ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<simplify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L67
L64:
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L95:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L77
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L65:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L28
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L98
  movl   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  jmp    L98
L28:
  nop
L98:
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L65
  jmp    L15
L77:
  nop
L15:
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L95
  addl   $0x1,-0xc(%rbp)
L67:
  cmpl   $0x9,-0xc(%rbp)
  jle    L64
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
bool simplify(int id, int jd, int idigit[id], int jdigit[jd], bool imask[id], bool jmask[jd]) {
  bool simplified = false;
  int a, x, y;
  for (a = 0; a < 10; ++a) {
    for (x = 0; x < id; ++x) {
      if (!imask[x]) {
        continue;
      }
      for (y = 0; y < jd; ++y) {
        if (!jmask[y]) {
          continue;
        }
        if (idigit[x] == jdigit[y]) {
          simplified = true;
          imask[x] = false;
          jmask[y] = false;
        }
      }
    }
  }
  return simplified;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<simplify>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r10d
  mov    %esi,%r11d
  mov    %rdx,%rdi
  mov    %rcx,%rsi
  mov    $0xa,%r13d
  mov    $0x0,%ebp
  mov    %r10d,%ebx
  mov    %r11d,%ecx
  mov    $0x1,%r12d
  jmp    L8
L46:
  add    $0x1,%rax
  cmp    %rax,%rcx
  je     L88
L65:
  cmpl   $0x0,(%r9,%rax,4)
  je     L46
  mov    (%rsi,%rax,4),%r14d
  cmp    %r14d,(%rdi,%rdx,4)
  jne    L46
  movl   $0x0,(%r8,%rdx,4)
  movl   $0x0,(%r9,%rax,4)
  mov    %r12d,%ebp
  jmp    L46
L88:
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  je     L15
L5:
  cmpl   $0x0,(%r8,%rdx,4)
  je     L88
  test   %r11d,%r11d
  jle    L88
  mov    $0x0,%eax
  jmp    L65
L15:
  sub    $0x1,%r13d
  je     L6
L8:
  mov    $0x0,%edx
  test   %r10d,%r10d
  jg     L5
  jmp    L15
L6:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
bool simplify(int id, int jd, int idigit[id], int jdigit[jd], bool imask[id], bool jmask[jd]) {
  bool simplified = false;
  int a, x, y;
  for (a = 0; a < 10; ++a) {
    for (x = 0; x < id; ++x) {
      if (!imask[x]) {
        continue;
      }
      for (y = 0; y < jd; ++y) {
        if (!jmask[y]) {
          continue;
        }
        if (idigit[x] == jdigit[y]) {
          simplified = true;
          imask[x] = false;
          jmask[y] = false;
        }
      }
    }
  }
  return simplified;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<simplify>:
  endbr64
  push   %r14
  mov    %esi,%r11d
  mov    %rcx,%rsi
  push   %r12
  movslq %r11d,%rcx
  xor    %r12d,%r12d
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  movslq %edi,%rbx
  mov    %rdx,%rdi
  mov    %rbx,%r10
  nopl   0x0(%rax)
L42:
  xor    %edx,%edx
  test   %r10d,%r10d
  jg     L87
  jmp    L92
  nopl   0x0(%rax)
L61:
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  je     L92
L87:
  mov    (%r8,%rdx,4),%eax
  test   %eax,%eax
  je     L61
  test   %r11d,%r11d
  jle    L61
  xor    %eax,%eax
L72:
  mov    (%r9,%rax,4),%r14d
  test   %r14d,%r14d
  je     L10
  mov    (%rsi,%rax,4),%r14d
  cmp    %r14d,(%rdi,%rdx,4)
  jne    L10
  movl   $0x0,(%r8,%rdx,4)
  mov    $0x1,%r12d
  movl   $0x0,(%r9,%rax,4)
L10:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L72
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L87
L92:
  sub    $0x1,%ebp
  jne    L42
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
bool simplify(int id, int jd, int idigit[id], int jdigit[jd], bool imask[id], bool jmask[jd]) {
  bool simplified = false;
  int a, x, y;
  for (a = 0; a < 10; ++a) {
    for (x = 0; x < id; ++x) {
      if (!imask[x]) {
        continue;
      }
      for (y = 0; y < jd; ++y) {
        if (!jmask[y]) {
          continue;
        }
        if (idigit[x] == jdigit[y]) {
          simplified = true;
          imask[x] = false;
          jmask[y] = false;
        }
      }
    }
  }
  return simplified;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<simplify>:
  endbr64
  push   %r14
  mov    %esi,%r11d
  mov    %rcx,%rsi
  push   %r12
  movslq %r11d,%rcx
  xor    %r12d,%r12d
  push   %rbp
  mov    $0xa,%ebp
  push   %rbx
  movslq %edi,%rbx
  mov    %rdx,%rdi
  mov    %rbx,%r10
  nopl   0x0(%rax)
L35:
  xor    %edx,%edx
  test   %r10d,%r10d
  jg     L56
  jmp    L16
  nopl   0x0(%rax)
L5:
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  je     L16
L56:
  mov    (%r8,%rdx,4),%eax
  test   %eax,%eax
  je     L5
  test   %r11d,%r11d
  jle    L5
  xor    %eax,%eax
L85:
  mov    (%r9,%rax,4),%r14d
  test   %r14d,%r14d
  je     L1
  mov    (%rsi,%rax,4),%r14d
  cmp    %r14d,(%rdi,%rdx,4)
  jne    L1
  movl   $0x0,(%r8,%rdx,4)
  mov    $0x1,%r12d
  movl   $0x0,(%r9,%rax,4)
L1:
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L85
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L56
L16:
  sub    $0x1,%ebp
  jne    L35
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
bool simplify(int id, int jd, int idigit[id], int jdigit[jd], bool imask[id], bool jmask[jd]) {
  bool simplified = false;
  int a, x, y;
  for (a = 0; a < 10; ++a) {
    for (x = 0; x < id; ++x) {
      if (!imask[x]) {
        continue;
      }
      for (y = 0; y < jd; ++y) {
        if (!jmask[y]) {
          continue;
        }
        if (idigit[x] == jdigit[y]) {
          simplified = true;
          imask[x] = false;
          jmask[y] = false;
        }
      }
    }
  }
  return simplified;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    $0x0,%eax
  call   <log_oom_and_exit@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p) {
    log_oom_and_exit();
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
L3:
  mov    %rbx,%rax
  pop    %rbx
  ret
L5:
  mov    $0x0,%eax
  call   <log_oom_and_exit@plt>
  jmp    L3
```

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p) {
    log_oom_and_exit();
  }
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L11
L13:
  mov    %r12,%rax
  pop    %r12
  ret
L11:
  xor    %eax,%eax
  call   <log_oom_and_exit@plt>
  jmp    L13
```

