ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edx
  add    $0x2cdb,%ax
  test   %dx,%dx
  je     L46
  test   %ax,%ax
  je     L4
  lea    0x0(,%rax,8),%ecx
  and    $0x78,%ecx
  or     %ecx,%eax
  cmp    $0x1,%dx
  je     L46
  cmp    $0x1,%ax
  jne    L12
  mov    $0x9,%eax
  jmp    L102
  nopl   0x0(%rax,%rax,1)
L4:
  cmp    $0x1,%dx
  je     L46
L12:
  lea    0x0(,%rax,8),%ecx
  and    $0x78,%ecx
  or     %ecx,%eax
L102:
  cmp    $0x2,%dx
  jbe    L46
  mov    $0x2,%ecx
L47:
  lea    0x0(,%rax,8),%edi
  cmp    %cx,%ax
  je     L54
  and    $0x78,%edi
  add    $0x1,%ecx
  or     %edi,%eax
  cmp    %cx,%dx
  jne    L47
L46:
  add    %eax,%eax
  mov    %ax,(%rsi)
  ret
  nopl   0x0(%rax)
L54:
  and    $0x38,%edi
  add    $0x1,%ecx
  or     %edi,%eax
  cmp    %dx,%cx
  jne    L47
  jmp    L46
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy12;
  {
    state[0UL] = input[0UL] + (unsigned short)11483;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] == local1) {
        if (state[0UL] < local1) {
          state[local1] = state[0UL] + state[local1];
          state[local1] |= ((state[0UL] - state[local1]) & (unsigned short)31) << 4UL;
        } else {
          state[local1] |= ((state[0UL] + state[0UL]) & (unsigned short)15) << 2UL;
        }
      } else {
        state[0UL] |= (state[local1] & (unsigned short)15) << 3UL;
        copy12 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = copy12;
        copy12 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy12;
      }
      local1++;
    }
    output[0UL] = state[0UL] << (unsigned short)1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L4
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L15
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L15
L4:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  jne    L15
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  movl   $0xffffffff,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st;
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: What is the c source code of the assembly code below:

```asm
<do_mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L8
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  neg    %rax
  sbb    %eax,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L39
  mov    $0x0,%eax
  jmp    L13
L39:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L13
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st;
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_mkdir>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L13
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  neg    %rax
  sbb    %eax,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L48
  xor    %eax,%eax
  jmp    L4
  nopl   0x0(%rax)
L48:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L4
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st;
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<do_mkdir>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L31
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  neg    %rax
  sbb    %eax,%eax
L34:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    0x4(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %eax,%eax
  je     L12
  xor    %eax,%eax
  jmp    L34
  nopl   0x0(%rax)
L12:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L34
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_mkdir(const char *path, mode_t mode) {
  struct stat st;
  int status = 0;
  if (stat(path, &st) != 0) {
    if (mkdir(path, mode) != 0)
      status = -1;
  } else if (!S_ISDIR(st.st_mode)) {
    errno = ENOTDIR;
    status = -1;
  }
  return (status);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_103_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x1c(%rbp),%al
  mov    %al,-0x3(%rbp)
  notb   -0x3(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_103_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | S;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_103_0_1>:
  endbr64
  mov    %edx,%ecx
  or     %esi,%ecx
  not    %ecx
  or     (%rdi),%cl
  xor    %esi,%ecx
  mov    %edx,%eax
  not    %eax
  or     %esi,%eax
  and    %ecx,%eax
  not    %esi
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_103_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | S;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rop3_103_0_1>:
  endbr64
  mov    %edx,%ecx
  mov    %edx,%eax
  or     %esi,%ecx
  not    %eax
  not    %ecx
  or     (%rdi),%cl
  or     %esi,%eax
  xor    %esi,%ecx
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_103_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | S;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rop3_103_0_1>:
  endbr64
  mov    %edx,%ecx
  mov    %edx,%eax
  or     %esi,%ecx
  not    %eax
  not    %ecx
  or     (%rdi),%cl
  or     %esi,%eax
  xor    %esi,%ecx
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_103_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = T | S;
  stk3 = ~stk3;
  stk2 = *D | stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D64(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,-0x38(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D74(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D36(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <print_strings@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D64
type_infered: string
