ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    $0x1,%edx
  mov    $0x0,%eax
L8:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L8
L20:
  mov    %edx,%eax
  ret
L18:
  mov    $0x1,%edx
  jmp    L20
```

assistant: ```c
int power(int b, int p) {
  int k;
  int result = 1;
  for (k = 0; k < p; k++) {
    result *= b;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<power>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L12
  xor    %eax,%eax
L1:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L1
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int b, int p) {
  int k;
  int result = 1;
  for (k = 0; k < p; k++) {
    result *= b;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L7
  xor    %eax,%eax
L11:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L11
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int b, int p) {
  int k;
  int result = 1;
  for (k = 0; k < p; k++) {
    result *= b;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L26
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L3:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
L26:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2:   

assistant: ```c
void ps(const int loglevel, const int verbosity, const int n) {
  int i;
  if (verbosity >= loglevel) {
    for (i = 0; i < n; i++) {
      printf("  ");
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ps>:
  endbr64
  cmp    %edi,%esi
  jl     L1
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebp
  test   %edx,%edx
  jle    L25
  mov    $0x0,%ebx
  lea    D7(%rip),%r12
L29:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L29
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D7:   

assistant: ```c
void ps(const int loglevel, const int verbosity, const int n) {
  int i;
  if (verbosity >= loglevel) {
    for (i = 0; i < n; i++) {
      printf("  ");
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ps>:
  endbr64
  cmp    %edi,%esi
  jl     L23
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  test   %edx,%edx
  jle    L7
  xor    %ebx,%ebx
  lea    D7(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L9
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7:   

assistant: ```c
void ps(const int loglevel, const int verbosity, const int n) {
  int i;
  if (verbosity >= loglevel) {
    for (i = 0; i < n; i++) {
      printf("  ");
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ps>:
  endbr64
  cmp    %edi,%esi
  jl     L23
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  test   %edx,%edx
  jle    L20
  xor    %ebx,%ebx
  lea    D3(%rip),%r12
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L18
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3:   

assistant: ```c
void ps(const int loglevel, const int verbosity, const int n) {
  int i;
  if (verbosity >= loglevel) {
    for (i = 0; i < n; i++) {
      printf("  ");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getsockname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x6,%edi
  call   <__socketcall@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int getsockname(int sockfd, struct sockaddr *addr, socklen_t *paddrlen) {
  unsigned long args[3];
  args[0] = sockfd;
  args[1] = (unsigned long)addr;
  args[2] = (unsigned long)paddrlen;
  return __socketcall(6, args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getsockname>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movslq %edi,%rdi
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %rdx,0x10(%rsp)
  mov    %rsp,%rsi
  mov    $0x6,%edi
  call   <__socketcall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getsockname(int sockfd, struct sockaddr *addr, socklen_t *paddrlen) {
  unsigned long args[3];
  args[0] = sockfd;
  args[1] = (unsigned long)addr;
  args[2] = (unsigned long)paddrlen;
  return __socketcall(6, args);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getsockname>:
  endbr64
  sub    $0x28,%rsp
  movslq %edi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,(%rsp)
  mov    $0x6,%edi
  mov    %rsi,0x8(%rsp)
  mov    %rsp,%rsi
  mov    %rdx,0x10(%rsp)
  call   <__socketcall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getsockname(int sockfd, struct sockaddr *addr, socklen_t *paddrlen) {
  unsigned long args[3];
  args[0] = sockfd;
  args[1] = (unsigned long)addr;
  args[2] = (unsigned long)paddrlen;
  return __socketcall(6, args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getsockname>:
  endbr64
  sub    $0x28,%rsp
  movq   %rsi,%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movslq %edi,%rax
  mov    %rsp,%rsi
  mov    $0x6,%edi
  movq   %rax,%xmm0
  mov    %rdx,0x10(%rsp)
  punpcklqdq %xmm1,%xmm0
  movaps %xmm0,(%rsp)
  call   <__socketcall@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getsockname(int sockfd, struct sockaddr *addr, socklen_t *paddrlen) {
  unsigned long args[3];
  args[0] = sockfd;
  args[1] = (unsigned long)addr;
  args[2] = (unsigned long)paddrlen;
  return __socketcall(6, args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<PRRealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  leave
  ret
```

