ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<calculate_crc32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r12
  mov    $0xffffffff,%ebp
  lea    0x1(%rdi,%rax,1),%rbx
L27:
  movzbl (%r12),%edi
  mov    $0x8,%esi
  call   <reflect@plt>
  lea    0x0(%rbp,%rbp,1),%edx
  shr    $0x1f,%ebp
  mov    %eax,%ecx
  mov    %edx,%esi
  sar    $0x7,%ecx
  xor    $0x4c11db7,%esi
  and    $0x1,%ecx
  cmp    %ebp,%ecx
  cmovne %esi,%edx
  mov    %eax,%esi
  shr    $0x6,%esi
  lea    (%rdx,%rdx,1),%ecx
  and    $0x1,%esi
  shr    $0x1f,%edx
  mov    %ecx,%edi
  xor    $0x4c11db7,%edi
  cmp    %edx,%esi
  mov    %eax,%esi
  cmovne %edi,%ecx
  shr    $0x5,%esi
  and    $0x1,%esi
  lea    (%rcx,%rcx,1),%edx
  shr    $0x1f,%ecx
  mov    %edx,%edi
  xor    $0x4c11db7,%edi
  cmp    %ecx,%esi
  mov    %eax,%esi
  cmovne %edi,%edx
  shr    $0x4,%esi
  and    $0x1,%esi
  lea    (%rdx,%rdx,1),%ecx
  shr    $0x1f,%edx
  mov    %ecx,%edi
  xor    $0x4c11db7,%edi
  cmp    %edx,%esi
  mov    %eax,%esi
  cmovne %edi,%ecx
  shr    $0x3,%esi
  and    $0x1,%esi
  lea    (%rcx,%rcx,1),%edx
  shr    $0x1f,%ecx
  mov    %edx,%edi
  xor    $0x4c11db7,%edi
  cmp    %ecx,%esi
  mov    %eax,%esi
  cmovne %edi,%edx
  shr    $0x2,%esi
  and    $0x1,%esi
  lea    (%rdx,%rdx,1),%ecx
  shr    $0x1f,%edx
  mov    %ecx,%edi
  xor    $0x4c11db7,%edi
  cmp    %edx,%esi
  mov    %eax,%esi
  cmovne %edi,%ecx
  shr    %esi
  and    $0x1,%esi
  lea    (%rcx,%rcx,1),%edx
  shr    $0x1f,%ecx
  mov    %edx,%edi
  xor    $0x4c11db7,%edi
  cmp    %ecx,%esi
  cmovne %edi,%edx
  and    $0x1,%eax
  lea    (%rdx,%rdx,1),%ebp
  shr    $0x1f,%edx
  mov    %ebp,%ecx
  xor    $0x4c11db7,%ecx
  cmp    %edx,%eax
  cmovne %ecx,%ebp
  add    $0x1,%r12
  cmp    %r12,%rbx
  jne    L27
L16:
  mov    %ebp,%edi
  mov    $0x20,%esi
  call   <reflect@plt>
  pop    %rbx
  pop    %rbp
  not    %eax
  pop    %r12
  ret
L6:
  mov    $0xffffffff,%ebp
  jmp    L16
```

assistant: ```c
unsigned int calculate_crc32(unsigned char *buffer, int len) {
  int byte_length = 8;
  int msb = 0;
  int polynomial = 0x04C11DB7;
  unsigned int regs = 0xFFFFFFFF;
  int regs_mask = 0xFFFFFFFF;
  int regs_msb = 0;
  unsigned int reflected_regs;
  for (int i = 0; i < len; i++) {
    int data_byte = buffer[i];
    data_byte = reflect(data_byte, 8);
    for (int j = 0; j < byte_length; j++) {
      msb = data_byte >> (byte_length - 1);
      msb &= 1;
      regs_msb = (regs >> 31) & 1;
      regs = regs << 1;
      if (regs_msb ^ msb) {
        regs = regs ^ polynomial;
      }
      regs = regs & regs_mask;
      data_byte <<= 1;
    }
  }
  regs = regs & regs_mask;
  reflected_regs = reflect(regs, 32) ^ 0xFFFFFFFF;
  return reflected_regs;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mixed_sort_selection>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L8
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    $0xe,%eax
  jg     L14
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <selection_sort@plt>
  jmp    L15
L14:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mixed_sort_selection>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <mixed_sort_selection>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge@plt>
  jmp    L15
L8:
  nop
L15:
  leave
  ret
```

