ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<stoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L14:
  cmp    %rdx,%rsp
  je     L53
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L53:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L2
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L2:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L20
L25:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %cl,(%rdx,%rax,1)
  addl   $0x1,-0x2c(%rbp)
L20:
  mov    -0x2c(%rbp),%eax
  cmp    -0x3c(%rbp),%eax
  jl     L25
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int stoi(char *number, int len) {
  int i;
  char temp[len];
  for (i = 0; i < len; i++)
    temp[i] = number[i];
  return atoi(temp);
}
```
user: What is the c source code of the assembly code below:

```asm
<stoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L7:
  cmp    %rdx,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L36:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L3
  orq    $0x0,-0x8(%rsp,%rax,1)
L3:
  mov    %rsp,%rdi
  test   %esi,%esi
  jle    L14
  mov    %esi,%esi
  mov    $0x0,%eax
L45:
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L45
L14:
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  leave
  ret
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stoi(char *number, int len) {
  int i;
  char temp[len];
  for (i = 0; i < len; i++)
    temp[i] = number[i];
  return atoi(temp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stoi>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%r8
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rcx
  cmp    %r8,%rsp
  je     L47
L34:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L34
L47:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L41
L9:
  mov    %rsp,%r12
  test   %esi,%esi
  jle    L52
  mov    %rdi,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
L52:
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  mov    -0x8(%rbp),%r12
  leave
  ret
  xchg   %ax,%ax
L41:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L9
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stoi(char *number, int len) {
  int i;
  char temp[len];
  for (i = 0; i < len; i++)
    temp[i] = number[i];
  return atoi(temp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<stoi>:
  endbr64
  push   %rbp
  movslq %esi,%rdx
  mov    %rsp,%rbp
  push   %r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0xf(%rdx),%rax
  mov    %rsp,%r8
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rcx
  cmp    %r8,%rsp
  je     L10
L52:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L52
L10:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L1
L6:
  mov    %rsp,%r12
  test   %esi,%esi
  jle    L44
  mov    %rdi,%rsi
  mov    %rsp,%rdi
  call   <memcpy@plt>
L44:
  mov    %r12,%rdi
  call   <atoi@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  mov    -0x8(%rbp),%r12
  leave
  ret
  xchg   %ax,%ax
L1:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L6
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int stoi(char *number, int len) {
  int i;
  char temp[len];
  for (i = 0; i < len; i++)
    temp[i] = number[i];
  return atoi(temp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<StrCmpNoCase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
L134:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L25
  mov    $0x0,%eax
  jmp    L72
L25:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L80
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L161
L80:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L90
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L90
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %al,-0x2(%rbp)
  jmp    L77
L90:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
L77:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L155
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L155
