38(%rip),%rsi
  lea    D4(%rip),%rdi
  push   %rbp
  lea    D9(%rip),%r12
  push   %rbx
  xor    %ebx,%ebx
  call   <fopen@plt>
  mov    $0x12,%edx
  mov    $0x1,%esi
  lea    D39(%rip),%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fwrite@plt>
L3:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L3
  mov    %rbp,%rdi
  call   <fclose@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
data_type: string
name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D39
data_type: string

tool: D38: w

tool: D4: file.txt

tool: D9: %d


tool: D39: Inteiros de 0 a 9


assistant: ```c
int main() {
  FILE *file = fopen("file.txt", "w");
  fprintf(file, "Inteiros de 0 a 9\n");
  for (int i = 0; i < 10; ++i) {
    fprintf(file, "%d\n", i);
  }
  fclose(file);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rsi
  lea    D20(%rip),%rdi
  push   %rbp
  lea    D13(%rip),%r12
  push   %rbx
  xor    %ebx,%ebx
  call   <fopen@plt>
  mov    $0x12,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  mov    %rax,%rcx
  mov    %rax,%rbp
  call   <fwrite@plt>
L1:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L1
  mov    %rbp,%rdi
  call   <fclose@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D23
type_guessed: string
name: parse_data
arguments: data_label: D20
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string
name: parse_data
arguments: data_label: D14
type_guessed: string

tool: D23: w

tool: D20: file.txt

tool: D13: %d


tool: D14: Inteiros de 0 a 9


assistant: ```c
int main() {
  FILE *file = fopen("file.txt", "w");
  fprintf(file, "Inteiros de 0 a 9\n");
  for (int i = 0; i < 10; ++i) {
    fprintf(file, "%d\n", i);
  }
  fclose(file);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x3c(%rbp)
  jmp    L58
L21:
  mov    -0x40(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x3c(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x40(%rbp)
  addl   $0x1,-0x3c(%rbp)
L58:
  mov    -0x40(%rbp),%eax
  test   %eax,%eax
  jg     L21
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  movl   $0x0,-0x3c(%rbp)
  jmp    L30
L46:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x38(%rbp)
  jmp    L27
L78:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L64
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L64:
  addl   $0x1,-0x38(%rbp)
L27:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L78
  addl   $0x1,-0x3c(%rbp)
L30:
  mov    -0x3c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L46
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L71
  call   <__stack_chk_fail@plt>
L71:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D22
type_infered: string
name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D21
type_infered: string

tool: D22: Vuvedete chislo:

tool: D9: %d

tool: D21: Chisloto %d se povtarq!


assistant: ```c
int main() {
  int n, i, k, b;
  int a[10];
  printf("Vuvedete chislo:");
  scanf("%d", &n);
  for (i = 0; n > 0; i++) {
    a[i] = n % 10;
    n = n / 10;
  }
  k = i;
  for (i = 0; i < k; i++)
    for (b = i + 1; b < k; b++) {
      if (a[i] == a[b]) {
        printf("Chisloto %d se povtarq!\n", a[i]);
      }
    }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    0x1c(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L64
  lea    0x20(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  mov    $0x0,%esi
L74:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%r8d
  sub    %ecx,%r8d
  mov    %r8d,(%rdi)
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %esi,%r14d
  add    $0x1,%esi
  add    $0x4,%rdi
  cmp    $0x9,%ecx
  jg     L74
  mov    %eax,0x1c(%rsp)
  test   %esi,%esi
  jle    L64
  mov    0x8(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D1(%rip),%r15
  jmp    L25
L55:
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L80:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L76
L88:
  mov    0x0(%rbp),%esi
  cmp    0x4(%rbx),%esi
  jne    L80
  jmp    L55
L76:
  add    $0x1,%r13
  add    $0x4,%rbp
L25:
  cmp    %r13d,%r14d
  jle    L64
  lea    -0x1(%r14),%eax
  sub    %r13d,%eax
  add    %r13,%rax
  mov    0x8(%rsp),%rdi
  lea    0x4(%rdi,%rax,4),%r12
  mov    %rbp,%rbx
  jmp    L88
L64:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D1
type_infered: string

tool: D24: Vuvedete chislo:

tool: D25: %d

tool: D1: Chisloto %d se povtarq!


assistant: ```c
int main() {
  int n, i, k, b;
  int a[10];
  printf("Vuvedete chislo:");
  scanf("%d", &n);
  for (i = 0; n > 0; i++) {
    a[i] = n % 10;
    n = n / 10;
  }
  k = i;
  for (i = 0; i < k; i++)
    for (b = i + 1; b < k; b++) {
      if (a[i] == a[b]) {
        printf("Chisloto %d se povtarq!\n", a[i]);
      }
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x2c(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x2c(%rsp),%edx
  test   %edx,%edx
  jle    L65
  lea    0x30(%rsp),%rax
  xor    %ecx,%ecx
  mov    $0xcccccccd,%r8d
  mov    %rax,0x8(%rsp)
  nopl   (%rax)
L80:
  mov    %edx,%eax
  mov    %edx,%edi
  mov    %ecx,0x14(%rsp)
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edi
  mov    0x8(%rsp),%rsi
  mov    %edi,(%rsi,%rcx,4)
  mov    %edx,%esi
  add    $0x1,%rcx
  mov    %eax,%edx
  cmp    $0x9,%esi
  jg     L80
  mov    %eax,0x2c(%rsp)
  mov    0x14(%rsp),%eax
  mov    $0x1,%r15d
  lea    D19(%rip),%r14
  mov    0x8(%rsp),%rbp
  add    $0x1,%eax
  mov    %rax,0x18(%rsp)
  cmp    0x18(%rsp),%r15
  je     L65
  nopl   (%rax)
L57:
  mov    0x14(%rsp),%eax
  mov    0x8(%rsp),%rcx
  mov    %rbp,%rbx
  mov    0x0(%rbp),%r12d
  sub    %r15d,%eax
  lea    -0x1(%r15,%rax,1),%rax
  lea    0x4(%rcx,%rax,4),%r13
  jmp    L77
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L13
L77:
  cmp    %r12d,0x4(%rbx)
  jne    L34
  mov    %r12d,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L77
L13:
  add    $0x1,%r15
  add    $0x4,%rbp
  cmp    0x18(%rsp),%r15
  jne    L57
L65:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D19
type_infered: string

tool: D0: Vuvedete chislo:

tool: D1: %d

tool: D19: Chisloto %d se povtarq!


assistant: ```c
int main() {
  int n, i, k, b;
  int a[10];
  printf("Vuvedete chislo:");
  scanf("%d", &n);
  for (i = 0; n > 0; i++) {
    a[i] = n % 10;
    n = n / 10;
  }
  k = i;
  for (i = 0; i < k; i++)
    for (b = i + 1; b < k; b++) {
      if (a[i] == a[b]) {
        printf("Chisloto %d se povtarq!\n", a[i]);
      }
    }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x966656409636261,%rax
  movabs $0x96c6b6a0a696867,%rdx
  mov    %rax,-0x410(%rbp)
  mov    %rdx,-0x408(%rbp)
  movabs $0xa727170096f6e6d,%rax
  mov    %rax,-0x400(%rbp)
  movb   $0x0,-0x3f8(%rbp)
  lea    -0x3f0(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <escape@plt>
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: %s


assistant: ```c
int main() {
  char s[] = "abc\tdef\tghi\njkl\tmno\tpqr\n";
  char t[1000];
  escape(s, t);
  printf("%s\n", t);
}
```