ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<fnmatch>:
  endbr64
  mov    $0x2,%eax
  test   $0x7,%dl
  jne    L70
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %edx,%ebp
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L72
  cmp    $0x2a,%dl
  je     L30
  movzbl (%rsi),%ecx
  mov    $0x1,%eax
  test   %cl,%cl
  je     L23
  cmp    $0x5b,%dl
  je     L4
  cmp    $0x3f,%dl
  je     L41
  mov    $0x1,%eax
  cmp    %cl,%dl
  jne    L23
  lea    0x1(%rsi),%rsi
  lea    0x1(%rdi),%rdi
  mov    %ebp,%edx
  call   <fnmatch>
  jmp    L23
L72:
  cmpb   $0x0,(%rsi)
  setne  %al
  movzbl %al,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L30:
  cmpb   $0x0,(%rsi)
  je     L47
  lea    0x1(%rdi),%r13
L106:
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <fnmatch>
  test   %eax,%eax
  je     L23
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L106
L47:
  lea    0x1(%r12),%rdi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <fnmatch>
  jmp    L23
L4:
  lea    0x1(%rdi),%rdi
  mov    %ebp,%edx
  call   <_fnmatch_class@plt>
  jmp    L23
L41:
  lea    0x1(%rsi),%rsi
  lea    0x1(%rdi),%rdi
  mov    %ebp,%edx
  call   <fnmatch>
  jmp    L23
L70:
  ret
```

assistant: ```c
int fnmatch(char const *pattern, char const *string, int flags) {
  if (flags & (0x1 | 0x2 | 0x4))
    return 2;
  if (pattern[0] == '\0')
    return (string[0] == '\0') ? 0 : 1;
  if (pattern[0] == '*') {
    for (; string[0] != '\0'; string++)
      if (fnmatch(&pattern[1], string, flags) == 0)
        return 0;
    return fnmatch(&pattern[1], string, flags);
  }
  if (string[0] == '\0')
    return 1;
  if (pattern[0] == '[')
    return _fnmatch_class(&pattern[1], string, flags);
  if (pattern[0] == '?')
    return fnmatch(&pattern[1], &string[1], flags);
  if (pattern[0] == string[0])
    return fnmatch(&pattern[1], &string[1], flags);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fnmatch>:
  endbr64
  test   $0x7,%dl
  jne    L6
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x1(%rdi),%r12
  push   %rbp
  mov    %rsi,%rbp
  movzbl (%rsi),%ecx
  jmp    L2
  nopl   0x0(%rax)
L110:
  test   %cl,%cl
  je     L48
  cmp    $0x5b,%al
  je     L20
  cmp    $0x3f,%al
  je     L18
  cmp    %cl,%al
  jne    L48
L18:
  movzbl 0x1(%rbp),%ecx
  add    $0x1,%rbp
L46:
  add    $0x1,%r12
L2:
  movzbl -0x1(%r12),%eax
  test   %al,%al
  je     L67
  cmp    $0x2a,%al
  jne    L110
  test   %cl,%cl
  je     L46
L54:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fnmatch>
  test   %eax,%eax
  je     L17
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L54
  xor    %ecx,%ecx
  jmp    L46
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    $0x1,%eax
L17:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  xor    %eax,%eax
  test   %cl,%cl
  pop    %rbp
  pop    %r12
  setne  %al
  pop    %r13
  ret
  nopl   (%rax)
L20:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <_fnmatch_class@plt>
L6:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int fnmatch(char const *pattern, char const *string, int flags) {
  if (flags & (0x1 | 0x2 | 0x4))
    return 2;
  if (pattern[0] == '\0')
    return (string[0] == '\0') ? 0 : 1;
  if (pattern[0] == '*') {
    for (; string[0] != '\0'; string++)
      if (fnmatch(&pattern[1], string, flags) == 0)
        return 0;
    return fnmatch(&pattern[1], string, flags);
  }
  if (string[0] == '\0')
    return 1;
  if (pattern[0] == '[')
    return _fnmatch_class(&pattern[1], string, flags);
  if (pattern[0] == '?')
    return fnmatch(&pattern[1], &string[1], flags);
  if (pattern[0] == string[0])
    return fnmatch(&pattern[1], &string[1], flags);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fnmatch>:
  endbr64
  test   $0x7,%dl
  jne    L7
  push   %r13
  mov    %edx,%r13d
  push   %r12
  lea    0x1(%rdi),%r12
  push   %rbp
  mov    %rsi,%rbp
  movzbl (%rsi),%ecx
  jmp    L28
  nopl   0x0(%rax)
L19:
  test   %cl,%cl
  je     L36
  cmp    $0x5b,%al
  je     L96
  cmp    $0x3f,%al
  je     L11
  cmp    %cl,%al
  jne    L36
L11:
  movzbl 0x1(%rbp),%ecx
  add    $0x1,%rbp
L92:
  add    $0x1,%r12
L28:
  movzbl -0x1(%r12),%eax
  test   %al,%al
  je     L63
  cmp    $0x2a,%al
  jne    L19
  test   %cl,%cl
  je     L92
L27:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <fnmatch>
  test   %eax,%eax
  je     L65
  add    $0x1,%rbp
  cmpb   $0x0,0x0(%rbp)
  jne    L27
  xor    %ecx,%ecx
  jmp    L92
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    $0x1,%eax
L65:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  xor    %eax,%eax
  test   %cl,%cl
  pop    %rbp
  pop    %r12
  setne  %al
  pop    %r13
  ret
  nopl   (%rax)
L96:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <_fnmatch_class@plt>
L7:
  mov    $0x2,%eax
  ret
```

