ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_sq_mat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D24(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L2
L7:
  add    $0x8,%rsp
  lea    D29(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L2:
  mov    (%r12),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    $0x1,%ebp
  jle    L7
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%r13
  lea    D23(%rip),%r12
  nopl   0x0(%rax)
L4:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    %r13,%rbx
  jne    L4
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D29
datatype: string
name: read_data
arguments: tag: D23
datatype: string

tool: D24: [

tool: D29: ]

tool: D23: ,


assistant: ```c
void print_sq_mat(int n, double **A) {
  printf("[");
  if (n > 0)
    print_vec(n, A[0]);
  int row;
  for (row = 1; row < n; row++) {
    printf(",\n");
    print_vec(n, A[row]);
  }
  printf("]");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_sq_mat>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D25(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jg     L31
L22:
  add    $0x8,%rsp
  lea    D10(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L31:
  mov    (%r12),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    $0x1,%ebp
  jle    L22
  lea    -0x2(%rbp),%eax
  lea    0x8(%r12),%rbx
  lea    0x10(%r12,%rax,8),%r13
  lea    D4(%rip),%r12
  nopl   0x0(%rax)
L36:
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  mov    -0x8(%rbx),%rsi
  mov    %ebp,%edi
  call   <print_vec@plt>
  cmp    %r13,%rbx
  jne    L36
  jmp    L22
```

tool_calls: name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string

tool: D25: [

tool: D10: ]

tool: D4: ,


assistant: ```c
void print_sq_mat(int n, double **A) {
  printf("[");
  if (n > 0)
    print_vec(n, A[0]);
  int row;
  for (row = 1; row < n; row++) {
    printf(",\n");
    print_vec(n, A[row]);
  }
  printf("]");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitcount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  jmp    L15
L6:
  addl   $0x1,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
L15:
  cmpl   $0x0,-0x14(%rbp)
  jne    L6
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitcount(unsigned int x) {
  int b;
  while (x) {
    ++b;
    x &= (x - 1);
  }
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitcount>:
  endbr64
  test   %edi,%edi
  je     L6
L10:
  add    $0x1,%edx
  lea    -0x1(%rdi),%eax
  and    %eax,%edi
  jne    L10
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int bitcount(unsigned int x) {
  int b;
  while (x) {
    ++b;
    x &= (x - 1);
  }
  return b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitcount>:
  endbr64
  test   %edi,%edi
  je     L18
  nopl   0x0(%rax,%rax,1)
L15:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L15
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount(unsigned int x) {
  int b;
  while (x) {
    ++b;
    x &= (x - 1);
  }
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitcount>:
  endbr64
  test   %edi,%edi
  je     L1
  nopl   0x0(%rax,%rax,1)
L12:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L12
L1:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int bitcount(unsigned int x) {
  int b;
  while (x) {
    ++b;
    x &= (x - 1);
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply305>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L9
L1:
  movl   $0x0,-0x3c(%rbp)
  jmp    L24
L37:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L24:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L37
  addl   $0x1,-0x40(%rbp)
L9:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L1
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply305(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<multiply305>:
  endbr64
  test   %edi,%edi
  jle    L28
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L19:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L6:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L6
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  ret
```

assistant: ```c
void multiply305(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiply305>:
  endbr64
  test   %edi,%edi
  jle    L26
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L6
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L14
  pop    %rbx
  ret
L26:
  ret
```

assistant: ```c
void multiply305(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply305>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L63
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L85:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L81
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L81
  nopl   0x0(%rax)
L6:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L6
  cmp    -0x24(%rsp),%r11d
  je     L28
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L28
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L28
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L28:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L85
L63:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L81:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L71:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L71
  mov    -0x18(%rsp),%r8
  jmp    L28
```

assistant: ```c
void multiply305(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_keybags>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x810(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <fget@plt>
  lea    -0x810(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <remove@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type: string
name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D9
type: string

tool: D28: Drag file here : 

tool: D5: bin\xpwntool %s nul | cut -f2 -d ' '

