user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x58(%rbp)
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x68(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x48(%rbp)
  mov    %rax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    %rax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L100:
  cmp    %rdx,%rsp
  je     L36
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L100
L36:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L26
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L26:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x40(%rbp)
  movq   $0x0,-0x60(%rbp)
  jmp    L108
L14:
  mov    -0x60(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addq   $0x1,-0x60(%rbp)
L108:
  mov    -0x68(%rbp),%rax
  cmp    %rax,-0x60(%rbp)
  jl     L14
  mov    -0x68(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quicksort@plt>
  mov    -0x40(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x58(%rbp)
  movq   $0x0,-0x60(%rbp)
  jmp    L68
L24:
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax,%rdx,8),%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%rdx
  mov    (%rax,%rdx,8),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    %rax,-0x58(%rbp)
  jl     L25
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax,%rdx,8),%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%rdx
  mov    (%rax,%rdx,8),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  mov    %rax,-0x58(%rbp)
L25:
  addq   $0x1,-0x60(%rbp)
L68:
  mov    -0x68(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x60(%rbp)
  jl     L24
  movq   $0x0,-0x60(%rbp)
  jmp    L95
L54:
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax,%rdx,8),%rcx
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%rdx
  mov    (%rax,%rdx,8),%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  cmp    %rax,-0x58(%rbp)
  jne    L21
  mov    -0x60(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x40(%rbp),%rax
  mov    (%rax,%rdx,8),%rdx
  mov    -0x40(%rbp),%rax
  mov    -0x60(%rbp),%rcx
  mov    (%rax,%rcx,8),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L21:
  addq   $0x1,-0x60(%rbp)
L95:
  mov    -0x68(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x60(%rbp)
  jl     L54
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L85
  call   <__stack_chk_fail@plt>
L85:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D25
data_type: string
name: read_data
arguments: data_label: D1
data_type: string

tool: D25: %ld

tool: D1: %ld %ld 

assistant: ```c
int main() {
  long int i, j, k = 0, l, n, min = 0;
  scanf("%ld", &n);
  long int a[n];
  for (i = 0; i < n; i++) {
    scanf("%ld", &a[i]);
  }
  quicksort(a, 0, n - 1);
  min = a[1] - a[0];
  for (i = 0; i < n - 1; i++) {
    {
      if (a[i + 1] - a[i] <= min) {
        min = a[i + 1] - a[i];
      }
    }
  }
  for (i = 0; i < n - 1; i++) {
    {
      if (a[i + 1] - a[i] == min) {
        printf("%ld %ld ", a[i], a[i + 1]);
      }
    }
  }
  return 0;
}
```