ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<concat>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D8(%rip),%rsi
  call   <asprintf@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: %s%s

assistant: ```c
char *concat(const char *str1, const char *str2) {
  char *newstr;
  if (asprintf(&newstr, "%s%s", str1, str2) == -1)
    return NULL;
  return newstr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<concat>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D4(%rip),%rsi
  call   <asprintf@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string

tool: D4: %s%s

assistant: ```c
char *concat(const char *str1, const char *str2) {
  char *newstr;
  if (asprintf(&newstr, "%s%s", str1, str2) == -1)
    return NULL;
  return newstr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<intersects>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L35:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L52
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L52
  mov    $0x1,%eax
  jmp    L17
L52:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L6
  addl   $0x1,-0xc(%rbp)
L33:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int intersects(int tupple1[], int cardinality1, int tupple2[], int cardinality2) {
  for (int i = 0; i < cardinality1; i++) {
    int num_matched = 0;
    for (int j = 0; j < cardinality2; j++) {
      if (tupple1[i] == tupple2[j]) {
        if (++num_matched == cardinality2)
          return 1;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intersects>:
  endbr64
  test   %esi,%esi
  jle    L65
  mov    %rdi,%r9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r8
  jmp    L28
L37:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L8
L45:
  cmp    (%rax),%edi
  jne    L37
  add    $0x1,%esi
  cmp    %esi,%ecx
  jne    L37
  mov    $0x1,%eax
  ret
L8:
  add    $0x4,%r9
  cmp    %r10,%r9
  je     L9
L28:
  test   %ecx,%ecx
  jle    L8
  mov    (%r9),%edi
  mov    %rdx,%rax
  mov    $0x0,%esi
  jmp    L45
L65:
  mov    $0x0,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int intersects(int tupple1[], int cardinality1, int tupple2[], int cardinality2) {
  for (int i = 0; i < cardinality1; i++) {
    int num_matched = 0;
    for (int j = 0; j < cardinality2; j++) {
      if (tupple1[i] == tupple2[j]) {
        if (++num_matched == cardinality2)
          return 1;
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<intersects>:
  endbr64
  test   %esi,%esi
  jle    L38
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r9
L12:
  test   %ecx,%ecx
  jle    L13
  mov    (%rdi),%r8d
  mov    %rdx,%rax
  xor    %esi,%esi
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L14:
  add    $0x4,%rax
  cmp    %r9,%rax
  je     L13
L1:
  cmp    (%rax),%r8d
  jne    L14
  add    $0x1,%esi
  cmp    %esi,%ecx
  jne    L14
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x4,%rdi
  cmp    %r10,%rdi
  jne    L12
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int intersects(int tupple1[], int cardinality1, int tupple2[], int cardinality2) {
  for (int i = 0; i < cardinality1; i++) {
    int num_matched = 0;
    for (int j = 0; j < cardinality2; j++) {
      if (tupple1[i] == tupple2[j]) {
        if (++num_matched == cardinality2)
          return 1;
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<intersects>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r10
  lea    -0x1(%rcx),%eax
  lea    0x4(%rdx,%rax,4),%r9
L23:
  test   %ecx,%ecx
  jle    L68
  mov    (%rdi),%r8d
  mov    %rdx,%rax
  xor    %esi,%esi
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x4,%rax
  cmp    %r9,%rax
