ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<strtoint>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L51
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L23
  movl   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
  jmp    L23
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x14(%rbp)
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L54
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
L54:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
L33:
  cmpl   $0x0,-0x10(%rbp)
  je     L51
  negl   -0x14(%rbp)
L51:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strtoint(const char string[]) {
  int result = 0, digit = 0;
  const char *cp = string;
  int negative = 0;
  if (cp) {
    if (*cp == '-') {
      negative = 1;
      cp++;
    }
    while (*cp != 0 && *(cp + 1) != 0) {
      digit = *cp - '0';
      result += digit;
      result *= 10;
      cp++;
    }
    if (*cp) {
      digit = *cp - '0';
      result += digit;
    }
    if (negative) {
      result *= -1;
    }
  }
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<strtoint>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  je     L78
  mov    $0x0,%ecx
  cmpb   $0x2d,(%rdi)
  je     L71
L24:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L41
  mov    $0x0,%edx
L4:
  cmpb   $0x0,0x1(%rdi)
  je     L57
  movsbl %al,%eax
  lea    -0x30(%rdx,%rax,1),%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
  jmp    L79
L71:
  add    $0x1,%rdi
  mov    $0x1,%ecx
  jmp    L24
L57:
  test   %al,%al
  je     L79
  movsbl %al,%eax
  lea    -0x30(%rdx,%rax,1),%edx
L79:
  mov    %edx,%eax
  neg    %eax
  test   %ecx,%ecx
  cmovne %eax,%edx
L78:
  mov    %edx,%eax
  ret
L41:
  mov    $0x0,%edx
  jmp    L79
```

assistant: ```c
int strtoint(const char string[]) {
  int result = 0, digit = 0;
  const char *cp = string;
  int negative = 0;
  if (cp) {
    if (*cp == '-') {
      negative = 1;
      cp++;
    }
    while (*cp != 0 && *(cp + 1) != 0) {
      digit = *cp - '0';
      result += digit;
      result *= 10;
      cp++;
    }
    if (*cp) {
      digit = *cp - '0';
      result += digit;
    }
    if (negative) {
      result *= -1;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strtoint>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L32
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L29
  test   %al,%al
  je     L32
  xor    %esi,%esi
L16:
  xor    %edx,%edx
  jmp    L17
  nopl   (%rax)
L45:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %cl,%eax
  add    %edx,%edx
L17:
  movzbl 0x1(%rdi),%ecx
  lea    -0x30(%rdx,%rax,1),%r8d
  test   %cl,%cl
  jne    L45
  mov    %r8d,%eax
  neg    %eax
  test   %esi,%esi
  cmovne %eax,%r8d
L32:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L29:
  movsbl 0x1(%rdi),%eax
  mov    $0x1,%esi
  add    $0x1,%rdi
  test   %al,%al
  jne    L16
  jmp    L32
```

assistant: ```c
int strtoint(const char string[]) {
  int result = 0, digit = 0;
  const char *cp = string;
  int negative = 0;
  if (cp) {
    if (*cp == '-') {
      negative = 1;
      cp++;
    }
    while (*cp != 0 && *(cp + 1) != 0) {
      digit = *cp - '0';
      result += digit;
      result *= 10;
      cp++;
    }
    if (*cp) {
      digit = *cp - '0';
      result += digit;
    }
    if (negative) {
      result *= -1;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strtoint>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L65
  movsbl (%rdi),%eax
  cmp    $0x2d,%al
  je     L25
  test   %al,%al
  je     L65
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rax),%r8d
  xor    %esi,%esi
  test   %dl,%dl
  je     L65
  nopl   (%rax)
L5:
  add    $0x1,%rdi
  movsbl %dl,%eax
  lea    (%r8,%r8,4),%ecx
  movzbl 0x1(%rdi),%edx
  lea    -0x30(%rax,%rcx,2),%r8d
  test   %dl,%dl
  jne    L5
  test   %esi,%esi
  je     L65
L48:
  neg    %r8d
L65:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  test   %al,%al
  je     L65
  movzbl 0x2(%rdi),%edx
  lea    -0x30(%rax),%r8d
  mov    %rcx,%rdi
  mov    $0x1,%esi
  test   %dl,%dl
  jne    L5
  jmp    L48
```

assistant: ```c
int strtoint(const char string[]) {
  int result = 0, digit = 0;
  const char *cp = string;
  int negative = 0;
  if (cp) {
    if (*cp == '-') {
      negative = 1;
      cp++;
    }
    while (*cp != 0 && *(cp + 1) != 0) {
      digit = *cp - '0';
      result += digit;
      result *= 10;
      cp++;
    }
