ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<transposer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L23
L19:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L7:
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x4(%rbp),%eax
  cltq
  add    %rsi,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x8(%rbp),%eax
  cltq
  add    %rsi,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  imul   -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x1c(%rbp),%eax
  imul   -0x8(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x4(%rbp),%eax
  cltq
  add    %rsi,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transposer(int *transpose, int size) {
  int i = 0, j;
  for (; i < size - 1; i++) {
    for (j = i + 1; j < size; j++) {
      {
        *(transpose + size * i + j) += *(transpose + size * j + i);
        *(transpose + size * j + i) = *(transpose + size * i + j) - *(transpose + size * j + i);
        *(transpose + size * i + j) -= *(transpose + size * j + i);
      };
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<transposer>:
  endbr64
  cmp    $0x1,%esi
  jle    L11
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r11d
  lea    -0x2(%rsi),%ebp
  add    $0x2,%rbp
  movslq %esi,%rdi
  shl    $0x2,%rdi
  mov    $0x1,%r8d
  mov    $0x0,%r10d
  mov    $0x0,%r9d
  lea    -0x1(%rsi),%r13d
  lea    0x8(%rbx),%r12
L25:
  cmp    %r8d,%r11d
  jle    L35
  movslq %r10d,%rsi
  lea    (%rsi,%r8,1),%rax
  lea    (%rbx,%rax,4),%rdx
  lea    (%r10,%r11,1),%eax
  cltq
  add    %r9,%rax
  lea    (%rbx,%rax,4),%rcx
  mov    %r13d,%eax
  sub    %r8d,%eax
  add    %r9,%rsi
  add    %rsi,%rax
  lea    (%r12,%rax,4),%rsi
L28:
  mov    (%rcx),%eax
  add    (%rdx),%eax
  mov    %eax,(%rdx)
  sub    (%rcx),%eax
  mov    %eax,(%rcx)
  sub    %eax,(%rdx)
  add    $0x4,%rdx
  add    %rdi,%rcx
  cmp    %rsi,%rdx
  jne    L28
L35:
  add    $0x1,%r9
  add    %r11d,%r10d
  add    $0x1,%r8
  cmp    %rbp,%r8
  jne    L25
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  ret
```

assistant: ```c
void transposer(int *transpose, int size) {
  int i = 0, j;
  for (; i < size - 1; i++) {
    for (j = i + 1; j < size; j++) {
      {
        *(transpose + size * i + j) += *(transpose + size * j + i);
        *(transpose + size * j + i) = *(transpose + size * i + j) - *(transpose + size * j + i);
        *(transpose + size * i + j) -= *(transpose + size * j + i);
      };
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transposer>:
  endbr64
  cmp    $0x1,%esi
  jle    L7
  push   %r13
  mov    %rdi,%r11
  movslq %esi,%rdi
  mov    %esi,%r10d
  push   %r12
  shl    $0x2,%rdi
  mov    $0x1,%r8d
  xor    %eax,%eax
  push   %rbp
  xor    %r9d,%r9d
  lea    -0x1(%rsi),%r12d
  lea    0x8(%r11),%rbp
  push   %rbx
  lea    -0x2(%rsi),%ebx
  add    $0x2,%rbx
  nopw   0x0(%rax,%rax,1)
L33:
  cmp    %r8d,%r10d
  jle    L15
  lea    (%rax,%r10,1),%r13d
  movslq %eax,%rsi
  movslq %r13d,%rax
  lea    (%rsi,%r8,1),%rdx
  add    %r9,%rsi
  add    %r9,%rax
  lea    (%r11,%rdx,4),%rdx
  lea    (%r11,%rax,4),%rcx
  mov    %r12d,%eax
  sub    %r8d,%eax
  add    %rsi,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  nop
L21:
  mov    (%rcx),%eax
  add    (%rdx),%eax
  mov    %eax,(%rdx)
  sub    (%rcx),%eax
  mov    %eax,(%rcx)
  add    %rdi,%rcx
  sub    %eax,(%rdx)
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L21
  add    $0x1,%r8
  add    $0x1,%r9
  mov    %r13d,%eax
  cmp    %rbx,%r8
  jne    L33
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L15:
  lea    (%rax,%r10,1),%r13d
  add    $0x1,%r8
  add    $0x1,%r9
  mov    %r13d,%eax
  cmp    %rbx,%r8
  jne    L33
  jmp    L10
L7:
  ret
```

assistant: ```c
void transposer(int *transpose, int size) {
  int i = 0, j;
  for (; i < size - 1; i++) {
    for (j = i + 1; j < size; j++) {
      {
        *(transpose + size * i + j) += *(transpose + size * j + i);
        *(transpose + size * j + i) = *(transpose + size * i + j) - *(transpose + size * j + i);
