ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<block_put>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L16:
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L9:
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    0x10(%rbp),%edx
  lea    (%rcx,%rdx,1),%esi
  mov    -0x4(%rbp),%ecx
  mov    0x18(%rbp),%edx
  add    %ecx,%edx
  imul   -0x2c(%rbp),%edx
  add    %esi,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void block_put(int *b, int wb, int hb, int *g, int wg, int hg, int i0, int j0) {
  int i, j;
  for (j = 0; j < hb; j++)
    for (i = 0; i < wb; i++)
      g[(i + i0) + ((j + j0) * wg)] = b[i + (j * wb)];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<block_put>:
  endbr64
  test   %edx,%edx
  jle    L59
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    %rcx,%r13
  mov    %r8d,%r11d
  imul   0x38(%rsp),%r11d
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  mov    %esi,%edi
  movslq 0x30(%rsp),%r14
  jmp    L5
L29:
  movslq %r10d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %r11d,%rax
  add    %r14,%rax
  lea    0x0(%r13,%rax,4),%rcx
  mov    $0x0,%eax
L24:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L24
L36:
  add    $0x1,%r9d
  add    %ebx,%r10d
  add    %r8d,%r11d
  cmp    %r9d,%r12d
  je     L25
L5:
  test   %ebx,%ebx
  jg     L29
  jmp    L36
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L59:
  ret
```

assistant: ```c
void block_put(int *b, int wb, int hb, int *g, int wg, int hg, int i0, int j0) {
  int i, j;
  for (j = 0; j < hb; j++)
    for (i = 0; i < wb; i++)
      g[(i + i0) + ((j + j0) * wg)] = b[i + (j * wb)];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<block_put>:
  endbr64
  test   %edx,%edx
  jle    L11
  push   %r14
  xor    %r10d,%r10d
  xor    %r9d,%r9d
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%edi
  push   %rbx
  mov    0x38(%rsp),%r11d
  mov    %esi,%ebx
  movslq 0x30(%rsp),%r14
  imul   %r8d,%r11d
  nopw   0x0(%rax,%rax,1)
L2:
  test   %ebx,%ebx
  jle    L18
  movslq %r10d,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  movslq %r11d,%rax
  add    %r14,%rax
  lea    0x0(%r13,%rax,4),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L14:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L14
L18:
  add    $0x1,%r9d
  add    %ebx,%r10d
  add    %r8d,%r11d
  cmp    %r9d,%r12d
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  ret
```

