ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<prost>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L26
L23:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L11
  mov    $0x0,%eax
  jmp    L13
L11:
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L23
  mov    $0x1,%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int prost(int n) {
  int i;
  for (i = 2; i * i <= n; ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prost>:
  endbr64
  cmp    $0x3,%edi
  jle    L48
  test   $0x1,%dil
  je     L4
  mov    $0x2,%ecx
L9:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L37
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L9
L20:
  ret
L37:
  mov    $0x1,%eax
  ret
L48:
  mov    $0x1,%eax
  ret
L4:
  mov    $0x0,%eax
  jmp    L20
```

assistant: ```c
int prost(int n) {
  int i;
  for (i = 2; i * i <= n; ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prost>:
  endbr64
  cmp    $0x3,%edi
  jle    L38
  test   $0x1,%dil
  je     L5
  mov    $0x2,%ecx
  jmp    L54
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L31
L54:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L59
L38:
  mov    $0x1,%edx
L31:
  mov    %edx,%eax
  ret
L5:
  xor    %edx,%edx
  jmp    L31
```

assistant: ```c
int prost(int n) {
  int i;
  for (i = 2; i * i <= n; ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prost>:
  endbr64
  cmp    $0x3,%edi
  jle    L59
  test   $0x1,%dil
  je     L42
  mov    $0x2,%ecx
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L21
L38:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jle    L28
L59:
  mov    $0x1,%edx
L21:
  mov    %edx,%eax
  ret
L42:
  xor    %edx,%edx
  jmp    L21
```

assistant: ```c
int prost(int n) {
  int i;
  for (i = 2; i * i <= n; ++i) {
    if (n % i == 0) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xac(%rbp)
  movl   $0x3,-0xa8(%rbp)
  movl   $0x5,-0xa4(%rbp)
  movl   $0x3,-0xb8(%rbp)
  movl   $0x24,-0xb4(%rbp)
  movl   $0x0,-0xbc(%rbp)
  jmp    L0
L18:
  mov    -0xbc(%rbp),%eax
  cltq
  movl   $0xffffffff,-0xa0(%rbp,%rax,4)
  addl   $0x1,-0xbc(%rbp)
L0:
  mov    -0xbc(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L18
  movl   $0x6,-0xb0(%rbp)
  mov    -0xb0(%rbp),%edi
  mov    -0xb8(%rbp),%ecx
  lea    -0xac(%rbp),%rdx
  mov    -0xb4(%rbp),%esi
  lea    -0xa0(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <sum_solve@plt>
  mov    %eax,%edx
  mov    -0xb0(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xb0(%rbp),%edx
  mov    -0xb8(%rbp),%ecx
  lea    -0xac(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sum_sovle_result_space@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: %d:%d


assistant: ```c
int test() {
  int set[] = {1, 3, 5};
  int num = 3;
  int dp[36];
  int size = 36;
  for (int i = 0; i < size; i++)
    dp[i] = -1;
  int n = 6;
  printf("%d:%d\n", n, sum_solve(dp, size, set, num, n));
  sum_sovle_result_space(set, num, n);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  lea    0x10(%rsp),%rax
  lea    0xa0(%rsp),%rdx
L0:
  movl   $0xffffffff,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L0
  lea    0x4(%rsp),%rbx
  lea    0x10(%rsp),%rdi
  mov    $0x6,%r8d
  mov    $0x3,%ecx
  mov    %rbx,%rdx
  mov    $0x24,%esi
  call   <sum_solve@plt>
  mov    %eax,%edx
  mov    $0x6,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x6,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <sum_sovle_result_space@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0xb0,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: %d:%d


assistant: ```c
int test() {
  int set[] = {1, 3, 5};
  int num = 3;
  int dp[36];
  int size = 36;
  for (int i = 0; i < size; i++)
    dp[i] = -1;
  int n = 6;
  printf("%d:%d\n", n, sum_solve(dp, size, set, num, n));
  sum_sovle_result_space(set, num, n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %rbp
  pcmpeqd %xmm0,%xmm0
  mov    $0x6,%r8d
  mov    $0x3,%ecx
  mov    $0x24,%esi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  movabs $0x300000001,%rax
