ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<dump_out_shammx>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  je     L19
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %edx,%r14d
  and    $0x3,%r14d
  mov    %edx,%eax
  shr    $0x2,%eax
  and    $0xfffffffc,%edx
  lea    (%rdx,%rax,1),%ebp
  shl    $0x2,%ebp
  lea    (%r14,%rbp,1),%eax
  lea    0x3(,%rax,4),%eax
  movzbl (%rdi,%rax,1),%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D9(%rip),%r15
  jmp    L36
L28:
  mov    $0x20,%edi
  call   <putchar@plt>
L36:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L19
  mov    %ebx,%eax
  and    $0xfffffffc,%eax
  or     %r14d,%eax
  add    %ebp,%eax
  mov    %ebx,%edx
  not    %edx
  and    $0x3,%edx
  lea    (%rdx,%rax,4),%eax
  movzbl 0x0(%r13,%rax,1),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L36
  jmp    L28
L19:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_guessed: string

tool: D9: %.2x

assistant: ```c
void dump_out_shammx(void *buf, unsigned int size, unsigned int index) {
  unsigned int i;
  for (i = 0; i < size; i++) {
    printf("%.2x", ((unsigned char *)buf)[((index & (4 - 1)) * 4 + ((i) & (0xffffffff - 3)) * 4 + (3 - ((i)&3)) + (unsigned int)index / 4 * 20 * 4)]);
    if ((i % 4) == 3)
      printf(" ");
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_out_shammx>:
  endbr64
  test   %esi,%esi
  je     L37
  mov    %edx,%eax
  push   %r15
  mov    %edx,%r15d
  and    $0xfffffffc,%edx
  shr    $0x2,%eax
  push   %r14
  and    $0x3,%r15d
  lea    D3(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    (%rdx,%rax,1),%ebp
  push   %rbx
  shl    $0x2,%ebp
  xor    %ebx,%ebx
  lea    (%r15,%rbp,1),%eax
  lea    0x3(,%rax,4),%eax
  sub    $0x8,%rsp
  movzbl (%rdi,%rax,1),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L38:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L29
L0:
  mov    %ebx,%eax
  mov    %ebx,%edx
  mov    %r14,%rdi
  and    $0xfffffffc,%eax
  not    %edx
  or     %r15d,%eax
  and    $0x3,%edx
  add    %ebp,%eax
  lea    (%rdx,%rax,4),%eax
  movzbl 0x0(%r13,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L38
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L0
L29:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
L37:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: %.2x

assistant: ```c
void dump_out_shammx(void *buf, unsigned int size, unsigned int index) {
  unsigned int i;
  for (i = 0; i < size; i++) {
    printf("%.2x", ((unsigned char *)buf)[((index & (4 - 1)) * 4 + ((i) & (0xffffffff - 3)) * 4 + (3 - ((i)&3)) + (unsigned int)index / 4 * 20 * 4)]);
    if ((i % 4) == 3)
      printf(" ");
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dump_out_shammx>:
  endbr64
  test   %esi,%esi
  je     L6
  mov    %edx,%eax
  push   %r15
  mov    %edx,%r15d
  and    $0xfffffffc,%edx
  shr    $0x2,%eax
  push   %r14
  and    $0x3,%r15d
  lea    D9(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  lea    (%rdx,%rax,1),%ebp
  push   %rbx
  shl    $0x2,%ebp
  mov    $0x1,%ebx
  lea    (%r15,%rbp,1),%eax
  lea    0x3(,%rax,4),%eax
  sub    $0x8,%rsp
  movzbl (%rdi,%rax,1),%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x1,%r12d
  jne    L3
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L0
L3:
  mov    %ebx,%eax
  mov    %ebx,%edx
  mov    %r14,%rdi
  and    $0xfffffffc,%eax
  not    %edx
  or     %r15d,%eax
  and    $0x3,%edx
  add    %ebp,%eax
  lea    (%rdx,%rax,4),%eax
  movzbl 0x0(%r13,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  and    $0x3,%eax
  cmp    $0x3,%eax
  jne    L25
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%r12d
  jne    L3
L0:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: %.2x

