ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_dir_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L24
  cmpq   $0x0,-0x20(%rbp)
  jne    L134
L24:
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D26(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L142
L134:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L13
L167:
  subq   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L61
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L167
  jmp    L61
L42:
  subq   $0x1,-0x10(%rbp)
L61:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L84
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L42
  jmp    L84
L144:
  subq   $0x1,-0x10(%rbp)
L84:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L90
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L144
L90:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L32
  cmpq   $0x1,-0x28(%rbp)
  ja     L177
  mov    D44(%rip),%rax
  mov    (%rax),%edx
  mov    D26(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L142
L177:
  mov    -0x20(%rbp),%rax
  movb   $0x2e,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L3
L32:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L25
  mov    D44(%rip),%rax
  mov    (%rax),%edx
  mov    D26(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L142
L25:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x20(%rbp),%rax
L142:
  leave
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  size_t len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if (len >= dstdirlen) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L55
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  test   %rsi,%rsi
  je     L55
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rax
  cmp    %rax,%rbp
  jae    L83
L135:
  cmpb   $0x2f,(%rax)
  jne    L181
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jne    L135
  mov    %rbp,%rax
L199:
  cmpb   $0x2f,(%rax)
  je     L154
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jbe    L199
L138:
  cmp    %rax,%rbp
  jae    L101
L136:
  cmpb   $0x2f,(%rax)
  jne    L209
  sub    $0x1,%rax
  cmp    %rax,%rbp
  jb     L136
L209:
  cmp    %rax,%rbp
  ja     L101
  sub    %rbp,%rax
  mov    %rax,%rbx
  lea    0x1(%rax),%rdx
  cmp    %r13,%rdx
  jae    L56
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  mov    %r12,%rax
  jmp    L129
L55:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L129
L181:
  cmp    %rax,%rbp
  jbe    L199
  jmp    L138
L154:
  cmp    %rax,%rbp
  jb     L136
  jmp    L209
L29:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L129
L56:
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L129
L83:
  jbe    L199
L101:
  cmp    $0x1,%r13
  jbe    L29
  movb   $0x2e,(%r12)
  movb   $0x0,0x1(%r12)
  mov    %r12,%rax
L129:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  size_t len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if (len >= dstdirlen) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L58
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L58
  mov    %rdi,%rbp
  mov    %rdx,%r13
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  cmp    %rcx,%rbp
  jb     L0
  jmp    L74
  nopl   0x0(%rax)
L171:
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  je     L46
L0:
  cmpb   $0x2f,(%rcx)
  je     L171
  jmp    L72
L74:
  ja     L60
  nopw   0x0(%rax,%rax,1)
L46:
  movzbl (%rcx),%edi
  cmp    $0x2f,%dil
  je     L160
  sub    $0x1,%rcx
L72:
  cmp    %rcx,%rbp
  jbe    L46
  cmp    %rbp,%rcx
  ja     L62
  jmp    L60
  nopl   0x0(%rax)
L101:
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  jae    L16
L62:
  movzbl (%rcx),%edi
L100:
  cmp    $0x2f,%dil
  je     L101
L16:
  cmp    %rcx,%rbp
  jbe    L153
L60:
  cmp    $0x1,%r13
  jbe    L52
  mov    $0x2e,%eax
  mov    %ax,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L153:
  mov    %rcx,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%rdx
  cmp    %r13,%rdx
  jae    L52
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L160:
  cmp    %rcx,%rbp
  jb     L100
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L58:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L52:
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  size_t len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if (len >= dstdirlen) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_dir_name>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L34
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L34
  mov    %rdi,%rbp
  mov    %rdx,%r13
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rcx
  cmp    %rcx,%rbp
  jb     L14
  jmp    L121
  nopl   0x0(%rax)
L0:
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  je     L140
L14:
  cmpb   $0x2f,(%rcx)
  je     L0
  jmp    L33
L121:
  ja     L23
  nopw   0x0(%rax,%rax,1)
L140:
  cmpb   $0x2f,(%rcx)
  je     L38
  sub    $0x1,%rcx
L33:
  cmp    %rcx,%rbp
  jbe    L140
  cmp    %rbp,%rcx
  jbe    L23
  nopl   0x0(%rax,%rax,1)
L52:
  cmpb   $0x2f,(%rcx)
  jne    L49
  sub    $0x1,%rcx
L38:
  cmp    %rcx,%rbp
  jb     L52
L49:
  cmp    %rcx,%rbp
  ja     L23
  mov    %rcx,%rbx
  sub    %rbp,%rbx
  lea    0x1(%rbx),%rdx
  cmp    %r13,%rdx
  jae    L5
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x1(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L23:
  cmp    $0x1,%r13
  jbe    L5
  mov    $0x2e,%eax
  mov    %ax,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L5:
  mov    D29(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    %edx,(%rax)
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *get_dir_name(const char *srcpath, char *dstdir, size_t dstdirlen) {
  const char *p;
  size_t len;
  if ((srcpath == NULL) || (dstdir == NULL)) {
    errno = EINVAL;
    return (NULL);
  }
  p = srcpath + strlen(srcpath) - 1;
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  while ((p >= srcpath) && (*p != '/')) {
    p--;
  }
  while ((p > srcpath) && (*p == '/')) {
    p--;
  }
  if (p < srcpath) {
    if (dstdirlen < 2) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    dstdir[0] = '.';
    dstdir[1] = '\0';
  } else {
    len = p - srcpath + 1;
    if (len >= dstdirlen) {
      errno = ENAMETOOLONG;
      return (NULL);
    }
    (void)strncpy(dstdir, srcpath, len);
    dstdir[len] = '\0';
  }
  return (dstdir);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<idct4x4dc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  mov    %rsp,%rdx
  lea    0x8(%rsp),%rbp
  mov    %rdx,%rcx
L15:
  movswl (%rdi),%r8d
  movswl 0x2(%rdi),%r11d
  movswl 0x4(%rdi),%eax
  movswl 0x6(%rdi),%r10d
  lea    (%r8,%r11,1),%r9d
  lea    (%rax,%r10,1),%ebx
  lea    (%rbx,%r9,1),%r12d
  mov    %r12w,(%rcx)
  sub    %ebx,%r9d
  mov    %r9w,0x8(%rcx)
  sub    %r11d,%r8d
  sub    %r10d,%eax
  mov    %r8d,%r9d
  sub    %eax,%r9d
  mov    %r9w,0x10(%rcx)
  add    %r8d,%eax
  mov    %ax,0x18(%rcx)
  add    $0x8,%rdi
  add    $0x2,%rcx
  cmp    %rbp,%rcx
  jne    L15
  lea    0x20(%rdx),%rbx
L12:
  movswl (%rdx),%ecx
  movswl 0x2(%rdx),%r9d
  movswl 0x4(%rdx),%eax
  movswl 0x6(%rdx),%r8d
  lea    (%rcx,%r9,1),%edi
  lea    (%rax,%r8,1),%r10d
  lea    (%r10,%rdi,1),%r11d
  mov    %r11w,(%rsi)
  sub    %r10d,%edi
  mov    %di,0x8(%rsi)
  sub    %r9d,%ecx
  sub    %r8d,%eax
  mov    %ecx,%edi
  sub    %eax,%edi
  mov    %di,0x10(%rsi)
  add    %ecx,%eax
  mov    %ax,0x18(%rsi)
  add    $0x8,%rdx
  add    $0x2,%rsi
  cmp    %rbx,%rdx
  jne    L12
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void idct4x4dc(short d[4][4]) {
  short tmp[4][4];
  int s01, s23;
  int d01, d23;
  int i;
  for (i = 0; i < 4; i++) {
    s01 = d[i][0] + d[i][1];
    d01 = d[i][0] - d[i][1];
    s23 = d[i][2] + d[i][3];
    d23 = d[i][2] - d[i][3];
    tmp[0][i] = s01 + s23;
    tmp[1][i] = s01 - s23;
    tmp[2][i] = d01 - d23;
    tmp[3][i] = d01 + d23;
  }
  for (i = 0; i < 4; i++) {
    s01 = tmp[i][0] + tmp[i][1];
    d01 = tmp[i][0] - tmp[i][1];
    s23 = tmp[i][2] + tmp[i][3];
    d23 = tmp[i][2] - tmp[i][3];
    d[0][i] = s01 + s23;
    d[1][i] = s01 - s23;
    d[2][i] = d01 - d23;
    d[3][i] = d01 + d23;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<idct4x4dc>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  lea    0x8(%rsp),%rbp
  mov    %rdx,%rcx
L20:
  movswl (%rdi),%r8d
  movswl 0x4(%rdi),%eax
  add    $0x2,%rcx
  add    $0x8,%rdi
  movswl -0x6(%rdi),%r11d
  movswl -0x2(%rdi),%r10d
  lea    (%r8,%r11,1),%r9d
  lea    (%rax,%r10,1),%ebx
  sub    %r11d,%r8d
  sub    %r10d,%eax
  lea    (%rbx,%r9,1),%r12d
  sub    %ebx,%r9d
  mov    %r9w,0x6(%rcx)
  mov    %r8d,%r9d
  sub    %eax,%r9d
  add    %r8d,%eax
  mov    %r12w,-0x2(%rcx)
  mov    %r9w,0xe(%rcx)
  mov    %ax,0x16(%rcx)
  cmp    %rcx,%rbp
  jne    L20
  lea    0x20(%rdx),%rbx
L12:
  movswl (%rdx),%ecx
  movswl 0x2(%rdx),%r9d
  add    $0x8,%rdx
  add    $0x2,%rsi
  movswl -0x4(%rdx),%eax
  movswl -0x2(%rdx),%r8d
  lea    (%rcx,%r9,1),%edi
  sub    %r9d,%ecx
  lea    (%rax,%r8,1),%r10d
  sub    %r8d,%eax
  lea    (%r10,%rdi,1),%r11d
  sub    %r10d,%edi
  mov    %di,0x6(%rsi)
  mov    %ecx,%edi
  sub    %eax,%edi
  add    %ecx,%eax
  mov    %r11w,-0x2(%rsi)
  mov    %di,0xe(%rsi)
  mov    %ax,0x16(%rsi)
  cmp    %rdx,%rbx
  jne    L12
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void idct4x4dc(short d[4][4]) {
  short tmp[4][4];
  int s01, s23;
  int d01, d23;
  int i;
  for (i = 0; i < 4; i++) {
    s01 = d[i][0] + d[i][1];
    d01 = d[i][0] - d[i][1];
    s23 = d[i][2] + d[i][3];
    d23 = d[i][2] - d[i][3];
    tmp[0][i] = s01 + s23;
    tmp[1][i] = s01 - s23;
    tmp[2][i] = d01 - d23;
    tmp[3][i] = d01 + d23;
  }
  for (i = 0; i < 4; i++) {
    s01 = tmp[i][0] + tmp[i][1];
    d01 = tmp[i][0] - tmp[i][1];
    s23 = tmp[i][2] + tmp[i][3];
    d23 = tmp[i][2] - tmp[i][3];
    d[0][i] = s01 + s23;
    d[1][i] = s01 - s23;
    d[2][i] = d01 - d23;
    d[3][i] = d01 + d23;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<os_check_compiler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x1,%eax
  jmp    L5
L11:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: test -f /usr/bin/gcc

