ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<has_magic>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %esi,%ebp
  and    $0x1,%ebp
  and    $0x8,%ebx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L159
  lea    0x1(%rdi),%r12
  movabs $0x2000000200001,%r13
  jmp    L88
L133:
  test   %ebp,%ebp
  jne    L143
  cmpb   $0x0,0x1(%rdi)
  je     L7
  add    $0x2,%rdi
  jmp    L90
L132:
  movzbl %al,%edx
  mov    %r12,%rdi
  test   $0x80,%al
  je     L14
L90:
  lea    0x1(%rdi),%r12
  movzbl (%rdi),%eax
  test   %al,%al
  je     L170
L88:
  cmp    $0x5c,%al
  je     L133
  jg     L132
  lea    -0x2a(%rax),%edx
  cmp    $0x31,%dl
  ja     L132
  bt     %rdx,%r13
  jae    L95
  mov    $0x1,%ebp
L7:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L143:
  mov    %r12,%rdi
  jmp    L90
L170:
  mov    $0x0,%ebp
  jmp    L7
L159:
  mov    $0x0,%ebp
  jmp    L7
L2:
  mov    $0x1,%ebp
  jmp    L7
L95:
  movzbl %al,%edx
L14:
  mov    %edx,%edi
  call   <isalpha@plt>
  test   %ebx,%ebx
  je     L112
  test   %eax,%eax
  jne    L2
L112:
  mov    %r12,%rdi
  jmp    L90
```

assistant: ```c
int has_magic(s, flags) const char *s;
int flags;
{
  const int escape = !(flags & 0x01);
  const int nocase = flags & 0x08;
  register const char *p = s;
  register char c;
  while ((c = *p++) != 0) {
    switch (c) {
    case '*':
    case '?':
    case '[':
      return 1;
    case '\\':
      if (escape && !(c = *p++))
        return 0;
      continue;
    default:
      if (!0 && (isascii((int)(unsigned char)(c)) && isalpha((int)(unsigned char)(c))) && nocase)
        return 1;
    }
    p = ((p - 1) + 1);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<has_magic>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  and    $0x1,%r12d
  push   %rbx
  mov    %esi,%ebx
  and    $0x8,%ebx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L81
  movabs $0xfffdffffffdffffe,%r13
  lea    0x1(%rdi),%rbp
L104:
  cmp    $0x5c,%al
  je     L14
  jg     L123
  lea    -0x2a(%rax),%edx
  cmp    $0x31,%dl
  jbe    L118
L123:
  movzbl %al,%r8d
  mov    %rbp,%rdi
  test   $0x80,%al
  je     L103
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rbp
  test   %al,%al
  jne    L104
  nopl   0x0(%rax,%rax,1)
L81:
  xor    %r12d,%r12d
  jmp    L115
  nopl   (%rax)
L118:
  bt     %rdx,%r13
  jb     L11
L82:
  mov    $0x1,%r12d
L115:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  test   %r12d,%r12d
  jne    L147
  cmpb   $0x0,0x1(%rdi)
  je     L115
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  lea    0x1(%rdi),%rbp
  test   %al,%al
  jne    L104
  jmp    L81
  nopl   (%rax)
L11:
  movsbl %al,%r8d
L103:
  mov    %r8d,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L147
  test   %ebx,%ebx
  jne    L82
L147:
  mov    %rbp,%rdi
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rbp
  test   %al,%al
  jne    L104
  jmp    L81
```

assistant: ```c
int has_magic(s, flags) const char *s;
int flags;
{
  const int escape = !(flags & 0x01);
  const int nocase = flags & 0x08;
  register const char *p = s;
  register char c;
  while ((c = *p++) != 0) {
    switch (c) {
    case '*':
    case '?':
    case '[':
      return 1;
    case '\\':
      if (escape && !(c = *p++))
        return 0;
      continue;
    default:
      if (!0 && (isascii((int)(unsigned char)(c)) && isalpha((int)(unsigned char)(c))) && nocase)
        return 1;
    }
    p = ((p - 1) + 1);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<has_magic>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  and    $0x1,%r12d
  push   %rbx
  mov    %esi,%ebx
  and    $0x8,%ebx
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  test   %al,%al
  je     L174
  movabs $0xfffdffffffdffffe,%r13
  lea    0x1(%rdi),%rbp
  test   %r12d,%r12d
  jne    L22
L30:
  cmp    $0x5c,%al
  je     L267
  jg     L251
  lea    -0x2a(%rax),%edx
  cmp    $0x31,%dl
  jbe    L203
L251:
  movzbl %al,%r8d
  mov    %rbp,%rdi
  test   $0x80,%al
  je     L204
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rbp
  test   %al,%al
  jne    L30
L109:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L195:
  jg     L142
  lea    -0x2a(%rax),%edx
  cmp    $0x31,%dl
  jbe    L262
L142:
  movzbl %al,%edi
  test   $0x80,%al
  je     L86
L121:
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  je     L174
L22:
  cmp    $0x5c,%al
  jne    L195
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rbp
  test   %al,%al
  jne    L22
  jmp    L174
  xchg   %ax,%ax
L203:
  bt     %rdx,%r13
  jb     L224
L217:
  add    $0x8,%rsp
  mov    $0x1,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L262:
  bt     %rdx,%r13
  jae    L109
  movsbl %al,%edi
L86:
  call   <isalpha@plt>
  test   %ebx,%ebx
  je     L121
  test   %eax,%eax
  je     L121
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L224:
  movsbl %al,%r8d
L204:
  mov    %r8d,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  je     L94
  test   %ebx,%ebx
  jne    L217
L94:
  mov    %rbp,%rdi
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rbp
  test   %al,%al
  jne    L30
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L267:
  cmpb   $0x0,0x1(%rdi)
  je     L109
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  lea    0x1(%rdi),%rbp
  test   %al,%al
  jne    L30
  jmp    L109
  nopl   0x0(%rax,%rax,1)
L174:
  xor    %r12d,%r12d
  jmp    L109
```

assistant: ```c
int has_magic(s, flags) const char *s;
int flags;
{
  const int escape = !(flags & 0x01);
  const int nocase = flags & 0x08;
  register const char *p = s;
  register char c;
  while ((c = *p++) != 0) {
    switch (c) {
    case '*':
    case '?':
    case '[':
      return 1;
    case '\\':
      if (escape && !(c = *p++))
        return 0;
      continue;
    default:
      if (!0 && (isascii((int)(unsigned char)(c)) && isalpha((int)(unsigned char)(c))) && nocase)
        return 1;
    }
    p = ((p - 1) + 1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printGrid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L31:
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L39:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0x8,-0x4(%rbp)
  jle    L39
  mov    $0x6e,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L38:
  cmpl   $0x8,-0x8(%rbp)
  jle    L31
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: string

tool: D4: %2d

assistant: ```c
void printGrid(int grid[9][9]) {
  for (int row = 0; row < 9; row++) {
    for (int col = 0; col < 9; col++)
      printf("%2d", grid[row][col]);
    printf("n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printGrid>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x24(%rdi),%rbp
  lea    0x168(%rdi),%r13
  lea    D5(%rip),%r12
L14:
  lea    -0x24(%rbp),%rbx
L2:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L2
  mov    $0x6e,%edi
  call   <putchar@plt>
  add    $0x24,%rbp
  cmp    %r13,%rbp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: D5: %2d

assistant: ```c
void printGrid(int grid[9][9]) {
  for (int row = 0; row < 9; row++) {
    for (int col = 0; col < 9; col++)
      printf("%2d", grid[row][col]);
    printf("n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printGrid>:
  endbr64
  push   %r13
  lea    0x168(%rdi),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  lea    0x24(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L16:
  lea    -0x24(%rbp),%rbx
  nopl   0x0(%rax)
L10:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0x6e,%edi
  lea    0x24(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: %2d

assistant: ```c
void printGrid(int grid[9][9]) {
  for (int row = 0; row < 9; row++) {
    for (int col = 0; col < 9; col++)
      printf("%2d", grid[row][col]);
    printf("n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<printGrid>:
  endbr64
  push   %r13
  lea    0x168(%rdi),%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    0x24(%rdi),%rbp
  push   %rbx
  sub    $0x8,%rsp
L13:
  lea    -0x24(%rbp),%rbx
  nopl   0x0(%rax)
L10:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L10
  mov    $0x6e,%edi
  lea    0x24(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: %2d

assistant: ```c
void printGrid(int grid[9][9]) {
  for (int row = 0; row < 9; row++) {
    for (int col = 0; col < 9; col++)
      printf("%2d", grid[row][col]);
