ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  je     L48
  cmp    $0x3,%eax
  jg     L68
  cmp    $0x1,%eax
  je     L88
  cmp    $0x2,%eax
  je     L52
  jmp    L68
L88:
  mov    $0x0,%eax
  call   <accept@plt>
  mov    $0x0,%eax
  call   <sjf@plt>
  jmp    L72
L52:
  mov    $0x0,%eax
  call   <rr@plt>
  jmp    L72
L68:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L72
L48:
  nop
L72:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D2
datatype: string
name: parse_data
arguments: label: D19
datatype: string

tool: D29: 
      ****MENU****
1.Shortest Job First
2.Round Robin Scheduling
3.Exit

Enter your choice:

tool: D2: %d

tool: D19: 
Invalid choice


assistant: ```c
void main() {
  int ch;
  printf("\n      ****MENU****\n1.Shortest Job First\n2.Round Robin Scheduling\n3.Exit\n\nEnter your choice:");
  scanf("%d", &ch);
  switch (ch) {
  case 1:
    accept();
    sjf();
    break;
  case 2:
    rr();
    break;
  case 3:
    break;
  default:
    printf("\nInvalid choice\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L39
  cmp    $0x3,%eax
  je     L42
  cmp    $0x1,%eax
  je     L2
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L2:
  mov    $0x0,%eax
  call   <accept@plt>
  mov    $0x0,%eax
  call   <sjf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  ret
L39:
  mov    $0x0,%eax
  call   <rr@plt>
  jmp    L42
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D12
datatype: string

tool: D13: 
      ****MENU****
1.Shortest Job First
2.Round Robin Scheduling
3.Exit

Enter your choice:

tool: D7: %d

tool: D12: 
Invalid choice


assistant: ```c
void main() {
  int ch;
  printf("\n      ****MENU****\n1.Shortest Job First\n2.Round Robin Scheduling\n3.Exit\n\nEnter your choice:");
  scanf("%d", &ch);
  switch (ch) {
  case 1:
    accept();
    sjf();
    break;
  case 2:
    rr();
    break;
  case 3:
    break;
  default:
    printf("\nInvalid choice\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L21
  cmp    $0x3,%eax
  je     L40
  cmp    $0x1,%eax
  je     L55
  lea    D15(%rip),%rdi
  call   <printf@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  ret
L21:
  xor    %eax,%eax
  call   <rr@plt>
  jmp    L40
L55:
  xor    %eax,%eax
  call   <accept@plt>
  xor    %eax,%eax
  call   <sjf@plt>
  jmp    L40
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D15
type: string

tool: D28: 
      ****MENU****
1.Shortest Job First
2.Round Robin Scheduling
3.Exit

Enter your choice:

tool: D17: %d

tool: D15: 
Invalid choice


assistant: ```c
void main() {
  int ch;
  printf("\n      ****MENU****\n1.Shortest Job First\n2.Round Robin Scheduling\n3.Exit\n\nEnter your choice:");
  scanf("%d", &ch);
  switch (ch) {
  case 1:
    accept();
    sjf();
    break;
  case 2:
    rr();
    break;
  case 3:
    break;
  default:
    printf("\nInvalid choice\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L26
  cmp    $0x3,%eax
  je     L37
  cmp    $0x1,%eax
  je     L44
  lea    D13(%rip),%rdi
  call   <printf@plt>
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  ret
L26:
  xor    %eax,%eax
  call   <rr@plt>
  jmp    L37
L44:
  xor    %eax,%eax
  call   <accept@plt>
  xor    %eax,%eax
  call   <sjf@plt>
  jmp    L37
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string

tool: D21: 
      ****MENU****
1.Shortest Job First
2.Round Robin Scheduling
3.Exit

Enter your choice:

tool: D5: %d

tool: D13: 
Invalid choice


assistant: ```c
void main() {
  int ch;
  printf("\n      ****MENU****\n1.Shortest Job First\n2.Round Robin Scheduling\n3.Exit\n\nEnter your choice:");
  scanf("%d", &ch);
  switch (ch) {
  case 1:
    accept();
    sjf();
    break;
  case 2:
    rr();
    break;
  case 3:
    break;
  default:
    printf("\nInvalid choice\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
int rab(char *pt, int *pti) {
  pt[2] = 0;
  pti[3] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rab>:
  endbr64
  movb   $0x0,0x2(%rdi)
  movl   $0x0,0xc(%rsi)
  ret
```

assistant: ```c
int rab(char *pt, int *pti) {
  pt[2] = 0;
  pti[3] = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rab>:
  endbr64
  movb   $0x0,0x2(%rdi)
  movl   $0x0,0xc(%rsi)
  ret
```

