ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<kernel4>:
  endbr64
  mov    %rsi,%rcx
  test   %edi,%edi
  jle    L52
  movslq %edi,%rsi
  lea    (%rcx,%rsi,4),%rax
  lea    (%rdx,%rsi,8),%rsi
  cmp    %rax,%rdx
  setae  %al
  cmp    %rsi,%rcx
  setae  %sil
  or     %sil,%al
  je     L26
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L26
  mov    %edi,%esi
  xor    %eax,%eax
  shr    $0x2,%esi
  shl    $0x4,%rsi
  nopw   0x0(%rax,%rax,1)
L63:
  movups (%rdx,%rax,2),%xmm2
  movups 0x10(%rdx,%rax,2),%xmm7
  movlps 0x8(%rcx,%rax,1),%xmm5
  movaps %xmm2,%xmm1
  shufps $0xdd,%xmm7,%xmm2
  movhlps %xmm2,%xmm4
  cvtps2pd %xmm2,%xmm6
  shufps $0x88,%xmm7,%xmm1
  movhlps %xmm1,%xmm3
  cvtps2pd %xmm1,%xmm0
  cvtps2pd %xmm4,%xmm2
  mulpd  %xmm6,%xmm6
  cvtps2pd %xmm3,%xmm1
  mulpd  %xmm2,%xmm2
  mulpd  %xmm0,%xmm0
  mulpd  %xmm1,%xmm1
  addpd  %xmm6,%xmm0
  cvtps2pd (%rcx,%rax,1),%xmm6
  addpd  %xmm2,%xmm1
  cvtps2pd %xmm5,%xmm2
  addpd  %xmm6,%xmm0
  addpd  %xmm2,%xmm1
  cvtpd2ps %xmm0,%xmm0
  cvtpd2ps %xmm1,%xmm1
  movlhps %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L63
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%r8d
  lea    (%rdx,%r8,8),%rsi
  lea    (%rcx,%r8,4),%rdx
  cmp    %eax,%edi
  je     L52
  pxor   %xmm0,%xmm0
  lea    0x1(%rax),%ecx
  cvtss2sd (%rsi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd (%rdx),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rdx)
  cmp    %ecx,%edi
  jle    L52
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtss2sd 0x8(%rsi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x4(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x4(%rdx)
  cmp    %eax,%edi
  jle    L52
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x14(%rsi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x8(%rdx),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
  xchg   %ax,%ax
L26:
  mov    %edi,%edi
  lea    (%rcx,%rdi,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L67:
  pxor   %xmm0,%xmm0
  add    $0x8,%rdx
  add    $0x4,%rcx
  cvtss2sd -0x8(%rdx),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rdx),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rcx),%xmm1
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rcx)
  cmp    %rcx,%rax
  jne    L67
L52:
  ret
```

assistant: ```c
void kernel4(int L, float *ai, float *ef) {
  float *p2 = ef;
  float *p1 = ai;
  double mag, t;
  int i;
  for (i = 0; i < L; i++) {
    t = *p2++;
    mag = t * t;
    t = *p2++;
    mag += t * t;
    *p1++ += mag;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<SOLVE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L9
L40:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L35:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L35
  addl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L40
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L55
L66:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L46
L44:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L44
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  subl   $0x1,-0x8(%rbp)
L55:
  cmpl   $0x0,-0x8(%rbp)
  jns    L66
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SOLVE(int n, double **A, double *b) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      b[i] -= A[i][j] * b[j];
    }
  }
  for (i = n - 1; i >= 0; i--) {
    for (j = i + 1; j < n; j++) {
      b[i] -= A[i][j] * b[j];
    }
    b[i] /= A[i][i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SOLVE>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rcx
  lea    0x8(%rdx),%rdx
  lea    0x8(%rsi),%r9
  mov    $0x8,%r8d
  mov    $0x0,%r10d
  jmp    L40
L45:
  mov    $0x0,%eax
L88:
  mov    (%r9),%rsi
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  (%rcx,%rax,1),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %r8,%rax
  jne    L88
L82:
  add    $0x8,%rdx
  add    $0x8,%r9
  add    $0x8,%r8
  mov    %r11d,%r10d
L40:
  lea    0x1(%r10),%r11d
  cmp    %r11d,%edi
  je     L48
  test   %r11d,%r11d
  jg     L45
  jmp    L82
L48:
  movslq %r10d,%r11
  add    $0x1,%r10d
  lea    0x0(,%r11,8),%r8
  lea    (%rcx,%r8,1),%rdx
  add    %rbx,%r8
  lea    -0x2(%rdi),%ebx
L17:
  cmp    %r10d,%edi
  jle    L5
  movslq %r10d,%rax
  shl    $0x3,%rax
  mov    %ebx,%esi
  sub    %r11d,%esi
  lea    0x2(%r11,%rsi,1),%r9
  shl    $0x3,%r9
L23:
  mov    (%r8),%rsi
  movsd  (%rsi,%rax,1),%xmm1
  mulsd  (%rcx,%rax,1),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  cmp    %rax,%r9
  jne    L23
L5:
  mov    (%r8),%rax
  movsd  (%rdx),%xmm0
  divsd  (%rax,%r11,8),%xmm0
  movsd  %xmm0,(%rdx)
  sub    $0x1,%r11
  sub    $0x1,%r10d
  sub    $0x8,%rdx
  sub    $0x8,%r8
  test   %r11d,%r11d
  jns    L17
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void SOLVE(int n, double **A, double *b) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      b[i] -= A[i][j] * b[j];
    }
  }
  for (i = n - 1; i >= 0; i--) {
    for (j = i + 1; j < n; j++) {
      b[i] -= A[i][j] * b[j];
    }
    b[i] /= A[i][i];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<SOLVE>:
  endbr64
  mov    %rsi,%r9
  lea    -0x1(%rdi),%r10d
  test   %edi,%edi
  jle    L55
  xor    %r11d,%r11d
  lea    0x8(%rdx),%rsi
  mov    $0x8,%ecx
  add    $0x1,%r11d
  cmp    %r11d,%edi
  je     L59
  nopl   0x0(%rax,%rax,1)
L17:
  mov    (%r9,%rcx,1),%r8
  movsd  (%rsi),%xmm1
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L45:
  movsd  (%r8,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%rcx
  jne    L45
  add    $0x1,%r11d
  add    $0x8,%rsi
  add    $0x8,%rcx
  cmp    %r11d,%edi
  jne    L17
L59:
  movslq %r10d,%r10
  mov    %edi,%r8d
  shl    $0x3,%r10
  lea    (%rdx,%r10,1),%rcx
  nopl   0x0(%rax,%rax,1)
L64:
  mov    (%r9,%r10,1),%rsi
  movsd  (%rcx),%xmm1
  cmp    %r8d,%edi
  jle    L49
  movslq %r8d,%rax
L41:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %eax,%edi
  jg     L41
L49:
  divsd  (%rsi,%r10,1),%xmm1
  sub    $0x8,%rcx
  movsd  %xmm1,0x8(%rcx)
  lea    -0x1(%r8),%eax
  sub    $0x8,%r10
  sub    $0x2,%r8d
  js     L70
  mov    %eax,%r8d
  jmp    L64
L55:
  test   %r10d,%r10d
  jns    L59
L70:
  ret
```

assistant: ```c
void SOLVE(int n, double **A, double *b) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      b[i] -= A[i][j] * b[j];
    }
  }
  for (i = n - 1; i >= 0; i--) {
    for (j = i + 1; j < n; j++) {
      b[i] -= A[i][j] * b[j];
    }
    b[i] /= A[i][i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SOLVE>:
  endbr64
  mov    %rsi,%r9
  lea    -0x1(%rdi),%r10d
  test   %edi,%edi
  jle    L26
  lea    0x8(%rdx),%rsi
  mov    $0x8,%ecx
  mov    $0x1,%r11d
  cmp    $0x1,%edi
  je     L82
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%r9,%rcx,1),%r8
  movsd  (%rsi),%xmm1
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L60:
  movsd  (%r8,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  add    $0x8,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi)
  cmp    %rax,%rcx
  jne    L60
  add    $0x1,%r11d
  add    $0x8,%rsi
  add    $0x8,%rcx
  cmp    %r11d,%edi
  jne    L15
L82:
  movslq %r10d,%r10
  mov    %edi,%r8d
  shl    $0x3,%r10
  lea    (%rdx,%r10,1),%rcx
  nopl   0x0(%rax,%rax,1)
L77:
  mov    (%r9,%r10,1),%rsi
  movsd  (%rcx),%xmm1
  cmp    %r8d,%edi
  jle    L61
  movslq %r8d,%rax
