ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strtok>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdx
  call   <strtok_r@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *strtok(char *s, const char *b) {
  static char *under_rock;
  return strtok_r(s, b, &under_rock);
}
```
user: What is the c source code of the assembly code below?

```asm
<strtok>:
  endbr64
  lea    D2(%rip),%rdx
  jmp    1050 <strtok_r@plt>
```

assistant: ```c
char *strtok(char *s, const char *b) {
  static char *under_rock;
  return strtok_r(s, b, &under_rock);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtok>:
  endbr64
  lea    D0(%rip),%rdx
  jmp    1050 <strtok_r@plt>
```

assistant: ```c
char *strtok(char *s, const char *b) {
  static char *under_rock;
  return strtok_r(s, b, &under_rock);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<halt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L0:
  jmp    L0
```

assistant: ```c
void __attribute__((always_)) __attribute__((noreturn)) halt(void) {
  for (;;)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<halt>:
  endbr64
L0:
  jmp    L0
```

assistant: ```c
void __attribute__((always_)) __attribute__((noreturn)) halt(void) {
  for (;;)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<halt>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void __attribute__((always_)) __attribute__((noreturn)) halt(void) {
  for (;;)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<halt>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
void __attribute__((always_)) __attribute__((noreturn)) halt(void) {
  for (;;)
    ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc2D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L21
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L21:
  mov    -0x28(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <alloc1D@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L1
L10:
  mov    -0x1c(%rbp),%eax
  imul   -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L1:
  mov    -0x1c(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
type_guessed: string

tool: D8: Could not allocate row access buffer

assistant: ```c
char **alloc2D(int Ydim, int Xdim, int Size) {
  char *Data1, **Data2;
  int y, Count, Offset;
  Count = Ydim;
  if ((Data2 = (char **)malloc((unsigned)(Count * sizeof(char *)))) == NULL) {
    printf("Could not allocate row access buffer");
    exit(1);
  };
  ;
  Offset = Xdim * Size;
  Data1 = alloc1D(Ydim, Xdim, Size);
  for (y = 0; y < Count; y++)
    Data2[y] = Data1 + y * Offset;
  return (Data2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<alloc2D>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %edx,%r14d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L37
L36:
  mov    %r13d,%r12d
  imul   %r14d,%r12d
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <alloc1D@plt>
  test   %ebx,%ebx
  jle    L1
  movslq %r12d,%rcx
  mov    %rbp,%rdx
  mov    %ebx,%ebx
  lea    0x0(%rbp,%rbx,8),%rsi
L10:
  mov    %rax,(%rdx)
  add    %rcx,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L10
L1:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L36
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: Could not allocate row access buffer

assistant: ```c
char **alloc2D(int Ydim, int Xdim, int Size) {
  char *Data1, **Data2;
  int y, Count, Offset;
  Count = Ydim;
  if ((Data2 = (char **)malloc((unsigned)(Count * sizeof(char *)))) == NULL) {
    printf("Could not allocate row access buffer");
    exit(1);
  };
  ;
  Offset = Xdim * Size;
  Data1 = alloc1D(Ydim, Xdim, Size);
  for (y = 0; y < Count; y++)
    Data2[y] = Data1 + y * Offset;
  return (Data2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<alloc2D>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L39
L8:
  mov    %r13d,%ebx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  imul   %r14d,%ebx
  call   <alloc1D@plt>
  test   %ebp,%ebp
  jle    L9
  movslq %ebx,%rcx
  mov    %r12,%rdx
  lea    (%r12,%rbp,8),%rsi
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rax,(%rdx)
  add    $0x8,%rdx
  add    %rcx,%rax
  cmp    %rsi,%rdx
  jne    L16
L9:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: Could not allocate row access buffer

