ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<output_system_error>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D2(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  call   <portable_snprintf@plt>
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x110,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %s: %s

assistant: ```c
void output_system_error(const char *s1, const char *s2) {
  char buf[0x100];
  portable_snprintf(buf, 0x100, "%s: %s", s1, s2);
  perror(buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<output_system_error>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  lea    D4(%rip),%rdx
  mov    $0x100,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <portable_snprintf@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
type: string

tool: D4: %s: %s

assistant: ```c
void output_system_error(const char *s1, const char *s2) {
  char buf[0x100];
  portable_snprintf(buf, 0x100, "%s: %s", s1, s2);
  perror(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<output_system_error>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rsi,%r8
  lea    D7(%rip),%rdx
  mov    $0x100,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <portable_snprintf@plt>
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
data_type: string

tool: D7: %s: %s

assistant: ```c
void output_system_error(const char *s1, const char *s2) {
  char buf[0x100];
  portable_snprintf(buf, 0x100, "%s: %s", s1, s2);
  perror(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  shlq   -0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <segment_lcd_data@plt>
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <segment_lcd_data@plt>
  nop
  leave
  ret
```

assistant: ```c
void clear_digit(unsigned long int digit) {
  digit *= 2;
  segment_lcd_data(digit, 0x0);
  segment_lcd_data(digit + 1, 0x0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clear_digit>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,1),%rbx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <segment_lcd_data@plt>
  lea    0x1(%rbx),%rdi
  mov    $0x0,%esi
  call   <segment_lcd_data@plt>
  pop    %rbx
  ret
```

assistant: ```c
void clear_digit(unsigned long int digit) {
  digit *= 2;
  segment_lcd_data(digit, 0x0);
  segment_lcd_data(digit + 1, 0x0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_digit>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,1),%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <segment_lcd_data@plt>
  lea    0x1(%rbx),%rdi
  xor    %esi,%esi
  pop    %rbx
  jmp    1050 <segment_lcd_data@plt>
```

assistant: ```c
void clear_digit(unsigned long int digit) {
  digit *= 2;
  segment_lcd_data(digit, 0x0);
  segment_lcd_data(digit + 1, 0x0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clear_digit>:
  endbr64
  push   %rbx
  lea    (%rdi,%rdi,1),%rbx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <segment_lcd_data@plt>
  lea    0x1(%rbx),%rdi
  xor    %esi,%esi
  pop    %rbx
  jmp    1050 <segment_lcd_data@plt>
```

assistant: ```c
void clear_digit(unsigned long int digit) {
  digit *= 2;
  segment_lcd_data(digit, 0x0);
  segment_lcd_data(digit + 1, 0x0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L9
  mov    -0x4(%rbp),%eax
  jmp    L16
L9:
  mov    $0xffffffff,%eax
L16:
  leave
  ret
```

assistant: ```c
int fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102>:
  endbr64
  sub    $0x8,%rsp
  call   <fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102>:
  endbr64
  jmp    1050 <fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102@plt>
```

