ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  cmpl   $0x80000000,-0x4(%rbp)
  jne    L18
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr_fd@plt>
  jmp    L20
L18:
  negl   -0x4(%rbp)
L19:
  cmpl   $0x9,-0x4(%rbp)
  jle    L29
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ft_putnbr_fd>
L29:
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  add    $0x30,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <ft_putchar_fd@plt>
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: MIN_INT

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  if (n < 0) {
    ft_putchar_fd('-', fd);
    if (n == -2147483648) {
      ft_putstr_fd("MIN_INT", fd);
      return;
    }
    n = -n;
  }
  if (n > 9)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_putnbr_fd>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   %edi,%edi
  js     L10
L29:
  cmp    $0x9,%ebx
  jg     L15
L43:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  mov    %ebp,%esi
  call   <ft_putchar_fd@plt>
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  cmp    $0x80000000,%ebx
  je     L34
  neg    %ebx
  jmp    L29
L34:
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <ft_putstr_fd@plt>
  jmp    L38
L15:
  movslq %ebx,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  mov    %ebp,%esi
  call   <ft_putnbr_fd>
  jmp    L43
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: MIN_INT

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  if (n < 0) {
    ft_putchar_fd('-', fd);
    if (n == -2147483648) {
      ft_putstr_fd("MIN_INT", fd);
      return;
    }
    n = -n;
  }
  if (n > 9)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  js     L15
L41:
  mov    %ebx,%ebp
  cmp    $0x9,%ebx
  jg     L39
L29:
  mov    $0xcccccccd,%eax
  mov    %r12d,%esi
  imul   %rbp,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <ft_putchar_fd@plt>
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0xcccccccd,%edi
  mov    %r12d,%esi
  imul   %rbp,%rdi
  shr    $0x23,%rdi
  call   <ft_putnbr_fd>
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L15:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  cmp    $0x80000000,%ebx
  je     L16
  neg    %ebx
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L16:
  pop    %rbx
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <ft_putstr_fd@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: MIN_INT

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  if (n < 0) {
    ft_putchar_fd('-', fd);
    if (n == -2147483648) {
      ft_putstr_fd("MIN_INT", fd);
      return;
    }
    n = -n;
  }
  if (n > 9)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_putnbr_fd>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  test   %edi,%edi
  js     L35
L20:
  mov    %ebx,%r13d
  cmp    $0x9,%ebx
  jg     L50
L85:
  mov    $0xcccccccd,%eax
  add    $0x18,%rsp
  mov    %ebp,%esi
  imul   %r13,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <ft_putchar_fd@plt>
  xchg   %ax,%ax
L50:
  mov    $0xcccccccd,%edi
  mov    %r13,%r12
  imul   %rdi,%r12
  shr    $0x23,%r12
  mov    %r12d,%r15d
  cmp    $0x63,%ebx
  jg     L5
L13:
  mov    $0xcccccccd,%eax
  mov    %ebp,%esi
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r12d
  lea    0x30(%r12),%edi
  call   <ft_putchar_fd@plt>
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L35:
  mov    $0x2d,%edi
  call   <ft_putchar_fd@plt>
  cmp    $0x80000000,%ebx
  je     L14
  neg    %ebx
  jmp    L20
  nopl   0x0(%rax)
L5:
  mov    %r15,%r14
  imul   %rdi,%r14
  shr    $0x23,%r14
  mov    %r14d,%eax
  cmp    $0x3e7,%ebx
  jg     L62
L40:
  mov    $0xcccccccd,%edx
  mov    %ebp,%esi
  imul   %rdx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r14d
  lea    0x30(%r14),%edi
  call   <ft_putchar_fd@plt>
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L62:
  imul   %rax,%rdi
  mov    %ebp,%esi
  mov    %rax,0x8(%rsp)
  shr    $0x23,%rdi
  call   <ft_putnbr_fd>
  mov    0x8(%rsp),%rax
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L14:
  add    $0x18,%rsp
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <ft_putstr_fd@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string

tool: D2: MIN_INT

assistant: ```c
void ft_putnbr_fd(int n, int fd) {
  if (n < 0) {
    ft_putchar_fd('-', fd);
    if (n == -2147483648) {
      ft_putstr_fd("MIN_INT", fd);
      return;
    }
    n = -n;
  }
  if (n > 9)
    ft_putnbr_fd(n / 10, fd);
  ft_putchar_fd(n % 10 + '0', fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L5:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _strlen(const char *s) {
  int i, count;
  count = 0;
  for (i = 0; s[i] != '\0'; i++) {
    count++;
  }
  return (i);
}
```
user: What is the c source code of the assembly code below?

