ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<zedsDevice>:
  endbr64
  mov    %edx,%r8d
  mov    %rdi,%rcx
  mov    %rsi,%rax
  mov    %r8d,%edi
  lea    0xe(%rdx),%esi
  add    $0x7,%edx
  cmovns %edx,%esi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  lea    (%r8,%rdi,1),%edx
  sar    $0x3,%esi
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L38
  lea    D0(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
L1:
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  lea    0x1(%rcx),%rdi
  movzbl (%rcx),%ecx
  lea    0x1(%rax),%rdx
  mov    %cl,(%rax)
L22:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%r10
  lea    0x1(%rax),%r9
  mov    %dl,(%rax)
L30:
  movzbl (%r10),%eax
  lea    0x1(%r10),%rdi
  lea    0x1(%r9),%rdx
  mov    %al,(%r9)
L24:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  sub    $0x1,%esi
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %esi,%esi
  jg     L1
L38:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L22
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L24
  nopl   0x0(%rax,%rax,1)
  mov    %rax,%r9
  mov    %rcx,%r10
  jmp    L30
```

assistant: ```c
int zedsDevice(char *from, char *to, int count) {
  {
    int n = (count + 7) / 8;
    switch (count % 8) {
    case 0:
    again:
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
      if (--n > 0)
        goto again;
    }
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<zedsDevice>:
  endbr64
  mov    %edx,%r8d
  mov    %rdi,%rcx
  mov    %rsi,%rax
  mov    %r8d,%edi
  lea    0xe(%rdx),%esi
  add    $0x7,%edx
  cmovns %edx,%esi
  sar    $0x1f,%edi
  shr    $0x1d,%edi
  lea    (%r8,%rdi,1),%edx
  sar    $0x3,%esi
  and    $0x7,%edx
  sub    %edi,%edx
  cmp    $0x7,%edx
  ja     L11
  lea    D2(%rip),%rdi
  movslq (%rdi,%rdx,4),%rdx
  add    %rdi,%rdx
  notrack jmp *%rdx
  nopl   (%rax)
L17:
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  movzbl (%rcx),%edx
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %dl,-0x1(%rax)
  lea    0x1(%rcx),%rdi
  movzbl (%rcx),%ecx
  lea    0x1(%rax),%rdx
  mov    %cl,(%rax)
L33:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  lea    0x1(%rcx),%r10
  lea    0x1(%rax),%r9
  mov    %dl,(%rax)
L8:
  movzbl (%r10),%eax
  lea    0x1(%r10),%rdi
  lea    0x1(%r9),%rdx
  mov    %al,(%r9)
L13:
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edi
  lea    0x1(%rdx),%rax
  mov    %dil,(%rdx)
  movzbl (%rcx),%edx
  sub    $0x1,%esi
  add    $0x1,%rcx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  test   %esi,%esi
  jg     L17
L11:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L33
  mov    %rax,%rdx
  mov    %rcx,%rdi
  jmp    L13
  nopl   0x0(%rax,%rax,1)
  mov    %rax,%r9
  mov    %rcx,%r10
  jmp    L8
```

assistant: ```c
int zedsDevice(char *from, char *to, int count) {
  {
    int n = (count + 7) / 8;
    switch (count % 8) {
    case 0:
    again:
      *to++ = *from++;
    case 7:
      *to++ = *from++;
    case 6:
      *to++ = *from++;
    case 5:
      *to++ = *from++;
    case 4:
      *to++ = *from++;
    case 3:
      *to++ = *from++;
    case 2:
      *to++ = *from++;
    case 1:
      *to++ = *from++;
      if (--n > 0)
        goto again;
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<monotonic_decrease>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L24
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L18
  mov    $0x0,%eax
  jmp    L17
L18:
  addl   $0x1,-0x4(%rbp)
L24:
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L12
  mov    $0x1,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int monotonic_decrease(int *ordg, int filenum) {
  int i;
  for (i = 1; i <= filenum - 1; i++)
    if (ordg[i] > ordg[i - 1])
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<monotonic_decrease>:
  endbr64
  cmp    $0x1,%esi
  jle    L28
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L8:
  mov    (%rax),%ecx
  cmp    %ecx,0x4(%rax)
  jg     L22
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L8
  mov    $0x1,%eax
  ret
L28:
  mov    $0x1,%eax
  ret
L22:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int monotonic_decrease(int *ordg, int filenum) {
  int i;
  for (i = 1; i <= filenum - 1; i++)
    if (ordg[i] > ordg[i - 1])
      return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<monotonic_decrease>:
  endbr64
  cmp    $0x1,%esi
  jle    L1
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L1
L25:
  mov    (%rdi),%edx
  cmp    %edx,0x4(%rdi)
  jle    L15
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int monotonic_decrease(int *ordg, int filenum) {
