ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sprint_mov_atRi_to_direct>:
  endbr64
  sub    $0x8,%rsp
  movzbl %sil,%ecx
  lea    D7(%rip),%rsi
  call   <sprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D7
type_guessed: string

tool: D7: MOV   0x%02X, @R%X                 

assistant: ```c
void sprint_mov_atRi_to_direct(char *str, unsigned char i, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", @R%X                 ",
          direct, i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sprint_mov_atRi_to_direct>:
  endbr64
  movzbl %sil,%ecx
  lea    D7(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: MOV   0x%02X, @R%X                 

assistant: ```c
void sprint_mov_atRi_to_direct(char *str, unsigned char i, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", @R%X                 ",
          direct, i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sprint_mov_atRi_to_direct>:
  endbr64
  movzbl %sil,%ecx
  lea    D3(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3: MOV   0x%02X, @R%X                 

assistant: ```c
void sprint_mov_atRi_to_direct(char *str, unsigned char i, uint8_t direct) {
  sprintf(str,
          "MOV   "
          "0x%02X"
          ", @R%X                 ",
          direct, i);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<suffix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x34(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D37(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x34(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  cmp    $0x3,%edx
  jg     L25
  mov    -0x34(%rbp),%eax
  sub    $0xa,%eax
  cmp    $0x9,%eax
  jbe    L25
  mov    -0x34(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  movslq %edx,%rax
  mov    -0x30(%rbp,%rax,8),%rax
  jmp    L26
L25:
  mov    -0x30(%rbp),%rax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D38
type: string
name: disassemble_data
arguments: data_label: D37
type: string
name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D27
type: string

tool: D38: th

tool: D37: st

tool: D28: nd

tool: D27: rd

assistant: ```c
const char *suffix(int n) {
  n %= 100;
  const char *s123[] = {"th", "st", "nd", "rd"};
  if (n % 10 <= 3 && n / 10 != 1)
    return s123[n % 10];
  return s123[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<suffix>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%edx
  mov    %edi,%eax
  sub    %edx,%eax
  lea    D41(%rip),%rsi
  mov    %rsi,(%rsp)
  lea    D47(%rip),%rsi
  mov    %rsi,0x8(%rsp)
  lea    D38(%rip),%rsi
  mov    %rsi,0x10(%rsp)
  lea    D27(%rip),%rsi
  mov    %rsi,0x18(%rsp)
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%ecx
  add    %ecx,%ecx
  mov    %eax,%edx
  sub    %ecx,%edx
  lea    D41(%rip),%rcx
  cmp    $0x3,%edx
  jg     L37
  sub    $0xa,%eax
  cmp    $0x9,%eax
  ja     L7
L37:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    %rcx,%rax
  add    $0x38,%rsp
  ret
L7:
  movslq %edx,%rdx
  mov    (%rsp,%rdx,8),%rcx
  jmp    L37
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D41
type: string
name: unpack_data
arguments: tag: D47
type: string
name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D27
type: string

tool: D41: th

tool: D47: st

tool: D38: nd

tool: D27: rd

assistant: ```c
const char *suffix(int n) {
  n %= 100;
  const char *s123[] = {"th", "st", "nd", "rd"};
  if (n % 10 <= 3 && n / 10 != 1)
    return s123[n % 10];
  return s123[0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<suffix>:
  endbr64
  movslq %edi,%rdx
  sub    $0x38,%rsp
  lea    D30(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  imul   $0x51eb851f,%rdx,%rdx
  mov    %edi,%eax
  mov    %rsi,0x8(%rsp)
  sar    $0x1f,%eax
  lea    D31(%rip),%rsi
  mov    %rsi,0x18(%rsp)
  sar    $0x25,%rdx
  sub    %eax,%edx
  imul   $0x64,%edx,%eax
  sub    %eax,%edi
  lea    D20(%rip),%rax
  movslq %edi,%rcx
  lea    D11(%rip),%rdi
  mov    %rax,(%rsp)
  mov    %rcx,%rdx
  imul   $0x66666667,%rcx,%rcx
  mov    %rdi,0x10(%rsp)
  mov    %edx,%esi
  sar    $0x1f,%esi
  sar    $0x22,%rcx
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  add    %esi,%esi
  sub    %esi,%ecx
  cmp    $0x3,%ecx
  jg     L18
  sub    $0xa,%edx
  cmp    $0x9,%edx
  ja     L35
L18:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x38,%rsp
  ret
  nopl   0x0(%rax)
L35:
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,8),%rax
  jmp    L18
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D31
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string

