ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<voptwave>:
  endbr64
  mov    %rcx,%rax
  divsd  D17(%rip),%xmm0
  test   %edi,%edi
  jle    L7
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%rcx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  mov    %edi,%edi
  lea    (%r9,%rdi,4),%rsi
  movsd  D17(%rip),%xmm2
L12:
  movapd %xmm2,%xmm1
  addsd  (%rax),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%r8)
  add    $0x4,%r9
  movl   $0x0,-0x4(%r9)
  add    %rcx,%rax
  add    %rdx,%r8
  cmp    %rsi,%r9
  jne    L12
L7:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: f64

tool: D17: 299792458

assistant: ```c
int voptwave(restwav, nvopt, svopt, swave, vopt, wave, stat)
double restwav;
int nvopt, svopt, swave;
const double vopt[];
double wave[];
int stat[];
{
  double r;
  register int ivopt, *statp;
  register const double *voptp;
  register double *wavep;
  r = restwav / 2.99792458e8;
  voptp = vopt;
  wavep = wave;
  statp = stat;
  for (ivopt = 0; ivopt < nvopt; ivopt++) {
    *wavep = r * (2.99792458e8 + *voptp);
    *(statp++) = 0;
    voptp += svopt;
    wavep += swave;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<voptwave>:
  endbr64
  movsd  D2(%rip),%xmm2
  mov    %rcx,%rax
  divsd  %xmm2,%xmm0
  test   %edi,%edi
  jle    L11
  movslq %esi,%rsi
  movslq %edx,%rdx
  movslq %edi,%rdi
  lea    0x0(,%rsi,8),%rcx
  shl    $0x3,%rdx
  lea    (%r9,%rdi,4),%rsi
L16:
  movsd  (%rax),%xmm1
  add    $0x4,%r9
  add    %rcx,%rax
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%r8)
  add    %rdx,%r8
  movl   $0x0,-0x4(%r9)
  cmp    %rsi,%r9
  jne    L16
L11:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: f64

