ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x18(%rbp)
  jmp    L38
L90:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L56
L91:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L26
L73:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L58
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x18(%rbp)
  jge    L58
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L58
  addl   $0x1,-0xc(%rbp)
L58:
  addl   $0x1,-0x10(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L73
  addl   $0x1,-0x14(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L91
  addl   $0x1,-0x18(%rbp)
L38:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L90
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D15
type: string

tool: D10: %d

tool: D15: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++) {
    for (j = i; j <= N; j = j + 1) {
      for (k = j; k <= N; k = k + 1) {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r11d
  test   %r11d,%r11d
  jle    L77
  lea    0x1(%r11),%esi
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  jmp    L120
L128:
  add    $0x1,%eax
  cmp    %esi,%eax
  je     L4
L95:
  cmp    %ecx,%eax
  jge    L128
  lea    (%rdx,%rax,1),%edi
  cmp    %r8d,%edi
  jle    L128
  lea    (%rax,%r10,1),%edi
  cmp    %edx,%edi
  setg   %dil
  movzbl %dil,%edi
  add    %edi,%r9d
  jmp    L128
L4:
  add    $0x1,%edx
  add    $0x1,%ecx
  cmp    %esi,%edx
  je     L0
L28:
  mov    %edx,%eax
  cmp    %edx,%r11d
  jge    L95
  jmp    L4
L0:
  add    $0x1,%r8d
  cmp    %esi,%r8d
  je     L98
L120:
  cmp    %r8d,%r11d
  jl     L0
  mov    %r8d,%r10d
  lea    (%r8,%r8,1),%ecx
  mov    %r8d,%edx
  jmp    L28
L77:
  mov    $0x0,%r9d
L98:
  mov    %r9d,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D4
data_type: string

tool: D1: %d

tool: D4: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++) {
    for (j = i; j <= N; j = j + 1) {
      for (k = j; k <= N; k = k + 1) {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%r10d
  test   %r10d,%r10d
  jle    L9
  lea    0x1(%r10),%esi
  xor    %r9d,%r9d
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L25:
  lea    (%r8,%r8,1),%ecx
  mov    %r8d,%edx
  nop
L8:
  mov    %edx,%eax
  cmp    %edx,%r10d
  jl     L29
  nopw   0x0(%rax,%rax,1)
L23:
  cmp    %ecx,%eax
  jge    L69
  lea    (%rdx,%rax,1),%edi
  cmp    %edi,%r8d
  jge    L69
  lea    (%rax,%r8,1),%edi
  cmp    %edx,%edi
  setg   %dil
  movzbl %dil,%edi
  add    %edi,%r9d
L69:
  add    $0x1,%eax
  cmp    %esi,%eax
  jne    L23
L29:
  add    $0x1,%edx
  add    $0x1,%ecx
  cmp    %r10d,%edx
  jle    L8
  add    $0x1,%r8d
  cmp    %esi,%r8d
  jne    L25
L58:
  mov    %r9d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  xor    %r9d,%r9d
  jmp    L58
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D6: %d

