ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<InvertErrorTable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %edx,-0x230(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x228(%rbp),%rcx
  lea    -0x210(%rbp),%rax
  mov    $0x208,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x214(%rbp)
  jmp    L18
L9:
  mov    -0x228(%rbp),%rax
  lea    0x104(%rax),%rdx
  mov    -0x214(%rbp),%eax
  cltq
  movss  -0x210(%rbp,%rax,4),%xmm0
  mov    -0x214(%rbp),%eax
  cltq
  movss  %xmm0,(%rdx,%rax,4)
  addl   $0x1,-0x214(%rbp)
L18:
  mov    -0x214(%rbp),%eax
  cmp    -0x22c(%rbp),%eax
  jl     L9
  movl   $0x0,-0x214(%rbp)
  jmp    L31
L36:
  mov    -0x230(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x214(%rbp),%eax
  cltq
  add    $0x41,%rax
  movss  -0x210(%rbp,%rax,4),%xmm0
  mov    -0x228(%rbp),%rax
  mov    -0x214(%rbp),%edx
  movslq %edx,%rdx
  movss  %xmm0,(%rax,%rdx,4)
  addl   $0x1,-0x214(%rbp)
L31:
  mov    -0x214(%rbp),%eax
  cmp    -0x230(%rbp),%eax
  jl     L36
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
void InvertErrorTable(float errorTable[2][65], int width, int height) {
  int i;
  float copy[2][65];
  memcpy(copy, errorTable, sizeof(copy));
  for (i = 0; i < width; i++) {
    errorTable[1][i] = copy[0][i];
  }
  for (i = 0; i < height; i++) {
    errorTable[0][i] = copy[1][height - 1 - i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<InvertErrorTable>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x208,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  test   %r12d,%r12d
  jle    L29
  mov    %r12d,%esi
  mov    $0x0,%eax
L46:
  movss  (%rsp,%rax,4),%xmm0
  movss  %xmm0,0x104(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L46
L29:
  test   %ebp,%ebp
  jle    L15
  movslq %ebp,%rcx
  shl    $0x2,%rcx
  lea    (%rsp,%rcx,1),%rdx
  mov    %rbx,%rax
  lea    -0x4(%rsp,%rcx,1),%rcx
  lea    -0x1(%rbp),%esi
  shl    $0x2,%rsi
  sub    %rsi,%rcx
L2:
  movss  0x100(%rdx),%xmm0
  movss  %xmm0,(%rax)
  sub    $0x4,%rdx
  add    $0x4,%rax
  cmp    %rcx,%rdx
  jne    L2
L15:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void InvertErrorTable(float errorTable[2][65], int width, int height) {
  int i;
  float copy[2][65];
  memcpy(copy, errorTable, sizeof(copy));
  for (i = 0; i < width; i++) {
    errorTable[1][i] = copy[0][i];
  }
  for (i = 0; i < height; i++) {
    errorTable[0][i] = copy[1][height - 1 - i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<InvertErrorTable>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  mov    $0x208,%edx
  push   %rbp
  mov    %esi,%ebp
  mov    %rdi,%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <memcpy@plt>
  test   %ebp,%ebp
  jle    L12
  movslq %ebp,%rdx
  lea    0x104(%rbx),%rdi
  mov    %r13,%rsi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L12:
  test   %r12d,%r12d
  jle    L25
  movslq %r12d,%rax
  lea    -0x1(%r12),%ecx
  lea    0x100(%r13,%rax,4),%rdx
  lea    0x4(%rbx,%rcx,4),%rcx
  mov    %rbx,%rax
  cs nopw 0x0(%rax,%rax,1)
L20:
  movss  (%rdx),%xmm0
  add    $0x4,%rax
  sub    $0x4,%rdx
  movss  %xmm0,-0x4(%rax)
  cmp    %rcx,%rax
  jne    L20
L25:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void InvertErrorTable(float errorTable[2][65], int width, int height) {
  int i;
  float copy[2][65];
  memcpy(copy, errorTable, sizeof(copy));
  for (i = 0; i < width; i++) {
    errorTable[1][i] = copy[0][i];
  }
  for (i = 0; i < height; i++) {
    errorTable[0][i] = copy[1][height - 1 - i];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L19
  mov    -0x4(%rbp),%eax
  jmp    L9
L19:
  mov    -0x4(%rbp),%eax
  neg    %eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int abs(int x) {
  if (x > 0) {
    return x;
  } else {
    return (0 - x);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int x) {
  if (x > 0) {
    return x;
  } else {
    return (0 - x);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int x) {
  if (x > 0) {
    return x;
  } else {
    return (0 - x);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<abs>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int abs(int x) {
  if (x > 0) {
    return x;
  } else {
    return (0 - x);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udelay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <timerE_get@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  nop
