user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x13880,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x13880,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    $0x13880,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  movdqa D6(%rip),%xmm3
  xor    %ecx,%ecx
  movdqa D31(%rip),%xmm5
  mov    %rax,%r9
  lea    0x320(%rbx),%rdx
  lea    0x13ba0(%rbx),%rsi
L2:
  movd   %ecx,%xmm6
  lea    -0x320(%rdx),%rax
  movdqa %xmm5,%xmm1
  pshufd $0x0,%xmm6,%xmm4
  nopl   0x0(%rax)
L37:
  movdqa %xmm1,%xmm0
  add    $0x20,%rax
  paddd  %xmm3,%xmm1
  paddd  %xmm4,%xmm0
  cvtdq2pd %xmm0,%xmm2
  pshufd $0xee,%xmm0,%xmm0
  movups %xmm2,-0x20(%rax)
  cvtdq2pd %xmm0,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L37
  lea    0x320(%rax),%rdx
  add    $0x3,%ecx
  cmp    %rsi,%rdx
  jne    L2
  lea    0x13880(%rbx),%rcx
  mov    %rbp,%r13
  pxor   %xmm2,%xmm2
  xor    %r12d,%r12d
  mov    %rcx,%rsi
L129:
  imul   $0x328,%r12,%r10
  mov    %r12d,%r8d
  lea    (%rbx,%r12,8),%r11
  xor    %edx,%edx
  mov    %r13,%rdi
  add    %rbp,%r10
L72:
  mov    %r11,%rax
  movapd %xmm2,%xmm1
  nopw   0x0(%rax,%rax,1)
L56:
  movsd  (%rdx,%rax,1),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x320,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L56
  add    $0x1,%r8d
  movsd  %xmm1,(%r10,%rdx,1)
  add    $0x320,%rdi
  add    $0x8,%rdx
  movsd  %xmm1,-0x320(%rdi)
  cmp    $0x64,%r8d
  jne    L72
  add    $0x1,%r12
  add    $0x328,%r13
  add    $0x8,%rsi
  cmp    $0x64,%r12
  jne    L129
  mov    %r9,%r12
  xor    %r11d,%r11d
L63:
  imul   $0x328,%r11,%r8
  mov    %r11d,%edi
  lea    (%rbx,%r11,8),%r10
  xor    %edx,%edx
  mov    %r12,%rsi
  add    %r9,%r8
L7:
  mov    %r10,%rax
  movapd %xmm2,%xmm1
  nopl   0x0(%rax,%rax,1)
L127:
  movsd  (%rax,%rdx,1),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x320,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rcx
  jne    L127
  add    $0x1,%edi
  movsd  %xmm1,(%r8,%rdx,1)
  add    $0x320,%rsi
  add    $0x8,%rdx
  movsd  %xmm1,-0x320(%rsi)
  cmp    $0x64,%edi
  jne    L7
  add    $0x1,%r11
  add    $0x328,%r12
  add    $0x8,%rcx
  cmp    $0x64,%r11
  jne    L63
  lea    0x320(%rbp),%rax
  lea    0x13ba0(%rbp),%rcx
  sub    %rbp,%r9
L116:
  lea    -0x320(%rax),%rdx
  jmp    L36
L5:
  add    $0x8,%rdx
  cmp    %rdx,%rax
  je     L4
L36:
  movsd  (%rdx),%xmm0
  movsd  (%r9,%rdx,1),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L32
  je     L5
L32:
  lea    D16(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L64:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  add    $0x320,%rax
  cmp    %rcx,%rax
  jne    L116
  lea    D12(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L64
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: byte[16]
name: parse_data
arguments: tag: D31
datatype: f32[4]
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D12
datatype: string

tool: {"D6": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D31": [0.0,1.401298464324817e-45,2.802596928649634e-45,4.203895392974451e-45]}

tool: D16: %f, %f


tool: D12: PASS

assistant: ```c
int main() {
  int n = 100;
  int i, j, j1, j2;
  double *data_in = (double *)malloc(n * n * sizeof(double));
  double *data_out = (double *)malloc(n * n * sizeof(double));
  double *data_host_out = (double *)malloc(n * n * sizeof(double));
  double tmp = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      data_in[i * n + j] = 3 * i + j;
    }
  }
#pragma acc data copyin(data_in [0:n * n]), copyout(data_out [0:n * n])
  {
#pragma acc parallel loop
    for (j1 = 0; j1 < n; j1++) {
#pragma acc loop private(tmp)
      for (j2 = j1; j2 < n; j2++) {
        tmp = 0;
#pragma acc loop reduction(+ : tmp)
        for (i = 0; i < n; i++) {
          tmp += data_in[i * n + j1] * data_in[i * n + j2];
        }
        data_out[j1 * n + j2] = tmp;
        data_out[j2 * n + j1] = data_out[j1 * n + j2];
      }
    }
  }
  for (j1 = 0; j1 < n; j1++) {
    for (j2 = j1; j2 < n; j2++) {
      tmp = 0;
      for (i = 0; i < n; i++) {
        tmp += data_in[i * n + j1] * data_in[i * n + j2];
      }
      data_host_out[j1 * n + j2] = tmp;
      data_host_out[j2 * n + j1] = data_host_out[j1 * n + j2];
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (data_out[i * n + j] != data_host_out[i * n + j]) {
        printf("%f, %f\n", data_out[i * n + j], data_host_out[i * n + j]);
        return 1;
      }
    }
  }
  printf("PASS\n");
  return 0;
}
```