ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reconstructQueue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L13:
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L13
  mov    -0x2c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  mov    (%rdx),%rdx
  add    $0x4,%rdx
  mov    0x4(%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%edi
  mov    -0x2c(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <allocatePeople@plt>
  mov    -0x38(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int **reconstructQueue(int **people, int peopleRowSize, int peopleColSize, int *returnSize) {
  int **queue = (int **)malloc(peopleRowSize * sizeof(int *));
  for (int i = 0; i < peopleRowSize; i++) {
    queue[i] = (int *)malloc(peopleColSize * sizeof(int));
  }
  quickSort(people, 0, peopleRowSize - 1);
  int queueRowSize = 0;
  int currAllocPerson = 1;
  queue[0][0] = people[0][0];
  queue[0][1] = people[0][1];
  allocatePeople(people, queue, queueRowSize, peopleRowSize, currAllocPerson);
  (*returnSize) = peopleRowSize;
  return queue;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<reconstructQueue>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    %rcx,0x8(%rsp)
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L15
  shl    $0x2,%ebp
  mov    %rax,%rbx
  mov    %r13d,%eax
  lea    (%r14,%rax,8),%r12
L3:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L3
L15:
  lea    -0x1(%r13),%edx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <quickSort@plt>
  mov    (%r14),%rax
  mov    (%r15),%rdx
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    (%r14),%rax
  mov    (%r15),%rdx
  mov    0x4(%rdx),%edx
  mov    %edx,0x4(%rax)
  mov    $0x1,%r8d
  mov    %r13d,%ecx
  mov    $0x0,%edx
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <allocatePeople@plt>
  mov    0x8(%rsp),%rax
  mov    %r13d,(%rax)
  mov    %r14,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **reconstructQueue(int **people, int peopleRowSize, int peopleColSize, int *returnSize) {
  int **queue = (int **)malloc(peopleRowSize * sizeof(int *));
  for (int i = 0; i < peopleRowSize; i++) {
    queue[i] = (int *)malloc(peopleColSize * sizeof(int));
  }
  quickSort(people, 0, peopleRowSize - 1);
  int queueRowSize = 0;
  int currAllocPerson = 1;
  queue[0][0] = people[0][0];
  queue[0][1] = people[0][1];
  allocatePeople(people, queue, queueRowSize, peopleRowSize, currAllocPerson);
  (*returnSize) = peopleRowSize;
  return queue;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reconstructQueue>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  lea    0x0(,%rsi,8),%edi
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L6
  mov    %rax,%r15
  mov    %r12d,%eax
  shl    $0x2,%ebx
  lea    0x0(%r13,%rax,8),%rbp
  nopl   0x0(%rax)
L7:
  mov    %ebx,%edi
  add    $0x8,%r15
  call   <malloc@plt>
  mov    %rax,-0x8(%r15)
  cmp    %rbp,%r15
  jne    L7
L6:
  lea    -0x1(%r12),%edx
  mov    %r14,%rdi
  xor    %esi,%esi
  call   <quickSort@plt>
  mov    (%r14),%rdx
  mov    0x0(%r13),%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x1,%r8d
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%edx
  mov    %r12d,%ecx
  mov    %edx,0x4(%rax)
  xor    %edx,%edx
  call   <allocatePeople@plt>
  mov    0x8(%rsp),%rax
  mov    %r12d,(%rax)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **reconstructQueue(int **people, int peopleRowSize, int peopleColSize, int *returnSize) {
  int **queue = (int **)malloc(peopleRowSize * sizeof(int *));
  for (int i = 0; i < peopleRowSize; i++) {
    queue[i] = (int *)malloc(peopleColSize * sizeof(int));
  }
  quickSort(people, 0, peopleRowSize - 1);
  int queueRowSize = 0;
  int currAllocPerson = 1;
  queue[0][0] = people[0][0];
  queue[0][1] = people[0][1];
  allocatePeople(people, queue, queueRowSize, peopleRowSize, currAllocPerson);
  (*returnSize) = peopleRowSize;
  return queue;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<reconstructQueue>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  lea    0x0(,%rsi,8),%edi
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L12
  mov    %rax,%r15
  mov    %r12d,%eax
  shl    $0x2,%ebx
  lea    0x0(%r13,%rax,8),%rbp
  nopl   0x0(%rax)
L2:
  mov    %ebx,%edi
  add    $0x8,%r15
  call   <malloc@plt>
  mov    %rax,-0x8(%r15)
  cmp    %rbp,%r15
  jne    L2
L12:
  lea    -0x1(%r12),%edx
  mov    %r14,%rdi
  xor    %esi,%esi
  call   <quickSort@plt>
  mov    (%r14),%rdx
  mov    0x0(%r13),%rax
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x1,%r8d
  mov    (%rdx),%ecx
  mov    %ecx,(%rax)
  mov    0x4(%rdx),%edx
  mov    %r12d,%ecx
  mov    %edx,0x4(%rax)
  xor    %edx,%edx
  call   <allocatePeople@plt>
  mov    0x8(%rsp),%rax
  mov    %r12d,(%rax)
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int **reconstructQueue(int **people, int peopleRowSize, int peopleColSize, int *returnSize) {
  int **queue = (int **)malloc(peopleRowSize * sizeof(int *));
  for (int i = 0; i < peopleRowSize; i++) {
    queue[i] = (int *)malloc(peopleColSize * sizeof(int));
  }
  quickSort(people, 0, peopleRowSize - 1);
  int queueRowSize = 0;
  int currAllocPerson = 1;
  queue[0][0] = people[0][0];
  queue[0][1] = people[0][1];
  allocatePeople(people, queue, queueRowSize, peopleRowSize, currAllocPerson);
  (*returnSize) = peopleRowSize;
  return queue;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normalize3_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  sar    %eax
  mov    %eax,%edx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm2
  mulss  -0x8(%rbp),%xmm2
  movss  D17(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  D24(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x10(%rbp),%xmm0
  movaps %xmm0,%xmm2
  mulss  -0x8(%rbp),%xmm2
  movss  D17(%rip),%xmm0
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  D24(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x10(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movss  (%rax),%xmm1
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  mov    -0x20(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  movss  -0x10(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mulss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: byte[4]
name: disassemble_data
arguments: data_label: D24
type: f32

