ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  lea    D38(%rip),%r13
  lea    D14(%rip),%r12
  movabs $0x6666666666666667,%rbp
  jmp    L24
L76:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L79:
  mov    %rbx,%rcx
L2:
  mov    %rcx,%rax
  imul   %rbp
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,4),%rdx
  add    %rdx,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  movslq %eax,%rdx
  cmpl   $0x0,0x10(%rsp,%rdx,4)
  jne    L81
  movl   $0x1,0x10(%rsp,%rdx,4)
  mov    %rcx,%rax
  imul   %rbp
  sar    $0x2,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rbx
  sub    %rax,%rbx
  mov    %esi,%edi
  cmp    $0x9,%rcx
  jg     L79
  mov    %rbx,0x8(%rsp)
L54:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L81:
  test   %dil,%dil
  je     L87
  mov    %rbx,0x8(%rsp)
L87:
  test   %rcx,%rcx
  jle    L54
  lea    D48(%rip),%rdi
  call   <printf@plt>
L24:
  mov    %r13,%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  jle    L76
  mov    $0x0,%edi
  mov    $0x1,%esi
  jmp    L2
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string
name: extract_symbolic_data
arguments: tag: D42
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D48
type: string

tool: D38: Enter a number: 

tool: D14: %ld

tool: D42: Error: the value of number is invailded.


tool: D29: No repeated digit


tool: D48: Repeated digit


assistant: ```c
int main(void) {
  bool digit_seen[10] = {false};
  int digit;
  long n;
  while (1) {
    printf("Enter a number: ");
    scanf("%ld", &n);
    if (n <= 0) {
      printf("Error: the value of number is invailded.\n");
      break;
    }
    while (n > 0) {
      digit = n % 10;
      if (digit_seen[digit])
        break;
      digit_seen[digit] = true;
      n /= 10;
    }
    if (n > 0)
      printf("Repeated digit\n");
    else
      printf("No repeated digit\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  movabs $0xcccccccccccccccd,%r15
  push   %r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D43(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D42(%rip),%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopl   (%rax)
L0:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  jle    L17
  xor    %edi,%edi
  jmp    L47
  nopl   (%rax)
L52:
  movl   $0x1,0x10(%rsp,%rax,4)
  mov    %rdx,%r14
  mov    $0x1,%edi
  cmp    $0x9,%rcx
  jle    L68
  mov    %r14,%rcx
L47:
  mov    %rcx,%rax
  mul    %r15
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  test   %esi,%esi
  je     L52
  test   %dil,%dil
  je     L45
  mov    %r14,0x8(%rsp)
L45:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L68:
  lea    D36(%rip),%rdi
  mov    %rdx,0x8(%rsp)
  call   <printf@plt>
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L17:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D43
type: string
name: retrieve_data
arguments: tag: D42
type: string
name: retrieve_data
arguments: tag: D36
type: string
name: retrieve_data
arguments: tag: D26
type: string

tool: D17: Repeated digit


tool: D43: Enter a number: 

tool: D42: %ld

tool: D36: No repeated digit


tool: D26: Error: the value of number is invailded.


