ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getMax>:
  endbr64
  mov    %edi,%eax
  cmp    $0x9,%edi
  jle    L13
L3:
  mov    %eax,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0x63,%ecx
  jg     L3
L13:
  ret
```

assistant: ```c
int getMax(int number) {
  while (number > 9) {
    number /= 10;
  }
  return number;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getMax>:
  endbr64
  mov    %edi,%eax
  cmp    $0x9,%edi
  jle    L4
  mov    $0xcccccccd,%ecx
L5:
  mov    %eax,%eax
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x63,%edx
  jg     L5
L4:
  ret
```

assistant: ```c
int getMax(int number) {
  while (number > 9) {
    number /= 10;
  }
  return number;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getMax>:
  endbr64
  mov    %edi,%eax
  cmp    $0x9,%edi
  jle    L18
  mov    $0xcccccccd,%ecx
L10:
  mov    %eax,%eax
  mov    %rax,%rdx
  imul   %rcx,%rax
  shr    $0x23,%rax
  cmp    $0x63,%edx
  jg     L10
L18:
  ret
```

assistant: ```c
int getMax(int number) {
  while (number > 9) {
    number /= 10;
  }
  return number;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<collect_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L26
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <BUF_MEM_grow_clean@plt>
  test   %eax,%eax
  jne    L6
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ASN1error@plt>
  mov    $0x0,%eax
  jmp    L7
L6:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    0x8(%rdx),%rcx
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  add    %rdx,%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
L26:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L7:
  leave
  ret
```

assistant: ```c
int collect_data(BUF_MEM *buf, const unsigned char **p, long plen) {
  int len;
  if (buf) {
    len = buf->length;
    if (!BUF_MEM_grow_clean(buf, len + plen)) {
      ASN1error(ERR_R_MALLOC_FAILURE);
      return 0;
    }
    memcpy(buf->data + len, *p, plen);
  }
  *p += plen;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<collect_data>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  test   %rdi,%rdi
  je     L19
  mov    %rdi,%rbx
  mov    (%rdi),%r14d
  lea    (%r14,%rdx,1),%esi
  call   <BUF_MEM_grow_clean@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L23
  movslq %r14d,%rdi
  add    0x8(%rbx),%rdi
  mov    %r12,%rdx
  mov    0x0(%rbp),%rsi
  call   <memcpy@plt>
L19:
  add    %r12,0x0(%rbp)
  mov    $0x1,%r13d
L4:
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L23:
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  jmp    L4
```

assistant: ```c
int collect_data(BUF_MEM *buf, const unsigned char **p, long plen) {
  int len;
  if (buf) {
    len = buf->length;
    if (!BUF_MEM_grow_clean(buf, len + plen)) {
      ASN1error(ERR_R_MALLOC_FAILURE);
      return 0;
    }
    memcpy(buf->data + len, *p, plen);
  }
  *p += plen;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<collect_data>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L10
  mov    (%rdi),%r14d
  mov    %rdi,%rbx
  lea    (%r14,%rdx,1),%esi
  call   <BUF_MEM_grow_clean@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L4
  mov    0x0(%rbp),%rsi
  movslq %r14d,%rdi
  mov    %r12,%rdx
  add    0x8(%rbx),%rdi
  call   <memcpy@plt>
L10:
  mov    $0x1,%r13d
  pop    %rbx
  add    %r12,0x0(%rbp)
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int collect_data(BUF_MEM *buf, const unsigned char **p, long plen) {
  int len;
  if (buf) {
    len = buf->length;
    if (!BUF_MEM_grow_clean(buf, len + plen)) {
      ASN1error(ERR_R_MALLOC_FAILURE);
      return 0;
    }
    memcpy(buf->data + len, *p, plen);
  }
  *p += plen;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<collect_data>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  test   %rdi,%rdi
  je     L13
  mov    (%rdi),%r14d
  mov    %rdi,%rbx
  lea    (%r14,%rdx,1),%esi
  call   <BUF_MEM_grow_clean@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  je     L9
