ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  lea    -0x50(%rbp),%rax
  movl   $0xfa1e0ff3,-0x4c(%rbp)
  movw   $0xbb49,-0x48(%rbp)
  lea    -0x52(%rip),%rcx        # 1179 <nested.0>
  mov    %rcx,-0x46(%rbp)
  movw   $0xba49,-0x3e(%rbp)
  mov    %rax,-0x3c(%rbp)
  movl   $0x90e3ff49,-0x34(%rbp)
  mov    %edi,-0x50(%rbp)
  movslq %edi,%rdx
  add    $0x7,%rdx
  and    $0xfffffffffffffffc,%rdx
  lea    0xf(%rdx),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L11:
  cmp    %rcx,%rsp
  je     L24
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L11
L24:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L21
  orq    $0x0,-0x8(%rsp,%rax,1)
L21:
  lea    0x3(%rsp),%r12
  mov    %r12,%r13
  shr    $0x2,%r13
  and    $0xfffffffffffffffc,%r12
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  movl   $0x7b,0x0(,%r13,4)
  lea    -0x4c(%rbp),%rdi
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string

tool: D0: %d


assistant: ```c
int main(int argc, char **argv) {
  struct s {
    int a;
    char b[argc];
  };
  int nested(struct s x) { return x.a + sizeof(x); }
  struct s t;
  memset(&t, 0, sizeof(t));
  t.a = 123;
  printf("%d\n", bar(nested, argc, &t));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  movslq %edi,%rdx
  mov    $0xffffbb49,%ecx
  mov    $0xffffba49,%esi
  mov    %rsp,%rbp
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  lea    D9(%rip),%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %edx,-0x40(%rbp)
  add    $0x7,%rdx
  mov    %rax,-0x20(%rbp)
  and    $0xfffffffffffffffc,%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x2c(%rbp)
  lea    0xf(%rdx),%rax
  mov    %cx,-0x38(%rbp)
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %si,-0x2e(%rbp)
  mov    %rsp,%rsi
  and    $0xfffffffffffffff0,%rcx
  sub    %rax,%rsi
  movl   $0xfa1e0ff3,-0x3c(%rbp)
  mov    %rbx,-0x36(%rbp)
  movl   $0x90e3ff49,-0x24(%rbp)
  cmp    %rsi,%rsp
  je     L36
L24:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L24
L36:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L1
L49:
  lea    0x3(%rsp),%r8
  xor    %esi,%esi
  mov    %r8,%rbx
  and    $0xfffffffffffffffc,%r8
  mov    %r8,%rdi
  shr    $0x2,%rbx
  call   <memset@plt>
  lea    -0x3c(%rbp),%rdi
  mov    %r12d,%esi
  movl   $0x7b,0x0(,%rbx,4)
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <bar@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  lea    -0x10(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L1:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L49
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: 

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  struct s {
    int a;
    char b[argc];
  };
  int nested(struct s x) { return x.a + sizeof(x); }
  struct s t;
  memset(&t, 0, sizeof(t));
  t.a = 123;
  printf("%d\n", bar(nested, argc, &t));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  movslq %edi,%rdx
  mov    $0xffffbb49,%ecx
  mov    $0xffffba49,%esi
  mov    %rsp,%rbp
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  lea    D17(%rip),%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x10(%rbp),%rax
  mov    %edx,-0x40(%rbp)
  add    $0x7,%rdx
  mov    %rax,-0x20(%rbp)
  and    $0xfffffffffffffffc,%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x2c(%rbp)
  lea    0xf(%rdx),%rax
  mov    %cx,-0x38(%rbp)
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %si,-0x2e(%rbp)
  mov    %rsp,%rsi
  and    $0xfffffffffffffff0,%rcx
  sub    %rax,%rsi
  movl   $0xfa1e0ff3,-0x3c(%rbp)
  mov    %rbx,-0x36(%rbp)
  movl   $0x90e3ff49,-0x24(%rbp)
  cmp    %rsi,%rsp
  je     L31
L10:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L10
L31:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L17
L38:
  lea    0x3(%rsp),%r8
  xor    %esi,%esi
  mov    %r8,%rbx
  and    $0xfffffffffffffffc,%r8
  mov    %r8,%rdi
  shr    $0x2,%rbx
  call   <memset@plt>
  lea    -0x3c(%rbp),%rdi
  mov    %r12d,%esi
  movl   $0x7b,0x0(,%rbx,4)
  mov    %rax,%rdx
  xor    %eax,%eax
  call   <bar@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  lea    -0x10(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L17:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L38
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string

