ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<malloc_double_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %rax,%rax
  je     L16
L86:
  test   %ebp,%ebp
  jle    L32
  mov    0x18(%rsp),%rcx
  mov    0xc(%rsp),%eax
  shl    $0x3,%ebx
  lea    (%rcx,%rbp,8),%rdx
  lea    0x0(,%rax,8),%r14d
  sub    $0x1,%eax
  mov    %rcx,%r15
  mov    %rdx,0x10(%rsp)
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  test   %rax,%rax
  je     L81
L27:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L11
  xor    %r13d,%r13d
  jmp    L91
  nopl   (%rax)
L40:
  add    $0x8,%r13
  cmp    %r13,%rbp
  je     L11
L91:
  mov    (%r15),%r12
  mov    %ebx,%edi
  call   <malloc@plt>
  add    %r13,%r12
  mov    %rax,(%r12)
  mov    (%r15),%rax
  cmpq   $0x0,(%rax,%r13,1)
  jne    L40
  xor    %eax,%eax
  add    $0x8,%r13
  call   <error_and_exit@plt>
  cmp    %r13,%rbp
  jne    L91
  nopl   0x0(%rax)
L11:
  add    $0x8,%r15
  cmp    0x10(%rsp),%r15
  jne    L41
L32:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L81:
  call   <error_and_exit@plt>
  jmp    L27
L16:
  call   <error_and_exit@plt>
  jmp    L86
```

assistant: ```c
double ***malloc_double_array(int dim1, int dim2, int dim3) {
  int i, j;
  double ***array;
  array = malloc(sizeof(double **) * dim1);
  if (array == NULL)
    error_and_exit();
  for (i = 0; i < dim1; i++) {
    array[i] = malloc(sizeof(double *) * dim2);
    if (array[i] == NULL)
      error_and_exit();
    for (j = 0; j < dim2; j++) {
      array[i][j] = malloc(sizeof(double) * dim3);
      if (array[i][j] == NULL)
        error_and_exit();
    }
  }
  return array;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iscsiAuthClientStringIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L2:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L17
  mov    -0x4(%rbp),%eax
  jmp    L5
L17:
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    $0xffffffff,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int iscsiAuthClientStringIndex(const char *s, int c) {
  int n = 0;
  while (*s != '\0') {
    if (*s++ == c) {
      return n;
    }
    n++;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<iscsiAuthClientStringIndex>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  mov    $0x0,%edx
L1:
  mov    %edx,%ecx
  movsbl %al,%eax
  cmp    %esi,%eax
  je     L3
  add    $0x1,%rdx
  movzbl (%rdi,%rdx,1),%eax
  test   %al,%al
  jne    L1
  mov    $0xffffffff,%ecx
L3:
  mov    %ecx,%eax
  ret
L28:
  mov    $0xffffffff,%ecx
  jmp    L3
```

assistant: ```c
int iscsiAuthClientStringIndex(const char *s, int c) {
  int n = 0;
  while (*s != '\0') {
    if (*s++ == c) {
      return n;
    }
    n++;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iscsiAuthClientStringIndex>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L27
  xor    %edx,%edx
  jmp    L2
  nop
L38:
  add    $0x1,%rdx
  movsbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L27
L2:
  mov    %edx,%r8d
  cmp    %esi,%eax
  jne    L38
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int iscsiAuthClientStringIndex(const char *s, int c) {
  int n = 0;
  while (*s != '\0') {
    if (*s++ == c) {
      return n;
    }
    n++;
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iscsiAuthClientStringIndex>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L6
  xor    %edx,%edx
  jmp    L12
  nop
L35:
  add    $0x1,%rdx
  movsbl (%rdi,%rdx,1),%eax
  test   %al,%al
  je     L6
L12:
  mov    %edx,%r8d
  cmp    %esi,%eax
  jne    L35
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int iscsiAuthClientStringIndex(const char *s, int c) {
  int n = 0;
  while (*s != '\0') {
    if (*s++ == c) {
      return n;
    }
    n++;
  }
  return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<remove_eol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L52
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L22:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L39
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L14
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L14:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jle    L22
  jmp    L52
L28:
  nop
L52:
  leave
  ret
```

assistant: ```c
void remove_eol(char *str) {
  int i;
  if (str == 0)
    return;
  if (strlen(str) > 0) {
    for (i = 1; i <= strlen(str); i++) {
      if ((str[i] == 10) || (str[i] == 13)) {
        str[i] = 0;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<remove_eol>:
  endbr64
  test   %rdi,%rdi
  je     L33
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    $0x1,%ebx
  test   %eax,%eax
  jg     L12
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L52:
  movb   $0x0,0x0(%rbp,%rbx,1)
L53:
  add    $0x1,%rbx
L12:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L25
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0xa,%al
  je     L52
  cmp    $0xd,%al
  jne    L53
  jmp    L52
L33:
  ret
```

