ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<OC_mkVarDec>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0xa(%rbx,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  mov    %rax,%rbx
  lea    D14(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D15(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D14
data_type: string
name: parse_data
arguments: data_tag: D15
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string

tool: D14: val 

tool: D15:  : 

tool: D0: 


assistant: ```c
char *OC_mkVarDec(char *varName, char *varType) {
  size_t length = strlen(varName) + strlen(varType) + 10;
  char *vardec = UTIL_mallocStr(length);
  strcpy(vardec, "val ");
  strcat(vardec, varName);
  strcat(vardec, " : ");
  strcat(vardec, varType);
  strcat(vardec, "\n");
  return vardec;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<OC_mkVarDec>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0xa(%r12,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  lea    D0(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D12(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D29(%rip),%rsi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string
name: parse_data
arguments: data_label: D29
data_type: string

tool: D0: val 

tool: D12:  : 

tool: D29: 


assistant: ```c
char *OC_mkVarDec(char *varName, char *varType) {
  size_t length = strlen(varName) + strlen(varType) + 10;
  char *vardec = UTIL_mallocStr(length);
  strcpy(vardec, "val ");
  strcat(vardec, varName);
  strcat(vardec, " : ");
  strcat(vardec, varType);
  strcat(vardec, "\n");
  return vardec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<OC_mkVarDec>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  lea    0xa(%r12,%rax,1),%edi
  movslq %edi,%rdi
  call   <UTIL_mallocStr@plt>
  lea    D12(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D18(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rdi
  lea    D8(%rip),%rsi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string
name: unpack_data
arguments: data_label: D8
data_type: string

tool: D12: val 

tool: D18:  : 

tool: D8: 


assistant: ```c
char *OC_mkVarDec(char *varName, char *varType) {
  size_t length = strlen(varName) + strlen(varType) + 10;
  char *vardec = UTIL_mallocStr(length);
  strcpy(vardec, "val ");
  strcat(vardec, varName);
  strcat(vardec, " : ");
  strcat(vardec, varType);
  strcat(vardec, "\n");
  return vardec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<readlines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %esi,-0x40c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x400(%rbp)
  jmp    L43
L48:
  mov    -0x400(%rbp),%eax
  cmp    -0x40c(%rbp),%eax
  jge    L44
  mov    -0x3fc(%rbp),%eax
  mov    %eax,%edi
  call   <alloc@plt>
  mov    %rax,-0x3f8(%rbp)
  cmpq   $0x0,-0x3f8(%rbp)
  jne    L2
L44:
  mov    $0xffffffff,%eax
  jmp    L45
L2:
  mov    -0x3fc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x3f0(%rbp,%rax,1)
  lea    -0x3f0(%rbp),%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x400(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x400(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x408(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rax,(%rdx)
L43:
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <_getline@plt>
  mov    %eax,-0x3fc(%rbp)
  cmpl   $0x0,-0x3fc(%rbp)
  jg     L48
  mov    -0x400(%rbp),%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

