ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x3e8,%edx
  xor    %esi,%esi
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x3f0(%rsp),%r14
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x3e8,%edx
  xor    %esi,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r12d
  jl     L39
L26:
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <iFunGetLine@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L45
  xor    %eax,%eax
  mov    %r12d,%edx
  lea    D16(%rip),%rdi
  mov    %r14,%rsi
  call   <printf@plt>
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x7e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L39:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    %ebx,%r12d
  call   <iFunCopyString@plt>
  jmp    L26
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string
name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string

tool: D1: string cArrayGet is
%s

tool: D24: Now, please input some words:

tool: D16: The longest line is %s
there %d words in the string.


assistant: ```c
int main(int argc, char **argv) {
  char cArrayGet[1000];
  char cArrayLongest[1000];
  memset(cArrayGet, 0, 1000);
  memset(cArrayLongest, 0, 1000);
  int iLongestLen = 0;
  int iGetLen = 0;
  printf("Now, please input some words:\n");
  while ((iGetLen = iFunGetLine(cArrayGet, 1000)) > 0) {
    printf("string cArrayGet is\n%s", cArrayGet);
    if (iGetLen > iLongestLen) {
      iLongestLen = iGetLen;
      iFunCopyString(cArrayLongest, cArrayGet);
    }
  }
  printf("The longest line is %s\nthere %d words in the string.\n", cArrayLongest, iLongestLen);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <foo@plt>
  leave
  ret
```

assistant: ```c
int main() {
  int a = 5;
  return foo(a);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <foo@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = 5;
  return foo(a);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x5,%edi
  jmp    1050 <foo@plt>
```

assistant: ```c
int main() {
  int a = 5;
  return foo(a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <int_len@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strnew@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L49
  mov    $0x0,%eax
  jmp    L30
L49:
  cmpl   $0x0,-0x24(%rbp)
  jns    L17
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  jmp    L17
L26:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  lea    0x30(%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  subq   $0x1,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
L17:
  mov    -0x24(%rbp),%eax
  sar    $0x1f,%eax
  cltq
  and    $0x1,%eax
  cmp    %rax,-0x10(%rbp)
  ja     L26
  mov    -0x8(%rbp),%rax
L30:
  leave
  ret
```

assistant: ```c
char *ft_itoa(int n) {
  size_t len;
  unsigned int nb;
  char *s;
  len = int_len(n);
  nb = n < 0 ? -n : n;
  if (!(s = ft_strnew(len)))
    return (NULL);
  if (n < 0)
    s[0] = '-';
  while (len > (n < 0 ? 1 : 0)) {
    s[len - 1] = (nb % 10) + '0';
    len--;
    nb /= 10;
  }
  return (s);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_itoa>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  call   <int_len@plt>
  mov    %rax,%r12
  mov    %ebp,%ebx
  neg    %ebx
  cmovs  %ebp,%ebx
  mov    %rax,%rdi
  call   <ft_strnew@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L35
  test   %ebp,%ebp
  js     L49
L32:
  shr    $0x1f,%ebp
  movslq %ebp,%rbp
  cmp    %rbp,%r12
  jbe    L35
  lea    -0x1(%r8,%r12,1),%rdx
  lea    -0x1(%r8,%rbp,1),%rdi
  mov    $0xcccccccd,%esi
L2:
  mov    %ebx,%eax
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,(%rdx)
  mov    %eax,%ebx
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  jne    L2
L35:
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  movb   $0x2d,(%rax)
  jmp    L32
```

