ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<read_all>:
  endbr64
  test   %edx,%edx
  jle    L20
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L29
  xchg   %ax,%ax
L30:
  add    %eax,%ebx
  cmp    %ebx,%ebp
  jle    L15
L29:
  mov    %ebp,%edx
  movslq %ebx,%rax
  mov    %r12d,%edi
  sub    %ebx,%edx
  lea    0x0(%r13,%rax,4),%rsi
  call   <read@plt>
  cmp    $0xffffffff,%eax
  jne    L30
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int read_all(int fd, uint8_t *buff, int size) {
  int n, sent;
  for (sent = 0; sent < size; sent += n)
    if ((n = read(fd, buff + sent, size - sent)) == -1)
      return -1;
  return sent;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<syserr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: Exit 
 

assistant: ```c
void syserr(char *s) {
  printf("Exit \n ");
  perror(s);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<syserr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
datatype: string

tool: D2: Exit 
 

assistant: ```c
void syserr(char *s) {
  printf("Exit \n ");
  perror(s);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<syserr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D1
data_type: string

tool: D1: Exit 
 

assistant: ```c
void syserr(char *s) {
  printf("Exit \n ");
  perror(s);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<syserr>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: Exit 
 

assistant: ```c
void syserr(char *s) {
  printf("Exit \n ");
  perror(s);
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<math_pow10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  fld1
  fstpt  -0x10(%rbp)
  jmp    L19
L6:
  fldt   -0x10(%rbp)
  fldt   0xeec(%rip)        # 2000 <_fini+0xed8>
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L19:
  cmpl   $0x0,-0x14(%rbp)
  jg     L6
  fldt   -0x10(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
long double math_pow10(int exponent) {
  long double result = 1;
  while (exponent > 0) {
    result *= 10;
    exponent--;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<math_pow10>:
  endbr64
  test   %edi,%edi
  jle    L19
  fld1
  flds   0xef7(%rip)        # 2000 <_fini+0xee8>
L2:
  fmul   %st,%st(1)
  sub    $0x1,%edi
  jne    L2
  fstp   %st(0)
  ret
L19:
  fld1
  ret
```

assistant: ```c
long double math_pow10(int exponent) {
  long double result = 1;
  while (exponent > 0) {
    result *= 10;
    exponent--;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<math_pow10>:
  endbr64
  fld1
  test   %edi,%edi
  jle    L12
  flds   0xef0(%rip)        # 2000 <_fini+0xedc>
L0:
  fmul   %st,%st(1)
  sub    $0x1,%edi
  jne    L0
  fstp   %st(0)
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

assistant: ```c
long double math_pow10(int exponent) {
  long double result = 1;
  while (exponent > 0) {
    result *= 10;
    exponent--;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<math_pow10>:
  endbr64
  fld1
  test   %edi,%edi
  jle    L2
  flds   0xef0(%rip)        # 2000 <_fini+0xedc>
L14:
  fmul   %st,%st(1)
  sub    $0x1,%edi
  jne    L14
  fstp   %st(0)
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
long double math_pow10(int exponent) {
  long double result = 1;
  while (exponent > 0) {
    result *= 10;
    exponent--;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add_strcut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int add_strcut(struct {
  int x;
  int y;
} a) {
  return a.x + a.y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add_strcut>:
  endbr64
  mov    %rdi,%rax
  shr    $0x20,%rax
  lea    (%rax,%rdi,1),%eax
  ret
```

assistant: ```c
int add_strcut(struct {
  int x;
  int y;
} a) {
  return a.x + a.y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_strcut>:
  endbr64
  mov    %rdi,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  ret
```

assistant: ```c
int add_strcut(struct {
  int x;
  int y;
} a) {
  return a.x + a.y;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<add_strcut>:
  endbr64
  mov    %rdi,%rax
  shr    $0x20,%rax
  add    %edi,%eax
  ret
```

assistant: ```c
int add_strcut(struct {
  int x;
  int y;
} a) {
  return a.x + a.y;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L16:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  add    %edx,%edx
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <sprintf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L16
  lea    D3(%rip),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D25
type: string

tool: D25: %02x

assistant: ```c
char *pt(unsigned char *md, unsigned int len) {
  unsigned int i;
  static char buf[80];
  for (i = 0; i < len; i++)
    sprintf(&(buf[i * 2]), "%02x", md[i]);
  return (buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pt>:
  endbr64
  test   %esi,%esi
  je     L12
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D7(%rip),%r14
  lea    D28(%rip),%r13
L6:
  movzbl (%r12,%rbx,1),%edx
  lea    (%rbx,%rbx,1),%edi
  mov    %edi,%edi
  add    %r14,%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
  lea    D7(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D28
data_type: string

