ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<gbcode_capitalize>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L16
  movzbl (%rbx),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L16
  sub    $0x20,%eax
  mov    %al,(%rbx)
L16:
  pop    %rbx
  ret
```

assistant: ```c
void gbcode_capitalize(char *pinyin) {
  if (strlen(pinyin) > 0) {
    if (pinyin[0] >= 'a' && pinyin[0] <= 'z') {
      pinyin[0] += 'A' - 'a';
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<gbcode_capitalize>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %rax,%rax
  je     L9
  movzbl (%rbx),%eax
  lea    -0x61(%rax),%edx
  cmp    $0x19,%dl
  ja     L9
  sub    $0x20,%eax
  mov    %al,(%rbx)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void gbcode_capitalize(char *pinyin) {
  if (strlen(pinyin) > 0) {
    if (pinyin[0] >= 'a' && pinyin[0] <= 'z') {
      pinyin[0] += 'A' - 'a';
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c50(%rbp),%rax
  mov    $0x9c44,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x2,-0x9c50(%rbp)
  movl   $0x3,-0x9c4c(%rbp)
  movl   $0x2,-0x9c5c(%rbp)
  jmp    L49
L40:
  mov    -0x9c5c(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  mov    %eax,-0x9c58(%rbp)
L64:
  movl   $0x0,-0x9c54(%rbp)
  jmp    L17
L66:
  mov    -0x9c54(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%ecx
  mov    -0x9c58(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  je     L28
  addl   $0x1,-0x9c54(%rbp)
L17:
  mov    -0x9c54(%rbp),%eax
  cmp    -0x9c5c(%rbp),%eax
  jl     L66
  jmp    L35
L28:
  nop
  nop
  addl   $0x1,-0x9c58(%rbp)
  jmp    L64
L35:
  mov    -0x9c5c(%rbp),%eax
  cltq
  mov    -0x9c58(%rbp),%edx
  mov    %edx,-0x9c50(%rbp,%rax,4)
  addl   $0x1,-0x9c5c(%rbp)
L49:
  cmpl   $0x2710,-0x9c5c(%rbp)
  jle    L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

assistant: ```c
int main() {
  int primes[10001] = {2, 3, 0};
  int i, j, k;
  for (i = 2; i < 10001; i++) {
    for (j = primes[i - 1];; j++) {
      for (k = 0; k < i; k++)
        if (j % primes[k] == 0)
          goto cont;
      break;
    cont:
      continue;
    }
    primes[i] = j;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  lea    -0x9000(%rsp),%r11
L9:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L9
  sub    $0xc50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x9c44,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  movl   $0x2,(%rsp)
  movl   $0x3,0x4(%rsp)
  lea    0x8(%rsp),%rdi
  mov    $0x2,%r8d
  jmp    L13
L20:
  add    $0x1,%esi
L3:
  test   %r8d,%r8d
  jle    L4
  mov    %rbx,%rcx
L39:
  mov    %esi,%eax
  cltd
  idivl  (%rcx)
  test   %edx,%edx
  je     L20
  add    $0x4,%rcx
  cmp    %rdi,%rcx
  jne    L39
L4:
  mov    %esi,(%r9)
  add    $0x1,%r8d
  add    $0x4,%rdi
  cmp    $0x2711,%r8d
  je     L57
L13:
  mov    %rdi,%r9
  mov    -0x4(%rdi),%esi
  jmp    L3
L57:
  mov    0x9c48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0x0,%eax
  add    $0x9c50,%rsp
  pop    %rbx
  ret
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int primes[10001] = {2, 3, 0};
  int i, j, k;
  for (i = 2; i < 10001; i++) {
    for (j = primes[i - 1];; j++) {
      for (k = 0; k < i; k++)
        if (j % primes[k] == 0)
          goto cont;
      break;
    cont:
      continue;
    }
    primes[i] = j;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int primes[10001] = {2, 3, 0};
  int i, j, k;
  for (i = 2; i < 10001; i++) {
    for (j = primes[i - 1];; j++) {
      for (k = 0; k < i; k++)
        if (j % primes[k] == 0)
          goto cont;
      break;
    cont:
      continue;
    }
