ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  lea    D31(%rip),%rdi
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  lea    0x28(%rsp),%r13
  movq   $0x0,0x20(%rsp)
  mov    %rbp,%rbx
  call   <puts@plt>
L5:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L5
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  lea    0x14(%rbp),%rdx
  xor    %esi,%esi
L12:
  xor    %eax,%eax
  cmp    %ecx,0x4(%rbp)
  sete   %al
  add    $0x4,%rbp
  add    %eax,%esi
  cmp    %rdx,%rbp
  jne    L12
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D31
data_type: string
name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D30
data_type: string
name: retrieve_data
arguments: data_tag: D26
data_type: string

tool: D31: intput array, a[6]

tool: D1: %d

tool: D30: input number to count in array ,

tool: D26: %d 

assistant: ```c
int main(void) {
  int array[6] = {};
  int i, count = 0, num;
  printf("intput array, a[6]\n");
  for (i = 0; i < 6; i++) {
    scanf("%d", &array[i]);
  }
  printf("input number to count in array ,\n");
  scanf("%d", &num);
  for (i = 1; i < 6; i++) {
    if (num == array[i])
      count += 1;
  }
  printf("%d ", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D9(%rip),%rdi
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  movaps %xmm0,0x10(%rsp)
  lea    0x28(%rsp),%r12
  movq   $0x0,0x20(%rsp)
  call   <puts@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbx,%r12
  jne    L19
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    0x24(%rsp),%eax
  lea    D1(%rip),%rdi
  movdqu 0x14(%rsp),%xmm3
  movd   %eax,%xmm2
  sete   %al
  pshufd $0x0,%xmm2,%xmm0
  movzbl %al,%eax
  pcmpeqd %xmm3,%xmm0
  pand   D10(%rip),%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  add    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string
name: disassemble_data
arguments: data_tag: D18
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string
name: disassemble_data
arguments: data_tag: D1
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: byte[16]

tool: D9: intput array, a[6]

tool: D18: %d

tool: D5: input number to count in array ,

tool: D1: %d 

tool: {"D10": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int array[6] = {};
  int i, count = 0, num;
  printf("intput array, a[6]\n");
  for (i = 0; i < 6; i++) {
    scanf("%d", &array[i]);
  }
  printf("input number to count in array ,\n");
  scanf("%d", &num);
  for (i = 1; i < 6; i++) {
    if (num == array[i])
      count += 1;
  }
  printf("%d ", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ExtractFileBase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L6
L65:
  subq   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L42
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L42
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L65
  jmp    L42
L46:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L61
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L46
L61:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void ExtractFileBase(const char *path, char *dest) {
  const char *src;
  src = path + strlen(path) - 1;
  while (src != path && *(src - 1) != '\\' && *(src - 1) != '/')
    src--;
  while (*src && *src != '.') {
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ExtractFileBase>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  je     L61
L57:
  movzbl -0x1(%rax),%edx
  cmp    $0x5c,%dl
  je     L61
  cmp    $0x2f,%dl
  je     L61
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L57
L61:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L9
  cmp    $0x2e,%dl
  je     L9
L46:
  add    $0x1,%rax
  add    $0x1,%rbx
  mov    %dl,-0x1(%rbx)
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L9
  cmp    $0x2e,%dl
  jne    L46
L9:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ExtractFileBase(const char *path, char *dest) {
  const char *src;
  src = path + strlen(path) - 1;
  while (src != path && *(src - 1) != '\\' && *(src - 1) != '/')
    src--;
  while (*src && *src != '.') {
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ExtractFileBase>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rdx
  cmp    %rdx,%rbp
  jne    L8
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L63:
  cmp    $0x2f,%al
  je     L79
  sub    $0x1,%rdx
  cmp    %rdx,%rbp
  je     L20
L8:
  movzbl -0x1(%rdx),%eax
  cmp    $0x5c,%al
  jne    L63
L79:
  movzbl (%rdx),%eax
L20:
  test   %al,%al
  jne    L68
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L44:
  add    $0x1,%rdx
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L29
L68:
  cmp    $0x2e,%al
  jne    L44
L29:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ExtractFileBase(const char *path, char *dest) {
  const char *src;
  src = path + strlen(path) - 1;
  while (src != path && *(src - 1) != '\\' && *(src - 1) != '/')
    src--;
  while (*src && *src != '.') {
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ExtractFileBase>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rdx
  cmp    %rdx,%rbp
  jne    L18
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L62:
  cmp    $0x2f,%al
  je     L19
  sub    $0x1,%rdx
  cmp    %rdx,%rbp
  je     L82
L18:
  movzbl -0x1(%rdx),%eax
  cmp    $0x5c,%al
  jne    L62
L19:
  movzbl (%rdx),%eax
L82:
  test   %al,%al
  jne    L22
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L53:
  add    $0x1,%rdx
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L4
L22:
  cmp    $0x2e,%al
  jne    L53
L4:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void ExtractFileBase(const char *path, char *dest) {
  const char *src;
  src = path + strlen(path) - 1;
  while (src != path && *(src - 1) != '\\' && *(src - 1) != '/')
    src--;
  while (*src && *src != '.') {
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_msf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L7
  mov    $0x0,%eax
  jmp    L24
L7:
  lea    -0x10(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r8
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3,-0xc(%rbp)
  je     L12
  mov    $0x0,%eax
  jmp    L24
L12:
  mov    -0x18(%rbp),%eax
  imul   $0xea60,%eax,%edx
  mov    -0x14(%rbp),%eax
  imul   $0x3e8,%eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: %i:%i:%i