tool: D28: %02x

assistant: ```c
char *pt(unsigned char *md, unsigned int len) {
  unsigned int i;
  static char buf[80];
  for (i = 0; i < len; i++)
    sprintf(&(buf[i * 2]), "%02x", md[i]);
  return (buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L2
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    D18(%rip),%r13
  xor    %r14d,%r14d
  cs nopw 0x0(%rax,%rax,1)
L18:
  movzbl 0x0(%rbp,%r14,1),%edx
  lea    (%r14,%r14,1),%edi
  mov    %r13,%rsi
  add    $0x1,%r14
  add    %r12,%rdi
  call   <sprintf@plt>
  cmp    %r14,%rbx
  jne    L18
L2:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
type: string

tool: D18: %02x

assistant: ```c
char *pt(unsigned char *md, unsigned int len) {
  unsigned int i;
  static char buf[80];
  for (i = 0; i < len; i++)
    sprintf(&(buf[i * 2]), "%02x", md[i]);
  return (buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  je     L0
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    D17(%rip),%r13
  xor    %r14d,%r14d
  cs nopw 0x0(%rax,%rax,1)
L12:
  movzbl 0x0(%rbp,%r14,1),%edx
  lea    (%r14,%r14,1),%edi
  mov    %r13,%rsi
  add    $0x1,%r14
  add    %r12,%rdi
  call   <sprintf@plt>
  cmp    %r14,%rbx
  jne    L12
L0:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type_guessed: string

tool: D17: %02x

assistant: ```c
char *pt(unsigned char *md, unsigned int len) {
  unsigned int i;
  static char buf[80];
  for (i = 0; i < len; i++)
    sprintf(&(buf[i * 2]), "%02x", md[i]);
  return (buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solo5_app_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D12(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D98(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movups -0x10(%rbp),%xmm1
  mulps  %xmm1,%xmm1
  movups %xmm1,-0x10(%rbp)
  movss  D97(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  D98(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x18(%rbp),%xmm0
  mulss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  -0x18(%rbp),%xmm0
  ucomiss D110(%rip),%xmm0
  jp     L18
  movss  -0x18(%rbp),%xmm0
  ucomiss D110(%rip),%xmm0
  jne    L18
  movss  -0x10(%rbp),%xmm0
  ucomiss D86(%rip),%xmm0
  jp     L18
  ucomiss D86(%rip),%xmm0
  jne    L18
  movss  -0xc(%rbp),%xmm0
  ucomiss D24(%rip),%xmm0
  jp     L18
  ucomiss D24(%rip),%xmm0
  jne    L18
  lea    D113(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L5
L18:
  mov    $0x1,%eax
L5:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D45
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: f32
name: retrieve_data
arguments: data_label: D98
type_infered: f32
name: retrieve_data
arguments: data_label: D97
type_infered: f32
name: retrieve_data
arguments: data_label: D110
type_infered: f32
name: retrieve_data
arguments: data_label: D86
type_infered: f32
name: retrieve_data
arguments: data_label: D24
type_infered: f32
name: retrieve_data
arguments: data_label: D113
type_infered: string

tool: D45: 
**** Solo5 standalone test_fpu ****



tool: D12: 2

tool: D98: 5

tool: D97: 1.5

tool: D110: 7.5

tool: D86: 4

tool: D24: 25

tool: D113: SUCCESS


assistant: ```c
int solo5_app_main(const struct solo5_start_info *si __attribute__((unused))) {
  puts("\n**** Solo5 standalone test_fpu ****\n\n");
  float a, b, c[2];
  c[0] = 2.0;
  c[1] = 5.0;
  __asm__("movups %0,%%xmm1;"
          "mulps %%xmm1, %%xmm1;"
          "movups %%xmm1, %0"
          : "=m"(c)
          : "m"(c)
          : "xmm1");
  a = 1.5;
  b = 5.0;
  a *= b;
  if (a == 7.5 && c[0] == 4.0 && c[1] == 25.0)
    puts("SUCCESS\n");
  else
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<solo5_app_main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <puts@plt>
  movl   $0x40000000,(%rsp)
  movl   $0x40a00000,0x4(%rsp)
  movups (%rsp),%xmm1
  mulps  %xmm1,%xmm1
  movups %xmm1,(%rsp)
  movss  (%rsp),%xmm0
  ucomiss D7(%rip),%xmm0
  jp     L45
  jne    L45
  movss  0x4(%rsp),%xmm0
  ucomiss D24(%rip),%xmm0
  jp     L53
  je     L25
L53:
  mov    $0x1,%eax
  jmp    L30
L25:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L30
L45:
  mov    $0x1,%eax
L30:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
type: string
name: parse_data
arguments: tag: D7
type: f32
name: parse_data
arguments: tag: D24
type: f32
name: parse_data
arguments: tag: D12
type: string

