ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<floats_rpy_to_mat44>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <floats_rpy_to_quat@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <floats_quat_to_mat44@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_rpy_to_mat44(const float rpy[3], float M[16]) {
  float q[4];
  floats_rpy_to_quat(rpy, q);
  floats_quat_to_mat44(q, M);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<floats_rpy_to_mat44>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <floats_rpy_to_quat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <floats_quat_to_mat44@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_rpy_to_mat44(const float rpy[3], float M[16]) {
  float q[4];
  floats_rpy_to_quat(rpy, q);
  floats_quat_to_mat44(q, M);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<floats_rpy_to_mat44>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <floats_rpy_to_quat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <floats_quat_to_mat44@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void floats_rpy_to_mat44(const float rpy[3], float M[16]) {
  float q[4];
  floats_rpy_to_quat(rpy, q);
  floats_quat_to_mat44(q, M);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L37:
  movl   $0x1,-0x8(%rbp)
  jmp    L34
L7:
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L7
  mov    $0xa,%edi
  call   <putchar@plt>
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jg     L37
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: % f 

assistant: ```c
void print_array(int N, float *arr) {
  int i, j;
  for (j = N; j >= 1; j--) {
    for (i = 1; i <= N; i++)
      printf("% f ", arr[((i) + (N + 2) * (j))]);
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L14
  mov    %edi,%r12d
  movslq %edi,%rax
  mov    $0xfffffffffffffffe,%r15
  sub    %rax,%r15
  shl    $0x2,%r15
  lea    0x2(%rdi),%eax
  imul   %edi,%eax
  cltq
  lea    (%rsi,%rax,4),%rbp
  mov    %edi,%r14d
  lea    D4(%rip),%r13
L5:
  mov    $0x1,%ebx
L22:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  add    %r15,%rbp
  sub    $0x1,%r14d
  jne    L5
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4: % f 

assistant: ```c
void print_array(int N, float *arr) {
  int i, j;
  for (j = N; j >= 1; j--) {
    for (i = 1; i <= N; i++)
      printf("% f ", arr[((i) + (N + 2) * (j))]);
    printf("\n");
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_array>:
  endbr64
  test   %edi,%edi
  jle    L12
  lea    0x2(%rdi),%eax
  push   %r15
  mov    $0xfffffffe,%r15d
  imul   %edi,%eax
  push   %r14
  sub    %edi,%r15d
  mov    %edi,%r14d
  push   %r13
  movslq %r15d,%r15
  lea    D9(%rip),%r13
  push   %r12
  shl    $0x2,%r15
  mov    %edi,%r12d
  push   %rbp
  cltq
  push   %rbx
  lea    (%rsi,%rax,4),%rbp
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L23:
  mov    $0x1,%ebx
  nopl   (%rax)
L27:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm0
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L27
  mov    $0xa,%edi
  add    %r15,%rbp
  call   <putchar@plt>
  sub    $0x1,%r14d
  jne    L23
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
L12:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D9: % f 

assistant: ```c
void print_array(int N, float *arr) {
  int i, j;
  for (j = N; j >= 1; j--) {
    for (i = 1; i <= N; i++)
      printf("% f ", arr[((i) + (N + 2) * (j))]);
    printf("\n");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<print_array>:
  endbr64
  test   %edi,%edi
  jle    L4
  lea    0x2(%rdi),%eax
  push   %r15
  mov    $0xfffffffe,%r15d
  imul   %edi,%eax
  push   %r14
  sub    %edi,%r15d
  mov    %edi,%r14d
  push   %r13
  movslq %r15d,%r15
  lea    D9(%rip),%r13
  push   %r12
  shl    $0x2,%r15
  mov    %edi,%r12d
  push   %rbp
  cltq
  push   %rbx
  lea    (%rsi,%rax,4),%rbp
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x1,%ebx
  nopl   (%rax)
L9:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm0
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L9
  mov    $0xa,%edi
  add    %r15,%rbp
  call   <putchar@plt>
  sub    $0x1,%r14d
  jne    L17
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
L4:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: % f 

