ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    $0x4,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    (%rsp),%rdx
  mov    %rsp,%rsi
  mov    0x8(%rsp),%rcx
  mov    %rax,0x10(%rsp)
  lea    D15(%rip),%rdi
  movl   $0xa,(%rdx)
  movl   $0x14,(%rcx)
  mov    (%rdx),%edx
  lea    0x10(%rsp),%rcx
  add    $0x14,%edx
  mov    %edx,(%rax)
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rcx
  mov    (%rsp),%rsi
  xor    %eax,%eax
  mov    0x8(%rsp),%rdx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x10(%rsp),%rax
  lea    D27(%rip),%rdi
  mov    (%rax),%ecx
  mov    0x8(%rsp),%rax
  mov    (%rax),%edx
  mov    (%rsp),%rax
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D8
type: string
name: parse_data
arguments: data_tag: D27
type: string

tool: D15: address of p1 = %p, p2 = %p, p3 = %p


tool: D8: address pointed by p1 = %p, p2 = %p, p3 = %p


tool: D27: value at address pointed by p1 = %d, p2 = %d, p3 = %d


assistant: ```c
int main() {
  int *p1 = malloc(sizeof(int));
  int *p2 = malloc(sizeof(int));
  int *p3 = malloc(sizeof(int));
  *p1 = 10;
  *p2 = 20;
  *p3 = *p1 + *p2;
  printf("address of p1 = %p, p2 = %p, p3 = %p\n", &p1, &p2, &p3);
  printf("address pointed by p1 = %p, p2 = %p, p3 = %p\n", p1, p2, p3);
  printf("value at address pointed by p1 = %d, p2 = %d, p3 = %d\n", *p1, *p2, *p3);
  free(p1);
  free(p2);
  free(p3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Kill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <kill@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L1
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <Sys_failure@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: kill

assistant: ```c
void Kill(pid_t pid, int sig) {
  int retval;
  retval = kill(pid, sig);
  if (retval == -1)
    Sys_failure("kill");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Kill>:
  endbr64
  sub    $0x8,%rsp
  call   <kill@plt>
  cmp    $0xffffffff,%eax
  je     L6
L11:
  add    $0x8,%rsp
  ret
L6:
  lea    D9(%rip),%rdi
  call   <Sys_failure@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: kill

assistant: ```c
void Kill(pid_t pid, int sig) {
  int retval;
  retval = kill(pid, sig);
  if (retval == -1)
    Sys_failure("kill");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Kill>:
  endbr64
  sub    $0x8,%rsp
  call   <kill@plt>
  cmp    $0xffffffff,%eax
  je     L2
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Sys_failure@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string

tool: D5: kill

assistant: ```c
void Kill(pid_t pid, int sig) {
  int retval;
  retval = kill(pid, sig);
  if (retval == -1)
    Sys_failure("kill");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Kill>:
  endbr64
  sub    $0x8,%rsp
  call   <kill@plt>
  cmp    $0xffffffff,%eax
  je     L7
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <Sys_failure@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
type: string

tool: D6: kill

assistant: ```c
void Kill(pid_t pid, int sig) {
  int retval;
  retval = kill(pid, sig);
  if (retval == -1)
    Sys_failure("kill");
}
```
user: Translate the below assembly code into C programming language:

```asm
<c6_to_8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  andl   $0x3f,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  or     %edx,%eax
  or     -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int c6_to_8(int v) {
  int b;
  v &= 0x3f;
  b = v & 1;
  return (v << 2) | (b << 1) | b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<c6_to_8>:
  endbr64
  mov    %edi,%edx
  and    $0x1,%edx
  lea    0x0(,%rdi,4),%eax
  movzbl %al,%eax
  lea    (%rdx,%rdx,1),%ecx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int c6_to_8(int v) {
  int b;
  v &= 0x3f;
  b = v & 1;
  return (v << 2) | (b << 1) | b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<c6_to_8>:
  endbr64
  mov    %edi,%edx
  lea    0x0(,%rdi,4),%eax
  and    $0x1,%edx
  movzbl %al,%eax
  lea    (%rdx,%rdx,1),%ecx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int c6_to_8(int v) {
  int b;
  v &= 0x3f;
  b = v & 1;
  return (v << 2) | (b << 1) | b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<c6_to_8>:
  endbr64
  mov    %edi,%edx
  lea    0x0(,%rdi,4),%eax
  and    $0x1,%edx
  movzbl %al,%eax
  lea    (%rdx,%rdx,1),%ecx
  or     %ecx,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int c6_to_8(int v) {
  int b;
  v &= 0x3f;
  b = v & 1;
  return (v << 2) | (b << 1) | b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<err_quit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_quit(const char *err) {
  printf(err);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<err_quit>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void err_quit(const char *err) {
  printf(err);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<err_quit>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_quit(const char *err) {
  printf(err);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<err_quit>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_quit(const char *err) {
  printf(err);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<CheckResult>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L121
  mov    $0x0,%eax
  jmp    L66
L121:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jg     L12
  mov    $0x0,%eax
  jmp    L66
L12:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L69
L97:
  mov    -0x10(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L66
L10:
  mov    -0x8(%rbp),%rax
  mov    $0x26,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L83
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L123
  mov    $0x1,%eax
  jmp    L66
L123:
  mov    $0x0,%eax
  jmp    L66
L83:
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  cmp    $0x1,%rax
  jle    L102
  mov    $0x1,%eax
  jmp    L66
L102:
  addq   $0x1,-0x10(%rbp)
L69:
  cmpl   $0x0,-0x14(%rbp)
  je     L97
  mov    $0x0,%eax
L66:
  leave
  ret
```

assistant: ```c
int CheckResult(char *res) {
  char *s, *t;
  int done = 0;
  if (!res)
    return (0);
  if ((int)strlen(res) < 3)
    return (0);
  t = res;
  while (!done) {
    s = strchr(t, '=');
    if (!s)
      return (0);
    t = strchr(s, '&');
    if (!t) {
      if ((int)strlen(s) > 1)
        return (1);
      else
        return (0);
    } else {
      if (t - s > 1)
        return (1);
      t++;
    }
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CheckResult>:
  endbr64
  test   %rdi,%rdi
  je     L38
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    $0x2,%edx
  jle    L44
L31:
  mov    $0x3d,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L77
  mov    $0x26,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L78
  mov    %rax,%rdx
  sub    %rbx,%rdx
  cmp    $0x1,%rdx
  jg     L19
  lea    0x1(%rax),%rbx
  jmp    L31
L78:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  setg   %al
  movzbl %al,%eax
  jmp    L44
L77:
  mov    $0x0,%eax
L44:
  pop    %rbx
  ret
L38:
  mov    $0x0,%eax
  ret
L19:
  mov    $0x1,%eax
  jmp    L44
```

assistant: ```c
int CheckResult(char *res) {
  char *s, *t;
  int done = 0;
  if (!res)
    return (0);
  if ((int)strlen(res) < 3)
    return (0);
  t = res;
  while (!done) {
    s = strchr(t, '=');
    if (!s)
      return (0);
    t = strchr(s, '&');
    if (!t) {
      if ((int)strlen(s) > 1)
        return (1);
      else
        return (0);
    } else {
      if (t - s > 1)
        return (1);
      t++;
    }
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CheckResult>:
  endbr64
  test   %rdi,%rdi
  je     L44
  push   %rbp
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rdi
  cmp    $0x2,%eax
  jg     L4
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L41:
  mov    $0x26,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L57
  mov    %rax,%rdx
  sub    %rbp,%rdx
  cmp    $0x1,%rdx
  jg     L8
  lea    0x1(%rax),%rdi
L4:
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L41
L36:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L57:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  setg   %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  xor    %eax,%eax
  ret
```

assistant: ```c
int CheckResult(char *res) {
  char *s, *t;
  int done = 0;
  if (!res)
    return (0);
  if ((int)strlen(res) < 3)
    return (0);
  t = res;
  while (!done) {
    s = strchr(t, '=');
    if (!s)
      return (0);
    t = strchr(s, '&');
    if (!t) {
      if ((int)strlen(s) > 1)
        return (1);
      else
        return (0);
    } else {
      if (t - s > 1)
        return (1);
      t++;
    }
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CheckResult>:
  endbr64
  test   %rdi,%rdi
  je     L32
  push   %rbp
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    0x8(%rsp),%rdi
  cmp    $0x2,%eax
  jg     L13
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x26,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L34
  mov    %rax,%rdx
  sub    %rbp,%rdx
  cmp    $0x1,%rdx
  jg     L40
  lea    0x1(%rax),%rdi
L13:
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L6
L14:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax)
L34:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  setg   %al
  add    $0x10,%rsp
  movzbl %al,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
int CheckResult(char *res) {
  char *s, *t;
  int done = 0;
  if (!res)
    return (0);
  if ((int)strlen(res) < 3)
    return (0);
  t = res;
  while (!done) {
    s = strchr(t, '=');
    if (!s)
      return (0);
    t = strchr(s, '&');
    if (!t) {
      if ((int)strlen(s) > 1)
        return (1);
      else
        return (0);
    } else {
      if (t - s > 1)
        return (1);
      t++;
    }
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lib_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <SSL_library_init@plt>
  mov    $0x0,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  mov    $0x0,%eax
  call   <SSL_load_error_strings@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lib_init() {
  SSL_library_init();
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lib_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <SSL_library_init@plt>
  mov    $0x0,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  mov    $0x0,%eax
  call   <SSL_load_error_strings@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void lib_init() {
  SSL_library_init();
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lib_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SSL_library_init@plt>
  xor    %eax,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <SSL_load_error_strings@plt>
```

