ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  cmpl   $0x2,-0x20(%rbp)
  jne    L22
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L52:
  movl   $0x0,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  mov    -0x4(%rbp),%esi
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    %esi,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x38(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L52
  jmp    L41
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L45
L30:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  imul   %eax,%esi
  mov    -0x2c(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%esi
  mov    %esi,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x38(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L30
L41:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(int *data, unsigned len, const int qlp_coeff[], unsigned order, int lp, int residual[]) {
  int i;
  int sum;
  if (order == 2)
    for (i = 0; i < (int)len; i++) {
      sum = 0;
      sum += qlp_coeff[1] * data[i - 2];
      sum += qlp_coeff[0] * data[i - 1];
      residual[i] = data[i] - (sum >> lp);
    }
  else
    for (i = 0; i < (int)len; i++)
      residual[i] = data[i] - ((qlp_coeff[0] * data[i - 1]) >> lp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  mov    %rdx,%r10
  mov    %ecx,%eax
  mov    %r8d,%ecx
  cmp    $0x2,%eax
  je     L42
  mov    %esi,%r8d
  mov    $0x0,%eax
  test   %esi,%esi
  jle    L2
L9:
  mov    (%r10),%edx
  imul   -0x4(%rdi,%rax,4),%edx
  sar    %cl,%edx
  mov    (%rdi,%rax,4),%esi
  sub    %edx,%esi
  mov    %esi,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L9
L8:
  ret
L2:
  ret
L42:
  test   %esi,%esi
  jle    L8
  mov    %esi,%r8d
  mov    $0x0,%edx
L16:
  mov    0x4(%r10),%eax
  imul   -0x8(%rdi,%rdx,4),%eax
  mov    (%r10),%esi
  imul   -0x4(%rdi,%rdx,4),%esi
  add    %esi,%eax
  sar    %cl,%eax
  mov    (%rdi,%rdx,4),%esi
  sub    %eax,%esi
  mov    %esi,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L16
  ret
```

assistant: ```c
void foo(int *data, unsigned len, const int qlp_coeff[], unsigned order, int lp, int residual[]) {
  int i;
  int sum;
  if (order == 2)
    for (i = 0; i < (int)len; i++) {
      sum = 0;
      sum += qlp_coeff[1] * data[i - 2];
      sum += qlp_coeff[0] * data[i - 1];
      residual[i] = data[i] - (sum >> lp);
    }
  else
    for (i = 0; i < (int)len; i++)
      residual[i] = data[i] - ((qlp_coeff[0] * data[i - 1]) >> lp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  mov    %ecx,%r11d
  mov    %rdx,%r10
  mov    %r8d,%ecx
  cmp    $0x2,%r11d
  je     L3
  mov    %esi,%r8d
  xor    %eax,%eax
  test   %esi,%esi
  jle    L26
  nopl   0x0(%rax)
L12:
  mov    (%r10),%edx
  imul   -0x4(%rdi,%rax,4),%edx
  mov    (%rdi,%rax,4),%esi
  sar    %cl,%edx
  sub    %edx,%esi
  mov    %esi,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L12
L47:
  ret
  nopl   (%rax)
L3:
  test   %esi,%esi
  jle    L47
  mov    %esi,%r8d
  xor    %edx,%edx
  nopl   0x0(%rax)
L48:
  mov    0x4(%r10),%eax
  mov    (%r10),%esi
  imul   -0x8(%rdi,%rdx,4),%eax
  imul   -0x4(%rdi,%rdx,4),%esi
  add    %esi,%eax
  mov    (%rdi,%rdx,4),%esi
  sar    %cl,%eax
  sub    %eax,%esi
  mov    %esi,(%r9,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L48
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  ret
```

assistant: ```c
void foo(int *data, unsigned len, const int qlp_coeff[], unsigned order, int lp, int residual[]) {
