ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rsp,%r15
  mov    %rbp,%r12
L35:
  lea    -0x10(%r12),%rbx
L39:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L39
  add    $0x4,%r14
  lea    0x10(%rbx),%r12
  cmp    $0x10,%r14
  jne    L35
  movd   0x4(%rsp),%xmm3
  movd   0x30(%rsp),%xmm1
  add    $0x50,%r15
  lea    D16(%rip),%r12
  movd   0x10(%rsp),%xmm0
  movd   0x20(%rsp),%xmm4
  punpckldq %xmm3,%xmm1
  movd   0x8(%rsp),%xmm2
  mov    0xc(%rsp),%eax
  punpckldq %xmm4,%xmm0
  movd   0x18(%rsp),%xmm5
  movd   0x34(%rsp),%xmm6
  punpcklqdq %xmm1,%xmm0
  movd   0x2c(%rsp),%xmm7
  movd   0x1c(%rsp),%xmm1
  movd   %eax,%xmm3
  movups %xmm0,0x4(%rsp)
  movd   0x24(%rsp),%xmm0
  punpckldq %xmm5,%xmm2
  punpckldq %xmm7,%xmm1
  punpckldq %xmm6,%xmm0
  punpcklqdq %xmm2,%xmm0
  movups %xmm0,0x18(%rsp)
  movd   0x38(%rsp),%xmm0
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,0x2c(%rsp)
L2:
  mov    $0xa,%edi
  lea    -0x10(%rbp),%rbx
  call   <putchar@plt>
L21:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L21
  lea    0x10(%rbx),%rbp
  cmp    %r15,%rbp
  jne    L2
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string
name: disassemble_data
arguments: data_tag: D16
data_type: string

tool: D3: %d

tool: D16: %2d 

assistant: ```c
int main() {
  int a[4][4], i = 0, k = 0;
  for (i = 0; i < 4; i++) {
    for (k = 0; k < 4; k++) {
      scanf("%d", &a[i][k]);
    }
  }
  int h;
  for (i = 1; i < 4; i++) {
    for (k = 0; k < i; k++) {
      h = a[i][k];
      a[i][k] = a[k][i];
      a[k][i] = h;
    }
  }
  for (i = 0; i < 4; i++) {
    printf("\n");
    for (k = 0; k < 4; k++) {
      printf("%2d ", a[i][k]);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L21
L27:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L43
L65:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x10(%rbp)
L43:
  cmpl   $0x0,-0x10(%rbp)
  jg     L65
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L34
L23:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0xc(%rbp)
L34:
  cmpl   $0x0,-0xc(%rbp)
  jg     L23
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D37
type_guessed: string
name: parse_data
arguments: data_tag: D29
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D37: %d

tool: D29:  

tool: D8: #

tool: D3: 


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) {
    for (int j = n - i; j > 0; --j)
      printf(" ");
    for (int k = i; k > 0; --k)
      printf("#");
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jle    L37
  mov    $0x1,%r13d
  lea    D24(%rip),%r12
  lea    D3(%rip),%rbp
  lea    D33(%rip),%r14
L47:
  sub    %r13d,%ebx
  test   %ebx,%ebx
  jle    L30
L7:
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
L30:
  test   %r13d,%r13d
  jle    L13
  mov    %r13d,%ebx
L54:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L54
L13:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%r13d
  mov    0x4(%rsp),%ebx
  cmp    %r13d,%ebx
  jge    L47
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D38
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D33
type: string

tool: D38: %d

tool: D24:  

tool: D3: #

tool: D33: 


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) {
    for (int j = n - i; j > 0; --j)
      printf(" ");
    for (int k = i; k > 0; --k)
      printf("#");
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jle    L12
  mov    $0x1,%r13d
  lea    D35(%rip),%r12
  lea    D21(%rip),%r14
  lea    D22(%rip),%rbp
  nopl   0x0(%rax)
L55:
  sub    %r13d,%ebx
  test   %ebx,%ebx
  jle    L30
  nop
L51:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L51
L30:
  mov    %r13d,%ebx
L49:
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L49
  mov    %r14,%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  cmp    %r13d,%ebx
  jge    L55
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D35
datatype: string
name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D22
datatype: string

tool: D11: %d

tool: D35: #

tool: D21: 


tool: D22:  

