ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<timegm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    (%rdi),%edi
  cmp    $0x45,%edi
  jle    L73
  mov    0x4(%rbp),%eax
  cmp    $0xb,%eax
  ja     L65
  mov    0x8(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  cmp    $0x1e,%ecx
  ja     L100
  cmpl   $0x17,0xc(%rbp)
  ja     L135
  cmpl   $0x3b,0x10(%rbp)
  ja     L58
  cmpl   $0x3c,0x14(%rbp)
  ja     L91
  cltq
  lea    D8(%rip),%rcx
  add    (%rcx,%rax,4),%edx
  lea    -0x46(%rdi),%eax
  imul   $0x16d,%eax,%eax
  lea    -0x1(%rdx,%rax,1),%r12d
  cmp    $0x46,%edi
  jle    L44
  mov    $0x46,%ebx
L13:
  lea    0x76c(%rbx),%edi
  call   <is_leap_year@plt>
  add    %eax,%r12d
  add    $0x1,%ebx
  mov    0x0(%rbp),%edi
  cmp    %ebx,%edi
  jg     L13
L44:
  cmpl   $0x1,0x4(%rbp)
  jg     L66
L95:
  lea    (%r12,%r12,2),%edx
  mov    0xc(%rbp),%eax
  lea    (%rax,%rdx,8),%eax
  imul   $0x3c,%eax,%eax
  add    0x10(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    0x14(%rbp),%eax
L132:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  add    $0x76c,%edi
  call   <is_leap_year@plt>
  add    %eax,%r12d
  jmp    L95
L73:
  mov    $0xffffffff,%eax
  jmp    L132
L65:
  mov    $0xffffffff,%eax
  jmp    L132
L100:
  mov    $0xffffffff,%eax
  jmp    L132
L135:
  mov    $0xffffffff,%eax
  jmp    L132
L58:
  mov    $0xffffffff,%eax
  jmp    L132
L91:
  mov    $0xffffffff,%eax
  jmp    L132
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: 

assistant: ```c
time_t timegm(struct tm *tm) {
  static const unsigned ydays[12 + 1] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  if (tm->tm_year < 70 || tm->tm_mon < 0 || tm->tm_mon > 11 || tm->tm_mday < 1 || tm->tm_mday > 31 || tm->tm_hour < 0 || tm->tm_hour > 23 || tm->tm_min < 0 || tm->tm_min > 59 || tm->tm_sec < 0 || tm->tm_sec > 60)
    return -1;
  unsigned t = 365 * (tm->tm_year - 70) + ydays[tm->tm_mon] + (tm->tm_mday - 1);
  for (int i = 70; i < tm->tm_year; i++)
    t += is_leap_year(1900 + i);
  if (tm->tm_mon > 1)
    t += is_leap_year(1900 + tm->tm_year);
  t *= 24;
  t += tm->tm_hour;
  t *= 60;
  t += tm->tm_min;
  t *= 60;
  t += tm->tm_sec;
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timegm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%edi
  cmp    $0x45,%edi
  jle    L29
  mov    0x4(%rbp),%edx
  cmp    $0xb,%edx
  ja     L29
  mov    0x8(%rbp),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0x1e,%ecx
  ja     L29
  cmpl   $0x17,0xc(%rbp)
  ja     L29
  cmpl   $0x3b,0x10(%rbp)
  ja     L29
  cmpl   $0x3c,0x14(%rbp)
  ja     L29
  movslq %edx,%rcx
  lea    D1(%rip),%rsi
  add    (%rsi,%rcx,4),%eax
  lea    -0x46(%rdi),%ecx
  imul   $0x16d,%ecx,%ecx
  lea    -0x1(%rax,%rcx,1),%r12d
  cmp    $0x46,%edi
  je     L24
  mov    $0x46,%ebx
  nopl   0x0(%rax)
L79:
  lea    0x76c(%rbx),%edi
  add    $0x1,%ebx
  call   <is_leap_year@plt>
  mov    0x0(%rbp),%edi
  add    %eax,%r12d
  cmp    %ebx,%edi
  jg     L79
  mov    0x4(%rbp),%edx
L24:
  cmp    $0x1,%edx
  jle    L89
  add    $0x76c,%edi
  call   <is_leap_year@plt>
  add    %eax,%r12d
L89:
  mov    0xc(%rbp),%eax
  lea    (%r12,%r12,2),%edx
  lea    (%rax,%rdx,8),%eax
  imul   $0x3c,%eax,%eax
  add    0x10(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    0x14(%rbp),%eax
