ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_test>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <sigemptyset@plt>
  mov    D74(%rip),%rax
  mov    %rbp,%rsi
  xor    %edx,%edx
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  call   <sigsetjmp@plt>
  endbr64
  lea    0x4(%rsp),%rbp
  test   %rax,%rax
  jne    L0
  mov    D38(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigaddset@plt>
  mov    D74(%rip),%rax
  xor    %edx,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <siglongjmp@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x10,%rsp
  pop    %rbp
  ret
  nop
L0:
  mov    D74(%rip),%rax
  xor    %esi,%esi
  mov    %rbp,%rdx
  mov    (%rax),%edi
  call   <sigprocmask@plt>
  mov    D38(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <sigismember@plt>
  test   %rax,%rax
  je     L29
  mov    D71(%rip),%rax
  mov    (%rax),%eax
  jmp    L28
  nopl   0x0(%rax)
L29:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  jmp    L28
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_test(void) {
  sigjmp_buf sj;
  sigset_t m;
  sigemptyset(&m);
  sigprocmask(SIG_SETMASK, &m, NULL);
  if (sigsetjmp(sj, 0) == 0) {
    sigaddset(&m, SIGUSR1);
    sigprocmask(SIG_SETMASK, &m, NULL);
    siglongjmp(sj, 1);
    return EXIT_FAILURE;
  }
  sigprocmask(SIG_SETMASK, NULL, &m);
  return sigismember(&m, SIGUSR1) ? EXIT_SUCCESS : EXIT_FAILURE;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pack16_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L10:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl 0x1(%rdx),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  addq   $0x4,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pack16_c(int *in, char *out, int n) {
  int i;
  char *s;
  s = (char *)in;
  for (i = 0; i < n; i++) {
    *out++ = *(s + 1);
    *out++ = *s;
    s += sizeof(int);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pack16_c>:
  endbr64
  test   %edx,%edx
  jle    L18
  mov    %edx,%edx
  lea    (%rsi,%rdx,2),%rdx
L10:
  movzbl 0x1(%rdi),%eax
  mov    %al,(%rsi)
  add    $0x2,%rsi
  movzbl (%rdi),%eax
  mov    %al,-0x1(%rsi)
  add    $0x4,%rdi
  cmp    %rsi,%rdx
  jne    L10
L18:
  ret
```

assistant: ```c
void pack16_c(int *in, char *out, int n) {
  int i;
  char *s;
  s = (char *)in;
  for (i = 0; i < n; i++) {
    *out++ = *(s + 1);
    *out++ = *s;
    s += sizeof(int);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pack16_c>:
  endbr64
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  lea    (%rsi,%rdx,2),%rdx
  nop
L12:
  movzbl 0x1(%rdi),%eax
  add    $0x2,%rsi
  add    $0x4,%rdi
  mov    %al,-0x2(%rsi)
  movzbl -0x4(%rdi),%eax
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%rdx
  jne    L12
L2:
  ret
```

