ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<PutImage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,-0x1c(%rbp)
  mov    %esi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0x7,%eax
  mov    -0x30(%rbp),%rsi
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    %rsi,%rbx
  int    $0x40
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void PutImage(unsigned x, unsigned y, unsigned w, unsigned h, char *image) {
  unsigned size, psize;
  size = x * 65536 + y;
  psize = w * 65536 + h;
  __asm__ __volatile__("int $0x40" ::"a"(7), "b"(image), "c"(psize), "d"(size));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PutImage>:
  endbr64
  push   %rbx
  shl    $0x10,%edx
  add    %edx,%ecx
  shl    $0x10,%edi
  lea    (%rdi,%rsi,1),%edx
  mov    $0x7,%eax
  mov    %r8,%rbx
  int    $0x40
  pop    %rbx
  ret
```

assistant: ```c
void PutImage(unsigned x, unsigned y, unsigned w, unsigned h, char *image) {
  unsigned size, psize;
  size = x * 65536 + y;
  psize = w * 65536 + h;
  __asm__ __volatile__("int $0x40" ::"a"(7), "b"(image), "c"(psize), "d"(size));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<PutImage>:
  endbr64
  shl    $0x10,%edx
  shl    $0x10,%edi
  push   %rbx
  mov    $0x7,%eax
  add    %edx,%ecx
  mov    %r8,%rbx
  lea    (%rdi,%rsi,1),%edx
  int    $0x40
  pop    %rbx
  ret
```

assistant: ```c
void PutImage(unsigned x, unsigned y, unsigned w, unsigned h, char *image) {
  unsigned size, psize;
  size = x * 65536 + y;
  psize = w * 65536 + h;
  __asm__ __volatile__("int $0x40" ::"a"(7), "b"(image), "c"(psize), "d"(size));
}
```
user: What is the c source code of the assembly code below?

```asm
<PutImage>:
  endbr64
  shl    $0x10,%edx
  shl    $0x10,%edi
  push   %rbx
  mov    $0x7,%eax
  add    %edx,%ecx
  mov    %r8,%rbx
  lea    (%rdi,%rsi,1),%edx
  int    $0x40
  pop    %rbx
  ret
```

assistant: ```c
void PutImage(unsigned x, unsigned y, unsigned w, unsigned h, char *image) {
  unsigned size, psize;
  size = x * 65536 + y;
  psize = w * 65536 + h;
  __asm__ __volatile__("int $0x40" ::"a"(7), "b"(image), "c"(psize), "d"(size));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<n_primes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L60
  mov    -0x18(%rbp),%rax
  movl   $0x2,(%rax)
  movl   $0x3,-0x10(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L14
L79:
  movl   $0x1,-0x4(%rbp)
  movl   $0x3,-0xc(%rbp)
  jmp    L78
L67:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L26
  movl   $0x0,-0x4(%rbp)
  jmp    L55
L26:
  addl   $0x2,-0xc(%rbp)
L78:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L67
L55:
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
L6:
  addl   $0x2,-0x10(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L79
  jmp    L27
L60:
  nop
L27:
  pop    %rbp
  ret
```

assistant: ```c
void n_primes(int *results, int n) {
  if (n < 1)
    return;
  *results = 2;
  int i, j, index;
  for (i = 3, index = 1; index < n; i += 2) {
    int prime = 1;
    for (j = 3; j * j <= i; j += 2)
      if (i % j == 0) {
        prime = 0;
        break;
      }
    if (prime)
      results[index++] = i;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<n_primes>:
  endbr64
  mov    %rdi,%r8
  mov    %esi,%r9d
  test   %esi,%esi
  jle    L76
  movl   $0x2,(%rdi)
  mov    $0x1,%edi
  mov    $0x3,%esi
  cmp    $0x1,%r9d
  jg     L19
  ret
L30:
  movslq %edi,%rax
  mov    %esi,(%r8,%rax,4)
  lea    0x1(%rdi),%edi
L10:
  add    $0x2,%esi
  cmp    %r9d,%edi
  jge    L76
L19:
  cmp    $0x8,%esi
  jle    L30
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%esi
  je     L10
  mov    $0x3,%ecx
L61:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %esi,%eax
  jg     L30
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L61
  jmp    L10
L76:
  ret
```

assistant: ```c
void n_primes(int *results, int n) {
  if (n < 1)
    return;
