ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<convert_dmatrix_imatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r14
  mov    %r8,%r13
  mov    %r9,%r12
  cmp    %rdx,%rsi
  jg     L13
L14:
  mov    (%r12,%rbx,8),%rcx
  mov    (%r15,%rbx,8),%rdi
  mov    %r13,%rdx
  mov    %r14,%rsi
  call   <convert_dvector_ivector@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jge    L14
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convert_dmatrix_imatrix(double **X, long nrl, long nrh, long ncl, long nch, int **Y) {
  long i;
  for (i = nrl; i <= nrh; i++)
    convert_dvector_ivector(X[i], ncl, nch, Y[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_dmatrix_imatrix>:
  endbr64
  cmp    %rdx,%rsi
  jg     L19
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    (%r14,%rbx,8),%rcx
  mov    (%r15,%rbx,8),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  add    $0x1,%rbx
  call   <convert_dvector_ivector@plt>
  cmp    %rbx,%rbp
  jge    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void convert_dmatrix_imatrix(double **X, long nrl, long nrh, long ncl, long nch, int **Y) {
  long i;
  for (i = nrl; i <= nrh; i++)
    convert_dvector_ivector(X[i], ncl, nch, Y[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<convert_dmatrix_imatrix>:
  endbr64
  cmp    %rdx,%rsi
  jg     L14
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    (%r14,%rbx,8),%rcx
  mov    (%r15,%rbx,8),%rdi
  mov    %r12,%rdx
  mov    %r13,%rsi
  add    $0x1,%rbx
  call   <convert_dvector_ivector@plt>
  cmp    %rbx,%rbp
  jge    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void convert_dmatrix_imatrix(double **X, long nrl, long nrh, long ncl, long nch, int **Y) {
  long i;
  for (i = nrl; i <= nrh; i++)
    convert_dvector_ivector(X[i], ncl, nch, Y[i]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stripquotes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L16
  addq   $0x1,-0x10(%rbp)
  jmp    L9
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  mov    $0x22,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L2:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *stripquotes(char *s) {
  char *start, *end;
  start = strchr(s, '"');
  if (start)
    ++start;
  else
    start = s;
  end = strrchr(start, '"');
  if (end)
    *(end) = '\0';
  return start;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stripquotes>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x22,%esi
  call   <strchr@plt>
  lea    0x1(%rax),%rbx
  test   %rax,%rax
  cmove  %rbp,%rbx
  mov    $0x22,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L0
  movb   $0x0,(%rax)
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *stripquotes(char *s) {
  char *start, *end;
  start = strchr(s, '"');
  if (start)
    ++start;
  else
    start = s;
  end = strrchr(start, '"');
  if (end)
    *(end) = '\0';
  return start;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stripquotes>:
  endbr64
  push   %r12
  mov    $0x22,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    $0x22,%esi
  test   %rax,%rax
  lea    0x1(%rax),%r12
  cmove  %rbx,%r12
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L9
  movb   $0x0,(%rax)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *stripquotes(char *s) {
  char *start, *end;
  start = strchr(s, '"');
  if (start)
    ++start;
  else
    start = s;
  end = strrchr(start, '"');
  if (end)
    *(end) = '\0';
  return start;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stripquotes>:
  endbr64
  push   %r12
  mov    $0x22,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    $0x22,%esi
  test   %rax,%rax
  lea    0x1(%rax),%r12
  cmove  %rbx,%r12
  mov    %r12,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L1
  movb   $0x0,(%rax)
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *stripquotes(char *s) {
  char *start, *end;
  start = strchr(s, '"');
  if (start)
    ++start;
  else
    start = s;
  end = strrchr(start, '"');
  if (end)
    *(end) = '\0';
  return start;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getchar_and_flush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
L9:
  cmpl   $0xa,-0x4(%rbp)
  jne    L6
  movzbl -0x5(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: Please enter some text. Press enter to finish. To quit, type a "%" symbol. 

assistant: ```c
char getchar_and_flush() {
  char foo;
  int loop;
  printf("Please enter some text. Press enter to finish. To quit, type a \"%\" symbol. ");
  foo = getchar();
  loop = foo;
  while (loop != '\n') {
    loop = getchar();
  }
  return foo;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getchar_and_flush>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  je     L4
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L8
L4:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4: Please enter some text. Press enter to finish. To quit, type a "%" symbol. 

