ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<join>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  call   <linear@plt>
  test   %rbx,%rbx
  js     L9
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbx,%xmm1
L48:
  mulsd  %xmm0,%xmm1
  mov    %rbp,%rdi
  movsd  %xmm1,0x8(%rsp)
  call   <linear@plt>
  mov    $0xff,%eax
  movapd %xmm0,%xmm1
  sub    %rbx,%rax
  js     L29
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
L69:
  mulsd  %xmm1,%xmm0
  movsd  D72(%rip),%xmm2
  movsd  D3(%rip),%xmm1
  addsd  0x8(%rsp),%xmm0
  divsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  jb     L25
  mulsd  D1(%rip),%xmm0
L13:
  mulsd  %xmm2,%xmm0
  movsd  D22(%rip),%xmm1
  addsd  D82(%rip),%xmm0
  comisd %xmm1,%xmm0
  jae    L64
  add    $0x18,%rsp
  cvttsd2si %xmm0,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  subsd  %xmm1,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  cvttsd2si %xmm0,%rax
  btc    $0x3f,%rax
  ret
  nopl   (%rax)
L9:
  mov    %rbx,%rax
  mov    %rbx,%rdx
  pxor   %xmm1,%xmm1
  shr    %rax
  and    $0x1,%edx
  or     %rdx,%rax
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L48
  nopl   0x0(%rax)
L29:
  mov    %rax,%rdx
  and    $0x1,%eax
  pxor   %xmm0,%xmm0
  shr    %rdx
  or     %rax,%rdx
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L69
  xchg   %ax,%ax
L25:
  movsd  D57(%rip),%xmm1
  call   <pow@plt>
  mov    D72(%rip),%rax
  mulsd  D45(%rip),%xmm0
  subsd  D74(%rip),%xmm0
  movq   %rax,%xmm2
  jmp    L13
```

tool_calls: name: read_data
arguments: label: D72
data_type: f64
name: read_data
arguments: label: D3
data_type: f64
name: read_data
arguments: label: D1
data_type: f64
name: read_data
arguments: label: D22
data_type: byte[8]
name: read_data
arguments: label: D82
data_type: f64
name: read_data
arguments: label: D57
data_type: byte[8]
name: read_data
arguments: label: D45
data_type: f64
name: read_data
arguments: label: D74
data_type: f64

tool: D72: 255

tool: D3: 0.00304

tool: D1: 12.92

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x43]}

tool: D82: 0.5

tool: {"D57": [0xab,0xaa,0xaa,0xaa,0xaa,0xaa,0xda,0x3f]}

tool: D45: 1.055

tool: D74: 0.055

assistant: ```c
__attribute__((const)) unsigned long join(unsigned long fg, unsigned long bg, unsigned long alpha) {
  double t = (double)alpha * linear(fg) + (double)(255 - alpha) * linear(bg);
  t /= 255.;
  if (t <= 0.00304)
    t *= 12.92;
  else
    t = 1.055 * pow(t, 1.0 / 2.4) - 0.055;
  return (unsigned long)(255. * t + 0.5);
}
```
user: What is the c source code of the assembly code below:

```asm
<lh_node_stats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_set_fp@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lh_node_stats_bio@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free@plt>
  jmp    L5
L0:
  nop
L5:
  nop
  leave
  ret
```

