ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rev>:
  endbr64
  mov    %edi,%eax
  lea    (%rdi,%rdi,1),%edi
  shr    %eax
  and    $0xaaaaaaaa,%edi
  and    $0x55555555,%eax
  or     %eax,%edi
  lea    0x0(,%rdi,4),%edx
  shr    $0x2,%edi
  and    $0xcccccccc,%edx
  and    $0x33333333,%edi
  or     %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%edx
  shl    $0x4,%eax
  and    $0xf0f0f0f,%edx
  and    $0xf0f0f0f0,%eax
  or     %edx,%eax
  bswap  %eax
  ret
```

assistant: ```c
int rev(int xi, int y, int z) {
  unsigned x = xi;
  x = (x & 0x55555555) << 1 | ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) << 2 | ((x >> 2) & 0x33333333);
  x = (x & 0x0F0F0F0F) << 4 | ((x >> 4) & 0x0F0F0F0F);
  x = (x << 24) | ((x & 0xFF00) << 8) | ((x >> 8) & 0xFF00) | (x >> 24);
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<VpuReadReg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <reg_map@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  leave
  ret
```

assistant: ```c
unsigned long VpuReadReg(unsigned long addr) {
  unsigned long *reg_addr = reg_map(addr);
  return *(volatile unsigned long *)reg_addr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<VpuReadReg>:
  endbr64
  sub    $0x8,%rsp
  call   <reg_map@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long VpuReadReg(unsigned long addr) {
  unsigned long *reg_addr = reg_map(addr);
  return *(volatile unsigned long *)reg_addr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VpuReadReg>:
  endbr64
  sub    $0x8,%rsp
  call   <reg_map@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long VpuReadReg(unsigned long addr) {
  unsigned long *reg_addr = reg_map(addr);
  return *(volatile unsigned long *)reg_addr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<VpuReadReg>:
  endbr64
  sub    $0x8,%rsp
  call   <reg_map@plt>
  mov    (%rax),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long VpuReadReg(unsigned long addr) {
  unsigned long *reg_addr = reg_map(addr);
  return *(volatile unsigned long *)reg_addr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arraycopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L38
L25:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  ja     L25
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L1:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void arraycopy(char from[], char to[]) {
  unsigned long len = strlen(to);
  for (int i = 0; i < len; i++)
    to[i] = '\0';
  for (int i = 0; i < strlen(from); i++)
    to[i] = from[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arraycopy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  cltq
  test   %rax,%rax
  je     L23
  mov    %r12,%rdx
  add    %r12,%rax
L35:
  movb   $0x0,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L35
L23:
  mov    $0x0,%ebx
  jmp    L3
L8:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arraycopy(char from[], char to[]) {
  unsigned long len = strlen(to);
  for (int i = 0; i < len; i++)
    to[i] = '\0';
  for (int i = 0; i < strlen(from); i++)
    to[i] = from[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arraycopy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  test   %rdx,%rdx
  je     L20
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L20:
  xor    %ebx,%ebx
  jmp    L11
  nopl   0x0(%rax)
L21:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arraycopy(char from[], char to[]) {
  unsigned long len = strlen(to);
  for (int i = 0; i < len; i++)
    to[i] = '\0';
  for (int i = 0; i < strlen(from); i++)
    to[i] = from[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<arraycopy>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  test   %rdx,%rdx
  je     L4
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
L4:
  xor    %ebx,%ebx
  jmp    L16
  nopl   0x0(%rax)
L13:
  movzbl 0x0(%rbp,%rbx,1),%eax
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void arraycopy(char from[], char to[]) {
  unsigned long len = strlen(to);
