ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<basename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,%rax
  mov    -0x18(%rbp),%rbx
  mov    %rbx,%r12
  jmp    L16
L20:
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rdx),%edx
  cmp    $0x2f,%dl
  jne    L16
  mov    %rbx,%r12
L16:
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L20
  sub    $0x1,%rbx
  jmp    L21
L81:
  sub    $0x1,%rbx
L21:
  movzbl (%rbx),%edx
  cmp    $0x2e,%dl
  je     L76
  cmp    %r12,%rbx
  ja     L81
L76:
  movzbl (%rbx),%edx
  cmp    $0x2e,%dl
  jne    L55
  movb   $0x0,(%rbx)
  nop
L73:
  mov    %r12,%rcx
  lea    0x1(%rcx),%r12
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rcx),%ecx
  mov    %cl,(%rdx)
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L73
  movb   $0x2e,(%rbx)
  jmp    L85
L55:
  nop
L32:
  mov    %r12,%rcx
  lea    0x1(%rcx),%r12
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rcx),%ecx
  mov    %cl,(%rdx)
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L32
L85:
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
basename(str, dst) char *str;
register char *dst;
{
  register char *p1 = str;
  register char *p2 = p1;
  while (*p1)
    if (*p1++ == '/')
      p2 = p1;
  p1--;
  while (*p1 != '.' && p1 > p2)
    p1--;
  if (*p1 == '.') {
    *p1 = '\0';
    while (*dst++ = *p2++)
      ;
    *p1 = '.';
  } else
    while (*dst++ = *p2++)
      ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<basename>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L57
  mov    %rdi,%rdx
L84:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  cmove  %rdi,%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L84
L2:
  lea    -0x1(%rdi),%rax
  movzbl -0x1(%rdi),%edi
  cmp    %rdx,%rax
  jbe    L11
  cmp    $0x2e,%dil
  je     L11
L42:
  sub    $0x1,%rax
  movzbl (%rax),%edi
  cmp    %rdx,%rax
  jbe    L11
  cmp    $0x2e,%dil
  jne    L42
L11:
  mov    $0x0,%ecx
  cmp    $0x2e,%dil
  je     L28
L75:
  movzbl (%rdx,%rcx,1),%eax
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  test   %al,%al
  jne    L75
  ret
L57:
  mov    %rdi,%rdx
  jmp    L2
L28:
  movb   $0x0,(%rax)
L15:
  movzbl (%rdx,%rcx,1),%edi
  mov    %dil,(%rsi,%rcx,1)
  add    $0x1,%rcx
  test   %dil,%dil
  jne    L15
  movb   $0x2e,(%rax)
  ret
```

assistant: ```c
basename(str, dst) char *str;
register char *dst;
{
  register char *p1 = str;
  register char *p2 = p1;
  while (*p1)
    if (*p1++ == '/')
      p2 = p1;
  p1--;
  while (*p1 != '.' && p1 > p2)
    p1--;
  if (*p1 == '.') {
    *p1 = '\0';
    while (*dst++ = *p2++)
      ;
    *p1 = '.';
  } else
    while (*dst++ = *p2++)
      ;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<basename>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L82
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %rdi,%rax
  add    $0x1,%rdi
  cmp    $0x2f,%cl
  movzbl (%rdi),%ecx
  cmove  %rdi,%rdx
  test   %cl,%cl
  jne    L32
L60:
  cmpb   $0x2e,-0x1(%rdi)
  je     L20
  cmp    %rdx,%rax
  ja     L65
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L9:
  cmp    %rdx,%rax
  je     L57
L65:
  sub    $0x1,%rax
  cmpb   $0x2e,(%rax)
  jne    L9
L20:
  movb   $0x0,(%rax)
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L69:
  movzbl (%rdx,%rcx,1),%edi
  mov    %dil,(%rsi,%rcx,1)
  add    $0x1,%rcx
  test   %dil,%dil
  jne    L69
  movb   $0x2e,(%rax)
  xor    %eax,%eax
  ret
  nop
L57:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L88:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L88
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  lea    -0x1(%rdi),%rax
  mov    %rdi,%rdx
  jmp    L60
```

assistant: ```c
basename(str, dst) char *str;
register char *dst;
{
  register char *p1 = str;
  register char *p2 = p1;
  while (*p1)
    if (*p1++ == '/')
      p2 = p1;
  p1--;
  while (*p1 != '.' && p1 > p2)
    p1--;
  if (*p1 == '.') {
    *p1 = '\0';
    while (*dst++ = *p2++)
      ;
    *p1 = '.';
  } else
    while (*dst++ = *p2++)
      ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<basename>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L89
