ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<key_schedule_stream>:
  endbr64
  mov    %rsi,%rcx
  movzbl (%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,(%rcx)
  movzbl (%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x4(%rcx)
  movzbl 0x1(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x8(%rcx)
  movzbl 0x1(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0xc(%rcx)
  movzbl 0x2(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x10(%rcx)
  movzbl 0x2(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x14(%rcx)
  movzbl 0x3(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x18(%rcx)
  movzbl 0x3(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x1c(%rcx)
  movzbl 0x4(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,(%rdx)
  movzbl 0x4(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0x4(%rdx)
  movzbl 0x5(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x8(%rdx)
  movzbl 0x5(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0xc(%rdx)
  movzbl 0x6(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x10(%rdx)
  movzbl 0x6(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0x14(%rdx)
  movzbl 0x7(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x18(%rdx)
  movzbl 0x7(%rdi),%eax
  and    $0xf,%eax
  mov    %eax,0x1c(%rdx)
  ret
```

assistant: ```c
void key_schedule_stream(unsigned char *ck, int *iA, int *iB) {
  iA[0] = (ck[0] >> 4) & 0xf;
  iA[1] = (ck[0]) & 0xf;
  iA[2] = (ck[1] >> 4) & 0xf;
  iA[3] = (ck[1]) & 0xf;
  iA[4] = (ck[2] >> 4) & 0xf;
  iA[5] = (ck[2]) & 0xf;
  iA[6] = (ck[3] >> 4) & 0xf;
  iA[7] = (ck[3]) & 0xf;
  iB[0] = (ck[4] >> 4) & 0xf;
  iB[1] = (ck[4]) & 0xf;
  iB[2] = (ck[5] >> 4) & 0xf;
  iB[3] = (ck[5]) & 0xf;
  iB[4] = (ck[6] >> 4) & 0xf;
  iB[5] = (ck[6]) & 0xf;
  iB[6] = (ck[7] >> 4) & 0xf;
  iB[7] = (ck[7]) & 0xf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<key_schedule_stream>:
  endbr64
  mov    %rsi,%rcx
  movzbl (%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,(%rcx)
  movzbl (%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x4(%rcx)
  movzbl 0x1(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x8(%rcx)
  movzbl 0x1(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0xc(%rcx)
  movzbl 0x2(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x10(%rcx)
  movzbl 0x2(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x14(%rcx)
  movzbl 0x3(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x18(%rcx)
  movzbl 0x3(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x1c(%rcx)
  movzbl 0x4(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,(%rdx)
  movzbl 0x4(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0x4(%rdx)
  movzbl 0x5(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x8(%rdx)
  movzbl 0x5(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0xc(%rdx)
  movzbl 0x6(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x10(%rdx)
  movzbl 0x6(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0x14(%rdx)
  movzbl 0x7(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x18(%rdx)
  movzbl 0x7(%rdi),%eax
  and    $0xf,%eax
  mov    %eax,0x1c(%rdx)
  ret
```