    if (*cp) {
      digit = *cp - '0';
      result += digit;
    }
    if (negative) {
      result *= -1;
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_input_fp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: r

assistant: ```c
FILE *get_input_fp(char *filename) {
  FILE *in;
  if ((in = fopen(filename, "r")) == NULL) {
    perror(filename);
    exit(1);
  }
  return (in);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_input_fp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L1:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: r

assistant: ```c
FILE *get_input_fp(char *filename) {
  FILE *in;
  if ((in = fopen(filename, "r")) == NULL) {
    perror(filename);
    exit(1);
  }
  return (in);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_input_fp>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L3:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: r

assistant: ```c
FILE *get_input_fp(char *filename) {
  FILE *in;
  if ((in = fopen(filename, "r")) == NULL) {
    perror(filename);
    exit(1);
  }
  return (in);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_input_fp>:
  endbr64
  push   %r12
  lea    D5(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L4:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
datatype: string

tool: D5: r

assistant: ```c
FILE *get_input_fp(char *filename) {
  FILE *in;
  if ((in = fopen(filename, "r")) == NULL) {
    perror(filename);
    exit(1);
  }
  return (in);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UI_CDKeyMenu_PreValidateKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x16,%eax
  jle    L3
  mov    $0xffffffff,%eax
  jmp    L78
L3:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L54
L129:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L55
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L39
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jle    L55
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L53
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L53
L55:
  addl   $0x1,-0x8(%rbp)
L53:
  addl   $0x1,-0x4(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jge    L47
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L129
L47:
  cmpl   $0xf,-0x8(%rbp)
  jle    L2
  cmpl   $0x12,-0x8(%rbp)
  jle    L74
L2:
  mov    $0xffffffff,%eax
  jmp    L78
L74:
  mov    $0x0,%eax
L78:
  leave
  ret
```

assistant: ```c
int UI_CDKeyMenu_PreValidateKey(const char *key) {
  int cnt, i;
  if (strlen(key) > 22) {
    return -1;
  }
  cnt = 0;
  for (i = 0; i < strlen(key) && key[i]; i++) {
    if ((key[i] >= '0' && key[i] <= '9') || (key[i] >= 'a' && key[i] <= 'z') || (key[i] >= 'A' && key[i] <= 'Z')) {
      cnt++;
    }
  }
  if ((cnt < 16) || (cnt > 18)) {
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<UI_CDKeyMenu_PreValidateKey>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  cmp    $0x16,%eax
  jg     L15
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L78
L24:
  add    $0x1,%r12d
L50:
  add    $0x1,%rbx
L78:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L29
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L29
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L24
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L50
  jmp    L24
L29:
  sub    $0x10,%r12d
  cmp    $0x2,%r12d
  seta   %al
  movzbl %al,%eax
  neg    %eax
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L51
```

assistant: ```c
int UI_CDKeyMenu_PreValidateKey(const char *key) {
  int cnt, i;
  if (strlen(key) > 22) {
    return -1;
  }
  cnt = 0;
  for (i = 0; i < strlen(key) && key[i]; i++) {
    if ((key[i] >= '0' && key[i] <= '9') || (key[i] >= 'a' && key[i] <= 'z') || (key[i] >= 'A' && key[i] <= 'Z')) {
      cnt++;
    }
  }
  if ((cnt < 16) || (cnt > 18)) {
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<UI_CDKeyMenu_PreValidateKey>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x16,%eax
  jg     L58
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L29
  nopl   0x0(%rax)
L45:
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L64
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L1
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L42
L1:
  add    $0x1,%r12d
L42:
  add    $0x1,%rbx
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L45
L64:
  sub    $0x10,%r12d
  xor    %eax,%eax
  cmp    $0x2,%r12d
  seta   %al
