ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Insertion_Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L13
L4:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L26
L1:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x0,-0x8(%rbp)
  jle    L41
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L1
L41:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Insertion_Sort(int array[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; i++) {
    tmp = array[i];
    for (j = i; j > 0 && array[j - 1] > tmp; j--)
      array[j] = array[j - 1];
    array[j] = tmp;
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<Insertion_Sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L52
  lea    0x4(%rdi),%r10
  mov    $0x1,%r9d
  jmp    L6
L18:
  movslq %edx,%rdx
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%r9d
  add    $0x4,%r10
  cmp    %r9d,%esi
  je     L52
L6:
  mov    (%r10),%r8d
  mov    %r10,%rax
  mov    %r9d,%edx
  test   %r9d,%r9d
  jle    L18
L61:
  mov    -0x4(%rax),%ecx
  cmp    %r8d,%ecx
  jle    L18
  mov    %ecx,(%rax)
  sub    $0x4,%rax
  sub    $0x1,%edx
  jne    L61
  jmp    L18
L52:
  ret
```

assistant: ```c
void Insertion_Sort(int array[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; i++) {
    tmp = array[i];
    for (j = i; j > 0 && array[j - 1] > tmp; j--)
      array[j] = array[j - 1];
    array[j] = tmp;
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<Insertion_Sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L5
  nopl   0x0(%rax,%rax,1)
L8:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L13:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L0
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rax,%rdi
  jne    L13
  mov    %rdi,%rcx
L0:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L8
L5:
  ret
```

assistant: ```c
void Insertion_Sort(int array[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; i++) {
    tmp = array[i];
    for (j = i; j > 0 && array[j - 1] > tmp; j--)
      array[j] = array[j - 1];
    array[j] = tmp;
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Insertion_Sort>:
  endbr64
  lea    0x4(%rdi),%r9
  mov    $0x1,%r10d
  cmp    $0x1,%esi
  jle    L22
  nopl   0x0(%rax,%rax,1)
L25:
  mov    (%r9),%r8d
  mov    %r9,%rax
  xchg   %ax,%ax
L7:
  mov    -0x4(%rax),%edx
  mov    %rax,%rcx
  cmp    %r8d,%edx
  jle    L8
  mov    %edx,(%rax)
  lea    -0x4(%rcx),%rax
  cmp    %rdi,%rax
  jne    L7
  mov    %rdi,%rcx
L8:
  add    $0x1,%r10d
  mov    %r8d,(%rcx)
  add    $0x4,%r9
  cmp    %r10d,%esi
  jne    L25
L22:
  ret
```

assistant: ```c
void Insertion_Sort(int array[], int n) {
  int i, j, tmp;
  for (i = 1; i < n; i++) {
    tmp = array[i];
    for (j = i; j > 0 && array[j - 1] > tmp; j--)
      array[j] = array[j - 1];
    array[j] = tmp;
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x4(%rbp)
  mov    %al,-0x8(%rbp)
  cmpb   $0x0,-0x4(%rbp)
  je     L5
  cmpb   $0x0,-0x8(%rbp)
  je     L5
  mov    $0x0,%eax
  call   <doo@plt>
  jmp    L12
L5:
  mov    $0x0,%eax
L12:
  leave
  ret
```

assistant: ```c
int foo(_Bool a, _Bool b) {
  if (a && b)
    return doo();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  test   %dil,%dil
  je     L7
  test   %sil,%sil
  jne    L9
L7:
  mov    $0x0,%eax
  ret
L9:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <doo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int foo(_Bool a, _Bool b) {
  if (a && b)
    return doo();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  test   %dil,%dil
  je     L0
  test   %sil,%sil
  jne    L4
L0:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  jmp    1050 <doo@plt>
```

assistant: ```c
int foo(_Bool a, _Bool b) {
  if (a && b)
    return doo();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  test   %dil,%dil
  je     L1
  test   %sil,%sil
  jne    L5
L1:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  jmp    1050 <doo@plt>
```

assistant: ```c
int foo(_Bool a, _Bool b) {
  if (a && b)
    return doo();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<median3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L0:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L17
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L23
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L23:
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int median3(int A[], int Left, int Right) {
  int Center = (Left + Right) / 2;
  if (A[Left] > A[Center])
    swap(&A[Left], &A[Center]);
  if (A[Left] > A[Right])
    swap(&A[Left], &A[Right]);
  if (A[Center] > A[Right])
    swap(&A[Center], &A[Right]);
  swap(&A[Center], &A[Right - 1]);
  return A[Right - 1];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<median3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%ebx
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r12
  add    %edx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r13
  mov    0x0(%r13),%eax
  cmp    %eax,(%r12)
  jg     L8
L11:
  movslq %ebx,%rbx
  shl    $0x2,%rbx
  lea    0x0(%rbp,%rbx,1),%r14
