ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <poDebugInit@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <runScenario@plt>
  mov    $0x32,%esi
  mov    $0x32,%edi
  call   <runScenario@plt>
  mov    $0x14,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x64,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  mov    $0xc8,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x64,%esi
  mov    $0xc8,%edi
  call   <runScenario@plt>
  mov    $0x1f4,%esi
  mov    $0x1f4,%edi
  call   <runScenario@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  poDebugInit();
  runScenario(10, 10);
  runScenario(50, 50);
  runScenario(200, 20);
  runScenario(500, 100);
  runScenario(200, 200);
  runScenario(200, 100);
  runScenario(500, 500);
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<carried_add_jnc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    (%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rbx
  xor    %rax,%rax
  adc    %rbx,%rdx
  jae    1136 <nofirst>
  mov    $0x1,%rax
```

assistant: ```c
unsigned long long carried_add_jnc(unsigned long long carry, unsigned long long *res, unsigned long long *a1, unsigned long long *a2) {
  asm("xor %%rax, %%rax;"
      "adc %%rbx, %%rdx;"
      "jnc nofirst;"
      "mov $1, %%rax;"
      "nofirst:"
      "adc %%rcx, %%rdx;"
      "jnc nosecond;"
      "mov $1, %%rax;"
      "nosecond:"
      : "=a"(carry), "=d"(*res)
      : "b"(*a1), "c"(*a2), "d"(carry));
  return carry;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<carried_add_jnc>:
  endbr64
  push   %rbx
  mov    (%rdx),%rbx
  mov    (%rcx),%rcx
  mov    %rdi,%rdx
  xor    %rax,%rax
  adc    %rbx,%rdx
  jae    1116 <nofirst>
  mov    $0x1,%rax
```

assistant: ```c
unsigned long long carried_add_jnc(unsigned long long carry, unsigned long long *res, unsigned long long *a1, unsigned long long *a2) {
  asm("xor %%rax, %%rax;"
      "adc %%rbx, %%rdx;"
      "jnc nofirst;"
      "mov $1, %%rax;"
      "nofirst:"
      "adc %%rcx, %%rdx;"
      "jnc nosecond;"
      "mov $1, %%rax;"
      "nosecond:"
      : "=a"(carry), "=d"(*res)
      : "b"(*a1), "c"(*a2), "d"(carry));
  return carry;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<carried_add_jnc>:
  endbr64
  push   %rbx
  mov    (%rdx),%rbx
  mov    %rdi,%rdx
  mov    (%rcx),%rcx
  xor    %rax,%rax
  adc    %rbx,%rdx
  jae    111d <nofirst>
  mov    $0x1,%rax
```

assistant: ```c
unsigned long long carried_add_jnc(unsigned long long carry, unsigned long long *res, unsigned long long *a1, unsigned long long *a2) {
  asm("xor %%rax, %%rax;"
      "adc %%rbx, %%rdx;"
      "jnc nofirst;"
      "mov $1, %%rax;"
      "nofirst:"
      "adc %%rcx, %%rdx;"
      "jnc nosecond;"
      "mov $1, %%rax;"
      "nosecond:"
      : "=a"(carry), "=d"(*res)
      : "b"(*a1), "c"(*a2), "d"(carry));
  return carry;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<carried_add_jnc>:
  endbr64
  push   %rbx
  mov    (%rdx),%rbx
  mov    %rdi,%rdx
  mov    (%rcx),%rcx
  xor    %rax,%rax
  adc    %rbx,%rdx
  jae    111d <nofirst>
  mov    $0x1,%rax
```

assistant: ```c
unsigned long long carried_add_jnc(unsigned long long carry, unsigned long long *res, unsigned long long *a1, unsigned long long *a2) {
  asm("xor %%rax, %%rax;"
      "adc %%rbx, %%rdx;"
      "jnc nofirst;"
      "mov $1, %%rax;"
      "nofirst:"
      "adc %%rcx, %%rdx;"
      "jnc nosecond;"
      "mov $1, %%rax;"
      "nosecond:"
      : "=a"(carry), "=d"(*res)
      : "b"(*a1), "c"(*a2), "d"(carry));
  return carry;
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix_multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L44
L55:
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L52:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%esi
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  imul   %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    0x10(%rbp),%rax
  add    %rax,%rdx
