ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<printconshelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D24
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D35
data_type: string
name: unpack_data
arguments: tag: D26
data_type: string
name: unpack_data
arguments: tag: D52
data_type: string
name: unpack_data
arguments: tag: D49
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string

tool: D24: Usage: DMCRadio [options]



tool: D4: 	-h	--help			This help


tool: D35: 	-m	--mute			Just mute and exit


tool: D26: 	-r dev	--radiodev dev		Set Radiodevice to dev [/dev/radio]


tool: D52: 	-x dev	--mixerdev dev		Set Mixerdevice to dev [/dev/mixer]


tool: D49: 	-d dev	--dspdev dev		Set DSPdevice to dev [/dev/dsp]


tool: D22: 	-v	--version		Print version and exit



assistant: ```c
void printconshelp(void) {
  printf("Usage: DMCRadio [options]\n\n");
  printf("	-h	--help			This help\n");
  printf("	-m	--mute			Just mute and exit\n");
  printf("	-r dev	--radiodev dev		Set Radiodevice to dev [/dev/radio]\n");
  printf("	-x dev	--mixerdev dev		Set Mixerdevice to dev [/dev/mixer]\n");
  printf("	-d dev	--dspdev dev		Set DSPdevice to dev [/dev/dsp]\n");
  printf("	-v	--version		Print version and exit\n\n");
  exit(-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<minDistance>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r15
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %eax,0x8(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rax,0x18(%rsp)
  mov    %eax,0x4(%rsp)
  lea    0x1(%rax),%ebx
  lea    0x2(%rbp),%edi
  imul   %ebx,%edi
  movslq %edi,%rdi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r14
  mov    %rax,0x28(%rsp)
  lea    0x1(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    %rcx,0x20(%rsp)
  mov    %rcx,%rdi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %ebp,%ebp
  js     L55
  mov    %rax,%r8
  movslq %ebx,%rsi
  shl    $0x2,%rsi
  mov    %r14,%rdx
  mov    %ebp,%edi
  mov    $0x0,%eax
L113:
  mov    %rdx,(%r8,%rax,8)
  mov    %eax,(%rdx)
  mov    %rax,%rcx
  add    $0x1,%rax
  add    %rsi,%rdx
  cmp    %rcx,%rdi
  jne    L113
L55:
  mov    0x18(%rsp),%rax
  test   %eax,%eax
  js     L115
  mov    0x10(%rsp),%rcx
  mov    (%rcx),%rsi
  mov    %eax,%ecx
  mov    $0x0,%eax
L50:
  mov    %eax,(%rsi,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L50
L115:
  test   %ebp,%ebp
  jle    L16
  mov    0x10(%rsp),%r12
  mov    %r13,%r14
  mov    $0x1,%eax
  sub    %r13d,%eax
  mov    %eax,0xc(%rsp)
  jmp    L103
L96:
  mov    0x8(%r12),%r13
  mov    (%r12),%rax
  mov    (%rax,%rbx,4),%esi
  mov    0x0(%r13,%rbp,1),%edi
  mov    $0x0,%eax
  call   <min@plt>
  add    $0x1,%eax
  mov    %eax,0x0(%r13,%rbx,4)
L56:
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jl     L41
L58:
  movzbl -0x1(%r15,%rbx,1),%eax
  cmp    %al,(%r14)
  jne    L96
  mov    (%r12),%rax
  mov    (%rax,%rbp,1),%edx
  mov    0x8(%r12),%rax
  mov    %edx,(%rax,%rbx,4)
  jmp    L56
L41:
  add    $0x8,%r12
  add    $0x1,%r14
  mov    0xc(%rsp),%eax
  add    %r14d,%eax
  cmp    %eax,0x8(%rsp)
  jl     L16
L103:
  mov    $0x0,%ebp
  mov    $0x1,%ebx
  cmpl   $0x0,0x4(%rsp)
  jg     L58
  jmp    L41
L16:
  movslq 0x18(%rsp),%rax
  mov    0x10(%rsp),%rdi
  mov    0x20(%rsp),%rcx
  mov    -0x8(%rdi,%rcx,1),%rdx
  mov    (%rdx,%rax,4),%ebx
  call   <free@plt>
  mov    0x28(%rsp),%rdi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minDistance(char *word1, char *word2) {
  int **dp, *temp, len1, len2, i, j, ret;
  len1 = strlen(word1);
