ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<sommetab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float sommetab(float tab[], int N) {
  float somme = 0;
  int i = 0;
  while (i < N) {
    somme = ((tab[i]) + (somme));
    i++;
  };
  return (somme);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sommetab>:
  endbr64
  test   %esi,%esi
  jle    L5
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L7:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L7
  ret
L5:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float sommetab(float tab[], int N) {
  float somme = 0;
  int i = 0;
  while (i < N) {
    somme = ((tab[i]) + (somme));
    i++;
  };
  return (somme);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sommetab>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L17:
  addss  (%rdi),%xmm0
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L17
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float sommetab(float tab[], int N) {
  float somme = 0;
  int i = 0;
  while (i < N) {
    somme = ((tab[i]) + (somme));
    i++;
  };
  return (somme);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sommetab>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L11
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L25:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L25
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L66
L27:
  movslq %eax,%rdx
  addss  (%rdi,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L59
  add    $0x2,%eax
  addss  0x4(%rdi,%rcx,1),%xmm0
  cmp    %eax,%esi
  jle    L59
  addss  0x8(%rdi,%rcx,1),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  pxor   %xmm0,%xmm0
L59:
  ret
  nopl   (%rax)
L66:
  ret
L11:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L27
```

assistant: ```c
float sommetab(float tab[], int N) {
  float somme = 0;
  int i = 0;
  while (i < N) {
    somme = ((tab[i]) + (somme));
    i++;
  };
  return (somme);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_invalid_clause>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L19:
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xf,-0x4(%rbp)
  jle    L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp target teams distribute simd foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_invalid_clause>:
  endbr64
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp target teams distribute simd foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_invalid_clause>:
  endbr64
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp target teams distribute simd foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_invalid_clause>:
  endbr64
  ret
```

assistant: ```c
void test_invalid_clause() {
  int i;
#pragma omp target teams distribute simd foo bar
  for (i = 0; i < 16; ++i)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<freqwavn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  movsd  %xmm0,-0x28(%rbp)
  mov    %edi,-0x2c(%rbp)
  mov    %esi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x40(%rbp),%rbx
  mov    -0x48(%rbp),%r12
  mov    -0x50(%rbp),%r14
  mov    $0x0,%r13d
  jmp    L8
L17:
  movsd  (%rbx),%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r12)
  mov    %r14,%rax
  lea    0x4(%rax),%r14
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rbx
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%r12
  add    $0x1,%r13d
L8:
  cmp    -0x2c(%rbp),%r13d
  jl     L17
  mov    $0x0,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type: f64

tool: D8: 299792458

assistant: ```c
int freqwavn(dummy, nfreq, sfreq, swavn, freq, wavn, stat)
double dummy;
int nfreq, sfreq, swavn;
const double freq[];
double wavn[];
int stat[];
{
  register int ifreq, *statp;
  register const double *freqp;
  register double *wavnp;
  freqp = freq;
  wavnp = wavn;
  statp = stat;
  for (ifreq = 0; ifreq < nfreq; ifreq++) {
    *wavnp = (*freqp) / 2.99792458e8;
    *(statp++) = 0;
    freqp += sfreq;
    wavnp += swavn;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<freqwavn>:
  endbr64
  mov    %rcx,%rax
  test   %edi,%edi
  jle    L10
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%rcx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  mov    %edi,%edi
  lea    (%r9,%rdi,4),%rsi
  movsd  D0(%rip),%xmm1
L12:
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8)
  add    $0x4,%r9
  movl   $0x0,-0x4(%r9)
  add    %rcx,%rax
  add    %rdx,%r8
  cmp    %rsi,%r9
  jne    L12
L10:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: f64

tool: D0: 299792458

assistant: ```c
int freqwavn(dummy, nfreq, sfreq, swavn, freq, wavn, stat)
double dummy;
int nfreq, sfreq, swavn;
const double freq[];
double wavn[];
int stat[];
{
  register int ifreq, *statp;
  register const double *freqp;
  register double *wavnp;
  freqp = freq;
  wavnp = wavn;
  statp = stat;
  for (ifreq = 0; ifreq < nfreq; ifreq++) {
    *wavnp = (*freqp) / 2.99792458e8;
    *(statp++) = 0;
    freqp += sfreq;
    wavnp += swavn;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<freqwavn>:
  endbr64
  mov    %rcx,%rax
  test   %edi,%edi
  jle    L18
  movslq %esi,%rsi
  movslq %edx,%rdx
  movslq %edi,%rdi
  movsd  D9(%rip),%xmm1
  lea    0x0(,%rsi,8),%rcx
  shl    $0x3,%rdx
  lea    (%r9,%rdi,4),%rsi
  nopl   0x0(%rax)
L1:
  movsd  (%rax),%xmm0
  add    $0x4,%r9
  add    %rcx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8)
  add    %rdx,%r8
  movl   $0x0,-0x4(%r9)
  cmp    %rsi,%r9
  jne    L1
L18:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: f64

