ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_if_addr>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  mov    $0x12,%esi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12,%rdi
  sub    $0x8,%rsp
  call   <bzero@plt>
  mov    D10(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <get_ifreq@plt>
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *get_if_addr(char *ifname) {
  static char buf[18];
  bzero(buf, sizeof(buf));
  struct ifreq *ifr = get_ifreq(ifname, SIOCGIFADDR);
  strcpy(buf, inet_ntoa(((struct sockaddr_in *)&ifr->ifr_addr)->sin_addr));
  return buf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L6:
  movl   $0x1,-0xc(%rbp)
  jmp    L54
L23:
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L53
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L12
L53:
  mov    $0x2a,%edi
  call   <putchar@plt>
L12:
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L23
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L6
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D8: %d

tool: D17: 


assistant: ```c
int main(void) {
  int n, row, col;
  scanf("%d", &n);
  for (row = 0; row < n; row++) {
    for (col = 1; col < n + row - 1; col++) {
      if (col < n - row)
        putchar(' ');
      else
        putchar('*');
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  lea    D16(%rip),%r12
  cmpl   $0x0,0x4(%rsp)
  jg     L79
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    $0x2a,%edi
  call   <putchar@plt>
L46:
  add    $0x1,%ebx
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rbp,1),%edx
  cmp    %ebx,%edx
  jle    L68
L25:
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jle    L19
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L46
L68:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    %ebp,0x4(%rsp)
  jle    L64
L79:
  mov    0x4(%rsp),%eax
  lea    (%rax,%rbp,1),%edx
  mov    $0x1,%ebx
  cmp    $0x2,%edx
  jg     L25
  jmp    L68
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string

tool: D2: %d

tool: D16: 


assistant: ```c
int main(void) {
  int n, row, col;
  scanf("%d", &n);
  for (row = 0; row < n; row++) {
    for (col = 1; col < n + row - 1; col++) {
      if (col < n - row)
        putchar(' ');
      else
        putchar('*');
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%rdi
  lea    D4(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L17
  xchg   %ax,%ax
L14:
  lea    (%rax,%rbp,1),%edx
  mov    $0x1,%ebx
  cmp    $0x2,%edx
  jg     L33
  jmp    L49
  nop
L57:
  mov    $0x20,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rbp,1),%edx
  cmp    %ebx,%edx
  jle    L49
L33:
  sub    %ebp,%eax
  cmp    %ebx,%eax
  jg     L57
  mov    $0x2a,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rbp,1),%edx
  cmp    %ebx,%edx
  jg     L33
L49:
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jg     L14
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string

tool: D12: %d

tool: D4: 


assistant: ```c
int main(void) {
  int n, row, col;
  scanf("%d", &n);
  for (row = 0; row < n; row++) {
    for (col = 1; col < n + row - 1; col++) {
      if (col < n - row)
        putchar(' ');
      else
        putchar('*');
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D15(%rip),%rdi
  lea    D17(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  xchg   %ax,%ax
L51:
  lea    (%rax,%rbp,1),%edx
  mov    $0x1,%ebx
  cmp    $0x2,%edx
  jle    L1
  nopl   (%rax)
L6:
  sub    %ebp,%eax
  mov    $0x20,%edi
  cmp    %ebx,%eax
  jg     L16
  mov    $0x2a,%edi
L16:
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%ebx
  lea    -0x1(%rax,%rbp,1),%edx
  cmp    %ebx,%edx
  jg     L6
L1:
  mov    %r12,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jg     L51
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string

tool: D15: %d

tool: D17: 


assistant: ```c
int main(void) {
  int n, row, col;
  scanf("%d", &n);
  for (row = 0; row < n; row++) {
    for (col = 1; col < n + row - 1; col++) {
      if (col < n - row)
        putchar(' ');
      else
        putchar('*');
    }
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<squarewave8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L24
  cmpl   $0xff,-0x8(%rbp)
  jne    L5
L24:
  mov    $0xff,%eax
  jmp    L28
L5:
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t squarewave8(uint8_t in, uint8_t pulsewidth) {
  if (in < pulsewidth || (pulsewidth == 255)) {
    return 255;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<squarewave8>:
  endbr64
  cmp    %esi,%edi
  jl     L1
  cmp    $0xff,%esi
  je     L1
  mov    $0x0,%eax
  ret
L1:
  mov    $0xff,%eax
  ret
```

assistant: ```c
uint8_t squarewave8(uint8_t in, uint8_t pulsewidth) {
  if (in < pulsewidth || (pulsewidth == 255)) {
    return 255;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squarewave8>:
  endbr64
  cmp    %esi,%edi
  jl     L15
  cmp    $0xff,%esi
  je     L15
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xff,%eax
  ret
```

