ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<crypto_aead_encrypt>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  mov    %r8,%rcx
  mov    %r9,%r8
  mov    %rdx,%r9
  sub    $0x10,%rsp
  push   %rbx
  mov    0x38(%rsp),%rdx
  add    $0x4,%rbx
  mov    0x40(%rsp),%rsi
  call   <enc@plt>
  mov    %rbx,0x0(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int crypto_aead_encrypt(unsigned char *c, unsigned long long *clen, const unsigned char *m, unsigned long long mlen, const unsigned char *ad, unsigned long long adlen, const unsigned char *nsec, const unsigned char *npub, const unsigned char *k) {
  int res = enc(c, k, npub, ad, adlen, m, mlen);
  *clen = mlen + (long long)(const int)32 / 8;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L9:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <glutBitmapCharacter@plt>
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void printstring(void *font, char *string) {
  int len, i;
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<printstring>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  mov    %r12,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%r12,%rax,1),%r12
L16:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <glutBitmapCharacter@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L16
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printstring(void *font, char *string) {
  int len, i;
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printstring>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  cmp    %r12,%rbx
  jne    L18
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printstring(void *font, char *string) {
  int len, i;
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<printstring>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  sub    $0x1,%eax
  lea    0x1(%rbx,%rax,1),%r12
  nopw   0x0(%rax,%rax,1)
L6:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <glutBitmapCharacter@plt>
  cmp    %r12,%rbx
  jne    L6
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printstring(void *font, char *string) {
  int len, i;
  len = (int)strlen(string);
  for (i = 0; i < len; i++)
    glutBitmapCharacter(font, string[i]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<shift_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <find_f@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <count_@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <count_@plt>
  sub    $0x1,%eax
  add    %eax,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L8:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L8
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <find_f@plt>
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void shift_right(int e, int pos, int *arr, int size) {
  int buff, i;
  int pos_e = find_f(e, arr, size);
  int count_e = count_(pos_e, arr);
  pos += (count_(pos, arr) - 1);
  for (i = 0; i < count_e; ++i) {
    while (arr[pos - i] != e) {
      buff = arr[pos_e];
      arr[pos_e] = arr[pos_e + 1];
      arr[pos_e + 1] = buff;
      ++pos_e;
    }
    pos_e = find_f(e, arr, size);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shift_right>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %ecx,%edx
  mov    %r12,%rsi
  call   <find_f@plt>
  mov    %eax,%r15d
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <count_@plt>
  mov    %eax,%r14d
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <count_@plt>
  lea    -0x1(%rbp,%rax,1),%eax
  test   %r14d,%r14d
  jle    L12
  cltq
  shl    $0x2,%rax
  lea    (%r12,%rax,1),%rbp
  lea    -0x4(%r12,%rax,1),%rdx
  lea    -0x1(%r14),%eax
  shl    $0x2,%rax
  sub    %rax,%rdx
  mov    %rdx,%r14
  jmp    L9
L26:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %ebx,(%rsi)
  jne    L26
L56:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <find_f@plt>
