ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L8
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L8:
  movl   $0x2,-0x4(%rbp)
  jmp    L4
L0:
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
  movl   $0x1,-0x8(%rbp)
L24:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4(%rbp)
  jle    L0
L16:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string

tool: D5: i = %d, n=%d


assistant: ```c
int check_prime(int num) {
  int flag = 0, i;
  if (num == 2)
    flag = 0;
  else {
    for (i = 2; i <= num / 2; i++) {
      printf("i = %d, n=%d\n", i, num);
      if (num % i == 0)
        flag = 1;
    }
  }
  return flag;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_prime>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%r12d
  cmp    $0x2,%edi
  je     L23
  mov    %edi,%ebp
  mov    %edi,%r13d
  shr    $0x1f,%r13d
  add    %edi,%r13d
  sar    %r13d
  cmp    $0x3,%edi
  jle    L30
  mov    $0x2,%ebx
  lea    D2(%rip),%r14
L19:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %ebp,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  mov    $0x1,%eax
  cmove  %eax,%r12d
  add    $0x1,%ebx
  cmp    %r13d,%ebx
  jle    L19
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  mov    $0x0,%r12d
  jmp    L23
```

tool_calls: name: read_data
arguments: data_label: D2
type: string

tool: D2: i = %d, n=%d


assistant: ```c
int check_prime(int num) {
  int flag = 0, i;
  if (num == 2)
    flag = 0;
  else {
    for (i = 2; i <= num / 2; i++) {
      printf("i = %d, n=%d\n", i, num);
      if (num % i == 0)
        flag = 1;
    }
  }
  return flag;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_prime>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L6
  mov    %edi,%ebp
  mov    %edi,%r12d
  shr    $0x1f,%ebp
  add    %edi,%ebp
  sar    %ebp
  cmp    $0x3,%edi
  jle    L6
  mov    $0x2,%ebx
  lea    D8(%rip),%r15
  mov    $0x1,%r14d
  nopl   (%rax)
L12:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  cmove  %r14d,%r13d
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L12
L6:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D8
data_type: string

tool: D8: i = %d, n=%d


assistant: ```c
int check_prime(int num) {
  int flag = 0, i;
  if (num == 2)
    flag = 0;
  else {
    for (i = 2; i <= num / 2; i++) {
      printf("i = %d, n=%d\n", i, num);
      if (num % i == 0)
        flag = 1;
    }
  }
  return flag;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<check_prime>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L10
  mov    %edi,%ebp
  mov    %edi,%r12d
  shr    $0x1f,%ebp
  add    %edi,%ebp
  sar    %ebp
  cmp    $0x3,%edi
  jle    L10
  mov    $0x2,%ebx
  lea    D7(%rip),%r15
  mov    $0x1,%r14d
  nopl   (%rax)
L2:
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  cmove  %r14d,%r13d
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jle    L2
L10:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D7: i = %d, n=%d


assistant: ```c
int check_prime(int num) {
  int flag = 0, i;
  if (num == 2)
    flag = 0;
  else {
    for (i = 2; i <= num / 2; i++) {
      printf("i = %d, n=%d\n", i, num);
      if (num % i == 0)
        flag = 1;
    }
  }
  return flag;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_key_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L6:
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L6
  mov    -0x8(%rbp),%eax
  lea    -0x3(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_mini_atoi@plt>
  leave
  ret
```

assistant: ```c
int ft_key_len(char *str) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\n')
    i++;
  return (ft_mini_atoi(str, i - 3));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_key_len>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0xa,(%rdi)
  je     L2
  mov    $0x1,%eax
L0:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rdi,%rax,1)
  jne    L0
L18:
  sub    $0x3,%esi
  call   <ft_mini_atoi@plt>
  add    $0x8,%rsp
  ret
L2:
  mov    $0x0,%esi
  jmp    L18
```

assistant: ```c
int ft_key_len(char *str) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\n')
    i++;
  return (ft_mini_atoi(str, i - 3));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_key_len>:
  endbr64
  cmpb   $0xa,(%rdi)
  je     L14
  mov    $0x1,%eax
  xchg   %ax,%ax
L10:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rdi,%rax,1)
  jne    L10
  sub    $0x3,%esi
  jmp    1050 <ft_mini_atoi@plt>
  nopl   (%rax)
L14:
  mov    $0xfffffffd,%esi
  jmp    1050 <ft_mini_atoi@plt>
```