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %al,-0x1(%rbp)
  jmp    L117
L155:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
L117:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jne    L51
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L161
L51:
  movzbl -0x2(%rbp),%eax
  cmp    -0x1(%rbp),%al
  jge    L43
  mov    $0xffffffff,%eax
  jmp    L72
L43:
  mov    $0x1,%eax
  jmp    L72
L161:
  jmp    L134
L72:
  pop    %rbp
  ret
```

assistant: ```c
int StrCmpNoCase(const char *a, const char *b) {
  char aU, bU;
  while (1) {
    if ((*a == '\0') && (*b == '\0'))
      return 0;
    if (*a == *b) {
      a++;
      b++;
      continue;
    }
    if ((*a >= 'a') && (*a <= 'z'))
      aU = *a - 'a' + 'A';
    else
      aU = *a;
    if ((*b >= 'a') && (*b <= 'z'))
      bU = *b - 'a' + 'A';
    else
      bU = *b;
    if (aU == bU) {
      a++;
      b++;
      continue;
    }
    if (aU < bU)
      return -1;
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<StrCmpNoCase>:
  endbr64
  add    $0x1,%rdi
  add    $0x1,%rsi
L3:
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L44
  movzbl -0x1(%rsi),%eax
  test   %al,%al
  je     L11
L75:
  mov    %eax,%ecx
  lea    -0x61(%rax),%r8d
  cmp    $0x19,%r8b
  jbe    L5
  jmp    L8
L67:
  add    $0x1,%rdi
  add    $0x1,%rsi
  jmp    L3
L44:
  movzbl -0x1(%rsi),%eax
  cmp    %al,%dl
  je     L67
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L75
  sub    $0x20,%edx
  mov    %eax,%ecx
  lea    -0x61(%rax),%r8d
  cmp    $0x19,%r8b
  ja     L13
L5:
  lea    -0x20(%rcx),%eax
L13:
  cmp    %dl,%al
  je     L67
L8:
  cmp    %al,%dl
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int StrCmpNoCase(const char *a, const char *b) {
  char aU, bU;
  while (1) {
    if ((*a == '\0') && (*b == '\0'))
      return 0;
    if (*a == *b) {
      a++;
      b++;
      continue;
    }
    if ((*a >= 'a') && (*a <= 'z'))
      aU = *a - 'a' + 'A';
    else
      aU = *a;
    if ((*b >= 'a') && (*b <= 'z'))
      bU = *b - 'a' + 'A';
    else
      bU = *b;
    if (aU == bU) {
      a++;
      b++;
      continue;
    }
    if (aU < bU)
      return -1;
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<StrCmpNoCase>:
  endbr64
L48:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  test   %al,%al
  jne    L39
  test   %dl,%dl
  je     L8
  lea    -0x61(%rdx),%ecx
L56:
  cmp    $0x19,%cl
  ja     L24
  sub    $0x20,%edx
L50:
  cmp    %al,%dl
  je     L48
L24:
  cmp    %dl,%al
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  cmp    %dl,%al
  je     L48
  lea    -0x61(%rax),%r8d
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%r8b
  ja     L56
  sub    $0x20,%eax
  cmp    $0x19,%cl
  ja     L50
  sub    $0x20,%edx
  jmp    L50
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int StrCmpNoCase(const char *a, const char *b) {
  char aU, bU;
  while (1) {
    if ((*a == '\0') && (*b == '\0'))
      return 0;
    if (*a == *b) {
      a++;
      b++;
      continue;
    }
    if ((*a >= 'a') && (*a <= 'z'))
      aU = *a - 'a' + 'A';
    else
      aU = *a;
    if ((*b >= 'a') && (*b <= 'z'))
      bU = *b - 'a' + 'A';
    else
      bU = *b;
    if (aU == bU) {
      a++;
      b++;
      continue;
    }
    if (aU < bU)
      return -1;
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<StrCmpNoCase>:
  endbr64
L1:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  test   %al,%al
  jne    L36
  test   %dl,%dl
  je     L50
  lea    -0x61(%rdx),%ecx
L2:
  cmp    $0x19,%cl
  ja     L33
  sub    $0x20,%edx
L76:
  cmp    %al,%dl
  je     L1
L33:
  cmp    %dl,%al
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %dl,%al
  je     L1
  lea    -0x61(%rax),%r8d
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%r8b
  ja     L2
  sub    $0x20,%eax
  cmp    $0x19,%cl
  ja     L76
  sub    $0x20,%edx
  jmp    L76
  xchg   %ax,%ax
L50:
  xor    %eax,%eax
  ret
```

