ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calculateMinimumHP1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,%r13d
  mov    %edx,%r14d
  lea    0x8(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %r13d,%r13d
  js     L9
  lea    0x4(,%r14,4),%eax
  mov    %eax,0x4(%rsp)
  mov    %r15,%rbx
  mov    %r15,%r12
  mov    $0x0,%ebp
L5:
  mov    0x4(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,(%r12)
  add    $0x1,%ebp
  add    $0x8,%r12
  cmp    %ebp,%r13d
  jge    L5
  movslq %r14d,%rcx
  shl    $0x2,%rcx
  lea    0x1(%r13),%eax
  lea    (%r15,%rax,8),%rdi
  mov    D14(%rip),%rsi
L41:
  mov    (%rsi),%edx
  mov    (%rbx),%rax
  mov    %edx,(%rax,%rcx,1)
  add    $0x8,%rbx
  cmp    %rdi,%rbx
  jne    L41
L9:
  test   %r14d,%r14d
  js     L80
  movslq %r13d,%rax
  lea    (%r15,%rax,8),%r8
  lea    0x1(%r14),%esi
  shl    $0x2,%rsi
  mov    $0x0,%eax
  mov    D14(%rip),%rdi
L49:
  mov    (%rdi),%ecx
  mov    (%r8),%rdx
  mov    %ecx,(%rdx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L49
L80:
  movslq %r13d,%rax
  movslq %r14d,%rdx
  mov    -0x8(%r15,%rax,8),%rcx
  movl   $0x1,(%rcx,%rdx,4)
  mov    (%r15,%rax,8),%rax
  movl   $0x1,-0x4(%rax,%rdx,4)
  mov    %r13d,%eax
  sub    $0x1,%eax
  js     L75
  cltq
  shl    $0x3,%rax
  mov    0x8(%rsp),%rdi
  lea    (%rdi,%rax,1),%rsi
  lea    -0x8(%rdi,%rax,1),%r10
  lea    -0x1(%r13),%eax
  shl    $0x3,%rax
  sub    %rax,%r10
  lea    -0x1(%r14),%eax
  movslq %eax,%r11
  shl    $0x2,%r11
  mov    %eax,%eax
  sub    %rax,%rdx
  lea    -0x8(,%rdx,4),%r9
  mov    %r15,%rbx
  sub    %rdi,%rbx
  lea    0x8(%rbx),%rbp
L65:
  test   %r14d,%r14d
  jle    L0
  lea    (%rbx,%rsi,1),%r8
  lea    0x0(%rbp,%rsi,1),%rdi
  mov    %r11,%rdx
L39:
  mov    (%r8),%rcx
  mov    (%rdi),%r12
  mov    0x4(%rcx,%rdx,1),%eax
  mov    (%r12,%rdx,1),%r12d
  cmp    %r12d,%eax
  cmovg  %r12d,%eax
  mov    (%rsi),%r12
  sub    (%r12,%rdx,1),%eax
  test   %eax,%eax
  mov    $0x1,%r12d
  cmovle %r12d,%eax
  mov    %eax,(%rcx,%rdx,1)
  sub    $0x4,%rdx
  cmp    %rdx,%r9
  jne    L39
L0:
  sub    $0x8,%rsi
  cmp    %r10,%rsi
  jne    L65
L75:
  mov    (%r15),%rax
  mov    (%rax),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int calculateMinimumHP1(int **dungeon, int rSize, int cSize) {
  int **mins = (int **)malloc(sizeof(int *) * (rSize + 1));
  for (int i = 0; i <= rSize; i++)
    mins[i] = (int *)malloc(sizeof(int) * (cSize + 1));
  for (int i = 0; i <= rSize; i++)
    mins[i][cSize] = INT_MAX;
  for (int i = 0; i <= cSize; i++)
    mins[rSize][i] = INT_MAX;
  mins[rSize - 1][cSize] = 1;
  mins[rSize][cSize - 1] = 1;
  for (int i = rSize - 1; i >= 0; i--)
    for (int j = cSize - 1; j >= 0; j--)
      mins[i][j] = ((1) > (((mins[i + 1][j]) < (mins[i][j + 1]) ? (mins[i + 1][j]) : (mins[i][j + 1])) - dungeon[i][j]) ? (1) : (((mins[i + 1][j]) < (mins[i][j + 1]) ? (mins[i + 1][j]) : (mins[i][j + 1])) - dungeon[i][j]));
  return mins[0][0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_log_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x428,%rsp
  mov    %edi,-0x444(%rbp)
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x3(%rax),%ebx
  movslq %ebx,%rbx
  lea    0xf(%rbx),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L54:
  cmp    %rdx,%rsp
  je     L44
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L54
L44:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L16
  orq    $0x0,-0x8(%rsp,%rax,1)
L16:
  mov    %rsp,%r15
  mov    %r12,%rdx
  lea    D11(%rip),%rsi
  mov    %rsp,%rdi
  call   <sprintf@plt>
  lea    -0x440(%rbp),%r12
  mov    %r14d,%ecx
  mov    %r13,%rdx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  lea    0x10(%rbx,%rax,1),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L36:
  cmp    %rdx,%rsp
  je     L64
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L36
L64:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L66
  orq    $0x0,-0x8(%rsp,%rax,1)
L66:
  movb   $0x0,(%rsp)
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  lea    -0x440(%rbp),%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rsp,%rdx
  lea    D14(%rip),%rsi
  mov    -0x444(%rbp),%edi
  call   <syslog@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string

