ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gpio_iic_read>:
  endbr64
  mov    $0xe02000c0,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    (%rdx),%eax
  mov    $0xe02000c4,%ebx
  and    $0xfffffff0,%eax
  or     $0x1,%eax
  mov    %eax,(%rdx)
  mov    (%rbx),%eax
  or     $0x1,%eax
  mov    %eax,(%rbx)
  mov    (%rdx),%eax
  and    $0xfffffff0,%eax
  mov    %eax,(%rdx)
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rbx),%eax
  mov    $0xa,%edi
  or     $0x2,%eax
  mov    %eax,(%rbx)
  call   <delay@plt>
  movzbl (%r12),%eax
  mov    $0xa,%edi
  add    %eax,%eax
  mov    %al,(%r12)
  mov    (%rbx),%ecx
  lea    0x1(%rax),%edx
  and    $0x1,%ecx
  cmovne %edx,%eax
  mov    %al,(%r12)
  mov    (%rbx),%eax
  and    $0xfffffffd,%eax
  mov    %eax,(%rbx)
  call   <delay@plt>
  sub    $0x1,%bpl
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void gpio_iic_read(unsigned char *rbyte) {
  unsigned char i;
  (*((volatile uint32_t *)0xE02000C0)) = ((*((volatile uint32_t *)0xE02000C0)) & 0xfffffff0) | 0x00000001;
  (*((volatile uint32_t *)0xE02000C4)) |= 1 << 0x00;
  (*((volatile uint32_t *)0xE02000C0)) = ((*((volatile uint32_t *)0xE02000C0)) & 0xfffffff0);
  for (i = 0; i < 8; i++) {
    (*((volatile uint32_t *)0xE02000C4)) |= 1 << 0x01;
    delay((10));
    (*rbyte) <<= 1;
    if (((*((volatile uint32_t *)0xE02000C4)) & 0x01))
      (*rbyte)++;
    (*((volatile uint32_t *)0xE02000C4)) &= ~(1 << 0x01);
    delay((10));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gpio_iic_read>:
  endbr64
  mov    $0xe02000c0,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    (%rdx),%eax
  mov    $0xe02000c4,%ebx
  and    $0xfffffff0,%eax
  or     $0x1,%eax
  mov    %eax,(%rdx)
  mov    (%rbx),%eax
  or     $0x1,%eax
  mov    %eax,(%rbx)
  mov    (%rdx),%eax
  and    $0xfffffff0,%eax
  mov    %eax,(%rdx)
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%eax
  mov    $0xa,%edi
  or     $0x2,%eax
  mov    %eax,(%rbx)
  call   <delay@plt>
  movzbl (%r12),%eax
  add    %eax,%eax
  mov    %al,(%r12)
  mov    (%rbx),%edx
  and    $0x1,%edx
  je     L9
  add    $0x1,%eax
  mov    %al,(%r12)
L9:
  mov    (%rbx),%eax
  mov    $0xa,%edi
  and    $0xfffffffd,%eax
  mov    %eax,(%rbx)
  call   <delay@plt>
  sub    $0x1,%bpl
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void gpio_iic_read(unsigned char *rbyte) {
  unsigned char i;
  (*((volatile uint32_t *)0xE02000C0)) = ((*((volatile uint32_t *)0xE02000C0)) & 0xfffffff0) | 0x00000001;
  (*((volatile uint32_t *)0xE02000C4)) |= 1 << 0x00;
  (*((volatile uint32_t *)0xE02000C0)) = ((*((volatile uint32_t *)0xE02000C0)) & 0xfffffff0);
  for (i = 0; i < 8; i++) {
    (*((volatile uint32_t *)0xE02000C4)) |= 1 << 0x01;
    delay((10));
    (*rbyte) <<= 1;
    if (((*((volatile uint32_t *)0xE02000C4)) & 0x01))
      (*rbyte)++;
    (*((volatile uint32_t *)0xE02000C4)) &= ~(1 << 0x01);
    delay((10));
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ltrimext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %esi,%eax
  mov    %al,-0x12c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0xfa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x128(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x114(%rbp)
  movl   $0x0,-0x118(%rbp)
  jmp    L68
L6:
  mov    -0x118(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x12c(%rbp)
  je     L44
  cmpl   $0x0,-0x118(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L29
L27:
  mov    -0x114(%rbp),%eax
  sub    -0x118(%rbp),%eax
  mov    %eax,%edx
  mov    -0x118(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x128(%rbp),%rax
  add    %rax,%rcx
  lea    -0x110(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x114(%rbp),%eax
  sub    -0x118(%rbp),%eax
  mov    %eax,%edx
  lea    -0x110(%rbp),%rcx
  mov    -0x128(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x114(%rbp),%eax
  sub    -0x118(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x128(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L57
L44:
  nop
  addl   $0x1,-0x118(%rbp)
