ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcSunApparentLong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  call   <calcSunTrueLong@plt>
  movq   %xmm0,%rbx
  movq   %rbp,%xmm0
  mulsd  D34(%rip),%xmm0
  movsd  D19(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <degToRad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  D30(%rip),%xmm0
  mulsd  D20(%rip),%xmm1
  subsd  %xmm1,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
type_infered: f64
name: extract_symbolic_data
arguments: tag: D19
type_infered: f64
name: extract_symbolic_data
arguments: tag: D30
type_infered: f64
name: extract_symbolic_data
arguments: tag: D20
type_infered: f64

tool: D34: 1934.136

tool: D19: 125.04

tool: D30: 0.00569

tool: D20: 0.00478

assistant: ```c
double calcSunApparentLong(double t) {
  double o = calcSunTrueLong(t);
  double omega = 125.04 - 1934.136 * t;
  double lambda = o - 0.00569 - 0.00478 * sin(degToRad(omega));
  return lambda;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calcSunApparentLong>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <calcSunTrueLong@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  D20(%rip),%xmm2
  movsd  %xmm0,(%rsp)
  movsd  D30(%rip),%xmm0
  subsd  %xmm2,%xmm0
  call   <degToRad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  mulsd  D2(%rip),%xmm0
  movsd  (%rsp),%xmm1
  subsd  D13(%rip),%xmm1
  add    $0x18,%rsp
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D20
type: f64
name: extract_symbolic_data
arguments: data_tag: D30
type: f64
name: extract_symbolic_data
arguments: data_tag: D2
type: f64
name: extract_symbolic_data
arguments: data_tag: D13
type: f64

tool: D20: 1934.136

tool: D30: 125.04

tool: D2: 0.00478

tool: D13: 0.00569

assistant: ```c
double calcSunApparentLong(double t) {
  double o = calcSunTrueLong(t);
  double omega = 125.04 - 1934.136 * t;
  double lambda = o - 0.00569 - 0.00478 * sin(degToRad(omega));
  return lambda;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calcSunApparentLong>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <calcSunTrueLong@plt>
  movsd  0x8(%rsp),%xmm2
  mulsd  D21(%rip),%xmm2
  movsd  %xmm0,(%rsp)
  movsd  D10(%rip),%xmm0
  subsd  %xmm2,%xmm0
  call   <degToRad@plt>
  mov    %eax,%edi
  call   <sin@plt>
  mulsd  D5(%rip),%xmm0
  movsd  (%rsp),%xmm1
  subsd  D30(%rip),%xmm1
  add    $0x18,%rsp
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D21
type: f64
name: parse_data
arguments: label: D10
type: f64
name: parse_data
arguments: label: D5
type: f64
name: parse_data
arguments: label: D30
type: f64

tool: D21: 1934.136

tool: D10: 125.04

tool: D5: 0.00478

tool: D30: 0.00569

assistant: ```c
double calcSunApparentLong(double t) {
  double o = calcSunTrueLong(t);
  double omega = 125.04 - 1934.136 * t;
  double lambda = o - 0.00569 - 0.00478 * sin(degToRad(omega));
  return lambda;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_void>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L15
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  jmp    L14
L1:
  addq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
L14:
  leave
  ret
```

assistant: ```c
int is_void(char *s) {
  while (*s != '\0') {
    if (!isspace(*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_void>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L18
L5:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L8
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
  mov    $0x1,%eax
L8:
  pop    %rbx
  ret
L18:
  mov    $0x1,%eax
  jmp    L8
```

