ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
  lea    D53(%rip),%r14
  lea    D60(%rip),%r13
L11:
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xb2,%ebx
  movsd  D13(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  lea    0x50(%rsp),%rbp
L7:
  movsd  D4(%rip),%xmm0
  addsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  movd   %xmm1,%r15d
  mov    %rbp,%rdi
  movaps %xmm1,%xmm0
  call   <CalcLon@plt>
  lea    0x10(%rsp),%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  movd   %r15d,%xmm0
  call   <CalcTass17Elem@plt>
  movsd  0x38(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  mov    %r13,%rdi
  mov    $0x7,%eax
  call   <printf@plt>
  movsd  D6(%rip),%xmm2
  addsd  0x8(%rsp),%xmm2
  movsd  %xmm2,0x8(%rsp)
  sub    $0x1,%ebx
  jne    L7
  lea    D69(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%r12d
  cmp    $0x8,%r12d
  jne    L11
  lea    D62(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string
name: read_data
arguments: data_label: D53
type_guessed: string
name: read_data
arguments: data_label: D60
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: byte[8]
name: read_data
arguments: data_label: D4
type_guessed: f64
name: read_data
arguments: data_label: D6
type_guessed: f64
name: read_data
arguments: data_label: D69
type_guessed: string
name: read_data
arguments: data_label: D62
type_guessed: string

tool: D3: {

tool: D53: 	"%d": [


tool: D60: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D4: 7305

tool: D6: 225

tool: D69: 	],

tool: D62: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[7];
  double lon[7];
  printf("{\n");
  for (body = 0; body < 8; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float time = jd2k + 7305.0;
      CalcLon(time, lon);
      CalcTass17Elem(time, lon, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%rdi
  lea    D8(%rip),%r15
  push   %r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  lea    0x10(%rsp),%r14
  call   <puts@plt>
L21:
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0xb2,%ebx
  call   <printf@plt>
  mov    D63(%rip),%rax
  movq   %rax,%xmm7
  nopl   (%rax)
L28:
  movsd  D43(%rip),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm7,0x8(%rsp)
  addsd  %xmm7,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsp)
  call   <CalcLon@plt>
  movss  (%rsp),%xmm0
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <CalcTass17Elem@plt>
  movsd  0x8(%rsp),%xmm7
  mov    %r13,%rdi
  movsd  0x38(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  mov    $0x7,%eax
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movapd %xmm7,%xmm0
  movsd  %xmm7,(%rsp)
  movsd  0x10(%rsp),%xmm1
  call   <printf@plt>
  movsd  (%rsp),%xmm7
  addsd  D16(%rip),%xmm7
  sub    $0x1,%ebx
  jne    L28
  lea    D62(%rip),%rdi
  add    $0x1,%r12d
  call   <puts@plt>
  cmp    $0x8,%r12d
  jne    L21
  lea    D75(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D8
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string
name: unpack_data
arguments: tag: D63
datatype: byte[8]
name: unpack_data
arguments: tag: D43
datatype: f64
name: unpack_data
arguments: tag: D16
datatype: f64
name: unpack_data
arguments: tag: D62
datatype: string
name: unpack_data
arguments: tag: D75
datatype: string

tool: D12: {

tool: D8: 	"%d": [


tool: D6: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D63": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D43: 7305

