ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binomial>:
  endbr64
  sub    %esi,%edi
  test   %esi,%esi
  jle    L13
  add    $0x1,%esi
  mov    $0x1,%edx
  mov    $0x1,%ecx
  mov    $0x1,%eax
  nopl   0x0(%rax)
L4:
  imul   %edx,%ecx
  lea    (%rdx,%rdi,1),%r8d
  add    $0x1,%edx
  imul   %r8d,%eax
  cmp    %edx,%esi
  jne    L4
  cltd
  idiv   %ecx
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int binomial(int n, int k) {
  register int up, down, loop, n_minus_k;
  for (up = 1, down = 1, n_minus_k = n - k, loop = 1; loop <= k; loop++) {
    up *= n_minus_k + loop;
    down *= loop;
  }
  return (up / down);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<find_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L16:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L24
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L24:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L16
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_min(int *nums, int nums_size) {
  int low = 0, high = nums_size - 1, mid;
  while (low < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] < nums[high]) {
      high = mid;
    } else {
      low = mid + 1;
    }
  }
  return nums[low];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_min>:
  endbr64
  sub    $0x1,%esi
  mov    $0x0,%edx
L22:
  cmp    %edx,%esi
  jle    L15
  mov    %esi,%ecx
  sub    %edx,%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r8
  movslq %esi,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%r8,4)
  jge    L0
  mov    %eax,%esi
  jmp    L22
L0:
  lea    0x1(%rax),%edx
  jmp    L22
L15:
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  ret
```

assistant: ```c
int find_min(int *nums, int nums_size) {
  int low = 0, high = nums_size - 1, mid;
  while (low < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] < nums[high]) {
      high = mid;
    } else {
      low = mid + 1;
    }
  }
  return nums[low];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_min>:
  endbr64
  sub    $0x1,%esi
  xor    %edx,%edx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %esi,%eax
  movslq %esi,%rcx
  sub    %edx,%eax
  mov    (%rdi,%rcx,4),%ecx
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  jge    L0
  mov    %eax,%esi
L1:
  cmp    %edx,%esi
  jg     L36
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  ret
  nopl   0x0(%rax)
L0:
  lea    0x1(%rax),%edx
  jmp    L1
```

assistant: ```c
int find_min(int *nums, int nums_size) {
  int low = 0, high = nums_size - 1, mid;
  while (low < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] < nums[high]) {
      high = mid;
    } else {
      low = mid + 1;
    }
  }
  return nums[low];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_min>:
  endbr64
  sub    $0x1,%esi
  xor    %edx,%edx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %esi,%eax
  movslq %esi,%rcx
  sub    %edx,%eax
  mov    (%rdi,%rcx,4),%ecx
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  jge    L26
  mov    %eax,%esi
L24:
  cmp    %edx,%esi
  jg     L12
  movslq %edx,%rdx
  mov    (%rdi,%rdx,4),%eax
  ret
  nopl   0x0(%rax)
L26:
  lea    0x1(%rax),%edx
  jmp    L24
```

assistant: ```c
int find_min(int *nums, int nums_size) {
  int low = 0, high = nums_size - 1, mid;
  while (low < high) {
    mid = low + (high - low) / 2;
    if (nums[mid] < nums[high]) {
      high = mid;
    } else {
      low = mid + 1;
    }
  }
  return nums[low];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nsvg__xformSetSkewX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movss  D18(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <tanf@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  movss  D18(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x14,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: byte[4]

tool: {"D18": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void nsvg__xformSetSkewX(float *t, float a) {
  t[0] = 1.0f;
  t[1] = 0.0f;
  t[2] = tanf(a);
  t[3] = 1.0f;
  t[4] = 0.0f;
  t[5] = 0.0f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nsvg__xformSetSkewX>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x3f800000,(%rdi)
  movl   $0x0,0x4(%rdi)
  call   <tanf@plt>
  movss  %xmm0,0x8(%rbx)
  movl   $0x3f800000,0xc(%rbx)
  movl   $0x0,0x10(%rbx)
  movl   $0x0,0x14(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void nsvg__xformSetSkewX(float *t, float a) {
  t[0] = 1.0f;
  t[1] = 0.0f;
  t[2] = tanf(a);
  t[3] = 1.0f;
  t[4] = 0.0f;