  *results = 2;
  int i, j, index;
  for (i = 3, index = 1; index < n; i += 2) {
    int prime = 1;
    for (j = 3; j * j <= i; j += 2)
      if (i % j == 0) {
        prime = 0;
        break;
      }
    if (prime)
      results[index++] = i;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<n_primes>:
  endbr64
  test   %esi,%esi
  jle    L35
  movl   $0x2,(%rdi)
  mov    $0x1,%r9d
  mov    $0x3,%r8d
  cmp    $0x1,%esi
  je     L15
  nop
L55:
  cmp    $0x8,%r8d
  jle    L52
  imul   $0xaaaaaaab,%r8d,%eax
  cmp    $0x55555555,%eax
  jbe    L36
  mov    $0x3,%ecx
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L36
L53:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %r8d,%eax
  jle    L4
L52:
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %r8d,(%rdi,%rax,4)
L36:
  add    $0x2,%r8d
  cmp    %esi,%r9d
  jl     L55
L35:
  ret
L15:
  ret
```

assistant: ```c
void n_primes(int *results, int n) {
  if (n < 1)
    return;
  *results = 2;
  int i, j, index;
  for (i = 3, index = 1; index < n; i += 2) {
    int prime = 1;
    for (j = 3; j * j <= i; j += 2)
      if (i % j == 0) {
        prime = 0;
        break;
      }
    if (prime)
      results[index++] = i;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<n_primes>:
  endbr64
  test   %esi,%esi
  jle    L35
  movl   $0x2,(%rdi)
  mov    $0x1,%r9d
  mov    $0x3,%r8d
  cmp    $0x1,%esi
  je     L61
  nop
L65:
  cmp    $0x8,%r8d
  jle    L60
  imul   $0xaaaaaaab,%r8d,%eax
  cmp    $0x55555555,%eax
  jbe    L77
  mov    $0x3,%ecx
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L77
L75:
  add    $0x2,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %r8d,%eax
  jle    L4
L60:
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %r8d,(%rdi,%rax,4)
L77:
  add    $0x2,%r8d
  cmp    %esi,%r9d
  jl     L65
L35:
  ret
L61:
  ret
```

assistant: ```c
void n_primes(int *results, int n) {
  if (n < 1)
    return;
  *results = 2;
  int i, j, index;
  for (i = 3, index = 1; index < n; i += 2) {
    int prime = 1;
    for (j = 3; j * j <= i; j += 2)
      if (i % j == 0) {
        prime = 0;
        break;
      }
    if (prime)
      results[index++] = i;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CSUB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x101,%eax
  jne    L33
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  movss  D17(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L33
  movss  D17(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  je     L0
  jmp    L33
L0:
  mov    $0x1,%edx
  lea    D36(%rip),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
L33:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D17
datatype: f32
name: read_data
arguments: tag: D36
datatype: string
name: read_data
arguments: tag: D39
datatype: string

tool: D17: 1

tool: D36: CSUB

tool: D39: MOSTF90CALL

assistant: ```c
void CSUB(int *i, float *r) {
  if (*i == 257 && *r == 1.0)
    setenv("MOSTF90CALL", "CSUB", 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<CSUB>:
  endbr64
  cmpl   $0x101,(%rdi)
  je     L21
L4:
  ret
L21:
  movss  D17(%rip),%xmm0
  ucomiss (%rsi),%xmm0
  jp     L4
  jne    L4
  sub    $0x8,%rsp
  mov    $0x1,%edx
  lea    D24(%rip),%rsi
  lea    D6(%rip),%rdi
  call   <setenv@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
datatype: f32
name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D17: 1

tool: D24: CSUB

tool: D6: MOSTF90CALL

assistant: ```c
void CSUB(int *i, float *r) {
  if (*i == 257 && *r == 1.0)
    setenv("MOSTF90CALL", "CSUB", 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CSUB>:
  endbr64
  cmpl   $0x101,(%rdi)
  je     L17
L24:
  ret
  nopl   (%rax)
L17:
  movss  D17(%rip),%xmm0
  ucomiss (%rsi),%xmm0
  jp     L24
  jne    L24
  mov    $0x1,%edx
  lea    D18(%rip),%rsi
  lea    D5(%rip),%rdi
  jmp    1050 <setenv@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
