ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<descale_and_clamp>:
  endbr64
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  shl    %cl,%eax
  mov    %esi,%ecx
  mov    %eax,%edx
  mov    %edi,%eax
  mov    $0xff,%edi
  add    %edx,%eax
  sar    %cl,%eax
  sub    $0xffffff80,%eax
  cmovl  %r8d,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  ret
```

assistant: ```c
unsigned char descale_and_clamp(int x, int shift) {
  __asm__("add %3,%1\n"
          "\tsar %2,%1\n"
          "\tsub $-128,%1\n"
          "\tcmovl %5,%1\n"
          "\tcmpl %4,%1\n"
          "\tcmovg %4,%1\n"
          : "=r"(x)
          : "0"(x), "Ic"((unsigned char)shift), "ir"(1U << (shift - 1)), "r"(0xff), "r"(0));
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L2:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
  addq   $0x8,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add(double *resultBegin, double *resultEnd, const double *a0Begin, const double *a1Begin) {
  unsigned i = 0;
  while (resultBegin < resultEnd) {
    *resultBegin = *(a0Begin + i) + *(a1Begin + i);
    ++i;
    ++resultBegin;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add>:
  endbr64
  mov    %rdi,%r8
  cmp    %rsi,%rdi
  jae    L3
  lea    -0x1(%rsi),%rdi
  sub    %r8,%rdi
  shr    $0x3,%rdi
  mov    $0x0,%eax
L10:
  mov    %eax,%esi
  movsd  (%rdx,%rsi,8),%xmm0
  addsd  (%rcx,%rsi,8),%xmm0
  movsd  %xmm0,(%r8,%rax,8)
  mov    %rax,%rsi
  add    $0x1,%rax
  cmp    %rdi,%rsi
  jne    L10
L3:
  ret
```

assistant: ```c
void add(double *resultBegin, double *resultEnd, const double *a0Begin, const double *a1Begin) {
  unsigned i = 0;
  while (resultBegin < resultEnd) {
    *resultBegin = *(a0Begin + i) + *(a1Begin + i);
    ++i;
    ++resultBegin;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add>:
  endbr64
  mov    %rdi,%r8
  cmp    %rsi,%rdi
  jae    L0
  lea    -0x1(%rsi),%rdi
  xor    %eax,%eax
  sub    %r8,%rdi
  shr    $0x3,%rdi
  nopl   0x0(%rax)
L18:
  mov    %eax,%esi
  movsd  (%rdx,%rsi,8),%xmm0
  addsd  (%rcx,%rsi,8),%xmm0
  mov    %rax,%rsi
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rdi
  jne    L18
L0:
  ret
```

assistant: ```c
void add(double *resultBegin, double *resultEnd, const double *a0Begin, const double *a1Begin) {
  unsigned i = 0;
  while (resultBegin < resultEnd) {
    *resultBegin = *(a0Begin + i) + *(a1Begin + i);
    ++i;
    ++resultBegin;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add>:
  endbr64
  mov    %rdi,%r8
  cmp    %rsi,%rdi
  jae    L13
  lea    -0x1(%rsi),%rdi
  xor    %eax,%eax
  sub    %r8,%rdi
  shr    $0x3,%rdi
  nopl   0x0(%rax)
L19:
  mov    %eax,%esi
  movsd  (%rdx,%rsi,8),%xmm0
  addsd  (%rcx,%rsi,8),%xmm0
  mov    %rax,%rsi
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  cmp    %rsi,%rdi
  jne    L19
L13:
  ret
```

assistant: ```c
void add(double *resultBegin, double *resultEnd, const double *a0Begin, const double *a1Begin) {
  unsigned i = 0;
  while (resultBegin < resultEnd) {
    *resultBegin = *(a0Begin + i) + *(a1Begin + i);
    ++i;
    ++resultBegin;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<glmGenerateZeroVector2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmGenerateZeroVector2d(double v[2]) {
  v[0] = 0;
  v[1] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<glmGenerateZeroVector2d>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,0x8(%rdi)
  ret
```

assistant: ```c
void glmGenerateZeroVector2d(double v[2]) {
  v[0] = 0;
  v[1] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<glmGenerateZeroVector2d>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,0x8(%rdi)
  ret
```

assistant: ```c
void glmGenerateZeroVector2d(double v[2]) {
  v[0] = 0;
  v[1] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<glmGenerateZeroVector2d>:
  endbr64
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void glmGenerateZeroVector2d(double v[2]) {
  v[0] = 0;
  v[1] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<leave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void leave(int sock) {
  close(sock);
  exit(1);
}
```
user: What is the c source code of the assembly code below?

