ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x20(%rbp)
  movl   $0xa,-0x1c(%rbp)
  movl   $0xa,-0x18(%rbp)
  movl   $0x64,-0x14(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  movl   $0x3e8,-0x40(%rbp)
  movl   $0x3,-0x3c(%rbp)
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L8
L6:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D7(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L32
  mov    $0x1,%edx
  jmp    L16
L32:
  mov    $0xffffffff,%edx
L16:
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x28(%rbp),%rdi
  mov    -0x40(%rbp),%ecx
  lea    -0x14(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  mov    -0x3c(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <stdlib_ndarray_minmax_view_buffer_index@plt>
  addl   $0x1,-0x44(%rbp)
L8:
  cmpl   $0xf423f,-0x44(%rbp)
  jle    L6
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: f64

tool: D7: 0.5

assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int i;
  int64_t out[2];
  int64_t shape[] = {10, 10, 10};
  int64_t strides[] = {100, 10, 1};
  int64_t offset = 1000;
  int64_t ndims = 3;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    strides[0] *= (rand_double() < 0.5) ? 1 : -1;
    stdlib_ndarray_minmax_view_buffer_index(ndims, shape, strides, offset, out);
    if (out[0] > 1e10) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] > 1e10) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<benchmark>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xa,0x10(%rsp)
  movl   $0xa,0x14(%rsp)
  movl   $0xa,0x18(%rsp)
  movl   $0x64,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  call   <tic@plt>
  movq   %xmm0,%r14
  mov    $0xf4240,%ebx
L14:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D2(%rip),%xmm1
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  imul   0x1c(%rsp),%eax
  mov    %eax,0x1c(%rsp)
  lea    0x1c(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%r8
  mov    $0x3e8,%ecx
  mov    $0x3,%edi
  call   <stdlib_ndarray_minmax_view_buffer_index@plt>
  sub    $0x1,%ebx
  jne    L14
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r14,%xmm2
  subsd  %xmm2,%xmm0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x38,%rsp
  pop    %rbx
  pop    %r14
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: f64

tool: D2: 0.5

assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int i;
  int64_t out[2];
  int64_t shape[] = {10, 10, 10};
  int64_t strides[] = {100, 10, 1};
  int64_t offset = 1000;
  int64_t ndims = 3;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    strides[0] *= (rand_double() < 0.5) ? 1 : -1;
    stdlib_ndarray_minmax_view_buffer_index(ndims, shape, strides, offset, out);
    if (out[0] > 1e10) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] > 1e10) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<benchmark>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xa0000000a,%rax
  lea    0x18(%rsp),%r13
  lea    0x2c(%rsp),%r12
  movl   $0xa,0x28(%rsp)
  movl   $0x1,0x34(%rsp)
  lea    0x20(%rsp),%rbp
  mov    %rax,0x20(%rsp)
  add    $0x5a,%rax
  mov    %rax,0x2c(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  nopl   (%rax)
L10:
  xor    %eax,%eax
  call   <rand_double@plt>
  xor    %eax,%eax
  mov    %r13,%r8
  mov    $0x3e8,%ecx
  movsd  D7(%rip),%xmm1
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  comisd %xmm0,%xmm1
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
  imul   0x2c(%rsp),%eax
  mov    %eax,0x2c(%rsp)
  call   <stdlib_ndarray_minmax_view_buffer_index@plt>
  sub    $0x1,%ebx
  jne    L10
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: f64