assistant: ```c
void print_array(int N, float *arr) {
  int i, j;
  for (j = N; j >= 1; j--) {
    for (i = 1; i <= N; i++)
      printf("% f ", arr[((i) + (N + 2) * (j))]);
    printf("\n");
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<l1_norm_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L21
L32:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L3
  movsd  -0x8(%rbp),%xmm0
  jmp    L25
L3:
  movsd  -0x8(%rbp),%xmm0
  movq   D4(%rip),%xmm1
  xorpd  %xmm1,%xmm0
L25:
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L21:
  mov    -0x34(%rbp),%eax
  imul   -0x38(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L32
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: f32[2]

tool: {"D4": [0.0,-0.0]}

assistant: ```c
double l1_norm_diff(double *mat1, double *mat2, int rows, int cols) {
  double sum = 0;
  int i;
  for (i = 0; i < rows * cols; i++) {
    double val = *mat1++ - *mat2++;
    sum += ((val) > 0 ? (val) : -(val));
  }
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<l1_norm_diff>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L47
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm2
  movq   D6(%rip),%xmm3
  jmp    L13
L28:
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L1
L13:
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  comisd %xmm2,%xmm0
  ja     L28
  xorpd  %xmm3,%xmm0
  jmp    L28
L47:
  pxor   %xmm1,%xmm1
L1:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: f32[2]

tool: {"D6": [0.0,-0.0]}

assistant: ```c
double l1_norm_diff(double *mat1, double *mat2, int rows, int cols) {
  double sum = 0;
  int i;
  for (i = 0; i < rows * cols; i++) {
    double val = *mat1++ - *mat2++;
    sum += ((val) > 0 ? (val) : -(val));
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<l1_norm_diff>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L5
  pxor   %xmm2,%xmm2
  movq   D1(%rip),%xmm3
  movslq %edx,%rdx
  xor    %eax,%eax
  movapd %xmm2,%xmm1
L28:
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  comisd %xmm2,%xmm0
  ja     L23
  xorpd  %xmm3,%xmm0
L23:
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L28
  movapd %xmm1,%xmm0
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: f32[2]

tool: {"D1": [0.0,-0.0]}

assistant: ```c
double l1_norm_diff(double *mat1, double *mat2, int rows, int cols) {
  double sum = 0;
  int i;
  for (i = 0; i < rows * cols; i++) {
    double val = *mat1++ - *mat2++;
    sum += ((val) > 0 ? (val) : -(val));
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<l1_norm_diff>:
  endbr64
  imul   %ecx,%edx
  test   %edx,%edx
  jle    L5
  cmp    $0x1,%edx
  je     L25
  mov    %edx,%ecx
  pxor   %xmm4,%xmm4
  movapd D2(%rip),%xmm6
  xor    %eax,%eax
  shr    %ecx
  movapd %xmm4,%xmm0
  pxor   %xmm5,%xmm5
  shl    $0x4,%rcx
  cs nopw 0x0(%rax,%rax,1)
L22:
  movupd (%rdi,%rax,1),%xmm2
  movupd (%rsi,%rax,1),%xmm7
  movapd %xmm5,%xmm1
  add    $0x10,%rax
  subpd  %xmm7,%xmm2
  cmpltpd %xmm2,%xmm1
  movapd %xmm2,%xmm3
  xorpd  %xmm6,%xmm3
  andpd  %xmm1,%xmm2
  andnpd %xmm3,%xmm1
  orpd   %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L22
  mov    %edx,%ecx
  and    $0xfffffffe,%ecx
  mov    %ecx,%eax
  shl    $0x3,%rax
  add    %rax,%rdi
  add    %rax,%rsi
  cmp    %ecx,%edx
  je     L4
L26:
  movsd  (%rdi),%xmm1
  subsd  (%rsi),%xmm1
  comisd %xmm4,%xmm1
  ja     L27
  xorpd  D3(%rip),%xmm1
L27:
  addsd  %xmm1,%xmm0
  ret
L4:
  ret
  nopl   0x0(%rax)
L5:
  pxor   %xmm0,%xmm0
  ret
L25:
  pxor   %xmm4,%xmm4
  movapd %xmm4,%xmm0
  jmp    L26
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: f32[4]
name: unpack_data
arguments: tag: D3
type_guessed: f32[4]

