ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<pthread_cond_init>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <cond_init@plt>
```

assistant: ```c
int pthread_cond_init(pthread_cond_t *cond, const pthread_condattr_t *attr) {
  (void)attr;
  assert(cond);
  return cond_init(cond);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<m68k_op_rtm_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <m68ki_exception_illegal@plt>
  pop    %rbp
  ret
```

assistant: ```c
void m68k_op_rtm_32(void) {
  if (0) {
    ;

    ;
    return;
  }
  m68ki_exception_illegal();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<m68k_op_rtm_32>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <m68ki_exception_illegal@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void m68k_op_rtm_32(void) {
  if (0) {
    ;

    ;
    return;
  }
  m68ki_exception_illegal();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m68k_op_rtm_32>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <m68ki_exception_illegal@plt>
```

assistant: ```c
void m68k_op_rtm_32(void) {
  if (0) {
    ;

    ;
    return;
  }
  m68ki_exception_illegal();
}
```
user: Translate the below assembly code into C programming language:

```asm
<m68k_op_rtm_32>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <m68ki_exception_illegal@plt>
```

assistant: ```c
void m68k_op_rtm_32(void) {
  if (0) {
    ;

    ;
    return;
  }
  m68ki_exception_illegal();
}
```
user: What is the c source code of the assembly code below?

