ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_105_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x1c(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x20(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_105_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rop3_105_0_0>:
  endbr64
  xor    %esi,%edx
  xor    (%rdi),%dl
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_105_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_105_0_0>:
  endbr64
  xor    %esi,%edx
  xor    (%rdi),%dl
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_105_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_105_0_0>:
  endbr64
  xor    %esi,%edx
  xor    (%rdi),%dl
  not    %edx
  mov    %dl,(%rdi)
  ret
```

assistant: ```c
void rop3_105_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D ^ S;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  *D = stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_combination>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L21
L24:
  movl   $0x0,-0x10(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L40
L20:
  mov    -0xc(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L15
  movl   $0x1,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,-0x8(%rbp)
L15:
  addl   $0x1,-0xc(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L20
  cmpl   $0x0,-0x10(%rbp)
  je     L44
  mov    $0xa,%edi
  call   <putchar@plt>
L44:
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x30(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L24
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: 

tool: D18: %s%d

tool: D7: , 

assistant: ```c
void list_combination(int a[], size_t n) {
  for (int i = 0; i < (1 << n); i++) {
    int printed = 0;
    char *sep = "";
    for (int j = 0; j < n; j++) {
      if ((i >> j) & 0x01) {
        printed = 1;
        printf("%s%d", sep, a[j]);
        sep = ", ";
      }
    }
    if (printed) {
      printf("\n");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<list_combination>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    $0x1,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  mov    %eax,0xc(%rsp)
  mov    $0x0,%r12d
  lea    D13(%rip),%r15
  test   %eax,%eax
  jg     L82
L79:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  add    $0x1,%rbx
  cmp    %rbx,%r13
  je     L77
L44:
  mov    %r12d,%ebp
  mov    %ebx,%ecx
  sar    %cl,%ebp
  and    $0x1,%ebp
  je     L5
  mov    (%r14,%rbx,4),%edx
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%eax
  mov    %r15,%rsi
  jmp    L5
L77:
  test   %eax,%eax
  jne    L8
L38:
  add    $0x1,%r12d
  cmp    0xc(%rsp),%r12d
  je     L79
L82:
  lea    D0(%rip),%rsi
  mov    $0x0,%eax
  mov    $0x0,%ebx
  test   %r13,%r13
  jne    L44
  jmp    L38
L8:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L38
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D13: , 

tool: D3: %s%d

tool: 

assistant: ```c
void list_combination(int a[], size_t n) {
  for (int i = 0; i < (1 << n); i++) {
    int printed = 0;
    char *sep = "";
    for (int j = 0; j < n; j++) {
      if ((i >> j) & 0x01) {
        printed = 1;
        printf("%s%d", sep, a[j]);
        sep = ", ";
      }
    }
    if (printed) {
      printf("\n");
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list_combination>:
  endbr64
  push   %r15
  mov    $0x1,%eax
  mov    %esi,%ecx
  push   %r14
  shl    %cl,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jle    L11
  mov    %rdi,%rbp
  mov    %rsi,%r14
  lea    D18(%rip),%r13
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L67:
  test   %r14,%r14
  je     L11
  lea    D26(%rip),%rsi
  xor    %edx,%edx
  xor    %ebx,%ebx
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L43:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L47
L64:
  mov    %r15d,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %eax,%r12d
  je     L43
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    %r12d,%edx
  lea    D27(%rip),%rsi
  cmp    %r14,%rbx
  jne    L64
L47:
  test   %edx,%edx
  je     L65
  mov    $0xa,%edi
  call   <putchar@plt>
L65:
  add    $0x1,%r15d
  cmp    0xc(%rsp),%r15d
  jne    L67
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D26
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: string

tool: D18: %s%d

tool: 

tool: D27: , 

assistant: ```c
void list_combination(int a[], size_t n) {
  for (int i = 0; i < (1 << n); i++) {
    int printed = 0;
    char *sep = "";
    for (int j = 0; j < n; j++) {
      if ((i >> j) & 0x01) {
        printed = 1;
        printf("%s%d", sep, a[j]);
        sep = ", ";
      }
    }
    if (printed) {
      printf("\n");
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_combination>:
  endbr64
  push   %r15
  mov    $0x1,%eax
  mov    %esi,%ecx
