ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xc,%ecx
  push   %r14
  lea    D34(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%rdi
  lea    0x30(%rsp),%rbx
  movq   $0x0,0x8(%rsp)
  mov    %rdi,0x28(%rsp)
  mov    %rbx,0x18(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x50(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x64(%rsp),%rax
  mov    %rax,(%rsp)
  movl   $0x0,(%rdi)
L9:
  mov    0x8(%rsp),%eax
  lea    D27(%rip),%rdi
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%r15
  mov    0x28(%rsp),%r13
  mov    %r15,0x10(%rsp)
  sub    %rbp,%r13
L46:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x0(%r13,%rbp,1),%rax
  add    $0x4,%r13
  mov    (%rax,%r12,1),%eax
  add    %eax,(%r15)
  add    $0x4,%r15
  add    %eax,(%rbx)
  cmp    (%rsp),%r15
  jne    L46
  addq   $0x1,0x8(%rsp)
  add    $0x4,%rbx
  sub    $0x14,%rbp
  add    $0x14,%r12
  mov    0x8(%rsp),%rax
  cmp    $0x5,%rax
  jne    L9
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  lea    D9(%rip),%rbx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  lea    0x14(%rax),%rbp
L12:
  mov    0x18(%rsp),%r14
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    (%r14),%esi
  call   <printf@plt>
  mov    %r14,%rax
  add    $0x4,%rax
  mov    %rax,0x18(%rsp)
  cmp    %rbp,%rax
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L32:
  mov    0x10(%rsp),%r14
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    (%r14),%esi
  call   <printf@plt>
  mov    %r14,%rax
  add    $0x4,%rax
  mov    %rax,0x10(%rsp)
  cmp    (%rsp),%rax
  jne    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D34
datatype: string
name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D40
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string
name: disassemble_data
arguments: data_tag: D30
datatype: string

tool: D34: %d

tool: D27: enter row %d: 

tool: D40: row totals: 

tool: D9: %d  

tool: D30: column totals: 

assistant: ```c
int main(void) {
  int a[5][5] = {};
  int i, j;
  int row_total[5], col_total[5];
  for (i = 0; i < 5; i++) {
    printf("enter row %d: ", i + 1);
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
      row_total[i] += a[i][j];
      col_total[j] += a[i][j];
    }
  }
  printf("row totals: ");
  for (i = 0; i < 5; i++) {
    printf("%d  ", row_total[i]);
  }
  printf("\n");
  printf("column totals: ");
  for (i = 0; i < 5; i++) {
    printf("%d  ", col_total[i]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0xc,%ecx
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%rdi
  lea    0x30(%rsp),%rbx
  movq   $0x0,0x8(%rsp)
  mov    %rdi,0x28(%rsp)
  mov    %rbx,0x18(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x50(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x64(%rsp),%rax
  mov    %rax,(%rsp)
  movl   $0x0,(%rdi)
L1:
  mov    0x8(%rsp),%eax
  lea    D29(%rip),%rdi
  lea    0x1(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x20(%rsp),%r15
  mov    0x28(%rsp),%r13
  mov    %r15,0x10(%rsp)
  sub    %rbp,%r13
L28:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  lea    0x0(%r13,%rbp,1),%rax
  add    $0x4,%r13
  mov    (%rax,%r12,1),%eax
  add    %eax,(%r15)
  add    $0x4,%r15
  add    %eax,(%rbx)
  cmp    (%rsp),%r15
  jne    L28
  addq   $0x1,0x8(%rsp)
  add    $0x4,%rbx
  sub    $0x14,%rbp
  add    $0x14,%r12
  mov    0x8(%rsp),%rax
  cmp    $0x5,%rax
  jne    L1
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  lea    D14(%rip),%rbx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  lea    0x14(%rax),%rbp
L49:
  mov    0x18(%rsp),%r14
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    (%r14),%esi
  call   <printf@plt>
  mov    %r14,%rax
  add    $0x4,%rax
  mov    %rax,0x18(%rsp)
  cmp    %rbp,%rax
  jne    L49
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L12:
  mov    0x10(%rsp),%r14
  mov    %rbx,%rdi
  xor    %eax,%eax
  mov    (%r14),%esi
  call   <printf@plt>
  mov    %r14,%rax
  add    $0x4,%rax
  mov    %rax,0x10(%rsp)
  cmp    (%rsp),%rax
  jne    L12
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D46
datatype: string
name: parse_data
arguments: label: D14
datatype: string
name: parse_data
arguments: label: D7
datatype: string

