ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<in_chksum_ip>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0x4(%rdi),%eax
  add    %ecx,%eax
  movzwl 0x6(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0x8(%rdi),%eax
  add    %ecx,%eax
  movzwl 0xa(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0xc(%rdi),%eax
  add    %ecx,%eax
  movzwl 0xe(%rdi),%ecx
  add    %eax,%ecx
  movzwl 0x10(%rdi),%eax
  add    %ecx,%eax
  movzwl 0x12(%rdi),%ecx
  add    %eax,%ecx
  lea    0x14(%rdi),%rax
  cmp    $0x14,%esi
  je     L16
  sub    $0x18,%esi
  lea    0x18(%rdi,%rsi,1),%rdi
  xchg   %ax,%ax
L17:
  movzwl (%rax),%edx
  movzwl 0x2(%rax),%esi
  add    $0x4,%rax
  add    %esi,%edx
  add    %edx,%ecx
  cmp    %rdi,%rax
  jne    L17
L16:
  mov    %ecx,%edx
  movzwl %cx,%ecx
  shr    $0x10,%edx
  add    %ecx,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
```

assistant: ```c
unsigned short in_chksum_ip(unsigned short *w, int blen) {
  unsigned int cksum;
  cksum = w[0];
  cksum += w[1];
  cksum += w[2];
  cksum += w[3];
  cksum += w[4];
  cksum += w[5];
  cksum += w[6];
  cksum += w[7];
  cksum += w[8];
  cksum += w[9];
  blen -= 20;
  w += 10;
  while (blen) {
    cksum += w[0];
    cksum += w[1];
    w += 2;
    blen -= 4;
  }
  cksum = (cksum >> 16) + (cksum & 0x0000ffff);
  cksum += (cksum >> 16);
  return (unsigned short)(~cksum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L18
L6:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x2c(%rbp)
L18:
  cmpl   $0x3,-0x2c(%rbp)
  jle    L6
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <min_max@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type: string
name: read_data
arguments: tag: D4
type: string

tool: D0: podaj liczbe 


tool: D4: %d

assistant: ```c
int main(void) {
  int i, *p, a[5];
  p = &a[0];
  i = 0;
  for (i = 0; i < 4; i++) {
    printf("podaj liczbe \n");
    scanf("%d", &a[i]);
  }
  min_max(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x10(%rsp),%r13
  lea    D7(%rip),%r12
  lea    D1(%rip),%rbp
L15:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L15
  mov    %rsp,%rdi
  call   <min_max@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D7: podaj liczbe 


tool: D1: %d

assistant: ```c
int main(void) {
  int i, *p, a[5];
  p = &a[0];
  i = 0;
  for (i = 0; i < 4; i++) {
    printf("podaj liczbe \n");
    scanf("%d", &a[i]);
  }
  min_max(p);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x10(%rsp),%r13
  mov    %r14,%rbx
L15:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L15
  mov    %r14,%rdi
  call   <min_max@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D18: podaj liczbe 


tool: D10: %d

assistant: ```c
int main(void) {
  int i, *p, a[5];
  p = &a[0];
  i = 0;
  for (i = 0; i < 4; i++) {
    printf("podaj liczbe \n");
    scanf("%d", &a[i]);
  }
  min_max(p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  lea    0x10(%rsp),%r13
  mov    %r14,%rbx
L3:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L3
  mov    %r14,%rdi
  call   <min_max@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string

tool: D6: podaj liczbe 


tool: D15: %d

assistant: ```c
int main(void) {
  int i, *p, a[5];
  p = &a[0];
  i = 0;
  for (i = 0; i < 4; i++) {
    printf("podaj liczbe \n");
    scanf("%d", &a[i]);
  }
  min_max(p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wcstombs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__wcstombs_alias@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long int wcstombs(char *restrict __dst, const signed int *restrict __src, unsigned long int __len) {
  unsigned long int return_value___wcstombs_chk$1;
  unsigned long int return_value___wcstombs_chk_warn$2;
  unsigned long int return_value___wcstombs_alias$3;
  return_value___wcstombs_alias$3 = __wcstombs_alias(__dst, __src, __len);
  return return_value___wcstombs_alias$3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wcstombs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__wcstombs_alias@plt>
  cltq
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long int wcstombs(char *restrict __dst, const signed int *restrict __src, unsigned long int __len) {
  unsigned long int return_value___wcstombs_chk$1;
  unsigned long int return_value___wcstombs_chk_warn$2;
  unsigned long int return_value___wcstombs_alias$3;
  return_value___wcstombs_alias$3 = __wcstombs_alias(__dst, __src, __len);
  return return_value___wcstombs_alias$3;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wcstombs>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__wcstombs_alias@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
unsigned long int wcstombs(char *restrict __dst, const signed int *restrict __src, unsigned long int __len) {
  unsigned long int return_value___wcstombs_chk$1;
  unsigned long int return_value___wcstombs_chk_warn$2;
  unsigned long int return_value___wcstombs_alias$3;
  return_value___wcstombs_alias$3 = __wcstombs_alias(__dst, __src, __len);
  return return_value___wcstombs_alias$3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcstombs>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__wcstombs_alias@plt>
  add    $0x8,%rsp
  cltq
  ret
```

