ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  mov    %r15,%rdi
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r12
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L10
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  cmp    %ebx,%ebp
  jne    L37
  add    0x4(%rsp),%r13d
L37:
  mov    (%rsp),%eax
  lea    (%rbx,%rbp,1),%edx
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jne    L13
  add    0x4(%rsp),%r14d
L13:
  add    $0x1,%ebx
  cmp    %ebx,%eax
  jg     L7
  add    $0x1,%ebp
  cmp    %ebp,%eax
  jg     L41
L10:
  sub    %r14d,%r13d
  mov    %r15,%rdi
  mov    %r13d,%esi
  neg    %esi
  cmovs  %r13d,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type_infered: string

tool: D0: %d

assistant: ```c
int main() {
  int n, i, j, a = 0, b = 0;
  scanf("%d", &n);
  int temp[n];
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      int temp;
      scanf("%d", &temp);
      if (i == j)
        a += temp;
      if (i + j == n - 1)
        b += temp;
    }
  }
  printf("%d", abs(a - b));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<sdb_print_devices>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <pp_printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <pp_printf@plt>
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <pp_printf@plt>
  mov    $0x30000000,%esi
  mov    $0x0,%edi
  call   <print_devices_deep@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D8
type: string
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D18: -------------------------------------------


tool: D8: |            SDB memory map               |


tool: D15: -------------------------------------------



assistant: ```c
void sdb_print_devices(void) {
  pp_printf("-------------------------------------------\n");
  pp_printf("|            SDB memory map               |\n");
  pp_printf("-------------------------------------------\n\n");
  print_devices_deep(0, 0x30000000);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sdb_print_devices>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <pp_printf@plt>
  lea    D29(%rip),%rdi
  call   <pp_printf@plt>
  lea    D0(%rip),%rdi
  call   <pp_printf@plt>
  mov    $0x30000000,%esi
  mov    $0x0,%edi
  call   <print_devices_deep@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D26
data_type: string
name: parse_data
arguments: tag: D29
data_type: string
name: parse_data
arguments: tag: D0
data_type: string

tool: D26: -------------------------------------------


tool: D29: |            SDB memory map               |


tool: D0: -------------------------------------------



assistant: ```c
void sdb_print_devices(void) {
  pp_printf("-------------------------------------------\n");
  pp_printf("|            SDB memory map               |\n");
  pp_printf("-------------------------------------------\n\n");
  print_devices_deep(0, 0x30000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sdb_print_devices>:
  endbr64
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  call   <pp_printf@plt>
  lea    D12(%rip),%rdi
  call   <pp_printf@plt>
  lea    D26(%rip),%rdi
  call   <pp_printf@plt>
  mov    $0x30000000,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <print_devices_deep@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string

tool: D10: -------------------------------------------


tool: D12: |            SDB memory map               |


tool: D26: -------------------------------------------



assistant: ```c
void sdb_print_devices(void) {
  pp_printf("-------------------------------------------\n");
  pp_printf("|            SDB memory map               |\n");
  pp_printf("-------------------------------------------\n\n");
  print_devices_deep(0, 0x30000000);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sdb_print_devices>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <pp_printf@plt>
  lea    D5(%rip),%rdi
  call   <pp_printf@plt>
  lea    D4(%rip),%rdi
  call   <pp_printf@plt>
  mov    $0x30000000,%esi
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <print_devices_deep@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D11: -------------------------------------------


tool: D5: |            SDB memory map               |


tool: D4: -------------------------------------------



assistant: ```c
void sdb_print_devices(void) {
  pp_printf("-------------------------------------------\n");
  pp_printf("|            SDB memory map               |\n");
  pp_printf("-------------------------------------------\n\n");
  print_devices_deep(0, 0x30000000);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<izborFilma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L26:
  mov    $0x0,%eax
  call   <clearScreen@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L26
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  jle    L18
  jmp    L26
L18:
  nop
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D14
data_type: string
name: parse_data
arguments: label: D45
data_type: string
name: parse_data
arguments: label: D21
data_type: string
name: parse_data
arguments: label: D27
data_type: string
name: parse_data
arguments: label: D33
data_type: string
name: parse_data
arguments: label: D0
data_type: string

