ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2724(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L2
L45:
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <is_funny@plt>
  test   %rax,%rax
  je     L37
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L37:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  mov    -0x2724(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2724(%rbp)
  test   %eax,%eax
  jg     L45
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: tag: D13
type_guessed: string
name: extract_symbolic_data
arguments: tag: D36
type_guessed: string

tool: D37: %d

tool: D16: %s

tool: D13: Funny


tool: D36: Not Funny


assistant: ```c
int main() {
  int T;
  char string[10000 + 1];
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%s", string);
    if (is_funny(string)) {
      printf("Funny\n");
    } else {
      printf("Not Funny\n");
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L3
  lea    0x10(%rsp),%rbx
  lea    D7(%rip),%rbp
  lea    D20(%rip),%r13
  lea    D3(%rip),%r12
  jmp    L29
L43:
  mov    %r13,%rdi
  call   <printf@plt>
L20:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L3
L29:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <is_funny@plt>
  test   %rax,%rax
  je     L43
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L20
L3:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x2738,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string

tool: D16: %d

tool: D7: %s

tool: D20: Not Funny


tool: D3: Funny


assistant: ```c
int main() {
  int T;
  char string[10000 + 1];
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%s", string);
    if (is_funny(string)) {
      printf("Funny\n");
    } else {
      printf("Not Funny\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L0
  lea    0x10(%rsp),%rbx
  lea    D32(%rip),%rbp
  lea    D8(%rip),%r13
  lea    D0(%rip),%r12
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L0
L36:
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <is_funny@plt>
  test   %rax,%rax
  jne    L43
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L36
L0:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x2738,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D38
type_guessed: string
name: unpack_data
arguments: label: D32
type_guessed: string
name: unpack_data
arguments: label: D8
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string

tool: D38: %d

tool: D32: %s

tool: D8: Not Funny


tool: D0: Funny


assistant: ```c
int main() {
  int T;
  char string[10000 + 1];
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%s", string);
    if (is_funny(string)) {
      printf("Funny\n");
    } else {
      printf("Not Funny\n");
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x738,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L2
  lea    0x10(%rsp),%rbx
  lea    D11(%rip),%rbp
  lea    D17(%rip),%r13
  lea    D22(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <is_funny@plt>
  mov    %r12,%rdi
  test   %rax,%rax
  jne    L10
  mov    %r13,%rdi
L10:
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L35
L2:
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x2738,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string

tool: D5: %d

tool: D11: %s

tool: D17: Not Funny


tool: D22: Funny


assistant: ```c
int main() {
  int T;
  char string[10000 + 1];
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%s", string);
    if (is_funny(string)) {
      printf("Funny\n");
    } else {
      printf("Not Funny\n");
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hit_return_now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <flush_input@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <my_printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <get_single_quiet@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string

tool: D0: 
Hit return to continue...

tool: D16: 


assistant: ```c
void hit_return_now(void) {
  flush_input(0);
  my_printf("\nHit return to continue...");
  get_single_quiet("\n");
  my_putchar('\n');
}
```
user: What is the c source code of the assembly code below:

```asm
<hit_return_now>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <flush_input@plt>
  lea    D9(%rip),%rdi
  call   <my_printf@plt>
  lea    D11(%rip),%rdi
  call   <get_single_quiet@plt>
  mov    $0xa,%edi
  call   <my_putchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_guessed: string
name: retrieve_data
arguments: tag: D11
type_guessed: string

tool: D9: 
Hit return to continue...

tool: D11: 


assistant: ```c
void hit_return_now(void) {
  flush_input(0);
  my_printf("\nHit return to continue...");
  get_single_quiet("\n");
  my_putchar('\n');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hit_return_now>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <flush_input@plt>
  lea    D1(%rip),%rdi
  call   <my_printf@plt>
  lea    D0(%rip),%rdi
  call   <get_single_quiet@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    10b0 <my_putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D1: 
Hit return to continue...

tool: D0: 


assistant: ```c
void hit_return_now(void) {
  flush_input(0);
  my_printf("\nHit return to continue...");
  get_single_quiet("\n");
  my_putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hit_return_now>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <flush_input@plt>
  lea    D10(%rip),%rdi
  call   <my_printf@plt>
  lea    D7(%rip),%rdi
  call   <get_single_quiet@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    10b0 <my_putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type_infered: string
name: read_data
arguments: tag: D7
type_infered: string

tool: D10: 
Hit return to continue...

