ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: There should be no explciit rules in either direction for the execution of this binary

assistant: ```c
int main(int argc, char *argv[]) {
  printf("There should be no explciit rules in either direction for the execution "
         "of "
         "this binary");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type: string

tool: D1: There should be no explciit rules in either direction for the execution of this binary

assistant: ```c
int main(int argc, char *argv[]) {
  printf("There should be no explciit rules in either direction for the execution "
         "of "
         "this binary");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string

tool: D4: There should be no explciit rules in either direction for the execution of this binary

assistant: ```c
int main(int argc, char *argv[]) {
  printf("There should be no explciit rules in either direction for the execution "
         "of "
         "this binary");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D0: There should be no explciit rules in either direction for the execution of this binary

assistant: ```c
int main(int argc, char *argv[]) {
  printf("There should be no explciit rules in either direction for the execution "
         "of "
         "this binary");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_string_to_defined_output_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L58:
  cmp    %rdx,%rsp
  je     L53
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L58
L53:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L11
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L11:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L24
L49:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L24:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L49
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x9e,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int write_string_to_defined_output_file(int n, char *s) {
  int i, b[n], fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc(158, &n, b, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_string_to_defined_output_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L19:
  cmp    %rdx,%rsp
  je     L28
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L19
L28:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L54
  orq    $0x0,-0x8(%rsp,%rax,1)
L54:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L13
  mov    %ecx,%ecx
  mov    $0x0,%eax
L32:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L32
L13:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x9e,%edi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  leave
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_string_to_defined_output_file(int n, char *s) {
  int i, b[n], fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc(158, &n, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<write_string_to_defined_output_file>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rdx
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsp,%r8
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rcx,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L5
L52:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L52
L5:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L56
L25:
  mov    %rsp,%r9
  test   %edx,%edx
  jle    L44
  xor    %eax,%eax
L60:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L60
L44:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r9,%rdx
  mov    $0x9e,%edi
  lea    -0x14(%rbp),%rsi
  call   <_ada_use_c2phc@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L56:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L25
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_string_to_defined_output_file(int n, char *s) {
  int i, b[n], fail;
  double *c;
  for (i = 0; i < n; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc(158, &n, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fn24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0xf,%eax
  test   %rax,%rax
  je     L5
  mov    $0x0,%eax
  call   <fn23@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
__attribute__((noipa)) void fn24(char *p) {
  if ((((long unsigned int)p) & 15) != 0)
    fn23();
  asm("");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn24>:
  endbr64
  test   $0xf,%dil
  jne    L3
  ret
L3:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fn23@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((noipa)) void fn24(char *p) {
  if ((((long unsigned int)p) & 15) != 0)
    fn23();
  asm("");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fn24>:
  endbr64
  and    $0xf,%edi
  jne    L3
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn23@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((noipa)) void fn24(char *p) {
  if ((((long unsigned int)p) & 15) != 0)
    fn23();
  asm("");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fn24>:
  endbr64
  and    $0xf,%edi
  jne    L1
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fn23@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
__attribute__((noipa)) void fn24(char *p) {
  if ((((long unsigned int)p) & 15) != 0)
    fn23();
  asm("");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%edi
  call   <user_byte@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x6,-0x8(%rbp)
  jmp    L87
L72:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L56
  cmp    $0x2,%eax
  jg     L97
  test   %eax,%eax
  je     L74
  cmp    $0x1,%eax
  je     L93
  jmp    L97
L74:
  addl   $0x2,-0x14(%rbp)
  jmp    L96
L93:
  addl   $0x1,-0x14(%rbp)
  jmp    L96
L56:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    %eax,%edi
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L116
  mov    $0x1,%eax
  jmp    L32
L97:
  mov    $0x0,%eax
  jmp    L32
L116:
  nop
L96:
  subl   $0x2,-0x8(%rbp)
L87:
  cmpl   $0x0,-0x8(%rbp)
  jns    L72
  mov    $0x0,%eax
L32:
  leave
  ret
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0) {
        return true;
      }
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x1(%rdi),%r12d
  call   <user_byte@plt>
  mov    %eax,%ebp
  mov    $0x6,%ebx
  jmp    L73
L32:
  add    $0x2,%r12d
L62:
  sub    $0x2,%ebx
  cmp    $0xfffffffe,%ebx
  je     L25
L73:
  mov    %ebp,%eax
  mov    %ebx,%ecx
  sar    %cl,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L38
  cmp    $0x2,%eax
  je     L86
  test   %eax,%eax
  je     L32
  mov    $0x0,%eax
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  add    $0x1,%r12d
  jmp    L62
L86:
  lea    0x1(%r12),%r13d
  mov    %r12d,%edi
  call   <user_byte@plt>
  test   %eax,%eax
  je     L98
  mov    %r13d,%r12d
  jmp    L62
L25:
  mov    $0x0,%eax
  jmp    L17
L98:
  mov    $0x1,%eax
  jmp    L17
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0) {
        return true;
      }
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: What is the c source code of the assembly code below?

