ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  lea    D13(%rip),%rdi
  lea    D59(%rip),%r12
  push   %rbp
  lea    D107(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x10,%rsp
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  movss  D47(%rip),%xmm2
  nopl   0x0(%rax,%rax,1)
L9:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm2,%xmm0
  movapd %xmm0,%xmm1
  subsd  D77(%rip),%xmm1
  mulsd  D100(%rip),%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  subss  D69(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L9
  mov    %r12,%rdi
  mov    $0x10,%ebx
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  movss  D47(%rip),%xmm2
  nopl   (%rax)
L11:
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm2,%xmm0
  movapd %xmm0,%xmm1
  divsd  D100(%rip),%xmm1
  addsd  D77(%rip),%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  subss  D69(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L11
  mov    %r12,%rdi
  call   <puts@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D59
type: string
name: extract_symbolic_data
arguments: tag: D107
type: string
name: extract_symbolic_data
arguments: tag: D47
type: byte[4]
name: extract_symbolic_data
arguments: tag: D77
type: f64
name: extract_symbolic_data
arguments: tag: D100
type: byte[8]
name: extract_symbolic_data
arguments: tag: D69
type: byte[4]
name: extract_symbolic_data
arguments: tag: D12
type: string

tool: D13: Fahrenheit | Celcius

tool: D59: --------------------

tool: D107: %10.f | %6.1f


tool: {"D47": [0x00,0x00,0x96,0x43]}

tool: D77: 32

tool: {"D100": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D69": [0x00,0x00,0xa0,0x41]}

