user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xf4000(%rsp),%r11
L149:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L149
  sub    $0x278,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf4268(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x3d090,%edx
  mov    $0xffffffff,%esi
  call   <memset@plt>
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  lea    D13(%rip),%r12
  cmpl   $0x0,0x1c(%rsp)
  jg     L199
  movl   $0x0,0xc(%rsp)
L290:
  mov    0xc(%rsp),%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0xf4268(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0xf4278,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L130:
  lea    0x20(%rsp,%r14,4),%rbp
  mov    $0x0,%ebx
L317:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L317
L289:
  add    $0x1,%r13d
  mov    0x1c(%rsp),%edi
  add    $0x1f4,%r14
  cmp    %r13d,%edi
  jle    L150
L199:
  cmpl   $0x0,0x1c(%rsp)
  jg     L130
  jmp    L289
L150:
  test   %edi,%edi
  jle    L169
  lea    0x20(%rsp),%rsi
  lea    -0x2(%rdi),%r14d
  mov    $0xffffffff,%r12d
  mov    $0x1,%r13d
  movl   $0x0,0xc(%rsp)
  mov    $0x0,%r11d
  lea    -0x1(%rdi),%ebx
  jmp    L310
L309:
  mov    $0x0,%ecx
  jmp    L257
L295:
  add    $0x1,%ecx
L161:
  mov    %r12d,%r15d
  test   %r12d,%r12d
  js     L306
  mov    %r8,%rax
L246:
  cmpl   $0x1,-0x7d0(%rax)
  je     L81
  sub    $0x1,%r15d
  sub    $0x7d0,%rax
  cmp    $0xffffffff,%r15d
  jne    L246
  jmp    L306
L81:
  add    $0x1,%ecx
L306:
  cmp    %r13d,%edi
  jle    L301
  lea    0x0(%rbp,%r8,1),%r15
  mov    %r8,%rax
L59:
  cmpl   $0x1,0x7d0(%rax)
  je     L30
  add    $0x7d0,%rax
  cmp    %r15,%rax
  jne    L59
  jmp    L301
L30:
  cmp    $0x3,%ecx
  sete   %al
  movzbl %al,%eax
  add    %eax,0xc(%rsp)
L301:
  add    $0x1,%edx
  add    $0x1,%r9
  add    $0x4,%r8
  add    $0x1,%r10
  cmp    %edx,%edi
  je     L18
L168:
  test   %r11d,%r11d
  je     L301
  test   %edx,%edx
  sete   %al
  cmp    %r11d,%ebx
  sete   %cl
  or     %cl,%al
  jne    L301
  cmp    %edx,%ebx
  je     L301
  cmpl   $0x1,(%r8)
  je     L301
  test   %r10d,%r10d
  js     L309
  mov    %r10,%rax
L49:
  mov    (%rsi,%rax,4),%ecx
  cmp    $0x1,%ecx
  je     L257
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L49
  mov    $0x0,%ecx
L257:
  cmp    %r9d,%edi
  jle    L161
  mov    %r9,%rax
L278:
  cmpl   $0x1,(%rsi,%rax,4)
  je     L295
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L278
  jmp    L161
L18:
  add    $0x1,%r11d
  add    $0x1,%r13d
  add    $0x1,%r12d
  add    $0x7d0,%rsi
  sub    $0x1,%r14d
  cmp    %r11d,%edi
  je     L290
L310:
  mov    %r14d,%ebp
  mov    %rsi,%r8
  mov    $0xffffffffffffffff,%r10
  mov    $0x1,%r9d
  mov    $0x0,%edx
  add    $0x1,%rbp
  imul   $0x7d0,%rbp,%rbp
  jmp    L168
L169:
  movl   $0x0,0xc(%rsp)
  jmp    L290
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D26
type: string

tool: D13: %d

tool: D26: %d


assistant: ```c
int main() {
  int n, i, j, k, flag, out;
  int map[500][500];
  scanf("%d", &n);
  memset(map, -1, 500 * 500);
  out = 0;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      scanf("%d", &map[i][j]);
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (i == 0 || i == n - 1 || j == 0 || j == n - 1)
        continue;
      if (map[i][j] == 1)
        continue;
      flag = 0;
      for (k = j - 1; k >= 0; k--) {
        if (map[i][k] == 1) {
          flag++;
          break;
        }
      }
      for (k = j + 1; k < n; k++) {
        if (map[i][k] == 1) {
          flag++;
          break;
        }
      }
      for (k = i - 1; k >= 0; k--) {
        if (map[k][j] == 1) {
          flag++;
          break;
        }
      }
      for (k = i + 1; k < n; k++) {
        if (map[k][j] == 1) {
          flag++;
          break;
        }
      }
      if (flag == 4)
        out++;
    }
  }
  printf("%d\n", out);
  return 0;
}
```