ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rob>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  je     L23
  jle    L15
  mov    (%rdi),%eax
  cmp    %eax,0x4(%rdi)
  jl     L59
L15:
  cmp    $0x2,%esi
  jle    L3
  lea    -0x3(%rsi),%edx
  mov    %rdi,%rax
  lea    0x4(%rdi,%rdx,4),%r8
  nopl   0x0(%rax,%rax,1)
L30:
  mov    0x4(%rax),%ecx
  mov    0x8(%rax),%edx
  add    (%rax),%edx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  add    $0x4,%rax
  mov    %edx,0x4(%rax)
  cmp    %rax,%r8
  jne    L30
L3:
  movslq %esi,%rsi
  mov    -0x4(%rdi,%rsi,4),%eax
  ret
  nopl   0x0(%rax)
L23:
  ret
  nopl   0x0(%rax)
L59:
  mov    %eax,0x4(%rdi)
  jmp    L15
```

assistant: ```c
int rob(int *nums, int numsSize) {
  int tmp;
  if (numsSize == 0) {
    return 0;
  }
  if (numsSize >= 1 && nums[1] < nums[0]) {
    nums[1] = nums[0];
  }
  for (int i = 2; i < numsSize; i++) {
    tmp = nums[i - 2] + nums[i];
    if (tmp > nums[i - 1]) {
      nums[i] = nums[i - 2] + nums[i];
    } else {
      nums[i] = nums[i - 1];
    }
  }
  return nums[numsSize - 1];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rob>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%rdi
  xor    %eax,%eax
  test   %edi,%edi
  je     L42
  jle    L36
  mov    (%rcx),%eax
  cmp    %eax,0x4(%rcx)
  jl     L18
L36:
  cmp    $0x2,%edi
  jle    L59
  cmp    $0x4,%edi
  jle    L23
  lea    -0x5(%rdi),%eax
  mov    (%rcx),%r8d
  mov    0x4(%rcx),%esi
  mov    $0x4,%edx
  shr    %eax
  lea    0x3(%rax),%r9d
  add    %r9,%r9
L75:
  add    -0x8(%rcx,%rdx,4),%r8d
  movslq %edx,%rax
  cmp    %esi,%r8d
  cmovl  %esi,%r8d
  add    -0x4(%rcx,%rdx,4),%esi
  cmp    %r8d,%esi
  mov    %r8d,-0x8(%rcx,%rdx,4)
  cmovl  %r8d,%esi
  mov    %esi,-0x4(%rcx,%rdx,4)
  add    $0x2,%rdx
  cmp    %r9,%rdx
  jne    L75
  nopw   0x0(%rax,%rax,1)
L5:
  mov    -0x4(%rcx,%rax,4),%esi
  mov    -0x8(%rcx,%rax,4),%edx
  add    (%rcx,%rax,4),%edx
  cmp    %esi,%edx
  cmovl  %esi,%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L5
L59:
  mov    -0x4(%rcx,%rdi,4),%eax
  ret
L42:
  ret
  nopl   0x0(%rax)
L18:
  mov    %eax,0x4(%rcx)
  jmp    L36
L23:
  mov    $0x2,%eax
  jmp    L5
```

assistant: ```c
int rob(int *nums, int numsSize) {
  int tmp;
  if (numsSize == 0) {
    return 0;
  }
  if (numsSize >= 1 && nums[1] < nums[0]) {
    nums[1] = nums[0];
  }
  for (int i = 2; i < numsSize; i++) {
    tmp = nums[i - 2] + nums[i];
    if (tmp > nums[i - 1]) {
      nums[i] = nums[i - 2] + nums[i];
    } else {
      nums[i] = nums[i - 1];
    }
  }
  return nums[numsSize - 1];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L21
L16:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L16
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (((*p) == ' ' || (*p) == '\t' || (*p) == '\n'))
    p++;
  strcpy(s, p);
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L29
  cmp    $0x20,%al
  jne    L21
L29:
  mov    %rbx,%rsi
L31:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L31
  cmp    $0x20,%al
  je     L31
L44:
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
L21:
  mov    %rdi,%rsi
  jmp    L44
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (((*p) == ' ' || (*p) == '\t' || (*p) == '\n'))
    p++;
  strcpy(s, p);
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ltrim>:
  endbr64
  push   %r12
  movzbl (%rdi),%eax
  mov    %rdi,%r12
  mov    %rdi,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  ja     L20
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L27
L20:
  cmp    $0x20,%al
  je     L27
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (((*p) == ' ' || (*p) == '\t' || (*p) == '\n'))
    p++;
  strcpy(s, p);
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ltrim>:
  endbr64
  push   %r12
  movzbl (%rdi),%eax
  mov    %rdi,%r12
  mov    %rdi,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  ja     L7
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  lea    -0x9(%rax),%edx
  cmp    $0x1,%dl
  jbe    L26
L7:
  cmp    $0x20,%al
  je     L26
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ltrim(char *s) {
  char *p = s;
  while (((*p) == ' ' || (*p) == '\t' || (*p) == '\n'))
    p++;
  strcpy(s, p);
