ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gettime>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  test   %eax,%eax
  js     L19
  mov    D33(%rip),%rsi
  mov    %rsi,%rdx
  add    (%rbx),%rdx
  mov    %rdx,(%rbx)
  mov    D12(%rip),%rcx
  cmp    %rcx,%rdx
  jge    L8
  mov    %rcx,%rdi
  sub    %rdx,%rdi
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdx,D38(%rip)
  mov    %rcx,(%rbx)
L8:
  mov    (%rbx),%rdx
  mov    %rdx,D38(%rip)
L19:
  pop    %rbx
  ret
```

assistant: ```c
int gettime(struct timeval *tv) {
  int rc;
  static time_t offset = 0, previous = 0;
  rc = gettimeofday(tv, NULL);
  if (rc < 0)
    return rc;
  tv->tv_sec += offset;
  if (previous > tv->tv_sec) {
    offset += previous - tv->tv_sec;
    tv->tv_sec = previous;
  }
  previous = tv->tv_sec;
  return rc;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gettime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  call   <gettimeofday@plt>
  test   %eax,%eax
  js     L6
  mov    (%rbx),%rdx
  mov    D2(%rip),%rsi
  mov    D11(%rip),%rcx
  add    %rsi,%rdx
  mov    %rdx,(%rbx)
  cmp    %rcx,%rdx
  jge    L11
  mov    %rcx,%rdi
  mov    %rcx,(%rbx)
  sub    %rdx,%rdi
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdx,D38(%rip)
  mov    %rcx,%rdx
L11:
  mov    %rdx,D38(%rip)
L6:
  pop    %rbx
  ret
```

assistant: ```c
int gettime(struct timeval *tv) {
  int rc;
  static time_t offset = 0, previous = 0;
  rc = gettimeofday(tv, NULL);
  if (rc < 0)
    return rc;
  tv->tv_sec += offset;
  if (previous > tv->tv_sec) {
    offset += previous - tv->tv_sec;
    tv->tv_sec = previous;
  }
  previous = tv->tv_sec;
  return rc;
}
```
user: What is the c source code of the assembly code below?

```asm
<gettime>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %rdi,%rbx
  call   <gettimeofday@plt>
  test   %eax,%eax
  js     L3
  mov    (%rbx),%rdx
  mov    D24(%rip),%rsi
  mov    D1(%rip),%rcx
  add    %rsi,%rdx
  mov    %rdx,(%rbx)
  cmp    %rcx,%rdx
  jge    L7
  mov    %rcx,%rdi
  mov    %rcx,(%rbx)
  sub    %rdx,%rdi
  lea    (%rdi,%rsi,1),%rdx
  mov    %rdx,D37(%rip)
  mov    %rcx,%rdx
L7:
  mov    %rdx,D37(%rip)
L3:
  pop    %rbx
  ret
```

assistant: ```c
int gettime(struct timeval *tv) {
  int rc;
  static time_t offset = 0, previous = 0;
  rc = gettimeofday(tv, NULL);
  if (rc < 0)
    return rc;
  tv->tv_sec += offset;
  if (previous > tv->tv_sec) {
    offset += previous - tv->tv_sec;
    tv->tv_sec = previous;
  }
  previous = tv->tv_sec;
  return rc;
}
```
user: What is the c source code of the assembly code below:

```asm
<square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x10(%rbp)
  jmp    L0
L31:
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x20(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x10(%rbp)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L31
  movl   $0x1,-0x10(%rbp)
  jmp    L66
L63:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L53
L56:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jg     L36
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
L36:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L53:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L56
  addl   $0x1,-0x10(%rbp)
L66:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L63
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: tot = %d


assistant: ```c
int square(int *A, int *S, int n) {
  int i, j, tot, best;
  tot = 0;
  best = A[1];
  S[0] = 0;
  for (i = 1; i <= n; i++)
    S[i] = S[i - 1] + A[i];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      if (S[j] - S[i - 1] >= best)
        best = S[j] - S[i - 1];
      tot++;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<square>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x4(%rdi),%ebx
  movl   $0x0,(%rsi)
  test   %edx,%edx
  jle    L42
  mov    %edx,%ebp
  lea    -0x1(%rdx),%r9d
  lea    0x1(%rdx),%r11d
  mov    $0x1,%eax
L45:
  mov    (%rdi,%rax,4),%edx
  add    -0x4(%rsi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %r11,%rax
  jne    L45
  lea    0x4(%rsi),%r8
  mov    $0x1,%edi
  mov    $0x0,%r12d
  mov    %r8,%r10
  jmp    L69
L51:
  mov    -0x4(%r8),%esi
  mov    %r9d,%eax
  add    %rdi,%rax
  lea    (%r10,%rax,4),%rcx
  mov    %r8,%rdx
L27:
  mov    (%rdx),%eax
  sub    %esi,%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L27
  lea    0x1(%r12,%r9,1),%r12d
L40:
  add    $0x1,%rdi
  sub    $0x1,%r9d
  add    $0x4,%r8
  cmp    %r11,%rdi
  je     L50
L69:
  cmp    %edi,%ebp
  jge    L51
