ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D8
data_type: string

tool: D17: Usage: %s -p pid -l libpath


tool: D8:     -h  --help      Display this usage information.
    -p  --pid       PID of target process.
    -l  --libpath   Absolute path of the shared library that will be injected.

assistant: ```c
void print_usage(const char *pname, int exit_code) {
  printf("Usage: %s -p pid -l libpath\n", pname);
  printf("    -h  --help      Display this usage information.\n"
         "    -p  --pid       PID of target process.\n"
         "    -l  --libpath   Absolute path of the shared library that will be injected.\n");
  exit(exit_code);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %rdi,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D12
datatype: string
name: read_data
arguments: label: D0
datatype: string

tool: D12: Usage: %s -p pid -l libpath


tool: D0:     -h  --help      Display this usage information.
    -p  --pid       PID of target process.
    -l  --libpath   Absolute path of the shared library that will be injected.

assistant: ```c
void print_usage(const char *pname, int exit_code) {
  printf("Usage: %s -p pid -l libpath\n", pname);
  printf("    -h  --help      Display this usage information.\n"
         "    -p  --pid       PID of target process.\n"
         "    -l  --libpath   Absolute path of the shared library that will be injected.\n");
  exit(exit_code);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_usage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D19: Usage: %s -p pid -l libpath


tool: D4:     -h  --help      Display this usage information.
    -p  --pid       PID of target process.
    -l  --libpath   Absolute path of the shared library that will be injected.

assistant: ```c
void print_usage(const char *pname, int exit_code) {
  printf("Usage: %s -p pid -l libpath\n", pname);
  printf("    -h  --help      Display this usage information.\n"
         "    -p  --pid       PID of target process.\n"
         "    -l  --libpath   Absolute path of the shared library that will be injected.\n");
  exit(exit_code);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_usage>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  mov    %rdi,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D10: Usage: %s -p pid -l libpath


tool: D6:     -h  --help      Display this usage information.
    -p  --pid       PID of target process.
    -l  --libpath   Absolute path of the shared library that will be injected.

assistant: ```c
void print_usage(const char *pname, int exit_code) {
  printf("Usage: %s -p pid -l libpath\n", pname);
  printf("    -h  --help      Display this usage information.\n"
         "    -p  --pid       PID of target process.\n"
         "    -l  --libpath   Absolute path of the shared library that will be injected.\n");
  exit(exit_code);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L128
  mov    -0x1c(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L128
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L128
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L52
L128:
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jge    L15
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L15
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L15
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L52
L15:
  mov    -0x14(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jge    L37
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L37
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L37
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L52
L37:
  mov    -0x10(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jge    L52
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L52
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L52
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L52:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D24
datatype: string
name: read_data
arguments: data_label: D1
datatype: string

tool: D11: Please enter 4 numbers separated by spaces > 

tool: D24: %d%d%d%d

tool: D1: %d is the smallest


assistant: ```c
int main(void) {
  int num1;
  int num2;
  int num3;
  int num4;
  int smallest;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &num1, &num2, &num3, &num4);
  if (num1 < num2 && num1 < num3 && num1 < num4)
    smallest = num1;
  else if (num2 < num1 && num2 < num3 && num2 < num4)
    smallest = num2;
  else if (num3 < num1 && num3 < num2 && num3 < num4)
    smallest = num3;
  else if (num4 < num1 && num4 < num2 && num4 < num3)
    smallest = num4;
  printf("%d is the smallest\n", smallest);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%eax
  cmp    %eax,%esi
  jge    L32
  cmp    0x10(%rsp),%esi
  jge    L50
  cmp    0x14(%rsp),%esi
  jl     L14
L50:
  mov    0x10(%rsp),%edx
  cmp    %eax,%esi
  mov    %eax,%ecx
  cmovle %esi,%ecx
  cmp    %ecx,%edx
  jl     L108
L54:
  mov    0x14(%rsp),%ecx
  cmp    %eax,%esi
  cmovle %esi,%eax
  cmp    %edx,%eax
  cmovg  %edx,%eax
  cmp    %eax,%ecx
  cmovl  %ecx,%esi
L14:
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L32:
  jle    L50
  mov    0x10(%rsp),%edx
  cmp    %edx,%eax
  jge    L50
  cmp    0x14(%rsp),%eax
  jge    L54
  mov    %eax,%esi
  jmp    L14
L108:
  cmp    0x14(%rsp),%edx
  jge    L54
  mov    %edx,%esi
  jmp    L14
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D18
datatype: string

