ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L32
  nopl   0x0(%rax)
L4:
  add    $0x1,%rbp
L32:
  mov    %r13,%rdi
  mov    %rbp,%r12
  call   <strlen@plt>
  sub    %rbx,%r12
  cltq
  cmp    %rax,%r12
  jl     L4
  mov    %r13,%rsi
  mov    %rbx,%rdi
  movzbl 0x0(%rbp),%ebp
  call   <strcpy@plt>
  cmpb   $0x0,(%rbx)
  je     L19
  nopl   (%rax)
L27:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L27
L19:
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fun(char *a, char *b) {
  char t, *p;
  for (p = a; p - a < strlen(b); p++)
    ;
  t = *p;
  strcpy(a, b);
  while (*a)
    a++;
  *a = t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fun>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L29
  nopl   0x0(%rax)
L30:
  add    $0x1,%rbp
L29:
  mov    %r13,%rdi
  mov    %rbp,%r12
  call   <strlen@plt>
  sub    %rbx,%r12
  cltq
  cmp    %rax,%r12
  jl     L30
  mov    %r13,%rsi
  mov    %rbx,%rdi
  movzbl 0x0(%rbp),%ebp
  call   <strcpy@plt>
  cmpb   $0x0,(%rbx)
  je     L6
  nopl   (%rax)
L38:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L38
L6:
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void fun(char *a, char *b) {
  char t, *p;
  for (p = a; p - a < strlen(b); p++)
    ;
  t = *p;
  strcpy(a, b);
  while (*a)
    a++;
  *a = t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clearbpt>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int clearbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clearbpt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int clearbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<clearbpt>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int clearbpt(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<opdi_string_cmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L13
  mov    $0xffffffff,%eax
  jmp    L12
L13:
  cmpl   $0x0,-0x4(%rbp)
  jle    L8
  mov    $0x1,%eax
  jmp    L12
L8:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int8_t opdi_string_cmp(const char *s1, const char *s2) {
  int result = strcmp(s1, s2);
  if (result < 0)
    return -1;
  if (result > 0)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<opdi_string_cmp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  js     L9
  setg   %dl
  movzbl %dl,%edx
L9:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int8_t opdi_string_cmp(const char *s1, const char *s2) {
  int result = strcmp(s1, s2);
  if (result < 0)
    return -1;
  if (result > 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<opdi_string_cmp>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  mov    $0xffffffff,%edx
  mov    %eax,%r8d
  xor    %eax,%eax
  test   %r8d,%r8d
  setne  %al
  cmovs  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int8_t opdi_string_cmp(const char *s1, const char *s2) {
  int result = strcmp(s1, s2);
  if (result < 0)
    return -1;
  if (result > 0)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prep_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void prep_list(unsigned int **list, unsigned int *N) {
  bzero(*list, sizeof(unsigned int) * (*N + 1));
  (*list)[0] = 1;
  (*list)[1] = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prep_list>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rsi),%eax
  lea    0x4(,%rax,4),%esi
  mov    (%rdi),%rdi
  call   <bzero@plt>
  mov    (%rbx),%rax
  movl   $0x1,(%rax)
  mov    (%rbx),%rax
  movl   $0x1,0x4(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void prep_list(unsigned int **list, unsigned int *N) {
  bzero(*list, sizeof(unsigned int) * (*N + 1));
  (*list)[0] = 1;
  (*list)[1] = 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prep_list>:
  endbr64
  push   %rbx
  mov    (%rsi),%eax
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  lea    0x4(,%rax,4),%esi
  call   <bzero@plt>
  mov    (%rbx),%rax
  movabs $0x100000001,%rdx
  mov    %rdx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void prep_list(unsigned int **list, unsigned int *N) {
  bzero(*list, sizeof(unsigned int) * (*N + 1));
  (*list)[0] = 1;
  (*list)[1] = 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<prep_list>:
  endbr64
  push   %rbx
  mov    (%rsi),%eax
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  lea    0x4(,%rax,4),%esi
  call   <bzero@plt>
  mov    (%rbx),%rax
  mov    D6(%rip),%rdx
  mov    %rdx,(%rax)
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: byte[8]

tool: {"D6": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void prep_list(unsigned int **list, unsigned int *N) {
  bzero(*list, sizeof(unsigned int) * (*N + 1));
  (*list)[0] = 1;
  (*list)[1] = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_mac_module>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x3,-0x4(%rbp)
  jmp    L6
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  cmpl   $0x0,-0x1c(%rbp)
  setne  %al
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_guessed: string
name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D40
type_guessed: string

