ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<divisible>:
  endbr64
  test   %rdi,%rdi
  js     L71
  pxor   %xmm3,%xmm3
  cvtsi2sd %rdi,%xmm3
L69:
  movsd  D2(%rip),%xmm2
  mov    $0x1,%edx
  movabs $0x8000000000000000,%rsi
  jmp    L59
  nop
L98:
  cvttsd2si %xmm0,%rax
  test   %rax,%rax
  js     L17
L9:
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
L18:
  ucomisd %xmm0,%xmm1
  jp     L66
  jne    L66
  add    $0x1,%rdx
  cmp    $0x15,%rdx
  je     L97
L59:
  pxor   %xmm1,%xmm1
  movapd %xmm3,%xmm0
  cvtsi2sd %rdx,%xmm1
  divsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jb     L98
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%rax
  xor    %rsi,%rax
  test   %rax,%rax
  jns    L9
L17:
  mov    %rax,%rcx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  shr    %rcx
  or     %rax,%rcx
  cvtsi2sd %rcx,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L18
  nopl   0x0(%rax)
L66:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L97:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L71:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm3,%xmm3
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm3
  addsd  %xmm3,%xmm3
  jmp    L69
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

assistant: ```c
bool divisible(size_t num) {
  double res;
  size_t i;
  for (i = 1; i <= 20; ++i) {
    res = num / (double)i;
    if (res != (size_t)res) {
      return false;
    }
  }
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divisible>:
  endbr64
  test   %rdi,%rdi
  js     L95
  pxor   %xmm3,%xmm3
  cvtsi2sd %rdi,%xmm3
L51:
  movsd  D9(%rip),%xmm2
  mov    $0x1,%edx
  movabs $0x8000000000000000,%rsi
  jmp    L21
  nop
L93:
  cvttsd2si %xmm0,%rax
  test   %rax,%rax
  js     L25
L79:
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
L43:
  ucomisd %xmm0,%xmm1
  jp     L44
  jne    L44
  add    $0x1,%rdx
  cmp    $0x15,%rdx
  je     L7
L21:
  pxor   %xmm1,%xmm1
  movapd %xmm3,%xmm0
  cvtsi2sd %rdx,%xmm1
  divsd  %xmm1,%xmm0
  comisd %xmm2,%xmm0
  jb     L93
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%rax
  xor    %rsi,%rax
  test   %rax,%rax
  jns    L79
L25:
  mov    %rax,%rcx
  and    $0x1,%eax
  pxor   %xmm1,%xmm1
  shr    %rcx
  or     %rax,%rcx
  cvtsi2sd %rcx,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L43
  nopl   0x0(%rax)
L44:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L95:
  mov    %rdi,%rax
  and    $0x1,%edi
  pxor   %xmm3,%xmm3
  shr    %rax
  or     %rdi,%rax
  cvtsi2sd %rax,%xmm3
  addsd  %xmm3,%xmm3
  jmp    L51
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

assistant: ```c
bool divisible(size_t num) {
  double res;
  size_t i;
  for (i = 1; i <= 20; ++i) {
    res = num / (double)i;
    if (res != (size_t)res) {
      return false;
    }
  }
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<countingSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L31:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L31
  sub    $0x918,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L35:
  cmp    %rdx,%rsp
  je     L55
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L55:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L17
  orq    $0x0,-0x8(%rsp,%rax,1)
L17:
  mov    %rsp,%r12
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  lea    -0x3d0930(%rbp),%rax
  lea    -0x30(%rbp),%rdx
L53:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L53
  test   %r13d,%r13d
  jle    L107
  mov    %rbx,%rax
  lea    -0x1(%r13),%ecx
  lea    0x4(%rbx,%rcx,4),%rsi
L67:
  movslq (%rax),%rcx
  addl   $0x1,-0x3d0930(%rbp,%rcx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L67
L107:
  lea    -0x3d092c(%rbp),%rax
L75:
  mov    -0x4(%rax),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L75
  mov    %r13d,%edx
  sub    $0x1,%edx
  js     L45
  movslq %edx,%rdx
L44:
  mov    (%rbx,%rdx,4),%esi
  movslq %esi,%rcx
  mov    -0x3d0930(%rbp,%rcx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%rdi
  mov    %esi,(%r12,%rdi,4)
  mov    %eax,-0x3d0930(%rbp,%rcx,4)
  sub    $0x1,%rdx
  test   %edx,%edx
  jns    L44
L45:
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <printArray@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D8: 


