ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pop_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x3c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x8,-0x1c(%rbp)
  jne    L59
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L62
L59:
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L62:
  movl   $0x0,-0x20(%rbp)
  jmp    L23
L8:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x20(%rbp)
L23:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  cmpl   $0x8,-0x1c(%rbp)
  jne    L30
  movsd  -0x18(%rbp),%xmm0
  jmp    L16
L30:
  movss  -0x24(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
L16:
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double pop_float(char *source, int num_bits) {
  int i, size = num_bits / 8;
  float float_val;
  double double_val;
  char *dest;
  if (size == sizeof(double))
    dest = (char *)(&double_val);
  else
    dest = (char *)(&float_val);
  for (i = 0; i < size; i++)
    dest[i] = source[i];
  if (size == sizeof(double))
    return double_val;
  else
    return float_val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pop_float>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsi),%ecx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x3,%ecx
  cmp    $0x8,%ecx
  je     L39
  lea    0xc(%rsp),%r8
  cmp    $0x7,%esi
  jle    L25
L35:
  mov    $0x0,%eax
L16:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L16
  movsd  0x10(%rsp),%xmm0
  cmp    $0x8,%ecx
  je     L21
L25:
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
L21:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x28,%rsp
  ret
L39:
  lea    0x10(%rsp),%r8
  jmp    L35
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double pop_float(char *source, int num_bits) {
  int i, size = num_bits / 8;
  float float_val;
  double double_val;
  char *dest;
  if (size == sizeof(double))
    dest = (char *)(&double_val);
  else
    dest = (char *)(&float_val);
  for (i = 0; i < size; i++)
    dest[i] = source[i];
  if (size == sizeof(double))
    return double_val;
  else
    return float_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pop_float>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x3,%eax
  cmp    $0x8,%eax
  je     L3
  cmp    $0x7,%esi
  jle    L17
  lea    0x4(%rsp),%r8
  lea    -0x1(%rax),%edx
  mov    %rdi,%rsi
  add    $0x1,%rdx
  mov    %r8,%rdi
  call   <memcpy@plt>
L17:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movsd  (%rdi),%xmm0
  jmp    L10
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double pop_float(char *source, int num_bits) {
  int i, size = num_bits / 8;
  float float_val;
  double double_val;
  char *dest;
  if (size == sizeof(double))
    dest = (char *)(&double_val);
  else
    dest = (char *)(&float_val);
  for (i = 0; i < size; i++)
    dest[i] = source[i];
  if (size == sizeof(double))
    return double_val;
  else
    return float_val;
}
```
user: What is the c source code of the assembly code below?

```asm
<pop_float>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x3,%eax
  cmp    $0x8,%eax
  je     L14
  cmp    $0x7,%esi
  jle    L37
  lea    0x4(%rsp),%r8
  lea    -0x1(%rax),%edx
  mov    %rdi,%rsi
  add    $0x1,%rdx
  mov    %r8,%rdi
  call   <memcpy@plt>
L37:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movsd  (%rdi),%xmm0
  jmp    L20
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double pop_float(char *source, int num_bits) {
  int i, size = num_bits / 8;
  float float_val;
  double double_val;
  char *dest;
  if (size == sizeof(double))
    dest = (char *)(&double_val);
  else
    dest = (char *)(&float_val);
  for (i = 0; i < size; i++)
    dest[i] = source[i];
  if (size == sizeof(double))
    return double_val;
  else
    return float_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sem_v>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <semop@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int sem_v(int semid) {
  struct sembuf buf = {
      .sem_num = 0,
      .sem_op = 1,
      .sem_flg = SEM_UNDO,
  };
  return semop(semid, &buf, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sem_v>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0xc(%rsp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x1,%edx
  call   <semop@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sem_v(int semid) {
  struct sembuf buf = {
      .sem_num = 0,
      .sem_op = 1,
      .sem_flg = SEM_UNDO,
  };
  return semop(semid, &buf, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sem_v>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0xc(%rsp),%rsi
  movl   $0x1,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sem_v(int semid) {
  struct sembuf buf = {
      .sem_num = 0,
      .sem_op = 1,
      .sem_flg = SEM_UNDO,
  };
  return semop(semid, &buf, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sem_v>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  lea    0xc(%rsp),%rsi
  movl   $0x1,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x10(%rsp)
  call   <semop@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sem_v(int semid) {
  struct sembuf buf = {
      .sem_num = 0,
      .sem_op = 1,
      .sem_flg = SEM_UNDO,
  };
  return semop(semid, &buf, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<asciiToUtf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L32:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  test   %al,%al
  js     L8
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  jmp    L12
L8:
  movzbl -0x9(%rbp),%eax
  shr    $0x6,%al
  or     $0xffffffc0,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movzbl -0x9(%rbp),%eax
  and    $0x3f,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  or     $0xffffff80,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *asciiToUtf8(char *ascii, char *utf8) {
  int i = 0, j = 0;
  unsigned char c;
  while (ascii[i]) {
    c = ascii[i++];
    if (c < 128) {
      utf8[j++] = c;
    } else {
      utf8[j++] = 0xC0 | (c >> 6);
      utf8[j++] = 0x80 | (c & 0x3f);
    }
  }
  utf8[j] = 0;
  return utf8;
}
```
user: What is the c source code of the assembly code below?