assistant: ```c
uint8_t squarewave8(uint8_t in, uint8_t pulsewidth) {
  if (in < pulsewidth || (pulsewidth == 255)) {
    return 255;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squarewave8>:
  endbr64
  cmp    %esi,%edi
  jl     L3
  cmp    $0xff,%esi
  je     L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xff,%eax
  ret
```

assistant: ```c
uint8_t squarewave8(uint8_t in, uint8_t pulsewidth) {
  if (in < pulsewidth || (pulsewidth == 255)) {
    return 255;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L43:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L43
  cmpl   $0x5,-0x14(%rbp)
  ja     L11
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  addl   $0x1,-0x4(%rbp)
  jmp    L17
  addl   $0x2,-0x4(%rbp)
  jmp    L17
  addl   $0x3,-0x4(%rbp)
  jmp    L17
  addl   $0x4,-0x4(%rbp)
  jmp    L17
  addl   $0x4,-0x4(%rbp)
  jmp    L17
L11:
  nop
L17:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int y) {
  int i = 0, j = 0;
  for (i = 0; i < y; i++) {
    j++;
  }
  switch (y) {
  case 0:
    j += 1;
    break;
  case 1:
    j += 2;
    break;
  case 2:
    j += 3;
    break;
  case 4:
    j += 4;
    break;
  case 5:
    j += 4;
    break;
  default:
    break;
  }
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  test   %edi,%edi
  jle    L75
  mov    $0x0,%eax
L35:
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L35
  mov    %edi,%edx
L24:
  cmp    $0x5,%edi
  ja     L68
  mov    %edi,%edi
  lea    D3(%rip),%rcx
  movslq (%rcx,%rdi,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
L75:
  mov    $0x0,%edx
  jmp    L24
  add    $0x1,%edx
L68:
  mov    %edx,%eax
  ret
  add    $0x2,%edx
  jmp    L68
  add    $0x3,%edx
  jmp    L68
  add    $0x4,%edx
  jmp    L68
  add    $0x4,%edx
  jmp    L68
```

assistant: ```c
int f(int y) {
  int i = 0, j = 0;
  for (i = 0; i < y; i++) {
    j++;
  }
  switch (y) {
  case 0:
    j += 1;
    break;
  case 1:
    j += 2;
    break;
  case 2:
    j += 3;
    break;
  case 4:
    j += 4;
    break;
  case 5:
    j += 4;
    break;
  default:
    break;
  }
  return j;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  test   %edi,%edi
  jle    L57
  cmp    $0x2,%edi
  je     L12
  mov    %edi,%eax
L2:
  cmp    $0x2,%edi
  jle    L5
  sub    $0x4,%edi
  lea    0x4(%rax),%edx
  cmp    $0x2,%edi
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax)
L5:
  test   %edi,%edi
  je     L46
  cmp    $0x1,%edi
  jne    L15
  add    $0x2,%eax
  ret
  nopl   (%rax)
L12:
  mov    $0x5,%eax
  ret
  xchg   %ax,%ax
L46:
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L57:
  xor    %eax,%eax
  jmp    L2
L15:
  ret
```

assistant: ```c
int f(int y) {
  int i = 0, j = 0;
  for (i = 0; i < y; i++) {
    j++;
  }
  switch (y) {
  case 0:
    j += 1;
    break;
  case 1:
    j += 2;
    break;
  case 2:
    j += 3;
    break;
  case 4:
    j += 4;
    break;
  case 5:
    j += 4;
    break;
  default:
    break;
  }
  return j;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  test   %edi,%edi
  jle    L16
  cmp    $0x2,%edi
  je     L8
  mov    %edi,%eax
L32:
  cmp    $0x2,%edi
  jle    L3
  sub    $0x4,%edi
  lea    0x4(%rax),%edx
  cmp    $0x2,%edi
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax)
L3:
  test   %edi,%edi
  je     L10
  cmp    $0x1,%edi
  jne    L54
  add    $0x2,%eax
  ret
  nopl   (%rax)
L8:
  mov    $0x5,%eax
  ret
  xchg   %ax,%ax
L10:
  add    $0x1,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  jmp    L32
L54:
  ret
```

