ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fib@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x9,-0x4(%rbp)
  jle    L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: Fibonacci Number #%d: %d


assistant: ```c
int main() {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("Fibonacci Number #%d: %d\n", i, fib(i));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D0(%rip),%rbp
L2:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D0: Fibonacci Number #%d: %d


assistant: ```c
int main() {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("Fibonacci Number #%d: %d\n", i, fib(i));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string

tool: D7: Fibonacci Number #%d: %d


assistant: ```c
int main() {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("Fibonacci Number #%d: %d\n", i, fib(i));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  call   <fib@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: D8: Fibonacci Number #%d: %d


assistant: ```c
int main() {
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("Fibonacci Number #%d: %d\n", i, fib(i));
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x20(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L22
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L22:
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D28
type_guessed: string
name: extract_symbolic_data
arguments: tag: D19
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string

tool: D23: Enter a sentence


tool: D28: is

tool: D19: The string "is" was found

tool: D10: Not found

assistant: ```c
main() {
  char input[20];
  printf("Enter a sentence\n");
  gets(input);
  if (strstr(input, "is") != NULL) {
    printf("The string \"is\" was found");
  } else {
    printf("Not found");
  }
  getchar();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L16
  lea    D24(%rip),%rdi
  call   <printf@plt>
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L16:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D37
datatype: string
name: read_data
arguments: tag: D5
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D31
datatype: string

tool: D37: Enter a sentence


tool: D5: is

tool: D24: The string "is" was found

tool: D31: Not found

assistant: ```c
main() {
  char input[20];
  printf("Enter a sentence\n");
  gets(input);
  if (strstr(input, "is") != NULL) {
    printf("The string \"is\" was found");
  } else {
    printf("Not found");
  }
  getchar();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L20
  lea    D37(%rip),%rdi
  call   <printf@plt>
L24:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L20:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D5
data_type: string
name: retrieve_data
arguments: label: D37
data_type: string
name: retrieve_data
arguments: label: D22
data_type: string

tool: D39: Enter a sentence


tool: D5: is

tool: D37: The string "is" was found

tool: D22: Not found

assistant: ```c
main() {
  char input[20];
  printf("Enter a sentence\n");
  gets(input);
  if (strstr(input, "is") != NULL) {
    printf("The string \"is\" was found");
  } else {
    printf("Not found");
  }
  getchar();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D37(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L13
  lea    D9(%rip),%rdi
  call   <printf@plt>
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D37
datatype: string
name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string

tool: D37: Enter a sentence


tool: D18: is

tool: D9: The string "is" was found

tool: D24: Not found

assistant: ```c
main() {
  char input[20];
  printf("Enter a sentence\n");
  gets(input);
  if (strstr(input, "is") != NULL) {
    printf("The string \"is\" was found");
  } else {
    printf("Not found");
  }
  getchar();
}
```
user: What is the c source code of the assembly code below:

```asm
<Make_bp_profile_bppm>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <get_iindx@plt>
  mov    %rax,%r13
  lea    0x3(%rbp,%rbp,2),%edi
  shl    $0x2,%edi
  call   <space@plt>
  mov    %rax,%r12
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  movss  %xmm0,(%rax)
  movl   $0x40400000,0x4(%rax)
  cmp    $0x1,%ebp
  jle    L1
  lea    0x4(%r13),%rsi
  mov    $0x3,%r10d
  mov    $0x1,%r9d
  lea    0x1(%rbp),%r8d
L29:
  add    $0x1,%r9d
  cmp    %r9d,%ebp
  jl     L64
  movslq %r10d,%rax
  lea    0x4(%r12,%rax,4),%rdi
  lea    0x3(%r10),%eax
  cltq
  lea    0x8(%r12,%rax,4),%rcx
  mov    %r9d,%edx
L27:
  mov    (%rsi),%eax
  sub    %edx,%eax
  cltq
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi),%xmm0
  addsd  (%rbx,%rax,8),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdi)
  mov    (%rsi),%eax
  sub    %edx,%eax
  cltq
  pxor   %xmm0,%xmm0
  cvtss2sd (%rcx),%xmm0
  addsd  (%rbx,%rax,8),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rcx)
  add    $0x1,%edx
  add    $0xc,%rcx
  cmp    %r8d,%edx
  jne    L27
  add    $0x4,%rsi
  add    $0x3,%r10d
  cmp    %r9d,%ebp
  jne    L29
L57:
  lea    0x10(%r12),%rax
  mov    $0x1,%edx
  movss  D3(%rip),%xmm1
L18:
  movaps %xmm1,%xmm0
  subss  (%rax),%xmm0
  subss  0x4(%rax),%xmm0
  movss  %xmm0,-0x4(%rax)
  add    $0x1,%edx
  add    $0xc,%rax
  cmp    %edx,%ebp
  jge    L18
L58:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  jne    L58
  jmp    L57
L64:
  add    $0x4,%rsi
  add    $0x3,%r10d
  jmp    L29
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float *Make_bp_profile_bppm(double *bppm, int length) {
  int i, j;
  int L = 3;
  float *P;
  int *index = get_iindx((unsigned)length);
  P = (float *)space((length + 1) * 3 * sizeof(float));
  P[0] = (float)length;
  P[1] = (float)L;
  for (i = 1; i < length; i++)
    for (j = i + 1; j <= length; j++) {
      P[i * L + 1] += bppm[index[i] - j];
      P[j * L + 2] += bppm[index[i] - j];
    }
  for (i = 1; i <= length; i++)
    P[i * 3 + 0] = 1 - P[i * 3 + 1] - P[i * 3 + 2];
  free(index);
  return (float *)P;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Make_bp_profile_bppm>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x3(%rbx,%rbx,2),%r14d
  call   <get_iindx@plt>
  lea    0x0(,%r14,4),%edi
  mov    %rax,%rbp
  call   <space@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  movl   $0x40400000,0x4(%rax)
  mov    %rax,%r12
  movss  %xmm0,(%rax)
  cmp    $0x1,%ebx
  jle    L31
  mov    $0x6,%r8d
  mov    $0x2,%edi
  lea    0x20(%rax),%r9
  nopl   0x0(%rax,%rax,1)
L9:
  cmp    %edi,%ebx
  jl     L27
  lea    -0x3(%r8),%eax
  mov    %ebx,%esi
  cltq
  sub    %edi,%esi
  lea    0x4(%r12,%rax,4),%rcx
  movslq -0x4(%rbp,%rdi,4),%rax
  lea    -0x1(%rdi,%rsi,1),%rsi
  lea    (%rsi,%rsi,2),%rsi
  sub    %rdi,%rax
  lea    (%r9,%rsi,4),%rsi
  lea    0x0(%r13,%rax,8),%rdx
  movslq %r8d,%rax
  lea    0x8(%r12,%rax,4),%rax
  nopl   (%rax)
L30:
  movsd  (%rdx),%xmm1
  pxor   %xmm0,%xmm0
  add    $0xc,%rax
  sub    $0x8,%rdx
  cvtss2sd (%rcx),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rcx)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rax),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rax)
  cmp    %rax,%rsi
  jne    L30
L27:
  add    $0x3,%r8d
  add    $0x1,%rdi
  cmp    %r8d,%r14d
  jne    L9
L55:
  movss  D2(%rip),%xmm1
  lea    0x10(%r12),%rax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L48:
  movaps %xmm1,%xmm0
  subss  (%rax),%xmm0
  subss  0x4(%rax),%xmm0
  add    $0x1,%edx
  add    $0xc,%rax
  movss  %xmm0,-0x10(%rax)
  cmp    %edx,%ebx
  jge    L48
L34:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L31:
  jne    L34
  jmp    L55
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type: byte[4]

