ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa0(%rbp),%rax
  mov    %rax,-0xa8(%rbp)
  movl   $0x0,-0xb4(%rbp)
  jmp    L32
L63:
  mov    -0xb4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0xa0(%rbp),%rax
  add    %rax,%rdx
  mov    -0xb4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xb4(%rbp)
L32:
  cmpl   $0x22,-0xb4(%rbp)
  jle    L63
  movl   $0x0,-0xb0(%rbp)
  jmp    L6
L68:
  movl   $0x0,-0xac(%rbp)
  jmp    L34
L49:
  mov    -0xac(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  add    %rcx,%rax
  mov    -0xa0(%rbp,%rax,4),%edx
  lea    -0xa0(%rbp),%rsi
  mov    -0xac(%rbp),%eax
  movslq %eax,%rdi
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x3,%rax
  sub    %rcx,%rax
  add    %rdi,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0xa8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xac(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0xb0(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x3,%rax
  sub    %rcx,%rax
  shl    $0x2,%rax
  mov    %rax,%rcx
  mov    -0xa8(%rbp),%rax
  add    %rax,%rcx
  mov    -0xac(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xac(%rbp)
L34:
  cmpl   $0x6,-0xac(%rbp)
  jle    L49
  addl   $0x1,-0xb0(%rbp)
L6:
  cmpl   $0x4,-0xb0(%rbp)
  jle    L68
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: %p %d


assistant: ```c
int main() {
  int a[5][7];
  int(*pa)[7] = a;
  for (int i = 0; i < 5 * 7; i++) {
    *((int *)a + i) = i;
  }
  for (int i = 0; i < 5; i++)
    for (int j = 0; j < 7; j++) {
      printf("%p %d\n", &a[i][j], a[i][j]);
      printf("%p %d\n", &pa[i][j], pa[i][j]);
    }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
L15:
  mov    %eax,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x23,%rax
  jne    L15
  lea    0x1c(%rsp),%r14
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    D2(%rip),%r12
L27:
  lea    -0x1c(%r14),%rbp
  mov    %rbp,%rbx
L4:
  lea    0x0(%rbp,%r13,1),%rax
  mov    (%rax,%r15,1),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  add    $0x4,%rbx
  cmp    %r14,%rbx
  jne    L4
  sub    $0x1c,%r13
  add    $0x1c,%r15
  add    $0x1c,%r14
  cmp    $0xffffffffffffff74,%r13
  jne    L27
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: %p %d


assistant: ```c
int main() {
  int a[5][7];
  int(*pa)[7] = a;
  for (int i = 0; i < 5 * 7; i++) {
    *((int *)a + i) = i;
  }
  for (int i = 0; i < 5; i++)
    for (int j = 0; j < 7; j++) {
      printf("%p %d\n", &a[i][j], a[i][j]);
      printf("%p %d\n", &pa[i][j], pa[i][j]);
    }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %eax,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0x23,%rax
  jne    L21
  lea    0x1c(%rsp),%r15
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D7(%rip),%r12
L0:
  lea    -0x1c(%r15),%rbp
  mov    %rbp,%rbx
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    0x0(%rbp,%r13,1),%rax
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  mov    (%rax,%r14,1),%edx
  call   <printf@plt>
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L10
  sub    $0x1c,%r13
  add    $0x1c,%r14
  lea    0x1c(%rbx),%r15
  cmp    $0xffffffffffffff74,%r13
  jne    L0
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0xa8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: %p %d


assistant: ```c
int main() {
  int a[5][7];
  int(*pa)[7] = a;
  for (int i = 0; i < 5 * 7; i++) {
    *((int *)a + i) = i;
  }
  for (int i = 0; i < 5; i++)
    for (int j = 0; j < 7; j++) {
      printf("%p %d\n", &a[i][j], a[i][j]);
      printf("%p %d\n", &pa[i][j], pa[i][j]);
    }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <doprintf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  doprintf();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <doprintf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  doprintf();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <doprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  doprintf();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <doprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  doprintf();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L8
L51:
  movl   $0x1,-0x10(%rbp)
  jmp    L13
L80:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L11
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L11:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L9
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L39
L9:
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L39:
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L80
L8:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L51
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D34
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D16
datatype: string
name: disassemble_data
arguments: label: D47
datatype: string
name: disassemble_data
arguments: label: D37
datatype: string

