ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<parse_repo_owner>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  test   %rdi,%rdi
  je     L86
  cmpb   $0x0,(%rdi)
  je     L86
  mov    %rsi,%r13
  call   <strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L86
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L88
  sub    %rbp,%r12
  mov    %r12d,%edx
  test   %r12d,%r12d
  je     L40
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <substr@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L40:
  mov    %rbp,%rdi
  call   <free@plt>
L86:
  xor    %r12d,%r12d
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L88:
  test   %r13,%r13
  je     L14
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L14
  cmpb   $0x40,0x0(%rbp)
  jne    L26
L14:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
  jmp    L14
```

assistant: ```c
char *parse_repo_owner(const char *slug, const char *fallback) {
  char *copy = NULL;
  char *owner = NULL;
  if (NULL == slug)
    return NULL;
  if (0 == strlen(slug))
    return NULL;
  if (!(copy = strdup(slug)))
    return NULL;
  if ((owner = strchr(copy, '/'))) {
    int delta = owner - copy;
    if (!delta) {
      free(copy);
      return NULL;
    }
    char *tmp = substr(copy, 0, delta);
    free(copy);
    return tmp;
  }
  if (fallback && 0 < strlen(copy) && '@' != copy[0]) {
    owner = strdup(fallback);
  }
  free(copy);
  return owner;
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L31
  mov    $0x0,%eax
  jmp    L11
L31:
  cmpl   $0x1,-0x8(%rbp)
  jne    L42
  mov    -0x4(%rbp),%eax
  jmp    L11
L42:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L49
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply>
  add    %eax,%eax
  jmp    L11
L49:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <multiply>
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
L11:
  leave
  ret
```

assistant: ```c
int multiply(int a, int b) {
  if (b == 0)
    return 0;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return 2 * multiply(a, b / 2);
  else
    return 2 * multiply(a, b / 2) + a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  je     L15
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    $0x1,%esi
  je     L19
  test   $0x1,%sil
  jne    L34
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  sar    %esi
  call   <multiply>
  add    %eax,%eax
L19:
  pop    %rbx
  ret
L34:
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  sar    %esi
  call   <multiply>
  lea    (%rbx,%rax,2),%eax
  jmp    L19
L15:
  ret
```

assistant: ```c
int multiply(int a, int b) {
  if (b == 0)
    return 0;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return 2 * multiply(a, b / 2);
  else
    return 2 * multiply(a, b / 2) + a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<multiply>:
  endbr64
  test   %esi,%esi
  je     L39
  cmp    $0x1,%esi
  je     L55
  mov    $0x1,%edx
  xor    %r9d,%r9d
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L45:
  cmp    $0x1,%eax
  je     L50
L36:
  mov    %esi,%eax
  mov    %esi,%r8d
  mov    %edx,%ecx
  add    %edx,%edx
  shr    $0x1f,%eax
  and    $0x1,%r8d
  add    %esi,%eax
  sar    %eax
  mov    %eax,%esi
  test   %r8d,%r8d
  je     L18
  imul   %edi,%ecx
  add    %ecx,%r9d
L18:
  test   %eax,%eax
  jne    L45
L16:
  mov    %r9d,%eax
  ret
  xchg   %ax,%ax
L50:
  imul   %edx,%edi
  add    %edi,%r9d
  mov    %r9d,%eax
  ret
L39:
  xor    %r9d,%r9d
  jmp    L16
L55:
  mov    %edi,%r9d
  jmp    L16
```