assistant: ```c
char getchar_and_flush() {
  char foo;
  int loop;
  printf("Please enter some text. Press enter to finish. To quit, type a \"%\" symbol. ");
  foo = getchar();
  loop = foo;
  while (loop != '\n') {
    loop = getchar();
  }
  return foo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getchar_and_flush>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0xa,%al
  je     L13
L19:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L19
L13:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: Please enter some text. Press enter to finish. To quit, type a "%" symbol. 

assistant: ```c
char getchar_and_flush() {
  char foo;
  int loop;
  printf("Please enter some text. Press enter to finish. To quit, type a \"%\" symbol. ");
  foo = getchar();
  loop = foo;
  while (loop != '\n') {
    loop = getchar();
  }
  return foo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getchar_and_flush>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0xa,%al
  je     L17
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L18
L17:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: Please enter some text. Press enter to finish. To quit, type a "%" symbol. 

assistant: ```c
char getchar_and_flush() {
  char foo;
  int loop;
  printf("Please enter some text. Press enter to finish. To quit, type a \"%\" symbol. ");
  foo = getchar();
  loop = foo;
  while (loop != '\n') {
    loop = getchar();
  }
  return foo;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
  cmpq   $0x0,-0x10(%rbp)
  je     L7
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
L7:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D5: comm: 

tool: D14: 


assistant: ```c
error(s, f) char *s, *f;
{
  std_err("comm: ");
  std_err(s);
  if (f)
    std_err(f);
  std_err("\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
  test   %rbx,%rbx
  je     L5
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
L5:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <std_err@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
data_type: string
name: retrieve_data
arguments: data_tag: D15
data_type: string

tool: D17: comm: 

tool: D15: 


assistant: ```c
error(s, f) char *s, *f;
{
  std_err("comm: ");
  std_err(s);
  if (f)
    std_err(f);
  std_err("\n");
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    D15(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <std_err@plt>
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <std_err@plt>
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <std_err@plt>
L3:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <std_err@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D15: comm: 

tool: D6: 


assistant: ```c
error(s, f) char *s, *f;
{
  std_err("comm: ");
  std_err(s);
  if (f)
    std_err(f);
  std_err("\n");
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<error>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  lea    D7(%rip),%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <std_err@plt>
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <std_err@plt>
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <std_err@plt>
L3:
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <std_err@plt>
  mov    $0x1,%edi
  call   <exit@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string

tool: D7: comm: 

tool: D1: 


