ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0xb,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    0x0,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    %esi,%edx
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %x,%x

assistant: ```c
int main() {
  int i[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}, *p = &i, *q, o;
  p = q;
  for (i[0], o = 0; o <= 10; o++, *(p + 1)) {
    printf("%x,%x", *p, *q);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0xb,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    0x0,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  mov    %esi,%edx
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: %x,%x

assistant: ```c
int main() {
  int i[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}, *p = &i, *q, o;
  p = q;
  for (i[0], o = 0; o <= 10; o++, *(p + 1)) {
    printf("%x,%x", *p, *q);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <parse_input@plt>
  test   %rax,%rax
  je     L8
  mov    $0x1,%eax
  jmp    L23
L8:
  mov    $0x0,%eax
  call   <process_img@plt>
  test   %rax,%rax
  jne    L28
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L28:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L11:
  mov    -0x4(%rbp),%eax
L23:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string

tool: D16: 
we done!


tool: D2: 
we failed


assistant: ```c
int main(int argc, char **argv) {
  int ret = 1;
  if (parse_input(argc, argv))
    return 1;
  if (0 == process_img()) {
    printf("\nwe done!\n");
    ret = 0;
  } else
    printf("\nwe failed\n");
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <parse_input@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L18
L10:
  add    $0x8,%rsp
  ret
L18:
  mov    $0x0,%eax
  call   <process_img@plt>
  test   %rax,%rax
  jne    L2
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L10
L2:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D1
type: string

tool: D3: 
we done!


tool: D1: 
we failed


assistant: ```c
int main(int argc, char **argv) {
  int ret = 1;
  if (parse_input(argc, argv))
    return 1;
  if (0 == process_img()) {
    printf("\nwe done!\n");
    ret = 0;
  } else
    printf("\nwe failed\n");
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  call   <parse_input@plt>
  test   %rax,%rax
  je     L12
L27:
  mov    %r12d,%eax
  pop    %r12
  ret
L12:
  call   <process_img@plt>
  test   %rax,%rax
  jne    L28
  lea    D5(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L27
L28:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D10
type_infered: string

tool: D5: 
we done!


tool: D10: 
we failed


assistant: ```c
int main(int argc, char **argv) {
  int ret = 1;
  if (parse_input(argc, argv))
    return 1;
  if (0 == process_img()) {
    printf("\nwe done!\n");
    ret = 0;
  } else
    printf("\nwe failed\n");
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  call   <parse_input@plt>
  test   %rax,%rax
  je     L3
L35:
  mov    %r12d,%eax
  pop    %r12
  ret
L3:
  call   <process_img@plt>
  test   %rax,%rax
  jne    L32
  lea    D5(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L35
L32:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: string
name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D5: 
we done!


tool: D2: 
we failed


assistant: ```c
int main(int argc, char **argv) {
  int ret = 1;
  if (parse_input(argc, argv))
    return 1;
  if (0 == process_img()) {
    printf("\nwe done!\n");
    ret = 0;
  } else
    printf("\nwe failed\n");
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L91
  mov    %rax,%rbp
  mov    %rax,%r12
  mov    $0x0,%ebx
  lea    D23(%rip),%r13
L124:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,0x4(%rsp)
  jg     L124
  cmpl   $0x0,0x4(%rsp)
  jle    L91
  mov    %rbp,%r13
  lea    -0x4(%rbp),%r12
  mov    $0xffffffffffffffff,%rbx
  lea    D6(%rip),%r14
  jmp    L42
L52:
  cmp    %edi,%edx
  jge    L55
L93:
  lea    -0x4(%r12),%rdi
  sub    $0x1,%ecx
  sub    %edx,%ecx
  shl    $0x2,%rcx
  sub    %rcx,%rdi
  mov    %r12,%rax
L121:
  mov    (%rax),%ecx
  mov    %ecx,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L121
L55:
  movslq %edx,%rdx
  mov    %esi,0x4(%rbp,%rdx,4)
  mov    (%r8),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  add    $0x4,%r13
  add    $0x4,%r12
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L15
L42:
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %ebx,%edi
  test   %ebx,%ebx
  js     L30
  mov    %r13,%r8
  mov    0x0(%r13),%esi
  mov    %r12,%rax
L80:
  cmp    (%rax),%esi
  jg     L52
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L80
  jmp    L93
L15:
  cmpl   $0x0,0x4(%rsp)
  jle    L91
  mov    $0x0,%ebx
  lea    D15(%rip),%r12
L82:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jg     L82
L91:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L122
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  mov    %r13,%r8
  mov    0x0(%r13),%esi
  jmp    L55
L122:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D6
datatype: string
name: unpack_data
arguments: label: D15
datatype: string

