ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<mbsnwidth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L61:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L48
  addl   $0x1,-0x14(%rbp)
  jmp    L13
L48:
  mov    -0x34(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  jne    L24
  movzbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  jmp    L13
L24:
  mov    $0xffffffff,%eax
  jmp    L53
L13:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L61
  mov    -0x14(%rbp),%eax
L53:
  leave
  ret
```

assistant: ```c
int mbsnwidth(const char *string, size_t nbytes, int flags) {
  const char *p = string;
  const char *plimit = p + nbytes;
  int width;
  width = 0;
  while (p < plimit) {
    unsigned char c = (unsigned char)*p++;
    if ((1 && isprint(c)))
      width++;
    else if (!(flags & 2))
      width += ((1 && iscntrl(c)) ? 0 : 1);
    else
      return -1;
  }
  return width;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mbsnwidth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdi,%rsi,1),%r13
  cmp    %r13,%rdi
  jae    L50
  mov    %rdi,%rbx
  mov    $0x0,%r12d
  and    $0x2,%edx
  mov    %edx,%r14d
  jmp    L1
L17:
  test   %r14d,%r14d
  jne    L4
  mov    %ebp,%edi
  call   <iscntrl@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
L59:
  cmp    %rbx,%r13
  je     L54
L1:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%ebp
  mov    %ebp,%edi
  call   <isprint@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%r12d
  jmp    L59
L50:
  mov    $0x0,%r12d
  jmp    L54
L4:
  mov    $0xffffffff,%r12d
L54:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int mbsnwidth(const char *string, size_t nbytes, int flags) {
  const char *p = string;
  const char *plimit = p + nbytes;
  int width;
  width = 0;
  while (p < plimit) {
    unsigned char c = (unsigned char)*p++;
    if ((1 && isprint(c)))
      width++;
    else if (!(flags & 2))
      width += ((1 && iscntrl(c)) ? 0 : 1);
    else
      return -1;
  }
  return width;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mbsnwidth>:
  endbr64
  push   %r14
  push   %r13
  lea    (%rdi,%rsi,1),%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %r13,%rdi
  jae    L34
  and    $0x2,%edx
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  mov    %edx,%r14d
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%r12d
  cmp    %rbx,%r13
  je     L3
L28:
  movzbl (%rbx),%ebp
  add    $0x1,%rbx
  mov    %ebp,%edi
  call   <isprint@plt>
  test   %rax,%rax
  jne    L16
  test   %r14d,%r14d
  jne    L5
  mov    %ebp,%edi
  call   <iscntrl@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  cmp    %rbx,%r13
  jne    L28
L3:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  xor    %r12d,%r12d
  jmp    L3
```

assistant: ```c
int mbsnwidth(const char *string, size_t nbytes, int flags) {
  const char *p = string;
  const char *plimit = p + nbytes;
  int width;
  width = 0;
  while (p < plimit) {
    unsigned char c = (unsigned char)*p++;
    if ((1 && isprint(c)))
      width++;
    else if (!(flags & 2))
      width += ((1 && iscntrl(c)) ? 0 : 1);
    else
      return -1;
  }
  return width;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mbsnwidth>:
  endbr64
  push   %r14
  push   %r13
  lea    (%rdi,%rsi,1),%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %r13,%rdi
  jae    L8
  mov    %edx,%r12d
  mov    %rdi,%rbx
  and    $0x2,%r12d
  je     L36
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x1,%r12d
  cmp    %rbx,%r13
  je     L96
L36:
  movzbl (%rbx),%ebp
  add    $0x1,%rbx
  mov    %ebp,%edi
  call   <isprint@plt>
  test   %rax,%rax
  jne    L50
  mov    %ebp,%edi
  call   <iscntrl@plt>
  cmp    $0x1,%rax
  adc    $0x0,%r12d
  cmp    %rbx,%r13
  jne    L36
L96:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  xor    %r12d,%r12d
  jmp    L96
L27:
  mov    %rdi,%rbp
  mov    $0x1,%r14d
  nopw   0x0(%rax,%rax,1)
L56:
  movzbl 0x0(%rbp),%edi
  call   <isprint@plt>
  test   %rax,%rax
  jne    L47
  mov    $0xffffffff,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r14d,%r12d
  sub    %ebx,%r12d
  add    %ebp,%r12d
  add    $0x1,%rbp
  cmp    %r13,%rbp
  jne    L56
  jmp    L96
```

assistant: ```c
int mbsnwidth(const char *string, size_t nbytes, int flags) {
  const char *p = string;
