ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x61000(%rsp),%r11
L74:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L74
  sub    $0xc30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x61c30(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x61c2c(%rbp)
  jmp    L126
L6:
  lea    -0x61c20(%rbp),%rdx
  mov    -0x61c2c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x2,-0x61c28(%rbp)
  jmp    L10
L128:
  mov    -0x61c28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x61c2c(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  movl   $0x1,-0x61a90(%rbp,%rax,4)
  addl   $0x1,-0x61c28(%rbp)
L10:
  mov    -0x61c2c(%rbp),%eax
  cltq
  mov    -0x61c20(%rbp,%rax,4),%eax
  cmp    %eax,-0x61c28(%rbp)
  jl     L128
  addl   $0x1,-0x61c2c(%rbp)
L126:
  mov    -0x61c30(%rbp),%eax
  cmp    %eax,-0x61c2c(%rbp)
  jl     L6
  movl   $0x0,-0x61c28(%rbp)
  jmp    L27
L57:
  movl   $0x2,-0x61c2c(%rbp)
  jmp    L38
L78:
  mov    -0x61c2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x61c28(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  mov    -0x61a90(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L50
  mov    -0x61c2c(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x2,-0x61c24(%rbp)
  jmp    L1
L125:
  mov    -0x61c2c(%rbp),%eax
  imul   -0x61c24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x61c28(%rbp),%eax
  cltq
  imul   $0x3e8,%rax,%rax
  add    %rdx,%rax
  movl   $0x0,-0x61a90(%rbp,%rax,4)
  addl   $0x1,-0x61c24(%rbp)
L1:
  mov    -0x61c2c(%rbp),%eax
  imul   -0x61c24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x61c28(%rbp),%eax
  cltq
  mov    -0x61c20(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jl     L125
L50:
  addl   $0x1,-0x61c2c(%rbp)
L38:
  mov    -0x61c28(%rbp),%eax
  cltq
  mov    -0x61c20(%rbp,%rax,4),%eax
  cmp    %eax,-0x61c2c(%rbp)
  jl     L78
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x61c28(%rbp)
L27:
  mov    -0x61c30(%rbp),%eax
  cmp    %eax,-0x61c28(%rbp)
  jl     L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string

tool: D16: %d

tool: D3: %d 

assistant: ```c
int main() {
  int t, i, n[100], j, k, a[100][1000], l;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n[i]);
    for (j = 2; j < n[i]; j++)
      a[i][j] = 1;
  }
  for (j = 0; j < t; j++) {
    for (i = 2; i < n[j]; i++) {
      if (a[j][i] != 0) {
        printf("%d ", i);
        l = 2;
        while (i * l < n[j]) {
          a[j][i * l] = 0;
          l++;
        }
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L25:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L25
  sub    $0xc48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x61c38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D18(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x1c(%rsp)
  jle    L5
  lea    0x20(%rsp),%r15
  lea    0x1b8(%rsp),%r13
  mov    %r15,%rbx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D18(%rip),%r14
L118:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  cmp    $0x2,%eax
  jle    L70
  lea    -0x3(%rax),%eax
  add    %r12,%rax
  lea    0x1bc(%rsp,%rax,4),%rdx
  mov    %r13,%rax
L131:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L131
L70:
  add    $0x1,%ebp
  mov    0x1c(%rsp),%eax
  add    $0x4,%rbx
  add    $0xfa0,%r13
  add    $0x3e8,%r12
  cmp    %ebp,%eax
  jg     L118
  test   %eax,%eax
  jle    L5
  lea    0x1b0(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  jmp    L39
L46:
  add    $0x1,%rbx
  add    $0x2,%rbp
  cmp    %ebx,(%r14)
  jle    L143
L71:
  mov    %ebx,%esi
  mov    %r12,%r13
  cmpl   $0x0,(%r12,%rbx,4)
  je     L46
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%r14),%edx
  cmp    %ebp,%edx
  jle    L46
  mov    %rbp,%rax
L90:
  movl   $0x0,0x0(%r13,%rax,4)
  add    %rbx,%rax
  cmp    %eax,%edx
  jg     L90
  jmp    L46
L143:
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  add    $0x4,%r15
  add    $0xfa0,%r12
  cmp    %eax,0x1c(%rsp)
  jle    L5
L39:
  mov    %r15,%r14
  mov    $0x4,%ebp
  mov    $0x2,%ebx
  cmpl   $0x2,(%r15)
  jg     L71
  jmp    L143
L5:
  mov    0x61c38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L97
  mov    $0x0,%eax
  add    $0x61c48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D18: %d

