ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movw   $0x0,-0x2(%rbp)
  jmp    L5
L23:
  movswq -0x2(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  test   %ax,%ax
  jne    L37
  movzwl -0x2(%rbp),%eax
  jmp    L16
L37:
  movzwl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0x2(%rbp)
L5:
  cmpw   $0xf,-0x2(%rbp)
  jle    L23
L16:
  pop    %rbp
  ret
```

assistant: ```c
short find_pos(short *puzzle) {
  short i;
  for (i = 0; i < 16; i++)
    if (puzzle[i] == 0)
      return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_pos>:
  endbr64
  mov    $0x0,%eax
L2:
  mov    %eax,%edx
  cmpw   $0x0,(%rdi,%rax,2)
  je     L1
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L2
L1:
  mov    %edx,%eax
  ret
```

assistant: ```c
short find_pos(short *puzzle) {
  short i;
  for (i = 0; i < 16; i++)
    if (puzzle[i] == 0)
      return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_pos>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L2:
  cmpw   $0x0,(%rdi,%rax,2)
  mov    %eax,%r8d
  je     L3
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L2
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
short find_pos(short *puzzle) {
  short i;
  for (i = 0; i < 16; i++)
    if (puzzle[i] == 0)
      return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_pos>:
  endbr64
  movzwl (%rdi),%eax
  test   %ax,%ax
  je     L54
  cmpw   $0x0,0x2(%rdi)
  je     L37
  cmpw   $0x0,0x4(%rdi)
  je     L59
  cmpw   $0x0,0x6(%rdi)
  je     L33
  cmpw   $0x0,0x8(%rdi)
  je     L132
  cmpw   $0x0,0xa(%rdi)
  je     L86
  cmpw   $0x0,0xc(%rdi)
  je     L134
  cmpw   $0x0,0xe(%rdi)
  je     L151
  cmpw   $0x0,0x10(%rdi)
  je     L117
  cmpw   $0x0,0x12(%rdi)
  je     L81
  cmpw   $0x0,0x14(%rdi)
  je     L48
  cmpw   $0x0,0x16(%rdi)
  je     L105
  cmpw   $0x0,0x18(%rdi)
  je     L27
  cmpw   $0x0,0x1a(%rdi)
  je     L124
  cmpw   $0x0,0x1c(%rdi)
  je     L123
  cmpw   $0x0,0x1e(%rdi)
  je     L51
L54:
  ret
L37:
  mov    $0x1,%eax
  ret
L27:
  mov    $0xc,%eax
  ret
L51:
  mov    $0xf,%eax
  ret
L59:
  mov    $0x2,%eax
  ret
L33:
  mov    $0x3,%eax
  ret
L132:
  mov    $0x4,%eax
  ret
L86:
  mov    $0x5,%eax
  ret
L134:
  mov    $0x6,%eax
  ret
L151:
  mov    $0x7,%eax
  ret
L117:
  mov    $0x8,%eax
  ret
L81:
  mov    $0x9,%eax
  ret
L48:
  mov    $0xa,%eax
  ret
L105:
  mov    $0xb,%eax
  ret
L124:
  mov    $0xd,%eax
  ret
L123:
  mov    $0xe,%eax
  ret
```

assistant: ```c
short find_pos(short *puzzle) {
  short i;
  for (i = 0; i < 16; i++)
    if (puzzle[i] == 0)
      return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_quadrado_magico>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x6,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x8,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <quadrado_magico@plt>
  test   %eax,%eax
  jne    L29
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L19
L29:
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
type: string
name: extract_symbolic_data
arguments: data_tag: D31
type: string
name: extract_symbolic_data
arguments: data_tag: D37
type: string
name: extract_symbolic_data
arguments: data_tag: D28
type: string

tool: D32: ------------------------------------


tool: D31: teste Q7: quadrado_magico.


tool: D37:     ok.


tool: D28:     not ok.


assistant: ```c
void test_quadrado_magico() {
  printf("------------------------------------\n");
  printf("teste Q7: quadrado_magico.\n");
  int mat[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  if (quadrado_magico(mat) == false) {
    printf("    ok.\n");
  } else {
    printf("    not ok.\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_quadrado_magico>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x7,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x9,0x20(%rsp)
  mov    %rsp,%rdi
  call   <quadrado_magico@plt>
  test   %eax,%eax
  jne    L4
  lea    D36(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x38,%rsp
  ret
L4:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D15
data_type: string
name: read_data
arguments: data_tag: D1
data_type: string
name: read_data
arguments: data_tag: D36
data_type: string
name: read_data
arguments: data_tag: D32
data_type: string

tool: D15: ------------------------------------


tool: D1: teste Q7: quadrado_magico.


tool: D36:     ok.


tool: D32:     not ok.


assistant: ```c
void test_quadrado_magico() {
  printf("------------------------------------\n");
  printf("teste Q7: quadrado_magico.\n");
  int mat[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  if (quadrado_magico(mat) == false) {
    printf("    ok.\n");
  } else {
