ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_243_0_1>:
  endbr64
  mov    %esi,%r8d
  mov    %rdi,%rcx
  mov    %edx,%edi
  not    %r8d
  not    %edi
  mov    %r8d,%eax
  or     %edx,%eax
  and    %edi,%eax
  movzbl (%rcx),%edi
  and    %edx,%edi
  and    %esi,%edx
  and    %r8d,%edi
  or     %edi,%eax
  or     %edx,%eax
  mov    %al,(%rcx)
  ret
```

assistant: ```c
void rop3_243_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x616c7546,-0xf(%rbp)
  movw   $0x6f6e,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xf(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xf(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: strlen: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char nome[] = "Fulano";
  printf("%s\n", nome);
  printf("strlen: %d\n", strlen(nome));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x616c7546,0x1(%rsp)
  movw   $0x6f6e,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x1(%rsp),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_infered: string

tool: D9: strlen: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char nome[] = "Fulano";
  printf("%s\n", nome);
  printf("strlen: %d\n", strlen(nome));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    $0x6f6e,%eax
  movl   $0x616c7546,0x1(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
datatype: string

tool: D3: strlen: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char nome[] = "Fulano";
  printf("%s\n", nome);
  printf("strlen: %d\n", strlen(nome));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rbp
  mov    $0x6f6e,%eax
  movl   $0x616c7546,0x1(%rsp)
  mov    %rbp,%rdi
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: strlen: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char nome[] = "Fulano";
  printf("%s\n", nome);
  printf("strlen: %d\n", strlen(nome));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<path_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pathcpy@plt>
L7:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <path_add_dir@plt>
  nop
  leave
  ret
```

assistant: ```c
void path_init(char *path, char const *dir, char const *def) {
  if (!path[0])
    pathcpy(path, def);
  path_add_dir(path, dir);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<path_init>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  cmpb   $0x0,(%rdi)
  je     L11
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <path_add_dir@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    %rdx,%rsi
  call   <pathcpy@plt>
  jmp    L3
```

assistant: ```c
void path_init(char *path, char const *dir, char const *def) {
  if (!path[0])
    pathcpy(path, def);
  path_add_dir(path, dir);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<path_init>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  sub    $0x10,%rsp
  cmpb   $0x0,(%rdi)
  je     L8
  add    $0x10,%rsp
  mov    %r12,%rsi
  pop    %r12
  jmp    1070 <path_add_dir@plt>
L8:
  mov    %rdx,%rsi
  mov    %rdi,0x8(%rsp)
  call   <pathcpy@plt>
  mov    0x8(%rsp),%rdi
  add    $0x10,%rsp
  mov    %r12,%rsi
  pop    %r12
  jmp    1070 <path_add_dir@plt>
```

assistant: ```c
void path_init(char *path, char const *dir, char const *def) {
  if (!path[0])
    pathcpy(path, def);
  path_add_dir(path, dir);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<path_init>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  sub    $0x10,%rsp
  cmpb   $0x0,(%rdi)
  je     L2
  add    $0x10,%rsp
  mov    %r12,%rsi
  pop    %r12
  jmp    1070 <path_add_dir@plt>
L2:
  mov    %rdx,%rsi
  mov    %rdi,0x8(%rsp)
  call   <pathcpy@plt>
  mov    0x8(%rsp),%rdi
  add    $0x10,%rsp
  mov    %r12,%rsi
  pop    %r12
  jmp    1070 <path_add_dir@plt>
```

assistant: ```c
void path_init(char *path, char const *dir, char const *def) {
  if (!path[0])
    pathcpy(path, def);
  path_add_dir(path, dir);
}
```
user: What is the c source code of the assembly code below:

```asm
<match_cc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %rsi,-0x140(%rbp)
  mov    %rdx,-0x148(%rbp)
  mov    %rcx,-0x150(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x128(%rbp)
  mov    -0x140(%rbp),%rdx
  lea    -0x120(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x120(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x128(%rbp),%rdi
  mov    -0x150(%rbp),%rcx
  mov    -0x148(%rbp),%rdx
  lea    -0x120(%rbp),%rsi
  mov    -0x138(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    %eax,-0x124(%rbp)
  cmpl   $0x1,-0x124(%rbp)
  jle    L5
  mov    -0x128(%rbp),%eax
  test   %eax,%eax
  jle    L5
  mov    -0x128(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x138(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jne    L5
  mov    $0x1,%eax
  jmp    L47
L5:
  mov    $0x0,%eax
L47:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: %n

assistant: ```c
int match_cc(const char *src, const char *o_fmt, char *c0, char *c1) {
  char fmt[256];
  int r;
  int len = 0;
  strcpy(fmt, o_fmt);
  strcat(fmt, "%n");
  r = sscanf(src, fmt, c0, c1, &len);
  return (r >= 2) && (len > 0) && ((size_t)len == strlen(src));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<match_cc>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x128,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  lea    0xc(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  jle    L10