tool: D14: 1) Odabir filma po imenu


tool: D45: 2) Odabir filma zanru


tool: D21: 3) Odabir filma po popularnosti


tool: D27: 0) Prekinite biranje


tool: D33: Unesite vas izbor: 

tool: D0: %i

assistant: ```c
int izborFilma() {
  int o;
  while (1) {
    clearScreen();
    printf("\b1) Odabir filma po imenu\n");
    printf("\b2) Odabir filma zanru\n");
    printf("\b3) Odabir filma po popularnosti\n");
    printf("\b0) Prekinite biranje\n");
    printf("Unesite vas izbor: ");
    scanf("%i", &o);
    if (o > 0 && o < 4)
      break;
  }
  return o;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<izborFilma>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%r13
  lea    D31(%rip),%r12
  lea    D32(%rip),%rbp
  lea    D12(%rip),%rbx
L15:
  mov    $0x0,%eax
  call   <clearScreen@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  ja     L15
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D5
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string
name: extract_symbolic_data
arguments: label: D32
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string
name: extract_symbolic_data
arguments: label: D21
data_type: string
name: extract_symbolic_data
arguments: label: D43
data_type: string

tool: D5: 1) Odabir filma po imenu


tool: D31: 2) Odabir filma zanru


tool: D32: 3) Odabir filma po popularnosti


tool: D12: 0) Prekinite biranje


tool: D21: Unesite vas izbor: 

tool: D43: %i

assistant: ```c
int izborFilma() {
  int o;
  while (1) {
    clearScreen();
    printf("\b1) Odabir filma po imenu\n");
    printf("\b2) Odabir filma zanru\n");
    printf("\b3) Odabir filma po popularnosti\n");
    printf("\b0) Prekinite biranje\n");
    printf("Unesite vas izbor: ");
    scanf("%i", &o);
    if (o > 0 && o < 4)
      break;
  }
  return o;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<izborFilma>:
  endbr64
  push   %r15
  lea    D35(%rip),%r15
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    D33(%rip),%r13
  push   %r12
  lea    D48(%rip),%r12
  push   %rbp
  lea    D58(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  call   <clearScreen@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  ja     L19
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D35
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D48
data_type: string
name: extract_symbolic_data
arguments: tag: D58
data_type: string
name: extract_symbolic_data
arguments: tag: D56
data_type: string

tool: D35: 1) Odabir filma po imenu


tool: D8: 2) Odabir filma zanru


tool: D33: 3) Odabir filma po popularnosti


tool: D48: 0) Prekinite biranje


tool: D58: Unesite vas izbor: 

tool: D56: %i

assistant: ```c
int izborFilma() {
  int o;
  while (1) {
    clearScreen();
    printf("\b1) Odabir filma po imenu\n");
    printf("\b2) Odabir filma zanru\n");
    printf("\b3) Odabir filma po popularnosti\n");
    printf("\b0) Prekinite biranje\n");
    printf("Unesite vas izbor: ");
    scanf("%i", &o);
    if (o > 0 && o < 4)
      break;
  }
  return o;
}
```
user: Translate the below assembly code into C programming language:

```asm
<izborFilma>:
  endbr64
  push   %r15
  lea    D28(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  lea    D53(%rip),%r12
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <clearScreen@plt>
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x2,%edx
  ja     L2
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D28
type_infered: string
name: disassemble_data
arguments: label: D21
type_infered: string
name: disassemble_data
arguments: label: D22
type_infered: string
name: disassemble_data
arguments: label: D53
type_infered: string
name: disassemble_data
arguments: label: D45
type_infered: string
name: disassemble_data
arguments: label: D12
type_infered: string

tool: D28: 1) Odabir filma po imenu


tool: D21: 2) Odabir filma zanru


tool: D22: 3) Odabir filma po popularnosti


tool: D53: 0) Prekinite biranje


tool: D45: Unesite vas izbor: 

