ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<JacobiOmpLoopV2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r15
  mov    (%r15),%ebx
  cmp    %r8d,%ebx
  jge    L80
  mov    %rdi,%r11
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %ecx,%r10d
  movapd %xmm0,%xmm4
  mov    %r8d,%r13d
  comisd %xmm0,%xmm0
  jb     L80
  lea    -0x3(%rdx),%eax
  lea    -0x3(%rcx),%edx
  lea    0x10(,%rdx,8),%r8
  lea    0x8(,%rax,8),%r14
  movsd  D6(%rip),%xmm3
  movq   D18(%rip),%xmm2
  pxor   %xmm5,%xmm5
  jmp    L1
L57:
  mov    %r9,-0x8(%rsp)
L0:
  mov    0x8(%rdx),%rsi
  mov    0x10(%rdx),%rcx
  mov    (%rdx),%r9
  movsd  (%r9,%rax,1),%xmm0
  addsd  (%rcx,%rax,1),%xmm0
  addsd  -0x8(%rsi,%rax,1),%xmm0
  mov    %rax,%rcx
  add    $0x8,%rax
  addsd  (%rsi,%rax,1),%xmm0
  mulsd  %xmm3,%xmm0
  mov    (%rdi),%rsi
  movsd  %xmm0,(%rsi,%rcx,1)
  mov    0x8(%rdx),%rsi
  mov    (%rdi),%r9
  movsd  (%r9,%rcx,1),%xmm0
  subsd  (%rsi,%rcx,1),%xmm0
  andpd  %xmm2,%xmm0
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmp    %r8,%rax
  jne    L0
  mov    -0x8(%rsp),%r9
L103:
  add    $0x8,%rdx
  add    $0x8,%rdi
  cmp    %r9,%rdx
  je     L98
L132:
  mov    $0x8,%eax
  cmp    $0x2,%r10d
  jg     L57
  jmp    L103
L98:
  comisd %xmm5,%xmm1
  jbe    L23
L22:
  add    $0x1,%ebx
  mov    %rbp,%rax
  mov    %r11,%rbp
  cmp    %ebx,%r13d
  jle    L116
  comisd %xmm4,%xmm1
  jb     L116
  mov    %rax,%r11
L1:
  cmp    $0x2,%r12d
  jle    L19
  mov    %r11,%rdx
  lea    0x8(%rbp),%rdi
  lea    (%r14,%r11,1),%r9
  pxor   %xmm1,%xmm1
  jmp    L132
L23:
  pxor   %xmm1,%xmm1
  jmp    L22
L19:
  pxor   %xmm1,%xmm1
  jmp    L22
L80:
  pxor   %xmm1,%xmm1
L116:
  mov    %ebx,(%r15)
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: f64
name: read_data
arguments: data_label: D18
data_type: qword

