ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<fatfs_lfn_entries_required>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  je     L7
  lea    0xc(%rax),%edx
  movslq %edx,%r8
  mov    %edx,%eax
  imul   $0x4ec4ec4f,%r8,%r8
  sar    $0x1f,%eax
  sar    $0x22,%r8
  sub    %eax,%r8d
L7:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fatfs_lfn_entries_required(char *filename) {
  int length = (int)strlen(filename);
  if (length)
    return (length + 13 - 1) / 13;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fatfs_lfn_entries_required>:
  endbr64
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%r8d
  test   %eax,%eax
  je     L2
  lea    0xc(%rax),%edx
  movslq %edx,%r8
  mov    %edx,%eax
  imul   $0x4ec4ec4f,%r8,%r8
  sar    $0x1f,%eax
  sar    $0x22,%r8
  sub    %eax,%r8d
L2:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int fatfs_lfn_entries_required(char *filename) {
  int length = (int)strlen(filename);
  if (length)
    return (length + 13 - 1) / 13;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pcm_SL24_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L11
L23:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L28
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  lea    -0x1000000(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L22
L28:
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L22:
  addq   $0x3,-0x10(%rbp)
  addq   $0x4,-0x18(%rbp)
  subl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x0,-0x4(%rbp)
  jne    L23
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pcm_SL24_to_int(unsigned total_samples, const unsigned char pcm_samples[], int int_samples[]) {
  for (; total_samples; total_samples--) {
    if (pcm_samples[2] & 0x80) {
      int_samples[0] = -(int)(0x1000000 - ((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]));
    } else {
      int_samples[0] = (int)((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]);
    }
    pcm_samples += 3;
    int_samples += 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pcm_SL24_to_int>:
  endbr64
  mov    %rsi,%rcx
  mov    %rdx,%rsi
  test   %edi,%edi
  je     L23
  mov    %edi,%edi
  lea    (%rdi,%rdi,2),%rdi
  add    %rcx,%rdi
  jmp    L13
L30:
  movzbl 0x1(%rcx),%eax
  shl    $0x8,%eax
  movzbl %dl,%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl (%rcx),%edx
  or     %edx,%eax
L31:
  mov    %eax,(%rsi)
  add    $0x3,%rcx
  add    $0x4,%rsi
  cmp    %rcx,%rdi
  je     L23
L13:
  movzbl 0x2(%rcx),%edx
  test   %dl,%dl
  jns    L30
  movzbl 0x1(%rcx),%eax
  shl    $0x8,%eax
  movzbl %dl,%edx
  shl    $0x10,%edx
  or     %edx,%eax
  movzbl (%rcx),%edx
  or     %edx,%eax
  sub    $0x1000000,%eax
  jmp    L31
L23:
  ret
```

assistant: ```c
void pcm_SL24_to_int(unsigned total_samples, const unsigned char pcm_samples[], int int_samples[]) {
  for (; total_samples; total_samples--) {
    if (pcm_samples[2] & 0x80) {
      int_samples[0] = -(int)(0x1000000 - ((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]));
    } else {
      int_samples[0] = (int)((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]);
    }
    pcm_samples += 3;
    int_samples += 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pcm_SL24_to_int>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rcx
  lea    (%rdx,%rax,4),%r8
  test   %edi,%edi
  je     L19
  nopl   0x0(%rax)
L8:
  movzbl 0x2(%rcx),%esi
  movzbl 0x1(%rcx),%eax
  mov    %esi,%edi
  shl    $0x8,%eax
  shl    $0x10,%esi
  or     %esi,%eax
  movzbl (%rcx),%esi
  or     %esi,%eax
  test   %dil,%dil
  lea    -0x1000000(%rax),%esi
  cmovs  %esi,%eax
  add    $0x4,%rdx
  add    $0x3,%rcx
  mov    %eax,-0x4(%rdx)
  cmp    %r8,%rdx
  jne    L8
L19:
  ret
```

