ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<compare_two_vectors_>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%edx
  mov    %rcx,0x8(%rsp)
  test   %edx,%edx
  jle    L48
  mov    %rsi,%r15
  movslq %edx,%r14
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L21
  nopl   0x0(%rax)
L47:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L34
L21:
  movss  (%r15,%rbx,4),%xmm0
  pxor   %xmm2,%xmm2
  mov    %ebx,%r13d
  ucomiss %xmm2,%xmm0
  jp     L32
  je     L47
L32:
  subss  0x0(%rbp,%rbx,4),%xmm0
  call   <fabsf@plt>
  pxor   %xmm1,%xmm1
  movss  (%r15,%rbx,4),%xmm0
  cvtsi2ss %eax,%xmm1
  divss  %xmm0,%xmm1
  cvtss2sd %xmm1,%xmm1
  comisd D29(%rip),%xmm1
  jbe    L47
  subss  0x0(%rbp,%rbx,4),%xmm0
  call   <fabsf@plt>
  test   %eax,%eax
  jle    L47
  add    $0x1,%r12d
  cmp    $0x9,%r12d
  jg     L47
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %r13d,%esi
  mov    $0x2,%eax
  cvtss2sd (%r15,%rbx,4),%xmm0
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm1
  lea    D1(%rip),%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L21
L34:
  mov    %r12d,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  mov    %r12d,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  xor    %r12d,%r12d
  jmp    L34
```

tool_calls: name: disassemble_data
arguments: data_label: D29
data_type: f64
name: disassemble_data
arguments: data_label: D1
data_type: string
name: disassemble_data
arguments: data_label: D23
data_type: string

tool: D29: 0.01

tool: D1: err[%d]: %e != %e


tool: D23: **** Error Count: %d ****


assistant: ```c
void compare_two_vectors_(int *sizef, float *vector1, float *vector2, int *num_errors) {
  int size = *sizef;
  int i;
  int error_count = 0;
  for (i = 0; i < size; ++i) {
    if (vector1[i] != 0) {
      if (fabsf(vector1[i] - vector2[i]) / vector1[i] > 0.01) {
        if (fabsf(vector1[i] - vector2[i]) > 1e-20) {
          error_count++;
          if (error_count < 10) {
            printf("err[%d]: %e != %e\n", i, vector1[i], vector2[i]);
          }
        }
      }
    }
  }
  printf("**** Error Count: %d ****\n", error_count);
  *num_errors = error_count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %esi,-0x68(%rbp)
  mov    %fs:0x28,%rcx
  mov    %rcx,-0x38(%rbp)
  xor    %ecx,%ecx
  mov    %rsp,%rcx
  mov    %rcx,%r15
  mov    -0x68(%rbp),%ecx
  mov    -0x64(%rbp),%esi
  movslq %ecx,%rdi
  sub    $0x1,%rdi
  mov    %rdi,-0x50(%rbp)
  movslq %ecx,%rdi
  mov    %rdi,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%rbx
  movslq %esi,%rdi
  sub    $0x1,%rdi
  mov    %rdi,-0x48(%rbp)
  movslq %ecx,%rdi
  mov    %rdi,%r12
  mov    $0x0,%r13d
  movslq %esi,%rdi
  mov    %rdi,%rax
  mov    $0x0,%edx
  mov    %r13,%r14
  imul   %rax,%r14
  mov    %rdx,%rdi
  imul   %r12,%rdi
  add    %r14,%rdi
  mul    %r12
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rax
  mov    %rax,%r10
  mov    $0x0,%r11d
  movslq %esi,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    %r11,%rdx
  imul   %r8,%rdx
  mov    %r9,%rax
  imul   %r10,%rax
  lea    (%rdx,%rax,1),%rdi
  mov    %r10,%rax
  mul    %r8
  add    %rdx,%rdi
  mov    %rdi,%rdx
  movslq %ecx,%rdx
  movslq %esi,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L13:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L28:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L41
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L41:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L20
L2:
  mov    %rbx,%rcx
  shr    $0x2,%rcx
  mov    -0x54(%rbp),%eax
  cltd
  idivl  -0x68(%rbp)
  mov    %eax,%edi
  mov    -0x54(%rbp),%eax
  cltd
  idivl  -0x68(%rbp)
  mov    -0x40(%rbp),%rax
  movslq %edx,%rsi
  movslq %edi,%rdx
  imul   %rcx,%rdx
  lea    (%rsi,%rdx,1),%rcx
  mov    -0x54(%rbp),%edx
  mov    %edx,(%rax,%rcx,4)
  addl   $0x1,-0x54(%rbp)
L20:
  mov    -0x64(%rbp),%eax
  imul   -0x68(%rbp),%eax
  cmp    %eax,-0x54(%rbp)
  jl     L2
  mov    -0x40(%rbp),%rdx
  mov    -0x68(%rbp),%ecx
  mov    -0x64(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <print@plt>
  mov    %r15,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void matrix(int n, int m) {
  int i, arr[n][m];
  for (i = 0; i < n * m; ++i) {
    arr[i / m][i % m] = i;
  }
  print(n, m, arr);
}
```
user: What is the c source code of the assembly code below?