    printf("n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dalibc_linux_enter_program>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <dalibc_linux_initialize@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <main@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <dalibc_linux_deinitialize@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int dalibc_linux_enter_program(int argc, char *argv[], char *envp[]) {
  int ret;
  dalibc_linux_initialize();
  ret = main(argc, argv, envp);
  dalibc_linux_deinitialize();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dalibc_linux_enter_program>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    $0x0,%eax
  call   <dalibc_linux_initialize@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <main@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <dalibc_linux_deinitialize@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dalibc_linux_enter_program(int argc, char *argv[], char *envp[]) {
  int ret;
  dalibc_linux_initialize();
  ret = main(argc, argv, envp);
  dalibc_linux_deinitialize();
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dalibc_linux_enter_program>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  call   <dalibc_linux_initialize@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <main@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <dalibc_linux_deinitialize@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dalibc_linux_enter_program(int argc, char *argv[], char *envp[]) {
  int ret;
  dalibc_linux_initialize();
  ret = main(argc, argv, envp);
  dalibc_linux_deinitialize();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dalibc_linux_enter_program>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  call   <dalibc_linux_initialize@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <main@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <dalibc_linux_deinitialize@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int dalibc_linux_enter_program(int argc, char *argv[], char *envp[]) {
  int ret;
  dalibc_linux_initialize();
  ret = main(argc, argv, envp);
  dalibc_linux_deinitialize();
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x70(%rbp),%rax
  mov    $0x4cf,%r8d
  lea    D2(%rip),%rdx
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %eax,-0x74(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x74(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string
name: unpack_data
arguments: data_label: D6
data_type: string

tool: D2: this is the number: 

tool: D0: %s %d

tool: D6: %s


assistant: ```c
int main() {
  char str[100];
  int retVal = snprintf(str, 100, "%s %d", "this is the number: ", 1231);
  printf("%s\n", str);
  return retVal;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x4cf,%r8d
  lea    D29(%rip),%rcx
  lea    D8(%rip),%rdx
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %eax,%ebx
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %ebx,%eax
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D17
datatype: string

tool: D29: this is the number: 

tool: D8: %s %d

tool: D17: %s


assistant: ```c
int main() {
  char str[100];
  int retVal = snprintf(str, 100, "%s %d", "this is the number: ", 1231);
  printf("%s\n", str);
  return retVal;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  mov    $0x4cf,%r8d
  lea    D10(%rip),%rcx
  push   %rbp
  lea    D5(%rip),%rdx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x78,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D5
type_infered: string
name: extract_symbolic_data
arguments: tag: D18
type_infered: string

tool: D10: this is the number: 

tool: D5: %s %d

tool: D18: %s


assistant: ```c
int main() {
  char str[100];
  int retVal = snprintf(str, 100, "%s %d", "this is the number: ", 1231);
  printf("%s\n", str);
  return retVal;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x64,%esi
  mov    $0x4cf,%r8d
  lea    D2(%rip),%rcx
  push   %rbp
  lea    D4(%rip),%rdx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  mov    %eax,%r12d
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x78,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string

tool: D2: this is the number: 

tool: D4: %s %d

tool: D27: %s


assistant: ```c
int main() {
  char str[100];
  int retVal = snprintf(str, 100, "%s %d", "this is the number: ", 1231);
