ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<printTotalFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  lea    0x2(%rdx),%r12d
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %r12d,%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L55
L37:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L37
L55:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L76
L48:
  call   <fopen@plt>
  mov    %rsp,%rbx
  lea    D24(%rip),%r14
  mov    %rax,%r13
  test   %rax,%rax
  jne    L73
  jmp    L64
  nopl   0x0(%rax)
L46:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L73:
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L46
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
L53:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L76:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L64:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L53
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string
name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D24: %s

tool: D4: @n

tool: D7: Error opening file printTotalFile

assistant: ```c
void printTotalFile(char *fileName, char *mode, int jdim) {
  char line[jdim + 2];
  FILE *file;
  file = fopen(fileName, mode);
  if (file != NULL) {
    while (fgets(line, jdim + 2, file) != NULL) {
      printf("%s", line);
    }
    printf("@n");
    fclose(file);
  } else {
    printf("Error opening file printTotalFile");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <test_single@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L16
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L16:
  mov    $0x0,%eax
  call   <test_double@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L18
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L18:
  mov    $0x0,%eax
  call   <test_modulo@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L30
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L35
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D21
data_type: string
name: read_data
arguments: label: D2
data_type: string
name: read_data
arguments: label: D38
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D21: WARNING: Single-precision floating point math might be broken


tool: D2: WARNING: Double-precision floating point math might be broken


tool: D38: WARNING: Modular arithmetic is broken


tool: D14: floating point and modular math appears to work


assistant: ```c
int main(void) {
  int i, j, k;
  if ((i = test_single()))
    printf("WARNING: Single-precision "
           "floating point math might be broken\n");
  if ((j = test_double()))
    printf("WARNING: Double-precision "
           "floating point math might be broken\n");
  if ((k = test_modulo()))
    printf("WARNING: Modular arithmetic is broken\n");
  i += j;
  i += k;
  if (i == 0)
    printf("floating point and modular math appears to work\n");
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <test_single@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L79
L2:
  mov    $0x0,%eax
  call   <test_double@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L4
L18:
  mov    $0x0,%eax
  call   <test_modulo@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L32
L37:
  add    %r12d,%ebp
  add    %ebp,%ebx
  je     L65
L30:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L79:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L4:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L32:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L37
L65:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L30
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
type_guessed: string
name: extract_symbolic_data
arguments: tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D29
type_guessed: string

tool: D31: WARNING: Single-precision floating point math might be broken


tool: D2: WARNING: Double-precision floating point math might be broken


tool: D7: WARNING: Modular arithmetic is broken


tool: D29: floating point and modular math appears to work


assistant: ```c
int main(void) {
  int i, j, k;
  if ((i = test_single()))
    printf("WARNING: Single-precision "
           "floating point math might be broken\n");
  if ((j = test_double()))
    printf("WARNING: Double-precision "
           "floating point math might be broken\n");
  if ((k = test_modulo()))
    printf("WARNING: Modular arithmetic is broken\n");
  i += j;
  i += k;
  if (i == 0)
    printf("floating point and modular math appears to work\n");
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <test_single@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L33
L8:
  xor    %eax,%eax
  call   <test_double@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L42
L29:
  xor    %eax,%eax
  call   <test_modulo@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L49
L75:
  add    %ebp,%r12d
  add    %ebx,%r12d
  je     L76
L24:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L76:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L49:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L75
L42:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L29
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D10
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string

tool: D16: WARNING: Single-precision floating point math might be broken


tool: D10: floating point and modular math appears to work


tool: D28: WARNING: Modular arithmetic is broken


tool: D38: WARNING: Double-precision floating point math might be broken


assistant: ```c
int main(void) {
  int i, j, k;
  if ((i = test_single()))
    printf("WARNING: Single-precision "
           "floating point math might be broken\n");
  if ((j = test_double()))
    printf("WARNING: Double-precision "
           "floating point math might be broken\n");
  if ((k = test_modulo()))
    printf("WARNING: Modular arithmetic is broken\n");
  i += j;
  i += k;
  if (i == 0)
    printf("floating point and modular math appears to work\n");
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <test_single@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L40
L78:
  xor    %eax,%eax
  call   <test_double@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L59
L44:
  xor    %eax,%eax
  call   <test_modulo@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L36
L31:
  add    %ebp,%r12d
  add    %ebx,%r12d
  je     L35
L6:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L78
L35:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L36:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L59:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L44
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D5
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string
name: retrieve_data
arguments: data_label: D25
type_infered: string

