ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stristr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L90
  mov    -0x28(%rbp),%rax
  jmp    L13
L58:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L23
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L84
L22:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L35
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L84:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  jmp    L25
L35:
  nop
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x28(%rbp),%rax
  jmp    L13
L23:
  addq   $0x1,-0x28(%rbp)
L90:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  mov    $0x0,%eax
L13:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
const char *stristr(const char *haystack, const char *needle) {
  if (!*needle) {
    return haystack;
  }
  for (; *haystack; ++haystack) {
    if ((toupper((unsigned char)(*haystack))) == (toupper((unsigned char)(*needle)))) {
      const char *h, *n;
      for (h = haystack, n = needle; *h && *n; ++h, ++n) {
        if ((toupper((unsigned char)(*h))) != (toupper((unsigned char)(*n)))) {
          break;
        }
      }
      if (!*n) {
        return haystack;
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<stristr>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  cmpb   $0x0,(%rsi)
  je     L109
  mov    %rsi,%r13
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L58
  mov    $0x0,%r12d
  jmp    L109
L90:
  cmpb   $0x0,(%rbx)
  je     L109
L95:
  add    $0x1,%r12
  movzbl (%r12),%edi
  test   %dil,%dil
  je     L22
L58:
  movzbl %dil,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  movzbl 0x0(%r13),%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L95
  movzbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%rbp
  test   %dil,%dil
  je     L90
L50:
  cmpb   $0x0,(%rbx)
  je     L109
  movzbl %dil,%edi
  call   <toupper@plt>
  mov    %rax,%r14
  movzbl (%rbx),%edi
  call   <toupper@plt>
  cmp    %rax,%r14
  jne    L90
  add    $0x1,%rbp
  add    $0x1,%rbx
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L50
  jmp    L90
L22:
  mov    $0x0,%r12d
L109:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
const char *stristr(const char *haystack, const char *needle) {
  if (!*needle) {
    return haystack;
  }
  for (; *haystack; ++haystack) {
    if ((toupper((unsigned char)(*haystack))) == (toupper((unsigned char)(*needle)))) {
      const char *h, *n;
      for (h = haystack, n = needle; *h && *n; ++h, ++n) {
        if ((toupper((unsigned char)(*h))) != (toupper((unsigned char)(*n)))) {
          break;
        }
      }
      if (!*n) {
        return haystack;
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<stristr>:
  endbr64
  cmpb   $0x0,(%rsi)
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  je     L87
  movzbl (%rdi),%edi
  mov    %rsi,%r13
  test   %dil,%dil
  jne    L57
  jmp    L40
  nopl   0x0(%rax)
L1:
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L40
L57:
  call   <toupper@plt>
  movzbl 0x0(%r13),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L1
  movzbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%r14
  test   %dil,%dil
  jne    L54
  jmp    L7
L73:
  call   <toupper@plt>
  movzbl (%rbx),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L7
  movzbl 0x1(%r14),%edi
  add    $0x1,%r14
  add    $0x1,%rbx
  test   %dil,%dil
  je     L7
L54:
  cmpb   $0x0,(%rbx)
  jne    L73
L87:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  cmpb   $0x0,(%rbx)
  je     L87
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L57
L40:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
const char *stristr(const char *haystack, const char *needle) {
  if (!*needle) {
    return haystack;
  }
  for (; *haystack; ++haystack) {
    if ((toupper((unsigned char)(*haystack))) == (toupper((unsigned char)(*needle)))) {
      const char *h, *n;
      for (h = haystack, n = needle; *h && *n; ++h, ++n) {
        if ((toupper((unsigned char)(*h))) != (toupper((unsigned char)(*n)))) {
          break;
        }
      }
      if (!*n) {
        return haystack;
      }
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stristr>:
  endbr64
  cmpb   $0x0,(%rsi)
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  je     L76
  movzbl (%rdi),%edi
  mov    %rsi,%r13
  test   %dil,%dil
  jne    L102
  jmp    L115
  nopl   0x0(%rax)
L73:
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L115
L102:
  call   <toupper@plt>
  movzbl 0x0(%r13),%edi
  mov    %rax,%rbx
  call   <toupper@plt>
  cmp    %rax,%rbx
  jne    L73
  movzbl (%r12),%edi
  mov    %r13,%rbx
  mov    %r12,%r14
  test   %dil,%dil
  jne    L26
  jmp    L105
L56:
  call   <toupper@plt>
  movzbl (%rbx),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L105
  movzbl 0x1(%r14),%edi
  add    $0x1,%r14
  add    $0x1,%rbx
  test   %dil,%dil
  je     L105
L26:
  cmpb   $0x0,(%rbx)
  jne    L56
L76:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L105:
  cmpb   $0x0,(%rbx)
  je     L76
  movzbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L102
L115:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
const char *stristr(const char *haystack, const char *needle) {
  if (!*needle) {
    return haystack;