tool: D8: %d

tool: D29: enter row %d: 

tool: D46: row totals: 

tool: D14: %d  

tool: D7: column totals: 

assistant: ```c
int main(void) {
  int a[5][5] = {};
  int i, j;
  int row_total[5], col_total[5];
  for (i = 0; i < 5; i++) {
    printf("enter row %d: ", i + 1);
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
      row_total[i] += a[i][j];
      col_total[j] += a[i][j];
    }
  }
  printf("row totals: ");
  for (i = 0; i < 5; i++) {
    printf("%d  ", row_total[i]);
  }
  printf("\n");
  printf("column totals: ");
  for (i = 0; i < 5; i++) {
    printf("%d  ", col_total[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dynamic_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gc_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: hash.c:dynamic_strcpy

assistant: ```c
char *dynamic_strcpy(char *str) {
  char *tmp = (char *)gc_alloc(sizeof(char) * (strlen(str) + 1), "hash.c:dynamic_strcpy");
  strcpy(tmp, str);
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dynamic_strcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  lea    D8(%rip),%rsi
  call   <gc_alloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string

tool: D8: hash.c:dynamic_strcpy

assistant: ```c
char *dynamic_strcpy(char *str) {
  char *tmp = (char *)gc_alloc(sizeof(char) * (strlen(str) + 1), "hash.c:dynamic_strcpy");
  strcpy(tmp, str);
  return tmp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dynamic_strcpy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D3(%rip),%rsi
  lea    0x1(%rax),%edi
  call   <gc_alloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: hash.c:dynamic_strcpy

assistant: ```c
char *dynamic_strcpy(char *str) {
  char *tmp = (char *)gc_alloc(sizeof(char) * (strlen(str) + 1), "hash.c:dynamic_strcpy");
  strcpy(tmp, str);
  return tmp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dynamic_strcpy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D6(%rip),%rsi
  lea    0x1(%rax),%edi
  call   <gc_alloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: hash.c:dynamic_strcpy

assistant: ```c
char *dynamic_strcpy(char *str) {
  char *tmp = (char *)gc_alloc(sizeof(char) * (strlen(str) + 1), "hash.c:dynamic_strcpy");
  strcpy(tmp, str);
  return tmp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_in_image>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L3
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
L3:
  cmpl   $0x0,-0x18(%rbp)
  jns    L9
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  add    $0x14,%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jge    L8
  mov    -0x14(%rbp),%eax
  add    $0x14,%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
L8:
  mov    -0x18(%rbp),%eax
  add    $0xf,%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L2
  mov    -0x18(%rbp),%eax
  add    $0xf,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D33
type_guessed: string

tool: D16: 
il=%d tool small

tool: D19: 
ie=%d tool small

tool: D6: 
ll=%d tool big

tool: D33: 
le=%d tool big

assistant: ```c
int is_in_image(il, ie, height, width)
int il, ie;
long height, width;
{
  int result = 1;
  if (il < 0) {
    printf("\nil=%d tool small", il);
    result = 0;
  }
  if (ie < 0) {
    printf("\nie=%d tool small", ie);
    result = 0;
  }
  if ((il + 20) > height) {
    printf("\nll=%d tool big", il + 20);
    result = 0;
  }
  if ((ie + 15) > width) {
    printf("\nle=%d tool big", ie + 15);
    result = 0;
  }
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_in_image>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    $0x1,%eax
  test   %edi,%edi
  js     L71
L75:
  test   %ebx,%ebx
  js     L20
L43:
  lea    0x14(%rbp),%esi
  movslq %esi,%rdx
  cmp    %r13,%rdx
  jg     L3
L11:
  lea    0xf(%rbx),%esi
  movslq %esi,%rdx
  cmp    %r12,%rdx
  jg     L17
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L75
L20:
  mov    %ebx,%esi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L43
L3:
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L11
L17:
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L29
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string
name: extract_symbolic_data
arguments: label: D18
type: string
name: extract_symbolic_data
arguments: label: D17
type: string
name: extract_symbolic_data
arguments: label: D33
type: string

