ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_user_cache_folder>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D27(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L27
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x3(%rbx,%r15,1),%eax
  cmp    %eax,%r13d
  jae    L39
L26:
  movb   $0x0,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L39:
  mov    %ebx,%edx
  mov    %r14,%rsi
  add    %rbp,%rbx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x1,%rbx
  movb   $0x2f,-0x1(%rbx)
L35:
  mov    %r15d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    %r15,%rbx
  call   <memcpy@plt>
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  mov    $0x1ed,%esi
  call   <mkdir@plt>
  mov    $0x2f,%eax
  mov    %ax,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    D8(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L26
  lea    D12(%rip),%r8
  mov    %rax,0x8(%rsp)
  mov    %r8,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x3(%r14,%rbx,1),%eax
  add    %r15d,%eax
  cmp    %r13d,%eax
  ja     L26
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    %rbp,%rbx
  add    $0x1,%rbx
  call   <memcpy@plt>
  movb   $0x2f,-0x1(%rbx)
  test   %r14d,%r14d
  je     L35
  lea    D12(%rip),%r8
  mov    %rbx,%rdi
  mov    %r14d,%edx
  add    %r14,%rbx
  mov    %r8,%rsi
  call   <memcpy@plt>
  movb   $0x0,(%rbx)
  mov    $0x1ed,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D27: XDG_CACHE_HOME

tool: D8: HOME

tool: D12: .cache/

assistant: ```c
void get_user_cache_folder(char *out, unsigned int maxlen, const char *appname) {
  const char *out_orig = out;
  char *home = getenv("XDG_CACHE_HOME");
  unsigned int config_len = 0;
  if (!home) {
    home = getenv("HOME");
    if (!home) {
      out[0] = 0;
      return;
    }
    config_len = strlen(".cache/");
  }
  unsigned int home_len = strlen(home);
  unsigned int appname_len = strlen(appname);
  if (home_len + 1 + config_len + appname_len + 1 + 1 > maxlen) {
    out[0] = 0;
    return;
  }
  memcpy(out, home, home_len);
  out += home_len;
  *out = '/';
  out++;
  if (config_len) {
    memcpy(out, ".cache/", config_len);
    out += config_len;
    *out = '\0';
    mkdir(out_orig, 0755);
  }
  memcpy(out, appname, appname_len);
  out += appname_len;
  *out = '\0';
  mkdir(out_orig, 0755);
  *out = '/';
  out++;
  *out = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_user_cache_folder>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D33(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L49
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x3(%rbx,%r15,1),%eax
  cmp    %eax,%r13d
  jae    L31
L18:
  movb   $0x0,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L31:
  mov    %ebx,%edx
  mov    %r14,%rsi
  add    %rbp,%rbx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x1,%rbx
  movb   $0x2f,-0x1(%rbx)
L5:
  mov    %r15d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  add    %r15,%rbx
  call   <memcpy@plt>
  movb   $0x0,(%rbx)
  mov    %rbp,%rdi
  mov    $0x1ed,%esi
  call   <mkdir@plt>
  mov    $0x2f,%eax
  mov    %ax,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  lea    D29(%rip),%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L18
  lea    D30(%rip),%r8
  mov    %rax,0x8(%rsp)
  mov    %r8,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%rdi
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %eax,%r15d
  lea    0x3(%r14,%rbx,1),%eax
  add    %r15d,%eax
  cmp    %r13d,%eax
  ja     L18
  mov    0x8(%rsp),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  add    %rbp,%rbx
  add    $0x1,%rbx
  call   <memcpy@plt>
  movb   $0x2f,-0x1(%rbx)
  test   %r14d,%r14d
  je     L5
  lea    D30(%rip),%r8
  mov    %rbx,%rdi
  mov    %r14d,%edx
  add    %r14,%rbx
  mov    %r8,%rsi
  call   <memcpy@plt>
  movb   $0x0,(%rbx)
  mov    $0x1ed,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  jmp    L5
```

tool_calls: name: read_data
arguments: data_label: D33
type_guessed: string
name: read_data
arguments: data_label: D29
type_guessed: string
name: read_data
arguments: data_label: D30
type_guessed: string

tool: D33: XDG_CACHE_HOME

tool: D29: HOME

tool: D30: .cache/

assistant: ```c
void get_user_cache_folder(char *out, unsigned int maxlen, const char *appname) {
  const char *out_orig = out;
  char *home = getenv("XDG_CACHE_HOME");
  unsigned int config_len = 0;
  if (!home) {
    home = getenv("HOME");
    if (!home) {
      out[0] = 0;
      return;
    }
    config_len = strlen(".cache/");
  }
  unsigned int home_len = strlen(home);
  unsigned int appname_len = strlen(appname);
