ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  jmp    L67
L83:
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L67:
  cmpl   $0x6,-0x3c(%rbp)
  jle    L83
  movl   $0x6,-0x3c(%rbp)
  jmp    L8
L23:
  movl   $0x0,-0x38(%rbp)
  jmp    L43
L5:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L27
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x34(%rbp),%edx
  mov    %edx,-0x30(%rbp,%rax,4)
L27:
  addl   $0x1,-0x38(%rbp)
L43:
  mov    -0x38(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L5
  subl   $0x1,-0x3c(%rbp)
L8:
  cmpl   $0x3,-0x3c(%rbp)
  jg     L23
  movl   $0x0,-0x3c(%rbp)
  jmp    L50
L45:
  mov    -0x3c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3c(%rbp)
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  cmpl   $0x6,-0x3c(%rbp)
  jle    L45
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string

tool: D0: %d

tool: D18: %d 

assistant: ```c
int main() {
  int i, j, k, a[7];
  for (i = 0; i < 7; scanf("%d", a + i++))
    ;
  for (i = 7 - 1; i >= 7 - 3; i--)
    for (j = 0; j < i; j++)
      if (a[j] > a[j + 1])
        k = a[j], a[j] = a[j + 1], a[j + 1] = k;
  for (i = 0; i < 7; printf("%d ", a[i++]))
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    %rbx,%rbp
  lea    D16(%rip),%r13
L35:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L35
  lea    0x18(%rbx),%rsi
  mov    $0x6,%edi
  jmp    L18
L9:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L59
L77:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L9
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L9
L59:
  sub    $0x1,%edi
  sub    $0x4,%rsi
  cmp    $0x3,%edi
  je     L4
L18:
  mov    %rbx,%rax
  test   %edi,%edi
  jg     L77
  jmp    L59
L4:
  lea    D6(%rip),%rbp
L97:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L97
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D6
type: string

tool: D16: %d

tool: D6: %d 

assistant: ```c
int main() {
  int i, j, k, a[7];
  for (i = 0; i < 7; scanf("%d", a + i++))
    ;
  for (i = 7 - 1; i >= 7 - 3; i--)
    for (j = 0; j < i; j++)
      if (a[j] > a[j + 1])
        k = a[j], a[j] = a[j + 1], a[j + 1] = k;
  for (i = 0; i < 7; printf("%d ", a[i++]))
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x1c(%rsp),%r12
  mov    %rbx,%rbp
L8:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %r12,%rbp
  jne    L8
  lea    0x18(%rbx),%rsi
  lea    0xc(%rbx),%rdi
L21:
  mov    %rbx,%rax
  nop
L58:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L44
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L44:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L58
  lea    -0x4(%rax),%rsi
  cmp    %rdi,%rsi
  jne    L21
  lea    D16(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L24
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D6: %d

