ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nthUglyNumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  movslq %edi,%rax
  mov    %rax,0x18(%rsp)
  lea    0x0(,%rdi,4),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,(%r14)
  cmp    $0x1,%ebp
  jle    L6
  lea    0x4(%r14),%rbx
  lea    -0x2(%rbp),%eax
  lea    0x8(%r14,%rax,4),%r15
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    $0x5,%r13d
  mov    $0x3,%r12d
  mov    $0x2,%ebp
  jmp    L39
L36:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%ecx
  movslq %ecx,%rdx
  mov    (%r14,%rdx,4),%ebp
  add    %ebp,%ebp
  jmp    L63
L70:
  addl   $0x1,0x10(%rsp)
  mov    0x10(%rsp),%esi
  movslq %esi,%rdx
  mov    (%r14,%rdx,4),%edx
  lea    (%rdx,%rdx,2),%r12d
  jmp    L35
L20:
  add    $0x4,%rbx
  cmp    %r15,%rbx
  je     L6
L39:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <min@plt>
  mov    %eax,(%rbx)
  cmp    %ebp,%eax
  je     L36
L63:
  cmp    %r12d,%eax
  je     L70
L35:
  cmp    %r13d,%eax
  jne    L20
  addl   $0x1,0x14(%rsp)
  mov    0x14(%rsp),%eax
  cltq
  mov    (%r14,%rax,4),%eax
  lea    (%rax,%rax,4),%r13d
  jmp    L20
L6:
  mov    0x18(%rsp),%rax
  mov    -0x4(%r14,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nthUglyNumber(int n) {
  int i = 0;
  int m = 0;
  int d2 = 2, d3 = 3, d5 = 5;
  int i2 = 0, i3 = 0, i5 = 0;
  int *p = (int *)malloc(sizeof(int) * n);
  memset(p, 0, sizeof(int) * n);
  p[0] = 1;
  for (i = 1; i < n; i++) {
    m = min(d2, d3, d5);
    p[i] = m;
    if (m == d2)
      d2 = 2 * p[++i2];
    if (m == d3)
      d3 = 3 * p[++i3];
    if (m == d5)
      d5 = 5 * p[++i5];
  }
  return p[n - 1];
}
```
user: What is the c source code of the assembly code below:

```asm
<nthUglyNumber>:
  endbr64
  push   %r15
  movslq %edi,%rax
  push   %r14
  push   %r13
  push   %r12
  lea    0x0(,%rax,4),%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rax,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rax,0x18(%rsp)
  call   <malloc@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,(%rbx)
  cmp    $0x1,%ebp
  jle    L27
  lea    -0x2(%rbp),%eax
  lea    0x4(%rbx),%r12
  xor    %r13d,%r13d
  mov    $0x5,%ebp
  lea    0x8(%rbx,%rax,4),%rax
  movl   $0x0,0xc(%rsp)
  mov    $0x3,%r14d
  mov    $0x2,%r15d
  mov    %rax,0x10(%rsp)
  movl   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L4:
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <min@plt>
  mov    %eax,(%r12)
  cmp    %r15d,%eax
  jne    L33
  addl   $0x1,0x8(%rsp)
  movslq 0x8(%rsp),%rdi
  mov    (%rbx,%rdi,4),%edi
  lea    (%rdi,%rdi,1),%r15d
L33:
  cmp    %r14d,%eax
  jne    L10
  addl   $0x1,0xc(%rsp)
  movslq 0xc(%rsp),%rsi
  mov    (%rbx,%rsi,4),%esi
  lea    (%rsi,%rsi,2),%r14d
L10:
  cmp    %ebp,%eax
  jne    L19
  add    $0x1,%r13d
  movslq %r13d,%rax
  mov    (%rbx,%rax,4),%eax
  lea    (%rax,%rax,4),%ebp
L19:
  add    $0x4,%r12
  cmp    0x10(%rsp),%r12
  jne    L4
L27:
  mov    0x18(%rsp),%rax
  mov    -0x4(%rbx,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nthUglyNumber(int n) {
  int i = 0;
  int m = 0;
  int d2 = 2, d3 = 3, d5 = 5;
  int i2 = 0, i3 = 0, i5 = 0;
  int *p = (int *)malloc(sizeof(int) * n);
  memset(p, 0, sizeof(int) * n);
  p[0] = 1;
  for (i = 1; i < n; i++) {
    m = min(d2, d3, d5);
    p[i] = m;
    if (m == d2)
      d2 = 2 * p[++i2];
    if (m == d3)
      d3 = 3 * p[++i3];
    if (m == d5)
      d5 = 5 * p[++i5];
  }
  return p[n - 1];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nthUglyNumber>:
  endbr64
  push   %r15
  movslq %edi,%rax
  push   %r14
  push   %r13
  push   %r12
  lea    0x0(,%rax,4),%r12d
  push   %rbp
  mov    %r12d,%edi
  mov    %rax,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rax,0x18(%rsp)
