ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D34(%rip),%rax
  movq   %rax,%xmm0
  call   <squareRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D16(%rip),%rax
  movq   %rax,%xmm0
  call   <squareRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    D12(%rip),%rax
  movq   %rax,%xmm0
  call   <squareRoot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D34
type: f64
name: read_data
arguments: data_tag: D47
type: string
name: read_data
arguments: data_tag: D16
type: byte[8]
name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D12
type: f64
name: read_data
arguments: data_tag: D14
type: string

tool: D34: 2

tool: D47: squareRoot(2.00) = %f


tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x62,0x40]}

tool: D11: squareRoot(144) = %f


tool: D12: 17.5

tool: D14: squareRoot(17.5) = %f


assistant: ```c
int main(void) {
  printf("squareRoot(2.00) = %f\n", squareRoot(2.00));
  printf("squareRoot(144) = %f\n", squareRoot(144));
  printf("squareRoot(17.5) = %f\n", squareRoot(17.5));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D46(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  movsd  D40(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  movsd  D35(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D46
type: f64
name: extract_symbolic_data
arguments: label: D13
type: string
name: extract_symbolic_data
arguments: label: D40
type: byte[8]
name: extract_symbolic_data
arguments: label: D48
type: string
name: extract_symbolic_data
arguments: label: D35
type: f64
name: extract_symbolic_data
arguments: label: D18
type: string

tool: D46: 2

tool: D13: squareRoot(2.00) = %f


tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x00,0x62,0x40]}

tool: D48: squareRoot(144) = %f


tool: D35: 17.5

tool: D18: squareRoot(17.5) = %f


assistant: ```c
int main(void) {
  printf("squareRoot(2.00) = %f\n", squareRoot(2.00));
  printf("squareRoot(144) = %f\n", squareRoot(144));
  printf("squareRoot(17.5) = %f\n", squareRoot(17.5));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D49(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  movsd  D39(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  movsd  D44(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D49
datatype: f64
name: unpack_data
arguments: tag: D29
datatype: string
name: unpack_data
arguments: tag: D39
datatype: byte[8]
name: unpack_data
arguments: tag: D19
datatype: string
name: unpack_data
arguments: tag: D44
datatype: f64
name: unpack_data
arguments: tag: D25
datatype: string

tool: D49: 2

tool: D29: squareRoot(2.00) = %f


tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x62,0x40]}

tool: D19: squareRoot(144) = %f


tool: D44: 17.5

tool: D25: squareRoot(17.5) = %f


assistant: ```c
int main(void) {
  printf("squareRoot(2.00) = %f\n", squareRoot(2.00));
  printf("squareRoot(144) = %f\n", squareRoot(144));
  printf("squareRoot(17.5) = %f\n", squareRoot(17.5));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D3(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  movsd  D45(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movsd  D14(%rip),%xmm0
  call   <squareRoot@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: f64
name: unpack_data
arguments: data_label: D15
data_type: string
name: unpack_data
arguments: data_label: D45
data_type: byte[8]
name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D14
data_type: f64
name: unpack_data
arguments: data_label: D44
data_type: string

tool: D3: 2

tool: D15: squareRoot(2.00) = %f


tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x62,0x40]}

tool: D10: squareRoot(144) = %f


tool: D14: 17.5

tool: D44: squareRoot(17.5) = %f


assistant: ```c
int main(void) {
  printf("squareRoot(2.00) = %f\n", squareRoot(2.00));
  printf("squareRoot(144) = %f\n", squareRoot(144));
  printf("squareRoot(17.5) = %f\n", squareRoot(17.5));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x64,-0x4(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L8
L13:
  movl   $0x1,-0x10(%rbp)
  jmp    L40
L71:
  movl   $0x1,-0xc(%rbp)
  jmp    L27
L81:
  movl   $0x1,-0x8(%rbp)
  jmp    L54
L5:
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <is_square@plt>
  test   %rax,%rax
  je     L56
  addl   $0x1,-0x18(%rbp)
L56:
  addl   $0x1,-0x8(%rbp)
L54:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L5
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L81
  addl   $0x1,-0x10(%rbp)
L40:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L71
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L13
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
data_type: string

tool: D8: answer: %d


assistant: ```c
int main() {
  int m = 100;
  int lp_square = 0;
  for (int a = 1; a <= m; a++) {
    for (int b = 1; b <= m; b++) {
      for (int c = 1; c <= m; c++) {
        for (int d = 1; d <= m; d++) {
          if (is_square(a, b, c, d))
            lp_square++;
        }
      }
    }
  }
  printf("answer: %d\n", lp_square);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%r13d
  mov    $0x0,%ebp
L35:
  mov    $0x1,%r14d
L14:
  mov    $0x1,%r12d
L26:
  mov    $0x1,%ebx
L23:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <is_square@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L23
  add    $0x1,%r12d
  cmp    $0x65,%r12d
  jne    L26
  add    $0x1,%r14d
  cmp    $0x65,%r14d
  jne    L14
  add    $0x1,%r13d
  cmp    $0x65,%r13d
  jne    L35
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: answer: %d