  je     L68
L43:
  cmp    (%rax),%r8d
  jne    L9
  add    $0x1,%esi
  cmp    %esi,%ecx
  jne    L9
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x4,%rdi
  cmp    %r10,%rdi
  jne    L23
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int intersects(int tupple1[], int cardinality1, int tupple2[], int cardinality2) {
  for (int i = 0; i < cardinality1; i++) {
    int num_matched = 0;
    for (int j = 0; j < cardinality2; j++) {
      if (tupple1[i] == tupple2[j]) {
        if (++num_matched == cardinality2)
          return 1;
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ascii2unicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L11:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  add    %edx,%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movw   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ascii2unicode(unsigned short *out, const unsigned char *in) {
  int i = 0;
  unsigned char *outp = (unsigned char *)out;
  const unsigned char *inp = in;
  while (inp[i]) {
    outp[i * 2] = inp[i];
    outp[i * 2 + 1] = 0x00;
    i++;
  }
  out[i] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ascii2unicode>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L3
  mov    $0x1,%eax
L26:
  mov    %dl,-0x2(%rdi,%rax,2)
  movb   $0x0,-0x1(%rdi,%rax,2)
  mov    %rax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L26
L24:
  movw   $0x0,(%rdi,%rcx,2)
  ret
L3:
  mov    $0x0,%ecx
  jmp    L24
```

assistant: ```c
void ascii2unicode(unsigned short *out, const unsigned char *in) {
  int i = 0;
  unsigned char *outp = (unsigned char *)out;
  const unsigned char *inp = in;
  while (inp[i]) {
    outp[i * 2] = inp[i];
    outp[i * 2 + 1] = 0x00;
    i++;
  }
  out[i] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ascii2unicode>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L17
  mov    $0x1,%eax
L2:
  mov    %dl,-0x2(%rdi,%rax,2)
  mov    %rax,%rcx
  movb   $0x0,-0x1(%rdi,%rax,2)
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L2
  lea    (%rdi,%rcx,2),%rdi
L17:
  xor    %eax,%eax
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void ascii2unicode(unsigned short *out, const unsigned char *in) {
  int i = 0;
  unsigned char *outp = (unsigned char *)out;
  const unsigned char *inp = in;
  while (inp[i]) {
    outp[i * 2] = inp[i];
    outp[i * 2 + 1] = 0x00;
    i++;
  }
  out[i] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ascii2unicode>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L10
  mov    $0x1,%eax
L19:
  mov    %dl,-0x2(%rdi,%rax,2)
  mov    %rax,%rcx
  movb   $0x0,-0x1(%rdi,%rax,2)
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L19
  lea    (%rdi,%rcx,2),%rdi
L10:
  xor    %eax,%eax
  mov    %ax,(%rdi)
  ret
```

assistant: ```c
void ascii2unicode(unsigned short *out, const unsigned char *in) {
  int i = 0;
  unsigned char *outp = (unsigned char *)out;
  const unsigned char *inp = in;
  while (inp[i]) {
    outp[i * 2] = inp[i];
    outp[i * 2 + 1] = 0x00;
    i++;
  }
  out[i] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cuckooClock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  mov    -0x24(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <valid@plt>
  test   %eax,%eax
  je     L33
  mov    0x28(%rbp),%esi
  mov    0x20(%rbp),%ecx
  mov    0x18(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    %esi,%r8d
  mov    0x10(%rbp),%esi
  mov    %eax,%edi
  call   <valid@plt>
  test   %eax,%eax
  jne    L51
L33:
  mov    $0x0,%eax
  jmp    L0
L51:
  mov    -0x28(%rbp),%r9d
  mov    -0x24(%rbp),%r8d
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    0x28(%rbp),%edi