assistant: ```c
void *PRRealloc(void *ptr, int size) {
  ;
  return realloc(ptr, size);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PRRealloc>:
  endbr64
  sub    $0x8,%rsp
  call   <realloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *PRRealloc(void *ptr, int size) {
  ;
  return realloc(ptr, size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<PRRealloc>:
  endbr64
  jmp    1050 <realloc@plt>
```

assistant: ```c
void *PRRealloc(void *ptr, int size) {
  ;
  return realloc(ptr, size);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PRRealloc>:
  endbr64
  jmp    1050 <realloc@plt>
```

assistant: ```c
void *PRRealloc(void *ptr, int size) {
  ;
  return realloc(ptr, size);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wcsutil_setAli>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L5
  cmpl   $0x0,-0x18(%rbp)
  jle    L5
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L24
L6:
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x8(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L6
  jmp    L39
L5:
  nop
L39:
  pop    %rbp
  ret
```

assistant: ```c
void wcsutil_setAli(int nvec, int nelem, int *first) {
  if (nvec <= 0 || nelem <= 0)
    return;
  int v0 = *first;
  for (int *vp = first + nelem; vp < first + nvec * nelem; vp += nelem) {
    *vp = v0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcsutil_setAli>:
  endbr64
  test   %edi,%edi
  jle    L11
  test   %esi,%esi
  jle    L11
  mov    (%rdx),%r8d
  movslq %esi,%rcx
  shl    $0x2,%rcx
  lea    (%rdx,%rcx,1),%rax
  imul   %esi,%edi
  movslq %edi,%rdi
  lea    (%rdx,%rdi,4),%rdx
  cmp    %rdx,%rax
  jae    L11
L8:
  mov    %r8d,(%rax)
  add    %rcx,%rax
  cmp    %rdx,%rax
  jb     L8
L11:
  ret
```

assistant: ```c
void wcsutil_setAli(int nvec, int nelem, int *first) {
  if (nvec <= 0 || nelem <= 0)
    return;
  int v0 = *first;
  for (int *vp = first + nelem; vp < first + nvec * nelem; vp += nelem) {
    *vp = v0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcsutil_setAli>:
  endbr64
  test   %edi,%edi
  jle    L3
  test   %esi,%esi
  jle    L3
  imul   %esi,%edi
  movslq %esi,%rcx
  mov    (%rdx),%r8d
  shl    $0x2,%rcx
  lea    (%rdx,%rcx,1),%rax
  movslq %edi,%rdi
  lea    (%rdx,%rdi,4),%rdx
  cmp    %rdx,%rax
  jae    L3
  nopl   0x0(%rax)
L32:
  mov    %r8d,(%rax)
  add    %rcx,%rax
  cmp    %rdx,%rax
  jb     L32
L3:
  ret
```

assistant: ```c
void wcsutil_setAli(int nvec, int nelem, int *first) {
  if (nvec <= 0 || nelem <= 0)
    return;
  int v0 = *first;
  for (int *vp = first + nelem; vp < first + nvec * nelem; vp += nelem) {
    *vp = v0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcsutil_setAli>:
  endbr64
  test   %edi,%edi
  jle    L28
  test   %esi,%esi
  jle    L28
  imul   %esi,%edi
  movslq %esi,%rcx
  mov    (%rdx),%r8d
  shl    $0x2,%rcx
  lea    (%rdx,%rcx,1),%rax
  movslq %edi,%rdi
  lea    (%rdx,%rdi,4),%rdx
  cmp    %rdx,%rax
  jae    L28
  cmp    $0x1,%esi
  jne    L26
  xchg   %ax,%ax
L55:
  mov    %r8d,(%rax)
  add    %rcx,%rax
  cmp    %rdx,%rax
  jb     L55
L28:
  ret
  nopl   0x0(%rax)
L26:
  mov    %r8d,(%rax)
  add    %rcx,%rax
  cmp    %rdx,%rax
  jb     L26
  ret
```

assistant: ```c
void wcsutil_setAli(int nvec, int nelem, int *first) {
  if (nvec <= 0 || nelem <= 0)
    return;
  int v0 = *first;
  for (int *vp = first + nelem; vp < first + nvec * nelem; vp += nelem) {
    *vp = v0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getTotalLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <debugMsg@plt>
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L43
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L9
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L28
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L28
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L28:
  addl   $0x1,-0x8(%rbp)
L43:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <debugMsg@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D18
type: string
name: parse_data
arguments: label: D19
type: string

tool: D18: getTotalLine() ...