tool: D6: %d 

assistant: ```c
int main() {
  int t, i, n[100], j, k, a[100][1000], l;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n[i]);
    for (j = 2; j < n[i]; j++)
      a[i][j] = 1;
  }
  for (j = 0; j < t; j++) {
    for (i = 2; i < n[j]; i++) {
      if (a[j][i] != 0) {
        printf("%d ", i);
        l = 2;
        while (i * l < n[j]) {
          a[j][i * l] = 0;
          l++;
        }
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x61000(%rsp),%r11
L21:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L21
  sub    $0xc48,%rsp
  lea    D19(%rip),%rbp
  mov    %rbp,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x61c38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x1c(%rsp),%edx
  test   %edx,%edx
  jle    L7
  lea    0x1bc(%rsp),%rax
  lea    0x20(%rsp),%r15
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  mov    %rax,0x8(%rsp)
  lea    0x1b8(%rsp),%r12
  mov    %r15,%rbx
  nopl   0x0(%rax)
L19:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  cmp    $0x2,%eax
  jle    L87
  mov    0x8(%rsp),%rcx
  sub    $0x3,%eax
  add    %r14,%rax
  lea    (%rcx,%rax,4),%rdx
  mov    %r12,%rax
  nopl   0x0(%rax)
L20:
  movl   $0x1,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L20
L87:
  mov    0x1c(%rsp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  add    $0xfa0,%r12
  add    $0x3e8,%r14
  cmp    %r13d,%eax
  jg     L19
  test   %eax,%eax
  jle    L7
  lea    0x1b0(%rsp),%rbp
  xor    %r12d,%r12d
  lea    D13(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L72:
  cmpl   $0x2,(%r15)
  mov    $0x4,%r14d
  mov    $0x2,%ebx
  jg     L57
  jmp    L113
  nopl   0x0(%rax,%rax,1)
L29:
  mov    (%r15),%edx
L130:
  add    $0x1,%rbx
  add    $0x2,%r14
  cmp    %ebx,%edx
  jle    L113
L57:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%esi
  test   %eax,%eax
  je     L29
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%r15),%edx
  cmp    %r14d,%edx
  jle    L130
  mov    %r14,%rax
  cs nopw 0x0(%rax,%rax,1)
L9:
  movl   $0x0,0x0(%rbp,%rax,4)
  add    %rbx,%rax
  cmp    %eax,%edx
  jg     L9
  add    $0x1,%rbx
  add    $0x2,%r14
  cmp    %ebx,%edx
  jg     L57
  nopl   0x0(%rax,%rax,1)
L113:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    $0x4,%r15
  add    $0xfa0,%rbp
  call   <putchar@plt>
  cmp    %r12d,0x1c(%rsp)
  jg     L72
L7:
  mov    0x61c38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x61c48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D13
type: string

