ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print_wifidirect_action_frame_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string
name: read_data
arguments: tag: D18
data_type: string

tool: D1: 
Usage : wifidirect_action_frame <CONFIG_FILE> | [<PeerAddr> <Category> <OUISubtype> <DialogToken>]


tool: D18: 
Action frame is sent using parameters in the CONFIG_FILE or parameters specified on command line.


assistant: ```c
void print_wifidirect_action_frame_usage(void) {
  printf("\nUsage : wifidirect_action_frame <CONFIG_FILE> |"
         " [<PeerAddr> <Category> <OUISubtype> <DialogToken>]\n");
  printf("\nAction frame is sent using parameters in the CONFIG_FILE "
         "or parameters specified on command line.\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<old_str_lpad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x2c(%rbp)
L27:
  movl   $0x0,-0x4(%rbp)
  jmp    L48
L5:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x2c(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L48:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L5
  jmp    L4
L17:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L4:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L53
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L53:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void old_str_lpad(char *dst, const char *src, size_t width, unsigned char pad) {
  int i;
  do {
    for (i = 0; i < width; i++) {
      *dst++ = pad;
    }
    while (*src != '\n' && *src) {
      *dst++ = *src++;
    }
    *dst++ = *src;
  } while (*src++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<old_str_lpad>:
  endbr64
  jmp    L35
L65:
  mov    %rdi,%r8
  jmp    L77
L62:
  lea    0x1(%r8),%rdi
  mov    %al,(%r8)
  add    $0x1,%rsi
  test   %al,%al
  je     L74
L35:
  test   %rdx,%rdx
  je     L65
  lea    (%rdi,%rdx,1),%r8
L64:
  add    $0x1,%rdi
  mov    %cl,-0x1(%rdi)
  cmp    %rdi,%r8
  jne    L64
L77:
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  je     L62
  test   %al,%al
  je     L62
L93:
  add    $0x1,%rsi
  add    $0x1,%r8
  mov    %al,-0x1(%r8)
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  je     L62
  test   %al,%al
  jne    L93
  jmp    L62
L74:
  ret
```

assistant: ```c
void old_str_lpad(char *dst, const char *src, size_t width, unsigned char pad) {
  int i;
  do {
    for (i = 0; i < width; i++) {
      *dst++ = pad;
    }
    while (*src != '\n' && *src) {
      *dst++ = *src++;
    }
    *dst++ = *src;
  } while (*src++);
}
```
user: Translate the below assembly code into C programming language:

```asm
<old_str_lpad>:
  endbr64
  push   %r12
  movsbl %cl,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L20:
  test   %rbp,%rbp
  je     L61
  mov    %rbp,%rdx
  mov    %r12d,%esi
  call   <memset@plt>
  lea    (%rax,%rbp,1),%rcx
L4:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L1
  cmp    $0xa,%al
  je     L1
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rbx
  mov    %al,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L1
  test   %al,%al
  jne    L40
L1:
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rdi
  add    $0x1,%rbx
  test   %al,%al
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %rdi,%rcx
  jmp    L4
```

assistant: ```c
void old_str_lpad(char *dst, const char *src, size_t width, unsigned char pad) {
  int i;
  do {
    for (i = 0; i < width; i++) {
      *dst++ = pad;
    }
    while (*src != '\n' && *src) {
      *dst++ = *src++;
    }
    *dst++ = *src;
  } while (*src++);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<old_str_lpad>:
  endbr64
  push   %r12
  movsbl %cl,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopw   0x0(%rax,%rax,1)
L30:
  test   %rbp,%rbp
  je     L48
  mov    %rbp,%rdx
  mov    %r12d,%esi
  call   <memset@plt>
  lea    (%rax,%rbp,1),%rcx
L3:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L64
  cmp    $0xa,%al
  je     L64
  nopw   0x0(%rax,%rax,1)
L67:
  add    $0x1,%rbx
  mov    %al,(%rcx)
  add    $0x1,%rcx
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L64
  test   %al,%al
  jne    L67
L64:
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rdi
  add    $0x1,%rbx
  test   %al,%al
  jne    L30
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    %rdi,%rcx
  jmp    L3
```

assistant: ```c
void old_str_lpad(char *dst, const char *src, size_t width, unsigned char pad) {
  int i;
  do {
    for (i = 0; i < width; i++) {
      *dst++ = pad;
    }
    while (*src != '\n' && *src) {
      *dst++ = *src++;
    }
    *dst++ = *src;
  } while (*src++);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D10(%rip),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L30
L36:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L30:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L36
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    D10(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  add    %rax,-0x10(%rbp)
  jmp    L21
L16:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %eax,%edi
  call   <puts@plt>
L21:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L16
  mov    $0x0,%eax
  call   <flushall@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: string

tool: D10: abcd

assistant: ```c
void main() {
  char *q = "abcd";
  while (*q)
    putchar(*q++);
  getchar();
  getchar();
  char *text = "abcd";
  char *p = text;
  p += strlen(p) - 1;
  while (text <= p)
    puts(p--);
  flushall();
  getchar();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D10(%rip),%rbx
  mov    $0x61,%edi
L15:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    D10(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rbx
  add    %rbp,%rbx
  jb     L10
L22:
  mov    %ebx,%edi
  call   <puts@plt>
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jae    L22
L10:
  mov    $0x0,%eax
  call   <flushall@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_guessed: string

tool: D10: abcd

assistant: ```c
void main() {
  char *q = "abcd";
  while (*q)
    putchar(*q++);
  getchar();
  getchar();
  char *text = "abcd";
  char *p = text;
  p += strlen(p) - 1;
  while (text <= p)
    puts(p--);
  flushall();
  getchar();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    $0x61,%edi
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L27:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L27
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rbx
  add    %rbp,%rbx
  jb     L8
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%edi
  sub    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jae    L15
L8:
  xor    %eax,%eax
  call   <flushall@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    10d0 <getchar@plt>
```

