ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decodeURI>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  test   %rdi,%rdi
  je     L64
  mov    %rdx,%rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  movslq %eax,%rdx
  test   %r12,%r12
  je     L31
  cmp    %rbx,%rdx
  jae    L64
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L2:
  mov    %r12,%r14
  lea    0x5(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L53:
  mov    $0x25,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L46
  movzbl 0x1(%rbp),%eax
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  lea    0x1(%rbp),%r14
  mov    %al,0x5(%rsp)
  movzbl 0x2(%rbp),%eax
  mov    %al,0x6(%rsp)
  call   <strtol@plt>
  test   %eax,%eax
  je     L53
  mov    %al,0x0(%rbp)
  add    $0x3,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  jmp    L53
  nopl   0x0(%rax,%rax,1)
L64:
  xor    %r12d,%r12d
L46:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %rbp,%r12
  jmp    L2
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *decodeURI(char *pcSrc, char *pcDst, size_t iDstLen) {
  char *pcDecode = pcSrc, *pNext;
  char hex[3] = {'\0', '\0', '\0'};
  int lValue;
  size_t iSrcLen;
  if (pcSrc) {
    iSrcLen = strlen(pcSrc);
    if (pcDst) {
      if (iSrcLen < iDstLen) {
        memmove(pcDst, pcSrc, iSrcLen + 1);
        pcDecode = pcDst;
      } else
        return NULL;
    } else
      pcDst = pcSrc;
    while ((pcDecode = strchr(pcDecode, '%'))) {
      hex[0] = pcDecode[1];
      hex[1] = pcDecode[2];
      if ((lValue = strtol(hex, NULL, 16))) {
        *pcDecode++ = (unsigned char)lValue;
        pNext = pcDecode + 2;
        memmove(pcDecode, pNext, strlen(pNext) + 1);
      } else
        pcDecode++;
    }
    return pcDst;
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decodeURI>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  movb   $0x0,0x7(%rsp)
  mov    %ax,0x5(%rsp)
  test   %rdi,%rdi
  je     L41
  mov    %rdx,%rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  movslq %eax,%rdx
  test   %r12,%r12
  je     L24
  cmp    %rbx,%rdx
  jae    L41
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L40:
  mov    %r12,%r14
  lea    0x5(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L75:
  mov    $0x25,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L70
  movzbl 0x1(%rbp),%eax
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  lea    0x1(%rbp),%r14
  mov    %al,0x5(%rsp)
  movzbl 0x2(%rbp),%eax
  mov    %al,0x6(%rsp)
  call   <strtol@plt>
  test   %eax,%eax
  je     L75
  mov    %al,0x0(%rbp)
  add    $0x3,%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  lea    0x1(%rax),%edx
  call   <memmove@plt>
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L41:
  xor    %r12d,%r12d
L70:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %rbp,%r12
  jmp    L40
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *decodeURI(char *pcSrc, char *pcDst, size_t iDstLen) {
  char *pcDecode = pcSrc, *pNext;
  char hex[3] = {'\0', '\0', '\0'};
  int lValue;
  size_t iSrcLen;
  if (pcSrc) {
    iSrcLen = strlen(pcSrc);
    if (pcDst) {
      if (iSrcLen < iDstLen) {
        memmove(pcDst, pcSrc, iSrcLen + 1);
        pcDecode = pcDst;
      } else
        return NULL;
    } else
      pcDst = pcSrc;
    while ((pcDecode = strchr(pcDecode, '%'))) {
      hex[0] = pcDecode[1];
      hex[1] = pcDecode[2];
      if ((lValue = strtol(hex, NULL, 16))) {
        *pcDecode++ = (unsigned char)lValue;
        pNext = pcDecode + 2;
        memmove(pcDecode, pNext, strlen(pNext) + 1);
      } else
        pcDecode++;
    }
    return pcDst;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sortPointers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L43
L10:
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L26
L44:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x28(%rbp),%rcx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   *%rcx
  test   %eax,%eax
  jle    L17
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L17:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L44
  addl   $0x1,-0x10(%rbp)