L68:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jl     L6
L57:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int ltrimext(char *Pts, char c) {
  int i, j;
  char s[250];
  memset(s, 0, sizeof(s));
  j = strlen(Pts);
  for (i = 0; i < j; i++) {
    if (Pts[i] == c)
      continue;
    else {
      if (i == 0)
        return 0;
      memcpy(s, Pts + i, j - i);
      memcpy(Pts, s, j - i);
      Pts[j - i] = 0;
      break;
    }
  }
  return (strlen(s));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ltrimext>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xfa,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L12
  mov    %rbp,%rcx
  mov    $0x0,%edx
L49:
  mov    %rcx,%rsi
  cmp    %bl,(%rcx)
  je     L2
  test   %edx,%edx
  je     L43
  sub    %edx,%eax
  mov    %eax,%ebx
  mov    %rsp,%r12
  mov    %eax,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
L12:
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
L43:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    %edx,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  add    $0x1,%edx
  add    $0x1,%rcx
  cmp    %edx,%eax
  jne    L49
  jmp    L12
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ltrimext(char *Pts, char c) {
  int i, j;
  char s[250];
  memset(s, 0, sizeof(s));
  j = strlen(Pts);
  for (i = 0; i < j; i++) {
    if (Pts[i] == c)
      continue;
    else {
      if (i == 0)
        return 0;
      memcpy(s, Pts + i, j - i);
      memcpy(Pts, s, j - i);
      Pts[j - i] = 0;
      break;
    }
  }
  return (strlen(s));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ltrimext>:
  endbr64
  push   %r12
  mov    $0xfa,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L25
  mov    %rbp,%rsi
  xor    %r8d,%r8d
L3:
  cmp    %bl,(%rsi)
  je     L53
  test   %r8d,%r8d
  jne    L57
L66:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x110,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  sub    %r8d,%eax
  mov    %r12,%rdi
  mov    %eax,%ebx
  mov    %eax,%edx
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  jmp    L66
  nopl   0x0(%rax)
L53:
  add    $0x1,%r8d
  add    $0x1,%rsi
  cmp    %r8d,%eax
  jne    L3
  jmp    L25
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ltrimext(char *Pts, char c) {
  int i, j;
  char s[250];
  memset(s, 0, sizeof(s));
  j = strlen(Pts);
  for (i = 0; i < j; i++) {
    if (Pts[i] == c)
      continue;
    else {
      if (i == 0)
        return 0;
      memcpy(s, Pts + i, j - i);
      memcpy(Pts, s, j - i);
      Pts[j - i] = 0;
      break;
    }
  }
  return (strlen(s));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ltrimext>:
  endbr64
  push   %r12
  mov    $0xfa,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L53
  mov    %rbp,%rsi
  xor    %r8d,%r8d
L66:
  cmp    %bl,(%rsi)
  je     L15
  test   %r8d,%r8d
  jne    L28
L39:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x110,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  sub    %r8d,%eax
  mov    %r12,%rdi
  mov    %eax,%ebx
  mov    %eax,%edx
  call   <memcpy@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %ebx,%rax
  movb   $0x0,0x0(%rbp,%rax,1)
L53:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  jmp    L39
  nopl   0x0(%rax)
L15:
  add    $0x1,%r8d
  add    $0x1,%rsi
  cmp    %r8d,%eax
  jne    L66
  jmp    L53
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ltrimext(char *Pts, char c) {
  int i, j;
  char s[250];
  memset(s, 0, sizeof(s));
  j = strlen(Pts);
  for (i = 0; i < j; i++) {
    if (Pts[i] == c)
      continue;
    else {
      if (i == 0)
        return 0;
      memcpy(s, Pts + i, j - i);
      memcpy(Pts, s, j - i);
      Pts[j - i] = 0;
      break;
    }
  }
  return (strlen(s));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movw   $0x63,-0xc(%rbp)
  movw   $0x6362,-0xa(%rbp)
  movb   $0x0,-0x19(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x18(%rbp)
  lea    -0xc(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *r;
  char s1[] = "c";
  char s2[] = {'b', 'c'};
  char s3 = 0;
  r = strpbrk(s1, s2);
