ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  lea    D82(%rip),%rdi
  lea    D11(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x64655a,0x9(%rsp)
  movabs $0x53202e412064655a,%rax
  mov    %rax,0xd(%rsp)
  mov    $0x6168,%eax
  mov    %ax,0x15(%rsp)
  xor    %eax,%eax
  movb   $0x77,0x17(%rsp)
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D45(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D86(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xa,%esi
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D62(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xb,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0xd(%rsp),%rdx
  lea    0x9(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D82
type: string
name: unpack_data
arguments: data_tag: D11
type: string
name: unpack_data
arguments: data_tag: D45
type: string
name: unpack_data
arguments: data_tag: D86
type: string
name: unpack_data
arguments: data_tag: D46
type: string
name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D62
type: string
name: unpack_data
arguments: data_tag: D30
type: string
name: unpack_data
arguments: data_tag: D25
type: string

tool: D82: The size of an int: %ld


tool: D11: The number of chars: %ld


tool: D45: The size of areas (int[]): %ld


tool: D86: The number of ints in areas: %ld


tool: D46: The first area is %d, the 2nd %d.


tool: D5: The size of a char: %ld
.

tool: D62: The size of name (char[]): %ld


tool: D30: The size of full_name (char[]): %ld


tool: D25: name="%s" and full_name="%s"


