ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<take_extension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  jmp    L18
L7:
  lea    D5(%rip),%rax
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: string

tool: 

assistant: ```c
char *take_extension(const char *target) {
  assert(target);
  char *temp = strrchr(target, '.');
  if (temp)
    return temp;
  else
    return "";
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<take_extension>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    $0x2e,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  lea    D0(%rip),%rdx
  cmove  %rdx,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_infered: string

tool: 

assistant: ```c
char *take_extension(const char *target) {
  assert(target);
  char *temp = strrchr(target, '.');
  if (temp)
    return temp;
  else
    return "";
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<take_extension>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    $0x2e,%esi
  call   <strrchr@plt>
  lea    D4(%rip),%rdx
  pop    %rbp
  test   %rax,%rax
  cmove  %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D4
data_type: string

tool: 

assistant: ```c
char *take_extension(const char *target) {
  assert(target);
  char *temp = strrchr(target, '.');
  if (temp)
    return temp;
  else
    return "";
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<take_extension>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  mov    $0x2e,%esi
  call   <strrchr@plt>
  lea    D7(%rip),%rdx
  pop    %rbp
  test   %rax,%rax
  cmove  %rdx,%rax
  ret
```

tool_calls: name: read_data
arguments: label: D7
datatype: string

tool: 

assistant: ```c
char *take_extension(const char *target) {
  assert(target);
  char *temp = strrchr(target, '.');
  if (temp)
    return temp;
  else
    return "";
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_bitstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L9
L7:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <write_bit@plt>
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  nop
  nop
  leave
  ret
```

assistant: ```c
void write_bitstring(struct bitstream *bs, char *str) {
  while (*str) {
    write_bit(bs, *str);
    str++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_bitstring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%esi
  test   %sil,%sil
  je     L18
L0:
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <write_bit@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L0
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_bitstring(struct bitstream *bs, char *str) {
  while (*str) {
    write_bit(bs, *str);
    str++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_bitstring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L16
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <write_bit@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L18
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_bitstring(struct bitstream *bs, char *str) {
  while (*str) {
    write_bit(bs, *str);
    str++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<write_bitstring>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%esi
  test   %sil,%sil
  je     L16
  mov    %rdi,%rbp
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <write_bit@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L0
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void write_bitstring(struct bitstream *bs, char *str) {
  while (*str) {
    write_bit(bs, *str);
    str++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L16
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <_uart_putc@plt>
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void _puts(char *s) {
  for (; *s != '\0'; s++) {
    _uart_putc(*s);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L17
L1:
  movsbl %dil,%edi
  call   <_uart_putc@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
L17:
  pop    %rbx
  ret
```

assistant: ```c
void _puts(char *s) {
  for (; *s != '\0'; s++) {
    _uart_putc(*s);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L16:
  call   <_uart_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L16
L7:
  pop    %rbx
  ret
```

assistant: ```c
void _puts(char *s) {
  for (; *s != '\0'; s++) {
    _uart_putc(*s);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L5:
  call   <_uart_putc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L5
L14:
  pop    %rbx
  ret
```

assistant: ```c
void _puts(char *s) {
  for (; *s != '\0'; s++) {
    _uart_putc(*s);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<euclid_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  jmp    L10
L6:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L10:
  cmpl   $0x0,-0x18(%rbp)
  jne    L6
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int euclid_gcd(int dividend, int divisor) {
  while (divisor != 0) {
    int remainder = dividend % divisor;
    dividend = divisor;
    divisor = remainder;
  }
  return dividend;
}
```
user: What is the c source code of the assembly code below:

```asm
<euclid_gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  je     L10
L29:
  mov    %esi,%ecx
  cltd
  idiv   %esi
  mov    %edx,%esi
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L29
L1:
  mov    %ecx,%eax
  ret
L10:
  mov    %edi,%ecx
  jmp    L1
```

assistant: ```c
int euclid_gcd(int dividend, int divisor) {
  while (divisor != 0) {
    int remainder = dividend % divisor;
    dividend = divisor;
    divisor = remainder;
  }
  return dividend;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<euclid_gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L13
  nopl   0x0(%rax)
L18:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int euclid_gcd(int dividend, int divisor) {
  while (divisor != 0) {
    int remainder = dividend % divisor;
    dividend = divisor;
    divisor = remainder;
  }
  return dividend;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<euclid_gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edx
  test   %esi,%esi
  je     L10
  nopl   0x0(%rax)
L5:
  mov    %edx,%r8d
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int euclid_gcd(int dividend, int divisor) {
  while (divisor != 0) {
    int remainder = dividend % divisor;
    dividend = divisor;
    divisor = remainder;
  }
  return dividend;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %edi,-0x1a4(%rbp)
  mov    %rsi,-0x1b0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a0(%rbp),%rax
  mov    %rax,%rdi
  call   <init_vector@plt>
  lea    -0x1a0(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <qsort_lib@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int vector[100];
  init_vector(vector);
  qsort_lib(vector, 100);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <init_vector@plt>
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <qsort_lib@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x1a0,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int vector[100];
  init_vector(vector);
  qsort_lib(vector, 100);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <init_vector@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <qsort_lib@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int vector[100];
  init_vector(vector);
  qsort_lib(vector, 100);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <init_vector@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <qsort_lib@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  int vector[100];
  init_vector(vector);
  qsort_lib(vector, 100);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<void_void_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_guessed: string
name: disassemble_data
arguments: tag: D16
type_guessed: string
name: disassemble_data
arguments: tag: D37
type_guessed: string