  int i;
  int sum;
  if (order == 2)
    for (i = 0; i < (int)len; i++) {
      sum = 0;
      sum += qlp_coeff[1] * data[i - 2];
      sum += qlp_coeff[0] * data[i - 1];
      residual[i] = data[i] - (sum >> lp);
    }
  else
    for (i = 0; i < (int)len; i++)
      residual[i] = data[i] - ((qlp_coeff[0] * data[i - 1]) >> lp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MemIntArrIO>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %ax,-0x1c(%rbp)
  movzwl -0x1c(%rbp),%eax
  test   %ax,%ax
  jns    L13
  movzwl -0x1c(%rbp),%eax
  shl    $0x2,%rax
  lea    -0x20000(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L17
L13:
  movzwl -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int MemIntArrIO(int *pMemBlk, unsigned short Wr_Addr, int data) {
  int *pWork;
  if (Wr_Addr >> 15) {
    pWork = pMemBlk + (Wr_Addr - 0x8000);
    *pWork = data;
  } else {
    pWork = pMemBlk + Wr_Addr;
    return *pWork;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MemIntArrIO>:
  endbr64
  test   %si,%si
  jns    L3
  movzwl %si,%esi
  mov    %edx,-0x20000(%rdi,%rsi,4)
  ret
L3:
  movzwl %si,%esi
  mov    (%rdi,%rsi,4),%eax
  ret
```

assistant: ```c
int MemIntArrIO(int *pMemBlk, unsigned short Wr_Addr, int data) {
  int *pWork;
  if (Wr_Addr >> 15) {
    pWork = pMemBlk + (Wr_Addr - 0x8000);
    *pWork = data;
  } else {
    pWork = pMemBlk + Wr_Addr;
    return *pWork;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MemIntArrIO>:
  endbr64
  movzwl %si,%eax
  lea    0x0(,%rax,4),%rcx
  test   %si,%si
  jns    L7
  mov    %edx,-0x20000(%rdi,%rcx,1)
  ret
  nopl   0x0(%rax)
L7:
  mov    (%rdi,%rax,4),%eax
  ret
```

assistant: ```c
int MemIntArrIO(int *pMemBlk, unsigned short Wr_Addr, int data) {
  int *pWork;
  if (Wr_Addr >> 15) {
    pWork = pMemBlk + (Wr_Addr - 0x8000);
    *pWork = data;
  } else {
    pWork = pMemBlk + Wr_Addr;
    return *pWork;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MemIntArrIO>:
  endbr64
  movzwl %si,%eax
  lea    0x0(,%rax,4),%rcx
  test   %si,%si
  jns    L1
  mov    %edx,-0x20000(%rdi,%rcx,1)
  ret
  nopl   0x0(%rax)
L1:
  mov    (%rdi,%rax,4),%eax
  ret
```

assistant: ```c
int MemIntArrIO(int *pMemBlk, unsigned short Wr_Addr, int data) {
  int *pWork;
  if (Wr_Addr >> 15) {
    pWork = pMemBlk + (Wr_Addr - 0x8000);
    *pWork = data;
  } else {
    pWork = pMemBlk + Wr_Addr;
    return *pWork;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<crc16_0x3D65_normal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %ecx,%eax
  mov    %dx,-0x20(%rbp)
  mov    %ax,-0x24(%rbp)
  movzwl -0x20(%rbp),%eax
  mov    %ax,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L5:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzwl -0x6(%rbp),%eax
  shr    $0x8,%ax
  xor    -0x9(%rbp),%al
  mov    %al,-0x8(%rbp)
  movzbl -0x8(%rbp),%eax
  shr    $0x5,%al
  mov    %eax,%edx
  movzbl -0x8(%rbp),%eax
  shr    $0x4,%al
  xor    %eax,%edx
  movzbl -0x8(%rbp),%eax
  shr    $0x3,%al
  xor    %edx,%eax
  xor    -0x8(%rbp),%al
  mov    %al,-0x7(%rbp)
  movzwl -0x6(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x7(%rbp),%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0x2,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0x5,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0x6,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0x8,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0xa,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0xb,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0xc,%eax