  lea    0x4(%rsp),%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  mov    %rbp,%rdx
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  mov    %rax,0x4(%rsp)
  movl   $0x5,0xc(%rsp)
  call   <sum_solve@plt>
  mov    $0x6,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x6,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <sum_sovle_result_space@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: %d:%d


assistant: ```c
int test() {
  int set[] = {1, 3, 5};
  int num = 3;
  int dp[36];
  int size = 36;
  for (int i = 0; i < size; i++)
    dp[i] = -1;
  int n = 6;
  printf("%d:%d\n", n, sum_solve(dp, size, set, num, n));
  sum_sovle_result_space(set, num, n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  push   %rbp
  pcmpeqd %xmm0,%xmm0
  mov    $0x6,%r8d
  mov    $0x3,%ecx
  mov    $0x24,%esi
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  mov    D13(%rip),%rax
  mov    %rbp,%rdx
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  mov    %rax,(%rsp)
  movl   $0x5,0x8(%rsp)
  call   <sum_solve@plt>
  mov    $0x6,%esi
  lea    D11(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0x6,%edx
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <sum_sovle_result_space@plt>
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xb0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: byte[8]
name: unpack_data
arguments: label: D11
type_infered: string

tool: {"D13": [0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: D11: %d:%d


assistant: ```c
int test() {
  int set[] = {1, 3, 5};
  int num = 3;
  int dp[36];
  int size = 36;
  for (int i = 0; i < size; i++)
    dp[i] = -1;
  int n = 6;
  printf("%d:%d\n", n, sum_solve(dp, size, set, num, n));
  sum_sovle_result_space(set, num, n);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: Hello, World!c


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello, World!\c\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: Hello, World!c


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello, World!\c\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: Hello, World!c


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello, World!\c\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: Hello, World!c


assistant: ```c
int main(int argc, char const *argv[]) {
  printf("Hello, World!\c\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<triangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D22
data_type: string
name: parse_data
arguments: tag: D6
data_type: string
name: parse_data
arguments: tag: D29
data_type: string
name: parse_data
arguments: tag: D13
data_type: string

tool: D22: 
    /\     

tool: D6: 
   /  \    

tool: D29: 
  /    \     

tool: D13: 
 /      \    

assistant: ```c
void triangle() {
  printf("\n    /\\     ");
  printf("\n   /  \\    ");
  printf("\n  /    \\     ");
  printf("\n /      \\    ");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<triangle>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D16
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string

tool: D23: 
    /\     

tool: D2: 
   /  \    

tool: D16: 
  /    \     

tool: D0: 
 /      \    

assistant: ```c
void triangle() {
  printf("\n    /\\     ");
  printf("\n   /  \\    ");
  printf("\n  /    \\     ");
  printf("\n /      \\    ");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<triangle>:
  endbr64
  sub    $0x8,%rsp
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D33
type_guessed: string

tool: D31: 
    /\     

tool: D2: 
   /  \    

tool: D6: 
  /    \     

tool: D33: 
 /      \    

assistant: ```c
void triangle() {
  printf("\n    /\\     ");
  printf("\n   /  \\    ");
  printf("\n  /    \\     ");
  printf("\n /      \\    ");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<triangle>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D19
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D36
datatype: string

tool: D19: 
    /\     

tool: D14: 