tool: 

tool: D8: %d


assistant: ```c
int main(int argc, char **argv) {
  struct s {
    int a;
    char b[argc];
  };
  int nested(struct s x) { return x.a + sizeof(x); }
  struct s t;
  memset(&t, 0, sizeof(t));
  t.a = 123;
  printf("%d\n", bar(nested, argc, &t));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ksft_print_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  test   %eax,%eax
  jne    L2
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D6
type_infered: string

tool: D10: KSFT_TAP_LEVEL

tool: D6: TAP version 13


assistant: ```c
void ksft_print_header(void) {
  if (!(getenv("KSFT_TAP_LEVEL")))
    printf("TAP version 13\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ksft_print_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <getenv@plt>
  test   %eax,%eax
  je     L5
L3:
  add    $0x8,%rsp
  ret
L5:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
datatype: string
name: extract_symbolic_data
arguments: data_tag: D13
datatype: string

tool: D18: KSFT_TAP_LEVEL

tool: D13: TAP version 13


assistant: ```c
void ksft_print_header(void) {
  if (!(getenv("KSFT_TAP_LEVEL")))
    printf("TAP version 13\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ksft_print_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <getenv@plt>
  test   %eax,%eax
  je     L3
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L3:
  lea    D4(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D5: KSFT_TAP_LEVEL

tool: D4: TAP version 13


assistant: ```c
void ksft_print_header(void) {
  if (!(getenv("KSFT_TAP_LEVEL")))
    printf("TAP version 13\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ksft_print_header>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <getenv@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L1:
  lea    D15(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D13: KSFT_TAP_LEVEL

tool: D15: TAP version 13


assistant: ```c
void ksft_print_header(void) {
  if (!(getenv("KSFT_TAP_LEVEL")))
    printf("TAP version 13\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L42
L8:
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rdi
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  mov    %rdi,%rdx
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L35
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xffffffff,%eax
  jmp    L42
L35:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L10
  mov    -0x4(%rbp),%eax
L42:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: send

assistant: ```c
int send_loop(int t, const char *c, size_t len, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<send_loop>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L12
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%r14d
  mov    $0x0,%ebx
L19:
  movslq %ebx,%rsi
  cmp    %rbp,%rsi
  jae    L7
  mov    %rbp,%rdx
  sub    %rsi,%rdx
  add    %r12,%rsi
  mov    %r14d,%ecx
  mov    %r13d,%edi
  call   <send@plt>
  add    %ebx,%eax
  mov    %eax,%ebx
  jns    L19
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0xffffffff,%ebx
L7:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    $0xffffffff,%ebx
  jmp    L7
```

tool_calls: name: retrieve_data
arguments: label: D3
type_infered: string

tool: D3: send

assistant: ```c
int send_loop(int t, const char *c, size_t len, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_loop>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L30
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  xor    %r14d,%r14d
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbx,%rdx
  mov    %r13d,%ecx
  mov    %r12d,%edi
  sub    %rsi,%rdx
  add    %rbp,%rsi
  call   <send@plt>
  add    %eax,%r14d
  js     L37
L18:
  movslq %r14d,%rsi
  cmp    %rbx,%rsi
  jb     L15
L38:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L37:
  mov    $0xffffffff,%r14d
  lea    D9(%rip),%rdi
  call   <perror@plt>
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L30:
  mov    $0xffffffff,%r14d
  jmp    L38
```