tool: D34: %d %d

tool: D17: <


tool: D16: >


tool: D47: =


tool: D37: %d

assistant: ```c
int main() {
  int t, a, b, i;
  int c = 1;
  while (scanf("%d", &t) == 1) {
    for (i = 1; i <= t; i++) {
      scanf("%d %d", &a, &b);
      if (a < b)
        printf("<\n");
      else if (a > b)
        printf(">\n");
      else
        printf("=\n");
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%r15
  lea    D34(%rip),%rbp
  lea    D19(%rip),%r14
L86:
  lea    0xc(%rsp),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jne    L9
  lea    D20(%rip),%r12
  lea    D22(%rip),%r13
  cmpl   $0x0,0xc(%rsp)
  jg     L22
  jmp    L86
L37:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L5
L49:
  mov    %r14,%rdi
  call   <printf@plt>
L5:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jl     L86
L22:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  mov    0x14(%rsp),%eax
  cmp    %eax,%edx
  jl     L37
  jle    L49
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L5
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string
name: parse_data
arguments: tag: D34
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D20
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string

tool: D0: %d

tool: D34: %d %d

tool: D19: =


tool: D20: >


tool: D22: <


assistant: ```c
int main() {
  int t, a, b, i;
  int c = 1;
  while (scanf("%d", &t) == 1) {
    for (i = 1; i <= t; i++) {
      scanf("%d %d", &a, &b);
      if (a < b)
        printf("<\n");
      else if (a > b)
        printf(">\n");
      else
        printf("=\n");
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D7(%rip),%r15
  push   %r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L55:
  mov    0x8(%rsp),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jne    L81
  mov    0x1c(%rsp),%eax
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%rbp
  lea    D49(%rip),%r14
  test   %eax,%eax
  jg     L68
  jmp    L55
  nopl   (%rax)
L27:
  lea    D2(%rip),%rdi
  call   <printf@plt>
L28:
  add    $0x1,%ebx
  cmp    %ebx,0x1c(%rsp)
  jl     L55
L68:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  cmp    %eax,0x20(%rsp)
  jl     L17
  jg     L27
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L81:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D49
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D7: =


tool: D29: %d %d

tool: D0: %d

tool: D49: <


tool: D2: >


assistant: ```c
int main() {
  int t, a, b, i;
  int c = 1;
  while (scanf("%d", &t) == 1) {
    for (i = 1; i <= t; i++) {
      scanf("%d %d", &a, &b);
      if (a < b)
        printf("<\n");
      else if (a > b)
        printf(">\n");
      else
        printf("=\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rax
  mov    %rax,0x8(%rsp)
  nopw   0x0(%rax,%rax,1)
L38:
  mov    0x8(%rsp),%rsi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %eax,%ebx
  cmp    $0x1,%eax
  jne    L29
  mov    0x1c(%rsp),%eax
  lea    0x24(%rsp),%r12
  lea    0x20(%rsp),%rbp
  lea    D10(%rip),%r14
  test   %eax,%eax
  jg     L32
  jmp    L38
  nopl   (%rax)
L60:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L87:
  add    $0x1,%ebx
  cmp    %ebx,0x1c(%rsp)
  jl     L38
L32:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  cmp    %eax,0x20(%rsp)
  jl     L81
  jg     L60
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L87
  nopl   0x0(%rax,%rax,1)
L81:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L87
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D11
type: string
name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D10
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D0: =


tool: D11: %d %d

tool: D23: %d

tool: D10: <


tool: D8: >


assistant: ```c
int main() {
  int t, a, b, i;
  int c = 1;
  while (scanf("%d", &t) == 1) {
    for (i = 1; i <= t; i++) {
      scanf("%d %d", &a, &b);
      if (a < b)
        printf("<\n");
      else if (a > b)
        printf(">\n");
      else
        printf("=\n");
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x24(%rbp)
  je     L3
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L25
L3:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <looser@plt>
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: Usage: %s "YOUR NAME"