tool: D30: st

tool: D31: rd

tool: D20: th

tool: D11: nd

assistant: ```c
const char *suffix(int n) {
  n %= 100;
  const char *s123[] = {"th", "st", "nd", "rd"};
  if (n % 10 <= 3 && n / 10 != 1)
    return s123[n % 10];
  return s123[0];
}
```
user: What is the c source code of the assembly code below:

```asm
<suffix>:
  endbr64
  movslq %edi,%rdx
  sub    $0x38,%rsp
  lea    D24(%rip),%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  imul   $0x51eb851f,%rdx,%rdx
  mov    %edi,%eax
  movq   %rcx,%xmm1
  sar    $0x1f,%eax
  lea    D6(%rip),%rcx
  lea    D35(%rip),%rsi
  movq   %rcx,%xmm2
  sar    $0x25,%rdx
  sub    %eax,%edx
  imul   $0x64,%edx,%eax
  sub    %eax,%edi
  lea    D11(%rip),%rax
  movslq %edi,%rcx
  movq   %rax,%xmm0
  imul   $0x66666667,%rcx,%rcx
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  movq   %rsi,%xmm0
  mov    %edi,%esi
  sar    $0x1f,%esi
  punpcklqdq %xmm2,%xmm0
  sar    $0x22,%rcx
  movaps %xmm0,0x10(%rsp)
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%esi
  mov    %edi,%ecx
  add    %esi,%esi
  sub    %esi,%ecx
  cmp    $0x3,%ecx
  jg     L5
  mov    %edi,%edx
  sub    $0xa,%edx
  cmp    $0x9,%edx
  ja     L12
L5:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  ret
  nopl   (%rax)
L12:
  movslq %ecx,%rcx
  mov    (%rsp,%rcx,8),%rax
  jmp    L5
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: string
name: extract_symbolic_data
arguments: label: D35
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string

tool: D24: st

tool: D6: rd

tool: D35: nd

tool: D11: th

assistant: ```c
const char *suffix(int n) {
  n %= 100;
  const char *s123[] = {"th", "st", "nd", "rd"};
  if (n % 10 <= 3 && n / 10 != 1)
    return s123[n % 10];
  return s123[0];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<preinc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *preinc(char *base) {
  ++base;
  return base;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<preinc>:
  endbr64
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *preinc(char *base) {
  ++base;
  return base;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<preinc>:
  endbr64
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *preinc(char *base) {
  ++base;
  return base;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<preinc>:
  endbr64
  lea    0x1(%rdi),%rax
  ret
```

assistant: ```c
char *preinc(char *base) {
  ++base;
  return base;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<writen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L37
L22:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L52
  mov    D10(%rip),%rax
  mov    (%rax),%rdx
  mov    D27(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L68
  mov    D28(%rip),%rax
  mov    (%rax),%rdx
  mov    D27(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L1
L68:
  movl   $0x0,-0x14(%rbp)
  jmp    L52
L1:
  mov    $0xffffffff,%eax
  jmp    L2
L52:
  mov    -0x14(%rbp),%eax
  cltq
  sub    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L37:
  cmpq   $0x0,-0x10(%rbp)
  jne    L22
  mov    -0x38(%rbp),%rax
L2:
  leave
  ret
```

