ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<read_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%esi
  je     L78
  jg     L85
  cmp    $0x1,%esi
  je     L4
  cmp    $0x2,%esi
  jne    L15
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  movzwl (%rdi),%edi
  add    $0x18,%rsp
  jmp    10d0 <__data2host2@plt>
  nopl   (%rax)
L85:
  xor    %eax,%eax
  cmp    $0x8,%esi
  jne    L15
  mov    %rsp,%r8
  mov    %rdi,%rsi
  mov    $0x8,%edx
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%rdi
  call   <__data2host8@plt>
  cltq
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movzbl (%rdi),%eax
  jmp    L15
  nopl   (%rax)
L78:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    (%rdi),%edi
  add    $0x18,%rsp
  jmp    10b0 <__data2host4@plt>
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long long read_size(void *ptr, int size) {
  switch (size) {
  case 1:
    return *(unsigned char *)ptr;
  case 2:
    return __data2host2(*(unsigned short *)ptr);
  case 4:
    return __data2host4(*(unsigned int *)ptr);
  case 8:
    return ({
      unsigned long long __val;
      memcpy(&__val, (ptr), sizeof(unsigned long long));
      __data2host8(__val);
    });
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L22
L2:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L21
L42:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <imprimirResponsavelPeloFeedback@plt>
L21:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  jg     L42
L22:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  test   %eax,%eax
  jg     L2
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
type_infered: string

tool: D14: %d

assistant: ```c
int main(void) {
  int casos, quantidadeDeFeedbacks, feedback;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%d", &quantidadeDeFeedbacks);
    while (quantidadeDeFeedbacks-- > 0) {
      scanf("%d", &feedback);
      imprimirResponsavelPeloFeedback(feedback);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L0
  lea    D19(%rip),%rbx
L36:
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x10(%rsp)
  test   %eax,%eax
  jle    L22
L13:
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <imprimirResponsavelPeloFeedback@plt>
  mov    0x10(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x10(%rsp)
  test   %eax,%eax
  jg     L13
L22:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L36
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string

tool: D19: %d

assistant: ```c
int main(void) {
  int casos, quantidadeDeFeedbacks, feedback;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%d", &quantidadeDeFeedbacks);
    while (quantidadeDeFeedbacks-- > 0) {
      scanf("%d", &feedback);
      imprimirResponsavelPeloFeedback(feedback);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L42
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rbp
  nopl   0x0(%rax)
L1:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  jmp    L47
  nopl   (%rax)
L11:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <imprimirResponsavelPeloFeedback@plt>
L47:
  mov    0x10(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x10(%rsp)
  test   %eax,%eax
  jg     L11
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L1
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: %d

assistant: ```c
int main(void) {
  int casos, quantidadeDeFeedbacks, feedback;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%d", &quantidadeDeFeedbacks);
    while (quantidadeDeFeedbacks-- > 0) {
      scanf("%d", &feedback);
      imprimirResponsavelPeloFeedback(feedback);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L35
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rbp
  nopl   0x0(%rax)
L13:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  jmp    L49
  nopl   (%rax)
L47:
  mov    %rbx,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edi
  call   <imprimirResponsavelPeloFeedback@plt>
L49:
  mov    0x10(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x10(%rsp)
  test   %eax,%eax
  jg     L47
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L13
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: %d

assistant: ```c
int main(void) {
  int casos, quantidadeDeFeedbacks, feedback;
  scanf("%d", &casos);
  while (casos-- > 0) {
    scanf("%d", &quantidadeDeFeedbacks);
    while (quantidadeDeFeedbacks-- > 0) {
      scanf("%d", &feedback);
      imprimirResponsavelPeloFeedback(feedback);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,-0x34(%rbp)
  jmp    L6
L36:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L6:
  cmpl   $0x1770,-0x34(%rbp)
  jle    L36
  lea    D26(%rip),%rax
  mov    %rax,%rdx
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x38(%rbp)
  jmp    L47
L22:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L47:
  cmpl   $0x6,-0x38(%rbp)
  jle    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D26
datatype: string
name: read_data
arguments: label: D18
datatype: string
name: read_data
arguments: label: D9
datatype: string
name: read_data
arguments: label: D15
datatype: string

