ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main(void) {
  int *p;
  {
    int x;
    p = &x;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int *p;
  {
    int x;
    p = &x;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int *p;
  {
    int x;
    p = &x;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int *p;
  {
    int x;
    p = &x;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: uid = %d gid = %d


assistant: ```c
int main(void) {
  printf("uid = %d gid = %d\n", getuid(), getgid());
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string

tool: D5: uid = %d gid = %d


assistant: ```c
int main(void) {
  printf("uid = %d gid = %d\n", getuid(), getgid());
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12d,%edx
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: uid = %d gid = %d


assistant: ```c
int main(void) {
  printf("uid = %d gid = %d\n", getuid(), getgid());
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getgid@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <getuid@plt>
  mov    %r12d,%edx
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: uid = %d gid = %d


assistant: ```c
int main(void) {
  printf("uid = %d gid = %d\n", getuid(), getgid());
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_get_uint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%eax
  test   %rax,%rax
  js     L4
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  jmp    L14
L4:
  mov    %rax,%rdx
  shr    %rdx
  and    $0x1,%eax
  or     %rax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rdx,%xmm0
  addsd  %xmm0,%xmm0
L14:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double _get_uint(const char *data, size_t pos) {
  unsigned int *buf = (unsigned int *)data;
  return ((double)buf[pos]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_get_uint>:
  endbr64
  mov    (%rdi,%rsi,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  ret
```

assistant: ```c
double _get_uint(const char *data, size_t pos) {
  unsigned int *buf = (unsigned int *)data;
  return ((double)buf[pos]);
}
```
user: What is the c source code of the assembly code below:

```asm
<_get_uint>:
  endbr64
  mov    (%rdi,%rsi,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  ret
```

assistant: ```c
double _get_uint(const char *data, size_t pos) {
  unsigned int *buf = (unsigned int *)data;
  return ((double)buf[pos]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_get_uint>:
  endbr64
  mov    (%rdi,%rsi,4),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  ret
```

assistant: ```c
double _get_uint(const char *data, size_t pos) {
  unsigned int *buf = (unsigned int *)data;
  return ((double)buf[pos]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<isgreater>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  comiss -0x18(%rbp),%xmm0
  seta   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L0
L13:
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int isgreater(float f1, float f2) {
  int r = (f1 > f2);
  return !r ? -1 : 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isgreater>:
  endbr64
  comiss %xmm1,%xmm0
  seta   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int isgreater(float f1, float f2) {
  int r = (f1 > f2);
  return !r ? -1 : 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<isgreater>:
  endbr64
  xor    %eax,%eax
  comiss %xmm1,%xmm0
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int isgreater(float f1, float f2) {
  int r = (f1 > f2);
  return !r ? -1 : 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isgreater>:
  endbr64
  xor    %eax,%eax
  comiss %xmm1,%xmm0
  seta   %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int isgreater(float f1, float f2) {
  int r = (f1 > f2);
  return !r ? -1 : 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getIP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L69:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L43
  addl   $0x1,-0x4(%rbp)
L43:
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    $0x7,%eax
  jbe    L69
  cmpl   $0x3,-0x4(%rbp)
  jne    L42
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L30:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  je     L32
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  add    %edx,%ecx
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D14(%rip),%rax
  mov    %ecx,(%rdx,%rax,1)
  jmp    L21
L32:
  subl   $0x1,-0x4(%rbp)
L21:
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  cmp    $0x7,%eax
  jbe    L30
L42:
  lea    D14(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *getIP(char *strIP) {
  int i, j;
  int commaCount = 0;
  static int pBytes[] = {0, 0, 0, 0};
  for (i = 0; i < sizeof(strIP); i++)
    if (strIP[i] == ',') {
      commaCount++;
    }
  if (commaCount == 3)
    for (j = 0; j < sizeof(strIP); j++) {
      if (strIP[j] != ',')
        pBytes[3 - commaCount] = pBytes[3 - commaCount] * 10 + (strIP[j] - '0');
      else
        commaCount--;
    }
  return pBytes;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getIP>:
  endbr64
  lea    0x8(%rdi),%rsi
  mov    %rdi,%rax
  mov    $0x0,%edx
L38:
  cmpb   $0x2c,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L38
  cmp    $0x3,%edx
  je     L39
L58:
  lea    D6(%rip),%rax
  ret
L39:
  mov    $0x3,%r10d
  lea    D6(%rip),%r9
  jmp    L14
L30:
  sub    $0x1,%edx
L40:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L58
L14:
  movzbl (%rdi),%eax
  cmp    $0x2c,%al
  je     L30
  mov    %r10d,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rcx
  mov    (%r9,%rcx,4),%r8d
  lea    (%r8,%r8,4),%r8d
  movsbl %al,%eax
  lea    -0x30(%rax,%r8,2),%eax
  mov    %eax,(%r9,%rcx,4)
  jmp    L40
```

