ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pth_rtn>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    D17(%rip),%rbp
  push   %rbx
  mov    $0xb,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <pthread_self@plt>
  mov    %eax,0x4(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <getpid@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L4
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D7(%rip),%rdi
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edi,%edi
  call   <pthread_exit@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D7
type_infered: string

tool: D17: %d: pthread_self = %p


tool: D7: %d: pthread_self[exit](%p) = %p


assistant: ```c
void *pth_rtn(void *p) {
  int c = 0;
  pthread_t pt = pthread_self();
  while (c < 11) {
    printf("%d: pthread_self = %p\n", getpid(), (void *)&pt);
    sleep(1);
    c++;
  }
  printf("%d: pthread_self[exit](%p) = %p\n", getpid(), p, (void *)&pt);
  pthread_exit(NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mem_printUsage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <mem_getAllocated@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x100000,-0x4(%rbp)
  jbe    L12
  mov    -0x4(%rbp),%eax
  shr    $0x14,%eax
  mov    $0x200,%edx
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L12:
  cmpl   $0x400,-0x4(%rbp)
  jbe    L37
  mov    -0x4(%rbp),%eax
  shr    $0xa,%eax
  mov    $0x80000,%edx
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L37:
  mov    -0x4(%rbp),%eax
  mov    $0x20000000,%edx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D6
type: string

tool: D9: mem stat: %d/%d mB allocated


tool: D28: mem stat: %d/%d kB allocated


tool: D6: mem stat: %d/%d bytes allocated


assistant: ```c
void mem_printUsage(void) {
  unsigned int allocated = mem_getAllocated();
  if (allocated > 1048576) {
    printf("mem stat: %d/%d mB allocated\n", allocated / 1024 / 1024, 536870912 / 1024 / 1024);
  } else if (allocated > 1024) {
    printf("mem stat: %d/%d kB allocated\n", allocated / 1024, 536870912 / 1024);
  } else {
    printf("mem stat: %d/%d bytes allocated\n", allocated, 536870912);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mem_printUsage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <mem_getAllocated@plt>
  mov    %eax,%esi
  cmp    $0x100000,%eax
  ja     L14
  cmp    $0x400,%eax
  jbe    L4
  shr    $0xa,%esi
  mov    $0x80000,%edx
  lea    D6(%rip),%rdi
  call   <printf@plt>
L38:
  add    $0x8,%rsp
  ret
L14:
  shr    $0x14,%esi
  mov    $0x200,%edx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L38
L4:
  mov    $0x20000000,%edx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L38
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D2
data_type: string

tool: D6: mem stat: %d/%d kB allocated


tool: D1: mem stat: %d/%d mB allocated


tool: D2: mem stat: %d/%d bytes allocated


assistant: ```c
void mem_printUsage(void) {
  unsigned int allocated = mem_getAllocated();
  if (allocated > 1048576) {
    printf("mem stat: %d/%d mB allocated\n", allocated / 1024 / 1024, 536870912 / 1024 / 1024);
  } else if (allocated > 1024) {
    printf("mem stat: %d/%d kB allocated\n", allocated / 1024, 536870912 / 1024);
  } else {
    printf("mem stat: %d/%d bytes allocated\n", allocated, 536870912);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_printUsage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mem_getAllocated@plt>
  mov    %eax,%esi
  cmp    $0x100000,%eax
  ja     L19
  cmp    $0x400,%eax
  jbe    L11
  shr    $0xa,%esi
  mov    $0x80000,%edx
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x20000000,%edx
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopl   (%rax)
L19:
  shr    $0x14,%esi
  mov    $0x200,%edx
  lea    D16(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D0
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string

tool: D19: mem stat: %d/%d kB allocated


tool: D0: mem stat: %d/%d bytes allocated


tool: D16: mem stat: %d/%d mB allocated


assistant: ```c
void mem_printUsage(void) {
  unsigned int allocated = mem_getAllocated();
  if (allocated > 1048576) {
    printf("mem stat: %d/%d mB allocated\n", allocated / 1024 / 1024, 536870912 / 1024 / 1024);
  } else if (allocated > 1024) {
    printf("mem stat: %d/%d kB allocated\n", allocated / 1024, 536870912 / 1024);
  } else {
    printf("mem stat: %d/%d bytes allocated\n", allocated, 536870912);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mem_printUsage>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <mem_getAllocated@plt>
  mov    %eax,%esi
  cmp    $0x100000,%eax
  ja     L5
  cmp    $0x400,%eax
  jbe    L3
  shr    $0xa,%esi
  mov    $0x80000,%edx
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x20000000,%edx
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
  nopl   (%rax)
L5:
  shr    $0x14,%esi
  mov    $0x200,%edx
  lea    D11(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D11
type_guessed: string