assistant: ```c
void pack16_c(int *in, char *out, int n) {
  int i;
  char *s;
  s = (char *)in;
  for (i = 0; i < n; i++) {
    *out++ = *(s + 1);
    *out++ = *s;
    s += sizeof(int);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strncat_symbolic_src_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x34333231,-0x18(%rbp)
  mov    -0x28(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  movq   $0x34333231,-0x10(%rbp)
  mov    -0x28(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void strncat_symbolic_src_length(char *src) {
  char dst[8] = "1234";
  strncat(dst, src, 3);
  if (strlen(dst) < 4)
    (void)*(char *)0;
  char dst2[8] = "1234";
  strncat(dst2, src, 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<strncat_symbolic_src_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x34333231,0x8(%rsp)
  lea    0x8(%rsp),%rbp
  mov    $0x3,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movq   $0x34333231,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbx,%rsi
  call   <strncat@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncat_symbolic_src_length(char *src) {
  char dst[8] = "1234";
  strncat(dst, src, 3);
  if (strlen(dst) < 4)
    (void)*(char *)0;
  char dst2[8] = "1234";
  strncat(dst2, src, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncat_symbolic_src_length>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x3,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  movq   $0x34333231,0x8(%rsp)
  mov    %r12,%rdi
  call   <strncat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  movq   $0x34333231,0x10(%rsp)
  call   <strncat@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncat_symbolic_src_length(char *src) {
  char dst[8] = "1234";
  strncat(dst, src, 3);
  if (strlen(dst) < 4)
    (void)*(char *)0;
  char dst2[8] = "1234";
  strncat(dst2, src, 4);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncat_symbolic_src_length>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    $0x3,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r12
  movq   $0x34333231,0x8(%rsp)
  mov    %r12,%rdi
  call   <strncat@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  mov    %rbp,%rsi
  movq   $0x34333231,0x10(%rsp)
  call   <strncat@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void strncat_symbolic_src_length(char *src) {
  char dst[8] = "1234";
  strncat(dst, src, 3);
  if (strlen(dst) < 4)
    (void)*(char *)0;
  char dst2[8] = "1234";
  strncat(dst2, src, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lin_solve_PSD>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x3c(%rbp)
  mov    %r8d,-0x40(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   %eax,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   %eax,%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x3c(%rbp),%eax
  imul   -0x40(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x3c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mtx_chol@plt>
  mov    -0x40(%rbp),%edi
  mov    -0x3c(%rbp),%ecx
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0x1,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    -0x3c(%rbp),%ecx
  mov    -0x3c(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <mtx_transpose@plt>
  mov    -0x40(%rbp),%edi
  mov    -0x3c(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x0,%r9d
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void lin_solve_PSD(double *A, double *X, double *B, int dim_i, int dim_j) {
  double *L = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *L_prime = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *Z = (double *)calloc(dim_i * dim_j, sizeof(double));
  mtx_chol(A, L, dim_i);
  lin_solve_triangular_equ(L, Z, B, dim_i, dim_j, 1);
  mtx_transpose(L, L_prime, dim_i, dim_i);
  lin_solve_triangular_equ(L_prime, X, Z, dim_i, dim_j, 0);
  free(L);
  free(L_prime);
  free(Z);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lin_solve_PSD>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %ecx,%ebx
  mov    %r8d,%r14d
  mov    %ecx,%r12d
  imul   %ecx,%r12d
  mov    $0x8,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    $0x8,%esi
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    %ebx,%edi
  imul   %r14d,%edi
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <mtx_chol@plt>
  mov    $0x1,%r9d
  mov    %r14d,%r8d
  mov    %ebx,%ecx
  mov    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <mtx_transpose@plt>
  mov    $0x0,%r9d
  mov    %r14d,%r8d
  mov    %ebx,%ecx
  mov    %r12,%rdx
  mov    (%rsp),%rsi
  mov    %r13,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void lin_solve_PSD(double *A, double *X, double *B, int dim_i, int dim_j) {
  double *L = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *L_prime = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *Z = (double *)calloc(dim_i * dim_j, sizeof(double));
  mtx_chol(A, L, dim_i);
  lin_solve_triangular_equ(L, Z, B, dim_i, dim_j, 1);
  mtx_transpose(L, L_prime, dim_i, dim_i);
  lin_solve_triangular_equ(L_prime, X, Z, dim_i, dim_j, 0);
  free(L);
  free(L_prime);
  free(Z);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<lin_solve_PSD>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    $0x8,%esi
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  imul   %ecx,%r13d
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %r13d,%edi
  mov    %rdx,(%rsp)
  call   <calloc@plt>
  mov    %r13d,%edi
  mov    $0x8,%esi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %r12d,%edi
  mov    $0x8,%esi
  imul   %ebx,%edi
  mov    %rax,%r14
  call   <calloc@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  call   <mtx_chol@plt>
  mov    (%rsp),%rdx
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    $0x1,%r9d
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <mtx_transpose@plt>
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %r15,%rsi
  xor    %r9d,%r9d
  mov    %r14,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <free@plt>
```

assistant: ```c
void lin_solve_PSD(double *A, double *X, double *B, int dim_i, int dim_j) {
  double *L = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *L_prime = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *Z = (double *)calloc(dim_i * dim_j, sizeof(double));
  mtx_chol(A, L, dim_i);
  lin_solve_triangular_equ(L, Z, B, dim_i, dim_j, 1);
  mtx_transpose(L, L_prime, dim_i, dim_i);
  lin_solve_triangular_equ(L_prime, X, Z, dim_i, dim_j, 0);
  free(L);
  free(L_prime);
  free(Z);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lin_solve_PSD>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    $0x8,%esi
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  imul   %ecx,%r13d
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %r13d,%edi
  mov    %rdx,(%rsp)
  call   <calloc@plt>
  mov    %r13d,%edi
  mov    $0x8,%esi
  mov    %rax,%rbp
  call   <calloc@plt>
  mov    %r12d,%edi
  mov    $0x8,%esi
  imul   %ebx,%edi
  mov    %rax,%r14
  call   <calloc@plt>
  mov    0x8(%rsp),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%r13
  call   <mtx_chol@plt>
  mov    (%rsp),%rdx
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    $0x1,%r9d
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    %r12d,%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <mtx_transpose@plt>
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %r13,%rdx
  mov    %r15,%rsi
  xor    %r9d,%r9d
  mov    %r14,%rdi
  call   <lin_solve_triangular_equ@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <free@plt>
```