    primes[i] = j;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int primes[10001] = {2, 3, 0};
  int i, j, k;
  for (i = 2; i < 10001; i++) {
    for (j = primes[i - 1];; j++) {
      for (k = 0; k < i; k++)
        if (j % primes[k] == 0)
          goto cont;
      break;
    cont:
      continue;
    }
    primes[i] = j;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hexDigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L23
  cmpb   $0x39,-0x4(%rbp)
  jg     L23
  movzbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L84
L23:
  cmpb   $0x40,-0x4(%rbp)
  jle    L31
  cmpb   $0x46,-0x4(%rbp)
  jg     L31
  movzbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L84
L31:
  cmpb   $0x60,-0x4(%rbp)
  jle    L46
  cmpb   $0x66,-0x4(%rbp)
  jg     L46
  movzbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L84
L46:
  mov    $0x0,%eax
L84:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t hexDigit(const char digit) {
  if (digit >= '0' && digit <= '9')
    return digit - '0';
  if (digit >= 'A' && digit <= 'F')
    return digit - 'A' + 0xA;
  if (digit >= 'a' && digit <= 'f')
    return digit - 'a' + 0xA;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hexDigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L8
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L19
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%al
  mov    $0x0,%eax
  cmovb  %edi,%eax
L8:
  ret
L19:
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
uint8_t hexDigit(const char digit) {
  if (digit >= '0' && digit <= '9')
    return digit - '0';
  if (digit >= 'A' && digit <= 'F')
    return digit - 'A' + 0xA;
  if (digit >= 'a' && digit <= 'f')
    return digit - 'a' + 0xA;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hexDigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L7
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L16
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%al
  mov    $0x0,%eax
  cmovb  %edi,%eax
L7:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
uint8_t hexDigit(const char digit) {
  if (digit >= '0' && digit <= '9')
    return digit - '0';
  if (digit >= 'A' && digit <= 'F')
    return digit - 'A' + 0xA;
  if (digit >= 'a' && digit <= 'f')
    return digit - 'a' + 0xA;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hexDigit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L2
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%al
  jbe    L18
  lea    -0x61(%rdi),%eax
  sub    $0x57,%edi
  cmp    $0x6,%al
  mov    $0x0,%eax
  cmovb  %edi,%eax
L2:
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
uint8_t hexDigit(const char digit) {
  if (digit >= '0' && digit <= '9')
    return digit - '0';
  if (digit >= 'A' && digit <= 'F')
    return digit - 'A' + 0xA;
  if (digit >= 'a' && digit <= 'f')
    return digit - 'a' + 0xA;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<UARTXON2XOFF2ValProgram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x8(%rbp)
  mov    %al,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x14,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  movzbl -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x1c,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  movzbl -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTXON2XOFF2ValProgram(unsigned int baseAdd, unsigned char xon2Value, unsigned char xoff2Value) {
  (*((volatile unsigned int *)(baseAdd + (0x14)))) = xon2Value;
  (*((volatile unsigned int *)(baseAdd + (0x1C)))) = xoff2Value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UARTXON2XOFF2ValProgram>:
  endbr64
  movzbl %sil,%esi
  mov    %esi,0x14(%edi)
  movzbl %dl,%edx
  mov    %edx,0x1c(%edi)
  ret
```

