ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<match_pattern>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L126:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  jbe    L83
L108:
  mov    %r15d,%r14d
  add    $0x1,%r15d
  add    %rbp,%r14
  movzbl (%r14),%eax
  cmp    $0x2a,%al
  je     L128
L63:
  cmp    $0x3f,%al
  je     L39
  mov    %ebx,%ecx
  cmp    (%r12,%rcx,1),%al
  je     L39
  mov    %rbp,%rdi
  xor    %r13d,%r13d
  call   <strlen@plt>
  cmp    %r15d,%eax
  ja     L108
L83:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L39:
  add    $0x1,%ebx
  jmp    L126
  nopl   (%rax)
L128:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %r15d,%eax
  ja     L52
  movzbl (%r14),%eax
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %r15d,%r14d
  mov    %ebx,%ecx
  lea    0x0(%rbp,%r14,1),%rax
  lea    (%r12,%rcx,1),%r14
  mov    %rax,0x8(%rsp)
  movzbl (%rax),%eax
  cmp    %al,(%r14)
  jne    L58
  jmp    L126
  nopl   0x0(%rax,%rax,1)
L105:
  lea    0x1(%rbx),%ecx
  mov    0x8(%rsp),%rax
  lea    (%r12,%rcx,1),%r14
  mov    %rcx,%rbx
  movzbl (%r14),%edx
  cmp    %dl,(%rax)
  je     L126
L58:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L105
  mov    0x8(%rsp),%rax
  movzbl (%r14),%esi
  cmp    %sil,(%rax)
  mov    $0x0,%eax
  cmovne %eax,%r13d
  jmp    L126
```

assistant: ```c
int match_pattern(char *string, char *pattern) {
  unsigned int result = 1, i, j = 0;
  for (i = 0; i < strlen(pattern); i++) {
    if (pattern[i] == '*' && i + 1 < strlen(pattern)) {
      while (pattern[i + 1] != string[j] && j < strlen(string))
        j++;
      if (pattern[i + 1] != string[j])
        result = 0;
    } else if (pattern[i] == '?') {
      j++;
    } else {
      if (pattern[i] != string[j])
        result = 0;
      else
        j++;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<LCD_draw_frame_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x6(%rax),%edx
  mov    -0x24(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <LCD_set_pos@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    -0x14(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L67
L38:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L46
L16:
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L75:
  mov    $0x0,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x10(%rbp),%eax
  mov    $0x80,%esi
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    %esi,%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L69
  mov    $0xff,%edx
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  jmp    L4
L69:
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
L4:
  mov    $0xff,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  addl   $0x1,-0x10(%rbp)
L9:
  cmpl   $0x7,-0x10(%rbp)
  jle    L75
  addl   $0x1,-0xc(%rbp)
L46:
  mov    -0x18(%rbp),%eax
  add    $0x53,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L16
  mov    -0x24(%rbp),%eax
  add    %eax,-0x8(%rbp)
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L38
  mov    $0xff,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  nop
  leave
  ret
```

