ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mult_n>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    D23(%rip),%r13
  test   %edi,%edi
  jle    L6
L12:
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  imul   0x4(%rsp),%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jge    L12
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  lea    D11(%rip),%rdi
  call   <puts@plt>
  jmp    L8
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D23
datatype: string
name: extract_symbolic_data
arguments: data_tag: D22
datatype: string
name: extract_symbolic_data
arguments: data_tag: D11
datatype: string

tool: D23: %d

tool: D22: %d


tool: D11: 0

assistant: ```c
void mult_n(int n) {
  int total = 1, i, input;
  if (n <= 0) {
    printf("0\n");
    return;
  }
  for (i = 1; i <= n; i++) {
    scanf("%d", &input);
    total *= input;
  }
  printf("%d\n", total);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mult_n>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L15
  mov    %edi,%r12d
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    0x4(%rsp),%r14
  lea    D13(%rip),%r13
  nopl   (%rax)
L7:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  imul   0x4(%rsp),%ebp
  cmp    %ebx,%r12d
  jge    L7
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <puts@plt>
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D27
type_infered: string
name: disassemble_data
arguments: label: D2
type_infered: string

tool: D13: %d

tool: D27: %d


tool: D2: 0

assistant: ```c
void mult_n(int n) {
  int total = 1, i, input;
  if (n <= 0) {
    printf("0\n");
    return;
  }
  for (i = 1; i <= n; i++) {
    scanf("%d", &input);
    total *= input;
  }
  printf("%d\n", total);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mult_n>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L8
  mov    %edi,%r12d
  mov    $0x1,%ebx
  mov    $0x1,%ebp
  lea    0x4(%rsp),%r14
  lea    D27(%rip),%r13
  nopl   (%rax)
L32:
  mov    %r14,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  imul   0x4(%rsp),%ebp
  cmp    %ebx,%r12d
  jge    L32
  xor    %eax,%eax
  mov    %ebp,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  lea    D21(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <puts@plt>
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D27
type_infered: string
name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D21
type_infered: string

tool: D27: %d

tool: D14: %d


tool: D21: 0

assistant: ```c
void mult_n(int n) {
  int total = 1, i, input;
  if (n <= 0) {
    printf("0\n");
    return;
  }
  for (i = 1; i <= n; i++) {
    scanf("%d", &input);
    total *= input;
  }
  printf("%d\n", total);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L12
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D46(%rip),%r12
L22:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L22
L12:
  lea    D57(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%ecx
  sub    $0x1,%ecx
  js     L90
  mov    0xc(%rsp),%edi
  mov    $0x0,%esi
  jmp    L78
L86:
  add    $0x1,%edx
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L62
L1:
  lea    0x1(%rdx),%esi
L2:
  cmp    %esi,%ecx
  jl     L90
L78:
  lea    (%rsi,%rcx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  movslq %edx,%rax
  mov    0x10(%rsp,%rax,4),%eax
  cmp    %edi,%eax
  je     L86
  jle    L1
  lea    -0x1(%rdx),%ecx
  jmp    L2
L90:
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L62:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L70
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L70:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D31
type_infered: string
name: extract_symbolic_data
arguments: data_label: D46
type_infered: string
name: extract_symbolic_data
arguments: data_label: D35
type_infered: string
name: extract_symbolic_data
arguments: data_label: D57
type_infered: string
name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D50
type_infered: string

tool: D31: Enter the how mny nos......

tool: D46: %d

tool: D35: Enter the element in sorted order .......

tool: D57: Enter the searching element......

tool: D0: %d is in %d position


tool: D50: Not found

assistant: ```c
void main() {
  int i, a[10], n, src, flg = 1, lb, ub, mid;
  printf("Enter the how mny nos......\n");
  scanf("%d", &n);
  printf("Enter the element in sorted order .......\n");
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  printf("Enter the searching element......\n");
  scanf("%d", &src);
  lb = 0;
  ub = n - 1;
  while (lb <= ub) {
    mid = (lb + ub) / 2;
    if (a[mid] == src) {
      printf("%d is in %d position\n", src, mid + 1);
      flg = 0;
      break;
    } else if (src < a[mid])
      ub = mid - 1;
    else
      lb = mid + 1;
  }
  if (flg)
    printf("Not found");
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%rdi
  lea    D55(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D50(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L67
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L60
L67:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  js     L21
  mov    0xc(%rsp),%r8d
  xor    %ecx,%ecx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L5:
  lea    -0x1(%rdx),%eax
  cmp    %eax,%ecx
  jg     L21
L8:
  lea    (%rax,%rcx,1),%edx
  sar    %edx
  movslq %edx,%rsi
  cmp    %r8d,0x10(%rsp,%rsi,4)
  je     L84
  jg     L5
  lea    0x1(%rdx),%ecx
  cmp    %eax,%ecx
  jle    L8
L21:
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L94:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L84:
  add    $0x1,%edx
  mov    %r8d,%esi
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L94
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D55
type_infered: string
name: read_data
arguments: data_tag: D50
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D51
type_infered: string

tool: D29: Enter the how mny nos......

