ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<merge_o_args>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  mov    (%rdi),%edx
  test   %edx,%edx
  jle    L13
  mov    %rdi,%r15
  lea    0x8(%rsi),%rbp
  lea    D9(%rip),%r13
  xor    %ebx,%ebx
  jmp    L11
  xchg   %ax,%ax
L52:
  mov    (%r15),%r12d
  lea    0x8(%rbp),%r14
  mov    %r14,%rbp
  cmp    %ebx,%r12d
  jle    L13
L11:
  mov    -0x8(%rbp),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  mov    %ebx,%edx
  add    $0x1,%ebx
  test   %rax,%rax
  jne    L52
  mov    (%r15),%eax
  lea    0x8(%rbp),%r14
  lea    -0x1(%rax),%r12d
  cmp    %ebx,%eax
  jg     L45
L54:
  mov    %r12d,(%r15)
  mov    %r14,%rbp
  cmp    %ebx,%r12d
  jg     L11
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L45:
  mov    0x0(%rbp),%rdi
  mov    %edx,0xc(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  lea    0x3(%rax),%rsi
  call   <arena_malloc@plt>
  mov    %rax,%r12
  mov    $0x6f2d,%eax
  mov    %ax,(%r12)
  mov    0x0(%rbp),%rsi
  lea    0x2(%r12),%rdi
  call   <strcpy@plt>
  mov    (%r15),%eax
  mov    %r12,-0x8(%rbp)
  lea    -0x1(%rax),%r12d
  cmp    %ebx,%r12d
  jle    L54
  mov    0xc(%rsp),%edx
  mov    $0xfffffffd,%esi
  mov    %rbp,%rdi
  sub    %edx,%esi
  add    %esi,%eax
  mov    %r14,%rsi
  mov    %eax,%eax
  lea    0x8(,%rax,8),%rdx
  call   <memmove@plt>
  jmp    L54
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: -o

assistant: ```c
void merge_o_args(int *argc, char **argv, struct arena *arena) {
  int i = 0;
  while (i < *argc) {
    char *arg = argv[i];
    if (strcmp(arg, "-o") == 0) {
      if (i + 1 < *argc) {
        char *merged = arena_malloc(arena, 2 + strlen(argv[i + 1]) + 1);
        merged[0] = '-';
        merged[1] = 'o';
        strcpy(&merged[2], argv[i + 1]);
        argv[i] = merged;
        for (int j = i + 1; j < *argc - 1; ++j) {
          argv[j] = argv[j + 1];
        }
      }
      --*argc;
    }
    ++i;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_func_02>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
L0:
  subq   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  subl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *test_func_02(int *p, int c, int x) {
  do {
    *--p = x;
  } while (--c);
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_func_02>:
  endbr64
  lea    -0x1(%rsi),%eax
  not    %rax
  lea    (%rdi,%rax,4),%rcx
  mov    %rdi,%rax
L8:
  sub    $0x4,%rax
  mov    %edx,(%rax)
  cmp    %rcx,%rax
  jne    L8
  lea    -0x1(%rsi),%eax
  not    %rax
  lea    (%rdi,%rax,4),%rax
  ret
```

assistant: ```c
int *test_func_02(int *p, int c, int x) {
  do {
    *--p = x;
  } while (--c);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_func_02>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    %rdi,%rax
  not    %rcx
  lea    (%rdi,%rcx,4),%rcx
  nopl   0x0(%rax)
L8:
  sub    $0x4,%rax
  mov    %edx,(%rax)
  cmp    %rcx,%rax
  jne    L8
  ret
```

assistant: ```c
int *test_func_02(int *p, int c, int x) {
  do {
    *--p = x;
  } while (--c);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_func_02>:
  endbr64
  lea    -0x1(%rsi),%eax
  mov    %esi,%ecx
  mov    %esi,%r10d
  mov    %edx,%r8d
  mov    %eax,%esi
  cmp    $0x2,%eax
  jbe    L54
  mov    %ecx,%r9d
  movd   %edx,%xmm1
