ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<yuzluk_tam_sayiya_yuvarla>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D1(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D17
datatype: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double yuzluk_tam_sayiya_yuvarla(double girilen_sayi) {
  double yuvarlanan_sayi;
  yuvarlanan_sayi = floor((girilen_sayi * 100) + .5) / 100;
  return yuvarlanan_sayi;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<yuzluk_tam_sayiya_yuvarla>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D5(%rip),%xmm0
  addsd  D8(%rip),%xmm0
  call   <floor@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: byte[8]
name: disassemble_data
arguments: tag: D8
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double yuzluk_tam_sayiya_yuvarla(double girilen_sayi) {
  double yuvarlanan_sayi;
  yuvarlanan_sayi = floor((girilen_sayi * 100) + .5) / 100;
  return yuvarlanan_sayi;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<yuzluk_tam_sayiya_yuvarla>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D2(%rip),%xmm0
  addsd  D1(%rip),%xmm0
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: byte[8]
name: retrieve_data
arguments: label: D1
type_guessed: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double yuzluk_tam_sayiya_yuvarla(double girilen_sayi) {
  double yuvarlanan_sayi;
  yuvarlanan_sayi = floor((girilen_sayi * 100) + .5) / 100;
  return yuvarlanan_sayi;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<yuzluk_tam_sayiya_yuvarla>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D6(%rip),%xmm0
  addsd  D8(%rip),%xmm0
  call   <floor@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
datatype: byte[8]
name: read_data
arguments: data_label: D8
datatype: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double yuzluk_tam_sayiya_yuvarla(double girilen_sayi) {
  double yuvarlanan_sayi;
  yuvarlanan_sayi = floor((girilen_sayi * 100) + .5) / 100;
  return yuvarlanan_sayi;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: this process has id %d


assistant: ```c
int main(int argc, char **argv) {
  int pid;
  pid = getpid();
  printf("this process has id %d\n", pid);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: this process has id %d


assistant: ```c
int main(int argc, char **argv) {
  int pid;
  pid = getpid();
  printf("this process has id %d\n", pid);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string

tool: D8: this process has id %d


assistant: ```c
int main(int argc, char **argv) {
  int pid;
  pid = getpid();
  printf("this process has id %d\n", pid);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: this process has id %d


assistant: ```c
int main(int argc, char **argv) {
  int pid;
  pid = getpid();
  printf("this process has id %d\n", pid);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FlattenWrappedPhase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L17
L39:
  movq   $0x0,-0x18(%rbp)
  jmp    L22
L6:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x18(%rbp),%rdx
  shl    $0x2,%rdx
  lea    (%rcx,%rdx,1),%rbx
  movsd  D17(%rip),%xmm0
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fmod@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comiss %xmm1,%xmm0
  jbe    L26
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D17(%rip),%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
L26:
  addq   $0x1,-0x18(%rbp)
L22:
  mov    -0x18(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jl     L6
  addq   $0x1,-0x20(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jl     L39
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D17
data_type: f64

tool: D17: 6.283185307179586

assistant: ```c
void FlattenWrappedPhase(float **wrappedphase, float **unwrappedest, long nrow, long ncol) {
  long row, col;
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol; col++) {
      wrappedphase[row][col] -= unwrappedest[row][col];
      wrappedphase[row][col] = fmod(wrappedphase[row][col], 6.28318530717958647692);
      if (wrappedphase[row][col] < 0) {
        wrappedphase[row][col] += 6.28318530717958647692;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FlattenWrappedPhase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rdx,%rdx
  jle    L9
  mov    %rcx,%r15
  mov    %rdi,%r12
  mov    %rsi,%r14
  movq   $0x0,(%rsp)
  jmp    L19
L34:
  add    $0x1,%rbp
  cmp    %rbp,%r15
  je     L77
L38:
  lea    0x0(,%rbp,4),%rbx
  mov    %rbx,%rax
  add    (%r12),%rax
  mov    (%r14),%rdx
  movss  (%rax),%xmm0
  subss  (%rdx,%rbp,4),%xmm0
  movss  %xmm0,(%rax)
  mov    %rbx,%r13
  add    (%r12),%r13
  movsd  D10(%rip),%xmm1
  movss  0x0(%r13),%xmm0
  call   <fmod@plt>
  movss  %xmm0,0x0(%r13)
  add    (%r12),%rbx
  movss  (%rbx),%xmm0
  pxor   %xmm2,%xmm2
  comiss %xmm0,%xmm2
  jbe    L34
  cvtss2sd %xmm0,%xmm0
  addsd  D10(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rbx)
  jmp    L34
L77:
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  add    $0x8,%r12
  add    $0x8,%r14
  cmp    %rax,0x8(%rsp)
  je     L9
L19:
  mov    $0x0,%ebp
  test   %r15,%r15
  jg     L38
  jmp    L77
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type: f64

