ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mob_class_change>:
  endbr64
  push   %r15
  lea    D5(%rip),%r15
  mov    %rdi,%rcx
  xor    %eax,%eax
  push   %r14
  mov    %rsi,%r14
  mov    $0xa22,%esi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  mov    %r15,%rdx
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <nullpo_chk@plt>
  test   %eax,%eax
  je     L15
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %r14,%rcx
  mov    %r15,%rdx
  mov    $0xa23,%esi
  mov    %rbp,%rdi
  call   <nullpo_chk@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L36
  test   %r12d,%r12d
  jle    L36
  mov    %r14,%rbp
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,%r12d
  je     L0
L54:
  mov    0x0(%rbp),%edi
  xor    %eax,%eax
  call   <mobdb_checkid@plt>
  test   %eax,%eax
  jne    L42
  test   %ebx,%ebx
  je     L36
  mov    %ebx,%r12d
L0:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r13,%rdi
  sar    $0x8,%eax
  xor    %ebx,%eax
  cltd
  idiv   %r12d
  xor    %eax,%eax
  movslq %edx,%rdx
  mov    (%r14,%rdx,4),%esi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <mob_class_change_id@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D18
type: string

tool: D5: mob_class_change

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/map/mob.c

assistant: ```c
int mob_class_change(struct mob_data *md, const int *value, int value_count) {
  int count = 0;
  if (nullpo_chk("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/map/mob.c", 2594, __FUNCTION__, (void *)(md))) {
    return (0);
  };
  if (nullpo_chk("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AurigaProject/root/refs/heads/master/src/map/mob.c", 2595, __FUNCTION__, (void *)(value))) {
    return (0);
  };
  while (count < value_count && mobdb_checkid(value[count])) {
    count++;
  }
  if (count <= 0)
    return 0;
  return mob_class_change_id(md, value[(rand() ^ (rand() >> 8)) % count]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L31
L12:
  movl   $0x0,-0x4(%rbp)
  jmp    L23
L17:
  addl   $0x1,-0x4(%rbp)
L23:
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x4(%rbp),%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
uint len(char *str) {
  if (str == NULL) {
    return 0;
  }
  int l = 0;
  while (*(++str) != '\0') {
    l++;
  }
  return l;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<len>:
  endbr64
  test   %rdi,%rdi
  je     L30
  lea    0x1(%rdi),%rcx
  cmpb   $0x0,0x1(%rdi)
  je     L42
  mov    %rcx,%rax
  mov    $0x1,%edx
  sub    %ecx,%edx
L11:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L11
L28:
  mov    %ecx,%eax
  ret
L30:
  mov    $0x0,%ecx
  jmp    L28
L42:
  mov    $0x0,%ecx
  jmp    L28
```

assistant: ```c
uint len(char *str) {
  if (str == NULL) {
    return 0;
  }
  int l = 0;
  while (*(++str) != '\0') {
    l++;
  }
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<len>:
  endbr64
  test   %rdi,%rdi
  je     L20
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L20
  mov    $0x1,%edx
  sub    %eax,%edx
  nopw   0x0(%rax,%rax,1)
L11:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L11
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L20:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint len(char *str) {
  if (str == NULL) {
    return 0;
  }
  int l = 0;
  while (*(++str) != '\0') {
    l++;
  }
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<len>:
  endbr64
  test   %rdi,%rdi
  je     L29
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L29
  mov    $0x1,%edx
  sub    %eax,%edx
  nopw   0x0(%rax,%rax,1)
L5:
  lea    (%rdx,%rax,1),%r8d
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L5
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L29:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint len(char *str) {
  if (str == NULL) {
    return 0;
  }
  int l = 0;
  while (*(++str) != '\0') {
    l++;
  }
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x24(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x14,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <islandPerimeter@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D37
datatype: string

tool: D37: %d


assistant: ```c
int main() {
  int i = 10;
  int *pInt;
  int **ppInt;
  int **ppInt2;
  ppInt2 = (int **)malloc(sizeof(int));
  pInt = &i;
  ppInt = &pInt;
  ppInt2 = &pInt;
  printf("%d\n", i);
  printf("%d\n", *pInt);
  printf("%d\n", **ppInt);
  printf("%d\n", **ppInt2);
  islandPerimeter(ppInt, 10, 20);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xa,0xc(%rsp)
  mov    $0x4,%edi
  call   <malloc@plt>
  lea    0xc(%rsp),%rax
  mov    %rax,0x10(%rsp)
  mov    0xc(%rsp),%esi
  lea    D7(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x14,%edx
  mov    $0xa,%esi
  call   <islandPerimeter@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main() {
  int i = 10;
  int *pInt;
  int **ppInt;
  int **ppInt2;
  ppInt2 = (int **)malloc(sizeof(int));
  pInt = &i;
  ppInt = &pInt;
  ppInt2 = &pInt;
  printf("%d\n", i);
  printf("%d\n", *pInt);
  printf("%d\n", **ppInt);
  printf("%d\n", **ppInt2);
  islandPerimeter(ppInt, 10, 20);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  lea    D2(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xa,0xc(%rsp)
  call   <malloc@plt>
  mov    0xc(%rsp),%esi
  lea    0xc(%rsp),%rax
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x14,%edx
  mov    $0xa,%esi
  call   <islandPerimeter@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main() {
  int i = 10;
  int *pInt;
  int **ppInt;
