ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<welcome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D58
type_guessed: string
name: unpack_data
arguments: data_label: D51
type_guessed: string
name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D15
type_guessed: string

tool: D41:         Welcome to Paul Brittains Lottery Checker       


tool: D1:                 1st Year, Computer Science              


tool: D58:               Dublin Institute of Technology            


tool: D51:                       Kevin Street                      


tool: D27:                     Dublin, Ireland                           




tool: D15: Press Enter To Access Main Menu

assistant: ```c
void welcome(void) {
  printf("        Welcome to Paul Brittains Lottery Checker       \n");
  printf("                1st Year, Computer Science              \n");
  printf("              Dublin Institute of Technology            \n");
  printf("                      Kevin Street                      \n");
  printf("                    Dublin, Ireland                           \n\n\n");
  printf("Press Enter To Access Main Menu");
  getchar();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<welcome>:
  endbr64
  sub    $0x8,%rsp
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D32
type_infered: string
name: disassemble_data
arguments: label: D24
type_infered: string
name: disassemble_data
arguments: label: D39
type_infered: string
name: disassemble_data
arguments: label: D55
type_infered: string
name: disassemble_data
arguments: label: D6
type_infered: string
name: disassemble_data
arguments: label: D50
type_infered: string

tool: D32:         Welcome to Paul Brittains Lottery Checker       


tool: D24:                 1st Year, Computer Science              


tool: D39:               Dublin Institute of Technology            


tool: D55:                       Kevin Street                      


tool: D6:                     Dublin, Ireland                           




tool: D50: Press Enter To Access Main Menu

assistant: ```c
void welcome(void) {
  printf("        Welcome to Paul Brittains Lottery Checker       \n");
  printf("                1st Year, Computer Science              \n");
  printf("              Dublin Institute of Technology            \n");
  printf("                      Kevin Street                      \n");
  printf("                    Dublin, Ireland                           \n\n\n");
  printf("Press Enter To Access Main Menu");
  getchar();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<welcome>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type: string
name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D59
type: string
name: disassemble_data
arguments: tag: D13
type: string
name: disassemble_data
arguments: tag: D9
type: string

tool: D5:         Welcome to Paul Brittains Lottery Checker       


tool: D7:                 1st Year, Computer Science              


tool: D0:               Dublin Institute of Technology            


tool: D59:                       Kevin Street                      


tool: D13:                     Dublin, Ireland                           




tool: D9: Press Enter To Access Main Menu

assistant: ```c
void welcome(void) {
  printf("        Welcome to Paul Brittains Lottery Checker       \n");
  printf("                1st Year, Computer Science              \n");
  printf("              Dublin Institute of Technology            \n");
  printf("                      Kevin Street                      \n");
  printf("                    Dublin, Ireland                           \n\n\n");
  printf("Press Enter To Access Main Menu");
  getchar();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<welcome>:
  endbr64
  sub    $0x8,%rsp
  lea    D39(%rip),%rdi
  call   <printf@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <getchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D39
type: string
name: read_data
arguments: data_tag: D49
type: string
name: read_data
arguments: data_tag: D6
type: string
name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D37
type: string
name: read_data
arguments: data_tag: D45
type: string

