ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L24
L57:
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L42:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L24
  cmpl   $0x3e7,-0x10(%rbp)
  jle    L42
L24:
  cmpl   $0x3e7,-0x10(%rbp)
  jle    L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
data_type: string
name: unpack_data
arguments: data_tag: D2
data_type: string

tool: D13:  %d

tool: D2: N[%d] = %d


assistant: ```c
int main() {
  int X, Y, i = 0, k;
  scanf(" %d", &X);
  while (i < 1000) {
    k = 0;
    while (k < X && i < 1000) {
      printf("N[%d] = %d\n", i, k);
      k++;
      i++;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D13(%rip),%r12
  jmp    L3
L43:
  cmp    $0x3e7,%ebx
  jg     L9
L3:
  cmpl   $0x0,0x4(%rsp)
  jle    L43
  mov    $0x0,%ebp
  cmp    $0x3e7,%ebx
  jg     L43
L18:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  add    $0x1,%ebx
  cmp    %ebp,0x4(%rsp)
  jle    L43
  cmp    $0x3e7,%ebx
  jle    L18
  jmp    L43
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string

tool: D5:  %d

tool: D13: N[%d] = %d


assistant: ```c
int main() {
  int X, Y, i = 0, k;
  scanf(" %d", &X);
  while (i < 1000) {
    k = 0;
    while (k < X && i < 1000) {
      printf("N[%d] = %d\n", i, k);
      k++;
      i++;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L15
  cmp    $0x3e8,%ebx
  je     L42
  xor    %ebp,%ebp
  jmp    L16
  nopl   0x0(%rax)
L64:
  cmp    $0x3e8,%ebx
  je     L42
L16:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,0x4(%rsp)
  jg     L64
L15:
  cmp    $0x3e8,%ebx
  jne    L24
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string

tool: D7:  %d

tool: D18: N[%d] = %d


assistant: ```c
int main() {
  int X, Y, i = 0, k;
  scanf(" %d", &X);
  while (i < 1000) {
    k = 0;
    while (k < X && i < 1000) {
      printf("N[%d] = %d\n", i, k);
      k++;
      i++;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  lea    D14(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
L33:
  test   %eax,%eax
  jle    L27
  cmp    $0x3e8,%ebx
  je     L66
  xor    %ebp,%ebp
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L80:
  cmp    $0x3e8,%ebx
  je     L66
L54:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%ebx
  cmp    %ebp,%eax
  jg     L80
  cmp    $0x3e8,%ebx
  jne    L33
  nopw   0x0(%rax,%rax,1)
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  cmp    $0x3e8,%ebx
  je     L66
L49:
  jmp    L49
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string

tool: D11:  %d

tool: D14: N[%d] = %d


assistant: ```c
int main() {
  int X, Y, i = 0, k;
  scanf(" %d", &X);
  while (i < 1000) {
    k = 0;
    while (k < X && i < 1000) {
      printf("N[%d] = %d\n", i, k);
      k++;
      i++;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L50
L13:
  lea    -0x14(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x20(%rbp)
L50:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x20(%rbp)
  jl     L13
  movl   $0x0,-0x20(%rbp)
  jmp    L11
L18:
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%edx
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L86
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%edx
  mov    -0x20(%rbp),%eax
  cltq
  mov    %edx,-0x14(%rbp,%rax,4)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x18(%rbp),%edx
  mov    %edx,-0x14(%rbp,%rax,4)
L86:
  addl   $0x1,-0x20(%rbp)
L11:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jl     L18
  movl   $0x1,-0x20(%rbp)
  jmp    L33
L128:
  movl   $0x0,-0x1c(%rbp)
  jmp    L115
L37:
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  cltd
  idivl  -0x20(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L92
  addl   $0x1,-0x1c(%rbp)
L115:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L37
  jmp    L71
L92:
  nop
L71:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L112
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L112:
  addl   $0x1,-0x20(%rbp)
L33:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L128
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D10: %d