  if (home_len + 1 + config_len + appname_len + 1 + 1 > maxlen) {
    out[0] = 0;
    return;
  }
  memcpy(out, home, home_len);
  out += home_len;
  *out = '/';
  out++;
  if (config_len) {
    memcpy(out, ".cache/", config_len);
    out += config_len;
    *out = '\0';
    mkdir(out_orig, 0755);
  }
  memcpy(out, appname, appname_len);
  out += appname_len;
  *out = '\0';
  mkdir(out_orig, 0755);
  *out = '/';
  out++;
  *out = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<left_exclude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x10(%rbx,%rax,1),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L50:
  cmp    %rcx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L50
L9:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L30
  orq    $0x0,-0x8(%rsp,%rdx,1)
L30:
  mov    %rsp,%r15
  test   %rax,%rax
  je     L57
  mov    %r13,%rbx
  add    %rax,%r13
  mov    $0x0,%r12d
  jmp    L87
L81:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L21
L87:
  movsbl (%rbx),%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L81
  lea    0x1(%r12),%eax
  movslq %r12d,%r12
  movzbl (%rbx),%edx
  mov    %dl,(%r15,%r12,1)
  movslq %eax,%rdx
  movb   $0x0,(%r15,%rdx,1)
  mov    %eax,%r12d
  jmp    L81
L57:
  mov    $0x0,%r12d
L21:
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <bubble_sort@plt>
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %r12d,%r12
  movb   $0x0,(%rbx,%r12,1)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    %rbx,%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *left_exclude(const char srcA[], const char srcB[]) {
  size_t lenA = strlen(srcA);
  size_t lenB = strlen(srcB);
  size_t tempSize = lenA + lenB + 1;
  int i, j, index = 0;
  char temp[tempSize];
  for (i = 0; i < lenB; i++) {
    if (strchr(srcA, srcB[i]) == NULL) {
      temp[index++] = srcB[i];
      temp[index] = '\0';
    }
  }
  bubble_sort(temp, index);
  char *result = (char *)malloc(index + 1);
  strncpy(result, temp, index);
  result[index] = '\0';
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<left_exclude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x10(%r12,%rax,1),%rdx
  mov    %rax,%r15
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L51
L96:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L96
L51:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L50
L58:
  mov    %rsp,%r14
  test   %rax,%rax
  je     L100
  lea    (%rbx,%rax,1),%r15
  xor    %r12d,%r12d
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L80
L20:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L32
  movzbl (%rbx),%edx
  lea    0x1(%r12),%eax
  add    $0x1,%rbx
  mov    %dl,(%r14,%r12,1)
  movslq %eax,%rdx
  movslq %eax,%r12
  movb   $0x0,(%r14,%rdx,1)
  cmp    %r15,%rbx
  jne    L20
L80:
  lea    0x1(%r12),%r13d
  movslq %r12d,%r15
L92:
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <bubble_sort@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r15,1)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  lea    -0x28(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L50:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L58
L100:
  mov    $0x1,%r13d
  xor    %r12d,%r12d
  jmp    L92
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *left_exclude(const char srcA[], const char srcB[]) {
  size_t lenA = strlen(srcA);
  size_t lenB = strlen(srcB);
  size_t tempSize = lenA + lenB + 1;
  int i, j, index = 0;
  char temp[tempSize];
  for (i = 0; i < lenB; i++) {
    if (strchr(srcA, srcB[i]) == NULL) {
      temp[index++] = srcB[i];
      temp[index] = '\0';
    }
  }
  bubble_sort(temp, index);
  char *result = (char *)malloc(index + 1);
  strncpy(result, temp, index);
  result[index] = '\0';
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<left_exclude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rsp,%rsi
  lea    0x10(%r12,%rax,1),%rdx
  mov    %rax,%r15
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L44
L80:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L80
L44:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L9
L4:
  mov    %rsp,%r14
  test   %rax,%rax
  je     L77
  lea    (%rbx,%rax,1),%r15
  xor    %r12d,%r12d
  jmp    L109
  nopw   0x0(%rax,%rax,1)
L92:
  add    $0x1,%rbx
  cmp    %rbx,%r15
  je     L16
L109:
  movsbl (%rbx),%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L92
  movzbl (%rbx),%edx
  lea    0x1(%r12),%eax
  add    $0x1,%rbx
  mov    %dl,(%r14,%r12,1)
  movslq %eax,%rdx
  movslq %eax,%r12
  movb   $0x0,(%r14,%rdx,1)
  cmp    %rbx,%r15
  jne    L109
L16:
  lea    0x1(%r12),%r13d
  movslq %r12d,%r15
L26:
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <bubble_sort@plt>
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r15,1)
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x28(%rbp),%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L4
L77:
  mov    $0x1,%r13d
  xor    %r12d,%r12d
  jmp    L26
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *left_exclude(const char srcA[], const char srcB[]) {
  size_t lenA = strlen(srcA);
  size_t lenB = strlen(srcB);
  size_t tempSize = lenA + lenB + 1;
  int i, j, index = 0;
  char temp[tempSize];
  for (i = 0; i < lenB; i++) {
    if (strchr(srcA, srcB[i]) == NULL) {
      temp[index++] = srcB[i];
      temp[index] = '\0';
    }
  }
  bubble_sort(temp, index);
  char *result = (char *)malloc(index + 1);
  strncpy(result, temp, index);
  result[index] = '\0';
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<replace_spec_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%r8d
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <replace_char@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    $0x4,%r8d
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    $0x9,%edi
  call   <replace_char@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string

tool: D18: #012

tool: D15: #011

assistant: ```c
int replace_spec_chars(char *string, int str_len) {
  replace_char('\n', "#012", string, str_len, 4);
  replace_char('\t', "#011", string, str_len, 4);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<replace_spec_chars>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x4,%r8d
  mov    %esi,%ecx
  mov    %rdi,%rdx
  lea    D0(%rip),%rsi
  mov    $0xa,%edi
  call   <replace_char@plt>
  mov    $0x4,%r8d
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  lea    D18(%rip),%rsi
  mov    $0x9,%edi
  call   <replace_char@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_guessed: string
name: read_data
arguments: data_label: D18
type_guessed: string

tool: D0: #012

tool: D18: #011

assistant: ```c
int replace_spec_chars(char *string, int str_len) {
  replace_char('\n', "#012", string, str_len, 4);
  replace_char('\t', "#011", string, str_len, 4);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<replace_spec_chars>:
  endbr64
  push   %r13
  mov    %esi,%ecx
  mov    %esi,%r13d
  mov    %rdi,%rdx
  push   %r12
  mov    $0x4,%r8d
  mov    %rdi,%r12
  lea    D15(%rip),%rsi
  mov    $0xa,%edi
  sub    $0x8,%rsp
  call   <replace_char@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    $0x9,%edi
  mov    $0x4,%r8d
  lea    D10(%rip),%rsi
  call   <replace_char@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D15
datatype: string
name: read_data
arguments: label: D10
datatype: string

tool: D15: #012

tool: D10: #011

assistant: ```c
int replace_spec_chars(char *string, int str_len) {
  replace_char('\n', "#012", string, str_len, 4);
  replace_char('\t', "#011", string, str_len, 4);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<replace_spec_chars>:
  endbr64
  push   %r13
  mov    %esi,%ecx
  mov    %esi,%r13d
  mov    %rdi,%rdx
  push   %r12
  mov    $0x4,%r8d
  mov    %rdi,%r12
  lea    D13(%rip),%rsi
  mov    $0xa,%edi
  sub    $0x8,%rsp
  call   <replace_char@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    $0x9,%edi
  mov    $0x4,%r8d
  lea    D17(%rip),%rsi
  call   <replace_char@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D17
type: string

tool: D13: #012

tool: D17: #011

assistant: ```c
int replace_spec_chars(char *string, int str_len) {
  replace_char('\n', "#012", string, str_len, 4);
  replace_char('\t', "#011", string, str_len, 4);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<math__Float__asin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <asin@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  nop
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double math__Float__asin(double self) {
  double var;
  double var1;
  var1 = asin(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<math__Float__asin>:
  endbr64
  sub    $0x8,%rsp
  call   <asin@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double math__Float__asin(double self) {
  double var;
  double var1;
  var1 = asin(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<math__Float__asin>:
  endbr64
  jmp    1050 <asin@plt>
```

assistant: ```c
double math__Float__asin(double self) {
  double var;
  double var1;
  var1 = asin(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<math__Float__asin>:
  endbr64
  jmp    1050 <asin@plt>
```

assistant: ```c
double math__Float__asin(double self) {
  double var;
  double var1;
  var1 = asin(self);