  call   <malloc@plt>
  mov    %r12d,%edx
  xor    %esi,%esi
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x1,(%rbx)
  cmp    $0x1,%ebp
  jle    L1
  lea    -0x2(%rbp),%eax
  lea    0x4(%rbx),%r12
  xor    %r13d,%r13d
  mov    $0x5,%ebp
  lea    0x8(%rbx,%rax,4),%rax
  movl   $0x0,0xc(%rsp)
  mov    $0x3,%r14d
  mov    $0x2,%r15d
  mov    %rax,0x10(%rsp)
  movl   $0x0,0x8(%rsp)
  nopl   0x0(%rax)
L28:
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r15d,%edi
  call   <min@plt>
  mov    %eax,(%r12)
  cmp    %r15d,%eax
  jne    L69
  addl   $0x1,0x8(%rsp)
  movslq 0x8(%rsp),%rdi
  mov    (%rbx,%rdi,4),%edi
  lea    (%rdi,%rdi,1),%r15d
L69:
  cmp    %r14d,%eax
  jne    L29
  addl   $0x1,0xc(%rsp)
  movslq 0xc(%rsp),%rsi
  mov    (%rbx,%rsi,4),%esi
  lea    (%rsi,%rsi,2),%r14d
L29:
  cmp    %ebp,%eax
  je     L60
  add    $0x4,%r12
  cmp    0x10(%rsp),%r12
  jne    L28
L1:
  mov    0x18(%rsp),%rax
  mov    -0x4(%rbx,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L60:
  add    $0x1,%r13d
  add    $0x4,%r12
  movslq %r13d,%rax
  mov    (%rbx,%rax,4),%eax
  lea    (%rax,%rax,4),%ebp
  cmp    0x10(%rsp),%r12
  jne    L28
  jmp    L1
```

assistant: ```c
int nthUglyNumber(int n) {
  int i = 0;
  int m = 0;
  int d2 = 2, d3 = 3, d5 = 5;
  int i2 = 0, i3 = 0, i5 = 0;
  int *p = (int *)malloc(sizeof(int) * n);
  memset(p, 0, sizeof(int) * n);
  p[0] = 1;
  for (i = 1; i < n; i++) {
    m = min(d2, d3, d5);
    p[i] = m;
    if (m == d2)
      d2 = 2 * p[++i2];
    if (m == d3)
      d3 = 3 * p[++i3];
    if (m == d5)
      d5 = 5 * p[++i5];
  }
  return p[n - 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<right_rotate_array_k_times_v1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L47
  cmpl   $0x0,-0x1c(%rbp)
  jle    L47
  cmpl   $0x0,-0x20(%rbp)
  jle    L47
  mov    -0x20(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L4
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L87:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L67
L50:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L67:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L50
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L87
  jmp    L22
L47:
  nop
  jmp    L22
L4:
  nop
L22:
  pop    %rbp
  ret
```

assistant: ```c
void right_rotate_array_k_times_v1(int *array, int len, int k) {
  int index, j, prev, temp;
  if (!array || (len <= 0) || (k <= 0)) {
    return;
  }
  k = k % len;
  if (!k) {
    return;
  }
  j = 0;
  while (j < k) {
    prev = array[len - 1];
    for (index = 0; index < len; ++index) {
      temp = array[index];
      array[index] = prev;
      prev = temp;
    }
    ++j;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<right_rotate_array_k_times_v1>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%r8d
  mov    %edx,%eax
  test   %esi,%esi
  setle  %dl
  test   %eax,%eax
  setle  %sil
  or     %sil,%dl
  jne    L30
  test   %rdi,%rdi
  je     L30
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L30
  movslq %r8d,%rax
  lea    -0x4(%rdi,%rax,4),%r10
  mov    $0x0,%r9d
L5:
  mov    (%r10),%esi
  mov    $0x0,%eax
L42:
  mov    %esi,%edi
  mov    (%rcx,%rax,4),%esi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L42
  add    $0x1,%r9d
  cmp    %r9d,%edx
  jne    L5
L30:
  ret
```

assistant: ```c
void right_rotate_array_k_times_v1(int *array, int len, int k) {
  int index, j, prev, temp;
  if (!array || (len <= 0) || (k <= 0)) {
    return;
  }
  k = k % len;
  if (!k) {
    return;
  }
  j = 0;
  while (j < k) {
    prev = array[len - 1];
    for (index = 0; index < len; ++index) {
      temp = array[index];
      array[index] = prev;
      prev = temp;
    }