tool: D2: 299792458

assistant: ```c
int voptwave(restwav, nvopt, svopt, swave, vopt, wave, stat)
double restwav;
int nvopt, svopt, swave;
const double vopt[];
double wave[];
int stat[];
{
  double r;
  register int ivopt, *statp;
  register const double *voptp;
  register double *wavep;
  r = restwav / 2.99792458e8;
  voptp = vopt;
  wavep = wave;
  statp = stat;
  for (ivopt = 0; ivopt < nvopt; ivopt++) {
    *wavep = r * (2.99792458e8 + *voptp);
    *(statp++) = 0;
    voptp += svopt;
    wavep += swave;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xcalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xcalloc(nblocks, nbytes)
int nblocks, nbytes;
{
  void *tmp = (void *)xmalloc(nblocks * nbytes);
  bzero(tmp, nblocks * nbytes);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xcalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  imul   %esi,%ebx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <xmalloc@plt>
  movslq %eax,%rbp
  movslq %ebx,%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *xcalloc(nblocks, nbytes)
int nblocks, nbytes;
{
  void *tmp = (void *)xmalloc(nblocks * nbytes);
  bzero(tmp, nblocks * nbytes);
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xcalloc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %eax,%eax
  imul   %esi,%ebx
  mov    %ebx,%edi
  call   <xmalloc@plt>
  movslq %ebx,%rdx
  xor    %esi,%esi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <memset@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *xcalloc(nblocks, nbytes)
int nblocks, nbytes;
{
  void *tmp = (void *)xmalloc(nblocks * nbytes);
  bzero(tmp, nblocks * nbytes);
  return tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xcalloc>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %eax,%eax
  imul   %esi,%ebx
  mov    %ebx,%edi
  call   <xmalloc@plt>
  movslq %ebx,%rdx
  xor    %esi,%esi
  movslq %eax,%r8
  mov    %r8,%rdi
  call   <memset@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *xcalloc(nblocks, nbytes)
int nblocks, nbytes;
{
  void *tmp = (void *)xmalloc(nblocks * nbytes);
  bzero(tmp, nblocks * nbytes);
  return tmp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  mov    $0x6996,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parity>:
  endbr64
  mov    %edi,%edx
  sar    $0x10,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%ecx
  sar    $0x4,%ecx
  xor    %eax,%ecx
  and    $0xf,%ecx
  mov    $0x6996,%eax
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parity>:
  endbr64
  mov    %edi,%edx
  sar    $0x10,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%ecx
  sar    $0x4,%ecx
  xor    %eax,%ecx
  mov    $0x6996,%eax
  and    $0xf,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parity>:
  endbr64
  mov    %edi,%edx
  sar    $0x10,%edx
  xor    %edi,%edx
  mov    %edx,%eax
  sar    $0x8,%eax
  xor    %edx,%eax
  mov    %eax,%ecx
  sar    $0x4,%ecx
  xor    %eax,%ecx
  mov    $0x6996,%eax
  and    $0xf,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int parity(uint32_t x) {
  x ^= x >> 16;
  x ^= x >> 8;
  x ^= x >> 4;
  return ((0x6996) >> (x & 0xf) & 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SkipWhiteSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  jmp    L11
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L37
  jmp    L19
L47:
  nop
L19:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *SkipWhiteSpace(char *p) {
  if (p != NULL) {
    while (iswspace(*p)) {
      if (*p != 0) {
        p++;
      } else {
        break;
      }
    };
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SkipWhiteSpace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L23
L26:
  movsbl (%rbx),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  je     L23
  cmpb   $0x0,(%rbx)
  je     L23
  add    $0x1,%rbx
  jmp    L26
L23:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *SkipWhiteSpace(char *p) {
  if (p != NULL) {
    while (iswspace(*p)) {
      if (*p != 0) {
        p++;
      } else {
        break;
      }
    };
  }
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<SkipWhiteSpace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L18
  jmp    L24
L25:
  cmpb   $0x0,(%r12)
  je     L24
  add    $0x1,%r12
L18:
  movsbl (%r12),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L25
L24:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *SkipWhiteSpace(char *p) {
  if (p != NULL) {
    while (iswspace(*p)) {
      if (*p != 0) {
        p++;
      } else {
        break;
      }
    };
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SkipWhiteSpace>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  jne    L11
  jmp    L24
L27:
  cmpb   $0x0,(%r12)
  je     L24
  add    $0x1,%r12
L11:
  movsbl (%r12),%edi
  call   <iswspace@plt>
  test   %rax,%rax
  jne    L27
L24:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *SkipWhiteSpace(char *p) {
  if (p != NULL) {
    while (iswspace(*p)) {
      if (*p != 0) {
        p++;
      } else {
        break;
      }
    };
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_guessed: string

tool: D9: Hello static library!

assistant: ```c
int main() {
  print("Hello static library!");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_infered: string

tool: D7: Hello static library!

assistant: ```c
int main() {
  print("Hello static library!");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: Hello static library!

assistant: ```c
int main() {
  print("Hello static library!");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: Hello static library!

assistant: ```c
int main() {
  print("Hello static library!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrixalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L16:
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
datatype: string

tool: D8: Memory allocation error!

assistant: ```c
int **matrixalloc(int n) {
  int **a, i;
  a = (int **)malloc(n * sizeof(int *));
  for (i = 0; i < n; i++)
    a[i] = (int *)malloc(n * sizeof(int));
  if (a == NULL) {
    perror("Memory allocation error!");
    exit(1);
  }
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<matrixalloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L18
  lea    0x0(,%rbp,4),%r12d
  mov    %rax,%rbx
  mov    %ebp,%ebp
  lea    (%rax,%rbp,8),%rbp
L39:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L39
L18:
  test   %r13,%r13
  je     L24
L34:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  lea    D5(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L34
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D5: Memory allocation error!