assistant: ```c
void lib_init() {
  SSL_library_init();
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lib_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <SSL_library_init@plt>
  xor    %eax,%eax
  call   <OpenSSL_add_all_algorithms@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <SSL_load_error_strings@plt>
```

assistant: ```c
void lib_init() {
  SSL_library_init();
  OpenSSL_add_all_algorithms();
  SSL_load_error_strings();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L3:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t cnt = 0;
  while (*s++ != '\0') {
    cnt++;
  }
  return cnt;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  mov    $0x0,%eax
L4:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L4
  ret
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t cnt = 0;
  while (*s++ != '\0') {
    cnt++;
  }
  return cnt;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L18
  nopl   0x0(%rax,%rax,1)
L16:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L16
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t cnt = 0;
  while (*s++ != '\0') {
    cnt++;
  }
  return cnt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L14
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L8
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t cnt = 0;
  while (*s++ != '\0') {
    cnt++;
  }
  return cnt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DIVIDER_32b_AUTOTEST>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L34:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_fudiv@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_fudiv@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L33
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L5
L33:
  addl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0x9,-0x14(%rbp)
  jle    L34
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D53
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D30
type_guessed: string
name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: string
name: disassemble_data
arguments: data_tag: D40
type_guessed: string

tool: D53: LAUNCHING THE (DIVIDER) RESOURCE TEST...

tool: D15: - TEST OF THE (DIVIDER) RESOURCE => FAILED !

tool: D30:   + %d COMPUTATION BEFORE ERROR... !


tool: D10:   + INSTRUCTION RESULT (%d l %d) => %d


tool: D16:   + C CODE RESULT      (%d l %d) => %d


tool: D40: - TEST OF THE (DIVIDER) RESOURCE => OK

assistant: ```c
int DIVIDER_32b_AUTOTEST() {
  int i, j;
  printf("LAUNCHING THE (DIVIDER) RESOURCE TEST...\n");
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 65536;
    int op2 = rand() % 65536;
    int res1 = instr_fudiv(op1, op2);
    int res3 = instr_fudiv(op1, op2);
    if (res1 != res3) {
      printf("- TEST OF THE (DIVIDER) RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op1, op2, res1);
      printf("  + C CODE RESULT      (%d l %d) => %d\n", op2, op1, res3);
      return 0;
    }
  }
  printf("- TEST OF THE (DIVIDER) RESOURCE => OK\n");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<DIVIDER_32b_AUTOTEST>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
L22:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  lea    (%rax,%rdx,1),%ebp
  movzwl %bp,%ebp
  sub    %edx,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  lea    (%rax,%rdx,1),%ebx
  movzwl %bx,%ebx
  sub    %edx,%ebx
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <instr_fudiv@plt>
  mov    %eax,%r14d
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <instr_fudiv@plt>
  mov    %eax,%r13d
  cmp    %eax,%r14d
  jne    L20
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L22
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14d,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L26
```

tool_calls: name: retrieve_data
arguments: data_tag: D36
type_infered: string
name: retrieve_data
arguments: data_tag: D16
type_infered: string
name: retrieve_data
arguments: data_tag: D59
type_infered: string
name: retrieve_data
arguments: data_tag: D19
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D12
type_infered: string

tool: D36: LAUNCHING THE (DIVIDER) RESOURCE TEST...

