ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%rbp
  mov    %r13,%rsi
  lea    0x14(%rsp),%r12
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L24
  xor    %ebx,%ebx
  xchg   %ax,%ax
L9:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L9
L24:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D12(%rip),%rdi
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D10: %d

tool: D12: %d %d %d


assistant: ```c
int main() {
  int times_swap;
  int count;
  int a, b, c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times_swap);
  for (count = 0; count < times_swap; count++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r13
  lea    0x10(%rsp),%rbp
  mov    %r13,%rsi
  lea    0x14(%rsp),%r12
  call   <scanf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L1
  xor    %ebx,%ebx
  xchg   %ax,%ax
L29:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <rotr@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L29
L1:
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D9(%rip),%rdi
  mov    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D8: %d

tool: D9: %d %d %d


assistant: ```c
int main() {
  int times_swap;
  int count;
  int a, b, c;
  scanf("%d", &a);
  scanf("%d", &b);
  scanf("%d", &c);
  scanf("%d", &times_swap);
  for (count = 0; count < times_swap; count++) {
    rotr(&a, &b, &c);
  }
  printf("%d %d %d\n", a, b, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<os_DirName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L84
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <xstrdup@plt>
  jmp    L63
L84:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L72
L75:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L86
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L86
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L86
  subq   $0x1,-0x8(%rbp)
L72:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L75
L86:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L25
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <xstrdup@plt>
  jmp    L63
L25:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L47
  addq   $0x1,-0x8(%rbp)
L47:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xmemdup@plt>
L63:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string
name: unpack_data
arguments: data_label: D19
data_type: string

tool: 

tool: D19: .

assistant: ```c
char *os_DirName(char const *str) {
  int len;
  char const *s;
  if (!str)
    return xstrdup("");
  len = strlen(str);
  for (s = str + len - 1; s >= str; s--) {
    if (*s == '/' || *s == '\\' || *s == ':') {
      break;
    }
  }
  if (s < str) {
    return xstrdup(".");
  }
  if (*s == ':')
    s++;
  return xmemdup(str, s - str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<os_DirName>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L75
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rsi
  cmp    %rsi,%rbx
  ja     L4
  movabs $0x200000000801,%rdx
  jmp    L31
L75:
  lea    D11(%rip),%rdi
  call   <xstrdup@plt>
  jmp    L21
L72:
  sub    $0x1,%rsi
  cmp    %rsi,%rbx
  ja     L4
L31:
  movzbl (%rsi),%eax
  sub    $0x2f,%eax
  cmp    $0x2d,%al
  ja     L72
  bt     %rax,%rdx
  jae    L72
  cmp    %rsi,%rbx
  ja     L4
  cmpb   $0x3a,(%rsi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rsi
  sub    %ebx,%esi
  mov    %rbx,%rdi
  call   <xmemdup@plt>
L21:
  pop    %rbx
  ret
L4:
  lea    D15(%rip),%rdi
  call   <xstrdup@plt>
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string

tool: 

tool: D15: .

assistant: ```c
char *os_DirName(char const *str) {
  int len;
  char const *s;
  if (!str)
    return xstrdup("");
  len = strlen(str);
  for (s = str + len - 1; s >= str; s--) {
    if (*s == '/' || *s == '\\' || *s == ':') {
      break;
    }
  }
  if (s < str) {
    return xstrdup(".");
  }
  if (*s == ':')
    s++;
  return xmemdup(str, s - str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<os_DirName>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rsi
  cmp    %rsi,%rbp
  ja     L56
  movabs $0xffffdffffffff7fe,%rcx
  jmp    L7
  nopw   0x0(%rax,%rax,1)
L68:
  sub    $0x1,%rsi
  cmp    %rsi,%rbp
  ja     L56
L7:
  movzbl (%rsi),%edx
  lea    -0x2f(%rdx),%eax
  cmp    $0x2d,%al
  ja     L68
  bt     %rax,%rcx
  jb     L68
  cmp    %rsi,%rbp
  ja     L56
  xor    %eax,%eax
  cmp    $0x3a,%dl
  mov    %rbp,%rdi
  sete   %al
  add    %rax,%rsi
  sub    %ebp,%esi
  pop    %rbp
  jmp    1090 <xmemdup@plt>
  nopl   0x0(%rax)
L39:
  lea    D7(%rip),%rdi
  jmp    1080 <xstrdup@plt>
  nopl   0x0(%rax)
L56:
  lea    D1(%rip),%rdi
  pop    %rbp
  jmp    1080 <xstrdup@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string
name: disassemble_data
arguments: tag: D1
type: string

tool: 

tool: D1: .