tool: D23: %d

tool: D6: %d


tool: D15: %d 

assistant: ```c
int main() {
  int n, c, i = -1, m, t = -1, z;
  int *a;
  scanf("%d", &n);
  a = (int *)malloc(n * sizeof(int));
  for (int k = 0; k < n; k++) {
    scanf("%d", &a[k]);
  }
  while (i < n - 1) {
    i++;
    for (t = i - 1; t >= 0; t--) {
      if (a[i] > a[t]) {
        break;
      }
    }
    m = a[i];
    z = t;
    for (int j = i - 1; j > t; j--) {
      a[j + 1] = a[j];
    }
    a[z + 1] = m;
    printf("%d\n", a[i]);
  }
  for (int p = 0; p < n; p++) {
    printf("%d ", a[p]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L6
  mov    %rax,%r12
  mov    %rax,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jg     L23
  test   %eax,%eax
  jle    L6
  mov    %r12,%r14
  mov    $0xffffffffffffffff,%rbp
  lea    D18(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%r14),%ebx
  mov    %ebp,%ecx
  mov    %ebp,%esi
  mov    %ebp,%edi
  cmp    $0xffffffff,%ebp
  je     L73
  lea    -0x4(%r14),%rdx
  mov    %ebp,%eax
  jmp    L130
  nopw   0x0(%rax,%rax,1)
L119:
  sub    $0x1,%eax
  sub    $0x4,%rdx
  cmp    $0xffffffff,%eax
  je     L79
L130:
  cmp    %ebx,(%rdx)
  jge    L119
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%r15
  cmp    %eax,%edi
  jle    L66
L104:
  sub    %eax,%ecx
  xor    %r8d,%r8d
  lea    -0x1(%rcx),%edi
  lea    0x0(,%rbp,4),%rcx
  mov    %rdi,%rdx
  neg    %rdx
  shl    $0x2,%rdx
  cmp    %esi,%eax
  mov    $0x4,%eax
  cmovge %r8,%rdx
  lea    0x4(,%rdi,4),%r8
  cmovge %rax,%r8
  lea    (%rdx,%rcx,1),%rsi
  lea    0x4(%rcx,%rdx,1),%rdi
  add    %r12,%rsi
  add    %r12,%rdi
  mov    %r8,%rdx
  call   <memmove@plt>
L66:
  mov    %ebx,(%r15)
  mov    (%r14),%esi
  mov    %r13,%rdi
  add    $0x1,%rbp
  add    $0x4,%r14
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %ebp,%edx
  jg     L18
  test   %eax,%eax
  jle    L6
  xor    %ebx,%ebx
  lea    D24(%rip),%rbp
  nopl   0x0(%rax)
L61:
  mov    (%r12),%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L61
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %r12,%r15
  jmp    L104
L73:
  mov    %r12,%r15
  jmp    L66
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string

