ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x670,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x658(%rbp)
  lea    -0x330(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x64,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x66c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x664(%rbp)
  jmp    L60
L67:
  movl   $0x0,-0x654(%rbp)
  lea    -0x668(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x660(%rbp)
  jmp    L15
L109:
  mov    -0x660(%rbp),%eax
  cltq
  mov    -0x650(%rbp,%rax,4),%edx
  mov    -0x668(%rbp),%eax
  cmp    %eax,%edx
  jne    L7
  movl   $0x1,-0x654(%rbp)
  mov    -0x660(%rbp),%eax
  cltq
  mov    -0x654(%rbp),%edx
  mov    %edx,-0x330(%rbp,%rax,4)
  jmp    L78
L7:
  addl   $0x1,-0x660(%rbp)
L15:
  mov    -0x660(%rbp),%eax
  cmp    -0x658(%rbp),%eax
  jl     L109
L78:
  cmpl   $0x0,-0x654(%rbp)
  jne    L72
  mov    -0x658(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x658(%rbp)
  mov    -0x668(%rbp),%edx
  cltq
  mov    %edx,-0x650(%rbp,%rax,4)
L72:
  addl   $0x1,-0x664(%rbp)
L60:
  mov    -0x66c(%rbp),%eax
  cmp    %eax,-0x664(%rbp)
  jl     L67
  movl   $0x0,-0x664(%rbp)
  mov    -0x664(%rbp),%eax
  mov    %eax,-0x65c(%rbp)
  jmp    L28
L18:
  mov    -0x664(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L99
  mov    -0x65c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x65c(%rbp)
  mov    -0x664(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x650(%rbp,%rdx,4),%ecx
  movslq %eax,%rdx
  mov    %ecx,-0x650(%rbp,%rdx,4)
  cltq
  mov    -0x650(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L99:
  addl   $0x1,-0x664(%rbp)
L28:
  mov    -0x664(%rbp),%eax
  cmp    -0x658(%rbp),%eax
  jl     L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L105
  call   <__stack_chk_fail@plt>
L105:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_guessed: string
name: read_data
arguments: data_tag: D26
type_guessed: string

tool: D13: %d

tool: D26: %d 

assistant: ```c
int main() {
  int i, j, c, n, k = 0;
  int arr[200], arr2[200] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    int nm, dp = 0;
    scanf("%d", &nm);
    for (j = 0; j < k; ++j) {
      if (arr[j] == nm) {
        arr2[j] = dp = 1;
        break;
      }
    }
    if (!dp) {
      arr[k++] = nm;
    }
  }
  for (c = i = 0; i < k; ++i) {
    if (!arr2[i])
      printf("%d ", arr[c++] = arr[i]);
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x668,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x658(%rsp)
  xor    %eax,%eax
  lea    0x330(%rsp),%rdi
  mov    $0x64,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x8(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L15
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D24(%rip),%r12
  jmp    L138
L18:
  movslq %eax,%rdx
  movl   $0x1,0x330(%rsp,%rdx,4)
  jmp    L123
L54:
  movslq %ebx,%rax
  mov    0xc(%rsp),%edx
  mov    %edx,0x10(%rsp,%rax,4)
  lea    0x1(%rbx),%ebx
L123:
  add    $0x1,%ebp
  cmp    %ebp,0x8(%rsp)
  jle    L56
L138:
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %ebx,%ebx
  jle    L54
  mov    0xc(%rsp),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  lea    0x10(%rsp),%rcx
L3:
  cmp    %esi,(%rcx,%rax,4)
  je     L18
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L3
  jmp    L54
L56:
  test   %ebx,%ebx
  jle    L15
  mov    %ebx,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%eax
  lea    D29(%rip),%r13
  jmp    L114
L83:
  add    $0x1,%rbp
  cmp    %rbp,%rbx
  je     L15
L114:
  cmpl   $0x0,0x330(%rsp,%rbp,4)
  jne    L83
  lea    0x1(%rax),%r12d
  mov    0x10(%rsp,%rbp,4),%esi
  cltq
  mov    %esi,0x10(%rsp,%rax,4)
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  jmp    L83
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x658(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  mov    $0x0,%eax
  add    $0x668,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D29
data_type: string