assistant: ```c
void mixed_sort_selection(int A[], int p, int r) {
  if (p >= r)
    return;
  if (r - p < 15) {
    selection_sort(A, p, r);
  } else {
    int q = (p + r) / 2;
    mixed_sort_selection(A, p, q);
    mixed_sort_selection(A, q + 1, r);
    merge(A, p, q, r);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mixed_sort_selection>:
  endbr64
  cmp    %edx,%esi
  jge    L21
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0xe,%eax
  jg     L13
  call   <selection_sort@plt>
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <mixed_sort_selection>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <mixed_sort_selection>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge@plt>
  jmp    L2
L21:
  ret
```

assistant: ```c
void mixed_sort_selection(int A[], int p, int r) {
  if (p >= r)
    return;
  if (r - p < 15) {
    selection_sort(A, p, r);
  } else {
    int q = (p + r) / 2;
    mixed_sort_selection(A, p, q);
    mixed_sort_selection(A, q + 1, r);
    merge(A, p, q, r);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mixed_sort_selection>:
  endbr64
  cmp    %edx,%esi
  jge    L8
  push   %r14
  mov    %edx,%eax
  push   %r13
  sub    %esi,%eax
  mov    %rdi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  cmp    $0xe,%eax
  jg     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <selection_sort@plt>
  nopl   0x0(%rax)
L6:
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r14d
  shr    $0x1f,%r14d
  add    %eax,%r14d
  sar    %r14d
  mov    %r14d,%edx
  call   <mixed_sort_selection>
  lea    0x1(%r14),%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  call   <mixed_sort_selection>
  add    $0x8,%rsp
  mov    %r12d,%ecx
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <merge@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void mixed_sort_selection(int A[], int p, int r) {
  if (p >= r)
    return;
  if (r - p < 15) {
    selection_sort(A, p, r);
  } else {
    int q = (p + r) / 2;
    mixed_sort_selection(A, p, q);
    mixed_sort_selection(A, q + 1, r);
    merge(A, p, q, r);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deserialize_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L42
  movl   $0x1,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  jmp    L42
L27:
  mov    -0x18(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L42:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L27
  cmpl   $0x0,-0x10(%rbp)
  je     L0
  mov    -0x18(%rbp),%eax
  neg    %eax
  mov    %eax,-0x18(%rbp)
L0:
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int deserialize_integer(int *result, const char *msg) {
  int cpt, neg, size;
  int res;
  neg = 0;
  res = 0;
  size = (int)msg[0] + 1;
  cpt = 1;
  if (msg[cpt] == '-') {
    neg = 1;
    ++cpt;
  }
  while (cpt < size) {
    res *= 10;
    res += msg[cpt] - '0';
    ++cpt;
  }
  if (neg)
    res *= -1;
  memcpy(result, &res, sizeof(int));
  return cpt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<deserialize_integer>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r10
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  movzbl (%rsi),%r8d
  movsbl %r8b,%edi
  cmpb   $0x2d,0x1(%rsi)
  je     L2
  mov    $0x0,%r11d
  mov    $0x1,%r9d
  mov    $0x1,%ebx
  test   %edi,%edi
  jle    L29
L35:
  movslq %r9d,%rax
  mov    $0x0,%edx
L21:
  movsbl (%rsi,%rax,1),%ecx
  lea    (%rdx,%rdx,4),%edx
  lea    -0x30(%rcx,%rdx,2),%edx
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L21
  movsbl %r8b,%eax
  sub    %r9d,%eax
  cmp    %r9d,%edi
  mov    $0x0,%ecx
  cmovl  %ecx,%eax
  lea    0x1(%r9,%rax,1),%ebx
  mov    %edx,0x4(%rsp)
  test   %r11d,%r11d
  je     L29
L5:
  negl   0x4(%rsp)
L29:
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %r10,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  mov    $0x1,%r11d
  mov    $0x2,%r9d
  mov    $0x2,%ebx
  cmp    $0x1,%edi
  jg     L35
  jmp    L5
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int deserialize_integer(int *result, const char *msg) {
  int cpt, neg, size;
  int res;
  neg = 0;
  res = 0;
  size = (int)msg[0] + 1;
  cpt = 1;
  if (msg[cpt] == '-') {
    neg = 1;
    ++cpt;
  }
  while (cpt < size) {
    res *= 10;
    res += msg[cpt] - '0';
    ++cpt;
  }
  if (neg)
    res *= -1;
  memcpy(result, &res, sizeof(int));
  return cpt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deserialize_integer>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  sub    $0x10,%rsp
  movsbl (%rsi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x2d,0x1(%rsi)
  movl   $0x0,0x4(%rsp)
  je     L46
  xor    %r10d,%r10d
  mov    $0x1,%r8d
  mov    $0x1,%r12d
  test   %edi,%edi
  jle    L54
L13:
  movslq %r8d,%rax
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L3:
  movsbl (%rsi,%rax,1),%ecx
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rax
  lea    -0x30(%rcx,%rdx,2),%edx
  cmp    %eax,%edi
  jge    L3
  mov    %edi,%eax
  xor    %ecx,%ecx
  mov    %edx,0x4(%rsp)
  sub    %r8d,%eax
  cmp    %r8d,%edi
  cmovl  %ecx,%eax
  lea    0x1(%r8,%rax,1),%r12d
  test   %r10d,%r10d
  je     L54
  neg    %edx
L11:
  mov    %edx,0x4(%rsp)
L54:
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %r9,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L46:
  mov    $0x1,%r10d
  mov    $0x2,%r8d
  xor    %edx,%edx
  mov    $0x2,%r12d
  cmp    $0x1,%edi
  jg     L13
  jmp    L11
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int deserialize_integer(int *result, const char *msg) {
  int cpt, neg, size;
  int res;
  neg = 0;
  res = 0;
  size = (int)msg[0] + 1;
  cpt = 1;
  if (msg[cpt] == '-') {
    neg = 1;
    ++cpt;
  }
  while (cpt < size) {
    res *= 10;
    res += msg[cpt] - '0';
    ++cpt;
  }
  if (neg)
    res *= -1;
  memcpy(result, &res, sizeof(int));
  return cpt;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<deserialize_integer>:
  endbr64
  push   %r12
  mov    %rdi,%r9
  sub    $0x10,%rsp
  movsbl (%rsi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x2d,0x1(%rsi)
  movl   $0x0,0x4(%rsp)
  je     L2
  xor    %r10d,%r10d
  mov    $0x1,%r8d
  mov    $0x1,%r12d
  test   %edi,%edi
  jle    L41
L66:
  movslq %r8d,%rax
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L19:
  movsbl (%rsi,%rax,1),%ecx
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rax
  lea    -0x30(%rcx,%rdx,2),%edx
  cmp    %eax,%edi
  jge    L19
  mov    %edi,%eax
  xor    %ecx,%ecx
  mov    %edx,0x4(%rsp)
  sub    %r8d,%eax
  cmp    %r8d,%edi
  cmovl  %ecx,%eax
  lea    0x1(%r8,%rax,1),%r12d
  test   %r10d,%r10d
  je     L41
  neg    %edx
L69:
  mov    %edx,0x4(%rsp)
L41:
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %r9,%rdi
  call   <memcpy@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L2:
  mov    $0x1,%r10d
  mov    $0x2,%r8d
  xor    %edx,%edx
  mov    $0x2,%r12d
  cmp    $0x1,%edi
  jg     L66
  jmp    L69
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int deserialize_integer(int *result, const char *msg) {
  int cpt, neg, size;
  int res;
  neg = 0;
  res = 0;
  size = (int)msg[0] + 1;
  cpt = 1;
  if (msg[cpt] == '-') {
    neg = 1;
    ++cpt;
  }
  while (cpt < size) {
    res *= 10;
    res += msg[cpt] - '0';
    ++cpt;
  }
  if (neg)
    res *= -1;
  memcpy(result, &res, sizeof(int));
  return cpt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseHistoryLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L0
L33:
  cmpl   $0x0,-0x1c(%rbp)
  je     L30
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L16
  movl   $0x1,-0x1c(%rbp)
L16:
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *parseHistoryLine(char *line) {
  char *c;
  c = &*line;
  int afterColon = 0;
  char *strCmd = malloc(sizeof(char) * 200);
  char *pointIt = strCmd;
  while (*c != '\0') {
    if (afterColon) {
      *pointIt = *c;
      pointIt++;
    }
    if (*c == ';')
      afterColon = 1;
    c++;
  }
  *pointIt = '\0';
  return strCmd;
}
```
user: What is the c source code of the assembly code below?

```asm
<parseHistoryLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc8,%edi
  call   <malloc@plt>
  mov    %rax,%rcx
  mov    $0x0,%esi
  mov    $0x1,%edi
  cmpb   $0x0,(%rbx)
  jne    L57
L54:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
L6:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L54
  mov    %edi,%esi
L5:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
L57:
  cmpb   $0x3b,(%rbx)
  je     L6
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L54
  test   %esi,%esi
  je     L57
  jmp    L5
```

