ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L9
  mov    %edi,%r13d
  mov    %edi,%ebp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L7:
  add    %ebp,%r12d
  add    $0x1,%ebx
  add    %r13d,%ebp
  mov    %r12d,%edi
  call   <putint@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jne    L7
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L9:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int f(int x) {
  int s;
  s = 0;
  int i;
  i = 0;
  while (i < x) {
    i = i + 1;
    s = s + x * i;
    putint(s);
    putchar(10);
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L2
  mov    %edi,%r13d
  mov    %edi,%ebp
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L15:
  add    %ebp,%r12d
  add    $0x1,%ebx
  add    %r13d,%ebp
  mov    %r12d,%edi
  call   <putint@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jne    L15
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L2:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int f(int x) {
  int s;
  s = 0;
  int i;
  i = 0;
  while (i < x) {
    i = i + 1;
    s = s + x * i;
    putint(s);
    putchar(10);
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lrevcomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %esi,-0xac(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x20,-0xac(%rbp)
  jle    L25
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <fatalx@plt>
L25:
  mov    -0xa8(%rbp),%rax
  mov    %rax,-0x98(%rbp)
  movl   $0x0,-0xa0(%rbp)
  jmp    L2
L46:
  mov    -0x98(%rbp),%rax
  not    %eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0xa0(%rbp),%eax
  cltq
  mov    %edx,-0x90(%rbp,%rax,4)
  sarq   $0x2,-0x98(%rbp)
  addl   $0x1,-0xa0(%rbp)
L2:
  mov    -0xa0(%rbp),%eax
  cmp    -0xac(%rbp),%eax
  jl     L46
  movq   $0x0,-0x98(%rbp)
  movl   $0x0,-0xa0(%rbp)
  jmp    L57
L19:
  mov    -0xa0(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%eax
  mov    %eax,-0x9c(%rbp)
  mov    -0x98(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x9c(%rbp),%eax
  cltq
  or     %rdx,%rax
  mov    %rax,-0x98(%rbp)
  addl   $0x1,-0xa0(%rbp)
L57:
  mov    -0xa0(%rbp),%eax
  cmp    -0xac(%rbp),%eax
  jl     L19
  mov    -0x98(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: stringlen > 32


assistant: ```c
long lrevcomp(long xx, int stringlen) {
  int aa[32], k, t;
  long xxx;
  if (stringlen > 32)
    fatalx("stringlen > 32\n");
  xxx = xx;
  for (k = 0; k < stringlen; ++k) {
    aa[k] = (xxx & 3) ^ 3;
    xxx = xxx >> 2;
  }
  xxx = 0;
  for (k = 0; k < stringlen; ++k) {
    t = aa[k];
    xxx = (xxx << 2) | t;
  }
  return xxx;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lrevcomp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%esi
  jg     L50
  test   %esi,%esi
  jle    L49
L3:
  mov    $0x0,%eax
L61:
  mov    %ebp,%edx
  not    %edx
  and    $0x3,%edx
  mov    %edx,(%rsp,%rax,4)
  sar    $0x2,%rbp
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L61
  mov    $0x0,%edx
  mov    $0x0,%eax
L51:
  shl    $0x2,%rax
  movslq (%rsp,%rdx,4),%rcx
  or     %rcx,%rax
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L51
L8:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L50:
  lea    D0(%rip),%rdi
  call   <fatalx@plt>
  jmp    L3
L49:
  mov    $0x0,%eax
  jmp    L8
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string

tool: D0: stringlen > 32


assistant: ```c
long lrevcomp(long xx, int stringlen) {
  int aa[32], k, t;
  long xxx;
  if (stringlen > 32)
    fatalx("stringlen > 32\n");
  xxx = xx;
  for (k = 0; k < stringlen; ++k) {
    aa[k] = (xxx & 3) ^ 3;
    xxx = xxx >> 2;
  }
  xxx = 0;
  for (k = 0; k < stringlen; ++k) {
    t = aa[k];
    xxx = (xxx << 2) | t;
  }
  return xxx;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lrevcomp>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%esi
  jg     L58
  test   %esi,%esi
  jle    L40
L32:
  xor    %eax,%eax
  mov    %rsp,%rcx
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ebx,%edx
  sar    $0x2,%rbx
  not    %edx
  and    $0x3,%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L26
  xor    %edx,%edx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L39:
  movslq (%rcx,%rdx,4),%rsi
  shl    $0x2,%rax
  add    $0x1,%rdx
  or     %rsi,%rax
  cmp    %edx,%ebp
  jg     L39
L6:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L60
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  lea    D2(%rip),%rdi
  call   <fatalx@plt>
  jmp    L32
  xchg   %ax,%ax
L40:
  xor    %eax,%eax
  jmp    L6
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: stringlen > 32


