ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<eigsrt>:
  endbr64
  cmp    $0x1,%edx
  jle    L0
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %rdi,%rcx
  mov    $0x1,%r8d
  push   %rbp
  mov    %edx,%edi
  movslq %edx,%rbp
  lea    0x10(%rsi,%rax,8),%r11
  push   %rbx
  mov    $0x2,%r10d
  mov    %rsi,%rbx
L34:
  movss  (%rcx,%r8,4),%xmm2
  movslq %r8d,%rdx
  lea    0x0(,%r8,4),%r9
  cmp    %r10d,%edi
  jl     L48
  mov    %r10,%rax
  movaps %xmm2,%xmm1
  nopl   0x0(%rax)
L41:
  movss  (%rcx,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jb     L28
  movaps %xmm0,%xmm1
  movslq %eax,%rdx
L28:
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L41
  cmp    %r8d,%edx
  jne    L78
L48:
  add    $0x1,%r8
  add    $0x1,%r10
  cmp    %rbp,%r8
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L78:
  movss  %xmm2,(%rcx,%rdx,4)
  lea    0x0(,%rdx,4),%r12
  lea    0x8(%rbx),%rdx
  movss  %xmm1,(%rcx,%r8,4)
  nopw   0x0(%rax,%rax,1)
L60:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  lea    (%rax,%r9,1),%rsi
  add    %r12,%rax
  movss  (%rsi),%xmm0
  movss  (%rax),%xmm1
  movss  %xmm1,(%rsi)
  movss  %xmm0,(%rax)
  cmp    %rdx,%r11
  jne    L60
  jmp    L48
L0:
  ret
```

assistant: ```c
void eigsrt(float d[], float **v, int n) {
  int k, j, i;
  float p;
  for (i = 1; i < n; i++) {
    p = d[k = i];
    for (j = i + 1; j <= n; j++)
      if (d[j] >= p)
        p = d[k = j];
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 1; j <= n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<eigsrt>:
  endbr64
  cmp    $0x1,%edx
  jle    L31
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %rdi,%rcx
  mov    $0x1,%r8d
  push   %rbp
  mov    %edx,%edi
  movslq %edx,%rbp
  lea    0x10(%rsi,%rax,8),%r11
  push   %rbx
  mov    $0x2,%r10d
  mov    %rsi,%rbx
L11:
  movss  (%rcx,%r8,4),%xmm2
  movslq %r8d,%rdx
  lea    0x0(,%r8,4),%r9
  cmp    %r10d,%edi
  jl     L76
  mov    %r10,%rax
  movaps %xmm2,%xmm1
  nopl   0x0(%rax)
L62:
  movss  (%rcx,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jb     L18
  movaps %xmm0,%xmm1
  movslq %eax,%rdx
L18:
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L62
  cmp    %r8d,%edx
  jne    L55
L76:
  add    $0x1,%r8
  add    $0x1,%r10
  cmp    %r8,%rbp
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L55:
  movss  %xmm2,(%rcx,%rdx,4)
  lea    0x0(,%rdx,4),%r12
  lea    0x8(%rbx),%rdx
  movss  %xmm1,(%rcx,%r8,4)
  nopw   0x0(%rax,%rax,1)
L46:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  lea    (%rax,%r9,1),%rsi
  add    %r12,%rax
  movss  (%rsi),%xmm0
  movss  (%rax),%xmm1
  movss  %xmm1,(%rsi)
  movss  %xmm0,(%rax)
  cmp    %r11,%rdx
  jne    L46
  jmp    L76
L31:
  ret
```

assistant: ```c
void eigsrt(float d[], float **v, int n) {
  int k, j, i;
  float p;
  for (i = 1; i < n; i++) {
    p = d[k = i];
    for (j = i + 1; j <= n; j++)
      if (d[j] >= p)
        p = d[k = j];
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 1; j <= n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  checkf(0, 0);
  checkf(0, 1);
  checkf(1, 1);
  checkf(1, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  checkf(0, 0);
  checkf(0, 1);
  checkf(1, 1);
  checkf(1, 0);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  checkf(0, 0);
  checkf(0, 1);
  checkf(1, 1);
  checkf(1, 0);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <checkf@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <checkf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  checkf(0, 0);
  checkf(0, 1);
  checkf(1, 1);
  checkf(1, 0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_dl_cache_libcmp>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%r9