  mov    %rdi,%rdx
  jmp    L62
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %ecx,%r8d
L62:
  mov    %rdi,%rax
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  cmp    $0x2f,%r8b
  cmove  %rdi,%rdx
  test   %cl,%cl
  jne    L53
L79:
  cmp    $0x2e,%r8b
  je     L55
  cmp    %rdx,%rax
  ja     L43
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L94:
  cmp    %rdx,%rax
  je     L93
L43:
  sub    $0x1,%rax
  cmpb   $0x2e,(%rax)
  jne    L94
L55:
  movb   $0x0,(%rax)
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L46:
  movzbl (%rdx,%rcx,1),%edi
  mov    %dil,(%rsi,%rcx,1)
  add    $0x1,%rcx
  test   %dil,%dil
  jne    L46
  movb   $0x2e,(%rax)
  xor    %eax,%eax
  ret
  nop
L93:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L41:
  movzbl (%rdx,%rax,1),%ecx
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  test   %cl,%cl
  jne    L41
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  movzbl -0x1(%rdi),%r8d
  lea    -0x1(%rdi),%rax
  mov    %rdi,%rdx
  jmp    L79
```

assistant: ```c
basename(str, dst) char *str;
register char *dst;
{
  register char *p1 = str;
  register char *p2 = p1;
  while (*p1)
    if (*p1++ == '/')
      p2 = p1;
  p1--;
  while (*p1 != '.' && p1 > p2)
    p1--;
  if (*p1 == '.') {
    *p1 = '\0';
    while (*dst++ = *p2++)
      ;
    *p1 = '.';
  } else
    while (*dst++ = *p2++)
      ;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ceil2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x8,-0x4(%rbp)
  jmp    L10
L25:
  shll   -0x4(%rbp)
L10:
  cmpl   $0x1ff,-0x4(%rbp)
  jg     L3
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
L3:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ceil2(int size) {
  int temp = 8;
  while (temp < 512 && temp < size) {
    temp = temp * 2;
  }
  return temp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ceil2>:
  endbr64
  cmp    $0x8,%edi
  jle    L1
  mov    $0x8,%eax
L21:
  add    %eax,%eax
  cmp    $0x1ff,%eax
  jg     L17
  cmp    %eax,%edi
  jg     L21
  ret
L1:
  mov    $0x8,%eax
L17:
  ret
```

assistant: ```c
int ceil2(int size) {
  int temp = 8;
  while (temp < 512 && temp < size) {
    temp = temp * 2;
  }
  return temp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ceil2>:
  endbr64
  mov    $0x8,%eax
  cmp    $0x8,%edi
  jle    L1
  xchg   %ax,%ax
L25:
  add    %eax,%eax
  cmp    $0x1ff,%eax
  jg     L1
  cmp    %eax,%edi
  jg     L25
  ret
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
int ceil2(int size) {
  int temp = 8;
  while (temp < 512 && temp < size) {
    temp = temp * 2;
  }
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ceil2>:
  endbr64
  mov    $0x8,%eax
  cmp    $0x8,%edi
  jle    L1
  xchg   %ax,%ax
L3:
  add    %eax,%eax
  cmp    $0x1ff,%eax
  jg     L1
  cmp    %eax,%edi
  jg     L3
  ret
  xchg   %ax,%ax
L1:
  ret
```

assistant: ```c
int ceil2(int size) {
  int temp = 8;
  while (temp < 512 && temp < size) {
    temp = temp * 2;
  }
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L26:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L8
  mov    -0x14(%rbp),%eax
  xor    %eax,-0x8(%rbp)
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mulX@plt>
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x7,-0x4(%rbp)
  jle    L26
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned mul(unsigned a, unsigned b) {
  unsigned v;
  int i;
  v = 0;
  for (i = 0; i < 8; i++) {
    if (b & (1 << i))
      v ^= a;
    a = mulX(a);
  }
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mul>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x1,%r13d
L9:
  mov    %r13d,%edx
  mov    %ebx,%ecx
  shl    %cl,%edx
  mov    %ebp,%eax
  xor    %edi,%eax
  test   %r12d,%edx
  cmovne %eax,%ebp
  call   <mulX@plt>
  mov    %eax,%edi
  add    $0x1,%ebx
  cmp    $0x8,%ebx
  jne    L9
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned mul(unsigned a, unsigned b) {
  unsigned v;
  int i;
  v = 0;
  for (i = 0; i < 8; i++) {
    if (b & (1 << i))
      v ^= a;