assistant: ```c
void key_schedule_stream(unsigned char *ck, int *iA, int *iB) {
  iA[0] = (ck[0] >> 4) & 0xf;
  iA[1] = (ck[0]) & 0xf;
  iA[2] = (ck[1] >> 4) & 0xf;
  iA[3] = (ck[1]) & 0xf;
  iA[4] = (ck[2] >> 4) & 0xf;
  iA[5] = (ck[2]) & 0xf;
  iA[6] = (ck[3] >> 4) & 0xf;
  iA[7] = (ck[3]) & 0xf;
  iB[0] = (ck[4] >> 4) & 0xf;
  iB[1] = (ck[4]) & 0xf;
  iB[2] = (ck[5] >> 4) & 0xf;
  iB[3] = (ck[5]) & 0xf;
  iB[4] = (ck[6] >> 4) & 0xf;
  iB[5] = (ck[6]) & 0xf;
  iB[6] = (ck[7] >> 4) & 0xf;
  iB[7] = (ck[7]) & 0xf;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<key_schedule_stream>:
  endbr64
  mov    %rsi,%rcx
  movzbl (%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,(%rcx)
  movzbl (%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x4(%rcx)
  movzbl 0x1(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x8(%rcx)
  movzbl 0x1(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0xc(%rcx)
  movzbl 0x2(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x10(%rcx)
  movzbl 0x2(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x14(%rcx)
  movzbl 0x3(%rdi),%esi
  shr    $0x4,%sil
  movzbl %sil,%esi
  mov    %esi,0x18(%rcx)
  movzbl 0x3(%rdi),%esi
  and    $0xf,%esi
  mov    %esi,0x1c(%rcx)
  movzbl 0x4(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,(%rdx)
  movzbl 0x4(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0x4(%rdx)
  movzbl 0x5(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x8(%rdx)
  movzbl 0x5(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0xc(%rdx)
  movzbl 0x6(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x10(%rdx)
  movzbl 0x6(%rdi),%ecx
  and    $0xf,%ecx
  mov    %ecx,0x14(%rdx)
  movzbl 0x7(%rdi),%ecx
  shr    $0x4,%cl
  movzbl %cl,%ecx
  mov    %ecx,0x18(%rdx)
  movzbl 0x7(%rdi),%eax
  and    $0xf,%eax
  mov    %eax,0x1c(%rdx)
  ret
```

assistant: ```c
void key_schedule_stream(unsigned char *ck, int *iA, int *iB) {
  iA[0] = (ck[0] >> 4) & 0xf;
  iA[1] = (ck[0]) & 0xf;
  iA[2] = (ck[1] >> 4) & 0xf;
  iA[3] = (ck[1]) & 0xf;
  iA[4] = (ck[2] >> 4) & 0xf;
  iA[5] = (ck[2]) & 0xf;
  iA[6] = (ck[3] >> 4) & 0xf;
  iA[7] = (ck[3]) & 0xf;
  iB[0] = (ck[4] >> 4) & 0xf;
  iB[1] = (ck[4]) & 0xf;
  iB[2] = (ck[5] >> 4) & 0xf;
  iB[3] = (ck[5]) & 0xf;
  iB[4] = (ck[6] >> 4) & 0xf;
  iB[5] = (ck[6]) & 0xf;
  iB[6] = (ck[7] >> 4) & 0xf;
  iB[7] = (ck[7]) & 0xf;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xe8(%rbp)
  jmp    L2
L10:
  mov    -0xe4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xe8(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0xe8(%rbp)
L2:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xe4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xe4(%rbp)
  je     L22
  cmpl   $0x63,-0xe8(%rbp)
  jle    L10
L22:
  mov    -0xe8(%rbp),%eax
  cltq
  movb   $0x0,-0x70(%rbp,%rax,1)
  lea    -0x70(%rbp),%rdx
  lea    -0xe0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <escape@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
int main(void) {
  char s[100], t[100];
  int c, i;
  for (i = 0; (c = getchar()) != EOF && i < 100; i++)
    t[i] = c;
  t[i] = '\0';
  escape(s, t);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
L23:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L38
  cmp    $0x63,%ebx
  jg     L38
  mov    %al,0x70(%rsp,%rbx,1)
  add    $0x1,%rbx
  jmp    L23
L38:
  movslq %ebp,%rbp
  movb   $0x0,0x70(%rsp,%rbp,1)
  lea    0x70(%rsp),%rsi
  mov    %rsp,%rdi
  call   <escape@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char s[100], t[100];
  int c, i;
  for (i = 0; (c = getchar()) != EOF && i < 100; i++)
    t[i] = c;
  t[i] = '\0';
  escape(s, t);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    D5(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%r12
  jmp    L21
  nopl   0x0(%rax)
L17:
  cmp    $0x64,%rbx
  je     L6
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L21:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    %eax,0x0(%r13)
  jne    L17
L31:
  mov    %rsp,%rdi
  mov    %r12,%rsi
  movb   $0x0,0x70(%rsp,%rbp,1)
  call   <escape@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  mov    $0x64,%ebp
  jmp    L31
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char s[100], t[100];
  int c, i;
  for (i = 0; (c = getchar()) != EOF && i < 100; i++)
    t[i] = c;
  t[i] = '\0';
  escape(s, t);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xe8,%rsp
  mov    D2(%rip),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x70(%rsp),%r12
  jmp    L8
  nopl   0x0(%rax)
L20:
  cmp    $0x64,%rbx
  je     L2
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
L8:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  cmp    %eax,0x0(%r13)
  jne    L20
L32:
  mov    %rsp,%rdi
  mov    %r12,%rsi
  movb   $0x0,0x70(%rsp,%rbp,1)
  call   <escape@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    $0x64,%ebp
  jmp    L32
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char s[100], t[100];
  int c, i;
  for (i = 0; (c = getchar()) != EOF && i < 100; i++)
    t[i] = c;
  t[i] = '\0';
  escape(s, t);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L22
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  jmp    L9
L22:
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
L9:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int *test(int **a2, int **b2) {
  int *temp = *a2;
  int *temp1 = *b2;
  if (*temp1 < *temp) {
    return *b2;
  } else {
    int *temp2 = (int *)malloc(sizeof(int));
    a2 = &temp2;
  }
  return *a2;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test>:
  endbr64
  push   %rbx
  mov    (%rsi),%rbx
  mov    (%rdi),%rax
  mov    (%rax),%eax
  cmp    %eax,(%rbx)
  jge    L18
L7:
  mov    %rbx,%rax
  pop    %rbx
  ret
L18:
  mov    $0x4,%edi
  call   <malloc@plt>
  jmp    L7
```

