ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<deamonize>:
  endbr64
  ret
```

assistant: ```c
void deamonize() {
  if (1)
    return;
  pid_t pid;
  pid = fork();
  if (pid < 0) {
    logM("Errore nella fork");
    exit(EXIT_FAILURE);
  }
  if (pid > 0) {
    logM("Prima fork\n");
    exit(EXIT_SUCCESS);
  }
  if (setsid() < 0) {
    logM("Errore sessione leader\n");
    exit(EXIT_FAILURE);
  }
  signal(SIGCHLD, SIG_IGN);
  signal(SIGHUP, SIG_IGN);
  pid = fork();
  if (pid < 0) {
    FILE *fp = fopen("Log.txt", "a");
    fprintf(fp, "Errore nella fork 2\n");
    fclose(fp);
    exit(EXIT_FAILURE);
  }
  if (pid > 0) {
    logM("Seconda fork.\n");
    exit(EXIT_SUCCESS);
  }
  umask(0);
  chdir("/home/isaacisback/Programmazione/programmazionedisistema/Linux/Server");
  close(STDIN_FILENO);
  close(STDOUT_FILENO);
  close(STDERR_FILENO);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<local>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x616d6172676f7270,%rax
  mov    %rax,-0x14(%rbp)
  movl   $0x726f64,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char *local(void) {
  static char nomex[12] = "aaaaaaaaaa";
  char nome[12] = "programador";
  char *ponteiro = nome;
  return ponteiro;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<local>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  lea    0xc(%rsp),%rax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *local(void) {
  static char nomex[12] = "aaaaaaaaaa";
  char nome[12] = "programador";
  char *ponteiro = nome;
  return ponteiro;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<local>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *local(void) {
  static char nomex[12] = "aaaaaaaaaa";
  char nome[12] = "programador";
  char *ponteiro = nome;
  return ponteiro;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<local>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *local(void) {
  static char nomex[12] = "aaaaaaaaaa";
  char nome[12] = "programador";
  char *ponteiro = nome;
  return ponteiro;
}
```
user: What is the c source code of the assembly code below:

```asm
<destroy_cache_lru_policy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <destroy_cache_queue_policy@plt>
  nop
  leave
  ret
```

assistant: ```c
void destroy_cache_lru_policy(struct cache_policy_ *policy) {
  struct cache_queue_policy_ *queue_policy;
  (void)0;
  queue_policy = (struct cache_queue_policy_ *)policy;
  destroy_cache_queue_policy(queue_policy);
  (void)0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<destroy_cache_lru_policy>:
  endbr64
  sub    $0x8,%rsp
  call   <destroy_cache_queue_policy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void destroy_cache_lru_policy(struct cache_policy_ *policy) {
  struct cache_queue_policy_ *queue_policy;
  (void)0;
  queue_policy = (struct cache_queue_policy_ *)policy;
  destroy_cache_queue_policy(queue_policy);
  (void)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_cache_lru_policy>:
  endbr64
  jmp    1050 <destroy_cache_queue_policy@plt>
```

assistant: ```c
void destroy_cache_lru_policy(struct cache_policy_ *policy) {
  struct cache_queue_policy_ *queue_policy;
  (void)0;
  queue_policy = (struct cache_queue_policy_ *)policy;
  destroy_cache_queue_policy(queue_policy);
  (void)0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<destroy_cache_lru_policy>:
  endbr64
  jmp    1050 <destroy_cache_queue_policy@plt>
```

assistant: ```c
void destroy_cache_lru_policy(struct cache_policy_ *policy) {
  struct cache_queue_policy_ *queue_policy;
  (void)0;
  queue_policy = (struct cache_queue_policy_ *)policy;
  destroy_cache_queue_policy(queue_policy);
