ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<chsq2d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  movss  %xmm0,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <okarea2@plt>
  test   %eax,%eax
  jne    L29
  movss  -0x4(%rbp),%xmm0
  jmp    L35
L29:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L51
L26:
  mov    -0xc(%rbp),%edi
  mov    -0x2c(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    0x18(%rbp),%rax
  mov    0x10(%rbp),%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   *%r9
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L56
L11:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  subss  -0x30(%rbp),%xmm0
  movd   %xmm0,%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L56:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L11
  addl   $0x1,-0xc(%rbp)
L51:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L26
  movss  -0x4(%rbp),%xmm0
L35:
  leave
  ret
```

assistant: ```c
float chsq2d(int idev, float *x, int ilowb, int ihighb, int ilowa, int ihigha, float avg, int (*read2d)(void *, int, float *, int, int), void *userdata) {
  int i, j;
  float svd = 0.0;
  if (!okarea2(ilowb, ihighb, ilowa, ihigha))
    return svd;
  for (i = ilowb; i <= ihighb; i++) {
    read2d(userdata, idev, x, ihigha, i);
    for (j = ilowa; j <= ihigha; j++)
      svd += pow(x[j - 1] - avg, 2);
  }
  return svd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chsq2d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %ecx,%r15d
  mov    %r8d,%r14d
  mov    %r9d,%ebp
  movss  %xmm0,0x8(%rsp)
  mov    %r9d,%ecx
  mov    %r8d,%edx
  mov    %r15d,%esi
  mov    %r13d,%edi
  call   <okarea2@plt>
  test   %eax,%eax
  je     L35
  cmp    %r15d,%r13d
  jg     L69
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x4(%rsp)
L8:
  mov    %r13d,%r8d
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    0xc(%rsp),%esi
  mov    0x58(%rsp),%rdi
  call   *0x50(%rsp)
  cmp    %ebp,%r14d
  jg     L21
  movslq %r14d,%rbx
L54:
  movss  -0x4(%r12,%rbx,4),%xmm0
  subss  0x8(%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L54
L21:
  add    $0x1,%r13d
  cmp    %r13d,%r15d
  jge    L8
L41:
  movss  0x4(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0x4(%rsp)
  jmp    L41
L69:
  pxor   %xmm5,%xmm5
  movss  %xmm5,0x4(%rsp)
  jmp    L41
```

assistant: ```c
float chsq2d(int idev, float *x, int ilowb, int ihighb, int ilowa, int ihigha, float avg, int (*read2d)(void *, int, float *, int, int), void *userdata) {
  int i, j;
  float svd = 0.0;
  if (!okarea2(ilowb, ihighb, ilowa, ihigha))
    return svd;
  for (i = ilowb; i <= ihighb; i++) {
    read2d(userdata, idev, x, ihigha, i);
    for (j = ilowa; j <= ihigha; j++)
      svd += pow(x[j - 1] - avg, 2);
  }
  return svd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chsq2d>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edx,%r12d
  mov    %r8d,%edx
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  mov    %r15d,%esi
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %r9d,%ecx
  movss  %xmm0,0x8(%rsp)
  call   <okarea2@plt>
  test   %eax,%eax
  je     L45
  cmp    %r15d,%r12d
  jg     L40
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x4(%rsp)
  nopw   0x0(%rax,%rax,1)
L46:
  mov    0x58(%rsp),%rdi
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  call   *0x50(%rsp)
  cmp    %ebx,%r13d
  jg     L21
  movslq %r13d,%r15
  nopl   0x0(%rax)
L49:
  movss  -0x4(%rbp,%r15,4),%xmm0