assistant: ```c
long lrevcomp(long xx, int stringlen) {
  int aa[32], k, t;
  long xxx;
  if (stringlen > 32)
    fatalx("stringlen > 32\n");
  xxx = xx;
  for (k = 0; k < stringlen; ++k) {
    aa[k] = (xxx & 3) ^ 3;
    xxx = xxx >> 2;
  }
  xxx = 0;
  for (k = 0; k < stringlen; ++k) {
    t = aa[k];
    xxx = (xxx << 2) | t;
  }
  return xxx;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lrevcomp>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x20,%esi
  jg     L16
  test   %esi,%esi
  jle    L56
L24:
  xor    %eax,%eax
  mov    %rsp,%rcx
  nopl   0x0(%rax,%rax,1)
L52:
  mov    %ebx,%edx
  sar    $0x2,%rbx
  not    %edx
  and    $0x3,%edx
  mov    %edx,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ebp
  jg     L52
  xor    %edx,%edx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L4:
  movslq (%rcx,%rdx,4),%rsi
  shl    $0x2,%rax
  add    $0x1,%rdx
  or     %rsi,%rax
  cmp    %edx,%ebp
  jg     L4
L66:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  lea    D2(%rip),%rdi
  call   <fatalx@plt>
  jmp    L24
  xchg   %ax,%ax
L56:
  xor    %eax,%eax
  jmp    L66
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: stringlen > 32


assistant: ```c
long lrevcomp(long xx, int stringlen) {
  int aa[32], k, t;
  long xxx;
  if (stringlen > 32)
    fatalx("stringlen > 32\n");
  xxx = xx;
  for (k = 0; k < stringlen; ++k) {
    aa[k] = (xxx & 3) ^ 3;
    xxx = xxx >> 2;
  }
  xxx = 0;
  for (k = 0; k < stringlen; ++k) {
    t = aa[k];
    xxx = (xxx << 2) | t;
  }
  return xxx;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %al,-0x1(%rbp)
  jmp    L46
L58:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rax
  jmp    L6
L30:
  addq   $0x1,-0x18(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  cmpb   $0x0,-0x1(%rbp)
  jne    L50
  mov    -0x18(%rbp),%rax
  jmp    L6
L50:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char ch = (char)c;
  while (*s) {
    if (*s == ch)
      return (char *)s;
    s++;
  }
  if (!ch)
    return (char *)s;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strchr>:
  endbr64
  mov    %esi,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
L22:
  cmp    %al,%dl
  je     L8
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L22
L1:
  test   %sil,%sil
  mov    $0x0,%eax
  cmove  %rdi,%rax
  ret
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char ch = (char)c;
  while (*s) {
    if (*s == ch)
      return (char *)s;
    s++;
  }
  if (!ch)
    return (char *)s;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  test   %al,%al
  jne    L16
  jmp    L30
  nop
L38:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L30
L16:
  cmp    %al,%dl
  jne    L38
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L30:
  xor    %eax,%eax
  test   %sil,%sil
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char ch = (char)c;
  while (*s) {
    if (*s == ch)
      return (char *)s;
    s++;
  }
  if (!ch)
    return (char *)s;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%eax
  mov    %esi,%edx
  test   %al,%al
  jne    L8
  jmp    L24
  nop
L38:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L24
L8:
  cmp    %al,%dl
  jne    L38
  mov    %rdi,%rax
  ret
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  test   %sil,%sil
  cmove  %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *s, int c) {
  char ch = (char)c;
  while (*s) {
    if (*s == ch)
      return (char *)s;
    s++;
  }
  if (!ch)
    return (char *)s;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: Usage: tyrd [OPTIONS]...

