ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<calcPower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  fld1
  fstpt  -0x10(%rbp)
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  jp     L0
  pxor   %xmm0,%xmm0
  ucomisd -0x30(%rbp),%xmm0
  je     L8
L0:
  movl   $0x0,-0x14(%rbp)
  jmp    L6
L3:
  fldl   -0x28(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L6:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movsd  -0x30(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L3
L8:
  fldt   -0x10(%rbp)
  fstpl  -0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double calcPower(double first, double second) {
  long double ans = 1;
  if (second != 0) {
    for (int i = 0; i < second; i++) {
      ans *= first;
    }
  }
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calcPower>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  %xmm0,-0x10(%rsp)
  ucomisd %xmm2,%xmm1
  jp     L36
  movsd  D0(%rip),%xmm0
  jne    L36
  ret
  nop
L36:
  comisd %xmm2,%xmm1
  jbe    L16
  fldl   -0x10(%rsp)
  xor    %eax,%eax
  fld1
  xchg   %ax,%ax
L11:
  add    $0x1,%eax
  fmul   %st(1),%st
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  comisd %xmm0,%xmm1
  ja     L11
  fstp   %st(1)
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
  ret
L16:
  movsd  D0(%rip),%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double calcPower(double first, double second) {
  long double ans = 1;
  if (second != 0) {
    for (int i = 0; i < second; i++) {
      ans *= first;
    }
  }
  return ans;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calcPower>:
  endbr64
  pxor   %xmm2,%xmm2
  movsd  %xmm0,-0x10(%rsp)
  ucomisd %xmm2,%xmm1
  jp     L20
  movsd  D13(%rip),%xmm0
  jne    L20
  ret
  nop
L20:
  comisd %xmm2,%xmm1
  jbe    L18
  fldl   -0x10(%rsp)
  xor    %eax,%eax
  fld1
  xchg   %ax,%ax
L28:
  add    $0x1,%eax
  fmul   %st(1),%st
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  comisd %xmm0,%xmm1
  ja     L28
  fstp   %st(1)
  fstpl  -0x10(%rsp)
  movsd  -0x10(%rsp),%xmm0
  ret
L18:
  movsd  D13(%rip),%xmm0
  ret
```

tool_calls: name: read_data
arguments: tag: D13
type_infered: byte[8]

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double calcPower(double first, double second) {
  long double ans = 1;
  if (second != 0) {
    for (int i = 0; i < second; i++) {
      ans *= first;
    }
  }
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_djb2a>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1505(%rax),%ebx
  jmp    L12
L7:
  mov    %ebx,%eax
  shl    $0x5,%eax
  add    %ebx,%eax
  mov    %r12d,%ebx
  xor    %eax,%ebx
L12:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%r12d
  test   %r12d,%r12d
  jne    L7
  movslq %ebx,%rax
  imul   $0x76f94e09,%rax,%rax
  shr    $0x20,%rax
  sar    $0xd,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x44db,%eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
uint32_t hash_djb2a(const char *str, const pid_t pid) {
  register uint32_t hash = 5381 + pid;
  register int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) ^ c;
  }
  return hash % (17627);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash_djb2a>:
  endbr64
  add    $0x1505,%esi
  lea    0x1(%rdi),%rdx
  movsbl (%rdi),%eax
  test   %eax,%eax
  je     L12
L1:
  mov    %esi,%ecx
  shl    $0x5,%ecx
  add    %ecx,%esi
  xor    %eax,%esi
  add    $0x1,%rdx
  movsbl -0x1(%rdx),%eax
  test   %eax,%eax
  jne    L1
L12:
  movslq %esi,%rax
  imul   $0x76f94e09,%rax,%rax
  sar    $0x2d,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x44db,%eax,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash_djb2a(const char *str, const pid_t pid) {
  register uint32_t hash = 5381 + pid;
  register int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) ^ c;
