ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ler_ficheiro>:
  endbr64
  push   %r15
  mov    $0x400,%esi
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x458,%rsp
  mov    %rdi,0x18(%rsp)
  lea    0x40(%rsp),%r12
  mov    %edx,0x2c(%rsp)
  mov    %rdi,%rdx
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  call   <fgets@plt>
  movslq %r14d,%rax
  lea    D0(%rip),%r14
  mov    %rax,%rcx
  shl    $0x2,%rax
  mov    %rax,0x20(%rsp)
  lea    -0x2(%rcx),%eax
  lea    0x8(%rbx,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  lea    0x4(%rbx),%rax
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x18(%rsp),%rdx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L35
  lea    0x3c(%rsp),%r13
  mov    %r14,%rsi
  mov    %r12,%rdi
  mov    %r13,%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L7
  mov    0x3c(%rsp),%eax
  mov    0x10(%rsp),%r15
  cmpl   $0x1,0x2c(%rsp)
  mov    %eax,-0x4(%r15)
  jle    L32
  xor    %ebp,%ebp
  nopl   (%rax)
L33:
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    %rdi,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  mov    $0x3a,%esi
  mov    %rax,%rbx
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  sub    %rax,%rbx
  add    %ebx,%ebp
  movslq %ebp,%rdi
  add    %r12,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  mov    $0xffffffff,%eax
  cmove  0x3c(%rsp),%eax
  add    $0x4,%r15
  mov    %eax,-0x4(%r15)
  cmp    0x8(%rsp),%r15
  jne    L33
L32:
  mov    0x20(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  add    %rcx,0x10(%rsp)
  jmp    L17
  nop
L7:
  mov    0x18(%rsp),%rdx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
L35:
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x458,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D0
data_type: string