tool: D10: 6.283185307179586

assistant: ```c
void FlattenWrappedPhase(float **wrappedphase, float **unwrappedest, long nrow, long ncol) {
  long row, col;
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol; col++) {
      wrappedphase[row][col] -= unwrappedest[row][col];
      wrappedphase[row][col] = fmod(wrappedphase[row][col], 6.28318530717958647692);
      if (wrappedphase[row][col] < 0) {
        wrappedphase[row][col] += 6.28318530717958647692;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FlattenWrappedPhase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rdx,%rdx
  jle    L18
  movq   $0x0,(%rsp)
  mov    %rcx,%r12
  mov    %rsi,%r14
  mov    %rdi,%rbp
  movsd  D12(%rip),%xmm1
  nopl   0x0(%rax)
L44:
  test   %r12,%r12
  jle    L7
  mov    0x0(%rbp),%rbx
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L41:
  mov    (%r14),%rcx
  lea    0x0(,%r13,4),%r15
  add    %r15,%rbx
  movss  (%rbx),%xmm0
  subss  (%rcx,%r13,4),%xmm0
  movss  %xmm0,(%rbx)
  call   <fmod@plt>
  pxor   %xmm2,%xmm2
  mov    D12(%rip),%rax
  movss  %xmm0,(%rbx)
  mov    0x0(%rbp),%rbx
  movq   %rax,%xmm1
  add    %rbx,%r15
  movss  (%r15),%xmm0
  comiss %xmm0,%xmm2
  jbe    L14
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r15)
L14:
  add    $0x1,%r13
  cmp    %r13,%r12
  jne    L41
L7:
  addq   $0x1,(%rsp)
  add    $0x8,%r14
  mov    (%rsp),%rax
  add    $0x8,%rbp
  cmp    %rax,0x8(%rsp)
  jne    L44
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: f64

tool: D12: 6.283185307179586

assistant: ```c
void FlattenWrappedPhase(float **wrappedphase, float **unwrappedest, long nrow, long ncol) {
  long row, col;
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol; col++) {
      wrappedphase[row][col] -= unwrappedest[row][col];
      wrappedphase[row][col] = fmod(wrappedphase[row][col], 6.28318530717958647692);
      if (wrappedphase[row][col] < 0) {
        wrappedphase[row][col] += 6.28318530717958647692;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FlattenWrappedPhase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %rdx,%rdx
  jle    L46
  mov    %rcx,%r12
  test   %rcx,%rcx
  jle    L46
  movq   $0x0,(%rsp)
  movsd  D0(%rip),%xmm1
  mov    %rdi,%rbp
  mov    %rsi,%r14
  nopw   0x0(%rax,%rax,1)
L1:
  mov    0x0(%rbp),%rbx
  xor    %r13d,%r13d
  nop
L32:
  mov    (%r14),%rcx
  lea    0x0(,%r13,4),%r15
  add    %r15,%rbx
  movss  (%rbx),%xmm0
  subss  (%rcx,%r13,4),%xmm0
  movss  %xmm0,(%rbx)
  call   <fmod@plt>
  pxor   %xmm2,%xmm2
  mov    D0(%rip),%rax
  movss  %xmm0,(%rbx)
  mov    0x0(%rbp),%rbx
  movq   %rax,%xmm1
  add    %rbx,%r15
  movss  (%r15),%xmm0
  comiss %xmm0,%xmm2
  jbe    L20
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%r15)
L20:
  add    $0x1,%r13
  cmp    %r13,%r12
  jne    L32
  addq   $0x1,(%rsp)
  add    $0x8,%rbp
  mov    (%rsp),%rax
  add    $0x8,%r14
  cmp    %rax,0x8(%rsp)
  jne    L1
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: f64

tool: D0: 6.283185307179586

assistant: ```c
void FlattenWrappedPhase(float **wrappedphase, float **unwrappedest, long nrow, long ncol) {
  long row, col;
  for (row = 0; row < nrow; row++) {
    for (col = 0; col < ncol; col++) {
      wrappedphase[row][col] -= unwrappedest[row][col];
      wrappedphase[row][col] = fmod(wrappedphase[row][col], 6.28318530717958647692);
      if (wrappedphase[row][col] < 0) {
        wrappedphase[row][col] += 6.28318530717958647692;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D17
type: string

