ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<unique_print_simple_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_infered: string
name: retrieve_data
arguments: data_tag: D21
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D5:  _____________________________________________________________________________


tool: D21:    IP            At MAC Address     Count     Len  MAC Vendor / Hostname      


tool: D0:  -----------------------------------------------------------------------------


assistant: ```c
void unique_print_simple_header() {
  printf(" _____________________________________________________________________________\n");
  printf("   IP            At MAC Address     Count     Len  MAC Vendor / Hostname      \n");
  printf(" -----------------------------------------------------------------------------\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<unique_print_simple_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D9
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D2:  _____________________________________________________________________________


tool: D9:    IP            At MAC Address     Count     Len  MAC Vendor / Hostname      


tool: D27:  -----------------------------------------------------------------------------


assistant: ```c
void unique_print_simple_header() {
  printf(" _____________________________________________________________________________\n");
  printf("   IP            At MAC Address     Count     Len  MAC Vendor / Hostname      \n");
  printf(" -----------------------------------------------------------------------------\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<unique_print_simple_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string

tool: D12:  _____________________________________________________________________________


tool: D13:    IP            At MAC Address     Count     Len  MAC Vendor / Hostname      


tool: D14:  -----------------------------------------------------------------------------


assistant: ```c
void unique_print_simple_header() {
  printf(" _____________________________________________________________________________\n");
  printf("   IP            At MAC Address     Count     Len  MAC Vendor / Hostname      \n");
  printf(" -----------------------------------------------------------------------------\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L32
L7:
  movl   $0x0,-0x14(%rbp)
  jmp    L49
L40:
  mov    -0x18(%rbp),%eax
  mov    -0x14(%rbp),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  neg    %eax
  lea    (%rcx,%rax,1),%esi
  addl   $0x1,-0xc(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L49:
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  neg    %eax
  mov    -0x18(%rbp),%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x14(%rbp)
  jle    L40
  addl   $0x1,-0x10(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x10(%rbp)
  jle    L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string

tool: D0: %d

tool: D2: %03d%12d%12d%12d


assistant: ```c
int main() {
  int n, b, c, i = 0;
  scanf("%d", &n);
  for (c = 0; c <= n / 5; ++c)
    for (b = 0; b <= (n - c * 5) / 2; ++b)
      printf("%03d%12d%12d%12d\n", ++i, n - b * 2 - c * 5, b, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D1(%rip),%r15
  cmpl   $0xfffffffc,0x4(%rsp)
  jge    L58
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  lea    0x1(%rbx,%r14,1),%r12d
  lea    (%rbx,%rbx,1),%eax
  sub    %eax,%edx
  add    %ebp,%edx
  mov    %r13d,%r8d
  mov    %ebx,%ecx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  lea    (%rdx,%rbp,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jge    L52
  mov    %r12d,%r14d
L5:
  add    $0x1,%r13d
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  cmp    %r13d,%eax
  jl     L28
L58:
  lea    0x0(%r13,%r13,4),%eax
  mov    %eax,%ebp
  neg    %ebp
  mov    0x4(%rsp),%edx
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    $0x0,%ebx
  cmp    $0xffffffff,%ecx
  jge    L52
  jmp    L5
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D11: %d

tool: D1: %03d%12d%12d%12d


assistant: ```c
int main() {
  int n, b, c, i = 0;
  scanf("%d", &n);
  for (c = 0; c <= n / 5; ++c)
    for (b = 0; b <= (n - c * 5) / 2; ++b)
      printf("%03d%12d%12d%12d\n", ++i, n - b * 2 - c * 5, b, c);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  lea    D17(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0xfffffffc,%edx
  jl     L33
  nopl   0x0(%rax)
L35:
  lea    (%r15,%r15,4),%eax
  mov    %edx,%ecx
  lea    0x1(%r13),%ebp
  xor    %ebx,%ebx
  mov    %eax,%r14d
  sub    %eax,%ecx
  neg    %r14d
  cmp    $0xffffffff,%ecx
  jl     L29
  nopl   0x0(%rax)
L25:
  lea    (%rbx,%rbx,1),%eax
  lea    0x0(%rbp,%rbx,1),%r13d
  mov    %ebx,%ecx
  mov    %r15d,%r8d
  sub    %eax,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    %r14d,%edx
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  lea    (%rdx,%r14,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jge    L25
L29:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    $0x1,%r15d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  cmp    %r15d,%eax
  jge    L35
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_infered: string
name: retrieve_data
arguments: data_tag: D11
type_infered: string