assistant: ```c
void lin_solve_PSD(double *A, double *X, double *B, int dim_i, int dim_j) {
  double *L = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *L_prime = (double *)calloc(dim_i * dim_i, sizeof(double));
  double *Z = (double *)calloc(dim_i * dim_j, sizeof(double));
  mtx_chol(A, L, dim_i);
  lin_solve_triangular_equ(L, Z, B, dim_i, dim_j, 1);
  mtx_transpose(L, L_prime, dim_i, dim_i);
  lin_solve_triangular_equ(L_prime, X, Z, dim_i, dim_j, 0);
  free(L);
  free(L_prime);
  free(Z);
}
```
user: What is the c source code of the assembly code below?

```asm
<intlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  nop
L9:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L9
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t intlen(int32_t *table) {
  int32_t len = 0;
  while (table[len++] != -1)
    ;
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<intlen>:
  endbr64
  mov    $0x1,%eax
L4:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpl   $0xffffffff,-0x8(%rdi,%rax,4)
  jne    L4
  mov    %edx,%eax
  ret
```

assistant: ```c
int32_t intlen(int32_t *table) {
  int32_t len = 0;
  while (table[len++] != -1)
    ;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<intlen>:
  endbr64
  mov    $0x1,%eax
  nopl   0x0(%rax)
L9:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpl   $0xffffffff,-0x8(%rdi,%rax,4)
  jne    L9
  mov    %r8d,%eax
  ret
```

