ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<hputi4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <hputc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: %d

assistant: ```c
int hputi4(hstring, keyword, ival)
char *hstring;
char *keyword;
int ival;
{
  char value[30];
  sprintf(value, "%d", ival);
  return (hputc(hstring, keyword, value));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hputi4>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D9(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <hputc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: %d

assistant: ```c
int hputi4(hstring, keyword, ival)
char *hstring;
char *keyword;
int ival;
{
  char value[30];
  sprintf(value, "%d", ival);
  return (hputc(hstring, keyword, value));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hputi4>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D3(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <hputc@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x30,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: %d

assistant: ```c
int hputi4(hstring, keyword, ival)
char *hstring;
char *keyword;
int ival;
{
  char value[30];
  sprintf(value, "%d", ival);
  return (hputc(hstring, keyword, value));
}
```
user: Translate the below assembly code into C programming language:

```asm
<tlist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tlistt@plt>
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <dbtgetnxt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
data_type: string

tool: D8: [tlist]


assistant: ```c
void tlist() {
  struct dbt *dt = NULL;
  printf("[tlist]\n");
  while ((dt = dbtgetnxt(dt)))
    tlistt(dt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tlist>:
  endbr64
  push   %rbx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L4
L0:
  mov    %rbx,%rdi
  call   <tlistt@plt>
L4:
  mov    %rbx,%rdi
  call   <dbtgetnxt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L0
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: [tlist]


assistant: ```c
void tlist() {
  struct dbt *dt = NULL;
  printf("[tlist]\n");
  while ((dt = dbtgetnxt(dt)))
    tlistt(dt);
}
```
user: What is the c source code of the assembly code below?

```asm
<tlist>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  xor    %ebp,%ebp
  call   <printf@plt>
  jmp    L8
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  call   <tlistt@plt>
L8:
  mov    %rbp,%rdi
  call   <dbtgetnxt@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L4
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7: [tlist]


assistant: ```c
void tlist() {
  struct dbt *dt = NULL;
  printf("[tlist]\n");
  while ((dt = dbtgetnxt(dt)))
    tlistt(dt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tlist>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  xor    %ebp,%ebp
  call   <printf@plt>
  jmp    L16
  nopl   (%rax)
L18:
  mov    %rbp,%rdi
  call   <tlistt@plt>
L16:
  mov    %rbp,%rdi
  call   <dbtgetnxt@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L18
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string

tool: D4: [tlist]