assistant: ```c
int f(int y) {
  int i = 0, j = 0;
  for (i = 0; i < y; i++) {
    j++;
  }
  switch (y) {
  case 0:
    j += 1;
    break;
  case 1:
    j += 2;
    break;
  case 2:
    j += 3;
    break;
  case 4:
    j += 4;
    break;
  case 5:
    j += 4;
    break;
  default:
    break;
  }
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L13
L16:
  mov    $0x0,%eax
  call   <random@plt>
  mov    $0x0,%edx
  divq   -0x30(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void shuffle(size_t *items, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    size_t j = random() % len;
    size_t t = items[i];
    items[i] = items[j];
    items[j] = t;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<shuffle>:
  endbr64
  test   %rsi,%rsi
  je     L17
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L15:
  mov    $0x0,%eax
  call   <random@plt>
  mov    (%r12,%rbx,8),%rcx
  mov    $0x0,%edx
  div    %rbp
  lea    (%r12,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%r12,%rbx,8)
  mov    %rcx,(%rax)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  ret
```

assistant: ```c
void shuffle(size_t *items, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    size_t j = random() % len;
    size_t t = items[i];
    items[i] = items[j];
    items[j] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shuffle>:
  endbr64
  test   %rsi,%rsi
  je     L6
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L9:
  xor    %eax,%eax
  call   <random@plt>
  xor    %edx,%edx
  mov    (%r12,%rbx,8),%rcx
  div    %rbp
  lea    (%r12,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%r12,%rbx,8)
  add    $0x1,%rbx
  mov    %rcx,(%rax)
  cmp    %rbx,%rbp
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
void shuffle(size_t *items, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    size_t j = random() % len;
    size_t t = items[i];
    items[i] = items[j];
    items[j] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shuffle>:
  endbr64
  test   %rsi,%rsi
  je     L8
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L12:
  xor    %eax,%eax
  call   <random@plt>
  xor    %edx,%edx
  mov    (%r12,%rbx,8),%rcx
  div    %rbp
  lea    (%r12,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%r12,%rbx,8)
  add    $0x1,%rbx
  mov    %rcx,(%rax)
  cmp    %rbx,%rbp
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L8:
  ret
```

assistant: ```c
void shuffle(size_t *items, size_t len) {
  size_t i;
  for (i = 0; i < len; i++) {
    size_t j = random() % len;
    size_t t = items[i];
    items[i] = items[j];
    items[j] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hfsplus_init_inode_security>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <hfsplus_init_acl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <hfsplus_init_security@plt>
  mov    %eax,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int hfsplus_init_inode_security(struct inode *inode, struct inode *dir, const struct qstr *qstr) {
  int err;
  err = hfsplus_init_acl(inode, dir);
  if (!err)
    err = hfsplus_init_security(inode, dir, qstr);
  return err;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hfsplus_init_inode_security>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <hfsplus_init_acl@plt>
  test   %eax,%eax
  je     L1
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <hfsplus_init_security@plt>
  jmp    L12
```

assistant: ```c
int hfsplus_init_inode_security(struct inode *inode, struct inode *dir, const struct qstr *qstr) {
  int err;
  err = hfsplus_init_acl(inode, dir);
  if (!err)
    err = hfsplus_init_security(inode, dir, qstr);
  return err;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hfsplus_init_inode_security>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <hfsplus_init_acl@plt>
  test   %eax,%eax
  je     L9
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L9:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <hfsplus_init_security@plt>
```

assistant: ```c
int hfsplus_init_inode_security(struct inode *inode, struct inode *dir, const struct qstr *qstr) {
  int err;
  err = hfsplus_init_acl(inode, dir);
  if (!err)
    err = hfsplus_init_security(inode, dir, qstr);
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hfsplus_init_inode_security>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <hfsplus_init_acl@plt>
  test   %eax,%eax
  je     L5
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <hfsplus_init_security@plt>
```

assistant: ```c
int hfsplus_init_inode_security(struct inode *inode, struct inode *dir, const struct qstr *qstr) {
  int err;
  err = hfsplus_init_acl(inode, dir);
  if (!err)
    err = hfsplus_init_security(inode, dir, qstr);
  return err;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<back_mouse_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void back_mouse_up(double x, double y) {
  (void)x;
  (void)y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<back_mouse_up>:
  endbr64
  ret
```

assistant: ```c
void back_mouse_up(double x, double y) {
  (void)x;
  (void)y;
}
```
user: What is the c source code of the assembly code below?