tool: D6: 0.25

tool: D18: 9223372036854775807

assistant: ```c
double JacobiOmpLoopV2(double **up, double **wp, int m, int n, double eps, int maxit, int iterations_print, int *iterations) {
  int i;
  int j;
  double **t;
  double diff;
  double my_diff;
  int my_iterations = *iterations;
  my_diff = eps;
#pragma omp parallel private(j) firstprivate(my_iterations, my_diff)
  {
    while (eps <= my_diff && my_iterations < maxit) {
      diff = 0.0;
      my_diff = 0.0;
#pragma omp for schedule(OMP_SCHED)
      for (i = 1; i < m - 1; i++) {
        for (j = 1; j < n - 1; j++) {
          wp[i][j] = 0.25 * (up[i - 1][j] + up[i + 1][j] + up[i][j - 1] + up[i][j + 1]);
          if (my_diff < fabs(wp[i][j] - up[i][j]))
            my_diff = fabs(wp[i][j] - up[i][j]);
        }
      }
      if (diff < my_diff)
#pragma omp atomic write
        diff = my_diff;
#pragma omp single
      {
        t = up;
        up = wp;
        wp = t;
      }
      my_iterations++;
      my_diff = diff;
#pragma omp barrier
    }
    *iterations = my_iterations;
  }
  return diff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<JacobiOmpLoopV2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r15
  mov    (%r15),%r12d
  cmp    %r8d,%r12d
  jge    L62
  comisd %xmm0,%xmm0
  movapd %xmm0,%xmm5
  pxor   %xmm4,%xmm4
  jb     L62
  mov    %r8d,%r14d
  lea    -0x3(%rdx),%ebp
  lea    -0x3(%rcx),%r8d
  mov    %edx,%r13d
  movsd  D3(%rip),%xmm3
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %ecx,%ebx
  movq   D1(%rip),%xmm2
  add    $0x2,%rbp
  add    $0x2,%r8
  cmp    $0x2,%r13d
  jle    L29
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%r9d
  movapd %xmm4,%xmm1
  nopw   0x0(%rax,%rax,1)
L111:
  cmp    $0x2,%ebx
  jle    L26
  mov    -0x8(%r10,%r9,8),%rdi
  mov    0x8(%r10,%r9,8),%rsi
  mov    $0x1,%eax
  mov    (%r10,%r9,8),%rdx
  mov    (%r11,%r9,8),%rcx
  nopl   0x0(%rax)
L55:
  movsd  (%rdi,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  subsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  andpd  %xmm2,%xmm0
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L55
L26:
  add    $0x1,%r9
  cmp    %r9,%rbp
  jne    L111
  comisd %xmm4,%xmm1
  jbe    L29
  add    $0x1,%r12d
  mov    %r11,%rax
  mov    %r10,%r11
  cmp    %r12d,%r14d
  jle    L53
L65:
  comisd %xmm5,%xmm1
  jb     L53
  mov    %rax,%r10
  cmp    $0x2,%r13d
  jg     L39
L29:
  add    $0x1,%r12d
  mov    %r11,%rax
  movapd %xmm4,%xmm1
  mov    %r10,%r11
  cmp    %r12d,%r14d
  jg     L65
L53:
  mov    %r12d,(%r15)
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L62:
  pxor   %xmm1,%xmm1
  jmp    L53
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: f64
name: retrieve_data
arguments: data_tag: D1
type_infered: qword

tool: D3: 0.25

tool: D1: 9223372036854775807

assistant: ```c
double JacobiOmpLoopV2(double **up, double **wp, int m, int n, double eps, int maxit, int iterations_print, int *iterations) {
  int i;
  int j;
  double **t;
  double diff;
  double my_diff;
  int my_iterations = *iterations;
  my_diff = eps;
#pragma omp parallel private(j) firstprivate(my_iterations, my_diff)
  {
    while (eps <= my_diff && my_iterations < maxit) {
      diff = 0.0;
      my_diff = 0.0;
#pragma omp for schedule(OMP_SCHED)
      for (i = 1; i < m - 1; i++) {
        for (j = 1; j < n - 1; j++) {
          wp[i][j] = 0.25 * (up[i - 1][j] + up[i + 1][j] + up[i][j - 1] + up[i][j + 1]);
          if (my_diff < fabs(wp[i][j] - up[i][j]))
            my_diff = fabs(wp[i][j] - up[i][j]);
        }
      }
      if (diff < my_diff)
#pragma omp atomic write
        diff = my_diff;
#pragma omp single
      {
        t = up;
        up = wp;
        wp = t;
      }
      my_iterations++;
      my_diff = diff;
#pragma omp barrier
    }
    *iterations = my_iterations;
  }
  return diff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<JacobiOmpLoopV2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r15
  mov    (%r15),%r12d
  cmp    %r8d,%r12d
  jge    L118
  comisd %xmm0,%xmm0
  movapd %xmm0,%xmm5
  jb     L118
  mov    %r8d,%r14d
  lea    -0x3(%rdx),%ebx
  lea    -0x3(%rcx),%r8d
  mov    %edx,%r13d
  mov    %rdi,%r10
  mov    %rsi,%r11
  lea    -0x1(%rcx),%ebp
  add    $0x2,%rbx
  movsd  D10(%rip),%xmm3
  movq   D0(%rip),%xmm2
  pxor   %xmm4,%xmm4
  add    $0x2,%r8
  cmp    $0x2,%r13d
  jle    L93
  nopl   0x0(%rax)
L95:
  mov    $0x1,%r9d
  movapd %xmm4,%xmm1
  nopw   0x0(%rax,%rax,1)
L85:
  cmp    $0x1,%ebp
  jle    L106
  mov    -0x8(%r10,%r9,8),%rdi
  mov    0x8(%r10,%r9,8),%rsi
  mov    $0x1,%eax
  mov    (%r10,%r9,8),%rdx
  mov    (%r11,%r9,8),%rcx
  nopl   0x0(%rax)
L45:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  subsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  andpd  %xmm2,%xmm0
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  cmp    %rax,%r8
  jne    L45
L106:
  add    $0x1,%r9
  cmp    %rbx,%r9
  jne    L85
  comisd %xmm4,%xmm1
  jbe    L93
  add    $0x1,%r12d
  mov    %r11,%rax
  mov    %r10,%r11
  cmp    %r12d,%r14d
  jle    L22
L86:
  comisd %xmm5,%xmm1
  jb     L22
  mov    %rax,%r10
  cmp    $0x2,%r13d
  jg     L95
L93:
  add    $0x1,%r12d
  mov    %r11,%rax
  movapd %xmm4,%xmm1
  mov    %r10,%r11
  cmp    %r12d,%r14d
  jg     L86
L22:
  mov    %r12d,(%r15)
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L118:
  pxor   %xmm1,%xmm1
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: label: D10
type: f64
name: disassemble_data
arguments: label: D0
type: qword