assistant: ```c
int **matrixalloc(int n) {
  int **a, i;
  a = (int **)malloc(n * sizeof(int *));
  for (i = 0; i < n; i++)
    a[i] = (int *)malloc(n * sizeof(int));
  if (a == NULL) {
    perror("Memory allocation error!");
    exit(1);
  }
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrixalloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L4
  lea    0x0(,%rbp,4),%r12d
  mov    %rax,%rbx
  lea    (%rax,%rbp,8),%rbp
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %r12d,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L20
L4:
  test   %r13,%r13
  je     L23
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Memory allocation error!

assistant: ```c
int **matrixalloc(int n) {
  int **a, i;
  a = (int **)malloc(n * sizeof(int *));
  for (i = 0; i < n; i++)
    a[i] = (int *)malloc(n * sizeof(int));
  if (a == NULL) {
    perror("Memory allocation error!");
    exit(1);
  }
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<matrixalloc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L25
  lea    0x0(,%rbp,4),%r12d
  mov    %rax,%rbx
  lea    (%rax,%rbp,8),%rbp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %rbp,%rbx
  jne    L3
L25:
  test   %r13,%r13
  je     L9
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string

tool: D9: Memory allocation error!

assistant: ```c
int **matrixalloc(int n) {
  int **a, i;
  a = (int **)malloc(n * sizeof(int *));
  for (i = 0; i < n; i++)
    a[i] = (int *)malloc(n * sizeof(int));
  if (a == NULL) {
    perror("Memory allocation error!");
    exit(1);
  }
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cstrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  cmpb   $0x0,-0xa(%rbp)
  je     L38
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <cstrlen@plt>
  mov    %rax,-0x8(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L8
L4:
  movzbl -0x9(%rbp),%eax
  cmp    -0xa(%rbp),%al
  jne    L26
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cstrncmp@plt>
  test   %rax,%rax
  jne    L26
  subq   $0x1,-0x18(%rbp)
L38:
  mov    -0x18(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
char *cstrstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != 0) {
    len = cstrlen(find);
    do {
      do {
        if ((sc = *s++) == 0)
          return (NULL);
      } while (sc != c);
    } while (cstrncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: What is the c source code of the assembly code below:

```asm
<cstrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rsi),%r12d
  test   %r12b,%r12b
  jne    L28
L7:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  lea    0x1(%rsi),%r13
  mov    %r13,%rdi
  call   <cstrlen@plt>
  mov    %rax,%r14
  lea    0x1(%rbp),%rbx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  jne    L51
  mov    $0x0,%ebp
  jmp    L7
L0:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L18
L51:
  lea    -0x1(%rbx),%rbp
  cmp    %al,%r12b
  jne    L0
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <cstrncmp@plt>
  test   %rax,%rax
  jne    L0
  jmp    L7
L18:
  mov    $0x0,%ebp
  jmp    L7
```

assistant: ```c
char *cstrstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != 0) {
    len = cstrlen(find);
    do {
      do {
        if ((sc = *s++) == 0)
          return (NULL);
      } while (sc != c);
    } while (cstrncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: What is the c source code of the assembly code below?

```asm
<cstrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  jne    L41
L7:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  lea    0x1(%rsi),%r13
  lea    0x1(%r12),%rbx
  mov    %r13,%rdi
  call   <cstrlen@plt>
  mov    %rax,%r14
  movzbl (%r12),%eax
  test   %al,%al
  jne    L1
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L37:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L38
L1:
  lea    -0x1(%rbx),%r12
  cmp    %al,%bpl
  jne    L37
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <cstrncmp@plt>
  test   %rax,%rax
  je     L7
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L1
L38:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *cstrstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != 0) {
    len = cstrlen(find);
    do {
      do {
        if ((sc = *s++) == 0)
          return (NULL);
      } while (sc != c);
    } while (cstrncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cstrstr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  jne    L63
L22:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  lea    0x1(%rsi),%r13
  lea    0x1(%r12),%rbx
  mov    %r13,%rdi
  call   <cstrlen@plt>
  mov    %rax,%r14
  movzbl (%r12),%eax
  test   %al,%al
  jne    L51
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L18
L51:
  lea    -0x1(%rbx),%r12
  cmp    %al,%bpl
  jne    L13
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <cstrncmp@plt>
  test   %rax,%rax
  je     L22
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L51
L18:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *cstrstr(const char *s, const char *find) {
  char c, sc;
  size_t len;
  if ((c = *find++) != 0) {
    len = cstrlen(find);
    do {
      do {
        if ((sc = *s++) == 0)
          return (NULL);
      } while (sc != c);
    } while (cstrncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<COMPARE2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  cmovbe %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L88
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jae    L31
  mov    $0xffffffff,%eax
  jmp    L42
L31:
  mov    $0x1,%eax
  jmp    L42
L88:
  movl   $0x0,-0x10(%rbp)
L8:
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    $0x0,%edx
  divl   -0x14(%rbp)
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    $0x0,%edx
  divl   -0x18(%rbp)
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L82
  mov    -0x10(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0xc(%rbp)
  jae    L92
  mov    $0x0,%eax
  jmp    L42
L82:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L14
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  jmp    L42
L14:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  neg    %eax
  jmp    L42
L92:
  addl   $0x1,-0x10(%rbp)
  jmp    L8
L42:
  pop    %rbp
  ret
```

