ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<jRead_atol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L42
  movl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L42
L36:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L45
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L36
L45:
  cmpl   $0x0,-0xc(%rbp)
  je     L41
  negq   -0x8(%rbp)
L41:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *jRead_atol(char *p, long *result) {
  long x = 0;
  int neg = 0;
  if (*p == '-') {
    neg = 1;
    ++p;
  }
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  if (neg) {
    x = -x;
  }
  *result = x;
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<jRead_atol>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%r8d
  cmpb   $0x2d,(%rdi)
  je     L34
L19:
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%edi
  mov    $0x0,%ecx
  cmp    $0x9,%dil
  ja     L0
L9:
  lea    (%rcx,%rcx,4),%rcx
  movsbl %dl,%edx
  sub    $0x30,%edx
  movslq %edx,%rdx
  lea    (%rdx,%rcx,2),%rcx
  add    $0x1,%rax
  movzbl (%rax),%edx
  lea    -0x30(%rdx),%edi
  cmp    $0x9,%dil
  jbe    L9
L0:
  mov    %rcx,%rdx
  neg    %rdx
  test   %r8d,%r8d
  cmovne %rdx,%rcx
  mov    %rcx,(%rsi)
  ret
L34:
  add    $0x1,%rax
  mov    $0x1,%r8d
  jmp    L19
```

assistant: ```c
char *jRead_atol(char *p, long *result) {
  long x = 0;
  int neg = 0;
  if (*p == '-') {
    neg = 1;
    ++p;
  }
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  if (neg) {
    x = -x;
  }
  *result = x;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jRead_atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L50
  lea    -0x30(%rax),%edx
  xor    %r8d,%r8d
  cmp    $0x9,%dl
  ja     L17
L69:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L58:
  sub    $0x30,%eax
  lea    (%rdx,%rdx,4),%rdx
  add    $0x1,%rdi
  movsbq %al,%rax
  lea    (%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L58
  mov    %rdx,%rax
  neg    %rdx
  test   %r8d,%r8d
  mov    %rdi,%r9
  cmove  %rax,%rdx
L8:
  mov    %rdx,(%rsi)
  mov    %r9,%rax
  ret
  nopl   (%rax)
L50:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r9
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L60
  mov    %r9,%rdi
  mov    $0x1,%r8d
  jmp    L69
L17:
  mov    %rdi,%r9
  xor    %edx,%edx
  jmp    L8
L60:
  xor    %edx,%edx
  jmp    L8
```

assistant: ```c
char *jRead_atol(char *p, long *result) {
  long x = 0;
  int neg = 0;
  if (*p == '-') {
    neg = 1;
    ++p;
  }
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  if (neg) {
    x = -x;
  }
  *result = x;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jRead_atol>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L8
  lea    -0x30(%rax),%edx
  xor    %r8d,%r8d
  cmp    $0x9,%dl
  ja     L69
L56:
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L23:
  sub    $0x30,%eax
  lea    (%rdx,%rdx,4),%rdx
  add    $0x1,%rdi
  movsbq %al,%rax
  lea    (%rax,%rdx,2),%rdx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L23
  mov    %rdx,%rax
  neg    %rdx
  test   %r8d,%r8d
  mov    %rdi,%r9
  cmove  %rax,%rdx
L9:
  mov    %rdx,(%rsi)
  mov    %r9,%rax
  ret
  nopl   (%rax)
L8:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r9
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L30
  mov    %r9,%rdi
  mov    $0x1,%r8d
  jmp    L56
L69:
  mov    %rdi,%r9
  xor    %edx,%edx
  jmp    L9
L30:
  xor    %edx,%edx
  jmp    L9
```

assistant: ```c
char *jRead_atol(char *p, long *result) {
  long x = 0;
  int neg = 0;
  if (*p == '-') {
    neg = 1;
    ++p;
  }
  while (*p >= '0' && *p <= '9') {
    x = (x * 10) + (*p - '0');
    ++p;
  }
  if (neg) {
    x = -x;
  }
  *result = x;
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mem_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <alloc_failed@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *mem_alloc(long nbytes, const char *file, int line) {
  assert(nbytes > 0);
  void *ptr = malloc(nbytes);
  if (ptr == NULL) {
    alloc_failed(file, line);
  }
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_alloc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  test   %rdi,%rdi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
L15:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <alloc_failed@plt>
  jmp    L15
```