```asm
<pkey_gost01_cp_sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_CTX_get0_pkey@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L23
  mov    $0x0,%eax
  jmp    L56
L23:
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
  mov    -0x28(%rbp),%rax
  movq   $0x40,(%rax)
  mov    $0x1,%eax
  jmp    L56
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <EVP_PKEY_get0@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <gost2001_do_sign@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L55
  mov    $0x0,%eax
  jmp    L56
L55:
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <pack_sign_cp@plt>
L56:
  leave
  ret
```

assistant: ```c
int pkey_gost01_cp_sign(EVP_PKEY_CTX *ctx, unsigned char *sig, size_t *siglen, const unsigned char *tbs, size_t tbs_len) {
  DSA_SIG *unpacked_sig = NULL;
  EVP_PKEY *pkey = EVP_PKEY_CTX_get0_pkey(ctx);
  if (!siglen)
    return 0;
  if (!sig) {
    *siglen = 64;
    return 1;
  }
  unpacked_sig = gost2001_do_sign(tbs, tbs_len, EVP_PKEY_get0(pkey));
  if (!unpacked_sig) {
    return 0;
  }
  return pack_sign_cp(unpacked_sig, 32, sig, siglen);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pkey_gost01_cp_sign>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  call   <EVP_PKEY_CTX_get0_pkey@plt>
  test   %rbx,%rbx
  je     L3
  test   %rbp,%rbp
  je     L9
  mov    %rax,%rdi
  call   <EVP_PKEY_get0@plt>
  mov    %eax,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <gost2001_do_sign@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L12
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    $0x20,%esi
  call   <pack_sign_cp@plt>
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  movq   $0x40,(%rbx)
  mov    $0x1,%eax
  jmp    L12
L3:
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
int pkey_gost01_cp_sign(EVP_PKEY_CTX *ctx, unsigned char *sig, size_t *siglen, const unsigned char *tbs, size_t tbs_len) {
  DSA_SIG *unpacked_sig = NULL;
  EVP_PKEY *pkey = EVP_PKEY_CTX_get0_pkey(ctx);
  if (!siglen)
    return 0;
  if (!sig) {
    *siglen = 64;
    return 1;
  }
  unpacked_sig = gost2001_do_sign(tbs, tbs_len, EVP_PKEY_get0(pkey));
  if (!unpacked_sig) {
    return 0;
  }
  return pack_sign_cp(unpacked_sig, 32, sig, siglen);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pkey_gost01_cp_sign>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <EVP_PKEY_CTX_get0_pkey@plt>
  test   %r12,%r12
  je     L18
  test   %r13,%r13
  je     L5
  mov    %rax,%rdi
  call   <EVP_PKEY_get0@plt>
  mov    %rbp,%rdi
  mov    %r14,%rsi
  mov    %eax,%edx
  call   <gost2001_do_sign@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L18
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    $0x20,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <pack_sign_cp@plt>
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  movq   $0x40,(%r12)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int pkey_gost01_cp_sign(EVP_PKEY_CTX *ctx, unsigned char *sig, size_t *siglen, const unsigned char *tbs, size_t tbs_len) {
  DSA_SIG *unpacked_sig = NULL;
  EVP_PKEY *pkey = EVP_PKEY_CTX_get0_pkey(ctx);
  if (!siglen)
    return 0;
  if (!sig) {
    *siglen = 64;
    return 1;
  }
  unpacked_sig = gost2001_do_sign(tbs, tbs_len, EVP_PKEY_get0(pkey));
  if (!unpacked_sig) {
    return 0;
  }
  return pack_sign_cp(unpacked_sig, 32, sig, siglen);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pkey_gost01_cp_sign>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <EVP_PKEY_CTX_get0_pkey@plt>
  test   %r12,%r12
  je     L29
  test   %r13,%r13
  je     L24
  mov    %rax,%rdi
  call   <EVP_PKEY_get0@plt>
  mov    %rbp,%rdi
  mov    %r14,%rsi
  mov    %eax,%edx
  call   <gost2001_do_sign@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L29
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    $0x20,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <pack_sign_cp@plt>
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  movq   $0x40,(%r12)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int pkey_gost01_cp_sign(EVP_PKEY_CTX *ctx, unsigned char *sig, size_t *siglen, const unsigned char *tbs, size_t tbs_len) {
  DSA_SIG *unpacked_sig = NULL;
  EVP_PKEY *pkey = EVP_PKEY_CTX_get0_pkey(ctx);
  if (!siglen)
    return 0;
  if (!sig) {
    *siglen = 64;
    return 1;
  }
  unpacked_sig = gost2001_do_sign(tbs, tbs_len, EVP_PKEY_get0(pkey));
  if (!unpacked_sig) {
    return 0;
  }
  return pack_sign_cp(unpacked_sig, 32, sig, siglen);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vuln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <setresgid@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: /bin/sh -i

assistant: ```c
void vuln() {
  gid_t gid = getegid();
  setresgid(gid, gid, gid);
  system("/bin/sh -i");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vuln>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getegid@plt>
  mov    %eax,%edi
  mov    %eax,%edx
  mov    %eax,%esi
  call   <setresgid@plt>
  lea    D7(%rip),%rdi
  call   <system@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: /bin/sh -i

assistant: ```c
void vuln() {
  gid_t gid = getegid();
  setresgid(gid, gid, gid);
  system("/bin/sh -i");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vuln>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getegid@plt>
  mov    %eax,%edi
  mov    %eax,%edx
  mov    %eax,%esi
  call   <setresgid@plt>
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <system@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: /bin/sh -i

assistant: ```c
void vuln() {
  gid_t gid = getegid();
  setresgid(gid, gid, gid);
  system("/bin/sh -i");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vuln>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getegid@plt>
  mov    %eax,%edi
  mov    %eax,%edx
  mov    %eax,%esi
  call   <setresgid@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <system@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: /bin/sh -i

assistant: ```c
void vuln() {
  gid_t gid = getegid();
  setresgid(gid, gid, gid);
  system("/bin/sh -i");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L17
L10:
  subq   $0x1,-0x8(%rbp)
L17:
  cmpq   $0x0,-0x8(%rbp)
  jg     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay(uint32_t i) {
  for (; i > 0; i--)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<delay>:
  endbr64
  test   %rdi,%rdi
  jle    L3
L8:
  sub    $0x1,%rdi
  jne    L8
L3:
  ret
```

assistant: ```c
void delay(uint32_t i) {
  for (; i > 0; i--)
    ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<delay>:
  endbr64
  ret
```

assistant: ```c
void delay(uint32_t i) {
  for (; i > 0; i--)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<delay>:
  endbr64
  ret
```

assistant: ```c
void delay(uint32_t i) {
  for (; i > 0; i--)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L4
L10:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  test   %eax,%eax
  jne    L10
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D1(%rip),%xmm0
  comiss -0x10(%rbp),%xmm0
  jb     L3
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  movss  -0x10(%rbp),%xmm0
  comiss D1(%rip),%xmm0
  jbe    L22
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D42
type: string
name: retrieve_data
arguments: data_tag: D1
type: byte[4]
name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D39
type: string