tool: D1: Please enter 4 numbers separated by spaces > 

tool: D5: %d%d%d%d

tool: D18: %d is the smallest


assistant: ```c
int main(void) {
  int num1;
  int num2;
  int num3;
  int num4;
  int smallest;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &num1, &num2, &num3, &num4);
  if (num1 < num2 && num1 < num3 && num1 < num4)
    smallest = num1;
  else if (num2 < num1 && num2 < num3 && num2 < num4)
    smallest = num2;
  else if (num3 < num1 && num3 < num2 && num3 < num4)
    smallest = num3;
  else if (num4 < num1 && num4 < num2 && num4 < num3)
    smallest = num4;
  printf("%d is the smallest\n", smallest);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  jge    L71
  cmp    0x10(%rsp),%eax
  jge    L39
  mov    %eax,%esi
  cmp    0x14(%rsp),%eax
  jl     L109
  mov    0x10(%rsp),%ecx
  nopw   0x0(%rax,%rax,1)
L65:
  cmp    %edx,%eax
  mov    0x14(%rsp),%edi
  cmovg  %edx,%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  xor    %esi,%esi
  cmp    %eax,%edi
  cmovl  %edi,%esi
L109:
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L71:
  mov    0x10(%rsp),%ecx
  jle    L13
  cmp    %ecx,%edx
  jge    L13
  mov    %edx,%esi
  cmp    0x14(%rsp),%edx
  jl     L109
  jmp    L65
L39:
  mov    0x10(%rsp),%ecx
L13:
  cmp    %edx,%eax
  mov    %edx,%edi
  mov    %ecx,%esi
  cmovle %eax,%edi
  cmp    %edi,%ecx
  jge    L65
  cmp    0x14(%rsp),%ecx
  jl     L109
  jmp    L65
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D17: Please enter 4 numbers separated by spaces > 

tool: D14: %d%d%d%d

tool: D6: %d is the smallest


assistant: ```c
int main(void) {
  int num1;
  int num2;
  int num3;
  int num4;
  int smallest;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &num1, &num2, &num3, &num4);
  if (num1 < num2 && num1 < num3 && num1 < num4)
    smallest = num1;
  else if (num2 < num1 && num2 < num3 && num2 < num4)
    smallest = num2;
  else if (num3 < num1 && num3 < num2 && num3 < num4)
    smallest = num3;
  else if (num4 < num1 && num4 < num2 && num4 < num3)
    smallest = num4;
  printf("%d is the smallest\n", smallest);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  mov    0xc(%rsp),%edx
  cmp    %edx,%eax
  jge    L105
  cmp    0x10(%rsp),%eax
  jge    L49
  mov    %eax,%esi
  cmp    0x14(%rsp),%eax
  jl     L73
  mov    0x10(%rsp),%ecx
  nopw   0x0(%rax,%rax,1)
L55:
  cmp    %edx,%eax
  mov    0x14(%rsp),%edi
  cmovg  %edx,%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  xor    %esi,%esi
  cmp    %eax,%edi
  cmovl  %edi,%esi
L73:
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L105:
  mov    0x10(%rsp),%ecx
  jle    L77
  cmp    %ecx,%edx
  jge    L77
  mov    %edx,%esi
  cmp    0x14(%rsp),%edx
  jl     L73
  jmp    L55
L49:
  mov    0x10(%rsp),%ecx
L77:
  cmp    %edx,%eax
  mov    %edx,%edi
  mov    %ecx,%esi
  cmovle %eax,%edi
  cmp    %edi,%ecx
  jge    L55
  cmp    0x14(%rsp),%ecx
  jl     L73
  jmp    L55
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D10
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string

tool: D8: Please enter 4 numbers separated by spaces > 

tool: D10: %d%d%d%d

tool: D16: %d is the smallest


assistant: ```c
int main(void) {
  int num1;
  int num2;
  int num3;
  int num4;
  int smallest;
  printf("Please enter 4 numbers separated by spaces > ");
  scanf("%d%d%d%d", &num1, &num2, &num3, &num4);
  if (num1 < num2 && num1 < num3 && num1 < num4)
    smallest = num1;
  else if (num2 < num1 && num2 < num3 && num2 < num4)
    smallest = num2;
  else if (num3 < num1 && num3 < num2 && num3 < num4)
    smallest = num3;
  else if (num4 < num1 && num4 < num2 && num4 < num3)
    smallest = num4;
  printf("%d is the smallest\n", smallest);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BitIsReset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int BitIsReset(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  return (D[Bit / 8] & (0x01 << (Bit % 8))) == 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<BitIsReset>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  shr    $0x3,%eax
  mov    %eax,%eax
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  test   $0x1,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int BitIsReset(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  return (D[Bit / 8] & (0x01 << (Bit % 8))) == 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<BitIsReset>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%ecx
  shr    $0x3,%eax
  and    $0x7,%ecx
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int BitIsReset(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  return (D[Bit / 8] & (0x01 << (Bit % 8))) == 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BitIsReset>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%ecx
  shr    $0x3,%eax
  and    $0x7,%ecx
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  not    %eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int BitIsReset(void *Data, unsigned Bit) {
  unsigned char *D = Data;
  return (D[Bit / 8] & (0x01 << (Bit % 8))) == 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<maxSubArrayMain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xfffffffe,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0xfffffffd,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0xffffffff,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  movl   $0xfffffffb,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x9,-0x34(%rbp)
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <maxSubArray@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: D1: %d