tool: D6: mem stat: %d/%d kB allocated


tool: D10: mem stat: %d/%d bytes allocated


tool: D11: mem stat: %d/%d mB allocated


assistant: ```c
void mem_printUsage(void) {
  unsigned int allocated = mem_getAllocated();
  if (allocated > 1048576) {
    printf("mem stat: %d/%d mB allocated\n", allocated / 1024 / 1024, 536870912 / 1024 / 1024);
  } else if (allocated > 1024) {
    printf("mem stat: %d/%d kB allocated\n", allocated / 1024, 536870912 / 1024);
  } else {
    printf("mem stat: %d/%d bytes allocated\n", allocated, 536870912);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rgb_to_yuv_2101010>:
  endbr64
  mov    %ecx,%r8d
  mov    %edi,%eax
  shr    $0x14,%eax
  and    $0x3ff,%eax
  mov    %edi,%r9d
  shr    $0xa,%r9d
  and    $0x3ff,%r9d
  and    $0x3ff,%edi
  imul   $0x74cc,%eax,%edx
  imul   $0xe54c,%r9d,%ecx
  add    %ecx,%edx
  imul   $0x2c88,%edi,%ecx
  add    %ecx,%edx
  shr    $0x5,%edx
  mov    %edx,%edx
  imul   $0xa7c5ac5,%rdx,%rdx
  shr    $0x27,%rdx
  imul   $0xc332,%edi,%r10d
  imul   $0xffffbe1c,%eax,%ecx
  lea    0x30d4000(%r10,%rcx,1),%ecx
  imul   $0x8153,%r9d,%r10d
  sub    %r10d,%ecx
  shr    $0x5,%ecx
  mov    %ecx,%ecx
  imul   $0xa7c5ac5,%rcx,%rcx
  shr    $0x27,%rcx
  imul   $0xc33c,%eax,%eax
  imul   $0x1fc0,%edi,%edi
  sub    %edi,%eax
  add    $0x30d4000,%eax
  imul   $0xa37a,%r9d,%r9d
  sub    %r9d,%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  test   %r8b,%r8b
  je     L6
  shl    $0xa,%ecx
  or     %edx,%ecx
  shl    $0x14,%eax
  or     %eax,%ecx
L12:
  mov    %ecx,(%rsi)
  ret
L6:
  shl    $0x14,%edx
  or     %eax,%edx
  shl    $0xa,%ecx
  or     %edx,%ecx
  jmp    L12
```

assistant: ```c
void rgb_to_yuv_2101010(unsigned int rgb1, unsigned int *yuv, int bpp, unsigned char swap_color) {
  static unsigned int YKr, YKg, YKb;
  static unsigned int CrKr, CrKg, CrKb;
  static unsigned int CbKr, CbKg, CbKb;
  unsigned int A, R, G, B;
  unsigned int Y, Cb, Cr;
  unsigned int yuv_pix;
  YKr = 29900;
  YKg = 58700;
  YKb = 11400;
  CbKr = 16868;
  CbKg = 33107;
  CbKb = 49970;
  CrKr = 49980;
  CrKg = 41850;
  CrKb = 8128;
  A = (rgb1 & 0xC000000) >> 30;
  R = (rgb1 & 0x3FF00000) >> 20;
  G = (rgb1 & 0x000FFC00) >> 10;
  B = (rgb1 & 0x000003FF) >> 0;
  Y = (((YKr * (R & 0x3FF)) + (YKg * (G & 0x3FF)) + (YKb * (B & 0x3FF))) / 100000);
  Cb = (((-CbKr * (R & 0x3FF)) - (CbKg * (G & 0x3FF)) + (CbKb * (B & 0x3FF)) + 51200000) / 100000);
  Cr = (((CrKr * (R & 0x3FF)) - (CrKg * (G & 0x3FF)) - (CrKb * (B & 0x3FF)) + 51200000) / 100000);
  if (swap_color)
    yuv_pix = (A << 30) | (Cr << 20) | (Cb << 10) | Y;
  else
    yuv_pix = (A << 30) | (Y << 20) | (Cb << 10) | Cr;
  *yuv = yuv_pix;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rgb_to_yuv_2101010>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%r9d
  mov    %ecx,%r8d
  and    $0x3ff,%edi
  shr    $0x14,%edx
  shr    $0xa,%r9d
  imul   $0x1fc0,%edi,%r10d
  and    $0x3ff,%edx
  and    $0x3ff,%r9d
  imul   $0xe54c,%r9d,%ecx
  imul   $0x74cc,%edx,%eax
  add    %ecx,%eax
  imul   $0x2c88,%edi,%ecx
  imul   $0xc332,%edi,%edi
  add    %ecx,%eax
  imul   $0xc33c,%edx,%ecx
  imul   $0xffffbe1c,%edx,%edx
  shr    $0x5,%eax
  imul   $0xa7c5ac5,%rax,%rax
  sub    %r10d,%ecx
  imul   $0xa37a,%r9d,%r10d
  imul   $0x8153,%r9d,%r9d
  lea    0x30d4000(%rdi,%rdx,1),%edx
  add    $0x30d4000,%ecx
  shr    $0x27,%rax
  sub    %r10d,%ecx
  sub    %r9d,%edx
  shr    $0x5,%ecx
  shr    $0x5,%edx
  imul   $0xa7c5ac5,%rcx,%rcx
  imul   $0xa7c5ac5,%rdx,%rdx
  shr    $0x27,%rcx
  shr    $0x27,%rdx
  shl    $0xa,%edx
  test   %r8b,%r8b
  je     L4
  or     %eax,%edx
  mov    %ecx,%eax
  shl    $0x14,%eax
