ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D73(%rip),%rdi
  call   <scanf@plt>
  lea    D90(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L23
  comiss %xmm0,%xmm1
  movss  0x8(%rsp),%xmm2
  jbe    L82
  comiss %xmm2,%xmm0
  jae    L86
L82:
  comiss %xmm0,%xmm2
  movss  0xc(%rsp),%xmm1
  ja     L107
L14:
  comiss %xmm0,%xmm1
  jbe    L68
  comiss 0x10(%rsp),%xmm0
  jae    L48
L68:
  lea    D3(%rip),%rdi
  call   <printf@plt>
L76:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L107:
  comiss %xmm1,%xmm0
  jb     L14
  lea    D48(%rip),%rdi
  call   <printf@plt>
  jmp    L76
L23:
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L76
L86:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L76
L48:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L76
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D56
type_guessed: string
name: unpack_data
arguments: tag: D73
type_guessed: string
name: unpack_data
arguments: tag: D90
type_guessed: string
name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string
name: unpack_data
arguments: tag: D79
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D53
type_guessed: string

tool: D7: Enter thresholds for A, B, C, D


tool: D56: in that order, decreasing percentages > 

tool: D73: %f%f%f%f

tool: D90: Thank you. Now enter student score (percent) >

tool: D37: %f

tool: D3: Student has failed the course


tool: D48: Student has an C grade


tool: D79: Student has an A grade


tool: D5: Student has an B grade


tool: D53: Student has an D grade


assistant: ```c
int main() {
  float A, B, C, D, score;
  printf("Enter thresholds for A, B, C, D\n");
  printf("in that order, decreasing percentages > ");
  scanf("%f%f%f%f", &A, &B, &C, &D);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &score);
  if (score >= A) {
    printf("Student has an A grade\n");
  } else if (score < A && score >= B) {
    printf("Student has an B grade\n");
  } else if (score < B && score >= C) {
    printf("Student has an C grade\n");
  } else if (score < C && score >= D) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has failed the course\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strrchrm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L50
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L28
  mov    -0x8(%rbp),%rax
  jmp    L37
L28:
  subq   $0x1,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jne    L34
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L39
  mov    -0x8(%rbp),%rax
  jmp    L37
L39:
  mov    $0x0,%eax
L37:
  leave
  ret
```

assistant: ```c
char *strrchrm(char *str, char v) {
  char *s = str + strlen(str) - 1;
  while (s != str) {
    if (*s == v)
      return s;
    s--;
  }
  if (*s == v)
    return s;
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<strrchrm>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%ebp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  je     L2
L19:
  cmp    %bpl,(%rax)
  je     L13
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L19
L2:
  cmp    %r12b,(%rax)
  mov    $0x0,%edx
  cmovne %rdx,%rax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strrchrm(char *str, char v) {
  char *s = str + strlen(str) - 1;
  while (s != str) {
    if (*s == v)
      return s;
    s--;
  }
  if (*s == v)
    return s;
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strrchrm>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jne    L32
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L34:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L24
L32:
  cmp    %bpl,(%rax)
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %edx,%edx
  cmp    %r12b,(%rax)
  pop    %rbx
  cmovne %rdx,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strrchrm(char *str, char v) {
  char *s = str + strlen(str) - 1;
  while (s != str) {
    if (*s == v)
      return s;
    s--;
  }
  if (*s == v)
    return s;
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strrchrm>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jne    L14
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L1:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L16
L14:
  cmp    %bpl,(%rax)
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %edx,%edx
  cmp    %r12b,(%rax)
  pop    %rbx
  cmovne %rdx,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strrchrm(char *str, char v) {
  char *s = str + strlen(str) - 1;
  while (s != str) {
    if (*s == v)
      return s;
    s--;
  }
  if (*s == v)
    return s;
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<geopm_field_to_signal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double geopm_field_to_signal(uint64_t field) {
  double result;
  memcpy(&result, &field, sizeof(result));
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<geopm_field_to_signal>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x8,%edx
  call   <memcpy@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double geopm_field_to_signal(uint64_t field) {
  double result;
  memcpy(&result, &field, sizeof(result));
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<geopm_field_to_signal>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x8,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double geopm_field_to_signal(uint64_t field) {
  double result;
  memcpy(&result, &field, sizeof(result));
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<geopm_field_to_signal>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x8,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  movsd  0x10(%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double geopm_field_to_signal(uint64_t field) {
  double result;
  memcpy(&result, &field, sizeof(result));
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x24(%rbp)
  je     L11
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L16
L11:
  addq   $0x8,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L34
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  mov    -0x14(%rbp),%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D1: Usage: %s [FILE]


tool: D17: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat st;
  int ret;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  ret = stat(*++argv, &st);
  if (ret == 0)
    printf("%lld\n", (long long)st.st_size);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L5
  mov    (%rsi),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%ebx
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  mov    %rsp,%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <stat@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L23
