ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_tok>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  movslq %edi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %r13d,%r13d
  jle    L14
  mov    %eax,%ebp
  xor    %ebx,%ebx
  jmp    L8
  xchg   %ax,%ax
L2:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L14
L8:
  mov    (%r12,%rbx,8),%rdi
  mov    %ebx,%r14d
  call   <strlen@plt>
  cmp    %eax,%ebp
  jg     L2
  mov    (%r12,%rbx,8),%rdi
  mov    %ebp,%edx
  mov    %r15,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L2
L4:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L14:
  mov    $0xffffffff,%r14d
  jmp    L4
```

assistant: ```c
int find_tok(int argc, char **argv, char *to_find) {
  int len = strlen(to_find);
  for (int i = 0; i < argc; i++) {
    int ll = strlen(argv[i]);
    if (ll >= len) {
      if (strncmp(argv[i], to_find, len) == 0)
        return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_tok>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  push   %r13
  movslq %edi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %r13d,%r13d
  jle    L0
  mov    %eax,%ebp
  xor    %ebx,%ebx
  jmp    L11
  xchg   %ax,%ax
L48:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L0
L11:
  mov    (%r12,%rbx,8),%rdi
  mov    %ebx,%r14d
  call   <strlen@plt>
  cmp    %eax,%ebp
  jg     L48
  mov    (%r12,%rbx,8),%rdi
  mov    %ebp,%edx
  mov    %r15,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L48
L49:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L0:
  mov    $0xffffffff,%r14d
  jmp    L49
```

assistant: ```c
int find_tok(int argc, char **argv, char *to_find) {
  int len = strlen(to_find);
  for (int i = 0; i < argc; i++) {
    int ll = strlen(argv[i]);
    if (ll >= len) {
      if (strncmp(argv[i], to_find, len) == 0)
        return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x9e370001,%edx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x20,%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long hash_long(unsigned long val, unsigned int bits) {
  unsigned long hash = val;
  hash *= 0x9e370001UL;
  return hash >> (32 - bits);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hash_long>:
  endbr64
  mov    $0x9e370001,%eax
  imul   %rdi,%rax
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%rax
  ret
```

assistant: ```c
unsigned long hash_long(unsigned long val, unsigned int bits) {
  unsigned long hash = val;
  hash *= 0x9e370001UL;
  return hash >> (32 - bits);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash_long>:
  endbr64
  mov    $0x9e370001,%eax
  mov    $0x20,%ecx
  imul   %rdi,%rax
  sub    %esi,%ecx
  shr    %cl,%rax
  ret
```

