ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<license>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2: 
MetaCalc is a program to calculate common (not individual!) 
metabolites of molecules.
Its purpose is to avoid drawing every single possible structure in 2D 
drawing software to receive monoisotopic molecular masses of compounds.
This tool might be usefull for high resolution mass spectrometry and 
in particular for metabolism studies using such techniques.

Copyright (C) 2017  Sascha Manier (SaschaManier@posteo.de)

This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation version 3 of the License.

This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.

You should have received a copy of the GNU General Public License
along with this program. If not, see http://www.gnu.org/licenses/.



assistant: ```c
void license() {
  printf("\nMetaCalc is a program to calculate common (not individual!) \n"
         "metabolites of molecules.\n"
         "Its purpose is to avoid drawing every single possible structure in 2D \n"
         "drawing software to receive monoisotopic molecular masses of compounds.\n"
         "This tool might be usefull for high resolution mass spectrometry and \n"
         "in particular for metabolism studies using such techniques.\n\n"
         "Copyright (C) 2017  Sascha Manier (SaschaManier@posteo.de)\n\n"
         "This program is free software: you can redistribute it and/or modify\n"
         "it under the terms of the GNU General Public License as published by\n"
         "the Free Software Foundation version 3 of the License.\n\n"
         "This program is distributed in the hope that it will be useful,\n"
         "but WITHOUT ANY WARRANTY; without even the implied warranty of\n"
         "MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the\n"
         "GNU General Public License for more details.\n\n"
         "You should have received a copy of the GNU General Public License\n"
         "along with this program. If not, see http://www.gnu.org/licenses/.\n\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<license>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: 
MetaCalc is a program to calculate common (not individual!) 
metabolites of molecules.
Its purpose is to avoid drawing every single possible structure in 2D 
drawing software to receive monoisotopic molecular masses of compounds.
This tool might be usefull for high resolution mass spectrometry and 
in particular for metabolism studies using such techniques.

Copyright (C) 2017  Sascha Manier (SaschaManier@posteo.de)

This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation version 3 of the License.

This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.

You should have received a copy of the GNU General Public License
along with this program. If not, see http://www.gnu.org/licenses/.



assistant: ```c
void license() {
  printf("\nMetaCalc is a program to calculate common (not individual!) \n"
         "metabolites of molecules.\n"
         "Its purpose is to avoid drawing every single possible structure in 2D \n"
         "drawing software to receive monoisotopic molecular masses of compounds.\n"
         "This tool might be usefull for high resolution mass spectrometry and \n"
         "in particular for metabolism studies using such techniques.\n\n"
         "Copyright (C) 2017  Sascha Manier (SaschaManier@posteo.de)\n\n"
         "This program is free software: you can redistribute it and/or modify\n"
         "it under the terms of the GNU General Public License as published by\n"
         "the Free Software Foundation version 3 of the License.\n\n"
         "This program is distributed in the hope that it will be useful,\n"
         "but WITHOUT ANY WARRANTY; without even the implied warranty of\n"
         "MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the\n"
         "GNU General Public License for more details.\n\n"
         "You should have received a copy of the GNU General Public License\n"
         "along with this program. If not, see http://www.gnu.org/licenses/.\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L7
L37:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L64:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jne    L0
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L29
L0:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L29:
  subl   $0x1,-0x18(%rbp)
L32:
  cmpl   $0x0,-0x18(%rbp)
  jg     L64
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L7:
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string

tool: D14:  %d

tool: D38: Mary won %d times and John won %d times


assistant: ```c
int main() {
  int N, win[3] = {0, 0, 0}, i;
  scanf(" %d", &N);
  while (N != 0) {
    i = N;
    win[1] = 0;
    win[2] = 0;
    while (i > 0) {
      scanf(" %d", &win[0]);
      win[0] == 0 ? win[1]++ : win[2]++;
      i--;
    }
    printf("Mary won %d times and John won %d times\n", win[1], win[2]);
    scanf(" %d", &N);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  test   %ebx,%ebx
  je     L71
  lea    D15(%rip),%rbp
  lea    0xc(%rsp),%r12
  lea    D1(%rip),%r14
  lea    0x8(%rsp),%r13
  jmp    L46
L27:
  addl   $0x1,0x14(%rsp)
L20:
  sub    $0x1,%ebx
  je     L75
L63:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jne    L27
  addl   $0x1,0x10(%rsp)
  jmp    L20
L75:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  test   %ebx,%ebx
  je     L71
L46:
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  test   %ebx,%ebx
  jg     L63
  jmp    L75
L71:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D1
data_type: string