  mov    0x0(%rbp),%rsi
  movslq %r14d,%rdi
  mov    %r12,%rdx
  add    0x8(%rbx),%rdi
  call   <memcpy@plt>
L13:
  mov    $0x1,%r13d
  pop    %rbx
  add    %r12,0x0(%rbp)
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <ASN1error@plt>
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int collect_data(BUF_MEM *buf, const unsigned char **p, long plen) {
  int len;
  if (buf) {
    len = buf->length;
    if (!BUF_MEM_grow_clean(buf, len + plen)) {
      ASN1error(ERR_R_MALLOC_FAILURE);
      return 0;
    }
    memcpy(buf->data + len, *p, plen);
  }
  *p += plen;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<projectOnLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm0
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x38(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x38(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm2
  movsd  -0x18(%rbp),%xmm3
  movsd  -0x18(%rbp),%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  movsd  -0x10(%rbp),%xmm3
  movsd  -0x10(%rbp),%xmm1
  mulsd  %xmm3,%xmm1
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L10
L9:
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x2c(%rbp),%eax
  cltq
  movsd  -0x20(%rbp,%rax,8),%xmm1
  mulsd  -0x28(%rbp),%xmm1
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x2c(%rbp)
L10:
  cmpl   $0x2,-0x2c(%rbp)
  jle    L9
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void projectOnLine(const double *p, const double *q, double *v) {
  double pq[3];
  double tmp;
  pq[0] = p[0] - q[0];
  pq[1] = p[1] - q[1];
  pq[2] = p[2] - q[2];
  tmp = (p[0] * pq[0] + p[1] * pq[1] + p[2] * pq[2]) / (pq[0] * pq[0] + pq[1] * pq[1] + pq[2] * pq[2]);
  for (int i = 0; i < 3; i++)
    v[i] = p[i] - pq[i] * tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<projectOnLine>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsd  (%rdi),%xmm1
  movapd %xmm1,%xmm0
  subsd  (%rsi),%xmm0
  movsd  %xmm0,(%rsp)
  movsd  0x8(%rdi),%xmm5
  movapd %xmm5,%xmm2
  subsd  0x8(%rsi),%xmm2
  movsd  %xmm2,0x8(%rsp)
  movsd  0x10(%rdi),%xmm4
  movapd %xmm4,%xmm3
  subsd  0x10(%rsi),%xmm3
  movsd  %xmm3,0x10(%rsp)
  mulsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm5
  addsd  %xmm5,%xmm1
  mulsd  %xmm3,%xmm4
  addsd  %xmm4,%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm2
  addsd  %xmm0,%xmm2
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm2
  movapd %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  mov    %rsp,%rsi
L9:
  movapd %xmm0,%xmm2
  mulsd  (%rax,%rsi,1),%xmm2
  movsd  (%rcx,%rax,1),%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x18,%rax
  jne    L9
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void projectOnLine(const double *p, const double *q, double *v) {
  double pq[3];
  double tmp;
  pq[0] = p[0] - q[0];
  pq[1] = p[1] - q[1];
  pq[2] = p[2] - q[2];
  tmp = (p[0] * pq[0] + p[1] * pq[1] + p[2] * pq[2]) / (pq[0] * pq[0] + pq[1] * pq[1] + pq[2] * pq[2]);
  for (int i = 0; i < 3; i++)
    v[i] = p[i] - pq[i] * tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<projectOnLine>:
  endbr64
  movsd  (%rdi),%xmm4
  movsd  0x8(%rdi),%xmm6
  movsd  0x10(%rdi),%xmm5
  movapd %xmm4,%xmm3
  movapd %xmm6,%xmm2
  subsd  (%rsi),%xmm3
  subsd  0x8(%rsi),%xmm2
  movapd %xmm4,%xmm0
  movapd %xmm5,%xmm1
  subsd  0x10(%rsi),%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm6
  mulsd  %xmm1,%xmm5
  addsd  %xmm6,%xmm0
  movapd %xmm2,%xmm6
  mulsd  %xmm2,%xmm6
  addsd  %xmm5,%xmm0
  movapd %xmm3,%xmm5
  mulsd  %xmm3,%xmm5
  addsd  %xmm6,%xmm5
  movapd %xmm1,%xmm6
  mulsd  %xmm1,%xmm6
  addsd  %xmm6,%xmm5
  divsd  %xmm5,%xmm0
  mulsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  subsd  %xmm3,%xmm4
  movsd  %xmm4,(%rdx)
  movsd  0x8(%rdi),%xmm3
  subsd  %xmm2,%xmm3
  movsd  %xmm3,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  ret
```

assistant: ```c
void projectOnLine(const double *p, const double *q, double *v) {