assistant: ```c
unsigned long int wcstombs(char *restrict __dst, const signed int *restrict __src, unsigned long int __len) {
  unsigned long int return_value___wcstombs_chk$1;
  unsigned long int return_value___wcstombs_chk_warn$2;
  unsigned long int return_value___wcstombs_alias$3;
  return_value___wcstombs_alias$3 = __wcstombs_alias(__dst, __src, __len);
  return return_value___wcstombs_alias$3;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  lea    0x5(%rax),%rcx
  movabs $0x2aaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  test   %rdx,%rdx
  jne    L30
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L53
L30:
  mov    -0x10(%rbp),%rax
  lea    0x3(%rax),%rcx
  movabs $0x2aaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  test   %rdx,%rdx
  jne    L21
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L53
L21:
  mov    -0x10(%rbp),%rcx
  movabs $0x2aaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  test   %rdx,%rdx
  jne    L59
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L53
L59:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L53:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D41
type: string
name: parse_data
arguments: tag: D22
type: string

tool: D0: %lld

tool: D41: yes

tool: D22: no

assistant: ```c
int main() {
  long long input = 0;
  scanf("%lld", &input);
  if ((input + 5) % 6 == 0)
    printf("yes");
  else if ((input + 3) % 6 == 0)
    printf("yes");
  else if (input % 6 == 0)
    printf("yes");
  else
    printf("no");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rcx
  lea    0x5(%rcx),%rsi
  movabs $0x2aaaaaaaaaaaaaab,%rdx
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  add    %rax,%rax
  cmp    %rax,%rsi
  je     L9
  lea    0x3(%rcx),%rsi
  movabs $0x2aaaaaaaaaaaaaab,%rdx
  mov    %rsi,%rax
  imul   %rdx
  mov    %rsi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  lea    (%rdx,%rdx,2),%rax
  add    %rax,%rax
  cmp    %rax,%rsi
  je     L35
  mov    $0x6,%esi
  mov    %rcx,%rax
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L14
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L9:
  lea    D35(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L35:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L14:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D35
type_guessed: string
name: unpack_data
arguments: label: D45
type_guessed: string