assistant: ```c
char **alloc2D(int Ydim, int Xdim, int Size) {
  char *Data1, **Data2;
  int y, Count, Offset;
  Count = Ydim;
  if ((Data2 = (char **)malloc((unsigned)(Count * sizeof(char *)))) == NULL) {
    printf("Could not allocate row access buffer");
    exit(1);
  };
  ;
  Offset = Xdim * Size;
  Data1 = alloc1D(Ydim, Xdim, Size);
  for (y = 0; y < Count; y++)
    Data2[y] = Data1 + y * Offset;
  return (Data2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alloc2D>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L66
L82:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  mov    %r13d,%ebp
  call   <alloc1D@plt>
  imul   %r14d,%ebp
  mov    %rax,%rcx
  test   %ebx,%ebx
  jle    L73
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L83
  movd   %ebp,%xmm5
  mov    %ebx,%edx
  movq   %rcx,%xmm3
  mov    %r12,%rax
  pshufd $0x0,%xmm5,%xmm4
  shr    $0x2,%edx
  punpcklqdq %xmm3,%xmm3
  movdqa D14(%rip),%xmm2
  shl    $0x5,%rdx
  movdqa %xmm4,%xmm6
  movdqa D11(%rip),%xmm7
  pxor   %xmm5,%xmm5
  add    %r12,%rdx
  psrlq  $0x20,%xmm6
  nopl   0x0(%rax)
L7:
  movdqa %xmm2,%xmm1
  movdqa %xmm5,%xmm8
  paddd  %xmm7,%xmm2
  add    $0x20,%rax
  movdqa %xmm1,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm4,%xmm0
  pmuludq %xmm6,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  punpckldq %xmm1,%xmm0
  pcmpgtd %xmm0,%xmm8
  movdqa %xmm0,%xmm1
  punpckldq %xmm8,%xmm1
  punpckhdq %xmm8,%xmm0
  paddq  %xmm3,%xmm1
  paddq  %xmm3,%xmm0
  movups %xmm1,-0x20(%rax)
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L7
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%bl
  je     L73
L14:
  mov    %ebp,%edx
  movslq %eax,%r8
  imul   %eax,%edx
  lea    0x0(,%r8,8),%rdi
  movslq %edx,%rsi
  add    %rcx,%rsi
  mov    %rsi,(%r12,%r8,8)
  lea    0x1(%rax),%esi
  cmp    %esi,%ebx
  jle    L73
  add    %ebp,%edx
  add    $0x2,%eax
  movslq %edx,%rsi
  add    %rcx,%rsi
  mov    %rsi,0x8(%r12,%rdi,1)
  cmp    %eax,%ebx
  jle    L73
  add    %edx,%ebp
  movslq %ebp,%rbp
  add    %rbp,%rcx
  mov    %rcx,0x10(%r12,%rdi,1)
L73:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L82
L83:
  xor    %eax,%eax
  jmp    L14
```

tool_calls: name: read_data
arguments: tag: D14
type: byte[16]
name: read_data
arguments: tag: D11
type: byte[16]
name: read_data
arguments: tag: D7
type: string

tool: {"D14": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D11": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D7: Could not allocate row access buffer

assistant: ```c
char **alloc2D(int Ydim, int Xdim, int Size) {
  char *Data1, **Data2;
  int y, Count, Offset;
  Count = Ydim;
  if ((Data2 = (char **)malloc((unsigned)(Count * sizeof(char *)))) == NULL) {
    printf("Could not allocate row access buffer");
    exit(1);
  };
  ;
  Offset = Xdim * Size;
  Data1 = alloc1D(Ydim, Xdim, Size);
  for (y = 0; y < Count; y++)
    Data2[y] = Data1 + y * Offset;
  return (Data2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outprintf@plt>
  addq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L18
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D23
datatype: string
name: retrieve_data
arguments: data_label: D29
datatype: string
name: retrieve_data
arguments: data_label: D1
datatype: string

tool: D23: 
/* Start of generated code */


tool: D29: %c

tool: D1: 
/* End of generated code */


assistant: ```c
void write_string(char *begin, char *end) {
  outprintf("\n/* Start of generated code */\n");
  for (char *iter = begin; iter < end; ++iter) {
    outprintf("%c", *iter);
  }
  outprintf("\n/* End of generated code */\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <outprintf@plt>
  cmp    %rbp,%rbx