assistant: ```c
int fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102>:
  endbr64
  jmp    1050 <fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102@plt>
```

assistant: ```c
int fn_al_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(const char *text) {
  int pos = 0;
  pos = fn_sq_ch_68_ch_97_ch_116_ch_97_ch_67_ch_111_ch_109_ch_112_ch_108_ch_101_ch_109_ch_101_ch_110_ch_116_ch_79_ch_102(text);
  if (pos != -1)
    return pos;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<protoA_radioReadId>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %esi,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movw   $0x0,-0x2(%rbp)
  cmpw   $0x9,-0x20(%rbp)
  jbe    L35
  cmpb   $0x5,-0x1c(%rbp)
  ja     L23
L35:
  mov    $0x1,%eax
  jmp    L12
L23:
  addq   $0x4,-0x28(%rbp)
  movzbl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x6,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movw   $0x0,-0x2(%rbp)
  jmp    L29
L26:
  movzwl -0x2(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzwl -0x2(%rbp),%edx
  mov    $0x6,%eax
  sub    %edx,%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzwl -0x2(%rbp),%esi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzwl -0x2(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzwl -0x2(%rbp),%edx
  mov    $0x6,%eax
  sub    %edx,%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzwl -0x2(%rbp),%esi
  mov    $0x6,%eax
  sub    %esi,%eax
  cltq
  lea    -0x1(%rax),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzwl -0x2(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzwl -0x2(%rbp),%edx
  mov    $0x6,%eax
  sub    %edx,%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzwl -0x2(%rbp),%esi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L29:
  cmpw   $0x2,-0x2(%rbp)
  jbe    L26
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
unsigned char protoA_radioReadId(unsigned char *gatewayId, unsigned char idLen, unsigned char *buf, unsigned short bufSize) {
  unsigned short i = 0;
  if (bufSize < (4 + 6) || idLen < 6) {
    return 0x01;
  }
  buf += 4;
  memset(gatewayId, 0, idLen);
  memcpy(gatewayId, buf, 6);
  for (i = 0; i < 6 / 2; i++) {
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[6 - i - 1] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
  }
  return 0x00;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<protoA_radioReadId>:
  endbr64
  cmp    $0x9,%cx
  jbe    L4
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  mov    $0x1,%eax
  cmp    $0x5,%sil
  jbe    L1
  movzbl %sil,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  lea    0x4(%rbp),%rsi
  mov    $0x6,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rcx
  lea    0x5(%rbx),%rdx
  add    $0x2,%rbx
L19:
  movzbl (%rcx),%eax
  xor    (%rdx),%al
  mov    %al,(%rcx)
  xor    (%rdx),%al
  mov    %al,(%rdx)
  xor    %al,(%rcx)
  add    $0x1,%rcx
  sub    $0x1,%rdx
  cmp    %rbx,%rdx
  jne    L19
  mov    $0x0,%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned char protoA_radioReadId(unsigned char *gatewayId, unsigned char idLen, unsigned char *buf, unsigned short bufSize) {
  unsigned short i = 0;
  if (bufSize < (4 + 6) || idLen < 6) {
    return 0x01;
  }
  buf += 4;
  memset(gatewayId, 0, idLen);
  memcpy(gatewayId, buf, 6);
  for (i = 0; i < 6 / 2; i++) {
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[6 - i - 1] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
  }
  return 0x00;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<protoA_radioReadId>:
  endbr64
  cmp    $0x9,%cx
  jbe    L18
  cmp    $0x5,%sil
  jbe    L18
  push   %rbp
  mov    %rdx,%rbp
  movzbl %sil,%edx
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  mov    $0x6,%edx
  mov    %rbx,%rdi
  lea    0x4(%rbp),%rsi
  call   <memcpy@plt>
  mov    %rbx,%rdi
  lea    0x5(%rbx),%rdx
  lea    0x2(%rbx),%rcx
L14:
  movzbl (%rdi),%eax
  xor    (%rdx),%al
  sub    $0x1,%rdx
  mov    %al,(%rdi)
  xor    0x1(%rdx),%al
  mov    %al,0x1(%rdx)
  xor    %al,(%rdi)
  add    $0x1,%rdi
  cmp    %rcx,%rdx
  jne    L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned char protoA_radioReadId(unsigned char *gatewayId, unsigned char idLen, unsigned char *buf, unsigned short bufSize) {
  unsigned short i = 0;
  if (bufSize < (4 + 6) || idLen < 6) {
    return 0x01;
  }
  buf += 4;
  memset(gatewayId, 0, idLen);
  memcpy(gatewayId, buf, 6);
  for (i = 0; i < 6 / 2; i++) {
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[6 - i - 1] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
  }
  return 0x00;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<protoA_radioReadId>:
  endbr64
  cmp    $0x9,%cx
  jbe    L14
  cmp    $0x5,%sil
  jbe    L14
  push   %rbp
  mov    %rdx,%rbp
  movzbl %sil,%edx
  xor    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <memset@plt>
  lea    0x4(%rbp),%rsi
  mov    $0x6,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movzbl 0x5(%rbx),%eax
  movzbl (%rbx),%edx
  rolw   $0x8,0x2(%rbx)
  mov    %dl,0x5(%rbx)
  movzbl 0x1(%rbx),%edx
  mov    %al,(%rbx)
  movzbl 0x4(%rbx),%eax
  mov    %dl,0x4(%rbx)
  mov    %al,0x1(%rbx)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned char protoA_radioReadId(unsigned char *gatewayId, unsigned char idLen, unsigned char *buf, unsigned short bufSize) {
  unsigned short i = 0;
  if (bufSize < (4 + 6) || idLen < 6) {
    return 0x01;
  }
  buf += 4;
  memset(gatewayId, 0, idLen);
  memcpy(gatewayId, buf, 6);
  for (i = 0; i < 6 / 2; i++) {
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[6 - i - 1] = gatewayId[i] ^ gatewayId[6 - i - 1];
    gatewayId[i] = gatewayId[i] ^ gatewayId[6 - i - 1];
  }
  return 0x00;
}
```
user: Translate the below assembly code into C programming language:

```asm
<libc_inttypes_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <tc_libc_inttypes_imaxabs@plt>
  mov    $0x0,%eax
  call   <tc_libc_inttypes_imaxdiv@plt>
  mov    $0x0,%eax
  call   <tc_libc_inttypes_strtoimax@plt>
  mov    $0x0,%eax
  call   <tc_libc_inttypes_strtoumax@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int libc_inttypes_main(void) {
  tc_libc_inttypes_imaxabs();
  tc_libc_inttypes_imaxdiv();
  tc_libc_inttypes_strtoimax();
  tc_libc_inttypes_strtoumax();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<libc_inttypes_main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <tc_libc_inttypes_imaxabs@plt>
  mov    $0x0,%eax
  call   <tc_libc_inttypes_imaxdiv@plt>
  mov    $0x0,%eax
  call   <tc_libc_inttypes_strtoimax@plt>
  mov    $0x0,%eax
  call   <tc_libc_inttypes_strtoumax@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int libc_inttypes_main(void) {
  tc_libc_inttypes_imaxabs();
  tc_libc_inttypes_imaxdiv();
  tc_libc_inttypes_strtoimax();
  tc_libc_inttypes_strtoumax();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<libc_inttypes_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tc_libc_inttypes_imaxabs@plt>
  xor    %eax,%eax
  call   <tc_libc_inttypes_imaxdiv@plt>
  xor    %eax,%eax
  call   <tc_libc_inttypes_strtoimax@plt>
  xor    %eax,%eax
  call   <tc_libc_inttypes_strtoumax@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int libc_inttypes_main(void) {
  tc_libc_inttypes_imaxabs();
  tc_libc_inttypes_imaxdiv();
  tc_libc_inttypes_strtoimax();
  tc_libc_inttypes_strtoumax();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<libc_inttypes_main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <tc_libc_inttypes_imaxabs@plt>
  xor    %eax,%eax
  call   <tc_libc_inttypes_imaxdiv@plt>
  xor    %eax,%eax
  call   <tc_libc_inttypes_strtoimax@plt>
  xor    %eax,%eax
  call   <tc_libc_inttypes_strtoumax@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int libc_inttypes_main(void) {
  tc_libc_inttypes_imaxabs();
  tc_libc_inttypes_imaxdiv();
  tc_libc_inttypes_strtoimax();
  tc_libc_inttypes_strtoumax();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<utencclock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  imul   $0x3c,%eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double utencclock(hours, minutes, seconds)
int hours;
int minutes;
double seconds;
{ return (hours * 60 + minutes) * 60 + seconds; }
```
user: What would the C source look like for the assembly code provided here:

```asm
<utencclock>:
  endbr64
  movapd %xmm0,%xmm1
  imul   $0x3c,%edi,%edi
  add    %esi,%edi
  imul   $0x3c,%edi,%edi
  pxor   %xmm0,%xmm0
  cvtsi2sd %edi,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double utencclock(hours, minutes, seconds)
int hours;
int minutes;
double seconds;
{ return (hours * 60 + minutes) * 60 + seconds; }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utencclock>:
  endbr64
  imul   $0x3c,%edi,%edi
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  add    %esi,%edi
  imul   $0x3c,%edi,%edi
  cvtsi2sd %edi,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double utencclock(hours, minutes, seconds)
int hours;
int minutes;
double seconds;
{ return (hours * 60 + minutes) * 60 + seconds; }
```
user: What would the C source look like for the assembly code provided here?

```asm
<utencclock>:
  endbr64
  imul   $0x3c,%edi,%edi
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  add    %esi,%edi
  imul   $0x3c,%edi,%edi
  cvtsi2sd %edi,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double utencclock(hours, minutes, seconds)
int hours;
int minutes;
double seconds;
{ return (hours * 60 + minutes) * 60 + seconds; }
```
user: What would the C source look like for the assembly code provided here:

```asm
<aligned_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x8(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  je     L14
  mov    $0x0,%eax
  jmp    L15
L14:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <memalign@plt>
L15:
  leave
  ret
```