  lea    -0x20(%rdi),%rdx
  shr    $0x2,%r9d
  pshufd $0x0,%xmm1,%xmm0
  lea    -0x10(%rdi),%rax
  sub    $0x1,%r9d
  shl    $0x4,%r9
  sub    %r9,%rdx
  nopl   0x0(%rax)
L31:
  movups %xmm0,(%rax)
  sub    $0x10,%rax
  cmp    %rdx,%rax
  jne    L31
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  sub    %eax,%ecx
  neg    %rdx
  lea    (%rdi,%rdx,4),%rdx
  cmp    %eax,%r10d
  je     L51
  lea    -0x1(%rcx),%eax
L46:
  mov    %r8d,-0x4(%rdx)
  test   %eax,%eax
  je     L51
  mov    %r8d,-0x8(%rdx)
  cmp    $0x2,%ecx
  je     L51
  mov    %r8d,-0xc(%rdx)
L51:
  mov    %esi,%esi
  not    %rsi
  lea    (%rdi,%rsi,4),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %rdi,%rdx
  jmp    L46
```

assistant: ```c
int *test_func_02(int *p, int c, int x) {
  do {
    *--p = x;
  } while (--c);
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<find_slashr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *find_slashr(const char *path) {
  char *result = strrchr(path, '/');
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_slashr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2f,%esi
  call   <strrchr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *find_slashr(const char *path) {
  char *result = strrchr(path, '/');
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_slashr>:
  endbr64
  mov    $0x2f,%esi
  jmp    1050 <strrchr@plt>
```

assistant: ```c
char *find_slashr(const char *path) {
  char *result = strrchr(path, '/');
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<find_slashr>:
  endbr64
  mov    $0x2f,%esi
  jmp    1050 <strrchr@plt>
```

assistant: ```c
char *find_slashr(const char *path) {
  char *result = strrchr(path, '/');
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mezery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  movsbl -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L3
  movsbq -0x1c(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *mezery(char *s, char len) {
  int i;
  for (i = 0; i < len; i++) {
    s[i] = ' ';
  }
  s[(int)len] = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mezery>:
  endbr64
  mov    %rdi,%rax
  test   %sil,%sil
  jle    L2
  mov    %rdi,%rdx
  movsbl %sil,%ecx
  lea    -0x1(%rcx),%ecx
  lea    0x1(%rdi,%rcx,1),%rcx
L3:
  movb   $0x20,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L3
L2:
  movsbq %sil,%rsi
  movb   $0x0,(%rax,%rsi,1)
  ret
```

assistant: ```c
char *mezery(char *s, char len) {
  int i;
  for (i = 0; i < len; i++) {
    s[i] = ' ';
  }
  s[(int)len] = '\0';
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mezery>:
  endbr64
  test   %sil,%sil
  mov    %rdi,%r8
  movsbq %sil,%rsi
  jle    L12
  movabs $0x2020202020202020,%rax
  cmp    $0x8,%esi
  jae    L64
  test   $0x4,%sil
  jne    L44
  test   %esi,%esi
  je     L12
  movb   $0x20,(%rdi)
  test   $0x2,%sil
  jne    L69
L12:
  movb   $0x0,(%r8,%rsi,1)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  mov    %esi,%edx
  mov    %rax,(%rdi)
  lea    0x8(%rdi),%rdi
  mov    %r8,%rcx
  mov    %rax,-0x10(%rdi,%rdx,1)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    %esi,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  movb   $0x0,(%r8,%rsi,1)
  mov    %r8,%rax
  ret
L69:
  mov    %esi,%eax
  mov    $0x2020,%edx
  mov    %dx,-0x2(%rdi,%rax,1)
  jmp    L12
L44:
  mov    %esi,%eax
  movl   $0x20202020,(%rdi)
  movl   $0x20202020,-0x4(%rdi,%rax,1)
  jmp    L12
```

assistant: ```c
char *mezery(char *s, char len) {
  int i;
  for (i = 0; i < len; i++) {
    s[i] = ' ';
  }
  s[(int)len] = '\0';
  return s;
}
```
user: What is the c source code of the assembly code below:

```asm
<mezery>:
  endbr64
  test   %sil,%sil
  mov    %rdi,%r8
  movsbq %sil,%rsi
  jle    L14
  movabs $0x2020202020202020,%rax
  cmp    $0x8,%esi
  jae    L64
  test   $0x4,%sil
  jne    L21
  test   %esi,%esi
  je     L14
  movb   $0x20,(%rdi)
  test   $0x2,%sil
  jne    L39
L14:
  movb   $0x0,(%r8,%rsi,1)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L64:
  mov    %esi,%edx
  mov    %rax,(%rdi)
  lea    0x8(%rdi),%rdi
  mov    %r8,%rcx
  mov    %rax,-0x10(%rdi,%rdx,1)
  and    $0xfffffffffffffff8,%rdi
  sub    %rdi,%rcx
  add    %esi,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  movb   $0x0,(%r8,%rsi,1)
  mov    %r8,%rax
  ret
L39:
  mov    %esi,%eax
  mov    $0x2020,%edx
  mov    %dx,-0x2(%rdi,%rax,1)
  jmp    L14
L21:
  mov    %esi,%eax
  movl   $0x20202020,(%rdi)
  movl   $0x20202020,-0x4(%rdi,%rax,1)
  jmp    L14
```

assistant: ```c
char *mezery(char *s, char len) {
  int i;
  for (i = 0; i < len; i++) {
    s[i] = ' ';
  }
  s[(int)len] = '\0';
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<longswap_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movzwl -0x10(%rbp),%eax
  mov    %ax,-0x12(%rbp)
  movzwl -0xe(%rbp),%eax
  mov    %ax,-0x10(%rbp)
  movzwl -0x12(%rbp),%eax
  mov    %ax,-0xe(%rbp)
  movzwl -0x10(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <shortswap_@plt>
  mov    %ax,-0x10(%rbp)
  movzwl -0xe(%rbp),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <shortswap_@plt>
  mov    %ax,-0xe(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
long int longswap_(le_long)
long int le_long;
{
  union {
    long wl;
    unsigned short ws[2];
  } wsbuf;
  short shold;
  wsbuf.wl = le_long;
  shold = wsbuf.ws[0];
  wsbuf.ws[0] = wsbuf.ws[1];
  wsbuf.ws[1] = shold;
  wsbuf.ws[0] = shortswap_(wsbuf.ws[0]);
  wsbuf.ws[1] = shortswap_(wsbuf.ws[1]);
  return (wsbuf.wl);
}
```
user: What is the c source code of the assembly code below:

```asm
<longswap_>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rbp
  shr    $0x10,%edi
  mov    $0x0,%eax
  call   <shortswap_@plt>
  mov    %ax,%bp
  movzwl %bx,%edi
  mov    $0x0,%eax
  call   <shortswap_@plt>
  movzwl %ax,%eax
  shl    $0x10,%rax
  movabs $0xffffffff0000ffff,%rdx
  and    %rdx,%rbp
  or     %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long int longswap_(le_long)
long int le_long;
{
  union {
    long wl;
    unsigned short ws[2];
  } wsbuf;
  short shold;
  wsbuf.wl = le_long;
  shold = wsbuf.ws[0];
  wsbuf.ws[0] = wsbuf.ws[1];
  wsbuf.ws[1] = shold;
  wsbuf.ws[0] = shortswap_(wsbuf.ws[0]);
  wsbuf.ws[1] = shortswap_(wsbuf.ws[1]);
  return (wsbuf.wl);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<longswap_>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  shr    $0x10,%edi
  sub    $0x8,%rsp
  call   <shortswap_@plt>
  movzwl %bx,%edi
  mov    %ax,%bp
  xor    %eax,%eax
  call   <shortswap_@plt>
  add    $0x8,%rsp
  movabs $0xffffffff0000ffff,%rdx
  movzwl %ax,%eax
  and    %rdx,%rbp
  pop    %rbx
  shl    $0x10,%rax