tool: D9: 299792458

assistant: ```c
int freqwavn(dummy, nfreq, sfreq, swavn, freq, wavn, stat)
double dummy;
int nfreq, sfreq, swavn;
const double freq[];
double wavn[];
int stat[];
{
  register int ifreq, *statp;
  register const double *freqp;
  register double *wavnp;
  freqp = freq;
  wavnp = wavn;
  statp = stat;
  for (ifreq = 0; ifreq < nfreq; ifreq++) {
    *wavnp = (*freqp) / 2.99792458e8;
    *(statp++) = 0;
    freqp += sfreq;
    wavnp += swavn;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<func_complete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func_complete(double input) {
  (void)input;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<func_complete>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int func_complete(double input) {
  (void)input;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<func_complete>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int func_complete(double input) {
  (void)input;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L18:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  imul   $0x32,%eax,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L18
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int delay(int m) {
  int i;
  for (i = 0; i < m * 50; i++) {
    i++;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<delay>:
  endbr64
  imul   $0x32,%edi,%eax
  test   %eax,%eax
  jle    L12
  mov    $0x0,%edx
L8:
  add    $0x2,%edx
  cmp    %eax,%edx
  jl     L8
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int delay(int m) {
  int i;
  for (i = 0; i < m * 50; i++) {
    i++;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay>:
  endbr64
  imul   $0x32,%edi,%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  ret
```

assistant: ```c
int delay(int m) {
  int i;
  for (i = 0; i < m * 50; i++) {
    i++;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<delay>:
  endbr64
  imul   $0x32,%edi,%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovle %edx,%eax
  ret
```

assistant: ```c
int delay(int m) {
  int i;
  for (i = 0; i < m * 50; i++) {
    i++;
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  jmp    L36
L15:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L54
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
  jmp    L1
L54:
  mov    -0xc(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L1
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L1:
  addl   $0x1,-0xc(%rbp)
L36:
  cmpl   $0x3b9ac9ff,-0xc(%rbp)
  jle    L15
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <difftime@plt>
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D8
type_infered: string

tool: D6: With conditional branches: %f


tool: D8: %d


assistant: ```c
int sum2(int start_n, int start_sum) {
  int sum = start_sum;
  int n = start_n;
  time_t start;
  time_t end;
  time(&start);
  while (n < 1000000000) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  time(&end);
  printf("With conditional branches: %f\n", difftime(end, start));
  printf("%d\n", sum);
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sum2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  cmp    $0x3b9ac9ff,%ebx
  jle    L4
L32:
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <difftime@plt>
  cvttsd2si %xmm0,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  lea    0x0(%rbp,%rbx,1),%eax
  cmp    %edx,%ebx
  cmove  %eax,%ebp
L28:
  add    $0x1,%ebx
  cmp    $0x3b9aca00,%ebx
  je     L32
L4:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L30
  add    %ebx,%ebp
  jmp    L28
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D3
type_infered: string

tool: D0: With conditional branches: %f


tool: D3: %d


assistant: ```c
int sum2(int start_n, int start_sum) {
  int sum = start_sum;
  int n = start_n;
  time_t start;
  time_t end;
  time(&start);
  while (n < 1000000000) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  time(&end);
  printf("With conditional branches: %f\n", difftime(end, start));
  printf("%d\n", sum);
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum2>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  cmp    $0x3b9ac9ff,%ebx
  jle    L11
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L17:
  add    %ebx,%r12d
  add    $0x1,%ebx
  cmp    $0x3b9aca00,%ebx
  je     L20
L11:
  imul   $0xcccccccd,%ebx,%eax
  add    $0x19999999,%eax
  cmp    $0x33333332,%eax
  jbe    L17
  imul   $0xaaaaaaab,%ebx,%eax
  lea    (%r12,%rbx,1),%edx
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555555,%eax
  cmovb  %edx,%r12d
  add    $0x1,%ebx
  cmp    $0x3b9aca00,%ebx
  jne    L11
L20:
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <difftime@plt>
  lea    D7(%rip),%rdi
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D5
type_infered: string

tool: D7: With conditional branches: %f


tool: D5: %d


assistant: ```c
int sum2(int start_n, int start_sum) {
  int sum = start_sum;
  int n = start_n;
  time_t start;
  time_t end;
  time(&start);
  while (n < 1000000000) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  time(&end);
  printf("With conditional branches: %f\n", difftime(end, start));
  printf("%d\n", sum);
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<sum2>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  cmp    $0x3b9ac9ff,%ebx
  jle    L20
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L10:
  add    %ebx,%r12d
  add    $0x1,%ebx
  cmp    $0x3b9aca00,%ebx
  je     L36
L20:
  imul   $0xcccccccd,%ebx,%eax
  add    $0x19999999,%eax
  cmp    $0x33333332,%eax
  jbe    L10
  imul   $0xaaaaaaab,%ebx,%eax
  lea    (%r12,%rbx,1),%edx
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555555,%eax
  cmovb  %edx,%r12d
  add    $0x1,%ebx
  cmp    $0x3b9aca00,%ebx
  jne    L20
L36:
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <difftime@plt>
  lea    D17(%rip),%rdi
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  mov    %r12d,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D12
type: string

