ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_next_pow2>:
  endbr64
  sub    $0x1,%rdi
  mov    %rdi,%rax
  shr    %rax
  or     %rdi,%rax
  mov    %rax,%rdi
  shr    $0x2,%rdi
  or     %rax,%rdi
  mov    %rdi,%rdx
  shr    $0x4,%rdx
  or     %rdi,%rdx
  mov    %rdx,%rax
  shr    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shr    $0x10,%rdx
  or     %rax,%rdx
  mov    %rdx,%rax
  shr    $0x20,%rax
  or     %rdx,%rax
  add    $0x1,%rax
  ret
```

assistant: ```c
unsigned long get_next_pow2(unsigned long n) {
  n--;
  n |= n >> 1;
  n |= n >> 2;
  n |= n >> 4;
  n |= n >> 8;
  n |= n >> 16;
  n |= n >> 32;
  n++;
  return n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_mul(int a, int b) {
  ft_putnbr(a * b);
  ft_putchar('\n');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_mul>:
  endbr64
  sub    $0x8,%rsp
  imul   %esi,%edi
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  call   <ft_putchar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ft_mul(int a, int b) {
  ft_putnbr(a * b);
  ft_putchar('\n');
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_mul>:
  endbr64
  imul   %esi,%edi
  sub    $0x8,%rsp
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <ft_putchar@plt>
```

assistant: ```c
void ft_mul(int a, int b) {
  ft_putnbr(a * b);
  ft_putchar('\n');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_mul>:
  endbr64
  imul   %esi,%edi
  sub    $0x8,%rsp
  call   <ft_putnbr@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1060 <ft_putchar@plt>
```

assistant: ```c
void ft_mul(int a, int b) {
  ft_putnbr(a * b);
  ft_putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<boithoad_getPassword>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa0,%rsp
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rax
  mov    $0x40,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0xda3,%esi
  lea    D21(%rip),%rdi
  call   <cconnect@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L67
L45:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %ebx,%eax
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L67:
  lea    D49(%rip),%r9
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x1e,%esi
  mov    %eax,%edi
  call   <sendpacked@plt>
  lea    0x10(%rsp),%rsi
  mov    $0x40,%edx
  mov    %ebx,%edi
  call   <sendall@plt>
  lea    0xc(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <recvall@plt>
  test   %eax,%eax
  je     L28
  mov    0xc(%rsp),%r12d
  cmp    $0x1,%r12d
  je     L88
  mov    $0xfd,%edx
  lea    D11(%rip),%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%r12d
L43:
  mov    %ebx,%edi
  call   <close@plt>
  mov    %r12d,%ebx
  jmp    L45
L88:
  lea    0x50(%rsp),%rsi
  mov    $0x40,%edx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <recvall@plt>
  test   %eax,%eax
  jne    L15
  mov    %eax,%ebx
  jmp    L45
L15:
  lea    0x50(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L43
L28:
  mov    %eax,%ebx
  jmp    L45
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_infered: string
name: retrieve_data
arguments: label: D49
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D21: localhost

tool: 

tool: D11: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bowlofstew/enterprise-search/refs/heads/master/src/boithoadClientLib/boithoadClientLib.c

tool: D15: dident have a passord at %s:%d


assistant: ```c
int boithoad_getPassword(const char username_in[], char password_in[]) {
  int socketha;
  int intresponse;
  char username[64];
  char password[64];
  int forreturn = 0;
  strncpy(username, username_in, sizeof(username));
  if ((socketha = cconnect("localhost", 3491)) == 0) {
    return 0;
  }
  sendpacked(socketha, 30, 1, 0, NULL, "");
  sendall(socketha, username, sizeof(username));
  if (!recvall(socketha, &intresponse, sizeof(intresponse))) {
    return 0;
  }
  if (intresponse == 1) {
    if (!recvall(socketha, password, sizeof(password))) {
      return 0;
    }
    strcpy(password_in, password);
    forreturn = 1;
  } else {
    printf("dident have a passord at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bowlofstew/enterprise-search/refs/heads/master/src/boithoadClientLib/boithoadClientLib.c", 253);
    strcpy(password_in, "");
    forreturn = 0;
  }
  close(socketha);
  return forreturn;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<boithoad_getPassword>:
  endbr64
  push   %r14
  mov    $0x40,%edx
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    $0xda3,%esi
  lea    D47(%rip),%rdi
  call   <cconnect@plt>
  test   %eax,%eax
  jne    L1
L14:
  xor    %r12d,%r12d
L24:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0xa8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L1:
  mov    %eax,%ebp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  lea    D14(%rip),%r9
  mov    $0x1e,%esi
  mov    %eax,%edi
  call   <sendpacked@plt>
  mov    $0x40,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <sendall@plt>
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  mov    %ebp,%edi
  mov    $0x4,%edx
  call   <recvall@plt>
  test   %eax,%eax
  je     L14
  mov    0xc(%rsp),%r12d
  cmp    $0x1,%r12d
  je     L11
  mov    $0xfd,%edx
  lea    D28(%rip),%rsi
  lea    D24(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  lea    D14(%rip),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
L19:
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L11:
  lea    0x50(%rsp),%r14
  xor    %eax,%eax
  mov    $0x40,%edx
  mov    %ebp,%edi
  mov    %r14,%rsi
  call   <recvall@plt>
  test   %eax,%eax
  je     L14
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  jmp    L19
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D47
datatype: string
name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D28
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string

tool: D47: localhost

tool: 

tool: D28: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bowlofstew/enterprise-search/refs/heads/master/src/boithoadClientLib/boithoadClientLib.c

tool: D24: dident have a passord at %s:%d


assistant: ```c
int boithoad_getPassword(const char username_in[], char password_in[]) {
  int socketha;
  int intresponse;
  char username[64];
  char password[64];
  int forreturn = 0;
  strncpy(username, username_in, sizeof(username));
  if ((socketha = cconnect("localhost", 3491)) == 0) {
    return 0;
  }
  sendpacked(socketha, 30, 1, 0, NULL, "");
  sendall(socketha, username, sizeof(username));
  if (!recvall(socketha, &intresponse, sizeof(intresponse))) {
    return 0;
  }
  if (intresponse == 1) {
    if (!recvall(socketha, password, sizeof(password))) {
      return 0;
    }
    strcpy(password_in, password);
    forreturn = 1;
  } else {
    printf("dident have a passord at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bowlofstew/enterprise-search/refs/heads/master/src/boithoadClientLib/boithoadClientLib.c", 253);
    strcpy(password_in, "");
    forreturn = 0;
  }
  close(socketha);
  return forreturn;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<boithoad_getPassword>:
  endbr64
  push   %r14
  mov    $0x40,%edx
  push   %r13
  mov    %rsi,%r13
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <strncpy@plt>
  mov    $0xda3,%esi
  lea    D30(%rip),%rdi
  call   <cconnect@plt>
  test   %eax,%eax
  jne    L7
L40:
  xor    %r12d,%r12d
L69:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0xa8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L7:
  mov    %eax,%ebp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  lea    D35(%rip),%r9
  mov    $0x1e,%esi
  mov    %eax,%edi
  call   <sendpacked@plt>
  mov    $0x40,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <sendall@plt>
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  mov    %ebp,%edi
  mov    $0x4,%edx
  call   <recvall@plt>
  test   %eax,%eax
  je     L40
  mov    0xc(%rsp),%r12d
  cmp    $0x1,%r12d
  je     L12
  mov    $0xfd,%edx
  lea    D21(%rip),%rsi
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  lea    D35(%rip),%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
L67:
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L12:
  lea    0x50(%rsp),%r14
  xor    %eax,%eax
  mov    $0x40,%edx
  mov    %ebp,%edi
  mov    %r14,%rsi
  call   <recvall@plt>
  test   %eax,%eax
  je     L40
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  jmp    L67
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D30
datatype: string
name: unpack_data
arguments: data_label: D35
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string

tool: D30: localhost

tool: 

tool: D21: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bowlofstew/enterprise-search/refs/heads/master/src/boithoadClientLib/boithoadClientLib.c

tool: D7: dident have a passord at %s:%d


assistant: ```c
int boithoad_getPassword(const char username_in[], char password_in[]) {
  int socketha;
  int intresponse;
  char username[64];
  char password[64];
  int forreturn = 0;
  strncpy(username, username_in, sizeof(username));
  if ((socketha = cconnect("localhost", 3491)) == 0) {
    return 0;
  }
  sendpacked(socketha, 30, 1, 0, NULL, "");
  sendall(socketha, username, sizeof(username));
  if (!recvall(socketha, &intresponse, sizeof(intresponse))) {
    return 0;
  }
  if (intresponse == 1) {
    if (!recvall(socketha, password, sizeof(password))) {
      return 0;
    }
    strcpy(password_in, password);