name: unpack_data
arguments: data_label: D42
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D33
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D74
type_infered: string
name: unpack_data
arguments: data_label: D36
type_infered: string
name: unpack_data
arguments: data_label: D2
type_infered: string

tool: D64: Four

tool: D42: score

tool: D4: and

tool: D33: seven

tool: D29: years

tool: D74: ago,

tool: D36: our

tool: D2: forefathers

assistant: ```c
int main(int argc, char *argv[]) {
  char *message[8] = {"Four", "score", "and", "seven", "years", "ago,", "our", "forefathers"};
  print_strings(message, 8);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,(%rsp)
  lea    D12(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D58(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D31(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D65(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D48(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D2(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D40(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <print_strings@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x58,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D58
type_infered: string
name: disassemble_data
arguments: data_tag: D31
type_infered: string
name: disassemble_data
arguments: data_tag: D65
type_infered: string
name: disassemble_data
arguments: data_tag: D48
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D40
type_infered: string

tool: D21: Four

tool: D12: score

tool: D58: and

tool: D31: seven

tool: D65: years

tool: D48: ago,

tool: D2: our

tool: D40: forefathers

assistant: ```c
int main(int argc, char *argv[]) {
  char *message[8] = {"Four", "score", "and", "seven", "years", "ago,", "our", "forefathers"};
  print_strings(message, 8);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  mov    $0x8,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  lea    D77(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  lea    D70(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D25(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D75(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D56(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D45(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x38(%rsp)
  call   <print_strings@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D77
data_type: string
name: read_data
arguments: data_label: D70
data_type: string
name: read_data
arguments: data_label: D25
data_type: string
name: read_data
arguments: data_label: D75
data_type: string
name: read_data
arguments: data_label: D56
data_type: string
name: read_data
arguments: data_label: D29
data_type: string
name: read_data
arguments: data_label: D45
data_type: string
name: read_data
arguments: data_label: D19
data_type: string

tool: D77: Four

tool: D70: score

tool: D25: and

tool: D75: seven

tool: D56: years

tool: D29: ago,

tool: D45: our

tool: D19: forefathers

assistant: ```c
int main(int argc, char *argv[]) {
  char *message[8] = {"Four", "score", "and", "seven", "years", "ago,", "our", "forefathers"};
  print_strings(message, 8);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  lea    D36(%rip),%rdx
  lea    D30(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  lea    D1(%rip),%rax
  movq   %rdx,%xmm0
  lea    D16(%rip),%rsi
  mov    %rsp,%rdi
  lea    D51(%rip),%rdx
  movq   %rax,%xmm1
  lea    D64(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  lea    D78(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   %rcx,%xmm0
  movq   %rax,%xmm3
  lea    D39(%rip),%rax
  punpcklqdq %xmm2,%xmm0
  movq   %rax,%xmm4
  movaps %xmm0,0x10(%rsp)
  movq   %rsi,%xmm0
  mov    $0x8,%esi
  punpcklqdq %xmm3,%xmm0
  movaps %xmm0,0x20(%rsp)
  movq   %rdx,%xmm0
  punpcklqdq %xmm4,%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <print_strings@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D36
type_guessed: string
name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string
name: read_data
arguments: tag: D51
type_guessed: string
name: read_data
arguments: tag: D64
type_guessed: string
name: read_data
arguments: tag: D78
type_guessed: string
name: read_data
arguments: tag: D39
type_guessed: string

tool: D36: Four

tool: D30: and

tool: D1: score

tool: D16: years

tool: D51: our

tool: D64: seven

tool: D78: ago,

tool: D39: forefathers

assistant: ```c
int main(int argc, char *argv[]) {
  char *message[8] = {"Four", "score", "and", "seven", "years", "ago,", "our", "forefathers"};
  print_strings(message, 8);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetTransformBits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jle    L20
  cmpl   $0x4,-0x14(%rbp)
  jle    L36
  mov    $0x4,%eax
  jmp    L19
L36:
  mov    $0x5,%eax
  jmp    L19
L20:
  mov    $0x6,%eax
L19:
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int GetTransformBits(int method, int histo_bits) {
  const int max_transform_bits = (method < 4) ? 6 : (method > 4) ? 4 : 5;
  return (histo_bits > max_transform_bits) ? max_transform_bits : histo_bits;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetTransformBits>:
  endbr64
  mov    $0x6,%eax
  cmp    $0x3,%edi
  jle    L8
  cmp    $0x5,%edi
  setl   %al
  movzbl %al,%eax
  add    $0x4,%eax
L8:
  cmp    %esi,%eax
  cmovg  %esi,%eax
  ret
```