  (void)0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stdlib_ndarray_singleton_dimensions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L17
L19:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    $0x1,%rax
  jne    L9
  addq   $0x1,-0x10(%rbp)
L9:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L19
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int64_t stdlib_ndarray_singleton_dimensions(int64_t ndims, int64_t *shape) {
  int64_t n;
  int64_t i;
  n = 0;
  for (i = 0; i < ndims; i++) {
    if (shape[i] == 1) {
      n += 1;
    }
  }
  return n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stdlib_ndarray_singleton_dimensions>:
  endbr64
  test   %rdi,%rdi
  je     L13
  mov    %rsi,%rdx
  lea    (%rsi,%rdi,8),%rsi
  mov    $0x0,%eax
L9:
  cmpq   $0x1,(%rdx)
  sete   %cl
  movzbl %cl,%ecx
  add    %rcx,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L9
  ret
L13:
  mov    %rdi,%rax
  ret
```

assistant: ```c
int64_t stdlib_ndarray_singleton_dimensions(int64_t ndims, int64_t *shape) {
  int64_t n;
  int64_t i;
  n = 0;
  for (i = 0; i < ndims; i++) {
    if (shape[i] == 1) {
      n += 1;
    }
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stdlib_ndarray_singleton_dimensions>:
  endbr64
  test   %rdi,%rdi
  je     L1
  lea    (%rsi,%rdi,8),%rcx
  xor    %eax,%eax
  nop
L13:
  xor    %edx,%edx
  cmpq   $0x1,(%rsi)
  sete   %dl
  add    $0x8,%rsi
  add    %rdx,%rax
  cmp    %rcx,%rsi
  jne    L13
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int64_t stdlib_ndarray_singleton_dimensions(int64_t ndims, int64_t *shape) {
  int64_t n;
  int64_t i;
  n = 0;
  for (i = 0; i < ndims; i++) {
    if (shape[i] == 1) {
      n += 1;
    }
  }
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<stdlib_ndarray_singleton_dimensions>:
  endbr64
  test   %rdi,%rdi
  je     L16
  lea    (%rsi,%rdi,8),%rcx
  xor    %eax,%eax
  nop
L10:
  xor    %edx,%edx
  cmpq   $0x1,(%rsi)
  sete   %dl
  add    $0x8,%rsi
  add    %rdx,%rax
  cmp    %rcx,%rsi
  jne    L10
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int64_t stdlib_ndarray_singleton_dimensions(int64_t ndims, int64_t *shape) {
  int64_t n;
  int64_t i;
  n = 0;
  for (i = 0; i < ndims; i++) {
    if (shape[i] == 1) {
      n += 1;
    }
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  movl   $0x1,-0x38(%rbp)
  jmp    L33
L0:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L33:
  mov    -0x38(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L0
  lea    D52(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D9(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L7
L5:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L7:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D41
type_guessed: string
name: retrieve_data
arguments: label: D52
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D9
type_guessed: string
name: retrieve_data
arguments: label: D13
type_guessed: string
name: retrieve_data
arguments: label: D19
type_guessed: string

tool: D41: arg %d: %s


tool: D52: California

tool: D22: Oregon

tool: D9: Washington

tool: D13: Texas

tool: D19: state %d: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0;
  for (i = 1; i < argc; ++i) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; ++i) {
    printf("state %d: %s\n", i, states[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L21
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x1,%ebx
  lea    D35(%rip),%r13
L36:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L36
L21:
  lea    D0(%rip),%rax
  mov    %rax,(%rsp)
