ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L17:
  mov    %ebx,%esi
  add    $0x1,%ebx
  call   <adder@plt>
  mov    %eax,%edi
  cmp    $0x14,%ebx
  jne    L17
  add    $0xbe,%ebp
  cmp    %eax,%ebp
  je     L0
  xor    %eax,%eax
  call   <abort@plt>
L0:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  int total = argc;
  for (i = 0; i < 20; i++)
    total = adder(total, i);
  if (total != (190 + argc))
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L13:
  mov    %ebx,%esi
  add    $0x1,%ebx
  call   <adder@plt>
  mov    %eax,%edi
  cmp    $0x14,%ebx
  jne    L13
  add    $0xbe,%ebp
  cmp    %eax,%ebp
  je     L19
  xor    %eax,%eax
  call   <abort@plt>
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int i;
  int total = argc;
  for (i = 0; i < 20; i++)
    total = adder(total, i);
  if (total != (190 + argc))
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  lea    D9(%rip),%r13
L41:
  mov    %rsp,%rdi
  mov    $0x3e8,%esi
  call   <getlineuser@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jle    L159
  mov    $0x0,%ebx
  jmp    L95
L104:
  lea    0x2(%rbx),%eax
  movslq %eax,%rdx
  cmpb   $0xa,(%rsp,%rdx,1)
  je     L68
  lea    0x3(%rbx),%eax
  cltq
  lea    -0x1(%rsp),%rdx
L63:
  mov    %eax,%ebx
  add    $0x1,%rax
  cmpb   $0xa,(%rdx,%rax,1)
  jne    L63
L114:
  movslq %ebx,%rax
  cmpb   $0x2a,(%rsp,%rax,1)
  je     L72
L56:
  cmp    $0x1,%r12d
  je     L80
L34:
  movslq %ebx,%rax
  movsbl (%rsp,%rax,1),%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  mov    $0x0,%r12d
L185:
  cmp    %ebp,%ebx
  jge    L41
L95:
  movslq %ebx,%rax
  cmpb   $0x2f,(%rsp,%rax,1)
  jne    L114
  lea    0x1(%rbx),%eax
  cltq
  movzbl (%rsp,%rax,1),%eax
  cmp    $0x2f,%al
  je     L104
  cmp    $0x2a,%al
  jne    L56
  lea    0x2(%rbx),%eax
  movslq %eax,%rdx
  cmpb   $0x2a,(%rsp,%rdx,1)
  je     L58
  mov    %eax,%ebx
L80:
  add    $0x1,%ebx
  mov    $0x1,%r12d
  jmp    L185
L72:
  lea    0x1(%rbx),%eax
  cltq
  cmpb   $0x2f,(%rsp,%rax,1)
  jne    L56
L120:
  add    $0x2,%ebx
  jmp    L34
L75:
  mov    %eax,%ebx
  jmp    L120
L68:
  mov    %eax,%ebx
  jmp    L56
L159:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L112
  mov    $0x0,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  add    $0x3,%ebx
  movslq %ebx,%rbx
  cmpb   $0x2f,(%rsp,%rbx,1)
  je     L75
  mov    %eax,%ebx
  jmp    L80
L112:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: %c

assistant: ```c
int main() {
  int len, t, flag_comment, flag_quote;
  char line[1000];
  flag_comment = 0;
  flag_quote = 0;
  while ((len = getlineuser(line, 1000)) > 0) {
    t = 0;
    while (t < len) {
      if (line[t] == '"') {
        flag_quote = 1;
      }
      if (flag_quote == 1 && line[t] == '"') {
        flag_quote = 0;
      }
      if (flag_quote == 0) {
        if (line[t] == '/' && line[t + 1] == '/') {
          t = t + 2;
          while (line[t] != '\n')
            t++;
        }
        if (line[t] == '/' && line[t + 1] == '*') {
          t = t + 2;
          flag_comment = 1;
        }
        if (line[t] == '*' && line[t + 1] == '/') {
          t = t + 2;
          flag_comment = 0;
        }
        if (flag_comment == 1)
          t++;
        else if (flag_comment == 0) {
          printf("%c", line[t]);
          t++;
        }
      } else if (flag_quote == 1) {
        printf("%c", line[t]);
        t++;
      }
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  lea    D2(%rip),%rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L134:
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getlineuser@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L68
  xor    %eax,%eax
  jmp    L22
  nopl   0x0(%rax)
L46:
  cmp    $0x2a,%dl
  jne    L50
  movslq %r14d,%rdx
  cmpb   $0x2f,(%rsp,%rdx,1)
  je     L159
L50:
  cmp    $0x1,%r13d
  je     L20
L114:
  cltq
  mov    %rbx,%rdi
  xor    %r13d,%r13d
  movsbl (%rsp,%rax,1),%esi
  call   <printf@plt>
  mov    %r14d,%eax
L63:
  cmp    %r12d,%r14d
  jge    L134
L22:
  movslq %eax,%rdx
  lea    0x1(%rax),%r14d
  movzbl (%rsp,%rdx,1),%edx
  cmp    $0x2f,%dl
  jne    L46
  movslq %r14d,%rdx
  movzbl (%rsp,%rdx,1),%edx
  cmp    $0x2f,%dl
  je     L102
  cmp    $0x2a,%dl
  jne    L50
  lea    0x2(%rax),%edx
  lea    0x3(%rax),%r14d
  movslq %edx,%rcx
  cmpb   $0x2a,(%rsp,%rcx,1)
  je     L129
L20:
  mov    %r14d,%eax
  mov    $0x1,%r13d
  jmp    L63
  nopl   0x0(%rax)