tool: D17: %d

tool: D11: %03d%12d%12d%12d


assistant: ```c
int main() {
  int n, b, c, i = 0;
  scanf("%d", &n);
  for (c = 0; c <= n / 5; ++c)
    for (b = 0; b <= (n - c * 5) / 2; ++b)
      printf("%03d%12d%12d%12d\n", ++i, n - b * 2 - c * 5, b, c);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%rdi
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D15(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    $0xfffffffc,%edx
  jl     L21
  nopl   0x0(%rax)
L47:
  lea    (%r15,%r15,4),%eax
  mov    %edx,%ecx
  lea    0x1(%r13),%ebp
  xor    %ebx,%ebx
  mov    %eax,%r14d
  sub    %eax,%ecx
  neg    %r14d
  cmp    $0xffffffff,%ecx
  jl     L35
  nopl   0x0(%rax)
L9:
  lea    (%rbx,%rbx,1),%eax
  lea    0x0(%rbp,%rbx,1),%r13d
  mov    %ebx,%ecx
  mov    %r15d,%r8d
  sub    %eax,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    %r14d,%edx
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  lea    (%rdx,%r14,1),%ecx
  mov    %ecx,%eax
  shr    $0x1f,%eax
  add    %ecx,%eax
  sar    %eax
  cmp    %ebx,%eax
  jge    L9
L35:
  movslq %edx,%rax
  mov    %edx,%ecx
  add    $0x1,%r15d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  cmp    %r15d,%eax
  jge    L47
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D15
type_infered: string

tool: D13: %d

tool: D15: %03d%12d%12d%12d


assistant: ```c
int main() {
  int n, b, c, i = 0;
  scanf("%d", &n);
  for (c = 0; c <= n / 5; ++c)
    for (b = 0; b <= (n - c * 5) / 2; ++b)
      printf("%03d%12d%12d%12d\n", ++i, n - b * 2 - c * 5, b, c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4e000(%rsp),%r11
L139:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L139
  sub    $0x230,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x4e224(%rbp)
  movl   $0xd,-0x4e218(%rbp)
  movl   $0x2,-0x4e210(%rbp)
  movl   $0x3,-0x4e220(%rbp)
  jmp    L132
L137:
  movl   $0x1,-0x4e214(%rbp)
  movl   $0x0,-0x4e21c(%rbp)
  jmp    L81
L65:
  mov    -0x4e21c(%rbp),%eax
  cltq
  mov    -0x4e210(%rbp,%rax,4),%ecx
  mov    -0x4e220(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L50
  movl   $0x0,-0x4e214(%rbp)
  jmp    L177
L50:
  addl   $0x1,-0x4e21c(%rbp)
L81:
  mov    -0x4e21c(%rbp),%eax
  cmp    -0x4e224(%rbp),%eax
  jl     L65
L177:
  cmpl   $0x0,-0x4e214(%rbp)
  je     L175
  mov    -0x4e224(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4e224(%rbp)
  cltq
  mov    -0x4e220(%rbp),%edx
  mov    %edx,-0x4e210(%rbp,%rax,4)
L175:
  addl   $0x1,-0x4e220(%rbp)
L132:
  cmpl   $0xf423f,-0x4e220(%rbp)
  jle    L137
  movl   $0x64,-0x4e220(%rbp)
  jmp    L176
L112:
  movl   $0x0,-0x4e214(%rbp)
  movl   $0x0,-0x4e21c(%rbp)
  jmp    L96
L103:
  mov    -0x4e21c(%rbp),%eax
  cltq
  mov    -0x4e210(%rbp,%rax,4),%eax
  cmp    %eax,-0x4e220(%rbp)
  jne    L21
  movl   $0x1,-0x4e214(%rbp)
  jmp    L77
L21:
  addl   $0x1,-0x4e21c(%rbp)
L96:
  mov    -0x4e21c(%rbp),%eax
  cmp    -0x4e224(%rbp),%eax
  jge    L77
  mov    -0x4e21c(%rbp),%eax
  cltq
  mov    -0x4e210(%rbp,%rax,4),%eax
  cmp    %eax,-0x4e220(%rbp)
  jge    L103
L77:
  cmpl   $0x0,-0x4e214(%rbp)
  je     L53
  mov    -0x4e224(%rbp),%edx
  lea    -0x4e210(%rbp),%rcx
  mov    -0x4e220(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <iscirc@plt>
  test   %rax,%rax
  je     L53
  addl   $0x1,-0x4e218(%rbp)
L53:
  addl   $0x1,-0x4e220(%rbp)
L176:
  cmpl   $0xf423f,-0x4e220(%rbp)
  jle    L112
  mov    -0x4e218(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: %d