tool_calls: name: read_data
arguments: label: D9
type_guessed: string

tool: D9: send

assistant: ```c
int send_loop(int t, const char *c, size_t len, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_loop>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L38
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  xor    %r14d,%r14d
  jmp    L14
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %rbx,%rdx
  mov    %r13d,%ecx
  mov    %r12d,%edi
  sub    %rsi,%rdx
  add    %rbp,%rsi
  call   <send@plt>
  add    %eax,%r14d
  js     L17
L14:
  movslq %r14d,%rsi
  cmp    %rbx,%rsi
  jb     L40
L25:
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L17:
  mov    $0xffffffff,%r14d
  lea    D0(%rip),%rdi
  call   <perror@plt>
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  mov    $0xffffffff,%r14d
  jmp    L25
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: send

assistant: ```c
int send_loop(int t, const char *c, size_t len, int flags) {
  if (c == NULL)
    return -1;
  int bytes_sent = 0;
  while (bytes_sent < len)
    if ((bytes_sent += send(t, c + bytes_sent, len - bytes_sent, flags)) < 0) {
      perror("send");
      return -1;
    }
  return bytes_sent;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  call   <check_offloading@plt>
  mov    $0x0,%eax
L33:
  movl   $0xffffffff,(%rsp,%rax,1)
  movl   $0xffffffff,0x190(%rsp,%rax,1)
  add    $0x4,%rax
  cmp    $0x190,%rax
  jne    L33
  mov    %rsp,%rax
  lea    0x190(%rsp),%rsi
  mov    $0x0,%edx
L44:
  mov    %edx,(%rax)
  lea    0x1(%rdx),%ecx
  mov    %ecx,0x4(%rax)
  lea    0x2(%rdx),%ecx
  mov    %ecx,0x8(%rax)
  lea    0x3(%rdx),%ecx
  mov    %ecx,0xc(%rax)
  add    $0x4,%edx
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L44
  mov    $0x0,%eax
L30:
  mov    %eax,0x190(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L30
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D26(%rip),%r12
  jmp    L82
L77:
  cmp    $0xa,%ebp
  jg     L65
  add    $0x1,%rbx
  cmp    $0x64,%rbx
  je     L45
L82:
  mov    %ebx,%esi
  mov    (%rsp,%rbx,4),%edx
  mov    0x190(%rsp,%rbx,4),%ecx
  cmp    %ecx,%edx
  je     L77
  add    $0x1,%ebp
  mov    %ebp,%r8d
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L77
L65:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
L22:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebp,%eax
  add    $0x330,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type_guessed: string
name: unpack_data
arguments: data_tag: D28
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D26: %d: a %d != %d (error %d)


tool: D28: abort

tool: D5: done with %d errors


assistant: ```c
int main() {
  check_offloading();
  int a[100], aa[100];
  int i, error = 0;
  for (i = 0; i < 100; i++)
    aa[i] = a[i] = -1;
#pragma omp target map(tofrom : a [0:100])
  {
    int k, l;
#pragma omp simd collapse(2)
    for (k = 0; k < 100 / 4; k++)
      for (l = 0; l < 4; l++)
        a[k * 4 + l] = k * 4 + l;
  }
  for (i = 0; i < 100; i++)
    aa[i] = i;
  for (i = 0; i < 100; i++) {
    if (a[i] != aa[i])
      printf("%d: a %d != %d (error %d)\n", i, a[i], aa[i], ++error);
    if (error > 10) {
      printf("abort\n");
      return 0;
    }
  }
  printf("done with %d errors\n", error);
  return error;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x330,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x328(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x190(%rsp),%rbx
  call   <check_offloading@plt>
  mov    $0x32,%ecx
  mov    %r12,%rdi
  xor    %edx,%edx
  mov    $0xffffffffffffffff,%rax
  rep stos %rax,%es:(%rdi)
  mov    $0x32,%ecx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L46:
  lea    0x1(%rdx),%ecx
  mov    %edx,(%rax)
  add    $0x10,%rax
  mov    %ecx,-0xc(%rax)
  lea    0x2(%rdx),%ecx
  mov    %ecx,-0x8(%rax)
  lea    0x3(%rdx),%ecx
  add    $0x4,%edx
  mov    %ecx,-0x4(%rax)
  cmp    %rbx,%rax
  jne    L46
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L50:
  mov    %eax,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L50
  xor    %ebp,%ebp
  xor    %r13d,%r13d
  lea    D23(%rip),%r14
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%rbp
  cmp    $0x64,%rbp
  je     L77
L36:
  mov    (%r12,%rbp,4),%edx
  mov    (%rbx,%rbp,4),%ecx
  mov    %ebp,%esi
  cmp    %ecx,%edx
  je     L68
  add    $0x1,%r13d
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %r13d,%r8d
  call   <printf@plt>
L68:
  cmp    $0xb,%r13d
  jne    L54
  lea    D8(%rip),%rdi
  xor    %r13d,%r13d
  call   <puts@plt>
L59:
  mov    0x328(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x330,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L59
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D23: %d: a %d != %d (error %d)