assistant: ```c
int *test(int **a2, int **b2) {
  int *temp = *a2;
  int *temp1 = *b2;
  if (*temp1 < *temp) {
    return *b2;
  } else {
    int *temp2 = (int *)malloc(sizeof(int));
    a2 = &temp2;
  }
  return *a2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test>:
  endbr64
  push   %r12
  mov    (%rsi),%r12
  mov    (%rdi),%rax
  mov    (%rax),%eax
  cmp    %eax,(%r12)
  jl     L6
  mov    $0x4,%edi
  call   <malloc@plt>
L6:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *test(int **a2, int **b2) {
  int *temp = *a2;
  int *temp1 = *b2;
  if (*temp1 < *temp) {
    return *b2;
  } else {
    int *temp2 = (int *)malloc(sizeof(int));
    a2 = &temp2;
  }
  return *a2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test>:
  endbr64
  push   %r12
  mov    (%rsi),%r12
  mov    (%rdi),%rax
  mov    (%rax),%eax
  cmp    %eax,(%r12)
  jl     L8
  mov    $0x4,%edi
  call   <malloc@plt>
L8:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
int *test(int **a2, int **b2) {
  int *temp = *a2;
  int *temp1 = *b2;
  if (*temp1 < *temp) {
    return *b2;
  } else {
    int *temp2 = (int *)malloc(sizeof(int));
    a2 = &temp2;
  }
  return *a2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L1:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L1
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
datatype: string

tool: D8: s[%d] = %d, 

assistant: ```c
void print_stack(int *stack, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    printf("s[%d] = %d, ", i, stack[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_stack>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L3
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
L11:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L11
L3:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: s[%d] = %d, 

assistant: ```c
void print_stack(int *stack, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    printf("s[%d] = %d, ", i, stack[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_stack>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   (%rax)
L1:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: s[%d] = %d, 

assistant: ```c
void print_stack(int *stack, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    printf("s[%d] = %d, ", i, stack[i]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_stack>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L18:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L18
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   (%rax)
L12:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: string

tool: D7: s[%d] = %d, 

assistant: ```c
void print_stack(int *stack, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    printf("s[%d] = %d, ", i, stack[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<TEST_cpp_predefined_macros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D119(%rip),%rax
  mov    %rax,%rsi
  lea    D105(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D101(%rip),%rax
  mov    %rax,%rsi
  lea    D142(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D66(%rip),%rax
  mov    %rax,%rsi
  lea    D105(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D65(%rip),%rax
  mov    %rax,%rsi
  lea    D105(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D123(%rip),%rax
  mov    %rax,%rsi
  lea    D105(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  lea    D68(%rip),%rax
  mov    %rax,%rsi
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <test@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D119
type_guessed: string
name: parse_data
arguments: tag: D105
type_guessed: string
name: parse_data
arguments: tag: D77
type_guessed: string
name: parse_data
arguments: tag: D56
type_guessed: string
name: parse_data
arguments: tag: D101
type_guessed: string
name: parse_data
arguments: tag: D142
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string
name: parse_data
arguments: tag: D19
type_guessed: string
name: parse_data
arguments: tag: D66
type_guessed: string
name: parse_data
arguments: tag: D65
type_guessed: string
name: parse_data
arguments: tag: D123
type_guessed: string
name: parse_data
arguments: tag: D68
type_guessed: string
name: parse_data
arguments: tag: D72
type_guessed: string