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L132
L104:
  movsbl (%r9),%eax
  neg    %eax
  ret
L119:
  movzbl (%r9),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  ja     L15
  lea    0x1(%r8),%rdi
  movsbl %al,%eax
  sub    $0x30,%eax
  lea    0x1(%r9),%rsi
  movsbl %cl,%ecx
  sub    $0x30,%ecx
  movzbl 0x1(%r8),%edx
  lea    -0x30(%rdx),%r8d
  cmp    $0x9,%r8b
  ja     L0
L17:
  add    $0x1,%rdi
  lea    (%rax,%rax,4),%eax
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rax,2),%eax
  movzbl (%rdi),%edx
  lea    -0x30(%rdx),%r8d
  cmp    $0x9,%r8b
  jbe    L17
  mov    %rdi,%r8
L46:
  movzbl 0x1(%r9),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  ja     L41
L117:
  add    $0x1,%rsi
  lea    (%rcx,%rcx,4),%ecx
  movsbl %dl,%edx
  lea    -0x30(%rdx,%rcx,2),%ecx
  movzbl (%rsi),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L117
  mov    %rsi,%r9
L51:
  cmp    %ecx,%eax
  jne    L126
L26:
  movzbl (%r8),%eax
  test   %al,%al
  je     L104
L132:
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L119
  movzbl (%r9),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L134
  cmp    %al,%dl
  jne    L20
  add    $0x1,%r8
  add    $0x1,%r9
  jmp    L26
L0:
  mov    %rdi,%r8
  jmp    L46
L41:
  mov    %rsi,%r9
  jmp    L51
L126:
  sub    %ecx,%eax
  ret
L20:
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  ret
L15:
  mov    $0x1,%eax
  ret
L134:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _dl_cache_libcmp(const char *p1, const char *p2) {
  while (*p1 != '\0') {
    if (*p1 >= '0' && *p1 <= '9') {
      if (*p2 >= '0' && *p2 <= '9') {
        int val1;
        int val2;
        val1 = *p1++ - '0';
        val2 = *p2++ - '0';
        while (*p1 >= '0' && *p1 <= '9')
          val1 = val1 * 10 + *p1++ - '0';
        while (*p2 >= '0' && *p2 <= '9')
          val2 = val2 * 10 + *p2++ - '0';
        if (val1 != val2)
          return val1 - val2;
      } else
        return 1;
    } else if (*p2 >= '0' && *p2 <= '9')
      return -1;
    else if (*p1 != *p2)
      return *p1 - *p2;
    else {
      ++p1;
      ++p2;
    }
  }
  return *p1 - *p2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_dl_cache_libcmp>:
  endbr64
  mov    %rsi,%rcx
L87:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L108
L14:
  movsbl (%rcx),%r8d
  lea    -0x30(%rdx),%eax
  lea    -0x30(%r8),%esi
  cmp    $0x9,%al
  jbe    L86
  cmp    $0x9,%sil
  jbe    L53
  cmp    %r8b,%dl
  jne    L10
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L14
L108:
  movsbl (%rcx),%eax
  neg    %eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L86:
  cmp    $0x9,%sil
  ja     L73
  movsbl 0x1(%rdi),%edx
  lea    0x1(%rdi),%r8
  movsbl %al,%eax
  lea    0x1(%rcx),%r9
  movsbl %sil,%esi
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  mov    %r8,%rdi
  ja     L46
  nopl   (%rax)
L49:
  add    $0x1,%rdi
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl (%rdi),%edx
  lea    -0x30(%rdx),%r8d
  cmp    $0x9,%r8b
  jbe    L49
L46:
  movsbl 0x1(%rcx),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  mov    %r9,%rcx
  ja     L83
  nop
L55:
  add    $0x1,%rcx
  lea    (%rsi,%rsi,4),%esi
  lea    -0x30(%rdx,%rsi,2),%esi
  movsbl (%rcx),%edx
  lea    -0x30(%rdx),%r8d
  cmp    $0x9,%r8b
  jbe    L55
L83:
  cmp    %eax,%esi
  je     L87
  sub    %esi,%eax
  ret
L53:
  mov    $0xffffffff,%eax
  ret
L10:
  movsbl %dl,%eax
  sub    %r8d,%eax
  ret
L73:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int _dl_cache_libcmp(const char *p1, const char *p2) {
  while (*p1 != '\0') {
    if (*p1 >= '0' && *p1 <= '9') {
      if (*p2 >= '0' && *p2 <= '9') {
        int val1;
        int val2;
        val1 = *p1++ - '0';
