ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rcx
  mov    %rcx,%rax
  imul   $0x51eb851f,%rcx,%rcx
  cltd
  sar    $0x25,%rcx
  mov    %ecx,%esi
  sub    %edx,%ecx
  sub    %edx,%esi
  imul   $0x64,%esi,%edi
  sub    %edi,%eax
  lea    D19(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%esi
  sar    $0x1f,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%eax
  add    %eax,%eax
  sub    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D16
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D13: Enter a three digit number: 

tool: D16: %d

tool: D19: The reversal is: %d%d%d

assistant: ```c
int main(void) {
  int d, d1, d2, d3;
  printf("Enter a three digit number: ");
  scanf("%d", &d);
  d1 = d / 100;
  d2 = (d % 100) / 10;
  d3 = (d % 100) % 10;
  printf("The reversal is: %d%d%d", d3, d2, d1);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<game_over>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <do_gameover@plt>
  mov    $0x0,%eax
  call   <do_hiscores@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void game_over() {
  do_gameover();
  do_hiscores();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<game_over>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <do_gameover@plt>
  mov    $0x0,%eax
  call   <do_hiscores@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void game_over() {
  do_gameover();
  do_hiscores();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<game_over>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_gameover@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <do_hiscores@plt>
```

assistant: ```c
void game_over() {
  do_gameover();
  do_hiscores();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<game_over>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <do_gameover@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <do_hiscores@plt>
```

assistant: ```c
void game_over() {
  do_gameover();
  do_hiscores();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factor_iteration>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L0
L10:
  mov    -0xc(%rbp),%eax
  cltq
  mov    -0x8(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x18(%rbp)
  jge    L10
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long factor_iteration(long n) {
  long final_value = 1;
  for (int i = 1; i <= n; ++i) {
    final_value *= i;
  }
  return final_value;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<factor_iteration>:
  endbr64
  test   %rdi,%rdi
  jle    L19
  mov    $0x1,%eax
  mov    $0x1,%edx
L9:
  imul   %rax,%rdx
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rdi,%rcx
  jne    L9
L4:
  mov    %rdx,%rax
  ret
L19:
  mov    $0x1,%edx
  jmp    L4
```

assistant: ```c
long factor_iteration(long n) {
  long final_value = 1;
  for (int i = 1; i <= n; ++i) {
    final_value *= i;
  }
  return final_value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<factor_iteration>:
  endbr64
  test   %rdi,%rdi
  jle    L16
  mov    $0x1,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L19:
  mov    %rax,%rdx
  imul   %rax,%r8
  add    $0x1,%rax
  cmp    %rdi,%rdx
  jne    L19
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L16:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long factor_iteration(long n) {
  long final_value = 1;
  for (int i = 1; i <= n; ++i) {
    final_value *= i;
  }
  return final_value;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<factor_iteration>:
  endbr64
  test   %rdi,%rdi
  jle    L18
  mov    $0x1,%eax
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L15:
  mov    %rax,%rdx
  imul   %rax,%r8
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L15
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L18:
  mov    $0x1,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long factor_iteration(long n) {
  long final_value = 1;
  for (int i = 1; i <= n; ++i) {
    final_value *= i;
  }
  return final_value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x1e8000(%rsp),%r11
L10:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L10
  sub    $0x4c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1e8498(%rbp)
  movl   $0x0,-0x1e84a8(%rbp)
  movl   $0x0,-0x1e84a4(%rbp)
  movl   $0x0,-0x1e84a0(%rbp)
  movl   $0x0,-0x1e849c(%rbp)
  lea    -0x1e84b4(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x1e84b0(%rbp)
