ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<transform>:
  endbr64
  push   %rbx
  movq   %xmm2,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <isinf@plt>
  test   %rax,%rax
  jne    L42
  movq   %rbx,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L6
L42:
  movq   %rbx,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L28
L50:
  movq   %rbx,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L12
L29:
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movsd  0x8(%rsp),%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L50
  movq   %rbx,%xmm0
  subsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  jmp    1080 <log@plt>
  nopl   0x0(%rax)
L12:
  movsd  0x8(%rsp),%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L29
  movsd  0x8(%rsp),%xmm5
  movsd  (%rsp),%xmm0
  movq   %rbx,%xmm1
  add    $0x10,%rsp
  pop    %rbx
  subsd  %xmm5,%xmm0
  subsd  %xmm5,%xmm1
  divsd  %xmm1,%xmm0
  jmp    1070 <logit@plt>
  cs nopw 0x0(%rax,%rax,1)
L6:
  movsd  (%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  jmp    1080 <log@plt>
```

assistant: ```c
double transform(double x, double lb, double ub) {
  if (!isinf(lb) && isinf(ub)) {
    return log(x - lb);
  } else if (!isinf(ub) && isinf(lb)) {
    return log(ub - x);
  } else if (!isinf(ub) && !isinf(lb)) {
    return logit((x - lb) / (ub - lb));
  }
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<transform>:
  endbr64
  push   %rbx
  movq   %xmm2,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <isinf@plt>
  test   %rax,%rax
  jne    L2
  movq   %rbx,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L56
L2:
  movq   %rbx,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L24
L33:
  movq   %rbx,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L32
L14:
  movsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  movsd  0x8(%rsp),%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L33
  movq   %rbx,%xmm0
  subsd  (%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  jmp    1080 <log@plt>
  nopl   0x0(%rax)
L32:
  movsd  0x8(%rsp),%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  jne    L14
  movsd  0x8(%rsp),%xmm5
  movsd  (%rsp),%xmm0
  movq   %rbx,%xmm1
  add    $0x10,%rsp
  pop    %rbx
  subsd  %xmm5,%xmm0
  subsd  %xmm5,%xmm1
  divsd  %xmm1,%xmm0
  jmp    1070 <logit@plt>
  cs nopw 0x0(%rax,%rax,1)
L56:
  movsd  (%rsp),%xmm0
  subsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  jmp    1080 <log@plt>
```

assistant: ```c
double transform(double x, double lb, double ub) {
  if (!isinf(lb) && isinf(ub)) {
    return log(x - lb);
  } else if (!isinf(ub) && isinf(lb)) {
    return log(ub - x);
  } else if (!isinf(ub) && !isinf(lb)) {
    return logit((x - lb) / (ub - lb));
  }
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<media>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L3:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <inputint@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L3
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  movss  -0x8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: inserisci un numero

assistant: ```c
float media(int a) {
  float media;
  int b = a;
  do {
    media += inputint("inserisci un numero");
    a--;
  } while (a);
  return media / b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<media>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %edi,%ebx
  lea    D1(%rip),%rbp
L7:
  mov    %rbp,%rdi
  call   <inputint@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L7
  pxor   %xmm1,%xmm1
  cvtsi2ss %r12d,%xmm1
  divss  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: inserisci un numero

assistant: ```c
float media(int a) {
  float media;
  int b = a;
  do {
    media += inputint("inserisci un numero");
    a--;
  } while (a);
  return media / b;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<media>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  call   <inputint@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L6
  pxor   %xmm1,%xmm1
  add    $0x10,%rsp
  cvtsi2ss %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: inserisci un numero

assistant: ```c
float media(int a) {
  float media;
  int b = a;
  do {
    media += inputint("inserisci un numero");
    a--;
  } while (a);
  return media / b;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<media>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x10,%rsp
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rdi
  call   <inputint@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L7
  pxor   %xmm1,%xmm1
  add    $0x10,%rsp
  cvtsi2ss %r12d,%xmm1
  pop    %rbx
  pop    %rbp
  pop    %r12
  divss  %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D3: inserisci un numero

assistant: ```c
float media(int a) {
  float media;
  int b = a;
  do {
    media += inputint("inserisci un numero");
    a--;
  } while (a);
  return media / b;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<file_getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L39
  mov    $0x0,%eax
  jmp    L27
L39:
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L23:
  cmpl   $0x0,-0x8(%rbp)
  jle    L72
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L6
L72:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jne    L16
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L23
  jmp    L67
L6:
  nop
  jmp    L67
L16:
  nop
L67:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
L27:
  leave
  ret
```

assistant: ```c
int file_getline(int fd, char *line, int len) {
  int i;
  int num;
  if (!fd) {
    return 0;
  }
  for (i = 0; i < len - 1; i++) {
    if (i > 0 && line[i - 1] == '\n') {
      break;
    }
    num = read(fd, line + i, 1);
    if (num != 1) {
      break;
    }
  }
  line[i] = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<file_getline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  test   %edi,%edi
  je     L58
  mov    %edi,%r13d
  mov    %rsi,%r15
  cmp    $0x1,%edx
  jle    L18
  mov    %rsi,%rbp
  lea    -0x1(%rdx),%r14d
  mov    $0x0,%ebx
  jmp    L57
L19:
  add    $0x1,%rbp
L57:
  mov    %rbp,%r12
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  cmp    $0x1,%eax
  jne    L64
  add    $0x1,%ebx
  cmp    %r14d,%ebx
  je     L67
  test   %ebx,%ebx
  jle    L19
  cmpb   $0xa,(%r12)
  jne    L19
  jmp    L64
L67:
  mov    %r14d,%ebx
L64:
  movslq %ebx,%rax
  movb   $0x0,(%r15,%rax,1)
L58:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    $0x0,%ebx
  jmp    L64
```