L86:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L29:
  mov    $0xffffffff,%eax
  jmp    L86
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: 

assistant: ```c
time_t timegm(struct tm *tm) {
  static const unsigned ydays[12 + 1] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  if (tm->tm_year < 70 || tm->tm_mon < 0 || tm->tm_mon > 11 || tm->tm_mday < 1 || tm->tm_mday > 31 || tm->tm_hour < 0 || tm->tm_hour > 23 || tm->tm_min < 0 || tm->tm_min > 59 || tm->tm_sec < 0 || tm->tm_sec > 60)
    return -1;
  unsigned t = 365 * (tm->tm_year - 70) + ydays[tm->tm_mon] + (tm->tm_mday - 1);
  for (int i = 70; i < tm->tm_year; i++)
    t += is_leap_year(1900 + i);
  if (tm->tm_mon > 1)
    t += is_leap_year(1900 + tm->tm_year);
  t *= 24;
  t += tm->tm_hour;
  t *= 60;
  t += tm->tm_min;
  t *= 60;
  t += tm->tm_sec;
  return t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<timegm>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdi),%edi
  cmp    $0x45,%edi
  jle    L27
  mov    0x4(%rbp),%edx
  cmp    $0xb,%edx
  ja     L27
  mov    0x8(%rbp),%eax
  lea    -0x1(%rax),%ecx
  cmp    $0x1e,%ecx
  ja     L27
  cmpl   $0x17,0xc(%rbp)
  ja     L27
  cmpl   $0x3b,0x10(%rbp)
  ja     L27
  cmpl   $0x3c,0x14(%rbp)
  ja     L27
  movslq %edx,%rcx
  lea    D4(%rip),%rsi
  add    (%rsi,%rcx,4),%eax
  lea    -0x46(%rdi),%ecx
  imul   $0x16d,%ecx,%ecx
  lea    -0x1(%rax,%rcx,1),%r12d
  cmp    $0x46,%edi
  je     L33
  mov    $0x46,%ebx
  nopl   0x0(%rax)
L36:
  lea    0x76c(%rbx),%edi
  add    $0x1,%ebx
  call   <is_leap_year@plt>
  mov    0x0(%rbp),%edi
  add    %eax,%r12d
  cmp    %ebx,%edi
  jg     L36
  mov    0x4(%rbp),%edx
L33:
  cmp    $0x1,%edx
  jle    L34
  add    $0x76c,%edi
  call   <is_leap_year@plt>
  add    %eax,%r12d
L34:
  mov    0xc(%rbp),%eax
  lea    (%r12,%r12,2),%edx
  lea    (%rax,%rdx,8),%eax
  imul   $0x3c,%eax,%eax
  add    0x10(%rbp),%eax
  imul   $0x3c,%eax,%eax
  add    0x14(%rbp),%eax
L91:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  mov    $0xffffffff,%eax
  jmp    L91
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: 

assistant: ```c
time_t timegm(struct tm *tm) {
  static const unsigned ydays[12 + 1] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  if (tm->tm_year < 70 || tm->tm_mon < 0 || tm->tm_mon > 11 || tm->tm_mday < 1 || tm->tm_mday > 31 || tm->tm_hour < 0 || tm->tm_hour > 23 || tm->tm_min < 0 || tm->tm_min > 59 || tm->tm_sec < 0 || tm->tm_sec > 60)
    return -1;
  unsigned t = 365 * (tm->tm_year - 70) + ydays[tm->tm_mon] + (tm->tm_mday - 1);
  for (int i = 70; i < tm->tm_year; i++)
    t += is_leap_year(1900 + i);
  if (tm->tm_mon > 1)
    t += is_leap_year(1900 + tm->tm_year);
  t *= 24;
  t += tm->tm_hour;
  t *= 60;
  t += tm->tm_min;
  t *= 60;
  t += tm->tm_sec;
  return t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<json_strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  setne  %al
  movzbl %al,%eax
  jmp    L63
L30:
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L63
L57:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  mov    $0x0,%eax
  jmp    L63
L22:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L57
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L63:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int json_strcasecmp(const char *s1, const char *s2) {
