ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<DrawTriangle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm2,%rbx
  movq   %xmm3,%rbp
  call   <MovePen@plt>
  pxor   %xmm1,%xmm1
  movq   %rbx,%xmm0
  call   <DrawLine@plt>
  movq   %rbx,%xmm0
  xorpd  D11(%rip),%xmm0
  mulsd  D0(%rip),%xmm0
  movq   %xmm0,%rbx
  movq   %rbp,%xmm1
  call   <DrawLine@plt>
  movq   %rbp,%xmm1
  xorpd  D11(%rip),%xmm1
  movq   %rbx,%xmm0
  call   <DrawLine@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D11
type: byte[16]
name: unpack_data
arguments: data_label: D0
type: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void DrawTriangle(double x, double y, double base, double height) {
  MovePen(x, y);
  DrawLine(base, 0);
  DrawLine(-base / 2, height);
  DrawLine(-base / 2, -height);
}
```
user: What is the c source code of the assembly code below:

```asm
<DrawTriangle>:
  endbr64
  push   %r14
  movq   %xmm3,%r14
  push   %rbx
  movq   %xmm2,%rbx
  sub    $0x18,%rsp
  call   <MovePen@plt>
  movq   %rbx,%xmm0
  pxor   %xmm1,%xmm1
  call   <DrawLine@plt>
  movq   %rbx,%xmm0
  movq   %r14,%xmm1
  movq   D8(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  mulsd  D2(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <DrawLine@plt>
  movq   %r14,%xmm1
  movq   D8(%rip),%xmm2
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  xorpd  %xmm2,%xmm1
  pop    %r14
  jmp    1070 <DrawLine@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: byte[8]
name: disassemble_data
arguments: data_label: D2
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void DrawTriangle(double x, double y, double base, double height) {
  MovePen(x, y);
  DrawLine(base, 0);
  DrawLine(-base / 2, height);
  DrawLine(-base / 2, -height);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<DrawTriangle>:
  endbr64
  push   %r14
  movq   %xmm3,%r14
  push   %rbx
  movq   %xmm2,%rbx
  sub    $0x18,%rsp
  call   <MovePen@plt>
  movq   %rbx,%xmm0
  pxor   %xmm1,%xmm1
  call   <DrawLine@plt>
  movq   %rbx,%xmm0
  movq   %r14,%xmm1
  movq   D26(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  mulsd  D29(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <DrawLine@plt>
  movq   %r14,%xmm1
  movq   D26(%rip),%xmm2
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  xorpd  %xmm2,%xmm1
  pop    %r14
  jmp    1070 <DrawLine@plt>
```

tool_calls: name: parse_data
arguments: label: D26
type: byte[8]
name: parse_data
arguments: label: D29
type: byte[8]

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void DrawTriangle(double x, double y, double base, double height) {
  MovePen(x, y);
  DrawLine(base, 0);
  DrawLine(-base / 2, height);
  DrawLine(-base / 2, -height);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<distributions_normal>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,(%rsp)
  movss  %xmm1,0x4(%rsp)
  mov    D83(%rip),%rax
  movq   %rax,%xmm1
  pxor   %xmm0,%xmm0
  call   <distributions_uniform@plt>
  movss  %xmm0,0x8(%rsp)
  mov    D83(%rip),%rax
  movq   %rax,%xmm1
  pxor   %xmm0,%xmm0
  call   <distributions_uniform@plt>
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  mulsd  D43(%rip),%xmm0
  call   <cos@plt>
  mov    %eax,%ebx
  movss  0xc(%rsp),%xmm0
  call   <log@plt>
  mulsd  D85(%rip),%xmm0
  call   <sqrt@plt>
  imul   %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  mulss  0x4(%rsp),%xmm0
  movaps %xmm0,%xmm6
  addss  (%rsp),%xmm6
  movd   %xmm6,%ebx
  jmp    L5
L2:
  movsd  D83(%rip),%xmm1
  pxor   %xmm0,%xmm0
  call   <distributions_uniform@plt>
  movss  %xmm0,0x8(%rsp)
  movsd  D83(%rip),%xmm1
  pxor   %xmm0,%xmm0
  call   <distributions_uniform@plt>
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  mulsd  D43(%rip),%xmm0
  call   <cos@plt>
  mov    %eax,%ebx
  movss  0xc(%rsp),%xmm0
  call   <log@plt>
  mulsd  D85(%rip),%xmm0
  call   <sqrt@plt>
  imul   %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  mulss  0x4(%rsp),%xmm0
  addss  (%rsp),%xmm0
  movd   %xmm0,%ebx
L5:
  movd   %ebx,%xmm0
  subss  (%rsp),%xmm0
  call   <fabs@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  mulsd  D24(%rip),%xmm0
  comisd %xmm0,%xmm1
  ja     L2
  movd   %ebx,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D83
type_guessed: f64
name: parse_data
arguments: data_label: D43
type_guessed: f64
name: parse_data
arguments: data_label: D85
type_guessed: f32[2]
name: parse_data
