user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D42(%rip),%rbp
L144:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L144
  lea    D103(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D86(%rip),%rbp
L60:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L60
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebp
  lea    D51(%rip),%r13
  lea    D42(%rip),%r12
  jmp    L27
L8:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <comb@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L8
L125:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0x9,%ebp
  je     L58
L27:
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  js     L125
  mov    $0x0,%ebx
  jmp    L8
L58:
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D42(%rip),%rbp
L57:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x9,%ebx
  jne    L57
  lea    D103(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D86(%rip),%rbp
L46:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%ebp
  lea    D51(%rip),%r13
  lea    D95(%rip),%r12
  jmp    L34
L45:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0x9,%ebp
  je     L62
L34:
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  js     L45
  mov    $0x0,%ebx
L123:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <combination@plt>
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L123
  jmp    L45
L62:
  mov    $0x0,%ebx
  lea    D22(%rip),%rbp
L98:
  mov    %ebx,%esi
  mov    $0x22,%edi
  call   <combination@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x12,%ebx
  jne    L98
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D69
type: string
name: retrieve_data
arguments: label: D42
type: string
name: retrieve_data
arguments: label: D103
type: string
name: retrieve_data
arguments: label: D86
type: string
name: retrieve_data
arguments: label: D51
type: string
name: retrieve_data
arguments: label: D95
type: string
name: retrieve_data
arguments: label: D22
type: string

tool: D69: 
  k

tool: D42: %10d

tool: D103: 
n  

tool: D86: ------

tool: D51: %10d |

tool: D95: %10lu

tool: D22: 34C%10d = %10lu


assistant: ```c
int main() {
  int n, k;
  printf("\n  k");
  for (k = 0; k <= 8; k++)
    printf("%10d", k);
  printf("\nn  ");
  for (k = 0; k <= 8; k++)
    printf("------");
  printf("\n");
  for (n = 0; n <= 8; n++) {
    printf("%10d |", n);
    for (k = 0; k <= n; k++)
      printf("%10d", comb(n, k));
    printf("\n");
  }
  printf("\n  k");
  for (k = 0; k <= 8; k++)
    printf("%10d", k);
  printf("\nn  ");
  for (k = 0; k <= 8; k++)
    printf("------");
  printf("\n");
  for (n = 0; n <= 8; n++) {
    printf("%10d |", n);
    for (k = 0; k <= n; k++)
      printf("%10lu", combination(n, k));
    printf("\n");
  }
  for (k = 0; k <= 17; k++)
    printf("34C%10d = %10lu\n", k, combination(34, k));
  return 0;
}
```