ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  mov    %esi,%edx
  lea    D8(%rip),%rcx
  cmp    $0x1,%esi
  je     L9
  movzbl 0x1(%rdi),%eax
  movzwl 0x6(%rcx,%rax,2),%edx
  add    %esi,%edx
L9:
  movzbl -0x1(%rdi,%rsi,1),%eax
  movzbl (%rdi),%esi
  movzwl (%rcx,%rax,2),%eax
  movzwl (%rcx,%rsi,2),%ecx
  add    %ecx,%eax
  add    %edx,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: 	

assistant: ```c
unsigned int hash(register const char *str, register size_t len) {
  static const unsigned short asso_values[] = {272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 9, 7, 6, 4, 4, 3, 4, 3, 3, 272, 272, 272, 272, 272, 272, 272, 70, 83, 152, 7, 16, 61, 98, 5, 76, 102, 126, 12, 19, 54, 54, 31, 97, 3, 4, 9, 33, 136, 113, 86, 15, 272, 272, 272, 272, 272, 272, 272, 70, 83, 152, 7, 16, 61, 98, 5, 76, 102, 126, 12, 19, 54, 54, 31, 97, 3, 4, 9, 33, 136, 113, 86, 15, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272, 272};
  register unsigned int hval = len;
  switch (hval) {
  default:
    hval += asso_values[(unsigned char)str[1] + 3];
  case 1:
    hval += asso_values[(unsigned char)str[0]];
    break;
  }
  return hval + asso_values[(unsigned char)str[len - 1]];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pdist_city_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L34
L29:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L2
L9:
  mov    -0x38(%rbp),%eax
  imul   -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <city_block_distance@plt>
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  addq   $0x8,-0x18(%rbp)
L2:
  mov    -0x1c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L9
  addl   $0x1,-0x20(%rbp)
L34:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L29
  nop
  nop
  leave
  ret
```

assistant: ```c
void pdist_city_block(const double *X, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = city_block_distance(u, v, n);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pdist_city_block>:
  endbr64
  test   %edx,%edx
  jle    L15
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %ecx,%r14d
  lea    -0x2(%rdx),%r15d
  movslq %ecx,%rax
  lea    0x0(,%rax,8),%rcx
  mov    %rcx,0x8(%rsp)
  add    %rcx,%rdi
  mov    %rdi,0x10(%rsp)
  neg    %rax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
L25:
  cmp    $0xffffffff,%r15d
  je     L21
  mov    0x10(%rsp),%rbp
  mov    %rbp,%r13
  add    0x18(%rsp),%r13
  mov    %r15d,%eax
  lea    0x8(%rbx,%rax,8),%r12
L39:
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <city_block_distance@plt>
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  add    0x8(%rsp),%rbp
  cmp    %r12,%rbx
  jne    L39
  sub    $0x1,%r15d
  mov    0x8(%rsp),%rcx
  add    %rcx,0x10(%rsp)
  mov    %r12,%rbx
  jmp    L25
L21:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  ret
```

assistant: ```c
void pdist_city_block(const double *X, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = city_block_distance(u, v, n);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<pdist_city_block>:
  endbr64
  test   %edx,%edx
  jle    L35
  push   %r15
  lea    -0x2(%rdx),%eax
  mov    %rsi,%r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  shl    $0x3,%rbx
  sub    $0x18,%rsp
  mov    %eax,0x4(%rsp)
  lea    (%rdi,%rbx,1),%rax
  mov    %rax,0x8(%rsp)
  mov    0x4(%rsp),%eax
  cmp    $0xffffffff,%eax
  je     L22
L17:
  mov    0x8(%rsp),%r14
  lea    0x1(%rax),%edx
  lea    (%r15,%rdx,8),%rbp
  mov    %r14,%r12
  sub    %rbx,%r12
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r14,%rsi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x8,%r15
  call   <city_block_distance@plt>
  add    %rbx,%r14
  movsd  %xmm0,-0x8(%r15)
  cmp    %rbp,%r15
  jne    L21
  subl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  add    %rbx,0x8(%rsp)
  cmp    $0xffffffff,%eax
  jne    L17
L22:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  ret
```

assistant: ```c
void pdist_city_block(const double *X, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = city_block_distance(u, v, n);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pdist_city_block>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  cmp    $0x1,%edx
  jle    L2
  movslq %ecx,%rbx
  mov    %edx,%eax
  movl   $0x1,0x18(%rsp)
  mov    %ecx,%r13d
  shl    $0x3,%rbx
  sub    $0x1,%eax
  lea    (%rdi,%rbx,1),%rsi
  mov    %eax,0x1c(%rsp)
  mov    %rsi,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L5:
  mov    0x10(%rsp),%rbp
  mov    0x8(%rsp),%r14
  mov    0x18(%rsp),%r15d
  mov    %rbp,%r12
  sub    %rbx,%r12
  nopl   (%rax)
L22:
  mov    %rbp,%rsi
  mov    %r13d,%edx
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <city_block_distance@plt>
