ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GrMapUTF8_Unicode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rdx,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%ebx
  mov    %rbp,%rax
  test   %rbp,%rbp
  je     L134
L62:
  mov    %rbp,%rax
  sub    %rbx,%rax
  movzbl (%r12,%rbx,1),%edx
  and    $0xffffffc0,%edx
  cmp    $0x80,%dl
  jne    L109
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L62
  mov    $0x0,%eax
  jmp    L134
L109:
  test   %rax,%rax
  je     L134
  lea    (%r12,%rbx,1),%r14
  movzbl (%r14),%eax
  test   %al,%al
  js     L3
  add    $0x1,%rbx
  movzbl %al,%eax
L106:
  mov    %rbx,0x0(%r13)
L134:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  movsbq %al,%rdi
  shl    $0x18,%rdi
  not    %rdi
  mov    $0x0,%eax
  call   <NumLeadingZeros@plt>
  sub    $0x1,%eax
  movslq %eax,%rsi
  cmp    $0x5,%rsi
  jbe    L44
  add    $0x1,%rbx
  mov    $0x0,%eax
  jmp    L106
L44:
  lea    0x1(%rbx),%rdi
  mov    $0x6,%ecx
  sub    %eax,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  and    (%r14),%al
  movzbl %al,%eax
  test   %rsi,%rsi
  jne    L114
  mov    %rdi,%rbx
  jmp    L106
L71:
  mov    %rbx,%rdi
L114:
  movzbl (%r12,%rdi,1),%edx
  mov    %edx,%ecx
  and    $0xffffffc0,%ecx
  cmp    $0x80,%cl
  jne    L33
  shl    $0x6,%rax
  lea    0x1(%rdi),%rbx
  and    $0x3f,%edx
  or     %rdx,%rax
  sub    $0x1,%rsi
  cmp    %rdi,%rbp
  je     L138
  test   %rsi,%rsi
  jne    L71
L138:
  test   %rsi,%rsi
  je     L106
  mov    %rbx,0x0(%r13)
  mov    $0x0,%eax
  jmp    L134
L33:
  mov    %rdi,0x0(%r13)
  mov    $0x0,%eax
  jmp    L134
```

assistant: ```c
unsigned long GrMapUTF8_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  unsigned long ulUnicode, ulToRead, ulIndex;
  assert(pulSkip);
  assert(pcSrcChar);
  ulUnicode = 0;
  ulIndex = 0;
  while (ulCount && ((unsigned char)pcSrcChar[ulIndex] & 0xC0) == 0x80) {
    ulIndex++;
    ulCount--;
  }
  if (!ulCount) {
    return (0);
  }
  if (!((unsigned char)(pcSrcChar[ulIndex]) & 0x80)) {
    ulUnicode = (unsigned char)(pcSrcChar[ulIndex++]) & 0x7F;
    ulToRead = 0;
  } else {
    ulToRead = NumLeadingZeros(~((unsigned long)pcSrcChar[ulIndex] << 24)) - 1;
    if (ulToRead > 5) {
      ulUnicode = 0;
      ulToRead = 0;
      ulIndex++;
    } else {
      ulUnicode = (unsigned char)pcSrcChar[ulIndex++] & ((1 << (6 - ulToRead)) - 1);
      while (ulCount && ulToRead) {
        if (((unsigned char)pcSrcChar[ulIndex] & 0xC0) != 0x80) {
          *pulSkip = ulIndex;
          return (0);
        } else {
          ulUnicode = ((ulUnicode << 6) | ((unsigned char)pcSrcChar[ulIndex++] & 0x3F));
          ulToRead--;
          ulCount--;
        }
      }
      if (ulToRead) {
        *pulSkip = ulIndex;
        return (0);
      }
    }
  }
  *pulSkip = ulIndex;
  return (ulUnicode);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<GrMapUTF8_Unicode>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <assert@plt>
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <assert@plt>
  test   %r12,%r12
  je     L58
  mov    %rbx,%r14
  mov    %r12,%rax
  lea    0x1(%r12),%rsi
  jmp    L28
  nop
L115:
  add    $0x1,%r14
  sub    $0x1,%rax
  je     L90
L28:
  movzbl (%r14),%edx
  mov    %rsi,%rbp
  sub    %rax,%rbp
  mov    %edx,%ecx
  and    $0xffffffc0,%ecx
  cmp    $0x80,%cl
  je     L115
  movsbq %dl,%rax
  test   %dl,%dl
  js     L66
L43:
  mov    %rbp,0x0(%r13)
L90:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  shl    $0x18,%rax
  not    %rax
