ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L6:
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L46
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L24:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L6
  jmp    L47
L46:
  nop
L47:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D79
type: string
name: disassemble_data
arguments: label: D58
type: string
name: disassemble_data
arguments: label: D8
type: string
name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D40
type: string
name: disassemble_data
arguments: label: D20
type: string
name: disassemble_data
arguments: label: D36
type: string

tool: D79: Enter the length of the rectangle: 

tool: D58: Length = %0.2f: 


tool: D8: Enter its width: 

tool: D3: %f

tool: D40: Width = %0.2f: 


tool: D20: Area = %0.2f: 


tool: D36: Done.

assistant: ```c
int main(int argc, char const *argv[]) {
  float length, width;
  printf("Enter the length of the rectangle: \n");
  while (scanf("%f", &length) == 1) {
    printf("Length = %0.2f: \n", length);
    printf("Enter its width: \n");
    if (scanf("%f", &width) != 1) {
      break;
    }
    printf("Width = %0.2f: \n", width);
    printf("Area = %0.2f: \n", length * width);
    printf("Enter the length of the rectangle: \n");
  }
  printf("Done.\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D65(%rip),%rbx
  lea    D42(%rip),%r12
  lea    D39(%rip),%rbp
  lea    D21(%rip),%r13
  jmp    L36
L17:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  mov    %r13,%rdi
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D7(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
L36:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L13
  pxor   %xmm0,%xmm0
  cvtss2sd (%rsp),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L17
L13:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type_guessed: string
name: extract_symbolic_data
arguments: label: D65
type_guessed: string
name: extract_symbolic_data
arguments: label: D42
type_guessed: string
name: extract_symbolic_data
arguments: label: D39
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: string

tool: D27: Enter the length of the rectangle: 

tool: D65: %f

tool: D42: Length = %0.2f: 


tool: D39: Enter its width: 

tool: D21: Width = %0.2f: 


tool: D7: Area = %0.2f: 


tool: D46: Done.

assistant: ```c
int main(int argc, char const *argv[]) {
  float length, width;
  printf("Enter the length of the rectangle: \n");
  while (scanf("%f", &length) == 1) {
    printf("Length = %0.2f: \n", length);
    printf("Enter its width: \n");
    if (scanf("%f", &width) != 1) {
      break;
    }
    printf("Width = %0.2f: \n", width);
    printf("Area = %0.2f: \n", length * width);
    printf("Enter the length of the rectangle: \n");
  }
  printf("Done.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  lea    D53(%rip),%r15
  push   %r14
  lea    D0(%rip),%r14
  push   %r13
  lea    D13(%rip),%r13
  push   %r12
  lea    D50(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  lea    D21(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %r14,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd (%rsp),%xmm0
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L16
  mov    %r15,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x4(%rsp),%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D59(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
L18:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L34
L16:
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D53
data_type: string
name: unpack_data
arguments: label: D0
data_type: string
name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D50
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D59
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: D53: Width = %0.2f: 


tool: D0: Length = %0.2f: 


tool: D13: Enter its width: 

tool: D50: Enter the length of the rectangle: 

tool: D21: %f

tool: D59: Area = %0.2f: 


tool: D20: Done.

assistant: ```c
int main(int argc, char const *argv[]) {
  float length, width;
  printf("Enter the length of the rectangle: \n");
  while (scanf("%f", &length) == 1) {
    printf("Length = %0.2f: \n", length);
    printf("Enter its width: \n");
    if (scanf("%f", &width) != 1) {
      break;
    }
    printf("Width = %0.2f: \n", width);
    printf("Area = %0.2f: \n", length * width);
    printf("Enter the length of the rectangle: \n");
  }
  printf("Done.\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D36(%rip),%r13
  push   %r12
  lea    D61(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  lea    D40(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <puts@plt>
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r14,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd (%rsp),%xmm0
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  jne    L34
  mov    %r15,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd 0x4(%rsp),%xmm0
  call   <printf@plt>
  movss  (%rsp),%xmm0
  mulss  0x4(%rsp),%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
L16:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L39
L34:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D29
type_infered: string
name: retrieve_data
arguments: tag: D36
type_infered: string
name: retrieve_data
arguments: tag: D61
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D43
type_infered: string

tool: D4: Width = %0.2f: 


tool: D29: Length = %0.2f: 


tool: D36: Enter its width: 

tool: D61: Enter the length of the rectangle: 

tool: D40: %f

tool: D13: Area = %0.2f: 


tool: D43: Done.

