ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %edi,-0xe4(%rbp)
  mov    %rsi,-0xf0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <init_map@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0xd8(%rbp)
  mov    -0xd8(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mother_fly@plt>
  mov    %eax,-0xd4(%rbp)
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <print_map@plt>
  mov    -0xd4(%rbp),%edx
  lea    -0xd0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <child_fly@plt>
  test   %rax,%rax
  je     L24
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L24:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D16: Yes


tool: D14: No


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  char map[10][20];
  init_map(map);
  int start = rand() % 20 * 10;
  int end = mother_fly(map, start);
  print_map(map);
  if (child_fly(map, end))
    printf("Yes\n");
  else
    printf("No\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <init_map@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  mov    %rbx,%rdi
  call   <mother_fly@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <print_map@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <child_fly@plt>
  test   %rax,%rax
  je     L25
  lea    D14(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
data_type: string
name: parse_data
arguments: label: D4
data_type: string

tool: D14: Yes


tool: D4: No


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  char map[10][20];
  init_map(map);
  int start = rand() % 20 * 10;
  int end = mother_fly(map, start);
  print_map(map);
  if (child_fly(map, end))
    printf("Yes\n");
  else
    printf("No\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rbp,%rdi
  call   <init_map@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  call   <mother_fly@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <print_map@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <child_fly@plt>
  test   %rax,%rax
  je     L25
  lea    D19(%rip),%rdi
  call   <printf@plt>
L4:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L25:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
datatype: string
name: disassemble_data
arguments: tag: D1
datatype: string

tool: D19: Yes


tool: D1: No


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  char map[10][20];
  init_map(map);
  int start = rand() % 20 * 10;
  int end = mother_fly(map, start);
  print_map(map);
  if (child_fly(map, end))
    printf("Yes\n");
  else
    printf("No\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    %rbp,%rdi
  call   <init_map@plt>
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbp,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  call   <mother_fly@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <print_map@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <child_fly@plt>
  test   %rax,%rax
  je     L7
  lea    D17(%rip),%rdi
  call   <printf@plt>
L14:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0xd8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L14
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D17: Yes


tool: D6: No


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  char map[10][20];
  init_map(map);
  int start = rand() % 20 * 10;
  int end = mother_fly(map, start);
  print_map(map);
  if (child_fly(map, end))
    printf("Yes\n");
  else
    printf("No\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x50,%esi
  mov    $0xa,%edi
  call   <areaOfRectangle@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: Area of Recctangle: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int aor;
  aor = areaOfRectangle(10, 80);
  printf("Area of Recctangle: %d", aor);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x50,%esi
  mov    $0xa,%edi
  call   <areaOfRectangle@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: Area of Recctangle: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int aor;
  aor = areaOfRectangle(10, 80);
  printf("Area of Recctangle: %d", aor);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x50,%esi
  mov    $0xa,%edi
  call   <areaOfRectangle@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: Area of Recctangle: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int aor;
  aor = areaOfRectangle(10, 80);
  printf("Area of Recctangle: %d", aor);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x50,%esi
  mov    $0xa,%edi
  call   <areaOfRectangle@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: Area of Recctangle: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int aor;
  aor = areaOfRectangle(10, 80);
  printf("Area of Recctangle: %d", aor);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L8
L16:
  movl   $0x0,-0x7c(%rbp)
  jmp    L35
L71:
  lea    -0x70(%rbp),%rcx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x80(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rsi,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x7c(%rbp)
L35:
  cmpl   $0x4,-0x7c(%rbp)
  jle    L71
  addl   $0x1,-0x80(%rbp)
L8:
  cmpl   $0x4,-0x80(%rbp)
  jle    L16
  lea    -0x70(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <change@plt>
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x80(%rbp)
  jmp    L4
L0:
  movl   $0x0,-0x7c(%rbp)
  jmp    L75
L6:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x80(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x70(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x7c(%rbp)
L75:
  cmpl   $0x4,-0x7c(%rbp)
  jle    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x80(%rbp)
L4:
  cmpl   $0x4,-0x80(%rbp)
  jle    L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L89
  call   <__stack_chk_fail@plt>
L89:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D37
data_type: string
name: unpack_data
arguments: data_label: D27
data_type: string

tool: D10: Input the matrix:

tool: D28: %d

tool: D37: Now,the matrix is :

tool: D27: %d 

assistant: ```c
int main() {
  void change(int *);
  int a[5][5], *p, i, j;
  printf("Input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
    }
  p = &a[0][0];
  change(p);
  printf("Now,the matrix is :\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbp
  lea    0x14(%rsp),%r12
  mov    $0x0,%r14d
  lea    D29(%rip),%r13
L42:
  lea    -0x14(%r12),%rbx
L37:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L37
  add    $0x5,%r14
  add    $0x14,%r12
  cmp    $0x19,%r14
  jne    L42
  mov    %rsp,%rdi
  call   <change@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0x64(%rbp),%r13
  lea    D31(%rip),%r12
L0:
  mov    $0x0,%ebx
L46:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L46
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x14,%rbp
  cmp    %r13,%rbp
  jne    L0
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D30
datatype: string
name: read_data
arguments: data_tag: D31
datatype: string

tool: D19: Input the matrix:

tool: D29: %d

tool: D30: Now,the matrix is :

