ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<_crc_ibutton_update>:
  endbr64
  xor    %esi,%edi
  mov    %edi,%eax
  sar    %eax
  mov    %eax,%edx
  xor    $0x8c,%dl
  and    $0x1,%edi
  cmovne %edx,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%ecx
  xor    $0x8c,%cl
  test   $0x1,%al
  cmovne %ecx,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  xor    $0x8c,%cl
  and    $0x1,%edx
  cmovne %ecx,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%ecx
  xor    $0x8c,%cl
  test   $0x1,%al
  cmovne %ecx,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  xor    $0x8c,%cl
  and    $0x1,%edx
  cmovne %ecx,%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%ecx
  xor    $0x8c,%cl
  test   $0x1,%al
  cmovne %ecx,%edx
  mov    %edx,%eax
  sar    %eax
  mov    %eax,%ecx
  xor    $0x8c,%cl
  and    $0x1,%edx
  cmovne %ecx,%eax
  mov    %eax,%r8d
  sar    %r8d
  mov    %r8d,%edx
  xor    $0x8c,%dl
  test   $0x1,%al
  cmovne %edx,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint8_t _crc_ibutton_update(uint8_t crc, uint8_t data) {
  uint8_t i;
  crc = crc ^ data;
  for (i = 0; i < 8; i++) {
    if (crc & 0x01)
      crc = (crc >> 1) ^ 0x8C;
    else
      crc >>= 1;
  }
  return crc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7473657474736574,%rax
  mov    %rax,-0x1c(%rbp)
  movw   $0x0,-0x14(%rbp)
  movq   $0x6573,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x12(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <squeeze@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: %s


assistant: ```c
main() {
  char s1[10] = "testtest";
  char s2[10] = "se";
  printf("%s\n", s1);
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x7473657474736574,%rax
  mov    %rax,0x4(%rsp)
  movw   $0x0,0xc(%rsp)
  movq   $0x6573,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rsi
  mov    %rbx,%rdi
  call   <squeeze@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D1: %s


assistant: ```c
main() {
  char s1[10] = "testtest";
  char s2[10] = "se";
  printf("%s\n", s1);
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  xor    %edx,%edx
  push   %rbp
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x7473657474736574,%rax
  lea    0x4(%rsp),%rbp
  mov    %dx,0x16(%rsp)
  movq   $0x6573,0xe(%rsp)
  mov    %rbp,%rsi
  mov    %rax,0x4(%rsp)
  xor    %eax,%eax
  mov    %ax,0xc(%rsp)
  call   <printf@plt>
  lea    0xe(%rsp),%rsi
  mov    %rbp,%rdi
  call   <squeeze@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9: %s


assistant: ```c
main() {
  char s1[10] = "testtest";
  char s2[10] = "se";
  printf("%s\n", s1);
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%r12
  xor    %edx,%edx
  push   %rbp
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x7473657474736574,%rax
  lea    0x4(%rsp),%rbp
  mov    %dx,0x16(%rsp)
  movq   $0x6573,0xe(%rsp)
  mov    %rbp,%rsi
  mov    %rax,0x4(%rsp)
  xor    %eax,%eax
  mov    %ax,0xc(%rsp)
  call   <printf@plt>
  lea    0xe(%rsp),%rsi
  mov    %rbp,%rdi
  call   <squeeze@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: %s


assistant: ```c
main() {
  char s1[10] = "testtest";
  char s2[10] = "se";
  printf("%s\n", s1);
  squeeze(s1, s2);
  printf("%s\n", s1);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hstr_chop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L11
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L1
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  nop
  leave
  ret
```

assistant: ```c
void hstr_chop(char *s) {
  if (s) {
    int i = strlen(s);
    if (i) {
      if (1 << 7 & s[i - 1]) {
        s[i - 2] = 0;
      } else {
        s[i - 1] = 0;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hstr_chop>:
  endbr64
  test   %rdi,%rdi
  je     L12
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L1
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  cmpb   $0x0,(%rdx)
  js     L11
  movb   $0x0,(%rdx)
L1:
  pop    %rbx
  ret
L11:
  movb   $0x0,-0x2(%rbx,%rax,1)
  jmp    L1
L12:
  ret
```

