ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<COM_FileBase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L35:
  subq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L32
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L35
L32:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L28
L6:
  subq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L6
L18:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  cmp    $0x1,%rax
  jg     L24
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L74
L24:
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L74:
  nop
  leave
  ret
```

assistant: ```c
void COM_FileBase(char *in, char *out) {
  char *s, *s2;
  s = in + strlen(in) - 1;
  while (s != in && *s != '.') {
    s--;
  }
  for (s2 = s; s2 != in && *s2 != '/'; s2--) {
  }
  if (s - s2 < 2) {
    out[0] = 0;
  } else {
    s--;
    strncpy(out, s2 + 1, s - s2);
    out[s - s2] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<COM_FileBase>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  je     L87
L62:
  cmpb   $0x2e,(%rax)
  je     L40
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L62
  jmp    L87
L40:
  cmp    %rax,%rbx
  je     L87
  mov    %rax,%rsi
L68:
  cmpb   $0x2f,(%rsi)
  je     L63
  sub    $0x1,%rsi
  cmp    %rsi,%rbx
  jne    L68
L63:
  mov    %rax,%rdx
  sub    %rsi,%rdx
  cmp    $0x1,%rdx
  jg     L31
L87:
  movb   $0x0,0x0(%rbp)
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  lea    -0x1(%rax),%rbx
  sub    %rsi,%rbx
  add    $0x1,%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L17
```

assistant: ```c
void COM_FileBase(char *in, char *out) {
  char *s, *s2;
  s = in + strlen(in) - 1;
  while (s != in && *s != '.') {
    s--;
  }
  for (s2 = s; s2 != in && *s2 != '/'; s2--) {
  }
  if (s - s2 < 2) {
    out[0] = 0;
  } else {
    s--;
    strncpy(out, s2 + 1, s - s2);
    out[s - s2] = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<COM_FileBase>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  cmp    %rdx,%rbx
  jne    L53
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L66:
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L12
L53:
  cmpb   $0x2e,(%rdx)
  jne    L66
  cmp    %rdx,%rbx
  je     L12
  mov    %rdx,%rax
  xchg   %ax,%ax
L49:
  mov    %rax,%rsi
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L47
  cmpb   $0x2f,(%rax)
  jne    L49
L47:
  mov    %rdx,%rcx
  sub    %rax,%rcx
  cmp    $0x1,%rcx
  jle    L12
  mov    %rdx,%rbx
  mov    %rbp,%rdi
  sub    %rsi,%rbx
  mov    %ebx,%edx
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void COM_FileBase(char *in, char *out) {
  char *s, *s2;
  s = in + strlen(in) - 1;
  while (s != in && *s != '.') {
    s--;
  }
  for (s2 = s; s2 != in && *s2 != '/'; s2--) {
  }
  if (s - s2 < 2) {
    out[0] = 0;
  } else {
    s--;
    strncpy(out, s2 + 1, s - s2);
    out[s - s2] = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<COM_FileBase>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  cmp    %rdx,%rbx
  jne    L12
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L33
L12:
  cmpb   $0x2e,(%rdx)
  jne    L9
  cmp    %rdx,%rbx
  je     L33
  mov    %rdx,%rax
  xchg   %ax,%ax
L77:
  mov    %rax,%rsi
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L32
  cmpb   $0x2f,(%rax)
  jne    L77
L32:
  mov    %rdx,%rcx
  sub    %rax,%rcx
  cmp    $0x1,%rcx
  jle    L33
  mov    %rdx,%rbx
  mov    %rbp,%rdi
  sub    %rsi,%rbx
  mov    %ebx,%edx
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L33:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void COM_FileBase(char *in, char *out) {
  char *s, *s2;
  s = in + strlen(in) - 1;
  while (s != in && *s != '.') {
    s--;
  }
  for (s2 = s; s2 != in && *s2 != '/'; s2--) {
  }
  if (s - s2 < 2) {
    out[0] = 0;
  } else {
    s--;
    strncpy(out, s2 + 1, s - s2);
    out[s - s2] = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn_dynamic_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <init_char@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <print_local_dynamic@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <print_char@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <print_char@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string

tool: D0: [HEAP] 2 matrices gemelas tipo char dinamicas


assistant: ```c
void fn_dynamic_char(void) {
  char *lo1 = (char *)malloc(5 * sizeof(char));
  char *lo2 = (char *)malloc(5 * sizeof(char));
  init_char(lo1, lo2);
  printf("[HEAP] 2 matrices gemelas tipo char dinamicas\n");
  print_local_dynamic((unsigned long)lo1, (unsigned long)lo2);
  print_char(lo1);
  print_char(lo2);
  free(lo1);
  free(lo2);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fn_dynamic_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x5,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <init_char@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <print_local_dynamic@plt>
  mov    %rbp,%rdi
  call   <print_char@plt>
  mov    %rbx,%rdi
  call   <print_char@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D5: [HEAP] 2 matrices gemelas tipo char dinamicas


