user: 请从给定的汇编指令推导出C源代码:

```asm
<dump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%rbp
  mov    %rdx,%r14
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r13
  mov    %r9,%r12
  lea    D95(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %rbp,%rbp
  jle    L2
  mov    $0x1,%ebx
  jmp    L99
L78:
  add    $0x1,%rbx
L99:
  mov    -0x8(%r15,%rbx,8),%rsi
  lea    D133(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %rbx,%rbp
  je     L2
  test   %ebx,%ebx
  je     L78
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L78
L2:
  lea    D106(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5b,%edi
  call   <putchar@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L73
  mov    $0x1,%ebx
  lea    D133(%rip),%r15
  jmp    L103
L185:
  add    $0x1,%rbx
L103:
  mov    -0x8(%r14,%rbx,8),%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    0x8(%rsp),%rbx
  je     L73
  test   %ebx,%ebx
  je     L185
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L185
L73:
  lea    D106(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5b,%edi
  call   <putchar@plt>
  add    0x8(%rsp),%rbp
  test   %rbp,%rbp
  jle    L89
  mov    $0x1,%ebx
  lea    D133(%rip),%r14
  lea    D18(%rip),%r15
  jmp    L54
L88:
  add    $0x1,%rbx
L54:
  mov    -0x8(%r13,%rbx,8),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %rbp,%rbx
  je     L8
  test   %ebx,%ebx
  je     L88
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L88
L136:
  mov    (%r12,%rbx,8),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L150
L138:
  test   %ebx,%ebx
  je     L136
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L136
L8:
  lea    D106(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5b,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  lea    D18(%rip),%r14
  lea    D133(%rip),%r13
  jmp    L138
L89:
  lea    D106(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x5b,%edi
  call   <putchar@plt>
L150:
  mov    $0x5d,%edi
  call   <putchar@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D95
datatype: string
name: disassemble_data
arguments: label: D133
datatype: string
name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D106
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string

tool: D95: failed:=[

tool: D133: %lu

tool: D18: , 

tool: D106: ],

tool: D17: ];

assistant: ```c
void dump(const unsigned long *a, long m, const unsigned long *b, long n, const unsigned long *c, const unsigned long *d) {
  printf("failed:=[");
  printf("[");
  int j;
  for (j = 0; j < m; j++) {
    if (j)
      printf(", ");
    printf("%lu", a[j]);
  }
  printf("],");
  printf("[");
  for (j = 0; j < n; j++) {
    if (j)
      printf(", ");
    printf("%lu", b[j]);
  }
  printf("],");
  printf("[");
  for (j = 0; j < m + n; j++) {
    if (j)
      printf(", ");
    printf("%lu", c[j]);
  }
  printf("],");
  printf("[");
  for (j = 0; j < m + n; j++) {
    if (j)
      printf(", ");
    printf("%lu", d[j]);
  }
  printf("]");
  printf("];\n");
}
```