ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<num_to_str>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x30,%esi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x21,%edx
  push   %rbx
  mov    %edi,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <memset@plt>
  movb   $0x0,0x20(%rsp)
  mov    $0x1f,%ecx
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %edx,%ecx
  mov    %eax,%ebx
L9:
  xor    %edx,%edx
  mov    %ebx,%eax
  div    %r12d
  lea    0x37(%rdx),%edi
  lea    0x30(%rdx),%esi
  cmp    $0xa,%dl
  cmovge %edi,%esi
  lea    -0x1(%rcx),%edx
  mov    %sil,(%rsp,%rcx,1)
  cmp    %r12d,%ebx
  jae    L20
  mov    %r13,%rdi
  call   <remove_zeros@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void num_to_str(unsigned int n, unsigned int base, char *output) {
  char buf[33];
  memset(buf, '0', sizeof(buf));
  *(buf + 32) = '\0';
  unsigned int ind = 31;
  do {
    char c = n % base;
    if (c > 9) {
      c = c - 10 + 'A';
    } else {
      c = c + '0';
    }
    buf[ind--] = c;
    n = n / base;
  } while (n > 0);
  remove_zeros(buf);
  strcpy(output, buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<num_to_str>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x30,%esi
  push   %rbp
  mov    %rdx,%rbp
  mov    $0x21,%edx
  push   %rbx
  mov    %edi,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <memset@plt>
  movb   $0x0,0x20(%rsp)
  mov    $0x1f,%ecx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L5:
  add    $0x37,%edx
  mov    %dl,(%rsp,%rcx,1)
  cmp    %ebx,%r12d
  ja     L11
L3:
  mov    %esi,%ecx
  mov    %eax,%ebx
L29:
  mov    %ebx,%eax
  xor    %edx,%edx
  lea    -0x1(%rcx),%esi
  div    %r12d
  cmp    $0x9,%dl
  jg     L5
  add    $0x30,%edx
  mov    %dl,(%rsp,%rcx,1)
  cmp    %ebx,%r12d
  jbe    L3
L11:
  mov    %r13,%rdi
  call   <remove_zeros@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void num_to_str(unsigned int n, unsigned int base, char *output) {
  char buf[33];
  memset(buf, '0', sizeof(buf));
  *(buf + 32) = '\0';
  unsigned int ind = 31;
  do {
    char c = n % base;
    if (c > 9) {
      c = c - 10 + 'A';
    } else {
      c = c + '0';
    }
    buf[ind--] = c;
    n = n / base;
  } while (n > 0);
  remove_zeros(buf);
  strcpy(output, buf);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memset15_region_cast>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x14,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x10(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void memset15_region_cast() {
  char *str = (char *)malloc(10 * sizeof(int));
  int *array = (int *)str;
  memset(array, 0, 5 * sizeof(int));
  clang_analyzer_eval(str[10] == '\0');
  clang_analyzer_eval(strlen((char *)array) == 0);
  clang_analyzer_eval(strlen(str) == 0);
  free(str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memset15_region_cast>:
  endbr64
  push   %rbx
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x14,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  cmpb   $0x0,0xa(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  cmpb   $0x0,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  cmpb   $0x0,(%rbx)
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void memset15_region_cast() {
  char *str = (char *)malloc(10 * sizeof(int));
  int *array = (int *)str;
  memset(array, 0, 5 * sizeof(int));
  clang_analyzer_eval(str[10] == '\0');
  clang_analyzer_eval(strlen((char *)array) == 0);
  clang_analyzer_eval(strlen(str) == 0);
  free(str);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memset15_region_cast>:
  endbr64
  push   %rbp
  mov    $0x28,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    $0x14,%edx
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  xor    %edi,%edi
  cmpb   $0x0,0xa(%rbp)
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmpb   $0x0,0x0(%rbp)
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmpb   $0x0,0x0(%rbp)
  sete   %dil
  call   <clang_analyzer_eval@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

