ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<decode_pl>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    0x1(%rdx),%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmpl   $0xff,(%rdi)
  je     L3
  movslq %edx,%rax
  mov    %rdi,%r15
  mov    %edx,%r12d
  mov    %rax,0x10(%rsp)
  lea    0x0(,%rax,4),%rbx
  mov    %rdi,%rax
  xor    %edi,%edi
  nopl   (%rax)
L62:
  add    %rbx,%rax
  mov    %edi,%ebp
  lea    0x1(%rdi),%edi
  cmpl   $0xff,(%rax)
  jne    L62
  mov    %r13d,%esi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L69
  movslq %r13d,%rsi
  mov    %rax,%r13
  add    $0x2,%rax
  xor    %r14d,%r14d
  mov    %rsi,0x8(%rsp)
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r15,%rsi
  mov    %r13,%rdi
  mov    %r12d,%edx
  add    %rbx,%r15
  call   <memcpy@plt>
  add    0x8(%rsp),%r13
  cmp    %r14d,%ebp
  je     L0
  mov    (%rsp),%rax
  mov    0x10(%rsp),%rcx
  add    $0x1,%r14d
  movb   $0x2c,(%rax)
  add    %rcx,%rax
  mov    %rax,(%rsp)
  jmp    L5
  nopl   0x0(%rax)
L3:
  mov    %r13d,%esi
  xor    %edi,%edi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L69
L0:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  movq   $0xffffffffffffffff,0x18(%rsp)
  jmp    L0
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: calloc()

assistant: ```c
char *decode_pl(uint8_t *data, int data_len, int record_len) {
  int rec_cnt = 0;
  uint8_t *tmpdata = data;
  while (*tmpdata != 0xFF) {
    rec_cnt++;
    tmpdata += record_len;
  }
  char *pl_ascii;
  if ((pl_ascii = calloc(rec_cnt, record_len + 1)) == NULL) {
    perror("calloc()");
    return (char *)-1;
  }
  int i;
  for (i = 0; i < rec_cnt; i++) {
    memcpy(pl_ascii + (record_len + 1) * i, data + record_len * i, record_len);
    if (i + 1 < rec_cnt)
      *(pl_ascii + record_len * i + 2) = ',';
  }
  return pl_ascii;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decode_pl>:
  endbr64
  push   %r15
  push   %r14
  lea    0x1(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmpl   $0xff,(%rdi)
  je     L40
  movslq %edx,%rax
  mov    %rdi,%r12
  mov    %edx,%r13d
  mov    %rax,0x10(%rsp)
  lea    0x0(,%rax,4),%rbx
  mov    %rdi,%rax
  xor    %edi,%edi
  cmp    $0x1,%edx
  jne    L4
  nopw   0x0(%rax,%rax,1)
L44:
  add    %rbx,%rax
  mov    %edi,0x4(%rsp)
  add    $0x1,%edi
  cmpl   $0xff,(%rax)
  jne    L44
L90:
  mov    %r14d,%esi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L80
  movslq %r14d,%rcx
  mov    %rax,%rbp
  mov    %r12,%r14
  xor    %r15d,%r15d
  mov    %rcx,0x8(%rsp)
  lea    0x2(%rax),%r12
  nopl   (%rax)
L47:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  add    %rbx,%r14
  call   <memcpy@plt>
  add    0x8(%rsp),%rbp
  cmp    0x4(%rsp),%r15d
  je     L39
  movb   $0x2c,(%r12)
  add    $0x1,%r15d
  add    0x10(%rsp),%r12
  jmp    L47
  nopl   (%rax)
L4:
  add    %rbx,%rax
  mov    %edi,0x4(%rsp)
  add    $0x1,%edi
  cmpl   $0xff,(%rax)
  jne    L4
  jmp    L90
  nopl   0x0(%rax)
L40:
  mov    %r14d,%esi
  xor    %edi,%edi
  call   <calloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L80
L39:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L80:
  lea    D1(%rip),%rdi
  call   <perror@plt>
  movq   $0xffffffffffffffff,0x18(%rsp)
  jmp    L39
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
datatype: string

tool: D1: calloc()

assistant: ```c
char *decode_pl(uint8_t *data, int data_len, int record_len) {
  int rec_cnt = 0;
  uint8_t *tmpdata = data;
  while (*tmpdata != 0xFF) {
    rec_cnt++;
    tmpdata += record_len;
  }
  char *pl_ascii;
  if ((pl_ascii = calloc(rec_cnt, record_len + 1)) == NULL) {
    perror("calloc()");
    return (char *)-1;
  }
  int i;
  for (i = 0; i < rec_cnt; i++) {
    memcpy(pl_ascii + (record_len + 1) * i, data + record_len * i, record_len);
    if (i + 1 < rec_cnt)
      *(pl_ascii + record_len * i + 2) = ',';
  }
  return pl_ascii;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_arr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type: string