assistant: ```c
int main(int argn, char **argv) {
  char user[10];
  if (argn != 2) {
    printf("Usage: %s \"YOUR NAME\"\n", argv[0]);
    return 1;
  }
  strcpy(user, argv[1]);
  looser(user);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L26
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x20,%rsp
  pop    %rbx
  ret
L26:
  mov    0x8(%rsi),%rsi
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <looser@plt>
  mov    $0x0,%eax
  jmp    L24
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: Usage: %s "YOUR NAME"


assistant: ```c
int main(int argn, char **argv) {
  char user[10];
  if (argn != 2) {
    printf("Usage: %s \"YOUR NAME\"\n", argv[0]);
    return 1;
  }
  strcpy(user, argv[1]);
  looser(user);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L18
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  ret
L18:
  mov    0x8(%rsi),%rsi
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <looser@plt>
  xor    %eax,%eax
  jmp    L8
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: Usage: %s "YOUR NAME"


assistant: ```c
int main(int argn, char **argv) {
  char user[10];
  if (argn != 2) {
    printf("Usage: %s \"YOUR NAME\"\n", argv[0]);
    return 1;
  }
  strcpy(user, argv[1]);
  looser(user);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L14
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L2:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x20,%rsp
  pop    %rbp
  ret
L14:
  mov    0x8(%rsi),%rsi
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <looser@plt>
  xor    %eax,%eax
  jmp    L2
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type: string

tool: D1: Usage: %s "YOUR NAME"


assistant: ```c
int main(int argn, char **argv) {
  char user[10];
  if (argn != 2) {
    printf("Usage: %s \"YOUR NAME\"\n", argv[0]);
    return 1;
  }
  strcpy(user, argv[1]);
  looser(user);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  jmp    L24
L12:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <reverse@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L38
L43:
  mov    -0x8(%rbp),%eax
  xor    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L52
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  xor    $0x4c11db7,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L13
L52:
  shll   -0x8(%rbp)
L13:
  shll   -0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L38:
  cmpl   $0x7,-0x10(%rbp)
  jle    L43
  addl   $0x1,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L12
  mov    -0x8(%rbp),%eax
  not    %eax
  mov    %eax,%edi
  call   <reverse@plt>
  leave
  ret
```

assistant: ```c
unsigned int crc32(unsigned char *message, int length) {
  int i, j;
  unsigned int byte, crc;
  int index = 0;
  i = 0;
  crc = 0xFFFFFFFF;
  while (index < length) {
    byte = message[i];
    byte = reverse(byte);
    for (j = 0; j <= 7; j++) {
      if ((int)(crc ^ byte) < 0)
        crc = (crc << 1) ^ 0x04C11DB7;
      else
        crc = crc << 1;
      byte = byte << 1;
    }
    i = i + 1;
    index++;
  }
  return reverse(~crc);
}
```
user: What is the c source code of the assembly code below?

```asm
<crc32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L49
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    $0xffffffff,%ebx
  jmp    L34
L22:
  add    $0x1,%rbp
  cmp    %r12,%rbp
  je     L31
L34:
  movzbl 0x0(%rbp),%edi
  call   <reverse@plt>
  mov    $0x8,%ecx
L33:
  lea    (%rbx,%rbx,1),%edx
  xor    $0x4c11db7,%edx
  lea    (%rbx,%rbx,1),%esi
  xor    %eax,%ebx
  cmovns %esi,%edx
  mov    %edx,%ebx
  add    %eax,%eax
  sub    $0x1,%ecx
  jne    L33
  jmp    L22
L49:
  mov    $0xffffffff,%ebx
L31:
  mov    %ebx,%edi
  not    %edi
  call   <reverse@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int crc32(unsigned char *message, int length) {
  int i, j;
  unsigned int byte, crc;
  int index = 0;
  i = 0;
  crc = 0xFFFFFFFF;
  while (index < length) {
    byte = message[i];
    byte = reverse(byte);
    for (j = 0; j <= 7; j++) {
      if ((int)(crc ^ byte) < 0)
        crc = (crc << 1) ^ 0x04C11DB7;
      else
        crc = crc << 1;
      byte = byte << 1;
    }
    i = i + 1;
    index++;
  }
  return reverse(~crc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc32>:
  endbr64
  test   %esi,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rdi,%rax,1),%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  nopl   0x0(%rax)
L22:
  movzbl (%r12),%edi
  call   <reverse@plt>
  mov    $0x8,%edx
  nop
L27:
  mov    %eax,%esi
  xor    %ebx,%esi
  add    %ebx,%ebx
  mov    %ebx,%ecx
  xor    $0x4c11db7,%ecx
  test   %esi,%esi
  cmovs  %ecx,%ebx
  add    %eax,%eax
  sub    $0x1,%edx
  jne    L27
  add    $0x1,%r12
  cmp    %rbp,%r12
  jne    L22
  mov    %ebx,%edi
  pop    %rbx
  pop    %rbp
  not    %edi
  pop    %r12
  jmp    1050 <reverse@plt>
L3:
  xor    %edi,%edi
  jmp    1050 <reverse@plt>
```