```asm
<back_mouse_up>:
  endbr64
  ret
```

assistant: ```c
void back_mouse_up(double x, double y) {
  (void)x;
  (void)y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<back_mouse_up>:
  endbr64
  ret
```

assistant: ```c
void back_mouse_up(double x, double y) {
  (void)x;
  (void)y;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_man>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L25
  mov    $0x0,%eax
  jmp    L11
L25:
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L5:
  mov    -0x18(%rbp),%eax
  add    $0x54,%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  movslq %ecx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <my_mvaddstr@plt>
  addl   $0x1,-0x4(%rbp)
L38:
  cmpl   $0x1,-0x4(%rbp)
  jle    L5
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int add_man(int y, int x) {
  static char *man[2][2] = {{"", "(O)"}, {"Help!", "\\O/"}};
  int i;
  if (x < 0) {
    return 0;
  }
  for (i = 0; i < 2; ++i) {
    my_mvaddstr(y + i, x, man[(84 + x) / 12 % 2][i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_man>:
  endbr64
  test   %esi,%esi
  js     L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  lea    0x54(%rsi),%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cltq
  shl    $0x4,%rax
  lea    D4(%rip),%r12
  add    %rax,%r12
  mov    (%r12),%rdx
  call   <my_mvaddstr@plt>
  lea    0x1(%rbp),%edi
  mov    0x8(%r12),%rdx
  mov    %ebx,%esi
  call   <my_mvaddstr@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int add_man(int y, int x) {
  static char *man[2][2] = {{"", "(O)"}, {"Help!", "\\O/"}};
  int i;
  if (x < 0) {
    return 0;
  }
  for (i = 0; i < 2; ++i) {
    my_mvaddstr(y + i, x, man[(84 + x) / 12 % 2][i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<add_man>:
  endbr64
  test   %esi,%esi
  js     L0
  lea    0x54(%rsi),%eax
  mov    $0xaaaaaaab,%edx
  push   %r12
  lea    D8(%rip),%r12
  imul   %rdx,%rax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  shr    $0x1f,%rax
  and    $0x10,%eax
  add    %rax,%r12
  mov    (%r12),%rdx
  call   <my_mvaddstr@plt>
  mov    0x8(%r12),%rdx
  lea    0x1(%rbx),%edi
  mov    %ebp,%esi
  call   <my_mvaddstr@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int add_man(int y, int x) {
  static char *man[2][2] = {{"", "(O)"}, {"Help!", "\\O/"}};
  int i;
  if (x < 0) {
    return 0;
  }
  for (i = 0; i < 2; ++i) {
    my_mvaddstr(y + i, x, man[(84 + x) / 12 % 2][i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<add_man>:
  endbr64
  test   %esi,%esi
  js     L3
  lea    0x54(%rsi),%eax
  mov    $0xaaaaaaab,%edx
  push   %r12
  lea    D2(%rip),%r12
  imul   %rdx,%rax
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  shr    $0x1f,%rax
  and    $0x10,%eax
  add    %rax,%r12
  mov    (%r12),%rdx
  call   <my_mvaddstr@plt>
  mov    0x8(%r12),%rdx
  lea    0x1(%rbx),%edi
  mov    %ebp,%esi
  call   <my_mvaddstr@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int add_man(int y, int x) {
  static char *man[2][2] = {{"", "(O)"}, {"Help!", "\\O/"}};
  int i;
  if (x < 0) {
    return 0;
  }
  for (i = 0; i < 2; ++i) {
    my_mvaddstr(y + i, x, man[(84 + x) / 12 % 2][i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<WAV_Done>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x46,%ecx
  mov    $0x49,%edx
  mov    $0x41,%esi
  mov    $0x52,%edi
  call   <FOURCC@plt>
  mov    %eax,%edi
  call   <NodeUnRegisterClass@plt>
  mov    $0x56,%ecx
  mov    $0x41,%edx
  mov    $0x57,%esi
  mov    $0x52,%edi
  call   <FOURCC@plt>
  mov    %eax,%edi
  call   <NodeUnRegisterClass@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WAV_Done() {
  NodeUnRegisterClass(FOURCC('R', 'A', 'I', 'F'));
  NodeUnRegisterClass(FOURCC('R', 'W', 'A', 'V'));
}
```