tool: D0: 
il=%d tool small

tool: D18: 
ie=%d tool small

tool: D17: 
ll=%d tool big

tool: D33: 
le=%d tool big

assistant: ```c
int is_in_image(il, ie, height, width)
int il, ie;
long height, width;
{
  int result = 1;
  if (il < 0) {
    printf("\nil=%d tool small", il);
    result = 0;
  }
  if (ie < 0) {
    printf("\nie=%d tool small", ie);
    result = 0;
  }
  if ((il + 20) > height) {
    printf("\nll=%d tool big", il + 20);
    result = 0;
  }
  if ((ie + 15) > width) {
    printf("\nle=%d tool big", ie + 15);
    result = 0;
  }
  return (result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_in_image>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L4
L32:
  test   %ebx,%ebx
  js     L54
L69:
  lea    0x14(%rbp),%esi
  movslq %esi,%rdx
  cmp    %r13,%rdx
  jg     L33
  lea    0xf(%rbx),%esi
  movslq %esi,%rdx
  cmp    %r12,%rdx
  jg     L23
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rbx),%esi
  xor    %eax,%eax
  movslq %esi,%rdx
  cmp    %r12,%rdx
  jle    L3
L23:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L69
  nopl   0x0(%rax)
L4:
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L32
```

tool_calls: name: parse_data
arguments: data_tag: D22
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D34
type_guessed: string

tool: D22: 
ll=%d tool big

tool: D3: 
le=%d tool big

tool: D25: 
ie=%d tool small

tool: D34: 
il=%d tool small

assistant: ```c
int is_in_image(il, ie, height, width)
int il, ie;
long height, width;
{
  int result = 1;
  if (il < 0) {
    printf("\nil=%d tool small", il);
    result = 0;
  }
  if (ie < 0) {
    printf("\nie=%d tool small", ie);
    result = 0;
  }
  if ((il + 20) > height) {
    printf("\nll=%d tool big", il + 20);
    result = 0;
  }
  if ((ie + 15) > width) {
    printf("\nle=%d tool big", ie + 15);
    result = 0;
  }
  return (result);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_in_image>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L33
L53:
  test   %ebx,%ebx
  js     L65
L2:
  lea    0x14(%rbp),%esi
  movslq %esi,%rdx
  cmp    %r13,%rdx
  jg     L12
  lea    0xf(%rbx),%esi
  movslq %esi,%rdx
  cmp    %r12,%rdx
  jg     L8
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xf(%rbx),%esi
  xor    %eax,%eax
  movslq %esi,%rdx
  cmp    %r12,%rdx
  jle    L13
L8:
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L65:
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L2
  nopl   0x0(%rax)
L33:
  mov    %edi,%esi
  xor    %eax,%eax
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L53
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_guessed: string
name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D24: 
ll=%d tool big

tool: D33: 
le=%d tool big

tool: D20: 
ie=%d tool small

tool: D16: 
il=%d tool small

assistant: ```c
int is_in_image(il, ie, height, width)
int il, ie;
long height, width;
{
  int result = 1;
  if (il < 0) {
    printf("\nil=%d tool small", il);
    result = 0;
  }
  if (ie < 0) {
    printf("\nie=%d tool small", ie);
    result = 0;
  }
  if ((il + 20) > height) {
    printf("\nll=%d tool big", il + 20);
    result = 0;
  }
  if ((ie + 15) > width) {
    printf("\nle=%d tool big", ie + 15);
    result = 0;
  }
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<div2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  jmp    L0
L11:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string

tool: D6: error!


assistant: ```c
int div2(int a, int b) {
  if (b != 0) {
    return a / b;
  } else {
    printf("error!\n");
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<div2>:
  endbr64
  test   %esi,%esi
  je     L6
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
L6:
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_infered: string

tool: D8: error!


assistant: ```c
int div2(int a, int b) {
  if (b != 0) {
    return a / b;
  } else {
    printf("error!\n");
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<div2>:
  endbr64
  test   %esi,%esi
  je     L0
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
  xchg   %ax,%ax
L0:
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: error!


assistant: ```c
int div2(int a, int b) {
  if (b != 0) {
    return a / b;
  } else {
    printf("error!\n");
    return 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<div2>:
  endbr64
  test   %esi,%esi
  je     L7
  mov    %edi,%eax
  cltd
  idiv   %esi
  ret
  xchg   %ax,%ax
L7:
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
datatype: string

tool: D3: error!


assistant: ```c
int div2(int a, int b) {
  if (b != 0) {
    return a / b;
  } else {
    printf("error!\n");
    return 1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<__halt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L9:
  jmp    L9
```

