user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r14
  movaps %xmm0,0x10(%rsp)
  mov    %r14,%rsi
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x70(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  call   <scanf@plt>
  mov    0x8(%rsp),%edx
  test   %edx,%edx
  jle    L130
  xor    %ebx,%ebx
  lea    0x7(%rsp),%r13
  lea    D12(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L46:
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  lea    -0x76(%rax),%edx
  and    $0xfd,%edx
  je     L97
  cmp    $0x2e,%al
  jne    L110
L97:
  mov    %al,0x10(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    %ebx,0x8(%rsp)
  jg     L46
L130:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L6
  xor    %ebx,%ebx
  lea    0xc(%rsp),%r13
  lea    0x11(%rsp),%r14
  lea    D3(%rip),%r12
  nop
L8:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r9d
  test   %r9d,%r9d
  jle    L30
  lea    -0x1(%r9),%ecx
  lea    0x10(%rsp),%rax
  xor    %r8d,%r8d
  add    %r14,%rcx
  jmp    L91
  nopl   0x0(%rax)
L65:
  cmp    $0x76,%dl
  je     L121
  lea    0x4(%r8),%esi
  cmp    $0x78,%dl
  cmove  %esi,%r8d
L164:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L76
L91:
  movzbl (%rax),%edx
  cmp    $0x2e,%dl
  jne    L65
  add    $0x1,%rax
  add    $0x1,%r8d
  cmp    %rax,%rcx
  jne    L91
L76:
  mov    %r8d,%edx
  mov    %r9d,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L8
L6:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L128
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L121:
  add    $0x2,%r8d
  jmp    L164
  xchg   %ax,%ax
L110:
  add    $0x1,%rbx
  cmp    %ebx,0x8(%rsp)
  jg     L46
  jmp    L130
  nopl   0x0(%rax,%rax,1)
L30:
  xor    %r8d,%r8d
  jmp    L76
L128:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D3
type: string

tool: D2:  %d

tool: D12:  %c

tool: D3: %d. segment: Nakon %d dana


assistant: ```c
int main() {
  int n = 0, i, j, segment = 0, br = 0;
  char unos;
  char put[100] = {};
  scanf(" %d", &n);
  for (i = 0; i < n; i++) {
    scanf(" %c", &unos);
    if (unos == '.' || unos == 'v' || unos == 'x') {
      put[i] = unos;
    } else {
      continue;
    }
  }
  scanf(" %d", &n);
  for (i = 0; i < n; i++) {
    scanf(" %d", &segment);
    for (j = 0; j < segment; j++) {
      if (put[j] == '.') {
        br += 1;
      } else if (put[j] == 'v') {
        br += 2;
      } else if (put[j] == 'x') {
        br += 4;
      }
    }
    printf("%d. segment: Nakon %d dana\n", segment, br);
    br = 0;
  }
  return 0;
}
```