ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  movss  %xmm0,0x8(%rsp)
  mov    %rsi,%rbx
  mov    $0x0,%eax
  call   <vnormal@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <vcopy@plt>
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  mulsd  D4(%rip),%xmm0
  call   <sincos@plt>
  movsd  0x10(%rsp),%xmm1
  movsd  %xmm1,0x8(%rsp)
  pxor   %xmm0,%xmm0
  cvtsd2ss 0x18(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <vscale@plt>
  pxor   %xmm0,%xmm0
  cvtsd2ss 0x8(%rsp),%xmm0
  movss  %xmm0,0xc(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void axis_to_quat(float *a, float phi, float *q) {
  vnormal(a);
  vcopy(a, q);
  double return_value_sin$1;
  return_value_sin$1 = sin((double)phi / 2.000000);
  vscale(q, (float)return_value_sin$1);
  double return_value_cos$2;
  return_value_cos$2 = cos((double)phi / 2.000000);
  q[(signed long int)3] = (float)return_value_cos$2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <vnormal@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <vcopy@plt>
  movss  0xc(%rsp),%xmm0
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  cvtss2sd %xmm0,%xmm0
  mulsd  D8(%rip),%xmm0
  call   <sincos@plt>
  mov    0x10(%rsp),%rbp
  mov    %rbx,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsd2ss 0x18(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <vscale@plt>
  movq   %rbp,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,0xc(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void axis_to_quat(float *a, float phi, float *q) {
  vnormal(a);
  vcopy(a, q);
  double return_value_sin$1;
  return_value_sin$1 = sin((double)phi / 2.000000);
  vscale(q, (float)return_value_sin$1);
  double return_value_cos$2;
  return_value_cos$2 = cos((double)phi / 2.000000);
  q[(signed long int)3] = (float)return_value_cos$2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<axis_to_quat>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <vnormal@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <vcopy@plt>
  movss  0xc(%rsp),%xmm0
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  cvtss2sd %xmm0,%xmm0
  mulsd  D9(%rip),%xmm0
  call   <sincos@plt>
  mov    0x10(%rsp),%rbp
  mov    %rbx,%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsd2ss 0x18(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <vscale@plt>
  movq   %rbp,%xmm1
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm0
  movss  %xmm0,0xc(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void axis_to_quat(float *a, float phi, float *q) {
  vnormal(a);
  vcopy(a, q);
  double return_value_sin$1;
  return_value_sin$1 = sin((double)phi / 2.000000);
  vscale(q, (float)return_value_sin$1);
  double return_value_cos$2;
  return_value_cos$2 = cos((double)phi / 2.000000);
  q[(signed long int)3] = (float)return_value_cos$2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <printchar@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void printstring(char *buf) {
  int i;
  for (i = 0; i < (int)strlen(buf); i++)
    printchar(buf[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<printstring>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L17
L10:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <printchar@plt>
  add    $0x1,%rbx
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void printstring(char *buf) {
  int i;
  for (i = 0; i < (int)strlen(buf); i++)
    printchar(buf[i]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printstring>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax)
L8:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <printchar@plt>
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void printstring(char *buf) {
  int i;
  for (i = 0; i < (int)strlen(buf); i++)
    printchar(buf[i]);
}
```
user: What is the c source code of the assembly code below:

```asm
<printstring>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L15
  nopl   0x0(%rax)
L2:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <printchar@plt>
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void printstring(char *buf) {
  int i;
  for (i = 0; i < (int)strlen(buf); i++)
    printchar(buf[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_elf_store_u64M>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    -0x10(%rbp),%rdx
  mov    %dl,(%rax)
  shrq   $0x20,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    -0x10(%rbp),%rdx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _elf_store_u64M(unsigned char *to, unsigned long long v) {
  ((((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_elf_store_u64M>:
  endbr64
  mov    %rsi,%rax
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %dl,0x4(%rdi)
  mov    %esi,%edx
  shr    $0x10,%edx
  mov    %dl,0x5(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rdi)
  mov    %sil,0x7(%rdi)
