ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_larx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xfc0007fe,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x7c000068,-0x4(%rbp)
  je     L12
  cmpl   $0x7c0000e8,-0x4(%rbp)
  je     L12
  cmpl   $0x7c000028,-0x4(%rbp)
  je     L12
  cmpl   $0x7c0000a8,-0x4(%rbp)
  je     L12
  cmpl   $0x7c000228,-0x4(%rbp)
  jne    L25
L12:
  mov    $0x1,%eax
  jmp    L8
L25:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
bool is_larx(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc0007fe;
  if ((insn_base == 0x7c000068) || (insn_base == 0x7c0000e8) || (insn_base == 0x7c000028) || (insn_base == 0x7c0000A8) || (insn_base == 0x7c000228))
    return true;
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_larx>:
  endbr64
  mov    %edi,%edx
  and    $0xfc0007be,%edx
  cmp    $0x7c000028,%edx
  sete   %al
  cmp    $0x7c0000a8,%edx
  sete   %dl
  or     %edx,%eax
  and    $0xfc0007fe,%edi
  cmp    $0x7c000228,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_larx(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc0007fe;
  if ((insn_base == 0x7c000068) || (insn_base == 0x7c0000e8) || (insn_base == 0x7c000028) || (insn_base == 0x7c0000A8) || (insn_base == 0x7c000228))
    return true;
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_larx>:
  endbr64
  mov    %edi,%eax
  and    $0xfc00073e,%eax
  cmp    $0x7c000028,%eax
  sete   %al
  and    $0xfc0007fe,%edi
  cmp    $0x7c000228,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_larx(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc0007fe;
  if ((insn_base == 0x7c000068) || (insn_base == 0x7c0000e8) || (insn_base == 0x7c000028) || (insn_base == 0x7c0000A8) || (insn_base == 0x7c000228))
    return true;
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_larx>:
  endbr64
  mov    %edi,%eax
  and    $0xfc00073e,%eax
  cmp    $0x7c000028,%eax
  sete   %al
  and    $0xfc0007fe,%edi
  cmp    $0x7c000228,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_larx(uint32_t insn) {
  uint32_t insn_base = insn & 0xfc0007fe;
  if ((insn_base == 0x7c000068) || (insn_base == 0x7c0000e8) || (insn_base == 0x7c000028) || (insn_base == 0x7c0000A8) || (insn_base == 0x7c000228))
    return true;
  return false;
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_cyclic>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x0,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  movl   $0x0,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  mov    $0x0,%edx
L86:
  mov    (%rdi,%rdx,1),%ecx
  movslq %ecx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,(%rsp,%rdx,1)
  imul   $0x64,%eax,%eax
  sub    %eax,%ecx
  mov    %ecx,0x20(%rsp,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x18,%rdx
  jne    L86
  mov    (%rsp),%ecx
  mov    %ecx,%edx
  add    0x4(%rsp),%edx
  add    0x8(%rsp),%edx
  add    0xc(%rsp),%edx
  add    0x10(%rsp),%edx
  add    0x14(%rsp),%edx
  mov    0x24(%rsp),%eax
  add    0x20(%rsp),%eax
  add    0x28(%rsp),%eax
  add    0x2c(%rsp),%eax
  add    0x30(%rsp),%eax
  add    0x34(%rsp),%eax
  mov    $0x0,%esi
  cmp    %eax,%edx
  jne    L71
  movl   $0x0,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0x2,0x48(%rsp)
  movl   $0x3,0x4c(%rsp)
  movl   $0x4,0x50(%rsp)
  movl   $0x5,0x54(%rsp)
  mov    $0x5,%r8d
L55:
  mov    $0x1,%eax
  movslq %esi,%rsi
  jmp    L83
L19:
  add    $0x1,%rax
  cmp    $0x6,%rax
  je     L81
L83:
  mov    %eax,%edi
  mov    0x40(%rsp,%rax,4),%edx
  cmp    $0xffffffff,%edx
  je     L19
  movslq %edx,%rdx
  mov    (%rsp,%rdx,4),%edx
  cmp    %edx,0x20(%rsp,%rsi,4)
  jne    L19
  cltq
  movl   $0xffffffff,0x40(%rsp,%rax,4)
  sub    $0x1,%r8d
  je     L95
  mov    %edi,%esi
  jmp    L55
L81:
  mov    $0x0,%esi
L71:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    %esi,%eax
  add    $0x68,%rsp
  ret
L95:
  movslq %edi,%rdi
  cmp    %ecx,0x20(%rsp,%rdi,4)
  sete   %sil
  movzbl %sil,%esi
  jmp    L71
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_cyclic(int *nums) {
  int l1[] = {0, 0, 0, 0, 0, 0};
  int l2[] = {0, 0, 0, 0, 0, 0};
  for (int i = 0; i < 6; i++) {
    l1[i] = nums[i] / 100;
    l2[i] = nums[i] - 100 * (nums[i] / 100);
    if (0)
      printf("%d\t%d\t%d\n", nums[i], l1[i], l2[i]);
  }
  if (l1[0] + l1[1] + l1[2] + l1[3] + l1[4] + l1[5] != l2[0] + l2[1] + l2[2] + l2[3] + l2[4] + l2[5])
