ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x57202c6f6c6c6548,%rax
  mov    %rax,0xa(%rsp)
  movl   $0x646c726f,0x12(%rsp)
  movw   $0x21,0x16(%rsp)
  lea    D62(%rip),%rdi
  call   <puts@plt>
  mov    $0x3039,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D56(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x52,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xa(%rsp),%rsi
  lea    D61(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xe,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D3(%rip),%xmm0
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D62
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D56
type: string
name: parse_data
arguments: label: D26
type: string
name: parse_data
arguments: label: D61
type: string
name: parse_data
arguments: label: D3
type: byte[8]
name: parse_data
arguments: label: D58
type: string

tool: D62: Practice 02

tool: D36: a=%d

tool: D56: 	size=%d


tool: D26: c=%c

tool: D61: s=%s

tool: {"D3": [0x00,0x00,0x00,0x20,0x83,0xc0,0xf3,0x3f]}

tool: D58: v=%f

assistant: ```c
int main() {
  int a = 12345;
  char c = 'R';
  char s[] = "Hello, World!";
  float v = 1.2345;
  int size;
  printf("Practice 02\n");
  printf("a=%d", a);
  size = sizeof(a);
  printf("\tsize=%d\n", size);
  printf("c=%c", c);
  size = sizeof(c);
  printf("\tsize=%d\n", size);
  printf("s=%s", s);
  size = sizeof(s);
  printf("\tsize=%d\n", size);
  printf("v=%f", v);
  size = sizeof(v);
  printf("\tsize=%d\n", size);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D54(%rip),%rdi
  lea    D68(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x57202c6f6c6c6548,%rax
  movl   $0x646c726f,0x12(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x16(%rsp)
  call   <puts@plt>
  mov    $0x3039,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x52,%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xa(%rsp),%rsi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xe,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D61(%rip),%xmm0
  mov    $0x1,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D54
type_infered: string
name: extract_symbolic_data
arguments: tag: D68
type_infered: string
name: extract_symbolic_data
arguments: tag: D35
type_infered: string
name: extract_symbolic_data
arguments: tag: D59
type_infered: string
name: extract_symbolic_data
arguments: tag: D30
type_infered: string
name: extract_symbolic_data
arguments: tag: D61
type_infered: byte[8]
name: extract_symbolic_data
arguments: tag: D31
type_infered: string

tool: D54: Practice 02

tool: D68: 	size=%d


tool: D35: a=%d

tool: D59: c=%c

tool: D30: s=%s

tool: {"D61": [0x00,0x00,0x00,0x20,0x83,0xc0,0xf3,0x3f]}

tool: D31: v=%f

assistant: ```c
int main() {
  int a = 12345;
  char c = 'R';
  char s[] = "Hello, World!";
  float v = 1.2345;
  int size;
  printf("Practice 02\n");
  printf("a=%d", a);
  size = sizeof(a);
  printf("\tsize=%d\n", size);
  printf("c=%c", c);
  size = sizeof(c);
  printf("\tsize=%d\n", size);
  printf("s=%s", s);
  size = sizeof(s);
  printf("\tsize=%d\n", size);
  printf("v=%f", v);
  size = sizeof(v);
  printf("\tsize=%d\n", size);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  lea    D59(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x57202c6f6c6c6548,%rax
  movl   $0x646c726f,0x12(%rsp)
  mov    %rax,0xa(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x16(%rsp)
  call   <puts@plt>
  mov    $0x3039,%esi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x52,%esi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xa(%rsp),%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xe,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  D60(%rip),%xmm0
  mov    $0x1,%eax
  lea    D48(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D59
data_type: string
name: parse_data
arguments: data_tag: D32
data_type: string
name: parse_data
arguments: data_tag: D35
data_type: string
name: parse_data
arguments: data_tag: D17
data_type: string
name: parse_data
arguments: data_tag: D60
data_type: byte[8]
name: parse_data
arguments: data_tag: D48
data_type: string

