ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_multiplier>:
  endbr64
  test   %rdi,%rdi
  je     L37
  push   %rbp
  movzbl (%rdi),%eax
  mov    %rdi,%rbp
  cmp    $0x20,%al
  jne    L10
  nopl   0x0(%rax)
L3:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  cmp    $0x20,%al
  je     L3
L10:
  cmp    $0x9,%al
  je     L3
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x400,%eax
  test   %r8d,%r8d
  je     L55
  lea    D10(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x100000,%eax
  test   %r8d,%r8d
  je     L55
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x40000001,%eax
  sub    $0x1,%eax
L55:
  pop    %rbp
  ret
  xchg   %ax,%ax
L37:
  mov    $0x1,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D4: KiB

tool: D10: MiB

tool: D5: GiB

assistant: ```c
int get_multiplier(const char *str) {
  if (!str)
    return 1;
  while (*str == ' ' || *str == '\t')
    str += 1;
  if (!strcmp(str, "KiB"))
    return 1024;
  if (!strcmp(str, "MiB"))
    return 1024 * 1024;
  if (!strcmp(str, "GiB"))
    return 1024 * 1024 * 1024;
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_multiplier>:
  endbr64
  test   %rdi,%rdi
  je     L14
  push   %rbp
  movzbl (%rdi),%eax
  mov    %rdi,%rbp
  cmp    $0x20,%al
  jne    L12
  nopl   0x0(%rax)
L21:
  movzbl 0x1(%rbp),%eax
  add    $0x1,%rbp
  cmp    $0x20,%al
  je     L21
L12:
  cmp    $0x9,%al
  je     L21
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x400,%eax
  test   %r8d,%r8d
  je     L30
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x100000,%eax
  test   %r8d,%r8d
  je     L30
  lea    D23(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x40000001,%eax
  sub    $0x1,%eax
L30:
  pop    %rbp
  ret
  xchg   %ax,%ax
L14:
  mov    $0x1,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D4
type: string
name: unpack_data
arguments: label: D23
type: string

tool: D9: KiB

tool: D4: MiB

tool: D23: GiB

assistant: ```c
int get_multiplier(const char *str) {
  if (!str)
    return 1;
  while (*str == ' ' || *str == '\t')
    str += 1;
  if (!strcmp(str, "KiB"))
    return 1024;
  if (!strcmp(str, "MiB"))
    return 1024 * 1024;
  if (!strcmp(str, "GiB"))
    return 1024 * 1024 * 1024;
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<snprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %esi,-0xcc(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xcc(%rbp),%esi
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int snprintf(char *s, int size, const char *fmt, ...) {
  va_list args;
  int err;
  va_start(args, fmt);
  err = vsnprintf(s, size, fmt, args);
  va_end(args);
  return err;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<snprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int snprintf(char *s, int size, const char *fmt, ...) {
  va_list args;
  int err;
  va_start(args, fmt);
  err = vsnprintf(s, size, fmt, args);
  va_end(args);
  return err;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int snprintf(char *s, int size, const char *fmt, ...) {
  va_list args;
  int err;
  va_start(args, fmt);
  err = vsnprintf(s, size, fmt, args);
  va_end(args);
  return err;
}
```
user: Translate the below assembly code into C programming language:

