ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xf,-0xc(%rbp)
  movl   $0xc,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D0
type: string

tool: D4: The height is %d, the width is %d.


tool: D0: And the area is : %d 


assistant: ```c
int main() {
  int height = 15;
  int width = 12;
  int area;
  area = height * width;
  printf("The height is %d, the width is %d.\n", height, width);
  printf("And the area is : %d \n", area);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edx
  mov    $0xf,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb4,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D5
type_infered: string

tool: D13: The height is %d, the width is %d.


tool: D5: And the area is : %d 


assistant: ```c
int main() {
  int height = 15;
  int width = 12;
  int area;
  area = height * width;
  printf("The height is %d, the width is %d.\n", height, width);
  printf("And the area is : %d \n", area);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edx
  mov    $0xf,%esi
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0xb4,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D6
type: string

tool: D15: The height is %d, the width is %d.


tool: D6: And the area is : %d 


assistant: ```c
int main() {
  int height = 15;
  int width = 12;
  int area;
  area = height * width;
  printf("The height is %d, the width is %d.\n", height, width);
  printf("And the area is : %d \n", area);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%edx
  mov    $0xf,%esi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xb4,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D1: The height is %d, the width is %d.


tool: D9: And the area is : %d 


assistant: ```c
int main() {
  int height = 15;
  int width = 12;
  int area;
  area = height * width;
  printf("The height is %d, the width is %d.\n", height, width);
  printf("And the area is : %d \n", area);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maybe_dup2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L21
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L21
  mov    $0x0,%eax
  jmp    L45
L21:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <dup2@plt>
  cmp    %eax,-0x8(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L45
L17:
  mov    $0xffffffff,%eax
L45:
  leave
  ret
```

assistant: ```c
int maybe_dup2(int oldfd, int newfd, fd_set *ignore) {
  if (ignore && FD_ISSET(newfd, ignore)) {
    return 0;
  }
  return dup2(oldfd, newfd) == newfd ? 0 : -1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<maybe_dup2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  test   %rdx,%rdx
  je     L11
  mov    %rdx,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L7
L11:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <dup2@plt>
  cmp    %ebx,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int maybe_dup2(int oldfd, int newfd, fd_set *ignore) {
  if (ignore && FD_ISSET(newfd, ignore)) {
    return 0;
  }
  return dup2(oldfd, newfd) == newfd ? 0 : -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<maybe_dup2>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L14
  mov    %rdx,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L17
L14:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <dup2@plt>
  cmp    %ebx,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  neg    %eax
  ret
  nopl   0x0(%rax)
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int maybe_dup2(int oldfd, int newfd, fd_set *ignore) {
  if (ignore && FD_ISSET(newfd, ignore)) {
    return 0;
  }
  return dup2(oldfd, newfd) == newfd ? 0 : -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<maybe_dup2>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L2
  mov    %rdx,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L10
L2:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <dup2@plt>
  cmp    %ebx,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  neg    %eax
  ret
  nopl   0x0(%rax)
