ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<display_score>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x28,%ecx
  mov    $0xf0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <my_gfx_cleararea@plt>
  mov    $0x5c,%edx
  mov    $0x38,%esi
  mov    $0x94,%edi
  call   <gfx_color@plt>
  mov    %rsp,%rbp
  mov    %ebx,%edx
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  movsd  D12(%rip),%xmm0
  mov    $0x28,%edi
  call   <gfx_text@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type: string
name: disassemble_data
arguments: data_label: D12
type: byte[8]

tool: D11: %d

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x3e,0x40]}

assistant: ```c
void display_score(int score) {
  char score_string[20];
  my_gfx_cleararea(0, 0, 12 * 20, 2 * 20);
  gfx_color(148, 56, 92);
  sprintf(score_string, "%d", score);
  gfx_text(2 * 20, 1.5 * 20, score_string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display_score>:
  endbr64
  push   %r12
  mov    $0x28,%ecx
  xor    %esi,%esi
  mov    %edi,%r12d
  push   %rbp
  xor    %edi,%edi
  mov    $0xf0,%edx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <my_gfx_cleararea@plt>
  mov    $0x5c,%edx
  mov    $0x38,%esi
  mov    $0x94,%edi
  call   <gfx_color@plt>
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r12d,%edx
  call   <sprintf@plt>
  movsd  D15(%rip),%xmm0
  mov    %rbp,%rsi
  mov    $0x28,%edi
  call   <gfx_text@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string
name: unpack_data
arguments: data_label: D15
type: byte[8]

tool: D8: %d

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x3e,0x40]}

assistant: ```c
void display_score(int score) {
  char score_string[20];
  my_gfx_cleararea(0, 0, 12 * 20, 2 * 20);
  gfx_color(148, 56, 92);
  sprintf(score_string, "%d", score);
  gfx_text(2 * 20, 1.5 * 20, score_string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<display_score>:
  endbr64
  push   %r12
  mov    $0x28,%ecx
  xor    %esi,%esi
  mov    %edi,%r12d
  push   %rbp
  xor    %edi,%edi
  mov    $0xf0,%edx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <my_gfx_cleararea@plt>
  mov    $0x5c,%edx
  mov    $0x38,%esi
  mov    $0x94,%edi
  call   <gfx_color@plt>
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  mov    %r12d,%edx
  call   <sprintf@plt>
  movsd  D19(%rip),%xmm0
  mov    %rbp,%rsi
  mov    $0x28,%edi
  call   <gfx_text@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D19
datatype: byte[8]

tool: D14: %d

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x3e,0x40]}

assistant: ```c
void display_score(int score) {
  char score_string[20];
  my_gfx_cleararea(0, 0, 12 * 20, 2 * 20);
  gfx_color(148, 56, 92);
  sprintf(score_string, "%d", score);
  gfx_text(2 * 20, 1.5 * 20, score_string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sendMsgToClient>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xd,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  movl   $0xd,(%rax)
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
datatype: string

tool: D8: 1233211234567

assistant: ```c
void sendMsgToClient(char *sendbuf, int *sendlen) {
  memcpy(sendbuf, "1233211234567", 13);
  *sendlen = 13;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendMsgToClient>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0xd,%edx
  lea    D3(%rip),%rsi
  call   <memcpy@plt>
  movl   $0xd,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: 1233211234567

assistant: ```c
void sendMsgToClient(char *sendbuf, int *sendlen) {
  memcpy(sendbuf, "1233211234567", 13);
  *sendlen = 13;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sendMsgToClient>:
  endbr64
  push   %rbx
  mov    $0xd,%edx
  mov    %rsi,%rbx
  lea    D9(%rip),%rsi
  call   <memcpy@plt>
  movl   $0xd,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: 1233211234567

assistant: ```c
void sendMsgToClient(char *sendbuf, int *sendlen) {
  memcpy(sendbuf, "1233211234567", 13);
  *sendlen = 13;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sendMsgToClient>:
  endbr64
  push   %rbx
  mov    $0xd,%edx
  mov    %rsi,%rbx
  lea    D3(%rip),%rsi
  call   <memcpy@plt>
  movl   $0xd,(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: 1233211234567

