ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mxCallocInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L10
L38:
  test   %ebx,%ebx
  jle    L2
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L2:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rsp,%rbp
  lea    D22(%rip),%r8
  mov    $0x25,%ecx
  mov    %rbp,%rdi
  lea    D26(%rip),%rdx
  lea    D7(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L38
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D22: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/charleseidsness/eispice/refs/heads/master/libs/superlu/SRC/sp_coletree.c

tool: D26: SUPERLU_MALLOC fails for buf in mxCallocInt()

tool: D7: %s at line %d in file %s


assistant: ```c
int *mxCallocInt(int n) {
  register int i;
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in mxCallocInt()", 37, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/charleseidsness/eispice/refs/heads/master/libs/superlu/SRC/sp_coletree.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; i++)
    buf[i] = 0;
  return (buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mxCallocInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x2,%edi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <superlu_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L6:
  test   %ebx,%ebx
  jle    L29
  movslq %ebx,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  shl    $0x2,%rdx
  call   <memset@plt>
L29:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rsp,%rbp
  lea    D19(%rip),%r8
  mov    $0x25,%ecx
  mov    %rbp,%rdi
  lea    D21(%rip),%rdx
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <superlu_abort_and_exit@plt>
  jmp    L6
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D21
data_type: string
name: parse_data
arguments: data_tag: D9
data_type: string

tool: D19: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/charleseidsness/eispice/refs/heads/master/libs/superlu/SRC/sp_coletree.c

tool: D21: SUPERLU_MALLOC fails for buf in mxCallocInt()

tool: D9: %s at line %d in file %s


assistant: ```c
int *mxCallocInt(int n) {
  register int i;
  int *buf;
  buf = (int *)superlu_malloc(n * sizeof(int));
  if (!buf) {
    {
      char msg[256];
      sprintf(msg, "%s at line %d in file %s\n", "SUPERLU_MALLOC fails for buf in mxCallocInt()", 37, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/charleseidsness/eispice/refs/heads/master/libs/superlu/SRC/sp_coletree.c");
      superlu_abort_and_exit(msg);
    };
  }
  for (i = 0; i < n; i++)
    buf[i] = 0;
  return (buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
L13:
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%edi
  mov    -0x10(%rbp),%eax
  cltd
  idiv   %edi
  mov    %eax,%esi
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  sar    $0x1f,%eax
  mov    %eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  imul   %eax,%esi
  mov    %esi,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L13
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D36
data_type: string
name: disassemble_data
arguments: data_tag: D21
data_type: string

tool: D36: %d

tool: D21: 
%d

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  i = 0;
  sum = 0;
  do {
    sum += m - (i / k * (2 * m / 100));
    i++;
  } while (n > i);
  printf("\n%d", sum);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%r9d
  mov    0x14(%rsp),%edi
  movslq %r9d,%r8
  imul   $0x51eb851f,%r8,%r8
  sar    $0x24,%r8
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sub    %eax,%r8d
  mov    0xc(%rsp),%r10d
  mov    $0x0,%esi
  mov    $0x0,%ecx
L11:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  imul   %r8d,%eax
  mov    %r9d,%edx
  sub    %eax,%edx
  add    %edx,%esi
  add    $0x1,%ecx
  cmp    %ecx,%r10d
  jg     L11
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D7
type_guessed: string

tool: D17: %d

tool: D7: 
%d

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  i = 0;
  sum = 0;
  do {
    sum += m - (i / k * (2 * m / 100));
    i++;
  } while (n > i);
  printf("\n%d", sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x10(%rsp),%r8
  mov    0x14(%rsp),%edi
  xor    %esi,%esi
  mov    0xc(%rsp),%r10d
  xor    %ecx,%ecx
  mov    %r8,%r9
  imul   $0x51eb851f,%r8,%r8
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sar    $0x24,%r8
  sub    %eax,%r8d
L14:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cltd
  idiv   %edi
  mov    %r9d,%edx
  imul   %r8d,%eax
  sub    %eax,%edx
  add    %edx,%esi
  cmp    %ecx,%r10d
  jg     L14
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string

tool: D4: %d

tool: D11: 
%d

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  i = 0;
  sum = 0;
  do {
    sum += m - (i / k * (2 * m / 100));
    i++;
  } while (n > i);
  printf("\n%d", sum);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movslq 0x10(%rsp),%r8
  mov    0x14(%rsp),%edi
  xor    %esi,%esi
  mov    0xc(%rsp),%r10d
  xor    %ecx,%ecx
  mov    %r8,%r9
  imul   $0x51eb851f,%r8,%r8
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sar    $0x24,%r8
  sub    %eax,%r8d
L13:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cltd
  idiv   %edi
  mov    %r9d,%edx
  imul   %r8d,%eax
  sub    %eax,%edx
  add    %edx,%esi
  cmp    %ecx,%r10d
  jg     L13
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string