assistant: ```c
void *aligned_alloc(size_t alignment, size_t size) {
  if (size % alignment)
    return NULL;
  return memalign(alignment, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<aligned_alloc>:
  endbr64
  mov    %rsi,%rax
  mov    $0x0,%edx
  div    %rdi
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L7
  sub    $0x8,%rsp
  call   <memalign@plt>
  add    $0x8,%rsp
  ret
L7:
  ret
```

assistant: ```c
void *aligned_alloc(size_t alignment, size_t size) {
  if (size % alignment)
    return NULL;
  return memalign(alignment, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aligned_alloc>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rdi
  test   %rdx,%rdx
  jne    L2
  jmp    1050 <memalign@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *aligned_alloc(size_t alignment, size_t size) {
  if (size % alignment)
    return NULL;
  return memalign(alignment, size);
}
```
user: What is the c source code of the assembly code below:

```asm
<aligned_alloc>:
  endbr64
  mov    %rsi,%rax
  xor    %edx,%edx
  div    %rdi
  test   %rdx,%rdx
  jne    L9
  jmp    1050 <memalign@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
void *aligned_alloc(size_t alignment, size_t size) {
  if (size % alignment)
    return NULL;
  return memalign(alignment, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<list_splice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <list_empty@plt>
  test   %eax,%eax
  jne    L5
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__list_splice@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    __list_splice(list, head);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_splice>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L12
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__list_splice@plt>
  jmp    L19
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    __list_splice(list, head);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<list_splice>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L1
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <__list_splice@plt>
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    __list_splice(list, head);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<list_splice>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <list_empty@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <__list_splice@plt>
```

