ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x1c(%rbp)
  jmp    L65
L38:
  mov    -0x1c(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L53
L2:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  add    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L83
L50:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  add    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L45:
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  add    $0x3e8,%eax
  mov    %eax,-0xc(%rbp)
L0:
  cmpl   $0x0,-0xc(%rbp)
  jns    L0
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L45
  subl   $0x1,-0x14(%rbp)
L83:
  cmpl   $0x0,-0x14(%rbp)
  jns    L50
  addl   $0x1,-0x18(%rbp)
L53:
  mov    -0x18(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L2
  addl   $0x1,-0x1c(%rbp)
L65:
  cmpl   $0x63,-0x1c(%rbp)
  jle    L38
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  int m;
  int a;
  int b;
  i = 0;
  while (i < 100) {
    a = i + 2;
    j = 0;
    while (j < a) {
      k = i + j + 3;
      while (k >= 0) {
        b = i + j + k + 4;
        l = 0;
        while (l < b) {
          m = i + j + k + l + 1000;
          while (m >= 0) {
            m = m - 0;
          }
          l = l + 1;
        }
        k = k - 1;
      }
      j = j + 1;
    }
    i = i + 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
L5:
  jmp    L5
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  int m;
  int a;
  int b;
  i = 0;
  while (i < 100) {
    a = i + 2;
    j = 0;
    while (j < a) {
      k = i + j + 3;
      while (k >= 0) {
        b = i + j + k + 4;
        l = 0;
        while (l < b) {
          m = i + j + k + l + 1000;
          while (m >= 0) {
            m = m - 0;
          }
          l = l + 1;
        }
        k = k - 1;
      }
      j = j + 1;
    }
    i = i + 1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  int m;
  int a;
  int b;
  i = 0;
  while (i < 100) {
    a = i + 2;
    j = 0;
    while (j < a) {
      k = i + j + 3;
      while (k >= 0) {
        b = i + j + k + 4;
        l = 0;
        while (l < b) {
          m = i + j + k + l + 1000;
          while (m >= 0) {
            m = m - 0;
          }
          l = l + 1;
        }
        k = k - 1;
      }
      j = j + 1;
    }
    i = i + 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L9:
  jmp    L9
```

assistant: ```c
int main() {
  int i;
  int j;
  int k;
  int l;
  int m;
  int a;
  int b;
  i = 0;
  while (i < 100) {
    a = i + 2;
    j = 0;
    while (j < a) {
      k = i + j + 3;
      while (k >= 0) {
        b = i + j + k + 4;
        l = 0;
        while (l < b) {
          m = i + j + k + l + 1000;
          while (m >= 0) {
            m = m - 0;
          }
          l = l + 1;
        }
        k = k - 1;
      }
      j = j + 1;
    }
    i = i + 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<copypad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L8:
  mov    -0x28(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L14:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L1
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  jmp    L1
L21:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movb   $0x20,(%rax)
L1:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L21
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copypad(char *restrict dst, size_t dst_len, const char *restrict src) {
  char *dst_end = dst + dst_len;
  while (dst < dst_end && *src)
    *dst++ = *src++;
  while (dst < dst_end)
    *dst++ = ' ';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<copypad>:
  endbr64
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  jae    L29
L20:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L20
  ret
L29:
  ret
L7:
  cmp    %rdi,%rsi
  jbe    L25
L1:
  add    $0x1,%rdi
  movb   $0x20,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L1
  ret
L25:
  ret
```