  if (!s1)
    return (s1 == s2) ? 0 : 1;
  if (!s2)
    return 1;
  for (; tolower(*s1) == tolower(*s2); ++s1, ++s2)
    if (*s1 == 0)
      return 0;
  return tolower(*(const unsigned char *)s1) - tolower(*(const unsigned char *)s2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<json_strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  test   %rdi,%rdi
  je     L7
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L72
L79:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  movzbl (%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L45
  cmpb   $0x0,(%rbx)
  je     L23
  add    $0x1,%rbx
  add    $0x1,%r12
  jmp    L79
L7:
  test   %rsi,%rsi
  setne  %al
  movzbl %al,%eax
  jmp    L44
L45:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L72:
  mov    $0x1,%eax
  jmp    L44
L23:
  mov    $0x0,%eax
  jmp    L44
```

assistant: ```c
int json_strcasecmp(const char *s1, const char *s2) {
  if (!s1)
    return (s1 == s2) ? 0 : 1;
  if (!s2)
    return 1;
  for (; tolower(*s1) == tolower(*s2); ++s1, ++s2)
    if (*s1 == 0)
      return 0;
  return tolower(*(const unsigned char *)s1) - tolower(*(const unsigned char *)s2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<json_strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L45
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L26
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L40:
  cmpb   $0x0,(%rbx)
  je     L4
  add    $0x1,%rbx
  add    $0x1,%r12
L26:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L40
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  test   %rsi,%rsi
  pop    %rbx
  pop    %rbp
  setne  %al
  pop    %r12
  ret
  nopl   (%rax)
L8:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int json_strcasecmp(const char *s1, const char *s2) {
  if (!s1)
    return (s1 == s2) ? 0 : 1;
  if (!s2)
    return 1;
  for (; tolower(*s1) == tolower(*s2); ++s1, ++s2)
    if (*s1 == 0)
      return 0;
  return tolower(*(const unsigned char *)s1) - tolower(*(const unsigned char *)s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<json_strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L14
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L18
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L7:
  cmpb   $0x0,(%rbx)
  je     L36
  add    $0x1,%rbx
  add    $0x1,%r12
L18:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L7
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  test   %rsi,%rsi
  pop    %rbx
  pop    %rbp
  setne  %al
  pop    %r12
  ret
  nopl   (%rax)
L25:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int json_strcasecmp(const char *s1, const char *s2) {
  if (!s1)
    return (s1 == s2) ? 0 : 1;
  if (!s2)
    return 1;
  for (; tolower(*s1) == tolower(*s2); ++s1, ++s2)
    if (*s1 == 0)
      return 0;
  return tolower(*(const unsigned char *)s1) - tolower(*(const unsigned char *)s2);
}
```
user: What is the c source code of the assembly code below:

```asm
<ppp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %rcx,%r11
  cmp    %r9d,%r8d
  mov    %r9d,%ebp
  cmovle %r8d,%ebp
  cmp    $0x1,%ebp
  jle    L52
  movslq %r9d,%rax
  lea    0x8(,%rax,8),%r10
  mov    %rbx,%rdx
  lea    -0x1(%rbp),%ecx
  mov    $0x0,%eax
L68:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,0x8(%rdx)
  add    $0x1,%rax