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int maybe_dup2(int oldfd, int newfd, fd_set *ignore) {
  if (ignore && FD_ISSET(newfd, ignore)) {
    return 0;
  }
  return dup2(oldfd, newfd) == newfd ? 0 : -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<MAX7219CleanScreen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L14:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <MAX7219WriteByte@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x7,-0xc(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int MAX7219CleanScreen() {
  int i, address, data;
  data = 0;
  for (i = 0; i < 8; i++) {
    address = i + 1;
    MAX7219WriteByte(0, address, data);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<MAX7219CleanScreen>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
L7:
  add    $0x1,%ebx
  mov    $0x0,%edx
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <MAX7219WriteByte@plt>
  cmp    $0x8,%ebx
  jne    L7
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int MAX7219CleanScreen() {
  int i, address, data;
  data = 0;
  for (i = 0; i < 8; i++) {
    address = i + 1;
    MAX7219WriteByte(0, address, data);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<MAX7219CleanScreen>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%ebx
  xor    %edx,%edx
  xor    %edi,%edi
  mov    %ebx,%esi
  call   <MAX7219WriteByte@plt>
  cmp    $0x8,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int MAX7219CleanScreen() {
  int i, address, data;
  data = 0;
  for (i = 0; i < 8; i++) {
    address = i + 1;
    MAX7219WriteByte(0, address, data);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MAX7219CleanScreen>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%ebx
  xor    %edx,%edx
  xor    %edi,%edi
  mov    %ebx,%esi
  call   <MAX7219WriteByte@plt>
  cmp    $0x8,%ebx
  jne    L0
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int MAX7219CleanScreen() {
  int i, address, data;
  data = 0;
  for (i = 0; i < 8; i++) {
    address = i + 1;
    MAX7219WriteByte(0, address, data);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<num_inversions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x0,-0x2(%rbp)
  movw   $0x0,-0x6(%rbp)
  jmp    L20
L22:
  movzwl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4(%rbp)
  jmp    L69
L66:
  movswq -0x6(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  je     L0
  movswq -0x4(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  je     L0
  movswq -0x6(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%edx
  movswq -0x4(%rbp),%rax
  lea    (%rax,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzwl (%rax),%eax
  cmp    %ax,%dx
  jle    L46
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
  jmp    L46
L0:
  nop
L46:
  movzwl -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x4(%rbp)
L69:
  cmpw   $0xf,-0x4(%rbp)
  jle    L66
  movzwl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x6(%rbp)
L20:
  cmpw   $0xf,-0x6(%rbp)
  jle    L22
  movzwl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
short num_inversions(short *puzzle) {
  short i, j;
  short result = 0;
  for (i = 0; i < 16; i++) {
    for (j = i + 1; j < 16; j++) {
      if (puzzle[i] == 0 || puzzle[j] == 0)
        continue;
      if (puzzle[i] > puzzle[j])
        result += 1;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<num_inversions>:
  endbr64
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  mov    $0x0,%esi
  mov    $0x1,%edx
  jmp    L64
L57:
  lea    0x1(%rdx),%eax
  mov    %eax,%edx
  cmp    $0xf,%ax
  jg     L63
L64:
  movswq %r8w,%rax
  movzwl (%rdi,%rax,2),%eax
  test   %ax,%ax
  je     L57
  movswq %dx,%rcx
  movzwl (%rdi,%rcx,2),%ecx
  cmp    %cx,%ax
  jle    L57
  test   %cx,%cx
  setne  %cl
  lea    0x1(%rsi),%eax
  test   %cl,%cl
  cmovne %eax,%esi
  jmp    L57
L63:
  lea    0x1(%r9),%eax
  mov    %eax,%edx
  cmp    $0xf,%ax
  jg     L66
  mov    %r9d,%r8d
  mov    %eax,%r9d
  jmp    L64
L66:
  mov    %esi,%eax
  ret
```

