ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<vasprintf>:
  endbr64
  push   %r14
  mov    %edx,%ecx
  mov    %edx,%r14d
  mov    %rsi,%rdx
  push   %r13
  mov    %rsi,%r13
  mov    $0x100,%esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  movslq %eax,%r12
  cmp    $0xff,%r12d
  jle    L20
  add    $0x1,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L10
  mov    %r12,%rsi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <vsnprintf@plt>
  mov    %eax,%r12d
L44:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x110,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L20:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L44
  nopl   (%rax)
L10:
  mov    D0(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  jmp    L44
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vasprintf(char **strp, const char *fmt, va_list ap) {
  char buffer[256];
  int count = vsnprintf(buffer, 256, fmt, ap);
  if (count < 256) {
    *strp = strdup(buffer);
    return count;
  } else {
    *strp = (char *)malloc((size_t)count + 1);
    if (*strp == NULL) {
      errno = ENOMEM;
      return -1;
    };
    return vsnprintf(*strp, (size_t)count + 1, fmt, ap);
  };
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vasprintf>:
  endbr64
  push   %r14
  mov    %edx,%ecx
  mov    %edx,%r14d
  mov    %rsi,%rdx
  push   %r13
  mov    %rsi,%r13
  mov    $0x100,%esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  movslq %eax,%r12
  cmp    $0xff,%r12d
  jle    L28
  add    $0x1,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L36
  mov    %r12,%rsi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <vsnprintf@plt>
  mov    %eax,%r12d
L20:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x110,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L28:
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L20
  nopl   (%rax)
L36:
  mov    D18(%rip),%rax
  mov    $0xffffffff,%r12d
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  jmp    L20
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int vasprintf(char **strp, const char *fmt, va_list ap) {
  char buffer[256];
  int count = vsnprintf(buffer, 256, fmt, ap);
  if (count < 256) {
    *strp = strdup(buffer);
    return count;
  } else {
    *strp = (char *)malloc((size_t)count + 1);
    if (*strp == NULL) {
      errno = ENOMEM;
      return -1;
    };
    return vsnprintf(*strp, (size_t)count + 1, fmt, ap);
  };
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x24a8,-0x4(%rbp)
  jmp    L9
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L9:
  cmpl   $0x0,-0x4(%rbp)
  jg     L12
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string

tool: D9: %d 

assistant: ```c
int main() {
  int i;
  for (i = 9384; i > 0; i /= 10) {
    printf("%d ", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%ebp
  mov    $0x24a8,%ebx
  lea    D4(%rip),%r12
L1:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  sub    $0x1,%ebp
  jne    L1
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: %d 

assistant: ```c
int main() {
  int i;
  for (i = 9384; i > 0; i /= 10) {
    printf("%d ", i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
  mov    $0x24a8,%ebx
L6:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%ebx
  sub    $0x1,%ebp
  jne    L6
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: %d 

assistant: ```c
int main() {
  int i;
  for (i = 9384; i > 0; i /= 10) {
    printf("%d ", i);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
  mov    $0x24a8,%ebx
L9:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  movslq %ebx,%rax
  mov    %ebx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  mov    %eax,%ebx
  sub    $0x1,%ebp
  jne    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: %d 

assistant: ```c
int main() {
  int i;
  for (i = 9384; i > 0; i /= 10) {
    printf("%d ", i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  movl   $0x6,-0xc(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    $0x3,%ecx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <uniao@plt>
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L25
L7:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L25:
  cmpl   $0x5,-0x2c(%rbp)
  jle    L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: %d


assistant: ```c
int main(void) {
  int v1[] = {1, 2, 3};
  int v2[] = {4, 5, 6};
  int *pAux = uniao(v1, 3, v2, 3);
  for (int i = 0; i < 6; i++) {
    printf("%d\n", pAux[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  lea    0xc(%rsp),%rdx
  mov    %rsp,%rdi
  mov    $0x3,%ecx
  mov    $0x3,%esi
  call   <uniao@plt>
  mov    %rax,%rbx
  lea    0x18(%rax),%r12
  lea    D6(%rip),%rbp
L7:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L7
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main(void) {
  int v1[] = {1, 2, 3};
  int v2[] = {4, 5, 6};
  int *pAux = uniao(v1, 3, v2, 3);
  for (int i = 0; i < 6; i++) {
    printf("%d\n", pAux[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%ecx
  mov    $0x3,%esi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  lea    0xc(%rsp),%rdx
  mov    %rsp,%rdi
  movl   $0x3,0x8(%rsp)
  movl   $0x6,0x14(%rsp)
  mov    %rax,(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0xc(%rsp)
  call   <uniao@plt>
  mov    %rax,%rbx
  lea    0x18(%rax),%r12
  nopl   0x0(%rax)
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: %d