assistant: ```c
void remove_eol(char *str) {
  int i;
  if (str == 0)
    return;
  if (strlen(str) > 0) {
    for (i = 1; i <= strlen(str); i++) {
      if ((str[i] == 10) || (str[i] == 13)) {
        str[i] = 0;
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_eol>:
  endbr64
  test   %rdi,%rdi
  je     L24
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jg     L21
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  movb   $0x0,0x0(%rbp,%rbx,1)
L6:
  add    $0x1,%rbx
L21:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L15
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0xa,%al
  je     L17
  cmp    $0xd,%al
  jne    L6
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L6
  nopl   0x0(%rax)
L24:
  ret
```

assistant: ```c
void remove_eol(char *str) {
  int i;
  if (str == 0)
    return;
  if (strlen(str) > 0) {
    for (i = 1; i <= strlen(str); i++) {
      if ((str[i] == 10) || (str[i] == 13)) {
        str[i] = 0;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<remove_eol>:
  endbr64
  test   %rdi,%rdi
  je     L19
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jg     L0
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  movb   $0x0,0x0(%rbp,%rbx,1)
L58:
  add    $0x1,%rbx
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L1
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0xa,%al
  je     L52
  cmp    $0xd,%al
  jne    L58
  movb   $0x0,0x0(%rbp,%rbx,1)
  jmp    L58
  nopl   0x0(%rax)
L19:
  ret
```

assistant: ```c
void remove_eol(char *str) {
  int i;
  if (str == 0)
    return;
  if (strlen(str) > 0) {
    for (i = 1; i <= strlen(str); i++) {
      if ((str[i] == 10) || (str[i] == 13)) {
        str[i] = 0;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<localvars_after_alloca>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %esi,%eax
  mov    %edx,-0x1c(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %edi,%edx
  mov    %dl,-0x14(%rbp)
  mov    %ax,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movswl -0x18(%rbp),%eax
  add    $0x32,%eax
  cltq
  lea    0x8(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L34:
  cmp    %rdx,%rsp
  je     L21
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L34
L21:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L29
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L29:
  mov    %rsp,%rax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,-0x10(%rbp)
  movb   $0x61,-0x14(%rbp)
  movw   $0x5,-0x18(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movq   $0x7,-0x28(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void localvars_after_alloca(c, s, i, l) char c;
short s;
int i;
long l;
{
  char *z = __builtin_alloca(s + 50);
  c = 'a';
  s = 5;
  i = 6;
  l = 7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<localvars_after_alloca>:
  endbr64
  ret
```

assistant: ```c
void localvars_after_alloca(c, s, i, l) char c;
short s;
int i;
long l;
{
  char *z = __builtin_alloca(s + 50);
  c = 'a';
  s = 5;
  i = 6;
  l = 7;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<localvars_after_alloca>:
  endbr64
  ret
```