  add    $0x8,%r14
  add    %rbx,%rbp
  movsd  %xmm0,-0x8(%r14)
  cmp    %r15d,0x4(%rsp)
  jg     L22
  mov    0x18(%rsp),%ecx
  mov    0x1c(%rsp),%eax
  mov    0x8(%rsp),%rdx
  add    %rbx,0x10(%rsp)
  sub    %ecx,%eax
  add    $0x1,%ecx
  lea    0x8(%rdx,%rax,8),%rax
  mov    %ecx,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  cmp    %ecx,0x4(%rsp)
  jne    L5
L2:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void pdist_city_block(const double *X, double *dm, int m, int n) {
  int i, j;
  const double *u, *v;
  double *it = dm;
  for (i = 0; i < m; i++) {
    for (j = i + 1; j < m; j++, it++) {
      u = X + (n * i);
      v = X + (n * j);
      *it = city_block_distance(u, v, n);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strv_freep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strv_free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L12
L0:
  nop
L12:
  leave
  ret
```

assistant: ```c
void strv_freep(char ***l) {
  if (!l)
    return;
  strv_free(*l);
  *l = NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strv_freep>:
  endbr64
  test   %rdi,%rdi
  je     L1
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <strv_free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void strv_freep(char ***l) {
  if (!l)
    return;
  strv_free(*l);
  *l = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strv_freep>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <strv_free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L4:
  ret
```

assistant: ```c
void strv_freep(char ***l) {
  if (!l)
    return;
  strv_free(*l);
  *l = NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strv_freep>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <strv_free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void strv_freep(char ***l) {
  if (!l)
    return;
  strv_free(*l);
  *l = NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%r10
  mov    $0x0,%eax
  call   <hello.0>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: D0: World

assistant: ```c
int main(void) {
  void hello() { printf("Hello\n"); }
  hello();
  printf("World\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D8
type_infered: string

tool: D16: Hello

tool: D8: World

assistant: ```c
int main(void) {
  void hello() { printf("Hello\n"); }
  hello();
  printf("World\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D13: Hello

tool: D4: World

assistant: ```c
int main(void) {
  void hello() { printf("Hello\n"); }
  hello();
  printf("World\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string

tool: D9: Hello

tool: D18: World

assistant: ```c
int main(void) {
  void hello() { printf("Hello\n"); }
  hello();
  printf("World\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cos>:
  endbr64
  addsd  D28(%rip),%xmm0
  movsd  D6(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L54
L57:
  subsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  ja     L57
L54:
  movsd  D6(%rip),%xmm2
  movsd  D52(%rip),%xmm1
  comisd %xmm0,%xmm1
  jbe    L2
L24:
  addsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  ja     L24
L2:
  movapd %xmm0,%xmm4
  mulsd  %xmm0,%xmm4
  xorpd  D25(%rip),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  D36(%rip),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm1,%xmm2
  andpd  D49(%rip),%xmm2
  mov    $0x2,%eax
  comisd D19(%rip),%xmm2
  jb     L47
  movsd  D65(%rip),%xmm7
  movq   D49(%rip),%xmm6
  movsd  D19(%rip),%xmm5
L55:
  mulsd  %xmm4,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  addsd  %xmm2,%xmm2
  movapd %xmm2,%xmm3
  addsd  %xmm7,%xmm3
  mulsd  %xmm3,%xmm2
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%eax
  movapd %xmm1,%xmm2
  andpd  %xmm6,%xmm2
  comisd %xmm5,%xmm2
  jae    L55
L47:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D28
datatype: byte[8]
name: unpack_data
arguments: data_label: D6
datatype: byte[8]
name: unpack_data
arguments: data_label: D52
datatype: byte[8]
name: unpack_data
arguments: data_label: D25
datatype: byte[16]
name: unpack_data
arguments: data_label: D36
datatype: byte[8]
name: unpack_data
arguments: data_label: D49
datatype: qword[2]
name: unpack_data
arguments: data_label: D19
datatype: f64[2]
name: unpack_data
arguments: data_label: D65
datatype: f64

tool: {"D28": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D6": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D52": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0xc0]}

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D36": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D49": [0x7fffffffffffffff,0x0000000000000000]}

tool: {"D19": [0.00001,1.0]}

tool: D65: 1