```asm
<leave>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void leave(int sock) {
  close(sock);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<leave>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void leave(int sock) {
  close(sock);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<leave>:
  endbr64
  sub    $0x8,%rsp
  call   <close@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void leave(int sock) {
  close(sock);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_s32l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L9
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <die_file_eof@plt>
L9:
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x10,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x18,%eax
  add    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int read_s32l(FILE *fp) {
  u_char b[4];
  if (fread(b, 4, 1, fp) != 1)
    die_file_eof(fp);
  return b[0] + (b[1] << 8) + (b[2] << 16) + (b[3] << 24);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_s32l>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  jne    L0
L20:
  mov    0x4(%rsp),%eax
  shl    $0x8,%eax
  add    (%rsp),%eax
  mov    0x8(%rsp),%edx
  shl    $0x10,%edx
  add    %edx,%eax
  mov    0xc(%rsp),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  mov    %rbx,%rdi
  call   <die_file_eof@plt>
  jmp    L20
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_s32l(FILE *fp) {
  u_char b[4];
  if (fread(b, 4, 1, fp) != 1)
    die_file_eof(fp);
  return b[0] + (b[1] << 8) + (b[2] << 16) + (b[3] << 24);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_s32l>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rbp,%rcx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L16
  mov    %rbp,%rdi
  call   <die_file_eof@plt>
L16:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  add    (%rsp),%eax
  add    %edx,%eax
  mov    0xc(%rsp),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_s32l(FILE *fp) {
  u_char b[4];
  if (fread(b, 4, 1, fp) != 1)
    die_file_eof(fp);
  return b[0] + (b[1] << 8) + (b[2] << 16) + (b[3] << 24);
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_s32l>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rbp,%rcx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L8
  mov    %rbp,%rdi
  call   <die_file_eof@plt>
L8:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  add    (%rsp),%eax
  add    %edx,%eax
  mov    0xc(%rsp),%edx
  shl    $0x18,%edx
  add    %edx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_s32l(FILE *fp) {
  u_char b[4];
  if (fread(b, 4, 1, fp) != 1)
    die_file_eof(fp);
  return b[0] + (b[1] << 8) + (b[2] << 16) + (b[3] << 24);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xcb0,%rsp
  mov    %rdi,-0xca8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc90(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    $0x190,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  movl   $0x0,-0xc94(%rbp)
  jmp    L6
L27:
  lea    -0xc90(%rbp),%rcx
  mov    -0xc94(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0xca8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L48
  mov    $0x1,%eax
  jmp    L43
L48:
  addl   $0x1,-0xc94(%rbp)
L6:
  mov    -0xc94(%rbp),%eax
  cmp    $0x1f,%eax
  jbe    L27
  mov    $0x0,%eax
L43:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D2: auto

assistant: ```c
int key(char *p) {
  char keyword[][100] = {"auto", "extern", "sizeof", "break", "float", "static", "case", "for", "struct", "char", "goto", "switch", "const", "if", "typedef", "continue", "int", "union", "default", "long", "unsigned", "do", "register", "void", "return", "double", "volatile", "else", "short", "while", "enum", "signed"};
  int i;
  for (i = 0; i < (sizeof(keyword) / sizeof(keyword[0])); i++) {
    if (!strcmp(keyword[i], p))
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<key>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc90,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xc88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D2(%rip),%rsi
  mov    $0x190,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    %rsp,%rbx
  lea    0xc80(%rsp),%r12
L28:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L18
  add    $0x64,%rbx
  cmp    %r12,%rbx
  jne    L28
  mov    $0x0,%eax
  jmp    L13
L18:
  mov    $0x1,%eax
L13:
  mov    0xc88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0xc90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: auto

assistant: ```c
int key(char *p) {
  char keyword[][100] = {"auto", "extern", "sizeof", "break", "float", "static", "case", "for", "struct", "char", "goto", "switch", "const", "if", "typedef", "continue", "int", "union", "default", "long", "unsigned", "do", "register", "void", "return", "double", "volatile", "else", "short", "while", "enum", "signed"};
  int i;
  for (i = 0; i < (sizeof(keyword) / sizeof(keyword[0])); i++) {
    if (!strcmp(keyword[i], p))
      return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<key>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  mov    $0x190,%ecx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0xc90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbx
  lea    0xc80(%rsp),%r12
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L44
  nopl   0x0(%rax)
L40:
  add    $0x64,%rbx
  cmp    %r12,%rbx
  je     L18
L44:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L40
  mov    $0x1,%eax
L37:
  mov    0xc88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0xc90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  jmp    L37
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: auto