    a = mulX(a);
  }
  return v;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mul>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r12d,%eax
  shl    %cl,%edx
  xor    %edi,%eax
  test   %ebp,%edx
  cmovne %eax,%r12d
  add    $0x1,%ebx
  call   <mulX@plt>
  mov    %eax,%edi
  cmp    $0x8,%ebx
  jne    L3
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned mul(unsigned a, unsigned b) {
  unsigned v;
  int i;
  v = 0;
  for (i = 0; i < 8; i++) {
    if (b & (1 << i))
      v ^= a;
    a = mulX(a);
  }
  return v;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mul>:
  endbr64
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r12d,%eax
  shl    %cl,%edx
  xor    %edi,%eax
  test   %ebp,%edx
  cmovne %eax,%r12d
  add    $0x1,%ebx
  call   <mulX@plt>
  mov    %eax,%edi
  cmp    $0x8,%ebx
  jne    L5
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned mul(unsigned a, unsigned b) {
  unsigned v;
  int i;
  v = 0;
  for (i = 0; i < 8; i++) {
    if (b & (1 << i))
      v ^= a;
    a = mulX(a);
  }
  return v;
}
```
user: Translate the below assembly code into C programming language:

```asm
<DirHasPandPARTS>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x418(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x418(%rbp),%rdx
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <strcpySafe@plt>
  lea    -0x410(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <strcatSafe@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  jne    L29
  mov    $0x0,%eax
  jmp    L20
L29:
  lea    -0x410(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <strcatSafe@plt>
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  jne    L24
  mov    $0x0,%eax
  jmp    L20
L24:
  mov    $0x1,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string

tool: D2: /P

tool: D11: ARTS

assistant: ```c
int DirHasPandPARTS(const char *PossibleLDrawDir) {
  char Str[1024];
  strcpySafe(Str, sizeof(Str), PossibleLDrawDir);
  strcatSafe(Str, sizeof(Str),
             "/"
             "P");
  if (!L3IsDir(Str))
    return 0;
  strcatSafe(Str, sizeof(Str), "ARTS");
  if (!L3IsDir(Str))
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DirHasPandPARTS>:
  endbr64
  push   %rbx
  sub    $0x410,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <strcpySafe@plt>
  lea    D17(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <strcatSafe@plt>
  mov    %rbx,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  jne    L14
L23:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x410,%rsp
  pop    %rbx
  ret
L14:
  lea    D3(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <strcatSafe@plt>
  mov    %rbx,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L23
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type: string
name: read_data
arguments: tag: D3
type: string

tool: D17: /P

tool: D3: ARTS

assistant: ```c
int DirHasPandPARTS(const char *PossibleLDrawDir) {
  char Str[1024];
  strcpySafe(Str, sizeof(Str), PossibleLDrawDir);
  strcatSafe(Str, sizeof(Str),
             "/"
             "P");
  if (!L3IsDir(Str))
    return 0;
  strcatSafe(Str, sizeof(Str), "ARTS");
  if (!L3IsDir(Str))
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DirHasPandPARTS>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0x400,%esi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpySafe@plt>
  mov    %rbp,%rdi
  mov    $0x400,%esi
  lea    D2(%rip),%rdx
  call   <strcatSafe@plt>
  mov    %rbp,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  je     L3
  lea    D13(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <strcatSafe@plt>
  mov    %rbp,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L3:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x410,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D13
type_guessed: string

tool: D2: /P

tool: D13: ARTS

assistant: ```c
int DirHasPandPARTS(const char *PossibleLDrawDir) {
  char Str[1024];
  strcpySafe(Str, sizeof(Str), PossibleLDrawDir);
  strcatSafe(Str, sizeof(Str),
             "/"
             "P");