tool: D0: %d 

assistant: ```c
void print_arr(int *arr, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_arr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D3(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: %d 

assistant: ```c
void print_arr(int *arr, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: %d 

assistant: ```c
void print_arr(int *arr, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_arr>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L18:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L18
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: %d 

assistant: ```c
void print_arr(int *arr, int num_elem) {
  for (int i = 0; i < num_elem; i++) {
    printf("%d ", arr[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L15
L16:
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L15:
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x2c(%rbp)
  test   %eax,%eax
  jne    L16
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D26
type: string

tool: D18: %i

tool: D3: %lf %lf

tool: D26: %.3lf


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  double i, j;
  scanf("%i", &n);
  while (n--) {
    scanf("%lf %lf", &i, &j);
    printf("%.3lf\n", (log(i) / log(j)));
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L9
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    D2(%rip),%r12
  lea    D28(%rip),%rbp
L10:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  mov    %eax,%ebx
  movsd  0x10(%rsp),%xmm0
  call   <log@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L10
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
datatype: string
name: retrieve_data
arguments: tag: D2
datatype: string
name: retrieve_data
arguments: tag: D28
datatype: string

tool: D19: %i

tool: D2: %lf %lf

tool: D28: %.3lf


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  double i, j;
  scanf("%i", &n);
  while (n--) {
    scanf("%lf %lf", &i, &j);
    printf("%.3lf\n", (log(i) / log(j)));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D23(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L21
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    D3(%rip),%r12
  lea    D19(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %eax,%ebx
  call   <log@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L10
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D23
datatype: string
name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D19
datatype: string

tool: D23: %i

tool: D3: %lf %lf

tool: D19: %.3lf


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  double i, j;
  scanf("%i", &n);
  while (n--) {
    scanf("%lf %lf", &i, &j);
    printf("%.3lf\n", (log(i) / log(j)));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D26(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L15
  lea    0x10(%rsp),%r14
  lea    0x8(%rsp),%r13
  lea    D16(%rip),%r12
  lea    D4(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %eax,%ebx
  call   <log@plt>
  mov    %rbp,%rdi
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L1
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type_guessed: string
name: extract_symbolic_data
arguments: tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D26: %i

tool: D16: %lf %lf

tool: D4: %.3lf


assistant: ```c
int main(int argc, char *argv[]) {
  int n;
  double i, j;
  scanf("%i", &n);
  while (n--) {
    scanf("%lf %lf", &i, &j);
    printf("%.3lf\n", (log(i) / log(j)));
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L51
L76:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x4,%ecx
  sub    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L44
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L33
L44:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L31
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L33
L31:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L13
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L33
L13:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L33:
  addl   $0x1,-0x4(%rbp)
L51:
  cmpl   $0x64,-0x4(%rbp)
  jle    L76
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D12
type_infered: string
name: extract_symbolic_data
arguments: label: D31
type_infered: string

tool: D10: fizzbuzz

tool: D19: fizz

tool: D12: buzz

tool: D31: %d


assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 100; i++) {
    if (i % 15 == 0) {
      printf("fizzbuzz\n");
    } else if (i % 3 == 0) {
      printf("fizz\n");
    } else if (i % 5 == 0) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  lea    D13(%rip),%r13
  lea    D23(%rip),%r12
  lea    D19(%rip),%r14
  lea    D24(%rip),%rbp
  jmp    L13
L76:
  mov    %rbp,%rdi
  call   <puts@plt>
L51:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L11
L13:
  movslq %ebx,%rax
  imul   $0xffffffff88888889,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x3,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  sub    %eax,%edx
  cmp    %edx,%ebx
  je     L76
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L16
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebx
  jne    L31
  mov    %r12,%rdi
  call   <puts@plt>
  jmp    L51
L16:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L51
L31:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L51
L11:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D23
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D24
type_guessed: string

