user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L3
L53:
  addl   $0x1,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L96
L95:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <cardNumber@plt>
  test   %al,%al
  jle    L43
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <cardNumber@plt>
  movsbl %al,%eax
  jmp    L9
L43:
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
L9:
  mov    %eax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <cardNumber@plt>
  test   %al,%al
  jle    L16
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <cardNumber@plt>
  movsbl %al,%eax
  jmp    L29
L16:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
L29:
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L78
  mov    -0x2c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%eax
  mov    %al,-0x2d(%rbp)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %dl,-0x15(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x2d(%rbp),%edx
  mov    %dl,-0x15(%rbp,%rax,1)
  movl   $0x0,-0x24(%rbp)
L78:
  addl   $0x1,-0x2c(%rbp)
L96:
  mov    $0xd,%eax
  sub    -0x28(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L95
L3:
  cmpl   $0x0,-0x24(%rbp)
  je     L53
  lea    -0x15(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L94
  call   <__stack_chk_fail@plt>
L94:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D24
type_infered: string
name: extract_symbolic_data
arguments: data_label: D28
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D24: %s

tool: D28: Original: %s


tool: D3: Sorted: %s


assistant: ```c
int main() {
  int i, j = 0, sorted = 0, n, m;
  char deck[13], temp;
  scanf("%s", deck);
  printf("Original: %s\n", deck);
  while (!sorted) {
    j++;
    sorted = 1;
    for (i = 0; i < 13 - j; i++) {
      n = cardNumber(deck[i]) > 0 ? cardNumber(deck[i]) : deck[i] - '0';
      m = cardNumber(deck[i + 1]) > 0 ? cardNumber(deck[i + 1]) : deck[i + 1] - '0';
      if (n > m) {
        temp = deck[i];
        deck[i] = deck[i + 1];
        deck[i + 1] = temp;
        sorted = 0;
      }
    }
  }
  printf("Sorted: %s\n", deck);
  return 0;
}
```