ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<is_str_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L26
  cmpq   $0x0,-0x10(%rbp)
  jne    L12
L26:
  cmpq   $0x0,-0x8(%rbp)
  je     L66
  cmpq   $0x0,-0x10(%rbp)
  je     L12
L66:
  cmpq   $0x0,-0x8(%rbp)
  je     L27
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L27
L12:
  mov    $0x1,%eax
  jmp    L62
L27:
  mov    $0x0,%eax
L62:
  leave
  ret
```

assistant: ```c
int is_str_equal(const char *expected, const char *actual) {
  if ((expected == NULL && actual != NULL) || (expected != NULL && actual == NULL) || (expected && strcmp(expected, actual) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_str_equal>:
  endbr64
  test   %rdi,%rdi
  sete   %cl
  test   %rsi,%rsi
  sete   %dl
  mov    $0x1,%eax
  cmp    %dl,%cl
  jne    L8
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L8
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L8:
  ret
```

assistant: ```c
int is_str_equal(const char *expected, const char *actual) {
  if ((expected == NULL && actual != NULL) || (expected != NULL && actual == NULL) || (expected && strcmp(expected, actual) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_str_equal>:
  endbr64
  test   %rdi,%rdi
  mov    $0x1,%eax
  sete   %cl
  test   %rsi,%rsi
  sete   %dl
  cmp    %dl,%cl
  je     L5
L3:
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_str_equal(const char *expected, const char *actual) {
  if ((expected == NULL && actual != NULL) || (expected != NULL && actual == NULL) || (expected && strcmp(expected, actual) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_str_equal>:
  endbr64
  test   %rdi,%rdi
  mov    $0x1,%eax
  sete   %cl
  test   %rsi,%rsi
  sete   %dl
  cmp    %dl,%cl
  je     L6
L2:
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L2
  sub    $0x8,%rsp
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_str_equal(const char *expected, const char *actual) {
  if ((expected == NULL && actual != NULL) || (expected != NULL && actual == NULL) || (expected && strcmp(expected, actual) != 0)) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<min3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L23
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L23:
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L6
  mov    -0x1c(%rbp),%eax
  jmp    L14
L6:
  mov    -0x4(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int min3(int x1, int x2, int x3) {
  int m;
  m = x1;
  if (x2 < m)
    m = x2;
  if (x3 < m) {
    return x3;
  } else {
    return m;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<min3>:
  endbr64
  cmp    %edx,%esi
  cmovg  %edx,%esi
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovle %esi,%eax
  ret
```

assistant: ```c
int min3(int x1, int x2, int x3) {
  int m;
  m = x1;
  if (x2 < m)
    m = x2;
  if (x3 < m) {
    return x3;
  } else {
    return m;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<min3>:
  endbr64
  cmp    %edx,%esi
  mov    %edi,%eax
  cmovg  %edx,%esi
  cmp    %edi,%esi
  cmovle %esi,%eax
  ret
```

