ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<doseek>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L30:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L30
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r13d
  shl    $0xe,%ebx
  xor    %edx,%edx
  mov    %ebp,%edi
  movslq %ebx,%r15
  mov    %r15,%rsi
  call   <lseek@plt>
  cmp    %ebx,%eax
  je     L41
  lea    D11(%rip),%rdi
  call   <io_error@plt>
L41:
  mov    %rsp,%r14
  mov    $0x4000,%edx
  mov    %ebp,%edi
  mov    %r14,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L39
L46:
  test   %r13d,%r13d
  jne    L15
L11:
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x4018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L15:
  xor    %eax,%eax
  call   <random@plt>
  movslq %r12d,%rcx
  xor    %edx,%edx
  mov    %r15,%rsi
  shr    $0x2,%rcx
  cltq
  mov    %ebp,%edi
  sub    $0x2,%rcx
  div    %rcx
  subl   $0x1,0x4(%rsp,%rdx,4)
  xor    %edx,%edx
  call   <lseek@plt>
  cmp    %ebx,%eax
  jne    L40
L73:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L11
  lea    D3(%rip),%rdi
  call   <io_error@plt>
  jmp    L11
  xchg   %ax,%ax
L39:
  lea    D33(%rip),%rdi
  call   <io_error@plt>
  jmp    L46
  nopl   0x0(%rax)
L40:
  lea    D27(%rip),%rdi
  call   <io_error@plt>
  jmp    L73
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: string
name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D33
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: string

tool: D11: lseek in doseek

tool: D3: write in doseek

tool: D33: read in doseek

tool: D27: lseek in doseek update

assistant: ```c
void doseek(off_t where, int fd, int update) {
  int buf[(16384) / (sizeof(int))];
  off_t probe;
  off_t size;
  probe = where * (16384);
  if (lseek(fd, probe, 0) != probe)
    io_error("lseek in doseek");
  if ((size = read(fd, (char *)buf, (16384))) == -1)
    io_error("read in doseek");
  if (update) {
    buf[((int)random() % (size / (sizeof(int)) - 2)) + 1]--;
    if (lseek(fd, (long)probe, 0) != probe)
      io_error("lseek in doseek update");
    if (write(fd, (char *)buf, size) == -1)
      io_error("write in doseek");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<doseek>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L97:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L97
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4008(%rsp)
  xor    %eax,%eax
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r13d
  shl    $0xe,%ebx
  xor    %edx,%edx
  mov    %ebp,%edi
  movslq %ebx,%r15
  mov    %r15,%rsi
  call   <lseek@plt>
  cmp    %ebx,%eax
  je     L92
  lea    D3(%rip),%rdi
  call   <io_error@plt>
L92:
  mov    %rsp,%r14
  mov    $0x4000,%edx
  mov    %ebp,%edi
  mov    %r14,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L10
L60:
  test   %r13d,%r13d
  jne    L49
L65:
  mov    0x4008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x4018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L49:
  xor    %eax,%eax
  call   <random@plt>
  movslq %r12d,%rcx
  xor    %edx,%edx
  mov    %r15,%rsi
  shr    $0x2,%rcx
  cltq
  mov    %ebp,%edi
  sub    $0x2,%rcx
  div    %rcx
  subl   $0x1,0x4(%rsp,%rdx,4)
  xor    %edx,%edx
  call   <lseek@plt>
  cmp    %ebx,%eax
  jne    L31
L29:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L65
  lea    D22(%rip),%rdi
  call   <io_error@plt>
  jmp    L65
  xchg   %ax,%ax
L10:
  lea    D23(%rip),%rdi
  call   <io_error@plt>
  jmp    L60
  nopl   0x0(%rax)
L31:
  lea    D34(%rip),%rdi
  call   <io_error@plt>
  jmp    L29
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D22
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D34
data_type: string

