ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sub_fun_3>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D15(%rip),%rdi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D15
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D15: sub_fun_2_1


tool: D12: sub_fun_2_2


assistant: ```c
char sub_fun_3(char x, char y) {
  char res;
  printf("sub_fun_2_1\n");
  ;
  res = x + y;
  ;
  printf("sub_fun_2_2\n");
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void yg() {
  int y1 __attribute__((blah));
  typedef int y2 __attribute__((blah));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<yg>:
  endbr64
  ret
```

assistant: ```c
void yg() {
  int y1 __attribute__((blah));
  typedef int y2 __attribute__((blah));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<yg>:
  endbr64
  ret
```

assistant: ```c
void yg() {
  int y1 __attribute__((blah));
  typedef int y2 __attribute__((blah));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yg>:
  endbr64
  ret
```

assistant: ```c
void yg() {
  int y1 __attribute__((blah));
  typedef int y2 __attribute__((blah));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<verify_benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x26ac,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L18
  mov    $0x0,%eax
  jmp    L5
L18:
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int verify_benchmark(int r) {
  int expected = 9900;
  if (r != expected)
    return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<verify_benchmark>:
  endbr64
  cmp    $0x26ac,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int verify_benchmark(int r) {
  int expected = 9900;
  if (r != expected)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<verify_benchmark>:
  endbr64
  xor    %eax,%eax
  cmp    $0x26ac,%edi
  sete   %al
  ret
```

