ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RateChange>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  je     L97
  push   %rbx
  mov    %rsi,%r9
  mov    %edx,%ebx
  cmp    %r8d,%ecx
  je     L111
  pxor   %xmm4,%xmm4
  cvtsi2ss %ecx,%xmm4
  pxor   %xmm1,%xmm1
  cvtsi2ss %r8d,%xmm1
  jle    L51
  divss  %xmm4,%xmm1
  mov    %rsi,%r8
  mov    $0x0,%esi
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  movss  D11(%rip),%xmm2
  movaps %xmm2,%xmm3
  jmp    L56
L111:
  lea    (%rdx,%rdx,1),%edx
  mov    %rdi,%rsi
  mov    %r9,%rdi
  call   <memcpy@plt>
  mov    %ebx,%eax
  jmp    L124
L93:
  subss  %xmm3,%xmm0
  lea    0x2(%r8),%rcx
  cltd
  idiv   %esi
  mov    %ax,(%r8)
  test   %ebx,%ebx
  je     L13
  mov    %rcx,%r8
  mov    %rdi,%rdx
  mov    $0x0,%esi
  mov    $0x0,%eax
L53:
  mov    %rdx,%rdi
L56:
  comiss %xmm0,%xmm2
  jbe    L93
  lea    0x2(%rdi),%rdx
  movswl (%rdi),%ecx
  add    %ecx,%eax
  addss  %xmm1,%xmm0
  add    $0x1,%esi
  sub    $0x1,%ebx
  jne    L53
  lea    0x2(%r8),%rcx
  cltd
  idiv   %esi
  mov    %ax,(%r8)
L13:
  sub    %r9,%rcx
  sar    %rcx
  mov    %ecx,%eax
L124:
  pop    %rbx
  ret
L51:
  divss  %xmm1,%xmm4
  cmp    $0x1,%edx
  je     L46
  lea    -0x1(%rdx),%eax
  lea    (%rdi,%rax,2),%r8
  mov    %rsi,%rcx
  pxor   %xmm0,%xmm0
  movss  D11(%rip),%xmm7
  movaps %xmm7,%xmm5
  movaps %xmm7,%xmm6
L130:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%eax
  movswl (%rdi),%edx
  movswl %ax,%esi
  sub    %esi,%edx
  comiss %xmm0,%xmm7
  jbe    L79
  pxor   %xmm3,%xmm3
  cvtsi2ss %edx,%xmm3
  pxor   %xmm2,%xmm2
  cvtsi2ss %esi,%xmm2
L11:
  add    $0x2,%rcx
  movaps %xmm3,%xmm1
  mulss  %xmm0,%xmm1
  addss  %xmm2,%xmm1
  cvttss2si %xmm1,%eax
  mov    %ax,-0x2(%rcx)
  addss  %xmm4,%xmm0
  comiss %xmm0,%xmm5
  ja     L11
L79:
  subss  %xmm6,%xmm0
  cmp    %rdi,%r8
  jne    L130
  jmp    L13
L46:
  mov    %rsi,%rcx
  jmp    L13
L97:
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type: f32