assistant: ```c
void dump_out_shammx(void *buf, unsigned int size, unsigned int index) {
  unsigned int i;
  for (i = 0; i < size; i++) {
    printf("%.2x", ((unsigned char *)buf)[((index & (4 - 1)) * 4 + ((i) & (0xffffffff - 3)) * 4 + (3 - ((i)&3)) + (unsigned int)index / 4 * 20 * 4)]);
    if ((i % 4) == 3)
      printf(" ");
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L19
L10:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm1
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  addss  %xmm0,%xmm1
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  add    %rdx,%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  movss  D2(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  mulss  -0x20(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L10
  movss  -0xc(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: f32

tool: D2: 4

assistant: ```c
float add(float *array, int size, float delta) {
  int i = 0, counter = 1;
  float sum = 0;
  while (i < size * (size - 1)) {
    float average = ((*(array + i)) + (*(array + i + 1)) + (*(array + i + size)) + (*(array + i + size + 1))) / 4;
    sum += average * delta;
    i++;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<add>:
  endbr64
  movaps %xmm0,%xmm2
  lea    -0x1(%rsi),%edx
  imul   %esi,%edx
  test   %edx,%edx
  jle    L19
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
  movslq %esi,%rsi
  movss  D3(%rip),%xmm3
L18:
  movss  (%rax),%xmm1
  addss  0x4(%rax),%xmm1
  addss  (%rax,%rsi,4),%xmm1
  addss  0x4(%rax,%rsi,4),%xmm1
  mulss  %xmm3,%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L18
  ret
L19:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3e]}

assistant: ```c
float add(float *array, int size, float delta) {
  int i = 0, counter = 1;
  float sum = 0;
  while (i < size * (size - 1)) {
    float average = ((*(array + i)) + (*(array + i + 1)) + (*(array + i + size)) + (*(array + i + size + 1))) / 4;
    sum += average * delta;
    i++;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<add>:
  endbr64
  lea    -0x1(%rsi),%eax
  movaps %xmm0,%xmm2
  imul   %esi,%eax
  test   %eax,%eax
  jle    L11
  sub    $0x1,%eax
  movss  D7(%rip),%xmm3
  movslq %esi,%rsi
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax,%rax,1)
L19:
  movss  (%rdi),%xmm1
  addss  0x4(%rdi),%xmm1
  addss  (%rdi,%rsi,4),%xmm1
  addss  0x4(%rdi,%rsi,4),%xmm1
  add    $0x4,%rdi
  mulss  %xmm3,%xmm1
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L19
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: byte[4]