tool: D12: Celcius | Fahrenheit

assistant: ```c
int main() {
  float degrees;
  printf("Fahrenheit | Celcius\n");
  printf("--------------------\n");
  for (degrees = 300; degrees >= 0; degrees -= 20)
    printf("%10.f | %6.1f\n", degrees, (5.0 / 9.0) * (degrees - 32.0));
  printf("--------------------\n");
  printf("\n");
  printf("Celcius | Fahrenheit\n");
  printf("--------------------\n");
  for (degrees = 300; degrees >= 0; degrees -= 20)
    printf("%10.f | %6.1f\n", degrees, ((degrees / (5.0 / 9.0)) + 32.0));
  printf("--------------------\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<csum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L3:
  mov    -0x18(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,-0x8(%rbp)
  subl   $0x1,-0x1c(%rbp)
L4:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L3
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  movzwl %ax,%eax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x10,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  not    %eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short csum(unsigned short *buf, int nwords) {
  unsigned long sum;
  for (sum = 0; nwords > 0; nwords--) {
    sum += *buf++;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<csum>:
  endbr64
  test   %esi,%esi
  jle    L4
  mov    %esi,%esi
  lea    (%rdi,%rsi,2),%rcx
  mov    $0x0,%eax
L21:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L21
L3:
  mov    %rax,%rdx
  shr    $0x10,%rdx
  movzwl %ax,%eax
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
L4:
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
unsigned short csum(unsigned short *buf, int nwords) {
  unsigned long sum;
  for (sum = 0; nwords > 0; nwords--) {
    sum += *buf++;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<csum>:
  endbr64
  test   %esi,%esi
  jle    L17
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    (%rdi,%rsi,2),%rcx
  nopl   0x0(%rax)
L8:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L8
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
unsigned short csum(unsigned short *buf, int nwords) {
  unsigned long sum;
  for (sum = 0; nwords > 0; nwords--) {
    sum += *buf++;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<csum>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L66
  cmp    $0x7,%esi
  jle    L88
  mov    %esi,%ecx
  pxor   %xmm2,%xmm2
  pxor   %xmm4,%xmm4
  mov    %rdi,%rax
  shr    $0x3,%ecx
  pxor   %xmm3,%xmm3
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L33:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  punpckhwd %xmm4,%xmm0
  movdqa %xmm0,%xmm5
  punpcklwd %xmm4,%xmm1
  punpckhdq %xmm3,%xmm0
  punpckldq %xmm3,%xmm5
  paddq  %xmm5,%xmm0
  movdqa %xmm1,%xmm5
  punpckldq %xmm3,%xmm1
  punpckhdq %xmm3,%xmm5
  paddq  %xmm5,%xmm1
  paddq  %xmm1,%xmm0
  paddq  %xmm0,%xmm2
  cmp    %rcx,%rax
  jne    L33
  movdqa %xmm2,%xmm0
  mov    %edx,%ecx
  and    $0xfffffff8,%ecx
  psrldq $0x8,%xmm0
  paddq  %xmm0,%xmm2
  mov    %ecx,%r8d
  sub    %ecx,%edx
  movq   %xmm2,%rax
  lea    (%rdi,%r8,2),%rdi
  cmp    %esi,%ecx
  je     L19
L68:
  movzwl (%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x1,%edx
  je     L19
  movzwl 0x2(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x2,%edx
  je     L19
  movzwl 0x4(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x3,%edx
  je     L19
  movzwl 0x6(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x4,%edx
  je     L19
  movzwl 0x8(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x5,%edx
  je     L19
  movzwl 0xa(%rdi),%ecx
  add    %rcx,%rax
  cmp    $0x6,%edx
  je     L19
  movzwl 0xc(%rdi),%edx
  add    %rdx,%rax
L19:
  mov    %rax,%rdx
  movzwl %ax,%eax
  shr    $0x10,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  add    %rdx,%rax
  not    %eax
  ret
  nopl   (%rax)
L66:
  mov    $0xffffffff,%eax
  ret
L88:
  xor    %eax,%eax
  jmp    L68
```

assistant: ```c
unsigned short csum(unsigned short *buf, int nwords) {
  unsigned long sum;
  for (sum = 0; nwords > 0; nwords--) {
    sum += *buf++;
  }
  sum = (sum >> 16) + (sum & 0xffff);
  sum += (sum >> 16);
  return (unsigned short)(~sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putnum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L29
  mov    $0x30,%edi
  call   <putch@plt>
  jmp    L5
L29:
  cmpl   $0x0,-0x1c(%rbp)
  jns    L28
  mov    $0x2d,%edi
  call   <putch@plt>
  negl   -0x1c(%rbp)
L28:
  movl   $0x0,-0x18(%rbp)
L56:
  cmpl   $0x8,-0x18(%rbp)
  jle    L14
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <putsln@plt>
  jmp    L30
L14:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L56
L30:
  jmp    L11
L69:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putch@plt>
L11:
  subl   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L69
L5:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L87
  call   <__stack_chk_fail@plt>
L87:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type_infered: string

tool: D1: Error: Number too large - will only be 10 digits

assistant: ```c
void putnum(int num) {
  int res = num;
  if (res == 0)
    putch('0');
  else {
    if (res < 0) {
      putch('-');
      res = -res;
    }
    char temp[10];
    int i = 0;
    do {
      if (i >= 9) {
        putsln("Error: Number too large - will only be 10 digits");
        break;
      }
      temp[i++] = res % 10 + '0';
      res /= 10;
    } while (res);
    while (--i >= 0) {
      putch(temp[i]);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L69
  mov    %edi,%ebx
  js     L97
L74:
  mov    $0x0,%edx
L57:
  mov    %edx,%ebp
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0xe(%rsp,%rdx,1)
  mov    %eax,%ebx
  test   %eax,%eax
  je     L92
  add    $0x1,%rdx
  cmp    $0x9,%rdx
  jne    L57
  lea    D1(%rip),%rdi
  call   <putsln@plt>
L51:
  movslq %ebp,%rbx
  lea    0xe(%rsp),%rbp
L21:
  movsbl (%rbx,%rbp,1),%edi
  call   <putch@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L21
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L69:
  mov    $0x30,%edi
  call   <putch@plt>
  jmp    L45
L97:
  mov    $0x2d,%edi
  call   <putch@plt>
  neg    %ebx
  jmp    L74
L92:
  test   %ebp,%ebp
  jns    L51
  jmp    L45
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string

tool: D1: Error: Number too large - will only be 10 digits

assistant: ```c
void putnum(int num) {
  int res = num;
  if (res == 0)
    putch('0');
  else {
    if (res < 0) {
      putch('-');
      res = -res;
    }
    char temp[10];
    int i = 0;
    do {
      if (i >= 9) {
        putsln("Error: Number too large - will only be 10 digits");
        break;
      }
      temp[i++] = res % 10 + '0';
      res /= 10;
    } while (res);
    while (--i >= 0) {
      putch(temp[i]);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<putnum>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  je     L31
  mov    %edi,%ebp
  js     L6
L37:
  xor    %ecx,%ecx
  lea    0xe(%rsp),%rbx
  mov    $0xcccccccd,%r8d
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %ebp,%eax
  mov    %ecx,%edx
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ebp
  lea    0x30(%rbp),%edi
  mov    %eax,%ebp
  mov    %dil,(%rbx,%rcx,1)
  test   %eax,%eax
  je     L36
  add    $0x1,%rcx
  cmp    $0x9,%rcx
  jne    L43
  lea    D9(%rip),%rdi
  call   <putsln@plt>
  movzbl 0x16(%rsp),%edi
  mov    $0x8,%edx
L36:
  lea    -0x1(%rdx),%ebp
  movslq %ebp,%rbp
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L25:
  movzbl (%rbx,%rbp,1),%edi
  sub    $0x1,%rbp
L88:
  movsbl %dil,%edi
  call   <putch@plt>
  cmp    $0xffffffff,%ebp
  jne    L25
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  mov    $0x30,%edi
  pop    %rbx
  pop    %rbp
  jmp    1090 <putch@plt>
L6:
  mov    $0x2d,%edi
  neg    %ebp
  call   <putch@plt>
  jmp    L37
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: Error: Number too large - will only be 10 digits

assistant: ```c
void putnum(int num) {
  int res = num;
  if (res == 0)
    putch('0');
  else {
    if (res < 0) {
      putch('-');
      res = -res;
    }
    char temp[10];
    int i = 0;
    do {
      if (i >= 9) {
        putsln("Error: Number too large - will only be 10 digits");
        break;
      }
      temp[i++] = res % 10 + '0';
      res /= 10;
    } while (res);
    while (--i >= 0) {
      putch(temp[i]);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L11
L35:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  je     L35
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2;
  return (int)tolower(*s1) - (int)tolower(*s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L1:
  cmpb   $0x0,(%rbx)
  je     L14
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %rax,%rbp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L14
  add    $0x1,%r12
  add    $0x1,%rbx
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L1
L14:
  movsbl (%r12),%edi
  call   <tolower@plt>
  mov    %rax,%rbp
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %rax,%rdx
  mov    %ebp,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2;
  return (int)tolower(*s1) - (int)tolower(*s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  jne    L29
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L33:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L34
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbx
  test   %dil,%dil
  je     L46
L29:
  cmpb   $0x0,(%rbx)
  jne    L33
L34:
  movsbl (%r12),%edi
L46:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  pop    %rbx
  mov    %rax,%r8
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2;
  return (int)tolower(*s1) - (int)tolower(*s2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  mov    %rsi,%rbx
  test   %dil,%dil
  jne    L43
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L51:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  cmp    %rax,%rbp
  jne    L33
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbx
  test   %dil,%dil
  je     L29
L43:
  cmpb   $0x0,(%rbx)
  jne    L51
L29:
  call   <tolower@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <tolower@plt>
  pop    %rbx
  mov    %rax,%r8
  mov    %ebp,%eax
  pop    %rbp
  pop    %r12
  sub    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  movsbl (%r12),%edi
  jmp    L29
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  while (*s1 && *s2 && tolower(*s1) == tolower(*s2))
    ++s1, ++s2;
  return (int)tolower(*s1) - (int)tolower(*s2);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_first_empty_block_from>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L37
L13:
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <block_read@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_block_icon@plt>
  test   %rax,%rax
  jne    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
  jmp    L14
L7:
  addl   $0x1,-0x14(%rbp)
L37:
  cmpl   $0x1fff,-0x14(%rbp)
  jle    L13
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
L14:
  leave
  ret
```

