ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<is_unicode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L106
  mov    $0x0,%eax
  jmp    L150
L106:
  movl   $0x0,-0x10(%rbp)
  jmp    L101
L149:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    $0x0,%eax
  jmp    L150
L28:
  addl   $0x1,-0x10(%rbp)
L101:
  cmpl   $0x5,-0x10(%rbp)
  jle    L149
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L140
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x75,%al
  jne    L140
  movl   $0x1,-0xc(%rbp)
  jmp    L14
L140:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  jne    L110
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L110
  movl   $0x2,-0xc(%rbp)
  jmp    L14
L110:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L77
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L77
  movl   $0x3,-0xc(%rbp)
  jmp    L14
L77:
  mov    $0x0,%eax
  jmp    L150
L14:
  movl   $0x2,-0x4(%rbp)
  jmp    L174
L190:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L246
L0:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L13
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jle    L246
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L49
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L49
L246:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L174
L49:
  movl   $0x0,-0x8(%rbp)
  jmp    L241
L174:
  cmpl   $0x5,-0x4(%rbp)
  jle    L190
L241:
  mov    -0x8(%rbp),%eax
L150:
  pop    %rbp
  ret
```

assistant: ```c
int is_unicode(char *p) {
  if (p == NULL)
    return 0;
  for (int i = 0; i < 6; ++i)
    if (*(p + i) == '\0')
      return 0;
  int type = 0, flag = 0;
  if (*p == '\\' && *(p + 1) == 'u')
    type = 1;
  else if (*p == '#' && *(p + 1) == 'x')
    type = 2;
  else if (*p == '0' && *(p + 1) == 'x')
    type = 3;
  else
    return 0;
  for (int i = 2; i < 6; ++i)
    if ((*(p + i) >= '0' && *(p + i) <= '9') || (*(p + i) >= 'A' && *(p + i) <= 'F') || (*(p + i) >= 'a' && *(p + i) <= 'f'))
      flag = type;
    else {
      flag = 0;
      break;
    }
  return flag;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_unicode>:
  endbr64
  test   %rdi,%rdi
  je     L137
  mov    %rdi,%rax
  lea    0x6(%rdi),%rdx
L61:
  cmpb   $0x0,(%rax)
  je     L86
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L61
  movzbl (%rdi),%eax
  cmp    $0x5c,%al
  je     L168
  cmp    $0x23,%al
  je     L99
  cmp    $0x30,%al
  jne    L151
  mov    $0x0,%esi
  cmpb   $0x78,0x1(%rdi)
  jne    L14
  mov    $0x3,%esi
L156:
  add    $0x2,%rdi
  jmp    L110
L168:
  mov    $0x0,%esi
  cmpb   $0x75,0x1(%rdi)
  jne    L14
  mov    $0x1,%esi
  jmp    L156
L99:
  mov    $0x0,%esi
  cmpb   $0x78,0x1(%rdi)
  jne    L14
  mov    $0x2,%esi
  jmp    L156
L55:
  add    $0x1,%rdi
  cmp    %rdx,%rdi
  je     L14
L110:
  movzbl (%rdi),%eax
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x5,%cl
  jbe    L55
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L55
  mov    $0x0,%esi
L14:
  mov    %esi,%eax
  ret
L137:
  mov    $0x0,%esi
  jmp    L14
L86:
  mov    $0x0,%esi
  jmp    L14
L151:
  mov    $0x0,%esi
  jmp    L14
```

