ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<add_const_i_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x2c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L15
  mov    -0x2c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x2c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  add    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *add_const_i_1(int *res, int cn, int *vec, int lo1, int hi1) {
  int i;
  for (i = 0; i <= hi1 - lo1; i++)
    res[i] = cn + vec[i];
  res[hi1 - lo1 + 1] += cn * (hi1 - lo1 + 1);
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<add_const_i_1>:
  endbr64
  sub    %ecx,%r8d
  js     L13
  lea    0x1(%r8),%r9d
  shl    $0x2,%r9
  mov    $0x0,%eax
L0:
  mov    %esi,%ecx
  add    (%rdx,%rax,1),%ecx
  mov    %ecx,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%r9
  jne    L0
L13:
  movslq %r8d,%rax
  add    $0x1,%r8d
  imul   %esi,%r8d
  add    %r8d,0x4(%rdi,%rax,4)
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *add_const_i_1(int *res, int cn, int *vec, int lo1, int hi1) {
  int i;
  for (i = 0; i <= hi1 - lo1; i++)
    res[i] = cn + vec[i];
  res[hi1 - lo1 + 1] += cn * (hi1 - lo1 + 1);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_const_i_1>:
  endbr64
  mov    %rdi,%r9
  sub    %ecx,%r8d
  js     L15
  movslq %r8d,%rax
  lea    0x4(,%rax,4),%rdi
  xor    %eax,%eax
  nopl   0x0(%rax)
L17:
  mov    (%rdx,%rax,1),%ecx
  add    %esi,%ecx
  mov    %ecx,(%r9,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rdi
  jne    L17
L15:
  add    $0x1,%r8d
  movslq %r8d,%rax
  imul   %r8d,%esi
  add    %esi,(%r9,%rax,4)
  mov    %r9,%rax
  ret
```

assistant: ```c
int *add_const_i_1(int *res, int cn, int *vec, int lo1, int hi1) {
  int i;
  for (i = 0; i <= hi1 - lo1; i++)
    res[i] = cn + vec[i];
  res[hi1 - lo1 + 1] += cn * (hi1 - lo1 + 1);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_const_i_1>:
  endbr64
  mov    %rdi,%r9
  sub    %ecx,%r8d
  js     L41
  lea    0x4(%rdx),%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
  cmp    $0x8,%rax
  jbe    L39
  cmp    $0x2,%r8d
  jbe    L39
  lea    0x1(%r8),%edi
  movd   %esi,%xmm2
  xor    %eax,%eax
  mov    %edi,%ecx
  pshufd $0x0,%xmm2,%xmm1
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  cs nopw 0x0(%rax,%rax,1)
L71:
  movdqu (%rdx,%rax,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%r9,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L71
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dil
  je     L13
  movslq %eax,%r10
  mov    (%rdx,%r10,4),%r11d
  lea    0x0(,%r10,4),%rcx
  add    %esi,%r11d
  mov    %r11d,(%r9,%r10,4)
  lea    0x1(%rax),%r10d
  cmp    %r10d,%r8d
  jl     L13
  mov    0x4(%rdx,%rcx,1),%r10d
  add    $0x2,%eax
  add    %esi,%r10d
  mov    %r10d,0x4(%r9,%rcx,1)
  cmp    %eax,%r8d
  jl     L13
  mov    0x8(%rdx,%rcx,1),%eax
  add    %esi,%eax
  mov    %eax,0x8(%r9,%rcx,1)
L13:
  movslq %edi,%rax
  imul   %edi,%esi
  add    %esi,(%r9,%rax,4)
  mov    %r9,%rax
  ret
  nop
L39:
  movslq %r8d,%rax
  lea    0x4(,%rax,4),%rdi
  xor    %eax,%eax
  nopl   (%rax)
L68:
  mov    (%rdx,%rax,1),%ecx
  add    %esi,%ecx
  mov    %ecx,(%r9,%rax,1)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L68
L41:
  lea    0x1(%r8),%edi
  movslq %edi,%rax
  imul   %edi,%esi
  add    %esi,(%r9,%rax,4)
  mov    %r9,%rax
  ret
```

assistant: ```c
int *add_const_i_1(int *res, int cn, int *vec, int lo1, int hi1) {
  int i;
  for (i = 0; i <= hi1 - lo1; i++)
    res[i] = cn + vec[i];
  res[hi1 - lo1 + 1] += cn * (hi1 - lo1 + 1);
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stop_timeout_timer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <setitimer@plt>
  mov    D1(%rip),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void stop_timeout_timer(void) {
  struct itimerval ival;
  int olderr = errno;
  ival.it_value.tv_sec = ival.it_value.tv_usec = 0;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
