ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<__fsetlocking>:
  endbr64
  mov    %rdi,%rdx
  mov    (%rdi),%ecx
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  test   %eax,%ecx
  je     L22
  mov    D10(%rip),%rdi
  mov    (%rdi),%edi
L5:
  mov    D43(%rip),%r8
  cmp    %esi,(%r8)
  je     L27
  not    %eax
  and    %ecx,%eax
  mov    %eax,(%rdx)
  mov    D10(%rip),%rcx
  cmp    %esi,(%rcx)
  je     L13
L27:
  mov    %edi,%eax
  ret
L22:
  mov    D28(%rip),%rdi
  mov    (%rdi),%edi
  jmp    L5
L13:
  mov    D49(%rip),%rcx
  or     (%rcx),%eax
  mov    %eax,(%rdx)
  jmp    L27
```

assistant: ```c
int __fsetlocking(FILE *fp, int type) {
  int result = ((fp->_flags & _IO_USER_LOCK) ? FSETLOCKING_BYCALLER : FSETLOCKING_INTERNAL);
  if (type != FSETLOCKING_QUERY) {
    fp->_flags &= ~_IO_USER_LOCK;
    if (type == FSETLOCKING_BYCALLER)
      fp->_flags |= _IO_USER_LOCK;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__fsetlocking>:
  endbr64
  mov    D38(%rip),%rcx
  mov    (%rdi),%edx
  mov    (%rcx),%eax
  test   %eax,%edx
  je     L6
  mov    D15(%rip),%r8
  mov    (%r8),%r8d
L16:
  mov    D49(%rip),%r9
  cmp    %esi,(%r9)
  je     L9
  not    %eax
  and    %edx,%eax
  mov    D15(%rip),%rdx
  mov    %eax,(%rdi)
  cmp    %esi,(%rdx)
  je     L30
L9:
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L30:
  or     (%rcx),%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D20(%rip),%r8
  mov    (%r8),%r8d
  jmp    L16
```

assistant: ```c
int __fsetlocking(FILE *fp, int type) {
  int result = ((fp->_flags & _IO_USER_LOCK) ? FSETLOCKING_BYCALLER : FSETLOCKING_INTERNAL);
  if (type != FSETLOCKING_QUERY) {
    fp->_flags &= ~_IO_USER_LOCK;
    if (type == FSETLOCKING_BYCALLER)
      fp->_flags |= _IO_USER_LOCK;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__fsetlocking>:
  endbr64
  mov    D33(%rip),%rcx
  mov    (%rdi),%edx
  mov    (%rcx),%eax
  test   %eax,%edx
  je     L36
  mov    D11(%rip),%r8
  mov    (%r8),%r8d
L39:
  mov    D26(%rip),%r9
  cmp    %esi,(%r9)
  je     L0
  not    %eax
  and    %edx,%eax
  mov    D11(%rip),%rdx
  mov    %eax,(%rdi)
  cmp    %esi,(%rdx)
  je     L38
L0:
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L38:
  or     (%rcx),%eax
  mov    %eax,(%rdi)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    D43(%rip),%r8
  mov    (%r8),%r8d
  jmp    L39
```

assistant: ```c
int __fsetlocking(FILE *fp, int type) {
  int result = ((fp->_flags & _IO_USER_LOCK) ? FSETLOCKING_BYCALLER : FSETLOCKING_INTERNAL);
  if (type != FSETLOCKING_QUERY) {
    fp->_flags &= ~_IO_USER_LOCK;
    if (type == FSETLOCKING_BYCALLER)
      fp->_flags |= _IO_USER_LOCK;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<S>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L16
L2:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <s@plt>
  add    %rax,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L2
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long int S(unsigned long long int k) {
  unsigned long long int n;
  unsigned long long int ret = 0;
  for (n = 1; n <= k; ++n) {
    ret += s(n);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<S>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L19
  mov    $0x0,%ebp
  mov    $0x1,%ebx
L10:
  mov    %rbx,%rdi
  call   <s@plt>
  add    %rax,%rbp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jae    L10
L4:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    %rdi,%rbp
  jmp    L4
```

assistant: ```c
unsigned long long int S(unsigned long long int k) {
  unsigned long long int n;
  unsigned long long int ret = 0;
  for (n = 1; n <= k; ++n) {
    ret += s(n);
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<S>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbp
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <s@plt>
  add    %rax,%r12
  cmp    %rbx,%rbp
  jae    L19
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned long long int S(unsigned long long int k) {
  unsigned long long int n;
  unsigned long long int ret = 0;
  for (n = 1; n <= k; ++n) {
    ret += s(n);
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<S>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%rbp
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rbx,%rdi
  add    $0x1,%rbx
  call   <s@plt>
  add    %rax,%r12
  cmp    %rbx,%rbp
  jae    L10
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L11:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