assistant: ```c
int min3(int x1, int x2, int x3) {
  int m;
  m = x1;
  if (x2 < m)
    m = x2;
  if (x3 < m) {
    return x3;
  } else {
    return m;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<min3>:
  endbr64
  cmp    %edx,%esi
  mov    %edi,%eax
  cmovg  %edx,%esi
  cmp    %edi,%esi
  cmovle %esi,%eax
  ret
```

assistant: ```c
int min3(int x1, int x2, int x3) {
  int m;
  m = x1;
  if (x2 < m)
    m = x2;
  if (x3 < m) {
    return x3;
  } else {
    return m;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  cltq
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r9
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D6(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: %s%s%s

assistant: ```c
char *concat(const char *innerHTML, const char *openTag, const char *closeTag) {
  size_t totalLength = strlen(innerHTML) + strlen(openTag) + strlen(closeTag) + 1;
  char *result = malloc(totalLength * sizeof(char));
  snprintf(result, totalLength, "%s%s%s", openTag, innerHTML, closeTag);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<concat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%r14d
  movslq %r14d,%r14
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,%r9
  mov    %r12,%r8
  mov    %rbp,%rcx
  lea    D2(%rip),%rdx
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: %s%s%s

assistant: ```c
char *concat(const char *innerHTML, const char *openTag, const char *closeTag) {
  size_t totalLength = strlen(innerHTML) + strlen(openTag) + strlen(closeTag) + 1;
  char *result = malloc(totalLength * sizeof(char));
  snprintf(result, totalLength, "%s%s%s", openTag, innerHTML, closeTag);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<concat>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r15,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %r15,%r9
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %rbp,%rsi
  lea    D9(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: %s%s%s

assistant: ```c
char *concat(const char *innerHTML, const char *openTag, const char *closeTag) {
  size_t totalLength = strlen(innerHTML) + strlen(openTag) + strlen(closeTag) + 1;
  char *result = malloc(totalLength * sizeof(char));
  snprintf(result, totalLength, "%s%s%s", openTag, innerHTML, closeTag);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<concat>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %r15,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rdi
  call   <malloc@plt>
  mov    %r15,%r9
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: %s%s%s

assistant: ```c
char *concat(const char *innerHTML, const char *openTag, const char *closeTag) {
  size_t totalLength = strlen(innerHTML) + strlen(openTag) + strlen(closeTag) + 1;
  char *result = malloc(totalLength * sizeof(char));
  snprintf(result, totalLength, "%s%s%s", openTag, innerHTML, closeTag);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ordinaParole>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L29
L1:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L30
L36:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L30:
  cmpl   $0x0,-0xc(%rbp)
  js     L27
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <confrontaParole@plt>
  cmp    $0x1,%eax
  je     L36
L27:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void ordinaParole(char *parole[1000], int np) {
  int i, j;
  char *x;
  for (i = 1; i < np; i++) {
    x = parole[i];
    j = i - 1;
    while (j >= 0 && confrontaParole(x, parole[j]) == 1) {
      parole[j + 1] = parole[j];
      j--;
    }
    parole[j + 1] = x;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ordinaParole>:
  endbr64
  cmp    $0x1,%esi
  jle    L45
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  lea    -0x1(%rsi),%r15d
  mov    $0x0,%r13d
  jmp    L39
L35:
  movslq %ebp,%rbp
  mov    %r12,0x8(%r14,%rbp,8)
  add    $0x1,%r13
  cmp    %r15,%r13
  je     L17
L39:
  mov    0x8(%r14,%r13,8),%r12
  mov    %r13d,%ebp
  test   %r13d,%r13d
  js     L35
  lea    (%r14,%r13,8),%rbx
L31:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <confrontaParole@plt>
  cmp    $0x1,%eax
  jne    L35
  mov    (%rbx),%rax
  mov    %rax,0x8(%rbx)
  sub    $0x1,%ebp
  sub    $0x8,%rbx
  cmp    $0xffffffff,%ebp
  jne    L31
  jmp    L35
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L45:
  ret
```

assistant: ```c
void ordinaParole(char *parole[1000], int np) {
  int i, j;
  char *x;
  for (i = 1; i < np; i++) {
    x = parole[i];
    j = i - 1;
    while (j >= 0 && confrontaParole(x, parole[j]) == 1) {
      parole[j + 1] = parole[j];
      j--;
    }
    parole[j + 1] = x;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ordinaParole>:
  endbr64
  cmp    $0x1,%esi
  jle    L37
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L36:
  mov    0x8(%rbp,%r14,8),%r13
  mov    %r14,%rbx
L7:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <confrontaParole@plt>
  cmp    $0x1,%eax
  jne    L18
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %rax,0x8(%rbp,%rbx,8)
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  jne    L7
  mov    %rbp,%rax
L22:
  add    $0x1,%r14
  mov    %r13,(%rax)
  cmp    %r14,%r15
  jne    L36
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  add    $0x1,%r12d
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,8),%rax
  jmp    L22
L37:
  ret
```

assistant: ```c
void ordinaParole(char *parole[1000], int np) {
  int i, j;
  char *x;
  for (i = 1; i < np; i++) {
    x = parole[i];
    j = i - 1;
    while (j >= 0 && confrontaParole(x, parole[j]) == 1) {
      parole[j + 1] = parole[j];
      j--;
    }
    parole[j + 1] = x;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ordinaParole>:
  endbr64
  cmp    $0x1,%esi
  jle    L45
  push   %r15
  lea    -0x1(%rsi),%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L11:
  mov    0x8(%rbp,%r14,8),%r13
  mov    %r14,%rbx
L33:
  mov    0x0(%rbp,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    %ebx,%r12d
  call   <confrontaParole@plt>
  cmp    $0x1,%eax
  jne    L34
  mov    0x0(%rbp,%rbx,8),%rax
  mov    %rax,0x8(%rbp,%rbx,8)
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  jne    L33
  mov    %rbp,%rax
L1:
  add    $0x1,%r14
  mov    %r13,(%rax)
  cmp    %r14,%r15
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  add    $0x1,%r12d
  movslq %r12d,%r12
  lea    0x0(%rbp,%r12,8),%rax
  jmp    L1
L45:
  ret
```