tool: D31: %d 

assistant: ```c
int main() {
  void change(int *);
  int a[5][5], *p, i, j;
  printf("Input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
    }
  p = &a[0][0];
  change(p);
  printf("Now,the matrix is :\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D32(%rip),%rdi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x14(%rsp),%r12
  call   <puts@plt>
  mov    %r15,%rbp
L20:
  lea    -0x14(%r12),%rbx
L19:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L19
  add    $0x5,%r14
  lea    0x14(%rbx),%r12
  cmp    $0x19,%r14
  jne    L20
  mov    %r15,%rdi
  lea    D37(%rip),%r12
  add    $0x64,%r15
  call   <change@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
L18:
  xor    %ebx,%ebx
L31:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L31
  mov    $0xa,%edi
  add    $0x14,%rbp
  call   <putchar@plt>
  cmp    %r15,%rbp
  jne    L18
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D37
type_infered: string
name: read_data
arguments: tag: D31
type_infered: string

tool: D32: Input the matrix:

tool: D9: %d

tool: D37: %d 

tool: D31: Now,the matrix is :

assistant: ```c
int main() {
  void change(int *);
  int a[5][5], *p, i, j;
  printf("Input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
    }
  p = &a[0][0];
  change(p);
  printf("Now,the matrix is :\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%rdi
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0x14(%rsp),%r12
  call   <puts@plt>
  mov    %r15,%rbp
L30:
  lea    -0x14(%r12),%rbx
L46:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L46
  add    $0x5,%r14
  lea    0x14(%rbx),%r12
  cmp    $0x19,%r14
  jne    L30
  mov    %r15,%rdi
  lea    D30(%rip),%r12
  add    $0x64,%r15
  call   <change@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
L41:
  xor    %ebx,%ebx
L27:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L27
  mov    $0xa,%edi
  add    $0x14,%rbp
  call   <putchar@plt>
  cmp    %r15,%rbp
  jne    L41
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D30
datatype: string
name: parse_data
arguments: tag: D2
datatype: string

tool: D16: Input the matrix:

tool: D22: %d

tool: D30: %d 

tool: D2: Now,the matrix is :

assistant: ```c
int main() {
  void change(int *);
  int a[5][5], *p, i, j;
  printf("Input the matrix:\n");
  for (i = 0; i < 5; i++)
    for (j = 0; j < 5; j++) {
      scanf("%d", &a[i][j]);
    }
  p = &a[0][0];
  change(p);
  printf("Now,the matrix is :\n");
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++) {
      printf("%d ", a[i][j]);
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_settimeofday_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <bt_sys_settimeofday@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int _settimeofday_r(struct _reent *r, struct timeval *p, struct timezone *z) {
  bt_sys_settimeofday(p, z);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_settimeofday_r>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <bt_sys_settimeofday@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _settimeofday_r(struct _reent *r, struct timeval *p, struct timezone *z) {
  bt_sys_settimeofday(p, z);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_settimeofday_r>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  call   <bt_sys_settimeofday@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _settimeofday_r(struct _reent *r, struct timeval *p, struct timezone *z) {
  bt_sys_settimeofday(p, z);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_login_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <prompt_run@plt>
  jmp    L4
L1:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string
name: read_data
arguments: data_label: D17
datatype: string

tool: D2: Request failed, reason %s


tool: D17: Request Successfull, waiting for leave msg

assistant: ```c
void _login_cb(int success, char *msg) {
  if (!success) {
    printf("Request failed, reason %s\n", msg);
    prompt_run();
  } else {
    printf("Request Successfull, waiting for leave msg\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_login_cb>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  jne    L1
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <prompt_run@plt>
L2:
  add    $0x8,%rsp
  ret
L1:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: label: D16
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D16: Request failed, reason %s


tool: D5: Request Successfull, waiting for leave msg

assistant: ```c
void _login_cb(int success, char *msg) {
  if (!success) {
    printf("Request failed, reason %s\n", msg);
    prompt_run();
  } else {
    printf("Request Successfull, waiting for leave msg\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_login_cb>:
  endbr64
  test   %edi,%edi
  jne    L2
  sub    $0x8,%rsp
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <prompt_run@plt>
  nopl   (%rax)
L2:
  lea    D0(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string

tool: D10: Request failed, reason %s


tool: D0: Request Successfull, waiting for leave msg

assistant: ```c
void _login_cb(int success, char *msg) {
  if (!success) {
    printf("Request failed, reason %s\n", msg);
    prompt_run();
  } else {
    printf("Request Successfull, waiting for leave msg\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_login_cb>:
  endbr64
  test   %edi,%edi
  jne    L0
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <prompt_run@plt>
  nopl   (%rax)
L0:
  lea    D16(%rip),%rdi
  jmp    1070 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D16
type_guessed: string

tool: D6: Request failed, reason %s


tool: D16: Request Successfull, waiting for leave msg

assistant: ```c
void _login_cb(int success, char *msg) {
  if (!success) {
    printf("Request failed, reason %s\n", msg);
    prompt_run();
  } else {
    printf("Request Successfull, waiting for leave msg\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<daapGetText>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void daapGetText(const char **d, int len, char *dst) {
  const char *p = *d;
  memcpy(dst, p, len);
  dst[len] = '\0';
  *d = p + len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<daapGetText>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r13
  mov    (%rdi),%r12
  mov    %esi,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%r13,%rbx,1)
  add    %rbx,%r12
  mov    %r12,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void daapGetText(const char **d, int len, char *dst) {
  const char *p = *d;
  memcpy(dst, p, len);
  dst[len] = '\0';
  *d = p + len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<daapGetText>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%edx
  sub    $0x8,%rsp
  mov    (%rdi),%r12
  mov    %r13,%rdi
  mov    %r12,%rsi
  add    %rbx,%r12
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    %r12,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void daapGetText(const char **d, int len, char *dst) {
  const char *p = *d;
  memcpy(dst, p, len);
  dst[len] = '\0';
  *d = p + len;
}
```