ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<replace_minus>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x10000,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L34
  mov    %rbp,%rbx
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  xor    %edx,%edx
  jmp    L103
L66:
  movzbl (%rbx),%edx
  movslq %r14d,%rax
  mov    %dl,(%r12,%rax,1)
L63:
  add    $0x1,%r15d
  add    $0x1,%r14d
  movslq %r15d,%rdx
  lea    0x0(%rbp,%rdx,1),%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L33
L103:
  cmp    $0x2d,%al
  jne    L66
  test   %r15d,%r15d
  je     L101
  lea    -0x1(%rbp,%rdx,1),%r13
  movsbl 0x0(%r13),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L66
  cmpb   $0x29,0x0(%r13)
  je     L66
L101:
  mov    %rbx,%rdi
  movslq %r14d,%rbx
  call   <atof@plt>
  add    %r12,%rbx
  xorpd  D10(%rip),%xmm0
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    0x1(%r14),%eax
  cmpb   $0x29,(%rbx)
  cltq
  je     L13
  nopl   0x0(%rax)
L19:
  movzbl (%r12,%rax,1),%edx
  mov    %eax,%r14d
  add    $0x1,%rax
  cmp    $0x29,%dl
  jne    L19
L13:
  movslq %r15d,%rbx
  nopl   0x0(%rax)
L60:
  movsbl 0x1(%rbp,%rbx,1),%edi
  mov    %ebx,%r15d
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L60
  jmp    L63
  nopl   0x0(%rax,%rax,1)
L33:
  movslq %r14d,%r14
  add    %r12,%r14
L17:
  movb   $0x0,(%r14)
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %r12,%r14
  jmp    L17
```

tool_calls: name: read_data
arguments: label: D10
datatype: byte[16]
name: read_data
arguments: label: D13
datatype: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D13: (0-%g)

assistant: ```c
void replace_minus(char *p) {
  int i, j;
  char *tmp = (char *)calloc(65536, sizeof(char));
  i = j = 0;
  while (p[i] != '\0') {
    if (p[i] == '-' && (i == 0 || (isdigit(p[i - 1]) == 0 && p[i - 1] != ')'))) {
      sprintf(tmp + j, "(0-%g)", -atof(p + i));
      while (tmp[j] != ')') {
        ++j;
      }
      while (isdigit(p[i + 1]) != 0) {
        ++i;
      }
    } else {
      tmp[j] = p[i];
    }
    ++i;
    ++j;
  }
  tmp[j] = '\0';
  strcpy(p, tmp);
  free(tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<replace_minus>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x10000,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L36
  mov    %rbp,%rbx
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  xor    %edx,%edx
  jmp    L105
L79:
  movslq %r14d,%rdx
  mov    %al,(%r12,%rdx,1)
L104:
  add    $0x1,%r15d
  add    $0x1,%r14d
  movslq %r15d,%rdx
  lea    0x0(%rbp,%rdx,1),%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L93
L105:
  cmp    $0x2d,%al
  jne    L79
  test   %r15d,%r15d
  je     L53
  lea    -0x1(%rbp,%rdx,1),%r13
  movsbl 0x0(%r13),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L2
  cmpb   $0x29,0x0(%r13)
  jne    L53
L2:
  movzbl (%rbx),%eax
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %rbx,%rdi
  movslq %r14d,%rbx
  call   <atof@plt>
  add    %r12,%rbx
  xorpd  D5(%rip),%xmm0
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  cmpb   $0x29,(%rbx)
  je     L81
  lea    0x1(%r14),%eax
  cltq
L58:
  movzbl (%r12,%rax,1),%edx
  mov    %eax,%r14d
  add    $0x1,%rax
  cmp    $0x29,%dl
  jne    L58
L81:
  movslq %r15d,%rbx
  nopl   0x0(%rax)
L20:
  movsbl 0x1(%rbp,%rbx,1),%edi
  mov    %ebx,%r15d
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L20
  jmp    L104
  nopl   0x0(%rax,%rax,1)
L93:
  movslq %r14d,%r14
  add    %r12,%r14
L118:
  movb   $0x0,(%r14)
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <free@plt>
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r12,%r14
  jmp    L118
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: byte[16]
name: read_data
arguments: data_tag: D15
type_infered: string

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D15: (0-%g)

assistant: ```c
void replace_minus(char *p) {
  int i, j;
  char *tmp = (char *)calloc(65536, sizeof(char));
  i = j = 0;
  while (p[i] != '\0') {
    if (p[i] == '-' && (i == 0 || (isdigit(p[i - 1]) == 0 && p[i - 1] != ')'))) {
      sprintf(tmp + j, "(0-%g)", -atof(p + i));
      while (tmp[j] != ')') {
        ++j;
      }
      while (isdigit(p[i + 1]) != 0) {
        ++i;
      }
    } else {
      tmp[j] = p[i];
    }
    ++i;
    ++j;
  }
  tmp[j] = '\0';
  strcpy(p, tmp);
  free(tmp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<eigsrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L41:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L43
L12:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  comiss -0x4(%rbp),%xmm0
  jb     L65
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
L65:
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L25
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L60
L56:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L60:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L56
L25:
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L41
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void eigsrt(d, v, n) float d[], **v;
int n;
{
  int k, j, i;
  for (i = 0; i < n - 1; i++) {
    float p = d[k = i];
    for (j = i + 1; j < n; j++)
      if (d[j] >= p)
        p = d[k = j];
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 0; j < n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<eigsrt>:
  endbr64
  cmp    $0x1,%edx
  jle    L92
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  lea    -0x2(%rdx),%ebp
  lea    -0x1(%rdx),%eax
  lea    0x8(%rsi,%rax,8),%r11
  mov    $0x1,%r10d
  mov    $0x0,%r8d
  jmp    L68
L77:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L96
L15:
  movss  (%rcx,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jb     L77
  movaps %xmm0,%xmm1
  mov    %eax,%esi
  jmp    L77
L96:
  cmp    %r8d,%esi
  jne    L117
L100:
  lea    0x1(%r8),%rax
  add    $0x1,%r10
  cmp    %rbp,%r8
  je     L3
  mov    %rax,%r8
L68:
  mov    %r8d,%esi
  lea    0x0(,%r8,4),%r9
  movss  (%rcx,%r8,4),%xmm2
  cmp    %r10d,%edx
  jle    L100
  mov    %r10,%rax
  movaps %xmm2,%xmm1
  jmp    L15
L117:
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%r12
  movss  %xmm2,(%rcx,%rsi,4)
  movss  %xmm1,(%rcx,%r8,4)
  test   %edx,%edx
  jle    L100
  mov    %rbx,%rax
L20:
  mov    (%rax),%rdi
  lea    (%rdi,%r9,1),%rsi
  movss  (%rsi),%xmm0
  movss  (%rdi,%r12,1),%xmm1
  movss  %xmm1,(%rsi)
  mov    (%rax),%rsi
  movss  %xmm0,(%rsi,%r12,1)
  add    $0x8,%rax
  cmp    %rax,%r11
  jne    L20
  jmp    L100
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L92:
  ret
```