  jmp    L40
L42:
  mov    $0x0,%r12d
L50:
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string

tool: D7: tot = %d


assistant: ```c
int square(int *A, int *S, int n) {
  int i, j, tot, best;
  tot = 0;
  best = A[1];
  S[0] = 0;
  for (i = 1; i <= n; i++)
    S[i] = S[i - 1] + A[i];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      if (S[j] - S[i - 1] >= best)
        best = S[j] - S[i - 1];
      tot++;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<square>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x4(%rdi),%r12d
  movl   $0x0,(%rsi)
  test   %edx,%edx
  jle    L41
  mov    %edx,%r11d
  lea    -0x1(%rdx),%r9d
  mov    %edx,%ecx
  mov    $0x1,%eax
  xor    %edx,%edx
  jmp    L32
  nopl   0x0(%rax)
L57:
  add    $0x1,%rax
L32:
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  cmp    %rcx,%rax
  jne    L57
  lea    0x4(%rsi),%r10
  lea    0x1(%r11),%ebx
  mov    $0x1,%edi
  xor    %ebp,%ebp
  mov    %r10,%r8
  nopl   0x0(%rax)
L47:
  cmp    %edi,%r11d
  jl     L28
  mov    %r9d,%eax
  mov    -0x4(%r8),%esi
  mov    %r8,%rdx
  add    %rdi,%rax
  lea    (%r10,%rax,4),%rcx
  xchg   %ax,%ax
L17:
  mov    (%rdx),%eax
  sub    %esi,%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L17
  lea    0x1(%rbp,%r9,1),%ebp
L28:
  add    $0x1,%rdi
  sub    $0x1,%r9d
  add    $0x4,%r8
  cmp    %rbx,%rdi
  jne    L47
L15:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  xor    %ebp,%ebp
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: tot = %d


assistant: ```c
int square(int *A, int *S, int n) {
  int i, j, tot, best;
  tot = 0;
  best = A[1];
  S[0] = 0;
  for (i = 1; i <= n; i++)
    S[i] = S[i - 1] + A[i];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      if (S[j] - S[i - 1] >= best)
        best = S[j] - S[i - 1];
      tot++;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<square>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x4(%rdi),%r12d
  movl   $0x0,(%rsi)
  test   %edx,%edx
  jle    L96
  lea    0x1(%rdx),%ecx
  mov    %edx,%r9d
  lea    -0x1(%rdx),%r8d
  mov    %rsi,%r11
  mov    %rcx,%rbx
  mov    $0x1,%eax
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L3:
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L3
  lea    0x4(%r11),%rdi
  xor    %ebp,%ebp
  mov    $0x1,%ecx
  mov    $0x1,%r13d
  nopl   0x0(%rax)
L18:
  lea    0x1(%r8),%esi
  cmp    %ecx,%r9d
  mov    -0x4(%rdi),%r10d
  cmovl  %r13d,%esi
  cmp    $0x2,%r8d
  jbe    L104
  cmp    %ecx,%r9d
  jl     L104
  mov    %esi,%eax
  movd   %r12d,%xmm4
  movd   %r10d,%xmm5
  shr    $0x2,%eax
  pshufd $0x0,%xmm4,%xmm2
  pshufd $0x0,%xmm5,%xmm3
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%rdx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L72:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  psubd  %xmm3,%xmm0
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L72
  movdqa %xmm2,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  movdqa %xmm1,%xmm0
  lea    (%rdx,%rcx,1),%eax
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movd   %xmm1,%r12d
  cmp    %esi,%edx
  je     L32
L60:
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    (%r11,%rdx,4),%edx
  sub    %r10d,%edx
  cmp    %edx,%r12d
  cmovl  %edx,%r12d
  lea    0x1(%rax),%edx
  cmp    %edx,%r9d
  jl     L32
  mov    0x4(%r11,%rsi,1),%edx
  sub    %r10d,%edx
  cmp    %edx,%r12d
  cmovl  %edx,%r12d
  add    $0x2,%eax
  cmp    %eax,%r9d
  jl     L32
  mov    0x8(%r11,%rsi,1),%eax
  sub    %r10d,%eax
  cmp    %eax,%r12d
  cmovl  %eax,%r12d
L32:
  add    $0x1,%ecx
  lea    0x1(%rbp,%r8,1),%ebp
  add    $0x4,%rdi
  sub    $0x1,%r8d
  cmp    %ebx,%ecx
  jne    L18
L92:
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L104:
  mov    %ecx,%eax
  jmp    L60
L96:
  xor    %ebp,%ebp
  jmp    L92
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string

tool: D2: tot = %d


assistant: ```c
int square(int *A, int *S, int n) {
  int i, j, tot, best;
  tot = 0;
  best = A[1];
  S[0] = 0;
  for (i = 1; i <= n; i++)
    S[i] = S[i - 1] + A[i];
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      if (S[j] - S[i - 1] >= best)
        best = S[j] - S[i - 1];
      tot++;
    }
  printf("tot = %d\n", tot);
  return best;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x7,-0x4(%rbp)
  cmpl   $0x7,-0x4(%rbp)
  jle    L18
  movl   $0x2,-0x4(%rbp)
  jmp    L19
L18:
  movl   $0x3,-0x4(%rbp)
L19:
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = 7;
  if (a > 7)
    a = 2;
  else
    a = 3;
