ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<procfs_lwp_enum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %edi,%ecx
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    D3(%rip),%rdx
  mov    $0x1000,%esi
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <procfs_enum_id@plt>
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x1010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string

tool: D3: /proc/%d/task

assistant: ```c
int procfs_lwp_enum(pid_t pid, int **lwps, int *num) {
  char path[4096];
  (void)snprintf(path, sizeof(path), "/proc/%d/task", pid);
  return (procfs_enum_id(path, lwps, num));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<procfs_lwp_enum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rsp,%r13
  mov    %edi,%ecx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x1000,%esi
  lea    D1(%rip),%rdx
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <procfs_enum_id@plt>
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x1010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
data_type: string

tool: D1: /proc/%d/task

assistant: ```c
int procfs_lwp_enum(pid_t pid, int **lwps, int *num) {
  char path[4096];
  (void)snprintf(path, sizeof(path), "/proc/%d/task", pid);
  return (procfs_enum_id(path, lwps, num));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<procfs_lwp_enum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rsp,%r13
  mov    %edi,%ecx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x1000,%esi
  lea    D6(%rip),%rdx
  mov    %r13,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <procfs_enum_id@plt>
  mov    0x1008(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x1010,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: /proc/%d/task

assistant: ```c
int procfs_lwp_enum(pid_t pid, int **lwps, int *num) {
  char path[4096];
  (void)snprintf(path, sizeof(path), "/proc/%d/task", pid);
  return (procfs_enum_id(path, lwps, num));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_circ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L27:
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  movsd  D19(%rip),%xmm0
  comisd %xmm1,%xmm0
  jb     L21
  mov    $0x0,%eax
  jmp    L19
L21:
  mov    $0x1,%eax
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D19
type_guessed: byte[8]

tool: D10: check_circ: invalid circle.

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int check_circ(double *cparam) {
  if (cparam == NULL)
    error("check_circ: invalid circle.");
  if (cparam[2] <= 1)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_circ>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L11
L14:
  movsd  D19(%rip),%xmm0
  comisd 0x10(%rbx),%xmm0
  setb   %al
  movzbl %al,%eax
  pop    %rbx
  ret
L11:
  lea    D7(%rip),%rdi
  call   <error@plt>
  jmp    L14
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D7: check_circ: invalid circle.