tool: D14: %d

tool: D17: 
%d

assistant: ```c
int main() {
  int n, m, k, i, sum;
  scanf("%d", &n);
  scanf("%d", &m);
  scanf("%d", &k);
  i = 0;
  sum = 0;
  do {
    sum += m - (i / k * (2 * m / 100));
    i++;
  } while (n > i);
  printf("\n%d", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<l4kdb_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L16
L14:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ser_out@plt>
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L14
  mov    -0x28(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t l4kdb_write(void *data, long int position, size_t count, void *handle) {
  size_t i;
  char *real_data = data;
  for (i = 0; i < count; i++)
    ser_out(real_data[i]);
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<l4kdb_write>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L0
  mov    %rdi,%rbx
  lea    (%rdi,%rdx,1),%rbp
L2:
  movsbl (%rbx),%edi
  call   <ser_out@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L2
L0:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t l4kdb_write(void *data, long int position, size_t count, void *handle) {
  size_t i;
  char *real_data = data;
  for (i = 0; i < count; i++)
    ser_out(real_data[i]);
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<l4kdb_write>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L5
  mov    %rdi,%rbx
  lea    (%rdi,%rdx,1),%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <ser_out@plt>
  cmp    %rbp,%rbx
  jne    L19
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t l4kdb_write(void *data, long int position, size_t count, void *handle) {
  size_t i;
  char *real_data = data;
  for (i = 0; i < count; i++)
    ser_out(real_data[i]);
  return count;
}
```
user: What is the c source code of the assembly code below:

```asm
<l4kdb_write>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  test   %rdx,%rdx
  je     L4
  mov    %rdi,%rbx
  lea    (%rdi,%rdx,1),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <ser_out@plt>
  cmp    %rbp,%rbx
  jne    L18
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t l4kdb_write(void *data, long int position, size_t count, void *handle) {
  size_t i;
  char *real_data = data;
  for (i = 0; i < count; i++)
    ser_out(real_data[i]);
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compare_eq8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int compare_eq8(uint8_t *p1, uint8_t *p2) {
  uint64_t *sp1, *sp2;
  sp1 = (uint64_t *)p1;
  sp2 = (uint64_t *)p2;
  return (p1[0] == p2[0]);
}
```
user: What is the c source code of the assembly code below:

```asm
<compare_eq8>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int compare_eq8(uint8_t *p1, uint8_t *p2) {
  uint64_t *sp1, *sp2;
  sp1 = (uint64_t *)p1;
  sp2 = (uint64_t *)p2;
  return (p1[0] == p2[0]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compare_eq8>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int compare_eq8(uint8_t *p1, uint8_t *p2) {
  uint64_t *sp1, *sp2;
  sp1 = (uint64_t *)p1;
  sp2 = (uint64_t *)p2;
  return (p1[0] == p2[0]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_eq8>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int compare_eq8(uint8_t *p1, uint8_t *p2) {
  uint64_t *sp1, *sp2;
  sp1 = (uint64_t *)p1;
  sp2 = (uint64_t *)p2;
  return (p1[0] == p2[0]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<radixSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L27:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bitReader@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void radixSort(int *Array, int arraySize) {
  int i;
  unsigned *x = (unsigned *)Array;
  for (i = 0; i < arraySize; i++)
    x[i] ^= INT_MIN;
  bitReader(x, x + arraySize, INT_MIN);
  for (i = 0; i < arraySize; i++)
    x[i] ^= INT_MIN;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<radixSort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L26
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rbp
  mov    %rdi,%rax
  mov    D16(%rip),%rcx
L23:
  mov    (%rcx),%edx
  xor    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L23
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rsi
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  call   <bitReader@plt>
  mov    D16(%rip),%rdx
L25:
  mov    (%rdx),%eax
  xor    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L25
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rsi
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  call   <bitReader@plt>
  jmp    L13
```

assistant: ```c
void radixSort(int *Array, int arraySize) {
  int i;
  unsigned *x = (unsigned *)Array;
  for (i = 0; i < arraySize; i++)
    x[i] ^= INT_MIN;
  bitReader(x, x + arraySize, INT_MIN);
  for (i = 0; i < arraySize; i++)
    x[i] ^= INT_MIN;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<radixSort>:
  endbr64
  push   %r12
  movslq %esi,%rax
  push   %rbp
  mov    D3(%rip),%rbp
  lea    (%rdi,%rax,4),%r8
  push   %rbx
  mov    0x0(%rbp),%edx
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x4(%rdi,%rax,4),%r12
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L20:
  mov    0x0(%rbp),%edx
  xor    %edx,(%rax)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L20
  mov    0x0(%rbp),%edx
  mov    %r8,%rsi
  call   <bitReader@plt>
  nopl   0x0(%rax)
L6:
  mov    0x0(%rbp),%eax
  xor    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  pop    %rbx
  mov    %r8,%rsi
  pop    %rbp
  pop    %r12
  jmp    1050 <bitReader@plt>
```