tool: D10: Number of possible triangles is %d

assistant: ```c
int main() {
  int N;
  int i, j, k;
  int count = 0;
  scanf("%d", &N);
  for (i = 1; i <= N; i++) {
    for (j = i; j <= N; j = j + 1) {
      for (k = j; k <= N; k = k + 1) {
        if (i + j > k && j + k > i && i + k > j)
          count = count + 1;
      }
    }
  }
  printf("Number of possible triangles is %d", count);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sockgetstatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  lea    -0x10(%rbp),%rdi
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <getsockopt@plt>
  test   %rax,%rax
  jns    L2
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int sockgetstatus(int sock) {
  socklen_t arglen = sizeof(int);
  int rc = 0;
  if (getsockopt(sock, SOL_SOCKET, SO_ERROR, (void *)&rc, &arglen) < 0) {
    rc = errno;
  }
  errno = rc;
  return rc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sockgetstatus>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x0,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    %rsp,%r8
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  call   <getsockopt@plt>
  test   %rax,%rax
  js     L2
L10:
  mov    0x4(%rsp),%eax
  mov    D33(%rip),%rdx
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L2:
  mov    D33(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  jmp    L10
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockgetstatus(int sock) {
  socklen_t arglen = sizeof(int);
  int rc = 0;
  if (getsockopt(sock, SOL_SOCKET, SO_ERROR, (void *)&rc, &arglen) < 0) {
    rc = errno;
  }
  errno = rc;
  return rc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sockgetstatus>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x4(%rsp),%rcx
  mov    %rsp,%r8
  movl   $0x4,(%rsp)
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%esi
  call   <getsockopt@plt>
  test   %rax,%rax
  js     L3
  mov    0x4(%rsp),%eax
  mov    D6(%rip),%rdx
L27:
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L3:
  mov    D6(%rip),%rdx
  mov    (%rdx),%eax
  jmp    L27
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockgetstatus(int sock) {
  socklen_t arglen = sizeof(int);
  int rc = 0;
  if (getsockopt(sock, SOL_SOCKET, SO_ERROR, (void *)&rc, &arglen) < 0) {
    rc = errno;
  }
  errno = rc;
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sockgetstatus>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D33(%rip),%rax
  lea    0x4(%rsp),%rcx
  mov    %rsp,%r8
  movl   $0x4,(%rsp)
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%esi
  call   <getsockopt@plt>
  test   %rax,%rax
  js     L11
  mov    0x4(%rsp),%eax
  mov    D5(%rip),%rdx
L5:
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L11:
  mov    D5(%rip),%rdx
  mov    (%rdx),%eax
  jmp    L5
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sockgetstatus(int sock) {
  socklen_t arglen = sizeof(int);
  int rc = 0;
  if (getsockopt(sock, SOL_SOCKET, SO_ERROR, (void *)&rc, &arglen) < 0) {
    rc = errno;
  }
  errno = rc;
  return rc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x80,-0x4(%rbp)
  jmp    L39
L25:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L12
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L12:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,-0x4(%rbp)
L39:
  cmpl   $0x0,-0x4(%rbp)
  jne    L25
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D27
type: string

tool: D22: 1

tool: D1: 0

tool: D27: 


assistant: ```c
void bin(unsigned n) {
  unsigned i;
  for (i = 1 << 7; i > 0; i = i / 2)
    (n & i) ? printf("1") : printf("0");
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x8,%ebp
  mov    $0x80,%ebx
  lea    D0(%rip),%r14
  lea    D24(%rip),%r13
  jmp    L33
L4:
  mov    %r14,%rdi
  call   <printf@plt>
L38:
  shr    %ebx
  sub    $0x1,%ebp
  je     L12
L33:
  test   %ebx,%r12d
  je     L4
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L38
L12:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D24
type_infered: string
name: retrieve_data
arguments: data_label: D6
type_infered: string

tool: D0: 0

tool: D24: 1

tool: D6: 


assistant: ```c
void bin(unsigned n) {
  unsigned i;
  for (i = 1 << 7; i > 0; i = i / 2)
    (n & i) ? printf("1") : printf("0");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bin>:
  endbr64
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    $0x80,%ebx
  jmp    L13
  nopl   0x0(%rax)
L12:
  mov    %r13,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  je     L35
L13:
  test   %ebx,%r12d
  jne    L12
  mov    %r14,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L13
L35:
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D29
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string

tool: D18: 0

tool: D29: 1

tool: D10: 


assistant: ```c
void bin(unsigned n) {
  unsigned i;
  for (i = 1 << 7; i > 0; i = i / 2)
    (n & i) ? printf("1") : printf("0");
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<bin>:
  endbr64
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    $0x80,%ebx
  jmp    L37
  nopl   0x0(%rax)
L6:
  mov    %r13,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  je     L27
L37:
  test   %ebx,%r12d
  jne    L6
  mov    %r14,%rdi
  shr    %ebx
  call   <printf@plt>
  sub    $0x1,%ebp
  jne    L37
L27:
  pop    %rbx
  lea    D19(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D0
type_infered: string
name: read_data
arguments: data_tag: D19
type_infered: string