  add    %r10,%rdx
  cmp    %rcx,%rax
  jne    L68
L52:
  movslq %ebp,%rdx
  shl    $0x3,%rdx
  lea    -0x1(%rbp),%eax
  imul   %r9d,%eax
  add    %ebp,%eax
  cltq
  movsd  -0x8(%rsi,%rdx,1),%xmm0
  movsd  %xmm0,-0x8(%rbx,%rax,8)
  cmp    %r9d,%r8d
  jge    L28
  movsd  -0x8(%rdi,%rdx,1),%xmm0
  movsd  %xmm0,(%rbx,%rax,8)
L28:
  cmp    $0x1,%r9d
  jle    L64
  lea    0x1(%r9),%ebx
  movslq %r9d,%rsi
  shl    $0x3,%rsi
  mov    $0x1,%r10d
  mov    $0x2,%edi
  mov    $0x0,%r8d
  lea    0x8(%r11),%rbp
L32:
  cmp    %edi,%r9d
  jl     L18
  movslq %r8d,%rcx
  lea    -0x1(%rcx,%rdi,1),%rax
  lea    (%r11,%rax,8),%rax
  lea    (%r8,%r9,1),%edx
  movslq %edx,%rdx
  add    %r10,%rdx
  lea    (%r11,%rdx,8),%rdx
  add    %r10,%rcx
  mov    %r9d,%r12d
  sub    %edi,%r12d
  add    %r12,%rcx
  lea    0x0(%rbp,%rcx,8),%rcx
L50:
  movsd  (%rax),%xmm0
  movsd  -0x8(%rdx),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,-0x8(%rdx)
  add    $0x8,%rax
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L50
L18:
  add    %r9d,%r8d
  add    $0x1,%rdi
  add    $0x1,%r10
  cmp    %rbx,%rdi
  jne    L32
L64:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ppp(double a[], double e[], double s[], double v[], int m, int n) {
  int i, j, p, q;
  double d;
  if (m >= n)
    i = n;
  else
    i = m;
  for (j = 1; j <= i - 1; j++) {
    a[(j - 1) * n + j - 1] = s[j - 1];
    a[(j - 1) * n + j] = e[j - 1];
  }
  a[(i - 1) * n + i - 1] = s[i - 1];
  if (m < n)
    a[(i - 1) * n + i] = e[i - 1];
  for (i = 1; i <= n - 1; i++)
    for (j = i + 1; j <= n; j++) {
      p = (i - 1) * n + j - 1;
      q = (j - 1) * n + i - 1;
      d = v[p];
      v[p] = v[q];
      v[q] = d;
    }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ppp>:
  endbr64
  push   %r12
  cmp    %r9d,%r8d
  mov    %r9d,%r12d
  mov    %rdi,%r11
  cmovle %r8d,%r12d
  push   %rbp
  mov    %rsi,%rdi
  mov    %rcx,%r10
  push   %rbx
  mov    %rdx,%rsi
  lea    -0x1(%r12),%ecx
  cmp    $0x1,%r12d
  jle    L4
  movslq %r9d,%rax
  lea    -0x1(%r12),%ebx
  mov    %r11,%rdx
  lea    0x8(,%rax,8),%rbp
  mov    %rbx,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L39:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  movsd  %xmm0,0x8(%rdx)
  add    %rbp,%rdx
  cmp    %rbx,%rax
  jne    L39
L4:
  imul   %r9d,%ecx
  movslq %r12d,%rdx
  shl    $0x3,%rdx
  movsd  -0x8(%rsi,%rdx,1),%xmm0
  lea    (%rcx,%r12,1),%eax
  cltq
  movsd  %xmm0,-0x8(%r11,%rax,8)
  cmp    %r9d,%r8d
  jge    L53
  movsd  -0x8(%rdi,%rdx,1),%xmm0
  movsd  %xmm0,(%r11,%rax,8)
L53:
  cmp    $0x1,%r9d
  jle    L55
  movslq %r9d,%rsi
  lea    0x1(%r9),%ebx
  mov    $0x1,%r11d
  xor    %edx,%edx
  shl    $0x3,%rsi
  mov    $0x2,%edi
  lea    0x8(%r10),%rbp
  nopl   0x0(%rax)
L46:
  lea    (%rdx,%r9,1),%r8d
  cmp    %edi,%r9d
  jl     L32
  movslq %edx,%rcx
  lea    (%rdx,%r9,1),%r8d
  mov    %r9d,%r12d
  lea    -0x1(%rcx,%rdi,1),%rax
  movslq %r8d,%rdx
  sub    %edi,%r12d
  add    %r11,%rcx
  add    %r11,%rdx
  add    %r12,%rcx
  lea    (%r10,%rax,8),%rax
  lea    (%r10,%rdx,8),%rdx
  lea    0x0(%rbp,%rcx,8),%rcx
  nopl   0x0(%rax)
L18:
  movsd  -0x8(%rdx),%xmm1
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,-0x8(%rdx)
  add    %rsi,%rdx
  cmp    %rcx,%rax
  jne    L18
L32:
  add    $0x1,%rdi
  mov    %r8d,%edx
  add    $0x1,%r11
  cmp    %rbx,%rdi