    return 0;
  int idx[] = {0, 1, 2, 3, 4, 5};
  int flag;
  int n = 0;
  for (int i = 0; i < 6 - 1; i++) {
    flag = 0;
    for (int j = 1; j < 6; j++) {
      if (idx[j] != -1) {
        if (l2[n] == l1[idx[j]]) {
          flag = 1;
          idx[j] = -1;
          n = j;
          break;
        }
      }
    }
    if (flag == 0)
      return 0;
  }
  if (l2[n] == l1[0])
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_cyclic>:
  endbr64
  sub    $0x68,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%r9
  lea    0x20(%rsp),%r8
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  nopw   0x0(%rax,%rax,1)
L82:
  movslq (%rdi,%rdx,1),%rax
  mov    %rax,%rcx
  imul   $0x51eb851f,%rax,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sar    $0x25,%rax
  sub    %esi,%eax
  mov    %eax,(%r9,%rdx,1)
  imul   $0x64,%eax,%eax
  sub    %eax,%ecx
  mov    %ecx,(%r8,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x18,%rdx
  jne    L82
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  mov    0x24(%rsp),%eax
  add    0x20(%rsp),%eax
  add    %ecx,%edx
  add    0x28(%rsp),%eax
  add    0x8(%rsp),%edx
  add    0x2c(%rsp),%eax
  add    0xc(%rsp),%edx
  add    0x30(%rsp),%eax
  add    0x10(%rsp),%edx
  add    0x34(%rsp),%eax
  add    0x14(%rsp),%edx
  cmp    %eax,%edx
  jne    L22
  movl   $0x1,0x44(%rsp)
  mov    $0x5,%r8d
  mov    $0x1,%edx
  xor    %esi,%esi
  movabs $0x300000002,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x50(%rsp)
L104:
  mov    $0x1,%eax
  movslq %eax,%rdi
  cmp    $0xffffffff,%edx
  je     L10
L9:
  mov    (%rsp,%rdx,4),%edx
  cmp    %edx,0x20(%rsp,%rsi,4)
  je     L59
L10:
  add    $0x1,%rax
  cmp    $0x6,%rax
  je     L22
L74:
  movslq 0x40(%rsp,%rax,4),%rdx
  movslq %eax,%rdi
  cmp    $0xffffffff,%edx
  jne    L9
  add    $0x1,%rax
  cmp    $0x6,%rax
  jne    L74
  nop
L22:
  xor    %eax,%eax
L52:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L98
  add    $0x68,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  movl   $0xffffffff,0x40(%rsp,%rdi,4)
  sub    $0x1,%r8d
  jne    L96
  xor    %eax,%eax
  cmp    %ecx,0x20(%rsp,%rdi,4)
  sete   %al
  jmp    L52
L98:
  call   <__stack_chk_fail@plt>
L96:
  movslq 0x44(%rsp),%rdx
  movslq %eax,%rsi
  jmp    L104
```

assistant: ```c
int check_cyclic(int *nums) {
  int l1[] = {0, 0, 0, 0, 0, 0};
  int l2[] = {0, 0, 0, 0, 0, 0};
  for (int i = 0; i < 6; i++) {
    l1[i] = nums[i] / 100;
    l2[i] = nums[i] - 100 * (nums[i] / 100);
    if (0)
      printf("%d\t%d\t%d\n", nums[i], l1[i], l2[i]);
  }
  if (l1[0] + l1[1] + l1[2] + l1[3] + l1[4] + l1[5] != l2[0] + l2[1] + l2[2] + l2[3] + l2[4] + l2[5])
    return 0;
  int idx[] = {0, 1, 2, 3, 4, 5};
  int flag;
  int n = 0;
  for (int i = 0; i < 6 - 1; i++) {
    flag = 0;
    for (int j = 1; j < 6; j++) {
      if (idx[j] != -1) {
        if (l2[n] == l1[idx[j]]) {
          flag = 1;
          idx[j] = -1;
          n = j;
          break;
        }
      }
    }
    if (flag == 0)
      return 0;
  }
  if (l2[n] == l1[0])
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<malloc_failure_short_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  cltq
  add    %eax,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xfffffed3,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string
name: extract_symbolic_data
arguments: tag: D18
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D8: 
*** FATAL ERROR IN %s FUNCTION


tool: D18: *** COMMAND WAS: %s = malloc(%d * sizeof(short int));


tool: D7: *** STATUS - FAILED TO ALLOCATE %d bytes


assistant: ```c
void malloc_failure_short_int(char *routine, char *var_name, int short_ints_requested) {
  printf("\n*** FATAL ERROR IN %s FUNCTION\n", routine);
  printf("*** COMMAND WAS: %s = malloc(%d * sizeof(short int));\n", var_name, short_ints_requested);
  printf("*** STATUS - FAILED TO ALLOCATE %d bytes\n", (int)(short_ints_requested * sizeof(short int)));
  exit(-301);
}
```
user: Translate the below assembly code into C programming language:

```asm
<malloc_failure_short_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    %rdi,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    (%rbx,%rbx,1),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xfffffed3,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D14: 