assistant: ```c
void hstr_chop(char *s) {
  if (s) {
    int i = strlen(s);
    if (i) {
      if (1 << 7 & s[i - 1]) {
        s[i - 2] = 0;
      } else {
        s[i - 1] = 0;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hstr_chop>:
  endbr64
  test   %rdi,%rdi
  je     L28
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L0
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  cmpb   $0x0,(%rdx)
  js     L10
  movb   $0x0,(%rdx)
L0:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  ret
  nopl   0x0(%rax)
L10:
  movb   $0x0,-0x2(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void hstr_chop(char *s) {
  if (s) {
    int i = strlen(s);
    if (i) {
      if (1 << 7 & s[i - 1]) {
        s[i - 2] = 0;
      } else {
        s[i - 1] = 0;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hstr_chop>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L4
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  cmpb   $0x0,(%rdx)
  js     L16
  movb   $0x0,(%rdx)
L4:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  ret
  nopl   0x0(%rax)
L16:
  movb   $0x0,-0x2(%rbx,%rax,1)
  pop    %rbx
  ret
```

assistant: ```c
void hstr_chop(char *s) {
  if (s) {
    int i = strlen(s);
    if (i) {
      if (1 << 7 & s[i - 1]) {
        s[i - 2] = 0;
      } else {
        s[i - 1] = 0;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x63,-0x4(%rbp)
  movb   $0x73,-0x5(%rbp)
  jmp    L58
L59:
  cmpl   $0x1,-0x4(%rbp)
  jne    L56
  mov    $0x1f,%eax
  jmp    L52
L56:
  mov    $0x73,%eax
L52:
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L58
L29:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    $0x0,%eax
  jmp    L57
L58:
  movsbl -0x5(%rbp),%esi
  movsbl -0x5(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  jmp    L59
L57:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D39
type: string
name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D38
type: string
name: unpack_data
arguments: label: D49
type: string
name: unpack_data
arguments: label: D20
type: string

tool: D39: %d bottle%c of beer on the wall!


tool: D4: no more bottles of beer on the wall!

tool: D38: No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall!

tool: D49: %d bottle%c of beer on the wall, %d bottle%c of beer


tool: D20: Take one down and pass it around, 

assistant: ```c
int main() {
  int n_beers = 99;
  char pl = 's';
  goto a;
z:
  return 0;
b:
  n_beers--;
  if (n_beers) {
    pl = (n_beers == 1 ? 31 : 's');
    printf("%d bottle%c of beer on the wall!\n", n_beers, pl);
    goto a;
  } else {
    printf("no more bottles of beer on the wall!\n");
    printf("No more bottles of beer on the wall,"
           " no more bottles of beer.\nGo to the store"
           " and buy some more, 99 bottles of beer on the wall!\n");
    goto z;
  }
a:
  printf("%d bottle%c of beer on the wall, "
         "%d bottle%c of beer\n",
         n_beers, pl, n_beers, pl);
  printf("Take one down and pass it around, ");
  goto b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x73,%r8d
  mov    $0x63,%ecx
  mov    $0x73,%edx
  mov    $0x63,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x62,%ebp
  mov    $0x73,%ebx
  lea    D1(%rip),%r14
  lea    D6(%rip),%r13
  lea    D5(%rip),%r12
  mov    $0x1f,%r15d
L11:
  movsbl %bl,%ebx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebp
  je     L3
  cmp    $0x1,%ebp
  mov    $0x73,%ebx
  cmove  %r15d,%ebx
  jmp    L11
L3:
  lea    D50(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string
name: unpack_data
arguments: data_tag: D50
type_guessed: string
name: unpack_data
arguments: data_tag: D26
type_guessed: string

tool: D6: %d bottle%c of beer on the wall, %d bottle%c of beer


tool: D5: Take one down and pass it around, 

tool: D1: %d bottle%c of beer on the wall!


tool: D50: no more bottles of beer on the wall!

tool: D26: No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall!

assistant: ```c
int main() {
  int n_beers = 99;
  char pl = 's';
  goto a;
z:
  return 0;
b:
  n_beers--;
  if (n_beers) {
    pl = (n_beers == 1 ? 31 : 's');
    printf("%d bottle%c of beer on the wall!\n", n_beers, pl);
    goto a;
  } else {
    printf("no more bottles of beer on the wall!\n");
    printf("No more bottles of beer on the wall,"
           " no more bottles of beer.\nGo to the store"
           " and buy some more, 99 bottles of beer on the wall!\n");
    goto z;
  }
a:
  printf("%d bottle%c of beer on the wall, "
         "%d bottle%c of beer\n",
         n_beers, pl, n_beers, pl);
  printf("Take one down and pass it around, ");
