user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  cmp    $0x2,%edi
  jle    L100
  mov    0x8(%rsp),%rax
  lea    D37(%rip),%r13
  mov    $0x1,%ebp
  mov    0x10(%rax),%rdi
  call   <atoi@plt>
  mov    %r13,%rdi
  mov    %eax,0x10(%rsp)
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  test   %ebx,%ebx
  jle    L30
  xor    %eax,%eax
  nopl   0x0(%rax)
L66:
  add    $0x1,%eax
  add    %rbp,%rbp
  cmp    %eax,%edx
  jne    L66
L30:
  mov    %r13,%rdi
  mov    %rbp,%rsi
  xor    %eax,%eax
  xor    %r15d,%r15d
  call   <printf@plt>
  lea    0x0(,%rbp,8),%edi
  call   <malloc@plt>
  movslq 0x10(%rsp),%rbx
  mov    %rax,%r13
  mov    %rax,%r12
  mov    %rbx,0x18(%rsp)
  lea    0x0(,%rbx,4),%r14d
  mov    %rax,%rbx
  nopl   0x0(%rax)
L24:
  mov    %r14d,%edi
  add    $0x1,%r15
  add    $0x8,%r12
  call   <malloc@plt>
  mov    %rax,-0x8(%r12)
  cmp    %rbp,%r15
  jne    L24
  mov    0x10(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  js     L93
  mov    0x18(%rsp),%r15
  movslq %eax,%r9
  mov    %eax,%eax
  mov    $0x1,%r8d
  shl    $0x2,%r9
  mov    %ebp,%r11d
  mov    $0x1,%r10d
  sub    %rax,%r15
  lea    -0x8(,%r15,4),%r14
  nop
L106:
  mov    %r13,%rdi
  xor    %esi,%esi
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L43:
  mov    (%rdi),%rax
  add    $0x1,%ecx
  mov    %esi,(%rax,%r9,1)
  mov    %ecx,%eax
  cltd
  idiv   %r8d
  mov    %r10d,%eax
  sub    %esi,%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x8,%rdi
  cmp    %r11d,%ecx
  jne    L43
  sub    $0x4,%r9
  add    %r8d,%r8d
  cmp    %r9,%r14
  jne    L106
L93:
  mov    0x8(%rsp),%rax
  lea    D6(%rip),%rsi
  xor    %r15d,%r15d
  lea    D13(%rip),%r13
  mov    0x8(%rax),%rdi
  call   <fopen@plt>
  mov    %rbp,0x8(%rsp)
  mov    %rax,%r12
  mov    0x14(%rsp),%eax
  lea    0x4(,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L79:
  mov    0x10(%rsp),%eax
  xor    %ebp,%ebp
  test   %eax,%eax
  jle    L84
  nopw   0x0(%rax,%rax,1)
L85:
  mov    (%rbx),%rax
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    (%rax,%rbp,1),%edx
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <fprintf@plt>
  cmp    %r14,%rbp
  jne    L85
L84:
  mov    %r12,%rsi
  mov    $0xa,%edi
  add    $0x1,%r15
  add    $0x8,%rbx
  call   <fputc@plt>
  cmp    %r15,0x8(%rsp)
  jne    L79
  mov    %r12,%rdi
  call   <fclose@plt>
L50:
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L100:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  jmp    L50
```

tool_calls: name: read_data
arguments: tag: D37
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D16
type: string

tool: D37: %d


tool: D6: w

tool: D13: %d

tool: D16: usage : ./main -file -NumberOfInputs

assistant: ```c
int main(int argc, char **argv) {
  if (argc < 3) {
    printf("usage : ./main -file -NumberOfInputs\n");
    return 0;
  }
  int i, j, N;
  long int count = 1;
  int step = 1;
  int flag = 0;
  N = atoi(argv[2]);
  printf("%d\n", N);
  for (i = 0; i < N; i++) {
    count *= 2;
  }
  printf("%d\n", count);
  int **A;
  A = (int **)malloc(count * sizeof(int *));
  for (i = 0; i < count; i++)
    A[i] = (int *)malloc(N * sizeof(int));
  for (j = N - 1; j >= 0; j--) {
    for (i = 0; i < count; i++) {
      A[i][j] = flag;
      if ((i + 1) % step == 0) {
        if (flag == 0)
          flag = 1;
        else if (flag == 1)
          flag = 0;
      }
    }
    step *= 2;
    flag = 0;
  }
  FILE *fp = NULL;
  fp = fopen(argv[1], "w");
  for (i = 0; i < count; i++) {
    for (j = 0; j < N; j++) {
      fprintf(fp, "%d", A[i][j]);
    }
    fprintf(fp, "\n");
  }
  fclose(fp);
  return 0;
}
```