  for (int i = 0; i < len; i++)
    to[i] = '\0';
  for (int i = 0; i < strlen(from); i++)
    to[i] = from[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jne    L14
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L17
L14:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <usage@plt>
L17:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <TCPecho@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *destination;
  int portN;
  if (argc == 3) {
    destination = argv[1];
    portN = atoi(argv[2]);
  } else
    usage(argv[0]);
  TCPecho(destination, portN);
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L4
  mov    (%rsi),%rdi
  call   <usage@plt>
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <TCPecho@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  jmp    L10
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *destination;
  int portN;
  if (argc == 3) {
    destination = argv[1];
    portN = atoi(argv[2]);
  } else
    usage(argv[0]);
  TCPecho(destination, portN);
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L15
  mov    (%rsi),%rdi
  call   <usage@plt>
L13:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <TCPecho@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    0x10(%rsi),%rdi
  mov    0x8(%rsi),%r12
  call   <atoi@plt>
  mov    %eax,%ebp
  jmp    L13
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *destination;
  int portN;
  if (argc == 3) {
    destination = argv[1];
    portN = atoi(argv[2]);
  } else
    usage(argv[0]);
  TCPecho(destination, portN);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L7
  mov    (%rsi),%rdi
  call   <usage@plt>
L11:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <TCPecho@plt>
  xor    %edi,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  mov    0x10(%rsi),%rdi
  mov    0x8(%rsi),%r12
  call   <atoi@plt>
  mov    %eax,%ebp
  jmp    L11
```

assistant: ```c
int main(int argc, char *argv[]) {
  char *destination;
  int portN;
  if (argc == 3) {
    destination = argv[1];
    portN = atoi(argv[2]);
  } else
    usage(argv[0]);
  TCPecho(destination, portN);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L92:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  jle    L92
  mov    -0x14(%rbp),%eax
  cmp    $0x14,%eax
  jg     L92
  movl   $0x0,-0x10(%rbp)
  jmp    L94
L42:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L75:
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L48
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L44
L48:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L74
L44:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L74:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L75
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L94:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L42
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L78
  call   <__stack_chk_fail@plt>
L78:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D3
datatype: string
name: disassemble_data
arguments: data_tag: D30
datatype: string

tool: D27: Inserisci lato tra 2 e 20:

tool: D7: %d

tool: D26: *

tool: D3:  

tool: D30: 


assistant: ```c
int main() {
  int n;
  int i;
  int k;
  do {
    printf("Inserisci lato tra 2 e 20:");
    scanf("%d", &n);
  } while (n < 2 || n > 20);
  i = 0;
  while (i < n) {
    printf("*");
    k = 0;
    while (k < (n - 1)) {
      if ((i = 0) || (i = n - 1)) {
        printf(" ");
      } else {
        printf("*");
      }
      k++;
    }
    printf("\n");
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D9(%rip),%rbx
L23:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x2,%eax
  cmp    $0x12,%eax
  ja     L23
  mov    $0x0,%ebx
  lea    D15(%rip),%r12
  lea    D25(%rip),%r13
  lea    D42(%rip),%r14
  jmp    L89
L82:
  mov    %r12,%rdi
  call   <printf@plt>
L51:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L50
  mov    %eax,%ebp
L9:
  test   %ebp,%ebp
  je     L82
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L51
