ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mat2_identity>:
  endbr64
  movss  D4(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat2_identity(float *dst) {
  dst[0] = 1;
  dst[3] = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mat2_identity>:
  endbr64
  movss  D9(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type: byte[4]

tool: {"D9": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat2_identity(float *dst) {
  dst[0] = 1;
  dst[3] = 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<mat2_identity>:
  endbr64
  movss  D3(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movss  %xmm0,0xc(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void mat2_identity(float *dst) {
  dst[0] = 1;
  dst[3] = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_window_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <isatty@plt>
  test   %eax,%eax
  jne    L14
  mov    $0x0,%eax
  jmp    L1
L14:
  mov    D10(%rip),%rax
  mov    (%rax),%ecx
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x4f,%eax
  jle    L49
  mov    $0x0,%eax
  jmp    L1
L49:
  mov    $0xffffffff,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int check_window_size(void) {
  struct winsize winsize;
  if (!isatty(STDOUT_FILENO))
    return 0;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &winsize);
  if (winsize.ws_col >= 80)
    return 0;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_window_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <isatty@plt>
  test   %eax,%eax
  jne    L14
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L14:
  lea    0x4(%rsp),%rdx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <ioctl@plt>
  cmpl   $0x4f,0x4(%rsp)
  setle  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L12
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_window_size(void) {
  struct winsize winsize;
  if (!isatty(STDOUT_FILENO))
    return 0;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &winsize);
  if (winsize.ws_col >= 80)
    return 0;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_window_size>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    D3(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rbx),%edi
  call   <isatty@plt>
  test   %eax,%eax
  je     L10
  mov    D13(%rip),%rax
  mov    (%rbx),%edi
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  xor    %eax,%eax
  cmpl   $0x4f,0x4(%rsp)
  setle  %al
  neg    %eax
L10:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_window_size(void) {
  struct winsize winsize;
  if (!isatty(STDOUT_FILENO))
    return 0;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &winsize);
  if (winsize.ws_col >= 80)
    return 0;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_window_size>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    D13(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rbx),%edi
  call   <isatty@plt>
  test   %eax,%eax
  je     L17
  mov    D3(%rip),%rax
  mov    (%rbx),%edi
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  xor    %eax,%eax
  cmpl   $0x4f,0x4(%rsp)
  setle  %al
  neg    %eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_window_size(void) {
  struct winsize winsize;
  if (!isatty(STDOUT_FILENO))
    return 0;
  ioctl(STDOUT_FILENO, TIOCGWINSZ, &winsize);
  if (winsize.ws_col >= 80)
    return 0;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  bar();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bar();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bar();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  bar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mgrShutdown>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: /sbin/shutdown now -h

assistant: ```c
int mgrShutdown(int code, void *arg1, void *arg2) {
  static const char *cmd = "/sbin/shutdown now -h";
  ;
  system(cmd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mgrShutdown>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
type: string

tool: D8: /sbin/shutdown now -h

assistant: ```c
int mgrShutdown(int code, void *arg1, void *arg2) {
  static const char *cmd = "/sbin/shutdown now -h";
  ;
  system(cmd);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mgrShutdown>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D6: /sbin/shutdown now -h

assistant: ```c
int mgrShutdown(int code, void *arg1, void *arg2) {
  static const char *cmd = "/sbin/shutdown now -h";
  ;
  system(cmd);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memccpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  jmp    L26
L5:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  movzbl -0x1(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L26
  mov    -0x20(%rbp),%rax
  jmp    L28
L26:
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  test   %rax,%rax
  jne    L5
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t len) {
  unsigned char c2;
  while (len--) {
    *(((unsigned char *)dst++)) = (c2 = *(((unsigned char *)src++)));
    if (c2 == c)
      return (void *)src;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memccpy>:
  endbr64
  add    %rdi,%rcx
L13:
  cmp    %rcx,%rdi
  je     L2
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%r8d
  add    $0x1,%rdi
  mov    %r8b,-0x1(%rdi)
  movzbl %r8b,%r8d
  cmp    %edx,%r8d
  jne    L13
  mov    %rsi,%rax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t len) {
  unsigned char c2;
  while (len--) {
    *(((unsigned char *)dst++)) = (c2 = *(((unsigned char *)src++)));
    if (c2 == c)
      return (void *)src;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memccpy>:
  endbr64
  add    %rdi,%rcx
  jmp    L11
  nopl   0x0(%rax)
L13:
  movzbl (%rsi),%r8d
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %r8b,-0x1(%rdi)
  cmp    %edx,%r8d
  je     L23
L11:
  cmp    %rcx,%rdi
  jne    L13
  xor    %eax,%eax
  ret
  nopl   (%rax)
L23:
  mov    %rsi,%rax
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t len) {
  unsigned char c2;
  while (len--) {
    *(((unsigned char *)dst++)) = (c2 = *(((unsigned char *)src++)));
    if (c2 == c)
      return (void *)src;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memccpy>:
  endbr64
  add    %rdi,%rcx
  jmp    L7
  nopl   0x0(%rax)
L16:
  movzbl (%rsi),%r8d
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %r8b,-0x1(%rdi)
  cmp    %edx,%r8d
  je     L19
L7:
  cmp    %rdi,%rcx
  jne    L16
  xor    %eax,%eax
  ret
  nopl   (%rax)
L19:
  mov    %rsi,%rax
  ret
```

assistant: ```c
void *memccpy(void *dst, const void *src, int c, size_t len) {
  unsigned char c2;
  while (len--) {
    *(((unsigned char *)dst++)) = (c2 = *(((unsigned char *)src++)));
    if (c2 == c)
      return (void *)src;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L17
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
L17:
  mov    $0xffffffff,%eax
  jmp    L25
L21:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <g@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <g@plt>
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int main() {
  int *a;
  int *b;
  init();
  a = malloc(sizeof(int));
  b = malloc(sizeof(int));
  if (a == 0 || b == 0)
    return -1;
  f(a);
  f(b);
  g(a);
  g(b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  test   %rbx,%rbx
  je     L3
  mov    %rax,%rbp
  test   %rax,%rax
  je     L3
  mov    %rbx,%rdi
  call   <f@plt>
  mov    %rbp,%rdi
  call   <f@plt>
  mov    %rbx,%rdi
  call   <g@plt>
  mov    %rbp,%rdi
  call   <g@plt>
  mov    $0x0,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    $0xffffffff,%eax
  jmp    L25
```

