ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GetOpenCLCode>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <system@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: sh ../get_opencl_code.sh

assistant: ```c
void GetOpenCLCode(void) {
  int status;
  status = system("sh ../get_opencl_code.sh");
  assert(status == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetOpenCLCode>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <system@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1070 <assert@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: sh ../get_opencl_code.sh

assistant: ```c
void GetOpenCLCode(void) {
  int status;
  status = system("sh ../get_opencl_code.sh");
  assert(status == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ExprEval>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x18(%rsp)
  test   %rdi,%rdi
  je     L2
  mov    %edx,%r13d
  lea    0x1(%rdi),%rbp
  movl   $0x0,0x14(%rsp)
  mov    $0x0,%r14d
  movl   $0x0,0x10(%rsp)
  movabs $0xac2000000000,%r15
  jmp    L177
L173:
  mov    %r14d,%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L176
L121:
  cmpl   $0x0,0x14(%rsp)
  je     L141
L29:
  mov    %r12,(%rsp)
  movl   $0x1,0x14(%rsp)
L148:
  add    $0x1,%rbp
L177:
  mov    %rbp,%r12
  cmpb   $0x0,-0x1(%rbp)
  je     L111
  test   %r13d,%r13d
  jne    L173
L176:
  movzbl -0x1(%r12),%ebx
  cmp    $0x2c,%bl
  je     L121
  cmp    $0x2f,%bl
  ja     L114
  bt     %rbx,%r15
  jb     L118
L114:
  movsbl %bl,%edi
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L148
  mov    $0x1,%eax
  jmp    L108
L141:
  movb   $0x0,-0x1(%r12)
  mov    (%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,0xc(%rsp)
  jmp    L29
L118:
  movb   $0x0,-0x1(%r12)
  mov    (%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,0x10(%rsp)
  sub    $0x25,%ebx
  cmp    $0xa,%bl
  ja     L105
  movzbl %bl,%ebx
  lea    D16(%rip),%rcx
  movslq (%rcx,%rbx,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  mov    0xc(%rsp),%r14d
  imul   0x10(%rsp),%r14d
L105:
  mov    %r14d,0xc(%rsp)
  mov    %r12,(%rsp)
  jmp    L148
  mov    0xc(%rsp),%r14d
  add    0x10(%rsp),%r14d
  jmp    L105
  mov    0xc(%rsp),%r14d
  sub    0x10(%rsp),%r14d
  jmp    L105
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  mov    %eax,%r14d
  jmp    L105
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  mov    %edx,%r14d
  jmp    L105
L2:
  mov    $0x0,%r14d
L111:
  mov    0x18(%rsp),%rax
  mov    %r14d,(%rax)
  mov    $0x0,%eax
L108:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: DEBUG: lv=%d rv=%d acc=%d


assistant: ```c
int ExprEval(char *expr, int *rtn, int debug) {
  char *pe = expr;
  char *ps = expr;
  int lv, rv, acc = (0, 0, 0);
  int flagLV = 0;
  int rc = 0;
  rv = 0;
  while (pe != NULL && *pe != '\000') {
    if (debug != 0) {
      printf("DEBUG: lv=%d rv=%d acc=%d\n", lv, rv, acc);
    }
    if (*pe == ',') {
      if (flagLV == 0) {
        *pe = '\000';
        lv = atoi(ps);
        flagLV = 1;
      }
      ps = pe + 1;
    } else if (*pe == '+' || *pe == '-' || *pe == '/' || *pe == '*' || *pe == '%') {
      char op = *pe;
      *pe = '\000';
      rv = atoi(ps);
      switch (op) {
      case '*':
        acc = (lv * rv);
        break;
      case '+':
        acc = (lv + rv);
        break;
      case '-':
        acc = (lv - rv);
        break;
      case '/':
        acc = (lv / rv);
        break;
      case '%':
        acc = (lv % rv);
        break;
      }
      ps = pe + 1;
      lv = acc;
    } else if (!isdigit(*pe)) {
      return (1);
    }
    ++pe;
  }
  *rtn = acc;
  return (rc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<HTCleanTelnetString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L47
L72:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toascii@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x9,-0xc(%rbp)
  je     L38
  cmpl   $0x1f,-0xc(%rbp)
  jle    L76
  cmpl   $0x7e,-0xc(%rbp)
  jle    L45
  cmpl   $0x9f,-0xc(%rbp)
  jle    L76
L45:
  cmpl   $0xfe,-0xc(%rbp)
  jle    L38
L76:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L47
L38:
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
  mov    $0x0,%eax
L47:
  leave
  ret
```

assistant: ```c
unsigned char HTCleanTelnetString(char *str) {
  char *cur = str;
  if (!str)
    return 0;
  while (*cur) {
    int a = toascii((unsigned char)*cur);
    if (a != 0x9 && (a < 0x20 || (a > 0x7E && a < 0xA0) || a > 0xFE)) {
      ;
      *cur = 0;
      ;
      return 1;
    }
    cur++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<HTCleanTelnetString>:
  endbr64
  test   %rdi,%rdi
  je     L78
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L3
  mov    $0x0,%eax
  jmp    L22
L73:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L26