assistant: ```c
void localvars_after_alloca(c, s, i, l) char c;
short s;
int i;
long l;
{
  char *z = __builtin_alloca(s + 50);
  c = 'a';
  s = 5;
  i = 6;
  l = 7;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<localvars_after_alloca>:
  endbr64
  ret
```

assistant: ```c
void localvars_after_alloca(c, s, i, l) char c;
short s;
int i;
long l;
{
  char *z = __builtin_alloca(s + 50);
  c = 'a';
  s = 5;
  i = 6;
  l = 7;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mysprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L14
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L14:
  movl   $0x0,-0xb8(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb8(%rbp)
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xcc(%rbp),%eax
  cmp    -0xb8(%rbp),%eax
  jg     L18
  mov    -0xcc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xb8(%rbp)
  jmp    L29
L18:
  cmpl   $0xffffffff,-0xb8(%rbp)
  jne    L29
  mov    -0xcc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xb8(%rbp)
L29:
  mov    -0xb8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xb8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int mysprintf(char *buffer, int len, const char *fmt, ...) {
  va_list ap;
  int ret = 0;
  va_start(ap, fmt);
  ret = vsnprintf(buffer, len, fmt, ap);
  va_end(ap);
  if (ret > len - 1)
    ret = len - 1;
  else if (ret == -1)
    ret = len - 1;
  buffer[ret] = '\0';
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mysprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %rbx,%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %r13d,%edi
  call   <va_end@plt>
  cmp    %ebx,%ebp
  jg     L1
  lea    -0x1(%rbp),%ebx
L9:
  movslq %ebx,%rax
  movb   $0x0,(%r12,%rax,1)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebx
  cmove  %ebp,%ebx
  jmp    L9
```

assistant: ```c
int mysprintf(char *buffer, int len, const char *fmt, ...) {
  va_list ap;
  int ret = 0;
  va_start(ap, fmt);
  ret = vsnprintf(buffer, len, fmt, ap);
  va_end(ap);
  if (ret > len - 1)
    ret = len - 1;
  else if (ret == -1)
    ret = len - 1;
  buffer[ret] = '\0';
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<mysprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %r13d,%ecx
  mov    %ebx,%esi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  cmp    %r12d,%ebx
  jle    L18
  cmp    $0xffffffff,%r12d
  je     L18
L20:
  movslq %r12d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  lea    -0x1(%rbx),%r12d
  jmp    L20
```

assistant: ```c
int mysprintf(char *buffer, int len, const char *fmt, ...) {
  va_list ap;
  int ret = 0;
  va_start(ap, fmt);
  ret = vsnprintf(buffer, len, fmt, ap);
  va_end(ap);
  if (ret > len - 1)
    ret = len - 1;
  else if (ret == -1)
    ret = len - 1;
  buffer[ret] = '\0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mysprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    %rdx,%rsi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    %r13d,%ecx
  mov    %ebx,%esi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  cmp    %r12d,%ebx
  jle    L9
  cmp    $0xffffffff,%r12d
  je     L9
L26:
  movslq %r12d,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  lea    -0x1(%rbx),%r12d
  jmp    L26
```

assistant: ```c
int mysprintf(char *buffer, int len, const char *fmt, ...) {
  va_list ap;
  int ret = 0;
  va_start(ap, fmt);
  ret = vsnprintf(buffer, len, fmt, ap);
  va_end(ap);
  if (ret > len - 1)
    ret = len - 1;
  else if (ret == -1)
    ret = len - 1;
  buffer[ret] = '\0';
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InputCardinal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %ecx,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
L69:
  mov    -0x44(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %eax,%edx
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <CursorXY@plt>
  mov    $0x0,%eax
  call   <ReadChar@plt>
  mov    %al,-0x35(%rbp)
  cmpb   $0x2f,-0x35(%rbp)
  jle    L156
  cmpb   $0x39,-0x35(%rbp)
  jg     L156
  mov    -0x34(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jge    L156
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  movzbl -0x35(%rbp),%edx
  mov    %dl,-0x30(%rbp,%rax,1)
  mov    -0x34(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  movsbl -0x35(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L68
L156:
  cmpb   $0x8,-0x35(%rbp)
  je     L108
  cmpb   $0x7f,-0x35(%rbp)
  jne    L52
L108:
  cmpl   $0x0,-0x34(%rbp)
  jle    L52
  subl   $0x1,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  movb   $0x0,-0x30(%rbp,%rax,1)
  mov    -0x44(%rbp),%edx
  mov    -0x34(%rbp),%eax
  add    %eax,%edx
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <CursorXY@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L68
L52:
  cmpb   $0x1b,-0x35(%rbp)
  je     L151
  cmpb   $0x3,-0x35(%rbp)
  jne    L68
L151:
  movb   $0x0,-0x30(%rbp)
L68:
  cmpb   $0x1b,-0x35(%rbp)
  je     L81
  cmpb   $0x3,-0x35(%rbp)
  je     L81
  cmpb   $0xd,-0x35(%rbp)
  jne    L9
  cmpl   $0x0,-0x34(%rbp)
  jne    L81
L9:
  cmpb   $0xa,-0x35(%rbp)
  jne    L69
  cmpl   $0x0,-0x34(%rbp)
  je     L69
L81:
  cmpb   $0x1b,-0x35(%rbp)
  je     L90
  cmpb   $0x3,-0x35(%rbp)
  jne    L12
L90:
  mov    $0x0,%eax
  jmp    L177
L12:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x50(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x1,%eax
L177:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L176
  call   <__stack_chk_fail@plt>
L176:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
datatype: string

