ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<make_space>:
  endbr64
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%rsi
  cmp    %rdx,%rsi
  jbe    L24
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L24:
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  add    %rsi,%rsi
  call   <realloc@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,0x0(%rbp)
  mov    %r12d,%eax
  shlq   (%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %r12d,%r12d
  jmp    L26
```

assistant: ```c
bool make_space(char **buf, size_t *buflen, size_t position) {
  char *tmp;
  if (position < *buflen) {
    return true;
  }
  tmp = realloc(*buf, (*buflen) * 2);
  if (tmp == NULL) {
    return false;
  }
  *buf = tmp;
  *buflen *= 2;
  return true;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_executable>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  test   %rdi,%rdi
  je     L7
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
  cmp    $0x2f,%al
  je     L32
  lea    D29(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L58
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,0x8(%rsp)
  lea    D15(%rip),%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L35
  lea    D36(%rip),%r14
  lea    D15(%rip),%r15
L90:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x2(%rbx,%rax,1),%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strncat@plt>
  mov    %rbx,%rdi
  call   <myaccess@plt>
  test   %rax,%rax
  je     L49
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r15,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L90
  mov    %rax,%rbx
L49:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L58:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  call   <myaccess@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  jne    L58
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %rax,%rbx
  jmp    L58
L35:
  mov    %rax,%rbx
  jmp    L49
L7:
  mov    %rdi,%rbx
  jmp    L58
L15:
  mov    $0x0,%ebx
  jmp    L58
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: string
name: retrieve_data
arguments: data_tag: D36
type_infered: string

tool: D29: PATH

tool: D15: :

tool: D36: /

assistant: ```c
char *find_executable(const char *fn) {
  char *s, *path, *t = NULL;
  if (fn == NULL || *fn == '\0')
    return NULL;
  if (*fn == '/') {
    if (myaccess(fn) == 0)
      return strdup(fn);
    else
      return NULL;
  }
  if ((s = getenv("PATH")) == NULL) {
    return NULL;
  } else {
    path = strdup(s);
  }
  for (s = strtok(path, ":"); s; s = strtok(NULL, ":")) {
    size_t len = strlen(fn) + strlen(s) + 2;
    t = (char *)malloc(len);
    strncpy(t, s, len);
    strncat(t, "/", len);
    strncat(t, fn, len);
    if (myaccess(t) == 0)
      break;
    else {
      free((void *)t);
      t = NULL;
    }
  }
  free((void *)path);
  return t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_executable>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L56
  movzbl (%rdi),%eax
  mov    %rdi,%r12
  test   %al,%al
  je     L56
  cmp    $0x2f,%al
  je     L73
  lea    D28(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L56
  call   <strdup@plt>
  lea    D12(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L64
  lea    D19(%rip),%r13
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L40:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L64
L27:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%edx
  movslq %edx,%r15
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <strncpy@plt>
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdi
  mov    %r15,%rdx
  mov    %r12,%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <myaccess@plt>
  test   %rax,%rax
  jne    L40
L30:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L19:
  mov    (%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L73:
  call   <myaccess@plt>
  test   %rax,%rax
  je     L7
L56:
  movq   $0x0,(%rsp)
  jmp    L19
  nopl   0x0(%rax)
L64:
  movq   $0x0,(%rsp)
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x18,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1150 <strdup@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
