ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<make_string_palindrom>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L23
  mov    $0xffffffff,%eax
  jmp    L29
L23:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L16
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <make_string_palindrom>
  cmp    $0xffffffff,%eax
  jne    L38
  mov    -0xc(%rbp),%eax
  jmp    L29
L38:
  mov    -0x10(%rbp),%eax
  jmp    L29
L16:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <make_string_palindrom>
L29:
  leave
  ret
```

assistant: ```c
int make_string_palindrom(char *s, int i, int j) {
  if (i > j)
    return -1;
  if (s[i] != s[j]) {
    if (make_string_palindrom(s, i + 1, j) == -1)
      return i;
    else
      return j;
  } else
    return make_string_palindrom(s, i + 1, j - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_string_palindrom>:
  endbr64
  cmp    %edx,%esi
  jg     L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    %edx,%ebp
  movslq %esi,%rax
  movslq %edx,%rdx
  movzbl (%rdi,%rdx,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L21
  lea    0x1(%rsi),%esi
  mov    %ebp,%edx
  call   <make_string_palindrom>
  cmp    $0xffffffff,%eax
  mov    %ebp,%eax
  cmove  %ebx,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  lea    -0x1(%rbp),%edx
  lea    0x1(%rsi),%esi
  call   <make_string_palindrom>
  jmp    L15
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int make_string_palindrom(char *s, int i, int j) {
  if (i > j)
    return -1;
  if (s[i] != s[j]) {
    if (make_string_palindrom(s, i + 1, j) == -1)
      return i;
    else
      return j;
  } else
    return make_string_palindrom(s, i + 1, j - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<make_string_palindrom>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %edx,%esi
  jg     L43
  movslq %esi,%rsi
  movslq %edx,%rdx
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L63:
  add    $0x1,%rsi
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jl     L43
L76:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %edx,%ebx
  mov    %esi,%r12d
  lea    0x1(%rsi),%eax
  cmp    %cl,(%rdi,%rsi,1)
  je     L63
  cmp    %eax,%edx
  jl     L116
  cltq
  movslq %edx,%rdx
  jmp    L169
  nopl   0x0(%rax,%rax,1)
L75:
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%edx
  jl     L116
  movzbl (%rdi,%rdx,1),%ecx
L169:
  mov    %edx,%r13d
  mov    %eax,%ebp
  lea    0x1(%rax),%esi
  cmp    %cl,(%rdi,%rax,1)
  je     L75
  cmp    %esi,%edx
  jl     L91
  movslq %edx,%rdx
  movslq %esi,%rax
  jmp    L0
  nopl   0x0(%rax)
L50:
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %eax,%edx
  jl     L91
  movzbl (%rdi,%rdx,1),%ecx
L0:
  mov    %eax,%r15d
  mov    %edx,%r14d
  lea    0x1(%rax),%esi
  cmp    %cl,(%rdi,%rax,1)
  je     L50
  cmp    %esi,%edx
  jl     L114
  movslq %edx,%r8
  movslq %esi,%rax
  jmp    L105
  nopw   0x0(%rax,%rax,1)
L107:
  sub    $0x1,%r8
  add    $0x1,%rax
  cmp    %r8d,%eax
  jg     L114
  movzbl (%rdi,%r8,1),%ecx
L105:
  mov    %r8d,%edx
  lea    0x1(%rax),%esi
  cmp    %cl,(%rdi,%rax,1)
  je     L107
  mov    %r8,(%rsp)
  mov    %eax,0xc(%rsp)
  call   <make_string_palindrom>
  mov    (%rsp),%r8
  mov    0xc(%rsp),%r9d
  cmp    $0xffffffff,%eax
  cmovne %r8d,%r9d
  cmp    $0xffffffff,%r9d
  cmovne %r14d,%r15d
L114:
  cmp    $0xffffffff,%r15d
  cmovne %r13d,%ebp
L91:
  cmp    $0xffffffff,%ebp
  cmovne %ebx,%r12d
  jmp    L116
  nopl   0x0(%rax,%rax,1)
L43:
  mov    $0xffffffff,%r12d
L116:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int make_string_palindrom(char *s, int i, int j) {
  if (i > j)
    return -1;
  if (s[i] != s[j]) {
    if (make_string_palindrom(s, i + 1, j) == -1)
      return i;
    else
      return j;
  } else
