ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<adjust_time>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D30(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L1
  mov    (%rbx),%rdi
  lea    D25(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L9
L1:
  lea    D49(%rip),%rsi
  mov    %r12,%rdi
  lea    D43(%rip),%rdx
  call   <inline_replace@plt>
  lea    D47(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D30
type: string
name: read_data
arguments: label: D25
type: string
name: read_data
arguments: label: D49
type: string
name: read_data
arguments: label: D43
type: string
name: read_data
arguments: label: D47
type: string

tool: D30: am

tool: D25: pm

tool: D49: %H

tool: D43: %I

tool: D47: %p

assistant: ```c
char *adjust_time(char **arg, char *format) {
  if (strstr(*arg, "am") || strstr(*arg, "pm")) {
    inline_replace(format, "%H", "%I");
    strcat(format, "%p");
  }
  return format;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<adjust_time>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D31(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L19
  mov    (%rbx),%rdi
  lea    D46(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L1
L19:
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  lea    D37(%rip),%rdx
  call   <inline_replace@plt>
  lea    D9(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D31
data_type: string
name: read_data
arguments: data_label: D46
data_type: string
name: read_data
arguments: data_label: D21
data_type: string
name: read_data
arguments: data_label: D37
data_type: string
name: read_data
arguments: data_label: D9
data_type: string

tool: D31: am

tool: D46: pm

tool: D21: %H

tool: D37: %I

tool: D9: %p

assistant: ```c
char *adjust_time(char **arg, char *format) {
  if (strstr(*arg, "am") || strstr(*arg, "pm")) {
    inline_replace(format, "%H", "%I");
    strcat(format, "%p");
  }
  return format;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<removeWhiteSpace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L29
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L36
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L39
L36:
  nop
L39:
  addq   $0x1,-0x18(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void removeWhiteSpace(char *html) {
  char *buffer = malloc(strlen(html) + 1), *in, *out;
  memset(buffer, 0, strlen(html) + 1);
  out = buffer;
  for (in = html; *in != '\0'; in++) {
    if (*in <= ' ')
      continue;
    *out++ = *in;
  }
  strcpy(html, buffer);
  free(buffer);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<removeWhiteSpace>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L35
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  jmp    L19
L10:
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rcx
L39:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L35
L19:
  cmp    $0x20,%al
  jg     L10
  jmp    L39
L35:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void removeWhiteSpace(char *html) {
  char *buffer = malloc(strlen(html) + 1), *in, *out;
  memset(buffer, 0, strlen(html) + 1);
  out = buffer;
  for (in = html; *in != '\0'; in++) {
    if (*in <= ' ')
      continue;
    *out++ = *in;
  }
  strcpy(html, buffer);
  free(buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<removeWhiteSpace>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L24
  mov    %r12,%rcx
  mov    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L10:
  cmp    $0x20,%al
  jle    L27
  mov    %al,(%rcx)
  add    $0x1,%rcx
L27:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L10
L24:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