  jne    L46
L55:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ppp(double a[], double e[], double s[], double v[], int m, int n) {
  int i, j, p, q;
  double d;
  if (m >= n)
    i = n;
  else
    i = m;
  for (j = 1; j <= i - 1; j++) {
    a[(j - 1) * n + j - 1] = s[j - 1];
    a[(j - 1) * n + j] = e[j - 1];
  }
  a[(i - 1) * n + i - 1] = s[i - 1];
  if (m < n)
    a[(i - 1) * n + i] = e[i - 1];
  for (i = 1; i <= n - 1; i++)
    for (j = i + 1; j <= n; j++) {
      p = (i - 1) * n + j - 1;
      q = (j - 1) * n + i - 1;
      d = v[p];
      v[p] = v[q];
      v[q] = d;
    }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ppp>:
  endbr64
  push   %r12
  cmp    %r9d,%r8d
  mov    %r9d,%r12d
  mov    %rdi,%r11
  cmovle %r8d,%r12d
  push   %rbp
  mov    %rsi,%rdi
  mov    %rcx,%r10
  push   %rbx
  mov    %rdx,%rsi
  lea    -0x1(%r12),%ecx
  cmp    $0x1,%r12d
  jle    L22
  movslq %r9d,%rax
  lea    -0x1(%r12),%ebx
  mov    %r11,%rdx
  lea    0x8(,%rax,8),%rbp
  mov    %rbx,%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L45:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx)
  movsd  (%rdi,%rax,8),%xmm0
  add    $0x1,%rax
  movsd  %xmm0,0x8(%rdx)
  add    %rbp,%rdx
  cmp    %rax,%rbx
  jne    L45
L22:
  imul   %r9d,%ecx
  movslq %r12d,%rdx
  shl    $0x3,%rdx
  movsd  -0x8(%rsi,%rdx,1),%xmm0
  lea    (%rcx,%r12,1),%eax
  cltq
  movsd  %xmm0,-0x8(%r11,%rax,8)
  cmp    %r9d,%r8d
  jge    L56
  movsd  -0x8(%rdi,%rdx,1),%xmm0
  movsd  %xmm0,(%r11,%rax,8)
L56:
  cmp    $0x1,%r9d
  jle    L27
  movslq %r9d,%rsi
  lea    0x1(%r9),%ebx
  mov    $0x1,%r11d
  xor    %edx,%edx
  shl    $0x3,%rsi
  mov    $0x2,%edi
  lea    0x8(%r10),%rbp
  nopl   0x0(%rax)
L5:
  lea    (%r9,%rdx,1),%r8d
  cmp    %edi,%r9d
  jl     L35
  movslq %edx,%rcx
  lea    (%r9,%rdx,1),%r8d
  mov    %r9d,%r12d
  lea    -0x1(%rdi,%rcx,1),%rax
  movslq %r8d,%rdx
  sub    %edi,%r12d
  add    %r11,%rcx
  add    %r11,%rdx
  add    %r12,%rcx
  lea    (%r10,%rax,8),%rax
  lea    (%r10,%rdx,8),%rdx
  lea    0x0(%rbp,%rcx,8),%rcx
  nopl   0x0(%rax)
L29:
  movsd  -0x8(%rdx),%xmm1
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,-0x8(%rdx)
  add    %rsi,%rdx
  cmp    %rax,%rcx
  jne    L29
L35:
  add    $0x1,%rdi
  mov    %r8d,%edx
  add    $0x1,%r11
  cmp    %rdi,%rbx
  jne    L5
L27:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void ppp(double a[], double e[], double s[], double v[], int m, int n) {
  int i, j, p, q;
  double d;
  if (m >= n)
    i = n;
  else
    i = m;
  for (j = 1; j <= i - 1; j++) {
    a[(j - 1) * n + j - 1] = s[j - 1];
    a[(j - 1) * n + j] = e[j - 1];
  }
  a[(i - 1) * n + i - 1] = s[i - 1];
  if (m < n)
    a[(i - 1) * n + i] = e[i - 1];
  for (i = 1; i <= n - 1; i++)
    for (j = i + 1; j <= n; j++) {
      p = (i - 1) * n + j - 1;
      q = (j - 1) * n + i - 1;
      d = v[p];
      v[p] = v[q];
      v[q] = d;
    }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fibseq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L13
L14:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L14
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D0
data_type: string

tool: D5: Fibonacci Series:

tool: D0:  %u

assistant: ```c
void fibseq(unsigned n) {
  unsigned i, x, y, t;
  puts("Fibonacci Series:");
  for (i = 0, x = y = 1; i < n; ++i) {