tool: D7: 


assistant: ```c
void hit_return_now(void) {
  flush_input(0);
  my_printf("\nHit return to continue...");
  get_single_quiet("\n");
  my_putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<perform_check>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    %edx,%r10d
  mov    %ecx,%r11d
  lea    0x1(%rsi),%ecx
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L1
  push   %rbx
  jmp    L82
L11:
  mov    %ecx,%esi
  sub    %r11d,%esi
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %esi,%ebx
  sar    $0x1f,%ebx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%esi
  cmp    $0x4,%esi
  je     L45
  cmp    $0xa,%al
  je     L102
  mov    %ecx,%r8d
L171:
  lea    0x1(%r8),%ecx
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L187
L82:
  cmp    $0x2e,%al
  je     L11
  cmp    $0x23,%al
  je     L11
  cmp    $0xa,%al
  jne    L176
  mov    %ecx,%edx
  sub    %r11d,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edx
  cmp    $0x4,%edx
  je     L164
  mov    $0x0,%eax
  jmp    L18
L53:
  lea    0x1(%r11),%eax
  cmp    $0x1a,%eax
  mov    $0x0,%edx
  cmovge %edx,%eax
  jmp    L18
L133:
  add    $0x1,%r11d
  add    $0x2,%r8d
  mov    $0x1,%r10d
  jmp    L171
L187:
  mov    $0x0,%eax
L18:
  pop    %rbx
  ret
L1:
  mov    $0x0,%eax
  ret
L176:
  mov    $0x0,%eax
  jmp    L18
L191:
  mov    $0x0,%eax
  jmp    L18
L102:
  mov    $0x0,%eax
  jmp    L18
L40:
  mov    $0x0,%eax
  jmp    L18
L45:
  cmp    $0xa,%al
  jne    L40
L164:
  movzbl 0x1(%r9,%rdi,1),%eax
  test   %al,%al
  je     L53
  cmp    $0xa,%al
  je     L133
  add    $0x1,%r10d
  cmp    $0x4,%r10d
  jg     L191
  mov    %ecx,%r8d
  jmp    L171
```

assistant: ```c
int perform_check(const char *str, int i, int j, int t) {
  while (str[++i])
    if ((str[i] != '.' && str[i] != '#' && str[i] != '\n') || ((i - t) % 5 == 4 && str[i] != '\n') || (str[i] == '\n' && (i - t) % 5 != 4))
      return (0);
    else if (str[i] == '\n') {
      j++;
      if (str[i + 1] == '\0')
        return (++t < 26 ? t : 0);
      else if (str[i + 1] == '\n') {
        t++;
        i++;
        j = 1;
      } else if (j > 4)
        return (0);
    }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<perform_check>:
  endbr64
  mov    %ecx,%r11d
  lea    0x1(%rsi),%ecx
  mov    %rdi,%r9
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L140
  push   %rbx
  mov    %esi,%r8d
  mov    %edx,%r10d
  jmp    L101
  cs nopw 0x0(%rax,%rax,1)
L60:
  cmp    $0xa,%al
  jne    L24
  mov    %ecx,%edx
  sub    %r11d,%edx
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x21,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edx
  cmp    $0x4,%edx
  jne    L24
  movzbl 0x1(%r9,%rdi,1),%eax
  test   %al,%al
  je     L14
L100:
  cmp    $0xa,%al
  je     L52
  add    $0x1,%r10d
  cmp    $0x4,%r10d
  jg     L24
L95:
  mov    %ecx,%r8d
L143:
  lea    0x1(%r8),%ecx
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L24
L101:
  cmp    $0x2e,%al
  je     L102
  cmp    $0x23,%al
  jne    L60
L102:
  mov    %ecx,%esi
  sub    %r11d,%esi
  movslq %esi,%rdx
  mov    %esi,%ebx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ebx
  sar    $0x21,%rdx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%esi
  cmp    $0x4,%esi
  je     L72
  cmp    $0xa,%al
  jne    L95
L24:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L72:
  cmp    $0xa,%al
  jne    L24
  movzbl 0x1(%r9,%rdi,1),%eax
  test   %al,%al
  jne    L100
L14:
  lea    0x1(%r11),%eax
  xor    %edx,%edx
  pop    %rbx
  cmp    $0x1a,%eax
  cmovge %edx,%eax
  ret
  nopl   0x0(%rax)
L52:
  add    $0x1,%r11d
  add    $0x2,%r8d
  mov    $0x1,%r10d
  jmp    L143
L140:
  xor    %eax,%eax
  ret
```