assistant: ```c
char *os_DirName(char const *str) {
  int len;
  char const *s;
  if (!str)
    return xstrdup("");
  len = strlen(str);
  for (s = str + len - 1; s >= str; s--) {
    if (*s == '/' || *s == '\\' || *s == ':') {
      break;
    }
  }
  if (s < str) {
    return xstrdup(".");
  }
  if (*s == ':')
    s++;
  return xmemdup(str, s - str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<os_DirName>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rsi
  cmp    %rsi,%rbp
  ja     L16
  movabs $0xffffdffffffff7fe,%rcx
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L49:
  sub    $0x1,%rsi
  cmp    %rsi,%rbp
  ja     L16
L40:
  movzbl (%rsi),%edx
  lea    -0x2f(%rdx),%eax
  cmp    $0x2d,%al
  ja     L49
  bt     %rax,%rcx
  jb     L49
  cmp    %rsi,%rbp
  ja     L16
  xor    %eax,%eax
  cmp    $0x3a,%dl
  mov    %rbp,%rdi
  sete   %al
  add    %rax,%rsi
  sub    %ebp,%esi
  pop    %rbp
  jmp    1090 <xmemdup@plt>
  nopl   0x0(%rax)
L3:
  lea    D5(%rip),%rdi
  jmp    1080 <xstrdup@plt>
  nopl   0x0(%rax)
L16:
  lea    D17(%rip),%rdi
  pop    %rbp
  jmp    1080 <xstrdup@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string

tool: 

tool: D17: .

assistant: ```c
char *os_DirName(char const *str) {
  int len;
  char const *s;
  if (!str)
    return xstrdup("");
  len = strlen(str);
  for (s = str + len - 1; s >= str; s--) {
    if (*s == '/' || *s == '\\' || *s == ':') {
      break;
    }
  }
  if (s < str) {
    return xstrdup(".");
  }
  if (*s == ':')
    s++;
  return xmemdup(str, s - str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<task_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L17:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%eax
  cmp    $0x98967f,%eax
  jle    L17
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9:   task b: %i


assistant: ```c
void task_b(void) {
  unsigned int n = 0;
  while (1) {
    printf("  task b: %i\n", n++);
    volatile int i;
    for (i = 0; i < 10000000; ++i)
      ;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<task_b>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
  jmp    L8
L18:
  add    $0x1,%ebx
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x98967f,%eax
  jg     L18
L1:
  mov    0xc(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x98967f,%eax
  jle    L1
  jmp    L18
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4:   task b: %i


assistant: ```c
void task_b(void) {
  unsigned int n = 0;
  while (1) {
    printf("  task b: %i\n", n++);
    volatile int i;
    for (i = 0; i < 10000000; ++i)
      ;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<task_b>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x98967f,%eax
  jg     L7
L5:
  mov    0xc(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x98967f,%eax
  jle    L5
L7:
  add    $0x1,%ebx
  jmp    L2
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6:   task b: %i


assistant: ```c
void task_b(void) {
  unsigned int n = 0;
  while (1) {
    printf("  task b: %i\n", n++);
    volatile int i;
    for (i = 0; i < 10000000; ++i)
      ;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<task_b>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  movl   $0x0,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x98967f,%eax
  jg     L27
L3:
  mov    0xc(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    $0x98967f,%eax
  jle    L3
L27:
  add    $0x1,%ebx
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string

tool: D6:   task b: %i


assistant: ```c
void task_b(void) {
  unsigned int n = 0;
  while (1) {
    printf("  task b: %i\n", n++);
    volatile int i;
    for (i = 0; i < 10000000; ++i)
      ;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<file_cache_abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    $0x40000000,%edi
  call   <cctools_debug@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: abort %s %s