unsigned long long int S(unsigned long long int k) {
  unsigned long long int n;
  unsigned long long int ret = 0;
  for (n = 1; n <= k; ++n) {
    ret += s(n);
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<checkExists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L1
  mov    -0x4(%rbp),%eax
  jmp    L25
L1:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L9
  mov    $0xffffffff,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int checkExists(char character, char *ocurrences, int maxCharacter) {
  int i;
  for (i = 0; i < maxCharacter; i++)
    if ((int)ocurrences[i] == (int)character)
      return i;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<checkExists>:
  endbr64
  test   %edx,%edx
  jle    L1
  mov    %edx,%edx
  mov    $0x0,%eax
L9:
  mov    %eax,%ecx
  cmp    %dil,(%rsi,%rax,1)
  je     L36
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
  mov    $0xffffffff,%ecx
L36:
  mov    %ecx,%eax
  ret
L1:
  mov    $0xffffffff,%ecx
  jmp    L36
```

assistant: ```c
int checkExists(char character, char *ocurrences, int maxCharacter) {
  int i;
  for (i = 0; i < maxCharacter; i++)
    if ((int)ocurrences[i] == (int)character)
      return i;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<checkExists>:
  endbr64
  test   %edx,%edx
  jle    L35
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L8
  nop
L14:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L35
L8:
  mov    %eax,%r8d
  cmp    %dil,(%rsi,%rax,1)
  jne    L14
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int checkExists(char character, char *ocurrences, int maxCharacter) {
  int i;
  for (i = 0; i < maxCharacter; i++)
    if ((int)ocurrences[i] == (int)character)
      return i;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<checkExists>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L36
  nop
L37:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L11
L36:
  mov    %eax,%r8d
  cmp    %dil,(%rsi,%rax,1)
  jne    L37
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int checkExists(char character, char *ocurrences, int maxCharacter) {
  int i;
  for (i = 0; i < maxCharacter; i++)
    if ((int)ocurrences[i] == (int)character)
      return i;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x30(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm3
  movapd %xmm0,%xmm2
  subsd  %xmm3,%xmm2
  movsd  -0x28(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
type_infered: string
name: unpack_data
arguments: tag: D17
type_infered: string

tool: D14: %lf %lf %lf %lf

tool: D17: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2, ans;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  ans = (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);
  ans = sqrt(ans);
  printf("%.4lf\n", ans);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  subsd  0x18(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  subsd  0x20(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L12
  sqrtsd %xmm0,%xmm0
L23:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L12:
  call   <sqrt@plt>
  jmp    L23
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D3: %lf %lf %lf %lf

tool: D1: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2, ans;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  ans = (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);
  ans = sqrt(ans);
  printf("%.4lf\n", ans);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D9(%rip),%rdi
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  subsd  0x18(%rsp),%xmm0
  subsd  0x20(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L5
  sqrtsd %xmm0,%xmm0
L4:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L5:
  call   <sqrt@plt>
  jmp    L4
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string

tool: D9: %lf %lf %lf %lf

tool: D15: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2, ans;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  ans = (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);
  ans = sqrt(ans);
  printf("%.4lf\n", ans);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D5(%rip),%rdi
  lea    0x18(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x20(%rsp),%r8
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  subsd  0x18(%rsp),%xmm0
  subsd  0x20(%rsp),%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L22
  sqrtsd %xmm0,%xmm0
L1:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L22:
  call   <sqrt@plt>
  jmp    L1
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string

tool: D5: %lf %lf %lf %lf

tool: D2: %.4lf


assistant: ```c
int main() {
  double x1, y1, x2, y2, ans;
  scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
  ans = (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2);
  ans = sqrt(ans);
  printf("%.4lf\n", ans);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L79
L24:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%r12d
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%ebx
  movsbl %r12b,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L67
  movsbl %r12b,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  jmp    L74
L67:
  mov    %r12d,%eax
L74:
  mov    %eax,%r12d
  movsbl %bl,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L50
  movsbl %bl,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  jmp    L28
L50:
  mov    %ebx,%eax
L28:
  mov    %eax,%ebx
  cmp    %bl,%r12b
  jne    L7
  subl   $0x1,-0x24(%rbp)
L79:
  cmpl   $0x0,-0x24(%rbp)
  jne    L24
  jmp    L66
L7:
  nop
L66:
  mov    -0x24(%rbp),%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int strncasecmp(string1, string2, count)
char *string1, *string2;
int count;
{
  register char ch1, ch2;
  while (count) {
    ch1 = *string1++;
    ch2 = *string2++;
    ch1 = (islower(ch1) ? toupper(ch1) : ch1);
    ch2 = (islower(ch2) ? toupper(ch2) : ch2);
    if (ch1 == ch2)
      count--;
    else
      break;
  }
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncasecmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    %edx,%r12d
  test   %edx,%edx
  jne    L28
  mov    %edx,%eax
  jmp    L47
L5:
  cmp    %bl,%bpl
  jne    L77
  sub    $0x1,%r12d
  je     L35
L28:
  add    $0x1,%r14
  movzbl -0x1(%r14),%ebp
  add    $0x1,%r13
  movzbl -0x1(%r13),%ebx
  movsbl %bpl,%r15d
  mov    %r15d,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L70
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebp
L70:
  movsbl %bl,%r15d
  mov    %r15d,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L5
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  jmp    L5
L35:
  mov    %r12d,%eax
  jmp    L47
L77:
  mov    %r12d,%eax
L47:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strncasecmp(string1, string2, count)
char *string1, *string2;
int count;
{
  register char ch1, ch2;
  while (count) {
    ch1 = *string1++;
    ch2 = *string2++;
    ch1 = (islower(ch1) ? toupper(ch1) : ch1);
    ch2 = (islower(ch2) ? toupper(ch2) : ch2);
    if (ch1 == ch2)
      count--;
    else
      break;
  }
  return (count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncasecmp>:
  endbr64
  test   %edx,%edx
  je     L31
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L38
  nopl   (%rax)
L28:
  sub    $0x1,%r12d
  je     L26
L38:
  movsbl (%r14),%r15d
  add    $0x1,%r14
  add    $0x1,%r13
  movzbl -0x1(%r13),%ebx
  mov    %r15d,%edi
  mov    %r15d,%ebp
  call   <islower@plt>
  test   %eax,%eax
  je     L8
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebp
L8:
  movsbl %bl,%r15d
  mov    %r15d,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L9
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
L9:
  cmp    %bl,%bpl
  je     L28
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncasecmp(string1, string2, count)
char *string1, *string2;
int count;
{
  register char ch1, ch2;
  while (count) {
    ch1 = *string1++;
    ch2 = *string2++;
    ch1 = (islower(ch1) ? toupper(ch1) : ch1);
    ch2 = (islower(ch2) ? toupper(ch2) : ch2);
    if (ch1 == ch2)
      count--;
    else
      break;
  }
  return (count);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strncasecmp>:
  endbr64
  test   %edx,%edx
  je     L15
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L16
  nopl   (%rax)
L34:
  sub    $0x1,%r12d
  je     L50
L16:
  movsbl (%r14),%r15d
  add    $0x1,%r14
  add    $0x1,%r13
  movzbl -0x1(%r13),%ebx
  mov    %r15d,%edi
  mov    %r15d,%ebp
  call   <islower@plt>
  test   %eax,%eax
  je     L41
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebp
L41:
  movsbl %bl,%r15d
  mov    %r15d,%edi
  call   <islower@plt>
  test   %eax,%eax
  je     L32
  mov    %r15d,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
L32:
  cmp    %bl,%bpl
  je     L34
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L50:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncasecmp(string1, string2, count)