assistant: ```c
int main() {
  int *a;
  int *b;
  init();
  a = malloc(sizeof(int));
  b = malloc(sizeof(int));
  if (a == 0 || b == 0)
    return -1;
  f(a);
  f(b);
  g(a);
  g(b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <init@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L28
  mov    %rax,%r12
  test   %rax,%rax
  je     L28
  mov    %rbp,%rdi
  call   <f@plt>
  mov    %r12,%rdi
  call   <f@plt>
  mov    %rbp,%rdi
  call   <g@plt>
  mov    %r12,%rdi
  call   <g@plt>
  xor    %eax,%eax
L10:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L28:
  or     $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int main() {
  int *a;
  int *b;
  init();
  a = malloc(sizeof(int));
  b = malloc(sizeof(int));
  if (a == 0 || b == 0)
    return -1;
  f(a);
  f(b);
  g(a);
  g(b);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <init@plt>
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L26
  mov    %rax,%r12
  test   %rax,%rax
  je     L26
  mov    %rbp,%rdi
  call   <f@plt>
  mov    %r12,%rdi
  call   <f@plt>
  mov    %rbp,%rdi
  call   <g@plt>
  mov    %r12,%rdi
  call   <g@plt>
  xor    %eax,%eax
L12:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L26:
  or     $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int main() {
  int *a;
  int *b;
  init();
  a = malloc(sizeof(int));
  b = malloc(sizeof(int));
  if (a == 0 || b == 0)
    return -1;
  f(a);
  f(b);
  g(a);
  g(b);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<largest_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %ax,-0x14(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  jmp    L36
L13:
  movzwl -0x14(%rbp),%ecx
  movswl %cx,%eax
  imul   $0x6667,%eax,%eax
  shr    $0x10,%eax
  sar    $0x2,%ax
  mov    %ecx,%esi
  sar    $0xf,%si
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movsbw -0x2(%rbp),%ax
  cmp    %ax,%dx
  jle    L23
  movzwl -0x14(%rbp),%ecx
  movswl %cx,%eax
  imul   $0x6667,%eax,%eax
  shr    $0x10,%eax
  sar    $0x2,%ax
  mov    %ecx,%esi
  sar    $0xf,%si
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %dl,-0x2(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L23
  mov    -0x20(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
L23:
  movzwl -0x14(%rbp),%eax
  movswl %ax,%edx
  imul   $0x6667,%edx,%edx
  shr    $0x10,%edx
  sar    $0x2,%dx
  sar    $0xf,%ax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %ax,-0x14(%rbp)
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L36:
  cmpb   $0x3,-0x1(%rbp)
  jle    L13
  movzbl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char largest_digit(short num, char *index) {
  char max = 0;
  for (char i = 0; i < 4; i++) {
    if (num % 10 > max) {
      max = num % 10;
      if (index)
        *index = i;
    }
    num /= 10;
  }
  return max;
}
```
user: What is the c source code of the assembly code below?

