user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%r13
L196:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <myGetline@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L70
  mov    %ebp,%r12d
  mov    $0x0,%ebx
  jmp    L4
L69:
  test   %ebx,%ebx
  jle    L5
  mov    %rbx,%rdx
  jmp    L116
L192:
  sub    $0x1,%rdx
  test   %edx,%edx
  jle    L5
L116:
  movzbl (%rsp,%rdx,1),%ecx
  cmp    $0x20,%cl
  je     L192
  cmp    $0x9,%cl
  je     L192
  mov    %edx,%r14d
L5:
  mov    %r14d,%edi
  sub    %esi,%edi
  cmp    $0xfffffff7,%edi
  jl     L26
  lea    0x9(%rdi),%esi
  mov    $0x0,%eax
  lea    (%rsp,%rbx,1),%rcx
L13:
  movzbl -0x9(%rcx,%rax,1),%edx
  mov    %dl,0x3f0(%rsp,%rax,1)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdx,%rsi
  jne    L13
  lea    0xa(%rdi),%eax
L26:
  movslq %eax,%rdx
  movb   $0xa,0x3f0(%rsp,%rdx,1)
  add    $0x1,%eax
  cltq
  movb   $0x0,0x3f0(%rsp,%rax,1)
  lea    0x3f0(%rsp),%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L64
L143:
  mov    $0x0,%edx
  jmp    L177
L70:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L197
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L112:
  cmp    $0x1,%ebp
  je     L177
L64:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L196
L4:
  mov    %ebx,%esi
  mov    %ebx,%edx
  test   %ebx,%ebx
  je     L112
  lea    0x1(%rbx),%edi
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%eax
  sub    %ecx,%eax
  je     L69
  lea    -0x1(%rbp),%eax
  cmp    %ebx,%eax
  jne    L64
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  mov    %ebx,%edx
  sub    %eax,%edx
  test   %edx,%edx
  jle    L143
  mov    $0x0,%eax
  sub    %edx,%esi
  movslq %esi,%rsi
  lea    (%rsp,%rsi,1),%rsi
L111:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,0x3f0(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L111
L177:
  movslq %edx,%rdx
  movb   $0x0,0x3f0(%rsp,%rdx,1)
  lea    0x3f0(%rsp),%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L64
L197:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string

tool: D6: %s

assistant: ```c
main() {
  int len;
  int lineLenLimit;
  char line[1000], outputLine[1000];
  int i, j;
  int foldCol;
  lineLenLimit = 10;
  while ((len = myGetline(line, 1000)) > 0) {
    for (i = 0; i < len; ++i) {
      if (i != 0 && (i + 1) % lineLenLimit == 0) {
        for (j = i; j > 0; --j) {
          if (line[j] != ' ' && line[j] != '\t') {
            foldCol = j;
            break;
          }
        }
        for (j = 0; j < foldCol - i + lineLenLimit; ++j) {
          outputLine[j] = line[j + i - lineLenLimit + 1];
        }
        outputLine[j] = '\n';
        outputLine[j + 1] = '\0';
        printf("%s", outputLine);
      } else if (i == len - 1) {
        for (j = 0; j < i % lineLenLimit; ++j)
          outputLine[j] = line[j + i - (i % lineLenLimit)];
        outputLine[j] = '\0';
        printf("%s", outputLine);
      }
    }
  }
}
```