ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  lea    0xc(%rsp),%rsi
  lea    D30(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strrep@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xc8,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D30
data_type: string
name: unpack_data
arguments: tag: D0
data_type: string

tool: D16: 
Please input original string:

tool: D12: 
Please input substitute string:

tool: D30: %d

tool: D0: 
The final string:%s


assistant: ```c
void main() {
  char string1[100];
  char string2[50];
  int position;
  printf("\nPlease input original string:");
  gets(string1);
  printf("\nPlease input substitute string:");
  gets(string2);
  scanf("%d", &position);
  strrep(string1, string2, position);
  printf("\nThe final string:%s\n", string1);
  getch();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D18(%rip),%rdi
  push   %rbp
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  lea    0x10(%rsp),%r12
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <gets@plt>
  lea    0xc(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strrep@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xc8,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D34
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string

tool: D18: 
Please input original string:

tool: D10: 
Please input substitute string:

tool: D34: %d

tool: D27: 
The final string:%s


assistant: ```c
void main() {
  char string1[100];
  char string2[50];
  int position;
  printf("\nPlease input original string:");
  gets(string1);
  printf("\nPlease input substitute string:");
  gets(string2);
  scanf("%d", &position);
  strrep(string1, string2, position);
  printf("\nThe final string:%s\n", string1);
  getch();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__wrap_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__real_free@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type: string

tool: D0: free: %p


assistant: ```c
void __wrap_free(void *ptr) {
  printf("free: %p\n", ptr);
  __real_free(ptr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__wrap_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <__real_free@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D3: free: %p


assistant: ```c
void __wrap_free(void *ptr) {
  printf("free: %p\n", ptr);
  __real_free(ptr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__wrap_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <__real_free@plt>
```

tool_calls: name: read_data
arguments: tag: D0
datatype: string

tool: D0: free: %p


assistant: ```c
void __wrap_free(void *ptr) {
  printf("free: %p\n", ptr);
  __real_free(ptr);
}
```
user: What is the c source code of the assembly code below?

```asm
<__wrap_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <__real_free@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: free: %p


assistant: ```c
void __wrap_free(void *ptr) {
  printf("free: %p\n", ptr);
  __real_free(ptr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<next_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L16
L2:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L5
  mov    -0x8(%rbp),%rax
  jmp    L24
L5:
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L2
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
long next_prime(long n, long N) {
  for (long i = n + 1; (i < N); i++)
    if (is_prime(i))
      return (i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<next_prime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  lea    0x1(%rdi),%rbx
  cmp    %rsi,%rbx
  jge    L5
L38:
  mov    %rbx,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  jne    L31
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L38
  mov    %rax,%rbx
L31:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x0,%ebx
  jmp    L31
```