assistant: ```c
ssize_t writen(int fd, void *vptr, size_t n) {
  ssize_t nwrite;
  size_t nleft;
  unsigned char *ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwrite = write(fd, ptr, nleft)) <= 0) {
      if (EINTR == errno || EAGAIN == errno) {
        nwrite = 0;
      } else {
        return (-1);
      }
    }
    nleft -= nwrite;
    ptr += nwrite;
  }
  return (n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writen>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%r13
  test   %rdx,%rdx
  je     L39
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x0,%r14d
  jmp    L38
L57:
  mov    %r14d,%eax
L29:
  cltq
  add    %rax,%rbp
  sub    %rax,%rbx
  je     L39
L38:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L29
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  mov    D5(%rip),%rdx
  cmp    %rax,(%rdx)
  je     L57
  mov    D7(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L49
  mov    %r14d,%eax
  jmp    L29
L39:
  mov    %r13d,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
ssize_t writen(int fd, void *vptr, size_t n) {
  ssize_t nwrite;
  size_t nleft;
  unsigned char *ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwrite = write(fd, ptr, nleft)) <= 0) {
      if (EINTR == errno || EAGAIN == errno) {
        nwrite = 0;
      } else {
        return (-1);
      }
    }
    nleft -= nwrite;
    ptr += nwrite;
  }
  return (n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L14
  xchg   %ax,%ax
L17:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L46
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L17
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L46:
  mov    D26(%rip),%rax
  mov    D1(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L17
  mov    D11(%rip),%rdx
  cmp    (%rdx),%rax
  je     L17
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen(int fd, void *vptr, size_t n) {
  ssize_t nwrite;
  size_t nleft;
  unsigned char *ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwrite = write(fd, ptr, nleft)) <= 0) {
      if (EINTR == errno || EAGAIN == errno) {
        nwrite = 0;
      } else {
        return (-1);
      }
    }
    nleft -= nwrite;
    ptr += nwrite;
  }
  return (n);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L28
  xchg   %ax,%ax
L24:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L3
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L24
L28:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L3:
  mov    D2(%rip),%rax
  mov    D17(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  je     L24
  mov    D10(%rip),%rdx
  cmp    (%rdx),%rax
  je     L24
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t writen(int fd, void *vptr, size_t n) {
  ssize_t nwrite;
  size_t nleft;
  unsigned char *ptr = vptr;
  nleft = n;
  while (nleft > 0) {
    if ((nwrite = write(fd, ptr, nleft)) <= 0) {
      if (EINTR == errno || EAGAIN == errno) {
        nwrite = 0;
      } else {
        return (-1);
      }
    }
    nleft -= nwrite;
    ptr += nwrite;
  }
  return (n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  D36(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D17(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D18(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd D31(%rip),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  je     L30
  cmpl   $0x0,-0xc(%rbp)
  je     L30
  cmpl   $0x0,-0x14(%rbp)
  je     L38
L30:
  mov    $0x1,%eax
  jmp    L1
L38:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D36
type: f64
name: extract_symbolic_data
arguments: data_label: D17
type: byte[8]
name: extract_symbolic_data
arguments: data_label: D18
type: f64
name: extract_symbolic_data
arguments: data_label: D31
type: f64