  neg    %eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  mov    $0xffffffff,%eax
  jmp    L4
```

assistant: ```c
int UI_CDKeyMenu_PreValidateKey(const char *key) {
  int cnt, i;
  if (strlen(key) > 22) {
    return -1;
  }
  cnt = 0;
  for (i = 0; i < strlen(key) && key[i]; i++) {
    if ((key[i] >= '0' && key[i] <= '9') || (key[i] >= 'a' && key[i] <= 'z') || (key[i] >= 'A' && key[i] <= 'Z')) {
      cnt++;
    }
  }
  if ((cnt < 16) || (cnt > 18)) {
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<UI_CDKeyMenu_PreValidateKey>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cmp    $0x16,%eax
  jg     L21
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L26
  nopl   0x0(%rax)
L7:
  movzbl 0x0(%rbp,%rbx,1),%eax
  test   %al,%al
  je     L40
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L17
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x19,%al
  ja     L28
L17:
  add    $0x1,%r12d
L28:
  add    $0x1,%rbx
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
L40:
  sub    $0x10,%r12d
  xor    %eax,%eax
  cmp    $0x2,%r12d
  seta   %al
  neg    %eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  mov    $0xffffffff,%eax
  jmp    L5
```

assistant: ```c
int UI_CDKeyMenu_PreValidateKey(const char *key) {
  int cnt, i;
  if (strlen(key) > 22) {
    return -1;
  }
  cnt = 0;
  for (i = 0; i < strlen(key) && key[i]; i++) {
    if ((key[i] >= '0' && key[i] <= '9') || (key[i] >= 'a' && key[i] <= 'z') || (key[i] >= 'A' && key[i] <= 'Z')) {
      cnt++;
    }
  }
  if ((cnt < 16) || (cnt > 18)) {
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<igraph_chebyshev_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L15
  mov    $0x0,%eax
  jmp    L28
L15:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L55
L23:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L43
  mov    -0x10(%rbp),%eax
  jmp    L28
L43:
  addl   $0x1,-0xc(%rbp)
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L23
  mov    -0x10(%rbp),%eax
L28:
  leave
  ret
```

assistant: ```c
int igraph_chebyshev_init(const double *dos, int nos, double eta) {
  int i, ii;
  double err;
  if (nos < 1)
    return 0;
  err = 0.0;
  i = 0;
  for (ii = 1; ii <= nos; ii++) {
    i = nos - ii;
    err += fabs(dos[i]);
    if (err > eta) {
      return i;
    }
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<igraph_chebyshev_init>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%r13d
  test   %esi,%esi
  jle    L21
  mov    %esi,%r12d
  movslq %esi,%rax
  lea    (%rdi,%rax,8),%rbp
  pxor   %xmm3,%xmm3
  movsd  %xmm3,(%rsp)
  mov    $0x1,%ebx
L20:
  mov    %r12d,%r13d
  sub    %ebx,%r13d
  movsd  -0x8(%rbp),%xmm0
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  comisd 0x8(%rsp),%xmm0
  ja     L21
  add    $0x1,%ebx
  sub    $0x8,%rbp
  cmp    %ebx,%r12d
  jge    L20
L21:
  mov    %r13d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int igraph_chebyshev_init(const double *dos, int nos, double eta) {
  int i, ii;
  double err;
  if (nos < 1)
    return 0;
  err = 0.0;
  i = 0;
  for (ii = 1; ii <= nos; ii++) {
    i = nos - ii;
    err += fabs(dos[i]);
    if (err > eta) {
      return i;
    }
  }
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<igraph_chebyshev_init>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %esi,%esi
  jle    L3
  movslq %esi,%rax
  mov    %esi,%r12d
  pxor   %xmm1,%xmm1
  mov    $0x1,%ebx
  lea    (%rdi,%rax,8),%rbp
  xchg   %ax,%ax
L16:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm1,(%rsp)
  mov    %r12d,%r13d
  sub    %ebx,%r13d
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  comisd 0x8(%rsp),%xmm1
  ja     L3
  add    $0x1,%ebx
  sub    $0x8,%rbp
  cmp    %ebx,%r12d
  jge    L16
L3:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int igraph_chebyshev_init(const double *dos, int nos, double eta) {
  int i, ii;
  double err;
  if (nos < 1)
    return 0;
  err = 0.0;
  i = 0;
  for (ii = 1; ii <= nos; ii++) {
    i = nos - ii;
    err += fabs(dos[i]);
    if (err > eta) {
      return i;
    }
  }
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<igraph_chebyshev_init>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  test   %esi,%esi
  jle    L9
  movslq %esi,%rax
  mov    %esi,%r12d
  pxor   %xmm1,%xmm1
  mov    $0x1,%ebx
  lea    (%rdi,%rax,8),%rbp
  xchg   %ax,%ax
L29:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm1,(%rsp)
  mov    %r12d,%r13d
  sub    %ebx,%r13d
