ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_fst>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x53,%al
  je     L57
  jg     L120
  cmp    $0x4d,%al
  je     L52
  cmp    $0x50,%al
  jne    L134
  mov    $0x1,%edx
  mov    $0x2,%ecx
  mov    $0x2,%eax
L93:
  cmpb   $0x4f,(%rdi,%rdx,1)
  jne    L134
  cmpb   $0x50,(%rdi,%rcx,1)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    $0x1,%ecx
  mov    $0x2,%esi
  xor    %eax,%eax
  mov    $0x1,%edx
L137:
  cmpb   $0x4f,(%rdi,%rcx,1)
  jne    L134
  movzbl (%rdi,%rsi,1),%ecx
  cmp    $0x50,%cl
  je     L0
  cmp    $0x54,%cl
  je     L24
L134:
  mov    $0xffffffff,%eax
L0:
  ret
  nopl   0x0(%rax,%rax,1)
L120:
  cmp    $0x54,%al
  jne    L134
  mov    $0x1,%edx
  mov    $0x2,%ecx
  mov    $0x6,%eax
  jmp    L93
  nopl   (%rax)
L57:
  movzbl 0x1(%rdi),%edx
  cmp    $0x4c,%dl
  je     L128
  mov    $0xffffffff,%eax
  cmp    $0x54,%dl
  jne    L0
  mov    $0x2,%edx
  mov    $0x3,%ecx
  mov    $0x5,%eax
  jmp    L93
  nop
L24:
  add    $0x2,%edx
  add    $0x1,%eax
  movslq %edx,%rdx
  cmpb   $0x48,(%rdi,%rdx,1)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L128:
  mov    $0x2,%ecx
  mov    $0x3,%esi
  mov    $0x3,%eax
  mov    $0x2,%edx
  jmp    L137
```

assistant: ```c
int compute_fst(const char *token) {
  int pos = 0;
  int total = 0;
NODE_0:
  pos++;
  switch (token[pos - 1]) {
  case 'P':
    total += 2;
    goto NODE_1;
  case 'T':
    total += 6;
    goto NODE_1;
  case 'S':
    total += 3;
    goto NODE_3;
  case 'M':
    goto NODE_4;
  default:
    return -1;
  }
NODE_1:
  pos++;
  switch (token[pos - 1]) {
  case 'O':
    goto NODE_2;
  default:
    return -1;
  }
NODE_2:
  pos++;
  switch (token[pos - 1]) {
  case 'P':
    goto NODE_7;
  default:
    return -1;
  }
NODE_3:
  pos++;
  switch (token[pos - 1]) {
  case 'T':
    total += 2;
    goto NODE_1;
  case 'L':
    goto NODE_4;
  default:
    return -1;
  }
NODE_4:
  pos++;
  switch (token[pos - 1]) {
  case 'O':
    goto NODE_5;
  default:
    return -1;
  }
NODE_5:
  pos++;
  switch (token[pos - 1]) {
  case 'T':
    total += 1;
    goto NODE_6;
  case 'P':
    goto NODE_7;
  default:
    return -1;
  }
NODE_6:
  pos++;
  switch (token[pos - 1]) {
  case 'H':
    goto NODE_7;
  default:
    return -1;
  }
NODE_7:
  goto END;
END:
  return total;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<compute_fst>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x53,%al
  je     L58
  jg     L41
  cmp    $0x4d,%al
  je     L25
  cmp    $0x50,%al
  jne    L2
  mov    $0x1,%edx
  mov    $0x2,%ecx
  mov    $0x2,%eax
L0:
  cmpb   $0x4f,(%rdi,%rdx,1)
  jne    L2
  cmpb   $0x50,(%rdi,%rcx,1)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    $0x54,%al
  jne    L2
  mov    $0x1,%edx
  mov    $0x2,%ecx
  mov    $0x6,%eax
  jmp    L0
  nopl   (%rax)
L2:
  mov    $0xffffffff,%eax
L61:
  ret
  xchg   %ax,%ax
L25:
  mov    $0x1,%esi
  mov    $0x3,%r8d
  mov    $0x1,%edx
  xor    %eax,%eax
  mov    $0x2,%ecx
L124:
  cmpb   $0x4f,(%rdi,%rdx,1)
  jne    L2
  movzbl (%rdi,%rcx,1),%edx
  cmp    $0x50,%dl
  je     L61
  mov    $0xffffffff,%eax
  cmp    $0x54,%dl
  jne    L61
  cmpb   $0x48,(%rdi,%r8,1)
  cmove  %esi,%eax
  ret
  nopl   0x0(%rax)
L58:
  movzbl 0x1(%rdi),%edx
  cmp    $0x4c,%dl
  je     L63
  mov    $0xffffffff,%eax
  cmp    $0x54,%dl
  jne    L61
  mov    $0x2,%edx
  mov    $0x3,%ecx
  mov    $0x5,%eax
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L63:
  mov    $0x4,%esi
  mov    $0x4,%r8d
  mov    $0x2,%edx
  mov    $0x3,%ecx
  mov    $0x3,%eax
  jmp    L124
```

assistant: ```c
int compute_fst(const char *token) {
  int pos = 0;
  int total = 0;
NODE_0:
  pos++;
  switch (token[pos - 1]) {
  case 'P':
    total += 2;
    goto NODE_1;
  case 'T':
    total += 6;
    goto NODE_1;
  case 'S':
    total += 3;
    goto NODE_3;
  case 'M':
    goto NODE_4;
  default:
    return -1;
  }
NODE_1:
  pos++;
  switch (token[pos - 1]) {
  case 'O':
    goto NODE_2;
  default:
    return -1;
  }
NODE_2:
  pos++;
  switch (token[pos - 1]) {
  case 'P':
    goto NODE_7;
  default:
    return -1;
  }
NODE_3:
  pos++;
  switch (token[pos - 1]) {
  case 'T':
    total += 2;
    goto NODE_1;
  case 'L':
    goto NODE_4;
  default:
    return -1;
  }
NODE_4:
  pos++;
  switch (token[pos - 1]) {
  case 'O':
    goto NODE_5;
  default:
    return -1;
  }
NODE_5:
  pos++;
  switch (token[pos - 1]) {
  case 'T':
    total += 1;
    goto NODE_6;
  case 'P':
    goto NODE_7;
  default:
    return -1;
  }
NODE_6:
  pos++;
  switch (token[pos - 1]) {
  case 'H':
    goto NODE_7;
  default:
    return -1;
