ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dirname>:
  endbr64
  lea    D21(%rip),%rax
  test   %rdi,%rdi
  je     L105
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L198
  cmp    %rax,%rbx
  je     L198
  cmpb   $0x0,0x1(%rax)
  jne    L160
  mov    %rax,%rdx
L146:
  cmpb   $0x2f,-0x1(%rdx)
  jne    L56
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L146
  jmp    L160
L56:
  cmp    %rdx,%rbx
  je     L160
L77:
  cmpb   $0x2f,(%rdx)
  je     L156
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L77
  cmpb   $0x2f,(%rdx)
  je     L191
  lea    D21(%rip),%rax
  jmp    L70
L191:
  mov    %rdx,%rax
  jmp    L91
L198:
  test   %rax,%rax
  je     L141
L160:
  cmp    %rax,%rbx
  je     L91
  mov    %rax,%rdx
L22:
  cmpb   $0x2f,-0x1(%rdx)
  jne    L202
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L22
L91:
  lea    0x1(%rbx),%rdx
  lea    0x1(%rax),%rcx
  cmp    %rax,%rdx
  mov    %rdx,%rax
  cmove  %rcx,%rax
  jmp    L27
L202:
  cmp    %rdx,%rbx
  je     L91
L27:
  movb   $0x0,(%rax)
  mov    %rbx,%rax
L70:
  pop    %rbx
  ret
L141:
  lea    D21(%rip),%rax
  jmp    L70
L156:
  mov    %rdx,%rax
  jmp    L160
L105:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
type_guessed: string

tool: D21: .

assistant: ```c
char *dirname(char *path) {
  static const char dot[] = ".";
  char *last_slash;
  last_slash = path != NULL ? strrchr(path, '/') : NULL;
  if (last_slash != NULL && last_slash != path && last_slash[1] == '\0') {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp != path) {
      for (last_slash = runp; (last_slash != path); last_slash--) {
        if (*last_slash == '/')
          break;
      }
      if (*last_slash != '/')
        last_slash = NULL;
    }
  }
  if (last_slash != NULL) {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp == path) {
      if (last_slash == path + 1)
        ++last_slash;
      else
        last_slash = path + 1;
    }
    last_slash[0] = '\0';
  } else
    path = (char *)dot;
  return path;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dirname>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L165
  cmp    %rax,%rbx
  je     L97
  cmpb   $0x0,0x1(%rax)
  je     L30
L58:
  mov    %rax,%rdx
  jmp    L153
  nopl   0x0(%rax)
L174:
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L44
L153:
  cmpb   $0x2f,-0x1(%rdx)
  je     L174
  movb   $0x0,(%rax)
  mov    %rbx,%rax
L3:
  pop    %rbx
  ret
  nop
L30:
  mov    %rax,%rdx
  jmp    L167
  nopl   (%rax)
L66:
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L42
L167:
  cmpb   $0x2f,-0x1(%rdx)
  je     L66
  nopw   0x0(%rax,%rax,1)
L163:
  cmpb   $0x2f,(%rdx)
  je     L22
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L163
  cmpb   $0x2f,(%rbx)
  je     L82
L165:
  lea    D2(%rip),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L2:
  lea    D2(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rdx,%rax
L42:
  cmp    %rax,%rbx
  jne    L58
  nopl   0x0(%rax,%rax,1)
L44:
  lea    0x1(%rbx),%rdx
  lea    0x2(%rbx),%rcx
  cmp    %rax,%rdx
  mov    %rdx,%rax
  cmove  %rcx,%rax
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L97:
  test   %rax,%rax
  jne    L44
  jmp    L165
L82:
  mov    %rbx,%rax
  jmp    L44
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: .