assistant: ```c
void ordinaParole(char *parole[1000], int np) {
  int i, j;
  char *x;
  for (i = 1; i < np; i++) {
    x = parole[i];
    j = i - 1;
    while (j >= 0 && confrontaParole(x, parole[j]) == 1) {
      parole[j + 1] = parole[j];
      j--;
    }
    parole[j + 1] = x;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<__format_uint>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %esi,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x8,%esi
  mov    %r9d,%r11d
  and    $0x20,%r11d
  jne    L53
  mov    %r9d,%eax
  and    $0x40,%eax
  cmp    $0x1,%eax
  sbb    %esi,%esi
  and    $0xfffffffa,%esi
  add    $0x10,%esi
L53:
  test   %edi,%edi
  je     L91
  mov    %r9d,%r10d
  and    $0x10,%r10d
  lea    D4(%rip),%rbx
  lea    D57(%rip),%rax
  cmove  %rax,%rbx
  movb   $0x0,0xf(%rsp)
  lea    0xe(%rsp),%r8
  mov    $0xe,%ecx
L16:
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  movzbl (%rbx,%rdx,1),%edx
  mov    %dl,(%r8)
  mov    %edi,%edx
  mov    %eax,%edi
  mov    %ecx,%eax
  sub    $0x1,%ecx
  sub    $0x1,%r8
  cmp    %edx,%esi
  ja     L80
  test   %ecx,%ecx
  jns    L16
L80:
  test   $0x1,%r9b
  je     L96
  movslq %ecx,%rcx
  movb   $0x2b,(%rsp,%rcx,1)
  lea    -0x2(%rax),%ecx
L96:
  add    $0x1,%ecx
  test   $0x4,%r9b
  je     L33
  test   %r11d,%r11d
  jne    L0
  test   $0x40,%r9b
  jne    L23
L33:
  movslq %ecx,%rcx
  lea    (%rsp,%rcx,1),%rdi
  call   <strdup@plt>
L54:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  ret
L91:
  lea    D22(%rip),%rdi
  call   <strdup@plt>
  jmp    L54
L0:
  movslq %ecx,%rcx
  lea    (%rsp,%rcx,1),%rsi
  mov    $0x0,%edx
  lea    D22(%rip),%rdi
  call   <strvcat@plt>
  jmp    L54
L23:
  movslq %ecx,%rcx
  lea    (%rsp,%rcx,1),%rsi
  test   %r10d,%r10d
  lea    D49(%rip),%rdi
  lea    D11(%rip),%rax
  cmove  %rax,%rdi
  mov    $0x0,%edx
  call   <strvcat@plt>
  jmp    L54
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D57
type_infered: string
name: unpack_data
arguments: label: D22
type_infered: string
name: unpack_data
arguments: label: D49
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D4: 0123456789ABCDEF

tool: D57: 0123456789abcdef

tool: D22: 0

tool: D49: 0X

tool: D11: 0x

assistant: ```c
char *__format_uint(unsigned int value, int flags) {
  char buffer[16];
  int i;
  int base;
  const char *digits_lower = "0123456789abcdef";
  const char *digits_upper = "0123456789ABCDEF";
  const char *digits;
  if (flags & 0x20)
    base = 8;
  else if (flags & 0x40)
    base = 16;
  else
    base = 10;
  if (value == 0) {
    return strdup("0");
  }
  if (flags & 0x10) {
    digits = digits_upper;
  } else {
    digits = digits_lower;
  }
  buffer[15] = '\0';
  for (i = 14; i >= 0; i--) {
    if (!value)
      break;
    buffer[i] = digits[value % base];
    value /= base;
  }
  if (flags & 0x01) {
    buffer[i--] = '+';
  }
  i++;
  if (flags & 0x04) {
    if (flags & 0x20) {
      return strvcat("0", &buffer[i], NULL);
    }
    if (flags & 0x40) {
      return strvcat((flags & 0x10) ? "0X" : "0x", &buffer[i], NULL);
    }
  }
  return strdup(&buffer[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__format_uint>:
  endbr64
  push   %rbx
  mov    %esi,%r10d
  mov    %esi,%r8d
  mov    $0x8,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  and    $0x20,%r10d
  jne    L10
  mov    %r8d,%eax
  and    $0x40,%eax
  cmp    $0x1,%eax
  sbb    %esi,%esi
  and    $0xfffffffa,%esi
  add    $0x10,%esi
L10:
  test   %edi,%edi
  je     L11
  mov    %r8d,%r11d
  movb   $0x0,0xf(%rsp)
  mov    $0xd,%ecx
  lea    D9(%rip),%r9
  and    $0x10,%r11d
  lea    D24(%rip),%rax
  lea    0x1(%rsp),%rbx
  cmove  %rax,%r9
  jmp    L79
  nopl   (%rax)
L1:
  sub    $0x1,%rcx
  cmp    %edx,%esi
  ja     L62
L79:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %esi
  movzbl (%r9,%rdx,1),%edx
  mov    %dl,(%rbx,%rcx,1)
  mov    %edi,%edx
  mov    %eax,%edi
  movslq %ecx,%rax
  cmp    $0xffffffffffffffff,%rcx
  jne    L1
  mov    $0xffffffffffffffff,%rax
L62:
  test   $0x1,%r8b
  jne    L33
  add    $0x1,%eax
  cltq
L95:
  lea    (%rsp,%rax,1),%rdi
  test   $0x4,%r8b
  je     L64
  test   %r10d,%r10d
  jne    L82
  and    $0x40,%r8d
  jne    L83
L64:
  call   <strdup@plt>
L130:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L137
  add    $0x20,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L33:
  movb   $0x2b,(%rsp,%rax,1)
  jmp    L95
  xchg   %ax,%ax
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L137
  add    $0x20,%rsp
  lea    D36(%rip),%rdi
  pop    %rbx
  jmp    1090 <strdup@plt>
  nopl   0x0(%rax)
L83:
  test   %r11d,%r11d
  lea    D15(%rip),%r8
  lea    D5(%rip),%rax
  mov    %rdi,%rsi
  cmove  %rax,%r8
  xor    %edx,%edx
  mov    %r8,%rdi
  call   <strvcat@plt>
  jmp    L130
  nopl   0x0(%rax)
L82:
  mov    %rdi,%rsi
  xor    %edx,%edx
  lea    D36(%rip),%rdi
  call   <strvcat@plt>
  jmp    L130
L137:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D36
data_type: string
name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D5
data_type: string