    ++j;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<right_rotate_array_k_times_v1>:
  endbr64
  test   %esi,%esi
  mov    %edx,%eax
  mov    %esi,%r8d
  mov    %rdi,%rcx
  setle  %dl
  test   %eax,%eax
  setle  %sil
  or     %sil,%dl
  jne    L3
  test   %rdi,%rdi
  je     L3
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L3
  movslq %r8d,%rax
  xor    %r9d,%r9d
  lea    -0x4(%rdi,%rax,4),%r10
  nopl   0x0(%rax)
L48:
  mov    (%r10),%esi
  xor    %eax,%eax
  nopl   (%rax)
L38:
  mov    %esi,%edi
  mov    (%rcx,%rax,4),%esi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L38
  add    $0x1,%r9d
  cmp    %r9d,%edx
  jne    L48
L3:
  ret
```

assistant: ```c
void right_rotate_array_k_times_v1(int *array, int len, int k) {
  int index, j, prev, temp;
  if (!array || (len <= 0) || (k <= 0)) {
    return;
  }
  k = k % len;
  if (!k) {
    return;
  }
  j = 0;
  while (j < k) {
    prev = array[len - 1];
    for (index = 0; index < len; ++index) {
      temp = array[index];
      array[index] = prev;
      prev = temp;
    }
    ++j;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<right_rotate_array_k_times_v1>:
  endbr64
  test   %esi,%esi
  mov    %edx,%eax
  mov    %esi,%r8d
  mov    %rdi,%rcx
  setle  %dl
  test   %eax,%eax
  setle  %sil
  or     %sil,%dl
  jne    L1
  test   %rdi,%rdi
  je     L1
  cltd
  idiv   %r8d
  test   %edx,%edx
  je     L1
  movslq %r8d,%rax
  xor    %r9d,%r9d
  lea    -0x4(%rdi,%rax,4),%r10
  nopl   0x0(%rax)
L27:
  mov    (%r10),%esi
  xor    %eax,%eax
  nopl   (%rax)
L34:
  mov    %esi,%edi
  mov    (%rcx,%rax,4),%esi
  mov    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L34
  add    $0x1,%r9d
  cmp    %r9d,%edx
  jne    L27
L1:
  ret
```

assistant: ```c
void right_rotate_array_k_times_v1(int *array, int len, int k) {
  int index, j, prev, temp;
  if (!array || (len <= 0) || (k <= 0)) {
    return;
  }
  k = k % len;
  if (!k) {
    return;
  }
  j = 0;
  while (j < k) {
    prev = array[len - 1];
    for (index = 0; index < len; ++index) {
      temp = array[index];
      array[index] = prev;
      prev = temp;
    }
    ++j;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<md5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %esi,-0x22c(%rbp)
  mov    %rdx,-0x238(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,-0x218(%rbp)
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rdi
  call   <MD5_Init@plt>
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x218(%rbp),%rcx
  lea    -0x21c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  mov    -0x22c(%rbp),%edx
  mov    -0x228(%rbp),%rcx
  lea    -0x21c(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  lea    -0x21c(%rbp),%rdx
  mov    -0x238(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MD5_Final@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D9
type: string

tool: D9: ge{}cen[]gun!@#komikti

assistant: ```c
void md5(char *data, int len, char *hash) {
  MD5_CTX c;
  int i, size;
  char *secret = "ge{}cen[]gun!@#komikti", msg[512];
  MD5_Init(&c);
  MD5_Update(&c, secret, strlen(secret));
  MD5_Update(&c, data, len);
  MD5_Final(hash, &c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<md5>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <MD5_Init@plt>
  lea    D8(%rip),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <MD5_Update@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <MD5_Update@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <MD5_Final@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
type_guessed: string

tool: D8: ge{}cen[]gun!@#komikti

assistant: ```c
void md5(char *data, int len, char *hash) {
  MD5_CTX c;
  int i, size;
  char *secret = "ge{}cen[]gun!@#komikti", msg[512];