assistant: ```c
void *mem_alloc(long nbytes, const char *file, int line) {
  assert(nbytes > 0);
  void *ptr = malloc(nbytes);
  if (ptr == NULL) {
    alloc_failed(file, line);
  }
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mem_alloc>:
  endbr64
  push   %r13
  test   %rdi,%rdi
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  setg   %dil
  push   %rbp
  movzbl %dil,%edi
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
L12:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <alloc_failed@plt>
  jmp    L12
```

assistant: ```c
void *mem_alloc(long nbytes, const char *file, int line) {
  assert(nbytes > 0);
  void *ptr = malloc(nbytes);
  if (ptr == NULL) {
    alloc_failed(file, line);
  }
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mem_alloc>:
  endbr64
  push   %r13
  test   %rdi,%rdi
  mov    %edx,%r13d
  push   %r12
  mov    %rdi,%r12
  setg   %dil
  push   %rbp
  movzbl %dil,%edi
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
L16:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <alloc_failed@plt>
  jmp    L16
```

assistant: ```c
void *mem_alloc(long nbytes, const char *file, int line) {
  assert(nbytes > 0);
  void *ptr = malloc(nbytes);
  if (ptr == NULL) {
    alloc_failed(file, line);
  }
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
datatype: f64
name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D11
datatype: string

tool: D27: 3.14159

tool: D21: %lf

tool: D11: A=%.4lf


assistant: ```c
int main(void) {
  double r;
  double pi = 3.14159;
  scanf("%lf", &r);
  printf("A=%.4lf\n", r * r * pi);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mulsd  %xmm0,%xmm0
  mulsd  D14(%rip),%xmm0
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_infered: string
name: parse_data
arguments: data_tag: D14
type_infered: f64
name: parse_data
arguments: data_tag: D24
type_infered: string

tool: D26: %lf

tool: D14: 3.14159

tool: D24: A=%.4lf


assistant: ```c
int main(void) {
  double r;
  double pi = 3.14159;
  scanf("%lf", &r);
  printf("A=%.4lf\n", r * r * pi);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  lea    D8(%rip),%rdi
  mulsd  %xmm0,%xmm0
  mulsd  D21(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type: string
name: parse_data
arguments: data_label: D8
type: string
name: parse_data
arguments: data_label: D21
type: f64

tool: D25: %lf

tool: D8: A=%.4lf


tool: D21: 3.14159

assistant: ```c
int main(void) {
  double r;
  double pi = 3.14159;
  scanf("%lf", &r);
  printf("A=%.4lf\n", r * r * pi);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  lea    D6(%rip),%rdi
  mulsd  %xmm0,%xmm0
  mulsd  D25(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string
name: retrieve_data
arguments: data_label: D25
datatype: f64

tool: D14: %lf

tool: D6: A=%.4lf


tool: D25: 3.14159

assistant: ```c
int main(void) {
  double r;
  double pi = 3.14159;
  scanf("%lf", &r);
  printf("A=%.4lf\n", r * r * pi);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Rec2020_EOTF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    %edi,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm1,%xmm0
  jbe    L34
  cmpl   $0xa,-0x18(%rbp)
  jne    L20
  movss  D25(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D14(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L38
L20:
  movss  D31(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D7(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
L38:
  movss  -0x4(%rbp),%xmm0
  comiss -0x14(%rbp),%xmm0
  jbe    L0
  movss  -0x14(%rbp),%xmm0
  movss  D37(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  jmp    L49
L0:
  movss  -0x8(%rbp),%xmm0
  movss  D19(%rip),%xmm1
  subss  %xmm1,%xmm0
  addss  -0x14(%rbp),%xmm0
  divss  -0x8(%rbp),%xmm0
  movd   %xmm0,%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L49
L34:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
L49:
  movss  -0xc(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D25
type: f32
name: read_data
arguments: tag: D14
type: f32
name: read_data
arguments: tag: D31
type: f32
name: read_data
arguments: tag: D7
type: f32
name: read_data
arguments: tag: D37
type: f32
name: read_data
arguments: tag: D19
type: byte[4]