  errno = olderr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stop_timeout_timer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rbx
  mov    (%rbx),%ebp
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    %ebp,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stop_timeout_timer(void) {
  struct itimerval ival;
  int olderr = errno;
  ival.it_value.tv_sec = ival.it_value.tv_usec = 0;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
  errno = olderr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stop_timeout_timer>:
  endbr64
  push   %rbp
  xor    %edx,%edx
  push   %rbx
  sub    $0x38,%rsp
  mov    D14(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rsi
  movq   $0x0,0x10(%rsp)
  mov    (%rbx),%ebp
  movq   $0x0,0x18(%rsp)
  mov    (%rax),%edi
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <setitimer@plt>
  mov    %ebp,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stop_timeout_timer(void) {
  struct itimerval ival;
  int olderr = errno;
  ival.it_value.tv_sec = ival.it_value.tv_usec = 0;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
  errno = olderr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stop_timeout_timer>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  push   %rbx
  sub    $0x38,%rsp
  mov    D10(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  mov    (%rbx),%ebp
  movaps %xmm0,0x10(%rsp)
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    %ebp,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stop_timeout_timer(void) {
  struct itimerval ival;
  int olderr = errno;
  ival.it_value.tv_sec = ival.it_value.tv_usec = 0;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
  errno = olderr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_pointer_to_arg_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L11:
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_pointer_to_arg_ptr(char *start_ptr, int arg) {
  for (int i = 0; i < arg; ++i) {
    start_ptr = strchr(start_ptr, ' ') + 1;
  }
  return start_ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_pointer_to_arg_ptr>:
  endbr64
  test   %esi,%esi
  jle    L17
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    $0x0,%ebx
L0:
  mov    $0x20,%esi
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L0
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *get_pointer_to_arg_ptr(char *start_ptr, int arg) {
  for (int i = 0; i < arg; ++i) {
    start_ptr = strchr(start_ptr, ' ') + 1;
  }
  return start_ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_pointer_to_arg_ptr>:
  endbr64
  test   %esi,%esi
  jle    L3
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x20,%esi
  add    $0x1,%ebx
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *get_pointer_to_arg_ptr(char *start_ptr, int arg) {
  for (int i = 0; i < arg; ++i) {
    start_ptr = strchr(start_ptr, ' ') + 1;
  }
  return start_ptr;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_pointer_to_arg_ptr>:
  endbr64
  test   %esi,%esi
  jle    L19
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    $0x20,%esi
  add    $0x1,%ebx
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *get_pointer_to_arg_ptr(char *start_ptr, int arg) {
  for (int i = 0; i < arg; ++i) {
    start_ptr = strchr(start_ptr, ' ') + 1;
  }
  return start_ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lookup1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x90(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x2,-0x88(%rbp)
  movl   $0x3,-0x84(%rbp)
  movl   $0x4,-0x80(%rbp)
  movl   $0x5,-0x7c(%rbp)
  movl   $0x6,-0x78(%rbp)
  movl   $0x7,-0x74(%rbp)
  movl   $0x8,-0x70(%rbp)
  movl   $0x9,-0x6c(%rbp)
  movl   $0xa,-0x68(%rbp)
  movl   $0xb,-0x64(%rbp)
  movl   $0xc,-0x60(%rbp)
  movl   $0xd,-0x5c(%rbp)
  movl   $0xe,-0x58(%rbp)
  movl   $0xf,-0x54(%rbp)
  movl   $0x10,-0x50(%rbp)
  movl   $0x11,-0x4c(%rbp)
  movl   $0x12,-0x48(%rbp)
  movl   $0x13,-0x44(%rbp)
  movl   $0x14,-0x40(%rbp)
  movl   $0x15,-0x3c(%rbp)
  movl   $0x16,-0x38(%rbp)
  movl   $0x17,-0x34(%rbp)