assistant: ```c
int main() {
  int m = 100;
  int lp_square = 0;
  for (int a = 1; a <= m; a++) {
    for (int b = 1; b <= m; b++) {
      for (int c = 1; c <= m; c++) {
        for (int d = 1; d <= m; d++) {
          if (is_square(a, b, c, d))
            lp_square++;
        }
      }
    }
  }
  printf("answer: %d\n", lp_square);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
L38:
  mov    $0x1,%r14d
L6:
  mov    $0x1,%r12d
L18:
  mov    $0x1,%ebx
  nopl   (%rax)
L14:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <is_square@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L14
  add    $0x1,%r12d
  cmp    $0x65,%r12d
  jne    L18
  add    $0x1,%r14d
  cmp    $0x65,%r14d
  jne    L6
  add    $0x1,%r13d
  cmp    $0x65,%r13d
  jne    L38
  mov    %ebp,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: answer: %d


assistant: ```c
int main() {
  int m = 100;
  int lp_square = 0;
  for (int a = 1; a <= m; a++) {
    for (int b = 1; b <= m; b++) {
      for (int c = 1; c <= m; c++) {
        for (int d = 1; d <= m; d++) {
          if (is_square(a, b, c, d))
            lp_square++;
        }
      }
    }
  }
  printf("answer: %d\n", lp_square);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
L22:
  mov    $0x1,%r14d
L35:
  mov    $0x1,%r12d
L34:
  mov    $0x1,%ebx
  nopl   (%rax)
L27:
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <is_square@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L27
  add    $0x1,%r12d
  cmp    $0x65,%r12d
  jne    L34
  add    $0x1,%r14d
  cmp    $0x65,%r14d
  jne    L35
  add    $0x1,%r13d
  cmp    $0x65,%r13d
  jne    L22
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
datatype: string

tool: D8: answer: %d


assistant: ```c
int main() {
  int m = 100;
  int lp_square = 0;
  for (int a = 1; a <= m; a++) {
    for (int b = 1; b <= m; b++) {
      for (int c = 1; c <= m; c++) {
        for (int d = 1; d <= m; d++) {
          if (is_square(a, b, c, d))
            lp_square++;
        }
      }
    }
  }
  printf("answer: %d\n", lp_square);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<crc32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L17:
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%eax
  shl    $0x18,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sar    $0x1c,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  xor    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sar    $0x1c,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  xor    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L12:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D10
type: string

tool: 

assistant: ```c
uint32_t crc32(uint8_t *buf, int len) {
  static const uint32_t table[16] = {
      0x00000000, 0x04C11DB7, 0x09823B6E, 0x0D4326D9, 0x130476DC, 0x17C56B6B, 0x1A864DB2, 0x1E475005, 0x2608EDB8, 0x22C9F00F, 0x2F8AD6D6, 0x2B4BCB61, 0x350C9B64, 0x31CD86D3, 0x3C8EA00A, 0x384FBDBD,
  };
  uint32_t crc = 0;
  while (len--) {
    crc ^= *buf++ << 24;
    crc = (crc << 4) ^ table[crc >> 28];
    crc = (crc << 4) ^ table[crc >> 28];
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc32>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L2
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%r8
  mov    $0x0,%esi
  lea    D3(%rip),%rdi
L9:
  add    $0x4,%rcx
  mov    -0x4(%rcx),%eax
  shl    $0x18,%eax
  xor    %esi,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  sar    $0x1c,%eax
  cltq
  xor    (%rdi,%rax,4),%edx
  mov    %edx,%esi
  shl    $0x4,%esi
  sar    $0x1c,%edx
  movslq %edx,%rdx
  xor    (%rdi,%rdx,4),%esi
  cmp    %r8,%rcx
  jne    L9
L2:
  mov    %esi,%eax
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string

tool: 