tool: {"D17": [0x00,0x00,0x40,0x40]}

tool: D24: 0.5

assistant: ```c
void normalize3_c(float v[3], float d[3]) {
  float b, c, x;
  union {
    float f;
    int i;
  } a;
  x = v[0] * v[0];
  x += v[1] * v[1];
  x += v[2] * v[2];
  a.f = x;
  a.i = 0x5F3759DF - (a.i >> 1);
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  d[0] = v[0] * a.f;
  d[1] = v[1] * a.f;
  d[2] = v[2] * a.f;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<normalize3_c>:
  endbr64
  movss  (%rdi),%xmm3
  movaps %xmm3,%xmm1
  mulss  %xmm3,%xmm1
  movss  0x4(%rdi),%xmm0
  mulss  %xmm0,%xmm0
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm0,%xmm1
  movd   %xmm1,%edx
  sar    %edx
  mov    $0x5f3759df,%eax
  sub    %edx,%eax
  movd   %eax,%xmm4
  movd   %eax,%xmm5
  mulss  %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  movss  D19(%rip),%xmm0
  movaps %xmm0,%xmm2
  subss  %xmm5,%xmm2
  movss  D11(%rip),%xmm5
  mulss  %xmm5,%xmm2
  mulss  %xmm4,%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mulss  %xmm5,%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm0,%xmm3
  movss  %xmm3,(%rsi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rdi),%xmm1
  movss  %xmm1,0x4(%rsi)
  mulss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
data_type: byte[4]
name: unpack_data
arguments: tag: D11
data_type: f32

tool: {"D19": [0x00,0x00,0x40,0x40]}

tool: D11: 0.5

assistant: ```c
void normalize3_c(float v[3], float d[3]) {
  float b, c, x;
  union {
    float f;
    int i;
  } a;
  x = v[0] * v[0];
  x += v[1] * v[1];
  x += v[2] * v[2];
  a.f = x;
  a.i = 0x5F3759DF - (a.i >> 1);
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  d[0] = v[0] * a.f;
  d[1] = v[1] * a.f;
  d[2] = v[2] * a.f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<normalize3_c>:
  endbr64
  movss  (%rdi),%xmm3
  movss  0x4(%rdi),%xmm0
  mov    $0x5f3759df,%eax
  mulss  %xmm0,%xmm0
  movaps %xmm3,%xmm1
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm0,%xmm1
  movss  D14(%rip),%xmm0
  movaps %xmm0,%xmm2
  movd   %xmm1,%edx
  sar    %edx
  sub    %edx,%eax
  movd   %eax,%xmm5
  movd   %eax,%xmm4
  mulss  %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  subss  %xmm5,%xmm2
  movss  D6(%rip),%xmm5
  mulss  %xmm5,%xmm2
  mulss  %xmm4,%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mulss  %xmm5,%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm0,%xmm3
  movss  %xmm3,(%rsi)
  movss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rsi)
  mulss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
datatype: byte[4]
name: retrieve_data
arguments: data_tag: D6
datatype: f32