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rdi
  movslq %r9d,%rax
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L6:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L6
L15:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L27
  orq    $0x0,-0x8(%rsp,%rax,1)
L27:
  mov    %rsp,%r8
  mov    %esi,%r10d
  imul   %r9d,%r10d
  test   %r10d,%r10d
  jle    L36
  shr    $0x2,%rdi
  mov    $0x0,%ecx
L29:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  movslq %edx,%rdx
  cltq
  imul   %rdi,%rax
  add    %rax,%rdx
  mov    %ecx,(%r8,%rdx,4)
  add    $0x1,%ecx
  cmp    %r10d,%ecx
  jne    L29
L36:
  mov    %r8,%rdx
  mov    %r9d,%edi
  call   <print@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  leave
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void matrix(int n, int m) {
  int i, arr[n][m];
  for (i = 0; i < n * m; ++i) {
    arr[i / m][i % m] = i;
  }
  print(n, m, arr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %edi,%r9d
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %r9d,%rax
  mov    %rsp,%rcx
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L32
L27:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L27
L32:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L55:
  mov    %esi,%r10d
  mov    %rsp,%r8
  imul   %r9d,%r10d
  test   %r10d,%r10d
  jle    L41
  shr    $0x2,%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  cltq
  movslq %edx,%rdx
  imul   %rdi,%rax
  add    %rax,%rdx
  mov    %ecx,(%r8,%rdx,4)
  add    $0x1,%ecx
  cmp    %r10d,%ecx
  jne    L68
L41:
  mov    %r8,%rdx
  mov    %r9d,%edi
  call   <print@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  leave
  ret
  nopl   0x0(%rax)
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L55
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void matrix(int n, int m) {
  int i, arr[n][m];
  for (i = 0; i < n * m; ++i) {
    arr[i / m][i % m] = i;
  }
  print(n, m, arr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matrix>:
  endbr64
  push   %rbp
  mov    %edi,%r9d
  movslq %esi,%rdx
  lea    0x0(,%rdx,4),%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %r9d,%rax
  mov    %rsp,%rcx
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L66
L30:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L30
L66:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L29
L59:
  mov    %esi,%r10d
  mov    %rsp,%r8
  imul   %r9d,%r10d
  test   %r10d,%r10d
  jle    L21
  shr    $0x2,%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  cltq
  movslq %edx,%rdx
  imul   %rdi,%rax
  add    %rax,%rdx
  mov    %ecx,(%r8,%rdx,4)
  add    $0x1,%ecx
  cmp    %r10d,%ecx
  jne    L2
L21:
  mov    %r8,%rdx
  mov    %r9d,%edi
  call   <print@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  leave
  ret
  nopl   0x0(%rax)
L29:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L59
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void matrix(int n, int m) {
  int i, arr[n][m];
  for (i = 0; i < n * m; ++i) {
    arr[i / m][i % m] = i;
  }
  print(n, m, arr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa4(%rbp)
  movl   $0x0,-0xa0(%rbp)
  jmp    L124
L55:
  mov    -0xa0(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0xa0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0xa0(%rbp)
L124:
  cmpl   $0xe,-0xa0(%rbp)
  jle    L55
  movl   $0x0,-0x9c(%rbp)
  jmp    L111
L121:
  movl   $0x1,-0x98(%rbp)
  jmp    L27
L70:
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  cmp    $0x1,%eax
  jne    L61
  addl   $0x1,-0xa4(%rbp)
L61:
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  cltd
  idivl  -0x98(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L125
  addl   $0x1,-0xa4(%rbp)
L125:
  addl   $0x1,-0x98(%rbp)
L27:
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  cmp    %eax,-0x98(%rbp)
  jle    L70
  cmpl   $0x1,-0xa4(%rbp)
  jne    L130
  mov    -0x9c(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%edx
  mov    -0x9c(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  jmp    L114
L130:
  mov    -0x9c(%rbp),%eax
  cltq
  movl   $0x0,-0x50(%rbp,%rax,4)
L114:
  movl   $0x0,-0xa4(%rbp)
  addl   $0x1,-0x9c(%rbp)
L111:
  cmpl   $0xe,-0x9c(%rbp)
  jle    L121
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x94(%rbp)
  jmp    L50
L83:
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L69
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L69:
  addl   $0x1,-0x94(%rbp)
L50:
  cmpl   $0xe,-0x94(%rbp)
  jle    L83
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D30
datatype: string
name: unpack_data
arguments: data_tag: D10
datatype: string