tool: D39:         Welcome to Paul Brittains Lottery Checker       


tool: D49:                 1st Year, Computer Science              


tool: D6:               Dublin Institute of Technology            


tool: D20:                       Kevin Street                      


tool: D37:                     Dublin, Ireland                           




tool: D45: Press Enter To Access Main Menu

assistant: ```c
void welcome(void) {
  printf("        Welcome to Paul Brittains Lottery Checker       \n");
  printf("                1st Year, Computer Science              \n");
  printf("              Dublin Institute of Technology            \n");
  printf("                      Kevin Street                      \n");
  printf("                    Dublin, Ireland                           \n\n\n");
  printf("Press Enter To Access Main Menu");
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<unescapeURLchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  cmpb   $0x40,-0xc(%rbp)
  jle    L38
  movzbl -0xc(%rbp),%eax
  and    $0xffffffdf,%eax
  sub    $0x37,%eax
  jmp    L13
L38:
  movzbl -0xc(%rbp),%eax
  sub    $0x30,%eax
L13:
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  cmpb   $0x40,-0x10(%rbp)
  jle    L14
  movzbl -0x10(%rbp),%eax
  and    $0xffffffdf,%eax
  sub    $0x37,%eax
  jmp    L1
L14:
  movzbl -0x10(%rbp),%eax
  sub    $0x30,%eax
L1:
  mov    %ebx,%edx
  add    %edx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char unescapeURLchar(char c1, char c2) {
  register char c;
  c = (c1 >= 'A') ? ((c1 & 0xdf) - 'A') + 10 : (c1 - '0');
  c *= 16;
  c += (c2 >= 'A') ? ((c2 & 0xdf) - 'A') + 10 : (c2 - '0');
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unescapeURLchar>:
  endbr64
  mov    %edi,%edx
  and    $0xffffffdf,%edx
  sub    $0x37,%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x41,%dil
  cmovge %edx,%eax
  shl    $0x4,%eax
  mov    %esi,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x37,%ecx
  lea    -0x30(%rsi),%edx
  cmp    $0x41,%sil
  cmovge %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
char unescapeURLchar(char c1, char c2) {
  register char c;
  c = (c1 >= 'A') ? ((c1 & 0xdf) - 'A') + 10 : (c1 - '0');
  c *= 16;
  c += (c2 >= 'A') ? ((c2 & 0xdf) - 'A') + 10 : (c2 - '0');
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<unescapeURLchar>:
  endbr64
  mov    %edi,%edx
  lea    -0x30(%rdi),%eax
  mov    %esi,%ecx
  and    $0xffffffdf,%edx
  sub    $0x37,%edx
  cmp    $0x41,%dil
  cmovge %edx,%eax
  and    $0xffffffdf,%ecx
  lea    -0x30(%rsi),%edx
  sub    $0x37,%ecx
  shl    $0x4,%eax
  cmp    $0x41,%sil
  cmovge %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
char unescapeURLchar(char c1, char c2) {
  register char c;
  c = (c1 >= 'A') ? ((c1 & 0xdf) - 'A') + 10 : (c1 - '0');
  c *= 16;
  c += (c2 >= 'A') ? ((c2 & 0xdf) - 'A') + 10 : (c2 - '0');
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unescapeURLchar>:
  endbr64
  mov    %edi,%edx
  lea    -0x30(%rdi),%eax
  mov    %esi,%ecx
  and    $0xffffffdf,%edx
  sub    $0x37,%edx
  cmp    $0x41,%dil
  cmovge %edx,%eax
  and    $0xffffffdf,%ecx
  lea    -0x30(%rsi),%edx
  sub    $0x37,%ecx
  shl    $0x4,%eax
  cmp    $0x41,%sil
  cmovge %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
char unescapeURLchar(char c1, char c2) {
  register char c;
  c = (c1 >= 'A') ? ((c1 & 0xdf) - 'A') + 10 : (c1 - '0');
  c *= 16;
  c += (c2 >= 'A') ? ((c2 & 0xdf) - 'A') + 10 : (c2 - '0');
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L72
  mov    $0x0,%eax
  jmp    L41
L72:
  cmpl   $0x2,-0x14(%rbp)
  jne    L67
  mov    $0x1,%eax
  jmp    L41
L67:
  movq   $0x2,-0x8(%rbp)
  jmp    L79
L5:
  mov    -0x14(%rbp),%eax
  cltq
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L54
  mov    $0x0,%eax
  jmp    L41
L54:
  addq   $0x1,-0x8(%rbp)
L79:
  mov    D2(%rip),%rdx
  mov    -0x14(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  cmp    %rax,-0x8(%rbp)
  jle    L5
  mov    $0x1,%eax
L41:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: f64