tool: D16: 225

tool: D62: 	],

tool: D75: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[7];
  double lon[7];
  printf("{\n");
  for (body = 0; body < 8; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float time = jd2k + 7305.0;
      CalcLon(time, lon);
      CalcTass17Elem(time, lon, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D61(%rip),%rdi
  lea    D8(%rip),%r15
  push   %r14
  push   %r13
  lea    D58(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x50(%rsp),%rbp
  lea    0x10(%rsp),%r14
  call   <puts@plt>
L25:
  mov    %r12d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  mov    $0xb2,%ebx
  call   <printf@plt>
  mov    D50(%rip),%rax
  movq   %rax,%xmm7
  nopl   (%rax)
L10:
  movsd  D43(%rip),%xmm0
  mov    %rbp,%rdi
  movsd  %xmm7,0x8(%rsp)
  addsd  %xmm7,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rsp)
  call   <CalcLon@plt>
  movss  (%rsp),%xmm0
  mov    %r14,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <CalcTass17Elem@plt>
  movsd  0x8(%rsp),%xmm7
  mov    %r13,%rdi
  movsd  0x38(%rsp),%xmm6
  movsd  0x30(%rsp),%xmm5
  movsd  0x28(%rsp),%xmm4
  mov    $0x7,%eax
  movsd  0x20(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  movapd %xmm7,%xmm0
  movsd  %xmm7,(%rsp)
  movsd  0x10(%rsp),%xmm1
  call   <printf@plt>
  movsd  (%rsp),%xmm7
  addsd  D42(%rip),%xmm7
  sub    $0x1,%ebx
  jne    L10
  lea    D71(%rip),%rdi
  add    $0x1,%r12d
  call   <puts@plt>
  cmp    $0x8,%r12d
  jne    L25
  lea    D34(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D61
datatype: string
name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D58
datatype: string
name: read_data
arguments: data_label: D50
datatype: byte[8]
name: read_data
arguments: data_label: D43
datatype: f64
name: read_data
arguments: data_label: D42
datatype: f64
name: read_data
arguments: data_label: D71
datatype: string
name: read_data
arguments: data_label: D34
datatype: string

tool: D61: {

tool: D8: 	"%d": [


tool: D58: 		[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],


tool: {"D50": [0x00,0x00,0x00,0x00,0x00,0x88,0xd3,0xc0]}

tool: D43: 7305

tool: D42: 225

tool: D71: 	],

tool: D34: }

assistant: ```c
int main() {
  int body;
  double jd2k;
  double start = -20000.0;
  double end = +20000.0;
  double step = 225.0;
  double elem[7];
  double lon[7];
  printf("{\n");
  for (body = 0; body < 8; body++) {
    printf("\t\"%d\": [\n", body);
    for (jd2k = start; jd2k < end; jd2k += step) {
      float time = jd2k + 7305.0;
      CalcLon(time, lon);
      CalcTass17Elem(time, lon, body, elem);
      printf("\t\t[%.13f, %.13f, %.13f, %.13f, %.13f, %.13f, %.13f],\n", jd2k, elem[0], elem[1], elem[2], elem[3], elem[4], elem[5]);
    }
    printf("\t],\n");
  }
  printf("}\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x2,-0x10(%rbp)
  jmp    L32
L21:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L31
  mov    $0x0,%eax
  jmp    L30
L31:
  addq   $0x1,-0x10(%rbp)
L32:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L21
  mov    $0x1,%eax
L30:
  leave
  ret
```

assistant: ```c
int prime(long long x) {
  long long i;
  long long sqrtx = ceil(sqrt(x));
  for (i = 2; i < sqrtx; i++) {
    if (x % i == 0)
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prime>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    $0x2,%rax
  jle    L61
  mov    %rax,%rsi
  test   $0x1,%bl
  je     L0
  mov    $0x2,%ecx
L49:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  je     L39
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  jne    L49
  mov    $0x0,%eax
  jmp    L24
L39:
  mov    $0x1,%eax
L24:
  pop    %rbx
  ret
L61:
  mov    $0x1,%eax
  jmp    L24
L0:
  mov    $0x0,%eax
  jmp    L24
```