```asm
<largest_digit>:
  endbr64
  mov    %rsi,%r8
  mov    %edi,%edx
  mov    $0x0,%ecx
  mov    $0x0,%esi
  jmp    L40
L28:
  movswl %dx,%eax
  imul   $0x6667,%eax,%eax
  sar    $0x12,%eax
  sar    $0xf,%dx
  mov    %edx,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  add    $0x1,%ecx
  cmp    $0x4,%cl
  je     L46
L40:
  movswl %dx,%eax
  imul   $0x6667,%eax,%eax
  sar    $0x12,%eax
  mov    %edx,%edi
  sar    $0xf,%di
  sub    %edi,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%edi
  mov    %edx,%eax
  sub    %edi,%eax
  movsbw %sil,%di
  cmp    %di,%ax
  jle    L28
  mov    %eax,%esi
  test   %r8,%r8
  je     L28
  mov    %cl,(%r8)
  jmp    L28
L46:
  mov    %esi,%eax
  ret
```

assistant: ```c
char largest_digit(short num, char *index) {
  char max = 0;
  for (char i = 0; i < 4; i++) {
    if (num % 10 > max) {
      max = num % 10;
      if (index)
        *index = i;
    }
    num /= 10;
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<largest_digit>:
  endbr64
  mov    %rsi,%r9
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L12:
  movswl %di,%edx
  mov    %edi,%esi
  imul   $0x6667,%edx,%eax
  sar    $0xf,%si
  sar    $0x12,%eax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  lea    (%rax,%rax,1),%esi
  mov    %edi,%eax
  sub    %esi,%eax
  movsbw %r8b,%si
  cmp    %si,%ax
  jle    L27
  mov    %eax,%r8d
  test   %r9,%r9
  je     L27
  mov    %cl,(%r9)
L27:
  imul   $0x6667,%edx,%edx
  mov    %edi,%eax
  add    $0x1,%ecx
  sar    $0xf,%ax
  sar    $0x12,%edx
  mov    %edx,%edi
  sub    %eax,%edi
  cmp    $0x4,%cl
  jne    L12
  mov    %r8d,%eax
  ret
```