  goto b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x73,%r8d
  mov    $0x63,%ecx
  xor    %eax,%eax
  push   %r14
  mov    $0x73,%edx
  mov    $0x63,%esi
  mov    $0x62,%r15d
  push   %r13
  mov    $0x1f,%r14d
  lea    D20(%rip),%r13
  push   %r12
  mov    $0x73,%r12d
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  lea    D16(%rip),%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
  nopl   0x0(%rax)
L14:
  cmp    $0x1,%r15d
  mov    $0x73,%r12d
  cmove  %r14d,%r12d
L9:
  mov    %r15d,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%ecx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12d,%r8d
  mov    %r12d,%edx
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  sub    $0x1,%r15d
  jne    L14
  lea    D9(%rip),%rdi
  call   <puts@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
datatype: string
name: unpack_data
arguments: tag: D1
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D9
datatype: string
name: unpack_data
arguments: tag: D24
datatype: string

tool: D20: %d bottle%c of beer on the wall!


tool: D1: %d bottle%c of beer on the wall, %d bottle%c of beer


tool: D16: Take one down and pass it around, 

tool: D9: no more bottles of beer on the wall!

tool: D24: No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall!

assistant: ```c
int main() {
  int n_beers = 99;
  char pl = 's';
  goto a;
z:
  return 0;
b:
  n_beers--;
  if (n_beers) {
    pl = (n_beers == 1 ? 31 : 's');
    printf("%d bottle%c of beer on the wall!\n", n_beers, pl);
    goto a;
  } else {
    printf("no more bottles of beer on the wall!\n");
    printf("No more bottles of beer on the wall,"
           " no more bottles of beer.\nGo to the store"
           " and buy some more, 99 bottles of beer on the wall!\n");
    goto z;
  }
a:
  printf("%d bottle%c of beer on the wall, "
         "%d bottle%c of beer\n",
         n_beers, pl, n_beers, pl);
  printf("Take one down and pass it around, ");
  goto b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x73,%r8d
  mov    $0x63,%ecx
  xor    %eax,%eax
  push   %r14
  mov    $0x73,%edx
  mov    $0x63,%esi
  mov    $0x62,%r15d
  push   %r13
  mov    $0x1f,%r14d
  lea    D46(%rip),%r13
  push   %r12
  mov    $0x73,%r12d
  push   %rbp
  lea    D44(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  lea    D31(%rip),%rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
  nopl   0x0(%rax)
L11:
  cmp    $0x1,%r15d
  mov    $0x73,%r12d
  cmove  %r14d,%r12d
L13:
  mov    %r15d,%esi
  mov    %r12d,%edx
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%ecx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    %r12d,%r8d
  mov    %r12d,%edx
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <printf@plt>
  sub    $0x1,%r15d
  jne    L11
  lea    D35(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D46
type_infered: string
name: retrieve_data
arguments: tag: D44
type_infered: string
name: retrieve_data
arguments: tag: D31
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string

tool: D46: %d bottle%c of beer on the wall!


tool: D44: %d bottle%c of beer on the wall, %d bottle%c of beer


tool: D31: Take one down and pass it around, 

tool: D35: no more bottles of beer on the wall!

tool: D20: No more bottles of beer on the wall, no more bottles of beer.
Go to the store and buy some more, 99 bottles of beer on the wall!

assistant: ```c
int main() {
  int n_beers = 99;
  char pl = 's';
  goto a;
z:
  return 0;
b:
  n_beers--;
  if (n_beers) {
    pl = (n_beers == 1 ? 31 : 's');
    printf("%d bottle%c of beer on the wall!\n", n_beers, pl);
    goto a;
  } else {
    printf("no more bottles of beer on the wall!\n");
    printf("No more bottles of beer on the wall,"
           " no more bottles of beer.\nGo to the store"
           " and buy some more, 99 bottles of beer on the wall!\n");
    goto z;
  }
a:
  printf("%d bottle%c of beer on the wall, "
         "%d bottle%c of beer\n",
         n_beers, pl, n_beers, pl);
  printf("Take one down and pass it around, ");
  goto b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atanl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  fldz
  fstpt  -0x10(%rbp)
  fldt   0x10(%rbp)
  fld1
  fpatan
  fstpt  -0x10(%rbp)
  fldt   -0x10(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
long double atanl(long double x) {
  long double res = 0.0L;
  asm volatile("fld1\n\t"
               "fpatan"
               : "=t"(res)
               : "0"(x));
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<atanl>:
  endbr64
  fldt   0x8(%rsp)
  fld1
  fpatan
  ret
```

