ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3d0900,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x1,%eax
L0:
  mov    %eax,-0x4(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0xf4241,%rax
  jne    L0
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0xf4240,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%ebp
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edx
  mov    $0xf4240,%esi
  mov    %rbx,%rdi
  call   <linear_search@plt>
  mov    %eax,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edx
  mov    $0xf4240,%esi
  mov    %rbx,%rdi
  call   <binary_search@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D22
type: string
name: parse_data
arguments: data_label: D12
type: string

tool: D20: Element for search: %d


tool: D22: Found with linear search at position: %d


tool: D12: Found with binary search at position: %d


assistant: ```c
int main() {
  int i;
  int *a = malloc(sizeof(int) * 1000000);
  for (i = 0; i < 1000000; i++) {
    *(a + i) = i + 1;
  }
  srand(time(NULL));
  int key = rand() % 1000000 + 1;
  printf("Element for search: %d\n", key);
  int found = linear_search(a, 1000000, key);
  printf("Found with linear search at position: %d\n", found);
  found = binary_search(a, 1000000, key);
  printf("Found with binary search at position: %d\n", found);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3d0900,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x1,%eax
  nopl   (%rax)
L7:
  mov    %eax,-0x4(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0xf4241,%rax
  jne    L7
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D25(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x32,%rdx
  sub    %ecx,%edx
  imul   $0xf4240,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    $0xf4240,%esi
  call   <linear_search@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    $0xf4240,%esi
  call   <binary_search@plt>
  lea    D28(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D25: Element for search: %d


tool: D15: Found with linear search at position: %d


tool: D28: Found with binary search at position: %d


assistant: ```c
int main() {
  int i;
  int *a = malloc(sizeof(int) * 1000000);
  for (i = 0; i < 1000000; i++) {
    *(a + i) = i + 1;
  }
  srand(time(NULL));
  int key = rand() % 1000000 + 1;
  printf("Element for search: %d\n", key);
  int found = linear_search(a, 1000000, key);
  printf("Found with linear search at position: %d\n", found);
  found = binary_search(a, 1000000, key);
  printf("Found with binary search at position: %d\n", found);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3d0900,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  movdqa D45(%rip),%xmm1
  movdqa D4(%rip),%xmm3
  movdqa D47(%rip),%xmm2
  mov    %rax,%rbp
  lea    0x3d0900(%rax),%rdx
  nopw   0x0(%rax,%rax,1)
L6:
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L6
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D29(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x32,%rdx
  sub    %ecx,%edx
  imul   $0xf4240,%edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%r12d
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    $0xf4240,%esi
  call   <linear_search@plt>
  lea    D50(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    $0xf4240,%esi
  call   <binary_search@plt>
  lea    D38(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D45
type_guessed: byte[16]
name: read_data
arguments: data_tag: D4
type_guessed: byte[16]
name: read_data
arguments: data_tag: D47
type_guessed: byte[16]
name: read_data
arguments: data_tag: D29
type_guessed: string
name: read_data
arguments: data_tag: D50
type_guessed: string
name: read_data
arguments: data_tag: D38
type_guessed: string

tool: {"D45": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D4": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D47": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D29: Element for search: %d


tool: D50: Found with linear search at position: %d


tool: D38: Found with binary search at position: %d


assistant: ```c
int main() {
  int i;
  int *a = malloc(sizeof(int) * 1000000);
  for (i = 0; i < 1000000; i++) {
    *(a + i) = i + 1;
  }
  srand(time(NULL));
  int key = rand() % 1000000 + 1;
  printf("Element for search: %d\n", key);
  int found = linear_search(a, 1000000, key);
  printf("Found with linear search at position: %d\n", found);
  found = binary_search(a, 1000000, key);
  printf("Found with binary search at position: %d\n", found);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<writelines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  jne    L34
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <atof@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  jmp    L52
L34:
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L28:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L28
L52:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D13
type_infered: string

tool: D18: '%s', and %ld;


tool: D13: '%s', and %f;


assistant: ```c
void writelines(char *lineptr[], int nlines, int reverse) {
  int i = 0;
  if (!reverse) {
    for (i = 0; i < nlines; i++) {
      printf("'%s', and %ld;\n", lineptr[i], atof(lineptr[i]));
    }
  } else {
    for (i = 1; i <= nlines; i++) {
      printf("'%s', and %f;\n", lineptr[nlines - i], lineptr[nlines - i]);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<writelines>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  test   %edx,%edx
  je     L10
  test   %esi,%esi
  jle    L40
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbp
  mov    $0x1,%ebx
  lea    D15(%rip),%r13
L26:
  mov    -0x8(%rbp),%rsi
  mov    %rsi,%rdx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  sub    $0x8,%rbp
  cmp    %ebx,%r12d
  jge    L26
  jmp    L40
L10:
  test   %esi,%esi
  jle    L40
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D12(%rip),%rbp
L58:
  mov    (%rbx),%rdi
  mov    $0x0,%eax
  call   <atof@plt>
  mov    %eax,%edx
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L58
L40:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string