  return EXIT_SUCCESS;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = 7;
  if (a > 7)
    a = 2;
  else
    a = 3;
  return EXIT_SUCCESS;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = 7;
  if (a > 7)
    a = 2;
  else
    a = 3;
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int a = 7;
  if (a > 7)
    a = 2;
  else
    a = 3;
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hd44780_is_busy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <hd44780_ll_instruction_read@plt>
  and    $0x80,%eax
  test   %eax,%eax
  je     L13
  mov    $0xffffffff,%eax
  jmp    L9
L13:
  mov    $0x0,%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int8_t hd44780_is_busy(void) {
  if (hd44780_ll_instruction_read() & 0x80) {
    return (-1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hd44780_is_busy>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <hd44780_ll_instruction_read@plt>
  shl    $0x18,%eax
  sar    $0x1f,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int8_t hd44780_is_busy(void) {
  if (hd44780_ll_instruction_read() & 0x80) {
    return (-1);
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hd44780_is_busy>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hd44780_ll_instruction_read@plt>
  add    $0x8,%rsp
  shl    $0x18,%eax
  sar    $0x1f,%eax
  ret
```

assistant: ```c
int8_t hd44780_is_busy(void) {
  if (hd44780_ll_instruction_read() & 0x80) {
    return (-1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hd44780_is_busy>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <hd44780_ll_instruction_read@plt>
  add    $0x8,%rsp
  shl    $0x18,%eax
  sar    $0x1f,%eax
  ret
```

assistant: ```c
int8_t hd44780_is_busy(void) {
  if (hd44780_ll_instruction_read() & 0x80) {
    return (-1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L50
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L25
L50:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L38
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L19:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L19
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L19
  mov    -0x18(%rbp),%rax
L38:
  leave
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  if (!str || strlen(str) < 1) {
    errno = EINVAL;
    return NULL;
  }
  p = str + strlen(str) - 1;
  while (*p == '\n' || *p == '\r')
    *p-- = 0;
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<chomp>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L38
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L38
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L2
  cmp    $0xd,%dl
  jne    L5
L2:
  sub    $0x1,%rax
  movb   $0x0,0x1(%rax)
  movzbl (%rax),%edx
  cmp    $0xa,%dl
  je     L2
  cmp    $0xd,%dl
  je     L2
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
L38:
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%ebx
  jmp    L5
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  if (!str || strlen(str) < 1) {
    errno = EINVAL;
    return NULL;
  }
  p = str + strlen(str) - 1;
  while (*p == '\n' || *p == '\r')
    *p-- = 0;
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<chomp>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L52
  cmp    $0xd,%al
  jne    L25
L52:
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  cmp    $0xa,%cl
  je     L52
  cmp    $0xd,%cl
  je     L52
L25:
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  if (!str || strlen(str) < 1) {
    errno = EINVAL;
    return NULL;
  }
  p = str + strlen(str) - 1;
  while (*p == '\n' || *p == '\r')
    *p-- = 0;
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chomp>:
  endbr64
  push   %rbx
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L11
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rdx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L18
  cmp    $0xd,%al
  jne    L58
L18:
  movzbl -0x1(%rdx),%ecx
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  cmp    $0xa,%cl
  je     L18
  cmp    $0xd,%cl
  je     L18
L58:
  mov    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  if (!str || strlen(str) < 1) {
    errno = EINVAL;
    return NULL;
  }
  p = str + strlen(str) - 1;
  while (*p == '\n' || *p == '\r')
    *p-- = 0;
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TclLooksLikeInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L91
L2:
  addq   $0x1,-0x8(%rbp)
L91:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L2
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L42
L30:
  addq   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L37
