ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x78(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  jmp    L23
L3:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <max_sub_min@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x74(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L34
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x74(%rbp),%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L23
L34:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L23:
  mov    -0x78(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x78(%rbp)
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D31
data_type: string
name: read_data
arguments: tag: D45
data_type: string
name: read_data
arguments: tag: D37
data_type: string
name: read_data
arguments: tag: D33
data_type: string

tool: D31: %d

tool: D45: Lucky Word

tool: D37: %d


tool: D33: No Answer

assistant: ```c
int main(int argc, char const *argv[]) {
  char s[100];
  int lines, d_value;
  scanf("%d", &lines);
  getchar();
  while (lines--) {
    gets(s);
    d_value = max_sub_min(s);
    if (isprime(d_value)) {
      printf("%s\n", "Lucky Word");
      printf("%d\n", d_value);
    } else {
      printf("%s\n", "No Answer");
      printf("%d\n", 0);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L22
  lea    0x10(%rsp),%rbp
  lea    D32(%rip),%r14
  lea    D18(%rip),%r12
  lea    D33(%rip),%r13
  jmp    L21
L15:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    $0x0,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L22
L21:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <max_sub_min@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L15
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L22:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D32
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D33
type_guessed: string

tool: D3: %d

tool: D32: No Answer

tool: D18: %d


tool: D33: Lucky Word

assistant: ```c
int main(int argc, char const *argv[]) {
  char s[100];
  int lines, d_value;
  scanf("%d", &lines);
  getchar();
  while (lines--) {
    gets(s);
    d_value = max_sub_min(s);
    if (isprime(d_value)) {
      printf("%s\n", "Lucky Word");
      printf("%d\n", d_value);
    } else {
      printf("%s\n", "No Answer");
      printf("%d\n", 0);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D34(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L1
  lea    0x10(%rsp),%rbx
  lea    D0(%rip),%r12
  lea    D9(%rip),%r14
  lea    D6(%rip),%r13
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L1
L48:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <max_sub_min@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <isprime@plt>
  test   %rax,%rax
  jne    L0
  mov    %r14,%rdi
  call   <puts@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L48
L1:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D34
type: string
name: parse_data
arguments: data_tag: D0
type: string
name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D34: %d

tool: D0: %d


tool: D9: No Answer

tool: D6: Lucky Word

assistant: ```c
int main(int argc, char const *argv[]) {
  char s[100];
  int lines, d_value;
  scanf("%d", &lines);
  getchar();
  while (lines--) {
    gets(s);
    d_value = max_sub_min(s);
    if (isprime(d_value)) {
      printf("%s\n", "Lucky Word");
      printf("%d\n", d_value);
    } else {
      printf("%s\n", "No Answer");
      printf("%d\n", 0);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  lea    D1(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L27
  lea    0x10(%rsp),%rbx
  lea    D35(%rip),%r12
  lea    D39(%rip),%r14
  lea    D4(%rip),%r13
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %ebp,%esi
L41:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L27
L50:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <max_sub_min@plt>
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <isprime@plt>
  test   %rax,%rax
  jne    L42
  mov    %r14,%rdi
  call   <puts@plt>
  xor    %esi,%esi
  jmp    L41
  nopl   (%rax)
L27:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D35
datatype: string
name: retrieve_data
arguments: label: D39
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string

tool: D1: %d

tool: D35: %d


tool: D39: No Answer

tool: D4: Lucky Word

assistant: ```c
int main(int argc, char const *argv[]) {
  char s[100];
  int lines, d_value;
  scanf("%d", &lines);
  getchar();
  while (lines--) {
    gets(s);
    d_value = max_sub_min(s);
    if (isprime(d_value)) {
      printf("%s\n", "Lucky Word");
      printf("%d\n", d_value);
    } else {
      printf("%s\n", "No Answer");
      printf("%d\n", 0);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modelview_load_push>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <modelview_push@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <modelview_load@plt>
  nop
  leave
  ret
```

assistant: ```c
void modelview_load_push(float m[4][4]) {
  modelview_push();
  modelview_load(m);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<modelview_load_push>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <modelview_push@plt>
  mov    %rbx,%rdi
  call   <modelview_load@plt>
  pop    %rbx
  ret
```

assistant: ```c
void modelview_load_push(float m[4][4]) {
  modelview_push();
  modelview_load(m);
}
```
user: Translate the below assembly code into C programming language:

```asm
<modelview_load_push>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <modelview_push@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <modelview_load@plt>
```

assistant: ```c
void modelview_load_push(float m[4][4]) {
  modelview_push();
  modelview_load(m);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<modelview_load_push>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  call   <modelview_push@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <modelview_load@plt>
```

assistant: ```c
void modelview_load_push(float m[4][4]) {
  modelview_push();
  modelview_load(m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %rsi,-0xe0(%rbp)
  mov    %rdx,-0xb0(%rbp)
  mov    %rcx,-0xa8(%rbp)
  mov    %r8,-0xa0(%rbp)
  mov    %r9,-0x98(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x90(%rbp)
  movaps %xmm1,-0x80(%rbp)
  movaps %xmm2,-0x70(%rbp)
  movaps %xmm3,-0x60(%rbp)
  movaps %xmm4,-0x50(%rbp)
  movaps %xmm5,-0x40(%rbp)
  movaps %xmm6,-0x30(%rbp)
  movaps %xmm7,-0x20(%rbp)
L6:
  mov    -0xd4(%rbp),%eax
  movslq %eax,%rbx
  mov    -0xe0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0xc8(%rbp)
  mov    -0xe0(%rbp),%rdx
  mov    -0xcc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xcc(%rbp),%edx
  mov    -0xe0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0xcc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <ch_screen_message@plt>
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void message(int extra, const char *format, ...) {
  char *buf;
  va_list ap;
  buf = malloc(extra + strlen(format) + 1);
  va_start(ap, format);
  vsprintf(buf, format, ap);
  va_end(ap);
  ch_screen_message(buf);
  free(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<message>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  movslq %ebx,%rbx
  lea    0x1(%rbx,%rax,1),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vsprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <ch_screen_message@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void message(int extra, const char *format, ...) {
  char *buf;
  va_list ap;
  buf = malloc(extra + strlen(format) + 1);
  va_start(ap, format);
  vsprintf(buf, format, ap);
  va_end(ap);
  ch_screen_message(buf);
  free(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<message>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <ch_screen_message@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void message(int extra, const char *format, ...) {
  char *buf;
  va_list ap;
  buf = malloc(extra + strlen(format) + 1);
  va_start(ap, format);
  vsprintf(buf, format, ap);
  va_end(ap);
  ch_screen_message(buf);
  free(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<message>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <ch_screen_message@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void message(int extra, const char *format, ...) {
  char *buf;
  va_list ap;
  buf = malloc(extra + strlen(format) + 1);
  va_start(ap, format);
  vsprintf(buf, format, ap);
  va_end(ap);
  ch_screen_message(buf);
  free(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<buscaBinaria>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L6
  mov    $0xffffffff,%eax
  jmp    L52
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L23
  mov    -0x4(%rbp),%eax
  jmp    L52
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x24(%rbp)
  jle    L12
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <buscaBinaria>
  jmp    L52
L12:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x1c(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <buscaBinaria>
L52:
  leave
  ret
```

assistant: ```c
int buscaBinaria(int numeros[], int inicio, int final, int n) {
  int meio = (int)(inicio + final) / 2;
  if (inicio > final)
    return -1;
  else if (n == numeros[meio])
    return meio;
  else if (n > numeros[meio])
    return buscaBinaria(numeros, n, meio + 1, final);
  else
    return buscaBinaria(numeros, n, inicio, meio - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<buscaBinaria>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%edi
  mov    %ecx,%esi
  lea    (%rdi,%rdx,1),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %eax,%ecx
  sar    %ecx
  cmp    %edx,%edi
  jg     L14
  sub    $0x8,%rsp
  mov    %edx,%r8d
  mov    %ecx,%eax
  movslq %ecx,%rdx
  mov    (%r9,%rdx,4),%edx
  cmp    %esi,%edx
  je     L5
  jge    L24
  lea    0x1(%rcx),%edx
  mov    %r8d,%ecx
  mov    %r9,%rdi
  call   <buscaBinaria>
L5:
  add    $0x8,%rsp
  ret
L24:
  sub    $0x1,%ecx
  mov    %edi,%edx
  mov    %r9,%rdi
  call   <buscaBinaria>
  jmp    L5
L14:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int buscaBinaria(int numeros[], int inicio, int final, int n) {
  int meio = (int)(inicio + final) / 2;
  if (inicio > final)
    return -1;
  else if (n == numeros[meio])
    return meio;
  else if (n > numeros[meio])
    return buscaBinaria(numeros, n, meio + 1, final);
  else
    return buscaBinaria(numeros, n, inicio, meio - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<buscaBinaria>:
  endbr64
  lea    (%rsi,%rdx,1),%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  cmp    %edx,%esi
  jle    L10
  jmp    L24
  nopl   0x0(%rax)
L39:
  mov    %edx,%r8d
  lea    0x1(%rax),%edx
L48:
  lea    (%rdx,%rcx,1),%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  mov    %ecx,%esi
  sar    %eax
  cmp    %ecx,%edx
  jl     L24
  mov    %r8d,%ecx
L10:
  movslq %eax,%r8
  cmp    %ecx,(%rdi,%r8,4)
  je     L47
  jl     L39
  lea    -0x1(%rax),%r8d
  mov    %esi,%edx
  jmp    L48
  xchg   %ax,%ax
L24:
  mov    $0xffffffff,%eax
L47:
  ret
```

