ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char input[], int length) {
  char temp;
  int j = length - 1;
  for (int i = 0; i < length; ++i, j++) {
    temp = input[i];
    input[i] = input[j];
    input[j] = temp;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdi
  movslq %esi,%rsi
L7:
  movzbl (%rax),%edx
  movzbl -0x1(%rax,%rsi,1),%ecx
  mov    %cl,(%rax)
  mov    %dl,-0x1(%rax,%rsi,1)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L7
L8:
  ret
```

assistant: ```c
void reverse(char input[], int length) {
  char temp;
  int j = length - 1;
  for (int i = 0; i < length; ++i, j++) {
    temp = input[i];
    input[i] = input[j];
    input[j] = temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<reverse>:
  endbr64
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  movslq %esi,%rsi
  lea    0x1(%rdi,%rax,1),%rcx
  nopl   0x0(%rax,%rax,1)
L7:
  movzbl (%rdi),%eax
  movzbl -0x1(%rdi,%rsi,1),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  mov    %al,-0x2(%rdi,%rsi,1)
  cmp    %rcx,%rdi
  jne    L7
L16:
  ret
```

assistant: ```c
void reverse(char input[], int length) {
  char temp;
  int j = length - 1;
  for (int i = 0; i < length; ++i, j++) {
    temp = input[i];
    input[i] = input[j];
    input[j] = temp;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spy_mach_read_from_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  leave
  ret
```

assistant: ```c
uint16_t spy_mach_read_from_2(unsigned char *b) {
  assert(b);
  return ((uint16_t)(b[0] << 8) | (uint16_t)b[1]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spy_mach_read_from_2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzbl (%rbx),%eax
  shl    $0x8,%eax
  movzbl 0x1(%rbx),%edx
  or     %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint16_t spy_mach_read_from_2(unsigned char *b) {
  assert(b);
  return ((uint16_t)(b[0] << 8) | (uint16_t)b[1]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<spy_mach_read_from_2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzwl (%rbx),%eax
  pop    %rbx
  rol    $0x8,%ax
  movzwl %ax,%eax
  ret
```

assistant: ```c
uint16_t spy_mach_read_from_2(unsigned char *b) {
  assert(b);
  return ((uint16_t)(b[0] << 8) | (uint16_t)b[1]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<spy_mach_read_from_2>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movzwl (%rbx),%eax
  pop    %rbx
  rol    $0x8,%ax
  movzwl %ax,%eax
  ret
```

assistant: ```c
uint16_t spy_mach_read_from_2(unsigned char *b) {
  assert(b);
  return ((uint16_t)(b[0] << 8) | (uint16_t)b[1]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<compare_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L52
  mov    $0xffffffff,%eax
  jmp    L38
L52:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L14
  mov    $0x0,%eax
  jmp    L38
L14:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L38
  mov    $0x1,%eax
  jmp    L38
L38:
  pop    %rbp
  ret
```

assistant: ```c
int compare_int(const void *arg1, const void *arg2) {
  if (*((int *)arg1) < *((int *)arg2))
    return -1;
  if (*((int *)arg1) == *((int *)arg2))
    return 0;
  if (*((int *)arg1) > *((int *)arg2))
    return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<compare_int>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,%ecx
  jl     L19
  mov    $0x0,%eax
  je     L19
  mov    $0x1,%eax
L19:
  ret
```

assistant: ```c
int compare_int(const void *arg1, const void *arg2) {
  if (*((int *)arg1) < *((int *)arg2))
    return -1;
  if (*((int *)arg1) == *((int *)arg2))
    return 0;
  if (*((int *)arg1) > *((int *)arg2))
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<compare_int>:
  endbr64
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,(%rdi)
  jl     L13
  mov    $0x0,%eax
  je     L13
  mov    $0x1,%eax
L13:
  ret
```