  xor    %eax,%edx
  movzbl -0x7(%rbp),%eax
  shl    $0xd,%eax
  xor    %edx,%eax
  mov    %ax,-0x6(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L5
  movzwl -0x24(%rbp),%eax
  xor    %ax,-0x6(%rbp)
  movzwl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short crc16_0x3D65_normal(unsigned char *message, unsigned int msgsize, unsigned short init, unsigned short xor) {
  unsigned short c;
  unsigned char d, s, t;
  unsigned int i;
  c = init;
  for (i = 0; i < msgsize; i++) {
    d = message[i];
    s = (c >> 8) ^ d;
    t = (s >> 5) ^ (s >> 4) ^ (s >> 3) ^ s;
    c = (c << 8) ^ t ^ (t << 2) ^ (t << 5) ^ (t << 6) ^ (t << 8) ^ (t << 10) ^ (t << 11) ^ (t << 12) ^ (t << 13);
  }
  c = c ^ xor;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<crc16_0x3D65_normal>:
  endbr64
  mov    %ecx,%r8d
  mov    %edx,%eax
  test   %esi,%esi
  je     L9
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
L16:
  mov    %eax,%edx
  shr    $0x8,%dx
  xor    (%rcx),%dl
  mov    %edx,%edi
  shr    $0x5,%dil
  mov    %edx,%r9d
  shr    $0x4,%r9b
  xor    %r9d,%edi
  xor    %edx,%edi
  shr    $0x3,%dl
  xor    %edx,%edi
  movzbl %dil,%edx
  shl    $0x8,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  lea    0x0(,%rdx,4),%edi
  xor    %edi,%eax
  mov    %edx,%edi
  shl    $0x5,%edi
  xor    %edi,%eax
  mov    %edx,%edi
  shl    $0x6,%edi
  xor    %edi,%eax
  mov    %edx,%edi
  shl    $0x8,%edi
  xor    %edi,%eax
  mov    %edx,%edi
  shl    $0xa,%edi
  xor    %edi,%eax
  mov    %edx,%edi
  shl    $0xb,%edi
  xor    %edi,%eax
  mov    %edx,%edi
  shl    $0xc,%edi
  xor    %edi,%eax
  shl    $0xd,%edx
  xor    %edx,%eax
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L16
L9:
  xor    %r8d,%eax
  ret
```

assistant: ```c
unsigned short crc16_0x3D65_normal(unsigned char *message, unsigned int msgsize, unsigned short init, unsigned short xor) {
  unsigned short c;
  unsigned char d, s, t;
  unsigned int i;
  c = init;
  for (i = 0; i < msgsize; i++) {
    d = message[i];
    s = (c >> 8) ^ d;
    t = (s >> 5) ^ (s >> 4) ^ (s >> 3) ^ s;
    c = (c << 8) ^ t ^ (t << 2) ^ (t << 5) ^ (t << 6) ^ (t << 8) ^ (t << 10) ^ (t << 11) ^ (t << 12) ^ (t << 13);
  }
  c = c ^ xor;
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<crc16_0x3D65_normal>:
  endbr64
  mov    %ecx,%r8d
  mov    %edx,%eax
  test   %esi,%esi
  je     L9
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
  nopl   (%rax)
L0:
  mov    %eax,%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  shr    $0x8,%dx
  xor    -0x1(%rdi),%dl
  mov    %edx,%esi
  mov    %edx,%r9d
  shr    $0x5,%sil
  shr    $0x4,%r9b
  xor    %r9d,%esi
  xor    %edx,%esi
  shr    $0x3,%dl
  xor    %edx,%esi
  movzbl %sil,%edx
  movzbl %sil,%esi
  or     %esi,%eax
  lea    0x0(,%rdx,4),%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0x5,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0x6,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0x8,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0xa,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0xb,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0xd,%edx
  shl    $0xc,%esi
  xor    %esi,%eax
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L0
L9:
  xor    %r8d,%eax
  ret
```

assistant: ```c
unsigned short crc16_0x3D65_normal(unsigned char *message, unsigned int msgsize, unsigned short init, unsigned short xor) {