assistant: ```c
void eigsrt(d, v, n) float d[], **v;
int n;
{
  int k, j, i;
  for (i = 0; i < n - 1; i++) {
    float p = d[k = i];
    for (j = i + 1; j < n; j++)
      if (d[j] >= p)
        p = d[k = j];
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 0; j < n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<eigsrt>:
  endbr64
  cmp    $0x1,%edx
  jle    L86
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %rdi,%rcx
  mov    $0x1,%r10d
  push   %rbp
  mov    %edx,%edi
  lea    -0x2(%rdx),%ebp
  lea    0x8(%rsi,%rax,8),%r11
  push   %rbx
  xor    %r8d,%r8d
  mov    %rsi,%rbx
  nopl   (%rax)
L16:
  movss  (%rcx,%r8,4),%xmm2
  movslq %r8d,%rdx
  lea    0x0(,%r8,4),%r9
  mov    %r10,%rax
  movaps %xmm2,%xmm1
  cmp    %r10d,%edi
  jle    L78
  nopl   0x0(%rax)
L51:
  movss  (%rcx,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jb     L9
  movaps %xmm0,%xmm1
  movslq %eax,%rdx
L9:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L51
  cmp    %r8d,%edx
  jne    L26
L78:
  lea    0x1(%r8),%rax
  add    $0x1,%r10
  cmp    %rbp,%r8
  je     L50
L6:
  mov    %rax,%r8
  jmp    L16
  nop
L26:
  movss  %xmm2,(%rcx,%rdx,4)
  lea    0x0(,%rdx,4),%r12
  mov    %rbx,%rdx
  movss  %xmm1,(%rcx,%r8,4)
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  lea    (%rax,%r9,1),%rsi
  add    %r12,%rax
  movss  (%rsi),%xmm0
  movss  (%rax),%xmm1
  movss  %xmm1,(%rsi)
  movss  %xmm0,(%rax)
  cmp    %rdx,%r11
  jne    L66
  lea    0x1(%r8),%rax
  add    $0x1,%r10
  cmp    %rbp,%r8
  jne    L6
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L86:
  ret
```

assistant: ```c
void eigsrt(d, v, n) float d[], **v;
int n;
{
  int k, j, i;
  for (i = 0; i < n - 1; i++) {
    float p = d[k = i];
    for (j = i + 1; j < n; j++)
      if (d[j] >= p)
        p = d[k = j];
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 0; j < n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<eigsrt>:
  endbr64
  cmp    $0x1,%edx
  jle    L31
  lea    -0x1(%rdx),%eax
  push   %r12
  mov    %rdi,%rcx
  mov    $0x1,%r10d
  push   %rbp
  mov    %edx,%edi
  lea    -0x2(%rdx),%ebp
  lea    0x8(%rsi,%rax,8),%r11
  push   %rbx
  xor    %r8d,%r8d
  mov    %rsi,%rbx
  nopl   (%rax)
L71:
  movss  (%rcx,%r8,4),%xmm2
  movslq %r8d,%rdx
  lea    0x0(,%r8,4),%r9
  mov    %r10,%rax
  movaps %xmm2,%xmm1
  cmp    %r10d,%edi
  jle    L40
  nopl   0x0(%rax)
L6:
  movss  (%rcx,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jb     L38
  movaps %xmm0,%xmm1
  movslq %eax,%rdx
L38:
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L6
  cmp    %r8d,%edx
  jne    L5
L40:
  lea    0x1(%r8),%rax
  add    $0x1,%r10
  cmp    %r8,%rbp
  je     L23
L29:
  mov    %rax,%r8
  jmp    L71
  nop
L5:
  movss  %xmm2,(%rcx,%rdx,4)
  lea    0x0(,%rdx,4),%r12
  mov    %rbx,%rdx
  movss  %xmm1,(%rcx,%r8,4)
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    (%rdx),%rax
  add    $0x8,%rdx
  lea    (%rax,%r9,1),%rsi
  add    %r12,%rax
  movss  (%rsi),%xmm0
  movss  (%rax),%xmm1
  movss  %xmm1,(%rsi)
  movss  %xmm0,(%rax)
  cmp    %rdx,%r11
  jne    L56
  lea    0x1(%r8),%rax
  add    $0x1,%r10
  cmp    %r8,%rbp
  jne    L29
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  ret
```