tool: D0: %d

assistant: ```c
void ler_ficheiro(FILE *fpin, int altura, int largura, int matriz[altura][largura]) {
  char linha[1024];
  int temp;
  int i, j, k;
  int linhas_em_branco = 0;
  fgets(linha, 1024, fpin);
  i = 0;
  while (fgets(linha, 1024, fpin) != NULL && linhas_em_branco == 0) {
    j = 0;
    if (sscanf(linha, "%d", &temp) == 1) {
      matriz[i][j] = temp;
      j++;
      k = 0;
      while (j < largura) {
        k += strlen(&linha[k]) - strlen(strchr(&linha[k], ':') + 1);
        if (sscanf(&linha[k], "%d", &temp) == 1) {
          matriz[i][j] = temp;
        } else {
          matriz[i][j] = -1;
        }
        j++;
      }
      i++;
    } else {
      linhas_em_branco++;
    }
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ler_ficheiro>:
  endbr64
  push   %r15
  mov    $0x400,%esi
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x458,%rsp
  mov    %rdi,0x18(%rsp)
  lea    0x40(%rsp),%r12
  mov    %edx,0x2c(%rsp)
  mov    %rdi,%rdx
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x448(%rsp)
  xor    %eax,%eax
  call   <fgets@plt>
  movslq %r15d,%rax
  lea    D8(%rip),%r15
  mov    %rax,%rcx
  shl    $0x2,%rax
  mov    %rax,0x20(%rsp)
  lea    -0x2(%rcx),%eax
  lea    0x8(%rbx,%rax,4),%rax
  mov    %rax,0x8(%rsp)
  lea    0x4(%rbx),%rax
  mov    %rax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x18(%rsp),%rdx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L73
  lea    0x3c(%rsp),%r13
  mov    %r15,%rsi
  mov    %r12,%rdi
  mov    %r13,%rdx
  call   <sscanf@plt>
  cmp    $0x1,%eax
  jne    L66
  mov    0x3c(%rsp),%eax
  mov    0x10(%rsp),%r14
  cmpl   $0x1,0x2c(%rsp)
  mov    %eax,-0x4(%r14)
  jle    L41
  xor    %ebp,%ebp
  nopl   (%rax)
L72:
  movslq %ebp,%rdi
  add    %r12,%rdi
  mov    %rdi,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  mov    $0x3a,%esi
  mov    %rax,%rbx
  call   <strchr@plt>
  lea    0x1(%rax),%rdi
  call   <strlen@plt>
  mov    %r13,%rdx
  mov    %r15,%rsi
  sub    %rax,%rbx
  add    %ebx,%ebp
  movslq %ebp,%rdi
  add    %r12,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L9
  movl   $0xffffffff,(%r14)
  add    $0x4,%r14
  cmp    0x8(%rsp),%r14
  jne    L72
L41:
  mov    0x20(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  add    %rcx,0x10(%rsp)
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x3c(%rsp),%eax
  add    $0x4,%r14
  mov    %eax,-0x4(%r14)
  cmp    0x8(%rsp),%r14
  jne    L72
  mov    0x20(%rsp),%rcx
  add    %rcx,0x8(%rsp)
  add    %rcx,0x10(%rsp)
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L66:
  mov    0x18(%rsp),%rdx
  mov    $0x400,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
L73:
  mov    0x448(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x458,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
void ler_ficheiro(FILE *fpin, int altura, int largura, int matriz[altura][largura]) {
  char linha[1024];
  int temp;
  int i, j, k;
  int linhas_em_branco = 0;
  fgets(linha, 1024, fpin);
  i = 0;
  while (fgets(linha, 1024, fpin) != NULL && linhas_em_branco == 0) {
    j = 0;
    if (sscanf(linha, "%d", &temp) == 1) {
      matriz[i][j] = temp;
      j++;
      k = 0;
      while (j < largura) {
        k += strlen(&linha[k]) - strlen(strchr(&linha[k], ':') + 1);
        if (sscanf(&linha[k], "%d", &temp) == 1) {
          matriz[i][j] = temp;
        } else {
          matriz[i][j] = -1;
        }
        j++;
      }
      i++;
    } else {
      linhas_em_branco++;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gammln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x24(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D35(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  D20(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x30(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movsd  -0x30(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L10
L13:
  movsd  -0x18(%rbp),%xmm1
  movsd  D5(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  lea    D31(%rip),%rax
  movsd  (%rdx,%rax,1),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L10:
  cmpl   $0x5,-0x1c(%rbp)
  jle    L13
  movsd  -0x10(%rbp),%xmm1
  movsd  D37(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x8(%rbp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: f64
name: extract_symbolic_data
arguments: data_label: D35
datatype: f64
name: extract_symbolic_data
arguments: data_label: D20
datatype: f64
name: extract_symbolic_data
arguments: data_label: D37
datatype: f64

tool: D5: 1

tool: D35: 5.5

tool: D20: 0.5

tool: D37: 2.50662827465

assistant: ```c
float gammln(float xx) {
  double x, tmp, ser;
  static double cof[6] = {76.18009173, -86.50532033, 24.01409822, -1.231739516, 0.120858003e-2, -0.536382e-5};
  int j;
  x = xx - 1.0;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.0;
  for (j = 0; j <= 5; j++) {
    x += 1.0;
    ser += cof[j] / x;
  }
  return -tmp + log(2.50662827465 * ser);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gammln>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  cvtss2sd %xmm0,%xmm0
  subsd  D5(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm0,%xmm4
  addsd  D55(%rip),%xmm4
  movq   %xmm4,%rbx
  movapd %xmm4,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  addsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movq   %rbx,%xmm6
  subsd  %xmm0,%xmm6
  movsd  %xmm6,0x8(%rsp)
  lea    D29(%rip),%rax
  lea    0x30(%rax),%rdx
  mov    D5(%rip),%rcx
  movq   %rcx,%xmm0
  movq   %rcx,%xmm2
L3:
  movsd  (%rsp),%xmm3
  addsd  %xmm2,%xmm3
  movsd  %xmm3,(%rsp)
  movsd  (%rax),%xmm1
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L3
  mulsd  D6(%rip),%xmm0
  call   <log@plt>
  subsd  0x8(%rsp),%xmm0
  cvtsd2ss %xmm0,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: f64
name: retrieve_data
arguments: label: D55
datatype: f64
name: retrieve_data
arguments: label: D9
datatype: f64
name: retrieve_data
arguments: label: D29
datatype: f64
name: retrieve_data
arguments: label: D6
datatype: f64

