ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<detab_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%r14d
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  imul   %r14d,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L6
  mov    %r13,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r13,%rax,1),%r13
  mov    $0x0,%ebp
  jmp    L29
L18:
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    %r14d,%edx
  mov    $0x20,%esi
  call   <memset@plt>
  add    %r14d,%ebp
L21:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L42
L29:
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L18
  movslq %ebp,%rdx
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%ebp
  jmp    L21
L6:
  mov    $0x0,%ebp
L42:
  movslq %ebp,%rbp
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: %s


assistant: ```c
void detab_string(const char *input_string, const int s_num) {
  char *output_string;
  int len, i, j;
  len = strlen(input_string);
  output_string = (char *)malloc((s_num * len + 1) * sizeof(char));
  j = 0;
  for (i = 0; i < len; i++) {
    if (input_string[i] == '\t') {
      memset(output_string + j, ' ', s_num * sizeof(char));
      j += s_num;
    } else {
      output_string[j] = input_string[i];
      j++;
    }
  }
  output_string[j] = '\0';
  printf("%s\n", output_string);
  free(output_string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<detab_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  imul   %r12d,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L9
  lea    -0x1(%rbp),%eax
  xor    %ebp,%ebp
  lea    0x1(%rbx,%rax,1),%r14
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L59:
  add    $0x1,%rbx
  mov    %al,(%rdi)
  add    $0x1,%ebp
  cmp    %rbx,%r14
  je     L30
L28:
  movzbl (%rbx),%eax
  movslq %ebp,%rdi
  add    %r13,%rdi
  cmp    $0x9,%al
  jne    L59
  mov    %r12d,%edx
  mov    $0x20,%esi
  add    $0x1,%rbx
  add    %r12d,%ebp
  call   <memset@plt>
  cmp    %rbx,%r14
  jne    L28
L30:
  movslq %ebp,%rbp
  add    %r13,%rbp
L32:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <free@plt>
  nopl   (%rax)
L9:
  mov    %rax,%rbp
  jmp    L32
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: %s


assistant: ```c
void detab_string(const char *input_string, const int s_num) {
  char *output_string;
  int len, i, j;
  len = strlen(input_string);
  output_string = (char *)malloc((s_num * len + 1) * sizeof(char));
  j = 0;
  for (i = 0; i < len; i++) {
    if (input_string[i] == '\t') {
      memset(output_string + j, ' ', s_num * sizeof(char));
      j += s_num;
    } else {
      output_string[j] = input_string[i];
      j++;
    }
  }
  output_string[j] = '\0';
  printf("%s\n", output_string);
  free(output_string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<detab_string>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  imul   %r12d,%edi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L43
  lea    -0x1(%rbp),%eax
  xor    %ebp,%ebp
  lea    0x1(%rbx,%rax,1),%r14
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L59:
  add    $0x1,%rbx
  mov    %al,(%rdi)
  add    $0x1,%ebp
  cmp    %r14,%rbx
  je     L19
L16:
  movzbl (%rbx),%eax
  movslq %ebp,%rdi
  add    %r13,%rdi
  cmp    $0x9,%al
  jne    L59
  mov    %r12d,%edx
  mov    $0x20,%esi
  add    $0x1,%rbx
  add    %r12d,%ebp
  call   <memset@plt>
  cmp    %r14,%rbx
  jne    L16
L19:
  movslq %ebp,%rbp
  add    %r13,%rbp
L52:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <free@plt>
  nopl   (%rax)
L43:
  mov    %rax,%rbp
  jmp    L52
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: %s


assistant: ```c
void detab_string(const char *input_string, const int s_num) {
  char *output_string;
  int len, i, j;
  len = strlen(input_string);
  output_string = (char *)malloc((s_num * len + 1) * sizeof(char));
  j = 0;
  for (i = 0; i < len; i++) {
    if (input_string[i] == '\t') {
      memset(output_string + j, ' ', s_num * sizeof(char));
      j += s_num;
    } else {
      output_string[j] = input_string[i];
      j++;
    }
  }
  output_string[j] = '\0';
  printf("%s\n", output_string);
  free(output_string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L4
L22:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  imul   -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
L4:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L22
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L18
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L18:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D23
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D10
type_infered: string