    forreturn = 1;
  } else {
    printf("dident have a passord at %s:%d\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/bowlofstew/enterprise-search/refs/heads/master/src/boithoadClientLib/boithoadClientLib.c", 253);
    strcpy(password_in, "");
    forreturn = 0;
  }
  close(socketha);
  return forreturn;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<popcnt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3f,%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((const)) unsigned popcnt(unsigned x) {
  x -= ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f;
  x += x >> 8;
  x += x >> 16;
  return x & 0x3f;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<popcnt>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  and    $0x33333333,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  and    $0x3f,%eax
  ret
```

assistant: ```c
__attribute__((const)) unsigned popcnt(unsigned x) {
  x -= ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f;
  x += x >> 8;
  x += x >> 16;
  return x & 0x3f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<popcnt>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  and    $0x3f,%eax
  ret
```

assistant: ```c
__attribute__((const)) unsigned popcnt(unsigned x) {
  x -= ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f;
  x += x >> 8;
  x += x >> 16;
  return x & 0x3f;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<popcnt>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55555555,%eax
  sub    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33333333,%edx
  and    $0x33333333,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%eax
  add    %edx,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  shr    $0x8,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  and    $0x3f,%eax
  ret
```

assistant: ```c
__attribute__((const)) unsigned popcnt(unsigned x) {
  x -= ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
  x = (x + (x >> 4)) & 0x0f0f0f0f;
  x += x >> 8;
  x += x >> 16;
  return x & 0x3f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<todegree>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%r14
  mov    %edx,%r13d
  mov    %ecx,(%rsp)
  mov    %r8d,0x4(%rsp)
  movslq %edx,%rbx
  lea    0x0(,%rbx,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L74
  lea    0x0(,%rbx,4),%rax
  mov    %rax,0x8(%rsp)
  mov    %r12,%rbp
  lea    -0x1(%r13),%eax
  shl    $0x3,%rax
  mov    %rax,0x18(%rsp)
  lea    0x8(%r12,%rax,1),%r15
  mov    %r12,%rbx
L28:
  mov    0x8(%rsp),%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L28
  mov    0x10(%rsp),%rax
  mov    %rax,%rsi
  mov    0x18(%rsp),%rdi
  lea    0x8(%rax,%rdi,1),%r8
  mov    %r13d,%ebx
  shl    $0x2,%rbx
  mov    %r12,%rdi
L25:
  mov    $0x0,%eax
L57:
  mov    (%rsi),%rdx
  mov    (%rdx,%rax,1),%ecx
  mov    (%rdi),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L57
  add    $0x8,%rsi
  add    $0x8,%rdi
  cmp    %r8,%rsi
  jne    L25
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r12,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <multy@plt>
  mov    %r14,%rsi
L109:
  mov    $0x0,%eax
L102:
  mov    0x0(%rbp),%rdx
  mov    (%rdx,%rax,1),%ecx
  mov    (%rsi),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L102
  add    $0x8,%rbp
  add    $0x8,%rsi
  cmp    %r15,%rbp
  jne    L109
  cmpl   $0x0,(%rsp)
  jle    L54
L99:
  mov    $0x1,%ebx
L34:
  mov    0x4(%rsp),%r8d
  mov    %r13d,%ecx
  mov    %r14,%rdx
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <block_mult_ed@plt>
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jge    L34
  test   %r13d,%r13d
  jle    L27
L54:
  mov    $0x0,%ebx
L107:
  mov    (%r12,%rbx,8),%rdi
  call   <free@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jg     L107
L27:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  mov    %r13d,%ecx
  mov    %rax,%rdx
  mov    %rax,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <multy@plt>
  cmpl   $0x0,(%rsp)
  jg     L99
  jmp    L27
```

assistant: ```c
int todegree(int **input, int **out, int size, int degree, int param) {
  int i, j;
  int **temp = (int **)malloc(size * sizeof(int *));
  for (i = 0; i < size; i++)
    temp[i] = (int *)malloc(size * sizeof(int));
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      temp[i][j] = input[i][j];
  multy(temp, temp, temp, size);
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      out[i][j] = temp[i][j];
  for (i = 1; i <= degree; i++)
    block_mult_ed(temp, out, out, size, param);
  for (i = 0; i < size; i++)
    free(temp[i]);
  free(temp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<todegree>:
  endbr64
  push   %r15