assistant: ```c
void removeWhiteSpace(char *html) {
  char *buffer = malloc(strlen(html) + 1), *in, *out;
  memset(buffer, 0, strlen(html) + 1);
  out = buffer;
  for (in = html; *in != '\0'; in++) {
    if (*in <= ' ')
      continue;
    *out++ = *in;
  }
  strcpy(html, buffer);
  free(buffer);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<removeWhiteSpace>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L39
  mov    %r12,%rcx
  mov    %rbp,%rdx
L24:
  cmp    $0x20,%al
  jle    L13
L44:
  add    $0x1,%rdx
  mov    %al,(%rcx)
  lea    0x1(%rcx),%rsi
  movzbl (%rdx),%eax
  test   %al,%al
  je     L39
  mov    %rsi,%rcx
  cmp    $0x20,%al
  jg     L44
L13:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L24
L39:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1090 <free@plt>
```

assistant: ```c
void removeWhiteSpace(char *html) {
  char *buffer = malloc(strlen(html) + 1), *in, *out;
  memset(buffer, 0, strlen(html) + 1);
  out = buffer;
  for (in = html; *in != '\0'; in++) {
    if (*in <= ' ')
      continue;
    *out++ = *in;
  }
  strcpy(html, buffer);
  free(buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_attroff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L39
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  jne    L12
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <report_error@plt>
  jmp    L32
L12:
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <attroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L32
L39:
  nop
L32:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string

tool: D17: %d

tool: D10: BAD ARGUMENT

assistant: ```c
void cmd_attroff(int nargs, char **args) {
  int attrib;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &attrib) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(attroff(attrib));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_attroff>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L22
  lea    0x4(%rsp),%rdx
  lea    D6(%rip),%rsi
  mov    (%rbx),%rdi
  call   <sscanf@plt>
  test   %rax,%rax
  je     L30
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    0x4(%rsp),%edi
  call   <attroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  ret
L30:
  mov    $0x1,%edi
  call   <report_count@plt>
  lea    D18(%rip),%rdi
  call   <report_error@plt>
  jmp    L22
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string
name: retrieve_data
arguments: tag: D18
datatype: string

tool: D6: %d

tool: D18: BAD ARGUMENT

assistant: ```c
void cmd_attroff(int nargs, char **args) {
  int attrib;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &attrib) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(attroff(attrib));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_attroff>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L33
  mov    (%rbx),%rdi
  lea    0x4(%rsp),%rdx
  lea    D17(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x1,%edi
  test   %rax,%rax
  je     L5
  call   <report_count@plt>
  mov    0x4(%rsp),%edi
  call   <attroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  call   <report_count@plt>
  lea    D16(%rip),%rdi
  call   <report_error@plt>
  jmp    L33
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string

tool: D17: %d

tool: D16: BAD ARGUMENT

assistant: ```c
void cmd_attroff(int nargs, char **args) {
  int attrib;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &attrib) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(attroff(attrib));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmd_attroff>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L2
  mov    (%rbx),%rdi
  lea    0x4(%rsp),%rdx
  lea    D10(%rip),%rsi
  call   <sscanf@plt>
  mov    $0x1,%edi
  test   %rax,%rax
  je     L19
  call   <report_count@plt>
  mov    0x4(%rsp),%edi
  call   <attroff@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  call   <report_count@plt>
  lea    D13(%rip),%rdi
  call   <report_error@plt>
  jmp    L2
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
type_infered: string
name: read_data
arguments: label: D13
type_infered: string

tool: D10: %d

tool: D13: BAD ARGUMENT

assistant: ```c
void cmd_attroff(int nargs, char **args) {
  int attrib;
  if (check_arg_count(nargs, 1) == 1)
    return;
  if (sscanf(args[0], "%d", &attrib) == 0) {
    report_count(1);
    report_error("BAD ARGUMENT");
    return;
  }
  report_count(1);
  report_return(attroff(attrib));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_to_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  leave
  ret
```

assistant: ```c
char *write_to_buf(char *buf, const char *content, int clen) {
  memcpy(buf, content, clen);
  return buf + clen;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_to_buf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  call   <memcpy@plt>
  movslq %ebp,%rbp
  lea    (%rbx,%rbp,1),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *write_to_buf(char *buf, const char *content, int clen) {
  memcpy(buf, content, clen);
  return buf + clen;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_to_buf>:
  endbr64
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *write_to_buf(char *buf, const char *content, int clen) {
  memcpy(buf, content, clen);
  return buf + clen;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_to_buf>:
  endbr64
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  mov    %ebp,%edx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memcpy@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *write_to_buf(char *buf, const char *content, int clen) {
  memcpy(buf, content, clen);
  return buf + clen;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Hsh_IntManHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  shll   $0x2,-0x1c(%rbp)
  jmp    L8
L12:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xa,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x6,%eax
  xor    %eax,-0xc(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jne    L12
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0xb,%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xf,%eax
  add    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%ecx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Hsh_IntManHash(unsigned *pData, int nSize, int nTableSize) {
  int i = 0;
  unsigned hash = 0;
  unsigned char *pDataC = (unsigned char *)pData;
  nSize <<= 2;
  while (i != nSize) {
    hash += pDataC[i++];
    hash += hash << 10;
    hash ^= hash >> 6;
  }
  hash += hash << 3;
  hash ^= hash >> 11;
  hash += hash << 15;
  return (int)(hash % nTableSize);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Hsh_IntManHash>:
  endbr64
  mov    %edx,%r8d
  shl    $0x2,%esi
  je     L4
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
L2:
  movzbl (%rcx),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L2
L26:
  lea    (%rax,%rax,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  mov    $0x0,%edx
  div    %r8d
  mov    %edx,%eax
  ret
L4:
  mov    $0x0,%eax
  jmp    L26
```

assistant: ```c
int Hsh_IntManHash(unsigned *pData, int nSize, int nTableSize) {
  int i = 0;
  unsigned hash = 0;
  unsigned char *pDataC = (unsigned char *)pData;
  nSize <<= 2;
  while (i != nSize) {
    hash += pDataC[i++];
    hash += hash << 10;
    hash ^= hash >> 6;
  }
  hash += hash << 3;
  hash ^= hash >> 11;
  hash += hash << 15;
  return (int)(hash % nTableSize);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Hsh_IntManHash>:
  endbr64
  shl    $0x2,%esi
  mov    %edx,%r9d
  mov    %esi,%r8d
  je     L12
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L4
  lea    (%rax,%rax,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  xor    %edx,%edx
  div    %r9d
  mov    %edx,%r8d
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Hsh_IntManHash(unsigned *pData, int nSize, int nTableSize) {
  int i = 0;
  unsigned hash = 0;
  unsigned char *pDataC = (unsigned char *)pData;
  nSize <<= 2;
  while (i != nSize) {
    hash += pDataC[i++];
    hash += hash << 10;
    hash ^= hash >> 6;
  }
  hash += hash << 3;
  hash ^= hash >> 11;
  hash += hash << 15;
  return (int)(hash % nTableSize);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Hsh_IntManHash>:
  endbr64
  shl    $0x2,%esi
  mov    %edx,%r9d
  mov    %esi,%r8d
  je     L6
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L2:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L2
  lea    (%rax,%rax,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  xor    %edx,%edx
  div    %r9d
  mov    %edx,%r8d
L6:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Hsh_IntManHash(unsigned *pData, int nSize, int nTableSize) {
  int i = 0;
  unsigned hash = 0;
  unsigned char *pDataC = (unsigned char *)pData;
  nSize <<= 2;
  while (i != nSize) {
    hash += pDataC[i++];
    hash += hash << 10;
    hash ^= hash >> 6;
  }
  hash += hash << 3;
  hash ^= hash >> 11;
  hash += hash << 15;
  return (int)(hash % nTableSize);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ocvp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double *ocvp(const double *v1, const double *v2, unsigned n) {
  double *product = (double *)malloc(sizeof(double) * n);
  return product;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ocvp>:
  endbr64
  sub    $0x8,%rsp
  lea    0x0(,%rdx,8),%edi
  call   <malloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double *ocvp(const double *v1, const double *v2, unsigned n) {
  double *product = (double *)malloc(sizeof(double) * n);
  return product;
}
```
user: What is the c source code of the assembly code below:

```asm
<ocvp>:
  endbr64
  lea    0x0(,%rdx,8),%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
double *ocvp(const double *v1, const double *v2, unsigned n) {
  double *product = (double *)malloc(sizeof(double) * n);
  return product;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ocvp>:
  endbr64
  lea    0x0(,%rdx,8),%edi
  jmp    1050 <malloc@plt>
```