tool: D4:  

assistant: ```c
int InputCardinal(int x, int y, int *pNumber, int l) {
  int i = 0;
  char ch;
  char s[31];
  do {
    CursorXY(x + i, y);
    ch = ReadChar();
    if (ch >= '0' && ch <= '9' && i < l) {
      s[i++] = ch;
      s[i] = '\0';
      putchar(ch);
    } else if ((ch == '\010' || ch == '\177') && i > 0) {
      s[--i] = '\0';
      CursorXY(x + i, y);
      printf(" ");
    } else if (ch == '\033' || ch == '\003') {
      s[0] = '\0';
    }
  } while (ch != '\033' && ch != '\003' && (ch != '\015' || i == 0) && (ch != '\012' || i == 0));
  if (ch == '\033' || ch == '\003')
    return 0;
  *pNumber = atoi(s);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<InputCardinal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %rdx,0x8(%rsp)
  mov    %ecx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  jmp    L76
L27:
  lea    0x1(%rbp),%r15d
  movslq %ebp,%rbp
  mov    %bl,0x10(%rsp,%rbp,1)
  movslq %r15d,%rax
  movb   $0x0,0x10(%rsp,%rax,1)
  movsbl %bl,%edi
  call   <putchar@plt>
  test   %r15d,%r15d
  sete   %al
  mov    %r15d,%ebp
  jmp    L34
L128:
  sub    $0x1,%ebp
  movslq %ebp,%rax
  movb   $0x0,0x10(%rsp,%rax,1)
  lea    0x0(%r13,%rbp,1),%edi
  mov    %r12d,%esi
  call   <CursorXY@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L141
L150:
  movb   $0x0,0x10(%rsp)
L141:
  cmp    $0x1b,%bl
  je     L90
  cmp    $0x3,%bl
  je     L90
L20:
  test   %ebp,%ebp
  sete   %al
  cmp    $0xd,%bl
  jne    L34
  test   %al,%al
  je     L140
L34:
  cmp    $0xa,%bl
  jne    L76
  test   %al,%al
  je     L140
L76:
  lea    0x0(%rbp,%r13,1),%edi
  mov    %r12d,%esi
  call   <CursorXY@plt>
  mov    $0x0,%eax
  call   <ReadChar@plt>
  mov    %eax,%ebx
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L97
  cmp    %r14d,%ebp
  jl     L27
L97:
  cmp    $0x8,%bl
  sete   %al
  cmp    $0x7f,%bl
  sete   %dl
  or     %dl,%al
  je     L194
  test   %ebp,%ebp
  jg     L128
L194:
  cmp    $0x1b,%bl
  je     L150
  cmp    $0x3,%bl
  jne    L20
  jmp    L150
L90:
  cmp    $0x1b,%bl
  je     L170
  cmp    $0x3,%bl
  jne    L140
L170:
  mov    $0x0,%eax
L173:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L144
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L140:
  lea    0x10(%rsp),%rdi
  call   <atoi@plt>
  mov    0x8(%rsp),%rcx
  mov    %eax,(%rcx)
  mov    $0x1,%eax
  jmp    L173
L144:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8:  

