ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_addr_bytelist>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jle    L21
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse_uintptr_hex@plt>
  test   %rax,%rax
  jne    L49
L21:
  cmpl   $0x3,-0x14(%rbp)
  jle    L48
  mov    -0x14(%rbp),%eax
  lea    -0x3(%rax),%esi
  mov    -0x20(%rbp),%rax
  lea    0x18(%rax),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rdi
  call   <parse_byte_list@plt>
  test   %eax,%eax
  jne    L48
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L53
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  addl   $0x1,-0x4(%rbp)
L53:
  mov    -0x14(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L28
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  jmp    L75
L49:
  nop
  jmp    L75
L48:
  nop
L75:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type: string
name: parse_data
arguments: tag: D4
type: string

tool: D16: %02X 

tool: D4: 


assistant: ```c
int parse_addr_bytelist(int ac, const char **av, uintptr_t *addr, uint8_t *bytes) {
  int rc = -1;
  int i;
  if (ac >= 3) {
    if (parse_uintptr_hex(av[2], addr)) {
      goto cleanup;
    }
  }
  if (ac >= 4 && !parse_byte_list(av + 3, ac - 3, bytes)) {
    rc = 0;
    for (i = 0; i < (ac - 3); ++i) {
      debug("%02X ", bytes[i] & 0xFF);
    }
    debug("\n");
  }
cleanup:
  return rc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_addr_bytelist>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rcx,%r12
  cmp    $0x2,%edi
  jg     L75
L38:
  cmp    $0x3,%ebp
  jle    L0
  lea    -0x3(%rbp),%esi
  lea    0x18(%rbx),%rdi
  mov    %r12,%rdx
  call   <parse_byte_list@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jne    L35
  mov    %r12,%rbx
  lea    -0x4(%rbp),%eax
  lea    0x4(%r12,%rax,4),%r12
  lea    D12(%rip),%rbp
L72:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L72
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
L43:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L75:
  mov    0x10(%rsi),%rdi
  mov    %rdx,%rsi
  call   <parse_uintptr_hex@plt>
  test   %rax,%rax
  je     L38
  mov    $0xffffffff,%r13d
  jmp    L43
L0:
  mov    $0xffffffff,%r13d
  jmp    L43
L35:
  mov    $0xffffffff,%r13d
  jmp    L43
```

tool_calls: name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D6
type_guessed: string

tool: D12: %02X 

tool: D6: 


assistant: ```c
int parse_addr_bytelist(int ac, const char **av, uintptr_t *addr, uint8_t *bytes) {
  int rc = -1;
  int i;
  if (ac >= 3) {
    if (parse_uintptr_hex(av[2], addr)) {
      goto cleanup;
    }
  }
  if (ac >= 4 && !parse_byte_list(av + 3, ac - 3, bytes)) {
    rc = 0;
    for (i = 0; i < (ac - 3); ++i) {
      debug("%02X ", bytes[i] & 0xFF);
    }
    debug("\n");
  }
cleanup:
  return rc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_addr_bytelist>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jg     L20
L43:
  mov    $0xffffffff,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %edi,%ebp
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%r12
  call   <parse_uintptr_hex@plt>
  test   %rax,%rax
  jne    L43
  cmp    $0x3,%ebp
  jle    L43
  sub    $0x3,%ebp
  lea    0x18(%rbx),%rdi
  mov    %r12,%rdx
  mov    %ebp,%esi
  call   <parse_byte_list@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jne    L43
  xor    %ebx,%ebx
  lea    D7(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <debug@plt>
  cmp    %ebx,%ebp
  jg     L39
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string

tool: D7: %02X 

tool: D13: 


assistant: ```c
int parse_addr_bytelist(int ac, const char **av, uintptr_t *addr, uint8_t *bytes) {
  int rc = -1;
  int i;
  if (ac >= 3) {
    if (parse_uintptr_hex(av[2], addr)) {
      goto cleanup;
    }
  }
  if (ac >= 4 && !parse_byte_list(av + 3, ac - 3, bytes)) {
    rc = 0;
    for (i = 0; i < (ac - 3); ++i) {
      debug("%02X ", bytes[i] & 0xFF);
    }
    debug("\n");
  }
cleanup:
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_addr_bytelist>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x2,%edi
  jg     L41