assistant: ```c
long double atanl(long double x) {
  long double res = 0.0L;
  asm volatile("fld1\n\t"
               "fpatan"
               : "=t"(res)
               : "0"(x));
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atanl>:
  endbr64
  fldt   0x8(%rsp)
  fld1
  fpatan
  ret
```

assistant: ```c
long double atanl(long double x) {
  long double res = 0.0L;
  asm volatile("fld1\n\t"
               "fpatan"
               : "=t"(res)
               : "0"(x));
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atanl>:
  endbr64
  fldt   0x8(%rsp)
  fld1
  fpatan
  ret
```

assistant: ```c
long double atanl(long double x) {
  long double res = 0.0L;
  asm volatile("fld1\n\t"
               "fpatan"
               : "=t"(res)
               : "0"(x));
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<LU_decomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L15:
  mov    -0x14(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L5
L44:
  mov    -0x1c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L34
L42:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L42
  addl   $0x1,-0x1c(%rbp)
L5:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L44
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LU_decomp(int const n, int const lda, double *const A) {
  int i, j, k;
  for (k = 0; k < n; k++) {
    double *const Ak = A + k * lda;
    for (i = k + 1; i < n; i++) {
      double *const Ai = A + i * lda;
      Ai[k] /= Ak[k];
      for (j = k + 1; j < n; j++)
        Ai[j] -= Ai[k] * Ak[j];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<LU_decomp>:
  endbr64
  test   %edi,%edi
  jle    L26
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ecx
  mov    %rdx,%rbp
  mov    %rdx,%r12
  movslq %esi,%r11
  lea    0x8(,%r11,8),%r14
  mov    %edi,%r13d
  shl    $0x3,%r11
  mov    $0x1,%ebx
L16:
  mov    %r12,%rdi
  mov    %ebx,%r9d
  cmp    %r13,%rbx
  je     L7
  lea    (%r11,%rbp,1),%r8
  add    %r11,%r12
  mov    %r12,%r10
L38:
  mov    %r10,%rdx
  mov    %r8,%rsi
  movsd  (%r8),%xmm0
  divsd  0x0(%rbp),%xmm0
  movsd  %xmm0,(%r8)
  mov    %rbx,%rax
L15:
  movsd  (%rsi),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  movsd  (%rdx,%rax,8),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L15
  add    $0x1,%r9d
  add    %r11,%r8
  add    %r11,%r10
  cmp    %r9d,%ecx
  jne    L38
  add    $0x1,%rbx
  add    %r14,%rbp
  jmp    L16
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  ret
```

assistant: ```c
void LU_decomp(int const n, int const lda, double *const A) {
  int i, j, k;
  for (k = 0; k < n; k++) {
    double *const Ak = A + k * lda;
    for (i = k + 1; i < n; i++) {
      double *const Ai = A + i * lda;
      Ai[k] /= Ak[k];
      for (j = k + 1; j < n; j++)
        Ai[j] -= Ai[k] * Ak[j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LU_decomp>:
  endbr64
  test   %edi,%edi
  jle    L50
  movslq %esi,%rax
  push   %r12
  mov    $0x1,%r10d
  mov    %rdx,%r11
  push   %rbp
  lea    0x0(,%rax,8),%r9
  movslq %edi,%rbp
  mov    %r10d,%r8d
  push   %rbx
  mov    %rdx,%rbx
  lea    0x8(%r9),%r12
  mov    %rbx,%rsi
  cmp    %rbp,%r10
  je     L10
  nopl   0x0(%rax)
L23:
  add    %r9,%rbx
  lea    (%r9,%r11,1),%rcx
  mov    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L32:
  movsd  (%rcx),%xmm0
  mov    %r10,%rax
  divsd  (%r11),%xmm0
  movsd  %xmm0,(%rcx)
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L14:
  movsd  (%rcx),%xmm0
L44:
  mulsd  (%rsi,%rax,8),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L14
  add    $0x1,%r8d
  add    %r9,%rcx
  add    %r9,%rdx
  cmp    %r8d,%edi
  jne    L32
  add    $0x1,%r10
  add    %r12,%r11
  mov    %rbx,%rsi
  mov    %r10d,%r8d
  cmp    %rbp,%r10
  jne    L23
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  ret
```

assistant: ```c
void LU_decomp(int const n, int const lda, double *const A) {
  int i, j, k;
  for (k = 0; k < n; k++) {
    double *const Ak = A + k * lda;
    for (i = k + 1; i < n; i++) {
      double *const Ai = A + i * lda;
      Ai[k] /= Ak[k];
      for (j = k + 1; j < n; j++)
        Ai[j] -= Ai[k] * Ak[j];
    }
  }
}
```