ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getAmt>:
  endbr64
  push   %r15
  lea    D28(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <getInput@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L27
L143:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L108
  lea    -0x1(%rax),%ecx
  mov    %eax,%ebx
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  mov    %ecx,0xc(%rsp)
  lea    D27(%rip),%r15
  lea    D16(%rip),%r14
  jmp    L69
  nopl   0x0(%rax,%rax,1)
L62:
  movsbl (%r12,%r13,1),%edi
  test   %ebp,%ebp
  jne    L139
  cmp    $0x2e,%dil
  je     L101
L139:
  cmp    $0xa,%dil
  jne    L8
  cmp    0xc(%rsp),%eax
  je     L34
L8:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L93
L34:
  add    $0x1,%r13
  cmp    %rbx,%r13
  je     L108
L69:
  mov    %r13d,%eax
  test   %r13,%r13
  jne    L62
  cmpb   $0x24,(%r12)
  jne    L62
  add    $0x1,%r13
  cmp    %rbx,%r13
  jne    L69
L108:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x12,%edi
  call   <exit@plt>
  jmp    L34
  nopl   0x0(%rax)
L101:
  mov    $0x1,%ebp
  jmp    L34
  nop
L27:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%edi
  call   <exit@plt>
  jmp    L143
```

tool_calls: name: parse_data
arguments: label: D28
data_type: string
name: parse_data
arguments: label: D27
data_type: string
name: parse_data
arguments: label: D16
data_type: string

tool: D28: Amount: 

tool: D27: You have entered an invalid amount.


tool: D16: Please use the format $123.45


assistant: ```c
char *getAmt(void) {
  printf("Amount: ");
  char *amnt = getInput();
  if (amnt == NULL) {
    printf("You have entered an invalid amount.\n");
    exit(16);
  }
  unsigned int len = strlen(amnt);
  unsigned int dot = 0;
  for (unsigned int i = 0; i < len; i++) {
    if (i == 0 && amnt[i] == '$') {
      continue;
    }
    if (amnt[i] == '.' && dot < 1) {
      dot++;
      continue;
    }
    if (i == len - 1 && amnt[i] == '\n') {
      continue;
    }
    if (!isdigit(amnt[i])) {
      printf("You have entered an invalid amount.\n");
      printf("Please use the format $123.45\n");
      free(amnt);
      exit(18);
    }
  }
  return amnt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getAmt>:
  endbr64
  push   %r15
  lea    D37(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  call   <getInput@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
L132:
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L137
  lea    -0x1(%rax),%ecx
  mov    %eax,%ebx
  xor    %r13d,%r13d
  xor    %ebp,%ebp
  mov    %ecx,0xc(%rsp)
  lea    D32(%rip),%r15
  lea    D20(%rip),%r14
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L113:
  movsbl (%r12,%r13,1),%edi
  test   %ebp,%ebp
  jne    L110
  cmp    $0x2e,%dil
  je     L27
L110:
  cmp    $0xa,%dil
  jne    L59
  cmp    %eax,0xc(%rsp)
  je     L44
L59:
  call   <isdigit@plt>
  test   %eax,%eax
  je     L42
L44:
  add    $0x1,%r13
  cmp    %r13,%rbx
  je     L137
L19:
  mov    %r13d,%eax
  test   %r13,%r13
  jne    L113
  cmpb   $0x24,(%r12)
  jne    L113
  add    $0x1,%r13
  cmp    %r13,%rbx
  jne    L19
L137:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x12,%edi
  call   <exit@plt>
  jmp    L44
  nopl   0x0(%rax)
L27:
  mov    $0x1,%ebp
  jmp    L44
  nop
L7:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x10,%edi
  call   <exit@plt>
  jmp    L132
```

tool_calls: name: read_data
arguments: label: D37
type_guessed: string
name: read_data
arguments: label: D32
type_guessed: string
name: read_data
arguments: label: D20
type_guessed: string

tool: D37: Amount: 

tool: D32: You have entered an invalid amount.