tool: D2: 0.5

assistant: ```c
int is_prime(int i) {
  if (i < 2)
    return 0;
  else if (i == 2)
    return 1;
  for (long j = 2; j <= pow(i, 0.5); j++) {
    if (i % j == 0)
      return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_prime>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%edi
  jle    L41
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x1,%eax
  mov    $0x2,%ebx
  cmp    $0x2,%edi
  je     L27
L4:
  mov    D0(%rip),%rax
  movq   %rax,%xmm0
  mov    %ebp,%edi
  call   <pow@plt>
  cmp    %rbx,%rax
  jl     L38
  movslq %ebp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L30
  add    $0x1,%rbx
  jmp    L4
L38:
  mov    $0x1,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    $0x0,%eax
  jmp    L27
L41:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: f64

tool: D0: 0.5

assistant: ```c
int is_prime(int i) {
  if (i < 2)
    return 0;
  else if (i == 2)
    return 1;
  for (long j = 2; j <= pow(i, 0.5); j++) {
    if (i % j == 0)
      return 0;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L38
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    $0x2,%ebx
  cmp    $0x2,%edi
  jne    L26
  jmp    L47
  nop
L8:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L24
  add    $0x1,%rbx
L26:
  mov    D8(%rip),%rax
  mov    %r12d,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  cmp    %rbx,%rax
  jge    L8
L47:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L38:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: f64

tool: D8: 0.5

assistant: ```c
int is_prime(int i) {
  if (i < 2)
    return 0;
  else if (i == 2)
    return 1;
  for (long j = 2; j <= pow(i, 0.5); j++) {
    if (i % j == 0)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_prime>:
  endbr64
  cmp    $0x1,%edi
  jle    L10
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    $0x2,%ebx
  cmp    $0x2,%edi
  jne    L33
  jmp    L23
  nop
L13:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  test   %rdx,%rdx
  je     L7
  add    $0x1,%rbx
L33:
  mov    D2(%rip),%rax
  mov    %r12d,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  cmp    %rbx,%rax
  jge    L13
L23:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L10:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: f64

tool: D2: 0.5

assistant: ```c
int is_prime(int i) {
  if (i < 2)
    return 0;
  else if (i == 2)
    return 1;
  for (long j = 2; j <= pow(i, 0.5); j++) {
    if (i % j == 0)
      return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L9:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  addq   $0x4,-0x10(%rbp)
  addq   $0x4,-0x8(%rbp)
L12:
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  test   %rax,%rax
  jne    L9
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memswap(void *first, void *second, size_t len) {
  uint8_t *first_bytes = first;
  uint8_t *second_bytes = second;
  uint8_t temp;
  for (; len--; first_bytes++, second_bytes++) {
    temp = *first_bytes;
    *first_bytes = *second_bytes;
    *second_bytes = temp;
  }
  return first;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memswap>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L12
  mov    $0x0,%ecx
L15:
  mov    (%rax,%rcx,4),%edi
  mov    (%rsi,%rcx,4),%r8d
  mov    %r8d,(%rax,%rcx,4)
  mov    %edi,(%rsi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L15
L12:
  ret
```

assistant: ```c
void *memswap(void *first, void *second, size_t len) {
  uint8_t *first_bytes = first;
  uint8_t *second_bytes = second;
  uint8_t temp;
  for (; len--; first_bytes++, second_bytes++) {
    temp = *first_bytes;
    *first_bytes = *second_bytes;
    *second_bytes = temp;
  }
  return first;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memswap>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L18
  xor    %ecx,%ecx
  xchg   %ax,%ax
L1:
  mov    (%rax,%rcx,4),%edi
  mov    (%rsi,%rcx,4),%r8d
  mov    %r8d,(%rax,%rcx,4)
  mov    %edi,(%rsi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L1
L18:
  ret
```