tool: D23: 
**** Solo5 standalone test_fpu ****



tool: D7: 4

tool: D24: 25

tool: D12: SUCCESS


assistant: ```c
int solo5_app_main(const struct solo5_start_info *si __attribute__((unused))) {
  puts("\n**** Solo5 standalone test_fpu ****\n\n");
  float a, b, c[2];
  c[0] = 2.0;
  c[1] = 5.0;
  __asm__("movups %0,%%xmm1;"
          "mulps %%xmm1, %%xmm1;"
          "movups %%xmm1, %0"
          : "=m"(c)
          : "m"(c)
          : "xmm1");
  a = 1.5;
  b = 5.0;
  a *= b;
  if (a == 7.5 && c[0] == 4.0 && c[1] == 25.0)
    puts("SUCCESS\n");
  else
    return 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<solo5_app_main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  movabs $0x40a0000040000000,%rax
  mov    %rax,(%rsp)
  movups (%rsp),%xmm1
  mulps  %xmm1,%xmm1
  movups %xmm1,(%rsp)
  movss  (%rsp),%xmm0
  ucomiss D5(%rip),%xmm0
  jp     L44
  jne    L44
  movss  0x4(%rsp),%xmm0
  ucomiss D20(%rip),%xmm0
  jp     L44
  je     L22
L44:
  mov    $0x1,%eax
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L27
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D5
datatype: f32
name: retrieve_data
arguments: label: D20
datatype: f32
name: retrieve_data
arguments: label: D25
datatype: string

tool: D17: 
**** Solo5 standalone test_fpu ****



tool: D5: 4

tool: D20: 25

tool: D25: SUCCESS


assistant: ```c
int solo5_app_main(const struct solo5_start_info *si __attribute__((unused))) {
  puts("\n**** Solo5 standalone test_fpu ****\n\n");
  float a, b, c[2];
  c[0] = 2.0;
  c[1] = 5.0;
  __asm__("movups %0,%%xmm1;"
          "mulps %%xmm1, %%xmm1;"
          "movups %%xmm1, %0"
          : "=m"(c)
          : "m"(c)
          : "xmm1");
  a = 1.5;
  b = 5.0;
  a *= b;
  if (a == 7.5 && c[0] == 4.0 && c[1] == 25.0)
    puts("SUCCESS\n");
  else
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<solo5_app_main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    D30(%rip),%rax
  mov    %rax,(%rsp)
  movups (%rsp),%xmm1
  mulps  %xmm1,%xmm1
  movups %xmm1,(%rsp)
  movss  (%rsp),%xmm0
  ucomiss D23(%rip),%xmm0
  jp     L58
  jne    L58
  movss  0x4(%rsp),%xmm0
  ucomiss D3(%rip),%xmm0
  jp     L58
  je     L29
L58:
  mov    $0x1,%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L29:
  lea    D46(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L28
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D31
data_type: string
name: parse_data
arguments: data_label: D30
data_type: f32[2]
name: parse_data
arguments: data_label: D23
data_type: f32
name: parse_data
arguments: data_label: D3
data_type: f32
name: parse_data
arguments: data_label: D46
data_type: string