  }
NODE_7:
  goto END;
END:
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<absDistinct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L65
L49:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L69
  addl   $0x1,-0xc(%rbp)
  jmp    L65
L69:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L42
  subl   $0x1,-0x8(%rbp)
  jmp    L65
L42:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovs  %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %eax,%ecx
  neg    %ecx
  cmovns %ecx,%eax
  cmp    %eax,%edx
  jle    L74
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L32
L74:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L32:
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L49
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int absDistinct(int A[], int N) {
  int count = 1;
  int left = 0;
  int right = N - 1;
  int cur = max(abs(A[left]), abs(A[right]));
  while (left <= right) {
    if (abs(A[left]) == cur) {
      left++;
    } else if (abs(A[right]) == cur) {
      right--;
    } else {
      if (abs(A[left]) > abs(A[right])) {
        cur = abs(A[left]);
        left++;
      } else {
        cur = abs(A[right]);
        right--;
      }
      count++;
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<absDistinct>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%ebx
  movslq %ebx,%rax
  mov    (%rdi,%rax,4),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    (%rdi),%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  call   <max@plt>
  test   %ebx,%ebx
  js     L63
  mov    $0x0,%esi
  mov    $0x1,%r8d
  jmp    L80
L59:
  add    $0x1,%esi
  jmp    L33
L41:
  sub    $0x1,%ebx
  jmp    L33
L8:
  sub    $0x1,%ebx
  mov    %ecx,%eax
L0:
  add    $0x1,%r8d
L33:
  cmp    %ebx,%esi
  jg     L68
L80:
  movslq %esi,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  cmp    %eax,%edx
  je     L59
  movslq %ebx,%rcx
  mov    0x0(%rbp,%rcx,4),%edi
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  cmp    %eax,%ecx
  je     L41
  cmp    %ecx,%edx
  jle    L8
  add    $0x1,%esi
  mov    %edx,%eax
  jmp    L0
L63:
  mov    $0x1,%r8d
L68:
  mov    %r8d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int absDistinct(int A[], int N) {
  int count = 1;
  int left = 0;
  int right = N - 1;
  int cur = max(abs(A[left]), abs(A[right]));
  while (left <= right) {
    if (abs(A[left]) == cur) {
      left++;
    } else if (abs(A[right]) == cur) {
      right--;
    } else {
      if (abs(A[left]) > abs(A[right])) {
        cur = abs(A[left]);
        left++;
      } else {
        cur = abs(A[right]);
        right--;
      }
      count++;
    }
  }
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<absDistinct>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  movslq %ebx,%rax
  sub    $0x8,%rsp
  mov    (%rdi,%rax,4),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    (%rdi),%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  call   <max@plt>
  test   %ebx,%ebx
  js     L18
  xor    %esi,%esi
  mov    $0x1,%r8d
  jmp    L65
  nopl   0x0(%rax)
L41:
  movslq %ebx,%rcx
  mov    0x0(%rbp,%rcx,4),%edi
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  cmp    %eax,%ecx
  je     L24
  cmp    %ecx,%edx
  jle    L54
  add    $0x1,%esi
  mov    %edx,%eax
L12:
  add    $0x1,%r8d
L84:
  cmp    %esi,%ebx
  jl     L29
L65:
  movslq %esi,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  cmp    %eax,%edx
  jne    L41
  add    $0x1,%esi
  cmp    %esi,%ebx
  jge    L65
L29:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  sub    $0x1,%ebx
  jmp    L84
  nopl   (%rax)
L54:
  sub    $0x1,%ebx
  mov    %ecx,%eax
  jmp    L12
  nop
L18:
  add    $0x8,%rsp
  mov    $0x1,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int absDistinct(int A[], int N) {
  int count = 1;
  int left = 0;
  int right = N - 1;
  int cur = max(abs(A[left]), abs(A[right]));
  while (left <= right) {
    if (abs(A[left]) == cur) {
      left++;
    } else if (abs(A[right]) == cur) {
      right--;
    } else {
      if (abs(A[left]) > abs(A[right])) {
        cur = abs(A[left]);
        left++;
      } else {
        cur = abs(A[right]);
        right--;
      }
      count++;
    }
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<absDistinct>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  movslq %ebx,%rax
  sub    $0x8,%rsp
  mov    (%rdi,%rax,4),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    (%rdi),%eax
  mov    %eax,%edi
  neg    %edi
  cmovs  %eax,%edi
  call   <max@plt>
  test   %ebx,%ebx
  js     L36
  xor    %esi,%esi
  mov    $0x1,%r8d
  jmp    L88
  nopl   0x0(%rax)
