ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<t2p_time2posix_timespec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <t2p_time2posix@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  mov    -0xc(%rbp),%eax
  cmp    $0x1,%eax
  jne    L32
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L31
L32:
  mov    -0xc(%rbp),%eax
  cmp    $0x2,%eax
  jne    L11
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x3b9aca00,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L31
L11:
  mov    -0xc(%rbp),%eax
  cmp    $0xffffffff,%eax
  jne    L31
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <t2p_normalize_timespec@plt>
L31:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
struct timespec *t2p_time2posix_timespec(struct timespec *ts) {
  int state;
  ts->tv_sec = t2p_time2posix(ts->tv_sec, &state);
  if (state == 1)
    ts->tv_nsec >>= 1;
  else if (state == 2)
    ts->tv_nsec = (ts->tv_nsec + 1000000000) >> 1;
  else if (state == -1) {
    ts->tv_nsec <<= 1;
    t2p_normalize_timespec(ts);
  }
  return ts;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<t2p_time2posix_timespec>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    0x4(%rdi),%edi
  call   <t2p_time2posix@plt>
  mov    %eax,0x4(%rbx)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L30
  cmp    $0x2,%eax
  je     L11
  cmp    $0xffffffff,%eax
  je     L21
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L30:
  sarl   (%rbx)
  jmp    L31
L11:
  mov    (%rbx),%eax
  add    $0x3b9aca00,%eax
  sar    %eax
  mov    %eax,(%rbx)
  jmp    L31
L21:
  shll   (%rbx)
  mov    %rbx,%rdi
  call   <t2p_normalize_timespec@plt>
  jmp    L31
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec *t2p_time2posix_timespec(struct timespec *ts) {
  int state;
  ts->tv_sec = t2p_time2posix(ts->tv_sec, &state);
  if (state == 1)
    ts->tv_nsec >>= 1;
  else if (state == 2)
    ts->tv_nsec = (ts->tv_nsec + 1000000000) >> 1;
  else if (state == -1) {
    ts->tv_nsec <<= 1;
    t2p_normalize_timespec(ts);
  }
  return ts;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t2p_time2posix_timespec>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    0x4(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <t2p_time2posix@plt>
  mov    %eax,0x4(%r12)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L13
  cmp    $0x2,%eax
  je     L55
  cmp    $0xffffffff,%eax
  je     L6
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  mov    (%r12),%eax
  add    $0x3b9aca00,%eax
  sar    %eax
  mov    %eax,(%r12)
  jmp    L20
  nopl   0x0(%rax)
L13:
  sarl   (%r12)
  jmp    L20
  xchg   %ax,%ax
L6:
  shll   (%r12)
  mov    %r12,%rdi
  call   <t2p_normalize_timespec@plt>
  jmp    L20
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec *t2p_time2posix_timespec(struct timespec *ts) {
  int state;
  ts->tv_sec = t2p_time2posix(ts->tv_sec, &state);
  if (state == 1)
    ts->tv_nsec >>= 1;
  else if (state == 2)
    ts->tv_nsec = (ts->tv_nsec + 1000000000) >> 1;
  else if (state == -1) {
    ts->tv_nsec <<= 1;
    t2p_normalize_timespec(ts);
  }
  return ts;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<t2p_time2posix_timespec>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    0x4(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <t2p_time2posix@plt>
  mov    %eax,0x4(%r12)
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L15
  cmp    $0x2,%eax
  je     L6
  cmp    $0xffffffff,%eax
  je     L62
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  mov    (%r12),%eax
  add    $0x3b9aca00,%eax
  sar    %eax
  mov    %eax,(%r12)
  jmp    L66
  nopl   0x0(%rax)
L15:
  sarl   (%r12)
  jmp    L66
  xchg   %ax,%ax
L62:
  shll   (%r12)
  mov    %r12,%rdi
  call   <t2p_normalize_timespec@plt>
  jmp    L66
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec *t2p_time2posix_timespec(struct timespec *ts) {
  int state;
  ts->tv_sec = t2p_time2posix(ts->tv_sec, &state);
  if (state == 1)
    ts->tv_nsec >>= 1;
  else if (state == 2)
    ts->tv_nsec = (ts->tv_nsec + 1000000000) >> 1;
  else if (state == -1) {
    ts->tv_nsec <<= 1;
    t2p_normalize_timespec(ts);
  }
  return ts;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x74(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x7c(%rbp)
  jmp    L24
L10:
  addl   $0x1,-0x74(%rbp)
  addl   $0x1,-0x7c(%rbp)
L24:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L10
  movl   $0x0,-0x7c(%rbp)
  mov    -0x74(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x78(%rbp)
  jmp    L36
L9:
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x7d(%rbp)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x7c(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x7d(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x7c(%rbp)
  subl   $0x1,-0x78(%rbp)
L36:
  mov    -0x7c(%rbp),%eax
  cmp    -0x78(%rbp),%eax
  jl     L9
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D17
type_infered: string