tool: D55: %d

tool: D50: Enter the element in sorted order .......

tool: D5: Enter the searching element......

tool: D21: Not found

tool: D51: %d is in %d position


assistant: ```c
void main() {
  int i, a[10], n, src, flg = 1, lb, ub, mid;
  printf("Enter the how mny nos......\n");
  scanf("%d", &n);
  printf("Enter the element in sorted order .......\n");
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  printf("Enter the searching element......\n");
  scanf("%d", &src);
  lb = 0;
  ub = n - 1;
  while (lb <= ub) {
    mid = (lb + ub) / 2;
    if (a[mid] == src) {
      printf("%d is in %d position\n", src, mid + 1);
      flg = 0;
      break;
    } else if (src < a[mid])
      ub = mid - 1;
    else
      lb = mid + 1;
  }
  if (flg)
    printf("Not found");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D46(%rip),%rdi
  lea    D54(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L2
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x8(%rsp)
  jg     L18
L2:
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  js     L22
  mov    0xc(%rsp),%r8d
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L38:
  lea    (%rax,%rcx,1),%edx
  sar    %edx
  movslq %edx,%rsi
  cmp    %r8d,0x10(%rsp,%rsi,4)
  je     L21
L73:
  jle    L69
  lea    -0x1(%rdx),%eax
  cmp    %ecx,%eax
  jge    L38
L22:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L46:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L69:
  lea    0x1(%rdx),%ecx
  cmp    %eax,%ecx
  jg     L22
  lea    (%rax,%rcx,1),%edx
  sar    %edx
  movslq %edx,%rsi
  cmp    %r8d,0x10(%rsp,%rsi,4)
  jne    L73
L21:
  add    $0x1,%edx
  mov    %r8d,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L46
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D46
datatype: string
name: read_data
arguments: data_label: D54
datatype: string
name: read_data
arguments: data_label: D4
datatype: string
name: read_data
arguments: data_label: D27
datatype: string
name: read_data
arguments: data_label: D11
datatype: string
name: read_data
arguments: data_label: D20
datatype: string

tool: D46: Enter the how mny nos......

tool: D54: %d

tool: D4: Enter the element in sorted order .......

tool: D27: Enter the searching element......