tool: D14: Practice 02

tool: D59: 	size=%d


tool: D32: a=%d

tool: D35: c=%c

tool: D17: s=%s

tool: {"D60": [0x00,0x00,0x00,0x20,0x83,0xc0,0xf3,0x3f]}

tool: D48: v=%f

assistant: ```c
int main() {
  int a = 12345;
  char c = 'R';
  char s[] = "Hello, World!";
  float v = 1.2345;
  int size;
  printf("Practice 02\n");
  printf("a=%d", a);
  size = sizeof(a);
  printf("\tsize=%d\n", size);
  printf("c=%c", c);
  size = sizeof(c);
  printf("\tsize=%d\n", size);
  printf("s=%s", s);
  size = sizeof(s);
  printf("\tsize=%d\n", size);
  printf("v=%f", v);
  size = sizeof(v);
  printf("\tsize=%d\n", size);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bn_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BN_print@plt>
  test   %eax,%eax
  jne    L31
  mov    $0x0,%eax
  jmp    L10
L31:
  mov    -0x18(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_printf@plt>
  test   %rax,%rax
  jg     L8
  mov    $0x0,%eax
  jmp    L10
L8:
  mov    $0x1,%eax
L10:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: 


assistant: ```c
int bn_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  BIGNUM *bn = (BIGNUM *)*pval;
  if (!BN_print(out, bn))
    return 0;
  if (BIO_printf(out, "\n") <= 0)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bn_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rsi),%rsi
  call   <BN_print@plt>
  test   %eax,%eax
  jne    L15
L6:
  pop    %rbx
  ret
L15:
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <BIO_printf@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  jmp    L6
```

tool_calls: name: parse_data
arguments: label: D9
datatype: string

tool: D9: 


assistant: ```c
int bn_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  BIGNUM *bn = (BIGNUM *)*pval;
  if (!BN_print(out, bn))
    return 0;
  if (BIO_printf(out, "\n") <= 0)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<bn_print>:
  endbr64
  push   %rbp
  mov    (%rsi),%rsi
  mov    %rdi,%rbp
  call   <BN_print@plt>
  test   %eax,%eax
  jne    L8
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <BIO_printf@plt>
  pop    %rbp
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: 


assistant: ```c
int bn_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  BIGNUM *bn = (BIGNUM *)*pval;
  if (!BN_print(out, bn))
    return 0;
  if (BIO_printf(out, "\n") <= 0)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bn_print>:
  endbr64
  push   %rbp
  mov    (%rsi),%rsi
  mov    %rdi,%rbp
  call   <BN_print@plt>
  test   %eax,%eax
  jne    L0
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  call   <BIO_printf@plt>
  pop    %rbp
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string

tool: D1: 


assistant: ```c
int bn_print(BIO *out, ASN1_VALUE **pval, const ASN1_ITEM *it, int indent, const ASN1_PCTX *pctx) {
  BIGNUM *bn = (BIGNUM *)*pval;
  if (!BN_print(out, bn))
    return 0;
  if (BIO_printf(out, "\n") <= 0)
    return 0;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<packet_fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0xffffff,-0x4(%rbp)
  jle    L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void packet_fill(u_char *packet) {
  int i;
  for (i = 0; i < 16 * (1024 * 1024); i++)
    packet[i] = (i & 0xff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<packet_fill>:
  endbr64
  mov    $0x0,%eax
L7:
  movzbl %al,%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x1000000,%rax
  jne    L7
  ret
```