  or     %edx,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  shl    $0x14,%eax
  or     %ecx,%edx
  or     %edx,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void rgb_to_yuv_2101010(unsigned int rgb1, unsigned int *yuv, int bpp, unsigned char swap_color) {
  static unsigned int YKr, YKg, YKb;
  static unsigned int CrKr, CrKg, CrKb;
  static unsigned int CbKr, CbKg, CbKb;
  unsigned int A, R, G, B;
  unsigned int Y, Cb, Cr;
  unsigned int yuv_pix;
  YKr = 29900;
  YKg = 58700;
  YKb = 11400;
  CbKr = 16868;
  CbKg = 33107;
  CbKb = 49970;
  CrKr = 49980;
  CrKg = 41850;
  CrKb = 8128;
  A = (rgb1 & 0xC000000) >> 30;
  R = (rgb1 & 0x3FF00000) >> 20;
  G = (rgb1 & 0x000FFC00) >> 10;
  B = (rgb1 & 0x000003FF) >> 0;
  Y = (((YKr * (R & 0x3FF)) + (YKg * (G & 0x3FF)) + (YKb * (B & 0x3FF))) / 100000);
  Cb = (((-CbKr * (R & 0x3FF)) - (CbKg * (G & 0x3FF)) + (CbKb * (B & 0x3FF)) + 51200000) / 100000);
  Cr = (((CrKr * (R & 0x3FF)) - (CrKg * (G & 0x3FF)) - (CrKb * (B & 0x3FF)) + 51200000) / 100000);
  if (swap_color)
    yuv_pix = (A << 30) | (Cr << 20) | (Cb << 10) | Y;
  else
    yuv_pix = (A << 30) | (Y << 20) | (Cb << 10) | Cr;
  *yuv = yuv_pix;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rgb_to_yuv_2101010>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%r9d
  mov    %ecx,%r8d
  and    $0x3ff,%edi
  shr    $0x14,%edx
  shr    $0xa,%r9d
  imul   $0x1fc0,%edi,%r10d
  and    $0x3ff,%edx
  and    $0x3ff,%r9d
  imul   $0xe54c,%r9d,%ecx
  imul   $0x74cc,%edx,%eax
  add    %ecx,%eax
  imul   $0x2c88,%edi,%ecx
  imul   $0xc332,%edi,%edi
  add    %ecx,%eax
  imul   $0xc33c,%edx,%ecx
  imul   $0xffffbe1c,%edx,%edx
  shr    $0x5,%eax
  imul   $0xa7c5ac5,%rax,%rax
  sub    %r10d,%ecx
  imul   $0xa37a,%r9d,%r10d
  imul   $0x8153,%r9d,%r9d
  lea    0x30d4000(%rdi,%rdx,1),%edx
  add    $0x30d4000,%ecx
  shr    $0x27,%rax
  sub    %r10d,%ecx
  sub    %r9d,%edx
  shr    $0x5,%ecx
  shr    $0x5,%edx
  imul   $0xa7c5ac5,%rcx,%rcx
  imul   $0xa7c5ac5,%rdx,%rdx
  shr    $0x27,%rcx
  shr    $0x27,%rdx
  shl    $0xa,%edx
  test   %r8b,%r8b
  je     L0
  or     %eax,%edx
  mov    %ecx,%eax
  shl    $0x14,%eax
  or     %edx,%eax
  mov    %eax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  shl    $0x14,%eax
  or     %ecx,%edx
  or     %edx,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void rgb_to_yuv_2101010(unsigned int rgb1, unsigned int *yuv, int bpp, unsigned char swap_color) {
  static unsigned int YKr, YKg, YKb;
  static unsigned int CrKr, CrKg, CrKb;
  static unsigned int CbKr, CbKg, CbKb;
  unsigned int A, R, G, B;
  unsigned int Y, Cb, Cr;
  unsigned int yuv_pix;
  YKr = 29900;
  YKg = 58700;
  YKb = 11400;
  CbKr = 16868;
  CbKg = 33107;
  CbKb = 49970;
  CrKr = 49980;
  CrKg = 41850;
  CrKb = 8128;
  A = (rgb1 & 0xC000000) >> 30;
  R = (rgb1 & 0x3FF00000) >> 20;
  G = (rgb1 & 0x000FFC00) >> 10;
  B = (rgb1 & 0x000003FF) >> 0;
  Y = (((YKr * (R & 0x3FF)) + (YKg * (G & 0x3FF)) + (YKb * (B & 0x3FF))) / 100000);
  Cb = (((-CbKr * (R & 0x3FF)) - (CbKg * (G & 0x3FF)) + (CbKb * (B & 0x3FF)) + 51200000) / 100000);
  Cr = (((CrKr * (R & 0x3FF)) - (CrKg * (G & 0x3FF)) - (CrKb * (B & 0x3FF)) + 51200000) / 100000);
  if (swap_color)
    yuv_pix = (A << 30) | (Cr << 20) | (Cb << 10) | Y;
  else
    yuv_pix = (A << 30) | (Y << 20) | (Cb << 10) | Cr;
  *yuv = yuv_pix;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<writefifo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L15
  mov    $0xffffffff,%eax
  jmp    L39
L15:
  lea    -0x1c(%rbp),%rcx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  cmpl   $0x1,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L39
L1:
  mov    $0xffffffff,%eax
L39:
  leave
  ret
```