  if (!L3IsDir(Str))
    return 0;
  strcatSafe(Str, sizeof(Str), "ARTS");
  if (!L3IsDir(Str))
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<DirHasPandPARTS>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0x400,%esi
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpySafe@plt>
  mov    %rbp,%rdi
  mov    $0x400,%esi
  lea    D17(%rip),%rdx
  call   <strcatSafe@plt>
  mov    %rbp,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  je     L4
  lea    D3(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <strcatSafe@plt>
  mov    %rbp,%rdi
  call   <L3IsDir@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L4:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x410,%rsp
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D17: /P

tool: D3: ARTS

assistant: ```c
int DirHasPandPARTS(const char *PossibleLDrawDir) {
  char Str[1024];
  strcpySafe(Str, sizeof(Str), PossibleLDrawDir);
  strcatSafe(Str, sizeof(Str),
             "/"
             "P");
  if (!L3IsDir(Str))
    return 0;
  strcatSafe(Str, sizeof(Str), "ARTS");
  if (!L3IsDir(Str))
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ILibFragmentTextLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  cmp    $0x1,%eax
  je     L5
  mov    -0x1c(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  jmp    L17
L5:
  mov    $0x0,%eax
L17:
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ILibFragmentTextLength(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength) {
  int RetVal = textLength + (((textLength / tokenLength) == 1 ? 0 : (textLength / tokenLength)) * delimiterLength);
  return (RetVal);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ILibFragmentTextLength>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %r8d
  cmp    $0x1,%eax
  mov    $0x0,%edx
  cmove  %edx,%eax
  imul   %ecx,%eax
  add    %esi,%eax
  ret
```

assistant: ```c
int ILibFragmentTextLength(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength) {
  int RetVal = textLength + (((textLength / tokenLength) == 1 ? 0 : (textLength / tokenLength)) * delimiterLength);
  return (RetVal);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ILibFragmentTextLength>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %r8d
  cmp    $0x1,%eax
  je     L2
  imul   %ecx,%eax
  add    %eax,%esi
L2:
  mov    %esi,%eax
  ret
```

assistant: ```c
int ILibFragmentTextLength(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength) {
  int RetVal = textLength + (((textLength / tokenLength) == 1 ? 0 : (textLength / tokenLength)) * delimiterLength);
  return (RetVal);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ILibFragmentTextLength>:
  endbr64
  mov    %esi,%eax
  cltd
  idiv   %r8d
  cmp    $0x1,%eax
  je     L6
  imul   %ecx,%eax
  add    %eax,%esi
L6:
  mov    %esi,%eax
  ret
```

assistant: ```c
int ILibFragmentTextLength(char *text, int textLength, char *delimiter, int delimiterLength, int tokenLength) {
  int RetVal = textLength + (((textLength / tokenLength) == 1 ? 0 : (textLength / tokenLength)) * delimiterLength);
  return (RetVal);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reset_bus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x2,%esi
  mov    $0x3f6,%edi
  call   <outb@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L6:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x270f,-0x4(%rbp)
  jle    L6
  mov    $0x0,%esi
  mov    $0x3f6,%edi
  call   <outb@plt>
  nop
  leave
  ret
```

assistant: ```c
void reset_bus() {
  outb(0x3F6, 0x02);
  int i;
  for (i = 0; i < 10000; i++)
    ;
  outb(0x3F6, 0x0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<reset_bus>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x3f6,%edi
  call   <outb@plt>
  mov    $0x2710,%eax
L8:
  sub    $0x1,%eax
  jne    L8
  mov    $0x0,%esi
  mov    $0x3f6,%edi
  call   <outb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void reset_bus() {
  outb(0x3F6, 0x02);
  int i;
  for (i = 0; i < 10000; i++)
    ;
  outb(0x3F6, 0x0);
}
```
user: What is the c source code of the assembly code below?