assistant: ```c
void UARTXON2XOFF2ValProgram(unsigned int baseAdd, unsigned char xon2Value, unsigned char xoff2Value) {
  (*((volatile unsigned int *)(baseAdd + (0x14)))) = xon2Value;
  (*((volatile unsigned int *)(baseAdd + (0x1C)))) = xoff2Value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<UARTXON2XOFF2ValProgram>:
  endbr64
  movzbl %sil,%esi
  movzbl %dl,%edx
  mov    %esi,0x14(%edi)
  mov    %edx,0x1c(%edi)
  ret
```

assistant: ```c
void UARTXON2XOFF2ValProgram(unsigned int baseAdd, unsigned char xon2Value, unsigned char xoff2Value) {
  (*((volatile unsigned int *)(baseAdd + (0x14)))) = xon2Value;
  (*((volatile unsigned int *)(baseAdd + (0x1C)))) = xoff2Value;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UARTXON2XOFF2ValProgram>:
  endbr64
  movzbl %sil,%esi
  movzbl %dl,%edx
  mov    %esi,0x14(%edi)
  mov    %edx,0x1c(%edi)
  ret
```

assistant: ```c
void UARTXON2XOFF2ValProgram(unsigned int baseAdd, unsigned char xon2Value, unsigned char xoff2Value) {
  (*((volatile unsigned int *)(baseAdd + (0x14)))) = xon2Value;
  (*((volatile unsigned int *)(baseAdd + (0x1C)))) = xoff2Value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cubic_io>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x18(%rbp),%xmm1
  movsd  D21(%rip),%xmm2
  divsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D46(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L4
  movss  -0x1c(%rbp),%xmm0
  movss  D49(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x3,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x20(%rbp),%xmm0
  jmp    L9
L4:
  movss  -0x1c(%rbp),%xmm0
  movss  D49(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  D49(%rip),%xmm1
  movaps %xmm0,%xmm5
  subss  %xmm1,%xmm5
  movd   %xmm5,%eax
  mov    $0x3,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  add    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  -0x20(%rbp),%xmm0
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D21
type_guessed: f64
name: unpack_data
arguments: label: D46
type_guessed: byte[4]
name: unpack_data
arguments: label: D49
type_guessed: byte[4]

tool: D21: 2

tool: {"D46": [0x00,0x00,0x80,0x3f]}

tool: {"D49": [0x00,0x00,0x00,0x40]}

assistant: ```c
float cubic_io(float step, float max_steps, float max_val) {
  float ratio = step / (max_steps / 2.0);
  if (ratio < 1)
    return max_val / 2 * pow(ratio, 3);
  return max_val / 2 * (pow(ratio - 2, 3) + 2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cubic_io>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm2,0xc(%rsp)
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  mulsd  D28(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  D15(%rip),%xmm1
  comiss %xmm0,%xmm1
  ja     L9
  subss  D8(%rip),%xmm0
  mov    $0x3,%edi
  call   <pow@plt>
  add    $0x2,%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  0xc(%rsp),%xmm1
  mulss  D46(%rip),%xmm1
  mulss  %xmm1,%xmm0
L14:
  add    $0x18,%rsp
  ret
L9:
  mov    $0x3,%edi
  call   <pow@plt>
  movss  0xc(%rsp),%xmm0
  mulss  D46(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  %xmm1,%xmm0
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D28
datatype: byte[8]
name: retrieve_data
arguments: tag: D15
datatype: byte[4]
name: retrieve_data
arguments: tag: D8
datatype: f32
name: retrieve_data
arguments: tag: D46
datatype: byte[4]

tool: {"D28": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D15": [0x00,0x00,0x80,0x3f]}

tool: D8: 2

tool: {"D46": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float cubic_io(float step, float max_steps, float max_val) {
  float ratio = step / (max_steps / 2.0);
  if (ratio < 1)
    return max_val / 2 * pow(ratio, 3);
  return max_val / 2 * (pow(ratio - 2, 3) + 2);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cubic_io>:
  endbr64
  sub    $0x18,%rsp
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  D25(%rip),%xmm1
  mulss  D31(%rip),%xmm2
  divsd  %xmm1,%xmm0
  movss  D37(%rip),%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm1
  ja     L8
  subss  D10(%rip),%xmm0
  mov    $0x3,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtsi2ss %eax,%xmm0
  mulss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x3,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D25
type: byte[8]
name: extract_symbolic_data
arguments: label: D31
type: byte[4]
name: extract_symbolic_data
arguments: label: D37
type: byte[4]
name: extract_symbolic_data
arguments: label: D10
type: f32

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D31": [0x00,0x00,0x00,0x3f]}

tool: {"D37": [0x00,0x00,0x80,0x3f]}

tool: D10: 2

assistant: ```c
float cubic_io(float step, float max_steps, float max_val) {
  float ratio = step / (max_steps / 2.0);
  if (ratio < 1)
    return max_val / 2 * pow(ratio, 3);
  return max_val / 2 * (pow(ratio - 2, 3) + 2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cubic_io>:
  endbr64
  sub    $0x18,%rsp
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  mulsd  D16(%rip),%xmm1
  mulss  D8(%rip),%xmm2
  divsd  %xmm1,%xmm0
  movss  D31(%rip),%xmm1
  movss  %xmm2,0xc(%rsp)
  cvtsd2ss %xmm0,%xmm0
  comiss %xmm0,%xmm1
  ja     L0
  subss  D11(%rip),%xmm0
  mov    $0x3,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtsi2ss %eax,%xmm0
  mulss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x3,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mulss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: byte[8]
name: retrieve_data
arguments: label: D8
data_type: byte[4]
name: retrieve_data
arguments: label: D31
data_type: byte[4]
name: retrieve_data
arguments: label: D11
data_type: f32

