ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  xor    %esi,%esi
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rdi
  lea    D23(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string

tool: D10: i = %d, 

tool: D23: j = %d


tool: D27: new

assistant: ```c
int main(void) {
  int i;
  int j;
  for (j = 0; j < 5; j++) {
    for (i = 0; i < 5; i++) {
      printf("i = %d, ", i);
      printf("j = %d\n", j);
      if (i == 1) {
        goto new;
      }
      if (i == 2) {
        goto end;
      }
    }
  }
  new : printf("new\n");
  return 1;
end:
  printf("end\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  movzwl %ax,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  or     %edx,%eax
  leave
  ret
```

assistant: ```c
int get32(void) {
  int b1 = getchar();
  int b2 = getchar();
  int b3 = getchar();
  int b4 = getchar();
  return ((b1 << 24) & 0xff000000) | ((b2 << 16) & 0xff0000) | ((b3 << 8) & 0xff00) | (b4 & 0xff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  shl    $0x18,%ebx
  movzbl %al,%eax
  or     %ebx,%eax
  shl    $0x10,%r12d
  and    $0xff0000,%r12d
  or     %r12d,%eax
  shl    $0x8,%ebp
  movzwl %bp,%ebp
  or     %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get32(void) {
  int b1 = getchar();
  int b2 = getchar();
  int b3 = getchar();
  int b4 = getchar();
  return ((b1 << 24) & 0xff000000) | ((b2 << 16) & 0xff0000) | ((b3 << 8) & 0xff00) | (b4 & 0xff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get32>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <getchar@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  shl    $0x18,%ebx
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getchar@plt>
  shl    $0x10,%r12d
  mov    %eax,%ebp
  xor    %eax,%eax
  and    $0xff0000,%r12d
  call   <getchar@plt>
  shl    $0x8,%ebp
  movzbl %al,%eax
  movzwl %bp,%ebp
  or     %ebx,%eax
  pop    %rbx
  or     %r12d,%eax
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get32(void) {
  int b1 = getchar();
  int b2 = getchar();
  int b3 = getchar();
  int b4 = getchar();
  return ((b1 << 24) & 0xff000000) | ((b2 << 16) & 0xff0000) | ((b3 << 8) & 0xff00) | (b4 & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get32>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <getchar@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  shl    $0x18,%ebx
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getchar@plt>
  shl    $0x10,%r12d
  mov    %eax,%ebp
  xor    %eax,%eax
  and    $0xff0000,%r12d
  call   <getchar@plt>
  shl    $0x8,%ebp
  movzbl %al,%eax
  movzwl %bp,%ebp
  or     %ebx,%eax
  pop    %rbx
  or     %r12d,%eax
  or     %ebp,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int get32(void) {
  int b1 = getchar();
  int b2 = getchar();
  int b3 = getchar();
  int b4 = getchar();
  return ((b1 << 24) & 0xff000000) | ((b2 << 16) & 0xff0000) | ((b3 << 8) & 0xff00) | (b4 & 0xff);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  fldt   0xee2(%rip)        # 2010 <_fini+0xebc>
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  movss  D18(%rip),%xmm1
  movq   %rax,%xmm0
  call   <test@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: f64
name: extract_symbolic_data
arguments: tag: D18
data_type: byte[4]

tool: D0: 3

tool: {"D18": [0x00,0x00,0x40,0x40]}

assistant: ```c
int main() {
  test(3.0, 3.0F, 3.0L);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  flds   0xee1(%rip)        # 2008 <_fini+0xeb4>
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  movss  D11(%rip),%xmm1
  movsd  D6(%rip),%xmm0
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
datatype: f32
name: parse_data
arguments: data_tag: D6
datatype: byte[8]

tool: D11: 3

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
int main() {
  test(3.0, 3.0F, 3.0L);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  flds   0xf9a(%rip)        # 2008 <_fini+0xeac>
  movss  D16(%rip),%xmm1
  movsd  D6(%rip),%xmm0
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
data_type: f32
name: retrieve_data
arguments: data_tag: D6
data_type: byte[8]

tool: D16: 3

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
int main() {
  test(3.0, 3.0F, 3.0L);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  flds   0xf9a(%rip)        # 2008 <_fini+0xeac>
  movss  D14(%rip),%xmm1
  movsd  D11(%rip),%xmm0
  fstpt  (%rsp)
  mov    (%rsp),%rax
  mov    0x8(%rsp),%edx
  push   %rdx
  push   %rax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D14
datatype: f32
name: unpack_data
arguments: label: D11
datatype: byte[8]

tool: D14: 3

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

assistant: ```c
int main() {
  test(3.0, 3.0F, 3.0L);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MyGemm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x20(%rbp)
  mov    %r9,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L18:
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L9:
  mov    -0x8(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  imul   0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int i = 0; i < m; i++)
    for (int j = 0; j < n; j++)
      for (int p = 0; p < k; p++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x4(%rsp)
  mov    0x40(%rsp),%r14
  test   %edi,%edi
  jle    L73
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rcx,%r11
  mov    %r8d,%eax
  mov    %r9,%r12
  cltq
  lea    0x0(,%rax,8),%rdi
  mov    $0x0,%r15d
  lea    -0x1(%rdx),%eax
  mov    %rax,-0x10(%rsp)
  lea    0x8(%r9),%r13
  jmp    L22
L40:
  movslq %r10d,%rax
  lea    (%r14,%rax,8),%rcx
  movslq %r9d,%rdx
  lea    (%r12,%rdx,8),%rax
  add    -0x10(%rsp),%rdx
  lea    0x0(%r13,%rdx,8),%rsi
  mov    %r11,%rdx
L25:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    %rdi,%rdx
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L25
L3:
  add    $0x1,%r8d
  add    0x38(%rsp),%r9d
  add    0x48(%rsp),%r10d
  cmp    %r8d,%ebx
  je     L1
L39:
  test   %ebp,%ebp
  jg     L40
  jmp    L3
L1:
  add    $0x1,%r15d
  add    $0x8,%r11
  cmp    %r15d,-0x4(%rsp)
  je     L73
L22:
  test   %ebx,%ebx
  jle    L1
  mov    %r15d,%r10d
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  jmp    L39
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int i = 0; i < m; i++)
    for (int j = 0; j < n; j++)
      for (int p = 0; p < k; p++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r12d
  mov    0x48(%rsp),%r13d
  mov    %edi,-0x4(%rsp)
  test   %edi,%edi
  jle    L50
  movslq %r8d,%rax
  movl   $0x0,-0x8(%rsp)
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    0x0(,%rax,8),%rdi
  lea    0x8(%r9),%rax
  mov    %rcx,%r11
  mov    %r9,%r14
  mov    %rax,-0x10(%rsp)
  lea    -0x1(%rdx),%r15d
  xchg   %ax,%ax
L23:
  test   %ebx,%ebx
  jle    L27
  mov    -0x8(%rsp),%r10d
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nop
L39:
  test   %ebp,%ebp
  jle    L28
  mov    0x40(%rsp),%rsi
  movslq %r10d,%rax
  movslq %r9d,%rdx
  lea    (%rsi,%rax,8),%rcx
  mov    -0x10(%rsp),%rsi
  lea    (%r14,%rdx,8),%rax
  add    %r15,%rdx
  movsd  (%rcx),%xmm1
  lea    (%rsi,%rdx,8),%rsi
  mov    %r11,%rdx
  nopw   0x0(%rax,%rax,1)
L45:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L45
L28:
  add    $0x1,%r8d
  add    %r12d,%r9d
  add    %r13d,%r10d
  cmp    %r8d,%ebx
  jne    L39
L27:
  addl   $0x1,-0x8(%rsp)
  add    $0x8,%r11
  mov    -0x8(%rsp),%eax
  cmp    %eax,-0x4(%rsp)
  jne    L23
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int i = 0; i < m; i++)
    for (int j = 0; j < n; j++)
      for (int p = 0; p < k; p++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MyGemm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x40(%rsp),%r15
  test   %r13d,%r13d
  jle    L13
  mov    %esi,%r10d
  test   %esi,%esi
  jle    L13
  test   %edx,%edx
  jle    L13
  movslq 0x48(%rsp),%rbp
  movslq 0x38(%rsp),%rbx
  sub    $0x1,%edx
  mov    %rcx,%rsi
  shl    $0x3,%rdx
  mov    %r9,%rcx
  movslq %r8d,%rax
  mov    %rsi,%r9
  shl    $0x3,%rbp
  shl    $0x3,%rbx
  lea    0x8(%rcx,%rdx,1),%r14
  xor    %r12d,%r12d
  mov    $0xfffffffffffffff8,%r11
  lea    0x0(,%rax,8),%rdi
  sub    %rdx,%r11
  nopl   0x0(%rax)
L40:
  lea    (%r15,%r12,8),%rsi
  mov    %r14,%rcx
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L20:
  movsd  (%rsi),%xmm1
  lea    (%r11,%rcx,1),%rax
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L44:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%rcx
  jne    L44
  add    $0x1,%r8d
  add    %rbp,%rsi
  add    %rbx,%rcx
  cmp    %r8d,%r10d
  jne    L20
  add    $0x1,%r12
  add    $0x8,%r9
  cmp    %r13,%r12
  jne    L40
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MyGemm(int m, int n, int k, double *A, int ldA, double *B, int ldB, double *C, int ldC) {
  for (int i = 0; i < m; i++)
    for (int j = 0; j < n; j++)
      for (int p = 0; p < k; p++)
        C[(j)*ldC + i] += A[(p)*ldA + i] * B[(j)*ldB + p];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<myrandmod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x1,-0x14(%rbp)
  ja     L13
  mov    $0x0,%eax
  jmp    L53
L13:
  mov    $0x0,%eax
  call   <myrand@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x10000,-0x14(%rbp)
  ja     L10
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzwl %ax,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
L10:
  cmpl   $0x100,-0x14(%rbp)
  ja     L9
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
L9:
  cmpl   $0x10,-0x14(%rbp)
  ja     L41
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
L41:
  cmpl   $0x4,-0x14(%rbp)
  ja     L42
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  xor    %edx,%eax
  mov    %eax,-0x4(%rbp)
L42:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x14(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L53:
  leave
  ret
```

