ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<send_char>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <report@plt>
  nopl   0x0(%rax)
L114:
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  test   $0x20,%al
  je     L114
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,%ebx
  test   $0x1e,%al
  je     L94
  test   $0x80,%al
  je     L1
L13:
  mov    $0x90,%esi
  lea    D13(%rip),%rdi
  call   <fail@plt>
L10:
  mov    %ebp,%esi
  mov    $0x9c000000,%edi
  call   <setreg@plt>
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,%ebx
  test   $0x1e,%al
  je     L21
  test   $0x80,%al
  je     L16
L90:
  add    $0x8,%rsp
  mov    $0x92,%esi
  lea    D13(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <fail@plt>
  cs nopw 0x0(%rax,%rax,1)
L21:
  test   $0x80,%al
  jne    L90
L96:
  and    $0x60,%ebx
  cmp    $0x40,%ebx
  je     L90
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L94:
  test   $0x80,%al
  jne    L13
L55:
  and    $0x60,%ebx
  cmp    $0x40,%ebx
  jne    L10
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    $0x92,%edx
  mov    %eax,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L96
  nopl   (%rax)
L1:
  mov    $0x90,%edx
  mov    %eax,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L55
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type: string
name: unpack_data
arguments: data_tag: D24
type: string

tool: D13: ?

tool: D24: LSR7 (0x%02x) ERR @ %i


assistant: ```c
void send_char(int ch) {
  report(ch);
  while (!(getreg(((0x9c000000) + 5)) & (0x20)))
    ;
  {
    unsigned x = getreg(((0x9c000000) + 5));
    if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
      printf("LSR7 (0x%02x) ERR @ %i\n", x, 144);
    ((!(x & (0x80)) && ((x & 0x60) != 0x40)) ? 1 : fail("?", 144));
  };
  setreg(((0x9c000000) + 0), ch);
  {
    unsigned x = getreg(((0x9c000000) + 5));
    if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
      printf("LSR7 (0x%02x) ERR @ %i\n", x, 146);
    ((!(x & (0x80)) && ((x & 0x60) != 0x40)) ? 1 : fail("?", 146));
  };
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<send_char>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <report@plt>
  nopl   0x0(%rax)
L23:
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  test   $0x20,%al
  je     L23
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,%ebx
  test   $0x1e,%al
  je     L28
  test   $0x80,%al
  je     L52
L43:
  mov    $0x90,%esi
  lea    D4(%rip),%rdi
  call   <fail@plt>
L27:
  mov    %ebp,%esi
  mov    $0x9c000000,%edi
  call   <setreg@plt>
  mov    $0x9c000005,%edi
  call   <getreg@plt>
  mov    %eax,%ebx
  test   $0x1e,%al
  je     L96
  test   $0x80,%al
  je     L115
L20:
  add    $0x8,%rsp
  mov    $0x92,%esi
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1090 <fail@plt>
  cs nopw 0x0(%rax,%rax,1)
L96:
  test   $0x80,%al
  jne    L20
L25:
  and    $0x60,%ebx
  cmp    $0x40,%ebx
  je     L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  test   $0x80,%al
  jne    L43
L10:
  and    $0x60,%ebx
  cmp    $0x40,%ebx
  jne    L27
  jmp    L43
  cs nopw 0x0(%rax,%rax,1)
L115:
  mov    $0x92,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L25
  nopl   (%rax)
L52:
  mov    $0x90,%edx
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string
name: read_data
arguments: tag: D0
type_guessed: string

tool: D4: ?