assistant: ```c
void packet_fill(u_char *packet) {
  int i;
  for (i = 0; i < 16 * (1024 * 1024); i++)
    packet[i] = (i & 0xff);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<packet_fill>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L0:
  movzbl %al,%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    $0x1000000,%rax
  jne    L0
  ret
```

assistant: ```c
void packet_fill(u_char *packet) {
  int i;
  for (i = 0; i < 16 * (1024 * 1024); i++)
    packet[i] = (i & 0xff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<packet_fill>:
  endbr64
  movdqa D11(%rip),%xmm1
  movdqa D28(%rip),%xmm3
  lea    0x4000000(%rdi),%rax
  movdqa D24(%rip),%xmm2
  nopl   0x0(%rax,%rax,1)
L7:
  movdqa %xmm1,%xmm0
  add    $0x10,%rdi
  paddd  %xmm3,%xmm1
  pand   %xmm2,%xmm0
  movups %xmm0,-0x10(%rdi)
  cmp    %rdi,%rax
  jne    L7
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: byte[16]
name: disassemble_data
arguments: data_label: D28
type: byte[16]
name: disassemble_data
arguments: data_label: D24
type: byte[16]

tool: {"D11": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D28": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D24": [0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00]}

assistant: ```c
void packet_fill(u_char *packet) {
  int i;
  for (i = 0; i < 16 * (1024 * 1024); i++)
    packet[i] = (i & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<df_f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L13:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((no, noclone)) df_f2(double *__restrict a, double *__restrict b, double *__restrict c) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = c[i * 2];
    b[i] = c[i * 2 + 1];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<df_f2>:
  endbr64
  mov    $0x0,%eax
L2:
  movsd  (%rdx,%rax,2),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  movsd  0x8(%rdx,%rax,2),%xmm0
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    $0x2000,%rax
  jne    L2
  ret
```

assistant: ```c
void __attribute__((no, noclone)) df_f2(double *__restrict a, double *__restrict b, double *__restrict c) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = c[i * 2];
    b[i] = c[i * 2 + 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<df_f2>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movsd  (%rdx,%rax,2),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  movsd  0x8(%rdx,%rax,2),%xmm0
  movsd  %xmm0,(%rsi,%rax,1)
  add    $0x8,%rax
  cmp    $0x2000,%rax
  jne    L2
  ret
```

assistant: ```c
void __attribute__((no, noclone)) df_f2(double *__restrict a, double *__restrict b, double *__restrict c) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = c[i * 2];
    b[i] = c[i * 2 + 1];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<df_f2>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  movupd (%rdx,%rax,2),%xmm0
  movhpd 0x10(%rdx,%rax,2),%xmm0
  movups %xmm0,(%rdi,%rax,1)
  movupd 0x10(%rdx,%rax,2),%xmm0
  movlpd 0x8(%rdx,%rax,2),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    $0x2000,%rax
  jne    L3
  ret
```

