ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<adc_test2>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    $0x5,%ebx
  call   <gpio_a_analog@plt>
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <adc_set_chan@plt>
L10:
  mov    $0x28,%edi
  call   <read_avg@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <delay_ms@plt>
  sub    $0x1,%ebx
  jne    L10
  mov    $0x64,%edi
  mov    $0x5,%ebx
  lea    D4(%rip),%r12
  call   <read_avg@plt>
  mov    %eax,%ebp
L11:
  mov    $0x28,%edi
  call   <read_avg@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  imul   $0x4cb,%eax,%eax
  cltd
  idiv   %ebp
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <delay_ms@plt>
  sub    $0x1,%ebx
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string

tool: D12: LM385 voltage: %d


tool: D1:  ADC channel %d


tool: D4: LM385 voltage: %d %d


assistant: ```c
void adc_test2(void) {
  int i;
  int val;
  int val2;
  int save;
  gpio_a_analog(1);
  printf(" ADC channel %d\n", 1);
  adc_set_chan(1);
  for (i = 0; i < 5; i++) {
    val = read_avg(40);
    printf("LM385 voltage: %d\n", val);
    delay_ms(10);
  }
  save = read_avg(100);
  for (i = 0; i < 5; i++) {
    val = read_avg(40);
    val2 = val * 1227;
    val2 /= save;
    printf("LM385 voltage: %d %d\n", val, val2);
    delay_ms(10);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  jmp    L8
L45:
  mov    -0x7e4(%rbp),%eax
  cmp    -0x7e8(%rbp),%eax
  jle    L8
  mov    -0x7e4(%rbp),%eax
  mov    %eax,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L8:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getlinee@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L45
  cmpl   $0x0,-0x7e8(%rbp)
  jle    L19
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlinee(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    %rsp,%r12
L31:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlinee@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L41
  cmp    %ebx,%ebp
  jge    L31
  lea    0x3f0(%rsp),%rdi
  mov    %r12,%rsi
  call   <copy@plt>
  mov    %ebx,%ebp
  jmp    L31
L41:
  test   %ebp,%ebp
  jg     L58
L15:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  lea    0x3f0(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
data_type: string

tool: D7: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlinee(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r13
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L50:
  cmp    %ebx,%ebp
  jl     L41
L66:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlinee@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L50
  test   %ebp,%ebp
  jne    L33
L46:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L41:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <copy@plt>
  jmp    L66
L33:
  lea    0x3f0(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L46
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlinee(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r13
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L22:
  cmp    %ebx,%ebp
  jl     L31
L53:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlinee@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L22
  test   %ebp,%ebp
  jne    L7
L57:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <copy@plt>
  jmp    L53
L7:
  lea    0x3f0(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlinee(line, 1000)) > 0) {
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<path_last>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L23
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L23:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *path_last(const char *p) {
  const char *s;
  for (s = p; *s != 0; s += 1)
    if (*s == '/')
      p = ++s;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<path_last>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L42
  mov    %rdi,%rsi
  jmp    L44
L35:
  lea    0x1(%rdx),%rsi
  movzbl 0x1(%rdx),%ecx
  test   %cl,%cl
  je     L42
L44:
  mov    %rsi,%rdx
  cmp    $0x2f,%cl
  jne    L35
  lea    0x1(%rsi),%rax
  mov    %rax,%rdx
  jmp    L35
L42:
  ret
```

assistant: ```c
const char *path_last(const char *p) {
  const char *s;
  for (s = p; *s != 0; s += 1)
    if (*s == '/')
      p = ++s;
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<path_last>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L3
  mov    %rdi,%rsi
  nopl   0x0(%rax)
L0:
  mov    %rsi,%rdx
  cmp    $0x2f,%cl
  jne    L14
  lea    0x1(%rsi),%rax
  mov    %rax,%rdx
L14:
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rsi
  test   %cl,%cl
  jne    L0
L3:
  ret
```