tool: D10: 0.25

tool: D0: 9223372036854775807

assistant: ```c
double JacobiOmpLoopV2(double **up, double **wp, int m, int n, double eps, int maxit, int iterations_print, int *iterations) {
  int i;
  int j;
  double **t;
  double diff;
  double my_diff;
  int my_iterations = *iterations;
  my_diff = eps;
#pragma omp parallel private(j) firstprivate(my_iterations, my_diff)
  {
    while (eps <= my_diff && my_iterations < maxit) {
      diff = 0.0;
      my_diff = 0.0;
#pragma omp for schedule(OMP_SCHED)
      for (i = 1; i < m - 1; i++) {
        for (j = 1; j < n - 1; j++) {
          wp[i][j] = 0.25 * (up[i - 1][j] + up[i + 1][j] + up[i][j - 1] + up[i][j + 1]);
          if (my_diff < fabs(wp[i][j] - up[i][j]))
            my_diff = fabs(wp[i][j] - up[i][j]);
        }
      }
      if (diff < my_diff)
#pragma omp atomic write
        diff = my_diff;
#pragma omp single
      {
        t = up;
        up = wp;
        wp = t;
      }
      my_iterations++;
      my_diff = diff;
#pragma omp barrier
    }
    *iterations = my_iterations;
  }
  return diff;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<min_clrbol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L3
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <min_putp@plt>
  mov    $0x0,%eax
  jmp    L1
L3:
  mov    $0x1,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int min_clrbol(void) {
  if (clr_bol) {
    min_putp(clr_bol);
    return 0;
  } else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<min_clrbol>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%rdi
  mov    $0x1,%eax
  test   %rdi,%rdi
  jne    L4
  ret
L4:
  sub    $0x8,%rsp
  call   <min_putp@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int min_clrbol(void) {
  if (clr_bol) {
    min_putp(clr_bol);
    return 0;
  } else
    return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<min_clrbol>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%rdi
  test   %rdi,%rdi
  jne    L9
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L9:
  sub    $0x8,%rsp
  call   <min_putp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int min_clrbol(void) {
  if (clr_bol) {
    min_putp(clr_bol);
    return 0;
  } else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<min_clrbol>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%rdi
  test   %rdi,%rdi
  jne    L7
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L7:
  sub    $0x8,%rsp
  call   <min_putp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int min_clrbol(void) {
  if (clr_bol) {
    min_putp(clr_bol);
    return 0;
  } else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movq   $0x51515151,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    $0x0,%eax
  call   *%rdx
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_guessed: string

tool: D1: crashexec


assistant: ```c
int main() {
  printf("crashexec\n");
  void (*fp)() = (void (*)())0x51515151;
  (*fp)();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    $0x51515151,%edx
  call   *%rdx
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
data_type: string

tool: D3: crashexec


assistant: ```c
int main() {
  printf("crashexec\n");
  void (*fp)() = (void (*)())0x51515151;
  (*fp)();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x51515151,%edx
  call   *%rdx
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string

tool: D9: crashexec


assistant: ```c
int main() {
  printf("crashexec\n");
  void (*fp)() = (void (*)())0x51515151;
  (*fp)();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  mov    $0x51515151,%edx
  call   *%rdx
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: crashexec


