ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6564333231636261,%rax
  mov    $0x36353466,%edx
  mov    %rax,-0x70(%rbp)
  mov    %rdx,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <numbersOfSubtitleInString@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D5: %d

assistant: ```c
int main(void) {
  char a[100] = "abc123def456";
  printf("%d", numbersOfSubtitleInString(a));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movabs $0x6564333231636261,%rax
  mov    $0x36353466,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rdi
  call   <numbersOfSubtitleInString@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: %d

assistant: ```c
int main(void) {
  char a[100] = "abc123def456";
  printf("%d", numbersOfSubtitleInString(a));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <numbersOfSubtitleInString@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: byte[16]
name: unpack_data
arguments: data_label: D16
datatype: string

tool: {"D1": [0x61,0x62,0x63,0x31,0x32,0x33,0x64,0x65,0x66,0x34,0x35,0x36,0x00,0x00,0x00,0x00]}

tool: D16: %d

assistant: ```c
int main(void) {
  char a[100] = "abc123def456";
  printf("%d", numbersOfSubtitleInString(a));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  movdqa D13(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x0,0x60(%rsp)
  movaps %xmm0,(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  call   <numbersOfSubtitleInString@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
data_type: byte[16]
name: disassemble_data
arguments: data_tag: D11
data_type: string

tool: {"D13": [0x61,0x62,0x63,0x31,0x32,0x33,0x64,0x65,0x66,0x34,0x35,0x36,0x00,0x00,0x00,0x00]}

tool: D11: %d

assistant: ```c
int main(void) {
  char a[100] = "abc123def456";
  printf("%d", numbersOfSubtitleInString(a));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<object_free_scenario_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x9adaf8,%eax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L0
  mov    $0x9adaf8,%eax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x9adaf8,%eax
  movq   $0x0,(%rax)
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void object_free_scenario_text() {
  if ((*((void **)(0x009ADAF8))) != NULL) {
    free((*((void **)(0x009ADAF8))));
    (*((void **)(0x009ADAF8))) = NULL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<object_free_scenario_text>:
  endbr64
  mov    0x9adaf8,%rdi
  test   %rdi,%rdi
  je     L9
  sub    $0x8,%rsp
  call   <free@plt>
  movq   $0x0,0x9adaf8
  add    $0x8,%rsp
  ret
L9:
  ret
```

assistant: ```c
void object_free_scenario_text() {
  if ((*((void **)(0x009ADAF8))) != NULL) {
    free((*((void **)(0x009ADAF8))));
    (*((void **)(0x009ADAF8))) = NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<object_free_scenario_text>:
  endbr64
  mov    0x9adaf8,%rdi
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  movq   $0x0,0x9adaf8
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void object_free_scenario_text() {
  if ((*((void **)(0x009ADAF8))) != NULL) {
    free((*((void **)(0x009ADAF8))));
    (*((void **)(0x009ADAF8))) = NULL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<object_free_scenario_text>:
  endbr64
  mov    0x9adaf8,%rdi
  test   %rdi,%rdi
  je     L0
  sub    $0x8,%rsp
  call   <free@plt>
  movq   $0x0,0x9adaf8
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void object_free_scenario_text() {
  if ((*((void **)(0x009ADAF8))) != NULL) {
    free((*((void **)(0x009ADAF8))));
    (*((void **)(0x009ADAF8))) = NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L1
  mov    $0x0,%eax
  jmp    L19
L1:
  mov    $0x1,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int filter(const struct dirent *d) {
  if (!isdigit(d->d_name[0]))
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filter>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int filter(const struct dirent *d) {
  if (!isdigit(d->d_name[0]))
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<filter>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int filter(const struct dirent *d) {
  if (!isdigit(d->d_name[0]))
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<filter>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int filter(const struct dirent *d) {
  if (!isdigit(d->d_name[0]))
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L67
L36:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L36
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L73
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x9(%rbp)
  cmpb   $0x20,-0x9(%rbp)
  je     L8
  cmpb   $0xa,-0x9(%rbp)
  jne    L34
L8:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  jmp    L86
L34:
  cmpb   $0x2f,-0x9(%rbp)
  jle    L3
  cmpb   $0x39,-0x9(%rbp)
  jg     L3
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L73
L3:
  mov    $0xffffffff,%eax
  jmp    L86
L73:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L23
  mov    $0xffffffff,%eax
L86:
  leave
  ret
```

