ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<invSqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  -0x24(%rbp),%xmm1
  movss  D1(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  sar    %rax
  mov    %rax,%rdx
  mov    $0x5f3759df,%eax
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x14(%rbp),%xmm1
  movss  -0x18(%rbp),%xmm0
  movaps %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  movss  D15(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: byte[4]
name: unpack_data
arguments: data_label: D15
type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x3f]}

tool: {"D15": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  long i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<invSqrt>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mov    -0x4(%rsp),%rdx
  sar    %rdx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  D17(%rip),%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  movss  D4(%rip),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
data_type: byte[4]
name: disassemble_data
arguments: data_label: D4
data_type: byte[4]

tool: {"D17": [0x00,0x00,0x00,0x3f]}

tool: {"D4": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  long i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<invSqrt>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mulss  D18(%rip),%xmm0
  mov    -0x4(%rsp),%rdx
  mov    $0x5f3759df,%eax
  movss  D17(%rip),%xmm1
  sar    %rdx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: byte[4]
name: extract_symbolic_data
arguments: label: D17
type_infered: byte[4]

tool: {"D18": [0x00,0x00,0x00,0x3f]}

tool: {"D17": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  long i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<invSqrt>:
  endbr64
  movss  %xmm0,-0x4(%rsp)
  mulss  D9(%rip),%xmm0
  mov    -0x4(%rsp),%rdx
  mov    $0x5f3759df,%eax
  movss  D18(%rip),%xmm1
  sar    %rdx
  sub    %edx,%eax
  movd   %eax,%xmm2
  mulss  %xmm2,%xmm0
  mulss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  mulss  %xmm2,%xmm1
  movaps %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: byte[4]
name: unpack_data
arguments: data_tag: D18
type: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x3f]}

tool: {"D18": [0x00,0x00,0xc0,0x3f]}

assistant: ```c
float invSqrt(float x) {
  float halfx = 0.5f * x;
  float y = x;
  long i = *(long *)&y;
  i = 0x5f3759df - (i >> 1);
  y = *(float *)&i;
  y = y * (1.5f - (halfx * y * y));
  return y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ssl_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RAND_pseudo_bytes@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L6
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RAND_bytes@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  je     L6
  mov    $0xffffffff,%eax
  jmp    L3
L6:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int ssl_rand(void *p, size_t sz) {
  int rv;
  rv = RAND_pseudo_bytes((unsigned char *)p, sz);
  if (rv == -1) {
    rv = RAND_bytes((unsigned char *)p, sz);
    if (rv != 1)
      return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ssl_rand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <RAND_pseudo_bytes@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xffffffff,%edx
  je     L6
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <RAND_bytes@plt>
  cmp    $0x1,%eax
  setne  %al
  movzbl %al,%eax
  neg    %eax
  jmp    L5
```

assistant: ```c
int ssl_rand(void *p, size_t sz) {
  int rv;
  rv = RAND_pseudo_bytes((unsigned char *)p, sz);
  if (rv == -1) {
    rv = RAND_bytes((unsigned char *)p, sz);
    if (rv != 1)
      return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ssl_rand>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <RAND_pseudo_bytes@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <RAND_bytes@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int ssl_rand(void *p, size_t sz) {
  int rv;
  rv = RAND_pseudo_bytes((unsigned char *)p, sz);
  if (rv == -1) {
    rv = RAND_bytes((unsigned char *)p, sz);
    if (rv != 1)
      return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ssl_rand>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <RAND_pseudo_bytes@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xffffffff,%r8d
  je     L3
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L3:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <RAND_bytes@plt>
  cmp    $0x1,%eax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  neg    %eax
  ret
```

