ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TransformAlarmC__1__Alarm__fired>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <CC2420TransmitP__BackoffTimer__fired@plt>
  mov    $0x0,%eax
  call   <CC2420ControlP__StartupTimer__fired@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void TransformAlarmC__1__Alarm__fired(void) {
  CC2420TransmitP__BackoffTimer__fired();
  CC2420ControlP__StartupTimer__fired();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TransformAlarmC__1__Alarm__fired>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CC2420TransmitP__BackoffTimer__fired@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <CC2420ControlP__StartupTimer__fired@plt>
```

assistant: ```c
void TransformAlarmC__1__Alarm__fired(void) {
  CC2420TransmitP__BackoffTimer__fired();
  CC2420ControlP__StartupTimer__fired();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TransformAlarmC__1__Alarm__fired>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <CC2420TransmitP__BackoffTimer__fired@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <CC2420ControlP__StartupTimer__fired@plt>
```

assistant: ```c
void TransformAlarmC__1__Alarm__fired(void) {
  CC2420TransmitP__BackoffTimer__fired();
  CC2420ControlP__StartupTimer__fired();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xil_fpo_abs_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  movq   %rdx,%xmm0
  mov    %rax,%rdi
  call   <xip_fpo_abs_d@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double xil_fpo_abs_d(double a) {
  double res_d;
  xip_fpo_abs_d(&res_d, a);
  return res_d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xil_fpo_abs_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_abs_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_abs_d(double a) {
  double res_d;
  xip_fpo_abs_d(&res_d, a);
  return res_d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xil_fpo_abs_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_abs_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_abs_d(double a) {
  double res_d;
  xip_fpo_abs_d(&res_d, a);
  return res_d;
}
```
user: What is the c source code of the assembly code below:

```asm
<xil_fpo_abs_d>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <xip_fpo_abs_d@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double xil_fpo_abs_d(double a) {
  double res_d;
  xip_fpo_abs_d(&res_d, a);
  return res_d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<myioctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x28(%rbp)
  jne    L15
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <um_mod_umoven@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L12
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <um_mod_ustoren@plt>
L12:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
  jmp    L24
L15:
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
L24:
  leave
  ret
```

assistant: ```c
int myioctl(int d, int request, void *arg) {
  if (request == SIOCGIFCONF) {
    int rv;
    void *save;
    struct ifconf *ifc = (struct ifconf *)arg;
    save = ifc->ifc_buf;
    ioctl(d, request, arg);
    ifc->ifc_buf = malloc(ifc->ifc_len);
    um_mod_umoven((long)save, ifc->ifc_len, ifc->ifc_buf);
    rv = ioctl(d, request, arg);
    if (rv >= 0)
      um_mod_ustoren((long)save, ifc->ifc_len, ifc->ifc_buf);
    free(ifc->ifc_buf);
    ifc->ifc_buf = save;
    return rv;
  }
  return ioctl(d, request, arg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<myioctl>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    D8(%rip),%rax
  cmp    %esi,(%rax)
  je     L32
  call   <ioctl@plt>
  mov    %eax,%ebp
L5:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    (%rdx),%r13
  call   <ioctl@plt>
  mov    0x8(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,(%rbx)
  mov    0x8(%rbx),%esi
  mov    %r13,%rdi
  call   <um_mod_umoven@plt>
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <ioctl@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jns    L25
L11:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %r13,(%rbx)
  jmp    L5
L25:
  mov    0x8(%rbx),%esi
  mov    (%rbx),%rdx
  mov    %r13,%rdi
  call   <um_mod_ustoren@plt>
  jmp    L11