```asm
<asciiToUtf8>:
  endbr64
  mov    %rsi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L17
  add    $0x1,%rdi
  mov    $0x0,%ecx
  jmp    L32
L34:
  movslq %ecx,%rsi
  mov    %dl,(%rax,%rsi,1)
  lea    0x1(%rcx),%ecx
L2:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L11
L32:
  test   %dl,%dl
  jns    L34
  lea    0x1(%rcx),%esi
  movslq %ecx,%r9
  mov    %edx,%r8d
  shr    $0x6,%r8b
  or     $0xffffffc0,%r8d
  mov    %r8b,(%rax,%r9,1)
  add    $0x2,%ecx
  movslq %esi,%rsi
  and    $0x3f,%edx
  or     $0xffffff80,%edx
  mov    %dl,(%rax,%rsi,1)
  jmp    L2
L17:
  mov    $0x0,%ecx
L11:
  movslq %ecx,%rcx
  movb   $0x0,(%rax,%rcx,1)
  ret
```

assistant: ```c
char *asciiToUtf8(char *ascii, char *utf8) {
  int i = 0, j = 0;
  unsigned char c;
  while (ascii[i]) {
    c = ascii[i++];
    if (c < 128) {
      utf8[j++] = c;
    } else {
      utf8[j++] = 0xC0 | (c >> 6);
      utf8[j++] = 0x80 | (c & 0x3f);
    }
  }
  utf8[j] = 0;
  return utf8;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<asciiToUtf8>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rsi,%rax
  test   %dl,%dl
  je     L18
  add    $0x1,%rdi
  xor    %ecx,%ecx
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L20:
  add    $0x1,%rdi
  mov    %dl,(%r8)
  mov    %r9d,%ecx
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  je     L30
L7:
  movslq %ecx,%r8
  lea    0x1(%rcx),%r9d
  add    %rax,%r8
  test   %dl,%dl
  jns    L20
  mov    %edx,%esi
  and    $0x3f,%edx
  movslq %r9d,%r9
  add    $0x1,%rdi
  shr    $0x6,%sil
  or     $0xffffff80,%edx
  add    $0x2,%ecx
  or     $0xffffffc0,%esi
  mov    %sil,(%r8)
  mov    %dl,(%rax,%r9,1)
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L7
L30:
  movslq %ecx,%rcx
  add    %rax,%rcx
  movb   $0x0,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rsi,%rcx
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *asciiToUtf8(char *ascii, char *utf8) {
  int i = 0, j = 0;
  unsigned char c;
  while (ascii[i]) {
    c = ascii[i++];
    if (c < 128) {
      utf8[j++] = c;
    } else {
      utf8[j++] = 0xC0 | (c >> 6);
      utf8[j++] = 0x80 | (c & 0x3f);
    }
  }
  utf8[j] = 0;
  return utf8;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<asciiToUtf8>:
  endbr64
  movzbl (%rdi),%eax
  mov    %rsi,%r8
  test   %al,%al
  je     L15
  xor    %edx,%edx
  add    $0x1,%rdi
  movslq %edx,%rcx
  lea    (%r8,%rcx,1),%rsi
  lea    0x1(%rdx),%ecx
  test   %al,%al
  js     L46
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rdi
  mov    %al,(%rsi)
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L28
L26:
  mov    %ecx,%edx
  movslq %edx,%rcx
  lea    (%r8,%rcx,1),%rsi
  lea    0x1(%rdx),%ecx
  test   %al,%al
  jns    L6
L46:
  mov    %eax,%r9d
  and    $0x3f,%eax
  movslq %ecx,%rcx
  add    $0x1,%rdi
  shr    $0x6,%r9b
  or     $0xffffff80,%eax
  add    $0x2,%edx
  or     $0xffffffc0,%r9d
  mov    %r9b,(%rsi)
  mov    %al,(%r8,%rcx,1)
  movzbl -0x1(%rdi),%eax
  mov    %edx,%ecx
  test   %al,%al
  jne    L26
L28:
  movslq %ecx,%rcx
  mov    %r8,%rax
  add    %r8,%rcx
  movb   $0x0,(%rcx)
  ret
  nop
L15:
  mov    %rsi,%rcx
  mov    %r8,%rax
  movb   $0x0,(%rcx)
  ret
```

assistant: ```c
char *asciiToUtf8(char *ascii, char *utf8) {
  int i = 0, j = 0;
  unsigned char c;
  while (ascii[i]) {
    c = ascii[i++];
    if (c < 128) {
      utf8[j++] = c;
    } else {
      utf8[j++] = 0xC0 | (c >> 6);
      utf8[j++] = 0x80 | (c & 0x3f);
    }
  }
  utf8[j] = 0;
  return utf8;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply400>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L29
L0:
  movl   $0x0,-0x3c(%rbp)
  jmp    L27
L9:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L27:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L9
  addl   $0x1,-0x40(%rbp)
L29:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L0
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply400(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply400>:
  endbr64
  test   %edi,%edi
  jle    L22