  push   %r14
  shl    %cl,%eax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jle    L68
  mov    %rdi,%rbp
  mov    %rsi,%r14
  lea    D29(%rip),%r13
  xor    %r15d,%r15d
  nopl   0x0(%rax,%rax,1)
L62:
  test   %r14,%r14
  je     L68
  lea    D21(%rip),%rsi
  xor    %edx,%edx
  xor    %ebx,%ebx
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L58:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L4
L36:
  mov    %r15d,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %eax,%r12d
  je     L58
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  mov    %r12d,%edx
  lea    D13(%rip),%rsi
  cmp    %r14,%rbx
  jne    L36
L4:
  test   %edx,%edx
  je     L7
  mov    $0xa,%edi
  call   <putchar@plt>
L7:
  add    $0x1,%r15d
  cmp    0xc(%rsp),%r15d
  jne    L62
L68:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D13
type: string

tool: D29: %s%d

tool: 

tool: D13: , 

assistant: ```c
void list_combination(int a[], size_t n) {
  for (int i = 0; i < (1 << n); i++) {
    int printed = 0;
    char *sep = "";
    for (int j = 0; j < n; j++) {
      if ((i >> j) & 0x01) {
        printed = 1;
        printf("%s%d", sep, a[j]);
        sep = ", ";
      }
    }
    if (printed) {
      printf("\n");
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D46(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x20(%rbp),%rax
  lea    D46(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string
name: unpack_data
arguments: data_tag: D46
type_infered: string

tool: D4: one

tool: D8: two

tool: D46: three

assistant: ```c
int main(int argc, char *argv[]) {
  char *s1 = "one";
  char *s2 = "two";
  char *s3 = "three";
  char *s[] = {s1, s2, s3};
  swap(s, 0, 2);
  assert(!strcmp(s[0], "three"));
  assert(!strcmp(s[2], "one"));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%rbx
  mov    %rbx,(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D20(%rip),%rbp
  mov    %rbp,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x2,%edx
  mov    $0x0,%esi
  call   <swap@plt>
  mov    %rbp,%rsi
  mov    (%rsp),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rsi
  mov    0x10(%rsp),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D19
type_guessed: string
name: parse_data
arguments: label: D20
type_guessed: string

tool: D24: one

tool: D19: two

tool: D20: three

assistant: ```c
int main(int argc, char *argv[]) {
  char *s1 = "one";
  char *s2 = "two";
  char *s3 = "three";
  char *s[] = {s1, s2, s3};
  swap(s, 0, 2);
  assert(!strcmp(s[0], "three"));
  assert(!strcmp(s[2], "one"));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  xor    %esi,%esi
  lea    D8(%rip),%r12
  push   %rbp
  lea    D29(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D5(%rip),%rax
  mov    %rbp,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %r12,0x10(%rsp)
  call   <swap@plt>
  mov    (%rsp),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string

tool: D8: three

tool: D29: one

tool: D5: two

assistant: ```c
int main(int argc, char *argv[]) {
  char *s1 = "one";
  char *s2 = "two";
  char *s3 = "three";
  char *s[] = {s1, s2, s3};
  swap(s, 0, 2);
  assert(!strcmp(s[0], "three"));
  assert(!strcmp(s[2], "one"));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x2,%edx
  xor    %esi,%esi
  lea    D27(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  movq   %rbp,%xmm0
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rsp,%rdi
  mov    %r12,0x10(%rsp)
  movq   %rax,%xmm1
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <swap@plt>
  mov    (%rsp),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string
name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D27: three

tool: D11: one

tool: D2: two

assistant: ```c
int main(int argc, char *argv[]) {
  char *s1 = "one";
  char *s2 = "two";
  char *s3 = "three";
  char *s[] = {s1, s2, s3};
  swap(s, 0, 2);
  assert(!strcmp(s[0], "three"));
  assert(!strcmp(s[2], "one"));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread_fourth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <foo@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  leave
  ret
```

assistant: ```c
void *thread_fourth(void *arg) {
  foo();
  return bar(arg);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<thread_fourth>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <foo@plt>
  mov    %rbx,%rdi
  call   <bar@plt>
  pop    %rbx
  ret
```

assistant: ```c
void *thread_fourth(void *arg) {
  foo();
  return bar(arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread_fourth>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <bar@plt>
```

assistant: ```c
void *thread_fourth(void *arg) {
  foo();
  return bar(arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread_fourth>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <foo@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <bar@plt>
