user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D46(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  imul   %eax,%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x10(%rsp),%edi
  mov    %rax,%rbp
  test   %edi,%edi
  jle    L55
  mov    %rax,%r13
  mov    %rax,%r14
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L172:
  shl    $0x2,%edi
  add    $0x1,%r12d
  add    $0x8,%r14
  call   <malloc@plt>
  mov    0x10(%rsp),%ebx
  mov    %rax,-0x8(%r14)
  mov    %ebx,%edi
  cmp    %r12d,%ebx
  jg     L172
  test   %ebx,%ebx
  jle    L55
  mov    %rbp,%rsi
  xor    %ecx,%ecx
  test   %ebx,%ebx
  jle    L140
  nopl   0x0(%rax,%rax,1)
L243:
  mov    (%rsi),%rdx
  xor    %eax,%eax
  nopl   (%rax)
L267:
  movl   $0x0,(%rdx,%rax,4)
  mov    0x10(%rsp),%ebx
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L267
  add    $0x1,%ecx
  cmp    %ecx,%ebx
  jle    L179
  add    $0x8,%rsi
  test   %ebx,%ebx
  jg     L243
L140:
  mov    %ebx,%r13d
  xor    %r15d,%r15d
  lea    D6(%rip),%r12
  xor    %r14d,%r14d
  movl   $0x0,0xc(%rsp)
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L192:
  cmp    $0x1,%r14d
  je     L79
  cmp    $0x2,%r14d
  je     L318
  cmp    $0x3,%r14d
  je     L204
L149:
  xor    %eax,%eax
  mov    %r13d,%edx
  lea    D62(%rip),%rdi
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    $0xf,%r15d
  jg     L278
L24:
  test   %r14d,%r14d
  jne    L192
  cmp    %r15d,%ebx
  jle    L317
  movslq %r15d,%r8
  lea    0x0(,%r8,4),%r14
  nopl   0x0(%rax)
L118:
  mov    %r15d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rax
  mov    %r15d,%edx
  add    $0x1,%r15d
  mov    %edx,(%rax,%r14,1)
  add    $0x4,%r14
  cmp    %ebx,%r15d
  jne    L118
L317:
  sub    $0x1,%r13d
  mov    $0x1,%r14d
  jmp    L149
  nopl   0x0(%rax,%rax,1)
L278:
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L176
  xor    %r13d,%r13d
  lea    D29(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L287:
  mov    0x0(%rbp),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L287
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    $0x8,%rbp
  call   <putchar@plt>
  cmp    %r13d,0x10(%rsp)
  jg     L39
L176:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L228
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L79:
  cmp    $0x1,%r13d
  jle    L269
  movslq %r15d,%r13
  mov    %r15d,%ebx
  lea    D6(%rip),%r12
  shl    $0x2,%r13
  nop
L127:
  mov    %r15d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rax
  mov    %ebx,(%rax,%r13,1)
  add    $0x1,%ebx
  jmp    L127
L269:
  sub    $0x1,%ebx
  mov    $0x2,%r14d
  jmp    L149
  nopw   0x0(%rax,%rax,1)
L318:
  cmp    %r15d,0xc(%rsp)
  jge    L115
  movslq %r15d,%r13
  mov    %r15d,%ebx
  lea    D6(%rip),%r12
  shl    $0x2,%r13
  nopl   0x0(%rax)
L4:
  mov    %r15d,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%rax
  mov    %ebx,(%rax,%r13,1)
  add    $0x1,%ebx
  jmp    L4
L204:
  addl   $0x1,0xc(%rsp)
  xor    %r14d,%r14d
  jmp    L149
L179:
  test   %ebx,%ebx
  jle    L140
  xor    %r14d,%r14d
  lea    D29(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L114:
  mov    0x0(%r13),%rax
  mov    %r12,%rdi
  mov    (%rax,%rbx,4),%esi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x10(%rsp)
  jg     L114
  mov    $0xa,%edi
  add    $0x1,%r14d
  add    $0x8,%r13
  call   <putchar@plt>
  mov    0x10(%rsp),%ebx
  cmp    %r14d,%ebx
  jg     L42
  jmp    L140
L55:
  mov    %edi,%ebx
  jmp    L140
L115:
  mov    $0x3,%r14d
  jmp    L149
L228:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D46
type_guessed: string
name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D62
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string

tool: D46: %d %d

tool: D6: %d %d


tool: D62: h=%d, v=%d


tool: D29: %d 

assistant: ```c
int main(void) {
  int **c, a, b, i, j;
  scanf("%d %d", &a, &b);
  c = (int **)malloc(a * a * sizeof(int));
  for (i = 0; i < a; i++) {
    c[i] = (int *)malloc(a * sizeof(int));
  }
  for (i = 0; i < a; i++) {
    for (j = 0; j < a; j++) {
      c[i][j] = 0;
    }
  }
  for (i = 0; i < a; i++) {
    for (j = 0; j < a; j++) {
      printf("%d ", c[i][j]);
    }
    printf("\n");
  }
  int o = 0;
  int h = a, v = a;
  int step = 0;
  int index = 0;
  int total = a * a;
  int x = 0;
  int y = 0;
  while (index < 16) {
    if (o == 0) {
      while (y < h) {
        printf("%d %d\n", x, y);
        c[x][y] = index++;
        y++;
      }
      o = 1;
      v--;
    } else if (o == 1) {
      while (x < v - 1) {
        printf("%d %d\n", x, y);
        c[x][y] = index++;
      }
      o = 2;
      h--;
    } else if (o == 2) {
      while (y > step) {
        printf("%d %d\n", x, y);
        c[x][y] = index++;
      }
      o = 3;
    } else if (o == 3) {
      while (x > step) {
        printf("%d %d\n", x, y);
        c[x][y] = index++;
      }
      o = 0;
      step++;
    }
    printf("h=%d, v=%d\n", h, v);
  }
  for (i = 0; i < a; i++) {
    for (j = 0; j < a; j++) {
      printf("%d ", c[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```