ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edi
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L11:
  cmp    %rdx,%rsp
  je     L8
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L11
L8:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L57
  orq    $0x0,-0x8(%rsp,%rax,1)
L57:
  mov    %rsp,%r14
  test   %edi,%edi
  jle    L50
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D18(%rip),%r13
L39:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%edi
  add    $0x4,%r12
  cmp    %ebx,%edi
  jg     L39
L50:
  mov    %r14,%rsi
  call   <insertionSort@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D18
data_type: string

tool: D18: %d

assistant: ```c
int main(void) {
  int _ar_size;
  scanf("%d", &_ar_size);
  int _ar[_ar_size], _ar_i;
  for (_ar_i = 0; _ar_i < _ar_size; _ar_i++) {
    scanf("%d", &_ar[_ar_i]);
  }
  insertionSort(_ar_size, _ar);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D7(%rip),%r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L45
L68:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L68
L45:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L60
L15:
  mov    %rsp,%r14
  test   %edi,%edi
  jle    L67
  mov    %r14,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edi
  cmp    %ebx,%edi
  jg     L4
L67:
  mov    %r14,%rsi
  call   <insertionSort@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L60:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L15
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: %d

assistant: ```c
int main(void) {
  int _ar_size;
  scanf("%d", &_ar_size);
  int _ar[_ar_size], _ar_i;
  for (_ar_i = 0; _ar_i < _ar_size; _ar_i++) {
    scanf("%d", &_ar[_ar_i]);
  }
  insertionSort(_ar_size, _ar);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D9(%rip),%r13
  lea    -0x2c(%rbp),%rsi
  push   %r12
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L24
L36:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L36
L24:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L11
L31:
  mov    %rsp,%r14
  test   %edi,%edi
  jle    L32
  mov    %r14,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L56:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  mov    -0x2c(%rbp),%edi
  cmp    %ebx,%edi
  jg     L56
L32:
  mov    %r14,%rsi
  call   <insertionSort@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L11:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L31
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: %d

assistant: ```c
int main(void) {
  int _ar_size;
  scanf("%d", &_ar_size);
  int _ar[_ar_size], _ar_i;
  for (_ar_i = 0; _ar_i < _ar_size; _ar_i++) {
    scanf("%d", &_ar[_ar_i]);
  }
  insertionSort(_ar_size, _ar);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D32(%rip),%xmm0
  movss  %xmm0,-0x10(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x18(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  D74(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  -0xc(%rbp),%xmm0
  divss  -0x10(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D32
type_infered: byte[4]
name: parse_data
arguments: label: D35
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D53
type_infered: string
name: parse_data
arguments: label: D74
type_infered: byte[4]
name: parse_data
arguments: label: D71
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: {"D32": [0x00,0x8b,0x1c,0x47]}

tool: D35: Gunde ortalama kac km. yuruyorsunuz?

tool: D16: %f

tool: D53: Kac yildir yuruyorsunuz?

tool: {"D74": [0x00,0x80,0xb6,0x43]}

tool: D71: Bugune kadar yurudugunuz toplam mesafe(km): %.f


tool: D13: Bugune kadar dunyanin cevresini kac kez turladiginiz: %f


assistant: ```c
int main() {
  float avg, age, r, res;
  r = 40075;
  printf("Gunde ortalama kac km. yuruyorsunuz?\n");
  scanf("%f", &avg);
  printf("Kac yildir yuruyorsunuz?\n");
  scanf("%f", &age);
  res = avg * age * 365;
  printf("Bugune kadar yurudugunuz toplam mesafe(km): %.f\n", res);
  printf("Bugune kadar dunyanin cevresini kac kez turladiginiz: %f\n", res / r);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D60(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm0
  mulss  0x14(%rsp),%xmm0
  mulss  D43(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  divss  D66(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string
name: retrieve_data
arguments: data_label: D60
type_infered: string
name: retrieve_data
arguments: data_label: D64
type_infered: string
name: retrieve_data
arguments: data_label: D43
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D66
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D58
type_infered: string

tool: D7: Gunde ortalama kac km. yuruyorsunuz?

tool: D60: %f

tool: D64: Kac yildir yuruyorsunuz?

