ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Merge1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L66
L60:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L39
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L66
L39:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L66:
  mov    -0x24(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L25
  mov    -0x28(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L60
  jmp    L25
L9:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L25:
  mov    -0x24(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L9
  jmp    L20
L87:
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x28(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L20:
  mov    -0x28(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L87
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Merge1(int A[], int TmpA[], int L, int R, int RightEnd) {
  int NumElements = RightEnd - L + 1;
  int LeftEnd = R - 1;
  int Tmp = L;
  int i;
  while (L <= LeftEnd && R <= RightEnd) {
    if (A[L] >= A[R])
      TmpA[Tmp++] = A[R++];
    else
      TmpA[Tmp++] = A[L++];
  }
  while (L <= LeftEnd)
    TmpA[Tmp++] = A[L++];
  while (R <= RightEnd)
    TmpA[Tmp++] = A[R++];
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Merge1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %edx,%esi
  mov    %ecx,%ebp
  lea    -0x1(%rcx),%r11d
  cmp    %r11d,%edx
  jg     L19
  cmp    %ecx,%r8d
  jl     L19
  lea    0x1(%rdx),%ecx
  movslq %edx,%rax
  lea    (%rbx,%rax,4),%rdx
  mov    %ebp,%eax
  jmp    L10
L24:
  add    $0x1,%esi
  mov    %ecx,%r12d
  mov    %r9d,(%rdx)
L45:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %r11d,%esi
  jg     L75
  cmp    %eax,%r8d
  jl     L75
L10:
  movslq %esi,%r9
  mov    (%rdi,%r9,4),%r9d
  movslq %eax,%r10
  mov    (%rdi,%r10,4),%r10d
  cmp    %r10d,%r9d
  jl     L24
  add    $0x1,%eax
  mov    %ecx,%r12d
  mov    %r10d,(%rdx)
  jmp    L45
L19:
  mov    %esi,%r12d
  mov    %ebp,%eax
L75:
  cmp    %esi,%r11d
  jl     L43
  movslq %esi,%rdx
  movslq %r12d,%rcx
  sub    %rdx,%rcx
  lea    (%rbx,%rcx,4),%r9
L78:
  mov    (%rdi,%rdx,4),%ecx
  mov    %ecx,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r11d
  jge    L78
  add    %r12d,%ebp
  sub    %esi,%ebp
  mov    %ebp,%r12d
L43:
  cmp    %eax,%r8d
  jl     L57
  cltq
  movslq %r12d,%r12
  sub    %rax,%r12
  lea    (%rbx,%r12,4),%rcx
L48:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L48
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Merge1(int A[], int TmpA[], int L, int R, int RightEnd) {
  int NumElements = RightEnd - L + 1;
  int LeftEnd = R - 1;
  int Tmp = L;
  int i;
  while (L <= LeftEnd && R <= RightEnd) {
    if (A[L] >= A[R])
      TmpA[Tmp++] = A[R++];
    else
      TmpA[Tmp++] = A[L++];
  }
  while (L <= LeftEnd)
    TmpA[Tmp++] = A[L++];
  while (R <= RightEnd)
    TmpA[Tmp++] = A[R++];
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Merge1>:
  endbr64
  lea    -0x1(%rcx),%r10d
  push   %rbp
  mov    %rsi,%r11
  mov    %edx,%esi
  push   %rbx
  mov    %ecx,%ebx
  cmp    %r10d,%edx
  jg     L11
  cmp    %ecx,%r8d
  jl     L11
  lea    0x1(%rdx),%edx
  mov    %ecx,%eax
  movslq %edx,%rdx
  jmp    L102
  nopl   (%rax)
L97:
  mov    %ecx,-0x4(%r11,%rdx,4)
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %r10d,%esi
  jg     L13
L45:
  cmp    %r8d,%eax
  jg     L13
L102:
  movslq %esi,%rcx
  movslq %edx,%rbp
  mov    (%rdi,%rcx,4),%r9d
  movslq %eax,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,%r9d
  jge    L97
  mov    %r9d,%ecx
  add    $0x1,%esi
  mov    %ecx,-0x4(%r11,%rdx,4)
  add    $0x1,%rdx
  cmp    %r10d,%esi
  jle    L45
L13:
  cmp    %esi,%r10d
  jl     L23
  movslq %esi,%rdx
  movslq %ebp,%rcx
  sub    %rdx,%rcx
  lea    (%r11,%rcx,4),%r9
  nopl   0x0(%rax)
L41:
  mov    (%rdi,%rdx,4),%ecx
  mov    %ecx,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r10d
  jge    L41
  add    %ebp,%ebx
  sub    %esi,%ebx
  movslq %ebx,%rbp
L23:
  cmp    %eax,%r8d