assistant: ```c
void *memswap(void *first, void *second, size_t len) {
  uint8_t *first_bytes = first;
  uint8_t *second_bytes = second;
  uint8_t temp;
  for (; len--; first_bytes++, second_bytes++) {
    temp = *first_bytes;
    *first_bytes = *second_bytes;
    *second_bytes = temp;
  }
  return first;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memswap>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdi,%r8
  lea    -0x1(%rdx),%rsi
  test   %rdx,%rdx
  je     L76
  lea    0xf(%rdi),%rax
  sub    %rcx,%rax
  cmp    $0x1e,%rax
  jbe    L98
  cmp    $0x1,%rdx
  je     L98
  cmp    $0x2,%rsi
  jbe    L63
  mov    %rdx,%rdi
  xor    %eax,%eax
  xor    %esi,%esi
  shr    $0x2,%rdi
  nopw   0x0(%rax,%rax,1)
L3:
  movdqu (%r8,%rax,1),%xmm0
  movdqu (%rcx,%rax,1),%xmm1
  add    $0x1,%rsi
  movups %xmm1,(%r8,%rax,1)
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rdi
  jne    L3
  mov    %rdx,%rdi
  and    $0xfffffffffffffffc,%rdi
  lea    0x0(,%rdi,4),%rax
  lea    (%r8,%rax,1),%rsi
  add    %rcx,%rax
  cmp    %rdi,%rdx
  je     L76
  sub    %rdi,%rdx
  cmp    $0x1,%rdx
  je     L79
L96:
  shl    $0x2,%rdi
  lea    (%r8,%rdi,1),%r9
  add    %rcx,%rdi
  mov    (%rdi),%r10
  mov    (%r9),%rcx
  mov    %r10,(%r9)
  mov    %rcx,(%rdi)
  mov    %rdx,%rcx
  and    $0xfffffffffffffffe,%rcx
  lea    0x0(,%rcx,4),%rdi
  add    %rdi,%rsi
  add    %rdi,%rax
  cmp    %rcx,%rdx
  je     L76
L79:
  mov    (%rsi),%edx
  mov    (%rax),%ecx
  mov    %ecx,(%rsi)
  mov    %edx,(%rax)
L76:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L98:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L38:
  mov    (%r8,%rax,4),%esi
  mov    (%rcx,%rax,4),%edi
  mov    %edi,(%r8,%rax,4)
  mov    %esi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L38
  mov    %r8,%rax
  ret
L63:
  mov    %rdi,%rsi
  mov    %rcx,%rax
  xor    %edi,%edi
  jmp    L96
```

assistant: ```c
void *memswap(void *first, void *second, size_t len) {
  uint8_t *first_bytes = first;
  uint8_t *second_bytes = second;
  uint8_t temp;
  for (; len--; first_bytes++, second_bytes++) {
    temp = *first_bytes;
    *first_bytes = *second_bytes;
    *second_bytes = temp;
  }
  return first;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L31
L69:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x20(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L31:
  cmpl   $0x4,-0x34(%rbp)
  jle    L69
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L60
L39:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  add    %eax,-0x30(%rbp)
  addl   $0x1,-0x34(%rbp)
L60:
  cmpl   $0x4,-0x34(%rbp)
  jle    L39
  movl   $0x0,-0x2c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L14
L47:
  mov    -0x28(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%eax
  add    %eax,-0x2c(%rbp)
  addl   $0x1,-0x34(%rbp)
L14:
  cmpl   $0x4,-0x34(%rbp)
  jle    L47
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

assistant: ```c
int main() {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    a[i] = i;
  }
  int s = 0;
  for (i = 0; i < 5; i++) {
    s += a[i];
  }
  int s2 = 0;
  int *pa = a;
  for (i = 0; i < 5; i++) {
    s2 += *(pa++);
  }
  return s == s2;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  mov    %rsp,%rax
  mov    $0x0,%edx
  lea    0x14(%rsp),%rcx
L18:
  add    $0x4,%rax
  add    -0x4(%rax),%edx
  cmp    %rcx,%rax
  jne    L18
  cmp    $0xa,%edx
  sete   %al
  movzbl %al,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x28,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    a[i] = i;
  }
  int s = 0;
  for (i = 0; i < 5; i++) {
    s += a[i];
  }
  int s2 = 0;
  int *pa = a;
  for (i = 0; i < 5; i++) {
    s2 += *(pa++);
  }
  return s == s2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000000,%rax
  lea    0x14(%rsp),%rsi
  add    %ecx,%edx
  movl   $0x4,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  mov    %rsp,%rax
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L11
L23:
  mov    (%rax),%ecx
  add    $0x4,%rax
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L23
L11:
  xor    %eax,%eax
  cmp    $0xa,%edx
  sete   %al
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x28,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    a[i] = i;
  }
  int s = 0;
  for (i = 0; i < 5; i++) {
    s += a[i];
  }
  int s2 = 0;
  int *pa = a;
  for (i = 0; i < 5; i++) {
    s2 += *(pa++);
  }
  return s == s2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  int a[5];
  int i;
  for (i = 0; i < 5; i++) {
    a[i] = i;
  }
  int s = 0;
  for (i = 0; i < 5; i++) {
    s += a[i];
  }
  int s2 = 0;
  int *pa = a;
  for (i = 0; i < 5; i++) {
    s2 += *(pa++);
  }
  return s == s2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<EMACTimestampSysTimeGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  add    $0x708,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x70c,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x70c,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jg     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EMACTimestampSysTimeGet(uint32_t ui32Base, uint32_t *pui32Seconds, uint32_t *pui32SubSeconds) {
  ;
  ;
  ;
  do {
    *pui32Seconds = (*((volatile uint32_t *)(ui32Base + 0x00000708)));
    *pui32SubSeconds = (*((volatile uint32_t *)(ui32Base + 0x0000070C)));
  } while (*pui32SubSeconds > (*((volatile uint32_t *)(ui32Base + 0x0000070C))));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<EMACTimestampSysTimeGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
L0:
  mov    -0x8(%rsp),%rax
  mov    0x708(%rax),%rax
  mov    %rax,(%rsi)
  mov    -0x8(%rsp),%rax
  mov    0x70c(%rax),%rax
  mov    %rax,(%rdx)
  mov    (%rdx),%rcx
  mov    -0x8(%rsp),%rax
  mov    0x70c(%rax),%rax
  cmp    %rax,%rcx
  jg     L0
  ret
```