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p) {
    log_oom_and_exit();
  }
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L8:
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  xor    %eax,%eax
  call   <log_oom_and_exit@plt>
  jmp    L8
```

assistant: ```c
char *xstrdup(const char *s) {
  char *p;
  p = strdup(s);
  if (!p) {
    log_oom_and_exit();
  }
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L12
  negl   -0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jg     L20
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  jmp    L22
L20:
  mov    -0x4(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%ecx
L22:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %cl,(%rax)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L12
  cmpl   $0x0,-0x8(%rbp)
  jns    L9
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <Reverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void itob(int n, char s[], int b) {
  void Reverse(char s[]);
  int yu;
  int i = 0;
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    yu = n % b;
    s[i++] = (yu <= 9) ? yu + '0' : yu + 'a' - 10;
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  Reverse(s);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itob>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r11d
  mov    %rsi,%r10
  mov    %edx,%esi
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    %r10,%rdi
  mov    $0x0,%r9d
  jmp    L2
L29:
  mov    %r8d,%r9d
L2:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  lea    0x30(%rdx),%r8d
  lea    0x57(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %r8d,%eax
  lea    0x1(%r9),%r8d
  mov    %al,(%rdi)
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  add    $0x1,%rdi
  test   %eax,%eax
  jg     L29
  test   %r11d,%r11d
  js     L10
L27:
  movslq %r8d,%r8
  movb   $0x0,(%r10,%r8,1)
  mov    %r10,%rdi
  call   <Reverse@plt>
  add    $0x8,%rsp
  ret
L10:
  movslq %r8d,%r8
  movb   $0x2d,(%r10,%r8,1)
  lea    0x2(%r9),%r8d
  jmp    L27
```

