ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<cvector_dot>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L10:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L11:
  movapd %xmm1,%xmm0
  ret
L0:
  pxor   %xmm1,%xmm1
  jmp    L11
```

assistant: ```c
double cvector_dot(const double *a, const double *b, int n) {
  double sum = 0.0;
  for (int i = 0; i < n; i++) {
    sum += a[i] * b[i];
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cvector_dot>:
  endbr64
  test   %edx,%edx
  jle    L4
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L12:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L12
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L4:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double cvector_dot(const double *a, const double *b, int n) {
  double sum = 0.0;
  for (int i = 0; i < n; i++) {
    sum += a[i] * b[i];
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cvector_dot>:
  endbr64
  test   %edx,%edx
  jle    L48
  cmp    $0x1,%edx
  je     L11
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L28:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L28
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L45
L36:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L45:
  ret
  nopl   0x0(%rax)
L48:
  pxor   %xmm0,%xmm0
  ret
L11:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L36
```

assistant: ```c
double cvector_dot(const double *a, const double *b, int n) {
  double sum = 0.0;
  for (int i = 0; i < n; i++) {
    sum += a[i] * b[i];
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<mi_strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mi_strncpy(char *Buffer, char *StringToCopy, int NumberOfCharsToCopy) {
  int index = 0;
  for (int i = 0; i < NumberOfCharsToCopy; i++) {
    Buffer[index] = StringToCopy[i];
    index++;
  }
  Buffer[index] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mi_strncpy>:
  endbr64
  test   %edx,%edx
  jle    L7
  mov    %edx,%r8d
  mov    $0x0,%eax
L19:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L19
L29:
  movslq %edx,%rdx
  movb   $0x0,(%rdi,%rdx,1)
  ret
L7:
  mov    $0x0,%edx
  jmp    L29
```

assistant: ```c
void mi_strncpy(char *Buffer, char *StringToCopy, int NumberOfCharsToCopy) {
  int index = 0;
  for (int i = 0; i < NumberOfCharsToCopy; i++) {
    Buffer[index] = StringToCopy[i];
    index++;
  }
  Buffer[index] = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mi_strncpy>:
  endbr64
  test   %edx,%edx
  jle    L9
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L19:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L19
  add    %rax,%rdi
L9:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void mi_strncpy(char *Buffer, char *StringToCopy, int NumberOfCharsToCopy) {
  int index = 0;
  for (int i = 0; i < NumberOfCharsToCopy; i++) {
    Buffer[index] = StringToCopy[i];
    index++;
  }
  Buffer[index] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mi_strncpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L85
  lea    0x1(%rsi),%r9
  mov    %edx,%r8d
  lea    -0x1(%rdx),%eax
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L100
  cmp    $0x6,%eax
  jbe    L100
  cmp    $0xe,%eax
  jbe    L115
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L37:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L37
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L65
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L93
L79:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rcx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L65
L93:
  movslq %eax,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L65
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L65
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L65
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L65
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L65
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L65
  cltq
  movzbl (%rsi,%rax,1),%esi
  mov    %sil,(%rcx,%rax,1)
L65:
  movslq %edx,%rdx
  add    %rdx,%rcx
L85:
  movb   $0x0,(%rcx)
  ret
  nopl   0x0(%rax)
L100:
  mov    %edx,%r8d
  xor    %eax,%eax
  nopl   (%rax)
L5:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L5
  jmp    L65
L115:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L79
```

assistant: ```c
void mi_strncpy(char *Buffer, char *StringToCopy, int NumberOfCharsToCopy) {
  int index = 0;
  for (int i = 0; i < NumberOfCharsToCopy; i++) {
    Buffer[index] = StringToCopy[i];
    index++;
  }
  Buffer[index] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gmi_base_end>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void gmi_base_end(struct gmi_model *m, struct gmi_iter *i) {
  (void)m;
  free(i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gmi_base_end>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gmi_base_end(struct gmi_model *m, struct gmi_iter *i) {
  (void)m;
  free(i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gmi_base_end>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void gmi_base_end(struct gmi_model *m, struct gmi_iter *i) {
  (void)m;
  free(i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<gmi_base_end>:
  endbr64
  mov    %rsi,%rdi
  jmp    1050 <free@plt>
```

assistant: ```c
void gmi_base_end(struct gmi_model *m, struct gmi_iter *i) {
  (void)m;
  free(i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<freeWords>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void freeWords(const int num, char **arr) {
  for (int i = 0; i < num; i++) {
    free(arr[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<freeWords>:
  endbr64
  test   %edi,%edi
  jle    L17
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L16:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  ret
```

assistant: ```c
void freeWords(const int num, char **arr) {
  for (int i = 0; i < num; i++) {
    free(arr[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<freeWords>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L12:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void freeWords(const int num, char **arr) {
  for (int i = 0; i < num; i++) {
    free(arr[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<freeWords>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void freeWords(const int num, char **arr) {
  for (int i = 0; i < num; i++) {
    free(arr[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x20(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x20(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x20(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x20(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x18(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm3,%xmm3
  cvtss2sd -0x14(%rbp),%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm5,%xmm5
  cvtss2sd -0xc(%rbp),%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D37
data_type: string
name: extract_symbolic_data
arguments: data_label: D42
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string
name: extract_symbolic_data
arguments: data_label: D43
data_type: string
name: extract_symbolic_data
arguments: data_label: D40
data_type: string
name: extract_symbolic_data
arguments: data_label: D55
data_type: string
name: extract_symbolic_data
arguments: data_label: D59
data_type: string

tool: D37: What is the number? 

