ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<leastvalueinv>:
  endbr64
  push   %r13
  push   %r12
  mov    $0xffffffff,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L55:
  mov    0x0(%rbp),%edi
  add    %r12d,%edi
  call   <value@plt>
  mov    0x0(%rbp),%edi
  mov    %rax,%r13
  add    %ebx,%edi
  call   <value@plt>
  cmp    %rax,%r13
  jg     L61
L69:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  je     L29
L72:
  cmp    $0xffffffff,%r12d
  jne    L55
  movslq %ebx,%rax
L47:
  mov    0x0(%rbp,%rax,4),%edx
  mov    %eax,%ebx
  test   %edx,%edx
  jle    L75
  add    $0x1,%ebx
  mov    %eax,%r12d
  cmp    $0xa,%ebx
  jne    L72
L29:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L75:
  add    $0x1,%rax
  cmp    $0xa,%eax
  jne    L47
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L61:
  mov    0x0(%rbp),%edi
  add    %ebx,%edi
  call   <value@plt>
  test   %rax,%rax
  cmovg  %ebx,%r12d
  jmp    L69
```

assistant: ```c
int leastvalueinv(int *inv) {
  int min = -1;
  int pos;
  for (pos = 0; pos < 10; pos++) {
    if (min < 0) {
      if (*(inv + pos) > 0)
        min = pos;
    } else if ((value(*inv + min) > value(*inv + pos)) && (value(*inv + pos) > 0))
      min = pos;
  }
  return min;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  jmp    L4
L14:
  mov    $0x0,%eax
  call   <getppid@plt>
  addq   $0x1,-0x8(%rbp)
L4:
  cmpq   $0x5f5e0ff,-0x8(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    getppid();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
L9:
  mov    $0x0,%eax
  call   <getppid@plt>
  sub    $0x1,%rbx
  jne    L9
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    getppid();
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <getppid@plt>
  sub    $0x1,%rbx
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    getppid();
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5f5e100,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  call   <getppid@plt>
  sub    $0x1,%rbx
  jne    L5
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  for (long long i = 0; i < 100000000; ++i) {
    getppid();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x2e333231,-0xe(%rbp)
  movw   $0x30,-0xa(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  movsd  D8(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D8
datatype: f64
name: unpack_data
arguments: tag: D5
datatype: f64

tool: D29: 

Hello World!


tool: D8: 180

tool: D5: 3.141592

assistant: ```c
int main(void) {
  printf("\n\nHello World!\n");
  char expression[] = "123.0";
  double res = atof(expression);
  res = atan(res) * 180.0 / 3.141592;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  movl   $0x2e333231,0x2(%rsp)
  movw   $0x30,0x6(%rsp)
  lea    0x2(%rsp),%rdi
  call   <atof@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: 

Hello World!


assistant: ```c
int main(void) {
  printf("\n\nHello World!\n");
  char expression[] = "123.0";
  double res = atof(expression);
  res = atan(res) * 180.0 / 3.141592;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x30,%eax
  lea    0x2(%rsp),%rdi
  movl   $0x2e333231,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <atof@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: 

Hello World!


assistant: ```c
int main(void) {
  printf("\n\nHello World!\n");
  char expression[] = "123.0";
  double res = atof(expression);
  res = atan(res) * 180.0 / 3.141592;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x30,%eax
  lea    0x2(%rsp),%rdi
  movl   $0x2e333231,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <atof@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
data_type: string

tool: D3: 

Hello World!


assistant: ```c
int main(void) {
  printf("\n\nHello World!\n");
  char expression[] = "123.0";
  double res = atof(expression);
  res = atan(res) * 180.0 / 3.141592;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log2v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L25
  movsd  -0x18(%rbp),%xmm0
  jmp    L39
L25:
  movsd  -0x20(%rbp),%xmm0
L39:
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x20(%rbp),%xmm0
  comisd -0x18(%rbp),%xmm0
  jb     L27
  movsd  -0x18(%rbp),%xmm0
  jmp    L22
L27:
  movsd  -0x20(%rbp),%xmm0
L22:
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm2
  divsd  -0x10(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <log1p@plt>
  addsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double log2v(double a, double b) {
  double max, min;
  max = (a > b) ? a : b;
  min = (a <= b) ? a : b;
  return (log(max) + log1p(min / max));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log2v>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movapd %xmm0,%xmm3
  maxsd  %xmm1,%xmm3
  movapd %xmm0,%xmm2
  cmplesd %xmm1,%xmm2
  andpd  %xmm2,%xmm0
  andnpd %xmm1,%xmm2
  orpd   %xmm0,%xmm2
  movq   %xmm2,%rbx
  movsd  %xmm3,0x8(%rsp)
  movapd %xmm3,%xmm0
  call   <log@plt>
  movq   %xmm0,%r14
  movq   %rbx,%xmm4
  divsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm0
  call   <log1p@plt>
  movq   %r14,%xmm5
  addsd  %xmm5,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double log2v(double a, double b) {
  double max, min;
  max = (a > b) ? a : b;
  min = (a <= b) ? a : b;
  return (log(max) + log1p(min / max));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log2v>:
  endbr64
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  sub    $0x28,%rsp
  cmplesd %xmm1,%xmm0
  maxsd  %xmm1,%xmm3
  andpd  %xmm0,%xmm2
  andnpd %xmm1,%xmm0
  movsd  %xmm3,0x10(%rsp)
  orpd   %xmm0,%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  divsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  call   <log1p@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

assistant: ```c
double log2v(double a, double b) {
  double max, min;
  max = (a > b) ? a : b;
  min = (a <= b) ? a : b;
  return (log(max) + log1p(min / max));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<log2v>:
  endbr64
  movapd %xmm0,%xmm2
  movapd %xmm0,%xmm3
  sub    $0x28,%rsp
  cmplesd %xmm1,%xmm0
  maxsd  %xmm1,%xmm3
  andpd  %xmm0,%xmm2
  andnpd %xmm1,%xmm0
  movsd  %xmm3,0x10(%rsp)
  orpd   %xmm0,%xmm2
  movapd %xmm3,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm3
  movsd  %xmm0,0x8(%rsp)
  divsd  %xmm3,%xmm2
  movapd %xmm2,%xmm0
  call   <log1p@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  ret
```

