ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<qksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jge    L69
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L3
  mov    $0xffffffff,%eax
  jmp    L66
L3:
  mov    -0x30(%rbp),%r8
  mov    -0x4(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <qksort>
  test   %eax,%eax
  jns    L35
  mov    $0xffffffff,%eax
  jmp    L66
L35:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x30(%rbp),%r8
  mov    -0x28(%rbp),%edi
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <qksort>
  test   %eax,%eax
  jns    L69
  mov    $0xffffffff,%eax
  jmp    L66
L69:
  mov    $0x0,%eax
L66:
  leave
  ret
```

assistant: ```c
int qksort(void *data, int size, int esize, int i, int k, int (*compare)(const void *key1, const void *key2)) {
  int j;
  if (i < k) {
    if ((j = partition(data, esize, i, k, compare)) < 0)
      return -1;
    if (qksort(data, size, esize, i, j, compare) < 0)
      return -1;
    if (qksort(data, size, esize, j + 1, k, compare) < 0)
      return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<qksort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    $0x0,%eax
  cmp    %r8d,%ecx
  jl     L44
L52:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  mov    %rdi,%r12
  mov    %edx,%r13d
  mov    %ecx,%ebx
  mov    %r8d,%ebp
  mov    %r9,%r14
  mov    %r9,%r8
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r13d,%esi
  call   <partition@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  js     L11
  mov    %r14,%r9
  mov    %eax,%r8d
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    0xc(%rsp),%ebx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <qksort>
  test   %eax,%eax
  js     L40
  lea    0x1(%r15),%ecx
  mov    %r14,%r9
  mov    %ebp,%r8d
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <qksort>
  sar    $0x1f,%eax
  jmp    L52
L11:
  mov    $0xffffffff,%eax
  jmp    L52
L40:
  mov    $0xffffffff,%eax
  jmp    L52
```

assistant: ```c
int qksort(void *data, int size, int esize, int i, int k, int (*compare)(const void *key1, const void *key2)) {
  int j;
  if (i < k) {
    if ((j = partition(data, esize, i, k, compare)) < 0)
      return -1;
    if (qksort(data, size, esize, i, j, compare) < 0)
      return -1;
    if (qksort(data, size, esize, j + 1, k, compare) < 0)
      return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qksort>:
  endbr64
  xor    %eax,%eax
  cmp    %r8d,%ecx
  jl     L15
  ret
  nopl   0x0(%rax)
L15:
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r9,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %ecx,%r12d
  mov    %r13d,%esi
  push   %rbp
  mov    %r12d,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  mov    %r9,%r8
  mov    %ebx,%ecx
  sub    $0x18,%rsp
  call   <partition@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  js     L21
  mov    %r14,%r9
  mov    %r12d,%ecx
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  mov    %eax,0xc(%rsp)
  call   <qksort>
  test   %eax,%eax
  js     L21
  mov    0xc(%rsp),%r8d
  mov    %r14,%r9
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rbp,%rdi
  lea    0x1(%r8),%ecx
  mov    %ebx,%r8d
  call   <qksort>
  sar    $0x1f,%eax
L18:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L18
```

assistant: ```c
int qksort(void *data, int size, int esize, int i, int k, int (*compare)(const void *key1, const void *key2)) {
  int j;
  if (i < k) {
    if ((j = partition(data, esize, i, k, compare)) < 0)
      return -1;