assistant: ```c
void memset15_region_cast() {
  char *str = (char *)malloc(10 * sizeof(int));
  int *array = (int *)str;
  memset(array, 0, 5 * sizeof(int));
  clang_analyzer_eval(str[10] == '\0');
  clang_analyzer_eval(strlen((char *)array) == 0);
  clang_analyzer_eval(strlen(str) == 0);
  free(str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memset15_region_cast>:
  endbr64
  push   %rbp
  mov    $0x28,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    $0x14,%edx
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <memset@plt>
  xor    %edi,%edi
  cmpb   $0x0,0xa(%rbp)
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmpb   $0x0,0x0(%rbp)
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmpb   $0x0,0x0(%rbp)
  sete   %dil
  call   <clang_analyzer_eval@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

assistant: ```c
void memset15_region_cast() {
  char *str = (char *)malloc(10 * sizeof(int));
  int *array = (int *)str;
  memset(array, 0, 5 * sizeof(int));
  clang_analyzer_eval(str[10] == '\0');
  clang_analyzer_eval(strlen((char *)array) == 0);
  clang_analyzer_eval(strlen(str) == 0);
  free(str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jhc_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <jhc_malloc_basic@plt>
  leave
  ret
```

assistant: ```c
void *__attribute__((malloc)) jhc_malloc(size_t n) {
  do {
  } while (0);
  return jhc_malloc_basic(n);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<jhc_malloc>:
  endbr64
  sub    $0x8,%rsp
  call   <jhc_malloc_basic@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *__attribute__((malloc)) jhc_malloc(size_t n) {
  do {
  } while (0);
  return jhc_malloc_basic(n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jhc_malloc>:
  endbr64
  jmp    1050 <jhc_malloc_basic@plt>
```