  const char *plimit = p + nbytes;
  int width;
  width = 0;
  while (p < plimit) {
    unsigned char c = (unsigned char)*p++;
    if ((1 && isprint(c)))
      width++;
    else if (!(flags & 2))
      width += ((1 && iscntrl(c)) ? 0 : 1);
    else
      return -1;
  }
  return width;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rsock_ip_optname_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  sub    $0x3,%rax
  cmp    $0x16,%rax
  ja     L22
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D12(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
  mov    $0xffffffff,%eax
  jmp    L126
L22:
  mov    $0xffffffff,%eax
L126:
  pop    %rbp
  ret
```

assistant: ```c
int rsock_ip_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 3:
    return -1;
  case 6:
    return -1;
  case 7:
    return -1;
  case 8:
    return -1;
  case 9:
    return -1;
  case 10:
    return -1;
  case 11:
    return -1;
  case 12:
    return -1;
  case 13:
    return -1;
  case 14:
    return -1;
  case 15:
    return -1;
  case 16:
    return -1;
  case 17:
    return -1;
  case 18:
    return -1;
  case 21:
    return -1;
  case 22:
    return -1;
  case 24:
    return -1;
  case 25:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rsock_ip_optname_to_int>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rsock_ip_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 3:
    return -1;
  case 6:
    return -1;
  case 7:
    return -1;
  case 8:
    return -1;
  case 9:
    return -1;
  case 10:
    return -1;
  case 11:
    return -1;
  case 12:
    return -1;
  case 13:
    return -1;
  case 14:
    return -1;
  case 15:
    return -1;
  case 16:
    return -1;
  case 17:
    return -1;
  case 18:
    return -1;
  case 21:
    return -1;
  case 22:
    return -1;
  case 24:
    return -1;
  case 25:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rsock_ip_optname_to_int>:
  endbr64
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int rsock_ip_optname_to_int(const char *str, long len, int *valp) {
  switch (len) {
  case 3:
    return -1;
  case 6:
    return -1;
  case 7:
    return -1;
  case 8:
    return -1;
  case 9:
    return -1;
  case 10:
    return -1;
  case 11:
    return -1;
  case 12:
    return -1;
  case 13:
    return -1;
  case 14:
    return -1;
  case 15:
    return -1;
  case 16:
    return -1;
  case 17:
    return -1;
  case 18:
    return -1;
  case 21:
    return -1;
  case 22:
    return -1;
  case 24:
    return -1;
  case 25:
    return -1;
  default:
    if (!str || !valp) {
    }
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isExecutable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jns    L30
  mov    $0x0,%eax
  jmp    L20
L30:
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L7
  mov    $0x0,%eax
  jmp    L20
L7:
  mov    -0x28(%rbp),%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  jne    L10
  mov    -0x30(%rbp),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  jmp    L20
L10:
  mov    -0x20(%rbp),%rbx
  mov    $0x0,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  jne    L69
  mov    -0x30(%rbp),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  jmp    L20
L69:
  mov    -0x30(%rbp),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
L20:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int isExecutable(char *filename) {
  int result;
  struct stat statinfo;
  result = stat(filename, &statinfo);
  if (result < 0)
    return 0;
  if (!S_ISREG(statinfo.st_mode))
    return 0;
  if (statinfo.st_uid == geteuid())
    return statinfo.st_mode & S_IXUSR;
  if (statinfo.st_gid == getegid())
    return statinfo.st_mode & S_IXGRP;
  return statinfo.st_mode & S_IXOTH;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isExecutable>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  js     L79
  mov    (%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L8
L79:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x20,%rsp
  pop    %rbx
  ret
L8:
  mov    0x8(%rsp),%rbx
  mov    $0x0,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  je     L21
  mov    0x10(%rsp),%rbx
  mov    $0x0,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  je     L42
  mov    D12(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L79
L21:
  mov    D20(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L79
L42:
  mov    D22(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L79
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isExecutable(char *filename) {
  int result;
  struct stat statinfo;
  result = stat(filename, &statinfo);
  if (result < 0)
    return 0;
  if (!S_ISREG(statinfo.st_mode))
    return 0;
  if (statinfo.st_uid == geteuid())
    return statinfo.st_mode & S_IXUSR;
  if (statinfo.st_gid == getegid())
    return statinfo.st_mode & S_IXGRP;
  return statinfo.st_mode & S_IXOTH;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isExecutable>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %eax,%eax
  js     L28
  mov    (%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L44
L28:
  xor    %eax,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L44:
  mov    0x8(%rsp),%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  je     L79
  mov    0x10(%rsp),%rbx
  xor    %eax,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  je     L41
  mov    D24(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L24
L79:
  mov    D6(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L24
  xchg   %ax,%ax
L41:
  mov    D12(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L24
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isExecutable(char *filename) {
  int result;
  struct stat statinfo;
  result = stat(filename, &statinfo);
  if (result < 0)
    return 0;
  if (!S_ISREG(statinfo.st_mode))
    return 0;
  if (statinfo.st_uid == geteuid())
    return statinfo.st_mode & S_IXUSR;
  if (statinfo.st_gid == getegid())
    return statinfo.st_mode & S_IXGRP;
  return statinfo.st_mode & S_IXOTH;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isExecutable>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %eax,%eax
  js     L37
  mov    (%rsp),%edi
  call   <S_ISREG@plt>
  test   %eax,%eax
  jne    L4
L37:
  xor    %eax,%eax
L57:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L4:
  mov    0x8(%rsp),%rbx
  xor    %eax,%eax
  call   <geteuid@plt>
  cmp    %rax,%rbx
  je     L6
  mov    0x10(%rsp),%rbx
  xor    %eax,%eax
  call   <getegid@plt>
  cmp    %rax,%rbx
  je     L47
  mov    D4(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L57
L6:
  mov    D18(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L57
  xchg   %ax,%ax
L47:
  mov    D6(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  jmp    L57
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isExecutable(char *filename) {
  int result;
  struct stat statinfo;
  result = stat(filename, &statinfo);
  if (result < 0)
    return 0;
  if (!S_ISREG(statinfo.st_mode))
    return 0;
  if (statinfo.st_uid == geteuid())
    return statinfo.st_mode & S_IXUSR;
  if (statinfo.st_gid == getegid())
    return statinfo.st_mode & S_IXGRP;
  return statinfo.st_mode & S_IXOTH;
}
```
user: What is the c source code of the assembly code below:

```asm
<gotbaha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L7
L31:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L25
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L25
  mov    $0x1,%eax
  jmp    L15
L25:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L31
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
int gotbaha(int n) {
  int i;
  for (i = 2; i < n; i++) {
    if (is_prime(i) && is_prime(n - i)) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gotbaha>:
  endbr64
  cmp    $0x2,%edi
  jle    L35
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x2,%ebx
  jmp    L59
L45:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L55
L59:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L45
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L45
  mov    $0x1,%eax
  jmp    L47
L55:
  mov    $0x0,%eax
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int gotbaha(int n) {
  int i;
  for (i = 2; i < n; i++) {
    if (is_prime(i) && is_prime(n - i)) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gotbaha>:
  endbr64
  cmp    $0x2,%edi
  jle    L3
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L14
L0:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L42
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L42
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L14:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int gotbaha(int n) {