tool: D16: %d 

assistant: ```c
int main() {
  int i, j, k, a[7];
  for (i = 0; i < 7; scanf("%d", a + i++))
    ;
  for (i = 7 - 1; i >= 7 - 3; i--)
    for (j = 0; j < i; j++)
      if (a[j] > a[j + 1])
        k = a[j], a[j] = a[j + 1], a[j + 1] = k;
  for (i = 0; i < 7; printf("%d ", a[i++]))
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_remainder>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L10
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L10:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  add    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_remainder(int a) {
  int max_n = 0;
  if (a % 2 == 0)
    max_n = a / 2 - 1;
  else
    max_n = a / 2;
  return 2 * max_n * a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<max_remainder>:
  endbr64
  test   $0x1,%dil
  jne    L14
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  sub    $0x1,%eax
L5:
  imul   %edi,%eax
  add    %eax,%eax
  ret
L14:
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  jmp    L5
```

assistant: ```c
int max_remainder(int a) {
  int max_n = 0;
  if (a % 2 == 0)
    max_n = a / 2 - 1;
  else
    max_n = a / 2;
  return 2 * max_n * a;
}
```
user: What is the c source code of the assembly code below:

```asm
<max_remainder>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shr    $0x1f,%eax
  and    $0x1,%edx
  add    %edi,%eax
  sar    %eax
  cmp    $0x1,%edx
  sbb    $0x0,%eax
  imul   %edi,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int max_remainder(int a) {
  int max_n = 0;
  if (a % 2 == 0)
    max_n = a / 2 - 1;
  else
    max_n = a / 2;
  return 2 * max_n * a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<max_remainder>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  shr    $0x1f,%eax
  and    $0x1,%edx
  add    %edi,%eax
  sar    %eax
  cmp    $0x1,%edx
  sbb    $0x0,%eax
  imul   %edi,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int max_remainder(int a) {
  int max_n = 0;
  if (a % 2 == 0)
    max_n = a / 2 - 1;
  else
    max_n = a / 2;
  return 2 * max_n * a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L55
L14:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L38
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  jmp    L48
L38:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L23
L55:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L14
  mov    $0x0,%eax
L48:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *scanp;
  int c, sc;
  while ((c = *s1++) != 0) {
    for (scanp = s2; (sc = *scanp++) != 0;)
      if (sc == c)
        return (char *)s1 - 1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strpbrk>:
  endbr64
  movsbl (%rdi),%ecx
  test   %ecx,%ecx
  je     L0
L28:
  mov    %rdi,%r8
  mov    %rsi,%rax
L37:
  add    $0x1,%rax
  movsbl -0x1(%rax),%edx
  test   %edx,%edx
  je     L7
  cmp    %ecx,%edx
  jne    L37
L18:
  mov    %r8,%rax
  ret
L7:
  movsbl 0x1(%r8),%ecx
  add    $0x1,%rdi
  test   %ecx,%ecx
  jne    L28
  mov    $0x0,%r8d
  jmp    L18
L0:
  mov    $0x0,%r8d
  jmp    L18
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *scanp;
  int c, sc;
  while ((c = *s1++) != 0) {
    for (scanp = s2; (sc = *scanp++) != 0;)
      if (sc == c)
        return (char *)s1 - 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<strpbrk>:
  endbr64
  movsbl (%rdi),%ecx
  test   %ecx,%ecx
  je     L1
L16:
  mov    %rdi,%r8
  mov    %rsi,%rax
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L3:
  cmp    %ecx,%edx
  je     L2
L48:
  movsbl (%rax),%edx
  add    $0x1,%rax
  test   %edx,%edx
  jne    L3
  movsbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %ecx,%ecx
  jne    L16
L1:
  xor    %r8d,%r8d
L2:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *scanp;
  int c, sc;
  while ((c = *s1++) != 0) {
    for (scanp = s2; (sc = *scanp++) != 0;)
      if (sc == c)
        return (char *)s1 - 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strpbrk>:
  endbr64
  movsbl (%rdi),%ecx
  test   %ecx,%ecx
  je     L12
L47:
  mov    %rdi,%r8
  mov    %rsi,%rax
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L38:
  cmp    %ecx,%edx
  je     L4
L21:
  movsbl (%rax),%edx
  add    $0x1,%rax
  test   %edx,%edx
  jne    L38
  movsbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %ecx,%ecx
  jne    L47
L12:
  xor    %r8d,%r8d
L4:
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  const char *scanp;
  int c, sc;
  while ((c = *s1++) != 0) {
    for (scanp = s2; (sc = *scanp++) != 0;)
      if (sc == c)
        return (char *)s1 - 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mismatch_rdp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  mov    %rdi,-0x18(%rbp)
  movsd  D13(%rip),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  D18(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D13(%rip),%xmm0
  subsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  D18(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movsd  D41(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_infered: byte[8]
name: read_data
arguments: label: D18
type_infered: byte[8]
name: read_data
arguments: label: D41
type_infered: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
double mismatch_rdp(double p, double q, void *data) {
  (void)data;
  return ((1 - p) * q / 3 + (1 - q) * p / 3 + 2 * p * q / 9);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mismatch_rdp>:
  endbr64
  movapd %xmm0,%xmm2
  movsd  D19(%rip),%xmm3
  movapd %xmm3,%xmm0
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D16(%rip),%xmm4
  divsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm3
  mulsd  %xmm2,%xmm3
  divsd  %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm2
  divsd  D11(%rip),%xmm2
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D19
datatype: byte[8]
name: read_data
arguments: data_label: D16
datatype: byte[8]
name: read_data
arguments: data_label: D11
datatype: byte[8]

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
double mismatch_rdp(double p, double q, void *data) {
  (void)data;
  return ((1 - p) * q / 3 + (1 - q) * p / 3 + 2 * p * q / 9);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mismatch_rdp>:
  endbr64
  movsd  D20(%rip),%xmm3
  movapd %xmm0,%xmm2
  movsd  D3(%rip),%xmm4
  movapd %xmm3,%xmm0
  subsd  %xmm1,%xmm3
  subsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm2
  divsd  D11(%rip),%xmm2
  divsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D20
data_type: byte[8]
name: unpack_data
arguments: data_label: D3
data_type: byte[8]
name: unpack_data
arguments: data_label: D11
data_type: byte[8]

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
double mismatch_rdp(double p, double q, void *data) {
  (void)data;
  return ((1 - p) * q / 3 + (1 - q) * p / 3 + 2 * p * q / 9);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mismatch_rdp>:
  endbr64
  movsd  D12(%rip),%xmm3
  movapd %xmm0,%xmm2
  movsd  D28(%rip),%xmm4
  movapd %xmm3,%xmm0
  subsd  %xmm1,%xmm3
  subsd  %xmm2,%xmm0
  mulsd  %xmm2,%xmm3
  addsd  %xmm2,%xmm2
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm2
  divsd  D26(%rip),%xmm2
  divsd  %xmm4,%xmm3
  divsd  %xmm4,%xmm0
  addsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
type_guessed: byte[8]
name: read_data
arguments: data_label: D28
type_guessed: byte[8]
name: read_data
arguments: data_label: D26
type_guessed: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

assistant: ```c
double mismatch_rdp(double p, double q, void *data) {
  (void)data;
  return ((1 - p) * q / 3 + (1 - q) * p / 3 + 2 * p * q / 9);
}
```
user: What is the c source code of the assembly code below?

```asm
<ustrnicmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L115
L106:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L76
  mov    $0x0,%eax
  jmp    L142
L76:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L116
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L116
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  jmp    L33
L116:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
L33:
  mov    %al,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L141
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L141
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  jmp    L99
L141:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
L99:
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  cmp    -0x2(%rbp),%al
  jge    L4
  mov    $0x1,%eax
  jmp    L142
L4:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L133
  mov    $0xffffffff,%eax
  jmp    L142
L133:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  subl   $0x1,-0x24(%rbp)
L115:
  cmpl   $0x0,-0x24(%rbp)
  jne    L106
  mov    $0x0,%eax
L142:
  pop    %rbp
  ret
```