  or     %rbp,%rax
  pop    %rbp
  ret
```

assistant: ```c
long int longswap_(le_long)
long int le_long;
{
  union {
    long wl;
    unsigned short ws[2];
  } wsbuf;
  short shold;
  wsbuf.wl = le_long;
  shold = wsbuf.ws[0];
  wsbuf.ws[0] = wsbuf.ws[1];
  wsbuf.ws[1] = shold;
  wsbuf.ws[0] = shortswap_(wsbuf.ws[0]);
  wsbuf.ws[1] = shortswap_(wsbuf.ws[1]);
  return (wsbuf.wl);
}
```
user: Translate the below assembly code into C programming language:

```asm
<longswap_>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  shr    $0x10,%edi
  sub    $0x8,%rsp
  call   <shortswap_@plt>
  movzwl %bx,%edi
  mov    %ax,%bp
  xor    %eax,%eax
  call   <shortswap_@plt>
  add    $0x8,%rsp
  movabs $0xffffffff0000ffff,%rdx
  movzwl %ax,%eax
  and    %rdx,%rbp
  pop    %rbx
  shl    $0x10,%rax
  or     %rbp,%rax
  pop    %rbp
  ret
```

assistant: ```c
long int longswap_(le_long)
long int le_long;
{
  union {
    long wl;
    unsigned short ws[2];
  } wsbuf;
  short shold;
  wsbuf.wl = le_long;
  shold = wsbuf.ws[0];
  wsbuf.ws[0] = wsbuf.ws[1];
  wsbuf.ws[1] = shold;
  wsbuf.ws[0] = shortswap_(wsbuf.ws[0]);
  wsbuf.ws[1] = shortswap_(wsbuf.ws[1]);
  return (wsbuf.wl);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BN_mod_add_quick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BN_uadd@plt>
  test   %eax,%eax
  jne    L39
  mov    $0x0,%eax
  jmp    L1
L39:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BN_ucmp@plt>
  test   %rax,%rax
  js     L15
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BN_usub@plt>
  jmp    L1
L15:
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int BN_mod_add_quick(BIGNUM *r, const BIGNUM *a, const BIGNUM *b, const BIGNUM *m) {
  if (!BN_uadd(r, a, b))
    return 0;
  if (BN_ucmp(r, m) >= 0)
    return BN_usub(r, r, m);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BN_mod_add_quick>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rcx,%rbp
  call   <BN_uadd@plt>
  test   %eax,%eax
  jne    L20
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <BN_ucmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  js     L16
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <BN_usub@plt>
  jmp    L16
```

assistant: ```c
int BN_mod_add_quick(BIGNUM *r, const BIGNUM *a, const BIGNUM *b, const BIGNUM *m) {
  if (!BN_uadd(r, a, b))
    return 0;
  if (BN_ucmp(r, m) >= 0)
    return BN_usub(r, r, m);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BN_mod_add_quick>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <BN_uadd@plt>
  test   %eax,%eax
  jne    L2
L0:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <BN_ucmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  js     L0
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <BN_usub@plt>
```

assistant: ```c
int BN_mod_add_quick(BIGNUM *r, const BIGNUM *a, const BIGNUM *b, const BIGNUM *m) {
  if (!BN_uadd(r, a, b))
    return 0;
  if (BN_ucmp(r, m) >= 0)
    return BN_usub(r, r, m);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BN_mod_add_quick>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <BN_uadd@plt>
  test   %eax,%eax
  jne    L9
L3:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <BN_ucmp@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  js     L3
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <BN_usub@plt>
