ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<IL_re_search>:
  endbr64
  sub    $0x10,%rsp
  push   %rdx
  push   %r9
  push   %r8
  mov    %ecx,%r9d
  mov    %edx,%r8d
  mov    %rsi,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%eax
  call   <IL_re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int IL_re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return IL_re_search_2(bufp, (void *)0, 0, string, size, startpos, range, regs, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<IL_re_search>:
  endbr64
  sub    $0x10,%rsp
  xor    %eax,%eax
  push   %rdx
  push   %r9
  mov    %ecx,%r9d
  mov    %rsi,%rcx
  xor    %esi,%esi
  push   %r8
  mov    %edx,%r8d
  xor    %edx,%edx
  call   <IL_re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int IL_re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return IL_re_search_2(bufp, (void *)0, 0, string, size, startpos, range, regs, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IL_re_search>:
  endbr64
  sub    $0x10,%rsp
  xor    %eax,%eax
  push   %rdx
  push   %r9
  mov    %ecx,%r9d
  mov    %rsi,%rcx
  xor    %esi,%esi
  push   %r8
  mov    %edx,%r8d
  xor    %edx,%edx
  call   <IL_re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int IL_re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return IL_re_search_2(bufp, (void *)0, 0, string, size, startpos, range, regs, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tcp_synack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void tcp_synack(struct Squirrel *squirrel, struct NetFrame *frame) {
  squirrel = (squirrel);
  frame = (frame);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tcp_synack>:
  endbr64
  ret
```

assistant: ```c
void tcp_synack(struct Squirrel *squirrel, struct NetFrame *frame) {
  squirrel = (squirrel);
  frame = (frame);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tcp_synack>:
  endbr64
  ret
```

assistant: ```c
void tcp_synack(struct Squirrel *squirrel, struct NetFrame *frame) {
  squirrel = (squirrel);
  frame = (frame);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tcp_synack>:
  endbr64
  ret
```

assistant: ```c
void tcp_synack(struct Squirrel *squirrel, struct NetFrame *frame) {
  squirrel = (squirrel);
  frame = (frame);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L5
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    $0xf,%rax
  ja     L45
L5:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  movq   $0x10,(%rax)
  jmp    L45
L37:
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jb     L30
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
L30:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0xa,-0x4(%rbp)
  je     L56
L45:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L37
  jmp    L1
L56:
  nop
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
ssize_t getline(char **lineptr, size_t *n, FILE *stream) {
  ssize_t written = 0;
  int character;
  if (*lineptr == NULL || *n < 16) {
    free(*lineptr);
    *lineptr = (char *)malloc(16);
    *n = 16;
  }
  while ((character = fgetc(stream)) != EOF) {
    written += 1;
    if (written >= *n) {
      *n = *n * 2;
      *lineptr = realloc(*lineptr, *n);
    }
    (*lineptr)[written - 1] = character;
    if (character == '\n') {
      break;
    }
  }
  (*lineptr)[written] = '\0';
  return written;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%r15
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L60
  cmpq   $0xf,(%rsi)
  ja     L42
L60:
  call   <free@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  movq   $0x10,(%r14)
L42:
  mov    $0x1,%ebp
  jmp    L49
L31:
  mov    (%r12),%rax
  mov    %bl,-0x1(%rax,%rbp,1)
  add    $0x1,%rbp
  cmp    $0xa,%ebx
  je     L11
L49:
  lea    -0x1(%rbp),%r13d
  mov    %r15,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    D8(%rip),%rax
  cmp    %ebx,(%rax)
  je     L11
  mov    %ebp,%r13d
  mov    (%r14),%rsi
  cmp    %rbp,%rsi
  ja     L31
  add    %rsi,%rsi
  mov    %rsi,(%r14)
  mov    (%r12),%rdi
  call   <realloc@plt>
  mov    %rax,(%r12)
  jmp    L31
L11:
  movslq %r13d,%rax
  mov    (%r12),%rdx
  movb   $0x0,(%rdx,%rax,1)
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
ssize_t getline(char **lineptr, size_t *n, FILE *stream) {
  ssize_t written = 0;
  int character;
  if (*lineptr == NULL || *n < 16) {
    free(*lineptr);
    *lineptr = (char *)malloc(16);
    *n = 16;
  }
  while ((character = fgetc(stream)) != EOF) {
    written += 1;
    if (written >= *n) {
      *n = *n * 2;
      *lineptr = realloc(*lineptr, *n);
    }
    (*lineptr)[written - 1] = character;
    if (character == '\n') {
      break;
    }
  }
  (*lineptr)[written] = '\0';
  return written;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getline>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L12
  cmpq   $0xf,(%rsi)
  jbe    L12
L86:
  mov    D4(%rip),%r15
  mov    $0x1,%ebx
  jmp    L9
  nop
L34:
  mov    %dl,-0x1(%rdi,%rbx,1)
  lea    0x1(%rbx),%rax
  cmp    $0xa,%edx
  je     L81
L13:
  mov    %rax,%rbx
L9:
  mov    %r14,%rdi
  lea    -0x1(%rbx),%r12d
  call   <fgetc@plt>
  mov    %eax,%edx
  cmp    %eax,(%r15)
  je     L2
  mov    0x0(%r13),%rsi
  mov    0x0(%rbp),%rdi
  mov    %ebx,%r12d
  cmp    %rbx,%rsi
  ja     L34
  add    %rsi,%rsi
  mov    %edx,0xc(%rsp)
  mov    %rsi,0x0(%r13)
  call   <realloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  lea    0x1(%rbx),%rax