assistant: ```c
void *__attribute__((malloc)) jhc_malloc(size_t n) {
  do {
  } while (0);
  return jhc_malloc_basic(n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jhc_malloc>:
  endbr64
  jmp    1050 <jhc_malloc_basic@plt>
```

assistant: ```c
void *__attribute__((malloc)) jhc_malloc(size_t n) {
  do {
  } while (0);
  return jhc_malloc_basic(n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BNDM>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x450,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %esi,-0x43c(%rbp)
  mov    %rdx,-0x448(%rbp)
  mov    %ecx,-0x440(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x40,-0x43c(%rbp)
  jle    L101
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <error@plt>
L101:
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,-0x41c(%rbp)
  mov    -0x43c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x424(%rbp)
  jmp    L59
L78:
  mov    -0x424(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x438(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  mov    -0x424(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x438(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%ecx
  or     -0x41c(%rbp),%eax
  mov    %eax,%edx
  movslq %ecx,%rax
  mov    %edx,-0x410(%rbp,%rax,4)
  shll   -0x41c(%rbp)
  subl   $0x1,-0x424(%rbp)
L59:
  cmpl   $0x0,-0x424(%rbp)
  jns    L78
  movl   $0x0,-0x420(%rbp)
  jmp    L25
L79:
  mov    -0x43c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x424(%rbp)
  mov    -0x43c(%rbp),%eax
  mov    %eax,-0x414(%rbp)
  movl   $0xffffffff,-0x418(%rbp)
  jmp    L65
L30:
  mov    -0x420(%rbp),%edx
  mov    -0x424(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x448(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cltq
  mov    -0x410(%rbp,%rax,4),%eax
  and    %eax,-0x418(%rbp)
  subl   $0x1,-0x424(%rbp)
  cmpl   $0x0,-0x418(%rbp)
  je     L0
  cmpl   $0x0,-0x424(%rbp)
  js     L0
  mov    -0x424(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x414(%rbp)
L0:
  shll   -0x418(%rbp)
L65:
  cmpl   $0x0,-0x424(%rbp)
  js     L99
  cmpl   $0x0,-0x418(%rbp)
  jne    L30
L99:
  mov    -0x414(%rbp),%eax
  add    %eax,-0x420(%rbp)
L25:
  mov    -0x440(%rbp),%eax
  sub    -0x43c(%rbp),%eax
  cmp    %eax,-0x420(%rbp)
  jle    L79
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: BNDM

assistant: ```c
void BNDM(char *x, int m, char *y, int n) {
  int B[256];
  int i, j, s, d, last;
  if (m > 64)
    error("BNDM");
  memset(B, 0, 256 * sizeof(int));
  s = 1;
  for (i = m - 1; i >= 0; i--) {
    B[x[i]] |= s;
    s <<= 1;
  }
  j = 0;
  while (j <= n - m) {
    i = m - 1;
    last = m;
    d = ~0;
    while (i >= 0 && d != 0) {
      d &= B[y[j + i]];
      i--;
      if (d != 0) {
        if (i >= 0)
          last = i + 1;
        else {
        }
      }
      d <<= 1;
    }
    j += last;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BNDM>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x40,%esi
  jg     L41
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %ebx,%r10d
  sub    $0x1,%r10d
  js     L63
L5:
  movslq %r10d,%rax
  mov    $0x1,%edx
L116:
  movsbq 0x0(%r13,%rax,1),%rcx
  or     %edx,(%rsp,%rcx,4)
  add    %edx,%edx
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L116
L63:
  mov    $0x0,%r9d
  movslq %r10d,%r13
  mov    $0xffffffff,%r11d
  sub    %ebx,%r12d
  jns    L15
L42:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L41:
  lea    D3(%rip),%rdi
  call   <error@plt>
  mov    %rsp,%rdi
  mov    $0x400,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    -0x1(%rbx),%r10d
  jmp    L5
L109:
  sub    $0x1,%rsi
  add    %eax,%eax
  je     L59
  test   %dl,%dl
  je     L59
L45:
  movsbq (%rsi),%r14
  mov    %ecx,%edi
  sub    $0x1,%ecx
  mov    %ecx,%edx
  not    %edx
  shr    $0x1f,%edx
  and    (%rsp,%r14,4),%eax
  je     L109
  test   %dl,%dl
  cmovne %edi,%r8d
  jmp    L109
L59:
  add    %r8d,%r9d
  cmp    %r12d,%r9d
  jg     L42
L15:
  mov    %ebx,%r8d
  test   %r10d,%r10d
  js     L59
  movslq %r9d,%rsi
  add    %r13,%rsi
  add    %rbp,%rsi
  mov    %ebx,%r8d
  mov    %r10d,%ecx
  mov    %r11d,%eax
  jmp    L45
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: BNDM

assistant: ```c
void BNDM(char *x, int m, char *y, int n) {
  int B[256];
  int i, j, s, d, last;
  if (m > 64)
    error("BNDM");
  memset(B, 0, 256 * sizeof(int));
  s = 1;
  for (i = m - 1; i >= 0; i--) {
    B[x[i]] |= s;
    s <<= 1;
  }
  j = 0;
  while (j <= n - m) {
    i = m - 1;
    last = m;
    d = ~0;
    while (i >= 0 && d != 0) {
      d &= B[y[j + i]];
      i--;
      if (d != 0) {
        if (i >= 0)
          last = i + 1;
        else {
        }
      }
      d <<= 1;
    }
    j += last;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BNDM>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x40,%esi
  jg     L8
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x400,%edx
  call   <memset@plt>
  test   %r12d,%r12d
  js     L61
L66:
  movslq %r12d,%rax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L27:
  movsbq (%r14,%rax,1),%rcx
  sub    $0x1,%rax
  or     %edx,(%rsp,%rcx,4)
  add    %edx,%edx
  test   %eax,%eax
  jns    L27
L61:
  xor    %r8d,%r8d
  movslq %r12d,%r9
  sub    %ebx,%r13d
  js     L58
  nopl   (%rax)
L50:
  mov    %ebx,%esi
  test   %r12d,%r12d
  js     L77
  movslq %r8d,%rcx
  mov    %ebx,%esi
  mov    %r12d,%edx
  mov    $0xffffffff,%eax
  add    %r9,%rcx
  add    %rbp,%rcx
  nopw   0x0(%rax,%rax,1)
L89:
  movsbq (%rcx),%rdi
  and    (%rsp,%rdi,4),%eax
