ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isdblquote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x22,-0x4(%rbp)
  jne    L19
  mov    $0x1,%eax
  jmp    L9
L19:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int isdblquote(int c) {
  if (c == '"') {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<isdblquote>:
  endbr64
  cmp    $0x22,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isdblquote(int c) {
  if (c == '"') {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isdblquote>:
  endbr64
  xor    %eax,%eax
  cmp    $0x22,%edi
  sete   %al
  ret
```

assistant: ```c
int isdblquote(int c) {
  if (c == '"') {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isdblquote>:
  endbr64
  xor    %eax,%eax
  cmp    $0x22,%edi
  sete   %al
  ret
```

assistant: ```c
int isdblquote(int c) {
  if (c == '"') {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_quoted>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x22,%edi
  call   <putchar@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L17
L8:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L39
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L33
L39:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  addl   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  mov    $0x22,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: %s

assistant: ```c
void print_quoted(char *path, char *quote) {
  int len = strlen(path);
  printf("\"");
  for (int i = 0; i < len; i++) {
    if (path[i] != '"') {
      printf("%c", path[i]);
    } else {
      printf("%s", quote);
    }
  }
  printf("\"");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_quoted>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    $0x22,%edi
  call   <putchar@plt>
  test   %r13d,%r13d
  jle    L32
  mov    %rbp,%rbx
  lea    -0x1(%r13),%eax
  lea    0x1(%rbp,%rax,1),%rbp
  lea    D0(%rip),%r13
  jmp    L2
L23:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L32
L2:
  movzbl (%rbx),%edi
  cmp    $0x22,%dil
  je     L23
  movsbl %dil,%edi
  call   <putchar@plt>
  jmp    L9
L32:
  mov    $0x22,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %s

assistant: ```c
void print_quoted(char *path, char *quote) {
  int len = strlen(path);
  printf("\"");
  for (int i = 0; i < len; i++) {
    if (path[i] != '"') {
      printf("%c", path[i]);
    } else {
      printf("%s", quote);
    }
  }
  printf("\"");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_quoted>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x22,%edi
  mov    %eax,%ebp
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%eax
  lea    D0(%rip),%r13
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L3:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L0
L43:
  movsbl (%rbx),%edi
  cmp    $0x22,%dil
  jne    L3
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L43
L0:
  add    $0x8,%rsp
  mov    $0x22,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: %s

assistant: ```c
void print_quoted(char *path, char *quote) {
  int len = strlen(path);
  printf("\"");
  for (int i = 0; i < len; i++) {
    if (path[i] != '"') {
      printf("%c", path[i]);
    } else {
      printf("%s", quote);
    }
  }
  printf("\"");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_quoted>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    $0x22,%edi
  mov    %eax,%ebp
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L36
  lea    -0x1(%rbp),%eax
  lea    D2(%rip),%r13
  lea    0x1(%rbx,%rax,1),%rbp
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L31:
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L36
L27:
  movsbl (%rbx),%edi
  cmp    $0x22,%dil
  jne    L31
  mov    %r12,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L27
L36:
  add    $0x8,%rsp
  mov    $0x22,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string