assistant: ```c
int prime(long long x) {
  long long i;
  long long sqrtx = ceil(sqrt(x));
  for (i = 2; i < sqrtx; i++) {
    if (x % i == 0)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<prime>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    $0x2,%rax
  jle    L13
  test   $0x1,%r12b
  je     L23
  mov    %rax,%rsi
  mov    $0x2,%ecx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L23
L4:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L6
L13:
  mov    $0x1,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L23:
  xor    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int prime(long long x) {
  long long i;
  long long sqrtx = ceil(sqrt(x));
  for (i = 2; i < sqrtx; i++) {
    if (x % i == 0)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<prime>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <ceil@plt>
  cmp    $0x2,%rax
  jle    L43
  test   $0x1,%r12b
  je     L21
  mov    %rax,%rsi
  mov    $0x2,%ecx
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r12,%rax
  cqto
  idiv   %rcx
  test   %rdx,%rdx
  je     L21
L24:
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L30
L43:
  mov    $0x1,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L21:
  xor    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int prime(long long x) {
  long long i;
  long long sqrtx = ceil(sqrt(x));
  for (i = 2; i < sqrtx; i++) {
    if (x % i == 0)
      return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0x18(%rbp),%ecx
  sub    %ecx,%eax
  seto   (%edx)
  sets   0x1(%edx)
  sete   0x2(%edx)
  setp   0x3(%edx)
  setb   0x4(%edx)
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int test(int a, int b, char flags[]) {
  int ret;
  __asm__ __volatile__("mov %3, %%edx\n\t"
                       "mov %k1, %%eax\n\t"
                       "mov %k2, %%ecx\n\t"
                       "sub %%ecx, %%eax\n\t"
                       "seto (%%edx)\n\t"
                       "sets 1(%%edx)\n\t"
                       "setz 2(%%edx)\n\t"
                       "setp 3(%%edx)\n\t"
                       "setc 4(%%edx)\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(ret)
                       : "m"(a), "m"(b), "m"(flags)
                       : "eax", "ecx", "edx", "memory");
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%edx
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%ecx
  sub    %ecx,%eax
  seto   (%edx)
  sets   0x1(%edx)
  sete   0x2(%edx)
  setp   0x3(%edx)
  setb   0x4(%edx)
  mov    %eax,0x14(%rsp)
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test(int a, int b, char flags[]) {
  int ret;
  __asm__ __volatile__("mov %3, %%edx\n\t"
                       "mov %k1, %%eax\n\t"
                       "mov %k2, %%ecx\n\t"
                       "sub %%ecx, %%eax\n\t"
                       "seto (%%edx)\n\t"
                       "sets 1(%%edx)\n\t"
                       "setz 2(%%edx)\n\t"
                       "setp 3(%%edx)\n\t"
                       "setc 4(%%edx)\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(ret)
                       : "m"(a), "m"(b), "m"(flags)
                       : "eax", "ecx", "edx", "memory");
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%edx
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%ecx
  sub    %ecx,%eax
  seto   (%edx)
  sets   0x1(%edx)
  sete   0x2(%edx)
  setp   0x3(%edx)
  setb   0x4(%edx)
  mov    %eax,0x14(%rsp)
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test(int a, int b, char flags[]) {
  int ret;
  __asm__ __volatile__("mov %3, %%edx\n\t"
                       "mov %k1, %%eax\n\t"
                       "mov %k2, %%ecx\n\t"
                       "sub %%ecx, %%eax\n\t"
                       "seto (%%edx)\n\t"
                       "sets 1(%%edx)\n\t"
                       "setz 2(%%edx)\n\t"
                       "setp 3(%%edx)\n\t"
                       "setc 4(%%edx)\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(ret)
                       : "m"(a), "m"(b), "m"(flags)
                       : "eax", "ecx", "edx", "memory");
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test>:
  endbr64
  sub    $0x28,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %rdx,(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    (%rsp),%edx
  mov    0xc(%rsp),%eax
  mov    0x8(%rsp),%ecx
  sub    %ecx,%eax
  seto   (%edx)
  sets   0x1(%edx)
  sete   0x2(%edx)
  setp   0x3(%edx)
  setb   0x4(%edx)
  mov    %eax,0x14(%rsp)
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test(int a, int b, char flags[]) {
  int ret;
  __asm__ __volatile__("mov %3, %%edx\n\t"
                       "mov %k1, %%eax\n\t"
                       "mov %k2, %%ecx\n\t"
                       "sub %%ecx, %%eax\n\t"
                       "seto (%%edx)\n\t"
                       "sets 1(%%edx)\n\t"
                       "setz 2(%%edx)\n\t"
                       "setp 3(%%edx)\n\t"
                       "setc 4(%%edx)\n\t"
                       "mov %%eax, %0\n\t"
                       : "=m"(ret)
                       : "m"(a), "m"(b), "m"(flags)
                       : "eax", "ecx", "edx", "memory");