assistant: ```c
int fnmatch(char const *pattern, char const *string, int flags) {
  if (flags & (0x1 | 0x2 | 0x4))
    return 2;
  if (pattern[0] == '\0')
    return (string[0] == '\0') ? 0 : 1;
  if (pattern[0] == '*') {
    for (; string[0] != '\0'; string++)
      if (fnmatch(&pattern[1], string, flags) == 0)
        return 0;
    return fnmatch(&pattern[1], string, flags);
  }
  if (string[0] == '\0')
    return 1;
  if (pattern[0] == '[')
    return _fnmatch_class(&pattern[1], string, flags);
  if (pattern[0] == '?')
    return fnmatch(&pattern[1], &string[1], flags);
  if (pattern[0] == string[0])
    return fnmatch(&pattern[1], &string[1], flags);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  mov    %r8,-0x1c(%rbp)
  mov    %r9d,-0x20(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <XSetClipMask@plt>
  mov    -0x1c(%rbp),%r8d
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  push   $0x0
  push   $0x0
  push   %r8
  push   %rdi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <XCopyArea@plt>
  add    $0x20,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <XSetClipMask@plt>
  nop
  leave
  ret
```

assistant: ```c
void copy(Display *d, Drawable from, Drawable to, GC gc, XRectangle r, Drawable mask) {
  XSetClipMask(d, gc, mask);
  XCopyArea(d, from, to, gc, 0, 0, r.width, r.height, 0, 0);
  XSetClipMask(d, gc, None);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %ecx,%r12d
  mov    %r8,%rbx
  mov    %r9d,%edx
  mov    %ecx,%esi
  call   <XSetClipMask@plt>
  push   $0x0
  push   $0x0
  push   %rbx
  sar    $0x20,%rbx
  push   %rbx
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %r12d,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <XCopyArea@plt>
  add    $0x20,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <XSetClipMask@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void copy(Display *d, Drawable from, Drawable to, GC gc, XRectangle r, Drawable mask) {
  XSetClipMask(d, gc, mask);
  XCopyArea(d, from, to, gc, 0, 0, r.width, r.height, 0, 0);
  XSetClipMask(d, gc, None);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  mov    %r9d,%edx
  push   %r13
  mov    %esi,%r13d
  mov    %ecx,%esi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  call   <XSetClipMask@plt>
  push   $0x0
  mov    %r14d,%edx
  mov    %r13d,%esi
  push   $0x0
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  xor    %r9d,%r9d
  push   %rbx
  sar    $0x20,%rbx
  xor    %r8d,%r8d
  push   %rbx
  call   <XCopyArea@plt>
  add    $0x20,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    D5(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%edx
  pop    %r13
  pop    %r14
  jmp    1070 <XSetClipMask@plt>
```

