ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_comparisons_32@plt>
  xor    %eax,%eax
  call   <test_comparisons_64@plt>
  xor    %eax,%eax
  call   <test_comparisons_buffers@plt>
  xor    %eax,%eax
  call   <test_hex@plt>
  xor    %eax,%eax
  call   <test_base64@plt>
  xor    %eax,%eax
  call   <test_mul@plt>
  xor    %eax,%eax
  call   <test_bitlength@plt>
  xor    %eax,%eax
  call   <test_i31_set@plt>
  xor    %eax,%eax
  call   <test_i31_codec@plt>
  xor    %eax,%eax
  call   <test_i31_cmp@plt>
  xor    %eax,%eax
  call   <test_i31_addsub@plt>
  xor    %eax,%eax
  call   <test_i31_mul@plt>
  xor    %eax,%eax
  call   <test_i31_shift@plt>
  xor    %eax,%eax
  call   <test_i31_div@plt>
  xor    %eax,%eax
  call   <test_i31_bool@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_comparisons_32();
  test_comparisons_64();
  test_comparisons_buffers();
  test_hex();
  test_base64();
  test_mul();
  test_bitlength();
  test_i31_set();
  test_i31_codec();
  test_i31_cmp();
  test_i31_addsub();
  test_i31_mul();
  test_i31_shift();
  test_i31_div();
  test_i31_bool();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_comparisons_32@plt>
  xor    %eax,%eax
  call   <test_comparisons_64@plt>
  xor    %eax,%eax
  call   <test_comparisons_buffers@plt>
  xor    %eax,%eax
  call   <test_hex@plt>
  xor    %eax,%eax
  call   <test_base64@plt>
  xor    %eax,%eax
  call   <test_mul@plt>
  xor    %eax,%eax
  call   <test_bitlength@plt>
  xor    %eax,%eax
  call   <test_i31_set@plt>
  xor    %eax,%eax
  call   <test_i31_codec@plt>
  xor    %eax,%eax
  call   <test_i31_cmp@plt>
  xor    %eax,%eax
  call   <test_i31_addsub@plt>
  xor    %eax,%eax
  call   <test_i31_mul@plt>
  xor    %eax,%eax
  call   <test_i31_shift@plt>
  xor    %eax,%eax
  call   <test_i31_div@plt>
  xor    %eax,%eax
  call   <test_i31_bool@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_comparisons_32();
  test_comparisons_64();
  test_comparisons_buffers();
  test_hex();
  test_base64();
  test_mul();
  test_bitlength();
  test_i31_set();
  test_i31_codec();
  test_i31_cmp();
  test_i31_addsub();
  test_i31_mul();
  test_i31_shift();
  test_i31_div();
  test_i31_bool();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getAccountId>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L57
  mov    $0x0,%eax
  jmp    L42
L68:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x43,%eax
  cmp    %eax,-0x3c(%rbp)
  jne    L57
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L57
  mov    -0x38(%rbp),%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L57
  mov    $0x41,%edi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    $0x2,%rax
  lea    (%rbx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x40,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%rax
  add    $0x40,%rax
  movb   $0x0,(%rax)
  jmp    L49
L57:
  mov    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  lea    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getline@plt>
  mov    %eax,-0x3c(%rbp)
  cmpl   $0xffffffff,-0x3c(%rbp)
  jne    L68
L49:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x28(%rbp),%rax
L42:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D5: r

assistant: ```c
const char *getAccountId(const char *pUser, const char *pAccounts) {
  char *toReturn = NULL;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  FILE *fp;
  fp = fopen(pAccounts, "r");
  if (fp == NULL) {
    return NULL;
  }
  while ((read = getline(&line, &len, fp)) != -1) {
    if ((read == strlen(pUser) + 64 + 3) && strncmp(pUser, line, strlen(pUser)) == 0 && line[strlen(pUser)] == ':') {
      toReturn = malloc(64 + 1);
      strncpy(toReturn, line + strlen(pUser) + 2, 64);
      toReturn[64] = '\0';
      break;
    }
  }
  free(line);
  fclose(fp);
  return toReturn;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getAccountId>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  lea    D4(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L72
  lea    0x10(%rsp),%r13
L66:
  lea    0x8(%rsp),%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <getline@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  je     L47
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x43,%eax
  cmp    %ebx,%eax
  jne    L66
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L66
  mov    0x8(%rsp),%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0x3a,(%rbx,%rax,1)
  jne    L66
  mov    $0x41,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    0x8(%rsp),%r13
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    0x2(%r13,%rax,1),%rsi
  mov    $0x40,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x40(%rbx)
  jmp    L62
L47:
  mov    $0x0,%ebx
L62:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  mov    %rax,%rbx
  jmp    L8
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: r

