ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotary_two_arm_calc>:
  endbr64
  sub    $0x28,%rsp
  movsd  D9(%rip),%xmm6
  movapd %xmm0,%xmm5
  mulsd  %xmm0,%xmm0
  movapd %xmm6,%xmm4
  divsd  %xmm1,%xmm4
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  movsd  D16(%rip),%xmm1
  addsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm0
  movapd %xmm0,%xmm3
  mulsd  %xmm4,%xmm1
  mulsd  %xmm5,%xmm4
  mulsd  %xmm1,%xmm3
  movapd %xmm4,%xmm5
  mulsd  %xmm4,%xmm5
  movapd %xmm3,%xmm0
  movapd %xmm3,%xmm1
  mulsd  %xmm3,%xmm0
  addsd  %xmm6,%xmm5
  mulsd  %xmm4,%xmm1
  mulsd  %xmm5,%xmm2
  subsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L3
  sqrtsd %xmm2,%xmm2
L4:
  addsd  %xmm2,%xmm1
  mulsd  %xmm5,%xmm3
  add    $0x28,%rsp
  mulsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  jmp    1070 <atan2@plt>
L3:
  movapd %xmm2,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm4,0x10(%rsp)
  movsd  %xmm3,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <sqrt@plt>
  movsd  0x18(%rsp),%xmm5
  movsd  0x10(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L4
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: f64
name: parse_data
arguments: tag: D16
datatype: byte[8]

tool: D9: 1

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double rotary_two_arm_calc(double dx, double dy, double upper_arm2, double lower_arm2) {
  double inv_dy = 1. / dy;
  double c1 = .5 * inv_dy * (dx * dx + dy * dy + upper_arm2 - lower_arm2);
  double c2 = dx * inv_dy;
  double scale = c2 * c2 + 1.0;
  double scaled_elbow_x = c1 * c2 + sqrt(scale * upper_arm2 - c1 * c1);
  double scaled_elbow_y = c1 * scale - c2 * scaled_elbow_x;
  return atan2(scaled_elbow_y, scaled_elbow_x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AssertNeqFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  mov    %edi,-0xc(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  movss  -0x8(%rbp),%xmm0
  mov    -0x4(%rbp),%eax
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <floatEq@plt>
  test   %rax,%rax
  je     L10
  mov    -0x30(%rbp),%r8
  mov    -0x8(%rbp),%esi
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  movd   %esi,%xmm0
  mov    %rdi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <TESTError_Fail@plt>
  mov    $0x0,%eax
  jmp    L7
L10:
  mov    $0x1,%eax
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type: string

tool: D0: %s:%d> %s() FAILED: %s should not be '%f' (%s)


assistant: ```c
int AssertNeqFloat(const float a, const float b, int line, const char *file, const char *function, const char *aexp, const char *bexp) {
  if (floatEq(a, b)) {
    TESTError_Fail("%s:%d> %s() FAILED: %s should not be '%f' (%s)\n", file, line, function, aexp, b, bexp);
    return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<AssertNeqFloat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%r14
  call   <floatEq@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L19
L13:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  mov    %r14,%r9
  movss  0xc(%rsp),%xmm0
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %ebp,%edx
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <TESTError_Fail@plt>
  mov    $0x0,%eax
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: label: D5
type_infered: string

tool: D5: %s:%d> %s() FAILED: %s should not be '%f' (%s)


assistant: ```c
int AssertNeqFloat(const float a, const float b, int line, const char *file, const char *function, const char *aexp, const char *bexp) {
  if (floatEq(a, b)) {
    TESTError_Fail("%s:%d> %s() FAILED: %s should not be '%f' (%s)\n", file, line, function, aexp, b, bexp);
    return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<AssertNeqFloat>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <floatEq@plt>
  movss  0xc(%rsp),%xmm1
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  movaps %xmm1,%xmm0
  lea    D2(%rip),%rdi
  call   <TESTError_Fail@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
data_type: string