*** FATAL ERROR IN %s FUNCTION


tool: D3: *** COMMAND WAS: %s = malloc(%d * sizeof(short int));


tool: D13: *** STATUS - FAILED TO ALLOCATE %d bytes


assistant: ```c
void malloc_failure_short_int(char *routine, char *var_name, int short_ints_requested) {
  printf("\n*** FATAL ERROR IN %s FUNCTION\n", routine);
  printf("*** COMMAND WAS: %s = malloc(%d * sizeof(short int));\n", var_name, short_ints_requested);
  printf("*** STATUS - FAILED TO ALLOCATE %d bytes\n", (int)(short_ints_requested * sizeof(short int)));
  exit(-301);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<malloc_failure_short_int>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  lea    D8(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbx,1),%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0xfffffed3,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D8: 
*** FATAL ERROR IN %s FUNCTION


tool: D7: *** COMMAND WAS: %s = malloc(%d * sizeof(short int));


tool: D3: *** STATUS - FAILED TO ALLOCATE %d bytes


assistant: ```c
void malloc_failure_short_int(char *routine, char *var_name, int short_ints_requested) {
  printf("\n*** FATAL ERROR IN %s FUNCTION\n", routine);
  printf("*** COMMAND WAS: %s = malloc(%d * sizeof(short int));\n", var_name, short_ints_requested);
  printf("*** STATUS - FAILED TO ALLOCATE %d bytes\n", (int)(short_ints_requested * sizeof(short int)));
  exit(-301);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<malloc_failure_short_int>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  lea    D7(%rip),%rdi
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbx,1),%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0xfffffed3,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string
name: disassemble_data
arguments: data_label: D28
type_infered: string

tool: D7: 
*** FATAL ERROR IN %s FUNCTION


tool: D25: *** COMMAND WAS: %s = malloc(%d * sizeof(short int));


tool: D28: *** STATUS - FAILED TO ALLOCATE %d bytes


assistant: ```c
void malloc_failure_short_int(char *routine, char *var_name, int short_ints_requested) {
  printf("\n*** FATAL ERROR IN %s FUNCTION\n", routine);
  printf("*** COMMAND WAS: %s = malloc(%d * sizeof(short int));\n", var_name, short_ints_requested);
  printf("*** STATUS - FAILED TO ALLOCATE %d bytes\n", (int)(short_ints_requested * sizeof(short int)));
  exit(-301);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_timegm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x1,%edx
  lea    D35(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <setenv@plt>
  jmp    L14
L8:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <unsetenv@plt>
L14:
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D23
data_type: string
name: disassemble_data
arguments: data_label: D35
data_type: string

tool: D23: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_timegm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D26(%rip),%r12
  mov    %r12,%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  mov    $0x1,%edx
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <setenv@plt>
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %rbp,%rdi
  call   <mktime@plt>
  mov    %eax,%ebp
  test   %rbx,%rbx
  je     L16
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <setenv@plt>
L10:
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  lea    D26(%rip),%rdi
  call   <unsetenv@plt>
  jmp    L10
```

tool_calls: name: unpack_data
arguments: data_tag: D26
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D26: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_timegm>:
  endbr64
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  call   <getenv@plt>
  mov    $0x1,%edx
  lea    D7(%rip),%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L3
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    %r13,%rdi
  call   <unsetenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type_guessed: string
name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D12: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_timegm>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  call   <getenv@plt>
  mov    $0x1,%edx
  lea    D1(%rip),%rsi
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12,%rdi
  call   <mktime@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L5
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x1,%edx
  call   <setenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %r13,%rdi
