user: Converte this assembly snippet into its equivalent C code:

```asm
<two>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4443434c58585649,%rax
  mov    %rax,-0x11(%rbp)
  movb   $0x4d,-0x9(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x5,-0x3c(%rbp)
  movl   $0xa,-0x38(%rbp)
  movl   $0xa,-0x34(%rbp)
  movl   $0x32,-0x30(%rbp)
  movl   $0x64,-0x2c(%rbp)
  movl   $0x64,-0x28(%rbp)
  movl   $0x1f4,-0x24(%rbp)
  movl   $0x3e8,-0x20(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0x48(%rbp)
  jmp    L18
L74:
  movl   $0x2,-0x44(%rbp)
  jmp    L75
L5:
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x11(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4c(%rbp)
L0:
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x4c(%rbp),%eax
  cmp    %eax,%edx
  jle    L5
  cmpl   $0x0,-0x44(%rbp)
  je     L71
  mov    -0x44(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  lea    -0x1(%rax),%ecx
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  imul   %eax,%ecx
  mov    %ecx,%edx
  mov    -0x4c(%rbp),%eax
  cmp    %eax,%edx
  jg     L70
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %edx,%eax
  cltq
  movzbl -0x11(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x48(%rbp),%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  cltq
  movzbl -0x11(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4c(%rbp),%ecx
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%esi
  mov    -0x48(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  sub    %eax,%esi
  mov    %esi,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4c(%rbp)
L70:
  subl   $0x1,-0x44(%rbp)
L75:
  cmpl   $0x0,-0x44(%rbp)
  jns    L0
  jmp    L37
L71:
  nop
L37:
  subl   $0x1,-0x48(%rbp)
L18:
  cmpl   $0x0,-0x48(%rbp)
  jns    L74
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D26
type: string
name: read_data
arguments: tag: D45
type: string
name: read_data
arguments: tag: D3
type: string
name: read_data
arguments: tag: D48
type: string

tool: D15: enter number (int): 

tool: D26: %d

tool: D45: 
generated roman representation: 

tool: D3: %c%c

tool: D48: 
returning to menu. press Enter...

assistant: ```c
void two() {
  char numerals[9] = {'I', 'V', 'X', 'X', 'L', 'C', 'C', 'D', 'M'};
  int values[9] = {1, 5, 10, 10, 50, 100, 100, 500, 1000}, number, i, j;
  printf("enter number (int): ");
  scanf("%d", &number);
  printf("\ngenerated roman representation: ");
  for (i = 2; i >= 0; --i)
    for (j = 2; j >= 0; --j) {
      while (number >= values[3 * i + j]) {
        printf("%c", numerals[3 * i + j]);
        number -= values[3 * i + j];
      }
      if (j == 0)
        break;
      if (number >= (5 * j - 1) * values[3 * i]) {
        printf("%c%c", numerals[3 * i], numerals[3 * i + j]);
        number -= values[3 * i + j] - values[3 * i];
      }
    }
  printf("\n");
  getchar();
  printf("\nreturning to menu. press Enter...");
  getchar();
}
```