assistant: ```c
void block_put(int *b, int wb, int hb, int *g, int wg, int hg, int i0, int j0) {
  int i, j;
  for (j = 0; j < hb; j++)
    for (i = 0; i < wb; i++)
      g[(i + i0) + ((j + j0) * wg)] = b[i + (j * wb)];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<block_put>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r8d
  mov    %edx,-0x20(%rsp)
  test   %edx,%edx
  jle    L90
  mov    %rdi,%rbx
  mov    %esi,%edi
  test   %esi,%esi
  jle    L90
  mov    0x40(%rsp),%esi
  movslq %r13d,%rax
  mov    %edi,%r12d
  mov    %rcx,%rbp
  and    $0xfffffffc,%r12d
  shl    $0x2,%rax
  xor    %r9d,%r9d
  imul   %r13d,%esi
  lea    (%r8,%r12,1),%r14d
  mov    %rax,-0x30(%rsp)
  movslq %r8d,%rax
  mov    %r14d,-0x18(%rsp)
  lea    0x1(%r12),%r14d
  lea    (%r14,%r8,1),%r10d
  movslq %esi,%rdx
  mov    %r10d,-0x14(%rsp)
  lea    0x2(%r12),%r10d
  add    %rdx,%rax
  add    %r10d,%r8d
  mov    %r10d,-0x10(%rsp)
  xor    %r10d,%r10d
  lea    (%rcx,%rax,4),%rdx
  mov    %edi,%ecx
  movslq %edi,%rax
  mov    %r8d,-0xc(%rsp)
  shr    $0x2,%ecx
  shl    $0x2,%rax
  lea    -0x1(%rdi),%r8d
  sub    $0x1,%ecx
  mov    %rax,-0x28(%rsp)
  mov    %rbx,%rax
  add    $0x1,%rcx
  mov    %r8d,-0x1c(%rsp)
  mov    %edi,%r8d
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L18:
  lea    0x4(%rax),%r15
  mov    %rdx,%r11
  sub    %r15,%r11
  cmp    $0x8,%r11
  jbe    L38
  xor    %r11d,%r11d
  cmpl   $0x2,-0x1c(%rsp)
  jbe    L38
  nopw   0x0(%rax,%rax,1)
L32:
  movdqu (%rax,%r11,1),%xmm0
  movups %xmm0,(%rdx,%r11,1)
  add    $0x10,%r11
  cmp    %rcx,%r11
  jne    L32
  cmp    %edi,%r12d
  je     L14
  lea    (%r9,%r12,1),%r11d
  movslq %r11d,%r11
  mov    (%rbx,%r11,4),%r15d
  mov    -0x18(%rsp),%r11d
  add    %esi,%r11d
  movslq %r11d,%r11
  mov    %r15d,0x0(%rbp,%r11,4)
  cmp    %r14d,%edi
  jle    L14
  lea    (%r9,%r14,1),%r11d
  movslq %r11d,%r11
  mov    (%rbx,%r11,4),%r15d
  mov    -0x14(%rsp),%r11d
  add    %esi,%r11d
  movslq %r11d,%r11
  mov    %r15d,0x0(%rbp,%r11,4)
  mov    -0x10(%rsp),%r15d
  cmp    %r15d,%edi
  jle    L14
  lea    (%r9,%r15,1),%r11d
  movslq %r11d,%r11
  mov    (%rbx,%r11,4),%r15d
  mov    -0xc(%rsp),%r11d
  add    %esi,%r11d
  movslq %r11d,%r11
  mov    %r15d,0x0(%rbp,%r11,4)
L14:
  add    $0x1,%r10d
  add    -0x30(%rsp),%rdx
  add    %edi,%r9d
  add    %r13d,%esi
  add    -0x28(%rsp),%rax
  cmp    %r10d,-0x20(%rsp)
  jne    L18
L90:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  xor    %r11d,%r11d
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%rax,%r11,4),%r15d
  mov    %r15d,(%rdx,%r11,4)
  add    $0x1,%r11
  cmp    %r8,%r11
  jne    L27
  jmp    L14
```

assistant: ```c
void block_put(int *b, int wb, int hb, int *g, int wg, int hg, int i0, int j0) {
  int i, j;
  for (j = 0; j < hb; j++)
    for (i = 0; i < wb; i++)
      g[(i + i0) + ((j + j0) * wg)] = b[i + (j * wb)];
}
```
user: Translate the below assembly code into C programming language:

```asm
<caddvrfield2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9d,-0x24(%rbp)
  lea    -0x24(%rbp),%r8
  lea    -0x20(%rbp),%rdi
  lea    -0x1c(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <addvrfield2_@plt>
  nop
  leave
  ret
```