assistant: ```c
int is_void(char *s) {
  while (*s != '\0') {
    if (!isspace(*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_void>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L14
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L37:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L21
L14:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L37
  pop    %rbx
  ret
L21:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_void(char *s) {
  while (*s != '\0') {
    if (!isspace(*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_void>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L33
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L27:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L39
L33:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L27
  pop    %rbx
  ret
L39:
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int is_void(char *s) {
  while (*s != '\0') {
    if (!isspace(*s))
      return 0;
    s++;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x5,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0xb,-0x20(%rbp)
  movl   $0xd,-0x1c(%rbp)
  movl   $0x11,-0x18(%rbp)
  movl   $0x1,-0x38(%rbp)
  jmp    L27
L30:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   $0x64,%eax,%ecx
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  lea    (%rcx,%rax,1),%edx
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x2(%rax),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%ecx
  mov    -0x34(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L24
  mov    $0x0,%eax
  jmp    L6
L24:
  addl   $0x1,-0x38(%rbp)
L27:
  cmpl   $0x7,-0x38(%rbp)
  jle    L30
  mov    $0x1,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
bool check(char *a) {
  int i;
  int divisors[] = {2, 3, 5, 7, 11, 13, 17};
  for (i = 1; i < 8; i++) {
    int n = a[i] * 100 + a[i + 1] * 10 + a[i + 2];
    if (n % divisors[i - 1] != 0) {
      return false;
    }
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  movl   $0x5,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0xb,0x10(%rsp)
  movl   $0xd,0x14(%rsp)
  movl   $0x11,0x18(%rsp)
  add    $0x1,%rdi
  mov    %rsp,%rcx
  lea    0x1c(%rsp),%rsi
L20:
  movsbl (%rdi),%eax
  imul   $0x64,%eax,%eax
  movsbl 0x1(%rdi),%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%eax
  movsbl 0x2(%rdi),%edx
  add    %edx,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  jne    L35
  add    $0x1,%rdi
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L20
  mov    $0x1,%eax
L0:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x38,%rsp
  ret
L35:
  mov    $0x0,%eax
  jmp    L0
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool check(char *a) {
  int i;
  int divisors[] = {2, 3, 5, 7, 11, 13, 17};
  for (i = 1; i < 8; i++) {
    int n = a[i] * 100 + a[i + 1] * 10 + a[i + 2];
    if (n % divisors[i - 1] != 0) {
      return false;
    }
  }
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check>:
  endbr64
  sub    $0x38,%rsp
  add    $0x1,%rdi
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x300000002,%rax
  lea    0x4(%rsp),%rcx
  lea    0x1c(%rsp),%r8
  movl   $0x11,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x700000005,%rax
  mov    %rax,0x8(%rsp)
  movabs $0xd0000000b,%rax
  mov    %rax,0x10(%rsp)
  jmp    L27
  nop
L7:
  mov    (%rcx),%esi
  add    $0x4,%rcx
L27:
  movsbl (%rdi),%eax
  movsbl 0x1(%rdi),%edx
  imul   $0x64,%eax,%eax
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%eax
  movsbl 0x2(%rdi),%edx
  add    %edx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L48
  add    $0x1,%rdi
  cmp    %rcx,%r8
  jne    L7
  mov    $0x1,%eax
L18:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x38,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  xor    %eax,%eax
  jmp    L18
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool check(char *a) {
  int i;
  int divisors[] = {2, 3, 5, 7, 11, 13, 17};
  for (i = 1; i < 8; i++) {
    int n = a[i] * 100 + a[i + 1] * 10 + a[i + 2];
    if (n % divisors[i - 1] != 0) {
      return false;
    }
  }
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check>:
  endbr64
  movsbl 0x3(%rdi),%esi
  movsbl 0x2(%rdi),%eax
  mov    %rdi,%rdx
  test   $0x1,%sil
  jne    L45
  imul   $0x64,%eax,%eax
  movsbl 0x4(%rdi),%r8d
  lea    (%rsi,%rsi,4),%ecx
  lea    (%rax,%rcx,2),%ecx
  add    %r8d,%ecx
  movslq %ecx,%rax
  mov    %ecx,%edi
  imul   $0x55555556,%rax,%rax
  sar    $0x1f,%edi
  shr    $0x20,%rax
  sub    %edi,%eax
  lea    (%rax,%rax,2),%edi
  mov    %ecx,%eax
  sub    %edi,%eax
  jne    L45
  imul   $0x64,%esi,%esi
  lea    (%r8,%r8,4),%ecx
  movsbl 0x5(%rdx),%edi
  lea    (%rsi,%rcx,2),%esi
  add    %edi,%esi
  movslq %esi,%rcx
  mov    %esi,%r9d
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%r9d
  sar    $0x21,%rcx
  sub    %r9d,%ecx
  lea    (%rcx,%rcx,4),%ecx
  cmp    %ecx,%esi
  jne    L49
  imul   $0x64,%r8d,%r8d
  lea    (%rdi,%rdi,4),%eax
  movsbl 0x6(%rdx),%esi
  lea    (%r8,%rax,2),%ecx
  add    %esi,%ecx
  movslq %ecx,%rax
  mov    %ecx,%r8d
  imul   $0xffffffff92492493,%rax,%rax
  sar    $0x1f,%r8d
  shr    $0x20,%rax
  add    %ecx,%eax
  sar    $0x2,%eax
  sub    %r8d,%eax
  lea    0x0(,%rax,8),%r8d
  sub    %eax,%r8d
  mov    %ecx,%eax
  sub    %r8d,%eax
  jne    L45
  imul   $0x64,%edi,%edi
  lea    (%rsi,%rsi,4),%ecx
  movsbl 0x7(%rdx),%r8d
  lea    (%rdi,%rcx,2),%edi
  add    %r8d,%edi
  movslq %edi,%rcx
  mov    %edi,%r9d
  imul   $0x2e8ba2e9,%rcx,%rcx
  sar    $0x1f,%r9d
  sar    $0x21,%rcx
  sub    %r9d,%ecx
  lea    (%rcx,%rcx,4),%r9d
  lea    (%rcx,%r9,2),%ecx
  cmp    %ecx,%edi
  jne    L49
  imul   $0x64,%esi,%esi
  movsbl 0x8(%rdx),%edi
  lea    (%r8,%r8,4),%ecx
  lea    (%rsi,%rcx,2),%ecx
  add    %edi,%ecx
  imul   $0xc4ec4ec5,%ecx,%ecx
  add    $0x9d89d89,%ecx
  cmp    $0x13b13b12,%ecx
  ja     L49
  imul   $0x64,%r8d,%r8d
  movsbl 0x9(%rdx),%edx
  lea    (%rdi,%rdi,4),%eax
  lea    (%r8,%rax,2),%eax
  add    %edx,%eax
  imul   $0xf0f0f0f1,%eax,%eax
  add    $0x7878787,%eax
  cmp    $0xf0f0f0e,%eax
  setbe  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
L49:
  ret
```

assistant: ```c
bool check(char *a) {
  int i;
  int divisors[] = {2, 3, 5, 7, 11, 13, 17};
  for (i = 1; i < 8; i++) {
    int n = a[i] * 100 + a[i + 1] * 10 + a[i + 2];
    if (n % divisors[i - 1] != 0) {
      return false;
    }
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<interrupcao_usr1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <carrega_config@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void interrupcao_usr1() {
  carrega_config();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interrupcao_usr1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <carrega_config@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void interrupcao_usr1() {
  carrega_config();
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<interrupcao_usr1>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <carrega_config@plt>
```

