ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L42
L60:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L60
L42:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L100
L69:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L76
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L101:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D12(%rip),%xmm0
  subsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L101
L76:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L70
  xor    %r14d,%r14d
  jmp    L61
  nopl   0x0(%rax)
L56:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L70
L61:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dnanmeanpw@plt>
  ucomisd %xmm0,%xmm0
  jnp    L56
  lea    D7(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L83:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L70:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L83
  cs nopw 0x0(%rax,%rax,1)
L100:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L69
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: f64
name: unpack_data
arguments: data_label: D17
datatype: f64
name: unpack_data
arguments: data_label: D7
datatype: string

tool: D12: 20000

tool: D17: 10000

tool: D7: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanmeanpw(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L51
L3:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L3
L51:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L93
L96:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L73
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L62:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D12(%rip),%xmm0
  subsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L62
L73:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L101
  xor    %r14d,%r14d
  jmp    L74
  nopl   0x0(%rax)
L99:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L101
L74:
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <stdlib_strided_dnanmeanpw@plt>
  ucomisd %xmm0,%xmm0
  jnp    L99
  lea    D8(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L110:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L101:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L110
  cs nopw 0x0(%rax,%rax,1)
L93:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L96
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: f64
name: retrieve_data
arguments: label: D9
type_infered: f64
name: retrieve_data
arguments: label: D8
type_infered: string

tool: D12: 20000

tool: D9: 10000

tool: D8: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanmeanpw(len, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_elapsed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    D0(%rip),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double get_elapsed(clock_t start, clock_t stop) {
  double elapsed = ((double)(stop - start)) / CLOCKS_PER_SEC;
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_elapsed>:
  endbr64
  sub    %rdi,%rsi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  mov    D6(%rip),%rax
  divsd  (%rax),%xmm0
  ret
```

assistant: ```c
double get_elapsed(clock_t start, clock_t stop) {
  double elapsed = ((double)(stop - start)) / CLOCKS_PER_SEC;
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_elapsed>:
  endbr64
  mov    D3(%rip),%rax
  sub    %rdi,%rsi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  divsd  (%rax),%xmm0
  ret
```