  mov    %edx,%edi
  sub    $0x1,%edx
  jb     L105
  test   %eax,%eax
  cmovne %edi,%esi
L105:
  add    %eax,%eax
  sub    $0x1,%rcx
  test   %edx,%edx
  js     L77
  test   %eax,%eax
  jne    L89
L77:
  add    %esi,%r8d
  cmp    %r13d,%r8d
  jle    L50
L58:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  lea    D8(%rip),%rdi
  call   <error@plt>
  mov    %rsp,%rdi
  mov    $0x400,%edx
  xor    %esi,%esi
  call   <memset@plt>
  jmp    L66
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: BNDM

assistant: ```c
void BNDM(char *x, int m, char *y, int n) {
  int B[256];
  int i, j, s, d, last;
  if (m > 64)
    error("BNDM");
  memset(B, 0, 256 * sizeof(int));
  s = 1;
  for (i = m - 1; i >= 0; i--) {
    B[x[i]] |= s;
    s <<= 1;
  }
  j = 0;
  while (j <= n - m) {
    i = m - 1;
    last = m;
    d = ~0;
    while (i >= 0 && d != 0) {
      d &= B[y[j + i]];
      i--;
      if (d != 0) {
        if (i >= 0)
          last = i + 1;
        else {
        }
      }
      d <<= 1;
    }
    j += last;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BNDM>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  cmp    $0x40,%esi
  jg     L11
  xor    %esi,%esi
  mov    %rsp,%rdi
  mov    $0x400,%edx
  call   <memset@plt>
  test   %r12d,%r12d
  js     L67
L21:
  movslq %r12d,%r10
  mov    $0x1,%edx
  mov    %r10,%rax
  nopl   (%rax)
L28:
  movsbq (%r14,%rax,1),%rcx
  sub    $0x1,%rax
  or     %edx,(%rsp,%rcx,4)
  add    %edx,%edx
  test   %eax,%eax
  jns    L28
  sub    %ebx,%r13d
  js     L67
  test   %r12d,%r12d
  js     L67
  xor    %r9d,%r9d
  nop
L105:
  movslq %r9d,%rcx
  mov    %ebx,%edi
  mov    %r12d,%edx
  mov    $0xffffffff,%eax
  add    %r10,%rcx
  add    %rbp,%rcx
  nopl   0x0(%rax,%rax,1)
L62:
  movsbq (%rcx),%rsi
  mov    %edx,%r8d
  sub    $0x1,%edx
  and    (%rsp,%rsi,4),%eax
  je     L85
  cmp    $0xffffffff,%edx
  cmovne %r8d,%edi
L85:
  sub    $0x1,%rcx
  add    %eax,%eax
  je     L46
  test   %edx,%edx
  jns    L62
L46:
  add    %edi,%r9d
  cmp    %r9d,%r13d
  jge    L105
L67:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x410,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  lea    D4(%rip),%rdi
  call   <error@plt>
  mov    %rsp,%rdi
  mov    $0x400,%edx
  xor    %esi,%esi
  call   <memset@plt>
  jmp    L21
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: BNDM

assistant: ```c
void BNDM(char *x, int m, char *y, int n) {
  int B[256];
  int i, j, s, d, last;
  if (m > 64)
    error("BNDM");
  memset(B, 0, 256 * sizeof(int));
  s = 1;
  for (i = m - 1; i >= 0; i--) {
    B[x[i]] |= s;
    s <<= 1;
  }
  j = 0;
  while (j <= n - m) {
    i = m - 1;
    last = m;
    d = ~0;
    while (i >= 0 && d != 0) {
      d &= B[y[j + i]];
      i--;
      if (d != 0) {
        if (i >= 0)
          last = i + 1;
        else {
        }
      }
      d <<= 1;
    }
    j += last;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reg_quadrant>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movq   $0x4,-0x8(%rbp)
  jmp    L25
L32:
  movsd  -0x10(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L25:
  pxor   %xmm0,%xmm0
  comisd -0x10(%rbp),%xmm0
  ja     L32
  movsd  -0x10(%rbp),%xmm0
  ucomisd D2(%rip),%xmm0
  jp     L9
  movsd  -0x10(%rbp),%xmm0
  ucomisd D2(%rip),%xmm0
  jne    L9
  mov    -0x8(%rbp),%rax
  jmp    L11
L9:
  movsd  D2(%rip),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <fmod@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  movsd  D59(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D4(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f64
name: disassemble_data
arguments: tag: D59
type_guessed: f64
name: disassemble_data
arguments: tag: D4
type_guessed: f32[2]

tool: D2: 360

tool: D59: 90

tool: {"D4": [0.0,1.875]}

assistant: ```c
long reg_quadrant(double ang1) {
  double ang = ang1;
  long quad = 4;
  while (ang < 0.0)
    ang += 360.0;
  if (ang == 360.0)
    return quad;
  ang = fmod(ang, 360.0);
  quad = (ang / 90.0) + 1;
  return quad;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reg_quadrant>:
  endbr64
  movsd  D13(%rip),%xmm2
  pxor   %xmm1,%xmm1
  comisd %xmm0,%xmm1
  jbe    L18
L25:
  addsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  ja     L25
L18:
  ucomisd D13(%rip),%xmm0
  jp     L13
  mov    $0x4,%eax
  je     L28
L13:
  sub    $0x8,%rsp
  movsd  D13(%rip),%xmm1
  call   <fmod@plt>
  divsd  D35(%rip),%xmm0
  addsd  D7(%rip),%xmm0
  cvttsd2si %xmm0,%rax
  add    $0x8,%rsp
  ret
L28:
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
type_infered: f64
name: read_data
arguments: data_label: D35
type_infered: f64
name: read_data
arguments: data_label: D7
type_infered: f32[2]

tool: D13: 360

tool: D35: 90

tool: {"D7": [0.0,1.875]}

assistant: ```c
long reg_quadrant(double ang1) {
  double ang = ang1;
  long quad = 4;
  while (ang < 0.0)
    ang += 360.0;
  if (ang == 360.0)
    return quad;
  ang = fmod(ang, 360.0);
  quad = (ang / 90.0) + 1;
  return quad;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reg_quadrant>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D29(%rip),%xmm1
  comisd %xmm0,%xmm2
  jbe    L28
  cs nopw 0x0(%rax,%rax,1)
L16:
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  ja     L16
L28:
  ucomisd %xmm1,%xmm0
  jp     L4
  mov    $0x4,%eax
  je     L12
L4:
  sub    $0x8,%rsp
  call   <fmod@plt>
  divsd  D22(%rip),%xmm0
  addsd  D2(%rip),%xmm0
  add    $0x8,%rsp
  cvttsd2si %xmm0,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  ret
```

