ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{ return 0; }
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(argc, argv)
int argc;
char **argv;
{ return 0; }
```
user: What is the c source code of the assembly code below:

```asm
<_get_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
unsigned _get_short(const uint8_t *buf) {
  uint16_t _tmp;
  memcpy(&_tmp, buf, 2);
  return _tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_get_short>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x2,%edx
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned _get_short(const uint8_t *buf) {
  uint16_t _tmp;
  memcpy(&_tmp, buf, 2);
  return _tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_get_short>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned _get_short(const uint8_t *buf) {
  uint16_t _tmp;
  memcpy(&_tmp, buf, 2);
  return _tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_get_short>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    $0x2,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned _get_short(const uint8_t *buf) {
  uint16_t _tmp;
  memcpy(&_tmp, buf, 2);
  return _tmp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  jmp    L7
L17:
  mov    $0x0,%eax
  call   <function_parent@plt>
L7:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int element = 10;
  while (--element)
    function_parent();
  putchar('\n');
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x9,%ebx
L9:
  mov    $0x0,%eax
  call   <function_parent@plt>
  sub    $0x1,%ebx
  jne    L9
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int element = 10;
  while (--element)
    function_parent();
  putchar('\n');
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x9,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <function_parent@plt>
  sub    $0x1,%ebx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int element = 10;
  while (--element)
    function_parent();
  putchar('\n');
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x9,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <function_parent@plt>
  sub    $0x1,%ebx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int element = 10;
  while (--element)
    function_parent();
  putchar('\n');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getv4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L48
L9:
  movsbl -0x19(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L91
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  je     L60
  cmpl   $0x0,-0x14(%rbp)
  jne    L60
  mov    $0x0,%eax
  jmp    L158
L60:
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x14(%rbp)
  lea    D0(%rip),%rdx
  mov    -0x8(%rbp),%rax
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0xff,-0x14(%rbp)
  jle    L48
  mov    $0x0,%eax
  jmp    L158
L91:
  cmpb   $0x2e,-0x19(%rbp)
  je     L167
  cmpb   $0x2f,-0x19(%rbp)
  jne    L64
L167:
  mov    -0x30(%rbp),%rax
  sub    -0x10(%rbp),%rax
  cmp    $0xc,%rax
  jle    L118
  mov    $0x0,%eax
  jmp    L158
L118:
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  cmpb   $0x2f,-0x19(%rbp)
  jne    L183
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <getbits@plt>
  jmp    L158
L183:
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L48
L64:
  mov    $0x0,%eax
  jmp    L158
L48:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  cmpb   $0x0,-0x19(%rbp)
  jne    L9
  cmpl   $0x0,-0x18(%rbp)
  jne    L145
  mov    $0x0,%eax
  jmp    L158
L145:
  mov    -0x30(%rbp),%rax
  sub    -0x10(%rbp),%rax
  cmp    $0xc,%rax
  jle    L166
  mov    $0x0,%eax
  jmp    L158
L166:
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
L158:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: 0123456789

assistant: ```c
int getv4(const char *src, u_char *dst, int *bitsp) {
  static const char digits[] = "0123456789";
  u_char *odst = dst;
  int n;
  u_int val;
  char ch;
  val = 0;
  n = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    pch = strchr(digits, ch);
    if (pch != NULL) {
      if (n++ != 0 && val == 0)
        return (0);
      val *= 10;
      val += (pch - digits);
      if (val > 255)
        return (0);
      continue;
    }
    if (ch == '.' || ch == '/') {
      if (dst - odst > 3)
        return (0);
      *dst++ = val;
      if (ch == '/')
        return (getbits(src, bitsp));
      val = 0;
      n = 0;
      continue;
    }
    return (0);
  }
  if (n == 0)
    return (0);
  if (dst - odst > 3)
    return (0);
  *dst++ = val;
  return (1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getv4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,(%rsp)
  mov    %rdx,0x8(%rsp)
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L69
  lea    0x1(%rdi),%r13
  mov    %rsi,%r15
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  lea    D9(%rip),%r14
  jmp    L64
L162:
  lea    -0x2e(%rbp),%eax
  cmp    $0x1,%al
  ja     L166
  mov    %r15,%rax
  sub    (%rsp),%rax
  cmp    $0xc,%rax
  jg     L62
  lea    0x4(%r15),%rax
  mov    %ebx,(%r15)
  cmp    $0x2f,%bpl
  je     L105
  mov    %rax,%r15
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L171
L105:
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <getbits@plt>
  mov    %eax,%r12d
  jmp    L188
L183:
  add    $0x1,%r12d
L171:
  add    $0x1,%r13
  movzbl -0x1(%r13),%ebp
  test   %bpl,%bpl
  je     L65
L64:
  movsbl %bpl,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L162
  test   %ebx,%ebx
  jne    L20
  test   %r12d,%r12d
  jne    L12
L20:
  sub    %r14,%rax
  lea    (%rbx,%rbx,4),%edx
  lea    (%rax,%rdx,2),%eax
  mov    %eax,%ebx
  cmp    $0xff,%eax
  jle    L183
  mov    $0x0,%r12d
L188:
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  test   %r12d,%r12d
  je     L188
  mov    %r15,%rax
  sub    (%rsp),%rax
  mov    $0x0,%r12d
  cmp    $0xc,%rax
  jg     L188
  mov    %ebx,(%r15)
  mov    $0x1,%r12d
  jmp    L188
L69:
  mov    $0x0,%r12d
  jmp    L188
L12:
  mov    $0x0,%r12d
  jmp    L188
L166:
  mov    $0x0,%r12d
  jmp    L188
L62:
  mov    $0x0,%r12d
  jmp    L188
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: 0123456789