  MD5_Init(&c);
  MD5_Update(&c, secret, strlen(secret));
  MD5_Update(&c, data, len);
  MD5_Final(hash, &c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<md5>:
  endbr64
  push   %r15
  lea    D2(%rip),%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <MD5_Init@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <MD5_Update@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r14d,%edx
  call   <MD5_Update@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <MD5_Final@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type_infered: string

tool: D2: ge{}cen[]gun!@#komikti

assistant: ```c
void md5(char *data, int len, char *hash) {
  MD5_CTX c;
  int i, size;
  char *secret = "ge{}cen[]gun!@#komikti", msg[512];
  MD5_Init(&c);
  MD5_Update(&c, secret, strlen(secret));
  MD5_Update(&c, data, len);
  MD5_Final(hash, &c);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<md5>:
  endbr64
  push   %r15
  lea    D0(%rip),%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <MD5_Init@plt>
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %r15,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <MD5_Update@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    %r14d,%edx
  call   <MD5_Update@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <MD5_Final@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string

tool: D0: ge{}cen[]gun!@#komikti

assistant: ```c
void md5(char *data, int len, char *hash) {
  MD5_CTX c;
  int i, size;
  char *secret = "ge{}cen[]gun!@#komikti", msg[512];
  MD5_Init(&c);
  MD5_Update(&c, secret, strlen(secret));
  MD5_Update(&c, data, len);
  MD5_Final(hash, &c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply179>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L1
L4:
  movl   $0x0,-0x3c(%rbp)
  jmp    L14
L36:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L14:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L36
  addl   $0x1,-0x40(%rbp)
L1:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L4
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply179(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply179>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L28:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L6:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L6
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  ret
```

assistant: ```c
void multiply179(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<multiply179>:
  endbr64
  test   %edi,%edi
  jle    L25
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L0:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L0
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L24
  pop    %rbx
  ret
L25:
  ret
```

assistant: ```c
void multiply179(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<multiply179>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L77
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L53:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L72
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L72
  nopl   0x0(%rax)
L74:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L74
  cmp    -0x24(%rsp),%r11d
  je     L25
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L25
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L25
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L25:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L53
L77:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L72:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L73:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L73
  mov    -0x18(%rsp),%r8
  jmp    L25
```

assistant: ```c
void multiply179(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```