user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1f,-0x110(%rbp)
  movl   $0xc9,-0x10c(%rbp)
  movl   $0xfb,-0x108(%rbp)
  movl   $0x82,-0x104(%rbp)
  movl   $0xaa,-0x100(%rbp)
  movl   $0xd3,-0xfc(%rbp)
  movl   $0x5,-0xf8(%rbp)
  movl   $0x81,-0xf4(%rbp)
  movl   $0x96,-0xf0(%rbp)
  movl   $0xe,-0xec(%rbp)
  movl   $0x25,-0xe8(%rbp)
  movl   $0xf9,-0xe4(%rbp)
  movl   $0xec,-0xe0(%rbp)
  movl   $0x12,-0xdc(%rbp)
  movl   $0x11,-0xd8(%rbp)
  movl   $0x81,-0xd4(%rbp)
  movl   $0x1f,-0xd0(%rbp)
  movl   $0xc9,-0xcc(%rbp)
  movl   $0xfb,-0xc8(%rbp)
  movl   $0x82,-0xc4(%rbp)
  movl   $0xaa,-0xc0(%rbp)
  movl   $0xd3,-0xbc(%rbp)
  movl   $0x5,-0xb8(%rbp)
  movl   $0x81,-0xb4(%rbp)
  movl   $0x96,-0xb0(%rbp)
  movl   $0xe,-0xac(%rbp)
  movl   $0x25,-0xa8(%rbp)
  movl   $0xf9,-0xa4(%rbp)
  movl   $0xec,-0xa0(%rbp)
  movl   $0x12,-0x9c(%rbp)
  movl   $0x11,-0x98(%rbp)
  movl   $0x81,-0x94(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x1,-0x88(%rbp)
  movl   $0x2,-0x80(%rbp)
  lea    -0x150(%rbp),%rsi
  lea    -0xd0(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <forward4x4@plt>
  movl   $0x0,-0x160(%rbp)
  jmp    L39
L40:
  movl   $0x0,-0x15c(%rbp)
  jmp    L20
L38:
  mov    -0x15c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x160(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x150(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x15c(%rbp)
L20:
  cmpl   $0x3,-0x15c(%rbp)
  jle    L38
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x160(%rbp)
L39:
  cmpl   $0x3,-0x160(%rbp)
  jle    L40
  movl   $0x7ba,-0x50(%rbp)
  movl   $0x22,-0x4c(%rbp)
  movl   $0x1d6,-0x48(%rbp)
  movl   $0xfffffec2,-0x44(%rbp)
  movl   $0x1eb,-0x40(%rbp)
  movl   $0xfffffe5f,-0x3c(%rbp)
  movl   $0xfffffa1d,-0x38(%rbp)
  movl   $0xfffffdf2,-0x34(%rbp)
  movl   $0x30,-0x30(%rbp)
  movl   $0xffffff9c,-0x2c(%rbp)
  movl   $0xfffffe78,-0x28(%rbp)
  movl   $0x212,-0x24(%rbp)
  movl   $0x53,-0x20(%rbp)
  movl   $0xfffffa37,-0x1c(%rbp)
  movl   $0xffffffa5,-0x18(%rbp)
  movl   $0x214,-0x14(%rbp)
  lea    -0x150(%rbp),%rsi
  lea    -0x50(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %rax,%rdi
  call   <inverse4x4@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x158(%rbp)
  jmp    L51
L77:
  movl   $0x0,-0x154(%rbp)
  jmp    L47
L29:
  mov    -0x154(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x158(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x150(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x154(%rbp)
L47:
  cmpl   $0x3,-0x154(%rbp)
  jle    L29
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x158(%rbp)
L51:
  cmpl   $0x3,-0x158(%rbp)
  jle    L77
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string

tool: D29: %2d 

tool: D28: Inverse: 

tool: D6: %5d 

assistant: ```c
int main(void) {
  int out[4][4];
  int in3[4][4] = {{31, 201, 251, 130}, {170, 211, 5, 129}, {150, 14, 37, 249}, {236, 18, 17, 129}};
  int in[4][4] = {{31, 201, 251, 130}, {170, 211, 5, 129}, {150, 14, 37, 249}, {236, 18, 17, 129}};
  int in2[4][4] = {{0, 1, 1, 0}, {2, 0, 0, 0}, {0, 0, 0, 0}, {0, 0, 0, 0}};
  forward4x4(in, out, 0, 0);
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      printf("%2d ", out[i][j]);
    }
    printf("\n");
  }
  int coeffs[4][4] = {{1978, 34, 470, -318}, {491, -417, -1507, -526}, {48, -100, -392, 530}, {83, -1481, -91, 532}};
  inverse4x4(coeffs, out, 0, 0);
  printf("Inverse: \n");
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      printf("%5d ", out[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```