tool: {"D43": [0x00,0x80,0xb6,0x43]}

tool: D10: Bugune kadar yurudugunuz toplam mesafe(km): %.f


tool: {"D66": [0x00,0x8b,0x1c,0x47]}

tool: D58: Bugune kadar dunyanin cevresini kac kez turladiginiz: %f


assistant: ```c
int main() {
  float avg, age, r, res;
  r = 40075;
  printf("Gunde ortalama kac km. yuruyorsunuz?\n");
  scanf("%f", &avg);
  printf("Kac yildir yuruyorsunuz?\n");
  scanf("%f", &age);
  res = avg * age * 365;
  printf("Bugune kadar yurudugunuz toplam mesafe(km): %.f\n", res);
  printf("Bugune kadar dunyanin cevresini kac kez turladiginiz: %f\n", res / r);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  lea    D53(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  mulss  0x14(%rsp),%xmm1
  lea    D18(%rip),%rdi
  mulss  D13(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D31(%rip),%rdi
  movss  0xc(%rsp),%xmm1
  divss  D1(%rip),%xmm1
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D37
type_infered: string
name: extract_symbolic_data
arguments: data_label: D53
type_infered: string
name: extract_symbolic_data
arguments: data_label: D46
type_infered: string
name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D13
type_infered: byte[4]
name: extract_symbolic_data
arguments: data_label: D31
type_infered: string
name: extract_symbolic_data
arguments: data_label: D1
type_infered: byte[4]

tool: D37: Gunde ortalama kac km. yuruyorsunuz?

tool: D53: %f

tool: D46: Kac yildir yuruyorsunuz?

tool: D18: Bugune kadar yurudugunuz toplam mesafe(km): %.f


tool: {"D13": [0x00,0x80,0xb6,0x43]}

tool: D31: Bugune kadar dunyanin cevresini kac kez turladiginiz: %f


tool: {"D1": [0x00,0x8b,0x1c,0x47]}

assistant: ```c
int main() {
  float avg, age, r, res;
  r = 40075;
  printf("Gunde ortalama kac km. yuruyorsunuz?\n");
  scanf("%f", &avg);
  printf("Kac yildir yuruyorsunuz?\n");
  scanf("%f", &age);
  res = avg * age * 365;
  printf("Bugune kadar yurudugunuz toplam mesafe(km): %.f\n", res);
  printf("Bugune kadar dunyanin cevresini kac kez turladiginiz: %f\n", res / r);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  lea    D27(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x10(%rsp),%xmm1
  mulss  0x14(%rsp),%xmm1
  lea    D43(%rip),%rdi
  mulss  D69(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D12(%rip),%rdi
  movss  0xc(%rsp),%xmm1
  divss  D51(%rip),%xmm1
  cvtss2sd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
data_type: string
name: retrieve_data
arguments: label: D27
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D43
data_type: string
name: retrieve_data
arguments: label: D69
data_type: byte[4]
name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D51
data_type: byte[4]

tool: D17: Gunde ortalama kac km. yuruyorsunuz?

tool: D27: %f

tool: D20: Kac yildir yuruyorsunuz?