assistant: ```c
char *ft_itoa(int n) {
  size_t len;
  unsigned int nb;
  char *s;
  len = int_len(n);
  nb = n < 0 ? -n : n;
  if (!(s = ft_strnew(len)))
    return (NULL);
  if (n < 0)
    s[0] = '-';
  while (len > (n < 0 ? 1 : 0)) {
    s[len - 1] = (nb % 10) + '0';
    len--;
    nb /= 10;
  }
  return (s);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_itoa>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ebp,%ebx
  call   <int_len@plt>
  neg    %ebx
  mov    %rax,%rdi
  cmovs  %ebp,%ebx
  mov    %rax,%r12
  call   <ft_strnew@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L7
  test   %ebp,%ebp
  jns    L23
  movb   $0x2d,(%rax)
L23:
  shr    $0x1f,%ebp
  cmp    %rbp,%r12
  jbe    L7
  lea    -0x1(%r8,%r12,1),%rdx
  lea    -0x1(%r8,%rbp,1),%rdi
  mov    $0xcccccccd,%esi
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %ebx,%eax
  sub    $0x1,%rdx
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rdx)
  mov    %eax,%ebx
  cmp    %rdx,%rdi
  jne    L22
L7:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_itoa(int n) {
  size_t len;
  unsigned int nb;
  char *s;
  len = int_len(n);
  nb = n < 0 ? -n : n;
  if (!(s = ft_strnew(len)))
    return (NULL);
  if (n < 0)
    s[0] = '-';
  while (len > (n < 0 ? 1 : 0)) {
    s[len - 1] = (nb % 10) + '0';
    len--;
    nb /= 10;
  }
  return (s);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_itoa>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ebp,%ebx
  call   <int_len@plt>
  neg    %ebx
  mov    %rax,%rdi
  cmovs  %ebp,%ebx
  mov    %rax,%r12
  call   <ft_strnew@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L30
  test   %ebp,%ebp
  jns    L31
  movb   $0x2d,(%rax)
L31:
  shr    $0x1f,%ebp
  cmp    %rbp,%r12
  jbe    L30
  lea    -0x1(%r8,%r12,1),%rdx
  lea    -0x1(%r8,%rbp,1),%rdi
  mov    $0xcccccccd,%esi
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%eax
  sub    $0x1,%rdx
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%ebx
  add    $0x30,%ebx
  mov    %bl,0x1(%rdx)
  mov    %eax,%ebx
  cmp    %rdx,%rdi
  jne    L2
L30:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *ft_itoa(int n) {
  size_t len;
  unsigned int nb;
  char *s;
  len = int_len(n);
  nb = n < 0 ? -n : n;
  if (!(s = ft_strnew(len)))
    return (NULL);
  if (n < 0)
    s[0] = '-';
  while (len > (n < 0 ? 1 : 0)) {
    s[len - 1] = (nb % 10) + '0';
    len--;
    nb /= 10;
  }
  return (s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<kernel_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <uname@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  mov    $0xffffffff,%eax
  jmp    L23
L18:
  mov    -0x10(%rbp),%eax
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    %rsi,%r8
  lea    D4(%rip),%rsi
  mov    %eax,%edi
  call   <sscanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <KERNEL_VERSION@plt>
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: %d.%d.%d

assistant: ```c
int kernel_version(void) {
  int major, minor, patch;
  struct utsname buf;
  int retval = uname(&buf);
  if (retval)
    return -1;
  sscanf(buf.release, "%d.%d.%d", &major, &minor, &patch);
  return KERNEL_VERSION(major, minor, patch);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kernel_version>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdi
  call   <uname@plt>
  test   %eax,%eax
  jne    L28
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%r8
  lea    D3(%rip),%rsi
  mov    0x14(%rsp),%edi
  call   <sscanf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <KERNEL_VERSION@plt>
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x28,%rsp
  ret
L28:
  mov    $0xffffffff,%eax
  jmp    L24
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d.%d.%d

assistant: ```c
int kernel_version(void) {
  int major, minor, patch;
  struct utsname buf;
  int retval = uname(&buf);
  if (retval)
    return -1;
  sscanf(buf.release, "%d.%d.%d", &major, &minor, &patch);
  return KERNEL_VERSION(major, minor, patch);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kernel_version>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdi
  call   <uname@plt>
  test   %eax,%eax
  jne    L26
  mov    0x14(%rsp),%edi
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  lea    D6(%rip),%rsi
  lea    0x10(%rsp),%r8
  call   <sscanf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <KERNEL_VERSION@plt>
L9:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0xffffffff,%eax
  jmp    L9
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: %d.%d.%d