  }
  return hash % (17627);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_djb2a>:
  endbr64
  movsbl (%rdi),%eax
  add    $0x1505,%esi
  lea    0x1(%rdi),%rdx
  test   %eax,%eax
  je     L14
  nopl   (%rax)
L16:
  mov    %esi,%ecx
  add    $0x1,%rdx
  shl    $0x5,%ecx
  add    %ecx,%esi
  xor    %eax,%esi
  movsbl -0x1(%rdx),%eax
  test   %eax,%eax
  jne    L16
L14:
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x76f94e09,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x2d,%rax
  sub    %edx,%eax
  imul   $0x44db,%eax,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash_djb2a(const char *str, const pid_t pid) {
  register uint32_t hash = 5381 + pid;
  register int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) ^ c;
  }
  return hash % (17627);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash_djb2a>:
  endbr64
  movsbl (%rdi),%eax
  add    $0x1505,%esi
  lea    0x1(%rdi),%rdx
  test   %eax,%eax
  je     L3
  nopl   (%rax)
L6:
  mov    %esi,%ecx
  add    $0x1,%rdx
  shl    $0x5,%ecx
  add    %ecx,%esi
  xor    %eax,%esi
  movsbl -0x1(%rdx),%eax
  test   %eax,%eax
  jne    L6
L3:
  movslq %esi,%rax
  mov    %esi,%edx
  imul   $0x76f94e09,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x2d,%rax
  sub    %edx,%eax
  imul   $0x44db,%eax,%edx
  mov    %esi,%eax
  sub    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash_djb2a(const char *str, const pid_t pid) {
  register uint32_t hash = 5381 + pid;
  register int c;
  while ((c = *str++)) {
    hash = ((hash << 5) + hash) ^ c;
  }
  return hash % (17627);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L60:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L60
  sub    $0x528,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc3518(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L16
  lea    0xc(%rsp),%r12
  lea    D2(%rip),%rbx
  lea    0x14(%rsp),%rbp
  jmp    L103
L112:
  lea    0x10(%rsp),%rdi
  lea    -0x1(%r8),%edx
  lea    0x0(%rbp,%rdx,4),%r9
L14:
  mov    %ecx,%edx
  imul   (%rdi),%edx
  add    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%eax
  lea    (%rax,%rax,4),%r10d
  add    %r10d,%r10d
  sub    %r10d,%edx
  mov    %edx,(%rdi)
  add    $0x4,%rdi
  cmp    %r9,%rdi
  jne    L14
L54:
  test   %eax,%eax
  jle    L15
  lea    0x1(%r8),%edi
  movslq %edi,%rdi
L134:
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  sub    %r8d,%edx
  lea    (%rdx,%rdx,4),%r8d
  add    %r8d,%r8d
  mov    %eax,%r9d
  sub    %r8d,%r9d
  mov    %r9d,0xc(%rsp,%rdi,4)
  mov    %eax,%r9d
  mov    %edx,%eax
  mov    %edi,%r8d
  add    $0x1,%rdi
  cmp    $0x9,%r9d
  jg     L134
L15:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  je     L138
L23:
  test   %r8d,%r8d
  jg     L112
  jmp    L54
L138:
  sub    $0x1,%r8d
  js     L21
L63:
  movslq %r8d,%r13
L88:
  mov    0x10(%rsp,%r13,4),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%r13
  test   %r13d,%r13d
  jns    L88
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L16
L103:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movl   $0x1,0x10(%rsp)
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jle    L77
  add    $0x1,%esi
  mov    $0x1,%r8d
  mov    $0x0,%eax
  mov    $0x1,%ecx
  jmp    L23
L77:
  mov    $0x0,%r8d
  jmp    L63
L16:
  mov    0xc3518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  mov    $0x0,%eax
  add    $0xc3528,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: %d

assistant: ```c
int main() {
  int t;
  int a[200001];
  int n, i, j, temp, m, x;
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    a[0] = 1;
    m = 1;
    temp = 0;
    for (i = 1; i <= n; i++) {
      for (j = 0; j < m; j++) {
        x = a[j] * i + temp;
        a[j] = x % 10;
        temp = x / 10;
      }
      while (temp > 0) {
