user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x53202e412064655a,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x776168,-0xc(%rbp)
  movl   $0xa,-0x30(%rbp)
  movl   $0xc,-0x2c(%rbp)
  movl   $0xf,-0x28(%rbp)
  movl   $0x12,-0x24(%rbp)
  movl   $0x5b,-0x20(%rbp)
  movl   $0x64655a,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %al,-0x14(%rbp)
  mov    $0x4,%esi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D92(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xc,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movzbl -0x18(%rbp),%eax
  movsbl %al,%eax
  lea    -0x14(%rbp),%rdx
  mov    %eax,%esi
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D72
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D66
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D50
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D92
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D54
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D84
type_guessed: string

tool: D72: The size of an int is %ld


tool: D66: The size of areas is %ld


tool: D67: The number of ints in areas is %ld


tool: D37: The first area is %d, the second one is %d


tool: D50: The size of a char is %ld


tool: D29: The size of name is %ld


tool: D92: The number of chars in name is %ld


tool: D54: The size of full_name is %ld


tool: D36: The number of chars in full_name is %ld


tool: D84: name is "%c" and full_name is "%s"


assistant: ```c
int main(int argc, char *argv[]) {
  char full_name[] = {'Z', 'e', 'd', ' ', 'A', '.', ' ', 'S', 'h', 'a', 'w', '\0'};
  int areas[] = {10, 12, 15, 18, 91};
  char name[] = "Zed";
  full_name[0] = areas[4];
  printf("The size of an int is %ld\n", sizeof(int));
  printf("The size of areas is %ld\n", sizeof(areas));
  printf("The number of ints in areas is %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the second one is %d\n", areas[0], areas[1]);
  printf("The size of a char is %ld\n", sizeof(char));
  printf("The size of name is %ld\n", sizeof(name));
  printf("The number of chars in name is %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full_name is %ld\n", sizeof(full_name));
  printf("The number of chars in full_name is %ld\n", sizeof(full_name) / sizeof(char));
  printf("name is \"%c\" and full_name is \"%s\"\n", name[0], full_name);
  return 0;
}
```