  double pq[3];
  double tmp;
  pq[0] = p[0] - q[0];
  pq[1] = p[1] - q[1];
  pq[2] = p[2] - q[2];
  tmp = (p[0] * pq[0] + p[1] * pq[1] + p[2] * pq[2]) / (pq[0] * pq[0] + pq[1] * pq[1] + pq[2] * pq[2]);
  for (int i = 0; i < 3; i++)
    v[i] = p[i] - pq[i] * tmp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<projectOnLine>:
  endbr64
  movupd (%rdi),%xmm1
  movupd (%rsi),%xmm6
  lea    0x8(%rdi),%rax
  movsd  0x10(%rdi),%xmm2
  movapd %xmm1,%xmm4
  movapd %xmm1,%xmm9
  movapd %xmm1,%xmm7
  subpd  %xmm6,%xmm4
  unpckhpd %xmm9,%xmm9
  movapd %xmm2,%xmm3
  movapd %xmm9,%xmm8
  subsd  0x10(%rsi),%xmm3
  movapd %xmm4,%xmm5
  movapd %xmm4,%xmm0
  movapd %xmm4,%xmm6
  mulsd  %xmm1,%xmm0
  unpckhpd %xmm5,%xmm5
  mulsd  %xmm5,%xmm8
  mulsd  %xmm3,%xmm2
  addsd  %xmm8,%xmm0
  movapd %xmm5,%xmm8
  mulsd  %xmm5,%xmm8
  addsd  %xmm2,%xmm0
  movapd %xmm4,%xmm2
  mulsd  %xmm4,%xmm2
  addsd  %xmm8,%xmm2
  movapd %xmm3,%xmm8
  mulsd  %xmm3,%xmm8
  addsd  %xmm8,%xmm2
  divsd  %xmm2,%xmm0
  cmp    %rax,%rdx
  je     L7
  movapd %xmm0,%xmm2
  mulsd  %xmm3,%xmm0
  unpcklpd %xmm2,%xmm2
  mulpd  %xmm4,%xmm2
  subpd  %xmm2,%xmm1
  movups %xmm1,(%rdx)
  movsd  0x10(%rdi),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x10(%rdx)
  ret
  nopl   0x0(%rax)
L7:
  mulsd  %xmm0,%xmm6
  mulsd  %xmm0,%xmm5
  mulsd  %xmm0,%xmm3
  subsd  %xmm6,%xmm7
  movsd  %xmm7,0x8(%rdi)
  subsd  %xmm5,%xmm7
  movsd  %xmm7,0x10(%rdi)
  subsd  %xmm3,%xmm7
  movsd  %xmm7,0x18(%rdi)
  ret
```

assistant: ```c
void projectOnLine(const double *p, const double *q, double *v) {
  double pq[3];
  double tmp;
  pq[0] = p[0] - q[0];
  pq[1] = p[1] - q[1];
  pq[2] = p[2] - q[2];
  tmp = (p[0] * pq[0] + p[1] * pq[1] + p[2] * pq[2]) / (pq[0] * pq[0] + pq[1] * pq[1] + pq[2] * pq[2]);
  for (int i = 0; i < 3; i++)
    v[i] = p[i] - pq[i] * tmp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<convertStrToIP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x38(%rbp)
  mov    %r8d,-0x3c(%rbp)
  mov    %r9d,-0x40(%rbp)
  mov    %esi,%edx
  mov    %dl,-0x2c(%rbp)
  mov    %al,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L2:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x40(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,(%rbx)
  cmpb   $0x0,-0x30(%rbp)
  je     L18
  cmpl   $0x3,-0x14(%rbp)
  jne    L18
  movsbl -0x30(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x28(%rbp)
  jmp    L29
L18:
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x28(%rbp)
L29:
  cmpq   $0x0,-0x28(%rbp)
  je     L43
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L43
  addq   $0x1,-0x28(%rbp)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L2
L43:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void convertStrToIP(const char *ipStr, char sep1, char sep2, unsigned char *ipByteArr, int maxBytes, int base) {
  int i;
  for (i = 0; i < maxBytes; i++) {
    ipByteArr[i] = strtoul(ipStr, NULL, base);
    if ((sep2 != '\0') && (i == 3)) {
      ipStr = strchr(ipStr, sep2);
    } else {
      ipStr = strchr(ipStr, sep1);
    }
    if (ipStr == NULL || *ipStr == '\0') {
      break;
    }
    ipStr++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convertStrToIP>:
  endbr64
  test   %r8d,%r8d
  jle    L1
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rcx,%r14
  mov    %r9d,%r15d
  mov    %edx,%r12d
  mov    %r8d,%r13d
  mov    $0x0,%ebp
  movsbl %sil,%eax
  mov    %eax,0xc(%rsp)
  jmp    L77
L39:
  movsbl %r12b,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
L78:
  test   %rax,%rax
  je     L13
  cmpb   $0x0,(%rax)
  je     L13
  lea    0x1(%rax),%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbp
  je     L13
L77:
  mov    %r15d,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <strtoul@plt>
  mov    %al,(%r14,%rbp,1)
  test   %r12b,%r12b
  je     L73
  cmp    $0x3,%ebp
  je     L39
L73:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  jmp    L78