assistant: ```c
void caddvrfield2(float a[], float b[], float c[], int ndim, int nxe, int nye) {
  addvrfield2_(a, b, c, &ndim, &nxe, &nye);
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<caddvrfield2>:
  endbr64
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %r8d,0x8(%rsp)
  mov    %r9d,0x4(%rsp)
  lea    0xc(%rsp),%rcx
  lea    0x4(%rsp),%r9
  lea    0x8(%rsp),%r8
  call   <addvrfield2_@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void caddvrfield2(float a[], float b[], float c[], int ndim, int nxe, int nye) {
  addvrfield2_(a, b, c, &ndim, &nxe, &nye);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<caddvrfield2>:
  endbr64
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  mov    %r8d,0x8(%rsp)
  lea    0x8(%rsp),%r8
  mov    %r9d,0x4(%rsp)
  lea    0x4(%rsp),%r9
  call   <addvrfield2_@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void caddvrfield2(float a[], float b[], float c[], int ndim, int nxe, int nye) {
  addvrfield2_(a, b, c, &ndim, &nxe, &nye);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<caddvrfield2>:
  endbr64
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  mov    %r8d,0x8(%rsp)
  lea    0x8(%rsp),%r8
  mov    %r9d,0x4(%rsp)
  lea    0x4(%rsp),%r9
  call   <addvrfield2_@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void caddvrfield2(float a[], float b[], float c[], int ndim, int nxe, int nye) {
  addvrfield2_(a, b, c, &ndim, &nxe, &nye);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_recursive_factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    $0x0,%eax
  jmp    L22
L2:
  cmpl   $0x1,-0x4(%rbp)
  je     L47
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
L47:
  mov    $0x1,%eax
  jmp    L22
L25:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <ft_recursive_factorial>
  imul   -0x4(%rbp),%eax
L22:
  leave
  ret
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb < 0)
    return (0);
  if (nb == 1 || nb == 0)
    return (1);
  return (nb * ft_recursive_factorial(nb - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_recursive_factorial>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L14
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jbe    L18
  lea    -0x1(%rdi),%edi
  call   <ft_recursive_factorial>
  imul   %ebx,%eax
L18:
  pop    %rbx
  ret
L14:
  ret
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb < 0)
    return (0);
  if (nb == 1 || nb == 0)
    return (1);
  return (nb * ft_recursive_factorial(nb - 1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_recursive_factorial>:
  endbr64
  test   %edi,%edi
  js     L16
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L17
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L4
  ret
L16:
  xor    %eax,%eax
  ret
L17:
  ret
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb < 0)
    return (0);
  if (nb == 1 || nb == 0)
    return (1);
  return (nb * ft_recursive_factorial(nb - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_recursive_factorial>:
  endbr64
  test   %edi,%edi
  js     L16
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L22
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L29
  ret
L16:
  xor    %eax,%eax
  ret
L22:
  ret
```

assistant: ```c
int ft_recursive_factorial(int nb) {
  if (nb < 0)
    return (0);
  if (nb == 1 || nb == 0)
    return (1);
  return (nb * ft_recursive_factorial(nb - 1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  movl   $0x55555555,-0x28(%rbp)
  movl   $0x33333333,-0x24(%rbp)
  movl   $0xf0f0f0f,-0x20(%rbp)
  movl   $0xff00ff,-0x1c(%rbp)
  movl   $0xffff,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  and    -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  sar    %eax
  and    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sar    $0x2,%eax
  and    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  sar    $0x4,%eax
  and    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  and    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  and    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int helper(int a) {
  int m_1 = 0x55555555;
  int m_2 = 0x33333333;
  int m_4 = 0x0f0f0f0f;
  int m_8 = 0x00ff00ff;
  int m_16 = 0x0000ffff;
  int b = (a & m_1) + ((a >> 1) & m_1);
  int c = (b & m_2) + ((b >> 2) & m_2);
  int d = (c & m_4) + ((c >> 4) & m_4);
  int e = (d & m_8) + ((d >> 8) & m_8);
  int f = (e & m_16) + ((e >> 16) & m_16);
  return f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<helper>:
  endbr64
  mov    %edi,%eax
  sar    %eax
  and    $0x55555555,%eax
  and    $0x55555555,%edi
  add    %eax,%edi
  mov    %edi,%edx
  sar    $0x2,%edx
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  sar    $0x4,%eax
  and    $0xf0f0f0f,%eax
  and    $0xf0f0f0f,%edx
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x8,%edx
  and    $0xff00ff,%edx
  and    $0xff00ff,%eax
  add    %eax,%edx
  movzwl %dx,%eax
  shr    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int helper(int a) {
  int m_1 = 0x55555555;
  int m_2 = 0x33333333;
  int m_4 = 0x0f0f0f0f;
  int m_8 = 0x00ff00ff;
  int m_16 = 0x0000ffff;
  int b = (a & m_1) + ((a >> 1) & m_1);
  int c = (b & m_2) + ((b >> 2) & m_2);
  int d = (c & m_4) + ((c >> 4) & m_4);
  int e = (d & m_8) + ((d >> 8) & m_8);
  int f = (e & m_16) + ((e >> 16) & m_16);
  return f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<helper>:
  endbr64
  mov    %edi,%eax
  and    $0x55555555,%edi
  sar    %eax
  and    $0x55555555,%eax
  add    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edi
  sar    $0x2,%edx
  and    $0x33333333,%edx
  add    %edi,%edx
  mov    %edx,%eax
  and    $0xf0f0f0f,%edx
  sar    $0x4,%eax
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xff00ff,%eax
  sar    $0x8,%edx
  and    $0xff00ff,%edx
  add    %eax,%edx
  movzwl %dx,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int helper(int a) {
  int m_1 = 0x55555555;
  int m_2 = 0x33333333;
  int m_4 = 0x0f0f0f0f;
  int m_8 = 0x00ff00ff;
  int m_16 = 0x0000ffff;
  int b = (a & m_1) + ((a >> 1) & m_1);
  int c = (b & m_2) + ((b >> 2) & m_2);
  int d = (c & m_4) + ((c >> 4) & m_4);
  int e = (d & m_8) + ((d >> 8) & m_8);
  int f = (e & m_16) + ((e >> 16) & m_16);
  return f;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<helper>:
  endbr64
  mov    %edi,%eax
  and    $0x55555555,%edi
  sar    %eax
  and    $0x55555555,%eax
  add    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edi
  sar    $0x2,%edx
  and    $0x33333333,%edx
  add    %edi,%edx
  mov    %edx,%eax
  and    $0xf0f0f0f,%edx
  sar    $0x4,%eax
  and    $0xf0f0f0f,%eax
  add    %edx,%eax
  mov    %eax,%edx
  and    $0xff00ff,%eax
  sar    $0x8,%edx
  and    $0xff00ff,%edx
  add    %eax,%edx
  movzwl %dx,%eax
  sar    $0x10,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int helper(int a) {
  int m_1 = 0x55555555;
  int m_2 = 0x33333333;
  int m_4 = 0x0f0f0f0f;
  int m_8 = 0x00ff00ff;
  int m_16 = 0x0000ffff;
  int b = (a & m_1) + ((a >> 1) & m_1);
  int c = (b & m_2) + ((b >> 2) & m_2);
  int d = (c & m_4) + ((c >> 4) & m_4);
  int e = (d & m_8) + ((d >> 8) & m_8);
  int f = (e & m_16) + ((e >> 16) & m_16);
  return f;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <func@plt>
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  __func__;
  return func();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <func@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  __func__;
  return func();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <func@plt>
```