        a[m] = temp % 10;
        temp = temp / 10;
        m++;
      }
    }
    for (i = m - 1; i >= 0; i--)
      printf("%d", a[i]);
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0xc3000(%rsp),%r11
L72:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L72
  sub    $0x520,%rsp
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0xc3518(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    0x10(%rsp),%r12
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L17
L77:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  movl   $0x1,0x10(%rsp)
  test   %esi,%esi
  jle    L48
  add    $0x1,%esi
  mov    $0x1,%r9d
  xor    %eax,%eax
  mov    $0x1,%ecx
  xor    %r11d,%r11d
  lea    0x14(%rsp),%rdi
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %r11d,%edx
  mov    %r12,%r8
  lea    (%rdi,%rdx,4),%r10
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%r8),%edx
  add    $0x4,%r8
  imul   %ecx,%edx
  add    %eax,%edx
  movslq %edx,%rax
  mov    %edx,%r13d
  mov    %edx,%r14d
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%r13d
  sar    $0x22,%rax
  sub    %r13d,%eax
  lea    (%rax,%rax,4),%r13d
  add    %r13d,%r13d
  sub    %r13d,%r14d
  mov    %r14d,-0x4(%r8)
  cmp    %r10,%r8
  jne    L4
  cmp    $0x9,%edx
  jle    L51
  lea    0x1(%r9),%r8d
  movslq %r8d,%r8
  cs nopw 0x0(%rax,%rax,1)
L55:
  movslq %eax,%rdx
  mov    %eax,%r9d
  mov    %eax,%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r9d
  sar    $0x22,%rdx
  sub    %r9d,%edx
  lea    (%rdx,%rdx,4),%r9d
  add    %r9d,%r9d
  sub    %r9d,%r10d
  mov    %r8d,%r9d
  mov    %r10d,-0x4(%r12,%r8,4)
  mov    %eax,%r10d
  add    $0x1,%r8
  mov    %edx,%eax
  cmp    $0x9,%r10d
  jg     L55
  lea    -0x1(%r9),%r11d
L51:
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jne    L58
L59:
  movslq %r11d,%rax
  mov    %rbp,%r14
  lea    (%r12,%rax,4),%r13
  nopl   (%rax)
L96:
  mov    0x0(%r13),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  sub    $0x4,%r13
  call   <printf@plt>
  cmp    %r13,%r14
  jne    L96
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L77
L17:
  mov    0xc3518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L82
  add    $0xc3520,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L48:
  xor    %r11d,%r11d
  jmp    L59
L82:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d

assistant: ```c
int main() {
  int t;
  int a[200001];
  int n, i, j, temp, m, x;
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    a[0] = 1;
    m = 1;
    temp = 0;
    for (i = 1; i <= n; i++) {
      for (j = 0; j < m; j++) {
        x = a[j] * i + temp;
        a[j] = x % 10;
        temp = x / 10;
      }
      while (temp > 0) {
        a[m] = temp % 10;
        temp = temp / 10;
        m++;
      }
    }
    for (i = m - 1; i >= 0; i--)
      printf("%d", a[i]);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L0
L12:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jbe    L12
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int getMask(int a, int b) {
  unsigned int i;
  unsigned int r = 0;
  for (i = a; i <= b; i++) {
    r |= 1 << i;
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getMask>:
  endbr64
  mov    %edi,%ecx
  cmp    %esi,%edi
  ja     L8
  mov    $0x0,%eax
  mov    $0x1,%edi
L6:
  mov    %edi,%edx
  shl    %cl,%edx
  or     %edx,%eax
  add    $0x1,%ecx
  cmp    %esi,%ecx
  jbe    L6
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int getMask(int a, int b) {
  unsigned int i;
  unsigned int r = 0;
  for (i = a; i <= b; i++) {
    r |= 1 << i;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMask>:
  endbr64
  mov    %edi,%ecx
  xor    %eax,%eax
  cmp    %esi,%edi
  ja     L9
  mov    $0x1,%edi
  nopl   0x0(%rax)
L12:
  mov    %edi,%edx
  shl    %cl,%edx
  add    $0x1,%ecx