  movl   $0x18,-0x30(%rbp)
  movl   $0x19,-0x2c(%rbp)
  movl   $0x1a,-0x28(%rbp)
  movl   $0x1b,-0x24(%rbp)
  movl   $0x1c,-0x20(%rbp)
  movl   $0x1d,-0x1c(%rbp)
  movl   $0x1e,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  mov    -0x94(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int lookup1(int i) {
  int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  return a[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lookup1>:
  endbr64
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x9,0x24(%rsp)
  movl   $0xa,0x28(%rsp)
  movl   $0xb,0x2c(%rsp)
  movl   $0xc,0x30(%rsp)
  movl   $0xd,0x34(%rsp)
  movl   $0xe,0x38(%rsp)
  movl   $0xf,0x3c(%rsp)
  movl   $0x10,0x40(%rsp)
  movl   $0x11,0x44(%rsp)
  movl   $0x12,0x48(%rsp)
  movl   $0x13,0x4c(%rsp)
  movl   $0x14,0x50(%rsp)
  movl   $0x15,0x54(%rsp)
  movl   $0x16,0x58(%rsp)
  movl   $0x17,0x5c(%rsp)
  movl   $0x18,0x60(%rsp)
  movl   $0x19,0x64(%rsp)
  movl   $0x1a,0x68(%rsp)
  movl   $0x1b,0x6c(%rsp)
  movl   $0x1c,0x70(%rsp)
  movl   $0x1d,0x74(%rsp)
  movl   $0x1e,0x78(%rsp)
  movl   $0x1f,0x7c(%rsp)
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x98,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lookup1(int i) {
  int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  return a[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<lookup1>:
  endbr64
  sub    $0x98,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xb0000000a,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xd0000000c,%rax
  mov    %rax,0x30(%rsp)
  movabs $0xf0000000e,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x1100000010,%rax
  mov    %rax,0x40(%rsp)
  movabs $0x1300000012,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x1500000014,%rax
  mov    %rax,0x50(%rsp)
  movabs $0x1700000016,%rax
  mov    %rax,0x58(%rsp)
  movabs $0x1900000018,%rax
  mov    %rax,0x60(%rsp)
  movabs $0x1b0000001a,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x1d0000001c,%rax
  mov    %rax,0x70(%rsp)
  movabs $0x1f0000001e,%rax
  mov    %rax,0x78(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x98,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lookup1(int i) {
  int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  return a[i];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lookup1>:
  endbr64
  sub    $0x98,%rsp
  movdqa D39(%rip),%xmm0
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movdqa D26(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D68(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movdqa D45(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movdqa D9(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movdqa D0(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  movdqa D75(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  movdqa D3(%rip),%xmm0
  movaps %xmm0,0x70(%rsp)
  mov    (%rsp,%rdi,4),%eax
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x98,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D39
type_infered: byte[16]
name: retrieve_data
arguments: label: D26
type_infered: byte[16]
name: retrieve_data
arguments: label: D68
type_infered: byte[16]
name: retrieve_data
arguments: label: D45
type_infered: byte[16]
name: retrieve_data
arguments: label: D9
type_infered: byte[16]
name: retrieve_data
arguments: label: D0
type_infered: byte[16]
name: retrieve_data
arguments: label: D75
type_infered: byte[16]
name: retrieve_data
arguments: label: D3
type_infered: byte[16]

tool: {"D39": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D26": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D68": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D45": [0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: {"D9": [0x10,0x00,0x00,0x00,0x11,0x00,0x00,0x00,0x12,0x00,0x00,0x00,0x13,0x00,0x00,0x00]}

tool: {"D0": [0x14,0x00,0x00,0x00,0x15,0x00,0x00,0x00,0x16,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

tool: {"D75": [0x18,0x00,0x00,0x00,0x19,0x00,0x00,0x00,0x1a,0x00,0x00,0x00,0x1b,0x00,0x00,0x00]}