tool: D15: '%s', and %f;


tool: D12: '%s', and %ld;


assistant: ```c
void writelines(char *lineptr[], int nlines, int reverse) {
  int i = 0;
  if (!reverse) {
    for (i = 0; i < nlines; i++) {
      printf("'%s', and %ld;\n", lineptr[i], atof(lineptr[i]));
    }
  } else {
    for (i = 1; i <= nlines; i++) {
      printf("'%s', and %f;\n", lineptr[nlines - i], lineptr[nlines - i]);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writelines>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L48
  test   %esi,%esi
  jle    L45
  movslq %esi,%rax
  mov    $0x1,%ebx
  lea    D0(%rip),%r13
  lea    (%rdi,%rax,8),%rbp
  nopl   0x0(%rax)
L39:
  mov    -0x8(%rbp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  sub    $0x8,%rbp
  mov    %rsi,%rdx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jge    L39
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    D1(%rip),%rbp
  lea    0x8(%rdi,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    (%rbx),%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <atof@plt>
  mov    -0x8(%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L26
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string

tool: D0: '%s', and %f;


tool: D1: '%s', and %ld;


assistant: ```c
void writelines(char *lineptr[], int nlines, int reverse) {
  int i = 0;
  if (!reverse) {
    for (i = 0; i < nlines; i++) {
      printf("'%s', and %ld;\n", lineptr[i], atof(lineptr[i]));
    }
  } else {
    for (i = 1; i <= nlines; i++) {
      printf("'%s', and %f;\n", lineptr[nlines - i], lineptr[nlines - i]);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writelines>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L25
  test   %esi,%esi
  jle    L0
  movslq %esi,%rax
  mov    $0x1,%ebx
  lea    D8(%rip),%r13
  lea    (%rdi,%rax,8),%rbp
  nopl   0x0(%rax)
L14:
  mov    -0x8(%rbp),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  sub    $0x8,%rbp
  mov    %rsi,%rdx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jge    L14
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    D4(%rip),%rbp
  lea    0x8(%rdi,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    (%rbx),%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <atof@plt>
  mov    -0x8(%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L48
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string
name: read_data
arguments: data_tag: D4
type: string

tool: D8: '%s', and %f;


tool: D4: '%s', and %ld;


assistant: ```c
void writelines(char *lineptr[], int nlines, int reverse) {
  int i = 0;
  if (!reverse) {
    for (i = 0; i < nlines; i++) {
      printf("'%s', and %ld;\n", lineptr[i], atof(lineptr[i]));
    }
  } else {
    for (i = 1; i <= nlines; i++) {
      printf("'%s', and %f;\n", lineptr[nlines - i], lineptr[nlines - i]);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_and>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L12
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  and    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L10
L12:
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__bitmap_and@plt>
L10:
  nop
  leave
  ret
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitmap_and>:
  endbr64
  mov    D9(%rip),%rax
  cmp    %ecx,(%rax)
  jl     L8
  mov    (%rsi),%rax
  and    (%rdx),%rax
  mov    %rax,(%rdi)
  ret
L8:
  sub    $0x8,%rsp
  call   <__bitmap_and@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmap_and>:
  endbr64
  mov    D4(%rip),%rax
  cmp    %ecx,(%rax)
  jl     L4
  mov    (%rsi),%rax
  and    (%rdx),%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L4:
  jmp    1050 <__bitmap_and@plt>
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bitmap_and>:
  endbr64
  mov    D6(%rip),%rax
  cmp    %ecx,(%rax)
  jl     L0
  mov    (%rsi),%rax
  and    (%rdx),%rax
  mov    %rax,(%rdi)
  ret
  nopl   0x0(%rax)
L0:
  jmp    1050 <__bitmap_and@plt>
```

assistant: ```c
void bitmap_and(unsigned long *dst, const unsigned long *src1, const unsigned long *src2, int nbits) {
  if (nbits <= __WORDSIZE)
    *dst = *src1 & *src2;
  else
    __bitmap_and(dst, src1, src2, nbits);
}
```
user: What is the c source code of the assembly code below:

```asm
<B>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <A@plt>
  mov    %eax,%edi
  call   <func@plt>
  mov    $0x0,%eax
  call   <A@plt>
  mov    %eax,%esi
  mov    D0(%rip),%rax
  mov    %rax,%rdi
  call   <C@plt>
  pop    %rbp
  ret
```

assistant: ```c
int *B() {
  func(A());
  return C(func, A());
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<B>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <A@plt>
  mov    %eax,%edi
  call   <func@plt>
  mov    $0x0,%eax
  call   <A@plt>
  mov    %eax,%esi
  mov    D6(%rip),%rdi
  call   <C@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int *B() {
  func(A());
  return C(func, A());
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<B>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <A@plt>
  mov    %eax,%edi
  call   <func@plt>
  xor    %eax,%eax
  call   <A@plt>
  mov    D3(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1080 <C@plt>
```

assistant: ```c
int *B() {
  func(A());
  return C(func, A());
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<B>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <A@plt>
  mov    %eax,%edi
  call   <func@plt>
  xor    %eax,%eax
  call   <A@plt>
  mov    D6(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1080 <C@plt>
```