```asm
<snprintf>:
  endbr64
  push   %r14
  mov    %esi,%r14d
  mov    %rdx,%rsi
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int snprintf(char *s, int size, const char *fmt, ...) {
  va_list args;
  int err;
  va_start(args, fmt);
  err = vsnprintf(s, size, fmt, args);
  va_end(args);
  return err;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<serverReceive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <serverReceiveNet@plt>
  mov    $0x0,%eax
  call   <serverReceiveLocal@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int serverReceive() {
  serverReceiveNet();
  serverReceiveLocal();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serverReceive>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <serverReceiveNet@plt>
  mov    $0x0,%eax
  call   <serverReceiveLocal@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int serverReceive() {
  serverReceiveNet();
  serverReceiveLocal();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<serverReceive>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <serverReceiveNet@plt>
  xor    %eax,%eax
  call   <serverReceiveLocal@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int serverReceive() {
  serverReceiveNet();
  serverReceiveLocal();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<concatenate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <Malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *concatenate(char *a, char *b) {
  char *base;
  base = (char *)Malloc(strlen(a) + strlen(b) + 1);
  strcpy(base, a);
  strcat(base, b);
  return base;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<concatenate>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%rdi
  call   <Malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *concatenate(char *a, char *b) {
  char *base;
  base = (char *)Malloc(strlen(a) + strlen(b) + 1);
  strcpy(base, a);
  strcat(base, b);
  return base;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<concatenate>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <Malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *concatenate(char *a, char *b) {
  char *base;
  base = (char *)Malloc(strlen(a) + strlen(b) + 1);
  strcpy(base, a);
  strcat(base, b);
  return base;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<concatenate>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%rdi
  call   <Malloc@plt>
  mov    %r13,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *concatenate(char *a, char *b) {
  char *base;
  base = (char *)Malloc(strlen(a) + strlen(b) + 1);
  strcpy(base, a);
  strcat(base, b);
  return base;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: %d	 

assistant: ```c
void print_array(int array[], int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("%d\t ", array[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L15
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D6(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D6
data_type: string

tool: D6: %d	 

assistant: ```c
void print_array(int array[], int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("%d\t ", array[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L13:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L13
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string

tool: D9: %d	 

assistant: ```c
void print_array(int array[], int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("%d\t ", array[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_array>:
  endbr64
  test   %esi,%esi
  jle    L7
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_guessed: string

tool: D0: %d	 

assistant: ```c
void print_array(int array[], int count) {
  int i = 0;
  for (i = 0; i < count; i++) {
    printf("%d\t ", array[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<listsubsets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L68
L4:
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L53
L32:
  lea    -0x22(%rbp),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x48(%rbp),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x22(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x30(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,-0x22(%rbp,%rax,1)
  lea    -0x22(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movb   $0x0,-0x22(%rbp,%rax,1)
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x30(%rbp),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <listsubsets>
  jmp    L46
L2:
  mov    -0x30(%rbp),%rax
  lea    0x1(%rax),%rdx
  lea    -0x22(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <listsubsets>
L46:
  addl   $0x1,-0x34(%rbp)
  addq   $0x1,-0x30(%rbp)
L53:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jbe    L32
L68:
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: {%s}


assistant: ```c
void listsubsets(char *element, char *subset) {
  if (*subset == 0) {
    printf("{%s}\n", element);
  } else {
    int i;
    char *tmpset = subset;
    for (i = 0; i <= strlen(subset); i++, tmpset++) {
      char buf[10];
      memset(buf, 0, 10);
      strcpy(buf, element);
      buf[strlen(buf)] = *tmpset;
      buf[strlen(buf)] = 0;
      if (*tmpset == 0) {
        listsubsets(buf, tmpset);
      } else {
        listsubsets(buf, tmpset + 1);
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<listsubsets>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsi,%rbp
  lea    0xe(%rsp),%rbx
  cmpb   $0x0,(%rsi)
  jne    L45
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  lea    0x1(%rbp),%rsi
  mov    %rbx,%rdi
  call   <listsubsets>
L5:
  add    $0x1,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbp,%rax
  sub    %r12,%rax
  cmp    %rax,%rdx
  jb     L14
L45:
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movzbl 0x0(%rbp),%r13d
  mov    %r13b,0xe(%rsp,%rax,1)
  mov    %rbx,%rdi
  call   <strlen@plt>
  movb   $0x0,0xe(%rsp,%rax,1)
  test   %r13b,%r13b
  jne    L3
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <listsubsets>
  jmp    L5
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: {%s}