  add    %esi,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L3
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L52
  addl   $0x1,-0xc(%rbp)
L44:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L55
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void matrix_multiply(int m1[][10], int r1, int c1, int m2[][10], int r2, int c2, int product[][10]) {
  int i, j, k;
  for (i = 0; i < r1; i++)
    for (j = 0; j < c2; j++) {
      product[i][j] = 0;
      for (k = 0; k < c1; k++)
        product[i][j] += m1[i][k] * m2[k][j];
    }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<matrix_multiply>:
  endbr64
  test   %esi,%esi
  jle    L9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r8
  mov    %edx,%ebx
  mov    %rcx,%r13
  mov    %r9d,%r12d
  lea    -0x1(%r9),%eax
  mov    0x30(%rsp),%rdx
  lea    0x4(%rdx,%rax,4),%r10
  mov    %rdi,%r11
  lea    -0x1(%rbx),%edx
  lea    0x4(%rdi,%rdx,4),%rdi
  lea    -0x1(%rsi),%edx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x28(%r8,%rdx,8),%r14
  not    %rax
  lea    0x0(,%rax,4),%rbp
  jmp    L60
L11:
  mov    %r8,%rsi
  movl   $0x0,(%r8)
  test   %ebx,%ebx
  jle    L26
  mov    %r9,%rcx
  mov    %r11,%rax
L23:
  mov    (%rax),%edx
  imul   (%rcx),%edx
  add    %edx,(%rsi)
  add    $0x4,%rax
  add    $0x28,%rcx
  cmp    %rdi,%rax
  jne    L23
L26:
  add    $0x4,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  jne    L11
L65:
  add    $0x28,%r10
  add    $0x28,%r11
  add    $0x28,%rdi
  cmp    %r14,%r11
  je     L45
L60:
  lea    0x0(%rbp,%r10,1),%r8
  mov    %r13,%r9
  test   %r12d,%r12d
  jg     L11
  jmp    L65
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  ret
```

assistant: ```c
void matrix_multiply(int m1[][10], int r1, int c1, int m2[][10], int r2, int c2, int product[][10]) {
  int i, j, k;
  for (i = 0; i < r1; i++)
    for (j = 0; j < c2; j++) {
      product[i][j] = 0;
      for (k = 0; k < c1; k++)
        product[i][j] += m1[i][k] * m2[k][j];
    }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matrix_multiply>:
  endbr64
  test   %esi,%esi
  jle    L29
  push   %r14
  lea    -0x1(%r9),%eax
  mov    %rdi,%r10
  push   %r13
  shl    $0x2,%rax
  mov    %rcx,%r13
  push   %r12
  mov    $0xfffffffffffffffc,%r12
  push   %rbp
  sub    %rax,%r12
  mov    %r9d,%ebp
  push   %rbx
  mov    %edx,%ebx
  mov    0x30(%rsp),%rdx
  lea    0x4(%rdx,%rax,1),%r11
  lea    -0x1(%rbx),%edx
  lea    0x4(%rdi,%rdx,4),%r8
  lea    -0x1(%rsi),%edx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x28(%rdi,%rdx,8),%r14
  nop
L26:
  lea    (%r12,%r11,1),%rdi
  mov    %r13,%r9
  test   %ebp,%ebp
  jle    L53
  nopl   0x0(%rax,%rax,1)
L44:
  movl   $0x0,(%rdi)
  mov    %r9,%rsi
  mov    %r10,%rax
  xor    %ecx,%ecx
  test   %ebx,%ebx
  jle    L41
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%rax),%edx
  imul   (%rsi),%edx
  add    $0x4,%rax
  add    $0x28,%rsi
  add    %edx,%ecx
  mov    %ecx,(%rdi)
  cmp    %r8,%rax
  jne    L21
L41:
  add    $0x4,%rdi
  add    $0x4,%r9
  cmp    %r11,%rdi
  jne    L44
L53:
  add    $0x28,%r10
  add    $0x28,%r11
  add    $0x28,%r8
  cmp    %r14,%r10
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  ret
```

assistant: ```c
void matrix_multiply(int m1[][10], int r1, int c1, int m2[][10], int r2, int c2, int product[][10]) {
  int i, j, k;
  for (i = 0; i < r1; i++)
    for (j = 0; j < c2; j++) {
      product[i][j] = 0;
      for (k = 0; k < c1; k++)
        product[i][j] += m1[i][k] * m2[k][j];
    }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_multiply>:
  endbr64
  movslq %esi,%rax
  test   %eax,%eax
  jle    L52
  mov    %edx,%esi
  test   %r9d,%r9d
  jle    L52
  push   %r13
  xor    %r10d,%r10d
  push   %r12
  push   %rbp
  lea    (%rax,%rax,4),%rbp
  lea    -0x1(%r9),%eax
  push   %rbx
  mov    %rcx,%rbx
  mov    0x28(%rsp),%r11
  mov    %rdi,%rcx
  add    %rbp,%rbp
  lea    0x4(%rbx,%rax,4),%r9
  xchg   %ax,%ax
L85:
  mov    %rbx,%rdx