assistant: ```c
int perform_check(const char *str, int i, int j, int t) {
  while (str[++i])
    if ((str[i] != '.' && str[i] != '#' && str[i] != '\n') || ((i - t) % 5 == 4 && str[i] != '\n') || (str[i] == '\n' && (i - t) % 5 != 4))
      return (0);
    else if (str[i] == '\n') {
      j++;
      if (str[i + 1] == '\0')
        return (++t < 26 ? t : 0);
      else if (str[i + 1] == '\n') {
        t++;
        i++;
        j = 1;
      } else if (j > 4)
        return (0);
    }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<perform_check>:
  endbr64
  mov    %ecx,%r11d
  lea    0x1(%rsi),%ecx
  mov    %rdi,%r9
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L97
  push   %rbx
  mov    %esi,%r8d
  mov    %edx,%r10d
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L62:
  cmp    $0xa,%al
  jne    L35
  mov    %ecx,%edx
  sub    %r11d,%edx
  movslq %edx,%rax
  mov    %edx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x21,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%eax
  sub    %eax,%edx
  cmp    $0x4,%edx
  jne    L35
  movzbl 0x1(%r9,%rdi,1),%eax
  test   %al,%al
  je     L89
L47:
  cmp    $0xa,%al
  je     L94
  add    $0x1,%r10d
  cmp    $0x4,%r10d
  jg     L35
L88:
  mov    %ecx,%r8d
L73:
  lea    0x1(%r8),%ecx
  movslq %ecx,%rdi
  movzbl (%r9,%rdi,1),%eax
  test   %al,%al
  je     L35
L52:
  cmp    $0x2e,%al
  je     L74
  cmp    $0x23,%al
  jne    L62
L74:
  mov    %ecx,%esi
  sub    %r11d,%esi
  movslq %esi,%rdx
  mov    %esi,%ebx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ebx
  sar    $0x21,%rdx
  sub    %ebx,%edx
  lea    (%rdx,%rdx,4),%edx
  sub    %edx,%esi
  cmp    $0x4,%esi
  je     L146
  cmp    $0xa,%al
  jne    L88
L35:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L146:
  cmp    $0xa,%al
  jne    L35
  movzbl 0x1(%r9,%rdi,1),%eax
  test   %al,%al
  jne    L47
L89:
  lea    0x1(%r11),%eax
  xor    %edx,%edx
  pop    %rbx
  cmp    $0x1a,%eax
  cmovge %edx,%eax
  ret
  nopl   0x0(%rax)
L94:
  add    $0x1,%r11d
  add    $0x2,%r8d
  mov    $0x1,%r10d
  jmp    L73
L97:
  xor    %eax,%eax
  ret
```

assistant: ```c
int perform_check(const char *str, int i, int j, int t) {
  while (str[++i])
    if ((str[i] != '.' && str[i] != '#' && str[i] != '\n') || ((i - t) % 5 == 4 && str[i] != '\n') || (str[i] == '\n' && (i - t) % 5 != 4))
      return (0);
    else if (str[i] == '\n') {
      j++;
      if (str[i + 1] == '\0')
        return (++t < 26 ? t : 0);
      else if (str[i + 1] == '\n') {
        t++;
        i++;
        j = 1;
      } else if (j > 4)
        return (0);
    }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<range_ushrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %ax,-0x2(%rbp)
  movzwl -0x2(%rbp),%eax
  cmp    -0x14(%rbp),%ax
  jb     L14
  movzwl -0x18(%rbp),%eax
  cmp    -0x2(%rbp),%ax
  jae    L10
L14:
  movzwl -0x14(%rbp),%eax
  jmp    L0
L10:
  movzwl -0x2(%rbp),%eax
L0:
  leave
  ret
```