assistant: ```c
void copypad(char *restrict dst, size_t dst_len, const char *restrict src) {
  char *dst_end = dst + dst_len;
  while (dst < dst_end && *src)
    *dst++ = *src++;
  while (dst < dst_end)
    *dst++ = ' ';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copypad>:
  endbr64
  lea    (%rdi,%rsi,1),%rcx
  cmp    %rcx,%rdi
  jae    L9
  add    %rdx,%rsi
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rsi,%rdx
  je     L9
L5:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L45
  cmp    %rdi,%rcx
  jbe    L9
  sub    %rdi,%rcx
  mov    $0x20,%esi
  mov    %rcx,%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void copypad(char *restrict dst, size_t dst_len, const char *restrict src) {
  char *dst_end = dst + dst_len;
  while (dst < dst_end && *src)
    *dst++ = *src++;
  while (dst < dst_end)
    *dst++ = ' ';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copypad>:
  endbr64
  lea    (%rdi,%rsi,1),%rcx
  cmp    %rcx,%rdi
  jae    L47
  add    %rdx,%rsi
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rdx
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  cmp    %rsi,%rdx
  je     L47
L34:
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L29
  cmp    %rdi,%rcx
  jbe    L47
  sub    %rdi,%rcx
  mov    $0x20,%esi
  mov    %rcx,%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L47:
  ret
```

assistant: ```c
void copypad(char *restrict dst, size_t dst_len, const char *restrict src) {
  char *dst_end = dst + dst_len;
  while (dst < dst_end && *src)
    *dst++ = *src++;
  while (dst < dst_end)
    *dst++ = ' ';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<V_C>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  D44(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D52(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  movsd  -0x20(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  -0x18(%rbp),%xmm1
  mulsd  -0x8(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  movapd %xmm2,%xmm1
  movsd  D50(%rip),%xmm0
  movapd %xmm1,%xmm2
  addsd  %xmm0,%xmm2
  movsd  D50(%rip),%xmm0
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D50(%rip),%xmm0
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D27
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D44
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D52
datatype: f64
name: extract_symbolic_data
arguments: label: D0
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D50
datatype: byte[8]

tool: {"D27": [0x56,0xd7,0xcd,0xea,0xd4,0xf4,0x73,0x43]}

tool: {"D44": [0xfe,0x53,0x5e,0xd5,0xda,0xa4,0x07,0x3c]}

tool: D52: 1000000

tool: {"D0": [0xa5,0xdc,0x03,0x14,0xf8,0x71,0x60,0x3a]}

tool: {"D50": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double V_C(double M0, double E) {
  double c2 = 2.99792458E8 * 2.99792458E8;
  E = E * 1.60217733E-19 * 1.0E6;
  M0 = M0 * 1.660540E-27;
  return (sqrt(1 - (1 / ((E * E / (M0 * M0 * c2 * c2) + (2 * E / (M0 * c2)) + 1)))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<V_C>:
  endbr64
  sub    $0x8,%rsp
  mulsd  D10(%rip),%xmm1
  mulsd  D24(%rip),%xmm1
  movapd %xmm0,%xmm2
  mulsd  D49(%rip),%xmm2
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm2,%xmm3
  mulsd  %xmm2,%xmm3
  movsd  D42(%rip),%xmm4
  mulsd  %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  divsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm1
  mulsd  %xmm4,%xmm2
  divsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  D35(%rip),%xmm1
  addsd  %xmm1,%xmm0
  movapd %xmm1,%xmm2
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%edi
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: byte[8]
name: read_data
arguments: data_tag: D24
datatype: f64
name: read_data
arguments: data_tag: D49
datatype: byte[8]
name: read_data
arguments: data_tag: D42
datatype: byte[8]
name: read_data
arguments: data_tag: D35
datatype: byte[8]

tool: {"D10": [0xfe,0x53,0x5e,0xd5,0xda,0xa4,0x07,0x3c]}

tool: D24: 1000000

tool: {"D49": [0xa5,0xdc,0x03,0x14,0xf8,0x71,0x60,0x3a]}

tool: {"D42": [0x56,0xd7,0xcd,0xea,0xd4,0xf4,0x73,0x43]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double V_C(double M0, double E) {
  double c2 = 2.99792458E8 * 2.99792458E8;
  E = E * 1.60217733E-19 * 1.0E6;
  M0 = M0 * 1.660540E-27;
  return (sqrt(1 - (1 / ((E * E / (M0 * M0 * c2 * c2) + (2 * E / (M0 * c2)) + 1)))));
}
```
user: Translate the below assembly code into C programming language:

```asm
<V_C>:
  endbr64
  movsd  D1(%rip),%xmm2
  movsd  D3(%rip),%xmm4
  mulsd  D33(%rip),%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  D32(%rip),%xmm1
  movapd %xmm2,%xmm3
  mulsd  %xmm2,%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm1
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm3
  divsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm3
  divsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D17(%rip),%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%edi
  jmp    1050 <sqrt@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D3
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D33
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D32
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D17
data_type: byte[8]

tool: {"D1": [0xa5,0xdc,0x03,0x14,0xf8,0x71,0x60,0x3a]}

tool: {"D3": [0x56,0xd7,0xcd,0xea,0xd4,0xf4,0x73,0x43]}

tool: {"D33": [0xfe,0x53,0x5e,0xd5,0xda,0xa4,0x07,0x3c]}

tool: D32: 1000000

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double V_C(double M0, double E) {
  double c2 = 2.99792458E8 * 2.99792458E8;
  E = E * 1.60217733E-19 * 1.0E6;
  M0 = M0 * 1.660540E-27;
  return (sqrt(1 - (1 / ((E * E / (M0 * M0 * c2 * c2) + (2 * E / (M0 * c2)) + 1)))));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<V_C>:
  endbr64
  movsd  D48(%rip),%xmm2
  movsd  D28(%rip),%xmm4
  mulsd  D43(%rip),%xmm1
  mulsd  %xmm0,%xmm2
  mulsd  D5(%rip),%xmm1
  movapd %xmm2,%xmm3
  mulsd  %xmm2,%xmm3
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm1,%xmm1
  mulsd  %xmm4,%xmm2
  mulsd  %xmm4,%xmm3
  divsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm3
  divsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D26(%rip),%xmm1
  movapd %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%edi
  jmp    1050 <sqrt@plt>
```

