ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<recursive_binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L28
  mov    $0xffffffff,%eax
  jmp    L58
L28:
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jge    L55
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <recursive_binary_search>
  jmp    L58
L55:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jle    L41
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <recursive_binary_search>
  jmp    L58
L41:
  mov    -0x4(%rbp),%eax
L58:
  leave
  ret
```

assistant: ```c
int recursive_binary_search(const int str[], int search, int imin, int imax) {
  int imid;
  if (imax < imin)
    return -1;
  else {
    int imid = (imin + imax) / 2;
    if (str[imid] > search) {
      return recursive_binary_search(str, search, imin, --imid);
    } else if (str[imid] < search) {
      return recursive_binary_search(str, search, imid + 1, imax);
    } else {
      return imid;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recursive_binary_search>:
  endbr64
  cmp    %edx,%ecx
  jl     L45
  sub    $0x8,%rsp
  mov    %rdi,%r8
  mov    %esi,%edi
  lea    (%rcx,%rdx,1),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %eax,%esi
  sar    %esi
  mov    %esi,%eax
  movslq %esi,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %edi,%r9d
  jg     L12
  jl     L24
L25:
  add    $0x8,%rsp
  ret
L12:
  lea    -0x1(%rsi),%ecx
  mov    %edi,%esi
  mov    %r8,%rdi
  call   <recursive_binary_search>
  jmp    L25
L24:
  lea    0x1(%rsi),%edx
  mov    %edi,%esi
  mov    %r8,%rdi
  call   <recursive_binary_search>
  jmp    L25
L45:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int recursive_binary_search(const int str[], int search, int imin, int imax) {
  int imid;
  if (imax < imin)
    return -1;
  else {
    int imid = (imin + imax) / 2;
    if (str[imid] > search) {
      return recursive_binary_search(str, search, imin, --imid);
    } else if (str[imid] < search) {
      return recursive_binary_search(str, search, imid + 1, imax);
    } else {
      return imid;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recursive_binary_search>:
  endbr64
  mov    %rdi,%r8
  cmp    %ecx,%edx
  jle    L31
  jmp    L20
  nopl   (%rax)
L5:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L20
L31:
  lea    (%rcx,%rdx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %esi,(%r8,%rdi,4)
  jg     L5
  jge    L3
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L31
L20:
  mov    $0xffffffff,%r9d
L3:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int recursive_binary_search(const int str[], int search, int imin, int imax) {
  int imid;
  if (imax < imin)
    return -1;
  else {
    int imid = (imin + imax) / 2;
    if (str[imid] > search) {
      return recursive_binary_search(str, search, imin, --imid);
    } else if (str[imid] < search) {
      return recursive_binary_search(str, search, imid + 1, imax);
    } else {
      return imid;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recursive_binary_search>:
  endbr64
  mov    %rdi,%r8
  cmp    %ecx,%edx
  jle    L28
  jmp    L20
  nopl   (%rax)
L55:
  lea    -0x1(%rax),%ecx
  cmp    %edx,%ecx
  jl     L20
L28:
  lea    (%rcx,%rdx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  mov    %eax,%r9d
  cmp    %esi,(%r8,%rdi,4)
  jg     L55
  jge    L45
  lea    0x1(%rax),%edx
  cmp    %edx,%ecx
  jge    L28
L20:
  mov    $0xffffffff,%r9d
L45:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int recursive_binary_search(const int str[], int search, int imin, int imax) {
  int imid;
  if (imax < imin)
    return -1;
  else {
    int imid = (imin + imax) / 2;
    if (str[imid] > search) {
      return recursive_binary_search(str, search, imin, --imid);
    } else if (str[imid] < search) {
      return recursive_binary_search(str, search, imid + 1, imax);
    } else {
      return imid;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <String_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  String_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <String_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  String_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <String_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  String_test();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <String_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  String_test();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L3:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int *arr, int size) {
  int i = 0;
  int sum = 0;
  for (i = 0; i < size; i++)
    sum += arr[i];
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L13
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L28:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L28
L15:
  mov    %edx,%eax
  ret
L13:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
int sum(int *arr, int size) {
  int i = 0;
  int sum = 0;
  for (i = 0; i < size; i++)
    sum += arr[i];
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L4:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L4
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum(int *arr, int size) {
  int i = 0;
  int sum = 0;
  for (i = 0; i < size; i++)
    sum += arr[i];
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L24
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L54:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L54
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L69
L55:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L6
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L6
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L45:
  xor    %eax,%eax
L6:
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  ret
L24:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L55
```