assistant: ```c
const char *getAccountId(const char *pUser, const char *pAccounts) {
  char *toReturn = NULL;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  FILE *fp;
  fp = fopen(pAccounts, "r");
  if (fp == NULL) {
    return NULL;
  }
  while ((read = getline(&line, &len, fp)) != -1) {
    if ((read == strlen(pUser) + 64 + 3) && strncmp(pUser, line, strlen(pUser)) == 0 && line[strlen(pUser)] == ':') {
      toReturn = malloc(64 + 1);
      strncpy(toReturn, line + strlen(pUser) + 2, 64);
      toReturn[64] = '\0';
      break;
    }
  }
  free(line);
  fclose(fp);
  return toReturn;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getAccountId>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D2(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L22
  mov    %rax,%rbp
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  jmp    L42
  nopl   0x0(%rax)
L38:
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x43,%eax
  cmp    %ebx,%eax
  je     L79
L42:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L38
  xor    %r13d,%r13d
L36:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L79:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L42
  mov    %r12,%rdi
  mov    0x8(%rsp),%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x3a,(%rbx,%rax,1)
  jne    L42
  mov    $0x41,%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    0x8(%rsp),%rbx
  mov    %rax,%r13
  call   <strlen@plt>
  mov    $0x40,%edx
  mov    %r13,%rdi
  cltq
  lea    0x2(%rbx,%rax,1),%rsi
  call   <strncpy@plt>
  movb   $0x0,0x40(%r13)
  jmp    L36
  nopl   (%rax)
L22:
  xor    %r13d,%r13d
  jmp    L21
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string

tool: D2: r

assistant: ```c
const char *getAccountId(const char *pUser, const char *pAccounts) {
  char *toReturn = NULL;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  FILE *fp;
  fp = fopen(pAccounts, "r");
  if (fp == NULL) {
    return NULL;
  }
  while ((read = getline(&line, &len, fp)) != -1) {
    if ((read == strlen(pUser) + 64 + 3) && strncmp(pUser, line, strlen(pUser)) == 0 && line[strlen(pUser)] == ':') {
      toReturn = malloc(64 + 1);
      strncpy(toReturn, line + strlen(pUser) + 2, 64);
      toReturn[64] = '\0';
      break;
    }
  }
  free(line);
  fclose(fp);
  return toReturn;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getAccountId>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  lea    D6(%rip),%rsi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  call   <fopen@plt>
  test   %rax,%rax
  je     L58
  mov    %rax,%rbp
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  jmp    L42
  nopl   0x0(%rax)
L30:
  mov    %r12,%rdi
  call   <strlen@plt>
  add    $0x43,%eax
  cmp    %ebx,%eax
  je     L46
L42:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <getline@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L30
  xor    %r13d,%r13d
L0:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L46:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    0x8(%rsp),%rsi
  mov    %r12,%rdi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L42
  mov    %r12,%rdi
  mov    0x8(%rsp),%rbx
  call   <strlen@plt>
  cltq
  cmpb   $0x3a,(%rbx,%rax,1)
  jne    L42
  mov    $0x41,%edi
  call   <malloc@plt>
  mov    %r12,%rdi
  mov    0x8(%rsp),%rbx
  mov    %rax,%r13
  call   <strlen@plt>
  mov    $0x40,%edx
  mov    %r13,%rdi
  cltq
  lea    0x2(%rbx,%rax,1),%rsi
  call   <strncpy@plt>
  movb   $0x0,0x40(%r13)
  jmp    L0
  nopl   (%rax)
L58:
  xor    %r13d,%r13d
  jmp    L9
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: r