  lea    D12(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D18(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D54(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D21(%rip),%rbp
L11:
  mov    (%rsp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L11
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D35
data_type: string
name: parse_data
arguments: tag: D0
data_type: string
name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D54
data_type: string
name: parse_data
arguments: tag: D21
data_type: string

tool: D35: arg %d: %s


tool: D0: California

tool: D12: Oregon

tool: D18: Washington

tool: D54: Texas

tool: D21: state %d: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0;
  for (i = 1; i < argc; ++i) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; ++i) {
    printf("state %d: %s\n", i, states[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L0
  mov    %rsi,%rbp
  movslq %edi,%r13
  mov    $0x1,%ebx
  lea    D27(%rip),%r12
  nopl   (%rax)
L14:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L14
L0:
  lea    D42(%rip),%rax
  xor    %ebx,%ebx
  lea    D31(%rip),%rdx
  mov    %rax,0x8(%rsp)
  lea    D6(%rip),%rax
  lea    D38(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    D29(%rip),%rax
  mov    %rax,0x18(%rsp)
L29:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L27
  mov    (%rsp,%rbx,8),%rdx
  jmp    L29
  xchg   %ax,%ax
L27:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D42
type_infered: string
name: unpack_data
arguments: label: D31
type_infered: string
name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D38
type_infered: string
name: unpack_data
arguments: label: D29
type_infered: string

tool: D27: arg %d: %s


tool: D42: Oregon

tool: D31: California

tool: D6: Washington

tool: D38: state %d: %s


tool: D29: Texas

assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0;
  for (i = 1; i < argc; ++i) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; ++i) {
    printf("state %d: %s\n", i, states[i]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  jle    L38
  mov    %rsi,%r12
  movslq %edi,%rbp
  mov    $0x1,%ebx
  lea    D22(%rip),%r13
  nopl   (%rax)
L37:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L37
L38:
  lea    D27(%rip),%rax
  lea    D24(%rip),%rcx
  xor    %ebx,%ebx
  mov    %rsp,%r12
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D15(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D29(%rip),%rax
  lea    D58(%rip),%rbp
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L2:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D22
datatype: string
name: parse_data
arguments: tag: D27
datatype: string
name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D15
datatype: string
name: parse_data
arguments: tag: D29
datatype: string
name: parse_data
arguments: tag: D58
datatype: string

tool: D22: arg %d: %s


tool: D27: Oregon

tool: D24: California

tool: D15: Washington

tool: D29: Texas

tool: D58: state %d: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  int i = 0;
  for (i = 1; i < argc; ++i) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  char *states[] = {"California", "Oregon", "Washington", "Texas"};
  int num_states = 4;
  for (i = 0; i < num_states; ++i) {
    printf("state %d: %s\n", i, states[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<svbksb>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %ecx,0xc(%rsp)
  mov    %r8d,%r15d
  mov    %r9,%rbp
  mov    0x50(%rsp),%r14
  mov    %r8d,%esi
  mov    $0x1,%edi
  call   <vector@plt>
  mov    %rax,%rdi
  test   %r15d,%r15d
  jle    L15
  lea    0x1(%r15),%edx
  lea    0x0(,%rdx,4),%r9
  mov    $0x4,%ecx
  pxor   %xmm3,%xmm3
  mov    0xc(%rsp),%eax