assistant: ```c
int readlines(char *lineptr[], int ml) {
  int l, nl;
  char *p, line[1000];
  nl = 0;
  while ((l = _getline(line, 1000)) > 0) {
    if (nl >= ml || (p = alloc(l)) == NULL) {
      return -1;
    } else {
      line[l - 1] = '\0';
      strcpy(p, line);
      lineptr[nl++] = p;
    }
  }
  return nl;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  mov    %rsp,%r13
  jmp    L41
L38:
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,(%r15,%r12,8)
  add    $0x1,%r12
L41:
  mov    %r12d,%ebp
  mov    $0x3e8,%esi
  mov    %r13,%rdi
  call   <_getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L10
  cmp    %r12d,%r14d
  jle    L58
  mov    %ebx,%edi
  call   <alloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L38
  mov    $0xffffffff,%ebp
  jmp    L10
L58:
  mov    $0xffffffff,%ebp
L10:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  mov    %ebp,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlines(char *lineptr[], int ml) {
  int l, nl;
  char *p, line[1000];
  nl = 0;
  while ((l = _getline(line, 1000)) > 0) {
    if (nl >= ml || (p = alloc(l)) == NULL) {
      return -1;
    } else {
      line[l - 1] = '\0';
      strcpy(p, line);
      lineptr[nl++] = p;
    }
  }
  return nl;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L56
  nopl   (%rax)
L27:
  cmp    %ebp,%r13d
  jle    L21
  mov    %ebx,%edi
  call   <alloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L21
  sub    $0x1,%ebx
  mov    %r12,%rsi
  mov    %rax,%rdi
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  call   <strcpy@plt>
  mov    %r15,(%r14,%rbp,8)
  add    $0x1,%rbp
L56:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %ebp,%r15d
  call   <_getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L27
L51:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x3f8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  mov    $0xffffffff,%r15d
  jmp    L51
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlines(char *lineptr[], int ml) {
  int l, nl;
  char *p, line[1000];
  nl = 0;
  while ((l = _getline(line, 1000)) > 0) {
    if (nl >= ml || (p = alloc(l)) == NULL) {
      return -1;
    } else {
      line[l - 1] = '\0';
      strcpy(p, line);
      lineptr[nl++] = p;
    }
  }
  return nl;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<readlines>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L6
  nopl   (%rax)
L11:
  cmp    %ebp,%r13d
  jle    L47
  mov    %ebx,%edi
  call   <alloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L47
  sub    $0x1,%ebx
  mov    %r12,%rsi
  mov    %rax,%rdi
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  call   <strcpy@plt>
  mov    %r15,(%r14,%rbp,8)
  add    $0x1,%rbp
L6:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %ebp,%r15d
  call   <_getline@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L11
L56:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x3f8,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0xffffffff,%r15d
  jmp    L56
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int readlines(char *lineptr[], int ml) {
  int l, nl;
  char *p, line[1000];
  nl = 0;
  while ((l = _getline(line, 1000)) > 0) {
    if (nl >= ml || (p = alloc(l)) == NULL) {
      return -1;
    } else {
      line[l - 1] = '\0';
      strcpy(p, line);
      lineptr[nl++] = p;
    }
  }
  return nl;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wtime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  D0(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: f64

tool: D0: 1000000

assistant: ```c
double wtime() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec + t.tv_usec / 1000000.0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wtime>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D2(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: f64

tool: D2: 1000000

assistant: ```c
double wtime() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec + t.tv_usec / 1000000.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wtime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D6(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: f64

tool: D6: 1000000

assistant: ```c
double wtime() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec + t.tv_usec / 1000000.0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wtime>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rsp),%xmm0
  divsd  D4(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: f64

tool: D4: 1000000

assistant: ```c
double wtime() {
  struct timeval t;
  gettimeofday(&t, NULL);
  return t.tv_sec + t.tv_usec / 1000000.0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<acosh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x3fefffff,-0xc(%rbp)
  jg     L58
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  movq   %xmm0,%rax
  jmp    L37
L58:
  cmpl   $0x41afffff,-0xc(%rbp)
  jle    L7
  cmpl   $0x7fefffff,-0xc(%rbp)
  jle    L89
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movq   %xmm0,%rax
  jmp    L37
L89:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movsd  D42(%rip),%xmm1
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  jmp    L37
L7:
  mov    -0xc(%rbp),%eax
  lea    -0x3ff00000(%rax),%edx
  lea    -0x18(%rbp),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  test   %eax,%eax
  jne    L92
  mov    D38(%rip),%rax
  jmp    L37
L92:
  cmpl   $0x40000000,-0xc(%rbp)
  jle    L16
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D1(%rip),%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D1(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x20(%rbp),%xmm2
  subsd  %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  jmp    L37
L16:
  movsd  -0x18(%rbp),%xmm0
  movsd  D1(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm4
  addsd  -0x8(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <log1p@plt>
  movq   %xmm0,%rax
L37:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D42
type: byte[8]
name: read_data
arguments: label: D38
type: f64
name: read_data
arguments: label: D1
type: f64