  t[5] = 0.0f;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<nsvg__xformSetSkewX>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movq   $0x3f800000,(%rdi)
  call   <tanf@plt>
  movq   $0x3f800000,0xc(%rbx)
  movl   $0x0,0x14(%rbx)
  movss  %xmm0,0x8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void nsvg__xformSetSkewX(float *t, float a) {
  t[0] = 1.0f;
  t[1] = 0.0f;
  t[2] = tanf(a);
  t[3] = 1.0f;
  t[4] = 0.0f;
  t[5] = 0.0f;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nsvg__xformSetSkewX>:
  endbr64
  mov    D4(%rip),%rax
  push   %rbx
  mov    %rdi,%rbx
  mov    %rax,(%rdi)
  call   <tanf@plt>
  movq   $0x3f800000,0xc(%rbx)
  movl   $0x0,0x14(%rbx)
  movss  %xmm0,0x8(%rbx)
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: byte[8]

tool: {"D4": [0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x00]}

assistant: ```c
void nsvg__xformSetSkewX(float *t, float a) {
  t[0] = 1.0f;
  t[1] = 0.0f;
  t[2] = tanf(a);
  t[3] = 1.0f;
  t[4] = 0.0f;
  t[5] = 0.0f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L84
L42:
  movl   $0x0,-0x3c(%rbp)
  jmp    L54
L102:
  cmpl   $0x1,-0x3c(%rbp)
  je     L67
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x0,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L67:
  cmpl   $0x1,-0x3c(%rbp)
  jne    L24
  addl   $0x1,-0x34(%rbp)
  cmpl   $0x2,-0x34(%rbp)
  jne    L47
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x0,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L47:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  movl   $0x8,-0x30(%rbp,%rax,4)
  mov    -0x38(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  addl   $0x1,-0x3c(%rbp)
L54:
  cmpl   $0x2,-0x3c(%rbp)
  jle    L102
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x38(%rbp)
L84:
  cmpl   $0x2,-0x38(%rbp)
  jle    L42
  jmp    L12
L50:
  addl   $0x1,-0x40(%rbp)
L12:
  cmpl   $0x9,-0x40(%rbp)
  jle    L50
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %d	

assistant: ```c
int main(void) {
  int n = 0, i, j, cont = 0;
  int m[3][3];
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (i != 1) {
        printf("%d\t", m[i][j] = 0);
      } else {
        if (i == 1) {
          cont++;
          if (cont == 2) {
            printf("%d\t", m[i][j] = 0);
          } else {
            printf("%d\t", m[i][j] = 8);
          }
        }
      }
    }
    printf("\n");
  }
  while (n < 10) {
    n++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%r12d
  mov    $0x0,%ebp
  lea    D4(%rip),%r13
  jmp    L21
L17:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  je     L24
  mov    $0x8,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L60:
  add    $0x1,%ebx
L1:
  cmp    $0x2,%ebx
  je     L17
  mov    $0x0,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x2,%ebx
  jle    L60
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  je     L36
L21:
  mov    $0x1,%ebx
  jmp    L1
L24:
  mov    $0x0,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L60
L36:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: string

tool: D4: %d	

assistant: ```c
int main(void) {
  int n = 0, i, j, cont = 0;
  int m[3][3];
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (i != 1) {
        printf("%d\t", m[i][j] = 0);
      } else {
        if (i == 1) {
          cont++;
          if (cont == 2) {
            printf("%d\t", m[i][j] = 0);
          } else {
            printf("%d\t", m[i][j] = 8);
          }
        }
      }
    }
    printf("\n");
  }
  while (n < 10) {
    n++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
L12:
  xor    %ebx,%ebx
L58:
  add    $0x1,%ebx
  cmp    $0x2,%ebx
  je     L2
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L58
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  jne    L12
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  je     L51
  mov    $0x8,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
  nopl   0x0(%rax)
L51:
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type: string

tool: D7: %d	

assistant: ```c
int main(void) {
  int n = 0, i, j, cont = 0;
  int m[3][3];
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (i != 1) {
        printf("%d\t", m[i][j] = 0);
      } else {
        if (i == 1) {
          cont++;
          if (cont == 2) {
            printf("%d\t", m[i][j] = 0);
          } else {
            printf("%d\t", m[i][j] = 8);
          }
        }
      }
    }
    printf("\n");
  }
  while (n < 10) {
    n++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    $0x3,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