    printf("    not ok.\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_quadrado_magico>:
  endbr64
  sub    $0x38,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  movl   $0x9,0x20(%rsp)
  movabs $0x200000001,%rax
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000005,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x800000007,%rax
  mov    %rax,0x18(%rsp)
  call   <quadrado_magico@plt>
  test   %eax,%eax
  jne    L21
  lea    D14(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L21:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D14
type: string
name: parse_data
arguments: tag: D38
type: string

tool: D19: ------------------------------------


tool: D11: teste Q7: quadrado_magico.


tool: D14:     ok.


tool: D38:     not ok.


assistant: ```c
void test_quadrado_magico() {
  printf("------------------------------------\n");
  printf("teste Q7: quadrado_magico.\n");
  int mat[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  if (quadrado_magico(mat) == false) {
    printf("    ok.\n");
  } else {
    printf("    not ok.\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_quadrado_magico>:
  endbr64
  sub    $0x38,%rsp
  lea    D44(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  movdqa D34(%rip),%xmm0
  mov    %rsp,%rdi
  movl   $0x9,0x20(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <quadrado_magico@plt>
  test   %eax,%eax
  jne    L15
  lea    D20(%rip),%rdi
  call   <printf@plt>
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x38,%rsp
  ret
  xchg   %ax,%ax
L15:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L21
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D44
datatype: string
name: parse_data
arguments: tag: D45
datatype: string
name: parse_data
arguments: tag: D34
datatype: byte[16]
name: parse_data
arguments: tag: D5
datatype: byte[16]
name: parse_data
arguments: tag: D20
datatype: string
name: parse_data
arguments: tag: D38
datatype: string

tool: D44: ------------------------------------


tool: D45: teste Q7: quadrado_magico.


tool: {"D34": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D5": [0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00]}

tool: D20:     ok.


tool: D38:     not ok.


assistant: ```c
void test_quadrado_magico() {
  printf("------------------------------------\n");
  printf("teste Q7: quadrado_magico.\n");
  int mat[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
  if (quadrado_magico(mat) == false) {
    printf("    ok.\n");
  } else {
    printf("    not ok.\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x61,%edi
  call   <putc@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  putc('a', stdout);
  putc('\n', stdout);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
  mov    (%rbx),%esi
  mov    $0x61,%edi
  call   <putc@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <putc@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  putc('a', stdout);
  putc('\n', stdout);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
  mov    $0x61,%edi
  mov    (%rbx),%esi
  call   <putc@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <putc@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  putc('a', stdout);
  putc('\n', stdout);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
  mov    $0x61,%edi
  mov    (%rbx),%esi
  call   <putc@plt>
  mov    (%rbx),%esi
  mov    $0xa,%edi
  call   <putc@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  putc('a', stdout);
  putc('\n', stdout);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L37
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L15
L37:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <authenticate@plt>
  test   %rax,%rax
  je     L32
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L4
L32:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L4:
  mov    $0x0,%eax
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
type: string
name: parse_data
arguments: data_tag: D27
type: string
name: parse_data
arguments: data_tag: D17
type: string

tool: D23: Provide password as a parameter.

tool: D27: Access GRANTED.

tool: D17: Access REFUSED.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    puts("Provide password as a parameter.");
    return 1;
  }
  if (authenticate(argv[1])) {
    puts("Access GRANTED.");
  } else {
    puts("Access REFUSED.");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L4
  mov    0x8(%rsi),%rdi
  call   <authenticate@plt>
  test   %rax,%rax
  je     L13
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L17:
  add    $0x8,%rsp
  ret
L4:
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L17
L13:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L17
```