assistant: ```c
double cos(double rad) {
  double app;
  double diff;
  int inc = 1;
  rad += 3.14159265358979323846 / 2.0;
  while (rad > 2 * 3.14159265358979323846)
    rad -= 2 * 3.14159265358979323846;
  while (rad < -2 * 3.14159265358979323846)
    rad += 2 * 3.14159265358979323846;
  app = diff = rad;
  diff = (diff * (-(rad * rad))) / ((2.0 * inc) * (2.0 * inc + 1.0));
  app = app + diff;
  inc++;
  while (fabs(diff) >= 0.00001) {
    diff = (diff * (-(rad * rad))) / ((2.0 * inc) * (2.0 * inc + 1.0));
    app = app + diff;
    inc++;
  }
  return app;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cos>:
  endbr64
  addsd  D40(%rip),%xmm0
  movsd  D64(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L48
  nopw   0x0(%rax,%rax,1)
L46:
  subsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  ja     L46
L48:
  movsd  D78(%rip),%xmm2
  comisd %xmm0,%xmm2
  jbe    L16
  nopl   0x0(%rax,%rax,1)
L0:
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  ja     L0
L16:
  movapd %xmm0,%xmm4
  movq   D52(%rip),%xmm6
  movsd  D39(%rip),%xmm5
  mov    $0x2,%eax
  mulsd  %xmm0,%xmm4
  movsd  D1(%rip),%xmm7
  xorpd  D51(%rip),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  D54(%rip),%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  andpd  %xmm6,%xmm2
  comisd %xmm5,%xmm2
  jb     L15
  nopl   0x0(%rax)
L14:
  mulsd  %xmm4,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  addsd  %xmm2,%xmm2
  movapd %xmm2,%xmm3
  addsd  %xmm7,%xmm3
  mulsd  %xmm3,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  andpd  %xmm6,%xmm2
  comisd %xmm5,%xmm2
  jae    L14
L15:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D40
type_guessed: byte[8]
name: retrieve_data
arguments: label: D64
type_guessed: byte[8]
name: retrieve_data
arguments: label: D78
type_guessed: byte[8]
name: retrieve_data
arguments: label: D52
type_guessed: qword
name: retrieve_data
arguments: label: D39
type_guessed: f64
name: retrieve_data
arguments: label: D1
type_guessed: f64
name: retrieve_data
arguments: label: D51
type_guessed: byte[16]
name: retrieve_data
arguments: label: D54
type_guessed: byte[8]

tool: {"D40": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D64": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D78": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0xc0]}

tool: D52: 9223372036854775807

tool: D39: 1e-05

tool: D1: 1

tool: {"D51": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D54": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

assistant: ```c
double cos(double rad) {
  double app;
  double diff;
  int inc = 1;
  rad += 3.14159265358979323846 / 2.0;
  while (rad > 2 * 3.14159265358979323846)
    rad -= 2 * 3.14159265358979323846;
  while (rad < -2 * 3.14159265358979323846)
    rad += 2 * 3.14159265358979323846;
  app = diff = rad;
  diff = (diff * (-(rad * rad))) / ((2.0 * inc) * (2.0 * inc + 1.0));
  app = app + diff;
  inc++;
  while (fabs(diff) >= 0.00001) {
    diff = (diff * (-(rad * rad))) / ((2.0 * inc) * (2.0 * inc + 1.0));
    app = app + diff;
    inc++;
  }
  return app;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cos>:
  endbr64
  addsd  D22(%rip),%xmm0
  movsd  D4(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L32
  nopw   0x0(%rax,%rax,1)
L10:
  subsd  %xmm1,%xmm0
  comisd %xmm1,%xmm0
  ja     L10
L32:
  movsd  D54(%rip),%xmm2
  comisd %xmm0,%xmm2
  jbe    L0
  nopl   0x0(%rax,%rax,1)
L51:
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  ja     L51
L0:
  movapd %xmm0,%xmm4
  movq   D23(%rip),%xmm6
  movsd  D8(%rip),%xmm5
  mov    $0x2,%eax
  mulsd  %xmm0,%xmm4
  movsd  D59(%rip),%xmm7
  xorpd  D67(%rip),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm0,%xmm1
  divsd  D58(%rip),%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  andpd  %xmm6,%xmm2
  comisd %xmm5,%xmm2
  jb     L20
  nopl   0x0(%rax)
L4:
  mulsd  %xmm4,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  add    $0x1,%eax
  addsd  %xmm2,%xmm2
  movapd %xmm2,%xmm3
  addsd  %xmm7,%xmm3
  mulsd  %xmm3,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  andpd  %xmm6,%xmm2
  comisd %xmm5,%xmm2
  jae    L4
L20:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D22
type_guessed: byte[8]
name: retrieve_data
arguments: label: D4
type_guessed: byte[8]
name: retrieve_data
arguments: label: D54
type_guessed: byte[8]
name: retrieve_data
arguments: label: D23
type_guessed: qword
name: retrieve_data
arguments: label: D8
type_guessed: f64
name: retrieve_data
arguments: label: D59
type_guessed: f64
name: retrieve_data
arguments: label: D67
type_guessed: byte[16]
name: retrieve_data
arguments: label: D58
type_guessed: byte[8]

tool: {"D22": [0x18,0x2d,0x44,0x54,0xfb,0x21,0xf9,0x3f]}