    if (qksort(data, size, esize, i, j, compare) < 0)
      return -1;
    if (qksort(data, size, esize, j + 1, k, compare) < 0)
      return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<setReadInGcStratum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x190,%eax,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  shl    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  sub    $0x1f40,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x59,-0x14(%rbp)
  jle    L73
  cmpl   $0x5a,-0x14(%rbp)
  jne    L37
L73:
  mov    -0x14(%rbp),%eax
  imul   $0x384,%eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  neg    %eax
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x1948b0fd,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x3,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L37:
  cmpl   $0x5a,-0x14(%rbp)
  jle    L101
  cmpl   $0x95,-0x14(%rbp)
  jle    L12
  cmpl   $0x96,-0x14(%rbp)
  jne    L101
L12:
  mov    -0x14(%rbp),%eax
  imul   $0x7d,%eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  add    %eax,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  sub    $0x1ccf,%eax
  mov    %eax,-0x4(%rbp)
L101:
  cmpl   $0x96,-0x14(%rbp)
  jle    L22
  cmpl   $0xd1,-0x14(%rbp)
  jle    L53
  cmpl   $0xd2,-0x14(%rbp)
  jne    L22
L53:
  mov    -0x14(%rbp),%eax
  imul   $0x53,%eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  sub    $0x109a,%eax
  mov    %eax,-0x4(%rbp)
L22:
  cmpl   $0xd2,-0x14(%rbp)
  jle    L79
  cmpl   $0x12b,-0x14(%rbp)
  jle    L43
  cmpl   $0x12c,-0x14(%rbp)
  jne    L79
L43:
  mov    -0x14(%rbp),%eax
  imul   $0x17,%eax,%ecx
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  sub    $0x5aa,%eax
  mov    %eax,-0x4(%rbp)
L79:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int setReadInGcStratum(int a) {
  int result = 0;
  result = 400 * a / 3 - 4 * a * a / 9 - 8000;
  if (a < 90 || a == 90) {
    result = (900 * a - 5 * a * a) / 81;
  }
  if ((a > 90) && ((a < 150) || (a == 150))) {
    result = 125 * a - 2 * a * a / 5 - 7375;
  }
  if ((a > 150) && ((a < 210) || (a == 210))) {
    result = 83 * a - 5 * a * a / 18 - 4250;
  }
  if ((a > 210) && ((a < 300) || (a == 300))) {
    result = 23 * a - a * a / 18 - 1450;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setReadInGcStratum>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%ecx
  imul   %edi,%ecx
  cmp    $0x5a,%edi
  jg     L1
  imul   $0x384,%edi,%esi
  lea    (%rcx,%rcx,4),%eax
  sub    %eax,%esi
  movslq %esi,%rax
  imul   $0x1948b0fd,%rax,%rax
  sar    $0x23,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %edi,%r8d
L39:
  sub    $0xd3,%r8d
  cmp    $0x59,%r8d
  ja     L12
  imul   $0x17,%edx,%edx
  movslq %ecx,%rax
  imul   $0x38e38e39,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ecx
  sub    %eax,%ecx
  lea    -0x5aa(%rdx,%rcx,1),%eax
L12:
  ret
L1:
  mov    %edi,%r8d
  lea    -0x5b(%rdi),%eax
  cmp    $0x3b,%eax
  ja     L26
  add    %ecx,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%ecx
  sub    %eax,%ecx
  imul   $0x7d,%edi,%edx
  lea    -0x1ccf(%rcx,%rdx,1),%eax
  ret
L26:
  imul   $0x190,%edi,%esi
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    0x0(,%rcx,4),%esi
  movslq %esi,%rdi
  imul   $0x38e38e39,%rdi,%rdi
  sar    $0x21,%rdi
  sar    $0x1f,%esi
  sub    %edi,%esi
  lea    -0x1f40(%rax,%rsi,1),%eax
  lea    -0x97(%rdx),%esi
  cmp    $0x3b,%esi
  ja     L39
  lea    (%rcx,%rcx,4),%eax
  movslq %eax,%rcx
  imul   $0x38e38e39,%rcx,%rcx
  sar    $0x22,%rcx
  sar    $0x1f,%eax