  mov    $0x2,%edi
  add    $0x1,%r15
  subss  0x8(%rsp),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  cmp    %r15d,%ebx
  jge    L49
L21:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jge    L46
L1:
  movss  0x4(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0x4(%rsp)
  jmp    L1
L40:
  pxor   %xmm5,%xmm5
  movss  %xmm5,0x4(%rsp)
  jmp    L1
```

assistant: ```c
float chsq2d(int idev, float *x, int ilowb, int ihighb, int ilowa, int ihigha, float avg, int (*read2d)(void *, int, float *, int, int), void *userdata) {
  int i, j;
  float svd = 0.0;
  if (!okarea2(ilowb, ihighb, ilowa, ihigha))
    return svd;
  for (i = ilowb; i <= ihighb; i++) {
    read2d(userdata, idev, x, ihigha, i);
    for (j = ilowa; j <= ihigha; j++)
      svd += pow(x[j - 1] - avg, 2);
  }
  return svd;
}
```
user: What is the c source code of the assembly code below:

```asm
<chsq2d>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edx,%r12d
  mov    %r8d,%edx
  push   %rbp
  mov    %r12d,%edi
  mov    %rsi,%rbp
  mov    %r15d,%esi
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %r9d,%ecx
  movss  %xmm0,0x8(%rsp)
  call   <okarea2@plt>
  test   %eax,%eax
  je     L39
  cmp    %r15d,%r12d
  jg     L23
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x4(%rsp)
  nopw   0x0(%rax,%rax,1)
L8:
  mov    0x58(%rsp),%rdi
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    %r14d,%esi
  call   *0x50(%rsp)
  cmp    %ebx,%r13d
  jg     L2
  movslq %r13d,%r15
  nopl   0x0(%rax)
L4:
  movss  -0x4(%rbp,%r15,4),%xmm0
  mov    $0x2,%edi
  add    $0x1,%r15
  subss  0x8(%rsp),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  addss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  cmp    %r15d,%ebx
  jge    L4
L2:
  add    $0x1,%r12d
  cmp    %r12d,0xc(%rsp)
  jge    L8
L14:
  movss  0x4(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0x4(%rsp)
  jmp    L14
L23:
  pxor   %xmm5,%xmm5
  movss  %xmm5,0x4(%rsp)
  jmp    L14
```

assistant: ```c
float chsq2d(int idev, float *x, int ilowb, int ihighb, int ilowa, int ihigha, float avg, int (*read2d)(void *, int, float *, int, int), void *userdata) {
  int i, j;
  float svd = 0.0;
  if (!okarea2(ilowb, ihighb, ilowa, ihigha))
    return svd;
  for (i = ilowb; i <= ihighb; i++) {
    read2d(userdata, idev, x, ihigha, i);
    for (j = ilowa; j <= ihigha; j++)
      svd += pow(x[j - 1] - avg, 2);
  }
  return svd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<git__substrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <git__malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *git__substrdup(const char *start, size_t n) {
  char *ptr = (char *)git__malloc(n + 1);
  memcpy(ptr, start, n);
  ptr[n] = '\0';
  return ptr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<git__substrdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x1(%rsi),%rdi
  call   <git__malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *git__substrdup(const char *start, size_t n) {
  char *ptr = (char *)git__malloc(n + 1);
  memcpy(ptr, start, n);
  ptr[n] = '\0';
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<git__substrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <git__malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *git__substrdup(const char *start, size_t n) {
  char *ptr = (char *)git__malloc(n + 1);
  memcpy(ptr, start, n);
  ptr[n] = '\0';
  return ptr;
}
```
user: What is the c source code of the assembly code below?