assistant: ```c
void interrupcao_usr1() {
  carrega_config();
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<interrupcao_usr1>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <carrega_config@plt>
```

assistant: ```c
void interrupcao_usr1() {
  carrega_config();
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<oneTimePadXOR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jne    L1
  mov    $0x1,%eax
  jmp    L2
L1:
  mov    $0x0,%eax
L2:
  mov    %eax,%edi
  call   <assert@plt>
  movq   $0x0,-0x38(%rbp)
  jmp    L43
L40:
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x38(%rbp)
L43:
  mov    -0x38(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  jb     L40
  mov    -0x58(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x60(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int oneTimePadXOR(FILE *argument1, FILE *argument2, FILE *output, const size_t length) {
  char *a = (char *)malloc(length);
  char *b = (char *)malloc(length);
  char *c = (char *)malloc(length);
  size_t read1 = fread(a, 1, length, argument1);
  size_t read2 = fread(b, 1, length, argument2);
  assert(read1 == length && read2 == length);
  for (size_t index = 0; index < length; index++)
    c[index] = a[index] ^ b[index];
  size_t wrote = fwrite(c, 1, length, output);
  assert(wrote == length);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<oneTimePadXOR>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rdx,0x8(%rsp)
  mov    %rcx,%rbx
  mov    %rcx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %r14,%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  mov    %rax,%r14
  mov    %r15,%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fread@plt>
  mov    %rax,%rdx
  cmp    %r14,%rbx
  sete   %al
  cmp    %rdx,%rbx
  sete   %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L1
  lea    (%rbx,%r12,1),%rsi
  mov    %r12,%rax
  mov    %r13,%rcx
  sub    %r12,%rcx
  sub    %r12,%rbp
L11:
  movzbl 0x0(%rbp,%rax,1),%edx
  xor    (%rax),%dl
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L11
L1:
  mov    0x8(%rsp),%rcx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <fwrite@plt>
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int oneTimePadXOR(FILE *argument1, FILE *argument2, FILE *output, const size_t length) {
  char *a = (char *)malloc(length);
  char *b = (char *)malloc(length);
  char *c = (char *)malloc(length);
  size_t read1 = fread(a, 1, length, argument1);
  size_t read2 = fread(b, 1, length, argument2);
  assert(read1 == length && read2 == length);
  for (size_t index = 0; index < length; index++)
    c[index] = a[index] ^ b[index];
  size_t wrote = fwrite(c, 1, length, output);
  assert(wrote == length);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<oneTimePadXOR>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  mov    %rcx,%rdi
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r15,%rcx
  mov    %rbp,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    %rax,%r13
  call   <fread@plt>
  mov    0x8(%rsp),%rcx
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    $0x1,%esi
  mov    %rax,%r15
  call   <fread@plt>
  cmp    %r15,%rbp
  mov    %rax,%r8
  sete   %al
  xor    %edi,%edi
  cmp    %r8,%rbp
  sete   %dil
  and    %eax,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  je     L5
  mov    %r13,%rsi
  mov    %r12,%rcx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %rbx,%rax
  sub    %rbx,%rsi
  sub    %rbx,%rcx
  xchg   %ax,%ax
L10:
  movzbl (%rcx,%rax,1),%edx
  xor    (%rax),%dl
  mov    %dl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L10
L5:
  mov    %r14,%rcx
  mov    %rbp,%rdx
  mov    %r13,%rdi
  mov    $0x1,%esi
  call   <fwrite@plt>
  xor    %edi,%edi
  cmp    %rax,%rbp
  sete   %dil
  call   <assert@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int oneTimePadXOR(FILE *argument1, FILE *argument2, FILE *output, const size_t length) {
  char *a = (char *)malloc(length);
  char *b = (char *)malloc(length);
  char *c = (char *)malloc(length);
  size_t read1 = fread(a, 1, length, argument1);
  size_t read2 = fread(b, 1, length, argument2);
  assert(read1 == length && read2 == length);
  for (size_t index = 0; index < length; index++)
    c[index] = a[index] ^ b[index];
  size_t wrote = fwrite(c, 1, length, output);
  assert(wrote == length);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uninitvar_wcstok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wcstok@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_wcstok(void) {
  wchar_t *s;
  const wchar_t *ct;
  wchar_t **ptr;
  (void)wcstok(s, ct, ptr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninitvar_wcstok>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <wcstok@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_wcstok(void) {
  wchar_t *s;
  const wchar_t *ct;
  wchar_t **ptr;
  (void)wcstok(s, ct, ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uninitvar_wcstok>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcstok@plt>
```