data_type: f32
name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D5
data_type: string

tool: D17: 1

tool: D18: CSUB

tool: D5: MOSTF90CALL

assistant: ```c
void CSUB(int *i, float *r) {
  if (*i == 257 && *r == 1.0)
    setenv("MOSTF90CALL", "CSUB", 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CSUB>:
  endbr64
  cmpl   $0x101,(%rdi)
  je     L8
L16:
  ret
  nopl   (%rax)
L8:
  movss  D11(%rip),%xmm0
  ucomiss (%rsi),%xmm0
  jp     L16
  jne    L16
  mov    $0x1,%edx
  lea    D14(%rip),%rsi
  lea    D3(%rip),%rdi
  jmp    1050 <setenv@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: f32
name: disassemble_data
arguments: data_label: D14
type: string
name: disassemble_data
arguments: data_label: D3
type: string

tool: D11: 1

tool: D14: CSUB

tool: D3: MOSTF90CALL

assistant: ```c
void CSUB(int *i, float *r) {
  if (*i == 257 && *r == 1.0)
    setenv("MOSTF90CALL", "CSUB", 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fabsolut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L0
  movss  -0x4(%rbp),%xmm0
  movss  D8(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L0:
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_infered: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x80]}

assistant: ```c
float fabsolut(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fabsolut>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L5
L15:
  ret
L5:
  xorps  D3(%rip),%xmm0
  jmp    L15
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: byte[16]

tool: {"D3": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float fabsolut(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fabsolut>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L0
  ret
  xchg   %ax,%ax
L0:
  xorps  D2(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: byte[16]

tool: {"D2": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float fabsolut(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fabsolut>:
  endbr64
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L6
  ret
  xchg   %ax,%ax
L6:
  xorps  D9(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
float fabsolut(float x) {
  if (x < 0) {
    x = -x;
  }
  return x;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<path_004_expected_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
void path_004_expected_3(int a, int b) {
  if (a) {
    return;
  }
  if (b) {
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<path_004_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_004_expected_3(int a, int b) {
  if (a) {
    return;
  }
  if (b) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<path_004_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_004_expected_3(int a, int b) {
  if (a) {
    return;
  }
  if (b) {
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<path_004_expected_3>:
  endbr64
  ret
```

assistant: ```c
void path_004_expected_3(int a, int b) {
  if (a) {
    return;
  }
  if (b) {
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0xa8(%rbp)
  cmpl   $0xffffffff,-0xa8(%rbp)
  jne    L14
  mov    $0x1,%edi
  call   <exit@plt>
L14:
  lea    -0x9c(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x94(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x98(%rbp)
  mov    $0xe678,%edi
  call   <htons@plt>
  mov    %eax,-0x9c(%rbp)
  lea    -0x9c(%rbp),%rcx
  mov    -0xa8(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    %eax,-0xa4(%rbp)
  cmpl   $0xffffffff,-0xa4(%rbp)
  jne    L42
  mov    $0x1,%edi
  call   <exit@plt>
L42:
  movl   $0xc,-0xac(%rbp)
  lea    -0xac(%rbp),%rcx
  lea    -0x9c(%rbp),%rdx
  lea    -0x90(%rbp),%rsi
  mov    -0xa8(%rbp),%eax
  mov    %rcx,%r9
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x80,%edx
  mov    %eax,%edi
  call   <recvfrom@plt>
  mov    %eax,-0xa0(%rbp)
  cmpl   $0xffffffff,-0xa0(%rbp)
  jne    L19
  mov    $0x1,%edi
  call   <exit@plt>