assistant: ```c
int is_unicode(char *p) {
  if (p == NULL)
    return 0;
  for (int i = 0; i < 6; ++i)
    if (*(p + i) == '\0')
      return 0;
  int type = 0, flag = 0;
  if (*p == '\\' && *(p + 1) == 'u')
    type = 1;
  else if (*p == '#' && *(p + 1) == 'x')
    type = 2;
  else if (*p == '0' && *(p + 1) == 'x')
    type = 3;
  else
    return 0;
  for (int i = 2; i < 6; ++i)
    if ((*(p + i) >= '0' && *(p + i) <= '9') || (*(p + i) >= 'A' && *(p + i) <= 'F') || (*(p + i) >= 'a' && *(p + i) <= 'f'))
      flag = type;
    else {
      flag = 0;
      break;
    }
  return flag;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_unicode>:
  endbr64
  test   %rdi,%rdi
  je     L42
  mov    %rdi,%rax
  lea    0x6(%rdi),%rdx
L2:
  cmpb   $0x0,(%rax)
  je     L42
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L2
  movzbl (%rdi),%eax
  cmp    $0x5c,%al
  je     L51
  cmp    $0x23,%al
  je     L106
  xor    %r8d,%r8d
  cmp    $0x30,%al
  jne    L39
  cmpb   $0x78,0x1(%rdi)
  jne    L39
  mov    $0x3,%r8d
L6:
  add    $0x2,%rdi
L19:
  movzbl (%rdi),%eax
  mov    %eax,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x5,%cl
  jbe    L4
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L42
L4:
  add    $0x1,%rdi
  cmp    %rdi,%rdx
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L51:
  cmpb   $0x75,0x1(%rdi)
  je     L105
  xchg   %ax,%ax
L42:
  xor    %r8d,%r8d
L39:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  mov    $0x1,%r8d
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L106:
  cmpb   $0x78,0x1(%rdi)
  jne    L42
  mov    $0x2,%r8d
  jmp    L6
```

assistant: ```c
int is_unicode(char *p) {
  if (p == NULL)
    return 0;
  for (int i = 0; i < 6; ++i)
    if (*(p + i) == '\0')
      return 0;
  int type = 0, flag = 0;
  if (*p == '\\' && *(p + 1) == 'u')
    type = 1;
  else if (*p == '#' && *(p + 1) == 'x')
    type = 2;
  else if (*p == '0' && *(p + 1) == 'x')
    type = 3;
  else
    return 0;
  for (int i = 2; i < 6; ++i)
    if ((*(p + i) >= '0' && *(p + i) <= '9') || (*(p + i) >= 'A' && *(p + i) <= 'F') || (*(p + i) >= 'a' && *(p + i) <= 'f'))
      flag = type;
    else {
      flag = 0;
      break;
    }
  return flag;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_unicode>:
  endbr64
  test   %rdi,%rdi
  je     L77
  movzbl (%rdi),%eax
  test   %al,%al
  je     L77
  movzbl 0x1(%rdi),%esi
  test   %sil,%sil
  je     L77
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  je     L77
  movzbl 0x3(%rdi),%ecx
  test   %cl,%cl
  je     L77
  movzbl 0x4(%rdi),%r8d
  test   %r8b,%r8b
  je     L77
  movzbl 0x5(%rdi),%edi
  test   %dil,%dil
  je     L77
  cmp    $0x5c,%al
  je     L35
  cmp    $0x23,%al
  je     L82
  cmp    $0x30,%al
  mov    $0x0,%eax
  jne    L155
  cmp    $0x78,%sil
  jne    L132
  mov    $0x3,%eax
L206:
  mov    %edx,%esi
  and    $0xffffffdf,%esi
  sub    $0x41,%esi
  cmp    $0x5,%sil
  jbe    L110
  sub    $0x30,%edx
  cmp    $0x9,%dl
  ja     L77
L110:
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  jbe    L115
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L77
L115:
  mov    %r8d,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  jbe    L61
  sub    $0x30,%r8d
  cmp    $0x9,%r8b
  ja     L77
L61:
  mov    %edi,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  jbe    L132
  sub    $0x30,%edi
  xor    %edx,%edx
  cmp    $0x9,%dil
  cmova  %edx,%eax
  ret
  nopl   (%rax)
L35:
  cmp    $0x75,%sil
  je     L85
  cs nopw 0x0(%rax,%rax,1)
L77:
  xor    %eax,%eax
L132:
  ret
  nopl   0x0(%rax,%rax,1)
L85:
  mov    $0x1,%eax
  jmp    L206
  nopw   0x0(%rax,%rax,1)
L82:
  cmp    $0x78,%sil
  jne    L77
  mov    $0x2,%eax
  jmp    L206
L155:
  ret
```