  mov    (%r14),%eax
  cmp    %eax,(%r12)
  jg     L54
L48:
  mov    (%r14),%eax
  cmp    %eax,0x0(%r13)
  jg     L32
L19:
  lea    -0x4(%rbp,%rbx,1),%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    (%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  jmp    L11
L54:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  jmp    L48
L32:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  jmp    L19
```

assistant: ```c
int median3(int A[], int Left, int Right) {
  int Center = (Left + Right) / 2;
  if (A[Left] > A[Center])
    swap(&A[Left], &A[Center]);
  if (A[Left] > A[Right])
    swap(&A[Left], &A[Right]);
  if (A[Center] > A[Right])
    swap(&A[Center], &A[Right]);
  swap(&A[Center], &A[Right - 1]);
  return A[Right - 1];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<median3>:
  endbr64
  push   %r14
  movslq %esi,%rax
  push   %r13
  lea    (%rdi,%rax,4),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  mov    0x0(%r13),%edx
  add    %ebx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r12
  cmp    (%r12),%edx
  jg     L32
  shl    $0x2,%rbx
  lea    0x0(%rbp,%rbx,1),%r14
  mov    (%r14),%eax
  cmp    %edx,%eax
  jl     L25
L46:
  cmp    %eax,(%r12)
  jg     L49
L36:
  lea    -0x4(%rbp,%rbx,1),%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    (%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L32:
  shl    $0x2,%rbx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  lea    0x0(%rbp,%rbx,1),%r14
  mov    0x0(%r13),%edx
  mov    (%r14),%eax
  cmp    %edx,%eax
  jge    L46
L25:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    (%r14),%eax
  cmp    %eax,(%r12)
  jle    L36
L49:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  jmp    L36
```

assistant: ```c
int median3(int A[], int Left, int Right) {
  int Center = (Left + Right) / 2;
  if (A[Left] > A[Center])
    swap(&A[Left], &A[Center]);
  if (A[Left] > A[Right])
    swap(&A[Left], &A[Right]);
  if (A[Center] > A[Right])
    swap(&A[Center], &A[Right]);
  swap(&A[Center], &A[Right - 1]);
  return A[Right - 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<median3>:
  endbr64
  push   %r14
  movslq %esi,%rax
  push   %r13
  lea    (%rdi,%rax,4),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  mov    0x0(%r13),%edx
  add    %ebx,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  cltq
  lea    (%rdi,%rax,4),%r12
  cmp    (%r12),%edx
  jg     L46
  shl    $0x2,%rbx
  lea    0x0(%rbp,%rbx,1),%r14
  mov    (%r14),%eax
  cmp    %edx,%eax
  jl     L56
L59:
  cmp    %eax,(%r12)
  jg     L54
L26:
  lea    -0x4(%rbp,%rbx,1),%rbx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    (%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L46:
  shl    $0x2,%rbx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  lea    0x0(%rbp,%rbx,1),%r14
  mov    0x0(%r13),%edx
  mov    (%r14),%eax
  cmp    %edx,%eax
  jge    L59
L56:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    (%r14),%eax
  cmp    %eax,(%r12)
  jle    L26
L54:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  jmp    L26
```

assistant: ```c
int median3(int A[], int Left, int Right) {
  int Center = (Left + Right) / 2;
  if (A[Left] > A[Center])
    swap(&A[Left], &A[Center]);
  if (A[Left] > A[Right])
    swap(&A[Left], &A[Right]);
  if (A[Center] > A[Right])
    swap(&A[Center], &A[Right]);
  swap(&A[Center], &A[Right - 1]);
  return A[Right - 1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6572656874206948,%rax
  mov    %rax,-0x12(%rbp)
  movw   $0x21,-0xa(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string

tool: D1: Hello, world!

tool: D25: world!

tool: D19: Hello, %s!


tool: D33: %d divided by %d is %d with remainder %d.


assistant: ```c
int main() {
  char msg[10] = "Hi there!";
  printf("Hello, world!\n");
  printf("Hello, %s!\n", "world!");
  printf("%s\n", msg);
  printf("%d divided by %d is %d with remainder %d.\n", 10, 3, 10 / 3, 10 % 3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6572656874206948,%rax
  mov    %rax,0xe(%rsp)
  movw   $0x21,0x16(%rsp)
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xe(%rsp),%rdi
  call   <puts@plt>
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D20
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D35
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D20: Hello, world!

tool: D3: world!

tool: D35: Hello, %s!


tool: D0: %d divided by %d is %d with remainder %d.


assistant: ```c
int main() {
  char msg[10] = "Hi there!";
  printf("Hello, world!\n");
  printf("Hello, %s!\n", "world!");
  printf("%s\n", msg);
  printf("%d divided by %d is %d with remainder %d.\n", 10, 3, 10 / 3, 10 % 3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6572656874206948,%rax
  mov    %rax,0xe(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x16(%rsp)
  call   <puts@plt>
  lea    D8(%rip),%rsi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xe(%rsp),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D33
type_guessed: string

tool: D2: Hello, world!

tool: D8: world!

