ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<inv_icm30xxx_get_reg_bits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %ecx,%ebp
  mov    %r8,%rbx
  mov    %r8,%rcx
  call   <inv_icm30xxx_read_reg_one@plt>
  test   %eax,%eax
  jne    L3
  and    %ebp,(%rbx)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int inv_icm30xxx_get_reg_bits(struct inv_icm30xxx *s, uint8_t bank, uint8_t reg, uint8_t bits_mask, uint8_t *bits_mask_state) {
  int rc;
  if ((rc = inv_icm30xxx_read_reg_one(s, bank, reg, bits_mask_state)) != 0)
    return rc;
  *bits_mask_state &= bits_mask;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inv_icm30xxx_get_reg_bits>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  mov    %r8,%rcx
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <inv_icm30xxx_read_reg_one@plt>
  test   %eax,%eax
  jne    L2
  and    %ebp,(%rbx)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int inv_icm30xxx_get_reg_bits(struct inv_icm30xxx *s, uint8_t bank, uint8_t reg, uint8_t bits_mask, uint8_t *bits_mask_state) {
  int rc;
  if ((rc = inv_icm30xxx_read_reg_one(s, bank, reg, bits_mask_state)) != 0)
    return rc;
  *bits_mask_state &= bits_mask;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<inv_icm30xxx_get_reg_bits>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  mov    %r8,%rcx
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  call   <inv_icm30xxx_read_reg_one@plt>
  test   %eax,%eax
  jne    L4
  and    %ebp,(%rbx)
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int inv_icm30xxx_get_reg_bits(struct inv_icm30xxx *s, uint8_t bank, uint8_t reg, uint8_t bits_mask, uint8_t *bits_mask_state) {
  int rc;
  if ((rc = inv_icm30xxx_read_reg_one(s, bank, reg, bits_mask_state)) != 0)
    return rc;
  *bits_mask_state &= bits_mask;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L19
L17:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  add    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x64,-0xc(%rbp)
  jle    L17
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, s1 = 0, s2 = 0;
  for (i = 1; i <= 100; i++) {
    s1 += i * i;
    s2 += i;
  }
  s2 *= s2;
  printf("%d\n", s2 - s1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  mov    $0x17ff976,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, s1 = 0, s2 = 0;
  for (i = 1; i <= 100; i++) {
    s1 += i * i;
    s2 += i;
  }
  s2 *= s2;
  printf("%d\n", s2 - s1);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17ff976,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type: string

tool: D3: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, s1 = 0, s2 = 0;
  for (i = 1; i <= 100; i++) {
    s1 += i * i;
    s2 += i;
  }
  s2 *= s2;
  printf("%d\n", s2 - s1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x17ff976,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, s1 = 0, s2 = 0;
  for (i = 1; i <= 100; i++) {
    s1 += i * i;
    s2 += i;
  }
  s2 *= s2;
  printf("%d\n", s2 - s1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<socks5_mkmethods_plain_wrapper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <socks5_mkmethods_plain@plt>
  leave
  ret
```

assistant: ```c
struct evbuffer *socks5_mkmethods_plain_wrapper(void *p) {
  int *do_password = p;
  return socks5_mkmethods_plain(*do_password);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<socks5_mkmethods_plain_wrapper>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <socks5_mkmethods_plain@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
struct evbuffer *socks5_mkmethods_plain_wrapper(void *p) {
  int *do_password = p;
  return socks5_mkmethods_plain(*do_password);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<socks5_mkmethods_plain_wrapper>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <socks5_mkmethods_plain@plt>
```

assistant: ```c
struct evbuffer *socks5_mkmethods_plain_wrapper(void *p) {
  int *do_password = p;
  return socks5_mkmethods_plain(*do_password);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<socks5_mkmethods_plain_wrapper>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <socks5_mkmethods_plain@plt>
```

assistant: ```c
struct evbuffer *socks5_mkmethods_plain_wrapper(void *p) {
  int *do_password = p;
  return socks5_mkmethods_plain(*do_password);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x10(%rbp)
  movq   $0x2a,-0x8(%rbp)