assistant: ```c
int verify_benchmark(int r) {
  int expected = 9900;
  if (r != expected)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<verify_benchmark>:
  endbr64
  xor    %eax,%eax
  cmp    $0x26ac,%edi
  sete   %al
  ret
```

assistant: ```c
int verify_benchmark(int r) {
  int expected = 9900;
  if (r != expected)
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x9b,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D11(%rip),%r12
L8:
  lea    0x15(%rbx),%ebp
  add    $0x1,%ebx
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1b,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x6,%edx
  sub    %ebx,%edx
  mov    %ebp,%ecx
  mov    $0x1b,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L8
  mov    $0x1b,%esi
  lea    D73(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D65(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: tag: D70
type_guessed: string
name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D73
type_guessed: string
name: extract_symbolic_data
arguments: tag: D38
type_guessed: string
name: extract_symbolic_data
arguments: tag: D65
type_guessed: string
name: extract_symbolic_data
arguments: tag: D39
type_guessed: string
name: extract_symbolic_data
arguments: tag: D40
type_guessed: string
name: extract_symbolic_data
arguments: tag: D32
type_guessed: string
name: extract_symbolic_data
arguments: tag: D26
type_guessed: string

tool: D3: If you can read this, CSI is not working.

tool: D8: %c2J

tool: D70: If this is the first thing you can read, CSI is OK.

tool: D11: %c[%u;%uH*


tool: D73: %c[1mBold Text


tool: D38: %c[2mDim text


tool: D65: %c[4mUnderlined Text


tool: D39: %c[24mUn-underlined text


tool: D40: %c[7mReverse Text


tool: D32: %c[27mUn-reverse text


tool: D26: %c[m

assistant: ```c
main() {
  int x;
  printf("If you can read this, CSI is not working.\n");
  printf("%c2J", 155);
  printf("If this is the first thing you can read, CSI is OK.\n");
  for (x = 0; x < 5; x++) {
    printf("%c[%u;%uH*\n", 27, 1 + x, 21 + x);
    printf("%c[%u;%uH*\n", 27, 5 - x, 21 + x);
  }
  printf("%c[1mBold Text\n", 27);
  printf("%c[2mDim text\n", 27);
  printf("%c[4mUnderlined Text\n", 27);
  printf("%c[24mUn-underlined text\n", 27);
  printf("%c[7mReverse Text\n", 27);
  printf("%c[27mUn-reverse text\n", 27);
  printf("%c[m", 27);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D44(%rip),%rdi
  mov    $0x6,%r13d
  push   %r12
  push   %rbp
  lea    D87(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x9b,%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <puts@plt>
L1:
  lea    0x15(%rbx),%r12d
  add    $0x1,%ebx
  mov    $0x1b,%esi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    %ebx,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%edx
  xor    %eax,%eax
  mov    %r12d,%ecx
  sub    %ebx,%edx
  mov    $0x1b,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L1
  mov    $0x1b,%esi
  lea    D61(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D105(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D92(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D71(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D44
type_infered: string
name: disassemble_data
arguments: data_tag: D87
type_infered: string
name: disassemble_data
arguments: data_tag: D27
type_infered: string
name: disassemble_data
arguments: data_tag: D84
type_infered: string
name: disassemble_data
arguments: data_tag: D61
type_infered: string
name: disassemble_data
arguments: data_tag: D25
type_infered: string
name: disassemble_data
arguments: data_tag: D105
type_infered: string
name: disassemble_data
arguments: data_tag: D92
type_infered: string
name: disassemble_data
arguments: data_tag: D71
type_infered: string
name: disassemble_data
arguments: data_tag: D12
type_infered: string
name: disassemble_data
arguments: data_tag: D15
type_infered: string

tool: D44: If you can read this, CSI is not working.

tool: D87: %c[%u;%uH*


tool: D27: %c2J

tool: D84: If this is the first thing you can read, CSI is OK.

tool: D61: %c[1mBold Text


tool: D25: %c[2mDim text


tool: D105: %c[4mUnderlined Text


tool: D92: %c[24mUn-underlined text


tool: D71: %c[7mReverse Text


tool: D12: %c[27mUn-reverse text


tool: D15: %c[m

assistant: ```c
main() {
  int x;
  printf("If you can read this, CSI is not working.\n");
  printf("%c2J", 155);
  printf("If this is the first thing you can read, CSI is OK.\n");
  for (x = 0; x < 5; x++) {
    printf("%c[%u;%uH*\n", 27, 1 + x, 21 + x);
    printf("%c[%u;%uH*\n", 27, 5 - x, 21 + x);
  }
  printf("%c[1mBold Text\n", 27);
  printf("%c[2mDim text\n", 27);
  printf("%c[4mUnderlined Text\n", 27);
  printf("%c[24mUn-underlined text\n", 27);
  printf("%c[7mReverse Text\n", 27);
  printf("%c[27mUn-reverse text\n", 27);
  printf("%c[m", 27);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D36(%rip),%rdi
  mov    $0x6,%r13d
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x9b,%esi
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <puts@plt>
L2:
  lea    0x15(%rbx),%r12d
  add    $0x1,%ebx
  mov    $0x1b,%esi
  mov    %rbp,%rdi
  mov    %r12d,%ecx
  mov    %ebx,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13d,%edx
  xor    %eax,%eax
  mov    %r12d,%ecx
  sub    %ebx,%edx
  mov    $0x1b,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x5,%ebx
  jne    L2
  mov    $0x1b,%esi
  lea    D65(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D109(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D87(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D107(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1b,%esi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D36
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D76
type_guessed: string
name: unpack_data
arguments: label: D51
type_guessed: string
name: unpack_data
arguments: label: D65
type_guessed: string
name: unpack_data
arguments: label: D109
type_guessed: string
name: unpack_data
arguments: label: D87
type_guessed: string
name: unpack_data
arguments: label: D47
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D107
type_guessed: string
name: unpack_data
arguments: label: D49
type_guessed: string

tool: D36: If you can read this, CSI is not working.

tool: D10: %c[%u;%uH*


tool: D76: %c2J

tool: D51: If this is the first thing you can read, CSI is OK.

tool: D65: %c[1mBold Text


tool: D109: %c[2mDim text


tool: D87: %c[4mUnderlined Text


tool: D47: %c[24mUn-underlined text


tool: D5: %c[7mReverse Text


tool: D107: %c[27mUn-reverse text


tool: D49: %c[m

assistant: ```c
main() {
  int x;
  printf("If you can read this, CSI is not working.\n");
  printf("%c2J", 155);
  printf("If this is the first thing you can read, CSI is OK.\n");
  for (x = 0; x < 5; x++) {
    printf("%c[%u;%uH*\n", 27, 1 + x, 21 + x);
    printf("%c[%u;%uH*\n", 27, 5 - x, 21 + x);
  }
  printf("%c[1mBold Text\n", 27);
  printf("%c[2mDim text\n", 27);
  printf("%c[4mUnderlined Text\n", 27);
  printf("%c[24mUn-underlined text\n", 27);
  printf("%c[7mReverse Text\n", 27);
  printf("%c[27mUn-reverse text\n", 27);
  printf("%c[m", 27);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write32(unsigned int reg1, signed int val) {
  unsigned int *reg;
  reg = (unsigned int *)reg1;
  *(reg) = (int)val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write32>:
  endbr64
  mov    %esi,(%edi)
  ret
```