    return make_string_palindrom(s, i + 1, j - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<make_string_palindrom>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %edx,%esi
  jg     L120
  movslq %esi,%rsi
  movslq %edx,%rdx
  jmp    L163
  nopw   0x0(%rax,%rax,1)
L88:
  add    $0x1,%rsi
  sub    $0x1,%rdx
  cmp    %esi,%edx
  jl     L120
L163:
  movzbl (%rdi,%rdx,1),%ecx
  mov    %edx,%ebx
  mov    %esi,%r12d
  lea    0x1(%rsi),%eax
  cmp    %cl,(%rdi,%rsi,1)
  je     L88
  cmp    %eax,%edx
  jl     L71
  cltq
  movslq %edx,%rdx
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L146:
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%edx
  jl     L71
  movzbl (%rdi,%rdx,1),%ecx
L38:
  mov    %edx,%r13d
  mov    %eax,%ebp
  lea    0x1(%rax),%esi
  cmp    %cl,(%rdi,%rax,1)
  je     L146
  cmp    %esi,%edx
  jl     L99
  movslq %edx,%rdx
  movslq %esi,%rax
  jmp    L13
  nopl   0x0(%rax)
L166:
  sub    $0x1,%rdx
  add    $0x1,%rax
  cmp    %eax,%edx
  jl     L99
  movzbl (%rdi,%rdx,1),%ecx
L13:
  mov    %eax,%r15d
  mov    %edx,%r14d
  lea    0x1(%rax),%esi
  cmp    %cl,(%rdi,%rax,1)
  je     L166
  cmp    %esi,%edx
  jl     L0
  movslq %edx,%rcx
  movslq %esi,%rax
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L46:
  sub    $0x1,%rcx
  add    $0x1,%rax
  cmp    %ecx,%eax
  jg     L0
L21:
  movzbl (%rdi,%rcx,1),%r9d
  mov    %ecx,%edx
  lea    0x1(%rax),%esi
  cmp    %r9b,(%rdi,%rax,1)
  je     L46
  mov    %rcx,0x8(%rsp)
  mov    %eax,0x4(%rsp)
  call   <make_string_palindrom>
  mov    0x4(%rsp),%r8d
  mov    0x8(%rsp),%rcx
  cmp    $0xffffffff,%eax
  cmovne %ecx,%r8d
  cmp    $0xffffffff,%r8d
  cmovne %r14d,%r15d
L0:
  cmp    $0xffffffff,%r15d
  cmovne %r13d,%ebp
L99:
  cmp    $0xffffffff,%ebp
  cmovne %ebx,%r12d
  jmp    L71
  nopl   0x0(%rax)
L120:
  mov    $0xffffffff,%r12d
L71:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int make_string_palindrom(char *s, int i, int j) {
  if (i > j)
    return -1;
  if (s[i] != s[j]) {
    if (make_string_palindrom(s, i + 1, j) == -1)
      return i;
    else
      return j;
  } else
    return make_string_palindrom(s, i + 1, j - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Cvar_Reset_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L15
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <Com_Printf@plt>
  jmp    L11
L15:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edi
  call   <Cvar_Reset@plt>
L11:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_guessed: string

tool: D5: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Cvar_Reset_f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L17
  lea    D1(%rip),%rdi
  call   <Com_Printf@plt>
L1:
  add    $0x8,%rsp
  ret
L17:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edi
  call   <Cvar_Reset@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Cvar_Reset_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L7
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <Com_Printf@plt>
  nopl   0x0(%rax)
L7:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    10b0 <Cvar_Reset@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cvar_Reset_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L0
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <Com_Printf@plt>
  nopl   0x0(%rax)
L0:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    10b0 <Cvar_Reset@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
data_type: string

tool: D3: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<refresh_TLB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  invlpg (%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void refresh_TLB(void *address) {
  __asm__ __volatile__("invlpg		(%0)\n" ::"a"(address));
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<refresh_TLB>:
  endbr64
  mov    %rdi,%rax
  invlpg (%rax)
  ret
```

assistant: ```c
void refresh_TLB(void *address) {
  __asm__ __volatile__("invlpg		(%0)\n" ::"a"(address));
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<refresh_TLB>:
  endbr64
  mov    %rdi,%rax
  invlpg (%rax)
  ret
```

assistant: ```c
void refresh_TLB(void *address) {
  __asm__ __volatile__("invlpg		(%0)\n" ::"a"(address));
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<refresh_TLB>:
  endbr64
  mov    %rdi,%rax
  invlpg (%rax)
  ret
```

assistant: ```c
void refresh_TLB(void *address) {
  __asm__ __volatile__("invlpg		(%0)\n" ::"a"(address));
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_mini_strtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L2
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
L2:
  mov    $0x0,%eax
  jmp    L11
L69:
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L63
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_mini_isspace@plt>
  test   %rax,%rax
  jne    L69
  jmp    L63
L50:
  subq   $0x1,-0x10(%rbp)
L63:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L65
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_mini_isspace@plt>
  test   %rax,%rax
  jne    L50
L65:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

assistant: ```c
size_t _mini_strtrim(char *str, size_t len) {
  char *start = str, *end = str + len - 1;
  size_t newlen;
  if (!(str && *str)) {
    return 0;
  }
  while (*start && _mini_isspace((int)*start)) {
    start++;
  }
  while (end > start && _mini_isspace((int)*end)) {
    end--;
  }
  *(++end) = '\0';
  newlen = (size_t)(end - start);
  memmove(str, start, newlen + 1);
  return newlen;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_mini_strtrim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L66
  mov    %rdi,%r12
  mov    %rsi,%r13
  movzbl (%rdi),%edi
  mov    $0x0,%ebx
  mov    %r12,%rbp
  test   %dil,%dil
  je     L12
L55:
  movsbl %dil,%edi
  call   <_mini_isspace@plt>
  test   %rax,%rax
  je     L31
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L55
L31:
  lea    -0x1(%r12,%r13,1),%rbx
  cmp    %rbp,%rbx
  jbe    L63
L25:
  movsbl (%rbx),%edi
  call   <_mini_isspace@plt>
  test   %rax,%rax
  je     L63
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L25
  mov    %rbp,%rbx
L63:
  movb   $0x0,0x1(%rbx)
  add    $0x1,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L12:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L66:
  mov    $0x0,%ebx
  jmp    L12
```

assistant: ```c
size_t _mini_strtrim(char *str, size_t len) {
  char *start = str, *end = str + len - 1;
  size_t newlen;
  if (!(str && *str)) {
    return 0;
  }
  while (*start && _mini_isspace((int)*start)) {
    start++;
  }
  while (end > start && _mini_isspace((int)*end)) {
    end--;
  }
  *(++end) = '\0';
  newlen = (size_t)(end - start);
  memmove(str, start, newlen + 1);
  return newlen;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_mini_strtrim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L96
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  xor    %r14d,%r14d
  test   %dil,%dil
  je     L5
  mov    %rsi,%r13
  mov    %r12,%rbp
  jmp    L49
  xchg   %ax,%ax
L16:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L109
L49:
  call   <_mini_isspace@plt>
  test   %rax,%rax
  jne    L16
L109:
  lea    -0x1(%r12,%r13,1),%r14
  cmp    %rbp,%r14
  ja     L77
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L98:
  lea    -0x1(%r14),%rax
  cmp    %rbp,%rax
  je     L6
  mov    %rax,%r14
L77:
  movsbl (%r14),%edi
  call   <_mini_isspace@plt>
  test   %rax,%rax
  jne    L98
  mov    %r14,%rax
  add    $0x1,%r14
L46:
  movb   $0x0,0x1(%rax)
  sub    %rbp,%r14
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%r14),%rdx