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<getch_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <initTermios@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  mov    $0x0,%eax
  call   <resetTermios@plt>
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char getch_(int echo) {
  char ch;
  initTermios(echo);
  ch = getchar();
  resetTermios();
  return ch;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getch_>:
  endbr64
  push   %rbx
  call   <initTermios@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <resetTermios@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char getch_(int echo) {
  char ch;
  initTermios(echo);
  ch = getchar();
  resetTermios();
  return ch;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getch_>:
  endbr64
  push   %r12
  call   <initTermios@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <resetTermios@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char getch_(int echo) {
  char ch;
  initTermios(echo);
  ch = getchar();
  resetTermios();
  return ch;
}
```
user: What is the c source code of the assembly code below:

```asm
<getch_>:
  endbr64
  push   %r12
  call   <initTermios@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <resetTermios@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char getch_(int echo) {
  char ch;
  initTermios(echo);
  ch = getchar();
  resetTermios();
  return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<quicksort_rec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L6
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%r8
  mov    -0x8(%rbp),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <quicksort_rec>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <quicksort_rec>
L6:
  nop
  leave
  ret
```

assistant: ```c
void quicksort_rec(void *base, int begin, int end, size_t size, int (*compare)(const void *, const void *)) {
  int pivot, pivotIndex;
  if (begin < end) {
    pivotIndex = (begin + end) / 2;
    pivot = partition(base, begin, end, size, pivotIndex, compare);
    quicksort_rec(base, begin, pivot - 1, size, compare);
    quicksort_rec(base, pivot + 1, end, size, compare);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quicksort_rec>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
L0:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    %r8,%r15
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  mov    %r15,%r9
  sar    %r8d
  call   <partition@plt>
  mov    %eax,%r14d
  lea    -0x1(%rax),%edx
  mov    %r15,%r8
  mov    %r13,%rcx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <quicksort_rec>
  lea    0x1(%r14),%esi
  mov    %r15,%r8
  mov    %r13,%rcx
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quicksort_rec>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort_rec(void *base, int begin, int end, size_t size, int (*compare)(const void *, const void *)) {
  int pivot, pivotIndex;
  if (begin < end) {
    pivotIndex = (begin + end) / 2;
    pivot = partition(base, begin, end, size, pivotIndex, compare);
    quicksort_rec(base, begin, pivot - 1, size, compare);
    quicksort_rec(base, pivot + 1, end, size, compare);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L15:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void string_reverse(char string[], int n) {
  int i, limit = n / 2;
  for (i = 0; i < limit; i++) {
    char temp = string[i];
    string[i] = string[n - i - 1];
    string[n - i - 1] = temp;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string_reverse>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L15
  movslq %esi,%rsi
  lea    -0x1(%rdi,%rsi,1),%rdx
  mov    $0x0,%eax
L5:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%rdx),%esi
  mov    %sil,(%rdi,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%r8d
  jg     L5
L15:
  ret
```

assistant: ```c
void string_reverse(char string[], int n) {
  int i, limit = n / 2;
  for (i = 0; i < limit; i++) {
    char temp = string[i];
    string[i] = string[n - i - 1];
    string[n - i - 1] = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<string_reverse>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L17
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    -0x1(%rdi,%rsi,1),%rdx