assistant: ```c
int key(char *p) {
  char keyword[][100] = {"auto", "extern", "sizeof", "break", "float", "static", "case", "for", "struct", "char", "goto", "switch", "const", "if", "typedef", "continue", "int", "union", "default", "long", "unsigned", "do", "register", "void", "return", "double", "volatile", "else", "short", "while", "enum", "signed"};
  int i;
  for (i = 0; i < (sizeof(keyword) / sizeof(keyword[0])); i++) {
    if (!strcmp(keyword[i], p))
      return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<key>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  mov    $0x190,%ecx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0xc90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbx
  lea    0xc80(%rsp),%r12
  rep movsq %ds:(%rsi),%es:(%rdi)
  jmp    L21
  nopl   0x0(%rax)
L32:
  add    $0x64,%rbx
  cmp    %r12,%rbx
  je     L6
L21:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L32
  mov    $0x1,%eax
L45:
  mov    0xc88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0xc90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  jmp    L45
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: auto

assistant: ```c
int key(char *p) {
  char keyword[][100] = {"auto", "extern", "sizeof", "break", "float", "static", "case", "for", "struct", "char", "goto", "switch", "const", "if", "typedef", "continue", "int", "union", "default", "long", "unsigned", "do", "register", "void", "return", "double", "volatile", "else", "short", "while", "enum", "signed"};
  int i;
  for (i = 0; i < (sizeof(keyword) / sizeof(keyword[0])); i++) {
    if (!strcmp(keyword[i], p))
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrixMulti>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L29:
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L49:
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rsi
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L0
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jl     L49
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L29
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrixMulti(int **result, int **A, int **B, int rowNumOfA, int colNumOfA, int rowNumOfB, int colNumOfB) {
  int i = 0, j = 0, k = 0;
  for (i = 0; i < rowNumOfA; i++) {
    for (j = 0; j < colNumOfB; j++) {
      for (k = 0; k < colNumOfA; k++) {
        result[i][j] += A[i][k] * B[k][j];
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrixMulti>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x28(%rsp),%r12d
  test   %ecx,%ecx
  jle    L53
  mov    %rsi,%r9
  mov    %rdx,%r10
  mov    %r8d,%ebx
  mov    %rdi,%r8
  lea    -0x1(%rcx),%edx
  lea    0x8(%rdi,%rdx,8),%r13
  lea    -0x1(%r12),%eax
  lea    0x4(,%rax,4),%rbp
  lea    -0x1(%rbx),%eax
  lea    0x4(,%rax,4),%r11
  jmp    L63
L73:
  mov    %rsi,%rcx
  add    (%r8),%rcx
  mov    (%r9),%rdx
  mov    (%r10,%rax,2),%rdi
  mov    (%rdx,%rax,1),%edx
  imul   (%rdi,%rsi,1),%edx
  add    %edx,(%rcx)
  add    $0x4,%rax
  cmp    %rax,%r11
  jne    L73
L48:
  add    $0x4,%rsi
  cmp    %rbp,%rsi
  je     L6
L14:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L73
  jmp    L48
L6:
  add    $0x8,%r8
  add    $0x8,%r9
  cmp    %r13,%r8
  je     L53
L63:
  mov    $0x0,%esi
  test   %r12d,%r12d
  jg     L14
  jmp    L6
L53:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void matrixMulti(int **result, int **A, int **B, int rowNumOfA, int colNumOfA, int rowNumOfB, int colNumOfB) {
  int i = 0, j = 0, k = 0;
  for (i = 0; i < rowNumOfA; i++) {
    for (j = 0; j < colNumOfB; j++) {
      for (k = 0; k < colNumOfA; k++) {
        result[i][j] += A[i][k] * B[k][j];
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<matrixMulti>:
  endbr64
  push   %r15
  push   %r14
  movslq %ecx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r15d
  test   %r14d,%r14d
  jle    L57
  lea    -0x1(%r15),%eax
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r9
  mov    %r8d,%ebx
  lea    0x4(,%rax,4),%r13
  xor    %r11d,%r11d
  movslq %r8d,%r10
  nopl   0x0(%rax)
L48:
  xor    %esi,%esi
  test   %r15d,%r15d
  jle    L7
  nopw   0x0(%rax,%rax,1)
L26:
  test   %ebx,%ebx
  jle    L18
  mov    0x0(%rbp,%r11,8),%rdi
  mov    (%r12,%r11,8),%r8
  xor    %eax,%eax
  add    %rsi,%rdi
  mov    (%rdi),%ecx
  nopl   0x0(%rax)
L50:
  mov    (%r9,%rax,8),%rdx
  mov    (%rdx,%rsi,1),%edx
  imul   (%r8,%rax,4),%edx
  add    $0x1,%rax
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %r10,%rax
  jne    L50
L18:
  add    $0x4,%rsi
  cmp    %rsi,%r13
  jne    L26
L7:
  add    $0x1,%r11
  cmp    %r11,%r14
  jne    L48
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void matrixMulti(int **result, int **A, int **B, int rowNumOfA, int colNumOfA, int rowNumOfB, int colNumOfB) {
  int i = 0, j = 0, k = 0;
  for (i = 0; i < rowNumOfA; i++) {
    for (j = 0; j < colNumOfB; j++) {
      for (k = 0; k < colNumOfA; k++) {
        result[i][j] += A[i][k] * B[k][j];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<matrixMulti>:
  endbr64
  push   %r14
  movslq %ecx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq 0x30(%rsp),%rax
  test   %r14d,%r14d
  jle    L57
  test   %eax,%eax
  jle    L57
  movslq %r8d,%r9
  test   %r9d,%r9d
  jle    L57
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r10
  xor    %r13d,%r13d
  lea    0x0(,%rax,4),%r12
  nopl   0x0(%rax)
L58:
  mov    (%rbx,%r13,8),%r11
  mov    0x0(%rbp,%r13,8),%r8
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L20:
  lea    (%r11,%rsi,1),%rdi
  xor    %eax,%eax
  mov    (%rdi),%ecx
  nopl   0x0(%rax,%rax,1)
L11:
  mov    (%r10,%rax,8),%rdx
  mov    (%rdx,%rsi,1),%edx
  imul   (%r8,%rax,4),%edx
  add    $0x1,%rax
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %rax,%r9
  jne    L11
  add    $0x4,%rsi
  cmp    %rsi,%r12
  jne    L20
  add    $0x1,%r13
  cmp    %r13,%r14
  jne    L58
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void matrixMulti(int **result, int **A, int **B, int rowNumOfA, int colNumOfA, int rowNumOfB, int colNumOfB) {
  int i = 0, j = 0, k = 0;
  for (i = 0; i < rowNumOfA; i++) {
    for (j = 0; j < colNumOfB; j++) {
      for (k = 0; k < colNumOfA; k++) {
        result[i][j] += A[i][k] * B[k][j];
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mp_squhf_use_infft>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %rdx,%r14
  mov    %rcx,%rdx
  mov    %r8,0x8(%rsp)
  mov    %r9,%r15
  mov    0x50(%rsp),%r12d
  mov    %r12d,%ecx
  sar    %ecx
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jge    L44
  movslq %ecx,%rax
L37:
  mov    %eax,%ecx
  cmpw   $0x0,0x8(%rdx,%rax,2)
  jne    L44
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L37
L44:
  mov    %ebx,%ebp
  shr    $0x1f,%ebp
  add    %ebx,%ebp
  sar    %ebp
  add    $0x1,%ebp
  mov    %ebx,%eax
  sub    %ecx,%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  mov    0x58(%rsp),%r9
  mov    %rdx,%r8
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <mp_mul_i2d@plt>
  mov    0x58(%rsp),%rdx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <mp_mul_cmul_nt_d1@plt>
  mov    %r15,%r8
  mov    0x58(%rsp),%rcx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mp_mul_d2i@plt>
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <mp_mul_csqu_nt_d1@plt>
  mov    0x8(%rsp),%r8
  mov    %r14,%rcx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <mp_mul_d2i@plt>
  cmpl   $0x0,(%r15)
  jne    L39
L23:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  mov    0x8(%rsp),%rdx
  mov    %rdx,%r8
  mov    %r15,%rcx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <mp_add@plt>
  jmp    L23
```

assistant: ```c
void mp_squhf_use_infft(int n, int radix, double infft[], int in[], int out[], int tmp[], int nfft, double tmpfft[]) {
  void mp_add(int n, int radix, int in1[], int in2[], int out[]);
  void mp_mul_i2d(int n, int radix, int nfft, int shift, int in[], double dout[]);
  void mp_mul_cmul_nt_d1(int nfft, double d1[], double d2[]);
  void mp_mul_csqu_nt_d1(int nfft, double d1[]);
  void mp_mul_d2i(int n, int radix, int nfft, double din[], int out[]);
  int n_h, shift;
  short int *indgt;
  indgt = (short int *)&in[2];
  shift = (nfft >> 1) + 1;
  while (n > shift) {
    if (indgt[shift] != 0) {
      break;
    }
    shift++;
  }
  n_h = n / 2 + 1;
  if (n_h < n - shift) {
    n_h = n - shift;
  }
  mp_mul_i2d(n, radix, nfft, shift, in, tmpfft);
  mp_mul_cmul_nt_d1(nfft, infft, tmpfft);
  mp_mul_d2i(n_h, radix, nfft, tmpfft, tmp);
  mp_mul_csqu_nt_d1(nfft, infft);
  mp_mul_d2i(n, radix, nfft, infft, out);
  if (tmp[0] != 0) {
    mp_add(n, radix, out, tmp, out);
  }
}
```