ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strtoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L68
L60:
  addq   $0x1,-0x8(%rbp)
L68:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L60
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L53
  movl   $0x1,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L73
L53:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L73
  addq   $0x1,-0x8(%rbp)
  jmp    L73
L39:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L73:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L39
  cmpq   $0x0,-0x30(%rbp)
  je     L4
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L4:
  cmpl   $0x0,-0x14(%rbp)
  jne    L87
  mov    -0x10(%rbp),%rax
  neg    %rax
  jmp    L5
L87:
  mov    -0x10(%rbp),%rax
L5:
  leave
  ret
```

assistant: ```c
long long strtoll(const char *str, char **endptr, int base) {
  long long ret = 0;
  char *p = (char *)str;
  int sig = 0;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    sig = 1;
    p++;
  } else {
    if (*p == '+')
      p++;
  }
  while (isdigit(*p)) {
    ret = ret * 10 + *p - '0';
    p++;
  }
  if (endptr)
    *endptr = p;
  return sig ? ret : -ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strtoll>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  jmp    L58
L13:
  add    $0x1,%rbp
L58:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L13
  movzbl 0x0(%rbp),%eax
  cmp    $0x2d,%al
  je     L57
  mov    $0x0,%r13d
  cmp    $0x2b,%al
  jne    L23
  add    $0x1,%rbp
  jmp    L23
L57:
  add    $0x1,%rbp
  mov    $0x1,%r13d
  jmp    L23
L68:
  lea    (%rbx,%rbx,4),%rdx
  movsbq 0x0(%rbp),%rax
  lea    -0x30(%rax,%rdx,2),%rbx
  add    $0x1,%rbp
L23:
  movsbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L68
  test   %r12,%r12
  je     L37
  mov    %rbp,(%r12)
L37:
  mov    %rbx,%rax
  neg    %rax
  test   %r13d,%r13d
  cmove  %rax,%rbx
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long long strtoll(const char *str, char **endptr, int base) {
  long long ret = 0;
  char *p = (char *)str;
  int sig = 0;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    sig = 1;
    p++;
  } else {
    if (*p == '+')
      p++;
  }
  while (isdigit(*p)) {
    ret = ret * 10 + *p - '0';
    p++;
  }
  if (endptr)
    *endptr = p;
  return sig ? ret : -ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strtoll>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L0
  cs nopw 0x0(%rax,%rax,1)
L64:
  add    $0x1,%rbx
L0:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L64
  movsbl (%rbx),%edi
  cmp    $0x2d,%dil
  je     L66
  xor    %r13d,%r13d
  cmp    $0x2b,%dil
  jne    L31
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %rax,%rax
  je     L55
  nopl   0x0(%rax,%rax,1)
L36:
  movsbq (%rbx),%rax
  lea    (%r12,%r12,4),%rdx
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12
L31:
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L36
L55:
  test   %rbp,%rbp
  je     L52
  mov    %rbx,0x0(%rbp)
L52:
  mov    %r12,%rax
  neg    %rax
  test   %r13d,%r13d
  cmove  %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  movsbl 0x1(%rbx),%edi
  mov    $0x1,%r13d
  add    $0x1,%rbx
  jmp    L31
```

assistant: ```c
long long strtoll(const char *str, char **endptr, int base) {
  long long ret = 0;
  char *p = (char *)str;
  int sig = 0;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    sig = 1;
    p++;
  } else {
    if (*p == '+')
      p++;
  }
  while (isdigit(*p)) {
    ret = ret * 10 + *p - '0';
    p++;
  }
  if (endptr)
    *endptr = p;
  return sig ? ret : -ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtoll>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L29:
  add    $0x1,%rbx
L35:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L29
  movzbl (%rbx),%eax
  cmp    $0x2d,%al
  je     L36
  xor    %r13d,%r13d
  cmp    $0x2b,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L16:
  movsbq (%rbx),%rax
  lea    (%r12,%r12,4),%rdx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rdx,2),%r12
L66:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L16
  test   %rbp,%rbp
  je     L69
  mov    %rbx,0x0(%rbp)
L69:
  mov    %r12,%rax
  neg    %rax
  test   %r13d,%r13d
  cmove  %rax,%r12
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  add    $0x1,%rbx
  mov    $0x1,%r13d
  jmp    L66
```

assistant: ```c
long long strtoll(const char *str, char **endptr, int base) {
  long long ret = 0;
  char *p = (char *)str;
  int sig = 0;
  while (isspace(*p))
    p++;
  if (*p == '-') {
    sig = 1;
    p++;
  } else {
    if (*p == '+')
      p++;
  }
  while (isdigit(*p)) {
    ret = ret * 10 + *p - '0';
    p++;
  }
  if (endptr)
    *endptr = p;
  return sig ? ret : -ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ReadEntireFileSafely>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <_GetFileSize@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L22
L29:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  lea    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ReadEntireFile@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L13