assistant: ```c
int file_cache_abort(struct file_cache *f, const char *path, const char *txn) {
  cctools_debug((1LL << 30), "abort %s %s", path, txn);
  return unlink(txn);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_cache_abort>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  mov    $0x40000000,%edi
  call   <cctools_debug@plt>
  mov    %rbx,%rdi
  call   <unlink@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: abort %s %s

assistant: ```c
int file_cache_abort(struct file_cache *f, const char *path, const char *txn) {
  cctools_debug((1LL << 30), "abort %s %s", path, txn);
  return unlink(txn);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_cache_abort>:
  endbr64
  push   %rbp
  mov    %rdx,%rcx
  mov    %rdx,%rbp
  mov    $0x40000000,%edi
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  call   <cctools_debug@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <unlink@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: abort %s %s

assistant: ```c
int file_cache_abort(struct file_cache *f, const char *path, const char *txn) {
  cctools_debug((1LL << 30), "abort %s %s", path, txn);
  return unlink(txn);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_cache_abort>:
  endbr64
  push   %rbp
  mov    %rdx,%rcx
  mov    %rdx,%rbp
  mov    $0x40000000,%edi
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  call   <cctools_debug@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <unlink@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: abort %s %s

assistant: ```c
int file_cache_abort(struct file_cache *f, const char *path, const char *txn) {
  cctools_debug((1LL << 30), "abort %s %s", path, txn);
  return unlink(txn);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeFromEmptyList>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L11:
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L6
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  add    $0x8,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L11
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movl   $0xffffffff,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movl   $0xffffffff,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movl   $0xffffffff,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void removeFromEmptyList(int **emptiedCells, int *nEmptied, int *targetCell) {
  int j = 0;
  while (j < *nEmptied && !(emptiedCells[j][0] == targetCell[0] && emptiedCells[j][1] == targetCell[1] && emptiedCells[j][2] == targetCell[2])) {
    j++;
  }
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<removeFromEmptyList>:
  endbr64
  mov    (%rsi),%r8d
  test   %r8d,%r8d
  jle    L12
  mov    (%rdx),%r9d
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L62
L21:
  add    $0x1,%eax
  add    $0x8,%rcx
  cmp    %r8d,%eax
  je     L39
L62:
  mov    (%rcx),%rsi
  cmp    %r9d,(%rsi)
  jne    L21
  mov    0x4(%rdx),%r10d
  cmp    %r10d,0x4(%rsi)
  jne    L21
  mov    0x8(%rdx),%r11d
  cmp    %r11d,0x8(%rsi)
  jne    L21
  mov    %eax,%r8d
L39:
  movslq %r8d,%r8
  lea    (%rdi,%r8,8),%rax
  mov    (%rax),%rdx
  movl   $0xffffffff,(%rdx)
  mov    (%rax),%rdx
  movl   $0xffffffff,(%rdx)
  mov    (%rax),%rax
  movl   $0xffffffff,(%rax)
  ret
L12:
  mov    $0x0,%r8d
  jmp    L39
```

assistant: ```c
void removeFromEmptyList(int **emptiedCells, int *nEmptied, int *targetCell) {
  int j = 0;
  while (j < *nEmptied && !(emptiedCells[j][0] == targetCell[0] && emptiedCells[j][1] == targetCell[1] && emptiedCells[j][2] == targetCell[2])) {
    j++;
  }
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<removeFromEmptyList>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%rcx
  test   %eax,%eax
  jle    L28
  lea    0x1(%rax),%r8d
  mov    (%rdx),%esi
  mov    $0x1,%eax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L12:
  movslq %eax,%rcx
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L48
L26:
  mov    -0x8(%rdi,%rax,8),%rcx
  cmp    %esi,(%rcx)
  jne    L12
  mov    0x4(%rdx),%r9d
  cmp    %r9d,0x4(%rcx)
  jne    L12
  mov    0x8(%rdx),%r10d
  cmp    %r10d,0x8(%rcx)
  jne    L12
L28:
  movl   $0xffffffff,(%rcx)
  ret
L48:
  mov    (%rdi,%rcx,8),%rcx
  movl   $0xffffffff,(%rcx)
  ret
```

