ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    $0xfb6,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string

tool: D5: %i 


assistant: ```c
int main() {
  int i = 0, pot = 0;
  do {
    pot = i * 2;
    printf("%i \n", pot);
    i++;
  } while (i <= 2010);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%r10
  call   <nested.0>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void test_4(void) {
  void nested(void) {}
  nested();
}
```
user: What is the c source code of the assembly code below:

```asm
<test_4>:
  endbr64
  ret
```

assistant: ```c
void test_4(void) {
  void nested(void) {}
  nested();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_4>:
  endbr64
  ret
```

assistant: ```c
void test_4(void) {
  void nested(void) {}
  nested();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_4>:
  endbr64
  ret
```

assistant: ```c
void test_4(void) {
  void nested(void) {}
  nested();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PB_Cnpreroc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    %r9d,-0x28(%rbp)
  cmpl   $0xffffffff,-0x28(%rbp)
  je     L74
  cmpl   $0x1,0x10(%rbp)
  jne    L82
L74:
  mov    $0x0,%eax
  jmp    L132
L82:
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L30
  mov    -0x1c(%rbp),%eax
  neg    %eax
  cltd
  idivl  -0x20(%rbp)
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  cltd
  idivl  0x10(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  add    %eax,-0x1c(%rbp)
L30:
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L58
  mov    $0x0,%eax
  jmp    L132
L58:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L41
  mov    -0x14(%rbp),%eax
  jmp    L132
L41:
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cltd
  idivl  -0x20(%rbp)
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L141
  mov    0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L141:
  mov    -0x8(%rbp),%eax
  cmp    0x10(%rbp),%eax
  jge    L113
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L88
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  jmp    L132
L88:
  mov    -0x14(%rbp),%eax
  jmp    L132
L113:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  0x10(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
  cmp    %eax,-0xc(%rbp)
  jg     L98
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  imul   -0x20(%rbp),%eax
  imul   -0xc(%rbp),%eax
  add    %edx,%eax
  jmp    L132
L98:
  mov    -0x20(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sub    0x10(%rbp),%eax
  imul   %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
L132:
  pop    %rbp
  ret
```