L43:
  mov    $0xffffffff,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  mov    %edi,%ebp
  mov    0x10(%rsi),%rdi
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%r12
  call   <parse_uintptr_hex@plt>
  test   %rax,%rax
  jne    L43
  cmp    $0x3,%ebp
  jle    L43
  sub    $0x3,%ebp
  lea    0x18(%rbx),%rdi
  mov    %r12,%rdx
  mov    %ebp,%esi
  call   <parse_byte_list@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  jne    L43
  xor    %ebx,%ebx
  lea    D12(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <debug@plt>
  cmp    %ebx,%ebp
  jg     L40
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string
name: read_data
arguments: label: D1
type_guessed: string

tool: D12: %02X 

tool: D1: 


assistant: ```c
int parse_addr_bytelist(int ac, const char **av, uintptr_t *addr, uint8_t *bytes) {
  int rc = -1;
  int i;
  if (ac >= 3) {
    if (parse_uintptr_hex(av[2], addr)) {
      goto cleanup;
    }
  }
  if (ac >= 4 && !parse_byte_list(av + 3, ac - 3, bytes)) {
    rc = 0;
    for (i = 0; i < (ac - 3); ++i) {
      debug("%02X ", bytes[i] & 0xFF);
    }
    debug("\n");
  }
cleanup:
  return rc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CalcCRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xffffffff,%edi
  call   <CalcCRCBase@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0xffffffff,%eax
  xor    %rax,-0x8(%rbp)
  mov    $0xffffffff,%eax
  and    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long CalcCRC(const char *buffer, int length) {
  unsigned long k = CalcCRCBase(0xFFFFFFFF, buffer, length);
  k ^= 0xffffffff;
  k &= 0xffffffff;
  return k;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CalcCRC>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    $0xffffffff,%edi
  call   <CalcCRCBase@plt>
  not    %eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long CalcCRC(const char *buffer, int length) {
  unsigned long k = CalcCRCBase(0xFFFFFFFF, buffer, length);
  k ^= 0xffffffff;
  k &= 0xffffffff;
  return k;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CalcCRC>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    $0xffffffff,%edi
  call   <CalcCRCBase@plt>
  add    $0x8,%rsp
  not    %eax
  ret
```

assistant: ```c
unsigned long CalcCRC(const char *buffer, int length) {
  unsigned long k = CalcCRCBase(0xFFFFFFFF, buffer, length);
  k ^= 0xffffffff;
  k &= 0xffffffff;
  return k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CalcCRC>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    $0xffffffff,%edi
  call   <CalcCRCBase@plt>
  add    $0x8,%rsp
  not    %eax
  ret
```

assistant: ```c
unsigned long CalcCRC(const char *buffer, int length) {
  unsigned long k = CalcCRCBase(0xFFFFFFFF, buffer, length);
  k ^= 0xffffffff;
  k &= 0xffffffff;
  return k;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L2
L16:
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D25(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L2:
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  jne    L16
  movsd  -0x10(%rbp),%xmm0
  movsd  D9(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D25
type_guessed: f64
name: unpack_data
arguments: tag: D9
type_guessed: f64
name: unpack_data
arguments: tag: D29
type_guessed: string

tool: D7: %d

tool: D8: %lf %lf

tool: D25: 2

tool: D9: 1000

tool: D29: %.6f


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  double curr_t, curr_v, prev_t, prev_v, sum = 0.0;
  scanf("%lf %lf", &prev_t, &prev_v);
  while (--n) {
    scanf("%lf %lf", &curr_t, &curr_v);
    sum += (prev_v + curr_v) / 2.0 * (curr_t - prev_t);
    prev_t = curr_t;
    prev_v = curr_v;
  }
  printf("%.6f\n", sum / 1000.0);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  lea    0x30(%rsp),%rdx
  lea    0x28(%rsp),%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  je     L6
  pxor   %xmm5,%xmm5
  movsd  %xmm5,0x8(%rsp)
  lea    0x20(%rsp),%r12
  lea    0x18(%rsp),%rbp
  lea    D1(%rip),%rbx
L25:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  movapd %xmm1,%xmm0
  addsd  0x30(%rsp),%xmm0
  mulsd  D41(%rip),%xmm0