L129:
  movslq %r14d,%rax
  cmpb   $0x2f,(%rsp,%rax,1)
  jne    L20
  mov    %edx,%eax
  nopl   0x0(%rax,%rax,1)
L159:
  lea    0x3(%rax),%r14d
  add    $0x2,%eax
  jmp    L114
  nopl   0x0(%rax)
L102:
  lea    0x2(%rax),%edx
  movslq %edx,%rcx
  cmpb   $0xa,(%rsp,%rcx,1)
  je     L32
  lea    0x3(%rax),%edx
  lea    -0x1(%rsp),%rcx
  movslq %edx,%rdx
  nop
L154:
  mov    %edx,%eax
  add    $0x1,%rdx
  cmpb   $0xa,(%rcx,%rdx,1)
  jne    L154
L160:
  lea    0x1(%rax),%r14d
  jmp    L50
  nopl   (%rax)
L68:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L125
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  mov    %edx,%eax
  jmp    L160
L125:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: %c

assistant: ```c
int main() {
  int len, t, flag_comment, flag_quote;
  char line[1000];
  flag_comment = 0;
  flag_quote = 0;
  while ((len = getlineuser(line, 1000)) > 0) {
    t = 0;
    while (t < len) {
      if (line[t] == '"') {
        flag_quote = 1;
      }
      if (flag_quote == 1 && line[t] == '"') {
        flag_quote = 0;
      }
      if (flag_quote == 0) {
        if (line[t] == '/' && line[t + 1] == '/') {
          t = t + 2;
          while (line[t] != '\n')
            t++;
        }
        if (line[t] == '/' && line[t + 1] == '*') {
          t = t + 2;
          flag_comment = 1;
        }
        if (line[t] == '*' && line[t + 1] == '/') {
          t = t + 2;
          flag_comment = 0;
        }
        if (flag_comment == 1)
          t++;
        else if (flag_comment == 0) {
          printf("%c", line[t]);
          t++;
        }
      } else if (flag_quote == 1) {
        printf("%c", line[t]);
        t++;
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  nopl   0x0(%rax,%rax,1)
L44:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlineuser@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  jle    L22
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax)
L46:
  cmp    $0x2a,%sil
  jne    L114
  movslq %ebx,%rdx
  cmpb   $0x2f,(%rsp,%rdx,1)
  je     L132
L114:
  cmp    $0x1,%r14d
  je     L24
L63:
  mov    %rbp,%rdi
  xor    %r14d,%r14d
  call   <printf@plt>
  mov    %ebx,%eax
L65:
  cmp    %r13d,%ebx
  jge    L44
L29:
  movslq %eax,%rdx
  lea    0x1(%rax),%ebx
  movsbl (%rsp,%rdx,1),%esi
  cmp    $0x2f,%sil
  jne    L46
  movslq %ebx,%rdx
  movzbl (%rsp,%rdx,1),%edx
  cmp    $0x2f,%dl
  je     L121
  cmp    $0x2a,%dl
  jne    L114
  lea    0x2(%rax),%edx
  lea    0x3(%rax),%ebx
  movslq %edx,%rcx
  cmpb   $0x2a,(%rsp,%rcx,1)
  je     L80
L24:
  mov    %ebx,%eax
  mov    $0x1,%r14d
  jmp    L65
  nopl   0x0(%rax)
L80:
  movslq %ebx,%rax
  cmpb   $0x2f,(%rsp,%rax,1)
  jne    L24
  mov    %edx,%eax
  nopl   0x0(%rax,%rax,1)
L132:
  lea    0x2(%rax),%edx
  lea    0x3(%rax),%ebx
  movslq %edx,%rdx
  movsbl (%rsp,%rdx,1),%esi
  jmp    L63
  nop
L121:
  lea    0x2(%rax),%ebx
  movslq %ebx,%rdx
  cmpb   $0xa,(%rsp,%rdx,1)
  je     L38
  add    $0x3,%eax
  lea    -0x1(%rsp),%rdx
  cltq
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    %eax,%ebx
  add    $0x1,%rax
  cmpb   $0xa,(%rdx,%rax,1)
  jne    L45
L38:
  add    $0x1,%ebx
  mov    $0xa,%esi
  jmp    L114
  nopl   0x0(%rax)
L22:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x3f0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: %c

assistant: ```c
int main() {
  int len, t, flag_comment, flag_quote;
  char line[1000];
  flag_comment = 0;
  flag_quote = 0;
  while ((len = getlineuser(line, 1000)) > 0) {
    t = 0;
    while (t < len) {
      if (line[t] == '"') {
        flag_quote = 1;
      }
      if (flag_quote == 1 && line[t] == '"') {
        flag_quote = 0;
      }
      if (flag_quote == 0) {
        if (line[t] == '/' && line[t + 1] == '/') {
          t = t + 2;
          while (line[t] != '\n')
            t++;
        }
        if (line[t] == '/' && line[t + 1] == '*') {
          t = t + 2;
          flag_comment = 1;
        }
        if (line[t] == '*' && line[t + 1] == '/') {
          t = t + 2;
          flag_comment = 0;
        }
        if (flag_comment == 1)
          t++;
        else if (flag_comment == 0) {
          printf("%c", line[t]);
          t++;
        }
      } else if (flag_quote == 1) {
        printf("%c", line[t]);
        t++;
      }
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<putchars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jle    L7