  mov    $0x0,%eax
  jmp    L43
L37:
  addq   $0x1,-0x8(%rbp)
  jmp    L115
L46:
  addq   $0x1,-0x8(%rbp)
L115:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L46
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L116
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x65,%al
  je     L116
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x45,%al
  je     L116
  mov    $0x1,%eax
  jmp    L43
L116:
  mov    $0x0,%eax
L43:
  leave
  ret
```

assistant: ```c
int TclLooksLikeInt(p)
char *p;
{
  while (isspace(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p == '+') || (*p == '-')) {
    p++;
  }
  if (!isdigit(((unsigned char)(*p)))) {
    return 0;
  }
  p++;
  while (isdigit(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p != '.') && (*p != 'e') && (*p != 'E')) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TclLooksLikeInt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  jmp    L8
L28:
  add    $0x1,%rbx
L8:
  movzbl (%rbx),%ebp
  movzbl %bpl,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L28
  sub    $0x2b,%ebp
  and    $0xfffffffd,%ebp
  cmp    $0x1,%bpl
  adc    $0x0,%rbx
  movzbl (%rbx),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L5
  lea    0x1(%rbx),%rdx
  movzbl 0x1(%rbx),%ecx
  movzbl %cl,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L21
L3:
  add    $0x1,%rdx
  movzbl (%rdx),%ecx
  movzbl %cl,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L3
L21:
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x45,%al
  setne  %dl
  cmp    $0x2e,%cl
  setne  %al
  movzbl %al,%eax
  and    %edx,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int TclLooksLikeInt(p)
char *p;
{
  while (isspace(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p == '+') || (*p == '-')) {
    p++;
  }
  if (!isdigit(((unsigned char)(*p)))) {
    return 0;
  }
  p++;
  while (isdigit(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p != '.') && (*p != 'e') && (*p != 'E')) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<TclLooksLikeInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L3
  nopl   (%rax)
L43:
  add    $0x1,%rbx
L3:
  movzbl (%rbx),%r12d
  mov    %r12d,%edi
  mov    %r12d,%ebp
  call   <isspace@plt>
  test   %eax,%eax
  jne    L43
  sub    $0x2b,%ebp
  and    $0xfd,%ebp
  jne    L46
  movzbl 0x1(%rbx),%r12d
  add    $0x1,%rbx
L46:
  sub    $0x30,%r12d
  cmp    $0x9,%r12d
  ja     L23
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rdx
  mov    %eax,%ecx
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L39
  nopw   0x0(%rax,%rax,1)
L30:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  mov    %eax,%ecx
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L30
L39:
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x45,%al
  setne  %dl
  xor    %eax,%eax
  cmp    $0x2e,%cl
  setne  %al
  and    %edx,%eax
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int TclLooksLikeInt(p)
char *p;
{
  while (isspace(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p == '+') || (*p == '-')) {
    p++;
  }
  if (!isdigit(((unsigned char)(*p)))) {
    return 0;
  }
  p++;
  while (isdigit(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p != '.') && (*p != 'e') && (*p != 'E')) {
    return 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<TclLooksLikeInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L3
  nopl   (%rax)
L56:
  add    $0x1,%rbx
L3:
  movzbl (%rbx),%r12d
  mov    %r12d,%edi
  mov    %r12d,%ebp
  call   <isspace@plt>
  test   %eax,%eax
  jne    L56
  sub    $0x2b,%ebp
  and    $0xfd,%ebp
  jne    L17
  movzbl 0x1(%rbx),%r12d
  add    $0x1,%rbx
L17:
  sub    $0x30,%r12d
  cmp    $0x9,%r12d
  ja     L34
  movzbl 0x1(%rbx),%eax
  lea    0x1(%rbx),%rdx
  mov    %eax,%ecx
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L41
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  mov    %eax,%ecx
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L39
L41:
  mov    %ecx,%eax
  and    $0xffffffdf,%eax
  cmp    $0x45,%al
  setne  %dl
  xor    %eax,%eax
  cmp    $0x2e,%cl
  setne  %al
  and    %edx,%eax
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int TclLooksLikeInt(p)
char *p;
{
  while (isspace(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p == '+') || (*p == '-')) {
    p++;
  }
  if (!isdigit(((unsigned char)(*p)))) {
    return 0;
  }
  p++;
  while (isdigit(((unsigned char)(*p)))) {
    p++;
  }
  if ((*p != '.') && (*p != 'e') && (*p != 'E')) {
    return 1;
  }
  return 0;
}
```