tool_calls: name: unpack_data
arguments: tag: D48
type_guessed: byte[8]
name: unpack_data
arguments: tag: D28
type_guessed: byte[8]
name: unpack_data
arguments: tag: D43
type_guessed: byte[8]
name: unpack_data
arguments: tag: D5
type_guessed: f64
name: unpack_data
arguments: tag: D26
type_guessed: byte[8]

tool: {"D48": [0xa5,0xdc,0x03,0x14,0xf8,0x71,0x60,0x3a]}

tool: {"D28": [0x56,0xd7,0xcd,0xea,0xd4,0xf4,0x73,0x43]}

tool: {"D43": [0xfe,0x53,0x5e,0xd5,0xda,0xa4,0x07,0x3c]}

tool: D5: 1000000

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double V_C(double M0, double E) {
  double c2 = 2.99792458E8 * 2.99792458E8;
  E = E * 1.60217733E-19 * 1.0E6;
  M0 = M0 * 1.660540E-27;
  return (sqrt(1 - (1 / ((E * E / (M0 * M0 * c2 * c2) + (2 * E / (M0 * c2)) + 1)))));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<subtilis_utils_basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    -0x18(%rbp),%rax
  jmp    L60
L30:
  mov    -0x8(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L22
  subl   $0x1,-0xc(%rbp)
  jmp    L22
L67:
  subl   $0x1,-0xc(%rbp)
L22:
  cmpl   $0x0,-0xc(%rbp)
  js     L35
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L67
L35:
  cmpl   $0x0,-0xc(%rbp)
  js     L2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L60
L2:
  mov    -0x18(%rbp),%rax
L60:
  leave
  ret
```

assistant: ```c
const char *subtilis_utils_basename(const char *path) {
  size_t len = strlen(path);
  int i;
  if (len == 0)
    return path;
  i = ((int)len) - 1;
  if (path[i] == '.')
    i--;
  for (; i >= 0 && path[i] != '.'; i--)
    ;
  if (i >= 0)
    return &path[i + 1];
  else
    return path;
}
```
user: What is the c source code of the assembly code below:

```asm
<subtilis_utils_basename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L8
  lea    -0x1(%rax),%edx
  movslq %edx,%rcx
  cmpb   $0x2e,(%rbx,%rcx,1)
  je     L41
L45:
  test   %edx,%edx
  js     L8
  movslq %edx,%rax
L38:
  cmpb   $0x2e,(%rbx,%rax,1)
  je     L44
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L38
  jmp    L8
L41:
  lea    -0x2(%rax),%edx
  jmp    L45
L44:
  test   %eax,%eax
  js     L8
  movslq %eax,%rdx
  lea    0x1(%rbx,%rdx,1),%rbx
L8:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *subtilis_utils_basename(const char *path) {
  size_t len = strlen(path);
  int i;
  if (len == 0)
    return path;
  i = ((int)len) - 1;
  if (path[i] == '.')
    i--;
  for (; i >= 0 && path[i] != '.'; i--)
    ;
  if (i >= 0)
    return &path[i + 1];
  else
    return path;
}
```
user: What is the c source code of the assembly code below?

```asm
<subtilis_utils_basename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L17
  lea    -0x1(%rax),%edx
  movslq %edx,%rcx
  cmpb   $0x2e,(%r12,%rcx,1)
  je     L4
L63:
  test   %edx,%edx
  js     L17
  movslq %edx,%rax
  jmp    L33
  nopl   0x0(%rax)
L41:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L17
L33:
  cmpb   $0x2e,(%r12,%rax,1)
  mov    %eax,%edx
  jne    L41
  add    $0x1,%edx
  movslq %edx,%rdx
  add    %rdx,%r12
L17:
  mov    %r12,%rax
  pop    %r12
  ret
L4:
  lea    -0x2(%rax),%edx
  jmp    L63
```

