ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D30(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <trueMain@plt>
  mov    $0x51,%esi
  lea    D58(%rip),%rdi
  mov    %eax,%ecx
  mov    %eax,%edx
  mov    %eax,%ebp
  call   <AMCPrintf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D30
datatype: string
name: disassemble_data
arguments: label: D51
datatype: string
name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D58
datatype: string
name: disassemble_data
arguments: label: D64
datatype: string

tool: D30: 
An application to test vfork and file handlers.


tool: D51: Version 0.0.1


tool: D18: Author: Andrew Chang


tool: D6: main() build time: 15:14:28, Mar 16 2022


tool: D27: ----START----


tool: D58: ##/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Andrew-M-C/Linux-Linux_Programming_Template/refs/heads/master/history/150701_vforkAndFds/main.c, %d: mainRet = 0x%x = %d


tool: D64: ----ENDS-----



assistant: ```c
int main(int argc, char *argv[]) {
  int mainRet;
  printf("\n"
         "An application to test vfork and file handlers."
         "\n");
  printf("Version "
         "0.0.1"
         "\n");
  printf("Author: "
         "Andrew Chang"
         "\n");
  printf("main() build time: "
         "15:14:28"
         ", "
         "Mar 16 2022"
         "\n");
  printf("----START----\n");
  mainRet = trueMain(argc, argv);
  AMCPrintf("##"
            "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Andrew-M-C/Linux-Linux_Programming_Template/refs/heads/master/history/150701_vforkAndFds/main.c"
            ", %d: "
            "mainRet"
            " = 0x%x = %d\n",
            81, (unsigned int)mainRet, mainRet);
  printf("----ENDS-----\n\n");
  exit(mainRet);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  lea    D33(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <trueMain@plt>
  mov    $0x51,%esi
  lea    D20(%rip),%rdi
  mov    %eax,%ecx
  mov    %eax,%edx
  mov    %eax,%ebp
  call   <AMCPrintf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D33
datatype: string
name: parse_data
arguments: data_tag: D41
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D55
datatype: string
name: parse_data
arguments: data_tag: D25
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D33: 
An application to test vfork and file handlers.


tool: D41: Version 0.0.1


tool: D7: Author: Andrew Chang


tool: D55: main() build time: 15:14:28, Mar 16 2022


tool: D25: ----START----


tool: D20: ##/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Andrew-M-C/Linux-Linux_Programming_Template/refs/heads/master/history/150701_vforkAndFds/main.c, %d: mainRet = 0x%x = %d


tool: D2: ----ENDS-----



assistant: ```c
int main(int argc, char *argv[]) {
  int mainRet;
  printf("\n"
         "An application to test vfork and file handlers."
         "\n");
  printf("Version "
         "0.0.1"
         "\n");
  printf("Author: "
         "Andrew Chang"
         "\n");
  printf("main() build time: "
         "15:14:28"
         ", "
         "Mar 16 2022"
         "\n");
  printf("----START----\n");
  mainRet = trueMain(argc, argv);
  AMCPrintf("##"
            "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Andrew-M-C/Linux-Linux_Programming_Template/refs/heads/master/history/150701_vforkAndFds/main.c"
            ", %d: "
            "mainRet"
            " = 0x%x = %d\n",
            81, (unsigned int)mainRet, mainRet);
  printf("----ENDS-----\n\n");
  exit(mainRet);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string

tool: D9: pthread_mutex_getprioceiling not supported

assistant: ```c
int main(void) {
  printf("pthread_mutex_getprioceiling not supported");
  return 4;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
data_type: string

tool: D1: pthread_mutex_getprioceiling not supported

assistant: ```c
int main(void) {
  printf("pthread_mutex_getprioceiling not supported");
  return 4;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string

tool: D9: pthread_mutex_getprioceiling not supported

assistant: ```c
int main(void) {
  printf("pthread_mutex_getprioceiling not supported");
  return 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: pthread_mutex_getprioceiling not supported

assistant: ```c
int main(void) {
  printf("pthread_mutex_getprioceiling not supported");
  return 4;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<stbi_write_bmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  lea    0x0(,%rax,4),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  and    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  imul   -0x20(%rbp),%eax
  lea    0x36(%rax),%esi
  mov    -0x24(%rbp),%r8d
  mov    -0x20(%rbp),%edi
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x18
  push   $0x1
  mov    -0x20(%rbp),%ecx
  push   %rcx
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  push   $0x28
  push   $0x36
  push   $0x0
  push   $0x0
  push   %rsi
  push   $0x4d
  push   $0x42
  lea    D5(%rip),%rcx
  push   %rcx
  mov    -0x4(%rbp),%ecx
  push   %rcx
  push   $0x0
  push   -0x30(%rbp)
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %edx,%ecx
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  mov    %rax,%rdi
  call   <outfile@plt>
  add    $0xb0,%rsp
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: 11 4 22 44 44 22 444444