L0:
  xor    %ebx,%ebx
L48:
  add    $0x1,%ebx
  cmp    $0x2,%ebx
  je     L54
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L48
  mov    $0xa,%edi
  call   <putchar@plt>
  sub    $0x1,%r12d
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L54:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  je     L51
  mov    $0x8,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
  nopl   0x0(%rax)
L51:
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: %d	

assistant: ```c
int main(void) {
  int n = 0, i, j, cont = 0;
  int m[3][3];
  for (j = 0; j < 3; j++) {
    for (i = 0; i < 3; i++) {
      if (i != 1) {
        printf("%d\t", m[i][j] = 0);
      } else {
        if (i == 1) {
          cont++;
          if (cont == 2) {
            printf("%d\t", m[i][j] = 0);
          } else {
            printf("%d\t", m[i][j] = 8);
          }
        }
      }
    }
    printf("\n");
  }
  while (n < 10) {
    n++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dlg_button_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L15:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int dlg_button_count(const char **labels) {
  int result = 0;
  while (*labels++ != 0)
    ++result;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dlg_button_count>:
  endbr64
  lea    0x8(%rdi),%rax
  cmpq   $0x0,(%rdi)
  je     L8
  mov    $0x0,%edx
L10:
  add    $0x1,%edx
  add    $0x8,%rax
  cmpq   $0x0,-0x8(%rax)
  jne    L10
L3:
  mov    %edx,%eax
  ret
L8:
  mov    $0x0,%edx
  jmp    L3
```

assistant: ```c
int dlg_button_count(const char **labels) {
  int result = 0;
  while (*labels++ != 0)
    ++result;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dlg_button_count>:
  endbr64
  xor    %r8d,%r8d
  cmpq   $0x0,(%rdi)
  lea    0x8(%rdi),%rax
  je     L3
  nopl   0x0(%rax)
L10:
  add    $0x8,%rax
  add    $0x1,%r8d
  cmpq   $0x0,-0x8(%rax)
  jne    L10
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int dlg_button_count(const char **labels) {
  int result = 0;
  while (*labels++ != 0)
    ++result;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dlg_button_count>:
  endbr64
  xor    %r8d,%r8d
  cmpq   $0x0,(%rdi)
  lea    0x8(%rdi),%rax
  je     L14
  nopl   0x0(%rax)
L7:
  add    $0x8,%rax
  add    $0x1,%r8d
  cmpq   $0x0,-0x8(%rax)
  jne    L7
L14:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int dlg_button_count(const char **labels) {
  int result = 0;
  while (*labels++ != 0)
    ++result;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_dns_query>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x818,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,(%r12)
  mov    %rsp,%r13
  mov    $0x800,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    (%r12),%esi
  mov    %r13,%rdi
  call   <dns_query_append16@plt>
  movl   $0x1,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  call   <dns_query_append16@plt>
  lea    0x18(%rsp),%rdi
  mov    $0x0,%esi
  call   <dns_query_append16@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x0,%esi
  call   <dns_query_append16@plt>
  lea    0x28(%rsp),%rdi
  mov    $0x0,%esi
  call   <dns_query_append16@plt>
  cmpb   $0x0,(%rbx)
  je     L81
  lea    0x30(%rsp),%rsi
  jmp    L79
L52:
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  sar    $0x2,%rcx
  sub    $0x1,%ecx
  mov    %ecx,(%rsi)
  cmp    $0x2e,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  je     L59
  mov    %rdx,%rsi
L79:
  lea    0x4(%rsi),%rdx
  movzbl (%rbx),%eax
  cmp    $0x2e,%al
  je     L52
  test   %al,%al
  je     L52
L63:
  add    $0x1,%rbx
  add    $0x4,%rdx
  movsbl %al,%eax
  mov    %eax,-0x4(%rdx)
  movzbl (%rbx),%eax
  cmp    $0x2e,%al
  je     L52
  test   %al,%al
  jne    L63
  jmp    L52
L81:
  lea    0x30(%rsp),%rdx
L59:
  lea    0x4(%rdx),%rdi
  movl   $0x0,(%rdx)
  mov    $0x1,%esi
  call   <dns_query_append16@plt>
  mov    %rax,%rdi
  mov    $0x1,%esi
  call   <dns_query_append16@plt>
  mov    %rsp,%rsi
  sub    %rsi,%rax
  mov    %rax,%rdx
  sar    $0x2,%rdx
  mov    $0x0,%ecx
  mov    %ebp,%edi
  call   <send@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  js     L101
L32:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L101:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L32
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_dns_query(int sock, const char *nodename, uint16_t *id) {
  uint8_t dns_query[512];
  size_t dns_query_len;
  uint8_t *pq;
  uint8_t *plen;