assistant: ```c
int get_first_empty_block_from(int i) {
  char *buffer = (char *)malloc(4096);
  for (; i < 8192; i++) {
    block_read(i, buffer);
    if (get_block_icon(buffer) == 0) {
      free(buffer);
      return i;
    }
  }
  free(buffer);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_first_empty_block_from>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x1000,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    $0x1fff,%ebx
  jg     L27
L32:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <block_read@plt>
  mov    %rbp,%rdi
  call   <get_block_icon@plt>
  test   %rax,%rax
  je     L36
  add    $0x1,%ebx
  cmp    $0x2000,%ebx
  jne    L32
L27:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %ebx,%eax
  jmp    L25
```

assistant: ```c
int get_first_empty_block_from(int i) {
  char *buffer = (char *)malloc(4096);
  for (; i < 8192; i++) {
    block_read(i, buffer);
    if (get_block_icon(buffer) == 0) {
      free(buffer);
      return i;
    }
  }
  free(buffer);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_first_empty_block_from>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1000,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    $0x1fff,%ebx
  jle    L8
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%ebx
  cmp    $0x2000,%ebx
  je     L11
L8:
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <block_read@plt>
  mov    %rbp,%rdi
  call   <get_block_icon@plt>
  test   %rax,%rax
  jne    L23
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_first_empty_block_from(int i) {
  char *buffer = (char *)malloc(4096);
  for (; i < 8192; i++) {
    block_read(i, buffer);
    if (get_block_icon(buffer) == 0) {
      free(buffer);
      return i;
    }
  }
  free(buffer);
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_first_empty_block_from>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1000,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  cmp    $0x1fff,%ebx
  jle    L22
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%ebx
  cmp    $0x2000,%ebx
  je     L21
L22:
  mov    %ebx,%edi
  mov    %rbp,%rsi
  call   <block_read@plt>
  mov    %rbp,%rdi
  call   <get_block_icon@plt>
  test   %rax,%rax
  jne    L5
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int get_first_empty_block_from(int i) {
  char *buffer = (char *)malloc(4096);
  for (; i < 8192; i++) {
    block_read(i, buffer);
    if (get_block_icon(buffer) == 0) {
      free(buffer);
      return i;
    }
  }
  free(buffer);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strxchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L94
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
L3:
  mov    -0xc(%rbp),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L90
  mov    -0x8(%rbp),%rax
  jmp    L10
L90:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L3
  jmp    L5
L94:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L97
L99:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L39
  mov    -0x8(%rbp),%rax
  jmp    L10
L39:
  subq   $0x1,-0x8(%rbp)
L97:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L99
L5:
  mov    $0x0,%eax
L10:
  leave
  ret
```