assistant: ```c
void countingSort(int *a, int size) {
  int output[size];
  memset(output, 0, size);
  int count[1000000];
  for (int i = 0; i < 1000000; i++)
    count[i] = 0;
  for (int i = 0; i < size; i++) {
    count[a[i]]++;
  }
  for (int i = 1; i < 1000000; i++)
    count[i] += count[i - 1];
  for (int i = size - 1; i >= 0; i--) {
    output[count[a[i]] - 1] = a[i];
    count[a[i]]--;
  }
  printArray(output, size);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<countingSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L72:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L72
  sub    $0x918,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  mov    %rdi,%rbx
  lea    0xf(,%rax,4),%rax
  mov    %esi,%r13d
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L54
L45:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L45
L54:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L73
L37:
  mov    %rsp,%r12
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  mov    $0x3d0900,%edx
  lea    -0x3d0930(%rbp),%rdi
  call   <memset@plt>
  lea    -0x1(%r13),%esi
  test   %r13d,%r13d
  jle    L53
  lea    -0x1(%r13),%edx
  mov    %rbx,%rax
  mov    %rdx,%rsi
  lea    0x4(%rbx,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L3:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,-0x3d0930(%rbp,%rdx,4)
  cmp    %rax,%rcx
  jne    L3
L53:
  lea    -0x3d092c(%rbp),%rax
  lea    -0x30(%rbp),%rcx
  nop
L57:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L57
  test   %esi,%esi
  js     L58
  movslq %esi,%rdx
  nopl   (%rax)
L69:
  movslq (%rbx,%rdx,4),%rcx
  sub    $0x1,%rdx
  mov    -0x3d0930(%rbp,%rcx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%rdi
  mov    %eax,-0x3d0930(%rbp,%rcx,4)
  mov    %ecx,(%r12,%rdi,4)
  test   %edx,%edx
  jns    L69
L58:
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <printArray@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L73:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L37
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: 


assistant: ```c
void countingSort(int *a, int size) {
  int output[size];
  memset(output, 0, size);
  int count[1000000];
  for (int i = 0; i < 1000000; i++)
    count[i] = 0;
  for (int i = 0; i < size; i++) {
    count[a[i]]++;
  }
  for (int i = 1; i < 1000000; i++)
    count[i] += count[i - 1];
  for (int i = size - 1; i >= 0; i--) {
    output[count[a[i]] - 1] = a[i];
    count[a[i]]--;
  }
  printArray(output, size);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<countingSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  lea    -0x3d0000(%rsp),%r11
L71:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L71
  sub    $0x918,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  mov    %rdi,%rbx
  lea    0xf(,%rax,4),%rax
  mov    %esi,%r13d
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L13
L84:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L84
L13:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L57
L19:
  mov    %rsp,%r12
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  xor    %esi,%esi
  mov    $0x3d0900,%edx
  lea    -0x3d0930(%rbp),%rdi
  call   <memset@plt>
  lea    -0x1(%r13),%esi
  test   %r13d,%r13d
  jle    L101
  lea    -0x1(%r13),%edx
  mov    %rbx,%rax
  mov    %rdx,%rsi
  lea    0x4(%rbx,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L73:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,-0x3d0930(%rbp,%rdx,4)
  cmp    %rax,%rcx
  jne    L73
L101:
  mov    -0x3d0930(%rbp),%edx
  lea    -0x3d092c(%rbp),%rax
  lea    -0x30(%rbp),%rcx
  nopl   (%rax)
L60:
  add    (%rax),%edx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %rax,%rcx
  jne    L60
  test   %esi,%esi
  js     L79
  movslq %esi,%rdx
  nopl   (%rax)
L67:
  movslq (%rbx,%rdx,4),%rcx
  sub    $0x1,%rdx
  mov    -0x3d0930(%rbp,%rcx,4),%eax
  sub    $0x1,%eax
  movslq %eax,%rdi
  mov    %eax,-0x3d0930(%rbp,%rcx,4)
  mov    %ecx,(%r12,%rdi,4)
  test   %edx,%edx
  jns    L67
L79:
  mov    %r12,%rdi
  mov    %r13d,%esi
  call   <printArray@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L57:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: 


