user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x5,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rbp),%r13
  mov    %rbp,%rbx
  lea    D52(%rip),%r14
L3:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L3
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movss  0x0(%rbp),%xmm0
  lea    0x4(%rbp),%rax
  movaps %xmm0,%xmm1
  movaps %xmm0,%xmm2
L22:
  minss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  cmp    %r13,%rax
  je     L24
  movss  (%rax),%xmm2
  movaps %xmm2,%xmm3
  maxss  %xmm0,%xmm3
  movaps %xmm3,%xmm0
  add    $0x4,%rax
  jmp    L22
L24:
  cvtss2sd %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  lea    D61(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rbp,%rax
  pxor   %xmm0,%xmm0
L35:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %r13,%rax
  jne    L35
  divss  D4(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D69(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    0x10(%rbp),%rax
  mov    %r12,%rdx
L25:
  movss  (%rax),%xmm0
  movss  %xmm0,(%rdx)
  mov    %rax,%rcx
  sub    $0x4,%rax
  add    $0x4,%rdx
  cmp    %rbp,%rcx
  jne    L25
  lea    D2(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D79(%rip),%r13
L2:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp,%rbx,1),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%r12,%rbx,1),%xmm1
  mov    %r13,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    $0x14,%rbx
  jne    L2
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D35
type: string
name: disassemble_data
arguments: label: D52
type: string
name: disassemble_data
arguments: label: D22
type: string
name: disassemble_data
arguments: label: D61
type: string
name: disassemble_data
arguments: label: D4
type: byte[4]
name: disassemble_data
arguments: label: D69
type: string
name: disassemble_data
arguments: label: D2
type: string
name: disassemble_data
arguments: label: D79
type: string

tool: D35: Please enter %d elements for arr1:


tool: D52: %f

tool: D22: [Press Enter]

tool: D61: Highest: %f
Lowest: %f
[Press Enter]

tool: {"D4": [0x00,0x00,0xa0,0x40]}

tool: D69: Average: %f
[Press Enter]

tool: D2: Arr1: 	Arr2: 

tool: D79: %f		%f


assistant: ```c
int main() {
  float *arr1, *arr2, hi, low, tally;
  int i;
  arr1 = (float *)malloc(5 * sizeof(float));
  arr2 = (float *)malloc(5 * sizeof(float));
  printf("Please enter %d elements for arr1:\n", 5);
  for (i = 0; i < 5; i++) {
    scanf("%f", arr1 + i);
    getchar();
  }
  printf("[Press Enter]");
  getchar();
  hi = *arr1;
  low = *arr1;
  for (i = 0; i < 5; i++) {
    if (hi < *(arr1 + i)) {
      hi = *(arr1 + i);
    }
    if (low > *(arr1 + i)) {
      low = *(arr1 + i);
    }
  }
  printf("Highest: %f\nLowest: %f\n[Press Enter]", hi, low);
  getchar();
  tally = 0;
  for (i = 0; i < 5; i++) {
    tally += *(arr1 + i);
  }
  printf("Average: %f\n[Press Enter]", tally / 5);
  getchar();
  for (i = 0; i < 5; i++) {
    *(arr2 + i) = *(arr1 + 5 - i - 1);
  }
  printf("Arr1: \tArr2: \n");
  for (i = 0; i < 5; i++) {
    printf("%f\t\t%f\n", *(arr1 + i), *(arr2 + i));
  }
  printf("[Press Enter]");
  getchar();
  free(arr1);
  free(arr2);
  return 0;
}
```