tool: D20: Please use the format $123.45


assistant: ```c
char *getAmt(void) {
  printf("Amount: ");
  char *amnt = getInput();
  if (amnt == NULL) {
    printf("You have entered an invalid amount.\n");
    exit(16);
  }
  unsigned int len = strlen(amnt);
  unsigned int dot = 0;
  for (unsigned int i = 0; i < len; i++) {
    if (i == 0 && amnt[i] == '$') {
      continue;
    }
    if (amnt[i] == '.' && dot < 1) {
      dot++;
      continue;
    }
    if (i == len - 1 && amnt[i] == '\n') {
      continue;
    }
    if (!isdigit(amnt[i])) {
      printf("You have entered an invalid amount.\n");
      printf("Please use the format $123.45\n");
      free(amnt);
      exit(18);
    }
  }
  return amnt;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x1,-0x64(%rbp)
  je     L21
  cmpl   $0x2,-0x64(%rbp)
  jg     L21
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x51,%eax
  je     L38
L21:
  mov    -0x70(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L26
L38:
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <kubedoku@plt>
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D24
type_guessed: string
name: retrieve_data
arguments: label: D20
type_guessed: string

tool: D24: Usage: %s "123456789..."


tool: D20: %s


assistant: ```c
int main(int argc, char *argv[]) {
  if ((argc == 1) || (argc > 2) || (strlen(argv[1]) != 81)) {
    printf("Usage: %s \"123456789...\"\n", argv[0]);
    return 1;
  } else {
    char sudoku[82];
    strcpy(sudoku, argv[1]);
    printf("%s\n", sudoku);
    kubedoku(sudoku);
    printf("%s\n", sudoku);
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L32
  cmp    $0x2,%edi
  jg     L32
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  cmp    $0x51,%eax
  je     L41
L32:
  mov    (%rbx),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L25:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L41:
  mov    0x8(%rbx),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rsi
  lea    D9(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <kubedoku@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L25
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D9
type: string

tool: D5: Usage: %s "123456789..."


tool: D9: %s


assistant: ```c
int main(int argc, char *argv[]) {
  if ((argc == 1) || (argc > 2) || (strlen(argv[1]) != 81)) {
    printf("Usage: %s \"123456789...\"\n", argv[0]);
    return 1;
  } else {
    char sudoku[82];
    strcpy(sudoku, argv[1]);
    printf("%s\n", sudoku);
    kubedoku(sudoku);
    printf("%s\n", sudoku);
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L20
  cmp    $0x2,%edi
  jg     L20
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  cmp    $0x51,%eax
  je     L39
L20:
  mov    (%rbx),%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L46:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    %rsp,%rbp
  mov    0x8(%rbx),%rsi
  lea    D14(%rip),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <kubedoku@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L46
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D14
type_guessed: string

tool: D3: Usage: %s "123456789..."


tool: D14: %s


assistant: ```c
int main(int argc, char *argv[]) {
  if ((argc == 1) || (argc > 2) || (strlen(argv[1]) != 81)) {
    printf("Usage: %s \"123456789...\"\n", argv[0]);
    return 1;
  } else {
    char sudoku[82];
    strcpy(sudoku, argv[1]);
    printf("%s\n", sudoku);
    kubedoku(sudoku);
    printf("%s\n", sudoku);
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  cmp    $0x1,%edi
  je     L13
  cmp    $0x2,%edi
  jg     L13
  mov    0x8(%rsi),%rdi
  call   <strlen@plt>
  cmp    $0x51,%eax
  je     L44
L13:
  mov    (%rbx),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L8:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L44:
  mov    %rsp,%rbp
  mov    0x8(%rbx),%rsi
  lea    D2(%rip),%r12
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <kubedoku@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L8
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
datatype: string
name: parse_data
arguments: tag: D2
datatype: string

tool: D14: Usage: %s "123456789..."