arguments: data_label: D24
type_guessed: f64

tool: D83: 1

tool: D43: 6.283185307179586

tool: {"D85": [0.0,-2.0]}

tool: D24: 20

assistant: ```c
float distributions_normal(float mean, float sigma) {
  float u1, u2, x, y;
  u1 = distributions_uniform(0.0, 1.0);
  u2 = distributions_uniform(0.0, 1.0);
  x = (float)(cos(6.283185307179586 * (float)u1) * sqrt(-2.0 * log((float)u2)));
  y = sigma * x + mean;
  while (fabs(y - mean) > 20.0 * sigma) {
    u1 = distributions_uniform(0.0, 1.0);
    u2 = distributions_uniform(0.0, 1.0);
    x = (float)(cos(6.283185307179586 * (float)u1) * sqrt(-2.0 * log((float)u2)));
    y = sigma * x + mean;
  }
  return (y);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<distributions_normal>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    D62(%rip),%rax
  movss  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  movss  %xmm1,0x14(%rsp)
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  mov    D62(%rip),%rax
  movd   %xmm0,%ebx
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  movd   %ebx,%xmm6
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm6,%xmm0
  mulsd  D38(%rip),%xmm0
  call   <cos@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <log@plt>
  mulsd  D37(%rip),%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movss  0x14(%rsp),%xmm7
  imul   %eax,%ebx
  cvtsi2ss %ebx,%xmm1
  mulss  %xmm7,%xmm1
  cvtss2sd %xmm7,%xmm7
  movsd  %xmm7,0x18(%rsp)
  addss  0x8(%rsp),%xmm1
  jmp    L10
  nopl   0x0(%rax)
L16:
  mov    D62(%rip),%rax
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  mov    D62(%rip),%rax
  movss  %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  movss  0x10(%rsp),%xmm2
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D38(%rip),%xmm0
  call   <cos@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <log@plt>
  mulsd  D37(%rip),%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  imul   %eax,%ebx
  cvtsi2ss %ebx,%xmm1
  mulss  0x14(%rsp),%xmm1
  addss  0x8(%rsp),%xmm1
L10:
  movaps %xmm1,%xmm0
  subss  0x8(%rsp),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <fabs@plt>
  movss  0xc(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movsd  D4(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  comisd %xmm0,%xmm2
  ja     L16
  add    $0x20,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D62
type_guessed: f64
name: unpack_data
arguments: tag: D38
type_guessed: f64
name: unpack_data
arguments: tag: D37
type_guessed: f32[2]
name: unpack_data
arguments: tag: D4
type_guessed: f64

tool: D62: 1

tool: D38: 6.283185307179586

tool: {"D37": [0.0,-2.0]}

tool: D4: 20

assistant: ```c
float distributions_normal(float mean, float sigma) {
  float u1, u2, x, y;
  u1 = distributions_uniform(0.0, 1.0);
  u2 = distributions_uniform(0.0, 1.0);
  x = (float)(cos(6.283185307179586 * (float)u1) * sqrt(-2.0 * log((float)u2)));
  y = sigma * x + mean;
  while (fabs(y - mean) > 20.0 * sigma) {
    u1 = distributions_uniform(0.0, 1.0);
    u2 = distributions_uniform(0.0, 1.0);
    x = (float)(cos(6.283185307179586 * (float)u1) * sqrt(-2.0 * log((float)u2)));
    y = sigma * x + mean;
  }
  return (y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<distributions_normal>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    D21(%rip),%rax
  movss  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  movss  %xmm1,0x14(%rsp)
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  mov    D21(%rip),%rax
  movd   %xmm0,%ebx
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  movd   %ebx,%xmm6
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm6,%xmm0
  mulsd  D3(%rip),%xmm0
  call   <cos@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <log@plt>
  mulsd  D59(%rip),%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  movss  0x14(%rsp),%xmm7
  imul   %eax,%ebx
  cvtsi2ss %ebx,%xmm1
  mulss  %xmm7,%xmm1
  cvtss2sd %xmm7,%xmm7
  movsd  %xmm7,0x18(%rsp)
  addss  0x8(%rsp),%xmm1
  jmp    L8
  nopl   0x0(%rax)
L9:
  mov    D21(%rip),%rax
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  mov    D21(%rip),%rax
  movss  %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movq   %rax,%xmm1
  call   <distributions_uniform@plt>
  movss  0x10(%rsp),%xmm2
  movss  %xmm0,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm0
  mulsd  D3(%rip),%xmm0
  call   <cos@plt>
  movss  0xc(%rsp),%xmm1
  mov    %eax,%ebx