assistant: ```c
char *dirname(char *path) {
  static const char dot[] = ".";
  char *last_slash;
  last_slash = path != NULL ? strrchr(path, '/') : NULL;
  if (last_slash != NULL && last_slash != path && last_slash[1] == '\0') {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp != path) {
      for (last_slash = runp; (last_slash != path); last_slash--) {
        if (*last_slash == '/')
          break;
      }
      if (*last_slash != '/')
        last_slash = NULL;
    }
  }
  if (last_slash != NULL) {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp == path) {
      if (last_slash == path + 1)
        ++last_slash;
      else
        last_slash = path + 1;
    }
    last_slash[0] = '\0';
  } else
    path = (char *)dot;
  return path;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dirname>:
  endbr64
  test   %rdi,%rdi
  je     L72
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  test   %rax,%rax
  je     L43
  cmp    %rax,%rbx
  je     L71
  cmpb   $0x0,0x1(%rax)
  je     L26
L175:
  mov    %rax,%rdx
  jmp    L45
  nopl   0x0(%rax)
L125:
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L94
L45:
  cmpb   $0x2f,-0x1(%rdx)
  je     L125
  movb   $0x0,(%rax)
  mov    %rbx,%rax
L134:
  pop    %rbx
  ret
  nop
L26:
  mov    %rax,%rdx
  jmp    L96
  nopl   (%rax)
L89:
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  je     L100
L96:
  cmpb   $0x2f,-0x1(%rdx)
  je     L89
  nopw   0x0(%rax,%rax,1)
L35:
  cmpb   $0x2f,(%rdx)
  je     L22
  sub    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L35
  cmpb   $0x2f,(%rbx)
  je     L54
L43:
  lea    D2(%rip),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L72:
  lea    D2(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %rdx,%rax
L100:
  cmp    %rax,%rbx
  jne    L175
  nopl   0x0(%rax,%rax,1)
L94:
  lea    0x1(%rbx),%rdx
  lea    0x2(%rbx),%rcx
  cmp    %rax,%rdx
  mov    %rdx,%rax
  cmove  %rcx,%rax
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L71:
  test   %rax,%rax
  jne    L94
  jmp    L43
L54:
  mov    %rbx,%rax
  jmp    L94
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: .

assistant: ```c
char *dirname(char *path) {
  static const char dot[] = ".";
  char *last_slash;
  last_slash = path != NULL ? strrchr(path, '/') : NULL;
  if (last_slash != NULL && last_slash != path && last_slash[1] == '\0') {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp != path) {
      for (last_slash = runp; (last_slash != path); last_slash--) {
        if (*last_slash == '/')
          break;
      }
      if (*last_slash != '/')
        last_slash = NULL;
    }
  }
  if (last_slash != NULL) {
    char *runp;
    for (runp = last_slash; runp != path; --runp)
      if (runp[-1] != '/')
        break;
    if (runp == path) {
      if (last_slash == path + 1)
        ++last_slash;
      else
        last_slash = path + 1;
    }
    last_slash[0] = '\0';
  } else
    path = (char *)dot;
  return path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L51
L30:
  addq   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L30
  jmp    L22
L25:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L48
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L25
L48:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *find_argument(char *line) {
  while (*line != '\0' && !isspace(*line))
    line++;
  while (*line != '\0' && isspace(*line))
    line++;
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_argument>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L69
L0:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L50
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L0
L69:
  mov    %rbx,%rax
  jmp    L55
L50:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L28
L23:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L41
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L23
  mov    %rbx,%rax
  jmp    L55
L28:
  mov    %rbx,%rax
  jmp    L55
L41:
  mov    %rbx,%rax
L55:
  pop    %rbx
  ret
```

assistant: ```c
char *find_argument(char *line) {
  while (*line != '\0' && !isspace(*line))
    line++;
  while (*line != '\0' && isspace(*line))
    line++;
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_argument>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L62
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L54:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L53
L62:
  call   <isspace@plt>
  test   %rax,%rax
  je     L54
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x1,%r12
L59:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L53
  call   <isspace@plt>
  test   %rax,%rax
  jne    L21
L53:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *find_argument(char *line) {
  while (*line != '\0' && !isspace(*line))
    line++;
  while (*line != '\0' && isspace(*line))
    line++;
  return line;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_argument>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L48
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L66:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L54
L48:
  call   <isspace@plt>
  test   %rax,%rax
  je     L66
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L69:
  add    $0x1,%r12
L19:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L54
  call   <isspace@plt>
  test   %rax,%rax
  jne    L69
L54:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *find_argument(char *line) {
  while (*line != '\0' && !isspace(*line))
    line++;
  while (*line != '\0' && isspace(*line))
    line++;
  return line;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_app_tick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D11(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D20(%rip)
  mov    D20(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
u_int64_t get_app_tick() {
  static u_int64_t tick = 0;
  return ++tick;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_app_tick>:
  endbr64
  mov    D15(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D2(%rip)
  ret
```

