ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L32:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L31
  mov    -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L31:
  cmpl   $0x20,-0x4(%rbp)
  je     L43
  cmpl   $0x9,-0x4(%rbp)
  je     L43
  cmpl   $0xa,-0x4(%rbp)
  jne    L23
L43:
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x1,-0x8(%rbp)
L23:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L32
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int input, state;
  state = 0;
  while ((input = getchar()) != EOF) {
    if (input != EOF)
      putchar(input);
    if (input == ' ' || input == '\t' || input == '\n') {
      putchar('\n');
      state = 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  jmp    L49
L41:
  mov    $0xa,%edi
  call   <putchar@plt>
L49:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D6(%rip),%rax
  cmp    %ebx,(%rax)
  je     L13
  movsbl %bl,%edi
  call   <putchar@plt>
  lea    -0x9(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L41
  cmp    $0x20,%ebx
  jne    L49
  jmp    L41
L13:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int input, state;
  state = 0;
  while ((input = getchar()) != EOF) {
    if (input != EOF)
      putchar(input);
    if (input == ' ' || input == '\t' || input == '\n') {
      putchar('\n');
      state = 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D3(%rip),%rbp
L31:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%rbp)
  je     L28
L11:
  movsbl %bl,%edi
  call   <putchar@plt>
  lea    -0x9(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L38
  cmp    $0x20,%ebx
  jne    L31
L38:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%rbp)
  jne    L11
L28:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int input, state;
  state = 0;
  while ((input = getchar()) != EOF) {
    if (input != EOF)
      putchar(input);
    if (input == ' ' || input == '\t' || input == '\n') {
      putchar('\n');
      state = 1;
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbp
L22:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%rbp)
  je     L39
L34:
  movsbl %bl,%edi
  call   <putchar@plt>
  lea    -0x9(%rbx),%eax
  cmp    $0x1,%eax
  jbe    L7
  cmp    $0x20,%ebx
  jne    L22
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%rbp)
  jne    L34
L39:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int input, state;
  state = 0;
  while ((input = getchar()) != EOF) {
    if (input != EOF)
      putchar(input);
    if (input == ' ' || input == '\t' || input == '\n') {
      putchar('\n');
      state = 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  D16(%rip),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L23:
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L57:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  divsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L57
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L31:
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x18(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  imul   $0x2580,%rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  divsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L31
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: f64
name: parse_data
arguments: tag: D5
type_guessed: f64

