user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x54(%rbp),%rsi
  lea    D57(%rip),%rdi
  call   <scanf@plt>
  mov    -0x54(%rbp),%edx
  movslq %edx,%rax
  add    $0xf,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L41:
  cmp    %rcx,%rsp
  je     L63
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L63:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L131
  orq    $0x0,-0x8(%rsp,%rax,1)
L131:
  mov    %rsp,%r12
  test   %edx,%edx
  jle    L122
  mov    $0x0,%ebx
  lea    -0x40(%rbp),%r15
  lea    -0x48(%rbp),%r14
  lea    D48(%rip),%r13
  jmp    L68
L112:
  mov    %edx,-0x50(%rbp)
  mov    %eax,-0x4c(%rbp)
L74:
  mov    %cl,(%r12,%rbx,1)
  mov    -0x54(%rbp),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jle    L45
L68:
  lea    -0x4c(%rbp),%rdx
  lea    -0x50(%rbp),%rsi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x50(%rbp),%edx
  mov    -0x4c(%rbp),%eax
  cmp    %eax,%edx
  jg     L17
  movsd  -0x48(%rbp),%xmm2
  movsd  -0x40(%rbp),%xmm1
  mov    $0x1,%ecx
L91:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  %xmm2,%xmm0
  divsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  add    %esi,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  divsd  D5(%rip),%xmm0
  cvttsd2si %xmm0,%esi
  add    %esi,%eax
  cmp    %eax,%edx
  jg     L112
  add    $0x1,%ecx
  cmp    $0x65,%ecx
  jne    L91
  mov    %edx,-0x50(%rbp)
  mov    %eax,-0x4c(%rbp)
  jmp    L74
L17:
  mov    $0x0,%ecx
  jmp    L74
L45:
  test   %eax,%eax
  jle    L122
  mov    $0x0,%ebx
  lea    D14(%rip),%r14
  lea    D0(%rip),%r13
  jmp    L120
L24:
  movsbl %sil,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L42:
  add    $0x1,%rbx
  cmp    %ebx,-0x54(%rbp)
  jle    L122
L120:
  movzbl (%r12,%rbx,1),%esi
  cmp    $0x64,%sil
  jle    L24
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L42
L122:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D57
type_infered: string
name: disassemble_data
arguments: data_tag: D48
type_infered: string
name: disassemble_data
arguments: data_tag: D5
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D14
type_infered: string
name: disassemble_data
arguments: data_tag: D0
type_infered: string

tool: D57: %d

tool: D48: %d %d %lf %lf

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D14: %d anos.


tool: D0: Mais de 1 seculo.

assistant: ```c
int main() {
  int testsQtt;
  int aPopulation, bPopulation;
  double aPercentualGrowing, bPercentualGrowing;
  scanf("%d", &testsQtt);
  char results[testsQtt];
  int i, years;
  for (i = 0; i < testsQtt; i++) {
    scanf("%d %d %lf %lf", &aPopulation, &bPopulation, &aPercentualGrowing, &bPercentualGrowing);
    years = 0;
    while (aPopulation <= bPopulation) {
      years++;
      if (years > 100) {
        break;
      }
      aPopulation += (int)(aPopulation * aPercentualGrowing / 100);
      bPopulation += (int)(bPopulation * bPercentualGrowing / 100);
    }
    results[i] = years;
  }
  for (i = 0; i < testsQtt; i++) {
    if (results[i] > 100) {
      printf("Mais de 1 seculo.\n");
    } else {
      printf("%d anos.\n", results[i]);
    }
  }
  return 0;
}
```