assistant: ```c
error(s, f) char *s, *f;
{
  std_err("comm: ");
  std_err(s);
  if (f)
    std_err(f);
  std_err("\n");
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<count_ns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L5
L1:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6e,%al
  jne    L12
  addl   $0x1,-0xc(%rbp)
L12:
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L1
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int count_ns(char *sequence) {
  int n;
  int sequence_length;
  int i;
  n = 0;
  sequence_length = strlen(sequence);
  for (i = 0; i < sequence_length; i++) {
    if (sequence[i] == 110) {
      n++;
    }
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count_ns>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L7
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L9:
  cmpb   $0x6e,(%rdx)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L9
L28:
  pop    %rbx
  ret
L7:
  mov    $0x0,%eax
  jmp    L28
```

assistant: ```c
int count_ns(char *sequence) {
  int n;
  int sequence_length;
  int i;
  n = 0;
  sequence_length = strlen(sequence);
  for (i = 0; i < sequence_length; i++) {
    if (sequence[i] == 110) {
      n++;
    }
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_ns>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L1
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L10:
  xor    %edx,%edx
  cmpb   $0x6e,(%rdi)
  sete   %dl
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L10
  pop    %rbx
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int count_ns(char *sequence) {
  int n;
  int sequence_length;
  int i;
  n = 0;
  sequence_length = strlen(sequence);
  for (i = 0; i < sequence_length; i++) {
    if (sequence[i] == 110) {
      n++;
    }
  }
  return n;
}
```
user: What is the c source code of the assembly code below?

```asm
<encode_base64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x2c(%rbp)
  mov    $0x0,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L54
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BIO_set_flags@plt>
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L16
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  cmp    %eax,-0x2c(%rbp)
  jne    L95
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  jne    L50
  lea    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L11
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L1
L54:
  nop
  jmp    L1
L16:
  nop
  jmp    L1
L95:
  nop
  jmp    L1
L50:
  nop
  jmp    L1
L11:
  nop
L1:
  cmpq   $0x0,-0x20(%rbp)
  je     L66
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free_all@plt>
L66:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
char *encode_base64(char *s) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  char *res = NULL;
  int len = strlen(s);
  if (!(b64 = BIO_new(BIO_f_base64())))
    goto done;
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  if (!(bmem = BIO_new(BIO_s_mem())))
    goto done;
  b64 = BIO_push(b64, bmem);
  if (BIO_write(b64, s, len) != len)
    goto done;
  if (BIO_flush(b64) != 1)
    goto done;
  BIO_get_mem_ptr(b64, &bptr);
  if (!(res = malloc(bptr->length + 1)))
    goto done;
  memcpy(res, bptr->data, bptr->length);
  res[bptr->length] = '\0';
done:
  if (b64)
    BIO_free_all(b64);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_base64>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    $0x0,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L28
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <BIO_set_flags@plt>
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L24
  mov    %rbx,%rdi
  call   <BIO_push@plt>
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    $0x0,%ebx
  cmp    %r13d,%eax
  jne    L51
  mov    %rbp,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  jne    L51
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    (%rsp),%rax
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L51
  mov    (%rsp),%rax
  mov    0x4(%rax),%esi
  mov    (%rax),%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rax
  movslq (%rax),%rax
  movb   $0x0,(%rbx,%rax,1)
L51:
  test   %rbp,%rbp
  je     L28
L30:
  mov    %rbp,%rdi
  call   <BIO_free_all@plt>
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    %rbx,%rbp
  mov    %rax,%rbx
  jmp    L30
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *encode_base64(char *s) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  char *res = NULL;
  int len = strlen(s);
  if (!(b64 = BIO_new(BIO_f_base64())))
    goto done;
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  if (!(bmem = BIO_new(BIO_s_mem())))
    goto done;
  b64 = BIO_push(b64, bmem);
  if (BIO_write(b64, s, len) != len)
    goto done;
  if (BIO_flush(b64) != 1)
    goto done;
  BIO_get_mem_ptr(b64, &bptr);
  if (!(res = malloc(bptr->length + 1)))
    goto done;
  memcpy(res, bptr->data, bptr->length);
  res[bptr->length] = '\0';
done:
  if (b64)
    BIO_free_all(b64);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encode_base64>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L59
  mov    D4(%rip),%rax
  mov    %r12,%rdi
  mov    (%rax),%esi
  call   <BIO_set_flags@plt>
  xor    %eax,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  je     L93
  mov    %r12,%rdi
  call   <BIO_push@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <BIO_write@plt>
  cmp    %ebx,%eax
  jne    L66
  mov    %r13,%rdi
  call   <BIO_flush@plt>
  cmp    $0x1,%eax
  jne    L66
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <BIO_get_mem_ptr@plt>
  mov    (%rsp),%rax
  mov    (%rax),%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L70
  mov    (%rsp),%rax
  mov    %r12,%rdi
  mov    0x4(%rax),%esi
  mov    (%rax),%edx
  call   <memcpy@plt>
  mov    (%rsp),%rax
  movslq (%rax),%rax
  movb   $0x0,(%r12,%rax,1)
  test   %r13,%r13
  je     L59
  nopl   (%rax)
L19:
  mov    %r13,%rdi
  call   <BIO_free_all@plt>
L59:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L66:
  xor    %r12d,%r12d
L70:
  test   %r13,%r13
  jne    L19
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %r12,%r13
  xor    %r12d,%r12d
  jmp    L19
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *encode_base64(char *s) {
  BIO *bmem, *b64;
  BUF_MEM *bptr;
  char *res = NULL;
  int len = strlen(s);
  if (!(b64 = BIO_new(BIO_f_base64())))
    goto done;
  BIO_set_flags(b64, BIO_FLAGS_BASE64_NO_NL);
  if (!(bmem = BIO_new(BIO_s_mem())))
    goto done;
  b64 = BIO_push(b64, bmem);
  if (BIO_write(b64, s, len) != len)
    goto done;
  if (BIO_flush(b64) != 1)
    goto done;
  BIO_get_mem_ptr(b64, &bptr);
  if (!(res = malloc(bptr->length + 1)))
    goto done;
  memcpy(res, bptr->data, bptr->length);
  res[bptr->length] = '\0';
done:
  if (b64)
    BIO_free_all(b64);
  return res;
}
```