assistant: ```c
int main(void) {
  __func__;
  return func();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x32,%edi
  call   <random_gen@plt>
  mov    %rax,-0x8(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <insertion_int@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <print_array@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free_array@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_infered: string
name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D24
type_infered: string

tool: D23: 
# ----- Original Data ----- #



tool: D28: 
# ----- Sorted Data ----- #



tool: D24: 


assistant: ```c
int main(int argc, char *argv[]) {
  int *array = random_gen(50);
  printf("\n# ----- Original Data ----- #\n\n");
  print_array(array, 50);
  insertion_int(array, 50);
  printf("\n# ----- Sorted Data ----- #\n\n");
  print_array(array, 50);
  printf("\n");
  free_array(array);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x32,%edi
  call   <random_gen@plt>
  mov    %rax,%rbx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <insertion_int@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <print_array@plt>
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <free_array@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D28
type_infered: string

tool: D10: 
# ----- Original Data ----- #



tool: D18: 
# ----- Sorted Data ----- #



tool: D28: 


assistant: ```c
int main(int argc, char *argv[]) {
  int *array = random_gen(50);
  printf("\n# ----- Original Data ----- #\n\n");
  print_array(array, 50);
  insertion_int(array, 50);
  printf("\n# ----- Sorted Data ----- #\n\n");
  print_array(array, 50);
  printf("\n");
  free_array(array);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%edi
  call   <random_gen@plt>
  lea    D14(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x32,%esi
  call   <print_array@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <insertion_int@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free_array@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D2
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string

tool: D14: 
# ----- Original Data ----- #



tool: D2: 
# ----- Sorted Data ----- #



tool: D29: 