  mov    0xc(%rsp),%ebp
  test   %ebp,%ebp
  jle    L10
  mov    %rbx,%rdi
  call   <strlen@plt>
  movslq %ebp,%rbp
  cmp    %rax,%rbp
  sete   %al
  movzbl %al,%eax
L10:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: %n

assistant: ```c
int match_cc(const char *src, const char *o_fmt, char *c0, char *c1) {
  char fmt[256];
  int r;
  int len = 0;
  strcpy(fmt, o_fmt);
  strcat(fmt, "%n");
  r = sscanf(src, fmt, c0, c1, &len);
  return (r >= 2) && (len > 0) && ((size_t)len == strlen(src));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<match_cc>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  mov    %r12,%rdi
  call   <strcpy@plt>
  lea    D9(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    0xc(%rsp),%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jle    L5
  movslq 0xc(%rsp),%r12
  test   %r12d,%r12d
  jle    L5
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rax,%r12
  sete   %al
  movzbl %al,%eax
L5:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x128,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: %n

assistant: ```c
int match_cc(const char *src, const char *o_fmt, char *c0, char *c1) {
  char fmt[256];
  int r;
  int len = 0;
  strcpy(fmt, o_fmt);
  strcat(fmt, "%n");
  r = sscanf(src, fmt, c0, c1, &len);
  return (r >= 2) && (len > 0) && ((size_t)len == strlen(src));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<match_cc>:
  endbr64
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x128,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  mov    %r12,%rdi
  call   <strcpy@plt>
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  lea    0xc(%rsp),%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  jle    L8
  movslq 0xc(%rsp),%r12
  test   %r12d,%r12d
  jle    L8
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rax,%r12
  sete   %al
  movzbl %al,%eax
L8:
  mov    0x118(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x128,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D3: %n

assistant: ```c
int match_cc(const char *src, const char *o_fmt, char *c0, char *c1) {
  char fmt[256];
  int r;
  int len = 0;
  strcpy(fmt, o_fmt);
  strcat(fmt, "%n");
  r = sscanf(src, fmt, c0, c1, &len);
  return (r >= 2) && (len > 0) && ((size_t)len == strlen(src));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strnshash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L7
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L7:
  addq   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int strnshash(const char *s) {
  unsigned int h = 0;
  while (*s) {
    if (!isspace(*s))
      h = (h << 5) - h + *s;
    s++;
  }
  return h;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strnshash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L27
  mov    $0x0,%ebp
  jmp    L20
L33:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L48
L20:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L33
  mov    %ebp,%eax
  shl    $0x5,%eax
  sub    %ebp,%eax
  movsbl (%rbx),%ebp
  add    %eax,%ebp
  jmp    L33
L27:
  mov    $0x0,%ebp
L48:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int strnshash(const char *s) {
  unsigned int h = 0;
  while (*s) {
    if (!isspace(*s))
      h = (h << 5) - h + *s;
    s++;
  }
  return h;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strnshash>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L17
  nopl   0x0(%rax)
L29:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L24
  mov    %r12d,%eax
  shl    $0x5,%eax
  sub    %r12d,%eax
  movsbl (%rbx),%r12d
  add    %eax,%r12d
L24:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L29
L17:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int strnshash(const char *s) {
  unsigned int h = 0;
  while (*s) {
    if (!isspace(*s))
      h = (h << 5) - h + *s;
    s++;
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strnshash>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L28
  nopl   0x0(%rax)
L12:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L4
  mov    %r12d,%eax
  shl    $0x5,%eax
  sub    %r12d,%eax
  movsbl (%rbx),%r12d
  add    %eax,%r12d
L4:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L12
L28:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
unsigned int strnshash(const char *s) {
  unsigned int h = 0;
  while (*s) {
    if (!isspace(*s))
      h = (h << 5) - h + *s;
    s++;
  }
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L36
L49:
  mov    $0x0,%edi
  call   <acos@plt>
  mov    -0x20(%rbp),%edx
  imul   %edx,%eax
  movslq %eax,%rdx
  imul   $0xffffffffb60b60b7,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  movsd  %xmm3,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <tan@plt>
  mulsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x28(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x10(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L12
  mov    -0x28(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D44(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x28(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x1c(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x38(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <tan@plt>