assistant: ```c
int main(int argc, char *argv[]) {
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Zed";
  char full_name[] = {'Z', 'e', 'd', ' ', 'A', '.', ' ', 'S', 'h', 'a', 'w'};
  printf("The size of an int: %ld\n", sizeof(int));
  printf("The size of areas (int[]): %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd %d.\n", areas[0], areas[1]);
  printf("The size of a char: %ld\n.", sizeof(char));
  printf("The size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full_name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars: %ld\n", sizeof(full_name) / sizeof(char));
  printf("name=\"%s\" and full_name=\"%s\"\n", name, full_name);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<int_comp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L35
  mov    $0xffffffff,%eax
  jmp    L17
L35:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L25
  mov    $0x1,%eax
  jmp    L17
L25:
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int int_comp(const void *r1_ptr, const void *r2_ptr) {
  int *r1 = (int *)r1_ptr;
  int *r2 = (int *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<int_comp>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jl     L8
  setg   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int int_comp(const void *r1_ptr, const void *r2_ptr) {
  int *r1 = (int *)r1_ptr;
  int *r2 = (int *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<int_comp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int int_comp(const void *r1_ptr, const void *r2_ptr) {
  int *r1 = (int *)r1_ptr;
  int *r2 = (int *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<int_comp>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  mov    $0xffffffff,%edx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int int_comp(const void *r1_ptr, const void *r2_ptr) {
  int *r1 = (int *)r1_ptr;
  int *r2 = (int *)r2_ptr;
  if (*r1 < *r2)
    return (-1);
  else if (*r1 > *r2)
    return (1);
  else
    return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<qpartition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
L41:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L17
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jg     L41
L17:
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L19
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  js     L17
L19:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L49
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L41
L49:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int qpartition(void **array, int a, int b, int (*compare)(void *, void *)) {
  void *z;
  int i = a - 1;
  int j = b + 1;
  void *tmp = NULL;
  z = array[a];
  while (1) {
    do {
      j--;
    } while (j > a && compare(array[j], z) > 0);
    do {
      i++;
    } while (i <= j && compare(array[i], z) < 0);
    if (i < j) {
      tmp = array[i];
      array[i] = array[j];
      array[j] = tmp;
    } else {
      return j;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<qpartition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%eax
  mov    %esi,0xc(%rsp)
  mov    %rcx,%r14
  lea    -0x1(%rsi),%ecx
  mov    %ecx,0x4(%rsp)
  cltq
  mov    (%rdi,%rax,8),%r15
  movslq %edx,%r13
  jmp    L22
L24:
  mov    0x4(%rsp),%ebx
  add    $0x1,%ebx
  movslq %ebx,%rbx
L51:
  mov    %ebx,0x4(%rsp)
  cmp    %ebx,%r12d
  jl     L14
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r15,%rsi
  call   *%r14
  add    $0x1,%rbx
  test   %eax,%eax
  js     L51
L14:
  mov    0x4(%rsp),%eax
  cmp    %r12d,%eax
  jge    L32
  cltq
  lea    0x0(%rbp,%rax,8),%rax
  mov    (%rax),%rdx
  mov    0x0(%rbp,%r13,8),%rcx
  mov    %rcx,(%rax)
  mov    %rdx,0x0(%rbp,%r13,8)
L23:
  sub    $0x1,%r13
L22:
  mov    %r13d,0x8(%rsp)
  mov    %r13d,%r12d
  cmp    %r13d,0xc(%rsp)
  jge    L24
  mov    0x0(%rbp,%r13,8),%rdi
  mov    %r15,%rsi
  call   *%r14
  test   %eax,%eax
  jg     L23
  jmp    L24
L32:
  mov    0x8(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int qpartition(void **array, int a, int b, int (*compare)(void *, void *)) {
  void *z;
  int i = a - 1;
  int j = b + 1;
  void *tmp = NULL;
  z = array[a];
  while (1) {
    do {
      j--;
    } while (j > a && compare(array[j], z) > 0);
    do {
      i++;
    } while (i <= j && compare(array[i], z) < 0);
    if (i < j) {
      tmp = array[i];
      array[i] = array[j];
      array[j] = tmp;
    } else {
      return j;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<qpartition>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  lea    -0x1(%rax),%r15d
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rdi,%rax,8),%r14
  mov    %rdi,0x10(%rsp)
  mov    %eax,0x1c(%rsp)
  mov    %rcx,0x8(%rsp)
  jmp    L45
L3:
  mov    0x10(%rsp),%rax
  mov    %r14,%rsi
  mov    (%rax,%rbp,8),%rdi
  mov    0x8(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jle    L68
L74:
  sub    $0x1,%rbp
L45:
  mov    %ebp,0x18(%rsp)
  mov    %ebp,%ebx
  cmp    %ebp,0x1c(%rsp)
  jl     L3
L68:
  mov    0x10(%rsp),%rdx
  movslq %r15d,%rax
  lea    0x8(%rdx,%rax,8),%r13
  jmp    L42
  cs nopw 0x0(%rax,%rax,1)
L52:
  mov    0x0(%r13),%rdi
  mov    0x8(%rsp),%rax
  mov    %r14,%rsi
  mov    %r13,%r12
  call   *%rax
  add    $0x8,%r13
  test   %eax,%eax
  jns    L62
L42:
  add    $0x1,%r15d
  cmp    %ebx,%r15d
  jle    L52
L4:
  mov    0x18(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L62:
  cmp    %ebx,%r15d
  jge    L4
  mov    0x10(%rsp),%rcx
  mov    (%r12),%rax
  mov    (%rcx,%rbp,8),%rdx
  mov    %rdx,(%r12)
  mov    %rax,(%rcx,%rbp,8)
  jmp    L74
```

assistant: ```c
int qpartition(void **array, int a, int b, int (*compare)(void *, void *)) {
  void *z;
  int i = a - 1;
  int j = b + 1;
  void *tmp = NULL;
  z = array[a];
  while (1) {
    do {
      j--;
    } while (j > a && compare(array[j], z) > 0);
    do {
      i++;
    } while (i <= j && compare(array[i], z) < 0);
    if (i < j) {
      tmp = array[i];
      array[i] = array[j];
      array[j] = tmp;
    } else {
      return j;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qpartition>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  lea    -0x1(%rax),%r15d
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rdi,%rax,8),%r14
  mov    %rdi,0x10(%rsp)
  mov    %eax,0x1c(%rsp)
  mov    %rcx,0x8(%rsp)
  jmp    L48
L54:
  mov    0x10(%rsp),%rax
  mov    %r14,%rsi
  mov    (%rax,%rbp,8),%rdi
  mov    0x8(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  jle    L75
L40:
  sub    $0x1,%rbp
L48:
  mov    %ebp,0x18(%rsp)
  mov    %ebp,%ebx
  cmp    %ebp,0x1c(%rsp)
  jl     L54
L75:
  mov    0x10(%rsp),%rdx
  movslq %r15d,%rax
  lea    0x8(%rdx,%rax,8),%r13
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L61:
  mov    0x0(%r13),%rdi
  mov    0x8(%rsp),%rax
  mov    %r14,%rsi
  mov    %r13,%r12
  call   *%rax
  add    $0x8,%r13
  test   %eax,%eax
  jns    L77
L68:
  add    $0x1,%r15d
  cmp    %ebx,%r15d
  jle    L61
L4:
  mov    0x18(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L77:
  cmp    %ebx,%r15d
  jge    L4
  mov    0x10(%rsp),%rcx
  mov    (%r12),%rax
  mov    (%rcx,%rbp,8),%rdx
  mov    %rdx,(%r12)
  mov    %rax,(%rcx,%rbp,8)
  jmp    L40
```