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %r13
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x8,%rsp
  call   <user_byte@plt>
  mov    %ebx,%ecx
  mov    %eax,%ebp
  mov    %ebp,%edx
  sar    %cl,%edx
  and    $0x3,%edx
  cmp    $0x1,%edx
  je     L72
L38:
  cmp    $0x2,%edx
  je     L77
  test   %edx,%edx
  je     L64
L60:
  xor    %eax,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  add    $0x2,%r12d
L45:
  sub    $0x2,%ebx
  cmp    $0xfffffffe,%ebx
  je     L60
  mov    %ebp,%edx
  mov    %ebx,%ecx
  sar    %cl,%edx
  and    $0x3,%edx
  cmp    $0x1,%edx
  jne    L38
L72:
  add    $0x1,%r12d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L77:
  mov    %r12d,%edi
  lea    0x1(%r12),%r13d
  call   <user_byte@plt>
  test   %eax,%eax
  je     L43
  mov    %r13d,%r12d
  jmp    L45
L43:
  mov    $0x1,%eax
  jmp    L11
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0) {
        return true;
      }
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<instruction_has_stack_argument>:
  endbr64
  push   %r12
  lea    0x1(%rdi),%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  call   <user_byte@plt>
  mov    %eax,%ebx
  sar    $0x6,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L193
  cmp    $0x2,%eax
  je     L118
  test   %eax,%eax
  je     L97
L120:
  xor    %eax,%eax
L187:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L97:
  add    $0x3,%ebp
L40:
  mov    %ebx,%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L24
L48:
  cmp    $0x2,%eax
  je     L39
  test   %eax,%eax
  jne    L120
  lea    0x2(%rbp),%r12d
L57:
  mov    %ebx,%eax
  sar    $0x2,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  je     L13
L104:
  cmp    $0x2,%eax
  je     L201
  test   %eax,%eax
  jne    L120
  lea    0x2(%r12),%ebp
L33:
  and    $0x3,%ebx
  cmp    $0x1,%ebx
  je     L120
  cmp    $0x2,%ebx
  jne    L120
  mov    %ebp,%edi
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L120
L214:
  mov    $0x1,%eax
  jmp    L187
  nopw   0x0(%rax,%rax,1)
L118:
  mov    %r12d,%edi
  add    $0x2,%ebp
  call   <user_byte@plt>
  test   %eax,%eax
  je     L214
  mov    %ebx,%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L48
L24:
  mov    %ebx,%eax
  lea    0x1(%rbp),%r12d
  sar    $0x2,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  jne    L104
L13:
  lea    0x1(%r12),%ebp
  jmp    L33
  nopl   0x0(%rax)
L193:
  add    $0x2,%ebp
  jmp    L40
L39:
  mov    %ebp,%edi
  lea    0x1(%rbp),%r12d
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L57
  jmp    L214
  nopl   (%rax)
L201:
  mov    %r12d,%edi
  lea    0x1(%r12),%ebp
  call   <user_byte@plt>
  test   %eax,%eax
  jne    L33
  jmp    L214
```

assistant: ```c
bool instruction_has_stack_argument(uint32_t addr) {
  uint32_t types = user_byte(addr++);
  for (int i = 6; i >= 0; i -= 2) {
    switch ((types >> i) & 0x03) {
    case 0:
      addr += 2;
      break;
    case 1:
      addr++;
      break;
    case 2:
      if (user_byte(addr++) == 0) {
        return true;
      }
      break;
    default:
      return false;
    }
  }
  return false;
}
```
user: What is the c source code of the assembly code below?

```asm
<cdflib_fpser>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    (%rdi),%r14
  movsd  D37(%rip),%xmm0
  mulsd  (%rcx),%xmm0
  movsd  D34(%rip),%xmm1
  movq   %r14,%xmm7
  comisd %xmm7,%xmm0
  jb     L28
L5:
  movsd  0x0(%rbp),%xmm0
  movsd  0x0(%r13),%xmm10
  divsd  %xmm0,%xmm10
  mulsd  %xmm1,%xmm10
