ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sin@plt>
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <exp@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <log@plt>
  lea    D90(%rip),%rdi
  call   <printf@plt>
  mov    $0x3e8,%edi
  call   <log10@plt>
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    $0x400,%edi
  call   <log2@plt>
  lea    D104(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  movsd  D48(%rip),%xmm0
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movsd  D58(%rip),%xmm0
  lea    D69(%rip),%rdi
  call   <printf@plt>
  mov    $0x17,%edi
  call   <fabs@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffe9,%edi
  call   <fabs@plt>
  lea    D105(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D74
type_guessed: string
name: extract_symbolic_data
arguments: tag: D90
type_guessed: string
name: extract_symbolic_data
arguments: tag: D72
type_guessed: string
name: extract_symbolic_data
arguments: tag: D104
type_guessed: string
name: extract_symbolic_data
arguments: tag: D67
type_guessed: string
name: extract_symbolic_data
arguments: tag: D48
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D58
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D69
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D105
type_guessed: string

tool: D12: sin(1) = %f


tool: D74: exp(10) = %f


tool: D90: log(10) = %f


tool: D72: log10(1000) = %f


tool: D104: log2(1024) = %f


tool: D67: pow(2, 10) = %f


tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D10: ceil(3.1415926) = %f


tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D69: floor(3.1415926) = %f


tool: D18: fabs(23) = %f


tool: D105: fabs(-23) = %f


assistant: ```c
int main() {
  printf("sin(1) = %f\n", sin(1));
  printf("exp(10) = %f\n", exp(10));
  printf("log(10) = %f\n", log(10));
  printf("log10(1000) = %f\n", log10(1000));
  printf("log2(1024) = %f\n", log2(1024));
  printf("pow(2, 10) = %f\n", pow(2, 10));
  printf("ceil(3.1415926) = %f\n", ceil(3.1415926));
  printf("floor(3.1415926) = %f\n", floor(3.1415926));
  printf("fabs(23) = %f\n", fabs(23));
  printf("fabs(-23) = %f\n", fabs(-23));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <sin@plt>
  lea    D107(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <exp@plt>
  lea    D114(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%edi
  call   <log@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    $0x3e8,%edi
  call   <log10@plt>
  lea    D98(%rip),%rdi
  call   <printf@plt>
  mov    $0x400,%edi
  call   <log2@plt>
  lea    D101(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    D0(%rip),%rdi
  call   <printf@plt>
  movsd  D13(%rip),%xmm0
  lea    D42(%rip),%rdi
  call   <printf@plt>
  movsd  D45(%rip),%xmm0
  lea    D106(%rip),%rdi
  call   <printf@plt>
  mov    $0x17,%edi
  call   <fabs@plt>
  lea    D80(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffe9,%edi
  call   <fabs@plt>
  lea    D49(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D107
type_infered: string
name: retrieve_data
arguments: tag: D114
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string
name: retrieve_data
arguments: tag: D98
type_infered: string
name: retrieve_data
arguments: tag: D101
type_infered: string
name: retrieve_data
arguments: tag: D0
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: byte[8]
name: retrieve_data
arguments: tag: D42
type_infered: string
name: retrieve_data
arguments: tag: D45
type_infered: byte[8]
name: retrieve_data
arguments: tag: D106
type_infered: string
name: retrieve_data
arguments: tag: D80
type_infered: string
name: retrieve_data
arguments: tag: D49
type_infered: string

tool: D107: sin(1) = %f


tool: D114: exp(10) = %f


tool: D40: log(10) = %f


tool: D98: log10(1000) = %f


tool: D101: log2(1024) = %f


tool: D0: pow(2, 10) = %f


tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D42: ceil(3.1415926) = %f


tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D106: floor(3.1415926) = %f