    -p, --port       specify server port


assistant: ```c
void show_help() {
  printf("Usage: tyrd [OPTIONS]...\n\n    -p, --port       specify server port\n");
  abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: Usage: tyrd [OPTIONS]...

    -p, --port       specify server port


assistant: ```c
void show_help() {
  printf("Usage: tyrd [OPTIONS]...\n\n    -p, --port       specify server port\n");
  abort();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: Usage: tyrd [OPTIONS]...

    -p, --port       specify server port


assistant: ```c
void show_help() {
  printf("Usage: tyrd [OPTIONS]...\n\n    -p, --port       specify server port\n");
  abort();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: Usage: tyrd [OPTIONS]...

    -p, --port       specify server port


assistant: ```c
void show_help() {
  printf("Usage: tyrd [OPTIONS]...\n\n    -p, --port       specify server port\n");
  abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<__stop_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x75,%esi
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    $0x76,%esi
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  leave
  ret
```

assistant: ```c
int __stop_trace(int fd) {
  ioctl(fd, _IO(0x12, 117));
  return ioctl(fd, _IO(0x12, 118));
}
```
user: What is the c source code of the assembly code below?

```asm
<__stop_trace>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x75,%esi
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  mov    $0x76,%esi
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  pop    %rbx
  ret
```

assistant: ```c
int __stop_trace(int fd) {
  ioctl(fd, _IO(0x12, 117));
  return ioctl(fd, _IO(0x12, 118));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__stop_trace>:
  endbr64
  push   %rbp
  mov    $0x75,%esi
  mov    %edi,%ebp
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <ioctl@plt>
  mov    $0x76,%esi
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <ioctl@plt>
```

assistant: ```c
int __stop_trace(int fd) {
  ioctl(fd, _IO(0x12, 117));
  return ioctl(fd, _IO(0x12, 118));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__stop_trace>:
  endbr64
  push   %rbp
  mov    $0x75,%esi
  mov    %edi,%ebp
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <ioctl@plt>
  mov    $0x76,%esi
  mov    $0x12,%edi
  call   <_IO@plt>
  mov    %ebp,%edi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <ioctl@plt>
```

assistant: ```c
int __stop_trace(int fd) {
  ioctl(fd, _IO(0x12, 117));
  return ioctl(fd, _IO(0x12, 118));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<endsWith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L27
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L27
  mov    $0x1,%eax
  jmp    L17
L27:
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
bool endsWith(char *base, char *str) {
  int blen = strlen(base);
  int slen = strlen(str);
  return (blen >= slen) && (0 == strcmp(base + blen - slen, str));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<endsWith>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %eax,%ebx
  jge    L1
L13:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  movslq %ebx,%rbx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L13
```

assistant: ```c
bool endsWith(char *base, char *str) {
  int blen = strlen(base);
  int slen = strlen(str);
  return (blen >= slen) && (0 == strcmp(base + blen - slen, str));
}
```
user: Translate the below assembly code into C programming language:

```asm
<endsWith>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  jge    L1
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L1:
  cltq
  mov    %r12,%rsi
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool endsWith(char *base, char *str) {
  int blen = strlen(base);
  int slen = strlen(str);
  return (blen >= slen) && (0 == strcmp(base + blen - slen, str));
}
```
user: What is the c source code of the assembly code below?

```asm
<endsWith>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %eax,%ebx
  jge    L0
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  cltq
  mov    %r12,%rsi
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool endsWith(char *base, char *str) {
  int blen = strlen(base);
  int slen = strlen(str);
  return (blen >= slen) && (0 == strcmp(base + blen - slen, str));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<replace_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L2
  movl   $0x0,-0x8(%rbp)
  jmp    L30
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  nop
L30:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L24
L25:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int replace_entry(wchar_t *str, const int len, const wchar_t *tmp) {
  int ret;
  int i;
  if (tmp == NULL) {
    ret = 0;
    goto done;
  }
  for (i = 0; tmp[i] != 0; i++) {
    str[i] = tmp[i];
  }
  ret = i;
  goto done;
done:
  for (i = ret; i < len; i++) {
    str[i] = 0;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace_entry>:
  endbr64
  mov    $0x0,%r8d
  test   %rdx,%rdx
  je     L41
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  je     L30
  mov    $0x0,%eax
L22:
  mov    %rcx,(%rdi,%rax,8)
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  mov    (%rdx,%rax,8),%rcx
  test   %rcx,%rcx
  jne    L22
L41:
  cmp    %esi,%r8d
  jge    L14
  movslq %r8d,%rdx
  lea    (%rdi,%rdx,8),%rax
  sub    $0x1,%esi
  sub    %r8d,%esi
  add    %rdx,%rsi
  lea    0x8(%rdi,%rsi,8),%rdx
L13:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
L14:
  mov    %r8d,%eax
  ret
L30:
  mov    $0x0,%r8d
  jmp    L41
```