        val2 = *p2++ - '0';
        while (*p1 >= '0' && *p1 <= '9')
          val1 = val1 * 10 + *p1++ - '0';
        while (*p2 >= '0' && *p2 <= '9')
          val2 = val2 * 10 + *p2++ - '0';
        if (val1 != val2)
          return val1 - val2;
      } else
        return 1;
    } else if (*p2 >= '0' && *p2 <= '9')
      return -1;
    else if (*p1 != *p2)
      return *p1 - *p2;
    else {
      ++p1;
      ++p2;
    }
  }
  return *p1 - *p2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_dl_cache_libcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  mov    %rdi,%r9
  mov    %rsi,%r8
L97:
  test   %dl,%dl
  je     L72
L63:
  lea    -0x30(%rdx),%eax
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%al
  jbe    L25
  cmp    $0x9,%sil
  jbe    L12
  cmp    %cl,%dl
  jne    L23
  movzbl 0x1(%r9),%edx
  movsbl 0x1(%r8),%ecx
  add    $0x1,%r9
  add    $0x1,%r8
  test   %dl,%dl
  jne    L63
L72:
  movsbl %cl,%eax
  neg    %eax
  ret
  nopl   0x0(%rax)
L25:
  cmp    $0x9,%sil
  ja     L75
  movsbl 0x1(%r9),%edx
  lea    0x1(%r9),%rdi
  movsbl %al,%eax
  lea    0x1(%r8),%r10
  movsbl %sil,%esi
  mov    %rdi,%r9
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L66
  nopl   (%rax)
L64:
  add    $0x1,%r9
  lea    (%rax,%rax,4),%eax
  lea    -0x30(%rdx,%rax,2),%eax
  movsbl (%r9),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L64
L66:
  movsbl 0x1(%r8),%ecx
  mov    %r10,%r8
  lea    -0x30(%rcx),%edi
  cmp    $0x9,%dil
  ja     L43
L106:
  add    $0x1,%r8
  lea    (%rsi,%rsi,4),%esi
  lea    -0x30(%rcx,%rsi,2),%esi
  movsbl (%r8),%ecx
  lea    -0x30(%rcx),%edi
  cmp    $0x9,%dil
  jbe    L106
L43:
  cmp    %eax,%esi
  je     L97
  sub    %esi,%eax
  ret
L12:
  mov    $0xffffffff,%eax
  ret
L23:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
L75:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int _dl_cache_libcmp(const char *p1, const char *p2) {
  while (*p1 != '\0') {
    if (*p1 >= '0' && *p1 <= '9') {
      if (*p2 >= '0' && *p2 <= '9') {
        int val1;
        int val2;
        val1 = *p1++ - '0';
        val2 = *p2++ - '0';
        while (*p1 >= '0' && *p1 <= '9')
          val1 = val1 * 10 + *p1++ - '0';
        while (*p2 >= '0' && *p2 <= '9')
          val2 = val2 * 10 + *p2++ - '0';
        if (val1 != val2)
          return val1 - val2;
      } else
        return 1;
    } else if (*p2 >= '0' && *p2 <= '9')
      return -1;
    else if (*p1 != *p2)
      return *p1 - *p2;
    else {
      ++p1;
      ++p2;
    }
  }
  return *p1 - *p2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D11(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x989680,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  jmp    L30
  endbr64
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  nop
L30:
  jmp    *%rax
  endbr64
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  jmp    L30
  endbr64
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  jmp    L30
  endbr64
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  jmp    L30
  endbr64
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  jmp    L30
  endbr64
  cmpl   $0x0,-0xc(%rbp)
  jle    L10
  subl   $0x1,-0xc(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    (%rax),%rax
  jmp    L30
L10:
  mov    $0x0,%edi
  call   <exit@plt>
```

assistant: ```c
main() {
  static void *cf[] = {&&next1, &&next2, &&next3, &&next4, &&next5, &&loop};
  static void **prog[] = {cf, cf + 1, cf, cf + 2, cf, cf + 3, cf, cf + 4, cf, cf + 5};
  void ***ip = prog;
  int count = 10000000;
  goto ***ip++;
next1:
  asm("#"
      "1");
  goto ***ip++;
next2:
  asm("#"
      "2");
  goto ***ip++;
next3:
  asm("#"
      "3");
  goto ***ip++;