assistant: ```c
int multiply(int a, int b) {
  if (b == 0)
    return 0;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return 2 * multiply(a, b / 2);
  else
    return 2 * multiply(a, b / 2) + a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<multiply>:
  endbr64
  test   %esi,%esi
  je     L0
  cmp    $0x1,%esi
  je     L70
  mov    $0x1,%edx
  xor    %r9d,%r9d
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L59:
  cmp    $0x1,%eax
  je     L3
L78:
  mov    %esi,%eax
  mov    %esi,%r8d
  mov    %edx,%ecx
  add    %edx,%edx
  shr    $0x1f,%eax
  and    $0x1,%r8d
  add    %esi,%eax
  sar    %eax
  mov    %eax,%esi
  test   %r8d,%r8d
  je     L31
  imul   %edi,%ecx
  add    %ecx,%r9d
L31:
  test   %eax,%eax
  jne    L59
L43:
  mov    %r9d,%eax
  ret
  xchg   %ax,%ax
L3:
  imul   %edx,%edi
  add    %edi,%r9d
  mov    %r9d,%eax
  ret
L0:
  xor    %r9d,%r9d
  jmp    L43
L70:
  mov    %edi,%r9d
  jmp    L43
```

assistant: ```c
int multiply(int a, int b) {
  if (b == 0)
    return 0;
  if (b == 1)
    return a;
  if (b % 2 == 0)
    return 2 * multiply(a, b / 2);
  else
    return 2 * multiply(a, b / 2) + a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compute_height>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int compute_height(int feet, int inches) {
  int value = 0;
  value = (feet * 12) + inches;
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compute_height>:
  endbr64
  lea    (%rdi,%rdi,2),%eax
  lea    (%rsi,%rax,4),%eax
  ret
```

assistant: ```c
int compute_height(int feet, int inches) {
  int value = 0;
  value = (feet * 12) + inches;
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<compute_height>:
  endbr64
  lea    (%rdi,%rdi,2),%eax
  lea    (%rsi,%rax,4),%eax
  ret
```

assistant: ```c
int compute_height(int feet, int inches) {
  int value = 0;
  value = (feet * 12) + inches;
  return value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compute_height>:
  endbr64
  lea    (%rdi,%rdi,2),%eax
  lea    (%rsi,%rax,4),%eax
  ret
```

assistant: ```c
int compute_height(int feet, int inches) {
  int value = 0;
  value = (feet * 12) + inches;
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ringbuffer_decrement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%ecx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <decrement@plt>
  mov    -0xc(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
unsigned int ringbuffer_decrement(unsigned int a, unsigned int delta, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return decrement(a - begin, delta, end - begin) + begin;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ringbuffer_decrement>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %ecx,%r12d
  cmp    %edx,%ecx
  setae  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %ebp,%ebx
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r12d,%edx
  sub    %ebx,%edx
  mov    %ebp,%edi
  sub    %ebx,%edi
  mov    %r13d,%esi
  call   <decrement@plt>
  add    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int ringbuffer_decrement(unsigned int a, unsigned int delta, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return decrement(a - begin, delta, end - begin) + begin;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ringbuffer_decrement>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%ecx
  setae  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setbe  %dil
  call   <assert@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %r13d,%esi
  sub    %ebx,%edx
  sub    %ebx,%edi
  call   <decrement@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int ringbuffer_decrement(unsigned int a, unsigned int delta, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return decrement(a - begin, delta, end - begin) + begin;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ringbuffer_decrement>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%ecx
  setae  %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %ebp,%ebx
  setbe  %dil
  call   <assert@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    %r13d,%esi
  sub    %ebx,%edx
  sub    %ebx,%edi
  call   <decrement@plt>
  add    $0x8,%rsp
  add    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned int ringbuffer_decrement(unsigned int a, unsigned int delta, unsigned int begin, unsigned int end) {
  assert(end >= begin);
  assert(a >= begin);
  return decrement(a - begin, delta, end - begin) + begin;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0xf,-0x14(%rbp)
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movb   $0x70,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x14(%rbp),%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D14
datatype: f64
name: read_data
arguments: tag: D1
datatype: f64
name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D17
datatype: string

tool: D14: 123555555678

tool: D1: 12345678.1234567

tool: D8: a=%d


tool: D17: a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x



assistant: ```c
void chars(void) {
  int a = 15;
  double b = 123555555678;
  double c = 12345678.1234567;
  char d = 'p';
  printf("a=%d\n", a);
  printf("a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x\n\n", a, a, a, a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chars>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xf,%r8d
  mov    $0xf,%ecx
  mov    $0xf,%edx
  mov    $0xf,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string
name: retrieve_data
arguments: label: D5
type_infered: string

tool: D9: a=%d


tool: D5: a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x



assistant: ```c
void chars(void) {
  int a = 15;
  double b = 123555555678;
  double c = 12345678.1234567;
  char d = 'p';
  printf("a=%d\n", a);
  printf("a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x\n\n", a, a, a, a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chars>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xf,%ecx
  xor    %eax,%eax
  add    $0x8,%rsp
  mov    $0xf,%r8d
  mov    $0xf,%edx
  mov    $0xf,%esi
  lea    D11(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D11
type: string