assistant: ```c
int PB_Cnpreroc(int N, int I, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  int ilocblk, mydist, nblocks;
  if ((SRCPROC == -1) || (NPROCS == 1))
    return (0);
  if ((INB -= I) <= 0) {
    nblocks = (-INB) / NB + 1;
    SRCPROC += nblocks;
    SRCPROC -= (SRCPROC / NPROCS) * NPROCS;
    INB += nblocks * NB;
  }
  if (PROC == SRCPROC)
    return (0);
  if (N <= INB)
    return (N);
  nblocks = (N - INB) / NB + 1;
  if ((mydist = PROC - SRCPROC) < 0)
    mydist += NPROCS;
  if (nblocks < NPROCS)
    return (((mydist <= nblocks) ? INB + NB * (mydist - 1) : N));
  ilocblk = nblocks / NPROCS;
  return (((mydist <= (nblocks - ilocblk * NPROCS)) ? INB - NB + (ilocblk + 1) * NB * mydist : N + NB * ilocblk * (mydist - NPROCS)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<PB_Cnpreroc>:
  endbr64
  mov    %esi,%eax
  mov    %ecx,%esi
  mov    0x8(%rsp),%r10d
  cmp    $0xffffffff,%r9d
  je     L18
  cmp    $0x1,%r10d
  je     L18
  mov    %edx,%r11d
  sub    %eax,%r11d
  test   %r11d,%r11d
  jle    L49
L79:
  mov    $0x0,%edx
  cmp    %r8d,%r9d
  je     L77
  mov    %edi,%edx
  cmp    %edi,%r11d
  jge    L77
  mov    %edi,%eax
  sub    %r11d,%eax
  cltd
  idiv   %esi
  add    $0x1,%eax
  sub    %r9d,%r8d
  lea    (%r8,%r10,1),%edx
  cmovs  %edx,%r8d
  cmp    %eax,%r10d
  jg     L21
  cltd
  idiv   %r10d
  cmp    %edx,%r8d
  jg     L75
  add    $0x1,%eax
  imul   %esi,%eax
  imul   %r8d,%eax
  sub    %esi,%r11d
  lea    (%rax,%r11,1),%edx
  jmp    L77
L49:
  sub    %edx,%eax
  cltd
  idiv   %ecx
  lea    0x1(%rax),%ecx
  lea    (%r9,%rcx,1),%eax
  cltd
  idiv   %r10d
  mov    %edx,%r9d
  imul   %esi,%ecx
  add    %ecx,%r11d
  jmp    L79
L21:
  mov    %edi,%edx
  cmp    %eax,%r8d
  jg     L77
  lea    -0x1(%r8),%edx
  imul   %esi,%edx
  add    %r11d,%edx
  jmp    L77
L75:
  imul   %eax,%esi
  sub    %r10d,%r8d
  imul   %r8d,%esi
  lea    (%rsi,%rdi,1),%edx
  jmp    L77
L18:
  mov    $0x0,%edx
L77:
  mov    %edx,%eax
  ret
```

assistant: ```c
int PB_Cnpreroc(int N, int I, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  int ilocblk, mydist, nblocks;
  if ((SRCPROC == -1) || (NPROCS == 1))
    return (0);
  if ((INB -= I) <= 0) {
    nblocks = (-INB) / NB + 1;
    SRCPROC += nblocks;
    SRCPROC -= (SRCPROC / NPROCS) * NPROCS;
    INB += nblocks * NB;
  }
  if (PROC == SRCPROC)
    return (0);
  if (N <= INB)
    return (N);
  nblocks = (N - INB) / NB + 1;
  if ((mydist = PROC - SRCPROC) < 0)
    mydist += NPROCS;
  if (nblocks < NPROCS)
    return (((mydist <= nblocks) ? INB + NB * (mydist - 1) : N));
  ilocblk = nblocks / NPROCS;
  return (((mydist <= (nblocks - ilocblk * NPROCS)) ? INB - NB + (ilocblk + 1) * NB * mydist : N + NB * ilocblk * (mydist - NPROCS)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PB_Cnpreroc>:
  endbr64
  push   %r12
  mov    0x10(%rsp),%r10d
  cmp    $0xffffffff,%r9d
  je     L83
  cmp    $0x1,%r10d
  je     L83
  mov    %esi,%eax
  mov    %edx,%r11d
  mov    %ecx,%esi
  sub    %eax,%r11d
  test   %r11d,%r11d
  jle    L7
L64:
  xor    %r12d,%r12d
  cmp    %r8d,%r9d
  je     L71
  mov    %edi,%r12d
  cmp    %edi,%r11d
  jge    L71
  mov    %edi,%eax
  sub    %r11d,%eax
  cltd
  idiv   %esi
  add    $0x1,%eax
  sub    %r9d,%r8d
  lea    (%r8,%r10,1),%edx
  cmovs  %edx,%r8d
  cmp    %eax,%r10d
  jg     L46
  cltd
  idiv   %r10d
  cmp    %edx,%r8d
  jg     L38
  add    $0x1,%eax
  sub    %esi,%r11d
  imul   %esi,%eax
  imul   %r8d,%eax
  lea    (%rax,%r11,1),%r12d
L71:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L7:
  sub    %edx,%eax
  cltd
  idiv   %ecx
  lea    0x1(%rax),%ecx
  lea    (%r9,%rcx,1),%eax
  cltd
  imul   %esi,%ecx
  idiv   %r10d
  add    %ecx,%r11d
  mov    %edx,%r9d
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L83:
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L38:
  imul   %eax,%esi
  sub    %r10d,%r8d
  imul   %r8d,%esi
  lea    (%rsi,%rdi,1),%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  cmp    %eax,%r8d
  jg     L71
  lea    -0x1(%r8),%r12d
  imul   %esi,%r12d
  add    %r11d,%r12d
  jmp    L71
```

assistant: ```c
int PB_Cnpreroc(int N, int I, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  int ilocblk, mydist, nblocks;
  if ((SRCPROC == -1) || (NPROCS == 1))
    return (0);
  if ((INB -= I) <= 0) {
    nblocks = (-INB) / NB + 1;
    SRCPROC += nblocks;
    SRCPROC -= (SRCPROC / NPROCS) * NPROCS;
    INB += nblocks * NB;
  }
  if (PROC == SRCPROC)
    return (0);
  if (N <= INB)
    return (N);
  nblocks = (N - INB) / NB + 1;
  if ((mydist = PROC - SRCPROC) < 0)
    mydist += NPROCS;
  if (nblocks < NPROCS)
    return (((mydist <= nblocks) ? INB + NB * (mydist - 1) : N));
  ilocblk = nblocks / NPROCS;
  return (((mydist <= (nblocks - ilocblk * NPROCS)) ? INB - NB + (ilocblk + 1) * NB * mydist : N + NB * ilocblk * (mydist - NPROCS)));
}
```
user: What is the c source code of the assembly code below?