tool: D12: %i

assistant: ```c
int izborFilma() {
  int o;
  while (1) {
    clearScreen();
    printf("\b1) Odabir filma po imenu\n");
    printf("\b2) Odabir filma zanru\n");
    printf("\b3) Odabir filma po popularnosti\n");
    printf("\b0) Prekinite biranje\n");
    printf("Unesite vas izbor: ");
    scanf("%i", &o);
    if (o > 0 && o < 4)
      break;
  }
  return o;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bpf_delete_elem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ptr_to_u64@plt>
  mov    %eax,-0xc(%rbp)
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    $0x4,%ecx
  mov    %eax,%edi
  call   <syscall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int bpf_delete_elem(int fd, void *key) {
  union bpf_attr attr = {
      .map_fd = fd,
      .key = ptr_to_u64(key),
  };
  return syscall(__NR_bpf, BPF_MAP_DELETE_ELEM, &attr, sizeof(attr));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bpf_delete_elem>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ptr_to_u64@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_delete_elem(int fd, void *key) {
  union bpf_attr attr = {
      .map_fd = fd,
      .key = ptr_to_u64(key),
  };
  return syscall(__NR_bpf, BPF_MAP_DELETE_ELEM, &attr, sizeof(attr));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bpf_delete_elem>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ptr_to_u64@plt>
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  mov    %eax,0x4(%rsp)
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_delete_elem(int fd, void *key) {
  union bpf_attr attr = {
      .map_fd = fd,
      .key = ptr_to_u64(key),
  };
  return syscall(__NR_bpf, BPF_MAP_DELETE_ELEM, &attr, sizeof(attr));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bpf_delete_elem>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ptr_to_u64@plt>
  lea    0x4(%rsp),%rdx
  mov    $0x4,%ecx
  mov    %eax,0x4(%rsp)
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  mov    (%rax),%edi
  call   <syscall@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bpf_delete_elem(int fd, void *key) {
  union bpf_attr attr = {
      .map_fd = fd,
      .key = ptr_to_u64(key),
  };
  return syscall(__NR_bpf, BPF_MAP_DELETE_ELEM, &attr, sizeof(attr));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<imdct_step3_inner_s_loop_ld654>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  sar    $0x3,%r8d
  movslq %r8d,%r8
  movss  (%rcx,%r8,4),%xmm7
  movss  %xmm7,0xc(%rsp)
  movslq %edx,%rdx
  lea    (%rsi,%rdx,4),%rbx
  shl    $0x4,%edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  mov    %rbx,%rbp
  sub    %rdi,%rbp
  cmp    %rbp,%rbx
  jbe    L2
L9:
  movss  (%rbx),%xmm1
  movss  -0x20(%rbx),%xmm3
  movss  -0x4(%rbx),%xmm0
  movss  -0x24(%rbx),%xmm2
  movaps %xmm1,%xmm4
  addss  %xmm3,%xmm4
  movss  %xmm4,(%rbx)