assistant: ```c
int file_getline(int fd, char *line, int len) {
  int i;
  int num;
  if (!fd) {
    return 0;
  }
  for (i = 0; i < len - 1; i++) {
    if (i > 0 && line[i - 1] == '\n') {
      break;
    }
    num = read(fd, line + i, 1);
    if (num != 1) {
      break;
    }
  }
  line[i] = '\0';
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_getline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L11
  mov    %rsi,%r15
  mov    %rsi,%rbp
  cmp    $0x1,%edx
  jle    L36
  lea    -0x2(%rdx),%r14d
  mov    %edi,%r13d
  mov    %rsi,%rax
  mov    $0x1,%ebx
  add    $0x1,%r14
  jmp    L54
  nopl   0x0(%rax)
L41:
  mov    %ebx,%r12d
  cmp    %r14,%rbx
  je     L28
  cmpb   $0xa,0x0(%rbp)
  lea    0x1(%rbx),%rdx
  lea    0x1(%rbp),%rax
  je     L28
  mov    %rdx,%rbx
L54:
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    %r13d,%edi
  mov    %rax,%rbp
  lea    -0x1(%rbx),%r12d
  call   <read@plt>
  cmp    $0x1,%eax
  je     L41
L36:
  movb   $0x0,0x0(%rbp)
L11:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    (%r15,%rbx,1),%rbp
  jmp    L36
```

assistant: ```c
int file_getline(int fd, char *line, int len) {
  int i;
  int num;
  if (!fd) {
    return 0;
  }
  for (i = 0; i < len - 1; i++) {
    if (i > 0 && line[i - 1] == '\n') {
      break;
    }
    num = read(fd, line + i, 1);
    if (num != 1) {
      break;
    }
  }
  line[i] = '\0';
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<file_getline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L21
  mov    %rsi,%r15
  mov    %rsi,%rbp
  cmp    $0x1,%edx
  jle    L7
  lea    -0x2(%rdx),%r14d
  mov    %edi,%r13d
  mov    %rsi,%rax
  mov    $0x1,%ebx
  add    $0x1,%r14
  jmp    L54
  nopl   0x0(%rax)
L53:
  mov    %ebx,%r12d
  cmp    %r14,%rbx
  je     L32
  cmpb   $0xa,0x0(%rbp)
  lea    0x1(%rbx),%rdx
  lea    0x1(%rbp),%rax
  je     L32
  mov    %rdx,%rbx
L54:
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    %r13d,%edi
  mov    %rax,%rbp
  lea    -0x1(%rbx),%r12d
  call   <read@plt>
  cmp    $0x1,%eax
  je     L53
L7:
  movb   $0x0,0x0(%rbp)
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  lea    (%r15,%rbx,1),%rbp
  jmp    L7
```

assistant: ```c
int file_getline(int fd, char *line, int len) {
  int i;
  int num;
  if (!fd) {
    return 0;
  }
  for (i = 0; i < len - 1; i++) {
    if (i > 0 && line[i - 1] == '\n') {
      break;
    }
    num = read(fd, line + i, 1);
    if (num != 1) {
      break;
    }
  }
  line[i] = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <iniciaPinos@plt>
  mov    $0x0,%eax
  call   <confTimerA0@plt>
  mov    $0x0,%eax
  call   <iniciaOperacao@plt>
  mov    $0x10,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: Cont 1seg = %d


assistant: ```c
void main() {
  iniciaPinos();
  confTimerA0();
  iniciaOperacao();
  printf("Cont 1seg = %d\n", (int)(1048576 / 65536));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <iniciaPinos@plt>
  mov    $0x0,%eax
  call   <confTimerA0@plt>
  mov    $0x0,%eax
  call   <iniciaOperacao@plt>
  mov    $0x10,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9: Cont 1seg = %d


assistant: ```c
void main() {
  iniciaPinos();
  confTimerA0();
  iniciaOperacao();
  printf("Cont 1seg = %d\n", (int)(1048576 / 65536));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <iniciaPinos@plt>
  xor    %eax,%eax
  call   <confTimerA0@plt>
  xor    %eax,%eax
  call   <iniciaOperacao@plt>
  mov    $0x10,%esi
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: Cont 1seg = %d