  int i;
  for (i = 1; i <= filenum - 1; i++)
    if (ordg[i] > ordg[i - 1])
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<monotonic_decrease>:
  endbr64
  cmp    $0x1,%esi
  jle    L34
  lea    -0x2(%rsi),%ecx
  mov    (%rdi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rcx,4),%rsi
  jmp    L31
  nopl   0x0(%rax)
L32:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L34
L31:
  mov    %edx,%ecx
  mov    (%rax),%edx
  cmp    %ecx,%edx
  jle    L32
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L34:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int monotonic_decrease(int *ordg, int filenum) {
  int i;
  for (i = 1; i <= filenum - 1; i++)
    if (ordg[i] > ordg[i - 1])
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<vrna_hamming_distance_bound>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L26
  addl   $0x1,-0x4(%rbp)
L26:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  subl   $0x1,-0x24(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  cmpl   $0x0,-0x24(%rbp)
  jne    L25
L28:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int vrna_hamming_distance_bound(const char *s1, const char *s2, int boundary) {
  int h = 0;
  for (; *s1 && *s2 && boundary; s1++, s2++, boundary--)
    if (*s1 != *s2)
      h++;
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<vrna_hamming_distance_bound>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L29
  movzbl (%rsi),%r8d
  test   %edx,%edx
  je     L4
  test   %r8b,%r8b
  je     L4
  mov    $0x1,%eax
  mov    $0x0,%r9d
L10:
  cmp    %r8b,%cl
  setne  %cl
  movzbl %cl,%ecx
  add    %ecx,%r9d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L9
  movzbl (%rsi,%rax,1),%r8d
  cmp    %eax,%edx
  setne  %r11b
  test   %r8b,%r8b
  setne  %r10b
  add    $0x1,%rax
  test   %r10b,%r11b
  jne    L10
L9:
  mov    %r9d,%eax
  ret
L29:
  mov    $0x0,%r9d
  jmp    L9
L4:
  mov    $0x0,%r9d
  jmp    L9
```

assistant: ```c
int vrna_hamming_distance_bound(const char *s1, const char *s2, int boundary) {
  int h = 0;
  for (; *s1 && *s2 && boundary; s1++, s2++, boundary--)
    if (*s1 != *s2)
      h++;
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<vrna_hamming_distance_bound>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L5
  movzbl (%rsi),%r8d
  test   %edx,%edx
  je     L5
  test   %r8b,%r8b
  je     L5
  mov    $0x1,%eax
  xor    %r9d,%r9d
L31:
  cmp    %r8b,%cl
  setne  %cl
  movzbl %cl,%ecx
  add    %ecx,%r9d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L47
  movzbl (%rsi,%rax,1),%r8d
  cmp    %eax,%edx
  setne  %r11b
  test   %r8b,%r8b
  setne  %r10b
  add    $0x1,%rax
  test   %r10b,%r11b
  jne    L31
L47:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int vrna_hamming_distance_bound(const char *s1, const char *s2, int boundary) {
  int h = 0;
  for (; *s1 && *s2 && boundary; s1++, s2++, boundary--)
    if (*s1 != *s2)
      h++;
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vrna_hamming_distance_bound>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L42
  movzbl (%rsi),%r8d
  test   %edx,%edx
  je     L42
  test   %r8b,%r8b
  je     L42
  mov    $0x1,%eax
  xor    %r9d,%r9d
L12:
  cmp    %r8b,%cl
  setne  %cl
  movzbl %cl,%ecx
  add    %ecx,%r9d
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L18
  movzbl (%rsi,%rax,1),%r8d
  cmp    %eax,%edx
  setne  %r11b
  test   %r8b,%r8b
  setne  %r10b
  add    $0x1,%rax
  test   %r10b,%r11b
  jne    L12
L18:
  mov    %r9d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int vrna_hamming_distance_bound(const char *s1, const char *s2, int boundary) {
  int h = 0;
  for (; *s1 && *s2 && boundary; s1++, s2++, boundary--)
    if (*s1 != *s2)
      h++;
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L2
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L2:
  nop
  leave
  ret
```

assistant: ```c
void strip(char *s) {
  int pos = strlen(s) - 1;
  if (s[pos] == '\n')
    s[pos] = '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<strip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L17
L7:
  pop    %rbx
  ret
L17:
  movb   $0x0,(%rbx)
  jmp    L7
```

assistant: ```c
void strip(char *s) {
  int pos = strlen(s) - 1;
  if (s[pos] == '\n')
    s[pos] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L1
  pop    %rbx
  ret
  nopl   0x0(%rax)
L1:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void strip(char *s) {
  int pos = strlen(s) - 1;
  if (s[pos] == '\n')
    s[pos] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,%rbx
