ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<liballoc_free>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <b_mem_release@plt>
  cmp    %eax,%ebx
  pop    %rbx
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int liballoc_free(void *mem, int n) {
  int freed = b_mem_release(mem, n);
  return freed != n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strings_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L18
  mov    $0x1,%eax
  jmp    L11
L18:
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int strings_equal(char *string1, char *string2) {
  if (!strcmp(string1, string2)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strings_equal>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int strings_equal(char *string1, char *string2) {
  if (!strcmp(string1, string2)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strings_equal>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int strings_equal(char *string1, char *string2) {
  if (!strcmp(string1, string2)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strings_equal>:
  endbr64
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int strings_equal(char *string1, char *string2) {
  if (!strcmp(string1, string2)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ggt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  jmp    L9
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L26
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  jmp    L9
L26:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L35
  nop
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ggt(unsigned int x, unsigned int y) {
  while (x != y) {
    if (x > y) {
      x = x - y;
    } else {
      y = y - x;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ggt>:
  endbr64
  cmp    %esi,%edi
  jne    L14
L8:
  ret
L30:
  sub    %edi,%esi
L18:
  cmp    %esi,%edi
  je     L8
L14:
  cmp    %esi,%edi
  jbe    L30
  sub    %esi,%edi
  jmp    L18
```

assistant: ```c
unsigned int ggt(unsigned int x, unsigned int y) {
  while (x != y) {
    if (x > y) {
      x = x - y;
    } else {
      y = y - x;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ggt>:
  endbr64
  cmp    %esi,%edi
  jne    L28
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L17:
  sub    %esi,%edi
  cmp    %edi,%esi
  je     L32
L28:
  cmp    %edi,%esi
  jb     L17
  sub    %edi,%esi
  cmp    %edi,%esi
  jne    L28
L32:
  ret
```

assistant: ```c
unsigned int ggt(unsigned int x, unsigned int y) {
  while (x != y) {
    if (x > y) {
      x = x - y;
    } else {
      y = y - x;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ggt>:
  endbr64
  cmp    %esi,%edi
  je     L13
  nopl   0x0(%rax,%rax,1)
L18:
  cmp    %esi,%edi
  jbe    L2
  sub    %esi,%edi
  cmp    %esi,%edi
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  sub    %edi,%esi
  cmp    %esi,%edi
  jne    L18
L13:
  ret
```

assistant: ```c
unsigned int ggt(unsigned int x, unsigned int y) {
  while (x != y) {
    if (x > y) {
      x = x - y;
    } else {
      y = y - x;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <__wrap_fork@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  __wrap_fork();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <__wrap_fork@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  __wrap_fork();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <__wrap_fork@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  __wrap_fork();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <__wrap_fork@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  srand(time(NULL));
  __wrap_fork();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x70(%rbp)
  je     L15
  mov    -0x70(%rbp),%rax
  movb   $0x0,(%rax)
L15:
  cmpq   $0x0,-0x78(%rbp)
  je     L88
  mov    -0x78(%rbp),%rax
  movb   $0x0,(%rax)
L88:
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x30(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x50(%rbp),%rcx
  lea    -0x30(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <getaddrinfo@plt>
  mov    %eax,-0x54(%rbp)
  cmpl   $0x0,-0x54(%rbp)
  je     L76
  mov    -0x54(%rbp),%eax
  jmp    L86
L76:
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  jmp    L12
L17:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x80,%eax
  je     L31
  cmp    $0x81,%eax
  jne    L57
  cmpq   $0x0,-0x70(%rbp)
  je     L66
  mov    -0x48(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x40(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x40(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x70(%rbp),%rdx
  mov    %eax,%edi
  call   <inet_ntop@plt>