assistant: ```c
int writefifo(const char *path, const char c) {
  int n, fd = open(path, O_WRONLY | O_NONBLOCK);
  if (fd == -1)
    return -1;
  n = write(fd, &c, 1);
  close(fd);
  return (n == 1) ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<writefifo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %sil,0xc(%rsp)
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  mov    D14(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L9
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <close@plt>
  cmp    $0x1,%ebp
  setne  %bl
  movzbl %bl,%ebx
  neg    %ebx
L9:
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int writefifo(const char *path, const char c) {
  int n, fd = open(path, O_WRONLY | O_NONBLOCK);
  if (fd == -1)
    return -1;
  n = write(fd, &c, 1);
  close(fd);
  return (n == 1) ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<writefifo>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    D14(%rip),%rax
  mov    %sil,0xc(%rsp)
  mov    (%rax),%esi
  mov    D11(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L9
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    %r12d,%edi
  xor    %r12d,%r12d
  mov    %eax,%ebx
  call   <close@plt>
  cmp    $0x1,%ebx
  setne  %r12b
  neg    %r12d
L9:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int writefifo(const char *path, const char c) {
  int n, fd = open(path, O_WRONLY | O_NONBLOCK);
  if (fd == -1)
    return -1;
  n = write(fd, &c, 1);
  close(fd);
  return (n == 1) ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<writefifo>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    D11(%rip),%rax
  mov    %sil,0xc(%rsp)
  mov    (%rax),%esi
  mov    D3(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L8
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <write@plt>
  mov    %r12d,%edi
  xor    %r12d,%r12d
  mov    %eax,%ebx
  call   <close@plt>
  cmp    $0x1,%ebx
  setne  %r12b
  neg    %r12d
L8:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int writefifo(const char *path, const char c) {
  int n, fd = open(path, O_WRONLY | O_NONBLOCK);
  if (fd == -1)
    return -1;
  n = write(fd, &c, 1);
  close(fd);
  return (n == 1) ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <hmean@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_infered: string
name: disassemble_data
arguments: label: D13
type_infered: string