assistant: ```c
int GetTransformBits(int method, int histo_bits) {
  const int max_transform_bits = (method < 4) ? 6 : (method > 4) ? 4 : 5;
  return (histo_bits > max_transform_bits) ? max_transform_bits : histo_bits;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GetTransformBits>:
  endbr64
  mov    $0x6,%eax
  cmp    $0x3,%edi
  jle    L6
  xor    %eax,%eax
  cmp    $0x4,%edi
  sete   %al
  add    $0x4,%eax
L6:
  cmp    %esi,%eax
  cmovg  %esi,%eax
  ret
```

assistant: ```c
int GetTransformBits(int method, int histo_bits) {
  const int max_transform_bits = (method < 4) ? 6 : (method > 4) ? 4 : 5;
  return (histo_bits > max_transform_bits) ? max_transform_bits : histo_bits;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetTransformBits>:
  endbr64
  mov    $0x6,%eax
  cmp    $0x3,%edi
  jle    L5
  xor    %eax,%eax
  cmp    $0x4,%edi
  sete   %al
  add    $0x4,%eax
L5:
  cmp    %esi,%eax
  cmovg  %esi,%eax
  ret
```

assistant: ```c
int GetTransformBits(int method, int histo_bits) {
  const int max_transform_bits = (method < 4) ? 6 : (method > 4) ? 4 : 5;
  return (histo_bits > max_transform_bits) ? max_transform_bits : histo_bits;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<execvp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <watch_log@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <libc_execvp@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: exec %s


assistant: ```c
int execvp(const char *file, char *const *argv) {
  watch_log("exec %s\n", file);
  return libc_execvp(file, argv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<execvp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <watch_log@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <libc_execvp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: exec %s


assistant: ```c
int execvp(const char *file, char *const *argv) {
  watch_log("exec %s\n", file);
  return libc_execvp(file, argv);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<execvp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <watch_log@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <libc_execvp@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: exec %s


assistant: ```c
int execvp(const char *file, char *const *argv) {
  watch_log("exec %s\n", file);
  return libc_execvp(file, argv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<execvp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  sub    $0x8,%rsp
  call   <watch_log@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <libc_execvp@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: exec %s


assistant: ```c
int execvp(const char *file, char *const *argv) {
  watch_log("exec %s\n", file);
  return libc_execvp(file, argv);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_do_step>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movss  %xmm0,-0x2c(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <compute_norm@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L7
  pxor   %xmm0,%xmm0
  ucomiss -0xc(%rbp),%xmm0
  je     L9
L7:
  movq   $0x0,-0x8(%rbp)
  jmp    L30
L12:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  divss  -0xc(%rbp),%xmm1
  mulss  -0x2c(%rbp),%xmm1
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  imul   %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L12
L9:
  nop
  leave
  ret
```

assistant: ```c
void compute_do_step(unsigned w, unsigned h, float *fdata, float *obj_gradient, float step_size) {
  float norm = compute_norm(w, h, obj_gradient);
  if (norm != 0.) {
    for (size_t i = 0; i < (size_t)h * w; i++) {
      fdata[i] = fdata[i] - step_size * (obj_gradient[i] / norm);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compute_do_step>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  movss  %xmm0,0xc(%rsp)
  mov    %rcx,%rdx
  call   <compute_norm@plt>
  ucomiss D4(%rip),%xmm0
  jp     L38
  jne    L38
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  mov    %r12d,%esi
  mov    %r13d,%r13d
  imul   %r13,%rsi
  test   %rsi,%rsi
  je     L13
  mov    $0x0,%eax
L19:
  movss  0x0(%rbp,%rax,4),%xmm1
  divss  %xmm0,%xmm1
  mulss  0xc(%rsp),%xmm1
  movss  (%rbx,%rax,4),%xmm2
  subss  %xmm1,%xmm2
  movss  %xmm2,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L19
  jmp    L13
```

tool_calls: name: parse_data
arguments: label: D4
datatype: f32

tool: D4: 0

assistant: ```c
void compute_do_step(unsigned w, unsigned h, float *fdata, float *obj_gradient, float step_size) {
  float norm = compute_norm(w, h, obj_gradient);
  if (norm != 0.) {
    for (size_t i = 0; i < (size_t)h * w; i++) {
      fdata[i] = fdata[i] - step_size * (obj_gradient[i] / norm);
    }
  }
}
```