L43:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void sortPointers(char **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  int i, j;
  for (i = 0; i < total_elems - 1; i++) {
    for (j = i + 1; j < total_elems; j++) {
      if (cmp(vals[i], vals[j]) > 0) {
        char *tmp = vals[i];
        vals[i] = vals[j];
        vals[j] = tmp;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sortPointers>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L50
  mov    %esi,%r15d
  mov    %rdx,%r13
  lea    0x8(%rdi),%rbp
  lea    -0x2(%rsi),%eax
  add    $0x2,%rax
  mov    %rax,0x8(%rsp)
  mov    $0x1,%r14d
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  jmp    L5
L55:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L79
L36:
  mov    -0x8(%rbp),%rdi
  mov    (%rbx),%rsi
  call   *%r13
  test   %eax,%eax
  jle    L55
  mov    -0x8(%rbp),%rax
  mov    (%rbx),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rax,(%rbx)
  jmp    L55
L79:
  add    $0x1,%r14
  add    $0x8,%rbp
  cmp    0x8(%rsp),%r14
  je     L50
L5:
  cmp    %r14d,%r15d
  jle    L79
  mov    0x1c(%rsp),%eax
  sub    %r14d,%eax
  lea    -0x1(%r14,%rax,1),%rax
  mov    0x10(%rsp),%rcx
  lea    0x10(%rcx,%rax,8),%r12
  mov    %rbp,%rbx
  jmp    L36
L50:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sortPointers(char **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  int i, j;
  for (i = 0; i < total_elems - 1; i++) {
    for (j = i + 1; j < total_elems; j++) {
      if (cmp(vals[i], vals[j]) > 0) {
        char *tmp = vals[i];
        vals[i] = vals[j];
        vals[j] = tmp;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sortPointers>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L5
  lea    -0x2(%rsi),%eax
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    $0x1,%r12d
  add    $0x2,%rax
  lea    0x8(%rdi),%r15
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  nop
L47:
  cmp    %r12d,%r13d
  jle    L15
  mov    0x1c(%rsp),%eax
  mov    0x10(%rsp),%rcx
  mov    %r15,%r14
  sub    %r12d,%eax
  lea    -0x1(%r12,%rax,1),%rax
  lea    0x10(%rcx,%rax,8),%rbx
  xchg   %ax,%ax
L37:
  mov    -0x8(%r15),%rdi
  mov    (%r14),%rsi
  call   *%rbp
  test   %eax,%eax
  jle    L16
  mov    -0x8(%r15),%rax
  mov    (%r14),%rsi
  mov    %rsi,-0x8(%r15)
  mov    %rax,(%r14)
L16:
  add    $0x8,%r14
  cmp    %rbx,%r14
  jne    L37
L15:
  add    $0x1,%r12
  add    $0x8,%r15
  cmp    0x8(%rsp),%r12
  jne    L47
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sortPointers(char **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  int i, j;
  for (i = 0; i < total_elems - 1; i++) {
    for (j = i + 1; j < total_elems; j++) {
      if (cmp(vals[i], vals[j]) > 0) {
        char *tmp = vals[i];
        vals[i] = vals[j];
        vals[j] = tmp;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sortPointers>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  cmp    $0x1,%esi
  jle    L9
  lea    -0x2(%rsi),%eax
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    $0x1,%r12d
  add    $0x2,%rax
  lea    0x8(%rdi),%r15
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  mov    %eax,0x1c(%rsp)
  nop
L48:
  cmp    %r12d,%r13d
  jle    L16
  mov    0x1c(%rsp),%eax
  mov    0x10(%rsp),%rcx
  mov    %r15,%r14
  sub    %r12d,%eax
  lea    -0x1(%r12,%rax,1),%rax
  lea    0x10(%rcx,%rax,8),%rbx
  xchg   %ax,%ax
L47:
  mov    -0x8(%r15),%rdi
  mov    (%r14),%rsi
  call   *%rbp
  test   %eax,%eax
  jle    L18
  mov    -0x8(%r15),%rax
  mov    (%r14),%rsi
  mov    %rsi,-0x8(%r15)
  mov    %rax,(%r14)
L18:
  add    $0x8,%r14
  cmp    %rbx,%r14
  jne    L47
L16:
  add    $0x1,%r12
  add    $0x8,%r15
  cmp    0x8(%rsp),%r12
  jne    L48
L9:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sortPointers(char **vals, int total_elems, int (*cmp)(const void *, const void *)) {
  int i, j;
  for (i = 0; i < total_elems - 1; i++) {
    for (j = i + 1; j < total_elems; j++) {
      if (cmp(vals[i], vals[j]) > 0) {
        char *tmp = vals[i];
        vals[i] = vals[j];
        vals[j] = tmp;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string
name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D22: Doing is right