tool: D42: %f

tool: D9: What is the other number? 

tool: D43: The sum is %f


tool: D40: The min is %f


tool: D55: The prod is %f


tool: D59: The div is %f


assistant: ```c
int main() {
  float num;
  float taco;
  printf("What is the number? \n");
  scanf("%f", &num);
  printf("What is the other number? \n");
  scanf("%f", &taco);
  float sum;
  sum = num + taco;
  float min;
  min = num - taco;
  float prod;
  prod = num * taco;
  float div;
  div = num / taco;
  printf("The sum is %f\n", sum);
  printf("The min is %f\n", min);
  printf("The prod is %f\n", prod);
  printf("The div is %f\n", div);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D64(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D52(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%ebx
  movss  0x14(%rsp),%xmm1
  movd   %ebx,%xmm0
  movss  %xmm1,0xc(%rsp)
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movd   %ebx,%xmm0
  subss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D24(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movd   %ebx,%xmm0
  mulss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D23(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movd   %ebx,%xmm0
  divss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D64
datatype: string
name: extract_symbolic_data
arguments: data_tag: D52
datatype: string
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string
name: extract_symbolic_data
arguments: data_tag: D38
datatype: string
name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D23
datatype: string
name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D64: What is the number? 

tool: D52: %f

tool: D35: What is the other number? 

tool: D38: The sum is %f


tool: D24: The min is %f


tool: D23: The prod is %f


tool: D3: The div is %f


assistant: ```c
int main() {
  float num;
  float taco;
  printf("What is the number? \n");
  scanf("%f", &num);
  printf("What is the other number? \n");
  scanf("%f", &taco);
  float sum;
  sum = num + taco;
  float min;
  min = num - taco;
  float prod;
  prod = num * taco;
  float div;
  div = num / taco;
  printf("The sum is %f\n", sum);
  printf("The min is %f\n", min);
  printf("The prod is %f\n", prod);
  printf("The div is %f\n", div);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D41(%rip),%rdi
  lea    D58(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  lea    D18(%rip),%rdi
  mov    $0x1,%eax
  movss  %xmm0,0x8(%rsp)
  addss  %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  subss  0xc(%rsp),%xmm0
  lea    D68(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  mulss  0xc(%rsp),%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  movss  0x8(%rsp),%xmm0
  divss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D41
type_guessed: string
name: unpack_data
arguments: data_label: D58
type_guessed: string
name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D18
type_guessed: string
name: unpack_data
arguments: data_label: D68
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D26
type_guessed: string

tool: D41: What is the number? 

tool: D58: %f

tool: D24: What is the other number? 

tool: D18: The sum is %f


tool: D68: The min is %f


tool: D17: The prod is %f


tool: D26: The div is %f


assistant: ```c
int main() {
  float num;
  float taco;
  printf("What is the number? \n");
  scanf("%f", &num);
  printf("What is the other number? \n");
  scanf("%f", &taco);
  float sum;
  sum = num + taco;
  float min;
  min = num - taco;
  float prod;
  prod = num * taco;
  float div;
  div = num / taco;
  printf("The sum is %f\n", sum);
  printf("The min is %f\n", min);
  printf("The prod is %f\n", prod);
  printf("The div is %f\n", div);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rdi
  lea    D0(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  movss  %xmm0,0x8(%rsp)
  addss  %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  subss  0xc(%rsp),%xmm0
  lea    D33(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm0
  mulss  0xc(%rsp),%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D37(%rip),%rdi
  mov    $0x1,%eax
  movss  0x8(%rsp),%xmm0
  divss  0xc(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D40
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D56
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D33
type_infered: string
name: parse_data
arguments: label: D55
type_infered: string
name: parse_data
arguments: label: D37
type_infered: string

tool: D40: What is the number? 

tool: D0: %f

tool: D56: What is the other number? 