assistant: ```c
void tlist() {
  struct dbt *dt = NULL;
  printf("[tlist]\n");
  while ((dt = dbtgetnxt(dt)))
    tlistt(dt);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<shell_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L37
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L51
L1:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L47
L15:
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  sub    %eax,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L53
  mov    -0xc(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L15
L53:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L18
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L18:
  addl   $0x1,-0x10(%rbp)
L51:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  cmpl   $0x1,-0x8(%rbp)
  jne    L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shell_sort(int a[], int size) {
  int i, j;
  int h = 1;
  do {
    h = h * 3 + 1;
  } while (h <= size);
  do {
    h /= 3;
    for (i = h; i < size; i++) {
      int v = a[i];
      for (j = i; j >= h && a[j - h] > v; j -= h)
        a[j] = a[j - h];
      if (i != j)
        a[j] = v;
    }
  } while (h != 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<shell_sort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x1,%esi
L80:
  lea    0x1(%rsi,%rsi,2),%esi
  cmp    %r12d,%esi
  jle    L80
  jmp    L26
L28:
  cmp    %edi,%r13d
  je     L7
  movslq %edi,%rdi
  mov    %r8d,0x0(%rbp,%rdi,4)
L7:
  add    $0x1,%r13d
  add    $0x4,%r11
  cmp    %r13d,%r12d
  je     L65
L60:
  mov    (%r11),%r8d
  mov    %r11,%rdx
  mov    %r13d,%eax
  cmp    %r13d,%esi
  jg     L7
L18:
  mov    %eax,%edi
  sub    %esi,%eax
  mov    (%rdx,%r9,1),%ecx
  cmp    %r8d,%ecx
  jle    L28
  mov    %ecx,(%rdx)
  add    %r10,%rdx
  cmp    %esi,%eax
  jge    L18
  mov    %eax,%edi
  jmp    L28
L65:
  cmp    $0x1,%ebx
  je     L20
L26:
  movslq %esi,%rbx
  imul   $0x55555556,%rbx,%rbx
  shr    $0x20,%rbx
  sar    $0x1f,%esi
  sub    %esi,%ebx
  mov    %ebx,%esi
  cmp    %ebx,%r12d
  jle    L65
  movslq %ebx,%r9
  lea    0x0(%rbp,%r9,4),%r11
  mov    %ebx,%r10d
  neg    %r10d
  movslq %r10d,%r10
  shl    $0x2,%r10
  neg    %r9
  shl    $0x2,%r9
  mov    %ebx,%r13d
  jmp    L60
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void shell_sort(int a[], int size) {
  int i, j;
  int h = 1;
  do {
    h = h * 3 + 1;
  } while (h <= size);
  do {
    h /= 3;
    for (i = h; i < size; i++) {
      int v = a[i];
      for (j = i; j >= h && a[j - h] > v; j -= h)
        a[j] = a[j - h];
      if (i != j)
        a[j] = v;
    }
  } while (h != 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<shell_sort>:
  endbr64
  push   %r13
  mov    $0x1,%r11d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L21:
  lea    0x1(%r11,%r11,2),%r11d
  cmp    %ebp,%r11d
  jle    L21
  nopw   0x0(%rax,%rax,1)
L5:
  movslq %r11d,%rsi
  sar    $0x1f,%r11d
  imul   $0x55555556,%rsi,%rsi
  shr    $0x20,%rsi
  sub    %r11d,%esi
  mov    %esi,%r11d
  cmp    %esi,%ebp
  jle    L7
  mov    %esi,%r10d
  movslq %esi,%r9
  mov    %esi,%r13d
  neg    %r10d
  shl    $0x2,%r9
  movslq %r10d,%r10
  lea    (%rbx,%r9,1),%r12
  neg    %r9
  shl    $0x2,%r10
  nopw   0x0(%rax,%rax,1)
L41:
  mov    (%r12),%edi
  mov    %r12,%rdx
  mov    %r13d,%eax
  jmp    L63
  nopl   0x0(%rax)
L14:
  mov    %ecx,(%rdx)
  add    %r10,%rdx
  cmp    %esi,%eax
  jl     L85
L63:
  mov    (%rdx,%r9,1),%ecx
  mov    %eax,%r8d
  sub    %esi,%eax
  cmp    %edi,%ecx
  jg     L14
  cmp    %r8d,%r13d
  jne    L26
L77:
  add    $0x1,%r13d
  add    $0x4,%r12
  cmp    %r13d,%ebp
  jne    L41
L7:
  cmp    $0x1,%esi
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  mov    %r8d,%eax
L85:
  cltq
  mov    %edi,(%rbx,%rax,4)
  jmp    L77
```

assistant: ```c
void shell_sort(int a[], int size) {
  int i, j;
  int h = 1;
  do {
    h = h * 3 + 1;
  } while (h <= size);
  do {
    h /= 3;
    for (i = h; i < size; i++) {
      int v = a[i];
      for (j = i; j >= h && a[j - h] > v; j -= h)
        a[j] = a[j - h];
      if (i != j)
        a[j] = v;
    }
  } while (h != 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<shell_sort>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  nopl   (%rax)
L90:
  lea    0x1(%rbp,%rbp,2),%ebp
  cmp    %r13d,%ebp
  jle    L90
  nopl   0x0(%rax)
L81:
  movslq %ebp,%rdi
  sar    $0x1f,%ebp
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  sub    %ebp,%edi
  mov    %edi,%ebp
  cmp    %edi,%r13d
  jle    L116
  movslq %edi,%r10
  mov    %edi,%r11d
  shl    $0x2,%r10
  mov    %r10,%r9
  lea    (%r12,%r10,1),%rbx
  neg    %r9
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%r8d
  mov    %rbx,%rax
  mov    %r11d,%edx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %ecx,(%rax)
  sub    %r10,%rax
  cmp    %edx,%edi
  jg     L52
L41:
  movslq %edx,%rsi
  mov    (%rax,%r9,1),%ecx
  mov    %esi,%edx
  sub    %edi,%edx
  cmp    %r8d,%ecx
  jg     L47
  cmp    %r11d,%esi
  je     L69
L91:
  add    $0x1,%r11d
  mov    %r8d,(%r12,%rsi,4)
  add    $0x4,%rbx
  cmp    %r11d,%r13d
  jne    L2
L116:
  cmp    $0x1,%edi
  jne    L81
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L52:
  movslq %edx,%rsi
  cmp    %r11d,%esi
  jne    L91
L69:
  add    $0x1,%r11d
  add    $0x4,%rbx
  cmp    %r13d,%r11d
  jne    L2
  cmp    $0x1,%edi
  jne    L81
  jmp    L78
```

assistant: ```c
void shell_sort(int a[], int size) {
  int i, j;
  int h = 1;
  do {
    h = h * 3 + 1;
  } while (h <= size);
  do {
    h /= 3;
    for (i = h; i < size; i++) {
      int v = a[i];
      for (j = i; j >= h && a[j - h] > v; j -= h)
        a[j] = a[j - h];
      if (i != j)
        a[j] = v;
    }
  } while (h != 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
datatype: string

tool: D3:  The number is %d


assistant: ```c
int main() {
  int number = 0;
  printf(" The number is %d\n", number);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6:  The number is %d


assistant: ```c
int main() {
  int number = 0;
  printf(" The number is %d\n", number);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2:  The number is %d


assistant: ```c
int main() {
  int number = 0;
  printf(" The number is %d\n", number);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
datatype: string