tool: D42: %d

tool: {"D1": [0x00,0x00,0xe0,0x40]}

tool: D8: light

tool: D39: heavy

assistant: ```c
int main() {
  int n, sum, count = 0, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    sum = sum + k;
    n = n / 10;
    count++;
  }
  float avg;
  avg = sum / count;
  if (avg <= 7) {
    printf("light");
  }
  if (avg > 7) {
    printf("heavy");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  je     L0
  mov    $0x0,%esi
L28:
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  add    %ecx,%ebx
  mov    %edx,%ecx
  add    $0x1,%esi
  test   %edx,%edx
  jne    L28
  movl   $0x0,0x14(%rsp)
L60:
  mov    %ebx,%eax
  cltd
  idiv   %esi
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  %xmm1,0xc(%rsp)
  movss  D26(%rip),%xmm0
  comiss %xmm1,%xmm0
  jae    L79
L19:
  movss  0xc(%rsp),%xmm2
  comiss D26(%rip),%xmm2
  ja     L7
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  mov    %ecx,%esi
  jmp    L60
L79:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L7:
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L29
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D32
data_type: string
name: unpack_data
arguments: data_label: D26
data_type: byte[4]
name: unpack_data
arguments: data_label: D25
data_type: string
name: unpack_data
arguments: data_label: D43
data_type: string

tool: D32: %d

tool: {"D26": [0x00,0x00,0xe0,0x40]}

tool: D25: light

tool: D43: heavy

assistant: ```c
int main() {
  int n, sum, count = 0, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    sum = sum + k;
    n = n / 10;
    count++;
  }
  float avg;
  avg = sum / count;
  if (avg <= 7) {
    printf("light");
  }
  if (avg > 7) {
    printf("heavy");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D13(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  je     10a0 <main.cold>
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  add    $0x1,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%ebx
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L13
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  movss  D29(%rip),%xmm1
  movl   $0x0,0x14(%rsp)
  cltd
  idiv   %edi
  cvtsi2ss %eax,%xmm0
  comiss %xmm0,%xmm1
  jb     L15
  lea    D2(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
L15:
  comiss D29(%rip),%xmm0
  ja     L42
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L42:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L45
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D29
type: byte[4]
name: parse_data
arguments: data_tag: D2
type: string
name: parse_data
arguments: data_tag: D28
type: string

tool: D13: %d

tool: {"D29": [0x00,0x00,0xe0,0x40]}

tool: D2: light

tool: D28: heavy

assistant: ```c
int main() {
  int n, sum, count = 0, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    sum = sum + k;
    n = n / 10;
    count++;
  }
  float avg;
  avg = sum / count;
  if (avg <= 7) {
    printf("light");
  }
  if (avg > 7) {
    printf("heavy");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D35(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  test   %ecx,%ecx
  je     10a0 <main.cold>
  xor    %edi,%edi
  nopl   0x0(%rax,%rax,1)
L40:
  movslq %ecx,%rdx
  mov    %ecx,%eax
  add    $0x1,%edi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    %ecx,%ebx
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L40
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  movss  D31(%rip),%xmm1
  movl   $0x0,0x14(%rsp)
  cltd
  idiv   %edi
  cvtsi2ss %eax,%xmm0
  comiss %xmm0,%xmm1
  jb     L32
  lea    D16(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
L32:
  comiss D31(%rip),%xmm0
  ja     L43
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L43:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D35
type: string
name: extract_symbolic_data
arguments: data_label: D31
type: byte[4]
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string