tool: D8: %d


assistant: ```c
int main(void) {
  int n, a[3], i, j, k, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n - 1; i++) {
    if (a[i] < a[i + 1]) {
      temp = a[i];
      a[i] = a[i + 1];
      a[i + 1] = temp;
    }
  }
  for (i = 1; i <= a[n - 1]; i++) {
    for (j = 0; j < n; j++) {
      if (a[j] % i != 0)
        break;
    }
    if (j == n)
      printf("%d\n", i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L76
  lea    0xc(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D3(%rip),%r12
L101:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x8(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L101
L76:
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L102
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%ecx
  cmp    %edx,%ecx
  jle    L22
  mov    %ecx,0xc(%rsp)
  mov    %edx,0x10(%rsp)
L22:
  cmp    $0x1,%eax
  jle    L102
  mov    0x10(%rsp),%eax
  mov    0x14(%rsp),%edx
  cmp    %edx,%eax
  jge    L102
  mov    %edx,0x10(%rsp)
  mov    %eax,0x14(%rsp)
L102:
  mov    0x8(%rsp),%edi
  lea    -0x1(%rdi),%eax
  cltq
  mov    $0x1,%ebx
  lea    D19(%rip),%rbp
  cmpl   $0x0,0xc(%rsp,%rax,4)
  jg     L131
L65:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  cmp    %ecx,%edi
  je     L114
L137:
  add    $0x1,%ebx
  mov    0x8(%rsp),%edi
  lea    -0x1(%rdi),%eax
  cltq
  cmp    %ebx,0xc(%rsp,%rax,4)
  jl     L65
L131:
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  test   %edi,%edi
  jle    L17
L60:
  mov    (%rsi),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L17
  add    $0x1,%ecx
  add    $0x4,%rsi
  cmp    %edi,%ecx
  jne    L60
L114:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L137
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D19
type_guessed: string

tool: D3: %d

tool: D19: %d


assistant: ```c
int main(void) {
  int n, a[3], i, j, k, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n - 1; i++) {
    if (a[i] < a[i + 1]) {
      temp = a[i];
      a[i] = a[i + 1];
      a[i + 1] = temp;
    }
  }
  for (i = 1; i <= a[n - 1]; i++) {
    for (j = 0; j < n; j++) {
      if (a[j] % i != 0)
        break;
    }
    if (j == n)
      printf("%d\n", i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  test   %edi,%edi
  jle    L149
  lea    0xc(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L61:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  cmp    %ebx,%edi
  jg     L61
L149:
  lea    -0x1(%rdi),%eax
  test   %eax,%eax
  jle    L159
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%ecx
  cmp    %edx,%ecx
  jle    L121
  mov    %ecx,0xc(%rsp)
  mov    %edx,0x10(%rsp)
L121:
  cmp    $0x1,%eax
  je     L159
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%ecx
  cmp    %ecx,%edx
  jge    L159
  mov    %ecx,0x10(%rsp)
  mov    %edx,0x14(%rsp)
L159:
  cltq
  mov    $0x1,%ebx
  lea    D17(%rip),%rbp
  mov    0xc(%rsp,%rax,4),%eax
  test   %eax,%eax
  jle    L23
  nopl   0x0(%rax)
L13:
  lea    0xc(%rsp),%rcx
  xor    %esi,%esi
  test   %edi,%edi
  jg     L66
  jmp    L106
  nopl   (%rax)
L71:
  add    $0x1,%esi
  add    $0x4,%rcx
  cmp    %edi,%esi
  je     L18
L66:
  mov    (%rcx),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L71
L17:
  lea    -0x1(%rdi),%eax
  add    $0x1,%ebx
  cltq
  cmp    %ebx,0xc(%rsp,%rax,4)
  jge    L13
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L106:
  jne    L17
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x8(%rsp),%edi
  lea    -0x1(%rdi),%eax
  cltq
  cmp    %ebx,0xc(%rsp,%rax,4)
  jge    L13
  jmp    L23
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D17
type: string