```asm
<PB_Cnpreroc>:
  endbr64
  push   %r12
  mov    0x10(%rsp),%r10d
  cmp    $0xffffffff,%r9d
  je     L72
  cmp    $0x1,%r10d
  je     L72
  mov    %esi,%eax
  mov    %edx,%r11d
  mov    %ecx,%esi
  sub    %eax,%r11d
  test   %r11d,%r11d
  jle    L57
L14:
  xor    %r12d,%r12d
  cmp    %r8d,%r9d
  je     L41
  mov    %edi,%r12d
  cmp    %edi,%r11d
  jge    L41
  mov    %edi,%eax
  sub    %r11d,%eax
  cltd
  idiv   %esi
  add    $0x1,%eax
  sub    %r9d,%r8d
  lea    (%r8,%r10,1),%edx
  cmovs  %edx,%r8d
  cmp    %eax,%r10d
  jg     L6
  cltd
  idiv   %r10d
  cmp    %edx,%r8d
  jg     L90
  add    $0x1,%eax
  sub    %esi,%r11d
  imul   %esi,%eax
  imul   %r8d,%eax
  lea    (%rax,%r11,1),%r12d
L41:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L57:
  sub    %edx,%eax
  cltd
  idiv   %ecx
  lea    0x1(%rax),%ecx
  lea    (%r9,%rcx,1),%eax
  cltd
  imul   %esi,%ecx
  idiv   %r10d
  add    %ecx,%r11d
  mov    %edx,%r9d
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L72:
  xor    %r12d,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L90:
  imul   %eax,%esi
  sub    %r10d,%r8d
  imul   %r8d,%esi
  lea    (%rsi,%rdi,1),%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  cmp    %eax,%r8d
  jg     L41
  lea    -0x1(%r8),%r12d
  imul   %esi,%r12d
  add    %r11d,%r12d
  jmp    L41
```

assistant: ```c
int PB_Cnpreroc(int N, int I, int INB, int NB, int PROC, int SRCPROC, int NPROCS) {
  int ilocblk, mydist, nblocks;
  if ((SRCPROC == -1) || (NPROCS == 1))
    return (0);
  if ((INB -= I) <= 0) {
    nblocks = (-INB) / NB + 1;
    SRCPROC += nblocks;
    SRCPROC -= (SRCPROC / NPROCS) * NPROCS;
    INB += nblocks * NB;
  }
  if (PROC == SRCPROC)
    return (0);
  if (N <= INB)
    return (N);
  nblocks = (N - INB) / NB + 1;
  if ((mydist = PROC - SRCPROC) < 0)
    mydist += NPROCS;
  if (nblocks < NPROCS)
    return (((mydist <= nblocks) ? INB + NB * (mydist - 1) : N));
  ilocblk = nblocks / NPROCS;
  return (((mydist <= (nblocks - ilocblk * NPROCS)) ? INB - NB + (ilocblk + 1) * NB * mydist : N + NB * ilocblk * (mydist - NPROCS)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nested_break_continue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  jmp    L76
L69:
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L18
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L145
  mov    -0x4(%rbp),%eax
  jmp    L141
L145:
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x2,%eax
  jne    L47
  nop
L47:
  cmpl   $0x3,-0xc(%rbp)
  jle    L69
  jmp    L108
L18:
  nop
L108:
  mov    -0x8(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L8
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L90
  mov    -0x8(%rbp),%eax
  jmp    L141
L90:
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x2,%eax
  jne    L21
  nop
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L47
  jmp    L2
L8:
  nop
L2:
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L121
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L27
  mov    -0x4(%rbp),%eax
  jmp    L141
L27:
  mov    -0x4(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cmp    $0x2,%eax
  jne    L76
  nop
L76:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L21
  jmp    L40
L121:
  nop
L40:
  mov    $0x0,%eax
L141:
  pop    %rbp
  ret
```

