ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<underline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L10
L17:
  mov    $0x3d,%edi
  call   <putchar@plt>
L10:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void underline(char *array) {
  puts(array);
  while (*array++) {
    putchar('=');
  }
  putchar('\n');
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<underline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <puts@plt>
  lea    0x1(%rbp),%rbx
  cmpb   $0x0,0x0(%rbp)
  je     L11
L2:
  mov    $0x3d,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmpb   $0x0,-0x1(%rbx)
  jne    L2
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void underline(char *array) {
  puts(array);
  while (*array++) {
    putchar('=');
  }
  putchar('\n');
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<underline>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  cmpb   $0x0,0x0(%rbp)
  je     L4
  lea    0x1(%rbp),%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x3d,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmpb   $0x0,-0x1(%rbx)
  jne    L6
L4:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

assistant: ```c
void underline(char *array) {
  puts(array);
  while (*array++) {
    putchar('=');
  }
  putchar('\n');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<underline>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  cmpb   $0x0,0x0(%rbp)
  je     L11
  lea    0x1(%rbp),%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x3d,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmpb   $0x0,-0x1(%rbx)
  jne    L6
L11:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

assistant: ```c
void underline(char *array) {
  puts(array);
  while (*array++) {
    putchar('=');
  }
  putchar('\n');
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <start_measurement@plt>
  mov    $0x3e8,%edi
  call   <dot_product@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <end_measurement@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <print_float@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  start_measurement();
  float res = dot_product(1000);
  end_measurement();
  print_float(res);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x0,%eax
  call   <start_measurement@plt>
  mov    $0x3e8,%edi
  call   <dot_product@plt>
  movss  %xmm0,0xc(%rsp)
  mov    $0x0,%eax
  call   <end_measurement@plt>
  movss  0xc(%rsp),%xmm0
  call   <print_float@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main() {
  start_measurement();
  float res = dot_product(1000);
  end_measurement();
  print_float(res);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <start_measurement@plt>
  mov    $0x3e8,%edi
  call   <dot_product@plt>
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  call   <end_measurement@plt>
  movss  0xc(%rsp),%xmm0
  call   <print_float@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main() {
  start_measurement();
  float res = dot_product(1000);
  end_measurement();
  print_float(res);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %eax,%eax
  call   <start_measurement@plt>
  mov    $0x3e8,%edi
  call   <dot_product@plt>
  xor    %eax,%eax
  movss  %xmm0,0xc(%rsp)
  call   <end_measurement@plt>
  movss  0xc(%rsp),%xmm0
  call   <print_float@plt>
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
```

assistant: ```c
int main() {
  start_measurement();
  float res = dot_product(1000);
  end_measurement();
  print_float(res);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ancestralGamma>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x20(%rsp)
  mov    %rsi,%r15
  mov    %rdx,%rbp
  mov    %ecx,0xc(%rsp)
  mov    %r8d,%ebx
  mov    %r9d,%r13d
  mov    %r8d,%eax
  imul   %r8d,%eax
  mov    %eax,0x8(%rsp)
  movslq %r8d,%r14
  mov    %r14,0x10(%rsp)
  lea    0x0(,%r8,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  cmpl   $0x0,0xc(%rsp)
  jle    L48
  movslq %r13d,%rax
  mov    %rax,0x18(%rsp)
  lea    -0x1(%rbx),%edi
  lea    0x8(%r12,%rdi,8),%r9
  lea    0x0(,%r14,8),%r10
  mov    $0x0,%r14d
  movq   $0x0,(%rsp)
  mov    $0x0,%r13d
  sub    %r12,%r15
  mov    %r15,0x28(%rsp)
  jmp    L5
L3:
  test   %ebx,%ebx
  jle    L79