assistant: ```c
unsigned long hash_long(unsigned long val, unsigned int bits) {
  unsigned long hash = val;
  hash *= 0x9e370001UL;
  return hash >> (32 - bits);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash_long>:
  endbr64
  mov    $0x9e370001,%eax
  mov    $0x20,%ecx
  imul   %rdi,%rax
  sub    %esi,%ecx
  shr    %cl,%rax
  ret
```

assistant: ```c
unsigned long hash_long(unsigned long val, unsigned int bits) {
  unsigned long hash = val;
  hash *= 0x9e370001UL;
  return hash >> (32 - bits);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<assemble_codepoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <get_hex_digit_value@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L26
  mov    $0x0,%eax
  jmp    L4
L26:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%esi
  mov    -0x10(%rbp),%edx
  mov    $0x3,%eax
  sub    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  lea    (%rsi,%rax,1),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
bool assemble_codepoint(const char *c, int n, int *id) {
  bool ok;
  int v;
  ok = get_hex_digit_value(*c, &v);
  if (!ok) {
    return false;
  }
  *id += v << (4 * (3 - n));
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<assemble_codepoint>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  movsbl (%rdi),%edi
  call   <get_hex_digit_value@plt>
  test   %eax,%eax
  je     L19
  mov    $0x3,%ecx
  sub    %ebp,%ecx
  shl    $0x2,%ecx
  mov    0x4(%rsp),%eax
  shl    %cl,%eax
  add    %eax,(%rbx)
  mov    $0x1,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool assemble_codepoint(const char *c, int n, int *id) {
  bool ok;
  int v;
  ok = get_hex_digit_value(*c, &v);
  if (!ok) {
    return false;
  }
  *id += v << (4 * (3 - n));
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<assemble_codepoint>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movsbl (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <get_hex_digit_value@plt>
  test   %eax,%eax
  je     L8
  mov    $0x3,%ecx
  mov    0x4(%rsp),%eax
  sub    %ebp,%ecx
  shl    $0x2,%ecx
  shl    %cl,%eax
  add    %eax,(%rbx)
  mov    $0x1,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool assemble_codepoint(const char *c, int n, int *id) {
  bool ok;
  int v;
  ok = get_hex_digit_value(*c, &v);
  if (!ok) {
    return false;
  }
  *id += v << (4 * (3 - n));
  return true;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<assemble_codepoint>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  movsbl (%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <get_hex_digit_value@plt>
  test   %eax,%eax
  je     L9
  mov    $0x3,%ecx
  mov    0x4(%rsp),%eax
  sub    %ebp,%ecx
  shl    $0x2,%ecx
  shl    %cl,%eax
  add    %eax,(%rbx)
  mov    $0x1,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool assemble_codepoint(const char *c, int n, int *id) {
  bool ok;
  int v;
  ok = get_hex_digit_value(*c, &v);
  if (!ok) {
    return false;
  }
  *id += v << (4 * (3 - n));
  return true;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copy_dobldobl_start_system_to_container>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xfd,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_dobldobl_start_system_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(253, a, b, c, 0);
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<copy_dobldobl_start_system_to_container>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xfd,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_dobldobl_start_system_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(253, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_dobldobl_start_system_to_container>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xfd,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_dobldobl_start_system_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(253, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_dobldobl_start_system_to_container>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xfd,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_dobldobl_start_system_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(253, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stringLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L10:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <loadCharacter@plt>
  test   %rax,%rax
  jne    L10
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int stringLength(int *s) {
  int i;
  i = 0;
  while (loadCharacter(s, i) != 0)
    i = i + 1;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stringLength>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L4
L18:
  add    $0x1,%ebx
L4:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <loadCharacter@plt>
  test   %rax,%rax
  jne    L18
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int stringLength(int *s) {
  int i;
  i = 0;
  while (loadCharacter(s, i) != 0)
    i = i + 1;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stringLength>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0x1,%r12d
L0:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <loadCharacter@plt>
  test   %rax,%rax
  jne    L10
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int stringLength(int *s) {
  int i;
  i = 0;
  while (loadCharacter(s, i) != 0)
    i = i + 1;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stringLength>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12d
L13:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <loadCharacter@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int stringLength(int *s) {
  int i;
  i = 0;
  while (loadCharacter(s, i) != 0)
    i = i + 1;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<modulo_unsigned_short_Good>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  movb   $0x7b,-0xd(%rbp,%rax,1)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void modulo_unsigned_short_Good(uint16_t i) {
  char arr[5];
  arr[i % 5] = 123;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<modulo_unsigned_short_Good>:
  endbr64
  ret
```

assistant: ```c
void modulo_unsigned_short_Good(uint16_t i) {
  char arr[5];
  arr[i % 5] = 123;
}
```
user: Translate the below assembly code into C programming language:

```asm
<modulo_unsigned_short_Good>:
  endbr64
  ret
```

assistant: ```c
void modulo_unsigned_short_Good(uint16_t i) {
  char arr[5];
  arr[i % 5] = 123;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<modulo_unsigned_short_Good>:
  endbr64
  ret
```

assistant: ```c
void modulo_unsigned_short_Good(uint16_t i) {
  char arr[5];
  arr[i % 5] = 123;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<M24_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D11: M24_f(const char *s) is not yet implemented!


tool: D6: %s


assistant: ```c
int M24_f(char *s) {
  debug("M24_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<M24_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D0: M24_f(const char *s) is not yet implemented!


tool: D6: %s


assistant: ```c
int M24_f(char *s) {
  debug("M24_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<M24_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D5(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string

tool: D5: M24_f(const char *s) is not yet implemented!