tool_calls: name: read_data
arguments: label: D1
datatype: string

tool: D1: abcd

assistant: ```c
void main() {
  char *q = "abcd";
  while (*q)
    putchar(*q++);
  getchar();
  getchar();
  char *text = "abcd";
  char *p = text;
  p += strlen(p) - 1;
  while (text <= p)
    puts(p--);
  flushall();
  getchar();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    $0x61,%edi
  push   %rbx
  mov    %rbp,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L23:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L23
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ebx
  movslq %ebx,%rbx
  add    %rbp,%rbx
  jb     L26
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  sub    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jae    L8
L26:
  xor    %eax,%eax
  call   <flushall@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  jmp    10d0 <getchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type: string

tool: D6: abcd

assistant: ```c
void main() {
  char *q = "abcd";
  while (*q)
    putchar(*q++);
  getchar();
  getchar();
  char *text = "abcd";
  char *p = text;
  p += strlen(p) - 1;
  while (text <= p)
    puts(p--);
  flushall();
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<subfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  shll   -0x4(%rbp)
  shll   -0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subfunc(int a) {
  a *= 2;
  a *= 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<subfunc>:
  endbr64
  ret
```

assistant: ```c
void subfunc(int a) {
  a *= 2;
  a *= 2;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subfunc>:
  endbr64
  ret
```

assistant: ```c
void subfunc(int a) {
  a *= 2;
  a *= 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subfunc>:
  endbr64
  ret
```

assistant: ```c
void subfunc(int a) {
  a *= 2;
  a *= 2;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prerr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <prraw@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type: string

tool: 

assistant: ```c
void prerr(int err, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  prraw("", err, fmt, ap);
  va_end(ap);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prerr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <prraw@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string

tool: 

assistant: ```c
void prerr(int err, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  prraw("", err, fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<prerr>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  lea    D7(%rip),%rdi
  call   <prraw@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: 

assistant: ```c
void prerr(int err, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  prraw("", err, fmt, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prerr>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13d,%esi
  lea    D3(%rip),%rdi
  call   <prraw@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: 

assistant: ```c
void prerr(int err, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  prraw("", err, fmt, ap);
  va_end(ap);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_display3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L13
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_display2d@plt>
L13:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_display3d(char **array[]) {
  int level;
  level = -1;
  while (array[++level])
    ft_display2d(array[level]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_display3d>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L11
  push   %rbx
  lea    0x8(%rax),%rbx
L18:
  call   <ft_display2d@plt>
  add    $0x8,%rbx
  mov    -0x8(%rbx),%rdi
  test   %rdi,%rdi
  jne    L18
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void ft_display3d(char **array[]) {
  int level;
  level = -1;
  while (array[++level])
    ft_display2d(array[level]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_display3d>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  push   %rbx
  lea    0x8(%rax),%rbx
  nopl   0x0(%rax)
L18:
  call   <ft_display2d@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L18
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void ft_display3d(char **array[]) {
  int level;
  level = -1;
  while (array[++level])
    ft_display2d(array[level]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_display3d>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L5
  push   %rbx
  lea    0x8(%rax),%rbx
  nopl   0x0(%rax)
L9:
  call   <ft_display2d@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L9
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void ft_display3d(char **array[]) {
  int level;
  level = -1;
  while (array[++level])
    ft_display2d(array[level]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L8:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <binomial@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rank(int k, int *a) {
  int i, r;
  r = 0;
  for (i = 0; i < k; ++i)
    r += binomial(a[i], i + 1);
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rank>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L29
  mov    %rsi,%r12
  lea    0x1(%rdi),%r13d
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L0:
  mov    -0x4(%r12,%rbx,4),%edi
  mov    %ebx,%esi
  call   <binomial@plt>
  add    %eax,%ebp
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L0
L24:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    $0x0,%ebp
  jmp    L24
```