  mov    %eax,%r15d
  sub    $0x4,%rbp
  cmp    %r14,%rbp
  je     L12
L9:
  mov    %rbp,%rsi
  movslq %r15d,%r15
  lea    (%r12,%r15,4),%rax
  cmp    0x0(%rbp),%ebx
  jne    L26
  jmp    L56
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shift_right(int e, int pos, int *arr, int size) {
  int buff, i;
  int pos_e = find_f(e, arr, size);
  int count_e = count_(pos_e, arr);
  pos += (count_(pos, arr) - 1);
  for (i = 0; i < count_e; ++i) {
    while (arr[pos - i] != e) {
      buff = arr[pos_e];
      arr[pos_e] = arr[pos_e + 1];
      arr[pos_e + 1] = buff;
      ++pos_e;
    }
    pos_e = find_f(e, arr, size);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<shift_right>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    %ecx,%edx
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %r15,%rsi
  sub    $0x8,%rsp
  call   <find_f@plt>
  mov    %r15,%rsi
  movslq %eax,%r14
  mov    %r14d,%edi
  call   <count_@plt>
  mov    %r15,%rsi
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <count_@plt>
  lea    -0x1(%rbx,%rax,1),%eax
  test   %r12d,%r12d
  jle    L18
  cltq
  shl    $0x2,%rax
  lea    -0x4(%r15,%rax,1),%rdx
  lea    (%r15,%rax,1),%rbx
  lea    -0x1(%r12),%eax
  shl    $0x2,%rax
  sub    %rax,%rdx
  mov    %rdx,%r12
  nopl   0x0(%rax,%rax,1)
L2:
  lea    (%r15,%r14,4),%rax
  cmp    (%rbx),%r13d
  je     L23
  nopl   0x0(%rax)
L3:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  add    $0x4,%rax
  mov    %ecx,-0x4(%rax)
  mov    %edx,(%rax)
  cmp    %r13d,(%rbx)
  jne    L3
L23:
  mov    %ebp,%edx
  mov    %r15,%rsi
  mov    %r13d,%edi
  sub    $0x4,%rbx
  call   <find_f@plt>
  movslq %eax,%r14
  cmp    %r12,%rbx
  jne    L2
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shift_right(int e, int pos, int *arr, int size) {
  int buff, i;
  int pos_e = find_f(e, arr, size);
  int count_e = count_(pos_e, arr);
  pos += (count_(pos, arr) - 1);
  for (i = 0; i < count_e; ++i) {
    while (arr[pos - i] != e) {
      buff = arr[pos_e];
      arr[pos_e] = arr[pos_e + 1];
      arr[pos_e + 1] = buff;
      ++pos_e;
    }
    pos_e = find_f(e, arr, size);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<shift_right>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  mov    %ecx,%edx
  push   %r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  mov    %r15,%rsi
  sub    $0x8,%rsp
  call   <find_f@plt>
  mov    %r15,%rsi
  movslq %eax,%r14
  mov    %r14d,%edi
  call   <count_@plt>
  mov    %r15,%rsi
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <count_@plt>
  lea    -0x1(%rbx,%rax,1),%eax
  test   %r12d,%r12d
  jle    L25
  cltq
  shl    $0x2,%rax
  lea    -0x4(%r15,%rax,1),%rdx
  lea    (%r15,%rax,1),%rbx
  lea    -0x1(%r12),%eax
  shl    $0x2,%rax
  sub    %rax,%rdx
  mov    %rdx,%r12
  nopl   0x0(%rax,%rax,1)
L8:
  cmp    (%rbx),%r13d
  je     L35
  lea    (%r15,%r14,4),%rax
  movd   (%rax),%xmm1
  nopl   (%rax)
L23:
  movd   0x4(%rax),%xmm0
  add    $0x4,%rax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0x4(%rax)
  cmp    %r13d,(%rbx)
  jne    L23
L35:
  mov    %ebp,%edx
  mov    %r15,%rsi
  mov    %r13d,%edi
  sub    $0x4,%rbx
  call   <find_f@plt>
  movslq %eax,%r14
  cmp    %rbx,%r12
  jne    L8
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shift_right(int e, int pos, int *arr, int size) {
  int buff, i;
  int pos_e = find_f(e, arr, size);
  int count_e = count_(pos_e, arr);
  pos += (count_(pos, arr) - 1);
  for (i = 0; i < count_e; ++i) {
    while (arr[pos - i] != e) {
      buff = arr[pos_e];
      arr[pos_e] = arr[pos_e + 1];
      arr[pos_e + 1] = buff;
      ++pos_e;
    }
    pos_e = find_f(e, arr, size);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string
name: disassemble_data
arguments: data_tag: D10
datatype: string