tool: D9: 0x

tool: D11: %02X

tool: D40: ,0x

assistant: ```c
void print_mac_module(unsigned char *mac, unsigned add) {
  int i;
  printf("0x");
  for (i = 3; i >= 0; i--)
    printf("%02X", mac[i]);
  printf(",0x");
  printf("%02X", mac[5] + (add ? 1 : 0));
  printf("%02X", mac[4]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_mac_module>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x3(%rbp),%rbx
  lea    D17(%rip),%r12
L6:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  sub    $0x1,%rbx
  cmp    %rbp,%rax
  jne    L6
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl 0x5(%rbp),%esi
  cmp    $0x1,%r13d
  sbb    $0xffffffff,%esi
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl 0x4(%rbp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D32
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string
name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D32: 0x

tool: D17: %02X

tool: D8: ,0x

assistant: ```c
void print_mac_module(unsigned char *mac, unsigned add) {
  int i;
  printf("0x");
  for (i = 3; i >= 0; i--)
    printf("%02X", mac[i]);
  printf(",0x");
  printf("%02X", mac[5] + (add ? 1 : 0));
  printf("%02X", mac[4]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_mac_module>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D15(%rip),%rdi
  push   %rbx
  lea    0x3(%rbp),%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
L5:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  sub    $0x1,%rbx
  cmp    %rbp,%rax
  jne    L5
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x5(%rbp),%esi
  cmp    $0x1,%r13d
  mov    %r12,%rdi
  sbb    $0xffffffff,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x4(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string

tool: D3: %02X

tool: D15: 0x

tool: D20: ,0x

assistant: ```c
void print_mac_module(unsigned char *mac, unsigned add) {
  int i;
  printf("0x");
  for (i = 3; i >= 0; i--)
    printf("%02X", mac[i]);
  printf(",0x");
  printf("%02X", mac[5] + (add ? 1 : 0));
  printf("%02X", mac[4]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_mac_module>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D20(%rip),%rdi
  push   %rbx
  lea    0x3(%rbp),%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
L8:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  sub    $0x1,%rbx
  cmp    %rbp,%rax
  jne    L8
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x5(%rbp),%esi
  cmp    $0x1,%r13d
  mov    %r12,%rdi
  sbb    $0xffffffff,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movzbl 0x4(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D20
data_type: string
name: parse_data
arguments: label: D13
data_type: string

tool: D12: %02X

tool: D20: 0x

tool: D13: ,0x

assistant: ```c
void print_mac_module(unsigned char *mac, unsigned add) {
  int i;
  printf("0x");
  for (i = 3; i >= 0; i--)
    printf("%02X", mac[i]);
  printf(",0x");
  printf("%02X", mac[5] + (add ? 1 : 0));
  printf("%02X", mac[4]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0xa,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  movslq %eax,%rdx
  mov    %rdx,%rsi
  mov    $0x0,%edi
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L51:
  cmp    %rdx,%rsp
  je     L68
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L51
L68:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L52
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L52:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  movl   $0x1,-0x30(%rbp)
  jmp    L90
L4:
  mov    -0x30(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    -0x30(%rbp),%edx
  neg    %edx
  imul   %edx,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x30(%rbp)
L90:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  movl   $0x0,-0x30(%rbp)
  jmp    L98
L27:
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  test   %eax,%eax
  js     L20
  mov    -0x20(%rbp),%rax
  mov    -0x30(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L63
L20:
  nop
L63:
  addl   $0x1,-0x30(%rbp)
L98:
  mov    -0x30(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L27
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_guessed: string

tool: D8: a[%d] = [%d]


assistant: ```c
int main(void) {
  int max = 10;
  int e, a[max];
  a[0] = 1;
  for (e = 1; e < max; ++e)
    a[e] = a[e - 1] * -e;
  for (e = 0; e < max; ++e) {
    if (a[e] < 0)
      continue;
    printf("a[%d] = [%d]\n", e, a[e]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0xffffffff,%eax
L5:
  mov    %eax,%ecx
  imul   -0x4(%rdx),%ecx
  mov    %ecx,(%rdx)
  sub    $0x1,%eax
  add    $0x4,%rdx
  cmp    $0xfffffff6,%eax
  jne    L5
  mov    $0x0,%ebx
  lea    D5(%rip),%rbp
  jmp    L35
L15:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  je     L39
L35:
  mov    %ebx,%esi
  mov    (%rsp,%rbx,4),%edx
  test   %edx,%edx
  js     L15
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L15
L39:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: a[%d] = [%d]


assistant: ```c
int main(void) {
  int max = 10;
  int e, a[max];
  a[0] = 1;
  for (e = 1; e < max; ++e)
    a[e] = a[e - 1] * -e;
  for (e = 0; e < max; ++e) {
    if (a[e] < 0)
      continue;
    printf("a[%d] = [%d]\n", e, a[e]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xffffffff,%ecx
  mov    $0x1,%edx
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rsi
  movl   $0x1,(%rsp)
  lea    0x4(%rsp),%rax
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L42:
  add    $0x4,%rax
L58:
  imul   %ecx,%edx
  sub    $0x1,%ecx
  mov    %edx,(%rax)
  cmp    %rsi,%rax
  jne    L42
  xor    %ebx,%ebx
  mov    $0x1,%edx
  lea    D7(%rip),%rbp
  jmp    L50
  nopl   0x0(%rax)
L54:
  mov    (%rsp,%rbx,4),%edx
L50:
  mov    %ebx,%esi
  test   %edx,%edx
  js     L26
  mov    %rbp,%rdi
  call   <printf@plt>
L26:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L54
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: a[%d] = [%d]