tool: D80: fabs(23) = %f


tool: D49: fabs(-23) = %f


assistant: ```c
int main() {
  printf("sin(1) = %f\n", sin(1));
  printf("exp(10) = %f\n", exp(10));
  printf("log(10) = %f\n", log(10));
  printf("log10(1000) = %f\n", log10(1000));
  printf("log2(1024) = %f\n", log2(1024));
  printf("pow(2, 10) = %f\n", pow(2, 10));
  printf("ceil(3.1415926) = %f\n", ceil(3.1415926));
  printf("floor(3.1415926) = %f\n", floor(3.1415926));
  printf("fabs(23) = %f\n", fabs(23));
  printf("fabs(-23) = %f\n", fabs(-23));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <crc32@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xc,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x16,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x9,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xa,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x2,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x7,%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0xc,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shr    $0x3,%rax
  mov    %rax,%rdx
  mov    $0x9e3779b1,%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int _hash(char *keystring) {
  unsigned long key = crc32((unsigned char *)(keystring), strlen(keystring));
  key += (key << 12);
  key ^= (key >> 22);
  key += (key << 4);
  key ^= (key >> 9);
  key += (key << 10);
  key ^= (key >> 2);
  key += (key << 7);
  key ^= (key >> 12);
  key = (key >> 3) * 2654435761;
  return key;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <crc32@plt>
  mov    %rax,%rdx
  shl    $0xc,%rdx
  lea    (%rdx,%rax,1),%rdx
  mov    %rdx,%rax
  shr    $0x16,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x7,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0xc,%rax
  xor    %rdx,%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int _hash(char *keystring) {
  unsigned long key = crc32((unsigned char *)(keystring), strlen(keystring));
  key += (key << 12);
  key ^= (key >> 22);
  key += (key << 4);
  key ^= (key >> 9);
  key += (key << 10);
  key ^= (key >> 2);
  key += (key << 7);
  key ^= (key >> 12);
  key = (key >> 3) * 2654435761;
  return key;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <crc32@plt>
  pop    %rbp
  mov    %rax,%rdx
  shl    $0xc,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x16,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x7,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0xc,%rax
  xor    %rdx,%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  ret
```

assistant: ```c
int _hash(char *keystring) {
  unsigned long key = crc32((unsigned char *)(keystring), strlen(keystring));
  key += (key << 12);
  key ^= (key >> 22);
  key += (key << 4);
  key ^= (key >> 9);
  key += (key << 10);
  key ^= (key >> 2);
  key += (key << 7);
  key ^= (key >> 12);
  key = (key >> 3) * 2654435761;
  return key;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_hash>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <crc32@plt>
  pop    %rbp
  mov    %rax,%rdx
  shl    $0xc,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x16,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x4,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0xa,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0x2,%rax
  xor    %rdx,%rax
  mov    %rax,%rdx
  shl    $0x7,%rdx
  add    %rax,%rdx
  mov    %rdx,%rax
  shr    $0xc,%rax
  xor    %rdx,%rax
  shr    $0x3,%rax
  imul   $0x9e3779b1,%eax,%eax
  ret
```