  or     %edx,%eax
  cmp    %esi,%ecx
  jbe    L12
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
unsigned int getMask(int a, int b) {
  unsigned int i;
  unsigned int r = 0;
  for (i = a; i <= b; i++) {
    r |= 1 << i;
  }
  return r;
}
```
user: What is the c source code of the assembly code below:

```asm
<getMask>:
  endbr64
  mov    %edi,%ecx
  xor    %eax,%eax
  cmp    %esi,%edi
  ja     L8
  mov    $0x1,%edi
  nopl   0x0(%rax)
L13:
  mov    %edi,%edx
  shl    %cl,%edx
  add    $0x1,%ecx
  or     %edx,%eax
  cmp    %esi,%ecx
  jbe    L13
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
unsigned int getMask(int a, int b) {
  unsigned int i;
  unsigned int r = 0;
  for (i = a; i <= b; i++) {
    r |= 1 << i;
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x6,-0x10(%rbp)
  movl   $0x7,-0xc(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main() {
  int z;
  int a[2][3] = {{z + 1, 2, 3}, {5, 6, 7}};
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int z;
  int a[2][3] = {{z + 1, 2, 3}, {5, 6, 7}};
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int z;
  int a[2][3] = {{z + 1, 2, 3}, {5, 6, 7}};
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int z;
  int a[2][3] = {{z + 1, 2, 3}, {5, 6, 7}};
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<md_initialize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <read_atoms@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <read_inputfile@plt>
  nop
  leave
  ret
```

assistant: ```c
void md_initialize(const char *cls_file, const char *input_file) {
  read_atoms(cls_file);
  read_inputfile(input_file);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<md_initialize>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <read_atoms@plt>
  mov    %rbx,%rdi
  call   <read_inputfile@plt>
  pop    %rbx
  ret
```

assistant: ```c
void md_initialize(const char *cls_file, const char *input_file) {
  read_atoms(cls_file);
  read_inputfile(input_file);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<md_initialize>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <read_atoms@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <read_inputfile@plt>
```

assistant: ```c
void md_initialize(const char *cls_file, const char *input_file) {
  read_atoms(cls_file);
  read_inputfile(input_file);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<md_initialize>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  call   <read_atoms@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <read_inputfile@plt>
```

assistant: ```c
void md_initialize(const char *cls_file, const char *input_file) {
  read_atoms(cls_file);
  read_inputfile(input_file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<seticanon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    -0x10(%rbp),%edx
  mov    D46(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L43
  mov    -0x10(%rbp),%edx
  mov    D46(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L28
L43:
  mov    -0x10(%rbp),%edx
  mov    D46(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x10(%rbp)
L28:
  cmpl   $0x0,-0x18(%rbp)
  je     L0
  mov    -0x10(%rbp),%edx
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L14
L0:
  mov    -0x10(%rbp),%edx
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x10(%rbp)
L14:
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
bool seticanon(bool icanon, bool echo) {
  struct termios termios;
  tcgetattr(0, &termios);
  bool ret = (termios.c_lflag & ICANON);
  if (icanon)
    termios.c_lflag |= ICANON;
  else
    termios.c_lflag &= ~ICANON;
  if (echo)
    termios.c_lflag |= ECHO;
  else
    termios.c_lflag &= ~ECHO;
  tcsetattr(0, TCSANOW, &termios);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<seticanon>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edi
