user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  jne    L128
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L109
L128:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L109:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L89
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L89:
  movl   $0x0,-0x10(%rbp)
  jmp    L110
L34:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  add    $0x2,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L110:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L34
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L77
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L101
L27:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0xc(%rbp)
L101:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L27
L77:
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L12
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L46
L94:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L118
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L118:
  addl   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L94
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string
name: read_data
arguments: data_tag: D33
type: string
name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D15
type: string

tool: D2: Usage: %s NUMBERS


tool: D33: Could not allocate memory

tool: D7: 1 

tool: D15: %d 

assistant: ```c
int main(int argc, char *argv[]) {
  int limit, i, j;
  if (argc != 2 || ((limit = atoi(argv[1]))) <= 0) {
    printf("Usage: %s NUMBERS\n", argv[0]);
    exit(1);
  }
  limit = limit - 1;
  int *numbers;
  numbers = (int *)malloc(sizeof(int) * limit);
  if (!numbers) {
    perror("Could not allocate memory");
    exit(1);
  }
  for (i = 0; i < limit; i++) {
    numbers[i] = i + 2;
  }
  for (i = 0; i < limit; i++) {
    if (numbers[i] != 0) {
      for (j = 2 * numbers[i] - 2; j < limit; j += numbers[i])
        numbers[j] = 0;
    }
  }
  printf("1 ");
  for (i = 0; i < limit; i++) {
    if (numbers[i] != 0) {
      printf("%d ", numbers[i]);
    }
  }
  printf("\n");
  free(numbers);
  return 0;
}
```