assistant: ```c
long next_prime(long n, long N) {
  for (long i = n + 1; (i < N); i++)
    if (is_prime(i))
      return (i);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<next_prime>:
  endbr64
  push   %r12
  lea    0x1(%rdi),%r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rsi,%r12
  jge    L28
  mov    %rsi,%rbx
  jmp    L33
  nopl   0x0(%rax)
L17:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L28
L33:
  mov    %r12,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L17
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L28:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
long next_prime(long n, long N) {
  for (long i = n + 1; (i < N); i++)
    if (is_prime(i))
      return (i);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<next_prime>:
  endbr64
  push   %r12
  lea    0x1(%rdi),%r12
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rsi,%r12
  jge    L34
  mov    %rsi,%rbx
  jmp    L5
  nopl   0x0(%rax)
L32:
  add    $0x1,%r12
  cmp    %r12,%rbx
  je     L34
L5:
  mov    %r12,%rdi
  call   <is_prime@plt>
  test   %rax,%rax
  je     L32
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax)
L34:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
long next_prime(long n, long N) {
  for (long i = n + 1; (i < N); i++)
    if (is_prime(i))
      return (i);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<arr_mean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L10
L24:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L24
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  js     L38
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L32
L38:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L32:
  movsd  -0x10(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double arr_mean(double x[], size_t N) {
  double sum = 0.0;
  double mean;
  for (int i = 0; i < N; ++i) {
    sum += x[i];
  }
  mean = (double)sum / N;
  return mean;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arr_mean>:
  endbr64
  test   %rsi,%rsi
  je     L16
  mov    %rdi,%rax
  lea    (%rdi,%rsi,8),%rdx
  pxor   %xmm0,%xmm0
L27:
  addsd  (%rax),%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L27
L49:
  test   %rsi,%rsi
  js     L44
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
L21:
  divsd  %xmm1,%xmm0
  ret
L16:
  pxor   %xmm0,%xmm0
  jmp    L49
L44:
  mov    %rsi,%rax
  shr    %rax
  and    $0x1,%esi
  or     %rsi,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  addsd  %xmm1,%xmm1
  jmp    L21
```

assistant: ```c
double arr_mean(double x[], size_t N) {
  double sum = 0.0;
  double mean;
  for (int i = 0; i < N; ++i) {
    sum += x[i];
  }
  mean = (double)sum / N;
  return mean;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arr_mean>:
  endbr64
  test   %rsi,%rsi
  je     L10
  lea    (%rdi,%rsi,8),%rax
  pxor   %xmm0,%xmm0
  nopl   0x0(%rax)
L2:
  addsd  (%rdi),%xmm0
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L2
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double arr_mean(double x[], size_t N) {
  double sum = 0.0;
  double mean;
  for (int i = 0; i < N; ++i) {
    sum += x[i];
  }
  mean = (double)sum / N;
  return mean;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arr_mean>:
  endbr64
  test   %rsi,%rsi
  je     L46
  cmp    $0x1,%rsi
  je     L41
  mov    %rsi,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L12:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L12
  mov    %rsi,%rax
  and    $0xfffffffffffffffe,%rax
  test   $0x1,%sil
  je     L44
L38:
  addsd  (%rdi,%rax,8),%xmm0
L44:
  pxor   %xmm1,%xmm1
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L41:
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  jmp    L38
```

assistant: ```c
double arr_mean(double x[], size_t N) {
  double sum = 0.0;
  double mean;
  for (int i = 0; i < N; ++i) {
    sum += x[i];
  }
  mean = (double)sum / N;
  return mean;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<triangle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  movss  -0x4(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  D5(%rip),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  lea    (%rax,%rax,1),%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type: byte[4]

tool: {"D5": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float triangle(float x) {
  x -= floor(x);
  return 1 - 2 * fabs(x - .5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<triangle>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  movss  0xc(%rsp),%xmm0
  subss  %xmm1,%xmm0
  subss  D1(%rip),%xmm0
  call   <fabs@plt>
  add    %eax,%eax
  mov    $0x1,%edx
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float triangle(float x) {
  x -= floor(x);
  return 1 - 2 * fabs(x - .5);
}
```
user: What is the c source code of the assembly code below:

```asm
<triangle>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  subss  %xmm1,%xmm0
  subss  D2(%rip),%xmm0
  call   <fabs@plt>
  mov    $0x1,%edx
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  add    %eax,%eax
  sub    %eax,%edx
  cvtsi2ss %edx,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float triangle(float x) {
  x -= floor(x);
  return 1 - 2 * fabs(x - .5);
}
```
user: What is the c source code of the assembly code below?