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  mov    %r13,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x0(,%r13,8),%rdi
  mov    %ecx,0x4(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L50
  lea    0x0(,%r13,4),%rax
  mov    %ebp,%r15d
  mov    %r12,%r13
  mov    %rax,0x10(%rsp)
  lea    (%r12,%r15,8),%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L58:
  mov    0x10(%rsp),%rdi
  add    $0x8,%r13
  call   <malloc@plt>
  mov    %rax,-0x8(%r13)
  cmp    0x18(%rsp),%r13
  jne    L58
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L44:
  mov    0x8(%rsp),%rax
  mov    (%r12,%rdi,8),%rcx
  mov    (%rax,%rdi,8),%rsi
  xor    %eax,%eax
  nop
L74:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %r15,%rax
  jne    L74
  add    $0x1,%rdi
  cmp    %r15,%rdi
  jne    L44
  mov    %r12,%rdi
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  call   <multy@plt>
  xor    %edi,%edi
  nopl   0x0(%rax)
L113:
  mov    (%r12,%rdi,8),%rsi
  mov    (%rbx,%rdi,8),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L40:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r15
  jne    L40
  add    $0x1,%rdi
  cmp    %rdi,%r15
  jne    L113
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L25
L103:
  mov    $0x1,%r13d
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r14d,%r8d
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <block_mult_ed@plt>
  cmp    %r13d,0x4(%rsp)
  jge    L22
  test   %ebp,%ebp
  jle    L51
L25:
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L42:
  mov    (%r12,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <free@plt>
  cmp    %ebx,%ebp
  jg     L42
L51:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  mov    %rax,%rdx
  mov    %rax,%rsi
  mov    %rax,%rdi
  mov    %r13d,%ecx
  xor    %eax,%eax
  call   <multy@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L103
  jmp    L51
```

assistant: ```c
int todegree(int **input, int **out, int size, int degree, int param) {
  int i, j;
  int **temp = (int **)malloc(size * sizeof(int *));
  for (i = 0; i < size; i++)
    temp[i] = (int *)malloc(size * sizeof(int));
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      temp[i][j] = input[i][j];
  multy(temp, temp, temp, size);
  for (i = 0; i < size; i++)
    for (j = 0; j < size; j++)
      out[i][j] = temp[i][j];
  for (i = 1; i <= degree; i++)
    block_mult_ed(temp, out, out, size, param);
  for (i = 0; i < size; i++)
    free(temp[i]);
  free(temp);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L15
L17:
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L15:
  cmpl   $0x0,-0xc(%rbp)
  jg     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void clear_array(int array[], int n_elements) {
  while (n_elements > 0)
    array[--n_elements] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_array>:
  endbr64
  test   %esi,%esi
  jle    L5
  movslq %esi,%rsi
L2:
  movl   $0x0,-0x4(%rdi,%rsi,4)
  sub    $0x1,%rsi
  test   %esi,%esi
  jg     L2
L5:
  ret
```

assistant: ```c
void clear_array(int array[], int n_elements) {
  while (n_elements > 0)
    array[--n_elements] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_array>:
  endbr64
  test   %esi,%esi
  jle    L2
  movslq %esi,%rax
  sub    $0x1,%esi
  movslq %esi,%rsi
  lea    0x0(,%rax,4),%rdx
  sub    %rsi,%rax
  xor    %esi,%esi
  lea    -0x4(%rdi,%rax,4),%rdi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void clear_array(int array[], int n_elements) {
  while (n_elements > 0)
    array[--n_elements] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clear_array>:
  endbr64
  test   %esi,%esi
  jle    L4
  movslq %esi,%rax
  sub    $0x1,%esi
  movslq %esi,%rsi
  lea    0x0(,%rax,4),%rdx
  sub    %rsi,%rax
  xor    %esi,%esi
  lea    -0x4(%rdi,%rax,4),%rdi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
void clear_array(int array[], int n_elements) {
  while (n_elements > 0)
    array[--n_elements] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L38
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <iracc_ctrl_main@plt>
  jmp    L49
L38:
  cmpl   $0x1,-0x4(%rbp)
  jle    L59
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L59
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <iracc_gate_main@plt>
  jmp    L49
L59:
  mov    $0x0,%eax
  call   <_print_help@plt>
  mov    $0x0,%eax
L49:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D1: ctrl

tool: D13: gate

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc > 1 && strcmp(argv[1], "ctrl") == 0) {
    return iracc_ctrl_main(argc - 1, argv + 1);
  } else if (argc > 1 && strcmp(argv[1], "gate") == 0) {
    return iracc_gate_main(argc - 1, argv + 1);
  }
  _print_help();
  return 0;
}
```