L44:
  mov    %ebx,%ebp
L50:
  mov    %r14,%rdi
  call   <printf@plt>
  lea    0x1(%rbp),%ebx
  cmp    %ebx,0x4(%rsp)
  jle    L42
L89:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebp
  test   %ebp,%ebp
  jle    L44
  mov    $0x0,%ebx
  jmp    L9
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: tag: D42
type_guessed: string

tool: D1: Inserisci lato tra 2 e 20:

tool: D9: %d

tool: D15: *

tool: D25:  

tool: D42: 


assistant: ```c
int main() {
  int n;
  int i;
  int k;
  do {
    printf("Inserisci lato tra 2 e 20:");
    scanf("%d", &n);
  } while (n < 2 || n > 20);
  i = 0;
  while (i < n) {
    printf("*");
    k = 0;
    while (k < (n - 1)) {
      if ((i = 0) || (i = n - 1)) {
        printf(" ");
      } else {
        printf("*");
      }
      k++;
    }
    printf("\n");
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D41(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D22(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   (%rax)
L14:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x2,%eax
  cmp    $0x12,%eax
  ja     L14
  xor    %r12d,%r12d
  lea    D10(%rip),%r15
  lea    D42(%rip),%r14
  lea    D24(%rip),%r13
  nop
L20:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  test   %ebx,%ebx
  jle    L32
  xor    %ebp,%ebp
  nopl   (%rax)
L44:
  mov    %r13,%rdi
  mov    %ebx,%r12d
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  cmp    %ebp,%ebx
  jg     L44
L32:
  mov    %r14,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L20
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D41
data_type: string
name: extract_symbolic_data
arguments: tag: D22
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D42
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string

tool: D41: Inserisci lato tra 2 e 20:

tool: D22: %d

tool: D10: *

tool: D42: 


tool: D24:  

assistant: ```c
int main() {
  int n;
  int i;
  int k;
  do {
    printf("Inserisci lato tra 2 e 20:");
    scanf("%d", &n);
  } while (n < 2 || n > 20);
  i = 0;
  while (i < n) {
    printf("*");
    k = 0;
    while (k < (n - 1)) {
      if ((i = 0) || (i = n - 1)) {
        printf(" ");
      } else {
        printf("*");
      }
      k++;
    }
    printf("\n");
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D49(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  nopl   (%rax)
L5:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  sub    $0x2,%eax
  cmp    $0x12,%eax
  ja     L5
  xor    %r12d,%r12d
  lea    D15(%rip),%r15
  lea    D29(%rip),%r14
  lea    D25(%rip),%r13
  nop
L40:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  test   %ebx,%ebx
  jle    L37
  xor    %ebp,%ebp
  nopl   (%rax)
L48:
  mov    %r13,%rdi
  mov    %ebx,%r12d
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%ebx
  cmp    %ebp,%ebx
  jg     L48
L37:
  mov    %r14,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L40
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D49
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D25
type_infered: string

tool: D49: Inserisci lato tra 2 e 20:

tool: D18: %d

tool: D15: *

tool: D29: 


tool: D25:  

assistant: ```c
int main() {
  int n;
  int i;
  int k;
  do {
    printf("Inserisci lato tra 2 e 20:");
    scanf("%d", &n);
  } while (n < 2 || n > 20);
  i = 0;
  while (i < n) {
    printf("*");
    k = 0;
    while (k < (n - 1)) {
      if ((i = 0) || (i = n - 1)) {
        printf(" ");
      } else {
        printf("*");
      }
      k++;
    }
    printf("\n");
    i++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<magt_binext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  %xmm5,-0x60(%rbp)
  movsd  %xmm6,-0x68(%rbp)
  movsd  %xmm7,-0x70(%rbp)
  mov    %rdi,-0x78(%rbp)
  mov    %esi,-0x7c(%rbp)
  mov    %rdx,-0x88(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x40(%rbp),%xmm0
  divsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x28(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <sincos@plt>