tool: D2: %s


assistant: ```c
int main(int argc, char *argv[]) {
  if ((argc == 1) || (argc > 2) || (strlen(argv[1]) != 81)) {
    printf("Usage: %s \"123456789...\"\n", argv[0]);
    return 1;
  } else {
    char sudoku[82];
    strcpy(sudoku, argv[1]);
    printf("%s\n", sudoku);
    kubedoku(sudoku);
    printf("%s\n", sudoku);
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D17(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L10
L4:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rbp),%xmm0
  movsd  D31(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D20(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  movapd %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x4(%rbp),%xmm0
  movss  D8(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
L10:
  movss  -0x4(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jae    L4
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D31
data_type: f64
name: extract_symbolic_data
arguments: data_tag: D20
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D29
data_type: string
name: extract_symbolic_data
arguments: data_tag: D8
data_type: byte[4]

tool: {"D17": [0x00,0x00,0x96,0x43]}

tool: D31: 32

tool: {"D20": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: D29: %3.0f %6.1f


tool: {"D8": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(void) {
  float fahr;
  for (fahr = 300; fahr >= 0; fahr -= 20)
    printf("%3.0f %6.1f\n", fahr, (5.0 / 9.0) * (fahr - 32.0));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x10,%ebx
  movss  D29(%rip),%xmm3
  movss  %xmm3,0xc(%rsp)
  lea    D2(%rip),%rbp
L4:
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm1
  subsd  D48(%rip),%xmm1
  mulsd  D38(%rip),%xmm1
  movaps %xmm2,%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  subss  D41(%rip),%xmm2
  movss  %xmm2,0xc(%rsp)
  sub    $0x1,%ebx
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: byte[4]
name: read_data
arguments: label: D2
type_guessed: string
name: read_data
arguments: label: D48
type_guessed: f64
name: read_data
arguments: label: D38
type_guessed: byte[8]
name: read_data
arguments: label: D41
type_guessed: byte[4]

tool: {"D29": [0x00,0x00,0x96,0x43]}

tool: D2: %3.0f %6.1f


tool: D48: 32

tool: {"D38": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D41": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(void) {
  float fahr;
  for (fahr = 300; fahr >= 0; fahr -= 20)
    printf("%3.0f %6.1f\n", fahr, (5.0 / 9.0) * (fahr - 32.0));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  movss  D8(%rip),%xmm0
  xchg   %ax,%ax
L0:
  pxor   %xmm1,%xmm1
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm1
  subsd  D37(%rip),%xmm1
  mulsd  D17(%rip),%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  subss  D5(%rip),%xmm0
  sub    $0x1,%ebx
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D37
type_infered: f64
name: retrieve_data
arguments: data_label: D17
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D5
type_infered: byte[4]

tool: D16: %3.0f %6.1f


tool: {"D8": [0x00,0x00,0x96,0x43]}

tool: D37: 32

tool: {"D17": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D5": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(void) {
  float fahr;
  for (fahr = 300; fahr >= 0; fahr -= 20)
    printf("%3.0f %6.1f\n", fahr, (5.0 / 9.0) * (fahr - 32.0));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    $0x10,%ebx
  sub    $0x18,%rsp
  movss  D38(%rip),%xmm0
  xchg   %ax,%ax
L9:
  pxor   %xmm1,%xmm1
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  cvtss2sd %xmm0,%xmm1
  subsd  D32(%rip),%xmm1
  mulsd  D10(%rip),%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm0
  subss  D41(%rip),%xmm0
  sub    $0x1,%ebx
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D38
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D32
type_infered: f64
name: retrieve_data
arguments: data_label: D10
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D41
type_infered: byte[4]