assistant: ```c
void radixSort(int *Array, int arraySize) {
  int i;
  unsigned *x = (unsigned *)Array;
  for (i = 0; i < arraySize; i++)
    x[i] ^= INT_MIN;
  bitReader(x, x + arraySize, INT_MIN);
  for (i = 0; i < arraySize; i++)
    x[i] ^= INT_MIN;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_start_test_lassert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  mov    D1(%rip),%eax
  test   %eax,%eax
  jne    L25
  mov    -0x8(%rbp),%eax
  mov    %eax,D15(%rip)
L25:
  mov    $0xffffffff,%edi
  call   <_nb_tests_lassert@plt>
  jmp    L14
L29:
  movl   $0x0,D15(%rip)
L14:
  mov    D15(%rip),%eax
  leave
  ret
```

assistant: ```c
int _start_test_lassert(int option, int set_start) {
  static int started = 0;
  if (option) {
    if (!started) {
      started = set_start;
    }
    _nb_tests_lassert(-1);
  } else
    started = 0;
  return started;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_start_test_lassert>:
  endbr64
  test   %edi,%edi
  je     L2
  sub    $0x8,%rsp
  cmpl   $0x0,D29(%rip)
  jne    L19
  mov    %esi,D1(%rip)
L19:
  mov    $0xffffffff,%edi
  call   <_nb_tests_lassert@plt>
  mov    D1(%rip),%eax
  add    $0x8,%rsp
  ret
L2:
  movl   $0x0,D1(%rip)
  mov    D1(%rip),%eax
  ret
```

assistant: ```c
int _start_test_lassert(int option, int set_start) {
  static int started = 0;
  if (option) {
    if (!started) {
      started = set_start;
    }
    _nb_tests_lassert(-1);
  } else
    started = 0;
  return started;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_start_test_lassert>:
  endbr64
  test   %edi,%edi
  je     L5
  sub    $0x8,%rsp
  mov    D6(%rip),%eax
  test   %eax,%eax
  jne    L18
  mov    %esi,D35(%rip)
L18:
  mov    $0xffffffff,%edi
  call   <_nb_tests_lassert@plt>
  mov    D35(%rip),%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  movl   $0x0,D35(%rip)
  xor    %eax,%eax
  ret
```

assistant: ```c
int _start_test_lassert(int option, int set_start) {
  static int started = 0;
  if (option) {
    if (!started) {
      started = set_start;
    }
    _nb_tests_lassert(-1);
  } else
    started = 0;
  return started;
}
```
user: What is the c source code of the assembly code below?

```asm
<_start_test_lassert>:
  endbr64
  test   %edi,%edi
  je     L3
  sub    $0x8,%rsp
  mov    D13(%rip),%eax
  test   %eax,%eax
  jne    L19
  mov    %esi,D26(%rip)
L19:
  mov    $0xffffffff,%edi
  call   <_nb_tests_lassert@plt>
  mov    D26(%rip),%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  movl   $0x0,D26(%rip)
  xor    %eax,%eax
  ret
```

assistant: ```c
int _start_test_lassert(int option, int set_start) {
  static int started = 0;
  if (option) {
    if (!started) {
      started = set_start;
    }
    _nb_tests_lassert(-1);
  } else
    started = 0;
  return started;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<current_time_us>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  cltq
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
long current_time_us(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_usec + t.tv_sec * 1000000;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<current_time_us>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  cltq
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long current_time_us(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_usec + t.tv_sec * 1000000;
}
```
user: What is the c source code of the assembly code below:

```asm
<current_time_us>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  cltq
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long current_time_us(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_usec + t.tv_sec * 1000000;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<current_time_us>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x8(%rsp),%eax
  cltq
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long current_time_us(void) {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_usec + t.tv_sec * 1000000;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FileIO_setFileContent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5: w+

assistant: ```c
void FileIO_setFileContent(char *file_path, char *file_content) {
  FILE *fp;
  fp = fopen(file_path, "w+");
  fputs(file_content, fp);
  fclose(fp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FileIO_setFileContent>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <fputs@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: w+

assistant: ```c
void FileIO_setFileContent(char *file_path, char *file_content) {
  FILE *fp;
  fp = fopen(file_path, "w+");
  fputs(file_content, fp);
  fclose(fp);
}
```