assistant: ```c
void list_splice(struct list_head *list, struct list_head *head) {
  if (!list_empty(list))
    __list_splice(list, head);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rand_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   $0x4,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff81020409,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x7,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  or     %edx,-0x14(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L11
L0:
  shll   $0x8,-0x14(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  or     %edx,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L11:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L0
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rand_int() {
  size_t byteSize = sizeof(int);
  int val = 0;
  val = val | rand() % 0x7F;
  for (size_t i = 1; i < byteSize; i++) {
    val = val << 8;
    val = val | (rand() % 0xFF);
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rand_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rbx
  imul   $0xffffffff81020409,%rbx,%rbx
  shr    $0x20,%rbx
  add    %eax,%ebx
  sar    $0x6,%ebx
  cltd
  sub    %edx,%ebx
  mov    %ebx,%edx
  shl    $0x7,%edx
  sub    %ebx,%edx
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    $0x3,%ebp
L3:
  shl    $0x8,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0xffffffff80808081,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x7,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  shl    $0x8,%ecx
  sub    %edx,%ecx
  sub    %ecx,%eax
  or     %eax,%ebx
  sub    $0x1,%rbp
  jne    L3
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rand_int() {
  size_t byteSize = sizeof(int);
  int val = 0;
  val = val | rand() % 0x7F;
  for (size_t i = 1; i < byteSize; i++) {
    val = val << 8;
    val = val | (rand() % 0xFF);
  }
  return val;
}
```