tool: D31: 
**** Solo5 standalone test_fpu ****



tool: {"D30": [2.0,5.0]}

tool: D23: 4

tool: D3: 25

tool: D46: SUCCESS


assistant: ```c
int solo5_app_main(const struct solo5_start_info *si __attribute__((unused))) {
  puts("\n**** Solo5 standalone test_fpu ****\n\n");
  float a, b, c[2];
  c[0] = 2.0;
  c[1] = 5.0;
  __asm__("movups %0,%%xmm1;"
          "mulps %%xmm1, %%xmm1;"
          "movups %%xmm1, %0"
          : "=m"(c)
          : "m"(c)
          : "xmm1");
  a = 1.5;
  b = 5.0;
  a *= b;
  if (a == 7.5 && c[0] == 4.0 && c[1] == 25.0)
    puts("SUCCESS\n");
  else
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_until>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x38(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L55:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L32
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L55
L32:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  ja     L36
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  je     L8
L36:
  mov    $0xffffffffffffffff,%rax
  jmp    L41
L8:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L41:
  leave
  ret
```

assistant: ```c
ssize_t copy_until(char *dest, const char *src, size_t size, char delim, const char **end) {
  const char *cur = src;
  ssize_t len = 0;
  while (*cur && *cur != delim) {
    cur++;
    len++;
  }
  if (len > size - 1 || *cur != delim) {
    return -1;
  }
  *end = cur + 1;
  strncpy(dest, src, len);
  dest[len] = '\0';
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_until>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r9
  movzbl (%rsi),%eax
  cmp    %cl,%al
  je     L29
  mov    %ecx,%edi
  test   %al,%al
  je     L29
  mov    $0x0,%ebx
L38:
  add    $0x1,%rsi
  add    $0x1,%rbx
  movzbl (%rsi),%eax
  cmp    %dil,%al
  je     L76
  test   %al,%al
  jne    L38
L76:
  sub    $0x1,%rdx
  cmp    %rbx,%rdx
  jb     L34
  cmp    %cl,%al
  jne    L34
  add    $0x1,%rsi
  mov    %rsi,(%r8)
  mov    %rbx,%rdx
  mov    %r9,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L9
L29:
  mov    %r9,%rsi
  mov    $0x0,%ebx
  jmp    L76
L34:
  mov    $0xffffffffffffffff,%rbx
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
ssize_t copy_until(char *dest, const char *src, size_t size, char delim, const char **end) {
  const char *cur = src;
  ssize_t len = 0;
  while (*cur && *cur != delim) {
    cur++;
    len++;
  }
  if (len > size - 1 || *cur != delim) {
    return -1;
  }
  *end = cur + 1;
  strncpy(dest, src, len);
  dest[len] = '\0';
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_until>:
  endbr64
  push   %r12
  mov    %rsi,%r9
  sub    $0x1,%rdx
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  mov    %ecx,%edi
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L22
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%r12
  test   %al,%al
  je     L57
L22:
  cmp    %al,%dil
  jne    L6
L57:
  cmp    %rdx,%r12
  seta   %dl
L11:
  cmp    %cl,%al
  jne    L8
  test   %dl,%dl
  jne    L8
  add    $0x1,%rsi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    %rsi,(%r8)
  mov    %r9,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L8:
  mov    $0xffffffffffffffff,%r12
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L16:
  xor    %edx,%edx
  jmp    L11
```

assistant: ```c
ssize_t copy_until(char *dest, const char *src, size_t size, char delim, const char **end) {
  const char *cur = src;
  ssize_t len = 0;
  while (*cur && *cur != delim) {
    cur++;
    len++;
  }
  if (len > size - 1 || *cur != delim) {
    return -1;
  }
  *end = cur + 1;
  strncpy(dest, src, len);
  dest[len] = '\0';
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_until>:
  endbr64
  push   %r12
  mov    %rsi,%r9
  sub    $0x1,%rdx
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  mov    %ecx,%edi
  sub    $0x8,%rsp
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L67
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%r12
  test   %al,%al
  je     L39
L67:
  cmp    %al,%dil
  jne    L44
L39:
  cmp    %rdx,%r12
  seta   %dl
L62:
  cmp    %cl,%al
  jne    L34
  test   %dl,%dl
  jne    L34
  add    $0x1,%rsi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  mov    %rsi,(%r8)
  mov    %r9,%rsi
  call   <strncpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L34:
  mov    $0xffffffffffffffff,%r12
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L25:
  xor    %edx,%edx
  jmp    L62
```

assistant: ```c
ssize_t copy_until(char *dest, const char *src, size_t size, char delim, const char **end) {
  const char *cur = src;
  ssize_t len = 0;
  while (*cur && *cur != delim) {
    cur++;
    len++;
  }
  if (len > size - 1 || *cur != delim) {
    return -1;
  }
  *end = cur + 1;
  strncpy(dest, src, len);
  dest[len] = '\0';
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D8(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: test1234/

assistant: ```c
int main() {
  char *arg = "test1234/";
  test(arg, __builtin_strlen(arg));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <__builtin_strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: test1234/

assistant: ```c
int main() {
  char *arg = "test1234/";
  test(arg, __builtin_strlen(arg));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <__builtin_strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <test@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: test1234/

assistant: ```c
int main() {
  char *arg = "test1234/";
  test(arg, __builtin_strlen(arg));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  mov    %rbp,%rdi
  call   <__builtin_strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <test@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: test1234/

assistant: ```c
int main() {
  char *arg = "test1234/";
  test(arg, __builtin_strlen(arg));
  return 0;
}
```