tool: {"D4": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

tool: {"D54": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0xc0]}

tool: D23: 9223372036854775807

tool: D8: 1e-05

tool: D59: 1

tool: {"D67": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

assistant: ```c
double cos(double rad) {
  double app;
  double diff;
  int inc = 1;
  rad += 3.14159265358979323846 / 2.0;
  while (rad > 2 * 3.14159265358979323846)
    rad -= 2 * 3.14159265358979323846;
  while (rad < -2 * 3.14159265358979323846)
    rad += 2 * 3.14159265358979323846;
  app = diff = rad;
  diff = (diff * (-(rad * rad))) / ((2.0 * inc) * (2.0 * inc + 1.0));
  app = app + diff;
  inc++;
  while (fabs(diff) >= 0.00001) {
    diff = (diff * (-(rad * rad))) / ((2.0 * inc) * (2.0 * inc + 1.0));
    app = app + diff;
    inc++;
  }
  return app;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_func_03>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  subq   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,(%rax)
  subq   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,(%rax)
  subq   $0x2,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
short *test_func_03(short *p, int c) {
  *--p = (short)c;
  *--p = (short)c;
  *--p = (short)c;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_func_03>:
  endbr64
  mov    %si,-0x2(%rdi)
  mov    %si,-0x4(%rdi)
  mov    %si,-0x6(%rdi)
  lea    -0x6(%rdi),%rax
  ret
```

assistant: ```c
short *test_func_03(short *p, int c) {
  *--p = (short)c;
  *--p = (short)c;
  *--p = (short)c;
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_func_03>:
  endbr64
  mov    %si,-0x2(%rdi)
  lea    -0x6(%rdi),%rax
  mov    %si,-0x4(%rdi)
  mov    %si,-0x6(%rdi)
  ret
```

assistant: ```c
short *test_func_03(short *p, int c) {
  *--p = (short)c;
  *--p = (short)c;
  *--p = (short)c;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_func_03>:
  endbr64
  mov    %si,-0x2(%rdi)
  lea    -0x6(%rdi),%rax
  mov    %si,-0x4(%rdi)
  mov    %si,-0x6(%rdi)
  ret
```

assistant: ```c
short *test_func_03(short *p, int c) {
  *--p = (short)c;
  *--p = (short)c;
  *--p = (short)c;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chibord_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L6:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <byte_reverse_int@plt>
  addl   $0x1,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
L1:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void chibord_(int *inarr, int *num) {
  int *ip;
  int k;
  ip = inarr;
  for (k = 0; k < *num; k++, ip++)
    byte_reverse_int(ip);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chibord_>:
  endbr64
  cmpl   $0x0,(%rsi)
  jle    L13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    $0x0,%ebp
L7:
  mov    %rbx,%rdi
  call   <byte_reverse_int@plt>
  add    $0x1,%ebp
  add    $0x4,%rbx
  cmp    %ebp,(%r12)
  jg     L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  ret
```

assistant: ```c
void chibord_(int *inarr, int *num) {
  int *ip;
  int k;
  ip = inarr;
  for (k = 0; k < *num; k++, ip++)
    byte_reverse_int(ip);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chibord_>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  jle    L8
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <byte_reverse_int@plt>
  cmp    %ebp,(%r12)
  jg     L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void chibord_(int *inarr, int *num) {
  int *ip;
  int k;
  ip = inarr;
  for (k = 0; k < *num; k++, ip++)
    byte_reverse_int(ip);
}
```
user: Translate the below assembly code into C programming language:

```asm
<chibord_>:
  endbr64
  mov    (%rsi),%eax
  test   %eax,%eax
  jle    L9
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  add    $0x1,%ebp
  add    $0x4,%rbx
  call   <byte_reverse_int@plt>
  cmp    %ebp,(%r12)
  jg     L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void chibord_(int *inarr, int *num) {
  int *ip;
  int k;
  ip = inarr;
  for (k = 0; k < *num; k++, ip++)
    byte_reverse_int(ip);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gen_XCPU>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <handle_XCPU@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int gen_XCPU() {
  handle_XCPU(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gen_XCPU>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <handle_XCPU@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_XCPU() {
  handle_XCPU(0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_XCPU>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <handle_XCPU@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_XCPU() {
  handle_XCPU(0);
  return 0;
}
```