assistant: ```c
void itob(int n, char s[], int b) {
  void Reverse(char s[]);
  int yu;
  int i = 0;
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    yu = n % b;
    s[i++] = (yu <= 9) ? yu + '0' : yu + 'a' - 10;
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  Reverse(s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<itob>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%r8
  mov    %edx,%edi
  mov    %r9d,%eax
  neg    %eax
  cmovs  %r9d,%eax
  xor    %r10d,%r10d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %edx,%r10d
L22:
  cltd
  idiv   %edi
  cmp    $0x9,%edx
  lea    0x30(%rdx),%r11d
  lea    0x57(%rdx),%ecx
  cmovle %r11d,%ecx
  lea    0x1(%r10),%edx
  add    $0x1,%rsi
  mov    %cl,-0x1(%rsi)
  test   %eax,%eax
  jg     L29
  test   %r9d,%r9d
  jns    L8
  movslq %edx,%rdx
  movb   $0x2d,(%r8,%rdx,1)
  lea    0x2(%r10),%edx
L8:
  movslq %edx,%rdx
  mov    %r8,%rdi
  movb   $0x0,(%r8,%rdx,1)
  jmp    1050 <Reverse@plt>
```

assistant: ```c
void itob(int n, char s[], int b) {
  void Reverse(char s[]);
  int yu;
  int i = 0;
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    yu = n % b;
    s[i++] = (yu <= 9) ? yu + '0' : yu + 'a' - 10;
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  Reverse(s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<itob>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%r8
  mov    %edx,%edi
  mov    %rsi,%rcx
  mov    %r9d,%eax
  neg    %eax
  cmovs  %r9d,%eax
  xor    %r10d,%r10d
  jmp    L35
  nopl   (%rax)
L7:
  add    $0x30,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  test   %eax,%eax
  jle    L31
L8:
  mov    %esi,%r10d
L35:
  cltd
  lea    0x1(%r10),%esi
  idiv   %edi
  cmp    $0x9,%edx
  jle    L7
  add    $0x57,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  test   %eax,%eax
  jg     L8
L31:
  test   %r9d,%r9d
  jns    L22
  movslq %esi,%rsi
  movb   $0x2d,(%r8,%rsi,1)
  lea    0x2(%r10),%esi
L22:
  movslq %esi,%rsi
  mov    %r8,%rdi
  movb   $0x0,(%r8,%rsi,1)
  jmp    1050 <Reverse@plt>
```

assistant: ```c
void itob(int n, char s[], int b) {
  void Reverse(char s[]);
  int yu;
  int i = 0;
  int sign;
  if ((sign = n) < 0)
    n = -n;
  do {
    yu = n % b;
    s[i++] = (yu <= 9) ? yu + '0' : yu + 'a' - 10;
  } while ((n /= b) > 0);
  if (sign < 0)
    s[i++] = '-';
  s[i] = '\0';
  Reverse(s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<emit_cmppl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0xfffffffe,%esi
  mov    %eax,%edi
  call   <emit_andimm@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <emit_cmpimm@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_orrgt_imm@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_cmppl(int s, int sr, int temp) {
  assert(temp >= 0);
  emit_andimm(sr, ~1, sr);
  emit_cmpimm(s, 0);
  emit_orrgt_imm(sr, 1, sr);
}
```
user: What is the c source code of the assembly code below:

```asm
<emit_cmppl>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  not    %edx
  mov    %edx,%edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %ebx,%edx
  mov    $0xfffffffe,%esi
  mov    %ebx,%edi
  call   <emit_andimm@plt>
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <emit_cmpimm@plt>
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <emit_orrgt_imm@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void emit_cmppl(int s, int sr, int temp) {
  assert(temp >= 0);
  emit_andimm(sr, ~1, sr);
  emit_cmpimm(s, 0);
  emit_orrgt_imm(sr, 1, sr);
}
```
user: Translate the below assembly code into C programming language:

```asm
<emit_cmppl>:
  endbr64
  push   %r12
  not    %edx
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%edi
  mov    %esi,%ebp
  shr    $0x1f,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0xfffffffe,%esi
  call   <emit_andimm@plt>
  mov    %r12d,%edi
  xor    %esi,%esi
  call   <emit_cmpimm@plt>
  add    $0x8,%rsp
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  jmp    10b0 <emit_orrgt_imm@plt>
```

assistant: ```c
void emit_cmppl(int s, int sr, int temp) {
  assert(temp >= 0);
  emit_andimm(sr, ~1, sr);
  emit_cmpimm(s, 0);
  emit_orrgt_imm(sr, 1, sr);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<emit_cmppl>:
  endbr64
  push   %r12
  not    %edx
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%edi
  mov    %esi,%ebp
  shr    $0x1f,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0xfffffffe,%esi
  call   <emit_andimm@plt>
  mov    %r12d,%edi
  xor    %esi,%esi
  call   <emit_cmpimm@plt>
  add    $0x8,%rsp
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbp
  pop    %r12
  jmp    10b0 <emit_orrgt_imm@plt>
```