```

assistant: ```c
int BN_mod_add_quick(BIGNUM *r, const BIGNUM *a, const BIGNUM *b, const BIGNUM *m) {
  if (!BN_uadd(r, a, b))
    return 0;
  if (BN_ucmp(r, m) >= 0)
    return BN_usub(r, r, m);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vector_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L13
L8:
  movslq %ebx,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movslq %ebx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  add    $0x1,%ebx
L13:
  cmp    $0x7,%ebx
  jle    L8
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void vector_copy(short *VD, short *VS) {
  register int i;
  for (i = 0; i < 8; i++)
    VD[i] = VS[i];
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vector_copy>:
  endbr64
  mov    $0x0,%eax
L3:
  movzwl (%rsi,%rax,1),%edx
  mov    %dx,(%rdi,%rax,1)
  add    $0x2,%rax
  cmp    $0x10,%rax
  jne    L3
  ret
```

assistant: ```c
void vector_copy(short *VD, short *VS) {
  register int i;
  for (i = 0; i < 8; i++)
    VD[i] = VS[i];
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<vector_copy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  movzwl (%rsi,%rax,1),%edx
  mov    %dx,(%rdi,%rax,1)
  add    $0x2,%rax
  cmp    $0x10,%rax
  jne    L4
  ret
```

assistant: ```c
void vector_copy(short *VD, short *VS) {
  register int i;
  for (i = 0; i < 8; i++)
    VD[i] = VS[i];
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<vector_copy>:
  endbr64
  lea    0x2(%rsi),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  cmp    $0xc,%rax
  jbe    L1
  movdqu (%rsi),%xmm0
  movups %xmm0,(%rdi)
  ret
  nopl   0x0(%rax)
L1:
  movzwl (%rsi),%eax
  mov    %ax,(%rdi)
  movzwl 0x2(%rsi),%eax
  mov    %ax,0x2(%rdi)
  movzwl 0x4(%rsi),%eax
  mov    %ax,0x4(%rdi)
  movzwl 0x6(%rsi),%eax
  mov    %ax,0x6(%rdi)
  movzwl 0x8(%rsi),%eax
  mov    %ax,0x8(%rdi)
  movzwl 0xa(%rsi),%eax
  mov    %ax,0xa(%rdi)
  movzwl 0xc(%rsi),%eax
  mov    %ax,0xc(%rdi)
  movzwl 0xe(%rsi),%eax
  mov    %ax,0xe(%rdi)
  ret
```

assistant: ```c
void vector_copy(short *VD, short *VS) {
  register int i;
  for (i = 0; i < 8; i++)
    VD[i] = VS[i];
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<combination_at_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%edx
  mov    -0x44(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <choose@plt>
  sub    $0x1,%rax
  sub    -0x50(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L27
L29:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_LargestV@plt>
  mov    %eax,(%rbx)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <choose@plt>
  sub    %rax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  mov    %rax,-0x30(%rbp)
  subq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x34(%rbp)
L27:
  mov    -0x34(%rbp),%eax
  cmp    %eax,-0x48(%rbp)
  ja     L29
  movq   $0x0,-0x18(%rbp)
  jmp    L4
L7:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x44(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x58(%rbp),%rax
  add    %rcx,%rax
  sub    $0x1,%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x18(%rbp)
L4:
  mov    -0x48(%rbp),%eax
  cmp    %rax,-0x18(%rbp)
  jl     L7
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void combination_at_index(unsigned int n, unsigned int k, long m, unsigned *ans) {
  long a = n;
  long b = k;