  jl     L119
  cltq
  sub    %rax,%rbp
  lea    (%r11,%rbp,4),%rcx
  nopl   (%rax)
L63:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jge    L63
L119:
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  movslq %esi,%rbp
  mov    %ebx,%eax
  jmp    L13
```

assistant: ```c
void Merge1(int A[], int TmpA[], int L, int R, int RightEnd) {
  int NumElements = RightEnd - L + 1;
  int LeftEnd = R - 1;
  int Tmp = L;
  int i;
  while (L <= LeftEnd && R <= RightEnd) {
    if (A[L] >= A[R])
      TmpA[Tmp++] = A[R++];
    else
      TmpA[Tmp++] = A[L++];
  }
  while (L <= LeftEnd)
    TmpA[Tmp++] = A[L++];
  while (R <= RightEnd)
    TmpA[Tmp++] = A[R++];
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xfma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x58(%rbp)
  movsd  %xmm1,-0x60(%rbp)
  movsd  %xmm2,-0x68(%rbp)
  movsd  -0x58(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x4000000,%rax
  and    $0xfffffffff8000000,%rax
  mov    %rax,-0x50(%rbp)
  movsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movsd  -0x58(%rbp),%xmm0
  subsd  -0x48(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x60(%rbp),%xmm0
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  add    $0x4000000,%rax
  and    $0xfffffffff8000000,%rax
  mov    %rax,-0x50(%rbp)
  movsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x60(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x58(%rbp),%xmm0
  mulsd  -0x60(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x48(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x28(%rbp),%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x38(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  addsd  -0x68(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x10(%rbp),%xmm2
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x68(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double xfma(double x, double y, double z) {
  union {
    double f;
    long long int i;
  } tmp;
  tmp.f = x;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double xh = tmp.f, xl = x - xh;
  tmp.f = y;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double yh = tmp.f, yl = y - yh;
  double h = x * y;
  double l = xh * yh - h + xl * yh + xh * yl + xl * yl;
  double h2, l2, v;
  h2 = h + z;
  v = h2 - h;
  l2 = (h - (h2 - v)) + (z - v) + l;
  return h2 + l2;
}
```
user: What is the c source code of the assembly code below:

```asm
<xfma>:
  endbr64
  mov    $0x4000000,%eax
  movq   %xmm0,-0x8(%rsp)
  add    -0x8(%rsp),%rax
  and    $0xfffffffff8000000,%rax
  movq   %rax,%xmm3
  movapd %xmm0,%xmm6
  subsd  %xmm3,%xmm6
  mov    $0x4000000,%eax
  movq   %xmm1,-0x8(%rsp)
  add    -0x8(%rsp),%rax
  and    $0xfffffffff8000000,%rax
  movq   %rax,%xmm4
  movapd %xmm1,%xmm8
  subsd  %xmm4,%xmm8
  mulsd  %xmm0,%xmm1
  movapd %xmm1,%xmm5
  addsd  %xmm2,%xmm5
  movapd %xmm5,%xmm7
  subsd  %xmm1,%xmm7
  movapd %xmm3,%xmm0
  mulsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm0
  mulsd  %xmm6,%xmm4
  addsd  %xmm4,%xmm0
  mulsd  %xmm8,%xmm3
  addsd  %xmm3,%xmm0
  mulsd  %xmm8,%xmm6
  addsd  %xmm6,%xmm0
  movapd %xmm5,%xmm3
  subsd  %xmm7,%xmm3
  subsd  %xmm3,%xmm1
  subsd  %xmm7,%xmm2
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm5,%xmm0
  ret
```

assistant: ```c
double xfma(double x, double y, double z) {
  union {
    double f;
    long long int i;
  } tmp;
  tmp.f = x;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double xh = tmp.f, xl = x - xh;
  tmp.f = y;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double yh = tmp.f, yl = y - yh;
  double h = x * y;
  double l = xh * yh - h + xl * yh + xh * yl + xl * yl;
  double h2, l2, v;
  h2 = h + z;
  v = h2 - h;
  l2 = (h - (h2 - v)) + (z - v) + l;
  return h2 + l2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xfma>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  mov    $0x4000000,%eax
  add    -0x8(%rsp),%rax
  movapd %xmm0,%xmm6
  and    $0xfffffffff8000000,%rax
  movq   %xmm1,-0x8(%rsp)
  movapd %xmm1,%xmm8
  mulsd  %xmm0,%xmm1