  jmp    L5
L17:
  mov    -0xc(%rbp),%eax
  imul   -0x10(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L17
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash(unsigned char *str) {
  int i = 1;
  unsigned long hash = 42;
  int c;
  while (c = *str++) {
    hash = hash + c * i;
    i++;
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hash>:
  endbr64
  lea    0x1(%rdi),%rax
  movzbl (%rdi),%ecx
  test   %ecx,%ecx
  je     L10
  mov    %rax,%rdx
  mov    $0x2a,%esi
  mov    $0x1,%edi
  sub    %eax,%edi
L6:
  lea    (%rdi,%rdx,1),%eax
  imul   %ecx,%eax
  cltq
  add    %rax,%rsi
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%ecx
  test   %ecx,%ecx
  jne    L6
L29:
  mov    %rsi,%rax
  ret
L10:
  mov    $0x2a,%esi
  jmp    L29
```

assistant: ```c
unsigned long hash(unsigned char *str) {
  int i = 1;
  unsigned long hash = 42;
  int c;
  while (c = *str++) {
    hash = hash + c * i;
    i++;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash>:
  endbr64
  movzbl (%rdi),%ecx
  lea    0x1(%rdi),%rdx
  mov    $0x2a,%r8d
  test   %ecx,%ecx
  je     L7
  mov    $0x1,%esi
  sub    %edx,%esi
  nopl   0x0(%rax)
L12:
  lea    (%rsi,%rdx,1),%eax
  add    $0x1,%rdx
  imul   %ecx,%eax
  movzbl -0x1(%rdx),%ecx
  cltq
  add    %rax,%r8
  test   %ecx,%ecx
  jne    L12
L7:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long hash(unsigned char *str) {
  int i = 1;
  unsigned long hash = 42;
  int c;
  while (c = *str++) {
    hash = hash + c * i;
    i++;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%ecx
  lea    0x1(%rdi),%rdx
  mov    $0x2a,%r8d
  test   %ecx,%ecx
  je     L3
  mov    $0x1,%esi
  sub    %edx,%esi
  nopl   0x0(%rax)
L11:
  lea    (%rsi,%rdx,1),%eax
  add    $0x1,%rdx
  imul   %ecx,%eax
  movzbl -0x1(%rdx),%ecx
  cltq
  add    %rax,%r8
  test   %ecx,%ecx
  jne    L11
L3:
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long hash(unsigned char *str) {
  int i = 1;
  unsigned long hash = 42;
  int c;
  while (c = *str++) {
    hash = hash + c * i;
    i++;
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L20
L42:
  mov    D2(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x8(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <recv@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L51
  cmpl   $0x0,-0x14(%rbp)
  je     L51
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x8(%rbp)
L20:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jb     L42
L51:
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpl   $0x0,-0x14(%rbp)
  jle    L56
  mov    -0x10(%rbp),%rax
  jmp    L23
L56:
  mov    -0x14(%rbp),%eax
L23:
  leave
  ret
```

assistant: ```c
int readn(int sfd, char *const data, size_t *dsize) {
  ssize_t n;
  size_t total = 0;
  size_t bytesleft = *dsize;
  while (total < *dsize) {
    n = recv(sfd, data + total, bytesleft, MSG_NOSIGNAL);
    if (-1 == n || 0 == n) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *dsize = total;
  data[total] = '\0';
  return n > 0 ? (int)total : n;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<readn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    (%rdx),%rbp
  test   %rbp,%rbp
  je     L21
  mov    %edi,%r14d
  mov    $0x0,%ebx
  mov    D4(%rip),%r15
L27:
  lea    0x0(%r13,%rbx,1),%rsi
  mov    (%r15),%ecx
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <recv@plt>
  lea    0x1(%rax),%edx
  cmp    $0x1,%edx
  jbe    L30
  movslq %eax,%rdx
  add    %rdx,%rbx
  sub    %rdx,%rbp
  cmp    %rbx,(%r12)
  ja     L27
L30:
  mov    %rbx,(%r12)
  movb   $0x0,0x0(%r13,%rbx,1)
  test   %eax,%eax
  cmovg  %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    %rbp,%rbx
  mov    $0x0,%eax
  jmp    L30
```

assistant: ```c
int readn(int sfd, char *const data, size_t *dsize) {
  ssize_t n;
  size_t total = 0;
  size_t bytesleft = *dsize;
  while (total < *dsize) {
    n = recv(sfd, data + total, bytesleft, MSG_NOSIGNAL);
    if (-1 == n || 0 == n) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *dsize = total;
  data[total] = '\0';
  return n > 0 ? (int)total : n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%r15
  test   %r15,%r15
  je     L2
  mov    %edi,%r12d
  xor    %r14d,%r14d
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L1:
  movslq %eax,%rdx
  add    %rdx,%r14
  sub    %rdx,%r15
  cmp    %r14,(%rbx)
  jbe    L37
L30:
  mov    D7(%rip),%rax