assistant: ```c
int main(int argc, char const *argv[]) {
  float length, width;
  printf("Enter the length of the rectangle: \n");
  while (scanf("%f", &length) == 1) {
    printf("Length = %0.2f: \n", length);
    printf("Enter its width: \n");
    if (scanf("%f", &width) != 1) {
      break;
    }
    printf("Width = %0.2f: \n", width);
    printf("Area = %0.2f: \n", length * width);
    printf("Enter the length of the rectangle: \n");
  }
  printf("Done.\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d2_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L16
  negl   -0x24(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
L16:
  mov    -0x24(%rbp),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%r10
  mov    %eax,%edi
  call   <i2a.0>
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void d2_itoa(int i, unsigned char *s) {
  if (i < 0) {
    i = -i;
    *s++ = '-';
  };
  void i2a(unsigned int i) {
    if (i / 10) {
      i2a(i / 10);
      *s = i % 10 + '0';
    } else
      *s = i % 10 + '0';
    s++;
  }
  i2a(i);
  *s = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<d2_itoa>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  test   %edi,%edi
  js     L3
  mov    %rsi,(%rsp)
L21:
  mov    %rsp,%r10
  call   <i2a.0>
  mov    (%rsp),%rax
  movb   $0x0,(%rax)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  ret
L3:
  neg    %edi
  lea    0x1(%rsi),%rax
  mov    %rax,(%rsp)
  movb   $0x2d,(%rsi)
  jmp    L21
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void d2_itoa(int i, unsigned char *s) {
  if (i < 0) {
    i = -i;
    *s++ = '-';
  };
  void i2a(unsigned int i) {
    if (i / 10) {
      i2a(i / 10);
      *s = i % 10 + '0';
    } else
      *s = i % 10 + '0';
    s++;
  }
  i2a(i);
  *s = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<d2_itoa>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  test   %edi,%edi
  js     L31
  mov    %rsi,(%rsp)
  cmp    $0x9,%ecx
  jg     L15
L38:
  mov    (%rsp),%rax
  add    $0x30,%ecx
  mov    %cl,(%rax)
L30:
  mov    (%rsp),%rax
  movb   $0x0,0x1(%rax)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L31:
  lea    0x1(%rsi),%rax
  neg    %ecx
  movb   $0x2d,(%rsi)
  mov    %rax,(%rsp)
  cmp    $0x9,%ecx
  jle    L38
L15:
  mov    %ecx,%esi
  mov    $0xcccccccd,%eax
  mov    %rsi,%r8
  imul   %rax,%r8
  shr    $0x23,%r8
  cmp    $0x63,%ecx
  jg     L59
  mov    (%rsp),%rax
  add    $0x30,%r8d
  mov    %r8b,(%rax)
L71:
  mov    (%rsp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rsp)
  mov    $0xcccccccd,%eax
  imul   %rax,%rsi
  shr    $0x23,%rsi
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  add    $0x30,%ecx
  mov    %cl,0x1(%rdx)
  jmp    L30
  nop
L59:
  mov    %r8d,%r9d
  mov    %r9,%r11
  imul   %rax,%r11
  shr    $0x23,%r11
  cmp    $0x3e7,%ecx
  ja     L76
  mov    (%rsp),%rax
  add    $0x30,%r11d
  mov    %r11b,(%rax)
L81:
  mov    (%rsp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rsp)
  mov    $0xcccccccd,%eax
  imul   %rax,%r9
  shr    $0x23,%r9
  lea    (%r9,%r9,4),%eax
  add    %eax,%eax
  sub    %eax,%r8d