assistant: ```c
void removeFromEmptyList(int **emptiedCells, int *nEmptied, int *targetCell) {
  int j = 0;
  while (j < *nEmptied && !(emptiedCells[j][0] == targetCell[0] && emptiedCells[j][1] == targetCell[1] && emptiedCells[j][2] == targetCell[2])) {
    j++;
  }
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<removeFromEmptyList>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%rcx
  test   %eax,%eax
  jle    L50
  lea    0x1(%rax),%r8d
  mov    (%rdx),%esi
  mov    $0x1,%eax
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L34:
  movslq %eax,%rcx
  add    $0x1,%rax
  cmp    %rax,%r8
  je     L44
L57:
  mov    -0x8(%rdi,%rax,8),%rcx
  cmp    %esi,(%rcx)
  jne    L34
  mov    0x4(%rdx),%r9d
  cmp    %r9d,0x4(%rcx)
  jne    L34
  mov    0x8(%rdx),%r10d
  cmp    %r10d,0x8(%rcx)
  jne    L34
L50:
  movl   $0xffffffff,(%rcx)
  ret
L44:
  mov    (%rdi,%rcx,8),%rcx
  movl   $0xffffffff,(%rcx)
  ret
```

assistant: ```c
void removeFromEmptyList(int **emptiedCells, int *nEmptied, int *targetCell) {
  int j = 0;
  while (j < *nEmptied && !(emptiedCells[j][0] == targetCell[0] && emptiedCells[j][1] == targetCell[1] && emptiedCells[j][2] == targetCell[2])) {
    j++;
  }
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
  emptiedCells[j][0] = -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  andl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitRead(int x, int n) {
  int bit;
  bit = x >> n;
  bit = bit & 0x0001;
  return (bit);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitRead>:
  endbr64
  mov    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int bitRead(int x, int n) {
  int bit;
  bit = x >> n;
  bit = bit & 0x0001;
  return (bit);
}
```
user: What is the c source code of the assembly code below?

```asm
<bitRead>:
  endbr64
  mov    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int bitRead(int x, int n) {
  int bit;
  bit = x >> n;
  bit = bit & 0x0001;
  return (bit);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitRead>:
  endbr64
  mov    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int bitRead(int x, int n) {
  int bit;
  bit = x >> n;
  bit = bit & 0x0001;
  return (bit);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <assign@plt>
  mov    $0x0,%eax
  call   <call@plt>
  mov    $0x0,%eax
  call   <address@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  assign();
  call();
  address();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <assign@plt>
  mov    $0x0,%eax
  call   <call@plt>
  mov    $0x0,%eax
  call   <address@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  assign();
  call();
  address();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assign@plt>
  xor    %eax,%eax
  call   <call@plt>
  xor    %eax,%eax
  call   <address@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  assign();
  call();
  address();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <assign@plt>
  xor    %eax,%eax
  call   <call@plt>
  xor    %eax,%eax
  call   <address@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  assign();
  call();
  address();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash_djbm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x14e3,-0x10(%rbp)
  jmp    L19
L10:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  xor    %rax,-0x10(%rbp)
  mov    $0xffffffff,%eax
  and    %rax,-0x10(%rbp)
L19:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_djbm(const char *chave, int tamanho) {
  unsigned long h, i;
  i = 0;
  h = 5347;
  while (chave[i]) {
    h *= 31;
    h ^= chave[i++];
    h &= 0xffffffff;
  }
  return h % tamanho;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_djbm>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L0
  add    $0x1,%rdi
  mov    $0x14e3,%eax
L26:
  mov    %rax,%rdx
  shl    $0x5,%rdx
  sub    %rax,%rdx
  movsbq %cl,%rax
  xor    %edx,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%ecx
  test   %cl,%cl
  jne    L26
L16:
  movslq %esi,%rsi
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rax
  ret
L0:
  mov    $0x14e3,%eax
  jmp    L16
```

assistant: ```c
unsigned long hash_djbm(const char *chave, int tamanho) {
  unsigned long h, i;
  i = 0;
  h = 5347;
  while (chave[i]) {
    h *= 31;
    h ^= chave[i++];
    h &= 0xffffffff;
  }
  return h % tamanho;
}
```