ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D9(%rip),%r15
  jmp    L13
L28:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L24
L13:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L34:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L34
  jmp    L28
L24:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D9: ssumpw

tool: D3: # c::%s:len=%d


tool: D2: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumpw", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D10(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L1:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L0:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L0
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L1
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
type: string
name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D10: ssumpw

tool: D15: # c::%s:len=%d


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumpw", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D2(%rip),%r15
  push   %r14
  lea    D9(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L15:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L3:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L3
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L15
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string
name: extract_symbolic_data
arguments: data_label: D9
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D2: ssumpw

tool: D9: # c::%s:len=%d


tool: D8: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "ssumpw", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<constrain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L31
  movss  -0x8(%rbp),%xmm0
  jmp    L15
L31:
  movss  -0x4(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L2
  movss  -0xc(%rbp),%xmm0
  jmp    L15
L2:
  movss  -0x4(%rbp),%xmm0
L15:
  pop    %rbp
  ret
```

assistant: ```c
float constrain(float v, float min, float max) {
  if (v < min)
    return min;
  else if (v > max)
    return max;
  else
    return v;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<constrain>:
  endbr64
  comiss %xmm0,%xmm1
  ja     L3
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
L3:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float constrain(float v, float min, float max) {
  if (v < min)
    return min;
  else if (v > max)
    return max;
  else
    return v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<constrain>:
  endbr64
  comiss %xmm0,%xmm1
  ja     L0
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L0:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float constrain(float v, float min, float max) {
  if (v < min)
    return min;
  else if (v > max)
    return max;
  else
    return v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<constrain>:
  endbr64
  comiss %xmm0,%xmm1
  ja     L1
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L1:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float constrain(float v, float min, float max) {
  if (v < min)
    return min;
  else if (v > max)
    return max;
  else
    return v;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L61
L27:
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x38(%rbp),%eax
  cltq
  movss  -0x30(%rbp,%rax,4),%xmm1
  movss  -0x34(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L45
  mov    -0x38(%rbp),%eax
  cltq
  movss  -0x30(%rbp,%rax,4),%xmm0
  movss  %xmm0,-0x34(%rbp)
L45:
  addl   $0x1,-0x38(%rbp)
L61:
  cmpl   $0x9,-0x38(%rbp)
  jle    L27
  movl   $0x0,-0x38(%rbp)
  jmp    L55
L43:
  mov    -0x38(%rbp),%eax
  cltq
  movss  -0x30(%rbp,%rax,4),%xmm0
  ucomiss -0x34(%rbp),%xmm0
  jp     L19
  ucomiss -0x34(%rbp),%xmm0
  jne    L19
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  addl   $0x1,-0x38(%rbp)
L55:
  cmpl   $0x9,-0x38(%rbp)
  jle    L43
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
data_type: f32
name: read_data
arguments: data_tag: D32
data_type: string
name: read_data
arguments: data_tag: D16
data_type: string
name: read_data
arguments: data_tag: D29
data_type: string

tool: D19: 999

tool: D32: /n Entre com AV1 do aluno %d :

tool: D16: %f

tool: D29: 
 Hall das menores notas! Aluno %d 

assistant: ```c
int main() {
  int i;
  float av1[10];
  float menor = 999;
  for (i = 0; i <= 9; i++) {
    printf("/n Entre com AV1 do aluno %d :", i + 1);
    scanf("%f", &av1[i]);
    if (av1[i] < menor) {
      menor = av1[i];
    }
  }
  for (i = 0; i <= 9; i++) {
    if (av1[i] == menor) {
      printf("\n Hall das menores notas! Aluno %d ", i + 1);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movss  D26(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
  lea    D15(%rip),%r12
L12:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x0(%rbp),%xmm0
