ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<submatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <nrerror@plt>
L2:
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L4:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x24(%rbp),%eax
  cltq
  mov    0x10(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: allocation failure in submatrix()

assistant: ```c
float **submatrix(a, oldrl, oldrh, oldcl, oldch, newrl, newcl)
float **a;
int oldrl, oldrh, oldcl, oldch, newrl, newcl;
{
  int i, j;
  float **m;
  m = (float **)malloc((unsigned)(oldrh - oldrl + 1) * sizeof(float *));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + oldcl - newcl;
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<submatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,%r14d
  mov    %r9d,%r15d
  mov    %edx,%eax
  sub    %esi,%eax
  lea    0x1(%rax),%edi
  shl    $0x3,%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L23
L33:
  movslq %r15d,%r15
  shl    $0x3,%r15
  mov    %r13,%rdi
  sub    %r15,%rdi
  cmp    %ebx,%ebp
  jl     L9
  movslq %r14d,%r14
  movslq 0x40(%rsp),%rax
  sub    %rax,%r14
  lea    0x0(,%r14,4),%rcx
  movslq %ebx,%rax
  mov    %rax,%rdx
  neg    %rdx
  lea    0x0(%r13,%rdx,8),%rsi
L5:
  mov    %rcx,%rdx
  add    (%r12,%rax,8),%rdx
  mov    %rdx,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jge    L5
L9:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <nrerror@plt>
  jmp    L33
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: allocation failure in submatrix()

assistant: ```c
float **submatrix(a, oldrl, oldrh, oldcl, oldch, newrl, newcl)
float **a;
int oldrl, oldrh, oldcl, oldch, newrl, newcl;
{
  int i, j;
  float **m;
  m = (float **)malloc((unsigned)(oldrh - oldrl + 1) * sizeof(float *));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + oldcl - newcl;
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<submatrix>:
  endbr64
  push   %r15
  mov    %edx,%eax
  push   %r14
  sub    %esi,%eax
  movslq %r9d,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rax),%edi
  push   %r12
  shl    $0x3,%rdi
  mov    %edx,%r12d
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L31
L18:
  shl    $0x3,%r14
  mov    %r15,%r8
  sub    %r14,%r8
  cmp    %ebx,%r12d
  jl     L15
  movslq 0x40(%rsp),%rax
  sub    %rax,%rbp
  movslq %ebx,%rax
  mov    %rax,%rdx
  lea    0x0(,%rbp,4),%rcx
  neg    %rdx
  lea    (%r15,%rdx,8),%rsi
  nopl   0x0(%rax)
L3:
  mov    0x0(%r13,%rax,8),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%r12d
  jge    L3
L15:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: allocation failure in submatrix()

assistant: ```c
float **submatrix(a, oldrl, oldrh, oldcl, oldch, newrl, newcl)
float **a;
int oldrl, oldrh, oldcl, oldch, newrl, newcl;
{
  int i, j;
  float **m;
  m = (float **)malloc((unsigned)(oldrh - oldrl + 1) * sizeof(float *));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + oldcl - newcl;
  return m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<submatrix>:
  endbr64
  push   %r15
  mov    %edx,%eax
  mov    %edx,%r15d
  push   %r14
  sub    %esi,%eax
  mov    %r9d,%r14d
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rax),%edi
  push   %r12
  shl    $0x3,%rdi
  push   %rbp
  movslq %ecx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L57
L45:
  movslq %r14d,%rcx
  mov    %r12,%r8
  lea    0x0(,%rcx,8),%rax
  sub    %rax,%r8
  cmp    %ebx,%r15d
  jl     L32
  movslq 0x40(%rsp),%rax
  mov    %r15d,%edi
  sub    %ebx,%edi
  sub    %rax,%rbp
  add    $0x1,%edi
  lea    0x0(,%rbp,4),%rdx
  cmp    %ebx,%r15d
  je     L3
  mov    %edi,%ecx
  movslq %ebx,%rax
  movq   %rdx,%xmm1
  shr    %ecx
  lea    0x0(%r13,%rax,8),%rsi
  punpcklqdq %xmm1,%xmm1
  xor    %eax,%eax
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L16:
  movdqu (%rsi,%rax,1),%xmm0
  paddq  %xmm1,%xmm0
  movups %xmm0,(%r12,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L16
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  add    %eax,%ebx
  add    %eax,%r14d
  cmp    %eax,%edi
  je     L32
  movslq %r14d,%rcx
L3:
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbx,8),%rax
  add    %rdx,%rax
  mov    %rax,(%r8,%rcx,8)
L32:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
  jmp    L45
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: allocation failure in submatrix()

