ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<num_char_in_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L28:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L13
  addl   $0x1,-0x4(%rbp)
L13:
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x8(%rbp)
  jb     L28
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int num_char_in_string(char *string, char c) {
  unsigned int i;
  int a = 0;
  for (i = 0; i < strlen(string); i++) {
    if (c == *(string + i))
      a++;
  }
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<num_char_in_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L0
L5:
  mov    %ebx,%eax
  cmp    %r13b,0x0(%rbp,%rax,1)
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  add    $0x1,%ebx
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L5
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_char_in_string(char *string, char c) {
  unsigned int i;
  int a = 0;
  for (i = 0; i < strlen(string); i++) {
    if (c == *(string + i))
      a++;
  }
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_char_in_string>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%eax
  cmp    %r13b,0x0(%rbp,%rax,1)
  sete   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%r12d
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L7
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_char_in_string(char *string, char c) {
  unsigned int i;
  int a = 0;
  for (i = 0; i < strlen(string); i++) {
    if (c == *(string + i))
      a++;
  }
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<num_char_in_string>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%eax
  cmp    %r13b,0x0(%rbp,%rax,1)
  sete   %al
  add    $0x1,%ebx
  movzbl %al,%eax
  add    %eax,%r12d
L16:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  ja     L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int num_char_in_string(char *string, char c) {
  unsigned int i;
  int a = 0;
  for (i = 0; i < strlen(string); i++) {
    if (c == *(string + i))
      a++;
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L35
L12:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L94
L77:
  addq   $0x1,-0x28(%rbp)
  subq   $0x1,-0x10(%rbp)
L94:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  test   %rax,%rax
  jne    L93
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
L93:
  cmpq   $0x0,-0x10(%rbp)
  je     L2
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L5
L2:
  mov    $0x0,%eax
  jmp    L35
L97:
  subq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x10(%rbp)
L5:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  test   %rax,%rax
  jne    L92
  cmpq   $0x1,-0x18(%rbp)
  ja     L97
L92:
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sub_trim@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L35:
  leave
  ret
```

assistant: ```c
char *trim_entry(char *str, size_t (*wfct)(char)) {
  char *tmp;
  size_t i;
  size_t len;
  tmp = NULL;
  if (str == NULL)
    return (NULL);
  len = ft_strlen(str);
  while (!wfct(*str) && *str != '\0') {
    ++str;
    --len;
  }
  if (len > 0)
    i = len - 1;
  else
    return (NULL);
  while (!wfct(str[i]) && i > 1) {
    --i;
    --len;
  }
  tmp = sub_trim(str, tmp, len, i);
  return (tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim_entry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L75
  mov    %rsi,%r13
  call   <ft_strlen@plt>
  mov    %r12,%rbx
  add    %rax,%r12
  jmp    L2
L53:
  add    $0x1,%rbx
L2:
  mov    %r12,%rbp
  sub    %rbx,%rbp
  movsbl (%rbx),%edi
  call   *%r13
  test   %rax,%rax
  jne    L69
  cmpb   $0x0,(%rbx)
  jne    L53
L69:
  test   %rbp,%rbp
  je     L63
  sub    $0x1,%rbp
L74:
  lea    0x1(%rbp),%r12
  movsbl (%rbx,%rbp,1),%edi
  call   *%r13
  cmp    $0x1,%rbp
  jbe    L84
  test   %rax,%rax
  jne    L84
  sub    $0x1,%rbp
  jmp    L74
L84:
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <sub_trim@plt>
L89:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L75:
  mov    %rdi,%rax
  jmp    L89
L63:
  mov    $0x0,%eax
  jmp    L89
```

assistant: ```c
char *trim_entry(char *str, size_t (*wfct)(char)) {
  char *tmp;
  size_t i;
  size_t len;
  tmp = NULL;
  if (str == NULL)
    return (NULL);
  len = ft_strlen(str);
  while (!wfct(*str) && *str != '\0') {
    ++str;
    --len;
  }
  if (len > 0)
    i = len - 1;
  else
    return (NULL);
  while (!wfct(str[i]) && i > 1) {
    --i;
    --len;
  }
  tmp = sub_trim(str, tmp, len, i);
  return (tmp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<trim_entry>:
  endbr64
  test   %rdi,%rdi
  je     L75
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  lea    0x0(%rbp,%rax,1),%r12
