user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<draw_hex_table>:
  endbr64
  push   %r14
  lea    D50(%rip),%rdi
  lea    D20(%rip),%r14
  push   %r13
  lea    D53(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  lea    D65(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  call   <puts@plt>
  xor    %eax,%eax
  xor    %edi,%edi
  xor    %esi,%esi
  jmp    L144
  xchg   %ax,%ax
L97:
  test   %esi,%esi
  je     L297
L149:
  test   %edi,%edi
  jne    L105
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L39:
  add    $0x1,%ebx
  test   $0x7,%bl
  je     L226
L152:
  cmp    $0x100,%ebx
  je     L276
L157:
  mov    %ebx,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L190
  cmp    $0x3,%eax
  je     L128
  cmp    $0x1,%eax
  sete   %al
  xor    %edi,%edi
  xor    %esi,%esi
  movzbl %al,%eax
L144:
  mov    %ebx,%edx
  shr    $0x2,%edx
  and    $0x3,%edx
  cmp    $0x2,%edx
  je     L213
L216:
  cmp    $0x3,%edx
  je     L209
  mov    %eax,%ecx
  or     $0x2,%ecx
  cmp    $0x1,%edx
  cmove  %rcx,%rax
L298:
  mov    %ebx,%edx
  mov    %ebx,%ecx
  shr    $0x4,%edx
  shr    $0x6,%ecx
  and    $0x3,%edx
  cmp    $0x2,%edx
  je     L321
  cmp    $0x3,%edx
  je     L137
  cmp    $0x1,%edx
  je     L247
  cmp    $0x2,%ecx
  je     L105
  cmp    $0x3,%ecx
  je     L262
L266:
  cmp    $0x1,%ecx
  jne    L97
  or     $0x8,%eax
  test   %esi,%esi
  jne    L149
L297:
  test   %edi,%edi
  jne    L105
  movsbl 0x0(%rbp,%rax,1),%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  test   $0x7,%bl
  jne    L152
L226:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x100,%ebx
  jne    L157
L276:
  pop    %rbx
  lea    D52(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1080 <puts@plt>
  nop
L128:
  mov    %ebx,%edx
  xor    %eax,%eax
  xor    %edi,%edi
  mov    $0x1,%esi
  shr    $0x2,%edx
  and    $0x3,%edx
  cmp    $0x2,%edx
  jne    L216
L213:
  add    $0x1,%edi
  jmp    L298
  nopw   0x0(%rax,%rax,1)
L321:
  add    $0x1,%edi
  cmp    $0x2,%ecx
  jne    L323
  cmp    $0x3,%edi
  jne    L105
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L39
  nopl   0x0(%rax)
L247:
  or     $0x4,%eax
L173:
  cmp    $0x2,%ecx
  je     L105
L323:
  cmp    $0x3,%ecx
  jne    L266
  add    $0x1,%esi
  cmp    $0x4,%esi
  jne    L97
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L39
  nopl   0x0(%rax)
L209:
  add    $0x1,%esi
  jmp    L298
L190:
  xor    %eax,%eax
  mov    $0x1,%edi
  xor    %esi,%esi
  jmp    L144
  xchg   %ax,%ax
L105:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L39
  nop
L137:
  add    $0x1,%esi
  jmp    L173
  nopl   (%rax)
L262:
  add    $0x1,%esi
  jmp    L97
```

tool_calls: name: unpack_data
arguments: data_tag: D50
data_type: string
name: unpack_data
arguments: data_tag: D20
data_type: string
name: unpack_data
arguments: data_tag: D53
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D65
data_type: string
name: unpack_data
arguments: data_tag: D38
data_type: string
name: unpack_data
arguments: data_tag: D6
data_type: string
name: unpack_data
arguments: data_tag: D52
data_type: string

tool: D50: extern const char hex_digits[256] = {

tool: D20:  'x',

tool: D53:  'z',

tool: D1:  'X',

tool: D65: 0123456789abcdef

tool: D38:  'Z',

tool: D6:  '%c',

tool: D52: };

assistant: ```c
void draw_hex_table(void) {
  unsigned idx;
  printf("extern const char hex_digits[256] = {\n");
  for (idx = 0; idx < 256; idx += 1) {
    unsigned cnt_z = 0, cnt_x = 0;
    unsigned bv = 0, bdx;
    for (bdx = 0; bdx < 4; bdx += 1) {
      switch ((idx >> (bdx * 2)) & 3) {
      case 0:
        break;
      case 1:
        bv |= 1 << bdx;
        break;
      case 2:
        cnt_x += 1;
        break;
      case 3:
        cnt_z += 1;
        break;
      }
    }
    if (cnt_z == 4)
      printf(" 'z',");
    else if (cnt_x == 4)
      printf(" 'x',");
    else if ((cnt_z > 0) && (cnt_x == 0))
      printf(" 'Z',");
    else if (cnt_x > 0)
      printf(" 'X',");
    else
      printf(" '%c',", "0123456789abcdef"[bv]);
    if (((idx + 1) % 8) == 0)
      printf("\n");
  }
  printf("};\n");
}
```