tool: D3: lseek in doseek

tool: D22: write in doseek

tool: D23: read in doseek

tool: D34: lseek in doseek update

assistant: ```c
void doseek(off_t where, int fd, int update) {
  int buf[(16384) / (sizeof(int))];
  off_t probe;
  off_t size;
  probe = where * (16384);
  if (lseek(fd, probe, 0) != probe)
    io_error("lseek in doseek");
  if ((size = read(fd, (char *)buf, (16384))) == -1)
    io_error("read in doseek");
  if (update) {
    buf[((int)random() % (size / (sizeof(int)) - 2)) + 1]--;
    if (lseek(fd, (long)probe, 0) != probe)
      io_error("lseek in doseek update");
    if (write(fd, (char *)buf, size) == -1)
      io_error("write in doseek");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getrateunit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x4,-0x8(%rbp)
  jle    L5
  mov    D15(%rip),%rax
  jmp    L0
L5:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D15(%rip),%rax
  mov    (%rdx,%rax,1),%rax
L0:
  pop    %rbp
  ret
```

assistant: ```c
char *getrateunit(int unit, int index) {
  static char *bunit[] = {"na", "KiB/s", "MiB/s", "GiB/s", "TiB/s", "KB/s", "MB/s", "GB/s", "TB/s", "kbit/s", "Mbit/s", "Gbit/s", "Tbit/s"};
  if (index > 4) {
    return bunit[0];
  } else {
    return bunit[(unit * 4) + index];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getrateunit>:
  endbr64
  lea    D5(%rip),%rax
  cmp    $0x4,%esi
  jg     L6
  lea    (%rsi,%rdi,4),%eax
  cltq
  lea    D2(%rip),%rdx
  mov    (%rdx,%rax,8),%rax
L6:
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
datatype: string

tool: D5: na

assistant: ```c
char *getrateunit(int unit, int index) {
  static char *bunit[] = {"na", "KiB/s", "MiB/s", "GiB/s", "TiB/s", "KB/s", "MB/s", "GB/s", "TB/s", "kbit/s", "Mbit/s", "Gbit/s", "Tbit/s"};
  if (index > 4) {
    return bunit[0];
  } else {
    return bunit[(unit * 4) + index];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getrateunit>:
  endbr64
  lea    D6(%rip),%rax
  cmp    $0x4,%esi
  jg     L0
  lea    (%rsi,%rdi,4),%eax
  lea    D9(%rip),%rdx
  cltq
  mov    (%rdx,%rax,8),%rax
L0:
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: na

assistant: ```c
char *getrateunit(int unit, int index) {
  static char *bunit[] = {"na", "KiB/s", "MiB/s", "GiB/s", "TiB/s", "KB/s", "MB/s", "GB/s", "TB/s", "kbit/s", "Mbit/s", "Gbit/s", "Tbit/s"};
  if (index > 4) {
    return bunit[0];
  } else {
    return bunit[(unit * 4) + index];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getrateunit>:
  endbr64
  lea    D1(%rip),%rax
  cmp    $0x4,%esi
  jg     L5
  lea    (%rsi,%rdi,4),%eax
  lea    D11(%rip),%rdx
  cltq
  mov    (%rdx,%rax,8),%rax
L5:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: na

assistant: ```c
char *getrateunit(int unit, int index) {
  static char *bunit[] = {"na", "KiB/s", "MiB/s", "GiB/s", "TiB/s", "KB/s", "MB/s", "GB/s", "TB/s", "kbit/s", "Mbit/s", "Gbit/s", "Tbit/s"};
  if (index > 4) {
    return bunit[0];
  } else {
    return bunit[(unit * 4) + index];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<lseek>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
off_t lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = EBADF;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lseek>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
off_t lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = EBADF;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lseek>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
off_t lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = EBADF;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lseek>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
off_t lseek(int fd, off_t offset, int whence) {
  (void)fd;
  (void)offset;
  (void)whence;
  errno = EBADF;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tcp_verify_checksum>:
  endbr64
  sub    $0xbc8,%rsp
  mov    %rdi,%rcx
  mov    %edx,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0xbb8(%rsp)
  xor    %eax,%eax
  test   $0x1,%dl
  je     L26
  mov    %edx,%eax
  movb   $0x0,(%rcx,%rax,1)
  add    $0x1,%edi
L26:
  mov    $0x0,%eax
L0:
  movzbl (%rsi,%rax,1),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rsi,%rax,1),%r8d
  or     %r8d,%edx
  mov    %edx,(%rsp,%rax,2)
  add    $0x2,%rax
  cmp    $0xc,%rax
  jne    L0
  test   %edi,%edi
  je     L43
  mov    $0x0,%eax
L41:
  movzbl (%rcx,%rax,1),%edx
  shl    $0x8,%edx
  movzbl 0x1(%rcx,%rax,1),%esi
  or     %esi,%edx
  mov    %edx,0x20(%rsp,%rax,2)
  add    $0x2,%rax
  cmp    %eax,%edi
  ja     L41
L43:
  mov    %rsp,%rax
  lea    0x18(%rsp),%rsi
  mov    $0x0,%edx
L69:
  mov    (%rax),%ecx
  add    %rcx,%rdx
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L69
  mov    %edi,%esi
  shr    %esi
  cmp    $0x1,%edi
  jbe    L73
  mov    $0x0,%eax
  lea    0x20(%rsp),%rdi
L32:
  mov    (%rdi,%rax,4),%ecx
  add    %rcx,%rdx
  add    $0x1,%rax
  cmp    %eax,%esi
  ja     L32
L73:
  movzwl %dx,%eax
  sar    $0x10,%rdx
  add    %edx,%eax
  not    %eax
  mov    0xbb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L71
  add    $0xbc8,%rsp
  ret
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int tcp_verify_checksum(unsigned char segment[], unsigned char psuedo[], unsigned int size) {
