user: Please show me the C implementation that matches the assembly code listed below:

```asm
<super_fast_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L29
  test   %rbx,%rbx
  je     L29
  mov    %eax,%r8d
  mov    %eax,%edx
  and    $0x3,%r8d
  sar    $0x2,%eax
  je     L106
  cltq
  mov    (%rbx),%rsi
  mov    0x2(%rbx),%rcx
  lea    (%rbx,%rax,8),%rdi
  nopl   (%rax)
L100:
  mov    %rsi,%r9
  mov    0x8(%rbx),%rsi
  add    $0x8,%rbx
  mov    %esi,%eax
  shl    $0x8,%eax
  add    %r9d,%eax
  mov    %rcx,%r9
  mov    0x2(%rbx),%rcx
  add    %edx,%eax
  mov    %ecx,%edx
  shl    $0x8,%edx
  add    %r9d,%edx
  shl    $0xb,%edx
  xor    %eax,%edx
  shl    $0x10,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  sar    $0xb,%edx
  add    %eax,%edx
  cmp    %rdi,%rbx
  jne    L100
L17:
  cmp    $0x2,%r8d
  je     L73
  cmp    $0x3,%r8d
  je     L76
  cmp    $0x1,%r8d
  je     L19
L13:
  lea    0x0(,%rdx,8),%eax
  pop    %rbx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0x5,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0x11,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0x19,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  sar    $0x6,%eax
  add    %edx,%eax
  ret
  xchg   %ax,%ax
L29:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  movsbl (%rdi),%eax
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  sar    %edx
  add    %eax,%edx
  jmp    L13
  nopl   0x0(%rax)
L76:
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  add    %edx,%eax
  movsbl 0x4(%rdi),%edx
  mov    %eax,%ecx
  shl    $0x12,%edx
  shl    $0x10,%ecx
  xor    %edx,%eax
  xor    %ecx,%eax
  mov    %eax,%edx
  sar    $0xb,%edx
  add    %eax,%edx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L73:
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  add    (%rdi),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0xb,%edx
  xor    %edx,%eax
  mov    %eax,%edx
  sar    $0x11,%edx
  add    %eax,%edx
  jmp    L13
  nopl   (%rax)
L106:
  mov    %rbx,%rdi
  jmp    L17
```

assistant: ```c
uint32_t super_fast_hash(const char *data) {
  uint32_t len = strlen(data);
  uint32_t hash = len, tmp;
  int rem;
  if (len <= 0 || data == NULL)
    return 0;
  rem = len & 3;
  len >>= 2;
  for (; len > 0; len--) {
    hash += ((((uint32_t)(((const uint8_t *)(data))[1])) << 8) + (uint32_t)(((const uint8_t *)(data))[0]));
    tmp = (((((uint32_t)(((const uint8_t *)(data + 2))[1])) << 8) + (uint32_t)(((const uint8_t *)(data + 2))[0])) << 11) ^ hash;
    hash = (hash << 16) ^ tmp;
    data += 2 * sizeof(uint16_t);
    hash += hash >> 11;
  }
  switch (rem) {
  case 3:
    hash += ((((uint32_t)(((const uint8_t *)(data))[1])) << 8) + (uint32_t)(((const uint8_t *)(data))[0]));
    hash ^= hash << 16;
    hash ^= ((signed char)data[sizeof(uint16_t)]) << 18;
    hash += hash >> 11;
    break;
  case 2:
    hash += ((((uint32_t)(((const uint8_t *)(data))[1])) << 8) + (uint32_t)(((const uint8_t *)(data))[0]));
    hash ^= hash << 11;
    hash += hash >> 17;
    break;
  case 1:
    hash += (signed char)*data;
    hash ^= hash << 10;
    hash += hash >> 1;
  }
  hash ^= hash << 3;
  hash += hash >> 5;
  hash ^= hash << 4;
  hash += hash >> 17;
  hash ^= hash << 25;
  hash += hash >> 6;
  return hash;
}
```