tool: D23: 
Enter a number


tool: D15: %d

tool: D27: 
Given number is a Armstrong Number


tool: D10: 
Given number is not a Armstrong Number


assistant: ```c
int main() {
  int iNum, iNum2, iSum = 0, iDig;
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iNum2 = iNum;
  while (iNum) {
    iDig = iNum % 10;
    iSum += iDig * iDig * iDig;
    iNum = iNum / 10;
  }
  if (iSum == iNum2)
    printf("\nGiven number is a Armstrong Number\n");
  else
    printf("\nGiven number is not a Armstrong Number\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  test   %r8d,%r8d
  je     L44
  mov    %r8d,%edx
  mov    $0x0,%edi
L28:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edx,%eax
  add    %eax,%edi
  mov    %esi,%edx
  test   %esi,%esi
  jne    L28
  movl   $0x0,0x4(%rsp)
  cmp    %edi,%r8d
  je     L44
  lea    D28(%rip),%rdi
  call   <printf@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L44:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D4
data_type: string

tool: D12: 
Enter a number


tool: D13: %d

tool: D28: 
Given number is not a Armstrong Number


tool: D4: 
Given number is a Armstrong Number


assistant: ```c
int main() {
  int iNum, iNum2, iSum = 0, iDig;
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iNum2 = iNum;
  while (iNum) {
    iDig = iNum % 10;
    iSum += iDig * iDig * iDig;
    iNum = iNum / 10;
  }
  if (iSum == iNum2)
    printf("\nGiven number is a Armstrong Number\n");
  else
    printf("\nGiven number is not a Armstrong Number\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D14(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  xor    %edi,%edi
  mov    %r8d,%edx
  test   %r8d,%r8d
  je     L29
  nopl   0x0(%rax)
L13:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edx,%eax
  mov    %ecx,%edx
  add    %eax,%edi
  test   %ecx,%ecx
  jne    L13
  movl   $0x0,0x4(%rsp)
  cmp    %edi,%r8d
  je     L29
  lea    D10(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L29:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string
name: read_data
arguments: data_label: D21
type_guessed: string

tool: D17: 
Enter a number


tool: D14: %d

tool: D10: 
Given number is not a Armstrong Number


tool: D21: 
Given number is a Armstrong Number


assistant: ```c
int main() {
  int iNum, iNum2, iSum = 0, iDig;
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iNum2 = iNum;
  while (iNum) {
    iDig = iNum % 10;
    iSum += iDig * iDig * iDig;
    iNum = iNum / 10;
  }
  if (iSum == iNum2)
    printf("\nGiven number is a Armstrong Number\n");
  else
    printf("\nGiven number is not a Armstrong Number\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r8d
  xor    %edi,%edi
  mov    %r8d,%edx
  test   %r8d,%r8d
  je     L39
  nopl   0x0(%rax)
L36:
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%esi
  mov    %eax,%ecx
  mov    %edx,%eax
  add    %esi,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  imul   %edx,%eax
  mov    %ecx,%edx
  add    %eax,%edi
  test   %ecx,%ecx
  jne    L36
  movl   $0x0,0x4(%rsp)
  cmp    %edi,%r8d
  je     L39
  lea    D22(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L39:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D27
type_guessed: string
name: parse_data
arguments: tag: D29
type_guessed: string
name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string