  movapd %xmm2,%xmm3
  subsd  0x28(%rsp),%xmm3
  mulsd  %xmm3,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm2,0x28(%rsp)
  movsd  %xmm1,0x30(%rsp)
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  jne    L25
L30:
  movsd  0x8(%rsp),%xmm0
  divsd  D25(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  pxor   %xmm6,%xmm6
  movsd  %xmm6,0x8(%rsp)
  jmp    L30
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D46
type: string
name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D41
type: f32[2]
name: disassemble_data
arguments: data_label: D25
type: f64
name: disassemble_data
arguments: data_label: D15
type: string

tool: D46: %d

tool: D1: %lf %lf

tool: {"D41": [0.0,1.75]}

tool: D25: 1000

tool: D15: %.6f


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  double curr_t, curr_v, prev_t, prev_v, sum = 0.0;
  scanf("%lf %lf", &prev_t, &prev_v);
  while (--n) {
    scanf("%lf %lf", &curr_t, &curr_v);
    sum += (prev_v + curr_v) / 2.0 * (curr_t - prev_t);
    prev_t = curr_t;
    prev_v = curr_v;
  }
  printf("%.6f\n", sum / 1000.0);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D6(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x30(%rsp),%rdx
  mov    %rbx,%rdi
  lea    0x28(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  pxor   %xmm0,%xmm0
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  je     L17
  lea    0x20(%rsp),%r12
  lea    0x18(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm2
  movsd  0x30(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  subl   $0x1,0x14(%rsp)
  addsd  %xmm2,%xmm1
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm2,0x30(%rsp)
  mulsd  D8(%rip),%xmm1
  movapd %xmm3,%xmm4
  subsd  0x28(%rsp),%xmm4
  movsd  %xmm3,0x28(%rsp)
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  jne    L8
L17:
  lea    D20(%rip),%rdi
  divsd  D0(%rip),%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: f32[2]
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D0
type_infered: f64

tool: D11: %d

tool: D6: %lf %lf

tool: {"D8": [0.0,1.75]}

tool: D20: %.6f


tool: D0: 1000

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  double curr_t, curr_v, prev_t, prev_v, sum = 0.0;
  scanf("%lf %lf", &prev_t, &prev_v);
  while (--n) {
    scanf("%lf %lf", &curr_t, &curr_v);
    sum += (prev_v + curr_v) / 2.0 * (curr_t - prev_t);
    prev_t = curr_t;
    prev_v = curr_v;
  }
  printf("%.6f\n", sum / 1000.0);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D36(%rip),%rdi
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  lea    0x30(%rsp),%rdx
  mov    %rbx,%rdi
  lea    0x28(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  pxor   %xmm0,%xmm0
  sub    $0x1,%eax
  mov    %eax,0x14(%rsp)
  je     L24
  lea    0x20(%rsp),%r12
  lea    0x18(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm2
  movsd  0x30(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm3
  subl   $0x1,0x14(%rsp)
  addsd  %xmm2,%xmm1
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm2,0x30(%rsp)
  mulsd  D33(%rip),%xmm1
  movapd %xmm3,%xmm4
  subsd  0x28(%rsp),%xmm4
  movsd  %xmm3,0x28(%rsp)
  mulsd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  jne    L9
L24:
  lea    D28(%rip),%rdi
  divsd  D10(%rip),%xmm0
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D36
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D33
data_type: f32[2]
name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D10
data_type: f64

tool: D36: %d

tool: D4: %lf %lf

tool: {"D33": [0.0,1.75]}

tool: D28: %.6f


tool: D10: 1000

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  double curr_t, curr_v, prev_t, prev_v, sum = 0.0;
  scanf("%lf %lf", &prev_t, &prev_v);
  while (--n) {
    scanf("%lf %lf", &curr_t, &curr_v);
    sum += (prev_v + curr_v) / 2.0 * (curr_t - prev_t);
    prev_t = curr_t;
    prev_v = curr_v;
  }
  printf("%.6f\n", sum / 1000.0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<returns_nonnull_warning_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void returns_nonnull_warning_tests() {
  if (returns_nonnull_whee() == (void *)0) {