tool: D2: %s

assistant: ```c
void print_quoted(char *path, char *quote) {
  int len = strlen(path);
  printf("\"");
  for (int i = 0; i < len; i++) {
    if (path[i] != '"') {
      printf("%c", path[i]);
    } else {
      printf("%s", quote);
    }
  }
  printf("\"");
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrixmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9,-0x48(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L10
L1:
  movl   $0x0,-0x1c(%rbp)
  jmp    L5
L50:
  mov    -0x20(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0x18(%rbp)
  jmp    L13
L39:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ebx
  mov    -0x18(%rbp),%eax
  imul   -0x3c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%eax
  imul   -0x38(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  add    %ecx,%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mul@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  xor    %ebx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x18(%rbp)
L13:
  mov    -0x38(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L39
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x3c(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L50
  addl   $0x1,-0x20(%rbp)
L10:
  mov    -0x34(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L1
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void matrixmul(unsigned char a[], unsigned char b[], int m, int n, int k, unsigned char c[]) {
  int i, j, l, u;
  for (i = 0; i <= m - 1; i++) {
    for (j = 0; j <= k - 1; j++) {
      u = i * k + j;
      c[u] = 0;
      for (l = 0; l <= n - 1; l++)
        c[u] = c[u] ^ (mul(a[i * n + l], b[l * k + j]));
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrixmul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,0x30(%rsp)
  mov    %rsi,0x38(%rsp)
  mov    %edx,0x54(%rsp)
  mov    %ecx,0x28(%rsp)
  mov    %r8d,0x1c(%rsp)
  mov    %r9,0x58(%rsp)
  test   %edx,%edx
  jle    L20
  movl   $0x0,0x50(%rsp)
  movl   $0x0,0x4c(%rsp)
  movl   $0x0,0x48(%rsp)
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  mov    %rax,0x40(%rsp)
  jmp    L26
L28:
  mov    0x50(%rsp),%eax
  mov    %eax,0x2c(%rsp)
  movslq 0x4c(%rsp),%rax
  mov    0x58(%rsp),%rcx
  lea    (%rcx,%rax,1),%r15
  mov    0x1c(%rsp),%eax
  mov    %rax,0x20(%rsp)
  movq   $0x0,0x10(%rsp)
L60:
  mov    %r15,%r13
  movb   $0x0,(%r15)
  cmpl   $0x0,0x28(%rsp)
  jle    L27
  movslq 0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x38(%rsp),%r12
  add    0x10(%rsp),%r12
  movslq 0x2c(%rsp),%r14
  mov    0x30(%rsp),%rax
  lea    (%rax,%r14,1),%rbx
  add    0x40(%rsp),%r14
L58:
  movzbl 0x0(%r13),%ebp
  movzbl (%r12),%esi
  movzbl (%rbx),%edi
  call   <mul@plt>
  xor    %eax,%ebp
  mov    %bpl,0x0(%r13)
  add    0x8(%rsp),%r12
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L58
L27:
  addq   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%rax
  add    $0x1,%r15
  cmp    0x20(%rsp),%rax
  jne    L60
L21:
  addl   $0x1,0x48(%rsp)
  mov    0x48(%rsp),%eax
  mov    0x1c(%rsp),%edx
  add    %edx,0x4c(%rsp)
  mov    0x28(%rsp),%edx
  add    %edx,0x50(%rsp)
  cmp    %eax,0x54(%rsp)
  je     L20
L26:
  cmpl   $0x0,0x1c(%rsp)
  jg     L28
  jmp    L21
L20:
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixmul(unsigned char a[], unsigned char b[], int m, int n, int k, unsigned char c[]) {
  int i, j, l, u;
  for (i = 0; i <= m - 1; i++) {
    for (j = 0; j <= k - 1; j++) {
      u = i * k + j;
      c[u] = 0;
      for (l = 0; l <= n - 1; l++)
        c[u] = c[u] ^ (mul(a[i * n + l], b[l * k + j]));
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrixmul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rsi,0x28(%rsp)
  mov    %edx,0x44(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %r8d,0x10(%rsp)
  mov    %r9,0x48(%rsp)
  test   %edx,%edx
  jle    L2
  lea    -0x1(%rcx),%eax
  movl   $0x0,0x40(%rsp)
  lea    0x1(%rdi,%rax,1),%rax
  movl   $0x0,0x38(%rsp)
  movl   $0x0,0x3c(%rsp)
  mov    %rax,0x30(%rsp)
  nopl   0x0(%rax,%rax,1)
L65:
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L42
  mov    0x10(%rsp),%eax
  movslq 0x40(%rsp),%rbp
  movq   $0x0,0x8(%rsp)
  add    0x48(%rsp),%rbp
  sub    $0x1,%eax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax,%rax,1)
L68:
  mov    0x14(%rsp),%edx
  movb   $0x0,0x0(%rbp)
  test   %edx,%edx
  jle    L21
  movslq 0x38(%rsp),%rbx
  mov    0x20(%rsp),%rax
  xor    %r14d,%r14d
  movslq 0x10(%rsp),%r12
  mov    0x28(%rsp),%r13
  lea    (%rax,%rbx,1),%r15
  add    0x8(%rsp),%r13
  add    0x30(%rsp),%rbx
  nopl   0x0(%rax)
L40:
  movzbl 0x0(%r13),%esi
  movzbl (%r15),%edi
  add    $0x1,%r15
  add    %r12,%r13
  call   <mul@plt>
  xor    %eax,%r14d
  mov    %r14b,0x0(%rbp)
  cmp    %rbx,%r15
  jne    L40
L21:
  mov    0x8(%rsp),%rdx
  add    $0x1,%rbp
  lea    0x1(%rdx),%rax
  cmp    0x18(%rsp),%rdx
  je     L42
  mov    %rax,0x8(%rsp)
  jmp    L68
  nopl   0x0(%rax)
L42:
  mov    0x14(%rsp),%edx
  addl   $0x1,0x3c(%rsp)
  add    %edx,0x38(%rsp)
  mov    0x3c(%rsp),%eax
  mov    0x10(%rsp),%edx
  add    %edx,0x40(%rsp)
  cmp    %eax,0x44(%rsp)
  jne    L65
L2:
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixmul(unsigned char a[], unsigned char b[], int m, int n, int k, unsigned char c[]) {
  int i, j, l, u;
  for (i = 0; i <= m - 1; i++) {
    for (j = 0; j <= k - 1; j++) {
      u = i * k + j;
      c[u] = 0;
      for (l = 0; l <= n - 1; l++)