assistant: ```c
int getv4(const char *src, u_char *dst, int *bitsp) {
  static const char digits[] = "0123456789";
  u_char *odst = dst;
  int n;
  u_int val;
  char ch;
  val = 0;
  n = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    pch = strchr(digits, ch);
    if (pch != NULL) {
      if (n++ != 0 && val == 0)
        return (0);
      val *= 10;
      val += (pch - digits);
      if (val > 255)
        return (0);
      continue;
    }
    if (ch == '.' || ch == '/') {
      if (dst - odst > 3)
        return (0);
      *dst++ = val;
      if (ch == '/')
        return (getbits(src, bitsp));
      val = 0;
      n = 0;
      continue;
    }
    return (0);
  }
  if (n == 0)
    return (0);
  if (dst - odst > 3)
    return (0);
  *dst++ = val;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getv4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%r15d
  mov    %rsi,(%rsp)
  mov    %rdx,0x8(%rsp)
  test   %r15b,%r15b
  je     L123
  lea    0x1(%rdi),%r13
  mov    %rsi,%r12
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  lea    D0(%rip),%rbx
L59:
  movsbl %r15b,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L60
  test   %r14d,%r14d
  jne    L124
  test   %ebp,%ebp
  jne    L123
L124:
  sub    %rbx,%rax
  lea    (%r14,%r14,4),%ecx
  lea    (%rax,%rcx,2),%r14d
  cmp    $0xff,%r14d
  jg     L123
  add    $0x1,%ebp
L17:
  movzbl 0x0(%r13),%r15d
  add    $0x1,%r13
  test   %r15b,%r15b
  jne    L59
  test   %ebp,%ebp
  je     L123
  mov    %r12,%rax
  sub    (%rsp),%rax
  cmp    $0xc,%rax
  jg     L123
  mov    %r14d,(%r12)
  mov    $0x1,%eax
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L123:
  xor    %eax,%eax
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L60:
  lea    -0x2e(%r15),%eax
  cmp    $0x1,%al
  ja     L123
  mov    %r12,%rax
  sub    (%rsp),%rax
  cmp    $0xc,%rax
  jg     L123
  mov    %r14d,(%r12)
  lea    0x4(%r12),%rax
  cmp    $0x2f,%r15b
  je     L49
  mov    %rax,%r12
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L17
  xchg   %ax,%ax
L49:
  mov    0x8(%rsp),%rsi
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <getbits@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string