assistant: ```c
char *strxchr(char *string, char *delim, int right) {
  char *p;
  if (right == 0) {
    int c;
    p = string;
    while ((c = *p) != 0) {
      if (strchr(delim, c) != NULL)
        return (p);
      p++;
    }
  } else {
    p = string + strlen(string) - 1;
    while (p >= string) {
      if (strchr(delim, *p) != NULL)
        return (p);
      p--;
    }
  }
  return (NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strxchr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  test   %edx,%edx
  jne    L67
  movzbl (%rdi),%eax
  movsbl %al,%esi
  test   %al,%al
  je     L55
L42:
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L62
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%eax
  movsbl %al,%esi
  test   %al,%al
  jne    L42
  jmp    L108
L67:
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L72
L79:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L108
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L79
  mov    %rax,%rbx
  jmp    L108
L55:
  mov    $0x0,%ebx
  jmp    L108
L62:
  mov    %rbp,%rbx
L108:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L72:
  mov    $0x0,%ebx
  jmp    L108
```

assistant: ```c
char *strxchr(char *string, char *delim, int right) {
  char *p;
  if (right == 0) {
    int c;
    p = string;
    while ((c = *p) != 0) {
      if (strchr(delim, c) != NULL)
        return (p);
      p++;
    }
  } else {
    p = string + strlen(string) - 1;
    while (p >= string) {
      if (strchr(delim, *p) != NULL)
        return (p);
      p--;
    }
  }
  return (NULL);
}
```