        c[u] = c[u] ^ (mul(a[i * n + l], b[l * k + j]));
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matrixmul>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,0x20(%rsp)
  mov    %edx,0x3c(%rsp)
  mov    %ecx,0x10(%rsp)
  test   %edx,%edx
  jle    L2
  movslq %r8d,%r12
  test   %r12d,%r12d
  jle    L2
  lea    -0x1(%rcx),%eax
  mov    %r9,0x30(%rsp)
  lea    0x1(%rdi,%rax,1),%rax
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x38(%rsp)
  mov    %rax,0x28(%rsp)
  nopw   0x0(%rax,%rax,1)
L56:
  movq   $0x0,0x8(%rsp)
  mov    0x30(%rsp),%rbp
  xchg   %ax,%ax
L58:
  mov    0x10(%rsp),%eax
  movb   $0x0,0x0(%rbp)
  test   %eax,%eax
  jle    L32
  movslq 0x14(%rsp),%rbx
  mov    0x18(%rsp),%rax
  xor    %r15d,%r15d
  mov    0x20(%rsp),%r13
  add    0x8(%rsp),%r13
  lea    (%rax,%rbx,1),%r14
  add    0x28(%rsp),%rbx
  nopl   0x0(%rax)
L3:
  movzbl 0x0(%r13),%esi
  movzbl (%r14),%edi
  add    $0x1,%r14
  add    %r12,%r13
  call   <mul@plt>
  xor    %eax,%r15d
  mov    %r15b,0x0(%rbp)
  cmp    %r14,%rbx
  jne    L3
L32:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  add    $0x1,%rbp
  cmp    %r12,%rax
  jne    L58
  addl   $0x1,0x38(%rsp)
  mov    0x10(%rsp),%edx
  add    %r12,0x30(%rsp)
  mov    0x38(%rsp),%eax
  add    %edx,0x14(%rsp)
  cmp    %eax,0x3c(%rsp)
  jne    L56
L2:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixmul(unsigned char a[], unsigned char b[], int m, int n, int k, unsigned char c[]) {
  int i, j, l, u;
  for (i = 0; i <= m - 1; i++) {
    for (j = 0; j <= k - 1; j++) {
      u = i * k + j;
      c[u] = 0;
      for (l = 0; l <= n - 1; l++)
        c[u] = c[u] ^ (mul(a[i * n + l], b[l * k + j]));
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L42
L20:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L32
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L56
L32:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rbx
  lea    0x4(%rbx),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  subl   $0x1,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L42
L56:
  addq   $0x1,-0x28(%rbp)
L42:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  cmpl   $0x0,-0x34(%rbp)
  jne    L20
L39:
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int string_split(char *str, int *n, int nlen) {
  char *ptr = str;
  while (*str && nlen) {
    if (*str == ' ' || *str == '\n') {
      *str++ = 0;
      *n++ = atoi(ptr);
      nlen--;
      ptr = str;
    } else
      str++;
  }
  return nlen;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<string_split>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebp
  movzbl (%rdi),%eax
  test   %edx,%edx
  je     L24
  mov    %rsi,%r13
  test   %al,%al
  je     L24
  lea    0x1(%rdi),%rbx
  jmp    L6
L34:
  mov    %rbx,%r12
  movb   $0x0,-0x1(%rbx)
  lea    0x4(%r13),%r14
  call   <atoi@plt>
  mov    %eax,0x0(%r13)
  sub    $0x1,%ebp
  mov    %rbx,%rdi
  mov    %r14,%r13
L17:
  movzbl (%r12),%eax
  add    $0x1,%rbx
  test   %ebp,%ebp
  je     L24
  test   %al,%al
  je     L24
L6:
  cmp    $0x20,%al
  je     L34
  mov    %rbx,%r12
  cmp    $0xa,%al
  jne    L17
  jmp    L34
L24:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int string_split(char *str, int *n, int nlen) {
  char *ptr = str;
  while (*str && nlen) {
    if (*str == ' ' || *str == '\n') {
      *str++ = 0;
      *n++ = atoi(ptr);
      nlen--;
      ptr = str;
    } else
      str++;
  }
  return nlen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L72
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %edx,%edx
  je     L61
  nopl   0x0(%rax)
L1:
  add    $0x1,%rbx
  cmp    $0x20,%cl
  je     L79
  cmp    $0xa,%cl
  je     L79
  movzbl (%rbx),%ecx
  test   %cl,%cl
  jne    L1
L72:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  movb   $0x0,-0x1(%rbx)
  lea    0x4(%r12),%r13
  sub    $0x1,%ebp
  call   <atoi@plt>
  mov    %eax,(%r12)
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L72
  test   %ebp,%ebp
  je     L61
  mov    %rbx,%rdi
  mov    %r13,%r12
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L61:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int string_split(char *str, int *n, int nlen) {
  char *ptr = str;
  while (*str && nlen) {
    if (*str == ' ' || *str == '\n') {
      *str++ = 0;
      *n++ = atoi(ptr);
      nlen--;
      ptr = str;
    } else
      str++;
  }
  return nlen;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_split>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L62
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %edx,%edx
  je     L21
  nopl   0x0(%rax)
L36:
  add    $0x1,%rbx
  cmp    $0x20,%cl
  je     L8
  cmp    $0xa,%cl
  je     L8
  movzbl (%rbx),%ecx
  test   %cl,%cl
  jne    L36
L62:
  add    $0x8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  movb   $0x0,-0x1(%rbx)
  lea    0x4(%r12),%r13
  sub    $0x1,%ebp
  call   <atoi@plt>
  mov    %eax,(%r12)
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L62
  test   %ebp,%ebp
  je     L21
  mov    %rbx,%rdi
  mov    %r13,%r12
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int string_split(char *str, int *n, int nlen) {
  char *ptr = str;
  while (*str && nlen) {
    if (*str == ' ' || *str == '\n') {
      *str++ = 0;
      *n++ = atoi(ptr);
      nlen--;
      ptr = str;
    } else
      str++;
  }
  return nlen;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L4
L8:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D12: %d