  minss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  add    $0x4,%rbp
  cmp    $0xa,%ebx
  jne    L12
  mov    $0x1,%ebx
  lea    D12(%rip),%rbp
  jmp    L22
L31:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L35:
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  je     L46
L22:
  movss  0xc(%rsp),%xmm1
  ucomiss 0xc(%rsp,%rbx,4),%xmm1
  jp     L35
  jne    L35
  jmp    L31
L46:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D26
type_infered: f32
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D26: 999

tool: D4: /n Entre com AV1 do aluno %d :

tool: D15: %f

tool: D12: 
 Hall das menores notas! Aluno %d 

assistant: ```c
int main() {
  int i;
  float av1[10];
  float menor = 999;
  for (i = 0; i <= 9; i++) {
    printf("/n Entre com AV1 do aluno %d :", i + 1);
    scanf("%f", &av1[i]);
    if (av1[i] < menor) {
      menor = av1[i];
    }
  }
  for (i = 0; i <= 9; i++) {
    if (av1[i] == menor) {
      printf("\n Hall das menores notas! Aluno %d ", i + 1);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x40,%rsp
  movss  D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  mov    %r12,%rbp
L54:
  add    $0x1,%ebx
  mov    %r14,%rdi
  movss  %xmm0,0xc(%rsp)
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  -0x4(%rbp),%xmm1
  minss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    $0xa,%ebx
  jne    L54
  mov    $0x1,%ebx
  lea    D1(%rip),%rbp
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%rbx
  cmp    $0xb,%rbx
  je     L41
L4:
  ucomiss -0x4(%r12,%rbx,4),%xmm0
  mov    %ebx,%esi
  jp     L14
  jne    L14
  mov    %rbp,%rdi
  add    $0x1,%rbx
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  cmp    $0xb,%rbx
  jne    L4
L41:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D22
datatype: f32
name: unpack_data
arguments: label: D1
datatype: string

tool: D20: /n Entre com AV1 do aluno %d :

tool: D14: %f

tool: D22: 999

tool: D1: 
 Hall das menores notas! Aluno %d 

assistant: ```c
int main() {
  int i;
  float av1[10];
  float menor = 999;
  for (i = 0; i <= 9; i++) {
    printf("/n Entre com AV1 do aluno %d :", i + 1);
    scanf("%f", &av1[i]);
    if (av1[i] < menor) {
      menor = av1[i];
    }
  }
  for (i = 0; i <= 9; i++) {
    if (av1[i] == menor) {
      printf("\n Hall das menores notas! Aluno %d ", i + 1);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<double64_le_write>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  movq   %rbp,%xmm2
  ucomisd D10(%rip),%xmm2
  jp     L42
  je     L43
L42:
  pxor   %xmm0,%xmm0
  movq   %rbp,%xmm4
  comisd %xmm4,%xmm0
  ja     L48
L2:
  lea    0x4(%rsp),%rdi
  movq   %rbp,%xmm0
  call   <frexp@plt>
  mov    0x4(%rsp),%eax
  add    $0x3fe,%eax
  mov    %eax,%edx
  sar    $0x4,%edx
  and    $0x7f,%edx
  or     %dl,0x7(%rbx)
  shl    $0x4,%eax
  or     %al,0x6(%rbx)
  mulsd  D29(%rip),%xmm0
  movq   %xmm0,%rbp
  call   <floor@plt>
  mov    %eax,%edi
  call   <lrint@plt>
  mov    %eax,%edx
  sar    $0x18,%edx
  and    $0xf,%edx
  or     %dl,0x6(%rbx)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rbx)
  movzbl %ah,%ecx
  mov    %cl,0x4(%rbx)
  mov    %al,0x3(%rbx)
  movsd  D0(%rip),%xmm1
  movq   %rbp,%xmm0
  call   <fmod@plt>
  mulsd  D14(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,%edi
  call   <lrint@plt>
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x2(%rbx)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rbx)
  mov    %al,(%rbx)
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  movq   %rbp,%xmm5
  xorpd  D27(%rip),%xmm5
  movq   %xmm5,%rbp
  orb    $0x80,0x7(%rbx)
  jmp    L2
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D29
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D0
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D14
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D27
type_infered: byte[16]

tool: D10: 0

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0xc0,0x41]}

tool: D0: 1

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x70,0x41]}

tool: {"D27": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void double64_le_write(double in, unsigned char *out) {
  int exponent, mantissa;
  memset(out, 0, sizeof(double));
  if (in == 0.0)
    return;
  if (in < 0.0) {
    in *= -1.0;
    out[7] |= 0x80;
  };
  in = frexp(in, &exponent);
  exponent += 1022;
  out[7] |= (exponent >> 4) & 0x7F;
  out[6] |= (exponent << 4) & 0xF0;
  in *= 0x20000000;
  mantissa = lrint(floor(in));
  out[6] |= (mantissa >> 24) & 0xF;
  out[5] = (mantissa >> 16) & 0xFF;
  out[4] = (mantissa >> 8) & 0xFF;
  out[3] = mantissa & 0xFF;
  in = fmod(in, 1.0);
  in *= 0x1000000;
  mantissa = lrint(floor(in));
  out[2] = (mantissa >> 16) & 0xFF;
  out[1] = (mantissa >> 8) & 0xFF;
  out[0] = mantissa & 0xFF;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<double64_le_write>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L43