tool: D6: %d

tool: D18: %d


tool: D24: %d 

assistant: ```c
int main() {
  int n, c, i = -1, m, t = -1, z;
  int *a;
  scanf("%d", &n);
  a = (int *)malloc(n * sizeof(int));
  for (int k = 0; k < n; k++) {
    scanf("%d", &a[k]);
  }
  while (i < n - 1) {
    i++;
    for (t = i - 1; t >= 0; t--) {
      if (a[i] > a[t]) {
        break;
      }
    }
    m = a[i];
    z = t;
    for (int j = i - 1; j > t; j--) {
      a[j + 1] = a[j];
    }
    a[z + 1] = m;
    printf("%d\n", a[i]);
  }
  for (int p = 0; p < n; p++) {
    printf("%d ", a[p]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L72
  mov    %eax,%edi
  mov    %rbx,%rcx
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L73
L138:
  lea    0x1(%rax),%r8d
  movslq %r8d,%r8
  lea    (%rbx,%r8,1),%r9
  movzbl (%r9),%esi
  cmp    $0x60,%sil
  jle    L11
  sub    $0x57,%esi
  mov    %sil,(%r9)
L51:
  lea    0x1(%rbx,%r8,1),%r8
  movzbl (%r8),%esi
  cmp    $0x60,%sil
  jle    L92
  sub    $0x57,%esi
  mov    %sil,(%r8)
L105:
  movzbl (%r9),%esi
  shl    $0x4,%esi
  add    (%r8),%sil
  mov    %sil,(%rcx)
  mov    %edx,%r8d
  add    $0x2,%eax
L48:
  add    $0x1,%eax
  add    $0x1,%edx
  add    $0x1,%rcx
  cmp    %eax,%edi
  jle    L71
L73:
  movslq %eax,%rsi
  movzbl (%rbx,%rsi,1),%esi
  cmp    $0x25,%sil
  je     L138
  mov    %edx,%r8d
  mov    %sil,(%rcx)
  jmp    L48
L11:
  cmp    $0x40,%sil
  jle    L32
  sub    $0x37,%esi
  mov    %sil,(%r9)
  jmp    L51
L32:
  cmp    $0x2f,%sil
  jle    L51
  sub    $0x30,%esi
  mov    %sil,(%r9)
  jmp    L51
L92:
  cmp    $0x40,%sil
  jle    L88
  sub    $0x37,%esi
  mov    %sil,(%r8)
  jmp    L105
L88:
  cmp    $0x2f,%sil
  jle    L105
  sub    $0x30,%esi
  mov    %sil,(%r8)
  jmp    L105
L72:
  mov    $0x0,%r8d
L71:
  movslq %r8d,%r8
  movb   $0x0,(%rbx,%r8,1)
  pop    %rbx
  ret
```

assistant: ```c
void decode(char *ch) {
  int n = 0;
  int i = 0;
  int j = 0;
  n = strlen(ch);
  for (i = 0; i < n; i++) {
    if (ch[i] == '%') {
      i++;
      if (ch[i] >= 'a')
        ch[i] = ch[i] - 'a' + 10;
      else if (ch[i] >= 'A')
        ch[i] = ch[i] - 'A' + 10;
      else if (ch[i] >= '0')
        ch[i] = ch[i] - '0';
      if (ch[i + 1] >= 'a')
        ch[i + 1] = ch[i + 1] - 'a' + 10;
      else if (ch[i + 1] >= 'A')
        ch[i + 1] = ch[i + 1] - 'A' + 10;
      else if (ch[i + 1] >= '0')
        ch[i + 1] = ch[i + 1] - '0';
      ch[j] = ch[i] * 16 + ch[i + 1];
      j++;
      i++;
    } else {
      ch[j++] = ch[i];
    }
  }
  ch[j] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L2
  mov    %eax,%edi
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L107
  nopl   0x0(%rax)
L57:
  add    $0x1,%eax
  mov    %dl,-0x1(%rbx,%rcx,1)
  add    $0x1,%rcx
  cmp    %eax,%edi
  jle    L66
L107:
  movslq %eax,%rdx
  movslq %ecx,%r8
  movzbl (%rbx,%rdx,1),%edx
  cmp    $0x25,%dl
  jne    L57
  lea    0x1(%rax),%esi
  movslq %esi,%rsi
  lea    (%rbx,%rsi,1),%r9
  movzbl (%r9),%edx
  cmp    $0x60,%dl
  jle    L13
  sub    $0x57,%edx
  mov    %dl,(%r9)
L123:
  lea    0x1(%rbx,%rsi,1),%rdx
  movzbl (%rdx),%esi
  cmp    $0x60,%sil
  jle    L71
L112:
  sub    $0x57,%esi
  mov    %sil,(%rdx)
L62:
  movzbl (%r9),%edx
  add    $0x2,%eax
  add    $0x1,%eax
  shl    $0x4,%edx
  add    %esi,%edx
  mov    %dl,-0x1(%rbx,%rcx,1)
  add    $0x1,%rcx
  cmp    %eax,%edi
  jg     L107
L66:
  add    %r8,%rbx
L2:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L13:
  cmp    $0x40,%dl
  jle    L141
  sub    $0x37,%edx
  mov    %dl,(%r9)
  lea    0x1(%rbx,%rsi,1),%rdx
  movzbl (%rdx),%esi
  cmp    $0x60,%sil
  jg     L112
L71:
  cmp    $0x40,%sil
  jle    L8
  sub    $0x37,%esi
  mov    %sil,(%rdx)
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L141:
  cmp    $0x2f,%dl
  jle    L123
  sub    $0x30,%edx
  mov    %dl,(%r9)
  jmp    L123
  nopl   (%rax)
L8:
  cmp    $0x2f,%sil
  jle    L62
  sub    $0x30,%esi
  mov    %sil,(%rdx)
  jmp    L62
```