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <NumLeadingZeros@plt>
  sub    $0x1,%eax
  movslq %eax,%rsi
  cmp    $0x5,%rsi
  ja     L75
  mov    $0x6,%ecx
  sub    %eax,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  and    (%r14),%al
  movzbl %al,%eax
  test   %rsi,%rsi
  jne    L123
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L26:
  shl    $0x6,%rax
  and    $0x3f,%edx
  lea    0x1(%rbp),%rcx
  sub    $0x1,%rsi
  or     %rdx,%rax
  cmp    %rbp,%r12
  je     L122
  test   %rsi,%rsi
  je     L142
  mov    %rcx,%rbp
L123:
  movzbl (%rbx,%rbp,1),%edx
  mov    %edx,%ecx
  and    $0xffffffc0,%ecx
  cmp    $0x80,%cl
  je     L26
  mov    %rbp,0x0(%r13)
  xor    %eax,%eax
  jmp    L90
L75:
  xor    %eax,%eax
  jmp    L43
L58:
  xor    %eax,%eax
  jmp    L90
L25:
  mov    %rbp,%rcx
L142:
  mov    %rcx,%rbp
  jmp    L43
L122:
  test   %rsi,%rsi
  je     L142
  mov    %rcx,0x0(%r13)
  xor    %eax,%eax
  jmp    L90
```

assistant: ```c
unsigned long GrMapUTF8_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  unsigned long ulUnicode, ulToRead, ulIndex;
  assert(pulSkip);
  assert(pcSrcChar);
  ulUnicode = 0;
  ulIndex = 0;
  while (ulCount && ((unsigned char)pcSrcChar[ulIndex] & 0xC0) == 0x80) {
    ulIndex++;
    ulCount--;
  }
  if (!ulCount) {
    return (0);
  }
  if (!((unsigned char)(pcSrcChar[ulIndex]) & 0x80)) {
    ulUnicode = (unsigned char)(pcSrcChar[ulIndex++]) & 0x7F;
    ulToRead = 0;
  } else {
    ulToRead = NumLeadingZeros(~((unsigned long)pcSrcChar[ulIndex] << 24)) - 1;
    if (ulToRead > 5) {
      ulUnicode = 0;
      ulToRead = 0;
      ulIndex++;
    } else {
      ulUnicode = (unsigned char)pcSrcChar[ulIndex++] & ((1 << (6 - ulToRead)) - 1);
      while (ulCount && ulToRead) {
        if (((unsigned char)pcSrcChar[ulIndex] & 0xC0) != 0x80) {
          *pulSkip = ulIndex;
          return (0);
        } else {
          ulUnicode = ((ulUnicode << 6) | ((unsigned char)pcSrcChar[ulIndex++] & 0x3F));
          ulToRead--;
          ulCount--;
        }
      }
      if (ulToRead) {
        *pulSkip = ulIndex;
        return (0);
      }
    }
  }
  *pulSkip = ulIndex;
  return (ulUnicode);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GrMapUTF8_Unicode>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <assert@plt>
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <assert@plt>
  test   %r12,%r12
  je     L38
  mov    %rbx,%r14
  mov    %r12,%rax
  lea    0x1(%r12),%rsi
  jmp    L132
  nop
L117:
  add    $0x1,%r14
  sub    $0x1,%rax
  je     L69
L132:
  movzbl (%r14),%edx
  mov    %rsi,%rbp
  sub    %rax,%rbp
  mov    %edx,%ecx
  and    $0xffffffc0,%ecx
  cmp    $0x80,%cl
  je     L117
  movsbq %dl,%rax
  test   %dl,%dl
  js     L82
L131:
  mov    %rbp,0x0(%r13)
L69:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L82:
  shl    $0x18,%rax
  not    %rax
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <NumLeadingZeros@plt>
  sub    $0x1,%eax
  movslq %eax,%rsi
  cmp    $0x5,%rsi
  ja     L133
  mov    $0x6,%ecx
  sub    %eax,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  and    (%r14),%al
  movzbl %al,%eax
  test   %rsi,%rsi
  jne    L19
  jmp    L148
  nopl   0x0(%rax,%rax,1)
L30:
  shl    $0x6,%rax
  and    $0x3f,%edx
  lea    0x1(%rbp),%rcx
  sub    $0x1,%rsi
  or     %rdx,%rax
  cmp    %rbp,%r12
  je     L97
  test   %rsi,%rsi
  je     L0
  mov    %rcx,%rbp
L19:
  movzbl (%rbx,%rbp,1),%edx
  mov    %edx,%ecx
  and    $0xffffffc0,%ecx
  cmp    $0x80,%cl
  je     L30
  mov    %rbp,0x0(%r13)
  xor    %eax,%eax
  jmp    L69