  movsd  -0x38(%rbp),%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L36
L12:
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  imul   %edx,%eax
  pxor   %xmm4,%xmm4
  cvtsi2sd %eax,%xmm4
  movsd  %xmm4,-0x38(%rbp)
  mov    -0x28(%rbp),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  %xmm2,-0x40(%rbp)
  mov    -0x24(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D44(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x48(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <tan@plt>
  movsd  -0x48(%rbp),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x40(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  mulsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L36:
  lea    -0x20(%rbp),%rsi
  lea    -0x28(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x4,%eax
  je     L49
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D44
type_infered: byte[8]
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: string

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D20: %.3lf mL


tool: D39: %d %d %d %d

assistant: ```c
int main() {
  int h, l, t, w;
  double trad, trih;
  while (scanf("%d %d %d %d", &l, &w, &h, &t) == 4) {
    trad = t * 2 * acos(0) / 180;
    trih = l * tan(trad);
    if (trih > h)
      printf("%.3lf mL\n", .5 * h * h * w / tan(trad));
    else
      printf("%.3lf mL\n", l * w * (h - .5 * l * tan(trad)));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rbp
  lea    D34(%rip),%r12
  jmp    L1
L31:
  imul   0x24(%rsp),%ebx
  pxor   %xmm3,%xmm3
  cvtsi2sd %ebx,%xmm3
  movsd  0x8(%rsp),%xmm2
  mulsd  D11(%rip),%xmm2
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  mulsd  %xmm1,%xmm3
  cvttsd2si %xmm3,%esi
  mov    %r12,%rdi
  call   <printf@plt>
L1:
  lea    0x18(%rsp),%rcx
  lea    0x24(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    0x20(%rsp),%r8
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x4,%eax
  jne    L6
  mov    $0x0,%edi
  call   <acos@plt>
  mov    0x1c(%rsp),%ebx
  pxor   %xmm4,%xmm4
  cvtsi2sd %ebx,%xmm4
  movsd  %xmm4,0x8(%rsp)
  imul   0x20(%rsp),%eax
  movslq %eax,%rdx
  imul   $0xffffffffb60b60b7,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  call   <tan@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x18(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm2
  mulsd  %xmm0,%xmm2
  comisd %xmm1,%xmm2
  jbe    L31
  movapd %xmm1,%xmm2
  mulsd  D11(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl 0x24(%rsp),%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L1
L6:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D33
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: byte[8]

tool: D33: %d %d %d %d

tool: D34: %.3lf mL


tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int main() {
  int h, l, t, w;
  double trad, trih;
  while (scanf("%d %d %d %d", &l, &w, &h, &t) == 4) {
    trad = t * 2 * acos(0) / 180;
    trih = l * tan(trad);
    if (trih > h)
      printf("%.3lf mL\n", .5 * h * h * w / tan(trad));
    else
      printf("%.3lf mL\n", l * w * (h - .5 * l * tan(trad)));
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D33(%rip),%rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  lea    0x18(%rsp),%r13
  lea    0x24(%rsp),%r12
  lea    0x1c(%rsp),%rbp
  nopl   (%rax)
L18:
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x4,%eax
  jne    L21
  xor    %edi,%edi
  call   <acos@plt>
  imul   0x20(%rsp),%eax
  mov    0x1c(%rsp),%r15d
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sd %r15d,%xmm2
  movslq %eax,%rdx
  imul   $0xffffffffb60b60b7,%rdx,%rdx
  movsd  %xmm2,0x8(%rsp)
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x1f,%eax
  sar    $0x6,%edx
  sub    %eax,%edx
  cvtsi2sd %edx,%xmm0
  call   <tan@plt>
  movsd  0x8(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sdl 0x18(%rsp),%xmm1
  movapd %xmm2,%xmm3
  mulsd  %xmm0,%xmm3
  comisd %xmm1,%xmm3
  jbe    L12
  movsd  D30(%rip),%xmm2
  lea    D3(%rip),%rdi
  mulsd  %xmm1,%xmm2
  mulsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  cvtsi2sdl 0x24(%rsp),%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  call   <printf@plt>
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L12:
  mulsd  D30(%rip),%xmm2
  mov    0x24(%rsp),%ecx
  pxor   %xmm3,%xmm3
  lea    D3(%rip),%rdi
  imul   %r15d,%ecx
  mulsd  %xmm0,%xmm2
  cvtsi2sd %ecx,%xmm3
  subsd  %xmm2,%xmm1
  mulsd  %xmm1,%xmm3
  cvttsd2si %xmm3,%esi
  call   <printf@plt>
  jmp    L18
  nopl   0x0(%rax)
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D33
data_type: string
name: parse_data
arguments: tag: D30
data_type: byte[8]
name: parse_data
arguments: tag: D3
data_type: string

tool: D33: %d %d %d %d

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

tool: D3: %.3lf mL


assistant: ```c
int main() {
  int h, l, t, w;
  double trad, trih;
  while (scanf("%d %d %d %d", &l, &w, &h, &t) == 4) {
    trad = t * 2 * acos(0) / 180;
    trih = l * tan(trad);
    if (trih > h)
      printf("%.3lf mL\n", .5 * h * h * w / tan(trad));
    else
      printf("%.3lf mL\n", l * w * (h - .5 * l * tan(trad)));
  }
  return 0;
}
```