assistant: ```c
int ssl_rand(void *p, size_t sz) {
  int rv;
  rv = RAND_pseudo_bytes((unsigned char *)p, sz);
  if (rv == -1) {
    rv = RAND_bytes((unsigned char *)p, sz);
    if (rv != 1)
      return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L43
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L29
L27:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L21
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%esi
  mov    -0x18(%rbp),%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <swap@plt>
L21:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L27
  mov    -0x20(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L19
L43:
  nop
L19:
  leave
  ret
```

assistant: ```c
void quicksort(int *values, int l, int r) {
  if (l >= r)
    return;
  int j = l;
  for (int i = l; i < r; i++) {
    if (values[i] < values[r]) {
      swap(values, i, j++);
    }
  }
  swap(values, j, r);
  quicksort(values, l, j - 1);
  quicksort(values, j + 1, r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<quicksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  cmp    %edx,%esi
  jge    L24
  mov    %rdi,%rbp
  movslq %edx,%rax
  lea    (%rdi,%rax,4),%r14
  movslq %esi,%rbx
  lea    -0x1(%rdx),%eax
  sub    %esi,%eax
  lea    0x1(%rbx,%rax,1),%r13
  mov    %esi,%r12d
  jmp    L14
L41:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L17
L14:
  mov    %ebx,%esi
  mov    (%r14),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L41
  lea    0x1(%r12),%r15d
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r15d,%r12d
  jmp    L41
L17:
  mov    0xc(%rsp),%ebx
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r12),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%r12),%esi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <quicksort>
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void quicksort(int *values, int l, int r) {
  if (l >= r)
    return;
  int j = l;
  for (int i = l; i < r; i++) {
    if (values[i] < values[r]) {
      swap(values, i, j++);
    }
  }
  swap(values, j, r);
  quicksort(values, l, j - 1);
  quicksort(values, j + 1, r);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quicksort>:
  endbr64
  cmp    %esi,%edx
  jle    L23
  push   %r15
  movslq %edx,%rax
  push   %r14
  lea    (%rdi,%rax,4),%r15
  mov    %esi,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
L11:
  movslq %r14d,%rbx
  mov    %r14d,%r12d
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jle    L10
L18:
  mov    (%r15),%eax
  mov    %ebx,%esi
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L0
  lea    0x1(%r12),%eax
  mov    %r12d,%edx
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mov    %eax,0xc(%rsp)
  call   <swap@plt>
  mov    0xc(%rsp),%r12d
  cmp    %ebx,%r13d
  jg     L18
L10:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r12),%edx
  mov    %rbp,%rdi
  call   <quicksort>
  lea    0x1(%r12),%r14d
  cmp    %r13d,%r14d
  jl     L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

assistant: ```c
void quicksort(int *values, int l, int r) {
  if (l >= r)
    return;
  int j = l;
  for (int i = l; i < r; i++) {
    if (values[i] < values[r]) {
      swap(values, i, j++);
    }
  }
  swap(values, j, r);
  quicksort(values, l, j - 1);
  quicksort(values, j + 1, r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4f494541,-0x117(%rbp)
  movw   $0x5955,-0x113(%rbp)
  movb   $0x0,-0x111(%rbp)
  movl   $0xffffffff,-0x128(%rbp)
  movl   $0x0,-0x124(%rbp)
  movl   $0x1,-0x120(%rbp)
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L51
L46:
  movl   $0x0,-0x11c(%rbp)
  jmp    L54
L50:
  mov    -0x11c(%rbp),%eax
  cltq
  movzbl -0x117(%rbp,%rax,1),%edx
  mov    -0x124(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L47
  mov    -0x124(%rbp),%eax
  sub    -0x128(%rbp),%eax
  mov    -0x120(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x120(%rbp)