assistant: ```c
int parse_msf(const char *str) {
  int res;
  int m, s, f;
  if (!str)
    return 0;
  res = sscanf(str, "%i:%i:%i", &m, &s, &f);
  if (res != 3)
    return 0;
  return m * 60 * 1000 + s * 1000 + f;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_msf>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L22
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x3,%edx
  jne    L22
  imul   $0xea60,0xc(%rsp),%eax
  imul   $0x3e8,0x10(%rsp),%edx
  add    %edx,%eax
  add    0x14(%rsp),%eax
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x28,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: %i:%i:%i

assistant: ```c
int parse_msf(const char *str) {
  int res;
  int m, s, f;
  if (!str)
    return 0;
  res = sscanf(str, "%i:%i:%i", &m, &s, &f);
  if (res != 3)
    return 0;
  return m * 60 * 1000 + s * 1000 + f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_msf>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L34
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L8
L34:
  xor    %eax,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L8:
  imul   $0xea60,0xc(%rsp),%eax
  imul   $0x3e8,0x10(%rsp),%edx
  add    %edx,%eax
  add    0x14(%rsp),%eax
  jmp    L24
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: %i:%i:%i

assistant: ```c
int parse_msf(const char *str) {
  int res;
  int m, s, f;
  if (!str)
    return 0;
  res = sscanf(str, "%i:%i:%i", &m, &s, &f);
  if (res != 3)
    return 0;
  return m * 60 * 1000 + s * 1000 + f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_msf>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L17
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%r8
  lea    D6(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x3,%eax
  je     L7
L17:
  xor    %eax,%eax
L39:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L7:
  imul   $0xea60,0xc(%rsp),%eax
  imul   $0x3e8,0x10(%rsp),%edx
  add    %edx,%eax
  add    0x14(%rsp),%eax
  jmp    L39
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: %i:%i:%i