  call   <tcgetattr@plt>
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%ebx
  and    0x4(%rsp),%ebx
  mov    %eax,%edx
  or     0x4(%rsp),%edx
  not    %eax
  and    0x4(%rsp),%eax
  test   %r12d,%r12d
  cmovne %edx,%eax
  test   %ebp,%ebp
  je     L28
  mov    D21(%rip),%rdx
  or     (%rdx),%eax
L11:
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D7(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    D21(%rip),%rdx
  mov    (%rdx),%edx
  not    %edx
  and    %edx,%eax
  jmp    L11
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool seticanon(bool icanon, bool echo) {
  struct termios termios;
  tcgetattr(0, &termios);
  bool ret = (termios.c_lflag & ICANON);
  if (icanon)
    termios.c_lflag |= ICANON;
  else
    termios.c_lflag &= ~ICANON;
  if (echo)
    termios.c_lflag |= ECHO;
  else
    termios.c_lflag &= ~ECHO;
  tcsetattr(0, TCSANOW, &termios);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<seticanon>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    D4(%rip),%rax
  mov    0x4(%rsp),%r12d
  mov    0x4(%rsp),%edx
  mov    (%rax),%eax
  or     %eax,%edx
  and    %eax,%r12d
  not    %eax
  and    0x4(%rsp),%eax
  test   %ebp,%ebp
  cmovne %edx,%eax
  mov    D7(%rip),%rdx
  mov    (%rdx),%edx
  mov    %eax,%ecx
  or     %edx,%ecx
  not    %edx
  and    %eax,%edx
  test   %ebx,%ebx
  mov    D21(%rip),%rax
  cmovne %ecx,%edx
  xor    %edi,%edi
  mov    (%rax),%esi
  mov    %edx,0x4(%rsp)
  mov    %r13,%rdx
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool seticanon(bool icanon, bool echo) {
  struct termios termios;
  tcgetattr(0, &termios);
  bool ret = (termios.c_lflag & ICANON);
  if (icanon)
    termios.c_lflag |= ICANON;
  else
    termios.c_lflag &= ~ICANON;
  if (echo)
    termios.c_lflag |= ECHO;
  else
    termios.c_lflag &= ~ECHO;
  tcsetattr(0, TCSANOW, &termios);
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<seticanon>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    D5(%rip),%rax
  mov    0x4(%rsp),%r12d
  mov    0x4(%rsp),%edx
  mov    (%rax),%eax
  or     %eax,%edx
  and    %eax,%r12d
  not    %eax
  and    0x4(%rsp),%eax
  test   %ebp,%ebp
  cmovne %edx,%eax
  mov    D13(%rip),%rdx
  mov    (%rdx),%edx
  mov    %eax,%ecx
  or     %edx,%ecx
  not    %edx
  and    %eax,%edx
  test   %ebx,%ebx
  mov    D17(%rip),%rax
  cmovne %ecx,%edx
  xor    %edi,%edi
  mov    (%rax),%esi
  mov    %edx,0x4(%rsp)
  mov    %r13,%rdx
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool seticanon(bool icanon, bool echo) {
  struct termios termios;
  tcgetattr(0, &termios);
  bool ret = (termios.c_lflag & ICANON);
  if (icanon)
    termios.c_lflag |= ICANON;
  else
    termios.c_lflag &= ~ICANON;
  if (echo)
    termios.c_lflag |= ECHO;
  else
    termios.c_lflag &= ~ECHO;
  tcsetattr(0, TCSANOW, &termios);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PsArc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  mov    -0x20(%rbp),%eax
  neg    %eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getPsFile@plt>
  mov    %eax,%edi
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x1c(%rbp),%eax
  mov    0x10(%rbp),%edx
  push   %rdx
  mov    -0x2c(%rbp),%edx
  push   %rdx
  mov    %esi,%r9d
  mov    %ecx,%r8d
  mov    %rbx,%rcx
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  call   <fprintf@plt>
  add    $0x10,%rsp
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: string

tool: D6: newpath %d %d %d %d %d %d ellipse stroke


assistant: ```c
void PsArc(struct ADrawTag *ctx, unsigned int cx, unsigned int cy, unsigned int w, unsigned int h, unsigned int s, unsigned int e) {
  fprintf(getPsFile(ctx),
          "newpath "
          "%d %d %d %d %d %d ellipse "
          "stroke\n",
          cx, 0 - cy, w, h, s, e);
}
```