assistant: ```c
unsigned myrandmod(unsigned mod) {
  unsigned res;
  assert(mod >= 1);
  if (mod <= 1)
    return 0;
  res = myrand();
  if (mod <= 65536)
    res = (res >> 16) ^ (res & 65535);
  if (mod <= 256)
    res = (res >> 8) ^ (res & 255);
  if (mod <= 16)
    res = (res >> 4) ^ (res & 15);
  if (mod <= 4)
    res = (res >> 2) ^ (res & 3);
  res %= mod;
  return res;
}
```
user: What is the c source code of the assembly code below?

```asm
<myrandmod>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edx
  cmp    $0x1,%ebx
  jbe    L20
  mov    $0x0,%eax
  call   <myrand@plt>
  cmp    $0x10000,%ebx
  ja     L43
  mov    %eax,%edx
  shr    $0x10,%edx
  movzwl %ax,%eax
  xor    %edx,%eax
L43:
  cmp    $0x100,%ebx
  ja     L37
  mov    %eax,%edx
  shr    $0x8,%edx
  movzbl %al,%eax
  xor    %edx,%eax
L37:
  cmp    $0x10,%ebx
  ja     L49
  mov    %eax,%edx
  shr    $0x4,%edx
  and    $0xf,%eax
  xor    %edx,%eax
L49:
  cmp    $0x4,%ebx
  ja     L32
  mov    %eax,%edx
  shr    $0x2,%edx
  and    $0x3,%eax
  xor    %edx,%eax
L32:
  mov    $0x0,%edx
  div    %ebx
L20:
  mov    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned myrandmod(unsigned mod) {
  unsigned res;
  assert(mod >= 1);
  if (mod <= 1)
    return 0;
  res = myrand();
  if (mod <= 65536)
    res = (res >> 16) ^ (res & 65535);
  if (mod <= 256)
    res = (res >> 8) ^ (res & 255);
  if (mod <= 16)
    res = (res >> 4) ^ (res & 15);
  if (mod <= 4)
    res = (res >> 2) ^ (res & 3);
  res %= mod;
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myrandmod>:
  endbr64
  test   %edi,%edi
  push   %rbx
  mov    %edi,%ebx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %r8d,%r8d
  cmp    $0x1,%ebx
  jbe    L35
  xor    %eax,%eax
  call   <myrand@plt>
  cmp    $0x10000,%ebx
  ja     L2
  mov    %eax,%edx
  movzwl %ax,%eax
  shr    $0x10,%edx
  xor    %edx,%eax
L2:
  cmp    $0x100,%ebx
  ja     L41
  mov    %eax,%edx
  movzbl %al,%eax
  shr    $0x8,%edx
  xor    %edx,%eax
L41:
  cmp    $0x10,%ebx
  ja     L50
  mov    %eax,%edx
  and    $0xf,%eax
  shr    $0x4,%edx
  xor    %edx,%eax
L50:
  cmp    $0x4,%ebx
  jbe    L0
L24:
  xor    %edx,%edx
  div    %ebx
  mov    %edx,%r8d
L35:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  mov    %eax,%edx
  and    $0x3,%eax
  shr    $0x2,%edx
  xor    %edx,%eax
  jmp    L24
```

assistant: ```c
unsigned myrandmod(unsigned mod) {
  unsigned res;
  assert(mod >= 1);
  if (mod <= 1)
    return 0;
  res = myrand();
  if (mod <= 65536)
    res = (res >> 16) ^ (res & 65535);
  if (mod <= 256)
    res = (res >> 8) ^ (res & 255);
  if (mod <= 16)
    res = (res >> 4) ^ (res & 15);
  if (mod <= 4)
    res = (res >> 2) ^ (res & 3);
  res %= mod;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<myrandmod>:
  endbr64
  test   %edi,%edi
  push   %rbx
  mov    %edi,%ebx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %r8d,%r8d
  cmp    $0x1,%ebx
  jbe    L49
  xor    %eax,%eax
  call   <myrand@plt>
  cmp    $0x10000,%ebx
  ja     L15
  mov    %eax,%edx
  movzwl %ax,%eax
  shr    $0x10,%edx
  xor    %edx,%eax
L15:
  cmp    $0x100,%ebx
  ja     L46
  mov    %eax,%edx
  movzbl %al,%eax
  shr    $0x8,%edx
  xor    %edx,%eax
L46:
  cmp    $0x10,%ebx
  ja     L7
  mov    %eax,%edx
  and    $0xf,%eax
  shr    $0x4,%edx
  xor    %edx,%eax
L7:
  cmp    $0x4,%ebx
  jbe    L40
L9:
  xor    %edx,%edx
  div    %ebx
  mov    %edx,%r8d
L49:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L40:
  mov    %eax,%edx
  and    $0x3,%eax
  shr    $0x2,%edx
  xor    %edx,%eax
  jmp    L9
```

