user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<editDistance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    %eax,-0x48(%rbp)
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,-0x44(%rbp)
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x68(%rbp)
  lea    0x1(%r15),%eax
  cltq
  imul   %rdx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L153:
  cmp    %rdx,%rsp
  je     L106
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L153
L106:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L3
  orq    $0x0,-0x8(%rsp,%rax,1)
L3:
  mov    %rsp,-0x60(%rbp)
  mov    -0x48(%rbp),%eax
  test   %eax,%eax
  js     L48
  mov    -0x68(%rbp),%rsi
  shr    $0x2,%rsi
  lea    0x1(%rax),%ecx
  mov    $0x0,%eax
L116:
  movslq %eax,%rdx
  imul   %rsi,%rdx
  mov    -0x60(%rbp),%rdi
  mov    %eax,(%rdi,%rdx,4)
  add    $0x1,%eax
  cmp    %ecx,%eax
  jne    L116
L48:
  mov    -0x44(%rbp),%eax
  test   %eax,%eax
  js     L100
  lea    0x1(%rax),%edx
  mov    $0x0,%eax
L96:
  mov    -0x60(%rbp),%rcx
  mov    %eax,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L96
L100:
  cmpl   $0x0,-0x48(%rbp)
  jle    L121
  mov    -0x60(%rbp),%r13
  mov    %r13,%r15
  mov    %r13,%rax
  add    -0x68(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    %rbx,%r12
  mov    %rax,%r14
  mov    $0x1,%eax
  sub    %ebx,%eax
  mov    %eax,-0x6c(%rbp)
  jmp    L151
L30:
  mov    -0x4(%r13,%rbx,4),%edx
  mov    0x0(%r13,%rbx,4),%esi
  mov    -0x4(%r14,%rbx,4),%edi
  call   <min@plt>
  add    $0x1,%eax
  mov    %eax,(%r14,%rbx,4)
L82:
  add    $0x1,%rbx
  cmp    %ebx,-0x44(%rbp)
  jl     L77
L42:
  mov    -0x50(%rbp),%rax
  movzbl -0x1(%rax,%rbx,1),%eax
  cmp    %al,(%r12)
  jne    L30
  mov    -0x4(%r15,%rbx,4),%eax
  mov    -0x58(%rbp),%rcx
  mov    %eax,(%rcx,%rbx,4)
  jmp    L82
L77:
  mov    -0x68(%rbp),%rax
  add    %rax,%r15
  add    %rax,-0x58(%rbp)
  add    %rax,%r13
  add    %rax,%r14
  add    $0x1,%r12
  mov    -0x6c(%rbp),%eax
  add    %r12d,%eax
  cmp    %eax,-0x48(%rbp)
  jl     L121
L151:
  mov    $0x1,%ebx
  cmpl   $0x0,-0x44(%rbp)
  jg     L42
  jmp    L77
L121:
  movslq -0x44(%rbp),%rax
  movslq -0x48(%rbp),%rcx
  mov    -0x68(%rbp),%rdx
  shr    $0x2,%rdx
  imul   %rcx,%rdx
  add    %rdx,%rax
  mov    -0x60(%rbp),%rcx
  mov    (%rcx,%rax,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L81
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L81:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int editDistance(char a[], char b[]) {
  int aLength = strlen(a), bLength = strlen(b);
  int dp[aLength + 1][bLength + 1];
  int i, j;
  for (i = 0; i <= aLength; ++i) {
    dp[i][0] = i;
  }
  for (j = 0; j <= bLength; ++j) {
    dp[0][j] = j;
  }
  for (i = 1; i <= aLength; ++i) {
    for (j = 1; j <= bLength; ++j) {
      if (a[i - 1] == b[j - 1]) {
        dp[i][j] = dp[i - 1][j - 1];
      } else {
        dp[i][j] = 1 + min(dp[i][j - 1], dp[i - 1][j], dp[i - 1][j - 1]);
      }
    }
  }
  return dp[aLength][bLength];
}
```