assistant: ```c
int ustrnicmp(const char *pcStr1, const char *pcStr2, int iCount) {
  char cL1, cL2;
  while (iCount) {
    if (!*pcStr1 && !*pcStr2) {
      return (0);
    }
    cL1 = (((*pcStr1 >= 'A') && (*pcStr1 <= 'Z')) ? (*pcStr1 + ('a' - 'A')) : *pcStr1);
    cL2 = (((*pcStr2 >= 'A') && (*pcStr2 <= 'Z')) ? (*pcStr2 + ('a' - 'A')) : *pcStr2);
    if (cL2 < cL1) {
      return (1);
    }
    if (cL1 < cL2) {
      return (-1);
    }
    pcStr1++;
    pcStr2++;
    iCount--;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ustrnicmp>:
  endbr64
  test   %edx,%edx
  je     L38
  mov    %edx,%eax
  mov    $0x0,%r9d
  jmp    L37
L76:
  lea    -0x41(%r8),%edx
  cmp    $0x19,%dl
  ja     L52
  add    $0x20,%r8d
L52:
  movzbl (%rsi,%r9,1),%ecx
  lea    -0x41(%rcx),%r11d
  lea    0x20(%rcx),%r10d
  cmp    $0x1a,%r11b
  cmovb  %r10d,%ecx
  cmp    %cl,%r8b
  jg     L42
  jl     L77
  add    $0x1,%r9
  cmp    %rax,%r9
  je     L75
L37:
  movzbl (%rdi,%r9,1),%r8d
  test   %r8b,%r8b
  jne    L76
  cmpb   $0x0,(%rsi,%r9,1)
  jne    L52
  mov    $0x0,%eax
  ret
L75:
  mov    $0x0,%eax
  ret
L38:
  mov    %edx,%eax
  ret
L42:
  mov    $0x1,%eax
  ret
L77:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ustrnicmp(const char *pcStr1, const char *pcStr2, int iCount) {
  char cL1, cL2;
  while (iCount) {
    if (!*pcStr1 && !*pcStr2) {
      return (0);
    }
    cL1 = (((*pcStr1 >= 'A') && (*pcStr1 <= 'Z')) ? (*pcStr1 + ('a' - 'A')) : *pcStr1);
    cL2 = (((*pcStr2 >= 'A') && (*pcStr2 <= 'Z')) ? (*pcStr2 + ('a' - 'A')) : *pcStr2);
    if (cL2 < cL1) {
      return (1);
    }
    if (cL1 < cL2) {
      return (-1);
    }
    pcStr1++;
    pcStr2++;
    iCount--;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ustrnicmp>:
  endbr64
  test   %edx,%edx
  je     L74
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L28
  xchg   %ax,%ax
L16:
  test   %al,%al
  je     L74
L79:
  lea    -0x41(%rax),%r10d
  lea    0x20(%rax),%r9d
  cmp    $0x1a,%r10b
  cmovb  %r9d,%eax
  cmp    %al,%r8b
  jg     L48
  jl     L19
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  je     L74
L28:
  movzbl (%rdi,%rcx,1),%r8d
  movzbl (%rsi,%rcx,1),%eax
  test   %r8b,%r8b
  je     L16
  lea    -0x41(%r8),%r9d
  cmp    $0x19,%r9b
  ja     L79
  add    $0x20,%r8d
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L74:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ustrnicmp(const char *pcStr1, const char *pcStr2, int iCount) {
  char cL1, cL2;
  while (iCount) {
    if (!*pcStr1 && !*pcStr2) {
      return (0);
    }
    cL1 = (((*pcStr1 >= 'A') && (*pcStr1 <= 'Z')) ? (*pcStr1 + ('a' - 'A')) : *pcStr1);
    cL2 = (((*pcStr2 >= 'A') && (*pcStr2 <= 'Z')) ? (*pcStr2 + ('a' - 'A')) : *pcStr2);
    if (cL2 < cL1) {
      return (1);
    }
    if (cL1 < cL2) {
      return (-1);
    }
    pcStr1++;
    pcStr2++;
    iCount--;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ustrnicmp>:
  endbr64
  test   %edx,%edx
  je     L74
  mov    %edx,%edx
  xor    %ecx,%ecx
  jmp    L17
  xchg   %ax,%ax
L51:
  test   %al,%al
  je     L74
L64:
  lea    -0x41(%rax),%r10d
  lea    0x20(%rax),%r9d
  cmp    $0x1a,%r10b
  cmovb  %r9d,%eax
  cmp    %al,%r8b
  jg     L72
  jl     L57
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  je     L74
L17:
  movzbl (%rdi,%rcx,1),%r8d
  movzbl (%rsi,%rcx,1),%eax
  test   %r8b,%r8b
  je     L51
  lea    -0x41(%r8),%r9d
  cmp    $0x19,%r9b
  ja     L64
  add    $0x20,%r8d
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L74:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ustrnicmp(const char *pcStr1, const char *pcStr2, int iCount) {
