ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gogetenv>:
  endbr64
  sub    $0x8,%rsp
  call   <getenv@plt>
  lea    D8(%rip),%rdx
  test   %rax,%rax
  cmove  %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: (NULL)

assistant: ```c
char *gogetenv(char *varname) {
  char *result;
  if ((result = getenv(varname)) == NULL) {
    result = "(NULL)";
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_again>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <emit_token@plt>
  mov    $0xc57be916,%edi
  call   <resolve_backward@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D5: bbranch

assistant: ```c
void emit_again(void) {
  emit_token("bbranch");
  resolve_backward(0xC57be916);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<emit_again>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <emit_token@plt>
  mov    $0xc57be916,%edi
  call   <resolve_backward@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: bbranch

assistant: ```c
void emit_again(void) {
  emit_token("bbranch");
  resolve_backward(0xC57be916);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_again>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <emit_token@plt>
  mov    $0xc57be916,%edi
  add    $0x8,%rsp
  jmp    1070 <resolve_backward@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string

tool: D0: bbranch

assistant: ```c
void emit_again(void) {
  emit_token("bbranch");
  resolve_backward(0xC57be916);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_again>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <emit_token@plt>
  mov    $0xc57be916,%edi
  add    $0x8,%rsp
  jmp    1070 <resolve_backward@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type: string

tool: D4: bbranch

assistant: ```c
void emit_again(void) {
  emit_token("bbranch");
  resolve_backward(0xC57be916);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x20(%rbp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L17
L11:
  movss  -0x4(%rbp),%xmm0
  mulss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  subq   $0x1,-0x20(%rbp)
L17:
  cmpq   $0x1,-0x20(%rbp)
  jg     L11
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float power(b, ex)
float b;
long int ex;
{
  float res;
  for (res = b; ex > 1; res *= b, ex--)
    ;
  return (res);
}
```
user: What is the c source code of the assembly code below?

```asm
<power>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  cmp    $0x1,%rdi
  jle    L3
  movaps %xmm1,%xmm0
L9:
  mulss  %xmm1,%xmm0
  sub    $0x1,%rdi
  cmp    $0x1,%rdi
  jne    L9
  ret
L3:
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float power(b, ex)
float b;
long int ex;
{
  float res;
  for (res = b; ex > 1; res *= b, ex--)
    ;
  return (res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<power>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    $0x1,%rdi
  jle    L12
  nopl   (%rax)
L2:
  mulss  %xmm1,%xmm0
  sub    $0x1,%rdi
  cmp    $0x1,%rdi
  jne    L2
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
float power(b, ex)
float b;
long int ex;
{
  float res;
  for (res = b; ex > 1; res *= b, ex--)
    ;
  return (res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<power>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  movaps %xmm1,%xmm0
  cmp    $0x1,%rdi
  jle    L8
  nopl   (%rax)
L6:
  mulss  %xmm1,%xmm0
  sub    $0x1,%rdi
  cmp    $0x1,%rdi
  jne    L6
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
float power(b, ex)
float b;
long int ex;
{
  float res;
  for (res = b; ex > 1; res *= b, ex--)
    ;
  return (res);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movq   $0x0,-0x40(%rbp)
  jmp    L28
L70:
  movq   $0x0,-0x30(%rbp)
  lea    -0x48(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  jmp    L99
L61:
  movq   $0x0,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x20(%rbp)
  jmp    L42
L93:
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L85
  addq   $0x1,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  cmp    %rax,-0x20(%rbp)
  je     L85
  addq   $0x1,-0x38(%rbp)
L85:
  addq   $0x1,-0x20(%rbp)
L42:
  mov    -0x20(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L93
  mov    -0x38(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L5
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L5:
  addq   $0x1,-0x28(%rbp)
L99:
  mov    -0x48(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jle    L61
  mov    -0x48(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    -0x30(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x40(%rbp)
L28:
  mov    -0x58(%rbp),%rax
  cmp    %rax,-0x40(%rbp)
  jl     L70
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L98
  call   <__stack_chk_fail@plt>
L98:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
type_infered: string
name: extract_symbolic_data
arguments: label: D6
type_infered: string
name: extract_symbolic_data
arguments: label: D22
type_infered: string

tool: D27: %lld

tool: D6: %lld %lld

tool: D22: Between %lld and %lld, %lld has a maximum of %lld divisors.