  movaps %xmm0,%xmm4
  addss  %xmm2,%xmm4
  movss  %xmm4,-0x4(%rbx)
  subss  %xmm3,%xmm1
  movss  %xmm1,-0x20(%rbx)
  subss  %xmm2,%xmm0
  movss  %xmm0,-0x24(%rbx)
  movss  -0x8(%rbx),%xmm2
  movss  -0x28(%rbx),%xmm5
  movaps %xmm2,%xmm3
  subss  %xmm5,%xmm3
  movss  -0xc(%rbx),%xmm1
  movss  -0x2c(%rbx),%xmm4
  movaps %xmm1,%xmm0
  subss  %xmm4,%xmm0
  addss  %xmm5,%xmm2
  movss  %xmm2,-0x8(%rbx)
  addss  %xmm4,%xmm1
  movss  %xmm1,-0xc(%rbx)
  movaps %xmm3,%xmm1
  addss  %xmm0,%xmm1
  movss  0xc(%rsp),%xmm6
  mulss  %xmm6,%xmm1
  movss  %xmm1,-0x28(%rbx)
  subss  %xmm3,%xmm0
  mulss  %xmm6,%xmm0
  movss  %xmm0,-0x2c(%rbx)
  movss  -0x30(%rbx),%xmm0
  movss  -0x10(%rbx),%xmm2
  movss  -0x14(%rbx),%xmm1
  movss  -0x34(%rbx),%xmm3
  movaps %xmm0,%xmm4
  addss  %xmm2,%xmm4
  movss  %xmm4,-0x10(%rbx)
  movaps %xmm1,%xmm4
  addss  %xmm3,%xmm4
  movss  %xmm4,-0x14(%rbx)
  subss  %xmm3,%xmm1
  movss  %xmm1,-0x30(%rbx)
  subss  %xmm2,%xmm0
  movss  %xmm0,-0x34(%rbx)
  movss  -0x38(%rbx),%xmm2
  movss  -0x18(%rbx),%xmm5
  movaps %xmm2,%xmm0
  subss  %xmm5,%xmm0
  movss  -0x1c(%rbx),%xmm1
  movss  -0x3c(%rbx),%xmm4
  movaps %xmm1,%xmm3
  subss  %xmm4,%xmm3
  addss  %xmm5,%xmm2
  movss  %xmm2,-0x18(%rbx)
  addss  %xmm4,%xmm1
  movss  %xmm1,-0x1c(%rbx)
  movaps %xmm0,%xmm1
  addss  %xmm3,%xmm1
  mulss  %xmm6,%xmm1
  movss  %xmm1,-0x38(%rbx)
  subss  %xmm3,%xmm0
  mulss  %xmm6,%xmm0
  movss  %xmm0,-0x3c(%rbx)
  mov    %rbx,%rdi
  call   <iter_54@plt>
  lea    -0x20(%rbx),%rdi
  call   <iter_54@plt>
  sub    $0x40,%rbx
  cmp    %rbx,%rbp
  jb     L9
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void imdct_step3_inner_s_loop_ld654(int n, float *e, int i_off, float *A, int base_n) {
  int a_off = base_n >> 3;
  float A2 = A[0 + a_off];
  float *z = e + i_off;
  float *base = z - 16 * n;
  while (z > base) {
    float k00, k11;
    k00 = z[-0] - z[-8];
    k11 = z[-1] - z[-9];
    z[-0] = z[-0] + z[-8];
    z[-1] = z[-1] + z[-9];
    z[-8] = k00;
    z[-9] = k11;
    k00 = z[-2] - z[-10];
    k11 = z[-3] - z[-11];
    z[-2] = z[-2] + z[-10];
    z[-3] = z[-3] + z[-11];
    z[-10] = (k00 + k11) * A2;
    z[-11] = (k11 - k00) * A2;
    k00 = z[-12] - z[-4];
    k11 = z[-5] - z[-13];
    z[-4] = z[-4] + z[-12];
    z[-5] = z[-5] + z[-13];
    z[-12] = k11;
    z[-13] = k00;
    k00 = z[-14] - z[-6];
    k11 = z[-7] - z[-15];
    z[-6] = z[-6] + z[-14];
    z[-7] = z[-7] + z[-15];
    z[-14] = (k00 + k11) * A2;
    z[-15] = (k00 - k11) * A2;
    iter_54(z);
    iter_54(z - 8);
    z -= 16;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<imdct_step3_inner_s_loop_ld654>:
  endbr64
  shl    $0x4,%edi
  movslq %edx,%rdx
  push   %rbp
  sar    $0x3,%r8d
  push   %rbx
  movslq %edi,%rdi
  lea    (%rsi,%rdx,4),%rbx
  movslq %r8d,%r8
  shl    $0x2,%rdi
  mov    %rbx,%rbp
  sub    %rdi,%rbp