tool: D4: usage: netread [-v | --version]      print the version number and exit
       netread [-h | -? | --help]    print this help message and exit
       netread                       capture the network packets



tool: D10: The netread program is used to capture and dump on its standard output, the
network packets at a low level. To work properly, this program needs to be run
as root or with the cap_net_raw capability. The capture stops when receiving an
INT, QUIT or TERM signal.


assistant: ```c
void usage(void) {
  printf("usage: netread [-v | --version]      print the version number "
         "and exit\n"
         "       netread [-h | -? | --help]    print this help message "
         "and exit\n"
         "       netread                       capture the network "
         "packets\n\n");
  printf("The netread program is used to capture and dump on its "
         "standard output, the\n"
         "network packets at a low level. To work properly, this "
         "program needs to be run\n"
         "as root or with the cap_net_raw capability. The capture stops "
         "when receiving an\n"
         "INT, QUIT or TERM signal.\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D15: usage: netread [-v | --version]      print the version number and exit
       netread [-h | -? | --help]    print this help message and exit
       netread                       capture the network packets



tool: D0: The netread program is used to capture and dump on its standard output, the
network packets at a low level. To work properly, this program needs to be run
as root or with the cap_net_raw capability. The capture stops when receiving an
INT, QUIT or TERM signal.


assistant: ```c
void usage(void) {
  printf("usage: netread [-v | --version]      print the version number "
         "and exit\n"
         "       netread [-h | -? | --help]    print this help message "
         "and exit\n"
         "       netread                       capture the network "
         "packets\n\n");
  printf("The netread program is used to capture and dump on its "
         "standard output, the\n"
         "network packets at a low level. To work properly, this "
         "program needs to be run\n"
         "as root or with the cap_net_raw capability. The capture stops "
         "when receiving an\n"
         "INT, QUIT or TERM signal.\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D7: usage: netread [-v | --version]      print the version number and exit
       netread [-h | -? | --help]    print this help message and exit
       netread                       capture the network packets



tool: D0: The netread program is used to capture and dump on its standard output, the
network packets at a low level. To work properly, this program needs to be run
as root or with the cap_net_raw capability. The capture stops when receiving an
INT, QUIT or TERM signal.


assistant: ```c
void usage(void) {
  printf("usage: netread [-v | --version]      print the version number "
         "and exit\n"
         "       netread [-h | -? | --help]    print this help message "
         "and exit\n"
         "       netread                       capture the network "
         "packets\n\n");
  printf("The netread program is used to capture and dump on its "
         "standard output, the\n"
         "network packets at a low level. To work properly, this "
         "program needs to be run\n"
         "as root or with the cap_net_raw capability. The capture stops "
         "when receiving an\n"
         "INT, QUIT or TERM signal.\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D9: usage: netread [-v | --version]      print the version number and exit
       netread [-h | -? | --help]    print this help message and exit
       netread                       capture the network packets



tool: D11: The netread program is used to capture and dump on its standard output, the
network packets at a low level. To work properly, this program needs to be run
as root or with the cap_net_raw capability. The capture stops when receiving an
INT, QUIT or TERM signal.


assistant: ```c
void usage(void) {
  printf("usage: netread [-v | --version]      print the version number "
         "and exit\n"
         "       netread [-h | -? | --help]    print this help message "
         "and exit\n"
         "       netread                       capture the network "
         "packets\n\n");
  printf("The netread program is used to capture and dump on its "
         "standard output, the\n"
         "network packets at a low level. To work properly, this "
         "program needs to be run\n"
         "as root or with the cap_net_raw capability. The capture stops "
         "when receiving an\n"
         "INT, QUIT or TERM signal.\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<FadeSetFromType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x1000,%eax
  test   %eax,%eax
  je     L1
  mov    $0x0,%eax
  call   <FadeSetEnterScreen@plt>
  jmp    L48
L1:
  mov    -0x4(%rbp),%eax
  and    $0x15000,%eax
  test   %eax,%eax
  je     L33
  mov    $0x0,%eax
  call   <FadeSetEnterMenu@plt>
  jmp    L48
L33:
  mov    -0x4(%rbp),%eax
  and    $0x2a000,%eax
  test   %eax,%eax
  je     L48
  mov    $0x0,%eax
  call   <FadeSetLeaveMenu@plt>
L48:
  nop
  leave
  ret
```

assistant: ```c
void FadeSetFromType(int type) {
  if (type & (1 << 12))
    FadeSetEnterScreen();
  else if (type & ((1 << 12) | (1 << 14) | (1 << 16)))
    FadeSetEnterMenu();
  else if (type & ((1 << 13) | (1 << 15) | (1 << 17)))
    FadeSetLeaveMenu();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FadeSetFromType>:
  endbr64
  sub    $0x8,%rsp
  test   $0x1000,%edi
  jne    L20
  test   $0x15000,%edi
  jne    L8
  test   $0x2a000,%edi
  je     L30
  mov    $0x0,%eax
  call   <FadeSetLeaveMenu@plt>
  jmp    L30
L20:
  mov    $0x0,%eax
  call   <FadeSetEnterScreen@plt>
L30:
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <FadeSetEnterMenu@plt>
  jmp    L30
```

