user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shellSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  jmp    L19
L33:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L79:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L78
L61:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L73
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
L78:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L61
  jmp    L20
L73:
  nop
L20:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L79
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <printArray@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
L19:
  cmpl   $0x0,-0x8(%rbp)
  jg     L33
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D36
type_guessed: string
name: disassemble_data
arguments: tag: D43
type_guessed: string
name: disassemble_data
arguments: tag: D1
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D20
type_guessed: string

tool: D36: Increment: %d


tool: D43: i: %d


tool: D1: tmp: %d


tool: D14: j: %d


tool: D15: %d-sort:

tool: D20: after %d-sort:

assistant: ```c
void shellSort(int A[], int N) {
  int i, j, increment, tmp;
  for (increment = N / 2; increment > 0; increment /= 2) {
    printf("Increment: %d\n", increment);
    for (i = increment; i < N; i++) {
      printf("i: %d\n", i);
      tmp = A[i];
      printf("tmp: %d\n", tmp);
      for (j = i; j >= increment; j -= increment) {
        printf("j: %d\n", j);
        if (tmp < A[j - increment])
          A[j] = A[j - increment];
        else
          break;
      }
      A[j] = tmp;
      printf("%d-sort:", increment);
      printArray(A, N);
    }
    printf("after %d-sort:", increment);
    printArray(A, N);
  }
}
```