        *(transpose + size * i + j) -= *(transpose + size * j + i);
      };
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<transposer>:
  endbr64
  cmp    $0x1,%esi
  jle    L1
  push   %r13
  mov    %rdi,%r11
  movslq %esi,%rdi
  mov    %esi,%r10d
  push   %r12
  shl    $0x2,%rdi
  mov    $0x1,%r8d
  xor    %eax,%eax
  push   %rbp
  xor    %r9d,%r9d
  lea    -0x1(%rsi),%r12d
  lea    0x8(%r11),%rbp
  push   %rbx
  lea    -0x2(%rsi),%ebx
  add    $0x2,%rbx
  nopw   0x0(%rax,%rax,1)
L43:
  cmp    %r8d,%r10d
  jle    L18
  lea    (%r10,%rax,1),%r13d
  movslq %eax,%rsi
  movslq %r13d,%rax
  lea    (%rsi,%r8,1),%rdx
  add    %r9,%rsi
  add    %r9,%rax
  lea    (%r11,%rdx,4),%rdx
  lea    (%r11,%rax,4),%rcx
  mov    %r12d,%eax
  sub    %r8d,%eax
  add    %rsi,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  nop
L6:
  mov    (%rcx),%eax
  add    (%rdx),%eax
  mov    %eax,(%rdx)
  sub    (%rcx),%eax
  mov    %eax,(%rcx)
  add    %rdi,%rcx
  sub    %eax,(%rdx)
  add    $0x4,%rdx
  cmp    %rdx,%rsi
  jne    L6
  add    $0x1,%r8
  add    $0x1,%r9
  mov    %r13d,%eax
  cmp    %rbx,%r8
  jne    L43
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L18:
  lea    (%rax,%r10,1),%r13d
  add    $0x1,%r8
  add    $0x1,%r9
  mov    %r13d,%eax
  cmp    %rbx,%r8
  jne    L43
  jmp    L17
L1:
  ret
```

assistant: ```c
void transposer(int *transpose, int size) {
  int i = 0, j;
  for (; i < size - 1; i++) {
    for (j = i + 1; j < size; j++) {
      {
        *(transpose + size * i + j) += *(transpose + size * j + i);
        *(transpose + size * j + i) = *(transpose + size * i + j) - *(transpose + size * j + i);
        *(transpose + size * i + j) -= *(transpose + size * j + i);
      };
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_split_empty_delim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2c(%rbp)
  movabs $0x61626473616f6f66,%rax
  movabs $0x6967616d64736172,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x63,-0x10(%rbp)
  lea    -0x2c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  lea    D28(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <pl_split@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D47(%rip),%rdx
  mov    %rdx,%rcx
  lea    D33(%rip),%rdx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <assert_equal_str@plt>
  mov    -0x2c(%rbp),%eax
  lea    D19(%rip),%rdx
  mov    %rdx,%rcx
  lea    D33(%rip),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <assert_equal_int@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D47
data_type: string
name: unpack_data
arguments: tag: D33
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: 

tool: D47: Test 1: NULL not returned.

tool: D33: test_split_empty_delim

tool: D19: Test 2: Size is not right.

assistant: ```c
void test_split_empty_delim() {
  int size = 0;
  char the_string[] = "fooasdbarasdmagic";
  char **ret_val;
  ret_val = pl_split(the_string, "", &size);
  assert_equal_str(NULL, (char *)ret_val, "test_split_empty_delim", "Test 1: NULL not returned.");
  assert_equal_int(0, size, "test_split_empty_delim", "Test 2: Size is not right.");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_split_empty_delim>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movabs $0x61626473616f6f66,%rax
  movabs $0x6967616d64736172,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movw   $0x63,0x20(%rsp)
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  lea    D4(%rip),%rsi
  call   <pl_split@plt>
  mov    %rax,%rsi
  lea    D12(%rip),%rcx
  lea    D36(%rip),%rbx
  mov    %rbx,%rdx
  mov    $0x0,%edi
  call   <assert_equal_str@plt>
  lea    D35(%rip),%rcx
  mov    %rbx,%rdx
  mov    0xc(%rsp),%esi
  mov    $0x0,%edi
  call   <assert_equal_int@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string
name: unpack_data
arguments: tag: D36
type_guessed: string
name: unpack_data
arguments: tag: D35
type_guessed: string

tool: 

tool: D12: Test 1: NULL not returned.

tool: D36: test_split_empty_delim

tool: D35: Test 2: Size is not right.