  call   <unsetenv@plt>
  xor    %eax,%eax
  call   <tzset@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string

tool: D5: TZ

tool: 

assistant: ```c
time_t my_timegm(struct tm *tm) {
  time_t ret;
  char *tz;
  tz = getenv("TZ");
  setenv("TZ", "", 1);
  tzset();
  ret = mktime(tm);
  if (tz)
    setenv("TZ", tz, 1);
  else
    unsetenv("TZ");
  tzset();
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<t4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void t4() {
  unsigned long long a;
  struct reg {
    unsigned long long a, b;
  } b;
  __asm__ volatile("" ::"m"(a), "m"(b));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t4>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t4() {
  unsigned long long a;
  struct reg {
    unsigned long long a, b;
  } b;
  __asm__ volatile("" ::"m"(a), "m"(b));
}
```
user: What is the c source code of the assembly code below:

```asm
<t4>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t4() {
  unsigned long long a;
  struct reg {
    unsigned long long a, b;
  } b;
  __asm__ volatile("" ::"m"(a), "m"(b));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t4>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void t4() {
  unsigned long long a;
  struct reg {
    unsigned long long a, b;
  } b;
  __asm__ volatile("" ::"m"(a), "m"(b));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<CountWords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L43
L30:
  movl   $0x0,-0x4(%rbp)
L57:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L41
  addl   $0x1,-0x4(%rbp)
  jmp    L11
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x5(%rbp)
L11:
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L3
L41:
  mov    D9(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L49
  cmpb   $0x0,-0x5(%rbp)
  je     L49
  jmp    L57
L49:
  mov    -0x4(%rbp),%eax
L43:
  leave
  ret
```

assistant: ```c
int CountWords(FILE *stream) {
  if (!stream) {
    errno = EINVAL;
    return 0;
  }
  int count = 0;
  char c;
  while (1) {
    c = fgetc(stream);
    if (isalnum(c)) {
      ++count;
      while (isalnum(c)) {
        c = fgetc(stream);
      }
    }
    if (c == EOF || c == '\0') {
      break;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CountWords>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x0,%r12d
  test   %rdi,%rdi
  jne    L47
  mov    D28(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
L34:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
L50:
  movsbl %bl,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L16
L8:
  mov    D24(%rip),%rax
  cmp    %bl,(%rax)
  je     L34
  test   %bl,%bl
  je     L34
L47:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  movsbl %al,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L8
  add    $0x1,%r12d
  jmp    L50
```

assistant: ```c
int CountWords(FILE *stream) {
  if (!stream) {
    errno = EINVAL;
    return 0;
  }
  int count = 0;
  char c;
  while (1) {
    c = fgetc(stream);
    if (isalnum(c)) {
      ++count;
      while (isalnum(c)) {
        c = fgetc(stream);
      }
    }
    if (c == EOF || c == '\0') {
      break;
    }
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CountWords>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L57
  mov    D25(%rip),%r12
  mov    %rdi,%rbp
  xor    %r13d,%r13d
  jmp    L46
L2:
  cmp    %bl,(%r12)
  je     L41
L79:
  test   %bl,%bl
  je     L41
L46:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  movsbl %al,%r14d
  mov    %r14d,%edi
  mov    %r14d,%ebx
  call   <isalnum@plt>
  test   %rax,%rax
  je     L2
  add    $0x1,%r13d
  jmp    L32
  nopl   0x0(%rax)
L53:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  movsbl %al,%r14d
  mov    %r14d,%ebx
L32:
  mov    %r14d,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  jne    L53
  cmp    %bl,(%r12)
  jne    L79
L41:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  mov    D4(%rip),%rax
  xor    %r13d,%r13d
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int CountWords(FILE *stream) {
  if (!stream) {
    errno = EINVAL;
    return 0;
  }
  int count = 0;
  char c;
  while (1) {
    c = fgetc(stream);
    if (isalnum(c)) {
      ++count;
      while (isalnum(c)) {
        c = fgetc(stream);
      }
    }
    if (c == EOF || c == '\0') {
      break;
    }
  }
  return count;
}
```