ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x150,%rsp
  mov    %edi,-0x144(%rbp)
  mov    %rsi,-0x150(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x2,-0x144(%rbp)
  je     L3
  mov    $0x0,%eax
  call   <printUsage@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L3:
  mov    -0x150(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <fileExist@plt>
  test   %eax,%eax
  jne    L18
  mov    -0x150(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L18:
  mov    -0x150(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x140(%rbp),%rax
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x140(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string

tool: D19: '%s' not exist!


tool: D13: mipsel-linux-objdump -D -m mips -b binary %s | sed '1, 7d'

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printUsage();
    exit(1);
  }
  if (!fileExist(argv[1])) {
    printf("\'%s\' not exist!\n", argv[1]);
    exit(1);
  }
  char str[300];
  sprintf(str, "mipsel-linux-objdump -D -m mips -b binary %s | sed \'1, 7d\'", argv[1]);
  system(str);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x140,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  jne    L35
L1:
  mov    0x8(%rbx),%rdi
  call   <fileExist@plt>
  test   %eax,%eax
  je     L36
L5:
  mov    0x8(%rbx),%rdx
  mov    %rsp,%rbx
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x140,%rsp
  pop    %rbx
  ret
L35:
  call   <printUsage@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
L36:
  mov    0x8(%rbx),%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
data_type: string
name: disassemble_data
arguments: data_tag: D11
data_type: string

tool: D19: mipsel-linux-objdump -D -m mips -b binary %s | sed '1, 7d'

tool: D11: '%s' not exist!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printUsage();
    exit(1);
  }
  if (!fileExist(argv[1])) {
    printf("\'%s\' not exist!\n", argv[1]);
    exit(1);
  }
  char str[300];
  sprintf(str, "mipsel-linux-objdump -D -m mips -b binary %s | sed \'1, 7d\'", argv[1]);
  system(str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L36
  call   <printUsage@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L36:
  mov    0x8(%rbx),%rdi
  call   <fileExist@plt>
  test   %eax,%eax
  je     L35
L38:
  mov    %rsp,%rbp
  mov    0x8(%rbx),%rdx
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x148,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L35:
  mov    0x8(%rbx),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L38
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string

tool: D13: mipsel-linux-objdump -D -m mips -b binary %s | sed '1, 7d'

tool: D0: '%s' not exist!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printUsage();
    exit(1);
  }
  if (!fileExist(argv[1])) {
    printf("\'%s\' not exist!\n", argv[1]);
    exit(1);
  }
  char str[300];
  sprintf(str, "mipsel-linux-objdump -D -m mips -b binary %s | sed \'1, 7d\'", argv[1]);
  system(str);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L29
  call   <printUsage@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L29:
  mov    0x8(%rbx),%rdi
  call   <fileExist@plt>
  test   %eax,%eax
  je     L32
L22:
  mov    %rsp,%rbp
  mov    0x8(%rbx),%rdx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x148,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  mov    0x8(%rbx),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L22
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D8
data_type: string

tool: D7: mipsel-linux-objdump -D -m mips -b binary %s | sed '1, 7d'

tool: D8: '%s' not exist!


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printUsage();
    exit(1);
  }
  if (!fileExist(argv[1])) {
    printf("\'%s\' not exist!\n", argv[1]);
    exit(1);
  }
  char str[300];
  sprintf(str, "mipsel-linux-objdump -D -m mips -b binary %s | sed \'1, 7d\'", argv[1]);
  system(str);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<restart_ddns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%r8
  lea    D9(%rip),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <va_cmd@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
data_type: string
name: extract_symbolic_data
arguments: data_label: D9
data_type: string
name: extract_symbolic_data
arguments: data_label: D2
data_type: string

tool: D10: 1

tool: D9: all

tool: D2: /bin/updateddctrl

assistant: ```c
int restart_ddns(void) {
  va_cmd("/bin/updateddctrl", 2, 1, "all", "1");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<restart_ddns>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%r8
  lea    D7(%rip),%rcx
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D8(%rip),%rdi
  call   <va_cmd@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D24
data_type: string
name: unpack_data
arguments: label: D7
data_type: string
name: unpack_data
arguments: label: D8
data_type: string

tool: D24: 1

tool: D7: all

tool: D8: /bin/updateddctrl

assistant: ```c
int restart_ddns(void) {
  va_cmd("/bin/updateddctrl", 2, 1, "all", "1");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<restart_ddns>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D24(%rip),%r8
  lea    D4(%rip),%rcx
  lea    D23(%rip),%rdi
  call   <va_cmd@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_infered: string
name: extract_symbolic_data
arguments: label: D4
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: string