tool: D10: WARNING: Single-precision floating point math might be broken


tool: D5: floating point and modular math appears to work


tool: D20: WARNING: Modular arithmetic is broken


tool: D25: WARNING: Double-precision floating point math might be broken


assistant: ```c
int main(void) {
  int i, j, k;
  if ((i = test_single()))
    printf("WARNING: Single-precision "
           "floating point math might be broken\n");
  if ((j = test_double()))
    printf("WARNING: Double-precision "
           "floating point math might be broken\n");
  if ((k = test_modulo()))
    printf("WARNING: Modular arithmetic is broken\n");
  i += j;
  i += k;
  if (i == 0)
    printf("floating point and modular math appears to work\n");
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CheckStrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D1(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1801,%edi
  call   <msgMessage@plt>
L8:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: Can't strdup "%s"

assistant: ```c
char *CheckStrdup(const char *s) {
  register char *r;
  if (!(r = strdup(s)))
    msgMessage((0x1000 | 0x0800 | 0x0001), "Can't strdup \"%s\"", s);
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<CheckStrdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L3
L7:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbp,%rdx
  lea    D3(%rip),%rsi
  mov    $0x1801,%edi
  call   <msgMessage@plt>
  jmp    L7
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3: Can't strdup "%s"

assistant: ```c
char *CheckStrdup(const char *s) {
  register char *r;
  if (!(r = strdup(s)))
    msgMessage((0x1000 | 0x0800 | 0x0001), "Can't strdup \"%s\"", s);
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<CheckStrdup>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L2:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L18:
  mov    %r13,%rdx
  lea    D9(%rip),%rsi
  mov    $0x1801,%edi
  call   <msgMessage@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: tag: D9
data_type: string

tool: D9: Can't strdup "%s"

assistant: ```c
char *CheckStrdup(const char *s) {
  register char *r;
  if (!(r = strdup(s)))
    msgMessage((0x1000 | 0x0800 | 0x0001), "Can't strdup \"%s\"", s);
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CheckStrdup>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %r13,%rdx
  lea    D6(%rip),%rsi
  mov    $0x1801,%edi
  call   <msgMessage@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: Can't strdup "%s"

