ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<str2enum>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  test   %rax,%rax
  je     L44
L79:
  cmpb   $0x3a,-0x1(%rax)
  je     L27
  lea    0x1(%rax),%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L79
L44:
  mov    %rsp,%r14
  mov    %r13,%rdx
  lea    D1(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <strstr@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L49
  nopl   0x0(%rax)
L87:
  mov    %r12,%rdx
  lea    D10(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L49:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L27:
  movzbl -0x2(%rax),%ecx
  lea    -0x2(%rax),%rdx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L11
  nopl   0x0(%rax,%rax,1)
L42:
  mov    %rdx,%rdi
  movzbl -0x1(%rdx),%eax
  sub    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L42
  jmp    L87
  nopl   0x0(%rax)
L11:
  lea    -0x1(%rax),%rdi
  jmp    L87
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D1: %30.30s:

tool: D10: %d

assistant: ```c
int str2enum(const char *str, const char *comment, int *val) {
  const char *p;
  char s[32];
  for (p = comment;; p++) {
    if (!(p = strstr(p, str)))
      break;
    if (*(p - 1) != ':')
      continue;
    for (p -= 2; '0' <= *p && *p <= '9'; p--)
      ;
    return sscanf(p + 1, "%d", val) == 1;
  }
  sprintf(s, "%30.30s:", str);
  if ((p = strstr(comment, s))) {
    return sscanf(p, "%d", val) == 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str2enum>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %r13,%rsi
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  test   %rax,%rax
  je     L83
L42:
  cmpb   $0x3a,-0x1(%rax)
  je     L70
  lea    0x1(%rax),%rdi
  mov    %r13,%rsi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L42
L83:
  mov    %rsp,%r14
  mov    %r13,%rdx
  lea    D16(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  mov    %r14,%rsi
  call   <strstr@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L74
  nopl   0x0(%rax)
L29:
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
L74:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L70:
  movzbl -0x2(%rax),%ecx
  lea    -0x2(%rax),%rdx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L80
  nopl   0x0(%rax,%rax,1)
L75:
  mov    %rdx,%rdi
  movzbl -0x1(%rdx),%eax
  sub    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L75
  jmp    L29
  nopl   0x0(%rax)
L80:
  lea    -0x1(%rax),%rdi
  jmp    L29
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D0
datatype: string

tool: D16: %30.30s:

tool: D0: %d

assistant: ```c
int str2enum(const char *str, const char *comment, int *val) {
  const char *p;
  char s[32];
  for (p = comment;; p++) {
    if (!(p = strstr(p, str)))
      break;
    if (*(p - 1) != ':')
      continue;
    for (p -= 2; '0' <= *p && *p <= '9'; p--)
      ;
    return sscanf(p + 1, "%d", val) == 1;
  }
  sprintf(s, "%30.30s:", str);
  if ((p = strstr(comment, s))) {
    return sscanf(p, "%d", val) == 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%rax),%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  mov    %ebx,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <ft_memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  ft_memcpy(s1 + ft_strlen(s1), s2, ft_strlen(s2) + 1);
  return (s1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_strcat>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <ft_strlen@plt>
  lea    0x1(%rbp),%edx
  movslq %eax,%rdi
  add    %rbx,%rdi
  mov    %r12,%rsi
  call   <ft_memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  ft_memcpy(s1 + ft_strlen(s1), s2, ft_strlen(s2) + 1);
  return (s1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ft_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <ft_strlen@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  movslq %eax,%rdi
  add    %r12,%rdi
  call   <ft_memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  ft_memcpy(s1 + ft_strlen(s1), s2, ft_strlen(s2) + 1);
  return (s1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strcat>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <ft_strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <ft_strlen@plt>
  lea    0x1(%rbx),%edx
  mov    %rbp,%rsi
  movslq %eax,%rdi
  add    %r12,%rdi
  call   <ft_memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_strcat(char *s1, const char *s2) {
  ft_memcpy(s1 + ft_strlen(s1), s2, ft_strlen(s2) + 1);
  return (s1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ParseElement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x78(%rbp),%rdx
  mov    -0x88(%rbp),%rax
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtok_r@plt>
  mov    %rax,%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x7c(%rbp)
  jmp    L16
L9:
  subl   $0x1,-0x7c(%rbp)
L16:
  cmpl   $0x0,-0x7c(%rbp)
  js     L42
  mov    -0x7c(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x2d,%al
  jne    L9
L42:
  cmpl   $0x0,-0x7c(%rbp)
  jle    L20
  mov    -0x7c(%rbp),%eax
  add    $0x1,%eax
  lea    -0x70(%rbp),%rdx
  cltq
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x98(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x7c(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  lea    -0x70(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L20:
  mov    -0x78(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D9:  	