L3:
  movzbl %dil,%edi
  call   <toascii@plt>
  cmp    $0x9,%eax
  je     L73
  lea    -0x7f(%rax),%edx
  cmp    $0x20,%edx
  jbe    L66
  sub    $0x20,%eax
  cmp    $0xde,%eax
  jbe    L73
L66:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
L22:
  pop    %rbx
  ret
L26:
  mov    $0x0,%eax
  jmp    L22
L78:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char HTCleanTelnetString(char *str) {
  char *cur = str;
  if (!str)
    return 0;
  while (*cur) {
    int a = toascii((unsigned char)*cur);
    if (a != 0x9 && (a < 0x20 || (a > 0x7E && a < 0xA0) || a > 0xFE)) {
      ;
      *cur = 0;
      ;
      return 1;
    }
    cur++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HTCleanTelnetString>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L37
  nopl   (%rax)
L29:
  call   <toascii@plt>
  cmp    $0x9,%eax
  je     L44
  lea    -0x7f(%rax),%edx
  cmp    $0x20,%edx
  jbe    L13
  sub    $0x20,%eax
  cmp    $0xde,%eax
  ja     L13
L44:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L29
L37:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L13:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char HTCleanTelnetString(char *str) {
  char *cur = str;
  if (!str)
    return 0;
  while (*cur) {
    int a = toascii((unsigned char)*cur);
    if (a != 0x9 && (a < 0x20 || (a > 0x7E && a < 0xA0) || a > 0xFE)) {
      ;
      *cur = 0;
      ;
      return 1;
    }
    cur++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<HTCleanTelnetString>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L33
  nopl   (%rax)
L53:
  call   <toascii@plt>
  cmp    $0x9,%eax
  je     L48
  lea    -0x7f(%rax),%edx
  cmp    $0x20,%edx
  jbe    L13
  sub    $0x20,%eax
  cmp    $0xde,%eax
  ja     L13
L48:
  movzbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L53
L33:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L13:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char HTCleanTelnetString(char *str) {
  char *cur = str;
  if (!str)
    return 0;
  while (*cur) {
    int a = toascii((unsigned char)*cur);
    if (a != 0x9 && (a < 0x20 || (a > 0x7E && a < 0xA0) || a > 0xFE)) {
      ;
      *cur = 0;
      ;
      return 1;
    }
    cur++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L38
L34:
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L43
L17:
  nop
L43:
  addl   $0x1,-0x14(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L34
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D14: %d%d

tool: D10: max yueshu=%d

assistant: ```c
int main() {
  int a, b, i, min, yueshu;
  scanf("%d%d", &a, &b);
  min = a < b ? a : b;
  for (i = 1; i <= min; i++) {
    if (a % i == 0 && b % i == 0)
      yueshu = i;
    else
      continue;
  }
  printf("max yueshu=%d", yueshu);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%esi
  cmp    %esi,%edi
  mov    %esi,%r8d
  cmovle %edi,%r8d
  test   %r8d,%r8d
  jle    L28
  add    $0x1,%r8d
  mov    $0x1,%ecx
  jmp    L25
L38:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%ebx
L34:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  je     L28
L25:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L38
  jmp    L34
L28:
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string
name: unpack_data
arguments: tag: D7
type: string

tool: D1: %d%d

tool: D7: max yueshu=%d

assistant: ```c
int main() {
  int a, b, i, min, yueshu;
  scanf("%d%d", &a, &b);
  min = a < b ? a : b;
  for (i = 1; i <= min; i++) {
    if (a % i == 0 && b % i == 0)
      yueshu = i;
    else
      continue;
  }
  printf("max yueshu=%d", yueshu);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%esi
  cmp    %esi,%edi
  mov    %esi,%r8d
  cmovle %edi,%r8d
  test   %r8d,%r8d
  jle    L19
  add    $0x1,%r8d
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L13
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%ebp
L13:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L24
L19:
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string

tool: D17: %d%d

tool: D11: max yueshu=%d

assistant: ```c
int main() {
  int a, b, i, min, yueshu;
  scanf("%d%d", &a, &b);
  min = a < b ? a : b;
  for (i = 1; i <= min; i++) {
    if (a % i == 0 && b % i == 0)
      yueshu = i;
    else
      continue;
  }
  printf("max yueshu=%d", yueshu);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    (%rsp),%esi
  cmp    %esi,%edi
  mov    %esi,%r8d
  cmovle %edi,%r8d
  test   %r8d,%r8d
  jle    L29
  add    $0x1,%r8d
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L31
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%ebp
L31:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  jne    L27
L29:
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D11
data_type: string

tool: D18: %d%d