assistant: ```c
short num_inversions(short *puzzle) {
  short i, j;
  short result = 0;
  for (i = 0; i < 16; i++) {
    for (j = i + 1; j < 16; j++) {
      if (puzzle[i] == 0 || puzzle[j] == 0)
        continue;
      if (puzzle[i] > puzzle[j])
        result += 1;
    }
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<num_inversions>:
  endbr64
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L7:
  movzwl (%rdi,%rsi,2),%edx
  test   %dx,%dx
  je     L35
  movswq %ax,%rcx
  movzwl (%rdi,%rcx,2),%ecx
  cmp    %cx,%dx
  jle    L35
  test   %cx,%cx
  lea    0x1(%r8),%edx
  setne  %cl
  test   %cl,%cl
  cmovne %edx,%r8d
L35:
  add    $0x1,%eax
  cmp    $0x10,%ax
  jne    L7
  lea    0x1(%r9),%eax
  cmp    $0xf,%r9w
  je     L21
  movswq %r9w,%rsi
  mov    %eax,%r9d
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r8d,%eax
  ret
```

assistant: ```c
short num_inversions(short *puzzle) {
  short i, j;
  short result = 0;
  for (i = 0; i < 16; i++) {
    for (j = i + 1; j < 16; j++) {
      if (puzzle[i] == 0 || puzzle[j] == 0)
        continue;
      if (puzzle[i] > puzzle[j])
        result += 1;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<num_inversions>:
  endbr64
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  mov    $0x1,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L2:
  movzwl (%rdi,%rsi,2),%edx
  test   %dx,%dx
  je     L20
  movswq %ax,%rcx
  movzwl (%rdi,%rcx,2),%ecx
  cmp    %cx,%dx
  jle    L20
  test   %cx,%cx
  lea    0x1(%r8),%edx
  setne  %cl
  test   %cl,%cl
  cmovne %edx,%r8d
L20:
  add    $0x1,%eax
  cmp    $0x10,%ax
  jne    L2
  lea    0x1(%r9),%eax
  cmp    $0xf,%r9w
  je     L30
  movswq %r9w,%rsi
  mov    %eax,%r9d
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r8d,%eax
  ret
```