assistant: ```c
void emit_cmppl(int s, int sr, int temp) {
  assert(temp >= 0);
  emit_andimm(sr, ~1, sr);
  emit_cmpimm(s, 0);
  emit_orrgt_imm(sr, 1, sr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
_Bool chk(unsigned long addr, unsigned long limit, unsigned long size) {
  _Bool ret;
  if (0)
    ret = 0 != (!!(addr > limit - size));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chk>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
_Bool chk(unsigned long addr, unsigned long limit, unsigned long size) {
  _Bool ret;
  if (0)
    ret = 0 != (!!(addr > limit - size));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chk>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
_Bool chk(unsigned long addr, unsigned long limit, unsigned long size) {
  _Bool ret;
  if (0)
    ret = 0 != (!!(addr > limit - size));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chk>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
_Bool chk(unsigned long addr, unsigned long limit, unsigned long size) {
  _Bool ret;
  if (0)
    ret = 0 != (!!(addr > limit - size));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L3
L8:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  sub    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jbe    L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t checksum(uint8_t *data) {
  uint8_t i, crc = 0;
  for (i = 0; i <= data[0]; i++) {
    crc -= data[i];
  }
  return crc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<checksum>:
  endbr64
  mov    (%rdi),%rax
  lea    0x8(%rdi,%rax,8),%rdx
  mov    $0x0,%eax
L4:
  sub    (%rdi),%rax
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L4
  ret
```

assistant: ```c
uint8_t checksum(uint8_t *data) {
  uint8_t i, crc = 0;
  for (i = 0; i <= data[0]; i++) {
    crc -= data[i];
  }
  return crc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checksum>:
  endbr64
  mov    (%rdi),%rdx
  add    $0x8,%rdi
  xor    %eax,%eax
  lea    (%rdi,%rdx,8),%rcx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%rdi),%rdx
  add    $0x8,%rdi
L16:
  sub    %rdx,%rax
  cmp    %rcx,%rdi
  jne    L17
  ret
```

assistant: ```c
uint8_t checksum(uint8_t *data) {
  uint8_t i, crc = 0;
  for (i = 0; i <= data[0]; i++) {
    crc -= data[i];
  }
  return crc;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<checksum>:
  endbr64
  mov    (%rdi),%rdx
  lea    0x1(%rdx),%rcx
  test   %rdx,%rdx
  je     L21
  mov    %rcx,%rdx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    %rdx
  shl    $0x4,%rdx
  add    %rdi,%rdx
  nopl   0x0(%rax)
L2:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  psubq  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L2
  movdqa %xmm0,%xmm1
  mov    %rcx,%rdx
  psrldq $0x8,%xmm1
  and    $0xfffffffffffffffe,%rdx
  and    $0x1,%ecx
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rax
  je     L8
  sub    (%rdi,%rdx,8),%rax
  ret
  nopl   0x0(%rax)
L8:
  ret
  nopl   0x0(%rax)
L21:
  xor    %eax,%eax
  sub    (%rdi,%rdx,8),%rax
  ret
```

assistant: ```c
uint8_t checksum(uint8_t *data) {
  uint8_t i, crc = 0;
  for (i = 0; i <= data[0]; i++) {
    crc -= data[i];
  }
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x270f,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assume@plt>
  cmpl   $0x186a0,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assume@plt>
  jmp    L15
L2:
  addl   $0x1,-0xc(%rbp)
  addl   $0x2,-0x8(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  i = 0;
  j = 0;
  int n;
  assume(n >= 10000);
  assume(n <= 100000);
  while (i < n) {
    i = i + 1;
    j = j + 2;
  }
  assert(j == n * 2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assume@plt>
  mov    $0x0,%eax
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  i = 0;
  j = 0;
  int n;
  assume(n >= 10000);
  assume(n <= 100000);
  while (i < n) {
    i = i + 1;
    j = j + 2;
  }
  assert(j == n * 2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  i = 0;
  j = 0;
  int n;
  assume(n >= 10000);
  assume(n <= 100000);
  while (i < n) {
    i = i + 1;
    j = j + 2;
  }
  assert(j == n * 2);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  i = 0;
  j = 0;
  int n;
  assume(n >= 10000);
  assume(n <= 100000);
  while (i < n) {
    i = i + 1;
    j = j + 2;
  }
  assert(j == n * 2);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
L3:
  jmp    L3
```

assistant: ```c
void _exit(int val) {
  while (1)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_exit>:
  endbr64
L1:
  jmp    L1
```

assistant: ```c
void _exit(int val) {
  while (1)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void _exit(int val) {
  while (1)
    ;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_exit>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
void _exit(int val) {
  while (1)
    ;
}
```