tool: {"D3": [0x1c,0x00,0x00,0x00,0x1d,0x00,0x00,0x00,0x1e,0x00,0x00,0x00,0x1f,0x00,0x00,0x00]}

assistant: ```c
int lookup1(int i) {
  int a[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31};
  return a[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Sprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <glRasterPos3i@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <glutBitmapCharacter@plt>
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void Sprint(int x, int y, int z, char *st) {
  int l, i;
  l = strlen(st);
  glRasterPos3i(x, y, z);
  for (i = 0; i < l; i++) {
    glutBitmapCharacter(GLUT_BITMAP_TIMES_ROMAN_24, st[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Sprint>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %rcx,%rbp
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %ebx,%edi
  call   <glRasterPos3i@plt>
  test   %r12d,%r12d
  jle    L1
  mov    %rbp,%rbx
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%r12
  mov    D4(%rip),%rbp
L17:
  movsbl (%rbx),%esi
  mov    0x0(%rbp),%edi
  call   <glutBitmapCharacter@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L17
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Sprint(int x, int y, int z, char *st) {
  int l, i;
  l = strlen(st);
  glRasterPos3i(x, y, z);
  for (i = 0; i < l; i++) {
    glutBitmapCharacter(GLUT_BITMAP_TIMES_ROMAN_24, st[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Sprint>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %rcx,%rdi
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <strlen@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <glRasterPos3i@plt>
  test   %ebp,%ebp
  jle    L8
  lea    -0x1(%rbp),%eax
  mov    D6(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl (%rbx),%esi
  mov    0x0(%rbp),%edi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  cmp    %r12,%rbx
  jne    L9
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Sprint(int x, int y, int z, char *st) {
  int l, i;
  l = strlen(st);
  glRasterPos3i(x, y, z);
  for (i = 0; i < l; i++) {
    glutBitmapCharacter(GLUT_BITMAP_TIMES_ROMAN_24, st[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Sprint>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %rcx,%rdi
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <strlen@plt>
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12d,%edi
  mov    %eax,%ebp
  call   <glRasterPos3i@plt>
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%eax
  mov    D3(%rip),%rbp
  lea    0x1(%rbx,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L0:
  movsbl (%rbx),%esi
  mov    0x0(%rbp),%edi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  cmp    %r12,%rbx
  jne    L0
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Sprint(int x, int y, int z, char *st) {
  int l, i;
  l = strlen(st);
  glRasterPos3i(x, y, z);
  for (i = 0; i < l; i++) {
    glutBitmapCharacter(GLUT_BITMAP_TIMES_ROMAN_24, st[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  neg    %eax
  and    -0xc(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  nop
  leave
  ret
```

assistant: ```c
void check(char const *type, int align) {
  if ((align & -align) != align) {
    abort();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  cmp    %esi,%eax
  jne    L8
  ret
L8:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void check(char const *type, int align) {
  if ((align & -align) != align) {
    abort();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  cmp    %esi,%eax
  jne    L6
  ret
  nop
L6:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void check(char const *type, int align) {
  if ((align & -align) != align) {
    abort();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<check>:
  endbr64
  mov    %esi,%eax
  neg    %eax
  and    %esi,%eax
  cmp    %esi,%eax
  jne    L0
  ret
  nop
L0:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void check(char const *type, int align) {
  if ((align & -align) != align) {
    abort();
  }
}
```