  mov    %r11,%rax
  cs nopw 0x0(%rax,%rax,1)
L100:
  movl   $0x0,(%rax)
  test   %esi,%esi
  jle    L81
  mov    (%rdx),%r8d
  imul   (%rcx),%r8d
  mov    %r8d,(%rax)
  cmp    $0x1,%esi
  je     L81
  mov    0x4(%rcx),%edi
  imul   0x28(%rdx),%edi
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x2,%esi
  je     L81
  mov    0x8(%rcx),%r8d
  imul   0x50(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x3,%esi
  je     L81
  mov    0xc(%rcx),%r8d
  imul   0x78(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x4,%esi
  je     L81
  mov    0x10(%rcx),%r8d
  imul   0xa0(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x5,%esi
  je     L81
  mov    0x14(%rcx),%r8d
  imul   0xc8(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x6,%esi
  je     L81
  mov    0x18(%rcx),%r8d
  imul   0xf0(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x7,%esi
  je     L81
  mov    0x1c(%rcx),%r8d
  imul   0x118(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x8,%esi
  je     L81
  mov    0x20(%rcx),%r8d
  imul   0x140(%rdx),%r8d
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0x9,%esi
  je     L81
  mov    0x24(%rcx),%r8d
  imul   0x168(%rdx),%r8d
  add    %edi,%r8d
  mov    %r8d,(%rax)
  cmp    $0xa,%esi
  je     L81
  mov    0x28(%rcx),%edi
  imul   0x190(%rdx),%edi
  add    %r8d,%edi
  mov    %edi,(%rax)
  cmp    $0xb,%esi
  je     L81
  mov    %rdx,%r12
  mov    $0xb,%r8d
L49:
  mov    (%rcx,%r8,4),%r13d
  add    $0x1,%r8
  add    $0x28,%r12
  imul   0x190(%r12),%r13d
  add    %r13d,%edi
  mov    %edi,(%rax)
  cmp    %r8d,%esi
  jg     L49
  nopl   0x0(%rax)
L81:
  add    $0x4,%rdx
  add    $0x4,%rax
  cmp    %r9,%rdx
  jne    L100
  add    $0xa,%r10
  add    $0x28,%r11
  add    $0x28,%rcx
  cmp    %rbp,%r10
  jne    L85
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  ret
```

assistant: ```c
void matrix_multiply(int m1[][10], int r1, int c1, int m2[][10], int r2, int c2, int product[][10]) {
  int i, j, k;
  for (i = 0; i < r1; i++)
    for (j = 0; j < c2; j++) {
      product[i][j] = 0;
      for (k = 0; k < c1; k++)
        product[i][j] += m1[i][k] * m2[k][j];
    }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strv_join>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L96
  lea    D0(%rip),%rax
  mov    %rax,-0x40(%rbp)
L96:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L37
L8:
  cmpq   $0x0,-0x18(%rbp)
  je     L12
  mov    -0x10(%rbp),%rax
  add    %rax,-0x18(%rbp)
L12:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rax,-0x18(%rbp)
  addq   $0x8,-0x20(%rbp)
L37:
  cmpq   $0x0,-0x20(%rbp)
  je     L109
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
L109:
  mov    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L74
L7:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L67
L40:
  mov    -0x28(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L75
  mov    -0x40(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stpcpy@plt>
  mov    %rax,-0x28(%rbp)
L75:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stpcpy@plt>
  mov    %rax,-0x28(%rbp)
  addq   $0x8,-0x20(%rbp)
L67:
  cmpq   $0x0,-0x20(%rbp)
  je     L89
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L40
L89:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L74:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D0:  

assistant: ```c
char *strv_join(char **l, const char *separator) {
  char *r, *e;
  char **s;
  size_t n, k;
  if (!separator)
    separator = " ";
  k = strlen(separator);
  n = 0;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (n != 0)
      n += k;
    n += strlen(*s);
  }
  r = ((char *)malloc(sizeof(char) * (n + 1)));
  if (!r)
    return NULL;
  e = r;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (e != r)
      e = stpcpy(e, separator);
    e = stpcpy(e, *s);
  }
  *e = 0;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strv_join>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %rsi,%rsi
