user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_subset_of>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L175
  mov    $0x0,%eax
  jmp    L170
L175:
  cmpl   $0x9,-0x30(%rbp)
  jg     L21
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L17
  mov    $0x0,%eax
  jmp    L170
L17:
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L63
L166:
  mov    -0x10(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  je     L64
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L129
L64:
  mov    $0x0,%eax
  jmp    L170
L129:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L193
  addl   $0x1,-0x10(%rbp)
  jmp    L166
L193:
  nop
  addl   $0x1,-0x14(%rbp)
L63:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L166
  mov    $0x1,%eax
  jmp    L170
L21:
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L95
L54:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
  jmp    L81
L115:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L152
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L81
L152:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L81:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L115
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L7
  mov    $0x0,%eax
  jmp    L170
L7:
  addl   $0x1,-0x14(%rbp)
L95:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L54
  mov    $0x1,%eax
L170:
  pop    %rbp
  ret
```

assistant: ```c
extern int is_subset_of(const int *a, const int a_cnt, const int *b, const int b_cnt) {
  if (a_cnt > b_cnt)
    return 0;
  int i;
  if (b_cnt < 10) {
    if (a_cnt > b_cnt)
      return 0;
    int j = 0;
    for (i = 0; i < a_cnt; i++)
      for (;; j++)
        if (j == b_cnt || b[j] > a[i])
          return 0;
        else if (a[i] == b[j])
          break;
    return 1;
  } else {
    int mid, high;
    int low = -1;
    for (i = 0; i < a_cnt; i++) {
      high = b_cnt - 1;
      low++;
      while (low < high) {
        mid = (low + high) / 2;
        if (b[mid] < a[i])
          low = mid + 1;
        else
          high = mid;
      }
      if (b[low] != a[i])
        return 0;
    }
    return 1;
  }
}
```