L19:
  mov    -0xac(%rbp),%edi
  lea    -0x9c(%rbp),%rcx
  mov    -0xa0(%rbp),%edx
  lea    -0x90(%rbp),%rsi
  mov    -0xa8(%rbp),%eax
  mov    %edi,%r9d
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0xa4(%rbp)
  cmpl   $0xffffffff,-0xa4(%rbp)
  jne    L42
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L42
```

assistant: ```c
int main(void) {
  int fd, addrlen, ret, nread;
  struct sockaddr_in addr;
  char buffer[128];
  if ((fd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
    exit(1);
  }
  memset((void *)&addr, (int)'\0', sizeof(addr));
  addr.sin_family = AF_INET;
  addr.sin_addr.s_addr = htonl(INADDR_ANY);
  addr.sin_port = htons(59000);
  ret = bind(fd, (struct sockaddr *)&addr, sizeof(addr));
  if (ret == -1) {
    exit(1);
  }
  while (1) {
    addrlen = sizeof(addr);
    nread = recvfrom(fd, buffer, 128, 0, (struct sockaddr *)&addr, &addrlen);
    if (nread == -1) {
      exit(1);
    }
    ret = sendto(fd, buffer, nread, 0, (struct sockaddr *)&addr, addrlen);
    if (ret == -1) {
      exit(1);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    D20(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    %eax,%r13d
  cmp    $0xffffffff,%eax
  je     L61
L34:
  lea    0x4(%rsp),%rbx
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0x8(%rsp)
  mov    $0xe678,%edi
  call   <htons@plt>
  mov    %eax,0x4(%rsp)
  mov    $0xc,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L49
L20:
  mov    %rsp,%r14
L10:
  lea    0x4(%rsp),%r12
  lea    0x10(%rsp),%rbp
L77:
  movl   $0xc,(%rsp)
  mov    %r14,%r9
  mov    %r12,%r8
  mov    $0x0,%ecx
  mov    $0x80,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <recvfrom@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L70
L41:
  mov    (%rsp),%r9d
  mov    %r12,%r8
  mov    $0x0,%ecx
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  jne    L77
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
L61:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
L49:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L20
L70:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L41
```

assistant: ```c
int main(void) {
  int fd, addrlen, ret, nread;
  struct sockaddr_in addr;
  char buffer[128];
  if ((fd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
    exit(1);
  }
  memset((void *)&addr, (int)'\0', sizeof(addr));
  addr.sin_family = AF_INET;
  addr.sin_addr.s_addr = htonl(INADDR_ANY);
  addr.sin_port = htons(59000);
  ret = bind(fd, (struct sockaddr *)&addr, sizeof(addr));
  if (ret == -1) {
    exit(1);
  }
  while (1) {
    addrlen = sizeof(addr);
    nread = recvfrom(fd, buffer, 128, 0, (struct sockaddr *)&addr, &addrlen);
    if (nread == -1) {
      exit(1);
    }
    ret = sendto(fd, buffer, nread, 0, (struct sockaddr *)&addr, addrlen);
    if (ret == -1) {
      exit(1);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    D7(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    D25(%rip),%rax
  mov    (%r12),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L10
L22:
  lea    0x14(%rsp),%rbp
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r12),%eax
  mov    %eax,0x1c(%rsp)
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0xe678,%edi
  mov    %eax,0x18(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  mov    %eax,0x14(%rsp)
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L3
L43:
  lea    0x10(%rsp),%r13
  lea    0x20(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x80,%edx
  mov    %r13,%r9
  mov    %rbp,%r8
  xor    %ecx,%ecx
  mov    %r12,%rsi
  mov    %ebx,%edi
  movl   $0xc,0x10(%rsp)
  call   <recvfrom@plt>
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  je     L14
L13:
  mov    0x10(%rsp),%r9d
  xor    %ecx,%ecx
  mov    %rbp,%r8
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%edi
  mov    %eax,0xc(%rsp)
  call   <exit@plt>
  mov    0xc(%rsp),%edx
