user: Translate the below assembly code into C programming language:

```asm
<residuo>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  lea    0x10(%rsp),%r12
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  mov    %ecx,%r14d
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <clean@plt>
  cmp    %r14d,%ebp
  jge    L195
  mov    %r14d,%ecx
  sub    %ebp,%ecx
  cmp    $0x1,%ecx
  je     L32
  movslq %ebp,%rax
  pxor   %xmm5,%xmm5
  lea    (%rbx,%rax,8),%rdx
  mov    %ecx,%eax
  movapd %xmm5,%xmm4
  shr    %eax
  lea    -0x1(%rax),%esi
  lea    0x10(%rdx),%rax
  shl    $0x4,%rsi
  add    %rax,%rsi
  jmp    L210
  nopl   0x0(%rax)
L84:
  add    $0x10,%rax
L210:
  movupd (%rdx),%xmm1
  mov    %rax,%rdx
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm4
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm4
  cmp    %rsi,%rax
  jne    L84
  mov    %ecx,%edx
  and    $0xfffffffe,%edx
  lea    (%rdx,%rbp,1),%eax
  cmp    %edx,%ecx
  je     L205
L124:
  cltq
  movsd  (%rbx,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm4
L205:
  ucomisd %xmm4,%xmm5
  ja     L152
L115:
  sqrtsd %xmm4,%xmm4
L50:
  test   %ebp,%ebp
  jle    L23
  mov    %r13,%rcx
  mov    %r13,%rsi
  mov    %r12,%r11
  mov    %rbx,%rdi
  mov    %ebp,%r10d
  mov    %r12,%r9
  xor    %r8d,%r8d
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L225:
  cmp    %r8d,%ebp
  mov    %r13d,%r14d
  movsd  (%r9),%xmm2
  cmovg  %r10d,%r14d
  cmp    $0x1,%r10d
  je     L234
  cmp    %r8d,%ebp
  jle    L234
  mov    %r14d,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  nopl   (%rax)
L129:
  movupd (%rsi,%rax,1),%xmm1
  movupd (%rdi,%rax,1),%xmm6
  add    $0x10,%rax
  mulpd  %xmm6,%xmm1
  addsd  %xmm1,%xmm2
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  cmp    %rdx,%rax
  jne    L129
  mov    %r14d,%edx
  and    $0xfffffffe,%edx
  lea    (%rdx,%r8,1),%eax
  cmp    %r14d,%edx
  je     L99
L249:
  cltq
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  addsd  %xmm1,%xmm2
L99:
  add    $0x1,%r8d
  add    $0x8,%r9
  sub    $0x1,%r10d
  add    $0x8,%rdi
  movsd  %xmm2,-0x8(%r9)
  add    $0x1f40,%rcx
  add    $0x1f48,%rsi
  cmp    %r8d,%ebp
  jne    L225
  cmp    $0x1,%ebp
  je     L0
  mov    %ebp,%eax
  add    $0x10,%r12
  movapd %xmm5,%xmm0
  shr    %eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  add    %r12,%rax
  jmp    L27
L28:
  add    $0x10,%r12
L27:
  movapd (%r11),%xmm1
  mov    %r12,%r11
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %r12,%rax
  jne    L28
  mov    %ebp,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ebp
  je     L42
L20:
  cltq
  movsd  0x10(%rsp,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L42:
  ucomisd %xmm0,%xmm5
  ja     L4
L19:
  sqrtsd %xmm0,%xmm0
L169:
  addsd  %xmm4,%xmm0
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L246
  add    $0x1f60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L234:
  mov    %r8d,%eax
  jmp    L249
L195:
  pxor   %xmm5,%xmm5
  movapd %xmm5,%xmm4
  jmp    L115
L23:
  movapd %xmm5,%xmm0
  jmp    L19
L0:
  xor    %eax,%eax
  movapd %xmm5,%xmm0
  jmp    L20
L32:
  pxor   %xmm5,%xmm5
  mov    %ebp,%eax
  movapd %xmm5,%xmm4
  jmp    L124
L152:
  movapd %xmm4,%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm5
  movapd %xmm0,%xmm4
  jmp    L50
L246:
  call   <__stack_chk_fail@plt>
L4:
  movsd  %xmm4,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm4
  jmp    L169
```

tool_calls: name: read_data
arguments: data_tag: D3
type: string

tool: D3: Residuo: = %.5f 


assistant: ```c
void residuo(double A[1000][1000], double b[1000], int rank, int n, int m) {
  double res1, res2;
  double aux[1000];
  int i, j;
  clean(aux, 1000);
  res1 = res2 = 0;
  for (i = rank; i < n; i++)
    res1 += (b[i] * b[i]);
  res1 = sqrt(res1);
  for (i = 0; i < rank; i++)
    for (j = i; j < rank; j++)
      aux[i] += (A[i][j] * b[j]);
  for (i = 0; i < rank; i++)
    res2 += (aux[i] * aux[i]);
  res2 = sqrt(res2);
  printf("Residuo: = %.5f \n", res1 + res2);
}
```