tool: {"D2": [0.0,-0.0,0.0,-0.0]}

tool: {"D3": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double l1_norm_diff(double *mat1, double *mat2, int rows, int cols) {
  double sum = 0;
  int i;
  for (i = 0; i < rows * cols; i++) {
    double val = *mat1++ - *mat2++;
    sum += ((val) > 0 ? (val) : -(val));
  }
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uninivar_wcrtomb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rdx
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <wcrtomb@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninivar_wcrtomb(void) {
  char *s;
  wchar_t wc;
  mbstate_t *ps;
  (void)wcrtomb(s, wc, ps);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninivar_wcrtomb>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <wcrtomb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninivar_wcrtomb(void) {
  char *s;
  wchar_t wc;
  mbstate_t *ps;
  (void)wcrtomb(s, wc, ps);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uninivar_wcrtomb>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcrtomb@plt>
```

assistant: ```c
void uninivar_wcrtomb(void) {
  char *s;
  wchar_t wc;
  mbstate_t *ps;
  (void)wcrtomb(s, wc, ps);
}
```
user: What is the c source code of the assembly code below?

```asm
<uninivar_wcrtomb>:
  endbr64
  xor    %edx,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <wcrtomb@plt>
```

assistant: ```c
void uninivar_wcrtomb(void) {
  char *s;
  wchar_t wc;
  mbstate_t *ps;
  (void)wcrtomb(s, wc, ps);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_argv_to_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  nop
  nop
  leave
  ret
```

assistant: ```c
void copy_argv_to_array(int *array, char *argv[], int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    array[i] = (int)strtol(argv[i], (char **)0, 10);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<copy_argv_to_array>:
  endbr64
  test   %edx,%edx
  jle    L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L11:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void copy_argv_to_array(int *array, char *argv[], int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    array[i] = (int)strtol(argv[i], (char **)0, 10);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copy_argv_to_array>:
  endbr64
  test   %edx,%edx
  jle    L4
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L12:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void copy_argv_to_array(int *array, char *argv[], int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    array[i] = (int)strtol(argv[i], (char **)0, 10);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<copy_argv_to_array>:
  endbr64
  test   %edx,%edx
  jle    L1
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L19:
  mov    0x0(%r13,%rbx,8),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %eax,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void copy_argv_to_array(int *array, char *argv[], int len) {
  int i = 0;
  for (i = 0; i < len; i++) {
    array[i] = (int)strtol(argv[i], (char **)0, 10);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getinput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L17
L28:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L17
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  js     L28
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D4: %d

tool: D10: I need a non-negative number: 

assistant: ```c
int getinput(void) {
  int inp;
  inp = -1;
  while (0 > inp) {
    scanf("%d", &inp);
    if (0 > inp) {
      printf("I need a non-negative number: ");
    }
  }
  return inp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getinput>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  lea    D11(%rip),%rbp
  lea    0x4(%rsp),%rbx
  lea    D19(%rip),%r12
L11:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jns    L27
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x4(%rsp)
  jns    L11
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L11
L27:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string

tool: D11: %d

tool: D19: I need a non-negative number: 

assistant: ```c
int getinput(void) {
  int inp;
  inp = -1;
  while (0 > inp) {
    scanf("%d", &inp);
    if (0 > inp) {
      printf("I need a non-negative number: ");