assistant: ```c
double get_elapsed(clock_t start, clock_t stop) {
  double elapsed = ((double)(stop - start)) / CLOCKS_PER_SEC;
  return elapsed;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_elapsed>:
  endbr64
  mov    D2(%rip),%rax
  sub    %rdi,%rsi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  divsd  (%rax),%xmm0
  ret
```

assistant: ```c
double get_elapsed(clock_t start, clock_t stop) {
  double elapsed = ((double)(stop - start)) / CLOCKS_PER_SEC;
  return elapsed;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L4
L63:
  movl   $0x0,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L31
L66:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L53
  jmp    L32
L3:
  addl   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x14(%rbp)
L32:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L3
L53:
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0xc(%rbp)
  jle    L66
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jle    L1
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L63
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string
name: read_data
arguments: data_tag: D11
type: string

tool: D2: %d


tool: D11: %d

assistant: ```c
int main() {
  int n, ans, i;
  while (scanf("%d", &n) == 1) {
    ans = 0;
    for (i = 2; i <= sqrt(n); i++) {
      if (n % i == 0) {
        while (n % i == 0) {
          ans++;
          n = n / i;
        }
      }
    }
    if (n > 1)
      ans++;
    printf("%d\n", ans);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  lea    D10(%rip),%r12
  lea    D11(%rip),%r14
  jmp    L67
L30:
  add    $0x1,%ebx
L66:
  mov    0x4(%rsp),%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L63
  mov    0x4(%rsp),%ecx
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L30
L51:
  add    $0x1,%ebp
  mov    %ecx,%eax
  cltd
  idiv   %ebx
  mov    %eax,%ecx
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L51
  mov    %ecx,0x4(%rsp)
  jmp    L30
L63:
  cmpl   $0x1,0x4(%rsp)
  setg   %al
  movzbl %al,%eax
  add    %eax,%ebp
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
L67:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L3
  mov    $0x2,%ebx
  mov    $0x0,%ebp
  jmp    L66
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D11
datatype: string

tool: D10: %d

tool: D11: %d


assistant: ```c
int main() {
  int n, ans, i;
  while (scanf("%d", &n) == 1) {
    ans = 0;
    for (i = 2; i <= sqrt(n); i++) {
      if (n % i == 0) {
        while (n % i == 0) {
          ans++;
          n = n / i;
        }
      }
    }
    if (n > 1)
      ans++;
    printf("%d\n", ans);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L28
  nopw   0x0(%rax,%rax,1)
L52:
  mov    0x4(%rsp),%edi
  mov    $0x2,%ebx
  xor    %r14d,%r14d
  jmp    L40
  xchg   %ax,%ax
L14:
  add    $0x1,%ebx
L40:
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L53
  mov    0x4(%rsp),%edi
  mov    %edi,%eax
  mov    %edi,%ecx
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L14
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %ecx,%eax
  add    $0x1,%r14d
  cltd
  idiv   %ebx
  cltd
  mov    %eax,%ecx
  idiv   %ebx
  test   %edx,%edx
  je     L31
  mov    %ecx,0x4(%rsp)
  mov    %ecx,%edi
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L53:
  xor    %eax,%eax
  cmpl   $0x1,0x4(%rsp)
  mov    %r13,%rdi
  setg   %al
  add    %eax,%r14d
  mov    %r14d,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L52
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D11: %d


tool: D5: %d

assistant: ```c
int main() {
  int n, ans, i;
  while (scanf("%d", &n) == 1) {
    ans = 0;
    for (i = 2; i <= sqrt(n); i++) {
      if (n % i == 0) {
        while (n % i == 0) {
          ans++;
          n = n / i;
        }
      }
    }
    if (n > 1)
      ans++;
    printf("%d\n", ans);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L79
  nopw   0x0(%rax,%rax,1)
L53:
  mov    0x4(%rsp),%edi
  mov    $0x2,%ebx
  xor    %r14d,%r14d
  jmp    L68
  xchg   %ax,%ax
L6:
  add    $0x1,%ebx
L68:
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jl     L32
  mov    0x4(%rsp),%edi
  mov    %edi,%eax
  mov    %edi,%ecx
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L6
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %ecx,%eax
  add    $0x1,%r14d
  cltd
  idiv   %ebx
  cltd
  mov    %eax,%ecx
  idiv   %ebx
  test   %edx,%edx
  je     L25
  mov    %ecx,0x4(%rsp)
  mov    %ecx,%edi
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  cmpl   $0x1,0x4(%rsp)
  mov    %r13,%rdi
  setg   %al
  add    %eax,%r14d
  mov    %r14d,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L53
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string
name: read_data
arguments: tag: D15
data_type: string

tool: D9: %d


tool: D15: %d

assistant: ```c
int main() {
  int n, ans, i;
  while (scanf("%d", &n) == 1) {
    ans = 0;
    for (i = 2; i <= sqrt(n); i++) {
      if (n % i == 0) {
        while (n % i == 0) {
          ans++;
          n = n / i;
        }
      }
    }
    if (n > 1)
      ans++;
    printf("%d\n", ans);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EPIIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x400d0000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x10,-0x8(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x210,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x210,%edx
  movslq %edx,%rdx
  or     -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void EPIIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32IntFlags < 17);
  (*((volatile uint32_t *)(ui32Base + 0x00000210))) |= ui32IntFlags;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<EPIIntEnable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x400d0000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x10,%ebp
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0x210,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     %ebp,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32IntFlags < 17);
  (*((volatile uint32_t *)(ui32Base + 0x00000210))) |= ui32IntFlags;
}
```
user: What is the c source code of the assembly code below:

```asm
<EPIIntEnable>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400d0000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x10,%ebp
  setle  %dil
  add    $0x210,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     %ebp,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32IntFlags < 17);
  (*((volatile uint32_t *)(ui32Base + 0x00000210))) |= ui32IntFlags;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EPIIntEnable>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400d0000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x10,%ebp
  setle  %dil
  add    $0x210,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  or     %ebp,%eax
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EPIIntEnable(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ASSERT(ui32Base == 0x400D0000);
  ASSERT(ui32IntFlags < 17);
  (*((volatile uint32_t *)(ui32Base + 0x00000210))) |= ui32IntFlags;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MixRatio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D3(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  subsd  -0x18(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: f64

tool: D3: 621.97

assistant: ```c
double MixRatio(double E, double Es) {
  double MixRatio = 621.97 * E / (Es - E);
  return MixRatio;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MixRatio>:
  endbr64
  movapd %xmm0,%xmm2
  mulsd  D6(%rip),%xmm0
  subsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: f64

tool: D6: 621.97

assistant: ```c
double MixRatio(double E, double Es) {
  double MixRatio = 621.97 * E / (Es - E);
  return MixRatio;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MixRatio>:
  endbr64
  movapd %xmm0,%xmm2
  movsd  D6(%rip),%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: f64

tool: D6: 621.97

assistant: ```c
double MixRatio(double E, double Es) {
  double MixRatio = 621.97 * E / (Es - E);
  return MixRatio;
}
```
user: What is the c source code of the assembly code below?

```asm
<MixRatio>:
  endbr64
  movapd %xmm0,%xmm2
  movsd  D9(%rip),%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: f64

tool: D9: 621.97

assistant: ```c
double MixRatio(double E, double Es) {
  double MixRatio = 621.97 * E / (Es - E);
  return MixRatio;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L8
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L10
L8:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L10:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <g@plt>
  leave
  ret
```