```asm
<reset_bus>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x3f6,%edi
  call   <outb@plt>
  xor    %esi,%esi
  mov    $0x3f6,%edi
  add    $0x8,%rsp
  jmp    1050 <outb@plt>
```

assistant: ```c
void reset_bus() {
  outb(0x3F6, 0x02);
  int i;
  for (i = 0; i < 10000; i++)
    ;
  outb(0x3F6, 0x0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<reset_bus>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x3f6,%edi
  call   <outb@plt>
  xor    %esi,%esi
  mov    $0x3f6,%edi
  add    $0x8,%rsp
  jmp    1050 <outb@plt>
```

assistant: ```c
void reset_bus() {
  outb(0x3F6, 0x02);
  int i;
  for (i = 0; i < 10000; i++)
    ;
  outb(0x3F6, 0x0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<astATand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  D44(%rip),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L50
  movsd  D44(%rip),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L50
  movsd  D47(%rip),%xmm0
  jmp    L36
L50:
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L73
  pxor   %xmm0,%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L73
  pxor   %xmm0,%xmm0
  jmp    L36
L73:
  movsd  D0(%rip),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L8
  movsd  D0(%rip),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L8
  movsd  D39(%rip),%xmm0
  jmp    L36
L8:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <atan@plt>
  movsd  D6(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D30(%rip),%xmm1
  divsd  %xmm1,%xmm0
L36:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D44
type_guessed: f32[2]
name: extract_symbolic_data
arguments: tag: D47
type_guessed: f32[2]
name: extract_symbolic_data
arguments: tag: D0
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D39
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D6
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D30
type_guessed: f64

tool: {"D44": [0.0,-1.875]}

tool: {"D47": [0.0,-3.1015625]}

tool: D0: 1

tool: D39: 45

tool: D6: 180

tool: D30: 3.141592653589793

assistant: ```c
double astATand(v) const double v;
{
  if (v == -1.0) {
    return -45.0;
  } else if (v == 0.0) {
    return 0.0;
  } else if (v == 1.0) {
    return 45.0;
  }
  return atan(v) * 180.0 / 3.141592653589793238462643;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<astATand>:
  endbr64
  ucomisd D43(%rip),%xmm0
  jp     L21
  movsd  D16(%rip),%xmm1
  je     L8
L21:
  ucomisd D55(%rip),%xmm0
  jp     L1
  pxor   %xmm1,%xmm1
  je     L8
L1:
  ucomisd D68(%rip),%xmm0
  jp     L3
  movsd  D58(%rip),%xmm1
  je     L8
L3:
  sub    $0x8,%rsp
  call   <atan@plt>
  movapd %xmm0,%xmm1
  mulsd  D3(%rip),%xmm1
  divsd  D62(%rip),%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rsp
  ret
L8:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D43
type_infered: f32[2]
name: unpack_data
arguments: data_tag: D16
type_infered: f32[2]
name: unpack_data
arguments: data_tag: D55
type_infered: f32[2]
name: unpack_data
arguments: data_tag: D68
type_infered: f64
name: unpack_data
arguments: data_tag: D58
type_infered: f64
name: unpack_data
arguments: data_tag: D3
type_infered: f64
name: unpack_data
arguments: data_tag: D62
type_infered: f64

tool: {"D43": [0.0,-1.875]}

tool: {"D16": [0.0,-3.1015625]}

tool: {"D55": [0.0,0.0]}

tool: D68: 1

tool: D58: 45

tool: D3: 180

tool: D62: 3.141592653589793

assistant: ```c
double astATand(v) const double v;
{
  if (v == -1.0) {
    return -45.0;
  } else if (v == 0.0) {
    return 0.0;
  } else if (v == 1.0) {
    return 45.0;
  }
  return atan(v) * 180.0 / 3.141592653589793238462643;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<astATand>:
  endbr64
  ucomisd D32(%rip),%xmm0
  jp     L29
  movsd  D16(%rip),%xmm1
  je     L39
L29:
  pxor   %xmm2,%xmm2
  ucomisd %xmm2,%xmm0
  jp     L43
  pxor   %xmm1,%xmm1
  je     L39
L43:
  ucomisd D15(%rip),%xmm0
  jp     L57
  movsd  D35(%rip),%xmm1
  je     L39
L57:
  sub    $0x8,%rsp
  call   <atan@plt>
  movsd  D2(%rip),%xmm1
  mulsd  %xmm0,%xmm1
  divsd  D41(%rip),%xmm1
  add    $0x8,%rsp
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D32
type_guessed: f32[2]
name: disassemble_data
arguments: tag: D16
type_guessed: f32[2]
name: disassemble_data
arguments: tag: D15
type_guessed: f64
name: disassemble_data
arguments: tag: D35
type_guessed: f64
name: disassemble_data
arguments: tag: D2
type_guessed: f64
name: disassemble_data
arguments: tag: D41
type_guessed: f64

tool: {"D32": [0.0,-1.875]}

tool: {"D16": [0.0,-3.1015625]}

tool: D15: 1

tool: D35: 45

tool: D2: 180

tool: D41: 3.141592653589793

assistant: ```c
double astATand(v) const double v;
{
  if (v == -1.0) {
    return -45.0;
  } else if (v == 0.0) {
    return 0.0;
  } else if (v == 1.0) {
    return 45.0;
  }
  return atan(v) * 180.0 / 3.141592653589793238462643;
}
```