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  mulsd  -0x58(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  0x18(%rbp),%xmm4
  mov    -0x88(%rbp),%rdx
  mov    -0x7c(%rbp),%esi
  mov    -0x78(%rbp),%rcx
  movsd  -0x70(%rbp),%xmm3
  movsd  -0x68(%rbp),%xmm2
  movsd  -0x60(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm4,%xmm6
  movsd  0x10(%rbp),%xmm5
  mov    %rcx,%rdi
  movapd %xmm3,%xmm4
  movapd %xmm2,%xmm3
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <mag_binext@plt>
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double magt_binext(double t, double t0, double tE, double alpha, double u0, double rho, double d, double q, double (*ld_func)(int, double *, double), int n, double gam[], double acc, double ld_acc) {
  double p;
  double y1, y2;
  double sa, ca;
  p = (t - t0) / tE;
  sincos(alpha, &sa, &ca);
  y1 = p * ca - u0 * sa;
  y2 = p * sa + u0 * ca;
  return (mag_binext(y1, y2, rho, d, q, ld_func, n, gam, acc, ld_acc));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<magt_binext>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm4,0x8(%rsp)
  movq   %xmm5,%rbx
  movq   %xmm6,%rbp
  movq   %xmm7,%r12
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %rdx,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  subsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rsp)
  lea    0x20(%rsp),%rsi
  lea    0x18(%rsp),%rdi
  movapd %xmm3,%xmm0
  call   <sincos@plt>
  movsd  0x20(%rsp),%xmm0
  movsd  0x18(%rsp),%xmm2
  movsd  (%rsp),%xmm5
  movapd %xmm5,%xmm7
  mulsd  %xmm2,%xmm7
  movsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  mulsd  %xmm5,%xmm0
  mulsd  %xmm4,%xmm2
  subsd  %xmm2,%xmm0
  movsd  0x78(%rsp),%xmm6
  movsd  0x70(%rsp),%xmm5
  mov    %r15,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  movq   %r12,%xmm4
  movq   %rbp,%xmm3
  movq   %rbx,%xmm2
  addsd  %xmm7,%xmm1
  call   <mag_binext@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double magt_binext(double t, double t0, double tE, double alpha, double u0, double rho, double d, double q, double (*ld_func)(int, double *, double), int n, double gam[], double acc, double ld_acc) {
  double p;
  double y1, y2;
  double sa, ca;
  p = (t - t0) / tE;
  sincos(alpha, &sa, &ca);
  y1 = p * ca - u0 * sa;
  y2 = p * sa + u0 * ca;
  return (mag_binext(y1, y2, rho, d, q, ld_func, n, gam, acc, ld_acc));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<magt_binext>:
  endbr64
  movapd %xmm0,%xmm9
  push   %r13
  movapd %xmm3,%xmm0
  mov    %rdx,%r13
  subsd  %xmm1,%xmm9
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  divsd  %xmm2,%xmm9
  sub    $0x50,%rsp
  movsd  %xmm4,0x28(%rsp)
  lea    0x40(%rsp),%rsi
  lea    0x38(%rsp),%rdi
  movsd  %xmm5,0x20(%rsp)
  movsd  %xmm6,0x18(%rsp)
  movsd  %xmm7,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movsd  %xmm9,0x8(%rsp)
  call   <sincos@plt>
  movsd  0x40(%rsp),%xmm8
  mov    %r13,%rdx
  movsd  0x38(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm9
  movsd  0x28(%rsp),%xmm10
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movapd %xmm0,%xmm11
  movapd %xmm8,%xmm1
  movsd  0x78(%rsp),%xmm6
  movsd  0x70(%rsp),%xmm5
  mulsd  %xmm10,%xmm0
  movsd  0x10(%rsp),%xmm4
  movsd  0x18(%rsp),%xmm3
  mulsd  %xmm9,%xmm8
  movsd  0x20(%rsp),%xmm2
  mulsd  %xmm9,%xmm11
  mulsd  %xmm10,%xmm1
  subsd  %xmm0,%xmm8
  addsd  %xmm11,%xmm1
  movapd %xmm8,%xmm0
  call   <mag_binext@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x50,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double magt_binext(double t, double t0, double tE, double alpha, double u0, double rho, double d, double q, double (*ld_func)(int, double *, double), int n, double gam[], double acc, double ld_acc) {
  double p;
  double y1, y2;
  double sa, ca;
  p = (t - t0) / tE;
  sincos(alpha, &sa, &ca);
  y1 = p * ca - u0 * sa;
  y2 = p * sa + u0 * ca;
  return (mag_binext(y1, y2, rho, d, q, ld_func, n, gam, acc, ld_acc));
}
```