tool: D11: %s: 

tool: D14: %s

assistant: ```c
_log_tag(int log_level, const char *src, const char *format, va_list argptr) {
  const size_t n_prefix = strlen(src) + 1 + 1 + 1;
  char prefix[n_prefix];
  sprintf(prefix, "%s: ", src);
  char suffix[1024];
  vsnprintf(suffix, sizeof(suffix), format, argptr);
  const size_t n_suffix = strlen(suffix);
  char log_msg[n_prefix + n_suffix + 1];
  log_msg[0] = '\0';
  strcat(log_msg, prefix);
  strcat(log_msg, suffix);
  syslog(log_level, "%s", log_msg);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_log_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %edi,%r14d
  mov    %rsi,%rdi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x3(%rax),%ebx
  movslq %ebx,%rbx
  lea    0xf(%rbx),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L57
L12:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L12
L57:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L14
L76:
  mov    %rsp,%r8
  mov    %r15,%rdx
  lea    D19(%rip),%rsi
  mov    %rsp,%rdi
  lea    -0x440(%rbp),%r15
  mov    %r8,-0x448(%rbp)
  call   <sprintf@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    $0x400,%esi
  mov    %r15,%rdi
  call   <vsnprintf@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rsp,%rcx
  mov    -0x448(%rbp),%r8
  cltq
  lea    0x10(%rbx,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L82
L24:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L24
L82:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L44
L74:
  mov    %r8,%rsi
  mov    %rsp,%rdi
  movb   $0x0,(%rsp)
  call   <strcat@plt>
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rsp,%rdx
  lea    D3(%rip),%rsi
  mov    %r14d,%edi
  call   <syslog@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L44:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L74
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D19: %s: 