next4:
  asm("#"
      "4");
  goto ***ip++;
next5:
  asm("#"
      "5");
  goto ***ip++;
loop:
  if (count > 0) {
    count--;
    ip = prog;
    goto ***ip++;
  }
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D29(%rip),%rax
  mov    (%rax),%rdx
  mov    $0x989680,%ecx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  jmp    L53
  endbr64
  mov    (%rax),%rdx
  mov    (%rdx),%rdx
  lea    0x8(%rax),%rax
L53:
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  mov    (%rdx),%rdx
  lea    0x8(%rax),%rax
  jmp    L53
  endbr64
  mov    (%rax),%rdx
  mov    (%rdx),%rdx
  lea    0x8(%rax),%rax
  jmp    L53
  endbr64
  mov    (%rax),%rdx
  mov    (%rdx),%rdx
  lea    0x8(%rax),%rax
  jmp    L53
  endbr64
  mov    (%rax),%rdx
  mov    (%rdx),%rdx
  lea    0x8(%rax),%rax
  jmp    L53
  endbr64
  test   %ecx,%ecx
  jle    L43
  sub    $0x1,%ecx
  mov    D29(%rip),%rax
  mov    (%rax),%rdx
  mov    %rsi,%rax
  jmp    L53
L43:
  mov    $0x0,%edi
  call   <exit@plt>
```

assistant: ```c
main() {
  static void *cf[] = {&&next1, &&next2, &&next3, &&next4, &&next5, &&loop};
  static void **prog[] = {cf, cf + 1, cf, cf + 2, cf, cf + 3, cf, cf + 4, cf, cf + 5};
  void ***ip = prog;
  int count = 10000000;
  goto ***ip++;
next1:
  asm("#"
      "1");
  goto ***ip++;
next2:
  asm("#"
      "2");
  goto ***ip++;
next3:
  asm("#"
      "3");
  goto ***ip++;
next4:
  asm("#"
      "4");
  goto ***ip++;
next5:
  asm("#"
      "5");
  goto ***ip++;
loop:
  if (count > 0) {
    count--;
    ip = prog;
    goto ***ip++;
  }
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D17(%rip),%rax
  mov    $0x989680,%ecx
  mov    (%rax),%rdx
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  jmp    *%rdx
  nopl   0x0(%rax,%rax,1)
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  nopl   0x0(%rax,%rax,1)
  endbr64
  test   %ecx,%ecx
  jle    L1
  mov    D17(%rip),%rax
  sub    $0x1,%ecx
  mov    (%rax),%rdx
  mov    %rsi,%rax
  jmp    *%rdx
  nopw   0x0(%rax,%rax,1)
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
L1:
  xor    %edi,%edi
  call   <exit@plt>
```

assistant: ```c
main() {
  static void *cf[] = {&&next1, &&next2, &&next3, &&next4, &&next5, &&loop};
  static void **prog[] = {cf, cf + 1, cf, cf + 2, cf, cf + 3, cf, cf + 4, cf, cf + 5};
  void ***ip = prog;
  int count = 10000000;
  goto ***ip++;
next1:
  asm("#"
      "1");
  goto ***ip++;
next2:
  asm("#"
      "2");
  goto ***ip++;
next3:
  asm("#"
      "3");
  goto ***ip++;
next4:
  asm("#"
      "4");
  goto ***ip++;
next5:
  asm("#"
      "5");
  goto ***ip++;
loop:
  if (count > 0) {
    count--;
    ip = prog;
    goto ***ip++;
  }
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    D20(%rip),%rax
  mov    $0x989680,%ecx
  mov    (%rax),%rdx
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  jmp    *%rdx
  nopl   0x0(%rax,%rax,1)
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  nopl   0x0(%rax,%rax,1)
  endbr64
  test   %ecx,%ecx
  jle    L0
  mov    D20(%rip),%rax
  sub    $0x1,%ecx
  mov    (%rax),%rdx
  mov    %rsi,%rax
  jmp    *%rdx
  nopw   0x0(%rax,%rax,1)
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
  endbr64
  mov    (%rax),%rdx
  add    $0x8,%rax
  mov    (%rdx),%rdx
  jmp    *%rdx
L0:
  xor    %edi,%edi
  call   <exit@plt>
```

assistant: ```c
main() {
  static void *cf[] = {&&next1, &&next2, &&next3, &&next4, &&next5, &&loop};
  static void **prog[] = {cf, cf + 1, cf, cf + 2, cf, cf + 3, cf, cf + 4, cf, cf + 5};
  void ***ip = prog;
  int count = 10000000;
  goto ***ip++;
next1:
  asm("#"
      "1");
  goto ***ip++;
next2:
  asm("#"
      "2");
  goto ***ip++;
next3:
  asm("#"
      "3");
  goto ***ip++;
next4:
  asm("#"