assistant: ```c
void test_split_empty_delim() {
  int size = 0;
  char the_string[] = "fooasdbarasdmagic";
  char **ret_val;
  ret_val = pl_split(the_string, "", &size);
  assert_equal_str(NULL, (char *)ret_val, "test_split_empty_delim", "Test 1: NULL not returned.");
  assert_equal_int(0, size, "test_split_empty_delim", "Test 2: Size is not right.");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_split_empty_delim>:
  endbr64
  push   %r12
  lea    D0(%rip),%rsi
  lea    D23(%rip),%r12
  sub    $0x30,%rsp
  movdqa D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  mov    $0x63,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %ax,0x20(%rsp)
  call   <pl_split@plt>
  xor    %edi,%edi
  lea    D26(%rip),%rcx
  mov    %r12,%rdx
  mov    %rax,%rsi
  call   <assert_equal_str@plt>
  mov    0xc(%rsp),%esi
  xor    %edi,%edi
  mov    %r12,%rdx
  lea    D32(%rip),%rcx
  call   <assert_equal_int@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D23
type_infered: string
name: retrieve_data
arguments: label: D7
type_infered: byte[16]
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D32
type_infered: string

tool: 

tool: D23: test_split_empty_delim

tool: {"D7": [0x66,0x6f,0x6f,0x61,0x73,0x64,0x62,0x61,0x72,0x61,0x73,0x64,0x6d,0x61,0x67,0x69]}

tool: D26: Test 1: NULL not returned.

tool: D32: Test 2: Size is not right.

assistant: ```c
void test_split_empty_delim() {
  int size = 0;
  char the_string[] = "fooasdbarasdmagic";
  char **ret_val;
  ret_val = pl_split(the_string, "", &size);
  assert_equal_str(NULL, (char *)ret_val, "test_split_empty_delim", "Test 1: NULL not returned.");
  assert_equal_int(0, size, "test_split_empty_delim", "Test 2: Size is not right.");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_split_empty_delim>:
  endbr64
  push   %r12
  lea    D32(%rip),%rsi
  lea    D15(%rip),%r12
  sub    $0x30,%rsp
  movdqa D28(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  mov    $0x63,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %ax,0x20(%rsp)
  call   <pl_split@plt>
  xor    %edi,%edi
  lea    D30(%rip),%rcx
  mov    %r12,%rdx
  mov    %rax,%rsi
  call   <assert_equal_str@plt>
  mov    0xc(%rsp),%esi
  xor    %edi,%edi
  mov    %r12,%rdx
  lea    D25(%rip),%rcx
  call   <assert_equal_int@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: byte[16]
name: extract_symbolic_data
arguments: label: D30
type_guessed: string
name: extract_symbolic_data
arguments: label: D25
type_guessed: string

tool: 

tool: D15: test_split_empty_delim

tool: {"D28": [0x66,0x6f,0x6f,0x61,0x73,0x64,0x62,0x61,0x72,0x61,0x73,0x64,0x6d,0x61,0x67,0x69]}

tool: D30: Test 1: NULL not returned.

tool: D25: Test 2: Size is not right.

assistant: ```c
void test_split_empty_delim() {
  int size = 0;
  char the_string[] = "fooasdbarasdmagic";
  char **ret_val;
  ret_val = pl_split(the_string, "", &size);
  assert_equal_str(NULL, (char *)ret_val, "test_split_empty_delim", "Test 1: NULL not returned.");
  assert_equal_int(0, size, "test_split_empty_delim", "Test 2: Size is not right.");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L6
L9:
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%rax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L6:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L9
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D9: %li 

tool: 

assistant: ```c
void printline(long *t) {
  for (; *t; printf("%li ", *t++))
    ;
  puts("");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printline>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L17
  mov    %rdi,%rbx
  lea    D19(%rip),%rbp
L18:
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L18
L17:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string

tool: D19: %li 

tool: 

assistant: ```c
void printline(long *t) {
  for (; *t; printf("%li ", *t++))
    ;
  puts("");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printline>:
  endbr64
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L6
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L4:
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L4
  add    $0x8,%rsp
  lea    D23(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    D23(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D23
type_guessed: string

tool: D3: %li 

tool: 

assistant: ```c
void printline(long *t) {
  for (; *t; printf("%li ", *t++))
    ;
  puts("");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printline>:
  endbr64
  mov    (%rdi),%rsi