  mov    -0x124(%rbp),%eax
  mov    %eax,-0x128(%rbp)
  nop
L47:
  addl   $0x1,-0x11c(%rbp)
L54:
  cmpl   $0x5,-0x11c(%rbp)
  jle    L50
  addl   $0x1,-0x124(%rbp)
L51:
  mov    -0x124(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L46
  mov    -0x124(%rbp),%eax
  sub    -0x128(%rbp),%eax
  mov    -0x120(%rbp),%edx
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x120(%rbp)
  mov    -0x120(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string

tool: D2: %s

tool: D19: %d

assistant: ```c
int main() {
  char buf[256], vowels[7] = "AEIOUY";
  int prev = -1, curr = 0, j = 1;
  scanf("%s", buf);
  while (buf[curr]) {
    for (int i = 0; i < 6; ++i) {
      if (vowels[i] == buf[curr]) {
        j = j > curr - prev ? j : curr - prev;
        prev = curr;
        continue;
      }
    }
    ++curr;
  }
  j = j > curr - prev ? j : curr - prev;
  printf("%d", j);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movl   $0x4f494541,0x9(%rsp)
  movw   $0x5955,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0x10(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x10(%rsp),%edx
  test   %dl,%dl
  je     L19
  lea    0x11(%rsp),%r9
  mov    $0x1,%edi
  mov    $0x0,%esi
  mov    $0xffffffff,%r10d
  lea    0xf(%rsp),%rcx
  jmp    L22
L4:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L44
L26:
  cmp    %dl,(%rax)
  jne    L4
  mov    %esi,%r8d
  sub    %r10d,%r8d
  cmp    %r8d,%edi
  cmovl  %r8d,%edi
  mov    %r11d,%r10d
  jmp    L4
L44:
  add    $0x1,%esi
  add    $0x1,%r9
  movzbl -0x1(%r9),%edx
  test   %dl,%dl
  je     L11
L22:
  lea    0x9(%rsp),%rax
  mov    %esi,%r11d
  jmp    L26
L19:
  mov    $0x1,%edi
  mov    $0x0,%esi
  mov    $0xffffffff,%r10d
L11:
  sub    %r10d,%esi
  cmp    %edi,%esi
  cmovl  %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  mov    $0x0,%eax
  add    $0x128,%rsp
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D9: %s

tool: D6: %d

assistant: ```c
int main() {
  char buf[256], vowels[7] = "AEIOUY";
  int prev = -1, curr = 0, j = 1;
  scanf("%s", buf);
  while (buf[curr]) {
    for (int i = 0; i < 6; ++i) {
      if (vowels[i] == buf[curr]) {
        j = j > curr - prev ? j : curr - prev;
        prev = curr;
        continue;
      }
    }
    ++curr;
  }
  j = j > curr - prev ? j : curr - prev;
  printf("%d", j);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x128,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  mov    $0x5955,%eax
  movl   $0x4f494541,0x9(%rsp)
  mov    %ax,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  call   <scanf@plt>
  movzbl 0x10(%rsp),%ecx
  test   %cl,%cl
  je     L5
  lea    0x11(%rsp),%r9
  mov    $0x1,%r8d
  xor    %esi,%esi
  mov    $0xffffffff,%r10d
  lea    0x9(%rsp),%r11
  lea    0xf(%rsp),%rdi
L35:
  mov    %r11,%rax
  mov    $0x41,%edx
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L60:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L23
L9:
  movzbl (%rax),%edx
L1:
  cmp    %cl,%dl
  jne    L60
  mov    %esi,%edx
  sub    %r10d,%edx
  mov    %esi,%r10d
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L9
L23:
  movzbl (%r9),%ecx
  add    $0x1,%r9
  add    $0x1,%esi
  test   %cl,%cl
  jne    L35
L62:
  sub    %r10d,%esi
  lea    D18(%rip),%rdi
  cmp    %r8d,%esi
  cmovl  %r8d,%esi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  xor    %eax,%eax
  add    $0x128,%rsp
  ret
L5:
  mov    $0x1,%r8d
  xor    %esi,%esi
  or     $0xffffffff,%r10d
  jmp    L62
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string

tool: D2: %s

tool: D18: %d

assistant: ```c
int main() {
  char buf[256], vowels[7] = "AEIOUY";
  int prev = -1, curr = 0, j = 1;
  scanf("%s", buf);
  while (buf[curr]) {
    for (int i = 0; i < 6; ++i) {
      if (vowels[i] == buf[curr]) {
        j = j > curr - prev ? j : curr - prev;
        prev = curr;
        continue;
      }
    }
    ++curr;
  }