tool: D19: %d

tool: D13: %d 

assistant: ```c
int main() {
  int t, i, n[100], j, k, a[100][1000], l;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n[i]);
    for (j = 2; j < n[i]; j++)
      a[i][j] = 1;
  }
  for (j = 0; j < t; j++) {
    for (i = 2; i < n[j]; i++) {
      if (a[j][i] != 0) {
        printf("%d ", i);
        l = 2;
        while (i * l < n[j]) {
          a[j][i * l] = 0;
          l++;
        }
      }
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<emit_cmpgt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <emit_orimm@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    $0xffffffff,%esi
  mov    %eax,%edi
  call   <emit_addimm@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_cmp@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_cmovle_reg@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_cmpgt(int s1, int s2, int sr, int temp) {
  assert(temp >= 0);
  emit_orimm(sr, 1, sr);
  emit_addimm(sr, -1, temp);
  emit_cmp(s2, s1);
  emit_cmovle_reg(temp, sr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_cmpgt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %edx,%ebx
  mov    %ecx,%ebp
  mov    %ecx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <assert@plt>
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <emit_orimm@plt>
  mov    %ebp,%edx
  mov    $0xffffffff,%esi
  mov    %ebx,%edi
  call   <emit_addimm@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmp@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <emit_cmovle_reg@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void emit_cmpgt(int s1, int s2, int sr, int temp) {
  assert(temp >= 0);
  emit_orimm(sr, 1, sr);
  emit_addimm(sr, -1, temp);
  emit_cmp(s2, s1);
  emit_cmovle_reg(temp, sr);
}
```
user: What is the c source code of the assembly code below:

```asm
<emit_cmpgt>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    %ecx,%edi
  push   %r13
  not    %edi
  mov    %esi,%r13d
  push   %r12
  shr    $0x1f,%edi
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <emit_orimm@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  call   <emit_addimm@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <emit_cmp@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <emit_cmovle_reg@plt>
```

assistant: ```c
void emit_cmpgt(int s1, int s2, int sr, int temp) {
  assert(temp >= 0);
  emit_orimm(sr, 1, sr);
  emit_addimm(sr, -1, temp);
  emit_cmp(s2, s1);
  emit_cmovle_reg(temp, sr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_cmpgt>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  mov    %ecx,%edi
  push   %r13
  not    %edi
  mov    %esi,%r13d
  push   %r12
  shr    $0x1f,%edi
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  sub    $0x8,%rsp
  call   <assert@plt>
  mov    %ebp,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <emit_orimm@plt>
  mov    %r12d,%edx
  mov    %ebp,%edi
  mov    $0xffffffff,%esi
  call   <emit_addimm@plt>
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <emit_cmp@plt>
  add    $0x8,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <emit_cmovle_reg@plt>
```

assistant: ```c
void emit_cmpgt(int s1, int s2, int sr, int temp) {
  assert(temp >= 0);
  emit_orimm(sr, 1, sr);
  emit_addimm(sr, -1, temp);
  emit_cmp(s2, s1);
  emit_cmovle_reg(temp, sr);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L24
L23:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x10(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L29
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L29:
  addl   $0x1,-0x1c(%rbp)
L24:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L23
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int partition(int n, double *arr) {
  int pivot_idx = n / 2;
  double pivot = arr[pivot_idx];
  double tmp;
  int i, store_index;
  tmp = arr[n - 1];
  arr[n - 1] = pivot;
  arr[pivot_idx] = tmp;
  store_index = 0;
  for (i = 0; i < n - 1; i++) {
    if (arr[i] < pivot) {
      tmp = arr[store_index];
      arr[store_index] = arr[i];
      arr[i] = tmp;
      store_index++;
    }
  }
  tmp = arr[store_index];
  arr[store_index] = arr[n - 1];
  arr[n - 1] = tmp;
  return store_index;
}
```
user: What is the c source code of the assembly code below?