assistant: ```c
int parse_msf(const char *str) {
  int res;
  int m, s, f;
  if (!str)
    return 0;
  res = sscanf(str, "%i:%i:%i", &m, &s, &f);
  if (res != 3)
    return 0;
  return m * 60 * 1000 + s * 1000 + f;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L22
  mov    $0x0,%eax
  jmp    L8
L22:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
bool is_file(const char *path) {
  struct stat st;
  int err;
  err = stat(path, &st);
  if (err)
    return false;
  return S_ISREG(st.st_mode);
}
```
user: What is the c source code of the assembly code below:

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  je     L22
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L22:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  jmp    L20
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_file(const char *path) {
  struct stat st;
  int err;
  err = stat(path, &st);
  if (err)
    return false;
  return S_ISREG(st.st_mode);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L9
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_file(const char *path) {
  struct stat st;
  int err;
  err = stat(path, &st);
  if (err)
    return false;
  return S_ISREG(st.st_mode);
}
```
user: What is the c source code of the assembly code below?

```asm
<is_file>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  jne    L6
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool is_file(const char *path) {
  struct stat st;
  int err;
  err = stat(path, &st);
  if (err)
    return false;
  return S_ISREG(st.st_mode);
}
```
user: What is the c source code of the assembly code below:

```asm
<toksplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %al,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  jmp    L75
L41:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L75:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L41
  jmp    L88
L2:
  cmpq   $0x0,-0x20(%rbp)
  je     L89
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x20(%rbp)
L89:
  addq   $0x1,-0x8(%rbp)
L88:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L2
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L1
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *toksplit(const char *src, char tokchar, char *token, size_t lgh) {
  if (src) {
    while (' ' == *src)
      *src++;
    while (*src && (tokchar != *src)) {
      if (lgh) {
        *token++ = *src;
        --lgh;
      }
      src++;
    }
    if (*src && (tokchar == *src))
      src++;
  }
  *token = '\0';
  return src;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<toksplit>:
  endbr64
  mov    %rdi,%rax
  mov    %esi,%r8d
  test   %rdi,%rdi
  je     L88
  cmpb   $0x20,(%rdi)
  jne    L20
L6:
  add    $0x1,%rax
  cmpb   $0x20,(%rax)
  je     L6
L20:
  movzbl (%rax),%edi
  cmp    %sil,%dil
  je     L76
  test   %dil,%dil
  jne    L63
L76:
  cmp    %sil,%dil
  jne    L88
  test   %dil,%dil
  setne  %cl
  cmp    $0x1,%cl
  sbb    $0xffffffffffffffff,%rax
L88:
  movb   $0x0,(%rdx)
  ret
L9:
  add    $0x1,%rax
  movzbl (%rax),%edi
  cmp    %r8b,%dil
  je     L76
  test   %dil,%dil
  je     L76
L63:
  test   %rcx,%rcx
  je     L9
  mov    %dil,(%rdx)
  sub    $0x1,%rcx
  lea    0x1(%rdx),%rdx
  jmp    L9
```