tool: {"D42": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: D38: 0

tool: D1: 1

assistant: ```c
double acosh(double x) {
  double t;
  int hx;
  hx = *(1 + (const int *)&x);
  if (hx < 0x3ff00000) {
    return (0.0 / 0.0);
  } else if (hx >= 0x41b00000) {
    if (hx >= 0x7ff00000) {
      return x + x;
    } else {
      return log(x) + 6.93147180559945286227e-01;
    }
  } else if (((hx - 0x3ff00000) | *(const int *)&x) == 0) {
    return 0.0;
  } else if (hx > 0x40000000) {
    t = x * x;
    return log(2.0 * x - 1.0 / (x + sqrt(t - 1.0)));
  } else {
    t = x - 1.0;
    return log1p(t + sqrt(2.0 * t + t * t));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<acosh>:
  endbr64
  movq   %xmm0,%rax
  sar    $0x20,%rax
  cmp    $0x3fefffff,%eax
  jle    L55
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%rbx
  cmp    $0x41afffff,%eax
  jle    L63
  cmp    $0x7fefffff,%eax
  jle    L23
  addsd  %xmm0,%xmm0
L89:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
L55:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  ret
L23:
  call   <log@plt>
  addsd  D3(%rip),%xmm0
  jmp    L89
L63:
  lea    -0x3ff00000(%rax),%ecx
  pxor   %xmm0,%xmm0
  or     %ebx,%ecx
  je     L89
  cmp    $0x40000000,%eax
  jle    L83
  movq   %rbx,%xmm4
  movq   %rbx,%xmm6
  addsd  %xmm4,%xmm4
  movq   %xmm4,%r14
  movq   %rbx,%xmm0
  mulsd  %xmm6,%xmm0
  subsd  D28(%rip),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L34
  sqrtsd %xmm0,%xmm0
L28:
  movq   %rbx,%xmm5
  addsd  %xmm0,%xmm5
  movsd  D28(%rip),%xmm1
  divsd  %xmm5,%xmm1
  movq   %r14,%xmm0
  subsd  %xmm1,%xmm0
  call   <log@plt>
  jmp    L89
L34:
  call   <sqrt@plt>
  jmp    L28
L83:
  movq   %rbx,%xmm0
  subsd  D28(%rip),%xmm0
  movapd %xmm0,%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L3
  sqrtsd %xmm0,%xmm0
L77:
  addsd  0x8(%rsp),%xmm0
  call   <log1p@plt>
  jmp    L89
L3:
  call   <sqrt@plt>
  jmp    L77
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: byte[8]
name: disassemble_data
arguments: data_label: D28
type_guessed: f64

tool: {"D3": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

tool: D28: 1

assistant: ```c
double acosh(double x) {
  double t;
  int hx;
  hx = *(1 + (const int *)&x);
  if (hx < 0x3ff00000) {
    return (0.0 / 0.0);
  } else if (hx >= 0x41b00000) {
    if (hx >= 0x7ff00000) {
      return x + x;
    } else {
      return log(x) + 6.93147180559945286227e-01;
    }
  } else if (((hx - 0x3ff00000) | *(const int *)&x) == 0) {
    return 0.0;
  } else if (hx > 0x40000000) {
    t = x * x;
    return log(2.0 * x - 1.0 / (x + sqrt(t - 1.0)));
  } else {
    t = x - 1.0;
    return log1p(t + sqrt(2.0 * t + t * t));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<acosh>:
  endbr64
  movq   %xmm0,%rax
  sar    $0x20,%rax
  cmp    $0x3fefffff,%eax
  jle    L40
  sub    $0x18,%rsp
  movapd %xmm0,%xmm1
  cmp    $0x41afffff,%eax
  jle    L61
  cmp    $0x7fefffff,%eax
  jle    L45
  addsd  %xmm0,%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
  nop
L61:
  movq   %xmm0,%rdx
  lea    -0x3ff00000(%rax),%ecx
  or     %edx,%ecx
  je     L58
  cmp    $0x40000000,%eax
  jle    L79
  movapd %xmm0,%xmm3
  movsd  D5(%rip),%xmm2
  pxor   %xmm4,%xmm4
  addsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm0
  subsd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L83
  sqrtsd %xmm0,%xmm0
L88:
  addsd  %xmm0,%xmm1
  add    $0x18,%rsp
  divsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  jmp    1070 <log@plt>
  nopl   (%rax)
L40:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L79:
  subsd  D5(%rip),%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  ucomisd %xmm0,%xmm2
  ja     L9
  sqrtsd %xmm0,%xmm0
L12:
  addsd  %xmm1,%xmm0
  add    $0x18,%rsp
  jmp    1090 <log1p@plt>
  nopw   0x0(%rax,%rax,1)
L58:
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L45:
  call   <log@plt>
  addsd  D37(%rip),%xmm0
  add    $0x18,%rsp
  ret
L9:
  movsd  %xmm1,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm1
  jmp    L12
L83:
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  mov    D5(%rip),%rax
  movq   %rax,%xmm2
  jmp    L88
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: f64
name: parse_data
arguments: label: D37
type_guessed: byte[8]

