user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%rdi
  lea    D14(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D42(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L124
  mov    %rbp,%r12
  xor    %ebx,%ebx
L177:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L177
  cmp    $0x1,%edx
  jle    L124
  mov    $0x1,%r8d
  xor    %edi,%edi
  nopw   0x0(%rax,%rax,1)
L145:
  cmp    %r8d,%edx
  jle    L175
  mov    0x0(%rbp,%rdi,4),%ecx
  mov    %r8,%rax
  test   $0x1,%dil
  jne    L17
  cs nopw 0x0(%rax,%rax,1)
L79:
  mov    0x0(%rbp,%rax,4),%esi
  cmp    %ecx,%esi
  jle    L187
L109:
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  mov    %esi,0x0(%rbp,%rdi,4)
  mov    0x4(%rsp),%edx
  cmp    %eax,%edx
  jle    L175
  mov    %esi,%ecx
  mov    0x0(%rbp,%rax,4),%esi
  cmp    %ecx,%esi
  jg     L109
L187:
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L79
L175:
  add    $0x1,%rdi
  lea    -0x1(%rdx),%eax
  add    $0x1,%r8
  cmp    %edi,%eax
  jg     L145
L124:
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    D6(%rip),%r12
  test   %eax,%eax
  jle    L102
  nopl   0x0(%rax)
L72:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L72
L102:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x1,%rax
  cmp    %eax,%edx
  jle    L175
L17:
  mov    0x0(%rbp,%rax,4),%esi
  cmp    %esi,%ecx
  jle    L25
L59:
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  mov    %esi,0x0(%rbp,%rdi,4)
  mov    0x4(%rsp),%edx
  cmp    %eax,%edx
  jle    L175
  mov    %esi,%ecx
  mov    0x0(%rbp,%rax,4),%esi
  cmp    %esi,%ecx
  jg     L59
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L17
  jmp    L175
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D42
type_guessed: string
name: read_data
arguments: label: D20
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string

tool: D15: Array size : 

tool: D14: %d

tool: D42: Enter Elements : 

tool: D20: Array elements  : 

tool: D6: %d 

assistant: ```c
int main(void) {
  int *a, n, i, j;
  printf("Array size : ");
  scanf("%d", &n);
  a = malloc(sizeof(int) * n);
  printf("Enter Elements : ");
  for (i = 0; i < n; i++)
    scanf("%d", a + i);
  for (i = 0; i < n - 1; i++)
    for (j = i + 1; j < n; j++) {
      if (i % 2) {
        if (a[i] > a[j])
          a[i] = a[i] + a[j] - (a[j] = a[i]);
      } else {
        if (a[i] < a[j])
          a[i] = a[i] + a[j] - (a[j] = a[i]);
      }
    }
  printf("Array elements  : ");
  for (i = 0; i < n; i++)
    printf("%d ", a[i]);
  printf("\n");
  free(a);
  return 0;
}
```