assistant: ```c
int InputCardinal(int x, int y, int *pNumber, int l) {
  int i = 0;
  char ch;
  char s[31];
  do {
    CursorXY(x + i, y);
    ch = ReadChar();
    if (ch >= '0' && ch <= '9' && i < l) {
      s[i++] = ch;
      s[i] = '\0';
      putchar(ch);
    } else if ((ch == '\010' || ch == '\177') && i > 0) {
      s[--i] = '\0';
      CursorXY(x + i, y);
      printf(" ");
    } else if (ch == '\033' || ch == '\003') {
      s[0] = '\0';
    }
  } while (ch != '\033' && ch != '\003' && (ch != '\015' || i == 0) && (ch != '\012' || i == 0));
  if (ch == '\033' || ch == '\003')
    return 0;
  *pNumber = atoi(s);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<InputCardinal>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  nopl   (%rax)
L9:
  mov    %ebp,%esi
  mov    %r14d,%edi
  call   <CursorXY@plt>
  xor    %eax,%eax
  call   <ReadChar@plt>
  mov    %eax,%ebx
  lea    -0x30(%rbx),%eax
  cmp    $0x9,%al
  ja     L59
  cmp    %r12d,%r15d
  jge    L9
  lea    0x1(%r15),%r14d
  movslq %r15d,%rdx
  movsbl %bl,%edi
  movslq %r14d,%rax
  mov    %bl,0x10(%rsp,%rdx,1)
  mov    %r14d,%r15d
  lea    (%r14,%r13,1),%r14d
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <putchar@plt>
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L59:
  cmp    $0x8,%bl
  sete   %al
  cmp    $0x7f,%bl
  sete   %sil
  or     %sil,%al
  je     L115
  test   %r15d,%r15d
  jle    L115
  sub    $0x1,%r15d
  mov    %ebp,%esi
  lea    0x0(%r13,%r15,1),%r14d
  movslq %r15d,%rax
  mov    %r14d,%edi
  movb   $0x0,0x10(%rsp,%rax,1)
  call   <CursorXY@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1b,%bl
  je     L85
L123:
  cmp    $0x3,%bl
  je     L142
L130:
  test   %r15d,%r15d
  sete   %al
  cmp    $0xd,%bl
  jne    L27
  test   %al,%al
  je     L145
L27:
  cmp    $0xa,%bl
  jne    L9
  test   %al,%al
  jne    L9
L145:
  lea    0x10(%rsp),%rdi
  call   <atoi@plt>
  mov    0x8(%rsp),%rcx
  mov    %eax,(%rcx)
  mov    $0x1,%eax
L41:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L109
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L115:
  cmp    $0x1b,%bl
  je     L131
  cmp    $0x3,%bl
  jne    L130
L131:
  movb   $0x0,0x10(%rsp)
  cmp    $0x1b,%bl
  jne    L123
L85:
  xor    %eax,%eax
  jmp    L41
L142:
  cmp    $0x1b,%bl
  je     L85
  cmp    $0x3,%bl
  jne    L145
  xor    %eax,%eax
  jmp    L41
L109:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string

tool: D8:  

assistant: ```c
int InputCardinal(int x, int y, int *pNumber, int l) {
  int i = 0;
  char ch;
  char s[31];
  do {
    CursorXY(x + i, y);
    ch = ReadChar();
    if (ch >= '0' && ch <= '9' && i < l) {
      s[i++] = ch;
      s[i] = '\0';
      putchar(ch);
    } else if ((ch == '\010' || ch == '\177') && i > 0) {
      s[--i] = '\0';
      CursorXY(x + i, y);
      printf(" ");
    } else if (ch == '\033' || ch == '\003') {
      s[0] = '\0';
    }
  } while (ch != '\033' && ch != '\003' && (ch != '\015' || i == 0) && (ch != '\012' || i == 0));
  if (ch == '\033' || ch == '\003')
    return 0;
  *pNumber = atoi(s);
  return 1;
}
```