  cmpb   $0xa,(%rbx)
  je     L5
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void strip(char *s) {
  int pos = strlen(s) - 1;
  if (s[pos] == '\n')
    s[pos] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string

tool: D2: Out of memory

assistant: ```c
char *xstrdup(const char *str) {
  char *s = strdup(str);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
L2:
  lea    D5(%rip),%rdi
  call   <fatal@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: Out of memory

assistant: ```c
char *xstrdup(const char *str) {
  char *s = strdup(str);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
L11:
  mov    %r12,%rax
  pop    %r12
  ret
L19:
  lea    D1(%rip),%rdi
  call   <fatal@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: Out of memory

assistant: ```c
char *xstrdup(const char *str) {
  char *s = strdup(str);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
L19:
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  lea    D7(%rip),%rdi
  call   <fatal@plt>
  jmp    L19
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: Out of memory

assistant: ```c
char *xstrdup(const char *str) {
  char *s = strdup(str);
  if (NULL == s)
    fatal("Out of memory");
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<svz_file_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L46
  mov    $0x0,%eax
  jmp    L20
L46:
  cmpq   $0x0,-0x28(%rbp)
  je     L28
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rbx
  jmp    L24
L28:
  mov    $0x0,%ebx
L24:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <svz_malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L71
  lea    D24(%rip),%rdx
  jmp    L6
L71:
  lea    D17(%rip),%rdx
L6:
  cmpq   $0x0,-0x28(%rbp)
  je     L55
  mov    -0x28(%rbp),%rax
  jmp    L41
L55:
  lea    D17(%rip),%rax
L41:
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rdi
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D24
type_guessed: string
name: unpack_data
arguments: data_label: D17
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D24: /

tool: 

tool: D3: %s%s%s

assistant: ```c
char *svz_file_path(char *path, char *file) {
  char *full;
  if (file == NULL)
    return NULL;
  full = svz_malloc((path ? strlen(path) + 1 : 0) + strlen(file) + 1);
  sprintf(full, "%s%s%s", path ? path : "", path ? "/" : "", file);
  return full;
}
```
user: Translate the below assembly code into C programming language:

```asm
<svz_file_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L30
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L19
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x2(%r12,%rax,1),%rdi
  call   <svz_malloc@plt>
  mov    %rax,%r12
  lea    D11(%rip),%rcx
L0:
  mov    %rbx,%r8
  mov    %rbp,%rdx
  lea    D6(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
L29:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  mov    %rsi,%r12
  jmp    L29
L19:
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <svz_malloc@plt>
  mov    %rax,%r12
  lea    D28(%rip),%rcx
  mov    %rcx,%rbp
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D6
type_infered: string
name: parse_data
arguments: data_label: D28
type_infered: string

tool: D11: /

tool: D6: %s%s%s

tool: 

assistant: ```c
char *svz_file_path(char *path, char *file) {
  char *full;
  if (file == NULL)
    return NULL;
  full = svz_malloc((path ? strlen(path) + 1 : 0) + strlen(file) + 1);
  sprintf(full, "%s%s%s", path ? path : "", path ? "/" : "", file);
  return full;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<svz_file_path>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  test   %rsi,%rsi
  je     L17
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rax,%r13
  test   %r12,%r12
  je     L38
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%r13,%rax,1),%rdi
  call   <svz_malloc@plt>
  lea    D13(%rip),%rcx
  mov    %rax,%r13
L11:
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D2(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
L25:
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L38:
  lea    0x1(%rax),%rdi
  call   <svz_malloc@plt>
  lea    D9(%rip),%rcx
  mov    %rax,%r13
  mov    %rcx,%r12
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %r13d,%r13d
  jmp    L25
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D2
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string

tool: D13: /

tool: D2: %s%s%s

tool: 

assistant: ```c
char *svz_file_path(char *path, char *file) {
  char *full;
  if (file == NULL)
    return NULL;
  full = svz_malloc((path ? strlen(path) + 1 : 0) + strlen(file) + 1);