assistant: ```c
int compare_int(const void *arg1, const void *arg2) {
  if (*((int *)arg1) < *((int *)arg2))
    return -1;
  if (*((int *)arg1) == *((int *)arg2))
    return 0;
  if (*((int *)arg1) > *((int *)arg2))
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compare_int>:
  endbr64
  mov    (%rsi),%edx
  mov    $0xffffffff,%eax
  cmp    %edx,(%rdi)
  jl     L3
  mov    $0x0,%eax
  je     L3
  mov    $0x1,%eax
L3:
  ret
```

assistant: ```c
int compare_int(const void *arg1, const void *arg2) {
  if (*((int *)arg1) < *((int *)arg2))
    return -1;
  if (*((int *)arg1) == *((int *)arg2))
    return 0;
  if (*((int *)arg1) > *((int *)arg2))
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<merge>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ecx
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %eax,%r8d
  sar    %r8d
  mov    %r8d,%r9d
  sub    %esi,%r9d
  add    $0x1,%r9d
  sub    %r8d,%edx
  add    $0x1,%r8d
  test   %r9d,%r9d
  jle    L51
  test   %edx,%edx
  jle    L51
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%rdi
  mov    %esi,%r11d
  lea    0x1(%rsi),%r10d
  lea    -0x8(%rbx),%r13
  jmp    L111
L120:
  sub    $0x1,%edx
  cmp    %r11d,%r8d
  jle    L29
  lea    -0x4(%rbx,%rcx,1),%rax
  add    %r13,%rcx
  lea    -0x1(%r8),%esi
  sub    %r11d,%esi
  shl    $0x2,%rsi
  sub    %rsi,%rcx
L35:
  mov    (%rax),%esi
  mov    %esi,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L35
L29:
  mov    %r10d,%ecx
  add    $0x1,%r8d
  mov    %ebp,(%r12)
L15:
  add    $0x4,%rdi
  add    $0x1,%r10d
  add    $0x1,%r11d
  test   %r9d,%r9d
  jle    L51
  test   %edx,%edx
  jle    L51
L111:
  mov    %rdi,%r12
  movslq %r8d,%rax
  lea    0x0(,%rax,4),%rcx
  mov    (%rbx,%rax,4),%ebp
  cmp    %ebp,(%rdi)
  jge    L120
  mov    %r10d,%ecx
  sub    $0x1,%r9d
  jmp    L15
L51:
  test   %r9d,%r9d
  jle    L77
  movslq %ecx,%rdi
  lea    (%rbx,%rdi,4),%rax
  lea    -0x1(%r9),%esi
  add    %rdi,%rsi
  lea    0x4(%rbx,%rsi,4),%rsi
L9:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L9
  lea    (%r9,%rcx,1),%ecx
L77:
  test   %edx,%edx
  jle    L42
  movslq %r8d,%r8
  lea    (%rbx,%r8,4),%rax
  lea    -0x1(%rdx),%edx
  add    %r8,%rdx
  lea    0x4(%rbx,%rdx,4),%rsi
  movslq %ecx,%rcx
  sub    %r8,%rcx
L72:
  mov    (%rax),%edx
  mov    %edx,(%rax,%rcx,4)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L72
L42:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void merge(int A[], int start, int end) {
  int l, r, val, i, j, k, reml, remr, temp;
  reml = (start + end) / 2 - start + 1;
  remr = end - start + 1 - reml;
  val = start;
  l = start;
  r = (start + end) / 2 + 1;
  while (reml > 0 && remr > 0) {
    if (A[l] < A[r]) {
      A[val++] = A[l++];
      reml--;
    } else {
      temp = A[r];
      remr--;
      for (j = r - 1; j >= l; j--)
        A[j + 1] = A[j];
      l++;
      r++;
      A[val++] = temp;
    }
  }
  while (reml > 0) {
    A[val++] = A[l++];
    reml--;
  }
  while (remr > 0) {
    A[val++] = A[r++];
    remr--;
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<merge>:
  endbr64
  lea    (%rsi,%rdx,1),%eax
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  push   %rbp
  mov    %esi,%ebp
  add    %eax,%r12d
  push   %rbx
  sar    %r12d
  mov    %r12d,%r14d
  sub    %r12d,%r15d
  add    $0x1,%r12d
  sub    %esi,%r14d
  sub    $0x18,%rsp
  add    $0x1,%r14d
  test   %r14d,%r14d
  jle    L4
  test   %r15d,%r15d
  jle    L4
  movslq %esi,%rbx
  jmp    L93
  nopw   0x0(%rax,%rax,1)
L23:
  sub    $0x1,%r14d
  add    $0x1,%rbx
  test   %r14d,%r14d
  jle    L4
L28:
  test   %r15d,%r15d
  jle    L4
L93:
  movslq %r12d,%rax
  lea    0x1(%rbx),%ebp
  mov    0x0(%r13,%rax,4),%ecx
  lea    0x0(,%rax,4),%rdi
  cmp    %ecx,0x0(%r13,%rbx,4)
  jl     L23
  sub    $0x1,%r15d
  cmp    %ebx,%r12d
  jle    L8
  mov    %r12d,%edx
  mov    %ecx,0xc(%rsp)
  sub    %ebx,%edx
  sub    $0x1,%edx
  mov    %rdx,%rax
  lea    0x4(,%rdx,4),%rdx
  neg    %rax
  shl    $0x2,%rax
  lea    -0x4(%rdi,%rax,1),%rsi
  add    %rax,%rdi
  add    %r13,%rsi
  add    %r13,%rdi
  call   <memmove@plt>
  mov    0xc(%rsp),%ecx
L8:
  mov    %ecx,0x0(%r13,%rbx,4)
  add    $0x1,%r12d
  add    $0x1,%rbx
  test   %r14d,%r14d
  jg     L28
  nopl   0x0(%rax)
L4:
  mov    %ebp,%eax
  test   %r14d,%r14d
  lea    (%r14,%rbp,1),%ebp
  cmovle %eax,%ebp
  test   %r15d,%r15d
  jle    L57
  movslq %r12d,%r12
  lea    -0x1(%r15),%edx
  movslq %ebp,%rbp
  add    %r12,%rdx
  lea    0x0(%r13,%r12,4),%rax
  sub    %r12,%rbp
  lea    0x4(%r13,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rax),%edx
  mov    %edx,(%rax,%rbp,4)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L18
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void merge(int A[], int start, int end) {
  int l, r, val, i, j, k, reml, remr, temp;
  reml = (start + end) / 2 - start + 1;
  remr = end - start + 1 - reml;
  val = start;
  l = start;
  r = (start + end) / 2 + 1;
  while (reml > 0 && remr > 0) {
    if (A[l] < A[r]) {
      A[val++] = A[l++];
      reml--;
    } else {
      temp = A[r];
      remr--;
      for (j = r - 1; j >= l; j--)
        A[j + 1] = A[j];
      l++;
      r++;
      A[val++] = temp;
    }
  }
  while (reml > 0) {
    A[val++] = A[l++];
    reml--;
  }
  while (remr > 0) {
    A[val++] = A[r++];
    remr--;
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<crc32c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  cmpl   $0x3,-0x8(%rbp)
  ja     L14
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <singletable_crc32c@plt>
  jmp    L1
L14:
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <multitable_crc32c@plt>
L1:
  leave
  ret
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const unsigned char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, buffer, length));
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<crc32c>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3,%edx
  ja     L19
  call   <singletable_crc32c@plt>
L7:
  add    $0x8,%rsp
  ret
L19:
  call   <multitable_crc32c@plt>
  jmp    L7
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const unsigned char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, buffer, length));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<crc32c>:
  endbr64
  cmp    $0x3,%edx
  ja     L5
  jmp    1070 <singletable_crc32c@plt>
  xchg   %ax,%ax
L5:
  jmp    1060 <multitable_crc32c@plt>
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const unsigned char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, buffer, length));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<crc32c>:
  endbr64
  cmp    $0x3,%edx
  ja     L4
  jmp    1070 <singletable_crc32c@plt>
  xchg   %ax,%ax
L4:
  jmp    1060 <multitable_crc32c@plt>
```