```asm
<partition>:
  endbr64
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  cltq
  lea    (%rsi,%rax,8),%rax
  movsd  (%rax),%xmm1
  movslq %edi,%rdx
  lea    -0x8(%rsi,%rdx,8),%r8
  movsd  (%r8),%xmm0
  movsd  %xmm1,(%r8)
  movsd  %xmm0,(%rax)
  cmp    $0x1,%edi
  jle    L33
  mov    %rsi,%rax
  lea    -0x2(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rdi
  mov    $0x0,%edx
  jmp    L23
L34:
  add    $0x8,%rax
  cmp    %rdi,%rax
  je     L36
L23:
  movsd  (%rax),%xmm0
  comisd %xmm0,%xmm1
  jbe    L34
  movslq %edx,%rcx
  lea    (%rsi,%rcx,8),%rcx
  movsd  (%rcx),%xmm2
  movsd  %xmm0,(%rcx)
  movsd  %xmm2,(%rax)
  add    $0x1,%edx
  jmp    L34
L33:
  mov    $0x0,%edx
L36:
  movslq %edx,%rax
  lea    (%rsi,%rax,8),%rax
  movsd  (%rax),%xmm0
  movsd  (%r8),%xmm1
  movsd  %xmm1,(%rax)
  movsd  %xmm0,(%r8)
  mov    %edx,%eax
  ret
```

assistant: ```c
int partition(int n, double *arr) {
  int pivot_idx = n / 2;
  double pivot = arr[pivot_idx];
  double tmp;
  int i, store_index;
  tmp = arr[n - 1];
  arr[n - 1] = pivot;
  arr[pivot_idx] = tmp;
  store_index = 0;
  for (i = 0; i < n - 1; i++) {
    if (arr[i] < pivot) {
      tmp = arr[store_index];
      arr[store_index] = arr[i];
      arr[i] = tmp;
      store_index++;
    }
  }
  tmp = arr[store_index];
  arr[store_index] = arr[n - 1];
  arr[n - 1] = tmp;
  return store_index;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<partition>:
  endbr64
  mov    %edi,%eax
  movslq %edi,%rcx
  mov    %rsi,%rdx
  shr    $0x1f,%eax
  lea    -0x8(%rsi,%rcx,8),%r9
  add    %edi,%eax
  movsd  (%r9),%xmm0
  sar    %eax
  cltq
  lea    (%rsi,%rax,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%r9)
  movsd  %xmm0,(%rax)
  cmp    $0x1,%edi
  jle    L26
  lea    -0x2(%rdi),%ecx
  mov    %rsi,%rax
  xor    %r8d,%r8d
  lea    0x8(%rsi,%rcx,8),%rsi
  nopl   0x0(%rax,%rax,1)
L23:
  movsd  (%rax),%xmm0
  comisd %xmm0,%xmm1
  jbe    L10
  movslq %r8d,%rcx
  add    $0x1,%r8d
  lea    (%rdx,%rcx,8),%rcx
  movsd  (%rcx),%xmm2
  movsd  %xmm0,(%rcx)
  movsd  %xmm2,(%rax)
L10:
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L23
  movslq %r8d,%rax
  lea    (%rdx,%rax,8),%rdx
L30:
  movsd  (%rdx),%xmm0
  movsd  (%r9),%xmm1
  mov    %r8d,%eax
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%r9)
  ret
  nop
L26:
  xor    %r8d,%r8d
  jmp    L30
```

assistant: ```c
int partition(int n, double *arr) {
  int pivot_idx = n / 2;
  double pivot = arr[pivot_idx];
  double tmp;
  int i, store_index;
  tmp = arr[n - 1];
  arr[n - 1] = pivot;
  arr[pivot_idx] = tmp;
  store_index = 0;
  for (i = 0; i < n - 1; i++) {
    if (arr[i] < pivot) {
      tmp = arr[store_index];
      arr[store_index] = arr[i];
      arr[i] = tmp;
      store_index++;
    }
  }
  tmp = arr[store_index];
  arr[store_index] = arr[n - 1];
  arr[n - 1] = tmp;
  return store_index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<partition>:
  endbr64
  mov    %edi,%eax
  movslq %edi,%rcx
  mov    %rsi,%rdx
  shr    $0x1f,%eax
  lea    -0x8(%rsi,%rcx,8),%r9
  add    %edi,%eax
  movsd  (%r9),%xmm0
  sar    %eax
  cltq
  lea    (%rsi,%rax,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm1,(%r9)
  movsd  %xmm0,(%rax)
  cmp    $0x1,%edi
  jle    L23
  lea    -0x2(%rdi),%ecx
  mov    %rsi,%rax
  xor    %r8d,%r8d
  lea    0x8(%rsi,%rcx,8),%rsi
  nopl   0x0(%rax,%rax,1)
L20:
  movsd  (%rax),%xmm0
  comisd %xmm0,%xmm1
  jbe    L31
  movslq %r8d,%rcx
  add    $0x1,%r8d
  lea    (%rdx,%rcx,8),%rcx
  movsd  (%rcx),%xmm2
  movsd  %xmm0,(%rcx)
  movsd  %xmm2,(%rax)
L31:
  add    $0x8,%rax
  cmp    %rax,%rsi
  jne    L20
  movslq %r8d,%rax
  lea    (%rdx,%rax,8),%rdx
L26:
  movsd  (%rdx),%xmm0
  movsd  (%r9),%xmm1
  mov    %r8d,%eax
  movsd  %xmm1,(%rdx)
  movsd  %xmm0,(%r9)
  ret
  nop
L23:
  xor    %r8d,%r8d
  jmp    L26
```

assistant: ```c
int partition(int n, double *arr) {
  int pivot_idx = n / 2;
  double pivot = arr[pivot_idx];
  double tmp;
  int i, store_index;
  tmp = arr[n - 1];
  arr[n - 1] = pivot;
  arr[pivot_idx] = tmp;
  store_index = 0;
  for (i = 0; i < n - 1; i++) {
    if (arr[i] < pivot) {
      tmp = arr[store_index];
      arr[store_index] = arr[i];
      arr[i] = tmp;
      store_index++;
    }
  }
  tmp = arr[store_index];
  arr[store_index] = arr[n - 1];
  arr[n - 1] = tmp;
  return store_index;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<irc_dcc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    $0xffffffff,%edi
  call   <_irc_queue_init@plt>
  mov    -0x8(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <client@plt>
  add    $0x10,%rsp
  leave
  ret
```