assistant: ```c
int getval(FILE *fp, char *buffer, const int buffsize) {
  char tpp;
  int id;
  int count;
  for (id = 0; id < buffsize; id++) {
    buffer[id] = 0;
  }
  id = 0;
  count = 0;
  while (count < buffsize) {
    tpp = fgetc(fp);
    if ((tpp == ' ') || (tpp == '\n')) {
      return atoi(buffer);
    } else if (tpp >= '0' && tpp <= '9') {
      buffer[id] = tpp;
      id++;
    } else {
      return -1;
    }
    count++;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getval>:
  endbr64
  test   %edx,%edx
  jle    L54
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%rbp
  mov    %rsi,%rax
L28:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rbp,%rax
  jne    L28
L59:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    $0x20,%al
  je     L15
  cmp    $0xa,%al
  je     L15
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L19
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L59
  mov    $0xffffffff,%eax
  jmp    L27
L15:
  mov    %r13,%rdi
  call   <atoi@plt>
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L54:
  mov    $0xffffffff,%eax
  ret
L19:
  mov    $0xffffffff,%eax
  jmp    L27
```

assistant: ```c
int getval(FILE *fp, char *buffer, const int buffsize) {
  char tpp;
  int id;
  int count;
  for (id = 0; id < buffsize; id++) {
    buffer[id] = 0;
  }
  id = 0;
  count = 0;
  while (count < buffsize) {
    tpp = fgetc(fp);
    if ((tpp == ' ') || (tpp == '\n')) {
      return atoi(buffer);
    } else if (tpp >= '0' && tpp <= '9') {
      buffer[id] = tpp;
      id++;
    } else {
      return -1;
    }
    count++;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getval>:
  endbr64
  test   %edx,%edx
  jle    L50
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %edx,%r12d
  mov    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  mov    %r13,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  lea    -0x1(%r12),%eax
  lea    0x1(%r13,%rax,1),%r12
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L24
L47:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0x20,%al
  je     L30
  cmp    $0xa,%al
  je     L30
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L15
L24:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getval(FILE *fp, char *buffer, const int buffsize) {
  char tpp;
  int id;
  int count;
  for (id = 0; id < buffsize; id++) {
    buffer[id] = 0;
  }
  id = 0;
  count = 0;
  while (count < buffsize) {
    tpp = fgetc(fp);
    if ((tpp == ' ') || (tpp == '\n')) {
      return atoi(buffer);
    } else if (tpp >= '0' && tpp <= '9') {
      buffer[id] = tpp;
      id++;
    } else {
      return -1;
    }
    count++;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getval>:
  endbr64
  test   %edx,%edx
  jle    L27
  push   %r13
  mov    %rsi,%r13
  xor    %esi,%esi
  push   %r12
  mov    %edx,%r12d
  mov    %edx,%edx
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  mov    %r13,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  lea    -0x1(%r12),%eax
  lea    0x1(%r13,%rax,1),%r12
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L31
L19:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0x20,%al
  je     L22
  cmp    $0xa,%al
  je     L22
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L50
L31:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <atoi@plt>
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int getval(FILE *fp, char *buffer, const int buffsize) {
  char tpp;
  int id;
  int count;
  for (id = 0; id < buffsize; id++) {
    buffer[id] = 0;
  }
  id = 0;
  count = 0;
  while (count < buffsize) {
    tpp = fgetc(fp);
    if ((tpp == ' ') || (tpp == '\n')) {
      return atoi(buffer);
    } else if (tpp >= '0' && tpp <= '9') {
      buffer[id] = tpp;
      id++;
    } else {
      return -1;
    }
    count++;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<serial_putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,%edx
  mov    %ax,-0x4(%rbp)
  mov    %edx,%eax
  mov    %al,-0x8(%rbp)
  movsbl -0x8(%rbp),%edx
  movswl -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <outb@plt>
  nop
  leave
  ret
```

