user: 这段汇编代码用C语言表示是什么样的？

```asm
<hexdump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  jne    L91
  call   <strlen@plt>
  xor    %edi,%edi
  lea    D44(%rip),%rsi
  mov    %rax,%rbx
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <server_log@plt>
  test   %rbx,%rbx
  je     L54
L98:
  lea    0x30(%rsp),%r13
  xor    %r15d,%r15d
  lea    D0(%rip),%r12
  mov    %r13,%r14
  jmp    L132
  cs nopw 0x0(%rax,%rax,1)
L108:
  cmp    $0x7a,%dl
  mov    $0x2e,%eax
  cmovle %edx,%eax
L96:
  mov    %r14,%rdi
  mov    %r12,%rsi
  add    $0x1,%r15
  mov    %al,0x10(%rsp,%r8,1)
  movb   $0x0,0x11(%rsp,%r8,1)
  add    $0x3,%r14
  call   <sprintf@plt>
  cmp    %rbx,%r15
  jae    L51
L132:
  mov    %r15,%r8
  and    $0xf,%r8d
  test   %r15,%r15
  je     L44
  test   %r8,%r8
  je     L112
L44:
  movsbl 0x0(%rbp,%r15,1),%edx
  cmp    $0x60,%dl
  jg     L108
  lea    -0x41(%rdx),%esi
  mov    %edx,%eax
  cmp    $0x1a,%sil
  jbe    L96
  mov    $0x5d,%eax
  cmp    $0x5d,%dl
  je     L96
  lea    -0x30(%rdx),%eax
  cmp    $0xa,%al
  mov    $0x2e,%eax
  cmovb  %edx,%eax
  jmp    L96
  xchg   %ax,%ax
L51:
  test   %rbx,%rbx
  mov    $0x1,%eax
  cmovne %rbx,%rax
  test   $0xf,%al
  jne    L138
L54:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L105
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L112:
  lea    0x10(%rsp),%rcx
  mov    %r13,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D42(%rip),%rsi
  mov    %r8,0x8(%rsp)
  mov    %r13,%r14
  call   <server_log@plt>
  movb   $0x0,0x30(%rsp)
  mov    0x8(%rsp),%r8
  jmp    L44
  nop
L91:
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D44(%rip),%rsi
  call   <server_log@plt>
  jmp    L98
  nopl   0x0(%rax,%rax,1)
L138:
  lea    0x10(%rsp),%rcx
  mov    %r13,%rdx
  xor    %edi,%edi
  xor    %eax,%eax
  lea    D42(%rip),%rsi
  call   <server_log@plt>
  jmp    L54
L105:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D44
datatype: string
name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D42
datatype: string

tool: D44: HEXDUMP size: %d

tool: D0: %02x 

tool: D42: %s	%s

assistant: ```c
void hexdump(char *str, size_t size) {
  size_t i;
  size_t len = (size) ? size : strlen(str);
  char buff1[3 * 16 + 1 + 5];
  char buff2[17];
  char *ptr = buff1;
  server_log(0, "HEXDUMP size: %d", len);
  for (i = 0; i < len; i++) {
    if (i != 0 && i % 16 == 0) {
      server_log(0, "%s\t%s", buff1, buff2);
      buff1[0] = 0x00;
      ptr = buff1;
    }
    if ((str[i] >= (int)*"a" && str[i] <= (int)*"z") || (str[i] >= (int)*"A" && str[i] <= (int)*"Z") || (str[i] == (int)*"[" || str[i] == (int)*"]") || (str[i] >= (int)*"0" && str[i] <= (int)*"9")) {
      buff2[i % 16] = str[i];
    } else {
      buff2[i % 16] = *".";
    }
    buff2[(i % 16) + 1] = 0x00;
    sprintf(ptr, "%02x ", str[i] & 0xff);
    ptr += 3;
  }
  if (i % 16 != 0)
    server_log(0, "%s\t%s", buff1, buff2);
}
```