assistant: ```c
const char *path_last(const char *p) {
  const char *s;
  for (s = p; *s != 0; s += 1)
    if (*s == '/')
      p = ++s;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<path_last>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%rax
  test   %cl,%cl
  je     L28
  mov    %rdi,%rsi
  nopl   0x0(%rax)
L9:
  mov    %rsi,%rdx
  cmp    $0x2f,%cl
  jne    L16
  lea    0x1(%rsi),%rax
  mov    %rax,%rdx
L16:
  movzbl 0x1(%rdx),%ecx
  lea    0x1(%rdx),%rsi
  test   %cl,%cl
  jne    L9
L28:
  ret
```

assistant: ```c
const char *path_last(const char *p) {
  const char *s;
  for (s = p; *s != 0; s += 1)
    if (*s == '/')
      p = ++s;
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_or_die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_or_die(void *ptr) {
  ;
  free(ptr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<free_or_die>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void free_or_die(void *ptr) {
  ;
  free(ptr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<free_or_die>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void free_or_die(void *ptr) {
  ;
  free(ptr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<free_or_die>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void free_or_die(void *ptr) {
  ;
  free(ptr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strcspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L61
L52:
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L19:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L12
  movl   $0x0,-0x14(%rbp)
L12:
  addl   $0x1,-0x10(%rbp)
L2:
  cmpl   $0x0,-0x14(%rbp)
  je     L72
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L19
L72:
  cmpl   $0x0,-0x14(%rbp)
  je     L39
  addq   $0x1,-0x8(%rbp)
L39:
  addq   $0x1,-0x28(%rbp)
L61:
  cmpl   $0x0,-0x14(%rbp)
  je     L75
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
L75:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  size_t l = 0;
  int a = 1;
  int i;
  int al = strlen(reject);
  while ((a) && (*s)) {
    for (i = 0; (a) && (i < al); i++) {
      if (*s == reject[i]) {
        a = 0;
      }
    }
    if (a) {
      l++;
    }
    s++;
  }
  return l;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcspn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  lea    -0x1(%rdi),%edx
  lea    0x1(%rbx,%rdx,1),%rsi
  jmp    L12
L23:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L18
L53:
  cmp    %cl,(%rdx)
  jne    L23
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  add    $0x1,%rax
L12:
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %cl,%cl
  je     L13
  mov    %rbx,%rdx
  test   %edi,%edi
  jg     L53
  jmp    L18
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  size_t l = 0;
  int a = 1;
  int i;
  int al = strlen(reject);
  while ((a) && (*s)) {
    for (i = 0; (a) && (i < al); i++) {
      if (*s == reject[i]) {
        a = 0;
      }
    }
    if (a) {
      l++;
    }
    s++;
  }
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcspn>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%esi
  xor    %eax,%eax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rbx,%rdx,1),%rdi
  nopl   0x0(%rax)
L25:
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %cl,%cl
  je     L31
  mov    %rbx,%rdx
  test   %esi,%esi
  jg     L11
  jmp    L55
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L55
L11:
  cmp    %cl,(%rdx)
  jne    L34
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L55:
  add    $0x1,%rax
  jmp    L25
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  size_t l = 0;
  int a = 1;
  int i;
  int al = strlen(reject);
  while ((a) && (*s)) {
    for (i = 0; (a) && (i < al); i++) {
      if (*s == reject[i]) {
        a = 0;
      }
    }
    if (a) {
      l++;
    }
    s++;
  }
  return l;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcspn>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%esi
  xor    %eax,%eax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rbx,%rdx,1),%rdi
  nopl   0x0(%rax)
L57:
  movzbl 0x0(%rbp,%rax,1),%ecx
  test   %cl,%cl
  je     L36
  mov    %rbx,%rdx
  test   %esi,%esi
  jg     L12
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L59
L12:
  cmp    %cl,(%rdx)
  jne    L20
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L59:
  add    $0x1,%rax
  jmp    L57
```

