ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<f2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3da000(%rsp),%r11
L25:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L25
  sub    $0x550,%rsp
  mov    $0x9c40,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3da548(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x9c40(%rsp),%rbx
  lea    0x3da540(%rsp),%r12
  mov    %rbp,%rdi
  call   <memset@plt>
  nopl   (%rax)
L17:
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <add_mat@plt>
  add    $0x9c40,%rbx
  cmp    %r12,%rbx
  jne    L17
  mov    0x3da548(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x3da550,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f2(void) {
  float array_of_mat[(100)][(100)][(100)];
  float mat_sum[(100)][(100)];
  memset(mat_sum, 0, sizeof(mat_sum));
  int i;
#pragma omp parallel for reduction(add_mat : mat_sum)
  for (i = 0; i < (100); i++) {
    add_mat((100), (100), &mat_sum[0][0], &array_of_mat[i][0][0]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x3da000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0x550,%rsp
  mov    $0x9c40,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x3da548(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x9c40(%rsp),%rbx
  lea    0x3da540(%rsp),%r12
  mov    %rbp,%rdi
  call   <memset@plt>
  nopl   (%rax)
L23:
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    $0x64,%esi
  mov    $0x64,%edi
  call   <add_mat@plt>
  add    $0x9c40,%rbx
  cmp    %r12,%rbx
  jne    L23
  mov    0x3da548(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3da550,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void f2(void) {
  float array_of_mat[(100)][(100)][(100)];
  float mat_sum[(100)][(100)];
  memset(mat_sum, 0, sizeof(mat_sum));
  int i;
#pragma omp parallel for reduction(add_mat : mat_sum)
  for (i = 0; i < (100); i++) {
    add_mat((100), (100), &mat_sum[0][0], &array_of_mat[i][0][0]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L31
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L56
L31:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x62,%eax
  cmp    $0x12,%eax
  ja     L28
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <certify@plt>
  jmp    L28
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <encrypt@plt>
  jmp    L28
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decrypt@plt>
  jmp    L28
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <bernstein@plt>
  jmp    L28
  mov    $0x0,%eax
  call   <tables@plt>
  nop
L28:
  mov    $0x0,%eax
L56:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D20
type: string

tool: D20: aescoder [cedbt]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("aescoder [cedbt]\n");
    return 0;
  }
  switch (argv[1][0]) {
  case 'c':
    certify();
    break;
  case 'e':
    encrypt(argv[2], argv[3]);
    break;
  case 'd':
    decrypt(argv[2], argv[3]);
    break;
  case 'b':
    bernstein(argv[2]);
    break;
  case 't':
    tables();
    break;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L52
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  sub    $0x62,%eax
  cmp    $0x12,%al
  ja     L45
  movzbl %al,%eax
  lea    D0(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L52:
  lea    D8(%rip),%rdi
  call   <printf@plt>
L45:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
  mov    $0x0,%eax
  call   <certify@plt>
  jmp    L45
  mov    0x18(%rsi),%rax
  mov    0x10(%rsi),%rdi
  mov    %rax,%rsi
  call   <encrypt@plt>
  jmp    L45
  mov    0x18(%rsi),%rax
  mov    0x10(%rsi),%rdi
  mov    %rax,%rsi
  call   <decrypt@plt>
  jmp    L45