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) {
    for (int j = n - i; j > 0; --j)
      printf(" ");
    for (int k = i; k > 0; --k)
      printf("#");
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D35(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  test   %ebx,%ebx
  jle    L28
  mov    $0x1,%r13d
  lea    D22(%rip),%r12
  lea    D36(%rip),%r14
  lea    D21(%rip),%rbp
  nopl   0x0(%rax)
L17:
  sub    %r13d,%ebx
  test   %ebx,%ebx
  jle    L57
  nop
L16:
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L16
L57:
  mov    %r13d,%ebx
L1:
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L1
  mov    %r14,%rdi
  add    $0x1,%r13d
  call   <printf@plt>
  mov    0x4(%rsp),%ebx
  cmp    %r13d,%ebx
  jge    L17
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
type_guessed: string
name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D36
type_guessed: string
name: extract_symbolic_data
arguments: label: D21
type_guessed: string

tool: D35: %d

tool: D22: #

tool: D36: 


tool: D21:  

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) {
    for (int j = n - i; j > 0; --j)
      printf(" ");
    for (int k = i; k > 0; --k)
      printf("#");
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x96,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  xor    %edx,%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5: %d


assistant: ```c
int main() {
  volatile unsigned a = 150, b = -1;
  printf("%d\n", a ^ b);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  movl   $0x96,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%eax
  xor    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: %d


assistant: ```c
int main() {
  volatile unsigned a = 150, b = -1;
  printf("%d\n", a ^ b);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  movl   $0x96,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%eax
  xor    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string

tool: D6: %d


assistant: ```c
int main() {
  volatile unsigned a = 150, b = -1;
  printf("%d\n", a ^ b);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  movl   $0x96,0x8(%rsp)
  movl   $0xffffffff,0xc(%rsp)
  mov    0x8(%rsp),%esi
  mov    0xc(%rsp),%eax
  xor    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string