   /  \    

tool: D7: 
  /    \     

tool: D36: 
 /      \    

assistant: ```c
void triangle() {
  printf("\n    /\\     ");
  printf("\n   /  \\    ");
  printf("\n  /    \\     ");
  printf("\n /      \\    ");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_in_hex_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
data_type: string

tool: D7: %x 

assistant: ```c
void print_in_hex_len(unsigned char *t, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%x ", t[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_in_hex_len>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D1(%rip),%rbp
L4:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: %x 

assistant: ```c
void print_in_hex_len(unsigned char *t, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%x ", t[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_in_hex_len>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L17:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: %x 

assistant: ```c
void print_in_hex_len(unsigned char *t, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%x ", t[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_in_hex_len>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x1(%rdi,%rax,1),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L6:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L3:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: %x 

assistant: ```c
void print_in_hex_len(unsigned char *t, int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    printf("%x ", t[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<process_raw_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L69
L28:
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  not    %eax
  shr    $0x7,%al
  mov    %al,-0x11(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cbtw
  and    $0x7f,%eax
  mov    %ax,-0x10(%rbp)
  cmpw   $0x0,-0x10(%rbp)
  jne    L61
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x2c(%rbp)
  jbe    L77
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x7,%eax
  and    $0x3f80,%ax
  mov    %ax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x7f,%eax
  or     %ax,-0x10(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L17
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L17
L61:
  movsbl -0x11(%rbp),%edx
  movswl -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <keycode_to_keysym@plt>
  mov    %ax,-0xe(%rbp)
  movsbl -0x11(%rbp),%edx
  movzwl -0xe(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <keysym_to_term_string@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <put_im_text@plt>
  jmp    L60
L17:
  nop
L60:
  addl   $0x1,-0xc(%rbp)
L69:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jb     L28
  jmp    L74
L77:
  nop
L74:
  nop
  leave
  ret
```

assistant: ```c
void process_raw_key(char *buf, unsigned len) {
  unsigned i;
  for (i = 0; i < len; i++) {
    char down = !(buf[i] & 0x80);
    short code = buf[i] & 0x7f;
    if (!code) {
      if (i + 2 >= len)
        break;
      code = (buf[++i] & 0x7f) << 7;
      code |= buf[++i] & 0x7f;
      if (!(buf[i] & 0x80) || !(buf[i - 1] & 0x80))
        continue;
    }
    unsigned short keysym = keycode_to_keysym(code, down);
    char *str = keysym_to_term_string(keysym, down);
    put_im_text(str, strlen(str));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<process_raw_key>:
  endbr64
  test   %esi,%esi
  je     L40
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    $0x0,%ebp
  jmp    L5
L64:
  movsbl %al,%ebx
  not    %ebx
  shr    $0x1f,%ebx
  movswl %di,%edi
  mov    %ebx,%esi
  call   <keycode_to_keysym@plt>
  movzwl %ax,%edi
  mov    %ebx,%esi
  call   <keysym_to_term_string@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <put_im_text@plt>
  mov    %ebp,%edx
L2:
  lea    0x1(%rdx),%ebp
  cmp    %ebp,%r13d
  jbe    L65
L5:
  mov    %ebp,%eax
  movzbl (%r12,%rax,1),%eax
  mov    %eax,%edi
  and    $0x7f,%di
  jne    L64
  lea    0x2(%rbp),%edx
  cmp    %r13d,%edx