```asm
<git__substrdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <git__malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *git__substrdup(const char *start, size_t n) {
  char *ptr = (char *)git__malloc(n + 1);
  memcpy(ptr, start, n);
  ptr[n] = '\0';
  return ptr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetCCITT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dx,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  shlw   $0x8,-0x8(%rbp)
  movl   $0x8,D37(%rip)
  jmp    L9
L23:
  movzwl -0x8(%rbp),%eax
  xor    -0x4(%rbp),%ax
  test   %ax,%ax
  jns    L20
  movzwl -0x4(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %ax,-0x4(%rbp)
  jmp    L39
L20:
  shlw   -0x4(%rbp)
L39:
  shlw   -0x8(%rbp)
  mov    D37(%rip),%eax
  sub    $0x1,%eax
  mov    %eax,D5(%rip)
L9:
  mov    D5(%rip),%eax
  test   %eax,%eax
  jne    L23
  movzwl -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short GetCCITT(unsigned short crc, unsigned short ch) {
  static unsigned int i;
  ch <<= 8;
  for (i = 8; i > 0; i--) {
    if ((ch ^ crc) & 0X8000)
      crc = (crc << 1) ^ 0x1021;
    else
      crc <<= 1;
    ch <<= 1;
  }
  return (crc);
}
```
user: What is the c source code of the assembly code below?

```asm
<GetCCITT>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%esi
  mov    $0x8,%edx
  jmp    L10
L20:
  add    %eax,%eax
L3:
  add    %esi,%esi
  sub    $0x1,%edx
  je     L14
L10:
  mov    %eax,%ecx
  xor    %si,%cx
  jns    L20
  add    %eax,%eax
  xor    $0x1021,%ax
  jmp    L3
L14:
  movl   $0x0,D1(%rip)
  ret
```

assistant: ```c
unsigned short GetCCITT(unsigned short crc, unsigned short ch) {
  static unsigned int i;
  ch <<= 8;
  for (i = 8; i > 0; i--) {
    if ((ch ^ crc) & 0X8000)
      crc = (crc << 1) ^ 0x1021;
    else
      crc <<= 1;
    ch <<= 1;
  }
  return (crc);
}
```
user: What is the c source code of the assembly code below?

```asm
<GetCCITT>:
  endbr64
  mov    %edi,%eax
  shl    $0x8,%esi
  mov    $0x8,%edx
  xchg   %ax,%ax
L15:
  mov    %eax,%ecx
  add    %eax,%eax
  xor    %si,%cx
  jns    L1
  xor    $0x1021,%ax
L1:
  add    %esi,%esi
  sub    $0x1,%edx
  jne    L15
  movl   $0x0,D8(%rip)
  ret
```

assistant: ```c
unsigned short GetCCITT(unsigned short crc, unsigned short ch) {
  static unsigned int i;
  ch <<= 8;
  for (i = 8; i > 0; i--) {
    if ((ch ^ crc) & 0X8000)
      crc = (crc << 1) ^ 0x1021;
    else
      crc <<= 1;
    ch <<= 1;
  }
  return (crc);
}
```
user: What is the c source code of the assembly code below?

```asm
<GetCCITT>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  shl    $0x8,%edx
  xor    %di,%dx
  js     L108
  add    %edi,%edi
L57:
  mov    %eax,%edx
  shl    $0x9,%edx
  xor    %di,%dx
  lea    (%rdi,%rdi,1),%edx
  jns    L66
  xor    $0x1021,%dx
L66:
  mov    %eax,%ecx
  shl    $0xa,%ecx
  xor    %dx,%cx
  js     L41
  add    %edx,%edx
L63:
  mov    %eax,%ecx
  shl    $0xb,%ecx
  xor    %dx,%cx
  js     L109
  add    %edx,%edx
L56:
  mov    %eax,%ecx
  shl    $0xc,%ecx
  xor    %dx,%cx
  js     L101
  add    %edx,%edx
L47:
  mov    %eax,%ecx
  shl    $0xd,%ecx
  xor    %dx,%cx
  js     L49
  add    %edx,%edx
L69:
  mov    %eax,%ecx
  shl    $0xe,%ecx
  xor    %dx,%cx
  js     L17
  add    %edx,%edx
L15:
  shl    $0xf,%eax
  lea    (%rdx,%rdx,1),%r8d
  xor    %dx,%ax
  jns    L20
  xor    $0x1021,%r8w
L20:
  movl   $0x0,D9(%rip)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  add    %edx,%edx
  xor    $0x1021,%dx
  jmp    L15
  nopl   0x0(%rax)
L49:
  add    %edx,%edx
  xor    $0x1021,%dx
  jmp    L69
  nopl   0x0(%rax)
L101:
  add    %edx,%edx
  xor    $0x1021,%dx