L41:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %eax,%edi
  jg     L41
L61:
  divsd  (%rsi,%r10,1),%xmm1
  sub    $0x8,%rcx
  movsd  %xmm1,0x8(%rcx)
  lea    -0x1(%r8),%eax
  sub    $0x8,%r10
  sub    $0x2,%r8d
  js     L5
  mov    %eax,%r8d
  jmp    L77
L26:
  test   %r10d,%r10d
  jns    L82
L5:
  ret
```

assistant: ```c
void SOLVE(int n, double **A, double *b) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++) {
      b[i] -= A[i][j] * b[j];
    }
  }
  for (i = n - 1; i >= 0; i--) {
    for (j = i + 1; j < n; j++) {
      b[i] -= A[i][j] * b[j];
    }
    b[i] /= A[i][i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0xa,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main(void) {
  int t[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p = t + 4;
  p += *p;
  printf("%d", *p);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main(void) {
  int t[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p = t + 4;
  p += *p;
  printf("%d", *p);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: %d

assistant: ```c
int main(void) {
  int t[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p = t + 4;
  p += *p;
  printf("%d", *p);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7: %d

assistant: ```c
int main(void) {
  int t[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, *p = t + 4;
  p += *p;
  printf("%d", *p);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str2html>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L121
L136:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x1f,%al
  jg     L83
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x8(%rbp),%rax
  lea    D39(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L166
L83:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3e,%eax
  je     L40
  cmp    $0x3e,%eax
  jg     L36
  cmp    $0x3c,%eax
  je     L161
  cmp    $0x3c,%eax
  jg     L36
  cmp    $0x22,%eax
  je     L111
  cmp    $0x26,%eax
  je     L98
  jmp    L36
L111:
  mov    -0x8(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L150
L98:
  mov    -0x8(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L150
L161:
  mov    -0x8(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L150
L40:
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L150
L36:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L52
L150:
  jmp    L166
L15:
  addq   $0x1,-0x8(%rbp)
L166:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
L52:
  addq   $0x1,-0x18(%rbp)
L121:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L136
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D42(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D39
type_guessed: string
name: retrieve_data
arguments: data_tag: D8
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string
name: retrieve_data
arguments: data_tag: D36
type_guessed: string
name: retrieve_data
arguments: data_tag: D7
type_guessed: string

tool: D39: &#%d;

tool: D8: &quot;

tool: D10: &amp;

tool: D36: &lt;

tool: D7: &gt;

assistant: ```c
char *str2html(const char *src) {
  static char buf[2048];
  char *dst;
  for (dst = buf; *src; ++src) {
    if (*src < ' ') {
      sprintf(dst, "&#%d;", *src);
    } else
      switch (*src) {
      case '"':
        sprintf(dst, "&quot;");
        break;
      case '&':
        sprintf(dst, "&amp;");
        break;
      case '<':
        sprintf(dst, "&lt;");
        break;
      case '>':
        sprintf(dst, "&gt;");
        break;
      default:
        *dst++ = *src;
        continue;
      }
    while (*dst)
      ++dst;
  }
  *dst = '\0';
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str2html>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%edx