tool: D23: Informe o valor da posicao %d: 

tool: D26: %d

tool: D30: Vetor P:

tool: D10: %d 

assistant: ```c
void main() {
  int K[15], vzs = 0, P[15];
  for (int i = 0; i < 15; i++) {
    printf("Informe o valor da posicao %d: ", i + 1);
    scanf("%d", &K[i]);
  }
  for (int i = 0; i < 15; i++) {
    for (int j = 1; j <= sqrt(K[i]); j++) {
      if (K[i] == 1) {
        vzs++;
      }
      if (K[i] % j == 0) {
        vzs++;
      }
    }
    if (vzs == 1) {
      P[i] = K[i];
    } else {
      P[i] = 0;
    }
    vzs = 0;
  }
  printf("Vetor P:\n");
  for (int i = 0; i < 15; i++) {
    if (P[i] != 0) {
      printf("%d ", P[i]);
    }
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%r12
  mov    $0x0,%ebx
  lea    D32(%rip),%r14
  lea    D25(%rip),%r13
L23:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    $0xf,%ebx
  jne    L23
  lea    0x50(%rsp),%r14
  lea    0x3c(%rbp),%rax
  mov    %rax,0x8(%rsp)
  mov    %r14,%r15
  jmp    L75
L69:
  mov    0x0(%rbp),%eax
  cmp    $0x1,%eax
  sete   %cl
  movzbl %cl,%ecx
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  adc    %ecx,%r12d
  add    $0x1,%ebx
L118:
  mov    0x0(%rbp),%edi
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L69
  mov    $0x0,%eax
  cmp    $0x1,%r12d
  je     L97
L103:
  mov    %eax,(%r15)
  add    $0x4,%r15
  add    $0x4,%rbp
  cmp    0x8(%rsp),%rbp
  je     L15
L75:
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  jmp    L118
L97:
  mov    0x0(%rbp),%eax
  jmp    L103
L15:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    0x3c(%r14),%rbx
  lea    D14(%rip),%rbp
  jmp    L53
L86:
  add    $0x4,%r14
  cmp    %rbx,%r14
  je     L85
L53:
  mov    (%r14),%esi
  test   %esi,%esi
  je     L86
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L86
L85:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D32
type_infered: string
name: parse_data
arguments: data_tag: D25
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string