assistant: ```c
int *B() {
  func(A());
  return C(func, A());
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <set>
  jmp    L3
L13:
  mov    -0x10(%rbp),%rax
  movl   $0xd,(%rax)
L3:
  nop
  leave
  ret
```

assistant: ```c
void set(int *n, int *x) {
  if (!x) {
    x = n;
    set(n, x);
  } else
    *x = 13;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set>:
  endbr64
  test   %rsi,%rsi
  je     L9
  movl   $0xd,(%rsi)
  ret
L9:
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  call   <set>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void set(int *n, int *x) {
  if (!x) {
    x = n;
    set(n, x);
  } else
    *x = 13;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set>:
  endbr64
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rsi
L7:
  test   %rsi,%rsi
  je     L9
  movl   $0xd,(%rsi)
  ret
```

assistant: ```c
void set(int *n, int *x) {
  if (!x) {
    x = n;
    set(n, x);
  } else
    *x = 13;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<set>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %rdi,%rsi
L12:
  test   %rsi,%rsi
  je     L9
  movl   $0xd,(%rsi)
  ret
```

assistant: ```c
void set(int *n, int *x) {
  if (!x) {
    x = n;
    set(n, x);
  } else
    *x = 13;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UI_write_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1a,%edx
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,D15(%rip)
  mov    $0x0,%eax
  call   <DISPLAY_get_line_capacity@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <DISPLAY_get_line_insert_index@plt>
  cmp    %rax,%rbx
  jne    L2
  mov    $0x0,%eax
  call   <DISPLAY_clear@plt>
L2:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <DISPLAY_output@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void UI_write_line(char *line) {
  static char out[27];
  strncpy(out, line, 26);
  out[26] = '\0';
  if (DISPLAY_get_line_capacity() == DISPLAY_get_line_insert_index())
    DISPLAY_clear();
  DISPLAY_output(out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UI_write_line>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  mov    $0x1a,%edx
  lea    D7(%rip),%rdi
  call   <strncpy@plt>
  movb   $0x0,D14(%rip)
  mov    $0x0,%eax
  call   <DISPLAY_get_line_capacity@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <DISPLAY_get_line_insert_index@plt>
  cmp    %rax,%rbx
  je     L5
L18:
  lea    D7(%rip),%rdi
  call   <DISPLAY_output@plt>
  pop    %rbx
  ret
L5:
  mov    $0x0,%eax
  call   <DISPLAY_clear@plt>
  jmp    L18
```

assistant: ```c
void UI_write_line(char *line) {
  static char out[27];
  strncpy(out, line, 26);
  out[26] = '\0';
  if (DISPLAY_get_line_capacity() == DISPLAY_get_line_insert_index())
    DISPLAY_clear();
  DISPLAY_output(out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UI_write_line>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rdi,%rsi
  mov    $0x1a,%edx
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strncpy@plt>
  xor    %eax,%eax
  movb   $0x0,D6(%rip)
  call   <DISPLAY_get_line_capacity@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <DISPLAY_get_line_insert_index@plt>
  cmp    %rax,%rbx
  je     L4
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <DISPLAY_output@plt>
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <DISPLAY_clear@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <DISPLAY_output@plt>
```

assistant: ```c
void UI_write_line(char *line) {
  static char out[27];
  strncpy(out, line, 26);
  out[26] = '\0';
  if (DISPLAY_get_line_capacity() == DISPLAY_get_line_insert_index())
    DISPLAY_clear();
  DISPLAY_output(out);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UI_write_line>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rdi,%rsi
  mov    $0x1a,%edx
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <strncpy@plt>
  xor    %eax,%eax
  movb   $0x0,D17(%rip)
  call   <DISPLAY_get_line_capacity@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <DISPLAY_get_line_insert_index@plt>
  cmp    %rax,%rbx
  je     L0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <DISPLAY_output@plt>
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <DISPLAY_clear@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10a0 <DISPLAY_output@plt>
```

assistant: ```c
void UI_write_line(char *line) {
  static char out[27];
  strncpy(out, line, 26);
  out[26] = '\0';
  if (DISPLAY_get_line_capacity() == DISPLAY_get_line_insert_index())
    DISPLAY_clear();
  DISPLAY_output(out);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ShouldTerminate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jb     L5
  mov    $0x1,%eax
  jmp    L2
L5:
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int ShouldTerminate(double number) {
  if (number <= 0.0) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ShouldTerminate>:
  endbr64
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  setae  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ShouldTerminate(double number) {
  if (number <= 0.0) {
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ShouldTerminate>:
  endbr64
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  setae  %al
  ret
```

assistant: ```c
int ShouldTerminate(double number) {
  if (number <= 0.0) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ShouldTerminate>:
  endbr64
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  setae  %al
  ret
```

assistant: ```c
int ShouldTerminate(double number) {
  if (number <= 0.0) {
    return 1;
  }
  return 0;
}
```