tool: D2: %s:%d> %s() FAILED: %s should not be '%f' (%s)


assistant: ```c
int AssertNeqFloat(const float a, const float b, int line, const char *file, const char *function, const char *aexp, const char *bexp) {
  if (floatEq(a, b)) {
    TESTError_Fail("%s:%d> %s() FAILED: %s should not be '%f' (%s)\n", file, line, function, aexp, b, bexp);
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<AssertNeqFloat>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  movss  %xmm1,0xc(%rsp)
  call   <floatEq@plt>
  movss  0xc(%rsp),%xmm1
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r14,%r9
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  movaps %xmm1,%xmm0
  lea    D6(%rip),%rdi
  call   <TESTError_Fail@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: %s:%d> %s() FAILED: %s should not be '%f' (%s)


assistant: ```c
int AssertNeqFloat(const float a, const float b, int line, const char *file, const char *function, const char *aexp, const char *bexp) {
  if (floatEq(a, b)) {
    TESTError_Fail("%s:%d> %s() FAILED: %s should not be '%f' (%s)\n", file, line, function, aexp, b, bexp);
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<read_serial_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L40
L28:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <read_serial_port@plt>
  mov    %al,(%rbx)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L39
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L39
  addl   $0x1,-0x14(%rbp)
  subl   $0x1,-0x2c(%rbp)
L40:
  cmpl   $0x0,-0x2c(%rbp)
  jg     L28
L39:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int read_serial_data(char *s, int size) {
  int i = 0;
  while (size > 0) {
    s[i] = read_serial_port();
    if (s[i] == 0x00 || s[i] == '\n' || s[i] == '\r')
      break;
    i++;
    size--;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_serial_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L33
  mov    %esi,%r12d
  mov    %rdi,%rbx
  mov    $0x0,%ebp
  mov    $0x2401,%r13d
  jmp    L38
L35:
  add    $0x1,%ebp
  add    $0x1,%rbx
  cmp    %ebp,%r12d
  je     L68
L38:
  mov    $0x0,%eax
  call   <read_serial_port@plt>
  mov    %al,(%rbx)
  cmp    $0xd,%al
  ja     L35
  bt     %rax,%r13
  jae    L35
L4:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L68:
  mov    %r12d,%ebp
  jmp    L4
L33:
  mov    $0x0,%ebp
  jmp    L4
```

assistant: ```c
int read_serial_data(char *s, int size) {
  int i = 0;
  while (size > 0) {
    s[i] = read_serial_port();
    if (s[i] == 0x00 || s[i] == '\n' || s[i] == '\r')
      break;
    i++;
    size--;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_serial_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L40
  mov    %esi,%ebp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  mov    $0xffffffffffffdbfe,%r13
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L17
L39:
  xor    %eax,%eax
  call   <read_serial_port@plt>
  mov    %al,(%rbx)
  cmp    $0xd,%al
  ja     L2
  bt     %rax,%r13
  jb     L2
L17:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L40:
  xor    %r12d,%r12d
  jmp    L17
```