tool: D12: %3.0f %6.1f


tool: {"D38": [0x00,0x00,0x96,0x43]}

tool: D32: 32

tool: {"D10": [0x72,0x1c,0xc7,0x71,0x1c,0xc7,0xe1,0x3f]}

tool: {"D41": [0x00,0x00,0xa0,0x41]}

assistant: ```c
int main(void) {
  float fahr;
  for (fahr = 300; fahr >= 0; fahr -= 20)
    printf("%3.0f %6.1f\n", fahr, (5.0 / 9.0) * (fahr - 32.0));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x290,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x280(%rbp)
  movl   $0x0,-0x200(%rbp)
  movl   $0x0,-0x180(%rbp)
  movl   $0x0,-0x100(%rbp)
  movl   $0x0,-0x80(%rbp)
  movl   $0x0,-0x28c(%rbp)
  movl   $0x0,-0x288(%rbp)
  movl   $0x0,-0x284(%rbp)
  lea    -0x28c(%rbp),%rdx
  lea    -0x200(%rbp),%rcx
  lea    -0x280(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <acceptData@plt>
  lea    -0x288(%rbp),%r9
  lea    -0x100(%rbp),%r8
  lea    -0x180(%rbp),%rcx
  lea    -0x28c(%rbp),%rdx
  lea    -0x200(%rbp),%rsi
  lea    -0x280(%rbp),%rax
  sub    $0x8,%rsp
  lea    -0x284(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <seperateLunch@plt>
  add    $0x10,%rsp
  lea    -0x288(%rbp),%rdx
  lea    -0x180(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sortArray@plt>
  lea    -0x284(%rbp),%rdx
  lea    -0x100(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sortArray@plt>
  lea    -0x284(%rbp),%rcx
  lea    -0x288(%rbp),%rdx
  lea    -0x100(%rbp),%rsi
  lea    -0x180(%rbp),%rax
  mov    %rax,%rdi
  call   <printFinalList@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int main() {
  int studID[30];
  studID[0] = 0;
  int prefer[30];
  prefer[0] = 0;
  int schoolLunch[30];
  schoolLunch[0] = 0;
  int homeLunch[30];
  homeLunch[0] = 0;
  int orderOfLine[30];
  orderOfLine[0] = 0;
  int actualSize = 0;
  int slSize = 0;
  int hlSize = 0;
  acceptData(studID, prefer, &actualSize);
  seperateLunch(studID, prefer, &actualSize, schoolLunch, homeLunch, &slSize, &hlSize);
  sortArray(schoolLunch, &slSize);
  sortArray(homeLunch, &hlSize);
  printFinalList(schoolLunch, homeLunch, &slSize, &hlSize);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x20(%rsp)
  movl   $0x0,0xa0(%rsp)
  movl   $0x0,0x120(%rsp)
  movl   $0x0,0x1a0(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  lea    0x14(%rsp),%r15
  lea    0xa0(%rsp),%r14
  lea    0x20(%rsp),%rax
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    %rax,0x8(%rsp)
  mov    %rax,%rdi
  call   <acceptData@plt>
  lea    0x18(%rsp),%r12
  lea    0x1a0(%rsp),%rbp
  lea    0x120(%rsp),%rbx
  sub    $0x8,%rsp
  lea    0x24(%rsp),%r13
  push   %r13
  mov    %r12,%r9
  mov    %rbp,%r8
  mov    %rbx,%rcx
  mov    %r15,%rdx
  mov    %r14,%rsi
  mov    0x18(%rsp),%rdi
  call   <seperateLunch@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <sortArray@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sortArray@plt>
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printFinalList@plt>
  add    $0x10,%rsp
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int studID[30];
  studID[0] = 0;
  int prefer[30];
  prefer[0] = 0;
  int schoolLunch[30];
  schoolLunch[0] = 0;
  int homeLunch[30];
  homeLunch[0] = 0;
  int orderOfLine[30];
  orderOfLine[0] = 0;
  int actualSize = 0;
  int slSize = 0;
  int hlSize = 0;
  acceptData(studID, prefer, &actualSize);
  seperateLunch(studID, prefer, &actualSize, schoolLunch, homeLunch, &slSize, &hlSize);
  sortArray(schoolLunch, &slSize);
  sortArray(homeLunch, &hlSize);