  jmp    L47
  nopl   0x0(%rax)
L109:
  add    %edx,%edx
  xor    $0x1021,%dx
  jmp    L56
  nopl   0x0(%rax)
L41:
  add    %edx,%edx
  xor    $0x1021,%dx
  jmp    L63
  nopl   0x0(%rax)
L108:
  add    %edi,%edi
  xor    $0x1021,%di
  jmp    L57
```

assistant: ```c
unsigned short GetCCITT(unsigned short crc, unsigned short ch) {
  static unsigned int i;
  ch <<= 8;
  for (i = 8; i > 0; i--) {
    if ((ch ^ crc) & 0X8000)
      crc = (crc << 1) ^ 0x1021;
    else
      crc <<= 1;
    ch <<= 1;
  }
  return (crc);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mountFileSystem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int mountFileSystem(const char *path, const char *reference, const char *type) {
  errno = ENOSYS;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mountFileSystem>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int mountFileSystem(const char *path, const char *reference, const char *type) {
  errno = ENOSYS;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mountFileSystem>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int mountFileSystem(const char *path, const char *reference, const char *type) {
  errno = ENOSYS;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mountFileSystem>:
  endbr64
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D14(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
int mountFileSystem(const char *path, const char *reference, const char *type) {
  errno = ENOSYS;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<binToStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0xb,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0xa,%rax
  movb   $0x0,(%rax)
  movl   $0x9,-0xc(%rbp)
  jmp    L17
L5:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  subl   $0x1,-0xc(%rbp)
  sarl   -0x14(%rbp)
L17:
  cmpl   $0x0,-0xc(%rbp)
  jns    L5
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *binToStr(int value) {
  int i;
  char *output = malloc(11 * sizeof(char));
  output[10] = '\0';
  for (i = 9; i >= 0; --i, value >>= 1) {
    output[i] = (value & 1) + '0';
  }
  return output;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binToStr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xb,%edi
  call   <malloc@plt>
  movb   $0x0,0xa(%rax)
  lea    0x9(%rax),%rdx
L1:
  mov    %ebx,%ecx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdx)
  sar    %ebx
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  cmp    %rax,%rcx
  jne    L1
  pop    %rbx
  ret
```

assistant: ```c
char *binToStr(int value) {
  int i;
  char *output = malloc(11 * sizeof(char));
  output[10] = '\0';
  for (i = 9; i >= 0; --i, value >>= 1) {
    output[i] = (value & 1) + '0';
  }
  return output;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binToStr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xb,%edi
  call   <malloc@plt>
  movb   $0x0,0xa(%rax)
  lea    0x9(%rax),%rdx
  nopl   0x0(%rax)
L6:
  mov    %ebx,%ecx
  sar    %ebx
  and    $0x1,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdx)
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  cmp    %rcx,%rax
  jne    L6
  pop    %rbx
  ret
```

assistant: ```c
char *binToStr(int value) {
  int i;
  char *output = malloc(11 * sizeof(char));
  output[10] = '\0';
  for (i = 9; i >= 0; --i, value >>= 1) {
    output[i] = (value & 1) + '0';
  }
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binToStr>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0xb,%edi
  call   <malloc@plt>
  mov    %ebx,%edx
  mov    %ebx,%ecx
  mov    %ebx,%esi
  movb   $0x0,0xa(%rax)
  mov    %rax,%r8
  mov    %ebx,%eax
  mov    %ebx,%edi
  and    $0x1,%eax