assistant: ```c
char *CheckStrdup(const char *s) {
  register char *r;
  if (!(r = strdup(s)))
    msgMessage((0x1000 | 0x0800 | 0x0001), "Can't strdup \"%s\"", s);
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<OBJ_txt2obj>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %esi,-0x4c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x34(%rbp)
  movq   $0x0,-0x18(%rbp)
  cmpl   $0x0,-0x4c(%rbp)
  jne    L9
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <OBJ_sn2nid@plt>
  mov    %eax,-0x34(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  jne    L28
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <OBJ_ln2nid@plt>
  mov    %eax,-0x34(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x34(%rbp)
  je     L9
L28:
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <OBJ_nid2obj@plt>
  jmp    L63
L9:
  mov    -0x48(%rbp),%rax
  mov    $0xffffffff,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <a2d_ASN1_OBJECT@plt>
  mov    %eax,-0x30(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  jg     L13
  mov    $0x0,%eax
  jmp    L63
L13:
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <ASN1_object_size@plt>
  mov    %eax,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L39
  mov    $0x0,%eax
  jmp    L63
L39:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    D3(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%edx
  lea    -0x28(%rbp),%rax
  mov    %esi,%r8d
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ASN1_put_object@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  mov    -0x30(%rbp),%esi
  mov    $0xffffffff,%ecx
  mov    %rax,%rdi
  call   <a2d_ASN1_OBJECT@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x2c(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <d2i_ASN1_OBJECT@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
L63:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L75
  call   <__stack_chk_fail@plt>
L75:
  leave
  ret
```

assistant: ```c
ASN1_OBJECT *OBJ_txt2obj(const char *s, int no_name) {
  int nid = NID_undef;
  ASN1_OBJECT *op = NULL;
  unsigned char *buf;
  unsigned char *p;
  const unsigned char *cp;
  int i, j;
  if (!no_name) {
    if (((nid = OBJ_sn2nid(s)) != NID_undef) || ((nid = OBJ_ln2nid(s)) != NID_undef))
      return OBJ_nid2obj(nid);
  }
  i = a2d_ASN1_OBJECT(NULL, 0, s, -1);
  if (i <= 0) {
    return NULL;
  }
  j = ASN1_object_size(0, i, V_ASN1_OBJECT);
  if ((buf = malloc(j)) == NULL)
    return NULL;
  p = buf;
  ASN1_put_object(&p, 0, i, V_ASN1_OBJECT, V_ASN1_UNIVERSAL);
  a2d_ASN1_OBJECT(p, i, s, -1);
  cp = buf;
  op = d2i_ASN1_OBJECT(NULL, &cp, j);
  free(buf);
  return op;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OBJ_txt2obj>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jne    L1
  call   <OBJ_sn2nid@plt>
  mov    D23(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L36
  mov    %rbx,%rdi
  call   <OBJ_ln2nid@plt>
  mov    D23(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L1
L36:
  mov    %eax,%edi
  call   <OBJ_nid2obj@plt>
  mov    %rax,%rbp
  jmp    L70
L1:
  mov    $0xffffffff,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <a2d_ASN1_OBJECT@plt>
  mov    %eax,%r12d
  mov    $0x0,%ebp
  test   %eax,%eax
  jle    L70
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%esi
  mov    $0x0,%edi
  call   <ASN1_object_size@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L53
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  mov    D20(%rip),%rax
  mov    (%rax),%r8d
  mov    D9(%rip),%rax
  mov    (%rax),%ecx
  mov    %r12d,%edx
  mov    $0x0,%esi
  call   <ASN1_put_object@plt>
  mov    $0xffffffff,%ecx
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    0x8(%rsp),%rdi
  call   <a2d_ASN1_OBJECT@plt>
  mov    %r13,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %ebp,%edx
  mov    $0x0,%edi
  call   <d2i_ASN1_OBJECT@plt>
  mov    %rax,%rbp
  mov    %r13,%rdi
  call   <free@plt>
L70:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  mov    %rax,%rbp
  jmp    L70
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OBJECT *OBJ_txt2obj(const char *s, int no_name) {
  int nid = NID_undef;
  ASN1_OBJECT *op = NULL;
  unsigned char *buf;
  unsigned char *p;
  const unsigned char *cp;
  int i, j;
  if (!no_name) {
    if (((nid = OBJ_sn2nid(s)) != NID_undef) || ((nid = OBJ_ln2nid(s)) != NID_undef))
      return OBJ_nid2obj(nid);
  }
  i = a2d_ASN1_OBJECT(NULL, 0, s, -1);
  if (i <= 0) {
    return NULL;
  }
  j = ASN1_object_size(0, i, V_ASN1_OBJECT);
  if ((buf = malloc(j)) == NULL)
    return NULL;
  p = buf;
  ASN1_put_object(&p, 0, i, V_ASN1_OBJECT, V_ASN1_UNIVERSAL);
  a2d_ASN1_OBJECT(p, i, s, -1);
  cp = buf;
  op = d2i_ASN1_OBJECT(NULL, &cp, j);
  free(buf);
  return op;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<OBJ_txt2obj>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jne    L64
  call   <OBJ_sn2nid@plt>
  mov    D17(%rip),%rbx
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L76
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1100 <OBJ_nid2obj@plt>
  xchg   %ax,%ax
L76:
  mov    %r12,%rdi
  call   <OBJ_ln2nid@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L28
L64:
  mov    $0xffffffff,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <a2d_ASN1_OBJECT@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L56
  mov    D25(%rip),%rbx
  mov    %eax,%esi
  xor    %edi,%edi
  mov    (%rbx),%edx
  call   <ASN1_object_size@plt>
  mov    %eax,%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L56
  mov    %rax,0x8(%rsp)
  mov    D0(%rip),%rax
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    (%rbx),%ecx
  lea    0x8(%rsp),%rdi
  mov    (%rax),%r8d
  call   <ASN1_put_object@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    $0xffffffff,%ecx
  call   <a2d_ASN1_OBJECT@plt>
  xor    %edi,%edi
  lea    0x10(%rsp),%rsi
  mov    %r14d,%edx
  mov    %r13,0x10(%rsp)
  call   <d2i_ASN1_OBJECT@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <free@plt>
L54:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L56:
  xor    %r12d,%r12d
  jmp    L54
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OBJECT *OBJ_txt2obj(const char *s, int no_name) {
  int nid = NID_undef;
  ASN1_OBJECT *op = NULL;
  unsigned char *buf;
  unsigned char *p;
  const unsigned char *cp;
  int i, j;
  if (!no_name) {
    if (((nid = OBJ_sn2nid(s)) != NID_undef) || ((nid = OBJ_ln2nid(s)) != NID_undef))
      return OBJ_nid2obj(nid);
  }
  i = a2d_ASN1_OBJECT(NULL, 0, s, -1);
  if (i <= 0) {
    return NULL;
  }
  j = ASN1_object_size(0, i, V_ASN1_OBJECT);
  if ((buf = malloc(j)) == NULL)
    return NULL;
  p = buf;
  ASN1_put_object(&p, 0, i, V_ASN1_OBJECT, V_ASN1_UNIVERSAL);
  a2d_ASN1_OBJECT(p, i, s, -1);
  cp = buf;
  op = d2i_ASN1_OBJECT(NULL, &cp, j);
  free(buf);
  return op;
}
```
user: What is the c source code of the assembly code below?

```asm
<OBJ_txt2obj>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jne    L47
  call   <OBJ_sn2nid@plt>
  mov    D23(%rip),%rbx
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  je     L60
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1100 <OBJ_nid2obj@plt>
  xchg   %ax,%ax
L60:
  mov    %r12,%rdi
  call   <OBJ_ln2nid@plt>
  mov    %eax,%edi
  cmp    %eax,(%rbx)
  jne    L44
L47:
  mov    $0xffffffff,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <a2d_ASN1_OBJECT@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L50
  mov    D3(%rip),%rbx
  mov    %eax,%esi
  xor    %edi,%edi
  mov    (%rbx),%edx
  call   <ASN1_object_size@plt>
  mov    %eax,%edi
  mov    %eax,%r14d
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L50
  mov    %rax,0x8(%rsp)
  mov    D20(%rip),%rax
  mov    %ebp,%edx
  xor    %esi,%esi
  mov    (%rbx),%ecx
  lea    0x8(%rsp),%rdi
  mov    (%rax),%r8d
  call   <ASN1_put_object@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %ebp,%esi
  mov    $0xffffffff,%ecx
  call   <a2d_ASN1_OBJECT@plt>
  xor    %edi,%edi
  lea    0x10(%rsp),%rsi
  mov    %r14d,%edx
  mov    %r13,0x10(%rsp)
  call   <d2i_ASN1_OBJECT@plt>
  mov    %r13,%rdi
  mov    %rax,%r12
  call   <free@plt>
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L50:
  xor    %r12d,%r12d
  jmp    L14
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ASN1_OBJECT *OBJ_txt2obj(const char *s, int no_name) {
  int nid = NID_undef;
  ASN1_OBJECT *op = NULL;
  unsigned char *buf;
  unsigned char *p;
  const unsigned char *cp;
  int i, j;
  if (!no_name) {
    if (((nid = OBJ_sn2nid(s)) != NID_undef) || ((nid = OBJ_ln2nid(s)) != NID_undef))
      return OBJ_nid2obj(nid);
  }
  i = a2d_ASN1_OBJECT(NULL, 0, s, -1);
  if (i <= 0) {
    return NULL;
  }
  j = ASN1_object_size(0, i, V_ASN1_OBJECT);
  if ((buf = malloc(j)) == NULL)
    return NULL;
  p = buf;
  ASN1_put_object(&p, 0, i, V_ASN1_OBJECT, V_ASN1_UNIVERSAL);
  a2d_ASN1_OBJECT(p, i, s, -1);
  cp = buf;
  op = d2i_ASN1_OBJECT(NULL, &cp, j);
  free(buf);
  return op;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<count_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L9:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x7,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  addl   $0x1,-0x8(%rbp)
L6:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x7f,-0x4(%rbp)
  jle    L9
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_lines(char code_arr[128][128]) {
  int counter = 0;
  for (int i = 0; i < 128; i++)
    if (code_arr[i][0] != '\0')
      counter++;
  return counter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count_lines>:
  endbr64
  lea    0x4000(%rdi),%rdx
  mov    $0x0,%eax
L6:
  cmpb   $0x1,(%rdi)
  sbb    $0xffffffff,%eax
  sub    $0xffffffffffffff80,%rdi
  cmp    %rdx,%rdi
  jne    L6
  ret
```

assistant: ```c
int count_lines(char code_arr[128][128]) {
  int counter = 0;
  for (int i = 0; i < 128; i++)
    if (code_arr[i][0] != '\0')
      counter++;
  return counter;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<count_lines>:
  endbr64
  lea    0x4000(%rdi),%rdx
  xor    %eax,%eax
  nopl   (%rax)
L8:
  cmpb   $0x1,(%rdi)
  sbb    $0xffffffff,%eax
  sub    $0xffffffffffffff80,%rdi
  cmp    %rdx,%rdi
  jne    L8
  ret
```

assistant: ```c
int count_lines(char code_arr[128][128]) {
  int counter = 0;
  for (int i = 0; i < 128; i++)
    if (code_arr[i][0] != '\0')
      counter++;
  return counter;
}
```