  jmp    L26
  nopl   0x0(%rax)
L35:
  cmpb   $0x0,0x0(%rbp)
  je     L28
  add    $0x1,%rbp
L26:
  mov    %r12,%r13
  movsbl 0x0(%rbp),%edi
  sub    %rbp,%r13
  call   *%rbx
  test   %rax,%rax
  je     L35
L28:
  lea    -0x1(%r13),%r12
  test   %r13,%r13
  jne    L48
  jmp    L57
  cs nopw 0x0(%rax,%rax,1)
L65:
  test   %rax,%rax
  jne    L72
  sub    $0x1,%r12
L48:
  movsbl 0x0(%rbp,%r12,1),%edi
  lea    0x1(%r12),%r13
  call   *%rbx
  cmp    $0x1,%r12
  ja     L65
L72:
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sub_trim@plt>
  cs nopw 0x0(%rax,%rax,1)
L57:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L75:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *trim_entry(char *str, size_t (*wfct)(char)) {
  char *tmp;
  size_t i;
  size_t len;
  tmp = NULL;
  if (str == NULL)
    return (NULL);
  len = ft_strlen(str);
  while (!wfct(*str) && *str != '\0') {
    ++str;
    --len;
  }
  if (len > 0)
    i = len - 1;
  else
    return (NULL);
  while (!wfct(str[i]) && i > 1) {
    --i;
    --len;
  }
  tmp = sub_trim(str, tmp, len, i);
  return (tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trim_entry>:
  endbr64
  test   %rdi,%rdi
  je     L47
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  lea    0x0(%rbp,%rax,1),%r12
  jmp    L27
  nopl   0x0(%rax)
L43:
  cmpb   $0x0,0x0(%rbp)
  je     L37
  add    $0x1,%rbp
L27:
  mov    %r12,%r13
  movsbl 0x0(%rbp),%edi
  sub    %rbp,%r13
  call   *%rbx
  test   %rax,%rax
  je     L43
L37:
  lea    -0x1(%r13),%r12
  test   %r13,%r13
  jne    L63
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L66:
  test   %rax,%rax
  jne    L41
  sub    $0x1,%r12
L63:
  movsbl 0x0(%rbp,%r12,1),%edi
  lea    0x1(%r12),%r13
  call   *%rbx
  cmp    $0x1,%r12
  ja     L66
L41:
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %esi,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <sub_trim@plt>
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L47:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *trim_entry(char *str, size_t (*wfct)(char)) {
  char *tmp;
  size_t i;
  size_t len;
  tmp = NULL;
  if (str == NULL)
    return (NULL);
  len = ft_strlen(str);
  while (!wfct(*str) && *str != '\0') {
    ++str;
    --len;
  }
  if (len > 0)
    i = len - 1;
  else
    return (NULL);
  while (!wfct(str[i]) && i > 1) {
    --i;
    --len;
  }
  tmp = sub_trim(str, tmp, len, i);
  return (tmp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply_convert_str_to_uint32_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <multiply_convert_str_to_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int multiply_convert_str_to_uint32_t(uint32_t *value_out, const char *str, const size_t len) {
  int ret = 0;
  int value;
  ret = multiply_convert_str_to_int(&value, str, len);
  *value_out = (uint32_t)value;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<multiply_convert_str_to_uint32_t>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <multiply_convert_str_to_int@plt>
  movslq 0x4(%rsp),%rdx
  mov    %rdx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int multiply_convert_str_to_uint32_t(uint32_t *value_out, const char *str, const size_t len) {
  int ret = 0;
  int value;
  ret = multiply_convert_str_to_int(&value, str, len);
  *value_out = (uint32_t)value;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply_convert_str_to_uint32_t>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <multiply_convert_str_to_int@plt>
  movslq 0x4(%rsp),%rdx
  mov    %rdx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int multiply_convert_str_to_uint32_t(uint32_t *value_out, const char *str, const size_t len) {
  int ret = 0;
  int value;
  ret = multiply_convert_str_to_int(&value, str, len);
  *value_out = (uint32_t)value;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply_convert_str_to_uint32_t>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <multiply_convert_str_to_int@plt>
  movslq 0x4(%rsp),%rdx
  mov    %rdx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int multiply_convert_str_to_uint32_t(uint32_t *value_out, const char *str, const size_t len) {
  int ret = 0;
  int value;
  ret = multiply_convert_str_to_int(&value, str, len);
  *value_out = (uint32_t)value;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_mid_level_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L10
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L5
L10:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L5:
  leave
  ret
```

assistant: ```c
int is_mid_level_match(char *line, char *device, bool class) {
  if (!class)
    return !memcmp(&line[1], &device[2], 4);
