ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<uninitvar_wcscmp>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcscmp@plt>
```

assistant: ```c
void uninitvar_wcscmp(void) {
  wchar_t *str1;
  wchar_t *str2;
  (void)wcscmp(str1, str2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<dSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L17
L7:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x18(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L7
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double dSum(double *pta, int n) {
  int i, cnt;
  double a, sum;
  sum = 0.0;
  cnt = 0;
  for (i = 0; i < n; i++) {
    a = *(pta + i);
    sum += a;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<dSum>:
  endbr64
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm0,%xmm0
L18:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L18
  ret
L9:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double dSum(double *pta, int n) {
  int i, cnt;
  double a, sum;
  sum = 0.0;
  cnt = 0;
  for (i = 0; i < n; i++) {
    a = *(pta + i);
    sum += a;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dSum>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L11:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L11
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double dSum(double *pta, int n) {
  int i, cnt;
  double a, sum;
  sum = 0.0;
  cnt = 0;
  for (i = 0; i < n; i++) {
    a = *(pta + i);
    sum += a;
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dSum>:
  endbr64
  test   %esi,%esi
  jle    L39
  cmp    $0x1,%esi
  je     L30
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax)
L43:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L43
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L32
L5:
  cltq
  addsd  (%rdi,%rax,8),%xmm0
  ret
  nopl   0x0(%rax)
L32:
  ret
  nopl   0x0(%rax)
L39:
  pxor   %xmm0,%xmm0
  ret
L30:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L5
```

assistant: ```c
double dSum(double *pta, int n) {
  int i, cnt;
  double a, sum;
  sum = 0.0;
  cnt = 0;
  for (i = 0; i < n; i++) {
    a = *(pta + i);
    sum += a;
  }
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<suzerain_inorder_wavenumber_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0x0,-0xc(%rbp)
  js     L64
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L64
  mov    $0x1,%eax
  jmp    L11
L64:
  mov    $0x0,%eax
L11:
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0xc(%rbp)
  jge    L15
  mov    -0xc(%rbp),%eax
  jmp    L38
L15:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  neg    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L16
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  jmp    L38
L16:
  mov    $0x0,%eax
L38:
  leave
  ret
```

assistant: ```c
int suzerain_inorder_wavenumber_diff(const int N, const int dN, const int i) {
  assert(N <= dN);
  assert(0 <= i && i < dN);
  if (i < (N + 1) / 2) {
    return i;
  } else if (i >= dN - (N - 1) / 2) {
    return -dN + i;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<suzerain_inorder_wavenumber_diff>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  cmp    %esi,%edi
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  cmp    %ebx,%r12d
  setg   %al
  and    %eax,%edi
  call   <assert@plt>
  lea    0x1(%rbp),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %ebx,%edx
  cmp    %ebx,%eax
  jg     L5
  sub    $0x1,%ebp
  mov    %ebp,%eax
  shr    $0x1f,%eax
  add    %ebp,%eax
  sar    %eax
  mov    %r12d,%ecx
  sub    %eax,%ecx
  sub    %r12d,%edx
  cmp    %ebx,%ecx
  mov    $0x0,%eax
  cmovg  %eax,%edx
L5:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int suzerain_inorder_wavenumber_diff(const int N, const int dN, const int i) {
  assert(N <= dN);
  assert(0 <= i && i < dN);
  if (i < (N + 1) / 2) {
    return i;
  } else if (i >= dN - (N - 1) / 2) {
    return -dN + i;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<suzerain_inorder_wavenumber_diff>:
  endbr64
  push   %r12
  cmp    %esi,%edi
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  setle  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %edx,%ebx
  call   <assert@plt>
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  cmp    %ebx,%r12d
  setg   %al
  and    %eax,%edi
  call   <assert@plt>
  lea    0x1(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %ebx,%eax
  sar    %edx
  cmp    %ebx,%edx
  jg     L5
  sub    $0x1,%ebp
  mov    %r12d,%ecx
  mov    $0x0,%eax
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
  sub    %edx,%ecx
  mov    %ebx,%edx
  sub    %r12d,%edx
  cmp    %ebx,%ecx
  cmovle %edx,%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int suzerain_inorder_wavenumber_diff(const int N, const int dN, const int i) {