tool: D7: 0.5

assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int i;
  int64_t out[2];
  int64_t shape[] = {10, 10, 10};
  int64_t strides[] = {100, 10, 1};
  int64_t offset = 1000;
  int64_t ndims = 3;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    strides[0] *= (rand_double() < 0.5) ? 1 : -1;
    stdlib_ndarray_minmax_view_buffer_index(ndims, shape, strides, offset, out);
    if (out[0] > 1e10) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] > 1e10) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<benchmark>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0xf4240,%ebx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  lea    0x28(%rsp),%r12
  mov    D22(%rip),%rax
  movl   $0xa,0x20(%rsp)
  lea    0x18(%rsp),%rbp
  mov    %rax,0x18(%rsp)
  mov    D26(%rip),%rax
  movl   $0x1,0x30(%rsp)
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <rand_double@plt>
  movsd  D10(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L6
  negl   0x28(%rsp)
L6:
  mov    %r13,%r8
  mov    $0x3e8,%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    $0x3,%edi
  call   <stdlib_ndarray_minmax_view_buffer_index@plt>
  sub    $0x1,%ebx
  jne    L23
  xor    %eax,%eax
  call   <tic@plt>
  subsd  0x8(%rsp),%xmm0
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D22
type_guessed: byte[8]
name: parse_data
arguments: data_label: D26
type_guessed: byte[8]
name: parse_data
arguments: data_label: D10
type_guessed: f64

tool: {"D22": [0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D26": [0x64,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: D10: 0.5

assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  int i;
  int64_t out[2];
  int64_t shape[] = {10, 10, 10};
  int64_t strides[] = {100, 10, 1};
  int64_t offset = 1000;
  int64_t ndims = 3;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    strides[0] *= (rand_double() < 0.5) ? 1 : -1;
    stdlib_ndarray_minmax_view_buffer_index(ndims, shape, strides, offset, out);
    if (out[0] > 1e10) {
      printf("unexpected result\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (out[0] > 1e10) {
    printf("unexpected result\n");
  }
  return elapsed;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trio_substring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *trio_substring(const char *string, const char *substring) {
  assert(string);
  assert(substring);
  return strstr(string, substring);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trio_substring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *trio_substring(const char *string, const char *substring) {
  assert(string);
  assert(substring);
  return strstr(string, substring);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trio_substring>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strstr@plt>
```

assistant: ```c
__attribute__((visibility("default"))) char *trio_substring(const char *string, const char *substring) {
  assert(string);
  assert(substring);
  return strstr(string, substring);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trio_substring>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <assert@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <strstr@plt>
```

assistant: ```c
__attribute__((visibility("default"))) char *trio_substring(const char *string, const char *substring) {
  assert(string);
  assert(substring);
  return strstr(string, substring);
}
```
user: Translate the below assembly code into C programming language:

```asm
<signextend_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  and    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  xor    -0x8(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long signextend_long(long x, int b) {
  intptr_t m = 1U << (b - 1);
  x = x & ((1U << b) - 1);
  return (x ^ m) - m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<signextend_long>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  mov    %eax,%edx
  shl    %cl,%edx
  mov    %esi,%ecx
  shl    %cl,%eax
  lea    -0x1(%rax),%eax
  and    %rdi,%rax
  xor    %rdx,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
long signextend_long(long x, int b) {
  intptr_t m = 1U << (b - 1);
  x = x & ((1U << b) - 1);
  return (x ^ m) - m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<signextend_long>:
  endbr64
  mov    $0x1,%eax
  lea    -0x1(%rsi),%ecx
  mov    %eax,%edx
  shl    %cl,%edx
  mov    %esi,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  and    %rdi,%rax
  xor    %rdx,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
long signextend_long(long x, int b) {
  intptr_t m = 1U << (b - 1);
  x = x & ((1U << b) - 1);
  return (x ^ m) - m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<signextend_long>:
  endbr64
  mov    $0x1,%eax
  lea    -0x1(%rsi),%ecx
  mov    %eax,%edx
  shl    %cl,%edx
  mov    %esi,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  and    %rdi,%rax
  xor    %rdx,%rax
  sub    %rdx,%rax
  ret
```

assistant: ```c
long signextend_long(long x, int b) {
  intptr_t m = 1U << (b - 1);
  x = x & ((1U << b) - 1);
  return (x ^ m) - m;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iir_mem16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x28(%rbp)
  cmpl   $0xa,-0x20(%rbp)
  jne    L23
  mov    -0x28(%rbp),%r8
  mov    -0x20(%rbp),%edi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <iir_mem16_10@plt>
  jmp    L9
L23:
  cmpl   $0x8,-0x20(%rbp)
  jne    L9
  mov    -0x28(%rbp),%r8
  mov    -0x20(%rbp),%edi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <iir_mem16_8@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void iir_mem16(const float *x, const float *_den, float *y, int N, int ord, float *_mem, char *stack) {
  if (ord == 10)
    iir_mem16_10(x, _den, y, N, ord, _mem);
  else if (ord == 8)
    iir_mem16_8(x, _den, y, N, ord, _mem);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iir_mem16>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xa,%r8d
  je     L27
  cmp    $0x8,%r8d
  je     L12
L0:
  add    $0x8,%rsp
  ret
L27:
  call   <iir_mem16_10@plt>
  jmp    L0
L12:
  call   <iir_mem16_8@plt>
  jmp    L0
```