  mov    %rsi,%rdx
  shr    $0x20,%rdx
  shr    $0x38,%rsi
  mov    %sil,(%rdi)
  mov    %rax,%rcx
  shr    $0x30,%rcx
  mov    %cl,0x1(%rdi)
  shr    $0x28,%rax
  mov    %al,0x2(%rdi)
  mov    %dl,0x3(%rdi)
  ret
```

assistant: ```c
void _elf_store_u64M(unsigned char *to, unsigned long long v) {
  ((((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_elf_store_u64M>:
  endbr64
  bswap  %rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void _elf_store_u64M(unsigned char *to, unsigned long long v) {
  ((((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_elf_store_u64M>:
  endbr64
  bswap  %rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void _elf_store_u64M(unsigned char *to, unsigned long long v) {
  ((((char *)(to + 4))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to + 4))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to + 4))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to + 4))[3] = ((unsigned int)((unsigned int)v) >> (0))));
  v >>= 32;
  ((((char *)(to))[0] = ((unsigned int)((unsigned int)v) >> (24))), (((char *)(to))[1] = ((unsigned int)((unsigned int)v) >> (16))), (((char *)(to))[2] = ((unsigned int)((unsigned int)v) >> (8))), (((char *)(to))[3] = ((unsigned int)((unsigned int)v) >> (0))));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L29:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L20:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L29
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D12
type: string

tool: D6: %d

tool: D12: %.2lf


assistant: ```c
int main() {
  int n, i, v;
  double s = 0;
  for (scanf("%d", &n), i = 0; i < n; i++)
    scanf("%d", &v), s += v;
  return 0 * printf("%.2lf\n", s / n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  test   %eax,%eax
  jle    L16
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  mov    $0x0,%ebx
  lea    D7(%rip),%rbp
L3:
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x14(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  mov    0x10(%rsp),%eax
  cmp    %ebx,%eax
  jg     L3
L21:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L21
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D17
type: string

tool: D7: %d

tool: D17: %.2lf


assistant: ```c
int main() {
  int n, i, v;
  double s = 0;
  for (scanf("%d", &n), i = 0; i < n; i++)
    scanf("%d", &v), s += v;
  return 0 * printf("%.2lf\n", s / n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L7
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L22:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  mov    0x10(%rsp),%eax
  add    $0x1,%ebx
  cvtsi2sdl 0x14(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  cmp    %ebx,%eax
  jg     L22
L7:
  pxor   %xmm1,%xmm1
  lea    D12(%rip),%rdi
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D12
data_type: string

tool: D10: %d

tool: D12: %.2lf


assistant: ```c
int main() {
  int n, i, v;
  double s = 0;
  for (scanf("%d", &n), i = 0; i < n; i++)
    scanf("%d", &v), s += v;
  return 0 * printf("%.2lf\n", s / n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  test   %eax,%eax
  jle    L28
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r12
  nopl   0x0(%rax,%rax,1)
L24:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <scanf@plt>
  pxor   %xmm1,%xmm1
  mov    0x10(%rsp),%eax
  add    $0x1,%ebx
  cvtsi2sdl 0x14(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  addsd  %xmm1,%xmm0
  cmp    %ebx,%eax
  jg     L24
L28:
  pxor   %xmm1,%xmm1
  lea    D5(%rip),%rdi
  cvtsi2sd %eax,%xmm1
  mov    $0x1,%eax
  divsd  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
type_infered: string
name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D12: %d

tool: D5: %.2lf


assistant: ```c
int main() {
  int n, i, v;
  double s = 0;
  for (scanf("%d", &n), i = 0; i < n; i++)
    scanf("%d", &v), s += v;
  return 0 * printf("%.2lf\n", s / n);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printDebug>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L5
L7:
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
L5:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void printDebug(const char *tag, int *codes, int codesSize, int MAX_PROXIMITY_CHARS) {
  unsigned char *buf = (unsigned char *)malloc((1 + codesSize) * sizeof(*buf));
  buf[codesSize] = 0;
  while (--codesSize >= 0)
    buf[codesSize] = (unsigned char)codes[codesSize * MAX_PROXIMITY_CHARS];
  ;
  free(buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printDebug>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %ecx,%ebp
  lea    0x1(%rdx),%edi
  call   <malloc@plt>
  mov    %rax,%r8
  movslq %ebx,%rsi
  movb   $0x0,(%rax,%rsi,1)
  mov    %ebx,%eax
  sub    $0x1,%eax
  js     L18
  mov    %ebp,%edi
  neg    %edi
  movslq %edi,%rdi
  shl    $0x2,%rdi