  lea    0x1(%rax),%r8d
  movaps %xmm3,%xmm5
  movaps %xmm3,%xmm4
  jmp    L43
L81:
  mov    (%rbx,%rax,8),%rsi
  movss  (%rsi,%rcx,1),%xmm0
  mulss  0x0(%rbp,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L81
L11:
  divss  %xmm2,%xmm1
L25:
  movss  %xmm1,(%rdi,%rcx,1)
  add    $0x4,%rcx
  cmp    %r9,%rcx
  je     L49
L43:
  movss  0x0(%r13,%rcx,1),%xmm2
  ucomiss %xmm3,%xmm2
  jp     L14
  ucomiss %xmm5,%xmm2
  movaps %xmm4,%xmm1
  je     L25
L14:
  cmpl   $0x0,0xc(%rsp)
  jle    L83
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
  jmp    L81
L83:
  pxor   %xmm1,%xmm1
  jmp    L11
L49:
  mov    $0x1,%esi
L0:
  mov    (%r12,%rsi,8),%rcx
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
L44:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L44
  movss  %xmm1,(%r14,%rsi,4)
  add    $0x1,%rsi
  cmp    %rdx,%rsi
  jne    L0
L15:
  mov    %r15d,%edx
  mov    $0x1,%esi
  call   <free_vector@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void svbksb(float **u, float *w, float **v, int m, int n, float *b, float *x) {
  int jj, j, i;
  float s, *tmp;
  tmp = vector(1, n);
  for (j = 1; j <= n; j++) {
    s = 0.0;
    if (w[j]) {
      for (i = 1; i <= m; i++)
        s += u[i][j] * b[i];
      s /= w[j];
    }
    tmp[j] = s;
  }
  for (j = 1; j <= n; j++) {
    s = 0.0;
    for (jj = 1; jj <= n; jj++)
      s += v[j][jj] * tmp[jj];
    x[j] = s;
  }
  free_vector(tmp, 1, n);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<svbksb>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %r8d,%esi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x18,%rsp
  mov    %r9,0x8(%rsp)
  mov    0x50(%rsp),%r13
  call   <vector@plt>
  mov    %rax,%rdi
  test   %r14d,%r14d
  jle    L39
  lea    0x1(%r14),%edx
  mov    0x8(%rsp),%r9
  pxor   %xmm2,%xmm2
  lea    0x1(%r15),%esi
  lea    0x0(,%rdx,4),%r8
  mov    $0x4,%ecx
  jmp    L3
  nopl   0x0(%rax)
L91:
  movss  %xmm1,(%rdi,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%r8
  je     L35
L3:
  movss  (%r12,%rcx,1),%xmm3
  ucomiss %xmm2,%xmm3
  jp     L106
  movaps %xmm2,%xmm1
  je     L91
L106:
  test   %r15d,%r15d
  jle    L50
  mov    $0x1,%eax
  movaps %xmm2,%xmm1
  nopw   0x0(%rax,%rax,1)
L22:
  mov    (%rbx,%rax,8),%r10
  movss  (%r10,%rcx,1),%xmm0
  mulss  (%r9,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L22
  divss  %xmm3,%xmm1
L1:
  movss  %xmm1,(%rdi,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%r8
  jne    L3
L35:
  mov    $0x1,%esi
  nopl   0x0(%rax)
L28:
  mov    0x0(%rbp,%rsi,8),%rcx
  mov    $0x1,%eax
  movaps %xmm2,%xmm1
  nopl   (%rax)
L105:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rdi,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L105
  movss  %xmm1,0x0(%r13,%rsi,4)
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  jne    L28
L39:
  add    $0x18,%rsp
  mov    %r14d,%edx
  mov    $0x1,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <free_vector@plt>
L50:
  movaps %xmm2,%xmm1
  divss  %xmm3,%xmm1
  jmp    L1
```

assistant: ```c
void svbksb(float **u, float *w, float **v, int m, int n, float *b, float *x) {
  int jj, j, i;
  float s, *tmp;
  tmp = vector(1, n);
  for (j = 1; j <= n; j++) {
    s = 0.0;
    if (w[j]) {
      for (i = 1; i <= m; i++)
        s += u[i][j] * b[i];
      s /= w[j];
    }
    tmp[j] = s;
  }
  for (j = 1; j <= n; j++) {
    s = 0.0;
    for (jj = 1; jj <= n; jj++)
      s += v[j][jj] * tmp[jj];
    x[j] = s;
  }
  free_vector(tmp, 1, n);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<svbksb>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %r8d,%esi
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x18,%rsp