L3:
  mov    $0x0,%eax
  call   <timerE_get@plt>
  shl    $0x8,%eax
  cltq
  mov    -0x8(%rbp),%rdx
  shl    $0x8,%rdx
  sub    %rdx,%rax
  shr    $0x8,%rax
  cmp    %rax,-0x18(%rbp)
  ja     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long base = timerE_get();
  while ((((timerE_get() << 8) - (base << 8)) >> 8) < usec)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<udelay>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%eax
  call   <timerE_get@plt>
  movslq %eax,%rbx
  shl    $0x8,%rbx
L7:
  mov    $0x0,%eax
  call   <timerE_get@plt>
  shl    $0x8,%eax
  cltq
  sub    %rbx,%rax
  shr    $0x8,%rax
  cmp    %rbp,%rax
  jb     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long base = timerE_get();
  while ((((timerE_get() << 8) - (base << 8)) >> 8) < usec)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<udelay>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <timerE_get@plt>
  movslq %eax,%rbx
  shl    $0x8,%rbx
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <timerE_get@plt>
  shl    $0x8,%eax
  cltq
  sub    %rbx,%rax
  shr    $0x8,%rax
  cmp    %rbp,%rax
  jb     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long base = timerE_get();
  while ((((timerE_get() << 8) - (base << 8)) >> 8) < usec)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<udelay>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <timerE_get@plt>
  movslq %eax,%rbx
  shl    $0x8,%rbx
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <timerE_get@plt>
  shl    $0x8,%eax
  cltq
  sub    %rbx,%rax
  shr    $0x8,%rax
  cmp    %rbp,%rax
  jb     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void udelay(unsigned long usec) {
  unsigned long base = timerE_get();
  while ((((timerE_get() << 8) - (base << 8)) >> 8) < usec)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dotelnet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <dotelnet_subr@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    $0x0,%eax
  jmp    L1
L8:
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int dotelnet(argc, argv)
int argc;
char *argv[];
{
  struct telnet *tn;
  tn = dotelnet_subr(argc, argv, 0);
  if (tn)
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dotelnet>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%eax
  call   <dotelnet_subr@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int dotelnet(argc, argv)
int argc;
char *argv[];
{
  struct telnet *tn;
  tn = dotelnet_subr(argc, argv, 0);
  if (tn)
    return 0;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dotelnet>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %eax,%eax
  call   <dotelnet_subr@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int dotelnet(argc, argv)
int argc;
char *argv[];
{
  struct telnet *tn;
  tn = dotelnet_subr(argc, argv, 0);
  if (tn)
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dotelnet>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  xor    %eax,%eax
  call   <dotelnet_subr@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int dotelnet(argc, argv)
int argc;
char *argv[];
{
  struct telnet *tn;
  tn = dotelnet_subr(argc, argv, 0);
  if (tn)
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L49
  mov    $0x2,%eax
  jmp    L10
L49:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jne    L22
  mov    $0x1,%eax
  jmp    L10
L22:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L43
  mov    $0x0,%eax
  jmp    L10
L43:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <path>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <path>
  add    %ebx,%eax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int path(int i, int j) {
  if (i == j - 2) {
    return 2;
  }
  if (i == j - 1) {
    return 1;
  }
  if (i >= j) {
    return 0;
  }
  return path(i + 1, j) + path(i + 2, j);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<path>:
  endbr64
  lea    -0x2(%rsi),%eax
  cmp    %edi,%eax
  je     L39
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  lea    -0x1(%rsi),%edx
  mov    $0x1,%eax
  cmp    %edi,%edx
  je     L34
  mov    $0x0,%eax
  cmp    %edi,%esi
  jg     L10
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  lea    0x1(%rdi),%edi