  imul   %eax,%ebp
  movslq %ebp,%rbp
  lea    (%r12,%rbp,4),%rdx
  cltq
  add    %r8,%rax
  sub    $0x2,%rsi
  lea    -0x1(%rbx),%ecx
  sub    %rcx,%rsi
  add    %r8,%rsi
L11:
  mov    (%rdx),%ecx
  mov    %cl,(%rax)
  add    %rdi,%rdx
  sub    $0x1,%rax
  cmp    %rsi,%rax
  jne    L11
L18:
  mov    %r8,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printDebug(const char *tag, int *codes, int codesSize, int MAX_PROXIMITY_CHARS) {
  unsigned char *buf = (unsigned char *)malloc((1 + codesSize) * sizeof(*buf));
  buf[codesSize] = 0;
  while (--codesSize >= 0)
    buf[codesSize] = (unsigned char)codes[codesSize * MAX_PROXIMITY_CHARS];
  ;
  free(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printDebug>:
  endbr64
  push   %r12
  lea    0x1(%rdx),%edi
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <malloc@plt>
  movslq %ebx,%rsi
  movb   $0x0,(%rax,%rsi,1)
  mov    %rax,%r8
  sub    $0x1,%ebx
  js     L13
  mov    %r12d,%edi
  imul   %ebx,%r12d
  movslq %ebx,%rax
  sub    $0x2,%rsi
  neg    %edi
  mov    %ebx,%ebx
  add    %r8,%rax
  movslq %edi,%rdi
  sub    %rbx,%rsi
  movslq %r12d,%r12
  shl    $0x2,%rdi
  add    %r8,%rsi
  lea    0x0(%rbp,%r12,4),%rcx
  nopl   0x0(%rax)
L3:
  mov    (%rcx),%edx
  sub    $0x1,%rax
  add    %rdi,%rcx
  mov    %dl,0x1(%rax)
  cmp    %rsi,%rax
  jne    L3
L13:
  pop    %rbx
  mov    %r8,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
```

assistant: ```c
void printDebug(const char *tag, int *codes, int codesSize, int MAX_PROXIMITY_CHARS) {
  unsigned char *buf = (unsigned char *)malloc((1 + codesSize) * sizeof(*buf));
  buf[codesSize] = 0;
  while (--codesSize >= 0)
    buf[codesSize] = (unsigned char)codes[codesSize * MAX_PROXIMITY_CHARS];
  ;
  free(buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printDebug>:
  endbr64
  push   %r12
  lea    0x1(%rdx),%edi
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rsi,%rbx
  call   <malloc@plt>
  movslq %ebp,%rsi
  movb   $0x0,(%rax,%rsi,1)
  mov    %rax,%rdi
  sub    $0x1,%ebp
  js     L25
  cmp    $0x1,%r12d
  jne    L8
  movslq %ebp,%rax
  sub    $0x2,%rsi
  mov    %ebp,%ebp
  mov    %rdi,%rdx
  sub    %rbp,%rsi
  neg    %rdx
  add    %rdi,%rax
  lea    (%rsi,%rdi,1),%rcx
  lea    (%rbx,%rdx,4),%rsi
  nopw   0x0(%rax,%rax,1)
L32:
  mov    (%rsi,%rax,4),%edx
  sub    $0x1,%rax
  mov    %dl,0x1(%rax)
  cmp    %rcx,%rax
  jne    L32
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r12d,%r8d
  imul   %ebp,%r12d
  movslq %ebp,%rax
  sub    $0x2,%rsi
  neg    %r8d
  mov    %ebp,%ebp
  add    %rdi,%rax
  movslq %r8d,%r8
  sub    %rbp,%rsi
  movslq %r12d,%r12
  shl    $0x2,%r8
  add    %rdi,%rsi
  lea    (%rbx,%r12,4),%rcx
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rcx),%edx
  sub    $0x1,%rax
  add    %r8,%rcx
  mov    %dl,0x1(%rax)
  cmp    %rsi,%rax
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
```

assistant: ```c
void printDebug(const char *tag, int *codes, int codesSize, int MAX_PROXIMITY_CHARS) {
  unsigned char *buf = (unsigned char *)malloc((1 + codesSize) * sizeof(*buf));
  buf[codesSize] = 0;
  while (--codesSize >= 0)
    buf[codesSize] = (unsigned char)codes[codesSize * MAX_PROXIMITY_CHARS];
  ;
  free(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fuse_opt_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <find_opt@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int fuse_opt_match(const struct fuse_opt *opts, const char *opt) {
  unsigned dummy;
  return find_opt(opts, opt, &dummy) ? 1 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fuse_opt_match>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <find_opt@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fuse_opt_match(const struct fuse_opt *opts, const char *opt) {
  unsigned dummy;
  return find_opt(opts, opt, &dummy) ? 1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fuse_opt_match>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <find_opt@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fuse_opt_match(const struct fuse_opt *opts, const char *opt) {
  unsigned dummy;
  return find_opt(opts, opt, &dummy) ? 1 : 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fuse_opt_match>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <find_opt@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fuse_opt_match(const struct fuse_opt *opts, const char *opt) {
  unsigned dummy;
  return find_opt(opts, opt, &dummy) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  jmp    L20
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L16
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
  jmp    L20
L16:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int gcd(int a, int b) {
  while (a != b) {
    if (a > b)
      a -= b;
    else
      b -= a;
  }
  return a;
}
```