ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<__hsail_sat_mul_u32>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  mov    %rax,%r8
  mov    0x4(%rsp),%eax
  test   %r8,%r8
  je     L3
  mov    D1(%rip),%rax
  mov    (%rax),%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t __hsail_sat_mul_u32(uint32_t a, uint32_t b) {
  uint32_t c;
  if (__builtin_mul_overflow(a, b, &c))
    return UINT32_MAX;
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__hsail_sat_mul_u32>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <__builtin_mul_overflow@plt>
  mov    %rax,%r8
  mov    0x4(%rsp),%eax
  test   %r8,%r8
  je     L2
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t __hsail_sat_mul_u32(uint32_t a, uint32_t b) {
  uint32_t c;
  if (__builtin_mul_overflow(a, b, &c))
    return UINT32_MAX;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printVerticalHallway>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <move@plt>
  movl   $0x2,-0x4(%rbp)
  jmp    L12
L1:
  mov    -0x18(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    $0x23,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void printVerticalHallway(int x, int y) {
  move(y, 0);
  for (int i = 2; i < x; i++) {
    mvaddch(i, y, '#');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printVerticalHallway>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <move@plt>
  cmp    $0x2,%ebp
  jle    L3
  mov    $0x2,%ebx
L15:
  mov    $0x23,%edx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mvaddch@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L15
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printVerticalHallway(int x, int y) {
  move(y, 0);
  for (int i = 2; i < x; i++) {
    mvaddch(i, y, '#');
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<printVerticalHallway>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  call   <move@plt>
  cmp    $0x2,%ebp
  jle    L5
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L8:
  mov    %ebx,%edi
  mov    $0x23,%edx
  mov    %r12d,%esi
  add    $0x1,%ebx
  call   <mvaddch@plt>
  cmp    %ebx,%ebp
  jne    L8
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printVerticalHallway(int x, int y) {
  move(y, 0);
  for (int i = 2; i < x; i++) {
    mvaddch(i, y, '#');
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<printVerticalHallway>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12d,%edi
  push   %rbx
  call   <move@plt>
  cmp    $0x2,%ebp
  jle    L19
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L9:
  mov    %ebx,%edi
  mov    $0x23,%edx
  mov    %r12d,%esi
  add    $0x1,%ebx
  call   <mvaddch@plt>
  cmp    %ebx,%ebp
  jne    L9
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printVerticalHallway(int x, int y) {
  move(y, 0);
  for (int i = 2; i < x; i++) {
    mvaddch(i, y, '#');
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x64(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x30(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x64(%rbp),%eax
  cmp    $0x18,%eax
  jg     L38
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L26
L38:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D44
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string

tool: D44: %s

tool: D0: %d

tool: D1: feminino

tool: D31: ACEITA

tool: D9: NAO ACEITA

assistant: ```c
int main() {
  char nome[40];
  char sexo[40];
  int idade;
  scanf("%s", nome);
  scanf("%s", sexo);
  scanf("%d", &idade);
  if (strcmp(sexo, "feminino") == 0 && idade < 25)
    printf("ACEITA");
  else
    printf("NAO ACEITA");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D47(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x40(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L36
  cmpl   $0x18,0xc(%rsp)
  jle    L15
L36:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L19:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D47
type: string
name: retrieve_data
arguments: data_tag: D11
type: string
name: retrieve_data
arguments: data_tag: D13
type: string
name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D45
type: string

tool: D47: %s

tool: D11: %d

tool: D13: feminino

tool: D8: NAO ACEITA

tool: D45: ACEITA

assistant: ```c
int main() {
  char nome[40];
  char sexo[40];
  int idade;
  scanf("%s", nome);
  scanf("%s", sexo);
  scanf("%d", &idade);
  if (strcmp(sexo, "feminino") == 0 && idade < 25)
    printf("ACEITA");
  else
    printf("NAO ACEITA");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  lea    D26(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x40(%rsp),%rbp
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L29
  cmpl   $0x18,0xc(%rsp)
  jle    L30
L29:
  lea    D40(%rip),%rdi
  call   <printf@plt>
L10:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L30:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D26
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D3
datatype: string
name: retrieve_data
arguments: label: D40
datatype: string
name: retrieve_data
arguments: label: D11
datatype: string