assistant: ```c
int32_t intlen(int32_t *table) {
  int32_t len = 0;
  while (table[len++] != -1)
    ;
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intlen>:
  endbr64
  mov    $0x1,%eax
  nopl   0x0(%rax)
L7:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpl   $0xffffffff,-0x8(%rdi,%rax,4)
  jne    L7
  mov    %r8d,%eax
  ret
```

assistant: ```c
int32_t intlen(int32_t *table) {
  int32_t len = 0;
  while (table[len++] != -1)
    ;
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <vnormal@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vcopy@plt>
  movss  -0x1c(%rbp),%xmm0
  movss  D17(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vscale@plt>
  movss  -0x1c(%rbp),%xmm0
  movss  D17(%rip),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  lea    0xc(%rdx),%rbx
  movd   %eax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
datatype: f32

tool: D17: 2

assistant: ```c
void axis_to_quat(float a[3], float phi, float q[4]) {
  vnormal(a);
  vcopy(a, q);
  vscale(q, sin(phi / 2.0));
  q[3] = cos(phi / 2.0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  movss  %xmm0,0xc(%rsp)
  mov    %rsi,%rbx
  call   <vnormal@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vcopy@plt>
  movss  0xc(%rsp),%xmm1
  mulss  D8(%rip),%xmm1
  movd   %xmm1,%ebp
  movaps %xmm1,%xmm0
  call   <sin@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <vscale@plt>
  movd   %ebp,%xmm0
  call   <cos@plt>
  movss  %xmm0,0xc(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: byte[4]

tool: {"D8": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void axis_to_quat(float a[3], float phi, float q[4]) {
  vnormal(a);
  vcopy(a, q);
  vscale(q, sin(phi / 2.0));
  q[3] = cos(phi / 2.0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <vnormal@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vcopy@plt>
  movss  0xc(%rsp),%xmm0
  mulss  D2(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <vscale@plt>
  movss  0xc(%rsp),%xmm0
  call   <cos@plt>
  movss  %xmm0,0xc(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void axis_to_quat(float a[3], float phi, float q[4]) {
  vnormal(a);
  vcopy(a, q);
  vscale(q, sin(phi / 2.0));
  q[3] = cos(phi / 2.0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <vnormal@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vcopy@plt>
  movss  0xc(%rsp),%xmm0
  mulss  D0(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  call   <sin@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <vscale@plt>
  movss  0xc(%rsp),%xmm0
  call   <cos@plt>
  movss  %xmm0,0xc(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x3f]}

assistant: ```c
void axis_to_quat(float a[3], float phi, float q[4]) {
  vnormal(a);
  vcopy(a, q);
  vscale(q, sin(phi / 2.0));
  q[3] = cos(phi / 2.0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strupr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L6:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void strupr(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; s[i] = toupper(s[i]), i++)
    ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L2
L1:
  movsbl %dil,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
L2:
  pop    %rbx
  ret
```

assistant: ```c
void strupr(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; s[i] = toupper(s[i]), i++)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L19
L14:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L14
L19:
  pop    %rbx
  ret
```

assistant: ```c
void strupr(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; s[i] = toupper(s[i]), i++)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L8
L15:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L15
L8:
  pop    %rbx
  ret
```

assistant: ```c
void strupr(char *s) {
  int i;
  for (i = 0; s[i] != '\0'; s[i] = toupper(s[i]), i++)
    ;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_color_primaries>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <print_enum@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: color_primaries

assistant: ```c
void print_color_primaries() {
  static const char *COLOR_PRIMARIES_STRINGS[] = {
      "HDTV",
      "SDTV 525",
      "SDTV 625",
      "D-Cinema",
  };
  print_enum("color_primaries", COLOR_PRIMARIES_STRINGS, (sizeof(COLOR_PRIMARIES_STRINGS) / sizeof((COLOR_PRIMARIES_STRINGS)[0])));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_color_primaries>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edx
  lea    D15(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <print_enum@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type: string

tool: D12: color_primaries

assistant: ```c
void print_color_primaries() {
  static const char *COLOR_PRIMARIES_STRINGS[] = {
      "HDTV",
      "SDTV 525",
      "SDTV 625",
      "D-Cinema",
  };
  print_enum("color_primaries", COLOR_PRIMARIES_STRINGS, (sizeof(COLOR_PRIMARIES_STRINGS) / sizeof((COLOR_PRIMARIES_STRINGS)[0])));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_color_primaries>:
  endbr64
  mov    $0x4,%edx
  lea    D19(%rip),%rsi
  lea    D17(%rip),%rdi
  jmp    1050 <print_enum@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
datatype: string

tool: D17: color_primaries

assistant: ```c
void print_color_primaries() {
  static const char *COLOR_PRIMARIES_STRINGS[] = {
      "HDTV",
      "SDTV 525",
      "SDTV 625",
      "D-Cinema",
  };
  print_enum("color_primaries", COLOR_PRIMARIES_STRINGS, (sizeof(COLOR_PRIMARIES_STRINGS) / sizeof((COLOR_PRIMARIES_STRINGS)[0])));
}
```