  printf("%s\n", str);
  return retVal;
}
```
user: What is the c source code of the assembly code below:

```asm
<worker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gang@plt>
  call   <worker>
  mov    $0x0,%eax
  call   <vector@plt>
  mov    $0x0,%eax
  call   <seq@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void worker(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<worker>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gang@plt>
  call   <worker>
  mov    $0x0,%eax
  call   <vector@plt>
  mov    $0x0,%eax
  call   <seq@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void worker(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<worker>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  call   <worker>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <seq@plt>
```

assistant: ```c
void worker(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<worker>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  xor    %eax,%eax
  call   <gang@plt>
  call   <worker>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  call   <seq@plt>
  xor    %eax,%eax
  call   <vector@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <seq@plt>
```

assistant: ```c
void worker(void) {
  gang();
  worker();
  vector();
  seq();
}
```
user: What is the c source code of the assembly code below:

```asm
<ngf_proplist_parse_boolean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L69
  cmpq   $0x0,-0x10(%rbp)
  jne    L41
L69:
  mov    $0x0,%eax
  jmp    L39
L41:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  lea    D30(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L67
  mov    -0x8(%rbp),%rax
  mov    $0x4,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L20
L67:
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  jmp    L39
L20:
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  mov    $0x5,%edx
  lea    D34(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L78
L8:
  mov    -0x10(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x1,%eax
  jmp    L39
L78:
  mov    $0x0,%eax
L39:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D30
type_guessed: string
name: unpack_data
arguments: data_tag: D0
type_guessed: string
name: unpack_data
arguments: data_tag: D9
type_guessed: string
name: unpack_data
arguments: data_tag: D34
type_guessed: string

tool: D30: 1

tool: D0: true

tool: D9: 0

tool: D34: false

assistant: ```c
int ngf_proplist_parse_boolean(const char *value, int *boolean_value) {
  if (value == NULL || boolean_value == NULL)
    return 0;
  if (strncmp(value, "1", 1) == 0 || strncasecmp(value, "true", 4) == 0) {
    *boolean_value = 1;
    return 1;
  } else if (strncmp(value, "0", 1) == 0 || strncasecmp(value, "false", 5) == 0) {
    *boolean_value = 0;
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ngf_proplist_parse_boolean>:
  endbr64
  test   %rdi,%rdi
  je     L48
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L50
  mov    $0x1,%edx
  lea    D13(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L42
L1:
  movl   $0x1,0x0(%rbp)
  mov    $0x1,%eax
L50:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  mov    $0x4,%edx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  test   %rax,%rax
  je     L1
  mov    $0x1,%edx
  lea    D30(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L53
L32:
  movl   $0x0,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L50
L53:
  mov    $0x5,%edx
  lea    D24(%rip),%rsi
  mov    %rbx,%rdi
  call   <strncasecmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L50
  jmp    L32
L48:
  mov    $0x0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D30
type_infered: string
name: disassemble_data
arguments: data_tag: D24
type_infered: string

tool: D13: 1

tool: D7: true

tool: D30: 0

tool: D24: false

assistant: ```c
int ngf_proplist_parse_boolean(const char *value, int *boolean_value) {
  if (value == NULL || boolean_value == NULL)
    return 0;
  if (strncmp(value, "1", 1) == 0 || strncasecmp(value, "true", 4) == 0) {
    *boolean_value = 1;
    return 1;
  } else if (strncmp(value, "0", 1) == 0 || strncasecmp(value, "false", 5) == 0) {
    *boolean_value = 0;
    return 1;
  }
  return 0;
}
```