      "4");
  goto ***ip++;
next5:
  asm("#"
      "5");
  goto ***ip++;
loop:
  if (count > 0) {
    count--;
    ip = prog;
    goto ***ip++;
  }
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<count_cr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L3
  addl   $0x1,-0xc(%rbp)
  jmp    L30
L3:
  movl   $0x0,-0x4(%rbp)
L30:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L17
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
L17:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_cr(char source[], int posn, int length) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (source[i] == 13) {
      c++;
    } else {
      cond = 0;
    }
    i++;
  } while ((i < length) && cond);
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<count_cr>:
  endbr64
  movslq %esi,%rsi
  mov    $0x0,%eax
  jmp    L22
L5:
  add    $0x1,%eax
  add    $0x1,%rsi
  cmp    %esi,%edx
  jle    L10
L22:
  cmpb   $0xd,(%rdi,%rsi,1)
  je     L5
L10:
  ret
```

assistant: ```c
int count_cr(char source[], int posn, int length) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (source[i] == 13) {
      c++;
    } else {
      cond = 0;
    }
    i++;
  } while ((i < length) && cond);
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<count_cr>:
  endbr64
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L3:
  cmpb   $0xd,(%rdi,%rsi,1)
  je     L11
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rsi
  add    $0x1,%eax
  cmp    %esi,%edx
  jg     L3
  ret
```

assistant: ```c
int count_cr(char source[], int posn, int length) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (source[i] == 13) {
      c++;
    } else {
      cond = 0;
    }
    i++;
  } while ((i < length) && cond);
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_cr>:
  endbr64
  movslq %esi,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  cmpb   $0xd,(%rdi,%rsi,1)
  je     L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rsi
  add    $0x1,%eax
  cmp    %esi,%edx
  jg     L10
  ret
```

assistant: ```c
int count_cr(char source[], int posn, int length) {
  int c = 0;
  int i = posn;
  int cond = 1;
  do {
    if (source[i] == 13) {
      c++;
    } else {
      cond = 0;
    }
    i++;
  } while ((i < length) && cond);
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L4
L25:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D14: %d

tool: D7: Case #%d: ___


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    printf("Case #%d: ___\n", caseIndex);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L8
  mov    $0x1,%ebx
  lea    D18(%rip),%rbp
L23:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L23
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D18
data_type: string

tool: D0: %d

tool: D18: Case #%d: ___


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    printf("Case #%d: ___\n", caseIndex);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L22
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
  nop
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L8
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D3
type_guessed: string

tool: D15: %d

tool: D3: Case #%d: ___


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    printf("Case #%d: ___\n", caseIndex);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L28
  mov    $0x1,%ebx
  lea    D17(%rip),%rbp
  nop
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L16
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string

tool: D3: %d

tool: D17: Case #%d: ___


assistant: ```c
int main() {
  int T;
  scanf("%d", &T);
  for (int caseIndex = 1; caseIndex <= T; caseIndex++) {
    printf("Case #%d: ___\n", caseIndex);
  }
  return 0;
}
```