assistant: ```c
void iir_mem16(const float *x, const float *_den, float *y, int N, int ord, float *_mem, char *stack) {
  if (ord == 10)
    iir_mem16_10(x, _den, y, N, ord, _mem);
  else if (ord == 8)
    iir_mem16_8(x, _den, y, N, ord, _mem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<iir_mem16>:
  endbr64
  cmp    $0xa,%r8d
  je     L17
  cmp    $0x8,%r8d
  je     L4
  ret
  nopl   0x0(%rax)
L17:
  jmp    1060 <iir_mem16_10@plt>
  nopl   (%rax)
L4:
  jmp    1070 <iir_mem16_8@plt>
```

assistant: ```c
void iir_mem16(const float *x, const float *_den, float *y, int N, int ord, float *_mem, char *stack) {
  if (ord == 10)
    iir_mem16_10(x, _den, y, N, ord, _mem);
  else if (ord == 8)
    iir_mem16_8(x, _den, y, N, ord, _mem);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<iir_mem16>:
  endbr64
  cmp    $0xa,%r8d
  je     L7
  cmp    $0x8,%r8d
  je     L3
  ret
  nopl   0x0(%rax)
L7:
  jmp    1060 <iir_mem16_10@plt>
  nopl   (%rax)
L3:
  jmp    1070 <iir_mem16_8@plt>
```