tool: D3: %s

assistant: ```c
_log_tag(int log_level, const char *src, const char *format, va_list argptr) {
  const size_t n_prefix = strlen(src) + 1 + 1 + 1;
  char prefix[n_prefix];
  sprintf(prefix, "%s: ", src);
  char suffix[1024];
  vsnprintf(suffix, sizeof(suffix), format, argptr);
  const size_t n_suffix = strlen(suffix);
  char log_msg[n_prefix + n_suffix + 1];
  log_msg[0] = '\0';
  strcat(log_msg, prefix);
  strcat(log_msg, suffix);
  syslog(log_level, "%s", log_msg);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_log_tag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %edi,%r14d
  mov    %rsi,%rdi
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  sub    $0x428,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  lea    0x3(%rax),%ebx
  movslq %ebx,%rbx
  lea    0xf(%rbx),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L59
L13:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L13
L59:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L44
L30:
  mov    %rsp,%r8
  mov    %r15,%rdx
  lea    D1(%rip),%rsi
  mov    %rsp,%rdi
  lea    -0x440(%rbp),%r15
  mov    %r8,-0x448(%rbp)
  call   <sprintf@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    $0x400,%esi
  mov    %r15,%rdi
  call   <vsnprintf@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %rsp,%rcx
  mov    -0x448(%rbp),%r8
  cltq
  lea    0x10(%rbx,%rax,1),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L58
L41:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L41
L58:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L11
L50:
  mov    %r8,%rsi
  mov    %rsp,%rdi
  movb   $0x0,(%rsp)
  call   <strcat@plt>
  mov    %r15,%rsi
  mov    %rsp,%rdi
  call   <strcat@plt>
  mov    %rsp,%rdx
  lea    D7(%rip),%rsi
  mov    %r14d,%edi
  call   <syslog@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L11:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L50
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D1: %s: 