assistant: ```c
int kernel_version(void) {
  int major, minor, patch;
  struct utsname buf;
  int retval = uname(&buf);
  if (retval)
    return -1;
  sscanf(buf.release, "%d.%d.%d", &major, &minor, &patch);
  return KERNEL_VERSION(major, minor, patch);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kernel_version>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rdi
  call   <uname@plt>
  test   %eax,%eax
  jne    L29
  mov    0x14(%rsp),%edi
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rcx
  lea    D4(%rip),%rsi
  lea    0x10(%rsp),%r8
  call   <sscanf@plt>
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%edi
  call   <KERNEL_VERSION@plt>
L7:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0xffffffff,%eax
  jmp    L7
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: %d.%d.%d

assistant: ```c
int kernel_version(void) {
  int major, minor, patch;
  struct utsname buf;
  int retval = uname(&buf);
  if (retval)
    return -1;
  sscanf(buf.release, "%d.%d.%d", &major, &minor, &patch);
  return KERNEL_VERSION(major, minor, patch);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncmp_diff_length_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D12(%rip),%rax
  mov    %rax,-0x10(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D12
type_infered: string
name: read_data
arguments: tag: D0
type_infered: string

tool: D12: 12345

tool: D0: 123

assistant: ```c
void strncmp_diff_length_2() {
  char *x = "12345";
  char *y = "123";
  clang_analyzer_eval(strncmp(x, y, 5) > 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<strncmp_diff_length_2>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edx
  lea    D12(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  setg   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D10
data_type: string

tool: D12: 123

tool: D10: 12345

assistant: ```c
void strncmp_diff_length_2() {
  char *x = "12345";
  char *y = "123";
  clang_analyzer_eval(strncmp(x, y, 5) > 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strncmp_diff_length_2>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  mov    $0x5,%edx
  lea    D13(%rip),%rsi
  call   <strncmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setg   %dil
  add    $0x8,%rsp
  jmp    1070 <clang_analyzer_eval@plt>
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string
name: read_data
arguments: label: D13
type_infered: string

