ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<compat_wcsdup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <wcslen@plt>
  lea    0x1(%rax),%r12d
  movslq %r12d,%r12
  shl    $0x2,%r12
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
wchar_t *compat_wcsdup(const wchar_t *src) {
  size_t n = (wcslen(src) + 1) * sizeof(wchar_t);
  wchar_t *dest = malloc(n);
  memcpy(dest, src, n);
  return dest;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L57:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  jmp    L116
L56:
  mov    -0x28(%rbp),%rax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L57
  movl   $0x1010101,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L86
L52:
  addq   $0x4,-0x28(%rbp)
L86:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %edx,%eax
  and    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L52
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  je     L106
  mov    -0xc(%rbp),%eax
  and    $0xff00,%eax
  test   %eax,%eax
  je     L55
  mov    -0xc(%rbp),%eax
  and    $0xff0000,%eax
  test   %eax,%eax
  je     L44
  addq   $0x4,-0x28(%rbp)
  jmp    L111
L44:
  addq   $0x3,-0x28(%rbp)
  jmp    L111
L55:
  addq   $0x2,-0x28(%rbp)
  jmp    L111
L106:
  addq   $0x1,-0x28(%rbp)
L111:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
L116:
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *a) {
  const char *x = a + 1;
  int w;
  while ((int)a & 3) {
    if (*a++ == 0)
      return a - x;
  }
  {
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (w = *(int *)a, !(((w)-ones_word) & ~(w)&eights_word))
      a += 4;
  }
  if (w & 0xff) {
    if (w & 0xff00) {
      if (w & 0xff0000)
        a += 4;
      else
        a += 3;
    } else
      a += 2;
  } else
    a += 1;
  return a - x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
L4:
  test   $0x3,%dl
  je     L39
  lea    0x1(%rdx),%rax
  cmpb   $0x0,(%rdx)
  je     L44
  mov    %rax,%rdx
  jmp    L4
L44:
  mov    %rdx,%rax
  sub    %rdi,%rax
  ret
L39:
  mov    (%rdx),%ecx
  lea    -0x1010101(%rcx),%eax
  mov    %ecx,%esi
  not    %esi
  and    %esi,%eax
  test   $0x80808080,%eax
  jne    L63
L50:
  add    $0x4,%rdx
  mov    (%rdx),%ecx
  lea    -0x1010101(%rcx),%eax
  mov    %ecx,%esi
  not    %esi
  and    %esi,%eax
  test   $0x80808080,%eax
  je     L50
L63:
  lea    0x1(%rdx),%rax
  test   %cl,%cl
  je     L13
  lea    0x2(%rdx),%rax
  test   $0xff,%ch
  je     L13
  test   $0xff0000,%ecx
  setne  %al
  movzbl %al,%eax
  lea    0x3(%rax,%rdx,1),%rax
L13:
  add    $0x1,%rdi
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strlen(const char *a) {
  const char *x = a + 1;
  int w;
  while ((int)a & 3) {
    if (*a++ == 0)
      return a - x;
  }
  {
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (w = *(int *)a, !(((w)-ones_word) & ~(w)&eights_word))
      a += 4;
  }
  if (w & 0xff) {
    if (w & 0xff00) {
      if (w & 0xff0000)
        a += 4;
      else
        a += 3;
    } else
      a += 2;
  } else
    a += 1;
  return a - x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
  jmp    L49
  nopl   0x0(%rax)
L18:
  cmpb   $0x0,(%rdx)
  lea    0x1(%rdx),%rax
  je     L57
  mov    %rax,%rdx
L49:
  test   $0x3,%dl
  jne    L18
  mov    (%rdx),%ecx
  mov    %ecx,%eax
  lea    -0x1010101(%rcx),%esi
  not    %eax
  and    %esi,%eax
  test   $0x80808080,%eax
  jne    L65
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    0x4(%rdx),%ecx
  add    $0x4,%rdx
  mov    %ecx,%esi
  lea    -0x1010101(%rcx),%eax
  not    %esi
  and    %esi,%eax
  test   $0x80808080,%eax
  je     L19
L65:
  lea    0x1(%rdx),%rax
  test   %cl,%cl
  je     L23
  lea    0x2(%rdx),%rax
  test   $0xff,%ch
  je     L23
  xor    %eax,%eax
  and    $0xff0000,%ecx
  setne  %al
  lea    0x3(%rax,%rdx,1),%rax
L23:
  add    $0x1,%rdi
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    %rdx,%rax
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strlen(const char *a) {
  const char *x = a + 1;
  int w;
  while ((int)a & 3) {
    if (*a++ == 0)
      return a - x;
  }
  {
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (w = *(int *)a, !(((w)-ones_word) & ~(w)&eights_word))
      a += 4;
  }
  if (w & 0xff) {
    if (w & 0xff00) {
      if (w & 0xff0000)
        a += 4;
      else
        a += 3;
    } else
      a += 2;
  } else
    a += 1;
  return a - x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
  jmp    L68
  nopl   0x0(%rax)
L18:
  cmpb   $0x0,(%rdx)
  lea    0x1(%rdx),%rax
  je     L52
  mov    %rax,%rdx
L68:
  test   $0x3,%dl
  jne    L18
  mov    (%rdx),%ecx
  mov    %ecx,%eax
  lea    -0x1010101(%rcx),%esi
  not    %eax
  and    %esi,%eax
  test   $0x80808080,%eax
  jne    L5
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    0x4(%rdx),%ecx
  add    $0x4,%rdx
  mov    %ecx,%esi
  lea    -0x1010101(%rcx),%eax
  not    %esi
  and    %esi,%eax
  test   $0x80808080,%eax
  je     L48
L5:
  lea    0x1(%rdx),%rax
  test   %cl,%cl
  je     L21
  lea    0x2(%rdx),%rax
  test   $0xff,%ch
  je     L21
  xor    %eax,%eax
  and    $0xff0000,%ecx
  setne  %al
  lea    0x3(%rax,%rdx,1),%rax
L21:
  add    $0x1,%rdi
  sub    %rdi,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %rdx,%rax
  sub    %rdi,%rax
  ret
```

assistant: ```c
size_t strlen(const char *a) {
  const char *x = a + 1;
  int w;
  while ((int)a & 3) {
    if (*a++ == 0)
      return a - x;
  }
  {
    int ones_word = 0x01010101;
    int eights_word = ones_word << 7;
    while (w = *(int *)a, !(((w)-ones_word) & ~(w)&eights_word))
      a += 4;
  }
  if (w & 0xff) {
    if (w & 0xff00) {
      if (w & 0xff0000)
        a += 4;
      else
        a += 3;
    } else
      a += 2;
  } else
    a += 1;
  return a - x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<loop_pcg32_linear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <ranged_random_pcg32_boundedrand@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movslq %edx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L2
  nop
  nop
  leave
  ret
```