assistant: ```c
void maxSubArrayMain(void) {
  int nums[] = {-2, 1, -3, 4, -1, 2, 1, -5, 4};
  int len = 0;
  { len = sizeof(nums) / sizeof(nums[0]); };
  printf("%d\n", maxSubArray(nums, len));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<maxSubArrayMain>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xfffffffe,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0xfffffffd,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0xfffffffb,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  mov    %rsp,%rdi
  mov    $0x9,%esi
  call   <maxSubArray@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: %d


assistant: ```c
void maxSubArrayMain(void) {
  int nums[] = {-2, 1, -3, 4, -1, 2, 1, -5, 4};
  int len = 0;
  { len = sizeof(nums) / sizeof(nums[0]); };
  printf("%d\n", maxSubArray(nums, len));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<maxSubArrayMain>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x9,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x1fffffffe,%rax
  mov    %rsp,%rdi
  movl   $0x4,0x20(%rsp)
  mov    %rax,(%rsp)
  movabs $0x4fffffffd,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2ffffffff,%rax
  mov    %rax,0x10(%rsp)
  movabs $0xfffffffb00000001,%rax
  mov    %rax,0x18(%rsp)
  call   <maxSubArray@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string

tool: D9: %d


assistant: ```c
void maxSubArrayMain(void) {
  int nums[] = {-2, 1, -3, 4, -1, 2, 1, -5, 4};
  int len = 0;
  { len = sizeof(nums) / sizeof(nums[0]); };
  printf("%d\n", maxSubArray(nums, len));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<maxSubArrayMain>:
  endbr64
  sub    $0x38,%rsp
  movdqa D3(%rip),%xmm0
  mov    $0x9,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x4,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D2(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <maxSubArray@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: byte[16]
name: retrieve_data
arguments: label: D2
data_type: byte[16]
name: retrieve_data
arguments: label: D22
data_type: string

tool: {"D3": [0xfe,0xff,0xff,0xff,0x01,0x00,0x00,0x00,0xfd,0xff,0xff,0xff,0x04,0x00,0x00,0x00]}

tool: {"D2": [0xff,0xff,0xff,0xff,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0xfb,0xff,0xff,0xff]}

tool: D22: %d


assistant: ```c
void maxSubArrayMain(void) {
  int nums[] = {-2, 1, -3, 4, -1, 2, 1, -5, 4};
  int len = 0;
  { len = sizeof(nums) / sizeof(nums[0]); };
  printf("%d\n", maxSubArray(nums, len));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L70
  movss  -0x14(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L70
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L12
L70:
  movss  -0x10(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L46
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L46
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L12
L46:
  movss  -0xc(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L12
  movss  -0xc(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L12
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string
name: retrieve_data
arguments: data_tag: D49
data_type: string

tool: D9: %f

tool: D49: %f


assistant: ```c
int main() {
  float a;
  float b;
  float c;
  printf("\n");
  scanf("%f", &a);
  printf("\n");
  scanf("%f", &b);
  printf("\n");
  scanf("%f", &c);
  if (a > b && a > c) {
    printf("%f\n", a);
  } else if (b > a && b > c) {
    printf("%f\n", b);
  } else if (c > a && c > b) {
    printf("%f\n", c);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  comiss %xmm0,%xmm1
  jbe    L65
  comiss 0x14(%rsp),%xmm1
  ja     L79
L65:
  comiss %xmm1,%xmm0
  jbe    L50
  comiss 0x14(%rsp),%xmm0
  ja     L14
L50:
  movss  0x14(%rsp),%xmm2
  comiss %xmm1,%xmm2
  jbe    L56
  comiss %xmm0,%xmm2
  ja     L74
L56:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L79:
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L56
L14:
  cvtss2sd %xmm0,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L56
L74:
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  lea    D19(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L56
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string

tool: D23: %f

tool: D19: %f


assistant: ```c
int main() {
  float a;
  float b;
  float c;
  printf("\n");
  scanf("%f", &a);
  printf("\n");
  scanf("%f", &b);
  printf("\n");
  scanf("%f", &c);
  if (a > b && a > c) {
    printf("%f\n", a);
  } else if (b > a && b > c) {
    printf("%f\n", b);
  } else if (c > a && c > b) {
    printf("%f\n", c);
  }
  return 0;
}
```