  mov    (%rsp),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D3
type: string

tool: D14: Usage: %s [FILE]


tool: D3: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat st;
  int ret;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  ret = stat(*++argv, &st);
  if (ret == 0)
    printf("%lld\n", (long long)st.st_size);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L39
  mov    (%rsi),%rsi
  lea    D2(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L39:
  mov    0x8(%rsi),%rdi
  mov    %rsp,%r8
  mov    %r8,%rsi
  call   <stat@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L26
  mov    (%rsp),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string

tool: D2: Usage: %s [FILE]


tool: D14: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat st;
  int ret;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  ret = stat(*++argv, &st);
  if (ret == 0)
    printf("%lld\n", (long long)st.st_size);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L1
  mov    (%rsi),%rsi
  lea    D17(%rip),%rdi
  mov    $0x1,%r12d
  call   <printf@plt>
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L1:
  mov    0x8(%rsi),%rdi
  mov    %rsp,%r8
  mov    %r8,%rsi
  call   <stat@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L5
  mov    (%rsp),%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L5
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
datatype: string
name: parse_data
arguments: label: D1
datatype: string

tool: D17: Usage: %s [FILE]


tool: D1: %lld


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat st;
  int ret;
  if (argc != 2) {
    printf("Usage: %s [FILE]\n", argv[0]);
    return 1;
  }
  ret = stat(*++argv, &st);
  if (ret == 0)
    printf("%lld\n", (long long)st.st_size);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<mostrarTaulell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L5:
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L18:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D24: 
	

tool: D10: %c 

assistant: ```c
void mostrarTaulell(char taulell[11][11], int col) {
  int i, j;
  printf("\n\t");
  for (i = 0; i < col; i++) {
    for (j = 0; j < col; j++) {
      printf("%c ", taulell[i][j]);
    }
    printf("\n\t");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<mostrarTaulell>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  lea    D21(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L10
  lea    -0x1(%rbx),%r13d
  lea    0x1(%r12,%r13,1),%rbp
  lea    0x0(%r13,%r13,2),%rax
  lea    0xc(%r12,%rax,4),%r15
  lea    D5(%rip),%r12
  lea    D21(%rip),%r14
L29:
  mov    %rbp,%rbx
  sub    %r13,%rbx
  sub    $0x1,%rbx
L18:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L18
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0xb,%rbp
  cmp    %r15,%rbp
  jne    L29
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D21: 
	

tool: D5: %c 

assistant: ```c
void mostrarTaulell(char taulell[11][11], int col) {
  int i, j;
  printf("\n\t");
  for (i = 0; i < col; i++) {
    for (j = 0; j < col; j++) {
      printf("%c ", taulell[i][j]);
    }
    printf("\n\t");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mostrarTaulell>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %r14,%rdi
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L7
  lea    -0x1(%rbx),%r13d
  lea    0x0(%r13,%r13,2),%rax
  lea    0x1(%r12,%r13,1),%rbp
  lea    0xc(%r12,%rax,4),%r15
  lea    D13(%rip),%r12
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rbx
  sub    %r13,%rbx
  sub    $0x1,%rbx
  nopw   0x0(%rax,%rax,1)
L29:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L29
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0xb,%rbp
  call   <printf@plt>
  cmp    %r15,%rbp
  jne    L13
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type: string
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: D16: 
	

tool: D13: %c 

assistant: ```c
void mostrarTaulell(char taulell[11][11], int col) {
  int i, j;
  printf("\n\t");
  for (i = 0; i < col; i++) {
    for (j = 0; j < col; j++) {
      printf("%c ", taulell[i][j]);
    }
    printf("\n\t");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mostrarTaulell>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %r13,%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L0
  lea    -0x1(%rbp),%eax
  lea    0xc(%r12),%rbx
  lea    (%rax,%rax,4),%rdx
  lea    (%rax,%rdx,2),%rax
  lea    0x17(%r12,%rax,1),%r14
  lea    -0xd(%rbp),%eax
  mov    %eax,0xc(%rsp)
  lea    D4(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L98:
  movsbl -0xc(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x1,%ebp
  je     L74
  movsbl -0xb(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x2,%ebp
  je     L74
  movsbl -0xa(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebp
  je     L74
  movsbl -0x9(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x4,%ebp
  je     L74
  movsbl -0x8(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebp
  je     L74
  movsbl -0x7(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x6,%ebp
  je     L74
  movsbl -0x6(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x7,%ebp
  je     L74
  movsbl -0x5(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x8,%ebp
  je     L74
  movsbl -0x4(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x9,%ebp
  je     L74
  movsbl -0x3(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xa,%ebp
  je     L74
  movsbl -0x2(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xb,%ebp
  je     L74
  movsbl -0x1(%rbx),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xc,%ebp
  je     L74
  mov    0xc(%rsp),%eax
  mov    %rbx,%r15
  lea    0x1(%rax,%rbx,1),%rax
  mov    %rax,(%rsp)
L79:
  movsbl (%r15),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    (%rsp),%r15
  jne    L79
L74:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0xb,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L98
L0:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D6: 
	

tool: D4: %c 

assistant: ```c
void mostrarTaulell(char taulell[11][11], int col) {
  int i, j;
  printf("\n\t");
  for (i = 0; i < col; i++) {
    for (j = 0; j < col; j++) {
      printf("%c ", taulell[i][j]);
    }
    printf("\n\t");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<before_url>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D24(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x3,%edi
  call   <init_pair@plt>
  mov    $0x3,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wattron@plt>
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wattron@plt>
  nop
  leave
  ret
```