  const char *pname;
  *id = rand();
  memset(dns_query, 0, sizeof(dns_query));
  dns_query_append16(&dns_query[0], *id);
  dns_query[2] = (0 << 3) | (1 << 0);
  dns_query[3] = 0x00;
  dns_query_append16(&dns_query[4], 1);
  dns_query_append16(&dns_query[6], 0);
  dns_query_append16(&dns_query[8], 0);
  dns_query_append16(&dns_query[10], 0);
  pq = &dns_query[12];
  pname = nodename;
  while (*pname != '\0') {
    plen = pq;
    pq++;
    while ((*pname != '.') && (*pname != '\0')) {
      *pq++ = *pname++;
    }
    *plen = pq - plen - 1;
    if (*pname == '.') {
      pname++;
    }
  }
  *pq++ = 0x00;
  pq = dns_query_append16(pq, 1);
  pq = dns_query_append16(pq, 1);
  dns_query_len = (size_t)(pq - &dns_query[0]);
  if (send(sock, dns_query, dns_query_len, 0) < 0) {
    return EAI_SYSTEM;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<send_dns_query>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  call   <rand@plt>
  mov    $0x800,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  mov    %eax,0x0(%r13)
  call   <memset@plt>
  mov    0x0(%r13),%esi
  mov    %r12,%rdi
  call   <dns_query_append16@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x1,%esi
  movq   $0x1,0x8(%rsp)
  call   <dns_query_append16@plt>
  lea    0x18(%rsp),%rdi
  xor    %esi,%esi
  call   <dns_query_append16@plt>
  lea    0x20(%rsp),%rdi
  xor    %esi,%esi
  call   <dns_query_append16@plt>
  lea    0x28(%rsp),%rdi
  xor    %esi,%esi
  call   <dns_query_append16@plt>
  movsbl (%rbx),%eax
  test   %al,%al
  je     L3
  lea    0x30(%rsp),%rsi
  lea    0x4(%rsi),%rdx
  cmp    $0x2e,%al
  je     L1
  nopl   0x0(%rax,%rax,1)
L56:
  add    $0x1,%rbx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movsbl (%rbx),%eax
  cmp    $0x2e,%al
  je     L27
  test   %al,%al
  jne    L56
L27:
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  sar    $0x2,%rcx
  sub    $0x1,%ecx
L22:
  cmp    $0x2e,%al
  mov    %ecx,(%rsi)
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  movsbl (%rbx),%eax
  test   %al,%al
  je     L32
  mov    %rdx,%rsi
  lea    0x4(%rsi),%rdx
  cmp    $0x2e,%al
  jne    L56
L1:
  xor    %ecx,%ecx
  jmp    L22
L3:
  lea    0x30(%rsp),%rdx
  nopw   0x0(%rax,%rax,1)
L32:
  movl   $0x0,(%rdx)
  lea    0x4(%rdx),%rdi
  mov    $0x1,%esi
  call   <dns_query_append16@plt>
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <dns_query_append16@plt>
  xor    %ecx,%ecx
  mov    %r12,%rsi
  mov    %ebp,%edi
  sub    %r12,%rax
  mov    %rax,%rdx
  sar    $0x2,%rdx
  call   <send@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  js     L78
L29:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x818,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L78:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  jmp    L29
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int send_dns_query(int sock, const char *nodename, uint16_t *id) {
  uint8_t dns_query[512];
  size_t dns_query_len;
  uint8_t *pq;
  uint8_t *plen;
  const char *pname;
  *id = rand();
  memset(dns_query, 0, sizeof(dns_query));
  dns_query_append16(&dns_query[0], *id);
  dns_query[2] = (0 << 3) | (1 << 0);
  dns_query[3] = 0x00;
  dns_query_append16(&dns_query[4], 1);
  dns_query_append16(&dns_query[6], 0);
  dns_query_append16(&dns_query[8], 0);
  dns_query_append16(&dns_query[10], 0);
  pq = &dns_query[12];
  pname = nodename;
  while (*pname != '\0') {
    plen = pq;
    pq++;
    while ((*pname != '.') && (*pname != '\0')) {
      *pq++ = *pname++;
    }
    *plen = pq - plen - 1;
    if (*pname == '.') {
      pname++;
    }
  }
  *pq++ = 0x00;
  pq = dns_query_append16(pq, 1);
  pq = dns_query_append16(pq, 1);
  dns_query_len = (size_t)(pq - &dns_query[0]);
  if (send(sock, dns_query, dns_query_len, 0) < 0) {
    return EAI_SYSTEM;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubbleSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L40
L21:
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L44:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L15
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L15:
  addl   $0x1,-0x8(%rbp)
L23:
  cmpl   $0x61,-0x8(%rbp)
  jle    L44
  addl   $0x1,-0xc(%rbp)
L40:
  cmpl   $0x62,-0xc(%rbp)
  jle    L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubbleSort(int a[]) {
  int pass, j, hold;
  for (pass = 1; pass <= 99 - 1; pass++) {
    for (j = 0; j <= 99 - 2; j++) {
      if (a[j] > a[j + 1]) {
        hold = a[j];
        a[j] = a[j + 1];
        a[j + 1] = hold;
      }
    }
  }
}
```