assistant: ```c
const char *getAccountId(const char *pUser, const char *pAccounts) {
  char *toReturn = NULL;
  char *line = NULL;
  size_t len = 0;
  ssize_t read;
  FILE *fp;
  fp = fopen(pAccounts, "r");
  if (fp == NULL) {
    return NULL;
  }
  while ((read = getline(&line, &len, fp)) != -1) {
    if ((read == strlen(pUser) + 64 + 3) && strncmp(pUser, line, strlen(pUser)) == 0 && line[strlen(pUser)] == ':') {
      toReturn = malloc(64 + 1);
      strncpy(toReturn, line + strlen(pUser) + 2, 64);
      toReturn[64] = '\0';
      break;
    }
  }
  free(line);
  fclose(fp);
  return toReturn;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  jmp    L51
L8:
  movl   $0x1,-0x4(%rbp)
  jmp    L50
L52:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L53
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L53:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L50:
  cmpl   $0x9,-0x4(%rbp)
  jle    L52
L39:
  addl   $0x1,-0x8(%rbp)
L51:
  cmpl   $0x9,-0x8(%rbp)
  jle    L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: string

tool: D12: %d x %d = %d


assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 9; i++)
    for (j = 1; j <= 9; j++) {
      if (i == j) {
        printf("%d x %d = %d\n", j, i, i * j);
        break;
      } else {
        printf("%d x %d = %d\n", j, i, i * j);
      }
    }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebp
  lea    D0(%rip),%r13
  jmp    L24
L39:
  mov    %ebp,%esi
L16:
  mov    %ebp,%ecx
  imul   %esi,%ecx
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <printf@plt>
L19:
  add    $0x1,%ebp
  cmp    $0xa,%ebp
  je     L66
L24:
  cmp    $0x1,%ebp
  je     L55
  mov    %ebp,%ecx
  mov    %ebp,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebp,%r14d
  lea    0x0(%rbp,%rbp,1),%r12d
  mov    $0x2,%ebx
L37:
  cmp    %ebp,%ebx
  je     L39
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r14d,%r12d
  cmp    $0xa,%ebx
  jne    L37
  jmp    L19
L55:
  mov    %ebp,%esi
  jmp    L16
L66:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: %d x %d = %d


assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 9; i++)
    for (j = 1; j <= 9; j++) {
      if (i == j) {
        printf("%d x %d = %d\n", j, i, i * j);
        break;
      } else {
        printf("%d x %d = %d\n", j, i, i * j);
      }
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%ebp
  je     L22
  nop
L28:
  mov    %ebp,%r12d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12d,%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    %ebp,%r12d
  cmp    %ebp,%ebx
  jne    L8
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  imul   %ebx,%ecx
  call   <printf@plt>
  cmp    $0x9,%ebx
  je     L32
L39:
  add    $0x1,%ebp
  cmp    $0x1,%ebp
  jne    L28
L22:
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L39
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: %d x %d = %d


assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 9; i++)
    for (j = 1; j <= 9; j++) {
      if (i == j) {
        printf("%d x %d = %d\n", j, i, i * j);
        break;
      } else {
        printf("%d x %d = %d\n", j, i, i * j);
      }
    }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%ebp
  je     L28
  nop
L10:
  mov    %ebp,%r12d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L49:
  mov    %r12d,%ecx
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    %ebp,%r12d
  cmp    %ebp,%ebx
  jne    L49
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  imul   %ebx,%ecx
  call   <printf@plt>
  cmp    $0x9,%ebx
  je     L9
L40:
  add    $0x1,%ebp
  cmp    $0x1,%ebp
  jne    L10
L28:
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L40
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: %d x %d = %d