assistant: ```c
void countingSort(int *a, int size) {
  int output[size];
  memset(output, 0, size);
  int count[1000000];
  for (int i = 0; i < 1000000; i++)
    count[i] = 0;
  for (int i = 0; i < size; i++) {
    count[a[i]]++;
  }
  for (int i = 1; i < 1000000; i++)
    count[i] += count[i - 1];
  for (int i = size - 1; i >= 0; i--) {
    output[count[a[i]] - 1] = a[i];
    count[a[i]]--;
  }
  printArray(output, size);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checkCeleb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L25
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L25
  mov    -0x10(%rbp),%eax
  jmp    L34
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L27
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L27
  mov    -0xc(%rbp),%eax
  jmp    L34
L27:
  mov    $0xffffffff,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int checkCeleb(int **xs, int i, int j) {
  if (xs[i][j] && !xs[j][i])
    return j;
  else if (!xs[i][j] && xs[i][j])
    return i;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkCeleb>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rax
  mov    (%rdi,%rsi,8),%rcx
  cmpl   $0x0,(%rcx,%rax,4)
  je     L3
  mov    (%rdi,%rax,8),%rax
  cmpl   $0x0,(%rax,%rsi,4)
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int checkCeleb(int **xs, int i, int j) {
  if (xs[i][j] && !xs[j][i])
    return j;
  else if (!xs[i][j] && xs[i][j])
    return i;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checkCeleb>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rax
  mov    (%rdi,%rsi,8),%rcx
  mov    (%rcx,%rax,4),%ecx
  test   %ecx,%ecx
  je     L9
  mov    (%rdi,%rax,8),%rax
  mov    (%rax,%rsi,4),%eax
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int checkCeleb(int **xs, int i, int j) {
  if (xs[i][j] && !xs[j][i])
    return j;
  else if (!xs[i][j] && xs[i][j])
    return i;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<checkCeleb>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rax
  mov    (%rdi,%rsi,8),%rcx
  mov    (%rcx,%rax,4),%ecx
  test   %ecx,%ecx
  je     L7
  mov    (%rdi,%rax,8),%rax
  mov    (%rax,%rsi,4),%eax
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmove  %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int checkCeleb(int **xs, int i, int j) {
  if (xs[i][j] && !xs[j][i])
    return j;
  else if (!xs[i][j] && xs[i][j])
    return i;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(char *message, ...) {
  va_list Args;
  va_start(Args, message);
  vfprintf(stderr, message, Args);
  va_end(Args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void error(char *message, ...) {
  va_list Args;
  va_start(Args, message);
  vfprintf(stderr, message, Args);
  va_end(Args);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(char *message, ...) {
  va_list Args;
  va_start(Args, message);
  vfprintf(stderr, message, Args);
  va_end(Args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(char *message, ...) {
  va_list Args;
  va_start(Args, message);
  vfprintf(stderr, message, Args);
  va_end(Args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<menu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string

tool: D6: FAIL: menu callback should never be called


assistant: ```c
void menu(int selection) {
  printf("FAIL: menu callback should never be called\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: FAIL: menu callback should never be called


assistant: ```c
void menu(int selection) {
  printf("FAIL: menu callback should never be called\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: FAIL: menu callback should never be called


assistant: ```c
void menu(int selection) {
  printf("FAIL: menu callback should never be called\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<menu>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: FAIL: menu callback should never be called