tool: D119: __8CC__

tool: D105: 1

tool: D77: __DATE__

tool: D56: "Jan 05 1980"

tool: D101: __TIME__

tool: D142: "17:55:02"

tool: D36: __FILE__

tool: D19: "-"

tool: D66: __LINE__

tool: D65: __STDC__

tool: D123: __STDC_HOSTED__

tool: D68: __STDC_VERSION__

tool: D72: 199901

assistant: ```c
void TEST_cpp_predefined_macros(void) {
  test("1", "__8CC__");
  test("\"Jan 05 1980\"", "__DATE__");
  test("\"17:55:02\"", "__TIME__");
  test("\"-\"", "__FILE__");
  test("1", "__LINE__");
  test("1", "__STDC__");
  test("1", "__STDC_HOSTED__");
  test("199901", "__STDC_VERSION__");
}
```
user: What is the c source code of the assembly code below:

```asm
<TEST_cpp_predefined_macros>:
  endbr64
  push   %rbx
  lea    D42(%rip),%rsi
  lea    D54(%rip),%rbx
  mov    %rbx,%rdi
  call   <test@plt>
  lea    D118(%rip),%rsi
  lea    D109(%rip),%rdi
  call   <test@plt>
  lea    D40(%rip),%rsi
  lea    D97(%rip),%rdi
  call   <test@plt>
  lea    D7(%rip),%rsi
  lea    D119(%rip),%rdi
  call   <test@plt>
  lea    D36(%rip),%rsi
  mov    %rbx,%rdi
  call   <test@plt>
  lea    D46(%rip),%rsi
  mov    %rbx,%rdi
  call   <test@plt>
  lea    D115(%rip),%rsi
  mov    %rbx,%rdi
  call   <test@plt>
  lea    D105(%rip),%rsi
  lea    D110(%rip),%rdi
  call   <test@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D42
type_infered: string
name: retrieve_data
arguments: tag: D54
type_infered: string
name: retrieve_data
arguments: tag: D118
type_infered: string
name: retrieve_data
arguments: tag: D109
type_infered: string
name: retrieve_data
arguments: tag: D40
type_infered: string
name: retrieve_data
arguments: tag: D97
type_infered: string
name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D119
type_infered: string
name: retrieve_data
arguments: tag: D36
type_infered: string
name: retrieve_data
arguments: tag: D46
type_infered: string
name: retrieve_data
arguments: tag: D115
type_infered: string
name: retrieve_data
arguments: tag: D105
type_infered: string
name: retrieve_data
arguments: tag: D110
type_infered: string

tool: D42: __8CC__

tool: D54: 1

tool: D118: __DATE__

tool: D109: "Jan 05 1980"

tool: D40: __TIME__

tool: D97: "17:55:02"

tool: D7: __FILE__

tool: D119: "-"

