ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LDA_izx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <c64_memIndirectZeroX@plt>
  mov    $0x0,%eax
  call   <LDA_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LDA_izx(void) {
  c64_memIndirectZeroX();
  LDA_();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LDA_izx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <c64_memIndirectZeroX@plt>
  mov    $0x0,%eax
  call   <LDA_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LDA_izx(void) {
  c64_memIndirectZeroX();
  LDA_();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LDA_izx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memIndirectZeroX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <LDA_@plt>
```

assistant: ```c
void LDA_izx(void) {
  c64_memIndirectZeroX();
  LDA_();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LDA_izx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memIndirectZeroX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <LDA_@plt>
```

assistant: ```c
void LDA_izx(void) {
  c64_memIndirectZeroX();
  LDA_();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D81(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D106(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D81
datatype: string
name: read_data
arguments: label: D61
datatype: string
name: read_data
arguments: label: D70
datatype: string
name: read_data
arguments: label: D53
datatype: string
name: read_data
arguments: label: D34
datatype: string
name: read_data
arguments: label: D33
datatype: string
name: read_data
arguments: label: D12
datatype: string
name: read_data
arguments: label: D106
datatype: string
name: read_data
arguments: label: D74
datatype: string
name: read_data
arguments: label: D5
datatype: string
name: read_data
arguments: label: D21
datatype: string
name: read_data
arguments: label: D41
datatype: string

tool: D81: %d

tool: D61: %dd**


tool: D70: %i

tool: D53: %di**


tool: D34: %o

tool: D33: %do**


tool: D12: %u

tool: D106: %du**


tool: D74: %x

tool: D5: %dx**


tool: D21: %X

tool: D41: %dX**


assistant: ```c
void main(void) {
  int a;
  scanf("%d", &a);
  printf("%dd**\n", a);
  scanf("%i", &a);
  printf("%di**\n", a);
  scanf("%o", &a);
  printf("%do**\n", a);
  scanf("%u", &a);
  printf("%du**\n", a);
  scanf("%x", &a);
  printf("%dx**\n", a);
  scanf("%X", &a);
  printf("%dX**\n", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D109(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D71(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D61(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D86(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D112(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D66(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D25
type_infered: string
name: read_data
arguments: label: D109
type_infered: string
name: read_data
arguments: label: D71
type_infered: string
name: read_data
arguments: label: D64
type_infered: string
name: read_data
arguments: label: D61
type_infered: string
name: read_data
arguments: label: D86
type_infered: string
name: read_data
arguments: label: D112
type_infered: string
name: read_data
arguments: label: D59
type_infered: string
name: read_data
arguments: label: D66
type_infered: string
name: read_data
arguments: label: D74
type_infered: string
name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D0
type_infered: string

tool: D25: %d

tool: D109: %dd**


tool: D71: %i

tool: D64: %di**


tool: D61: %o

tool: D86: %do**


tool: D112: %u

tool: D59: %du**


tool: D66: %x

tool: D74: %dx**


tool: D16: %X

tool: D0: %dX**


assistant: ```c
void main(void) {
  int a;
  scanf("%d", &a);
  printf("%dd**\n", a);
  scanf("%i", &a);
  printf("%di**\n", a);
  scanf("%o", &a);
  printf("%do**\n", a);
  scanf("%u", &a);
  printf("%du**\n", a);
  scanf("%x", &a);
  printf("%dx**\n", a);
  scanf("%X", &a);
  printf("%dX**\n", a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D118(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D96(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D111(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D115(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D80(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D97(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D92(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D75(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D118
type_guessed: string
name: disassemble_data
arguments: tag: D45
type_guessed: string
name: disassemble_data
arguments: tag: D43
type_guessed: string
name: disassemble_data
arguments: tag: D96
type_guessed: string
name: disassemble_data
arguments: tag: D111
type_guessed: string
name: disassemble_data
arguments: tag: D20
type_guessed: string
name: disassemble_data
arguments: tag: D24
type_guessed: string
name: disassemble_data
arguments: tag: D115
type_guessed: string
name: disassemble_data
arguments: tag: D80
type_guessed: string
name: disassemble_data
arguments: tag: D97
type_guessed: string
name: disassemble_data
arguments: tag: D92
type_guessed: string
name: disassemble_data
arguments: tag: D75
type_guessed: string