  }
  for (; *haystack; ++haystack) {
    if ((toupper((unsigned char)(*haystack))) == (toupper((unsigned char)(*needle)))) {
      const char *h, *n;
      for (h = haystack, n = needle; *h && *n; ++h, ++n) {
        if ((toupper((unsigned char)(*h))) != (toupper((unsigned char)(*n)))) {
          break;
        }
      }
      if (!*n) {
        return haystack;
      }
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<twoSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x4,%esi
  mov    $0x2,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L68
L35:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L0
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L54
L29:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jne    L52
  mov    -0x8(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  jmp    L12
L52:
  addl   $0x1,-0xc(%rbp)
L54:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L29
L0:
  addl   $0x1,-0x10(%rbp)
L68:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L35
  mov    -0x8(%rbp),%rax
L12:
  leave
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result;
  result = calloc(2, sizeof(int));
  for (int i = 0; i < numsSize - 1; i++) {
    if (nums[i] < target) {
      for (int j = i + 1; j < numsSize; j++) {
        if (nums[i] + nums[j] == target) {
          result[0] = i;
          result[1] = j;
          return result;
        }
      }
    }
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<twoSum>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    $0x4,%esi
  mov    $0x2,%edi
  call   <calloc@plt>
  cmp    $0x1,%r12d
  jle    L76
  lea    -0x2(%r12),%r9d
  add    $0x2,%r9
  mov    $0x1,%ecx
  jmp    L71
L72:
  mov    %r10d,(%rax)
  mov    %edx,0x4(%rax)
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  add    $0x1,%rcx
  cmp    %r9,%rcx
  je     L76
L71:
  lea    -0x1(%rcx),%r10d
  mov    -0x4(%rbx,%rcx,4),%edi
  cmp    %ebp,%edi
  jge    L28
  cmp    %ecx,%r12d
  jle    L28
  mov    %rcx,%rdx
L74:
  mov    %edi,%esi
  add    (%rbx,%rdx,4),%esi
  cmp    %ebp,%esi
  je     L72
  add    $0x1,%rdx
  cmp    %edx,%r12d
  jg     L74
  jmp    L28
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result;
  result = calloc(2, sizeof(int));
  for (int i = 0; i < numsSize - 1; i++) {
    if (nums[i] < target) {
      for (int j = i + 1; j < numsSize; j++) {
        if (nums[i] + nums[j] == target) {
          result[0] = i;
          result[1] = j;
          return result;
        }
      }
    }
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <calloc@plt>
  cmp    $0x1,%r12d
  jle    L52
  lea    -0x2(%r12),%edx
  mov    $0x1,%esi
  add    $0x2,%rdx
  jmp    L46
  nopl   (%rax)
L41:
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  je     L52
L46:
  mov    -0x4(%rbx,%rsi,4),%r8d
  lea    -0x1(%rsi),%r9d
  cmp    %ebp,%r8d
  jge    L41
  cmp    %esi,%r12d
  jle    L41
  mov    %rsi,%rcx
  jmp    L10
  nopl   0x0(%rax)
L45:
  add    $0x1,%rcx
  cmp    %ecx,%r12d
  jle    L41
L10:
  mov    (%rbx,%rcx,4),%edi
  add    %r8d,%edi
  cmp    %ebp,%edi
  jne    L45
  mov    %r9d,(%rax)
  mov    %ecx,0x4(%rax)
L52:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result;
  result = calloc(2, sizeof(int));
  for (int i = 0; i < numsSize - 1; i++) {
    if (nums[i] < target) {
      for (int j = i + 1; j < numsSize; j++) {
        if (nums[i] + nums[j] == target) {
          result[0] = i;
          result[1] = j;
          return result;
        }
      }
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<twoSum>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    $0x4,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2,%edi
  call   <calloc@plt>
  cmp    $0x1,%r12d
  jle    L74
  lea    -0x2(%r12),%r9d
  mov    $0x1,%ecx
  add    $0x2,%r9
  jmp    L29
  nopl   (%rax)
L15:
  add    $0x1,%rcx
  cmp    %rcx,%r9
  je     L74
L29:
  mov    -0x4(%rbx,%rcx,4),%edi
  lea    -0x1(%rcx),%r10d
  cmp    %ebp,%edi
  jge    L15
  cmp    %ecx,%r12d
  jle    L15
  mov    %rcx,%rdx
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L50:
  add    $0x1,%rdx
  cmp    %edx,%r12d
  jle    L15
L79:
  mov    (%rbx,%rdx,4),%esi
  add    %edi,%esi
  cmp    %ebp,%esi
  jne    L50
  movd   %r10d,%xmm0
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rax)
L74:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int *twoSum(int *nums, int numsSize, int target) {
  int *result;
  result = calloc(2, sizeof(int));
  for (int i = 0; i < numsSize - 1; i++) {
    if (nums[i] < target) {
      for (int j = i + 1; j < numsSize; j++) {
        if (nums[i] + nums[j] == target) {
          result[0] = i;
          result[1] = j;
          return result;
        }
      }
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x28,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int arg1 = 40;
  int add = 0;
  __asm__("addl $15, %%eax;" : "=a"(add) : "a"(arg1));
  return add;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x28,%eax
  add    $0xf,%eax
  ret
```

assistant: ```c
int main() {
  int arg1 = 40;
  int add = 0;
  __asm__("addl $15, %%eax;" : "=a"(add) : "a"(arg1));
  return add;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  mov    $0x28,%eax
  add    $0xf,%eax
  ret
```