assistant: ```c
float **submatrix(a, oldrl, oldrh, oldcl, oldch, newrl, newcl)
float **a;
int oldrl, oldrh, oldcl, oldch, newrl, newcl;
{
  int i, j;
  float **m;
  m = (float **)malloc((unsigned)(oldrh - oldrl + 1) * sizeof(float *));
  if (!m)
    nrerror("allocation failure in submatrix()");
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + oldcl - newcl;
  return m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<unsetbit_rng>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  and    $0x1f,%eax
  test   %rax,%rax
  je     L37
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  mov    %rdx,%rcx
  and    $0x1f,%ecx
  mov    $0x20,%edx
  sub    %rcx,%rdx
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L58
L10:
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <unsetbit@plt>
  addl   $0x1,-0x10(%rbp)
L58:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L10
  mov    -0xc(%rbp),%eax
  add    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x20(%rbp)
  jmp    L37
L21:
  mov    -0x1c(%rbp),%eax
  cltq
  shr    $0x5,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x20(%rbp),%eax
  sub    $0x20,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x20,%eax
  mov    %eax,-0x1c(%rbp)
L37:
  mov    -0x20(%rbp),%eax
  cmp    $0x1f,%eax
  ja     L21
  cmpl   $0x0,-0x20(%rbp)
  jle    L40
  mov    -0x1c(%rbp),%eax
  cltq
  shr    $0x5,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  neg    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  shr    $0x5,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  and    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
L40:
  nop
  leave
  ret
```

assistant: ```c
void unsetbit_rng(unsigned int *map, int bit, int len) {
  if (bit % (sizeof(unsigned int) * 8) != 0) {
    int i;
    int l = ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) < (len) ? ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) : (len);
    for (i = 0; i < l; i++)
      unsetbit(map, bit + i);
    bit += l;
    len -= l;
  }
  while (len >= (sizeof(unsigned int) * 8)) {
    map[bit / (sizeof(unsigned int) * 8)] = (unsigned int)0;
    len -= (sizeof(unsigned int) * 8);
    bit += (sizeof(unsigned int) * 8);
  }
  if (len > 0) {
    unsigned int v = map[bit / (sizeof(unsigned int) * 8)];
    int m = ((unsigned int)-1) ^ ((1 << len) - 1);
    map[bit / (sizeof(unsigned int) * 8)] = v & m;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unsetbit_rng>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %edx,%r13d
  mov    %esi,%eax
  and    $0x1f,%eax
  je     L31
  cltq
  mov    $0x20,%r14d
  sub    %rax,%r14
  movslq %edx,%rax
  cmp    %rax,%r14
  cmova  %rax,%r14
  test   %r14d,%r14d
  jle    L13
  mov    %esi,%r12d
  lea    (%rsi,%r14,1),%r15d
L42:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <unsetbit@plt>
  add    $0x1,%r12d
  cmp    %r15d,%r12d
  jne    L42
L13:
  add    %r14d,%ebx
  sub    %r14d,%r13d
L31:
  cmp    $0x1f,%r13d
  jbe    L56
  sub    $0x20,%r13d
  mov    %ebx,%ecx
  mov    %r13d,%eax
  and    $0xffffffe0,%eax
  lea    0x20(%rbx,%rax,1),%edx
L41:
  movslq %ebx,%rax
  shr    $0x5,%rax
  movl   $0x0,0x0(%rbp,%rax,4)
  lea    0x20(%rbx),%eax
  mov    %eax,%ebx
  cmp    %eax,%edx
  jne    L41
  mov    %r13d,%eax
  and    $0xffffffe0,%eax
  lea    0x20(%rcx,%rax,1),%ebx
  and    $0x1f,%r13d
L56:
  test   %r13d,%r13d
  jle    L28
  movslq %ebx,%rbx
  shr    $0x5,%rbx
  mov    $0xffffffff,%eax
  mov    %r13d,%ecx
  shl    %cl,%eax
  and    %eax,0x0(%rbp,%rbx,4)
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void unsetbit_rng(unsigned int *map, int bit, int len) {
  if (bit % (sizeof(unsigned int) * 8) != 0) {
    int i;
    int l = ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) < (len) ? ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) : (len);
    for (i = 0; i < l; i++)
      unsetbit(map, bit + i);
    bit += l;
    len -= l;
  }
  while (len >= (sizeof(unsigned int) * 8)) {
    map[bit / (sizeof(unsigned int) * 8)] = (unsigned int)0;
    len -= (sizeof(unsigned int) * 8);
    bit += (sizeof(unsigned int) * 8);
  }
  if (len > 0) {
    unsigned int v = map[bit / (sizeof(unsigned int) * 8)];
    int m = ((unsigned int)-1) ^ ((1 << len) - 1);
    map[bit / (sizeof(unsigned int) * 8)] = v & m;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<unsetbit_rng>:
  endbr64