  jmp    L66
L31:
  cmpq   $0x0,-0x78(%rbp)
  je     L118
  mov    -0x48(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x38(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x38(%rbp),%rsi
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x78(%rbp),%rdx
  mov    %eax,%edi
  call   <inet_ntop@plt>
  jmp    L118
L66:
  nop
  jmp    L57
L118:
  nop
L57:
  mov    -0x48(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x48(%rbp)
L12:
  cmpq   $0x0,-0x48(%rbp)
  jne    L17
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <freeaddrinfo@plt>
  mov    $0x0,%eax
L86:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int get_address(const char *hostname, char *ipv4, char *ipv6) {
  struct addrinfo *result, *res;
  struct addrinfo hints;
  int err;
  if (ipv4)
    *ipv4 = 0;
  if (ipv6)
    *ipv6 = 0;
  memset(&hints, 0, sizeof(hints));
  hints.ai_family = AF_UNSPEC;
  hints.ai_socktype = SOCK_STREAM;
  err = getaddrinfo(hostname, NULL, &hints, &result);
  if (err)
    return err;
  for (res = result; res; res = res->ai_next)
    switch (res->ai_family) {
    case AF_INET:
      if (ipv4) {
        struct sockaddr_in *sin = (struct sockaddr_in *)res->ai_addr;
        inet_ntop(res->ai_family, &sin->sin_addr, ipv4, INET_ADDRSTRLEN);
      }
      break;
    case AF_INET6:
      if (ipv6) {
        struct sockaddr_in6 *sin6 = (struct sockaddr_in6 *)res->ai_addr;
        inet_ntop(res->ai_family, &sin6->sin6_addr, ipv6, INET6_ADDRSTRLEN);
      }
      break;
    }
  freeaddrinfo(result);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_address>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L35
  movb   $0x0,(%rsi)
L35:
  test   %r12,%r12
  je     L16
  movb   $0x0,(%r12)
L16:
  lea    0x10(%rsp),%r13
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    D38(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x28(%rsp)
  lea    0x8(%rsp),%rcx
  mov    %r13,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <getaddrinfo@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jne    L102
  mov    0x8(%rsp),%rbx
  test   %rbx,%rbx
  jne    L21
L0:
  mov    0x8(%rsp),%rdi
  call   <freeaddrinfo@plt>
L102:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %r13d,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L100:
  test   %r12,%r12
  je     L54
  mov    0x8(%rbx),%rsi
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  mov    %r12,%rdx
  mov    $0x80,%edi
  call   <inet_ntop@plt>
L54:
  mov    0x10(%rbx),%rbx
  test   %rbx,%rbx
  je     L0
L21:
  mov    (%rbx),%eax
  cmp    $0x80,%eax
  je     L100
  cmp    $0x81,%eax
  jne    L54
  test   %rbp,%rbp
  je     L54
  mov    0x8(%rbx),%rsi
  mov    D27(%rip),%rax
  mov    (%rax),%ecx
  mov    %rbp,%rdx
  mov    $0x81,%edi
  call   <inet_ntop@plt>
  jmp    L54
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_address(const char *hostname, char *ipv4, char *ipv6) {
  struct addrinfo *result, *res;
  struct addrinfo hints;
  int err;
  if (ipv4)
    *ipv4 = 0;
  if (ipv6)
    *ipv6 = 0;
  memset(&hints, 0, sizeof(hints));
  hints.ai_family = AF_UNSPEC;
  hints.ai_socktype = SOCK_STREAM;
  err = getaddrinfo(hostname, NULL, &hints, &result);
  if (err)
    return err;
  for (res = result; res; res = res->ai_next)
    switch (res->ai_family) {
    case AF_INET:
      if (ipv4) {
        struct sockaddr_in *sin = (struct sockaddr_in *)res->ai_addr;
        inet_ntop(res->ai_family, &sin->sin_addr, ipv4, INET_ADDRSTRLEN);
      }
      break;
    case AF_INET6:
      if (ipv6) {
        struct sockaddr_in6 *sin6 = (struct sockaddr_in6 *)res->ai_addr;
        inet_ntop(res->ai_family, &sin6->sin6_addr, ipv6, INET6_ADDRSTRLEN);
      }
      break;
    }
  freeaddrinfo(result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_address>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L84
  movb   $0x0,(%rsi)
L84:
  test   %r12,%r12
  je     L75
  movb   $0x0,(%r12)
L75:
  lea    0x10(%rsp),%r13
  mov    $0x20,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %r13,%rdx
  lea    0x8(%rsp),%rcx
  xor    %esi,%esi
  mov    D4(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x28(%rsp)
  call   <getaddrinfo@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jne    L82
  mov    0x8(%rsp),%rbp
  test   %rbp,%rbp
  jne    L57
  jmp    L87
L93:
  cmp    $0x81,%eax
  jne    L85
  test   %rbx,%rbx
  je     L85
  mov    D31(%rip),%rax
  mov    0x8(%rbp),%rsi
  mov    %rbx,%rdx
  mov    $0x81,%edi
  mov    (%rax),%ecx
  call   <inet_ntop@plt>
  cs nopw 0x0(%rax,%rax,1)
L85:
  mov    0x10(%rbp),%rbp
  test   %rbp,%rbp
  je     L41
L57:
  mov    0x0(%rbp),%eax
  cmp    $0x80,%eax
  jne    L93
  test   %r12,%r12
  je     L85
  mov    D33(%rip),%rax
  mov    0x8(%rbp),%rsi
  mov    %r12,%rdx
  mov    $0x80,%edi
  mov    (%rax),%ecx
  call   <inet_ntop@plt>
  mov    0x10(%rbp),%rbp
  test   %rbp,%rbp
  jne    L57
  nopl   0x0(%rax,%rax,1)
L41:
  mov    0x8(%rsp),%rbp
L87:
  mov    %rbp,%rdi
  call   <freeaddrinfo@plt>
L82:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x48,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_address(const char *hostname, char *ipv4, char *ipv6) {
  struct addrinfo *result, *res;
  struct addrinfo hints;
  int err;
  if (ipv4)
    *ipv4 = 0;
  if (ipv6)
    *ipv6 = 0;
  memset(&hints, 0, sizeof(hints));
  hints.ai_family = AF_UNSPEC;
  hints.ai_socktype = SOCK_STREAM;
  err = getaddrinfo(hostname, NULL, &hints, &result);
  if (err)
    return err;
  for (res = result; res; res = res->ai_next)
    switch (res->ai_family) {
    case AF_INET:
      if (ipv4) {
        struct sockaddr_in *sin = (struct sockaddr_in *)res->ai_addr;
        inet_ntop(res->ai_family, &sin->sin_addr, ipv4, INET_ADDRSTRLEN);
      }
      break;
    case AF_INET6:
      if (ipv6) {
        struct sockaddr_in6 *sin6 = (struct sockaddr_in6 *)res->ai_addr;
        inet_ntop(res->ai_family, &sin6->sin6_addr, ipv6, INET6_ADDRSTRLEN);
      }
      break;
    }
  freeaddrinfo(result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<signal_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L1
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <_exit@plt>
L1:
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <_exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void signal_handler(int sig) {
  if (sig == SIGTERM)
    _exit(EXIT_SUCCESS);
  _exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<signal_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  cmp    %edi,(%rax)
  je     L8
L16:
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
L8:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <_exit@plt>
  jmp    L16
```

assistant: ```c
void signal_handler(int sig) {
  if (sig == SIGTERM)
    _exit(EXIT_SUCCESS);
  _exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<signal_handler>:
  endbr64
  mov    D13(%rip),%rax
  cmp    %edi,(%rax)
  je     L4
  mov    D27(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <_exit@plt>
  nopl   (%rax)
L4:
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <_exit@plt>
  mov    D27(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1050 <_exit@plt>
```

assistant: ```c
void signal_handler(int sig) {
  if (sig == SIGTERM)
    _exit(EXIT_SUCCESS);
  _exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<signal_handler>:
  endbr64
  mov    D33(%rip),%rax
  cmp    %edi,(%rax)
  je     L7
  mov    D32(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <_exit@plt>
  nopl   (%rax)
L7:
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <_exit@plt>
  mov    D32(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1050 <_exit@plt>
```

assistant: ```c
void signal_handler(int sig) {
  if (sig == SIGTERM)
    _exit(EXIT_SUCCESS);
  _exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_csv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  jmp    L54
L52:
  mov    -0x20(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L54
  addq   $0x1,-0x20(%rbp)
L54:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  je     L57
  cmpq   $0x0,-0x20(%rbp)
  jne    L52
L57:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbp)
  jmp    L39
L36:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x8(%rbp)
L39:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L61
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L36
L61:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *get_csv(char *obuff, const char *ibuff, unsigned nval) {
  size_t i;
  while (nval-- && ibuff) {
    ibuff = strchr(ibuff, ',');
    if (ibuff)
      ibuff++;
  }
  assert(ibuff);
  for (i = 0; ibuff[i] && ibuff[i] != ','; i++)
    obuff[i] = ibuff[i];
  obuff[i] = '\0';
  return (obuff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_csv>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  test   %rsi,%rsi
  je     L51
  lea    -0x1(%rdx),%ebp
  test   %edx,%edx
  jne    L89
  jmp    L51
L23:
  add    $0x1,%rbx
  lea    -0x1(%rbp),%eax
  test   %ebp,%ebp
  je     L51
  mov    %eax,%ebp
L89:
  mov    $0x2c,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L23
L51:
  mov    %rbx,%rdi
  call   <assert@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L33
  cmp    $0x2c,%al
  je     L33
  mov    $0x0,%edx
L9:
  mov    %al,(%r12,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%eax
  test   %al,%al
  je     L73
  cmp    $0x2c,%al
  jne    L9
L73:
  movb   $0x0,(%r12,%rdx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    $0x0,%edx
  jmp    L73
```

assistant: ```c
char *get_csv(char *obuff, const char *ibuff, unsigned nval) {
  size_t i;
  while (nval-- && ibuff) {
    ibuff = strchr(ibuff, ',');
    if (ibuff)
      ibuff++;
  }
  assert(ibuff);
  for (i = 0; ibuff[i] && ibuff[i] != ','; i++)
    obuff[i] = ibuff[i];
  obuff[i] = '\0';
  return (obuff);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_csv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  je     L44
  lea    -0x1(%rdx),%ebx
  test   %rsi,%rsi
  je     1080 <get_csv.cold>
  nopl   0x0(%rax)
L4:
  mov    $0x2c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     1080 <get_csv.cold>
  lea    0x1(%rax),%rdi
  sub    $0x1,%ebx
  jae    L4
L44:
  mov    %rdi,0x8(%rsp)
  call   <assert@plt>
  mov    0x8(%rsp),%rdi
  xor    %eax,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L24
  jmp    L9
  xchg   %ax,%ax
L15:
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L9
L24:
  cmp    $0x2c,%dl
  jne    L15
L9:
  movb   $0x0,(%r12,%rax,1)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *get_csv(char *obuff, const char *ibuff, unsigned nval) {
  size_t i;
  while (nval-- && ibuff) {
    ibuff = strchr(ibuff, ',');
    if (ibuff)
      ibuff++;
  }
  assert(ibuff);
  for (i = 0; ibuff[i] && ibuff[i] != ','; i++)
    obuff[i] = ibuff[i];
  obuff[i] = '\0';
  return (obuff);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_csv>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  je     L47
  lea    -0x1(%rdx),%ebx
  test   %rsi,%rsi
  je     1080 <get_csv.cold>
  nopl   0x0(%rax)
L43:
  mov    $0x2c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     1080 <get_csv.cold>
  lea    0x1(%rax),%rdi
  sub    $0x1,%ebx
  jae    L43
L47:
  mov    %rdi,0x8(%rsp)
  call   <assert@plt>
  mov    0x8(%rsp),%rdi
  xor    %eax,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L5
  jmp    L58
  xchg   %ax,%ax
L33:
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  je     L58
L5:
  cmp    $0x2c,%dl
  jne    L33
L58:
  movb   $0x0,(%r12,%rax,1)
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *get_csv(char *obuff, const char *ibuff, unsigned nval) {
  size_t i;
  while (nval-- && ibuff) {
    ibuff = strchr(ibuff, ',');
    if (ibuff)
      ibuff++;
  }
  assert(ibuff);
  for (i = 0; ibuff[i] && ibuff[i] != ','; i++)
    obuff[i] = ibuff[i];
  obuff[i] = '\0';
  return (obuff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_submask_testmaskc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L12
  cmpl   $0x20,-0x4(%rbp)
  jle    L13
L12:
  mov    $0x0,%eax
  jmp    L0
L13:
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int _submask_testmaskc(int maskc) {
  if (maskc <= 0 || maskc > 32) {
    return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_submask_testmaskc>:
  endbr64
  sub    $0x1,%edi
  cmp    $0x1f,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int _submask_testmaskc(int maskc) {
  if (maskc <= 0 || maskc > 32) {
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_submask_testmaskc>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x1f,%edi
  setbe  %al
  ret
```

assistant: ```c
int _submask_testmaskc(int maskc) {
  if (maskc <= 0 || maskc > 32) {
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_submask_testmaskc>:
  endbr64
  sub    $0x1,%edi
  xor    %eax,%eax
  cmp    $0x1f,%edi
  setbe  %al
  ret
```

assistant: ```c
int _submask_testmaskc(int maskc) {
  if (maskc <= 0 || maskc > 32) {
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void test4() {
  int i;
  short j;
  float *k = 1 ? &i : &j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test4>:
  endbr64
  ret
```

assistant: ```c
void test4() {
  int i;
  short j;
  float *k = 1 ? &i : &j;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test4>:
  endbr64
  ret
```

assistant: ```c
void test4() {
  int i;
  short j;
  float *k = 1 ? &i : &j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test4>:
  endbr64
  ret
```

assistant: ```c
void test4() {
  int i;
  short j;
  float *k = 1 ? &i : &j;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_popeye_log_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vsyslog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void _popeye_log_write(int level, const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vsyslog(level, fmt, args);
  va_end(args);
  return;
}
```