tool: D5: 1

tool: D55: 5.5

tool: D9: 0.5

tool: D29: 76.18009173

tool: D6: 2.50662827465

assistant: ```c
float gammln(float xx) {
  double x, tmp, ser;
  static double cof[6] = {76.18009173, -86.50532033, 24.01409822, -1.231739516, 0.120858003e-2, -0.536382e-5};
  int j;
  x = xx - 1.0;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.0;
  for (j = 0; j <= 5; j++) {
    x += 1.0;
    ser += cof[j] / x;
  }
  return -tmp + log(2.50662827465 * ser);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gammln>:
  endbr64
  sub    $0x18,%rsp
  movsd  D41(%rip),%xmm3
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  subsd  %xmm3,%xmm1
  movapd %xmm1,%xmm2
  addsd  D47(%rip),%xmm2
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  movsd  %xmm2,(%rsp)
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  lea    D69(%rip),%rax
  movapd %xmm0,%xmm4
  movsd  D30(%rip),%xmm0
  mov    D41(%rip),%rcx
  lea    0x30(%rax),%rdx
  addsd  %xmm1,%xmm0
  movq   %rcx,%xmm3
  mulsd  %xmm4,%xmm0
  subsd  %xmm0,%xmm2
  movq   %rcx,%xmm0
  movsd  %xmm2,(%rsp)
  movsd  D54(%rip),%xmm2
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L8:
  movsd  (%rax),%xmm2
L17:
  addsd  %xmm3,%xmm1
  add    $0x8,%rax
  divsd  %xmm1,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L8
  mulsd  D65(%rip),%xmm0
  call   <log@plt>
  subsd  (%rsp),%xmm0
  add    $0x18,%rsp
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D41
data_type: f64
name: unpack_data
arguments: tag: D47
data_type: f64
name: unpack_data
arguments: tag: D69
data_type: f64
name: unpack_data
arguments: tag: D30
data_type: f64
name: unpack_data
arguments: tag: D54
data_type: f64
name: unpack_data
arguments: tag: D65
data_type: f64

tool: D41: 1

tool: D47: 5.5

tool: D69: 76.18009173

tool: D30: 0.5

tool: D54: 76.18009173

tool: D65: 2.50662827465

assistant: ```c
float gammln(float xx) {
  double x, tmp, ser;
  static double cof[6] = {76.18009173, -86.50532033, 24.01409822, -1.231739516, 0.120858003e-2, -0.536382e-5};
  int j;
  x = xx - 1.0;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.0;
  for (j = 0; j <= 5; j++) {
    x += 1.0;
    ser += cof[j] / x;
  }
  return -tmp + log(2.50662827465 * ser);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gammln>:
  endbr64
  sub    $0x28,%rsp
  movsd  D70(%rip),%xmm2
  cvtss2sd %xmm0,%xmm0
  movsd  D28(%rip),%xmm4
  subsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm4
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm4,%xmm0
  movsd  %xmm4,0x18(%rsp)
  call   <log@plt>
  mov    D70(%rip),%rax
  movsd  0x8(%rsp),%xmm1
  movsd  D98(%rip),%xmm3
  movsd  %xmm0,0x10(%rsp)
  movsd  D80(%rip),%xmm0
  movq   %rax,%xmm2
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm2,%xmm3
  addsd  %xmm3,%xmm0
  movsd  D39(%rip),%xmm3
  divsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm3
  movsd  D89(%rip),%xmm0
  divsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm0
  movsd  D34(%rip),%xmm3
  divsd  %xmm1,%xmm3
  addsd  %xmm2,%xmm1
  movsd  D1(%rip),%xmm2
  divsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm3
  movapd %xmm2,%xmm0
  addsd  %xmm3,%xmm0
  mulsd  D47(%rip),%xmm0
  call   <log@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  D109(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm4
  add    $0x28,%rsp
  subsd  %xmm1,%xmm4
  subsd  %xmm4,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D70
type: f64
name: read_data
arguments: data_tag: D28
type: f64
name: read_data
arguments: data_tag: D98
type: f64
name: read_data
arguments: data_tag: D80
type: byte[8]
name: read_data
arguments: data_tag: D39
type: f64
name: read_data
arguments: data_tag: D89
type: byte[8]
name: read_data
arguments: data_tag: D34
type: byte[8]
name: read_data
arguments: data_tag: D1
type: byte[8]
name: read_data
arguments: data_tag: D47
type: f64
name: read_data
arguments: data_tag: D109
type: f64

