ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrixMultF>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,-0x28(%rsp)
  mov    %edx,-0x1c(%rsp)
  mov    %r9,-0x18(%rsp)
  test   %edx,%edx
  jle    L56
  mov    %r8d,%ebp
  test   %r8d,%r8d
  jle    L56
  mov    %rdi,%rbx
  movslq %r8d,%r15
  mov    %ecx,%r10d
  xor    %r14d,%r14d
  lea    0x4(%rbx),%rax
  xor    %r13d,%r13d
  pxor   %xmm2,%xmm2
  xor    %r12d,%r12d
  mov    %rax,-0x8(%rsp)
  lea    -0x1(%rcx),%eax
  lea    0x0(,%r15,4),%rdi
  mov    %rax,-0x10(%rsp)
  nop
L4:
  mov    -0x18(%rsp),%rax
  mov    -0x8(%rsp),%rsi
  xor    %r8d,%r8d
  mov    -0x28(%rsp),%r9
  lea    (%rax,%r14,4),%rcx
  movslq %r13d,%rax
  lea    (%rbx,%rax,4),%r11
  add    -0x10(%rsp),%rax
  lea    (%rsi,%rax,4),%rsi
  cs nopw 0x0(%rax,%rax,1)
L44:
  movl   $0x0,(%rcx)
  mov    %r9,%rdx
  mov    %r11,%rax
  movaps %xmm2,%xmm1
  test   %r10d,%r10d
  jle    L25
  nopl   0x0(%rax)
L26:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rdi,%rdx
  addss  %xmm0,%xmm1
  movss  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L26
L25:
  add    $0x1,%r8d
  add    $0x4,%rcx
  add    $0x4,%r9
  cmp    %r8d,%ebp
  jne    L44
  add    $0x1,%r12d
  add    %r10d,%r13d
  add    %r15,%r14
  cmp    %r12d,-0x1c(%rsp)
  jne    L4
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixMultF(float *matrixA, float *matrixB, int numRowsA, int numColsA, int numColsB, float *matrixC) {
  int i, j, k;
  for (i = 0; i < numRowsA; i++)
    for (j = 0; j < numColsB; j++) {
      matrixC[numColsB * i + j] = 0;
      for (k = 0; k < numColsA; k++)
        matrixC[numColsB * i + j] = matrixC[numColsB * i + j] + matrixA[numColsA * i + k] * matrixB[numColsB * k + j];
    }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.

assistant: ```c
int main() {
  puts("This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string

tool: D4: This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.

assistant: ```c
int main() {
  puts("This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.

assistant: ```c
int main() {
  puts("This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.

assistant: ```c
int main() {
  puts("This is a test progam that pulls in all of the Sandford libraries to ensure they all compile successfully, it does not do anything.");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<delimit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L24
  mov    -0xc(%rbp),%eax
  jmp    L34
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L37
  mov    -0x8(%rbp),%eax
  jmp    L34
L37:
  mov    -0x4(%rbp),%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int delimit(int val, int min, int max) {
  if (val > max)
    return max;
  if (val < min)
    return min;
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<delimit>:
  endbr64
  cmp    %esi,%edi
  cmovge %edi,%esi
  cmp    %edx,%edi
  mov    %edx,%eax
  cmovle %esi,%eax
  ret
```

assistant: ```c
int delimit(int val, int min, int max) {
  if (val > max)
    return max;
  if (val < min)
    return min;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<delimit>:
  endbr64
  cmp    %esi,%edi
  mov    %edx,%eax
  cmovge %edi,%esi
  cmp    %edx,%edi
  cmovle %esi,%eax
  ret
```