tool: D16: 1.5

tool: D5: 1

assistant: ```c
void init_array(int m, int n, double *alpha, double A[1000 + 0][1000 + 0], double B[1000 + 0][1200 + 0]) {
  int i, j;
  *alpha = 1.5;
  for (i = 0; i < m; i++) {
    for (j = 0; j < i; j++) {
      A[i][j] = (double)((i + j) % m) / m;
    }
    A[i][i] = 1.0;
    for (j = 0; j < n; j++) {
      B[i][j] = (double)((n + (i - j)) % n) / n;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<init_array>:
  endbr64
  mov    D10(%rip),%rax
  mov    %rax,(%rdx)
  test   %edi,%edi
  jle    L10
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%r13
  mov    %r8,%r12
  lea    0x1f40(%rcx),%rbp
  lea    -0x1(%rdi),%r14d
  mov    %esi,%r10d
  mov    $0x2,%r9d
  mov    $0x0,%ebx
  movsd  D17(%rip),%xmm2
  mov    %esi,%r11d
  jmp    L29
L75:
  mov    %rbp,%r15
  mov    $0x1,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
L50:
  lea    (%r8,%rcx,1),%eax
  cltd
  idiv   %edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r15,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L50
L31:
  add    $0x1,%rbx
  add    $0x1f48,%r13
  add    $0x1,%r10d
  add    $0x2580,%r12
  add    $0x1f40,%rbp
  add    $0x1,%r9
L29:
  mov    %ebx,%r8d
  movsd  %xmm2,0x0(%r13)
  test   %esi,%esi
  jle    L74
  mov    %r12,%r15
  mov    $0x0,%ecx
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
L55:
  mov    %r10d,%eax
  sub    %ecx,%eax
  cltd
  idiv   %esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r15,%rcx,8)
  add    $0x1,%rcx
  cmp    %r11,%rcx
  jne    L55
L74:
  cmp    %r14,%rbx
  je     L79
  lea    0x1(%r8),%eax
  test   %eax,%eax
  jg     L75
  jmp    L31
L79:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  ret
```

tool_calls: name: read_data
arguments: label: D10
type_guessed: f64
name: read_data
arguments: label: D17
type_guessed: f64

tool: D10: 1.5

tool: D17: 1

assistant: ```c
void init_array(int m, int n, double *alpha, double A[1000 + 0][1000 + 0], double B[1000 + 0][1200 + 0]) {
  int i, j;
  *alpha = 1.5;
  for (i = 0; i < m; i++) {
    for (j = 0; j < i; j++) {
      A[i][j] = (double)((i + j) % m) / m;
    }
    A[i][i] = 1.0;
    for (j = 0; j < n; j++) {
      B[i][j] = (double)((n + (i - j)) % n) / n;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<init_array>:
  endbr64
  mov    D11(%rip),%rax
  mov    %rax,(%rdx)
  test   %edi,%edi
  jle    L17
  push   %r14
  mov    %esi,%r10d
  lea    -0x1(%rdi),%r14d
  mov    $0x2,%r9d
  push   %r13
  movsd  D19(%rip),%xmm2
  mov    %rcx,%r13
  lea    0x1f40(%rcx),%r11
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %r12d,%ebx
  movsd  %xmm2,0x0(%r13)
  test   %esi,%esi
  jle    L54
  pxor   %xmm1,%xmm1
  xor    %ecx,%ecx
  cvtsi2sd %esi,%xmm1
  nop
L24:
  mov    %r10d,%eax
  pxor   %xmm0,%xmm0
  sub    %ecx,%eax
  cltd
  idiv   %esi
  mov    %rcx,%rax
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %rbp,%rax
  jne    L24
L54:
  cmp    %r14,%r12
  je     L0
  pxor   %xmm1,%xmm1
  mov    $0x1,%ecx
  cvtsi2sd %edi,%xmm1
  nopl   0x0(%rax,%rax,1)
L28:
  lea    (%rbx,%rcx,1),%eax
  pxor   %xmm0,%xmm0
  cltd
  idiv   %edi