tool: D0: 0123456789

assistant: ```c
int getv4(const char *src, u_char *dst, int *bitsp) {
  static const char digits[] = "0123456789";
  u_char *odst = dst;
  int n;
  u_int val;
  char ch;
  val = 0;
  n = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    pch = strchr(digits, ch);
    if (pch != NULL) {
      if (n++ != 0 && val == 0)
        return (0);
      val *= 10;
      val += (pch - digits);
      if (val > 255)
        return (0);
      continue;
    }
    if (ch == '.' || ch == '/') {
      if (dst - odst > 3)
        return (0);
      *dst++ = val;
      if (ch == '/')
        return (getbits(src, bitsp));
      val = 0;
      n = 0;
      continue;
    }
    return (0);
  }
  if (n == 0)
    return (0);
  if (dst - odst > 3)
    return (0);
  *dst++ = val;
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getv4>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movzbl (%rdi),%r15d
  mov    %rsi,(%rsp)
  mov    %rdx,0x8(%rsp)
  test   %r15b,%r15b
  je     L75
  lea    0x1(%rdi),%r13
  mov    %rsi,%r12
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  lea    D2(%rip),%rbx
L44:
  movsbl %r15b,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L56
  test   %r14d,%r14d
  jne    L30
  test   %ebp,%ebp
  jne    L75
L30:
  sub    %rbx,%rax
  lea    (%r14,%r14,4),%ecx
  lea    (%rax,%rcx,2),%r14d
  cmp    $0xff,%r14d
  jg     L75
  add    $0x1,%ebp
L50:
  movzbl 0x0(%r13),%r15d
  add    $0x1,%r13
  test   %r15b,%r15b
  jne    L44
  test   %ebp,%ebp
  je     L75
  mov    %r12,%rax
  sub    (%rsp),%rax
  cmp    $0xc,%rax
  jg     L75
  mov    %r14d,(%r12)
  mov    $0x1,%eax
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L75:
  xor    %eax,%eax
L26:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L56:
  lea    -0x2e(%r15),%eax
  cmp    $0x1,%al
  ja     L75
  mov    %r12,%rax
  sub    (%rsp),%rax
  cmp    $0xc,%rax
  jg     L75
  mov    %r14d,(%r12)
  lea    0x4(%r12),%rax
  cmp    $0x2f,%r15b
  je     L129
  mov    %rax,%r12
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L50
  xchg   %ax,%ax
L129:
  mov    0x8(%rsp),%rsi
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <getbits@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: 0123456789

assistant: ```c
int getv4(const char *src, u_char *dst, int *bitsp) {
  static const char digits[] = "0123456789";
  u_char *odst = dst;
  int n;
  u_int val;
  char ch;
  val = 0;
  n = 0;
  while ((ch = *src++) != '\0') {
    const char *pch;
    pch = strchr(digits, ch);
    if (pch != NULL) {
      if (n++ != 0 && val == 0)
        return (0);
      val *= 10;
      val += (pch - digits);
      if (val > 255)
        return (0);
      continue;
    }
    if (ch == '.' || ch == '/') {
      if (dst - odst > 3)
        return (0);
      *dst++ = val;
      if (ch == '/')
        return (getbits(src, bitsp));
      val = 0;
      n = 0;
      continue;
    }
    return (0);
  }
  if (n == 0)
    return (0);
  if (dst - odst > 3)
    return (0);
  *dst++ = val;
  return (1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__ccaprice_syscall_args_3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x28(%rbp),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    %rsi,%rbx
  int    $0x80
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long __ccaprice_syscall_args_3(long A0, long A1, long A2, long A3) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3) : "memory");
  return R;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__ccaprice_syscall_args_3>:
  endbr64
  push   %rbx
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r8,%rcx
  int    $0x80
  pop    %rbx
  ret
```

assistant: ```c
long __ccaprice_syscall_args_3(long A0, long A1, long A2, long A3) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3) : "memory");
  return R;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__ccaprice_syscall_args_3>:
  endbr64
  mov    %rdx,%r8
  push   %rbx
  mov    %rcx,%rdx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r8,%rcx
  int    $0x80
  pop    %rbx
  ret
```

assistant: ```c
long __ccaprice_syscall_args_3(long A0, long A1, long A2, long A3) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3) : "memory");
  return R;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__ccaprice_syscall_args_3>:
  endbr64
  mov    %rdx,%r8
  push   %rbx
  mov    %rcx,%rdx
  mov    %rdi,%rax
  mov    %rsi,%rbx
  mov    %r8,%rcx
  int    $0x80
  pop    %rbx
  ret
```

assistant: ```c
long __ccaprice_syscall_args_3(long A0, long A1, long A2, long A3) {
  unsigned long R;
  __asm__ __volatile__("int $0x80" : "=a"(R) : "a"(A0), "b"(A1), "c"(A2), "d"(A3) : "memory");
  return R;
}
```
user: What is the c source code of the assembly code below:

```asm
<fb_hGetShortPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L9
L29:
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L50
L22:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L5
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x5c,(%rax)
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  je     L70
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L50:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L22
  jmp    L53
L70:
  nop
L53:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  mov    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *fb_hGetShortPath(char *src, char *dst, int maxlen) {
  if (strchr(src, 32) == 0) {
    strcpy(dst, src);
  } else {
    int i = 0;
    char *old_dst = dst;
    while ((*src) && (i < maxlen - 1)) {
      if (*src == ' ') {
        *dst++ = '\\';
        i++;
      }
      if (i == maxlen - 1)
        break;
      *dst++ = *src++;
      i++;
    }
    dst = old_dst;
    dst[maxlen - 1] = '\0';
  }
  return dst;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fb_hGetShortPath>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    $0x20,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L76
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L35
  lea    -0x1(%r12),%edi
  mov    %rbp,%rsi
  mov    $0x0,%eax
  test   %edi,%edi
  jg     L53
L35:
  movslq %r12d,%r12
  movb   $0x0,-0x1(%rbp,%r12,1)
L47:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L76:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L47
L84:
  cmp    %edi,%eax
  je     L35
  add    $0x1,%rbx
  lea    0x1(%rdx),%rsi
  movzbl -0x1(%rbx),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%eax
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L35
  cmp    %edi,%eax
  jge    L35
L53:
  mov    %rsi,%rdx
  cmp    $0x20,%cl
  jne    L84
  lea    0x1(%rsi),%rdx
  movb   $0x5c,(%rsi)
  add    $0x1,%eax
  jmp    L84
```