assistant: ```c
void loop_pcg32_linear(size_t count, uint32_t range, uint32_t *output) {
  for (size_t i = 0; i < count; i++) {
    *output++ = ranged_random_pcg32_boundedrand(range + i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<loop_pcg32_linear>:
  endbr64
  test   %rdi,%rdi
  je     L10
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    (%rsi,%rdi,1),%rbp
  neg    %rsi
  lea    (%rdx,%rsi,8),%r12
L17:
  mov    %rbx,%rdi
  call   <ranged_random_pcg32_boundedrand@plt>
  cltq
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  ret
```

assistant: ```c
void loop_pcg32_linear(size_t count, uint32_t range, uint32_t *output) {
  for (size_t i = 0; i < count; i++) {
    *output++ = ranged_random_pcg32_boundedrand(range + i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<loop_pcg32_linear>:
  endbr64
  test   %rdi,%rdi
  je     L5
  mov    %rsi,%rax
  push   %r12
  neg    %rax
  push   %rbp
  lea    (%rsi,%rdi,1),%rbp
  push   %rbx
  lea    (%rdx,%rax,8),%r12
  mov    %rsi,%rbx
  xchg   %ax,%ax
L0:
  mov    %rbx,%rdi
  call   <ranged_random_pcg32_boundedrand@plt>
  cltq
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void loop_pcg32_linear(size_t count, uint32_t range, uint32_t *output) {
  for (size_t i = 0; i < count; i++) {
    *output++ = ranged_random_pcg32_boundedrand(range + i);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<loop_pcg32_linear>:
  endbr64
  test   %rdi,%rdi
  je     L18
  mov    %rsi,%rax
  push   %r12
  neg    %rax
  push   %rbp
  lea    (%rsi,%rdi,1),%rbp
  push   %rbx
  lea    (%rdx,%rax,8),%r12
  mov    %rsi,%rbx
  xchg   %ax,%ax
L8:
  mov    %rbx,%rdi
  call   <ranged_random_pcg32_boundedrand@plt>
  cltq
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L18:
  ret
```