assistant: ```c
int main(void) {
  bool digit_seen[10] = {false};
  int digit;
  long n;
  while (1) {
    printf("Enter a number: ");
    scanf("%ld", &n);
    if (n <= 0) {
      printf("Error: the value of number is invailded.\n");
      break;
    }
    while (n > 0) {
      digit = n % 10;
      if (digit_seen[digit])
        break;
      digit_seen[digit] = true;
      n /= 10;
    }
    if (n > 0)
      printf("Repeated digit\n");
    else
      printf("No repeated digit\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  pxor   %xmm0,%xmm0
  movabs $0xcccccccccccccccd,%r15
  push   %r14
  push   %r13
  lea    D42(%rip),%r13
  push   %r12
  lea    D40(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  movq   $0x0,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopl   (%rax)
L3:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rcx
  test   %rcx,%rcx
  jle    L38
  xor    %edi,%edi
  jmp    L0
  nopl   (%rax)
L26:
  movl   $0x1,0x10(%rsp,%rax,4)
  mov    %rdx,%r14
  mov    $0x1,%edi
  cmp    $0x9,%rcx
  jle    L51
  mov    %r14,%rcx
L0:
  mov    %rcx,%rax
  mul    %r15
  mov    %rcx,%rax
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rsi
  add    %rsi,%rsi
  sub    %rsi,%rax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  test   %esi,%esi
  je     L26
  test   %dil,%dil
  je     L75
  mov    %r14,0x8(%rsp)
L75:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L51:
  lea    D19(%rip),%rdi
  mov    %rdx,0x8(%rsp)
  call   <printf@plt>
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L38:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D42
type_guessed: string
name: parse_data
arguments: data_label: D40
type_guessed: string
name: parse_data
arguments: data_label: D23
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string
name: parse_data
arguments: data_label: D34
type_guessed: string

tool: D42: Repeated digit


tool: D40: Enter a number: 

tool: D23: %ld

tool: D19: No repeated digit


tool: D34: Error: the value of number is invailded.