tool: D0: %lf%lf

tool: D13: %g


assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf%lf", &a, &b);
  printf("%g\n", hmean(a, b));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <hmean@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D13: %lf%lf

tool: D4: %g


assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf%lf", &a, &b);
  printf("%g\n", hmean(a, b));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <hmean@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_infered: string
name: extract_symbolic_data
arguments: data_label: D15
type_infered: string

tool: D19: %lf%lf

tool: D15: %g


assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf%lf", &a, &b);
  printf("%g\n", hmean(a, b));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <hmean@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: string

tool: D15: %lf%lf

tool: D10: %g


assistant: ```c
int main(void) {
  double a, b;
  scanf("%lf%lf", &a, &b);
  printf("%g\n", hmean(a, b));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modify_filename_extention>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    $0x0,%r12d
  jmp    L53
L59:
  movzbl (%rbx),%eax
  cmp    $0x2e,%al
  jne    L56
  mov    %rbx,%r12
  jmp    L54
L56:
  movzbl (%rbx),%eax
  cmp    $0x2f,%al
  jne    L54
  mov    $0x0,%r12d
L54:
  add    $0x1,%rbx
L53:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L59
  test   %r12,%r12
  je     L51
  mov    %r12,%rbx
L51:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  nop
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void modify_filename_extention(buffer, ext) char *buffer;
char *ext;
{
  register char *p, *dot;
  for (p = buffer, dot = (char *)0; *p; p++) {
    if (*p == '.')
      dot = p;
    else if (*p == '/')
      dot = (char *)0;
  }
  if (dot)
    p = dot;
  strcpy(p, ext);
}
```
user: Translate the below assembly code into C programming language:

```asm
<modify_filename_extention>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L51
  mov    $0x0,%edx
  mov    $0x0,%ecx
  jmp    L57
L12:
  mov    %rdi,%rdx
L23:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L34
L57:
  cmp    $0x2e,%al
  je     L12
  cmp    $0x2f,%al
  cmove  %rcx,%rdx
  jmp    L23
L34:
  test   %rdx,%rdx
  cmove  %rdi,%rdx
L33:
  mov    %rdx,%rdi
  call   <strcpy@plt>
  add    $0x8,%rsp
  ret
L51:
  mov    %rdi,%rdx
  jmp    L33
```

assistant: ```c
void modify_filename_extention(buffer, ext) char *buffer;
char *ext;
{
  register char *p, *dot;
  for (p = buffer, dot = (char *)0; *p; p++) {
    if (*p == '.')
      dot = p;
    else if (*p == '/')
      dot = (char *)0;
  }
  if (dot)
    p = dot;
  strcpy(p, ext);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<modify_filename_extention>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L47:
  cmp    $0x2f,%al
  cmove  %rdx,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L7
L45:
  cmp    $0x2e,%al
  jne    L47
  mov    %rdi,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L45
L7:
  test   %r8,%r8
  je     L12
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %rdi,%r8
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
```

assistant: ```c
void modify_filename_extention(buffer, ext) char *buffer;
char *ext;
{
  register char *p, *dot;
  for (p = buffer, dot = (char *)0; *p; p++) {
    if (*p == '.')
      dot = p;
    else if (*p == '/')
      dot = (char *)0;
  }
  if (dot)
    p = dot;
  strcpy(p, ext);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<modify_filename_extention>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L26
  xor    %r8d,%r8d
  xor    %edx,%edx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L9:
  cmp    $0x2f,%al
  cmove  %rdx,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L11
L38:
  cmp    $0x2e,%al
  jne    L9
  mov    %rdi,%r8
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L38
L11:
  test   %r8,%r8
  je     L26
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rdi,%r8
  mov    %r8,%rdi
  jmp    1050 <strcpy@plt>
```

assistant: ```c
void modify_filename_extention(buffer, ext) char *buffer;
char *ext;
{
  register char *p, *dot;
  for (p = buffer, dot = (char *)0; *p; p++) {
    if (*p == '.')
      dot = p;
    else if (*p == '/')
      dot = (char *)0;
  }
  if (dot)
    p = dot;
  strcpy(p, ext);
}
```