tool: D17: %s


assistant: ```c
int M24_f(char *s) {
  debug("M24_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<M24_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D14(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D4
type: string

tool: D14: M24_f(const char *s) is not yet implemented!


tool: D4: %s


assistant: ```c
int M24_f(char *s) {
  debug("M24_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <test_hmac_md5@plt>
  test   %rax,%rax
  je     L5
  movl   $0xffffffff,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int r = 0;
  if (test_hmac_md5())
    r = -1;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_hmac_md5@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int r = 0;
  if (test_hmac_md5())
    r = -1;
  return r;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_hmac_md5@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int r = 0;
  if (test_hmac_md5())
    r = -1;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_hmac_md5@plt>
  neg    %rax
  sbb    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int r = 0;
  if (test_hmac_md5())
    r = -1;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ml_factorise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x3,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movl   $0x4e,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movl   $0x1f,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movl   $0x1,(%rax)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ml_factorise(int n1, int *factors, int *exponent) {
  factors[0] = 3;
  exponent[0] = 1;
  factors[1] = 78;
  exponent[1] = 1;
  factors[2] = 31;
  exponent[2] = 1;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ml_factorise>:
  endbr64
  movl   $0x3,(%rsi)
  movl   $0x1,(%rdx)
  movl   $0x4e,0x4(%rsi)
  movl   $0x1,0x4(%rdx)
  movl   $0x1f,0x8(%rsi)
  movl   $0x1,0x8(%rdx)
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ml_factorise(int n1, int *factors, int *exponent) {
  factors[0] = 3;
  exponent[0] = 1;
  factors[1] = 78;
  exponent[1] = 1;
  factors[2] = 31;
  exponent[2] = 1;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ml_factorise>:
  endbr64
  movl   $0x3,(%rsi)
  mov    $0x1,%eax
  movl   $0x1,(%rdx)
  movl   $0x4e,0x4(%rsi)
  movl   $0x1,0x4(%rdx)
  movl   $0x1f,0x8(%rsi)
  movl   $0x1,0x8(%rdx)
  ret
```

assistant: ```c
int ml_factorise(int n1, int *factors, int *exponent) {
  factors[0] = 3;
  exponent[0] = 1;
  factors[1] = 78;
  exponent[1] = 1;
  factors[2] = 31;
  exponent[2] = 1;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ml_factorise>:
  endbr64
  movl   $0x3,(%rsi)
  mov    $0x1,%eax
  movl   $0x1,(%rdx)
  movl   $0x4e,0x4(%rsi)
  movl   $0x1,0x4(%rdx)
  movl   $0x1f,0x8(%rsi)
  movl   $0x1,0x8(%rdx)
  ret
```

assistant: ```c
int ml_factorise(int n1, int *factors, int *exponent) {
  factors[0] = 3;
  exponent[0] = 1;
  factors[1] = 78;
  exponent[1] = 1;
  factors[2] = 31;
  exponent[2] = 1;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L12:
  cmpq   $0x0,-0x18(%rbp)
  jne    L18
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  imul   $0x446f8657,%rax,%rax
  shr    $0x20,%rax
  mov    %rax,%rcx
  mov    %edx,%eax
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x6,%eax
  imul   $0x65,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval;
  for (hashval = 0; s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  return hashval % 101;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval;
  for (hashval = 0; s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  return hashval % 101;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval;
  for (hashval = 0; s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  return hashval % 101;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hash(char *s) {
  unsigned int hashval;
  for (hashval = 0; s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  return hashval % 101;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_181_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_181_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_181_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     $0xff,%al
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  and    %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_181_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_181_0_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     $0xff,%al
  or     %esi,%edx
  and    %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_181_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_181_0_0>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     $0xff,%al
  or     %esi,%edx
  and    %edx,%eax
  xor    $0xffffff00,%eax
  ret
```

assistant: ```c
unsigned xrop3_181_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = S | D;
  stk2 = T & stk3;
  stk1 = D ^ stk2;
  stk1 = ~stk1;
  return stk1;
}
```