user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tabPrintTransform>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x20(%rsp)
  mov    %esi,0x18(%rsp)
  mov    %ecx,0x1c(%rsp)
  test   %edi,%edi
  je     L58
  test   %esi,%esi
  je     L58
  mov    %ecx,%esi
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  mov    %rdx,%r12
  call   <tabprintf@plt>
  mov    0x20(%rsp),%eax
  test   %eax,%eax
  jle    L69
  sub    $0x1,%eax
  movl   $0x0,0x14(%rsp)
  lea    D48(%rip),%r13
  mov    %eax,0x24(%rsp)
  movslq 0x18(%rsp),%rax
  mov    %rax,0x8(%rsp)
  shl    $0x3,%rax
  mov    %rax,0x28(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L20
  mov    0x18(%rsp),%eax
  mov    0x14(%rsp),%edx
  xor    %r15d,%r15d
  lea    D63(%rip),%rbp
  lea    D33(%rip),%rbx
  lea    -0x1(%rax),%r14d
  cmp    %edx,0x24(%rsp)
  je     L114
  nopl   0x0(%rax,%rax,1)
L95:
  movsd  (%r12,%r15,8),%xmm0
  lea    D106(%rip),%rsi
  lea    D62(%rip),%rcx
  movmskpd %xmm0,%eax
  test   $0x1,%al
  lea    D48(%rip),%rax
  cmove  %rax,%rsi
  cmp    %r15d,%r14d
  je     L120
  mov    %r13,%rcx
L120:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    0x8(%rsp),%r15
  jne    L95
L94:
  lea    D56(%rip),%rsi
  lea    D125(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L117:
  mov    0x1c(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <tabprintf@plt>
  addl   $0x1,0x14(%rsp)
  add    0x28(%rsp),%r12
  mov    0x14(%rsp),%eax
  cmp    %eax,0x20(%rsp)
  jne    L45
L69:
  add    $0x38,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L114:
  movsd  (%r12,%r15,8),%xmm0
  lea    D48(%rip),%rsi
  movmskpd %xmm0,%eax
  test   $0x1,%al
  lea    D106(%rip),%rax
  cmovne %rax,%rsi
  mov    %rax,%rcx
  cmp    %r15d,%r14d
  je     L19
  mov    %r13,%rcx
L19:
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  mov    $0x1,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    0x8(%rsp),%r15
  jne    L114
L93:
  lea    D90(%rip),%rdi
  call   <puts@plt>
  jmp    L117
  nopl   (%rax)
L20:
  mov    0x14(%rsp),%edx
  cmp    %edx,0x24(%rsp)
  jne    L94
  jmp    L93
L58:
  mov    0x1c(%rsp),%esi
  add    $0x38,%rsp
  lea    D124(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <tabprintf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D48
type: string
name: read_data
arguments: data_tag: D63
type: string
name: read_data
arguments: data_tag: D33
type: string
name: read_data
arguments: data_tag: D106
type: string
name: read_data
arguments: data_tag: D62
type: string
name: read_data
arguments: data_tag: D56
type: string
name: read_data
arguments: data_tag: D125
type: string
name: read_data
arguments: data_tag: D90
type: string
name: read_data
arguments: data_tag: D124
type: string

tool: D17: [

tool: D48:  

tool: D63: 	

tool: D33: %s%.3lf%s%s

tool: 

tool: D62: ;

tool: D56: 
 

tool: D125: %s

tool: D90: ]

tool: 

assistant: ```c
void tabPrintTransform(int r, int c, double M[r][c], int indent) {
  if (r == 0 || c == 0) {
    tabprintf("[]\n", indent);
    return;
  }
  tabprintf("[", indent);
  for (int i = 0; i < r; i++) {
    for (int j = 0; j < c; j++) {
      char *pre = signbit(M[i][j]) ? "" : " ";
      char *post1 = "\t";
      char *post2 = (j == (c - 1)) ? (i == (r - 1)) ? "" : ";" : " ";
      printf("%s%.3lf%s%s", pre, M[i][j], post1, post2);
    }
    printf("%s", (i == (r - 1)) ? "]\n" : "\n ");
    tabprintf(" ", indent);
  }
  printf("\n");
}
```