tool: D26: %s

tool: D4: %d

tool: D3: feminino

tool: D40: NAO ACEITA

tool: D11: ACEITA

assistant: ```c
int main() {
  char nome[40];
  char sexo[40];
  int idade;
  scanf("%s", nome);
  scanf("%s", sexo);
  scanf("%d", &idade);
  if (strcmp(sexo, "feminino") == 0 && idade < 25)
    printf("ACEITA");
  else
    printf("NAO ACEITA");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D31(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x40(%rsp),%rbp
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  cmpl   $0x18,0xc(%rsp)
  jle    L1
L2:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L36:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
type: string
name: retrieve_data
arguments: data_tag: D36
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D3
type: string
name: retrieve_data
arguments: data_tag: D48
type: string

tool: D31: %s

tool: D36: %d

tool: D10: feminino

tool: D3: NAO ACEITA

tool: D48: ACEITA

assistant: ```c
int main() {
  char nome[40];
  char sexo[40];
  int idade;
  scanf("%s", nome);
  scanf("%s", sexo);
  scanf("%d", &idade);
  if (strcmp(sexo, "feminino") == 0 && idade < 25)
    printf("ACEITA");
  else
    printf("NAO ACEITA");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L16
L41:
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x50(%rbp),%rdx
  lea    -0x54(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0x54(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x4c(%rbp),%eax
  imul   %edx,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L40:
  cmp    %rdx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L40
L9:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L37
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L37:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x50(%rbp),%ecx
  mov    -0x54(%rbp),%edx
  mov    -0x4c(%rbp),%eax
  mov    -0x40(%rbp),%rsi
  mov    %eax,%edi
  call   <fill_dist@plt>
  mov    -0x4c(%rbp),%eax
  mov    -0x40(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tsp@plt>
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
L16:
  mov    -0x58(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x58(%rbp)
  test   %eax,%eax
  jne    L41
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D32
type: string
name: read_data
arguments: label: D43
type: string
name: read_data
arguments: label: D17
type: string

tool: D32: %d

tool: D43: %d %d

tool: D17: %d


assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--) {
    int x, y;
    scanf("%d %d", &x, &y);
    scanf("%d %d", &x, &y);
    int n;
    scanf("%d", &n);
    n++;
    int dist[n * n];
    fill_dist(n, dist, x, y);
    printf("%d\n", tsp(n, dist));
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x48(%rbp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x48(%rbp)
  test   %eax,%eax
  je     L41
  lea    -0x40(%rbp),%r13
  lea    D23(%rip),%r12
  lea    D0(%rip),%r15
  jmp    L68
L4:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L14
  orq    $0x0,-0x8(%rsp,%rax,1)
L14:
  mov    %rsp,%rbx
  mov    -0x40(%rbp),%ecx
  mov    -0x44(%rbp),%edx
  mov    %rbx,%rsi
  call   <fill_dist@plt>
  mov    %rbx,%rsi
  mov    -0x3c(%rbp),%edi
  call   <tsp@plt>
  mov    %eax,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    %r14,%rsp
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x48(%rbp)
  test   %eax,%eax
  je     L41
L68:
  mov    %rsp,%r14
  lea    -0x44(%rbp),%rbx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x3c(%rbp),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    %edi,-0x3c(%rbp)
  mov    %edi,%eax
  imul   %edi,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L27:
  cmp    %rdx,%rsp
  je     L4
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L41:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D36
type_guessed: string

tool: D0: %d

tool: D23: %d %d

tool: D36: %d


assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--) {
    int x, y;
    scanf("%d %d", &x, &y);
    scanf("%d %d", &x, &y);
    int n;
    scanf("%d", &n);
    n++;
    int dist[n * n];
    fill_dist(n, dist, x, y);
    printf("%d\n", tsp(n, dist));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D11(%rip),%r15
  push   %r14
  lea    -0x48(%rbp),%rsi
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x48(%rbp)
  test   %eax,%eax
  je     L54
  lea    -0x3c(%rbp),%rax
  lea    -0x40(%rbp),%r13
  mov    %rax,-0x58(%rbp)
  lea    -0x44(%rbp),%r12
  lea    D3(%rip),%rbx
L10:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <scanf@plt>
  mov    -0x58(%rbp),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  mov    %rsp,%rcx
  lea    0x1(%rax),%edi
  mov    %edi,%eax
  mov    %edi,-0x3c(%rbp)
  imul   %edi,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L20
L40:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L40
L20:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L35
  orq    $0x0,-0x8(%rsp,%rdx,1)
L35:
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%ecx
  mov    %rsp,%rsi
  mov    %rsi,-0x60(%rbp)
  call   <fill_dist@plt>
  mov    -0x60(%rbp),%rsi
  mov    -0x3c(%rbp),%edi
  call   <tsp@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    -0x48(%rbp),%eax
  mov    %r14,%rsp
  lea    -0x1(%rax),%edx
  mov    %edx,-0x48(%rbp)
  test   %eax,%eax
  jne    L10
L54:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string