assistant: ```c
void write32(unsigned int reg1, signed int val) {
  unsigned int *reg;
  reg = (unsigned int *)reg1;
  *(reg) = (int)val;
}
```
user: What is the c source code of the assembly code below?

```asm
<write32>:
  endbr64
  mov    %esi,(%edi)
  ret
```

assistant: ```c
void write32(unsigned int reg1, signed int val) {
  unsigned int *reg;
  reg = (unsigned int *)reg1;
  *(reg) = (int)val;
}
```
user: What is the c source code of the assembly code below:

```asm
<write32>:
  endbr64
  mov    %esi,(%edi)
  ret
```

assistant: ```c
void write32(unsigned int reg1, signed int val) {
  unsigned int *reg;
  reg = (unsigned int *)reg1;
  *(reg) = (int)val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printwrap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strlcpy@plt>
  jmp    L20
L5:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <putcharwrap@plt>
L20:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void printwrap(FILE *f, const char *p) {
  char *q;
  char buf[12];
  q = buf;
  strlcpy(buf, p, sizeof(buf));
  while (*q)
    putcharwrap(f, *q++);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printwrap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    $0xc,%edx
  call   <strlcpy@plt>
  movzbl 0xc(%rsp),%esi
  test   %sil,%sil
  je     L8
  lea    0xc(%rsp),%rbx
L9:
  add    $0x1,%rbx
  movsbl %sil,%esi
  mov    %rbp,%rdi
  call   <putcharwrap@plt>
  movzbl (%rbx),%esi
  test   %sil,%sil
  jne    L9
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printwrap(FILE *f, const char *p) {
  char *q;
  char buf[12];
  q = buf;
  strlcpy(buf, p, sizeof(buf));
  while (*q)
    putcharwrap(f, *q++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printwrap>:
  endbr64
  push   %rbp
  mov    $0xc,%edx
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
  movsbl 0xc(%rsp),%esi
  test   %sil,%sil
  je     L19
  nopl   0x0(%rax)
L14:
  add    $0x1,%rbx
  mov    %rbp,%rdi
  call   <putcharwrap@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L14
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printwrap(FILE *f, const char *p) {
  char *q;
  char buf[12];
  q = buf;
  strlcpy(buf, p, sizeof(buf));
  while (*q)
    putcharwrap(f, *q++);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printwrap>:
  endbr64
  push   %rbp
  mov    $0xc,%edx
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strlcpy@plt>
  movsbl 0xc(%rsp),%esi
  test   %sil,%sil
  je     L0
  nopl   0x0(%rax)
L1:
  add    $0x1,%rbx
  mov    %rbp,%rdi
  call   <putcharwrap@plt>
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L1
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printwrap(FILE *f, const char *p) {
  char *q;
  char buf[12];
  q = buf;
  strlcpy(buf, p, sizeof(buf));
  while (*q)
    putcharwrap(f, *q++);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setsockopt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8d,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int setsockopt(int sockfd, int level, int optname, const void *optval, unsigned int optlen) {
  errno = ENOSYS;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setsockopt>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int setsockopt(int sockfd, int level, int optname, const void *optval, unsigned int optlen) {
  errno = ENOSYS;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setsockopt>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int setsockopt(int sockfd, int level, int optname, const void *optval, unsigned int optlen) {
  errno = ENOSYS;
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setsockopt>:
  endbr64
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int setsockopt(int sockfd, int level, int optname, const void *optval, unsigned int optlen) {
  errno = ENOSYS;
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_priv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  andb   $0xf,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  cmp    $0xf,%eax
  ja     L34
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D69(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D69(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D89(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
  lea    D59(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
  lea    D65(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
  lea    D77(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
  lea    D52(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
L34:
  lea    D88(%rip),%rax
  mov    %rax,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D89
data_type: string
name: retrieve_data
arguments: data_tag: D59
data_type: string
name: retrieve_data
arguments: data_tag: D65
data_type: string
name: retrieve_data
arguments: data_tag: D77
data_type: string
name: retrieve_data
arguments: data_tag: D52
data_type: string
name: retrieve_data
arguments: data_tag: D5
data_type: string
name: retrieve_data
arguments: data_tag: D88
data_type: string