assistant: ```c
int stbi_write_bmp(char *filename, int x, int y, int comp, void *data) {
  int pad = (-x * 3) & 3;
  return outfile(filename, -1, -1, x, y, comp, data, 0, pad,
                 "11 4 22 4"
                 "4 44 22 444444",
                 'B', 'M', 14 + 40 + (x * 3 + pad) * y, 0, 0, 14 + 40, 40, x, y, 1, 24, 0, 0, 0, 0, 0, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stbi_write_bmp>:
  endbr64
  sub    $0x10,%rsp
  mov    %esi,%eax
  mov    %ecx,%r9d
  lea    0x0(,%rsi,4),%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %eax,%r10d
  and    $0x3,%r10d
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x0
  push   $0x18
  push   $0x1
  push   %rdx
  push   %rax
  push   $0x28
  push   $0x36
  push   $0x0
  push   $0x0
  mov    %r10d,%esi
  sub    %ecx,%esi
  imul   %edx,%esi
  add    $0x36,%esi
  push   %rsi
  push   $0x4d
  push   $0x42
  lea    D2(%rip),%rcx
  push   %rcx
  push   %r10
  push   $0x0
  push   %r8
  mov    %edx,%r8d
  mov    %eax,%ecx
  mov    $0xffffffff,%edx
  mov    $0xffffffff,%esi
  call   <outfile@plt>
  add    $0xb8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: string

tool: D2: 11 4 22 44 44 22 444444

assistant: ```c
int stbi_write_bmp(char *filename, int x, int y, int comp, void *data) {
  int pad = (-x * 3) & 3;
  return outfile(filename, -1, -1, x, y, comp, data, 0, pad,
                 "11 4 22 4"
                 "4 44 22 444444",
                 'B', 'M', 14 + 40 + (x * 3 + pad) * y, 0, 0, 14 + 40, 40, x, y, 1, 24, 0, 0, 0, 0, 0, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<stbi_write_bmp>:
  endbr64
  mov    %esi,%r10d
  lea    0x0(,%rsi,4),%eax
  mov    %ecx,%r9d
  mov    %esi,%ecx
  and    $0x3,%esi
  sub    %eax,%ecx
  sub    $0x10,%rsp
  mov    %esi,%eax
  push   $0x0
  sub    %ecx,%eax
  push   $0x0
  mov    %r10d,%ecx
  imul   %edx,%eax
  push   $0x0
  push   $0x0
  push   $0x0
  add    $0x36,%eax
  push   $0x0
  push   $0x18
  push   $0x1
  push   %rdx
  push   %r10
  push   $0x28
  push   $0x36
  push   $0x0
  push   $0x0
  push   %rax
  lea    D1(%rip),%rax
  push   $0x4d
  push   $0x42
  push   %rax
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile@plt>
  add    $0xb8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: 11 4 22 44 44 22 444444

assistant: ```c
int stbi_write_bmp(char *filename, int x, int y, int comp, void *data) {
  int pad = (-x * 3) & 3;
  return outfile(filename, -1, -1, x, y, comp, data, 0, pad,
                 "11 4 22 4"
                 "4 44 22 444444",
                 'B', 'M', 14 + 40 + (x * 3 + pad) * y, 0, 0, 14 + 40, 40, x, y, 1, 24, 0, 0, 0, 0, 0, 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stbi_write_bmp>:
  endbr64
  mov    %esi,%r10d
  lea    0x0(,%rsi,4),%eax
  mov    %ecx,%r9d
  mov    %esi,%ecx
  and    $0x3,%esi
  sub    %eax,%ecx
  sub    $0x10,%rsp
  mov    %esi,%eax
  push   $0x0
  sub    %ecx,%eax
  push   $0x0
  mov    %r10d,%ecx
  imul   %edx,%eax
  push   $0x0
  push   $0x0
  push   $0x0
  add    $0x36,%eax
  push   $0x0
  push   $0x18
  push   $0x1
  push   %rdx
  push   %r10
  push   $0x28
  push   $0x36
  push   $0x0
  push   $0x0
  push   %rax
  lea    D6(%rip),%rax
  push   $0x4d
  push   $0x42
  push   %rax
  push   %rsi
  mov    $0xffffffff,%esi
  push   $0x0
  push   %r8
  mov    %edx,%r8d
  mov    $0xffffffff,%edx
  call   <outfile@plt>
  add    $0xb8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: 11 4 22 44 44 22 444444