assistant: ```c
void fn_dynamic_char(void) {
  char *lo1 = (char *)malloc(5 * sizeof(char));
  char *lo2 = (char *)malloc(5 * sizeof(char));
  init_char(lo1, lo2);
  printf("[HEAP] 2 matrices gemelas tipo char dinamicas\n");
  print_local_dynamic((unsigned long)lo1, (unsigned long)lo2);
  print_char(lo1);
  print_char(lo2);
  free(lo1);
  free(lo2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fn_dynamic_char>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x5,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <init_char@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <print_local_dynamic@plt>
  mov    %r12,%rdi
  call   <print_char@plt>
  mov    %rbp,%rdi
  call   <print_char@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <free@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: [HEAP] 2 matrices gemelas tipo char dinamicas


assistant: ```c
void fn_dynamic_char(void) {
  char *lo1 = (char *)malloc(5 * sizeof(char));
  char *lo2 = (char *)malloc(5 * sizeof(char));
  init_char(lo1, lo2);
  printf("[HEAP] 2 matrices gemelas tipo char dinamicas\n");
  print_local_dynamic((unsigned long)lo1, (unsigned long)lo2);
  print_char(lo1);
  print_char(lo2);
  free(lo1);
  free(lo2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fn_dynamic_char>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x5,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <init_char@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <print_local_dynamic@plt>
  mov    %r12,%rdi
  call   <print_char@plt>
  mov    %rbp,%rdi
  call   <print_char@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10a0 <free@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: [HEAP] 2 matrices gemelas tipo char dinamicas


assistant: ```c
void fn_dynamic_char(void) {
  char *lo1 = (char *)malloc(5 * sizeof(char));
  char *lo2 = (char *)malloc(5 * sizeof(char));
  init_char(lo1, lo2);
  printf("[HEAP] 2 matrices gemelas tipo char dinamicas\n");
  print_local_dynamic((unsigned long)lo1, (unsigned long)lo2);
  print_char(lo1);
  print_char(lo2);
  free(lo1);
  free(lo2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1b4(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1b0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1ac(%rbp)
  jmp    L67
L5:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1ac(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1ac(%rbp)
L67:
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L5
  movl   $0x0,-0x1a8(%rbp)
  jmp    L43
L75:
  mov    -0x1b4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1b4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1ac(%rbp)
  jmp    L35
L59:
  mov    -0x1ac(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  subl   $0x1,-0x1ac(%rbp)
L35:
  cmpl   $0x0,-0x1ac(%rbp)
  jg     L59
  mov    -0x1a4(%rbp),%eax
  mov    %eax,-0x1a0(%rbp)
  addl   $0x1,-0x1a8(%rbp)
L43:
  mov    -0x1b0(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L75
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x1ac(%rbp)
  jmp    L73
L52:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1ac(%rbp)
L73:
  mov    -0x1b4(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L52
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D18
type_infered: string
name: read_data
arguments: tag: D0
type_infered: string

tool: D18: %d

tool: D0: %d 

assistant: ```c
int main() {
  int n, i;
  int a[100];
  scanf("%d", &n);
  int m;
  scanf("%d", &m);
  for (i = 0; i < n; ++i) {
    scanf("%d", &a[i]);
  }
  int j;
  for (j = 0; j < m; j++) {
    int temp = a[n - 1];
    for (i = n - 1; i > 0; i--) {
      a[i] = a[i - 1];
    }
    a[0] = temp;
  }
  printf("\n");
  for (i = 0; i < n; ++i) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L22
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L87:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x8(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L87
L22:
  mov    0xc(%rsp),%r9d
  test   %r9d,%r9d
  jle    L36
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    0x10(%rsp,%rdx,1),%r11
  lea    0xc(%rsp,%rdx,1),%rcx
  lea    -0x2(%rax),%edx
  shl    $0x2,%rdx
  sub    %rdx,%rcx
  mov    $0x0,%edi
  lea    -0x1(%rax),%esi
  movslq %esi,%r10
L21:
  mov    0x10(%rsp,%r10,4),%r8d
  test   %esi,%esi
  jle    L77
  mov    %r11,%rax
L32:
  mov    -0x8(%rax),%edx
  mov    %edx,-0x4(%rax)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L32
L77:
  mov    %r8d,0x10(%rsp)
  add    $0x1,%edi
  cmp    %r9d,%edi
  jne    L21
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L38
  mov    $0x0,%ebx
  lea    D10(%rip),%rbp
L54:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x8(%rsp)
  jg     L54
L38:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string