  lea    D3(%rip),%rax
  cmove  %rax,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    %rbp,%r14
  mov    $0x0,%ebx
  test   %rbp,%rbp
  jne    L18
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L86
  mov    %rax,%rbx
L79:
  movb   $0x0,(%rdi)
L90:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  lea    (%rbx,%r15,1),%rax
  test   %rbx,%rbx
  cmovne %rax,%rbx
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %rax,%rbx
  add    $0x8,%r14
L18:
  mov    (%r14),%r13
  test   %r13,%r13
  jne    L57
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L98
  mov    %rax,%rdi
  jmp    L81
L28:
  mov    0x0(%rbp),%rsi
  call   <stpcpy@plt>
  mov    %rax,%rdi
  add    $0x8,%rbp
L81:
  cmpq   $0x0,0x0(%rbp)
  je     L79
  cmp    %rdi,%rbx
  je     L28
  mov    %r12,%rsi
  call   <stpcpy@plt>
  mov    %rax,%rdi
  jmp    L28
L98:
  mov    %r13,%rbx
  jmp    L90
L86:
  mov    %rbp,%rbx
  jmp    L90
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3:  

assistant: ```c
char *strv_join(char **l, const char *separator) {
  char *r, *e;
  char **s;
  size_t n, k;
  if (!separator)
    separator = " ";
  k = strlen(separator);
  n = 0;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (n != 0)
      n += k;
    n += strlen(*s);
  }
  r = ((char *)malloc(sizeof(char) * (n + 1)));
  if (!r)
    return NULL;
  e = r;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (e != r)
      e = stpcpy(e, separator);
    e = stpcpy(e, *s);
  }
  *e = 0;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strv_join>:
  endbr64
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %rsi,%rsi
  je     L31
  mov    %rsi,%rdi
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%r14
L31:
  mov    %rbp,%r13
  xor    %ebx,%ebx
  test   %rbp,%rbp
  jne    L45
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L77:
  test   %rbx,%rbx
  lea    (%rbx,%r14,1),%rax
  cmovne %rax,%rbx
  add    $0x8,%r13
  call   <strlen@plt>
  add    %rax,%rbx
L45:
  mov    0x0(%r13),%rdi
  test   %rdi,%rdi
  jne    L77
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L25
  jmp    L10
  nopl   (%rax)
L46:
  cmp    %rdi,%r13
  je     L60
  mov    %r12,%rsi
  call   <stpcpy@plt>
  mov    0x0(%rbp),%rsi
  mov    %rax,%rdi
L60:
  call   <stpcpy@plt>
  add    $0x8,%rbp
  mov    %rax,%rdi
L25:
  mov    0x0(%rbp),%rsi
  test   %rsi,%rsi
  jne    L46
L35:
  movb   $0x0,(%rdi)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L14
L10:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    %rax,%r13
  jmp    L35
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9:  

assistant: ```c
char *strv_join(char **l, const char *separator) {
  char *r, *e;
  char **s;
  size_t n, k;
  if (!separator)
    separator = " ";
  k = strlen(separator);
  n = 0;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (n != 0)
      n += k;
    n += strlen(*s);
  }
  r = ((char *)malloc(sizeof(char) * (n + 1)));
  if (!r)
    return NULL;
  e = r;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (e != r)
      e = stpcpy(e, separator);
    e = stpcpy(e, *s);
  }
  *e = 0;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strv_join>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  test   %rsi,%rsi
  je     L127
  mov    %rsi,%rdi
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%r13
L127:
  test   %rbp,%rbp
  je     L121
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L53
  mov    %rbp,%r14
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L143:
  test   %rax,%rax
  je     L61
  add    $0x8,%r14
  lea    0x0(%r13,%rax,1),%rbx
  call   <strlen@plt>
  mov    (%r14),%rdi
  add    %rbx,%rax
  test   %rdi,%rdi
  jne    L143
L4:
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L71
L60:
  mov    0x0(%rbp),%rsi
  mov    %rax,%rdi
  test   %rsi,%rsi
  jne    L145
  jmp    L123
  nopl   0x0(%rax)
L124:
  mov    %r12,%rsi
  call   <stpcpy@plt>
  mov    0x0(%rbp),%rsi
  mov    %rax,%rdi
L0:
  call   <stpcpy@plt>