assistant: ```c
double *ocvp(const double *v1, const double *v2, unsigned n) {
  double *product = (double *)malloc(sizeof(double) * n);
  return product;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<topchead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7:   pid command  cpu%% |   pid command  cpu%% |   pid command  cpu%%_top3_

assistant: ```c
void topchead(int osvers, int osrel, int ossub) {
  printf("  pid command  cpu%% |   pid command  cpu%% | "
         "  pid command  cpu%%_top3_");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<topchead>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type: string

tool: D4:   pid command  cpu%% |   pid command  cpu%% |   pid command  cpu%%_top3_

assistant: ```c
void topchead(int osvers, int osrel, int ossub) {
  printf("  pid command  cpu%% |   pid command  cpu%% | "
         "  pid command  cpu%%_top3_");
}
```
user: Translate the below assembly code into C programming language:

```asm
<topchead>:
  endbr64
  lea    D7(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7:   pid command  cpu%% |   pid command  cpu%% |   pid command  cpu%%_top3_

assistant: ```c
void topchead(int osvers, int osrel, int ossub) {
  printf("  pid command  cpu%% |   pid command  cpu%% | "
         "  pid command  cpu%%_top3_");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<topchead>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string

tool: D5:   pid command  cpu%% |   pid command  cpu%% |   pid command  cpu%%_top3_

assistant: ```c
void topchead(int osvers, int osrel, int ossub) {
  printf("  pid command  cpu%% |   pid command  cpu%% | "
         "  pid command  cpu%%_top3_");
}
```
user: What is the c source code of the assembly code below:

```asm
<test_positive_negative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x18(%rbp)
  movl   $0xffffffec,-0x14(%rbp)
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x1e,-0x10(%rbp)
  movl   $0xffffffd8,-0xc(%rbp)
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap_bits@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0xffffffec,%eax
  jne    L15
  mov    -0x14(%rbp),%eax
  cmp    $0xa,%eax
  jne    L15
  mov    -0x10(%rbp),%eax
  cmp    $0xffffffd8,%eax
  jne    L15
  mov    -0xc(%rbp),%eax
  cmp    $0x1e,%eax
  jne    L15
  mov    $0x1,%eax
  jmp    L40
L15:
  mov    $0x0,%eax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int test_positive_negative() {
  int a = 10;
  int b = -20;
  swap(&a, &b);
  int c = 30;
  int d = -40;
  swap_bits(&c, &d);
  return a == -20 && b == 10 && c == -40 && d == 30;
}
```