  var = var1;
  goto RET_LABEL;
RET_LABEL:;
  return var;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kadane>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L73
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  jmp    L11
L73:
  movq   $0x1,-0x8(%rbp)
  jmp    L40
L9:
  mov    -0x8(%rbp),%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L38
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L38:
  addq   $0x1,-0x8(%rbp)
L40:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L62
L51:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L57
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L57:
  addq   $0x1,-0x8(%rbp)
L62:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L51
  mov    -0xc(%rbp),%eax
L11:
  pop    %rbp
  ret
```

assistant: ```c
int kadane(int *a, size_t n) {
  size_t i;
  int r;
  if (n == 0)
    return INT_MIN;
  for (i = 1; i < n; i++) {
    if (a[i - 1] > 0)
      a[i] += a[i - 1];
  }
  r = a[0];
  for (i = 1; i < n; i++) {
    if (r < a[i])
      r = a[i];
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<kadane>:
  endbr64
  test   %rsi,%rsi
  je     L53
  cmp    $0x1,%rsi
  jbe    L36
  lea    0x4(%rdi),%rdx
  lea    (%rdi,%rsi,4),%rsi
  mov    %rdx,%rax
  jmp    L0
L53:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
L8:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L17
L0:
  mov    -0x4(%rax),%ecx
  test   %ecx,%ecx
  jle    L8
  add    %ecx,(%rax)
  jmp    L8
L17:
  mov    (%rdi),%eax
L10:
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L10
  ret
L36:
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int kadane(int *a, size_t n) {
  size_t i;
  int r;
  if (n == 0)
    return INT_MIN;
  for (i = 1; i < n; i++) {
    if (a[i - 1] > 0)
      a[i] += a[i - 1];
  }
  r = a[0];
  for (i = 1; i < n; i++) {
    if (r < a[i])
      r = a[i];
  }
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<kadane>:
  endbr64
  test   %rsi,%rsi
  je     L5
  mov    (%rdi),%eax
  cmp    $0x1,%rsi
  je     L46
  lea    0x4(%rdi),%rdx
  lea    (%rdi,%rsi,4),%rsi
  mov    %rdx,%rax
  nopl   0x0(%rax)
L33:
  mov    -0x4(%rax),%ecx
  test   %ecx,%ecx
  jle    L18
  add    %ecx,(%rax)
L18:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L33
  mov    (%rdi),%eax
  nopl   0x0(%rax)
L48:
  mov    (%rdx),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L48
  ret
  nopl   0x0(%rax)
L5:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  ret
```

assistant: ```c
int kadane(int *a, size_t n) {
  size_t i;
  int r;
  if (n == 0)
    return INT_MIN;
  for (i = 1; i < n; i++) {
    if (a[i - 1] > 0)
      a[i] += a[i - 1];
  }
  r = a[0];
  for (i = 1; i < n; i++) {
    if (r < a[i])
      r = a[i];
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kadane>:
  endbr64
  test   %rsi,%rsi
  je     L88
  mov    (%rdi),%eax
  cmp    $0x1,%rsi
  je     L39
  lea    0x4(%rdi),%rax
  mov    %rdi,%rcx
  lea    (%rdi,%rsi,4),%r8
  nopl   0x0(%rax)
L42:
  mov    -0x4(%rax),%edx
  test   %edx,%edx
  jle    L32
  add    %edx,(%rax)
L32:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L42
  lea    -0x2(%rsi),%rdx
  mov    (%rdi),%eax
  lea    -0x1(%rsi),%r8
  cmp    $0x2,%rdx
  jbe    L96
  movd   %eax,%xmm3
  mov    %r8,%rax
  shr    $0x2,%rax
  pshufd $0x0,%xmm3,%xmm0
  shl    $0x4,%rax
  add    %rdi,%rax
  nopl   (%rax)
L13:
  movdqu 0x4(%rcx),%xmm1
  add    $0x10,%rcx
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm0,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  por    %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L13
  movdqa %xmm0,%xmm2
  mov    %r8,%rcx
  psrldq $0x8,%xmm2
  and    $0xfffffffffffffffc,%rcx
  movdqa %xmm2,%xmm1
  lea    0x1(%rcx),%rdx
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%eax
  cmp    %r8,%rcx
  je     L87
L0:
  mov    (%rdi,%rdx,4),%ecx
  lea    0x0(,%rdx,4),%r8
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  lea    0x1(%rdx),%rcx
  cmp    %rcx,%rsi
  jbe    L3
  mov    0x4(%rdi,%r8,1),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  add    $0x2,%rdx
  cmp    %rdx,%rsi
  jbe    L3
  mov    0x8(%rdi,%r8,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
  nopl   0x0(%rax)
L88:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  ret
  nopl   0x0(%rax)
L39:
  ret
L96:
  mov    $0x1,%edx
  jmp    L0
```

assistant: ```c
int kadane(int *a, size_t n) {
  size_t i;
  int r;
  if (n == 0)
    return INT_MIN;
  for (i = 1; i < n; i++) {
    if (a[i - 1] > 0)
      a[i] += a[i - 1];
  }
  r = a[0];
  for (i = 1; i < n; i++) {
    if (r < a[i])
      r = a[i];
  }
  return r;
}
```