assistant: ```c
int nested_break_continue(int a, int b, int c) {
  while (a < b) {
    while (b < c) {
      while (c < 4) {
        c++;
        if (c % 4 == 0)
          break;
        if (c % 4 == 1)
          return a;
        if (c % 4 == 2)
          continue;
      }
      if (b % 4 == 0)
        break;
      if (b % 4 == 1)
        return b;
      if (b % 4 == 2)
        continue;
    }
    if (a % 4 == 0)
      break;
    if (a % 4 == 1)
      return a;
    if (a % 4 == 2)
      continue;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<nested_break_continue>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%rsi,%rdx,1),%r8d
  and    $0x3,%r8d
  sub    %edx,%r8d
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  lea    (%rdi,%rcx,1),%edx
  and    $0x3,%edx
  sub    %ecx,%edx
  mov    %edx,%r9d
  mov    %esi,%r10d
  and    $0x3,%r10d
  mov    %edi,%r11d
  and    $0x3,%r11d
L94:
  cmp    %esi,%edi
  jl     L16
  mov    $0x0,%edi
  jmp    L8
L67:
  test   %r10d,%r10d
  je     L37
  cmp    $0x1,%r8d
  je     L44
L16:
  cmp    %esi,%eax
  jle    L37
L65:
  cmp    $0x3,%eax
  jg     L67
  add    $0x1,%eax
  test   $0x3,%al
  je     L67
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  lea    (%rax,%rcx,1),%edx
  and    $0x3,%edx
  sub    %ecx,%edx
  cmp    $0x1,%edx
  jne    L65
L8:
  mov    %edi,%eax
  ret
L37:
  test   %r11d,%r11d
  je     L121
  cmp    $0x1,%r9d
  jne    L94
  jmp    L8
L44:
  mov    %esi,%edi
  jmp    L8
L121:
  mov    $0x0,%edi
  jmp    L8
```

assistant: ```c
int nested_break_continue(int a, int b, int c) {
  while (a < b) {
    while (b < c) {
      while (c < 4) {
        c++;
        if (c % 4 == 0)
          break;
        if (c % 4 == 1)
          return a;
        if (c % 4 == 2)
          continue;
      }
      if (b % 4 == 0)
        break;
      if (b % 4 == 1)
        return b;
      if (b % 4 == 2)
        continue;
    }
    if (a % 4 == 0)
      break;
    if (a % 4 == 1)
      return a;
    if (a % 4 == 2)
      continue;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nested_break_continue>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%edx
  mov    %edi,%r9d
  mov    %esi,%ecx
  sar    $0x1f,%edx
  sar    $0x1f,%r9d
  mov    %edi,%r8d
  shr    $0x1e,%edx
  shr    $0x1e,%r9d
  mov    %r8d,%r10d
  lea    (%rsi,%rdx,1),%esi
  and    $0x3,%r10d
  and    $0x3,%esi
  sub    %edx,%esi
  lea    (%rdi,%r9,1),%edx
  and    $0x3,%edx
  mov    %edx,%edi
  sub    %r9d,%edi
  mov    %ecx,%r9d
  and    $0x3,%r9d
L23:
  cmp    %ecx,%r8d
  jge    L105
L27:
  cmp    %ecx,%eax
  jg     L28
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L32:
  add    $0x1,%eax
  test   $0x3,%al
  je     L33
  mov    %eax,%edx
  and    $0x80000003,%edx
  cmp    $0x1,%edx
  je     L47
L28:
  cmp    $0x3,%eax
  jle    L32
L33:
  test   %r9d,%r9d
  je     L49
  cmp    $0x1,%esi
  jne    L27
  mov    %ecx,%r8d
L47:
  mov    %r8d,%eax
  ret
L49:
  test   %r10d,%r10d
  je     L105
  cmp    $0x1,%edi
  jne    L23
  jmp    L47
L105:
  xor    %r8d,%r8d
  jmp    L47
```