  movslq %esi,%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  mov    %eax,%edx
  push   %rbp
  push   %rbx
  and    $0x1f,%edx
  je     L52
  movslq %edx,%rdx
  mov    $0x20,%r14d
  mov    %eax,%ebp
  sub    %rdx,%r14
  movslq %r12d,%rdx
  cmp    %rdx,%r14
  cmova  %rdx,%r14
  test   %r14,%r14
  je     L37
  mov    %eax,%ebx
  lea    (%rax,%r14,1),%ebp
  nop
L56:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <unsetbit@plt>
  cmp    %ebp,%ebx
  jne    L56
L37:
  movslq %ebp,%rax
  sub    %r14d,%r12d
L52:
  cmp    $0x1f,%r12d
  jbe    L11
  sub    $0x20,%r12d
  lea    0x20(%rax),%edx
  mov    %eax,%edi
  mov    %r12d,%ecx
  and    $0xffffffe0,%ecx
  lea    (%rdx,%rcx,1),%esi
  jmp    L40
  nopl   0x0(%rax)
L5:
  add    $0x20,%edx
L40:
  shr    $0x5,%rax
  movl   $0x0,0x0(%r13,%rax,4)
  movslq %edx,%rax
  cmp    %eax,%esi
  jne    L5
  lea    0x20(%rcx,%rdi,1),%eax
  and    $0x1f,%r12d
L11:
  test   %r12d,%r12d
  je     L67
  cltq
  mov    $0xffffffff,%edx
  mov    %r12d,%ecx
  shr    $0x5,%rax
  shl    %cl,%edx
  and    %edx,0x0(%r13,%rax,4)
L67:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void unsetbit_rng(unsigned int *map, int bit, int len) {
  if (bit % (sizeof(unsigned int) * 8) != 0) {
    int i;
    int l = ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) < (len) ? ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) : (len);
    for (i = 0; i < l; i++)
      unsetbit(map, bit + i);
    bit += l;
    len -= l;
  }
  while (len >= (sizeof(unsigned int) * 8)) {
    map[bit / (sizeof(unsigned int) * 8)] = (unsigned int)0;
    len -= (sizeof(unsigned int) * 8);
    bit += (sizeof(unsigned int) * 8);
  }
  if (len > 0) {
    unsigned int v = map[bit / (sizeof(unsigned int) * 8)];
    int m = ((unsigned int)-1) ^ ((1 << len) - 1);
    map[bit / (sizeof(unsigned int) * 8)] = v & m;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<unsetbit_rng>:
  endbr64
  movslq %esi,%rax
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  mov    %eax,%edx
  push   %rbp
  push   %rbx
  and    $0x1f,%edx
  je     L14
  movslq %edx,%rdx
  mov    $0x20,%r14d
  mov    %eax,%ebp
  sub    %rdx,%r14
  movslq %r12d,%rdx
  cmp    %rdx,%r14
  cmova  %rdx,%r14
  test   %r14,%r14
  je     L27
  mov    %eax,%ebx
  lea    (%rax,%r14,1),%ebp
  nop
L56:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <unsetbit@plt>
  cmp    %ebx,%ebp
  jne    L56
L27:
  movslq %ebp,%rax
  sub    %r14d,%r12d
L14:
  cmp    $0x1f,%r12d
  jbe    L52
  sub    $0x20,%r12d
  lea    0x20(%rax),%edx
  mov    %eax,%edi
  mov    %r12d,%ecx
  and    $0xffffffe0,%ecx
  lea    (%rdx,%rcx,1),%esi
  jmp    L66
  nopl   0x0(%rax)
L51:
  add    $0x20,%edx
L66:
  shr    $0x5,%rax
  movl   $0x0,0x0(%r13,%rax,4)
  movslq %edx,%rax
  cmp    %esi,%eax
  jne    L51
  lea    0x20(%rdi,%rcx,1),%eax
  and    $0x1f,%r12d
L52:
  test   %r12d,%r12d
  je     L11
  cltq
  mov    $0xffffffff,%edx
  mov    %r12d,%ecx
  shr    $0x5,%rax
  shl    %cl,%edx
  and    %edx,0x0(%r13,%rax,4)
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void unsetbit_rng(unsigned int *map, int bit, int len) {
  if (bit % (sizeof(unsigned int) * 8) != 0) {
    int i;
    int l = ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) < (len) ? ((sizeof(unsigned int) * 8) - (bit % (sizeof(unsigned int) * 8))) : (len);
    for (i = 0; i < l; i++)
      unsetbit(map, bit + i);
    bit += l;
    len -= l;
  }
  while (len >= (sizeof(unsigned int) * 8)) {
    map[bit / (sizeof(unsigned int) * 8)] = (unsigned int)0;
    len -= (sizeof(unsigned int) * 8);
    bit += (sizeof(unsigned int) * 8);
  }
  if (len > 0) {
    unsigned int v = map[bit / (sizeof(unsigned int) * 8)];
    int m = ((unsigned int)-1) ^ ((1 << len) - 1);
    map[bit / (sizeof(unsigned int) * 8)] = v & m;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<_string_duplicate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  jmp    L10
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: Not enough memory for error message

assistant: ```c
char *_string_duplicate(const char *string) {
  char *copy = malloc(sizeof(*copy) * (strlen(string) + 1));
  if (copy == NULL) {
    strcpy(copy, "Not enough memory for error message");
    return (copy);
  }
  strcpy(copy, string);
  return copy;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_string_duplicate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L15