L133:
  xor    %eax,%eax
  jmp    L131
L38:
  xor    %eax,%eax
  jmp    L69
L148:
  mov    %rbp,%rcx
L0:
  mov    %rcx,%rbp
  jmp    L131
L97:
  test   %rsi,%rsi
  je     L0
  mov    %rcx,0x0(%r13)
  xor    %eax,%eax
  jmp    L69
```

assistant: ```c
unsigned long GrMapUTF8_Unicode(const char *pcSrcChar, unsigned long ulCount, unsigned long *pulSkip) {
  unsigned long ulUnicode, ulToRead, ulIndex;
  assert(pulSkip);
  assert(pcSrcChar);
  ulUnicode = 0;
  ulIndex = 0;
  while (ulCount && ((unsigned char)pcSrcChar[ulIndex] & 0xC0) == 0x80) {
    ulIndex++;
    ulCount--;
  }
  if (!ulCount) {
    return (0);
  }
  if (!((unsigned char)(pcSrcChar[ulIndex]) & 0x80)) {
    ulUnicode = (unsigned char)(pcSrcChar[ulIndex++]) & 0x7F;
    ulToRead = 0;
  } else {
    ulToRead = NumLeadingZeros(~((unsigned long)pcSrcChar[ulIndex] << 24)) - 1;
    if (ulToRead > 5) {
      ulUnicode = 0;
      ulToRead = 0;
      ulIndex++;
    } else {
      ulUnicode = (unsigned char)pcSrcChar[ulIndex++] & ((1 << (6 - ulToRead)) - 1);
      while (ulCount && ulToRead) {
        if (((unsigned char)pcSrcChar[ulIndex] & 0xC0) != 0x80) {
          *pulSkip = ulIndex;
          return (0);
        } else {
          ulUnicode = ((ulUnicode << 6) | ((unsigned char)pcSrcChar[ulIndex++] & 0x3F));
          ulToRead--;
          ulCount--;
        }
      }
      if (ulToRead) {
        *pulSkip = ulIndex;
        return (0);
      }
    }
  }
  *pulSkip = ulIndex;
  return (ulUnicode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gnargs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <onum@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outstr@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string

tool: D18: mov.l	&

tool: D12: ,%d3


assistant: ```c
gnargs(d) int d;
{
  ot("mov.l\t&");
  onum(d);
  outstr(",%d3\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<gnargs>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <onum@plt>
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <outstr@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
data_type: string
name: disassemble_data
arguments: label: D0
data_type: string

tool: D13: mov.l	&

tool: D0: ,%d3


assistant: ```c
gnargs(d) int d;
{
  ot("mov.l\t&");
  onum(d);
  outstr(",%d3\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gnargs>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  lea    D18(%rip),%rdi
  call   <ot@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <onum@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <outstr@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
type_infered: string
name: unpack_data
arguments: label: D1
type_infered: string

tool: D18: mov.l	&

tool: D1: ,%d3


assistant: ```c
gnargs(d) int d;
{
  ot("mov.l\t&");
  onum(d);
  outstr(",%d3\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gnargs>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  lea    D16(%rip),%rdi
  call   <ot@plt>
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <onum@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1070 <outstr@plt>
```

tool_calls: name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D3
data_type: string

tool: D16: mov.l	&

tool: D3: ,%d3


assistant: ```c
gnargs(d) int d;
{
  ot("mov.l\t&");
  onum(d);
  outstr(",%d3\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<imd_find_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imd_next@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L31
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imd_read_type@plt>