tool: D5: 1

tool: {"D37": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double acosh(double x) {
  double t;
  int hx;
  hx = *(1 + (const int *)&x);
  if (hx < 0x3ff00000) {
    return (0.0 / 0.0);
  } else if (hx >= 0x41b00000) {
    if (hx >= 0x7ff00000) {
      return x + x;
    } else {
      return log(x) + 6.93147180559945286227e-01;
    }
  } else if (((hx - 0x3ff00000) | *(const int *)&x) == 0) {
    return 0.0;
  } else if (hx > 0x40000000) {
    t = x * x;
    return log(2.0 * x - 1.0 / (x + sqrt(t - 1.0)));
  } else {
    t = x - 1.0;
    return log1p(t + sqrt(2.0 * t + t * t));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<acosh>:
  endbr64
  movq   %xmm0,%rax
  sar    $0x20,%rax
  cmp    $0x3fefffff,%eax
  jle    L6
  sub    $0x18,%rsp
  movapd %xmm0,%xmm1
  cmp    $0x41afffff,%eax
  jle    L83
  cmp    $0x7fefffff,%eax
  jle    L40
  addsd  %xmm0,%xmm1
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  ret
  nop
L83:
  movq   %xmm0,%rdx
  lea    -0x3ff00000(%rax),%ecx
  or     %edx,%ecx
  je     L24
  cmp    $0x40000000,%eax
  jle    L76
  movapd %xmm0,%xmm3
  movsd  D18(%rip),%xmm2
  pxor   %xmm4,%xmm4
  addsd  %xmm0,%xmm3
  mulsd  %xmm0,%xmm0
  subsd  %xmm2,%xmm0
  ucomisd %xmm0,%xmm4
  ja     L25
  sqrtsd %xmm0,%xmm0
L84:
  addsd  %xmm0,%xmm1
  add    $0x18,%rsp
  divsd  %xmm1,%xmm2
  subsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  jmp    1070 <log@plt>
  nopl   (%rax)
L6:
  pxor   %xmm0,%xmm0
  divsd  %xmm0,%xmm0
  ret
  nopl   0x0(%rax)
L76:
  subsd  D18(%rip),%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  mulsd  %xmm1,%xmm2
  addsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  ucomisd %xmm0,%xmm2
  ja     L0
  sqrtsd %xmm0,%xmm0
L18:
  addsd  %xmm1,%xmm0
  add    $0x18,%rsp
  jmp    1090 <log1p@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  pxor   %xmm0,%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L40:
  call   <log@plt>
  addsd  D38(%rip),%xmm0
  add    $0x18,%rsp
  ret
L0:
  movsd  %xmm1,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm1
  jmp    L18
L25:
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,(%rsp)
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm3
  mov    D18(%rip),%rax
  movq   %rax,%xmm2
  jmp    L84
```

tool_calls: name: unpack_data
arguments: data_label: D18
type_guessed: f64
name: unpack_data
arguments: data_label: D38
type_guessed: byte[8]

tool: D18: 1

tool: {"D38": [0xef,0x39,0xfa,0xfe,0x42,0x2e,0xe6,0x3f]}

assistant: ```c
double acosh(double x) {
  double t;
  int hx;
  hx = *(1 + (const int *)&x);
  if (hx < 0x3ff00000) {
    return (0.0 / 0.0);
  } else if (hx >= 0x41b00000) {
    if (hx >= 0x7ff00000) {
      return x + x;
    } else {
      return log(x) + 6.93147180559945286227e-01;
    }
  } else if (((hx - 0x3ff00000) | *(const int *)&x) == 0) {
    return 0.0;
  } else if (hx > 0x40000000) {
    t = x * x;
    return log(2.0 * x - 1.0 / (x + sqrt(t - 1.0)));
  } else {
    t = x - 1.0;
    return log1p(t + sqrt(2.0 * t + t * t));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L32:
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L50:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  jg     L19
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L19:
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L50
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L25
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L33
L25:
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L33:
  addl   $0x1,-0x10(%rbp)
L39:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L32
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D27
type_infered: string
name: read_data
arguments: tag: D36
type_infered: string
name: read_data
arguments: tag: D45
type_infered: string

tool: D32: %d

tool: D27: %d %d

tool: D36: NO


tool: D45: YES


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  int n, k, a;
  for (int a0 = 0; a0 < t; a0++) {
    scanf("%d %d", &n, &k);
    for (int a_i = 0; a_i < n; a_i++) {
      scanf("%d", &a);
      if (a <= 0)
        k--;
    }
    k <= 0 ? printf("NO\n") : printf("YES\n");
  }
  return 0;
}
```