L3:
  movzbl (%rdx),%esi
  movzbl (%rdi,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%r8d
  jg     L3
L17:
  ret
```

assistant: ```c
void string_reverse(char string[], int n) {
  int i, limit = n / 2;
  for (i = 0; i < limit; i++) {
    char temp = string[i];
    string[i] = string[n - i - 1];
    string[n - i - 1] = temp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<string_reverse>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L19
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    -0x1(%rdi,%rsi,1),%rdx
L0:
  movzbl (%rdx),%esi
  movzbl (%rdi,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%r8d
  jg     L0
L19:
  ret
```

assistant: ```c
void string_reverse(char string[], int n) {
  int i, limit = n / 2;
  for (i = 0; i < limit; i++) {
    char temp = string[i];
    string[i] = string[n - i - 1];
    string[n - i - 1] = temp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
L1:
  mov    $0x20000020,%eax
  mov    (%rax),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L1
  mov    $0x20000000,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putchar(int value) {
  while (((*(volatile unsigned int *)(0x20000020)) & 0x02) == 0)
    ;
  *(volatile unsigned int *)(0x20000000) = (value);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putchar>:
  endbr64
L2:
  mov    0x20000020,%eax
  test   $0x2,%al
  je     L2
  mov    %edi,0x20000000
  ret
```

assistant: ```c
void putchar(int value) {
  while (((*(volatile unsigned int *)(0x20000020)) & 0x02) == 0)
    ;
  *(volatile unsigned int *)(0x20000000) = (value);
}
```
user: Translate the below assembly code into C programming language:

```asm
<putchar>:
  endbr64
  nopl   0x0(%rax)
L6:
  mov    0x20000020,%eax
  test   $0x2,%al
  je     L6
  mov    %edi,0x20000000
  ret
```

assistant: ```c
void putchar(int value) {
  while (((*(volatile unsigned int *)(0x20000020)) & 0x02) == 0)
    ;
  *(volatile unsigned int *)(0x20000000) = (value);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<putchar>:
  endbr64
  nopl   0x0(%rax)
L7:
  mov    0x20000020,%eax
  test   $0x2,%al
  je     L7
  mov    %edi,0x20000000
  ret
```

assistant: ```c
void putchar(int value) {
  while (((*(volatile unsigned int *)(0x20000020)) & 0x02) == 0)
    ;
  *(volatile unsigned int *)(0x20000000) = (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L44
  cmpq   $0x1,-0x20(%rbp)
  jne    L45
L44:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <pthread_exit@plt>
L45:
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rdx,%rcx
  mov    D14(%rip),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <pthread_create@plt>
  test   %rax,%rax
  je     L24
  mov    $0x0,%edi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L24:
  mov    -0x10(%rbp),%rdx
  lea    -0x34(%rbp),%rax
  mov    %rdx,%rcx
  mov    D14(%rip),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <pthread_create@plt>
  test   %rax,%rax
  je     L17
  mov    $0x0,%edi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L17:
  mov    -0x38(%rbp),%eax
  lea    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <pthread_join@plt>
  mov    -0x34(%rbp),%eax
  lea    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <pthread_join@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <pthread_exit@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
void *fib(void *args) {
  pthread_t th1, th2;
  intptr_t arg1, arg2;
  intptr_t ret1, ret2;
  intptr_t n = (intptr_t)args;
  int status;
  if (n == 0 || n == 1)
    pthread_exit((void *)n);
  arg1 = n - 1;
  arg2 = n - 2;
  if (pthread_create(&th1, NULL, fib, (void *)arg1) != 0) {
    perror(NULL);
    abort();
  }
  if (pthread_create(&th2, NULL, fib, (void *)arg2) != 0) {
    perror(NULL);
    abort();
  }
  pthread_join(th1, (void **)&ret1);
  pthread_join(th2, (void **)&ret2);
  pthread_exit((void *)(ret1 + ret2));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdi
  jbe    L23
L16:
  lea    -0x2(%rbx),%rbp
  lea    -0x1(%rbx),%rcx
  mov    %rsp,%rdi
  mov    D16(%rip),%rdx
  mov    $0x0,%esi
  call   <pthread_create@plt>
  test   %rax,%rax
  jne    L35
L20:
  lea    0x4(%rsp),%rdi
  mov    %rbp,%rcx
  mov    D16(%rip),%rdx