  assert(N <= dN);
  assert(0 <= i && i < dN);
  if (i < (N + 1) / 2) {
    return i;
  } else if (i >= dN - (N - 1) / 2) {
    return -dN + i;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<suzerain_inorder_wavenumber_diff>:
  endbr64
  push   %r12
  cmp    %esi,%edi
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  setle  %dil
  push   %rbx
  movzbl %dil,%edi
  mov    %edx,%ebx
  call   <assert@plt>
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  cmp    %ebx,%r12d
  setg   %al
  and    %eax,%edi
  call   <assert@plt>
  lea    0x1(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  mov    %ebx,%eax
  sar    %edx
  cmp    %ebx,%edx
  jg     L0
  sub    $0x1,%ebp
  mov    %r12d,%ecx
  mov    $0x0,%eax
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
  sub    %edx,%ecx
  mov    %ebx,%edx
  sub    %r12d,%edx
  cmp    %ebx,%ecx
  cmovle %edx,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int suzerain_inorder_wavenumber_diff(const int N, const int dN, const int i) {
  assert(N <= dN);
  assert(0 <= i && i < dN);
  if (i < (N + 1) / 2) {
    return i;
  } else if (i >= dN - (N - 1) / 2) {
    return -dN + i;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread2_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x214(%rbp)
  jmp    L22
L1:
  mov    -0x228(%rbp),%rcx
  mov    -0x214(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D7(%rip),%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x249f0,%edi
  call   <usleep@plt>
  addl   $0x1,-0x214(%rbp)
L22:
  cmpl   $0x13,-0x214(%rbp)
  jle    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D7
datatype: string

tool: D7: thread2: %d %s


assistant: ```c
void *thread2_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 20; i++) {
    snprintf(buf, sizeof(buf), "thread2: %d %s\n", i, (char *)arg);
    write(1, buf, strlen(buf));
    usleep(150 * 1000);
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<thread2_func>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
L0:
  mov    %rsp,%rbp
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x249f0,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmp    $0x14,%ebx
  jne    L0
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: thread2: %d %s


assistant: ```c
void *thread2_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 20; i++) {
    snprintf(buf, sizeof(buf), "thread2: %d %s\n", i, (char *)arg);
    write(1, buf, strlen(buf));
    usleep(150 * 1000);
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<thread2_func>:
  endbr64
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%ecx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x249f0,%edi
  call   <usleep@plt>
  cmp    $0x14,%ebx
  jne    L0
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string

tool: D8: thread2: %d %s


assistant: ```c
void *thread2_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 20; i++) {
    snprintf(buf, sizeof(buf), "thread2: %d %s\n", i, (char *)arg);
    write(1, buf, strlen(buf));
    usleep(150 * 1000);
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<thread2_func>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%ecx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    $0x249f0,%edi
  call   <usleep@plt>
  cmp    $0x14,%ebx
  jne    L5
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: thread2: %d %s


assistant: ```c
void *thread2_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 20; i++) {
    snprintf(buf, sizeof(buf), "thread2: %d %s\n", i, (char *)arg);
    write(1, buf, strlen(buf));
    usleep(150 * 1000);
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_bfr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  jmp    L19
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L19:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: 0x%x 

assistant: ```c
void print_bfr(void *b, unsigned size) {
  char *c;
  while (size--) {
    c = (char *)b++;
    printf("0x%x ", *c);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_bfr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L6
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  mov    %eax,%eax
  lea    0x1(%rdi,%rax,1),%r12
  lea    D3(%rip),%rbp
L5:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
L6:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: 0x%x 

assistant: ```c
void print_bfr(void *b, unsigned size) {
  char *c;
  while (size--) {
    c = (char *)b++;
    printf("0x%x ", *c);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_bfr>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %esi,%esi
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L12:
  movsbl (%rbx),%esi
  add    $0x1,%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L12
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: 0x%x 