assistant: ```c
int _hash(char *keystring) {
  unsigned long key = crc32((unsigned char *)(keystring), strlen(keystring));
  key += (key << 12);
  key ^= (key >> 22);
  key += (key << 4);
  key ^= (key >> 9);
  key += (key << 10);
  key ^= (key >> 2);
  key += (key << 7);
  key ^= (key >> 12);
  key = (key >> 3) * 2654435761;
  return key;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_lws_b64_encode_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r10
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r9d
  lea    0x8(%rsp),%rbx
  mov    $0x0,%r11d
  mov    $0x3d,%ebp
  test   %edx,%edx
  jne    L105
  mov    %edx,%r9d
L11:
  lea    0x1(%r9),%eax
  cmp    %r8d,%eax
  jge    L50
  movb   $0x0,(%rcx)
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  mov    %r9d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L103:
  mov    %r12b,(%rax)
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L67
L24:
  mov    %r11d,%r12d
  test   %edx,%edx
  je     L103
  movzbl (%rdi),%r12d
  add    $0x1,%esi
  sub    $0x1,%edx
  lea    0x1(%rdi),%rdi
  jmp    L103
L67:
  add    $0x4,%r9d
  cmp    %r8d,%r9d
  jge    L115
  movzbl 0x5(%rsp),%eax
  mov    %eax,%r12d
  shr    $0x2,%r12b
  movzbl %r12b,%r12d
  movzbl (%r10,%r12,1),%r12d
  mov    %r12b,(%rcx)
  movzbl 0x6(%rsp),%r12d
  shl    $0x4,%eax
  and    $0x30,%eax
  mov    %r12d,%r13d
  shr    $0x4,%r13b
  movzbl %r13b,%r13d
  or     %r13d,%eax
  cltq
  movzbl (%r10,%rax,1),%eax
  mov    %al,0x1(%rcx)
  mov    %ebp,%eax
  cmp    $0x1,%esi
  jle    L29
  lea    0x0(,%r12,4),%eax
  and    $0x3c,%eax
  movzbl 0x7(%rsp),%r12d
  shr    $0x6,%r12b
  movzbl %r12b,%r12d
  or     %r12d,%eax
  cltq
  movzbl (%r10,%rax,1),%eax
L29:
  mov    %al,0x2(%rcx)
  mov    %ebp,%eax
  cmp    $0x2,%esi
  jle    L39
  movzbl 0x7(%rsp),%eax
  and    $0x3f,%eax
  movzbl (%r10,%rax,1),%eax
L39:
  add    $0x4,%rcx
  mov    %al,-0x1(%rcx)
  test   %edx,%edx
  je     L11
L105:
  lea    0x5(%rsp),%rax
  mov    $0x0,%esi
  jmp    L24
L115:
  mov    $0xffffffff,%r9d
  jmp    L22
L50:
  mov    $0xffffffff,%r9d
  jmp    L22
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _lws_b64_encode_string(const char *encode, const char *in, int in_len, char *out, int out_size) {
  unsigned char triple[3];
  int i;
  int len;
  int line = 0;
  int done = 0;
  while (in_len) {
    len = 0;
    for (i = 0; i < 3; i++) {
      if (in_len) {
        triple[i] = *in++;
        len++;
        in_len--;
      } else
        triple[i] = 0;
    }
    if (done + 4 >= out_size)
      return -1;
    *out++ = encode[triple[0] >> 2];
    *out++ = encode[((triple[0] & 0x03) << 4) | ((triple[1] & 0xf0) >> 4)];
    *out++ = (len > 1 ? encode[((triple[1] & 0x0f) << 2) | ((triple[2] & 0xc0) >> 6)] : '=');
    *out++ = (len > 2 ? encode[triple[2] & 0x3f] : '=');
    done += 4;
    line += 4;
  }
  if (done + 1 >= out_size)
    return -1;
  *out++ = '\0';
  return done;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_lws_b64_encode_string>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  je     L112
  mov    %rsi,%r9
  mov    %rdi,%r10
  mov    %edx,%esi
  xor    %ebx,%ebx
  lea    0x5(%rsp),%rbp
  mov    $0x3,%r12d
  nopl   0x0(%rax,%rax,1)
L52:
  xor    %edx,%edx
  mov    %rbp,%rax
  lea    0x1(%rdx),%edi
  test   %esi,%esi
  je     L95
L153:
  movzbl (%r9),%edx
  add    $0x1,%r9
  sub    $0x1,%esi
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    $0x3,%edi
  je     L143
  mov    %edi,%edx
  lea    0x1(%rdx),%edi
  test   %esi,%esi
  jne    L153
L95:
  movslq %edx,%rdi
  mov    %r12d,%r13d
  add    %rbp,%rdi
  sub    %edx,%r13d
  je     L53
  xor    %eax,%eax
L5:
  mov    %eax,%r11d
  add    $0x1,%eax
  movb   $0x0,(%rdi,%r11,1)
  cmp    %r13d,%eax
  jb     L5
L53:
  mov    %edx,%edi
L143:
  lea    0x4(%rbx),%r11d
  cmp    %r8d,%r11d
  jge    L86
  movzbl 0x5(%rsp),%eax
  mov    %eax,%edx
  shl    $0x4,%eax
  shr    $0x2,%dl
  and    $0x30,%eax
  movzbl %dl,%edx
  movzbl (%r10,%rdx,1),%edx
  mov    %dl,(%rcx)
  movzbl 0x6(%rsp),%edx
  mov    %edx,%r13d
  shr    $0x4,%r13b
  movzbl %r13b,%r13d
  or     %r13d,%eax
  cltq
  movzbl (%r10,%rax,1),%eax