L13:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  ret
```

assistant: ```c
void convertStrToIP(const char *ipStr, char sep1, char sep2, unsigned char *ipByteArr, int maxBytes, int base) {
  int i;
  for (i = 0; i < maxBytes; i++) {
    ipByteArr[i] = strtoul(ipStr, NULL, base);
    if ((sep2 != '\0') && (i == 3)) {
      ipStr = strchr(ipStr, sep2);
    } else {
      ipStr = strchr(ipStr, sep1);
    }
    if (ipStr == NULL || *ipStr == '\0') {
      break;
    }
    ipStr++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<convertStrToIP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %dl,0xf(%rsp)
  test   %r8d,%r8d
  jle    L55
  test   %dl,%dl
  mov    %rdi,%r14
  mov    %rcx,%rbp
  mov    %r9d,%r12d
  setne  0xe(%rsp)
  movslq %r8d,%rbx
  xor    %r15d,%r15d
  movsbl %sil,%r13d
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L17:
  movsbl 0xf(%rsp),%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L55
L10:
  cmpb   $0x0,(%rax)
  je     L55
  add    $0x1,%r15
  lea    0x1(%rax),%r14
  cmp    %rbx,%r15
  je     L55
L32:
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <strtoul@plt>
  mov    %al,0x0(%rbp,%r15,1)
  cmp    $0x3,%r15d
  jne    L72
  cmpb   $0x0,0xe(%rsp)
  jne    L17
L72:
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L10
L55:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convertStrToIP(const char *ipStr, char sep1, char sep2, unsigned char *ipByteArr, int maxBytes, int base) {
  int i;
  for (i = 0; i < maxBytes; i++) {
    ipByteArr[i] = strtoul(ipStr, NULL, base);
    if ((sep2 != '\0') && (i == 3)) {
      ipStr = strchr(ipStr, sep2);
    } else {
      ipStr = strchr(ipStr, sep1);
    }
    if (ipStr == NULL || *ipStr == '\0') {
      break;
    }
    ipStr++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<convertStrToIP>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %dl,0xf(%rsp)
  test   %r8d,%r8d
  jle    L21
  test   %dl,%dl
  mov    %rdi,%r14
  mov    %rcx,%rbp
  mov    %r9d,%r12d
  setne  0xe(%rsp)
  movslq %r8d,%rbx
  xor    %r15d,%r15d
  movsbl %sil,%r13d
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L8:
  movsbl 0xf(%rsp),%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L21
L36:
  cmpb   $0x0,(%rax)
  je     L21
  add    $0x1,%r15
  lea    0x1(%rax),%r14
  cmp    %rbx,%r15
  je     L21
L30:
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <strtoul@plt>
  mov    %al,0x0(%rbp,%r15,1)
  cmp    $0x3,%r15d
  jne    L13
  cmpb   $0x0,0xe(%rsp)
  jne    L8
L13:
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L36
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void convertStrToIP(const char *ipStr, char sep1, char sep2, unsigned char *ipByteArr, int maxBytes, int base) {
  int i;
  for (i = 0; i < maxBytes; i++) {
    ipByteArr[i] = strtoul(ipStr, NULL, base);
    if ((sep2 != '\0') && (i == 3)) {
      ipStr = strchr(ipStr, sep2);
    } else {
      ipStr = strchr(ipStr, sep1);
    }
    if (ipStr == NULL || *ipStr == '\0') {
      break;
    }
    ipStr++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uintToBase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
L12:
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x38(%rbp)
  mov    %edx,-0x1c(%rbp)
  cmpl   $0x9,-0x1c(%rbp)
  jg     L23
  mov    -0x1c(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  jmp    L20
L23:
  mov    -0x1c(%rbp),%eax
  add    $0x37,%eax
  mov    %eax,%ecx
L20:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %cl,(%rax)
  addl   $0x1,-0x20(%rbp)
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x38(%rbp)
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L12
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L40:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x21(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L40
  mov    -0x20(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t uintToBase(uint64_t value, char *buffer, uint32_t base) {