type: string
name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D28: PATH

tool: D12: :

tool: D19: /

assistant: ```c
char *find_executable(const char *fn) {
  char *s, *path, *t = NULL;
  if (fn == NULL || *fn == '\0')
    return NULL;
  if (*fn == '/') {
    if (myaccess(fn) == 0)
      return strdup(fn);
    else
      return NULL;
  }
  if ((s = getenv("PATH")) == NULL) {
    return NULL;
  } else {
    path = strdup(s);
  }
  for (s = strtok(path, ":"); s; s = strtok(NULL, ":")) {
    size_t len = strlen(fn) + strlen(s) + 2;
    t = (char *)malloc(len);
    strncpy(t, s, len);
    strncat(t, "/", len);
    strncat(t, fn, len);
    if (myaccess(t) == 0)
      break;
    else {
      free((void *)t);
      t = NULL;
    }
  }
  free((void *)path);
  return t;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_executable>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rdi,%rdi
  je     L66
  movzbl (%rdi),%eax
  mov    %rdi,%r12
  test   %al,%al
  je     L66
  cmp    $0x2f,%al
  je     L36
  lea    D0(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L66
  call   <strdup@plt>
  lea    D8(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  mov    %rax,0x8(%rsp)
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L65
  lea    D15(%rip),%r13
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rsi
  xor    %edi,%edi
  call   <strtok@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L65
L41:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x2(%rbp,%rax,1),%edx
  movslq %edx,%r15
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <strncpy@plt>
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  mov    %rbp,%rdi
  mov    %r15,%rdx
  mov    %r12,%rsi
  call   <strncat@plt>
  mov    %rbp,%rdi
  call   <myaccess@plt>
  test   %rax,%rax
  jne    L19
L79:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
L30:
  mov    (%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  call   <myaccess@plt>
  test   %rax,%rax
  je     L59
L66:
  movq   $0x0,(%rsp)
  jmp    L30
  nopl   0x0(%rax)
L65:
  movq   $0x0,(%rsp)
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L59:
  add    $0x18,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1150 <strdup@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string

tool: D0: PATH

tool: D8: :

tool: D15: /

assistant: ```c
char *find_executable(const char *fn) {
  char *s, *path, *t = NULL;
  if (fn == NULL || *fn == '\0')
    return NULL;
  if (*fn == '/') {
    if (myaccess(fn) == 0)
      return strdup(fn);
    else
      return NULL;
  }
  if ((s = getenv("PATH")) == NULL) {
    return NULL;
  } else {
    path = strdup(s);
  }
  for (s = strtok(path, ":"); s; s = strtok(NULL, ":")) {
    size_t len = strlen(fn) + strlen(s) + 2;
    t = (char *)malloc(len);
    strncpy(t, s, len);
    strncat(t, "/", len);
    strncat(t, fn, len);
    if (myaccess(t) == 0)
      break;
    else {
      free((void *)t);
      t = NULL;
    }
  }
  free((void *)path);
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<clr_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L26
L21:
  mov    -0x24(%rbp),%edi
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  je     L10
  mov    $0x0,%eax
  jmp    L23
L10:
  addl   $0x2,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L21
  mov    $0x1,%eax
L23:
  leave
  ret
```

assistant: ```c
int clr_row(char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<clr_row>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %ecx,%ebx
  and    $0x1,%ebx
  cmp    %edx,%ebx
  jge    L11
  mov    %rdi,%r13
  mov    %esi,%r14d
  mov    %edx,%ebp
  mov    %ecx,%r12d
  lea    -0x1(%rdx),%eax
  sub    %ebx,%eax
  and    $0xfffffffe,%eax
  lea    0x2(%rbx,%rax,1),%r15d
L36:
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  jne    L9
  add    $0x2,%ebx
  cmp    %r15d,%ebx
  jne    L36
  mov    $0x1,%eax
  jmp    L27
L11:
  mov    $0x1,%eax
  jmp    L27
L9:
  mov    $0x0,%eax
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int clr_row(char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clr_row>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  and    $0x1,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%ebx