assistant: ```c
int main() {
  int i, j;
  for (i = 1; i <= 9; i++)
    for (j = 1; j <= 9; j++) {
      if (i == j) {
        printf("%d x %d = %d\n", j, i, i * j);
        break;
      } else {
        printf("%d x %d = %d\n", j, i, i * j);
      }
    }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int kill(int pid __attribute__((unused)), int sig __attribute__((unused))) {
  errno = EINVAL;
  return (-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<kill>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int kill(int pid __attribute__((unused)), int sig __attribute__((unused))) {
  errno = EINVAL;
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<kill>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int kill(int pid __attribute__((unused)), int sig __attribute__((unused))) {
  errno = EINVAL;
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<kill>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int kill(int pid __attribute__((unused)), int sig __attribute__((unused))) {
  errno = EINVAL;
  return (-1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inet6_opt_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0xff,%r8d
  jg     L30
  mov    %esi,%r10d
  mov    %edx,%esi
  mov    %ecx,%r12d
  mov    %r8d,%ebp
  cmp    $0x1,%ecx
  jle    L30
  lea    -0x4(%r9),%eax
  test   $0xfffffffb,%eax
  je     L139
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L142
L139:
  cmp    %r9d,%ebp
  jl     L99
  lea    0x2(%rsi,%rbp,1),%r13d
  mov    %r13d,%eax
  cltd
  idiv   %r9d
  sub    %edx,%r9d
  test   %edx,%edx
  mov    %edx,%ebx
  cmovne %r9d,%ebx
  add    %ebx,%r13d
  test   %r10d,%r10d
  je     L48
  cmp    %r10d,%r13d
  jg     L90
L48:
  test   %rdi,%rdi
  je     L57
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebx
  je     L41
  test   %ebx,%ebx
  jg     L50
L85:
  mov    %r12d,(%rax)
  mov    %ebp,0x4(%rax)
  add    $0x8,%rax
  mov    0x30(%rsp),%rdx
  mov    %rax,(%rdx)
L57:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  mov    D3(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  jmp    L85
L50:
  mov    D9(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    0x8(%rax),%r14
  lea    -0x2(%rbx),%edx
  mov    %edx,0x4(%rax)
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  movslq %ebx,%rbx
  lea    -0x8(%r14,%rbx,4),%rax
  jmp    L85
L30:
  mov    $0xffffffff,%r13d
  jmp    L57
L142:
  mov    $0xffffffff,%r13d
  jmp    L57
L99:
  mov    $0xffffffff,%r13d
  jmp    L57
L90:
  mov    $0xffffffff,%r13d
  jmp    L57
```

assistant: ```c
__attribute__((visibility("default"))) int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len > 255) {
    return (-1);
  }
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inet6_opt_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0xff,%r8d
  jg     L92
  mov    %ecx,%r12d
  cmp    $0x1,%ecx
  jle    L92
  lea    -0x4(%r9),%eax
  mov    %esi,%r10d
  mov    %r8d,%ebx
  movslq %edx,%rsi
  and    $0xfffffffb,%eax
  je     L42
  lea    -0x1(%r9),%eax
  cmp    $0x1,%eax
  ja     L92
L42:
  cmp    %r9d,%ebx
  jl     L92
  lea    0x2(%rsi,%rbx,1),%r13d
  mov    %r13d,%eax
  cltd
  idiv   %r9d
  movslq %edx,%rbp
  test   %ebp,%ebp
  je     L87
  sub    %ebp,%r9d
  movslq %r9d,%rbp
  add    %ebp,%r13d
L87:
  test   %r10d,%r10d
  je     L97
  cmp    %r13d,%r10d
  jl     L92
L97:
  test   %rdi,%rdi
  je     L30
  lea    (%rdi,%rsi,4),%rax
  cmp    $0x1,%ebp
  je     L122
  test   %ebp,%ebp
  jle    L66
  mov    D17(%rip),%rdx
  lea    0x8(%rax),%r14
  xor    %esi,%esi
  mov    %r14,%rdi
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    -0x2(%rbp),%edx
  mov    %edx,0x4(%rax)
  call   <memset@plt>
  lea    -0x8(%r14,%rbp,4),%rax
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L122:
  mov    D16(%rip),%rdx
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,-0x4(%rax)
L66:
  mov    0x30(%rsp),%rdx
  mov    %r12d,(%rax)
  add    $0x8,%rax
  mov    %ebx,-0x4(%rax)
  mov    %rax,(%rdx)
L30:
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L92:
  mov    $0xffffffff,%r13d
  jmp    L30
```

assistant: ```c
__attribute__((visibility("default"))) int inet6_opt_append(void *extbuf, socklen_t extlen, int offset, u_int8_t type, socklen_t len, u_int8_t align, void **databufp) {
  int currentlen = offset, padlen = 0;
  if (type < 2)
    return (-1);
  if (len > 255) {
    return (-1);
  }
  if (align != 1 && align != 2 && align != 4 && align != 8)
    return (-1);
  if (align > len)
    return (-1);
  currentlen += 2 + len;
  if (currentlen % align)
    padlen = align - (currentlen % align);
  currentlen += padlen;
  if (extlen && currentlen > extlen)
    return (-1);
  if (extbuf) {
    u_int8_t *optp = (u_int8_t *)extbuf + offset;
    if (padlen == 1) {
      *optp = IP6OPT_PAD1;
      optp++;
    } else if (padlen > 0) {
      *optp++ = IP6OPT_PADN;
      *optp++ = padlen - 2;
      memset(optp, 0, padlen - 2);
      optp += (padlen - 2);
    }
    *optp++ = type;
    *optp++ = len;
    *databufp = optp;
  }
  return (currentlen);
}
```