tool: D9: nul

assistant: ```c
int get_keybags() {
  char file_here[1024], buildCommand[1024];
  printf("Drag file here : ");
  fget(file_here, 1024);
  sprintf(buildCommand, "bin\\xpwntool %s nul | cut -f2 -d ' '", file_here);
  system(buildCommand);
  remove("nul");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_keybags>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbp
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <fget@plt>
  lea    0x400(%rsp),%rbx
  mov    %rbp,%rdx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  lea    D22(%rip),%rdi
  call   <remove@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string
name: read_data
arguments: data_tag: D22
type_infered: string

tool: D19: Drag file here : 

tool: D2: bin\xpwntool %s nul | cut -f2 -d ' '

tool: D22: nul

assistant: ```c
int get_keybags() {
  char file_here[1024], buildCommand[1024];
  printf("Drag file here : ");
  fget(file_here, 1024);
  sprintf(buildCommand, "bin\\xpwntool %s nul | cut -f2 -d ' '", file_here);
  system(buildCommand);
  remove("nul");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_keybags>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x400(%rsp),%rbp
  call   <printf@plt>
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <fget@plt>
  mov    %r12,%rdx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  lea    D5(%rip),%rdi
  call   <remove@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x818,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D1: Drag file here : 

tool: D27: bin\xpwntool %s nul | cut -f2 -d ' '

tool: D5: nul

assistant: ```c
int get_keybags() {
  char file_here[1024], buildCommand[1024];
  printf("Drag file here : ");
  fget(file_here, 1024);
  sprintf(buildCommand, "bin\\xpwntool %s nul | cut -f2 -d ' '", file_here);
  system(buildCommand);
  remove("nul");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_keybags>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  push   %rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x400(%rsp),%rbp
  call   <printf@plt>
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <fget@plt>
  mov    %r12,%rdx
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  lea    D3(%rip),%rdi
  call   <remove@plt>
  mov    0x808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x818,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D17: Drag file here : 

tool: D10: bin\xpwntool %s nul | cut -f2 -d ' '

tool: D3: nul

assistant: ```c
int get_keybags() {
  char file_here[1024], buildCommand[1024];
  printf("Drag file here : ");
  fget(file_here, 1024);
  sprintf(buildCommand, "bin\\xpwntool %s nul | cut -f2 -d ' '", file_here);
  system(buildCommand);
  remove("nul");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_strequ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_strcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    $0x1,%eax
  jmp    L24
L6:
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  if (s1 && s2) {
    if (ft_strcmp(s1, s2) == 0)
      return (1);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strequ>:
  endbr64
  test   %rdi,%rdi
  je     L0
  test   %rsi,%rsi
  jne    L10
L0:
  mov    $0x0,%eax
  ret
L10:
  sub    $0x8,%rsp
  call   <ft_strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  if (s1 && s2) {
    if (ft_strcmp(s1, s2) == 0)
      return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strequ>:
  endbr64
  test   %rdi,%rdi
  je     L11
  test   %rsi,%rsi
  jne    L4
L11:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  call   <ft_strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  if (s1 && s2) {
    if (ft_strcmp(s1, s2) == 0)
      return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_strequ>:
  endbr64
  test   %rdi,%rdi
  je     L3
  test   %rsi,%rsi
  jne    L1
L3:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  call   <ft_strcmp@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  if (s1 && s2) {
    if (ft_strcmp(s1, s2) == 0)
      return (1);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_active_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L24
  addl   $0x1,-0x4(%rbp)
L24:
  sarl   -0x14(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jg     L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ft_active_bits(int value) {
  unsigned int n;
  n = 0;
  while (value > 0) {
    if (value & 1 == 1)
      n++;
    value >>= 1;
  }
  return (n);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ft_active_bits>:
  endbr64
  test   %edi,%edi
  jle    L2
  mov    $0x0,%eax
L11:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  test   %edi,%edi
  jg     L11
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int ft_active_bits(int value) {
  unsigned int n;
  n = 0;
  while (value > 0) {
    if (value & 1 == 1)
      n++;
    value >>= 1;
  }
  return (n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_active_bits>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L7
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  jne    L9
  ret
L7:
  ret
```

assistant: ```c
unsigned int ft_active_bits(int value) {
  unsigned int n;
  n = 0;
  while (value > 0) {
    if (value & 1 == 1)
      n++;
    value >>= 1;
  }
  return (n);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_active_bits>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %edi,%edx
  and    $0x1,%edx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  sar    %edi
  jne    L4
  ret
L6:
  ret
```