  mov    %r9,0x8(%rsp)
  mov    0x50(%rsp),%r14
  call   <vector@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L100
  lea    0x1(%r12),%ecx
  mov    0x8(%rsp),%r9
  lea    -0x1(%r12),%esi
  mov    $0x4,%edx
  lea    0x0(,%rcx,4),%r10
  pxor   %xmm3,%xmm3
  lea    0x1(%r15),%r8d
  jmp    L130
  nopw   0x0(%rax,%rax,1)
L154:
  movss  %xmm1,(%rdi,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdx,%r10
  je     L17
L130:
  movss  0x0(%r13,%rdx,1),%xmm2
  ucomiss %xmm3,%xmm2
  jp     L94
  movaps %xmm3,%xmm1
  je     L154
L94:
  test   %r15d,%r15d
  jle    L25
  mov    $0x1,%eax
  movaps %xmm3,%xmm1
L62:
  mov    (%rbx,%rax,8),%r11
  movss  (%r11,%rdx,1),%xmm0
  mulss  (%r9,%rax,4),%xmm0
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L62
  divss  %xmm2,%xmm1
L63:
  movss  %xmm1,(%rdi,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdx,%r10
  jne    L130
L17:
  mov    %r12d,%eax
  mov    %r12d,%r11d
  mov    $0x1,%r9d
  shr    $0x2,%eax
  and    $0xfffffffc,%r11d
  lea    -0x1(%rax),%r8d
  lea    0x1(%r11),%ebx
  shl    $0x4,%r8
  add    $0x14,%r8
  nopw   0x0(%rax,%rax,1)
L23:
  mov    0x0(%rbp,%r9,8),%rdx
  cmp    $0x2,%esi
  jbe    L48
  mov    $0x4,%eax
  movaps %xmm3,%xmm1
  xchg   %ax,%ax
L38:
  movups (%rdi,%rax,1),%xmm0
  movups (%rdx,%rax,1),%xmm4
  add    $0x10,%rax
  mulps  %xmm4,%xmm0
  addss  %xmm0,%xmm1
  movaps %xmm0,%xmm2
  shufps $0x55,%xmm0,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm0,%xmm1
  unpckhps %xmm0,%xmm1
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm2,%xmm1
  addss  %xmm0,%xmm1
  cmp    %r8,%rax
  jne    L38
  mov    %ebx,%eax
  cmp    %r11d,%r12d
  je     L57
L40:
  movslq %eax,%r13
  movss  (%rdx,%r13,4),%xmm0
  mulss  (%rdi,%r13,4),%xmm0
  lea    0x0(,%r13,4),%r10
  lea    0x1(%rax),%r13d
  addss  %xmm0,%xmm1
  cmp    %r13d,%r12d
  jl     L57
  movss  0x4(%rdi,%r10,1),%xmm0
  mulss  0x4(%rdx,%r10,1),%xmm0
  add    $0x2,%eax
  addss  %xmm0,%xmm1
  cmp    %eax,%r12d
  jl     L57
  movss  0x8(%rdi,%r10,1),%xmm0
  mulss  0x8(%rdx,%r10,1),%xmm0
  addss  %xmm0,%xmm1
L57:
  movss  %xmm1,(%r14,%r9,4)
  add    $0x1,%r9
  cmp    %r9,%rcx
  jne    L23
L100:
  add    $0x18,%rsp
  mov    %r12d,%edx
  mov    $0x1,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <free_vector@plt>
  nopw   0x0(%rax,%rax,1)
L48:
  movaps %xmm3,%xmm1
  mov    $0x1,%eax
  jmp    L40
L25:
  movaps %xmm3,%xmm1
  divss  %xmm2,%xmm1
  jmp    L63
```

assistant: ```c
void svbksb(float **u, float *w, float **v, int m, int n, float *b, float *x) {
  int jj, j, i;
  float s, *tmp;
  tmp = vector(1, n);
  for (j = 1; j <= n; j++) {
    s = 0.0;
    if (w[j]) {
      for (i = 1; i <= m; i++)
        s += u[i][j] * b[i];
      s /= w[j];
    }
    tmp[j] = s;
  }
  for (j = 1; j <= n; j++) {
    s = 0.0;
    for (jj = 1; jj <= n; jj++)
      s += v[j][jj] * tmp[jj];
    x[j] = s;
  }
  free_vector(tmp, 1, n);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<copyUC_DependencyNode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  mov    $0x0,%edi
  call   <show_stack@plt>
  mov    $0x0,%eax
  call   <breakpoint@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D7
datatype: string
name: read_data
arguments: label: D0
datatype: string

tool: D8: Dependency management doesn't work yet


tool: D7: BUG

tool: D0: kgdb assertion failed: %s


assistant: ```c
struct UC_DependencyNode *copyUC_DependencyNode(struct UC_DependencyNode *sdep) {
  printk("Dependency management doesn't work yet\n");
  do {
    if (!(0)) {
      printk("kgdb assertion failed: %s\n", "BUG");
      show_stack(((void *)0));
      breakpoint();
    }
  } while (0);
  return ((void *)0);
}
```