  len2 = strlen(word2);
  temp = (int *)calloc((len1 + 2) * (len2 + 1), sizeof(int));
  dp = (int **)malloc((len1 + 1) * sizeof(int *));
  for (i = 0; i <= len1; ++i) {
    dp[i] = temp + i * (len2 + 1);
    dp[i][0] = i;
  }
  for (j = 0; j <= len2; ++j)
    dp[0][j] = j;
  for (i = 1; i <= len1; ++i) {
    for (j = 1; j <= len2; ++j) {
      if (word1[i - 1] == word2[j - 1])
        dp[i][j] = dp[i - 1][j - 1];
      else
        dp[i][j] = min(dp[i][j - 1], dp[i - 1][j]) + 1;
    }
  }
  ret = dp[len1][len2];
  free(dp);
  free(temp);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<minDistance>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  mov    %eax,0x10(%rsp)
  call   <strlen@plt>
  lea    0x2(%r12),%edi
  mov    $0x4,%esi
  lea    0x1(%r12),%r15d
  lea    0x1(%rax),%r14d
  mov    %rax,0x18(%rsp)
  mov    %eax,%ebx
  movslq %r15d,%r15
  imul   %r14d,%edi
  movslq %edi,%rdi
  call   <calloc@plt>
  mov    %rax,0x20(%rsp)
  lea    0x0(,%r15,8),%rax
  mov    %rax,%rdi
  mov    %rax,0x28(%rsp)
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %r12d,%r12d
  js     L50
  movslq %r14d,%rdx
  mov    %r12d,%r8d
  xor    %eax,%eax
  lea    0x0(,%rdx,4),%rdi
  mov    0x20(%rsp),%rdx
  xchg   %ax,%ax
L76:
  mov    0x8(%rsp),%rcx
  mov    %rax,%rsi
  mov    %eax,(%rdx)
  mov    %rdx,(%rcx,%rax,8)
  add    $0x1,%rax
  add    %rdi,%rdx
  cmp    %rsi,%r8
  jne    L76
L50:
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  js     L73
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%esi
  mov    (%rax),%rdi
  xor    %eax,%eax
L27:
  mov    %rax,%rdx
  mov    %eax,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L27
L73:
  test   %r12d,%r12d
  jle    L105
  mov    $0x1,%r12d
  mov    0x8(%rsp),%r14
  mov    %rbp,%r15
  sub    %ebp,%r12d
  mov    %r12d,0x14(%rsp)
  xchg   %ax,%ax
L21:
  mov    $0x1,%r12d
  test   %ebx,%ebx
  jg     L59
  jmp    L36
  nopl   0x0(%rax)
L82:
  mov    -0x4(%rdi,%rax,1),%eax
  add    $0x1,%r12
  mov    %eax,0x0(%rbp)
  cmp    %r12d,%ebx
  jl     L36
L59:
  mov    0x8(%r14),%rsi
  lea    0x0(,%r12,4),%rax
  mov    (%r14),%rdi
  movzbl -0x1(%r13,%r12,1),%ecx
  lea    (%rsi,%rax,1),%rbp
  cmp    %cl,(%r15)
  je     L82
  mov    (%rdi,%r12,4),%r11d
  mov    -0x4(%rsi,%rax,1),%edi
  xor    %eax,%eax
  add    $0x1,%r12
  mov    %r11d,%esi
  call   <min@plt>
  add    $0x1,%eax
  mov    %eax,0x0(%rbp)
  cmp    %r12d,%ebx
  jge    L59
L36:
  mov    0x14(%rsp),%eax
  add    $0x1,%r15
  add    $0x8,%r14
  add    %r15d,%eax
  cmp    0x10(%rsp),%eax
  jle    L21
L105:
  mov    0x8(%rsp),%rdi
  mov    0x28(%rsp),%rax
  movslq 0x18(%rsp),%r13
  mov    -0x8(%rdi,%rax,1),%rax
  mov    (%rax,%r13,4),%r12d
  call   <free@plt>
  mov    0x20(%rsp),%rdi
  call   <free@plt>
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int minDistance(char *word1, char *word2) {
  int **dp, *temp, len1, len2, i, j, ret;
  len1 = strlen(word1);
  len2 = strlen(word2);
  temp = (int *)calloc((len1 + 2) * (len2 + 1), sizeof(int));
  dp = (int **)malloc((len1 + 1) * sizeof(int *));
  for (i = 0; i <= len1; ++i) {
    dp[i] = temp + i * (len2 + 1);
    dp[i][0] = i;
  }
  for (j = 0; j <= len2; ++j)
    dp[0][j] = j;
  for (i = 1; i <= len1; ++i) {
    for (j = 1; j <= len2; ++j) {
      if (word1[i - 1] == word2[j - 1])
        dp[i][j] = dp[i - 1][j - 1];
      else
        dp[i][j] = min(dp[i][j - 1], dp[i - 1][j]) + 1;
    }
  }
  ret = dp[len1][len2];
  free(dp);
  free(temp);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L25