assistant: ```c
int StrCmpNoCase(const char *a, const char *b) {
  char aU, bU;
  while (1) {
    if ((*a == '\0') && (*b == '\0'))
      return 0;
    if (*a == *b) {
      a++;
      b++;
      continue;
    }
    if ((*a >= 'a') && (*a <= 'z'))
      aU = *a - 'a' + 'A';
    else
      aU = *a;
    if ((*b >= 'a') && (*b <= 'z'))
      bU = *b - 'a' + 'A';
    else
      bU = *b;
    if (aU == bU) {
      a++;
      b++;
      continue;
    }
    if (aU < bU)
      return -1;
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ans>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L6
L43:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L11
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L11
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L11:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L34
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L43
L34:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ans(int x, int y) {
  int i, gcd;
  for (i = 1; (i <= x && i <= y); i++)
    if (((x % i) == 0) && ((y % i) == 0))
      gcd = i;
  return gcd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ans>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%r8d
  cmovle %edi,%r8d
  test   %r8d,%r8d
  jle    L29
  add    $0x1,%r8d
  mov    $0x0,%r9d
  mov    $0x1,%ecx
  jmp    L27
L48:
  add    $0x1,%ecx
  cmp    %r8d,%ecx
  je     L16
L27:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L48
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%r9d
  jmp    L48
L29:
  mov    $0x0,%r9d
L16:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int ans(int x, int y) {
  int i, gcd;
  for (i = 1; (i <= x && i <= y); i++)
    if (((x % i) == 0) && ((y % i) == 0))
      gcd = i;
  return gcd;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ans>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%r8d
  cmovle %edi,%r8d
  test   %r8d,%r8d
  jle    L13
  add    $0x1,%r8d
  xor    %r9d,%r9d
  mov    $0x1,%ecx
  xchg   %ax,%ax
L21:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L0
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%r9d
L0:
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L21
  mov    %r9d,%eax
  ret
L13:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int ans(int x, int y) {
  int i, gcd;
  for (i = 1; (i <= x && i <= y); i++)
    if (((x % i) == 0) && ((y % i) == 0))
      gcd = i;
  return gcd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ans>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%r8d
  cmovle %edi,%r8d
  test   %r8d,%r8d
  jle    L17
  add    $0x1,%r8d
  xor    %r9d,%r9d
  mov    $0x1,%ecx
  xchg   %ax,%ax
L21:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L3
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %ecx,%r9d
L3:
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L21
  mov    %r9d,%eax
  ret
L17:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int ans(int x, int y) {
  int i, gcd;
  for (i = 1; (i <= x && i <= y); i++)
    if (((x % i) == 0) && ((y % i) == 0))
      gcd = i;
  return gcd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zero_sub8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    %edx,%ebx
  sub    %al,%bl
  mov    %rbx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int64_t zero_sub8(int64_t in) {
  int64_t out;
  asm("sub %%al, %%bl" : "=b"(out) : "a"(in), "0"(0));
  return out;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<zero_sub8>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  mov    %rdi,%rax
  sub    %al,%bl
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int64_t zero_sub8(int64_t in) {
  int64_t out;
  asm("sub %%al, %%bl" : "=b"(out) : "a"(in), "0"(0));
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<zero_sub8>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  xor    %ebx,%ebx
  sub    %al,%bl
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int64_t zero_sub8(int64_t in) {
  int64_t out;
  asm("sub %%al, %%bl" : "=b"(out) : "a"(in), "0"(0));
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zero_sub8>:
  endbr64
  push   %rbx
  mov    %rdi,%rax
  xor    %ebx,%ebx
  sub    %al,%bl
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
int64_t zero_sub8(int64_t in) {
  int64_t out;
  asm("sub %%al, %%bl" : "=b"(out) : "a"(in), "0"(0));
  return out;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<glmGenerateInertiaMatrixForTorus3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  movsd  %xmm1,-0x18(%rbp)
  movsd  %xmm2,-0x20(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D63(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D61(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x20(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm1
  movsd  D19(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D63(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm1
  movsd  D61(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x10(%rbp),%xmm1
  movsd  D41(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x40,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D63
datatype: byte[8]
name: disassemble_data
arguments: data_tag: D61
datatype: f64
name: disassemble_data
arguments: data_tag: D41
datatype: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D63": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D61: 0.125

