user: 请从给定的汇编指令推导出C源代码：

```asm
<loadStackAddressOf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x5b,%esi
  mov    %rbx,%rdi
  call   <contentToOperator@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jne    L55
L51:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  je     L51
L55:
  cmp    $0x5b,%al
  je     L49
  mov    %r12,%rdi
  call   <stackAddressOfVar@plt>
  mov    %eax,%ebx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x18,%eax
  lea    (%rbx,%rax,1),%edx
  movzbl %dl,%edx
  sub    %eax,%edx
  mov    %rsp,%r13
  lea    D21(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  lea    0xff(%rbx),%edx
  test   %ebx,%ebx
  cmovns %ebx,%edx
  sar    $0x8,%edx
  lea    D22(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  jmp    L1
L49:
  add    $0x1,%rdi
  mov    $0x5d,%edx
  mov    $0x5b,%esi
  call   <closureContent@plt>
  mov    %rax,%r13
  mov    %r12,%rdi
  call   <stackAddressOfVar@plt>
  mov    %eax,%ebx
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  mov    %ebx,%eax
  sar    $0x1f,%eax
  shr    $0x18,%eax
  lea    (%rbx,%rax,1),%edx
  movzbl %dl,%edx
  sub    %eax,%edx
  mov    %rsp,%r14
  lea    D21(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  lea    0xff(%rbx),%edx
  test   %ebx,%ebx
  cmovns %ebx,%edx
  sar    $0x8,%edx
  lea    D22(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  test   %r13,%r13
  je     L1
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <pemdas@plt>
  mov    $0x10,%esi
  mov    %rbp,%rdi
  call   <stackPop@plt>
  lea    D54(%rip),%rsi
  mov    %rbp,%rdi
  call   <writeAsmBlock@plt>
  mov    %r13,%rdi
  call   <free@plt>
L1:
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D7
data_type: string
name: unpack_data
arguments: tag: D21
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D54
data_type: string

tool: D7: mov yh, xh
mov yl, xl


tool: D21: ldi r16, %i
sub yl, r16

tool: D22: ldi r16, %i
sbc yl, r16

tool: D54: add yl, r16
ldi r16, 0
adc yh, r16


assistant: ```c
void loadStackAddressOf(FILE *execfile, char *var) {
  char *name = contentToOperator(var, '[', '\0', '\0');
  char *tmp = &var[strlen(name)];
  while (*tmp == ' ')
    tmp = &tmp[1];
  char *arrIndex = NULL;
  if (*tmp == '[')
    arrIndex = closureContent(&tmp[1], '[', ']');
  int stkptr = stackAddressOfVar(name);
  writeAsmBlock(execfile, "mov yh, xh\nmov yl, xl\n");
  char buffer[64];
  sprintf(buffer, "ldi r16, %i\nsub yl, r16", stkptr % 256);
  writeAsmBlock(execfile, buffer);
  sprintf(buffer, "ldi r16, %i\nsbc yl, r16", stkptr / 256);
  writeAsmBlock(execfile, buffer);
  if (arrIndex) {
    pemdas(execfile, arrIndex, 1);
    stackPop(execfile, 16);
    writeAsmBlock(execfile, "add yl, r16\nldi r16, 0\nadc yh, r16\n");
    free(arrIndex);
  }
  free(name);
}
```