  sub    $0x18,%rsp
  movss  (%rcx,%r8,4),%xmm3
  cmp    %rbp,%rbx
  jbe    L8
  nopw   0x0(%rax,%rax,1)
L16:
  movss  (%rbx),%xmm1
  movss  -0x20(%rbx),%xmm4
  mov    %rbx,%rdi
  movss  %xmm3,0xc(%rsp)
  movss  -0x4(%rbx),%xmm0
  movss  -0x24(%rbx),%xmm2
  movaps %xmm1,%xmm5
  subss  %xmm4,%xmm1
  movss  -0x28(%rbx),%xmm6
  addss  %xmm4,%xmm5
  movss  %xmm1,-0x20(%rbx)
  movss  -0xc(%rbx),%xmm1
  movss  %xmm5,(%rbx)
  movaps %xmm0,%xmm5
  subss  %xmm2,%xmm0
  addss  %xmm2,%xmm5
  movss  -0x8(%rbx),%xmm2
  movaps %xmm2,%xmm4
  movss  %xmm0,-0x24(%rbx)
  movaps %xmm1,%xmm0
  addss  %xmm6,%xmm2
  movss  %xmm5,-0x4(%rbx)
  movss  -0x2c(%rbx),%xmm5
  subss  %xmm6,%xmm4
  movss  -0x18(%rbx),%xmm6
  addss  %xmm5,%xmm1
  subss  %xmm5,%xmm0
  movss  %xmm2,-0x8(%rbx)
  movss  -0x10(%rbx),%xmm2
  movss  %xmm1,-0xc(%rbx)
  movaps %xmm4,%xmm1
  addss  %xmm0,%xmm1
  subss  %xmm4,%xmm0
  movss  -0x34(%rbx),%xmm4
  mulss  %xmm3,%xmm0
  mulss  %xmm3,%xmm1
  movss  %xmm0,-0x2c(%rbx)
  movss  -0x30(%rbx),%xmm0
  movss  %xmm1,-0x28(%rbx)
  movss  -0x14(%rbx),%xmm1
  movaps %xmm0,%xmm5
  subss  %xmm2,%xmm0
  addss  %xmm2,%xmm5
  movss  -0x38(%rbx),%xmm2
  movss  %xmm0,-0x34(%rbx)
  movaps %xmm2,%xmm0
  addss  %xmm6,%xmm2
  movss  %xmm5,-0x10(%rbx)
  movaps %xmm1,%xmm5
  subss  %xmm4,%xmm1
  subss  %xmm6,%xmm0
  addss  %xmm4,%xmm5
  movss  %xmm2,-0x18(%rbx)
  movss  %xmm1,-0x30(%rbx)
  movss  -0x1c(%rbx),%xmm1
  movss  %xmm5,-0x14(%rbx)
  movss  -0x3c(%rbx),%xmm5
  movaps %xmm1,%xmm4
  addss  %xmm5,%xmm1
  subss  %xmm5,%xmm4
  movss  %xmm1,-0x1c(%rbx)
  movaps %xmm0,%xmm1
  subss  %xmm4,%xmm0
  addss  %xmm4,%xmm1
  mulss  %xmm3,%xmm0
  mulss  %xmm3,%xmm1
  movss  %xmm1,-0x38(%rbx)
  movss  %xmm0,-0x3c(%rbx)
  call   <iter_54@plt>
  lea    -0x20(%rbx),%rdi
  sub    $0x40,%rbx
  call   <iter_54@plt>
  cmp    %rbx,%rbp
  movss  0xc(%rsp),%xmm3
  jb     L16
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void imdct_step3_inner_s_loop_ld654(int n, float *e, int i_off, float *A, int base_n) {
  int a_off = base_n >> 3;
  float A2 = A[0 + a_off];
  float *z = e + i_off;
  float *base = z - 16 * n;
  while (z > base) {
    float k00, k11;
    k00 = z[-0] - z[-8];
    k11 = z[-1] - z[-9];
    z[-0] = z[-0] + z[-8];
    z[-1] = z[-1] + z[-9];
    z[-8] = k00;
    z[-9] = k11;
    k00 = z[-2] - z[-10];
    k11 = z[-3] - z[-11];
    z[-2] = z[-2] + z[-10];
    z[-3] = z[-3] + z[-11];
    z[-10] = (k00 + k11) * A2;
    z[-11] = (k11 - k00) * A2;
    k00 = z[-12] - z[-4];
    k11 = z[-5] - z[-13];
    z[-4] = z[-4] + z[-12];
    z[-5] = z[-5] + z[-13];
    z[-12] = k11;
    z[-13] = k00;
    k00 = z[-14] - z[-6];
    k11 = z[-7] - z[-15];
    z[-6] = z[-6] + z[-14];
    z[-7] = z[-7] + z[-15];
    z[-14] = (k00 + k11) * A2;
    z[-15] = (k00 - k11) * A2;
    iter_54(z);
    iter_54(z - 8);
    z -= 16;
  }
}
```