assistant: ```c
void decode(char *ch) {
  int n = 0;
  int i = 0;
  int j = 0;
  n = strlen(ch);
  for (i = 0; i < n; i++) {
    if (ch[i] == '%') {
      i++;
      if (ch[i] >= 'a')
        ch[i] = ch[i] - 'a' + 10;
      else if (ch[i] >= 'A')
        ch[i] = ch[i] - 'A' + 10;
      else if (ch[i] >= '0')
        ch[i] = ch[i] - '0';
      if (ch[i + 1] >= 'a')
        ch[i + 1] = ch[i + 1] - 'a' + 10;
      else if (ch[i + 1] >= 'A')
        ch[i + 1] = ch[i + 1] - 'A' + 10;
      else if (ch[i + 1] >= '0')
        ch[i + 1] = ch[i + 1] - '0';
      ch[j] = ch[i] * 16 + ch[i + 1];
      j++;
      i++;
    } else {
      ch[j++] = ch[i];
    }
  }
  ch[j] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L119
  mov    $0x1,%esi
  xor    %ecx,%ecx
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%ecx
  mov    %dl,-0x1(%rbx,%rsi,1)
  add    $0x1,%rsi
  cmp    %ecx,%eax
  jle    L102
L28:
  movslq %ecx,%rdx
  movslq %esi,%r8
  movzbl (%rbx,%rdx,1),%edx
  cmp    $0x25,%dl
  jne    L46
  lea    0x1(%rcx),%edi
  movslq %edi,%rdi
  lea    (%rbx,%rdi,1),%r9
  movzbl (%r9),%edx
  cmp    $0x60,%dl
  jle    L115
  sub    $0x57,%edx
  mov    %dl,(%r9)
L131:
  lea    0x1(%rbx,%rdi,1),%r10
  movzbl (%r10),%edi
  cmp    $0x60,%dil
  jle    L145
L52:
  sub    $0x57,%edi
  mov    %dil,(%r10)
  movzbl (%r9),%edx
L93:
  shl    $0x4,%edx
  add    $0x2,%ecx
  add    %edi,%edx
  add    $0x1,%ecx
  mov    %dl,-0x1(%rbx,%rsi,1)
  add    $0x1,%rsi
  cmp    %ecx,%eax
  jg     L28
L102:
  add    %r8,%rbx
L119:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
  nop
L115:
  cmp    $0x40,%dl
  jle    L75
  sub    $0x37,%edx
  lea    0x1(%rbx,%rdi,1),%r10
  mov    %dl,(%r9)
  movzbl (%r10),%edi
  cmp    $0x60,%dil
  jg     L52
L145:
  cmp    $0x40,%dil
  jle    L12
  sub    $0x37,%edi
  mov    %dil,(%r10)
  movzbl (%r9),%edx
  jmp    L93
  nopl   0x0(%rax)
L75:
  cmp    $0x2f,%dl
  jle    L131
  sub    $0x30,%edx
  mov    %dl,(%r9)
  jmp    L131
  nopl   (%rax)
L12:
  cmp    $0x2f,%dil
  jle    L93
  sub    $0x30,%edi
  mov    %dil,(%r10)
  movzbl (%r9),%edx
  jmp    L93
```

assistant: ```c
void decode(char *ch) {
  int n = 0;
  int i = 0;
  int j = 0;
  n = strlen(ch);
  for (i = 0; i < n; i++) {
    if (ch[i] == '%') {
      i++;
      if (ch[i] >= 'a')
        ch[i] = ch[i] - 'a' + 10;
      else if (ch[i] >= 'A')
        ch[i] = ch[i] - 'A' + 10;
      else if (ch[i] >= '0')
        ch[i] = ch[i] - '0';
      if (ch[i + 1] >= 'a')
        ch[i + 1] = ch[i + 1] - 'a' + 10;
      else if (ch[i + 1] >= 'A')
        ch[i + 1] = ch[i + 1] - 'A' + 10;
      else if (ch[i + 1] >= '0')
        ch[i + 1] = ch[i + 1] - '0';
      ch[j] = ch[i] * 16 + ch[i + 1];
      j++;
      i++;
    } else {
      ch[j++] = ch[i];
    }
  }
  ch[j] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gf8mul_01001011>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm1
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm3
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm2
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm1
  pxor   %xmm3,%xmm4
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm0
  pxor   %xmm2,%xmm7
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm3
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm2
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm1
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gf8mul_01001011(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm3, %xmm4\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm0\n"
                       "\tpxor    %xmm2, %xmm7\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm3\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm2\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm1\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<gf8mul_01001011>:
  endbr64
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm1
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm3
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm2
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm1
  pxor   %xmm3,%xmm4
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm0
  pxor   %xmm2,%xmm7
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm3
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm2
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm1
  ret
```