assistant: ```c
unsigned myrandmod(unsigned mod) {
  unsigned res;
  assert(mod >= 1);
  if (mod <= 1)
    return 0;
  res = myrand();
  if (mod <= 65536)
    res = (res >> 16) ^ (res & 65535);
  if (mod <= 256)
    res = (res >> 8) ^ (res & 255);
  if (mod <= 16)
    res = (res >> 4) ^ (res & 15);
  if (mod <= 4)
    res = (res >> 2) ^ (res & 3);
  res %= mod;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cr_has_byte_in_string_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L23
L39:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  movsbl -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cr_has_byte_in_string@plt>
  test   %rax,%rax
  je     L30
  mov    $0x1,%eax
  jmp    L1
L30:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L39
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int cr_has_byte_in_string_array(char byte, char *argv[], int argc) {
  int x;
  for (x = 1; x < argc; ++x) {
    if (cr_has_byte_in_string(byte, argv[x])) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cr_has_byte_in_string_array>:
  endbr64
  cmp    $0x1,%edx
  jle    L8
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdx),%eax
  lea    0x10(%rsi,%rax,8),%r12
  movsbl %dil,%ebp
L7:
  mov    (%rbx),%rsi
  mov    %ebp,%edi
  call   <cr_has_byte_in_string@plt>
  test   %rax,%rax
  jne    L19
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L7
  jmp    L3
L8:
  mov    $0x0,%eax
  ret
L19:
  mov    $0x1,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cr_has_byte_in_string_array(char byte, char *argv[], int argc) {
  int x;
  for (x = 1; x < argc; ++x) {
    if (cr_has_byte_in_string(byte, argv[x])) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cr_has_byte_in_string_array>:
  endbr64
  cmp    $0x1,%edx
  jle    L16
  lea    -0x2(%rdx),%eax
  push   %r12
  lea    0x10(%rsi,%rax,8),%r12
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  lea    0x8(%rsi),%rbx
  jmp    L4
  nop
L39:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L27
L4:
  mov    (%rbx),%rsi
  mov    %ebp,%edi
  call   <cr_has_byte_in_string@plt>
  test   %rax,%rax
  je     L39
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cr_has_byte_in_string_array(char byte, char *argv[], int argc) {
  int x;
  for (x = 1; x < argc; ++x) {
    if (cr_has_byte_in_string(byte, argv[x])) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cr_has_byte_in_string_array>:
  endbr64
  cmp    $0x1,%edx
  jle    L39
  lea    -0x2(%rdx),%eax
  push   %r12
  lea    0x10(%rsi,%rax,8),%r12
  push   %rbp
  movsbl %dil,%ebp
  push   %rbx
  lea    0x8(%rsi),%rbx
  jmp    L15
  nop
L4:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L11
L15:
  mov    (%rbx),%rsi
  mov    %ebp,%edi
  call   <cr_has_byte_in_string@plt>
  test   %rax,%rax
  je     L4
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int cr_has_byte_in_string_array(char byte, char *argv[], int argc) {
  int x;
  for (x = 1; x < argc; ++x) {
    if (cr_has_byte_in_string(byte, argv[x])) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<vector3d_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x2,-0x4(%rbp)
  jle    L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vector3d_add(double u[3], double v[3], double w[3]) {
  int i;
  for (i = 0; i < 3; i++)
    u[i] = v[i] + w[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vector3d_add>:
  endbr64
  mov    $0x0,%eax
L9:
  movsd  (%rsi,%rax,1),%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L9
  ret
```

assistant: ```c
void vector3d_add(double u[3], double v[3], double w[3]) {
  int i;
  for (i = 0; i < 3; i++)
    u[i] = v[i] + w[i];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vector3d_add>:
  endbr64
  xor    %eax,%eax
L4:
  movsd  (%rsi,%rax,1),%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L4
  ret
```

assistant: ```c
void vector3d_add(double u[3], double v[3], double w[3]) {
  int i;
  for (i = 0; i < 3; i++)
    u[i] = v[i] + w[i];
}
```