  mov    0x28(%rsp),%rax
  lea    (%rax,%r14,8),%rdx
  mov    %r12,%rax
L94:
  movsd  (%rax),%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %r9,%rax
  jne    L94
L79:
  add    $0x1,%r13d
  mov    0x18(%rsp),%rsi
  add    %rsi,(%rsp)
  add    0x10(%rsp),%r14
  cmp    %r13d,0xc(%rsp)
  je     L48
L5:
  test   %ebx,%ebx
  jle    L18
  mov    %r12,%rax
L33:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %r9,%rax
  jne    L33
L18:
  mov    0x20(%rsp),%rax
  mov    (%rsp),%rsi
  lea    (%rax,%rsi,8),%rsi
  mov    $0x0,%r15d
  mov    $0x4,%r11d
  pxor   %xmm2,%xmm2
L72:
  test   %ebx,%ebx
  jle    L59
  movslq %r15d,%rax
  lea    0x0(%rbp,%rax,8),%rcx
  mov    %r12,%r8
L112:
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L116:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rdi,%rdx
  jne    L116
  movapd %xmm1,%xmm0
  addsd  (%r8),%xmm0
  movsd  %xmm0,(%r8)
  addsd  %xmm1,%xmm2
  add    $0x8,%r8
  add    %r10,%rcx
  cmp    %r9,%r8
  jne    L112
L59:
  add    %r10,%rsi
  add    0x8(%rsp),%r15d
  sub    $0x1,%r11d
  jne    L72
  jmp    L3
L48:
  mov    %r12,%rdi
  call   <free@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ancestralGamma(double *x3, double *ancestralBuffer, double *diagptable, const int n, const int numStates, const int gammaStates) {
  int i;
  const int statesSquare = numStates * numStates;
  double *term = (double *)malloc(sizeof(double) * numStates);
  for (i = 0; i < n; i++) {
    double sum = 0.0, *_v = &x3[gammaStates * i], *ancestral = &ancestralBuffer[numStates * i];
    int k, j, l;
    for (l = 0; l < numStates; l++)
      term[l] = 0.0;
    for (k = 0; k < 4; k++) {
      double *v = &(_v[numStates * k]);
      for (l = 0; l < numStates; l++) {
        double al = 0.0;
        for (j = 0; j < numStates; j++)
          al += v[j] * diagptable[k * statesSquare + l * numStates + j];
        term[l] += al;
        sum += al;
      }
    }
    for (l = 0; l < numStates; l++)
      ancestral[l] = term[l] / sum;
  }
  free(term);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ancestralGamma>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  movslq %r8d,%rbp
  push   %rbx
  mov    %ebp,%r8d
  mov    %r9d,%ebx
  imul   %ebp,%r8d
  sub    $0x48,%rsp
  mov    %rdi,0x28(%rsp)
  lea    0x0(,%rbp,8),%edi
  mov    %ecx,0x34(%rsp)
  mov    %r8d,0x8(%rsp)
  mov    %rbp,0x10(%rsp)
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %r12d,%r12d
  jle    L19
  movslq %ebx,%rax
  lea    -0x1(%rbp),%ebx
  sub    %rdi,%r15
  mov    %rbp,%r13
  mov    %rax,0x20(%rsp)
  lea    0x8(,%rbx,8),%rax
  xor    %r9d,%r9d
  pxor   %xmm3,%xmm3
  mov    %rax,0x18(%rsp)
  lea    0x0(,%rbp,8),%r12
  lea    (%rdi,%rax,1),%rbp
  movq   $0x0,(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    %r15,0x38(%rsp)
  mov    0x8(%rsp),%r15d
L42:
  test   %r13d,%r13d
  jle    L79
  mov    0x18(%rsp),%rdx
  xor    %esi,%esi
  mov    %r9,0x8(%rsp)
  call   <memset@plt>
  mov    0x8(%rsp),%r9
  pxor   %xmm3,%xmm3
  mov    %rax,%rdi
L79:
  mov    0x28(%rsp),%rax
  xor    %r11d,%r11d
  mov    $0x4,%r10d
  movapd %xmm3,%xmm2
  lea    (%rax,%r9,8),%rsi
L2:
  test   %r13d,%r13d
  jle    L84
  movslq %r11d,%rax
  mov    %rdi,%r8
  lea    (%r14,%rax,8),%rcx
  nopl   (%rax)
L10:
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  xchg   %ax,%ax
L85:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rcx,%rax,8),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rbx,%rdx
  jne    L85
  movsd  (%r8),%xmm0
  add    $0x8,%r8
  addsd  %xmm1,%xmm2
  add    %r12,%rcx
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%r8)
  cmp    %r8,%rbp
  jne    L10
L84:
  add    %r12,%rsi
  add    %r15d,%r11d
  sub    $0x1,%r10d
  jne    L2
  test   %r13d,%r13d
  jle    L83
  mov    0x38(%rsp),%rax
  mov    (%rsp),%rsi
  lea    (%rax,%rsi,8),%rdx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L57:
  movsd  (%rax),%xmm0
  divsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %rax,%rbp
  jne    L57
L83:
  addl   $0x1,0x30(%rsp)
  mov    0x10(%rsp),%rcx
  mov    0x30(%rsp),%eax
  add    %rcx,(%rsp)
  add    0x20(%rsp),%r9
  cmp    %eax,0x34(%rsp)
  jne    L42
L19:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <free@plt>
```