  jmp    L21
L97:
  movl   $0x0,-0x1e849c(%rbp)
  movl   $0x0,-0x1e84a8(%rbp)
  lea    -0x1e8490(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x1e8490(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1e8494(%rbp)
  movl   $0x0,-0x1e84ac(%rbp)
  jmp    L27
L89:
  movl   $0x0,-0x1e84a4(%rbp)
  jmp    L36
L14:
  mov    -0x1e84ac(%rbp),%eax
  cltq
  movzbl -0x1e8490(%rbp,%rax,1),%edx
  mov    -0x1e84a4(%rbp),%eax
  cltq
  movzbl -0xf4250(%rbp,%rax,1),%eax
  cmp    %al,%dl
  jne    L19
  movl   $0x1,-0x1e84a0(%rbp)
L19:
  addl   $0x1,-0x1e84a4(%rbp)
L36:
  mov    -0x1e84a4(%rbp),%eax
  cmp    -0x1e84a8(%rbp),%eax
  jl     L14
  cmpl   $0x1,-0x1e84a0(%rbp)
  je     L83
  mov    -0x1e84ac(%rbp),%eax
  cltq
  movzbl -0x1e8490(%rbp,%rax,1),%edx
  mov    -0x1e849c(%rbp),%eax
  cltq
  mov    %dl,-0xf4250(%rbp,%rax,1)
  addl   $0x1,-0x1e849c(%rbp)
L83:
  mov    -0x1e849c(%rbp),%eax
  mov    %eax,-0x1e84a8(%rbp)
  movl   $0x0,-0x1e84a0(%rbp)
  addl   $0x1,-0x1e84ac(%rbp)
L27:
  mov    -0x1e84ac(%rbp),%eax
  cmp    -0x1e8494(%rbp),%eax
  jl     L89
  mov    -0x1e849c(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x1e84b0(%rbp)
L21:
  mov    -0x1e84b4(%rbp),%eax
  cmp    %eax,-0x1e84b0(%rbp)
  jl     L97
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type_infered: string
name: extract_symbolic_data
arguments: data_label: D25
type_infered: string

tool: D13: %d

tool: D25: %s

assistant: ```c
main() {
  int t, i, l, j, k, m = 0, n = 0, o = 0, p = 0, q = 0;
  char c[1000000], d[1000000];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    q = 0;
    n = 0;
    scanf("%s", c);
    l = strlen(c);
    for (j = 0; j < l; j++) {
      for (o = 0; o < n; o++) {
        if (c[j] == d[o])
          p = 1;
      }
      if (p != 1) {
        d[q] = c[j];
        q++;
      }
      n = q;
      p = 0;
    }
    printf("%d", q);
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L74:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L74
  sub    $0x4a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8498(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L113
  mov    $0x0,%ebp
  lea    D27(%rip),%r13
  lea    0xf4251(%rsp),%rbx
  lea    D23(%rip),%r12
  jmp    L80
L8:
  movslq %r9d,%rax
  movzbl (%r8),%edx
  mov    %dl,0xf4250(%rsp,%rax,1)
  add    $0x1,%r9d
L63:
  add    $0x1,%r8
  cmp    %r10,%r8
  je     L72
L77:
  test   %r9d,%r9d
  jle    L8
  movzbl (%r8),%esi
  lea    0xf4250(%rsp),%rax
  lea    -0x1(%r9),%ecx
  add    %rbx,%rcx
  mov    $0x0,%edx
L30:
  cmp    (%rax),%sil
  cmove  %edi,%edx
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L30
  cmp    $0x1,%edx
  jne    L8
  jmp    L63
L36:
  mov    $0x0,%r9d
L72:
  mov    %r9d,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jle    L113
L80:
  lea    0x10(%rsp),%r14
  mov    %r14,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L36
  mov    %r14,%r8
  lea    -0x1(%rax),%eax
  lea    0x11(%rsp,%rax,1),%r10
  mov    $0x0,%r9d
  mov    $0x1,%edi
  jmp    L77
L113:
  mov    0x1e8498(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x1e84a0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D27
type: string

tool: D23: %d

tool: D27: %s

assistant: ```c
main() {
  int t, i, l, j, k, m = 0, n = 0, o = 0, p = 0, q = 0;
  char c[1000000], d[1000000];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    q = 0;
    n = 0;
    scanf("%s", c);
    l = strlen(c);
    for (j = 0; j < l; j++) {
      for (o = 0; o < n; o++) {
        if (c[j] == d[o])
          p = 1;
      }
      if (p != 1) {
        d[q] = c[j];
        q++;
      }
      n = q;
      p = 0;
    }
    printf("%d", q);
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L61:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L61
  sub    $0x4b8,%rsp
  lea    D15(%rip),%r12
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1e84a8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  lea    0x21(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L88
  xor    %ebx,%ebx
  lea    0x20(%rsp),%rbp
  lea    D5(%rip),%r13
  mov    $0x1,%r15d
  lea    0xf4261(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L51:
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L46
  lea    -0x1(%rax),%r10d
  mov    %rbp,%rdi
  add    0x8(%rsp),%r10
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L17:
  movzbl (%rdi),%esi
  test   %r9d,%r9d
  je     L90
  lea    -0x1(%r9),%ecx
  lea    0xf4260(%rsp),%rax
  xor    %edx,%edx
  add    %r14,%rcx
  nopl   0x0(%rax)
L76:
  cmp    %sil,(%rax)
  cmove  %r15d,%edx
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L76
  cmp    $0x1,%edx
  je     L16
L90:
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %sil,0xf4260(%rsp,%rax,1)
L16:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  jne    L17
L47:
  mov    %r9d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebx,0x1c(%rsp)
  jg     L51
L88:
  mov    0x1e84a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x1e84b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L46:
  xor    %r9d,%r9d
  jmp    L47
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D15: %d

tool: D5: %s

assistant: ```c
main() {
  int t, i, l, j, k, m = 0, n = 0, o = 0, p = 0, q = 0;
  char c[1000000], d[1000000];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    q = 0;
    n = 0;
    scanf("%s", c);
    l = strlen(c);
    for (j = 0; j < l; j++) {
      for (o = 0; o < n; o++) {
        if (c[j] == d[o])
          p = 1;
      }
      if (p != 1) {
        d[q] = c[j];
        q++;
      }
      n = q;
      p = 0;
    }
    printf("%d", q);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0x4b8,%rsp
  lea    D16(%rip),%r12
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1e84a8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  lea    0x21(%rsp),%rax
  mov    %rax,0x8(%rsp)
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L49
  xor    %ebx,%ebx
  lea    0x20(%rsp),%rbp
  lea    D11(%rip),%r13
  mov    $0x1,%r15d
  lea    0xf4261(%rsp),%r14
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L31
  lea    -0x1(%rax),%r10d
  mov    %rbp,%rdi
  add    0x8(%rsp),%r10
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L54:
  movzbl (%rdi),%esi
  test   %r9d,%r9d
  je     L72
  lea    -0x1(%r9),%ecx
  lea    0xf4260(%rsp),%rax
  xor    %edx,%edx
  add    %r14,%rcx
  nopl   0x0(%rax)
L63:
  cmp    (%rax),%sil
  cmove  %r15d,%edx
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L63
  cmp    $0x1,%edx
  je     L70
L72:
  movslq %r9d,%rax
  add    $0x1,%r9d
  mov    %sil,0xf4260(%rsp,%rax,1)
L70:
  add    $0x1,%rdi
  cmp    %r10,%rdi
  jne    L54
L1:
  mov    %r9d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebx,0x1c(%rsp)
  jg     L64
L49:
  mov    0x1e84a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x1e84b8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  xor    %r9d,%r9d
  jmp    L1
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D16
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string

tool: D16: %d

tool: D11: %s

assistant: ```c
main() {
  int t, i, l, j, k, m = 0, n = 0, o = 0, p = 0, q = 0;
  char c[1000000], d[1000000];
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    q = 0;
    n = 0;
    scanf("%s", c);
    l = strlen(c);
    for (j = 0; j < l; j++) {
      for (o = 0; o < n; o++) {
        if (c[j] == d[o])
          p = 1;
      }
      if (p != 1) {
        d[q] = c[j];
        q++;
      }
      n = q;
      p = 0;
    }
    printf("%d", q);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2d,-0x30(%rbp)
  movl   $0x30,-0x2c(%rbp)
  movl   $0x18,-0x28(%rbp)
  movl   $0x18,-0x24(%rbp)
  movl   $0x39,-0x20(%rbp)
  movl   $0x57,-0x1c(%rbp)
  movl   $0x76,-0x18(%rbp)
  movl   $0x15,-0x14(%rbp)
  movl   $0x36,-0x10(%rbp)
  movl   $0x36,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L17
L27:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L17:
  cmpl   $0x9,-0x34(%rbp)
  jle    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D2
type_guessed: string

tool: D2: %d,

assistant: ```c
int main() {
  int a[10] = {45, 48, 24, 24, 57, 87, 118, 21, 54, 54};
  quickSort(a, 10);
  for (int i = 0; i < 10; i++) {
    printf("%d,", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x2d,(%rsp)
  movl   $0x30,0x4(%rsp)
  movl   $0x18,0x8(%rsp)
  movl   $0x18,0xc(%rsp)
  movl   $0x39,0x10(%rsp)
  movl   $0x57,0x14(%rsp)
  movl   $0x76,0x18(%rsp)
  movl   $0x15,0x1c(%rsp)
  movl   $0x36,0x20(%rsp)
  movl   $0x36,0x24(%rsp)
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <quickSort@plt>
  lea    0x28(%rsp),%r12
  lea    D0(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: %d,

assistant: ```c
int main() {