assistant: ```c
int rab(char *pt, int *pti) {
  pt[2] = 0;
  pti[3] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rab>:
  endbr64
  movb   $0x0,0x2(%rdi)
  movl   $0x0,0xc(%rsi)
  ret
```

assistant: ```c
int rab(char *pt, int *pti) {
  pt[2] = 0;
  pti[3] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_numbers_construct@plt>
  mov    $0x0,%eax
  call   <test_numbers_destruct@plt>
  mov    $0x0,%eax
  call   <test_numbers_sort@plt>
  mov    $0x0,%eax
  call   <test_numbers_mean@plt>
  mov    $0x0,%eax
  call   <test_numbers_variance@plt>
  mov    $0x0,%eax
  call   <test_numbers_sd@plt>
  mov    $0x0,%eax
  call   <test_numbers_random@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_all(void) {
  test_numbers_construct();
  test_numbers_destruct();
  test_numbers_sort();
  test_numbers_mean();
  test_numbers_variance();
  test_numbers_sd();
  test_numbers_random();
}
```
user: What is the c source code of the assembly code below:

```asm
<test_all>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_numbers_construct@plt>
  mov    $0x0,%eax
  call   <test_numbers_destruct@plt>
  mov    $0x0,%eax
  call   <test_numbers_sort@plt>
  mov    $0x0,%eax
  call   <test_numbers_mean@plt>
  mov    $0x0,%eax
  call   <test_numbers_variance@plt>
  mov    $0x0,%eax
  call   <test_numbers_sd@plt>
  mov    $0x0,%eax
  call   <test_numbers_random@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_all(void) {
  test_numbers_construct();
  test_numbers_destruct();
  test_numbers_sort();
  test_numbers_mean();
  test_numbers_variance();
  test_numbers_sd();
  test_numbers_random();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_all>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_numbers_construct@plt>
  xor    %eax,%eax
  call   <test_numbers_destruct@plt>
  xor    %eax,%eax
  call   <test_numbers_sort@plt>
  xor    %eax,%eax
  call   <test_numbers_mean@plt>
  xor    %eax,%eax
  call   <test_numbers_variance@plt>
  xor    %eax,%eax
  call   <test_numbers_sd@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10d0 <test_numbers_random@plt>
```

assistant: ```c
void test_all(void) {
  test_numbers_construct();
  test_numbers_destruct();
  test_numbers_sort();
  test_numbers_mean();
  test_numbers_variance();
  test_numbers_sd();
  test_numbers_random();
}
```
user: What is the c source code of the assembly code below?

```asm
<inportb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x14(%rbp)
  movzwl -0x14(%rbp),%eax
  mov    %eax,%edx
  in     (%dx),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char inportb(unsigned short port) {
  unsigned char result;
  __asm__ __volatile__("inb %1, %0" : "=a"(result) : "dN"(port));
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inportb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inportb(unsigned short port) {
  unsigned char result;
  __asm__ __volatile__("inb %1, %0" : "=a"(result) : "dN"(port));
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<inportb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inportb(unsigned short port) {
  unsigned char result;
  __asm__ __volatile__("inb %1, %0" : "=a"(result) : "dN"(port));
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inportb>:
  endbr64
  mov    %edi,%edx
  in     (%dx),%al
  ret
```

assistant: ```c
unsigned char inportb(unsigned short port) {
  unsigned char result;
  __asm__ __volatile__("inb %1, %0" : "=a"(result) : "dN"(port));
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ld>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L10:
  addl   $0x1,-0x4(%rbp)
L0:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ld(int x) {
  int ret = 0;
  while (x >>= 1)
    ret++;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ld>:
  endbr64
  sar    %edi
  je     L8
  mov    $0x0,%eax
L13:
  add    $0x1,%eax
  sar    %edi
  jne    L13
  ret
L8:
  mov    %edi,%eax
  ret
```