tool: D27: 
Enter a number


tool: D29: %d

tool: D22: 
Given number is not a Armstrong Number


tool: D36: 
Given number is a Armstrong Number


assistant: ```c
int main() {
  int iNum, iNum2, iSum = 0, iDig;
  printf("\nEnter a number\n");
  scanf("%d", &iNum);
  iNum2 = iNum;
  while (iNum) {
    iDig = iNum % 10;
    iSum += iDig * iDig * iDig;
    iNum = iNum / 10;
  }
  if (iSum == iNum2)
    printf("\nGiven number is a Armstrong Number\n");
  else
    printf("\nGiven number is not a Armstrong Number\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kbhit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D120(%rip),%rax
  mov    (%rax),%eax
  lea    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    D37(%rip),%rax
  mov    (%rax),%ecx
  mov    D96(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    D32(%rip),%rax
  mov    (%rax),%ecx
  mov    D120(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%ecx
  mov    D120(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x10(%rbp)
  mov    D54(%rip),%rax
  mov    (%rax),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    D56(%rip),%rax
  mov    (%rax),%ecx
  mov    D120(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    D32(%rip),%rax
  mov    (%rax),%ecx
  mov    D120(%rip),%rax
  mov    (%rax),%eax
  lea    -0x18(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    D56(%rip),%rax
  mov    (%rax),%ecx
  mov    D120(%rip),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L15
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ungetc@plt>
  mov    $0x1,%eax
  jmp    L0
L15:
  mov    $0x0,%eax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
int kbhit(void) {
  struct termios oldt, newt;
  int ch;
  int oldf;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  oldf = fcntl(STDIN_FILENO, F_GETFL, 0);
  fcntl(STDIN_FILENO, F_SETFL, oldf | O_NONBLOCK);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  fcntl(STDIN_FILENO, F_SETFL, oldf);
  if (ch != EOF) {
    ungetc(ch, stdin);
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<kbhit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    D59(%rip),%rbx
  mov    %r12,%rsi
  mov    (%rbx),%edi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    D58(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D3(%rip),%r15
  mov    (%r15),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    $0x0,%edx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    (%rbx),%edi
  call   <fcntl@plt>
  mov    %eax,%ebp
  mov    D63(%rip),%rax
  mov    %ebp,%edx
  or     (%rax),%edx
  mov    D2(%rip),%r14
  mov    (%r14),%esi
  mov    (%rbx),%edi
  call   <fcntl@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%r13d
  mov    %r12,%rdx
  mov    (%r15),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    %ebp,%edx
  mov    (%r14),%esi
  mov    (%rbx),%edi
  call   <fcntl@plt>
  mov    $0x0,%eax
  mov    D8(%rip),%rdx
  cmp    %r13d,(%rdx)
  jne    L22
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L22:
  mov    D30(%rip),%rax
  mov    (%rax),%esi
  mov    %r13d,%edi
  call   <ungetc@plt>
  mov    $0x1,%eax
  jmp    L19
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  struct termios oldt, newt;
  int ch;
  int oldf;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  oldf = fcntl(STDIN_FILENO, F_GETFL, 0);
  fcntl(STDIN_FILENO, F_SETFL, oldf | O_NONBLOCK);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  fcntl(STDIN_FILENO, F_SETFL, oldf);
  if (ch != EOF) {
    ungetc(ch, stdin);
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<kbhit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D25(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    (%rbx),%edi
  mov    %r15,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D52(%rip),%r13
  mov    D42(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D32(%rip),%rax
  mov    0x0(%r13),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  mov    D62(%rip),%rax
  mov    (%rbx),%edi
  xor    %edx,%edx
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    D10(%rip),%r14
  mov    (%rbx),%edi
  mov    %eax,%r12d
  mov    D50(%rip),%rax
  mov    (%r14),%esi
  mov    (%rax),%edx
  or     %r12d,%edx
  call   <fcntl@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  mov    %r15,%rdx
  mov    %eax,%ebp
  call   <tcsetattr@plt>
  mov    (%r14),%esi
  mov    (%rbx),%edi
  mov    %r12d,%edx
  call   <fcntl@plt>
  mov    D64(%rip),%rdx
  xor    %eax,%eax
  cmp    %ebp,(%rdx)
  jne    L27
L21:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L27:
  mov    D69(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    $0x1,%eax
  jmp    L21
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  struct termios oldt, newt;
  int ch;
  int oldf;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  oldf = fcntl(STDIN_FILENO, F_GETFL, 0);
  fcntl(STDIN_FILENO, F_SETFL, oldf | O_NONBLOCK);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  fcntl(STDIN_FILENO, F_SETFL, oldf);
  if (ch != EOF) {
    ungetc(ch, stdin);
    return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kbhit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D44(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    (%rbx),%edi
  mov    %r15,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D58(%rip),%r13
  mov    D82(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D60(%rip),%rax
  mov    0x0(%r13),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  mov    D5(%rip),%rax
  mov    (%rbx),%edi
  xor    %edx,%edx
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    D16(%rip),%r14
  mov    (%rbx),%edi
  mov    %eax,%r12d
  mov    D78(%rip),%rax
  mov    (%r14),%esi
  mov    (%rax),%edx
  or     %r12d,%edx
  call   <fcntl@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  mov    %r15,%rdx
  mov    %eax,%ebp
  call   <tcsetattr@plt>
  mov    (%r14),%esi
  mov    (%rbx),%edi
  mov    %r12d,%edx
  call   <fcntl@plt>
  mov    D77(%rip),%rdx
  xor    %eax,%eax
  cmp    %ebp,(%rdx)
  jne    L17
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L17:
  mov    D11(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    $0x1,%eax
  jmp    L19
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  struct termios oldt, newt;
  int ch;
  int oldf;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  oldf = fcntl(STDIN_FILENO, F_GETFL, 0);
  fcntl(STDIN_FILENO, F_SETFL, oldf | O_NONBLOCK);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  fcntl(STDIN_FILENO, F_SETFL, oldf);
  if (ch != EOF) {
    ungetc(ch, stdin);
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xa,%ecx
  mov    $0xd,%edx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D21
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D56
datatype: string
name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string
name: unpack_data
arguments: data_tag: D22
datatype: string