tool_calls: name: parse_data
arguments: label: D29
type_guessed: f64
name: parse_data
arguments: label: D22
type_guessed: f64
name: parse_data
arguments: label: D2
type_guessed: f32[2]

tool: D29: 360

tool: D22: 90

tool: {"D2": [0.0,1.875]}

assistant: ```c
long reg_quadrant(double ang1) {
  double ang = ang1;
  long quad = 4;
  while (ang < 0.0)
    ang += 360.0;
  if (ang == 360.0)
    return quad;
  ang = fmod(ang, 360.0);
  quad = (ang / 90.0) + 1;
  return quad;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reg_quadrant>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D3(%rip),%xmm1
  comisd %xmm0,%xmm2
  jbe    L34
  cs nopw 0x0(%rax,%rax,1)
L16:
  addsd  %xmm1,%xmm0
  comisd %xmm0,%xmm2
  ja     L16
L34:
  ucomisd %xmm1,%xmm0
  jp     L13
  mov    $0x4,%eax
  je     L30
L13:
  sub    $0x8,%rsp
  call   <fmod@plt>
  divsd  D8(%rip),%xmm0
  addsd  D0(%rip),%xmm0
  add    $0x8,%rsp
  cvttsd2si %xmm0,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: f64
name: disassemble_data
arguments: data_label: D8
type_infered: f64
name: disassemble_data
arguments: data_label: D0
type_infered: f32[2]

tool: D3: 360

tool: D8: 90

tool: {"D0": [0.0,1.875]}

assistant: ```c
long reg_quadrant(double ang1) {
  double ang = ang1;
  long quad = 4;
  while (ang < 0.0)
    ang += 360.0;
  if (ang == 360.0)
    return quad;
  ang = fmod(ang, 360.0);
  quad = (ang / 90.0) + 1;
  return quad;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pr_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string

tool: D4: %s, 

assistant: ```c
void pr_array(char *a[], int len) {
  int k;
  for (k = 0; k < len; k++)
    printf("%s, ", a[k]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pr_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D1(%rip),%rbp
L7:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L7
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: %s, 

assistant: ```c
void pr_array(char *a[], int len) {
  int k;
  for (k = 0; k < len; k++)
    printf("%s, ", a[k]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pr_array>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L1:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L18:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: string

tool: D4: %s, 

assistant: ```c
void pr_array(char *a[], int len) {
  int k;
  for (k = 0; k < len; k++)
    printf("%s, ", a[k]);
  printf("\n");
}
```