assistant: ```c
int check_circ(double *cparam) {
  if (cparam == NULL)
    error("check_circ: invalid circle.");
  if (cparam[2] <= 1)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_circ>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L4
L1:
  xor    %eax,%eax
  movsd  D19(%rip),%xmm0
  comisd 0x10(%rbx),%xmm0
  pop    %rbx
  setb   %al
  ret
  nopl   0x0(%rax)
L4:
  lea    D17(%rip),%rdi
  call   <error@plt>
  jmp    L1
```

tool_calls: name: read_data
arguments: label: D19
type: byte[8]
name: read_data
arguments: label: D17
type: string

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D17: check_circ: invalid circle.

assistant: ```c
int check_circ(double *cparam) {
  if (cparam == NULL)
    error("check_circ: invalid circle.");
  if (cparam[2] <= 1)
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_circ>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L13
L18:
  xor    %eax,%eax
  movsd  D0(%rip),%xmm0
  comisd 0x10(%rbx),%xmm0
  pop    %rbx
  setb   %al
  ret
  nopl   0x0(%rax)
L13:
  lea    D3(%rip),%rdi
  call   <error@plt>
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: byte[8]
name: retrieve_data
arguments: data_tag: D3
type: string

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D3: check_circ: invalid circle.

assistant: ```c
int check_circ(double *cparam) {
  if (cparam == NULL)
    error("check_circ: invalid circle.");
  if (cparam[2] <= 1)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bcmp_translate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rbx
  mov    -0x20(%rbp),%r12
  jmp    L18
L21:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L19
  mov    $0x1,%eax
  jmp    L24
L19:
  subl   $0x1,-0x24(%rbp)
L18:
  cmpl   $0x0,-0x24(%rbp)
  jne    L21
  mov    $0x0,%eax
L24:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int bcmp_translate(unsigned char *s1, unsigned char *s2, int len, char *translate) {
  register unsigned char *p1 = s1, *p2 = s2;
  while (len) {
    if (translate[*p1++] != translate[*p2++])
      return 1;
    len--;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bcmp_translate>:
  endbr64
  test   %edx,%edx
  je     L27
  mov    %edx,%eax
  mov    $0x0,%r8d
L22:
  movzbl (%rdi,%r8,1),%r10d
  movzbl (%rsi,%r8,1),%r9d
  movzbl (%rcx,%r9,1),%edx
  cmp    %dl,(%rcx,%r10,1)
  jne    L21
  add    $0x1,%r8
  cmp    %rax,%r8
  jne    L22
  mov    $0x0,%eax
  ret
L27:
  mov    %edx,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int bcmp_translate(unsigned char *s1, unsigned char *s2, int len, char *translate) {
  register unsigned char *p1 = s1, *p2 = s2;
  while (len) {
    if (translate[*p1++] != translate[*p2++])
      return 1;
    len--;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bcmp_translate>:
  endbr64
  test   %edx,%edx
  je     L16
  mov    %edx,%edx
  xor    %eax,%eax
  jmp    L38
  xchg   %ax,%ax
L28:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L16
L38:
  movzbl (%rsi,%rax,1),%r8d
  movzbl (%rdi,%rax,1),%r9d
  movzbl (%rcx,%r8,1),%r10d
  cmp    %r10b,(%rcx,%r9,1)
  je     L28
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bcmp_translate(unsigned char *s1, unsigned char *s2, int len, char *translate) {
  register unsigned char *p1 = s1, *p2 = s2;
  while (len) {
    if (translate[*p1++] != translate[*p2++])
      return 1;
    len--;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bcmp_translate>:
  endbr64
  test   %edx,%edx
  je     L11
  mov    %edx,%edx
  xor    %eax,%eax
  jmp    L5
  xchg   %ax,%ax
L8:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L11
L5:
  movzbl (%rsi,%rax,1),%r8d
  movzbl (%rdi,%rax,1),%r9d
  movzbl (%rcx,%r8,1),%r10d
  cmp    %r10b,(%rcx,%r9,1)
  je     L8
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int bcmp_translate(unsigned char *s1, unsigned char *s2, int len, char *translate) {
  register unsigned char *p1 = s1, *p2 = s2;
  while (len) {
    if (translate[*p1++] != translate[*p2++])
      return 1;
    len--;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basRight>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <popString@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <right@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <eFree@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <eFree@plt>
  nop
  leave
  ret
```

assistant: ```c
void basRight() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = right(string, pos);
  pushStringCopy(dest);
  eFree(string);
  eFree(dest);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<basRight>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <popString@plt>
  mov    %rax,%rbp
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <right@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <pushStringCopy@plt>
  mov    %rbp,%rdi
  call   <eFree@plt>
  mov    %rbx,%rdi
  call   <eFree@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void basRight() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = right(string, pos);
  pushStringCopy(dest);
  eFree(string);
  eFree(dest);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<basRight>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <popNumber@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <popString@plt>
  mov    %ebx,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <right@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <pushStringCopy@plt>
  mov    %r12,%rdi
  call   <eFree@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <eFree@plt>
```

assistant: ```c
void basRight() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = right(string, pos);
  pushStringCopy(dest);
  eFree(string);
  eFree(dest);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<basRight>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <popNumber@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <popString@plt>
  mov    %ebx,%esi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <right@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <pushStringCopy@plt>
  mov    %r12,%rdi
  call   <eFree@plt>
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10c0 <eFree@plt>
```