  call   <path>
  mov    %eax,%r12d
  lea    0x2(%rbx),%edi
  mov    %ebp,%esi
  call   <path>
  add    %r12d,%eax
  jmp    L34
L39:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int path(int i, int j) {
  if (i == j - 2) {
    return 2;
  }
  if (i == j - 1) {
    return 1;
  }
  if (i >= j) {
    return 0;
  }
  return path(i + 1, j) + path(i + 2, j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: %lu


assistant: ```c
void print_array(unsigned long *a, int b) {
  int c;
  for (c = 0; c < b; c++)
    printf("%lu\n", a[c]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D8(%rip),%rbp
L19:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %lu


assistant: ```c
void print_array(unsigned long *a, int b) {
  int c;
  for (c = 0; c < b; c++)
    printf("%lu\n", a[c]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %lu


assistant: ```c
void print_array(unsigned long *a, int b) {
  int c;
  for (c = 0; c < b; c++)
    printf("%lu\n", a[c]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L12:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: %lu


assistant: ```c
void print_array(unsigned long *a, int b) {
  int c;
  for (c = 0; c < b; c++)
    printf("%lu\n", a[c]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bmi2_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  sub    $0x40,%rsp
  movabs $0xce7ace0ce7ace0,%rax
  mov    %rax,-0x50(%rbp)
  movq   $0xface,-0x48(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L18
L28:
  mov    -0x54(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x50(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x54(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  mov    -0x48(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <calc_mul_u64@plt>
  cltq
  mov    %rax,-0x40(%rbp)
  sar    $0x3f,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x48(%rbp),%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    %r13,%rdx
  imul   %r14,%rdx
  mov    %r15,%rax
  imul   %r12,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    %r12,%rax
  mul    %r14
  add    %rdx,%rcx
  mov    %rcx,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rcx
  xor    -0x38(%rbp),%rcx
  xor    -0x40(%rbp),%rax
  or     %rcx,%rax
  test   %rax,%rax
  je     L7
  call   <abort@plt>
L7:
  addl   $0x1,-0x54(%rbp)
L18:
  cmpl   $0x4,-0x54(%rbp)
  jbe    L28
  nop
  nop
  add    $0x40,%rsp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned long long a = 0xce7ace0ce7ace0;
  unsigned long long b = 0xface;
  unsigned __int128 res, res_ref;
  for (i = 0; i < 5; ++i) {
    a = a * (i + 1);
    b = b / (i + 1);
    res_ref = calc_mul_u64(a, b);
    res = (unsigned __int128)a * b;
    if (res != res_ref)
      abort();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bmi2_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xface,%esi
  movabs $0xce7ace0ce7ace0,%rdi
  mov    $0x0,%eax
  call   <calc_mul_u64@plt>
  call   <abort@plt>
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned long long a = 0xce7ace0ce7ace0;
  unsigned long long b = 0xface;
  unsigned __int128 res, res_ref;
  for (i = 0; i < 5; ++i) {
    a = a * (i + 1);
    b = b / (i + 1);
    res_ref = calc_mul_u64(a, b);
    res = (unsigned __int128)a * b;
    if (res != res_ref)
      abort();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bmi2_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xface,%esi
  xor    %eax,%eax
  movabs $0xce7ace0ce7ace0,%rdi
  call   <calc_mul_u64@plt>
  call   <abort@plt>
```

assistant: ```c
void bmi2_test() {
  unsigned i;
  unsigned long long a = 0xce7ace0ce7ace0;
  unsigned long long b = 0xface;
  unsigned __int128 res, res_ref;
  for (i = 0; i < 5; ++i) {
    a = a * (i + 1);
    b = b / (i + 1);
    res_ref = calc_mul_u64(a, b);
    res = (unsigned __int128)a * b;
    if (res != res_ref)
      abort();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <abs@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L1:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  mov    $0x8,%eax
  sub    %rdx,%rax
  shl    $0x3,%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  sar    $0x38,%rax
  mov    %rax,%rcx
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  cmpq   $0x0,-0x18(%rbp)
  jns    L20