tool: D43: Bugune kadar yurudugunuz toplam mesafe(km): %.f


tool: {"D69": [0x00,0x80,0xb6,0x43]}

tool: D12: Bugune kadar dunyanin cevresini kac kez turladiginiz: %f


tool: {"D51": [0x00,0x8b,0x1c,0x47]}

assistant: ```c
int main() {
  float avg, age, r, res;
  r = 40075;
  printf("Gunde ortalama kac km. yuruyorsunuz?\n");
  scanf("%f", &avg);
  printf("Kac yildir yuruyorsunuz?\n");
  scanf("%f", &age);
  res = avg * age * 365;
  printf("Bugune kadar yurudugunuz toplam mesafe(km): %.f\n", res);
  printf("Bugune kadar dunyanin cevresini kac kez turladiginiz: %f\n", res / r);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<vperror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4e0,%rsp
  mov    %rdi,-0x4d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4c8(%rbp)
  mov    -0x4d8(%rbp),%rdx
  mov    -0x4c4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x4c4(%rbp),%ecx
  mov    -0x4d8(%rbp),%rdx
  lea    -0x4c0(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  movb   $0x0,-0xc1(%rbp)
L7:
  mov    -0x4c4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D12(%rip),%rax
  mov    -0x4c8(%rbp),%edx
  mov    %edx,(%rax)
  lea    -0x4c0(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  nop
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void vperror(const char *fmt, ...) {
  int old_errno = errno;
  char buf[1024];
  va_list ap;
  va_start(ap, fmt);
  if (vsnprintf(buf, sizeof(buf), fmt, ap) == -1) {
    buf[sizeof(buf) - 1] = '\0';
  }
  va_end(ap);
  errno = old_errno;
  perror(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<vperror>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%r12d
  mov    %rdi,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    $0x400,%esi
  call   <vsnprintf@plt>
  cmp    $0xffffffff,%eax
  je     L11
L16:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    D3(%rip),%rax
  mov    %r12d,(%rax)
  mov    %rsp,%rdi
  call   <perror@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  movb   $0x0,0x3ff(%rsp)
  jmp    L16
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vperror(const char *fmt, ...) {
  int old_errno = errno;
  char buf[1024];
  va_list ap;
  va_start(ap, fmt);
  if (vsnprintf(buf, sizeof(buf), fmt, ap) == -1) {
    buf[sizeof(buf) - 1] = '\0';
  }
  va_end(ap);
  errno = old_errno;
  perror(buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vperror>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  sub    $0x410,%rsp
  mov    D8(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    (%rbx),%r14d
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L17
  movb   $0x0,0x3ff(%rsp)
L17:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  mov    %r14d,(%rbx)
  call   <perror@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vperror(const char *fmt, ...) {
  int old_errno = errno;
  char buf[1024];
  va_list ap;
  va_start(ap, fmt);
  if (vsnprintf(buf, sizeof(buf), fmt, ap) == -1) {
    buf[sizeof(buf) - 1] = '\0';
  }
  va_end(ap);
  errno = old_errno;
  perror(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vperror>:
  endbr64
  push   %r14
  mov    %rdi,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  push   %rbx
  sub    $0x410,%rsp
  mov    D0(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    (%rbx),%r14d
  call   <va_start@plt>
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L3
  movb   $0x0,0x3ff(%rsp)
L3:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  mov    %r14d,(%rbx)
  call   <perror@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void vperror(const char *fmt, ...) {
  int old_errno = errno;
  char buf[1024];
  va_list ap;
  va_start(ap, fmt);
  if (vsnprintf(buf, sizeof(buf), fmt, ap) == -1) {
    buf[sizeof(buf) - 1] = '\0';
  }
  va_end(ap);
  errno = old_errno;
  perror(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L0:
  mov    $0x8,%edi
  call   <foo@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L0
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++)
    foo(8);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
L3:
  mov    $0x8,%edi
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++)
    foo(8);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x8,%edi
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L5
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++)
    foo(8);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x3e8,%ebx
  nopw   0x0(%rax,%rax,1)
L3:
  mov    $0x8,%edi
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L3
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int i;
  for (i = 0; i < 1000; i++)
    foo(8);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_in_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L24:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  ucomiss -0x14(%rbp),%xmm0
  jp     L13
  ucomiss -0x14(%rbp),%xmm0
  jne    L13
  mov    $0x1,%eax
  jmp    L28
L13:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  mov    $0x0,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int is_in_array(float num, float *arr, int len) {
  for (int i = 0; i < len; i++) {
    if (arr[i] == num) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_in_array>:
  endbr64
  test   %esi,%esi
  jle    L36
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L4:
  ucomiss (%rax),%xmm0
  jp     L17
  je     L0
L17:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
  mov    $0x0,%eax
  ret
L36:
  mov    $0x0,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_in_array(float num, float *arr, int len) {
  for (int i = 0; i < len; i++) {
    if (arr[i] == num) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_in_array>:
  endbr64
  test   %esi,%esi
  jle    L23
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L23
L27:
  ucomiss (%rdi),%xmm0
  jp     L29
  jne    L29
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_in_array(float num, float *arr, int len) {
  for (int i = 0; i < len; i++) {
    if (arr[i] == num) {
      return 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_in_array>:
  endbr64
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x4,%rdi
  cmp    %rax,%rdi
  je     L12
L16:
  ucomiss (%rdi),%xmm0
  jp     L45
  jne    L45
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_in_array(float num, float *arr, int len) {
  for (int i = 0; i < len; i++) {
    if (arr[i] == num) {
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L24
L11:
  addq   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L28
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L11
L28:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chomp(char *string) {
  while (*string && *string != '\n' && *string != '\r')
    string++;
  *string = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L29
  mov    $0x2401,%edx
  bt     %rax,%rdx
  jb     L15
L29:
  mov    $0x2401,%edx
L37:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L37
  bt     %rax,%rdx
  jae    L37
L15:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *string) {
  while (*string && *string != '\n' && *string != '\r')
    string++;
  *string = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L24
  mov    $0xffffffffffffdbfe,%rdx
  bt     %rax,%rdx
  jae    L23
L24:
  mov    $0xffffffffffffdbfe,%rdx
  nop
L33:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0xd,%al
  ja     L33
  bt     %rax,%rdx
  jb     L33
L23:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *string) {
  while (*string && *string != '\n' && *string != '\r')
    string++;
  *string = 0;
}
```