tool: D15:  %d

tool: D1: Mary won %d times and John won %d times


assistant: ```c
int main() {
  int N, win[3] = {0, 0, 0}, i;
  scanf(" %d", &N);
  while (N != 0) {
    i = N;
    win[1] = 0;
    win[2] = 0;
    while (i > 0) {
      scanf(" %d", &win[0]);
      win[0] == 0 ? win[1]++ : win[2]++;
      i--;
    }
    printf("Mary won %d times and John won %d times\n", win[1], win[2]);
    scanf(" %d", &N);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  test   %ebx,%ebx
  je     L82
  nopw   0x0(%rax,%rax,1)
L71:
  movq   $0x0,0x10(%rsp)
  test   %ebx,%ebx
  jle    L44
  lea    0xc(%rsp),%r12
  jmp    L60
  nopl   0x0(%rax)
L68:
  addl   $0x1,0x10(%rsp)
  sub    $0x1,%ebx
  je     L57
L60:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  je     L68
  addl   $0x1,0x14(%rsp)
  sub    $0x1,%ebx
  jne    L60
L57:
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
L32:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%ebx
  test   %ebx,%ebx
  jne    L71
L82:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L44:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L32
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D6
data_type: string

tool: D0: Mary won %d times and John won %d times


tool: D6:  %d

assistant: ```c
int main() {
  int N, win[3] = {0, 0, 0}, i;
  scanf(" %d", &N);
  while (N != 0) {
    i = N;
    win[1] = 0;
    win[2] = 0;
    while (i > 0) {
      scanf(" %d", &win[0]);
      win[0] == 0 ? win[1]++ : win[2]++;
      i--;
    }
    printf("Mary won %d times and John won %d times\n", win[1], win[2]);
    scanf(" %d", &N);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  movl   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %r13,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  je     L6
  nopw   0x0(%rax,%rax,1)
L21:
  movq   $0x0,0xc(%rsp)
  test   %ebx,%ebx
  jle    L34
  lea    0x8(%rsp),%r12
  jmp    L83
  nopl   0x0(%rax)
L24:
  addl   $0x1,0xc(%rsp)
  sub    $0x1,%ebx
  je     L19
L83:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L24
  addl   $0x1,0x10(%rsp)
  sub    $0x1,%ebx
  jne    L83
L19:
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
L5:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jne    L21
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L34:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L5
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D6
type: string

tool: D10: Mary won %d times and John won %d times


tool: D6:  %d

assistant: ```c
int main() {
  int N, win[3] = {0, 0, 0}, i;
  scanf(" %d", &N);
  while (N != 0) {
    i = N;
    win[1] = 0;
    win[2] = 0;
    while (i > 0) {
      scanf(" %d", &win[0]);
      win[0] == 0 ? win[1]++ : win[2]++;
      i--;
    }
    printf("Mary won %d times and John won %d times\n", win[1], win[2]);
    scanf(" %d", &N);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<PutConsolidatedCode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L47
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L33
  addl   $0x1,-0x4(%rbp)
L33:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  je     L22
  cmpl   $0xa,-0x8(%rbp)
  je     L22
  cmpl   $0xd,-0x8(%rbp)
  je     L22
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <PutIndent@plt>
  cmpl   $0x1,-0x4(%rbp)
  jne    L11
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L60
L11:
  mov    -0x4(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L60:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D16: %s;


tool: D5: %s%d;