  cmp    %eax,-0xc(%rbp)
  jne    L26
  mov    -0x8(%rbp),%rax
  jmp    L14
L26:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imd_next@plt>
  mov    %rax,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <imd_read_type@plt>
  cmp    $0x640c7fff,%eax
  jne    L21
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
struct imd_header *imd_find_type(struct imd_header *imd, uint32_t type) {
  for (imd = imd_next(imd); imd_read_type(imd) != 0x640c7fff; imd = imd_next(imd))
    if (imd_read_type(imd) == type)
      return imd;
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imd_find_type>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  call   <imd_next@plt>
  mov    %rax,%rbx
  jmp    L28
L36:
  mov    %rbx,%rdi
  call   <imd_next@plt>
  mov    %rax,%rbx
L28:
  mov    %rbx,%rdi
  call   <imd_read_type@plt>
  cmp    $0x640c7fff,%eax
  je     L4
  mov    %rbx,%rdi
  call   <imd_read_type@plt>
  cmp    %ebp,%eax
  jne    L36
  jmp    L10
L4:
  mov    $0x0,%ebx
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct imd_header *imd_find_type(struct imd_header *imd, uint32_t type) {
  for (imd = imd_next(imd); imd_read_type(imd) != 0x640c7fff; imd = imd_next(imd))
    if (imd_read_type(imd) == type)
      return imd;
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imd_find_type>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <imd_next@plt>
  mov    %rax,%rbp
  jmp    L1
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rdi
  call   <imd_read_type@plt>
  cmp    %ebx,%eax
  je     L18
  mov    %rbp,%rdi
  call   <imd_next@plt>
  mov    %rax,%rbp
L1:
  mov    %rbp,%rdi
  call   <imd_read_type@plt>
  cmp    $0x640c7fff,%eax
  jne    L21
  xor    %ebp,%ebp
L18:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct imd_header *imd_find_type(struct imd_header *imd, uint32_t type) {
  for (imd = imd_next(imd); imd_read_type(imd) != 0x640c7fff; imd = imd_next(imd))
    if (imd_read_type(imd) == type)
      return imd;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<imd_find_type>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <imd_next@plt>
  mov    %rax,%rbp
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  call   <imd_read_type@plt>
  cmp    %ebx,%eax
  je     L13
  mov    %rbp,%rdi
  call   <imd_next@plt>
  mov    %rax,%rbp
L8:
  mov    %rbp,%rdi
  call   <imd_read_type@plt>
  cmp    $0x640c7fff,%eax
  jne    L14
  xor    %ebp,%ebp
L13:
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct imd_header *imd_find_type(struct imd_header *imd, uint32_t type) {
  for (imd = imd_next(imd); imd_read_type(imd) != 0x640c7fff; imd = imd_next(imd))
    if (imd_read_type(imd) == type)
      return imd;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L3:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
  subl   $0x1,-0x14(%rbp)
L18:
  cmpl   $0x0,-0x14(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int multiply(int a, int b) {
  int t = 0;
  for (; a > 0; a--) {
    t += b;
  }
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiply>:
  endbr64
  test   %edi,%edi
  jle    L0
  mov    %edi,%edx
L11:
  sub    $0x1,%edx
  jne    L11
  mov    %edi,%eax
  imul   %esi,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int multiply(int a, int b) {
  int t = 0;
  for (; a > 0; a--) {
    t += b;
  }
  return t;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply>:
  endbr64
  test   %edi,%edi
  jle    L0
  mov    %edi,%eax
  imul   %esi,%eax
  ret
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int multiply(int a, int b) {