tool: D0: LSR7 (0x%02x) ERR @ %i


assistant: ```c
void send_char(int ch) {
  report(ch);
  while (!(getreg(((0x9c000000) + 5)) & (0x20)))
    ;
  {
    unsigned x = getreg(((0x9c000000) + 5));
    if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
      printf("LSR7 (0x%02x) ERR @ %i\n", x, 144);
    ((!(x & (0x80)) && ((x & 0x60) != 0x40)) ? 1 : fail("?", 144));
  };
  setreg(((0x9c000000) + 0), ch);
  {
    unsigned x = getreg(((0x9c000000) + 5));
    if ((x & ((0x10) | (0x08) | (0x04) | (0x02))) && !(x & (0x80)))
      printf("LSR7 (0x%02x) ERR @ %i\n", x, 146);
    ((!(x & (0x80)) && ((x & 0x60) != 0x40)) ? 1 : fail("?", 146));
  };
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wavg_impl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double wavg_impl(double x, double y, double w, const char *file, int line) {
  (void)(file);
  (void)(line);
  (void)(w >= 0.0);
  (void)(w <= 1.0);
  return (x + (y - x) * w);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wavg_impl>:
  endbr64
  subsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double wavg_impl(double x, double y, double w, const char *file, int line) {
  (void)(file);
  (void)(line);
  (void)(w >= 0.0);
  (void)(w <= 1.0);
  return (x + (y - x) * w);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wavg_impl>:
  endbr64
  subsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double wavg_impl(double x, double y, double w, const char *file, int line) {
  (void)(file);
  (void)(line);
  (void)(w >= 0.0);
  (void)(w <= 1.0);
  return (x + (y - x) * w);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wavg_impl>:
  endbr64
  subsd  %xmm0,%xmm1
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double wavg_impl(double x, double y, double w, const char *file, int line) {
  (void)(file);
  (void)(line);
  (void)(w >= 0.0);
  (void)(w <= 1.0);
  return (x + (y - x) * w);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cta_ifdb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x5,%al
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jbe    L52
  mov    -0x8(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x1c(%rbp)
  jb     L8
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  sub    %edx,%eax
  sub    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x2,%rax
  add    %rax,-0x18(%rbp)
  jmp    L80
L40:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  shr    $0x5,%al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x1f,%eax
  cmp    $0x1,%eax
  jne    L31
  cmpl   $0x3,-0x1c(%rbp)
  jbe    L31
  addq   $0x4,-0x18(%rbp)
  subl   $0x4,-0x1c(%rbp)
  jmp    L77
L31:
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x1c(%rbp)
L77:
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L80:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L40
  jmp    L38
L52:
  nop
  jmp    L38
L8:
  nop
L38:
  pop    %rbp
  ret
```

assistant: ```c
void cta_ifdb(const unsigned char *x, unsigned int length) {
  int len_hdr = x[0] >> 5;
  if (length < 2)
    return;
  (void)("    VSIFs: %d\n", x[1]);
  if (length < len_hdr + 2)
    return;
  length -= len_hdr + 2;
  x += len_hdr + 2;
  while (length > 0) {
    int payload_len = x[0] >> 5;
    if ((x[0] & 0x1f) == 1 && length >= 4) {
      (void)("    InfoFrame Type Code %d IEEE OUI: %02x%02x%02x\n", x[0] & 0x1f, x[3], x[2], x[1]);
      x += 4;
      length -= 4;
    } else {
      (void)("    InfoFrame Type Code %d\n", x[0] & 0x1f);
      x++;
      length--;
    }
    x += payload_len;
    length -= payload_len;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cta_ifdb>:
  endbr64
  cmp    $0x1,%esi
  jbe    L1
  movzbl (%rdi),%eax
  shr    $0x5,%al
  lea    0x2(%rax),%edx
  movzbl %dl,%ecx
  cmp    %esi,%ecx
  ja     L1
  sub    $0x2,%esi
  movzbl %al,%eax
  movzbl %dl,%edx
  add    %rdx,%rdi
  sub    %eax,%esi
  jne    L49
L1:
  ret
L61:
  add    $0x1,%rdi
  sub    $0x1,%esi
L41:
  movzbl %al,%edx
  add    %rdx,%rdi
  movzbl %al,%eax
  sub    %eax,%esi
  je     L1
L49:
  movzbl (%rdi),%edx
  mov    %edx,%eax
  shr    $0x5,%al
  and    $0x1f,%edx
  cmp    $0x1,%dl
  jne    L61
  cmp    $0x3,%esi
  jbe    L61
  add    $0x4,%rdi
  sub    $0x4,%esi
  jmp    L41
```