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <putchars>
L7:
  nop
  leave
  ret
```

assistant: ```c
void putchars(char *start, int count) {
  if (count > 0) {
    char c = *start;
    putchar(c);
    putchars(start + 1, count - 1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<putchars>:
  endbr64
  test   %esi,%esi
  jg     L4
  ret
L4:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  movsbl (%rdi),%edi
  call   <putchar@plt>
  lea    -0x1(%rbx),%esi
  lea    0x1(%rbp),%rdi
  call   <putchars>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void putchars(char *start, int count) {
  if (count > 0) {
    char c = *start;
    putchar(c);
    putchars(start + 1, count - 1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<putchars>:
  endbr64
  test   %esi,%esi
  jle    L10
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
void putchars(char *start, int count) {
  if (count > 0) {
    char c = *start;
    putchar(c);
    putchars(start + 1, count - 1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putchars>:
  endbr64
  test   %esi,%esi
  jle    L8
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  lea    (%rdi,%rsi,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void putchars(char *start, int count) {
  if (count > 0) {
    char c = *start;
    putchar(c);
    putchars(start + 1, count - 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setkeepalive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  test   %rax,%rax
  je     L16
  mov    $0xffffffff,%eax
  jmp    L6
L16:
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int setkeepalive(int fd) {
  int keepalive = 1;
  if (setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, &keepalive, sizeof(int)) != 0) {
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setkeepalive>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    $0x4,%r8d
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  neg    %rax
  sbb    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int setkeepalive(int fd) {
  int keepalive = 1;
  if (setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, &keepalive, sizeof(int)) != 0) {
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<setkeepalive>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  neg    %rax
  sbb    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int setkeepalive(int fd) {
  int keepalive = 1;
  if (setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, &keepalive, sizeof(int)) != 0) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<setkeepalive>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x4,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rcx
  movl   $0x1,0x4(%rsp)
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  call   <setsockopt@plt>
  neg    %rax
  sbb    %eax,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int setkeepalive(int fd) {
  int keepalive = 1;
  if (setsockopt(fd, SOL_SOCKET, SO_KEEPALIVE, &keepalive, sizeof(int)) != 0) {
    return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<timespec_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    0x10(%rbp),%edx
  mov    0x28(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    $0x3b9aca00,%eax
  jle    L2
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x3b9aca00,%eax
  mov    %eax,-0x20(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  mov    0x18(%rbp),%rcx
  mov    0x30(%rbp),%rdx
  add    %rcx,%rdx
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rcx)
  mov    %rdx,0x8(%rcx)
  mov    -0x10(%rbp),%rax
  mov    %rax,0x10(%rcx)
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec x, struct timespec y) {
  struct timespec ret = {0, 0};
  ret.tv_nsec = x.tv_nsec + y.tv_nsec;
  if (ret.tv_nsec > 1000000000) {
    ret.tv_sec++;
    ret.tv_nsec -= 1000000000;
  }
  ret.tv_sec += x.tv_sec + y.tv_sec;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<timespec_add>:
  endbr64
  mov    %rdi,%rax
  mov    0x20(%rsp),%ecx
  add    0x8(%rsp),%ecx
  mov    $0x0,%esi
  cmp    $0x3b9aca00,%ecx
  jle    L1
  sub    $0x3b9aca00,%ecx
  mov    $0x1,%esi
L1:
  mov    0x28(%rsp),%rdx
  add    0x10(%rsp),%rdx
  add    %rsi,%rdx
  mov    %ecx,(%rax)
  mov    %rdx,0x8(%rax)
  movl   $0x0,0x10(%rax)
  movl   $0x0,0x14(%rax)
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec x, struct timespec y) {
  struct timespec ret = {0, 0};
  ret.tv_nsec = x.tv_nsec + y.tv_nsec;