  push   %rdi
  mov    0x20(%rbp),%edi
  push   %rdi
  mov    0x18(%rbp),%edi
  push   %rdi
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %eax,%edi
  call   <position@plt>
  add    $0x20,%rsp
  test   %eax,%eax
  jne    L67
  mov    $0x0,%eax
  jmp    L0
L67:
  mov    0x28(%rbp),%esi
  mov    0x20(%rbp),%ecx
  mov    0x18(%rbp),%edx
  mov    -0x28(%rbp),%eax
  mov    $0x1,%r9d
  mov    %esi,%r8d
  mov    0x10(%rbp),%esi
  mov    %eax,%edi
  call   <uniqtimeidentifier@plt>
  mov    %rax,%rbx
  mov    -0x24(%rbp),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r9d
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <uniqtimeidentifier@plt>
  sub    %rax,%rbx
  mov    %rbx,%rdx
  mov    0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L81
  mov    -0x18(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jne    L81
  mov    -0x1c(%rbp),%eax
  cmp    0x18(%rbp),%eax
  jne    L81
  mov    -0x20(%rbp),%eax
  cmp    0x20(%rbp),%eax
  jne    L81
  cmpl   $0x1e,-0x24(%rbp)
  jne    L81
  cmpl   $0x1e,0x28(%rbp)
  jne    L81
  mov    0x30(%rbp),%rax
  movq   $0x1,(%rax)
L81:
  mov    $0x1,%eax
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int cuckooClock(int y1, int m1, int d1, int h1, int i1, int y2, int m2, int d2, int h2, int i2, long long int *cuckoo) {
  if (!valid(y1, m1, d1, h1, i1) || !valid(y2, m2, d2, h2, i2))
    return 0;
  if (!position(y1, m1, d1, h1, i1, y2, m2, d2, h2, i2))
    return 0;
  *cuckoo = uniqtimeidentifier(y2, m2, d2, h2, i2, 1) - uniqtimeidentifier(y1, m1, d1, h1, i1, 0);
  if (y1 == y2 && m1 == m2 && d1 == d2 && h1 == h2 && i1 == 30 && i2 == 30)
    *cuckoo = 1;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cuckooClock>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    %r9d,%r15d
  call   <valid@plt>
  test   %eax,%eax
  jne    L62
L72:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  mov    0x68(%rsp),%r8d
  mov    0x60(%rsp),%ecx
  mov    0x58(%rsp),%edx
  mov    0x50(%rsp),%esi
  mov    %r15d,%edi
  call   <valid@plt>
  test   %eax,%eax
  je     L72
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <position@plt>
  add    $0x20,%rsp
  test   %eax,%eax
  je     L72
  mov    $0x1,%r9d
  mov    0x68(%rsp),%r8d
  mov    0x60(%rsp),%ecx
  mov    0x58(%rsp),%edx
  mov    0x50(%rsp),%esi
  mov    %r15d,%edi
  call   <uniqtimeidentifier@plt>
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <uniqtimeidentifier@plt>
  mov    %rax,%rdx
  mov    0x8(%rsp),%rax
  sub    %rdx,%rax
  mov    0x70(%rsp),%rcx
  mov    %rax,(%rcx)
  cmp    %r15d,%ebx
  jne    L71
  cmp    0x50(%rsp),%ebp
  jne    L71
  cmp    0x58(%rsp),%r12d
  jne    L76
  cmp    0x60(%rsp),%r13d
  jne    L76
  cmp    $0x1e,%r14d
  jne    L7
  cmpl   $0x1e,0x68(%rsp)
  jne    L7
  movq   $0x1,(%rcx)
  mov    $0x1,%eax
  jmp    L72
L71:
  mov    $0x1,%eax
  jmp    L72
L76:
  mov    $0x1,%eax
  jmp    L72
L7:
  mov    $0x1,%eax
  jmp    L72
```

assistant: ```c
int cuckooClock(int y1, int m1, int d1, int h1, int i1, int y2, int m2, int d2, int h2, int i2, long long int *cuckoo) {
  if (!valid(y1, m1, d1, h1, i1) || !valid(y2, m2, d2, h2, i2))
    return 0;
  if (!position(y1, m1, d1, h1, i1, y2, m2, d2, h2, i2))
    return 0;
  *cuckoo = uniqtimeidentifier(y2, m2, d2, h2, i2, 1) - uniqtimeidentifier(y1, m1, d1, h1, i1, 0);
  if (y1 == y2 && m1 == m2 && d1 == d2 && h1 == h2 && i1 == 30 && i2 == 30)
    *cuckoo = 1;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cuckooClock>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  call   <valid@plt>
  test   %eax,%eax
  jne    L22
L80:
  xor    %eax,%eax