assistant: ```c
void pcm_SL24_to_int(unsigned total_samples, const unsigned char pcm_samples[], int int_samples[]) {
  for (; total_samples; total_samples--) {
    if (pcm_samples[2] & 0x80) {
      int_samples[0] = -(int)(0x1000000 - ((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]));
    } else {
      int_samples[0] = (int)((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]);
    }
    pcm_samples += 3;
    int_samples += 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pcm_SL24_to_int>:
  endbr64
  mov    %edi,%eax
  mov    %rsi,%rcx
  lea    (%rdx,%rax,4),%r8
  test   %edi,%edi
  je     L15
  nopl   0x0(%rax)
L11:
  movzbl 0x2(%rcx),%esi
  movzbl 0x1(%rcx),%eax
  mov    %esi,%edi
  shl    $0x8,%eax
  shl    $0x10,%esi
  or     %esi,%eax
  movzbl (%rcx),%esi
  or     %esi,%eax
  test   %dil,%dil
  lea    -0x1000000(%rax),%esi
  cmovs  %esi,%eax
  add    $0x4,%rdx
  add    $0x3,%rcx
  mov    %eax,-0x4(%rdx)
  cmp    %r8,%rdx
  jne    L11
L15:
  ret
```

assistant: ```c
void pcm_SL24_to_int(unsigned total_samples, const unsigned char pcm_samples[], int int_samples[]) {
  for (; total_samples; total_samples--) {
    if (pcm_samples[2] & 0x80) {
      int_samples[0] = -(int)(0x1000000 - ((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]));
    } else {
      int_samples[0] = (int)((pcm_samples[2] << 16) | (pcm_samples[1] << 8) | pcm_samples[0]);
    }
    pcm_samples += 3;
    int_samples += 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<deslash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L2
  lea    0x1(%rdi),%rbx
  mov    %rdi,%rdx
  lea    D3(%rip),%r12
  jmp    L170
L52:
  lea    0x1(%rdx),%rax
  mov    %rax,(%rsp)
  movzbl 0x1(%rdx),%eax
  cmp    $0x78,%al
  ja     L140
  cmp    $0x61,%al
  jbe    L136
  sub    $0x62,%eax
  cmp    $0x16,%al
  ja     L140
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
L136:
  cmp    $0x30,%al
  je     L35
  sub    $0x31,%eax
  cmp    $0x8,%al
  ja     L140
  mov    %rsp,%rdi
  mov    $0xa,%esi
  call   <get_char_code@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  mov    %dl,-0x1(%rbx)
L146:
  mov    (%rsp),%rdx
  movzbl (%rdx),%ecx
  add    $0x1,%rbx
  test   %cl,%cl
  je     L133
L170:
  cmp    $0x5c,%cl
  je     L52
  lea    0x1(%rdx),%rax
  mov    %rax,(%rsp)
  mov    %rbx,%rax
  movzbl (%rdx),%edx
  mov    %dl,-0x1(%rbx)
  jmp    L146
  mov    %rbx,%rax
  movb   $0xa,-0x1(%rbx)
  add    $0x2,%rdx
  mov    %rdx,(%rsp)
  jmp    L146
  mov    %rbx,%rax
  movb   $0xd,-0x1(%rbx)
  add    $0x2,%rdx
  mov    %rdx,(%rsp)
  jmp    L146
  mov    %rbx,%rax
  movb   $0x9,-0x1(%rbx)
  add    $0x2,%rdx
  mov    %rdx,(%rsp)
  jmp    L146
  mov    %rbx,%rax
  movb   $0x8,-0x1(%rbx)
  add    $0x2,%rdx
  mov    %rdx,(%rsp)
  jmp    L146
  add    $0x2,%rdx
  mov    %rdx,(%rsp)
  mov    %rsp,%rdi
  mov    $0x10,%esi
  call   <get_char_code@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  mov    %dl,-0x1(%rbx)
  jmp    L146
L35:
  mov    %rsp,%rdi
  mov    $0x8,%esi
  call   <get_char_code@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  mov    %dl,-0x1(%rbx)
  jmp    L146
L140:
  lea    0x2(%rdx),%rax
  mov    %rax,(%rsp)
  mov    %rbx,%rax
  movzbl 0x1(%rdx),%edx
  mov    %dl,-0x1(%rbx)
  jmp    L146
L2:
  mov    %rdi,%rax
L133:
  movb   $0x0,(%rax)
  sub    %ebp,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int deslash(unsigned char *str) {
  unsigned char *wp, *rp;
  rp = wp = str;
  while (*rp) {
    if (*rp != '\\')
      *wp++ = *rp++;
    else {
      switch (*++rp) {
      case 'n':
        *wp++ = 10;
        ++rp;
        break;
      case 'r':
        *wp++ = 13;
        ++rp;
        break;
      case 't':
        *wp++ = 9;
        ++rp;
        break;
      case 'b':
        *wp++ = 8;
        ++rp;
        break;
      case 'x':
        ++rp;
        *wp++ = get_char_code(&rp, 16);
        break;
      case '0':
        *wp++ = get_char_code(&rp, 8);
        break;
      case '1':
      case '2':
      case '3':
      case '4':
      case '5':
      case '6':
      case '7':
      case '8':
      case '9':
        *wp++ = get_char_code(&rp, 10);
        break;
      default:
        *wp++ = *rp++;
        break;
      }
    }
  }
  *wp = '\0';
  return wp - str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<font_draw_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %al,-0x4(%rbp)
  cmpb   $0xa,-0x4(%rbp)
  je     L12
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <font_get_bitmap@plt>
  mov    %eax,%edi
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%r9
  mov    $0xe,%r8d
  mov    $0x7,%ecx
  mov    %rax,%rsi
  call   <gfx_draw_bitmap_transparent@plt>
  jmp    L6
L12:
  nop
L6:
  leave
  ret
```