assistant: ```c
int os_check_compiler() {
  if (system("test -f /usr/bin/gcc") == 0)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<os_check_compiler>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: test -f /usr/bin/gcc

assistant: ```c
int os_check_compiler() {
  if (system("test -f /usr/bin/gcc") == 0)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<os_check_compiler>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
datatype: string

tool: D9: test -f /usr/bin/gcc

assistant: ```c
int os_check_compiler() {
  if (system("test -f /usr/bin/gcc") == 0)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<os_check_compiler>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <system@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string

tool: D6: test -f /usr/bin/gcc

assistant: ```c
int os_check_compiler() {
  if (system("test -f /usr/bin/gcc") == 0)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_check_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  ja     L4
  cmpl   $0x10000000,-0xc(%rbp)
  jbe    L17
L4:
  mov    $0x11c,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L17:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c", 284));
  return word_ans;
}
```
user: What is the c source code of the assembly code below?

```asm
<_check_times>:
  endbr64
  push   %rbx
  mov    %edi,%edi
  mov    %esi,%esi
  imul   %rsi,%rdi
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    %rax,%rdi
  ja     L5
  cmp    $0x10000000,%edi
  jbe    L18
L5:
  mov    $0x11c,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L18:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c", 284));
  return word_ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L16
  cmp    $0x10000000,%edi
  ja     L16
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    $0x11c,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
data_type: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c", 284));
  return word_ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L2
  cmp    $0x10000000,%edi
  ja     L2
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x11c,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string

tool: D1: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/genfiles/position.c", 284));
  return word_ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x3,%eax
  je     L89
  cmp    $0x3,%eax
  jg     L0
  cmp    $0x1,%eax
  je     L3
  cmp    $0x2,%eax
  je     L48
  jmp    L0
L3:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L48:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L89:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L0:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L36:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string
name: disassemble_data
arguments: data_label: D49
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string
name: disassemble_data
arguments: data_label: D44
datatype: string

tool: D21: %d

tool: D13: ONE

tool: D49: TWO

tool: D25: THREE

tool: D44: Some other number

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 1:
    printf("ONE");
    break;
  case 2:
    printf("TWO");
    break;
  case 3:
    printf("THREE");
    break;
  default:
    printf("Some other number");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x2,%eax
  je     L61
  cmp    $0x3,%eax
  je     L22
  cmp    $0x1,%eax
  je     L69
  lea    D43(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L69:
  lea    D29(%rip),%rdi
  call   <printf@plt>
L52:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L61:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L22:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D35
type_infered: string
name: disassemble_data
arguments: data_label: D43
type_infered: string
name: disassemble_data
arguments: data_label: D29
type_infered: string
name: disassemble_data
arguments: data_label: D26
type_infered: string
name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D35: %d

tool: D43: Some other number

tool: D29: ONE

tool: D26: TWO

tool: D4: THREE

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  switch (n) {
  case 1:
    printf("ONE");
    break;
  case 2:
    printf("TWO");
    break;
  case 3:
    printf("THREE");
    break;
  default:
    printf("Some other number");
  }
  return 0;
}
```