ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<rmsummary_parse_next>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <jx_parse_stream@plt>
  test   %rax,%rax
  je     L4
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <json_to_rmsummary@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <jx_delete@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct rmsummary *rmsummary_parse_next(FILE *stream) {
  struct jx *j = jx_parse_stream(stream);
  if (!j)
    return NULL;
  struct rmsummary *s = json_to_rmsummary(j);
  jx_delete(j);
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L11:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L23
  movl   $0x0,-0xc(%rbp)
  jmp    L56
L23:
  movl   $0x1,-0xc(%rbp)
  jmp    L56
L37:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L38
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L38:
  addl   $0x2,-0xc(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L37
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L11
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int xSort(int a[], int n) {
  int count = 0, i, k;
  for (k = 0; k < n / 2; k++) {
    if (count % 2 == 0)
      i = 0;
    else
      i = 1;
    for (; i < n - 1; i = i + 2) {
      if (a[i] > a[i + 1]) {
        int temp = a[i];
        a[i] = a[i + 1];
        a[i + 1] = temp;
      }
    }
    count = count + 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xSort>:
  endbr64
  mov    %esi,%r9d
  shr    $0x1f,%r9d
  add    %esi,%r9d
  sar    %r9d
  cmp    $0x1,%esi
  jle    L72
  push   %rbx
  mov    %rdi,%r10
  mov    $0x0,%edi
  lea    -0x1(%rsi),%r11d
  lea    -0x2(%rsi),%r8d
  lea    0x8(%r10),%rbx
  jmp    L47
L18:
  add    $0x8,%rax
  cmp    %rsi,%rax
  je     L67
L66:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L18
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L18
L67:
  add    $0x1,%edi
  cmp    %r9d,%edi
  jge    L15
L47:
  mov    %edi,%edx
  and    $0x1,%edx
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    %r11d,%eax
  jge    L67
  movzbl %dl,%esi
  lea    (%r10,%rsi,4),%rax
  movzbl %dl,%ecx
  mov    %r8d,%edx
  sub    %ecx,%edx
  shr    %edx
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
  lea    (%rbx,%rdx,4),%rsi
  jmp    L66
L15:
  mov    $0x0,%eax
  pop    %rbx
  ret
L72:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int xSort(int a[], int n) {
  int count = 0, i, k;
  for (k = 0; k < n / 2; k++) {
    if (count % 2 == 0)
      i = 0;
    else
      i = 1;
    for (; i < n - 1; i = i + 2) {
      if (a[i] > a[i + 1]) {
        int temp = a[i];
        a[i] = a[i + 1];
        a[i + 1] = temp;
      }
    }
    count = count + 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xSort>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L36
  mov    %rdi,%r9
  push   %rbx
  lea    -0x1(%rsi),%r10d
  xor    %edi,%edi
  lea    -0x2(%rsi),%ebx
  lea    0x8(%r9),%r11
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %edi,%ecx
  and    $0x1,%ecx
  cmp    %r10d,%ecx
  jge    L21
  mov    %rbx,%rdx
  movslq %ecx,%rsi
  sub    %rcx,%rdx
  lea    (%r9,%rsi,4),%rax
  and    $0xfffffffe,%edx
  add    %rsi,%rdx
  lea    (%r11,%rdx,4),%rsi
  nopl   0x0(%rax)
L38:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L45
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L45:
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L38
L21:
  add    $0x1,%edi
  cmp    %r8d,%edi
  jl     L2
  xor    %eax,%eax
  pop    %rbx
  ret
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xSort(int a[], int n) {
  int count = 0, i, k;
  for (k = 0; k < n / 2; k++) {
    if (count % 2 == 0)
      i = 0;
    else
      i = 1;
    for (; i < n - 1; i = i + 2) {
      if (a[i] > a[i + 1]) {
        int temp = a[i];
        a[i] = a[i + 1];
        a[i + 1] = temp;
      }
    }
    count = count + 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xSort>:
  endbr64
  mov    %esi,%r8d
  shr    $0x1f,%r8d
  add    %esi,%r8d
  sar    %r8d
  cmp    $0x1,%esi
  jle    L49
  mov    %rdi,%r9
  push   %rbx
  lea    -0x1(%rsi),%r10d
  xor    %edi,%edi
  lea    -0x2(%rsi),%ebx
  lea    0x8(%r9),%r11
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %edi,%ecx
  and    $0x1,%ecx
  cmp    %r10d,%ecx
  jge    L2
  mov    %rbx,%rax
  movslq %ecx,%rsi
  sub    %rcx,%rax
  lea    (%r9,%rsi,4),%rdx
  and    $0xfffffffe,%eax
  add    %rsi,%rax
  lea    (%r11,%rax,4),%rsi
  nopl   0x0(%rax)
L8:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L27
  movq   %xmm1,(%rdx)
L27:
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L8
L2:
  add    $0x1,%edi
  cmp    %r8d,%edi
  jl     L47
  xor    %eax,%eax
  pop    %rbx
  ret
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xSort(int a[], int n) {
  int count = 0, i, k;
  for (k = 0; k < n / 2; k++) {
    if (count % 2 == 0)
      i = 0;
    else
      i = 1;
    for (; i < n - 1; i = i + 2) {
      if (a[i] > a[i + 1]) {
        int temp = a[i];
        a[i] = a[i + 1];
        a[i + 1] = temp;
      }
    }
    count = count + 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetCrc16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  movw   $0x0,-0x4(%rbp)
  jmp    L48
L5:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x4(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0x4(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L7
L22:
  movzwl -0x4(%rbp),%eax
  test   %ax,%ax
  jns    L49
  movzwl -0x4(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %ax,-0x4(%rbp)
  jmp    L15
L49:
  shlw   -0x4(%rbp)
L15:
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L7:
  cmpw   $0x7,-0x2(%rbp)
  jbe    L22
L48:
  movzwl -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x1c(%rbp)
  test   %ax,%ax
  jne    L5
  movzwl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short GetCrc16(char *ptr, unsigned short count) {
  unsigned short crc, i;
  crc = 0;
  while (count--) {
    crc = crc ^ (int)*ptr++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return (crc & 0xFFFF);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GetCrc16>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %si,%si
  je     L40
  movzwl %ax,%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0x0,%eax
  jmp    L43
L37:
  cmp    %r8,%rdi
  je     L7
L43:
  add    $0x1,%rdi
  movsbl -0x1(%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L44:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  lea    (%rax,%rax,1),%esi
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%cx
  jne    L44
  jmp    L37
L7:
  ret
L40:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned short GetCrc16(char *ptr, unsigned short count) {
  unsigned short crc, i;
  crc = 0;
  while (count--) {
    crc = crc ^ (int)*ptr++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return (crc & 0xFFFF);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<GetCrc16>:
  endbr64
  test   %si,%si
  je     L11
  movzwl %si,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%r8
  nopw   0x0(%rax,%rax,1)
L25:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  mov    $0x8,%ecx
  shl    $0x8,%edx
  xor    %edx,%eax
  nopl   0x0(%rax)
L2:
  lea    (%rax,%rax,1),%edx
  lea    (%rax,%rax,1),%esi
  xor    $0x1021,%dx
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%cx
  jne    L2
  cmp    %rdi,%r8
  jne    L25
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short GetCrc16(char *ptr, unsigned short count) {
  unsigned short crc, i;
  crc = 0;
  while (count--) {
    crc = crc ^ (int)*ptr++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return (crc & 0xFFFF);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<GetCrc16>:
  endbr64
  mov    %rdi,%rcx
  test   %si,%si
  je     L56
  movzwl %si,%esi
  xor    %eax,%eax
  add    %rdi,%rsi
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L45:
  lea    (%rax,%rax,1),%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L145
L161:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L149
L52:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L121
L96:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L75
L151:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L127
L24:
  add    %edx,%edx
  mov    %edx,%eax
  test   %ax,%ax
  js     L166
L47:
  add    %edx,%edx
  mov    %edx,%edi
L13:
  lea    (%rdx,%rdx,1),%r8d
  mov    %r8d,%eax
  xor    $0x1021,%ax
  test   %di,%di
  mov    %eax,%edx
  mov    %r8d,%eax
  cmovs  %edx,%eax
  cmp    %rcx,%rsi
  je     L137
L69:
  movsbl (%rcx),%edx
  add    $0x1,%rcx
  shl    $0x8,%edx
  xor    %dx,%ax
  jns    L45
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L161
L145:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L52
L149:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L96
L121:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L151
L75:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L24
L127:
  lea    (%rdx,%rdx,1),%eax
  xor    $0x1021,%ax
  mov    %eax,%edx
  test   %ax,%ax
  jns    L47
L166:
  lea    (%rdx,%rdx,1),%edi
  xor    $0x1021,%di
  mov    %edi,%edx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L137:
  ret
L56:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned short GetCrc16(char *ptr, unsigned short count) {
  unsigned short crc, i;
  crc = 0;
  while (count--) {
    crc = crc ^ (int)*ptr++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return (crc & 0xFFFF);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bbm_com_tuner_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,%esi
  mov    %ecx,%edx
  mov    %r8,-0x30(%rbp)
  mov    %r9d,%ecx
  mov    %ax,-0x1c(%rbp)
  mov    %esi,%eax
  mov    %al,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x28(%rbp)
  movzbl -0x28(%rbp),%r8d
  movzbl -0x24(%rbp),%ecx
  movzbl -0x20(%rbp),%edx
  movzwl -0x1c(%rbp),%esi
  mov    -0x30(%rbp),%rdi
  mov    -0x18(%rbp),%rax
  mov    %r8d,%r9d
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <tuner_i2c_read@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int bbm_com_tuner_read(void *handle, unsigned short devid, unsigned char addr, unsigned char alen, unsigned char *buffer, unsigned char len) {
  int res;
  res = tuner_i2c_read(handle, devid, addr, alen, buffer, len);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bbm_com_tuner_read>:
  endbr64
  sub    $0x8,%rsp
  movzbl %cl,%ecx
  movzbl %dl,%edx
  movzwl %si,%esi
  movzbl %r9b,%r9d
  call   <tuner_i2c_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int bbm_com_tuner_read(void *handle, unsigned short devid, unsigned char addr, unsigned char alen, unsigned char *buffer, unsigned char len) {
  int res;
  res = tuner_i2c_read(handle, devid, addr, alen, buffer, len);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bbm_com_tuner_read>:
  endbr64
  movzbl %cl,%ecx
  movzbl %dl,%edx
  movzwl %si,%esi
  movzbl %r9b,%r9d
  jmp    1050 <tuner_i2c_read@plt>
```

assistant: ```c
int bbm_com_tuner_read(void *handle, unsigned short devid, unsigned char addr, unsigned char alen, unsigned char *buffer, unsigned char len) {
  int res;
  res = tuner_i2c_read(handle, devid, addr, alen, buffer, len);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<bbm_com_tuner_read>:
  endbr64
  movzbl %cl,%ecx
  movzbl %dl,%edx
  movzwl %si,%esi
  movzbl %r9b,%r9d
  jmp    1050 <tuner_i2c_read@plt>
```