  lea    D27(%rip),%rbx
  test   %dl,%dl
  je     L60
  mov    %rdi,%rbp
  lea    D11(%rip),%r12
  jmp    L154
L8:
  movsbl %dl,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L12
L17:
  cmp    $0x3e,%dl
  jne    L2
  movl   $0x3b746726,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L12
L99:
  movl   $0x6f757126,(%rbx)
  movw   $0x3b74,0x4(%rbx)
  movb   $0x0,0x6(%rbx)
L12:
  cmpb   $0x0,(%rbx)
  je     L49
L114:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L114
L49:
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L60
L154:
  cmp    $0x1f,%dl
  jle    L8
  cmp    $0x3c,%dl
  je     L64
  jg     L17
  cmp    $0x22,%dl
  je     L99
  cmp    $0x26,%dl
  jne    L2
  movl   $0x706d6126,(%rbx)
  movw   $0x3b,0x4(%rbx)
  jmp    L12
L64:
  movl   $0x3b746c26,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L12
L2:
  mov    %dl,(%rbx)
  lea    0x1(%rbx),%rbx
  jmp    L49
L60:
  movb   $0x0,(%rbx)
  lea    D27(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: string

tool: D11: &#%d;

assistant: ```c
char *str2html(const char *src) {
  static char buf[2048];
  char *dst;
  for (dst = buf; *src; ++src) {
    if (*src < ' ') {
      sprintf(dst, "&#%d;", *src);
    } else
      switch (*src) {
      case '"':
        sprintf(dst, "&quot;");
        break;
      case '&':
        sprintf(dst, "&amp;");
        break;
      case '<':
        sprintf(dst, "&lt;");
        break;
      case '>':
        sprintf(dst, "&gt;");
        break;
      default:
        *dst++ = *src;
        continue;
      }
    while (*dst)
      ++dst;
  }
  *dst = '\0';
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str2html>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L115
  lea    D14(%rip),%r12
  mov    %rdi,%rbp
  lea    D12(%rip),%r13
  mov    %r12,%rbx
  nopl   (%rax)
L118:
  cmp    $0x1f,%dl
  jle    L82
  cmp    $0x3c,%dl
  je     L99
  jg     L36
  cmp    $0x22,%dl
  je     L27
  cmp    $0x26,%dl
  jne    L146
  mov    $0x3b,%eax
  movl   $0x706d6126,(%rbx)
  mov    %ax,0x4(%rbx)
  jmp    L57
  nop
L91:
  add    $0x1,%rbx
L57:
  cmpb   $0x0,(%rbx)
  jne    L91
  movsbl 0x1(%rbp),%edx
  add    $0x1,%rbp
  test   %dl,%dl
  jne    L118
L31:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  cmp    $0x3e,%dl
  jne    L146
  movl   $0x3b746726,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L57
  nopl   0x0(%rax)
L146:
  add    $0x1,%rbp
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  jne    L118
  jmp    L31
L27:
  mov    $0x3b74,%edx
  movl   $0x6f757126,(%rbx)
  mov    %dx,0x4(%rbx)
  movb   $0x0,0x6(%rbx)
  jmp    L57
  nopl   (%rax)
L99:
  movl   $0x3b746c26,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L57
  nopl   0x0(%rax)
L82:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L57
L115:
  lea    D14(%rip),%r12
  mov    %r12,%rbx
  jmp    L31
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string

tool: D12: &#%d;

assistant: ```c
char *str2html(const char *src) {
  static char buf[2048];
  char *dst;
  for (dst = buf; *src; ++src) {
    if (*src < ' ') {
      sprintf(dst, "&#%d;", *src);
    } else
      switch (*src) {
      case '"':
        sprintf(dst, "&quot;");
        break;
      case '&':
        sprintf(dst, "&amp;");
        break;
      case '<':
        sprintf(dst, "&lt;");
        break;
      case '>':
        sprintf(dst, "&gt;");
        break;
      default:
        *dst++ = *src;
        continue;
      }
    while (*dst)
      ++dst;
  }
  *dst = '\0';
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<str2html>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L123