```

assistant: ```c
int myioctl(int d, int request, void *arg) {
  if (request == SIOCGIFCONF) {
    int rv;
    void *save;
    struct ifconf *ifc = (struct ifconf *)arg;
    save = ifc->ifc_buf;
    ioctl(d, request, arg);
    ifc->ifc_buf = malloc(ifc->ifc_len);
    um_mod_umoven((long)save, ifc->ifc_len, ifc->ifc_buf);
    rv = ioctl(d, request, arg);
    if (rv >= 0)
      um_mod_ustoren((long)save, ifc->ifc_len, ifc->ifc_buf);
    free(ifc->ifc_buf);
    ifc->ifc_buf = save;
    return rv;
  }
  return ioctl(d, request, arg);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<myioctl>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  cmp    %esi,(%rax)
  je     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <ioctl@plt>
L5:
  mov    (%rdx),%rbx
  call   <ioctl@plt>
  mov    0x8(%r12),%edi
  call   <malloc@plt>
  mov    0x8(%r12),%esi
  mov    %rbx,%rdi
  mov    %rax,(%r12)
  mov    %rax,%rdx
  call   <um_mod_umoven@plt>
  mov    %r13d,%edi
  mov    %r12,%rdx
  mov    %ebp,%esi
  call   <ioctl@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jns    L29
L14:
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L29:
  mov    0x8(%r12),%esi
  mov    (%r12),%rdx
  mov    %rbx,%rdi
  call   <um_mod_ustoren@plt>
  jmp    L14
```

assistant: ```c
int myioctl(int d, int request, void *arg) {
  if (request == SIOCGIFCONF) {
    int rv;
    void *save;
    struct ifconf *ifc = (struct ifconf *)arg;
    save = ifc->ifc_buf;
    ioctl(d, request, arg);
    ifc->ifc_buf = malloc(ifc->ifc_len);
    um_mod_umoven((long)save, ifc->ifc_len, ifc->ifc_buf);
    rv = ioctl(d, request, arg);
    if (rv >= 0)
      um_mod_ustoren((long)save, ifc->ifc_len, ifc->ifc_buf);
    free(ifc->ifc_buf);
    ifc->ifc_buf = save;
    return rv;
  }
  return ioctl(d, request, arg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<myioctl>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  cmp    %esi,(%rax)
  je     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <ioctl@plt>
L2:
  mov    (%rdx),%rbx
  call   <ioctl@plt>
  mov    0x8(%r12),%edi
  call   <malloc@plt>
  mov    0x8(%r12),%esi
  mov    %rbx,%rdi
  mov    %rax,(%r12)
  mov    %rax,%rdx
  call   <um_mod_umoven@plt>
  mov    %r13d,%edi
  mov    %r12,%rdx
  mov    %ebp,%esi
  call   <ioctl@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jns    L21
L17:
  mov    (%r12),%rdi
  call   <free@plt>
  mov    %rbx,(%r12)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L21:
  mov    0x8(%r12),%esi
  mov    (%r12),%rdx
  mov    %rbx,%rdi
  call   <um_mod_ustoren@plt>
  jmp    L17
```

assistant: ```c
int myioctl(int d, int request, void *arg) {
  if (request == SIOCGIFCONF) {
    int rv;
    void *save;
    struct ifconf *ifc = (struct ifconf *)arg;
    save = ifc->ifc_buf;
    ioctl(d, request, arg);
    ifc->ifc_buf = malloc(ifc->ifc_len);
    um_mod_umoven((long)save, ifc->ifc_len, ifc->ifc_buf);
    rv = ioctl(d, request, arg);
    if (rv >= 0)
      um_mod_ustoren((long)save, ifc->ifc_len, ifc->ifc_buf);
    free(ifc->ifc_buf);
    ifc->ifc_buf = save;
    return rv;
  }
  return ioctl(d, request, arg);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x200,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <acc_malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  mov    -0xc(%rbp),%eax
  sar    %eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <acc_free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  const int N = 512;
  void *d;
  d = acc_malloc(N);
  if (d == NULL)
    abort();
  acc_free((void *)((uintptr_t)d + (uintptr_t)(N >> 1)));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x200,%edi
  call   <acc_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
L2:
  lea    0x100(%rbx),%rdi
  call   <acc_free@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L9:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char **argv) {
  const int N = 512;
  void *d;
  d = acc_malloc(N);
  if (d == NULL)
    abort();
  acc_free((void *)((uintptr_t)d + (uintptr_t)(N >> 1)));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x200,%edi
  call   <acc_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L15:
  lea    0x100(%rbx),%rdi