assistant: ```c
void print_bfr(void *b, unsigned size) {
  char *c;
  while (size--) {
    c = (char *)b++;
    printf("0x%x ", *c);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_bfr>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %esi,%esi
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L7:
  movsbl (%rbx),%esi
  add    $0x1,%rbx
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L7
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_infered: string

tool: D5: 0x%x 

assistant: ```c
void print_bfr(void *b, unsigned size) {
  char *c;
  while (size--) {
    c = (char *)b++;
    printf("0x%x ", *c);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L4:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L35:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  nop
L24:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x28(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  subq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  movl   $0x0,-0xc(%rbp)
  jmp    L36
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x30(%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L36:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
int encode(char *src, int len, char *dest, char **encode_table) {
  for (int i = 0; i < len; ++i) {
    char *p = encode_table[src[i]];
    while (*dest++ = *p++)
      ;
    dest--;
  }
  for (int i = 0; i < len; ++i) {
    *dest++ = strlen(encode_table[src[i]]) + '0';
  }
  *dest = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %esi,%esi
  jle    L36
  mov    %rdi,%r12
  mov    %rcx,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r8
L4:
  movsbq (%rdi),%rax
  mov    0x0(%rbp,%rax,8),%rdx
  mov    %rbx,%rax
L14:
  add    $0x1,%rdx
  mov    %rax,%rbx
  add    $0x1,%rax
  movzbl -0x1(%rdx),%ecx
  mov    %cl,-0x1(%rax)
  test   %cl,%cl
  jne    L14
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L4
  mov    %esi,%r14d
  mov    $0x0,%r13d
L13:
  movsbq (%r12,%r13,1),%rax
  mov    0x0(%rbp,%rax,8),%rdi
  call   <strlen@plt>
  add    $0x30,%eax
  mov    %al,(%rbx,%r13,1)
  add    $0x1,%r13
  cmp    %r13,%r14
  jne    L13
  add    %r14,%rbx
L36:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int encode(char *src, int len, char *dest, char **encode_table) {
  for (int i = 0; i < len; ++i) {
    char *p = encode_table[src[i]];
    while (*dest++ = *p++)
      ;
    dest--;
  }
  for (int i = 0; i < len; ++i) {
    *dest++ = strlen(encode_table[src[i]]) + '0';
  }
  *dest = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<encode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r12
  mov    %rcx,%r14
  lea    0x1(%rdi,%rax,1),%r8
  nopl   0x0(%rax)
L37:
  movsbq (%rdi),%rax
  mov    (%r14,%rax,8),%rdx
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L1:
  movzbl (%rdx),%ecx
  mov    %rax,%rbx
  add    $0x1,%rdx
  lea    0x1(%rax),%rax
  mov    %cl,-0x1(%rax)
  test   %cl,%cl
  jne    L1
  add    $0x1,%rdi
  cmp    %r8,%rdi
  jne    L37
  mov    %esi,%r13d
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L28:
  movsbq (%r12,%rbp,1),%rax
  mov    (%r14,%rax,8),%rdi
  call   <strlen@plt>
  add    $0x30,%eax
  mov    %al,(%rbx,%rbp,1)
  add    $0x1,%rbp
  cmp    %rbp,%r13
  jne    L28
  add    %r13,%rbx
L5:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int encode(char *src, int len, char *dest, char **encode_table) {
  for (int i = 0; i < len; ++i) {
    char *p = encode_table[src[i]];
    while (*dest++ = *p++)
      ;
    dest--;
  }
  for (int i = 0; i < len; ++i) {
    *dest++ = strlen(encode_table[src[i]]) + '0';
  }
  *dest = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  test   %esi,%esi
  jle    L38
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r12
  mov    %rcx,%r14
  lea    0x1(%rdi,%rax,1),%r8
  nopl   0x0(%rax)
L24:
  movsbq (%rdi),%rax
  mov    (%r14,%rax,8),%rdx
  mov    %rbx,%rax
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rdx),%ecx
  mov    %rax,%rbx
  add    $0x1,%rdx
  lea    0x1(%rax),%rax
  mov    %cl,-0x1(%rax)
  test   %cl,%cl
  jne    L14
  add    $0x1,%rdi
  cmp    %rdi,%r8
  jne    L24
  mov    %esi,%r13d
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L9:
  movsbq (%r12,%rbp,1),%rax
  mov    (%r14,%rax,8),%rdi
  call   <strlen@plt>
  add    $0x30,%eax
  mov    %al,(%rbx,%rbp,1)
  add    $0x1,%rbp
  cmp    %rbp,%r13
  jne    L9
  add    %r13,%rbx
L38:
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int encode(char *src, int len, char *dest, char **encode_table) {
  for (int i = 0; i < len; ++i) {
    char *p = encode_table[src[i]];
    while (*dest++ = *p++)
      ;
    dest--;
  }
  for (int i = 0; i < len; ++i) {
    *dest++ = strlen(encode_table[src[i]]) + '0';
  }
  *dest = '\0';
}
```