  int t = 0;
  for (; a > 0; a--) {
    t += b;
  }
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<multiply>:
  endbr64
  test   %edi,%edi
  jle    L0
  mov    %edi,%eax
  imul   %esi,%eax
  ret
  xchg   %ax,%ax
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int multiply(int a, int b) {
  int t = 0;
  for (; a > 0; a--) {
    t += b;
  }
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<twoSum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L84
  mov    %rax,%rdx
  mov    $0x0,%eax
L18:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%r12d
  jne    L18
L84:
  sub    $0x1,%r12d
  mov    %r12d,%ecx
  mov    $0x0,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sort@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r9
  mov    $0x0,%edi
  jmp    L4
L42:
  mov    %eax,%edi
  lea    0x0(,%rax,4),%r8
  mov    0x0(%rbp,%rax,4),%ecx
  add    $0x1,%rax
  lea    (%rcx,%rdx,1),%esi
  cmp    %ebx,%esi
  jl     L42
L8:
  add    %ecx,%edx
  cmp    %edx,%ebx
  jge    L54
  lea    -0x1(%r12),%eax
  cltq
L95:
  mov    %eax,%r12d
  lea    0x0(,%rax,4),%r10
  mov    %ecx,%edx
  add    0x0(%rbp,%rax,4),%edx
  sub    $0x1,%rax
  cmp    %ebx,%edx
  jg     L95
L54:
  cmp    %edx,%ebx
  je     L80
L4:
  cmp    %r12d,%edi
  jge    L82
  movslq %edi,%rax
  lea    0x0(,%rax,4),%r8
  mov    0x0(%rbp,%rax,4),%ecx
  movslq %r12d,%rax
  lea    0x0(,%rax,4),%r10
  mov    0x0(%rbp,%rax,4),%edx
  lea    (%rcx,%rdx,1),%esi
  lea    0x1(%rdi),%eax
  cltq
  cmp    %esi,%ebx
  jg     L42
  jmp    L8
L80:
  mov    %r9,%rdx
  add    %r13,%r10
  add    %r8,%r13
  mov    (%r10),%eax
  mov    0x0(%r13),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%r9)
  mov    (%r10),%eax
  mov    0x0(%r13),%ecx
  cmp    %ecx,%eax
  cmovl  %ecx,%eax
  mov    %eax,0x4(%r9)
L82:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *twoSum(int *nums, int size, int target) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  for (int i = 0; i < size; i++)
    indexes[i] = i;
  sort(nums, indexes, 0, size - 1);
  int *result = (int *)malloc(sizeof(int) * 2);
  int l = 0, r = size - 1;
  while (l < r) {
    while (nums[l] + nums[r] < target)
      l++;
    while (nums[l] + nums[r] > target)
      r--;
    if (nums[l] + nums[r] == target) {
      result[0] = ((indexes[l]) < (indexes[r]) ? (indexes[l]) : (indexes[r]));
      result[1] = ((indexes[l]) > (indexes[r]) ? (indexes[l]) : (indexes[r]));
      return result;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<twoSum>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    0x0(,%rsi,4),%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %r12d,%r12d
  jle    L38
  nop
L66:
  mov    %eax,(%rdx)
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %eax,%r12d
  jne    L66
L38:
  sub    $0x1,%r12d
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  call   <sort@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  xchg   %ax,%ax
L76:
  cmp    %r12d,%edi
  jge    L45
  movslq %edi,%rdx
  mov    0x0(%rbp,%rdx,4),%esi
  lea    0x0(,%rdx,4),%r10
  movslq %r12d,%rdx
  mov    0x0(%rbp,%rdx,4),%r8d
  lea    0x0(,%rdx,4),%r9
  lea    0x1(%rdi),%edx
  movslq %edx,%rdx
  lea    (%r8,%rsi,1),%ecx
  cmp    %ecx,%ebx
  jle    L69
  cs nopw 0x0(%rax,%rax,1)
L67:
  mov    0x0(%rbp,%rdx,4),%esi
  mov    %edx,%edi
  lea    0x0(,%rdx,4),%r10
  add    $0x1,%rdx
  lea    (%rsi,%r8,1),%ecx
  cmp    %ebx,%ecx
  jl     L67
L69:
  cmp    %ecx,%ebx
  jge    L28
  lea    -0x1(%r12),%edx
  movslq %edx,%rdx