  call   <memmove@plt>
L5:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L6:
  mov    %rbp,%rax
  jmp    L46
  nopl   (%rax)
L96:
  add    $0x8,%rsp
  xor    %r14d,%r14d
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    %r14,%rax
  lea    (%r12,%r13,1),%r14
  jmp    L46
```

assistant: ```c
size_t _mini_strtrim(char *str, size_t len) {
  char *start = str, *end = str + len - 1;
  size_t newlen;
  if (!(str && *str)) {
    return 0;
  }
  while (*start && _mini_isspace((int)*start)) {
    start++;
  }
  while (end > start && _mini_isspace((int)*end)) {
    end--;
  }
  *(++end) = '\0';
  newlen = (size_t)(end - start);
  memmove(str, start, newlen + 1);
  return newlen;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_mini_strtrim>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L28
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  xor    %r14d,%r14d
  test   %dil,%dil
  je     L73
  mov    %rsi,%r13
  mov    %r12,%rbp
  jmp    L68
  xchg   %ax,%ax
L16:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  test   %dil,%dil
  je     L43
L68:
  call   <_mini_isspace@plt>
  test   %rax,%rax
  jne    L16
L43:
  lea    -0x1(%r12,%r13,1),%r14
  cmp    %rbp,%r14
  ja     L92
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L93:
  lea    -0x1(%r14),%rax
  cmp    %rbp,%rax
  je     L12
  mov    %rax,%r14
L92:
  movsbl (%r14),%edi
  call   <_mini_isspace@plt>
  test   %rax,%rax
  jne    L93
  mov    %r14,%rax
  add    $0x1,%r14
L8:
  movb   $0x0,0x1(%rax)
  sub    %rbp,%r14
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%r14),%rdx
  call   <memmove@plt>
L73:
  add    $0x8,%rsp
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L12:
  mov    %rbp,%rax
  jmp    L8
  nopl   (%rax)
L28:
  add    $0x8,%rsp
  xor    %r14d,%r14d
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  mov    %r14,%rax
  lea    (%r12,%r13,1),%r14
  jmp    L8
```

assistant: ```c
size_t _mini_strtrim(char *str, size_t len) {
  char *start = str, *end = str + len - 1;
  size_t newlen;
  if (!(str && *str)) {
    return 0;
  }
  while (*start && _mini_isspace((int)*start)) {
    start++;
  }
  while (end > start && _mini_isspace((int)*end)) {
    end--;
  }
  *(++end) = '\0';
  newlen = (size_t)(end - start);
  memmove(str, start, newlen + 1);
  return newlen;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3fffffff,%edi
  call   <foo@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo(0x3fffffff) == 0)
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3fffffff,%edi
  call   <foo@plt>
  test   %rax,%rax
  je     L3
L13:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  call   <abort@plt>
  jmp    L13
```

assistant: ```c
int main() {
  if (foo(0x3fffffff) == 0)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3fffffff,%edi
  call   <foo@plt>
  test   %rax,%rax
  je     L6
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  call   <abort@plt>
  jmp    L0
```

assistant: ```c
int main() {
  if (foo(0x3fffffff) == 0)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3fffffff,%edi
  call   <foo@plt>
  test   %rax,%rax
  je     L18
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L18:
  call   <abort@plt>
  jmp    L0
```

assistant: ```c
int main() {
  if (foo(0x3fffffff) == 0)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cobs_encode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x1,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L9
L35:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L20
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  movq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L9
L20:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x8(%rbp)
  cmpq   $0xff,-0x8(%rbp)
  jne    L9