assistant: ```c
int rank(int k, int *a) {
  int i, r;
  r = 0;
  for (i = 0; i < k; ++i)
    r += binomial(a[i], i + 1);
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rank>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L4
  mov    %rsi,%r13
  lea    0x1(%rdi),%ebp
  mov    $0x1,%ebx
  xor    %r12d,%r12d
L14:
  mov    -0x4(%r13,%rbx,4),%edi
  mov    %ebx,%esi
  add    $0x1,%rbx
  call   <binomial@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rank(int k, int *a) {
  int i, r;
  r = 0;
  for (i = 0; i < k; ++i)
    r += binomial(a[i], i + 1);
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rank>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L13
  mov    %rsi,%r13
  lea    0x1(%rdi),%ebp
  mov    $0x1,%ebx
  xor    %r12d,%r12d
L1:
  mov    -0x4(%r13,%rbx,4),%edi
  mov    %ebx,%esi
  add    $0x1,%rbx
  call   <binomial@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L1
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int rank(int k, int *a) {
  int i, r;
  r = 0;
  for (i = 0; i < k; ++i)
    r += binomial(a[i], i + 1);
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<do_read_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <set_offset@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <read_buffer@plt>
  nop
  leave
  ret
```

assistant: ```c
void do_read_header(void *buff, int size, unsigned long block_addr) {
  set_offset(block_addr);
  read_buffer(buff, size);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<do_read_header>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %rdx,%rdi
  call   <set_offset@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <read_buffer@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void do_read_header(void *buff, int size, unsigned long block_addr) {
  set_offset(block_addr);
  read_buffer(buff, size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_read_header>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <set_offset@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <read_buffer@plt>
```

assistant: ```c
void do_read_header(void *buff, int size, unsigned long block_addr) {
  set_offset(block_addr);
  read_buffer(buff, size);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<do_read_header>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  sub    $0x8,%rsp
  call   <set_offset@plt>
  add    $0x8,%rsp
  mov    %r12d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <read_buffer@plt>
```

assistant: ```c
void do_read_header(void *buff, int size, unsigned long block_addr) {
  set_offset(block_addr);
  read_buffer(buff, size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usd_perror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void usd_perror(const char *s) {
  if (0) {
    perror(s);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usd_perror>:
  endbr64
  ret
```

assistant: ```c
void usd_perror(const char *s) {
  if (0) {
    perror(s);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usd_perror>:
  endbr64
  ret
```

assistant: ```c
void usd_perror(const char *s) {
  if (0) {
    perror(s);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  D19(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm1
  movss  D21(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  D21(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x14(%rbp),%xmm1
  movss  D21(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  D21(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm2
  movss  -0x8(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_infered: byte[4]
name: retrieve_data
arguments: data_tag: D21
type_infered: f32
name: retrieve_data
arguments: data_tag: D13
type_infered: string

tool: {"D19": [0x00,0x23,0x48,0x47]}

tool: D21: 7

tool: D13: %.2f %.2f %.2f %.2f


assistant: ```c
int main() {
  float target, a, b, c, d;
  target = 51235;
  a = target + 7.0;
  b = target - 7.0;
  c = target * 7.0;
  d = target / 7.0;
  printf("%.2f %.2f %.2f %.2f\n", a, b, c, d);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movss  D48(%rip),%xmm3
  movss  D26(%rip),%xmm2
  movss  D11(%rip),%xmm1
  movss  D35(%rip),%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D48
type: byte[4]
name: disassemble_data
arguments: tag: D26
type: byte[4]
name: disassemble_data
arguments: tag: D11
type: byte[4]
name: disassemble_data
arguments: tag: D35
type: byte[4]
name: disassemble_data
arguments: tag: D10
type: string

tool: {"D48": [0x49,0xba,0xe4,0x45]}

tool: {"D26": [0xa0,0x1e,0xaf,0x48]}

tool: {"D11": [0x00,0x1c,0x48,0x47]}

tool: {"D35": [0x00,0x2a,0x48,0x47]}

tool: D10: %.2f %.2f %.2f %.2f


assistant: ```c
int main() {
  float target, a, b, c, d;
  target = 51235;
  a = target + 7.0;
  b = target - 7.0;
  c = target * 7.0;
  d = target / 7.0;
  printf("%.2f %.2f %.2f %.2f\n", a, b, c, d);
  return 0;
}
```