assistant: ```c
char *parseHistoryLine(char *line) {
  char *c;
  c = &*line;
  int afterColon = 0;
  char *strCmd = malloc(sizeof(char) * 200);
  char *pointIt = strCmd;
  while (*c != '\0') {
    if (afterColon) {
      *pointIt = *c;
      pointIt++;
    }
    if (*c == ';')
      afterColon = 1;
    c++;
  }
  *pointIt = '\0';
  return strCmd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parseHistoryLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc8,%edi
  call   <malloc@plt>
  movzbl (%rbx),%ecx
  xor    %edi,%edi
  mov    %rax,%rsi
  test   %cl,%cl
  jne    L67
  jmp    L14
L37:
  test   %dl,%dl
  je     L14
  test   %edi,%edi
  jne    L5
L21:
  movzbl (%rbx),%ecx
L67:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x3b,%cl
  jne    L37
  test   %dl,%dl
  je     L14
L5:
  mov    %dl,(%rsi)
  mov    $0x1,%edi
  add    $0x1,%rsi
  jmp    L21
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
```

assistant: ```c
char *parseHistoryLine(char *line) {
  char *c;
  c = &*line;
  int afterColon = 0;
  char *strCmd = malloc(sizeof(char) * 200);
  char *pointIt = strCmd;
  while (*c != '\0') {
    if (afterColon) {
      *pointIt = *c;
      pointIt++;
    }
    if (*c == ';')
      afterColon = 1;
    c++;
  }
  *pointIt = '\0';
  return strCmd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parseHistoryLine>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xc8,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  cmpb   $0x0,(%rbx)
  mov    %rax,%rsi
  je     L57
  nopl   0x0(%rax)
L35:
  movzbl (%rbx),%ecx
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x3b,%cl
  je     L13
L51:
  test   %dl,%dl
  je     L57
  test   %edi,%edi
  je     L35
L3:
  mov    %dl,(%rsi)
  movzbl (%rbx),%ecx
  add    $0x1,%rsi
  mov    $0x1,%edi
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  cmp    $0x3b,%cl
  jne    L51
L13:
  test   %dl,%dl
  jne    L3
L57:
  movb   $0x0,(%rsi)
  pop    %rbx
  ret
```