  mov    %ebx,%r9d
  mov    %ebx,%r10d
  mov    %ebx,%r11d
  sar    $0x3,%r11d
  add    $0x30,%eax
  sar    $0x4,%r10d
  movq   D3(%rip),%xmm0
  mov    %al,0x9(%r8)
  mov    %ebx,%eax
  sar    $0x2,%ebx
  movzbl %r11b,%r11d
  sar    %eax
  movzbl %r10b,%r10d
  sar    $0x5,%r9d
  movq   D12(%rip),%xmm1
  sar    $0x6,%edi
  and    $0x1,%eax
  movzbl %r9b,%r9d
  sar    $0x7,%esi
  add    $0x30,%eax
  movzbl %dil,%edi
  movzbl %sil,%esi
  sar    $0x8,%ecx
  mov    %al,0x8(%r8)
  movzbl %bl,%eax
  movzbl %cl,%ecx
  sar    $0x9,%edx
  shl    $0x8,%rax
  movzbl %dl,%edx
  or     %r11,%rax
  shl    $0x8,%rax
  or     %r10,%rax
  shl    $0x8,%rax
  or     %r9,%rax
  shl    $0x8,%rax
  or     %rdi,%rax
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  movq   %rax,%xmm2
  mov    %r8,%rax
  pand   %xmm2,%xmm0
  paddb  %xmm1,%xmm0
  movq   %xmm0,(%r8)
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: byte[8]
name: read_data
arguments: tag: D12
type_guessed: byte[8]

tool: {"D3": [0x01,0x01,0x01,0x01,0x01,0x01,0x01,0x01]}

tool: {"D12": [0x30,0x30,0x30,0x30,0x30,0x30,0x30,0x30]}

assistant: ```c
char *binToStr(int value) {
  int i;
  char *output = malloc(11 * sizeof(char));
  output[10] = '\0';
  for (i = 9; i >= 0; --i, value >>= 1) {
    output[i] = (value & 1) + '0';
  }
  return output;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x0,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L37
  mov    -0x38(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L20
L37:
  movl   $0x0,-0x24(%rbp)
  jmp    L52
L25:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L0
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x20(%rbp)
  jmp    L55
L0:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L55:
  addl   $0x1,-0x24(%rbp)
L52:
  mov    -0x24(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%eax
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lc(char *buff, const char *string) {
  char *buffer;
  int i, j = 0;
  int len = strlen(string);
  buffer = malloc(len + 1);
  if (len == 0) {
    buff[0] = 0;
    free(buffer);
    return 0;
  }
  for (i = 0; i < len; i++) {
    if (isupper((int)string[i])) {
      buffer[i] = tolower(string[i]);
      j++;
    } else {
      buffer[i] = string[i];
    }
  }
  buffer[len] = 0;
  strcpy(buff, buffer);
  free(buffer);
  return j;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  je     L59
  mov    $0x0,%r15d
  jle    L67
  mov    %r13,%rbx
  mov    %rax,%rbp
  lea    -0x1(%r12),%eax
  lea    0x1(%r13,%rax,1),%r13
  mov    $0x0,%r15d
  jmp    L56
L59:
  mov    0x8(%rsp),%rax
  movb   $0x0,(%rax)
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r12d,%r15d
  jmp    L29
L51:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
L42:
  add    $0x1,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  je     L67
L56:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L51
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%r15d
  jmp    L42
L67:
  movslq %r12d,%r12
  movb   $0x0,(%r14,%r12,1)
  mov    %r14,%rsi
  mov    0x8(%rsp),%rdi
  call   <strcpy@plt>
  mov    %r14,%rdi
  call   <free@plt>
L29:
  mov    %r15d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int lc(char *buff, const char *string) {
  char *buffer;
  int i, j = 0;
  int len = strlen(string);
  buffer = malloc(len + 1);
  if (len == 0) {
    buff[0] = 0;
    free(buffer);
    return 0;
  }
  for (i = 0; i < len; i++) {
    if (isupper((int)string[i])) {
      buffer[i] = tolower(string[i]);
      j++;
    } else {
      buffer[i] = string[i];
    }
  }
  buffer[len] = 0;
  strcpy(buff, buffer);
  free(buffer);
  return j;
}
```