  mov    %dl,-0x1(%rdi,%rbx,1)
  cmp    $0xa,%edx
  jne    L13
L81:
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%rbx,1)
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L12:
  call   <free@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  movq   $0x10,0x0(%r13)
  jmp    L86
  nopl   0x0(%rax,%rax,1)
L2:
  movslq %r12d,%rbx
  jmp    L81
```

assistant: ```c
ssize_t getline(char **lineptr, size_t *n, FILE *stream) {
  ssize_t written = 0;
  int character;
  if (*lineptr == NULL || *n < 16) {
    free(*lineptr);
    *lineptr = (char *)malloc(16);
    *n = 16;
  }
  while ((character = fgetc(stream)) != EOF) {
    written += 1;
    if (written >= *n) {
      *n = *n * 2;
      *lineptr = realloc(*lineptr, *n);
    }
    (*lineptr)[written - 1] = character;
    if (character == '\n') {
      break;
    }
  }
  (*lineptr)[written] = '\0';
  return written;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getline>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L19
  cmpq   $0xf,(%rsi)
  jbe    L19
L84:
  mov    D3(%rip),%r15
  mov    $0x1,%ebx
  jmp    L41
  nop
L2:
  mov    %dl,-0x1(%rdi,%rbx,1)
  lea    0x1(%rbx),%rax
  cmp    $0xa,%edx
  je     L11
L58:
  mov    %rax,%rbx
L41:
  mov    %r14,%rdi
  lea    -0x1(%rbx),%r12d
  call   <fgetc@plt>
  mov    %eax,%edx
  cmp    %eax,(%r15)
  je     L42
  mov    0x0(%r13),%rsi
  mov    0x0(%rbp),%rdi
  mov    %ebx,%r12d
  cmp    %rbx,%rsi
  ja     L2
  add    %rsi,%rsi
  mov    %edx,0xc(%rsp)
  mov    %rsi,0x0(%r13)
  call   <realloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rax,0x0(%rbp)
  mov    %dl,-0x1(%rax,%rbx,1)
  lea    0x1(%rbx),%rax
  cmp    $0xa,%edx
  jne    L58
L11:
  mov    0x0(%rbp),%rax
  movb   $0x0,(%rax,%rbx,1)
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  call   <free@plt>
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  movq   $0x10,0x0(%r13)
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L42:
  movslq %r12d,%rbx
  jmp    L11
```

assistant: ```c
ssize_t getline(char **lineptr, size_t *n, FILE *stream) {
  ssize_t written = 0;
  int character;
  if (*lineptr == NULL || *n < 16) {
    free(*lineptr);
    *lineptr = (char *)malloc(16);
    *n = 16;
  }
  while ((character = fgetc(stream)) != EOF) {
    written += 1;
    if (written >= *n) {
      *n = *n * 2;
      *lineptr = realloc(*lineptr, *n);
    }
    (*lineptr)[written - 1] = character;
    if (character == '\n') {
      break;
    }
  }
  (*lineptr)[written] = '\0';
  return written;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D14(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L28
L29:
  mov    -0x10(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0xc(%rbp),%xmm0
  addss  %xmm0,%xmm0
  divss  %xmm0,%xmm1
  cvttss2si %xmm1,%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L28:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L29
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: byte[4]
name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D27
type_infered: string

tool: {"D14": [0xdb,0x0f,0x49,0x40]}

tool: D7: %d

tool: D27: %.2lf


assistant: ```c
int main() {
  int L;
  float pi = atan(1.0) * 4.0;
  scanf("%d", &L);
  while (L != 0) {
    printf("%.2lf\n", (L * L) / (2.0f * pi));
    scanf("%d", &L);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L11
  lea    D10(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D11(%rip),%rbx
L22:
  imul   %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  divss  D33(%rip),%xmm0
  cvttss2si %xmm0,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L22
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D10
data_type: string
name: read_data
arguments: data_label: D33
data_type: byte[4]

tool: D11: %d

tool: D10: %.2lf


tool: {"D33": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
int main() {
  int L;
  float pi = atan(1.0) * 4.0;
  scanf("%d", &L);
  while (L != 0) {
    printf("%.2lf\n", (L * L) / (2.0f * pi));
    scanf("%d", &L);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L19
  lea    D1(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L23:
  imul   %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  cvtsi2ss %eax,%xmm0
  divss  D17(%rip),%xmm0
  cvttss2si %xmm0,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L23
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D24
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: byte[4]

tool: D24: %d

tool: D1: %.2lf


tool: {"D17": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
int main() {
  int L;
  float pi = atan(1.0) * 4.0;
  scanf("%d", &L);
  while (L != 0) {
    printf("%.2lf\n", (L * L) / (2.0f * pi));
    scanf("%d", &L);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L25
  lea    D27(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L19:
  imul   %eax,%eax
  pxor   %xmm0,%xmm0
  mov    %r12,%rdi
  cvtsi2ss %eax,%xmm0
  divss  D21(%rip),%xmm0
  cvttss2si %xmm0,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L19
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
type: string
name: retrieve_data
arguments: label: D27
type: string
name: retrieve_data
arguments: label: D21
type: byte[4]

tool: D29: %d

tool: D27: %.2lf


tool: {"D21": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
int main() {
  int L;
  float pi = atan(1.0) * 4.0;
  scanf("%d", &L);