assistant: ```c
int main() {
  long long t, i, l, h, count, max, root, p, q, num;
  scanf("%lld", &t);
  for (i = 0; i < t; i++) {
    max = 0;
    scanf("%lld %lld", &l, &h);
    for (p = l; p <= h; p++) {
      count = 0;
      root = sqrt(p);
      for (q = 1; q <= root; q++) {
        if (p % q == 0) {
          count++;
          if ((p / q) != q)
            count++;
        }
      }
      if (count > max) {
        max = count;
        num = p;
      }
    }
    printf("Between %lld and %lld, %lld has a maximum of %lld divisors.\n", l, h, num, max);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  cmpq   $0x0,(%rsp)
  jle    L32
  mov    $0x0,%r13d
  lea    0x10(%rsp),%r15
  lea    0x8(%rsp),%r14
  jmp    L59
L23:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  je     L82
L60:
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L23
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  mov    %rsi,%rdx
  cmp    %rcx,%rax
  setne  %sil
  movzbl %sil,%esi
  lea    0x1(%rsi,%rdx,1),%rsi
  jmp    L23
L13:
  mov    $0x0,%esi
L82:
  cmp    %rbp,%rsi
  jle    L61
  mov    %rbx,%r12
  mov    %rsi,%rbp
L61:
  add    $0x1,%rbx
  mov    0x10(%rsp),%rdx
  cmp    %rbx,%rdx
  jl     L54
L45:
  mov    %rbx,%rdi
  call   <sqrt@plt>
  test   %rax,%rax
  jle    L13
  lea    0x1(%rax),%rdi
  mov    $0x1,%ecx
  mov    $0x0,%esi
  jmp    L60
L106:
  mov    $0x0,%ebp
L54:
  mov    %rbp,%r8
  mov    %r12,%rcx
  mov    0x8(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%r13
  cmp    %r13,(%rsp)
  jle    L32
L59:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%rbx
  mov    0x10(%rsp),%rdx
  cmp    %rdx,%rbx
  jg     L106
  mov    $0x0,%ebp
  jmp    L45
L32:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string
name: retrieve_data
arguments: data_label: D15
type: string
name: retrieve_data
arguments: data_label: D10
type: string

tool: D9: %lld

tool: D15: Between %lld and %lld, %lld has a maximum of %lld divisors.


tool: D10: %lld %lld

assistant: ```c
int main() {
  long long t, i, l, h, count, max, root, p, q, num;
  scanf("%lld", &t);
  for (i = 0; i < t; i++) {
    max = 0;
    scanf("%lld %lld", &l, &h);
    for (p = l; p <= h; p++) {
      count = 0;
      root = sqrt(p);
      for (q = 1; q <= root; q++) {
        if (p % q == 0) {
          count++;
          if ((p / q) != q)
            count++;
        }
      }
      if (count > max) {
        max = count;
        num = p;
      }
    }
    printf("Between %lld and %lld, %lld has a maximum of %lld divisors.\n", l, h, num, max);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x10(%rsp),%r15
  lea    0x8(%rsp),%r14
  call   <scanf@plt>
  cmpq   $0x0,(%rsp)
  jle    L6
  nopl   0x0(%rax)
L69:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%r13
  mov    0x10(%rsp),%rdx
  xor    %ebx,%ebx
  cmp    %rdx,%r13
  jg     L62
  nopl   (%rax)
L13:
  mov    %r13,%rdi
  call   <sqrt@plt>
  test   %rax,%rax
  jle    L29
  lea    0x1(%rax),%rdi
  mov    $0x1,%ecx
  xor    %esi,%esi
L33:
  mov    %r13,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L26
  mov    %rsi,%rdx
  xor    %esi,%esi
  cmp    %rcx,%rax
  setne  %sil
  lea    0x1(%rsi,%rdx,1),%rsi
L26:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L33
  cmp    %rbx,%rsi
  jle    L29
  mov    %r13,%rbp
  mov    %rsi,%rbx
L29:
  mov    0x10(%rsp),%rdx
  add    $0x1,%r13
  cmp    %r13,%rdx
  jge    L13
  mov    0x8(%rsp),%r13
L62:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r13,%rsi
  add    $0x1,%r12
  lea    D19(%rip),%rdi
  call   <printf@plt>
  cmp    %r12,(%rsp)
  jg     L69
L6:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D28: %lld

tool: D3: %lld %lld

tool: D19: Between %lld and %lld, %lld has a maximum of %lld divisors.