assistant: ```c
int delimit(int val, int min, int max) {
  if (val > max)
    return max;
  if (val < min)
    return min;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delimit>:
  endbr64
  cmp    %esi,%edi
  mov    %edx,%eax
  cmovge %edi,%esi
  cmp    %edx,%edi
  cmovle %esi,%eax
  ret
```

assistant: ```c
int delimit(int val, int min, int max) {
  if (val > max)
    return max;
  if (val < min)
    return min;
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intToStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  movb   $0x0,-0x1(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L47
L43:
  cmpl   $0x0,-0x14(%rbp)
  jle    L15
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L53
L15:
  movzbl -0x1(%rbp),%eax
  cmp    -0x18(%rbp),%al
  jae    L36
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x30,(%rax)
L53:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L47:
  cmpb   $0x31,-0x1(%rbp)
  jbe    L43
  jmp    L52
L36:
  nop
L52:
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <reverse@plt>
  movzbl -0x1(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char intToStr(int x, char str[], unsigned char d) {
  unsigned char i = 0;
  for (i = 0; i < 50; i++) {
    if (x > 0) {
      str[i] = (x % 10) + '0';
      x = x / 10;
    } else {
      if (i < d)
        str[i] = '0';
      else
        break;
    }
  }
  reverse(str, i);
  str[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intToStr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ecx
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  jmp    L28
L38:
  cmp    %bl,%dl
  jbe    L4
  movb   $0x30,(%rsi)
L30:
  add    $0x1,%ebx
  add    $0x1,%rsi
  cmp    $0x32,%bl
  je     L4
L28:
  test   %ecx,%ecx
  jle    L38
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rsi)
  mov    %eax,%ecx
  jmp    L30
L4:
  movzbl %bl,%esi
  mov    %rbp,%rdi
  call   <reverse@plt>
  movzbl %bl,%eax
  movb   $0x0,0x0(%rbp,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char intToStr(int x, char str[], unsigned char d) {
  unsigned char i = 0;
  for (i = 0; i < 50; i++) {
    if (x > 0) {
      str[i] = (x % 10) + '0';
      x = x / 10;
    } else {
      if (i < d)
        str[i] = '0';
      else
        break;
    }
  }
  reverse(str, i);
  str[i] = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<intToStr>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L55
  nopl   0x0(%rax)
L28:
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%ecx
  mov    %ecx,%esi
  mov    %eax,%ecx
  add    $0x30,%esi
  mov    %sil,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x32,%rbx
  je     L48
L55:
  mov    %ebx,%r12d
  test   %ecx,%ecx
  jg     L28
  cmp    %dl,%bl
  jae    L54
  mov    $0x30,%esi
  mov    %sil,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x32,%rbx
  jne    L55
L48:
  mov    $0x32,%esi
  mov    $0x32,%r12d
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L54:
  movzbl %bl,%esi
L24:
  mov    %rbp,%rdi
  call   <reverse@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned char intToStr(int x, char str[], unsigned char d) {
  unsigned char i = 0;
  for (i = 0; i < 50; i++) {
    if (x > 0) {
      str[i] = (x % 10) + '0';
      x = x / 10;
    } else {
      if (i < d)
        str[i] = '0';
      else
        break;
    }
  }
  reverse(str, i);
  str[i] = '\0';
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<intToStr>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  mov    %edx,%r8d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,%r12d
  test   %ecx,%ecx
  jle    L99
  nopl   0x0(%rax)
L83:
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x22,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%ecx
  mov    %ecx,%esi
  mov    %eax,%ecx
  add    $0x30,%esi
  mov    %sil,0x0(%rbp,%rbx,1)
  cmp    $0x31,%rbx
  je     L0
  add    $0x1,%rbx
  mov    %ebx,%r12d
  test   %ecx,%ecx
  jg     L83
L99:
  cmp    %bl,%dl
  jbe    L12
  movb   $0x30,0x0(%rbp,%rbx,1)
  cmp    $0x31,%rbx
  je     L0
  add    $0x1,%rbx
  jmp    L94
  xchg   %ax,%ax
L79:
  movb   $0x30,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  mov    %ebx,%r12d
  cmp    $0x32,%bl
  je     L35
L94:
  mov    %ebx,%r12d
  cmp    %bl,%r8b
  ja     L79
L12:
  movzbl %r12b,%esi
L27:
  mov    %rbp,%rdi
  call   <reverse@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x32,%ebx
  mov    $0x32,%esi
  mov    $0x32,%r12d
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L35:
  mov    $0x32,%ebx
  mov    $0x32,%esi
  jmp    L27
```

