ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  lea    D16(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L2
  xor    %ebx,%ebx
  lea    D29(%rip),%r13
  nopl   (%rax)
L4:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L4
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string
name: read_data
arguments: data_tag: D29
type_infered: string

tool: D16: Hello argv!

tool: D7: argc len = %d


tool: D29: argv[ %d ] = %s


assistant: ```c
int main(int argc, char **argv) {
  printf("Hello argv!\n");
  printf("argc len = %d\n", argc);
  for (int i = 0; i < argc; ++i) {
    printf("argv[ %d ] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test(void) {
  pid_t pid;
  pid = getpid();
  return pid;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int test(void) {
  pid_t pid;
  pid = getpid();
  return pid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <getpid@plt>
```

assistant: ```c
int test(void) {
  pid_t pid;
  pid = getpid();
  return pid;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<characterReplacement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %esi,-0x8c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x80(%rbp)
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x74(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L16
L33:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  mov    -0x74(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x74(%rbp)
  jmp    L43
L5:
  mov    -0x78(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x78(%rbp)
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x41,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  sub    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
L43:
  mov    -0x7c(%rbp),%eax
  sub    -0x78(%rbp),%eax
  add    $0x1,%eax
  sub    -0x74(%rbp),%eax
  cmp    %eax,-0x8c(%rbp)
  jl     L5
  mov    -0x7c(%rbp),%eax
  sub    -0x78(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x80(%rbp),%eax
  cmp    %edx,%eax
  cmovl  %edx,%eax
  mov    %eax,-0x80(%rbp)
  addl   $0x1,-0x7c(%rbp)
L16:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x80(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int characterReplacement(char *s, int k) {
  int ret = 0, i, start = 0, count[26] = {0}, dominant = 0;
  for (i = 0; s[i]; ++i) {
    ++count[s[i] - 'A'];
    dominant = ((dominant) > (count[s[i] - 'A']) ? (dominant) : (count[s[i] - 'A']));
    while (i - start + 1 - dominant > k)
      --count[s[start++] - 'A'];
    ret = ((ret) > (i - start + 1) ? (ret) : (i - start + 1));
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<characterReplacement>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  movzbl (%r8),%eax
  test   %al,%al
  je     L3
  mov    %esi,%r9d
  mov    $0x0,%r10d
  mov    $0x0,%r11d
  mov    $0x0,%edi
  mov    $0x0,%ebx
L0:
  mov    %r10d,%esi
  movsbl %al,%eax
  sub    $0x41,%eax
  cltq
  mov    (%rsp,%rax,4),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%rsp,%rax,4)
  cmp    %edx,%r11d
  cmovl  %edx,%r11d
  mov    %r10d,%ecx
  sub    %edi,%ecx
  add    $0x1,%ecx
  mov    %ecx,%eax
  sub    %r11d,%eax
  cmp    %eax,%r9d
  jge    L30
  lea    0x1(%rdi),%edx
  movslq %edx,%rdx
  lea    0x1(%r10),%ebp
  add    $0x2,%esi
  sub    %r11d,%esi
L36:
  mov    %edx,%edi
  movsbl -0x1(%r8,%rdx,1),%eax
  sub    $0x41,%eax
  cltq
  subl   $0x1,(%rsp,%rax,4)
  mov    %ebp,%ecx
  sub    %edx,%ecx
  add    $0x1,%rdx
  mov    %esi,%eax
  sub    %edx,%eax
  cmp    %eax,%r9d
  jl     L36
L30:
  cmp    %ecx,%ebx
  cmovl  %ecx,%ebx
  add    $0x1,%r10
  movzbl (%r8,%r10,1),%eax
  test   %al,%al
  jne    L0
L46:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %ebx,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0x0,%ebx
  jmp    L46
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int characterReplacement(char *s, int k) {
  int ret = 0, i, start = 0, count[26] = {0}, dominant = 0;
  for (i = 0; s[i]; ++i) {
    ++count[s[i] - 'A'];
    dominant = ((dominant) > (count[s[i] - 'A']) ? (dominant) : (count[s[i] - 'A']));
    while (i - start + 1 - dominant > k)
      --count[s[start++] - 'A'];