tool: D13: %d

tool: D17: %d


assistant: ```c
int main(void) {
  int n, a[3], i, j, k, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n - 1; i++) {
    if (a[i] < a[i + 1]) {
      temp = a[i];
      a[i] = a[i + 1];
      a[i + 1] = temp;
    }
  }
  for (i = 1; i <= a[n - 1]; i++) {
    for (j = 0; j < n; j++) {
      if (a[j] % i != 0)
        break;
    }
    if (j == n)
      printf("%d\n", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  test   %ecx,%ecx
  jle    L124
  lea    0x8(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L113:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebx,%ecx
  jg     L113
L124:
  lea    -0x1(%rcx),%eax
  test   %eax,%eax
  jle    L37
  movq   0x8(%rsp),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%edx
  movd   %xmm2,%esi
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %edx,%esi
  jle    L126
  movq   %xmm1,0x8(%rsp)
L126:
  cmp    $0x1,%eax
  je     L37
  movq   0xc(%rsp),%xmm0
  pshufd $0xe5,%xmm0,%xmm3
  movd   %xmm0,%esi
  movd   %xmm3,%edx
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %edx,%esi
  jge    L37
  movq   %xmm1,0xc(%rsp)
L37:
  cltq
  mov    $0x1,%ebx
  lea    D13(%rip),%rbp
  mov    0x8(%rsp,%rax,4),%esi
  test   %esi,%esi
  jle    L43
L104:
  xor    %eax,%eax
  test   %ecx,%ecx
  jle    L150
  mov    0x8(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L62
  cmp    $0x1,%ecx
  je     L95
  mov    0xc(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L62
  cmp    $0x2,%ecx
  je     L120
  mov    0x10(%rsp),%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L62
  mov    $0x3,%eax
L150:
  cmp    %eax,%ecx
  jne    L62
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  lea    -0x1(%rcx),%eax
  cltq
  mov    0x8(%rsp,%rax,4),%esi
L62:
  add    $0x1,%ebx
  cmp    %esi,%ebx
  jle    L104
L43:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L95:
  mov    $0x1,%eax
  jmp    L150
L120:
  mov    $0x2,%eax
  jmp    L150
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string
name: disassemble_data
arguments: data_tag: D13
type: string