tool: {"D7": [0x00,0x00,0x80,0x3e]}

assistant: ```c
float add(float *array, int size, float delta) {
  int i = 0, counter = 1;
  float sum = 0;
  while (i < size * (size - 1)) {
    float average = ((*(array + i)) + (*(array + i + 1)) + (*(array + i + size)) + (*(array + i + size + 1))) / 4;
    sum += average * delta;
    i++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add>:
  endbr64
  movslq %esi,%rcx
  mov    %rdi,%rax
  movaps %xmm0,%xmm2
  lea    -0x1(%rcx),%edi
  imul   %ecx,%edi
  test   %edi,%edi
  jle    L26
  lea    -0x1(%rdi),%edx
  cmp    $0x2,%edx
  jbe    L56
  mov    %edi,%esi
  movaps D2(%rip),%xmm4
  movaps %xmm0,%xmm5
  pxor   %xmm3,%xmm3
  lea    0x0(,%rcx,4),%rdx
  shr    $0x2,%esi
  shufps $0x0,%xmm5,%xmm5
  lea    (%rax,%rdx,1),%r9
  lea    0x4(%rax,%rdx,1),%r8
  shl    $0x4,%rsi
  xor    %edx,%edx
  nopl   (%rax)
L59:
  movups (%rax,%rdx,1),%xmm6
  movups 0x4(%rax,%rdx,1),%xmm0
  movups (%r9,%rdx,1),%xmm7
  addps  %xmm6,%xmm0
  movups (%r8,%rdx,1),%xmm6
  add    $0x10,%rdx
  addps  %xmm7,%xmm0
  addps  %xmm6,%xmm0
  mulps  %xmm4,%xmm0
  mulps  %xmm5,%xmm0
  movaps %xmm0,%xmm1
  addss  %xmm3,%xmm1
  movaps %xmm0,%xmm3
  shufps $0x55,%xmm0,%xmm3
  addss  %xmm3,%xmm1
  movaps %xmm0,%xmm3
  unpckhps %xmm0,%xmm3
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm3,%xmm1
  addss  %xmm0,%xmm1
  movaps %xmm1,%xmm3
  cmp    %rsi,%rdx
  jne    L59
  mov    %edi,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%edx
  cmp    %edi,%esi
  je     L17
L68:
  sub    %esi,%edi
  cmp    $0x1,%edi
  je     L27
  movq   (%rax,%rsi,4),%xmm1
  movq   0x4(%rax,%rsi,4),%xmm0
  lea    (%rcx,%rsi,1),%r8
  mov    %edi,%esi
  and    $0xfffffffe,%esi
  addps  %xmm1,%xmm0
  movq   (%rax,%r8,4),%xmm1
  add    %esi,%edx
  addps  %xmm1,%xmm0
  movq   0x4(%rax,%r8,4),%xmm1
  addps  %xmm1,%xmm0
  movq   D2(%rip),%xmm1
  mulps  %xmm1,%xmm0
  movaps %xmm2,%xmm1
  shufps $0xe0,%xmm1,%xmm1
  mulps  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  shufps $0xe5,%xmm0,%xmm0
  addss  %xmm3,%xmm1
  movaps %xmm0,%xmm3
  addss  %xmm1,%xmm3
  cmp    %esi,%edi
  je     L17
L27:
  movslq %edx,%rdx
  add    %rdx,%rcx
  movss  0x4(%rax,%rdx,4),%xmm0
  addss  (%rax,%rdx,4),%xmm0
  addss  (%rax,%rcx,4),%xmm0
  addss  0x4(%rax,%rcx,4),%xmm0
  mulss  D2(%rip),%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm0,%xmm3
L17:
  movaps %xmm3,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  pxor   %xmm3,%xmm3
  movaps %xmm3,%xmm0
  ret
L56:
  xor    %esi,%esi
  pxor   %xmm3,%xmm3
  xor    %edx,%edx
  jmp    L68
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: byte[16]

tool: {"D2": [0x00,0x00,0x80,0x3e,0x00,0x00,0x80,0x3e,0x00,0x00,0x80,0x3e,0x00,0x00,0x80,0x3e]}

assistant: ```c
float add(float *array, int size, float delta) {
  int i = 0, counter = 1;
  float sum = 0;
  while (i < size * (size - 1)) {
    float average = ((*(array + i)) + (*(array + i + 1)) + (*(array + i + size)) + (*(array + i + size + 1))) / 4;
    sum += average * delta;
    i++;
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_isascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L19
  cmpl   $0x7f,-0x4(%rbp)
  jg     L19
  mov    $0x1,%eax
  jmp    L21
L19:
  mov    $0x0,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c > -1 && c <= 127)
    return (1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_isascii>:
  endbr64
  cmp    $0x7f,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c > -1 && c <= 127)
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_isascii>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7f,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c > -1 && c <= 127)
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_isascii>:
  endbr64
  xor    %eax,%eax
  cmp    $0x7f,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isascii(int c) {
  if (c > -1 && c <= 127)
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x20(%rbp)
  movl   $0x7,-0x1c(%rbp)
  movl   $0x11,-0x18(%rbp)
  movl   $0x20,-0x14(%rbp)
  movl   $0x3e8,-0x10(%rbp)
  movl   $0x1388,-0xc(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L9
L4:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <powers_of_2@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x24(%rbp)
L9:
  cmpl   $0x5,-0x24(%rbp)
  jle    L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type: string

tool: D7: All powers of 2 up to %d:

assistant: ```c
int main() {
  int set[6] = {4, 7, 17, 32, 1000, 5000};
  for (int c = 0; c < 6; c++) {
    printf("All powers of 2 up to %d:", set[c]);
    powers_of_2(set[c]);
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x7,0x4(%rsp)
  movl   $0x11,0x8(%rsp)
  movl   $0x20,0xc(%rsp)
  movl   $0x3e8,0x10(%rsp)
  movl   $0x1388,0x14(%rsp)
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r13
  lea    D3(%rip),%r12
L18:
  mov    (%rbx),%ebp
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <powers_of_2@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L18
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: All powers of 2 up to %d:

assistant: ```c
int main() {
  int set[6] = {4, 7, 17, 32, 1000, 5000};
  for (int c = 0; c < 6; c++) {
    printf("All powers of 2 up to %d:", set[c]);
    powers_of_2(set[c]);
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    $0x4,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r13
  movabs $0x2000000011,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x1388000003e8,%rax
  movl   $0x7,0x4(%rsp)
  mov    %rax,0x10(%rsp)
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%ebp
L20:
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  mov    %ebp,%edi
  call   <powers_of_2@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: All powers of 2 up to %d:

assistant: ```c
int main() {
  int set[6] = {4, 7, 17, 32, 1000, 5000};
  for (int c = 0; c < 6; c++) {
    printf("All powers of 2 up to %d:", set[c]);
    powers_of_2(set[c]);
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movdqa D16(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    %rsp,%rbx
  lea    0x18(%rsp),%r13
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  nopl   (%rax)
L3:
  mov    (%rbx),%ebp
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  mov    %ebp,%esi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <powers_of_2@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %rbx,%r13
  jne    L3
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type_infered: string
name: extract_symbolic_data
arguments: tag: D16
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D26
type_infered: byte[8]

tool: D21: All powers of 2 up to %d:

tool: {"D16": [0x04,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x20,0x00,0x00,0x00]}

tool: {"D26": [0xe8,0x03,0x00,0x00,0x88,0x13,0x00,0x00]}

assistant: ```c
int main() {
  int set[6] = {4, 7, 17, 32, 1000, 5000};
  for (int c = 0; c < 6; c++) {
    printf("All powers of 2 up to %d:", set[c]);
    powers_of_2(set[c]);
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmp_integers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int cmp_integers(const void *e1, const void *e2) {
  int *n1, *n2;
  n1 = (int *)e1;
  n2 = (int *)e2;
  return *n1 - *n2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmp_integers>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int cmp_integers(const void *e1, const void *e2) {
  int *n1, *n2;
  n1 = (int *)e1;
  n2 = (int *)e2;
  return *n1 - *n2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_integers>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int cmp_integers(const void *e1, const void *e2) {
  int *n1, *n2;
  n1 = (int *)e1;
  n2 = (int *)e2;
  return *n1 - *n2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmp_integers>:
  endbr64
  mov    (%rdi),%eax
  sub    (%rsi),%eax
  ret
```

assistant: ```c
int cmp_integers(const void *e1, const void *e2) {
  int *n1, *n2;
  n1 = (int *)e1;
  n2 = (int *)e2;
  return *n1 - *n2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<copy_bitmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <allocate_bitmap@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assign_bitmap@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned char **copy_bitmap(unsigned char **src, int w, int h) {
  unsigned char **result = allocate_bitmap(w, h);
  assign_bitmap(result, src, w, h);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_bitmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %edx,%esi
  mov    %ebp,%edi
  call   <allocate_bitmap@plt>
  mov    %rax,%rbx
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <assign_bitmap@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char **copy_bitmap(unsigned char **src, int w, int h) {
  unsigned char **result = allocate_bitmap(w, h);
  assign_bitmap(result, src, w, h);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy_bitmap>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  mov    %edx,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <allocate_bitmap@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <assign_bitmap@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char **copy_bitmap(unsigned char **src, int w, int h) {
  unsigned char **result = allocate_bitmap(w, h);
  assign_bitmap(result, src, w, h);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_bitmap>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  mov    %edx,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  sub    $0x8,%rsp
  call   <allocate_bitmap@plt>
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <assign_bitmap@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
unsigned char **copy_bitmap(unsigned char **src, int w, int h) {
  unsigned char **result = allocate_bitmap(w, h);
  assign_bitmap(result, src, w, h);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<duplicate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L0
L7:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
char *duplicate(const char *s) {
  char *t = malloc((strlen(s) + 1) * sizeof(char));
  if (!t)
    return NULL;
  strcpy(t, s);
  return t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<duplicate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *duplicate(const char *s) {
  char *t = malloc((strlen(s) + 1) * sizeof(char));
  if (!t)
    return NULL;
  strcpy(t, s);
  return t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<duplicate>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *duplicate(const char *s) {
  char *t = malloc((strlen(s) + 1) * sizeof(char));
  if (!t)
    return NULL;
  strcpy(t, s);
  return t;
}
```