ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<packet_crc_block>:
  endbr64
  test   %edx,%edx
  jle    L12
  movslq %edx,%rdx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    (%rsi,%rdx,1),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L17:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  mov    %r12,%rdi
  call   <packet_crc_process@plt>
  cmp    %rbp,%rbx
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L12:
  ret
```

assistant: ```c
void packet_crc_block(unsigned short *context, const unsigned char *blk, int len) {
  while (len-- > 0)
    packet_crc_process(context, *blk++);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<packet_crc_block>:
  endbr64
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    (%rsi,%rdx,1),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax)
L17:
  movzbl (%rbx),%esi
  add    $0x1,%rbx
  mov    %r12,%rdi
  call   <packet_crc_process@plt>
  cmp    %rbx,%rbp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
void packet_crc_block(unsigned short *context, const unsigned char *blk, int len) {
  while (len-- > 0)
    packet_crc_process(context, *blk++);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<maior_elemento>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L39:
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L0:
  cmpl   $0x0,-0xc(%rbp)
  jne    L17
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L41
L17:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L41
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,-0x4(%rbp)
L41:
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x31,-0x8(%rbp)
  jle    L0
  addl   $0x1,-0xc(%rbp)
L30:
  cmpl   $0x31,-0xc(%rbp)
  jle    L39
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int maior_elemento(int mat[50][50]) {
  int i, j, maior;
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0) {
        maior = mat[i][j];
      } else if (mat[i][j] > maior) {
        maior = mat[i][j];
      }
    }
  }
  return maior;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<maior_elemento>:
  endbr64
  mov    %rdi,%r8
  mov    %rdi,%r9
  mov    $0x0,%esi
  jmp    L18
L7:
  mov    (%r8,%rax,1),%edx
L37:
  add    $0x4,%rax
  cmp    $0xc8,%rax
  je     L14
L39:
  test   %esi,%esi
  je     L7
  mov    (%rdi,%rax,1),%ecx
  cmp    %ecx,%edx
  cmovl  %ecx,%edx
  jmp    L37
L14:
  add    $0x1,%esi
  add    $0xc8,%r9
  cmp    $0x32,%esi
  je     L6
L18:
  mov    %r9,%rdi
  mov    $0x0,%eax
  jmp    L39
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int maior_elemento(int mat[50][50]) {
  int i, j, maior;
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0) {
        maior = mat[i][j];
      } else if (mat[i][j] > maior) {
        maior = mat[i][j];
      }
    }
  }
  return maior;
}
```
user: Translate the below assembly code into C programming language:

```asm
<maior_elemento>:
  endbr64
  mov    %rdi,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L42:
  xor    %eax,%eax
  jmp    L48
  nopl   0x0(%rax)
L35:
  mov    (%rsi,%rax,1),%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x4,%rax
  cmp    $0xc8,%rax
  je     L40
L48:
  test   %ecx,%ecx
  jne    L35
  mov    (%rdi,%rax,1),%r8d
  add    $0x4,%rax
  cmp    $0xc8,%rax
  jne    L48
L40:
  add    $0x1,%ecx
  add    $0xc8,%rsi
  cmp    $0x32,%ecx
  jne    L42
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maior_elemento(int mat[50][50]) {
  int i, j, maior;
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0) {
        maior = mat[i][j];
      } else if (mat[i][j] > maior) {
        maior = mat[i][j];
      }
    }
  }
  return maior;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<maior_elemento>:
  endbr64
  mov    %rdi,%rax
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L19:
  test   %ecx,%ecx
  jne    L13
  mov    0xc4(%rdi),%r8d
  add    $0xc8,%rax
  mov    $0x1,%ecx
L13:
  movdqu (%rax),%xmm1
  movdqu 0x10(%rax),%xmm4
  movdqu 0x20(%rax),%xmm2
  movdqu 0x30(%rax),%xmm6
  movdqa %xmm1,%xmm0
  movdqu 0x70(%rax),%xmm7
  movdqu 0x80(%rax),%xmm5
  pcmpgtd %xmm4,%xmm0
  mov    0xc4(%rax),%esi
  pand   %xmm0,%xmm1
  pandn  %xmm4,%xmm0
  movdqu 0x50(%rax),%xmm4
  por    %xmm1,%xmm0
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm6,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm6,%xmm1