tool: D24: %d

tool: D29: %d 

assistant: ```c
int main() {
  int i, j, c, n, k = 0;
  int arr[200], arr2[200] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    int nm, dp = 0;
    scanf("%d", &nm);
    for (j = 0; j < k; ++j) {
      if (arr[j] == nm) {
        arr2[j] = dp = 1;
        break;
      }
    }
    if (!dp) {
      arr[k++] = nm;
    }
  }
  for (c = i = 0; i < k; ++i) {
    if (!arr2[i])
      printf("%d ", arr[c++] = arr[i]);
  }
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x64,%ecx
  push   %r14
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x678,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x668(%rsp)
  xor    %eax,%eax
  lea    0x340(%rsp),%rdi
  lea    0x18(%rsp),%rsi
  mov    %rdi,0x8(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%ecx
  test   %ecx,%ecx
  jle    L8
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  lea    0x1c(%rsp),%r13
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r14
  xchg   %ax,%ax
L75:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  xor    %eax,%eax
  test   %ebp,%ebp
  jne    L67
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L10:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L13
L67:
  movslq %eax,%rcx
  cmp    %edx,(%r14,%rax,4)
  jne    L10
  movl   $0x1,0x340(%rsp,%rcx,4)
L74:
  add    $0x1,%r15d
  cmp    %r15d,0x18(%rsp)
  jg     L75
  xor    %r12d,%r12d
  xor    %eax,%eax
  lea    D4(%rip),%r14
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L8
L23:
  mov    0x8(%rsp),%rdi
  mov    (%rdi,%r12,4),%edx
  test   %edx,%edx
  jne    L36
  mov    0x20(%rsp,%r12,4),%esi
  lea    0x1(%rax),%r13d
  mov    %r14,%rdi
  add    $0x1,%r12
  mov    %esi,0x20(%rsp,%rax,4)
  xor    %eax,%eax
  call   <printf@plt>
  movslq %r13d,%rax
  cmp    %r12,%rbx
  jne    L23
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x668(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  add    $0x678,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%ebp
  mov    %edx,0x20(%rsp,%rbx,4)
  movslq %ebp,%rbx
  jmp    L74
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D5: %d

tool: D4: %d 

assistant: ```c
int main() {
  int i, j, c, n, k = 0;
  int arr[200], arr2[200] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    int nm, dp = 0;
    scanf("%d", &nm);
    for (j = 0; j < k; ++j) {
      if (arr[j] == nm) {
        arr2[j] = dp = 1;
        break;
      }
    }
    if (!dp) {
      arr[k++] = nm;
    }
  }
  for (c = i = 0; i < k; ++i) {
    if (!arr2[i])
      printf("%d ", arr[c++] = arr[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x64,%ecx
  push   %r14
  push   %r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x678,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x668(%rsp)
  xor    %eax,%eax
  lea    0x340(%rsp),%rdi
  lea    0x18(%rsp),%rsi
  mov    %rdi,0x8(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x18(%rsp),%ecx
  test   %ecx,%ecx
  jle    L105
  xor    %ebp,%ebp
  xor    %r15d,%r15d
  lea    0x1c(%rsp),%r13
  xor    %ebx,%ebx
  lea    0x20(%rsp),%r14
  xchg   %ax,%ax
L19:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  xor    %eax,%eax
  test   %ebp,%ebp
  jne    L79
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L100:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L56
L79:
  movslq %eax,%rcx
  cmp    %edx,(%r14,%rax,4)
  jne    L100
  movl   $0x1,0x340(%rsp,%rcx,4)
L45:
  add    $0x1,%r15d
  cmp    %r15d,0x18(%rsp)
  jg     L19
  xor    %r12d,%r12d
  xor    %eax,%eax
  lea    D6(%rip),%r14
  jmp    L98
  nopw   0x0(%rax,%rax,1)
L85:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L105
L98:
  mov    0x8(%rsp),%rdi
  mov    (%rdi,%r12,4),%edx
  test   %edx,%edx
  jne    L85
  mov    0x20(%rsp,%r12,4),%esi
  lea    0x1(%rax),%r13d
  mov    %r14,%rdi
  add    $0x1,%r12
  mov    %esi,0x20(%rsp,%rax,4)
  xor    %eax,%eax
  call   <printf@plt>
  movslq %r13d,%rax
  cmp    %r12,%rbx
  jne    L98
L105:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x668(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x678,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L56:
  add    $0x1,%ebp
  mov    %edx,0x20(%rsp,%rbx,4)
  movslq %ebp,%rbx
  jmp    L45
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D11: %d