  movaps %xmm1,%xmm0
  call   <log@plt>
  mulsd  D59(%rip),%xmm0
  call   <sqrt@plt>
  pxor   %xmm1,%xmm1
  imul   %eax,%ebx
  cvtsi2ss %ebx,%xmm1
  mulss  0x14(%rsp),%xmm1
  addss  0x8(%rsp),%xmm1
L8:
  movaps %xmm1,%xmm0
  subss  0x8(%rsp),%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <fabs@plt>
  movss  0xc(%rsp),%xmm1
  movapd %xmm0,%xmm2
  movsd  D36(%rip),%xmm0
  mulsd  0x18(%rsp),%xmm0
  comisd %xmm0,%xmm2
  ja     L9
  add    $0x20,%rsp
  movaps %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: f64
name: read_data
arguments: data_label: D3
datatype: f64
name: read_data
arguments: data_label: D59
datatype: f32[2]
name: read_data
arguments: data_label: D36
datatype: f64

tool: D21: 1

tool: D3: 6.283185307179586

tool: {"D59": [0.0,-2.0]}

tool: D36: 20

assistant: ```c
float distributions_normal(float mean, float sigma) {
  float u1, u2, x, y;
  u1 = distributions_uniform(0.0, 1.0);
  u2 = distributions_uniform(0.0, 1.0);
  x = (float)(cos(6.283185307179586 * (float)u1) * sqrt(-2.0 * log((float)u2)));
  y = sigma * x + mean;
  while (fabs(y - mean) > 20.0 * sigma) {
    u1 = distributions_uniform(0.0, 1.0);
    u2 = distributions_uniform(0.0, 1.0);
    x = (float)(cos(6.283185307179586 * (float)u1) * sqrt(-2.0 * log((float)u2)));
    y = sigma * x + mean;
  }
  return (y);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L25
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  jmp    L31
L25:
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    $0x0,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' || s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strcmp>:
  endbr64
  mov    $0x0,%eax
  jmp    L11
L29:
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %dl,%cl
  jne    L39
L11:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L29
  movzbl (%rsi,%rax,1),%ecx
  test   %cl,%cl
  je     L33
L39:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L33:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' || s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_strcmp>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L20
  test   %cl,%cl
  je     L12
L3:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L2
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' || s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strcmp>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L24
  test   %cl,%cl
  je     L18
L34:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  add    $0x1,%rax
  cmp    %cl,%dl
  je     L3
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strcmp(const char *s1, const char *s2) {
  int i;
  i = 0;
  while (s1[i] != '\0' || s2[i] != '\0') {
    if (s1[i] != s2[i])
      return (s1[i] - s2[i]);
    i++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_guessed: string
name: disassemble_data
arguments: data_tag: D39
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D36
type_guessed: string

tool: D11: 

p = %x


tool: D39: p + 0x1 = %x


tool: D19: (unsigned long)p + 0x1 = %x


tool: D36: (unsigned int *)p + 0x1 = %x


assistant: ```c
void test() {
  struct Test {
    int num;
    char *pNum;
    short sDate;
    char c[2];
    short sBa[4];
  } * p;
  printf("\n\np = %x\n", p);
  printf("p + 0x1 = %x\n", p + 0x1);
  printf("(unsigned long)p + 0x1 = %x\n", (unsigned long)p + 0x1);
  printf("(unsigned int *)p + 0x1 = %x\n", (unsigned int *)p + 0x1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x20(%rbx),%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rbx),%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
datatype: string
name: extract_symbolic_data
arguments: data_tag: D6
datatype: string
name: extract_symbolic_data
arguments: data_tag: D27
datatype: string
name: extract_symbolic_data
arguments: data_tag: D35
datatype: string

tool: D16: 

p = %x


tool: D6: p + 0x1 = %x


tool: D27: (unsigned long)p + 0x1 = %x


tool: D35: (unsigned int *)p + 0x1 = %x


assistant: ```c
void test() {
  struct Test {
    int num;
    char *pNum;
    short sDate;
    char c[2];
    short sBa[4];
  } * p;
  printf("\n\np = %x\n", p);
  printf("p + 0x1 = %x\n", p + 0x1);
  printf("(unsigned long)p + 0x1 = %x\n", (unsigned long)p + 0x1);
  printf("(unsigned int *)p + 0x1 = %x\n", (unsigned int *)p + 0x1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <printf@plt>
  lea    0x20(%rbx),%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rbx),%rsi