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r11,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L28
  add    $0x1,%r12
  add    $0x1,%r10d
  add    $0x1f48,%r13
  add    $0x2580,%r8
  add    $0x1f40,%r11
  add    $0x1,%r9
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
type: f64
name: extract_symbolic_data
arguments: label: D19
type: f64

tool: D11: 1.5

tool: D19: 1

assistant: ```c
void init_array(int m, int n, double *alpha, double A[1000 + 0][1000 + 0], double B[1000 + 0][1200 + 0]) {
  int i, j;
  *alpha = 1.5;
  for (i = 0; i < m; i++) {
    for (j = 0; j < i; j++) {
      A[i][j] = (double)((i + j) % m) / m;
    }
    A[i][i] = 1.0;
    for (j = 0; j < n; j++) {
      B[i][j] = (double)((n + (i - j)) % n) / n;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<init_array>:
  endbr64
  mov    D4(%rip),%rax
  mov    %rax,(%rdx)
  test   %edi,%edi
  jle    L43
  push   %r14
  mov    %esi,%r10d
  lea    -0x1(%rdi),%r14d
  mov    $0x2,%r9d
  push   %r13
  movsd  D18(%rip),%xmm2
  mov    %rcx,%r13
  lea    0x1f40(%rcx),%r11
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %r12d,%ebx
  movsd  %xmm2,0x0(%r13)
  test   %esi,%esi
  jle    L3
  pxor   %xmm1,%xmm1
  xor    %ecx,%ecx
  cvtsi2sd %esi,%xmm1
  nop
L53:
  mov    %r10d,%eax
  pxor   %xmm0,%xmm0
  sub    %ecx,%eax
  cltd
  idiv   %esi
  mov    %rcx,%rax
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%r8,%rcx,8)
  add    $0x1,%rcx
  cmp    %rax,%rbp
  jne    L53
L3:
  cmp    %r14,%r12
  je     L51
  pxor   %xmm1,%xmm1
  mov    $0x1,%ecx
  cvtsi2sd %edi,%xmm1
  nopl   0x0(%rax,%rax,1)
L16:
  lea    (%rbx,%rcx,1),%eax
  pxor   %xmm0,%xmm0
  cltd
  idiv   %edi
  cvtsi2sd %edx,%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r11,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L16
  add    $0x1,%r12
  add    $0x1,%r10d
  add    $0x1f48,%r13
  add    $0x2580,%r8
  add    $0x1f40,%r11
  add    $0x1,%r9
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: f64
name: unpack_data
arguments: label: D18
type_infered: f64

tool: D4: 1.5

tool: D18: 1

assistant: ```c
void init_array(int m, int n, double *alpha, double A[1000 + 0][1000 + 0], double B[1000 + 0][1200 + 0]) {
  int i, j;
  *alpha = 1.5;
  for (i = 0; i < m; i++) {
    for (j = 0; j < i; j++) {
      A[i][j] = (double)((i + j) % m) / m;
    }
    A[i][i] = 1.0;
    for (j = 0; j < n; j++) {
      B[i][j] = (double)((n + (i - j)) % n) / n;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_replaceChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  jmp    L12
L5:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0xc(%rbp)
  jne    L29
  mov    -0x8(%rbp),%rax
  movzbl -0x10(%rbp),%edx
  mov    %dl,(%rax)
L29:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void str_replaceChar(char *pStr, char c1, char c2) {
  while (*pStr) {
    if (*pStr == c1)
      *pStr = c2;
    ++pStr;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_replaceChar>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L11
L35:
  ret
L23:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L35
L11:
  cmp    %al,%sil
  jne    L23
  mov    %dl,(%rdi)
  jmp    L23
```