assistant: ```c
void lh_node_stats(const _LHASH *lh, FILE *fp) {
  BIO *bp;
  bp = BIO_new(BIO_s_file());
  if (bp == NULL)
    goto end;
  BIO_set_fp(bp, fp, BIO_NOCLOSE);
  lh_node_stats_bio(lh, bp);
  BIO_free(bp);
end:;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lh_node_stats>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%eax
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbx
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <BIO_set_fp@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <lh_node_stats_bio@plt>
  mov    %rbx,%rdi
  call   <BIO_free@plt>
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lh_node_stats(const _LHASH *lh, FILE *fp) {
  BIO *bp;
  bp = BIO_new(BIO_s_file());
  if (bp == NULL)
    goto end;
  BIO_set_fp(bp, fp, BIO_NOCLOSE);
  lh_node_stats_bio(lh, bp);
  BIO_free(bp);
end:;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lh_node_stats>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L2
  mov    %rax,%rbp
  mov    D1(%rip),%rax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <BIO_set_fp@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <lh_node_stats_bio@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <BIO_free@plt>
  nopl   0x0(%rax)
L2:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void lh_node_stats(const _LHASH *lh, FILE *fp) {
  BIO *bp;
  bp = BIO_new(BIO_s_file());
  if (bp == NULL)
    goto end;
  BIO_set_fp(bp, fp, BIO_NOCLOSE);
  lh_node_stats_bio(lh, bp);
  BIO_free(bp);
end:;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lh_node_stats>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <BIO_s_file@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
  mov    D7(%rip),%rax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <BIO_set_fp@plt>
  mov    %r12,%rdi
  mov    %rbp,%rsi
  call   <lh_node_stats_bio@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <BIO_free@plt>
  nopl   0x0(%rax)
L7:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void lh_node_stats(const _LHASH *lh, FILE *fp) {
  BIO *bp;
  bp = BIO_new(BIO_s_file());
  if (bp == NULL)
    goto end;
  BIO_set_fp(bp, fp, BIO_NOCLOSE);
  lh_node_stats_bio(lh, bp);
  BIO_free(bp);
end:;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringToHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L8:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  shl    $0x5,%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rcx,%rax
  mov    %rax,-0x8(%rbp)
L12:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long stringToHash(const char *str) {
  const char *s = str;
  unsigned long hash = 0;
  while (*s != '\0')
    hash = ((hash * 33) ^ (*s++));
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stringToHash>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  mov    $0x0,%eax
L6:
  mov    %rax,%rcx
  shl    $0x5,%rcx
  add    %rcx,%rax
  add    $0x1,%rdi
  movsbq %dl,%rdx
  xor    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L6
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned long stringToHash(const char *str) {
  const char *s = str;
  unsigned long hash = 0;
  while (*s != '\0')
    hash = ((hash * 33) ^ (*s++));
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stringToHash>:
  endbr64
  movsbq (%rdi),%rdx
  xor    %eax,%eax
  test   %dl,%dl
  je     L15
  xchg   %ax,%ax
L0:
  mov    %rax,%rcx
  add    $0x1,%rdi
  shl    $0x5,%rcx
  add    %rcx,%rax
  xor    %rdx,%rax
  movsbq (%rdi),%rdx
  test   %dl,%dl
  jne    L0
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
unsigned long stringToHash(const char *str) {
  const char *s = str;
  unsigned long hash = 0;
  while (*s != '\0')
    hash = ((hash * 33) ^ (*s++));
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stringToHash>:
  endbr64
  movsbq (%rdi),%rdx
  xor    %eax,%eax
  test   %dl,%dl
  je     L2
  xchg   %ax,%ax
L13:
  mov    %rax,%rcx
  add    $0x1,%rdi
  shl    $0x5,%rcx
  add    %rcx,%rax
  xor    %rdx,%rax
  movsbq (%rdi),%rdx
  test   %dl,%dl
  jne    L13
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
unsigned long stringToHash(const char *str) {
  const char *s = str;
  unsigned long hash = 0;
  while (*s != '\0')
    hash = ((hash * 33) ^ (*s++));
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mg_strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %eax,%edi
  call   <lowercase@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    %eax,%edi
  call   <lowercase@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L18:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int mg_strcasecmp(const char *s1, const char *s2) {
  int diff;
  do {
    diff = lowercase(s1++) - lowercase(s2++);
  } while (diff == 0 && s1[-1] != '\0');
  return diff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mg_strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
L11:
  mov    %ebp,%edi
  call   <lowercase@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <lowercase@plt>
  sub    %eax,%ebx
  jne    L17
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbp
  add    $0x1,%r12
  test   %al,%al
  jne    L11
L17:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mg_strcasecmp(const char *s1, const char *s2) {
  int diff;
  do {
    diff = lowercase(s1++) - lowercase(s2++);
  } while (diff == 0 && s1[-1] != '\0');
  return diff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mg_strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L8
L13:
  movzbl 0x0(%rbp),%eax
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %al,%al
  je     L4
L8:
  mov    %ebp,%edi
  call   <lowercase@plt>
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <lowercase@plt>
  sub    %eax,%ebx
  je     L13
L4:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mg_strcasecmp(const char *s1, const char *s2) {
  int diff;
  do {
    diff = lowercase(s1++) - lowercase(s2++);
  } while (diff == 0 && s1[-1] != '\0');
  return diff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mg_strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L7