tool: D118: %d

tool: D45: %dd**


tool: D43: %i

tool: D96: %di**


tool: D111: %o

tool: D20: %do**


tool: D24: %u

tool: D115: %du**


tool: D80: %x

tool: D97: %dx**


tool: D92: %X

tool: D75: %dX**


assistant: ```c
void main(void) {
  int a;
  scanf("%d", &a);
  printf("%dd**\n", a);
  scanf("%i", &a);
  printf("%di**\n", a);
  scanf("%o", &a);
  printf("%do**\n", a);
  scanf("%u", &a);
  printf("%du**\n", a);
  scanf("%x", &a);
  printf("%dx**\n", a);
  scanf("%X", &a);
  printf("%dX**\n", a);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D82(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D112(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D88(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D58(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D87(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D82
datatype: string
name: parse_data
arguments: data_tag: D112
datatype: string
name: parse_data
arguments: data_tag: D65
datatype: string
name: parse_data
arguments: data_tag: D88
datatype: string
name: parse_data
arguments: data_tag: D28
datatype: string
name: parse_data
arguments: data_tag: D54
datatype: string
name: parse_data
arguments: data_tag: D58
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D87
datatype: string
name: parse_data
arguments: data_tag: D36
datatype: string
name: parse_data
arguments: data_tag: D1
datatype: string

tool: D82: %d

tool: D112: %dd**


tool: D65: %i

tool: D88: %di**


tool: D28: %o

tool: D54: %do**


tool: D58: %u

tool: D24: %du**


tool: D9: %x

tool: D87: %dx**


tool: D36: %X

tool: D1: %dX**


assistant: ```c
void main(void) {
  int a;
  scanf("%d", &a);
  printf("%dd**\n", a);
  scanf("%i", &a);
  printf("%di**\n", a);
  scanf("%o", &a);
  printf("%do**\n", a);
  scanf("%u", &a);
  printf("%du**\n", a);
  scanf("%x", &a);
  printf("%dx**\n", a);
  scanf("%X", &a);
  printf("%dX**\n", a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  xor    $0x29be1cdb,%rax
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L33
  mov    $0x0,%edx
  jmp    L8
L43:
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  jae    L33
L8:
  cmp    %rdx,%rax
  je     L43
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  jmp    L43
L33:
  and    $0x1603b040,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        state[local1] = state[0UL] << (((state[0UL] >> 2UL) & 7UL) | 1UL);
        state[0UL] = state[local1] >> (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy12 = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = copy12;
        copy12 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  xor    $0x29be1cdb,%rax
  test   %rdi,%rdi
  je     L24
  xor    %edx,%edx
L3:
  cmp    %rax,%rdx
  je     L1
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
L1:
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  jb     L3
L24:
  and    $0x1603b040,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        state[local1] = state[0UL] << (((state[0UL] >> 2UL) & 7UL) | 1UL);
        state[0UL] = state[local1] >> (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy12 = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = copy12;
        copy12 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    0x8(%rdi),%rdi
  mov    %rdx,%rax
  xor    $0x29be1cdb,%rax
  test   %rdi,%rdi
  je     L33
  cmp    $0x29be1cdb,%rdx
  je     L7
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  cmp    $0x2,%rdi
  jbe    L33
  cmp    $0x2,%rax
  je     L19
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  cmp    $0x2,%rdi
  jbe    L33
L15:
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
L19:
  cmp    $0x4,%rdi
  jbe    L33
  mov    $0x4,%edx
L51:
  cmp    %rdx,%rax
  je     L32
  mov    %rax,%rcx
  add    $0x2,%rdx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shr    %cl,%rax
  cmp    %rdi,%rdx
  jb     L51
L33:
  and    $0x1603b040,%eax
  mov    %rax,(%rsi)
  ret
L32:
  lea    0x2(%rax),%rdx
  cmp    %rdx,%rdi
  ja     L51
  jmp    L33
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy12;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] != local1) {
        state[local1] = state[0UL] << (((state[0UL] >> 2UL) & 7UL) | 1UL);
        state[0UL] = state[local1] >> (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy12 = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = copy12;
        copy12 = *((unsigned int *)(&state[local1]) + 1);
        *((unsigned int *)(&state[local1]) + 1) = *((unsigned int *)(&state[local1]) + 0);
        *((unsigned int *)(&state[local1]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] & 387166272UL) & 913307615UL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<precedence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x2f,%eax
  jg     L17
  cmp    $0x23,%eax
  jl     L60
  sub    $0x23,%eax
  cmp    $0xc,%eax
  ja     L60
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D15(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D15(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L17:
  cmp    $0x5e,%eax
  je     L40
  jmp    L60
  mov    $0x1,%eax
  jmp    L60
  mov    $0x2,%eax
  jmp    L60
L40:
  mov    $0x3,%eax
  jmp    L60
  mov    $0x0,%eax
  jmp    L60
L60:
  pop    %rbp
  ret
```

assistant: ```c
char precedence(char elem) {
  switch (elem) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  case ')':
  case '#':
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<precedence>:
  endbr64
  cmp    $0x2f,%dil
  jg     L20
  cmp    $0x22,%dil
  jle    L2
  sub    $0x23,%edi
  cmp    $0xc,%dil
  ja     L2
  movzbl %dil,%edi
  lea    D2(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2,%eax
  ret
L20:
  mov    $0x3,%eax
  cmp    $0x5e,%dil
  jne    L2
L49:
  ret
L2:
  ret
  mov    $0x1,%eax
  ret
  mov    $0x0,%eax
  jmp    L49
```