  unsigned int actual_size, header_16bit_words[740], psuedo_header_16bit_words[6], count, index, result;
  long sum = 0, temp = 0;
  if (size % 2 != 0) {
    segment[size] = 0;
    actual_size = size + 1;
  } else {
    actual_size = size;
  }
  for (count = 0, index = 0; index < 12; ++count, index += 2) {
    psuedo_header_16bit_words[count] = psuedo[index];
    psuedo_header_16bit_words[count] = (psuedo_header_16bit_words[count] << 8);
    psuedo_header_16bit_words[count] |= psuedo[index + 1];
  }
  for (count = 0, index = 0; index < actual_size; ++count, index += 2) {
    header_16bit_words[count] = segment[index];
    header_16bit_words[count] = (header_16bit_words[count] << 8);
    header_16bit_words[count] |= segment[index + 1];
  }
  for (count = 0; count < 6; ++count) {
    sum += psuedo_header_16bit_words[count];
  }
  for (count = 0; count < (actual_size / 2); ++count) {
    sum += header_16bit_words[count];
  }
  temp = (sum >> 16);
  sum &= 0xFFFF;
  result = sum + temp;
  result = ~result;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<tcp_verify_checksum>:
  endbr64
  sub    $0xbc8,%rsp
  mov    %edx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xbb8(%rsp)
  xor    %eax,%eax
  and    $0x1,%edx
  je     L48
  mov    %r8d,%eax
  add    $0x1,%r8d
  movb   $0x0,(%rdi,%rax,1)
L48:
  xor    %eax,%eax
  mov    %rsp,%rcx
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl (%rsi,%rax,1),%edx
  movzbl 0x1(%rsi,%rax,1),%r9d
  shl    $0x8,%edx
  or     %r9d,%edx
  mov    %edx,(%rcx,%rax,2)
  add    $0x2,%rax
  cmp    $0xc,%rax
  jne    L5
  test   %r8d,%r8d
  je     L42
  xor    %eax,%eax
  lea    0x20(%rsp),%r9
  nopl   0x0(%rax)
L64:
  movzbl (%rdi,%rax,1),%edx
  movzbl 0x1(%rdi,%rax,1),%esi
  shl    $0x8,%edx
  or     %esi,%edx
  mov    %edx,(%r9,%rax,2)
  add    $0x2,%rax
  cmp    %eax,%r8d
  ja     L64
L42:
  mov    %rcx,%rax
  lea    0x18(%rsp),%rsi
  xor    %edx,%edx
  nopl   (%rax)
L67:
  mov    (%rax),%ecx
  add    $0x4,%rax
  add    %rcx,%rdx
  cmp    %rax,%rsi
  jne    L67
  shr    %r8d
  je     L55
  lea    -0x1(%r8),%ecx
  lea    0x20(%rsp),%rax
  lea    0x24(%rsp,%rcx,4),%rsi
  nopl   0x0(%rax)
L16:
  mov    (%rax),%ecx
  add    $0x4,%rax
  add    %rcx,%rdx
  cmp    %rax,%rsi
  jne    L16
L55:
  movzwl %dx,%eax
  sar    $0x10,%rdx
  add    %edx,%eax
  not    %eax
  mov    0xbb8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0xbc8,%rsp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int tcp_verify_checksum(unsigned char segment[], unsigned char psuedo[], unsigned int size) {
  unsigned int actual_size, header_16bit_words[740], psuedo_header_16bit_words[6], count, index, result;
  long sum = 0, temp = 0;
  if (size % 2 != 0) {
    segment[size] = 0;
    actual_size = size + 1;
  } else {
    actual_size = size;
  }
  for (count = 0, index = 0; index < 12; ++count, index += 2) {
    psuedo_header_16bit_words[count] = psuedo[index];
    psuedo_header_16bit_words[count] = (psuedo_header_16bit_words[count] << 8);
    psuedo_header_16bit_words[count] |= psuedo[index + 1];
  }
  for (count = 0, index = 0; index < actual_size; ++count, index += 2) {
    header_16bit_words[count] = segment[index];
    header_16bit_words[count] = (header_16bit_words[count] << 8);
    header_16bit_words[count] |= segment[index + 1];
  }
  for (count = 0; count < 6; ++count) {
    sum += psuedo_header_16bit_words[count];
  }
  for (count = 0; count < (actual_size / 2); ++count) {
    sum += header_16bit_words[count];
  }
  temp = (sum >> 16);
  sum &= 0xFFFF;
  result = sum + temp;
  result = ~result;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<any>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L8
L35:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L8
  mov    $0x1,%eax
  jmp    L38
L8:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int any(int c, char *s) {
  while (*s) {
    if (c == *s++)
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<any>:
  endbr64
L17:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L6
  add    $0x1,%rsi
  movsbl %al,%eax
  cmp    %edi,%eax
  jne    L17
  mov    $0x1,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int any(int c, char *s) {
  while (*s) {
    if (c == *s++)
      return 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<any>:
  endbr64
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L12:
  add    $0x1,%rsi
  cmp    %edi,%eax
  je     L1
L17:
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L12
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int any(int c, char *s) {
  while (*s) {
    if (c == *s++)
      return 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<any>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L28:
  add    $0x1,%rsi
  cmp    %edi,%eax
  je     L17
L7:
  movsbl (%rsi),%eax
  test   %al,%al
  jne    L28
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int any(int c, char *s) {
  while (*s) {
    if (c == *s++)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Mult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float Mult(float num3, float num4) {
  float result2 = 0.0;
  result2 = num3 * num4;
  return result2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Mult>:
  endbr64
  mulss  %xmm1,%xmm0
  ret
```