assistant: ```c
int nested_break_continue(int a, int b, int c) {
  while (a < b) {
    while (b < c) {
      while (c < 4) {
        c++;
        if (c % 4 == 0)
          break;
        if (c % 4 == 1)
          return a;
        if (c % 4 == 2)
          continue;
      }
      if (b % 4 == 0)
        break;
      if (b % 4 == 1)
        return b;
      if (b % 4 == 2)
        continue;
    }
    if (a % 4 == 0)
      break;
    if (a % 4 == 1)
      return a;
    if (a % 4 == 2)
      continue;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<nested_break_continue>:
  endbr64
  mov    %edx,%eax
  mov    %esi,%edx
  mov    %edi,%r9d
  mov    %esi,%r10d
  sar    $0x1f,%edx
  mov    %esi,%ecx
  sar    $0x1f,%r9d
  mov    %edi,%r11d
  shr    $0x1e,%edx
  shr    $0x1e,%r9d
  mov    %edi,%r8d
  and    $0x3,%r10d
  lea    (%rsi,%rdx,1),%esi
  and    $0x3,%r11d
  and    $0x3,%esi
  sub    %edx,%esi
  lea    (%rdi,%r9,1),%edx
  and    $0x3,%edx
  mov    %edx,%edi
  sub    %r9d,%edi
L48:
  cmp    %ecx,%r8d
  jge    L118
L19:
  cmp    %ecx,%eax
  jg     L1
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L82:
  add    $0x1,%eax
  test   $0x3,%al
  je     L60
  mov    %eax,%edx
  and    $0x80000003,%edx
  cmp    $0x1,%edx
  je     L58
L1:
  cmp    $0x3,%eax
  jle    L82
L60:
  test   %r10d,%r10d
  je     L36
  cmp    $0x1,%esi
  jne    L19
  mov    %ecx,%r8d
L58:
  mov    %r8d,%eax
  ret
L36:
  test   %r11d,%r11d
  je     L118
  cmp    $0x1,%edi
  jne    L48
  jmp    L58
L118:
  xor    %r8d,%r8d
  jmp    L58
```

assistant: ```c
int nested_break_continue(int a, int b, int c) {
  while (a < b) {
    while (b < c) {
      while (c < 4) {
        c++;
        if (c % 4 == 0)
          break;
        if (c % 4 == 1)
          return a;
        if (c % 4 == 2)
          continue;
      }
      if (b % 4 == 0)
        break;
      if (b % 4 == 1)
        return b;
      if (b % 4 == 2)
        continue;
    }
    if (a % 4 == 0)
      break;
    if (a % 4 == 1)
      return a;
    if (a % 4 == 2)
      continue;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<floats_squared_distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  movss  -0x8(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float floats_squared_distance(const float *a, const float *b, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += (a[i] - b[i]) * (a[i] - b[i]);
  return acc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<floats_squared_distance>:
  endbr64
  test   %edx,%edx
  jle    L19
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L17:
  movss  (%rdi,%rax,4),%xmm0
  subss  (%rsi,%rax,4),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L24:
  movaps %xmm1,%xmm0
  ret
L19:
  pxor   %xmm1,%xmm1
  jmp    L24
```

assistant: ```c
float floats_squared_distance(const float *a, const float *b, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += (a[i] - b[i]) * (a[i] - b[i]);
  return acc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<floats_squared_distance>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L0:
  movss  (%rdi,%rax,4),%xmm0
  subss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  mulss  %xmm0,%xmm0
  addss  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L0
  movaps %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  pxor   %xmm1,%xmm1
  movaps %xmm1,%xmm0
  ret
```

assistant: ```c
float floats_squared_distance(const float *a, const float *b, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += (a[i] - b[i]) * (a[i] - b[i]);
  return acc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floats_squared_distance>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L54
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L19
  mov    %edx,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L65:
  movups (%rdi,%rax,1),%xmm1
  movups (%rcx,%rax,1),%xmm3
  add    $0x10,%rax
  subps  %xmm3,%xmm1
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L65
  mov    %edx,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%eax
  cmp    %esi,%edx
  je     L57
L63:
  sub    %esi,%edx
  cmp    $0x1,%edx
  je     L5
  movq   (%rdi,%rsi,4),%xmm1
  movq   (%rcx,%rsi,4),%xmm2
  mov    %edx,%esi
  and    $0xfffffffe,%esi
  subps  %xmm2,%xmm1
  add    %esi,%eax
  mulps  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  shufps $0xe5,%xmm1,%xmm1
  addss  %xmm1,%xmm0
  cmp    %esi,%edx
  je     L10
L5:
  cltq
  movss  (%rdi,%rax,4),%xmm1
  subss  (%rcx,%rax,4),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  pxor   %xmm0,%xmm0
L10:
  ret
  nopl   (%rax)
L57:
  ret
L19:
  xor    %esi,%esi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L63
```

assistant: ```c
float floats_squared_distance(const float *a, const float *b, int len) {
  float acc = 0;
  for (int i = 0; i < len; i++)
    acc += (a[i] - b[i]) * (a[i] - b[i]);
  return acc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parseNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L27
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L27
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parseBinary@plt>
  mov    %eax,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string

tool: D16: 0x%x

tool: D10: %u

assistant: ```c
unsigned int parseNumber(char *str) {
  unsigned int addr = 0;
  if (!sscanf(str, "0x%x", &addr)) {
    if (!sscanf(str, "%u", &addr)) {
      addr = parseBinary(str);
    }
  }
  return addr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parseNumber>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  test   %eax,%eax
  je     L17
L38:
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  lea    0x4(%rsp),%rdx
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L38
  mov    %rbx,%rdi
  call   <parseBinary@plt>
  mov    %eax,0x4(%rsp)
  jmp    L38
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string

tool: D2: 0x%x

tool: D11: %u

assistant: ```c
unsigned int parseNumber(char *str) {
  unsigned int addr = 0;
  if (!sscanf(str, "0x%x", &addr)) {
    if (!sscanf(str, "%u", &addr)) {
      addr = parseBinary(str);
    }
  }
  return addr;
}
```