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %edx,%r12d
  lea    0x0(,%rdx,4),%r9
  sub    $0x1,%rdx
  add    %esi,%ecx
  cmp    %ebx,%ecx
  jg     L46
L28:
  cmp    %ecx,%ebx
  jne    L76
  add    %r13,%r9
  add    %r10,%r13
  mov    0x0(%r13),%ecx
  mov    (%r9),%edx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  mov    %edx,(%rax)
  mov    (%r9),%edx
  mov    0x0(%r13),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  mov    %edx,0x4(%rax)
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *twoSum(int *nums, int size, int target) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  for (int i = 0; i < size; i++)
    indexes[i] = i;
  sort(nums, indexes, 0, size - 1);
  int *result = (int *)malloc(sizeof(int) * 2);
  int l = 0, r = size - 1;
  while (l < r) {
    while (nums[l] + nums[r] < target)
      l++;
    while (nums[l] + nums[r] > target)
      r--;
    if (nums[l] + nums[r] == target) {
      result[0] = ((indexes[l]) < (indexes[r]) ? (indexes[l]) : (indexes[r]));
      result[1] = ((indexes[l]) > (indexes[r]) ? (indexes[l]) : (indexes[r]));
      return result;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<execcmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <trace@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: execcmd: cmd=%s


assistant: ```c
extern int execcmd(const char *cmd) {
  trace(3, "execcmd: cmd=%s\n", cmd);
  return system(cmd);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<execcmd>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rdx
  lea    D9(%rip),%rsi
  mov    $0x3,%edi
  call   <trace@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D9
type: string

tool: D9: execcmd: cmd=%s


assistant: ```c
extern int execcmd(const char *cmd) {
  trace(3, "execcmd: cmd=%s\n", cmd);
  return system(cmd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<execcmd>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %rdi,%rbp
  lea    D5(%rip),%rsi
  mov    $0x3,%edi
  call   <trace@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <system@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: execcmd: cmd=%s


assistant: ```c
extern int execcmd(const char *cmd) {
  trace(3, "execcmd: cmd=%s\n", cmd);
  return system(cmd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<execcmd>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    %rdi,%rbp
  lea    D3(%rip),%rsi
  mov    $0x3,%edi
  call   <trace@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <system@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: execcmd: cmd=%s


assistant: ```c
extern int execcmd(const char *cmd) {
  trace(3, "execcmd: cmd=%s\n", cmd);
  return system(cmd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <mcu_init@plt>
L5:
  mov    $0x1,%edi
  call   <motor_control@plt>
  mov    $0x1f4,%edi
  call   <delay_ms@plt>
  mov    $0x4,%edi
  call   <motor_control@plt>
  mov    $0x64,%edi
  call   <delay_ms@plt>
  mov    $0x1,%edi
  call   <motor_control@plt>
  mov    $0x1f4,%edi
  call   <delay_ms@plt>
  mov    $0x3,%edi
  call   <motor_control@plt>
  mov    $0x64,%edi
  call   <delay_ms@plt>
  mov    $0x2,%edi
  call   <motor_control@plt>
  mov    $0x1f4,%edi
  call   <delay_ms@plt>
  mov    $0x5,%edi
  call   <motor_control@plt>
  jmp    L5
```

assistant: ```c
void main() {
  mcu_init();
  while (1) {
    motor_control(1);
    delay_ms(500);
    motor_control(4);
    delay_ms(100);
    motor_control(1);
    delay_ms(500);
    motor_control(3);
    delay_ms(100);
    motor_control(2);
    delay_ms(500);
    motor_control(5);
  }
}
```