  add    $0x30,%r8d
  mov    %r8b,0x1(%rdx)
  jmp    L71
  nopl   (%rax)
L76:
  mov    %r11d,%ebx
  mov    %rsp,%r10
  imul   %rax,%rbx
  shr    $0x23,%rbx
  mov    %ebx,%edi
  call   <i2a.0>
  lea    (%rbx,%rbx,4),%eax
  add    %eax,%eax
  sub    %eax,%r11d
  mov    (%rsp),%rax
  add    $0x30,%r11d
  mov    %r11b,(%rax)
  jmp    L81
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void d2_itoa(int i, unsigned char *s) {
  if (i < 0) {
    i = -i;
    *s++ = '-';
  };
  void i2a(unsigned int i) {
    if (i / 10) {
      i2a(i / 10);
      *s = i % 10 + '0';
    } else
      *s = i % 10 + '0';
    s++;
  }
  i2a(i);
  *s = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<d2_itoa>:
  endbr64
  push   %rbx
  mov    %edi,%ecx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  test   %edi,%edi
  js     L79
  mov    %rsi,(%rsp)
  cmp    $0x9,%ecx
  jg     L73
L5:
  add    $0x30,%ecx
  mov    %cl,(%rsi)
L70:
  mov    (%rsp),%rax
  movb   $0x0,0x1(%rax)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L79:
  lea    0x1(%rsi),%rax
  neg    %ecx
  movb   $0x2d,(%rsi)
  mov    %rax,(%rsp)
  mov    %rax,%rsi
  cmp    $0x9,%ecx
  jle    L5
L73:
  mov    %ecx,%r8d
  mov    $0xcccccccd,%eax
  mov    %r8,%r9
  imul   %rax,%r9
  shr    $0x23,%r9
  cmp    $0x63,%ecx
  jg     L72
  add    $0x30,%r9d
  mov    %r9b,(%rsi)
L33:
  mov    (%rsp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rsp)
  mov    $0xcccccccd,%eax
  imul   %rax,%r8
  shr    $0x23,%r8
  lea    (%r8,%r8,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  add    $0x30,%ecx
  mov    %cl,0x1(%rdx)
  jmp    L70
L72:
  mov    %r9d,%r11d
  mov    %r11,%rbx
  imul   %rax,%rbx
  shr    $0x23,%rbx
  cmp    $0x3e7,%ecx
  ja     L65
  add    $0x30,%ebx
  mov    %bl,(%rsi)
L21:
  mov    (%rsp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,(%rsp)
  mov    $0xcccccccd,%eax
  imul   %rax,%r11
  shr    $0x23,%r11
  lea    (%r11,%r11,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  add    $0x30,%r9d
  mov    %r9b,0x1(%rdx)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %ebx,%esi
  mov    %rsp,%r10
  imul   %rax,%rsi
  shr    $0x23,%rsi
  mov    %esi,%edi
  call   <i2a.0>
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    (%rsp),%rax
  add    $0x30,%ebx
  mov    %bl,(%rax)
  jmp    L21
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void d2_itoa(int i, unsigned char *s) {
  if (i < 0) {
    i = -i;
    *s++ = '-';
  };
  void i2a(unsigned int i) {
    if (i / 10) {
      i2a(i / 10);
      *s = i % 10 + '0';
    } else
      *s = i % 10 + '0';
    s++;
  }
  i2a(i);
  *s = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rdx
  mov    %esi,%eax
  mov    %rdx,%rbx
  jmp    L51
L12:
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  sub    $0x40,%eax
L51:
  cmp    $0x3f,%eax
  ja     L12
  jmp    L9
L38:
  mov    %rbx,%rdx
  lea    0x8(%rdx),%rbx
  movq   $0x0,(%rdx)
  sub    $0x8,%eax
L9:
  cmp    $0x7,%eax
  ja     L38
  mov    %rbx,%rdx
  jmp    L28
L17:
  mov    %rdx,%rcx
  lea    0x1(%rcx),%rdx
  movb   $0x0,(%rcx)
L28:
  mov    %eax,%ecx