char *string1, *string2;
int count;
{
  register char ch1, ch2;
  while (count) {
    ch1 = *string1++;
    ch2 = *string2++;
    ch1 = (islower(ch1) ? toupper(ch1) : ch1);
    ch2 = (islower(ch2) ? toupper(ch2) : ch2);
    if (ch1 == ch2)
      count--;
    else
      break;
  }
  return (count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__wrap_calloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <irq_disable@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__real_calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <irq_restore@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *__wrap_calloc(size_t nmemb, size_t size) {
  unsigned state = irq_disable();
  void *ptr = __real_calloc(nmemb, size);
  irq_restore(state);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__wrap_calloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    $0x0,%eax
  call   <irq_disable@plt>
  mov    %eax,%ebp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <__real_calloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <irq_restore@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *__wrap_calloc(size_t nmemb, size_t size) {
  unsigned state = irq_disable();
  void *ptr = __real_calloc(nmemb, size);
  irq_restore(state);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__wrap_calloc>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <irq_disable@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <__real_calloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <irq_restore@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *__wrap_calloc(size_t nmemb, size_t size) {
  unsigned state = irq_disable();
  void *ptr = __real_calloc(nmemb, size);
  irq_restore(state);
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__wrap_calloc>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <irq_disable@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <__real_calloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r12
  call   <irq_restore@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *__wrap_calloc(size_t nmemb, size_t size) {
  unsigned state = irq_disable();
  void *ptr = __real_calloc(nmemb, size);
  irq_restore(state);
  return ptr;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_sentence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  jne    L78
  mov    -0x18(%rbp),%rax
  mov    $0x24,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L9
L78:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x10(%rbp)
L9:
  cmpq   $0x0,-0x10(%rbp)
  jne    L73
  mov    $0x0,%eax
  jmp    L52
L73:
  mov    -0x10(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L52
L49:
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jge    L23
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  jmp    L52
L23:
  mov    $0x0,%eax
L52:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
data_type: string

tool: D2: 


assistant: ```c
char *find_sentence(char *buf, int bsz, const char *prfx) {
  char *bp = NULL, *ep = NULL;
  buf[bsz - 1] = '\0';
  if (prfx == NULL)
    bp = strstr(buf, "$");
  else
    bp = strstr(buf, prfx);
  if (bp == NULL)
    return NULL;
  ep = strstr(bp, "\r\n");
  if (ep == NULL)
    return NULL;
  if (ep + 2 - buf < bsz)
    ep[2] = '\0';
  else
    return NULL;
  return bp;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<find_sentence>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  movslq %esi,%rax
  movb   $0x0,-0x1(%rdi,%rax,1)
  test   %rdx,%rdx
  je     L17
  mov    %rdx,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
L59:
  test   %rbp,%rbp
  je     L56
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L25
  lea    0x2(%rax),%rdx
  sub    %r12,%rdx
  movslq %ebx,%rbx
  cmp    %rbx,%rdx
  jge    L40
  movb   $0x0,0x2(%rax)
L56:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x24,%esi
  call   <strchr@plt>
  mov    %rax,%rbp
  jmp    L59
L25:
  mov    %rax,%rbp
  jmp    L56
L40:
  mov    $0x0,%ebp
  jmp    L56
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string

tool: D2: 


assistant: ```c
char *find_sentence(char *buf, int bsz, const char *prfx) {
  char *bp = NULL, *ep = NULL;
  buf[bsz - 1] = '\0';
  if (prfx == NULL)
    bp = strstr(buf, "$");
  else
    bp = strstr(buf, prfx);
  if (bp == NULL)
    return NULL;
  ep = strstr(bp, "\r\n");
  if (ep == NULL)
    return NULL;
  if (ep + 2 - buf < bsz)
    ep[2] = '\0';
  else
    return NULL;
  return bp;
}
```