tool: {"D2": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float *Make_bp_profile_bppm(double *bppm, int length) {
  int i, j;
  int L = 3;
  float *P;
  int *index = get_iindx((unsigned)length);
  P = (float *)space((length + 1) * 3 * sizeof(float));
  P[0] = (float)length;
  P[1] = (float)L;
  for (i = 1; i < length; i++)
    for (j = i + 1; j <= length; j++) {
      P[i * L + 1] += bppm[index[i] - j];
      P[j * L + 2] += bppm[index[i] - j];
    }
  for (i = 1; i <= length; i++)
    P[i * 3 + 0] = 1 - P[i * 3 + 1] - P[i * 3 + 2];
  free(index);
  return (float *)P;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Make_bp_profile_bppm>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %esi,%edi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x3(%rbx,%rbx,2),%r14d
  call   <get_iindx@plt>
  lea    0x0(,%r14,4),%edi
  mov    %rax,%rbp
  call   <space@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  movl   $0x40400000,0x4(%rax)
  mov    %rax,%r12
  movss  %xmm0,(%rax)
  cmp    $0x1,%ebx
  jle    L43
  mov    $0x6,%r8d
  mov    $0x2,%edi
  lea    0x20(%rax),%r9
  nopl   0x0(%rax,%rax,1)
L42:
  cmp    %edi,%ebx
  jl     L16
  lea    -0x3(%r8),%eax
  mov    %ebx,%esi
  cltq
  sub    %edi,%esi
  lea    0x4(%r12,%rax,4),%rcx
  movslq -0x4(%rbp,%rdi,4),%rax
  lea    -0x1(%rdi,%rsi,1),%rsi
  lea    (%rsi,%rsi,2),%rsi
  sub    %rdi,%rax
  lea    (%r9,%rsi,4),%rsi
  lea    0x0(%r13,%rax,8),%rdx
  movslq %r8d,%rax
  lea    0x8(%r12,%rax,4),%rax
  nopl   (%rax)
L15:
  movsd  (%rdx),%xmm1
  pxor   %xmm0,%xmm0
  add    $0xc,%rax
  sub    $0x8,%rdx
  cvtss2sd (%rcx),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rcx)
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rax),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rax)
  cmp    %rax,%rsi
  jne    L15
L16:
  add    $0x3,%r8d
  add    $0x1,%rdi
  cmp    %r8d,%r14d
  jne    L42
L55:
  movss  D4(%rip),%xmm1
  lea    0x10(%r12),%rax
  mov    $0x1,%edx
  nopw   0x0(%rax,%rax,1)
L14:
  movaps %xmm1,%xmm0
  subss  (%rax),%xmm0
  subss  0x4(%rax),%xmm0
  add    $0x1,%edx
  add    $0xc,%rax
  movss  %xmm0,-0x10(%rax)
  cmp    %edx,%ebx
  jge    L14
L10:
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L43:
  jne    L10
  jmp    L55
```

tool_calls: name: parse_data
arguments: tag: D4
type: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float *Make_bp_profile_bppm(double *bppm, int length) {
  int i, j;
  int L = 3;
  float *P;
  int *index = get_iindx((unsigned)length);
  P = (float *)space((length + 1) * 3 * sizeof(float));
  P[0] = (float)length;
  P[1] = (float)L;
  for (i = 1; i < length; i++)
    for (j = i + 1; j <= length; j++) {
      P[i * L + 1] += bppm[index[i] - j];
      P[j * L + 2] += bppm[index[i] - j];
    }
  for (i = 1; i <= length; i++)
    P[i * 3 + 0] = 1 - P[i * 3 + 1] - P[i * 3 + 2];
  free(index);
  return (float *)P;
}
```
user: Translate the below assembly code into C programming language:

```asm
<eal_bf_bphash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L12:
  mov    -0x8(%rbp),%eax
  shl    $0x7,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %edx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L12
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int eal_bf_bphash(const unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash << 7 ^ (*str);
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eal_bf_bphash>:
  endbr64
  test   %esi,%esi
  je     L12
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rcx
  mov    $0x0,%eax
L17:
  shl    $0x7,%eax
  movzbl (%rdi),%edx
  xor    %edx,%eax
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L17
  ret
L12:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int eal_bf_bphash(const unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash << 7 ^ (*str);
  }
  return hash;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eal_bf_bphash>:
  endbr64
  test   %esi,%esi
  je     L18
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L19:
  movzbl (%rdi),%edx
  shl    $0x7,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L19