tool: D3: %d


assistant: ```c
int main() {
  volatile unsigned a = 150, b = -1;
  printf("%d\n", a ^ b);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<zero_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    -0x38(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x28(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x38(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L62
L85:
  movl   $0x0,-0x2c(%rbp)
  jmp    L33
L45:
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  jne    L93
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L93:
  addl   $0x1,-0x2c(%rbp)
L33:
  mov    -0x2c(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L45
  addl   $0x1,-0x30(%rbp)
L62:
  mov    -0x30(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L85
  movl   $0x0,-0x30(%rbp)
  jmp    L60
L39:
  movl   $0x0,-0x2c(%rbp)
  jmp    L81
L92:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L96
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L89
L96:
  mov    -0x30(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
L89:
  addl   $0x1,-0x2c(%rbp)
L81:
  mov    -0x2c(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L92
  addl   $0x1,-0x30(%rbp)
L60:
  mov    -0x30(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L39
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void zero_out(int m, int n, int matrix[m][n]) {
  int x, y;
  bool *col_zero = (bool *)calloc(n, sizeof(bool));
  bool *row_zero = (bool *)calloc(m, sizeof(bool));
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (matrix[x][y] == 0)
        row_zero[y] = col_zero[x] = true;
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (col_zero[x] || row_zero[y])
        matrix[x][y] = 0;
  free(row_zero);
  free(col_zero);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zero_out>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%ebx
  mov    %rdx,%r12
  movslq %esi,%r14
  mov    $0x4,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x4,%esi
  mov    %r13d,%edi
  call   <calloc@plt>
  mov    %rax,%r10
  test   %r13d,%r13d
  jle    L28
  mov    %rbp,%r9
  shl    $0x2,%r14
  mov    %r12,%rsi
  sub    %rax,%rsi
  mov    %r13d,%r13d
  lea    0x0(%rbp,%r13,4),%r11
  lea    -0x1(%rbx),%eax
  lea    0x4(%r10,%rax,4),%rdx
  mov    %rsi,%rcx
  mov    %rbp,%r8
  jmp    L29
L149:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L142
L136:
  cmpl   $0x0,(%rcx,%rax,1)
  jne    L149
  movl   $0x1,(%rdi)
  movl   $0x1,(%rax)
  jmp    L149
L142:
  add    $0x4,%r8
  add    %r14,%rcx
  cmp    %r11,%r8
  je     L130
L29:
  mov    %r8,%rdi
  mov    %r10,%rax
  test   %ebx,%ebx
  jg     L136
  jmp    L142
L68:
  movl   $0x0,(%rsi,%rax,1)
L19:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L106
L93:
  cmpl   $0x0,(%rcx)
  jne    L68
  cmpl   $0x0,(%rax)
  je     L19
  jmp    L68
L106:
  add    %r14,%rsi
  add    $0x4,%r9
  cmp    %r11,%r9
  je     L28
L130:
  mov    %r9,%rcx
  mov    %r10,%rax
  test   %ebx,%ebx
  jg     L93
  jmp    L106
L28:
  mov    %r10,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void zero_out(int m, int n, int matrix[m][n]) {
  int x, y;
  bool *col_zero = (bool *)calloc(n, sizeof(bool));
  bool *row_zero = (bool *)calloc(m, sizeof(bool));
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (matrix[x][y] == 0)
        row_zero[y] = col_zero[x] = true;
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (col_zero[x] || row_zero[y])
        matrix[x][y] = 0;
  free(row_zero);
  free(col_zero);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<zero_out>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  movslq %esi,%r13
  mov    $0x4,%esi
  push   %r12
  mov    %r13d,%edi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <calloc@plt>
  mov    $0x4,%esi
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <calloc@plt>
  mov    %rax,%r9
  test   %r14d,%r14d
  jle    L0
  sub    %rax,%rbx
  lea    -0x1(%r13),%eax
  mov    %r13,%rbp
  mov    %r12,%rcx
  mov    %rbx,%rdi
  lea    (%r12,%r14,4),%r10
  lea    0x4(%r9,%rax,4),%rdx
  mov    %rbx,%rsi
  lea    0x0(,%r13,4),%r11
  mov    %r12,%r8
  nopl   (%rax)
L94:
  mov    %r9,%rax
  test   %ebp,%ebp
  jle    L51
  nop
L17:
  mov    (%rsi,%rax,1),%ebx
  test   %ebx,%ebx
  jne    L44
  movl   $0x1,(%r8)
  movl   $0x1,(%rax)
L44:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L17
L51:
  add    $0x4,%r8
  add    %r11,%rsi
  cmp    %r10,%r8
  jne    L94
  nopl   0x0(%rax)
L99:
  mov    %r9,%rax
  test   %ebp,%ebp
  jle    L92
  nopw   0x0(%rax,%rax,1)
L5:
  mov    (%rcx),%r8d
  test   %r8d,%r8d
  jne    L90
  mov    (%rax),%esi
  test   %esi,%esi
  je     L63
L90:
  movl   $0x0,(%rdi,%rax,1)
L63:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L5
L92:
  add    $0x4,%rcx
  add    %r11,%rdi
  cmp    %r10,%rcx
  jne    L99
L0:
  mov    %r9,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <free@plt>
```

assistant: ```c
void zero_out(int m, int n, int matrix[m][n]) {
  int x, y;
  bool *col_zero = (bool *)calloc(n, sizeof(bool));
  bool *row_zero = (bool *)calloc(m, sizeof(bool));
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (matrix[x][y] == 0)
        row_zero[y] = col_zero[x] = true;
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (col_zero[x] || row_zero[y])
        matrix[x][y] = 0;
  free(row_zero);
  free(col_zero);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zero_out>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  movslq %esi,%r12
  mov    $0x4,%esi
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  mov    %rdx,%rbx
  call   <calloc@plt>
  mov    %r14d,%edi
  mov    $0x4,%esi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %rax,%rdi
  test   %r14d,%r14d
  jle    L75
  test   %r12d,%r12d
  jle    L75
  mov    %rbx,%rdx
  mov    %r14d,%r11d
  mov    %r12d,%r9d
  mov    %rbp,%rsi
  lea    0x0(,%r12,4),%r10
  sub    %rax,%rdx
  lea    0x0(%rbp,%r11,4),%r8
  lea    (%rax,%r9,4),%rcx
  nopw   0x0(%rax,%rax,1)
L53:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L57:
  mov    (%rdx,%rax,1),%r13d
  test   %r13d,%r13d
  jne    L3
  movl   $0x1,(%rsi)
  movl   $0x1,(%rax)
L3:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L57
  add    $0x4,%rsi
  add    %r10,%rdx
  cmp    %r8,%rsi
  jne    L53
  sub    %rdi,%rbx
  lea    0x0(%rbp,%r11,4),%r10
  lea    (%rdi,%r9,4),%rsi
  mov    %rbp,%rdx
  lea    0x0(,%r12,4),%r8
  mov    %rbx,%rcx
  nopl   0x0(%rax)
L60:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L89:
  mov    (%rdx),%r11d
  test   %r11d,%r11d
  jne    L78
  mov    (%rax),%r9d
  test   %r9d,%r9d
  je     L54
L78:
  movl   $0x0,(%rcx,%rax,1)
L54:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L89
  add    $0x4,%rdx
  add    %r8,%rcx
  cmp    %r10,%rdx
  jne    L60
L75:
  call   <free@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <free@plt>
```