tool: D24: void_void_test

tool: D16: Entered %s:


tool: D37: Exited  %s:


assistant: ```c
void void_void_test(void) {
  printf("Entered %s:\n", __FUNCTION__);
  printf("Exited  %s:\n", __FUNCTION__);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<void_void_test>:
  endbr64
  push   %rbx
  lea    D18(%rip),%rbx
  mov    %rbx,%rsi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D22
data_type: string
name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D18: void_void_test

tool: D22: Entered %s:


tool: D7: Exited  %s:


assistant: ```c
void void_void_test(void) {
  printf("Entered %s:\n", __FUNCTION__);
  printf("Exited  %s:\n", __FUNCTION__);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<void_void_test>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rbp
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
type: string
name: retrieve_data
arguments: tag: D4
type: string
name: retrieve_data
arguments: tag: D1
type: string

tool: D21: void_void_test

tool: D4: Entered %s:


tool: D1: Exited  %s:


assistant: ```c
void void_void_test(void) {
  printf("Entered %s:\n", __FUNCTION__);
  printf("Exited  %s:\n", __FUNCTION__);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<void_void_test>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D9: void_void_test

tool: D24: Entered %s:


tool: D2: Exited  %s:


assistant: ```c
void void_void_test(void) {
  printf("Entered %s:\n", __FUNCTION__);
  printf("Exited  %s:\n", __FUNCTION__);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x1(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: Bir tusa basiniz.


assistant: ```c
int main() {
  char tus = 0;
  printf("Bir tusa basiniz.\n");
  tus = getchar();
  putchar(tus);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: Bir tusa basiniz.


assistant: ```c
int main() {
  char tus = 0;
  printf("Bir tusa basiniz.\n");
  tus = getchar();
  putchar(tus);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_infered: string

tool: D1: Bir tusa basiniz.


assistant: ```c
int main() {
  char tus = 0;
  printf("Bir tusa basiniz.\n");
  tus = getchar();
  putchar(tus);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: Bir tusa basiniz.


assistant: ```c
int main() {
  char tus = 0;
  printf("Bir tusa basiniz.\n");
  tus = getchar();
  putchar(tus);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<give_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <xstrdup@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <uniquestr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <xfree@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *give_basename(const char *c) {
  char *tmp = xstrdup(c);
  char *basename_tmp = basename(tmp);
  const char *result = uniquestr(basename_tmp);
  xfree(tmp);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<give_basename>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <xstrdup@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <basename@plt>
  mov    %rax,%rdi
  call   <uniquestr@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <xfree@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
const char *give_basename(const char *c) {
  char *tmp = xstrdup(c);
  char *basename_tmp = basename(tmp);
  const char *result = uniquestr(basename_tmp);
  xfree(tmp);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<give_basename>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <xstrdup@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <basename@plt>
  mov    %rax,%rdi
  call   <uniquestr@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <xfree@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char *give_basename(const char *c) {
  char *tmp = xstrdup(c);
  char *basename_tmp = basename(tmp);
  const char *result = uniquestr(basename_tmp);
  xfree(tmp);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<parseline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x20,(%rax)
  jmp    L13
L50:
  addq   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L54
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L50
L54:
  movl   $0x0,-0x14(%rbp)
  jmp    L24
L91:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L61
L15:
  addq   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L15
L24:
  mov    -0x10(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L91
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  cmpl   $0x0,-0x14(%rbp)
  jne    L85
  mov    $0x1,%eax
  jmp    L93
L85:
  mov    $0x0,%eax
L93:
  leave
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' ')) {
    buf++;
  }
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parseline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdi,%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx),%rdx
  movb   $0x20,(%rax,%rdx,1)
  cmpb   $0x20,D2(%rip)
  jne    L23
L50:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L50
L23:
  mov    $0x0,%ebp
  jmp    L40
L15:
  add    $0x1,%rbp
L40:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  mov    %rbx,(%r12,%rbp,8)
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rbx
  cmpb   $0x20,0x1(%rax)
  jne    L15
L3:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L3
  jmp    L15
L2:
  movslq %ebp,%rax
  movq   $0x0,(%r12,%rax,8)
  test   %ebp,%ebp
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' ')) {
    buf++;
  }
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<parseline>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  push   %rbx
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x20,-0x1(%rax,%rbx,1)
  cmpb   $0x20,D5(%rip)
  jne    L8
  nopl   (%rax)
L14:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L14
L8:
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L30:
  mov    $0x20,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L28
  mov    %rbx,0x0(%rbp)
  add    $0x1,%r12d
  cmpb   $0x20,0x1(%rax)
  lea    0x1(%rax),%rbx
  movb   $0x0,(%rax)
  jne    L33
  nop
L6:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L6
L33:
  add    $0x8,%rbp
  jmp    L30
  nop
L28:
  xor    %eax,%eax
  test   %r12d,%r12d
  pop    %rbx
  movq   $0x0,0x0(%rbp)
  sete   %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int parseline(const char *cmdline, char **argv) {
  static char array[1024];
  char *buf = array;
  char *delim;
  int argc;
  strcpy(buf, cmdline);
  buf[strlen(buf) - 1] = ' ';
  while (*buf && (*buf == ' ')) {
    buf++;
  }
  argc = 0;
  while ((delim = strchr(buf, ' '))) {
    argv[argc++] = buf;
    *delim = '\0';
    buf = delim + 1;
    while (*buf && (*buf == ' '))
      buf++;
  }
  argv[argc] = NULL;
  if (argc == 0)
    return 1;
  return 0;
}
```