    ret = ((ret) > (i - start + 1) ? (ret) : (i - start + 1));
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<characterReplacement>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    $0xd,%ecx
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  movsbl (%r8),%eax
  test   %al,%al
  je     L22
  mov    %esi,%r9d
  xor    %edi,%edi
  xor    %r10d,%r10d
  xor    %ebx,%ebx
  xor    %r11d,%r11d
  nopl   0x0(%rax)
L53:
  sub    $0x41,%eax
  mov    %edi,%esi
  cltq
  mov    (%rsp,%rax,4),%ecx
  lea    0x1(%rcx),%edx
  mov    %edi,%ecx
  cmp    %edx,%r10d
  mov    %edx,(%rsp,%rax,4)
  cmovl  %edx,%r10d
  sub    %ebx,%ecx
  add    $0x1,%ecx
  mov    %ecx,%eax
  sub    %r10d,%eax
  cmp    %eax,%r9d
  jge    L4
  lea    0x1(%rbx),%edx
  add    $0x2,%esi
  lea    0x1(%rdi),%ebp
  movslq %edx,%rdx
  sub    %r10d,%esi
  nop
L35:
  movsbl -0x1(%r8,%rdx,1),%eax
  mov    %ebp,%ecx
  mov    %edx,%ebx
  sub    %edx,%ecx
  add    $0x1,%rdx
  sub    $0x41,%eax
  cltq
  subl   $0x1,(%rsp,%rax,4)
  mov    %esi,%eax
  sub    %edx,%eax
  cmp    %eax,%r9d
  jl     L35
L4:
  cmp    %ecx,%r11d
  cmovl  %ecx,%r11d
  add    $0x1,%rdi
  movsbl (%r8,%rdi,1),%eax
  test   %al,%al
  jne    L53
L58:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x78,%rsp
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  xor    %r11d,%r11d
  jmp    L58
L44:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int characterReplacement(char *s, int k) {
  int ret = 0, i, start = 0, count[26] = {0}, dominant = 0;
  for (i = 0; s[i]; ++i) {
    ++count[s[i] - 'A'];
    dominant = ((dominant) > (count[s[i] - 'A']) ? (dominant) : (count[s[i] - 'A']));
    while (i - start + 1 - dominant > k)
      --count[s[start++] - 'A'];
    ret = ((ret) > (i - start + 1) ? (ret) : (i - start + 1));
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<characterReplacement>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    $0xd,%ecx
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  rep stos %rax,%es:(%rdi)
  movsbl (%r8),%eax
  test   %al,%al
  je     L58
  mov    %esi,%r9d
  xor    %edi,%edi
  xor    %r10d,%r10d
  xor    %ebx,%ebx
  xor    %r11d,%r11d
  nopl   0x0(%rax)
L42:
  sub    $0x41,%eax
  mov    %edi,%esi
  cltq
  mov    (%rsp,%rax,4),%ecx
  lea    0x1(%rcx),%edx
  mov    %edi,%ecx
  cmp    %edx,%r10d
  mov    %edx,(%rsp,%rax,4)
  cmovl  %edx,%r10d
  sub    %ebx,%ecx
  add    $0x1,%ecx
  mov    %ecx,%eax
  sub    %r10d,%eax
  cmp    %eax,%r9d
  jge    L56
  lea    0x1(%rbx),%edx
  add    $0x2,%esi
  lea    0x1(%rdi),%ebp
  movslq %edx,%rdx
  sub    %r10d,%esi
  nop
L57:
  movsbl -0x1(%r8,%rdx,1),%eax
  mov    %ebp,%ecx
  mov    %edx,%ebx
  sub    %edx,%ecx
  add    $0x1,%rdx
  sub    $0x41,%eax
  cltq
  subl   $0x1,(%rsp,%rax,4)
  mov    %esi,%eax
  sub    %edx,%eax
  cmp    %eax,%r9d
  jl     L57
L56:
  cmp    %ecx,%r11d
  cmovl  %ecx,%r11d
  add    $0x1,%rdi
  movsbl (%r8,%rdi,1),%eax
  test   %al,%al
  jne    L42
L34:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x78,%rsp
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  ret
L58:
  xor    %r11d,%r11d
  jmp    L34
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int characterReplacement(char *s, int k) {
  int ret = 0, i, start = 0, count[26] = {0}, dominant = 0;
  for (i = 0; s[i]; ++i) {
    ++count[s[i] - 'A'];
    dominant = ((dominant) > (count[s[i] - 'A']) ? (dominant) : (count[s[i] - 'A']));
    while (i - start + 1 - dominant > k)
      --count[s[start++] - 'A'];
    ret = ((ret) > (i - start + 1) ? (ret) : (i - start + 1));
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L149
  mov    %rbx,%r12
  mov    $0x0,%ebp
  lea    D7(%rip),%r13
L44:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebp
  add    $0x4,%r12
  cmp    %ebp,0x4(%rsp)
  jg     L44
L149:
  cmpl   $0x1,0x4(%rsp)
  jle    L58
  mov    %rbx,%rdx
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  jmp    L62
L148:
  mov    (%rdx),%esi
  mov    (%rbx,%rax,4),%ecx
  cmp    %ecx,%esi
  jge    L122
  mov    %esi,(%rbx,%rax,4)
  mov    %ecx,(%rdx)
L122:
  add    $0x1,%rax
  cmp    %eax,0x4(%rsp)
  jle    L55