L3:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    $0x0,%eax
  jmp    L14
L25:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L3
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L14:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const unsigned char *us1 = (const unsigned char *)s1;
  const unsigned char *us2 = (const unsigned char *)s2;
  while (tolower(*us1) == tolower(*us2++)) {
    if (*us1++ == '\0')
      return 0;
  }
  return tolower(*us1) - tolower(*--us2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
L23:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  add    $0x1,%r12
  movzbl -0x1(%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L8
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  jne    L23
  mov    $0x0,%eax
  jmp    L21
L8:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl -0x1(%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const unsigned char *us1 = (const unsigned char *)s1;
  const unsigned char *us2 = (const unsigned char *)s2;
  while (tolower(*us1) == tolower(*us2++)) {
    if (*us1++ == '\0')
      return 0;
  }
  return tolower(*us1) - tolower(*--us2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L15
L3:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L12
L15:
  movzbl (%rbx),%edi
  add    $0x1,%r12
  call   <tolower@plt>
  movzbl -0x1(%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L3
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl -0x1(%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const unsigned char *us1 = (const unsigned char *)s1;
  const unsigned char *us2 = (const unsigned char *)s2;
  while (tolower(*us1) == tolower(*us2++)) {
    if (*us1++ == '\0')
      return 0;
  }
  return tolower(*us1) - tolower(*--us2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L9
L19:
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  je     L11
L9:
  movzbl (%rbx),%edi
  add    $0x1,%r12
  call   <tolower@plt>
  movzbl -0x1(%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L19
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl -0x1(%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const unsigned char *us1 = (const unsigned char *)s1;
  const unsigned char *us2 = (const unsigned char *)s2;
  while (tolower(*us1) == tolower(*us2++)) {
    if (*us1++ == '\0')
      return 0;
  }
  return tolower(*us1) - tolower(*--us2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  movb   $0xa,-0x12(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  je     L21
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L106
L21:
  addq   $0x8,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L50
L75:
  cmp    $0x2e,%eax
  jg     L135
  cmp    $0xa,%eax
  je     L64
  cmp    $0x2c,%eax
  je     L116
  jmp    L135
L64:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L10
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0xa,-0x12(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L50
L31:
  cmpb   $0x59,-0x12(%rbp)
  je     L50
  addl   $0x1,-0xc(%rbp)
  jmp    L50
L116:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L48
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L48:
  movl   $0x0,-0xc(%rbp)
L135:
  movzbl -0x11(%rbp),%eax
  mov    %al,-0x12(%rbp)
L50:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %al,-0x11(%rbp)
  movsbl -0x11(%rbp),%eax
  cmp    $0x2e,%eax
  je     L31
  jmp    L75
L106:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D12
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D25: Usage: %s [FILE]