assistant: ```c
size_t strcspn(const char *s, const char *reject) {
  size_t l = 0;
  int a = 1;
  int i;
  int al = strlen(reject);
  while ((a) && (*s)) {
    for (i = 0; (a) && (i < al); i++) {
      if (*s == reject[i]) {
        a = 0;
      }
    }
    if (a) {
      l++;
    }
    s++;
  }
  return l;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<baz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    $0x0,%edi
  call   <proxy@plt>
  jmp    L32
L4:
  cmpl   $0x0,-0x4(%rbp)
  jle    L19
  mov    $0x1,%edi
  call   <proxy@plt>
  jmp    L32
L19:
  mov    $0xffffffff,%edi
  call   <proxy@plt>
L32:
  leave
  ret
```

assistant: ```c
int baz(int i) {
  if (i == 0)
    return proxy(0);
  else if (i > 0)
    return proxy(1);
  else
    return proxy(-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<baz>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L3
  jle    L24
  mov    $0x1,%edi
  call   <proxy@plt>
L6:
  add    $0x8,%rsp
  ret
L3:
  call   <proxy@plt>
  jmp    L6
L24:
  mov    $0xffffffff,%edi
  call   <proxy@plt>
  jmp    L6
```

assistant: ```c
int baz(int i) {
  if (i == 0)
    return proxy(0);
  else if (i > 0)
    return proxy(1);
  else
    return proxy(-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<baz>:
  endbr64
  test   %edi,%edi
  je     L14
  jle    L5
  mov    $0x1,%edi
  jmp    1050 <proxy@plt>
  nopl   0x0(%rax)
L5:
  mov    $0xffffffff,%edi
L14:
  jmp    1050 <proxy@plt>
```

assistant: ```c
int baz(int i) {
  if (i == 0)
    return proxy(0);
  else if (i > 0)
    return proxy(1);
  else
    return proxy(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<baz>:
  endbr64
  test   %edi,%edi
  je     L8
  jle    L0
  mov    $0x1,%edi
  jmp    1050 <proxy@plt>
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%edi
L8:
  jmp    1050 <proxy@plt>
```

assistant: ```c
int baz(int i) {
  if (i == 0)
    return proxy(0);
  else if (i > 0)
    return proxy(1);
  else
    return proxy(-1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BMP_InvalidExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <ErrorLine@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: Bitmap file extension not recognized for file %s (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)

assistant: ```c
void BMP_InvalidExtension(const char *fileName) {
  ErrorLine("Bitmap file extension not recognized for file %s"
            " (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)",
            fileName);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BMP_InvalidExtension>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <ErrorLine@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
data_type: string

tool: D4: Bitmap file extension not recognized for file %s (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)

assistant: ```c
void BMP_InvalidExtension(const char *fileName) {
  ErrorLine("Bitmap file extension not recognized for file %s"
            " (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)",
            fileName);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BMP_InvalidExtension>:
  endbr64
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  jmp    1050 <ErrorLine@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
datatype: string

tool: D7: Bitmap file extension not recognized for file %s (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)

assistant: ```c
void BMP_InvalidExtension(const char *fileName) {
  ErrorLine("Bitmap file extension not recognized for file %s"
            " (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)",
            fileName);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BMP_InvalidExtension>:
  endbr64
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  jmp    1050 <ErrorLine@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D1: Bitmap file extension not recognized for file %s (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)