assistant: ```c
unsigned char intToStr(int x, char str[], unsigned char d) {
  unsigned char i = 0;
  for (i = 0; i < 50; i++) {
    if (x > 0) {
      str[i] = (x % 10) + '0';
      x = x / 10;
    } else {
      if (i < d)
        str[i] = '0';
      else
        break;
    }
  }
  reverse(str, i);
  str[i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L15:
  movl   $0x2,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L0:
  cmpl   $0x9,-0x14(%rbp)
  jle    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  int *p;
  while (i < 10) {
    int x = 2;
    i++;
    p = &x;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  int *p;
  while (i < 10) {
    int x = 2;
    i++;
    p = &x;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  int *p;
  while (i < 10) {
    int x = 2;
    i++;
    p = &x;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i = 0;
  int *p;
  while (i < 10) {
    int x = 2;
    i++;
    p = &x;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<synth_4to1_mono>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x44(%rbp)
  lea    -0x44(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <synth_4to1@plt>
  mov    %eax,-0x3c(%rbp)
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rax,-0x60(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L22
L19:
  mov    -0x38(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x60(%rbp),%rax
  mov    %dx,(%rax)
  addq   $0x2,-0x60(%rbp)
  addq   $0x4,-0x38(%rbp)
  addl   $0x1,-0x40(%rbp)
L22:
  cmpl   $0x7,-0x40(%rbp)
  jle    L19
  mov    -0x68(%rbp),%rax
  mov    (%rax),%eax
  lea    0x10(%rax),%edx
  mov    -0x68(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x3c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int synth_4to1_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[16];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_4to1(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < 8; i++) {
    *((short *)samples) = *tmp1;
    samples += 2;
    tmp1 += 2;
  }
  *pnt += 16;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<synth_4to1_mono>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  call   <synth_4to1@plt>
  movslq (%r12),%rdx
  lea    0x0(%rbp,%rdx,1),%rcx
  mov    %rbx,%rdx
  lea    0x30(%rsp),%rdi
L2:
  movzwl (%rdx),%esi
  mov    %si,(%rcx)
  add    $0x2,%rcx
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L2
  addl   $0x10,(%r12)
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synth_4to1_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[16];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_4to1(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < 8; i++) {
    *((short *)samples) = *tmp1;
    samples += 2;
    tmp1 += 2;
  }
  *pnt += 16;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<synth_4to1_mono>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xc(%rsp),%rcx
  movl   $0x0,0xc(%rsp)
  mov    %rbx,%rdx
  call   <synth_4to1@plt>
  movslq (%r12),%rdx
  lea    0x30(%rsp),%rdi
  mov    %rdx,%r8
  lea    0x0(%rbp,%rdx,1),%rcx
  mov    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L15:
  movzwl (%rdx),%esi
  add    $0x4,%rdx
  add    $0x2,%rcx
  mov    %si,-0x2(%rcx)
  cmp    %rdi,%rdx
  jne    L15
  add    $0x10,%r8d
  mov    %r8d,(%r12)
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synth_4to1_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[16];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_4to1(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < 8; i++) {
    *((short *)samples) = *tmp1;
    samples += 2;
    tmp1 += 2;
  }
  *pnt += 16;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<synth_4to1_mono>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  movl   $0x0,0xc(%rsp)
  call   <synth_4to1@plt>
  movdqa 0x10(%rsp),%xmm0
  movslq (%rbx),%rcx
  movdqa %xmm0,%xmm1
  punpcklwd 0x20(%rsp),%xmm0
  punpckhwd 0x20(%rsp),%xmm1
  mov    %rcx,%rdx
  add    $0x10,%edx
  movdqa %xmm0,%xmm2
  punpcklwd %xmm1,%xmm0
  punpckhwd %xmm1,%xmm2
  punpcklwd %xmm2,%xmm0
  movups %xmm0,0x0(%rbp,%rcx,1)
  mov    %edx,(%rbx)
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int synth_4to1_mono(double *bandPtr, unsigned char *samples, int *pnt) {
  short samples_tmp[16];
  short *tmp1 = samples_tmp;
  int i, ret;
  int pnt1 = 0;
  ret = synth_4to1(bandPtr, 0, (unsigned char *)samples_tmp, &pnt1);
  samples += *pnt;
  for (i = 0; i < 8; i++) {
    *((short *)samples) = *tmp1;
    samples += 2;
    tmp1 += 2;
  }
  *pnt += 16;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xc,-0x30(%rbp)
  movl   $0xf,-0x2c(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <dotest@plt>
  movl   $0xf,-0x30(%rbp)
  movl   $0x15,-0x2c(%rbp)
  movl   $0x18,-0x28(%rbp)
  movl   $0x1e,-0x24(%rbp)
  movl   $0x2d,-0x20(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <dotest@plt>
  movl   $0x6b,-0x30(%rbp)
  movl   $0x9e,-0x2c(%rbp)
  movl   $0xcc,-0x28(%rbp)
  movl   $0x64,-0x24(%rbp)
  movl   $0x76,-0x20(%rbp)
  movl   $0x7b,-0x1c(%rbp)
  movl   $0x7e,-0x18(%rbp)
  movl   $0x6e,-0x14(%rbp)
  movl   $0x74,-0x10(%rbp)
  movl   $0x64,-0xc(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <dotest@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D8
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D18: (2 12)(3 27)(5 15)

tool: D8: (2 54)(3 135)(5 90)(7 21)

tool: D6: (2 1032)(3 453)(5 310)(7 126)(11 110)(17 204)(29 116)(41 123)(59 118)(79 158)(107 107)