  jae    L5
  lea    D21(%rip),%r12
L8:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <outprintf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L8
L5:
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <outprintf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D3
data_type: string

tool: D5: 
/* Start of generated code */


tool: D21: %c

tool: D3: 
/* End of generated code */


assistant: ```c
void write_string(char *begin, char *end) {
  outprintf("\n/* Start of generated code */\n");
  for (char *iter = begin; iter < end; ++iter) {
    outprintf("%c", *iter);
  }
  outprintf("\n/* End of generated code */\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_string>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D7(%rip),%rdi
  call   <outprintf@plt>
  cmp    %rbp,%rbx
  jae    L10
  lea    D5(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <outprintf@plt>
  cmp    %rbx,%rbp
  jne    L6
L10:
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <outprintf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string
name: disassemble_data
arguments: tag: D5
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D7: 
/* Start of generated code */


tool: D5: %c

tool: D0: 
/* End of generated code */


assistant: ```c
void write_string(char *begin, char *end) {
  outprintf("\n/* Start of generated code */\n");
  for (char *iter = begin; iter < end; ++iter) {
    outprintf("%c", *iter);
  }
  outprintf("\n/* End of generated code */\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_string>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D10(%rip),%rdi
  call   <outprintf@plt>
  cmp    %rbp,%rbx
  jae    L9
  lea    D25(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <outprintf@plt>
  cmp    %rbx,%rbp
  jne    L6
L9:
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1050 <outprintf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D25
type: string
name: retrieve_data
arguments: data_tag: D23
type: string

tool: D10: 
/* Start of generated code */


tool: D25: %c

tool: D23: 
/* End of generated code */


assistant: ```c
void write_string(char *begin, char *end) {
  outprintf("\n/* Start of generated code */\n");
  for (char *iter = begin; iter < end; ++iter) {
    outprintf("%c", *iter);
  }
  outprintf("\n/* End of generated code */\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CreateArrayIntensity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float *CreateArrayIntensity(float red0, float green0, float blue0) {
  float *TabIntensity;
  TabIntensity = (float *)malloc(3 * sizeof(float));
  TabIntensity[0] = red0;
  TabIntensity[1] = green0;
  TabIntensity[2] = blue0;
  return TabIntensity;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<CreateArrayIntensity>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movd   %xmm0,%r12d
  movd   %xmm1,%ebp
  movd   %xmm2,%ebx
  mov    $0xc,%edi
  call   <malloc@plt>
  mov    %r12d,(%rax)
  mov    %ebp,0x4(%rax)
  mov    %ebx,0x8(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
float *CreateArrayIntensity(float red0, float green0, float blue0) {
  float *TabIntensity;
  TabIntensity = (float *)malloc(3 * sizeof(float));
  TabIntensity[0] = red0;
  TabIntensity[1] = green0;
  TabIntensity[2] = blue0;
  return TabIntensity;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CreateArrayIntensity>:
  endbr64
  sub    $0x18,%rsp
  mov    $0xc,%edi
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  movss  %xmm2,0x4(%rsp)
  call   <malloc@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm2
  movss  %xmm0,(%rax)
  movss  %xmm1,0x4(%rax)
  movss  %xmm2,0x8(%rax)
  add    $0x18,%rsp
  ret
```