assistant: ```c
short num_inversions(short *puzzle) {
  short i, j;
  short result = 0;
  for (i = 0; i < 16; i++) {
    for (j = i + 1; j < 16; j++) {
      if (puzzle[i] == 0 || puzzle[j] == 0)
        continue;
      if (puzzle[i] > puzzle[j])
        result += 1;
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<m_prod>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,-0x8(%rsp)
  mov    (%rdi),%eax
  movl   $0x1,D19(%rip)
  test   %eax,%eax
  jle    L72
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r15
  movslq %eax,%rbx
  mov    %rbx,-0x20(%rsp)
  add    $0x1,%eax
  mov    %eax,-0x14(%rsp)
  movslq %eax,%rdx
  mov    %rbx,%rax
  sub    %rdx,%rax
  lea    0x8(,%rax,8),%rbp
  lea    0x0(,%rbx,8),%rsi
  lea    (%r15,%rbp,1),%rax
  mov    %rax,-0x10(%rsp)
  mov    $0x0,%eax
  movl   $0x1,-0x18(%rsp)
  add    $0x8,%r15
  jmp    L20
L47:
  mov    %eax,%ebx
L102:
  mov    %r9,%rcx
  movq   $0x0,(%r9)
  mov    (%r12),%r8d
  test   %r8d,%r8d
  jle    L103
  lea    0x0(%r13,%rbp,1),%rdx
  lea    -0x1(%r8),%eax
  sub    -0x20(%rsp),%rax
  add    %r11,%rax
  lea    (%r15,%rax,8),%rdi
  mov    %r10,%rax
L100:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    %rsi,%rdx
  add    $0x8,%rax
  cmp    %rdi,%rax
  jne    L100
  add    $0x1,%r8d
L14:
  lea    0x1(%rbx),%eax
  add    %rsi,%r9
  add    %rsi,%r10
  add    -0x20(%rsp),%r11
  cmp    %r14d,%eax
  jne    L47
  add    $0x2,%ebx
  mov    $0x1,%eax
L0:
  addl   $0x1,-0x18(%rsp)
  mov    -0x18(%rsp),%edi
  add    $0x8,%rbp
  cmp    -0x14(%rsp),%edi
  je     L81
L20:
  mov    (%r12),%r14d
  test   %r14d,%r14d
  jle    L41
  mov    -0x8(%rsp),%rax
  lea    (%rax,%rbp,1),%r9
  mov    -0x20(%rsp),%r11
  mov    -0x10(%rsp),%r10
  mov    $0x0,%ebx
  jmp    L102
L103:
  mov    $0x1,%r8d
  jmp    L14
L41:
  mov    $0x1,%ebx
  jmp    L0
L81:
  mov    %ebx,D7(%rip)
  mov    -0x14(%rsp),%ebx
  mov    %ebx,D32(%rip)
  test   %al,%al
  je     L72
  mov    %r8d,D32(%rip)
L72:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int m_prod(n, a, b, c)
int *n;
double *a, *b, *c;
{
  int a_dim1, a_offset, b_dim1, b_offset, c_dim1, c_offset, i__1, i__2, i__3;
  static int i, j, k;
  c_dim1 = *n;
  c_offset = c_dim1 + 1;
  c -= c_offset;
  b_dim1 = *n;
  b_offset = b_dim1 + 1;
  b -= b_offset;
  a_dim1 = *n;
  a_offset = a_dim1 + 1;
  a -= a_offset;
  i__1 = *n;
  for (i = 1; i <= i__1; ++i) {
    i__2 = *n;
    for (j = 1; j <= i__2; ++j) {
      c[i + j * c_dim1] = (double)0.;
      i__3 = *n;
      for (k = 1; k <= i__3; ++k) {
        c[i + j * c_dim1] += a[i + k * a_dim1] * b[k + j * b_dim1];
      }
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<m_prod>:
  endbr64
  movl   $0x1,D21(%rip)
  mov    (%rdi),%r10d
  test   %r10d,%r10d
  jle    L24
  lea    -0x1(%r10),%eax
  movslq %r10d,%rdi
  mov    $0xfffffffffffffff8,%r11
  push   %r13
  shl    $0x3,%rax
  push   %r12
  mov    %rsi,%r9
  lea    0x1(%r10),%r13d
  push   %rbp
  shl    $0x3,%rdi
  lea    0x8(%rdx,%rax,1),%r12
  mov    $0x1,%ebp
  push   %rbx
  pxor   %xmm2,%xmm2
  mov    %rcx,%rbx
  sub    %rax,%r11
  nopl   0x0(%rax)
L49:
  mov    %r12,%rsi
  mov    %rbx,%rcx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L43:
  movq   $0x0,(%rcx)
  lea    (%r11,%rsi,1),%rax
  mov    %r9,%rdx
  movapd %xmm2,%xmm1
  nopw   0x0(%rax,%rax,1)
L31:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rsi,%rax
  jne    L31
  add    $0x1,%r8d
  add    %rdi,%rcx
  lea    (%rax,%rdi,1),%rsi
  cmp    %r10d,%r8d
  jne    L43
  lea    0x1(%rbp),%eax
  add    $0x8,%r9
  add    $0x8,%rbx
  cmp    %ebp,%r8d
  je     L12
  mov    %eax,%ebp
  jmp    L49
L12:
  pop    %rbx
  mov    %r13d,D18(%rip)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  mov    %r13d,D36(%rip)
  mov    %r13d,D29(%rip)
  pop    %r13
  ret
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int m_prod(n, a, b, c)
int *n;
double *a, *b, *c;
{
  int a_dim1, a_offset, b_dim1, b_offset, c_dim1, c_offset, i__1, i__2, i__3;
  static int i, j, k;
  c_dim1 = *n;
  c_offset = c_dim1 + 1;
  c -= c_offset;