assistant: ```c
void LCD_draw_frame_buffer(int start_row, int start_column, unsigned char *frame_buffer, int column_max) {
  int i, column, row;
  int row_max = (start_row + 6) * column_max;
  LCD_set_pos(0, 0);
  GPIOPinWrite(0x40004000, 0x00000001, 0x00);
  GPIOPinWrite(0x40004000, 0x00000010, 0xff);
  for (row = start_row * column_max; row < row_max; row += column_max) {
    for (column = start_column; column < start_column + 84; column++) {
      for (i = 0; i < 8; i++) {
        GPIOPinWrite(0x40004000, 0x00000008, 0x00);
        if ((*(frame_buffer + row + column)) & 0x80 >> i)
          GPIOPinWrite(0x40004000, 0x00000004, 0xff);
        else
          GPIOPinWrite(0x40004000, 0x00000004, 0x00);
        GPIOPinWrite(0x40004000, 0x00000008, 0xff);
      }
    }
  }
  GPIOPinWrite(0x40004000, 0x00000001, 0xff);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LCD_draw_frame_buffer>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%r15d
  mov    %esi,%r13d
  mov    %esi,0x20(%rsp)
  mov    %rdx,%rbx
  mov    %ecx,%r14d
  mov    %ecx,0x24(%rsp)
  lea    0x6(%rdi),%eax
  imul   %ecx,%eax
  mov    %eax,%ebp
  mov    %eax,0x14(%rsp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <LCD_set_pos@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  imul   %r14d,%r15d
  cmp    %r15d,%ebp
  jle    L10
  mov    %r14d,%eax
  cltq
  mov    %rax,0x18(%rsp)
  movslq %r15d,%rax
  mov    %rax,0x8(%rsp)
  movslq %r13d,%rax
  add    %rbx,%rax
  mov    %rax,0x28(%rsp)
  jmp    L82
L87:
  mov    $0x0,%edx
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
L24:
  mov    $0xff,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  je     L74
L66:
  mov    $0x0,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  movzbl 0x0(%rbp),%edx
  mov    %r12d,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  test   %eax,%edx
  je     L87
  mov    $0xff,%edx
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  jmp    L24
L74:
  add    $0x1,%r13d
  add    $0x1,%rbp
  cmp    %r14d,%r13d
  jg     L72
L59:
  mov    $0x0,%ebx
  jmp    L66
L72:
  add    0x24(%rsp),%r15d
  mov    0x18(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  cmp    %r15d,0x14(%rsp)
  jle    L10
L82:
  mov    0x20(%rsp),%r13d
  lea    0x53(%r13),%r14d
  mov    0x28(%rsp),%rbp
  add    0x8(%rsp),%rbp
  mov    $0x80,%r12d
  jmp    L59
L10:
  mov    $0xff,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void LCD_draw_frame_buffer(int start_row, int start_column, unsigned char *frame_buffer, int column_max) {
  int i, column, row;
  int row_max = (start_row + 6) * column_max;
  LCD_set_pos(0, 0);
  GPIOPinWrite(0x40004000, 0x00000001, 0x00);
  GPIOPinWrite(0x40004000, 0x00000010, 0xff);
  for (row = start_row * column_max; row < row_max; row += column_max) {
    for (column = start_column; column < start_column + 84; column++) {
      for (i = 0; i < 8; i++) {
        GPIOPinWrite(0x40004000, 0x00000008, 0x00);
        if ((*(frame_buffer + row + column)) & 0x80 >> i)
          GPIOPinWrite(0x40004000, 0x00000004, 0xff);
        else
          GPIOPinWrite(0x40004000, 0x00000004, 0x00);
        GPIOPinWrite(0x40004000, 0x00000008, 0xff);
      }
    }
  }
  GPIOPinWrite(0x40004000, 0x00000001, 0xff);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LCD_draw_frame_buffer>:
  endbr64
  push   %r15
  lea    0x6(%rdi),%eax
  mov    %ecx,%r15d
  push   %r14
  imul   %ecx,%eax
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  mov    %eax,%r14d
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %esi,0x10(%rsp)
  xor    %esi,%esi
  mov    %ecx,0x14(%rsp)
  mov    %eax,0xc(%rsp)
  call   <LCD_set_pos@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    %ebp,%ecx
  movslq %r15d,%rax
  imul   %eax,%ecx
  mov    %ecx,0x8(%rsp)
  cmp    %ecx,%r14d
  jle    L1
  mov    %rax,(%rsp)
  movslq %r13d,%rax
  lea    0x53(%r13),%r14d
  movslq %ecx,%r15
  add    %rbx,%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%r13d
  mov    $0x80,%r12d
  lea    (%rax,%r15,1),%rbp
  nopl   0x0(%rax)
L51:
  xor    %ebx,%ebx
  jmp    L19
  nopl   0x0(%rax)
L6:
  mov    $0xff,%edx
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
L15:
  mov    $0xff,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  add    $0x1,%ebx
  call   <GPIOPinWrite@plt>
  cmp    $0x8,%ebx
  je     L48
L19:
  xor    %edx,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    %r12d,%eax
  mov    %ebx,%ecx
  movzbl 0x0(%rbp),%edx
  sar    %cl,%eax
  test   %eax,%edx
  jne    L6
  xor    %edx,%edx
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L48:
  add    $0x1,%r13d
  add    $0x1,%rbp
  cmp    %r13d,%r14d
  jge    L51
  mov    0x14(%rsp),%ecx
  add    (%rsp),%r15
  add    %ecx,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  jg     L4
L1:
  add    $0x28,%rsp
  mov    $0xff,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <GPIOPinWrite@plt>
```

assistant: ```c
void LCD_draw_frame_buffer(int start_row, int start_column, unsigned char *frame_buffer, int column_max) {
  int i, column, row;
  int row_max = (start_row + 6) * column_max;
  LCD_set_pos(0, 0);
  GPIOPinWrite(0x40004000, 0x00000001, 0x00);
  GPIOPinWrite(0x40004000, 0x00000010, 0xff);
  for (row = start_row * column_max; row < row_max; row += column_max) {
    for (column = start_column; column < start_column + 84; column++) {
      for (i = 0; i < 8; i++) {
        GPIOPinWrite(0x40004000, 0x00000008, 0x00);
        if ((*(frame_buffer + row + column)) & 0x80 >> i)
          GPIOPinWrite(0x40004000, 0x00000004, 0xff);
        else
          GPIOPinWrite(0x40004000, 0x00000004, 0x00);
        GPIOPinWrite(0x40004000, 0x00000008, 0xff);
      }
    }
  }
  GPIOPinWrite(0x40004000, 0x00000001, 0xff);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<LCD_draw_frame_buffer>:
  endbr64
  push   %r15
  lea    0x6(%rdi),%eax
  mov    %ecx,%r15d
  push   %r14
  imul   %ecx,%eax
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  mov    %eax,%r14d
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %esi,0x10(%rsp)
  xor    %esi,%esi
  mov    %ecx,0x14(%rsp)
  mov    %eax,0xc(%rsp)
  call   <LCD_set_pos@plt>
  xor    %edx,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x10,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    %ebp,%ecx
  movslq %r15d,%rax
  imul   %eax,%ecx
  mov    %ecx,0x8(%rsp)
  cmp    %ecx,%r14d
  jle    L3
  mov    %rax,(%rsp)
  movslq %r13d,%rax
  lea    0x53(%r13),%r14d
  movslq %ecx,%r15
  add    %rbx,%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L1:
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%r13d
  mov    $0x80,%r12d
  lea    (%rax,%r15,1),%rbp
  nopl   0x0(%rax)
L6:
  xor    %ebx,%ebx
  jmp    L41
  nopl   0x0(%rax)
L24:
  mov    $0xff,%edx
L42:
  mov    $0x4,%esi
  mov    $0x40004000,%edi
  add    $0x1,%ebx
  call   <GPIOPinWrite@plt>
  mov    $0xff,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  cmp    $0x8,%ebx
  je     L37
L41:
  xor    %edx,%edx
  mov    $0x8,%esi
  mov    $0x40004000,%edi
  call   <GPIOPinWrite@plt>
  mov    %r12d,%eax
  mov    %ebx,%ecx
  movzbl 0x0(%rbp),%edx
  sar    %cl,%eax
  test   %eax,%edx
  jne    L24
  xor    %edx,%edx
  jmp    L42
  nopl   0x0(%rax)
L37:
  add    $0x1,%r13d
  add    $0x1,%rbp
  cmp    %r13d,%r14d
  jge    L6
  mov    0x14(%rsp),%ecx
  add    (%rsp),%r15
  add    %ecx,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  jg     L1
L3:
  add    $0x28,%rsp
  mov    $0xff,%edx
  mov    $0x1,%esi
  mov    $0x40004000,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <GPIOPinWrite@plt>
```