  movd   %r8d,%xmm6
  mov    0xc0(%rax),%r8d
  por    %xmm2,%xmm1
  movdqa %xmm0,%xmm2
  pcmpgtd %xmm1,%xmm2
  cmp    %esi,%r8d
  cmovl  %esi,%r8d
  pand   %xmm2,%xmm0
  pandn  %xmm1,%xmm2
  por    %xmm0,%xmm2
  movdqu 0x40(%rax),%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm4,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm4,%xmm1
  por    %xmm0,%xmm1
  pshufd $0x0,%xmm6,%xmm0
  movdqa %xmm1,%xmm3
  pcmpgtd %xmm0,%xmm3
  pand   %xmm3,%xmm1
  pandn  %xmm0,%xmm3
  por    %xmm1,%xmm3
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm3,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm3,%xmm1
  por    %xmm2,%xmm1
  movdqu 0x60(%rax),%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm7,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm7,%xmm0
  movdqu 0xa0(%rax),%xmm7
  por    %xmm2,%xmm0
  movdqa %xmm0,%xmm2
  pcmpgtd %xmm5,%xmm2
  pand   %xmm2,%xmm0
  pandn  %xmm5,%xmm2
  movdqu 0xb0(%rax),%xmm5
  por    %xmm0,%xmm2
  movdqa %xmm1,%xmm0
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  movdqu 0x90(%rax),%xmm2
  por    %xmm1,%xmm0
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm7,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm7,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  pcmpgtd %xmm5,%xmm2
  pand   %xmm2,%xmm1
  pandn  %xmm5,%xmm2
  por    %xmm1,%xmm2
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x8,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm2
  pandn  %xmm1,%xmm0
  por    %xmm2,%xmm0
  movd   %xmm0,%edx
  cmp    %edx,%r8d
  cmovl  %edx,%r8d
  add    $0x1,%ecx
  add    $0xc8,%rax
  cmp    $0x32,%ecx
  jne    L19
  mov    %r8d,%eax
  ret
```

assistant: ```c
int maior_elemento(int mat[50][50]) {
  int i, j, maior;
  for (i = 0; i < 50; i++) {
    for (j = 0; j < 50; j++) {
      if (i == 0) {
        maior = mat[i][j];
      } else if (mat[i][j] > maior) {
        maior = mat[i][j];
      }
    }
  }
  return maior;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__vfprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_lock_file@plt>
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    %rax,%rsi
  mov    $0x6000,%edi
  call   <__pformat@plt>
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_unlock_file@plt>
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vfprintf(FILE *stream, const char *fmt, va_list argv) {
  register int retval;
  _lock_file(stream);
  retval = __pformat(0x2000 | 0x4000, stream, 0, fmt, argv);
  _unlock_file(stream);
  return retval;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__vfprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  call   <_lock_file@plt>
  mov    %r12d,%r8d
  mov    %rbp,%rcx
  mov    $0x0,%edx
  mov    %rbx,%rsi
  mov    $0x6000,%edi
  call   <__pformat@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <_unlock_file@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vfprintf(FILE *stream, const char *fmt, va_list argv) {
  register int retval;
  _lock_file(stream);
  retval = __pformat(0x2000 | 0x4000, stream, 0, fmt, argv);
  _unlock_file(stream);
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__vfprintf>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <_lock_file@plt>
  mov    %ebx,%r8d
  mov    %r12,%rcx
  mov    %rbp,%rsi
  xor    %edx,%edx
  mov    $0x6000,%edi
  call   <__pformat@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <_unlock_file@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __attribute__((__cdecl__)) __vfprintf(FILE *stream, const char *fmt, va_list argv) {
  register int retval;
  _lock_file(stream);
  retval = __pformat(0x2000 | 0x4000, stream, 0, fmt, argv);
  _unlock_file(stream);
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_little_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x1,-0xa(%rbp)
  lea    -0xa(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int is_little_endian(void) {
  unsigned short n = 1;
  return *((unsigned char *)&n) != 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_little_endian(void) {
  unsigned short n = 1;
  return *((unsigned char *)&n) != 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_little_endian(void) {
  unsigned short n = 1;
  return *((unsigned char *)&n) != 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_little_endian(void) {
  unsigned short n = 1;