tool: D9: 0123456789ABCDEF

tool: D24: 0123456789abcdef

tool: D36: 0

tool: D15: 0X

tool: D5: 0x

assistant: ```c
char *__format_uint(unsigned int value, int flags) {
  char buffer[16];
  int i;
  int base;
  const char *digits_lower = "0123456789abcdef";
  const char *digits_upper = "0123456789ABCDEF";
  const char *digits;
  if (flags & 0x20)
    base = 8;
  else if (flags & 0x40)
    base = 16;
  else
    base = 10;
  if (value == 0) {
    return strdup("0");
  }
  if (flags & 0x10) {
    digits = digits_upper;
  } else {
    digits = digits_lower;
  }
  buffer[15] = '\0';
  for (i = 14; i >= 0; i--) {
    if (!value)
      break;
    buffer[i] = digits[value % base];
    value /= base;
  }
  if (flags & 0x01) {
    buffer[i--] = '+';
  }
  i++;
  if (flags & 0x04) {
    if (flags & 0x20) {
      return strvcat("0", &buffer[i], NULL);
    }
    if (flags & 0x40) {
      return strvcat((flags & 0x10) ? "0X" : "0x", &buffer[i], NULL);
    }
  }
  return strdup(&buffer[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<forwardline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <settokens@plt>
  mov    $0x0,%eax
  call   <addone@plt>
  leave
  ret
```

assistant: ```c
int forwardline(char *line) {
  settokens(line);
  return addone();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<forwardline>:
  endbr64
  sub    $0x8,%rsp
  call   <settokens@plt>
  mov    $0x0,%eax
  call   <addone@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int forwardline(char *line) {
  settokens(line);
  return addone();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<forwardline>:
  endbr64
  sub    $0x8,%rsp
  call   <settokens@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <addone@plt>
```

assistant: ```c
int forwardline(char *line) {
  settokens(line);
  return addone();
}
```
user: Translate the below assembly code into C programming language:

```asm
<forwardline>:
  endbr64
  sub    $0x8,%rsp
  call   <settokens@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <addone@plt>
```

assistant: ```c
int forwardline(char *line) {
  settokens(line);
  return addone();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<iter_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void iter_free(void *iterdata) {
  struct iter_node *iter = (struct iter_node *)iterdata;
  free(iter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<iter_free>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void iter_free(void *iterdata) {
  struct iter_node *iter = (struct iter_node *)iterdata;
  free(iter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iter_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void iter_free(void *iterdata) {
  struct iter_node *iter = (struct iter_node *)iterdata;
  free(iter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<iter_free>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void iter_free(void *iterdata) {
  struct iter_node *iter = (struct iter_node *)iterdata;
  free(iter);
}
```
user: What is the c source code of the assembly code below?

```asm
<sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int(sprintf)(char *buf, const char *fmt, ...) {
  va_list ap;
  int r;
  va_start(ap, fmt);
  r = vsprintf(buf, fmt, ap);
  va_end(ap);
  return r;
}
```