assistant: ```c
int sum(int *arr, int size) {
  int i = 0;
  int sum = 0;
  for (i = 0; i < size; i++)
    sum += arr[i];
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gethostid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  ret
```

assistant: ```c
long int gethostid() {
  __set_errno(ENOSYS);
  return -1L;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gethostid>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffffffffffff,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long int gethostid() {
  __set_errno(ENOSYS);
  return -1L;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gethostid>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffffffffffff,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long int gethostid() {
  __set_errno(ENOSYS);
  return -1L;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gethostid>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffffffffffff,%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
long int gethostid() {
  __set_errno(ENOSYS);
  return -1L;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_strdupl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <n_malloc@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jne    L4
  mov    $0x0,%eax
  call   <nomem@plt>
  mov    $0x0,%eax
  jmp    L10
L4:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  add    %rbx,%rax
  movb   $0x0,(%rax)
  mov    %rbx,%rax
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *n_strdupl(const char *s, size_t length) {
  register char *new;
  if ((new = n_malloc(length + 1)) == NULL) {
    nomem();
    return NULL;
  }
  memcpy(new, s, length);
  new[length] = '\0';
  return new;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<n_strdupl>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rdi
  call   <n_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L12
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
L15:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    $0x0,%eax
  call   <nomem@plt>
  jmp    L15
```

assistant: ```c
char *n_strdupl(const char *s, size_t length) {
  register char *new;
  if ((new = n_malloc(length + 1)) == NULL) {
    nomem();
    return NULL;
  }
  memcpy(new, s, length);
  new[length] = '\0';
  return new;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<n_strdupl>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <n_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <nomem@plt>
  jmp    L6
```

assistant: ```c
char *n_strdupl(const char *s, size_t length) {
  register char *new;
  if ((new = n_malloc(length + 1)) == NULL) {
    nomem();
    return NULL;
  }
  memcpy(new, s, length);
  new[length] = '\0';
  return new;
}
```
user: What is the c source code of the assembly code below:

```asm
<n_strdupl>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <n_malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L6:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <nomem@plt>
  jmp    L6
```

assistant: ```c
char *n_strdupl(const char *s, size_t length) {
  register char *new;
  if ((new = n_malloc(length + 1)) == NULL) {
    nomem();
    return NULL;
  }
  memcpy(new, s, length);
  new[length] = '\0';
  return new;
}
```
user: What is the c source code of the assembly code below?