assistant: ```c
int bbm_com_tuner_read(void *handle, unsigned short devid, unsigned char addr, unsigned char alen, unsigned char *buffer, unsigned char len) {
  int res;
  res = tuner_i2c_read(handle, devid, addr, alen, buffer, len);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lcg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D27(%rip),%rax
  imul   %rax,%rdx
  mov    D26(%rip),%rax
  add    %rdx,%rax
  mov    D6(%rip),%rcx
  cqto
  idiv   %rcx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  D11(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double lcg(long int *seed) {
  static long int a = 69069, c = 1, m = 2147483647;
  static double rm = 2147483647.0;
  *seed = (*seed * a + c) % m;
  return (double)*seed / rm;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lcg>:
  endbr64
  imul   $0x10dcd,(%rdi),%rcx
  add    $0x1,%rcx
  movabs $0x8000000100000003,%rdx
  mov    %rcx,%rax
  imul   %rdx
  add    %rcx,%rdx
  sar    $0x1e,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x1f,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,(%rdi)
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
  divsd  D2(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: f64

tool: D2: 2147483647

assistant: ```c
double lcg(long int *seed) {
  static long int a = 69069, c = 1, m = 2147483647;
  static double rm = 2147483647.0;
  *seed = (*seed * a + c) % m;
  return (double)*seed / rm;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lcg>:
  endbr64
  imul   $0x10dcd,(%rdi),%rcx
  pxor   %xmm0,%xmm0
  movabs $0x8000000100000003,%rdx
  add    $0x1,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  add    %rcx,%rdx
  sar    $0x1e,%rdx
  sub    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x1f,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  cvtsi2sd %rcx,%xmm0
  mov    %rcx,(%rdi)
  divsd  D7(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: f64