tool: D21: Content-Type:text/html;charset=iso-8859-1

tool: D7: %s%c%c


tool: D56: <html>
<head>

tool: D17: 	<title>Logging In...</title>
<link href='../a4/common.css' rel='stylesheet' type='text/css'>

<body>

tool: D1: 	<div id='content'>
 		<span id='heading'>The <span id='teamname'>Quad-Core</span><br />Programmers</span><br /><br /> 		This is not implemented yet!<br /><a href='http://cs.mcgill.ca/~vserva1/welcome.html'>Go Home</a>
<br/> 		or go straight to the <a href='http://cs.mcgill.ca/~vserva1/room1.html'>first room.</a> 	</div>
 	<div id='left' class='wing'>&nbsp;</div>
 	<div id='right' class='wing'>&nbsp;</div>	<div id='border'></div>

tool: D22: 
</body>
</html>

assistant: ```c
int main(void) {
  printf("%s%c%c\n", "Content-Type:text/html;charset=iso-8859-1", 13, 10);
  printf("<html>\n<head>\n");
  printf("\t<title>Logging In...</title>\n<link href='../a4/common.css' rel='stylesheet' type='text/css'>\n\n<body>\n");
  printf("\t<div id='content'>\n 		<span id='heading'>The <span id='teamname'>Quad-Core</span><br />Programmers</span><br /><br /> 		This is not implemented yet!<br /><a href='http://cs.mcgill.ca/~vserva1/welcome.html'>Go Home</a>\n<br/> 		or go straight to the <a href='http://cs.mcgill.ca/~vserva1/room1.html'>first room.</a> 	</div>\n 	<div id='left' class='wing'>&nbsp;</div>\n 	<div id='right' class='wing'>&nbsp;</div>	<div id='border'></div>");
  printf("\n</body>\n</html>");
  return 0;
}
```