tool: D0:  The number is %d


assistant: ```c
int main() {
  int number = 0;
  printf(" The number is %d\n", number);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xdr_bool>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L115
  cmp    $0x82,%eax
  jg     L83
  cmp    $0x80,%eax
  je     L15
  cmp    $0x81,%eax
  jne    L83
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L29
  mov    $0x1,%eax
  jmp    L60
L29:
  mov    $0x0,%eax
L60:
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    (%rax),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  jmp    L47
L115:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    0x8(%rax),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jne    L85
  mov    $0x0,%eax
  jmp    L47
L85:
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
  jmp    L47
L15:
  mov    $0x1,%eax
  jmp    L47
L83:
  mov    $0x0,%eax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
bool_t xdr_bool(XDR *xdrs, int32_t *bp) {
  long lb;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    lb = *bp ? ((long)1) : ((long)0);
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, &lb));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, &lb)) {
      return (0);
    }
    *bp = (lb == ((long)0)) ? 0 : 1;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xdr_bool>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L21
  cmp    $0x82,%eax
  je     L35
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x10,%rsp
  pop    %rbx
  ret
L21:
  cmpl   $0x0,(%rsi)
  setne  %al
  movzbl %al,%eax
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  mov    0x8(%rdi),%rax
  call   *(%rax)
  jmp    L5
L35:
  mov    %rsp,%rsi
  mov    0x8(%rdi),%rax
  call   *0x8(%rax)
  test   %eax,%eax
  je     L5
  cmpq   $0x0,(%rsp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L5
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_bool(XDR *xdrs, int32_t *bp) {
  long lb;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    lb = *bp ? ((long)1) : ((long)0);
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, &lb));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, &lb)) {
      return (0);
    }
    *bp = (lb == ((long)0)) ? 0 : 1;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xdr_bool>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L49
  cmp    $0x82,%eax
  je     L34
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  mov    (%rsi),%edx
  xor    %eax,%eax
  mov    %rsp,%rsi
  test   %edx,%edx
  setne  %al
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rax
  call   *(%rax)
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L34:
  mov    0x8(%rdi),%rax
  mov    %rsp,%rsi
  call   *0x8(%rax)
  test   %eax,%eax
  je     L9
  xor    %eax,%eax
  cmpq   $0x0,(%rsp)
  setne  %al
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L9
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_bool(XDR *xdrs, int32_t *bp) {
  long lb;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    lb = *bp ? ((long)1) : ((long)0);
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, &lb));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, &lb)) {
      return (0);
    }
    *bp = (lb == ((long)0)) ? 0 : 1;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<xdr_bool>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L58
  cmp    $0x82,%eax
  je     L33
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L18:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L56
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L58:
  mov    (%rsi),%edx
  xor    %eax,%eax
  mov    %rsp,%rsi
  test   %edx,%edx
  setne  %al
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rax
  call   *(%rax)
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L33:
  mov    0x8(%rdi),%rax
  mov    %rsp,%rsi
  call   *0x8(%rax)
  test   %eax,%eax
  je     L18
  xor    %eax,%eax
  cmpq   $0x0,(%rsp)
  setne  %al
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  jmp    L18
L56:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool_t xdr_bool(XDR *xdrs, int32_t *bp) {
  long lb;
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    lb = *bp ? ((long)1) : ((long)0);
    return ((*(xdrs)->x_ops->x_putlong)(xdrs, &lb));
  case XDR_DECODE:
    if (!(*(xdrs)->x_ops->x_getlong)(xdrs, &lb)) {
      return (0);
    }
    *bp = (lb == ((long)0)) ? 0 : 1;
    return (1);
  case XDR_FREE:
    return (1);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reference>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L56
L52:
  movl   $0x0,-0x14(%rbp)
  jmp    L70
L91:
  mov    -0x8(%rbp),%eax
  neg    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L54
L9:
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  jmp    L15
L25:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  js     L73
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x34(%rbp)
  jle    L73
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  js     L73
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x38(%rbp)
  jle    L73
  mov    -0x14(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x34(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x14(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
L73:
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L25
  addl   $0x1,-0x10(%rbp)
L54:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L9
  addl   $0x1,-0x14(%rbp)
L70:
  mov    -0x14(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L91
  addl   $0x1,-0x18(%rbp)
L56:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L52
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int reference(float *in, float *out, int data_size_X, int data_size_Y, float *kernel) {
  int kern_cent_X = (3 - 1) / 2;
  int kern_cent_Y = (3 - 1) / 2;
  for (int x = 0; x < data_size_X; x++) {
    for (int y = 0; y < data_size_Y; y++) {
      for (int i = -kern_cent_X; i <= kern_cent_X; i++) {
        for (int j = -kern_cent_Y; j <= kern_cent_Y; j++) {
          if (x + i > -1 && x + i < data_size_X && y + j > -1 && y + j < data_size_Y) {
            out[x + y * data_size_X] += kernel[(kern_cent_X - i) + (kern_cent_Y - j) * 3] * in[(x + i) + (y + j) * data_size_X];
          }
        }
      }
    }
  }
  return 1;
}
```