```asm
<_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  mov    $0x1,%eax
L13:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L13
L10:
  mov    %edx,%eax
  ret
L12:
  mov    $0x0,%edx
  jmp    L10
```

assistant: ```c
int _strlen(const char *s) {
  int i, count;
  count = 0;
  for (i = 0; s[i] != '\0'; i++) {
    count++;
  }
  return (i);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  xchg   %ax,%ax
L6:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L6
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _strlen(const char *s) {
  int i, count;
  count = 0;
  for (i = 0; s[i] != '\0'; i++) {
    count++;
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L10
  mov    $0x1,%eax
  xchg   %ax,%ax
L17:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L17
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _strlen(const char *s) {
  int i, count;
  count = 0;
  for (i = 0; s[i] != '\0'; i++) {
    count++;
  }
  return (i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_be_decode_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_be_decode_int@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  jns    L59
  mov    -0x28(%rbp),%rax
  jmp    L36
L59:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rax,%rdx
  jg     L35
  mov    -0x28(%rbp),%rax
  jmp    L36
L35:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L45
  mov    -0x18(%rbp),%rax
  add    $0x9,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  sub    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,(%rax)
L45:
  mov    -0x28(%rbp),%rax
L36:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char *_be_decode_str(const char **data, long long *data_len) {
  long long sllen = _be_decode_int(data, data_len);
  long slen = sllen;
  unsigned long len;
  char *ret = NULL;
  if (sllen < 0)
    return ret;
  if (sizeof(long long) != sizeof(long))
    if (sllen != slen)
      return ret;
  if (sllen > *data_len - 1)
    return ret;
  len = slen;
  if (**data == ':') {
    char *_ret = malloc(sizeof(sllen) + len + 1);
    memcpy(_ret, &sllen, sizeof(sllen));
    ret = _ret + sizeof(sllen);
    memcpy(ret, *data + 1, len);
    ret[len] = '\0';
    *data += len + 1;
    *data_len -= len + 1;
    do {
      if (0)
        dump_string(ret, sllen);
    } while (0);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_be_decode_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_be_decode_int@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  js     L29
  mov    %rax,%rbx
  cmp    (%r12),%rax
  jge    L51
  mov    0x0(%rbp),%rax
  mov    $0x0,%r13d
  cmpb   $0x3a,(%rax)
  je     L64
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    %r13,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L64:
  lea    0x9(%rbx),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  lea    0x8(%r14),%r13
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <memcpy@plt>
  movb   $0x0,0x8(%r14,%rbx,1)
  lea    0x1(%rbx),%rax
  add    %rax,0x0(%rbp)
  not    %rbx
  add    %rbx,(%r12)
  jmp    L1
L29:
  mov    $0x0,%r13d
  jmp    L1
L51:
  mov    $0x0,%r13d
  jmp    L1
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *_be_decode_str(const char **data, long long *data_len) {
  long long sllen = _be_decode_int(data, data_len);
  long slen = sllen;
  unsigned long len;
  char *ret = NULL;
  if (sllen < 0)
    return ret;
  if (sizeof(long long) != sizeof(long))
    if (sllen != slen)
      return ret;
  if (sllen > *data_len - 1)
    return ret;
  len = slen;
  if (**data == ':') {
    char *_ret = malloc(sizeof(sllen) + len + 1);
    memcpy(_ret, &sllen, sizeof(sllen));
    ret = _ret + sizeof(sllen);
    memcpy(ret, *data + 1, len);
    ret[len] = '\0';
    *data += len + 1;
    *data_len -= len + 1;
    do {
      if (0)
        dump_string(ret, sllen);
    } while (0);
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_be_decode_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_be_decode_int@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  js     L45
  mov    %rax,%rbx
  cmp    (%r12),%rax
  jge    L45