tool: D7: %d minus %d is %d


tool: D6: Doing it wrong

assistant: ```c
int main(void) {
  int ten = 10;
  int two = 2;
  printf("Doing is right\n");
  printf("%d minus %d is %d\n", ten, two, ten - two);
  printf("Doing it wrong\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x8,%ecx
  mov    $0x2,%edx
  mov    $0xa,%esi
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D25
type_guessed: string

tool: D0: Doing is right

tool: D11: %d minus %d is %d


tool: D25: Doing it wrong

assistant: ```c
int main(void) {
  int ten = 10;
  int two = 2;
  printf("Doing is right\n");
  printf("%d minus %d is %d\n", ten, two, ten - two);
  printf("Doing it wrong\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D17(%rip),%rdi
  lea    D6(%rip),%rbp
  call   <puts@plt>
  mov    $0x8,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0xa,%esi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D17
type_infered: string
name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D5
type_infered: string

tool: D17: Doing is right

tool: D6: %d minus %d is %d


tool: D5: Doing it wrong

assistant: ```c
int main(void) {
  int ten = 10;
  int two = 2;
  printf("Doing is right\n");
  printf("%d minus %d is %d\n", ten, two, ten - two);
  printf("Doing it wrong\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  lea    D10(%rip),%rbp
  call   <puts@plt>
  mov    $0x8,%ecx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x2,%edx
  mov    $0xa,%esi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0xa,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D24: Doing is right

tool: D10: %d minus %d is %d


tool: D1: Doing it wrong

assistant: ```c
int main(void) {
  int ten = 10;
  int two = 2;
  printf("Doing is right\n");
  printf("%d minus %d is %d\n", ten, two, ten - two);
  printf("Doing it wrong\n");
  printf("%d minus %d is %d\n", ten);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  jmp    L20
L30:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
L20:
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  jmp    L29
L1:
  nop
L29:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strsplit(char *str, char *parts[], char *delimiter) {
  char *pch;
  int i = 0;
  pch = strtok(str, delimiter);
  parts[i++] = strdup(pch);
  while (pch) {
    pch = strtok(NULL, delimiter);
    if (NULL == pch)
      break;
    parts[i++] = strdup(pch);
  }
  free(pch);
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strsplit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  mov    $0x1,%ebx
  jmp    L2
L1:
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
L2:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L1
  mov    $0x0,%edi
  call   <free@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strsplit(char *str, char *parts[], char *delimiter) {
  char *pch;
  int i = 0;
  pch = strtok(str, delimiter);
  parts[i++] = strdup(pch);
  while (pch) {
    pch = strtok(NULL, delimiter);
    if (NULL == pch)
      break;
    parts[i++] = strdup(pch);
  }
  free(pch);
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strsplit>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  jmp    L5
  nop
L11:
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
L5:
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
  xor    %edi,%edi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strsplit(char *str, char *parts[], char *delimiter) {
  char *pch;
  int i = 0;
  pch = strtok(str, delimiter);
  parts[i++] = strdup(pch);
  while (pch) {
    pch = strtok(NULL, delimiter);
    if (NULL == pch)
      break;
    parts[i++] = strdup(pch);
  }
  free(pch);
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strsplit>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    %rdx,%rsi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <strtok@plt>
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%r12)
  jmp    L9
  nop
L8:
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
L9:
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L8
  xor    %edi,%edi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strsplit(char *str, char *parts[], char *delimiter) {
  char *pch;
  int i = 0;
  pch = strtok(str, delimiter);
  parts[i++] = strdup(pch);
  while (pch) {
    pch = strtok(NULL, delimiter);
    if (NULL == pch)
      break;
    parts[i++] = strdup(pch);
  }
  free(pch);
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_isprint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  jle    L28
  cmpl   $0x7e,-0x4(%rbp)
  jg     L28
  mov    $0x1,%eax
  jmp    L8
L28:
  mov    $0x0,%eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (c >= 32 && c <= 126) {
    return (1);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_isprint>:
  endbr64
  sub    $0x20,%edi
  cmp    $0x5e,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (c >= 32 && c <= 126) {
    return (1);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_isprint>:
  endbr64
  sub    $0x20,%edi
  xor    %eax,%eax
  cmp    $0x5e,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (c >= 32 && c <= 126) {
    return (1);
  }
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_isprint>:
  endbr64
  sub    $0x20,%edi
  xor    %eax,%eax
  cmp    $0x5e,%edi
  setbe  %al
  ret
```

assistant: ```c
int ft_isprint(int c) {
  if (c >= 32 && c <= 126) {
    return (1);
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_unicode_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x10ffff,-0x4(%rbp)
  jle    L58
  mov    $0x0,%eax
  jmp    L81
L58:
  mov    -0x4(%rbp),%eax
  and    $0xfffff800,%eax
  cmp    $0xd800,%eax
  jne    L46
  mov    $0x0,%eax
  jmp    L81
L46:
  cmpl   $0xfdcf,-0x4(%rbp)
  jle    L43
  cmpl   $0xfdef,-0x4(%rbp)
  jg     L43
  mov    $0x0,%eax
  jmp    L81
L43:
  mov    -0x4(%rbp),%eax
  and    $0xfffe,%eax
  cmp    $0xfffe,%eax
  jne    L64
  mov    $0x0,%eax
  jmp    L81
L64:
  mov    $0x1,%eax
L81:
  pop    %rbp
  ret
```