assistant: ```c
int f(int t, int c) {
  int d = 0;
  int e = 0;
  if (t) {
    d = c + 1;
    e = t;
  } else
    d = 0, e = 0;
  return g(e, d);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%esi
  test   %edi,%edi
  cmove  %edi,%esi
  call   <g@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int f(int t, int c) {
  int d = 0;
  int e = 0;
  if (t) {
    d = c + 1;
    e = t;
  } else
    d = 0, e = 0;
  return g(e, d);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  add    $0x1,%esi
  xor    %eax,%eax
  test   %edi,%edi
  cmove  %eax,%esi
  jmp    1050 <g@plt>
```

assistant: ```c
int f(int t, int c) {
  int d = 0;
  int e = 0;
  if (t) {
    d = c + 1;
    e = t;
  } else
    d = 0, e = 0;
  return g(e, d);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<f>:
  endbr64
  add    $0x1,%esi
  xor    %eax,%eax
  test   %edi,%edi
  cmove  %eax,%esi
  jmp    1050 <g@plt>
```

assistant: ```c
int f(int t, int c) {
  int d = 0;
  int e = 0;
  if (t) {
    d = c + 1;
    e = t;
  } else
    d = 0, e = 0;
  return g(e, d);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<create_bro_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0xc,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void create_bro_addr(int port, struct sockaddr_in *addrto) {
  bzero(addrto, sizeof(struct sockaddr_in));
  addrto->sin_family = AF_INET;
  addrto->sin_addr.s_addr = htonl(INADDR_BROADCAST);
  addrto->sin_port = htons(port);
}
```
user: What is the c source code of the assembly code below:

```asm
<create_bro_addr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  call   <bzero@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0x4(%rbx)
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_bro_addr(int port, struct sockaddr_in *addrto) {
  bzero(addrto, sizeof(struct sockaddr_in));
  addrto->sin_family = AF_INET;
  addrto->sin_addr.s_addr = htonl(INADDR_BROADCAST);
  addrto->sin_port = htons(port);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<create_bro_addr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <bzero@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %ebp,%edi
  mov    %eax,0x4(%rbx)
  call   <htons@plt>
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_bro_addr(int port, struct sockaddr_in *addrto) {
  bzero(addrto, sizeof(struct sockaddr_in));
  addrto->sin_family = AF_INET;
  addrto->sin_addr.s_addr = htonl(INADDR_BROADCAST);
  addrto->sin_port = htons(port);
}
```
user: What is the c source code of the assembly code below:

```asm
<create_bro_addr>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xc,%esi
  mov    %rbx,%rdi
  sub    $0x8,%rsp
  call   <bzero@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rbx)
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %ebp,%edi
  mov    %eax,0x4(%rbx)
  call   <htons@plt>
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void create_bro_addr(int port, struct sockaddr_in *addrto) {
  bzero(addrto, sizeof(struct sockaddr_in));
  addrto->sin_family = AF_INET;
  addrto->sin_addr.s_addr = htonl(INADDR_BROADCAST);
  addrto->sin_port = htons(port);
}
```