assistant: ```c
char precedence(char elem) {
  switch (elem) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  case ')':
  case '#':
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<precedence>:
  endbr64
  cmp    $0x2f,%dil
  jg     L23
  cmp    $0x22,%dil
  jle    L24
  sub    $0x23,%edi
  cmp    $0xc,%dil
  ja     L24
  lea    D3(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
L23:
  mov    $0x3,%eax
  cmp    $0x5e,%dil
  jne    L24
  ret
  nopl   0x0(%rax)
L24:
  ret
  nopl   0x0(%rax)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0x2,%eax
  ret
```

assistant: ```c
char precedence(char elem) {
  switch (elem) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  case ')':
  case '#':
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<precedence>:
  endbr64
  cmp    $0x2f,%dil
  jg     L2
  cmp    $0x22,%dil
  jle    L1
  sub    $0x23,%edi
  cmp    $0xc,%dil
  ja     L1
  lea    D7(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
L2:
  mov    $0x3,%eax
  cmp    $0x5e,%dil
  jne    L1
  ret
  nopl   0x0(%rax)
L1:
  ret
  nopl   0x0(%rax)
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  mov    $0x2,%eax
  ret
```

assistant: ```c
char precedence(char elem) {
  switch (elem) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  case ')':
  case '#':
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getline_my>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movb   $0x0,-0x5(%rbp)
  jmp    L24
L22:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x5(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L24:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    D5(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  je     L5
  cmpb   $0xa,-0x5(%rbp)
  jne    L22
L5:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getline_my(char *line) {
  int i = 0;
  char c = 0;
  while ((c = getchar()) != EOF && c != '\n') {
    *line++ = c;
    i++;
  };
  *line = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getline_my>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L27:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D6(%rip),%rdx
  cmp    %al,(%rdx)
  je     L24
  cmp    $0xa,%al
  je     L24
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  add    $0x1,%ebp
  jmp    L27
L24:
  movb   $0x0,(%rbx)
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int getline_my(char *line) {
  int i = 0;
  char c = 0;
  while ((c = getchar()) != EOF && c != '\n') {
    *line++ = c;
    i++;
  };
  *line = '\0';
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getline_my>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L21:
  cmp    $0xa,%al
  je     L20
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%r12d
L26:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,0x0(%rbp)
  jne    L21
L20:
  mov    %r12d,%eax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getline_my(char *line) {
  int i = 0;
  char c = 0;
  while ((c = getchar()) != EOF && c != '\n') {
    *line++ = c;
    i++;
  };
  *line = '\0';
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getline_my>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    D8(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L19:
  cmp    $0xa,%al
  je     L14
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%r12d
L21:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,0x0(%rbp)
  jne    L19
L14:
  mov    %r12d,%eax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getline_my(char *line) {
  int i = 0;
  char c = 0;
  while ((c = getchar()) != EOF && c != '\n') {
    *line++ = c;
    i++;
  };
  *line = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_argb8888_get_alpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0xff0011bb,%eax
  mov    %rax,-0x40(%rbp)
  movq   $0xff,-0x38(%rbp)
  movq   $0x12345678,-0x30(%rbp)
  movq   $0x12,-0x28(%rbp)
  movl   $0x0,-0x44(%rbp)
  jmp    L6
L3:
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  sub    $0x28,%rax
  mov    (%rax),%rbx
  mov    -0x44(%rbp),%eax
  cltq
  shl    $0x4,%rax
  lea    -0x10(%rax),%rax
  add    %rbp,%rax
  sub    $0x30,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <argb8888_get_alpha@plt>
  cmp    %rax,%rbx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x44(%rbp)
L6:
  mov    -0x44(%rbp),%eax
  cmp    $0x1,%eax
  jbe    L3
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void test_argb8888_get_alpha() {
  uint32_t cases[][2] = {{0xff0011bb, 0xff}, {0x12345678, 0x12}};
  int i;
  for (i = 0; i < sizeof(cases) / sizeof(cases[0]); ++i) {
    assert(cases[i][1] == argb8888_get_alpha(cases[i][0]));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_argb8888_get_alpha>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff0011bb,%edi
  call   <argb8888_get_alpha@plt>
  cmp    $0xff,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x12345678,%edi
  call   <argb8888_get_alpha@plt>
  cmp    $0x12,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test_argb8888_get_alpha() {
  uint32_t cases[][2] = {{0xff0011bb, 0xff}, {0x12345678, 0x12}};
  int i;
  for (i = 0; i < sizeof(cases) / sizeof(cases[0]); ++i) {
    assert(cases[i][1] == argb8888_get_alpha(cases[i][0]));
  }
}
```