assistant: ```c
int main() {
  long long t, i, l, h, count, max, root, p, q, num;
  scanf("%lld", &t);
  for (i = 0; i < t; i++) {
    max = 0;
    scanf("%lld %lld", &l, &h);
    for (p = l; p <= h; p++) {
      count = 0;
      root = sqrt(p);
      for (q = 1; q <= root; q++) {
        if (p % q == 0) {
          count++;
          if ((p / q) != q)
            count++;
        }
      }
      if (count > max) {
        max = count;
        num = p;
      }
    }
    printf("Between %lld and %lld, %lld has a maximum of %lld divisors.\n", l, h, num, max);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D22(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x10(%rsp),%r15
  lea    0x8(%rsp),%r14
  call   <scanf@plt>
  cmpq   $0x0,(%rsp)
  jle    L57
  nopl   0x0(%rax)
L73:
  mov    %r15,%rdx
  mov    %r14,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%r13
  mov    0x10(%rsp),%rdx
  xor    %ebx,%ebx
  cmp    %rdx,%r13
  jg     L53
  nopl   (%rax)
L4:
  mov    %r13,%rdi
  call   <sqrt@plt>
  test   %rax,%rax
  jle    L45
  lea    0x1(%rax),%rdi
  mov    $0x1,%ecx
  xor    %esi,%esi
L75:
  mov    %r13,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L16
  mov    %rsi,%rdx
  xor    %esi,%esi
  cmp    %rcx,%rax
  setne  %sil
  lea    0x1(%rsi,%rdx,1),%rsi
L16:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L75
  cmp    %rbx,%rsi
  jle    L45
  mov    %r13,%rbp
  mov    %rsi,%rbx
L45:
  mov    0x10(%rsp),%rdx
  add    $0x1,%r13
  cmp    %r13,%rdx
  jge    L4
  mov    0x8(%rsp),%r13
L53:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r13,%rsi
  add    $0x1,%r12
  lea    D29(%rip),%rdi
  call   <printf@plt>
  cmp    %r12,(%rsp)
  jg     L73
L57:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string

tool: D22: %lld

tool: D0: %lld %lld

tool: D29: Between %lld and %lld, %lld has a maximum of %lld divisors.


assistant: ```c
int main() {
  long long t, i, l, h, count, max, root, p, q, num;
  scanf("%lld", &t);
  for (i = 0; i < t; i++) {
    max = 0;
    scanf("%lld %lld", &l, &h);
    for (p = l; p <= h; p++) {
      count = 0;
      root = sqrt(p);
      for (q = 1; q <= root; q++) {
        if (p % q == 0) {
          count++;
          if ((p / q) != q)
            count++;
        }
      }
      if (count > max) {
        max = count;
        num = p;
      }
    }
    printf("Between %lld and %lld, %lld has a maximum of %lld divisors.\n", l, h, num, max);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<StrUtil_copyString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jg     L50
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L56
  lea    D25(%rip),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  mov    $0xc,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L27
L56:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  jmp    L48
L50:
  mov    -0x24(%rbp),%eax
  sub    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x3,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L49
  lea    D25(%rip),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  mov    $0xc,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L27
L49:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L48:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D25
datatype: string
name: unpack_data
arguments: data_tag: D31
datatype: string