assistant: ```c
void font_draw_char(char character, long x, long y, long color) {
  if (character == '\n') {
    return;
  }
  gfx_draw_bitmap_transparent(font_get_bitmap(character), x, y, 7, 14, color);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<font_draw_char>:
  endbr64
  cmp    $0xa,%dil
  je     L3
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  movsbl %dil,%edi
  call   <font_get_bitmap@plt>
  mov    %eax,%edi
  mov    %r12,%r9
  mov    $0xe,%r8d
  mov    $0x7,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <gfx_draw_bitmap_transparent@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void font_draw_char(char character, long x, long y, long color) {
  if (character == '\n') {
    return;
  }
  gfx_draw_bitmap_transparent(font_get_bitmap(character), x, y, 7, 14, color);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<font_draw_char>:
  endbr64
  cmp    $0xa,%dil
  je     L8
  push   %r12
  movsbl %dil,%edi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <font_get_bitmap@plt>
  mov    %rbx,%r9
  mov    %r12,%rdx
  pop    %rbx
  mov    %rbp,%rsi
  mov    %eax,%edi
  pop    %rbp
  mov    $0xe,%r8d
  mov    $0x7,%ecx
  pop    %r12
  jmp    1060 <gfx_draw_bitmap_transparent@plt>
  nop
L8:
  ret
```

assistant: ```c
void font_draw_char(char character, long x, long y, long color) {
  if (character == '\n') {
    return;
  }
  gfx_draw_bitmap_transparent(font_get_bitmap(character), x, y, 7, 14, color);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<font_draw_char>:
  endbr64
  cmp    $0xa,%dil
  je     L8
  push   %r12
  movsbl %dil,%edi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  call   <font_get_bitmap@plt>
  mov    %rbx,%r9
  mov    %r12,%rdx
  pop    %rbx
  mov    %rbp,%rsi
  mov    %eax,%edi
  pop    %rbp
  mov    $0xe,%r8d
  mov    $0x7,%ecx
  pop    %r12
  jmp    1060 <gfx_draw_bitmap_transparent@plt>
  nop
L8:
  ret
```

assistant: ```c
void font_draw_char(char character, long x, long y, long color) {
  if (character == '\n') {
    return;
  }
  gfx_draw_bitmap_transparent(font_get_bitmap(character), x, y, 7, 14, color);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__tfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <__tfree>
  mov    -0x8(%rbp),%rax
  sub    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <__tfree>
  mov    -0x8(%rbp),%rax
  sub    $0x18,%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L16
L8:
  nop
L16:
  leave
  ret
```

assistant: ```c
void __tfree(void *mem) {
  if (!mem)
    return;
  assert((((void **)(mem))[-1]));
  (((void **)(mem))[-1]) = NULL;
  __tfree((((void **)(mem))[-3]));
  __tfree((((void **)(mem))[-2]));
  free((void *)((void **)(mem)-3));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__tfree>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %rdi,%rbx
  mov    -0x8(%rdi),%rdi
  call   <assert@plt>
  movq   $0x0,-0x8(%rbx)
  mov    -0x18(%rbx),%rdi
  call   <__tfree>
  mov    -0x10(%rbx),%rdi
  call   <__tfree>
  lea    -0x18(%rbx),%rdi
  call   <free@plt>
  pop    %rbx
  ret
L4:
  ret
```