tool: D24: 1

tool: D4: all

tool: D23: /bin/updateddctrl

assistant: ```c
int restart_ddns(void) {
  va_cmd("/bin/updateddctrl", 2, 1, "all", "1");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<restart_ddns>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edx
  mov    $0x2,%esi
  lea    D2(%rip),%r8
  lea    D25(%rip),%rcx
  lea    D0(%rip),%rdi
  call   <va_cmd@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D25
type_guessed: string
name: retrieve_data
arguments: tag: D0
type_guessed: string

tool: D2: 1

tool: D25: all

tool: D0: /bin/updateddctrl

assistant: ```c
int restart_ddns(void) {
  va_cmd("/bin/updateddctrl", 2, 1, "all", "1");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <gmx_helix@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_helix(argc, argv);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_helix@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_helix(argc, argv);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_helix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_helix(argc, argv);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  call   <gmx_helix@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  gmx_helix(argc, argv);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x40(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L33:
  cmp    %rdx,%rsp
  je     L13
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L13:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L38
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L38:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x3c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x40(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x40(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *substr(const char *buff, int start, int len) {
  char subbuff[len + 1];
  memcpy(subbuff, &buff[start], len);
  subbuff[len] = '\0';
  return strdup(subbuff);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rdx),%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L15:
  cmp    %rdx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L15
L5:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L28
  orq    $0x0,-0x8(%rsp,%rax,1)
L28:
  movslq %esi,%rsi
  add    %rdi,%rsi
  mov    %ebx,%edx
  mov    %rsp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rsp,%rbx,1)
  mov    %rsp,%rdi
  call   <strdup@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  mov    -0x8(%rbp),%rbx
  leave
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *substr(const char *buff, int start, int len) {
  char subbuff[len + 1];
  memcpy(subbuff, &buff[start], len);
  subbuff[len] = '\0';
  return strdup(subbuff);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rsp,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rbx),%eax
  mov    %rsp,%rdi
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rdi,%rsp
  je     L8
L13:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L13
L8:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L46
L45:
  movslq %esi,%rsi
  mov    %ebx,%edx
  mov    %rsp,%rdi
  add    %rcx,%rsi
  call   <memcpy@plt>
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <strdup@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L46:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L45
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *substr(const char *buff, int start, int len) {
  char subbuff[len + 1];
  memcpy(subbuff, &buff[start], len);
  subbuff[len] = '\0';
  return strdup(subbuff);
}
```
user: What is the c source code of the assembly code below?

```asm
<substr>:
  endbr64
  push   %rbp
  mov    %rdi,%rcx
  mov    %rsp,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    0x1(%rbx),%eax
  mov    %rsp,%rdi
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rdi,%rsp
  je     L33
L9:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L9
L33:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L14
L42:
  movslq %esi,%rsi
  mov    %ebx,%edx
  mov    %rsp,%rdi
  add    %rcx,%rsi
  call   <memcpy@plt>
  mov    %rsp,%rdi
  movb   $0x0,(%rsp,%rbx,1)
  call   <strdup@plt>
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L42
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *substr(const char *buff, int start, int len) {
  char subbuff[len + 1];
  memcpy(subbuff, &buff[start], len);
  subbuff[len] = '\0';
  return strdup(subbuff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_in_case_lassert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    D9(%rip),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L9
  mov    -0x14(%rbp),%eax
  mov    %eax,D1(%rip)
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _in_case_lassert(int option) {
  static int is_in = 0;
  int i = is_in;
  if (option != -1)
    is_in = option;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_in_case_lassert>:
  endbr64
  mov    D7(%rip),%eax
  cmp    $0xffffffff,%edi
  je     L4
  mov    %edi,D8(%rip)
L4:
  ret
```

assistant: ```c
int _in_case_lassert(int option) {
  static int is_in = 0;
  int i = is_in;
  if (option != -1)
    is_in = option;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_in_case_lassert>:
  endbr64
  mov    D14(%rip),%eax
  cmp    $0xffffffff,%edi
  je     L6
  mov    %edi,D13(%rip)
L6:
  ret
```