tool: D25: to

tool: D31: StrUtil_copyString

assistant: ```c
char *StrUtil_copyString(char **to, char *from, int Start) {
  char *cp;
  int Len;
  if ((Len = strlen(from)) - 1 < Start) {
    if ((*to = (char *)calloc(1, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    (*to)[0] = '\0';
  } else {
    Len -= Start;
    cp = &from[Start];
    if ((*to = (char *)calloc(Len + 3, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    strcpy(*to, cp);
  }
  return *to;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<StrUtil_copyString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %r12d,%eax
  jg     L48
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L59
  movb   $0x0,(%rax)
L58:
  mov    0x0(%rbp),%rax
L57:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  lea    D29(%rip),%rcx
  mov    $0x2,%edx
  lea    D30(%rip),%rsi
  mov    $0xc,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L57
L48:
  movslq %r12d,%rdx
  add    %rdx,%rbx
  sub    %r12d,%eax
  lea    0x3(%rax),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L41
  mov    %rbx,%rsi
  call   <strcpy@plt>
  jmp    L58
L41:
  lea    D29(%rip),%rcx
  mov    $0x2,%edx
  lea    D30(%rip),%rsi
  mov    $0xc,%edi
  call   <Error_write@plt>
  mov    $0x0,%eax
  jmp    L57
```

tool_calls: name: read_data
arguments: data_tag: D29
type_infered: string
name: read_data
arguments: data_tag: D30
type_infered: string

tool: D29: to

tool: D30: StrUtil_copyString

assistant: ```c
char *StrUtil_copyString(char **to, char *from, int Start) {
  char *cp;
  int Len;
  if ((Len = strlen(from)) - 1 < Start) {
    if ((*to = (char *)calloc(1, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    (*to)[0] = '\0';
  } else {
    Len -= Start;
    cp = &from[Start];
    if ((*to = (char *)calloc(Len + 3, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    strcpy(*to, cp);
  }
  return *to;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<StrUtil_copyString>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L22
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L8
  movb   $0x0,(%rax)
L36:
  mov    0x0(%rbp),%rax
L14:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  sub    %r13d,%eax
  movslq %r13d,%rdx
  mov    $0x1,%esi
  lea    0x3(%rax),%edi
  add    %rdx,%r12
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L8
  mov    %r12,%rsi
  call   <strcpy@plt>
  jmp    L36
  nopl   0x0(%rax)
L8:
  lea    D11(%rip),%rcx
  mov    $0x2,%edx
  mov    $0xc,%edi
  lea    D7(%rip),%rsi
  call   <Error_write@plt>
  xor    %eax,%eax
  jmp    L14
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D11: to

tool: D7: StrUtil_copyString

assistant: ```c
char *StrUtil_copyString(char **to, char *from, int Start) {
  char *cp;
  int Len;
  if ((Len = strlen(from)) - 1 < Start) {
    if ((*to = (char *)calloc(1, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    (*to)[0] = '\0';
  } else {
    Len -= Start;
    cp = &from[Start];
    if ((*to = (char *)calloc(Len + 3, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    strcpy(*to, cp);
  }
  return *to;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<StrUtil_copyString>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  jg     L39
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L19
  movb   $0x0,(%rax)
L12:
  mov    0x0(%rbp),%rax
L34:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L39:
  sub    %r13d,%eax
  movslq %r13d,%rdx
  mov    $0x1,%esi
  lea    0x3(%rax),%edi
  add    %rdx,%r12
  call   <calloc@plt>
  mov    %rax,0x0(%rbp)
  mov    %rax,%rdi
  test   %rax,%rax
  je     L19
  mov    %r12,%rsi
  call   <strcpy@plt>
  jmp    L12
  nopl   0x0(%rax)
L19:
  lea    D5(%rip),%rcx
  mov    $0x2,%edx
  mov    $0xc,%edi
  lea    D19(%rip),%rsi
  call   <Error_write@plt>
  xor    %eax,%eax
  jmp    L34
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string

tool: D5: to

tool: D19: StrUtil_copyString

assistant: ```c
char *StrUtil_copyString(char **to, char *from, int Start) {
  char *cp;
  int Len;
  if ((Len = strlen(from)) - 1 < Start) {
    if ((*to = (char *)calloc(1, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    (*to)[0] = '\0';
  } else {
    Len -= Start;
    cp = &from[Start];
    if ((*to = (char *)calloc(Len + 3, sizeof(char))) == NULL) {
      Error_write(12, "StrUtil_copyString", 2, "to");
      return NULL;
    }
    strcpy(*to, cp);
  }
  return *to;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<guess_script_title_from_first_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L26
L87:
  addq   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L87
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L87
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L87
  mov    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%esi
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D3(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L125
L59:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L82
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L11
L82:
  addq   $0x1,-0x10(%rbp)
L125:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
L11:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L89
L107:
  subq   $0x1,-0x8(%rbp)
L89:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L107
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L107
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L107
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L17
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L17:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %s

assistant: ```c
void guess_script_title_from_first_line(char *src, char *dst, int maxsize) {
  while (isspace(*src) || *src == '/' || *src == '*')
    src++;
  snprintf(dst, maxsize, "%s", src);
  for (char *c = dst; *c; c++)
    if (*c == '\n') {
      *c = 0;
      break;
    }
  char *last = dst + strlen(dst) - 1;
  while (isspace(*last) || *last == '/' || *last == '*')
    last--;
  last++;
  if (last > dst)
    *last = 0;
}
```