tool: D7: %s

assistant: ```c
_log_tag(int log_level, const char *src, const char *format, va_list argptr) {
  const size_t n_prefix = strlen(src) + 1 + 1 + 1;
  char prefix[n_prefix];
  sprintf(prefix, "%s: ", src);
  char suffix[1024];
  vsnprintf(suffix, sizeof(suffix), format, argptr);
  const size_t n_suffix = strlen(suffix);
  char log_msg[n_prefix + n_suffix + 1];
  log_msg[0] = '\0';
  strcat(log_msg, prefix);
  strcat(log_msg, suffix);
  syslog(log_level, "%s", log_msg);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test(1, 2, 3);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(1, 2, 3);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(1, 2, 3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test(1, 2, 3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L7
L13:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x8(%rbp)
L7:
  cmpq   $0x0,-0x8(%rbp)
  jne    L13
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int split(char *args[], char *str, const char *spl) {
  int n = 0;
  char *result = NULL;
  result = strtok(str, spl);
  while (result != NULL) {
    args[n] = (char *)malloc(sizeof(char) * (strlen(result) + 1));
    strcpy(args[n++], result);
    result = strtok(NULL, spl);
  }
  return n;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<split>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rdx,%r12
  mov    %rdx,%rsi
  call   <strtok@plt>
  test   %rax,%rax
  je     L20
  mov    %rax,%rbx
  mov    $0x1,%ebp
L9:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,-0x8(%r13,%rbp,8)
  mov    %ebp,%r14d
  mov    %rbx,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rbx
  add    $0x1,%rbp
  test   %rax,%rax
  jne    L9
L25:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    $0x0,%r14d
  jmp    L25
```

assistant: ```c
int split(char *args[], char *str, const char *spl) {
  int n = 0;
  char *result = NULL;
  result = strtok(str, spl);
  while (result != NULL) {
    args[n] = (char *)malloc(sizeof(char) * (strlen(result) + 1));
    strcpy(args[n++], result);
    result = strtok(NULL, spl);
  }
  return n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<split>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  call   <strtok@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rdi
  mov    %ebx,%r14d
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,-0x8(%r13,%rbx,8)
  mov    %rax,%rdi
  add    $0x1,%rbx
  call   <strcpy@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L13
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L6:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int split(char *args[], char *str, const char *spl) {
  int n = 0;
  char *result = NULL;
  result = strtok(str, spl);
  while (result != NULL) {
    args[n] = (char *)malloc(sizeof(char) * (strlen(result) + 1));
    strcpy(args[n++], result);
    result = strtok(NULL, spl);
  }
  return n;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<split>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  call   <strtok@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbp
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  mov    %ebx,%r14d
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,-0x8(%r13,%rbx,8)
  mov    %rax,%rdi
  add    $0x1,%rbx
  call   <strcpy@plt>
  mov    %r12,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L14
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L11:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int split(char *args[], char *str, const char *spl) {
  int n = 0;
  char *result = NULL;
  result = strtok(str, spl);
  while (result != NULL) {
    args[n] = (char *)malloc(sizeof(char) * (strlen(result) + 1));
    strcpy(args[n++], result);
    result = strtok(NULL, spl);
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_str_array_diff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D43(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D31(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,-0x40(%rbp)
  lea    D43(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D31(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D67(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x3,-0x54(%rbp)
  mov    -0x54(%rbp),%edx
  lea    -0x30(%rbp),%rcx
  lea    -0x50(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <str_array_diff@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D43
type: string
name: parse_data
arguments: data_tag: D31
type: string
name: parse_data
arguments: data_tag: D67
type: string
name: parse_data
arguments: data_tag: D38
type: string

tool: D43: dog

tool: D31: cat

tool: D67: monkey

tool: D38: rat

assistant: ```c
void test_str_array_diff() {
  char *first[] = {"dog", "cat", "monkey"};
  char *second[] = {"dog", "cat", "rat", "monkey"};
  int size = 3;
  str_array_diff(first, second, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_str_array_diff>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rcx
  mov    %rcx,(%rsp)
  lea    D12(%rip),%rdx
  mov    %rdx,0x8(%rsp)
  lea    D11(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    %rcx,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  lea    D33(%rip),%rcx
  mov    %rcx,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  mov    $0x3,%edx
  call   <str_array_diff@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D12
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string

tool: D15: dog

tool: D12: cat

tool: D11: monkey

tool: D33: rat

assistant: ```c
void test_str_array_diff() {
  char *first[] = {"dog", "cat", "monkey"};
  char *second[] = {"dog", "cat", "rat", "monkey"};
  int size = 3;
  str_array_diff(first, second, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_str_array_diff>:
  endbr64
  sub    $0x58,%rsp
  lea    D5(%rip),%rcx
  lea    D30(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  mov    %rcx,(%rsp)
  mov    %rsp,%rdi
  lea    D18(%rip),%rax
  mov    %rdx,0x8(%rsp)
  mov    %rcx,0x20(%rsp)
  lea    D8(%rip),%rcx
  mov    %rdx,0x28(%rsp)
  mov    $0x3,%edx
  mov    %rax,0x10(%rsp)
  mov    %rcx,0x30(%rsp)
  mov    %rax,0x38(%rsp)
  call   <str_array_diff@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x58,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string
name: read_data
arguments: data_tag: D30
data_type: string
name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D8
data_type: string

tool: D5: dog

tool: D30: cat

tool: D18: monkey

tool: D8: rat

assistant: ```c
void test_str_array_diff() {
  char *first[] = {"dog", "cat", "monkey"};
  char *second[] = {"dog", "cat", "rat", "monkey"};
  int size = 3;
  str_array_diff(first, second, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_str_array_diff>:
  endbr64
  sub    $0x58,%rsp
  lea    D5(%rip),%rcx
  lea    D13(%rip),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  lea    D16(%rip),%rax
  movq   %rcx,%xmm0
  lea    0x20(%rsp),%rsi
  mov    %rsp,%rdi
  movq   %rax,%xmm1
  lea    D37(%rip),%rax
  punpcklqdq %xmm1,%xmm0
  movq   %rax,%xmm2
  mov    %rax,0x10(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x20(%rsp)
  movq   %rdx,%xmm0
  mov    $0x3,%edx
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x30(%rsp)
  call   <str_array_diff@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string

tool: D5: dog

tool: D13: rat

tool: D16: cat

tool: D37: monkey

assistant: ```c
void test_str_array_diff() {
  char *first[] = {"dog", "cat", "monkey"};
  char *second[] = {"dog", "cat", "rat", "monkey"};
  int size = 3;
  str_array_diff(first, second, size);
}
```