assistant: ```c
double log2v(double a, double b) {
  double max, min;
  max = (a > b) ? a : b;
  min = (a <= b) ? a : b;
  return (log(max) + log1p(min / max));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L3
L70:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x48(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x38(%rbp)
L3:
  cmpl   $0x3,-0x38(%rbp)
  jle    L70
  movl   $0xa,-0x38(%rbp)
  jmp    L53
L55:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x38(%rbp),%edx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rrr_enc_dec_round@plt>
  addl   $0xc,-0x34(%rbp)
  subl   $0x1,-0x38(%rbp)
L53:
  cmpl   $0x0,-0x38(%rbp)
  jg     L55
  movl   $0x0,-0x38(%rbp)
  jmp    L4
L72:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x38(%rbp)
L4:
  cmpl   $0x3,-0x38(%rbp)
  jle    L72
  movl   $0x0,-0x38(%rbp)
  jmp    L67
L56:
  mov    -0x38(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x38(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  mov    %eax,%edx
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x48(%rbp),%rax
  add    %rcx,%rax
  xor    %ebx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x38(%rbp)
L67:
  cmpl   $0x3,-0x38(%rbp)
  jle    L56
  movl   $0x0,-0x38(%rbp)
  jmp    L16
L20:
  mov    -0x38(%rbp),%eax
  cltq
  add    $0x4,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x38(%rbp)
L16:
  cmpl   $0x3,-0x38(%rbp)
  jle    L20
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void Encrypt(uint8_t *block, uint8_t *roundKeys) {
  uint8_t i, temp[4] = {0}, j = 4;
  for (i = 0; i < 4; i++)
    block[i] ^= READ_ROUND_KEY_BYTE(roundKeys[i]);
  for (i = 10; i > 0; i--) {
    rrr_enc_dec_round(block, roundKeys + j, i);
    j += 12;
  }
  for (i = 0; i < 4; i++)
    temp[i] = block[i];
  for (i = 0; i < 4; i++)
    block[i] = block[i + 4] ^ READ_ROUND_KEY_BYTE(roundKeys[i + 4]);
  for (i = 0; i < 4; i++)
    block[i + 4] = temp[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Encrypt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    $0x0,%ebx
L26:
  mov    0x0(%r13,%rbx,1),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,0x0(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L26
  lea    0x10(%r13),%r14
  mov    $0xa,%r12d
L1:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <rrr_enc_dec_round@plt>
  add    $0x30,%r14
  sub    $0x1,%r12d
  jne    L1
  mov    0x0(%rbp),%r15d
  mov    0x4(%rbp),%r14d
  mov    0x8(%rbp),%eax
  mov    %eax,0xc(%rsp)
  mov    0xc(%rbp),%eax
  mov    %eax,0x8(%rsp)
L23:
  mov    0x0(%rbp,%rbx,1),%r12d
  mov    0x0(%r13,%rbx,1),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%r12d
  mov    %r12d,-0x10(%rbp,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  jne    L23
  mov    %r15d,0x10(%rbp)
  mov    %r14d,0x14(%rbp)
  mov    0xc(%rsp),%eax
  mov    %eax,0x18(%rbp)
  mov    0x8(%rsp),%eax
  mov    %eax,0x1c(%rbp)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Encrypt(uint8_t *block, uint8_t *roundKeys) {
  uint8_t i, temp[4] = {0}, j = 4;
  for (i = 0; i < 4; i++)
    block[i] ^= READ_ROUND_KEY_BYTE(roundKeys[i]);
  for (i = 10; i > 0; i--) {
    rrr_enc_dec_round(block, roundKeys + j, i);
    j += 12;
  }
  for (i = 0; i < 4; i++)
    temp[i] = block[i];
  for (i = 0; i < 4; i++)
    block[i] = block[i + 4] ^ READ_ROUND_KEY_BYTE(roundKeys[i + 4]);
  for (i = 0; i < 4; i++)