tool: D32: Informe o valor da posicao %d: 

tool: D25: %d

tool: D27: Vetor P:

tool: D14: %d 

assistant: ```c
void main() {
  int K[15], vzs = 0, P[15];
  for (int i = 0; i < 15; i++) {
    printf("Informe o valor da posicao %d: ", i + 1);
    scanf("%d", &K[i]);
  }
  for (int i = 0; i < 15; i++) {
    for (int j = 1; j <= sqrt(K[i]); j++) {
      if (K[i] == 1) {
        vzs++;
      }
      if (K[i] % j == 0) {
        vzs++;
      }
    }
    if (vzs == 1) {
      P[i] = K[i];
    } else {
      P[i] = 0;
    }
    vzs = 0;
  }
  printf("Vetor P:\n");
  for (int i = 0; i < 15; i++) {
    if (P[i] != 0) {
      printf("%d ", P[i]);
    }
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D4(%rip),%r14
  push   %r13
  lea    D30(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
  xchg   %ax,%ax
L80:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0xf,%ebx
  jne    L80
  lea    0x40(%rsp),%r13
  lea    0x3c(%r12),%r15
  mov    %r13,%r14
L87:
  mov    (%r12),%edi
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  jmp    L43
  nopl   (%rax)
L97:
  mov    (%r12),%edi
  xor    %ecx,%ecx
  mov    %edi,%eax
  cmp    $0x1,%edi
  sete   %cl
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  adc    %ecx,%ebp
  add    $0x1,%ebx
L43:
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L97
  xor    %eax,%eax
  cmp    $0x1,%ebp
  jne    L44
  mov    (%r12),%eax
L44:
  add    $0x4,%r12
  mov    %eax,(%r14)
  add    $0x4,%r14
  cmp    %r15,%r12
  jne    L87
  lea    D20(%rip),%rdi
  lea    0x3c(%r13),%rbx
  call   <puts@plt>
  lea    D15(%rip),%rbp
  jmp    L78
  cs nopw 0x0(%rax,%rax,1)
L3:
  add    $0x4,%r13
  cmp    %rbx,%r13
  je     L35
L78:
  mov    0x0(%r13),%esi
  test   %esi,%esi
  je     L3
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L78
L35:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string
name: retrieve_data
arguments: data_label: D30
data_type: string
name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D15
data_type: string

tool: D4: Informe o valor da posicao %d: 

tool: D30: %d

tool: D20: Vetor P:

tool: D15: %d 

assistant: ```c
void main() {
  int K[15], vzs = 0, P[15];
  for (int i = 0; i < 15; i++) {
    printf("Informe o valor da posicao %d: ", i + 1);
    scanf("%d", &K[i]);
  }
  for (int i = 0; i < 15; i++) {
    for (int j = 1; j <= sqrt(K[i]); j++) {
      if (K[i] == 1) {
        vzs++;
      }
      if (K[i] % j == 0) {
        vzs++;
      }
    }
    if (vzs == 1) {
      P[i] = K[i];
    } else {
      P[i] = 0;
    }
    vzs = 0;
  }
  printf("Vetor P:\n");
  for (int i = 0; i < 15; i++) {
    if (P[i] != 0) {
      printf("%d ", P[i]);
    }
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nacl_incnonce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  add    $0x1,%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L38
L15:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  jmp    L22
L38:
  nop
L22:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void nacl_incnonce(unsigned char *p, size_t len) {
  int i = len;
  for (; --i >= 0;) {
    if (++p[i] != 0)
      break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nacl_incnonce>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
L17:
  test   %esi,%esi
  js     L8
  movzbl (%rdi,%rsi,1),%eax
  add    $0x1,%eax
  mov    %al,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  test   %al,%al
  je     L17
L8:
  ret
```

assistant: ```c
void nacl_incnonce(unsigned char *p, size_t len) {
  int i = len;
  for (; --i >= 0;) {
    if (++p[i] != 0)
      break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nacl_incnonce>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
  jmp    L5
  nopl   0x0(%rax)
L8:
  movzbl (%rdi,%rsi,1),%eax
  add    $0x1,%eax
  mov    %al,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  test   %al,%al
  jne    L6
L5:
  test   %esi,%esi
  jns    L8
L6:
  ret
```