  lea    -0x1(%rcx),%eax
  test   %ecx,%ecx
  jne    L17
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void clear(ptr, n) register char *ptr;
register unsigned int n;
{
  register long *q = (long *)ptr;
  while (n >= 8 * sizeof(long)) {
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    n -= 8 * sizeof(long);
  }
  while (n >= sizeof(long)) {
    *q++ = 0;
    n -= sizeof(long);
  }
  ptr = (char *)q;
  while (n--)
    *ptr++ = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clear>:
  endbr64
  cmp    $0x3f,%esi
  jbe    L63
  lea    -0x40(%rsi),%eax
  shr    $0x6,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x6,%rax
  add    %rdi,%rax
L3:
  movq   $0x0,(%rdi)
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x20(%rdi)
  movq   $0x0,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  add    $0x40,%rdi
  movq   $0x0,-0x8(%rdi)
  cmp    %rdi,%rax
  jne    L3
  and    $0x3f,%esi
L63:
  cmp    $0x7,%esi
  jbe    L7
  lea    -0x8(%rsi),%eax
  shr    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    (%rdi,%rax,8),%rax
L33:
  add    $0x8,%rdi
  movq   $0x0,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L33
  and    $0x7,%esi
L41:
  lea    -0x1(%rsi),%edx
  test   %esi,%esi
  je     L42
  mov    %edx,%edx
  lea    0x1(%rax,%rdx,1),%rdx
L46:
  add    $0x1,%rax
  movb   $0x0,-0x1(%rax)
  cmp    %rdx,%rax
  jne    L46
L42:
  ret
L7:
  mov    %rdi,%rax
  jmp    L41
```

assistant: ```c
void clear(ptr, n) register char *ptr;
register unsigned int n;
{
  register long *q = (long *)ptr;
  while (n >= 8 * sizeof(long)) {
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    n -= 8 * sizeof(long);
  }
  while (n >= sizeof(long)) {
    *q++ = 0;
    n -= sizeof(long);
  }
  ptr = (char *)q;
  while (n--)
    *ptr++ = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clear>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%ecx
  cmp    $0x3f,%esi
  jbe    L1
  lea    -0x40(%rsi),%edx
  shr    $0x6,%edx
  add    $0x1,%edx
  shl    $0x6,%rdx
  add    %rdi,%rdx
  xchg   %ax,%ax
L65:
  movq   $0x0,(%rax)
  add    $0x40,%rax
  movq   $0x0,-0x38(%rax)
  movq   $0x0,-0x30(%rax)
  movq   $0x0,-0x28(%rax)
  movq   $0x0,-0x20(%rax)
  movq   $0x0,-0x18(%rax)
  movq   $0x0,-0x10(%rax)
  movq   $0x0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L65
  and    $0x3f,%ecx
L1:
  cmp    $0x7,%ecx
  jbe    L32
  lea    -0x8(%rcx),%edx
  lea    0x8(%rax),%r8
  movq   $0x0,(%rax)
  xor    %r10d,%r10d
  shr    $0x3,%edx
  and    $0xfffffffffffffff8,%r8
  add    $0x1,%edx
  shl    $0x3,%rdx
  mov    %edx,%esi
  movq   $0x0,-0x8(%rax,%rsi,1)
  mov    %rax,%rsi
  sub    %r8,%rsi
  add    %edx,%esi
  and    $0xfffffff8,%esi
  cmp    $0x8,%esi
  jb     L40
  mov    %esi,%edi
  xor    %esi,%esi
  and    $0xfffffff8,%edi
L43:
  mov    %esi,%r9d
  add    $0x8,%esi
  mov    %r10,(%r8,%r9,1)
  cmp    %edi,%esi
  jb     L43
L40:
  and    $0x7,%ecx
  add    %rdx,%rax
L32:
  test   %ecx,%ecx
  je     L8
  xor    %edx,%edx
L41:
  mov    %edx,%esi
  add    $0x1,%edx
  movb   $0x0,(%rax,%rsi,1)
  cmp    %ecx,%edx
  jb     L41
L8:
  ret
```