assistant: ```c
void ancestralGamma(double *x3, double *ancestralBuffer, double *diagptable, const int n, const int numStates, const int gammaStates) {
  int i;
  const int statesSquare = numStates * numStates;
  double *term = (double *)malloc(sizeof(double) * numStates);
  for (i = 0; i < n; i++) {
    double sum = 0.0, *_v = &x3[gammaStates * i], *ancestral = &ancestralBuffer[numStates * i];
    int k, j, l;
    for (l = 0; l < numStates; l++)
      term[l] = 0.0;
    for (k = 0; k < 4; k++) {
      double *v = &(_v[numStates * k]);
      for (l = 0; l < numStates; l++) {
        double al = 0.0;
        for (j = 0; j < numStates; j++)
          al += v[j] * diagptable[k * statesSquare + l * numStates + j];
        term[l] += al;
        sum += al;
      }
    }
    for (l = 0; l < numStates; l++)
      ancestral[l] = term[l] / sum;
  }
  free(term);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<readtxtbin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L47:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  subq   $0x1,-0x28(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jae    L16
  mov    $0x0,%eax
  jmp    L18
L16:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jae    L53
  mov    $0x0,%eax
  jmp    L18
L53:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  sub    %rax,-0x28(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  sub    %rax,-0x38(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L27:
  cmpq   $0x0,-0x28(%rbp)
  jne    L47
  mov    -0x10(%rbp),%eax
L18:
  leave
  ret
```

assistant: ```c
int readtxtbin(char *packet, char **src, size_t srcremain, char *dst, size_t dstremain) {
  unsigned char *uc;
  int tocopy;
  int dstused = 0;
  while (srcremain > 0) {
    uc = (unsigned char *)(*src);
    tocopy = *uc;
    (*src)++;
    srcremain--;
    if (tocopy > srcremain)
      return 0;
    if (tocopy > dstremain)
      return 0;
    memcpy(dst, *src, tocopy);
    dst += tocopy;
    (*src) += tocopy;
    srcremain -= tocopy;
    dstremain -= tocopy;
    dstused += tocopy;
  }
  return dstused;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readtxtbin>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdx,%rdx
  je     L28
  mov    %rsi,%r13
  mov    %rcx,%r14
  mov    %r8,%r12
  mov    (%rsi),%rax
  movzbl (%rax),%ebx
  movzbl %bl,%r15d
  lea    0x1(%rax),%rsi
  mov    %rsi,0x0(%r13)
  lea    -0x1(%rdx),%rbp
  movzbl %bl,%ebx
  cmp    %rbp,%r8
  mov    %rbp,%rax
  cmovbe %r8,%rax
  cmp    %rbx,%rax
  jb     L36
  movl   $0x0,0xc(%rsp)
L59:
  mov    %r15d,%edx
  mov    %r14,%rdi
  call   <memcpy@plt>
  add    %rbx,%r14
  mov    %rbx,%rax
  add    0x0(%r13),%rax
  mov    %rax,0x0(%r13)
  sub    %rbx,%r12
  add    %r15d,0xc(%rsp)
  sub    %rbx,%rbp
  je     L42
  movzbl (%rax),%ebx
  movzbl %bl,%r15d
  lea    0x1(%rax),%rsi
  mov    %rsi,0x0(%r13)
  sub    $0x1,%rbp
  movzbl %bl,%ebx
  cmp    %r12,%rbp
  mov    %r12,%rax
  cmovbe %rbp,%rax
  cmp    %rax,%rbx
  jbe    L59
  movl   $0x0,0xc(%rsp)
L42:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  movl   $0x0,0xc(%rsp)
  jmp    L42
L36:
  movl   $0x0,0xc(%rsp)
  jmp    L42
```

assistant: ```c
int readtxtbin(char *packet, char **src, size_t srcremain, char *dst, size_t dstremain) {
  unsigned char *uc;
  int tocopy;
  int dstused = 0;
  while (srcremain > 0) {
    uc = (unsigned char *)(*src);
    tocopy = *uc;
    (*src)++;
    srcremain--;
    if (tocopy > srcremain)
      return 0;
    if (tocopy > dstremain)
      return 0;
    memcpy(dst, *src, tocopy);
    dst += tocopy;
    (*src) += tocopy;
    srcremain -= tocopy;
    dstremain -= tocopy;
    dstused += tocopy;
  }
  return dstused;
}
```
user: What is the c source code of the assembly code below:

```asm
<readtxtbin>:
  endbr64
  test   %rdx,%rdx
  je     L9
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%rax
  cmp    %rbp,%r8
  movzbl (%rax),%r15d
  lea    0x1(%rax),%rsi
  mov    %rbp,%rax
  cmovbe %r8,%rax
  mov    %rsi,0x0(%r13)
  mov    %r15,%rbx
  cmp    %r15,%rax
  jb     L37
  mov    %rcx,%r14
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L18:
  mov    %r14,%rdi
  mov    %r15d,%edx
  mov    %r8d,0xc(%rsp)
  add    %rbx,%r14
  call   <memcpy@plt>
  mov    0x0(%r13),%rax
  mov    0xc(%rsp),%r8d
  sub    %rbx,%r12
  add    %rbx,%rax
  add    %r15d,%r8d
  mov    %rax,0x0(%r13)
  sub    %rbx,%rbp
  je     L31
  sub    $0x1,%rbp
  movzbl (%rax),%r15d
  lea    0x1(%rax),%rsi
  mov    %r12,%rax
  cmp    %r12,%rbp
  mov    %rsi,0x0(%r13)
  cmovbe %rbp,%rax
  mov    %r15,%rbx
  cmp    %rax,%r15
  jbe    L18
L37:
  xor    %r8d,%r8d
L31:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readtxtbin(char *packet, char **src, size_t srcremain, char *dst, size_t dstremain) {
  unsigned char *uc;
  int tocopy;
  int dstused = 0;
  while (srcremain > 0) {
    uc = (unsigned char *)(*src);
    tocopy = *uc;
    (*src)++;
    srcremain--;
    if (tocopy > srcremain)
      return 0;
    if (tocopy > dstremain)
      return 0;
    memcpy(dst, *src, tocopy);
    dst += tocopy;
    (*src) += tocopy;
    srcremain -= tocopy;
    dstremain -= tocopy;
    dstused += tocopy;
  }
  return dstused;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<readtxtbin>:
  endbr64
  test   %rdx,%rdx
  je     L38
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %r8,%r12
  push   %rbp
  lea    -0x1(%rdx),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rsi),%rax
  cmp    %rbp,%r8
  movzbl (%rax),%r15d
  lea    0x1(%rax),%rsi
  mov    %rbp,%rax
  cmovbe %r8,%rax
  mov    %rsi,0x0(%r13)
  mov    %r15,%rbx
  cmp    %r15,%rax
  jb     L26
  mov    %rcx,%r14
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L12:
  mov    %r14,%rdi
  mov    %r15d,%edx
  mov    %r8d,0xc(%rsp)
  add    %rbx,%r14
  call   <memcpy@plt>
  mov    0x0(%r13),%rax
  mov    0xc(%rsp),%r8d
  sub    %rbx,%r12
  add    %rbx,%rax
  add    %r15d,%r8d
  mov    %rax,0x0(%r13)
  sub    %rbx,%rbp
  je     L27
  sub    $0x1,%rbp
  movzbl (%rax),%r15d
  lea    0x1(%rax),%rsi
  mov    %r12,%rax
  cmp    %r12,%rbp
  mov    %rsi,0x0(%r13)
  cmovbe %rbp,%rax
  mov    %r15,%rbx
  cmp    %rax,%r15
  jbe    L12
L26:
  xor    %r8d,%r8d
L27:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readtxtbin(char *packet, char **src, size_t srcremain, char *dst, size_t dstremain) {
  unsigned char *uc;
  int tocopy;
  int dstused = 0;
  while (srcremain > 0) {
    uc = (unsigned char *)(*src);
    tocopy = *uc;
    (*src)++;
    srcremain--;
    if (tocopy > srcremain)
      return 0;
    if (tocopy > dstremain)
      return 0;
    memcpy(dst, *src, tocopy);
    dst += tocopy;
    (*src) += tocopy;
    srcremain -= tocopy;
    dstremain -= tocopy;
    dstused += tocopy;
  }
  return dstused;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LoadInt64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0x7,%eax
  test   %rax,%rax
  je     L1
  mov    $0x0,%eax
  call   <panicUnaligned@plt>
L1:
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <__atomic_load_n@plt>
  leave
  ret
```

assistant: ```c
int64_t LoadInt64(int64_t *addr) {
  if (((uintptr_t)addr & 7) != 0)
    panicUnaligned();
  return __atomic_load_n(addr, 5);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<LoadInt64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   $0x7,%dil
  jne    L16
L17:
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <__atomic_load_n@plt>
  pop    %rbx
  ret
L16:
  mov    $0x0,%eax
  call   <panicUnaligned@plt>
  jmp    L17
```