assistant: ```c
int main(void) {
  bool digit_seen[10] = {false};
  int digit;
  long n;
  while (1) {
    printf("Enter a number: ");
    scanf("%ld", &n);
    if (n <= 0) {
      printf("Error: the value of number is invailded.\n");
      break;
    }
    while (n > 0) {
      digit = n % 10;
      if (digit_seen[digit])
        break;
      digit_seen[digit] = true;
      n /= 10;
    }
    if (n > 0)
      printf("Repeated digit\n");
    else
      printf("No repeated digit\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x100,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    $0x100,%edi
  call   <acc_malloc@plt>
  mov    %rax,%r14
  mov    $0x100,%edx
  mov    $0x9,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x100,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <acc_memcpy_to_device@plt>
  mov    $0x100,%edx
  mov    $0x28,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_map_data@plt>
  mov    %r13,%rbx
  lea    0x100(%r13),%rbp
  mov    %r13,%r12
  jmp    L131
L88:
  add    $0x1,%r12
  cmp    %rbp,%r12
  je     L10
L131:
  cmpb   $0x28,(%r12)
  je     L88
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L88
L10:
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_memcpy_from_device@plt>
  mov    %r13,%r12
  jmp    L92
L24:
  add    $0x1,%r12
  cmp    %rbp,%r12
  je     L89
L92:
  cmpb   $0x9,(%r12)
  je     L24
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L24
L89:
  mov    $0x100,%edx
  mov    $0x2f,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %r13,%rdi
  call   <acc_unmap_data@plt>
  mov    %r13,%r12
  jmp    L19
L22:
  add    $0x1,%r12
  cmp    %rbp,%r12
  je     L80
L19:
  cmpb   $0x2f,(%r12)
  je     L22
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L22
L80:
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_memcpy_from_device@plt>
  jmp    L66
L91:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L72
L66:
  cmpb   $0x9,(%rbx)
  je     L91
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L91
L72:
  mov    %r14,%rdi
  call   <acc_free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main() {
  const int c0 = 9;
  const int c1 = 40;
  const int c2 = 47;
  const size_t N = 256;
  unsigned char *h = (unsigned char *)malloc(N);
  void *d = acc_malloc(N);
  memset(h, c0, N);
  acc_memcpy_to_device(d, h, N);
  memset(h, c1, N);
  acc_map_data(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c1)
      abort();
  acc_memcpy_from_device(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c0)
      abort();
  memset(h, c2, N);
  acc_unmap_data(h);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c2)
      abort();
  acc_memcpy_from_device(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c0)
      abort();
  acc_free(d);
  free(h);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x100,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%r13
  call   <acc_malloc@plt>
  mov    $0x100,%edx
  mov    $0x9,%esi
  mov    %r13,%rdi
  mov    %rax,%r14
  mov    %r13,%rbx
  lea    0x100(%r13),%rbp
  mov    %r13,%r12
  call   <memset@plt>
  mov    $0x100,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <acc_memcpy_to_device@plt>
  mov    $0x100,%edx
  mov    $0x28,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_map_data@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  cmpb   $0x28,(%r12)
  je     L69
  xor    %eax,%eax
  call   <abort@plt>
L69:
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L18
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %r13,%r12
  call   <acc_memcpy_from_device@plt>
  nopw   0x0(%rax,%rax,1)
L35:
  cmpb   $0x9,(%r12)
  je     L1
  xor    %eax,%eax
  call   <abort@plt>
L1:
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L35
  mov    $0x100,%edx
  mov    $0x2f,%esi
  mov    %r13,%rdi
  mov    %r13,%r12
  call   <memset@plt>
  mov    %r13,%rdi
  call   <acc_unmap_data@plt>
  nopl   0x0(%rax)
L29:
  cmpb   $0x2f,(%r12)
  je     L78
  xor    %eax,%eax
  call   <abort@plt>
L78:
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L29
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_memcpy_from_device@plt>
  nop
L43:
  cmpb   $0x9,(%rbx)
  je     L79
  xor    %eax,%eax
  call   <abort@plt>
L79:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L43
  mov    %r14,%rdi
  call   <acc_free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main() {
  const int c0 = 9;
  const int c1 = 40;
  const int c2 = 47;
  const size_t N = 256;
  unsigned char *h = (unsigned char *)malloc(N);
  void *d = acc_malloc(N);
  memset(h, c0, N);
  acc_memcpy_to_device(d, h, N);
  memset(h, c1, N);
  acc_map_data(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c1)
      abort();
  acc_memcpy_from_device(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c0)
      abort();
  memset(h, c2, N);
  acc_unmap_data(h);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c2)
      abort();
  acc_memcpy_from_device(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c0)
      abort();
  acc_free(d);
  free(h);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x100,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <malloc@plt>
  mov    $0x100,%edi
  mov    %rax,%r13
  call   <acc_malloc@plt>
  mov    $0x100,%edx
  mov    $0x9,%esi
  mov    %r13,%rdi
  mov    %rax,%r14
  mov    %r13,%rbx
  lea    0x100(%r13),%rbp
  mov    %r13,%r12
  call   <memset@plt>
  mov    $0x100,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <acc_memcpy_to_device@plt>
  mov    $0x100,%edx
  mov    $0x28,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_map_data@plt>
  nopw   0x0(%rax,%rax,1)
L42:
  cmpb   $0x28,(%r12)
  je     L57
  xor    %eax,%eax
  call   <abort@plt>
L57:
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L42
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    %r13,%r12
  call   <acc_memcpy_from_device@plt>
  nopw   0x0(%rax,%rax,1)
L39:
  cmpb   $0x9,(%r12)
  je     L18
  xor    %eax,%eax
  call   <abort@plt>
L18:
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L39
  mov    $0x100,%edx
  mov    $0x2f,%esi
  mov    %r13,%rdi
  mov    %r13,%r12
  call   <memset@plt>
  mov    %r13,%rdi
  call   <acc_unmap_data@plt>
  nopl   0x0(%rax)
L65:
  cmpb   $0x2f,(%r12)
  je     L71
  xor    %eax,%eax
  call   <abort@plt>
L71:
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L65
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <acc_memcpy_from_device@plt>
  nop
L40:
  cmpb   $0x9,(%rbx)
  je     L25
  xor    %eax,%eax
  call   <abort@plt>
L25:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L40
  mov    %r14,%rdi
  call   <acc_free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main() {
  const int c0 = 9;
  const int c1 = 40;
  const int c2 = 47;
  const size_t N = 256;
  unsigned char *h = (unsigned char *)malloc(N);
  void *d = acc_malloc(N);
  memset(h, c0, N);
  acc_memcpy_to_device(d, h, N);
  memset(h, c1, N);
  acc_map_data(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c1)
      abort();
  acc_memcpy_from_device(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c0)
      abort();
  memset(h, c2, N);
  acc_unmap_data(h);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c2)
      abort();
  acc_memcpy_from_device(h, d, N);
  for (size_t i = 0; i < N; ++i)
    if (h[i] != c0)
      abort();
  acc_free(d);
  free(h);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rc_url_get_patch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %rdx,-0xb8(%rbp)
  mov    %rcx,-0xc0(%rbp)
  mov    %r8d,-0xc4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xb8(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  je     L18
  mov    $0xffffffff,%eax
  jmp    L53
L18:
  mov    -0xc0(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  je     L17
  mov    $0xffffffff,%eax
  jmp    L53
L17:
  mov    -0xc4(%rbp),%edi
  lea    -0x50(%rbp),%rcx
  lea    -0x90(%rbp),%rdx
  mov    -0xb0(%rbp),%rsi
  mov    -0xa8(%rbp),%rax
  mov    %edi,%r9d
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0x94(%rbp)
  mov    -0x94(%rbp),%eax
  cltq
  cmp    %rax,-0xb0(%rbp)
  ja     L44
  mov    $0xffffffff,%eax
  jmp    L53
L44:
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type: string