tool: D11: 1

assistant: ```c
int RateChange(short *src, short *dest, int srcLen, int srcRate, int destRate) {
  short *sourceShortPtr;
  short *destShortPtr;
  float nSrcRate, nDestRate;
  nSrcRate = srcRate;
  nDestRate = destRate;
  if (!srcLen)
    return 0;
  if (srcRate == destRate) {
    memcpy((char *)dest, (char *)src, srcLen * 2);
    return srcLen;
  }
  sourceShortPtr = src;
  destShortPtr = dest;
  if (srcRate > destRate) {
    float destStep = nDestRate / nSrcRate;
    float position = 0;
    while (srcLen) {
      int destSample = 0;
      int count = 0;
      while (srcLen && (position < 1.0)) {
        destSample += *sourceShortPtr++;
        srcLen--;
        position += destStep;
        count++;
      }
      position = position - 1.0;
      *destShortPtr++ = (destSample / count);
    }
  } else {
    float sourceStep = nSrcRate / nDestRate;
    float position = 0;
    while (--srcLen) {
      int leftSample = *sourceShortPtr++;
      int sampleDifference = *sourceShortPtr - leftSample;
      while (position < 1.0) {
        *destShortPtr++ = leftSample + ((float)sampleDifference * position);
        position += sourceStep;
      }
      position = position - 1.0;
    }
  }
  return destShortPtr - dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RateChange>:
  endbr64
  xor    %eax,%eax
  test   %edx,%edx
  je     L69
  push   %rbx
  mov    %rdi,%r9
  mov    %edx,%ebx
  mov    %rsi,%rdi
  cmp    %r8d,%ecx
  je     L63
  pxor   %xmm5,%xmm5
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm5
  cvtsi2ss %r8d,%xmm1
  jg     L88
  divss  %xmm1,%xmm5
  cmp    $0x1,%edx
  je     L61
  lea    -0x1(%rdx),%eax
  movss  D13(%rip),%xmm2
  pxor   %xmm0,%xmm0
  lea    (%r9,%rax,2),%rsi
  mov    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L36:
  movswl 0x2(%r9),%edx
  movswl (%r9),%ecx
  add    $0x2,%r9
  sub    %ecx,%edx
  comiss %xmm0,%xmm2
  jbe    L44
  pxor   %xmm4,%xmm4
  pxor   %xmm3,%xmm3
  cvtsi2ss %ecx,%xmm4
  cvtsi2ss %edx,%xmm3
  nopl   0x0(%rax)
L3:
  movaps %xmm0,%xmm1
  addss  %xmm5,%xmm0
  add    $0x2,%rax
  mulss  %xmm3,%xmm1
  comiss %xmm0,%xmm2
  addss  %xmm4,%xmm1
  cvttss2si %xmm1,%edx
  mov    %dx,-0x2(%rax)
  ja     L3
L44:
  subss  %xmm2,%xmm0
  cmp    %rsi,%r9
  jne    L36
  sub    %rdi,%rax
  sar    %rax
L61:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L88:
  divss  %xmm5,%xmm1
  movss  D13(%rip),%xmm2
  mov    %rsi,%rcx
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax,%rax,1)
L91:
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L45:
  comiss %xmm0,%xmm2
  jbe    L6
  movswl (%r9),%edx
  add    $0x2,%r9
  addss  %xmm1,%xmm0
  add    $0x1,%esi
  add    %edx,%eax
  sub    $0x1,%ebx
  jne    L45
  cltd
  idiv   %esi
  mov    %ax,(%rcx)
  lea    0x2(%rcx),%rax
  pop    %rbx
  sub    %rdi,%rax
  sar    %rax
  ret
  nopl   (%rax)
L6:
  cltd
  add    $0x2,%rcx
  subss  %xmm2,%xmm0
  idiv   %esi
  mov    %ax,-0x2(%rcx)
  jmp    L91
  nopl   0x0(%rax)
L69:
  ret
L63:
  lea    (%rdx,%rdx,1),%edx
  mov    %r9,%rsi
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D13
type_guessed: f32