assistant: ```c
int *getIP(char *strIP) {
  int i, j;
  int commaCount = 0;
  static int pBytes[] = {0, 0, 0, 0};
  for (i = 0; i < sizeof(strIP); i++)
    if (strIP[i] == ',') {
      commaCount++;
    }
  if (commaCount == 3)
    for (j = 0; j < sizeof(strIP); j++) {
      if (strIP[j] != ',')
        pBytes[3 - commaCount] = pBytes[3 - commaCount] * 10 + (strIP[j] - '0');
      else
        commaCount--;
    }
  return pBytes;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getIP>:
  endbr64
  lea    0x8(%rdi),%rsi
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   (%rax)
L7:
  xor    %ecx,%ecx
  cmpb   $0x2c,(%rax)
  sete   %cl
  add    $0x1,%rax
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L7
  lea    D8(%rip),%r8
  cmp    $0x3,%edx
  je     L57
L9:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L57:
  mov    $0x3,%r10d
  jmp    L55
L26:
  mov    %r10d,%ecx
  sub    %edx,%ecx
  movslq %ecx,%rcx
  mov    (%r8,%rcx,4),%r9d
  lea    (%r9,%r9,4),%r9d
  lea    -0x30(%rax,%r9,2),%eax
  mov    %eax,(%r8,%rcx,4)
L49:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  je     L9
L55:
  movsbl (%rdi),%eax
  cmp    $0x2c,%al
  jne    L26
  sub    $0x1,%edx
  jmp    L49
```

assistant: ```c
int *getIP(char *strIP) {
  int i, j;
  int commaCount = 0;
  static int pBytes[] = {0, 0, 0, 0};
  for (i = 0; i < sizeof(strIP); i++)
    if (strIP[i] == ',') {
      commaCount++;
    }
  if (commaCount == 3)
    for (j = 0; j < sizeof(strIP); j++) {
      if (strIP[j] != ',')
        pBytes[3 - commaCount] = pBytes[3 - commaCount] * 10 + (strIP[j] - '0');
      else
        commaCount--;
    }
  return pBytes;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<testXMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L55
L63:
  movl   $0x0,-0xc(%rbp)
  jmp    L52
L23:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L16
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  D5(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L18
L16:
  movl   $0xffffffff,-0x14(%rbp)
L18:
  mov    -0x10(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L52:
  cmpl   $0x3,-0xc(%rbp)
  jle    L23
  addl   $0x1,-0x10(%rbp)
L55:
  cmpl   $0x3,-0x10(%rbp)
  jle    L63
  movsd  -0x8(%rbp),%xmm0
  movsd  D5(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L10
  movl   $0xffffffff,-0x14(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int testXMat(double x[]) {
  int it = 0, i, j;
  double t;
  for (i = 0, t = 0; i < 4; i++)
    for (j = 0; j < 4; j++) {
      if (x[i * 4 + j] < 0 || x[i * 4 + j] > 1)
        it = -1;
      t += x[i * 4 + j];
    }
  if (fabs(t - 1) > 1e-4)
    it = -1;
  return (it);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testXMat>:
  endbr64
  push   %rbx
  add    $0x20,%rdi
  mov    $0x0,%edx
  pxor   %xmm0,%xmm0
  mov    $0x0,%ebx
  movapd %xmm0,%xmm2
  movsd  D18(%rip),%xmm3
  mov    $0xffffffff,%ecx
  jmp    L41
L33:
  mov    $0xffffffff,%ebx
L17:
  addsd  %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdi,%rax
  je     L37
L1:
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm2
  ja     L33
  ucomisd %xmm3,%xmm1
  cmova  %ecx,%ebx
  jmp    L17
L37:
  add    $0x20,%rdi
  add    $0x4,%edx
  cmp    $0x10,%edx
  je     L32
L41:
  lea    -0x20(%rdi),%rax
  jmp    L1
L32:
  subsd  D18(%rip),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovg  %eax,%ebx
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
type_guessed: byte[8]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int testXMat(double x[]) {
  int it = 0, i, j;
  double t;
  for (i = 0, t = 0; i < 4; i++)
    for (j = 0; j < 4; j++) {
      if (x[i * 4 + j] < 0 || x[i * 4 + j] > 1)
        it = -1;
      t += x[i * 4 + j];
    }
  if (fabs(t - 1) > 1e-4)
    it = -1;
  return (it);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<testXMat>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  D9(%rip),%xmm3
  push   %r12
  xor    %edx,%edx
  add    $0x20,%rdi
  movapd %xmm2,%xmm0
  xor    %r12d,%r12d
  mov    $0xffffffff,%ecx
L38:
  lea    -0x20(%rdi),%rax
L11:
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm2
  ja     L9
  ucomisd %xmm3,%xmm1
  cmova  %ecx,%r12d
L37:
  add    $0x8,%rax
  addsd  %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L11
  add    $0x4,%edx
  lea    0x20(%rax),%rdi
  cmp    $0x10,%edx
  jne    L38
  subsd  %xmm3,%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  mov    $0xffffffff,%eax
  cmovg  %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L9:
  mov    $0xffffffff,%r12d
  jmp    L37
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
int testXMat(double x[]) {
  int it = 0, i, j;
  double t;
  for (i = 0, t = 0; i < 4; i++)
    for (j = 0; j < 4; j++) {
      if (x[i * 4 + j] < 0 || x[i * 4 + j] > 1)
        it = -1;
      t += x[i * 4 + j];
    }
  if (fabs(t - 1) > 1e-4)
    it = -1;
  return (it);
}
```
user: What is the c source code of the assembly code below:

```asm
<count_cpus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L31