assistant: ```c
int main(void) {
  int v1[] = {1, 2, 3};
  int v2[] = {4, 5, 6};
  int *pAux = uniao(v1, 3, v2, 3);
  for (int i = 0; i < 6; i++) {
    printf("%d\n", pAux[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%ecx
  mov    $0x3,%esi
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D19(%rip),%rax
  lea    0x18(%rsp),%rdx
  lea    0x8(%rsp),%rdi
  movl   $0x3,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  mov    D9(%rip),%rax
  movl   $0x6,0x20(%rsp)
  mov    %rax,0x18(%rsp)
  call   <uniao@plt>
  mov    %rax,%rbx
  lea    0x18(%rax),%r12
  nopl   0x0(%rax,%rax,1)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D19
type: byte[8]
name: disassemble_data
arguments: data_tag: D9
type: byte[8]

tool: D16: %d


tool: {"D19": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D9": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int v1[] = {1, 2, 3};
  int v2[] = {4, 5, 6};
  int *pAux = uniao(v1, 3, v2, 3);
  for (int i = 0; i < 6; i++) {
    printf("%d\n", pAux[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pyth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pyth(int side1, int side2) {
  int a = abs(side1);
  int b = abs(side2);
  return (a > b) ? a : b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pyth>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  mov    %esi,%edx
  neg    %edx
  cmovs  %esi,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int pyth(int side1, int side2) {
  int a = abs(side1);
  int b = abs(side2);
  return (a > b) ? a : b;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pyth>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  neg    %eax
  cmovs  %edi,%eax
  neg    %edx
  cmovs  %esi,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int pyth(int side1, int side2) {
  int a = abs(side1);
  int b = abs(side2);
  return (a > b) ? a : b;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pyth>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  neg    %eax
  cmovs  %edi,%eax
  neg    %edx
  cmovs  %esi,%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
  ret
```

assistant: ```c
int pyth(int side1, int side2) {
  int a = abs(side1);
  int b = abs(side2);
  return (a > b) ? a : b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DataFlag_waitAndSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <DataFlag_set@plt>
  test   %eax,%eax
  je     L7
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int DataFlag_waitAndSet(struct DataFlag *this, char *dataToWrite) {
  while (!DataFlag_set(this, dataToWrite)) {
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DataFlag_waitAndSet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
L7:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <DataFlag_set@plt>
  test   %eax,%eax
  je     L7
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DataFlag_waitAndSet(struct DataFlag *this, char *dataToWrite) {
  while (!DataFlag_set(this, dataToWrite)) {
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DataFlag_waitAndSet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L2:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <DataFlag_set@plt>
  test   %eax,%eax
  je     L2
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DataFlag_waitAndSet(struct DataFlag *this, char *dataToWrite) {
  while (!DataFlag_set(this, dataToWrite)) {
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DataFlag_waitAndSet>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
L4:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <DataFlag_set@plt>
  test   %eax,%eax
  je     L4
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int DataFlag_waitAndSet(struct DataFlag *this, char *dataToWrite) {
  while (!DataFlag_set(this, dataToWrite)) {
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_find_operator_function_by_string_valid_null_functions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <find_operator_function_by_string@plt>
  mov    %eax,%edi
  mov    $0xa2,%ecx
  lea    D2(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string
name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D5: test

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_find_operator_function_by_string_valid_null_functions(void **state) {
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(find_operator_function_by_string(0, NULL, "test")))), ((unsigned long long)((unsigned)(size_t)(NULL))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 162);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_find_operator_function_by_string_valid_null_functions>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <find_operator_function_by_string@plt>
  mov    %eax,%edi
  mov    $0xa2,%ecx
  lea    D13(%rip),%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D13
type_guessed: string

tool: D10: test

tool: D13: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_find_operator_function_by_string_valid_null_functions(void **state) {
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(find_operator_function_by_string(0, NULL, "test")))), ((unsigned long long)((unsigned)(size_t)(NULL))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 162);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_find_operator_function_by_string_valid_null_functions>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <find_operator_function_by_string@plt>
  mov    $0xa2,%ecx
  xor    %esi,%esi
  add    $0x8,%rsp
  mov    %eax,%edi
  lea    D16(%rip),%rdx
  jmp    1070 <_assert_int_equal@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_guessed: string
name: unpack_data