assistant: ```c
void iir_mem16(const float *x, const float *_den, float *y, int N, int ord, float *_mem, char *stack) {
  if (ord == 10)
    iir_mem16_10(x, _den, y, N, ord, _mem);
  else if (ord == 8)
    iir_mem16_8(x, _den, y, N, ord, _mem);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mdelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L19
L11:
  mov    $0x3e8,%edi
  call   <udelay@plt>
L19:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void mdelay(unsigned long msec) {
  while (msec--)
    udelay(1000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mdelay>:
  endbr64
  push   %rbx
  lea    -0x1(%rdi),%rbx
  test   %rdi,%rdi
  je     L11
L18:
  mov    $0x3e8,%edi
  call   <udelay@plt>
  sub    $0x1,%rbx
  cmp    $0xffffffffffffffff,%rbx
  jne    L18
L11:
  pop    %rbx
  ret
```

assistant: ```c
void mdelay(unsigned long msec) {
  while (msec--)
    udelay(1000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mdelay>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  lea    -0x1(%rdi),%rbx
  xchg   %ax,%ax
L10:
  mov    $0x3e8,%edi
  call   <udelay@plt>
  sub    $0x1,%rbx
  jae    L10
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void mdelay(unsigned long msec) {
  while (msec--)
    udelay(1000);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mdelay>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  lea    -0x1(%rdi),%rbx
  xchg   %ax,%ax
L2:
  mov    $0x3e8,%edi
  call   <udelay@plt>
  sub    $0x1,%rbx
  jae    L2
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void mdelay(unsigned long msec) {
  while (msec--)
    udelay(1000);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<etheraddr_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L38
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  jmp    L54
L38:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x30,(%rax)
L54:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  movq   $0x5,-0x20(%rbp)
  jmp    L28
L32:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x3a,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L57
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  jmp    L43
L57:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x30,(%rax)
L43:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
L28:
  subq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  test   %eax,%eax
  jns    L32
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: 0123456789ABCDEF

assistant: ```c
char *etheraddr_string(const unsigned char *ep, char *buf) {
  char *hex = "0123456789ABCDEF";
  u_int i, j;
  char *cp;
  cp = buf;
  if ((j = *ep >> 4) != 0)
    *cp++ = hex[j];
  else
    *cp++ = '0';
  *cp++ = hex[*ep++ & 0xf];
  for (i = 5; (int)--i >= 0;) {
    *cp++ = ':';
    if ((j = *ep >> 4) != 0)
      *cp++ = hex[j];
    else
      *cp++ = '0';
    *cp++ = hex[*ep++ & 0xf];
  }
  *cp = '\0';
  return (buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<etheraddr_string>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  movzbl (%rdi),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  test   %rax,%rax
  je     L9
  lea    0x1(%rsi),%r11
  lea    D14(%rip),%rdx
  movzbl (%rdx,%rax,1),%eax
L6:
  mov    %al,(%r10)
  lea    0x1(%rdi),%rdx
  movzbl (%rdi),%eax
  and    $0xf,%eax
  lea    D14(%rip),%rcx
  movzbl (%rcx,%rax,1),%eax
  mov    %al,(%r11)
  lea    0x3(%r11),%rcx
  add    $0x6,%rdi
  mov    $0x30,%ebx
  lea    D14(%rip),%r9
  jmp    L39
L9:
  lea    0x1(%rsi),%r11
  mov    $0x30,%eax
  jmp    L6
L28:
  mov    %r8b,-0x1(%rsi)
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  and    $0xf,%eax
  movzbl (%r9,%rax,1),%eax
  mov    %al,(%rsi)
  add    $0x3,%rcx
  cmp    %rdx,%rdi
  je     L8
L39:
  mov    %rcx,%rsi
  movb   $0x3a,-0x2(%rcx)
  movzbl (%rdx),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %ebx,%r8d
  test   %rax,%rax
  je     L28
  movzbl (%r9,%rax,1),%r8d
  jmp    L28
L8:
  movb   $0x0,0x10(%r11)
  mov    %r10,%rax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D14
type_guessed: string

tool: D14: 0123456789ABCDEF

assistant: ```c