assistant: ```c
const char *toksplit(const char *src, char tokchar, char *token, size_t lgh) {
  if (src) {
    while (' ' == *src)
      *src++;
    while (*src && (tokchar != *src)) {
      if (lgh) {
        *token++ = *src;
        --lgh;
      }
      src++;
    }
    if (*src && (tokchar == *src))
      src++;
  }
  *token = '\0';
  return src;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toksplit>:
  endbr64
  test   %rdi,%rdi
  jne    L10
  jmp    L51
  nopl   0x0(%rax,%rax,1)
L52:
  add    $0x1,%rdi
L10:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L52
  test   %al,%al
  je     L22
  nop
L39:
  cmp    %al,%sil
  je     L17
  test   %rcx,%rcx
  je     L31
  mov    %al,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
L31:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L39
L22:
  movb   $0x0,(%rdx)
  mov    %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
const char *toksplit(const char *src, char tokchar, char *token, size_t lgh) {
  if (src) {
    while (' ' == *src)
      *src++;
    while (*src && (tokchar != *src)) {
      if (lgh) {
        *token++ = *src;
        --lgh;
      }
      src++;
    }
    if (*src && (tokchar == *src))
      src++;
  }
  *token = '\0';
  return src;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<toksplit>:
  endbr64
  test   %rdi,%rdi
  jne    L60
  jmp    L57
  nopl   0x0(%rax,%rax,1)
L96:
  add    $0x1,%rdi
L60:
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L96
  test   %al,%al
  jne    L74
L20:
  movb   $0x0,(%rdx)
  mov    %rdi,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L46:
  add    $0x1,%rdi
  mov    %al,(%rdx)
  lea    0x1(%rdx),%r8
  sub    $0x1,%rcx
  movzbl (%rdi),%eax
  mov    %r8,%rdx
  test   %al,%al
  je     L20
L74:
  cmp    %al,%sil
  je     L22
  test   %rcx,%rcx
  jne    L46
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L20
  cmp    %sil,%al
  je     L22
L71:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L20
  cmp    %sil,%al
  jne    L71
L22:
  movb   $0x0,(%rdx)
  lea    0x1(%rdi),%rax
  ret
  nopl   0x0(%rax)
L57:
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  ret
```

assistant: ```c
const char *toksplit(const char *src, char tokchar, char *token, size_t lgh) {
  if (src) {
    while (' ' == *src)
      *src++;
    while (*src && (tokchar != *src)) {
      if (lgh) {
        *token++ = *src;
        --lgh;
      }
      src++;
    }
    if (*src && (tokchar == *src))
      src++;
  }
  *token = '\0';
  return src;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x8,-0x1c(%rbp)
  je     L84
  cmpl   $0x8,-0x1c(%rbp)
  jg     L22
  cmpl   $0x4,-0x1c(%rbp)
  je     L19
  cmpl   $0x4,-0x1c(%rbp)
  jg     L22
  cmpl   $0x1,-0x1c(%rbp)
  je     L25
  cmpl   $0x2,-0x1c(%rbp)
  je     L52
  jmp    L22
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  jmp    L2
L52:
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  mov    %eax,%edi
  call   <__data2host2@plt>
  jmp    L2
L19:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__data2host4@plt>
  jmp    L2
L84:
  mov    -0x18(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <__data2host8@plt>
  cltq
  jmp    L2
L22:
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
unsigned long long read_size(void *ptr, int size) {
  switch (size) {
  case 1:
    return *(unsigned char *)ptr;
  case 2:
    return __data2host2(*(unsigned short *)ptr);
  case 4:
    return __data2host4(*(unsigned int *)ptr);
  case 8:
    return ({
      unsigned long long __val;
      memcpy(&__val, (ptr), sizeof(unsigned long long));
      __data2host8(__val);
    });
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%esi
  je     L68
  jg     L11
  cmp    $0x1,%esi
  je     L7
  cmp    $0x2,%esi
  jne    L29
  movzwl (%rdi),%edi
  call   <__data2host2@plt>
  jmp    L29
L11:
  mov    $0x0,%eax
  cmp    $0x8,%esi
  jne    L29
  mov    %rsp,%rax
  mov    $0x8,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rdi
  call   <__data2host8@plt>
  cltq
  jmp    L29
L7:
  movzbl (%rdi),%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  ret
L68:
  mov    (%rdi),%edi
  call   <__data2host4@plt>
  jmp    L29
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long read_size(void *ptr, int size) {
  switch (size) {
  case 1:
    return *(unsigned char *)ptr;
  case 2:
    return __data2host2(*(unsigned short *)ptr);
  case 4:
    return __data2host4(*(unsigned int *)ptr);
  case 8:
    return ({
      unsigned long long __val;
      memcpy(&__val, (ptr), sizeof(unsigned long long));
      __data2host8(__val);
    });
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%esi
  je     L56
  jg     L15
  cmp    $0x1,%esi
  je     L87
  cmp    $0x2,%esi
  jne    L21
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  movzwl (%rdi),%edi
  add    $0x18,%rsp
  jmp    10d0 <__data2host2@plt>
  nopl   (%rax)
L15:
  xor    %eax,%eax
  cmp    $0x8,%esi
  jne    L21
  mov    %rsp,%r8
  mov    %rdi,%rsi
  mov    $0x8,%edx
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rdi
  call   <__data2host8@plt>
  cltq
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L73
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  movzbl (%rdi),%eax
  jmp    L21
  nopl   (%rax)
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    (%rdi),%edi
  add    $0x18,%rsp
  jmp    10b0 <__data2host4@plt>
L73:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long read_size(void *ptr, int size) {
  switch (size) {
  case 1:
    return *(unsigned char *)ptr;
  case 2:
    return __data2host2(*(unsigned short *)ptr);
  case 4:
    return __data2host4(*(unsigned int *)ptr);
  case 8:
    return ({
      unsigned long long __val;
      memcpy(&__val, (ptr), sizeof(unsigned long long));
      __data2host8(__val);
    });
  default:
    return 0;
  }
}
```