assistant: ```c
void EMACTimestampSysTimeGet(uint32_t ui32Base, uint32_t *pui32Seconds, uint32_t *pui32SubSeconds) {
  ;
  ;
  ;
  do {
    *pui32Seconds = (*((volatile uint32_t *)(ui32Base + 0x00000708)));
    *pui32SubSeconds = (*((volatile uint32_t *)(ui32Base + 0x0000070C)));
  } while (*pui32SubSeconds > (*((volatile uint32_t *)(ui32Base + 0x0000070C))));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<EMACTimestampSysTimeGet>:
  endbr64
  mov    %rdi,-0x8(%rsp)
  nopl   0x0(%rax)
L8:
  mov    -0x8(%rsp),%rax
  mov    0x708(%rax),%rax
  mov    %rax,(%rsi)
  mov    -0x8(%rsp),%rax
  mov    0x70c(%rax),%rax
  mov    %rax,(%rdx)
  mov    (%rdx),%rcx
  mov    -0x8(%rsp),%rax
  mov    0x70c(%rax),%rax
  cmp    %rax,%rcx
  jg     L8
  ret
```

assistant: ```c
void EMACTimestampSysTimeGet(uint32_t ui32Base, uint32_t *pui32Seconds, uint32_t *pui32SubSeconds) {
  ;
  ;
  ;
  do {
    *pui32Seconds = (*((volatile uint32_t *)(ui32Base + 0x00000708)));
    *pui32SubSeconds = (*((volatile uint32_t *)(ui32Base + 0x0000070C)));
  } while (*pui32SubSeconds > (*((volatile uint32_t *)(ui32Base + 0x0000070C))));
}
```