assistant: ```c
int qpartition(void **array, int a, int b, int (*compare)(void *, void *)) {
  void *z;
  int i = a - 1;
  int j = b + 1;
  void *tmp = NULL;
  z = array[a];
  while (1) {
    do {
      j--;
    } while (j > a && compare(array[j], z) > 0);
    do {
      i++;
    } while (i <= j && compare(array[i], z) < 0);
    if (i < j) {
      tmp = array[i];
      array[i] = array[j];
      array[j] = tmp;
    } else {
      return j;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetNextStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movb   $0x0,D3(%rip)
  cmpq   $0x0,-0x28(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L84
L17:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <NextStr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L56
  lea    D3(%rip),%rax
  jmp    L84
L56:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <NextBlank@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  lea    D3(%rip),%rax
  jmp    L84
L6:
  movl   $0x0,-0x14(%rbp)
  jmp    L77
L60:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %ecx,-0x14(%rbp)
  movzbl (%rax),%ecx
  movslq %edx,%rax
  lea    D3(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
L77:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L3
  cmpl   $0x62,-0x14(%rbp)
  jle    L60
L3:
  mov    -0x14(%rbp),%eax
  cltq
  lea    D3(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D3(%rip),%rax
L84:
  leave
  ret
```

assistant: ```c
const char *GetNextStr(char *pBuffer) {
  static char buff[100] = {0};
  buff[0] = '\0';
  if (!pBuffer)
    return NULL;
  char *p1 = NextStr(pBuffer);
  if (!p1)
    return buff;
  char *p2 = NextBlank(p1);
  if (!p2)
    return buff;
  int i = 0;
  while (p1 != p2 && i < 99)
    buff[i++] = *(p1++);
  buff[i] = '\0';
  return buff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetNextStr>:
  endbr64
  movb   $0x0,D15(%rip)
  test   %rdi,%rdi
  je     L54
  push   %rbx
  call   <NextStr@plt>
  mov    %rax,%rbx
  lea    D15(%rip),%rax
  test   %rbx,%rbx
  je     L26
  mov    %rbx,%rdi
  call   <NextBlank@plt>
  mov    %rax,%rdi
  lea    D15(%rip),%rax
  test   %rdi,%rdi
  je     L26
  cmp    %rdi,%rbx
  je     L22
  mov    $0x1,%edx
  lea    -0x1(%rax),%rax
L41:
  add    $0x1,%rbx
  mov    %edx,%r8d
  movzbl -0x1(%rbx),%ecx
  mov    %cl,(%rdx,%rax,1)
  cmp    %rbx,%rdi
  setne  %sil
  cmp    $0x62,%edx
  setle  %cl
  add    $0x1,%rdx
  test   %cl,%sil
  jne    L41
L35:
  lea    D15(%rip),%rax
  movslq %r8d,%r8
  movb   $0x0,(%rax,%r8,1)
L26:
  pop    %rbx
  ret
L22:
  mov    $0x0,%r8d
  jmp    L35
L54:
  mov    %rdi,%rax
  ret
```