assistant: ```c
const char *subtilis_utils_basename(const char *path) {
  size_t len = strlen(path);
  int i;
  if (len == 0)
    return path;
  i = ((int)len) - 1;
  if (path[i] == '.')
    i--;
  for (; i >= 0 && path[i] != '.'; i--)
    ;
  if (i >= 0)
    return &path[i + 1];
  else
    return path;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<subtilis_utils_basename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  test   %rax,%rax
  je     L11
  lea    -0x1(%rax),%edx
  movslq %edx,%rcx
  cmpb   $0x2e,(%r12,%rcx,1)
  je     L43
L38:
  test   %edx,%edx
  js     L11
  movslq %edx,%rax
  jmp    L3
  nopl   0x0(%rax)
L52:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L11
L3:
  cmpb   $0x2e,(%r12,%rax,1)
  mov    %eax,%edx
  jne    L52
  add    $0x1,%edx
  movslq %edx,%rdx
  add    %rdx,%r12
L11:
  mov    %r12,%rax
  pop    %r12
  ret
L43:
  lea    -0x2(%rax),%edx
  jmp    L38
```

assistant: ```c
const char *subtilis_utils_basename(const char *path) {
  size_t len = strlen(path);
  int i;
  if (len == 0)
    return path;
  i = ((int)len) - 1;
  if (path[i] == '.')
    i--;
  for (; i >= 0 && path[i] != '.'; i--)
    ;
  if (i >= 0)
    return &path[i + 1];
  else
    return path;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x14(%rbp)
  jg     L51
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L49
L51:
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L25:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L61
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L53
L61:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <print_info@plt>
L53:
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
  mov    $0x0,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_infered: string
name: read_data
arguments: tag: D8
type_infered: string

tool: D3: Missing input files

tool: D8: File: '%s':


assistant: ```c
int main(int argc, char *argv[]) {
  struct stat buf;
  int i;
  if (argc < 2) {
    printf("Missing input files\n");
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if (stat(argv[i], &buf) != 0) {
      perror(argv[i]);
      continue;
    }
    printf("File: '%s':\n", argv[i]);
    print_info(&buf);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L38
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%rbp
  lea    D3(%rip),%r12
  jmp    L35
L38:
  lea    D7(%rip),%rdi
  call   <puts@plt>
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdi
  call   <print_info@plt>
L15:
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  je     L25
L35:
  lea    0x4(%rsp),%rsi
  mov    (%rbx),%rdi
  call   <stat@plt>
  test   %rax,%rax
  je     L49
  mov    (%rbx),%rdi
  call   <perror@plt>
  jmp    L15
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string

tool: D3: File: '%s':


tool: D7: Missing input files

assistant: ```c
int main(int argc, char *argv[]) {
  struct stat buf;
  int i;
  if (argc < 2) {
    printf("Missing input files\n");
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if (stat(argv[i], &buf) != 0) {
      perror(argv[i]);
      continue;
    }
    printf("File: '%s':\n", argv[i]);
    print_info(&buf);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L35
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    0x4(%rsp),%rbp
  lea    D17(%rip),%r13
  jmp    L26
  nopl   (%rax)
L19:
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_info@plt>
  cmp    %r12,%rbx
  je     L5
L26:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L19
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <perror@plt>
  cmp    %r12,%rbx
  jne    L26
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  jmp    L5
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D7
type_guessed: string

tool: D17: File: '%s':


tool: D7: Missing input files

assistant: ```c
int main(int argc, char *argv[]) {
  struct stat buf;
  int i;
  if (argc < 2) {
    printf("Missing input files\n");
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if (stat(argv[i], &buf) != 0) {
      perror(argv[i]);
      continue;
    }
    printf("File: '%s':\n", argv[i]);
    print_info(&buf);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L14
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  lea    0x4(%rsp),%rbp
  lea    D14(%rip),%r13
  jmp    L48
  nopl   (%rax)
L32:
  mov    (%rbx),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <print_info@plt>
  cmp    %r12,%rbx
  je     L40
L48:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  je     L32
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <perror@plt>
  cmp    %r12,%rbx
  jne    L48
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  jmp    L40
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D15
data_type: string

tool: D14: File: '%s':


tool: D15: Missing input files

assistant: ```c
int main(int argc, char *argv[]) {
  struct stat buf;
  int i;
  if (argc < 2) {
    printf("Missing input files\n");
    return 0;
  }
  for (i = 1; i < argc; i++) {
    if (stat(argv[i], &buf) != 0) {
      perror(argv[i]);
      continue;
    }
    printf("File: '%s':\n", argv[i]);
    print_info(&buf);
  }
  return 0;
}
```