  int **ppInt2;
  ppInt2 = (int **)malloc(sizeof(int));
  pInt = &i;
  ppInt = &pInt;
  ppInt2 = &pInt;
  printf("%d\n", i);
  printf("%d\n", *pInt);
  printf("%d\n", **ppInt);
  printf("%d\n", **ppInt2);
  islandPerimeter(ppInt, 10, 20);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  lea    D0(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xa,0xc(%rsp)
  call   <malloc@plt>
  mov    0xc(%rsp),%esi
  lea    0xc(%rsp),%rax
  mov    %rbp,%rdi
  mov    %rax,0x10(%rsp)
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x14,%edx
  mov    $0xa,%esi
  call   <islandPerimeter@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
datatype: string

tool: D0: %d


assistant: ```c
int main() {
  int i = 10;
  int *pInt;
  int **ppInt;
  int **ppInt2;
  ppInt2 = (int **)malloc(sizeof(int));
  pInt = &i;
  ppInt = &pInt;
  ppInt2 = &pInt;
  printf("%d\n", i);
  printf("%d\n", *pInt);
  printf("%d\n", **ppInt);
  printf("%d\n", **ppInt2);
  islandPerimeter(ppInt, 10, 20);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  movw   $0xffff,-0x2(%rbp)
  jmp    L34
L49:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x2(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0x2(%rbp)
  movb   $0x0,-0x3(%rbp)
  jmp    L39
L56:
  movzwl -0x2(%rbp),%eax
  test   %ax,%ax
  jns    L53
  movzwl -0x2(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%ax
  jmp    L5
L53:
  movzwl -0x2(%rbp),%eax
  add    %eax,%eax
L5:
  mov    %ax,-0x2(%rbp)
  movzbl -0x3(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x3(%rbp)
L39:
  cmpb   $0x7,-0x3(%rbp)
  jbe    L56
L34:
  movzwl -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x1c(%rbp)
  test   %ax,%ax
  jne    L49
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short crc16(unsigned char *pcBlock, unsigned short len) {
  unsigned short crc = 0xFFFF;
  unsigned char i;
  while (len--) {
    crc ^= *pcBlock++ << 8;
    for (i = 0; i < 8; i++)
      crc = crc & 0x8000 ? (crc << 1) ^ 0x1021 : crc << 1;
  }
  return crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crc16>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %si,%si
  je     L22
  movzwl %ax,%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0xffffffff,%eax
  jmp    L2
L4:
  cmp    %r8,%rdi
  je     L39
L2:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L42:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  lea    (%rax,%rax,1),%esi
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%cl
  jne    L42
  jmp    L4
L39:
  ret
L22:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short crc16(unsigned char *pcBlock, unsigned short len) {
  unsigned short crc = 0xFFFF;
  unsigned char i;
  while (len--) {
    crc ^= *pcBlock++ << 8;
    for (i = 0; i < 8; i++)
      crc = crc & 0x8000 ? (crc << 1) ^ 0x1021 : crc << 1;
  }
  return crc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crc16>:
  endbr64
  test   %si,%si
  je     L0
  movzwl %si,%esi
  mov    $0xffffffff,%eax
  lea    (%rdi,%rsi,1),%r8
  nopl   (%rax)
L28:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    $0x8,%ecx
  shl    $0x8,%edx
  xor    %edx,%eax
  nopl   0x0(%rax)
L24:
  lea    (%rax,%rax,1),%edx
  lea    (%rax,%rax,1),%esi
  xor    $0x1021,%dx
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%cl
  jne    L24
  cmp    %rdi,%r8
  jne    L28
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short crc16(unsigned char *pcBlock, unsigned short len) {
  unsigned short crc = 0xFFFF;
  unsigned char i;
  while (len--) {
    crc ^= *pcBlock++ << 8;
    for (i = 0; i < 8; i++)
      crc = crc & 0x8000 ? (crc << 1) ^ 0x1021 : crc << 1;
  }
  return crc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crc16>:
  endbr64
  mov    %rdi,%rcx
  test   %si,%si
  je     L99
  movzwl %si,%esi
  mov    $0xffffffff,%eax
  add    %rdi,%rsi
  jmp    L10
  nopl   (%rax)
L152:
  lea    (%rax,%rax,1),%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L18
L53:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L49
L9:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L151
L28:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L116
L29:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L85
L8:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L141
L148:
  add    %edx,%edx
  mov    %edx,%edi
L161:
  lea    (%rdx,%rdx,1),%r8d
  mov    %r8d,%eax
  xor    $0x1021,%ax
  test   %di,%di
  mov    %eax,%edx
  mov    %r8d,%eax
  cmovs  %edx,%eax
  cmp    %rcx,%rsi
  je     L97
L10:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  shl    $0x8,%edx
  xor    %dx,%ax
  jns    L152
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L53
L18:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L9
L49:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L28
L151:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L29
L116:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L8
L85:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L148
L141:
  lea    (%rdx,%rdx,1),%edi
  xor    $0x1021,%di
  mov    %edi,%edx
  jmp    L161
  nopl   0x0(%rax,%rax,1)
L97:
  ret
L99:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short crc16(unsigned char *pcBlock, unsigned short len) {
  unsigned short crc = 0xFFFF;
  unsigned char i;
  while (len--) {
    crc ^= *pcBlock++ << 8;
    for (i = 0; i < 8; i++)
      crc = crc & 0x8000 ? (crc << 1) ^ 0x1021 : crc << 1;
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L17
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
  jmp    L3
L17:
  nop
L3:
  leave
  ret
```