assistant: ```c
void loop_pcg32_linear(size_t count, uint32_t range, uint32_t *output) {
  for (size_t i = 0; i < count; i++) {
    *output++ = ranged_random_pcg32_boundedrand(range + i);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0xe0(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xe0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xe0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: [INFO] 

assistant: ```c
void info(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list args;
  printf("[INFO] ");
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<info>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rcx,%rbx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string

tool: D1: [INFO] 

assistant: ```c
void info(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list args;
  printf("[INFO] ");
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<info>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: [INFO] 

assistant: ```c
void info(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list args;
  printf("[INFO] ");
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<info>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: [INFO] 

assistant: ```c
void info(const char *file, int line, const char *func, const char *fmt, ...) {
  va_list args;
  printf("[INFO] ");
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_normalize_block_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_block_size_by_payload@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <round_up_2power@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long _normalize_block_size(long payload_size) {
  long blk_size = _block_size_by_payload(payload_size);
  blk_size = round_up_2power(blk_size);
  return blk_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_normalize_block_size>:
  endbr64
  sub    $0x8,%rsp
  call   <_block_size_by_payload@plt>
  mov    %rax,%rdi
  call   <round_up_2power@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
long _normalize_block_size(long payload_size) {
  long blk_size = _block_size_by_payload(payload_size);
  blk_size = round_up_2power(blk_size);
  return blk_size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_normalize_block_size>:
  endbr64
  sub    $0x8,%rsp
  call   <_block_size_by_payload@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <round_up_2power@plt>
```

assistant: ```c
long _normalize_block_size(long payload_size) {
  long blk_size = _block_size_by_payload(payload_size);
  blk_size = round_up_2power(blk_size);
  return blk_size;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_normalize_block_size>:
  endbr64
  sub    $0x8,%rsp
  call   <_block_size_by_payload@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1060 <round_up_2power@plt>
```

assistant: ```c
long _normalize_block_size(long payload_size) {
  long blk_size = _block_size_by_payload(payload_size);
  blk_size = round_up_2power(blk_size);
  return blk_size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dmedian_ordered>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  jmp    L8
L3:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D9(%rip),%xmm1
  divsd  %xmm1,%xmm0
L8:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: f64

tool: D9: 2

assistant: ```c
double dmedian_ordered(const double *v, int len) {
  int rank = len / 2;
  if (len & 1) {
    return v[rank];
  }
  return (v[rank - 1] + v[rank]) / 2.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dmedian_ordered>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  test   $0x1,%sil
  jne    L7
  cltq
  movsd  -0x8(%rdi,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  mulsd  D9(%rip),%xmm0
  ret
L7:
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double dmedian_ordered(const double *v, int len) {
  int rank = len / 2;
  if (len & 1) {
    return v[rank];
  }
  return (v[rank - 1] + v[rank]) / 2.0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dmedian_ordered>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  and    $0x1,%esi
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  lea    0x0(,%rax,8),%rdx
  jne    L6
  addsd  -0x8(%rdi,%rdx,1),%xmm0
  mulsd  D5(%rip),%xmm0
L6:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double dmedian_ordered(const double *v, int len) {
  int rank = len / 2;
  if (len & 1) {
    return v[rank];
  }
  return (v[rank - 1] + v[rank]) / 2.0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dmedian_ordered>:
  endbr64
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  and    $0x1,%esi
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  lea    0x0(,%rax,8),%rdx
  jne    L2
  addsd  -0x8(%rdi,%rdx,1),%xmm0
  mulsd  D9(%rip),%xmm0
L2:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double dmedian_ordered(const double *v, int len) {
  int rank = len / 2;
  if (len & 1) {
    return v[rank];
  }
  return (v[rank - 1] + v[rank]) / 2.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  movl   $0x2,-0x8(%rbp)
  movl   $0x3,-0x4(%rbp)
  mov    -0x8(%rbp),%r8d
  mov    -0xc(%rbp),%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  sub    $0x8,%rsp
  mov    -0x4(%rbp),%esi
  push   %rsi
  mov    %r8d,%r9d
  mov    %edi,%r8d
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D4
type_guessed: string