assistant: ```c
void nacl_incnonce(unsigned char *p, size_t len) {
  int i = len;
  for (; --i >= 0;) {
    if (++p[i] != 0)
      break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nacl_incnonce>:
  endbr64
  sub    $0x1,%esi
  movslq %esi,%rsi
  jmp    L16
  nopl   0x0(%rax)
L7:
  movzbl (%rdi,%rsi,1),%eax
  add    $0x1,%eax
  mov    %al,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  test   %al,%al
  jne    L19
L16:
  test   %esi,%esi
  jns    L7
L19:
  ret
```

assistant: ```c
void nacl_incnonce(unsigned char *p, size_t len) {
  int i = len;
  for (; --i >= 0;) {
    if (++p[i] != 0)
      break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xb,%r9d
  mov    $0x9,%r8d
  mov    $0x7,%ecx
  mov    $0x5,%edx
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <print_args@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  print_args(5, 3, 5, 7, 9, 11);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%r9d
  mov    $0x9,%r8d
  mov    $0x7,%ecx
  mov    $0x5,%edx
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <print_args@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_args(5, 3, 5, 7, 9, 11);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%r9d
  mov    $0x9,%r8d
  mov    $0x7,%ecx
  mov    $0x5,%edx
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <print_args@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_args(5, 3, 5, 7, 9, 11);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xb,%r9d
  mov    $0x9,%r8d
  mov    $0x7,%ecx
  mov    $0x5,%edx
  mov    $0x3,%esi
  mov    $0x5,%edi
  call   <print_args@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  print_args(5, 3, 5, 7, 9, 11);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L25:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L10
  mov    -0x4(%rbp),%eax
  jmp    L30
L10:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L25
  mov    $0xffffffff,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int search(char arr[], int start, int end, char value) {
  int i;
  for (i = start; i <= end; i++) {
    if (arr[i] == value) {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<search>:
  endbr64
  cmp    %edx,%esi
  jg     L25
  movslq %esi,%rsi
L23:
  mov    %esi,%eax
  cmp    %cl,(%rdi,%rsi,1)
  je     L29
  add    $0x1,%rsi
  cmp    %esi,%edx
  jge    L23
  mov    $0xffffffff,%eax
  ret
L25:
  mov    $0xffffffff,%eax
L29:
  ret
```

assistant: ```c
int search(char arr[], int start, int end, char value) {
  int i;
  for (i = start; i <= end; i++) {
    if (arr[i] == value) {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<search>:
  endbr64
  cmp    %edx,%esi
  jg     L36
  movslq %esi,%rsi
  jmp    L0
  nopl   (%rax)
L2:
  add    $0x1,%rsi
  cmp    %esi,%edx
  jl     L36
L0:
  mov    %esi,%eax
  cmp    %cl,(%rdi,%rsi,1)
  jne    L2
  ret
L36:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int search(char arr[], int start, int end, char value) {
  int i;
  for (i = start; i <= end; i++) {
    if (arr[i] == value) {
      return i;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<search>:
  endbr64
  cmp    %edx,%esi
  jg     L0
  movslq %esi,%rsi
  jmp    L22
  nopl   (%rax)
L15:
  add    $0x1,%rsi
  cmp    %esi,%edx
  jl     L0
L22:
  mov    %esi,%eax
  cmp    %cl,(%rdi,%rsi,1)
  jne    L15
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int search(char arr[], int start, int end, char value) {
  int i;
  for (i = start; i <= end; i++) {
    if (arr[i] == value) {
      return i;
    }
  }
  return -1;
}
```