assistant: ```c
char largest_digit(short num, char *index) {
  char max = 0;
  for (char i = 0; i < 4; i++) {
    if (num % 10 > max) {
      max = num % 10;
      if (index)
        *index = i;
    }
    num /= 10;
  }
  return max;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<largest_digit>:
  endbr64
  mov    %edi,%edx
  test   %rsi,%rsi
  je     L4
  movswl %di,%ecx
  mov    %edx,%eax
  imul   $0x6667,%ecx,%edi
  sar    $0xf,%ax
  sar    $0x12,%edi
  sub    %eax,%edi
  lea    (%rdi,%rdi,4),%edi
  lea    (%rdi,%rdi,1),%eax
  mov    %edx,%edi
  sub    %eax,%edi
  xor    %eax,%eax
  test   %di,%di
  jle    L48
  movb   $0x0,(%rsi)
  mov    %edi,%eax
L48:
  imul   $0x6667,%ecx,%ecx
  sar    $0xf,%dx
  sar    $0x12,%ecx
  sub    %edx,%ecx
  movswl %cx,%edx
  mov    %ecx,%edi
  imul   $0x6667,%edx,%r8d
  sar    $0xf,%di
  sar    $0x12,%r8d
  sub    %edi,%r8d
  lea    (%r8,%r8,4),%r8d
  lea    (%r8,%r8,1),%edi
  mov    %ecx,%r8d
  sub    %edi,%r8d
  movsbw %al,%di
  cmp    %di,%r8w
  jle    L5
  movb   $0x1,(%rsi)
  movsbw %r8b,%di
  mov    %edi,%eax
L5:
  imul   $0x6667,%edx,%edx
  sar    $0xf,%cx
  sar    $0x12,%edx
  sub    %ecx,%edx
  movswl %dx,%r8d
  mov    %edx,%r9d
  imul   $0x6667,%r8d,%ecx
  sar    $0xf,%r9w
  sar    $0x12,%ecx
  sub    %r9d,%ecx
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rcx,%rcx,1),%r9d
  mov    %edx,%ecx
  sub    %r9d,%ecx
  cmp    %di,%cx
  jle    L32
  movb   $0x2,(%rsi)
  movsbw %cl,%di
  mov    %edi,%eax
L32:
  imul   $0x6667,%r8d,%ecx
  sar    $0xf,%dx
  sar    $0x12,%ecx
  sub    %edx,%ecx
  movswl %cx,%edx
  mov    %ecx,%r8d
  imul   $0x6667,%edx,%edx
  sar    $0xf,%r8w
  sar    $0x12,%edx
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,1),%r8d
  mov    %ecx,%edx
  sub    %r8d,%edx
  cmp    %di,%dx
  jle    L26
  movb   $0x3,(%rsi)
  mov    %edx,%eax
L26:
  ret
  nopl   0x0(%rax)
L4:
  movswl %di,%eax
  mov    %edi,%ecx
  xor    %edx,%edx
  imul   $0x6667,%eax,%eax
  sar    $0xf,%cx
  sar    $0x12,%eax
  sub    %ecx,%eax
  mov    %eax,%esi
  mov    %edi,%eax
  lea    (%rsi,%rsi,4),%ecx
  mov    %esi,%edi
  add    %ecx,%ecx
  sub    %ecx,%eax
  test   %ax,%ax
  cmovs  %edx,%eax
  movswl %si,%edx
  sar    $0xf,%di
  imul   $0x6667,%edx,%edx
  sar    $0x12,%edx
  mov    %edx,%ecx
  sub    %edi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rcx,%rcx,1),%r8d
  sub    %r8d,%esi
  mov    %esi,%ecx
  movsbw %al,%si
  cmp    %cx,%si
  cmovl  %ecx,%eax
  sub    %edi,%edx
  movswl %dx,%esi
  mov    %edx,%edi
  imul   $0x6667,%esi,%ecx
  sar    $0xf,%di
  sar    $0x12,%ecx
  sub    %edi,%ecx
  lea    (%rcx,%rcx,4),%ecx
  lea    (%rcx,%rcx,1),%edi
  mov    %edx,%ecx
  sub    %edi,%ecx
  movsbw %al,%di
  cmp    %cx,%di
  jge    L8
  movsbw %cl,%di
  mov    %edi,%eax
L8:
  imul   $0x6667,%esi,%ecx
  sar    $0xf,%dx
  sar    $0x12,%ecx
  sub    %edx,%ecx
  movswl %cx,%edx
  mov    %ecx,%esi
  imul   $0x6667,%edx,%edx
  sar    $0xf,%si
  sar    $0x12,%edx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rdx,%rdx,1),%esi
  mov    %ecx,%edx
  sub    %esi,%edx
  cmp    %di,%dx
  cmovg  %edx,%eax
  ret
```

assistant: ```c
char largest_digit(short num, char *index) {
  char max = 0;
  for (char i = 0; i < 4; i++) {
    if (num % 10 > max) {
      max = num % 10;
      if (index)
        *index = i;
    }
    num /= 10;
  }
  return max;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vec3_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *vec3_add(float *result, float *a, float *b) {
  result[0] = a[0] + b[0];
  result[1] = a[1] + b[1];
  result[2] = a[2] + b[2];
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<vec3_add>:
  endbr64
  mov    %rdi,%rax
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_add(float *result, float *a, float *b) {
  result[0] = a[0] + b[0];
  result[1] = a[1] + b[1];
  result[2] = a[2] + b[2];
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec3_add>:
  endbr64
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_add(float *result, float *a, float *b) {
  result[0] = a[0] + b[0];
  result[1] = a[1] + b[1];
  result[2] = a[2] + b[2];
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vec3_add>:
  endbr64
  movss  (%rsi),%xmm0
  addss  (%rdx),%xmm0
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  0x4(%rsi),%xmm0
  addss  0x4(%rdx),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rsi),%xmm0
  addss  0x8(%rdx),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *vec3_add(float *result, float *a, float *b) {
  result[0] = a[0] + b[0];
  result[1] = a[1] + b[1];
  result[2] = a[2] + b[2];
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_write_planes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x3c4,%esi
  mov    $0x2,%edi
  call   <outb@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x3c5,%esi
  mov    %eax,%edi
  call   <outb@plt>
  nop
  leave
  ret
```

assistant: ```c
void set_write_planes(int mask) {
  outb(2, 0x3c4);
  outb(mask, 0x3c5);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<set_write_planes>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3c4,%esi
  mov    $0x2,%edi
  call   <outb@plt>
  mov    $0x3c5,%esi
  mov    %ebx,%edi
  call   <outb@plt>
  pop    %rbx
  ret
```

assistant: ```c
void set_write_planes(int mask) {
  outb(2, 0x3c4);
  outb(mask, 0x3c5);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_write_planes>:
  endbr64
  push   %rbp
  mov    $0x3c4,%esi
  mov    %edi,%ebp
  mov    $0x2,%edi
  call   <outb@plt>
  mov    %ebp,%edi
  mov    $0x3c5,%esi
  pop    %rbp
  jmp    1050 <outb@plt>
```

assistant: ```c
void set_write_planes(int mask) {
  outb(2, 0x3c4);
  outb(mask, 0x3c5);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<set_write_planes>:
  endbr64
  push   %rbp
  mov    $0x3c4,%esi
  mov    %edi,%ebp
  mov    $0x2,%edi
  call   <outb@plt>
  mov    %ebp,%edi
  mov    $0x3c5,%esi
  pop    %rbp
  jmp    1050 <outb@plt>
```

assistant: ```c
void set_write_planes(int mask) {
  outb(2, 0x3c4);
  outb(mask, 0x3c5);
}
```