assistant: ```c
void __attribute__((no, noclone)) df_f2(double *__restrict a, double *__restrict b, double *__restrict c) {
  for (int i = 0; i < 1024; ++i) {
    a[i] = c[i * 2];
    b[i] = c[i * 2 + 1];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<unix_domain_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L42
  mov    $0xffffffff,%eax
  jmp    L8
L42:
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x28(%rbp),%rcx
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <strncpy@plt>
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  test   %rax,%rax
  je     L34
  mov    $0xffffffff,%eax
  jmp    L8
L34:
  mov    -0x14(%rbp),%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int unix_domain_socket(const char *source) {
  int sockfd;
  struct sockaddr_un servaddr;
  if ((sockfd = socket(AF_UNIX, SOCK_STREAM, 0)) == -1)
    return -1;
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sun_family = AF_UNIX;
  strncpy(servaddr.sun_path, source, sizeof(servaddr.sun_path) - 1);
  if (connect(sockfd, &servaddr, sizeof(servaddr)))
    return -1;
  return sockfd;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unix_domain_socket>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L13
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    (%rsp),%edi
  call   <strncpy@plt>
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <connect@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovne %eax,%ebx
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unix_domain_socket(const char *source) {
  int sockfd;
  struct sockaddr_un servaddr;
  if ((sockfd = socket(AF_UNIX, SOCK_STREAM, 0)) == -1)
    return -1;
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sun_family = AF_UNIX;
  strncpy(servaddr.sun_path, source, sizeof(servaddr.sun_path) - 1);
  if (connect(sockfd, &servaddr, sizeof(servaddr)))
    return -1;
  return sockfd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unix_domain_socket>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D0(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    (%rsp),%edi
  mov    $0x3,%edx
  mov    %r13,%rsi
  mov    %eax,0x4(%rsp)
  call   <strncpy@plt>
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L9
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L9:
  mov    $0xffffffff,%r12d
  jmp    L17
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unix_domain_socket(const char *source) {
  int sockfd;
  struct sockaddr_un servaddr;
  if ((sockfd = socket(AF_UNIX, SOCK_STREAM, 0)) == -1)
    return -1;
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sun_family = AF_UNIX;
  strncpy(servaddr.sun_path, source, sizeof(servaddr.sun_path) - 1);
  if (connect(sockfd, &servaddr, sizeof(servaddr)))
    return -1;
  return sockfd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unix_domain_socket>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D10(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L33
  mov    %rsp,%rbp
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    (%rsp),%edi
  mov    $0x3,%edx
  mov    %r13,%rsi
  mov    %eax,0x4(%rsp)
  call   <strncpy@plt>
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <connect@plt>
  test   %rax,%rax
  jne    L33
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L33:
  mov    $0xffffffff,%r12d
  jmp    L25
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int unix_domain_socket(const char *source) {
  int sockfd;
  struct sockaddr_un servaddr;
  if ((sockfd = socket(AF_UNIX, SOCK_STREAM, 0)) == -1)
    return -1;
  memset(&servaddr, 0, sizeof(servaddr));
  servaddr.sun_family = AF_UNIX;
  strncpy(servaddr.sun_path, source, sizeof(servaddr.sun_path) - 1);
  if (connect(sockfd, &servaddr, sizeof(servaddr)))
    return -1;
  return sockfd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PWMGenDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  and    $0xfffffffe,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PWMGenDisable(uint32_t ui32Base, uint32_t ui32Gen) {
  ;
  ;
  (*((volatile uint32_t *)(((ui32Base) + (ui32Gen)) + 0x00000000))) &= ~(0x00000001);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<PWMGenDisable>:
  endbr64
  add    %esi,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void PWMGenDisable(uint32_t ui32Base, uint32_t ui32Gen) {
  ;
  ;
  (*((volatile uint32_t *)(((ui32Base) + (ui32Gen)) + 0x00000000))) &= ~(0x00000001);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PWMGenDisable>:
  endbr64
  add    %esi,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void PWMGenDisable(uint32_t ui32Base, uint32_t ui32Gen) {
  ;
  ;
  (*((volatile uint32_t *)(((ui32Base) + (ui32Gen)) + 0x00000000))) &= ~(0x00000001);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PWMGenDisable>:
  endbr64
  add    %esi,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffffe,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void PWMGenDisable(uint32_t ui32Base, uint32_t ui32Gen) {
  ;
  ;
  (*((volatile uint32_t *)(((ui32Base) + (ui32Gen)) + 0x00000000))) &= ~(0x00000001);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fake_secret_peer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    -0x14(%rbp),%eax
  jmp    L0
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: SSSD_INTG_SECRETS_PEER

assistant: ```c
uid_t fake_secret_peer(uid_t orig_id) {
  char *val;
  val = getenv("SSSD_INTG_SECRETS_PEER");
  if (val == NULL) {
    return orig_id;
  }
  return atoi(val);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fake_secret_peer>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D1(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  mov    %ebx,%eax
  test   %rdi,%rdi
  je     L5
  call   <atoi@plt>
L5:
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: SSSD_INTG_SECRETS_PEER

assistant: ```c
uid_t fake_secret_peer(uid_t orig_id) {
  char *val;
  val = getenv("SSSD_INTG_SECRETS_PEER");
  if (val == NULL) {
    return orig_id;
  }
  return atoi(val);
}
```