assistant: ```c
void menu(int selection) {
  printf("FAIL: menu callback should never be called\n");
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mmul3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x20(%rsp)
  mov    %rsi,-0x18(%rsp)
  mov    %rdx,-0x10(%rsp)
  mov    %ecx,-0x2c(%rsp)
  mov    %r8d,-0x30(%rsp)
  test   %ecx,%ecx
  jle    L33
  mov    %rdi,%r11
  lea    0x0(,%r8,4),%r9d
  movslq %r9d,%r9
  shl    $0x2,%r9
  lea    -0x1(%r8),%r12d
  mov    %r12d,%eax
  shr    $0x2,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rsp)
  movslq %r8d,%rdi
  lea    (%rdi,%rdi,2),%r10
  shl    $0x2,%r10
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    %r12d,%r12d
  lea    0x10(%r11),%rax
  mov    %rax,-0x8(%rsp)
  jmp    L5
L24:
  add    $0x1,%r13d
  add    -0x30(%rsp),%r14d
  cmp    %r13d,-0x2c(%rsp)
  je     L33
L5:
  cmpl   $0x0,-0x30(%rsp)
  jle    L24
  movslq %r14d,%rax
  mov    -0x18(%rsp),%r11
  lea    0x0(,%rax,4),%rbp
  mov    -0x10(%rsp),%rbx
  lea    (%rbx,%rbp,1),%rsi
  add    -0x20(%rsp),%rbp
  add    -0x28(%rsp),%rax
  mov    -0x8(%rsp),%rbx
  lea    (%rbx,%rax,4),%r8
  mov    $0x0,%ebx
L51:
  mov    %r11,%r15
  mov    %rbp,%rax
L6:
  mov    (%rax),%edx
  imul   (%r15),%edx
  add    (%rsi),%edx
  mov    %edx,(%rsi)
  mov    0x4(%rax),%ecx
  imul   (%r15,%rdi,4),%ecx
  add    %edx,%ecx
  mov    %ecx,(%rsi)
  mov    0x8(%rax),%edx
  imul   (%r15,%rdi,8),%edx
  add    %ecx,%edx
  mov    %edx,(%rsi)
  mov    0xc(%rax),%ecx
  imul   (%r15,%r10,1),%ecx
  add    %ecx,%edx
  mov    %edx,(%rsi)
  add    $0x10,%rax
  add    %r9,%r15
  cmp    %r8,%rax
  jne    L6
  lea    0x1(%rbx),%rax
  add    $0x4,%r11
  add    $0x4,%rsi
  cmp    %r12,%rbx
  je     L24
  mov    %rax,%rbx
  jmp    L51
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmul3(int *a, int *b, int *res, int h, int w) {
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      for (int k = 0; k < w; k += 4) {
        (res + i * w)[j] += (a + i * w)[k] * (b + k * w)[j];
        (res + i * w)[j] += (a + i * w)[k + 1] * (b + (k + 1) * w)[j];
        (res + i * w)[j] += (a + i * w)[k + 2] * (b + (k + 2) * w)[j];
        (res + i * w)[j] += (a + i * w)[k + 3] * (b + (k + 3) * w)[j];
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mmul3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,-0x20(%rsp)
  mov    %rsi,-0x18(%rsp)
  mov    %rdx,-0x10(%rsp)
  mov    %ecx,-0x2c(%rsp)
  mov    %r8d,-0x30(%rsp)
  test   %ecx,%ecx
  jle    L37
  lea    -0x1(%r8),%r12d
  mov    %rdi,%r11
  movslq %r8d,%rdi
  xor    %r14d,%r14d
  mov    %r12d,%eax
  lea    0x0(,%r8,4),%r9d
  lea    (%rdi,%rdi,2),%r10
  xor    %r13d,%r13d
  shr    $0x2,%eax
  movslq %r9d,%r9
  shl    $0x2,%r10
  shl    $0x2,%rax
  shl    $0x2,%r9
  mov    %rax,-0x28(%rsp)
  lea    0x10(%r11),%rax
  mov    %rax,-0x8(%rsp)
  nopl   (%rax)
L47:
  mov    -0x30(%rsp),%eax
  test   %eax,%eax
  jle    L34
  mov    -0x10(%rsp),%rbx
  movslq %r14d,%rax
  mov    -0x18(%rsp),%r11
  lea    0x0(,%rax,4),%rbp
  add    -0x28(%rsp),%rax
  lea    (%rbx,%rbp,1),%rsi
  mov    -0x8(%rsp),%rbx
  add    -0x20(%rsp),%rbp
  lea    (%rbx,%rax,4),%r8
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    (%rsi),%eax
  mov    %r11,%rcx
  mov    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rdx),%r15d
  imul   (%rcx),%r15d
  add    $0x10,%rdx
  add    %eax,%r15d
  mov    %r15d,(%rsi)
  mov    -0xc(%rdx),%eax
  imul   (%rcx,%rdi,4),%eax
  add    %r15d,%eax
  mov    %eax,(%rsi)
  mov    -0x8(%rdx),%r15d
  imul   (%rcx,%rdi,8),%r15d
  add    %eax,%r15d
  mov    %r15d,(%rsi)
  mov    -0x4(%rdx),%eax
  imul   (%rcx,%r10,1),%eax
  add    %r9,%rcx
  add    %r15d,%eax
  mov    %eax,(%rsi)
  cmp    %r8,%rdx
  jne    L17
  lea    0x1(%rbx),%rax
  add    $0x4,%rsi
  add    $0x4,%r11
  cmp    %rbx,%r12
  je     L34
  mov    %rax,%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%r13d
  add    -0x30(%rsp),%r14d
  cmp    %r13d,-0x2c(%rsp)
  jne    L47
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mmul3(int *a, int *b, int *res, int h, int w) {
  for (int i = 0; i < h; i++) {
    for (int j = 0; j < w; j++) {
      for (int k = 0; k < w; k += 4) {
        (res + i * w)[j] += (a + i * w)[k] * (b + k * w)[j];
        (res + i * w)[j] += (a + i * w)[k + 1] * (b + (k + 1) * w)[j];
        (res + i * w)[j] += (a + i * w)[k + 2] * (b + (k + 2) * w)[j];
        (res + i * w)[j] += (a + i * w)[k + 3] * (b + (k + 3) * w)[j];
      }
    }
  }
}
```