tool: D6: %-3.5f   

tool: D17: 


assistant: ```c
void write_out(int neq, float **A) {
  for (int i = 0; i < neq; i++) {
    for (int j = 0; j < neq + 1; j++) {
      printf("%-3.5f   ", A[i][j]);
    }
    printf("\n");
  }
  printf("\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_out>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L3
  mov    %edi,%r12d
  mov    %rsi,%rbp
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r14
  lea    D7(%rip),%r13
L10:
  mov    $0x0,%ebx
L29:
  mov    0x0(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtss2sd (%rax,%rbx,4),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  jne    L10
L3:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D12
datatype: string

tool: D7: %-3.5f   

tool: D12: 


assistant: ```c
void write_out(int neq, float **A) {
  for (int i = 0; i < neq; i++) {
    for (int j = 0; j < neq + 1; j++) {
      printf("%-3.5f   ", A[i][j]);
    }
    printf("\n");
  }
  printf("\n\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<write_out>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %r14
  lea    -0x1(%rdi),%eax
  mov    %rsi,%r14
  push   %r13
  lea    0x8(%rsi,%rax,8),%r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  nopl   0x0(%rax)
L5:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%r14),%rax
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  cvtss2sd (%rax,%rbx,4),%xmm0
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L20
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r14,%r13
  jne    L5
  pop    %rbx
  lea    D23(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <puts@plt>
L7:
  lea    D23(%rip),%rdi
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string

tool: D24: %-3.5f   

tool: D23: 


assistant: ```c
void write_out(int neq, float **A) {
  for (int i = 0; i < neq; i++) {
    for (int j = 0; j < neq + 1; j++) {
      printf("%-3.5f   ", A[i][j]);
    }
    printf("\n");
  }
  printf("\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_out>:
  endbr64
  test   %edi,%edi
  jle    L29
  push   %r14
  lea    -0x1(%rdi),%eax
  mov    %rsi,%r14
  push   %r13
  lea    0x8(%rsi,%rax,8),%r13
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  nopl   0x0(%rax)
L15:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%r14),%rax
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  cvtss2sd (%rax,%rbx,4),%xmm0
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L22
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r14,%r13
  jne    L15
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <puts@plt>
L29:
  lea    D10(%rip),%rdi
  jmp    1080 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D19: %-3.5f   

tool: D10: 


assistant: ```c
void write_out(int neq, float **A) {
  for (int i = 0; i < neq; i++) {
    for (int j = 0; j < neq + 1; j++) {
      printf("%-3.5f   ", A[i][j]);
    }
    printf("\n");
  }
  printf("\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <recSum@plt>
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D21
type_guessed: string

tool: D15: For how many consecutive natural numbers would you like to calculate the sum?

tool: D3: %d

tool: D21: The sum is %d.


assistant: ```c
int main() {
  int term = 0;
  printf("For how many consecutive natural numbers would you like to calculate the sum?\n");
  scanf("%d", &term);
  printf("The sum is %d.\n", recSum(term));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D3(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <recSum@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D28
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string

tool: D3: For how many consecutive natural numbers would you like to calculate the sum?

tool: D28: %d

tool: D24: The sum is %d.


assistant: ```c
int main() {
  int term = 0;
  printf("For how many consecutive natural numbers would you like to calculate the sum?\n");
  scanf("%d", &term);
  printf("The sum is %d.\n", recSum(term));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <recSum@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
type: string
name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D14: For how many consecutive natural numbers would you like to calculate the sum?

tool: D13: %d

tool: D7: The sum is %d.


assistant: ```c
int main() {
  int term = 0;
  printf("For how many consecutive natural numbers would you like to calculate the sum?\n");
  scanf("%d", &term);
  printf("The sum is %d.\n", recSum(term));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <recSum@plt>
  lea    D21(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D21
type_infered: string

tool: D5: For how many consecutive natural numbers would you like to calculate the sum?

tool: D7: %d

tool: D21: The sum is %d.


assistant: ```c
int main() {
  int term = 0;
  printf("For how many consecutive natural numbers would you like to calculate the sum?\n");
  scanf("%d", &term);
  printf("The sum is %d.\n", recSum(term));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<putchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x804,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  or     $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  nop
L1:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putchar(uint8_t c) {
  uint32_t a3;
  volatile uint32_t *tx_reg = (uint32_t *)((1 << 11) + 4);
  a3 = 1 | (c << 8);
  *tx_reg = a3;
  a3 = c << 8;
  *tx_reg = a3;
  while (*((uint8_t *)tx_reg) == 0) {
  }
}
```