  return *((unsigned char *)&n) != 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x763d6b,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movw   $0x6b,-0xe(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  lea    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <getsubopt@plt>
  test   %rax,%rax
  jne    L13
  lea    -0xc(%rbp),%rax
  add    $0x2,%rax
  mov    -0x28(%rbp),%rdx
  cmp    %rdx,%rax
  jne    L13
  lea    -0xc(%rbp),%rax
  add    $0x3,%rax
  mov    -0x30(%rbp),%rdx
  cmp    %rdx,%rax
  je     L40
L13:
  mov    $0x1,%eax
  jmp    L34
L40:
  mov    $0x0,%eax
L34:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

assistant: ```c
int main(void) {
  char buf[] = "k=v";
  char *options = buf;
  char token0[] = "k";
  char *const tokens[] = {token0, NULL};
  char *value = NULL;
  return !(getsubopt(&options, tokens, &value) == 0 && value == buf + 2 && options == buf + 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x763d6b,0x24(%rsp)
  lea    0x24(%rsp),%rax
  mov    %rax,(%rsp)
  movw   $0x6b,0x22(%rsp)
  lea    0x22(%rsp),%rax
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  call   <getsubopt@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L17
  lea    0x26(%rsp),%rdx
  cmp    %rdx,0x8(%rsp)
  je     L8
L17:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x38,%rsp
  ret
L8:
  lea    0x27(%rsp),%rax
  cmp    %rax,(%rsp)
  setne  %al
  movzbl %al,%eax
  jmp    L17
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char buf[] = "k=v";
  char *options = buf;
  char token0[] = "k";
  char *const tokens[] = {token0, NULL};
  char *value = NULL;
  return !(getsubopt(&options, tokens, &value) == 0 && value == buf + 2 && options == buf + 3);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rax
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    $0x6b,%eax
  lea    0x10(%rsp),%rsi
  mov    %ax,0x22(%rsp)
  lea    0x22(%rsp),%rax
  movl   $0x763d6b,0x24(%rsp)
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <getsubopt@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L21
  lea    0x26(%rsp),%rdx
  cmp    %rdx,0x8(%rsp)
  je     L37
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x38,%rsp
  ret
L37:
  lea    0x27(%rsp),%rax
  cmp    %rax,(%rsp)
  setne  %al
  movzbl %al,%eax
  jmp    L21
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char buf[] = "k=v";
  char *options = buf;
  char token0[] = "k";
  char *const tokens[] = {token0, NULL};
  char *value = NULL;
  return !(getsubopt(&options, tokens, &value) == 0 && value == buf + 2 && options == buf + 3);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rax
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  mov    $0x6b,%eax
  lea    0x10(%rsp),%rsi
  mov    %ax,0x22(%rsp)
  lea    0x22(%rsp),%rax
  movl   $0x763d6b,0x24(%rsp)
  mov    %rax,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <getsubopt@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L21
  lea    0x26(%rsp),%rdx
  cmp    %rdx,0x8(%rsp)
  je     L3
L21:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x38,%rsp
  ret
L3:
  lea    0x27(%rsp),%rax
  cmp    %rax,(%rsp)
  setne  %al
  movzbl %al,%eax
  jmp    L21
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char buf[] = "k=v";
  char *options = buf;
  char token0[] = "k";
  char *const tokens[] = {token0, NULL};
  char *value = NULL;
  return !(getsubopt(&options, tokens, &value) == 0 && value == buf + 2 && options == buf + 3);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_duplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L30:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L30
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: %d


assistant: ```c
void find_duplicates(int vec[], int size) {
  for (int i = 0; i < size; i++) {
    for (int j = i + 1; j < size; j++) {
      if (vec[i] == vec[j]) {
        printf("%d\n", vec[i]);
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find_duplicates>:
  endbr64
  test   %esi,%esi
  jle    L55
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  lea    0x4(%rdi),%rbp
  lea    -0x1(%rsi),%eax
  mov    %eax,0xc(%rsp)
  mov    %esi,%eax
  mov    %rax,(%rsp)
  mov    $0x1,%r13d
  lea    D0(%rip),%r14
  jmp    L9
L1:
  mov    %r14,%rdi
  call   <printf@plt>
L12:
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L25
L10:
  mov    -0x4(%rbp),%esi
  cmp    (%rbx),%esi
  jne    L12
  jmp    L1
L25:
  add    $0x1,%r13
  add    $0x4,%rbp
L9:
  cmp    (%rsp),%r13
  je     L11
  mov    0xc(%rsp),%eax
  sub    %r13d,%eax
  lea    -0x1(%r13,%rax,1),%rax
  lea    0x8(%r15,%rax,4),%r12
  mov    %rbp,%rbx
  jmp    L10
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
void find_duplicates(int vec[], int size) {
  for (int i = 0; i < size; i++) {
    for (int j = i + 1; j < size; j++) {
      if (vec[i] == vec[j]) {
        printf("%d\n", vec[i]);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<find_duplicates>:
  endbr64
  test   %esi,%esi
  jle    L49
  push   %r15
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi),%r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %eax,0xc(%rsp)
  mov    %esi,%eax
  mov    %rax,(%rsp)
  cmp    (%rsp),%rbp
  je     L51
L45:
  mov    0xc(%rsp),%eax
  mov    %r15,%rbx
  sub    %ebp,%eax
  lea    -0x1(%rbp,%rax,1),%rax
  lea    0x8(%r13,%rax,4),%r14
  jmp    L4
  nopl   (%rax)
L52:
  add    $0x4,%rbx
  cmp    %r14,%rbx
  je     L5
L4:
  mov    -0x4(%r15),%esi
  cmp    (%rbx),%esi
  jne    L52
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r14,%rbx
  jne    L4
L5:
  add    $0x1,%rbp
  add    $0x4,%r15
  cmp    (%rsp),%rbp
  jne    L45
L51:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L49:
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: %d


assistant: ```c
void find_duplicates(int vec[], int size) {
  for (int i = 0; i < size; i++) {
    for (int j = i + 1; j < size; j++) {
      if (vec[i] == vec[j]) {
        printf("%d\n", vec[i]);
      }
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_duplicates>:
  endbr64
  cmp    $0x1,%esi
  jle    L15
  push   %r15
  mov    %esi,%r15d
  push   %r14
  movslq %esi,%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L28:
  mov    %r12,%rbx
  jmp    L20
  nopl   (%rax)
L39:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jle    L56
L20:
  mov    -0x4(%rbp,%r12,4),%esi
  cmp    0x0(%rbp,%rbx,4),%esi
  jne    L39
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r15d
  jg     L20
L56:
  add    $0x1,%r12
  cmp    %r14,%r12
  jne    L28
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string

tool: D9: %d


assistant: ```c
void find_duplicates(int vec[], int size) {
  for (int i = 0; i < size; i++) {
    for (int j = i + 1; j < size; j++) {
      if (vec[i] == vec[j]) {
        printf("%d\n", vec[i]);
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <STK_newStack@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x4,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <STK_push@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STK_size@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STK_top@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x1c(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STK_pop@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STK_size@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <STK_deleteStack@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int main(void) {
  struct Stack *testStack = STK_newStack();
  int testInt = 4;
  STK_push(testStack, &testInt);
  assert(STK_size(testStack) == 1);
  int *testPtr = (int *)STK_top(testStack);
  assert(testPtr != NULL);
  assert(testPtr == &testInt);
  STK_pop(testStack);
  assert(STK_size(testStack) == 0);
  STK_deleteStack(testStack);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <STK_newStack@plt>
  mov    %rax,%rbx
  movl   $0x4,0x4(%rsp)
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <STK_push@plt>
  mov    %rbx,%rdi
  call   <STK_size@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <STK_top@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %rbp,%r12
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <STK_pop@plt>
  mov    %rbx,%rdi
  call   <STK_size@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <STK_deleteStack@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  struct Stack *testStack = STK_newStack();
  int testInt = 4;
  STK_push(testStack, &testInt);
  assert(STK_size(testStack) == 1);
  int *testPtr = (int *)STK_top(testStack);
  assert(testPtr != NULL);
  assert(testPtr == &testInt);
  STK_pop(testStack);
  assert(STK_size(testStack) == 0);
  STK_deleteStack(testStack);
  return 0;
}
```