assistant: ```c
int PutConsolidatedCode(int opcode, int indent, char *instructions, char *instructionm) {
  int c;
  int n = 1;
  c = getchar();
  while (c == opcode || c == 10 || c == 13) {
    if (c == opcode)
      ++n;
    c = getchar();
  }
  PutIndent(indent);
  if (n == 1)
    printf("%s;\n", instructions);
  else
    printf("%s%d;\n", instructionm, n);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PutConsolidatedCode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %rdx,%r15
  mov    %rcx,%r14
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %ebp,%eax
  sete   %al
  cmp    $0xa,%ebx
  sete   %dl
  or     %dl,%al
  jne    L45
  cmp    $0xd,%ebx
  jne    L23
L45:
  mov    $0x1,%r12d
L36:
  cmp    %ebx,%ebp
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,%ebp
  sete   %al
  cmp    $0xa,%ebx
  sete   %dl
  or     %dl,%al
  jne    L36
  cmp    $0xd,%ebx
  je     L36
  mov    %r13d,%edi
  call   <PutIndent@plt>
  cmp    $0x1,%r12d
  je     L59
  mov    %r12d,%edx
  mov    %r14,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    %r13d,%edi
  call   <PutIndent@plt>
L59:
  mov    %r15,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
```

tool_calls: name: read_data
arguments: label: D12
type: string
name: read_data
arguments: label: D9
type: string

tool: D12: %s%d;


tool: D9: %s;


assistant: ```c
int PutConsolidatedCode(int opcode, int indent, char *instructions, char *instructionm) {
  int c;
  int n = 1;
  c = getchar();
  while (c == opcode || c == 10 || c == 13) {
    if (c == opcode)
      ++n;
    c = getchar();
  }
  PutIndent(indent);
  if (n == 1)
    printf("%s;\n", instructions);
  else
    printf("%s%d;\n", instructionm, n);
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PutConsolidatedCode>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0xa,%eax
  sete   %al
  cmp    %ebx,%r12d
  sete   %dl
  or     %dl,%al
  jne    L16
  cmp    $0xd,%r12d
  jne    L17
L16:
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %eax,%eax
  cmp    %r12d,%ebx
  sete   %al
  add    %eax,%r13d
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  sete   %al
  cmp    $0xa,%r12d
  sete   %dl
  or     %dl,%al
  jne    L31
  cmp    $0xd,%r12d
  je     L31
  mov    %ebp,%edi
  call   <PutIndent@plt>
  cmp    $0x1,%r13d
  je     L1
  mov    %r13d,%edx
  mov    %r14,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    %ebp,%edi
  call   <PutIndent@plt>
  nopl   (%rax)
L1:
  mov    %r15,%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string

tool: D0: %s%d;


tool: D16: %s;


assistant: ```c
int PutConsolidatedCode(int opcode, int indent, char *instructions, char *instructionm) {
  int c;
  int n = 1;
  c = getchar();
  while (c == opcode || c == 10 || c == 13) {
    if (c == opcode)
      ++n;
    c = getchar();
  }
  PutIndent(indent);
  if (n == 1)
    printf("%s;\n", instructions);
  else
    printf("%s%d;\n", instructionm, n);
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PutConsolidatedCode>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0xa,%eax
  sete   %al
  cmp    %ebx,%r12d
  sete   %dl
  or     %dl,%al
  jne    L0
  cmp    $0xd,%r12d
  jne    L58
L0:
  mov    $0x1,%r13d
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  cmp    %r12d,%ebx
  sete   %al
  add    %eax,%r13d
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    %eax,%ebx
  sete   %al
  cmp    $0xa,%r12d
  sete   %dl
  or     %dl,%al
  jne    L17
  cmp    $0xd,%r12d
  je     L17
  mov    %ebp,%edi
  call   <PutIndent@plt>
  cmp    $0x1,%r13d
  je     L38
  mov    %r13d,%edx
  mov    %r14,%rsi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L26:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  mov    %ebp,%edi
  call   <PutIndent@plt>
  nopl   (%rax)
L38:
  mov    %r15,%rsi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: label: D12
type: string
name: retrieve_data
arguments: label: D13
type: string

tool: D12: %s%d;


tool: D13: %s;


assistant: ```c
int PutConsolidatedCode(int opcode, int indent, char *instructions, char *instructionm) {
  int c;
  int n = 1;
  c = getchar();
  while (c == opcode || c == 10 || c == 13) {
    if (c == opcode)
      ++n;
    c = getchar();
  }
  PutIndent(indent);
  if (n == 1)
    printf("%s;\n", instructions);
  else
    printf("%s%d;\n", instructionm, n);
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<in_alpha>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  mov    %edx,%ebx
  mov    %r8,%r13
  mov    %r9,%r12
  cmp    %edx,(%rcx)
  jle    L57
  mov    $0x1,%eax
  cmpl   $0x0,0x50(%rsp)
  je     L81
  cmpl   $0x0,(%r9)
  je     L81
  mov    %esi,%edx
  sub    $0x1,%edx
  mov    $0x24,%eax
  cmp    %ebx,%edx
  jg     L16
L129:
  mov    %eax,0x0(%r13)
  movl   $0x0,(%r12)
  mov    $0x1,%eax
  jmp    L81
L16:
  movslq %ebx,%rbx
  mov    0x4(%rdi,%rbx,4),%edi
  mov    0x50(%rsp),%esi
  call   <is_alpha@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0x3,%eax
  add    $0x21,%eax
  jmp    L129
L57:
  mov    %rcx,%rbp
  movslq %edx,%r14
  shl    $0x2,%r14
  mov    (%rsp),%rax
  lea    (%rax,%r14,1),%r15
  mov    0x50(%rsp),%esi
  mov    (%r15),%edi
  call   <is_alpha@plt>
  test   %rax,%rax
  je     L97
  cmpl   $0x0,0x50(%rsp)
  je     L26
  cmpl   $0x25,(%r15)
  je     L73
L26:
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jg     L91
L40:
  add    $0x1,%ebx
  mov    %ebx,0x0(%rbp)
  movl   $0x24,0x0(%r13)
  mov    $0x0,%eax
L34:
  mov    %eax,(%r12)
  mov    $0x1,%eax
L81:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L97:
  movl   $0x0,0x0(%rbp)
  movl   $0x0,(%r12)
  jmp    L81
L73:
  add    $0x1,%ebx
  mov    %ebx,0x0(%rbp)
  movl   $0x42,0x0(%r13)
  movl   $0x0,(%r12)
  mov    $0x1,%eax
  jmp    L81
L91:
  mov    (%rsp),%rax
  lea    0x4(%rax,%r14,1),%r14
  mov    0x50(%rsp),%esi
  mov    (%r14),%edi
  call   <is_alpha@plt>
  test   %rax,%rax
  je     L40
  add    $0x2,%ebx
  mov    %ebx,0x0(%rbp)
  movl   $0x21,0x0(%r13)
  cmpl   $0x0,0x50(%rsp)
  je     L33
  cmpl   $0x25,(%r14)
  sete   %al
  movzbl %al,%eax
  jmp    L34
L33:
  mov    $0x0,%eax
  jmp    L34
```