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0x3f]}

tool: {"D31": [0x00,0x00,0x80,0x3f]}

tool: D11: 2

assistant: ```c
float cubic_io(float step, float max_steps, float max_val) {
  float ratio = step / (max_steps / 2.0);
  if (ratio < 1)
    return max_val / 2 * pow(ratio, 3);
  return max_val / 2 * (pow(ratio - 2, 3) + 2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ba_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L16
L2:
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
L16:
  pop    %rbp
  ret
```

assistant: ```c
size_t ba_size(void *ptr) {
  if (ptr == NULL)
    return 0;
  return (size_t) * ((char *)ptr - sizeof(size_t));
}
```
user: What is the c source code of the assembly code below?

```asm
<ba_size>:
  endbr64
  test   %rdi,%rdi
  je     L0
  movsbq -0x8(%rdi),%rax
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t ba_size(void *ptr) {
  if (ptr == NULL)
    return 0;
  return (size_t) * ((char *)ptr - sizeof(size_t));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ba_size>:
  endbr64
  test   %rdi,%rdi
  je     L5
  movsbq -0x8(%rdi),%rax
  ret
  nop
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t ba_size(void *ptr) {
  if (ptr == NULL)
    return 0;
  return (size_t) * ((char *)ptr - sizeof(size_t));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ba_size>:
  endbr64
  test   %rdi,%rdi
  je     L5
  movsbq -0x8(%rdi),%rax
  ret
  nop
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t ba_size(void *ptr) {
  if (ptr == NULL)
    return 0;
  return (size_t) * ((char *)ptr - sizeof(size_t));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_17_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movl   $0xff,-0xc(%rbp)
  movzbl -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x14(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_17_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_17_0_0>:
  endbr64
  movzbl %dil,%eax
  shl    $0x8,%eax
  or     $0xff,%al
  not    %eax
  ret
```

assistant: ```c
unsigned xrop3_17_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_17_0_0>:
  endbr64
  movzbl %dil,%eax
  shl    $0x8,%eax
  or     $0xff,%al
  not    %eax
  ret
```

assistant: ```c
unsigned xrop3_17_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned stk1;
  stk1 = D | S;
  stk1 = ~stk1;
  return stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_less>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <gen_len@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <gen_not@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct block *gen_less(n)
int n;
{
  struct block *b;
  b = gen_len(0x20, n);
  gen_not(b);
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gen_less>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    $0x20,%edi
  mov    $0x0,%eax
  call   <gen_len@plt>
  movslq %eax,%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <gen_not@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
struct block *gen_less(n)
int n;
{
  struct block *b;
  b = gen_len(0x20, n);
  gen_not(b);
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_less>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  mov    $0x20,%edi
  call   <gen_len@plt>
  movslq %eax,%r12
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <gen_not@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct block *gen_less(n)
int n;
{
  struct block *b;
  b = gen_len(0x20, n);
  gen_not(b);
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gen_less>:
  endbr64
  push   %r12
  mov    %edi,%esi
  xor    %eax,%eax
  mov    $0x20,%edi
  call   <gen_len@plt>
  movslq %eax,%r12
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <gen_not@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct block *gen_less(n)
int n;
{
  struct block *b;
  b = gen_len(0x20, n);
  gen_not(b);
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L9:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t len(char *string) {
  char *end = string;
  for (; *end; ++end) {
  }
  return (size_t)(end - string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
  mov    %rdi,%rax
L2:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
L17:
  sub    %rdi,%rax
  ret
L7:
  mov    %rdi,%rax
  jmp    L17
```

assistant: ```c
size_t len(char *string) {
  char *end = string;
  for (; *end; ++end) {
  }
  return (size_t)(end - string);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    %rdi,%rax
  nopl   0x0(%rax)
L0:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L0
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t len(char *string) {
  char *end = string;
  for (; *end; ++end) {
  }
  return (size_t)(end - string);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  mov    %rdi,%rax
  nopl   0x0(%rax)
L2:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
  sub    %rdi,%rax
  ret
  nopl   (%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t len(char *string) {
  char *end = string;
  for (; *end; ++end) {
  }
  return (size_t)(end - string);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trim_mark_cols>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L6:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L41
L28:
  addl   $0x1,-0x4(%rbp)
L41:
  addl   $0x1,-0xc(%rbp)
L27:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L6
  mov    -0x18(%rbp),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <blank_y@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int trim_mark_cols(char ***piece, int x, int y, char c) {
  int i;
  int j;
  int blank_cols;
  int num_blanks;
  i = 0;
  j = 0;
  num_blanks = 0;
  blank_cols = 0;
  while (i < x) {
    while (j < y) {
      if ((*piece)[j][i] == c || (*piece)[j][i] == ' ')
        num_blanks++;
      j++;
    }
    blank_cols += blank_y(i, y, num_blanks, piece);
    num_blanks = 0;
    j = 0;
    i++;
  }
  return (blank_cols);
}
```