  je     L45
L43:
  comisd %xmm0,%xmm1
  ja     L17
L19:
  lea    0x14(%rsp),%rdi
  call   <frexp@plt>
  mov    0x14(%rsp),%eax
  mulsd  D2(%rip),%xmm0
  add    $0x3fe,%eax
  mov    %eax,%edx
  shl    $0x4,%eax
  or     %al,0x6(%rbx)
  sar    $0x4,%edx
  and    $0x7f,%edx
  or     %dl,0x7(%rbx)
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  mov    %eax,%edi
  call   <lrint@plt>
  movsd  D7(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%edx
  mov    %ax,0x3(%rbx)
  sar    $0x18,%edx
  and    $0xf,%edx
  or     %dl,0x6(%rbx)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rbx)
  call   <fmod@plt>
  mulsd  D5(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,%edi
  call   <lrint@plt>
  mov    %eax,%edx
  mov    %ax,(%rbx)
  sar    $0x10,%edx
  mov    %dl,0x2(%rbx)
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  orb    $0x80,0x7(%rbx)
  xorpd  D34(%rip),%xmm0
  jmp    L19
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: f32[2]
name: read_data
arguments: data_tag: D7
datatype: f64
name: read_data
arguments: data_tag: D5
datatype: f32[2]
name: read_data
arguments: data_tag: D34
datatype: f32[4]

tool: {"D2": [0.0,24.0]}

tool: D7: 1

tool: {"D5": [0.0,15.0]}

tool: {"D34": [0.0,-0.0,0.0,0.0]}

assistant: ```c
void double64_le_write(double in, unsigned char *out) {
  int exponent, mantissa;
  memset(out, 0, sizeof(double));
  if (in == 0.0)
    return;
  if (in < 0.0) {
    in *= -1.0;
    out[7] |= 0x80;
  };
  in = frexp(in, &exponent);
  exponent += 1022;
  out[7] |= (exponent >> 4) & 0x7F;
  out[6] |= (exponent << 4) & 0xF0;
  in *= 0x20000000;
  mantissa = lrint(floor(in));
  out[6] |= (mantissa >> 24) & 0xF;
  out[5] = (mantissa >> 16) & 0xFF;
  out[4] = (mantissa >> 8) & 0xFF;
  out[3] = mantissa & 0xFF;
  in = fmod(in, 1.0);
  in *= 0x1000000;
  mantissa = lrint(floor(in));
  out[2] = (mantissa >> 16) & 0xFF;
  out[1] = (mantissa >> 8) & 0xFF;
  out[0] = mantissa & 0xFF;
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<double64_le_write>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    $0x8,%edx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memset@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L25
  je     L40
L25:
  comisd %xmm0,%xmm1
  ja     L34
L8:
  lea    0x14(%rsp),%rdi
  call   <frexp@plt>
  mov    0x14(%rsp),%eax
  mulsd  D13(%rip),%xmm0
  add    $0x3fe,%eax
  mov    %eax,%edx
  shl    $0x4,%eax
  or     %al,0x6(%rbx)
  sar    $0x4,%edx
  and    $0x7f,%edx
  or     %dl,0x7(%rbx)
  movsd  %xmm0,0x8(%rsp)
  call   <floor@plt>
  mov    %eax,%edi
  call   <lrint@plt>
  movsd  D26(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%edx
  mov    %ax,0x3(%rbx)
  sar    $0x18,%edx
  and    $0xf,%edx
  or     %dl,0x6(%rbx)
  mov    %eax,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rbx)
  call   <fmod@plt>
  mulsd  D2(%rip),%xmm0
  call   <floor@plt>
  mov    %eax,%edi
  call   <lrint@plt>
  mov    %eax,%edx
  mov    %ax,(%rbx)
  sar    $0x10,%edx
  mov    %dl,0x2(%rbx)
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  orb    $0x80,0x7(%rbx)
  xorpd  D0(%rip),%xmm0
  jmp    L8
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: f32[2]
name: unpack_data
arguments: tag: D26
type_guessed: f64
name: unpack_data
arguments: tag: D2
type_guessed: f32[2]
name: unpack_data
arguments: tag: D0
type_guessed: f32[4]

tool: {"D13": [0.0,24.0]}

tool: D26: 1

tool: {"D2": [0.0,15.0]}

tool: {"D0": [0.0,-0.0,0.0,0.0]}

assistant: ```c
void double64_le_write(double in, unsigned char *out) {
  int exponent, mantissa;
  memset(out, 0, sizeof(double));
  if (in == 0.0)
    return;
  if (in < 0.0) {
    in *= -1.0;
    out[7] |= 0x80;
  };
  in = frexp(in, &exponent);
  exponent += 1022;
  out[7] |= (exponent >> 4) & 0x7F;
  out[6] |= (exponent << 4) & 0xF0;
  in *= 0x20000000;
  mantissa = lrint(floor(in));
  out[6] |= (mantissa >> 24) & 0xF;
  out[5] = (mantissa >> 16) & 0xFF;
  out[4] = (mantissa >> 8) & 0xFF;
  out[3] = mantissa & 0xFF;
  in = fmod(in, 1.0);
  in *= 0x1000000;
  mantissa = lrint(floor(in));
  out[2] = (mantissa >> 16) & 0xFF;
  out[1] = (mantissa >> 8) & 0xFF;
  out[0] = mantissa & 0xFF;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xe0(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <getline@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcaat@plt>
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D15
type_guessed: string

tool: D25: Enter first string

tool: D13: Enter second string

tool: D15: %s

assistant: ```c
int main() {
  char a[100];
  char b[100];
  printf("Enter first string\n");
  getline(a, 100);
  printf("Enter second string\n");
  getline(b, 100);
  strcaat(a, b);
  printf("%s", a);
  getchar();
  return 0;
}
```