  unsigned short c;
  unsigned char d, s, t;
  unsigned int i;
  c = init;
  for (i = 0; i < msgsize; i++) {
    d = message[i];
    s = (c >> 8) ^ d;
    t = (s >> 5) ^ (s >> 4) ^ (s >> 3) ^ s;
    c = (c << 8) ^ t ^ (t << 2) ^ (t << 5) ^ (t << 6) ^ (t << 8) ^ (t << 10) ^ (t << 11) ^ (t << 12) ^ (t << 13);
  }
  c = c ^ xor;
  return c;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc16_0x3D65_normal>:
  endbr64
  mov    %ecx,%r8d
  mov    %edx,%eax
  test   %esi,%esi
  je     L11
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
  nopl   (%rax)
L1:
  mov    %eax,%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  shr    $0x8,%dx
  xor    -0x1(%rdi),%dl
  mov    %edx,%esi
  mov    %edx,%r9d
  shr    $0x5,%sil
  shr    $0x4,%r9b
  xor    %r9d,%esi
  xor    %edx,%esi
  shr    $0x3,%dl
  xor    %edx,%esi
  movzbl %sil,%edx
  movzbl %sil,%esi
  or     %esi,%eax
  lea    0x0(,%rdx,4),%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0x5,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0x6,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0x8,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0xa,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0xb,%esi
  xor    %esi,%eax
  mov    %edx,%esi
  shl    $0xd,%edx
  shl    $0xc,%esi
  xor    %esi,%eax
  xor    %edx,%eax
  cmp    %rcx,%rdi
  jne    L1
L11:
  xor    %r8d,%eax
  ret
```

assistant: ```c
unsigned short crc16_0x3D65_normal(unsigned char *message, unsigned int msgsize, unsigned short init, unsigned short xor) {
  unsigned short c;
  unsigned char d, s, t;
  unsigned int i;
  c = init;
  for (i = 0; i < msgsize; i++) {
    d = message[i];
    s = (c >> 8) ^ d;
    t = (s >> 5) ^ (s >> 4) ^ (s >> 3) ^ s;
    c = (c << 8) ^ t ^ (t << 2) ^ (t << 5) ^ (t << 6) ^ (t << 8) ^ (t << 10) ^ (t << 11) ^ (t << 12) ^ (t << 13);
  }
  c = c ^ xor;
  return c;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ascii85_tuple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rdx,%rax
  shl    $0x10,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%rax
  or     %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %rdx,%rax
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L9
  mov    -0x28(%rbp),%rax
  movb   $0x7a,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  jmp    L7
L9:
  movq   $0x31c84b1,-0x18(%rbp)
  mov    $0x0,%ebx
  jmp    L17
L12:
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rax,%r12
  mov    %r12,%rax
  imul   -0x18(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  mov    %r12d,%eax
  lea    0x21(%rax),%edx
  mov    %rbx,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movabs $0xc0c0c0c0c0c0c0c1,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x6,%rax
  mov    %rax,-0x18(%rbp)
  add    $0x1,%rbx
L17:
  cmp    $0x3,%rbx
  jle    L12
  mov    -0x20(%rbp),%rcx
  movabs $0xc0c0c0c0c0c0c0c1,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x6,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  lea    0x21(%rax),%edx
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  add    $0x5,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
L7:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *ascii85_tuple(char *tuple, unsigned char *data) {
  register long i, x;
  unsigned long code, quantum;
  code = ((((unsigned long)data[0] << 8) | (unsigned long)data[1]) << 16) | ((unsigned long)data[2] << 8) | (unsigned long)data[3];
  if (code == 0L) {
    tuple[0] = 'z';
    tuple[1] = '\0';