assistant: ```c
void eigsrt(d, v, n) float d[], **v;
int n;
{
  int k, j, i;
  for (i = 0; i < n - 1; i++) {
    float p = d[k = i];
    for (j = i + 1; j < n; j++)
      if (d[j] >= p)
        p = d[k = j];
    if (k != i) {
      d[k] = d[i];
      d[i] = p;
      for (j = 0; j < n; j++) {
        p = v[j][i];
        v[j][i] = v[j][k];
        v[j][k] = p;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rq_settlement_information_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <rq_settlement_information_clear@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void rq_settlement_information_free(struct rq_settlement_information *p) {
  rq_settlement_information_clear(p);
  free(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rq_settlement_information_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <rq_settlement_information_clear@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void rq_settlement_information_free(struct rq_settlement_information *p) {
  rq_settlement_information_clear(p);
  free(p);
}
```
user: What is the c source code of the assembly code below:

```asm
<rq_settlement_information_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <rq_settlement_information_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void rq_settlement_information_free(struct rq_settlement_information *p) {
  rq_settlement_information_clear(p);
  free(p);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rq_settlement_information_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <rq_settlement_information_clear@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void rq_settlement_information_free(struct rq_settlement_information *p) {
  rq_settlement_information_clear(p);
  free(p);
}
```
user: What is the c source code of the assembly code below?