assistant: ```c
int is_unicode(char *p) {
  if (p == NULL)
    return 0;
  for (int i = 0; i < 6; ++i)
    if (*(p + i) == '\0')
      return 0;
  int type = 0, flag = 0;
  if (*p == '\\' && *(p + 1) == 'u')
    type = 1;
  else if (*p == '#' && *(p + 1) == 'x')
    type = 2;
  else if (*p == '0' && *(p + 1) == 'x')
    type = 3;
  else
    return 0;
  for (int i = 2; i < 6; ++i)
    if ((*(p + i) >= '0' && *(p + i) <= '9') || (*(p + i) >= 'A' && *(p + i) <= 'F') || (*(p + i) >= 'a' && *(p + i) <= 'f'))
      flag = type;
    else {
      flag = 0;
      break;
    }
  return flag;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<js_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x1,%edi
  call   <exit@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *js_malloc(size_t size) {
  void *mem = malloc(size);
  if (mem == NULL) {
    exit(1);
  }
  return mem;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<js_malloc>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L13
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
L13:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

assistant: ```c
void *js_malloc(size_t size) {
  void *mem = malloc(size);
  if (mem == NULL) {
    exit(1);
  }
  return mem;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<js_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
L5:
  mov    %r12,%rax
  pop    %r12
  ret
L3:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

assistant: ```c
void *js_malloc(size_t size) {
  void *mem = malloc(size);
  if (mem == NULL) {
    exit(1);
  }
  return mem;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<js_malloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L16
L5:
  mov    %r12,%rax
  pop    %r12
  ret
L16:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

assistant: ```c
void *js_malloc(size_t size) {
  void *mem = malloc(size);
  if (mem == NULL) {
    exit(1);
  }
  return mem;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L43
L18:
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L36
L9:
  mov    -0x24(%rbp),%edx
  mov    -0x24(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  lea    -0x11(%rbp),%rax
  lea    D42(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ecx
  movzbl -0xd(%rbp),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  lea    (%rcx,%rax,1),%edx
  movzbl -0xe(%rbp),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   $0x64,%eax,%eax
  add    %eax,%edx
  movzbl -0xf(%rbp),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  imul   $0x3e8,%eax,%eax
  add    %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L36:
  cmpl   $0x9,-0x18(%rbp)
  jle    L9
  addl   $0x1,-0x1c(%rbp)
L43:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L18
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D32
datatype: string
name: parse_data
arguments: data_label: D17
datatype: string
name: parse_data
arguments: data_label: D42
datatype: string
name: parse_data
arguments: data_label: D21
datatype: string

tool: D32: %d

tool: D17: Case %d:


tool: D42: %08d

tool: D21: %d


assistant: ```c
int main(void) {
  int s, i, j, k, num;
  char t[9];
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    scanf("%d", &s);
    printf("Case %d:\n", i + 1);
    for (j = 0; j < 10; j++) {
      s = s * s;
      sprintf(t, "%08d", s);
      s = (t[5] - '0') + (t[4] - '0') * 10 + (t[3] - '0') * 100 + (t[2] - '0') * 1000;
      printf("%d\n", s);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L35
  mov    $0x0,%r14d
  lea    D7(%rip),%r15
  lea    D42(%rip),%r13
  lea    D36(%rip),%r12
L14:
  lea    0x4(%rsp),%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  add    $0x1,%r14d
  mov    %r14d,%esi
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%ebx
  lea    0xf(%rsp),%rbp
L31:
  mov    0x4(%rsp),%edx
  imul   %edx,%edx
  mov    %edx,0x4(%rsp)
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  movsbl 0x13(%rsp),%eax
  lea    -0xf0(%rax,%rax,4),%edx
  movsbl 0x14(%rsp),%eax
  lea    -0x30(%rax,%rdx,2),%esi
  movsbl 0x12(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x64,%eax,%eax
  add    %eax,%esi
  movsbl 0x11(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x3e8,%eax,%eax
  add    %eax,%esi
  mov    %esi,0x4(%rsp)
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L31
  cmp    0x8(%rsp),%r14d
  jl     L14
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D42
datatype: string
name: read_data
arguments: data_tag: D36
datatype: string
name: read_data
arguments: data_tag: D40
datatype: string