tool: D13: 1

assistant: ```c
int RateChange(short *src, short *dest, int srcLen, int srcRate, int destRate) {
  short *sourceShortPtr;
  short *destShortPtr;
  float nSrcRate, nDestRate;
  nSrcRate = srcRate;
  nDestRate = destRate;
  if (!srcLen)
    return 0;
  if (srcRate == destRate) {
    memcpy((char *)dest, (char *)src, srcLen * 2);
    return srcLen;
  }
  sourceShortPtr = src;
  destShortPtr = dest;
  if (srcRate > destRate) {
    float destStep = nDestRate / nSrcRate;
    float position = 0;
    while (srcLen) {
      int destSample = 0;
      int count = 0;
      while (srcLen && (position < 1.0)) {
        destSample += *sourceShortPtr++;
        srcLen--;
        position += destStep;
        count++;
      }
      position = position - 1.0;
      *destShortPtr++ = (destSample / count);
    }
  } else {
    float sourceStep = nSrcRate / nDestRate;
    float position = 0;
    while (--srcLen) {
      int leftSample = *sourceShortPtr++;
      int sampleDifference = *sourceShortPtr - leftSample;
      while (position < 1.0) {
        *destShortPtr++ = leftSample + ((float)sampleDifference * position);
        position += sourceStep;
      }
      position = position - 1.0;
    }
  }
  return destShortPtr - dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RateChange>:
  endbr64
  xor    %eax,%eax
  test   %edx,%edx
  je     L51
  push   %rbx
  mov    %rdi,%r9
  mov    %edx,%ebx
  mov    %rsi,%rdi
  cmp    %r8d,%ecx
  je     L5
  pxor   %xmm5,%xmm5
  pxor   %xmm1,%xmm1
  cvtsi2ss %ecx,%xmm5
  cvtsi2ss %r8d,%xmm1
  jg     L78
  divss  %xmm1,%xmm5
  cmp    $0x1,%edx
  je     L49
  lea    -0x1(%rdx),%eax
  movss  D19(%rip),%xmm2
  pxor   %xmm0,%xmm0
  lea    (%r9,%rax,2),%rsi
  mov    %rdi,%rax
  cs nopw 0x0(%rax,%rax,1)
L74:
  movswl 0x2(%r9),%edx
  movswl (%r9),%ecx
  add    $0x2,%r9
  sub    %ecx,%edx
  comiss %xmm0,%xmm2
  jbe    L35
  pxor   %xmm4,%xmm4
  pxor   %xmm3,%xmm3
  cvtsi2ss %ecx,%xmm4
  cvtsi2ss %edx,%xmm3
  nopl   0x0(%rax)
L60:
  movaps %xmm0,%xmm1
  addss  %xmm5,%xmm0
  add    $0x2,%rax
  mulss  %xmm3,%xmm1
  comiss %xmm0,%xmm2
  addss  %xmm4,%xmm1
  cvttss2si %xmm1,%edx
  mov    %dx,-0x2(%rax)
  ja     L60
L35:
  subss  %xmm2,%xmm0
  cmp    %rsi,%r9
  jne    L74
  sub    %rdi,%rax
  sar    %rax
L49:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L78:
  divss  %xmm5,%xmm1
  movss  D19(%rip),%xmm2
  mov    %rsi,%rcx
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax,%rax,1)
L72:
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L38:
  comiss %xmm0,%xmm2
  jbe    L24
  movswl (%r9),%edx
  add    $0x2,%r9
  addss  %xmm1,%xmm0
  add    $0x1,%esi
  add    %edx,%eax
  sub    $0x1,%ebx
  jne    L38
  cltd
  idiv   %esi
  mov    %ax,(%rcx)
  lea    0x2(%rcx),%rax
  pop    %rbx
  sub    %rdi,%rax
  sar    %rax
  ret
  nopl   (%rax)
L24:
  cltd
  add    $0x2,%rcx
  subss  %xmm2,%xmm0
  idiv   %esi
  mov    %ax,-0x2(%rcx)
  jmp    L72
  nopl   0x0(%rax)
L51:
  ret
L5:
  lea    (%rdx,%rdx,1),%edx
  mov    %r9,%rsi
  call   <memcpy@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: f32

tool: D19: 1

assistant: ```c
int RateChange(short *src, short *dest, int srcLen, int srcRate, int destRate) {
  short *sourceShortPtr;
  short *destShortPtr;
  float nSrcRate, nDestRate;
  nSrcRate = srcRate;
  nDestRate = destRate;
  if (!srcLen)
    return 0;
  if (srcRate == destRate) {
    memcpy((char *)dest, (char *)src, srcLen * 2);
    return srcLen;
  }
  sourceShortPtr = src;
  destShortPtr = dest;
  if (srcRate > destRate) {
    float destStep = nDestRate / nSrcRate;
    float position = 0;
    while (srcLen) {
      int destSample = 0;
      int count = 0;
      while (srcLen && (position < 1.0)) {
        destSample += *sourceShortPtr++;
        srcLen--;
        position += destStep;
        count++;
      }
      position = position - 1.0;
      *destShortPtr++ = (destSample / count);
    }
  } else {
    float sourceStep = nSrcRate / nDestRate;
    float position = 0;
    while (--srcLen) {
      int leftSample = *sourceShortPtr++;
      int sampleDifference = *sourceShortPtr - leftSample;
      while (position < 1.0) {
        *destShortPtr++ = leftSample + ((float)sampleDifference * position);
        position += sourceStep;
      }
      position = position - 1.0;
    }
  }
  return destShortPtr - dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <waiter1@plt>
  mov    $0x0,%edi
  call   <waiter2@plt>
  mov    $0x0,%edi
  call   <waker1@plt>
  mov    $0x0,%edi
  call   <waker2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  waiter1(0);
__CPROVER_ASYNC_2:
  waiter2(0);
__CPROVER_ASYNC_3:
  waker1(0);
__CPROVER_ASYNC_4:
  waker2(0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <waiter1@plt>
  mov    $0x0,%edi
  call   <waiter2@plt>
  mov    $0x0,%edi
  call   <waker1@plt>
  mov    $0x0,%edi
  call   <waker2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  waiter1(0);
__CPROVER_ASYNC_2:
  waiter2(0);
__CPROVER_ASYNC_3:
  waker1(0);
__CPROVER_ASYNC_4:
  waker2(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <waiter1@plt>
  xor    %edi,%edi
  call   <waiter2@plt>
  xor    %edi,%edi
  call   <waker1@plt>
  xor    %edi,%edi
  call   <waker2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  waiter1(0);
__CPROVER_ASYNC_2:
  waiter2(0);
__CPROVER_ASYNC_3:
  waker1(0);
__CPROVER_ASYNC_4:
  waker2(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <waiter1@plt>
  xor    %edi,%edi
  call   <waiter2@plt>
  xor    %edi,%edi
  call   <waker1@plt>
  xor    %edi,%edi
  call   <waker2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
__CPROVER_ASYNC_1:
  waiter1(0);
__CPROVER_ASYNC_2:
  waiter2(0);
__CPROVER_ASYNC_3:
  waker1(0);
__CPROVER_ASYNC_4:
  waker2(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0xfffffff9,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <sumarr@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D5: sum = %d