tool: {"D14": [0x00,0x00,0x40,0x40]}

tool: D6: 0.5

assistant: ```c
void normalize3_c(float v[3], float d[3]) {
  float b, c, x;
  union {
    float f;
    int i;
  } a;
  x = v[0] * v[0];
  x += v[1] * v[1];
  x += v[2] * v[2];
  a.f = x;
  a.i = 0x5F3759DF - (a.i >> 1);
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  d[0] = v[0] * a.f;
  d[1] = v[1] * a.f;
  d[2] = v[2] * a.f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normalize3_c>:
  endbr64
  movss  (%rdi),%xmm3
  movss  0x4(%rdi),%xmm0
  mov    $0x5f3759df,%eax
  mulss  %xmm0,%xmm0
  movaps %xmm3,%xmm1
  mulss  %xmm3,%xmm1
  addss  %xmm1,%xmm0
  movss  0x8(%rdi),%xmm1
  mulss  %xmm1,%xmm1
  addss  %xmm0,%xmm1
  movss  D5(%rip),%xmm0
  movaps %xmm0,%xmm2
  movd   %xmm1,%edx
  sar    %edx
  sub    %edx,%eax
  movd   %eax,%xmm5
  movd   %eax,%xmm4
  mulss  %xmm1,%xmm5
  mulss  %xmm4,%xmm5
  subss  %xmm5,%xmm2
  movss  D1(%rip),%xmm5
  mulss  %xmm5,%xmm2
  mulss  %xmm4,%xmm2
  mulss  %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  mulss  %xmm5,%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm0,%xmm3
  movss  %xmm3,(%rsi)
  movss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rsi)
  mulss  0x8(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: byte[4]
name: unpack_data
arguments: data_label: D1
data_type: f32

tool: {"D5": [0x00,0x00,0x40,0x40]}

tool: D1: 0.5

assistant: ```c
void normalize3_c(float v[3], float d[3]) {
  float b, c, x;
  union {
    float f;
    int i;
  } a;
  x = v[0] * v[0];
  x += v[1] * v[1];
  x += v[2] * v[2];
  a.f = x;
  a.i = 0x5F3759DF - (a.i >> 1);
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  c = x * a.f;
  b = (3.0f - c * a.f) * 0.5;
  a.f = a.f * b;
  d[0] = v[0] * a.f;
  d[1] = v[1] * a.f;
  d[2] = v[2] * a.f;
}
```
user: What is the c source code of the assembly code below:

```asm
<djb2hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  lea    -0x13(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  lea    -0x13(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x28(%rbp)
  lea    -0x13(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  lea    -0x13(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  movq   $0x1505,-0x30(%rbp)
  jmp    L13
L21:
  mov    -0x30(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
L13:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x0,-0x3c(%rbp)
  jne    L21
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
long djb2hash() {
  char input[11];
  fgets(input, 10, stdin);
  size_t nl = strlen(input) - 1;
  input[nl] = '\0';
  unsigned char *str = input;
  unsigned long hash = 5381;
  int c;
  while (c = *str++) {
    hash = ((hash << 5) + hash) + c;
  }
  long int deliverable = hash;
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<djb2hash>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xd(%rsp),%rbx
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,0xd(%rsp,%rax,1)
  movzbl 0xd(%rsp),%edx
  test   %dl,%dl
  je     L6
  lea    0xe(%rsp),%rcx
  mov    $0x1505,%eax
L16:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movzbl %dl,%edx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L16
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  mov    $0x1505,%eax
  jmp    L1
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long djb2hash() {
  char input[11];
  fgets(input, 10, stdin);
  size_t nl = strlen(input) - 1;
  input[nl] = '\0';
  unsigned char *str = input;
  unsigned long hash = 5381;
  int c;
  while (c = *str++) {
    hash = ((hash << 5) + hash) + c;
  }
  long int deliverable = hash;
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<djb2hash>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0xd(%rsp),%rbp
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,0xd(%rsp,%rax,1)
  movzbl 0xd(%rsp),%edx
  test   %dl,%dl
  je     L35
  lea    0xe(%rsp),%rcx
  mov    $0x1505,%eax
  nopl   0x0(%rax)
L26:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L26
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L35:
  mov    $0x1505,%eax
  jmp    L16
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long djb2hash() {
  char input[11];
  fgets(input, 10, stdin);
  size_t nl = strlen(input) - 1;
  input[nl] = '\0';
  unsigned char *str = input;
  unsigned long hash = 5381;
  int c;
  while (c = *str++) {
    hash = ((hash << 5) + hash) + c;
  }
  long int deliverable = hash;
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<djb2hash>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0xd(%rsp),%rbp
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,0xd(%rsp,%rax,1)
  movzbl 0xd(%rsp),%edx
  test   %dl,%dl
  je     L0
  lea    0xe(%rsp),%rcx
  mov    $0x1505,%eax
  nopl   0x0(%rax)
L11:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L11
L20:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x20,%rsp
  pop    %rbp
  ret
  nop
L0:
  mov    $0x1505,%eax
  jmp    L20
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long djb2hash() {
  char input[11];
  fgets(input, 10, stdin);
  size_t nl = strlen(input) - 1;
  input[nl] = '\0';
  unsigned char *str = input;
  unsigned long hash = 5381;
  int c;
  while (c = *str++) {
    hash = ((hash << 5) + hash) + c;
  }
  long int deliverable = hash;
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<random_matrix_double_3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L52
L18:
  movl   $0x0,-0x8(%rbp)
  jmp    L53
L41:
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L22:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  shl    $0x3,%rax
  add    %rcx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L45:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jb     L22
  addl   $0x1,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L41
  addl   $0x1,-0xc(%rbp)
L52:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void random_matrix_double_3d(double ***a, const unsigned int rows, const unsigned int cols, const unsigned int dimz) {
  for (unsigned int z = 0; z < dimz; z++) {
    for (unsigned int r = 0; r < rows; r++) {
      for (unsigned int c = 0; c < cols; c++) {
        a[z][r][c] = (double)rand();
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<random_matrix_double_3d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %ecx,%ecx
  je     L30
  mov    %edx,%r14d
  mov    %rdi,%r12
  lea    -0x1(%rcx),%edx
  lea    0x8(%rdi,%rdx,8),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x8(,%rax,8),%r15
  lea    -0x1(%r14),%eax
  lea    0x8(,%rax,8),%r13
  jmp    L50
L89:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%rdx
  mov    (%r12),%rax
  mov    (%rax,%rbp,1),%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  movsd  %xmm0,(%rax,%rbx,1)
  add    $0x8,%rbx
  cmp    %rbx,%r13
  jne    L89
L76:
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L55
L9:
  mov    $0x0,%ebx
  test   %r14d,%r14d
  jne    L89
  jmp    L76
L55:
  add    $0x8,%r12
  cmp    (%rsp),%r12
  je     L30
L50:
  mov    $0x0,%ebp
  cmpl   $0x0,0xc(%rsp)
  jne    L9
  jmp    L55
L30:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void random_matrix_double_3d(double ***a, const unsigned int rows, const unsigned int cols, const unsigned int dimz) {
  for (unsigned int z = 0; z < dimz; z++) {
    for (unsigned int r = 0; r < rows; r++) {
      for (unsigned int c = 0; c < cols; c++) {
        a[z][r][c] = (double)rand();
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<random_matrix_double_3d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %ecx,%ecx
  je     L4
  mov    %ecx,%eax
  mov    %edx,%r12d
  mov    %rdi,%r15
  sub    $0x1,%eax
  lea    0x8(%rdi,%rax,8),%rax
  mov    %rax,(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x8(,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L57:
  mov    0xc(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  je     L59
  nopw   0x0(%rax,%rax,1)
L31:
  xor    %r14d,%r14d
  test   %r12d,%r12d
  je     L6
  nopl   0x0(%rax,%rax,1)
L26:
  xor    %eax,%eax
  call   <rand@plt>
  pxor   %xmm0,%xmm0
  mov    %rax,%r8
  mov    (%r15),%rax
  cvtsi2sd %r8,%xmm0
  mov    (%rax,%rbx,1),%rax
  movsd  %xmm0,(%rax,%r14,1)
  add    $0x8,%r14
  cmp    %r14,%rbp
  jne    L26
L6:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L31
L59:
  add    $0x8,%r15
  cmp    (%rsp),%r15
  jne    L57
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void random_matrix_double_3d(double ***a, const unsigned int rows, const unsigned int cols, const unsigned int dimz) {
  for (unsigned int z = 0; z < dimz; z++) {
    for (unsigned int r = 0; r < rows; r++) {
      for (unsigned int c = 0; c < cols; c++) {
        a[z][r][c] = (double)rand();
      }
    }
  }
}
```