assistant: ```c
void cta_ifdb(const unsigned char *x, unsigned int length) {
  int len_hdr = x[0] >> 5;
  if (length < 2)
    return;
  (void)("    VSIFs: %d\n", x[1]);
  if (length < len_hdr + 2)
    return;
  length -= len_hdr + 2;
  x += len_hdr + 2;
  while (length > 0) {
    int payload_len = x[0] >> 5;
    if ((x[0] & 0x1f) == 1 && length >= 4) {
      (void)("    InfoFrame Type Code %d IEEE OUI: %02x%02x%02x\n", x[0] & 0x1f, x[3], x[2], x[1]);
      x += 4;
      length -= 4;
    } else {
      (void)("    InfoFrame Type Code %d\n", x[0] & 0x1f);
      x++;
      length--;
    }
    x += payload_len;
    length -= payload_len;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cta_ifdb>:
  endbr64
  cmp    $0x1,%esi
  jbe    L68
  movzbl (%rdi),%eax
  shr    $0x5,%al
  lea    0x2(%rax),%edx
  movzbl %dl,%ecx
  cmp    %esi,%ecx
  ja     L68
  movzbl %dl,%edx
  sub    $0x2,%esi
  movzbl %al,%eax
  add    %rdx,%rdi
  sub    %eax,%esi
  jne    L74
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L38:
  movzbl %al,%edx
  add    $0x1,%rdi
  sub    $0x1,%esi
  movzbl %al,%eax
  add    %rdx,%rdi
  sub    %eax,%esi
  je     L68
L74:
  movzbl (%rdi),%edx
  mov    %edx,%eax
  and    $0x1f,%edx
  shr    $0x5,%al
  cmp    $0x1,%dl
  jne    L38
  cmp    $0x3,%esi
  jbe    L38
  movzbl %al,%edx
  add    $0x4,%rdi
  sub    $0x4,%esi
  movzbl %al,%eax
  add    %rdx,%rdi
  sub    %eax,%esi
  jne    L74
L68:
  ret
```

assistant: ```c
void cta_ifdb(const unsigned char *x, unsigned int length) {
  int len_hdr = x[0] >> 5;
  if (length < 2)
    return;
  (void)("    VSIFs: %d\n", x[1]);
  if (length < len_hdr + 2)
    return;
  length -= len_hdr + 2;
  x += len_hdr + 2;
  while (length > 0) {
    int payload_len = x[0] >> 5;
    if ((x[0] & 0x1f) == 1 && length >= 4) {
      (void)("    InfoFrame Type Code %d IEEE OUI: %02x%02x%02x\n", x[0] & 0x1f, x[3], x[2], x[1]);
      x += 4;
      length -= 4;
    } else {
      (void)("    InfoFrame Type Code %d\n", x[0] & 0x1f);
      x++;
      length--;
    }
    x += payload_len;
    length -= payload_len;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cta_ifdb>:
  endbr64
  cmp    $0x1,%esi
  jbe    L51
  movzbl (%rdi),%eax
  shr    $0x5,%al
  lea    0x2(%rax),%edx
  movzbl %dl,%ecx
  cmp    %esi,%ecx
  ja     L51
  movzbl %dl,%edx
  sub    $0x2,%esi
  movzbl %al,%eax
  add    %rdx,%rdi
  sub    %eax,%esi
  je     L51
  nopl   0x0(%rax)
L5:
  movzbl (%rdi),%edx
  mov    %edx,%eax
  and    $0x1f,%edx
  shr    $0x5,%al
  cmp    $0x1,%dl
  jne    L33
  cmp    $0x3,%esi
  ja     L26
L33:
  lea    0x1(%rax),%edx
  sub    $0x1,%esi
  movzbl %al,%eax
  movzbl %dl,%edx
  add    %rdx,%rdi
  sub    %eax,%esi
  jne    L5
L51:
  ret
  nopl   0x0(%rax)
L26:
  lea    0x4(%rax),%edx
  sub    $0x4,%esi
  movzbl %al,%eax
  movzbl %dl,%edx
  add    %rdx,%rdi
  sub    %eax,%esi
  jne    L5
  ret
```