  int i;
  for (i = 2; i < n; i++) {
    if (is_prime(i) && is_prime(n - i)) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gotbaha>:
  endbr64
  cmp    $0x2,%edi
  jle    L40
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L18
L4:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L39
  mov    %ebp,%edi
  sub    %ebx,%edi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L39
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L18:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L40:
  xor    %eax,%eax
  ret
```

assistant: ```c
int gotbaha(int n) {
  int i;
  for (i = 2; i < n; i++) {
    if (is_prime(i) && is_prime(n - i)) {
      return 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mem_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <mem_get@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *mem_str(char *str) {
  char *mem;
  if (mem = mem_get((unsigned int)strlen(str) + 1)) {
    strcpy(mem, str);
  }
  return (mem);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mem_str>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <mem_get@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mem_str(char *str) {
  char *mem;
  if (mem = mem_get((unsigned int)strlen(str) + 1)) {
    strcpy(mem, str);
  }
  return (mem);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mem_str>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <mem_get@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mem_str(char *str) {
  char *mem;
  if (mem = mem_get((unsigned int)strlen(str) + 1)) {
    strcpy(mem, str);
  }
  return (mem);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mem_str>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <mem_get@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L0:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *mem_str(char *str) {
  char *mem;
  if (mem = mem_get((unsigned int)strlen(str) + 1)) {
    strcpy(mem, str);
  }
  return (mem);
}
```
user: What is the c source code of the assembly code below?

```asm
<is_valid_netmask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <is_valid_ip@plt>
  test   %rax,%rax
  jle    L57
  movl   $0x0,-0x28(%rbp)
  lea    -0x20(%rbp),%rsi
  lea    -0x20(%rbp),%rax
  lea    0x4(%rax),%rdi
  lea    -0x20(%rbp),%rax
  lea    0x8(%rax),%rcx
  lea    -0x20(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rsi,%r9
  mov    %rdi,%r8
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L8
L4:
  mov    -0x24(%rbp),%eax
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    %eax,-0x28(%rbp)
  addl   $0x1,-0x24(%rbp)
L8:
  cmpl   $0x3,-0x24(%rbp)
  jbe    L4
  negl   -0x28(%rbp)
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  and    -0x28(%rbp),%eax
  test   %eax,%eax
  jne    L57
  mov    $0x1,%eax
  jmp    L34
L57:
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: %u.%u.%u.%u

assistant: ```c
int is_valid_netmask(unsigned char netmask[16]) {
  if (is_valid_ip(netmask) > 0) {
    unsigned int b = 0, i, n[4];
    sscanf(netmask, "%u.%u.%u.%u", &n[3], &n[2], &n[1], &n[0]);
    for (i = 0; i < 4; ++i)
      b += n[i] << (i * 8);
    b = ~b + 1;
    if ((b & (b - 1)) == 0)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_valid_netmask>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <is_valid_ip@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jg     L26
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L26:
  lea    0x8(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %rsp,%r9
  lea    0x4(%rsp),%r8
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0x4(%rsp),%eax
  shl    $0x8,%eax
  add    (%rsp),%eax
  mov    0x8(%rsp),%edx
  shl    $0x10,%edx
  add    %eax,%edx
  mov    0xc(%rsp),%eax
  shl    $0x18,%eax
  add    %edx,%eax
  mov    %eax,%edx
  not    %edx
  neg    %eax
  test   %eax,%edx
  sete   %al
  movzbl %al,%eax
  jmp    L8
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D0: %u.%u.%u.%u

assistant: ```c
int is_valid_netmask(unsigned char netmask[16]) {
  if (is_valid_ip(netmask) > 0) {
    unsigned int b = 0, i, n[4];
    sscanf(netmask, "%u.%u.%u.%u", &n[3], &n[2], &n[1], &n[0]);
    for (i = 0; i < 4; ++i)
      b += n[i] << (i * 8);
    b = ~b + 1;
    if ((b & (b - 1)) == 0)
      return 1;
  }
  return 0;
}
```