user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x20(%rbp)
  movl   $0xc8,-0x1c(%rbp)
  movl   $0x12c,-0x18(%rbp)
  movl   $0x190,-0x14(%rbp)
  movl   $0x1f4,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x30(%rbp)
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  lea    -0x38(%rbp),%rcx
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x28(%rbp)
  lea    D119(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  mov    -0x38(%rbp),%rdx
  lea    0x10(%rdx),%rcx
  mov    %eax,%edx
  mov    %rcx,%rsi
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x38(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  lea    -0x38(%rbp),%rcx
  mov    %rax,%rsi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rax
  sub    $0x4,%rax
  mov    %rax,-0x30(%rbp)
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  lea    -0x30(%rbp),%rcx
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    $0x4,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x30(%rbp)
  lea    D123(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D111(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x30(%rbp),%rax
  mov    -0x38(%rbp),%rdx
  sub    %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x28(%rbp),%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D81
data_type: string
name: parse_data
arguments: label: D45
data_type: string
name: parse_data
arguments: label: D119
data_type: string
name: parse_data
arguments: label: D60
data_type: string
name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D59
data_type: string
name: parse_data
arguments: label: D9
data_type: string
name: parse_data
arguments: label: D123
data_type: string
name: parse_data
arguments: label: D111
data_type: string
name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D58
data_type: string
name: parse_data
arguments: label: D49
data_type: string
name: parse_data
arguments: label: D43
data_type: string

tool: D81: pointer value, deferenced pointer, pointer address:

tool: D45: ptr1 = %p, *ptr1 = %d, &ptr1 = %p


tool: D119: 
adding an int to a pointer:

tool: D60: ptr1 + 4 = %p, *(ptr4 + 3) = %d


tool: D16: 
values after ptr1++:

tool: D59: 
values after --ptr2:

tool: D9: ptr2 = %p, *ptr2 = %d, &ptr2 = %p


tool: D123: 
Pointers reset to original values:

tool: D111: ptr1 = %p, ptr2 = %p


tool: D8: 
subtracting one pointer from another:

tool: D58: ptr2 = %p, ptr1 = %p, ptr2 - ptr1 = %td


tool: D49: 
subtracting an int from a pointer:

tool: D43: ptr3 = %p, ptr3 - 2 = %p


assistant: ```c
int main(void) {
  int urn[5] = {100, 200, 300, 400, 500};
  int *ptr1, *ptr2, *ptr3;
  ptr1 = urn;
  ptr2 = &urn[2];
  printf("pointer value, deferenced pointer, pointer address:\n");
  printf("ptr1 = %p, *ptr1 = %d, &ptr1 = %p\n", ptr1, *ptr1, &ptr1);
  ptr3 = ptr1 + 4;
  printf("\nadding an int to a pointer:\n");
  printf("ptr1 + 4 = %p, *(ptr4 + 3) = %d\n", ptr1 + 4, *(ptr1 + 3));
  ptr1++;
  printf("\nvalues after ptr1++:\n");
  printf("ptr1 = %p, *ptr1 = %d, &ptr1 = %p\n", ptr1, *ptr1, &ptr1);
  ptr2--;
  printf("\nvalues after --ptr2:\n");
  printf("ptr2 = %p, *ptr2 = %d, &ptr2 = %p\n", ptr2, *ptr2, &ptr2);
  --ptr1;
  ++ptr2;
  printf("\nPointers reset to original values:\n");
  printf("ptr1 = %p, ptr2 = %p\n", ptr1, ptr2);
  printf("\nsubtracting one pointer from another:\n");
  printf("ptr2 = %p, ptr1 = %p, ptr2 - ptr1 = %td\n", ptr2, ptr1, ptr2 - ptr1);
  printf("\nsubtracting an int from a pointer:\n");
  printf("ptr3 = %p, ptr3 - 2 = %p\n", ptr3, ptr3 - 2);
  return 0;
}
```