char *etheraddr_string(const unsigned char *ep, char *buf) {
  char *hex = "0123456789ABCDEF";
  u_int i, j;
  char *cp;
  cp = buf;
  if ((j = *ep >> 4) != 0)
    *cp++ = hex[j];
  else
    *cp++ = '0';
  *cp++ = hex[*ep++ & 0xf];
  for (i = 5; (int)--i >= 0;) {
    *cp++ = ':';
    if ((j = *ep >> 4) != 0)
      *cp++ = hex[j];
    else
      *cp++ = '0';
    *cp++ = hex[*ep++ & 0xf];
  }
  *cp = '\0';
  return (buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<etheraddr_string>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rsi,%r9
  mov    $0x30,%edx
  lea    D2(%rip),%r8
  shr    $0x4,%al
  je     L10
  movzbl %al,%eax
  movzbl (%r8,%rax,1),%edx
L10:
  mov    %dl,(%r9)
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  lea    0x2(%r9),%rax
  lea    0x11(%r9),%rdi
  and    $0xf,%edx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,0x1(%r9)
  nopl   0x0(%rax)
L20:
  movb   $0x3a,(%rax)
  movzbl (%rcx),%edx
  mov    $0x30,%esi
  shr    $0x4,%dl
  je     L29
  movzbl %dl,%edx
  movzbl (%r8,%rdx,1),%esi
L29:
  add    $0x1,%rcx
  mov    %sil,0x1(%rax)
  add    $0x3,%rax
  movzbl -0x1(%rcx),%edx
  and    $0xf,%edx
  movzbl (%r8,%rdx,1),%edx
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rdi
  jne    L20
  movb   $0x0,0x11(%r9)
  mov    %r9,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: 0123456789ABCDEF

assistant: ```c
char *etheraddr_string(const unsigned char *ep, char *buf) {
  char *hex = "0123456789ABCDEF";
  u_int i, j;
  char *cp;
  cp = buf;
  if ((j = *ep >> 4) != 0)
    *cp++ = hex[j];
  else
    *cp++ = '0';
  *cp++ = hex[*ep++ & 0xf];
  for (i = 5; (int)--i >= 0;) {
    *cp++ = ':';
    if ((j = *ep >> 4) != 0)
      *cp++ = hex[j];
    else
      *cp++ = '0';
    *cp++ = hex[*ep++ & 0xf];
  }
  *cp = '\0';
  return (buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<etheraddr_string>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rax
  mov    $0x30,%edi
  movzbl (%rdx),%esi
  lea    D9(%rip),%rcx
  shr    $0x4,%sil
  je     L8
  movzbl %sil,%esi
  movzbl (%rcx,%rsi,1),%edi
L8:
  mov    %dil,(%rax)
  movzbl (%rdx),%esi
  mov    $0x30,%edi
  movb   $0x3a,0x2(%rax)
  and    $0xf,%esi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0x1(%rax)
  movzbl 0x1(%rdx),%esi
  shr    $0x4,%sil
  je     L15
  movzbl %sil,%esi
  movzbl (%rcx,%rsi,1),%edi
L15:
  mov    %dil,0x3(%rax)
  movzbl 0x1(%rdx),%esi
  mov    $0x30,%edi
  movb   $0x3a,0x5(%rax)
  and    $0xf,%esi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0x4(%rax)
  movzbl 0x2(%rdx),%esi
  shr    $0x4,%sil
  je     L33
  movzbl %sil,%esi
  movzbl (%rcx,%rsi,1),%edi
L33:
  mov    %dil,0x6(%rax)
  movzbl 0x2(%rdx),%esi
  mov    $0x30,%edi
  movb   $0x3a,0x8(%rax)
  and    $0xf,%esi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0x7(%rax)
  movzbl 0x3(%rdx),%esi
  shr    $0x4,%sil
  je     L57
  movzbl %sil,%esi
  movzbl (%rcx,%rsi,1),%edi
L57:
  mov    %dil,0x9(%rax)
  movzbl 0x3(%rdx),%esi
  mov    $0x30,%edi
  movb   $0x3a,0xb(%rax)
  and    $0xf,%esi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0xa(%rax)
  movzbl 0x4(%rdx),%esi
  shr    $0x4,%sil
  je     L13
  movzbl %sil,%esi
  movzbl (%rcx,%rsi,1),%edi
L13:
  mov    %dil,0xc(%rax)
  movzbl 0x4(%rdx),%esi
  mov    $0x30,%edi
  movb   $0x3a,0xe(%rax)
  and    $0xf,%esi
  movzbl (%rcx,%rsi,1),%esi
  mov    %sil,0xd(%rax)
  movzbl 0x5(%rdx),%esi
  shr    $0x4,%sil
  je     L2
  movzbl %sil,%esi
  movzbl (%rcx,%rsi,1),%edi
L2:
  mov    %dil,0xf(%rax)
  movzbl 0x5(%rdx),%edx
  movb   $0x0,0x11(%rax)
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,0x10(%rax)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: 0123456789ABCDEF

assistant: ```c
char *etheraddr_string(const unsigned char *ep, char *buf) {
  char *hex = "0123456789ABCDEF";
  u_int i, j;
  char *cp;
  cp = buf;
  if ((j = *ep >> 4) != 0)
    *cp++ = hex[j];
  else
    *cp++ = '0';
  *cp++ = hex[*ep++ & 0xf];
  for (i = 5; (int)--i >= 0;) {
    *cp++ = ':';
    if ((j = *ep >> 4) != 0)
      *cp++ = hex[j];
    else
      *cp++ = '0';
    *cp++ = hex[*ep++ & 0xf];
  }
  *cp = '\0';
  return (buf);
}
```