assistant: ```c
int COMPARE2(unsigned int nA, unsigned int nB, const char *const a, const char *const b, unsigned int i, unsigned int j) {
  unsigned int k, s = ((nA) > (nB) ? (nB) : (nA));
  if (s == 0) {
    return (nB < nA) ? -1 : 1;
  }
  for (k = 0;; k++) {
    int A = (int)a[(i + k) % nA];
    int B = (int)b[(j + k) % nB];
    if (A == B) {
      if (k + 2 > s)
        return 0;
    } else if (A < B) {
      return (int)(k + 1u);
    } else {
      return -(int)(k + 1u);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<COMPARE2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r10d
  cmp    %esi,%edi
  mov    %esi,%ebp
  cmovbe %edi,%ebp
  test   %ebp,%ebp
  je     L19
  mov    %rdx,%r11
  mov    %rcx,%rbx
  mov    %r8d,%eax
  mov    $0x0,%edx
  div    %edi
  movsbl (%r11,%rdx,1),%r12d
  mov    %r9d,%eax
  mov    $0x0,%edx
  div    %esi
  movsbl (%rcx,%rdx,1),%edx
  cmp    %edx,%r12d
  jne    L71
  cmp    $0x1,%ebp
  jbe    L29
  mov    $0x0,%ecx
L32:
  mov    %ecx,%esi
  add    $0x1,%ecx
  lea    (%r8,%rcx,1),%eax
  mov    $0x0,%edx
  div    %edi
  movsbl (%r11,%rdx,1),%r12d
  lea    (%r9,%rcx,1),%eax
  mov    $0x0,%edx
  div    %r10d
  movsbl (%rbx,%rdx,1),%edx
  cmp    %edx,%r12d
  jne    L6
  add    $0x3,%esi
  cmp    %esi,%ebp
  jae    L32
  mov    $0x0,%eax
  jmp    L10
L19:
  cmp    %edi,%esi
  sbb    %eax,%eax
  or     $0x1,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L71:
  mov    $0x0,%ecx
L6:
  lea    0x1(%rcx),%eax
  not    %ecx
  cmp    %edx,%r12d
  cmovge %ecx,%eax
  jmp    L10
L29:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
int COMPARE2(unsigned int nA, unsigned int nB, const char *const a, const char *const b, unsigned int i, unsigned int j) {
  unsigned int k, s = ((nA) > (nB) ? (nB) : (nA));
  if (s == 0) {
    return (nB < nA) ? -1 : 1;
  }
  for (k = 0;; k++) {
    int A = (int)a[(i + k) % nA];
    int B = (int)b[(j + k) % nB];
    if (A == B) {
      if (k + 2 > s)
        return 0;
    } else if (A < B) {
      return (int)(k + 1u);
    } else {
      return -(int)(k + 1u);
    }
  }
}
```