```asm
<update_framecrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  cmpl   $0x24b,-0x2c(%rbp)
  jg     L11
  movl   $0x0,-0x4(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x6f74ae27,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x8,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x24c,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  imul   -0x30(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L3
L11:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x6f74ae27,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x8,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x24c,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x6f74ae27,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x8,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x24c,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x30(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x30(%rbp),%eax
  imul   $0x24c,%eax,%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    %eax,%edx
  add    %ecx,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L3:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  sub    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_framecrc(uint32_t *restrict frame, uint32_t *restrict framesum, uint32_t *restrict framecrc, int ti, uint32_t value) {
  uint32_t subtr;
  if (ti < 588) {
    subtr = 0;
    frame[ti % 588] = value;
    *framecrc += value * (ti + 1);
  } else {
    subtr = frame[ti % 588];
    frame[ti % 588] = value;
    *framecrc += value * 588 - *framesum;
  }
  *framesum += value - subtr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<update_framecrc>:
  endbr64
  mov    %ecx,%eax
  cmp    $0x24b,%ecx
  jg     L15
  movslq %ecx,%rcx
  imul   $0x6f74ae27,%rcx,%rcx
  sar    $0x28,%rcx
  mov    %eax,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%ecx
  imul   $0x24c,%ecx,%ecx
  mov    %eax,%r9d
  sub    %ecx,%r9d
  movslq %r9d,%rcx
  mov    %r8d,(%rdi,%rcx,4)
  add    $0x1,%eax
  imul   %r8d,%eax
  add    (%rdx),%eax
  mov    $0x0,%ecx
L10:
  mov    %eax,(%rdx)
  sub    %ecx,%r8d
  add    %r8d,(%rsi)
  ret
L15:
  movslq %ecx,%rcx
  imul   $0x6f74ae27,%rcx,%rcx
  sar    $0x28,%rcx
  mov    %eax,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%ecx
  imul   $0x24c,%ecx,%ecx
  sub    %ecx,%eax
  cltq
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%ecx
  mov    %r8d,(%rax)
  imul   $0x24c,%r8d,%eax
  sub    (%rsi),%eax
  add    (%rdx),%eax
  jmp    L10
```

assistant: ```c
void update_framecrc(uint32_t *restrict frame, uint32_t *restrict framesum, uint32_t *restrict framecrc, int ti, uint32_t value) {
  uint32_t subtr;
  if (ti < 588) {
    subtr = 0;
    frame[ti % 588] = value;
    *framecrc += value * (ti + 1);
  } else {
    subtr = frame[ti % 588];
    frame[ti % 588] = value;
    *framecrc += value * 588 - *framesum;
  }
  *framesum += value - subtr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_framecrc>:
  endbr64
  movslq %ecx,%rax
  mov    %rdi,%r9
  mov    %rdx,%rdi
  mov    %rax,%rdx
  imul   $0x6f74ae27,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x28,%rax
  sub    %ecx,%eax
  mov    %edx,%ecx
  imul   $0x24c,%eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rax
  mov    (%rsi),%ecx
  lea    (%r9,%rax,4),%r9
  mov    (%rdi),%eax
  cmp    $0x24b,%edx
  jg     L8
  add    $0x1,%edx
  mov    %r8d,(%r9)
  imul   %r8d,%edx
  add    %eax,%edx
  mov    %r8d,%eax
  add    %ecx,%eax
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L8:
  imul   $0x24c,%r8d,%edx
  sub    %ecx,%edx
  add    %eax,%edx
  mov    %r8d,%eax
  sub    (%r9),%eax
  mov    %r8d,(%r9)
  add    %ecx,%eax
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void update_framecrc(uint32_t *restrict frame, uint32_t *restrict framesum, uint32_t *restrict framecrc, int ti, uint32_t value) {
  uint32_t subtr;
  if (ti < 588) {
    subtr = 0;
    frame[ti % 588] = value;
    *framecrc += value * (ti + 1);
  } else {
    subtr = frame[ti % 588];
    frame[ti % 588] = value;
    *framecrc += value * 588 - *framesum;
  }
  *framesum += value - subtr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<update_framecrc>:
  endbr64
  movslq %ecx,%rax
  mov    %rdi,%r9
  mov    %rdx,%rdi
  mov    %rax,%rdx
  imul   $0x6f74ae27,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x28,%rax
  sub    %ecx,%eax
  mov    %edx,%ecx
  imul   $0x24c,%eax,%eax
  sub    %eax,%ecx
  movslq %ecx,%rax
  mov    (%rsi),%ecx
  lea    (%r9,%rax,4),%r9
  mov    (%rdi),%eax
  cmp    $0x24b,%edx
  jg     L1
  add    $0x1,%edx
  mov    %r8d,(%r9)
  imul   %r8d,%edx
  add    %eax,%edx
  mov    %r8d,%eax
  add    %ecx,%eax
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
  nopl   (%rax)
L1:
  imul   $0x24c,%r8d,%edx
  sub    %ecx,%edx
  add    %eax,%edx
  mov    %r8d,%eax
  sub    (%r9),%eax
  mov    %r8d,(%r9)
  add    %ecx,%eax
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void update_framecrc(uint32_t *restrict frame, uint32_t *restrict framesum, uint32_t *restrict framecrc, int ti, uint32_t value) {
  uint32_t subtr;
  if (ti < 588) {
    subtr = 0;
    frame[ti % 588] = value;
    *framecrc += value * (ti + 1);
  } else {
    subtr = frame[ti % 588];
    frame[ti % 588] = value;
    *framecrc += value * 588 - *framesum;
  }
  *framesum += value - subtr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<G>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <exp@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D8(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double G(double x) {
  double value = exp(x);
  value = sqrt(value);
  value = value / 2;
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<G>:
  endbr64
  sub    $0x8,%rsp
  call   <exp@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L4
  sqrtsd %xmm0,%xmm0
L16:
  mulsd  D2(%rip),%xmm0
  add    $0x8,%rsp
  ret
L4:
  call   <sqrt@plt>
  jmp    L16
```