assistant: ```c
u_int64_t get_app_tick() {
  static u_int64_t tick = 0;
  return ++tick;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_app_tick>:
  endbr64
  mov    D10(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D19(%rip)
  ret
```

assistant: ```c
u_int64_t get_app_tick() {
  static u_int64_t tick = 0;
  return ++tick;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_app_tick>:
  endbr64
  mov    D10(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D7(%rip)
  ret
```

assistant: ```c
u_int64_t get_app_tick() {
  static u_int64_t tick = 0;
  return ++tick;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x5,%eax
  ja     L57
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D41(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D41(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <min@plt>
  mov    %eax,%esi
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
  mov    $0x0,%eax
  call   <max@plt>
  mov    %eax,%esi
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
  mov    $0x0,%eax
  call   <logg@plt>
  mov    %eax,%esi
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
  mov    $0x0,%eax
  call   <kup@plt>
  mov    %eax,%esi
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
  mov    $0x0,%eax
  call   <mutlak@plt>
  mov    %eax,%esi
  lea    D93(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L57:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D90
type: string
name: retrieve_data
arguments: data_label: D93
type: string
name: retrieve_data
arguments: data_label: D15
type: string

tool: D18: Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.
1. Iki sayinin minimumunu bulma.
2. Iki sayinin maximumunu bulma.
3. Logaritma.
4. Bir sayinin kupunu alma.
5. Bir sayinin mutlak degerini alma.
Cikmak icin 1-5 disinda bir deger giriniz.

tool: D90: %d

tool: D93: %lf


tool: D15: Cikis yapiliyor.

assistant: ```c
int main() {
  int n;
  printf("Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.\n1. Iki sayinin minimumunu bulma.\n2. Iki sayinin maximumunu bulma.\n3. Logaritma.\n4. Bir sayinin kupunu alma.\n5. Bir sayinin mutlak degerini alma.\nCikmak icin 1-5 disinda bir deger giriniz.\n");
  scanf("%d", &n);
  switch (n) {
  case 1:
    printf("%lf\n", min());
    break;
  case 2:
    printf("%lf\n", max());
    break;
  case 3:
    printf("%lf\n", logg());
    break;
  case 4:
    printf("%lf\n", kup());
    break;
  case 5:
    printf("%lf\n", mutlak());
    break;
  default:
    printf("Cikis yapiliyor.\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D41(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L61
  mov    0x4(%rsp),%eax
  lea    D0(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <min@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
  mov    $0x0,%eax
  call   <max@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L65
  mov    $0x0,%eax
  call   <logg@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L65
  mov    $0x0,%eax
  call   <kup@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L65
  mov    $0x0,%eax
  call   <mutlak@plt>
  mov    %eax,%esi
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L65
L61:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L65
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string
name: unpack_data
arguments: data_label: D41
datatype: string
name: unpack_data
arguments: data_label: D53
datatype: string
name: unpack_data
arguments: data_label: D23
datatype: string

tool: D9: Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.
1. Iki sayinin minimumunu bulma.
2. Iki sayinin maximumunu bulma.
3. Logaritma.
4. Bir sayinin kupunu alma.
5. Bir sayinin mutlak degerini alma.
Cikmak icin 1-5 disinda bir deger giriniz.

tool: D41: %d

tool: D53: %lf


tool: D23: Cikis yapiliyor.

assistant: ```c
int main() {
  int n;
  printf("Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.\n1. Iki sayinin minimumunu bulma.\n2. Iki sayinin maximumunu bulma.\n3. Logaritma.\n4. Bir sayinin kupunu alma.\n5. Bir sayinin mutlak degerini alma.\nCikmak icin 1-5 disinda bir deger giriniz.\n");
  scanf("%d", &n);
  switch (n) {
  case 1:
    printf("%lf\n", min());
    break;
  case 2:
    printf("%lf\n", max());
    break;
  case 3:
    printf("%lf\n", logg());
    break;
  case 4:
    printf("%lf\n", kup());
    break;
  case 5:
    printf("%lf\n", mutlak());
    break;
  default:
    printf("Cikis yapiliyor.\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D26(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D84(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L5
  mov    0x4(%rsp),%eax
  lea    D14(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xor    %eax,%eax
  call   <mutlak@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L43:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  xor    %eax,%eax
  call   <min@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
  xor    %eax,%eax
  call   <max@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
  xor    %eax,%eax
  call   <logg@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
  xor    %eax,%eax
  call   <kup@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L43
L5:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L43
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D84
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string

tool: D26: Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.
1. Iki sayinin minimumunu bulma.
2. Iki sayinin maximumunu bulma.
3. Logaritma.
4. Bir sayinin kupunu alma.
5. Bir sayinin mutlak degerini alma.
Cikmak icin 1-5 disinda bir deger giriniz.