tool: D35: %d

tool: {"D31": [0x00,0x00,0xe0,0x40]}

tool: D16: light

tool: D8: heavy

assistant: ```c
int main() {
  int n, sum, count = 0, k;
  scanf("%d", &n);
  while (n != 0) {
    k = n % 10;
    sum = sum + k;
    n = n / 10;
    count++;
  }
  float avg;
  avg = sum / count;
  if (avg <= 7) {
    printf("light");
  }
  if (avg > 7) {
    printf("heavy");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D93(%rip),%rdi
  call   <scanf@plt>
  testb  $0x1,(%rsp)
  je     L13
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  testb  $0x3,(%rsp)
  je     L33
  lea    D59(%rip),%rdi
  call   <puts@plt>
L4:
  mov    (%rsp),%eax
  lea    (%rax,%rax,1),%esi
  lea    D47(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D85(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  rol    %cl,%esi
  lea    D97(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  ror    %cl,%esi
  lea    D49(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L13:
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L33:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D93
data_type: string
name: parse_data
arguments: tag: D55
data_type: string
name: parse_data
arguments: tag: D59
data_type: string
name: parse_data
arguments: tag: D47
data_type: string
name: parse_data
arguments: tag: D85
data_type: string
name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D97
data_type: string
name: parse_data
arguments: tag: D49
data_type: string
name: parse_data
arguments: tag: D25
data_type: string
name: parse_data
arguments: tag: D7
data_type: string

tool: D93: %u

tool: D55: 
n is odd

tool: D59: 
n is not divisible by 4

tool: D47: 
2n = %u


tool: D85: 
k:?

tool: D26: %d

tool: D97: 
m after left rotation by k bits = %u


tool: D49: 
m after right rotation by k bits = %u


tool: D25: 
n is even

tool: D7: 
n is divisible by 4

assistant: ```c
int main() {
  unsigned int m, n, compn;
  int k;
  scanf("%u", &n);
  m = n & 1;
  if (m)
    printf("\nn is odd");
  else
    printf("\nn is even");
  compn = ~n;
  if ((compn & 1) && (compn & (1 << 1)))
    printf("\nn is divisible by 4\n");
  else
    printf("\nn is not divisible by 4\n");
  m = n << 1;
  printf("\n2n = %u\n", m);
  printf("\nk:?\n");
  scanf("%d", &k);
  m = n << k | n >> ((sizeof(int) * 8) - k);
  printf("\nm after left rotation by k bits = %u\n", m);
  m = n >> k | n << ((sizeof(int) * 8) - k);
  printf("\nm after right rotation by k bits = %u\n", m);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  testb  $0x1,(%rsp)
  je     L44
  lea    D96(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L14:
  testb  $0x3,(%rsp)
  je     L2
  lea    D64(%rip),%rdi
  call   <puts@plt>
L4:
  mov    (%rsp),%eax
  lea    D48(%rip),%rdi
  lea    (%rax,%rax,1),%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D47(%rip),%rdi
  rol    %cl,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%ecx
  mov    (%rsp),%esi
  xor    %eax,%eax
  lea    D45(%rip),%rdi
  ror    %cl,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L44:
  lea    D88(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L14
L2:
  lea    D60(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D96
type_guessed: string
name: read_data
arguments: data_label: D64
type_guessed: string
name: read_data
arguments: data_label: D48
type_guessed: string
name: read_data
arguments: data_label: D40
type_guessed: string
name: read_data
arguments: data_label: D42
type_guessed: string
name: read_data
arguments: data_label: D47
type_guessed: string
name: read_data
arguments: data_label: D45
type_guessed: string
name: read_data
arguments: data_label: D88
type_guessed: string
name: read_data
arguments: data_label: D60
type_guessed: string

tool: D9: %u

tool: D96: 
n is odd

tool: D64: 
n is not divisible by 4

tool: D48: 
2n = %u


tool: D40: 
k:?

tool: D42: %d

tool: D47: 
m after left rotation by k bits = %u


tool: D45: 
m after right rotation by k bits = %u


tool: D88: 
n is even

tool: D60: 
n is divisible by 4

assistant: ```c
int main() {
  unsigned int m, n, compn;
  int k;
  scanf("%u", &n);
  m = n & 1;
  if (m)
    printf("\nn is odd");
  else
    printf("\nn is even");
  compn = ~n;
  if ((compn & 1) && (compn & (1 << 1)))
    printf("\nn is divisible by 4\n");
  else
    printf("\nn is not divisible by 4\n");
  m = n << 1;
  printf("\n2n = %u\n", m);
  printf("\nk:?\n");
  scanf("%d", &k);
  m = n << k | n >> ((sizeof(int) * 8) - k);
  printf("\nm after left rotation by k bits = %u\n", m);
  m = n >> k | n << ((sizeof(int) * 8) - k);
  printf("\nm after right rotation by k bits = %u\n", m);
  return 0;
}
```