```asm
<triangle>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <floor@plt>
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  cvtsi2ss %rax,%xmm1
  subss  %xmm1,%xmm0
  subss  D4(%rip),%xmm0
  call   <fabs@plt>
  mov    $0x1,%edx
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  add    %eax,%eax
  sub    %eax,%edx
  cvtsi2ss %edx,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float triangle(float x) {
  x -= floor(x);
  return 1 - 2 * fabs(x - .5);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cc_str_concatenate_char_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,%eax
  mov    %al,-0x3c(%rbp)
  cmpq   $0x0,-0x38(%rbp)
  jne    L20
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L44
  mov    $0x0,%eax
  jmp    L40
L44:
  mov    -0x8(%rbp),%rax
  movzbl -0x3c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L40
L20:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <cc_str_len@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L60
  mov    $0x0,%eax
  jmp    L40
L60:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L57
L37:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x20(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L57:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L37
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl -0x3c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
L40:
  leave
  ret
```

assistant: ```c
char *cc_str_concatenate_char_new(char const *const restrict str, char const chr) {
  if (!str) {
    char *new = (char *)malloc(2);
    if (!new)
      return NULL;
    *new = chr;
    *(new + 1) = '\0';
    return new;
  }
  size_t len = cc_str_len(str) + 1;
  char *new = (char *)malloc(len + 1);
  if (!new)
    return NULL;
  char const *s = str;
  char *n = new;
  while (*s)
    *n++ = *s++;
  *n++ = chr;
  *n = '\0';
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cc_str_concatenate_char_new>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %rdi,%rdi
  je     L56
  call   <cc_str_len@plt>
  movslq %eax,%rdi
  add    $0x2,%rdi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L8
  movzbl (%rbx),%ecx
  test   %cl,%cl
  je     L60
  mov    %rax,%rdx
  sub    %rax,%rbx
  mov    %rbx,%rsi
L13:
  mov    %rdx,%rax
  add    $0x1,%rdx
  mov    %cl,(%rax)
  movzbl (%rdx,%rsi,1),%ecx
  test   %cl,%cl
  jne    L13
L28:
  mov    %bpl,(%rdx)
  movb   $0x0,0x1(%rdx)
L10:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L56:
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  test   %rax,%rax
  je     L10
  mov    %rax,%rdi
  mov    %bpl,(%rax)
  movb   $0x0,0x1(%rax)
  jmp    L10
L60:
  mov    %rax,%rdx
  jmp    L28
L8:
  mov    $0x0,%edi
  jmp    L10
```

assistant: ```c
char *cc_str_concatenate_char_new(char const *const restrict str, char const chr) {
  if (!str) {
    char *new = (char *)malloc(2);
    if (!new)
      return NULL;
    *new = chr;
    *(new + 1) = '\0';
    return new;
  }
  size_t len = cc_str_len(str) + 1;
  char *new = (char *)malloc(len + 1);
  if (!new)
    return NULL;
  char const *s = str;
  char *n = new;
  while (*s)
    *n++ = *s++;
  *n++ = chr;
  *n = '\0';
  return new;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cc_str_concatenate_char_new>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L2
  mov    %rdi,%rbx
  call   <cc_str_len@plt>
  movslq %eax,%rdi
  add    $0x2,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L30
  movzbl (%rbx),%ecx
  mov    %rax,%rdx
  test   %cl,%cl
  je     L48
  sub    %rax,%rbx
  mov    %rbx,%rdi
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rdx,%rsi
  add    $0x1,%rdx
  mov    %cl,(%rsi)
  movzbl (%rdx,%rdi,1),%ecx
  test   %cl,%cl
  jne    L7
L48:
  mov    %bpl,(%rdx)
  movb   $0x0,0x1(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L2:
  mov    $0x2,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L30
  mov    %bpl,(%rax)
  movb   $0x0,0x1(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L30:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *cc_str_concatenate_char_new(char const *const restrict str, char const chr) {
  if (!str) {
    char *new = (char *)malloc(2);
    if (!new)
      return NULL;
    *new = chr;
    *(new + 1) = '\0';
    return new;
  }
  size_t len = cc_str_len(str) + 1;
  char *new = (char *)malloc(len + 1);
  if (!new)
    return NULL;
  char const *s = str;
  char *n = new;
  while (*s)
    *n++ = *s++;
  *n++ = chr;
  *n = '\0';
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cc_str_concatenate_char_new>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L48
  mov    %rdi,%rbx
  call   <cc_str_len@plt>
  movslq %eax,%rdi
  add    $0x2,%rdi
  call   <malloc@plt>
  test   %rax,%rax
  je     L36
  movzbl (%rbx),%ecx
  mov    %rax,%rdx
  test   %cl,%cl
  je     L26
  sub    %rax,%rbx
  mov    %rbx,%rdi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rdx,%rsi
  add    $0x1,%rdx
  mov    %cl,(%rsi)
  movzbl (%rdx,%rdi,1),%ecx
  test   %cl,%cl
  jne    L8
L26:
  mov    %bpl,(%rdx)
  movb   $0x0,0x1(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L48:
  mov    $0x2,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L36
  mov    %bpl,(%rax)
  movb   $0x0,0x1(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *cc_str_concatenate_char_new(char const *const restrict str, char const chr) {
  if (!str) {
    char *new = (char *)malloc(2);
    if (!new)
      return NULL;
    *new = chr;
    *(new + 1) = '\0';
    return new;
  }
  size_t len = cc_str_len(str) + 1;
  char *new = (char *)malloc(len + 1);
  if (!new)
    return NULL;
  char const *s = str;
  char *n = new;
  while (*s)
    *n++ = *s++;
  *n++ = chr;
  *n = '\0';
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getTensYear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  jmp    L0
L3:
  subl   $0x64,-0x4(%rbp)
L0:
  cmpl   $0x63,-0x4(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t getTensYear(int year) {
  while (year >= 100) {
    year -= 100;
  }
  return year;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getTensYear>:
  endbr64
  mov    %edi,%eax
  cmp    $0x63,%edi
  jle    L16
L10:
  sub    $0x64,%eax
  cmp    $0x63,%eax
  jg     L10
L16:
  ret
```

assistant: ```c
uint64_t getTensYear(int year) {
  while (year >= 100) {
    year -= 100;
  }
  return year;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getTensYear>:
  endbr64
  mov    %edi,%eax
  cmp    $0x63,%edi
  jle    L14
  nopl   0x0(%rax,%rax,1)
L12:
  sub    $0x64,%eax
  cmp    $0x63,%eax
  jg     L12
L14:
  ret
```