tool: D2: 12345

tool: D13: 123

assistant: ```c
void strncmp_diff_length_2() {
  char *x = "12345";
  char *y = "123";
  clang_analyzer_eval(strncmp(x, y, 5) > 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmp_diff_length_2>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  mov    $0x5,%edx
  lea    D1(%rip),%rsi
  call   <strncmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  setg   %dil
  add    $0x8,%rsp
  jmp    1070 <clang_analyzer_eval@plt>
```

tool_calls: name: disassemble_data
arguments: label: D17
type: string
name: disassemble_data
arguments: label: D1
type: string

tool: D17: 12345

tool: D1: 123

assistant: ```c
void strncmp_diff_length_2() {
  char *x = "12345";
  char *y = "123";
  clang_analyzer_eval(strncmp(x, y, 5) > 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %al,-0x11(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L20
L35:
  mov    -0x28(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movzbl -0x11(%rbp),%eax
  cmp    %eax,%edx
  jne    L8
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  jmp    L6
L8:
  addq   $0x1,-0x10(%rbp)
L20:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  char *cstr = (char *)str;
  const unsigned char cc = (const unsigned char)c;
  for (size_t i = 0; cstr[i] != '\0'; i++) {
    if (str[i] == cc) {
      return &cstr[i];
    }
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L25
  movzbl %sil,%esi
L26:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L8
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L26
  mov    $0x0,%eax
  ret
L25:
  mov    $0x0,%eax
  ret
L8:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  char *cstr = (char *)str;
  const unsigned char cc = (const unsigned char)c;
  for (size_t i = 0; cstr[i] != '\0'; i++) {
    if (str[i] == cc) {
      return &cstr[i];
    }
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strchr>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L25
  movzbl %sil,%esi
  jmp    L39
  nopl   0x0(%rax)
L29:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L25
L39:
  cmp    %esi,%edx
  jne    L29
  ret
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  char *cstr = (char *)str;
  const unsigned char cc = (const unsigned char)c;
  for (size_t i = 0; cstr[i] != '\0'; i++) {
    if (str[i] == cc) {
      return &cstr[i];
    }
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strchr>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L16
  movzbl %sil,%esi
  jmp    L23
  nopl   0x0(%rax)
L18:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L16
L23:
  cmp    %edx,%esi
  jne    L18
  ret
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strchr(const char *str, int c) {
  char *cstr = (char *)str;
  const unsigned char cc = (const unsigned char)c;
  for (size_t i = 0; cstr[i] != '\0'; i++) {
    if (str[i] == cc) {
      return &cstr[i];
    }
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Unescape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L46
L50:
  cmpb   $0x5c,-0x9(%rbp)
  jne    L58
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  cmp    $0x6e,%eax
  je     L66
  cmp    $0x72,%eax
  je     L18
  jmp    L58
L66:
  movb   $0xa,-0x9(%rbp)
  jmp    L58
L18:
  movb   $0xd,-0x9(%rbp)
  nop
L58:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
L46:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L50
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Unescape(char *p1) {
  char *p2, c;
  p2 = p1;
  while ((c = *p1++) != '\0') {
    if (c == '\\') {
      c = *p1++;
      switch (c) {
      case 'n':
        c = '\n';
        break;
      case 'r':
        c = '\r';
        break;
      }
    }
    *p2++ = c;
  }
  *p2 = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<Unescape>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L30
  mov    %rdi,%rdx
  mov    $0xa,%r8d
  mov    $0xd,%esi
  jmp    L49
L36:
  lea    0x2(%rdi),%rcx
  movzbl 0x1(%rdi),%eax
  cmp    $0x6e,%al
  je     L37
  mov    %rcx,%rdi
  cmp    $0x72,%al
  jne    L21
  mov    %esi,%eax
L21:
  add    $0x1,%rdx
  mov    %al,-0x1(%rdx)
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
L49:
  cmp    $0x5c,%al
  je     L36
  mov    %rcx,%rdi
  jmp    L21
L37:
  mov    %rcx,%rdi
  mov    %r8d,%eax
  jmp    L21
L30:
  mov    %rdi,%rdx
L4:
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
void Unescape(char *p1) {
  char *p2, c;
  p2 = p1;
  while ((c = *p1++) != '\0') {
    if (c == '\\') {
      c = *p1++;
      switch (c) {
      case 'n':
        c = '\n';
        break;
      case 'r':
        c = '\r';
        break;
      }
    }
    *p2++ = c;
  }
  *p2 = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Unescape>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  mov    %rdi,%rdx
  test   %al,%al
  jne    L77
  jmp    L46
  nopl   0x0(%rax)
L1:
  mov    %rcx,%rdi
L3:
  mov    %al,(%rdx)
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L46
L77:
  cmp    $0x5c,%al
  jne    L1
  movzbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rcx
  mov    %rcx,%rdi
  cmp    $0x6e,%al
  je     L67
  cmp    $0x72,%al
  jne    L3
  mov    $0xd,%eax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L46:
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax)
L67:
  mov    $0xa,%eax
  jmp    L3
```

assistant: ```c
void Unescape(char *p1) {
  char *p2, c;
  p2 = p1;
  while ((c = *p1++) != '\0') {
    if (c == '\\') {
      c = *p1++;
      switch (c) {
      case 'n':
        c = '\n';
        break;
      case 'r':
        c = '\r';
        break;
      }
    }
    *p2++ = c;
  }
  *p2 = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Unescape>:
  endbr64
  movzbl (%rdi),%eax
  lea    0x1(%rdi),%rcx
  mov    %rdi,%rdx
  test   %al,%al
  jne    L36
  jmp    L15
  nopl   0x0(%rax)
L39:
  mov    %rcx,%rdi
L79:
  mov    %al,(%rdx)
  movzbl (%rdi),%eax
  add    $0x1,%rdx
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L15
L36:
  cmp    $0x5c,%al
  jne    L39
  movzbl 0x1(%rdi),%eax
  lea    0x2(%rdi),%rcx
  mov    %rcx,%rdi
  cmp    $0x6e,%al
  je     L30
  cmp    $0x72,%al
  jne    L79
  mov    $0xd,%eax
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L15:
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax)
L30:
  mov    $0xa,%eax
  jmp    L79
```

assistant: ```c
void Unescape(char *p1) {
  char *p2, c;
  p2 = p1;
  while ((c = *p1++) != '\0') {
    if (c == '\\') {
      c = *p1++;
      switch (c) {
      case 'n':
        c = '\n';
        break;
      case 'r':
        c = '\r';
        break;
      }
    }
    *p2++ = c;
  }
  *p2 = '\0';
}
```