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<determine_output_during_continuation>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x47,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int determine_output_during_continuation(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(71, a, b, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<determine_output_during_continuation>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x47,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int determine_output_during_continuation(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(71, a, b, c);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<determine_output_during_continuation>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x47,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int determine_output_during_continuation(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(71, a, b, c);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<determine_output_during_continuation>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x47,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int determine_output_during_continuation(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(71, a, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lexer_skip_comment_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
L39:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2a,-0x4(%rbp)
  jne    L0
  movl   $0x1,-0x8(%rbp)
  jmp    L39
L0:
  cmpl   $0x1,-0x8(%rbp)
  jne    L38
  cmpl   $0x2f,-0x4(%rbp)
  je     L8
L38:
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L8:
  nop
  leave
  ret
```

assistant: ```c
void lexer_skip_comment_block(void) {
  enum { comment_outside, comment_astrick } state = comment_outside;
  for (;;) {
    int c = getc(stdin);
    if (c == '*')
      state = comment_astrick;
    else if (state == comment_astrick && c == '/')
      return;
    else
      state = comment_outside;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<lexer_skip_comment_block>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  mov    D9(%rip),%rbp
  jmp    L11
L15:
  mov    $0x1,%ebx
  jmp    L11
L32:
  mov    $0x0,%ebx
L11:
  mov    0x0(%rbp),%edi
  call   <getc@plt>
  cmp    $0x2a,%eax
  je     L15
  test   %ebx,%ebx
  je     L32
  cmp    $0x2f,%eax
  jne    L32
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lexer_skip_comment_block(void) {
  enum { comment_outside, comment_astrick } state = comment_outside;
  for (;;) {
    int c = getc(stdin);
    if (c == '*')
      state = comment_astrick;
    else if (state == comment_astrick && c == '/')
      return;
    else
      state = comment_outside;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lexer_skip_comment_block>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp),%edi
  call   <getc@plt>
  cmp    $0x2a,%eax
  je     L43
L44:
  cmp    $0x2f,%eax
  jne    L49
  test   %ebx,%ebx
  jne    L18
L49:
  mov    0x0(%rbp),%edi
  xor    %ebx,%ebx
  call   <getc@plt>
  cmp    $0x2a,%eax
  jne    L44
L43:
  mov    $0x1,%ebx
  jmp    L11
  nopl   0x0(%rax)
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lexer_skip_comment_block(void) {
  enum { comment_outside, comment_astrick } state = comment_outside;
  for (;;) {
    int c = getc(stdin);
    if (c == '*')
      state = comment_astrick;
    else if (state == comment_astrick && c == '/')
      return;
    else
      state = comment_outside;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<lexer_skip_comment_block>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  mov    D7(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    0x0(%rbp),%edi
  call   <getc@plt>
  cmp    $0x2a,%eax
  je     L20
L18:
  cmp    $0x2f,%eax
  jne    L30
  test   %ebx,%ebx
  jne    L3
L30:
  mov    0x0(%rbp),%edi
  xor    %ebx,%ebx
  call   <getc@plt>
  cmp    $0x2a,%eax
  jne    L18
L20:
  mov    $0x1,%ebx
  jmp    L15
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lexer_skip_comment_block(void) {
  enum { comment_outside, comment_astrick } state = comment_outside;
  for (;;) {
    int c = getc(stdin);
    if (c == '*')
      state = comment_astrick;
    else if (state == comment_astrick && c == '/')
      return;
    else
      state = comment_outside;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<echo_write_complete_cb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_get_output@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_get_length@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bufferevent_free@plt>
L8:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: write_complete_cb, remain %zd


assistant: ```c
void echo_write_complete_cb(struct bufferevent *bev, void *ctx) {
  struct evbuffer *output = bufferevent_get_output(bev);
  size_t remain = evbuffer_get_length(output);
  printf("write_complete_cb, remain %zd\n", remain);
  if (remain == 0)
    bufferevent_free(bev);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<echo_write_complete_cb>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <bufferevent_get_output@plt>
  mov    %rax,%rdi
  call   <evbuffer_get_length@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  test   %rbx,%rbx
  je     L10
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %rbp,%rdi
  call   <bufferevent_free@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D1: write_complete_cb, remain %zd


assistant: ```c
void echo_write_complete_cb(struct bufferevent *bev, void *ctx) {
  struct evbuffer *output = bufferevent_get_output(bev);
  size_t remain = evbuffer_get_length(output);
  printf("write_complete_cb, remain %zd\n", remain);
  if (remain == 0)
    bufferevent_free(bev);
}
```