  movsd  (%rbx),%xmm6
  divsd  %xmm0,%xmm6
  movapd %xmm0,%xmm2
  addsd  D34(%rip),%xmm2
  movsd  (%r12),%xmm5
  movapd %xmm5,%xmm4
  divsd  %xmm2,%xmm4
  movapd %xmm5,%xmm3
  movsd  D34(%rip),%xmm9
  movq   D49(%rip),%xmm8
L12:
  addsd  %xmm9,%xmm2
  mulsd  %xmm5,%xmm3
  movapd %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm4
  andpd  %xmm8,%xmm1
  comisd %xmm6,%xmm1
  ja     L12
  mulsd  %xmm4,%xmm0
  addsd  D34(%rip),%xmm0
  mulsd  %xmm10,%xmm0
L24:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  movsd  (%rdx),%xmm0
  call   <log@plt>
  movq   %r14,%xmm7
  mulsd  %xmm0,%xmm7
  movsd  %xmm7,0x8(%rsp)
  lea    D53(%rip),%rdi
  call   <cdflib_exparg@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm7
  comisd %xmm7,%xmm1
  ja     L24
  movapd %xmm7,%xmm0
  call   <exp@plt>
  movapd %xmm0,%xmm1
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_label: D37
type_infered: byte[8]
name: disassemble_data
arguments: data_label: D34
type_infered: f64
name: disassemble_data
arguments: data_label: D49
type_infered: qword
name: disassemble_data
arguments: data_label: D53
type_infered: string

tool: {"D37": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D34: 1

tool: D49: 9223372036854775807

tool: D53: 

assistant: ```c
double cdflib_fpser(double *a, double *b, double *x, double *eps) {
  static const int K1 = 1;
  double fpser, an, c, s, t, tol;
  fpser = 1.0e0;
  if (*a <= 1.e-3 * *eps) {
    goto S10;
  }
  fpser = 0.0e0;
  t = *a * log(*x);
  if (t < cdflib_exparg(&K1)) {
    return fpser;
  }
  fpser = exp(t);
S10:
  fpser = *b / *a * fpser;
  tol = *eps / *a;
  an = *a + 1.0e0;
  t = *x;
  s = t / an;
S20:
  an += 1.0e0;
  t = *x * t;
  c = t / an;
  s += c;
  if (fabs(c) > tol) {
    goto S20;
  }
  fpser *= (1.0e0 + *a * s);
  return fpser;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cdflib_fpser>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  (%rcx),%xmm5
  movsd  D12(%rip),%xmm1
  movsd  (%rdi),%xmm8
  movsd  (%rdx),%xmm0
  mulsd  %xmm5,%xmm1
  comisd %xmm8,%xmm1
  jb     L10
  movsd  D37(%rip),%xmm6
  movapd %xmm6,%xmm1
L31:
  movsd  0x0(%r13),%xmm9
  movapd %xmm8,%xmm2
  movapd %xmm0,%xmm4
  movq   D20(%rip),%xmm7
  addsd  %xmm6,%xmm2
  divsd  %xmm8,%xmm5
  movapd %xmm0,%xmm3
  divsd  %xmm8,%xmm9
  divsd  %xmm2,%xmm4
  mulsd  %xmm1,%xmm9
  nop
L13:
  mulsd  %xmm0,%xmm3
  addsd  %xmm6,%xmm2
  movapd %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm4
  andpd  %xmm7,%xmm1
  comisd %xmm5,%xmm1
  ja     L13
  mulsd  %xmm8,%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm9,%xmm0
L24:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  movsd  %xmm8,0x8(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm8
  lea    D31(%rip),%rdi
  mulsd  %xmm0,%xmm8
  movsd  %xmm8,0x8(%rsp)
  call   <cdflib_exparg@plt>
  movsd  0x8(%rsp),%xmm8
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm8,%xmm2
  ja     L24
  movapd %xmm8,%xmm0
  call   <exp@plt>
  movsd  (%r12),%xmm8
  movsd  0x0(%rbp),%xmm5
  movapd %xmm0,%xmm1
  movsd  D37(%rip),%xmm6
  movsd  (%rbx),%xmm0
  jmp    L31
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: byte[8]
name: unpack_data
arguments: data_label: D37
type_infered: f64
name: unpack_data
arguments: data_label: D20
type_infered: qword
name: unpack_data
arguments: data_label: D31
type_infered: string

tool: {"D12": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D37: 1

tool: D20: 9223372036854775807

tool: D31: 

assistant: ```c