  assert(r == s1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movw   $0x63,0x4(%rsp)
  movw   $0x6362,0x6(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  cmp    %rax,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char *r;
  char s1[] = "c";
  char s2[] = {'b', 'c'};
  char s3 = 0;
  r = strpbrk(s1, s2);
  assert(r == s1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x6362,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    $0x63,%eax
  lea    0x6(%rsp),%rsi
  mov    %rbx,%rdi
  mov    %ax,0x4(%rsp)
  mov    %dx,0x6(%rsp)
  call   <strpbrk@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char *r;
  char s1[] = "c";
  char s2[] = {'b', 'c'};
  char s3 = 0;
  r = strpbrk(s1, s2);
  assert(r == s1);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x6362,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    $0x63,%eax
  lea    0x6(%rsp),%rsi
  mov    %rbx,%rdi
  mov    %ax,0x4(%rsp)
  mov    %dx,0x6(%rsp)
  call   <strpbrk@plt>
  xor    %edi,%edi
  cmp    %rax,%rbx
  sete   %dil
  call   <assert@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char *r;
  char s1[] = "c";
  char s2[] = {'b', 'c'};
  char s3 = 0;
  r = strpbrk(s1, s2);
  assert(r == s1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_empty>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void make_empty(char stack[], int coun) {
  int o;
  for (o = 0; o < coun; o++) {
    stack[o] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<make_empty>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L13:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L13
L16:
  ret
```

assistant: ```c
void make_empty(char stack[], int coun) {
  int o;
  for (o = 0; o < coun; o++) {
    stack[o] = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<make_empty>:
  endbr64
  test   %esi,%esi
  jle    L7
  movslq %esi,%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void make_empty(char stack[], int coun) {
  int o;
  for (o = 0; o < coun; o++) {
    stack[o] = '\0';
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<make_empty>:
  endbr64
  test   %esi,%esi
  jle    L2
  movslq %esi,%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

assistant: ```c
void make_empty(char stack[], int coun) {
  int o;
  for (o = 0; o < coun; o++) {
    stack[o] = '\0';
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3e8,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <DentroEsfera@plt>
  mov    %eax,-0xc(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0xc(%rbp),%xmm1
  movsd  D5(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x10(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D20
data_type: string
name: disassemble_data
arguments: data_tag: D5
data_type: f64
name: disassemble_data
arguments: data_tag: D10
data_type: string

tool: D20: Ensayos a realizar:  %d


tool: D5: 8

tool: D10: 
Volumen estimado = %g


assistant: ```c
main() {
  const int TOTAL = 1000;
  double Volumen_esfera;
  int dentro;
  printf("Ensayos a realizar:  %d\n", TOTAL);
  dentro = DentroEsfera(TOTAL);
  Volumen_esfera = 8.0 * dentro / TOTAL;
  printf("\nVolumen estimado = %g\n", Volumen_esfera);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x3e8,%edi
  call   <DentroEsfera@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D25(%rip),%xmm0
  divsd  D12(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D38
datatype: string
name: read_data
arguments: data_label: D25
datatype: f64
name: read_data
arguments: data_label: D12
datatype: byte[8]
name: read_data
arguments: data_label: D37
datatype: string

tool: D38: Ensayos a realizar:  %d


tool: D25: 8

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

tool: D37: 
Volumen estimado = %g


assistant: ```c
main() {
  const int TOTAL = 1000;
  double Volumen_esfera;
  int dentro;
  printf("Ensayos a realizar:  %d\n", TOTAL);
  dentro = DentroEsfera(TOTAL);
  Volumen_esfera = 8.0 * dentro / TOTAL;
  printf("\nVolumen estimado = %g\n", Volumen_esfera);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x3e8,%edi
  call   <DentroEsfera@plt>
  pxor   %xmm0,%xmm0