tool: D17: With conditional branches: %f


tool: D12: %d


assistant: ```c
int sum2(int start_n, int start_sum) {
  int sum = start_sum;
  int n = start_n;
  time_t start;
  time_t end;
  time(&start);
  while (n < 1000000000) {
    if (n % 5 == 0)
      sum += n;
    else if (n % 3 == 0)
      sum += n;
    n++;
  }
  time(&end);
  printf("With conditional branches: %f\n", difftime(end, start));
  printf("%d\n", sum);
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_strfind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L35
  mov    -0x4(%rbp),%eax
  jmp    L25
L35:
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    $0xffffffff,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strfind(char *str, char c) {
  int res = 0;
  while (str[res]) {
    if (str[res] == c)
      return (res);
    res++;
  }
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strfind>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L4
  mov    $0x0,%eax
L6:
  mov    %eax,%ecx
  cmp    %dl,%sil
  je     L29
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L6
  mov    $0xffffffff,%ecx
L29:
  mov    %ecx,%eax
  ret
L4:
  mov    $0xffffffff,%ecx
  jmp    L29
```

assistant: ```c
int ft_strfind(char *str, char c) {
  int res = 0;
  while (str[res]) {
    if (str[res] == c)
      return (res);
    res++;
  }
  return (-1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strfind>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L9
  xor    %eax,%eax
  jmp    L38
  nop
L5:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L9
L38:
  mov    %eax,%r8d
  cmp    %dl,%sil
  jne    L5
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strfind(char *str, char c) {
  int res = 0;
  while (str[res]) {
    if (str[res] == c)
      return (res);
    res++;
  }
  return (-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strfind>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L35
  xor    %eax,%eax
  jmp    L8
  nop
L11:
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L35
L8:
  mov    %eax,%r8d
  cmp    %dl,%sil
  jne    L11
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_strfind(char *str, char c) {
  int res = 0;
  while (str[res]) {
    if (str[res] == c)
      return (res);
    res++;
  }
  return (-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wine_rb_remove_key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wine_rb_get@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wine_rb_remove@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void wine_rb_remove_key(struct wine_rb_tree *tree, const void *key) {
  struct wine_rb_entry *entry = wine_rb_get(tree, key);
  if (entry)
    wine_rb_remove(tree, entry);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wine_rb_remove_key>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <wine_rb_get@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <wine_rb_remove@plt>
L7:
  pop    %rbx
  ret
```

assistant: ```c
void wine_rb_remove_key(struct wine_rb_tree *tree, const void *key) {
  struct wine_rb_entry *entry = wine_rb_get(tree, key);
  if (entry)
    wine_rb_remove(tree, entry);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wine_rb_remove_key>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <wine_rb_get@plt>
  test   %rax,%rax
  je     L2
  mov    %rbp,%rdi
  mov    %rax,%rsi
  pop    %rbp
  jmp    1070 <wine_rb_remove@plt>
  xchg   %ax,%ax
L2:
  pop    %rbp
  ret
```

assistant: ```c
void wine_rb_remove_key(struct wine_rb_tree *tree, const void *key) {
  struct wine_rb_entry *entry = wine_rb_get(tree, key);
  if (entry)
    wine_rb_remove(tree, entry);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wine_rb_remove_key>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <wine_rb_get@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdi
  mov    %rax,%rsi
  pop    %rbp
  jmp    1070 <wine_rb_remove@plt>
  xchg   %ax,%ax
L7:
  pop    %rbp
  ret
```

assistant: ```c
void wine_rb_remove_key(struct wine_rb_tree *tree, const void *key) {
  struct wine_rb_entry *entry = wine_rb_get(tree, key);
  if (entry)
    wine_rb_remove(tree, entry);
}
```
user: Translate the below assembly code into C programming language:

```asm
<QRinput_mask3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L46:
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L23:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L34
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L31
L34:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  sete   %al
  xor    %esi,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
L31:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x1,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L46
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int QRinput_mask3(int width, const unsigned char *s, unsigned char *d) {
  int x, y;
  unsigned int b = 0;
  for (y = 0; y < width; y++) {
    for (x = 0; x < width; x++) {
      if (*s & 0x80) {
        *d = *s;
      } else {
        *d = *s ^ (((x + y) % 3) == 0);
      }
      b += (*d & 1);
      s++;
      d++;
    }
  }
  return b;
}
```