assistant: ```c
void str_replaceChar(char *pStr, char c1, char c2) {
  while (*pStr) {
    if (*pStr == c1)
      *pStr = c2;
    ++pStr;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_replaceChar>:
  endbr64
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L26:
  cmp    %al,%sil
  jne    L27
  mov    %dl,(%rdi)
L27:
  add    $0x1,%rdi
L6:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L26
  ret
```

assistant: ```c
void str_replaceChar(char *pStr, char c1, char c2) {
  while (*pStr) {
    if (*pStr == c1)
      *pStr = c2;
    ++pStr;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_replaceChar>:
  endbr64
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L35:
  add    $0x1,%rdi
L38:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L12
L22:
  cmp    %al,%sil
  jne    L35
  mov    %dl,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L22
  ret
  nop
L12:
  ret
```

assistant: ```c
void str_replaceChar(char *pStr, char c1, char c2) {
  while (*pStr) {
    if (*pStr == c1)
      *pStr = c2;
    ++pStr;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_blk2link>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  lea    0x3(%rax),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <lswap4@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
long read_blk2link(unsigned char *datablk) {
  long link;
  memmove((unsigned char *)&link, datablk + 3, sizeof(long));
  return lswap4(link);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_blk2link>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3(%rdi),%rsi
  mov    %rsp,%rdi
  mov    $0x8,%edx
  call   <memmove@plt>
  mov    (%rsp),%rdi
  call   <lswap4@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long read_blk2link(unsigned char *datablk) {
  long link;
  memmove((unsigned char *)&link, datablk + 3, sizeof(long));
  return lswap4(link);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_blk2link>:
  endbr64
  sub    $0x18,%rsp
  lea    0x3(%rdi),%rsi
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memmove@plt>
  mov    (%rsp),%rdi
  call   <lswap4@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long read_blk2link(unsigned char *datablk) {
  long link;
  memmove((unsigned char *)&link, datablk + 3, sizeof(long));
  return lswap4(link);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_blk2link>:
  endbr64
  sub    $0x18,%rsp
  lea    0x3(%rdi),%rsi
  mov    $0x8,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memmove@plt>
  mov    (%rsp),%rdi
  call   <lswap4@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long read_blk2link(unsigned char *datablk) {
  long link;
  memmove((unsigned char *)&link, datablk + 3, sizeof(long));
  return lswap4(link);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mon_sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    $0x0,%eax
  call   <monLock@plt>
  mov    -0x30(%rbp),%r9d
  mov    -0x2c(%rbp),%r8d
  mov    -0x28(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    0x48(%rbp),%edi
  push   %rdi
  mov    0x40(%rbp),%edi
  push   %rdi
  mov    0x38(%rbp),%edi
  push   %rdi
  mov    0x30(%rbp),%edi
  push   %rdi
  mov    0x28(%rbp),%edi
  push   %rdi
  mov    0x20(%rbp),%edi
  push   %rdi
  mov    0x18(%rbp),%edi
  push   %rdi
  mov    0x10(%rbp),%edi
  push   %rdi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_sprintf@plt>
  add    $0x40,%rsp
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <monUnlock@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mon_sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12)
char *fmt, *buf;
int a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12;
{
  int ret;
  monLock();
  ret = _sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12);
  monUnlock();
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mon_sprintf>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%r14d
  mov    %r9d,%r15d
  mov    $0x0,%eax
  call   <monLock@plt>
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    %r15d,%r9d
  mov    %r14d,%r8d
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <_sprintf@plt>
  mov    %eax,%ebx
  add    $0x40,%rsp
  mov    $0x0,%eax
  call   <monUnlock@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int mon_sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12)
char *fmt, *buf;
int a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12;
{
  int ret;
  monLock();
  ret = _sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12);
  monUnlock();
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mon_sprintf>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %r9d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x8,%rsp
  call   <monLock@plt>
  mov    0x78(%rsp),%eax
  mov    %r15d,%r9d
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  xor    %eax,%eax
  call   <_sprintf@plt>
  add    $0x40,%rsp
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <monUnlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int mon_sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12)
char *fmt, *buf;
int a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12;
{
  int ret;
  monLock();
  ret = _sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12);
  monUnlock();
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mon_sprintf>:
  endbr64
  push   %r15
  xor    %eax,%eax
  mov    %r9d,%r15d
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x8,%rsp
  call   <monLock@plt>
  mov    0x78(%rsp),%eax
  mov    %r15d,%r9d
  mov    %ebx,%r8d
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  mov    0x78(%rsp),%eax
  push   %rax
  xor    %eax,%eax
  call   <_sprintf@plt>
  add    $0x40,%rsp
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <monUnlock@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int mon_sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12)
char *fmt, *buf;
int a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12;
{
  int ret;
  monLock();
  ret = _sprintf(buf, fmt, a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12);
  monUnlock();
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f11>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x210(%rbp),%rax
  mov    $0x100,%edx
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  lea    -0x210(%rbp),%rcx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D16
type_guessed: string
name: unpack_data
arguments: label: D0
type_guessed: string

tool: D16: world

tool: D0: hello 

assistant: ```c
void f11() {
  char a[256], b[256];
  strlcpy(a, "world", sizeof(a));
  strlcpy(b, "hello ", sizeof(b));
  strlcat(b, a, sizeof(b));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f11>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x100,%edx
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <strlcpy@plt>
  lea    0x100(%rsp),%rbx
  mov    $0x100,%edx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strlcpy@plt>
  mov    $0x100,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strlcat@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string
name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D2: world

tool: D4: hello 

assistant: ```c
void f11() {
  char a[256], b[256];
  strlcpy(a, "world", sizeof(a));
  strlcpy(b, "hello ", sizeof(b));
  strlcat(b, a, sizeof(b));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f11>:
  endbr64
  push   %r12
  mov    $0x100,%edx
  lea    D0(%rip),%rsi
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x100(%rsp),%rbp
  mov    %r12,%rdi
  call   <strlcpy@plt>
  mov    $0x100,%edx
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <strlcpy@plt>
  mov    $0x100,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strlcat@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x218,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string

tool: D0: world

tool: D10: hello 

assistant: ```c
void f11() {
  char a[256], b[256];
  strlcpy(a, "world", sizeof(a));
  strlcpy(b, "hello ", sizeof(b));
  strlcat(b, a, sizeof(b));
}
```