ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D2
datatype: string

tool: D10: ############## %s ##############


tool: D2: ############## End of test %s ##############


assistant: ```c
void run_test(char *name, int (*test)(char *), char *input_data_path) {
  printf("############## %s ##############\n", name);
  test(input_data_path);
  printf("############## End of test %s ##############\n", name);
}
```
user: What is the c source code of the assembly code below:

```asm
<run_test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rdi,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   *%rbp
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D12: ############## %s ##############


tool: D6: ############## End of test %s ##############


assistant: ```c
void run_test(char *name, int (*test)(char *), char *input_data_path) {
  printf("############## %s ##############\n", name);
  test(input_data_path);
  printf("############## End of test %s ##############\n", name);
}
```
user: What is the c source code of the assembly code below?

```asm
<run_test>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   *%rbx
  pop    %rbx
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
type_guessed: string
name: disassemble_data
arguments: data_tag: D1
type_guessed: string

tool: D12: ############## %s ##############


tool: D1: ############## End of test %s ##############


assistant: ```c
void run_test(char *name, int (*test)(char *), char *input_data_path) {
  printf("############## %s ##############\n", name);
  test(input_data_path);
  printf("############## End of test %s ##############\n", name);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_test>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   *%rbx
  pop    %rbx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D17: ############## %s ##############


tool: D2: ############## End of test %s ##############


assistant: ```c
void run_test(char *name, int (*test)(char *), char *input_data_path) {
  printf("############## %s ##############\n", name);
  test(input_data_path);
  printf("############## End of test %s ##############\n", name);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<basename_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  jmp    L6
L12:
  mov    -0x18(%rbp),%rax
L6:
  leave
  ret
```

assistant: ```c
const char *basename_c(const char *path) {
  const char *t = strrchr(path, '/');
  return (t == 0 ? path : ++t);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<basename_c>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
const char *basename_c(const char *path) {
  const char *t = strrchr(path, '/');
  return (t == 0 ? path : ++t);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<basename_c>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *basename_c(const char *path) {
  const char *t = strrchr(path, '/');
  return (t == 0 ? path : ++t);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basename_c>:
  endbr64
  push   %rbx
  mov    $0x2f,%esi
  mov    %rdi,%rbx
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
const char *basename_c(const char *path) {
  const char *t = strrchr(path, '/');
  return (t == 0 ? path : ++t);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EMACTimestampTargetIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x700,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x700,%edx
  movslq %edx,%rdx
  or     $0x10,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EMACTimestampTargetIntEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000010;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<EMACTimestampTargetIntEnable>:
  endbr64
  add    $0x700,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x10,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACTimestampTargetIntEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000010;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<EMACTimestampTargetIntEnable>:
  endbr64
  add    $0x700,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x10,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACTimestampTargetIntEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000010;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<EMACTimestampTargetIntEnable>:
  endbr64
  add    $0x700,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x10,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACTimestampTargetIntEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000700))) |= 0x00000010;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<vlmcsd_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  call   <OutOfMemory@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *vlmcsd_strdup(const char *src) {
  char *dst = strdup(src);
  if (!dst)
    OutOfMemory();
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vlmcsd_strdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
L17:
  mov    $0x0,%eax
  call   <OutOfMemory@plt>
  jmp    L5
```

assistant: ```c
char *vlmcsd_strdup(const char *src) {
  char *dst = strdup(src);
  if (!dst)
    OutOfMemory();
  return dst;
}
```
user: What is the c source code of the assembly code below:

```asm
<vlmcsd_strdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
L5:
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  xor    %eax,%eax
  call   <OutOfMemory@plt>
  jmp    L5
```

assistant: ```c
char *vlmcsd_strdup(const char *src) {
  char *dst = strdup(src);
  if (!dst)
    OutOfMemory();
  return dst;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vlmcsd_strdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L5:
  mov    %r12,%rax
  pop    %r12
  ret
L18:
  xor    %eax,%eax
  call   <OutOfMemory@plt>
  jmp    L5
```

assistant: ```c
char *vlmcsd_strdup(const char *src) {
  char *dst = strdup(src);
  if (!dst)
    OutOfMemory();
  return dst;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <test32@plt>
  test   %rax,%rax
  jne    L21
  cmpl   $0x0,-0x4(%rbp)
  je     L8
L21:
  mov    $0x1,%eax
  jmp    L39
L8:
  mov    $0x0,%eax
L39:
  mov    %eax,-0x4(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <test64@plt>
  test   %rax,%rax
  jne    L11
  cmpl   $0x0,-0x4(%rbp)
  je     L56
L11:
  mov    $0x1,%eax
  jmp    L54
L56:
  mov    $0x0,%eax
L54:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L27
  lea    D9(%rip),%rax
  jmp    L32
L27:
  lea    D17(%rip),%rax
L32:
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: string
name: parse_data
arguments: data_tag: D22
type: string
name: parse_data
arguments: data_tag: D9
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D29: testing 32-bit code...