tool: D2: 
 Enter the string :

tool: D17: 
 Reverse string is :%s

assistant: ```c
void main() {
  char str[100], temp;
  int i, j = 0, len = 0;
  printf("\n Enter the string :");
  gets(str);
  for (i = 0; str[i] != '\0'; i++) {
    len++;
  }
  i = 0;
  j = len - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\n Reverse string is :%s", str);
  getch();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L30
  mov    $0x0,%edx
  mov    %rsp,%rcx
L6:
  mov    %edx,%eax
  mov    %rdx,%rsi
  add    $0x1,%rdx
  cmpb   $0x0,(%rdx,%rcx,1)
  jne    L6
  test   %eax,%eax
  jle    L30
  mov    %rsp,%rcx
  movslq %eax,%rdx
  add    %rcx,%rdx
L36:
  movzbl (%rcx),%edi
  movzbl (%rdx),%r8d
  mov    %r8b,(%rcx)
  mov    %dil,(%rdx)
  sub    $0x1,%eax
  add    $0x1,%rcx
  sub    $0x1,%rdx
  mov    %esi,%edi
  sub    %eax,%edi
  cmp    %edi,%eax
  jg     L36
L30:
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x78,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D1: 
 Enter the string :

tool: D5: 
 Reverse string is :%s

assistant: ```c
void main() {
  char str[100], temp;
  int i, j = 0, len = 0;
  printf("\n Enter the string :");
  gets(str);
  for (i = 0; str[i] != '\0'; i++) {
    len++;
  }
  i = 0;
  j = len - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\n Reverse string is :%s", str);
  getch();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  movzbl (%rsp),%edi
  test   %dil,%dil
  je     L36
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%esi
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,0x0(%rbp,%rax,1)
  jne    L5
  test   %esi,%esi
  je     L36
  movslq %esi,%rax
  mov    %rbp,%rcx
  add    %rbp,%rax
  jmp    L34
  xchg   %ax,%ax
L28:
  movzbl (%rcx),%edi
L34:
  movzbl (%rax),%r8d
  sub    $0x1,%edx
  sub    $0x1,%rax
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  mov    %dil,0x1(%rax)
  mov    %esi,%edi
  sub    %edx,%edi
  cmp    %edi,%edx
  jg     L28
L36:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D17: 
 Enter the string :

tool: D6: 
 Reverse string is :%s

assistant: ```c
void main() {
  char str[100], temp;
  int i, j = 0, len = 0;
  printf("\n Enter the string :");
  gets(str);
  for (i = 0; str[i] != '\0'; i++) {
    len++;
  }
  i = 0;
  j = len - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\n Reverse string is :%s", str);
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L23
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %eax,%esi
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,0x0(%rbp,%rax,1)
  jne    L19
  test   %esi,%esi
  je     L23
  movslq %esi,%rax
  mov    %rbp,%rcx
  add    %rbp,%rax
  nopl   0x0(%rax)
L6:
  movzbl (%rcx),%edi
  movzbl (%rax),%r8d
  sub    $0x1,%edx
  add    $0x1,%rcx
  sub    $0x1,%rax
  mov    %r8b,-0x1(%rcx)
  mov    %dil,0x1(%rax)
  mov    %esi,%edi
  sub    %edx,%edi
  cmp    %edi,%edx
  jg     L6
L23:
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x70,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D9: 
 Enter the string :