assistant: ```c
void copy(Display *d, Drawable from, Drawable to, GC gc, XRectangle r, Drawable mask) {
  XSetClipMask(d, gc, mask);
  XCopyArea(d, from, to, gc, 0, 0, r.width, r.height, 0, 0);
  XSetClipMask(d, gc, None);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  mov    %r9d,%edx
  push   %r13
  mov    %esi,%r13d
  mov    %ecx,%esi
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8,%rbx
  call   <XSetClipMask@plt>
  push   $0x0
  mov    %r14d,%edx
  mov    %r13d,%esi
  push   $0x0
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  xor    %r9d,%r9d
  push   %rbx
  sar    $0x20,%rbx
  xor    %r8d,%r8d
  push   %rbx
  call   <XCopyArea@plt>
  add    $0x20,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    D1(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%edx
  pop    %r13
  pop    %r14
  jmp    1070 <XSetClipMask@plt>
```

assistant: ```c
void copy(Display *d, Drawable from, Drawable to, GC gc, XRectangle r, Drawable mask) {
  XSetClipMask(d, gc, mask);
  XCopyArea(d, from, to, gc, 0, 0, r.width, r.height, 0, 0);
  XSetClipMask(d, gc, None);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__aosc_encode_and_16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__aosc_split_and_16@plt>
  mov    -0x18(%rbp),%rax
  movb   $0x66,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movb   $0x25,(%rax)
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movb   $0x66,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movb   $0x25,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x7,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
char *__aosc_encode_and_16(char *dst) {
  uint16_t word1, word2;
  __aosc_split_and_16(&word1, &word2);
  dst[0] = 0x66;
  dst[1] = 0x25;
  do {
    (&dst[2])[1] = (word1) >> 8;
    (&dst[2])[0] = (word1);
  } while (0);
  dst[4] = 0x66;
  dst[5] = 0x25;
  do {
    (&dst[6])[1] = (word2) >> 8;
    (&dst[6])[0] = (word2);
  } while (0);
  dst[8] = 0;
  return dst;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__aosc_encode_and_16>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <__aosc_split_and_16@plt>
  movb   $0x66,(%rbx)
  movb   $0x25,0x1(%rbx)
  mov    (%rsp),%eax
  movzbl %ah,%edx
  mov    %dl,0x3(%rbx)
  mov    %al,0x2(%rbx)
  movb   $0x66,0x4(%rbx)
  movb   $0x25,0x5(%rbx)
  mov    0x4(%rsp),%eax
  movzbl %ah,%ecx
  mov    %cl,0x7(%rbx)
  mov    %al,0x6(%rbx)
  movb   $0x0,0x8(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %rbx,%rax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *__aosc_encode_and_16(char *dst) {
  uint16_t word1, word2;
  __aosc_split_and_16(&word1, &word2);
  dst[0] = 0x66;
  dst[1] = 0x25;
  do {
    (&dst[2])[1] = (word1) >> 8;
    (&dst[2])[0] = (word1);
  } while (0);
  dst[4] = 0x66;
  dst[5] = 0x25;
  do {
    (&dst[6])[1] = (word2) >> 8;
    (&dst[6])[0] = (word2);
  } while (0);
  dst[8] = 0;
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__aosc_encode_and_16>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <__aosc_split_and_16@plt>
  mov    $0x2566,%eax
  mov    $0x2566,%edx
  movb   $0x0,0x8(%r12)
  mov    %ax,(%r12)
  movzwl (%rsp),%eax
  mov    %dx,0x4(%r12)
  mov    %ax,0x2(%r12)
  movzwl 0x4(%rsp),%eax
  mov    %ax,0x6(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *__aosc_encode_and_16(char *dst) {
  uint16_t word1, word2;
  __aosc_split_and_16(&word1, &word2);
  dst[0] = 0x66;
  dst[1] = 0x25;
  do {
    (&dst[2])[1] = (word1) >> 8;
    (&dst[2])[0] = (word1);
  } while (0);
  dst[4] = 0x66;
  dst[5] = 0x25;
  do {
    (&dst[6])[1] = (word2) >> 8;
    (&dst[6])[0] = (word2);
  } while (0);
  dst[8] = 0;
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__aosc_encode_and_16>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <__aosc_split_and_16@plt>
  mov    $0x2566,%eax
  mov    $0x2566,%edx
  movb   $0x0,0x8(%r12)
  mov    %ax,(%r12)
  movzwl (%rsp),%eax
  mov    %dx,0x4(%r12)
  mov    %ax,0x2(%r12)
  movzwl 0x4(%rsp),%eax
  mov    %ax,0x6(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *__aosc_encode_and_16(char *dst) {
  uint16_t word1, word2;
  __aosc_split_and_16(&word1, &word2);
  dst[0] = 0x66;