  printFinalList(schoolLunch, homeLunch, &slSize, &hlSize);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xa0(%rsp),%rbx
  lea    0x20(%rsp),%r15
  movl   $0x0,0x20(%rsp)
  lea    0x14(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  movl   $0x0,0xa0(%rsp)
  movl   $0x0,0x120(%rsp)
  lea    0x18(%rsp),%r13
  lea    0x1a0(%rsp),%r12
  movl   $0x0,0x14(%rsp)
  lea    0x120(%rsp),%rbp
  movl   $0x0,0x1a0(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  mov    %rdx,0x8(%rsp)
  call   <acceptData@plt>
  sub    $0x8,%rsp
  mov    %r13,%r9
  mov    %r12,%r8
  lea    0x24(%rsp),%r14
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  push   %r14
  mov    0x18(%rsp),%rdx
  call   <seperateLunch@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sortArray@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sortArray@plt>
  mov    %r13,%rdx
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printFinalList@plt>
  pop    %rax
  pop    %rdx
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int studID[30];
  studID[0] = 0;
  int prefer[30];
  prefer[0] = 0;
  int schoolLunch[30];
  schoolLunch[0] = 0;
  int homeLunch[30];
  homeLunch[0] = 0;
  int orderOfLine[30];
  orderOfLine[0] = 0;
  int actualSize = 0;
  int slSize = 0;
  int hlSize = 0;
  acceptData(studID, prefer, &actualSize);
  seperateLunch(studID, prefer, &actualSize, schoolLunch, homeLunch, &slSize, &hlSize);
  sortArray(schoolLunch, &slSize);
  sortArray(homeLunch, &hlSize);
  printFinalList(schoolLunch, homeLunch, &slSize, &hlSize);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xa0(%rsp),%rbx
  lea    0x20(%rsp),%r15
  movl   $0x0,0x20(%rsp)
  lea    0x14(%rsp),%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  movl   $0x0,0xa0(%rsp)
  movl   $0x0,0x120(%rsp)
  lea    0x18(%rsp),%r13
  lea    0x1a0(%rsp),%r12
  movl   $0x0,0x14(%rsp)
  lea    0x120(%rsp),%rbp
  movl   $0x0,0x1a0(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  mov    %rdx,0x8(%rsp)
  call   <acceptData@plt>
  sub    $0x8,%rsp
  mov    %r13,%r9
  mov    %r12,%r8
  lea    0x24(%rsp),%r14
  mov    %rbp,%rcx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  push   %r14
  mov    0x18(%rsp),%rdx
  call   <seperateLunch@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sortArray@plt>
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <sortArray@plt>
  mov    %r13,%rdx
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printFinalList@plt>
  pop    %rax
  pop    %rdx
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x228,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int studID[30];
  studID[0] = 0;
  int prefer[30];
  prefer[0] = 0;
  int schoolLunch[30];
  schoolLunch[0] = 0;
  int homeLunch[30];
  homeLunch[0] = 0;
  int orderOfLine[30];
  orderOfLine[0] = 0;
  int actualSize = 0;
  int slSize = 0;
  int hlSize = 0;
  acceptData(studID, prefer, &actualSize);
  seperateLunch(studID, prefer, &actualSize, schoolLunch, homeLunch, &slSize, &hlSize);
  sortArray(schoolLunch, &slSize);
  sortArray(homeLunch, &hlSize);
  printFinalList(schoolLunch, homeLunch, &slSize, &hlSize);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_sp_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  mov    $0x0,%eax
  jmp    L17
L16:
  mov    $0x1,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int check_sp_value(void *arg) {
  if (arg != 0)
    return 0;
  return 1;
}
```