  lea    0x0(%rbp,%r14,1),%r13
  mov    %r15,%rdx
  mov    %r12d,%edi
  mov    %r13,%rsi
  mov    (%rax),%ecx
  call   <recv@plt>
  lea    0x1(%rax),%edx
  cmp    $0x1,%edx
  ja     L1
  mov    %r14,(%rbx)
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L37:
  add    %r14,%rbp
L17:
  test   %eax,%eax
  mov    %r14,(%rbx)
  cmovg  %r14d,%eax
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  xor    %r14d,%r14d
  xor    %eax,%eax
  jmp    L17
```

assistant: ```c
int readn(int sfd, char *const data, size_t *dsize) {
  ssize_t n;
  size_t total = 0;
  size_t bytesleft = *dsize;
  while (total < *dsize) {
    n = recv(sfd, data + total, bytesleft, MSG_NOSIGNAL);
    if (-1 == n || 0 == n) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *dsize = total;
  data[total] = '\0';
  return n > 0 ? (int)total : n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    (%rdx),%r15
  test   %r15,%r15
  je     L8
  mov    %edi,%r12d
  xor    %r14d,%r14d
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L14:
  movslq %eax,%rdx
  add    %rdx,%r14
  sub    %rdx,%r15
  cmp    %r14,(%rbx)
  jbe    L29
L43:
  mov    D3(%rip),%rax
  lea    0x0(%rbp,%r14,1),%r13
  mov    %r15,%rdx
  mov    %r12d,%edi
  mov    %r13,%rsi
  mov    (%rax),%ecx
  call   <recv@plt>
  lea    0x1(%rax),%edx
  cmp    $0x1,%edx
  ja     L14
  mov    %r14,(%rbx)
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  add    %r14,%rbp
L39:
  test   %eax,%eax
  mov    %r14,(%rbx)
  cmovg  %r14d,%eax
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  xor    %r14d,%r14d
  xor    %eax,%eax
  jmp    L39
```

assistant: ```c
int readn(int sfd, char *const data, size_t *dsize) {
  ssize_t n;
  size_t total = 0;
  size_t bytesleft = *dsize;
  while (total < *dsize) {
    n = recv(sfd, data + total, bytesleft, MSG_NOSIGNAL);
    if (-1 == n || 0 == n) {
      break;
    }
    total += n;
    bytesleft -= n;
  }
  *dsize = total;
  data[total] = '\0';
  return n > 0 ? (int)total : n;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strrep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L69
  mov    -0x50(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L25
L69:
  mov    $0x0,%eax
  jmp    L63
L67:
  cmpl   $0x0,-0x34(%rbp)
  jle    L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memmove@plt>
  jmp    L43
L9:
  cmpl   $0x0,-0x34(%rbp)
  jns    L43
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x34(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rax,%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L43:
  mov    -0x20(%rbp),%rdx
  mov    -0x58(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
L25:
  mov    -0x50(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L67
  mov    $0x1,%eax
L63:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strrep(char *buf, char *mae, char *ato) {
  char *mitsuke, *findpos;
  size_t maelen, atolen;
  int shift;
  findpos = buf;
  maelen = strlen(mae);
  atolen = strlen(ato);
  shift = (int)(strlen(ato) - strlen(mae));
  if (maelen == 0 || strstr(findpos, mae) == NULL)
    return 0;
  while ((mitsuke = strstr(findpos, mae)) != NULL) {
    if (shift > 0) {
      memmove(mitsuke + shift, mitsuke, strlen(mitsuke) + 1);
    } else if (shift < 0) {
      memmove(mitsuke, mitsuke - shift, strlen(mitsuke) + shift + 1);
    }
    memmove(mitsuke, ato, atolen);
    findpos = mitsuke + atolen;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strrep>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r15
  mov    $0x0,%eax
  test   %r15,%r15
  je     L32
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L71
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %eax,%r13d
  sub    %r15d,%r13d
  movslq %r13d,%r15
  jmp    L36
L67:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  lea    (%rbx,%r15,1),%rdi
  mov    %rbx,%rsi
  call   <memmove@plt>
L19:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L61
L36:
  test   %r13d,%r13d
  jg     L67
  jns    L19
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%r15,%rax,1),%rdx
  mov    %rbx,%rsi
  sub    %r15,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
  jmp    L19
L61:
  mov    $0x1,%eax
L32:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  mov    $0x0,%eax
  jmp    L32
```

assistant: ```c
int strrep(char *buf, char *mae, char *ato) {
  char *mitsuke, *findpos;
  size_t maelen, atolen;
  int shift;