  call   <fabs@plt>
  pxor   %xmm0,%xmm0
  movsd  (%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  addsd  %xmm0,%xmm1
  comisd 0x8(%rsp),%xmm1
  ja     L9
  add    $0x1,%ebx
  sub    $0x8,%rbp
  cmp    %ebx,%r12d
  jge    L29
L9:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int igraph_chebyshev_init(const double *dos, int nos, double eta) {
  int i, ii;
  double err;
  if (nos < 1)
    return 0;
  err = 0.0;
  i = 0;
  for (ii = 1; ii <= nos; ii++) {
    i = nos - ii;
    err += fabs(dos[i]);
    if (err > eta) {
      return i;
    }
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<substringcln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L15
L22:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isgraph@plt>
  test   %rax,%rax
  je     L21
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L21:
  addq   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L22
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *substringcln(const char *start, const char *end) {
  char *result = malloc(end - start + 1);
  char *scan_result = result;
  const char *scan = start;
  while (scan < end) {
    if (isgraph(*scan))
      *scan_result++ = *scan;
    scan++;
  }
  *scan_result = 0;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<substringcln>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rsi,%rdi
  sub    %rbx,%rdi
  add    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  cmp    %rbx,%r12
  jbe    L37
  mov    %rax,%rbp
  jmp    L16
L30:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  je     L35
L16:
  movsbl (%rbx),%edi
  call   <isgraph@plt>
  test   %rax,%rax
  je     L30
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L30
L37:
  mov    %rax,%rbp
L35:
  movb   $0x0,0x0(%rbp)
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substringcln(const char *start, const char *end) {
  char *result = malloc(end - start + 1);
  char *scan_result = result;
  const char *scan = start;
  while (scan < end) {
    if (isgraph(*scan))
      *scan_result++ = *scan;
    scan++;
  }
  *scan_result = 0;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<substringcln>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    %rbx,%rdi
  add    $0x1,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  cmp    %rbx,%r12
  jbe    L8
  nopl   (%rax)
L10:
  movsbl (%rbx),%edi
  call   <isgraph@plt>
  test   %rax,%rax
  je     L17
  movzbl (%rbx),%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
L17:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L10
L8:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substringcln(const char *start, const char *end) {
  char *result = malloc(end - start + 1);
  char *scan_result = result;
  const char *scan = start;
  while (scan < end) {
    if (isgraph(*scan))
      *scan_result++ = *scan;
    scan++;
  }
  *scan_result = 0;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<substringcln>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    %rbx,%rdi
  add    $0x1,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbp
  cmp    %rbx,%r12
  jbe    L7
  nopl   (%rax)
L9:
  movsbl (%rbx),%edi
  call   <isgraph@plt>
  test   %rax,%rax
  je     L21
  movzbl (%rbx),%eax
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
L21:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L9
L7:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *substringcln(const char *start, const char *end) {
  char *result = malloc(end - start + 1);
  char *scan_result = result;
  const char *scan = start;
  while (scan < end) {
    if (isgraph(*scan))
      *scan_result++ = *scan;
    scan++;
  }
  *scan_result = 0;
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imv_window_get_mouse_position>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void imv_window_get_mouse_position(struct imv_window *window, double *x, double *y) {
  (void)window;
  (void)x;
  (void)y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<imv_window_get_mouse_position>:
  endbr64
  ret
```

assistant: ```c
void imv_window_get_mouse_position(struct imv_window *window, double *x, double *y) {
  (void)window;
  (void)x;
  (void)y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<imv_window_get_mouse_position>:
  endbr64
  ret
```

assistant: ```c
void imv_window_get_mouse_position(struct imv_window *window, double *x, double *y) {
  (void)window;
  (void)x;
  (void)y;
}
```