assistant: ```c
float *CreateArrayIntensity(float red0, float green0, float blue0) {
  float *TabIntensity;
  TabIntensity = (float *)malloc(3 * sizeof(float));
  TabIntensity[0] = red0;
  TabIntensity[1] = green0;
  TabIntensity[2] = blue0;
  return TabIntensity;
}
```
user: What is the c source code of the assembly code below?

```asm
<CreateArrayIntensity>:
  endbr64
  sub    $0x18,%rsp
  unpcklps %xmm1,%xmm0
  mov    $0xc,%edi
  movss  %xmm2,0xc(%rsp)
  movlps %xmm0,(%rsp)
  call   <malloc@plt>
  movq   (%rsp),%xmm0
  movss  0xc(%rsp),%xmm2
  movlps %xmm0,(%rax)
  movss  %xmm2,0x8(%rax)
  add    $0x18,%rsp
  ret
```

assistant: ```c
float *CreateArrayIntensity(float red0, float green0, float blue0) {
  float *TabIntensity;
  TabIntensity = (float *)malloc(3 * sizeof(float));
  TabIntensity[0] = red0;
  TabIntensity[1] = green0;
  TabIntensity[2] = blue0;
  return TabIntensity;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_(struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this, unsigned int ***llvm_cbe___i) {
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this_2e_addr;
  unsigned int ***llvm_cbe___i_2e_addr;
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this1;
  unsigned int ***llvm_cbe_tmp__23;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe___i_2e_addr) = llvm_cbe___i;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp__23 = *(&llvm_cbe___i_2e_addr);
  _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_(llvm_cbe_this1, llvm_cbe_tmp__23);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_>:
  endbr64
  sub    $0x8,%rsp
  call   <_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_(struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this, unsigned int ***llvm_cbe___i) {
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this_2e_addr;
  unsigned int ***llvm_cbe___i_2e_addr;
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this1;
  unsigned int ***llvm_cbe_tmp__23;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe___i_2e_addr) = llvm_cbe___i;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp__23 = *(&llvm_cbe___i_2e_addr);
  _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_(llvm_cbe_this1, llvm_cbe_tmp__23);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_>:
  endbr64
  jmp    1050 <_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_@plt>
```

assistant: ```c
void _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_(struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this, unsigned int ***llvm_cbe___i) {
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this_2e_addr;
  unsigned int ***llvm_cbe___i_2e_addr;
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this1;
  unsigned int ***llvm_cbe_tmp__23;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe___i_2e_addr) = llvm_cbe___i;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp__23 = *(&llvm_cbe___i_2e_addr);
  _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_(llvm_cbe_this1, llvm_cbe_tmp__23);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_>:
  endbr64
  jmp    1050 <_ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_@plt>
```

assistant: ```c
void _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC1ERKS2_(struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this, unsigned int ***llvm_cbe___i) {
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this_2e_addr;
  unsigned int ***llvm_cbe___i_2e_addr;
  struct l_class_OC___gnu_cxx_KD__KD___normal_iterator *llvm_cbe_this1;
  unsigned int ***llvm_cbe_tmp__23;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe___i_2e_addr) = llvm_cbe___i;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  llvm_cbe_tmp__23 = *(&llvm_cbe___i_2e_addr);
  _ZN9__gnu_cxx17__normal_iteratorIPPiSt6vectorIS1_SaIS1_EEEC2ERKS2_(llvm_cbe_this1, llvm_cbe_tmp__23);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<int32toa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L30
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x2d,(%rax)
  negl   -0x24(%rbp)
  jmp    L5
L30:
  cmpl   $0x0,-0x24(%rbp)
  jne    L5
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x30,(%rax)
L5:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L32
L0:
  mov    -0x24(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movslq %edx,%rdx
  lea    D0(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  mov    %dl,(%rax)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x24(%rbp)
L32:
  cmpl   $0x0,-0x24(%rbp)
  jg     L0
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L38
L4:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x11(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L4
  mov    -0x30(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: 0123456789

assistant: ```c
char *int32toa(int32_t v, char *s) {
  char *s1, *s2;
  char c;
  s1 = s;
  if (v < 0) {
    *s1++ = '-';
    v = -v;
  } else if (v == 0)
    *s1++ = '0';
  s2 = s1;
  while (v > 0) {
    *s2++ = "0123456789"[v % 10];
    v /= 10;
  }
  *s2-- = 0;
  while (s2 > s1) {
    c = *s1;
    *s1 = *s2;
    *s2 = c;
    s1++;
    s2--;
  }
  return s;
}
```