assistant: ```c
void sendMsgToClient(char *sendbuf, int *sendlen) {
  memcpy(sendbuf, "1233211234567", 13);
  *sendlen = 13;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<simple_guess_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L36
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L29
  mov    $0x10,%eax
  jmp    L8
L29:
  mov    $0x8,%eax
  jmp    L8
L36:
  mov    $0xa,%eax
L8:
  leave
  ret
```

assistant: ```c
unsigned int simple_guess_base(const char *cp) {
  if (cp[0] == '0') {
    if (((cp[1]) | 0x20) == 'x' && isxdigit(cp[2]))
      return 16;
    else
      return 8;
  } else {
    return 10;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simple_guess_base>:
  endbr64
  mov    $0xa,%eax
  cmpb   $0x30,(%rdi)
  jne    L6
  movzbl 0x1(%rdi),%edx
  or     $0x20,%edx
  mov    $0x8,%eax
  cmp    $0x78,%dl
  je     L8
L6:
  ret
L8:
  sub    $0x8,%rsp
  movsbl 0x2(%rdi),%edi
  call   <isxdigit@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xfffffff8,%eax
  add    $0x10,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int simple_guess_base(const char *cp) {
  if (cp[0] == '0') {
    if (((cp[1]) | 0x20) == 'x' && isxdigit(cp[2]))
      return 16;
    else
      return 8;
  } else {
    return 10;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<simple_guess_base>:
  endbr64
  cmpb   $0x30,(%rdi)
  mov    $0xa,%eax
  jne    L9
  movzbl 0x1(%rdi),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  je     L18
  mov    $0x8,%eax
  ret
  nop
L9:
  ret
  nopl   0x0(%rax)
L18:
  sub    $0x8,%rsp
  movsbl 0x2(%rdi),%edi
  call   <isxdigit@plt>
  mov    %rax,%r8
  mov    $0x10,%eax
  test   %r8,%r8
  jne    L15
  mov    $0x8,%eax
L15:
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int simple_guess_base(const char *cp) {
  if (cp[0] == '0') {
    if (((cp[1]) | 0x20) == 'x' && isxdigit(cp[2]))
      return 16;
    else
      return 8;
  } else {
    return 10;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<simple_guess_base>:
  endbr64
  cmpb   $0x30,(%rdi)
  mov    $0xa,%eax
  jne    L29
  movzbl 0x1(%rdi),%eax
  or     $0x20,%eax
  cmp    $0x78,%al
  je     L7
  mov    $0x8,%eax
  ret
  nop
L29:
  ret
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  movsbl 0x2(%rdi),%edi
  call   <isxdigit@plt>
  mov    %rax,%r8
  mov    $0x10,%eax
  test   %r8,%r8
  jne    L14
  mov    $0x8,%eax
L14:
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int simple_guess_base(const char *cp) {
  if (cp[0] == '0') {
    if (((cp[1]) | 0x20) == 'x' && isxdigit(cp[2]))
      return 16;
    else
      return 8;
  } else {
    return 10;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2728(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L143
  lea    0x10(%rsp),%r12
  mov    %r12,%rbp
  mov    $0x0,%r14d
  lea    D23(%rip),%r13
  jmp    L67
L103:
  lea    (%rbx,%rbp,1),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L103
L96:
  add    $0x1,%r14d
  mov    0xc(%rsp),%edx
  add    $0x64,%rbp
  cmp    %r14d,%edx
  jle    L50
L67:
  mov    $0x0,%ebx
  cmpl   $0x0,0xc(%rsp)
  jg     L103
  jmp    L96
L50:
  test   %edx,%edx
  jle    L95
  lea    0x74(%rsp),%rdi
  lea    -0x1(%rdx),%eax
  mov    %eax,%ecx
  lea    0x1(%r12,%rcx,1),%r9
  shr    %eax
  mov    %eax,%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x12c(%r12,%rax,8),%r11
  mov    $0x0,%eax
  mov    $0x0,%esi
  mov    $0x0,%r8d
  lea    -0x1(%rdx),%r10d
  jmp    L10
L17:
  cmp    $0x41,%cl
  cmove  %r8d,%eax
L92:
  cmp    %eax,%esi
  cmovl  %eax,%esi
  add    $0x1,%rdx
  cmp    %r9,%rdx
  je     L8
L139:
  movzbl (%rdx),%ecx