L29:
  movl   $0x0,-0x14(%rbp)
  nop
L28:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L28
  jmp    L40
L12:
  nop
L50:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L50
L40:
  lea    -0x14(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L12
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
L31:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D23
type: string
name: retrieve_data
arguments: label: D25
type: string

tool: D14: r

tool: D23: /proc/stat

tool: D25: cpu%d

assistant: ```c
int count_cpus() {
  FILE *stat = fopen("/proc/stat", "r");
  if (!stat)
    return -1;
  int cpu_count = 0;
  while (fgetc(stat) != '\n')
    ;
  while (fscanf(stat, "cpu%d", &cpu_count) == 1)
    while (fgetc(stat) != '\n')
      ;
  fclose(stat);
  return cpu_count + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<count_cpus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rsi
  lea    D3(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L62
  mov    %rax,%rbx
  movl   $0x0,0x4(%rsp)
L63:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L63
  lea    D13(%rip),%rbp
  jmp    L56
L48:
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L48
L56:
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L48
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
L65:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L68
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L62:
  mov    $0xffffffff,%eax
  jmp    L65
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D26
type_infered: string
name: parse_data
arguments: label: D3
type_infered: string
name: parse_data
arguments: label: D13
type_infered: string

tool: D26: r

tool: D3: /proc/stat

tool: D13: cpu%d

assistant: ```c
int count_cpus() {
  FILE *stat = fopen("/proc/stat", "r");
  if (!stat)
    return -1;
  int cpu_count = 0;
  while (fgetc(stat) != '\n')
    ;
  while (fscanf(stat, "cpu%d", &cpu_count) == 1)
    while (fgetc(stat) != '\n')
      ;
  fclose(stat);
  return cpu_count + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<count_cpus>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  lea    D19(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L21
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L32:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L32
  lea    0x4(%rsp),%r12
  lea    D26(%rip),%rbx
L60:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L8
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L61
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L28
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string

tool: D6: r

tool: D19: /proc/stat

tool: D26: cpu%d

assistant: ```c
int count_cpus() {
  FILE *stat = fopen("/proc/stat", "r");
  if (!stat)
    return -1;
  int cpu_count = 0;
  while (fgetc(stat) != '\n')
    ;
  while (fscanf(stat, "cpu%d", &cpu_count) == 1)
    while (fgetc(stat) != '\n')
      ;
  fclose(stat);
  return cpu_count + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count_cpus>:
  endbr64
  push   %r12
  lea    D7(%rip),%rsi
  lea    D18(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L32
  movl   $0x0,0x4(%rsp)
  mov    %rax,%rbp
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L12
  lea    0x4(%rsp),%r12
  lea    D10(%rip),%rbx
L69:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L59
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  call   <fgetc@plt>
  cmp    $0xa,%al
  jne    L17
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L59:
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x4(%rsp),%eax
  add    $0x1,%eax
L62:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  mov    $0xffffffff,%eax
  jmp    L62
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string

tool: D7: r

tool: D18: /proc/stat

tool: D10: cpu%d

assistant: ```c
int count_cpus() {
  FILE *stat = fopen("/proc/stat", "r");
  if (!stat)
    return -1;
  int cpu_count = 0;
  while (fgetc(stat) != '\n')
    ;
  while (fscanf(stat, "cpu%d", &cpu_count) == 1)
    while (fgetc(stat) != '\n')
      ;
  fclose(stat);
  return cpu_count + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_line_no>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L45
  mov    $0x0,%eax
  jmp    L21
L45:
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L0:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L47
  addl   $0x1,-0x4(%rbp)
L47:
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x4(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int get_line_no(const char *text) {
  int i;
  int total = 1;
  if (!text)
    return 0;
  for (i = 0; text[i] != '\0'; i++)
    if (text[i] == '\n')
      total++;
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_line_no>:
  endbr64
  test   %rdi,%rdi
  je     L40
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  add    $0x1,%rdi
  mov    $0x1,%edx
L44:
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L44
L48:
  mov    %edx,%eax
  ret
L40:
  mov    $0x0,%edx
  jmp    L48
L25:
  mov    $0x1,%edx
  jmp    L48
```