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int eal_bf_bphash(const unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash << 7 ^ (*str);
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<eal_bf_bphash>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L4:
  movzbl (%rdi),%edx
  shl    $0x7,%eax
  add    $0x1,%rdi
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L4
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int eal_bf_bphash(const unsigned char *str, unsigned int len) {
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = hash << 7 ^ (*str);
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *memdup(void *src, int len) {
  void *res = malloc(len);
  if (res)
    memcpy(res, src, len);
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L1
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L1:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(void *src, int len) {
  void *res = malloc(len);
  if (res)
    memcpy(res, src, len);
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L5:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(void *src, int len) {
  void *res = malloc(len);
  if (res)
    memcpy(res, src, len);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L1:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(void *src, int len) {
  void *res = malloc(len);
  if (res)
    memcpy(res, src, len);
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L50
L0:
  movl   $0x0,-0x18(%rbp)
  jmp    L28
L21:
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L55:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  mov    $0x0,%eax
  call   <rng_theta@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x8(%rax),%rbx
  mov    $0x0,%eax
  call   <rng_phi@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x13,-0x14(%rbp)
  jle    L55
  addl   $0x1,-0x18(%rbp)
L28:
  cmpl   $0x13,-0x18(%rbp)
  jle    L21
  addl   $0x1,-0x1c(%rbp)
L50:
  cmpl   $0x13,-0x1c(%rbp)
  jle    L0
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void initialize(double ****lattice) {
  int i, j, k;
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      for (k = 0; k < 20; k++) {
        lattice[i][j][k][0] = rng_theta();
        lattice[i][j][k][1] = rng_phi();
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<initialize>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0xa0(%rdi),%r14
L9:
  mov    $0x0,%ebp
L21:
  mov    $0x0,%ebx
L2:
  mov    (%r12),%rax
  mov    (%rax,%rbp,1),%rax
  mov    (%rax,%rbx,1),%r13
  mov    $0x0,%eax
  call   <rng_theta@plt>
  movsd  %xmm0,0x0(%r13)
  mov    (%r12),%rax
  mov    (%rax,%rbp,1),%rax
  mov    (%rax,%rbx,1),%r13
  mov    $0x0,%eax
  call   <rng_phi@plt>
  movsd  %xmm0,0x8(%r13)
  add    $0x8,%rbx
  cmp    $0xa0,%rbx
  jne    L2
  add    $0x8,%rbp
  cmp    $0xa0,%rbp
  jne    L21
  add    $0x8,%r12
  cmp    %r12,%r14
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void initialize(double ****lattice) {
  int i, j, k;
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      for (k = 0; k < 20; k++) {
        lattice[i][j][k][0] = rng_theta();
        lattice[i][j][k][1] = rng_phi();
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<initialize>:
  endbr64
  push   %r14
  lea    0xa0(%rdi),%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
L9:
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L25:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L20:
  mov    (%r12),%rax
  mov    (%rax,%rbp,1),%rax
  mov    (%rax,%rbx,1),%r13
  xor    %eax,%eax
  call   <rng_theta@plt>
  mov    (%r12),%rax
  movsd  %xmm0,0x0(%r13)
  mov    (%rax,%rbp,1),%rax
  mov    (%rax,%rbx,1),%r13
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <rng_phi@plt>
  movsd  %xmm0,0x8(%r13)
  cmp    $0xa0,%rbx
  jne    L20
  add    $0x8,%rbp
  cmp    $0xa0,%rbp
  jne    L25
  add    $0x8,%r12
  cmp    %r12,%r14
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void initialize(double ****lattice) {
  int i, j, k;
  for (i = 0; i < 20; i++) {
    for (j = 0; j < 20; j++) {
      for (k = 0; k < 20; k++) {
        lattice[i][j][k][0] = rng_theta();
        lattice[i][j][k][1] = rng_phi();
      }
    }
  }
}
```