assistant: ```c
void before_url(WINDOW *win) {
  init_pair(3, COLOR_BLUE, COLOR_BLACK);
  wattron(win, COLOR_PAIR(3));
  wattron(win, A_UNDERLINE);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<before_url>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    $0x3,%edi
  call   <init_pair@plt>
  mov    $0x3,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <wattron@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <wattron@plt>
  pop    %rbx
  ret
```

assistant: ```c
void before_url(WINDOW *win) {
  init_pair(3, COLOR_BLUE, COLOR_BLACK);
  wattron(win, COLOR_PAIR(3));
  wattron(win, A_UNDERLINE);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<before_url>:
  endbr64
  mov    D21(%rip),%rax
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    (%rax),%esi
  call   <init_pair@plt>
  mov    $0x3,%edi
  call   <COLOR_PAIR@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <wattron@plt>
  mov    D8(%rip),%rax
  mov    %rbp,%rdi
  pop    %rbp
  mov    (%rax),%esi
  jmp    1080 <wattron@plt>
```

assistant: ```c
void before_url(WINDOW *win) {
  init_pair(3, COLOR_BLUE, COLOR_BLACK);
  wattron(win, COLOR_PAIR(3));
  wattron(win, A_UNDERLINE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<before_url>:
  endbr64
  mov    D8(%rip),%rax
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x3,%edi
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  call   <init_pair@plt>
  mov    $0x3,%edi
  call   <COLOR_PAIR@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <wattron@plt>
  mov    D1(%rip),%rax
  mov    %rbp,%rdi
  pop    %rbp
  mov    (%rax),%esi
  jmp    1080 <wattron@plt>
```

assistant: ```c
void before_url(WINDOW *win) {
  init_pair(3, COLOR_BLUE, COLOR_BLACK);
  wattron(win, COLOR_PAIR(3));
  wattron(win, A_UNDERLINE);
}
```