assistant: ```c
const char *GetNextStr(char *pBuffer) {
  static char buff[100] = {0};
  buff[0] = '\0';
  if (!pBuffer)
    return NULL;
  char *p1 = NextStr(pBuffer);
  if (!p1)
    return buff;
  char *p2 = NextBlank(p1);
  if (!p2)
    return buff;
  int i = 0;
  while (p1 != p2 && i < 99)
    buff[i++] = *(p1++);
  buff[i] = '\0';
  return buff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GetNextStr>:
  endbr64
  movb   $0x0,D35(%rip)
  test   %rdi,%rdi
  je     L28
  push   %rbx
  call   <NextStr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
  mov    %rax,%rdi
  call   <NextBlank@plt>
  test   %rax,%rax
  je     L15
  cmp    %rax,%rbx
  je     L18
  mov    $0x1,%edx
  lea    D36(%rip),%r8
  nopl   0x0(%rax)
L56:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%ecx
  movslq %edx,%rdi
  cmp    %rbx,%rax
  setne  %sil
  cmp    $0x62,%edx
  mov    %cl,(%r8,%rdx,1)
  setle  %cl
  add    $0x1,%rdx
  test   %cl,%sil
  jne    L56
L1:
  lea    D35(%rip),%rax
  movb   $0x0,(%rax,%rdi,1)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  lea    D35(%rip),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L28:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %edi,%edi
  jmp    L1
```

assistant: ```c
const char *GetNextStr(char *pBuffer) {
  static char buff[100] = {0};
  buff[0] = '\0';
  if (!pBuffer)
    return NULL;
  char *p1 = NextStr(pBuffer);
  if (!p1)
    return buff;
  char *p2 = NextBlank(p1);
  if (!p2)
    return buff;
  int i = 0;
  while (p1 != p2 && i < 99)
    buff[i++] = *(p1++);
  buff[i] = '\0';
  return buff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GetNextStr>:
  endbr64
  movb   $0x0,D20(%rip)
  test   %rdi,%rdi
  je     L53
  push   %rbx
  call   <NextStr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L59
  mov    %rax,%rdi
  call   <NextBlank@plt>
  test   %rax,%rax
  je     L59
  cmp    %rax,%rbx
  je     L47
  mov    $0x1,%edx
  lea    D17(%rip),%r8
  nopl   0x0(%rax)
L49:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%ecx
  movslq %edx,%rdi
  cmp    %rbx,%rax
  setne  %sil
  cmp    $0x62,%edx
  mov    %cl,(%r8,%rdx,1)
  setle  %cl
  add    $0x1,%rdx
  test   %cl,%sil
  jne    L49
L38:
  lea    D20(%rip),%rax
  movb   $0x0,(%rax,%rdi,1)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  lea    D20(%rip),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L53:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  xor    %edi,%edi
  jmp    L38
```

