user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%rdi
  lea    D11(%rip),%r13
  push   %r12
  lea    D51(%rip),%r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  lea    D35(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x18(%rsp),%rcx
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L0:
  movss  0x18(%rsp),%xmm3
  comiss %xmm3,%xmm1
  ja     L17
L15:
  pxor   %xmm2,%xmm2
  mov    %rbx,%rdi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mov    $0x3,%eax
  cvtss2sd %xmm3,%xmm2
  call   <printf@plt>
L2:
  movss  0x10(%rsp),%xmm0
  movss  0x14(%rsp),%xmm1
  movss  0x18(%rsp),%xmm2
  comiss %xmm0,%xmm1
  jb     L39
  comiss %xmm1,%xmm2
  jae    L6
L39:
  mov    %rbp,%rdi
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm2
  mov    $0x3,%eax
  call   <printf@plt>
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L0
  pxor   %xmm3,%xmm3
  pxor   %xmm2,%xmm2
  mov    %r13,%rdi
  mov    $0x3,%eax
  cvtss2sd %xmm1,%xmm3
  movss  %xmm1,0x10(%rsp)
  pxor   %xmm1,%xmm1
  cvtss2sd 0x18(%rsp),%xmm2
  cvtss2sd %xmm0,%xmm1
  movss  %xmm0,0x14(%rsp)
  movapd %xmm3,%xmm0
  call   <printf@plt>
  movss  0x14(%rsp),%xmm1
  movss  0x18(%rsp),%xmm3
  movss  0x10(%rsp),%xmm0
  comiss %xmm3,%xmm1
  jbe    L15
L17:
  pxor   %xmm2,%xmm2
  movss  %xmm1,0x18(%rsp)
  mov    %r12,%rdi
  mov    $0x3,%eax
  cvtss2sd %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  movss  %xmm3,0x14(%rsp)
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm1
  call   <printf@plt>
  movss  0x18(%rsp),%xmm3
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  jmp    L15
  nopl   0x0(%rax)
L6:
  pxor   %xmm0,%xmm0
  lea    D32(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D51
type_infered: string
name: parse_data
arguments: tag: D22
type_infered: string
name: parse_data
arguments: tag: D35
type_infered: string
name: parse_data
arguments: tag: D38
type_infered: string
name: parse_data
arguments: tag: D32
type_infered: string

tool: D18: Please enter three numbers separated by spaces > 

tool: D11: Swap 2 & 1 for %f, %f, %f


tool: D51: Swap 2 & 3 for %f, %f, %f


tool: D22: Before swaps:  %f, %f, %f


tool: D35: After swaps: %f, %f, %f


tool: D38: %f%f%f

tool: D32: %.0f is the median


assistant: ```c
int main() {
  float data[3], temp = 0;
  printf("Please enter three numbers separated by spaces > ");
  scanf("%f%f%f", &data[1], &data[2], &data[3]);
  while (!((data[1] <= data[2]) && (data[2] <= data[3]))) {
    printf("Before swaps:  %f, %f, %f\n", data[1], data[2], data[3]);
    if (data[2] < data[1]) {
      temp = data[2];
      data[2] = data[1];
      data[1] = temp;
      printf("Swap 2 & 1 for %f, %f, %f\n", data[1], data[2], data[3]);
    }
    if (data[3] < data[2]) {
      temp = data[2];
      data[2] = data[3];
      data[3] = temp;
      printf("Swap 2 & 3 for %f, %f, %f\n", data[1], data[2], data[3]);
    }
    printf("After swaps: %f, %f, %f\n", data[1], data[2], data[3]);
  }
  printf("%.0f is the median\n", data[2]);
  return 0;
}
```