tool: D12: r

tool: D19: %d


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char c, p = '\n';
  int m = 10, dots = 0;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  fp = fopen(*++argv, "r");
  while ((c = getc(fp)) != EOF || p != '\n') {
    switch (c) {
    case '\n':
    case EOF:
      if (dots < m)
        m = dots;
      printf("%d\n", m);
      p = '\n';
      m = 10;
      dots = 0;
      break;
    case '.':
      if (p != 'Y')
        dots++;
      break;
    case ',':
      if (dots < m)
        m = dots;
      dots = 0;
    default:
      p = c;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L79
  mov    0x8(%rsi),%rdi
  lea    D13(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r14
  mov    $0x0,%r12d
  mov    $0xa,%ebp
  mov    $0xa,%r13d
  lea    D7(%rip),%r15
  jmp    L3
L62:
  mov    %r13d,%ebx
  cmp    $0x59,%r13b
  je     L64
  add    $0x1,%r12d
  jmp    L64
L22:
  cmp    %r12d,%ebp
  cmovg  %r12d,%ebp
  mov    $0x0,%r12d
L64:
  mov    %ebx,%r13d
L3:
  mov    %r14,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    $0x2c,%al
  je     L22
  cmp    $0x2e,%al
  je     L62
  cmp    $0xa,%al
  jne    L64
  cmp    %r12d,%ebp
  mov    %r12d,%esi
  cmovle %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%r12d
  mov    $0xa,%ebp
  jmp    L64
L79:
  mov    (%rsi),%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string

tool: D13: r

tool: D7: %d


tool: D11: Usage: %s [FILE]


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char c, p = '\n';
  int m = 10, dots = 0;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  fp = fopen(*++argv, "r");
  while ((c = getc(fp)) != EOF || p != '\n') {
    switch (c) {
    case '\n':
    case EOF:
      if (dots < m)
        m = dots;
      printf("%d\n", m);
      p = '\n';
      m = 10;
      dots = 0;
      break;
    case '.':
      if (p != 'Y')
        dots++;
      break;
    case ',':
      if (dots < m)
        m = dots;
      dots = 0;
    default:
      p = c;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L61
  mov    0x8(%rsi),%rdi
  lea    D26(%rip),%rsi
  xor    %r12d,%r12d
  mov    $0xa,%ebp
  mov    $0xa,%r13d
  lea    D2(%rip),%r15
  call   <fopen@plt>
  mov    %rax,%r14
  jmp    L77
  nopl   (%rax)
L70:
  cmp    $0xa,%al
  je     L62
L8:
  mov    %ebx,%r13d
L77:
  mov    %r14,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    $0x2c,%al
  je     L73
  cmp    $0x2e,%al
  jne    L70
  mov    $0x59,%ebx
  cmp    $0x59,%r13b
  je     L8
  add    $0x1,%r12d
  mov    %r13d,%ebx
  jmp    L8
  nopl   (%rax)
L73:
  cmp    %r12d,%ebp
  cmovg  %r12d,%ebp
  xor    %r12d,%r12d
  jmp    L8
  nopl   0x0(%rax)
L62:
  cmp    %r12d,%ebp
  mov    %r12d,%esi
  mov    %r15,%rdi
  cmovle %ebp,%esi
  xor    %eax,%eax
  xor    %r12d,%r12d
  mov    $0xa,%ebp
  call   <printf@plt>
  jmp    L8
L61:
  mov    (%rsi),%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rdx
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D26: r

tool: D2: %d


tool: D9: Usage: %s [FILE]


