user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<numDistinct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  lea    0x1(%rbx),%esi
  mov    %rsp,%rdi
  lea    0x1(%rax),%edx
  mov    %eax,-0x44(%rbp)
  movslq %edx,%rcx
  lea    0x0(,%rcx,4),%rax
  mov    %rax,-0x50(%rbp)
  movslq %esi,%rax
  imul   %rcx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L35
L137:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L137
L35:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L45
L79:
  imul   %esi,%edx
  mov    %rsp,%r14
  mov    %r14,%rdi
  lea    0x0(,%rdx,4),%esi
  call   <bzero@plt>
  mov    -0x50(%rbp),%r11
  shr    $0x2,%r11
  test   %ebx,%ebx
  js     L26
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L43:
  movslq %eax,%rdx
  imul   %r11,%rdx
  movl   $0x1,(%r14,%rdx,4)
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %edx,%ebx
  jne    L43
  test   %ebx,%ebx
  je     L26
  mov    -0x44(%rbp),%eax
  test   %eax,%eax
  jle    L26
  cmp    $0x2,%ebx
  jle    L71
  lea    0x0(,%r11,8),%rax
  mov    -0x44(%rbp),%edi
  xor    %ecx,%ecx
  mov    %ebx,-0x48(%rbp)
  mov    %rax,-0x60(%rbp)
  mov    -0x50(%rbp),%rax
  mov    $0x2,%esi
  mov    %rcx,%rbx
  lea    -0x1(%rdi),%r8d
  mov    %r14,-0x78(%rbp)
  mov    $0x1,%r15d
  lea    0x4(%r14,%rax,1),%rax
  mov    %r8d,-0x6c(%rbp)
  mov    %esi,%r14d
  mov    %rax,-0x58(%rbp)
  lea    0x1(%r12),%rax
  mov    %rax,-0x68(%rbp)
  add    %rax,%r8
L17:
  mov    %rbx,%rdi
  movzbl 0x0(%r13,%rbx,1),%r10d
  mov    -0x58(%rbp),%rax
  mov    %r12,%rdx
  sub    %r15,%rdi
  movzbl 0x0(%r13,%r15,1),%r9d
  imul   %r11,%rdi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rax,%rdi,4),%ecx
  movzbl (%rdx),%esi
  mov    %ecx,(%rax)
  cmp    %sil,%r10b
  jne    L89
  add    -0x4(%rax,%rdi,4),%ecx
  mov    %ecx,(%rax)
L89:
  mov    (%rax),%ecx
  mov    %ecx,(%rax,%r11,4)
  cmp    %r9b,%sil
  jne    L32
  add    -0x4(%rax),%ecx
  mov    %ecx,(%rax,%r11,4)
L32:
  add    $0x1,%rdx
  add    $0x4,%rax
  cmp    %r8,%rdx
  jne    L18
  mov    -0x60(%rbp),%rdi
  lea    0x1(%r14),%r9d
  add    %rdi,-0x58(%rbp)
  add    $0x2,%r14d
  add    $0x2,%r15
  add    $0x2,%rbx
  cmp    %r14d,-0x48(%rbp)
  jg     L17
  movslq -0x48(%rbp),%rbx
  mov    -0x78(%rbp),%r14
L117:
  movslq %r9d,%r9
  mov    %r11,%rax
  mov    %r14,-0x58(%rbp)
  mov    -0x6c(%rbp),%r8d
  lea    -0x1(%r9),%r10
  add    -0x68(%rbp),%r8
  imul   %r10,%rax
  lea    0x4(%r14,%rax,4),%r15
  mov    -0x50(%rbp),%r14
  nopl   0x0(%rax,%rax,1)
L36:
  mov    %r9,%rsi
  movzbl 0x0(%r13,%r10,1),%edi
  mov    %r12,%rdx
  mov    %r15,%rax
  sub    %r10,%rsi
  imul   %r11,%rsi
  cs nopw 0x0(%rax,%rax,1)
L130:
  mov    (%rax),%ecx
  mov    %ecx,(%rax,%rsi,4)
  cmp    (%rdx),%dil
  jne    L90
  add    -0x4(%rax),%ecx
  mov    %ecx,(%rax,%rsi,4)
L90:
  add    $0x1,%rdx
  add    $0x4,%rax
  cmp    %r8,%rdx
  jne    L130
  add    $0x1,%r9
  add    %r14,%r15
  add    $0x1,%r10
  cmp    %r9d,%ebx
  jge    L36
  mov    -0x58(%rbp),%r14
L26:
  imul   %r11,%rbx
  movslq -0x44(%rbp),%rax
  add    %rbx,%rax
  mov    (%r14,%rax,4),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L119
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L45:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L79
L71:
  lea    0x1(%r12),%rax
  mov    $0x1,%r9d
  mov    %rax,-0x68(%rbp)
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x6c(%rbp)
  jmp    L117
L119:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int numDistinct(char *s, char *t) {
  int l1 = strlen(s), l2 = strlen(t);
  int c[l1 + 1][l2 + 1];
  int i, j;
  bzero(c, sizeof(c));
  for (i = 0; i <= l1; i++)
    c[i][0] = 1;
  for (i = 1; i <= l1; i++) {
    for (j = 1; j <= l2; j++) {
      c[i][j] = c[i - 1][j];
      if (s[i - 1] == t[j - 1])
        c[i][j] += c[i - 1][j - 1];
    }
  }
  return (c[l1][l2]);
}
```