assistant: ```c
int stbi_write_bmp(char *filename, int x, int y, int comp, void *data) {
  int pad = (-x * 3) & 3;
  return outfile(filename, -1, -1, x, y, comp, data, 0, pad,
                 "11 4 22 4"
                 "4 44 22 444444",
                 'B', 'M', 14 + 40 + (x * 3 + pad) * y, 0, 0, 14 + 40, 40, x, y, 1, 24, 0, 0, 0, 0, 0, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<stmt_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L18
L5:
  mov    $0x0,%eax
  call   <stmt@plt>
L18:
  mov    $0x0,%eax
  call   <is_stmt@plt>
  test   %rax,%rax
  jne    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void stmt_list() {
  while (is_stmt()) {
    stmt();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stmt_list>:
  endbr64
  sub    $0x8,%rsp
  jmp    L14
L4:
  mov    $0x0,%eax
  call   <stmt@plt>
L14:
  mov    $0x0,%eax
  call   <is_stmt@plt>
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stmt_list() {
  while (is_stmt()) {
    stmt();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stmt_list>:
  endbr64
  sub    $0x8,%rsp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <stmt@plt>
L17:
  xor    %eax,%eax
  call   <is_stmt@plt>
  test   %rax,%rax
  jne    L13
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stmt_list() {
  while (is_stmt()) {
    stmt();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stmt_list>:
  endbr64
  sub    $0x8,%rsp
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <stmt@plt>
L3:
  xor    %eax,%eax
  call   <is_stmt@plt>
  test   %rax,%rax
  jne    L17
  add    $0x8,%rsp
  ret
```

assistant: ```c
void stmt_list() {
  while (is_stmt()) {
    stmt();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<random_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    D93(%rip),%eax
  cmp    $0xffffffff,%eax
  jne    L64
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D42(%rip)
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D42(%rip)
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D95(%rip)
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D27(%rip)
L64:
  mov    D42(%rip),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L63
L3:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D42(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  lea    D42(%rip),%rdx
  mov    %eax,(%rcx,%rdx,1)
  addl   $0x1,-0xc(%rbp)
L63:
  cmpl   $0x3,-0xc(%rbp)
  jle    L3
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,D113(%rip)
  movl   $0x0,-0x8(%rbp)
  jmp    L58
L79:
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D42(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    D113(%rip),%eax
  cmp    %eax,%edx
  jne    L53
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x3,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,D113(%rip)
  jmp    L4
L53:
  addl   $0x1,-0xc(%rbp)
L31:
  cmpl   $0x2,-0xc(%rbp)
  jle    L0
L4:
  addl   $0x1,-0x8(%rbp)
L58:
  cmpl   $0x3,-0x8(%rbp)
  jle    L79
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int random_block() {
  static int queue[4] = {-1, -1, -1, -1};
  int current;
  int i, j;
  if (queue[0] == -1) {
    queue[0] = random_number(7);
    queue[1] = random_number(7);
    queue[2] = random_number(7);
    queue[3] = random_number(7);
  }
  current = queue[0];
  for (i = 0; i < 4; ++i) {
    queue[i] = queue[i + 1];
  }
  queue[3] = rand() % 7;
  for (j = 0; j < 4; ++j) {
    for (i = 0; i < 3; ++i) {
      if (queue[i] == queue[3]) {
        queue[3] = rand() % 7;
        break;
      }
    }
  }
  return current;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<random_block>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpl   $0xffffffff,D131(%rip)
  je     L43
L20:
  mov    D131(%rip),%ebp
  mov    D33(%rip),%eax
  mov    %eax,D92(%rip)
  mov    D92(%rip),%eax
  mov    %eax,D167(%rip)
  mov    D167(%rip),%eax
  mov    %eax,D69(%rip)
  mov    D69(%rip),%eax
  mov    %eax,D115(%rip)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,D115(%rip)
  mov    $0x4,%ebx
L3:
  mov    D115(%rip),%eax
  cmp    D92(%rip),%eax
  je     L13
  cmp    D167(%rip),%eax
  je     L13
  cmp    %eax,D115(%rip)
  je     L13
L48:
  sub    $0x1,%ebx
  jne    L3
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D115(%rip)
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D115(%rip)
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D115(%rip)
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    %eax,D115(%rip)
  jmp    L20
L13:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,D115(%rip)
  jmp    L48
```