  mov    %al,0x1(%rcx)
  cmp    $0x1,%edi
  jle    L45
  movzbl 0x7(%rsp),%r13d
  lea    0x0(,%rdx,4),%eax
  and    $0x3c,%eax
  mov    %r13d,%edx
  shr    $0x6,%dl
  movzbl %dl,%edx
  or     %edx,%eax
  cltq
  movzbl (%r10,%rax,1),%eax
  mov    %al,0x2(%rcx)
  cmp    $0x3,%edi
  jne    L92
  and    $0x3f,%r13d
  movzbl (%r10,%r13,1),%eax
L169:
  add    $0x4,%rcx
  mov    %al,-0x1(%rcx)
  test   %esi,%esi
  je     L159
L167:
  mov    %r11d,%ebx
  jmp    L52
  nopl   (%rax)
L45:
  movb   $0x3d,0x2(%rcx)
  mov    $0x3d,%eax
  add    $0x4,%rcx
  mov    %al,-0x1(%rcx)
  test   %esi,%esi
  jne    L167
L159:
  add    $0x5,%ebx
L19:
  cmp    %ebx,%r8d
  jle    L86
  movb   $0x0,(%rcx)
  jmp    L166
  nopl   0x0(%rax)
L92:
  mov    $0x3d,%eax
  jmp    L169
  nop
L86:
  mov    $0xffffffff,%r11d
L166:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r11d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L112:
  xor    %r11d,%r11d
  mov    $0x1,%ebx
  jmp    L19
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _lws_b64_encode_string(const char *encode, const char *in, int in_len, char *out, int out_size) {
  unsigned char triple[3];
  int i;
  int len;
  int line = 0;
  int done = 0;
  while (in_len) {
    len = 0;
    for (i = 0; i < 3; i++) {
      if (in_len) {
        triple[i] = *in++;
        len++;
        in_len--;
      } else
        triple[i] = 0;
    }
    if (done + 4 >= out_size)
      return -1;
    *out++ = encode[triple[0] >> 2];
    *out++ = encode[((triple[0] & 0x03) << 4) | ((triple[1] & 0xf0) >> 4)];
    *out++ = (len > 1 ? encode[((triple[1] & 0x0f) << 2) | ((triple[2] & 0xc0) >> 6)] : '=');
    *out++ = (len > 2 ? encode[triple[2] & 0x3f] : '=');
    done += 4;
    line += 4;
  }
  if (done + 1 >= out_size)
    return -1;
  *out++ = '\0';
  return done;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_lws_b64_encode_string>:
  endbr64
  push   %r12
  xor    %r11d,%r11d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  test   %edx,%edx
  je     L94
  mov    %rdi,%r9
  xor    %ebp,%ebp
  mov    %edx,%edi
  jmp    L59
  nopl   0x0(%rax)
L17:
  add    $0x1,%rsi
  mov    $0x1,%ebx
  xor    %edx,%edx
  xor    %r10d,%r10d
  xor    %edi,%edi
L126:
  lea    0x4(%rbp),%r11d
  cmp    %r8d,%r11d
  jge    L115
L39:
  mov    %eax,%r12d
  shl    $0x4,%eax
  shr    $0x2,%r12b
  and    $0x30,%eax
  movzbl %r12b,%r12d
  movzbl (%r9,%r12,1),%r12d
  mov    %r12b,(%rcx)
  mov    %edx,%r12d
  shr    $0x4,%r12b
  movzbl %r12b,%r12d
  or     %r12d,%eax
  cltq
  movzbl (%r9,%rax,1),%eax
  mov    %al,0x1(%rcx)
  cmp    $0x1,%ebx
  je     L90
  lea    0x0(,%rdx,4),%eax
  mov    %r10d,%edx
  shr    $0x6,%dl
  and    $0x3c,%eax
  movzbl %dl,%edx
  or     %edx,%eax
  cltq
  movzbl (%r9,%rax,1),%eax
  mov    %al,0x2(%rcx)
  cmp    $0x3,%ebx
  jne    L99
  and    $0x3f,%r10d
  movzbl (%r9,%r10,1),%eax
L14:
  add    $0x4,%rcx
  mov    %al,-0x1(%rcx)
  test   %edi,%edi
  je     L113
L16:
  mov    %r11d,%ebp
L59:
  movzbl (%rsi),%eax
  cmp    $0x1,%edi
  je     L17
  movzbl 0x1(%rsi),%edx
  cmp    $0x2,%edi
  je     L127
  lea    0x4(%rbp),%r11d
  movzbl 0x2(%rsi),%r10d
  sub    $0x3,%edi
  add    $0x3,%rsi
  mov    $0x3,%ebx
  cmp    %r8d,%r11d
  jl     L39
L115:
  mov    $0xffffffff,%r11d
  pop    %rbx
  pop    %rbp
  mov    %r11d,%eax
  pop    %r12
  ret
  nop
L90:
  movb   $0x3d,0x2(%rcx)
  mov    $0x3d,%eax
  add    $0x4,%rcx
  mov    %al,-0x1(%rcx)
  test   %edi,%edi
  jne    L16
L113:
  add    $0x5,%ebp
L94:
  cmp    %ebp,%r8d
  jle    L115
  pop    %rbx
  mov    %r11d,%eax
  pop    %rbp
  movb   $0x0,(%rcx)
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L127:
  add    $0x2,%rsi
  mov    $0x2,%ebx
  xor    %r10d,%r10d
  xor    %edi,%edi
  jmp    L126
  nopl   0x0(%rax,%rax,1)
L99:
  mov    $0x3d,%eax
  jmp    L14
```

assistant: ```c
int _lws_b64_encode_string(const char *encode, const char *in, int in_len, char *out, int out_size) {
  unsigned char triple[3];
  int i;
  int len;
  int line = 0;
  int done = 0;
  while (in_len) {
    len = 0;
    for (i = 0; i < 3; i++) {
      if (in_len) {
        triple[i] = *in++;
        len++;
        in_len--;
      } else
