user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D19(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x3a0(%rsp),%rbx
  lea    0x10(%rsp),%r12
  lea    0x330(%rsp),%r13
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  lea    -0x1(%rax),%ebp
  mov    %eax,%r14d
  call   <strlen@plt>
  mov    $0x64,%ecx
  mov    %r12,%rdi
  lea    -0x1(%rax),%r10d
  mov    %eax,%edx
  cmp    %r10d,%ebp
  mov    %r10d,%eax
  cmovge %ebp,%eax
  lea    0x2(%rax,%rax,1),%eax
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  rep stos %rax,%es:(%rdi)
  test   %r10d,%r10d
  js     L108
  movslq 0x4(%rsp),%rax
  add    %edx,%r14d
  mov    %r12,0x8(%rsp)
  movslq %r10d,%r10
  mov    %rax,%rdi
  lea    (%r12,%rax,4),%r11
  sub    %edx,%eax
  sub    %r14d,%edi
  mov    %eax,%r14d
  mov    %edi,(%rsp)
  nopl   0x0(%rax)
L27:
  mov    %r10d,%r12d
  lea    (%r14,%r10,1),%edx
  test   %ebp,%ebp
  js     L53
  movsbl 0x0(%r13,%r10,1),%r9d
  movslq %ebp,%r8
  mov    %r11,%rdi
  xor    %eax,%eax
  sub    $0x30,%r9d
  nopl   0x0(%rax)
L71:
  movsbl (%rbx,%r8,1),%ecx
  movslq -0x4(%rdi),%rsi
  sub    $0x1,%r8
  sub    $0x30,%ecx
  mov    %rsi,%rdx
  imul   %r9d,%ecx
  imul   $0x66666667,%rsi,%rsi
  add    %eax,%ecx
  mov    %edx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  mov    %ecx,%r15d
  sub    %eax,%esi
  sar    $0x1f,%r15d
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %r15d,%eax
  lea    (%rax,%rax,4),%r15d
  add    %r15d,%r15d
  sub    %r15d,%ecx
  add    %ecx,%edx
  movslq %edx,%rcx
  mov    %edx,%r15d
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%r15d
  sar    $0x22,%rcx
  sub    %r15d,%ecx
  add    %ecx,%esi
  lea    (%rcx,%rcx,4),%ecx
  add    %esi,-0x8(%rdi)
  sub    $0x4,%rdi
  add    %ecx,%ecx
  sub    %ecx,%edx
  mov    %edx,(%rdi)
  test   %r8d,%r8d
  jns    L71
  mov    (%rsp),%edi
  lea    (%rdi,%r12,1),%edx
L111:
  movslq %edx,%rdx
  sub    $0x1,%r10
  sub    $0x4,%r11
  add    %eax,0x10(%rsp,%rdx,4)
  test   %r10d,%r10d
  jns    L27
  mov    0x8(%rsp),%r12
L108:
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movslq 0x4(%rsp),%rdx
  xor    %eax,%eax
  test   %edx,%edx
  jle    L14
  xchg   %ax,%ax
L57:
  mov    (%r12,%rax,4),%esi
  mov    %eax,%ebx
  test   %esi,%esi
  je     L46
  add    $0x1,%ebx
  mov    0x4(%rsp),%r13d
  lea    D23(%rip),%rbp
  movslq %ebx,%rbx
  jmp    L102
  xchg   %ax,%ax
L9:
  mov    (%r12,%rbx,4),%esi
  add    $0x1,%rbx
L102:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    %ebx,%r13d
  jg     L9
L14:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L46:
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L57
  jmp    L14
L53:
  xor    %eax,%eax
  jmp    L111
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D8
type_guessed: string
name: read_data
arguments: label: D32
type_guessed: string
name: read_data
arguments: label: D31
type_guessed: string
name: read_data
arguments: label: D23
type_guessed: string

tool: D19: 
Enter the first number

tool: D8: %s

tool: D32: 
Enter the second number

tool: D31: 
The product is : 

tool: D23: %d

assistant: ```c
void main() {
  int c[200], car, i, j, k, l, r, s, a, flag = 0;
  char n[100], m[100];
  printf("\nEnter the first number");
  scanf("%s", m);
  printf("\nEnter the second number");
  scanf("%s", n);
  k = strlen(m) - 1;
  l = strlen(n) - 1;
  r = 2 * (((k) > (l)) ? (k) : (l)) + 2;
  for (i = 0; i < 200; i++)
    c[i] = 0;
  s = r;
  for (j = l; j >= 0; j--) {
    s--;
    a = 0;
    car = 0;
    for (i = k; i >= 0; i--) {
      c[s - a - 1] += (c[s - a] / 10);
      c[s - a] %= 10;
      c[s - a] += (((int)(m[i] - '0') * (int)(n[j] - '0') + car) % 10);
      car = ((int)(m[i] - '0') * (int)(n[j] - '0') + car) / 10;
      c[s - a - 1] += (c[s - a] / 10);
      c[s - a] %= 10;
      a++;
    }
    c[s - a] += car;
  }
  printf("\nThe product is : ");
  for (i = 0; i < r; i++) {
    if (c[i] != 0 && flag == 0)
      flag = 1;
    if (flag == 1)
      printf("%d", c[i]);
  }
}
```