tool_calls: name: parse_data
arguments: tag: D2
data_type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double G(double x) {
  double value = exp(x);
  value = sqrt(value);
  value = value / 2;
  return value;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<G>:
  endbr64
  sub    $0x8,%rsp
  call   <exp@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L8
  sqrtsd %xmm0,%xmm0
L7:
  mulsd  D1(%rip),%xmm0
  add    $0x8,%rsp
  ret
L8:
  call   <sqrt@plt>
  jmp    L7
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: byte[8]

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double G(double x) {
  double value = exp(x);
  value = sqrt(value);
  value = value / 2;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<G>:
  endbr64
  sub    $0x8,%rsp
  call   <exp@plt>
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L17
  sqrtsd %xmm0,%xmm0
L9:
  mulsd  D7(%rip),%xmm0
  add    $0x8,%rsp
  ret
L17:
  call   <sqrt@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double G(double x) {
  double value = exp(x);
  value = sqrt(value);
  value = value / 2;
  return value;
}
```
user: What is the c source code of the assembly code below?

```asm
<checkForOption>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L28
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strmatch@plt>
  test   %rax,%rax
  je     L24
  mov    -0x4(%rbp),%eax
  jmp    L37
L24:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
int checkForOption(char *key, int argc, char *argv[]) {
  int ii = 1;
  while (ii < argc) {
    if (strmatch(key, argv[ii]))
      return (ii);
    ++ii;
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checkForOption>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L38
  mov    %rdi,%r12
  mov    %rdx,%r13
  mov    %esi,%ebp
  mov    $0x1,%ebx
L29:
  mov    %ebx,%r14d
  mov    0x0(%r13,%rbx,8),%rsi
  mov    %r12,%rdi
  call   <strmatch@plt>
  test   %rax,%rax
  jne    L26
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L29
  mov    $0x0,%r14d
L26:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    $0x0,%r14d
  jmp    L26
```

assistant: ```c
int checkForOption(char *key, int argc, char *argv[]) {
  int ii = 1;
  while (ii < argc) {
    if (strmatch(key, argv[ii]))
      return (ii);
    ++ii;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<checkForOption>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%esi
  jle    L13
  mov    %rdi,%r12
  mov    %rdx,%r14
  movslq %esi,%rbp
  mov    $0x1,%ebx
  jmp    L23
  nopl   0x0(%rax)
L9:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L13
L23:
  mov    (%r14,%rbx,8),%rsi
  mov    %r12,%rdi
  mov    %ebx,%r13d
  call   <strmatch@plt>
  test   %rax,%rax
  je     L9
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L13:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int checkForOption(char *key, int argc, char *argv[]) {
  int ii = 1;
  while (ii < argc) {
    if (strmatch(key, argv[ii]))
      return (ii);
    ++ii;
  }
  return (0);
}
```