assistant: ```c
uint64_t getTensYear(int year) {
  while (year >= 100) {
    year -= 100;
  }
  return year;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getTensYear>:
  endbr64
  cmp    $0x63,%edi
  jle    L1
  lea    -0x64(%rdi),%edx
  mov    %rdx,%rax
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x25,%rdx
  add    $0x1,%edx
  cmp    $0x12b,%eax
  jbe    L30
  movd   %edi,%xmm4
  mov    %edx,%ecx
  movdqa D0(%rip),%xmm3
  xor    %eax,%eax
  pshufd $0x0,%xmm4,%xmm1
  movdqa D25(%rip),%xmm2
  paddd  D20(%rip),%xmm1
  shr    $0x2,%ecx
L32:
  movdqa %xmm1,%xmm0
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %ecx,%eax
  jne    L32
  mov    %edx,%ecx
  pshufd $0xff,%xmm0,%xmm0
  and    $0xfffffffc,%ecx
  movd   %xmm0,%eax
  imul   $0xffffff9c,%ecx,%esi
  add    %esi,%edi
  cmp    %ecx,%edx
  je     L18
  lea    -0x64(%rdi),%eax
L30:
  cmp    $0x63,%eax
  jle    L18
  lea    -0xc8(%rdi),%eax
  sub    $0x12c,%edi
  cmp    $0x63,%eax
  cmovg  %edi,%eax
  ret
  nopl   (%rax)
L1:
  mov    %edi,%eax
L18:
  ret
```

tool_calls: name: read_data
arguments: label: D0
datatype: byte[16]
name: read_data
arguments: label: D25
datatype: byte[16]
name: read_data
arguments: label: D20
datatype: byte[16]

tool: {"D0": [0x70,0xfe,0xff,0xff,0x70,0xfe,0xff,0xff,0x70,0xfe,0xff,0xff,0x70,0xfe,0xff,0xff]}

tool: {"D25": [0x9c,0xff,0xff,0xff,0x9c,0xff,0xff,0xff,0x9c,0xff,0xff,0xff,0x9c,0xff,0xff,0xff]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x9c,0xff,0xff,0xff,0x38,0xff,0xff,0xff,0xd4,0xfe,0xff,0xff]}

assistant: ```c
uint64_t getTensYear(int year) {
  while (year >= 100) {
    year -= 100;
  }
  return year;
}
```