assistant: ```c
void basRight() {
  int pos;
  char *string;
  char *dest;
  pos = (int)popNumber();
  string = popString();
  dest = right(string, pos);
  pushStringCopy(dest);
  eFree(string);
  eFree(dest);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_reversed_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <merge_sort@plt>
  mov    -0x14(%rbp),%eax
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void test_reversed_list() {
  int array[] = {3, 2, 1};
  merge_sort(array, 0, 2);
  assert(array[0] == 1);
  assert(array[1] == 2);
  assert(array[2] == 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_reversed_list>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  lea    0xc(%rsp),%rdi
  mov    $0x2,%edx
  mov    $0x0,%esi
  call   <merge_sort@plt>
  cmpl   $0x1,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x2,0x10(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x3,0x14(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_reversed_list() {
  int array[] = {3, 2, 1};
  merge_sort(array, 0, 2);
  assert(array[0] == 1);
  assert(array[1] == 2);
  assert(array[2] == 3);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_reversed_list>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000003,%rax
  lea    0xc(%rsp),%rdi
  movl   $0x1,0x14(%rsp)
  mov    %rax,0xc(%rsp)
  call   <merge_sort@plt>
  xor    %edi,%edi
  cmpl   $0x1,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x2,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x14(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_reversed_list() {
  int array[] = {3, 2, 1};
  merge_sort(array, 0, 2);
  assert(array[0] == 1);
  assert(array[1] == 2);
  assert(array[2] == 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_reversed_list>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x8(%rsp),%rdi
  movl   $0x1,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  call   <merge_sort@plt>
  xor    %edi,%edi
  cmpl   $0x1,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x2,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmpl   $0x3,0x10(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: byte[8]

tool: {"D2": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
void test_reversed_list() {
  int array[] = {3, 2, 1};
  merge_sort(array, 0, 2);
  assert(array[0] == 1);
  assert(array[1] == 2);
  assert(array[2] == 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swapString2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swapString2(char **x, char **y) {
  char *t = *y;
  *y = *x;
  *x = t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swapString2>:
  endbr64
  mov    (%rsi),%rax
  mov    (%rdi),%rdx
  mov    %rdx,(%rsi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void swapString2(char **x, char **y) {
  char *t = *y;
  *y = *x;
  *x = t;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<swapString2>:
  endbr64
  mov    (%rsi),%rax
  mov    (%rdi),%rdx
  mov    %rdx,(%rsi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void swapString2(char **x, char **y) {
  char *t = *y;
  *y = *x;
  *x = t;
}
```
user: What is the c source code of the assembly code below?

```asm
<swapString2>:
  endbr64
  mov    (%rsi),%rax
  mov    (%rdi),%rdx
  mov    %rdx,(%rsi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void swapString2(char **x, char **y) {
  char *t = *y;
  *y = *x;
  *x = t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<data_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L65:
  movss  -0x24(%rbp),%xmm0
  movss  D24(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x24(%rbp)
  addl   $0x1,-0x18(%rbp)
L32:
  movss  -0x24(%rbp),%xmm0
  comiss D24(%rip),%xmm0
  jbe    L12
  cmpl   $0x3,-0x18(%rbp)
  jle    L65
L12:
  jmp    L35
L36:
  movss  -0x24(%rbp),%xmm1
  movss  D24(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x24(%rbp)
  subl   $0x1,-0x18(%rbp)
L35:
  movss  D2(%rip),%xmm0
  comiss -0x24(%rbp),%xmm0
  jbe    L59
  cmpl   $0xfffffffd,-0x18(%rbp)
  jge    L36
L59:
  movabs $0x474d6b206d756e70,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x54,-0xa(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x4,%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%edx
  mov    -0x38(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x30(%rbp),%rax
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D24
type_guessed: byte[4]
name: unpack_data
arguments: tag: D2
type_guessed: byte[4]