  b_dim1 = *n;
  b_offset = b_dim1 + 1;
  b -= b_offset;
  a_dim1 = *n;
  a_offset = a_dim1 + 1;
  a -= a_offset;
  i__1 = *n;
  for (i = 1; i <= i__1; ++i) {
    i__2 = *n;
    for (j = 1; j <= i__2; ++j) {
      c[i + j * c_dim1] = (double)0.;
      i__3 = *n;
      for (k = 1; k <= i__3; ++k) {
        c[i + j * c_dim1] += a[i + k * a_dim1] * b[k + j * b_dim1];
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<m_prod>:
  endbr64
  movl   $0x1,D30(%rip)
  mov    (%rdi),%r10d
  test   %r10d,%r10d
  jle    L4
  lea    -0x1(%r10),%eax
  push   %r14
  movslq %r10d,%rdi
  mov    $0xfffffffffffffff8,%r11
  push   %r13
  lea    0x2(%rax),%r13
  shl    $0x3,%rax
  mov    %rsi,%r9
  push   %r12
  lea    0x1(%r10),%r14d
  shl    $0x3,%rdi
  lea    0x8(%rdx,%rax,1),%r12
  push   %rbp
  pxor   %xmm2,%xmm2
  mov    $0x1,%ebp
  sub    %rax,%r11
  push   %rbx
  mov    %rcx,%rbx
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %r12,%rsi
  mov    %rbx,%rcx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L0:
  movq   $0x0,(%rcx)
  lea    (%r11,%rsi,1),%rax
  mov    %r9,%rdx
  movapd %xmm2,%xmm1
  nopw   0x0(%rax,%rax,1)
L30:
  movsd  (%rdx),%xmm0
  mulsd  (%rax),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rsi,%rax
  jne    L30
  add    $0x1,%r8d
  add    %rdi,%rcx
  lea    (%rax,%rdi,1),%rsi
  cmp    %r10d,%r8d
  jne    L0
  add    $0x1,%rbp
  add    $0x8,%r9
  add    $0x8,%rbx
  cmp    %r13,%rbp
  jne    L24
  pop    %rbx
  mov    %r14d,D28(%rip)
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  mov    %r14d,D3(%rip)
  mov    %r14d,D2(%rip)
  pop    %r13
  pop    %r14
  ret
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int m_prod(n, a, b, c)
int *n;
double *a, *b, *c;
{
  int a_dim1, a_offset, b_dim1, b_offset, c_dim1, c_offset, i__1, i__2, i__3;
  static int i, j, k;
  c_dim1 = *n;
  c_offset = c_dim1 + 1;
  c -= c_offset;
  b_dim1 = *n;
  b_offset = b_dim1 + 1;
  b -= b_offset;
  a_dim1 = *n;
  a_offset = a_dim1 + 1;
  a -= a_offset;
  i__1 = *n;
  for (i = 1; i <= i__1; ++i) {
    i__2 = *n;
    for (j = 1; j <= i__2; ++j) {
      c[i + j * c_dim1] = (double)0.;
      i__3 = *n;
      for (k = 1; k <= i__3; ++k) {
        c[i + j * c_dim1] += a[i + k * a_dim1] * b[k + j * b_dim1];
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x30(%rbp)
  movl   $0x5,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x7,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x7,%esi
  mov    %rax,%rdi
  call   <search@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D7
type: string

tool: D7: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[] = {4, 5, 6, 7, 0, 1, 2};
  printf("%d\n", search(nums, sizeof(nums) / 4, 0));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x7,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%edx
  mov    $0x7,%esi
  call   <search@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[] = {4, 5, 6, 7, 0, 1, 2};
  printf("%d\n", search(nums, sizeof(nums) / 4, 0));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  xor    %edx,%edx
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x500000004,%rax
  mov    %rsp,%rdi
  movl   $0x2,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0x10(%rsp)
  call   <search@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[] = {4, 5, 6, 7, 0, 1, 2};
  printf("%d\n", search(nums, sizeof(nums) / 4, 0));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D7(%rip),%xmm0
  xor    %edx,%edx
  mov    $0x7,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    %rsp,%rdi
  movl   $0x2,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <search@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: byte[16]
name: extract_symbolic_data
arguments: label: D15
type: byte[8]
name: extract_symbolic_data
arguments: label: D0
type: string

tool: {"D7": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D0: %d


assistant: ```c
int main(int argc, char *argv[]) {
  int nums[] = {4, 5, 6, 7, 0, 1, 2};
  printf("%d\n", search(nums, sizeof(nums) / 4, 0));
  return 0;
}
```