  return !memcmp(&line[1], device, 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_mid_level_match>:
  endbr64
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L18
  add    $0x1,%rdi
  mov    $0x2,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L7:
  add    $0x8,%rsp
  ret
L18:
  add    $0x2,%rsi
  add    $0x1,%rdi
  mov    $0x4,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L7
```

assistant: ```c
int is_mid_level_match(char *line, char *device, bool class) {
  if (!class)
    return !memcmp(&line[1], &device[2], 4);
  return !memcmp(&line[1], device, 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_mid_level_match>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%rdi
  test   %edx,%edx
  je     L5
  mov    $0x2,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x2,%rsi
  mov    $0x4,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_mid_level_match(char *line, char *device, bool class) {
  if (!class)
    return !memcmp(&line[1], &device[2], 4);
  return !memcmp(&line[1], device, 2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_mid_level_match>:
  endbr64
  sub    $0x8,%rsp
  add    $0x1,%rdi
  test   %edx,%edx
  je     L9
  mov    $0x2,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x2,%rsi
  mov    $0x4,%edx
  call   <memcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_mid_level_match(char *line, char *device, bool class) {
  if (!class)
    return !memcmp(&line[1], &device[2], 4);
  return !memcmp(&line[1], device, 2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L12
  mov    -0x4(%rbp),%eax
  test   %eax,%eax
  jns    L12
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
div_t div(int num, int denom) {
  div_t r;
  r.quot = num / denom;
  r.rem = num % denom;
  if (num >= 0 && r.rem < 0) {
    r.quot++;
    r.rem -= denom;
  }
  return (r);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<div>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  mov    %edx,%r8d
  not    %edi
  test   %edx,%edi
  js     L17
L2:
  shl    $0x20,%r8
  mov    %ecx,%eax
  or     %r8,%rax
  ret
L17:
  lea    0x1(%rax),%ecx
  sub    %esi,%edx
  mov    %edx,%r8d
  jmp    L2
```

assistant: ```c
div_t div(int num, int denom) {
  div_t r;
  r.quot = num / denom;
  r.rem = num % denom;
  if (num >= 0 && r.rem < 0) {
    r.quot++;
    r.rem -= denom;
  }
  return (r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<div>:
  endbr64
  mov    %edi,%eax
  not    %edi
  cltd
  idiv   %esi
  test   %edx,%edi
  js     L8
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
  nopl   0x0(%rax)
L8:
  add    $0x1,%eax
  sub    %esi,%edx
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
div_t div(int num, int denom) {
  div_t r;
  r.quot = num / denom;
  r.rem = num % denom;
  if (num >= 0 && r.rem < 0) {
    r.quot++;
    r.rem -= denom;
  }
  return (r);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<div>:
  endbr64
  mov    %edi,%eax
  not    %edi
  cltd
  idiv   %esi
  test   %edx,%edi
  js     L11
L8:
  movd   %eax,%xmm0
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,%rax
  ret
  nopl   0x0(%rax)
L11:
  add    $0x1,%eax
  sub    %esi,%edx
  jmp    L8
```

assistant: ```c
div_t div(int num, int denom) {
  div_t r;
  r.quot = num / denom;
  r.rem = num % denom;
  if (num >= 0 && r.rem < 0) {
    r.quot++;
    r.rem -= denom;
  }
  return (r);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NF_WritePage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <select_ship@plt>
  mov    $0x0,%eax
  call   <clean_RnB@plt>
  mov    $0x80,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%edi
  call   <nand_addr@plt>
  mov    $0x0,%edi
  call   <nand_addr@plt>
  mov    -0x18(%rbp),%rax
  movzbl %al,%eax
  mov    %rax,%rdi
  call   <nand_addr@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x8,%rax
  movzbl %al,%eax
  mov    %rax,%rdi
  call   <nand_addr@plt>
  mov    -0x18(%rbp),%rax
  shr    $0x10,%rax
  movzbl %al,%eax
  mov    %rax,%rdi
  call   <nand_addr@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L7:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    $0x70200010,%edx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0xfff,-0x8(%rbp)
  jle    L7
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%eax
  call   <wait_RnB@plt>
  mov    $0x70,%edi
  call   <nand_cmd@plt>
  mov    $0x70200010,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <delselect_ship@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int NF_WritePage(unsigned long addr, unsigned char *buff) {
  int ret, i;
  select_ship();
  clean_RnB();
  nand_cmd(0x80);