  dst[1] = 0x25;
  do {
    (&dst[2])[1] = (word1) >> 8;
    (&dst[2])[0] = (word1);
  } while (0);
  dst[4] = 0x66;
  dst[5] = 0x25;
  do {
    (&dst[6])[1] = (word2) >> 8;
    (&dst[6])[0] = (word2);
  } while (0);
  dst[8] = 0;
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<client_403>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x100,%edi
  call   <safe_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D44(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D58(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D21(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  lea    D24(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  test   %rax,%rax
  jns    L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x14(%rbp),%eax
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <server_error@plt>
L9:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D44
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string
name: parse_data
arguments: tag: D58
type_infered: string
name: parse_data
arguments: tag: D21
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string

tool: D44: HTTP/1.1 403 Forbidden


tool: D9: <HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>

tool: D58: 403 Forbidden.  Your request could not be completed due to encountering

tool: D21:  HTTP error number 403.</BODY></HTML>

tool: D24: 


tool: D23: writing 403 to client

assistant: ```c
void client_403(int sock) {
  char *buf = safe_malloc(256);
  strcpy(buf, "HTTP/1.1 403 Forbidden\r\n");
  strcat(buf, "<HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>");
  strcat(buf, "403 Forbidden.  Your request could not be completed due to encountering");
  strcat(buf, " HTTP error number 403.</BODY></HTML>");
  strcat(buf, "\r\n");
  if ((write(sock, buf, strlen(buf)) < 0)) {
    free(buf);
    server_error(sock, "writing 403 to client");
  }
  free(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<client_403>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x100,%edi
  call   <safe_malloc@plt>
  mov    %rax,%rbx
  lea    D41(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D33(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D51(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %rax,%rax
  js     L3
L2:
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbx,%rdi
  call   <free@plt>
  lea    D26(%rip),%rsi
  mov    %ebp,%edi
  call   <server_error@plt>
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D41
data_type: string
name: unpack_data
arguments: data_tag: D33
data_type: string
name: unpack_data
arguments: data_tag: D47
data_type: string
name: unpack_data
arguments: data_tag: D51
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string

tool: D41: HTTP/1.1 403 Forbidden


tool: D33: <HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>

tool: D47: 403 Forbidden.  Your request could not be completed due to encountering

tool: D51:  HTTP error number 403.</BODY></HTML>

tool: D7: 


tool: D26: writing 403 to client

assistant: ```c
void client_403(int sock) {
  char *buf = safe_malloc(256);
  strcpy(buf, "HTTP/1.1 403 Forbidden\r\n");
  strcat(buf, "<HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>");
  strcat(buf, "403 Forbidden.  Your request could not be completed due to encountering");
  strcat(buf, " HTTP error number 403.</BODY></HTML>");
  strcat(buf, "\r\n");
  if ((write(sock, buf, strlen(buf)) < 0)) {
    free(buf);
    server_error(sock, "writing 403 to client");
  }
  free(buf);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<client_403>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x100,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <safe_malloc@plt>
  lea    D49(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D34(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D32(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %rax,%rax
  js     L0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
  nop
L0:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12d,%edi
  lea    D44(%rip),%rsi
  call   <server_error@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
```