assistant: ```c
float Mult(float num3, float num4) {
  float result2 = 0.0;
  result2 = num3 * num4;
  return result2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Mult>:
  endbr64
  mulss  %xmm1,%xmm0
  ret
```

assistant: ```c
float Mult(float num3, float num4) {
  float result2 = 0.0;
  result2 = num3 * num4;
  return result2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Mult>:
  endbr64
  mulss  %xmm1,%xmm0
  ret
```

assistant: ```c
float Mult(float num3, float num4) {
  float result2 = 0.0;
  result2 = num3 * num4;
  return result2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L13
L1:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <get_number@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x14(%rbp,%rdx,4)
  addl   $0x1,-0x18(%rbp)
L13:
  cmpl   $0x2,-0x18(%rbp)
  jle    L1
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L18
L5:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  movl   $0x0,-0x14(%rbp,%rax,4)
  addl   $0x1,-0x18(%rbp)
L18:
  cmpl   $0x2,-0x18(%rbp)
  jle    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string
name: read_data
arguments: tag: D1
datatype: string
name: read_data
arguments: tag: D31
datatype: string
name: read_data
arguments: tag: D23
datatype: string

tool: D0: Valid digits are from 0 to 99

tool: D1: Enter digit #%d: 

tool: D31: The combination is: 

tool: D23:  %02d

assistant: ```c
int main() {
  int x, digit[3];
  puts("Valid digits are from 0 to 99");
  for (x = 0; x < 3; x++) {
    printf("Enter digit #%d: ", x + 1);
    digit[x] = get_number();
  }
  printf("The combination is: ");
  for (x = 0; x < 3; x++) {
    printf(" %02d", digit[x]);
    digit[x] = 0;
  }
  putchar('\n');
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%ebx
  lea    D32(%rip),%rbp
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <get_number@plt>
  mov    %eax,0x8(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L9
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rbx
  lea    0x18(%rsp),%r12
  lea    D12(%rip),%rbp
L27:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D23
datatype: string
name: parse_data
arguments: data_label: D32
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string

tool: D23: Valid digits are from 0 to 99

tool: D32: Enter digit #%d: 

tool: D5: The combination is: 

tool: D12:  %02d

assistant: ```c
int main() {
  int x, digit[3];
  puts("Valid digits are from 0 to 99");
  for (x = 0; x < 3; x++) {
    printf("Enter digit #%d: ", x + 1);
    digit[x] = get_number();
  }
  printf("The combination is: ");
  for (x = 0; x < 3; x++) {
    printf(" %02d", digit[x]);
    digit[x] = 0;
  }
  putchar('\n');
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%rdi
  lea    D28(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  call   <puts@plt>
L12:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <get_number@plt>
  mov    %eax,-0x4(%rbx,%rbp,4)
  add    $0x1,%rbp
  cmp    $0x4,%rbp
  jne    L12
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  lea    0x18(%rsp),%r12
  call   <printf@plt>
  lea    D14(%rip),%rbp
L1:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  movl   $0x0,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L1
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D14
type_infered: string

tool: D2: Valid digits are from 0 to 99

tool: D28: Enter digit #%d: 

tool: D38: The combination is: 

tool: D14:  %02d

assistant: ```c
int main() {
  int x, digit[3];
  puts("Valid digits are from 0 to 99");
  for (x = 0; x < 3; x++) {
    printf("Enter digit #%d: ", x + 1);
    digit[x] = get_number();
  }
  printf("The combination is: ");
  for (x = 0; x < 3; x++) {
    printf(" %02d", digit[x]);
    digit[x] = 0;
  }
  putchar('\n');
  return (0);
}
```