assistant: ```c
void cta_ifdb(const unsigned char *x, unsigned int length) {
  int len_hdr = x[0] >> 5;
  if (length < 2)
    return;
  (void)("    VSIFs: %d\n", x[1]);
  if (length < len_hdr + 2)
    return;
  length -= len_hdr + 2;
  x += len_hdr + 2;
  while (length > 0) {
    int payload_len = x[0] >> 5;
    if ((x[0] & 0x1f) == 1 && length >= 4) {
      (void)("    InfoFrame Type Code %d IEEE OUI: %02x%02x%02x\n", x[0] & 0x1f, x[3], x[2], x[1]);
      x += 4;
      length -= 4;
    } else {
      (void)("    InfoFrame Type Code %d\n", x[0] & 0x1f);
      x++;
      length--;
    }
    x += payload_len;
    length -= payload_len;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nand_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x7ff,%eax
  mov    %eax,-0x14(%rbp)
  mov    $0x0,%eax
  call   <nand_select@plt>
  jmp    L10
L21:
  mov    $0x80,%edi
  call   <nand_cmd@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <nand_send_addr@plt>
  jmp    L30
L39:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <nand_send_data@plt>
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L30:
  cmpl   $0x7ff,-0x14(%rbp)
  jg     L22
  mov    -0x28(%rbp),%eax
  cmp    %rax,-0x10(%rbp)
  jb     L39
L22:
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%eax
  call   <wait_ready@plt>
  movl   $0x0,-0x14(%rbp)
L10:
  mov    -0x28(%rbp),%eax
  cmp    %rax,-0x10(%rbp)
  jb     L21
  mov    $0x0,%eax
  call   <nand_deselect@plt>
  nop
  leave
  ret
```

assistant: ```c
int nand_write(unsigned int nand_start, unsigned char *buf, unsigned int len) {
  unsigned long count = 0;
  unsigned long addr = nand_start;
  int i = nand_start % 2048;
  nand_select();
  while (count < len) {
    nand_cmd(0x80);
    nand_send_addr(addr);
    for (; i < 2048 && count < len; i++) {
      nand_send_data(buf[count++]);
      addr++;
    }
    nand_cmd(0x10);
    wait_ready();
    i = 0;
  }
  nand_deselect();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<nand_write>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r14d
  mov    %rsi,%r15
  mov    %edx,%r12d
  mov    %edi,%r13d
  and    $0x7ff,%r14d
  mov    $0x0,%eax
  call   <nand_select@plt>
  mov    %r12d,%r12d
  test   %r12,%r12
  je     L46
  mov    $0x0,%ebp
  jmp    L12
L6:
  mov    %rdx,%r13
  mov    %rbx,%rbp
L2:
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  mov    $0x0,%eax
  call   <wait_ready@plt>
  mov    $0x0,%r14d
  cmp    %rbp,%r12
  jbe    L46
L12:
  mov    $0x80,%edi
  call   <nand_cmd@plt>
  mov    %r13,%rdi
  call   <nand_send_addr@plt>
  cmp    %rbp,%r12
  jbe    L2
  mov    %rbp,%rbx
L5:
  add    $0x1,%rbx
  movzbl -0x1(%r15,%rbx,1),%edi
  call   <nand_send_data@plt>
  lea    (%rbx,%r13,1),%rax
  sub    %rbp,%rax
  mov    %rax,%rdx
  lea    (%r14,%rbx,1),%eax
  sub    %ebp,%eax
  cmp    %r12,%rbx
  jae    L6
  cmp    $0x7ff,%eax
  jle    L5
  jmp    L6
L46:
  mov    $0x0,%eax
  call   <nand_deselect@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nand_write(unsigned int nand_start, unsigned char *buf, unsigned int len) {
  unsigned long count = 0;
  unsigned long addr = nand_start;
  int i = nand_start % 2048;
  nand_select();
  while (count < len) {
    nand_cmd(0x80);
    nand_send_addr(addr);
    for (; i < 2048 && count < len; i++) {
      nand_send_data(buf[count++]);
      addr++;
    }
    nand_cmd(0x10);
    wait_ready();
    i = 0;
  }
  nand_deselect();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nand_write>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbx,%r14
  and    $0x7ff,%r14d
  sub    $0x8,%rsp
  call   <nand_select@plt>
  test   %r12,%r12
  je     L36
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0x80,%edi
  mov    %rbp,%r15
  call   <nand_cmd@plt>
  mov    %rbx,%rdi
  call   <nand_send_addr@plt>
  mov    $0x7ff,%eax
  sub    %r14d,%eax
  lea    0x1(%rbp,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L46:
  cmp    %r15,%r12
  jbe    L48
  add    $0x1,%r15
  add    $0x1,%rbx
  movzbl -0x1(%r13,%r15,1),%edi
  call   <nand_send_data@plt>
  cmp    %r15,%rbp
  jne    L46
  mov    $0x10,%edi
  xor    %r14d,%r14d
  call   <nand_cmd@plt>
  xor    %eax,%eax
  call   <wait_ready@plt>
  cmp    %r12,%rbp
  jb     L31
L36:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10d0 <nand_deselect@plt>
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  xor    %eax,%eax
  call   <wait_ready@plt>
  jmp    L36
```