assistant: ```c
unsigned int ft_active_bits(int value) {
  unsigned int n;
  n = 0;
  while (value > 0) {
    if (value & 1 == 1)
      n++;
    value >>= 1;
  }
  return (n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Act_Div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <ArgNum@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <ArgNum@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <Log@plt>
  mov    $0x0,%eax
  call   <Me@plt>
  mov    %eax,%edx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <SendItem@plt>
  jmp    L9
L12:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <GetFlag@plt>
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <SetFlag@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string

tool: D5: Division By Zero

tool: D11: Division By Zero!


assistant: ```c
void Act_Div(void) {
  int a = ArgNum();
  int b = ArgNum();
  if (b == 0) {
    Log("Division By Zero");
    SendItem(Me(), "Division By Zero!\n");
    return;
  }
  SetFlag(a, GetFlag(a) / b);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Act_Div>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ArgNum@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <ArgNum@plt>
  test   %eax,%eax
  je     L12
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <GetFlag@plt>
  cltd
  idiv   %ebx
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <SetFlag@plt>
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  lea    D3(%rip),%rdi
  call   <Log@plt>
  mov    $0x0,%eax
  call   <Me@plt>
  mov    %eax,%edi
  lea    D14(%rip),%rsi
  call   <SendItem@plt>
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D14
datatype: string

tool: D3: Division By Zero

tool: D14: Division By Zero!


assistant: ```c
void Act_Div(void) {
  int a = ArgNum();
  int b = ArgNum();
  if (b == 0) {
    Log("Division By Zero");
    SendItem(Me(), "Division By Zero!\n");
    return;
  }
  SetFlag(a, GetFlag(a) / b);
}
```
user: What is the c source code of the assembly code below?

```asm
<Act_Div>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <ArgNum@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <ArgNum@plt>
  test   %eax,%eax
  je     L8
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <GetFlag@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  mov    %eax,%esi
  jmp    10b0 <SetFlag@plt>
  nopl   0x0(%rax)
L8:
  lea    D2(%rip),%rdi
  call   <Log@plt>
  xor    %eax,%eax
  call   <Me@plt>
  add    $0x8,%rsp
  lea    D0(%rip),%rsi
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  jmp    10c0 <SendItem@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string

tool: D2: Division By Zero

tool: D0: Division By Zero!


assistant: ```c
void Act_Div(void) {
  int a = ArgNum();
  int b = ArgNum();
  if (b == 0) {
    Log("Division By Zero");
    SendItem(Me(), "Division By Zero!\n");
    return;
  }
  SetFlag(a, GetFlag(a) / b);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Act_Div>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <ArgNum@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <ArgNum@plt>
  test   %eax,%eax
  je     L4
  mov    %ebp,%edi
  mov    %eax,%ebx
  call   <GetFlag@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  mov    %eax,%esi
  jmp    10b0 <SetFlag@plt>
  nopl   0x0(%rax)
L4:
  lea    D14(%rip),%rdi
  call   <Log@plt>
  xor    %eax,%eax
  call   <Me@plt>
  add    $0x8,%rsp
  lea    D13(%rip),%rsi
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  jmp    10c0 <SendItem@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string

tool: D14: Division By Zero

tool: D13: Division By Zero!


assistant: ```c
void Act_Div(void) {
  int a = ArgNum();
  int b = ArgNum();
  if (b == 0) {
    Log("Division By Zero");
    SendItem(Me(), "Division By Zero!\n");
    return;
  }
  SetFlag(a, GetFlag(a) / b);
}
```