L35:
  test   %edi,%edi
  je     L148
  mov    (%rdx),%esi
  mov    (%rbx,%rax,4),%ecx
  cmp    %ecx,%esi
  jle    L122
  mov    %esi,(%rbx,%rax,4)
  mov    %ecx,(%rdx)
  jmp    L122
L55:
  add    $0x1,%r9
  add    $0x4,%rdx
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r8d,%eax
  jle    L58
L62:
  add    $0x1,%r8d
  cmp    0x4(%rsp),%r8d
  jge    L55
  movslq %r8d,%rax
  mov    %r9d,%edi
  and    $0x1,%edi
  jmp    L35
L58:
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L139
  mov    $0x0,%ebp
  lea    D20(%rip),%r12
L138:
  mov    (%rbx,%rbp,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbp
  cmp    %ebp,0x4(%rsp)
  jg     L138
L139:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D20
datatype: string

tool: D8: Array size : 

tool: D7: %d

tool: D4: Enter Elements : 

tool: D5: Array elements  : 

tool: D20: %d 

assistant: ```c
int main(void) {
  int *a, n, i, j;
  printf("Array size : ");
  scanf("%d", &n);
  a = malloc(sizeof(int) * n);
  printf("Enter Elements : ");
  for (i = 0; i < n; i++)
    scanf("%d", a + i);
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++) {
      if (i % 2) {
        if (a[i] > a[j])
          a[i] = a[i] + a[j] - (a[j] = a[i]);
      } else {
        if (a[i] < a[j])
          a[i] = a[i] + a[j] - (a[j] = a[i]);
      }
    }
  printf("Array elements  : ");
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n");
  free(a);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%rdi
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D35(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L134
  mov    %rbp,%r12
  xor    %ebx,%ebx
L114:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L114
  cmp    $0x1,%esi
  jle    L134
  mov    %rbp,%rdi
  mov    $0x1,%r10d
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L50:
  cmp    %r10d,%esi
  jle    L25
  mov    %r9d,%r8d
  mov    %r10,%rax
  and    $0x1,%r8d
  jmp    L40
  nopl   0x0(%rax)
L124:
  cmp    %edx,%ecx
  jle    L39
L67:
  mov    %ecx,0x0(%rbp,%rax,4)
  mov    %edx,(%rdi)
  mov    0x4(%rsp),%esi
L39:
  add    $0x1,%rax
  cmp    %eax,%esi
  jle    L25
L40:
  mov    (%rdi),%ecx
  mov    0x0(%rbp,%rax,4),%edx
  test   %r8d,%r8d
  jne    L124
  cmp    %edx,%ecx
  jl     L67
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L40
L25:
  add    $0x1,%r9d
  lea    -0x1(%rsi),%eax
  add    $0x1,%r10
  add    $0x4,%rdi
  cmp    %r9d,%eax
  jg     L50
L134:
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D3(%rip),%r12
  test   %eax,%eax
  jle    L82
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L7
L82:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string
name: retrieve_data
arguments: data_tag: D27
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D25: Array size : 

tool: D8: %d

tool: D35: Enter Elements : 

tool: D27: Array elements  : 

tool: D3: %d 

assistant: ```c
int main(void) {
  int *a, n, i, j;
  printf("Array size : ");
  scanf("%d", &n);
  a = malloc(sizeof(int) * n);
  printf("Enter Elements : ");
  for (i = 0; i < n; i++)
    scanf("%d", a + i);
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++) {
      if (i % 2) {
        if (a[i] > a[j])
          a[i] = a[i] + a[j] - (a[j] = a[i]);
      } else {
        if (a[i] < a[j])
          a[i] = a[i] + a[j] - (a[j] = a[i]);
      }
    }
  printf("Array elements  : ");
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n");
  free(a);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_linear_search_with_heap_elements>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x3c(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  movl   $0x1,-0x38(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x3c(%rbp),%ecx
  lea    -0x30(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <linear_search@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  je     L15
  mov    $0x36,%ecx
  lea    D27(%rip),%rax
  mov    %rax,%rdx
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__test_fail@plt>
L15:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D2
type: string

tool: D27: test_linear_search_with_heap_elements