assistant: ```c
int main(void) {
  int max = 10;
  int e, a[max];
  a[0] = 1;
  for (e = 1; e < max; ++e)
    a[e] = a[e - 1] * -e;
  for (e = 0; e < max; ++e) {
    if (a[e] < 0)
      continue;
    printf("a[%d] = [%d]\n", e, a[e]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  movdqa D26(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D38(%rip),%rax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movdqa D19(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   (%rax)
L21:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  test   %edx,%edx
  js     L26
  mov    %r12,%rdi
  call   <printf@plt>
L26:
  add    $0x1,%rbx
  cmp    $0xa,%rbx
  jne    L21
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D26
type: byte[16]
name: parse_data
arguments: data_label: D38
type: byte[8]
name: parse_data
arguments: data_label: D19
type: byte[16]

tool: D10: a[%d] = [%d]


tool: {"D26": [0x01,0x00,0x00,0x00,0xff,0xff,0xff,0xff,0x02,0x00,0x00,0x00,0xfa,0xff,0xff,0xff]}

tool: {"D38": [0x80,0x9d,0x00,0x00,0x80,0x76,0xfa,0xff]}

tool: {"D19": [0x18,0x00,0x00,0x00,0x88,0xff,0xff,0xff,0xd0,0x02,0x00,0x00,0x50,0xec,0xff,0xff]}

assistant: ```c
int main(void) {
  int max = 10;
  int e, a[max];
  a[0] = 1;
  for (e = 1; e < max; ++e)
    a[e] = a[e - 1] * -e;
  for (e = 0; e < max; ++e) {
    if (a[e] < 0)
      continue;
    printf("a[%d] = [%d]\n", e, a[e]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L0
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L22:
  subl   $0x1,-0x8(%rbp)
L75:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L63
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L22
  jmp    L63
L31:
  addl   $0x1,-0xc(%rbp)
L63:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L67
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L31
L67:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L11
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <itoj@plt>
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L75
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <itoj@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  jmp    L26
L0:
  nop
L26:
  leave
  ret
```

assistant: ```c
void quick_sort(int a[], int low, int high) {
  if (low > high)
    return;
  int pi = a[low];
  int i = low;
  int j = high;
  while (i < j) {
    while (a[j] >= pi && i < j)
      j--;
    while (a[i] <= pi && i < j)
      i++;
    if (j > i) {
      itoj(a, i, j);
    }
  }
  itoj(a, low, i);
  quick_sort(a, low, i - 1);
  quick_sort(a, i + 1, high);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<quick_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  jg     L89
  mov    %rdi,%r12
  mov    %esi,%r14d
  mov    %edx,%r15d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r13d
  mov    %edx,%ebp
  mov    %esi,%ebx
  jl     L72
  jmp    L57
L27:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <itoj@plt>
L72:
  movslq %ebp,%rax
  cmp    (%r12,%rax,4),%r13d
  jg     L40
  cmp    %ebp,%ebx
  setl   %dl
  lea    -0x1(%rbp),%eax
  cltq
  test   %dl,%dl
  je     L40
L44:
  mov    %eax,%ebp
  cmp    %r13d,(%r12,%rax,4)
  setge  %cl
  cmp    %eax,%ebx
  setl   %dl
  sub    $0x1,%rax
  test   %dl,%cl
  jne    L44
L40:
  movslq %ebx,%rax
  cmp    (%r12,%rax,4),%r13d
  jl     L26
  cmp    %ebp,%ebx
  jge    L26
  lea    0x1(%rbx),%eax
  cltq
L77:
  mov    %eax,%ebx
  cmp    %r13d,(%r12,%rax,4)
  setle  %cl
  cmp    %eax,%ebp
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L77
L26:
  cmp    %ebp,%ebx
  jl     L27
L57:
  mov    %ebx,%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <itoj@plt>
  lea    -0x1(%rbx),%edx
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%esi
  mov    %r15d,%edx
  mov    %r12,%rdi
  call   <quick_sort>
L89:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quick_sort(int a[], int low, int high) {
  if (low > high)
    return;
  int pi = a[low];
  int i = low;
  int j = high;
  while (i < j) {
    while (a[j] >= pi && i < j)
      j--;
    while (a[i] <= pi && i < j)
      i++;
    if (j > i) {
      itoj(a, i, j);
    }
  }
  itoj(a, low, i);
  quick_sort(a, low, i - 1);
  quick_sort(a, i + 1, high);
}
```