assistant: ```c
void BMP_InvalidExtension(const char *fileName) {
  ErrorLine("Bitmap file extension not recognized for file %s"
            " (Supported extensions: .BMP, .pbitm, .xbm and .pbm/.ppm/.pnm)",
            fileName);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<evalBefore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <precedenceLevel@plt>
  mov    %rax,%rbx
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <precedenceLevel@plt>
  cmp    %rax,%rbx
  jle    L29
  mov    $0x1,%eax
  jmp    L35
L29:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <precedenceLevel@plt>
  mov    %rax,%rbx
  movsbl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <precedenceLevel@plt>
  cmp    %rax,%rbx
  jne    L47
  movzbl -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%al
  jne    L3
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <isLeftAssociative@plt>
  jmp    L35
L3:
  mov    $0x1,%eax
  jmp    L35
L47:
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool evalBefore(char op1, char op2) {
  if (precedenceLevel(op1) > precedenceLevel(op2)) {
    return true;
  }
  if (precedenceLevel(op1) == precedenceLevel(op2)) {
    if (op1 == op2) {
      return isLeftAssociative(op1);
    }
    return true;
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<evalBefore>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  movsbl %dil,%r13d
  mov    %r13d,%edi
  call   <precedenceLevel@plt>
  mov    %rax,%r12
  movsbl %bl,%r14d
  mov    %r14d,%edi
  call   <precedenceLevel@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  cmp    %rdx,%r12
  jle    L20
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    %r13d,%edi
  call   <precedenceLevel@plt>
  mov    %rax,%r12
  mov    %r14d,%edi
  call   <precedenceLevel@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%r12
  jne    L8
  mov    $0x1,%eax
  cmp    %bl,%bpl
  jne    L8
  mov    %r13d,%edi
  call   <isLeftAssociative@plt>
  jmp    L8
```

assistant: ```c
bool evalBefore(char op1, char op2) {
  if (precedenceLevel(op1) > precedenceLevel(op2)) {
    return true;
  }
  if (precedenceLevel(op1) == precedenceLevel(op2)) {
    if (op1 == op2) {
      return isLeftAssociative(op1);
    }
    return true;
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<evalBefore>:
  endbr64
  push   %r14
  push   %r13
  movsbl %dil,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  push   %rbx
  mov    %esi,%ebx
  movsbl %bl,%r14d
  call   <precedenceLevel@plt>
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <precedenceLevel@plt>
  cmp    %rax,%r12
  jle    L17
L11:
  mov    $0x1,%eax
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L17:
  mov    %r13d,%edi
  call   <precedenceLevel@plt>
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <precedenceLevel@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%r12
  jne    L29
  cmp    %bl,%bpl
  jne    L11
  pop    %rbx
  mov    %r13d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <isLeftAssociative@plt>
```

assistant: ```c
bool evalBefore(char op1, char op2) {
  if (precedenceLevel(op1) > precedenceLevel(op2)) {
    return true;
  }
  if (precedenceLevel(op1) == precedenceLevel(op2)) {
    if (op1 == op2) {
      return isLeftAssociative(op1);
    }
    return true;
  }
  return false;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<evalBefore>:
  endbr64
  push   %r14
  push   %r13
  movsbl %dil,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  push   %rbx
  mov    %esi,%ebx
  movsbl %bl,%r14d
  call   <precedenceLevel@plt>
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <precedenceLevel@plt>
  cmp    %rax,%r12
  jle    L25
L1:
  mov    $0x1,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L25:
  mov    %r13d,%edi
  call   <precedenceLevel@plt>
  mov    %r14d,%edi
  mov    %rax,%r12
  call   <precedenceLevel@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%r12
  jne    L18
  cmp    %bl,%bpl
  jne    L1
  pop    %rbx
  mov    %r13d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <isLeftAssociative@plt>
```

assistant: ```c
bool evalBefore(char op1, char op2) {
  if (precedenceLevel(op1) > precedenceLevel(op2)) {
    return true;
  }
  if (precedenceLevel(op1) == precedenceLevel(op2)) {
    if (op1 == op2) {
      return isLeftAssociative(op1);
    }
    return true;
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x40(%rbp)
  movl   $0x2,-0x3c(%rbp)
  movl   $0x37,-0x38(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x25,-0x30(%rbp)
  movl   $0x3,-0x2c(%rbp)
  movl   $0x2c,-0x28(%rbp)
  movl   $0x15,-0x24(%rbp)
  movl   $0x21,-0x20(%rbp)
  movl   $0x130,-0x1c(%rbp)
  movl   $0x2d,-0x18(%rbp)
  movl   $0x10,-0x14(%rbp)
  movl   $0xc,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <selectSort@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L17
L15:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x48(%rbp)
L17:
  mov    -0x48(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string

tool: D3: %d 

assistant: ```c
int main() {
  int arr[] = {1, 2, 55, 4, 37, 3, 44, 21, 33, 304, 45, 16};
  int len = sizeof(arr) / 4;
  selectSort(arr, 0, len - 1);
  int i;
  for (i = 0; i < len; i++) {
    printf("%d ", arr[i]);
  }
}
```