tool: D6: http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u

assistant: ```c
int rc_url_get_patch(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rc_url_get_patch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rcx,%rbp
  mov    %r8d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x40,%esi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L37
  lea    0x40(%rsp),%rdi
  mov    %rbp,%rdx
  mov    $0x40,%esi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L13
  mov    %rsp,%rcx
  mov    %r13d,%r9d
  lea    0x40(%rsp),%r8
  lea    D4(%rip),%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <snprintf@plt>
  cltq
  cmp    %rbx,%rax
  setae  %al
  movzbl %al,%eax
  neg    %eax
L0:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  mov    $0xffffffff,%eax
  jmp    L0
L13:
  mov    $0xffffffff,%eax
  jmp    L0
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string

tool: D4: http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u

assistant: ```c
int rc_url_get_patch(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rc_url_get_patch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x40,%esi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L8
  lea    0x40(%rsp),%r15
  mov    %r12,%rdx
  mov    $0x40,%esi
  mov    %r15,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L8
  mov    %r13d,%r9d
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rsi
  lea    D0(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cltq
  cmp    %rbx,%rax
  setae  %al
  movzbl %al,%eax
  neg    %eax
L24:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L24
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type_guessed: string

tool: D0: http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u

assistant: ```c
int rc_url_get_patch(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rc_url_get_patch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x40,%esi
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L16
  lea    0x40(%rsp),%r15
  mov    %r12,%rdx
  mov    $0x40,%esi
  mov    %r15,%rdi
  call   <rc_url_encode@plt>
  test   %rax,%rax
  jne    L16
  mov    %r13d,%r9d
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdx
  mov    %rbp,%rdi
  call   <snprintf@plt>
  cltq
  cmp    %rbx,%rax
  setae  %al
  movzbl %al,%eax
  neg    %eax
L15:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L15
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: string

tool: D9: http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u

assistant: ```c
int rc_url_get_patch(char *buffer, size_t size, const char *user_name, const char *login_token, unsigned gameid) {
  char urle_user_name[64];
  char urle_login_token[64];
  int written;
  if (rc_url_encode(urle_user_name, sizeof(urle_user_name), user_name) != 0) {
    return -1;
  }
  if (rc_url_encode(urle_login_token, sizeof(urle_login_token), login_token) != 0) {
    return -1;
  }
  written = snprintf(buffer, size, "http://retroachievements.org/dorequest.php?r=patch&u=%s&t=%s&g=%u", urle_user_name, urle_login_token, gameid);
  return (size_t)written >= size ? -1 : 0;
}
```