assistant: ```c
void gf8mul_01001011(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm3, %xmm4\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm0\n"
                       "\tpxor    %xmm2, %xmm7\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm3\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm2\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm1\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gf8mul_01001011>:
  endbr64
  pxor   %xmm7,%xmm5
  pxor   %xmm7,%xmm4
  pxor   %xmm7,%xmm3
  pxor   %xmm7,%xmm1
  pxor   %xmm7,%xmm0
  pxor   %xmm6,%xmm7
  pxor   %xmm6,%xmm5
  pxor   %xmm6,%xmm3
  pxor   %xmm5,%xmm6
  pxor   %xmm5,%xmm4
  pxor   %xmm5,%xmm2
  pxor   %xmm4,%xmm5
  pxor   %xmm4,%xmm3
  pxor   %xmm4,%xmm1
  pxor   %xmm3,%xmm4
  pxor   %xmm3,%xmm2
  pxor   %xmm3,%xmm0
  pxor   %xmm2,%xmm7
  pxor   %xmm2,%xmm6
  pxor   %xmm2,%xmm5
  pxor   %xmm2,%xmm3
  pxor   %xmm2,%xmm1
  pxor   %xmm2,%xmm0
  pxor   %xmm1,%xmm7
  pxor   %xmm1,%xmm4
  pxor   %xmm1,%xmm2
  pxor   %xmm0,%xmm6
  pxor   %xmm0,%xmm3
  pxor   %xmm0,%xmm1
  ret
```

assistant: ```c
void gf8mul_01001011(void) {
  __asm__ __volatile__("\tpxor    %xmm7, %xmm5\n"
                       "\tpxor    %xmm7, %xmm4\n"
                       "\tpxor    %xmm7, %xmm3\n"
                       "\tpxor    %xmm7, %xmm1\n"
                       "\tpxor    %xmm7, %xmm0\n"
                       "\tpxor    %xmm6, %xmm7\n"
                       "\tpxor    %xmm6, %xmm5\n"
                       "\tpxor    %xmm6, %xmm3\n"
                       "\tpxor    %xmm5, %xmm6\n"
                       "\tpxor    %xmm5, %xmm4\n"
                       "\tpxor    %xmm5, %xmm2\n"
                       "\tpxor    %xmm4, %xmm5\n"
                       "\tpxor    %xmm4, %xmm3\n"
                       "\tpxor    %xmm4, %xmm1\n"
                       "\tpxor    %xmm3, %xmm4\n"
                       "\tpxor    %xmm3, %xmm2\n"
                       "\tpxor    %xmm3, %xmm0\n"
                       "\tpxor    %xmm2, %xmm7\n"
                       "\tpxor    %xmm2, %xmm6\n"
                       "\tpxor    %xmm2, %xmm5\n"
                       "\tpxor    %xmm2, %xmm3\n"
                       "\tpxor    %xmm2, %xmm1\n"
                       "\tpxor    %xmm2, %xmm0\n"
                       "\tpxor    %xmm1, %xmm7\n"
                       "\tpxor    %xmm1, %xmm4\n"
                       "\tpxor    %xmm1, %xmm2\n"
                       "\tpxor    %xmm0, %xmm6\n"
                       "\tpxor    %xmm0, %xmm3\n"
                       "\tpxor    %xmm0, %xmm1\n");
}
```