double cdflib_fpser(double *a, double *b, double *x, double *eps) {
  static const int K1 = 1;
  double fpser, an, c, s, t, tol;
  fpser = 1.0e0;
  if (*a <= 1.e-3 * *eps) {
    goto S10;
  }
  fpser = 0.0e0;
  t = *a * log(*x);
  if (t < cdflib_exparg(&K1)) {
    return fpser;
  }
  fpser = exp(t);
S10:
  fpser = *b / *a * fpser;
  tol = *eps / *a;
  an = *a + 1.0e0;
  t = *x;
  s = t / an;
S20:
  an += 1.0e0;
  t = *x * t;
  c = t / an;
  s += c;
  if (fabs(c) > tol) {
    goto S20;
  }
  fpser *= (1.0e0 + *a * s);
  return fpser;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cdflib_fpser>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  (%rcx),%xmm5
  movsd  D27(%rip),%xmm1
  movsd  (%rdi),%xmm8
  movsd  (%rdx),%xmm0
  mulsd  %xmm5,%xmm1
  comisd %xmm8,%xmm1
  jb     L2
  movsd  D45(%rip),%xmm6
  movapd %xmm6,%xmm1
L0:
  movsd  0x0(%r13),%xmm9
  movapd %xmm8,%xmm2
  movapd %xmm0,%xmm4
  movq   D22(%rip),%xmm7
  addsd  %xmm6,%xmm2
  divsd  %xmm8,%xmm5
  movapd %xmm0,%xmm3
  divsd  %xmm8,%xmm9
  divsd  %xmm2,%xmm4
  mulsd  %xmm1,%xmm9
  nop
L34:
  mulsd  %xmm0,%xmm3
  addsd  %xmm6,%xmm2
  movapd %xmm3,%xmm1
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm4
  andpd  %xmm7,%xmm1
  comisd %xmm5,%xmm1
  ja     L34
  mulsd  %xmm8,%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  mulsd  %xmm9,%xmm0
L36:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  movsd  %xmm8,0x8(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm8
  lea    D14(%rip),%rdi
  mulsd  %xmm0,%xmm8
  movsd  %xmm8,0x8(%rsp)
  call   <cdflib_exparg@plt>
  movsd  0x8(%rsp),%xmm8
  movapd %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  comisd %xmm8,%xmm2
  ja     L36
  movapd %xmm8,%xmm0
  call   <exp@plt>
  movsd  (%r12),%xmm8
  movsd  0x0(%rbp),%xmm5
  movapd %xmm0,%xmm1
  movsd  D45(%rip),%xmm6
  movsd  (%rbx),%xmm0
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_tag: D27
data_type: byte[8]
name: unpack_data
arguments: data_tag: D45
data_type: f64
name: unpack_data
arguments: data_tag: D22
data_type: qword
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: {"D27": [0xfc,0xa9,0xf1,0xd2,0x4d,0x62,0x50,0x3f]}

tool: D45: 1

tool: D22: 9223372036854775807

tool: D14: 

assistant: ```c
double cdflib_fpser(double *a, double *b, double *x, double *eps) {
  static const int K1 = 1;
  double fpser, an, c, s, t, tol;
  fpser = 1.0e0;
  if (*a <= 1.e-3 * *eps) {
    goto S10;
  }
  fpser = 0.0e0;
  t = *a * log(*x);
  if (t < cdflib_exparg(&K1)) {
    return fpser;
  }
  fpser = exp(t);
S10:
  fpser = *b / *a * fpser;
  tol = *eps / *a;
  an = *a + 1.0e0;
  t = *x;
  s = t / an;
S20:
  an += 1.0e0;
  t = *x * t;
  c = t / an;
  s += c;
  if (fabs(c) > tol) {
    goto S20;
  }
  fpser *= (1.0e0 + *a * s);
  return fpser;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bubbleSort3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L47
L42:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L28
L5:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L34
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L34:
  addl   $0x1,-0xc(%rbp)
L28:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L5
L47:
  cmpl   $0x0,-0x8(%rbp)
  jg     L42
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubbleSort3(int a[], int n) {
  int j, k;
  int flag;
  flag = n;
  while (flag > 0) {
    k = flag;
    flag = 0;
    for (j = 1; j < k; j++)
      if (a[j] < a[j - 1]) {
        swap(a[j], a[j - 1]);
        flag = j;
      }
  }
}
```