tool: D6: %d 

assistant: ```c
int main() {
  int i, j, c, n, k = 0;
  int arr[200], arr2[200] = {0};
  scanf("%d", &n);
  for (i = 0; i < n; ++i) {
    int nm, dp = 0;
    scanf("%d", &nm);
    for (j = 0; j < k; ++j) {
      if (arr[j] == nm) {
        arr2[j] = dp = 1;
        break;
      }
    }
    if (!dp) {
      arr[k++] = nm;
    }
  }
  for (c = i = 0; i < k; ++i) {
    if (!arr2[i])
      printf("%d ", arr[c++] = arr[i]);
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D20(%rip),%r13
  lea    D47(%rip),%rbx
  lea    D6(%rip),%r12
  lea    D55(%rip),%rbp
L68:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  je     L68
  lea    0x1(%rdx),%eax
  cmp    %eax,%esi
  je     L68
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  je     L68
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%eax
  cmp    %eax,%edx
  jge    L23
  mov    %edx,(%rsp)
  mov    %eax,0x4(%rsp)
L23:
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L4
  mov    $0x0,%ebp
  lea    D76(%rip),%r12
L40:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %ebx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L40
L34:
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    $0x0,%ebp
  jmp    L34
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D47
data_type: string
name: retrieve_data
arguments: label: D6
data_type: string
name: retrieve_data
arguments: label: D55
data_type: string
name: retrieve_data
arguments: label: D22
data_type: string
name: retrieve_data
arguments: label: D24
data_type: string
name: retrieve_data
arguments: label: D76
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string

tool: D20: Insira um numero inteiro: 

tool: D47: %d

tool: D6: Insira outro numero inteiro: 

tool: D55: cls

tool: D22: A = %d; B = %d


tool: D24: Soma = 

tool: D76: %d + 

tool: D7:  = %d

assistant: ```c
main() {
  int A, B, x;
  int soma = 0;
  int N1, N2;
  do {
    printf("Insira um numero inteiro: ");
    scanf("%d", &A);
    printf("Insira outro numero inteiro: ");
    scanf("%d", &B);
    system("cls");
  } while ((A == B) || (A == (B + 1)) || (A == (B - 1)));
  printf("A = %d; B = %d\n", A, B);
  if (B < A) {
    x = A;
    A = B;
    B = x;
  }
  printf("Soma = ");
  for (int i = A; i <= B; i++) {
    printf("%d + ", i);
    soma = soma + i;
  }
  printf(" = %d", soma);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  lea    D45(%rip),%r15
  push   %r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbp
  lea    D72(%rip),%rbp
  push   %rbx
  lea    D62(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x4(%rsp),%r12
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  je     L33
  lea    0x1(%rdx),%eax
  cmp    %eax,%esi
  je     L33
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  je     L33
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%eax
  cmp    %eax,%edx
  jge    L69
  mov    %edx,(%rsp)
  mov    %eax,0x4(%rsp)
L69:
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L52
  lea    D53(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %ebx,%ebp
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L39
L52:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D45
type_infered: string
name: read_data
arguments: label: D21
type_infered: string
name: read_data
arguments: label: D72
type_infered: string
name: read_data
arguments: label: D62
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D57
type_infered: string
name: read_data
arguments: label: D53
type_infered: string
name: read_data
arguments: label: D3
type_infered: string

tool: D45: Insira um numero inteiro: 

tool: D21: Insira outro numero inteiro: 

