user: 下面的汇编指令对应的C源代码是什么:

```asm
<SubStr>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <StrLength@plt>
  test   %r12d,%r12d
  mov    %ebp,%edx
  mov    %r13,%rdi
  setle  %r14b
  shr    $0x1f,%edx
  or     %edx,%r14d
  cmp    %r12d,%eax
  setl   %al
  or     %eax,%r14d
  call   <StrLength@plt>
  sub    %r12d,%eax
  add    $0x1,%eax
  cmp    %ebp,%eax
  jl     L124
  test   %r14b,%r14b
  jne    L124
  test   %ebp,%ebp
  je     L63
  movslq %r12d,%rax
  mov    %rbx,%rdi
  lea    -0x1(%rbp),%edx
  mov    %ebp,%esi
  lea    0x0(%r13,%rax,1),%rcx
  sub    %rcx,%rdi
  cmp    $0xe,%rdi
  jbe    L156
  cmp    $0x6,%edx
  jbe    L156
  cmp    $0xe,%edx
  jbe    L130
  mov    %ebp,%edx
  lea    -0x1(%r13,%rax,1),%rsi
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nopl   (%rax)
L93:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L93
  mov    %ebp,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebp
  je     L49
  mov    %ebp,%esi
  sub    %edx,%esi
  lea    -0x1(%rsi),%edi
  cmp    $0x6,%edi
  jbe    L153
L43:
  mov    -0x1(%rdx,%rcx,1),%rcx
  mov    %rcx,(%rbx,%rdx,1)
  mov    %esi,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%esi
  je     L49
L153:
  lea    (%r12,%rax,1),%edx
  movslq %edx,%rdx
  movzbl -0x1(%r13,%rdx,1),%ecx
  movslq %eax,%rdx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L49
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl -0x1(%r13,%rcx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebp
  jle    L49
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl -0x1(%r13,%rcx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebp
  jle    L49
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl -0x1(%r13,%rcx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebp
  jle    L49
  lea    (%r12,%rdx,1),%ecx
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl -0x1(%r13,%rcx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebp
  jle    L49
  lea    (%r12,%rdx,1),%ecx
  add    $0x6,%eax
  movslq %edx,%rdx
  movslq %ecx,%rcx
  movzbl -0x1(%r13,%rcx,1),%ecx
  mov    %cl,(%rbx,%rdx,1)
  cmp    %eax,%ebp
  jle    L49
  add    %eax,%r12d
  cltq
  movslq %r12d,%r12
  movzbl -0x1(%r13,%r12,1),%edx
  mov    %dl,(%rbx,%rax,1)
L49:
  movslq %ebp,%rbp
  add    %rbp,%rbx
L63:
  movb   $0x0,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L124:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L156:
  mov    %ebp,%esi
  xor    %eax,%eax
  nopl   0x0(%rax)
L71:
  movzbl -0x1(%rcx,%rax,1),%edx
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L71
  jmp    L49
L130:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L43
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: wrong parameter


assistant: ```c
int SubStr(char *dst, char *src, int i, int len) {
  if (i<1 | i> StrLength(src) | len<0 | len> StrLength(src) - i + 1) {
    printf("wrong parameter\n");
    return 0;
  }
  int j = 0;
  while (j < len) {
    dst[j] = src[i + j - 1];
    ++j;
  }
  dst[j] = '\0';
  return 1;
}
```