tool: D6: %lld

tool: D35: yes

tool: D45: no

assistant: ```c
int main() {
  long long input = 0;
  scanf("%lld", &input);
  if ((input + 5) % 6 == 0)
    printf("yes");
  else if ((input + 3) % 6 == 0)
    printf("yes");
  else if (input % 6 == 0)
    printf("yes");
  else
    printf("no");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%rax
  movabs $0xaaaaaaaaaaaaaaab,%rsi
  movabs $0x2aaaaaaaaaaaaaaa,%rcx
  lea    0x5(%rax),%rdx
  imul   %rsi,%rdx
  add    %rcx,%rdx
  ror    %rdx
  cmp    %rcx,%rdx
  jbe    L7
  lea    0x3(%rax),%rdx
  imul   %rsi,%rdx
  add    %rcx,%rdx
  ror    %rdx
  cmp    %rcx,%rdx
  jbe    L7
  mov    $0x6,%ecx
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L7
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L7:
  lea    D2(%rip),%rdi
  call   <printf@plt>
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string

tool: D19: %lld

tool: D25: no

tool: D2: yes

assistant: ```c
int main() {
  long long input = 0;
  scanf("%lld", &input);
  if ((input + 5) % 6 == 0)
    printf("yes");
  else if ((input + 3) % 6 == 0)
    printf("yes");
  else if (input % 6 == 0)
    printf("yes");
  else
    printf("no");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%rax
  movabs $0xaaaaaaaaaaaaaaab,%rsi
  movabs $0x2aaaaaaaaaaaaaaa,%rcx
  lea    0x5(%rax),%rdx
  imul   %rsi,%rdx
  add    %rcx,%rdx
  ror    %rdx
  cmp    %rcx,%rdx
  jbe    L19
  lea    0x3(%rax),%rdx
  imul   %rsi,%rdx
  add    %rcx,%rdx
  ror    %rdx
  cmp    %rcx,%rdx
  jbe    L19
  mov    $0x6,%ecx
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L19
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L19:
  lea    D11(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string
name: extract_symbolic_data
arguments: data_tag: D16
type: string
name: extract_symbolic_data
arguments: data_tag: D11
type: string

tool: D4: %lld

tool: D16: no

tool: D11: yes

assistant: ```c
int main() {
  long long input = 0;
  scanf("%lld", &input);
  if ((input + 5) % 6 == 0)
    printf("yes");
  else if ((input + 3) % 6 == 0)
    printf("yes");
  else if (input % 6 == 0)
    printf("yes");
  else
    printf("no");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L93:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L93
  sub    $0xa30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa28(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x10(%rsp)
  mov    $0x1,%ebp
  mov    $0x3,%ebx
  jmp    L121
L116:
  movslq %ebp,%rax
  mov    %ebx,0x10(%rsp,%rax,4)
  lea    0x1(%rbp),%ebp
L173:
  add    $0x2,%ebx
  cmp    $0x7d01,%ebx
  je     L41
L121:
  mov    %ebx,%edi
  call   <sqrt@plt>
  test   %ebp,%ebp
  jle    L116
  mov    0x10(%rsp),%ecx
  cmp    %ecx,%eax
  jl     L116
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L173
  jmp    L116
L41:
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L136
  lea    0xc(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D29(%rip),%rbx
  jmp    L135
L169:
  movl   $0x2,0x8(%rsp)
  jmp    L162
L24:
  mov    0x8(%rsp),%eax
  lea    0x1(%rax),%edi
  mov    %edi,0x8(%rsp)
  cmp    0xc(%rsp),%edi
  jg     L48
L133:
  call   <sqrt@plt>
  mov    %eax,%r8d
  mov    0x10(%rsp),%ecx
  cmp    %ecx,%eax
  jl     L39
  mov    0x8(%rsp),%edi
  lea    0x14(%rsp),%rsi
L40:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L24
  add    $0x4,%rsi
  mov    -0x4(%rsi),%ecx
  cmp    %r8d,%ecx
  jle    L40
L39:
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L48:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L136
L135:
  lea    0x8(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  cmpl   $0x1,0x8(%rsp)
  jle    L169
L162:
  mov    0x8(%rsp),%edi
  cmp    0xc(%rsp),%edi
  jle    L133
  jmp    L48
L136:
  mov    0xfa28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L160
  mov    $0x0,%eax
  add    $0xfa30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L160:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type: string
name: disassemble_data
arguments: tag: D18
type: string
name: disassemble_data
arguments: tag: D29
type: string