```

assistant: ```c
void *thread_fourth(void *arg) {
  foo();
  return bar(arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<in4hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rcx
  lea    -0xd(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x9(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0xd(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: %x

assistant: ```c
int in4hex(char *ptr) {
  char str[5];
  int val;
  memcpy(str, ptr, 4);
  str[4] = '\0';
  sscanf(str, "%x", &val);
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<in4hex>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x13(%rsp),%rbx
  mov    $0x4,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x17(%rsp)
  lea    0xc(%rsp),%rdx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: %x

assistant: ```c
int in4hex(char *ptr) {
  char str[5];
  int val;
  memcpy(str, ptr, 4);
  str[4] = '\0';
  sscanf(str, "%x", &val);
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<in4hex>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x13(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  movb   $0x0,0x17(%rsp)
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: string

tool: D1: %x

assistant: ```c
int in4hex(char *ptr) {
  char str[5];
  int val;
  memcpy(str, ptr, 4);
  str[4] = '\0';
  sscanf(str, "%x", &val);
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<in4hex>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    $0x4,%edx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x13(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0xc(%rsp),%rdx
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  movb   $0x0,0x17(%rsp)
  call   <sscanf@plt>
  mov    0xc(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x20,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %x

assistant: ```c
int in4hex(char *ptr) {
  char str[5];
  int val;
  memcpy(str, ptr, 4);
  str[4] = '\0';
  sscanf(str, "%x", &val);
  return val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<recv_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  lea    -0xe(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    $0x5,%eax
  je     L0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L9
L0:
  lea    -0xe(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D4: Couldn't read 5 chars

tool: D9: Message from server: %s
	

assistant: ```c
void recv_message(int sockfd) {
  char message[6];
  message[5] = '\0';
  if (read(sockfd, message, 5) != 5) {
    perror("Couldn't read 5 chars");
  } else {
    printf("Message from server: %s\n	", message);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<recv_message>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  lea    0x2(%rsp),%rsi
  mov    $0x5,%edx
  call   <read@plt>
  cmp    $0x5,%eax
  je     L9
  lea    D10(%rip),%rdi
  call   <perror@plt>
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L9:
  lea    0x2(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D5
datatype: string

tool: D10: Couldn't read 5 chars

tool: D5: Message from server: %s
	

assistant: ```c
void recv_message(int sockfd) {
  char message[6];
  message[5] = '\0';
  if (read(sockfd, message, 5) != 5) {
    perror("Couldn't read 5 chars");
  } else {
    printf("Message from server: %s\n	", message);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recv_message>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  movb   $0x0,0x7(%rsp)
  mov    %rbp,%rsi
  call   <read@plt>
  cmp    $0x5,%eax
  je     L26
  lea    D12(%rip),%rdi
  call   <perror@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D12: Couldn't read 5 chars

tool: D0: Message from server: %s
	

assistant: ```c
void recv_message(int sockfd) {
  char message[6];
  message[5] = '\0';
  if (read(sockfd, message, 5) != 5) {
    perror("Couldn't read 5 chars");
  } else {
    printf("Message from server: %s\n	", message);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<recv_message>:
  endbr64
  push   %rbp
  mov    $0x5,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  movb   $0x0,0x7(%rsp)
  mov    %rbp,%rsi
  call   <read@plt>
  cmp    $0x5,%eax
  je     L18
  lea    D16(%rip),%rdi
  call   <perror@plt>
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L6
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type: string
name: retrieve_data
arguments: data_label: D19
type: string

tool: D16: Couldn't read 5 chars

tool: D19: Message from server: %s
	

assistant: ```c
void recv_message(int sockfd) {
  char message[6];
  message[5] = '\0';
  if (read(sockfd, message, 5) != 5) {
    perror("Couldn't read 5 chars");
  } else {
    printf("Message from server: %s\n	", message);
  }
}
```