assistant: ```c
uint32_t crc32c(uint32_t crc32c, const unsigned char *buffer, unsigned int length) {
  if (length < 4) {
    return (singletable_crc32c(crc32c, buffer, length));
  } else {
    return (multitable_crc32c(crc32c, buffer, length));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sincosf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x4(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinf@plt>
  movd   %xmm0,%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <cosf@plt>
  movd   %xmm0,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void sincosf(float r, float *restrict sr, float *restrict cr) {
  *sr = sinf(r);
  *cr = cosf(r);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sincosf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sincosf(float r, float *restrict sr, float *restrict cr) {
  *sr = sinf(r);
  *cr = cosf(r);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sincosf>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sincosf(float r, float *restrict sr, float *restrict cr) {
  *sr = sinf(r);
  *cr = cosf(r);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sincosf>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  lea    0xc(%rsp),%rdi
  lea    0x8(%rsp),%rsi
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sincosf(float r, float *restrict sr, float *restrict cr) {
  *sr = sinf(r);
  *cr = cosf(r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rol_epi64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_slli_epi64@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x40,%eax
  sub    -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_srli_epi64@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_xor_si128@plt>
  leave
  ret
```

assistant: ```c
__m128i rol_epi64(__m128i v, int s) {
  __m128i v1 = _mm_slli_epi64(v, s);
  __m128i v2 = _mm_srli_epi64(v, 64 - s);
  return _mm_xor_si128(v1, v2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rol_epi64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  call   <_mm_slli_epi64@plt>
  mov    %eax,%r12d
  mov    $0x40,%esi
  sub    %ebp,%esi
  mov    %ebx,%edi
  call   <_mm_srli_epi64@plt>
  mov    %eax,%esi
  mov    %r12d,%edi
  call   <_mm_xor_si128@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__m128i rol_epi64(__m128i v, int s) {
  __m128i v1 = _mm_slli_epi64(v, s);
  __m128i v2 = _mm_srli_epi64(v, 64 - s);
  return _mm_xor_si128(v1, v2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rol_epi64>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <_mm_slli_epi64@plt>
  mov    $0x40,%esi
  mov    %ebp,%edi
  sub    %ebx,%esi
  mov    %eax,%r12d
  call   <_mm_srli_epi64@plt>
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1070 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i rol_epi64(__m128i v, int s) {
  __m128i v1 = _mm_slli_epi64(v, s);
  __m128i v2 = _mm_srli_epi64(v, 64 - s);
  return _mm_xor_si128(v1, v2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rol_epi64>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  call   <_mm_slli_epi64@plt>
  mov    $0x40,%esi
  mov    %ebp,%edi
  sub    %ebx,%esi
  mov    %eax,%r12d
  call   <_mm_srli_epi64@plt>
  pop    %rbx
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1070 <_mm_xor_si128@plt>
```