assistant: ```c
int read_serial_data(char *s, int size) {
  int i = 0;
  while (size > 0) {
    s[i] = read_serial_port();
    if (s[i] == 0x00 || s[i] == '\n' || s[i] == '\r')
      break;
    i++;
    size--;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_serial_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L45
  mov    %esi,%ebp
  mov    %rdi,%rbx
  xor    %r12d,%r12d
  mov    $0xffffffffffffdbfe,%r13
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L43:
  add    $0x1,%r12d
  add    $0x1,%rbx
  cmp    %r12d,%ebp
  je     L4
L18:
  xor    %eax,%eax
  call   <read_serial_port@plt>
  mov    %al,(%rbx)
  cmp    $0xd,%al
  ja     L43
  bt     %rax,%r13
  jb     L43
L4:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  xor    %r12d,%r12d
  jmp    L4
```

assistant: ```c
int read_serial_data(char *s, int size) {
  int i = 0;
  while (size > 0) {
    s[i] = read_serial_port();
    if (s[i] == 0x00 || s[i] == '\n' || s[i] == '\r')
      break;
    i++;
    size--;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L7
  cmpl   $0x7a,-0x4(%rbp)
  jg     L7
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L18
L7:
  mov    -0x4(%rbp),%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int toupper(int ch) {
  if ((ch >= 'a') && (ch <= 'z'))
    return ch + 'A' - 'a';
  else
    return ch;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<toupper>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int ch) {
  if ((ch >= 'a') && (ch <= 'z'))
    return ch + 'A' - 'a';
  else
    return ch;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int ch) {
  if ((ch >= 'a') && (ch <= 'z'))
    return ch + 'A' - 'a';
  else
    return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper(int ch) {
  if ((ch >= 'a') && (ch <= 'z'))
    return ch + 'A' - 'a';
  else
    return ch;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StringReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L34
  cmpl   $0x0,-0x1c(%rbp)
  js     L34
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L22
L34:
  mov    $0x1,%eax
  jmp    L52
L22:
  movb   $0x0,-0x1(%rbp)
  jmp    L57
L53:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x20(%rbp)
L57:
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L53
  mov    $0x0,%eax
L52:
  pop    %rbp
  ret
```

assistant: ```c
int StringReverse(char *s, int first, int last) {
  if (!s || first < 0 || last < first) {
    return 1;
  }
  char temp = '\0';
  while (first < last) {
    temp = s[first];
    s[first] = s[last];
    s[last] = temp;
    ++first;
    --last;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<StringReverse>:
  endbr64
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  cmp    %edx,%esi
  setg   %al
  or     %cl,%al
  jne    L23
  test   %rdi,%rdi
  je     L23
  cmp    %edx,%esi
  jge    L31
  movslq %esi,%rsi
  movslq %edx,%rdx
L13:
  movzbl (%rdi,%rsi,1),%eax
  movzbl (%rdi,%rdx,1),%ecx
  mov    %cl,(%rdi,%rsi,1)
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rsi
  sub    $0x1,%rdx
  cmp    %edx,%esi
  jl     L13
  mov    $0x0,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
L31:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int StringReverse(char *s, int first, int last) {
  if (!s || first < 0 || last < first) {
    return 1;
  }
  char temp = '\0';
  while (first < last) {
    temp = s[first];
    s[first] = s[last];
    s[last] = temp;
    ++first;
    --last;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<StringReverse>:
  endbr64
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  cmp    %edx,%esi
  setg   %al
  or     %cl,%al
  jne    L33
  test   %rdi,%rdi
  je     L33
  movslq %edx,%rcx
  movslq %esi,%rax
  cmp    %edx,%esi
  jge    L9
  nopl   0x0(%rax)
L26:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rcx,1),%esi
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  cmp    %eax,%ecx
  jg     L26
L9:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int StringReverse(char *s, int first, int last) {
  if (!s || first < 0 || last < first) {
    return 1;
  }
  char temp = '\0';
  while (first < last) {
    temp = s[first];
    s[first] = s[last];
    s[last] = temp;
    ++first;
    --last;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<StringReverse>:
  endbr64
  mov    %esi,%ecx
  shr    $0x1f,%ecx
  cmp    %edx,%esi
  setg   %al
  or     %cl,%al
  jne    L1
  test   %rdi,%rdi
  je     L1
  movslq %edx,%rcx
  movslq %esi,%rax
  cmp    %edx,%esi
  jge    L20
  nopl   0x0(%rax)
L23:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rcx,1),%esi
  mov    %sil,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rcx,1)
  sub    $0x1,%rcx
  cmp    %eax,%ecx
  jg     L23
L20:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int StringReverse(char *s, int first, int last) {
  if (!s || first < 0 || last < first) {
    return 1;
  }
  char temp = '\0';
  while (first < last) {
    temp = s[first];
    s[first] = s[last];
    s[last] = temp;
    ++first;
    --last;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_any>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L22
L36:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  test   %eax,%eax
  je     L22
  mov    $0x1,%eax
  jmp    L9
L22:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L36
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab != 0) {
    if (f(*(tab++)))
      return (1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_any>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
L16:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  je     L2
  add    $0x8,%rbx
  call   *%rbp
  test   %eax,%eax
  je     L16
  mov    $0x1,%eax
  jmp    L4
L2:
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab != 0) {
    if (f(*(tab++)))
      return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_any>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rbx
  call   *%rbp
  test   %eax,%eax
  jne    L15
L12:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab != 0) {
    if (f(*(tab++)))
      return (1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_any>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rbx
  call   *%rbp
  test   %eax,%eax
  jne    L17
L25:
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int ft_any(char **tab, int (*f)(char *)) {
  while (*tab != 0) {
    if (f(*(tab++)))
      return (1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<umatch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0x1,%eax
  jmp    L41
L34:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <amatch@plt>
  test   %rax,%rax
  je     L2
  mov    $0x1,%eax
  jmp    L41
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    $0x0,%eax
L41:
  leave
  ret
```

assistant: ```c
int umatch(char *s, char *p) {
  if (*p == 0)
    return 1;
  while (*s)
    if (amatch(s++, p))
      return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<umatch>:
  endbr64
  mov    $0x1,%eax
  cmpb   $0x0,(%rsi)
  je     L38
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdi,%rbx
L33:
  cmpb   $0x0,(%rbx)
  je     L32
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <amatch@plt>
  add    $0x1,%rbx
  test   %rax,%rax
  je     L33
  mov    $0x1,%eax
  jmp    L9
L32:
  mov    $0x0,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  ret
```