assistant: ```c
bool is_unicode_valid(uint32_t ch) {
  if (ch >= 0x110000)
    return false;
  if ((ch & 0xFFFFF800) == 0xD800)
    return false;
  if ((ch >= 0xFDD0) && (ch <= 0xFDEF))
    return false;
  if ((ch & 0xFFFE) == 0xFFFE)
    return false;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_unicode_valid>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x10ffff,%edi
  jg     L4
  mov    %edi,%edx
  and    $0xfffff800,%edx
  cmp    $0xd800,%edx
  je     L4
  lea    -0xfdd0(%rdi),%edx
  cmp    $0x1f,%edx
  jbe    L4
  and    $0xfffe,%edi
  cmp    $0xfffe,%edi
  setne  %al
  movzbl %al,%eax
L4:
  ret
```

assistant: ```c
bool is_unicode_valid(uint32_t ch) {
  if (ch >= 0x110000)
    return false;
  if ((ch & 0xFFFFF800) == 0xD800)
    return false;
  if ((ch >= 0xFDD0) && (ch <= 0xFDEF))
    return false;
  if ((ch & 0xFFFE) == 0xFFFE)
    return false;
  return true;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_unicode_valid>:
  endbr64
  xor    %eax,%eax
  cmp    $0x10ffff,%edi
  jg     L22
  mov    %edi,%edx
  and    $0xfffff800,%edx
  cmp    $0xd800,%edx
  je     L22
  lea    -0xfdd0(%rdi),%edx
  cmp    $0x1f,%edx
  jbe    L22
  and    $0xfffe,%edi
  xor    %eax,%eax
  cmp    $0xfffe,%edi
  setne  %al
L22:
  ret
```

assistant: ```c
bool is_unicode_valid(uint32_t ch) {
  if (ch >= 0x110000)
    return false;
  if ((ch & 0xFFFFF800) == 0xD800)
    return false;
  if ((ch >= 0xFDD0) && (ch <= 0xFDEF))
    return false;
  if ((ch & 0xFFFE) == 0xFFFE)
    return false;
  return true;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_unicode_valid>:
  endbr64
  xor    %eax,%eax
  cmp    $0x10ffff,%edi
  jg     L25
  mov    %edi,%edx
  and    $0xfffff800,%edx
  cmp    $0xd800,%edx
  je     L25
  lea    -0xfdd0(%rdi),%edx
  cmp    $0x1f,%edx
  jbe    L25
  and    $0xfffe,%edi
  xor    %eax,%eax
  cmp    $0xfffe,%edi
  setne  %al
L25:
  ret
```

assistant: ```c
bool is_unicode_valid(uint32_t ch) {
  if (ch >= 0x110000)
    return false;
  if ((ch & 0xFFFFF800) == 0xD800)
    return false;
  if ((ch >= 0xFDD0) && (ch <= 0xFDEF))
    return false;
  if ((ch & 0xFFFE) == 0xFFFE)
    return false;
  return true;
}
```