tool: D23: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c

tool: D2: index == 0

assistant: ```c
void test_linear_search_with_heap_elements(void) {
  int length = 10;
  int array[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int element = 1;
  int index = linear_search(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c", __FUNCTION__, 54)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_linear_search_with_heap_elements>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  movl   $0xa,0x24(%rsp)
  mov    %rsp,%rdi
  mov    $0x1,%edx
  mov    $0xa,%esi
  call   <linear_search@plt>
  test   %eax,%eax
  jne    L16
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x38,%rsp
  ret
L16:
  mov    $0x36,%ecx
  lea    D9(%rip),%rdx
  lea    D29(%rip),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <__test_fail@plt>
  jmp    L21
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D29
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: D9: test_linear_search_with_heap_elements

tool: D29: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c

tool: D17: index == 0

assistant: ```c
void test_linear_search_with_heap_elements(void) {
  int length = 10;
  int array[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int element = 1;
  int index = linear_search(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c", __FUNCTION__, 54)));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_linear_search_with_heap_elements>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xa00000009,%rax
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  call   <linear_search@plt>
  test   %eax,%eax
  jne    L23
L25:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L23:
  mov    $0x36,%ecx
  lea    D7(%rip),%rdx
  lea    D13(%rip),%rsi
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <__test_fail@plt>
  jmp    L25
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D13
type: string
name: read_data
arguments: data_label: D26
type: string

tool: D7: test_linear_search_with_heap_elements

tool: D13: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c

tool: D26: index == 0

assistant: ```c
void test_linear_search_with_heap_elements(void) {
  int length = 10;
  int array[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int element = 1;
  int index = linear_search(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c", __FUNCTION__, 54)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_linear_search_with_heap_elements>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x1,%edx
  mov    $0xa,%esi
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D36(%rip),%rax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  movdqa D55(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  call   <linear_search@plt>
  test   %eax,%eax
  jne    L5
L25:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x36,%ecx
  lea    D46(%rip),%rdx
  lea    D39(%rip),%rsi
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  call   <__test_fail@plt>
  jmp    L25
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D36
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D55
type_guessed: byte[16]
name: disassemble_data
arguments: tag: D46
type_guessed: string
name: disassemble_data
arguments: tag: D39
type_guessed: string
name: disassemble_data
arguments: tag: D47
type_guessed: string

tool: {"D18": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D36": [0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D55": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D46: test_linear_search_with_heap_elements

tool: D39: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c

tool: D47: index == 0

assistant: ```c
void test_linear_search_with_heap_elements(void) {
  int length = 10;
  int array[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  int element = 1;
  int index = linear_search(array, length, element);
  ((void)((index == 0) ? ((void)0) : __test_fail("index == 0", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/michaelreneer/Algorithms/refs/heads/master/c/test/test_linear_search.c", __FUNCTION__, 54)));
}
```