    block[i + 4] = temp[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Encrypt>:
  endbr64
  push   %r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L0:
  mov    (%r14,%rbx,1),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L0
  lea    0x10(%r14),%r13
  mov    $0xa,%ebp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rsi
  mov    %ebp,%edx
  mov    %r12,%rdi
  add    $0x30,%r13
  call   <rrr_enc_dec_round@plt>
  sub    $0x1,%ebp
  jne    L8
  mov    (%r12),%r15
  mov    0x8(%r12),%r13
L5:
  mov    (%r14,%rbx,1),%edi
  mov    (%r12,%rbx,1),%ebp
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%ebp
  mov    %ebp,-0x10(%r12,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  jne    L5
  mov    %r15d,0x10(%r12)
  sar    $0x20,%r15
  mov    %r13d,0x18(%r12)
  sar    $0x20,%r13
  mov    %r15d,0x14(%r12)
  mov    %r13d,0x1c(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void Encrypt(uint8_t *block, uint8_t *roundKeys) {
  uint8_t i, temp[4] = {0}, j = 4;
  for (i = 0; i < 4; i++)
    block[i] ^= READ_ROUND_KEY_BYTE(roundKeys[i]);
  for (i = 10; i > 0; i--) {
    rrr_enc_dec_round(block, roundKeys + j, i);
    j += 12;
  }
  for (i = 0; i < 4; i++)
    temp[i] = block[i];
  for (i = 0; i < 4; i++)
    block[i] = block[i + 4] ^ READ_ROUND_KEY_BYTE(roundKeys[i + 4]);
  for (i = 0; i < 4; i++)
    block[i + 4] = temp[i];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Encrypt>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
L25:
  mov    (%r14,%rbx,1),%edi
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,0x0(%r13,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L25
  lea    0x10(%r14),%r12
  mov    $0xa,%ebp
  nopl   0x0(%rax)
L9:
  mov    %r12,%rsi
  mov    %ebp,%edx
  mov    %r13,%rdi
  add    $0x30,%r12
  call   <rrr_enc_dec_round@plt>
  sub    $0x1,%ebp
  jne    L9
  movdqu 0x0(%r13),%xmm0
  movaps %xmm0,(%rsp)
L5:
  mov    (%r14,%rbx,1),%edi
  mov    0x0(%r13,%rbx,1),%ebp
  call   <READ_ROUND_KEY_BYTE@plt>
  xor    %eax,%ebp
  mov    %ebp,-0x10(%r13,%rbx,1)
  add    $0x4,%rbx
  cmp    $0x20,%rbx
  jne    L5
  movdqa (%rsp),%xmm1
  movups %xmm1,0x10(%r13)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void Encrypt(uint8_t *block, uint8_t *roundKeys) {
  uint8_t i, temp[4] = {0}, j = 4;
  for (i = 0; i < 4; i++)
    block[i] ^= READ_ROUND_KEY_BYTE(roundKeys[i]);
  for (i = 10; i > 0; i--) {
    rrr_enc_dec_round(block, roundKeys + j, i);
    j += 12;
  }
  for (i = 0; i < 4; i++)
    temp[i] = block[i];
  for (i = 0; i < 4; i++)
    block[i] = block[i + 4] ^ READ_ROUND_KEY_BYTE(roundKeys[i + 4]);
  for (i = 0; i < 4; i++)
    block[i + 4] = temp[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<buffer_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <buffer_move_logic@plt>
  leave
  ret
```

assistant: ```c
size_t buffer_move(void *buf, void *data, size_t length) {
  struct Buffer *buffer = buf;
  return buffer_move_logic(buffer, data, length, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<buffer_move>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  call   <buffer_move_logic@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
size_t buffer_move(void *buf, void *data, size_t length) {
  struct Buffer *buffer = buf;
  return buffer_move_logic(buffer, data, length, 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<buffer_move>:
  endbr64
  xor    %ecx,%ecx
  jmp    1050 <buffer_move_logic@plt>
```