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char c, p = '\n';
  int m = 10, dots = 0;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  fp = fopen(*++argv, "r");
  while ((c = getc(fp)) != EOF || p != '\n') {
    switch (c) {
    case '\n':
    case EOF:
      if (dots < m)
        m = dots;
      printf("%d\n", m);
      p = '\n';
      m = 10;
      dots = 0;
      break;
    case '.':
      if (p != 'Y')
        dots++;
      break;
    case ',':
      if (dots < m)
        m = dots;
      dots = 0;
    default:
      p = c;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jne    L84
  mov    0x8(%rsi),%rdi
  lea    D7(%rip),%rsi
  xor    %r12d,%r12d
  mov    $0xa,%ebp
  mov    $0xa,%r13d
  lea    D0(%rip),%r15
  call   <fopen@plt>
  mov    %rax,%r14
  jmp    L32
  nopl   (%rax)
L75:
  cmp    $0xa,%al
  je     L12
L9:
  mov    %ebx,%r13d
L32:
  mov    %r14,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  cmp    $0x2c,%al
  je     L83
  cmp    $0x2e,%al
  jne    L75
  mov    $0x59,%ebx
  cmp    $0x59,%r13b
  je     L9
  add    $0x1,%r12d
  mov    %r13d,%ebx
  jmp    L9
  nopl   (%rax)
L83:
  cmp    %r12d,%ebp
  cmovg  %r12d,%ebp
  xor    %r12d,%r12d
  jmp    L9
  nopl   0x0(%rax)
L12:
  cmp    %r12d,%ebp
  mov    %r12d,%esi
  mov    %r15,%rdi
  cmovle %ebp,%esi
  xor    %eax,%eax
  xor    %r12d,%r12d
  mov    $0xa,%ebp
  call   <printf@plt>
  jmp    L9
L84:
  mov    (%rsi),%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rdx
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type: string
name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D7: r

tool: D0: %d


tool: D3: Usage: %s [FILE]


assistant: ```c
int main(int argc, char *argv[]) {
  FILE *fp;
  char c, p = '\n';
  int m = 10, dots = 0;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  fp = fopen(*++argv, "r");
  while ((c = getc(fp)) != EOF || p != '\n') {
    switch (c) {
    case '\n':
    case EOF:
      if (dots < m)
        m = dots;
      printf("%d\n", m);
      p = '\n';
      m = 10;
      dots = 0;
      break;
    case '.':
      if (p != 'Y')
        dots++;
      break;
    case ',':
      if (dots < m)
        m = dots;
      dots = 0;
    default:
      p = c;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_tok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L9:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L28
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L28
  mov    -0xc(%rbp),%eax
  jmp    L34
L28:
  addl   $0x1,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  mov    $0xffffffff,%eax
L34:
  leave
  ret
```

assistant: ```c
int find_tok(int argc, char **argv, char *to_find) {
  int len = strlen(to_find);
  for (int i = 0; i < argc; i++) {
    int ll = strlen(argv[i]);
    if (ll >= len) {
      if (strncmp(argv[i], to_find, len) == 0)
        return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_tok>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%r15
  mov    %rdx,%rdi
  call   <strlen@plt>
  test   %r13d,%r13d
  jle    L22
  mov    %eax,%ebp
  mov    %r13d,%r13d
  mov    $0x0,%ebx
  jmp    L46
L52:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L50
L46:
  mov    %ebx,%r14d
  mov    (%r12,%rbx,8),%rdi
  call   <strlen@plt>
  cmp    %eax,%ebp
  jg     L52
  mov    (%r12,%rbx,8),%rdi
  mov    %ebp,%edx
  mov    %r15,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L52
  jmp    L29
L50:
  mov    $0xffffffff,%r14d
L29:
  mov    %r14d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    $0xffffffff,%r14d
  jmp    L29
```

assistant: ```c
int find_tok(int argc, char **argv, char *to_find) {
  int len = strlen(to_find);
  for (int i = 0; i < argc; i++) {
    int ll = strlen(argv[i]);
    if (ll >= len) {
      if (strncmp(argv[i], to_find, len) == 0)
        return i;
    }
  }
  return -1;
}
```