tool: D25: 1.099

tool: D14: 0.018

tool: D31: 1.0993

tool: D7: 0.0181

tool: D37: 4.5

tool: {"D19": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float Rec2020_EOTF(float value, int bitdepth) {
  float linear_out;
  if (value > 0) {
    float alpha, beta;
    if (bitdepth == 10) {
      alpha = 1.099;
      beta = 0.018;
    } else {
      alpha = 1.0993;
      beta = 0.0181;
    }
    if (value < beta) {
      linear_out = value / 4.5;
    } else {
      linear_out = pow((value + (alpha - 1)) / alpha, 1 / 0.45);
    }
  } else {
    linear_out = 0;
  }
  return linear_out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Rec2020_EOTF>:
  endbr64
  comiss D36(%rip),%xmm0
  jbe    L10
  cmp    $0xa,%edi
  je     L21
  movss  D20(%rip),%xmm1
  movss  D51(%rip),%xmm2
L18:
  comiss %xmm0,%xmm1
  jbe    L33
  divss  D39(%rip),%xmm0
  ret
L21:
  movss  D13(%rip),%xmm1
  movss  D5(%rip),%xmm2
  jmp    L18
L33:
  sub    $0x8,%rsp
  movaps %xmm2,%xmm1
  subss  D68(%rip),%xmm1
  addss  %xmm1,%xmm0
  divss  %xmm2,%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  add    $0x8,%rsp
  ret
L10:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D36
datatype: byte[4]
name: unpack_data
arguments: data_tag: D20
datatype: f32
name: unpack_data
arguments: data_tag: D51
datatype: f32
name: unpack_data
arguments: data_tag: D39
datatype: f32
name: unpack_data
arguments: data_tag: D13
datatype: f32
name: unpack_data
arguments: data_tag: D5
datatype: f32
name: unpack_data
arguments: data_tag: D68
datatype: byte[4]

tool: {"D36": [0x00,0x00,0x00,0x00]}

tool: D20: 0.0181

tool: D51: 1.0993

tool: D39: 4.5

tool: D13: 0.018

tool: D5: 1.099

tool: {"D68": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float Rec2020_EOTF(float value, int bitdepth) {
  float linear_out;
  if (value > 0) {
    float alpha, beta;
    if (bitdepth == 10) {
      alpha = 1.099;
      beta = 0.018;
    } else {
      alpha = 1.0993;
      beta = 0.0181;
    }
    if (value < beta) {
      linear_out = value / 4.5;
    } else {
      linear_out = pow((value + (alpha - 1)) / alpha, 1 / 0.45);
    }
  } else {
    linear_out = 0;
  }
  return linear_out;
}
```
user: What is the c source code of the assembly code below:

```asm
<Rec2020_EOTF>:
  endbr64
  pxor   %xmm3,%xmm3
  comiss %xmm3,%xmm0
  jbe    L36
  cmp    $0xa,%edi
  je     L26
  movss  D37(%rip),%xmm1
  movss  D43(%rip),%xmm2
  comiss %xmm0,%xmm1
  jbe    L24
L29:
  divss  D49(%rip),%xmm0
  ret
L26:
  movss  D24(%rip),%xmm1
  movss  D52(%rip),%xmm2
  comiss %xmm0,%xmm1
  ja     L29
L24:
  movaps %xmm2,%xmm1
  subss  D33(%rip),%xmm1
  mov    $0x2,%edi
  addss  %xmm1,%xmm0
  divss  %xmm2,%xmm0
  jmp    1050 <pow@plt>
  nopw   0x0(%rax,%rax,1)
L36:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D37
type_guessed: f32
name: retrieve_data
arguments: tag: D43
type_guessed: f32
name: retrieve_data
arguments: tag: D49
type_guessed: f32
name: retrieve_data
arguments: tag: D24
type_guessed: f32
name: retrieve_data
arguments: tag: D52
type_guessed: f32
name: retrieve_data
arguments: tag: D33
type_guessed: byte[4]