tool: D25: Hello, %s!


tool: D33: %d divided by %d is %d with remainder %d.


assistant: ```c
int main() {
  char msg[10] = "Hi there!";
  printf("Hello, world!\n");
  printf("Hello, %s!\n", "world!");
  printf("%s\n", msg);
  printf("%d divided by %d is %d with remainder %d.\n", 10, 3, 10 / 3, 10 % 3);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6572656874206948,%rax
  mov    %rax,0xe(%rsp)
  mov    $0x21,%eax
  mov    %ax,0x16(%rsp)
  call   <puts@plt>
  lea    D32(%rip),%rsi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xe(%rsp),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    $0x1,%r8d
  mov    $0x3,%ecx
  mov    $0x3,%edx
  mov    $0xa,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
type_infered: string
name: read_data
arguments: label: D32
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D6
type_infered: string

tool: D7: Hello, world!

tool: D32: world!

tool: D14: Hello, %s!


tool: D6: %d divided by %d is %d with remainder %d.


assistant: ```c
int main() {
  char msg[10] = "Hi there!";
  printf("Hello, world!\n");
  printf("Hello, %s!\n", "world!");
  printf("%s\n", msg);
  printf("%d divided by %d is %d with remainder %d.\n", 10, 3, 10 / 3, 10 % 3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x17,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  lea    -0x9(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <read@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x59,%al
  je     L23
  movzbl -0x9(%rbp),%eax
  cmp    $0x79,%al
  jne    L6
L23:
  mov    $0x6,%edx
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x61a8,%edi
  call   <usleep@plt>
  jmp    L23
L6:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D19
type: string

tool: D3: Gob's Program:  Y/N?
? 

tool: D19: PENUS 

assistant: ```c
int main() {
  char buffer[1];
  write(1, "Gob's Program:  Y/N?\n? ", 23);
  read(0, buffer, 1);
  if (buffer[0] != 'Y' && buffer[0] != 'y') {
    goto end;
  }
  while (1) {
    write(1, "PENUS ", 6);
    usleep(25000);
  }
end:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x17,%edx
  lea    D15(%rip),%rsi
  mov    $0x1,%edi
  call   <write@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    $0x0,%edi
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  and    $0xffffffdf,%eax
  lea    D4(%rip),%rbx
  cmp    $0x59,%al
  jne    L12
L15:
  mov    $0x6,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x61a8,%edi
  call   <usleep@plt>
  jmp    L15
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D4
data_type: string

tool: D15: Gob's Program:  Y/N?
? 

tool: D4: PENUS 

assistant: ```c
int main() {
  char buffer[1];
  write(1, "Gob's Program:  Y/N?\n? ", 23);
  read(0, buffer, 1);
  if (buffer[0] != 'Y' && buffer[0] != 'y') {
    goto end;
  }
  while (1) {
    write(1, "PENUS ", 6);
    usleep(25000);
  }
end:
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x17,%edx
  lea    D3(%rip),%rsi
  mov    $0x1,%edi
  lea    D5(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <write@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  xor    %edi,%edi
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x59,%al
  jne    L6
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0x6,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x61a8,%edi
  call   <usleep@plt>
  jmp    L17
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D3: Gob's Program:  Y/N?
? 

tool: D5: PENUS 

assistant: ```c
int main() {
  char buffer[1];
  write(1, "Gob's Program:  Y/N?\n? ", 23);
  read(0, buffer, 1);
  if (buffer[0] != 'Y' && buffer[0] != 'y') {
    goto end;
  }
  while (1) {
    write(1, "PENUS ", 6);
    usleep(25000);
  }
end:
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x17,%edx
  lea    D19(%rip),%rsi
  mov    $0x1,%edi
  lea    D7(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <write@plt>
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  xor    %edi,%edi
  call   <read@plt>
  movzbl 0x7(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x59,%al
  jne    L0
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x6,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x61a8,%edi
  call   <usleep@plt>
  jmp    L8
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D7
datatype: string

tool: D19: Gob's Program:  Y/N?
? 

tool: D7: PENUS 

assistant: ```c
int main() {
  char buffer[1];
  write(1, "Gob's Program:  Y/N?\n? ", 23);
  read(0, buffer, 1);
  if (buffer[0] != 'Y' && buffer[0] != 'y') {
    goto end;
  }
  while (1) {
    write(1, "PENUS ", 6);
    usleep(25000);
  }
end:
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<safe_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L34:
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jns    L6
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  je     L6
  mov    -0xc(%rbp),%eax
  jmp    L3
L6:
  mov    -0x10(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jg     L34
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int safe_write(int fd, const void *buf, signed int len) {
  const char *b = (const char *)buf;
  while (1) {
    int res = write(fd, b, len);
    if (res < 0) {
      int err = errno;
      if (err != EINTR) {
        return err;
      }
    }
    len -= res;
    b += res;
    if (len <= 0)
      return 0;
  }
}
```