tool: D11: Not found

tool: D20: %d is in %d position


assistant: ```c
void main() {
  int i, a[10], n, src, flg = 1, lb, ub, mid;
  printf("Enter the how mny nos......\n");
  scanf("%d", &n);
  printf("Enter the element in sorted order .......\n");
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  printf("Enter the searching element......\n");
  scanf("%d", &src);
  lb = 0;
  ub = n - 1;
  while (lb <= ub) {
    mid = (lb + ub) / 2;
    if (a[mid] == src) {
      printf("%d is in %d position\n", src, mid + 1);
      flg = 0;
      break;
    } else if (src < a[mid])
      ub = mid - 1;
    else
      lb = mid + 1;
  }
  if (flg)
    printf("Not found");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ext_snpintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L4
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L4:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xd0(%rbp),%rsi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ext_snpintf(char *buffer, size_t buffer_size, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int res_len = vsnprintf(buffer, buffer_size, format, args);
  va_end(args);
  return res_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ext_snpintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int ext_snpintf(char *buffer, size_t buffer_size, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int res_len = vsnprintf(buffer, buffer_size, format, args);
  va_end(args);
  return res_len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ext_snpintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ext_snpintf(char *buffer, size_t buffer_size, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int res_len = vsnprintf(buffer, buffer_size, format, args);
  va_end(args);
  return res_len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ext_snpintf>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int ext_snpintf(char *buffer, size_t buffer_size, const char *format, ...) {
  va_list args;
  va_start(args, format);
  int res_len = vsnprintf(buffer, buffer_size, format, args);
  va_end(args);
  return res_len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<terminate_ui>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int terminate_ui(void) {
  endwin();
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<terminate_ui>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int terminate_ui(void) {
  endwin();
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<terminate_ui>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int terminate_ui(void) {
  endwin();
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<terminate_ui>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <endwin@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int terminate_ui(void) {
  endwin();
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<neos_rstrip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L2
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x0,-0x4(%rbp)
  js     L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L24
L23:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *neos_rstrip(char *s) {
  int n = strlen(s) - 1;
  while (n >= 0 && isspace(s[n])) {
    s[n] = '\0';
    n--;
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<neos_rstrip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L7
  movslq %ebx,%rbx
  add    %r12,%rbx
  movslq %eax,%rdx
  lea    -0x2(%r12,%rdx,1),%rbp
  lea    -0x1(%rax),%eax
  sub    %rax,%rbp
L0:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L0
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *neos_rstrip(char *s) {
  int n = strlen(s) - 1;
  while (n >= 0 && isspace(s[n])) {
    s[n] = '\0';
    n--;
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<neos_rstrip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L3
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  lea    -0x2(%r12,%rax,1),%rbp
  add    %r12,%rbx
  sub    %rdx,%rbp
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L20:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L3
L34:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L20
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *neos_rstrip(char *s) {
  int n = strlen(s) - 1;
  while (n >= 0 && isspace(s[n])) {
    s[n] = '\0';
    n--;
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<neos_rstrip>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L17
  cltq
  movslq %edx,%rbx
  mov    %edx,%edx
  lea    -0x2(%r12,%rax,1),%rbp
  add    %r12,%rbx
  sub    %rdx,%rbp
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L39:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L17
L14:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L39
L17:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *neos_rstrip(char *s) {
  int n = strlen(s) - 1;
  while (n >= 0 && isspace(s[n])) {
    s[n] = '\0';
    n--;
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<chkparam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chkparam() {
  if ((4 != 2) && (4 != 4))
    chk_err("chkparam: Width parameter is illegal.");
  if ((4 == 2) && (0x1EDC6F41L & 0xFFFF0000L))
    chk_err("chkparam: Poly parameter is too wide.");
  if ((1 != 0) && (1 != 1))
    chk_err("chkparam: Reverse parameter is not boolean.");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<chkparam>:
  endbr64
  ret
```

assistant: ```c
void chkparam() {
  if ((4 != 2) && (4 != 4))
    chk_err("chkparam: Width parameter is illegal.");
  if ((4 == 2) && (0x1EDC6F41L & 0xFFFF0000L))
    chk_err("chkparam: Poly parameter is too wide.");
  if ((1 != 0) && (1 != 1))
    chk_err("chkparam: Reverse parameter is not boolean.");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chkparam>:
  endbr64
  ret
```

assistant: ```c
void chkparam() {
  if ((4 != 2) && (4 != 4))
    chk_err("chkparam: Width parameter is illegal.");
  if ((4 == 2) && (0x1EDC6F41L & 0xFFFF0000L))
    chk_err("chkparam: Poly parameter is too wide.");
  if ((1 != 0) && (1 != 1))
    chk_err("chkparam: Reverse parameter is not boolean.");
}
```
user: Translate the below assembly code into C programming language:

```asm
<chkparam>:
  endbr64
  ret
```

assistant: ```c
void chkparam() {
  if ((4 != 2) && (4 != 4))
    chk_err("chkparam: Width parameter is illegal.");
  if ((4 == 2) && (0x1EDC6F41L & 0xFFFF0000L))
    chk_err("chkparam: Poly parameter is too wide.");
  if ((1 != 0) && (1 != 1))
    chk_err("chkparam: Reverse parameter is not boolean.");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<updateCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jle    L14
  cmpl   $0x6,-0x4(%rbp)
  jg     L14
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L14:
  cmpl   $0xa,-0x4(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L2:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: current count: %i


assistant: ```c
void updateCount(int val, int *count) {
  if ((val > 2) && (val < 7))
    (*count)++;
  if (val == 10)
    (*count)--;
  printf("current count: %i\n", *count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<updateCount>:
  endbr64
  sub    $0x8,%rsp
  lea    -0x3(%rdi),%eax
  cmp    $0x3,%eax
  ja     L19
  addl   $0x1,(%rsi)
L21:
  mov    (%rsi),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
L19:
  cmp    $0xa,%edi
  jne    L21
  subl   $0x1,(%rsi)
  jmp    L21
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: current count: %i


assistant: ```c
void updateCount(int val, int *count) {
  if ((val > 2) && (val < 7))
    (*count)++;
  if (val == 10)
    (*count)--;
  printf("current count: %i\n", *count);
}
```