tool: D4: %d
	%d  %d
    %d   %d	%d


assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = 3;
  printf("%d\n\t%d  %d\n    %d   %d\t\b%d\n", a, b, c, a, b, c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  push   $0x3
  mov    $0x2,%r9d
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
data_type: string

tool: D3: %d
	%d  %d
    %d   %d	%d


assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = 3;
  printf("%d\n\t%d  %d\n    %d   %d\t\b%d\n", a, b, c, a, b, c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x2,%r9d
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  push   $0x3
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d
	%d  %d
    %d   %d	%d


assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = 3;
  printf("%d\n\t%d  %d\n    %d   %d\t\b%d\n", a, b, c, a, b, c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x2,%r9d
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  push   $0x3
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d
	%d  %d
    %d   %d	%d


assistant: ```c
int main() {
  int a, b, c;
  a = 1;
  b = 2;
  c = 3;
  printf("%d\n\t%d  %d\n    %d   %d\t\b%d\n", a, b, c, a, b, c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_product_symbology>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  jne    L5
  movl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_product_symbology(char *buf) {
  int result = 0;
  if (((unsigned char)*(buf + 2) * 0x100 + (unsigned char)*((buf + 2) + 1)) == 1)
    result = 1;
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_product_symbology>:
  endbr64
  movzbl 0x2(%rdi),%eax
  shl    $0x8,%eax
  movzbl 0x3(%rdi),%edx
  add    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_product_symbology(char *buf) {
  int result = 0;
  if (((unsigned char)*(buf + 2) * 0x100 + (unsigned char)*((buf + 2) + 1)) == 1)
    result = 1;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_product_symbology>:
  endbr64
  movzbl 0x2(%rdi),%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_product_symbology(char *buf) {
  int result = 0;
  if (((unsigned char)*(buf + 2) * 0x100 + (unsigned char)*((buf + 2) + 1)) == 1)
    result = 1;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_product_symbology>:
  endbr64
  movzbl 0x2(%rdi),%eax
  movzbl 0x3(%rdi),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_product_symbology(char *buf) {
  int result = 0;
  if (((unsigned char)*(buf + 2) * 0x100 + (unsigned char)*((buf + 2) + 1)) == 1)
    result = 1;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dec_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L13
L9:
  mov    -0x18(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <hex_val@plt>
  mov    %al,(%rbx)
  mov    -0x18(%rbp),%eax
  lea    0xf(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x4,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L13:
  cmpl   $0x0,-0x18(%rbp)
  jne    L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int dec_to_hex(int n, char hex[]) {
  int helper, i;
  helper = n;
  for (i = 0; helper; i++) {
    hex[i] = hex_val(helper % 16);
    helper = helper / 16;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dec_to_hex>:
  endbr64
  test   %edi,%edi
  je     L1
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
L2:
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x1c,%eax
  lea    (%rbx,%rax,1),%edi
  and    $0xf,%edi
  sub    %eax,%edi
  call   <hex_val@plt>
  mov    %al,0x0(%rbp)
  lea    0xf(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x4,%eax
  mov    %eax,%ebx
  add    $0x1,%rbp
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int dec_to_hex(int n, char hex[]) {
  int helper, i;
  helper = n;
  for (i = 0; helper; i++) {
    hex[i] = hex_val(helper % 16);
    helper = helper / 16;
  }
  return 0;
}
```