tool: D26: Frequency

tool: D18: Face

tool: D9: %s%17s


tool: D15: %4d%17d


assistant: ```c
int main(void) {
  int face;
  int roll;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s%17s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%4d%17d\n", face, frequency[face]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x1770,%ebx
L27:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L27
  lea    D36(%rip),%rdx
  lea    D6(%rip),%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D22(%rip),%rbp
L8:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x7,%rbx
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D36
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D18
datatype: string
name: disassemble_data
arguments: tag: D22
datatype: string

tool: D36: Frequency

tool: D6: Face

tool: D18: %s%17s


tool: D22: %4d%17d


assistant: ```c
int main(void) {
  int face;
  int roll;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s%17s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%4d%17d\n", face, frequency[face]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  mov    $0x1770,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L23
  lea    D12(%rip),%rdx
  lea    D19(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D8(%rip),%rdi
  mov    %rsp,%r12
  lea    D34(%rip),%rbp
  call   <printf@plt>
  nopl   0x0(%rax)
L13:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L13
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string
name: retrieve_data
arguments: data_tag: D34
data_type: string

tool: D12: Frequency

tool: D19: Face

tool: D8: %s%17s


tool: D34: %4d%17d


assistant: ```c
int main(void) {
  int face;
  int roll;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s%17s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%4d%17d\n", face, frequency[face]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  mov    $0x1770,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L4
  lea    D2(%rip),%rdx
  lea    D18(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D35(%rip),%rdi
  mov    %rsp,%r12
  lea    D7(%rip),%rbp
  call   <printf@plt>
  nopl   0x0(%rax)
L8:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L8
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string
name: read_data
arguments: data_label: D18
data_type: string
name: read_data
arguments: data_label: D35
data_type: string
name: read_data
arguments: data_label: D7
data_type: string

tool: D2: Frequency

tool: D18: Face

tool: D35: %s%17s


tool: D7: %4d%17d


assistant: ```c
int main(void) {
  int face;
  int roll;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s%17s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%4d%17d\n", face, frequency[face]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getBinomialCoefficient>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <getFactorial@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <getFactorial@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <getFactorial@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%eax
  cltd
  idiv   %ecx
  leave
  ret
```

assistant: ```c
int getBinomialCoefficient(int n, int k) {
  int nFact = getFactorial(n);
  int kFact = getFactorial(k);
  int n_kFact = getFactorial(n - k);
  return nFact / (kFact * n_kFact);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getBinomialCoefficient>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %esi,%r13d
  call   <getFactorial@plt>
  mov    %eax,%ebx
  mov    %r13d,%edi
  call   <getFactorial@plt>
  mov    %eax,%ebp
  mov    %r12d,%edi
  sub    %r13d,%edi
  call   <getFactorial@plt>
  mov    %ebp,%ecx
  imul   %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int getBinomialCoefficient(int n, int k) {
  int nFact = getFactorial(n);
  int kFact = getFactorial(k);
  int n_kFact = getFactorial(n - k);
  return nFact / (kFact * n_kFact);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getBinomialCoefficient>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getFactorial@plt>
  mov    %r13d,%edi
  mov    %eax,%ebx
  call   <getFactorial@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  sub    %r13d,%edi
  call   <getFactorial@plt>
  mov    %ebp,%ecx
  add    $0x8,%rsp
  imul   %eax,%ecx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  cltd
  pop    %r12
  pop    %r13
  idiv   %ecx
  ret
```