assistant: ```c
int ld(int x) {
  int ret = 0;
  while (x >>= 1)
    ret++;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ld>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L4
  nopw   0x0(%rax,%rax,1)
L2:
  add    $0x1,%eax
  sar    %edi
  jne    L2
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
int ld(int x) {
  int ret = 0;
  while (x >>= 1)
    ret++;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ld>:
  endbr64
  xor    %eax,%eax
  sar    %edi
  je     L6
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%eax
  sar    %edi
  jne    L3
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
int ld(int x) {
  int ret = 0;
  while (x >>= 1)
    ret++;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<h_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x31,%eax
  mov    %al,D23(%rip)
  movzbl D23(%rip),%eax
  mov    %al,D30(%rip)
  lea    D13(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *h_name(int x) {
  static char s[5] = "B-G-";
  int i = x / 8;
  s[3] = s[1] = '1' + i;
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<h_name>:
  endbr64
  lea    0x7(%rdi),%eax
  test   %edi,%edi
  cmovns %edi,%eax
  sar    $0x3,%eax
  add    $0x31,%eax
  mov    %al,D10(%rip)
  mov    %al,D7(%rip)
  lea    D29(%rip),%rax
  ret
```

assistant: ```c
char *h_name(int x) {
  static char s[5] = "B-G-";
  int i = x / 8;
  s[3] = s[1] = '1' + i;
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<h_name>:
  endbr64
  test   %edi,%edi
  lea    0x7(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x3,%eax
  add    $0x31,%eax
  mov    %al,D9(%rip)
  mov    %al,D13(%rip)
  lea    D24(%rip),%rax
  ret
```

assistant: ```c
char *h_name(int x) {
  static char s[5] = "B-G-";
  int i = x / 8;
  s[3] = s[1] = '1' + i;
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<h_name>:
  endbr64
  test   %edi,%edi
  lea    0x7(%rdi),%eax
  cmovns %edi,%eax
  sar    $0x3,%eax
  add    $0x31,%eax
  mov    %al,D15(%rip)
  mov    %al,D1(%rip)
  lea    D22(%rip),%rax
  ret
```

assistant: ```c
char *h_name(int x) {
  static char s[5] = "B-G-";
  int i = x / 8;
  s[3] = s[1] = '1' + i;
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__udivmoddi4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L39
  mov    $0x0,%eax
  call   <__divide_error@plt>
  mov    $0x0,%eax
  jmp    L60
L15:
  shll   -0x18(%rbp)
  shll   -0x4(%rbp)
L39:
  cmpl   $0x0,-0x18(%rbp)
  jns    L15
  jmp    L55
L49:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L34
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L34:
  sarl   -0x18(%rbp)
  sarl   -0x4(%rbp)
L55:
  cmpl   $0x0,-0x4(%rbp)
  jne    L49
  cmpq   $0x0,-0x20(%rbp)
  je     L32
  mov    -0x20(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L32:
  mov    -0x8(%rbp),%eax
L60:
  leave
  ret
```

assistant: ```c
uint64_t __udivmoddi4(uint64_t num, uint64_t den, uint64_t *rem_p) {
  uint64_t quot = 0, qbit = 1;
  if (den == 0) {
    __divide_error();
    return 0;
  }
  while ((int64_t)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__udivmoddi4>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  test   %esi,%esi
  je     L51
  mov    $0x1,%eax
  js     L79
L97:
  add    %eax,%eax
  add    %ebx,%ebx
  jns    L97
  test   %eax,%eax
  je     L5
L79:
  mov    $0x0,%ecx
  jmp    L95
L51:
  mov    $0x0,%eax
  call   <__divide_error@plt>
  mov    %ebx,%ecx
  jmp    L3
L12:
  sar    %ebx
  sar    %eax
  je     L73
L95:
  cmp    %ebx,%edi
  jl     L12
  sub    %ebx,%edi
  add    %eax,%ecx
  jmp    L12
L5:
  mov    %eax,%ecx
L73:
  test   %rdx,%rdx
  je     L3
  mov    %edi,(%rdx)
L3:
  mov    %ecx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint64_t __udivmoddi4(uint64_t num, uint64_t den, uint64_t *rem_p) {
  uint64_t quot = 0, qbit = 1;
  if (den == 0) {
    __divide_error();
    return 0;
  }
  while ((int64_t)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__udivmoddi4>:
  endbr64
  test   %esi,%esi
  je     L78
  mov    $0x1,%eax
  js     L66
  nop
L18:
  add    %eax,%eax
  add    %esi,%esi
  jns    L18
  test   %eax,%eax
  je     L49
L66:
  xor    %r8d,%r8d
  nopl   (%rax)
L48:
  cmp    %esi,%edi
  jl     L27
  sub    %esi,%edi
  add    %eax,%r8d
L27:
  sar    %esi
  sar    %eax
  jne    L48
L11:
  test   %rdx,%rdx
  je     L52
  mov    %edi,(%rdx)
L52:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L78:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__divide_error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L49:
  xor    %r8d,%r8d
  jmp    L11
```

assistant: ```c
uint64_t __udivmoddi4(uint64_t num, uint64_t den, uint64_t *rem_p) {
  uint64_t quot = 0, qbit = 1;
  if (den == 0) {
    __divide_error();
    return 0;
  }
  while ((int64_t)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__udivmoddi4>:
  endbr64
  test   %esi,%esi
  je     L71
  mov    $0x1,%eax
  js     L20
  nop
L15:
  add    %eax,%eax
  add    %esi,%esi
  jns    L15
  test   %eax,%eax
  je     L30
L20:
  xor    %r8d,%r8d
  nopl   (%rax)
L28:
  cmp    %esi,%edi
  jl     L14
  sub    %esi,%edi
  add    %eax,%r8d
L14:
  sar    %esi
  sar    %eax
  jne    L28
L11:
  test   %rdx,%rdx
  je     L31
  mov    %edi,(%rdx)
L31:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__divide_error@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  xor    %r8d,%r8d
  jmp    L11
```