  findpos = buf;
  maelen = strlen(mae);
  atolen = strlen(ato);
  shift = (int)(strlen(ato) - strlen(mae));
  if (maelen == 0 || strstr(findpos, mae) == NULL)
    return 0;
  while ((mitsuke = strstr(findpos, mae)) != NULL) {
    if (shift > 0) {
      memmove(mitsuke + shift, mitsuke, strlen(mitsuke) + 1);
    } else if (shift < 0) {
      memmove(mitsuke, mitsuke - shift, strlen(mitsuke) + shift + 1);
    }
    memmove(mitsuke, ato, atolen);
    findpos = mitsuke + atolen;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strrep>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L39
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r15
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L39
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rax,%rbp
  sub    %r15d,%r14d
  movslq %r14d,%r15
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L10:
  jne    L12
L28:
  mov    %rbx,%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L77
L79:
  test   %r14d,%r14d
  jle    L10
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%rbx,%r15,1),%rdi
  mov    %rbx,%rsi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L77:
  mov    $0x1,%r14d
L39:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  lea    0x1(%r15,%rax,1),%rdx
  sub    %r15,%rsi
  call   <memmove@plt>
  jmp    L28
```

assistant: ```c
int strrep(char *buf, char *mae, char *ato) {
  char *mitsuke, *findpos;
  size_t maelen, atolen;
  int shift;
  findpos = buf;
  maelen = strlen(mae);
  atolen = strlen(ato);
  shift = (int)(strlen(ato) - strlen(mae));
  if (maelen == 0 || strstr(findpos, mae) == NULL)
    return 0;
  while ((mitsuke = strstr(findpos, mae)) != NULL) {
    if (shift > 0) {
      memmove(mitsuke + shift, mitsuke, strlen(mitsuke) + 1);
    } else if (shift < 0) {
      memmove(mitsuke, mitsuke - shift, strlen(mitsuke) + shift + 1);
    }
    memmove(mitsuke, ato, atolen);
    findpos = mitsuke + atolen;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strrep>:
  endbr64
  push   %r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L55
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %rax,%r15
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L55
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %rax,%rbp
  sub    %r15d,%r14d
  test   %r14d,%r14d
  jg     L39
  movslq %r14d,%r14
  lea    0x1(%r14),%r15
  jne    L37
  nopl   0x0(%rax)
L88:
  mov    %rbx,%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L88
L46:
  mov    $0x1,%r14d
L55:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  lea    (%r15,%rax,1),%rdx
  sub    %r14,%rsi
  call   <memmove@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L37
  jmp    L46
  cs nopw 0x0(%rax,%rax,1)
L39:
  movslq %r14d,%r14
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%rbx,%r14,1),%rdi
  mov    %rbx,%rsi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rdx
  mov    %r13,%rsi
  call   <memmove@plt>
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L27
  mov    $0x1,%r14d
  jmp    L55
```

assistant: ```c
int strrep(char *buf, char *mae, char *ato) {
  char *mitsuke, *findpos;
  size_t maelen, atolen;
  int shift;
  findpos = buf;
  maelen = strlen(mae);
  atolen = strlen(ato);
  shift = (int)(strlen(ato) - strlen(mae));
  if (maelen == 0 || strstr(findpos, mae) == NULL)
    return 0;
  while ((mitsuke = strstr(findpos, mae)) != NULL) {
    if (shift > 0) {
      memmove(mitsuke + shift, mitsuke, strlen(mitsuke) + 1);
    } else if (shift < 0) {
      memmove(mitsuke, mitsuke - shift, strlen(mitsuke) + shift + 1);
    }
    memmove(mitsuke, ato, atolen);
    findpos = mitsuke + atolen;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_fail_if>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <eval_boolean@plt>
  test   %rax,%rax
  je     L7
  mov    $0x1,%edi
  call   <exit@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void cmd_fail_if(const char *assign_to, char *arg) {
  (void)assign_to;
  if (eval_boolean(arg))
    exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmd_fail_if>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  call   <eval_boolean@plt>
  test   %rax,%rax
  jne    L17
L5:
  add    $0x8,%rsp
  ret
L17:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

assistant: ```c
void cmd_fail_if(const char *assign_to, char *arg) {
  (void)assign_to;
  if (eval_boolean(arg))
    exit(1);
}
```