tool: D72: cls

tool: D62: %d

tool: D28: A = %d; B = %d


tool: D57: Soma = 

tool: D53: %d + 

tool: D3:  = %d

assistant: ```c
main() {
  int A, B, x;
  int soma = 0;
  int N1, N2;
  do {
    printf("Insira um numero inteiro: ");
    scanf("%d", &A);
    printf("Insira outro numero inteiro: ");
    scanf("%d", &B);
    system("cls");
  } while ((A == B) || (A == (B + 1)) || (A == (B - 1)));
  printf("A = %d; B = %d\n", A, B);
  if (B < A) {
    x = A;
    A = B;
    B = x;
  }
  printf("Soma = ");
  for (int i = A; i <= B; i++) {
    printf("%d + ", i);
    soma = soma + i;
  }
  printf(" = %d", soma);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%r15
  push   %r14
  push   %r13
  lea    D75(%rip),%r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  lea    D68(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x4(%rsp),%r12
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  cmp    %edx,%esi
  je     L1
  lea    0x1(%rdx),%eax
  cmp    %eax,%esi
  je     L1
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  je     L1
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%eax
  cmp    %eax,%edx
  jge    L60
  mov    %edx,(%rsp)
  mov    %eax,0x4(%rsp)
L60:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  mov    (%rsp),%ebx
  cmp    0x4(%rsp),%ebx
  jg     L17
  lea    D65(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    %ebx,%ebp
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L45
L17:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
data_type: string
name: parse_data
arguments: data_tag: D75
data_type: string
name: parse_data
arguments: data_tag: D5
data_type: string
name: parse_data
arguments: data_tag: D68
data_type: string
name: parse_data
arguments: data_tag: D46
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string
name: parse_data
arguments: data_tag: D65
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string

tool: D32: Insira um numero inteiro: 

tool: D75: Insira outro numero inteiro: 

tool: D5: cls

tool: D68: %d

tool: D46: A = %d; B = %d


tool: D10: Soma = 

tool: D65: %d + 

tool: D0:  = %d

assistant: ```c
main() {
  int A, B, x;
  int soma = 0;
  int N1, N2;
  do {
    printf("Insira um numero inteiro: ");
    scanf("%d", &A);
    printf("Insira outro numero inteiro: ");
    scanf("%d", &B);
    system("cls");
  } while ((A == B) || (A == (B + 1)) || (A == (B - 1)));
  printf("A = %d; B = %d\n", A, B);
  if (B < A) {
    x = A;
    A = B;
    B = x;
  }
  printf("Soma = ");
  for (int i = A; i <= B; i++) {
    printf("%d + ", i);
    soma = soma + i;
  }
  printf(" = %d", soma);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_pgm_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_pgm_id() {
  int rval = 0;
  return rval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_pgm_id>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int get_pgm_id() {
  int rval = 0;
  return rval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_pgm_id>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_pgm_id() {
  int rval = 0;
  return rval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_pgm_id>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_pgm_id() {
  int rval = 0;
  return rval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sdmmc_sdcard_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <InitSD@plt>
  mov    $0x0,%eax
  call   <Nand_Init@plt>
  mov    $0x0,%eax
  call   <SD_Init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sdmmc_sdcard_init() {
  ;
  InitSD();
  Nand_Init();
  ;
  SD_Init();
  ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sdmmc_sdcard_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <InitSD@plt>
  mov    $0x0,%eax
  call   <Nand_Init@plt>
  mov    $0x0,%eax
  call   <SD_Init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sdmmc_sdcard_init() {
  ;
  InitSD();
  Nand_Init();
  ;
  SD_Init();
  ;
}
```
user: What is the c source code of the assembly code below:

```asm
<sdmmc_sdcard_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <InitSD@plt>
  xor    %eax,%eax
  call   <Nand_Init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <SD_Init@plt>
```

assistant: ```c
void sdmmc_sdcard_init() {
  ;
  InitSD();
  Nand_Init();
  ;
  SD_Init();
  ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sdmmc_sdcard_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <InitSD@plt>
  xor    %eax,%eax
  call   <Nand_Init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <SD_Init@plt>
```

assistant: ```c
void sdmmc_sdcard_init() {
  ;
  InitSD();
  Nand_Init();
  ;
  SD_Init();
  ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L22
L16:
  addq   $0x1,-0x18(%rbp)
L22:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  test   %rax,%rax
  je     L50
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
L50:
  mov    -0x18(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L48
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  jmp    L65
L24:
  cmpq   $0x1,-0x10(%rbp)
  je     L0
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
L0:
  addq   $0x1,-0x20(%rbp)
L48:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L65:
  leave
  ret
```

assistant: ```c
size_t ft_strlcat(char *dst, const char *src, size_t size) {
  const char *s;
  char *d;
  size_t n;
  size_t dst_len;
  s = src;
  d = dst;
  n = size;
  while (n-- != 0 && *d != '\0')
    d++;
  dst_len = d - dst;
  n = size - dst_len;
  if (n == 0)
    return (dst_len + ft_strlen(s));
  while (*s != '\0') {
    if (n != 1) {
      *d++ = *s;
      n--;
    }
    s++;
  }
  *d = '\0';
  return (dst_len + (s - src));
}
```