tool_calls: name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string

tool: D22: Access GRANTED.

tool: D5: Provide password as a parameter.

tool: D0: Access REFUSED.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    puts("Provide password as a parameter.");
    return 1;
  }
  if (authenticate(argv[1])) {
    puts("Access GRANTED.");
  } else {
    puts("Access REFUSED.");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L12
  mov    0x8(%rsi),%rdi
  call   <authenticate@plt>
  test   %rax,%rax
  jne    L32
  lea    D0(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
L39:
  add    $0x8,%rsp
  ret
L32:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L39
L12:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L39
```

tool_calls: name: unpack_data
arguments: label: D0
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D21
type: string

tool: D0: Access REFUSED.

tool: D23: Access GRANTED.

tool: D21: Provide password as a parameter.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    puts("Provide password as a parameter.");
    return 1;
  }
  if (authenticate(argv[1])) {
    puts("Access GRANTED.");
  } else {
    puts("Access REFUSED.");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L7
  mov    0x8(%rsi),%rdi
  call   <authenticate@plt>
  test   %rax,%rax
  jne    L17
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
L26:
  add    $0x8,%rsp
  ret
L17:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  jmp    L26
L7:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L26
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D3
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string

tool: D6: Access REFUSED.

tool: D3: Access GRANTED.

tool: D24: Provide password as a parameter.

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc < 2) {
    puts("Provide password as a parameter.");
    return 1;
  }
  if (authenticate(argv[1])) {
    puts("Access GRANTED.");
  } else {
    puts("Access REFUSED.");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<slibbasename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L54
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L41
L54:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L24
L111:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L104
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L104
  subl   $0x1,-0x10(%rbp)
L24:
  cmpl   $0x0,-0x10(%rbp)
  jns    L111
L104:
  mov    -0x8(%rbp),%eax
  sub    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x18(%rbp),%rax
  mov    $0xffffffff,%ecx
  mov    %rax,%rdi
  call   <slibcpy@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L41
  cmpl   $0x0,-0x24(%rbp)
  jne    L41
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L57
L100:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L103
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L41
L103:
  addl   $0x1,-0x10(%rbp)
L57:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L100
L41:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int slibbasename(char **sbase, char *spath, int withext) {
  int i, iErr = 0;
  int spath_len;
  int sbase_len;
  if (spath == 0) {
    *sbase = 0;
  } else {
    spath_len = strlen(spath);
    for (i = spath_len - 1; i >= 0; i--)
      if (spath[i] == '\\' || spath[i] == '/')
        break;
    iErr = slibcpy(sbase, spath + i + 1, spath_len - i - 1, -1);
    if (iErr == 0 && !withext) {
      sbase_len = strlen(*sbase);
      for (i = 0; i < sbase_len; i++)
        if ((*sbase)[i] == '.') {
          (*sbase)[i] = 0;
          break;
        }
    }
  }
  return iErr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<slibbasename>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rsi,%rsi
  je     L76
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L96
  movslq %ecx,%rsi
  add    %rbx,%rsi
L81:
  movzbl (%rsi),%edi
  cmp    $0x5c,%dil
  je     L96
  cmp    $0x2f,%dil
  je     L96
  sub    $0x1,%ecx
  sub    $0x1,%rsi
  cmp    $0xffffffff,%ecx
  jne    L81
L96:
  sub    %ecx,%eax
  lea    -0x1(%rax),%edx
  movslq %ecx,%rcx
  lea    0x1(%rbx,%rcx,1),%rsi
  mov    $0xffffffff,%ecx
  mov    %r12,%rdi
  call   <slibcpy@plt>
  or     %eax,%ebp
  jne    L43
  mov    (%r12),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L25
  mov    (%r12),%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rdx,%rax,1),%rcx
L68:
  cmpb   $0x2e,(%rdx)
  je     L92
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L68
  mov    %ebp,%eax
  jmp    L43
L76:
  movq   $0x0,(%rdi)
  mov    $0x0,%eax
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L92:
  movb   $0x0,(%rdx)
  mov    %ebp,%eax
  jmp    L43
L25:
  mov    %ebp,%eax
  jmp    L43
```