assistant: ```c
int64_t LoadInt64(int64_t *addr) {
  if (((uintptr_t)addr & 7) != 0)
    panicUnaligned();
  return __atomic_load_n(addr, 5);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<LoadInt64>:
  endbr64
  test   $0x7,%dil
  jne    L0
  mov    $0x5,%esi
  jmp    1060 <__atomic_load_n@plt>
  nopl   0x0(%rax)
L0:
  sub    $0x18,%rsp
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <panicUnaligned@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x5,%esi
  add    $0x18,%rsp
  jmp    1060 <__atomic_load_n@plt>
```

assistant: ```c
int64_t LoadInt64(int64_t *addr) {
  if (((uintptr_t)addr & 7) != 0)
    panicUnaligned();
  return __atomic_load_n(addr, 5);
}
```
user: What is the c source code of the assembly code below:

```asm
<LoadInt64>:
  endbr64
  test   $0x7,%dil
  jne    L2
  mov    $0x5,%esi
  jmp    1060 <__atomic_load_n@plt>
  nopl   0x0(%rax)
L2:
  sub    $0x18,%rsp
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  call   <panicUnaligned@plt>
  mov    0x8(%rsp),%rdi
  mov    $0x5,%esi
  add    $0x18,%rsp
  jmp    1060 <__atomic_load_n@plt>
```

assistant: ```c
int64_t LoadInt64(int64_t *addr) {
  if (((uintptr_t)addr & 7) != 0)
    panicUnaligned();
  return __atomic_load_n(addr, 5);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<opcode_bbb_set_addr_mode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  andb   $0x7,-0x8(%rbp)
  movzbl -0x8(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  movzbl -0x4(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char opcode_bbb_set_addr_mode(unsigned char base, unsigned char addr_mode) {
  addr_mode = addr_mode & 0x7;
  return base | (addr_mode << 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<opcode_bbb_set_addr_mode>:
  endbr64
  and    $0x7,%esi
  shl    $0x2,%esi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned char opcode_bbb_set_addr_mode(unsigned char base, unsigned char addr_mode) {
  addr_mode = addr_mode & 0x7;
  return base | (addr_mode << 2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<opcode_bbb_set_addr_mode>:
  endbr64
  and    $0x7,%esi
  mov    %edi,%eax
  shl    $0x2,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned char opcode_bbb_set_addr_mode(unsigned char base, unsigned char addr_mode) {
  addr_mode = addr_mode & 0x7;
  return base | (addr_mode << 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pr_conversion>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rsi
  mov    $0x28,%edi
  mov    $0x0,%eax
  call   <find@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <match_bracket@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L22
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L22:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    $0x4,%edx
  lea    D24(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L18
L37:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    %rcx,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L18:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D26
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D36
type: string

tool: D26: eval( %s);

tool: D24: dist

tool: D23: dist( %s);

tool: D36: fprint( outfile, "%%%s", %s);

assistant: ```c
char *pr_conversion(str)
char *str;
{
  char *start, *ptr, *match_bracket(), *find();
  start = find('(', str + 1);
  *start++ = '\0';
  ptr = match_bracket(start);
  *ptr = '\0';
  if (*(str + 1) == '$')
    printf("eval( %s);", start);
  else if (strncmp(str + 1, "dist", 4) == 0)
    printf("dist( %s);", start);
  else
    printf("fprint( outfile, \"%%%s\", %s);", str + 1, start);
  return (ptr + 1);
}
```