tool: D10: 0

tool: D0: 1

tool: D19: 


assistant: ```c
void bin(unsigned n) {
  unsigned i;
  for (i = 1 << 7; i > 0; i = i / 2)
    (n & i) ? printf("1") : printf("0");
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<measurement_open_html_table_pipe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,-0x420(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x418(%rbp)
  mov    -0x418(%rbp),%rcx
  mov    -0x420(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    %rcx,%r9
  mov    $0x7c,%r8d
  mov    %rdx,%rcx
  mov    $0x32,%edx
  lea    D16(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x410(%rbp),%rax
  lea    D10(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <popen@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D10
type_infered: string

tool: D9: station,datatype,measurement_date,measurement_time,measurement_value

tool: D2: left,left,left,left,right

tool: D16: queue_top_bottom_lines.e %d |html_table.e '' '%s' '%c' '%s'

tool: D10: w

assistant: ```c
FILE *measurement_open_html_table_pipe(void) {
  char sys_string[1024];
  char *heading_comma_string;
  char *justify_string;
  heading_comma_string = "station,datatype,measurement_date,measurement_time,measurement_value";
  justify_string = "left,left,left,left,right";
  sprintf(sys_string,
          "queue_top_bottom_lines.e %d |"
          "html_table.e '' '%s' '%c' '%s'",
          50, heading_comma_string, '|', justify_string);
  return popen(sys_string, "w");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<measurement_open_html_table_pipe>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D22(%rip),%r9
  mov    $0x7c,%r8d
  lea    D11(%rip),%rcx
  mov    $0x32,%edx
  lea    D2(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <popen@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x410,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D22
type: string
name: retrieve_data
arguments: data_label: D11
type: string
name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D8
type: string

tool: D22: left,left,left,left,right

tool: D11: station,datatype,measurement_date,measurement_time,measurement_value

tool: D2: queue_top_bottom_lines.e %d |html_table.e '' '%s' '%c' '%s'

tool: D8: w

assistant: ```c
FILE *measurement_open_html_table_pipe(void) {
  char sys_string[1024];
  char *heading_comma_string;
  char *justify_string;
  heading_comma_string = "station,datatype,measurement_date,measurement_time,measurement_value";
  justify_string = "left,left,left,left,right";
  sprintf(sys_string,
          "queue_top_bottom_lines.e %d |"
          "html_table.e '' '%s' '%c' '%s'",
          50, heading_comma_string, '|', justify_string);
  return popen(sys_string, "w");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<measurement_open_html_table_pipe>:
  endbr64
  push   %rbp
  mov    $0x32,%edx
  lea    D19(%rip),%rsi
  lea    D23(%rip),%r9
  mov    $0x7c,%r8d
  lea    D35(%rip),%rcx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  call   <popen@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x410,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string
name: unpack_data
arguments: data_label: D35
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string

tool: D19: queue_top_bottom_lines.e %d |html_table.e '' '%s' '%c' '%s'

tool: D23: left,left,left,left,right

tool: D35: station,datatype,measurement_date,measurement_time,measurement_value

tool: D2: w

assistant: ```c
FILE *measurement_open_html_table_pipe(void) {
  char sys_string[1024];
  char *heading_comma_string;
  char *justify_string;
  heading_comma_string = "station,datatype,measurement_date,measurement_time,measurement_value";
  justify_string = "left,left,left,left,right";
  sprintf(sys_string,
          "queue_top_bottom_lines.e %d |"
          "html_table.e '' '%s' '%c' '%s'",
          50, heading_comma_string, '|', justify_string);
  return popen(sys_string, "w");
}
```
user: Translate the below assembly code into C programming language:

```asm
<measurement_open_html_table_pipe>:
  endbr64
  push   %rbp
  mov    $0x32,%edx
  lea    D28(%rip),%rsi
  lea    D31(%rip),%r9
  mov    $0x7c,%r8d
  lea    D38(%rip),%rcx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <popen@plt>
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x410,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
type_guessed: string
name: disassemble_data
arguments: data_tag: D31
type_guessed: string
name: disassemble_data
arguments: data_tag: D38
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D28: queue_top_bottom_lines.e %d |html_table.e '' '%s' '%c' '%s'

tool: D31: left,left,left,left,right

tool: D38: station,datatype,measurement_date,measurement_time,measurement_value

tool: D7: w

assistant: ```c
FILE *measurement_open_html_table_pipe(void) {
  char sys_string[1024];
  char *heading_comma_string;
  char *justify_string;
  heading_comma_string = "station,datatype,measurement_date,measurement_time,measurement_value";
  justify_string = "left,left,left,left,right";
  sprintf(sys_string,
          "queue_top_bottom_lines.e %d |"
          "html_table.e '' '%s' '%c' '%s'",
          50, heading_comma_string, '|', justify_string);
  return popen(sys_string, "w");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<autostart_disk_cook_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L21:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa0,%al
  jne    L37
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <lib_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <lib_free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L18
L37:
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L21
  nop
L18:
  nop
  leave
  ret
```

assistant: ```c
void autostart_disk_cook_name(char **name) {
  unsigned int pos;
  pos = 0;
  while ((*name)[pos] != '\0') {
    if (((unsigned char)((*name)[pos])) == 0xa0) {
      char *ptr;
      ptr = lib_malloc(pos + 1);
      memcpy(ptr, *name, pos);
      ptr[pos] = '\0';
      lib_free(*name);
      *name = ptr;
      break;
    }
    pos++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<autostart_disk_cook_name>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L33
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L3:
  cmp    $0xa0,%al
  je     L16
  add    $0x1,%ebx
  mov    %ebx,%ebp
  movzbl (%rdx,%rbp,1),%eax
  test   %al,%al
  jne    L3
  jmp    L27
L16:
  lea    0x1(%rbx),%edi
  call   <lib_malloc@plt>
  mov    %rax,%r13
  mov    %ebx,%edx
  mov    (%r12),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
  mov    (%r12),%rdi
  call   <lib_free@plt>
  mov    %r13,(%r12)
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  ret
```

assistant: ```c
void autostart_disk_cook_name(char **name) {
  unsigned int pos;
  pos = 0;
  while ((*name)[pos] != '\0') {
    if (((unsigned char)((*name)[pos])) == 0xa0) {
      char *ptr;
      ptr = lib_malloc(pos + 1);
      memcpy(ptr, *name, pos);
      ptr[pos] = '\0';
      lib_free(*name);
      *name = ptr;
      break;
    }
    pos++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<autostart_disk_cook_name>:
  endbr64
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L22
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax)
L12:
  mov    %edi,%ebx
  movzbl (%rdx,%rbx,1),%eax
  test   %al,%al
  je     L25
L13:
  mov    %edi,%r12d
  add    $0x1,%edi
  cmp    $0xa0,%al
  jne    L12
  call   <lib_malloc@plt>
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edx
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbx,1)
  mov    0x0(%rbp),%rdi
  call   <lib_free@plt>
  mov    %r13,0x0(%rbp)
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  ret
```

assistant: ```c
void autostart_disk_cook_name(char **name) {
  unsigned int pos;
  pos = 0;
  while ((*name)[pos] != '\0') {
    if (((unsigned char)((*name)[pos])) == 0xa0) {
      char *ptr;
      ptr = lib_malloc(pos + 1);
      memcpy(ptr, *name, pos);
      ptr[pos] = '\0';
      lib_free(*name);
      *name = ptr;
      break;
    }
    pos++;
  }
}
```