  lea    D18(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D1(%rip),%xmm0
  divsd  D13(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D12
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D1
datatype: f64
name: read_data
arguments: tag: D13
datatype: byte[8]

tool: D12: Ensayos a realizar:  %d


tool: D18: 
Volumen estimado = %g


tool: D1: 8

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
main() {
  const int TOTAL = 1000;
  double Volumen_esfera;
  int dentro;
  printf("Ensayos a realizar:  %d\n", TOTAL);
  dentro = DentroEsfera(TOTAL);
  Volumen_esfera = 8.0 * dentro / TOTAL;
  printf("\nVolumen estimado = %g\n", Volumen_esfera);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x3e8,%edi
  call   <DentroEsfera@plt>
  pxor   %xmm0,%xmm0
  lea    D2(%rip),%rdi
  cvtsi2sd %eax,%xmm0
  mulsd  D4(%rip),%xmm0
  divsd  D26(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: f64
name: extract_symbolic_data
arguments: label: D26
type_guessed: byte[8]

tool: D0: Ensayos a realizar:  %d


tool: D2: 
Volumen estimado = %g


tool: D4: 8

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x40,0x8f,0x40]}

assistant: ```c
main() {
  const int TOTAL = 1000;
  double Volumen_esfera;
  int dentro;
  printf("Ensayos a realizar:  %d\n", TOTAL);
  dentro = DentroEsfera(TOTAL);
  Volumen_esfera = 8.0 * dentro / TOTAL;
  printf("\nVolumen estimado = %g\n", Volumen_esfera);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<htmlspecialchars2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  movzbl (%rdi),%eax
  test   %al,%al
  je     L90
  mov    %esi,%ebp
  mov    %rdi,%rbx
  lea    D36(%rip),%r15
  lea    D5(%rip),%r14
  jmp    L48
L51:
  cmp    $0x3e,%al
  jne    L16
  lea    0x4(%rbx),%r13
  mov    %rbx,%rax
  sub    %r12,%rax
  mov    %ebp,%edx
  sub    %eax,%edx
  lea    0x1(%rbx),%rsi
  mov    %r13,%rdi
  call   <memmove@plt>
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x4,%ebp
  mov    %r13,%rbx
  jmp    L29
L33:
  lea    0x4(%rbx),%r13
  mov    %rbx,%rax
  sub    %r12,%rax
  mov    %ebp,%edx
  sub    %eax,%edx
  lea    0x1(%rbx),%rsi
  mov    %r13,%rdi
  call   <memmove@plt>
  mov    $0x4,%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x4,%ebp
  mov    %r13,%rbx
L29:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L64
L48:
  cmp    $0x3c,%al
  je     L33
  jg     L51
  cmp    $0x22,%al
  je     L44
  cmp    $0x26,%al
  jne    L16
  lea    0x5(%rbx),%r13
  mov    %rbx,%rax
  sub    %r12,%rax
  mov    %ebp,%edx
  sub    %eax,%edx
  lea    0x1(%rbx),%rsi
  mov    %r13,%rdi
  call   <memmove@plt>
  mov    $0x5,%edx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x5,%ebp
  mov    %r13,%rbx
  jmp    L29
L44:
  lea    0x6(%rbx),%r13
  mov    %rbx,%rax
  sub    %r12,%rax
  mov    %ebp,%edx
  sub    %eax,%edx
  lea    0x1(%rbx),%rsi
  mov    %r13,%rdi
  call   <memmove@plt>
  mov    $0x6,%edx
  lea    D30(%rip),%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x6,%ebp
  mov    %r13,%rbx
  jmp    L29
L16:
  add    $0x1,%rbx
  jmp    L29
L90:
  mov    %rdi,%rbx
L64:
  mov    %ebx,%eax
  sub    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D36
type: string
name: unpack_data
arguments: data_label: D5
type: string
name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D30
type: string

tool: D36: &lt;

tool: D5: &gt;

tool: D4: &amp;

tool: D30: &quot;

assistant: ```c
int htmlspecialchars2(char *in, int len) {
  char *p = in;
  while (*p) {
    switch (*p) {
    case '&':
      memmove(p + 5, p + 1, len - (p - in));
      memcpy(p, "&amp;", 5);
      p += 5;
      len += 5;
      break;
      ;
    case '<':
      memmove(p + 4, p + 1, len - (p - in));
      memcpy(p, "&lt;", 4);
      p += 4;
      len += 4;
      break;
      ;
    case '>':
      memmove(p + 4, p + 1, len - (p - in));
      memcpy(p, "&gt;", 4);
      p += 4;
      len += 4;
      break;
      ;
    case '"':
      memmove(p + 6, p + 1, len - (p - in));
      memcpy(p, "&quot;", 6);
      p += 6;
      len += 6;
      break;
      ;
    default:
      p++;
      break;
    }
  }
  return p - in;
}
```