assistant: ```c
int main() {
  printf("crashexec\n");
  void (*fp)() = (void (*)())0x51515151;
  (*fp)();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_getline_ptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movb   $0x0,-0x9(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L0:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L10:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L31
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x9(%rbp)
  mov    D8(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x9(%rbp)
  je     L31
  cmpb   $0xa,-0x9(%rbp)
  jne    L0
L31:
  cmpb   $0xa,-0x9(%rbp)
  jne    L25
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L25:
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int _getline_ptr(char *s, int lim) {
  char c = '\0';
  char *p = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *s++ = c;
  if (c == '\n')
    *s++ = c;
  *s = '\0';
  return s - p;
}
```
user: What is the c source code of the assembly code below?

```asm
<_getline_ptr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  cmp    $0x1,%esi
  jle    L10
  lea    -0x2(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r12
  mov    %rdi,%rbx
L17:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    %al,(%rdx)
  je     L44
  cmp    $0xa,%al
  je     L44
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %r12,%rbx
  jne    L17
L49:
  mov    %r12,%rbx
L58:
  movb   $0x0,(%rbx)
  mov    %ebx,%eax
  sub    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  cmp    $0xa,%al
  jne    L58
  movb   $0xa,(%rbx)
  lea    0x1(%rbx),%rbx
  jmp    L58
L10:
  mov    %rdi,%r12
  jmp    L49
```

assistant: ```c
int _getline_ptr(char *s, int lim) {
  char c = '\0';
  char *p = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *s++ = c;
  if (c == '\n')
    *s++ = c;
  *s = '\0';
  return s - p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_getline_ptr>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L49
  lea    -0x2(%rsi),%eax
  mov    D0(%rip),%rbx
  mov    %rdi,%r13
  lea    0x1(%rdi,%rax,1),%rbp
  jmp    L32
  nop
L20:
  lea    0x1(%r13),%rdx
  mov    %rdx,%rcx
  cmp    $0xa,%al
  je     L46
  mov    %al,-0x1(%rdx)
  cmp    %rcx,%rbp
  je     L57
  mov    %rdx,%r13
L32:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,(%rbx)
  jne    L20
  lea    0x1(%r13),%rdx
  cmp    $0xa,%al
  je     L46
  mov    %r13d,%eax
  mov    %r13,%rcx
  sub    %r12d,%eax
L49:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  movb   $0xa,0x0(%r13)
  mov    %rdx,%rcx
L57:
  movb   $0x0,(%rcx)
  mov    %ecx,%eax
  add    $0x8,%rsp
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _getline_ptr(char *s, int lim) {
  char c = '\0';
  char *p = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *s++ = c;
  if (c == '\n')
    *s++ = c;
  *s = '\0';
  return s - p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_getline_ptr>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  xor    %eax,%eax
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L56
  lea    -0x2(%rsi),%eax
  mov    D7(%rip),%rbp
  mov    %rdi,%r13
  lea    0x1(%rdi,%rax,1),%rbx
  jmp    L19
  nop
L45:
  lea    0x1(%r13),%rdx
  mov    %rdx,%rcx
  cmp    $0xa,%al
  je     L21
  mov    %al,-0x1(%rdx)
  cmp    %rbx,%rcx
  je     L28
  mov    %rdx,%r13
L19:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %al,0x0(%rbp)
  jne    L45
  lea    0x1(%r13),%rdx
  cmp    $0xa,%al
  je     L21
  mov    %r13d,%eax
  mov    %r13,%rcx
  sub    %r12d,%eax
L56:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  mov    %rdx,%rcx
  movb   $0xa,0x0(%r13)
  mov    %edx,%eax
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  sub    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  movb   $0x0,(%rcx)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  sub    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int _getline_ptr(char *s, int lim) {
  char c = '\0';
  char *p = s;
  while (--lim > 0 && (c = getchar()) != EOF && c != '\n')
    *s++ = c;
  if (c == '\n')
    *s++ = c;
  *s = '\0';
  return s - p;
}
```
user: What is the c source code of the assembly code below?

```asm
<computeAllPairShortestPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L75
L74:
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L85:
  movl   $0x0,-0xc(%rbp)
  jmp    L92
L39:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L80
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L80
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  test   %eax,%eax
  je     L11
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L80
L11:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rcx,%rax,4)
L80:
  addl   $0x1,-0xc(%rbp)
L92:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L39
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L85
  addl   $0x1,-0x8(%rbp)
L75:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L74
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void computeAllPairShortestPath(int adjMat[][20], int numV) {
  int i, j, k, dist;
  for (k = 0; k < numV; k++)
    for (i = 0; i < numV; i++)
      for (j = 0; j < numV; j++) {
        if (adjMat[i][k] && adjMat[k][j]) {
          dist = adjMat[i][k] + adjMat[k][j];
          if (adjMat[i][j] == 0 || dist < adjMat[i][j])
            adjMat[i][j] = dist;
        }
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<computeAllPairShortestPath>:
  endbr64
  test   %esi,%esi
  jle    L108
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  lea    0x50(%rdi,%rax,1),%r11
  mov    %esi,%edi
  mov    %rdi,%r12
  neg    %r12
  shl    $0x2,%r12
  mov    %rbx,%rbp
  mov    $0x0,%r10d
  jmp    L18
L6:
  mov    %edx,(%r8,%rax,4)
L116:
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L105
L19:
  mov    (%rcx),%edx
  test   %edx,%edx
  je     L116
  mov    (%r9,%rax,4),%esi
  test   %esi,%esi
  je     L116
  add    %esi,%edx
  mov    (%r8,%rax,4),%esi
  cmp    %edx,%esi
  jg     L6
  test   %esi,%esi
  je     L6
  jmp    L116
L105:
  add    $0x50,%rcx
  cmp    %r11,%rcx
  je     L68
L51:
  lea    (%rcx,%r10,1),%r8
  mov    $0x0,%eax
  jmp    L19
L68:
  add    $0x4,%r11
  add    $0x50,%rbp
  sub    $0x4,%r10
  cmp    %r12,%r10
  je     L3
L18:
  mov    %rbp,%r9
  mov    %rbx,%rcx
  sub    %r10,%rcx
  jmp    L51
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L108:
  ret
```