assistant: ```c
void zero_out(int m, int n, int matrix[m][n]) {
  int x, y;
  bool *col_zero = (bool *)calloc(n, sizeof(bool));
  bool *row_zero = (bool *)calloc(m, sizeof(bool));
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (matrix[x][y] == 0)
        row_zero[y] = col_zero[x] = true;
  for (x = 0; x < m; x++)
    for (y = 0; y < n; y++)
      if (col_zero[x] || row_zero[y])
        matrix[x][y] = 0;
  free(row_zero);
  free(col_zero);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fcas3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((noipa)) void fcas3(char a[3]) {
  sink(0, a[0]);
  sink(0, a[1]);
  sink(0, a[2]);
  sink(0, a[3]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fcas3>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  movsbl 0x1(%rbx),%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  movsbl 0x2(%rbx),%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  movsbl 0x3(%rbx),%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <sink@plt>
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((noipa)) void fcas3(char a[3]) {
  sink(0, a[0]);
  sink(0, a[1]);
  sink(0, a[2]);
  sink(0, a[3]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fcas3>:
  endbr64
  push   %rbx
  movsbl (%rdi),%esi
  mov    %rdi,%rbx
  xor    %eax,%eax
  xor    %edi,%edi
  call   <sink@plt>
  movsbl 0x1(%rbx),%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <sink@plt>
  movsbl 0x2(%rbx),%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <sink@plt>
  movsbl 0x3(%rbx),%esi
  xor    %edi,%edi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <sink@plt>
```

assistant: ```c
__attribute__((noipa)) void fcas3(char a[3]) {
  sink(0, a[0]);
  sink(0, a[1]);
  sink(0, a[2]);
  sink(0, a[3]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fcas3>:
  endbr64
  push   %rbx
  movsbl (%rdi),%esi
  mov    %rdi,%rbx
  xor    %eax,%eax
  xor    %edi,%edi
  call   <sink@plt>
  movsbl 0x1(%rbx),%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <sink@plt>
  movsbl 0x2(%rbx),%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <sink@plt>
  movsbl 0x3(%rbx),%esi
  xor    %edi,%edi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <sink@plt>
```

assistant: ```c
__attribute__((noipa)) void fcas3(char a[3]) {
  sink(0, a[0]);
  sink(0, a[1]);
  sink(0, a[2]);
  sink(0, a[3]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L8
L15:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl -0x9(%rbp),%edx
  imul   %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  addb   $0x2,-0xa(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L15
  movzbl -0x9(%rbp),%eax
  lea    0x5e(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] = state[local1] * state[0UL];
      state[local1] = state[0UL] + state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 838946365UL) - (unsigned char)223;
  }
}
```