assistant: ```c
void __tfree(void *mem) {
  if (!mem)
    return;
  assert((((void **)(mem))[-1]));
  (((void **)(mem))[-1]) = NULL;
  __tfree((((void **)(mem))[-3]));
  __tfree((((void **)(mem))[-2]));
  free((void *)((void **)(mem)-3));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse_vertically_uint8_buffer_inplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L5:
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L18:
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L7:
  mov    -0x20(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  sub    -0x10(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x10(%rbp)
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse_vertically_uint8_buffer_inplace(uint8_t *buff, int w, int h, int nch) {
  for (int j = 0; j < h / 2; j++)
    for (int i = 0; i < w; i++)
      for (int c = 0; c < nch; c++) {
        {
          uint8_t t = buff[nch * (i + (h - j - 1) * w) + c];
          buff[nch * (i + (h - j - 1) * w) + c] = buff[nch * (i + j * w) + c];
          buff[nch * (i + j * w) + c] = t;
        };
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverse_vertically_uint8_buffer_inplace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%r15d
  shr    $0x1f,%r15d
  add    %edx,%r15d
  sar    %r15d
  cmp    $0x1,%edx
  jle    L1
  mov    %rdi,%rbx
  mov    %esi,%r11d
  mov    %edx,%eax
  mov    %ecx,%r9d
  imul   %ecx,%esi
  mov    %esi,-0x8(%rsp)
  sub    $0x1,%eax
  mov    %esi,%r14d
  imul   %eax,%r14d
  add    %esi,%esi
  mov    %esi,-0x4(%rsp)
  imul   %r11d,%eax
  imul   %ecx,%eax
  mov    %eax,%r10d
  neg    %r10d
  mov    $0x0,%r13d
  lea    -0x1(%rcx),%r12d
  lea    0x4(%rdi),%rbp
  jmp    L9
L62:
  lea    (%rdi,%r10,1),%edx
  movslq %edi,%rcx
  lea    (%rbx,%rcx,4),%rax
  lea    (%r12,%rcx,1),%rsi
  lea    0x0(%rbp,%rsi,4),%rsi
  movslq %edx,%rdx
  sub    %rcx,%rdx
  mov    %edi,-0xc(%rsp)
L61:
  mov    (%rax),%ecx
  mov    (%rax,%rdx,4),%edi
  mov    %edi,(%rax)
  mov    %ecx,(%rax,%rdx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L61
  mov    -0xc(%rsp),%edi
L44:
  add    $0x1,%r8d
  add    %r9d,%edi
  cmp    %r8d,%r11d
  je     L41
L50:
  test   %r9d,%r9d
  jg     L62
  jmp    L44
L41:
  add    $0x1,%r13d
  sub    -0x8(%rsp),%r14d
  add    -0x4(%rsp),%r10d
  cmp    %r15d,%r13d
  jge    L1
L9:
  mov    %r14d,%edi
  mov    $0x0,%r8d
  test   %r11d,%r11d
  jg     L50
  jmp    L41
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void reverse_vertically_uint8_buffer_inplace(uint8_t *buff, int w, int h, int nch) {
  for (int j = 0; j < h / 2; j++)
    for (int i = 0; i < w; i++)
      for (int c = 0; c < nch; c++) {
        {
          uint8_t t = buff[nch * (i + (h - j - 1) * w) + c];
          buff[nch * (i + (h - j - 1) * w) + c] = buff[nch * (i + j * w) + c];
          buff[nch * (i + j * w) + c] = t;
        };
      }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse_vertically_uint8_buffer_inplace>:
  endbr64
  push   %r15
  mov    %edx,%eax
  shr    $0x1f,%edx
  push   %r14
  add    %eax,%edx
  push   %r13
  sar    %edx
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,-0x4(%rsp)
  cmp    $0x1,%eax
  jle    L8
  mov    %esi,%r15d
  mov    %esi,%r11d
  sub    $0x1,%eax
  mov    %rdi,%rbx
  imul   %ecx,%r15d
  mov    %ecx,%r9d
  lea    -0x1(%rcx),%r12d
  xor    %r13d,%r13d
  lea    0x4(%rdi),%rbp
  mov    %r15d,%r14d
  lea    (%r15,%r15,1),%esi
  imul   %eax,%r14d
  mov    %esi,-0x8(%rsp)
  imul   %r11d,%eax
  imul   %ecx,%eax
  mov    %eax,%r10d
  neg    %r10d
  xchg   %ax,%ax
L30:
  mov    %r14d,%edi
  xor    %r8d,%r8d
  test   %r11d,%r11d
  jle    L14
  nopl   0x0(%rax,%rax,1)
L45:
  test   %r9d,%r9d
  jle    L11
  movslq %edi,%rcx
  lea    (%rdi,%r10,1),%edx
  mov    %edi,-0xc(%rsp)
  lea    (%r12,%rcx,1),%rsi
  movslq %edx,%rdx
  lea    (%rbx,%rcx,4),%rax
  lea    0x0(%rbp,%rsi,4),%rsi
  sub    %rcx,%rdx
  nopl   0x0(%rax,%rax,1)
L54:
  mov    (%rax),%ecx
  mov    (%rax,%rdx,4),%edi
  mov    %edi,(%rax)
  mov    %ecx,(%rax,%rdx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L54
  mov    -0xc(%rsp),%edi
L11:
  add    $0x1,%r8d
  add    %r9d,%edi
  cmp    %r8d,%r11d
  jne    L45
L14:
  add    $0x1,%r13d
  sub    %r15d,%r14d
  add    -0x8(%rsp),%r10d
  cmp    -0x4(%rsp),%r13d
  jl     L30
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void reverse_vertically_uint8_buffer_inplace(uint8_t *buff, int w, int h, int nch) {
  for (int j = 0; j < h / 2; j++)
    for (int i = 0; i < w; i++)
      for (int c = 0; c < nch; c++) {
        {
          uint8_t t = buff[nch * (i + (h - j - 1) * w) + c];
          buff[nch * (i + (h - j - 1) * w) + c] = buff[nch * (i + j * w) + c];
          buff[nch * (i + j * w) + c] = t;
        };
      }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x730,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L4
L35:
  mov    -0x2724(%rbp),%edx
  lea    -0x2720(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <cleanaline@plt>
  movzbl -0x2720(%rbp),%eax
  cmp    $0xa,%al
  jne    L33
  jmp    L4
L33:
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  lea    -0x2720(%rbp),%rax
  mov    $0x2710,%esi
  mov    %rax,%rdi
  call   <getaline@plt>
  mov    %eax,-0x2724(%rbp)
  cmpl   $0x0,-0x2724(%rbp)
  jg     L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_guessed: string