  cmp    $0x6f,%cl
  jne    L17
  add    $0x1,%eax
  jmp    L92
L8:
  movslq %r10d,%rdx
  jmp    L113
L106:
  cmp    $0x41,%cl
  cmove  %r8d,%eax
L109:
  cmp    %eax,%esi
  cmovl  %eax,%esi
  sub    $0x1,%rdx
  test   %edx,%edx
  js     L76
L113:
  movzbl (%rdi,%rdx,1),%ecx
  cmp    $0x6f,%cl
  jne    L106
  add    $0x1,%eax
  jmp    L109
L76:
  add    $0xc8,%rdi
  add    $0xc8,%r9
  cmp    %r11,%rdi
  je     L177
L10:
  lea    -0x64(%rdi),%rdx
  jmp    L139
L143:
  mov    $0x0,%esi
L177:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x2728(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x2730,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L95:
  mov    $0x0,%esi
  jmp    L177
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D17
type: string

tool: D10:  %d

tool: D23:  %c

tool: D17: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int size, i, j, maior = 0;
  char arr[100][100];
  int value = 0;
  char buff;
  scanf(" %d", &size);
  for (i = 0; i < size; ++i) {
    for (j = 0; j < size; ++j) {
      scanf(" %c", &arr[i][j]);
    }
  }
  for (i = 0; i < size; i++) {
    for (j = 0; j < size; ++j) {
      if (arr[i][j] == 'o')
        value++;
      else if (arr[i][j] == 'A')
        value = 0;
      if (value > maior)
        maior = value;
    }
    i++;
    for (j = size - 1; j >= 0; --j) {
      if (arr[i][j] == 'o')
        value++;
      else if (arr[i][j] == 'A')
        value = 0;
      if (value > maior)
        maior = value;
    }
  }
  printf("%d\n", maior);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fgmvwrite_surfflag_name_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rcx
  lea    -0x12(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0xa(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%edx
  lea    -0x12(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <gmvwrite_surfflag_name@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void fgmvwrite_surfflag_name_(char flagname[], int *numtypes) {
  char name[10];
  strncpy(name, flagname, 8);
  *(name + 8) = '\0';
  gmvwrite_surfflag_name(name, *numtypes);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fgmvwrite_surfflag_name_>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    $0x8,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x16(%rsp)
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <gmvwrite_surfflag_name@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fgmvwrite_surfflag_name_(char flagname[], int *numtypes) {
  char name[10];
  strncpy(name, flagname, 8);
  *(name + 8) = '\0';
  gmvwrite_surfflag_name(name, *numtypes);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fgmvwrite_surfflag_name_>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  movb   $0x0,0x16(%rsp)
  call   <gmvwrite_surfflag_name@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fgmvwrite_surfflag_name_(char flagname[], int *numtypes) {
  char name[10];
  strncpy(name, flagname, 8);
  *(name + 8) = '\0';
  gmvwrite_surfflag_name(name, *numtypes);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fgmvwrite_surfflag_name_>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  movb   $0x0,0x16(%rsp)
  call   <gmvwrite_surfflag_name@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fgmvwrite_surfflag_name_(char flagname[], int *numtypes) {
  char name[10];
  strncpy(name, flagname, 8);
  *(name + 8) = '\0';
  gmvwrite_surfflag_name(name, *numtypes);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_pthread_attr_getstack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pthread_attr_getstack@plt>
  leave
  ret
```