assistant: ```c
void __halt() {
  while (1)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__halt>:
  endbr64
L7:
  jmp    L7
```

assistant: ```c
void __halt() {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__halt>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
void __halt() {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<__halt>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void __halt() {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_cdq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <assem_debug@plt>
  mov    $0x99,%edi
  call   <output_byte@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_guessed: string

tool: D4: cdq

assistant: ```c
void emit_cdq(void) {
  assem_debug("cdq");
  output_byte(0x99);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<emit_cdq>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x99,%edi
  call   <output_byte@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: cdq

assistant: ```c
void emit_cdq(void) {
  assem_debug("cdq");
  output_byte(0x99);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<emit_cdq>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x99,%edi
  add    $0x8,%rsp
  jmp    1070 <output_byte@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: cdq

assistant: ```c
void emit_cdq(void) {
  assem_debug("cdq");
  output_byte(0x99);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<emit_cdq>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x99,%edi
  add    $0x8,%rsp
  jmp    1070 <output_byte@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: cdq

assistant: ```c
void emit_cdq(void) {
  assem_debug("cdq");
  output_byte(0x99);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<boolXor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7e,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <boolTerm@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <emitln@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <emitln@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D2: pop	%%ebx

tool: D13: xor	%%ebx,%%eax

assistant: ```c
void boolXor() {
  match('~');
  boolTerm();
  emitln("pop\t%%ebx");
  emitln("xor\t%%ebx,%%eax");
}
```
user: Translate the below assembly code into C programming language:

```asm
<boolXor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e,%edi
  call   <match@plt>
  mov    $0x0,%eax
  call   <boolTerm@plt>
  lea    D19(%rip),%rdi
  call   <emitln@plt>
  lea    D1(%rip),%rdi
  call   <emitln@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D19: pop	%%ebx

tool: D1: xor	%%ebx,%%eax

assistant: ```c
void boolXor() {
  match('~');
  boolTerm();
  emitln("pop\t%%ebx");
  emitln("xor\t%%ebx,%%eax");
}
```
user: Translate the below assembly code into C programming language:

```asm
<boolXor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e,%edi
  call   <match@plt>
  xor    %eax,%eax
  call   <boolTerm@plt>
  lea    D8(%rip),%rdi
  call   <emitln@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <emitln@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D10
type_guessed: string

tool: D8: pop	%%ebx

tool: D10: xor	%%ebx,%%eax

assistant: ```c
void boolXor() {
  match('~');
  boolTerm();
  emitln("pop\t%%ebx");
  emitln("xor\t%%ebx,%%eax");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<boolXor>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7e,%edi
  call   <match@plt>
  xor    %eax,%eax
  call   <boolTerm@plt>
  lea    D4(%rip),%rdi
  call   <emitln@plt>
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <emitln@plt>
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D4: pop	%%ebx

tool: D11: xor	%%ebx,%%eax

assistant: ```c
void boolXor() {
  match('~');
  boolTerm();
  emitln("pop\t%%ebx");
  emitln("xor\t%%ebx,%%eax");
}
```