assistant: ```c
unsigned short range_ushrt(unsigned short min, unsigned short max) {
  unsigned short val = rand();
  return val < min || max < val ? min : val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<range_ushrt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edi,%r12d
  mov    $0x0,%eax
  call   <rand@plt>
  cmp    %bx,%ax
  jb     L4
  cmp    %bp,%ax
  cmovbe %eax,%r12d
L4:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned short range_ushrt(unsigned short min, unsigned short max) {
  unsigned short val = rand();
  return val < min || max < val ? min : val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<range_ushrt>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  cmp    %bx,%ax
  jb     L0
  cmp    %bp,%ax
  ja     L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short range_ushrt(unsigned short min, unsigned short max) {
  unsigned short val = rand();
  return val < min || max < val ? min : val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<range_ushrt>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <rand@plt>
  cmp    %bx,%ax
  jb     L15
  cmp    %bp,%ax
  ja     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned short range_ushrt(unsigned short min, unsigned short max) {
  unsigned short val = rand();
  return val < min || max < val ? min : val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<seq2xy>:
  endbr64
  cmp    $0x30c5cf,%edx
  ja     L2
  mov    %edx,%ecx
  imul   $0x78fc217,%rcx,%rcx
  mov    %rcx,%rax
  shr    $0x2a,%rax
  imul   $0x876c,%eax,%r8d
  mov    %edx,%eax
  sub    %r8d,%eax
  shr    $0x2a,%rcx
  lea    (%rcx,%rcx,2),%ecx
  shl    $0x3,%ecx
  mov    %ecx,(%rsi)
  cmp    $0x1aff,%eax
  jbe    L15
  sub    $0x1b00,%eax
  mov    %eax,%edx
  mov    $0xaa00aa01,%r8d
  imul   %r8,%rdx
  shr    $0x2a,%rdx
  lea    0x6(%rcx,%rdx,1),%ecx
  mov    %ecx,(%rsi)
  imul   $0x606,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rdi)
  ret
L2:
  movl   $0xffffffff,(%rdi)
  movl   $0xffffffff,(%rsi)
  ret
L15:
  movl   $0x6,(%rdi)
  mov    %eax,%edx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x28,%rdx
  add    %edx,(%rsi)
  lea    (%rdx,%rdx,8),%edx
  shl    $0x7,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,8),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  lea    (%rdx,%rdx,2),%edx
  lea    (%rax,%rdx,8),%eax
  add    %eax,(%rdi)
  ret
```

assistant: ```c
void seq2xy(int *x, int *y, unsigned seq) {
  unsigned rep;
  if (seq >= ((long)(((24 - 2 * 3) * ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2)) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1)))) * (93 - 1) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1))))) {
    *x = -1;
    *y = -1;
    return;
  }
  rep = seq / (((24 - 2 * 3) * ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2)) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1))));
  seq = seq % (((24 - 2 * 3) * ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2)) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1))));
  *y = ((2 * 3) + (24 - 2 * 3)) * rep;
  if (seq >= ((2 * 3) * ((24 - 2 * 3) * (65 - 1)))) {
    *y += (2 * 3);
    seq -= ((2 * 3) * ((24 - 2 * 3) * (65 - 1)));
    *y += seq / ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2);
    *x = seq % ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2);
  } else {
    unsigned gap;
    *x = 2 * 3;
    *y += seq / ((24 - 2 * 3) * (65 - 1));
    seq %= ((24 - 2 * 3) * (65 - 1));
    gap = seq / (24 - 2 * 3);
    *x += gap * 24;
    seq %= (24 - 2 * 3);
    *x += seq;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<seq2xy>:
  endbr64
  cmp    $0x30c5cf,%edx
  ja     L7
  mov    %edx,%ecx
  imul   $0x78fc217,%rcx,%rcx
  mov    %rcx,%rax
  shr    $0x2a,%rcx
  shr    $0x2a,%rax
  lea    (%rcx,%rcx,2),%ecx
  imul   $0x876c,%eax,%r8d
  mov    %edx,%eax
  shl    $0x3,%ecx
  mov    %ecx,(%rsi)
  sub    %r8d,%eax
  cmp    $0x1aff,%eax
  jbe    L5
  lea    -0x1b00(%rax),%edx
  mov    $0xaa00aa01,%r8d
  mov    %rdx,%rax
  imul   %r8,%rdx
  shr    $0x2a,%rdx
  lea    0x6(%rcx,%rdx,1),%ecx
  imul   $0x606,%edx,%edx
  mov    %ecx,(%rsi)
  sub    %edx,%eax
  mov    %eax,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %eax,%edx
  movl   $0x6,(%rdi)
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x28,%rdx
  add    %edx,(%rsi)
  lea    (%rdx,%rdx,8),%edx
  shl    $0x7,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x22,%rdx
  lea    (%rdx,%rdx,8),%ecx
  lea    (%rdx,%rdx,2),%edx
  add    %ecx,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rdx,8),%eax
  add    %eax,(%rdi)
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movl   $0xffffffff,(%rdi)
  movl   $0xffffffff,(%rsi)
  ret
```

assistant: ```c
void seq2xy(int *x, int *y, unsigned seq) {
  unsigned rep;
  if (seq >= ((long)(((24 - 2 * 3) * ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2)) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1)))) * (93 - 1) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1))))) {
    *x = -1;
    *y = -1;
    return;
  }
  rep = seq / (((24 - 2 * 3) * ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2)) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1))));
  seq = seq % (((24 - 2 * 3) * ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2)) + ((2 * 3) * ((24 - 2 * 3) * (65 - 1))));
  *y = ((2 * 3) + (24 - 2 * 3)) * rep;
  if (seq >= ((2 * 3) * ((24 - 2 * 3) * (65 - 1)))) {
    *y += (2 * 3);
    seq -= ((2 * 3) * ((24 - 2 * 3) * (65 - 1)));
    *y += seq / ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2);
    *x = seq % ((2 * 2 + (24 * (65 - 1) + 2 * 3)) - 2 * 2);
  } else {
    unsigned gap;
    *x = 2 * 3;
    *y += seq / ((24 - 2 * 3) * (65 - 1));
    seq %= ((24 - 2 * 3) * (65 - 1));
    gap = seq / (24 - 2 * 3);
    *x += gap * 24;
    seq %= (24 - 2 * 3);
    *x += seq;
  }
}
```