tool: D41: 0.75

assistant: ```c
void glmGenerateInertiaMatrixForTorus3d(double m[9], double a, double c, double mass) {
  m[0] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[3] = 0;
  m[6] = 0;
  m[1] = 0;
  m[4] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[7] = 0;
  m[2] = 0;
  m[5] = 0;
  m[8] = (0.75 * a * a + c * c) * mass;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<glmGenerateInertiaMatrixForTorus3d>:
  endbr64
  movapd %xmm0,%xmm4
  movapd %xmm0,%xmm3
  mulsd  D30(%rip),%xmm3
  mulsd  %xmm0,%xmm3
  movapd %xmm1,%xmm0
  mulsd  D16(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  mulsd  D21(%rip),%xmm3
  mulsd  %xmm2,%xmm3
  movsd  %xmm3,(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x30(%rdi)
  movq   $0x0,0x8(%rdi)
  movsd  %xmm3,0x20(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x28(%rdi)
  movapd %xmm4,%xmm0
  mulsd  D35(%rip),%xmm0
  mulsd  %xmm4,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x40(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D30
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D16
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D21
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D35
data_type: f64

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D21: 0.125

tool: D35: 0.75

assistant: ```c
void glmGenerateInertiaMatrixForTorus3d(double m[9], double a, double c, double mass) {
  m[0] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[3] = 0;
  m[6] = 0;
  m[1] = 0;
  m[4] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[7] = 0;
  m[2] = 0;
  m[5] = 0;
  m[8] = (0.75 * a * a + c * c) * mass;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<glmGenerateInertiaMatrixForTorus3d>:
  endbr64
  movsd  D19(%rip),%xmm3
  movapd %xmm0,%xmm4
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x30(%rdi)
  mulsd  %xmm0,%xmm3
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x28(%rdi)
  mulsd  %xmm0,%xmm3
  movsd  D28(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm0,%xmm3
  movsd  D7(%rip),%xmm0
  mulsd  D1(%rip),%xmm3
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm3
  mulsd  %xmm4,%xmm0
  movsd  %xmm3,(%rdi)
  movsd  %xmm3,0x20(%rdi)
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x40(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D19
datatype: byte[8]
name: unpack_data
arguments: data_tag: D28
datatype: byte[8]
name: unpack_data
arguments: data_tag: D7
datatype: f64
name: unpack_data
arguments: data_tag: D1
datatype: f64

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D7: 0.75

tool: D1: 0.125

assistant: ```c
void glmGenerateInertiaMatrixForTorus3d(double m[9], double a, double c, double mass) {
  m[0] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[3] = 0;
  m[6] = 0;
  m[1] = 0;
  m[4] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[7] = 0;
  m[2] = 0;
  m[5] = 0;
  m[8] = (0.75 * a * a + c * c) * mass;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<glmGenerateInertiaMatrixForTorus3d>:
  endbr64
  movsd  D4(%rip),%xmm3
  movapd %xmm0,%xmm4
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x30(%rdi)
  mulsd  %xmm0,%xmm3
  movq   $0x0,0x8(%rdi)
  movq   $0x0,0x38(%rdi)
  movq   $0x0,0x10(%rdi)
  movq   $0x0,0x28(%rdi)
  mulsd  %xmm0,%xmm3
  movsd  D29(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm0,%xmm3
  movsd  D24(%rip),%xmm0
  mulsd  D9(%rip),%xmm3
  mulsd  %xmm4,%xmm0
  mulsd  %xmm2,%xmm3
  mulsd  %xmm4,%xmm0
  movsd  %xmm3,(%rdi)
  movsd  %xmm3,0x20(%rdi)
  addsd  %xmm1,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x40(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D29
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D24
type_guessed: f64
name: retrieve_data
arguments: data_label: D9
type_guessed: f64

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D24: 0.75

tool: D9: 0.125

assistant: ```c
void glmGenerateInertiaMatrixForTorus3d(double m[9], double a, double c, double mass) {
  m[0] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[3] = 0;
  m[6] = 0;
  m[1] = 0;
  m[4] = 0.125 * (5 * a * a + 4 * c * c) * mass;
  m[7] = 0;
  m[2] = 0;
  m[5] = 0;
  m[8] = (0.75 * a * a + c * c) * mass;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<padcon_get_dobldobl_t_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x363,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int padcon_get_dobldobl_t_value(double *tval) {
  int fail;
  int precision = 1;
  int *b;
  fail = _ada_use_c2phc4c(867, &precision, b, tval, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<padcon_get_dobldobl_t_value>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%edx
  mov    $0x363,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_dobldobl_t_value(double *tval) {
  int fail;
  int precision = 1;
  int *b;
  fail = _ada_use_c2phc4c(867, &precision, b, tval, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<padcon_get_dobldobl_t_value>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  xor    %r8d,%r8d
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x363,%edi
  movl   $0x1,0x4(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int padcon_get_dobldobl_t_value(double *tval) {
  int fail;
  int precision = 1;
  int *b;
  fail = _ada_use_c2phc4c(867, &precision, b, tval, 0);
  return fail;
}
```