assistant: ```c
int buscaBinaria(int numeros[], int inicio, int final, int n) {
  int meio = (int)(inicio + final) / 2;
  if (inicio > final)
    return -1;
  else if (n == numeros[meio])
    return meio;
  else if (n > numeros[meio])
    return buscaBinaria(numeros, n, meio + 1, final);
  else
    return buscaBinaria(numeros, n, inicio, meio - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<buscaBinaria>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%edi
  mov    %ecx,%edx
  lea    (%rsi,%rdi,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %edi,%esi
  jle    L35
  jmp    L16
  nopl   (%rax)
L30:
  lea    0x1(%rax),%esi
  lea    (%rsi,%rdx,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %edx,%esi
  jl     L16
L7:
  mov    %esi,%ecx
  mov    %edx,%esi
  mov    %edi,%edx
  mov    %ecx,%edi
L35:
  movslq %eax,%rcx
  cmp    %edx,(%r8,%rcx,4)
  je     L40
  jl     L30
  lea    (%rsi,%rdx,1),%ecx
  lea    -0x1(%rax),%edi
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %edx,%esi
  jge    L7
L16:
  mov    $0xffffffff,%eax
L40:
  ret
```

assistant: ```c
int buscaBinaria(int numeros[], int inicio, int final, int n) {
  int meio = (int)(inicio + final) / 2;
  if (inicio > final)
    return -1;
  else if (n == numeros[meio])
    return meio;
  else if (n > numeros[meio])
    return buscaBinaria(numeros, n, meio + 1, final);
  else
    return buscaBinaria(numeros, n, inicio, meio - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<printarray_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L4:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x3,-0xc(%rbp)
  jle    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D7: 
%d

assistant: ```c
void printarray_1(int (*ptr)[4]) {
  int *p, count;
  p = (int *)ptr;
  for (count = 0; count < 4; count++)
    printf("\n%d", *p++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printarray_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x10(%rdi),%r12
  lea    D4(%rip),%rbp
L8:
  add    $0x4,%rbx
  mov    -0x4(%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: 
%d

assistant: ```c
void printarray_1(int (*ptr)[4]) {
  int *p, count;
  p = (int *)ptr;
  for (count = 0; count < 4; count++)
    printf("\n%d", *p++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printarray_1>:
  endbr64
  push   %r12
  lea    0x10(%rdi),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L5:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: 
%d

assistant: ```c
void printarray_1(int (*ptr)[4]) {
  int *p, count;
  p = (int *)ptr;
  for (count = 0; count < 4; count++)
    printf("\n%d", *p++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<printarray_1>:
  endbr64
  push   %r12
  lea    0x10(%rdi),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
L6:
  mov    (%rbx),%esi
  add    $0x4,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type: string

tool: D6: 
%d

assistant: ```c
void printarray_1(int (*ptr)[4]) {
  int *p, count;
  p = (int *)ptr;
  for (count = 0; count < 4; count++)
    printf("\n%d", *p++);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L9
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_infered: string

tool: D5: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("%s\n", argv[i]);
    ++i;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%r12
  lea    D9(%rip),%rbp
L10:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L10
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    $0x0,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D9
data_type: string

tool: D9: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("%s\n", argv[i]);
    ++i;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L16
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L5:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L16:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("%s\n", argv[i]);
    ++i;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L6
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x8(%rsi,%rax,8),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L7:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L6:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string

tool: D3: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("%s\n", argv[i]);
    ++i;
  }
  return 0;
}
```