  movq   %rax,%xmm3
  mov    $0x4000000,%eax
  add    -0x8(%rsp),%rax
  and    $0xfffffffff8000000,%rax
  movapd %xmm3,%xmm0
  subsd  %xmm3,%xmm6
  movq   %rax,%xmm4
  mulsd  %xmm4,%xmm0
  subsd  %xmm4,%xmm8
  mulsd  %xmm6,%xmm4
  movapd %xmm1,%xmm5
  addsd  %xmm2,%xmm5
  mulsd  %xmm8,%xmm3
  mulsd  %xmm8,%xmm6
  subsd  %xmm1,%xmm0
  movapd %xmm5,%xmm7
  subsd  %xmm1,%xmm7
  addsd  %xmm4,%xmm0
  subsd  %xmm7,%xmm2
  addsd  %xmm3,%xmm0
  movapd %xmm5,%xmm3
  subsd  %xmm7,%xmm3
  addsd  %xmm6,%xmm0
  subsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm5,%xmm0
  ret
```

assistant: ```c
double xfma(double x, double y, double z) {
  union {
    double f;
    long long int i;
  } tmp;
  tmp.f = x;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double xh = tmp.f, xl = x - xh;
  tmp.f = y;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double yh = tmp.f, yl = y - yh;
  double h = x * y;
  double l = xh * yh - h + xl * yh + xh * yl + xl * yl;
  double h2, l2, v;
  h2 = h + z;
  v = h2 - h;
  l2 = (h - (h2 - v)) + (z - v) + l;
  return h2 + l2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xfma>:
  endbr64
  movq   %xmm0,-0x8(%rsp)
  mov    $0x4000000,%eax
  add    -0x8(%rsp),%rax
  movapd %xmm0,%xmm6
  and    $0xfffffffff8000000,%rax
  movq   %xmm1,-0x8(%rsp)
  movapd %xmm1,%xmm8
  mulsd  %xmm0,%xmm1
  movq   %rax,%xmm3
  mov    $0x4000000,%eax
  add    -0x8(%rsp),%rax
  and    $0xfffffffff8000000,%rax
  movapd %xmm3,%xmm0
  subsd  %xmm3,%xmm6
  movq   %rax,%xmm4
  mulsd  %xmm4,%xmm0
  subsd  %xmm4,%xmm8
  mulsd  %xmm6,%xmm4
  movapd %xmm1,%xmm5
  addsd  %xmm2,%xmm5
  mulsd  %xmm8,%xmm3
  mulsd  %xmm8,%xmm6
  subsd  %xmm1,%xmm0
  movapd %xmm5,%xmm7
  subsd  %xmm1,%xmm7
  addsd  %xmm4,%xmm0
  subsd  %xmm7,%xmm2
  addsd  %xmm3,%xmm0
  movapd %xmm5,%xmm3
  subsd  %xmm7,%xmm3
  addsd  %xmm6,%xmm0
  subsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  addsd  %xmm5,%xmm0
  ret
```

assistant: ```c
double xfma(double x, double y, double z) {
  union {
    double f;
    long long int i;
  } tmp;
  tmp.f = x;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double xh = tmp.f, xl = x - xh;
  tmp.f = y;
  tmp.i = (tmp.i + 0x4000000) & 0xfffffffff8000000LL;
  double yh = tmp.f, yl = y - yh;
  double h = x * y;
  double l = xh * yh - h + xl * yh + xh * yl + xl * yl;
  double h2, l2, v;
  h2 = h + z;
  v = h2 - h;
  l2 = (h - (h2 - v)) + (z - v) + l;
  return h2 + l2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chopmins_ns_i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L6:
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chopmins_ns_i(double *ind, int mini, int np) {
  int i;
  for (i = mini; i < np - 1; i++) {
    ind[i] = ind[i + 1];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chopmins_ns_i>:
  endbr64
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  jge    L13
  movslq %esi,%rcx
  lea    (%rdi,%rcx,8),%rax
  sub    $0x2,%edx
  sub    %esi,%edx
  add    %rcx,%rdx
  lea    0x8(%rdi,%rdx,8),%rdx
L16:
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L16
L13:
  ret
```

assistant: ```c
void chopmins_ns_i(double *ind, int mini, int np) {
  int i;
  for (i = mini; i < np - 1; i++) {
    ind[i] = ind[i + 1];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<chopmins_ns_i>:
  endbr64
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  jge    L5
  movslq %esi,%rax
  sub    $0x2,%edx
  shl    $0x3,%rax
  sub    %esi,%edx
  lea    0x8(,%rdx,8),%rdx
  lea    0x8(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  jmp    1050 <memmove@plt>
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void chopmins_ns_i(double *ind, int mini, int np) {
  int i;
  for (i = mini; i < np - 1; i++) {
    ind[i] = ind[i + 1];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<chopmins_ns_i>:
  endbr64
  lea    -0x1(%rdx),%eax
  cmp    %eax,%esi
  jge    L3
  movslq %esi,%rax
  sub    $0x2,%edx
  shl    $0x3,%rax
  sub    %esi,%edx
  lea    0x8(,%rdx,8),%rdx