  mov    0x10(%rsi),%rdi
  call   <bernstein@plt>
  jmp    L45
  mov    $0x0,%eax
  call   <tables@plt>
  jmp    L45
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: aescoder [cedbt]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("aescoder [cedbt]\n");
    return 0;
  }
  switch (argv[1][0]) {
  case 'c':
    certify();
    break;
  case 'e':
    encrypt(argv[2], argv[3]);
    break;
  case 'd':
    decrypt(argv[2], argv[3]);
    break;
  case 'b':
    bernstein(argv[2]);
    break;
  case 't':
    tables();
    break;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L56
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  sub    $0x62,%eax
  cmp    $0x12,%al
  ja     L2
  lea    D0(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L56:
  lea    D19(%rip),%rdi
  call   <printf@plt>
L2:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xor    %eax,%eax
  call   <tables@plt>
  jmp    L2
  mov    0x10(%rsi),%rdi
  call   <bernstein@plt>
  jmp    L2
  xor    %eax,%eax
  call   <certify@plt>
  jmp    L2
  mov    0x18(%rsi),%r8
  mov    0x10(%rsi),%rdi
  mov    %r8,%rsi
  call   <decrypt@plt>
  jmp    L2
  mov    0x18(%rsi),%r8
  mov    0x10(%rsi),%rdi
  mov    %r8,%rsi
  call   <encrypt@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: string

tool: D19: aescoder [cedbt]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("aescoder [cedbt]\n");
    return 0;
  }
  switch (argv[1][0]) {
  case 'c':
    certify();
    break;
  case 'e':
    encrypt(argv[2], argv[3]);
    break;
  case 'd':
    decrypt(argv[2], argv[3]);
    break;
  case 'b':
    bernstein(argv[2]);
    break;
  case 't':
    tables();
    break;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L7
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  sub    $0x62,%eax
  cmp    $0x12,%al
  ja     L43
  lea    D13(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L7:
  lea    D9(%rip),%rdi
  call   <printf@plt>
L43:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  xor    %eax,%eax
  call   <tables@plt>
  jmp    L43
  mov    0x10(%rsi),%rdi
  call   <bernstein@plt>
  jmp    L43
  xor    %eax,%eax
  call   <certify@plt>
  jmp    L43
  mov    0x18(%rsi),%r8
  mov    0x10(%rsi),%rdi
  mov    %r8,%rsi
  call   <decrypt@plt>
  jmp    L43
  mov    0x18(%rsi),%r8
  mov    0x10(%rsi),%rdi
  mov    %r8,%rsi
  call   <encrypt@plt>
  jmp    L43
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: D9: aescoder [cedbt]


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    printf("aescoder [cedbt]\n");
    return 0;
  }
  switch (argv[1][0]) {
  case 'c':
    certify();
    break;
  case 'e':
    encrypt(argv[2], argv[3]);
    break;
  case 'd':
    decrypt(argv[2], argv[3]);
    break;
  case 'b':
    bernstein(argv[2]);
    break;
  case 't':
    tables();
    break;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  test   %eax,%eax
  jne    L55
  mov    -0x18(%rbp),%rax
  jmp    L4
L55:
  movl   $0x0,-0x8(%rbp)
  jmp    L90
L35:
  movl   $0x0,-0x4(%rbp)
  jmp    L98
L96:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    -0x4(%rbp),%edx
  add    $0x1,%edx
  cmp    %edx,%eax
  jne    L15
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L4
L15:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L98:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L39
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L39
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L96
L39:
  addl   $0x1,-0x8(%rbp)
L90:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int ii;
  if (!my_strlen(to_find))
    return (str);
  for (i = 0; str[i]; i++) {