tool: D13: %d


tool: D23: buzz

tool: D19: fizz

tool: D24: fizzbuzz

assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 100; i++) {
    if (i % 15 == 0) {
      printf("fizzbuzz\n");
    } else if (i % 3 == 0) {
      printf("fizz\n");
    } else if (i % 5 == 0) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D23(%rip),%r14
  push   %r13
  lea    D39(%rip),%r13
  push   %r12
  lea    D35(%rip),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L62
  nop
L26:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  jbe    L58
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L71
  mov    %r12,%rdi
  call   <puts@plt>
L69:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L66
L62:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  ja     L26
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L62
L66:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L69
```

tool_calls: name: disassemble_data
arguments: label: D23
type_infered: string
name: disassemble_data
arguments: label: D39
type_infered: string
name: disassemble_data
arguments: label: D35
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D23: fizz

tool: D39: %d


tool: D35: buzz

tool: D4: fizzbuzz

assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 100; i++) {
    if (i % 15 == 0) {
      printf("fizzbuzz\n");
    } else if (i % 3 == 0) {
      printf("fizz\n");
    } else if (i % 5 == 0) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D15(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L53
  nop
L0:
  imul   $0xaaaaaaab,%ebx,%eax
  cmp    $0x55555555,%eax
  jbe    L62
  imul   $0xcccccccd,%ebx,%eax
  cmp    $0x33333333,%eax
  ja     L79
  mov    %r12,%rdi
  call   <puts@plt>
L71:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L33
L53:
  imul   $0xeeeeeeef,%ebx,%eax
  cmp    $0x11111111,%eax
  ja     L0
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <puts@plt>
  cmp    $0x65,%ebx
  jne    L53
L33:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L79:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L71
  cs nopw 0x0(%rax,%rax,1)
L62:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L71
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string
name: extract_symbolic_data
arguments: data_tag: D11
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: string
name: extract_symbolic_data
arguments: data_tag: D15
data_type: string

tool: D1: fizz

tool: D11: %d


tool: D21: buzz

tool: D15: fizzbuzz

assistant: ```c
int main() {
  int i;
  for (i = 1; i <= 100; i++) {
    if (i % 15 == 0) {
      printf("fizzbuzz\n");
    } else if (i % 3 == 0) {
      printf("fizz\n");
    } else if (i % 5 == 0) {
      printf("buzz\n");
    } else {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<delete_spaces1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L91
L190:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L129
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L129
  addq   $0x1,-0x18(%rbp)
  jmp    L91
L129:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L214
L105:
  addq   $0x1,-0x8(%rbp)
L214:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L105
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L105
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x60,-0x10(%rbp)
  jle    L92
  cmpl   $0x7a,-0x10(%rbp)
  jle    L215
L92:
  cmpl   $0x40,-0x10(%rbp)
  jle    L64
  cmpl   $0x5a,-0x10(%rbp)
  jle    L215
L64:
  cmpl   $0x2f,-0x10(%rbp)
  jle    L49
  cmpl   $0x39,-0x10(%rbp)
  jle    L215
L49:
  cmpl   $0x5f,-0x10(%rbp)
  jne    L212
L215:
  cmpl   $0x60,-0xc(%rbp)
  jle    L67
  cmpl   $0x7a,-0xc(%rbp)
  jle    L138
L67:
  cmpl   $0x40,-0xc(%rbp)
  jle    L121
  cmpl   $0x5a,-0xc(%rbp)
  jle    L138
L121:
  cmpl   $0x2f,-0xc(%rbp)
  jle    L3
  cmpl   $0x39,-0xc(%rbp)
  jle    L138
L3:
  cmpl   $0x5f,-0xc(%rbp)
  je     L138
L212:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  addq   $0x1,-0x18(%rbp)
  jmp    L91
L138:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcpy@plt>
  addq   $0x1,-0x18(%rbp)
L91:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L190
  nop
  nop
  leave
  ret
```

assistant: ```c
void delete_spaces1(char *s) {
  char *p;
  int c1, c2;
  while (*s) {
    if (!((*s) == ' ' || (*s) == '\t')) {
      s++;
      continue;
    }
    for (p = s; ((*p) == ' ' || (*p) == '\t'); p++)
      ;
    c1 = *(s - 1);
    c2 = *p;
    if ((!(((c1) >= 'a' && (c1) <= 'z') || ((c1) >= 'A' && (c1) <= 'Z') || ((c1) >= '0' && (c1) <= '9')) && c1 != '_') || (!(((c2) >= 'a' && (c2) <= 'z') || ((c2) >= 'A' && (c2) <= 'Z') || ((c2) >= '0' && (c2) <= '9')) && c2 != '_')) {
      strcpy(s, p);
      s++;
    } else {
      strcpy(s + 1, p);
      s++;
    }
  }
}
```