assistant: ```c
int irc_dcc(int sid, char *addr, int port) {
  _irc_queue_init(-1);
  return client(sid, 2, addr, port, NULL, NULL, NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<irc_dcc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    $0xffffffff,%edi
  call   <_irc_queue_init@plt>
  sub    $0x8,%rsp
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %r12d,%ecx
  mov    %rbp,%rdx
  mov    $0x2,%esi
  mov    %ebx,%edi
  call   <client@plt>
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int irc_dcc(int sid, char *addr, int port) {
  _irc_queue_init(-1);
  return client(sid, 2, addr, port, NULL, NULL, NULL);
}
```
user: What is the c source code of the assembly code below:

```asm
<irc_dcc>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0xffffffff,%edi
  call   <_irc_queue_init@plt>
  sub    $0x8,%rsp
  mov    %r13d,%ecx
  mov    %r12,%rdx
  push   $0x0
  mov    %ebp,%edi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x2,%esi
  call   <client@plt>
  pop    %rdx
  pop    %rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int irc_dcc(int sid, char *addr, int port) {
  _irc_queue_init(-1);
  return client(sid, 2, addr, port, NULL, NULL, NULL);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<irc_dcc>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0xffffffff,%edi
  call   <_irc_queue_init@plt>
  sub    $0x8,%rsp
  mov    %r13d,%ecx
  mov    %r12,%rdx
  push   $0x0
  mov    %ebp,%edi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  mov    $0x2,%esi
  call   <client@plt>
  pop    %rdx
  pop    %rcx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int irc_dcc(int sid, char *addr, int port) {
  _irc_queue_init(-1);
  return client(sid, 2, addr, port, NULL, NULL, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  mov    $0x0,%eax
  call   <foo@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void test5(int e) {
  if ((e >> (32 - 1)) & 64)
    foo();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test5>:
  endbr64
  test   %edi,%edi
  js     L9
  ret
L9:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void test5(int e) {
  if ((e >> (32 - 1)) & 64)
    foo();
}
```
user: What is the c source code of the assembly code below?

```asm
<test5>:
  endbr64
  test   %edi,%edi
  js     L0
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
void test5(int e) {
  if ((e >> (32 - 1)) & 64)
    foo();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test5>:
  endbr64
  test   %edi,%edi
  js     L5
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  jmp    1050 <foo@plt>
```

assistant: ```c
void test5(int e) {
  if ((e >> (32 - 1)) & 64)
    foo();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printPath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd0(%rbp),%rax
  mov    $0xc8,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void printPath() {
  char path[200];
  getcwd(path, 200);
  puts(path);
}
```