  lea    D8(%rip),%r12
  mov    %rdi,%rbp
  lea    D16(%rip),%r13
  mov    %r12,%rbx
  nopl   (%rax)
L22:
  cmp    $0x1f,%dl
  jle    L106
  cmp    $0x3c,%dl
  je     L144
  jg     L126
  cmp    $0x22,%dl
  je     L90
  cmp    $0x26,%dl
  jne    L86
  mov    $0x3b,%eax
  movl   $0x706d6126,(%rbx)
  mov    %ax,0x4(%rbx)
  jmp    L18
  nop
L117:
  add    $0x1,%rbx
L18:
  cmpb   $0x0,(%rbx)
  jne    L117
  movsbl 0x1(%rbp),%edx
  add    $0x1,%rbp
  test   %dl,%dl
  jne    L22
L5:
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L126:
  cmp    $0x3e,%dl
  jne    L86
  movl   $0x3b746726,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L18
  nopl   0x0(%rax)
L86:
  add    $0x1,%rbp
  mov    %dl,(%rbx)
  add    $0x1,%rbx
  movsbl 0x0(%rbp),%edx
  test   %dl,%dl
  jne    L22
  jmp    L5
L90:
  mov    $0x3b74,%edx
  movl   $0x6f757126,(%rbx)
  mov    %dx,0x4(%rbx)
  movb   $0x0,0x6(%rbx)
  jmp    L18
  nopl   (%rax)
L144:
  movl   $0x3b746c26,(%rbx)
  movb   $0x0,0x4(%rbx)
  jmp    L18
  nopl   0x0(%rax)
L106:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  jmp    L18
L123:
  lea    D8(%rip),%r12
  mov    %r12,%rbx
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string

tool: D16: &#%d;

assistant: ```c
char *str2html(const char *src) {
  static char buf[2048];
  char *dst;
  for (dst = buf; *src; ++src) {
    if (*src < ' ') {
      sprintf(dst, "&#%d;", *src);
    } else
      switch (*src) {
      case '"':
        sprintf(dst, "&quot;");
        break;
      case '&':
        sprintf(dst, "&amp;");
        break;
      case '<':
        sprintf(dst, "&lt;");
        break;
      case '>':
        sprintf(dst, "&gt;");
        break;
      default:
        *dst++ = *src;
        continue;
      }
    while (*dst)
      ++dst;
  }
  *dst = '\0';
  return buf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jpip_read_cptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    %eax,-0x18(%rbp)
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x8,%edi
  call   <cio_read@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x8,%edi
  call   <cio_read@plt>
  mov    %rax,-0x8(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void jpip_read_cptr() {
  int DR, CONT;
  long long Coff, codestream_size;
  DR = cio_read(2);
  CONT = cio_read(2);
  Coff = cio_read(8);
  codestream_size = cio_read(8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<jpip_read_cptr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    $0x8,%edi
  call   <cio_read@plt>
  mov    $0x8,%edi
  call   <cio_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void jpip_read_cptr() {
  int DR, CONT;
  long long Coff, codestream_size;
  DR = cio_read(2);
  CONT = cio_read(2);
  Coff = cio_read(8);
  codestream_size = cio_read(8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<jpip_read_cptr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    $0x8,%edi
  call   <cio_read@plt>
  mov    $0x8,%edi
  add    $0x8,%rsp
  jmp    1050 <cio_read@plt>
```

assistant: ```c
void jpip_read_cptr() {
  int DR, CONT;
  long long Coff, codestream_size;
  DR = cio_read(2);
  CONT = cio_read(2);
  Coff = cio_read(8);
  codestream_size = cio_read(8);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jpip_read_cptr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    $0x2,%edi
  call   <cio_read@plt>
  mov    $0x8,%edi
  call   <cio_read@plt>
  mov    $0x8,%edi
  add    $0x8,%rsp
  jmp    1050 <cio_read@plt>
```

assistant: ```c
void jpip_read_cptr() {
  int DR, CONT;
  long long Coff, codestream_size;
  DR = cio_read(2);
  CONT = cio_read(2);
  Coff = cio_read(8);
  codestream_size = cio_read(8);
}
```