user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D74(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D76(%rip),%rdi
  call   <scanf@plt>
  jmp    L71
  cs nopw 0x0(%rax,%rax,1)
L27:
  add    $0x1,%ebx
L71:
  mov    0x14(%rsp),%r12d
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  cltd
  idiv   %r8d
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L27
  mov    %ebx,%esi
  lea    D101(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  mov    %ebx,0xc(%rsp)
  jmp    L58
  nopl   (%rax)
L56:
  cmp    %r14d,%r15d
  jge    L20
L47:
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  cmp    0xc(%rsp),%r12d
  je     L42
L58:
  mov    %r12d,%ebx
  add    $0x1,%r12d
  mov    $0xa,%edi
  mov    %r12d,%esi
  call   <power@plt>
  lea    D106(%rip),%rdi
  mov    %eax,%r14d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    D64(%rip),%rdi
  cltd
  idiv   %r14d
  mov    %eax,%r13d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   %r13d,%r14d
  mov    0x14(%rsp),%r15d
  xor    %eax,%eax
  lea    D54(%rip),%rdi
  sub    %r14d,%r15d
  mov    %r15d,%esi
  call   <printf@plt>
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <power@plt>
  lea    D67(%rip),%rdi
  mov    %eax,%r14d
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  imul   %r14d,%r13d
  lea    (%r14,%r14,1),%eax
  add    %r13d,%ebp
  cmp    %r15d,%eax
  jg     L56
  lea    D58(%rip),%rdi
  add    %r14d,%ebp
  call   <puts@plt>
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L20:
  sub    %r14d,%r15d
  lea    D45(%rip),%rdi
  lea    0x1(%rbp,%r15,1),%ebp
  call   <puts@plt>
  jmp    L47
  nopl   0x0(%rax)
L42:
  mov    %ebp,%esi
  lea    D102(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D74
type_guessed: string
name: parse_data
arguments: label: D76
type_guessed: string
name: parse_data
arguments: label: D101
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D106
type_guessed: string
name: parse_data
arguments: label: D64
type_guessed: string
name: parse_data
arguments: label: D54
type_guessed: string
name: parse_data
arguments: label: D67
type_guessed: string
name: parse_data
arguments: label: D58
type_guessed: string
name: parse_data
arguments: label: D45
type_guessed: string
name: parse_data
arguments: label: D102
type_guessed: string

tool: D74: Enter a number: 

tool: D76: %d

tool: D101: the digit is: %d



tool: D18: The n1 is: %d



tool: D106: The base is: %d


tool: D64: The fra is: %d


tool: D54: The mod is: %d


tool: D67: The quan is: %d


tool: D58: A

tool: D45: B

tool: D102: The number of ones is: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int num;
  int frac = 1;
  int digit = 1;
  printf("Enter a number: ");
  scanf("%d", &num);
  while (1) {
    frac = num / power(10, digit);
    if (frac == 0)
      break;
    digit += 1;
  }
  printf("the digit is: %d\n\n", digit);
  int j;
  int n1;
  for (j = 0, n1 = 0; j < digit; j++) {
    int base = power(10, j + 1);
    printf("The base is: %d\n", base);
    int fra = num / base;
    printf("The fra is: %d\n", fra);
    int mod = num - base * fra;
    printf("The mod is: %d\n", mod);
    int quan = power(10, j);
    printf("The quan is: %d\n", quan);
    n1 += fra * quan;
    if (mod > 2 * quan - 1) {
      n1 += quan;
      printf("A\n");
    } else if (mod > quan - 1) {
      n1 += mod - quan + 1;
      printf("B\n");
    }
    printf("The n1 is: %d\n\n", n1);
  }
  printf("The number of ones is: %d\n", n1);
  getchar();
  getchar();
  return 0;
}
```