L74:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L22:
  mov    0x68(%rsp),%r8d
  mov    0x60(%rsp),%ecx
  mov    %r15d,%edi
  mov    0x58(%rsp),%edx
  mov    0x50(%rsp),%esi
  call   <valid@plt>
  test   %eax,%eax
  je     L80
  mov    0x68(%rsp),%eax
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  call   <position@plt>
  add    $0x20,%rsp
  test   %eax,%eax
  je     L80
  mov    0x68(%rsp),%r8d
  mov    0x60(%rsp),%ecx
  mov    $0x1,%r9d
  mov    %r15d,%edi
  mov    0x58(%rsp),%edx
  mov    0x50(%rsp),%esi
  call   <uniqtimeidentifier@plt>
  mov    %r14d,%r8d
  mov    %r12d,%edx
  xor    %r9d,%r9d
  mov    %r13d,%ecx
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    %rax,0x8(%rsp)
  call   <uniqtimeidentifier@plt>
  mov    0x70(%rsp),%rdx
  mov    %rax,%r8
  mov    0x8(%rsp),%rax
  sub    %r8,%rax
  mov    %rax,(%rdx)
  cmp    %r15d,%ebx
  jne    L47
  cmp    0x50(%rsp),%ebp
  jne    L47
  cmp    0x58(%rsp),%r12d
  jne    L47
  cmp    0x60(%rsp),%r13d
  jne    L47
  cmp    $0x1e,%r14d
  jne    L47
  cmpl   $0x1e,0x68(%rsp)
  jne    L47
  movq   $0x1,(%rdx)
  mov    $0x1,%eax
  jmp    L74
  nopl   0x0(%rax)
L47:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int cuckooClock(int y1, int m1, int d1, int h1, int i1, int y2, int m2, int d2, int h2, int i2, long long int *cuckoo) {
  if (!valid(y1, m1, d1, h1, i1) || !valid(y2, m2, d2, h2, i2))
    return 0;
  if (!position(y1, m1, d1, h1, i1, y2, m2, d2, h2, i2))
    return 0;
  *cuckoo = uniqtimeidentifier(y2, m2, d2, h2, i2, 1) - uniqtimeidentifier(y1, m1, d1, h1, i1, 0);
  if (y1 == y2 && m1 == m2 && d1 == d2 && h1 == h2 && i1 == 30 && i2 == 30)
    *cuckoo = 1;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cuckooClock>:
  endbr64
  push   %r15
  mov    %r9d,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  call   <valid@plt>
  test   %eax,%eax
  jne    L21
L23:
  xor    %eax,%eax
L78:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  mov    0x68(%rsp),%r8d
  mov    0x60(%rsp),%ecx
  mov    %r15d,%edi
  mov    0x58(%rsp),%edx
  mov    0x50(%rsp),%esi
  call   <valid@plt>
  test   %eax,%eax
  je     L23
  mov    0x68(%rsp),%eax
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  mov    0x68(%rsp),%eax
  push   %rax
  call   <position@plt>
  add    $0x20,%rsp
  test   %eax,%eax
  je     L23
  mov    0x68(%rsp),%r8d
  mov    0x60(%rsp),%ecx
  mov    $0x1,%r9d
  mov    %r15d,%edi
  mov    0x58(%rsp),%edx
  mov    0x50(%rsp),%esi
  call   <uniqtimeidentifier@plt>
  mov    %r14d,%r8d
  mov    %r12d,%edx
  xor    %r9d,%r9d
  mov    %r13d,%ecx
  mov    %ebp,%esi
  mov    %ebx,%edi
  mov    %rax,0x8(%rsp)
  call   <uniqtimeidentifier@plt>
  mov    0x70(%rsp),%rdx
  mov    %rax,%r8
  mov    0x8(%rsp),%rax
  sub    %r8,%rax
  mov    %rax,(%rdx)
  cmp    %r15d,%ebx
  jne    L41
  cmp    0x50(%rsp),%ebp
  jne    L41
  cmp    0x58(%rsp),%r12d
  jne    L41
  cmp    0x60(%rsp),%r13d
  jne    L41
  cmp    $0x1e,%r14d
  jne    L41
  cmpl   $0x1e,0x68(%rsp)
  jne    L41
  movq   $0x1,(%rdx)
  mov    $0x1,%eax
  jmp    L78
  nopl   0x0(%rax)
L41:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int cuckooClock(int y1, int m1, int d1, int h1, int i1, int y2, int m2, int d2, int h2, int i2, long long int *cuckoo) {
  if (!valid(y1, m1, d1, h1, i1) || !valid(y2, m2, d2, h2, i2))
    return 0;
  if (!position(y1, m1, d1, h1, i1, y2, m2, d2, h2, i2))
    return 0;
  *cuckoo = uniqtimeidentifier(y2, m2, d2, h2, i2, 1) - uniqtimeidentifier(y1, m1, d1, h1, i1, 0);
  if (y1 == y2 && m1 == m2 && d1 == d2 && h1 == h2 && i1 == 30 && i2 == 30)