assistant: ```c
uint32_t crc32(uint8_t *buf, int len) {
  static const uint32_t table[16] = {
      0x00000000, 0x04C11DB7, 0x09823B6E, 0x0D4326D9, 0x130476DC, 0x17C56B6B, 0x1A864DB2, 0x1E475005, 0x2608EDB8, 0x22C9F00F, 0x2F8AD6D6, 0x2B4BCB61, 0x350C9B64, 0x31CD86D3, 0x3C8EA00A, 0x384FBDBD,
  };
  uint32_t crc = 0;
  while (len--) {
    crc ^= *buf++ << 24;
    crc = (crc << 4) ^ table[crc >> 28];
    crc = (crc << 4) ^ table[crc >> 28];
  }
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc32>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L16
  mov    %esi,%esi
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,4),%rdi
  lea    D8(%rip),%rsi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rcx),%eax
  add    $0x4,%rcx
  shl    $0x18,%eax
  xor    %r8d,%eax
  mov    %eax,%edx
  sar    $0x1c,%eax
  cltq
  shl    $0x4,%edx
  xor    (%rsi,%rax,4),%edx
  mov    %edx,%r8d
  sar    $0x1c,%edx
  movslq %edx,%rdx
  shl    $0x4,%r8d
  xor    (%rsi,%rdx,4),%r8d
  cmp    %rdi,%rcx
  jne    L18
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string

tool: 

assistant: ```c
uint32_t crc32(uint8_t *buf, int len) {
  static const uint32_t table[16] = {
      0x00000000, 0x04C11DB7, 0x09823B6E, 0x0D4326D9, 0x130476DC, 0x17C56B6B, 0x1A864DB2, 0x1E475005, 0x2608EDB8, 0x22C9F00F, 0x2F8AD6D6, 0x2B4BCB61, 0x350C9B64, 0x31CD86D3, 0x3C8EA00A, 0x384FBDBD,
  };
  uint32_t crc = 0;
  while (len--) {
    crc ^= *buf++ << 24;
    crc = (crc << 4) ^ table[crc >> 28];
    crc = (crc << 4) ^ table[crc >> 28];
  }
  return crc;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crc32>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L8
  mov    %esi,%esi
  xor    %r8d,%r8d
  lea    (%rdi,%rsi,4),%rdi
  lea    D6(%rip),%rsi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rcx),%eax
  add    $0x4,%rcx
  shl    $0x18,%eax
  xor    %r8d,%eax
  mov    %eax,%edx
  sar    $0x1c,%eax
  cltq
  shl    $0x4,%edx
  xor    (%rsi,%rax,4),%edx
  mov    %edx,%r8d
  sar    $0x1c,%edx
  movslq %edx,%rdx
  shl    $0x4,%r8d
  xor    (%rsi,%rdx,4),%r8d
  cmp    %rdi,%rcx
  jne    L18
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: 

assistant: ```c
uint32_t crc32(uint8_t *buf, int len) {
  static const uint32_t table[16] = {
      0x00000000, 0x04C11DB7, 0x09823B6E, 0x0D4326D9, 0x130476DC, 0x17C56B6B, 0x1A864DB2, 0x1E475005, 0x2608EDB8, 0x22C9F00F, 0x2F8AD6D6, 0x2B4BCB61, 0x350C9B64, 0x31CD86D3, 0x3C8EA00A, 0x384FBDBD,
  };
  uint32_t crc = 0;
  while (len--) {
    crc ^= *buf++ << 24;
    crc = (crc << 4) ^ table[crc >> 28];
    crc = (crc << 4) ^ table[crc >> 28];
  }
  return crc;
}
```
user: What is the c source code of the assembly code below:

```asm
<randomIndexArray>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L7:
  mov    $0x0,%eax
  call   <getCount@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *randomIndexArray(int size) {
  int i;
  int *idcs = malloc(size * sizeof(int));
  for (i = 0; i < size; i++) {
    idcs[i] = getCount() % size;
  }
  return idcs;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<randomIndexArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  lea    0x0(,%rdi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L18
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    0x0(%r13,%rax,4),%r12
L14:
  mov    $0x0,%eax
  call   <getCount@plt>
  cltd
  idiv   %ebp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
L18:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *randomIndexArray(int size) {
  int i;
  int *idcs = malloc(size * sizeof(int));
  for (i = 0; i < size; i++) {
    idcs[i] = getCount() % size;
  }
  return idcs;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<randomIndexArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L5
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    0x0(%r13,%rax,4),%r12
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <getCount@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L15
L5:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *randomIndexArray(int size) {
  int i;
  int *idcs = malloc(size * sizeof(int));
  for (i = 0; i < size; i++) {
    idcs[i] = getCount() % size;
  }
  return idcs;
}
```
user: Translate the below assembly code into C programming language:

```asm
<randomIndexArray>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  shl    $0x2,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L6
  mov    %rax,%rbx
  mov    %ebp,%eax
  lea    0x0(%r13,%rax,4),%r12
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <getCount@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L3
L6:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *randomIndexArray(int size) {
  int i;
  int *idcs = malloc(size * sizeof(int));
  for (i = 0; i < size; i++) {
    idcs[i] = getCount() % size;
  }
  return idcs;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<makeEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L65
L27:
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L61
L51:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L54
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L54:
  addl   $0x1,-0xc(%rbp)
L61:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L51
L14:
  cmpl   $0x1,-0x4(%rbp)
  jne    L25
  addl   $0x1,-0x8(%rbp)
L25:
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, c, k;
  c = 0;
  for (i = 0; i < n1; i++) {
    k = 0;
    for (j = 0; j < n2; j++) {
      if (*(s1 + i) == *(s2 + j)) {
        *(s2 + j) = 0;
        k = 1;
        break;
      }
    }
    if (k == 1)
      c = c + 1;
  }
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<makeEqual>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    %rdi,%r9
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r11
  mov    $0x0,%r10d
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%r8
  jmp    L39
L32:
  movb   $0x0,(%rax)
  add    $0x1,%r10d
L63:
  add    $0x1,%r9
  cmp    %r11,%r9
  je     L67
L39:
  test   %ecx,%ecx
  jle    L63
  movzbl (%r9),%esi
  mov    %rdx,%rax
L27:
  cmp    (%rax),%sil
  je     L32
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L27
  jmp    L63
L18:
  mov    $0x0,%r10d
L67:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, c, k;
  c = 0;
  for (i = 0; i < n1; i++) {
    k = 0;
    for (j = 0; j < n2; j++) {
      if (*(s1 + i) == *(s2 + j)) {
        *(s2 + j) = 0;
        k = 1;
        break;
      }
    }
    if (k == 1)
      c = c + 1;
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<makeEqual>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  xor    %r9d,%r9d
  lea    0x1(%rdi,%rax,1),%r10
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%r8
  nopl   0x0(%rax,%rax,1)
L26:
  test   %ecx,%ecx
  jle    L18
  movzbl (%rdi),%esi
  mov    %rdx,%rax
  jmp    L20
  nopl   0x0(%rax)
L0:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L18
L20:
  cmp    (%rax),%sil
  jne    L0
  movb   $0x0,(%rax)
  add    $0x1,%r9d
L18:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  jne    L26
  mov    %r9d,%eax
  ret
L14:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, c, k;
  c = 0;
  for (i = 0; i < n1; i++) {
    k = 0;
    for (j = 0; j < n2; j++) {
      if (*(s1 + i) == *(s2 + j)) {
        *(s2 + j) = 0;
        k = 1;
        break;
      }
    }
    if (k == 1)
      c = c + 1;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<makeEqual>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  xor    %r9d,%r9d
  lea    0x1(%rdi,%rax,1),%r10
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%r8
  nopl   0x0(%rax,%rax,1)
L37:
  test   %ecx,%ecx
  jle    L58
  movzbl (%rdi),%esi
  mov    %rdx,%rax
  jmp    L7
  nopl   0x0(%rax)
L15:
  add    $0x1,%rax
  cmp    %r8,%rax
  je     L58
L7:
  cmp    (%rax),%sil
  jne    L15
  movb   $0x0,(%rax)
  add    $0x1,%r9d
L58:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  jne    L37
  mov    %r9d,%eax
  ret
L9:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int makeEqual(char *s1, int n1, char *s2, int n2) {
  int i, j, c, k;
  c = 0;
  for (i = 0; i < n1; i++) {
    k = 0;
    for (j = 0; j < n2; j++) {
      if (*(s1 + i) == *(s2 + j)) {
        *(s2 + j) = 0;
        k = 1;
        break;
      }
    }
    if (k == 1)
      c = c + 1;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ehnlc_ffsll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L51
L0:
  movq   $0x0,-0x8(%rbp)
  jmp    L28
L59:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L29
  mov    -0x8(%rbp),%rax
  add    $0x1,%eax
  jmp    L51
L29:
  addq   $0x1,-0x8(%rbp)
L28:
  cmpq   $0x3f,-0x8(%rbp)
  jbe    L59
  mov    $0xffffffff,%eax
L51:
  pop    %rbp
  ret
```

assistant: ```c
int ehnlc_ffsll(long long int lld) {
  size_t i;
  if (lld == 0) {
    return 0;
  }
  for (i = 0; i < 8 * sizeof(long long int); ++i) {
    if (lld & (1ULL << i)) {
      return i + 1;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ehnlc_ffsll>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L19
  test   $0x1,%dil
  jne    L26
  mov    $0x1,%edx
L0:
  mov    %edx,%eax
  bt     %rdx,%rdi
  jb     L37
  add    $0x1,%rdx
  cmp    $0x40,%rdx
  jne    L0
  mov    $0xffffffff,%eax
L19:
  ret
L26:
  mov    $0x0,%eax
L37:
  add    $0x1,%eax
  ret
```

assistant: ```c
int ehnlc_ffsll(long long int lld) {
  size_t i;
  if (lld == 0) {
    return 0;
  }
  for (i = 0; i < 8 * sizeof(long long int); ++i) {
    if (lld & (1ULL << i)) {
      return i + 1;
    }
  }
  return -1;
}
```