```asm
<console_backspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L18:
  mov    $0x1,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <console_write@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: 

assistant: ```c
void console_backspace(int n) {
  int t;
  for (t = 0; t < n; t++)
    console_write("\b", 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<console_backspace>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L17:
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <console_write@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: 

assistant: ```c
void console_backspace(int n) {
  int t;
  for (t = 0; t < n; t++)
    console_write("\b", 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<console_backspace>:
  endbr64
  test   %edi,%edi
  jle    L15
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <console_write@plt>
  cmp    %ebx,%ebp
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L15:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string

tool: D0: 

assistant: ```c
void console_backspace(int n) {
  int t;
  for (t = 0; t < n; t++)
    console_write("\b", 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<console_backspace>:
  endbr64
  test   %edi,%edi
  jle    L16
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <console_write@plt>
  cmp    %ebx,%ebp
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string

tool: D3: 

assistant: ```c
void console_backspace(int n) {
  int t;
  for (t = 0; t < n; t++)
    console_write("\b", 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cdoProcessTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cdoProcessTime(double *utime, double *stime) {
  *utime = 0;
  *stime = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cdoProcessTime>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
void cdoProcessTime(double *utime, double *stime) {
  *utime = 0;
  *stime = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cdoProcessTime>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
void cdoProcessTime(double *utime, double *stime) {
  *utime = 0;
  *stime = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cdoProcessTime>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
void cdoProcessTime(double *utime, double *stime) {
  *utime = 0;
  *stime = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_args>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L12
  mov    $0x0,%eax
  call   <console_header@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <message_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L13
L12:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <type_command@plt>
L13:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: Gnu emu need arguments

assistant: ```c
void check_args(int argc, char **argv) {
  if (argc < 2) {
    console_header();
    message_error("Gnu emu need arguments");
    exit(1);
  } else {
    type_command(argc, argv);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_args>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L8
  call   <type_command@plt>
L2:
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <console_header@plt>
  lea    D0(%rip),%rdi
  call   <message_error@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: Gnu emu need arguments

assistant: ```c
void check_args(int argc, char **argv) {
  if (argc < 2) {
    console_header();
    message_error("Gnu emu need arguments");
    exit(1);
  } else {
    type_command(argc, argv);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<check_args>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  jmp    1090 <type_command@plt>
  xchg   %ax,%ax
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <console_header@plt>
  lea    D7(%rip),%rdi
  call   <message_error@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: Gnu emu need arguments

assistant: ```c
void check_args(int argc, char **argv) {
  if (argc < 2) {
    console_header();
    message_error("Gnu emu need arguments");
    exit(1);
  } else {
    type_command(argc, argv);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_args>:
  endbr64
  cmp    $0x1,%edi
  jle    L0
  jmp    1090 <type_command@plt>
  xchg   %ax,%ax
L0:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <console_header@plt>
  lea    D3(%rip),%rdi
  call   <message_error@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    10b0 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_guessed: string

tool: D3: Gnu emu need arguments

assistant: ```c
void check_args(int argc, char **argv) {
  if (argc < 2) {
    console_header();
    message_error("Gnu emu need arguments");
    exit(1);
  } else {
    type_command(argc, argv);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L8:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    $0xe00,%eax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <interrupt@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void printString(char *str) {
  unsigned int i = 0;
  while (str[i] != '\0') {
    interrupt(0x10, 0xe * 256 + str[i], 0, 0, 0);
    i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printString>:
  endbr64
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L7
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
L13:
  movsbl %sil,%esi
  add    $0xe00,%esi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x10,%edi
  call   <interrupt@plt>
  add    $0x1,%ebx
  mov    %ebx,%eax
  movzbl 0x0(%rbp,%rax,1),%esi
  test   %sil,%sil
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  ret
```

assistant: ```c
void printString(char *str) {
  unsigned int i = 0;
  while (str[i] != '\0') {
    interrupt(0x10, 0xe * 256 + str[i], 0, 0, 0);
    i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printString>:
  endbr64
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0xe00,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x10,%edi
  call   <interrupt@plt>
  lea    0x1(%rbx),%eax
  movsbl 0x0(%rbp,%rax,1),%esi
  mov    %rax,%rbx
  test   %sil,%sil
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L3:
  ret
```

assistant: ```c
void printString(char *str) {
  unsigned int i = 0;
  while (str[i] != '\0') {
    interrupt(0x10, 0xe * 256 + str[i], 0, 0, 0);
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printString>:
  endbr64
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L15
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0xe00,%esi
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    $0x10,%edi
  call   <interrupt@plt>
  lea    0x1(%rbx),%eax
  movsbl 0x0(%rbp,%rax,1),%esi
  mov    %rax,%rbx
  test   %sil,%sil
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L15:
  ret
```

assistant: ```c
void printString(char *str) {
  unsigned int i = 0;
  while (str[i] != '\0') {
    interrupt(0x10, 0xe * 256 + str[i], 0, 0, 0);
    i++;
  }
}
```