    for (ii = 0; to_find[ii] == str[i] && to_find[ii] && str[i]; ii++, i++) {
      if (my_strlen(to_find) == (ii + 1))
        return (&str[i - ii]);
    }
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <my_strlen@plt>
  mov    %eax,%edx
  mov    %r14,%rax
  test   %edx,%edx
  je     L53
  mov    $0x0,%ebp
  mov    $0x0,%eax
  cmpb   $0x0,(%r14)
  jne    L74
  jmp    L53
L20:
  sub    %r15d,%ebp
  movslq %ebp,%rax
  add    %r14,%rax
L53:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L61:
  add    $0x1,%ebp
  movslq %ebp,%rax
  cmpb   $0x0,(%r14,%rax,1)
  je     L55
L74:
  movzbl (%r12),%edx
  movslq %ebp,%r13
  add    %r14,%r13
  movzbl 0x0(%r13),%eax
  cmp    %al,%dl
  sete   %cl
  test   %al,%al
  setne  %al
  test   %al,%cl
  je     L61
  mov    $0x1,%ebx
  test   %dl,%dl
  je     L61
L100:
  lea    -0x1(%rbx),%r15d
  mov    %r12,%rdi
  call   <my_strlen@plt>
  cmp    %ebx,%eax
  je     L20
  add    $0x1,%ebp
  movzbl (%r12,%rbx,1),%eax
  movzbl 0x0(%r13,%rbx,1),%edx
  add    $0x1,%rbx
  test   %al,%al
  setne  %cl
  cmp    %dl,%al
  sete   %al
  test   %al,%cl
  je     L61
  test   %dl,%dl
  jne    L100
  jmp    L61
L55:
  mov    $0x0,%eax
  jmp    L53
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int ii;
  if (!my_strlen(to_find))
    return (str);
  for (i = 0; str[i]; i++) {
    for (ii = 0; to_find[ii] == str[i] && to_find[ii] && str[i]; ii++, i++) {
      if (my_strlen(to_find) == (ii + 1))
        return (&str[i - ii]);
    }
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strstr>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %r12,%rax
  test   %r8d,%r8d
  je     L28
  movzbl (%r12),%eax
  xor    %ecx,%ecx
  test   %al,%al
  je     L85
L39:
  movzbl (%r15),%edx
  test   %dl,%dl
  je     L81
  movslq %ecx,%r13
  mov    $0x1,%ebx
  mov    %r13,%rbp
  cmp    %al,%dl
  je     L88
  jmp    L81
  nopl   0x0(%rax,%rax,1)
L23:
  test   %dl,%dl
  je     L87
L88:
  mov    %r15,%rdi
  lea    -0x1(%rbx),%r14d
  call   <my_strlen@plt>
  cmp    %ebx,%eax
  je     L61
  movzbl (%r15,%rbx,1),%eax
  lea    (%r12,%r13,1),%rdx
  add    $0x1,%ebp
  movzbl (%rdx,%rbx,1),%edx
  add    $0x1,%rbx
  test   %al,%al
  setne  %cl
  cmp    %dl,%al
  sete   %al
  test   %al,%cl
  jne    L23
L87:
  lea    0x1(%rbp),%ecx
  movslq %ecx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jne    L39
L85:
  xor    %eax,%eax
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L61:
  sub    %r14d,%ebp
  add    $0x8,%rsp
  movslq %ebp,%rax
  pop    %rbx
  pop    %rbp
  add    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L81:
  mov    %ecx,%ebp
  lea    0x1(%rbp),%ecx
  movslq %ecx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jne    L39
  jmp    L85
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int ii;
  if (!my_strlen(to_find))
    return (str);
  for (i = 0; str[i]; i++) {
    for (ii = 0; to_find[ii] == str[i] && to_find[ii] && str[i]; ii++, i++) {
      if (my_strlen(to_find) == (ii + 1))
        return (&str[i - ii]);
    }
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_strstr>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <my_strlen@plt>
  mov    %eax,%r8d
  mov    %r12,%rax
  test   %r8d,%r8d
  je     L34
  movzbl (%r12),%eax
  xor    %ecx,%ecx
  test   %al,%al
  je     L44
L36:
  movzbl (%r15),%edx
  test   %dl,%dl
  je     L10
  movslq %ecx,%r13
  mov    $0x1,%ebx
  mov    %r13,%rbp
  cmp    %al,%dl
  je     L60
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L67:
  test   %dl,%dl
  je     L70
L60:
  mov    %r15,%rdi
  lea    -0x1(%rbx),%r14d
  call   <my_strlen@plt>
  cmp    %ebx,%eax