tool: D22: testing 64-bit code...

tool: D9: OK

tool: D17: FAILED

assistant: ```c
int main() {
  int result = 0;
  puts("testing 32-bit code...");
  result = test32() || result;
  puts("testing 64-bit code...");
  result = test64() || result;
  puts(result ? "OK" : "FAILED");
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D27(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <test32@plt>
  mov    %rax,%rbx
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <test64@plt>
  or     %rax,%rbx
  lea    D26(%rip),%rdi
  lea    D7(%rip),%rax
  cmove  %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
datatype: string
name: parse_data
arguments: data_label: D16
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D7
datatype: string

tool: D27: testing 32-bit code...

tool: D16: testing 64-bit code...

tool: D26: OK

tool: D7: FAILED

assistant: ```c
int main() {
  int result = 0;
  puts("testing 32-bit code...");
  result = test32() || result;
  puts("testing 64-bit code...");
  result = test64() || result;
  puts(result ? "OK" : "FAILED");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  lea    D38(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  xor    %eax,%eax
  call   <test32@plt>
  lea    D30(%rip),%rdi
  test   %rax,%rax
  je     L17
  call   <puts@plt>
  xor    %eax,%eax
  call   <test64@plt>
  lea    D17(%rip),%rdi
L1:
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L17:
  call   <puts@plt>
  xor    %eax,%eax
  call   <test64@plt>
  lea    D17(%rip),%rdi
  test   %rax,%rax
  lea    D33(%rip),%rax
  cmove  %rax,%rdi
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: label: D38
type_infered: string
name: disassemble_data
arguments: label: D30
type_infered: string
name: disassemble_data
arguments: label: D17
type_infered: string
name: disassemble_data
arguments: label: D33
type_infered: string

tool: D38: testing 32-bit code...

tool: D30: testing 64-bit code...

tool: D17: OK

tool: D33: FAILED

assistant: ```c
int main() {
  int result = 0;
  puts("testing 32-bit code...");
  result = test32() || result;
  puts("testing 64-bit code...");
  result = test64() || result;
  puts(result ? "OK" : "FAILED");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  lea    D1(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  xor    %eax,%eax
  call   <test32@plt>
  lea    D9(%rip),%rdi
  test   %rax,%rax
  je     L13
  call   <puts@plt>
  xor    %eax,%eax
  call   <test64@plt>
  lea    D48(%rip),%rdi
L16:
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L13:
  call   <puts@plt>
  xor    %eax,%eax
  call   <test64@plt>
  lea    D48(%rip),%rdi
  test   %rax,%rax
  lea    D49(%rip),%rax
  cmove  %rax,%rdi
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D48
type_infered: string
name: read_data
arguments: data_label: D49
type_infered: string

tool: D1: testing 32-bit code...

tool: D9: testing 64-bit code...

tool: D48: OK

tool: D49: FAILED

assistant: ```c
int main() {
  int result = 0;
  puts("testing 32-bit code...");
  result = test32() || result;
  puts("testing 64-bit code...");
  result = test64() || result;
  puts(result ? "OK" : "FAILED");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x20,%rsp
  mov    %rdi,-0x2018(%rbp)
  mov    %esi,-0x201c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x2010(%rbp),%rax
  movabs $0x5542205d2a2a2a5b,%rcx
  mov    %rcx,(%rax)
  movl   $0x203a47,0x8(%rax)
  lea    -0x2010(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    -0x2010(%rbp),%rdx
  lea    (%rdx,%rax,1),%rcx
  mov    -0x201c(%rbp),%edx
  mov    -0x2018(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  lea    -0x2010(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
void bug(const char *str, int param) {
  char buf[8192];
  strcpy(buf, "[***] BUG: ");
  sprintf(buf + strlen(buf), str, param);
  log_string(buf);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bug>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movabs $0x5542205d2a2a2a5b,%rax
  mov    %rax,(%rsp)
  movl   $0x203a47,0x8(%rsp)
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <log_string@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bug(const char *str, int param) {
  char buf[8192];
  strcpy(buf, "[***] BUG: ");
  sprintf(buf + strlen(buf), str, param);
  log_string(buf);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bug>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r8
  mov    %esi,%edx
  lea    0xb(%rsp),%rdi
  movabs $0x5542205d2a2a2a5b,%rax
  mov    %rsp,%rbp
  mov    %r8,%rsi
  movl   $0x203a47,0x8(%rsp)
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <log_string@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x2010,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bug(const char *str, int param) {
  char buf[8192];
  strcpy(buf, "[***] BUG: ");
  sprintf(buf + strlen(buf), str, param);
  log_string(buf);
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bug>:
  endbr64
  push   %rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rdi,%r8
  mov    %esi,%edx
  lea    0xb(%rsp),%rdi
  movabs $0x5542205d2a2a2a5b,%rax
  mov    %rsp,%rbp
  mov    %r8,%rsi
  movl   $0x203a47,0x8(%rsp)
  mov    %rax,(%rsp)
  xor    %eax,%eax
  call   <sprintf@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <log_string@plt>
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x2010,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bug(const char *str, int param) {
  char buf[8192];
  strcpy(buf, "[***] BUG: ");
  sprintf(buf + strlen(buf), str, param);
  log_string(buf);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subOK>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  not    %rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int subOK(int x, int y) {
  long long a = x;
  long long b = y;
  long long z = a + ~b;
  int z2;
  ++z;
  z2 = z;
  return !(z2 ^ z);
}
```
user: Translate the below assembly code into C programming language:

```asm
<subOK>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  sub    %rsi,%rdi
  movslq %edi,%rax
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int subOK(int x, int y) {
  long long a = x;
  long long b = y;
  long long z = a + ~b;
  int z2;
  ++z;
  z2 = z;
  return !(z2 ^ z);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subOK>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  sub    %rsi,%rdi
  movslq %edi,%rax
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int subOK(int x, int y) {
  long long a = x;
  long long b = y;
  long long z = a + ~b;
  int z2;
  ++z;
  z2 = z;
  return !(z2 ^ z);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<subOK>:
  endbr64
  movslq %esi,%rsi
  movslq %edi,%rdi
  sub    %rsi,%rdi
  movslq %edi,%rax
  cmp    %rdi,%rax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int subOK(int x, int y) {
  long long a = x;
  long long b = y;
  long long z = a + ~b;
  int z2;
  ++z;
  z2 = z;
  return !(z2 ^ z);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movb   $0x64,-0xd(%rbp)
  movss  D4(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movsbl -0xd(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  addss  -0xc(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: f32

tool: D4: 50

assistant: ```c
int main() {
  char x = 100;
  float y = 50;
  double z = x + y;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  char x = 100;
  float y = 50;
  double z = x + y;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char x = 100;
  float y = 50;
  double z = x + y;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  char x = 100;
  float y = 50;
  double z = x + y;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x2,-0x18(%rbp)
  jmp    L25
L49:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L20
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L20
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  movsbl %al,%eax
  sub    $0x61,%eax
  add    %ebx,%eax
  add    $0xa,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L29
L20:
  mov    -0x14(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L29:
  addl   $0x1,-0x18(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L49
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  for (i = 2; s[i] != '\0'; ++i) {
    if (tolower(s[i]) >= 'a' && tolower(s[i]) <= 'f')
      n = 16 * n + (tolower(s[i]) - 'a') + 10;
    else
      n = 16 * n + (s[i] - '0');
  }
  return n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<htoi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    0x2(%rdi),%rbx
  movzbl 0x2(%rdi),%edi
  test   %dil,%dil
  je     L14
  mov    $0x0,%ebp
  jmp    L2
L29:
  shl    $0x4,%ebp
  movsbl (%rbx),%eax
  lea    -0x30(%rbp,%rax,1),%ebp
L48:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L31
L2:
  movsbl %dil,%edi
  call   <tolower@plt>
  cmp    $0x60,%al
  jle    L29
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L29
  movsbl (%rbx),%edi
  call   <tolower@plt>
  shl    $0x4,%ebp
  movsbl %al,%eax
  lea    -0x57(%rbp,%rax,1),%ebp
  jmp    L48
L14:
  mov    $0x0,%ebp
L31:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  for (i = 2; s[i] != '\0'; ++i) {
    if (tolower(s[i]) >= 'a' && tolower(s[i]) <= 'f')
      n = 16 * n + (tolower(s[i]) - 'a') + 10;
    else
      n = 16 * n + (s[i] - '0');
  }
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<htoi>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  lea    0x2(%rdi),%rbx
  sub    $0x8,%rsp
  movsbl 0x2(%rdi),%edi
  test   %dil,%dil
  jne    L21
  jmp    L14
  nopl   (%rax)
L11:
  movsbl (%rbx),%eax
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  lea    -0x30(%r12,%rax,1),%r12d
  test   %dil,%dil
  je     L14
L21:
  call   <tolower@plt>
  shl    $0x4,%r12d
  cmp    $0x60,%al
  jle    L11
  movsbl (%rbx),%edi
  call   <tolower@plt>
  cmp    $0x66,%al
  jg     L11
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  movsbl (%rbx),%edi
  movsbl %al,%eax
  lea    -0x57(%r12,%rax,1),%r12d
  test   %dil,%dil
  jne    L21
L14:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  n = 0;
  for (i = 2; s[i] != '\0'; ++i) {
    if (tolower(s[i]) >= 'a' && tolower(s[i]) <= 'f')
      n = 16 * n + (tolower(s[i]) - 'a') + 10;
    else
      n = 16 * n + (s[i] - '0');
  }
  return n;
}
```