  int a[10] = {45, 48, 24, 24, 57, 87, 118, 21, 54, 54};
  quickSort(a, 10);
  for (int i = 0; i < 10; i++) {
    printf("%d,", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x300000002d,%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  mov    %rbx,%rdi
  mov    %rax,(%rsp)
  movabs $0x1800000018,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x5700000039,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1500000076,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3600000036,%rax
  mov    %rax,0x20(%rsp)
  call   <quickSort@plt>
L5:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D9: %d,

assistant: ```c
int main() {
  int a[10] = {45, 48, 24, 24, 57, 87, 118, 21, 54, 54};
  quickSort(a, 10);
  for (int i = 0; i < 10; i++) {
    printf("%d,", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%esi
  push   %rbp
  lea    D31(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D23(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    D11(%rip),%rax
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D25(%rip),%xmm0
  mov    %rbx,%rdi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <quickSort@plt>
  nopl   (%rax)
L6:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L6
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D31
type: string
name: disassemble_data
arguments: label: D23
type: byte[16]
name: disassemble_data
arguments: label: D11
type: byte[8]
name: disassemble_data
arguments: label: D25
type: byte[16]

tool: D31: %d,

tool: {"D23": [0x2d,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x18,0x00,0x00,0x00,0x18,0x00,0x00,0x00]}

tool: {"D11": [0x36,0x00,0x00,0x00,0x36,0x00,0x00,0x00]}

tool: {"D25": [0x39,0x00,0x00,0x00,0x57,0x00,0x00,0x00,0x76,0x00,0x00,0x00,0x15,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int a[10] = {45, 48, 24, 24, 57, 87, 118, 21, 54, 54};
  quickSort(a, 10);
  for (int i = 0; i < 10; i++) {
    printf("%d,", a[i]);
  }
  printf("\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<alpha_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x3f,-0x1(%rbp)
  movzbl -0x14(%rbp),%eax
  cmp    $0x48,%eax
  ja     L133
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D0(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D0(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  movzbl -0x14(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x1(%rbp)
  jmp    L127
  movb   $0x20,-0x1(%rbp)
  jmp    L127
  movzbl -0x14(%rbp),%eax
  add    $0x36,%eax
  mov    %al,-0x1(%rbp)
  jmp    L127
  movzbl -0x14(%rbp),%eax
  add    $0x3c,%eax
  mov    %al,-0x1(%rbp)
  jmp    L127
  movb   $0x2d,-0x1(%rbp)
  jmp    L127
  movb   $0x25,-0x1(%rbp)
  jmp    L127
  movb   $0x2f,-0x1(%rbp)
  jmp    L127
  movb   $0x28,-0x1(%rbp)
  jmp    L127
  movb   $0x29,-0x1(%rbp)
  jmp    L127
  movb   $0x2a,-0x1(%rbp)
  jmp    L127
  movb   $0x2b,-0x1(%rbp)
  jmp    L127
  movb   $0x2e,-0x1(%rbp)
  jmp    L127
  movb   $0x3a,-0x1(%rbp)
  jmp    L127
  movb   $0x3f,-0x1(%rbp)
  jmp    L127
L133:
  nop
L127:
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char alpha_map(unsigned char c) {
  char a = '?';
  switch (c) {
  case 0:
  case 1:
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
  case 7:
  case 8:
  case 9:
    a = '0' + c;
    break;
  case 10:
    a = ' ';
    break;
  case 11:
  case 12:
  case 13:
  case 14:
  case 15:
  case 16:
  case 17:
  case 18:
  case 19:
  case 20:
  case 21:
  case 22:
  case 23:
  case 24:
  case 25:
  case 26:
  case 27:
  case 28:
  case 29:
  case 30:
  case 31:
  case 32:
  case 33:
  case 34:
  case 35:
  case 36:
    a = 'A' + c - 11;
    break;
  case 37:
  case 38:
  case 39:
  case 40:
  case 41:
  case 42:
  case 43:
  case 44:
  case 45:
  case 46:
  case 47:
  case 48:
  case 49:
  case 50:
  case 51:
  case 52:
  case 53:
  case 54:
  case 55:
  case 56:
  case 57:
  case 58:
  case 59:
  case 60:
  case 61:
  case 62:
    a = 'a' + c - 37;
    break;
  case 63:
    a = '-';
    break;
  case 64:
    a = '%';
    break;
  case 65:
    a = '/';
    break;
  case 66:
    a = '(';
    break;
  case 67:
    a = ')';
    break;
  case 68:
    a = '*';
    break;
  case 69:
    a = '+';
    break;
  case 70:
    a = '.';
    break;
  case 71:
    a = ':';
    break;
  case 72:
    a = '?';
    break;
  default:
    break;
  }
  return a;
}
```