  mov    0x0(%rbp),%rax
  xor    %r13d,%r13d
  cmpb   $0x3a,(%rax)
  je     L4
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L4:
  lea    0x9(%rbx),%edi
  call   <malloc@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,%r14
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x0(%rbp),%rax
  lea    0x8(%r14),%r13
  mov    %rbx,%rdx
  mov    %r13,%rdi
  lea    0x1(%rax),%rsi
  xor    %eax,%eax
  call   <memcpy@plt>
  movb   $0x0,0x8(%r14,%rbx,1)
  lea    0x1(%rbx),%rax
  not    %rbx
  add    %rax,0x0(%rbp)
  add    %rbx,(%r12)
  jmp    L55
  nopl   (%rax)
L45:
  xor    %r13d,%r13d
  jmp    L55
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *_be_decode_str(const char **data, long long *data_len) {
  long long sllen = _be_decode_int(data, data_len);
  long slen = sllen;
  unsigned long len;
  char *ret = NULL;
  if (sllen < 0)
    return ret;
  if (sizeof(long long) != sizeof(long))
    if (sllen != slen)
      return ret;
  if (sllen > *data_len - 1)
    return ret;
  len = slen;
  if (**data == ':') {
    char *_ret = malloc(sizeof(sllen) + len + 1);
    memcpy(_ret, &sllen, sizeof(sllen));
    ret = _ret + sizeof(sllen);
    memcpy(ret, *data + 1, len);
    ret[len] = '\0';
    *data += len + 1;
    *data_len -= len + 1;
    do {
      if (0)
        dump_string(ret, sllen);
    } while (0);
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_be_decode_str>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <_be_decode_int@plt>
  mov    %rax,(%rsp)
  test   %rax,%rax
  js     L15
  mov    %rax,%rbx
  cmp    (%r12),%rax
  jge    L15
  mov    0x0(%rbp),%rax
  xor    %r13d,%r13d
  cmpb   $0x3a,(%rax)
  je     L40
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L40:
  lea    0x9(%rbx),%edi
  call   <malloc@plt>
  mov    %rsp,%rsi
  mov    $0x8,%edx
  mov    %rax,%r14
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <memcpy@plt>
  mov    0x0(%rbp),%rax
  lea    0x8(%r14),%r13
  mov    %rbx,%rdx
  mov    %r13,%rdi
  lea    0x1(%rax),%rsi
  xor    %eax,%eax
  call   <memcpy@plt>
  movb   $0x0,0x8(%r14,%rbx,1)
  lea    0x1(%rbx),%rax
  not    %rbx
  add    %rax,0x0(%rbp)
  add    %rbx,(%r12)
  jmp    L21
  nopl   (%rax)
L15:
  xor    %r13d,%r13d
  jmp    L21
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *_be_decode_str(const char **data, long long *data_len) {
  long long sllen = _be_decode_int(data, data_len);
  long slen = sllen;
  unsigned long len;
  char *ret = NULL;
  if (sllen < 0)
    return ret;
  if (sizeof(long long) != sizeof(long))
    if (sllen != slen)
      return ret;
  if (sllen > *data_len - 1)
    return ret;
  len = slen;
  if (**data == ':') {
    char *_ret = malloc(sizeof(sllen) + len + 1);
    memcpy(_ret, &sllen, sizeof(sllen));
    ret = _ret + sizeof(sllen);
    memcpy(ret, *data + 1, len);
    ret[len] = '\0';
    *data += len + 1;
    *data_len -= len + 1;
    do {
      if (0)
        dump_string(ret, sllen);
    } while (0);
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<mode_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%esi
  mov    $0x1a,%edi
  call   <gpio_make_output@plt>
  mov    $0x15,%edi
  call   <gpio_make_input@plt>
  mov    $0x14,%edi
  call   <gpio_make_input@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mode_init(void) {
  gpio_make_output((26), 0);
  gpio_make_input((21));
  gpio_make_input((20));
}
```
user: What is the c source code of the assembly code below:

```asm
<mode_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x1a,%edi
  call   <gpio_make_output@plt>
  mov    $0x15,%edi
  call   <gpio_make_input@plt>
  mov    $0x14,%edi
  call   <gpio_make_input@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void mode_init(void) {
  gpio_make_output((26), 0);
  gpio_make_input((21));
  gpio_make_input((20));
}
```
user: What is the c source code of the assembly code below:

```asm
<mode_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x1a,%edi
  call   <gpio_make_output@plt>
  mov    $0x15,%edi
  call   <gpio_make_input@plt>
  mov    $0x14,%edi
  add    $0x8,%rsp
  jmp    1070 <gpio_make_input@plt>
```