  jmp    L13
L10:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
L3:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L43
```

assistant: ```c
int main(void) {
  int fd, addrlen, ret, nread;
  struct sockaddr_in addr;
  char buffer[128];
  if ((fd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
    exit(1);
  }
  memset((void *)&addr, (int)'\0', sizeof(addr));
  addr.sin_family = AF_INET;
  addr.sin_addr.s_addr = htonl(INADDR_ANY);
  addr.sin_port = htons(59000);
  ret = bind(fd, (struct sockaddr *)&addr, sizeof(addr));
  if (ret == -1) {
    exit(1);
  }
  while (1) {
    addrlen = sizeof(addr);
    nread = recvfrom(fd, buffer, 128, 0, (struct sockaddr *)&addr, &addrlen);
    if (nread == -1) {
      exit(1);
    }
    ret = sendto(fd, buffer, nread, 0, (struct sockaddr *)&addr, addrlen);
    if (ret == -1) {
      exit(1);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edx,%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    D24(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    (%r12),%edi
  mov    (%rax),%esi
  call   <socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L23
L28:
  lea    0x4(%rsp),%rbp
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    (%r12),%eax
  mov    %eax,0xc(%rsp)
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0xe678,%edi
  mov    %eax,0x8(%rsp)
  call   <htons@plt>
  mov    $0xc,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  mov    %eax,0x4(%rsp)
  call   <bind@plt>
  cmp    $0xffffffff,%eax
  je     L11
L26:
  mov    %rsp,%r13
  lea    0x10(%rsp),%r12
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    $0x80,%edx
  mov    %r13,%r9
  mov    %rbp,%r8
  xor    %ecx,%ecx
  mov    %r12,%rsi
  mov    %ebx,%edi
  movl   $0xc,(%rsp)
  call   <recvfrom@plt>
  mov    %eax,%edx
  cmp    $0xffffffff,%eax
  je     L60
  mov    (%rsp),%r9d
  mov    %rbp,%r8
  xor    %ecx,%ecx
L29:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  jne    L30
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L30
  nopl   0x0(%rax)
L60:
  mov    $0x1,%edi
  call   <exit@plt>
  mov    (%rsp),%r9d
  mov    %rbp,%r8
  xor    %ecx,%ecx
  mov    $0xffffffff,%edx
  jmp    L29
L23:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L28
L11:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L26
```

assistant: ```c
int main(void) {
  int fd, addrlen, ret, nread;
  struct sockaddr_in addr;
  char buffer[128];
  if ((fd = socket(AF_INET, SOCK_DGRAM, 0)) == -1) {
    exit(1);
  }
  memset((void *)&addr, (int)'\0', sizeof(addr));
  addr.sin_family = AF_INET;
  addr.sin_addr.s_addr = htonl(INADDR_ANY);
  addr.sin_port = htons(59000);
  ret = bind(fd, (struct sockaddr *)&addr, sizeof(addr));
  if (ret == -1) {
    exit(1);
  }
  while (1) {
    addrlen = sizeof(addr);
    nread = recvfrom(fd, buffer, 128, 0, (struct sockaddr *)&addr, &addrlen);
    if (nread == -1) {
      exit(1);
    }
    ret = sendto(fd, buffer, nread, 0, (struct sockaddr *)&addr, addrlen);
    if (ret == -1) {
      exit(1);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dump_out_shammx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L18:
  mov    -0x20(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x20(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x4(%rbp),%eax
  not    %eax
  and    $0x3,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L29
  mov    $0x20,%edi
  call   <putchar@plt>
L29:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L18
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D1: %.2x

assistant: ```c
void dump_out_shammx(void *buf, unsigned int size, unsigned int index) {
  unsigned int i;
  for (i = 0; i < size; i++) {
    printf("%.2x", ((unsigned char *)buf)[((index & (4 - 1)) * 4 + ((i) & (0xffffffff - 3)) * 4 + (3 - ((i)&3)) + (unsigned int)index / 4 * 20 * 4)]);
    if ((i % 4) == 3)
      printf(" ");
  }
  printf("\n");
}
```