tool: D3: a=%d


tool: D11: a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x



assistant: ```c
void chars(void) {
  int a = 15;
  double b = 123555555678;
  double c = 12345678.1234567;
  char d = 'p';
  printf("a=%d\n", a);
  printf("a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x\n\n", a, a, a, a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chars>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xf,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xf,%ecx
  xor    %eax,%eax
  add    $0x8,%rsp
  mov    $0xf,%r8d
  mov    $0xf,%edx
  mov    $0xf,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D9: a=%d


tool: D1: a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x



assistant: ```c
void chars(void) {
  int a = 15;
  double b = 123555555678;
  double c = 12345678.1234567;
  char d = 'p';
  printf("a=%d\n", a);
  printf("a(%%d)=%d, a(%%5d)=%5d, a(%%o)=%o, a(%%x)=%x\n\n", a, a, a, a);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cleanup_session>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <logout@plt>
  test   %rax,%rax
  je     L0
  mov    -0x8(%rbp),%rax
  lea    D15(%rip),%rdx
  lea    D15(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <logwtmp@plt>
L0:
  mov    -0x18(%rbp),%rax
  mov    $0x1b6,%esi
  mov    %rax,%rdi
  call   <chmod@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <chown@plt>
  mov    -0x1c(%rbp),%eax
  mov    $0x1b6,%esi
  mov    %eax,%edi
  call   <fchmod@plt>
  mov    -0x1c(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <fchown@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D15
type_infered: string

tool: 

assistant: ```c
void cleanup_session(char *tty, int pty_fd) {
  char *line;
  line = tty;
  if (logout(line))
    logwtmp(line, "", "");
  chmod(tty, 0666);
  chown(tty, 0, 0);
  fchmod(pty_fd, 0666);
  fchown(pty_fd, 0, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cleanup_session>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <logout@plt>
  test   %rax,%rax
  jne    L5
L14:
  mov    $0x1b6,%esi
  mov    %rbx,%rdi
  call   <chmod@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <chown@plt>
  mov    $0x1b6,%esi
  mov    %ebp,%edi
  call   <fchmod@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <fchown@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    D1(%rip),%rsi
  mov    %rsi,%rdx
  mov    %rbx,%rdi
  call   <logwtmp@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D1
datatype: string

tool: 

assistant: ```c
void cleanup_session(char *tty, int pty_fd) {
  char *line;
  line = tty;
  if (logout(line))
    logwtmp(line, "", "");
  chmod(tty, 0666);
  chown(tty, 0, 0);
  fchmod(pty_fd, 0666);
  fchown(pty_fd, 0, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cleanup_session>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <logout@plt>
  test   %rax,%rax
  jne    L19
L13:
  mov    %rbp,%rdi
  mov    $0x1b6,%esi
  call   <chmod@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <chown@plt>
  mov    %r12d,%edi
  mov    $0x1b6,%esi
  call   <fchmod@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  xor    %edx,%edx
  pop    %rbp
  xor    %esi,%esi
  pop    %r12
  jmp    10f0 <fchown@plt>
  nopl   0x0(%rax)
L19:
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rsi,%rdx
  call   <logwtmp@plt>
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: 

assistant: ```c
void cleanup_session(char *tty, int pty_fd) {
  char *line;
  line = tty;
  if (logout(line))
    logwtmp(line, "", "");
  chmod(tty, 0666);
  chown(tty, 0, 0);
  fchmod(pty_fd, 0666);
  fchown(pty_fd, 0, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cleanup_session>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <logout@plt>
  test   %rax,%rax
  jne    L6
L19:
  mov    %rbp,%rdi
  mov    $0x1b6,%esi
  call   <chmod@plt>
  xor    %edx,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  call   <chown@plt>
  mov    %r12d,%edi
  mov    $0x1b6,%esi
  call   <fchmod@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  xor    %edx,%edx
  pop    %rbp
  xor    %esi,%esi
  pop    %r12
  jmp    10f0 <fchown@plt>
  nopl   0x0(%rax)
L6:
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rsi,%rdx
  call   <logwtmp@plt>
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: 