tool: D16: - TEST OF THE (DIVIDER) RESOURCE => OK

tool: D59: - TEST OF THE (DIVIDER) RESOURCE => FAILED !

tool: D19:   + %d COMPUTATION BEFORE ERROR... !


tool: D11:   + INSTRUCTION RESULT (%d l %d) => %d


tool: D12:   + C CODE RESULT      (%d l %d) => %d


assistant: ```c
int DIVIDER_32b_AUTOTEST() {
  int i, j;
  printf("LAUNCHING THE (DIVIDER) RESOURCE TEST...\n");
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 65536;
    int op2 = rand() % 65536;
    int res1 = instr_fudiv(op1, op2);
    int res3 = instr_fudiv(op1, op2);
    if (res1 != res3) {
      printf("- TEST OF THE (DIVIDER) RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op1, op2, res1);
      printf("  + C CODE RESULT      (%d l %d) => %d\n", op2, op1, res3);
      return 0;
    }
  }
  printf("- TEST OF THE (DIVIDER) RESOURCE => OK\n");
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<DIVIDER_32b_AUTOTEST>:
  endbr64
  push   %r15
  lea    D54(%rip),%rdi
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  call   <puts@plt>
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  lea    (%rax,%rdx,1),%r12d
  xor    %eax,%eax
  movzwl %r12w,%r12d
  sub    %edx,%r12d
  call   <rand@plt>
  mov    %r12d,%edi
  cltd
  shr    $0x10,%edx
  lea    (%rax,%rdx,1),%ebp
  movzwl %bp,%ebp
  sub    %edx,%ebp
  mov    %ebp,%esi
  call   <instr_fudiv@plt>
  mov    %ebp,%esi
  mov    %r12d,%edi
  mov    %eax,%r15d
  call   <instr_fudiv@plt>
  mov    %eax,%r14d
  cmp    %eax,%r15d
  jne    L4
  add    $0x1,%r13d
  cmp    $0xa,%r13d
  jne    L19
  lea    D13(%rip),%rdi
  call   <puts@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L4:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %r13d,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15d,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D54
type: string
name: parse_data
arguments: data_label: D13
type: string
name: parse_data
arguments: data_label: D15
type: string
name: parse_data
arguments: data_label: D28
type: string
name: parse_data
arguments: data_label: D23
type: string
name: parse_data
arguments: data_label: D57
type: string

tool: D54: LAUNCHING THE (DIVIDER) RESOURCE TEST...

tool: D13: - TEST OF THE (DIVIDER) RESOURCE => OK

tool: D15: - TEST OF THE (DIVIDER) RESOURCE => FAILED !

tool: D28:   + %d COMPUTATION BEFORE ERROR... !


tool: D23:   + INSTRUCTION RESULT (%d l %d) => %d


tool: D57:   + C CODE RESULT      (%d l %d) => %d


assistant: ```c
int DIVIDER_32b_AUTOTEST() {
  int i, j;
  printf("LAUNCHING THE (DIVIDER) RESOURCE TEST...\n");
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 65536;
    int op2 = rand() % 65536;
    int res1 = instr_fudiv(op1, op2);
    int res3 = instr_fudiv(op1, op2);
    if (res1 != res3) {
      printf("- TEST OF THE (DIVIDER) RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d l %d) => %d\n", op1, op2, res1);
      printf("  + C CODE RESULT      (%d l %d) => %d\n", op2, op1, res3);
      return 0;
    }
  }
  printf("- TEST OF THE (DIVIDER) RESOURCE => OK\n");
  return 1;
}
```