        triple[i] = 0;
    }
    if (done + 4 >= out_size)
      return -1;
    *out++ = encode[triple[0] >> 2];
    *out++ = encode[((triple[0] & 0x03) << 4) | ((triple[1] & 0xf0) >> 4)];
    *out++ = (len > 1 ? encode[((triple[1] & 0x0f) << 2) | ((triple[2] & 0xc0) >> 6)] : '=');
    *out++ = (len > 2 ? encode[triple[2] & 0x3f] : '=');
    done += 4;
    line += 4;
  }
  if (done + 1 >= out_size)
    return -1;
  *out++ = '\0';
  return done;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L52
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L42
L52:
  cmpl   $0x2,-0x14(%rbp)
  jle    L34
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L42
L34:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L45
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L42
L38:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L45:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
L42:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D23
type_guessed: string

tool: D21: the command need a dirname

tool: D25: the program can only deal with one dir at once

tool: D23: open dir error !

assistant: ```c
int main(int argc, char **argv) {
  DIR *dirptr = NULL;
  struct dirent *entry;
  if (argc < 2) {
    printf("the command need a dirname\n");
    return 1;
  }
  if (argc > 2) {
    printf("the program can only deal with one dir at once\n");
    return 1;
  }
  if ((dirptr = opendir(argv[1])) == NULL) {
    printf("open dir error !\n");
    return 1;
  } else {
    while (entry = readdir(dirptr)) {
      printf("%s\n", entry->d_name);
    }
    closedir(dirptr);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x1,%edi
  jle    L36
  cmp    $0x2,%edi
  jg     L1
  mov    0x8(%rsi),%rdi
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L0
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L17
L36:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L17
L1:
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L17
L22:
  mov    (%rax),%rdi
  call   <puts@plt>
L0:
  mov    %rbx,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L22
  mov    %rbx,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
L17:
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D1: open dir error !

tool: D3: the command need a dirname

tool: D12: the program can only deal with one dir at once

assistant: ```c
int main(int argc, char **argv) {
  DIR *dirptr = NULL;
  struct dirent *entry;
  if (argc < 2) {
    printf("the command need a dirname\n");
    return 1;
  }
  if (argc > 2) {
    printf("the program can only deal with one dir at once\n");
    return 1;
  }
  if ((dirptr = opendir(argv[1])) == NULL) {
    printf("open dir error !\n");
    return 1;
  } else {
    while (entry = readdir(dirptr)) {
      printf("%s\n", entry->d_name);
    }
    closedir(dirptr);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  cmp    $0x1,%edi
  jle    L2
  cmp    $0x2,%edi
  jne    L30
  mov    0x8(%rsi),%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L23
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L10:
  mov    (%rax),%rdi
  call   <puts@plt>
L23:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L10
  mov    %rbp,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L30:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
L2:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
L41:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D21
type_infered: string
name: parse_data
arguments: data_label: D25
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D21: the program can only deal with one dir at once

tool: D25: the command need a dirname

tool: D3: open dir error !

assistant: ```c
int main(int argc, char **argv) {
  DIR *dirptr = NULL;
  struct dirent *entry;
  if (argc < 2) {
    printf("the command need a dirname\n");
    return 1;
  }
  if (argc > 2) {
    printf("the program can only deal with one dir at once\n");
    return 1;
  }
  if ((dirptr = opendir(argv[1])) == NULL) {
    printf("open dir error !\n");
    return 1;
  } else {
    while (entry = readdir(dirptr)) {
      printf("%s\n", entry->d_name);
    }
    closedir(dirptr);
  }
  return 0;
}
```