L41:
  movslq %ebx,%rcx
  mov    0x0(%rbp,%rcx,4),%edi
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  cmp    %eax,%ecx
  je     L64
  cmp    %ecx,%edx
  jle    L49
  add    $0x1,%esi
  mov    %edx,%eax
L18:
  add    $0x1,%r8d
L55:
  cmp    %esi,%ebx
  jl     L62
L88:
  movslq %esi,%rdx
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %ecx,%edx
  neg    %edx
  cmovs  %ecx,%edx
  cmp    %eax,%edx
  jne    L41
  add    $0x1,%esi
  cmp    %esi,%ebx
  jge    L88
L62:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L64:
  sub    $0x1,%ebx
  jmp    L55
  nopl   (%rax)
L49:
  sub    $0x1,%ebx
  mov    %ecx,%eax
  jmp    L18
  nop
L36:
  add    $0x8,%rsp
  mov    $0x1,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int absDistinct(int A[], int N) {
  int count = 1;
  int left = 0;
  int right = N - 1;
  int cur = max(abs(A[left]), abs(A[right]));
  while (left <= right) {
    if (abs(A[left]) == cur) {
      left++;
    } else if (abs(A[right]) == cur) {
      right--;
    } else {
      if (abs(A[left]) > abs(A[right])) {
        cur = abs(A[left]);
        left++;
      } else {
        cur = abs(A[right]);
        right--;
      }
      count++;
    }
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bubble_sort1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L10
L22:
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L28:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L15
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L15:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L28
  subl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x0,-0x8(%rbp)
  jg     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort1(int a[], int n) {
  int i, j;
  for (i = n - 1; i > 0; i--) {
    for (j = 0; j < i; j++) {
      if (a[j] > a[j + 1])
        (a[j] ^= a[j + 1], a[j + 1] ^= a[j], a[j] ^= a[j + 1]);
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<bubble_sort1>:
  endbr64
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  test   %r8d,%r8d
  jg     L63
  ret
L22:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L64
L65:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L22
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L22
L64:
  sub    $0x1,%r8d
  je     L24
L63:
  test   %r8d,%r8d
  jle    L64
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L65
L24:
  ret
```

assistant: ```c
void bubble_sort1(int a[], int n) {
  int i, j;
  for (i = n - 1; i > 0; i--) {
    for (j = 0; j < i; j++) {
      if (a[j] > a[j + 1])
        (a[j] ^= a[j + 1], a[j + 1] ^= a[j], a[j] ^= a[j + 1]);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort1>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L20
  nopl   (%rax)
L19:
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   (%rax)
L29:
  mov    (%rax),%esi
  mov    0x4(%rax),%ecx
  cmp    %ecx,%esi
  jle    L30
  mov    %esi,0x4(%rax)
  mov    %ecx,(%rax)
L30:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%r8d
  jg     L29
  sub    $0x1,%r8d
  jne    L19
L20:
  ret
```

assistant: ```c
void bubble_sort1(int a[], int n) {
  int i, j;
  for (i = n - 1; i > 0; i--) {
    for (j = 0; j < i; j++) {
      if (a[j] > a[j + 1])
        (a[j] ^= a[j + 1], a[j + 1] ^= a[j], a[j] ^= a[j + 1]);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bubble_sort1>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L5
  nopl   (%rax)
L4:
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   (%rax)
L9:
  mov    (%rax),%esi
  mov    0x4(%rax),%ecx
  cmp    %ecx,%esi
  jle    L22
  mov    %esi,0x4(%rax)
  mov    %ecx,(%rax)
L22:
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%r8d
  jg     L9
  sub    $0x1,%r8d
  jne    L4
L5:
  ret
```

assistant: ```c
void bubble_sort1(int a[], int n) {
  int i, j;
  for (i = n - 1; i > 0; i--) {
    for (j = 0; j < i; j++) {
      if (a[j] > a[j + 1])
        (a[j] ^= a[j + 1], a[j + 1] ^= a[j], a[j] ^= a[j + 1]);
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L5
L12:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L12
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
data_type: string

tool: D4: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int index, sum = 0;
  for (index = 1; index <= argc; index++) {
    sum += atoi(argv[index]);
  }
  printf("%d\n", sum);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L0
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L6:
  mov    0x0(%r13,%rbx,8),%rdi
  call   <atoi@plt>
  add    %eax,%ebp
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L6
L5:
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    $0x0,%ebp