tool: D1: %s

assistant: ```c
int main(void) {
  int len;
  char line[10000];
  while ((len = getaline(line, 10000)) > 0) {
    cleanaline(line, len);
    if (line[0] == '\n')
      continue;
    printf("%s", line);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rbp
L27:
  mov    %rsp,%rbx
L19:
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <getaline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jle    L25
  mov    %rbx,%rdi
  call   <cleanaline@plt>
  cmpb   $0xa,(%rsp)
  je     L19
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L27
L25:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x2728,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string

tool: D3: %s

assistant: ```c
int main(void) {
  int len;
  char line[10000];
  while ((len = getaline(line, 10000)) > 0) {
    cleanaline(line, len);
    if (line[0] == '\n')
      continue;
    printf("%s", line);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  lea    D2(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  nopw   0x0(%rax,%rax,1)
L39:
  mov    $0x2710,%esi
  mov    %rbx,%rdi
  call   <getaline@plt>
  mov    %eax,%esi
  test   %eax,%eax
  jle    L30
  mov    %rbx,%rdi
  call   <cleanaline@plt>
  cmpb   $0xa,(%rsp)
  je     L39
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L30:
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x2728,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: %s

assistant: ```c
int main(void) {
  int len;
  char line[10000];
  while ((len = getaline(line, 10000)) > 0) {
    cleanaline(line, len);
    if (line[0] == '\n')
      continue;
    printf("%s", line);
  }
  return 0;
}
```