assistant: ```c
void serial_putc(short combase, char c) {
  outb(combase, c);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<serial_putc>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  movswl %di,%edi
  call   <outb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void serial_putc(short combase, char c) {
  outb(combase, c);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<serial_putc>:
  endbr64
  movsbl %sil,%esi
  movswl %di,%edi
  jmp    1050 <outb@plt>
```

assistant: ```c
void serial_putc(short combase, char c) {
  outb(combase, c);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<serial_putc>:
  endbr64
  movsbl %sil,%esi
  movswl %di,%edi
  jmp    1050 <outb@plt>
```

assistant: ```c
void serial_putc(short combase, char c) {
  outb(combase, c);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<remove_iacs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L46
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    D3(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L27
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L46
L27:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L0
  addq   $0x3,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L15
  jmp    L54
L0:
  nop
L54:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  cltq
  neg    %rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  leave
  ret
```

assistant: ```c
char *remove_iacs(unsigned char *bf, int len, int *processed, int *num_totty) {
  unsigned char *ptr = bf;
  unsigned char *totty = bf;
  unsigned char *end = bf + len;
  while (ptr < end) {
    if (*ptr != IAC) {
      *totty++ = *ptr++;
    } else {
      if ((ptr + 2) < end) {
        ;
        ptr += 3;
      } else {
        break;
      }
    }
  }
  *processed = ptr - bf;
  *num_totty = totty - bf;
  return memmove(ptr - *num_totty, bf, *num_totty);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<remove_iacs>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%r10
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L33
  mov    %rdi,%r8
  mov    D9(%rip),%r9
  jmp    L17
L1:
  add    $0x1,%rdi
  mov    %al,(%r8)
  lea    0x1(%r8),%r8
L43:
  cmp    %rsi,%rdi
  jae    L23
L17:
  movzbl (%rdi),%eax
  cmp    (%r9),%al
  jne    L1
  lea    0x2(%rdi),%rax
  cmp    %rax,%rsi
  jbe    L23
  add    $0x3,%rdi
  jmp    L43
L33:
  mov    %rdi,%r8
L23:
  mov    %rdi,%rax
  sub    %r10,%rax
  mov    %eax,(%rdx)
  sub    %r10,%r8
  mov    %r8d,%edx
  mov    %r8d,(%rcx)
  movslq %r8d,%r8
  sub    %r8,%rdi
  mov    %r10,%rsi
  call   <memmove@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *remove_iacs(unsigned char *bf, int len, int *processed, int *num_totty) {
  unsigned char *ptr = bf;
  unsigned char *totty = bf;
  unsigned char *end = bf + len;
  while (ptr < end) {
    if (*ptr != IAC) {
      *totty++ = *ptr++;
    } else {
      if ((ptr + 2) < end) {
        ;
        ptr += 3;
      } else {
        break;
      }
    }
  }
  *processed = ptr - bf;
  *num_totty = totty - bf;
  return memmove(ptr - *num_totty, bf, *num_totty);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<remove_iacs>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,%r8
  mov    %rdx,%r9
  mov    %rcx,%r10
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L19
  mov    D8(%rip),%rcx
  mov    %rdi,%rdx
  jmp    L60
  nopl   0x0(%rax)
L65:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %rsi,%rdi
  jae    L59
L60:
  movzbl (%rdi),%eax
  cmp    (%rcx),%al
  jne    L65
  lea    0x2(%rdi),%rax
  cmp    %rax,%rsi
  jbe    L59
  add    $0x3,%rdi
  cmp    %rsi,%rdi
  jb     L60
L59:
  sub    %r8,%rdx
  mov    %edi,%eax
  mov    %edx,%r11d
  movslq %edx,%rdx
  sub    %r8d,%eax
  sub    %rdx,%rdi
L0:
  mov    %eax,(%r9)
  mov    %r11d,%edx
  mov    %r8,%rsi
  mov    %r11d,(%r10)
  jmp    1050 <memmove@plt>
L19:
  xor    %r11d,%r11d
  xor    %eax,%eax
  jmp    L0
```