  nand_addr(0x00);
  nand_addr(0x00);
  nand_addr(addr & 0xff);
  nand_addr((addr >> 8) & (0xff));
  nand_addr((addr >> 16) & (0xff));
  for (i = 0; i < 1024 * 4; i++) {
    (*((volatile unsigned char *)0x70200010)) = buff[i];
  }
  nand_cmd(0x10);
  wait_RnB();
  nand_cmd(0x70);
  ret = (*((volatile unsigned char *)0x70200010));
  delselect_ship();
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<NF_WritePage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <select_ship@plt>
  mov    $0x0,%eax
  call   <clean_RnB@plt>
  mov    $0x80,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%edi
  call   <nand_addr@plt>
  mov    $0x0,%edi
  call   <nand_addr@plt>
  movzbl %bpl,%edi
  call   <nand_addr@plt>
  mov    %rbp,%rax
  movzbl %ah,%edi
  call   <nand_addr@plt>
  shr    $0x10,%rbp
  movzbl %bpl,%edi
  call   <nand_addr@plt>
  mov    %rbx,%rax
  lea    0x1000(%rbx),%rcx
L1:
  movzbl (%rax),%edx
  mov    %dl,0x70200010
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L1
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%eax
  call   <wait_RnB@plt>
  mov    $0x70,%edi
  call   <nand_cmd@plt>
  movzbl 0x70200010,%ebx
  mov    $0x0,%eax
  call   <delselect_ship@plt>
  movzbl %bl,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int NF_WritePage(unsigned long addr, unsigned char *buff) {
  int ret, i;
  select_ship();
  clean_RnB();
  nand_cmd(0x80);
  nand_addr(0x00);
  nand_addr(0x00);
  nand_addr(addr & 0xff);
  nand_addr((addr >> 8) & (0xff));
  nand_addr((addr >> 16) & (0xff));
  for (i = 0; i < 1024 * 4; i++) {
    (*((volatile unsigned char *)0x70200010)) = buff[i];
  }
  nand_cmd(0x10);
  wait_RnB();
  nand_cmd(0x70);
  ret = (*((volatile unsigned char *)0x70200010));
  delselect_ship();
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<NF_WritePage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <select_ship@plt>
  xor    %eax,%eax
  call   <clean_RnB@plt>
  mov    $0x80,%edi
  call   <nand_cmd@plt>
  xor    %edi,%edi
  call   <nand_addr@plt>
  xor    %edi,%edi
  call   <nand_addr@plt>
  movzbl %bpl,%edi
  call   <nand_addr@plt>
  mov    %rbp,%rax
  shr    $0x10,%rbp
  movzbl %ah,%edi
  call   <nand_addr@plt>
  movzbl %bpl,%edi
  call   <nand_addr@plt>
  mov    %rbx,%rsi
  lea    0x1000(%rbx),%rdx
  nopl   0x0(%rax)
L6:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  mov    %al,0x70200010
  cmp    %rdx,%rsi
  jne    L6
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  xor    %eax,%eax
  call   <wait_RnB@plt>
  mov    $0x70,%edi
  call   <nand_cmd@plt>
  movzbl 0x70200010,%ebx
  xor    %eax,%eax
  call   <delselect_ship@plt>
  add    $0x8,%rsp
  movzbl %bl,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int NF_WritePage(unsigned long addr, unsigned char *buff) {
  int ret, i;
  select_ship();
  clean_RnB();
  nand_cmd(0x80);
  nand_addr(0x00);
  nand_addr(0x00);
  nand_addr(addr & 0xff);
  nand_addr((addr >> 8) & (0xff));
  nand_addr((addr >> 16) & (0xff));
  for (i = 0; i < 1024 * 4; i++) {
    (*((volatile unsigned char *)0x70200010)) = buff[i];
  }
  nand_cmd(0x10);
  wait_RnB();
  nand_cmd(0x70);
  ret = (*((volatile unsigned char *)0x70200010));
  delselect_ship();
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NF_WritePage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <select_ship@plt>
  xor    %eax,%eax
  call   <clean_RnB@plt>
  mov    $0x80,%edi
  call   <nand_cmd@plt>
  xor    %edi,%edi
  call   <nand_addr@plt>
  xor    %edi,%edi
  call   <nand_addr@plt>
  movzbl %bpl,%edi
  call   <nand_addr@plt>
  mov    %rbp,%rax
  shr    $0x10,%rbp
  movzbl %ah,%edi
  call   <nand_addr@plt>
  movzbl %bpl,%edi
  call   <nand_addr@plt>
  mov    %rbx,%rsi
  lea    0x1000(%rbx),%rdx
  nopl   0x0(%rax)
L2:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  mov    %al,0x70200010
  cmp    %rdx,%rsi
  jne    L2
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  xor    %eax,%eax
  call   <wait_RnB@plt>
  mov    $0x70,%edi
  call   <nand_cmd@plt>
  movzbl 0x70200010,%ebx
  xor    %eax,%eax
  call   <delselect_ship@plt>
  add    $0x8,%rsp
  movzbl %bl,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int NF_WritePage(unsigned long addr, unsigned char *buff) {
  int ret, i;
  select_ship();
  clean_RnB();
  nand_cmd(0x80);
  nand_addr(0x00);
  nand_addr(0x00);
  nand_addr(addr & 0xff);
  nand_addr((addr >> 8) & (0xff));
  nand_addr((addr >> 16) & (0xff));
  for (i = 0; i < 1024 * 4; i++) {
    (*((volatile unsigned char *)0x70200010)) = buff[i];
  }
  nand_cmd(0x10);
  wait_RnB();
  nand_cmd(0x70);
  ret = (*((volatile unsigned char *)0x70200010));
  delselect_ship();
  return ret;
}
```