  call   <acc_free@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L5:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L15
```

assistant: ```c
int main(int argc, char **argv) {
  const int N = 512;
  void *d;
  d = acc_malloc(N);
  if (d == NULL)
    abort();
  acc_free((void *)((uintptr_t)d + (uintptr_t)(N >> 1)));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x200,%edi
  call   <acc_malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
L2:
  lea    0x100(%rbx),%rdi
  call   <acc_free@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L1:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char **argv) {
  const int N = 512;
  void *d;
  d = acc_malloc(N);
  if (d == NULL)
    abort();
  acc_free((void *)((uintptr_t)d + (uintptr_t)(N >> 1)));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<logbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <isfinite@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L30
  fldt   0x10(%rbp)
  fmul   %st(0),%st
  jmp    L21
L30:
  fldt   0x10(%rbp)
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  jp     L24
  fldt   0x10(%rbp)
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  jne    L24
  fldt   0x10(%rbp)
  fmul   %st(0),%st
  fld1
  fchs
  fdivp  %st,%st(1)
  jmp    L21
L24:
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <ilogbl@plt>
  add    $0x10,%rsp
L21:
  leave
  ret
```

assistant: ```c
long double logbl(long double x) {
  if (!isfinite(x))
    return x * x;
  if (x == 0)
    return -1 / (x * x);
  return ilogbl(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logbl>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <isfinite@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  je     L17
  fldz
  fldt   0x10(%rsp)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L59
  jne    L2
  fld    %st(0)
  fmulp  %st,%st(1)
  fld1
  fchs
  fdivp  %st,%st(1)
  jmp    L12
L17:
  fldt   0x10(%rsp)
  fmul   %st(0),%st
L12:
  add    $0x8,%rsp
  ret
L59:
  fstp   %st(0)
  jmp    L0
L2:
  fstp   %st(0)
L0:
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <ilogbl@plt>
  add    $0x10,%rsp
  jmp    L12
```

assistant: ```c
long double logbl(long double x) {
  if (!isfinite(x))
    return x * x;
  if (x == 0)
    return -1 / (x * x);
  return ilogbl(x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<logbl>:
  endbr64
  sub    $0x28,%rsp
  fldt   0x30(%rsp)
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x10(%rsp)
  call   <isfinite@plt>
  pop    %rdx
  pop    %rcx
  fldt   (%rsp)
  test   %eax,%eax
  je     L18
  fldz
  fxch   %st(1)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L7
  jne    L7
  fmul   %st(0),%st
  add    $0x18,%rsp
  fld1
  fchs
  fdivp  %st,%st(1)
  ret
  nopl   0x0(%rax)
L7:
  fstpt  0x20(%rsp)
  add    $0x18,%rsp
  jmp    1070 <ilogbl@plt>
  nopl   (%rax)
L18:
  fmul   %st(0),%st
  add    $0x18,%rsp
  ret
```

assistant: ```c
long double logbl(long double x) {
  if (!isfinite(x))
    return x * x;
  if (x == 0)
    return -1 / (x * x);
  return ilogbl(x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<logbl>:
  endbr64
  sub    $0x28,%rsp
  fldt   0x30(%rsp)
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x10(%rsp)
  call   <isfinite@plt>
  pop    %rdx
  pop    %rcx
  fldt   (%rsp)
  test   %eax,%eax
  je     L27
  fldz
  fxch   %st(1)
  fucomi %st(1),%st
  fstp   %st(1)
  jp     L28
  jne    L28
  fmul   %st(0),%st
  add    $0x18,%rsp
  fld1
  fchs
  fdivp  %st,%st(1)
  ret
  nopl   0x0(%rax)
L28:
  fstpt  0x20(%rsp)
  add    $0x18,%rsp
  jmp    1070 <ilogbl@plt>
  nopl   (%rax)
L27:
  fmul   %st(0),%st
  add    $0x18,%rsp
  ret
```

assistant: ```c
long double logbl(long double x) {
  if (!isfinite(x))
    return x * x;
  if (x == 0)
    return -1 / (x * x);
  return ilogbl(x);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__setresgid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __setresgid(gid_t rgid, gid_t egid, gid_t sgid) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__setresgid>:
  endbr64
  sub    $0x8,%rsp