tool: D84: %d

tool: D22: %lf


tool: D11: Cikis yapiliyor.

assistant: ```c
int main() {
  int n;
  printf("Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.\n1. Iki sayinin minimumunu bulma.\n2. Iki sayinin maximumunu bulma.\n3. Logaritma.\n4. Bir sayinin kupunu alma.\n5. Bir sayinin mutlak degerini alma.\nCikmak icin 1-5 disinda bir deger giriniz.\n");
  scanf("%d", &n);
  switch (n) {
  case 1:
    printf("%lf\n", min());
    break;
  case 2:
    printf("%lf\n", max());
    break;
  case 3:
    printf("%lf\n", logg());
    break;
  case 4:
    printf("%lf\n", kup());
    break;
  case 5:
    printf("%lf\n", mutlak());
    break;
  default:
    printf("Cikis yapiliyor.\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D43(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L29
  mov    0x4(%rsp),%eax
  lea    D27(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xor    %eax,%eax
  call   <mutlak@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopl   0x0(%rax)
L60:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  xor    %eax,%eax
  call   <min@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L60
  xor    %eax,%eax
  call   <max@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L60
  xor    %eax,%eax
  call   <logg@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L60
  xor    %eax,%eax
  call   <kup@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L60
L29:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  jmp    L60
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D43
type_guessed: string
name: unpack_data
arguments: data_label: D36
type_guessed: string
name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D43: Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.
1. Iki sayinin minimumunu bulma.
2. Iki sayinin maximumunu bulma.
3. Logaritma.
4. Bir sayinin kupunu alma.
5. Bir sayinin mutlak degerini alma.
Cikmak icin 1-5 disinda bir deger giriniz.

tool: D36: %d

tool: D32: %lf


tool: D14: Cikis yapiliyor.

assistant: ```c
int main() {
  int n;
  printf("Hangi islemi yapmak istiyorsaniz yanindaki rakami giriniz.\n1. Iki sayinin minimumunu bulma.\n2. Iki sayinin maximumunu bulma.\n3. Logaritma.\n4. Bir sayinin kupunu alma.\n5. Bir sayinin mutlak degerini alma.\nCikmak icin 1-5 disinda bir deger giriniz.\n");
  scanf("%d", &n);
  switch (n) {
  case 1:
    printf("%lf\n", min());
    break;
  case 2:
    printf("%lf\n", max());
    break;
  case 3:
    printf("%lf\n", logg());
    break;
  case 4:
    printf("%lf\n", kup());
    break;
  case 5:
    printf("%lf\n", mutlak());
    break;
  default:
    printf("Cikis yapiliyor.\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<free2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x8(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  mov    0x10(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x10(%rbp),%rax
  mov    0x18(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    -0x10(%rbp),%rax
  add    $0x40,%rax
  mov    0x10(%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  nop
  leave
  ret
```

assistant: ```c
void free2d(double *vals[4][8], int *indices[4][8]) {
  sfree(vals[0][1]);
  sfree(vals[0][2]);
  sfree(vals[0][3]);
  sfree(vals[1][2]);
  sfree(indices[0][1]);
  sfree(indices[0][2]);
  sfree(indices[0][3]);
  sfree(indices[1][2]);
}
```
user: What is the c source code of the assembly code below?

```asm
<free2d>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    0x8(%rdi),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x10(%rbp),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x18(%rbp),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x50(%rbp),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x8(%rbx),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x10(%rbx),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x18(%rbx),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  mov    0x50(%rbx),%rdi
  mov    $0x0,%eax
  call   <sfree@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void free2d(double *vals[4][8], int *indices[4][8]) {
  sfree(vals[0][1]);
  sfree(vals[0][2]);
  sfree(vals[0][3]);
  sfree(vals[1][2]);
  sfree(indices[0][1]);
  sfree(indices[0][2]);
  sfree(indices[0][3]);
  sfree(indices[1][2]);
}
```