  sprintf(full, "%s%s%s", path ? path : "", path ? "/" : "", file);
  return full;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<svz_file_path>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  test   %rsi,%rsi
  je     L1
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rax,%r13
  test   %r12,%r12
  je     L17
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%r13,%rax,1),%rdi
  call   <svz_malloc@plt>
  lea    D2(%rip),%rcx
  mov    %rax,%r13
L22:
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D4(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
L33:
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L17:
  lea    0x1(%rax),%rdi
  call   <svz_malloc@plt>
  lea    D17(%rip),%rcx
  mov    %rax,%r13
  mov    %rcx,%r12
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r13d,%r13d
  jmp    L33
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string

tool: D2: /

tool: D4: %s%s%s

tool: 

assistant: ```c
char *svz_file_path(char *path, char *file) {
  char *full;
  if (file == NULL)
    return NULL;
  full = svz_malloc((path ? strlen(path) + 1 : 0) + strlen(file) + 1);
  sprintf(full, "%s%s%s", path ? path : "", path ? "/" : "", file);
  return full;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stpcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L3:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *stpcpy(char *dest, const char *src) {
  unsigned i = 0;
  for (; src[i]; ++i)
    dest[i] = src[i];
  dest[i] = 0;
  return dest + i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stpcpy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L14
  mov    $0x0,%r8d
  mov    $0x0,%ecx
L6:
  mov    %dl,(%rdi,%rcx,1)
  add    $0x1,%r8d
  mov    %r8d,%ecx
  movzbl (%rsi,%rcx,1),%edx
  test   %dl,%dl
  jne    L6
L15:
  lea    (%rdi,%rcx,1),%rax
  movb   $0x0,(%rax)
  ret
L14:
  mov    $0x0,%ecx
  jmp    L15
```

assistant: ```c
char *stpcpy(char *dest, const char *src) {
  unsigned i = 0;
  for (; src[i]; ++i)
    dest[i] = src[i];
  dest[i] = 0;
  return dest + i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stpcpy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L17
  xor    %r8d,%r8d
  xor    %ecx,%ecx
L1:
  mov    %dl,(%rdi,%rcx,1)
  lea    0x1(%r8),%ecx
  movzbl (%rsi,%rcx,1),%edx
  mov    %rcx,%r8
  test   %dl,%dl
  jne    L1
  lea    (%rdi,%rcx,1),%rax
  movb   $0x0,(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rdi,%rax
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *stpcpy(char *dest, const char *src) {
  unsigned i = 0;
  for (; src[i]; ++i)
    dest[i] = src[i];
  dest[i] = 0;
  return dest + i;
}
```
user: What is the c source code of the assembly code below?

```asm
<stpcpy>:
  endbr64
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L14
  xor    %r8d,%r8d
  xor    %ecx,%ecx
L8:
  mov    %dl,(%rdi,%rcx,1)
  lea    0x1(%r8),%ecx
  movzbl (%rsi,%rcx,1),%edx
  mov    %rcx,%r8
  test   %dl,%dl
  jne    L8
  lea    (%rdi,%rcx,1),%rax
  movb   $0x0,(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rdi,%rax
  movb   $0x0,(%rax)
  ret
```

assistant: ```c
char *stpcpy(char *dest, const char *src) {
  unsigned i = 0;
  for (; src[i]; ++i)
    dest[i] = src[i];
  dest[i] = 0;
  return dest + i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <arg_ok@plt>
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  jmp    L20
L10:
  movl   $0x0,-0xc(%rbp)
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L35
L19:
  mov    $0x48,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,(%rax)
L35:
  cmpl   $0x8,-0xc(%rbp)
  jle    L19
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <ft_extract@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <base_ok@plt>
  test   %eax,%eax
  jne    L77
  mov    $0x0,%eax
  jmp    L20
L77:
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ft_resolve@plt>
  test   %rax,%rax
  je     L48
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_printsudoku@plt>
  jmp    L18
L48:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
L18:
  mov    $0x0,%eax
L20:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string

tool: D2: Erreur


assistant: ```c
int main(int ac, char **av) {
  int i;
  int **tab;
  if (!arg_ok(ac, av))
    return (0);
  i = 0;
  tab = (int **)malloc(sizeof(int **) * 9);
  while (i < 9)
    tab[i++] = (int *)malloc(sizeof(int *) * 9);
  tab = ft_extract(av + 1);
  if (!base_ok(tab))
    return (0);
  if (ft_resolve(tab, 0))
    ft_printsudoku(tab);
  else
    ft_putstr("Erreur\n");
  return (0);
}
```