assistant: ```c
int ft_key_len(char *str) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\n')
    i++;
  return (ft_mini_atoi(str, i - 3));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_key_len>:
  endbr64
  cmpb   $0xa,(%rdi)
  je     L3
  mov    $0x1,%eax
  xchg   %ax,%ax
L11:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0xa,-0x1(%rdi,%rax,1)
  jne    L11
  sub    $0x3,%esi
  jmp    1050 <ft_mini_atoi@plt>
  nopl   (%rax)
L3:
  mov    $0xfffffffd,%esi
  jmp    1050 <ft_mini_atoi@plt>
```

assistant: ```c
int ft_key_len(char *str) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (str[i] != '\n')
    i++;
  return (ft_mini_atoi(str, i - 3));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wl_numb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <explication@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L12
  mov    $0xfffffffd,%edi
  call   <errPointer@plt>
L12:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <init_numb@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  lea    -0x2c(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <manage_size@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  mov    $0xfffffffc,%edi
  call   <errPointer@plt>
L10:
  mov    $0x0,%eax
  call   <manage_file@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <totDispRip@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%esi
  mov    -0x10(%rbp),%rdi
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdi,%r9
  mov    %esi,%r8d
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <disprip_numb@plt>
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <end@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void wl_numb() {
  FILE *fp = NULL;
  int *v = NULL, *sol = NULL;
  int size = 0;
  long int tot = 0;
  explication();
  fflush(stdin);
  v = malloc(10 * sizeof(int));
  if (v == NULL)
    errPointer(-3);
  v = init_numb(v);
  sol = manage_size(&size, sol);
  sol = malloc(size * sizeof(int));
  if (sol == NULL)
    errPointer(-4);
  fp = manage_file();
  tot = totDispRip(size, 10);
  disprip_numb(fp, 0, v, sol, size, tot);
  end(size);
  fclose(fp);
  free(v);
  free(sol);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wl_numb>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <explication@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L37
L49:
  mov    %rbx,%rdi
  call   <init_numb@plt>
  mov    %rax,%rbp
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <manage_size@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L44
L40:
  mov    $0x0,%eax
  call   <manage_file@plt>
  mov    %rax,%r12
  mov    $0xa,%esi
  mov    0x4(%rsp),%edi
  call   <totDispRip@plt>
  mov    %rax,%r9
  mov    0x4(%rsp),%r8d
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <disprip_numb@plt>
  mov    0x4(%rsp),%edi
  call   <end@plt>
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  mov    $0xfffffffd,%edi
  call   <errPointer@plt>
  jmp    L49
L44:
  mov    $0xfffffffc,%edi
  call   <errPointer@plt>
  jmp    L40
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wl_numb() {
  FILE *fp = NULL;
  int *v = NULL, *sol = NULL;
  int size = 0;
  long int tot = 0;
  explication();
  fflush(stdin);
  v = malloc(10 * sizeof(int));
  if (v == NULL)
    errPointer(-3);
  v = init_numb(v);
  sol = manage_size(&size, sol);
  sol = malloc(size * sizeof(int));
  if (sol == NULL)
    errPointer(-4);
  fp = manage_file();
  tot = totDispRip(size, 10);
  disprip_numb(fp, 0, v, sol, size, tot);
  end(size);
  fclose(fp);
  free(v);
  free(sol);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wl_numb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <explication@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L13
L38:
  mov    %rbp,%rdi
  call   <init_numb@plt>
  lea    0x4(%rsp),%rdi
  xor    %esi,%esi
  mov    %rax,%r12
  call   <manage_size@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L29
L48:
  xor    %eax,%eax
  call   <manage_file@plt>
  mov    0x4(%rsp),%edi
  mov    $0xa,%esi
  mov    %rax,%r13
  call   <totDispRip@plt>
  mov    0x4(%rsp),%r8d
  xor    %esi,%esi
  mov    %rbp,%rcx
  mov    %rax,%r9
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <disprip_numb@plt>
  mov    0x4(%rsp),%edi
  call   <end@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L13:
  mov    $0xfffffffd,%edi
  call   <errPointer@plt>
  jmp    L38
  nop
L29:
  mov    $0xfffffffc,%edi
  call   <errPointer@plt>
  jmp    L48
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wl_numb() {
  FILE *fp = NULL;
  int *v = NULL, *sol = NULL;
  int size = 0;
  long int tot = 0;
  explication();
  fflush(stdin);
  v = malloc(10 * sizeof(int));
  if (v == NULL)
    errPointer(-3);
  v = init_numb(v);
  sol = manage_size(&size, sol);
  sol = malloc(size * sizeof(int));
  if (sol == NULL)
    errPointer(-4);
  fp = manage_file();
  tot = totDispRip(size, 10);
  disprip_numb(fp, 0, v, sol, size, tot);
  end(size);
  fclose(fp);
  free(v);
  free(sol);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wl_numb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <explication@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L31
L33:
  mov    %rbp,%rdi
  call   <init_numb@plt>
  lea    0x4(%rsp),%rdi
  xor    %esi,%esi
  mov    %rax,%r12
  call   <manage_size@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L0
L4:
  xor    %eax,%eax
  call   <manage_file@plt>
  mov    0x4(%rsp),%edi
  mov    $0xa,%esi
  mov    %rax,%r13
  call   <totDispRip@plt>
  mov    0x4(%rsp),%r8d
  xor    %esi,%esi
  mov    %rbp,%rcx
  mov    %rax,%r9
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <disprip_numb@plt>
  mov    0x4(%rsp),%edi
  call   <end@plt>
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L31:
  mov    $0xfffffffd,%edi
  call   <errPointer@plt>
  jmp    L33
  nop
L0:
  mov    $0xfffffffc,%edi
  call   <errPointer@plt>
  jmp    L4
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void wl_numb() {
  FILE *fp = NULL;
  int *v = NULL, *sol = NULL;
  int size = 0;
  long int tot = 0;
  explication();
  fflush(stdin);
  v = malloc(10 * sizeof(int));
  if (v == NULL)
    errPointer(-3);
  v = init_numb(v);
  sol = manage_size(&size, sol);
  sol = malloc(size * sizeof(int));
  if (sol == NULL)
    errPointer(-4);
  fp = manage_file();
  tot = totDispRip(size, 10);
  disprip_numb(fp, 0, v, sol, size, tot);
  end(size);
  fclose(fp);
  free(v);
  free(sol);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L11:
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L20:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L19
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L19:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L20
  subl   $0x1,-0xc(%rbp)
L0:
  cmpl   $0x0,-0xc(%rbp)
  jg     L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  test   %r8d,%r8d
  jg     L22
  ret
L63:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L64
L8:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L63
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L63
L64:
  sub    $0x1,%r8d
  je     L58
L22:
  test   %r8d,%r8d
  jle    L64
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L8
L58:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L28
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rdi,%rax,4),%edx
  mov    0x4(%rdi,%rax,4),%ecx
  cmp    %ecx,%edx
  jle    L12
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,0x4(%rdi,%rax,4)
L12:
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L29
  sub    $0x1,%esi
  jne    L21
L28:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L26
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L0:
  movq   (%rdi,%rdx,4),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L2
  movq   %xmm1,(%rdi,%rdx,4)
L2:
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L0
  sub    $0x1,%esi
  jne    L10
L26:
  ret
```