tool: {"D24": [0x00,0x00,0x80,0x44]}

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int data_to_string(float data, float *base, char *cexp) {
  int exp = 0;
  while ((data > (1 << 10)) && (exp < 4)) {
    data /= (1 << 10);
    exp++;
  }
  while ((data < 1) && (exp > -4)) {
    data *= (1 << 10);
    exp--;
  }
  char lexp[] = "pnum kMGT";
  *cexp = lexp[exp + 4];
  *base = data;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<data_to_string>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movss  D16(%rip),%xmm1
  comiss D46(%rip),%xmm0
  jbe    L20
L86:
  mulss  %xmm1,%xmm0
  add    $0x1,%eax
  cmp    $0x3,%eax
  jg     L10
  comiss D46(%rip),%xmm0
  ja     L86
L10:
  cmp    $0xfffffffd,%eax
  jl     L17
  movss  D10(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L17
  movss  D46(%rip),%xmm1
  movss  D10(%rip),%xmm2
L53:
  mulss  %xmm1,%xmm0
  sub    $0x1,%eax
  cmp    $0xfffffffd,%eax
  jl     L17
  comiss %xmm0,%xmm2
  ja     L53
L17:
  movabs $0x474d6b206d756e70,%rdx
  mov    %rdx,0xe(%rsp)
  movw   $0x54,0x16(%rsp)
  add    $0x4,%eax
  cltq
  movzbl 0xe(%rsp,%rax,1),%eax
  mov    %al,(%rsi)
  movss  %xmm0,(%rdi)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x1,%eax
  add    $0x28,%rsp
  ret
L20:
  mov    $0x0,%eax
  jmp    L10
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
data_type: byte[4]
name: unpack_data
arguments: tag: D46
data_type: byte[4]
name: unpack_data
arguments: tag: D10
data_type: byte[4]

tool: {"D16": [0x00,0x00,0x80,0x3a]}

tool: {"D46": [0x00,0x00,0x80,0x44]}

tool: {"D10": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int data_to_string(float data, float *base, char *cexp) {
  int exp = 0;
  while ((data > (1 << 10)) && (exp < 4)) {
    data /= (1 << 10);
    exp++;
  }
  while ((data < 1) && (exp > -4)) {
    data *= (1 << 10);
    exp--;
  }
  char lexp[] = "pnum kMGT";
  *cexp = lexp[exp + 4];
  *base = data;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<data_to_string>:
  endbr64
  sub    $0x28,%rsp
  movss  D51(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  comiss D12(%rip),%xmm0
  jbe    L62
L46:
  mulss  %xmm1,%xmm0
  add    $0x1,%eax
  comiss D12(%rip),%xmm0
  jbe    L15
  cmp    $0x4,%eax
  jne    L46
L15:
  movss  D45(%rip),%xmm1
  lea    0x4(%rax),%edx
  comiss %xmm0,%xmm1
  jbe    L82
L97:
  movss  D12(%rip),%xmm2
  jmp    L18
  nopl   0x0(%rax)
L14:
  cmp    $0xfffffffc,%eax
  je     L86
L18:
  mulss  %xmm2,%xmm0
  mov    %eax,%edx
  sub    $0x1,%eax
  comiss %xmm0,%xmm1
  ja     L14
  add    $0x3,%edx
L82:
  movabs $0x474d6b206d756e70,%rax
  movslq %edx,%rdx
  mov    %rax,0xe(%rsp)
  mov    $0x54,%eax
  mov    %ax,0x16(%rsp)
  movzbl 0xe(%rsp,%rdx,1),%eax
  mov    %al,(%rsi)
  movss  %xmm0,(%rdi)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    $0x1,%eax
  add    $0x28,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  xor    %edx,%edx
  jmp    L82
L62:
  movss  D45(%rip),%xmm1
  mov    $0x4,%edx
  comiss %xmm0,%xmm1
  ja     L97
  jmp    L82
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D51
data_type: byte[4]
name: extract_symbolic_data
arguments: data_label: D12
data_type: byte[4]
name: extract_symbolic_data
arguments: data_label: D45
data_type: byte[4]

tool: {"D51": [0x00,0x00,0x80,0x3a]}

tool: {"D12": [0x00,0x00,0x80,0x44]}

tool: {"D45": [0x00,0x00,0x80,0x3f]}

assistant: ```c
int data_to_string(float data, float *base, char *cexp) {
  int exp = 0;
  while ((data > (1 << 10)) && (exp < 4)) {
    data /= (1 << 10);
    exp++;
  }
  while ((data < 1) && (exp > -4)) {
    data *= (1 << 10);
    exp--;
  }
  char lexp[] = "pnum kMGT";
  *cexp = lexp[exp + 4];
  *base = data;
  return 1;
}
```