  sub    %ecx,%eax
  imul   $0x53,%edx,%edx
  lea    -0x109a(%rax,%rdx,1),%eax
  ret
```

assistant: ```c
int setReadInGcStratum(int a) {
  int result = 0;
  result = 400 * a / 3 - 4 * a * a / 9 - 8000;
  if (a < 90 || a == 90) {
    result = (900 * a - 5 * a * a) / 81;
  }
  if ((a > 90) && ((a < 150) || (a == 150))) {
    result = 125 * a - 2 * a * a / 5 - 7375;
  }
  if ((a > 150) && ((a < 210) || (a == 210))) {
    result = 83 * a - 5 * a * a / 18 - 4250;
  }
  if ((a > 210) && ((a < 300) || (a == 300))) {
    result = 23 * a - a * a / 18 - 1450;
  }
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setReadInGcStratum>:
  endbr64
  mov    %edi,%esi
  mov    %edi,%ecx
  imul   %edi,%esi
  cmp    $0x5a,%edi
  jg     L11
  imul   $0x384,%edi,%edx
  lea    (%rsi,%rsi,4),%eax
  sub    %eax,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x1948b0fd,%rax,%rax
  sar    $0x23,%rax
  sub    %edx,%eax
L35:
  lea    -0x97(%rcx),%edx
  cmp    $0x3b,%edx
  ja     L41
  imul   $0x53,%ecx,%ecx
  lea    (%rsi,%rsi,4),%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %edx,%eax
  lea    -0x109a(%rax,%rcx,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  lea    -0x5b(%rdi),%eax
  cmp    $0x3b,%eax
  ja     L6
  add    %esi,%esi
  imul   $0x7d,%edi,%ecx
  movslq %esi,%rax
  sar    $0x1f,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %eax,%esi
  lea    -0x1ccf(%rsi,%rcx,1),%eax
  ret
L41:
  lea    -0xd3(%rcx),%edx
  cmp    $0x59,%edx
  ja     L44
  movslq %esi,%rax
  imul   $0x17,%ecx,%ecx
  sar    $0x1f,%esi
  imul   $0x38e38e39,%rax,%rax
  sar    $0x22,%rax
  sub    %eax,%esi
  lea    -0x5aa(%rcx,%rsi,1),%eax
L44:
  ret
L6:
  imul   $0x190,%edi,%eax
  mov    $0x3,%edi
  mov    $0xfffffff7,%r8d
  cltd
  idiv   %edi
  mov    %eax,%edi
  lea    0x0(,%rsi,4),%eax
  cltd
  idiv   %r8d
  lea    -0x1f40(%rdi,%rax,1),%eax
  jmp    L35
```

assistant: ```c
int setReadInGcStratum(int a) {
  int result = 0;
  result = 400 * a / 3 - 4 * a * a / 9 - 8000;
  if (a < 90 || a == 90) {
    result = (900 * a - 5 * a * a) / 81;
  }
  if ((a > 90) && ((a < 150) || (a == 150))) {
    result = 125 * a - 2 * a * a / 5 - 7375;
  }
  if ((a > 150) && ((a < 210) || (a == 210))) {
    result = 83 * a - 5 * a * a / 18 - 4250;
  }
  if ((a > 210) && ((a < 300) || (a == 300))) {
    result = 23 * a - a * a / 18 - 1450;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<setReadInGcStratum>:
  endbr64
  mov    %edi,%esi
  mov    %edi,%ecx
  imul   %edi,%esi
  cmp    $0x5a,%edi
  jg     L46
  imul   $0x384,%edi,%edx
  lea    (%rsi,%rsi,4),%eax
  sub    %eax,%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x1948b0fd,%rax,%rax
  sar    $0x23,%rax
  sub    %edx,%eax
L22:
  lea    -0x97(%rcx),%edx
  cmp    $0x3b,%edx
  ja     L41
  imul   $0x53,%ecx,%ecx
  lea    (%rsi,%rsi,4),%eax
  movslq %eax,%rdx
  sar    $0x1f,%eax
  imul   $0x38e38e39,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %edx,%eax
  lea    -0x109a(%rax,%rcx,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  lea    -0x5b(%rdi),%eax
  cmp    $0x3b,%eax
  ja     L10
  add    %esi,%esi
  imul   $0x7d,%edi,%ecx
  movslq %esi,%rax
  sar    $0x1f,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sub    %eax,%esi
  lea    -0x1ccf(%rsi,%rcx,1),%eax
  ret
L41:
  lea    -0xd3(%rcx),%edx
  cmp    $0x59,%edx
  ja     L5
  movslq %esi,%rax
  imul   $0x17,%ecx,%ecx
  sar    $0x1f,%esi
  imul   $0x38e38e39,%rax,%rax
  sar    $0x22,%rax
  sub    %eax,%esi
  lea    -0x5aa(%rcx,%rsi,1),%eax
L5:
  ret
L10:
  imul   $0x190,%edi,%eax
  mov    $0x3,%edi
  mov    $0xfffffff7,%r8d
  cltd
  idiv   %edi
  mov    %eax,%edi
  lea    0x0(,%rsi,4),%eax
  cltd
  idiv   %r8d
  lea    -0x1f40(%rdi,%rax,1),%eax
  jmp    L22
```

assistant: ```c
int setReadInGcStratum(int a) {
  int result = 0;
  result = 400 * a / 3 - 4 * a * a / 9 - 8000;
  if (a < 90 || a == 90) {
    result = (900 * a - 5 * a * a) / 81;
  }
  if ((a > 90) && ((a < 150) || (a == 150))) {
    result = 125 * a - 2 * a * a / 5 - 7375;
  }
  if ((a > 150) && ((a < 210) || (a == 210))) {
    result = 83 * a - 5 * a * a / 18 - 4250;
  }
  if ((a > 210) && ((a < 300) || (a == 300))) {
    result = 23 * a - a * a / 18 - 1450;
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_fltswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
_fltswap(i1, i2) double *i1, *i2;
{
  double i3;
  i3 = *i1;
  *i1 = *i2;
  *i2 = i3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_fltswap>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
_fltswap(i1, i2) double *i1, *i2;
{
  double i3;
  i3 = *i1;
  *i1 = *i2;
  *i2 = i3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_fltswap>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
_fltswap(i1, i2) double *i1, *i2;
{
  double i3;
  i3 = *i1;
  *i1 = *i2;
  *i2 = i3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_fltswap>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,(%rsi)
  ret
```

assistant: ```c
_fltswap(i1, i2) double *i1, *i2;
{
  double i3;
  i3 = *i1;
  *i1 = *i2;
  *i2 = i3;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_keydefs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gen_keydefs>:
  endbr64
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gen_keydefs>:
  endbr64
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_keydefs>:
  endbr64
  ret
```

assistant: ```c
void gen_keydefs(int mode) {
  char buf[16];
  char obuf[16];
  int i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Cvar_Reset_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L4
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <Com_Printf@plt>
  jmp    L5
L4:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edi
  call   <Cvar_Reset@plt>
L5:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Cvar_Reset_f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L12
  lea    D4(%rip),%rdi
  call   <Com_Printf@plt>
L0:
  add    $0x8,%rsp
  ret
L12:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  mov    %eax,%edi
  call   <Cvar_Reset@plt>
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Cvar_Reset_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L2
  lea    D0(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <Com_Printf@plt>
  nopl   0x0(%rax)
L2:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    10b0 <Cvar_Reset@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Cvar_Reset_f>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cmd_Argc@plt>
  cmp    $0x2,%eax
  je     L9
  lea    D3(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <Com_Printf@plt>
  nopl   0x0(%rax)
L9:
  mov    $0x1,%edi
  call   <Cmd_Argv@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    10b0 <Cvar_Reset@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
type: string

tool: D3: usage: reset <variable>


assistant: ```c
void Cvar_Reset_f(void) {
  if (Cmd_Argc() != 2) {
    Com_Printf("usage: reset <variable>\n");
    return;
  }
  Cvar_Reset(Cmd_Argv(1));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strycmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  sub    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jge    L75