assistant: ```c
int random_block() {
  static int queue[4] = {-1, -1, -1, -1};
  int current;
  int i, j;
  if (queue[0] == -1) {
    queue[0] = random_number(7);
    queue[1] = random_number(7);
    queue[2] = random_number(7);
    queue[3] = random_number(7);
  }
  current = queue[0];
  for (i = 0; i < 4; ++i) {
    queue[i] = queue[i + 1];
  }
  queue[3] = rand() % 7;
  for (j = 0; j < 4; ++j) {
    for (i = 0; i < 3; ++i) {
      if (queue[i] == queue[3]) {
        queue[3] = rand() % 7;
        break;
      }
    }
  }
  return current;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<random_block>:
  endbr64
  push   %r12
  mov    D116(%rip),%r12d
  push   %rbp
  push   %rbx
  cmp    $0xffffffff,%r12d
  je     L38
  mov    D115(%rip),%eax
L42:
  mov    D67(%rip),%edx
  lea    D116(%rip),%rbp
  mov    $0x4,%ebx
  mov    %edx,D21(%rip)
  mov    D21(%rip),%edx
  mov    %eax,D44(%rip)
  mov    D44(%rip),%eax
  mov    %edx,D95(%rip)
  mov    %eax,D95(%rip)
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff92492493,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,D95(%rip)
  mov    %eax,%edx
  cmp    %edx,0x0(%rbp)
  je     L53
L41:
  cmp    %edx,D95(%rip)
  je     L53
  cmp    %edx,D95(%rip)
  je     L53
  sub    $0x1,%ebx
  je     L52
L58:
  mov    D95(%rip),%edx
  cmp    %edx,0x0(%rbp)
  jne    L41
L53:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0xffffffff92492493,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sub    %ecx,%edx
  lea    0x0(,%rdx,8),%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,D95(%rip)
  sub    $0x1,%ebx
  jne    L58
L52:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L38:
  mov    $0x7,%edi
  call   <random_number@plt>
  mov    $0x7,%edi
  mov    %eax,D95(%rip)
  call   <random_number@plt>
  mov    $0x7,%edi
  mov    %eax,D95(%rip)
  call   <random_number@plt>
  mov    $0x7,%edi
  mov    %eax,D95(%rip)
  call   <random_number@plt>
  mov    D95(%rip),%r12d
  jmp    L42
```

assistant: ```c
int random_block() {
  static int queue[4] = {-1, -1, -1, -1};
  int current;
  int i, j;
  if (queue[0] == -1) {
    queue[0] = random_number(7);
    queue[1] = random_number(7);
    queue[2] = random_number(7);
    queue[3] = random_number(7);
  }
  current = queue[0];
  for (i = 0; i < 4; ++i) {
    queue[i] = queue[i + 1];
  }
  queue[3] = rand() % 7;
  for (j = 0; j < 4; ++j) {
    for (i = 0; i < 3; ++i) {
      if (queue[i] == queue[3]) {
        queue[3] = rand() % 7;
        break;
      }
    }
  }
  return current;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<linear_gradient>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  D2(%rip),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double linear_gradient(const double x) {
  (void)x;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<linear_gradient>:
  endbr64
  movsd  D9(%rip),%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double linear_gradient(const double x) {
  (void)x;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<linear_gradient>:
  endbr64
  movsd  D3(%rip),%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double linear_gradient(const double x) {
  (void)x;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<linear_gradient>:
  endbr64
  movsd  D1(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double linear_gradient(const double x) {
  (void)x;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printd@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <printd@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,%edi
  call   <printd@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
datatype: string
name: unpack_data
arguments: data_tag: D28
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string

tool: D4:  / 

tool: D28:  -> 

tool: D15: 


assistant: ```c
void div(int a, int b) {
  printd(a);
  print(" / ");
  printd(b);
  print(" -> ");
  printd(a / b);
  print("\r\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<div>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <printd@plt>
  lea    D10(%rip),%rdi
  call   <print@plt>
  mov    %ebp,%edi
  call   <printd@plt>
  lea    D20(%rip),%rdi
  call   <print@plt>
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%edi
  call   <printd@plt>
  lea    D17(%rip),%rdi
  call   <print@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D20
data_type: string
name: parse_data
arguments: label: D17
data_type: string

tool: D10:  / 

tool: D20:  -> 

tool: D17: 


assistant: ```c
void div(int a, int b) {
  printd(a);
  print(" / ");
  printd(b);
  print(" -> ");
  printd(a / b);
  print("\r\n");
}
```