assistant: ```c
void cleanup_session(char *tty, int pty_fd) {
  char *line;
  line = tty;
  if (logout(line))
    logwtmp(line, "", "");
  chmod(tty, 0666);
  chown(tty, 0, 0);
  fchmod(pty_fd, 0666);
  fchown(pty_fd, 0, 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<extend_environment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L10
L6:
  addl   $0x1,-0x14(%rbp)
  addq   $0x8,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L6
  mov    -0x14(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L34
L37:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x18(%rbp)
L34:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L37
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **extend_environment(char **old_env, int inc, char **new_strings) {
  int i, count = 0;
  char **p = old_env;
  while (*p != NULL) {
    count++;
    p++;
  }
  char **new_env = (char **)malloc(sizeof(char *) * (count + inc + 1));
  memcpy(new_env, old_env, sizeof(char *) * count);
  for (i = 0; i < inc; i++)
    new_env[count + i] = new_strings[i];
  new_env[count + 1] = NULL;
  return new_env;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<extend_environment>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r12d
  mov    %rdx,%r14
  cmpq   $0x0,(%rdi)
  je     L24
  mov    %rdi,%rax
  mov    $0x0,%ebx
L25:
  add    $0x1,%ebx
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L25
L22:
  lea    0x1(%rbx,%r12,1),%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  movslq %ebx,%r13
  lea    0x0(,%rbx,8),%edx
  mov    %r15,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  test   %r12d,%r12d
  jle    L37
  lea    0x0(%rbp,%r13,8),%rax
  lea    -0x1(%r12),%edx
  add    %r13,%rdx
  lea    0x8(%rbp,%rdx,8),%rsi
  mov    %r13,%rdx
  neg    %rdx
  lea    (%r14,%rdx,8),%rcx
  sub    %rbp,%rcx
L27:
  mov    (%rcx,%rax,1),%rdx
  mov    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L27
L37:
  movq   $0x0,0x8(%rbp,%r13,8)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    $0x0,%ebx
  jmp    L22
```

assistant: ```c
char **extend_environment(char **old_env, int inc, char **new_strings) {
  int i, count = 0;
  char **p = old_env;
  while (*p != NULL) {
    count++;
    p++;
  }
  char **new_env = (char **)malloc(sizeof(char *) * (count + inc + 1));
  memcpy(new_env, old_env, sizeof(char *) * count);
  for (i = 0; i < inc; i++)
    new_env[count + i] = new_strings[i];
  new_env[count + 1] = NULL;
  return new_env;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<extend_environment>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmpq   $0x0,(%rdi)
  je     L32
  mov    %rdi,%rax
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rax
  add    $0x1,%ebx
  cmpq   $0x0,(%rax)
  jne    L11
  movslq %ebx,%rcx
  lea    (%r15,%rbx,1),%eax
  lea    0x0(,%rbx,8),%edx
  lea    0x8(,%rcx,8),%rbp
L45:
  lea    0x8(,%rax,8),%edi
  mov    %edx,0xc(%rsp)
  call   <malloc@plt>
  mov    0xc(%rsp),%edx
  mov    %r14,%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <memcpy@plt>
  test   %r15d,%r15d
  jle    L5
  movslq %ebx,%rbx
  lea    -0x1(%r15),%edx
  mov    %r12,%rcx
  lea    0x0(,%rbx,8),%rdi
  add    %rbx,%rdx
  sub    %r13,%rcx
  lea    0x0(%r13,%rdi,1),%rax
  lea    0x8(%r13,%rdx,8),%rsi
  sub    %rdi,%rcx
  nop
L31:
  mov    (%rcx,%rax,1),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rax,%rsi
  jne    L31
L5:
  movq   $0x0,0x0(%r13,%rbp,1)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L32:
  mov    %esi,%eax
  mov    $0x8,%ebp
  xor    %edx,%edx
  xor    %ebx,%ebx
  jmp    L45
```

assistant: ```c
char **extend_environment(char **old_env, int inc, char **new_strings) {
  int i, count = 0;
  char **p = old_env;
  while (*p != NULL) {
    count++;
    p++;
  }
  char **new_env = (char **)malloc(sizeof(char *) * (count + inc + 1));
  memcpy(new_env, old_env, sizeof(char *) * count);
  for (i = 0; i < inc; i++)
    new_env[count + i] = new_strings[i];
  new_env[count + 1] = NULL;
  return new_env;
}
```