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  movq   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %rax,-0x10(%rbp)
L9:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L35
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t cobs_encode(const uint8_t *input, size_t length, uint8_t *output) {
  size_t read_index = 0;
  size_t write_index = 1;
  size_t code_index = 0;
  uint8_t code = 1;
  while (read_index < length) {
    if (input[read_index] == 0) {
      output[code_index] = code;
      code = 1;
      code_index = write_index++;
      read_index++;
    } else {
      output[write_index++] = input[read_index++];
      code++;
      if (code == 0xFF) {
        output[code_index] = code;
        code = 1;
        code_index = write_index++;
      }
    }
  }
  output[code_index] = code;
  return write_index;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cobs_encode>:
  endbr64
  test   %rsi,%rsi
  je     L45
  mov    $0x1,%eax
  mov    $0x1,%r8d
  mov    $0x0,%r10d
  mov    $0x1,%ecx
  jmp    L39
L58:
  lea    0x1(%rcx),%r11
  mov    %r9,(%rdx,%rcx,8)
  add    $0x1,%r8
  cmp    $0xff,%r8
  je     L49
  mov    %r11,%rcx
L14:
  lea    0x1(%rax),%r9
  cmp    %rsi,%rax
  jae    L59
  mov    %r9,%rax
L39:
  mov    -0x8(%rdi,%rax,8),%r9
  test   %r9,%r9
  jne    L58
  mov    %r8,(%rdx,%r10,8)
  mov    %rcx,%r10
  lea    0x1(%rcx),%rcx
  mov    $0x1,%r8d
  jmp    L14
L49:
  movq   $0xff,(%rdx,%r10,8)
  add    $0x2,%rcx
  mov    %r11,%r10
  mov    $0x1,%r8d
  jmp    L14
L45:
  mov    %rsi,%r10
  mov    $0x1,%r8d
  mov    $0x1,%ecx
L59:
  mov    %r8,(%rdx,%r10,8)
  mov    %rcx,%rax
  ret
```

assistant: ```c
size_t cobs_encode(const uint8_t *input, size_t length, uint8_t *output) {
  size_t read_index = 0;
  size_t write_index = 1;
  size_t code_index = 0;
  uint8_t code = 1;
  while (read_index < length) {
    if (input[read_index] == 0) {
      output[code_index] = code;
      code = 1;
      code_index = write_index++;
      read_index++;
    } else {
      output[write_index++] = input[read_index++];
      code++;
      if (code == 0xFF) {
        output[code_index] = code;
        code = 1;
        code_index = write_index++;
      }
    }
  }
  output[code_index] = code;
  return write_index;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cobs_encode>:
  endbr64
  test   %rsi,%rsi
  je     L25
  lea    (%rdi,%rsi,8),%r11
  mov    $0x1,%ecx
  xor    %r9d,%r9d
  mov    $0x1,%eax
  jmp    L52
  nopl   0x0(%rax)
L22:
  mov    %rcx,(%r10)
  mov    %rax,%r9
  mov    $0x1,%ecx
  mov    %r8,%rax
L2:
  add    $0x8,%rdi
  cmp    %r11,%rdi
  je     L65
L52:
  mov    (%rdi),%rsi
  lea    (%rdx,%r9,8),%r10
  lea    0x1(%rax),%r8
  test   %rsi,%rsi
  je     L22
  add    $0x1,%rcx
  mov    %rsi,(%rdx,%rax,8)
  cmp    $0xff,%rcx
  je     L23
  add    $0x8,%rdi
  mov    %r8,%rax
  cmp    %r11,%rdi
  jne    L52
L65:
  lea    (%rdx,%r9,8),%rdx
  mov    %rcx,(%rdx)
  ret
  nopl   0x0(%rax)
L23:
  movq   $0xff,(%r10)
  add    $0x2,%rax
  mov    %r8,%r9
  mov    $0x1,%ecx
  jmp    L2
  nopl   (%rax)
L25:
  mov    $0x1,%ecx
  mov    $0x1,%eax
  mov    %rcx,(%rdx)
  ret
```

assistant: ```c
size_t cobs_encode(const uint8_t *input, size_t length, uint8_t *output) {
  size_t read_index = 0;
  size_t write_index = 1;
  size_t code_index = 0;
  uint8_t code = 1;
  while (read_index < length) {
    if (input[read_index] == 0) {
      output[code_index] = code;
      code = 1;
      code_index = write_index++;
      read_index++;
    } else {
      output[write_index++] = input[read_index++];
      code++;
      if (code == 0xFF) {
        output[code_index] = code;
        code = 1;
        code_index = write_index++;
      }
    }
  }
  output[code_index] = code;
  return write_index;
}
```