assistant: ```c
int replace_entry(wchar_t *str, const int len, const wchar_t *tmp) {
  int ret;
  int i;
  if (tmp == NULL) {
    ret = 0;
    goto done;
  }
  for (i = 0; tmp[i] != 0; i++) {
    str[i] = tmp[i];
  }
  ret = i;
  goto done;
done:
  for (i = ret; i < len; i++) {
    str[i] = 0;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<replace_entry>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdx,%rdx
  je     L1
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  je     L1
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rcx,(%rdi,%rax,8)
  lea    0x1(%rax),%r12d
  add    $0x1,%rax
  mov    (%rdx,%rax,8),%rcx
  test   %rcx,%rcx
  jne    L7
L1:
  cmp    %esi,%r12d
  jge    L26
  sub    $0x1,%esi
  movslq %r12d,%rax
  sub    %r12d,%esi
  lea    (%rdi,%rax,8),%rdi
  lea    0x8(,%rsi,8),%rdx
  xor    %esi,%esi
  call   <memset@plt>
L26:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int replace_entry(wchar_t *str, const int len, const wchar_t *tmp) {
  int ret;
  int i;
  if (tmp == NULL) {
    ret = 0;
    goto done;
  }
  for (i = 0; tmp[i] != 0; i++) {
    str[i] = tmp[i];
  }
  ret = i;
  goto done;
done:
  for (i = ret; i < len; i++) {
    str[i] = 0;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<replace_entry>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdx,%rdx
  je     L0
  mov    (%rdx),%rcx
  test   %rcx,%rcx
  je     L0
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rcx,(%rdi,%rax,8)
  lea    0x1(%rax),%r12d
  add    $0x1,%rax
  mov    (%rdx,%rax,8),%rcx
  test   %rcx,%rcx
  jne    L21
L0:
  cmp    %esi,%r12d
  jge    L15
  sub    $0x1,%esi
  movslq %r12d,%rax
  sub    %r12d,%esi
  lea    (%rdi,%rax,8),%rdi
  lea    0x8(,%rsi,8),%rdx
  xor    %esi,%esi
  call   <memset@plt>
L15:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int replace_entry(wchar_t *str, const int len, const wchar_t *tmp) {
  int ret;
  int i;
  if (tmp == NULL) {
    ret = 0;
    goto done;
  }
  for (i = 0; tmp[i] != 0; i++) {
    str[i] = tmp[i];
  }
  ret = i;
  goto done;
done:
  for (i = ret; i < len; i++) {
    str[i] = 0;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x68(%rbp)
  jmp    L2
L37:
  mov    -0x68(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cmp    $0x14,%eax
  seta   %dl
  test   %dl,%dl
  jne    L39
  mov    $0x104111,%edx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L39
  addl   $0x1,-0x64(%rbp)
L39:
  addl   $0x1,-0x68(%rbp)
L2:
  mov    -0x68(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L37
  mov    -0x64(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type: string

tool: D6: %d

assistant: ```c
int main() {
  char str[80];
  int i, n = 0, len;
  gets(str);
  i = 0;
  while (str[i] != '\0') {
    switch (toupper(str[i])) {
    case 'A':
    case 'E':
    case 'I':
    case 'O':
    case 'U':
      n++;
    }
    i++;
  }
  printf("%d", n);
  return 0;
}
```