  jae    L65
  lea    0x1(%rbp),%ecx
  movzbl (%r12,%rcx,1),%ecx
  mov    %edx,%esi
  movzbl (%r12,%rsi,1),%edi
  test   %dil,%cl
  jns    L2
  shl    $0x7,%ecx
  and    $0x3f80,%cx
  and    $0x7f,%edi
  or     %ecx,%edi
  mov    %edx,%ebp
  jmp    L64
L65:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  ret
```

assistant: ```c
void process_raw_key(char *buf, unsigned len) {
  unsigned i;
  for (i = 0; i < len; i++) {
    char down = !(buf[i] & 0x80);
    short code = buf[i] & 0x7f;
    if (!code) {
      if (i + 2 >= len)
        break;
      code = (buf[++i] & 0x7f) << 7;
      code |= buf[++i] & 0x7f;
      if (!(buf[i] & 0x80) || !(buf[i - 1] & 0x80))
        continue;
    }
    unsigned short keysym = keycode_to_keysym(code, down);
    char *str = keysym_to_term_string(keysym, down);
    put_im_text(str, strlen(str));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<process_raw_key>:
  endbr64
  test   %esi,%esi
  je     L77
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L8
L52:
  lea    0x2(%rax),%r13d
  cmp    %r12d,%r13d
  jae    L74
  add    $0x1,%eax
  mov    %r13d,%edx
  movzbl (%rbx,%rax,1),%eax
  movzbl (%rbx,%rdx,1),%edi
  test   %dil,%al
  js     L53
  lea    0x1(%r13),%eax
  cmp    %eax,%r12d
  jbe    L74
L8:
  mov    %eax,%edx
  mov    %eax,%r13d
  movzbl (%rbx,%rdx,1),%esi
  mov    %esi,%edi
  and    $0x7f,%edi
  movsbw %dil,%di
  je     L52
L11:
  movsbl %sil,%ebp
  movswl %di,%edi
  not    %ebp
  shr    $0x1f,%ebp
  mov    %ebp,%esi
  call   <keycode_to_keysym@plt>
  mov    %ebp,%esi
  movzwl %ax,%edi
  call   <keysym_to_term_string@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <put_im_text@plt>
  lea    0x1(%r13),%eax
  cmp    %eax,%r12d
  ja     L8
L74:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  shl    $0x7,%eax
  and    $0x7f,%edi
  and    $0x3f80,%ax
  or     %eax,%edi
  jmp    L11
L77:
  ret
```

assistant: ```c
void process_raw_key(char *buf, unsigned len) {
  unsigned i;
  for (i = 0; i < len; i++) {
    char down = !(buf[i] & 0x80);
    short code = buf[i] & 0x7f;
    if (!code) {
      if (i + 2 >= len)
        break;
      code = (buf[++i] & 0x7f) << 7;
      code |= buf[++i] & 0x7f;
      if (!(buf[i] & 0x80) || !(buf[i - 1] & 0x80))
        continue;
    }
    unsigned short keysym = keycode_to_keysym(code, down);
    char *str = keysym_to_term_string(keysym, down);
    put_im_text(str, strlen(str));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<process_raw_key>:
  endbr64
  test   %esi,%esi
  je     L42
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L30
L65:
  lea    0x2(%rax),%r13d
  cmp    %r12d,%r13d
  jae    L66
  add    $0x1,%eax
  mov    %r13d,%edx
  movzbl (%rbx,%rax,1),%eax
  movzbl (%rbx,%rdx,1),%edi
  test   %dil,%al
  js     L43
  lea    0x1(%r13),%eax
  cmp    %eax,%r12d
  jbe    L66
L30:
  mov    %eax,%edx
  mov    %eax,%r13d
  movzbl (%rbx,%rdx,1),%esi
  mov    %esi,%edi
  and    $0x7f,%edi
  movsbw %dil,%di
  je     L65
L24:
  movsbl %sil,%ebp
  movswl %di,%edi
  not    %ebp
  shr    $0x1f,%ebp
  mov    %ebp,%esi
  call   <keycode_to_keysym@plt>
  mov    %ebp,%esi
  movzwl %ax,%edi
  call   <keysym_to_term_string@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <put_im_text@plt>
  lea    0x1(%r13),%eax
  cmp    %eax,%r12d
  ja     L30
L66:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  shl    $0x7,%eax
  and    $0x7f,%edi
  and    $0x3f80,%ax
  or     %eax,%edi
  jmp    L24
L42:
  ret
```

assistant: ```c
void process_raw_key(char *buf, unsigned len) {
  unsigned i;
  for (i = 0; i < len; i++) {
    char down = !(buf[i] & 0x80);
    short code = buf[i] & 0x7f;
    if (!code) {
      if (i + 2 >= len)
        break;
      code = (buf[++i] & 0x7f) << 7;
      code |= buf[++i] & 0x7f;
      if (!(buf[i] & 0x80) || !(buf[i - 1] & 0x80))
        continue;
    }
    unsigned short keysym = keycode_to_keysym(code, down);
    char *str = keysym_to_term_string(keysym, down);
    put_im_text(str, strlen(str));
  }
}
```