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L14:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D2(%rip),%rsi
  mov    $0x0,%edi
  call   <strcpy@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_infered: string

tool: D2: Not enough memory for error message

assistant: ```c
char *_string_duplicate(const char *string) {
  char *copy = malloc(sizeof(*copy) * (strlen(string) + 1));
  if (copy == NULL) {
    strcpy(copy, "Not enough memory for error message");
    return (copy);
  }
  strcpy(copy, string);
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_string_duplicate>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D2(%rip),%rsi
  xor    %edi,%edi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string

tool: D2: Not enough memory for error message

assistant: ```c
char *_string_duplicate(const char *string) {
  char *copy = malloc(sizeof(*copy) * (strlen(string) + 1));
  if (copy == NULL) {
    strcpy(copy, "Not enough memory for error message");
    return (copy);
  }
  strcpy(copy, string);
  return copy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_string_duplicate>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D3(%rip),%rsi
  xor    %edi,%edi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: Not enough memory for error message

assistant: ```c
char *_string_duplicate(const char *string) {
  char *copy = malloc(sizeof(*copy) * (strlen(string) + 1));
  if (copy == NULL) {
    strcpy(copy, "Not enough memory for error message");
    return (copy);
  }
  strcpy(copy, string);
  return copy;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Jump_If_Greater>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <Inst_Printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D13
type_infered: string

tool: D19: cr1,_%s

tool: D13: bgt

assistant: ```c
void Jump_If_Greater(char *label) {
  Inst_Printf("bgt",
              "cr"
              "1"
              ","
              "_"
              "%s",
              label);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Jump_If_Greater>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  lea    D5(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <Inst_Printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D13
type: string

tool: D5: cr1,_%s

tool: D13: bgt

assistant: ```c
void Jump_If_Greater(char *label) {
  Inst_Printf("bgt",
              "cr"
              "1"
              ","
              "_"
              "%s",
              label);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Jump_If_Greater>:
  endbr64
  mov    %rdi,%rdx
  lea    D6(%rip),%rsi
  lea    D9(%rip),%rdi
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D6: cr1,_%s

tool: D9: bgt

assistant: ```c
void Jump_If_Greater(char *label) {
  Inst_Printf("bgt",
              "cr"
              "1"
              ","
              "_"
              "%s",
              label);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Jump_If_Greater>:
  endbr64
  mov    %rdi,%rdx
  lea    D16(%rip),%rsi
  lea    D17(%rip),%rdi
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string

tool: D16: cr1,_%s

tool: D17: bgt

assistant: ```c
void Jump_If_Greater(char *label) {
  Inst_Printf("bgt",
              "cr"
              "1"
              ","
              "_"
              "%s",
              label);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtoi_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L7
L18:
  mov    D16(%rip),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x34(%rbp),%edx
  lea    -0x10(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L60
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L7
L60:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jne    L23
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L7
L23:
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
  mov    $0x2,%eax
  jmp    L7
L38:
  mov    $0x1,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
int strtoi_base(char **str, int *dest, int base) {
  ((void)0);
  if (**str == '\0')
    return -EINVAL;
  char *endptr;
  errno = 0;
  int num = strtol(*str, &endptr, base);
  if (errno != 0)
    return -errno;
  if (*str == endptr)
    return -EINVAL;
  *dest = num;
  *str = endptr;
  if (*endptr == 0)
    return 2;
  return 1;
}
```