tool: D8: abort

tool: D1: done with %d errors


assistant: ```c
int main() {
  check_offloading();
  int a[100], aa[100];
  int i, error = 0;
  for (i = 0; i < 100; i++)
    aa[i] = a[i] = -1;
#pragma omp target map(tofrom : a [0:100])
  {
    int k, l;
#pragma omp simd collapse(2)
    for (k = 0; k < 100 / 4; k++)
      for (l = 0; l < 4; l++)
        a[k * 4 + l] = k * 4 + l;
  }
  for (i = 0; i < 100; i++)
    aa[i] = i;
  for (i = 0; i < 100; i++) {
    if (a[i] != aa[i])
      printf("%d: a %d != %d (error %d)\n", i, a[i], aa[i], ++error);
    if (error > 10) {
      printf("abort\n");
      return 0;
    }
  }
  printf("done with %d errors\n", error);
  return error;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    $0x136ff696,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L33
L34:
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L3:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,%edx
  je     L57
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L44
L57:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp,%rax,4),%eax
  imul   %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,-0xc(%rbp,%rax,4)
L44:
  addl   $0x1,-0x14(%rbp)
L1:
  cmpl   $0x0,-0x14(%rbp)
  je     L3
  addl   $0x2,-0x10(%rbp)
L33:
  cmpl   $0x0,-0x10(%rbp)
  je     L34
  mov    -0xc(%rbp),%eax
  imul   $0xbf382a0,%eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  lea    (%rax,%rax,1),%edx
  cmovne %edx,%eax
  imul   $0xbf382a0,%eax,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  imul   $0x17e70540,%eax,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x136ff696,%eax
  imul   $0x17e70540,%eax,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local2;
  unsigned int local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        if (state[0UL] != local2 - local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          state[local1] = state[0UL] * state[local1];
        }
        local2++;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 200508064U;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<can_relocate_jump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
```

assistant: ```c
void can_relocate_jump(void) {
  int ok = 0;
  asm("    .global "
      "set_point1"
      "\n"
      "set_point1"
      ":\n"
      ".byte 0xe9\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      "  mov $1, %[ok]\n"
      : [ok] "=r"(ok));
  if (ok == 1)
    pass();
  else
    fail();
}
```
user: Translate the below assembly code into C programming language:

```asm
<can_relocate_jump>:
  endbr64
  sub    $0x8,%rsp
```

assistant: ```c
void can_relocate_jump(void) {
  int ok = 0;
  asm("    .global "
      "set_point1"
      "\n"
      "set_point1"
      ":\n"
      ".byte 0xe9\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      "  mov $1, %[ok]\n"
      : [ok] "=r"(ok));
  if (ok == 1)
    pass();
  else
    fail();
}
```
user: What is the c source code of the assembly code below:

```asm
<can_relocate_jump>:
  endbr64
```

assistant: ```c
void can_relocate_jump(void) {
  int ok = 0;
  asm("    .global "
      "set_point1"
      "\n"
      "set_point1"
      ":\n"
      ".byte 0xe9\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      ".byte 0x00\n"
      "  mov $1, %[ok]\n"
      : [ok] "=r"(ok));
  if (ok == 1)
    pass();
  else
    fail();
}
```