  jge    L17
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  sub    %ebx,%eax
  mov    %ecx,%r15d
  and    $0xfffffffe,%eax
  lea    0x2(%rbx,%rax,1),%r14d
  jmp    L34
  nopl   (%rax)
L36:
  add    $0x2,%ebx
  cmp    %r14d,%ebx
  je     L17
L34:
  mov    %r15d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  je     L36
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int clr_row(char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<clr_row>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  and    $0x1,%ebx
  sub    $0x8,%rsp
  cmp    %edx,%ebx
  jge    L23
  lea    -0x1(%rdx),%eax
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebp
  sub    %ebx,%eax
  mov    %ecx,%r15d
  and    $0xfffffffe,%eax
  lea    0x2(%rbx,%rax,1),%r14d
  jmp    L20
  nopl   (%rax)
L1:
  add    $0x2,%ebx
  cmp    %r14d,%ebx
  je     L23
L20:
  mov    %r15d,%r8d
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <get_dot@plt>
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int clr_row(char *Dots, const int Hgt, const int Wid, const int y) {
  int x;
  for (x = y & 1; x < Wid; x += 2) {
    if (get_dot(Dots, Hgt, Wid, x, y)) {
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memparse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <simple_strtoul@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x47,%eax
  cmp    $0x26,%eax
  seta   %dl
  test   %dl,%dl
  jne    L3
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  movabs $0x1000000010,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L29
  movabs $0x4000000040,%rdx
  and    %rax,%rdx
  test   %rdx,%rdx
  setne  %dl
  test   %dl,%dl
  jne    L30
  movabs $0x100000001,%rdx
  and    %rdx,%rax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L3
  shlq   $0xa,-0x8(%rbp)
L30:
  shlq   $0xa,-0x8(%rbp)
L29:
  shlq   $0xa,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
L3:
  nop
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long memparse(char *ptr, char **retptr) {
  unsigned long ret = simple_strtoul(ptr, retptr, 0);
  switch (**retptr) {
  case 'G':
  case 'g':
    ret <<= 10;
  case 'M':
  case 'm':
    ret <<= 10;
  case 'K':
  case 'k':
    ret <<= 10;
    (*retptr)++;
  default:
    break;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memparse>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x0,%edx
  call   <simple_strtoul@plt>
  mov    (%rbx),%rsi
  movzbl (%rsi),%edx
  lea    -0x47(%rdx),%ecx
  cmp    $0x26,%cl
  ja     L17
  mov    $0x1,%edx
  shl    %cl,%rdx
  movabs $0x1000000010,%rcx
  test   %rcx,%rdx
  jne    L19
  movabs $0x4000000040,%rcx
  test   %rcx,%rdx
  jne    L13
  movabs $0x100000001,%rcx
  test   %rcx,%rdx
  je     L17
  shl    $0xa,%rax
L13:
  shl    $0xa,%rax
L19:
  shl    $0xa,%rax
  add    $0x1,%rsi
  mov    %rsi,(%rbx)
L17:
  pop    %rbx
  ret
```

assistant: ```c
unsigned long memparse(char *ptr, char **retptr) {
  unsigned long ret = simple_strtoul(ptr, retptr, 0);
  switch (**retptr) {
  case 'G':
  case 'g':
    ret <<= 10;
  case 'M':
  case 'm':
    ret <<= 10;
  case 'K':
  case 'k':
    ret <<= 10;
    (*retptr)++;
  default:
    break;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<memparse>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %rsi,%rbx
  call   <simple_strtoul@plt>
  mov    (%rbx),%rsi
  movzbl (%rsi),%edx
  lea    -0x47(%rdx),%ecx
  cmp    $0x26,%cl
  ja     L16
  mov    $0x1,%edx
  shl    %cl,%rdx
  movabs $0x1000000010,%rcx
  test   %rcx,%rdx
  jne    L7
  movabs $0x4000000040,%rcx
  test   %rcx,%rdx
  jne    L23
  movabs $0x100000001,%rcx
  test   %rcx,%rdx
  jne    L31
L16:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L31:
  shl    $0xa,%rax
L23:
  shl    $0xa,%rax
L7:
  add    $0x1,%rsi
  shl    $0xa,%rax
  mov    %rsi,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
unsigned long memparse(char *ptr, char **retptr) {
  unsigned long ret = simple_strtoul(ptr, retptr, 0);
  switch (**retptr) {
  case 'G':
  case 'g':
    ret <<= 10;
  case 'M':
  case 'm':
    ret <<= 10;
  case 'K':
  case 'k':
    ret <<= 10;