tool: D36: __LINE__

tool: D46: __STDC__

tool: D115: __STDC_HOSTED__

tool: D105: __STDC_VERSION__

tool: D110: 199901

assistant: ```c
void TEST_cpp_predefined_macros(void) {
  test("1", "__8CC__");
  test("\"Jan 05 1980\"", "__DATE__");
  test("\"17:55:02\"", "__TIME__");
  test("\"-\"", "__FILE__");
  test("1", "__LINE__");
  test("1", "__STDC__");
  test("1", "__STDC_HOSTED__");
  test("199901", "__STDC_VERSION__");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TEST_cpp_predefined_macros>:
  endbr64
  push   %rbp
  lea    D108(%rip),%rbp
  lea    D56(%rip),%rsi
  mov    %rbp,%rdi
  call   <test@plt>
  lea    D109(%rip),%rsi
  lea    D21(%rip),%rdi
  call   <test@plt>
  lea    D7(%rip),%rsi
  lea    D110(%rip),%rdi
  call   <test@plt>
  lea    D100(%rip),%rsi
  lea    D123(%rip),%rdi
  call   <test@plt>
  mov    %rbp,%rdi
  lea    D76(%rip),%rsi
  call   <test@plt>
  mov    %rbp,%rdi
  lea    D119(%rip),%rsi
  call   <test@plt>
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <test@plt>
  lea    D50(%rip),%rsi
  lea    D93(%rip),%rdi
  pop    %rbp
  jmp    1050 <test@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D108
datatype: string
name: retrieve_data
arguments: tag: D56
datatype: string
name: retrieve_data
arguments: tag: D109
datatype: string
name: retrieve_data
arguments: tag: D21
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D110
datatype: string
name: retrieve_data
arguments: tag: D100
datatype: string
name: retrieve_data
arguments: tag: D123
datatype: string
name: retrieve_data
arguments: tag: D76
datatype: string
name: retrieve_data
arguments: tag: D119
datatype: string
name: retrieve_data
arguments: tag: D15
datatype: string
name: retrieve_data
arguments: tag: D50
datatype: string
name: retrieve_data
arguments: tag: D93
datatype: string

tool: D108: 1

tool: D56: __8CC__

tool: D109: __DATE__

tool: D21: "Jan 05 1980"

tool: D7: __TIME__

tool: D110: "17:55:02"

tool: D100: __FILE__

tool: D123: "-"

tool: D76: __LINE__

tool: D119: __STDC__

tool: D15: __STDC_HOSTED__

tool: D50: __STDC_VERSION__

tool: D93: 199901

assistant: ```c
void TEST_cpp_predefined_macros(void) {
  test("1", "__8CC__");
  test("\"Jan 05 1980\"", "__DATE__");
  test("\"17:55:02\"", "__TIME__");
  test("\"-\"", "__FILE__");
  test("1", "__LINE__");
  test("1", "__STDC__");
  test("1", "__STDC_HOSTED__");
  test("199901", "__STDC_VERSION__");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<TEST_cpp_predefined_macros>:
  endbr64
  push   %rbp
  lea    D101(%rip),%rbp
  lea    D90(%rip),%rsi
  mov    %rbp,%rdi
  call   <test@plt>
  lea    D0(%rip),%rsi
  lea    D78(%rip),%rdi
  call   <test@plt>
  lea    D115(%rip),%rsi
  lea    D94(%rip),%rdi
  call   <test@plt>
  lea    D100(%rip),%rsi
  lea    D33(%rip),%rdi
  call   <test@plt>
  mov    %rbp,%rdi
  lea    D79(%rip),%rsi
  call   <test@plt>
  mov    %rbp,%rdi
  lea    D120(%rip),%rsi
  call   <test@plt>
  mov    %rbp,%rdi
  lea    D76(%rip),%rsi
  call   <test@plt>
  lea    D105(%rip),%rsi
  lea    D49(%rip),%rdi
  pop    %rbp
  jmp    1050 <test@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D101
data_type: string
name: disassemble_data
arguments: tag: D90
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D78
data_type: string
name: disassemble_data
arguments: tag: D115
data_type: string
name: disassemble_data
arguments: tag: D94
data_type: string
name: disassemble_data
arguments: tag: D100
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string
name: disassemble_data
arguments: tag: D79
data_type: string
name: disassemble_data
arguments: tag: D120
data_type: string
name: disassemble_data
arguments: tag: D76
data_type: string
name: disassemble_data
arguments: tag: D105
data_type: string
name: disassemble_data
arguments: tag: D49
data_type: string

tool: D101: 1

tool: D90: __8CC__

tool: D0: __DATE__

tool: D78: "Jan 05 1980"

tool: D115: __TIME__

tool: D94: "17:55:02"

tool: D100: __FILE__

tool: D33: "-"

tool: D79: __LINE__

tool: D120: __STDC__

tool: D76: __STDC_HOSTED__

tool: D105: __STDC_VERSION__

tool: D49: 199901

assistant: ```c
void TEST_cpp_predefined_macros(void) {
  test("1", "__8CC__");
  test("\"Jan 05 1980\"", "__DATE__");
  test("\"17:55:02\"", "__TIME__");
  test("\"-\"", "__FILE__");
  test("1", "__LINE__");
  test("1", "__STDC__");
  test("1", "__STDC_HOSTED__");
  test("199901", "__STDC_VERSION__");
}
```