tool: D37: 0.0181

tool: D43: 1.0993

tool: D49: 4.5

tool: D24: 0.018

tool: D52: 1.099

tool: {"D33": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float Rec2020_EOTF(float value, int bitdepth) {
  float linear_out;
  if (value > 0) {
    float alpha, beta;
    if (bitdepth == 10) {
      alpha = 1.099;
      beta = 0.018;
    } else {
      alpha = 1.0993;
      beta = 0.0181;
    }
    if (value < beta) {
      linear_out = value / 4.5;
    } else {
      linear_out = pow((value + (alpha - 1)) / alpha, 1 / 0.45);
    }
  } else {
    linear_out = 0;
  }
  return linear_out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Rec2020_EOTF>:
  endbr64
  pxor   %xmm4,%xmm4
  comiss %xmm4,%xmm0
  jbe    L39
  cmp    $0xa,%edi
  je     L35
  movss  D25(%rip),%xmm1
  movss  D64(%rip),%xmm3
  movss  D23(%rip),%xmm2
  comiss %xmm0,%xmm1
  jbe    L24
L10:
  divss  D54(%rip),%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  movss  D12(%rip),%xmm1
  movss  D13(%rip),%xmm3
  movss  D27(%rip),%xmm2
  comiss %xmm0,%xmm1
  ja     L10
L24:
  addss  %xmm3,%xmm0
  mov    $0x2,%edi
  divss  %xmm2,%xmm0
  jmp    1050 <pow@plt>
  nop
L39:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_tag: D25
type: f32
name: read_data
arguments: data_tag: D64
type: byte[4]
name: read_data
arguments: data_tag: D23
type: f32
name: read_data
arguments: data_tag: D54
type: f32
name: read_data
arguments: data_tag: D12
type: f32
name: read_data
arguments: data_tag: D13
type: byte[4]
name: read_data
arguments: data_tag: D27
type: f32

tool: D25: 0.0181

tool: {"D64": [0xd0,0x5d,0xcb,0x3d]}

tool: D23: 1.0993

tool: D54: 4.5

tool: D12: 0.018

tool: {"D13": [0x80,0xc0,0xca,0x3d]}

tool: D27: 1.099

assistant: ```c
float Rec2020_EOTF(float value, int bitdepth) {
  float linear_out;
  if (value > 0) {
    float alpha, beta;
    if (bitdepth == 10) {
      alpha = 1.099;
      beta = 0.018;
    } else {
      alpha = 1.0993;
      beta = 0.0181;
    }
    if (value < beta) {
      linear_out = value / 4.5;
    } else {
      linear_out = pow((value + (alpha - 1)) / alpha, 1 / 0.45);
    }
  } else {
    linear_out = 0;
  }
  return linear_out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<alloc_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *alloc_(size_t sz) {
  void *allocated_memory = malloc(sz);
  assert(allocated_memory != NULL);
  return allocated_memory;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<alloc_>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *alloc_(size_t sz) {
  void *allocated_memory = malloc(sz);
  assert(allocated_memory != NULL);
  return allocated_memory;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alloc_>:
  endbr64
  push   %r12
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *alloc_(size_t sz) {
  void *allocated_memory = malloc(sz);
  assert(allocated_memory != NULL);
  return allocated_memory;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_>:
  endbr64
  push   %r12
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%r12
  setne  %dil
  call   <assert@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *alloc_(size_t sz) {
  void *allocated_memory = malloc(sz);
  assert(allocated_memory != NULL);
  return allocated_memory;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<MIC_vAppend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L6
L0:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <s_vAppendByte@plt>
  subl   $0x1,-0xc(%rbp)
L6:
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void MIC_vAppend(unsigned char *src, unsigned int nBytes) {
  while (nBytes > 0) {
    s_vAppendByte(*src++);
    nBytes--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MIC_vAppend>:
  endbr64
  test   %esi,%esi
  je     L4
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rbp
L14:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  call   <s_vAppendByte@plt>
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
```

assistant: ```c
void MIC_vAppend(unsigned char *src, unsigned int nBytes) {
  while (nBytes > 0) {
    s_vAppendByte(*src++);
    nBytes--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<MIC_vAppend>:
  endbr64
  test   %esi,%esi
  je     L8
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  call   <s_vAppendByte@plt>
  cmp    %rbp,%rbx
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void MIC_vAppend(unsigned char *src, unsigned int nBytes) {
  while (nBytes > 0) {
    s_vAppendByte(*src++);
    nBytes--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MIC_vAppend>:
  endbr64
  test   %esi,%esi
  je     L6
  push   %rbp
  mov    %esi,%esi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  call   <s_vAppendByte@plt>
  cmp    %rbx,%rbp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void MIC_vAppend(unsigned char *src, unsigned int nBytes) {
  while (nBytes > 0) {
    s_vAppendByte(*src++);
    nBytes--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L5
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
L5:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  if (a = b) {
    b = 0;
    c = 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  if (a = b) {
    b = 0;
    c = 0;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  if (a = b) {
    b = 0;
    c = 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a, b, c;
  if (a = b) {
    b = 0;
    c = 0;
  }
  return 0;
}
```