  char *p = buffer;
  char *p1, *p2;
  uint32_t digits = 0;
  do {
    uint32_t remainder = value % base;
    *p++ = (remainder < 10) ? remainder + '0' : remainder + 'A' - 10;
    digits++;
  } while (value /= base);
  *p = 0;
  p1 = buffer;
  p2 = p - 1;
  while (p1 < p2) {
    char tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return digits;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uintToBase>:
  endbr64
  mov    %edx,%r8d
  mov    %rsi,%rcx
  mov    $0x0,%r10d
  jmp    L30
L25:
  mov    %r9,%rcx
L30:
  mov    %edi,%eax
  cltd
  idiv   %r8d
  lea    0x30(%rdx),%r9d
  lea    0x37(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %r9d,%eax
  lea    0x1(%rcx),%r9
  mov    %al,-0x1(%r9)
  add    $0x1,%r10d
  mov    %edi,%eax
  cltd
  idiv   %r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L25
  movb   $0x0,(%r9)
  cmp    %rsi,%rcx
  jbe    L27
L22:
  movzbl (%rsi),%eax
  movzbl (%rcx),%edx
  mov    %dl,(%rsi)
  mov    %al,(%rcx)
  add    $0x1,%rsi
  sub    $0x1,%rcx
  cmp    %rcx,%rsi
  jb     L22
L27:
  mov    %r10d,%eax
  ret
```

assistant: ```c
uint32_t uintToBase(uint64_t value, char *buffer, uint32_t base) {
  char *p = buffer;
  char *p1, *p2;
  uint32_t digits = 0;
  do {
    uint32_t remainder = value % base;
    *p++ = (remainder < 10) ? remainder + '0' : remainder + 'A' - 10;
    digits++;
  } while (value /= base);
  *p = 0;
  p1 = buffer;
  p2 = p - 1;
  while (p1 < p2) {
    char tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return digits;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uintToBase>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    %rsi,%rcx
  xor    %r9d,%r9d
  jmp    L22
  nopl   0x0(%rax)
L2:
  mov    %rdi,%rcx
L22:
  cltd
  idiv   %r8d
  lea    0x30(%rdx),%r10d
  lea    0x37(%rdx),%edi
  cmp    $0x9,%edx
  mov    %r10d,%edx
  cmovg  %edi,%edx
  lea    0x1(%rcx),%rdi
  add    $0x1,%r9d
  mov    %dl,-0x1(%rdi)
  test   %eax,%eax
  jne    L2
  movb   $0x0,(%rdi)
  cmp    %rsi,%rcx
  ja     L12
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L42:
  movzbl (%rcx),%edx
L12:
  movzbl (%rsi),%eax
  sub    $0x1,%rcx
  mov    %dl,(%rsi)
  add    $0x1,%rsi
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rsi
  jb     L42
L10:
  mov    %r9d,%eax
  ret
```

assistant: ```c
uint32_t uintToBase(uint64_t value, char *buffer, uint32_t base) {
  char *p = buffer;
  char *p1, *p2;
  uint32_t digits = 0;
  do {
    uint32_t remainder = value % base;
    *p++ = (remainder < 10) ? remainder + '0' : remainder + 'A' - 10;
    digits++;
  } while (value /= base);
  *p = 0;
  p1 = buffer;
  p2 = p - 1;
  while (p1 < p2) {
    char tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return digits;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uintToBase>:
  endbr64
  mov    %edi,%eax
  mov    %edx,%r8d
  mov    %rsi,%rcx
  xor    %r9d,%r9d
  jmp    L19
  nopl   0x0(%rax)
L21:
  add    $0x30,%edx
  add    $0x1,%r9d
  mov    %dl,-0x1(%rdi)
  test   %eax,%eax
  je     L35
L14:
  mov    %rdi,%rcx
L19:
  cltd
  lea    0x1(%rcx),%rdi
  idiv   %r8d
  cmp    $0x9,%edx
  jle    L21
  add    $0x37,%edx
  add    $0x1,%r9d
  mov    %dl,-0x1(%rdi)
  test   %eax,%eax
  jne    L14
L35:
  movb   $0x0,(%rdi)
  cmp    %rsi,%rcx
  jbe    L29
  nopl   0x0(%rax)
L31:
  movzbl (%rsi),%eax
  movzbl (%rcx),%edx
  add    $0x1,%rsi
  sub    $0x1,%rcx
  mov    %dl,-0x1(%rsi)
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rsi
  jb     L31
L29:
  mov    %r9d,%eax
  ret
```

assistant: ```c
uint32_t uintToBase(uint64_t value, char *buffer, uint32_t base) {
  char *p = buffer;
  char *p1, *p2;
  uint32_t digits = 0;
  do {
    uint32_t remainder = value % base;
    *p++ = (remainder < 10) ? remainder + '0' : remainder + 'A' - 10;
    digits++;
  } while (value /= base);
  *p = 0;
  p1 = buffer;
  p2 = p - 1;
  while (p1 < p2) {
    char tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return digits;
}
```