assistant: ```c
void listsubsets(char *element, char *subset) {
  if (*subset == 0) {
    printf("{%s}\n", element);
  } else {
    int i;
    char *tmpset = subset;
    for (i = 0; i <= strlen(subset); i++, tmpset++) {
      char buf[10];
      memset(buf, 0, 10);
      strcpy(buf, element);
      buf[strlen(buf)] = *tmpset;
      buf[strlen(buf)] = 0;
      if (*tmpset == 0) {
        listsubsets(buf, tmpset);
      } else {
        listsubsets(buf, tmpset + 1);
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<listsubsets>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  je     L16
  mov    %rsi,%r12
  mov    %rsi,%rbx
  lea    0xe(%rsp),%rbp
L49:
  mov    $0xa,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  movzbl (%rbx),%r13d
  mov    %rbp,%rdi
  mov    %r13b,0xe(%rsp,%rax,1)
  call   <strlen@plt>
  mov    %rbx,%rsi
  add    $0x1,%rbx
  movb   $0x0,0xe(%rsp,%rax,1)
  test   %r13b,%r13b
  je     L39
  mov    %rbx,%rsi
L39:
  mov    %rbp,%rdi
  call   <listsubsets>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r8
  mov    %rbx,%rax
  sub    %r12,%rax
  cmp    %rax,%r8
  jae    L49
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L16:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x20,%rsp
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <printf@plt>
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: {%s}


assistant: ```c
void listsubsets(char *element, char *subset) {
  if (*subset == 0) {
    printf("{%s}\n", element);
  } else {
    int i;
    char *tmpset = subset;
    for (i = 0; i <= strlen(subset); i++, tmpset++) {
      char buf[10];
      memset(buf, 0, 10);
      strcpy(buf, element);
      buf[strlen(buf)] = *tmpset;
      buf[strlen(buf)] = 0;
      if (*tmpset == 0) {
        listsubsets(buf, tmpset);
      } else {
        listsubsets(buf, tmpset + 1);
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<listsubsets>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rsi)
  je     L51
  mov    %rsi,%rbp
  mov    %rsi,%r12
  lea    0xe(%rsp),%rbx
L26:
  mov    $0xa,%edx
  xor    %esi,%esi
  lea    0x1(%r12),%r13
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  movzbl (%r12),%r14d
  mov    %rbx,%rdi
  mov    %r14b,0xe(%rsp,%rax,1)
  call   <strlen@plt>
  mov    %r12,%rsi
  movb   $0x0,0xe(%rsp,%rax,1)
  test   %r14b,%r14b
  je     L15
  mov    %r13,%rsi
L15:
  mov    %rbx,%rdi
  call   <listsubsets>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%r8
  mov    %r13,%rax
  sub    %rbp,%rax
  cmp    %rax,%r8
  jb     L14
  mov    %r13,%r12
  jmp    L26
  nopl   (%rax)
L14:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10c0 <printf@plt>
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: {%s}


assistant: ```c
void listsubsets(char *element, char *subset) {
  if (*subset == 0) {
    printf("{%s}\n", element);
  } else {
    int i;
    char *tmpset = subset;
    for (i = 0; i <= strlen(subset); i++, tmpset++) {
      char buf[10];
      memset(buf, 0, 10);
      strcpy(buf, element);
      buf[strlen(buf)] = *tmpset;
      buf[strlen(buf)] = 0;
      if (*tmpset == 0) {
        listsubsets(buf, tmpset);
      } else {
        listsubsets(buf, tmpset + 1);
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1a8(%rbp)
  jmp    L48
L65:
  mov    -0x1a8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    -0x1a0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L38
  mov    -0x1a8(%rbp),%eax
  mov    %eax,-0x1a4(%rbp)
  jmp    L12
L27:
  subl   $0x1,-0x1a4(%rbp)
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  cmpl   $0x0,-0x1a4(%rbp)
  jg     L27
  mov    $0x0,%eax
  jmp    L53
L38:
  addl   $0x1,-0x1a8(%rbp)
L48:
  cmpl   $0x63,-0x1a8(%rbp)
  jle    L65
  mov    $0x0,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D9
type: string

tool: D11: %d

tool: D9: %d 

assistant: ```c
int main() {
  int a[100], i, j;
  for (i = 0; i < 100; i++)
    if (scanf("%d", a + i), !a[i]) {
      for (j = i; j > 0; printf("%d ", a[--j]))
        ;
      return 0;
    }
}
```