assistant: ```c
int main(int argc, char *argv[]) {
  int *array = random_gen(50);
  printf("\n# ----- Original Data ----- #\n\n");
  print_array(array, 50);
  insertion_int(array, 50);
  printf("\n# ----- Sorted Data ----- #\n\n");
  print_array(array, 50);
  printf("\n");
  free_array(array);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x32,%edi
  call   <random_gen@plt>
  lea    D12(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x32,%esi
  call   <print_array@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <insertion_int@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x32,%esi
  mov    %rbp,%rdi
  call   <print_array@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <free_array@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: string

tool: D12: 
# ----- Original Data ----- #



tool: D23: 
# ----- Sorted Data ----- #



tool: D13: 


assistant: ```c
int main(int argc, char *argv[]) {
  int *array = random_gen(50);
  printf("\n# ----- Original Data ----- #\n\n");
  print_array(array, 50);
  insertion_int(array, 50);
  printf("\n# ----- Sorted Data ----- #\n\n");
  print_array(array, 50);
  printf("\n");
  free_array(array);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_bright>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L9
  movl   $0x80,-0x4(%rbp)
L9:
  mov    $0x2100,%eax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void set_bright(unsigned int i) {
  if (!i)
    i = 0x80;
  *((unsigned char *)0x2100) = (i);
  ;
}
```
user: What is the c source code of the assembly code below:

```asm
<set_bright>:
  endbr64
  test   %edi,%edi
  mov    $0x80,%eax
  cmove  %eax,%edi
  mov    %dil,0x2100
  ret
```

assistant: ```c
void set_bright(unsigned int i) {
  if (!i)
    i = 0x80;
  *((unsigned char *)0x2100) = (i);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_bright>:
  endbr64
  test   %edi,%edi
  mov    $0x80,%eax
  cmove  %eax,%edi
  mov    %dil,0x2100
  ret
```

assistant: ```c
void set_bright(unsigned int i) {
  if (!i)
    i = 0x80;
  *((unsigned char *)0x2100) = (i);
  ;
}
```
user: What is the c source code of the assembly code below?

```asm
<set_bright>:
  endbr64
  test   %edi,%edi
  mov    $0x80,%eax
  cmove  %eax,%edi
  mov    %dil,0x2100
  ret
```

assistant: ```c
void set_bright(unsigned int i) {
  if (!i)
    i = 0x80;
  *((unsigned char *)0x2100) = (i);
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<eisinf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  and    $0x7fff,%eax
  cmp    $0x7fff,%eax
  jne    L21
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <eisnan@plt>
  test   %eax,%eax
  je     L31
  mov    $0x0,%eax
  jmp    L27
L31:
  mov    $0x1,%eax
  jmp    L27
L21:
  mov    $0x0,%eax
L27:
  leave
  ret
```

assistant: ```c
int eisinf(x)
unsigned short x[];
{
  if ((x[6 - 1] & 0x7fff) == 0x7fff) {
    if (eisnan(x))
      return (0);
    return (1);
  } else
    return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<eisinf>:
  endbr64
  movzwl 0xa(%rdi),%eax
  and    $0x7fff,%ax
  mov    $0x0,%edx
  cmp    $0x7fff,%ax
  je     L6
  mov    %edx,%eax
  ret
L6:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <eisnan@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int eisinf(x)
unsigned short x[];
{
  if ((x[6 - 1] & 0x7fff) == 0x7fff) {
    if (eisnan(x))
      return (0);
    return (1);
  } else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eisinf>:
  endbr64
  movzwl 0xa(%rdi),%eax
  and    $0x7fff,%ax
  cmp    $0x7fff,%ax
  je     L6
  xor    %eax,%eax
  ret
  nopl   (%rax)
L6:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <eisnan@plt>
  xor    %r8d,%r8d
  test   %eax,%eax
  sete   %r8b
  add    $0x8,%rsp
  mov    %r8d,%eax
  ret
```

assistant: ```c
int eisinf(x)
unsigned short x[];
{
  if ((x[6 - 1] & 0x7fff) == 0x7fff) {
    if (eisnan(x))
      return (0);
    return (1);
  } else
    return (0);
}
```