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  jmp    L22
L13:
  cmpq   $0x0,-0x40(%rbp)
  je     L54
  mov    -0x10(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
L54:
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int ReadEntireFileSafely(char *filename, char *mode, char **pbuf, long *pbufsize) {
  long filesize;
  int nret;
  filesize = _GetFileSize(filename);
  (*pbuf) = (char *)malloc(filesize + 1);
  if ((*pbuf) == NULL)
    return -1;
  memset((*pbuf), 0x00, filesize + 1);
  nret = ReadEntireFile(filename, mode, (*pbuf), &filesize);
  if (nret) {
    free((*pbuf));
    (*pbuf) = NULL;
    return nret;
  } else {
    if (pbufsize)
      (*pbufsize) = filesize;
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ReadEntireFileSafely>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_GetFileSize@plt>
  mov    %rax,(%rsp)
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rsp,%rcx
  mov    (%rbx),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <ReadEntireFile@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jne    L9
  test   %r12,%r12
  je     L3
  mov    (%rsp),%rax
  mov    %rax,(%r12)
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    (%rbx),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  jmp    L3
L6:
  mov    $0xffffffff,%ebp
  jmp    L3
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadEntireFileSafely(char *filename, char *mode, char **pbuf, long *pbufsize) {
  long filesize;
  int nret;
  filesize = _GetFileSize(filename);
  (*pbuf) = (char *)malloc(filesize + 1);
  if ((*pbuf) == NULL)
    return -1;
  memset((*pbuf), 0x00, filesize + 1);
  nret = ReadEntireFile(filename, mode, (*pbuf), &filesize);
  if (nret) {
    free((*pbuf));
    (*pbuf) = NULL;
    return nret;
  } else {
    if (pbufsize)
      (*pbufsize) = filesize;
    return 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ReadEntireFileSafely>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_GetFileSize@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L37
  mov    %rax,%rdi
  mov    (%rsp),%rax
  xor    %esi,%esi
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  mov    (%rbx),%rdx
  mov    %r12,%rsi
  mov    %rsp,%rcx
  mov    %r13,%rdi
  call   <ReadEntireFile@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L31
  test   %rbp,%rbp
  je     L10
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L31:
  mov    (%rbx),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  jmp    L10
L37:
  mov    $0xffffffff,%r12d
  jmp    L10
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadEntireFileSafely(char *filename, char *mode, char **pbuf, long *pbufsize) {
  long filesize;
  int nret;
  filesize = _GetFileSize(filename);
  (*pbuf) = (char *)malloc(filesize + 1);
  if ((*pbuf) == NULL)
    return -1;
  memset((*pbuf), 0x00, filesize + 1);
  nret = ReadEntireFile(filename, mode, (*pbuf), &filesize);
  if (nret) {
    free((*pbuf));
    (*pbuf) = NULL;
    return nret;
  } else {
    if (pbufsize)
      (*pbufsize) = filesize;
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ReadEntireFileSafely>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_GetFileSize@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,(%rsp)
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L22
  mov    %rax,%rdi
  mov    (%rsp),%rax
  xor    %esi,%esi
  lea    0x1(%rax),%rdx
  call   <memset@plt>
  mov    (%rbx),%rdx
  mov    %r12,%rsi
  mov    %rsp,%rcx
  mov    %r13,%rdi
  call   <ReadEntireFile@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L8
  test   %rbp,%rbp
  je     L23
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L8:
  mov    (%rbx),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  jmp    L23
L22:
  mov    $0xffffffff,%r12d
  jmp    L23
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadEntireFileSafely(char *filename, char *mode, char **pbuf, long *pbufsize) {
  long filesize;
  int nret;
  filesize = _GetFileSize(filename);
  (*pbuf) = (char *)malloc(filesize + 1);
  if ((*pbuf) == NULL)
    return -1;
  memset((*pbuf), 0x00, filesize + 1);
  nret = ReadEntireFile(filename, mode, (*pbuf), &filesize);
  if (nret) {
    free((*pbuf));
    (*pbuf) = NULL;
    return nret;
  } else {
    if (pbufsize)
      (*pbufsize) = filesize;
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tensor_i3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%esi
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    0x10(%rbp),%rdx
  mov    %rax,%rdi
  call   <tensor_mtxv@plt>
  mov    -0x20(%rbp),%edi
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x34(%rbp),%esi
  mov    0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <tensor_mtxv@plt>
  mov    -0x34(%rbp),%edx
  mov    0x18(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <tensor_dot@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double tensor_i3(const double *Jr, unsigned int nr, const double *Js, unsigned int ns, const double *Jt, unsigned int nt, const double *u, double *work) {
  double *work2 = work + nt;