assistant: ```c
int umatch(char *s, char *p) {
  if (*p == 0)
    return 1;
  while (*s)
    if (amatch(s++, p))
      return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<umatch>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L24
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <amatch@plt>
  test   %rax,%rax
  jne    L22
L18:
  cmpb   $0x0,(%rbx)
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L22:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int umatch(char *s, char *p) {
  if (*p == 0)
    return 1;
  while (*s)
    if (amatch(s++, p))
      return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<umatch>:
  endbr64
  cmpb   $0x0,(%rsi)
  je     L11
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <amatch@plt>
  test   %rax,%rax
  jne    L39
L17:
  cmpb   $0x0,(%rbx)
  jne    L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L39:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int umatch(char *s, char *p) {
  if (*p == 0)
    return 1;
  while (*s)
    if (amatch(s++, p))
      return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_more>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    D1(%rip),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <adagain@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <primary_five@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <primary_six@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int add_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  two = adagain(two);
  primary_five(two);
  primary_six(two);
  return two;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<add_more>:
  endbr64
  push   %rbx
  add    $0x3,%edi
  call   <adagain@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <primary_five@plt>
  mov    %ebx,%edi
  call   <primary_six@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int add_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  two = adagain(two);
  primary_five(two);
  primary_six(two);
  return two;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<add_more>:
  endbr64
  push   %r12
  add    $0x3,%edi
  call   <adagain@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <primary_five@plt>
  mov    %r12d,%edi
  call   <primary_six@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int add_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  two = adagain(two);
  primary_five(two);
  primary_six(two);
  return two;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<add_more>:
  endbr64
  push   %r12
  add    $0x3,%edi
  call   <adagain@plt>
  mov    %eax,%r12d
  mov    %eax,%edi
  call   <primary_five@plt>
  mov    %r12d,%edi
  call   <primary_six@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int add_more(int input) {
  static int one = 1;
  int two = 2;
  two += input;
  two += one;
  two = adagain(two);
  primary_five(two);
  primary_six(two);
  return two;
}
```