tool: D2: %d

tool: D10: %d 

assistant: ```c
int main() {
  int n, i;
  int a[100];
  scanf("%d", &n);
  int m;
  scanf("%d", &m);
  for (i = 0; i < n; ++i) {
    scanf("%d", &a[i]);
  }
  int j;
  for (j = 0; j < m; j++) {
    int temp = a[n - 1];
    for (i = n - 1; i > 0; i--) {
      a[i] = a[i - 1];
    }
    a[0] = temp;
  }
  printf("\n");
  for (i = 0; i < n; ++i) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L75
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  cmp    %ebx,%eax
  jg     L73
L75:
  mov    0x1c(%rsp),%ecx
  mov    %ecx,0xc(%rsp)
  test   %ecx,%ecx
  jle    L42
  lea    -0x1(%rax),%r14d
  sub    $0x2,%eax
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  lea    0x4(,%rax,4),%r15
  neg    %rax
  movslq %r14d,%r12
  shl    $0x2,%rax
  lea    (%rax,%r12,4),%rdi
  lea    -0x4(%rax,%r12,4),%rax
  add    %rbp,%rdi
  add    %rax,%rbp
  nopl   (%rax)
L35:
  mov    0x20(%rsp,%r12,4),%r13d
  test   %r14d,%r14d
  jle    L46
  mov    %r15,%rdx
  mov    %rbp,%rsi
  call   <memmove@plt>
  mov    %rax,%rdi
L46:
  mov    %r13d,0x20(%rsp)
  add    $0x1,%ebx
  cmp    0xc(%rsp),%ebx
  jne    L35
L42:
  mov    $0xa,%edi
  xor    %ebx,%ebx
  lea    0x20(%rsp),%rbp
  call   <putchar@plt>
  mov    0x18(%rsp),%eax
  lea    D16(%rip),%r12
  test   %eax,%eax
  jle    L58
  xchg   %ax,%ax
L29:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x18(%rsp)
  jg     L29
L58:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D16
data_type: string

tool: D18: %d

tool: D16: %d 

assistant: ```c
int main() {
  int n, i;
  int a[100];
  scanf("%d", &n);
  int m;
  scanf("%d", &m);
  for (i = 0; i < n; ++i) {
    scanf("%d", &a[i]);
  }
  int j;
  for (j = 0; j < m; j++) {
    int temp = a[n - 1];
    for (i = n - 1; i > 0; i--) {
      a[i] = a[i - 1];
    }
    a[0] = temp;
  }
  printf("\n");
  for (i = 0; i < n; ++i) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x1c(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L28
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L86:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  cmp    %ebx,%eax
  jg     L86
L28:
  mov    0x1c(%rsp),%r12d
  test   %r12d,%r12d
  jle    L96
  lea    -0x1(%rax),%ecx
  sub    $0x2,%eax
  lea    0x20(%rsp),%rbp
  xor    %ebx,%ebx
  lea    0x4(,%rax,4),%r15
  neg    %rax
  movslq %ecx,%r13
  mov    %ecx,0xc(%rsp)
  shl    $0x2,%rax
  lea    (%rax,%r13,4),%rdi
  lea    -0x4(%rax,%r13,4),%rax
  add    %rbp,%rdi
  add    %rax,%rbp
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    0xc(%rsp),%edx
  mov    0x20(%rsp,%r13,4),%r14d
  test   %edx,%edx
  jle    L4
  mov    %r15,%rdx
  mov    %rbp,%rsi
  add    $0x1,%ebx
  call   <memmove@plt>
  mov    %r14d,0x20(%rsp)
  mov    %rax,%rdi
  cmp    %ebx,%r12d
  jne    L1
L96:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L48
  xor    %ebx,%ebx
  lea    0x20(%rsp),%rbp
  lea    D11(%rip),%r12
  nopl   0x0(%rax)
L65:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x18(%rsp)
  jg     L65
L48:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L4:
  add    $0x1,%ebx
  mov    %r14d,0x20(%rsp)
  cmp    %r12d,%ebx
  jne    L1
  jmp    L96
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string