assistant: ```c
void computeAllPairShortestPath(int adjMat[][20], int numV) {
  int i, j, k, dist;
  for (k = 0; k < numV; k++)
    for (i = 0; i < numV; i++)
      for (j = 0; j < numV; j++) {
        if (adjMat[i][k] && adjMat[k][j]) {
          dist = adjMat[i][k] + adjMat[k][j];
          if (adjMat[i][j] == 0 || dist < adjMat[i][j])
            adjMat[i][j] = dist;
        }
      }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<computeAllPairShortestPath>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  test   %edi,%edi
  jle    L8
  lea    -0x1(%rdi),%eax
  mov    %rdi,%rbp
  mov    %rbx,%r9
  xor    %r10d,%r10d
  lea    (%rax,%rax,4),%rax
  neg    %rbp
  shl    $0x4,%rax
  shl    $0x2,%rbp
  lea    0x50(%rbx,%rax,1),%r11
  nopl   0x0(%rax,%rax,1)
L38:
  mov    %rbx,%rcx
  sub    %r10,%rcx
  xchg   %ax,%ax
L78:
  lea    (%rcx,%r10,1),%r8
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%rcx),%edx
  test   %edx,%edx
  je     L39
  mov    (%r9,%rax,4),%esi
  test   %esi,%esi
  je     L39
  add    %esi,%edx
  mov    (%r8,%rax,4),%esi
  test   %esi,%esi
  je     L43
  cmp    %edx,%esi
  jle    L39
L43:
  mov    %edx,(%r8,%rax,4)
L39:
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L4
  add    $0x50,%rcx
  cmp    %r11,%rcx
  jne    L78
  sub    $0x4,%r10
  add    $0x4,%r11
  add    $0x50,%r9
  cmp    %rbp,%r10
  jne    L38
L8:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void computeAllPairShortestPath(int adjMat[][20], int numV) {
  int i, j, k, dist;
  for (k = 0; k < numV; k++)
    for (i = 0; i < numV; i++)
      for (j = 0; j < numV; j++) {
        if (adjMat[i][k] && adjMat[k][j]) {
          dist = adjMat[i][k] + adjMat[k][j];
          if (adjMat[i][j] == 0 || dist < adjMat[i][j])
            adjMat[i][j] = dist;
        }
      }
}
```