assistant: ```c
int my_pthread_attr_getstack(pthread_attr_t const *__attr, void **stack_base, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstack(realattr, stack_base, stack_size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_pthread_attr_getstack>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <pthread_attr_getstack@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int my_pthread_attr_getstack(pthread_attr_t const *__attr, void **stack_base, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstack(realattr, stack_base, stack_size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<my_pthread_attr_getstack>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <pthread_attr_getstack@plt>
```

assistant: ```c
int my_pthread_attr_getstack(pthread_attr_t const *__attr, void **stack_base, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstack(realattr, stack_base, stack_size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_pthread_attr_getstack>:
  endbr64
  mov    (%rdi),%edi
  jmp    1050 <pthread_attr_getstack@plt>
```

assistant: ```c
int my_pthread_attr_getstack(pthread_attr_t const *__attr, void **stack_base, size_t *stack_size) {
  pthread_attr_t *realattr = (pthread_attr_t *)*(unsigned int *)__attr;
  return pthread_attr_getstack(realattr, stack_base, stack_size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<run_dobldobl_continuation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <read_dobldobl_target_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <read_dobldobl_start_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <define_output_file@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <write_dobldobl_target_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <write_dobldobl_start_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <write_dobldobl_start_solutions@plt>
  mov    %eax,-0xc(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xe,%esi
  mov    $0x0,%edi
  call   <autotune_continuation_parameters@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <tune_continuation_parameters@plt>
  mov    %eax,-0xc(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <determine_output_during_continuation@plt>
  mov    %eax,-0xc(%rbp)
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <solve_by_dobldobl_homotopy_continuation@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <write_dobldobl_target_solutions@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string
name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D46
type: string
name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D11
type: string

tool: D2: 
Calling the double double path trackers in PHCpack...


tool: D30: 


tool: D46: 
Give the number of tasks (0 for no multitasking ) : 

tool: D28: %d

tool: D11: 
See the output file for results ...


assistant: ```c
int run_dobldobl_continuation(void) {
  int fail, nbtasks;
  printf("\nCalling the double double path trackers in PHCpack...\n");
  fail = read_dobldobl_target_system();
  fail = read_dobldobl_start_system();
  fail = define_output_file();
  fail = write_dobldobl_target_system();
  fail = write_dobldobl_start_system();
  fail = write_dobldobl_start_solutions();
  printf("\n");
  fail = autotune_continuation_parameters(0, 14);
  fail = tune_continuation_parameters();
  printf("\n");
  fail = determine_output_during_continuation();
  printf("\nGive the number of tasks (0 for no multitasking ) : ");
  scanf("%d", &nbtasks);
  printf("\nSee the output file for results ...\n");
  fail = solve_by_dobldobl_homotopy_continuation(nbtasks);
  fail = write_dobldobl_target_solutions();
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<run_dobldobl_continuation>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <read_dobldobl_target_system@plt>
  mov    $0x0,%eax
  call   <read_dobldobl_start_system@plt>
  mov    $0x0,%eax
  call   <define_output_file@plt>
  mov    $0x0,%eax
  call   <write_dobldobl_target_system@plt>
  mov    $0x0,%eax
  call   <write_dobldobl_start_system@plt>
  mov    $0x0,%eax
  call   <write_dobldobl_start_solutions@plt>
  lea    D17(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xe,%esi
  mov    $0x0,%edi
  call   <autotune_continuation_parameters@plt>
  mov    $0x0,%eax
  call   <tune_continuation_parameters@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <determine_output_during_continuation@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D49(%rip),%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <solve_by_dobldobl_homotopy_continuation@plt>
  mov    $0x0,%eax
  call   <write_dobldobl_target_solutions@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D49
data_type: string
name: disassemble_data
arguments: tag: D29
data_type: string

tool: D22: 
Calling the double double path trackers in PHCpack...


tool: D17: 


tool: D13: 
Give the number of tasks (0 for no multitasking ) : 

tool: D49: %d

tool: D29: 
See the output file for results ...


assistant: ```c
int run_dobldobl_continuation(void) {
  int fail, nbtasks;
  printf("\nCalling the double double path trackers in PHCpack...\n");
  fail = read_dobldobl_target_system();
  fail = read_dobldobl_start_system();
  fail = define_output_file();
  fail = write_dobldobl_target_system();
  fail = write_dobldobl_start_system();
  fail = write_dobldobl_start_solutions();
  printf("\n");
  fail = autotune_continuation_parameters(0, 14);
  fail = tune_continuation_parameters();
  printf("\n");
  fail = determine_output_during_continuation();
  printf("\nGive the number of tasks (0 for no multitasking ) : ");
  scanf("%d", &nbtasks);
  printf("\nSee the output file for results ...\n");
  fail = solve_by_dobldobl_homotopy_continuation(nbtasks);
  fail = write_dobldobl_target_solutions();
  return fail;
}
```