user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x40(%rbp)
  movl   $0xc,-0x3c(%rbp)
  movl   $0xd,-0x38(%rbp)
  movl   $0xe,-0x34(%rbp)
  movl   $0x14,-0x30(%rbp)
  movl   $0x6c726143,-0x27(%rbp)
  movw   $0x736f,-0x23(%rbp)
  movb   $0x0,-0x21(%rbp)
  movabs $0x4520736f6c726143,%rax
  movabs $0x61706c6c694b202e,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x6b63,-0x10(%rbp)
  movb   $0x0,-0xe(%rbp)
  mov    $0x4,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x3c(%rbp),%edx
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x13,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x13,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x27(%rbp),%rax
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D78
type_infered: string
name: read_data
arguments: data_label: D67
type_infered: string
name: read_data
arguments: data_label: D95
type_infered: string
name: read_data
arguments: data_label: D63
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D49
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string
name: read_data
arguments: data_label: D66
type_infered: string

tool: D78: The size of an int: %ld


tool: D67: The size of areas (int[]): %ld


tool: D95: The number of ints in areas: %ld


tool: D63: The first area is %d, the 2nd is %d.


tool: D18: The size of a char: %ld


tool: D49: The size of name (char[]): %ld


tool: D1: The number of chars: %ld


tool: D7: The size of full_name (char[]): %ld


tool: D66: name="%s" and full_name="%s"


assistant: ```c
int main(int argc, char *argv[]) {
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Carlos";
  char full_name[] = {'C', 'a', 'r', 'l', 'o', 's', ' ', 'E', '.', ' ', 'K', 'i', 'l', 'l', 'p', 'a', 'c', 'k', '\0'};
  printf("The size of an int: %ld\n", sizeof(int));
  printf("The size of areas (int[]): %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd is %d.\n", areas[0], areas[1]);
  printf("The size of a char: %ld\n", sizeof(char));
  printf("The size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full_name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars: %ld\n", sizeof(full_name) / sizeof(char));
  printf("name=\"%s\" and full_name=\"%s\"\n", name, full_name);
  return 0;
}
```