assistant: ```c
__m128i rol_epi64(__m128i v, int s) {
  __m128i v1 = _mm_slli_epi64(v, s);
  __m128i v2 = _mm_srli_epi64(v, 64 - s);
  return _mm_xor_si128(v1, v2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ps_test_dummy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L26:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
  addl   $0x1,-0x4(%rbp)
L18:
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: Number of '0' in data: %d


assistant: ```c
int ps_test_dummy(const void *data, int n) {
  int i, cnt = 0;
  for (i = 0; i < n; i++)
    if (((char *)data)[i] == '\0')
      cnt++;
  printf("Number of '0' in data: %d\n", cnt);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ps_test_dummy>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
  mov    $0x0,%esi
L16:
  cmpb   $0x1,(%rax)
  adc    $0x0,%esi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L16
L14:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
L18:
  mov    $0x0,%esi
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: Number of '0' in data: %d


assistant: ```c
int ps_test_dummy(const void *data, int n) {
  int i, cnt = 0;
  for (i = 0; i < n; i++)
    if (((char *)data)[i] == '\0')
      cnt++;
  printf("Number of '0' in data: %d\n", cnt);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ps_test_dummy>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  xor    %esi,%esi
  lea    0x1(%rdi,%rax,1),%rax
  cs nopw 0x0(%rax,%rax,1)
L14:
  cmpb   $0x1,(%rdi)
  adc    $0x0,%esi
  add    $0x1,%rdi
  cmp    %rax,%rdi
  jne    L14
L1:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L10:
  xor    %esi,%esi
  jmp    L1
```

tool_calls: name: parse_data
arguments: label: D3
type: string

tool: D3: Number of '0' in data: %d


assistant: ```c
int ps_test_dummy(const void *data, int n) {
  int i, cnt = 0;
  for (i = 0; i < n; i++)
    if (((char *)data)[i] == '\0')
      cnt++;
  printf("Number of '0' in data: %d\n", cnt);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nthSuperUglyNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x38(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x40(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x1,-0x24(%rbp)
  jmp    L38
L26:
  mov    -0x38(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <getMin@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x20(%rbp)
  jmp    L36
L43:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L23
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x10(%rbp),%rdx
  add    %rsi,%rdx
  imul   %ecx,%eax
  mov    %eax,(%rdx)
L23:
  addl   $0x1,-0x20(%rbp)
L36:
  mov    -0x20(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L43
  addl   $0x1,-0x24(%rbp)
L38:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L26
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int nthSuperUglyNumber(int n, int *primes, int size) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  int *factors = (int *)malloc(sizeof(int) * size);
  int *uglies = (int *)malloc(sizeof(int) * n);
  uglies[0] = 1;
  int min;
  memset(indexes, 0, sizeof(int) * size);
  memcpy(factors, primes, sizeof(int) * size);
  for (int i = 1; i < n; i++) {
    min = getMin(factors, size);
    uglies[i] = min;
    for (int j = 0; j < size; j++)
      if (min == factors[j])
        factors[j] = primes[j] * uglies[++indexes[j]];
  }
  return uglies[n - 1];
}
```