tool: D11: max yueshu=%d

assistant: ```c
int main() {
  int a, b, i, min, yueshu;
  scanf("%d%d", &a, &b);
  min = a < b ? a : b;
  for (i = 1; i <= min; i++) {
    if (a % i == 0 && b % i == 0)
      yueshu = i;
    else
      continue;
  }
  printf("max yueshu=%d", yueshu);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x3f60a4d,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L59:
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jbe    L48
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  je     L29
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    $0x2,%rax
  lea    -0xc(%rbp),%rcx
  mov    -0x10(%rbp),%edx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0xc(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x2(%rax),%rdx
  movzwl -0x12(%rbp),%eax
  mov    %ax,(%rdx)
  jmp    L1
L29:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L48:
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
L1:
  addl   $0x1,-0x10(%rbp)
L7:
  cmpl   $0x0,-0x10(%rbp)
  je     L59
  mov    -0xc(%rbp),%eax
  lea    0x50edd68c(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x4901c1f2(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x4901c1f2(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  lea    0x4901c1f2(%rax,%rax,1),%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - 981234615U;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        if (state[0UL] != local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] = state[local1] + state[local1];
          state[0UL] += state[0UL];
        }
      } else {
        state[0UL] = state[local1] + state[local1];
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 469123144UL) + 888641092U;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<linha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L8:
  nop
  leave
  ret
```

assistant: ```c
void linha(char *nome) {
  if (nome[strlen(nome) - 1] == '\n') {
    nome[strlen(nome) - 1] = '\0';
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<linha>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L5
L14:
  pop    %rbx
  ret
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L14
```

assistant: ```c
void linha(char *nome) {
  if (nome[strlen(nome) - 1] == '\n') {
    nome[strlen(nome) - 1] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<linha>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L4
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void linha(char *nome) {
  if (nome[strlen(nome) - 1] == '\n') {
    nome[strlen(nome) - 1] = '\0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<linha>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L8
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void linha(char *nome) {
  if (nome[strlen(nome) - 1] == '\n') {
    nome[strlen(nome) - 1] = '\0';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isNumericOk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <strToLong@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  je     L19
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jl     L19
  mov    -0x20(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jle    L27
L19:
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <logMsg@plt>
  mov    $0x0,%eax
  jmp    L17
L27:
  mov    $0x1,%eax
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: Attempt to update numeric config with invalid/out-of-range value of %s (min=%d max=%d)

assistant: ```c
int isNumericOk(char *value, int minValue, int maxValue) {
  long longVal = strToLong(value, -1);
  if ((longVal == -1) || (longVal < minValue) || (longVal > maxValue)) {
    logMsg(4, "Attempt to update numeric config with invalid/out-of-range value of %s (min=%d max=%d)", value, minValue, maxValue);
    return 0;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isNumericOk>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    $0xffffffff,%esi
  call   <strToLong@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L6
  movslq %ebp,%rdx
  cmp    %rax,%rdx
  jg     L6
  movslq %r12d,%rdx
  mov    $0x1,%ecx
  cmp    %rax,%rdx
  jge    L8
L6:
  mov    %r12d,%r8d
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  lea    D2(%rip),%rsi
  mov    $0x4,%edi
  call   <logMsg@plt>
  mov    $0x0,%ecx
L8:
  mov    %ecx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: Attempt to update numeric config with invalid/out-of-range value of %s (min=%d max=%d)

assistant: ```c
int isNumericOk(char *value, int minValue, int maxValue) {
  long longVal = strToLong(value, -1);
  if ((longVal == -1) || (longVal < minValue) || (longVal > maxValue)) {
    logMsg(4, "Attempt to update numeric config with invalid/out-of-range value of %s (min=%d max=%d)", value, minValue, maxValue);
    return 0;
  } else {
    return 1;
  }
}
```