assistant: ```c
int get_line_no(const char *text) {
  int i;
  int total = 1;
  if (!text)
    return 0;
  for (i = 0; text[i] != '\0'; i++)
    if (text[i] == '\n')
      total++;
  return total;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_line_no>:
  endbr64
  test   %rdi,%rdi
  je     L6
  movzbl (%rdi),%eax
  test   %al,%al
  je     L22
  add    $0x1,%rdi
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L32:
  cmp    $0xa,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L32
L13:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    $0x1,%r8d
  jmp    L13
```

assistant: ```c
int get_line_no(const char *text) {
  int i;
  int total = 1;
  if (!text)
    return 0;
  for (i = 0; text[i] != '\0'; i++)
    if (text[i] == '\n')
      total++;
  return total;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_line_no>:
  endbr64
  test   %rdi,%rdi
  je     L5
  movzbl (%rdi),%eax
  test   %al,%al
  je     L7
  add    $0x1,%rdi
  mov    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L28:
  cmp    $0xa,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L28
L18:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%r8d
  jmp    L18
```

assistant: ```c
int get_line_no(const char *text) {
  int i;
  int total = 1;
  if (!text)
    return 0;
  for (i = 0; text[i] != '\0'; i++)
    if (text[i] == '\n')
      total++;
  return total;
}
```