assistant: ```c
void LCD_draw_frame_buffer(int start_row, int start_column, unsigned char *frame_buffer, int column_max) {
  int i, column, row;
  int row_max = (start_row + 6) * column_max;
  LCD_set_pos(0, 0);
  GPIOPinWrite(0x40004000, 0x00000001, 0x00);
  GPIOPinWrite(0x40004000, 0x00000010, 0xff);
  for (row = start_row * column_max; row < row_max; row += column_max) {
    for (column = start_column; column < start_column + 84; column++) {
      for (i = 0; i < 8; i++) {
        GPIOPinWrite(0x40004000, 0x00000008, 0x00);
        if ((*(frame_buffer + row + column)) & 0x80 >> i)
          GPIOPinWrite(0x40004000, 0x00000004, 0xff);
        else
          GPIOPinWrite(0x40004000, 0x00000004, 0x00);
        GPIOPinWrite(0x40004000, 0x00000008, 0xff);
      }
    }
  }
  GPIOPinWrite(0x40004000, 0x00000001, 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L29
  mov    $0xffffffff,%eax
  jmp    L20
L29:
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L16
  mov    $0x1,%eax
  jmp    L20
L16:
  mov    $0x0,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int sign(double a) {
  if (a < 0) {
    return -1;
  }
  if (a > 0) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sign>:
  endbr64
  mov    $0xffffffff,%eax
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  ja     L8
  comisd %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int sign(double a) {
  if (a < 0) {
    return -1;
  }
  if (a > 0) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sign>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm0,%xmm1
  ja     L6
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L6:
  ret
```

assistant: ```c
int sign(double a) {
  if (a < 0) {
    return -1;
  }
  if (a > 0) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sign>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%eax
  comisd %xmm0,%xmm1
  ja     L0
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L0:
  ret
```