assistant: ```c
void quickSort(int A[], int s, int e) {
  int index;
  if (s >= e)
    return;
  index = partition(A, s, e);
  quickSort(A, s, index - 1);
  quickSort(A, index + 1, e);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quickSort>:
  endbr64
  cmp    %edx,%esi
  jl     L7
  ret
L7:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quickSort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quickSort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quickSort(int A[], int s, int e) {
  int index;
  if (s >= e)
    return;
  index = partition(A, s, e);
  quickSort(A, s, index - 1);
  quickSort(A, index + 1, e);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L51:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L51
  sub    $0xc70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c50(%rbp),%rax
  mov    $0x9c40,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x2,-0x9c50(%rbp)
  movl   $0x3,-0x9c60(%rbp)
  movl   $0x1,-0x9c5c(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x9c64(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L69
L50:
  movl   $0x0,-0x9c58(%rbp)
  movl   $0x2,-0x9c54(%rbp)
  jmp    L21
L106:
  mov    -0x9c60(%rbp),%eax
  cltd
  idivl  -0x9c54(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L71
  movl   $0x1,-0x9c58(%rbp)
  jmp    L103
L71:
  addl   $0x1,-0x9c54(%rbp)
L21:
  mov    -0x9c54(%rbp),%eax
  cmp    -0x9c60(%rbp),%eax
  jl     L106
L103:
  cmpl   $0x0,-0x9c58(%rbp)
  jne    L95
  mov    -0x9c5c(%rbp),%eax
  cltq
  mov    -0x9c60(%rbp),%edx
  mov    %edx,-0x9c50(%rbp,%rax,4)
  addl   $0x1,-0x9c5c(%rbp)
L95:
  addl   $0x1,-0x9c60(%rbp)
L69:
  mov    -0x9c64(%rbp),%eax
  cmp    %eax,-0x9c60(%rbp)
  jl     L50
  mov    -0x9c5c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x9c64(%rbp),%eax
  lea    -0x9c50(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <isPrime@plt>
  cmp    $0x1,%eax
  jne    L26
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L68
L26:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L68:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D17
type_infered: string
name: read_data
arguments: data_label: D7
type_infered: string