  mov    0x8(%rbp),%rsi
  add    $0x8,%rbp
  mov    %rax,%rdi
  test   %rsi,%rsi
  je     L123
L145:
  cmp    %rdi,%r13
  jne    L124
  mov    %r13,%rdi
  jmp    L0
  xchg   %ax,%ax
L61:
  call   <strlen@plt>
  mov    0x8(%r14),%rdi
  add    $0x8,%r14
  test   %rdi,%rdi
  jne    L143
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L60
L71:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L121:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L71
  mov    %rax,%r13
L123:
  movb   $0x0,(%rdi)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  xor    %eax,%eax
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6:  

assistant: ```c
char *strv_join(char **l, const char *separator) {
  char *r, *e;
  char **s;
  size_t n, k;
  if (!separator)
    separator = " ";
  k = strlen(separator);
  n = 0;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (n != 0)
      n += k;
    n += strlen(*s);
  }
  r = ((char *)malloc(sizeof(char) * (n + 1)));
  if (!r)
    return NULL;
  e = r;
  for ((s) = (l); (s) && *(s); (s)++) {
    if (e != r)
      e = stpcpy(e, separator);
    e = stpcpy(e, *s);
  }
  *e = 0;
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <fn1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  fn1(0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <fn1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fn1(0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <fn1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  fn1(0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Find_Shortest_Route>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  and    %eax,-0x30(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L51
L20:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L7
L45:
  mov    -0x1c(%rbp),%eax
  mov    -0x30(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L26
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x30(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Find_Shortest_Route>
  add    %ebx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jge    L26
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L26:
  addl   $0x1,-0x1c(%rbp)
L7:
  cmpl   $0xf,-0x1c(%rbp)
  jle    L45
  mov    -0x18(%rbp),%eax
L51:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int Find_Shortest_Route(int **distances, int startNode, uint16_t unvisitedMask) {
  int n, minDist, nextDist;
  unvisitedMask &= ~(1 << startNode);
  if (unvisitedMask == 0x0000)
    return 0;
  minDist = INT_MAX;
  for (n = 0; n < 16; n++) {
    if (unvisitedMask & (1 << n)) {
      nextDist = distances[startNode][n] + Find_Shortest_Route(distances, n, unvisitedMask);
      if (nextDist < minDist)
        minDist = nextDist;
    }
  }
  return minDist;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Find_Shortest_Route>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  btr    %esi,%edx
  mov    %edx,%r13d
  test   %edx,%edx
  je     L13
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    D6(%rip),%rax
  mov    (%rax),%r13d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%r14
  mov    $0x0,%ebx
  jmp    L38
L23:
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  je     L13
L38:
  mov    %ebx,%esi
  bt     %ebx,%ebp
  jae    L23
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <Find_Shortest_Route>
  mov    (%r14),%rdx
  add    (%rdx,%rbx,4),%eax
  cmp    %eax,%r13d
  cmovg  %eax,%r13d
  jmp    L23
L13:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int Find_Shortest_Route(int **distances, int startNode, uint16_t unvisitedMask) {
  int n, minDist, nextDist;
  unvisitedMask &= ~(1 << startNode);
  if (unvisitedMask == 0x0000)
    return 0;
  minDist = INT_MAX;
  for (n = 0; n < 16; n++) {
    if (unvisitedMask & (1 << n)) {
      nextDist = distances[startNode][n] + Find_Shortest_Route(distances, n, unvisitedMask);
      if (nextDist < minDist)
        minDist = nextDist;
    }
  }
  return minDist;
}
```