assistant: ```c
int nand_write(unsigned int nand_start, unsigned char *buf, unsigned int len) {
  unsigned long count = 0;
  unsigned long addr = nand_start;
  int i = nand_start % 2048;
  nand_select();
  while (count < len) {
    nand_cmd(0x80);
    nand_send_addr(addr);
    for (; i < 2048 && count < len; i++) {
      nand_send_data(buf[count++]);
      addr++;
    }
    nand_cmd(0x10);
    wait_ready();
    i = 0;
  }
  nand_deselect();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<nand_write>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rbx,%r14
  and    $0x7ff,%r14d
  sub    $0x8,%rsp
  call   <nand_select@plt>
  test   %r12,%r12
  je     L6
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x80,%edi
  mov    %rbp,%r15
  call   <nand_cmd@plt>
  mov    %rbx,%rdi
  call   <nand_send_addr@plt>
  mov    $0x7ff,%eax
  sub    %r14d,%eax
  lea    0x1(%rbp,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L10:
  cmp    %r15,%r12
  jbe    L24
  add    $0x1,%r15
  add    $0x1,%rbx
  movzbl -0x1(%r13,%r15,1),%edi
  call   <nand_send_data@plt>
  cmp    %r15,%rbp
  jne    L10
  mov    $0x10,%edi
  xor    %r14d,%r14d
  call   <nand_cmd@plt>
  xor    %eax,%eax
  call   <wait_ready@plt>
  cmp    %r12,%rbp
  jb     L11
L6:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10d0 <nand_deselect@plt>
  nopl   0x0(%rax,%rax,1)
L24:
  mov    $0x10,%edi
  call   <nand_cmd@plt>
  xor    %eax,%eax
  call   <wait_ready@plt>
  jmp    L6
```

assistant: ```c
int nand_write(unsigned int nand_start, unsigned char *buf, unsigned int len) {
  unsigned long count = 0;
  unsigned long addr = nand_start;
  int i = nand_start % 2048;
  nand_select();
  while (count < len) {
    nand_cmd(0x80);
    nand_send_addr(addr);
    for (; i < 2048 && count < len; i++) {
      nand_send_data(buf[count++]);
      addr++;
    }
    nand_cmd(0x10);
    wait_ready();
    i = 0;
  }
  nand_deselect();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L3
  lea    D8(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <xwrite@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L3:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: Get Next Line Error : malloc error

assistant: ```c
void *xmalloc(int size) {
  void *tmp;
  char *err;
  tmp = malloc(size);
  if (tmp == NULL) {
    err = "Get Next Line Error : malloc error";
    xwrite(2, err, my_strlen(err));
    free(err);
    exit(-1);
  }
  return (tmp);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L16:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    $0x2,%edi
  call   <xwrite@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: Get Next Line Error : malloc error

assistant: ```c
void *xmalloc(int size) {
  void *tmp;
  char *err;
  tmp = malloc(size);
  if (tmp == NULL) {
    err = "Get Next Line Error : malloc error";
    xwrite(2, err, my_strlen(err));
    free(err);
    exit(-1);
  }
  return (tmp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  mov    %eax,%edx
  call   <xwrite@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D1: Get Next Line Error : malloc error

assistant: ```c
void *xmalloc(int size) {
  void *tmp;
  char *err;
  tmp = malloc(size);
  if (tmp == NULL) {
    err = "Get Next Line Error : malloc error";
    xwrite(2, err, my_strlen(err));
    free(err);
    exit(-1);
  }
  return (tmp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmalloc>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  call   <my_strlen@plt>
  mov    %rbp,%rsi
  mov    $0x2,%edi
  mov    %eax,%edx
  call   <xwrite@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: Get Next Line Error : malloc error

assistant: ```c
void *xmalloc(int size) {
  void *tmp;
  char *err;
  tmp = malloc(size);
  if (tmp == NULL) {
    err = "Get Next Line Error : malloc error";
    xwrite(2, err, my_strlen(err));
    free(err);
    exit(-1);
  }
  return (tmp);
}
```
user: What is the c source code of the assembly code below:

```asm
<insertion_sort_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L5
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L48
L4:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x38(%rbp),%rdi
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <swap@plt>
  subq   $0x1,-0x8(%rbp)
L48:
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jb     L4
L18:
  addq   $0x1,-0x28(%rbp)
L5:
  mov    -0x28(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jbe    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void insertion_sort_r(char *base, size_t es, size_t lo, size_t hi, size_t *index) {
  for (++lo; lo <= hi; ++lo)
    for (size_t j = lo; j > 0 && index[j] < index[j - 1]; --j)
      swap(base, es, j, j - 1, index);
}
```