tool: D7: %d

tool: D42: %08d

tool: D36: %d


tool: D40: Case %d:


assistant: ```c
int main(void) {
  int s, i, j, k, num;
  char t[9];
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    scanf("%d", &s);
    printf("Case %d:\n", i + 1);
    for (j = 0; j < 10; j++) {
      s = s * s;
      sprintf(t, "%08d", s);
      s = (t[5] - '0') + (t[4] - '0') * 10 + (t[3] - '0') * 100 + (t[2] - '0') * 1000;
      printf("%d\n", s);
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D15(%rip),%r15
  push   %r14
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L32
  lea    0x14(%rsp),%rax
  xor    %r14d,%r14d
  lea    0x1f(%rsp),%r13
  mov    %rax,0x8(%rsp)
  lea    D37(%rip),%r12
  lea    D14(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L8:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdi
  add    $0x1,%r14d
  mov    $0xa,%ebx
  call   <scanf@plt>
  mov    %r14d,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L7:
  mov    0x14(%rsp),%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  imul   %edx,%edx
  mov    %edx,0x14(%rsp)
  call   <sprintf@plt>
  movsbl 0x23(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0xf0(%rax,%rax,4),%edx
  movsbl 0x24(%rsp),%eax
  lea    -0x30(%rax,%rdx,2),%esi
  movsbl 0x22(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x64,%eax,%eax
  add    %eax,%esi
  movsbl 0x21(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x3e8,%eax,%eax
  add    %eax,%esi
  mov    %esi,0x14(%rsp)
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  cmp    0x18(%rsp),%r14d
  jl     L8
L32:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
datatype: string
name: unpack_data
arguments: label: D37
datatype: string
name: unpack_data
arguments: label: D14
datatype: string
name: unpack_data
arguments: label: D35
datatype: string

tool: D15: %d

tool: D37: %08d

tool: D14: %d


tool: D35: Case %d:


assistant: ```c
int main(void) {
  int s, i, j, k, num;
  char t[9];
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    scanf("%d", &s);
    printf("Case %d:\n", i + 1);
    for (j = 0; j < 10; j++) {
      s = s * s;
      sprintf(t, "%08d", s);
      s = (t[5] - '0') + (t[4] - '0') * 10 + (t[3] - '0') * 100 + (t[2] - '0') * 1000;
      printf("%d\n", s);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%r15
  push   %r14
  mov    %r15,%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L10
  lea    0x14(%rsp),%rax
  xor    %r14d,%r14d
  lea    0x1f(%rsp),%r13
  mov    %rax,0x8(%rsp)
  lea    D14(%rip),%r12
  lea    D21(%rip),%rbp
  nopw   0x0(%rax,%rax,1)
L12:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdi
  add    $0x1,%r14d
  mov    $0xa,%ebx
  call   <scanf@plt>
  mov    %r14d,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L6:
  mov    0x14(%rsp),%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  imul   %edx,%edx
  mov    %edx,0x14(%rsp)
  call   <sprintf@plt>
  movsbl 0x23(%rsp),%eax
  mov    %rbp,%rdi
  lea    -0xf0(%rax,%rax,4),%edx
  movsbl 0x24(%rsp),%eax
  lea    -0x30(%rax,%rdx,2),%esi
  movsbl 0x22(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x64,%eax,%eax
  add    %eax,%esi
  movsbl 0x21(%rsp),%eax
  sub    $0x30,%eax
  imul   $0x3e8,%eax,%eax
  add    %eax,%esi
  mov    %esi,0x14(%rsp)
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L6
  cmp    0x18(%rsp),%r14d
  jl     L12
L10:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string
name: unpack_data
arguments: label: D14
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D35
data_type: string

tool: D9: %d

tool: D14: %08d

tool: D21: %d


tool: D35: Case %d:


assistant: ```c
int main(void) {
  int s, i, j, k, num;
  char t[9];
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    scanf("%d", &s);
    printf("Case %d:\n", i + 1);
    for (j = 0; j < 10; j++) {
      s = s * s;
      sprintf(t, "%08d", s);
      s = (t[5] - '0') + (t[4] - '0') * 10 + (t[3] - '0') * 100 + (t[2] - '0') * 1000;
      printf("%d\n", s);
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0xc(%rbp)
  movl   $0x3,-0x10(%rbp)
  mov    $0x0,%eax
  call   <array@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
main() {
  static j = 2;
  unsigned i = 5;
  int k = 3;
  int l, m, n;
  (int)k;
  (int *)&k;
  return array();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <array@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  static j = 2;
  unsigned i = 5;
  int k = 3;
  int l, m, n;
  (int)k;
  (int *)&k;
  return array();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <array@plt>
```

assistant: ```c
main() {
  static j = 2;
  unsigned i = 5;
  int k = 3;
  int l, m, n;
  (int)k;
  (int *)&k;
  return array();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <array@plt>
```

assistant: ```c
main() {
  static j = 2;
  unsigned i = 5;
  int k = 3;
  int l, m, n;
  (int)k;
  (int *)&k;
  return array();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  and    $0xcccccccc,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rev(int xi, int y, int z) {
  unsigned x = xi;
  x = (x & 0x55555555) << 1 | ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) << 2 | ((x >> 2) & 0x33333333);
  x = (x & 0x0F0F0F0F) << 4 | ((x >> 4) & 0x0F0F0F0F);
  x = (x << 24) | ((x & 0xFF00) << 8) | ((x >> 8) & 0xFF00) | (x >> 24);
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rev>:
  endbr64
  mov    %edi,%eax
  lea    (%rdi,%rdi,1),%edi
  and    $0xaaaaaaaa,%edi
  shr    %eax
  and    $0x55555555,%eax
  or     %eax,%edi
  lea    0x0(,%rdi,4),%eax
  and    $0xcccccccc,%eax
  shr    $0x2,%edi
  and    $0x33333333,%edi
  or     %edi,%eax
  mov    %eax,%edx
  shl    $0x4,%edx
  and    $0xf0f0f0f0,%edx
  shr    $0x4,%eax
  and    $0xf0f0f0f,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x8,%eax
  and    $0xff00,%eax
  mov    %edx,%ecx
  shl    $0x18,%ecx
  mov    %edx,%esi
  shr    $0x18,%esi
  or     %esi,%ecx
  shl    $0x8,%edx
  and    $0xff0000,%edx
  or     %ecx,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
int rev(int xi, int y, int z) {
  unsigned x = xi;
  x = (x & 0x55555555) << 1 | ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) << 2 | ((x >> 2) & 0x33333333);
  x = (x & 0x0F0F0F0F) << 4 | ((x >> 4) & 0x0F0F0F0F);
  x = (x << 24) | ((x & 0xFF00) << 8) | ((x >> 8) & 0xFF00) | (x >> 24);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<rev>:
  endbr64
  mov    %edi,%eax
  lea    (%rdi,%rdi,1),%edi
  shr    %eax
  and    $0xaaaaaaaa,%edi
  and    $0x55555555,%eax
  or     %eax,%edi
  lea    0x0(,%rdi,4),%edx
  shr    $0x2,%edi
  and    $0xcccccccc,%edx
  and    $0x33333333,%edi
  or     %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%edx
  shl    $0x4,%eax
  and    $0xf0f0f0f,%edx
  and    $0xf0f0f0f0,%eax
  or     %edx,%eax
  bswap  %eax
  ret
```

assistant: ```c
int rev(int xi, int y, int z) {
  unsigned x = xi;
  x = (x & 0x55555555) << 1 | ((x >> 1) & 0x55555555);
  x = (x & 0x33333333) << 2 | ((x >> 2) & 0x33333333);
  x = (x & 0x0F0F0F0F) << 4 | ((x >> 4) & 0x0F0F0F0F);
  x = (x << 24) | ((x & 0xFF00) << 8) | ((x >> 8) & 0xFF00) | (x >> 24);
  return x;
}
```