assistant: ```c
void f(void) {
  int sum = 0;
  int arr[5];
  arr[0] = 4;
  arr[1] = -7;
  arr[2] = 2;
  arr[3] = 3;
  arr[4] = 9;
  sum = sumarr(arr, 5);
  printf("sum = %d\n", sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0xfffffff9,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x9,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <sumarr@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string

tool: D0: sum = %d


assistant: ```c
void f(void) {
  int sum = 0;
  int arr[5];
  arr[0] = 4;
  arr[1] = -7;
  arr[2] = 2;
  arr[3] = 3;
  arr[4] = 9;
  sum = sumarr(arr, 5);
  printf("sum = %d\n", sum);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xfffffff900000004,%rax
  mov    %rsp,%rdi
  movl   $0x9,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  call   <sumarr@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string

tool: D3: sum = %d


assistant: ```c
void f(void) {
  int sum = 0;
  int arr[5];
  arr[0] = 4;
  arr[1] = -7;
  arr[2] = 2;
  arr[3] = 3;
  arr[4] = 9;
  sum = sumarr(arr, 5);
  printf("sum = %d\n", sum);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f>:
  endbr64
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x9,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <sumarr@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: byte[16]
name: unpack_data
arguments: tag: D15
type_infered: string

tool: {"D2": [0x04,0x00,0x00,0x00,0xf9,0xff,0xff,0xff,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D15: sum = %d


assistant: ```c
void f(void) {
  int sum = 0;
  int arr[5];
  arr[0] = 4;
  arr[1] = -7;
  arr[2] = 2;
  arr[3] = 3;
  arr[4] = 9;
  sum = sumarr(arr, 5);
  printf("sum = %d\n", sum);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setstacksizeunlimited>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getrlimit@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <setrlimit@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void setstacksizeunlimited(void) {
  struct rlimit limit;
  getrlimit(RLIMIT_STACK, &limit);
  limit.rlim_cur = limit.rlim_max;
  setrlimit(RLIMIT_STACK, &limit);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setstacksizeunlimited>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D5(%rip),%rbx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <getrlimit@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <setrlimit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setstacksizeunlimited(void) {
  struct rlimit limit;
  getrlimit(RLIMIT_STACK, &limit);
  limit.rlim_cur = limit.rlim_max;
  setrlimit(RLIMIT_STACK, &limit);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setstacksizeunlimited>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D7(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  call   <getrlimit@plt>
  mov    (%rsp),%eax
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  mov    %eax,0x4(%rsp)
  call   <setrlimit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setstacksizeunlimited(void) {
  struct rlimit limit;
  getrlimit(RLIMIT_STACK, &limit);
  limit.rlim_cur = limit.rlim_max;
  setrlimit(RLIMIT_STACK, &limit);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setstacksizeunlimited>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D3(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  call   <getrlimit@plt>
  mov    (%rsp),%eax
  mov    (%rbx),%edi
  mov    %rbp,%rsi
  mov    %eax,0x4(%rsp)
  call   <setrlimit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setstacksizeunlimited(void) {
  struct rlimit limit;
  getrlimit(RLIMIT_STACK, &limit);
  limit.rlim_cur = limit.rlim_max;
  setrlimit(RLIMIT_STACK, &limit);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_mean_sidereal_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  D34(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D0(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D49(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D12(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm2
  movsd  D3(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  D44(%rip),%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <range_degrees@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_infered: f64
name: parse_data
arguments: tag: D34
type_infered: f64
name: parse_data
arguments: tag: D49
type_infered: f64
name: parse_data
arguments: tag: D12
type_infered: f64
name: parse_data
arguments: tag: D3
type_infered: f64
name: parse_data
arguments: tag: D44
type_infered: f64