assistant: ```c
int main() {
  {
    int d1[2] = {12, 15};
    char *sol1 = "(2 12)(3 27)(5 15)";
    dotest(d1, 2, sol1);
  }
  {
    int d1[5] = {15, 21, 24, 30, 45};
    char *sol1 = "(2 54)(3 135)(5 90)(7 21)";
    dotest(d1, 5, sol1);
  }
  {
    int d1[10] = {107, 158, 204, 100, 118, 123, 126, 110, 116, 100};
    char *sol1 = "(2 1032)(3 453)(5 310)(7 126)(11 110)(17 204)(29 116)(41 123)(59 118)(79 158)(107 107)";
    dotest(d1, 10, sol1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xc,(%rsp)
  movl   $0xf,0x4(%rsp)
  mov    %rsp,%rbx
  lea    D28(%rip),%rdx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <dotest@plt>
  movl   $0xf,(%rsp)
  movl   $0x15,0x4(%rsp)
  movl   $0x18,0x8(%rsp)
  movl   $0x1e,0xc(%rsp)
  movl   $0x2d,0x10(%rsp)
  lea    D11(%rip),%rdx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <dotest@plt>
  movl   $0x6b,(%rsp)
  movl   $0x9e,0x4(%rsp)
  movl   $0xcc,0x8(%rsp)
  movl   $0x64,0xc(%rsp)
  movl   $0x76,0x10(%rsp)
  movl   $0x7b,0x14(%rsp)
  movl   $0x7e,0x18(%rsp)
  movl   $0x6e,0x1c(%rsp)
  movl   $0x74,0x20(%rsp)
  movl   $0x64,0x24(%rsp)
  lea    D15(%rip),%rdx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <dotest@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D28
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string
name: extract_symbolic_data
arguments: data_label: D15
data_type: string

tool: D28: (2 12)(3 27)(5 15)

tool: D11: (2 54)(3 135)(5 90)(7 21)

tool: D15: (2 1032)(3 453)(5 310)(7 126)(11 110)(17 204)(29 116)(41 123)(59 118)(79 158)(107 107)

assistant: ```c
int main() {
  {
    int d1[2] = {12, 15};
    char *sol1 = "(2 12)(3 27)(5 15)";
    dotest(d1, 2, sol1);
  }
  {
    int d1[5] = {15, 21, 24, 30, 45};
    char *sol1 = "(2 54)(3 135)(5 90)(7 21)";
    dotest(d1, 5, sol1);
  }
  {
    int d1[10] = {107, 158, 204, 100, 118, 123, 126, 110, 116, 100};
    char *sol1 = "(2 1032)(3 453)(5 310)(7 126)(11 110)(17 204)(29 116)(41 123)(59 118)(79 158)(107 107)";
    dotest(d1, 10, sol1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdx
  mov    $0x2,%esi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xf0000000c,%rax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  call   <dotest@plt>
  lea    D19(%rip),%rdx
  mov    %rbp,%rdi
  movabs $0x150000000f,%rax
  mov    %rax,(%rsp)
  mov    $0x5,%esi
  movabs $0x1e00000018,%rax
  mov    %rax,0x8(%rsp)
  movl   $0x2d,0x10(%rsp)
  call   <dotest@plt>
  lea    D4(%rip),%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  movabs $0x9e0000006b,%rax
  mov    %rax,(%rsp)
  movabs $0x64000000cc,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x7b00000076,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x6e0000007e,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6400000074,%rax
  mov    %rax,0x20(%rsp)
  call   <dotest@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string
name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D2: (2 12)(3 27)(5 15)

tool: D19: (2 54)(3 135)(5 90)(7 21)

tool: D4: (2 1032)(3 453)(5 310)(7 126)(11 110)(17 204)(29 116)(41 123)(59 118)(79 158)(107 107)

assistant: ```c
int main() {
  {
    int d1[2] = {12, 15};
    char *sol1 = "(2 12)(3 27)(5 15)";
    dotest(d1, 2, sol1);
  }
  {
    int d1[5] = {15, 21, 24, 30, 45};
    char *sol1 = "(2 54)(3 135)(5 90)(7 21)";
    dotest(d1, 5, sol1);
  }
  {
    int d1[10] = {107, 158, 204, 100, 118, 123, 126, 110, 116, 100};
    char *sol1 = "(2 1032)(3 453)(5 310)(7 126)(11 110)(17 204)(29 116)(41 123)(59 118)(79 158)(107 107)";
    dotest(d1, 10, sol1);
  }
}
```