L25:
  movzbl 0x0(%rbp),%eax
  add    $0x1,%r12
  add    $0x1,%rbp
  test   %al,%al
  je     L10
L7:
  mov    %ebp,%edi
  call   <lowercase@plt>
  mov    %r12d,%edi
  mov    %eax,%ebx
  call   <lowercase@plt>
  sub    %eax,%ebx
  je     L25
L10:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int mg_strcasecmp(const char *s1, const char *s2) {
  int diff;
  do {
    diff = lowercase(s1++) - lowercase(s2++);
  } while (diff == 0 && s1[-1] != '\0');
  return diff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<term_discard_paste>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <term_read_paste@plt>
  mov    %eax,%edi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void term_discard_paste(void) {
  long size;
  free(term_read_paste(&size));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<term_discard_paste>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <term_read_paste@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void term_discard_paste(void) {
  long size;
  free(term_read_paste(&size));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<term_discard_paste>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <term_read_paste@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void term_discard_paste(void) {
  long size;
  free(term_read_paste(&size));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<term_discard_paste>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <term_read_paste@plt>
  mov    %eax,%edi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void term_discard_paste(void) {
  long size;
  free(term_read_paste(&size));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L29:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0x5(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x4(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpb   $0x2f,-0x5(%rbp)
  jle    L2
  cmpb   $0x39,-0x5(%rbp)
  jle    L29
L2:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getnum(s)
char *s;
{
  int a;
  char c;
  a = 0;
  while ((c = *s++) >= '0' && c <= '9') {
    a = a * 10 + c - '0';
  }
  return (a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getnum>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L2
  mov    $0x0,%edx
L3:
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L3
L6:
  mov    %edx,%eax
  ret
L2:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int getnum(s)
char *s;
{
  int a;
  char c;
  a = 0;
  while ((c = *s++) >= '0' && c <= '9') {
    a = a * 10 + c - '0';
  }
  return (a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getnum>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L13
  cs nopw 0x0(%rax,%rax,1)
L9:
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  lea    -0x30(%rax,%rcx,2),%r8d
  movsbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L9
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getnum(s)
char *s;
{
  int a;
  char c;
  a = 0;
  while ((c = *s++) >= '0' && c <= '9') {
    a = a * 10 + c - '0';
  }
  return (a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getnum>:
  endbr64
  movsbl (%rdi),%eax
  lea    0x1(%rdi),%rdx
  xor    %r8d,%r8d
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L18
  cs nopw 0x0(%rax,%rax,1)
L8:
  lea    (%r8,%r8,4),%ecx
  add    $0x1,%rdx
  lea    -0x30(%rax,%rcx,2),%r8d
  movsbl -0x1(%rdx),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L8
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getnum(s)
char *s;
{
  int a;
  char c;
  a = 0;
  while ((c = *s++) >= '0' && c <= '9') {
    a = a * 10 + c - '0';
  }
  return (a);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_missing_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L13:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L6
L32:
  addl   $0x1,-0x4(%rbp)
L34:
  cmpl   $0x8,-0x4(%rbp)
  jle    L13
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int ft_missing_l(int k, int sudoku[9][9], int i) {
  int j;
  j = 0;
  while (j < 9) {
    if (sudoku[i][j] == k)
      return (0);
    j++;
  }
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_missing_l>:
  endbr64
  movslq %edx,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rsi,%rax,4),%rax
  lea    0x24(%rax),%rdx
L5:
  cmp    %edi,(%rax)
  je     L16
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
  mov    $0x1,%eax
  ret
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_missing_l(int k, int sudoku[9][9], int i) {
  int j;
  j = 0;
  while (j < 9) {
    if (sudoku[i][j] == k)
      return (0);
    j++;
  }
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_missing_l>:
  endbr64
  movslq %edx,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rsi,%rax,4),%rax
  lea    0x24(%rax),%rdx
  nopl   0x0(%rax,%rax,1)
L2:
  cmp    %edi,(%rax)
  je     L14
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L2
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_missing_l(int k, int sudoku[9][9], int i) {
  int j;
  j = 0;
  while (j < 9) {
    if (sudoku[i][j] == k)
      return (0);
    j++;
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_missing_l>:
  endbr64
  movslq %edx,%rdx
  lea    (%rdx,%rdx,8),%rax
  lea    (%rsi,%rax,4),%rax
  cmp    (%rax),%edi
  je     L36
  cmp    0x4(%rax),%edi
  je     L36
  cmp    0x8(%rax),%edi
  je     L36
  cmp    0xc(%rax),%edi
  je     L36
  cmp    0x10(%rax),%edi
  je     L36
  cmp    0x14(%rax),%edi
  je     L36
  cmp    0x18(%rax),%edi
  je     L36
  cmp    0x1c(%rax),%edi
  je     L36
  cmp    %edi,0x20(%rax)
  setne  %al
  movzbl %al,%eax
  ret
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_missing_l(int k, int sudoku[9][9], int i) {
  int j;
  j = 0;
  while (j < 9) {
    if (sudoku[i][j] == k)
      return (0);
    j++;
  }
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<SVC_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  jmp    L1
```

assistant: ```c
void __attribute__((section(".after_vectors"), weak)) SVC_Handler(void) {
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<SVC_Handler>:
  endbr64
L8:
  jmp    L8
```