tool: D7: 2147483647

assistant: ```c
double lcg(long int *seed) {
  static long int a = 69069, c = 1, m = 2147483647;
  static double rm = 2147483647.0;
  *seed = (*seed * a + c) % m;
  return (double)*seed / rm;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lcg>:
  endbr64
  imul   $0x10dcd,(%rdi),%rcx
  pxor   %xmm0,%xmm0
  movabs $0x8000000100000003,%rdx
  add    $0x1,%rcx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  add    %rcx,%rdx
  sar    $0x1e,%rdx
  sub    %rax,%rdx
  mov    %rdx,%rax
  shl    $0x1f,%rax
  sub    %rdx,%rax
  sub    %rax,%rcx
  cvtsi2sd %rcx,%xmm0
  mov    %rcx,(%rdi)
  divsd  D9(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: f64

tool: D9: 2147483647

assistant: ```c
double lcg(long int *seed) {
  static long int a = 69069, c = 1, m = 2147483647;
  static double rm = 2147483647.0;
  *seed = (*seed * a + c) % m;
  return (double)*seed / rm;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <number_square@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: %d

assistant: ```c
int main() {
  int nummer;
  scanf("%d", &nummer);
  printf("%d", number_square(nummer));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <number_square@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int nummer;
  scanf("%d", &nummer);
  printf("%d", number_square(nummer));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <number_square@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: %d

assistant: ```c
int main() {
  int nummer;
  scanf("%d", &nummer);
  printf("%d", number_square(nummer));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <number_square@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  int nummer;
  scanf("%d", &nummer);
  printf("%d", number_square(nummer));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_on_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    %esi,-0x14(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  cmpl   $0x1,-0x18(%rbp)
  jne    L4
  movsd  -0x20(%rbp),%xmm0
  mov    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movapd %xmm0,%xmm1
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L17
L4:
  mov    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  lea    D54(%rip),%rdx
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D31
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D54
type_guessed: string
name: extract_symbolic_data
arguments: label: D30
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string

tool: D31: 
	---------------%s----------------



tool: D23: 			SIZE	 TIME_SEC	 gflops 


tool: D4: 			%d	%f	 %lf	


tool: D54: ---

tool: D30: 			%d	%lf 	%s	


tool: D3: 
	-------------------------------------------------------------------------

assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n\n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-------------------------------------------------------------------------");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_on_screen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %esi,%ebx
  movq   %xmm1,%r13
  mov    %edx,%r12d
  mov    %rdi,%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  cmp    $0x1,%r12d
  je     L1
  lea    D43(%rip),%rdx
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  movq   %r13,%xmm1
  movq   %rbp,%xmm0
  mov    %ebx,%esi
  lea    D28(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L17
```

tool_calls: name: parse_data
arguments: data_tag: D35
type_infered: string
name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D43
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D58
type_infered: string
name: parse_data
arguments: data_tag: D28
type_infered: string

tool: D35: 
	---------------%s----------------



tool: D18: 			SIZE	 TIME_SEC	 gflops 


tool: D43: ---

tool: D14: 			%d	%lf 	%s	


tool: D58: 
	-------------------------------------------------------------------------

tool: D28: 			%d	%f	 %lf	


assistant: ```c
void print_on_screen(char *programName, double tsec, int size, double gflops, int flag) {
  printf("\n\t---------------%s----------------\n\n", programName);
  printf("\t\t\tSIZE\t TIME_SEC\t gflops \n\n");
  if (flag == 1)
    printf("\t\t\t%d\t%f\t %lf\t\n", size, tsec, gflops);
  else
    printf("\t\t\t%d\t%lf \t%s\t\n", size, tsec, "---");
  printf("\n\t-------------------------------------------------------------------------");
}
```