assistant: ```c
char *ParseElement(char *p, char *s, int *sid) {
  char dum[100], *q;
  int j;
  strcpy(dum, strtok_r(p, " \t\n", &q));
  j = strlen(dum) - 1;
  while ((j >= 0) && (dum[j] != '-'))
    j--;
  if (j > 0) {
    *sid = atoi(&(dum[j + 1]));
    dum[j] = '\0';
    strcpy(s, dum);
  }
  return (q);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ParseElement>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    D8(%rip),%rsi
  call   <strtok_r@plt>
  mov    %rax,%rsi
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  sub    $0x1,%ebx
  js     L37
  cltq
  lea    0x10(%rsp,%rax,1),%rax
L11:
  cmpb   $0x2d,-0x1(%rax)
  je     L37
  sub    $0x1,%ebx
  sub    $0x1,%rax
  cmp    $0xffffffff,%ebx
  jne    L11
L48:
  mov    0x8(%rsp),%rax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  test   %ebx,%ebx
  jle    L48
  lea    0x10(%rsp),%r13
  lea    0x1(%rbx),%edi
  movslq %edi,%rdi
  add    %r13,%rdi
  call   <atoi@plt>
  mov    %eax,(%r12)
  movslq %ebx,%rbx
  movb   $0x0,0x10(%rsp,%rbx,1)
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  jmp    L48
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8:  	


assistant: ```c
char *ParseElement(char *p, char *s, int *sid) {
  char dum[100], *q;
  int j;
  strcpy(dum, strtok_r(p, " \t\n", &q));
  j = strlen(dum) - 1;
  while ((j >= 0) && (dum[j] != '-'))
    j--;
  if (j > 0) {
    *sid = atoi(&(dum[j + 1]));
    dum[j] = '\0';
    strcpy(s, dum);
  }
  return (q);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ParseElement>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D6(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rbp
  call   <strtok_r@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L51
  cltq
  jmp    L30
  nopl   0x0(%rax)
L47:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L51
L30:
  cmpb   $0x2d,0x0(%rbp,%rax,1)
  movslq %eax,%r13
  jne    L47
  test   %r13d,%r13d
  jle    L51
  lea    0x1(%r13),%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  call   <atoi@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x0,0x10(%rsp,%r13,1)
  mov    %eax,(%rbx)
  call   <strcpy@plt>
L51:
  mov    0x8(%rsp),%rax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string

tool: D6:  	


assistant: ```c
char *ParseElement(char *p, char *s, int *sid) {
  char dum[100], *q;
  int j;
  strcpy(dum, strtok_r(p, " \t\n", &q));
  j = strlen(dum) - 1;
  while ((j >= 0) && (dum[j] != '-'))
    j--;
  if (j > 0) {
    *sid = atoi(&(dum[j + 1]));
    dum[j] = '\0';
    strcpy(s, dum);
  }
  return (q);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ParseElement>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D4(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rbp
  call   <strtok_r@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L2
  cltq
  jmp    L18
  nopl   0x0(%rax)
L6:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L2
L18:
  cmpb   $0x2d,0x0(%rbp,%rax,1)
  movslq %eax,%r13
  jne    L6
  test   %r13d,%r13d
  jle    L2
  lea    0x1(%r13),%edi
  movslq %edi,%rdi
  add    %rbp,%rdi
  call   <atoi@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movb   $0x0,0x10(%rsp,%r13,1)
  mov    %eax,(%rbx)
  call   <strcpy@plt>
L2:
  mov    0x8(%rsp),%rax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4:  	


assistant: ```c
char *ParseElement(char *p, char *s, int *sid) {
  char dum[100], *q;
  int j;
  strcpy(dum, strtok_r(p, " \t\n", &q));
  j = strlen(dum) - 1;
  while ((j >= 0) && (dum[j] != '-'))
    j--;
  if (j > 0) {
    *sid = atoi(&(dum[j + 1]));
    dum[j] = '\0';
    strcpy(s, dum);
  }
  return (q);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D1(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test2(void) {
  static int a = ((char *)&&l2 - (char *)&&l3) + ((char *)&&l1 - (char *)&&l2);
l1:
l2:
l3:
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test2>:
  endbr64
  mov    D2(%rip),%eax
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x00]}

assistant: ```c
int test2(void) {
  static int a = ((char *)&&l2 - (char *)&&l3) + ((char *)&&l1 - (char *)&&l2);
l1:
l2:
l3:
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test2>:
  endbr64
  mov    D4(%rip),%eax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type: byte[4]

tool: {"D4": [0x00,0x00,0x00,0x00]}

assistant: ```c
int test2(void) {
  static int a = ((char *)&&l2 - (char *)&&l3) + ((char *)&&l1 - (char *)&&l2);
l1:
l2:
l3:
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test2>:
  endbr64
  mov    D9(%rip),%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x00]}

assistant: ```c
int test2(void) {
  static int a = ((char *)&&l2 - (char *)&&l3) + ((char *)&&l1 - (char *)&&l2);
l1:
l2:
l3:
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<retrieve_and_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  add    %eax,%eax
  add    $0x5,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L70:
  cmp    %rdx,%rsp
  je     L78
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L70
L78:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L40
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L40:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  lea    -0x34(%rbp),%rdx
  mov    -0x48(%rbp),%esi
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <solcon_retrieve_standard_solution@plt>
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jne    L76
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L55
L76:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x30(%rbp)
  jmp    L1
L25:
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  lea    0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  movsd  (%rax,%rdx,8),%xmm0
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  addl   $0x1,-0x30(%rbp)
L1:
  mov    -0x30(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L25
L55:
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D9: some failure occurred...