tool_calls: name: read_data
arguments: tag: D49
type_guessed: string
name: read_data
arguments: tag: D34
type_guessed: string
name: read_data
arguments: tag: D3
type_guessed: string
name: read_data
arguments: tag: D5
type_guessed: string
name: read_data
arguments: tag: D32
type_guessed: string
name: read_data
arguments: tag: D44
type_guessed: string

tool: D49: HTTP/1.1 403 Forbidden


tool: D34: <HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>

tool: D3: 403 Forbidden.  Your request could not be completed due to encountering

tool: D5:  HTTP error number 403.</BODY></HTML>

tool: D32: 


tool: D44: writing 403 to client

assistant: ```c
void client_403(int sock) {
  char *buf = safe_malloc(256);
  strcpy(buf, "HTTP/1.1 403 Forbidden\r\n");
  strcat(buf, "<HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>");
  strcat(buf, "403 Forbidden.  Your request could not be completed due to encountering");
  strcat(buf, " HTTP error number 403.</BODY></HTML>");
  strcat(buf, "\r\n");
  if ((write(sock, buf, strlen(buf)) < 0)) {
    free(buf);
    server_error(sock, "writing 403 to client");
  }
  free(buf);
}
```
user: What is the c source code of the assembly code below?

```asm
<client_403>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    $0x100,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <safe_malloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D51(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    D31(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %rax,%rax
  js     L4
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
  nop
L4:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12d,%edi
  lea    D23(%rip),%rsi
  call   <server_error@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    10b0 <free@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string
name: parse_data
arguments: label: D51
type_guessed: string
name: parse_data
arguments: label: D31
type_guessed: string
name: parse_data
arguments: label: D23
type_guessed: string

tool: D5: HTTP/1.1 403 Forbidden


tool: D24: <HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>

tool: D26: 403 Forbidden.  Your request could not be completed due to encountering

tool: D51:  HTTP error number 403.</BODY></HTML>

tool: D31: 


tool: D23: writing 403 to client

assistant: ```c
void client_403(int sock) {
  char *buf = safe_malloc(256);
  strcpy(buf, "HTTP/1.1 403 Forbidden\r\n");
  strcat(buf, "<HTML><HEAD><TITLE>HTTP ERROR 403</TITLE></HEAD><BODY>");
  strcat(buf, "403 Forbidden.  Your request could not be completed due to encountering");
  strcat(buf, " HTTP error number 403.</BODY></HTML>");
  strcat(buf, "\r\n");
  if ((write(sock, buf, strlen(buf)) < 0)) {
    free(buf);
    server_error(sock, "writing 403 to client");
  }
  free(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L9
  subb   $0x20,-0x4(%rbp)
L9:
  movzbl -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned char toupper(unsigned char c) {
  if (islower(c)) {
    c -= 'a' - 'A';
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<toupper>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %dil,%edi
  call   <islower@plt>
  mov    %rax,%rdx
  lea    -0x20(%rbx),%eax
  test   %rdx,%rdx
  cmove  %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned char toupper(unsigned char c) {
  if (islower(c)) {
    c -= 'a' - 'A';
  }
  return c;
}
```