assistant: ```c
char *fb_hGetShortPath(char *src, char *dst, int maxlen) {
  if (strchr(src, 32) == 0) {
    strcpy(dst, src);
  } else {
    int i = 0;
    char *old_dst = dst;
    while ((*src) && (i < maxlen - 1)) {
      if (*src == ' ') {
        *dst++ = '\\';
        i++;
      }
      if (i == maxlen - 1)
        break;
      *dst++ = *src++;
      i++;
    }
    dst = old_dst;
    dst[maxlen - 1] = '\0';
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fb_hGetShortPath>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x20,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L68
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L7
  lea    -0x1(%rbx),%r8d
  mov    %r12,%rdi
  xor    %eax,%eax
  test   %r8d,%r8d
  jg     L57
  jmp    L7
  nopl   0x0(%rax)
L35:
  movzbl 0x0(%rbp),%esi
  add    $0x1,%rbp
  lea    0x1(%rcx),%rdi
  add    $0x1,%eax
  mov    %sil,(%rcx)
  movzbl 0x0(%rbp),%esi
  test   %sil,%sil
  je     L7
  cmp    %eax,%r8d
  jle    L7
L57:
  mov    %rdi,%rcx
  cmp    $0x20,%sil
  jne    L35
  add    $0x1,%eax
  movb   $0x5c,(%rdi)
  cmp    %r8d,%eax
  je     L7
  add    $0x1,%rcx
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L7:
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L68:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *fb_hGetShortPath(char *src, char *dst, int maxlen) {
  if (strchr(src, 32) == 0) {
    strcpy(dst, src);
  } else {
    int i = 0;
    char *old_dst = dst;
    while ((*src) && (i < maxlen - 1)) {
      if (*src == ' ') {
        *dst++ = '\\';
        i++;
      }
      if (i == maxlen - 1)
        break;
      *dst++ = *src++;
      i++;
    }
    dst = old_dst;
    dst[maxlen - 1] = '\0';
  }
  return dst;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fb_hGetShortPath>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    $0x20,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L52
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L19
  lea    -0x1(%rbx),%r9d
  mov    %r12,%r8
  xor    %ecx,%ecx
  test   %r9d,%r9d
  jg     L67
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%rbp
  mov    %al,(%rdi)
  lea    0x1(%rdi),%r8
  add    $0x1,%ecx
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L19
  cmp    %ecx,%r9d
  jle    L19
L67:
  mov    %r8,%rdi
  cmp    $0x20,%al
  jne    L35
  add    $0x1,%ecx
  movb   $0x5c,(%r8)
  cmp    %ecx,%r9d
  je     L19
  movzbl 0x0(%rbp),%eax
  add    $0x1,%rdi
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L19:
  movb   $0x0,-0x1(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L52:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *fb_hGetShortPath(char *src, char *dst, int maxlen) {
  if (strchr(src, 32) == 0) {
    strcpy(dst, src);
  } else {
    int i = 0;
    char *old_dst = dst;
    while ((*src) && (i < maxlen - 1)) {
      if (*src == ' ') {
        *dst++ = '\\';
        i++;
      }
      if (i == maxlen - 1)
        break;
      *dst++ = *src++;
      i++;
    }
    dst = old_dst;
    dst[maxlen - 1] = '\0';
  }
  return dst;
}
```
user: What is the c source code of the assembly code below?

```asm
<generateWorst>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <allocateMem@plt>
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L11
L9:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void generateWorst(int **x, int n) {
  allocateMem(x, n);
  int i = 0;
  for (i = n - 1; i >= 0; i--) {
    *(*x + i) = n - i;
  }
}
```