assistant: ```c
int in_alpha(const unsigned int jisdata[], const int length, const int in_posn, unsigned int *p_end, unsigned int *p_cost, unsigned int *p_pcent, unsigned int gs1) {
  int two_alphas;
  if (in_posn < (int)*p_end) {
    if (gs1 && *p_pcent) {
      two_alphas = in_posn < length - 1 && is_alpha(jisdata[in_posn + 1], gs1);
      *p_cost = two_alphas ? 33 : 36;
      *p_pcent = 0;
    }
    return 1;
  }
  if (!is_alpha(jisdata[in_posn], gs1)) {
    *p_end = 0;
    *p_pcent = 0;
    return 0;
  }
  if (gs1 && jisdata[in_posn] == '%') {
    *p_end = in_posn + 1;
    *p_cost = 66;
    *p_pcent = 0;
    return 1;
  }
  two_alphas = in_posn < length - 1 && is_alpha(jisdata[in_posn + 1], gs1);
  *p_end = two_alphas ? in_posn + 2 : in_posn + 1;
  *p_cost = two_alphas ? 33 : 36;
  *p_pcent = two_alphas && gs1 && jisdata[in_posn + 1] == '%';
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L12:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  cmpl   $0xa,-0x8(%rbp)
  jle    L12
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print@plt>
  nop
  leave
  ret
```

assistant: ```c
void main() {
  int i, sum = 0;
  for (i = 0; i <= 10; i++) {
    sum = sum + i;
  }
  print(sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x37,%edi
  call   <print@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main() {
  int i, sum = 0;
  for (i = 0; i <= 10; i++) {
    sum = sum + i;
  }
  print(sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x37,%edi
  jmp    1050 <print@plt>
```

assistant: ```c
void main() {
  int i, sum = 0;
  for (i = 0; i <= 10; i++) {
    sum = sum + i;
  }
  print(sum);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x37,%edi
  jmp    1050 <print@plt>
```

assistant: ```c
void main() {
  int i, sum = 0;
  for (i = 0; i <= 10; i++) {
    sum = sum + i;
  }
  print(sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L17:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strln(char arr[]) {
  int i = 0;
  while (arr[i] != '\0') {
    i++;
  }
  return i;
}
```