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __setresgid(gid_t rgid, gid_t egid, gid_t sgid) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__setresgid>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __setresgid(gid_t rgid, gid_t egid, gid_t sgid) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__setresgid>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __setresgid(gid_t rgid, gid_t egid, gid_t sgid) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hashCrc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L16:
  shll   $0x2,-0x10(%rbp)
  movzbl -0x11(%rbp),%eax
  add    %eax,-0x10(%rbp)
  movzbl -0x11(%rbp),%eax
  add    %eax,-0xc(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L16
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned hashCrc(char *string) {
  unsigned char *us = (unsigned char *)string;
  unsigned char c;
  unsigned shiftAcc = 0;
  unsigned addAcc = 0;
  while ((c = *us++) != 0) {
    shiftAcc <<= 2;
    shiftAcc += c;
    addAcc += c;
  }
  return shiftAcc + addAcc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hashCrc>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L9
  mov    $0x0,%esi
  mov    $0x0,%eax
L22:
  movzbl %dl,%edx
  lea    (%rdx,%rax,4),%eax
  add    %edx,%esi
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L22
L3:
  add    %esi,%eax
  ret
L9:
  mov    $0x0,%esi
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
unsigned hashCrc(char *string) {
  unsigned char *us = (unsigned char *)string;
  unsigned char c;
  unsigned shiftAcc = 0;
  unsigned addAcc = 0;
  while ((c = *us++) != 0) {
    shiftAcc <<= 2;
    shiftAcc += c;
    addAcc += c;
  }
  return shiftAcc + addAcc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hashCrc>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L7
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rcx
  lea    (%rdx,%rax,4),%eax
  add    %edx,%esi
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L5
  add    %esi,%eax
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned hashCrc(char *string) {
  unsigned char *us = (unsigned char *)string;
  unsigned char c;
  unsigned shiftAcc = 0;
  unsigned addAcc = 0;
  while ((c = *us++) != 0) {
    shiftAcc <<= 2;
    shiftAcc += c;
    addAcc += c;
  }
  return shiftAcc + addAcc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hashCrc>:
  endbr64
  movzbl (%rdi),%edx
  lea    0x1(%rdi),%rcx
  test   %dl,%dl
  je     L4
  xor    %esi,%esi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%rcx
  lea    (%rdx,%rax,4),%eax
  add    %edx,%esi
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L17
  add    %esi,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned hashCrc(char *string) {
  unsigned char *us = (unsigned char *)string;
  unsigned char c;
  unsigned shiftAcc = 0;
  unsigned addAcc = 0;
  while ((c = *us++) != 0) {
    shiftAcc <<= 2;
    shiftAcc += c;
    addAcc += c;
  }
  return shiftAcc + addAcc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xrop3_164_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  notl   -0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_164_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_164_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%edx
  or     %esi,%edx
  not    %edx
  or     $0xff,%dl
  xor    %esi,%edx
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  not    %edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_164_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_164_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  or     %esi,%edx
  mov    %esi,%eax
  not    %edx
  not    %eax
  or     $0xff,%dl
  or     %edi,%eax
  not    %edi
  xor    %esi,%edx
  and    %esi,%edi
  not    %edx
  movzbl %dil,%edi
  and    %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_164_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_164_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  or     %esi,%edx
  mov    %esi,%eax
  not    %edx
  not    %eax
  or     $0xff,%dl
  or     %edi,%eax
  not    %edi
  xor    %esi,%edx
  and    %esi,%edi
  not    %edx
  movzbl %dil,%edi
  and    %edx,%eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_164_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | T;
  stk3 = ~stk3;
  stk2 = D | stk3;
  stk1 = T ^ stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```