  tensor_mtxv(work2, ns * nt, u, Jr, nr);
  tensor_mtxv(work, nt, work2, Js, ns);
  return tensor_dot(Jt, work, nt);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tensor_i3>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %esi,%edi
  mov    %rdx,%r14
  mov    %ecx,%ebp
  mov    %r8,%r12
  mov    %r9d,%ebx
  mov    0x48(%rsp),%r13
  mov    %r9d,%edx
  lea    0x0(%r13,%rdx,8),%r15
  mov    %r9d,%esi
  imul   %ecx,%esi
  mov    %edi,%r8d
  mov    %rax,%rcx
  mov    0x40(%rsp),%rdx
  mov    %r15,%rdi
  call   <tensor_mtxv@plt>
  mov    %ebp,%r8d
  mov    %r14,%rcx
  mov    %r15,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <tensor_mtxv@plt>
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <tensor_dot@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double tensor_i3(const double *Jr, unsigned int nr, const double *Js, unsigned int ns, const double *Jt, unsigned int nt, const double *u, double *work) {
  double *work2 = work + nt;
  tensor_mtxv(work2, ns * nt, u, Jr, nr);
  tensor_mtxv(work, nt, work2, Js, ns);
  return tensor_dot(Jt, work, nt);
}
```
user: Translate the below assembly code into C programming language:

```asm
<tensor_i3>:
  endbr64
  push   %r15
  mov    %r9d,%eax
  mov    %esi,%r11d
  push   %r14
  mov    %eax,%esi
  mov    %rdx,%r14
  push   %r13
  imul   %ecx,%esi
  push   %r12
  mov    %rax,%r12
  push   %rbp
  mov    %r8,%rbp
  mov    %r11d,%r8d
  push   %rbx
  mov    %ecx,%ebx
  mov    %rdi,%rcx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%r13
  mov    0x40(%rsp),%rdx
  lea    0x0(%r13,%rax,8),%r15
  mov    %r15,%rdi
  call   <tensor_mtxv@plt>
  mov    %r15,%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %ebx,%r8d
  mov    %r14,%rcx
  call   <tensor_mtxv@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %r13,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <tensor_dot@plt>
```

assistant: ```c
double tensor_i3(const double *Jr, unsigned int nr, const double *Js, unsigned int ns, const double *Jt, unsigned int nt, const double *u, double *work) {
  double *work2 = work + nt;
  tensor_mtxv(work2, ns * nt, u, Jr, nr);
  tensor_mtxv(work, nt, work2, Js, ns);
  return tensor_dot(Jt, work, nt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tensor_i3>:
  endbr64
  push   %r15
  mov    %r9d,%eax
  mov    %esi,%r11d
  push   %r14
  mov    %eax,%esi
  mov    %rdx,%r14
  push   %r13
  imul   %ecx,%esi
  push   %r12
  mov    %rax,%r12
  push   %rbp
  mov    %r8,%rbp
  mov    %r11d,%r8d
  push   %rbx
  mov    %ecx,%ebx
  mov    %rdi,%rcx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%r13
  mov    0x40(%rsp),%rdx
  lea    0x0(%r13,%rax,8),%r15
  mov    %r15,%rdi
  call   <tensor_mtxv@plt>
  mov    %r15,%rdx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    %ebx,%r8d
  mov    %r14,%rcx
  call   <tensor_mtxv@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %r13,%rsi
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <tensor_dot@plt>
```

assistant: ```c
double tensor_i3(const double *Jr, unsigned int nr, const double *Js, unsigned int ns, const double *Jt, unsigned int nt, const double *u, double *work) {
  double *work2 = work + nt;
  tensor_mtxv(work2, ns * nt, u, Jr, nr);
  tensor_mtxv(work, nt, work2, Js, ns);
  return tensor_dot(Jt, work, nt);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L67
  mov    $0x1,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L67:
  movl   $0x0,-0x1c(%rbp)
  jmp    L34
L61:
  mov    -0x1c(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  mov    -0x14(%rbp),%edx
  mov    %edx,-0x10(%rbp,%rax,4)
  addl   $0x1,-0x1c(%rbp)
L34:
  cmpl   $0x0,-0x1c(%rbp)
  jle    L61
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x2bbffeea,%eax
  jne    L35
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L35:
  movl   $0x0,-0x18(%rbp)
  jmp    L51
L3:
  mov    -0x18(%rbp),%eax
  cltq
  mov    -0xc(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L51:
  cmpl   $0x0,-0x18(%rbp)
  jle    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D20
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: string

tool: D20: Call this program with %i arguments


tool: D9: You win!

tool: D28: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 734002922U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L11
L5:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <RandomFunc@plt>
  cmpl   $0x2bbffeea,0x4(%rsp)
  je     L0
L43:
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x1,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L5
L0:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  jmp    L43
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string

tool: D7: %u


tool: D17: Call this program with %i arguments


tool: D18: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int input[1];
  unsigned int output[1];
  int randomFuns_i5;
  unsigned int randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned int)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 734002922U) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```