tool: D9: %d

tool: D13: %d


assistant: ```c
int main(void) {
  int n, a[3], i, j, k, temp;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  for (i = 0; i < n - 1; i++) {
    if (a[i] < a[i + 1]) {
      temp = a[i];
      a[i] = a[i + 1];
      a[i + 1] = temp;
    }
  }
  for (i = 1; i <= a[n - 1]; i++) {
    for (j = 0; j < n; j++) {
      if (a[j] % i != 0)
        break;
    }
    if (j == n)
      printf("%d\n", i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<udev_device_get_parent_with_subsystem_devtype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L30
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_device_get_parent@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L53
L107:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_device_get_subsystem@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L71
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L71
  cmpq   $0x0,-0x38(%rbp)
  je     L24
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_device_get_devtype@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L71
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L4
L71:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <udev_device_get_parent@plt>
  mov    %rax,-0x18(%rbp)
L53:
  cmpq   $0x0,-0x18(%rbp)
  jne    L107
  jmp    L84
L24:
  nop
  jmp    L84
L4:
  nop
L84:
  mov    -0x18(%rbp),%rax
L30:
  leave
  ret
```

assistant: ```c
struct udev_device *udev_device_get_parent_with_subsystem_devtype(struct udev_device *udev_device, const char *subsystem, const char *devtype) {
  struct udev_device *parent;
  if (subsystem == NULL)
    return NULL;
  parent = udev_device_get_parent(udev_device);
  while (parent != NULL) {
    const char *parent_subsystem;
    const char *parent_devtype;
    parent_subsystem = udev_device_get_subsystem(parent);
    if (parent_subsystem != NULL && strcmp(parent_subsystem, subsystem) == 0) {
      if (devtype == NULL)
        break;
      parent_devtype = udev_device_get_devtype(parent);
      if (parent_devtype != NULL && strcmp(parent_devtype, devtype) == 0)
        break;
    }
    parent = udev_device_get_parent(parent);
  }
  return parent;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<udev_device_get_parent_with_subsystem_devtype>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L36
  mov    %rdx,%r12
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L12
  jmp    L54
L67:
  mov    %rbx,%rdi
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L54
L12:
  mov    %rbx,%rdi
  call   <udev_device_get_subsystem@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L67
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L67
  test   %r12,%r12
  je     L54
  mov    %rbx,%rdi
  call   <udev_device_get_devtype@plt>
  test   %rax,%rax
  je     L67
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L67
  jmp    L54
L36:
  mov    %rsi,%rbx
L54:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct udev_device *udev_device_get_parent_with_subsystem_devtype(struct udev_device *udev_device, const char *subsystem, const char *devtype) {
  struct udev_device *parent;
  if (subsystem == NULL)
    return NULL;
  parent = udev_device_get_parent(udev_device);
  while (parent != NULL) {
    const char *parent_subsystem;
    const char *parent_devtype;
    parent_subsystem = udev_device_get_subsystem(parent);
    if (parent_subsystem != NULL && strcmp(parent_subsystem, subsystem) == 0) {
      if (devtype == NULL)
        break;
      parent_devtype = udev_device_get_devtype(parent);
      if (parent_devtype != NULL && strcmp(parent_devtype, devtype) == 0)
        break;
    }
    parent = udev_device_get_parent(parent);
  }
  return parent;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<udev_device_get_parent_with_subsystem_devtype>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L76
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L76
L1:
  mov    %rbp,%rdi
  call   <udev_device_get_subsystem@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L32
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L32
  test   %r12,%r12
  je     L40
  mov    %rbp,%rdi
  call   <udev_device_get_devtype@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L32
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L40
  nop
L32:
  mov    %rbp,%rdi
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L1
L76:
  xor    %ebp,%ebp
L40:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct udev_device *udev_device_get_parent_with_subsystem_devtype(struct udev_device *udev_device, const char *subsystem, const char *devtype) {
  struct udev_device *parent;
  if (subsystem == NULL)
    return NULL;
  parent = udev_device_get_parent(udev_device);
  while (parent != NULL) {
    const char *parent_subsystem;
    const char *parent_devtype;
    parent_subsystem = udev_device_get_subsystem(parent);
    if (parent_subsystem != NULL && strcmp(parent_subsystem, subsystem) == 0) {
      if (devtype == NULL)
        break;
      parent_devtype = udev_device_get_devtype(parent);
      if (parent_devtype != NULL && strcmp(parent_devtype, devtype) == 0)
        break;
    }
    parent = udev_device_get_parent(parent);
  }
  return parent;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<udev_device_get_parent_with_subsystem_devtype>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L75
  mov    %rsi,%rbx
  mov    %rdx,%r12
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L75
  test   %r12,%r12
  je     L58
  nopl   0x0(%rax)
L35:
  mov    %rbp,%rdi
  call   <udev_device_get_subsystem@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L27
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L27
  mov    %rbp,%rdi
  call   <udev_device_get_devtype@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L27
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L99
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rdi
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L35
L75:
  xor    %ebp,%ebp
L99:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %rbx,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L99
L7:
  mov    %rbp,%rdi
  call   <udev_device_get_parent@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L75
L58:
  mov    %rbp,%rdi
  call   <udev_device_get_subsystem@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L44
  jmp    L7
```

assistant: ```c
struct udev_device *udev_device_get_parent_with_subsystem_devtype(struct udev_device *udev_device, const char *subsystem, const char *devtype) {
  struct udev_device *parent;
  if (subsystem == NULL)
    return NULL;
  parent = udev_device_get_parent(udev_device);
  while (parent != NULL) {
    const char *parent_subsystem;
    const char *parent_devtype;
    parent_subsystem = udev_device_get_subsystem(parent);
    if (parent_subsystem != NULL && strcmp(parent_subsystem, subsystem) == 0) {
      if (devtype == NULL)
        break;
      parent_devtype = udev_device_get_devtype(parent);
      if (parent_devtype != NULL && strcmp(parent_devtype, devtype) == 0)
        break;
    }
    parent = udev_device_get_parent(parent);
  }
  return parent;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<linexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  %xmm3,-0x20(%rbp)
  movsd  %xmm4,-0x28(%rbp)
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L34
  movsd  -0x20(%rbp),%xmm0
  jmp    L3
L34:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L13
  movsd  -0x28(%rbp),%xmm0
  jmp    L3
L13:
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  subsd  -0x10(%rbp),%xmm1
  movapd %xmm0,%xmm2
  divsd  %xmm1,%xmm2
  movsd  -0x28(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movapd %xmm2,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mulsd  -0x20(%rbp),%xmm0
L3:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double linexp(double x, double a, double b, double c, double d) {
  if (x <= a)
    return c;
  if (x >= b)
    return d;
  return pow(d / c, (x - a) / (b - a)) * c;
}
```