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D28
type_infered: string
name: read_data
arguments: label: D31
type_infered: string

tool: D25: 

p = %x


tool: D4: p + 0x1 = %x


tool: D28: (unsigned long)p + 0x1 = %x


tool: D31: (unsigned int *)p + 0x1 = %x


assistant: ```c
void test() {
  struct Test {
    int num;
    char *pNum;
    short sDate;
    char c[2];
    short sBa[4];
  } * p;
  printf("\n\np = %x\n", p);
  printf("p + 0x1 = %x\n", p + 0x1);
  printf("(unsigned long)p + 0x1 = %x\n", (unsigned long)p + 0x1);
  printf("(unsigned int *)p + 0x1 = %x\n", (unsigned int *)p + 0x1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <printf@plt>
  lea    0x20(%rbx),%rsi
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%rsi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rbx),%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D21
data_type: string
name: parse_data
arguments: data_label: D35
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string

tool: D21: 

p = %x


tool: D35: p + 0x1 = %x


tool: D18: (unsigned long)p + 0x1 = %x


tool: D5: (unsigned int *)p + 0x1 = %x


assistant: ```c
void test() {
  struct Test {
    int num;
    char *pNum;
    short sDate;
    char c[2];
    short sBa[4];
  } * p;
  printf("\n\np = %x\n", p);
  printf("p + 0x1 = %x\n", p + 0x1);
  printf("(unsigned long)p + 0x1 = %x\n", (unsigned long)p + 0x1);
  printf("(unsigned int *)p + 0x1 = %x\n", (unsigned int *)p + 0x1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<array_uint24_be_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void array_uint24_be_set(unsigned char data[], const unsigned int input) {
  data[0] = (input >> 16) & 0xFF;
  data[1] = (input >> 8) & 0xFF;
  data[2] = input & 0xFF;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<array_uint24_be_set>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rdi)
  mov    %sil,0x2(%rdi)
  ret
```

assistant: ```c
void array_uint24_be_set(unsigned char data[], const unsigned int input) {
  data[0] = (input >> 16) & 0xFF;
  data[1] = (input >> 8) & 0xFF;
  data[2] = input & 0xFF;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<array_uint24_be_set>:
  endbr64
  mov    %esi,%eax
  rol    $0x8,%si
  shr    $0x10,%eax
  mov    %si,0x1(%rdi)
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void array_uint24_be_set(unsigned char data[], const unsigned int input) {
  data[0] = (input >> 16) & 0xFF;
  data[1] = (input >> 8) & 0xFF;
  data[2] = input & 0xFF;
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_uint24_be_set>:
  endbr64
  mov    %esi,%eax
  rol    $0x8,%si
  shr    $0x10,%eax
  mov    %si,0x1(%rdi)
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void array_uint24_be_set(unsigned char data[], const unsigned int input) {
  data[0] = (input >> 16) & 0xFF;
  data[1] = (input >> 8) & 0xFF;
  data[2] = input & 0xFF;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<std_dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ave_dvector@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x1,-0x18(%rbp)
  jmp    L8
L7:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  -0x20(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jle    L7
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double std_dvector(double *d, long n) {
  double aved, dsum = 0.0, temp;
  long i;
  aved = ave_dvector(d, n);
  for (i = 1; i <= n; i++) {
    temp = d[i] - aved;
    dsum += temp * temp;
  }
  return sqrt(dsum / (n - 1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<std_dvector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <ave_dvector@plt>
  test   %rbx,%rbx
  jle    L45
  movapd %xmm0,%xmm2
  lea    0x8(%rbp),%rax
  lea    0x0(%rbp,%rbx,8),%rcx
  pxor   %xmm0,%xmm0
L6:
  movsd  (%rax),%xmm1
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mov    %rax,%rdx
  add    $0x8,%rax
  cmp    %rcx,%rdx
  jne    L6
L8:
  sub    $0x1,%rbx
  pxor   %xmm1,%xmm1
  cvtsi2sd %rbx,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L27
  sqrtsd %xmm0,%xmm0
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L45:
  pxor   %xmm0,%xmm0
  jmp    L8
L27:
  call   <sqrt@plt>
  jmp    L14
```

assistant: ```c
double std_dvector(double *d, long n) {
  double aved, dsum = 0.0, temp;
  long i;
  aved = ave_dvector(d, n);
  for (i = 1; i <= n; i++) {
    temp = d[i] - aved;
    dsum += temp * temp;
  }
  return sqrt(dsum / (n - 1));
}
```