assistant: ```c
const char *GetNextStr(char *pBuffer) {
  static char buff[100] = {0};
  buff[0] = '\0';
  if (!pBuffer)
    return NULL;
  char *p1 = NextStr(pBuffer);
  if (!p1)
    return buff;
  char *p2 = NextBlank(p1);
  if (!p2)
    return buff;
  int i = 0;
  while (p1 != p2 && i < 99)
    buff[i++] = *(p1++);
  buff[i] = '\0';
  return buff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unquote_and_strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <unquote@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L36
L11:
  addq   $0x1,-0x18(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L16
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
L16:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <emalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L55
  mov    -0x10(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L55
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L55:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L22
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L22
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L22:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *unquote_and_strip(char *line) {
  char *p = unquote(line);
  char *p2;
  char *cvtd_line;
  while (*p && isspace(*p))
    ++p;
  cvtd_line = (char *)emalloc(strlen(p) + 1);
  strcpy(cvtd_line, p);
  p2 = cvtd_line + strlen(cvtd_line);
  if (p2 > cvtd_line && p2[-1] == '\n')
    *--p2 = 0;
  if (p2 > cvtd_line && *--p2 == '-')
    *p2 = 0;
  return cvtd_line;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unquote_and_strip>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <unquote@plt>
  mov    %rax,%rbx
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L8
L47:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L8
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L47
L8:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <emalloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbp,%rax
  cmp    %rax,%rbp
  jae    L67
  cmpb   $0xa,-0x1(%rax)
  je     L82
L65:
  cmpb   $0x2d,-0x1(%rax)
  je     L27
L67:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L82:
  lea    -0x1(%rax),%rdx
  movb   $0x0,-0x1(%rax)
  cmp    %rdx,%rbp
  jae    L67
  mov    %rdx,%rax
  jmp    L65
L27:
  movb   $0x0,-0x1(%rax)
  jmp    L67
```

assistant: ```c
char *unquote_and_strip(char *line) {
  char *p = unquote(line);
  char *p2;
  char *cvtd_line;
  while (*p && isspace(*p))
    ++p;
  cvtd_line = (char *)emalloc(strlen(p) + 1);
  strcpy(cvtd_line, p);
  p2 = cvtd_line + strlen(cvtd_line);
  if (p2 > cvtd_line && p2[-1] == '\n')
    *--p2 = 0;
  if (p2 > cvtd_line && *--p2 == '-')
    *p2 = 0;
  return cvtd_line;
}
```
user: What is the c source code of the assembly code below:

```asm
<unquote_and_strip>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <unquote@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L92
  jmp    L81
  nopl   (%rax)
L77:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L81
L92:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L77
L81:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <emalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  cmp    %rax,%r12
  jae    L55
  movzbl -0x1(%rax),%edx
  cmp    $0xa,%dl
  je     L48
  cmp    $0x2d,%dl
  je     L56
L55:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L56:
  movb   $0x0,-0x1(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L48:
  lea    -0x1(%rax),%rcx
  movb   $0x0,-0x1(%rax)
  cmp    %rcx,%r12
  jae    L55
  movzbl -0x2(%rax),%edx
  mov    %rcx,%rax
  cmp    $0x2d,%dl
  jne    L55
  jmp    L56
```

assistant: ```c
char *unquote_and_strip(char *line) {
  char *p = unquote(line);
  char *p2;
  char *cvtd_line;
  while (*p && isspace(*p))
    ++p;
  cvtd_line = (char *)emalloc(strlen(p) + 1);
  strcpy(cvtd_line, p);
  p2 = cvtd_line + strlen(cvtd_line);
  if (p2 > cvtd_line && p2[-1] == '\n')
    *--p2 = 0;
  if (p2 > cvtd_line && *--p2 == '-')
    *p2 = 0;
  return cvtd_line;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unquote_and_strip>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <unquote@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L25
  jmp    L85
  nopl   (%rax)
L83:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L85
L25:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L83
L85:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <emalloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  add    %r12,%rax
  cmp    %rax,%r12
  jae    L10
  movzbl -0x1(%rax),%edx
  cmp    $0xa,%dl
  je     L48
  cmp    $0x2d,%dl
  je     L2
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L2:
  movb   $0x0,-0x1(%rax)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L48:
  lea    -0x1(%rax),%rcx
  movb   $0x0,-0x1(%rax)
  cmp    %rcx,%r12
  jae    L10
  movzbl -0x2(%rax),%edx
  mov    %rcx,%rax
  cmp    $0x2d,%dl
  jne    L10
  jmp    L2
```

assistant: ```c
char *unquote_and_strip(char *line) {
  char *p = unquote(line);
  char *p2;
  char *cvtd_line;
  while (*p && isspace(*p))
    ++p;
  cvtd_line = (char *)emalloc(strlen(p) + 1);
  strcpy(cvtd_line, p);
  p2 = cvtd_line + strlen(cvtd_line);
  if (p2 > cvtd_line && p2[-1] == '\n')
    *--p2 = 0;
  if (p2 > cvtd_line && *--p2 == '-')
    *p2 = 0;
  return cvtd_line;
}
```