    }
  }
  return inp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getinput>:
  endbr64
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  mov    $0xffffffff,%eax
  lea    0x4(%rsp),%rbp
L17:
  test   %eax,%eax
  jns    L31
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L5
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L17
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_infered: string
name: retrieve_data
arguments: data_tag: D19
type_infered: string

tool: D9: I need a non-negative number: 

tool: D19: %d

assistant: ```c
int getinput(void) {
  int inp;
  inp = -1;
  while (0 > inp) {
    scanf("%d", &inp);
    if (0 > inp) {
      printf("I need a non-negative number: ");
    }
  }
  return inp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getinput>:
  endbr64
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0x4(%rsp)
  mov    $0xffffffff,%eax
  lea    0x4(%rsp),%rbp
L19:
  test   %eax,%eax
  jns    L35
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L32
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L32:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  jmp    L19
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
datatype: string
name: extract_symbolic_data
arguments: data_tag: D15
datatype: string

tool: D16: I need a non-negative number: 

tool: D15: %d

assistant: ```c
int getinput(void) {
  int inp;
  inp = -1;
  while (0 > inp) {
    scanf("%d", &inp);
    if (0 > inp) {
      printf("I need a non-negative number: ");
    }
  }
  return inp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<itoa10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movb   $0x0,D10(%rip)
  movl   $0x9,-0x4(%rbp)
  jmp    L17
L11:
  mov    -0x18(%rbp),%rcx
  movabs $0xcccccccccccccccd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  mov    %edx,%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    D17(%rip),%rdx
  mov    %cl,(%rax,%rdx,1)
  mov    -0x18(%rbp),%rax
  movabs $0xcccccccccccccccd,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x3,%rax
  mov    %rax,-0x18(%rbp)
  subl   $0x1,-0x4(%rbp)
L17:
  cmpl   $0x0,-0x4(%rbp)
  jns    L11
  lea    D17(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *itoa10(unsigned long num) {
  static char buf[12];
  int i;
  buf[10] = 0;
  for (i = 9; i >= 0; --i) {
    buf[i] = (char)((num % 10) + '0');
    num /= 10;
  }
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa10>:
  endbr64
  lea    D13(%rip),%r8
  movb   $0x0,D3(%rip)
  lea    0x9(%r8),%rcx
  movabs $0xcccccccccccccccd,%rsi
L4:
  mov    %rdi,%rax
  mul    %rsi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rdi
  add    $0x30,%edi
  mov    %dil,(%rcx)
  mov    %rdx,%rdi
  mov    %rcx,%rax
  sub    $0x1,%rcx
  cmp    %r8,%rax
  jne    L4
  lea    D13(%rip),%rax
  ret
```

assistant: ```c
char *itoa10(unsigned long num) {
  static char buf[12];
  int i;
  buf[10] = 0;
  for (i = 9; i >= 0; --i) {
    buf[i] = (char)((num % 10) + '0');
    num /= 10;
  }
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<itoa10>:
  endbr64
  movb   $0x0,D17(%rip)
  lea    D12(%rip),%r8
  movabs $0xcccccccccccccccd,%rsi
  lea    0x9(%r8),%rcx
L2:
  mov    %rdi,%rax
  mul    %rsi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rdi
  mov    %rcx,%rax
  sub    $0x1,%rcx
  add    $0x30,%edi
  mov    %dil,0x1(%rcx)
  mov    %rdx,%rdi
  cmp    %r8,%rax
  jne    L2
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa10(unsigned long num) {
  static char buf[12];
  int i;
  buf[10] = 0;
  for (i = 9; i >= 0; --i) {
    buf[i] = (char)((num % 10) + '0');
    num /= 10;
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<unlink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int unlink(const char *pathname) {
  _exit(-1);
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<unlink>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int unlink(const char *pathname) {
  _exit(-1);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<unlink>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int unlink(const char *pathname) {
  _exit(-1);
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unlink>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int unlink(const char *pathname) {
  _exit(-1);
  return -1;
}
```