assistant: ```c
int main() {
  int arg1 = 40;
  int add = 0;
  __asm__("addl $15, %%eax;" : "=a"(add) : "a"(arg1));
  return add;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: f64
name: unpack_data
arguments: tag: D1
type_infered: string

tool: D20: %lf

tool: D12: 3.14159

tool: D1: A=%.4lf


assistant: ```c
int main() {
  double R;
  scanf("%lf", &R);
  printf("A=%.4lf\n", 3.14159 * R * R);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movapd %xmm1,%xmm0
  mulsd  D11(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string
name: unpack_data
arguments: data_tag: D11
type_guessed: f64
name: unpack_data
arguments: data_tag: D20
type_guessed: string

tool: D5: %lf

tool: D11: 3.14159

tool: D20: A=%.4lf


assistant: ```c
int main() {
  double R;
  scanf("%lf", &R);
  printf("A=%.4lf\n", 3.14159 * R * R);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D28(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D13(%rip),%xmm0
  lea    D7(%rip),%rdi
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D28
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: f64
name: retrieve_data
arguments: tag: D7
datatype: string

tool: D28: %lf

tool: D13: 3.14159

tool: D7: A=%.4lf


assistant: ```c
int main() {
  double R;
  scanf("%lf", &R);
  printf("A=%.4lf\n", 3.14159 * R * R);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm1
  movsd  D17(%rip),%xmm0
  lea    D19(%rip),%rdi
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string
name: disassemble_data
arguments: data_tag: D17
datatype: f64
name: disassemble_data
arguments: data_tag: D19
datatype: string