tool: D70: 1

tool: D28: 5.5

tool: D98: 76.18009173

tool: {"D80": [0xa7,0xd6,0x14,0x2b,0x57,0xa0,0x55,0xc0]}

tool: D39: 24.01409822

tool: {"D89": [0xeb,0x92,0xa6,0x7e,0x34,0xb5,0xf3,0xbf]}

tool: {"D34": [0xb1,0x4d,0x05,0xed,0x26,0xcd,0x53,0x3f]}

tool: {"D1": [0x31,0x21,0x65,0x9d,0x5b,0x7f,0xd6,0xbe]}

tool: D47: 2.50662827465

tool: D109: 0.5

assistant: ```c
float gammln(float xx) {
  double x, tmp, ser;
  static double cof[6] = {76.18009173, -86.50532033, 24.01409822, -1.231739516, 0.120858003e-2, -0.536382e-5};
  int j;
  x = xx - 1.0;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * log(tmp);
  ser = 1.0;
  for (j = 0; j <= 5; j++) {
    x += 1.0;
    ser += cof[j] / x;
  }
  return -tmp + log(2.50662827465 * ser);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<proto_Prepend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L35
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L35
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rdi
  mov    %edx,%ecx
  mov    $0x1,%edx
  mov    %rax,%rsi
  call   <m_prepend@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L11
L35:
  mov    -0x24(%rbp),%edx
  lea    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %rax,%rdi
  call   <m_prepend@plt>
  mov    %rax,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
struct mbuf *proto_Prepend(struct mbuf *bp, u_short proto, unsigned comp, int extra) {
  u_char cp[2];
  cp[0] = proto >> 8;
  cp[1] = proto & 0xff;
  if (comp && cp[0] == 0)
    bp = m_prepend(bp, cp + 1, 1, extra);
  else
    bp = m_prepend(bp, cp, 2, extra);
  return bp;
}
```
user: What is the c source code of the assembly code below:

```asm
<proto_Prepend>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,%eax
  sar    $0x8,%eax
  mov    %eax,(%rsp)
  and    $0xff,%esi
  mov    %esi,0x4(%rsp)
  test   %eax,%eax
  jne    L8
  test   %edx,%edx
  jne    L31
L8:
  mov    %rsp,%rsi
  mov    $0x2,%edx
  call   <m_prepend@plt>
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L31:
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <m_prepend@plt>
  jmp    L26
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct mbuf *proto_Prepend(struct mbuf *bp, u_short proto, unsigned comp, int extra) {
  u_char cp[2];
  cp[0] = proto >> 8;
  cp[1] = proto & 0xff;
  if (comp && cp[0] == 0)
    bp = m_prepend(bp, cp + 1, 1, extra);
  else
    bp = m_prepend(bp, cp, 2, extra);
  return bp;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<proto_Prepend>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    %esi,%eax
  and    $0xff,%esi
  mov    %esi,0x4(%rsp)
  sar    $0x8,%eax
  mov    %eax,(%rsp)
  test   %eax,%eax
  jne    L23
  test   %edx,%edx
  jne    L36
L23:
  mov    %rsp,%rsi
  mov    $0x2,%edx
  call   <m_prepend@plt>
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <m_prepend@plt>
  jmp    L14
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct mbuf *proto_Prepend(struct mbuf *bp, u_short proto, unsigned comp, int extra) {
  u_char cp[2];
  cp[0] = proto >> 8;
  cp[1] = proto & 0xff;
  if (comp && cp[0] == 0)
    bp = m_prepend(bp, cp + 1, 1, extra);
  else
    bp = m_prepend(bp, cp, 2, extra);
  return bp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<proto_Prepend>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    %esi,%eax
  movzbl %sil,%esi
  movd   %esi,%xmm1
  sar    $0x8,%eax
  movd   %eax,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  jne    L19
  test   %edx,%edx
  jne    L29
L19:
  mov    %rsp,%rsi
  mov    $0x2,%edx
  call   <m_prepend@plt>
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <m_prepend@plt>
  jmp    L23
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct mbuf *proto_Prepend(struct mbuf *bp, u_short proto, unsigned comp, int extra) {
  u_char cp[2];
  cp[0] = proto >> 8;
  cp[1] = proto & 0xff;
  if (comp && cp[0] == 0)
    bp = m_prepend(bp, cp + 1, 1, extra);
  else
    bp = m_prepend(bp, cp, 2, extra);
  return bp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<printResults>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   $0x3d0900,%eax,%eax
  mov    -0x18(%rbp),%rdx
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <report@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <compare@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L11
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L15
L11:
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L15:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D28: Count: %d


tool: D26: Success!

tool: D9: Try again :)

assistant: ```c
void printResults(double cycleNS, int count, int *actual, int *expected) {
  report(((2000 * 2000) * count), cycleNS);
  printf("Count: %d\n", count);
  int equal = compare(actual, expected);
  if (equal)
    printf("Success!\n");
  else
    printf("Try again :)\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printResults>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  imul   $0x3d0900,%edi,%edi
  call   <report@plt>
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <compare@plt>
  test   %eax,%eax
  je     L11
  lea    D13(%rip),%rdi
  call   <puts@plt>
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  lea    D28(%rip),%rdi
  call   <puts@plt>
  jmp    L7
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string
name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D28
type: string

tool: D8: Count: %d


tool: D13: Success!

tool: D28: Try again :)

assistant: ```c
void printResults(double cycleNS, int count, int *actual, int *expected) {
  report(((2000 * 2000) * count), cycleNS);
  printf("Count: %d\n", count);
  int equal = compare(actual, expected);
  if (equal)
    printf("Success!\n");
  else
    printf("Try again :)\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printResults>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  imul   $0x3d0900,%edi,%edi
  call   <report@plt>
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <compare@plt>
  test   %eax,%eax
  je     L1
  pop    %rbp
  lea    D4(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
  nopl   0x0(%rax)
L1:
  pop    %rbp
  lea    D26(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string

tool: D10: Count: %d


tool: D4: Success!

tool: D26: Try again :)

assistant: ```c
void printResults(double cycleNS, int count, int *actual, int *expected) {
  report(((2000 * 2000) * count), cycleNS);
  printf("Count: %d\n", count);
  int equal = compare(actual, expected);
  if (equal)
    printf("Success!\n");
  else
    printf("Try again :)\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printResults>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  imul   $0x3d0900,%edi,%edi
  call   <report@plt>
  mov    %ebp,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <compare@plt>
  test   %eax,%eax
  je     L4
  pop    %rbp
  lea    D16(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
  nopl   0x0(%rax)
L4:
  pop    %rbp
  lea    D27(%rip),%rdi
  pop    %r12
  pop    %r13
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string
name: retrieve_data
arguments: data_tag: D16
datatype: string
name: retrieve_data
arguments: data_tag: D27
datatype: string

tool: D3: Count: %d


tool: D16: Success!

tool: D27: Try again :)

assistant: ```c
void printResults(double cycleNS, int count, int *actual, int *expected) {
  report(((2000 * 2000) * count), cycleNS);
  printf("Count: %d\n", count);
  int equal = compare(actual, expected);
  if (equal)
    printf("Success!\n");
  else
    printf("Try again :)\n");
}
```