tool: D0: %d

tool: D18: %d %d

tool: D29: %d


assistant: ```c
int main() {
  int i, j, k, c, len, num, temp, t, l, r, flag;
  int prm[16005];
  num = 0;
  prm[num++] = 2;
  for (i = 3; i <= 32000; i += 2) {
    flag = 1;
    int cap = sqrt(i) + 1;
    for (j = 0; j < num; j++) {
      if (prm[j] >= cap)
        break;
      if (i % prm[j] == 0)
        flag = 0;
      break;
    }
    if (flag)
      prm[num++] = i;
  }
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &l, &r);
    if (l < 2)
      l = 2;
    for (; l <= r; l++) {
      flag = 1;
      temp = sqrt(l);
      for (i = 0; prm[i] <= temp; i++)
        if ((l % prm[i]) == 0) {
          flag = 0;
          break;
        }
      if (flag)
        printf("%d\n", l);
    }
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf000(%rsp),%r11
L84:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L84
  sub    $0xa30,%rsp
  mov    $0x3,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbx
  mov    %rbx,%r12
  nopl   0x0(%rax)
L40:
  mov    %ebp,%edi
  add    $0x4,%r12
  call   <sqrt@plt>
  mov    %ebp,-0x4(%r12)
  add    $0x2,%ebp
  cmp    $0x7d01,%ebp
  jne    L40
  lea    0x4(%rsp),%rsi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    D4(%rip),%r12
  lea    D27(%rip),%rbp
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L56
  nopl   0x0(%rax)
L41:
  mov    %r12,%rdi
  mov    %r14,%rdx
  mov    %r13,%rsi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  cmp    $0x1,%edi
  jg     L48
  movl   $0x2,0x8(%rsp)
  mov    $0x2,%edi
L48:
  cmp    0xc(%rsp),%edi
  jg     L81
  nopl   0x0(%rax)
L67:
  call   <sqrt@plt>
  mov    0x8(%rsp),%r8d
  mov    %eax,%edi
  cmp    $0x1,%eax
  jle    L121
  mov    %rbx,%rsi
  mov    $0x2,%ecx
  jmp    L105
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%rsi),%ecx
  add    $0x4,%rsi
  cmp    %edi,%ecx
  jg     L121
L105:
  mov    %r8d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L25
  lea    0x1(%r8),%edi
  mov    %edi,0x8(%rsp)
L92:
  cmp    0xc(%rsp),%edi
  jle    L67
L81:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L41
L56:
  mov    0xfa28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  add    $0xfa30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L121:
  mov    %r8d,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%r8d
  lea    0x1(%r8),%edi
  mov    %edi,0x8(%rsp)
  jmp    L92
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D26
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D27
datatype: string

tool: D26: %d

tool: D4: %d %d

tool: D27: %d


assistant: ```c
int main() {
  int i, j, k, c, len, num, temp, t, l, r, flag;
  int prm[16005];
  num = 0;
  prm[num++] = 2;
  for (i = 3; i <= 32000; i += 2) {
    flag = 1;
    int cap = sqrt(i) + 1;
    for (j = 0; j < num; j++) {
      if (prm[j] >= cap)
        break;
      if (i % prm[j] == 0)
        flag = 0;
      break;
    }
    if (flag)
      prm[num++] = i;
  }
  scanf("%d", &t);
  while (t--) {
    scanf("%d %d", &l, &r);
    if (l < 2)
      l = 2;
    for (; l <= r; l++) {
      flag = 1;
      temp = sqrt(l);
      for (i = 0; prm[i] <= temp; i++)
        if ((l % prm[i]) == 0) {
          flag = 0;
          break;
        }
      if (flag)
        printf("%d\n", l);
    }
    printf("\n");
  }
  return 0;
}
```