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L0:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L11:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L11
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  ret
```

assistant: ```c
void multiply400(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply400>:
  endbr64
  test   %edi,%edi
  jle    L2
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L27
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L24
  pop    %rbx
  ret
L2:
  ret
```

assistant: ```c
void multiply400(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply400>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L99
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L89:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L80
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L80
  nopl   0x0(%rax)
L67:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L67
  cmp    -0x24(%rsp),%r11d
  je     L27
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L27
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L27
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L27:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L89
L99:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L80:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L41:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L41
  mov    -0x18(%rsp),%r8
  jmp    L27
```

assistant: ```c
void multiply400(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_unlock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  movq   $0x0,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int do_unlock(int fd) {
  struct flock fl;
  memset((void *)&fl, 0, sizeof(fl));
  fl.l_type = F_UNLCK;
  fl.l_whence = fl.l_start = 0;
  fl.l_len = 0;
  return fcntl(fd, F_SETLK, &fl);
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_unlock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x20,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x18(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,(%rsp)
  mov    %rbp,%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_unlock(int fd) {
  struct flock fl;
  memset((void *)&fl, 0, sizeof(fl));
  fl.l_type = F_UNLCK;
  fl.l_whence = fl.l_start = 0;
  fl.l_len = 0;
  return fcntl(fd, F_SETLK, &fl);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<do_unlock>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x20,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D3(%rip),%rax
  mov    %r12,%rdx
  mov    %ebp,%edi
  movq   $0x0,0x8(%rsp)
  mov    (%rax),%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %eax,0x18(%rsp)
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_unlock(int fd) {
  struct flock fl;
  memset((void *)&fl, 0, sizeof(fl));
  fl.l_type = F_UNLCK;
  fl.l_whence = fl.l_start = 0;
  fl.l_len = 0;
  return fcntl(fd, F_SETLK, &fl);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_unlock>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x20,%edx
  push   %rbp
  mov    %edi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <memset@plt>
  pxor   %xmm0,%xmm0
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    D15(%rip),%rax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    (%rax),%eax
  mov    %eax,0x18(%rsp)
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int do_unlock(int fd) {
  struct flock fl;
  memset((void *)&fl, 0, sizeof(fl));
  fl.l_type = F_UNLCK;
  fl.l_whence = fl.l_start = 0;
  fl.l_len = 0;
  return fcntl(fd, F_SETLK, &fl);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
lldiv_t lldiv(long long numer, long long denom) {
  lldiv_t ret;
  ret.quot = numer / denom;
  ret.rem = numer % denom;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
lldiv_t lldiv(long long numer, long long denom) {
  lldiv_t ret;
  ret.quot = numer / denom;
  ret.rem = numer % denom;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
lldiv_t lldiv(long long numer, long long denom) {
  lldiv_t ret;
  ret.quot = numer / denom;
  ret.rem = numer % denom;
  return ret;
}
```