assistant: ```c
void __attribute__((section(".after_vectors"), weak)) SVC_Handler(void) {
  while (1)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SVC_Handler>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
void __attribute__((section(".after_vectors"), weak)) SVC_Handler(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SVC_Handler>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
void __attribute__((section(".after_vectors"), weak)) SVC_Handler(void) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L35
L47:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    $0xf0,%eax
  jg     L29
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x18(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    $0xf0,%eax
  jg     L57
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L47
  jmp    L57
L29:
  nop
L57:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D19
data_type: string

tool: D7: %d %d

tool: D19: %d


assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int i = 1;
  int answer = 0;
  int time = 0;
  while (time + k <= 240 && i <= n) {
    time += 5 * i;
    i++;
    if (time + k > 240)
      break;
    answer++;
  }
  printf("%d\n", answer);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xf0,%esi
  jg     L8
  mov    (%rsp),%r8d
  mov    $0x1,%eax
  mov    $0x0,%edx
  jmp    L51
L16:
  add    $0x1,%eax
L51:
  lea    -0x1(%rax),%edi
  cmp    %eax,%r8d
  jl     L37
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%edx
  lea    (%rdx,%rsi,1),%ecx
  cmp    $0xf0,%ecx
  jle    L16
L37:
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  mov    $0x0,%edi
  jmp    L37
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
type_infered: string
name: disassemble_data
arguments: tag: D6
type_infered: string

tool: D13: %d %d

tool: D6: %d


assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int i = 1;
  int answer = 0;
  int time = 0;
  while (time + k <= 240 && i <= n) {
    time += 5 * i;
    i++;
    if (time + k > 240)
      break;
    answer++;
  }
  printf("%d\n", answer);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0xf0,%esi
  jg     L38
  mov    (%rsp),%edi
  xor    %edx,%edx
  mov    $0x1,%eax
  jmp    L23
  nopl   0x0(%rax)
L1:
  lea    (%rax,%rax,4),%ecx
  add    $0x1,%eax
  add    %ecx,%edx
  lea    (%rdx,%rsi,1),%ecx
  cmp    $0xf0,%ecx
  jg     L7
L23:
  lea    -0x1(%rax),%r8d
  cmp    %eax,%edi
  jge    L1
L7:
  mov    %r8d,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L38:
  xor    %r8d,%r8d
  jmp    L7
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D9: %d %d

tool: D6: %d


assistant: ```c
int main() {
  int n, k;
  scanf("%d %d", &n, &k);
  int i = 1;
  int answer = 0;
  int time = 0;
  while (time + k <= 240 && i <= n) {
    time += 5 * i;
    i++;
    if (time + k > 240)
      break;
    answer++;
  }
  printf("%d\n", answer);
  return 0;
}
```