arguments: data_tag: D16
type_guessed: string

tool: D14: test

tool: D16: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_find_operator_function_by_string_valid_null_functions(void **state) {
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(find_operator_function_by_string(0, NULL, "test")))), ((unsigned long long)((unsigned)(size_t)(NULL))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 162);
}
```
user: What is the c source code of the assembly code below?

```asm
<test_find_operator_function_by_string_valid_null_functions>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <find_operator_function_by_string@plt>
  mov    $0xa2,%ecx
  xor    %esi,%esi
  add    $0x8,%rsp
  mov    %eax,%edi
  lea    D3(%rip),%rdx
  jmp    1070 <_assert_int_equal@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D3
type_guessed: string

tool: D18: test

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_find_operator_function_by_string_valid_null_functions(void **state) {
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(find_operator_function_by_string(0, NULL, "test")))), ((unsigned long long)((unsigned)(size_t)(NULL))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 162);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bufwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L19
L13:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    D35(%rip),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,D18(%rip)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L19:
  subl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L13
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D37
type: string

tool: D37: buffer:%s


assistant: ```c
void bufwrite(char *p, int n) {
  static char buffer[1024];
  static char *bufptr = &buffer[0];
  while (--n >= 0) {
    if (bufptr == &buffer[1024]) {
    }
    *bufptr++ = *p++;
  }
  printf("buffer:%s\n", &buffer[0]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bufwrite>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L8
  mov    D19(%rip),%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
L5:
  add    $0x1,%rdi
  mov    %rax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%rdi),%edx
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rdi
  jne    L5
  mov    %rax,D11(%rip)
  mov    %dl,(%rcx)
L8:
  lea    D11(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: string

tool: D16: buffer:%s


assistant: ```c
void bufwrite(char *p, int n) {
  static char buffer[1024];
  static char *bufptr = &buffer[0];
  while (--n >= 0) {
    if (bufptr == &buffer[1024]) {
    }
    *bufptr++ = *p++;
  }
  printf("buffer:%s\n", &buffer[0]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bufwrite>:
  endbr64
  test   %esi,%esi
  jle    L3
  sub    $0x1,%esi
  mov    D35(%rip),%rcx
  xor    %eax,%eax
  lea    0x1(%rsi),%r8
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L13
  add    %r8,%rcx
  mov    %rcx,D27(%rip)
L3:
  lea    D27(%rip),%rsi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: buffer:%s


assistant: ```c
void bufwrite(char *p, int n) {
  static char buffer[1024];
  static char *bufptr = &buffer[0];
  while (--n >= 0) {
    if (bufptr == &buffer[1024]) {
    }
    *bufptr++ = *p++;
  }
  printf("buffer:%s\n", &buffer[0]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bufwrite>:
  endbr64
  mov    %esi,%edx
  push   %rbx
  sub    $0x1,%edx
  js     L43
  mov    %rdi,%rcx
  mov    %esi,%edi
  mov    D11(%rip),%rsi
  mov    %edx,%r10d
  lea    0x1(%rcx),%r8
  mov    %edi,%r9d
  mov    %rsi,%rax
  sub    %r8,%rax
  cmp    $0xe,%rax
  jbe    L56
  cmp    $0x6,%edx
  jbe    L56
  cmp    $0xe,%edx
  jbe    L51
  mov    %edi,%r8d
  xor    %eax,%eax
  shr    $0x4,%r8d
  shl    $0x4,%r8
  nopl   (%rax)
L41:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r8
  jne    L41
  mov    %edi,%ebx
  and    $0xfffffff0,%ebx
  mov    %ebx,%r11d
  sub    %ebx,%edx
  lea    (%rcx,%r11,1),%r8
  lea    (%rsi,%r11,1),%rax
  cmp    %ebx,%edi
  je     L126
  sub    %ebx,%edi
  mov    %edi,%r9d
  lea    -0x1(%rdi),%edi
  cmp    $0x6,%edi
  jbe    L112
L26:
  mov    (%rcx,%r11,1),%rcx
  mov    %rcx,(%rsi,%r11,1)
  mov    %r9d,%ecx
  and    $0xfffffff8,%ecx
  mov    %ecx,%edi
  sub    %ecx,%edx
  add    %rdi,%r8
  add    %rdi,%rax
  cmp    %ecx,%r9d
  je     L126
L112:
  movzbl (%r8),%ecx
  mov    %edx,%ebx
  sub    $0x1,%ebx
  mov    %cl,(%rax)
  js     L126
  movzbl 0x1(%r8),%ecx
  mov    %cl,0x1(%rax)
  cmp    $0x1,%edx
  je     L126
  movzbl 0x2(%r8),%ecx
  mov    %cl,0x2(%rax)
  cmp    $0x2,%edx
  je     L126
  movzbl 0x3(%r8),%ecx
  mov    %cl,0x3(%rax)
  cmp    $0x3,%edx
  je     L126
  movzbl 0x4(%r8),%ecx
  mov    %cl,0x4(%rax)
  cmp    $0x4,%edx
  je     L126
  movzbl 0x5(%r8),%ecx
  mov    %cl,0x5(%rax)
  cmp    $0x5,%edx
  je     L126
  movzbl 0x6(%r8),%edx
  mov    %dl,0x6(%rax)
L126:
  mov    %r10d,%r10d
  lea    0x1(%rsi,%r10,1),%rax
  mov    %rax,D14(%rip)
L43:
  lea    D14(%rip),%rsi
  lea    D0(%rip),%rdi
  pop    %rbx
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L105:
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rsi,%rax,1)
  mov    %rax,%rdi
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L105
  jmp    L126
L51:
  mov    %rsi,%rax
  mov    %rcx,%r8
  xor    %r11d,%r11d
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: buffer:%s


assistant: ```c
void bufwrite(char *p, int n) {
  static char buffer[1024];
  static char *bufptr = &buffer[0];
  while (--n >= 0) {
    if (bufptr == &buffer[1024]) {
    }
    *bufptr++ = *p++;
  }
  printf("buffer:%s\n", &buffer[0]);
}
```