tool: D89: Callback

tool: D59: User  

tool: D65: Operator

tool: D77: Admin 

tool: D52: OEM   

tool: D5: No access

tool: D88: Reserved

assistant: ```c
char *parse_priv(unsigned char c) {
  char *p;
  c = (c & 0x0f);
  switch (c) {
  case 1:
    p = "Callback";
    break;
  case 2:
    p = "User  ";
    break;
  case 3:
    p = "Operator";
    break;
  case 4:
    p = "Admin ";
    break;
  case 5:
    p = "OEM   ";
    break;
  case 0x0f:
    p = "No access";
    break;
  default:
    p = "Reserved";
  }
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_priv>:
  endbr64
  and    $0xf,%edi
  lea    D52(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D34(%rip),%rax
  ret
  lea    D54(%rip),%rax
  ret
  lea    D27(%rip),%rax
  ret
  lea    D15(%rip),%rax
  ret
  lea    D26(%rip),%rax
  ret
  lea    D47(%rip),%rax
  ret
  lea    D40(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D34
data_type: string
name: disassemble_data
arguments: data_label: D54
data_type: string
name: disassemble_data
arguments: data_label: D27
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string
name: disassemble_data
arguments: data_label: D26
data_type: string
name: disassemble_data
arguments: data_label: D47
data_type: string
name: disassemble_data
arguments: data_label: D40
data_type: string

tool: D34: User  

tool: D54: Operator

tool: D27: Admin 

tool: D15: OEM   

tool: D26: No access

tool: D47: Reserved

tool: D40: Callback

assistant: ```c
char *parse_priv(unsigned char c) {
  char *p;
  c = (c & 0x0f);
  switch (c) {
  case 1:
    p = "Callback";
    break;
  case 2:
    p = "User  ";
    break;
  case 3:
    p = "Operator";
    break;
  case 4:
    p = "Admin ";
    break;
  case 5:
    p = "OEM   ";
    break;
  case 0x0f:
    p = "No access";
    break;
  default:
    p = "Reserved";
  }
  return (p);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_priv>:
  endbr64
  lea    D26(%rip),%rdx
  and    $0xf,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  lea    D37(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D48(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D13(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D77(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D43(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D8(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D72(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D37
data_type: string
name: retrieve_data
arguments: data_tag: D48
data_type: string
name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D77
data_type: string
name: retrieve_data
arguments: data_tag: D43
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string
name: retrieve_data
arguments: data_tag: D72
data_type: string

tool: D37: Reserved

tool: D48: Operator

tool: D13: Admin 

tool: D77: OEM   

tool: D43: No access

tool: D8: Callback

tool: D72: User  

assistant: ```c
char *parse_priv(unsigned char c) {
  char *p;
  c = (c & 0x0f);
  switch (c) {
  case 1:
    p = "Callback";
    break;
  case 2:
    p = "User  ";
    break;
  case 3:
    p = "Operator";
    break;
  case 4:
    p = "Admin ";
    break;
  case 5:
    p = "OEM   ";
    break;
  case 0x0f:
    p = "No access";
    break;
  default:
    p = "Reserved";
  }
  return (p);
}
```