assistant: ```c
void sort(int *number, int n) {
  int temp;
  for (int i = n - 1; i > 0; i--) {
    for (int j = 0; j < i; j++)
      if (number[j] > number[j + 1]) {
        temp = number[j];
        number[j] = number[j + 1];
        number[j + 1] = temp;
      }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<arr_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %rax,%r10
  mov    $0x0,%r11d
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L18:
  cmp    %rdx,%rsp
  je     L8
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L18
L8:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L13
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L13:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <arr_get@plt>
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <arr_put@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void arr_pop(void *dst, void *src, size_t size) {
  char tmp[size];
  arr_get(tmp, src, size);
  arr_put(dst, tmp, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arr_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L5:
  cmp    %rdx,%rsp
  je     L2
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L2:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L24
  orq    $0x0,-0x8(%rsp,%rax,1)
L24:
  mov    %rbx,%rdx
  mov    %rsp,%rdi
  call   <arr_get@plt>
  mov    %rbx,%rdx
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <arr_put@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void arr_pop(void *dst, void *src, size_t size) {
  char tmp[size];
  arr_get(tmp, src, size);
  arr_put(dst, tmp, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arr_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L37
L3:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L3
L37:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L32
L2:
  mov    %r12,%rdx
  mov    %rsp,%rdi
  call   <arr_get@plt>
  mov    %r12,%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <arr_put@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L2
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void arr_pop(void *dst, void *src, size_t size) {
  char tmp[size];
  arr_get(tmp, src, size);
  arr_put(dst, tmp, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arr_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L48
L42:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L42
L48:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L40
L3:
  mov    %r12,%rdx
  mov    %rsp,%rdi
  call   <arr_get@plt>
  mov    %r12,%rdx
  mov    %rsp,%rsi
  mov    %r13,%rdi
  call   <arr_put@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  lea    -0x10(%rbp),%rsp
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L40:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L3
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void arr_pop(void *dst, void *src, size_t size) {
  char tmp[size];
  arr_get(tmp, src, size);
  arr_put(dst, tmp, size);
}
```