tool: D36: 2

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D18: 0.2

tool: D31: 0.3

assistant: ```c
int test() {
  double x = 2;
  x /= 3;
  int false1 = 0.2 > x;
  int true1 = 0.3 < x;
  int true2 = 0.3 != 3.2;
  return (true1 && true2 && false1 == 0) ? 0 : 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int test() {
  double x = 2;
  x /= 3;
  int false1 = 0.2 > x;
  int true1 = 0.3 < x;
  int true2 = 0.3 != 3.2;
  return (true1 && true2 && false1 == 0) ? 0 : 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test() {
  double x = 2;
  x /= 3;
  int false1 = 0.2 > x;
  int true1 = 0.3 < x;
  int true2 = 0.3 != 3.2;
  return (true1 && true2 && false1 == 0) ? 0 : 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test() {
  double x = 2;
  x /= 3;
  int false1 = 0.2 > x;
  int true1 = 0.3 < x;
  int true2 = 0.3 != 3.2;
  return (true1 && true2 && false1 == 0) ? 0 : 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_dl_elf_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L55
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x5,-0x18(%rbp)
  jmp    L37
L0:
  mov    -0x10(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %rcx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x18,%rax
  xor    %rax,-0x10(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  andq   $0xfffffff,-0x10(%rbp)
L55:
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_dl_elf_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %rax,%rax
  je     L5
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L5
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  movzbl 0x2(%rdi),%ecx
  test   %cl,%cl
  je     L5
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  movzbl 0x3(%rdi),%ecx
  test   %cl,%cl
  je     L5
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  movzbl 0x4(%rdi),%ecx
  test   %cl,%cl
  je     L5
  shl    $0x4,%rax
  movzbl %cl,%ecx
  add    %rcx,%rax
  lea    0x5(%rdi),%rcx
  movzbl 0x5(%rdi),%edx
  test   %dl,%dl
  je     L8
L19:
  shl    $0x4,%rax
  add    $0x1,%rcx
  movzbl %dl,%edx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x18,%rax
  and    $0xf0,%eax
  xor    %rdx,%rax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L19
L8:
  and    $0xfffffff,%eax
L5:
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_dl_elf_hash>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%rcx
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L23
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  je     L22
  movzbl %dl,%eax
  movzbl 0x2(%rcx),%edx
  shl    $0x4,%rsi
  add    %rsi,%rax
  test   %dl,%dl
  je     L23
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x3(%rcx),%edx
  test   %dl,%dl
  je     L23
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x4(%rcx),%edx
  test   %dl,%dl
  je     L23
  shl    $0x4,%rax
  lea    0x5(%rcx),%rsi
  add    %rdx,%rax
  movzbl 0x5(%rcx),%edx
  test   %dl,%dl
  je     L23
  nopl   0x0(%rax)
L40:
  shl    $0x4,%rax
  add    $0x1,%rsi
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x18,%rax
  and    $0xf0,%eax
  xor    %rdx,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L40
  and    $0xfffffff,%eax
L23:
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_dl_elf_hash>:
  endbr64
  movzbl (%rdi),%esi
  mov    %rdi,%rcx
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L36
  movzbl 0x1(%rcx),%edx
  test   %dl,%dl
  je     L12
  movzbl %dl,%eax
  movzbl 0x2(%rcx),%edx
  shl    $0x4,%rsi
  add    %rsi,%rax
  test   %dl,%dl
  je     L36
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x3(%rcx),%edx
  test   %dl,%dl
  je     L36
  shl    $0x4,%rax
  add    %rdx,%rax
  movzbl 0x4(%rcx),%edx
  test   %dl,%dl
  je     L36
  shl    $0x4,%rax
  lea    0x5(%rcx),%rsi
  add    %rdx,%rax
  movzbl 0x5(%rcx),%edx
  test   %dl,%dl
  je     L36
  nopl   0x0(%rax)
L27:
  shl    $0x4,%rax
  add    $0x1,%rsi
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x18,%rax
  and    $0xf0,%eax
  xor    %rdx,%rax
  movzbl (%rsi),%edx
  test   %dl,%dl
  jne    L27
  and    $0xfffffff,%eax
L36:
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  movzbl %sil,%eax
  ret
```

assistant: ```c
unsigned int __attribute__((unused)) _dl_elf_hash(const char *name_arg) {
  const unsigned char *name = (const unsigned char *)name_arg;
  unsigned long int hash = *name;
  if (hash != 0 && name[1] != '\0') {
    hash = (hash << 4) + name[1];
    if (name[2] != '\0') {
      hash = (hash << 4) + name[2];
      if (name[3] != '\0') {
        hash = (hash << 4) + name[3];
        if (name[4] != '\0') {
          hash = (hash << 4) + name[4];
          name += 5;
          while (*name != '\0') {
            unsigned long int hi;
            hash = (hash << 4) + *name++;
            hi = hash & 0xf0000000;
            hash ^= hi >> 24;
          }
          hash &= 0x0fffffff;
        }
      }
    }
  }
  return hash;
}
```