  mov    $0x1,%eax
  jmp    L6
L75:
  mov    -0xc(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L80
L50:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L80:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L50
L7:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L65
  mov    $0x0,%eax
  jmp    L6
L65:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jae    L78
  mov    $0xffffffff,%eax
  jmp    L6
L78:
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int strycmp(const char *s1, const char *s2) {
  const char *s1e;
  int l;
  l = strchr(s2, 0) - s2;
  s1e = strchr(s1, 0);
  if (s1e - s1 < l)
    return 1;
  s1 = s1e - l;
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strycmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %r12d,%rdx
  mov    $0x1,%esi
  cmp    %rax,%rdx
  jg     L4
  sub    %rdx,%rax
  lea    (%rbx,%rax,1),%rsi
  movzbl (%rsi),%edx
  movzbl 0x0(%rbp),%ecx
  test   %dl,%dl
  je     L42
  cmp    %cl,%dl
  jne    L42
  mov    $0x1,%eax
L34:
  movzbl (%rsi,%rax,1),%edx
  movzbl 0x0(%rbp,%rax,1),%ecx
  add    $0x1,%rax
  test   %dl,%dl
  je     L42
  cmp    %cl,%dl
  je     L34
L42:
  mov    $0x0,%esi
  test   %cl,%cl
  je     L4
  cmp    %cl,%dl
  sbb    %esi,%esi
  or     $0x1,%esi
L4:
  mov    %esi,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strycmp(const char *s1, const char *s2) {
  const char *s1e;
  int l;
  l = strchr(s2, 0) - s2;
  s1e = strchr(s1, 0);
  if (s1e - s1 < l)
    return 1;
  s1 = s1e - l;
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strycmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  movslq %r12d,%rdx
  mov    $0x1,%r8d
  cmp    %rax,%rdx
  jg     L49
  sub    %rdx,%rax
  movzbl (%rbx),%ecx
  lea    0x0(%rbp,%rax,1),%rsi
  mov    $0x1,%eax
  movzbl (%rsi),%edx
  cmp    %cl,%dl
  je     L48
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L13:
  movzbl (%rsi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rbx,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L11
L48:
  test   %dl,%dl
  jne    L13
L11:
  xor    %r8d,%r8d
  test   %cl,%cl
  je     L49
  cmp    %cl,%dl
  sbb    %r8d,%r8d
  or     $0x1,%r8d
L49:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strycmp(const char *s1, const char *s2) {
  const char *s1e;
  int l;
  l = strchr(s2, 0) - s2;
  s1e = strchr(s1, 0);
  if (s1e - s1 < l)
    return 1;
  s1 = s1e - l;
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strycmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  movslq %r12d,%rdx
  mov    $0x1,%r8d
  cmp    %rax,%rdx
  jg     L46
  sub    %rdx,%rax
  movzbl (%rbx),%ecx
  lea    0x0(%rbp,%rax,1),%rsi
  mov    $0x1,%eax
  movzbl (%rsi),%edx
  cmp    %cl,%dl
  je     L48
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L6:
  movzbl (%rsi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rbx,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L7
L48:
  test   %dl,%dl
  jne    L6
L7:
  xor    %r8d,%r8d
  test   %cl,%cl
  je     L46
  cmp    %cl,%dl
  sbb    %r8d,%r8d
  or     $0x1,%r8d
L46:
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strycmp(const char *s1, const char *s2) {
  const char *s1e;
  int l;
  l = strchr(s2, 0) - s2;
  s1e = strchr(s1, 0);
  if (s1e - s1 < l)
    return 1;
  s1 = s1e - l;
  while (*s1 == *s2 && *s1 != 0) {
    s1++;
    s2++;
  }
  if (*s2 == 0)
    return 0;
  return *(unsigned char *)s1 < *(unsigned char *)s2 ? -1 : 1;
}
```