assistant: ```c
void uninitvar_wcstok(void) {
  wchar_t *s;
  const wchar_t *ct;
  wchar_t **ptr;
  (void)wcstok(s, ct, ptr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uninitvar_wcstok>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcstok@plt>
```

assistant: ```c
void uninitvar_wcstok(void) {
  wchar_t *s;
  const wchar_t *ct;
  wchar_t **ptr;
  (void)wcstok(s, ct, ptr);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<process_jiffies_to_msecs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <trace_seq_printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: D7: %lld

assistant: ```c
unsigned long long process_jiffies_to_msecs(struct trace_seq *s, unsigned long long *args) {
  unsigned long long jiffies = args[0];
  trace_seq_printf(s, "%lld", jiffies);
  return jiffies;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<process_jiffies_to_msecs>:
  endbr64
  push   %rbx
  mov    (%rsi),%rbx
  mov    %rbx,%rdx
  lea    D2(%rip),%rsi
  call   <trace_seq_printf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: %lld

assistant: ```c
unsigned long long process_jiffies_to_msecs(struct trace_seq *s, unsigned long long *args) {
  unsigned long long jiffies = args[0];
  trace_seq_printf(s, "%lld", jiffies);
  return jiffies;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<process_jiffies_to_msecs>:
  endbr64
  push   %r12
  mov    (%rsi),%r12
  lea    D2(%rip),%rsi
  mov    %r12,%rdx
  call   <trace_seq_printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: %lld

assistant: ```c
unsigned long long process_jiffies_to_msecs(struct trace_seq *s, unsigned long long *args) {
  unsigned long long jiffies = args[0];
  trace_seq_printf(s, "%lld", jiffies);
  return jiffies;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<process_jiffies_to_msecs>:
  endbr64
  push   %r12
  mov    (%rsi),%r12
  lea    D4(%rip),%rsi
  mov    %r12,%rdx
  call   <trace_seq_printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %lld

assistant: ```c
unsigned long long process_jiffies_to_msecs(struct trace_seq *s, unsigned long long *args) {
  unsigned long long jiffies = args[0];
  trace_seq_printf(s, "%lld", jiffies);
  return jiffies;
}
```