assistant: ```c
unsigned int crc32(unsigned char *message, int length) {
  int i, j;
  unsigned int byte, crc;
  int index = 0;
  i = 0;
  crc = 0xFFFFFFFF;
  while (index < length) {
    byte = message[i];
    byte = reverse(byte);
    for (j = 0; j <= 7; j++) {
      if ((int)(crc ^ byte) < 0)
        crc = (crc << 1) ^ 0x04C11DB7;
      else
        crc = crc << 1;
      byte = byte << 1;
    }
    i = i + 1;
    index++;
  }
  return reverse(~crc);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<crc32>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0x1(%rdi,%rax,1),%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
L7:
  movzbl (%r12),%edi
  call   <reverse@plt>
  lea    (%rbx,%rbx,1),%edx
  mov    %edx,%ecx
  lea    (%rax,%rax,1),%esi
  xor    $0x4c11db7,%ecx
  xor    %eax,%ebx
  cmovs  %ecx,%edx
  lea    (%rdx,%rdx,1),%ecx
  mov    %ecx,%edi
  xor    $0x4c11db7,%edi
  xor    %edx,%esi
  lea    0x0(,%rax,4),%esi
  cmovs  %edi,%ecx
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,%edi
  xor    $0x4c11db7,%edi
  xor    %ecx,%esi
  lea    0x0(,%rax,8),%esi
  cmovs  %edi,%edx
  lea    (%rdx,%rdx,1),%ecx
  mov    %ecx,%edi
  xor    $0x4c11db7,%edi
  xor    %edx,%esi
  mov    %eax,%esi
  cmovs  %edi,%ecx
  shl    $0x4,%esi
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,%edi
  xor    $0x4c11db7,%edi
  xor    %ecx,%esi
  mov    %eax,%esi
  cmovs  %edi,%edx
  shl    $0x5,%esi
  lea    (%rdx,%rdx,1),%ecx
  mov    %ecx,%edi
  xor    $0x4c11db7,%edi
  xor    %edx,%esi
  mov    %eax,%esi
  cmovs  %edi,%ecx
  shl    $0x6,%esi
  lea    (%rcx,%rcx,1),%edx
  mov    %edx,%edi
  xor    $0x4c11db7,%edi
  xor    %ecx,%esi
  cmovs  %edi,%edx
  shl    $0x7,%eax
  lea    (%rdx,%rdx,1),%ebx
  mov    %ebx,%ecx
  xor    $0x4c11db7,%ecx
  xor    %edx,%eax
  cmovs  %ecx,%ebx
  add    $0x1,%r12
  cmp    %r12,%rbp
  jne    L7
  not    %ebx
  mov    %ebx,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <reverse@plt>
L17:
  xor    %edi,%edi
  jmp    1050 <reverse@plt>
```

assistant: ```c
unsigned int crc32(unsigned char *message, int length) {
  int i, j;
  unsigned int byte, crc;
  int index = 0;
  i = 0;
  crc = 0xFFFFFFFF;
  while (index < length) {
    byte = message[i];
    byte = reverse(byte);
    for (j = 0; j <= 7; j++) {
      if ((int)(crc ^ byte) < 0)
        crc = (crc << 1) ^ 0x04C11DB7;
      else
        crc = crc << 1;
      byte = byte << 1;
    }
    i = i + 1;
    index++;
  }
  return reverse(~crc);
}
```