  mov    $0x0,%esi
  call   <pthread_create@plt>
  test   %rax,%rax
  jne    L24
L54:
  lea    0x8(%rsp),%rsi
  mov    (%rsp),%edi
  call   <pthread_join@plt>
  lea    0x10(%rsp),%rsi
  mov    0x4(%rsp),%edi
  call   <pthread_join@plt>
  mov    0x10(%rsp),%rdi
  add    0x8(%rsp),%rdi
  call   <pthread_exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <pthread_exit@plt>
  jmp    L16
L35:
  mov    $0x0,%edi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L20
L24:
  mov    $0x0,%edi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L54
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *fib(void *args) {
  pthread_t th1, th2;
  intptr_t arg1, arg2;
  intptr_t ret1, ret2;
  intptr_t n = (intptr_t)args;
  int status;
  if (n == 0 || n == 1)
    pthread_exit((void *)n);
  arg1 = n - 1;
  arg2 = n - 2;
  if (pthread_create(&th1, NULL, fib, (void *)arg1) != 0) {
    perror(NULL);
    abort();
  }
  if (pthread_create(&th2, NULL, fib, (void *)arg2) != 0) {
    perror(NULL);
    abort();
  }
  pthread_join(th1, (void **)&ret1);
  pthread_join(th2, (void **)&ret2);
  pthread_exit((void *)(ret1 + ret2));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fib>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdi
  jbe    L25
L42:
  mov    D4(%rip),%r12
  xor    %esi,%esi
  lea    -0x1(%rbx),%rcx
  mov    %rsp,%rdi
  lea    -0x2(%rbx),%r13
  mov    %r12,%rdx
  call   <pthread_create@plt>
  test   %rax,%rax
  jne    L32
L19:
  xor    %esi,%esi
  lea    0x4(%rsp),%rdi
  mov    %r13,%rcx
  mov    %r12,%rdx
  call   <pthread_create@plt>
  test   %rax,%rax
  jne    L45
L6:
  mov    (%rsp),%edi
  lea    0x8(%rsp),%rsi
  call   <pthread_join@plt>
  mov    0x4(%rsp),%edi
  lea    0x10(%rsp),%rsi
  call   <pthread_join@plt>
  mov    0x10(%rsp),%rdi
  add    0x8(%rsp),%rdi
  call   <pthread_exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  xor    %edi,%edi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L19
L45:
  xor    %edi,%edi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L6
L25:
  call   <pthread_exit@plt>
  jmp    L42
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *fib(void *args) {
  pthread_t th1, th2;
  intptr_t arg1, arg2;
  intptr_t ret1, ret2;
  intptr_t n = (intptr_t)args;
  int status;
  if (n == 0 || n == 1)
    pthread_exit((void *)n);
  arg1 = n - 1;
  arg2 = n - 2;
  if (pthread_create(&th1, NULL, fib, (void *)arg1) != 0) {
    perror(NULL);
    abort();
  }
  if (pthread_create(&th2, NULL, fib, (void *)arg2) != 0) {
    perror(NULL);
    abort();
  }
  pthread_join(th1, (void **)&ret1);
  pthread_join(th2, (void **)&ret2);
  pthread_exit((void *)(ret1 + ret2));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fib>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%rdi
  jbe    L65
L49:
  mov    D3(%rip),%r12
  xor    %esi,%esi
  lea    -0x1(%rbx),%rcx
  mov    %rsp,%rdi
  lea    -0x2(%rbx),%r13
  mov    %r12,%rdx
  call   <pthread_create@plt>
  test   %rax,%rax
  jne    L50
L59:
  xor    %esi,%esi
  lea    0x4(%rsp),%rdi
  mov    %r13,%rcx
  mov    %r12,%rdx
  call   <pthread_create@plt>
  test   %rax,%rax
  jne    L1
L48:
  mov    (%rsp),%edi
  lea    0x8(%rsp),%rsi
  call   <pthread_join@plt>
  mov    0x4(%rsp),%edi
  lea    0x10(%rsp),%rsi
  call   <pthread_join@plt>
  mov    0x10(%rsp),%rdi
  add    0x8(%rsp),%rdi
  call   <pthread_exit@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  xor    %edi,%edi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L59
L1:
  xor    %edi,%edi
  call   <perror@plt>
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L48
L65:
  call   <pthread_exit@plt>
  jmp    L49
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *fib(void *args) {
  pthread_t th1, th2;
  intptr_t arg1, arg2;
  intptr_t ret1, ret2;
  intptr_t n = (intptr_t)args;
  int status;
  if (n == 0 || n == 1)
    pthread_exit((void *)n);
  arg1 = n - 1;
  arg2 = n - 2;
  if (pthread_create(&th1, NULL, fib, (void *)arg1) != 0) {
    perror(NULL);
    abort();
  }
  if (pthread_create(&th2, NULL, fib, (void *)arg2) != 0) {
    perror(NULL);
    abort();
  }
  pthread_join(th1, (void **)&ret1);
  pthread_join(th2, (void **)&ret2);
  pthread_exit((void *)(ret1 + ret2));
}
```