assistant: ```c
uint64_t __udivmoddi4(uint64_t num, uint64_t den, uint64_t *rem_p) {
  uint64_t quot = 0, qbit = 1;
  if (den == 0) {
    __divide_error();
    return 0;
  }
  while ((int64_t)den >= 0) {
    den <<= 1;
    qbit <<= 1;
  }
  while (qbit) {
    if (den <= num) {
      num -= den;
      quot += qbit;
    }
    den >>= 1;
    qbit >>= 1;
  }
  if (rem_p)
    *rem_p = num;
  return quot;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strlist_compare_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  leave
  ret
```

assistant: ```c
int strlist_compare_strings(const void *a, const void *b) {
  const char *sa = *(const char **)a;
  const char *sb = *(const char **)b;
  return strcmp(sa, sb);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlist_compare_strings>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  call   <strcmp@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int strlist_compare_strings(const void *a, const void *b) {
  const char *sa = *(const char **)a;
  const char *sb = *(const char **)b;
  return strcmp(sa, sb);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlist_compare_strings>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int strlist_compare_strings(const void *a, const void *b) {
  const char *sa = *(const char **)a;
  const char *sb = *(const char **)b;
  return strcmp(sa, sb);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlist_compare_strings>:
  endbr64
  mov    (%rsi),%rsi
  mov    (%rdi),%rdi
  jmp    1050 <strcmp@plt>
```

assistant: ```c
int strlist_compare_strings(const void *a, const void *b) {
  const char *sa = *(const char **)a;
  const char *sb = *(const char **)b;
  return strcmp(sa, sb);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L5
L2:
  movq   $0x0,-0x20(%rbp)
  jmp    L11
L9:
  lea    -0x28(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%rax
  add    %rax,-0x20(%rbp)
L11:
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  test   %rax,%rax
  jne    L9
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  lea    -0x30(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  je     L0
  mov    -0x38(%rbp),%rax
  test   %rax,%rax
  jne    L2
L0:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D21
type_infered: string
name: parse_data
arguments: label: D20
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string

tool: D21: %s %d

tool: D20: %d


tool: D18: %d %d

assistant: ```c
int main() {
  int16_t t, j, n, s;
  char x[10];
  while (scanf("%d %d", &t, &j) && t != 0) {
    s = 0;
    while (t--) {
      scanf("%s %d", x, &n);
      s += n;
    }
    printf("%d\n", j * 3 - s);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    D2(%rip),%r12
  lea    D27(%rip),%rbp
  lea    D23(%rip),%r14
  jmp    L46
L3:
  mov    0x8(%rsp),%rax
  lea    (%rax,%rax,2),%rsi
  sub    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
L46:
  mov    %rsp,%rsi
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  test   %rax,%rax
  je     L31
  mov    (%rsp),%rax
  test   %rax,%rax
  je     L31
  sub    $0x1,%rax
  mov    %rax,(%rsp)
  mov    $0x0,%ebx
L33:
  lea    0x10(%rsp),%rdx
  lea    0x1e(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    0x10(%rsp),%rbx
  mov    (%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  test   %rax,%rax
  jne    L33
  jmp    L3
L31:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: string
name: parse_data
arguments: tag: D27
data_type: string
name: parse_data
arguments: tag: D23
data_type: string

tool: D2: %d %d

tool: D27: %s %d

tool: D23: %d


assistant: ```c
int main() {
  int16_t t, j, n, s;
  char x[10];
  while (scanf("%d %d", &t, &j) && t != 0) {
    s = 0;
    while (t--) {
      scanf("%s %d", x, &n);
      s += n;
    }
    printf("%d\n", j * 3 - s);
  }
  return 0;
}
```