  j = j > curr - prev ? j : curr - prev;
  printf("%d", j);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x118,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L56
  lea    0x1(%rsp),%rcx
  mov    $0x1,%edx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  jmp    L45
  nopl   0x0(%rax)
L84:
  cmp    $0x45,%al
  je     L3
  cmp    $0x49,%al
  je     L3
  cmp    $0x4f,%al
  je     L3
  cmp    $0x55,%al
  je     L3
  cmp    $0x59,%al
  je     L3
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  add    $0x1,%esi
  test   %al,%al
  je     L14
  nopw   0x0(%rax,%rax,1)
L45:
  cmp    $0x41,%al
  jne    L84
  nopl   0x0(%rax)
L3:
  mov    %esi,%eax
  sub    %edi,%eax
  mov    %esi,%edi
  cmp    %eax,%edx
  cmovl  %eax,%edx
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  add    $0x1,%esi
  test   %al,%al
  jne    L45
L14:
  sub    %edi,%esi
  lea    D7(%rip),%rdi
  cmp    %edx,%esi
  cmovl  %edx,%esi
  call   <printf@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  xor    %eax,%eax
  add    $0x118,%rsp
  ret
L56:
  mov    $0x1,%edx
  xor    %esi,%esi
  or     $0xffffffff,%edi
  jmp    L14
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string

tool: D5: %s

tool: D7: %d

assistant: ```c
int main() {
  char buf[256], vowels[7] = "AEIOUY";
  int prev = -1, curr = 0, j = 1;
  scanf("%s", buf);
  while (buf[curr]) {
    for (int i = 0; i < 6; ++i) {
      if (vowels[i] == buf[curr]) {
        j = j > curr - prev ? j : curr - prev;
        prev = curr;
        continue;
      }
    }
    ++curr;
  }
  j = j > curr - prev ? j : curr - prev;
  printf("%d", j);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<save_image>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%r15
  mov    %ecx,%r14d
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbp
  mov    %edi,%edx
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L34
  mov    %rax,%r13
  mov    $0xff,%r8d
  mov    $0x8,%ecx
  mov    $0x50,%edx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  lea    0x280(%rbx),%rax
  mov    %rax,(%rsp)
  lea    0x1680(%rbx),%rax
  mov    %rax,0x18(%rsp)
  pxor   %xmm2,%xmm2
  cvtsi2sd %r14d,%xmm2
  movsd  %xmm2,0x10(%rsp)
L18:
  mov    (%rsp),%rax
  lea    -0x280(%rax),%rbp
L3:
  movsd  0x10(%rsp),%xmm0
  mulsd  0x0(%rbp),%xmm0
  divsd  0x8(%rsp),%xmm0
  cvttsd2si %xmm0,%eax
  cmp    %r14d,%eax
  cmovg  %r14d,%eax
  cltq
  mov    (%r15,%rax,4),%ebx
  mov    %ebx,%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,0x2c(%rsp)
  lea    0x2c(%rsp),%r12
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  movzbl %bh,%eax
  mov    %eax,0x2c(%rsp)
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  and    $0xff,%ebx
  mov    %ebx,0x2c(%rsp)
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fwrite@plt>
  add    $0x8,%rbp
  cmp    (%rsp),%rbp
  jne    L3
  addq   $0x280,(%rsp)
  mov    (%rsp),%rax
  cmp    0x18(%rsp),%rax
  jne    L18
  mov    %r13,%rdi
  call   <fclose@plt>
L34:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string

tool: D12: metaballs%03d.ppm

tool: D11: wb

tool: D8: P6
%d %d
%d


assistant: ```c
void save_image(int index, double field[][80], uint32_t palet[], int max_col, double scale) {
  FILE *file;
  char filename[128];
  int row, col;
  uint32_t rgb;
  uint8_t b;
  sprintf(filename, "metaballs%03d.ppm", index);
  file = fopen(filename, "wb");
  if (file != NULL) {
    fprintf(file, "P6\n%d %d\n%d\n", 80, 8, 255);
    for (row = 0; row < 8; row++) {
      for (col = 0; col < 80; col++) {
        double v = field[row][col];
        int j = max_col * v / scale;
        if (j > max_col) {
          j = max_col;
        }
        rgb = palet[j];
        b = (rgb >> 16) & 0xFF;
        fwrite(&b, 1, 1, file);
        b = (rgb >> 8) & 0xFF;
        fwrite(&b, 1, 1, file);
        b = (rgb >> 0) & 0xFF;
        fwrite(&b, 1, 1, file);
      }
    }
    fclose(file);
  }
}
```