tool: D6: %lf

tool: D17: 3.14159

tool: D19: A=%.4lf


assistant: ```c
int main() {
  double R;
  scanf("%lf", &R);
  printf("A=%.4lf\n", 3.14159 * R * R);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertado>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  mov    -0x14(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
char *insertado(int tam_dest, int tam_src, int pos_in, char *destino, char *origen) {
  char *string = malloc((tam_dest + tam_src) * sizeof(char));
  strncpy(string, destino, pos_in);
  strncpy(string + pos_in, origen, tam_src);
  strncpy(string + pos_in + tam_src, destino + pos_in, tam_dest - pos_in + 1);
  free(string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<insertado>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r14d
  mov    %rcx,%r13
  mov    %r8,0x8(%rsp)
  lea    (%rdi,%rsi,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movslq %r14d,%r15
  lea    (%r12,%r15,1),%rdi
  mov    %ebx,%edx
  mov    0x8(%rsp),%rsi
  call   <strncpy@plt>
  sub    %r14d,%ebp
  lea    0x1(%rbp),%edx
  lea    0x0(%r13,%r15,1),%rsi
  movslq %ebx,%rdi
  add    %r15,%rdi
  add    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *insertado(int tam_dest, int tam_src, int pos_in, char *destino, char *origen) {
  char *string = malloc((tam_dest + tam_src) * sizeof(char));
  strncpy(string, destino, pos_in);
  strncpy(string + pos_in, origen, tam_src);
  strncpy(string + pos_in + tam_src, destino + pos_in, tam_dest - pos_in + 1);
  free(string);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insertado>:
  endbr64
  push   %r15
  movslq %edx,%r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    (%rdi,%rsi,1),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    %r15d,%ebp
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    0x8(%rsp),%rsi
  lea    (%r12,%r15,1),%rdi
  mov    %ebx,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdi
  lea    0x0(%r13,%r15,1),%rsi
  lea    0x1(%rbp),%edx
  add    %r15,%rdi
  add    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *insertado(int tam_dest, int tam_src, int pos_in, char *destino, char *origen) {
  char *string = malloc((tam_dest + tam_src) * sizeof(char));
  strncpy(string, destino, pos_in);
  strncpy(string + pos_in, origen, tam_src);
  strncpy(string + pos_in + tam_src, destino + pos_in, tam_dest - pos_in + 1);
  free(string);
}
```
user: What is the c source code of the assembly code below?

```asm
<insertado>:
  endbr64
  push   %r15
  movslq %edx,%r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    (%rdi,%rsi,1),%edi
  push   %rbx
  mov    %esi,%ebx
  sub    %r15d,%ebp
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  call   <malloc@plt>
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strncpy@plt>
  mov    0x8(%rsp),%rsi
  lea    (%r12,%r15,1),%rdi
  mov    %ebx,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdi
  lea    0x0(%r13,%r15,1),%rsi
  lea    0x1(%rbp),%edx
  add    %r15,%rdi
  add    %r12,%rdi
  call   <strncpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char *insertado(int tam_dest, int tam_src, int pos_in, char *destino, char *origen) {
  char *string = malloc((tam_dest + tam_src) * sizeof(char));
  strncpy(string, destino, pos_in);
  strncpy(string + pos_in, origen, tam_src);
  strncpy(string + pos_in + tam_src, destino + pos_in, tam_dest - pos_in + 1);
  free(string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pp_setbit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    $0x5,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  or     -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pp_setbit(int *vec, int bit) {
  int byte = bit >> 5;
  int offset = 1 << (bit & 31);
  vec[byte] |= offset;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pp_setbit>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  sar    $0x5,%eax
  cltq
  mov    $0x1,%edx
  shl    %cl,%edx
  or     %edx,(%rdi,%rax,4)
  ret
```

assistant: ```c
void pp_setbit(int *vec, int bit) {
  int byte = bit >> 5;
  int offset = 1 << (bit & 31);
  vec[byte] |= offset;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pp_setbit>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%ecx
  mov    $0x1,%edx
  sar    $0x5,%eax
  shl    %cl,%edx
  cltq
  or     %edx,(%rdi,%rax,4)
  ret
```

assistant: ```c
void pp_setbit(int *vec, int bit) {
  int byte = bit >> 5;
  int offset = 1 << (bit & 31);
  vec[byte] |= offset;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pp_setbit>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%ecx
  mov    $0x1,%edx
  sar    $0x5,%eax
  shl    %cl,%edx
  cltq
  or     %edx,(%rdi,%rax,4)
  ret
```

assistant: ```c
void pp_setbit(int *vec, int bit) {
  int byte = bit >> 5;
  int offset = 1 << (bit & 31);
  vec[byte] |= offset;
}
```