assistant: ```c
size_t buffer_move(void *buf, void *data, size_t length) {
  struct Buffer *buffer = buf;
  return buffer_move_logic(buffer, data, length, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<buffer_move>:
  endbr64
  xor    %ecx,%ecx
  jmp    1050 <buffer_move_logic@plt>
```

assistant: ```c
size_t buffer_move(void *buf, void *data, size_t length) {
  struct Buffer *buffer = buf;
  return buffer_move_logic(buffer, data, length, 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  cld
L8:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L8
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
extern char *strcpy(char *dest, const char *src) {
  __asm__("cld\n"
          "1:\tlodsb\n\t"
          "stosb\n\t"
          "testb %%al,%%al\n\t"
          "jne 1b" ::"S"(src),
          "D"(dest));
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcpy>:
  endbr64
  cld
L9:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L9
  mov    %rdi,%rax
  ret
```

assistant: ```c
extern char *strcpy(char *dest, const char *src) {
  __asm__("cld\n"
          "1:\tlodsb\n\t"
          "stosb\n\t"
          "testb %%al,%%al\n\t"
          "jne 1b" ::"S"(src),
          "D"(dest));
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  cld
L0:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L0
  ret
```

assistant: ```c
extern char *strcpy(char *dest, const char *src) {
  __asm__("cld\n"
          "1:\tlodsb\n\t"
          "stosb\n\t"
          "testb %%al,%%al\n\t"
          "jne 1b" ::"S"(src),
          "D"(dest));
  return dest;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  cld
L2:
  lods   %ds:(%rsi),%al
  stos   %al,%es:(%rdi)
  test   %al,%al
  jne    L2
  ret
```

assistant: ```c
extern char *strcpy(char *dest, const char *src) {
  __asm__("cld\n"
          "1:\tlodsb\n\t"
          "stosb\n\t"
          "testb %%al,%%al\n\t"
          "jne 1b" ::"S"(src),
          "D"(dest));
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<splitStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x2000,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x48(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L16
L15:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L31
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,(%rbx)
  addl   $0x1,-0x34(%rbp)
L31:
  lea    -0x30(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strsep@plt>
  mov    %rax,-0x28(%rbp)
L16:
  cmpq   $0x0,-0x28(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D19
data_type: string

tool: D19: ,

assistant: ```c
int splitStr(char *input, int *output) {
  char *str = malloc(sizeof(char) * 8192);
  strcpy(str, input);
  char *str_start = str;
  int i = 0;
  for (char *token = strsep(&str, ","); token != NULL; token = strsep(&str, ",")) {
    if (token[0] != '\0') {
      output[i] = strtol(token, NULL, 10);
      i++;
    }
  }
  free(str_start);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<splitStr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x2000,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    (%rsp),%r12
  mov    %rsp,%rdi
  lea    D2(%rip),%rsi
  call   <strsep@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rdi
  mov    $0x0,%r13d
  lea    D2(%rip),%rbx
  jmp    L12
L43:
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <strsep@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L10
L12:
  cmpb   $0x0,(%rdi)
  je     L43
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%r14
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,(%r14)
  add    $0x1,%r13d
  jmp    L43
L10:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_infered: string

tool: D2: ,

assistant: ```c
int splitStr(char *input, int *output) {
  char *str = malloc(sizeof(char) * 8192);
  strcpy(str, input);
  char *str_start = str;
  int i = 0;
  for (char *token = strsep(&str, ","); token != NULL; token = strsep(&str, ",")) {
    if (token[0] != '\0') {
      output[i] = strtol(token, NULL, 10);
      i++;
    }
  }
  free(str_start);
  return 0;
}
```