user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D133(%rip),%rdi
  call   <puts@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L86:
  add    $0x1,%eax
  cmp    $0xf,%eax
  jne    L86
  mov    $0x0,%eax
L80:
  add    $0x1,%eax
  cmp    $0x1f,%eax
  jne    L80
  mov    $0x0,%eax
L58:
  add    $0x1,%eax
  cmp    $0x3f,%eax
  jne    L58
  mov    $0x0,%eax
  movss  D111(%rip),%xmm0
  movss  D28(%rip),%xmm3
L49:
  movaps %xmm0,%xmm1
  addss  %xmm0,%xmm0
  mov    %eax,%ebx
  add    $0x1,%eax
  movaps %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  ucomiss %xmm1,%xmm2
  jp     L81
  je     L49
L81:
  mov    $0x0,%eax
L5:
  add    $0x1,%eax
  cmp    $0x96,%eax
  jne    L5
  mov    $0x0,%eax
  movsd  D12(%rip),%xmm0
  movsd  D45(%rip),%xmm3
L39:
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm0
  mov    %eax,%ebp
  add    $0x1,%eax
  movapd %xmm0,%xmm2
  mulsd  %xmm3,%xmm2
  ucomisd %xmm1,%xmm2
  jp     L16
  je     L39
L16:
  mov    $0x0,%eax
  movsd  D12(%rip),%xmm0
  movsd  D45(%rip),%xmm2
  pxor   %xmm1,%xmm1
L3:
  mulsd  %xmm2,%xmm0
  mov    %eax,%r12d
  add    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L3
  mov    $0x6,%esi
  lea    D95(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xe,%esi
  lea    D110(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1e,%esi
  lea    D88(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3e,%esi
  lea    D122(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x95,%edx
  mov    %ebx,%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D133
type: string
name: read_data
arguments: data_tag: D59
type: string
name: read_data
arguments: data_tag: D111
type: f32
name: read_data
arguments: data_tag: D28
type: byte[4]
name: read_data
arguments: data_tag: D12
type: byte[8]
name: read_data
arguments: data_tag: D45
type: byte[8]
name: read_data
arguments: data_tag: D95
type: string
name: read_data
arguments: data_tag: D110
type: string
name: read_data
arguments: data_tag: D88
type: string
name: read_data
arguments: data_tag: D122
type: string
name: read_data
arguments: data_tag: D37
type: string
name: read_data
arguments: data_tag: D35
type: string

tool: D133: char is signed

tool: D59: This machine is little endian

tool: D111: 1

tool: {"D28": [0x00,0x00,0x00,0x3f]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D95: The largest positive power of 2 represented with char  is %d


tool: D110: The largest positive power of 2 represented with short is %d


tool: D88: The largest positive power of 2 represented with int is %d


tool: D122: The largest positive power of 2 represented with long is %d


tool: D37: The largest positive and negative powers of 2 represented with float are %d and %d respectively


tool: D35: The largest positive and negative powers of 2 represented with double are %d and %d respectively


assistant: ```c
int main(void) {
  char a = 1, a1 = 1, a2 = 1;
  short b = 1, b1;
  int c = 1, c1, x = 1;
  long d = 1, d1;
  float e = 1, e1 = 1, e2 = 1, g = 1, g1;
  double f = 1, f1 = 1, f2 = 1, h = 1, h1;
  int i = 0, j = 0, k = 0, l = 0, m = 0, n = 0, o = 0, p = 0;
  char *y = (char *)&x;
  while (a1 > 0) {
    a = a1;
    a1 = a * 2;
    a2 = a1 / 2;
    i++;
  }
  if (a2 != 0)
    printf("char is signed\n");
  else
    printf("char is unsigned\n");
  if (y[0] == 0)
    printf("This machine is BIG endian\n");
  else
    printf("This machine is little endian\n");
  while (b > 0) {
    b = b * 2;
    b1 = b / 2;
    j++;
  }
  while (c > 0) {
    c = c * 2;
    c1 = c / 2;
    k++;
  }
  while (d > 0) {
    d = d * 2;
    d1 = d / 2;
    l++;
  }
  while (e == e2) {
    e = e1;
    e1 = e * 2;
    e2 = e1 / 2;
    m++;
  }
  while (g > 0) {
    g = g / 2;
    g1 = g * 2;
    o++;
  }
  while (f == f2) {
    f = f1;
    f1 = f * 2;
    f2 = f1 / 2;
    n++;
  }
  while (h > 0) {
    h = h / 2;
    h1 = h * 2;
    p++;
  }
  i = i - 1;
  j = j - 1;
  k = k - 1;
  l = l - 1;
  m = m - 1;
  n = n - 1;
  o = o - 1;
  p = p - 1;
  printf("The largest positive power of 2 represented with char  is %d\n", i);
  printf("The largest positive power of 2 represented with short is %d\n", j);
  printf("The largest positive power of 2 represented with int is %d\n", k);
  printf("The largest positive power of 2 represented with long is %d\n", l);
  printf("The largest positive and negative powers of 2 represented with float are %d and %d respectively\n", m, o);
  printf("The largest positive and negative powers of 2 represented with double are %d and %d respectively\n", n, p);
  return 0;
}
```