tool: D3: 
 Reverse string is :%s

assistant: ```c
void main() {
  char str[100], temp;
  int i, j = 0, len = 0;
  printf("\n Enter the string :");
  gets(str);
  for (i = 0; str[i] != '\0'; i++) {
    len++;
  }
  i = 0;
  j = len - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\n Reverse string is :%s", str);
  getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<log_quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <log_doit@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void log_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_quit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <log_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void log_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<log_quit>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %ebp,%ecx
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    (%rax),%esi
  call   <log_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_quit>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %ebp,%ecx
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    (%rax),%esi
  call   <log_doit@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void log_quit(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  log_doit(0, LOG_ERR, fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ihevca_aligned_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void ihevca_aligned_free(void *pv_buf) {
  free(pv_buf);
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ihevca_aligned_free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ihevca_aligned_free(void *pv_buf) {
  free(pv_buf);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ihevca_aligned_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void ihevca_aligned_free(void *pv_buf) {
  free(pv_buf);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ihevca_aligned_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void ihevca_aligned_free(void *pv_buf) {
  free(pv_buf);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_any_but>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L32:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L22
  mov    $0x0,%eax
  jmp    L0
L22:
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L32
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int is_any_but(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      return 0;
    }
  (*ofs)++;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_any_but>:
  endbr64
  mov    (%rcx),%r9d
  movslq %r9d,%rax
  movsbl (%rdx,%rax,1),%r8d
  test   %esi,%esi
  jle    L23
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
L16:
  movzbl (%rax),%edx
  cmp    %r8d,%edx
  je     L20
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L16
L23:
  add    $0x1,%r9d
  mov    %r9d,(%rcx)
  mov    $0x1,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_any_but(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      return 0;
    }
  (*ofs)++;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<is_any_but>:
  endbr64
  movslq (%rcx),%rax
  movsbl (%rdx,%rax,1),%edx
  mov    %rax,%r8
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  jmp    L32
  nopl   0x0(%rax)
L18:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L23
L32:
  movzbl (%rdi),%eax
  cmp    %edx,%eax
  jne    L18
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%r8d
  mov    $0x1,%eax
  mov    %r8d,(%rcx)
  ret
```

assistant: ```c
int is_any_but(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      return 0;
    }
  (*ofs)++;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_any_but>:
  endbr64
  movslq (%rcx),%rax
  movsbl (%rdx,%rax,1),%edx
  mov    %rax,%r8
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  jmp    L28
  nopl   0x0(%rax)
L29:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L6
L28:
  movzbl (%rdi),%eax
  cmp    %edx,%eax
  jne    L29
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%r8d
  mov    $0x1,%eax
  mov    %r8d,(%rcx)
  ret
```

assistant: ```c
int is_any_but(const unsigned char *p, int len, const char *s, int *ofs) {
  int i, ch;
  ch = s[*ofs];
  for (i = 0; i < len; i++)
    if (p[i] == ch) {
      return 0;
    }
  (*ofs)++;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L11
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
L11:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L15
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *str, int c, size_t n) {
  size_t i = 0;
  while (i < n) {
    *((char *)str + i++) = (char)(c);
  }
  return str;
}
```
user: What is the c source code of the assembly code below?

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L0
  mov    %rdi,%rcx
  add    %rdi,%rdx
L16:
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L16
L0:
  ret
```

assistant: ```c
void *memset(void *str, int c, size_t n) {
  size_t i = 0;
  while (i < n) {
    *((char *)str + i++) = (char)(c);
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L5
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *str, int c, size_t n) {
  size_t i = 0;
  while (i < n) {
    *((char *)str + i++) = (char)(c);
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L5
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *str, int c, size_t n) {
  size_t i = 0;
  while (i < n) {
    *((char *)str + i++) = (char)(c);
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skip_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L35:
  addq   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L16
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  je     L16
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L35
L16:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void skip_whitespace(const char **cp, int n, char term) {
  const char *cp1 = *cp;
  while (isspace((int)*cp1) && *cp1 != term && n--)
    cp1++;
  *cp = cp1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_whitespace>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    (%rdi),%rbx
  mov    %esi,%esi
  lea    (%rbx,%rsi,1),%rbp
  jmp    L13
L9:
  add    $0x1,%rbx
L13:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L23
  cmp    %r12b,(%rbx)
  je     L23
  cmp    %rbp,%rbx
  jne    L9
  mov    %rbp,%rbx
L23:
  mov    %rbx,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void skip_whitespace(const char **cp, int n, char term) {
  const char *cp1 = *cp;
  while (isspace((int)*cp1) && *cp1 != term && n--)
    cp1++;
  *cp = cp1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skip_whitespace>:
  endbr64
  push   %r13
  mov    %esi,%esi
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  lea    (%rbx,%rsi,1),%rbp
  jmp    L15
  nop
L19:
  cmp    %r12b,(%rbx)
  je     L6
  cmp    %rbp,%rbx
  je     L6
  add    $0x1,%rbx
L15:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
L6:
  mov    %rbx,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void skip_whitespace(const char **cp, int n, char term) {
  const char *cp1 = *cp;
  while (isspace((int)*cp1) && *cp1 != term && n--)
    cp1++;
  *cp = cp1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<skip_whitespace>:
  endbr64
  push   %r13
  mov    %esi,%esi
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  lea    (%rbx,%rsi,1),%rbp
  jmp    L17
  nop
L3:
  cmp    %r12b,(%rbx)
  je     L18
  cmp    %rbp,%rbx
  je     L18
  add    $0x1,%rbx
L17:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
L18:
  mov    %rbx,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void skip_whitespace(const char **cp, int n, char term) {
  const char *cp1 = *cp;
  while (isspace((int)*cp1) && *cp1 != term && n--)
    cp1++;
  *cp = cp1;
}
```