tool: D19: getTotalLine() ... ok ...

assistant: ```c
int getTotalLine(char *str) {
  debugMsg("getTotalLine() ...");
  int i = 0, j = 0;
  while (str[i] != '\0') {
    if (str[i] == '\n') {
      j++;
    }
    if (i == strlen(str) - 1 && str[i] != '\n') {
      str[i + 1] = '\n';
      str[i + 2] = '\0';
    }
    i++;
  }
  debugMsg("getTotalLine() ... ok ...");
  return j;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getTotalLine>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  call   <debugMsg@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L41
  mov    $0x0,%r12d
  mov    $0x0,%ebx
  jmp    L59
L11:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L13
L59:
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L11
  cmpb   $0xa,0x0(%rbp,%rbx,1)
  je     L11
  movb   $0xa,0x1(%rbp,%rbx,1)
  movb   $0x0,0x2(%rbp,%rbx,1)
  jmp    L11
L41:
  mov    $0x0,%r12d
L13:
  lea    D5(%rip),%rdi
  call   <debugMsg@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D18: getTotalLine() ...

tool: D5: getTotalLine() ... ok ...

assistant: ```c
int getTotalLine(char *str) {
  debugMsg("getTotalLine() ...");
  int i = 0, j = 0;
  while (str[i] != '\0') {
    if (str[i] == '\n') {
      j++;
    }
    if (i == strlen(str) - 1 && str[i] != '\n') {
      str[i + 1] = '\n';
      str[i + 2] = '\0';
    }
    i++;
  }
  debugMsg("getTotalLine() ... ok ...");
  return j;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getTotalLine>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  push   %rbx
  call   <debugMsg@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L55
  xor    %ebx,%ebx
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L28:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L55
L41:
  cmp    $0xa,%al
  mov    %rbp,%rdi
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L28
  cmpb   $0xa,0x0(%rbp,%rbx,1)
  je     L28
  movb   $0xa,0x1(%rbp,%rbx,1)
  movb   $0x0,0x2(%rbp,%rbx,1)
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  jne    L41
L55:
  lea    D17(%rip),%rdi
  call   <debugMsg@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D13
datatype: string
name: parse_data
arguments: label: D17
datatype: string

tool: D13: getTotalLine() ...

tool: D17: getTotalLine() ... ok ...

assistant: ```c
int getTotalLine(char *str) {
  debugMsg("getTotalLine() ...");
  int i = 0, j = 0;
  while (str[i] != '\0') {
    if (str[i] == '\n') {
      j++;
    }
    if (i == strlen(str) - 1 && str[i] != '\n') {
      str[i + 1] = '\n';
      str[i + 2] = '\0';
    }
    i++;
  }
  debugMsg("getTotalLine() ... ok ...");
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getTotalLine>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  push   %rbx
  call   <debugMsg@plt>
  movzbl 0x0(%rbp),%eax
  test   %al,%al
  je     L7
  xor    %ebx,%ebx
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L36:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L7
L48:
  cmp    $0xa,%al
  mov    %rbp,%rdi
  sete   %al
  movzbl %al,%eax
  add    %eax,%r12d
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L36
  cmpb   $0xa,0x0(%rbp,%rbx,1)
  je     L36
  movb   $0xa,0x1(%rbp,%rbx,1)
  movb   $0x0,0x2(%rbp,%rbx,1)
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  jne    L48
L7:
  lea    D15(%rip),%rdi
  call   <debugMsg@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string

tool: D8: getTotalLine() ...

tool: D15: getTotalLine() ... ok ...

assistant: ```c
int getTotalLine(char *str) {
  debugMsg("getTotalLine() ...");
  int i = 0, j = 0;
  while (str[i] != '\0') {
    if (str[i] == '\n') {
      j++;
    }
    if (i == strlen(str) - 1 && str[i] != '\n') {
      str[i + 1] = '\n';
      str[i + 2] = '\0';
    }
    i++;
  }
  debugMsg("getTotalLine() ... ok ...");
  return j;
}
```
user: Translate the below assembly code into C programming language:

```asm
<puthd>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x7d,(%rdx)
  je     L13
  mov    %rdx,%rax
L101:
  add    $0x1,%rax
  cmpb   $0x7d,(%rax)
  jne    L101
L3:
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L106
L16:
  mov    %dl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L16
L106:
  lea    0x1(%rax),%rcx
  movb   $0x3d,(%rax)
  movzbl (%rsi),%eax
  test   %al,%al
  je     L10
L59:
  mov    %al,(%rcx)
  add    $0x1,%rcx
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L59
L10:
  movb   $0x3b,(%rcx)
  movb   $0xa,0x1(%rcx)
  lea    0x3(%rcx),%rdx
  movb   $0x7d,0x2(%rcx)
  mov    %rdx,%rax
  sub    %rbx,%rax
  mov    %eax,%esi
  sar    $0x1f,%esi
  shr    $0x1e,%esi
  add    %esi,%eax
  and    $0x3,%eax
  sub    %esi,%eax
  mov    $0x4,%edi
  sub    %eax,%edi
  cmp    $0x3,%edi
  jg     L33
  mov    $0x0,%esi
L82:
  movb   $0x20,0x3(%rcx,%rsi,1)
  add    $0x1,%rsi
  cmp    %esi,%edi
  jg     L82
  mov    $0x4,%ecx
  sub    %eax,%ecx
  add    %rcx,%rdx
L33:
  lea    0x3(%rsp),%rdi
  sub    %ebx,%edx
  lea    D6(%rip),%rsi
  call   <sprintf@plt>
  mov    $0x0,%eax
L97:
  movzbl 0x3(%rsp,%rax,1),%edx
  mov    %dl,0xf(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x5,%rax
  jne    L97
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x10,%rsp
  pop    %rbx
  ret
L13:
  mov    %rdx,%rax
  jmp    L3
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: %5d

assistant: ```c
void puthd(char *field, char *value, char *header) {
  char temp[5];
  int i, diff;
  char *hp, *vp, *tp, *fp;
  for (hp = header; *hp != '}'; hp++)
    ;
  for (fp = field; *fp != 0; hp++, fp++)
    *hp = *fp;
  *hp++ = '=';
  for (vp = value; *vp != 0; hp++, vp++)
    *hp = *vp;
  *hp++ = ';';
  *hp++ = 10;
  *hp++ = '}';
  i = (int)(hp - header);
  diff = 4 - i % 4;
  if (diff < 4)
    for (i = 0; i < diff; i++)
      *hp++ = ' ';
  sprintf(temp, "%5d", (int)(hp - header));
  for (i = 0, hp = header + 15, tp = temp; i < 5; i++)
    *hp++ = *tp++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<puthd>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    %rdx,%rax
  cmpb   $0x7d,(%rdx)
  je     L43
  nopw   0x0(%rax,%rax,1)
L61:
  add    $0x1,%rax
  cmpb   $0x7d,(%rax)
  jne    L61
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L99
  nopl   0x0(%rax,%rax,1)
L64:
  mov    %dl,(%rax)
  add    $0x1,%rdi
  add    $0x1,%rax
L43:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L64
L99:
  movb   $0x3d,(%rax)
  lea    0x1(%rax),%rdx
  movzbl (%rsi),%eax
  test   %al,%al
  je     L21
  nop
L11:
  add    $0x1,%rsi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L11
L21:
  lea    0x3(%rdx),%rsi
  mov    $0xa3b,%eax
  movb   $0x7d,0x2(%rdx)
  mov    %ax,(%rdx)
  mov    %rsi,%rax
  sub    %rbx,%rax
  mov    %eax,%ecx
  mov    %eax,%edx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%eax
  and    $0x3,%eax
  sub    %eax,%ecx
  add    $0x4,%ecx
  cmp    $0x3,%ecx
  jg     L24
  movslq %ecx,%rdx
  test   %ecx,%ecx
  je     L14
  xor    %eax,%eax
L82:
  mov    %eax,%edi
  add    $0x1,%eax
  movb   $0x20,(%rsi,%rdi,1)
  cmp    %ecx,%eax
  jb     L82
L14:
  add    %rsi,%rdx
  sub    %ebx,%edx
L24:
  lea    0x3(%rsp),%rdi
  lea    D4(%rip),%rsi
  call   <sprintf@plt>
  mov    0x3(%rsp),%eax
  mov    %eax,0xf(%rbx)
  movzbl 0x7(%rsp),%eax
  mov    %al,0x13(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x10,%rsp
  pop    %rbx
  ret
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: string