tool: D11: %d 

assistant: ```c
int main() {
  int i = 1, n = 0, a = 0, b = 1, c = 0;
  scanf("%d", &n);
  for (i; i <= n; i++) {
    c = a + b;
    a = b;
    b = c;
    printf("%d ", c);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L3
  mov    $0x1,%ebp
  mov    $0x0,%eax
  mov    $0x1,%ebx
  lea    D17(%rip),%r13
  jmp    L13
L9:
  mov    %r12d,%ebp
L13:
  lea    (%rax,%rbp,1),%r12d
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  mov    %ebp,%eax
  cmp    %ebx,0x4(%rsp)
  jge    L9
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
type_guessed: string
name: disassemble_data
arguments: data_label: D17
type_guessed: string

tool: D14: %d

tool: D17: %d 

assistant: ```c
int main() {
  int i = 1, n = 0, a = 0, b = 1, c = 0;
  scanf("%d", &n);
  for (i; i <= n; i++) {
    c = a + b;
    a = b;
    b = c;
    printf("%d ", c);
  }
  printf("\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  mov    $0x1,%ebp
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D16(%rip),%r13
  jmp    L10
  nopl   0x0(%rax)
L14:
  mov    %r12d,%ebp
L10:
  lea    (%rax,%rbp,1),%r12d
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %ebp,%eax
  cmp    %ebx,0x4(%rsp)
  jge    L14
L30:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type_guessed: string
name: retrieve_data
arguments: data_label: D16
type_guessed: string

tool: D1: %d

tool: D16: %d 

assistant: ```c
int main() {
  int i = 1, n = 0, a = 0, b = 1, c = 0;
  scanf("%d", &n);
  for (i; i <= n; i++) {
    c = a + b;
    a = b;
    b = c;
    printf("%d ", c);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movl   $0x0,0x4(%rsp)
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L36
  mov    $0x1,%ebp
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D17(%rip),%r13
  jmp    L21
  nopl   0x0(%rax)
L6:
  mov    %r12d,%ebp
L21:
  lea    (%rax,%rbp,1),%r12d
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %ebp,%eax
  cmp    %ebx,0x4(%rsp)
  jge    L6
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string

tool: D3: %d

tool: D17: %d 

assistant: ```c
int main() {
  int i = 1, n = 0, a = 0, b = 1, c = 0;
  scanf("%d", &n);
  for (i; i <= n; i++) {
    c = a + b;
    a = b;
    b = c;
    printf("%d ", c);
  }
  printf("\n");
  return 0;
}
```