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int index, sum = 0;
  for (index = 1; index <= argc; index++) {
    sum += atoi(argv[index]);
  }
  printf("%d\n", sum);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L27
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  nop
L1:
  mov    0x0(%r13,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <atoi@plt>
  add    %eax,%ebp
  cmp    %ebx,%r12d
  jge    L1
L12:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  xor    %ebp,%ebp
  jmp    L12
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
datatype: string

tool: D4: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int index, sum = 0;
  for (index = 1; index <= argc; index++) {
    sum += atoi(argv[index]);
  }
  printf("%d\n", sum);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L23
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  nop
L21:
  mov    0x0(%r13,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <atoi@plt>
  add    %eax,%ebp
  cmp    %ebx,%r12d
  jge    L21
L22:
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  xor    %ebp,%ebp
  jmp    L22
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d


assistant: ```c
int main(int argc, char const *argv[]) {
  int index, sum = 0;
  for (index = 1; index <= argc; index++) {
    sum += atoi(argv[index]);
  }
  printf("%d\n", sum);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_actual_malloc_address>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <get_malloc_address_location@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void set_actual_malloc_address(void *const mem, const void *const malloc_addr) {
  size_t *const malloc_addr_location = get_malloc_address_location(mem);
  *malloc_addr_location = (size_t)malloc_addr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<set_actual_malloc_address>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <get_malloc_address_location@plt>
  mov    %rbx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void set_actual_malloc_address(void *const mem, const void *const malloc_addr) {
  size_t *const malloc_addr_location = get_malloc_address_location(mem);
  *malloc_addr_location = (size_t)malloc_addr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<set_actual_malloc_address>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <get_malloc_address_location@plt>
  mov    %rbx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void set_actual_malloc_address(void *const mem, const void *const malloc_addr) {
  size_t *const malloc_addr_location = get_malloc_address_location(mem);
  *malloc_addr_location = (size_t)malloc_addr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<set_actual_malloc_address>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <get_malloc_address_location@plt>
  mov    %rbx,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void set_actual_malloc_address(void *const mem, const void *const malloc_addr) {
  size_t *const malloc_addr_location = get_malloc_address_location(mem);
  *malloc_addr_location = (size_t)malloc_addr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cs_ipvec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L42
  cmpq   $0x0,-0x20(%rbp)
  jne    L68
L42:
  mov    $0x0,%eax
  jmp    L25
L68:
  movl   $0x0,-0x4(%rbp)
  jmp    L60
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  cmpq   $0x0,-0x18(%rbp)
  je     L31
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  jmp    L67
L31:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
L67:
  mov    -0x28(%rbp),%rcx
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L60:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L4
  mov    $0x1,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int cs_ipvec(const int *p, const double *b, double *x, int n) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[p ? p[k] : k] = b[k];
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cs_ipvec>:
  endbr64
  test   %rdx,%rdx
  je     L28
  test   %rsi,%rsi
  je     L28
  test   %ecx,%ecx
  jle    L52
  mov    %ecx,%ecx
  mov    $0x0,%eax
  jmp    L24
L12:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%r8,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L0
L24:
  lea    0x0(,%rax,8),%r8
  test   %rdi,%rdi
  je     L12
  movslq (%rdi,%rax,4),%r8
  shl    $0x3,%r8
  jmp    L12
L0:
  mov    $0x1,%eax
  ret
L28:
  mov    $0x0,%eax
  ret
L52:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int cs_ipvec(const int *p, const double *b, double *x, int n) {
  int k;
  if (!x || !b)
    return (0);
  for (k = 0; k < n; k++)
    x[p ? p[k] : k] = b[k];
  return (1);
}
```