assistant: ```c
char *parseHistoryLine(char *line) {
  char *c;
  c = &*line;
  int afterColon = 0;
  char *strCmd = malloc(sizeof(char) * 200);
  char *pointIt = strCmd;
  while (*c != '\0') {
    if (afterColon) {
      *pointIt = *c;
      pointIt++;
    }
    if (*c == ';')
      afterColon = 1;
    c++;
  }
  *pointIt = '\0';
  return strCmd;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<err_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_exit(char *msg) {
  perror(msg);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<err_exit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void err_exit(char *msg) {
  perror(msg);
  exit(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<err_exit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_exit(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<err_exit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_exit(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x7e4(%rbp)
  jmp    L24
L8:
  lea    -0x7e0(%rbp),%rdx
  mov    -0x7e4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7e4(%rbp)
L24:
  mov    -0x7f0(%rbp),%eax
  cmp    %eax,-0x7e4(%rbp)
  jl     L8
  mov    -0x7f0(%rbp),%esi
  lea    -0x7ec(%rbp),%rcx
  lea    -0x7e8(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rax,%rdi
  call   <minmax@plt>
  mov    -0x7e8(%rbp),%edx
  mov    -0x7ec(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D25
data_type: string

tool: D25: %d

assistant: ```c
int main() {
  int r[500];
  int i, n;
  int max, min;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &r[i]);
  }
  minmax(r, n, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L7
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D12(%rip),%r12
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%esi
  add    $0x4,%rbp
  cmp    %ebx,%esi
  jg     L14
L7:
  lea    0x8(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <minmax@plt>
  mov    0x8(%rsp),%esi
  add    0xc(%rsp),%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x7f0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string

tool: D12: %d

assistant: ```c
int main() {
  int r[500];
  int i, n;
  int max, min;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &r[i]);
  }
  minmax(r, n, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L9
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L15
L9:
  mov    %r13,%rdi
  lea    0x8(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  call   <minmax@plt>
  mov    0x8(%rsp),%esi
  mov    %r12,%rdi
  add    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: %d

assistant: ```c
int main() {
  int r[500];
  int i, n;
  int max, min;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &r[i]);
  }
  minmax(r, n, &min, &max);
  printf("%d", min + max);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x7f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7e8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r13
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %r13,%rbp
  test   %esi,%esi
  jle    L12
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    %ebx,%esi
  jg     L10
L12:
  mov    %r13,%rdi
  lea    0x8(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  call   <minmax@plt>
  mov    0x8(%rsp),%esi
  mov    %r12,%rdi
  add    0xc(%rsp),%esi
  call   <printf@plt>
  mov    0x7e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x7f8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: %d

assistant: ```c
int main() {
  int r[500];
  int i, n;
  int max, min;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &r[i]);
  }
  minmax(r, n, &min, &max);
  printf("%d", min + max);
  return 0;
}
```