tool: D13: %d

tool: D11: %d 

assistant: ```c
int main() {
  int n, i;
  int a[100];
  scanf("%d", &n);
  int m;
  scanf("%d", &m);
  for (i = 0; i < n; ++i) {
    scanf("%d", &a[i]);
  }
  int j;
  for (j = 0; j < m; j++) {
    int temp = a[n - 1];
    for (i = n - 1; i > 0; i--) {
      a[i] = a[i - 1];
    }
    a[0] = temp;
  }
  printf("\n");
  for (i = 0; i < n; ++i) {
    printf("%d ", a[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cpuid_extended>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x80000000,%eax
  cpuid
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t cpuid_extended() {
  uint32_t out;
  asm("mov $0x80000000, %%eax\n\t"
      "cpuid"
      : "=a"(out));
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cpuid_extended>:
  endbr64
  mov    $0x80000000,%eax
  cpuid
  ret
```

assistant: ```c
uint32_t cpuid_extended() {
  uint32_t out;
  asm("mov $0x80000000, %%eax\n\t"
      "cpuid"
      : "=a"(out));
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<cpuid_extended>:
  endbr64
  mov    $0x80000000,%eax
  cpuid
  ret
```

assistant: ```c
uint32_t cpuid_extended() {
  uint32_t out;
  asm("mov $0x80000000, %%eax\n\t"
      "cpuid"
      : "=a"(out));
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cpuid_extended>:
  endbr64
  mov    $0x80000000,%eax
  cpuid
  ret
```

assistant: ```c
uint32_t cpuid_extended() {
  uint32_t out;
  asm("mov $0x80000000, %%eax\n\t"
      "cpuid"
      : "=a"(out));
  return out;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rank_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L41
L22:
  movl   $0x0,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L44
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L46
  addl   $0x1,-0x4(%rbp)
L46:
  addl   $0x1,-0xc(%rbp)
L44:
  cmpl   $0x7,-0xc(%rbp)
  jle    L9
  mov    $0x7,%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fact@plt>
  imul   -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L41:
  cmpl   $0x7,-0x10(%rbp)
  jle    L22
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rank_of(int *a) {
  int i, j;
  int rank = 0, count;
  for (i = 0; i < 8; i++) {
    count = 0;
    for (j = i + 1; j < 8; j++)
      if (a[j] < a[i])
        count++;
    rank = rank + count * fact(8 - i - 1);
  }
  return rank;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rank_of>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x1,%r12d
  mov    $0x0,%r13d
  mov    $0x8,%r15d
  jmp    L53
L9:
  add    $0x1,%rax
  cmp    $0x7,%eax
  jg     L25
L31:
  cmp    %edx,0x0(%rbp,%rax,4)
  jge    L9
  add    $0x1,%ebx
  jmp    L9
L25:
  mov    %r15d,%edi
  sub    %ecx,%edi
  call   <fact@plt>
  imul   %eax,%ebx
  add    %ebx,%r13d
  add    $0x1,%r12
  cmp    $0x8,%r12
  je     L30
L53:
  mov    %r12d,%ecx
  mov    %r12d,%r14d
  mov    -0x4(%rbp,%r12,4),%edx
  mov    %r12,%rax
  mov    $0x0,%ebx
  jmp    L31
L30:
  mov    $0x7,%edi
  sub    %r14d,%edi
  call   <fact@plt>
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int rank_of(int *a) {
  int i, j;
  int rank = 0, count;
  for (i = 0; i < 8; i++) {
    count = 0;
    for (j = i + 1; j < 8; j++)
      if (a[j] < a[i])
        count++;
    rank = rank + count * fact(8 - i - 1);
  }
  return rank;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rank_of>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    $0x8,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xchg   %ax,%ax
L24:
  mov    -0x4(%rbp,%r14,4),%edx
  mov    %r14d,%ecx
  mov    %r14,%rax
  xor    %ebx,%ebx
  nopl   (%rax)
L9:
  cmp    %edx,0x0(%rbp,%rax,4)
  jge    L3
  add    $0x1,%ebx
L3:
  add    $0x1,%rax
  cmp    $0x8,%eax
  jne    L9
  mov    %r13d,%edi
  add    $0x1,%r14
  sub    %ecx,%edi
  call   <fact@plt>
  imul   %eax,%ebx
  add    %ebx,%r12d
  cmp    $0x8,%r14
  jne    L24
  xor    %edi,%edi
  call   <fact@plt>
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int rank_of(int *a) {
  int i, j;
  int rank = 0, count;
  for (i = 0; i < 8; i++) {
    count = 0;
    for (j = i + 1; j < 8; j++)
      if (a[j] < a[i])
        count++;
    rank = rank + count * fact(8 - i - 1);
  }
  return rank;
}
```