assistant: ```c
int _in_case_lassert(int option) {
  static int is_in = 0;
  int i = is_in;
  if (option != -1)
    is_in = option;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_in_case_lassert>:
  endbr64
  mov    D10(%rip),%eax
  cmp    $0xffffffff,%edi
  je     L5
  mov    %edi,D8(%rip)
L5:
  ret
```

assistant: ```c
int _in_case_lassert(int option) {
  static int is_in = 0;
  int i = is_in;
  if (option != -1)
    is_in = option;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<free_pipe_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_pipe_array(int max, char **array) {
  int i;
  for (i = 0; i < max; ++i)
    free(array[i]);
  free(array);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<free_pipe_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  test   %edi,%edi
  jle    L17
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L6:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L6
L17:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void free_pipe_array(int max, char **array) {
  int i;
  for (i = 0; i < max; ++i)
    free(array[i]);
  free(array);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<free_pipe_array>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L0
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L12
L0:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_pipe_array(int max, char **array) {
  int i;
  for (i = 0; i < max; ++i)
    free(array[i]);
  free(array);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_pipe_array>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L1
  lea    -0x1(%rdi),%eax
  mov    %rsi,%rbx
  lea    0x8(%rsi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L17
L1:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void free_pipe_array(int max, char **array) {
  int i;
  for (i = 0; i < max; ++i)
    free(array[i]);
  free(array);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_spec_text>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <inst_2_str@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <inst_has_argu@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L12
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L21
L12:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  addq   $0x4,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D24
type_infered: string
name: extract_symbolic_data
arguments: label: D0
type_infered: string
name: extract_symbolic_data
arguments: label: D21
type_infered: string

tool: D24: addr %p ## %s

tool: D0: addr %p ## %x

tool: D21:  %#x(%d)

assistant: ```c
int print_spec_text(int *cur_text) {
  int has_argu = 0;
  const char *inst_str = inst_2_str(*cur_text);
  has_argu = inst_has_argu(*cur_text);
  if (inst_str)
    printf("addr %p ## %s", cur_text, inst_str);
  else
    printf("addr %p ## %x", cur_text, *cur_text);
  if (has_argu) {
    ++cur_text;
    printf(" %#x(%d)", *cur_text, *cur_text);
  }
  printf("\n");
  return has_argu;
}
```
user: What is the c source code of the assembly code below:

```asm
<print_spec_text>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <inst_2_str@plt>
  mov    %rax,%r12
  mov    (%rbx),%edi
  call   <inst_has_argu@plt>
  mov    %eax,%ebp
  test   %r12,%r12
  je     L22
  mov    %r12,%rdx
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L28:
  test   %ebp,%ebp
  jne    L15
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L28
L15:
  mov    0x4(%rbx),%esi
  mov    %esi,%edx
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D24
type: string
name: unpack_data
arguments: label: D20
type: string

tool: D10: addr %p ## %s

tool: D24: addr %p ## %x

tool: D20:  %#x(%d)

assistant: ```c
int print_spec_text(int *cur_text) {
  int has_argu = 0;
  const char *inst_str = inst_2_str(*cur_text);
  has_argu = inst_has_argu(*cur_text);
  if (inst_str)
    printf("addr %p ## %s", cur_text, inst_str);
  else
    printf("addr %p ## %x", cur_text, *cur_text);
  if (has_argu) {
    ++cur_text;
    printf(" %#x(%d)", *cur_text, *cur_text);
  }
  printf("\n");
  return has_argu;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_spec_text>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%edi
  call   <inst_2_str@plt>
  mov    (%rbx),%edi
  mov    %rax,%r13
  call   <inst_has_argu@plt>
  mov    %eax,%r12d
  test   %r13,%r13
  je     L27
  mov    %r13,%rdx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L6:
  test   %r12d,%r12d
  jne    L31
L10:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L31:
  mov    0x4(%rbx),%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  mov    %esi,%edx
  call   <printf@plt>
  jmp    L10
  nopl   (%rax)
L27:
  mov    (%rbx),%edx
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string
name: unpack_data
arguments: data_tag: D1
data_type: string
name: unpack_data
arguments: data_tag: D26
data_type: string

tool: D6: addr %p ## %s

tool: D1:  %#x(%d)

tool: D26: addr %p ## %x

assistant: ```c
int print_spec_text(int *cur_text) {
  int has_argu = 0;
  const char *inst_str = inst_2_str(*cur_text);
  has_argu = inst_has_argu(*cur_text);
  if (inst_str)
    printf("addr %p ## %s", cur_text, inst_str);
  else
    printf("addr %p ## %x", cur_text, *cur_text);
  if (has_argu) {
    ++cur_text;
    printf(" %#x(%d)", *cur_text, *cur_text);
  }
  printf("\n");
  return has_argu;
}
```