    return (tuple);
  }
  quantum = 85UL * 85UL * 85UL * 85UL;
  for (i = 0; i < 4; i++) {
    x = (long)(code / quantum);
    code -= quantum * x;
    tuple[i] = (char)(x + (int)'!');
    quantum /= 85L;
  }
  tuple[4] = (char)((code % 85L) + (int)'!');
  tuple[5] = '\0';
  return tuple;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ascii85_tuple>:
  endbr64
  mov    %rdi,%r8
  movzbl (%rsi),%ecx
  shl    $0x8,%rcx
  movzbl 0x1(%rsi),%eax
  or     %rax,%rcx
  shl    $0x10,%rcx
  movzbl 0x2(%rsi),%eax
  shl    $0x8,%rax
  movzbl 0x3(%rsi),%edx
  or     %rdx,%rax
  mov    $0x31c84b1,%esi
  mov    $0x0,%edi
  movabs $0xc0c0c0c0c0c0c0c1,%r9
  or     %rax,%rcx
  je     L20
L7:
  mov    %rcx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rcx
  add    $0x21,%eax
  mov    %al,(%r8,%rdi,1)
  mov    %rsi,%rax
  mul    %r9
  mov    %rdx,%rsi
  shr    $0x6,%rsi
  add    $0x1,%rdi
  cmp    $0x4,%rdi
  jne    L7
  movabs $0xc0c0c0c0c0c0c0c1,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x6,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rdx,%rax
  sub    %rax,%rcx
  add    $0x21,%ecx
  mov    %cl,0x4(%r8)
  movb   $0x0,0x5(%r8)
L2:
  mov    %r8,%rax
  ret
L20:
  movb   $0x7a,(%r8)
  movb   $0x0,0x1(%r8)
  jmp    L2
```

assistant: ```c
char *ascii85_tuple(char *tuple, unsigned char *data) {
  register long i, x;
  unsigned long code, quantum;
  code = ((((unsigned long)data[0] << 8) | (unsigned long)data[1]) << 16) | ((unsigned long)data[2] << 8) | (unsigned long)data[3];
  if (code == 0L) {
    tuple[0] = 'z';
    tuple[1] = '\0';
    return (tuple);
  }
  quantum = 85UL * 85UL * 85UL * 85UL;
  for (i = 0; i < 4; i++) {
    x = (long)(code / quantum);
    code -= quantum * x;
    tuple[i] = (char)(x + (int)'!');
    quantum /= 85L;
  }
  tuple[4] = (char)((code % 85L) + (int)'!');
  tuple[5] = '\0';
  return tuple;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ascii85_tuple>:
  endbr64
  movabs $0xc0c0c0c0c0c0c0c1,%r9
  mov    (%rsi),%ecx
  mov    %rdi,%r8
  mov    $0x31c84b1,%esi
  xor    %edi,%edi
  bswap  %ecx
  mov    %ecx,%ecx
  test   %rcx,%rcx
  je     L10
L12:
  mov    %rcx,%rax
  xor    %edx,%edx
  div    %rsi
  add    $0x21,%eax
  mov    %rdx,%rcx
  mov    %al,(%r8,%rdi,1)
  mov    %rsi,%rax
  add    $0x1,%rdi
  mul    %r9
  mov    %rdx,%rsi
  shr    $0x6,%rsi
  cmp    $0x4,%rdi
  jne    L12
  mov    %rcx,%rax
  movb   $0x0,0x5(%r8)
  mul    %r9
  shr    $0x6,%rdx
  lea    (%rdx,%rdx,4),%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %r8,%rax
  add    $0x21,%ecx
  mov    %cl,0x4(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x7a,%eax
  mov    %ax,(%r8)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ascii85_tuple(char *tuple, unsigned char *data) {
  register long i, x;
  unsigned long code, quantum;
  code = ((((unsigned long)data[0] << 8) | (unsigned long)data[1]) << 16) | ((unsigned long)data[2] << 8) | (unsigned long)data[3];
  if (code == 0L) {
    tuple[0] = 'z';
    tuple[1] = '\0';
    return (tuple);
  }
  quantum = 85UL * 85UL * 85UL * 85UL;
  for (i = 0; i < 4; i++) {
    x = (long)(code / quantum);
    code -= quantum * x;
    tuple[i] = (char)(x + (int)'!');
    quantum /= 85L;
  }
  tuple[4] = (char)((code % 85L) + (int)'!');
  tuple[5] = '\0';
  return tuple;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ascii85_tuple>:
  endbr64
  mov    (%rsi),%ecx
  mov    %rdi,%r8
  bswap  %ecx
  mov    %ecx,%ecx
  test   %rcx,%rcx
  je     L5