assistant: ```c
char *remove_iacs(unsigned char *bf, int len, int *processed, int *num_totty) {
  unsigned char *ptr = bf;
  unsigned char *totty = bf;
  unsigned char *end = bf + len;
  while (ptr < end) {
    if (*ptr != IAC) {
      *totty++ = *ptr++;
    } else {
      if ((ptr + 2) < end) {
        ;
        ptr += 3;
      } else {
        break;
      }
    }
  }
  *processed = ptr - bf;
  *num_totty = totty - bf;
  return memmove(ptr - *num_totty, bf, *num_totty);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<remove_iacs>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,%r8
  mov    %rdx,%r9
  mov    %rcx,%r10
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L23
  mov    D7(%rip),%rcx
  mov    %rdi,%rdx
  jmp    L50
  nopl   0x0(%rax)
L31:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmp    %rsi,%rdi
  jae    L28
L50:
  movzbl (%rdi),%eax
  cmp    (%rcx),%al
  jne    L31
  lea    0x2(%rdi),%rax
  cmp    %rax,%rsi
  jbe    L28
  add    $0x3,%rdi
  cmp    %rsi,%rdi
  jb     L50
L28:
  sub    %r8,%rdx
  mov    %edi,%eax
  mov    %edx,%r11d
  movslq %edx,%rdx
  sub    %r8d,%eax
  sub    %rdx,%rdi
L42:
  mov    %eax,(%r9)
  mov    %r11d,%edx
  mov    %r8,%rsi
  mov    %r11d,(%r10)
  jmp    1050 <memmove@plt>
L23:
  xor    %r11d,%r11d
  xor    %eax,%eax
  jmp    L42
```

assistant: ```c
char *remove_iacs(unsigned char *bf, int len, int *processed, int *num_totty) {
  unsigned char *ptr = bf;
  unsigned char *totty = bf;
  unsigned char *end = bf + len;
  while (ptr < end) {
    if (*ptr != IAC) {
      *totty++ = *ptr++;
    } else {
      if ((ptr + 2) < end) {
        ;
        ptr += 3;
      } else {
        break;
      }
    }
  }
  *processed = ptr - bf;
  *num_totty = totty - bf;
  return memmove(ptr - *num_totty, bf, *num_totty);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D17(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x237,-0x4(%rbp)
  movb   $0x41,-0x9(%rbp)
  mov    $0x1,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D17
datatype: f32
name: retrieve_data
arguments: tag: D18
datatype: string

tool: D17: 1

tool: D18: %d


assistant: ```c
main() {
  float f = 1.0;
  int i = 567;
  char c = 'A';
  void *p;
  printf("%d\n", sizeof(*p));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: %d


assistant: ```c
main() {
  float f = 1.0;
  int i = 567;
  char c = 'A';
  void *p;
  printf("%d\n", sizeof(*p));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string

tool: D9: %d


assistant: ```c
main() {
  float f = 1.0;
  int i = 567;
  char c = 'A';
  void *p;
  printf("%d\n", sizeof(*p));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5: %d


assistant: ```c
main() {
  float f = 1.0;
  int i = 567;
  char c = 'A';
  void *p;
  printf("%d\n", sizeof(*p));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply147>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L36
L29:
  movl   $0x0,-0x3c(%rbp)
  jmp    L5
L21:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L5:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L21
  addl   $0x1,-0x40(%rbp)
L36:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L29
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply147(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```