assistant: ```c
int getBinomialCoefficient(int n, int k) {
  int nFact = getFactorial(n);
  int kFact = getFactorial(k);
  int n_kFact = getFactorial(n - k);
  return nFact / (kFact * n_kFact);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getBinomialCoefficient>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <getFactorial@plt>
  mov    %r13d,%edi
  mov    %eax,%ebx
  call   <getFactorial@plt>
  mov    %r12d,%edi
  mov    %eax,%ebp
  sub    %r13d,%edi
  call   <getFactorial@plt>
  mov    %ebp,%ecx
  add    $0x8,%rsp
  imul   %eax,%ecx
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  cltd
  pop    %r12
  pop    %r13
  idiv   %ecx
  ret
```

assistant: ```c
int getBinomialCoefficient(int n, int k) {
  int nFact = getFactorial(n);
  int kFact = getFactorial(k);
  int n_kFact = getFactorial(n - k);
  return nFact / (kFact * n_kFact);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_sizeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0xffffffffffffffff,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L64
  mov    -0x30(%rbp),%rax
  jmp    L10
L64:
  mov    D13(%rip),%rax
  movq   $0x0,(%rax)
  lea    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L0
  mov    -0x30(%rbp),%rax
  jmp    L10
L0:
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L78
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  mov    -0x10(%rbp),%rax
  jmp    L10
L78:
  mov    -0x30(%rbp),%rax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
ssize_t get_sizeval(const char *envar, const ssize_t deflt) {
  char *str = NULL, *eptr = NULL;
  long lval = -1;
  assert(envar);
  if (NULL == (str = getenv(envar)))
    return deflt;
  errno = 0;
  lval = strtol(str, &eptr, 10);
  if (errno)
    return deflt;
  if (eptr && (0 == *eptr))
    return lval;
  return deflt;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_sizeval>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rdi
  mov    D7(%rip),%rbx
  movq   $0x0,(%rbx)
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  cmpq   $0x0,(%rbx)
  jne    L12
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L12
  cmpb   $0x0,(%rdx)
  cmove  %rax,%rbp
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %rbp,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t get_sizeval(const char *envar, const ssize_t deflt) {
  char *str = NULL, *eptr = NULL;
  long lval = -1;
  assert(envar);
  if (NULL == (str = getenv(envar)))
    return deflt;
  errno = 0;
  lval = strtol(str, &eptr, 10);
  if (errno)
    return deflt;
  if (eptr && (0 == *eptr))
    return lval;
  return deflt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_sizeval>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L29
  mov    D5(%rip),%rbp
  mov    %rax,%rdi
  mov    %rsp,%rsi
  mov    $0xa,%edx
  movq   $0x0,0x0(%rbp)
  call   <strtol@plt>
  cmpq   $0x0,0x0(%rbp)
  jne    L29
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L29
  cmpb   $0x0,(%rdx)
  je     L43
L29:
  mov    %rbx,%rax
L43:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t get_sizeval(const char *envar, const ssize_t deflt) {
  char *str = NULL, *eptr = NULL;
  long lval = -1;
  assert(envar);
  if (NULL == (str = getenv(envar)))
    return deflt;
  errno = 0;
  lval = strtol(str, &eptr, 10);
  if (errno)
    return deflt;
  if (eptr && (0 == *eptr))
    return lval;
  return deflt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_sizeval>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <getenv@plt>
  test   %rax,%rax
  je     L22
  mov    D1(%rip),%rbp
  mov    %rax,%rdi
  mov    %rsp,%rsi
  mov    $0xa,%edx
  movq   $0x0,0x0(%rbp)
  call   <strtol@plt>
  cmpq   $0x0,0x0(%rbp)
  jne    L22
  mov    (%rsp),%rdx
  test   %rdx,%rdx
  je     L22
  cmpb   $0x0,(%rdx)
  je     L15
L22:
  mov    %rbx,%rax
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t get_sizeval(const char *envar, const ssize_t deflt) {
  char *str = NULL, *eptr = NULL;
  long lval = -1;
  assert(envar);
  if (NULL == (str = getenv(envar)))
    return deflt;
  errno = 0;
  lval = strtol(str, &eptr, 10);
  if (errno)
    return deflt;
  if (eptr && (0 == *eptr))
    return lval;
  return deflt;
}
```