  char cL1, cL2;
  while (iCount) {
    if (!*pcStr1 && !*pcStr2) {
      return (0);
    }
    cL1 = (((*pcStr1 >= 'A') && (*pcStr1 <= 'Z')) ? (*pcStr1 + ('a' - 'A')) : *pcStr1);
    cL2 = (((*pcStr2 >= 'A') && (*pcStr2 <= 'Z')) ? (*pcStr2 + ('a' - 'A')) : *pcStr2);
    if (cL2 < cL1) {
      return (1);
    }
    if (cL1 < cL2) {
      return (-1);
    }
    pcStr1++;
    pcStr2++;
    iCount--;
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<orInstruction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int orInstruction(int i, int j) {
  int mask = i | j;
  return mask;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<orInstruction>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int orInstruction(int i, int j) {
  int mask = i | j;
  return mask;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<orInstruction>:
  endbr64
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
int orInstruction(int i, int j) {
  int mask = i | j;
  return mask;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <fn1@plt>
  mov    $0x0,%eax
  call   <fn2@plt>
  mov    $0x0,%eax
  call   <fn3@plt>
  mov    $0x0,%eax
  call   <fn4@plt>
  mov    $0x0,%eax
  call   <fn5@plt>
  mov    $0x0,%eax
  call   <fn6@plt>
  mov    $0x0,%eax
  call   <fn7@plt>
  mov    $0x0,%eax
  call   <fn8@plt>
  mov    $0x0,%eax
  call   <fn9@plt>
  mov    $0x0,%eax
  call   <fn10@plt>
  mov    $0x0,%eax
  call   <fn11@plt>
  mov    $0x5,%edi
  call   <fn12@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  fn1();
  fn2();
  fn3();
  fn4();
  fn5();
  fn6();
  fn7();
  fn8();
  fn9();
  fn10();
  fn11();
  fn12(5);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fn1@plt>
  mov    $0x0,%eax
  call   <fn2@plt>
  mov    $0x0,%eax
  call   <fn3@plt>
  mov    $0x0,%eax
  call   <fn4@plt>
  mov    $0x0,%eax
  call   <fn5@plt>
  mov    $0x0,%eax
  call   <fn6@plt>
  mov    $0x0,%eax
  call   <fn7@plt>
  mov    $0x0,%eax
  call   <fn8@plt>
  mov    $0x0,%eax
  call   <fn9@plt>
  mov    $0x0,%eax
  call   <fn10@plt>
  mov    $0x0,%eax
  call   <fn11@plt>
  mov    $0x5,%edi
  call   <fn12@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  fn1();
  fn2();
  fn3();
  fn4();
  fn5();
  fn6();
  fn7();
  fn8();
  fn9();
  fn10();
  fn11();
  fn12(5);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn1@plt>
  xor    %eax,%eax
  call   <fn2@plt>
  xor    %eax,%eax
  call   <fn3@plt>
  xor    %eax,%eax
  call   <fn4@plt>
  xor    %eax,%eax
  call   <fn5@plt>
  xor    %eax,%eax
  call   <fn6@plt>
  xor    %eax,%eax
  call   <fn7@plt>
  xor    %eax,%eax
  call   <fn8@plt>
  xor    %eax,%eax
  call   <fn9@plt>
  xor    %eax,%eax
  call   <fn10@plt>
  xor    %eax,%eax
  call   <fn11@plt>
  mov    $0x5,%edi
  call   <fn12@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  fn1();
  fn2();
  fn3();
  fn4();
  fn5();
  fn6();
  fn7();
  fn8();
  fn9();
  fn10();
  fn11();
  fn12(5);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn1@plt>
  xor    %eax,%eax
  call   <fn2@plt>
  xor    %eax,%eax
  call   <fn3@plt>
  xor    %eax,%eax
  call   <fn4@plt>
  xor    %eax,%eax
  call   <fn5@plt>
  xor    %eax,%eax
  call   <fn6@plt>
  xor    %eax,%eax
  call   <fn7@plt>
  xor    %eax,%eax
  call   <fn8@plt>
  xor    %eax,%eax
  call   <fn9@plt>
  xor    %eax,%eax
  call   <fn10@plt>
  xor    %eax,%eax
  call   <fn11@plt>
  mov    $0x5,%edi
  call   <fn12@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  fn1();
  fn2();
  fn3();
  fn4();
  fn5();
  fn6();
  fn7();
  fn8();
  fn9();
  fn10();
  fn11();
  fn12(5);
  return 0;
}
```