assistant: ```c
int main() {
  int len = 1;
  int primes[80000];
  int i, j;
  int counter = 13;
  int isprime;
  primes[0] = 2;
  for (i = 3; i < 1000000; i++) {
    isprime = 1;
    for (j = 0; j < len; j++) {
      if (!(i % primes[j])) {
        isprime = 0;
        break;
      }
    }
    if (isprime) {
      primes[len++] = i;
    }
  }
  for (i = 100; i < 1000000; i++) {
    isprime = 0;
    for (j = 0; j < len && primes[j] <= i; j++)
      if (primes[j] == i) {
        isprime = 1;
        break;
      }
    if (isprime)
      if (iscirc(i, primes, len))
        counter++;
  }
  printf("%d\n", counter);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4e000(%rsp),%r11
L85:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L85
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x4e208(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  mov    $0x3,%esi
  mov    $0x1,%r12d
  lea    0x4(%rsp),%r8
  jmp    L17
L97:
  mov    %rsp,%r13
  lea    -0x1(%r12),%eax
  lea    0x4(%rsp,%rax,4),%rbp
  mov    $0xd,%r14d
  mov    $0x64,%ebx
  mov    %rsp,%r15
  jmp    L83
L116:
  mov    %r14d,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x4e208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x4e218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L74:
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %ebx,%edi
  call   <iscirc@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r14d
L61:
  add    $0x1,%ebx
  cmp    $0xf4240,%ebx
  je     L116
L83:
  mov    %r13,%rax
  test   %r12d,%r12d
  jle    L61
L136:
  mov    (%rax),%edx
  cmp    %ebx,%edx
  jg     L61
  je     L74
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L136
  jmp    L61
L71:
  movslq %r12d,%rax
  mov    %esi,(%rsp,%rax,4)
  lea    0x1(%r12),%r12d
L139:
  add    $0x1,%esi
  cmp    $0xf4240,%esi
  je     L97
L17:
  test   %r12d,%r12d
  jle    L71
  mov    %rsp,%rcx
  lea    -0x1(%r12),%eax
  lea    (%r8,%rax,4),%rdi
L82:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  je     L139
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L82
  jmp    L71
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: %d


assistant: ```c
int main() {
  int len = 1;
  int primes[80000];
  int i, j;
  int counter = 13;
  int isprime;
  primes[0] = 2;
  for (i = 3; i < 1000000; i++) {
    isprime = 1;
    for (j = 0; j < len; j++) {
      if (!(i % primes[j])) {
        isprime = 0;
        break;
      }
    }
    if (isprime) {
      primes[len++] = i;
    }
  }
  for (i = 100; i < 1000000; i++) {
    isprime = 0;
    for (j = 0; j < len && primes[j] <= i; j++)
      if (primes[j] == i) {
        isprime = 1;
        break;
      }
    if (isprime)
      if (iscirc(i, primes, len))
        counter++;
  }
  printf("%d\n", counter);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4e000(%rsp),%r11
L83:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L83
  sub    $0x218,%rsp
  mov    $0x3,%edi
  mov    $0x1,%r14d
  xor    %r9d,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x4e208(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  lea    0x4(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r9d,%eax
  mov    %rbp,%rcx
  mov    $0x2,%esi
  lea    0x0(%rbp,%rax,4),%r8
  jmp    L121
  nopw   0x0(%rax,%rax,1)
L105:
  mov    (%rcx),%esi
  add    $0x4,%rcx
L121:
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L119
  cmp    %r8,%rcx
  jne    L105
  movslq %r14d,%rax
  add    $0x1,%r14d
  mov    %edi,(%rsp,%rax,4)
  lea    -0x1(%r14),%r9d
L119:
  add    $0x1,%edi
  cmp    $0xf4240,%edi
  jne    L39
  lea    0x0(%rbp,%r9,4),%r15
  mov    $0x2,%edx
  mov    $0x64,%ebx
  mov    %rsp,%r13
  mov    $0xd,%r12d
  nopl   (%rax)
L118:
  mov    %rbp,%rax
  jmp    L123
  nopl   (%rax)
L79:
  mov    (%rax),%edx
  add    $0x4,%rax
L123:
  cmp    %ebx,%edx
  jg     L126
  je     L125
  cmp    %r15,%rax
  jne    L79
L126:
  add    $0x1,%ebx
  cmp    $0xf4240,%ebx
  je     L56
L96:
  mov    (%rsp),%edx
  jmp    L118
  nopl   0x0(%rax)
L125:
  mov    %ebx,%edi
  mov    %r14d,%edx
  mov    %r13,%rsi
  call   <iscirc@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r12d
  add    $0x1,%ebx
  cmp    $0xf4240,%ebx
  jne    L96
L56:
  mov    %r12d,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x4e208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L99
  add    $0x4e218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: %d