assistant: ```c
void clear(ptr, n) register char *ptr;
register unsigned int n;
{
  register long *q = (long *)ptr;
  while (n >= 8 * sizeof(long)) {
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    n -= 8 * sizeof(long);
  }
  while (n >= sizeof(long)) {
    *q++ = 0;
    n -= sizeof(long);
  }
  ptr = (char *)q;
  while (n--)
    *ptr++ = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<clear>:
  endbr64
  cmp    $0x3f,%esi
  jbe    L61
  lea    -0x40(%rsi),%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  shr    $0x6,%ecx
  add    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%edx
  movups %xmm0,(%rax)
  add    $0x40,%rax
  movups %xmm0,-0x30(%rax)
  movups %xmm0,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %edx,%ecx
  ja     L3
  shl    $0x6,%rcx
  and    $0x3f,%esi
  add    %rcx,%rdi
L61:
  cmp    $0x7,%esi
  jbe    L1
  lea    -0x8(%rsi),%eax
  lea    0x8(%rdi),%r8
  movq   $0x0,(%rdi)
  xor    %r10d,%r10d
  shr    $0x3,%eax
  and    $0xfffffffffffffff8,%r8
  add    $0x1,%eax
  shl    $0x3,%rax
  mov    %eax,%edx
  movq   $0x0,-0x8(%rdi,%rdx,1)
  mov    %rdi,%rdx
  sub    %r8,%rdx
  add    %eax,%edx
  and    $0xfffffff8,%edx
  cmp    $0x8,%edx
  jb     L32
  mov    %edx,%ecx
  xor    %edx,%edx
  and    $0xfffffff8,%ecx
L59:
  mov    %edx,%r9d
  add    $0x8,%edx
  mov    %r10,(%r8,%r9,1)
  cmp    %ecx,%edx
  jb     L59
L32:
  and    $0x7,%esi
  add    %rax,%rdi
L1:
  test   %esi,%esi
  je     L27
  xor    %eax,%eax
L11:
  mov    %eax,%edx
  add    $0x1,%eax
  movb   $0x0,(%rdi,%rdx,1)
  cmp    %esi,%eax
  jb     L11
L27:
  ret
```

assistant: ```c
void clear(ptr, n) register char *ptr;
register unsigned int n;
{
  register long *q = (long *)ptr;
  while (n >= 8 * sizeof(long)) {
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    *q++ = 0;
    n -= 8 * sizeof(long);
  }
  while (n >= sizeof(long)) {
    *q++ = 0;
    n -= sizeof(long);
  }
  ptr = (char *)q;
  while (n--)
    *ptr++ = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<duasStrings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x114(%rbp)
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <_strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x118(%rbp)
  jmp    L35
L24:
  mov    -0x114(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x118(%rbp),%eax
  cltq
  mov    %dl,-0x110(%rbp,%rax,1)
  subl   $0x1,-0x118(%rbp)
  addl   $0x1,-0x114(%rbp)
L35:
  cmpl   $0x0,-0x118(%rbp)
  js     L26
  mov    -0x114(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
L26:
  mov    -0x114(%rbp),%eax
  cltq
  movb   $0x0,-0x110(%rbp,%rax,1)
  mov    -0x128(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string
name: disassemble_data
arguments: data_tag: D5
datatype: string

tool: D4: 

A string normal: %s


tool: D5: String de tras para frente: %s



assistant: ```c
void duasStrings(char s[]) {
  char aux[255];
  int i, j = 0;
  i = _strlen(s) - 1;
  while ((i >= 0) && (s[j] != '\0')) {
    aux[i] = s[j];
    --i;
    j++;
  }
  aux[j] = '\0';
  printf("\n\nA string normal: %s\n", s);
  printf("String de tras para frente: %s\n\n", aux);
}
```