tool: D4: %5d

assistant: ```c
void puthd(char *field, char *value, char *header) {
  char temp[5];
  int i, diff;
  char *hp, *vp, *tp, *fp;
  for (hp = header; *hp != '}'; hp++)
    ;
  for (fp = field; *fp != 0; hp++, fp++)
    *hp = *fp;
  *hp++ = '=';
  for (vp = value; *vp != 0; hp++, vp++)
    *hp = *vp;
  *hp++ = ';';
  *hp++ = 10;
  *hp++ = '}';
  i = (int)(hp - header);
  diff = 4 - i % 4;
  if (diff < 4)
    for (i = 0; i < diff; i++)
      *hp++ = ' ';
  sprintf(temp, "%5d", (int)(hp - header));
  for (i = 0, hp = header + 15, tp = temp; i < 5; i++)
    *hp++ = *tp++;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puthd>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    %rdx,%rax
  cmpb   $0x7d,(%rdx)
  je     L40
  nopw   0x0(%rax,%rax,1)
L90:
  add    $0x1,%rax
  cmpb   $0x7d,(%rax)
  jne    L90
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L8
  nopl   0x0(%rax,%rax,1)
L95:
  mov    %dl,(%rax)
  add    $0x1,%rdi
  add    $0x1,%rax
L40:
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L95
L8:
  movb   $0x3d,(%rax)
  lea    0x1(%rax),%rdx
  movzbl (%rsi),%eax
  test   %al,%al
  je     L13
  nop
L27:
  add    $0x1,%rsi
  mov    %al,(%rdx)
  add    $0x1,%rdx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L27
L13:
  lea    0x3(%rdx),%rsi
  mov    $0xa3b,%eax
  movb   $0x7d,0x2(%rdx)
  mov    %ax,(%rdx)
  mov    %rsi,%rax
  sub    %rbx,%rax
  mov    %eax,%ecx
  mov    %eax,%edx
  sar    $0x1f,%ecx
  shr    $0x1e,%ecx
  add    %ecx,%eax
  and    $0x3,%eax
  sub    %eax,%ecx
  add    $0x4,%ecx
  cmp    $0x3,%ecx
  jg     L33
  movslq %ecx,%rdx
  test   %ecx,%ecx
  je     L20
  xor    %eax,%eax
L41:
  mov    %eax,%edi
  add    $0x1,%eax
  movb   $0x20,(%rsi,%rdi,1)
  cmp    %ecx,%eax
  jb     L41
L20:
  add    %rsi,%rdx
  sub    %ebx,%edx
L33:
  lea    0x3(%rsp),%rdi
  lea    D6(%rip),%rsi
  call   <sprintf@plt>
  mov    0x3(%rsp),%eax
  mov    %eax,0xf(%rbx)
  movzbl 0x7(%rsp),%eax
  mov    %al,0x13(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x10,%rsp
  pop    %rbx
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_guessed: string

tool: D6: %5d

assistant: ```c
void puthd(char *field, char *value, char *header) {
  char temp[5];
  int i, diff;
  char *hp, *vp, *tp, *fp;
  for (hp = header; *hp != '}'; hp++)
    ;
  for (fp = field; *fp != 0; hp++, fp++)
    *hp = *fp;
  *hp++ = '=';
  for (vp = value; *vp != 0; hp++, vp++)
    *hp = *vp;
  *hp++ = ';';
  *hp++ = 10;
  *hp++ = '}';
  i = (int)(hp - header);
  diff = 4 - i % 4;
  if (diff < 4)
    for (i = 0; i < diff; i++)
      *hp++ = ' ';
  sprintf(temp, "%5d", (int)(hp - header));
  for (i = 0, hp = header + 15, tp = temp; i < 5; i++)
    *hp++ = *tp++;
}
```