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  or     $0xffffff80,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
L20:
  nop
  leave
  ret
```

assistant: ```c
void set_bytes(long in, int numbytes, char *out) {
  int i;
  long tmp;
  tmp = abs(in);
  for (i = 0; i < numbytes; i++) {
    out[numbytes - 1 - i] = (tmp << (sizeof(long) - (i + 1)) * 8) >> (sizeof(long) - 1) * 8;
  }
  if (in < 0)
    out[0] |= 0x0080;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<set_bytes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%rbx
  call   <abs@plt>
  test   %r12d,%r12d
  jle    L37
  movslq %r12d,%rcx
  lea    -0x1(%rbx,%rcx,1),%rdx
  lea    -0x2(%rbx,%rcx,1),%rdi
  lea    -0x1(%r12),%ecx
  sub    %rcx,%rdi
  mov    $0x38,%ecx
L34:
  mov    %rax,%rsi
  shl    %cl,%rsi
  sar    $0x38,%rsi
  mov    %sil,(%rdx)
  sub    $0x8,%ecx
  sub    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L34
L37:
  test   %rbp,%rbp
  js     L31
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  orb    $0x80,(%rbx)
  jmp    L32
```

assistant: ```c
void set_bytes(long in, int numbytes, char *out) {
  int i;
  long tmp;
  tmp = abs(in);
  for (i = 0; i < numbytes; i++) {
    out[numbytes - 1 - i] = (tmp << (sizeof(long) - (i + 1)) * 8) >> (sizeof(long) - 1) * 8;
  }
  if (in < 0)
    out[0] |= 0x0080;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_bytes>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  call   <abs@plt>
  test   %ebx,%ebx
  jle    L25
  lea    -0x1(%rbx),%ecx
  lea    -0x2(%r12,%rbx,1),%rdi
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  sub    %rcx,%rdi
  add    %r12,%rdx
  mov    $0x38,%ecx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rax,%rsi
  sub    $0x1,%rdx
  shl    %cl,%rsi
  sub    $0x8,%ecx
  sar    $0x38,%rsi
  mov    %sil,0x1(%rdx)
  cmp    %rdi,%rdx
  jne    L12
L25:
  test   %rbp,%rbp
  jns    L1
  orb    $0x80,(%r12)
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void set_bytes(long in, int numbytes, char *out) {
  int i;
  long tmp;
  tmp = abs(in);
  for (i = 0; i < numbytes; i++) {
    out[numbytes - 1 - i] = (tmp << (sizeof(long) - (i + 1)) * 8) >> (sizeof(long) - 1) * 8;
  }
  if (in < 0)
    out[0] |= 0x0080;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_bytes>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  call   <abs@plt>
  test   %ebx,%ebx
  jle    L3
  lea    -0x1(%rbx),%ecx
  lea    -0x2(%r12,%rbx,1),%rdi
  movslq %ecx,%rdx
  mov    %ecx,%ecx
  sub    %rcx,%rdi
  add    %r12,%rdx
  mov    $0x38,%ecx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rax,%rsi
  sub    $0x1,%rdx
  shl    %cl,%rsi
  sub    $0x8,%ecx
  sar    $0x38,%rsi
  mov    %sil,0x1(%rdx)
  cmp    %rdx,%rdi
  jne    L7
L3:
  test   %rbp,%rbp
  jns    L0
  orb    $0x80,(%r12)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void set_bytes(long in, int numbytes, char *out) {
  int i;
  long tmp;
  tmp = abs(in);
  for (i = 0; i < numbytes; i++) {
    out[numbytes - 1 - i] = (tmp << (sizeof(long) - (i + 1)) * 8) >> (sizeof(long) - 1) * 8;
  }
  if (in < 0)
    out[0] |= 0x0080;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mystrndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  leave
  ret
```

assistant: ```c
char *mystrndup(const char *src, size_t len) {
  char *r = malloc(len + 1);
  r[len] = 0;
  return memcpy(r, src, len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mystrndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  movb   $0x0,(%rax,%rbx,1)
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrndup(const char *src, size_t len) {
  char *r = malloc(len + 1);
  r[len] = 0;
  return memcpy(r, src, len);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mystrndup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
char *mystrndup(const char *src, size_t len) {
  char *r = malloc(len + 1);
  r[len] = 0;
  return memcpy(r, src, len);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mystrndup>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  movb   $0x0,(%rax,%r12,1)
  add    $0x8,%rsp
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <memcpy@plt>
```

assistant: ```c
char *mystrndup(const char *src, size_t len) {
  char *r = malloc(len + 1);
  r[len] = 0;
  return memcpy(r, src, len);
}
```