  long x = (choose(n, k) - 1) - m;
  for (int i = 0; i < k; i++) {
    ans[i] = _LargestV(a, b, x);
    x = x - choose(ans[i], b);
    a = ans[i];
    b--;
  }
  for (long i = 0; i < k; ++i) {
    ans[i] = (n - 1) - ans[i];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<combination_at_index>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %rcx,%r15
  mov    %rcx,0x10(%rsp)
  mov    %edi,%r14d
  mov    %esi,%ebx
  mov    %rbx,%rsi
  call   <choose@plt>
  lea    -0x1(%rax),%r13
  sub    %rbp,%r13
  test   %r12d,%r12d
  je     L11
  mov    %r15,%rcx
  mov    %r15,%rbp
  mov    %r12d,%eax
  mov    %rax,0x18(%rsp)
  lea    -0x1(%rax),%r15
  lea    -0x1(%r12),%eax
  sub    %rax,%r15
  mov    %rcx,%r12
L22:
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <_LargestV@plt>
  mov    %eax,%edi
  mov    %eax,(%r12)
  mov    %rbx,%rsi
  call   <choose@plt>
  sub    %rax,%r13
  mov    (%r12),%r14d
  sub    $0x1,%rbx
  add    $0x4,%r12
  cmp    %r15,%rbx
  jne    L22
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rcx
  lea    (%rax,%rcx,4),%rcx
  mov    0xc(%rsp),%edx
  sub    $0x1,%edx
L17:
  mov    %edx,%eax
  sub    0x0(%rbp),%eax
  mov    %eax,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %rbp,%rcx
  jne    L17
L11:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void combination_at_index(unsigned int n, unsigned int k, long m, unsigned *ans) {
  long a = n;
  long b = k;
  long x = (choose(n, k) - 1) - m;
  for (int i = 0; i < k; i++) {
    ans[i] = _LargestV(a, b, x);
    x = x - choose(ans[i], b);
    a = ans[i];
    b--;
  }
  for (long i = 0; i < k; ++i) {
    ans[i] = (n - 1) - ans[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<combination_at_index>:
  endbr64
  push   %r15
  mov    %edi,%r9d
  mov    %rcx,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r14,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x28,%rsp
  mov    %edi,0x4(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %r9,0x10(%rsp)
  call   <choose@plt>
  lea    -0x1(%rax),%r8
  sub    %rbx,%r8
  test   %r14d,%r14d
  je     L35
  mov    %r15,%rcx
  mov    %r15,%rbx
  lea    -0x1(%r14),%r15
  mov    %r14,0x18(%rsp)
  lea    -0x1(%r14),%eax
  mov    %r15,%r13
  mov    0x10(%rsp),%r9
  mov    %r8,%r12
  sub    %rax,%r13
  mov    %rcx,%rbp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L15:
  sub    $0x1,%r15
L19:
  mov    %r9,%rdi
  mov    %r12,%rdx
  mov    %r14,%rsi
  add    $0x4,%rbp
  call   <_LargestV@plt>
  mov    %r14,%rsi
  mov    %r15,%r14
  mov    %eax,-0x4(%rbp)
  mov    %eax,%edi
  call   <choose@plt>
  mov    -0x4(%rbp),%r9d
  sub    %rax,%r12
  cmp    %r13,%r15
  jne    L15
  mov    0x4(%rsp),%r12d
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rcx
  sub    $0x1,%r12d
  lea    (%rax,%rcx,4),%rdx
  nopl   0x0(%rax)
L9:
  mov    %r12d,%eax
  sub    (%rbx),%eax
  add    $0x4,%rbx
  mov    %eax,-0x4(%rbx)
  cmp    %rbx,%rdx
  jne    L9
L35:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void combination_at_index(unsigned int n, unsigned int k, long m, unsigned *ans) {
  long a = n;
  long b = k;
  long x = (choose(n, k) - 1) - m;
  for (int i = 0; i < k; i++) {
    ans[i] = _LargestV(a, b, x);
    x = x - choose(ans[i], b);
    a = ans[i];
    b--;
  }
  for (long i = 0; i < k; ++i) {
    ans[i] = (n - 1) - ans[i];
  }
}
```