assistant: ```c
int slibbasename(char **sbase, char *spath, int withext) {
  int i, iErr = 0;
  int spath_len;
  int sbase_len;
  if (spath == 0) {
    *sbase = 0;
  } else {
    spath_len = strlen(spath);
    for (i = spath_len - 1; i >= 0; i--)
      if (spath[i] == '\\' || spath[i] == '/')
        break;
    iErr = slibcpy(sbase, spath + i + 1, spath_len - i - 1, -1);
    if (iErr == 0 && !withext) {
      sbase_len = strlen(*sbase);
      for (i = 0; i < sbase_len; i++)
        if ((*sbase)[i] == '.') {
          (*sbase)[i] = 0;
          break;
        }
    }
  }
  return iErr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<slibbasename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L46
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    %edx,%esi
  sub    $0x1,%esi
  js     L91
  movslq %esi,%rcx
  add    %rbp,%rcx
  nopl   0x0(%rax)
L36:
  movzbl (%rcx),%edi
  mov    %rcx,%r8
  cmp    $0x5c,%dil
  je     L129
  cmp    $0x2f,%dil
  je     L129
  sub    $0x1,%esi
  sub    $0x1,%rcx
  cmp    $0xffffffff,%esi
  jne    L36
L112:
  mov    $0xffffffff,%ecx
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <slibcpy@plt>
  or     %eax,%ebx
  je     L99
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L46:
  movq   $0x0,(%rdi)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L129:
  sub    %esi,%edx
  add    $0x1,%esi
  movslq %esi,%rsi
  sub    $0x1,%edx
  lea    0x0(%rbp,%rsi,1),%r8
  jmp    L112
  nopw   0x0(%rax,%rax,1)
L99:
  mov    (%r12),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L79
  mov    (%r12),%rdx
  sub    $0x1,%eax
  lea    0x1(%rdx,%rax,1),%rax
  jmp    L84
  nopl   0x0(%rax,%rax,1)
L70:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L79
L84:
  cmpb   $0x2e,(%rdx)
  jne    L70
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  jmp    L50
  nopl   (%rax)
L79:
  xor    %eax,%eax
  jmp    L50
L91:
  lea    0x0(%rbp,%rdx,1),%r8
  xor    %edx,%edx
  jmp    L112
```

assistant: ```c
int slibbasename(char **sbase, char *spath, int withext) {
  int i, iErr = 0;
  int spath_len;
  int sbase_len;
  if (spath == 0) {
    *sbase = 0;
  } else {
    spath_len = strlen(spath);
    for (i = spath_len - 1; i >= 0; i--)
      if (spath[i] == '\\' || spath[i] == '/')
        break;
    iErr = slibcpy(sbase, spath + i + 1, spath_len - i - 1, -1);
    if (iErr == 0 && !withext) {
      sbase_len = strlen(*sbase);
      for (i = 0; i < sbase_len; i++)
        if ((*sbase)[i] == '.') {
          (*sbase)[i] = 0;
          break;
        }
    }
  }
  return iErr;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<slibbasename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L25
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    %edx,%esi
  sub    $0x1,%esi
  js     L48
  movslq %esi,%rcx
  add    %rbp,%rcx
  nopl   0x0(%rax)
L137:
  movzbl (%rcx),%edi
  mov    %rcx,%r8
  cmp    $0x5c,%dil
  je     L129
  cmp    $0x2f,%dil
  je     L129
  sub    $0x1,%esi
  sub    $0x1,%rcx
  cmp    $0xffffffff,%esi
  jne    L137
L17:
  mov    $0xffffffff,%ecx
  mov    %r8,%rsi
  mov    %r12,%rdi
  call   <slibcpy@plt>
  or     %eax,%ebx
  je     L94
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L25:
  movq   $0x0,(%rdi)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L129:
  sub    %esi,%edx
  add    $0x1,%esi
  movslq %esi,%rsi
  sub    $0x1,%edx
  lea    0x0(%rbp,%rsi,1),%r8
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L94:
  mov    (%r12),%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L78
  mov    (%r12),%rdx
  sub    $0x1,%eax
  lea    0x1(%rdx,%rax,1),%rax
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L78
L97:
  cmpb   $0x2e,(%rdx)
  jne    L0
  movb   $0x0,(%rdx)
  xor    %eax,%eax
  jmp    L12
  nopl   (%rax)
L78:
  xor    %eax,%eax
  jmp    L12
L48:
  lea    0x0(%rbp,%rdx,1),%r8
  xor    %edx,%edx
  jmp    L17
```

assistant: ```c
int slibbasename(char **sbase, char *spath, int withext) {
  int i, iErr = 0;
  int spath_len;
  int sbase_len;
  if (spath == 0) {
    *sbase = 0;
  } else {
    spath_len = strlen(spath);
    for (i = spath_len - 1; i >= 0; i--)
      if (spath[i] == '\\' || spath[i] == '/')
        break;
    iErr = slibcpy(sbase, spath + i + 1, spath_len - i - 1, -1);
    if (iErr == 0 && !withext) {
      sbase_len = strlen(*sbase);
      for (i = 0; i < sbase_len; i++)
        if ((*sbase)[i] == '.') {
          (*sbase)[i] = 0;
          break;
        }
    }
  }
  return iErr;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rcon>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L31
L5:
  movl   $0x1,-0x8(%rbp)
  jmp    L8
L10:
  mov    -0x8(%rbp),%eax
  and    $0x80,%eax
  mov    %eax,-0x4(%rbp)
  shll   -0x8(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  jne    L23
  xorl   $0x1b,-0x8(%rbp)
L23:
  subl   $0x1,-0x14(%rbp)
L8:
  cmpl   $0x1,-0x14(%rbp)
  jne    L10
  mov    -0x8(%rbp),%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t rcon(uint8_t in) {
  if (in == 0) {
    return 0;
  }
  uint8_t c = 1;
  while (in != 1) {
    uint8_t b = c & 0x80;
    c <<= 1;
    if (b == 0x80) {
      c ^= 0x1b;
    }
    in--;
  }
  return c;
}
```