    *cuckoo = 1;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L60:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  cmpb   $0x40,-0xd(%rbp)
  jle    L10
  cmpb   $0x5a,-0xd(%rbp)
  jg     L10
  movzbl -0xd(%rbp),%eax
  add    $0x20,%eax
  mov    %al,-0xd(%rbp)
L10:
  cmpb   $0x2d,-0xd(%rbp)
  jne    L27
  movb   $0x2d,-0xd(%rbp)
  jmp    L34
L27:
  movzbl -0xd(%rbp),%eax
  sub    $0x61,%eax
  mov    %al,-0xd(%rbp)
L34:
  mov    -0x20(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  movsbl -0xd(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L60
L53:
  mov    -0x1c(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen(char *str, int base, int mul) {
  unsigned int hash = 0;
  for (char *p = str; *p != 0 && *p != ' '; ++p) {
    char ch = *p;
    if (ch >= 'A' && ch <= 'Z') {
      ch += 'a' - 'A';
    }
    if ('-' == ch) {
      ch = '-';
    } else {
      ch -= 'a';
    }
    hash = hash * mul + ch;
  }
  hash %= base;
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gen>:
  endbr64
  movzbl (%rdi),%ecx
  test   $0xdf,%cl
  je     L17
  mov    $0x0,%eax
  jmp    L31
L3:
  cmp    $0x2d,%cl
  je     L48
L18:
  sub    $0x61,%ecx
L48:
  imul   %edx,%eax
  movsbl %cl,%ecx
  add    %ecx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   $0xdf,%cl
  je     L19
L31:
  lea    -0x41(%rcx),%r8d
  cmp    $0x19,%r8b
  ja     L3
  add    $0x20,%ecx
  jmp    L18
L17:
  mov    $0x0,%eax
L19:
  mov    $0x0,%edx
  div    %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int gen(char *str, int base, int mul) {
  unsigned int hash = 0;
  for (char *p = str; *p != 0 && *p != ' '; ++p) {
    char ch = *p;
    if (ch >= 'A' && ch <= 'Z') {
      ch += 'a' - 'A';
    }
    if ('-' == ch) {
      ch = '-';
    } else {
      ch -= 'a';
    }
    hash = hash * mul + ch;
  }
  hash %= base;
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen>:
  endbr64
  movzbl (%rdi),%r8d
  test   $0xdf,%r8b
  je     L44
  xor    %eax,%eax
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x2d,%ecx
  cmp    $0x2d,%r8b
  jne    L26
L7:
  imul   %edx,%eax
  movzbl 0x1(%rdi),%r8d
  add    $0x1,%rdi
  add    %ecx,%eax
  test   $0xdf,%r8b
  je     L8
L61:
  lea    -0x41(%r8),%ecx
  cmp    $0x19,%cl
  ja     L1
  movsbl %cl,%ecx
  jmp    L7
  nopl   (%rax)
L26:
  lea    -0x61(%r8),%ecx
  movsbl %cl,%ecx
  jmp    L7
  nopl   0x0(%rax)
L8:
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gen(char *str, int base, int mul) {
  unsigned int hash = 0;
  for (char *p = str; *p != 0 && *p != ' '; ++p) {
    char ch = *p;
    if (ch >= 'A' && ch <= 'Z') {
      ch += 'a' - 'A';
    }
    if ('-' == ch) {
      ch = '-';
    } else {
      ch -= 'a';
    }
    hash = hash * mul + ch;
  }
  hash %= base;
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen>:
  endbr64
  movzbl (%rdi),%r8d
  test   $0xdf,%r8b
  je     L15
  xor    %eax,%eax
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L54:
  mov    $0x2d,%ecx
  cmp    $0x2d,%r8b
  jne    L2
L60:
  imul   %edx,%eax
  movzbl 0x1(%rdi),%r8d
  add    $0x1,%rdi
  add    %ecx,%eax
  test   $0xdf,%r8b
  je     L18
L34:
  lea    -0x41(%r8),%ecx
  cmp    $0x19,%cl
  ja     L54
  movsbl %cl,%ecx
  jmp    L60
  nopl   (%rax)
L2:
  lea    -0x61(%r8),%ecx
  movsbl %cl,%ecx
  jmp    L60
  nopl   0x0(%rax)
L18:
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gen(char *str, int base, int mul) {
  unsigned int hash = 0;
  for (char *p = str; *p != 0 && *p != ' '; ++p) {
    char ch = *p;
    if (ch >= 'A' && ch <= 'Z') {
      ch += 'a' - 'A';
    }
    if ('-' == ch) {
      ch = '-';
    } else {
      ch -= 'a';
    }
    hash = hash * mul + ch;
  }
  hash %= base;
  return hash;
}
```