assistant: ```c
void FadeSetFromType(int type) {
  if (type & (1 << 12))
    FadeSetEnterScreen();
  else if (type & ((1 << 12) | (1 << 14) | (1 << 16)))
    FadeSetEnterMenu();
  else if (type & ((1 << 13) | (1 << 15) | (1 << 17)))
    FadeSetLeaveMenu();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FadeSetFromType>:
  endbr64
  test   $0x1000,%edi
  jne    L9
  test   $0x15000,%edi
  jne    L4
  and    $0x2a000,%edi
  jne    L7
  ret
  nopl   (%rax)
L4:
  xor    %eax,%eax
  jmp    1070 <FadeSetEnterMenu@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  jmp    1080 <FadeSetEnterScreen@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  jmp    1090 <FadeSetLeaveMenu@plt>
```

assistant: ```c
void FadeSetFromType(int type) {
  if (type & (1 << 12))
    FadeSetEnterScreen();
  else if (type & ((1 << 12) | (1 << 14) | (1 << 16)))
    FadeSetEnterMenu();
  else if (type & ((1 << 13) | (1 << 15) | (1 << 17)))
    FadeSetLeaveMenu();
}
```
user: What is the c source code of the assembly code below?

```asm
<FadeSetFromType>:
  endbr64
  test   $0x1000,%edi
  jne    L7
  test   $0x15000,%edi
  jne    L26
  and    $0x2a000,%edi
  jne    L14
  ret
  nopl   (%rax)
L26:
  xor    %eax,%eax
  jmp    1070 <FadeSetEnterMenu@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  jmp    1080 <FadeSetEnterScreen@plt>
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  jmp    1090 <FadeSetLeaveMenu@plt>
```

assistant: ```c
void FadeSetFromType(int type) {
  if (type & (1 << 12))
    FadeSetEnterScreen();
  else if (type & ((1 << 12) | (1 << 14) | (1 << 16)))
    FadeSetEnterMenu();
  else if (type & ((1 << 13) | (1 << 15) | (1 << 17)))
    FadeSetLeaveMenu();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hashWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L3:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x6,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%edx
  mov    %edx,%ecx
  mov    $0xd1b71759,%eax
  imul   %rcx,%rax
  shr    $0x20,%rax
  shr    $0x11,%eax
  imul   $0x27100,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hashWord(const char *word) {
  unsigned int count;
  unsigned int hashValue = 0;
  for (count = 0; word[count] != '\0'; count++)
    hashValue = word[count] + (hashValue << 6) + (hashValue << 16) - hashValue;
  return (hashValue % 160000);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashWord>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  mov    $0x0,%edx
  mov    $0x0,%ecx
L2:
  imul   $0x1003f,%edx,%edx
  movsbl %al,%eax
  add    %eax,%edx
  add    $0x1,%ecx
  mov    %ecx,%eax
  movzbl (%rdi,%rax,1),%eax
  test   %al,%al
  jne    L2
L11:
  mov    %edx,%eax
  mov    $0xd1b71759,%ecx
  imul   %rcx,%rax
  shr    $0x31,%rax
  imul   $0x27100,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L24:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
unsigned int hashWord(const char *word) {
  unsigned int count;
  unsigned int hashValue = 0;
  for (count = 0; word[count] != '\0'; count++)
    hashValue = word[count] + (hashValue << 6) + (hashValue << 16) - hashValue;
  return (hashValue % 160000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hashWord>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L12
  xor    %edx,%edx
  xor    %ecx,%ecx
  nop
L19:
  imul   $0x1003f,%edx,%edx
  add    %eax,%edx
  lea    0x1(%rcx),%eax
  mov    %rax,%rcx
  movsbl (%rdi,%rax,1),%eax
  test   %al,%al
  jne    L19
  mov    %edx,%eax
  mov    $0xd1b71759,%ecx
  imul   %rcx,%rax
  shr    $0x31,%rax
  imul   $0x27100,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hashWord(const char *word) {
  unsigned int count;
  unsigned int hashValue = 0;
  for (count = 0; word[count] != '\0'; count++)
    hashValue = word[count] + (hashValue << 6) + (hashValue << 16) - hashValue;
  return (hashValue % 160000);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hashWord>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L15
  xor    %edx,%edx
  xor    %ecx,%ecx
  nop
L10:
  imul   $0x1003f,%edx,%edx
  add    %eax,%edx
  lea    0x1(%rcx),%eax
  mov    %rax,%rcx
  movsbl (%rdi,%rax,1),%eax
  test   %al,%al
  jne    L10
  mov    %edx,%eax
  mov    $0xd1b71759,%ecx
  imul   %rcx,%rax
  shr    $0x31,%rax
  imul   $0x27100,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hashWord(const char *word) {
  unsigned int count;
  unsigned int hashValue = 0;
  for (count = 0; word[count] != '\0'; count++)
    hashValue = word[count] + (hashValue << 6) + (hashValue << 16) - hashValue;
  return (hashValue % 160000);
}
```
user: What is the c source code of the assembly code below:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L18
L19:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L18:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *destinationString, const char *sourceString) {
  while (*sourceString) {
    *destinationString = *sourceString;
    sourceString++;
    destinationString++;
  }
  *destinationString = '\0';
  return destinationString;
}
```