tool: D11: %d

tool: D3: %d %d

tool: D15: %d


assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--) {
    int x, y;
    scanf("%d %d", &x, &y);
    scanf("%d %d", &x, &y);
    int n;
    scanf("%d", &n);
    n++;
    int dist[n * n];
    fill_dist(n, dist, x, y);
    printf("%d\n", tsp(n, dist));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  lea    D8(%rip),%r15
  push   %r14
  lea    -0x48(%rbp),%rsi
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x48(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x48(%rbp)
  test   %eax,%eax
  je     L59
  lea    -0x3c(%rbp),%rax
  lea    -0x40(%rbp),%r13
  mov    %rax,-0x58(%rbp)
  lea    -0x44(%rbp),%r12
  lea    D13(%rip),%rbx
L28:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    %rsp,%r14
  call   <scanf@plt>
  mov    -0x58(%rbp),%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  mov    %rsp,%rcx
  lea    0x1(%rax),%edi
  mov    %edi,%eax
  mov    %edi,-0x3c(%rbp)
  imul   %edi,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L1
L23:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L23
L1:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L0
  orq    $0x0,-0x8(%rsp,%rdx,1)
L0:
  mov    -0x44(%rbp),%edx
  mov    -0x40(%rbp),%ecx
  mov    %rsp,%rsi
  mov    %rsi,-0x60(%rbp)
  call   <fill_dist@plt>
  mov    -0x60(%rbp),%rsi
  mov    -0x3c(%rbp),%edi
  call   <tsp@plt>
  lea    D12(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    -0x48(%rbp),%eax
  mov    %r14,%rsp
  lea    -0x1(%rax),%edx
  mov    %edx,-0x48(%rbp)
  test   %eax,%eax
  jne    L28
L59:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D13
type_infered: string
name: read_data
arguments: tag: D12
type_infered: string

tool: D8: %d

tool: D13: %d %d

tool: D12: %d


assistant: ```c
int main() {
  int tc;
  scanf("%d", &tc);
  while (tc--) {
    int x, y;
    scanf("%d %d", &x, &y);
    scanf("%d %d", &x, &y);
    int n;
    scanf("%d", &n);
    n++;
    int dist[n * n];
    fill_dist(n, dist, x, y);
    printf("%d\n", tsp(n, dist));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L9
L12:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L9:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverse_string(char *destination, char *source) {
  char *marker = destination;
  char *ptr = source + strlen(source) - 1;
  while (ptr >= source) {
    *destination++ = *ptr--;
  }
  *destination = '\0';
  return marker;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdi
  cmp    %rdi,%rbx
  ja     L4
  lea    -0x1(%rbx),%rsi
  mov    %rdi,%rax
  mov    %rbp,%rdx
L17:
  sub    $0x1,%rax
  add    $0x1,%rdx
  movzbl 0x1(%rax),%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rax
  jne    L17
  sub    %rbx,%rdi
  lea    0x1(%rbp,%rdi,1),%rax
L13:
  movb   $0x0,(%rax)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %rbp,%rax
  jmp    L13
```

assistant: ```c
char *reverse_string(char *destination, char *source) {
  char *marker = destination;
  char *ptr = source + strlen(source) - 1;
  while (ptr >= source) {
    *destination++ = *ptr--;
  }
  *destination = '\0';
  return marker;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reverse_string>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rsi
  cmp    %rsi,%rbx
  ja     L18
  lea    -0x1(%rbx),%rdi
  mov    %rsi,%rax
  mov    %r12,%rdx
  nop
L0:
  movzbl (%rax),%ecx
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rax,%rdi
  jne    L0
  sub    %rbx,%rsi
  lea    0x1(%r12,%rsi,1),%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  mov    %r12,%rax
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *reverse_string(char *destination, char *source) {
  char *marker = destination;
  char *ptr = source + strlen(source) - 1;
  while (ptr >= source) {
    *destination++ = *ptr--;
  }
  *destination = '\0';
  return marker;
}
```