tool: D0: Enter a number to judge if it is a Prime:

tool: D16: %d

tool: D17: Not a Prime


tool: D7: Yes, it is a Prime


assistant: ```c
int main() {
  int input_num;
  int Primes[10000] = {2};
  int prime_test = 3;
  int cnt = 1;
  printf("Enter a number to judge if it is a Prime:");
  scanf("%d", &input_num);
  while (prime_test < input_num) {
    int judge_Prime = 0;
    for (int i = 2; i < prime_test; i++) {
      if (prime_test % i == 0) {
        judge_Prime = 1;
        break;
      }
    }
    if (judge_Prime == 0) {
      Primes[cnt] = prime_test;
      cnt++;
    }
    prime_test++;
  }
  if (isPrime(input_num, Primes, cnt - 1) == 1) {
    printf("Not a Prime\n");
  } else {
    printf("Yes, it is a Prime\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    -0x9000(%rsp),%r11
L35:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L35
  sub    $0xc68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x9c40,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movl   $0x2,0x10(%rsp)
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    $0x1,%edi
  mov    $0x3,%esi
  cmp    $0x3,%r8d
  jg     L68
L80:
  lea    -0x1(%rdi),%edx
  lea    0x10(%rsp),%rsi
  mov    %r8d,%edi
  call   <isPrime@plt>
  cmp    $0x1,%eax
  je     L36
  lea    D23(%rip),%rdi
  call   <printf@plt>
L65:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  mov    $0x0,%eax
  add    $0x9c68,%rsp
  ret
L36:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L73:
  movslq %edi,%rax
  mov    %esi,0x10(%rsp,%rax,4)
  add    $0x1,%edi
L98:
  add    $0x1,%esi
  cmp    %r8d,%esi
  je     L80
L68:
  cmp    $0x2,%esi
  jle    L73
  test   $0x1,%sil
  je     L98
  mov    $0x2,%ecx
L9:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  je     L73
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L9
  jmp    L98
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D33
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string
name: extract_symbolic_data
arguments: data_tag: D23
data_type: string
name: extract_symbolic_data
arguments: data_tag: D31
data_type: string

tool: D33: Enter a number to judge if it is a Prime:

tool: D3: %d

tool: D23: Yes, it is a Prime


tool: D31: Not a Prime


assistant: ```c
int main() {
  int input_num;
  int Primes[10000] = {2};
  int prime_test = 3;
  int cnt = 1;
  printf("Enter a number to judge if it is a Prime:");
  scanf("%d", &input_num);
  while (prime_test < input_num) {
    int judge_Prime = 0;
    for (int i = 2; i < prime_test; i++) {
      if (prime_test % i == 0) {
        judge_Prime = 1;
        break;
      }
    }
    if (judge_Prime == 0) {
      Primes[cnt] = prime_test;
      cnt++;
    }
    prime_test++;
  }
  if (isPrime(input_num, Primes, cnt - 1) == 1) {
    printf("Not a Prime\n");
  } else {
    printf("Yes, it is a Prime\n");
  }
  return 0;
}
```