  }
  if (returns_nonnull_whee() != (void *)0) {
  }
  if (returns_nonnull_whee()) {
  }
  if (!returns_nonnull_whee()) {
  }
  int and_again = !returns_nonnull_whee();
  and_again = !returns_nonnull_whee();
}
```
user: Translate the below assembly code into C programming language:

```asm
<returns_nonnull_warning_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  mov    $0x0,%eax
  call   <returns_nonnull_whee@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void returns_nonnull_warning_tests() {
  if (returns_nonnull_whee() == (void *)0) {
  }
  if (returns_nonnull_whee() != (void *)0) {
  }
  if (returns_nonnull_whee()) {
  }
  if (!returns_nonnull_whee()) {
  }
  int and_again = !returns_nonnull_whee();
  and_again = !returns_nonnull_whee();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<returns_nonnull_warning_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <returns_nonnull_whee@plt>
```

assistant: ```c
void returns_nonnull_warning_tests() {
  if (returns_nonnull_whee() == (void *)0) {
  }
  if (returns_nonnull_whee() != (void *)0) {
  }
  if (returns_nonnull_whee()) {
  }
  if (!returns_nonnull_whee()) {
  }
  int and_again = !returns_nonnull_whee();
  and_again = !returns_nonnull_whee();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<returns_nonnull_warning_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  call   <returns_nonnull_whee@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <returns_nonnull_whee@plt>
```

assistant: ```c
void returns_nonnull_warning_tests() {
  if (returns_nonnull_whee() == (void *)0) {
  }
  if (returns_nonnull_whee() != (void *)0) {
  }
  if (returns_nonnull_whee()) {
  }
  if (!returns_nonnull_whee()) {
  }
  int and_again = !returns_nonnull_whee();
  and_again = !returns_nonnull_whee();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rdigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L46
  mov    $0x0,%eax
  jmp    L40
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L4
  mov    $0x0,%eax
  jmp    L40
L4:
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
  mov    $0x1,%eax
L40:
  pop    %rbp
  ret
```

assistant: ```c
int rdigits(s)
char *s;
{
  if (!s)
    return (0);
  do {
    if (!isdigit(*s))
      return (0);
    s++;
  } while (*s);
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rdigits>:
  endbr64
  test   %rdi,%rdi
  je     L15
L14:
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L27
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L14
  mov    $0x1,%eax
  ret
L15:
  mov    $0x0,%eax
  ret
L27:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int rdigits(s)
char *s;
{
  if (!s)
    return (0);
  do {
    if (!isdigit(*s))
      return (0);
    s++;
  } while (*s);
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rdigits>:
  endbr64
  test   %rdi,%rdi
  je     L10
  movsbl (%rdi),%eax
  jmp    L31
  xchg   %ax,%ax
L29:
  movsbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L27
L31:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L29
L10:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int rdigits(s)
char *s;
{
  if (!s)
    return (0);
  do {
    if (!isdigit(*s))
      return (0);
    s++;
  } while (*s);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rdigits>:
  endbr64
  test   %rdi,%rdi
  jne    L17
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  je     L39
L17:
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L38
L26:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int rdigits(s)
char *s;
{
  if (!s)
    return (0);
  do {
    if (!isdigit(*s))
      return (0);
    s++;
  } while (*s);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fputs2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L8
L18:
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L18
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L24
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  jmp    L22
L24:
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int fputs2(char *s, FILE *iop) {
  int c;
  while (c = *s++)
    putc(c, iop);
  return ferror(iop) ? EOF : 0;
}
```