tool: D6: The solution vector :

tool: D0:  %.15e  %.15e


assistant: ```c
void retrieve_and_write(int n, int k) {
  int i, m, fail;
  double sol[2 * n + 5];
  fail = solcon_retrieve_standard_solution(n, k, &m, sol);
  if (fail == 1)
    printf("some failure occurred...\n");
  else {
    printf("The solution vector :\n");
    for (i = 0; i < n; i++)
      printf(" %.15e  %.15e\n", sol[2 + 2 * i], sol[2 + 2 * i + 1]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<retrieve_and_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x5(%rdi,%rdi,1),%eax
  cltq
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L30:
  cmp    %rdx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L30
L5:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L1
  orq    $0x0,-0x8(%rsp,%rax,1)
L1:
  mov    %rsp,%r13
  lea    -0x2c(%rbp),%rdx
  mov    %r13,%rcx
  mov    %r12d,%edi
  call   <solcon_retrieve_standard_solution@plt>
  cmp    $0x1,%eax
  je     L63
  lea    D6(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L54
  lea    0x10(%r13),%rbx
  lea    -0x1(%r12),%eax
  shl    $0x4,%rax
  lea    0x20(%r13,%rax,1),%r13
  lea    D1(%rip),%r12
L13:
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  add    $0x10,%rbx
  cmp    %r13,%rbx
  jne    L13
L54:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L63:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  jmp    L54
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string
name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D6: The solution vector :

tool: D1:  %.15e  %.15e


tool: D9: some failure occurred...

assistant: ```c
void retrieve_and_write(int n, int k) {
  int i, m, fail;
  double sol[2 * n + 5];
  fail = solcon_retrieve_standard_solution(n, k, &m, sol);
  if (fail == 1)
    printf("some failure occurred...\n");
  else {
    printf("The solution vector :\n");
    for (i = 0; i < n; i++)
      printf(" %.15e  %.15e\n", sol[2 + 2 * i], sol[2 + 2 * i + 1]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<retrieve_and_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x5(%rdi,%rdi,1),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L5
L45:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L45
L5:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L8
L64:
  mov    %rsp,%r13
  lea    -0x2c(%rbp),%rdx
  mov    %r12d,%edi
  mov    %r13,%rcx
  call   <solcon_retrieve_standard_solution@plt>
  cmp    $0x1,%eax
  je     L12
  lea    D15(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L82
  lea    -0x1(%r12),%eax
  lea    0x10(%r13),%rbx
  shl    $0x4,%rax
  lea    D26(%rip),%r12
  lea    0x20(%r13,%rax,1),%r13
  nopl   0x0(%rax)
L71:
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  add    $0x10,%rbx
  mov    $0x2,%eax
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L71
L82:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L12:
  lea    D2(%rip),%rdi
  call   <puts@plt>
  jmp    L82
  cs nopw 0x0(%rax,%rax,1)
L8:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L64
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D15: The solution vector :

tool: D26:  %.15e  %.15e


tool: D2: some failure occurred...

assistant: ```c
void retrieve_and_write(int n, int k) {
  int i, m, fail;
  double sol[2 * n + 5];
  fail = solcon_retrieve_standard_solution(n, k, &m, sol);
  if (fail == 1)
    printf("some failure occurred...\n");
  else {
    printf("The solution vector :\n");
    for (i = 0; i < n; i++)
      printf(" %.15e  %.15e\n", sol[2 + 2 * i], sol[2 + 2 * i + 1]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<retrieve_and_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x5(%rdi,%rdi,1),%eax
  mov    %rsp,%rcx
  cltq
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L21
L81:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L81
L21:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L23
L39:
  mov    %rsp,%r13
  lea    -0x2c(%rbp),%rdx
  mov    %r12d,%edi
  mov    %r13,%rcx
  call   <solcon_retrieve_standard_solution@plt>
  cmp    $0x1,%eax
  je     L0
  lea    D5(%rip),%rdi
  call   <puts@plt>
  test   %r12d,%r12d
  jle    L35
  lea    -0x1(%r12),%eax
  lea    0x10(%r13),%rbx
  shl    $0x4,%rax
  lea    D1(%rip),%r12
  lea    0x20(%r13,%rax,1),%r13
  nopl   0x0(%rax)
L43:
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  add    $0x10,%rbx
  mov    $0x2,%eax
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L43
L35:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L23:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L39
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string
name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D24
datatype: string

tool: D5: The solution vector :

tool: D1:  %.15e  %.15e


tool: D24: some failure occurred...

assistant: ```c
void retrieve_and_write(int n, int k) {
  int i, m, fail;
  double sol[2 * n + 5];
  fail = solcon_retrieve_standard_solution(n, k, &m, sol);
  if (fail == 1)
    printf("some failure occurred...\n");
  else {
    printf("The solution vector :\n");
    for (i = 0; i < n; i++)
      printf(" %.15e  %.15e\n", sol[2 + 2 * i], sol[2 + 2 * i + 1]);
  }
}
```