assistant: ```c
int main() {
  int len = 1;
  int primes[80000];
  int i, j;
  int counter = 13;
  int isprime;
  primes[0] = 2;
  for (i = 3; i < 1000000; i++) {
    isprime = 1;
    for (j = 0; j < len; j++) {
      if (!(i % primes[j])) {
        isprime = 0;
        break;
      }
    }
    if (isprime) {
      primes[len++] = i;
    }
  }
  for (i = 100; i < 1000000; i++) {
    isprime = 0;
    for (j = 0; j < len && primes[j] <= i; j++)
      if (primes[j] == i) {
        isprime = 1;
        break;
      }
    if (isprime)
      if (iscirc(i, primes, len))
        counter++;
  }
  printf("%d\n", counter);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4e000(%rsp),%r11
L63:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L63
  sub    $0x210,%rsp
  mov    $0x3,%esi
  mov    $0x1,%r13d
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x4e208(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  mov    %rsp,%r12
  lea    0x4(%rsp),%r9
  nopl   0x0(%rax)
L46:
  mov    %r8d,%eax
  mov    %r12,%rcx
  lea    (%r9,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  je     L104
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L13
  movslq %r13d,%rax
  add    $0x1,%r13d
  mov    %esi,(%rsp,%rax,4)
  lea    -0x1(%r13),%r8d
L104:
  add    $0x1,%esi
  cmp    $0xf4240,%esi
  jne    L46
  lea    (%r9,%r8,4),%rbp
  mov    $0xd,%r14d
  mov    $0x64,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %ebx,(%rax)
  jg     L64
  je     L37
  add    $0x4,%rax
  cmp    %rax,%rbp
  jne    L0
L64:
  add    $0x1,%ebx
  cmp    $0xf4240,%ebx
  jne    L4
L42:
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x4e208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x4e210,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %ebx,%edi
  mov    %r13d,%edx
  mov    %r12,%rsi
  call   <iscirc@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%r14d
  add    $0x1,%ebx
  cmp    $0xf4240,%ebx
  jne    L4
  jmp    L42
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main() {
  int len = 1;
  int primes[80000];
  int i, j;
  int counter = 13;
  int isprime;
  primes[0] = 2;
  for (i = 3; i < 1000000; i++) {
    isprime = 1;
    for (j = 0; j < len; j++) {
      if (!(i % primes[j])) {
        isprime = 0;
        break;
      }
    }
    if (isprime) {
      primes[len++] = i;
    }
  }
  for (i = 100; i < 1000000; i++) {
    isprime = 0;
    for (j = 0; j < len && primes[j] <= i; j++)
      if (primes[j] == i) {
        isprime = 1;
        break;
      }
    if (isprime)
      if (iscirc(i, primes, len))
        counter++;
  }
  printf("%d\n", counter);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<msleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x3e8,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  imul   $0xf4240,%edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void msleep(int ms) {
  struct timespec tm;
  tm.tv_sec = ms / 1000;
  tm.tv_nsec = (ms % 1000) * 1000000;
  nanosleep(&tm, NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<msleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(int ms) {
  struct timespec tm;
  tm.tv_sec = ms / 1000;
  tm.tv_nsec = (ms % 1000) * 1000000;
  nanosleep(&tm, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<msleep>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  mov    %eax,(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0xf4240,%edi,%edi
  mov    %edi,0x4(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void msleep(int ms) {
  struct timespec tm;
  tm.tv_sec = ms / 1000;
  tm.tv_nsec = (ms % 1000) * 1000000;
  nanosleep(&tm, NULL);
}
```