  if (ret.tv_nsec > 1000000000) {
    ret.tv_sec++;
    ret.tv_nsec -= 1000000000;
  }
  ret.tv_sec += x.tv_sec + y.tv_sec;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<timespec_add>:
  endbr64
  mov    0x20(%rsp),%ecx
  add    0x8(%rsp),%ecx
  mov    %rdi,%rax
  xor    %esi,%esi
  cmp    $0x3b9aca00,%ecx
  jle    L2
  sub    $0x3b9aca00,%ecx
  mov    $0x1,%esi
L2:
  mov    0x28(%rsp),%rdx
  add    0x10(%rsp),%rdx
  mov    %ecx,(%rax)
  add    %rsi,%rdx
  movq   $0x0,0x10(%rax)
  mov    %rdx,0x8(%rax)
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec x, struct timespec y) {
  struct timespec ret = {0, 0};
  ret.tv_nsec = x.tv_nsec + y.tv_nsec;
  if (ret.tv_nsec > 1000000000) {
    ret.tv_sec++;
    ret.tv_nsec -= 1000000000;
  }
  ret.tv_sec += x.tv_sec + y.tv_sec;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timespec_add>:
  endbr64
  mov    0x20(%rsp),%ecx
  add    0x8(%rsp),%ecx
  mov    %rdi,%rax
  xor    %esi,%esi
  cmp    $0x3b9aca00,%ecx
  jle    L8
  sub    $0x3b9aca00,%ecx
  mov    $0x1,%esi
L8:
  mov    0x28(%rsp),%rdx
  add    0x10(%rsp),%rdx
  mov    %ecx,(%rax)
  add    %rsi,%rdx
  movq   $0x0,0x10(%rax)
  mov    %rdx,0x8(%rax)
  ret
```

assistant: ```c
struct timespec timespec_add(struct timespec x, struct timespec y) {
  struct timespec ret = {0, 0};
  ret.tv_nsec = x.tv_nsec + y.tv_nsec;
  if (ret.tv_nsec > 1000000000) {
    ret.tv_sec++;
    ret.tv_nsec -= 1000000000;
  }
  ret.tv_sec += x.tv_sec + y.tv_sec;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_gsub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <make_lookup_tables@plt>
  mov    $0x0,%eax
  call   <init_text@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_gsub() {
  make_lookup_tables();
  init_text();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<init_gsub>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <make_lookup_tables@plt>
  mov    $0x0,%eax
  call   <init_text@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_gsub() {
  make_lookup_tables();
  init_text();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_gsub>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <make_lookup_tables@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <init_text@plt>
```

assistant: ```c
void init_gsub() {
  make_lookup_tables();
  init_text();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<init_gsub>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <make_lookup_tables@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <init_text@plt>
```

assistant: ```c
void init_gsub() {
  make_lookup_tables();
  init_text();
}
```
user: Translate the below assembly code into C programming language:

```asm
<equal_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L18
  mov    $0x0,%eax
  jmp    L1
L18:
  mov    $0x1,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int equal_int(void *ip, void *jp) {
  if (*(int *)ip == *(int *)jp) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<equal_int>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_int(void *ip, void *jp) {
  if (*(int *)ip == *(int *)jp) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<equal_int>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_int(void *ip, void *jp) {
  if (*(int *)ip == *(int *)jp) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<equal_int>:
  endbr64
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int equal_int(void *ip, void *jp) {
  if (*(int *)ip == *(int *)jp) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transfer_YUV888_to_YUV101010>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  shl    $0x10,%eax
  and    $0xffc00000,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shl    $0x6,%eax
  and    $0x3ff000,%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  and    $0xffc,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    %rcx,(%rdx)
  mov    %esi,%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_YUV888_to_YUV101010(unsigned char *(*output), unsigned char *input) {
  uint16_t y_i = ((uint16_t)input[0]) << 8;
  uint16_t u_i = ((uint16_t)input[1]) << 8;
  uint16_t v_i = ((uint16_t)input[2]) << 8;
  {
    uint32_t output_i = ((y_i & 0xffc0) << 16) | ((u_i & 0xffc0) << 6) | ((v_i & 0xffc0) >> 4);
    *(*output)++ = (output_i & 0xff);
    *(*output)++ = (output_i & 0xff00) >> 8;
    *(*output)++ = (output_i & 0xff0000) >> 16;
    *(*output)++ = (output_i & 0xff000000) >> 24;
  };
}
```