    printf(" %u", t = x);
    x = y;
    y += t;
  }
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fibseq>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  lea    D10(%rip),%rdi
  call   <puts@plt>
  test   %r13d,%r13d
  je     L12
  mov    $0x1,%r12d
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  lea    D3(%rip),%r14
  jmp    L27
L25:
  mov    %eax,%r12d
L27:
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  lea    0x0(%rbp,%r12,1),%eax
  add    $0x1,%ebx
  mov    %r12d,%ebp
  cmp    %ebx,%r13d
  jne    L25
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D3
datatype: string

tool: D10: Fibonacci Series:

tool: D3:  %u

assistant: ```c
void fibseq(unsigned n) {
  unsigned i, x, y, t;
  puts("Fibonacci Series:");
  for (i = 0, x = y = 1; i < n; ++i) {
    printf(" %u", t = x);
    x = y;
    y += t;
  }
  putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<fibseq>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  lea    D4(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  call   <puts@plt>
  test   %r13d,%r13d
  je     L8
  mov    $0x1,%r12d
  mov    $0x1,%ebp
  xor    %ebx,%ebx
  lea    D5(%rip),%r14
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %eax,%r12d
L24:
  mov    %ebp,%esi
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  lea    0x0(%rbp,%r12,1),%eax
  mov    %r12d,%ebp
  cmp    %ebx,%r13d
  jne    L3
L8:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: D4: Fibonacci Series:

tool: D5:  %u

assistant: ```c
void fibseq(unsigned n) {
  unsigned i, x, y, t;
  puts("Fibonacci Series:");
  for (i = 0, x = y = 1; i < n; ++i) {
    printf(" %u", t = x);
    x = y;
    y += t;
  }
  putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fibseq>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  lea    D5(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  call   <puts@plt>
  test   %r13d,%r13d
  je     L14
  mov    $0x1,%r12d
  mov    $0x1,%ebp
  xor    %ebx,%ebx
  lea    D13(%rip),%r14
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %eax,%r12d
L22:
  mov    %ebp,%esi
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  lea    0x0(%rbp,%r12,1),%eax
  mov    %r12d,%ebp
  cmp    %ebx,%r13d
  jne    L0
L14:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D5: Fibonacci Series:

tool: D13:  %u

assistant: ```c
void fibseq(unsigned n) {
  unsigned i, x, y, t;
  puts("Fibonacci Series:");
  for (i = 0, x = y = 1; i < n; ++i) {
    printf(" %u", t = x);
    x = y;
    y += t;
  }
  putchar('\n');
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap_double>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_double(double *a, double *b) {
  double t;
  t = *a;
  *a = *b;
  *b = t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<swap_double>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void swap_double(double *a, double *b) {
  double t;
  t = *a;
  *a = *b;
  *b = t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_double>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void swap_double(double *a, double *b) {
  double t;
  t = *a;
  *a = *b;
  *b = t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_double>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
void swap_double(double *a, double *b) {
  double t;
  t = *a;
  *a = *b;
  *b = t;
}
```