    (*retptr)++;
  default:
    break;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<memparse>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %rsi,%rbx
  call   <simple_strtoul@plt>
  mov    (%rbx),%rsi
  movzbl (%rsi),%edx
  lea    -0x47(%rdx),%ecx
  cmp    $0x26,%cl
  ja     L0
  mov    $0x1,%edx
  shl    %cl,%rdx
  movabs $0x1000000010,%rcx
  test   %rcx,%rdx
  jne    L5
  movabs $0x4000000040,%rcx
  test   %rcx,%rdx
  jne    L26
  movabs $0x100000001,%rcx
  test   %rcx,%rdx
  jne    L15
L0:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L15:
  shl    $0xa,%rax
L26:
  shl    $0xa,%rax
L5:
  add    $0x1,%rsi
  shl    $0xa,%rax
  mov    %rsi,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
unsigned long memparse(char *ptr, char **retptr) {
  unsigned long ret = simple_strtoul(ptr, retptr, 0);
  switch (**retptr) {
  case 'G':
  case 'g':
    ret <<= 10;
  case 'M':
  case 'm':
    ret <<= 10;
  case 'K':
  case 'k':
    ret <<= 10;
    (*retptr)++;
  default:
    break;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bx_unicode_sqlite3StrNICmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
L44:
  mov    -0x18(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <bx_unicode_sqlite3Utf8Read@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x10(%rbp),%rax
  lea    -0x10(%rbp),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <bx_unicode_sqlite3Utf8Read@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  sub    -0x40(%rbp),%rax
  cmp    %rax,%rdx
  jle    L71
  mov    -0x18(%rbp),%rax
  sub    -0x38(%rbp),%rax
  jmp    L35
L71:
  mov    -0x10(%rbp),%rax
  sub    -0x40(%rbp),%rax
L35:
  mov    %eax,-0x1c(%rbp)
  mov    -0x44(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L53
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  mov    -0x24(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L44
L53:
  cmpl   $0x0,-0x44(%rbp)
  js     L64
  mov    -0x24(%rbp),%eax
  sub    -0x20(%rbp),%eax
  jmp    L70
L64:
  mov    $0x0,%eax
L70:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp(const unsigned char *zLeft, const unsigned char *zRight, int N) {
  const unsigned char *a = zLeft;
  const unsigned char *b = zRight;
  signed int ua = 0, ub = 0;
  int Z = 0;
  do {
    ua = bx_unicode_sqlite3Utf8Read(a, 0, &a);
    ub = bx_unicode_sqlite3Utf8Read(b, 0, &b);
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    Z = (int)(((a - zLeft) > (b - zRight)) ? (a - zLeft) : (b - zRight));
  } while (N > Z && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bx_unicode_sqlite3StrNICmp>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  lea    0x8(%rsp),%r14
L27:
  mov    %r14,%rdx
  mov    $0x0,%esi
  mov    0x8(%rsp),%rdi
  call   <bx_unicode_sqlite3Utf8Read@plt>
  mov    %eax,%ebx
  lea    0x10(%rsp),%rdx
  mov    $0x0,%esi
  mov    0x10(%rsp),%rdi
  call   <bx_unicode_sqlite3Utf8Read@plt>
  mov    %eax,%r15d
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    %eax,%ebx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %r15d,%edi
  call   <bx_unicode_sqlite3_unicode_unacc@plt>
  mov    %eax,%edi
  call   <bx_unicode_sqlite3_unicode_fold@plt>
  mov    0x8(%rsp),%rsi
  mov    %rsi,%rcx
  sub    %r13,%rcx
  mov    0x10(%rsp),%rdx
  sub    %r12,%rdx
  cmp    %rdx,%rcx
  cmovg  %ecx,%edx
  cmp    %ebp,%edx
  jge    L25
  cmpb   $0x0,(%rsi)
  je     L25
  cmp    %eax,%ebx
  je     L27
L25:
  sub    %eax,%ebx
  test   %ebp,%ebp
  mov    $0x0,%eax
  cmovns %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bx_unicode_sqlite3StrNICmp(const unsigned char *zLeft, const unsigned char *zRight, int N) {
  const unsigned char *a = zLeft;
  const unsigned char *b = zRight;
  signed int ua = 0, ub = 0;
  int Z = 0;
  do {
    ua = bx_unicode_sqlite3Utf8Read(a, 0, &a);
    ub = bx_unicode_sqlite3Utf8Read(b, 0, &b);
    ua = ua = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ua, 0, 0));
    ub = ub = bx_unicode_sqlite3_unicode_fold(bx_unicode_sqlite3_unicode_unacc(ub, 0, 0));
    Z = (int)(((a - zLeft) > (b - zRight)) ? (a - zLeft) : (b - zRight));
  } while (N > Z && *a != 0 && ua == ub);
  return N < 0 ? 0 : ua - ub;
}
```