assistant: ```c
int sign(double a) {
  if (a < 0) {
    return -1;
  }
  if (a > 0) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  je     L1
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L1:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D5
data_type: string

tool: D15: usage %s <v1> <v2>


tool: D5: %d+%d=%d


assistant: ```c
int main(int argc, char *args[]) {
  int i = 0;
  if (argc != 3) {
    printf("usage %s <v1> <v2>\n", args[0]);
    exit(1);
  }
  int v1 = atoi(args[1]);
  int v2 = atoi(args[2]);
  printf("%d+%d=%d\n", v1, v2, v1 + v2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  cmp    $0x3,%edi
  jne    L1
L2:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  mov    0x10(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  lea    0x0(%rbp,%rax,1),%ecx
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    (%rsi),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D17
data_type: string

tool: D2: %d+%d=%d


tool: D17: usage %s <v1> <v2>


assistant: ```c
int main(int argc, char *args[]) {
  int i = 0;
  if (argc != 3) {
    printf("usage %s <v1> <v2>\n", args[0]);
    exit(1);
  }
  int v1 = atoi(args[1]);
  int v2 = atoi(args[2]);
  printf("%d+%d=%d\n", v1, v2, v1 + v2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L5
  mov    (%rsi),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  lea    0x0(%rbp,%rax,1),%ecx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type: string
name: unpack_data
arguments: tag: D6
type: string

tool: D16: usage %s <v1> <v2>


tool: D6: %d+%d=%d


assistant: ```c
int main(int argc, char *args[]) {
  int i = 0;
  if (argc != 3) {
    printf("usage %s <v1> <v2>\n", args[0]);
    exit(1);
  }
  int v1 = atoi(args[1]);
  int v2 = atoi(args[2]);
  printf("%d+%d=%d\n", v1, v2, v1 + v2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  je     L5
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  mov    0x10(%rbx),%rdi
  mov    %eax,%ebp
  call   <atoi@plt>
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  lea    0x0(%rbp,%rax,1),%ecx
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D5
data_type: string