  test   %rsi,%rsi
  je     L0
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L5:
  add    $0x8,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    (%rbx),%rsi
  test   %rsi,%rsi
  jne    L5
  add    $0x8,%rsp
  lea    D11(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1060 <puts@plt>
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D11(%rip),%rdi
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D21
type: string
name: disassemble_data
arguments: tag: D11
type: string

tool: D21: %li 

tool: 

assistant: ```c
void printline(long *t) {
  for (; *t; printf("%li ", *t++))
    ;
  puts("");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<list5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <newvec@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *list5(x, y, z, t, u)
int *y, *z, *t, *u;
{
  int *p = newvec(4);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  p[4] = (int)u;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list5>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8,%rbx
  mov    $0x4,%edi
  mov    $0x0,%eax
  call   <newvec@plt>
  cltq
  mov    %r14d,(%rax)
  mov    %r13d,0x4(%rax)
  mov    %r12d,0x8(%rax)
  mov    %ebp,0xc(%rax)
  mov    %ebx,0x10(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *list5(x, y, z, t, u)
int *y, *z, *t, *u;
{
  int *p = newvec(4);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  p[4] = (int)u;
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<list5>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  mov    $0x4,%edi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  call   <newvec@plt>
  cltq
  mov    %r13d,(%rax)
  mov    %r14d,0x4(%rax)
  mov    %r12d,0x8(%rax)
  mov    %ebp,0xc(%rax)
  mov    %ebx,0x10(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *list5(x, y, z, t, u)
int *y, *z, *t, *u;
{
  int *p = newvec(4);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  p[4] = (int)u;
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list5>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  call   <newvec@plt>
  movd   %ebp,%xmm1
  movd   %r13d,%xmm2
  movd   %ebx,%xmm0
  movd   %r12d,%xmm3
  punpckldq %xmm2,%xmm1
  cltq
  punpckldq %xmm3,%xmm0
  mov    %r14d,0x10(%rax)
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rax)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *list5(x, y, z, t, u)
int *y, *z, *t, *u;
{
  int *p = newvec(4);
  p[0] = x;
  p[1] = (int)y;
  p[2] = (int)z;
  p[3] = (int)t;
  p[4] = (int)u;
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<bandsol>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%rbx
  mov    %edx,%r9d
  mov    %ecx,%edi
  lea    (%rdx,%rcx,1),%r11d
  lea    0x1(%r11),%r12d
  test   %r8d,%r8d
  jle    L56
  mov    %rsi,%rdx
  movslq %r12d,%rbp
  shl    $0x3,%rbp
  movslq %r9d,%rax
  lea    (%r10,%rax,8),%rcx
  mov    $0x0,%esi
  mov    %r9d,%r13d
  neg    %r13d
L62:
  mov    %esi,%r14d
  neg    %r14d
  cmp    %esi,%r9d
  cmovl  %r13d,%r14d
  movslq %r14d,%rax
  test   %r14d,%r14d
  jns    L9
L53:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  test   %eax,%eax
  js     L53
L9:
  movsd  (%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%esi
  add    $0x8,%rdx
  add    %rbp,%rcx
  cmp    %esi,%r8d
  jne    L62
L56:
  mov    %r8d,%ebp
  sub    $0x2,%ebp
  js     L47
  movslq %ebp,%rax
  lea    (%rbx,%rax,8),%rdx
  not    %r11d
  movslq %r11d,%r11
  shl    $0x3,%r11
  imul   %ebp,%r12d
  movslq %r12d,%rax
  movslq %r9d,%r9
  add    %r9,%rax
  lea    (%r10,%rax,8),%rcx
  sub    $0x1,%r8d
L5:
  mov    %r8d,%eax
  sub    %ebp,%eax
  cmp    %edi,%eax
  cmovg  %edi,%eax
  test   %eax,%eax
  jle    L63
  lea    0x1(%rax),%esi
  mov    $0x1,%eax
L11:
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  (%rdx,%rax,8),%xmm1
  movsd  (%rdx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L11
L63:
  sub    $0x1,%ebp
  sub    $0x8,%rdx
  add    %r11,%rcx
  cmp    $0xffffffff,%ebp
  jne    L5
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void bandsol(double *a, double *b, int ml, int mr, int n) {
  int i, j, k, r0;
  int mt = ml + mr + 1;
  int m, n1 = n - 1, row;
  for (i = 0; i < n; i++) {
    r0 = i * mt + ml;
    m = ((-ml) > (-i) ? (-ml) : (-i));
    for (j = m; j < 0; j++)
      b[i] += a[r0 + j] * b[i + j];
    b[i] *= a[r0];
  }
  for (row = n1 - 1; row >= 0; row--) {
    m = ((mr) < (n1 - row) ? (mr) : (n1 - row));
    r0 = row * mt + ml;
    for (k = 1; k <= m; k++)
      b[row] = b[row] - a[r0 + k] * b[row + k];
  }
}
```