  lea    0x8(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  jmp    1050 <memmove@plt>
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void chopmins_ns_i(double *ind, int mini, int np) {
  int i;
  for (i = mini; i < np - 1; i++) {
    ind[i] = ind[i + 1];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  cmp    %rax,-0x20(%rbp)
  jbe    L21
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  jmp    L19
L21:
  mov    -0x20(%rbp),%rax
  add    $0x1,%eax
L19:
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L11:
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  int l = n > strlen(s) ? strlen(s) + 1 : n + 1;
  char *d = malloc(l);
  if (d)
    memcpy(d, s, l);
  d[n] = '\0';
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strndup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  cltq
  lea    0x1(%rbp),%r13d
  cmp    %rbp,%rax
  jb     L15
L17:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L9:
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  jmp    L17
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  int l = n > strlen(s) ? strlen(s) + 1 : n + 1;
  char *d = malloc(l);
  if (d)
    memcpy(d, s, l);
  d[n] = '\0';
  return d;
}
```
user: What is the c source code of the assembly code below:

```asm
<strndup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x1(%rbx),%r13d
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmp    %rbx,%rax
  jb     L12
L17:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L13:
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  jmp    L17
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  int l = n > strlen(s) ? strlen(s) + 1 : n + 1;
  char *d = malloc(l);
  if (d)
    memcpy(d, s, l);
  d[n] = '\0';
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strndup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    0x1(%rbx),%r13d
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  cmp    %rbx,%rax
  jb     L8
L28:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L27:
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%r13d
  jmp    L28
```

assistant: ```c
char *strndup(const char *s, size_t n) {
  int l = n > strlen(s) ? strlen(s) + 1 : n + 1;
  char *d = malloc(l);
  if (d)
    memcpy(d, s, l);
  d[n] = '\0';
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CompareSquare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_mul@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: What is the c source code of the assembly code below:

```asm
<CompareSquare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init@plt>
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_mul@plt>
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <mpz_cmp@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <mpz_clear@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CompareSquare>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_cmp@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <mpz_clear@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CompareSquare>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <mpz_mul@plt>
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_cmp@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <mpz_clear@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int CompareSquare(mpz_t Nbr1, mpz_t Nbr2) {
  mpz_t tmp;
  int cmp = 0;
  mpz_init(tmp);
  mpz_mul(tmp, Nbr1, Nbr1);
  cmp = mpz_cmp(tmp, Nbr2);
  mpz_clear(tmp);
  return cmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Xprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Xprint(char t) {
  (void)t;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Xprint>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Xprint(char t) {
  (void)t;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Xprint>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int Xprint(char t) {
  (void)t;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Xprint>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int Xprint(char t) {
  (void)t;
  return 0;
}
```