tool: D0: usage %s <v1> <v2>


tool: D5: %d+%d=%d


assistant: ```c
int main(int argc, char *args[]) {
  int i = 0;
  if (argc != 3) {
    printf("usage %s <v1> <v2>\n", args[0]);
    exit(1);
  }
  int v1 = atoi(args[1]);
  int v2 = atoi(args[2]);
  printf("%d+%d=%d\n", v1, v2, v1 + v2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L32:
  mov    -0x20(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzwl (%rax),%eax
  cwtl
  cmp    %eax,-0x14(%rbp)
  jg     L18
  mov    -0x4(%rbp),%eax
  jmp    L22
L18:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L32
  mov    -0x18(%rbp),%eax
L22:
  pop    %rbp
  ret
```

assistant: ```c
int search(int val, short *table, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (val <= *table++)
      return i;
  }
  return size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<search>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L6
  mov    %edx,%r10d
  mov    $0x0,%ecx
L4:
  movswl (%rsi,%rcx,2),%r8d
  cmp    %edi,%r8d
  jge    L24
  add    $0x1,%rcx
  cmp    %r10,%rcx
  jne    L4
  ret
L24:
  mov    %ecx,%eax
L6:
  ret
```

assistant: ```c
int search(int val, short *table, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (val <= *table++)
      return i;
  }
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<search>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L8
  movslq %edx,%r9
  xor    %ecx,%ecx
  jmp    L33
  nopl   0x0(%rax)
L16:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  je     L20
L33:
  movswl (%rsi,%rcx,2),%r8d
  cmp    %edi,%r8d
  jl     L16
  mov    %ecx,%eax
L8:
  ret
  xchg   %ax,%ax
L20:
  ret
```

assistant: ```c
int search(int val, short *table, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (val <= *table++)
      return i;
  }
  return size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<search>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  jle    L9
  movslq %edx,%r9
  xor    %ecx,%ecx
  jmp    L13
  nopl   0x0(%rax)
L37:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  je     L31
L13:
  movswl (%rsi,%rcx,2),%r8d
  cmp    %edi,%r8d
  jl     L37
  mov    %ecx,%eax
L9:
  ret
  xchg   %ax,%ax
L31:
  ret
```

assistant: ```c
int search(int val, short *table, int size) {
  int i;
  for (i = 0; i < size; i++) {
    if (val <= *table++)
      return i;
  }
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pathconN_nm5_name_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  cmpl   $0x1,-0x4(%rbp)
  je     L26
  jmp    L3
L2:
  lea    D8(%rip),%rax
  jmp    L18
L26:
  lea    D16(%rip),%rax
  jmp    L18
L3:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string

tool: D8: o0

tool: D16: o1

assistant: ```c
const char *pathconN_nm5_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pathconN_nm5_name_out>:
  endbr64
  lea    D15(%rip),%rax
  test   %edi,%edi
  je     L4
  cmp    $0x1,%edi
  lea    D6(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L4:
  ret
```

tool_calls: name: read_data
arguments: data_label: D15
type: string
name: read_data
arguments: data_label: D6
type: string

tool: D15: o0

tool: D6: o1

assistant: ```c
const char *pathconN_nm5_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pathconN_nm5_name_out>:
  endbr64
  lea    D19(%rip),%rax
  test   %edi,%edi
  je     L5
  cmp    $0x1,%edi
  lea    D2(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
L5:
  ret
```

tool_calls: name: read_data
arguments: tag: D19
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string

tool: D19: o0

tool: D2: o1

assistant: ```c
const char *pathconN_nm5_name_out(int i) {
  switch (i) {
  case 0:
    return "o0";
  case 1:
    return "o1";
  default:
    return 0;
  }
}
```