user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encode_url>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L83
L3:
  cmpl   $0x0,-0x10(%rbp)
  jne    L89
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L77
L89:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L85
  cmpl   $0x0,-0x10(%rbp)
  jne    L85
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L85
L77:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    D2(%rip),%rdx
  movb   $0x25,(%rax,%rdx,1)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  lea    -0xc(%rbp),%rax
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movzbl -0xc(%rbp),%edx
  cltq
  lea    D2(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movzbl -0xb(%rbp),%edx
  cltq
  lea    D2(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  jmp    L34
L85:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    D2(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
L34:
  cmpl   $0x0,-0x10(%rbp)
  je     L71
  movl   $0x0,-0x10(%rbp)
  jmp    L62
L71:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L62
  movl   $0x1,-0x10(%rbp)
L62:
  addl   $0x1,-0x18(%rbp)
L83:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x14(%rbp),%eax
  cltq
  lea    D2(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  lea    D2(%rip),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D25
datatype: string

tool: D1: ~`!@#$%%^&*()-_=+[{]}\|;:'",<.>/? 

tool: D25: %02X

assistant: ```c
char *encode_url(unsigned char *s) {
  int i, j, half = 0;
  static char buf[1024];
  char a[4];
  j = 0;
  for (i = 0; s[i]; i++) {
    if ((!half && strchr("~`!@#$%%^&*()-_=+[{]}\\|;:'\",<.>/? ", s[i])) || (s[i + 1] == 0 && !half && (unsigned char)s[i] >= 128)) {
      buf[j++] = '%';
      sprintf(a, "%02X", s[i]);
      buf[j++] = a[0];
      buf[j++] = a[1];
    } else
      buf[j++] = s[i];
    if (half)
      half = 0;
    else if ((unsigned char)s[i] >= 128)
      half = 1;
  }
  buf[j] = 0;
  return buf;
}
```