assistant: ```c
void mode_init(void) {
  gpio_make_output((26), 0);
  gpio_make_input((21));
  gpio_make_input((20));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mode_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  mov    $0x1a,%edi
  call   <gpio_make_output@plt>
  mov    $0x15,%edi
  call   <gpio_make_input@plt>
  mov    $0x14,%edi
  add    $0x8,%rsp
  jmp    1070 <gpio_make_input@plt>
```

assistant: ```c
void mode_init(void) {
  gpio_make_output((26), 0);
  gpio_make_input((21));
  gpio_make_input((20));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L15:
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned strlen(const char *s) {
  unsigned int result = 1;
  while (*s != 0) {
    s++;
    result++;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    %rdi,%rdx
L2:
  add    $0x1,%rdx
  lea    0x1(%rdx),%eax
  sub    %edi,%eax
  cmpb   $0x0,(%rdx)
  jne    L2
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned strlen(const char *s) {
  unsigned int result = 1;
  while (*s != 0) {
    s++;
    result++;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L8
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L17:
  add    $0x1,%rdx
  lea    0x1(%rdx),%eax
  sub    %edi,%eax
  cmpb   $0x0,(%rdx)
  jne    L17
  ret
  nop
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned strlen(const char *s) {
  unsigned int result = 1;
  while (*s != 0) {
    s++;
    result++;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L12
  mov    %rdi,%rdx
  nopl   0x0(%rax)
L1:
  add    $0x1,%rdx
  lea    0x1(%rdx),%eax
  sub    %edi,%eax
  cmpb   $0x0,(%rdx)
  jne    L1
  ret
  nop
L12:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned strlen(const char *s) {
  unsigned int result = 1;
  while (*s != 0) {
    s++;
    result++;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fgets_with_openclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L5
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L29
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L10
L29:
  mov    $0x0,%eax
  jmp    L10
L5:
  mov    $0xffffffff,%eax
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: r

assistant: ```c
int fgets_with_openclose(char *fname, char *buf, size_t maxlen) {
  FILE *fp;
  char *s;
  if ((fp = fopen(fname, "r")) != NULL) {
    s = fgets(buf, maxlen, fp);
    fclose(fp);
    return (s != NULL) ? strlen(buf) : 0;
  } else {
    return -1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fgets_with_openclose>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  lea    D5(%rip),%rsi
  call   <fopen@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    $0x0,%eax
  test   %r12,%r12
  je     L25
  mov    %rbp,%rdi
  call   <strlen@plt>
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    $0xffffffff,%eax
  jmp    L25
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string

tool: D5: r

assistant: ```c
int fgets_with_openclose(char *fname, char *buf, size_t maxlen) {
  FILE *fp;
  char *s;
  if ((fp = fopen(fname, "r")) != NULL) {
    s = fgets(buf, maxlen, fp);
    fclose(fp);
    return (s != NULL) ? strlen(buf) : 0;
  } else {
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fgets_with_openclose>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D6(%rip),%rsi
  push   %rbp
  call   <fopen@plt>
  test   %rax,%rax
  je     L2
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  mov    %rax,%rbp
  call   <fgets@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <fclose@plt>
  test   %r13,%r13
  je     L24
  pop    %rbp
  mov    %r12,%rdi
  pop    %r12
  pop    %r13
  jmp    1090 <strlen@plt>
  xchg   %ax,%ax
L24:
  xor    %eax,%eax
L29:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0xffffffff,%eax
  jmp    L29
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: r

assistant: ```c
int fgets_with_openclose(char *fname, char *buf, size_t maxlen) {
  FILE *fp;
  char *s;
  if ((fp = fopen(fname, "r")) != NULL) {
    s = fgets(buf, maxlen, fp);
    fclose(fp);
    return (s != NULL) ? strlen(buf) : 0;
  } else {
    return -1;
  }
}
```