  while (L != 0) {
    printf("%.2lf\n", (L * L) / (2.0f * pi));
    scanf("%d", &L);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_best_eci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x3,-0x2c(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L43:
  cmp    %rdx,%rsp
  je     L59
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L43
L59:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L51
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L51:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
L60:
  lea    -0x40(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <utf_to_eci@plt>
  test   %rax,%rax
  jne    L11
  mov    -0x2c(%rbp),%eax
  jmp    L46
L11:
  addl   $0x1,-0x2c(%rbp)
  cmpl   $0x18,-0x2c(%rbp)
  jle    L60
  mov    $0x1a,%eax
L46:
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__attribute__((visibility("hidden"))) int get_best_eci(unsigned char source[], size_t length) {
  int eci = 3;
  unsigned char local_source[length + 1];
  do {
    if (utf_to_eci(eci, source, local_source, &length) == 0) {
      return eci;
    }
    eci++;
  } while (eci < 25);
  return 26;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_best_eci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rax
  mov    %rsi,-0x38(%rbp)
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x28(%rbp)
  xor    %edx,%edx
  add    $0x10,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L48:
  cmp    %rdx,%rsp
  je     L14
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L48
L14:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L40
  orq    $0x0,-0x8(%rsp,%rax,1)
L40:
  mov    %rsp,%r14
  mov    $0x3,%ebx
  lea    -0x38(%rbp),%r13
L21:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <utf_to_eci@plt>
  test   %rax,%rax
  je     L36
  add    $0x1,%ebx
  cmp    $0x19,%ebx
  jne    L21
  mov    $0x1a,%ebx
L36:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    %ebx,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("hidden"))) int get_best_eci(unsigned char source[], size_t length) {
  int eci = 3;
  unsigned char local_source[length + 1];
  do {
    if (utf_to_eci(eci, source, local_source, &length) == 0) {
      return eci;
    }
    eci++;
  } while (eci < 25);
  return 26;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_best_eci>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  add    $0x10,%rax
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %rsi,-0x38(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x28(%rbp)
  xor    %edx,%edx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L80
L59:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L59
L80:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L48
L57:
  mov    %rsp,%r14
  mov    $0x3,%r12d
  lea    -0x38(%rbp),%r13
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%r12d
  cmp    $0x19,%r12d
  je     L61
L12:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <utf_to_eci@plt>
  test   %rax,%rax
  jne    L20
L16:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  lea    -0x20(%rbp),%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nop
L61:
  mov    $0x1a,%r12d
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L48:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L57
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("hidden"))) int get_best_eci(unsigned char source[], size_t length) {
  int eci = 3;
  unsigned char local_source[length + 1];
  do {
    if (utf_to_eci(eci, source, local_source, &length) == 0) {
      return eci;
    }
    eci++;
  } while (eci < 25);
  return 26;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_best_eci>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  add    $0x10,%rax
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %rsi,-0x38(%rbp)
  mov    %rsp,%rcx
  mov    %fs:0x28,%rdx
  mov    %rdx,-0x28(%rbp)
  xor    %edx,%edx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L70
L34:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L34
L70:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L3
L2:
  mov    %rsp,%r14
  mov    $0x3,%r12d
  lea    -0x38(%rbp),%r13
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L75:
  add    $0x1,%r12d
  cmp    $0x19,%r12d
  je     L12
L84:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <utf_to_eci@plt>
  test   %rax,%rax
  jne    L75
L11:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  lea    -0x20(%rbp),%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nop
L12:
  mov    $0x1a,%r12d
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L3:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L2
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("hidden"))) int get_best_eci(unsigned char source[], size_t length) {
  int eci = 3;
  unsigned char local_source[length + 1];
  do {
    if (utf_to_eci(eci, source, local_source, &length) == 0) {
      return eci;
    }
    eci++;
  } while (eci < 25);
  return 26;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L15
L21:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  jg     L21
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
data_type: string
name: unpack_data
arguments: label: D18
data_type: string

tool: D8: %d

tool: D18: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  while (n-- > 0) {
    int k;
    scanf("%d", &k);
    printf("%d\n", (1 << k) - 1);
  }
  return 0;
}
```