tool: D0: 2451545

tool: D34: 36525

tool: D49: 360.98564736629

tool: D12: 280.46061837

tool: D3: 0.000387933

tool: D44: 38710000

assistant: ```c
double get_mean_sidereal_time(double JD) {
  double sidereal;
  double T;
  T = (JD - 2451545.0) / 36525.0;
  sidereal = 280.46061837 + (360.98564736629 * (JD - 2451545.0)) + (0.000387933 * T * T) - (T * T * T / 38710000.0);
  sidereal = range_degrees(sidereal);
  return sidereal;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_mean_sidereal_time>:
  endbr64
  sub    $0x8,%rsp
  subsd  D57(%rip),%xmm0
  movapd %xmm0,%xmm2
  divsd  D58(%rip),%xmm2
  mulsd  D14(%rip),%xmm0
  addsd  D42(%rip),%xmm0
  movapd %xmm2,%xmm1
  mulsd  D56(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  D33(%rip),%xmm1
  subsd  %xmm1,%xmm0
  call   <range_degrees@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D57
type_guessed: f64
name: disassemble_data
arguments: data_tag: D58
type_guessed: f64
name: disassemble_data
arguments: data_tag: D14
type_guessed: f64
name: disassemble_data
arguments: data_tag: D42
type_guessed: f64
name: disassemble_data
arguments: data_tag: D56
type_guessed: f64
name: disassemble_data
arguments: data_tag: D33
type_guessed: f64

tool: D57: 2451545

tool: D58: 36525

tool: D14: 360.98564736629

tool: D42: 280.46061837

tool: D56: 0.000387933

tool: D33: 38710000

assistant: ```c
double get_mean_sidereal_time(double JD) {
  double sidereal;
  double T;
  T = (JD - 2451545.0) / 36525.0;
  sidereal = 280.46061837 + (360.98564736629 * (JD - 2451545.0)) + (0.000387933 * T * T) - (T * T * T / 38710000.0);
  sidereal = range_degrees(sidereal);
  return sidereal;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_mean_sidereal_time>:
  endbr64
  subsd  D19(%rip),%xmm0
  movsd  D26(%rip),%xmm1
  movapd %xmm0,%xmm2
  divsd  D57(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  D4(%rip),%xmm0
  addsd  D17(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  D44(%rip),%xmm1
  subsd  %xmm1,%xmm0
  jmp    1050 <range_degrees@plt>
```

tool_calls: name: parse_data
arguments: label: D19
datatype: f64
name: parse_data
arguments: label: D26
datatype: f64
name: parse_data
arguments: label: D57
datatype: f64
name: parse_data
arguments: label: D4
datatype: f64
name: parse_data
arguments: label: D17
datatype: f64
name: parse_data
arguments: label: D44
datatype: f64

tool: D19: 2451545

tool: D26: 0.000387933

tool: D57: 36525

tool: D4: 360.98564736629

tool: D17: 280.46061837

tool: D44: 38710000

assistant: ```c
double get_mean_sidereal_time(double JD) {
  double sidereal;
  double T;
  T = (JD - 2451545.0) / 36525.0;
  sidereal = 280.46061837 + (360.98564736629 * (JD - 2451545.0)) + (0.000387933 * T * T) - (T * T * T / 38710000.0);
  sidereal = range_degrees(sidereal);
  return sidereal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_mean_sidereal_time>:
  endbr64
  subsd  D30(%rip),%xmm0
  movsd  D22(%rip),%xmm1
  movapd %xmm0,%xmm2
  divsd  D31(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  D4(%rip),%xmm0
  addsd  D0(%rip),%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm1
  divsd  D27(%rip),%xmm1
  subsd  %xmm1,%xmm0
  jmp    1050 <range_degrees@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D30
datatype: f64
name: parse_data
arguments: data_tag: D22
datatype: f64
name: parse_data
arguments: data_tag: D31
datatype: f64
name: parse_data
arguments: data_tag: D4
datatype: f64
name: parse_data
arguments: data_tag: D0
datatype: f64
name: parse_data
arguments: data_tag: D27
datatype: f64

tool: D30: 2451545

tool: D22: 0.000387933

tool: D31: 36525

tool: D4: 360.98564736629

tool: D0: 280.46061837

tool: D27: 38710000

assistant: ```c
double get_mean_sidereal_time(double JD) {
  double sidereal;
  double T;
  T = (JD - 2451545.0) / 36525.0;
  sidereal = 280.46061837 + (360.98564736629 * (JD - 2451545.0)) + (0.000387933 * T * T) - (T * T * T / 38710000.0);
  sidereal = range_degrees(sidereal);
  return sidereal;
}
```