  je     L37
  movzbl (%r15,%rbx,1),%eax
  lea    (%r12,%r13,1),%rdx
  add    $0x1,%ebp
  movzbl (%rdx,%rbx,1),%edx
  add    $0x1,%rbx
  test   %al,%al
  setne  %cl
  cmp    %dl,%al
  sete   %al
  test   %al,%cl
  jne    L67
L70:
  lea    0x1(%rbp),%ecx
  movslq %ecx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jne    L36
L44:
  xor    %eax,%eax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L37:
  sub    %r14d,%ebp
  add    $0x8,%rsp
  movslq %ebp,%rax
  pop    %rbx
  pop    %rbp
  add    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  mov    %ecx,%ebp
  lea    0x1(%rbp),%ecx
  movslq %ecx,%rax
  movzbl (%r12,%rax,1),%eax
  test   %al,%al
  jne    L36
  jmp    L44
```

assistant: ```c
char *my_strstr(char *str, char *to_find) {
  int i;
  int ii;
  if (!my_strlen(to_find))
    return (str);
  for (i = 0; str[i]; i++) {
    for (ii = 0; to_find[ii] == str[i] && to_find[ii] && str[i]; ii++, i++) {
      if (my_strlen(to_find) == (ii + 1))
        return (&str[i - ii]);
    }
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mixColumn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  jmp    L38
L18:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  mov    %dl,-0x1c(%rbp,%rax,1)
  addl   $0x1,-0x20(%rbp)
L38:
  cmpl   $0x3,-0x20(%rbp)
  jle    L18
  movl   $0x0,-0x20(%rbp)
  jmp    L61
L50:
  mov    -0x20(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <mul_GF@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  mov    -0x20(%rbp),%eax
  add    $0x2,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  mov    -0x20(%rbp),%eax
  add    $0x3,%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  mov    %ebx,%edx
  mov    -0x20(%rbp),%eax
  cltq
  mov    %dl,-0x1c(%rbp,%rax,1)
  addl   $0x1,-0x20(%rbp)
L61:
  cmpl   $0x3,-0x20(%rbp)
  jle    L50
  movl   $0x0,-0x20(%rbp)
  jmp    L0
L68:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  movzbl -0x1c(%rbp,%rax,1),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L0:
  cmpl   $0x3,-0x20(%rbp)
  jle    L68
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L62
  call   <__stack_chk_fail@plt>
L62:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void mixColumn(unsigned char buf[]) {
  int i;
  unsigned char a[4];
  for (i = 0; i < 4; i++) {
    a[i] = buf[i];
  }
  for (i = 0; i < 4; i++) {
    a[i] = mul_GF(buf[(i) % 4], 2) ^ mul_GF(buf[(i + 1) % 4], 3) ^ mul_GF(buf[(i + 2) % 4], 1) ^ mul_GF(buf[(i + 3) % 4], 1);
  }
  for (i = 0; i < 4; i++) {
    buf[i] = a[i];
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mixColumn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
L20:
  movzbl (%r12,%rax,1),%edx
  mov    %dl,0x4(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L20
  mov    $0x0,%ebp
L13:
  mov    %ebp,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%rdx,%rbp,1),%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cltq
  movzbl (%r12,%rax,1),%edi
  mov    $0x2,%esi
  call   <mul_GF@plt>
  mov    %eax,%ebx
  lea    0x1(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cltq
  movzbl (%r12,%rax,1),%edi
  mov    $0x3,%esi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  lea    0x2(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cltq
  movzbl (%r12,%rax,1),%edi
  mov    $0x1,%esi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  lea    0x3(%rbp),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  cltq
  movzbl (%r12,%rax,1),%edi
  mov    $0x1,%esi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  mov    %bl,0x4(%rsp,%rbp,1)
  add    $0x1,%rbp
  cmp    $0x4,%rbp
  jne    L13
  mov    $0x0,%eax
L38:
  movzbl 0x4(%rsp,%rax,1),%edx
  mov    %dl,(%r12,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L38
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mixColumn(unsigned char buf[]) {
  int i;
  unsigned char a[4];
  for (i = 0; i < 4; i++) {
    a[i] = buf[i];
  }
  for (i = 0; i < 4; i++) {
    a[i] = mul_GF(buf[(i) % 4], 2) ^ mul_GF(buf[(i + 1) % 4], 3) ^ mul_GF(buf[(i + 2) % 4], 1) ^ mul_GF(buf[(i + 3) % 4], 1);
  }
  for (i = 0; i < 4; i++) {
    buf[i] = a[i];
  }
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<mixColumn>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  lea    0x3(%rsp),%r13
  mov    %eax,0x4(%rsp)
L16:
  movzbl -0x1(%r12,%rbp,1),%edi
  mov    $0x2,%esi
  call   <mul_GF@plt>
  mov    $0x3,%esi
  mov    %eax,%ebx
  mov    %rbp,%rax
  and    $0x3,%eax
  movzbl (%r12,%rax,1),%edi
  call   <mul_GF@plt>
  mov    $0x1,%esi
  xor    %eax,%ebx
  lea    0x1(%rbp),%eax
  and    $0x3,%eax
  movzbl (%r12,%rax,1),%edi
  call   <mul_GF@plt>
  mov    $0x1,%esi
  xor    %eax,%ebx
  lea    0x2(%rbp),%eax
  and    $0x3,%eax
  movzbl (%r12,%rax,1),%edi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  mov    %bl,0x0(%r13,%rbp,1)
  add    $0x1,%rbp
  cmp    $0x5,%rbp
  jne    L16
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mixColumn(unsigned char buf[]) {
  int i;
  unsigned char a[4];
  for (i = 0; i < 4; i++) {
    a[i] = buf[i];
  }
  for (i = 0; i < 4; i++) {
    a[i] = mul_GF(buf[(i) % 4], 2) ^ mul_GF(buf[(i + 1) % 4], 3) ^ mul_GF(buf[(i + 2) % 4], 1) ^ mul_GF(buf[(i + 3) % 4], 1);
  }
  for (i = 0; i < 4; i++) {
    buf[i] = a[i];
  }
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<mixColumn>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  lea    0x3(%rsp),%r13
  mov    %eax,0x4(%rsp)
L0:
  movzbl -0x1(%r12,%rbp,1),%edi
  mov    $0x2,%esi
  call   <mul_GF@plt>
  mov    $0x3,%esi
  mov    %eax,%ebx
  mov    %rbp,%rax
  and    $0x3,%eax
  movzbl (%r12,%rax,1),%edi
  call   <mul_GF@plt>
  mov    $0x1,%esi
  xor    %eax,%ebx
  lea    0x1(%rbp),%eax
  and    $0x3,%eax
  movzbl (%r12,%rax,1),%edi
  call   <mul_GF@plt>
  mov    $0x1,%esi
  xor    %eax,%ebx
  lea    0x2(%rbp),%eax
  and    $0x3,%eax
  movzbl (%r12,%rax,1),%edi
  call   <mul_GF@plt>
  xor    %eax,%ebx
  mov    %bl,0x0(%r13,%rbp,1)
  add    $0x1,%rbp
  cmp    $0x5,%rbp
  jne    L0
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mixColumn(unsigned char buf[]) {
  int i;
  unsigned char a[4];
  for (i = 0; i < 4; i++) {
    a[i] = buf[i];
  }
  for (i = 0; i < 4; i++) {
    a[i] = mul_GF(buf[(i) % 4], 2) ^ mul_GF(buf[(i + 1) % 4], 3) ^ mul_GF(buf[(i + 2) % 4], 1) ^ mul_GF(buf[(i + 3) % 4], 1);
  }
  for (i = 0; i < 4; i++) {
    buf[i] = a[i];
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wcscpy_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L21
  cmpq   $0x0,-0x20(%rbp)
  jne    L32
L21:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  jmp    L8
L32:
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  jne    L50
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  jmp    L8
L50:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <wcslen@plt>
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L47
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L8
L47:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
int wcscpy_s(wchar_t *dest, size_t numElem, const wchar_t *src) {
  size_t size = 0;
  if (!dest || !numElem)
    return EINVAL;
  dest[0] = 0;
  if (!src)
    return EINVAL;
  size = wcslen(src) + 1;
  if (size > numElem)
    return ERANGE;
  memcpy(dest, src, size * sizeof(wchar_t));
  return 0;
}
```