tool: D13: The sum is %f


tool: D33: The min is %f


tool: D55: The prod is %f


tool: D37: The div is %f


assistant: ```c
int main() {
  float num;
  float taco;
  printf("What is the number? \n");
  scanf("%f", &num);
  printf("What is the other number? \n");
  scanf("%f", &taco);
  float sum;
  sum = num + taco;
  float min;
  min = num - taco;
  float prod;
  prod = num * taco;
  float div;
  div = num / taco;
  printf("The sum is %f\n", sum);
  printf("The min is %f\n", min);
  printf("The prod is %f\n", prod);
  printf("The div is %f\n", div);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<u8_rune_length>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x0,%eax
  test   %dl,%dl
  je     L120
  mov    $0x1,%eax
  jg     L120
  lea    0x3e(%rdx),%eax
  cmp    $0x1d,%al
  ja     L127
  mov    $0x2,%eax
  cmpb   $0xc0,0x1(%rdi)
  jl     L52
L26:
  lea    0xf(%rdx),%eax
  cmp    $0x2,%al
  ja     L83
  mov    $0xffffffff,%eax
  cmpb   $0xc0,0x1(%rdi)
  jge    L120
  cmpb   $0xc0,0x2(%rdi)
  jge    L120
  cmpb   $0xbf,0x3(%rdi)
  setle  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,4),%eax
  ret
L52:
  ret
L127:
  cmp    $0xe0,%dl
  jne    L5
  movzbl 0x1(%rdi),%eax
  lea    0x60(%rax),%edx
  mov    $0xffffffff,%eax
  cmp    $0x1f,%dl
  jbe    L158
L120:
  ret
L158:
  cmpb   $0xc0,0x2(%rdi)
  setl   %al
  movzbl %al,%eax
  lea    -0x1(,%rax,4),%eax
  ret
L5:
  lea    0x1f(%rdx),%eax
  cmp    $0xb,%al
  ja     L62
  mov    $0xffffffff,%eax
  cmpb   $0xc0,0x1(%rdi)
  jge    L120
  cmpb   $0xc0,0x2(%rdi)
  setl   %al
  movzbl %al,%eax
  lea    -0x1(,%rax,4),%eax
  ret
L62:
  cmp    $0xed,%dl
  jne    L169
  mov    $0xffffffff,%eax
  cmpb   $0xa0,0x1(%rdi)
  jge    L120
  cmpb   $0xc0,0x2(%rdi)
  setl   %al
  movzbl %al,%eax
  lea    -0x1(,%rax,4),%eax
  ret
L169:
  cmp    $0xf0,%dl
  jne    L26
  movzbl 0x1(%rdi),%eax
  lea    0x70(%rax),%edx
  mov    $0xffffffff,%eax
  cmp    $0x2f,%dl
  ja     L120
  cmpb   $0xc0,0x2(%rdi)
  jge    L120
  cmpb   $0xbf,0x3(%rdi)
  setle  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,4),%eax
  ret
L83:
  cmp    $0xf4,%dl
  jne    L66
  cmpb   $0x90,0x1(%rdi)
  jge    L49
  cmpb   $0xc0,0x2(%rdi)
  jge    L135
  cmpb   $0xbf,0x3(%rdi)
  setle  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,4),%eax
  ret
L66:
  mov    $0xffffffff,%eax
  ret
L49:
  mov    $0xffffffff,%eax
  ret
L135:
  mov    $0xffffffff,%eax
  jmp    L120
```

assistant: ```c
int u8_rune_length(const char *p) {
  if (*p == '\x00')
    return 0;
  if (*p > '\x00' && *p <= '\x7f')
    return 1;
  if (*p >= '\xc2' && *p <= '\xdf' && *(p + 1) >= '\x80' && *(p + 1) <= '\xbf')
    return 2;
  if (*p == '\xe0' && *(p + 1) >= '\xa0' && *(p + 1) <= '\xbf' && *(p + 2) >= '\x80' && *(p + 2) <= '\xbf')
    return 3;
  if (*p >= '\xe1' && *p <= '\xec' && *(p + 1) >= '\x80' && *(p + 1) <= '\xbf' && *(p + 2) >= '\x80' && *(p + 2) <= '\xbf')
    return 3;
  if (*p == '\xed' && *(p + 1) >= '\x80' && *(p + 1) <= '\x9f' && *(p + 2) >= '\x80' && *(p + 2) <= '\xbf')
    return 3;
  if (*p == '\xf0' && *(p + 1) >= '\x90' && *(p + 1) <= '\xbf' && *(p + 2) >= '\x80' && *(p + 2) <= '\xbf' && *(p + 3) >= '\x80' && *(p + 3) <= '\xbf')
    return 4;
  if (*p >= '\xf1' && *p <= '\xf3' && *(p + 1) >= '\x80' && *(p + 1) <= '\xbf' && *(p + 2) >= '\x80' && *(p + 2) <= '\xbf' && *(p + 3) >= '\x80' && *(p + 3) <= '\xbf')
    return 4;
  if (*p == '\xf4' && *(p + 1) >= '\x80' && *(p + 1) <= '\x8f' && *(p + 2) >= '\x80' && *(p + 2) <= '\xbf' && *(p + 3) >= '\x80' && *(p + 3) <= '\xbf')
    return 4;
  return -1;
}
```