assistant: ```c
void main() {
  iniciaPinos();
  confTimerA0();
  iniciaOperacao();
  printf("Cont 1seg = %d\n", (int)(1048576 / 65536));
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <iniciaPinos@plt>
  xor    %eax,%eax
  call   <confTimerA0@plt>
  xor    %eax,%eax
  call   <iniciaOperacao@plt>
  mov    $0x10,%esi
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1090 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string

tool: D8: Cont 1seg = %d


assistant: ```c
void main() {
  iniciaPinos();
  confTimerA0();
  iniciaOperacao();
  printf("Cont 1seg = %d\n", (int)(1048576 / 65536));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x94(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x8c(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x88(%rbp)
  cmpq   $0x0,-0x88(%rbp)
  jne    L25
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L25
L24:
  mov    -0x8c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8c(%rbp)
  lea    -0x7a(%rbp),%rdi
  mov    %eax,%ecx
  lea    D38(%rip),%rax
  mov    %rax,%rdx
  mov    $0xa,%esi
  call   <snprintf@plt>
  lea    -0x7a(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <add_to_cache@plt>
L25:
  mov    -0x88(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    $0x64,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L24
  mov    -0x88(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D36
type_infered: string
name: parse_data
arguments: data_tag: D38
type_infered: string

tool: D25: r

tool: D14: test65.dat

tool: D36: can't open: 

tool: D38: %u

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  if ((file = fopen("test65.dat", "r")) == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rsi
  lea    D27(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L39:
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
  jmp    L22
L9:
  lea    D39(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L39
L26:
  lea    0x1(%rbx),%r14d
  lea    0x6(%rsp),%rbp
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <add_to_cache@plt>
  mov    %r14d,%ebx
L22:
  lea    0x10(%rsp),%rdi
  mov    %r12,%rdx
  mov    $0x64,%esi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L26
  mov    %r12,%rdi
  call   <fclose@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
data_type: string
name: extract_symbolic_data
arguments: data_tag: D27
data_type: string
name: extract_symbolic_data
arguments: data_tag: D7
data_type: string
name: extract_symbolic_data
arguments: data_tag: D39
data_type: string

tool: D8: r

tool: D27: test65.dat

tool: D7: %u

tool: D39: can't open: 

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  if ((file = fopen("test65.dat", "r")) == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%rsi
  lea    D1(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L0
L49:
  xor    %r12d,%r12d
  lea    0x10(%rsp),%rbx
  lea    D0(%rip),%r14
  jmp    L46
  nopl   (%rax)
L3:
  lea    0x6(%rsp),%rbp
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  lea    0x1(%r12),%r15d
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r15d,%r12d
  call   <add_to_cache@plt>
L46:
  mov    %r13,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L3
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  lea    D19(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L49
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D0
type: string
name: disassemble_data
arguments: data_label: D19
type: string

tool: D28: r

tool: D1: test65.dat

tool: D0: %u

tool: D19: can't open: 

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  if ((file = fopen("test65.dat", "r")) == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%rsi
  lea    D23(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L42
L28:
  xor    %r12d,%r12d
  lea    0x10(%rsp),%rbx
  lea    D13(%rip),%r14
  jmp    L30
  nopl   (%rax)
L49:
  lea    0x6(%rsp),%rbp
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    $0xa,%esi
  mov    %rbp,%rdi
  lea    0x1(%r12),%r15d
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r15d,%r12d
  call   <add_to_cache@plt>
L30:
  mov    %r13,%rdx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L49
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
  jmp    L28
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
type_guessed: string
name: retrieve_data
arguments: label: D23
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D37: r

tool: D23: test65.dat

tool: D13: %u

tool: D3: can't open: 

assistant: ```c
int main(int argc, char *argv[]) {
  char linebuf[100], nbuf[10];
  FILE *file;
  int i = 0;
  if ((file = fopen("test65.dat", "r")) == NULL) {
    perror("can't open: ");
    exit(-1);
  }
  while (fgets(linebuf, sizeof(linebuf), file) != NULL) {
    snprintf(nbuf, sizeof(nbuf), "%u", i++);
    add_to_cache(linebuf, nbuf);
  }
  fclose(file);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  movl   $0x3,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  mov    -0x1c(%rbp),%esi
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type: string
name: parse_data
arguments: tag: D8
type: string

tool: D13: %d

tool: D8: 
%d

assistant: ```c
int main() {
  int display;
  int par;
  int i;
  int j;
  int k;
  int chamada;
  scanf("%d", &par);
  i = 1;
  j = 3;
  k = 4;
  chamada = foo(i, par, j, k);
  printf("\n%d", chamada);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    $0x4,%ecx
  mov    $0x3,%edx
  mov    0x4(%rsp),%esi
  mov    $0x1,%edi
  call   <foo@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D18
datatype: string

tool: D2: %d

tool: D18: 
%d

assistant: ```c
int main() {
  int display;
  int par;
  int i;
  int j;
  int k;
  int chamada;
  scanf("%d", &par);
  i = 1;
  j = 3;
  k = 4;
  chamada = foo(i, par, j, k);
  printf("\n%d", chamada);
}
```