  mov    %rcx,%rax
  movb   $0x0,0x5(%r8)
  movabs $0xa48e60be49a57459,%rdx
  mul    %rdx
  mov    %rdx,%rdi
  shr    $0x19,%rdx
  shr    $0x19,%rdi
  add    $0x21,%edx
  imul   $0x31c84b1,%rdi,%rax
  mov    %rcx,%rdi
  mov    %dl,(%r8)
  movabs $0xda8d187cb9cfbe87,%rdx
  sub    %rax,%rdi
  mov    %rdi,%rax
  mul    %rdx
  mov    %rdx,%rsi
  shr    $0x13,%rdx
  shr    $0x13,%rsi
  add    $0x21,%edx
  imul   $0x95eed,%rsi,%rax
  mov    %rdi,%rsi
  mov    %dl,0x1(%r8)
  movabs $0x4890d92169b1fa43,%rdx
  sub    %rax,%rsi
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sar    $0xb,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rdx
  sub    %rax,%rcx
  add    $0x21,%edx
  imul   $0x1c39,%rcx,%rdi
  mov    %dl,0x2(%r8)
  movabs $0xc0c0c0c0c0c0c0c1,%rdx
  sub    %rdi,%rsi
  mov    %rsi,%rax
  mov    %rsi,%rcx
  mul    %rdx
  shr    $0x6,%rdx
  lea    0x21(%rdx),%eax
  mov    %al,0x3(%r8)
  lea    (%rdx,%rdx,4),%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rdx,%rax
  sub    %rax,%rcx
  mov    %r8,%rax
  add    $0x21,%ecx
  mov    %cl,0x4(%r8)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x7a,%eax
  mov    %ax,(%rdi)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ascii85_tuple(char *tuple, unsigned char *data) {
  register long i, x;
  unsigned long code, quantum;
  code = ((((unsigned long)data[0] << 8) | (unsigned long)data[1]) << 16) | ((unsigned long)data[2] << 8) | (unsigned long)data[3];
  if (code == 0L) {
    tuple[0] = 'z';
    tuple[1] = '\0';
    return (tuple);
  }
  quantum = 85UL * 85UL * 85UL * 85UL;
  for (i = 0; i < 4; i++) {
    x = (long)(code / quantum);
    code -= quantum * x;
    tuple[i] = (char)(x + (int)'!');
    quantum /= 85L;
  }
  tuple[4] = (char)((code % 85L) + (int)'!');
  tuple[5] = '\0';
  return tuple;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sscal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L28
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L11:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  add    %eax,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L11
  jmp    L26
L28:
  nop
L26:
  pop    %rbp
  ret
```

assistant: ```c
void sscal(int n, double sa, double *sx, int incx) {
  int i, nincx;
  if (n <= 0)
    return;
  nincx = n * incx;
  for (i = 0; i < nincx; i += incx)
    sx[i] *= sa;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sscal>:
  endbr64
  test   %edi,%edi
  jle    L4
  imul   %edx,%edi
  test   %edi,%edi
  jle    L4
  movslq %edx,%rcx
  shl    $0x3,%rcx
  mov    $0x0,%eax
L19:
  movapd %xmm0,%xmm1
  mulsd  (%rsi),%xmm1
  movsd  %xmm1,(%rsi)
  add    %edx,%eax
  add    %rcx,%rsi
  cmp    %eax,%edi
  jg     L19
L4:
  ret
```

assistant: ```c
void sscal(int n, double sa, double *sx, int incx) {
  int i, nincx;
  if (n <= 0)
    return;
  nincx = n * incx;
  for (i = 0; i < nincx; i += incx)
    sx[i] *= sa;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sscal>:
  endbr64
  test   %edi,%edi
  jle    L23
  imul   %edx,%edi
  test   %edi,%edi
  jle    L23
  movslq %edx,%rcx
  xor    %eax,%eax
  shl    $0x3,%rcx
  nopl   0x0(%rax,%rax,1)
L6:
  movsd  (%rsi),%xmm1
  add    %edx,%eax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  add    %rcx,%rsi
  cmp    %eax,%edi
  jg     L6
L23:
  ret
```

assistant: ```c
void sscal(int n, double sa, double *sx, int incx) {
  int i, nincx;
  if (n <= 0)
    return;
  nincx = n * incx;
  for (i = 0; i < nincx; i += incx)
    sx[i] *= sa;
}
```