ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D52(%rip),%rsi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D68(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <puts@plt>
  lea    D54(%rip),%rbp
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D34(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D52
type: string
name: read_data
arguments: label: D2
type: string
name: read_data
arguments: label: D68
type: string
name: read_data
arguments: label: D19
type: string
name: read_data
arguments: label: D18
type: string
name: read_data
arguments: label: D67
type: string
name: read_data
arguments: label: D54
type: string
name: read_data
arguments: label: D34
type: string

tool: D52:   JJ     

tool: D2: %s 


tool: D68:  J       

tool: D19: J        

tool: D18:   JJJJJJJ

tool: 

tool: D54:         T

tool: D34: TTTTTTTTT

assistant: ```c
int main() {
  printf("%s \n", "  JJ     ");
  printf("%s \n", " J       ");
  printf("%s \n", "J        ");
  printf("%s \n", " J       ");
  printf("%s \n", "  JJJJJJJ");
  puts("");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "TTTTTTTTT");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D75(%rip),%rsi
  lea    D22(%rip),%r12
  push   %rbp
  lea    D72(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D27(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D50(%rip),%r12
  call   <printf@plt>
  lea    D49(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D2(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D75
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: string
name: disassemble_data
arguments: label: D72
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D50
type_guessed: string
name: disassemble_data
arguments: label: D49
type_guessed: string
name: disassemble_data
arguments: label: D61
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D75:   JJ     

tool: D22:  J       

tool: D72: %s 


tool: D27: J        

tool: D50:         T

tool: D49:   JJJJJJJ

tool: 

tool: D2: TTTTTTTTT

assistant: ```c
int main() {
  printf("%s \n", "  JJ     ");
  printf("%s \n", " J       ");
  printf("%s \n", "J        ");
  printf("%s \n", " J       ");
  printf("%s \n", "  JJJJJJJ");
  puts("");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "TTTTTTTTT");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rsi
  lea    D11(%rip),%r12
  push   %rbp
  lea    D66(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D34(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    D25(%rip),%r12
  call   <printf@plt>
  lea    D56(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D64(%rip),%rsi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D66
data_type: string
name: read_data
arguments: data_tag: D34
data_type: string
name: read_data
arguments: data_tag: D25
data_type: string
name: read_data
arguments: data_tag: D56
data_type: string
name: read_data
arguments: data_tag: D68
data_type: string
name: read_data
arguments: data_tag: D64
data_type: string

tool: D6:   JJ     

tool: D11:  J       

tool: D66: %s 


tool: D34: J        

tool: D25:         T

tool: D56:   JJJJJJJ

tool: 

tool: D64: TTTTTTTTT

assistant: ```c
int main() {
  printf("%s \n", "  JJ     ");
  printf("%s \n", " J       ");
  printf("%s \n", "J        ");
  printf("%s \n", " J       ");
  printf("%s \n", "  JJJJJJJ");
  puts("");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "TTTTTTTTT");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  printf("%s \n", "        T");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<unaligned_read_le32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,%rdi
  call   <unaligned_read_le16@plt>
  shl    $0x10,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unaligned_read_le16@plt>
  or     %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
uint32_t unaligned_read_le32(const void *_u) {
  const uint8_t *u = _u;
  return (((uint32_t)unaligned_read_le16(u + 2)) << 16) | ((uint32_t)unaligned_read_le16(u));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<unaligned_read_le32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    0x8(%rdi),%rdi
  call   <unaligned_read_le16@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <unaligned_read_le16@plt>
  shl    $0x10,%ebx
  or     %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t unaligned_read_le32(const void *_u) {
  const uint8_t *u = _u;
  return (((uint32_t)unaligned_read_le16(u + 2)) << 16) | ((uint32_t)unaligned_read_le16(u));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<unaligned_read_le32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x8(%rdi),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <unaligned_read_le16@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <unaligned_read_le16@plt>
  shl    $0x10,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t unaligned_read_le32(const void *_u) {
  const uint8_t *u = _u;
  return (((uint32_t)unaligned_read_le16(u + 2)) << 16) | ((uint32_t)unaligned_read_le16(u));
}
```
user: Translate the below assembly code into C programming language:

```asm
<unaligned_read_le32>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x8(%rdi),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <unaligned_read_le16@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <unaligned_read_le16@plt>
  shl    $0x10,%ebx
  add    $0x8,%rsp
  or     %ebx,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t unaligned_read_le32(const void *_u) {
  const uint8_t *u = _u;
  return (((uint32_t)unaligned_read_le16(u + 2)) << 16) | ((uint32_t)unaligned_read_le16(u));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  movl   $0x0,-0x78(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x74(%rbp)
  jmp    L22
L15:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %al,-0x79(%rbp)
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x79(%rbp),%edx
  mov    %dl,-0x70(%rbp,%rax,1)
  addl   $0x1,-0x78(%rbp)
  subl   $0x1,-0x74(%rbp)
L22:
  mov    -0x78(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L15
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
data_type: string
name: extract_symbolic_data
arguments: label: D12
data_type: string

tool: D6: 
Enter string: 

tool: D12: 
Reversed string: 

assistant: ```c
int main() {
  char str[100], temp;
  printf("\nEnter string: ");
  gets(str);
  int i = 0, j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReversed string: ");
  puts(str);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L28
  mov    %rsp,%rsi
  movslq %eax,%rdx
  add    %rbx,%rdx
L25:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  mov    %r8b,(%rsi)
  mov    %dil,-0x1(%rdx)
  mov    %ecx,%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %eax,%edi
  sub    %r8d,%edi
  cmp    %edi,%ecx
  jg     L25
L28:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D7
data_type: string

tool: D8: 
Enter string: 

tool: D7: 
Reversed string: 

assistant: ```c
int main() {
  char str[100], temp;
  printf("\nEnter string: ");
  gets(str);
  int i = 0, j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReversed string: ");
  puts(str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L22
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L17:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L17
L22:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D17
datatype: string

tool: D3: 
Enter string: 

tool: D17: 
Reversed string: 

assistant: ```c
int main() {
  char str[100], temp;
  printf("\nEnter string: ");
  gets(str);
  int i = 0, j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReversed string: ");
  puts(str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L23
  movslq %eax,%rdx
  mov    %rbp,%rsi
  add    %rbp,%rdx
  nopl   0x0(%rax,%rax,1)
L25:
  movzbl (%rsi),%edi
  movzbl -0x1(%rdx),%r8d
  sub    $0x1,%ecx
  add    $0x1,%rsi
  sub    $0x1,%rdx
  mov    %r8b,-0x1(%rsi)
  mov    %dil,(%rdx)
  mov    %eax,%edi
  sub    %ecx,%edi
  sub    $0x1,%edi
  cmp    %edi,%ecx
  jg     L25
L23:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
datatype: string
name: unpack_data
arguments: tag: D11
datatype: string

tool: D0: 
Enter string: 

tool: D11: 
Reversed string: 

assistant: ```c
int main() {
  char str[100], temp;
  printf("\nEnter string: ");
  gets(str);
  int i = 0, j = strlen(str) - 1;
  while (i < j) {
    temp = str[i];
    str[i] = str[j];
    str[j] = temp;
    i++;
    j--;
  }
  printf("\nReversed string: ");
  puts(str);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<exitif>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: Carre : %s


assistant: ```c
void exitif(int test, char *message) {
  if (test) {
    printf("Carre : %s\n", message);
    exit(1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<exitif>:
  endbr64
  test   %edi,%edi
  jne    L6
  ret
L6:
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_guessed: string

tool: D8: Carre : %s


assistant: ```c
void exitif(int test, char *message) {
  if (test) {
    printf("Carre : %s\n", message);
    exit(1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<exitif>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
data_type: string

tool: D7: Carre : %s


assistant: ```c
void exitif(int test, char *message) {
  if (test) {
    printf("Carre : %s\n", message);
    exit(1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<exitif>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: Carre : %s


assistant: ```c
void exitif(int test, char *message) {
  if (test) {
    printf("Carre : %s\n", message);
    exit(1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
  orq    $0x100,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <smunch@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: SMUNCH RETURNED %d 


assistant: ```c
int main(int argc, char **argv) {
  int ret;
  unsigned long bitpattern = 0;
  int pid = atoi(argv[1]);
  bitpattern |= 256;
  ret = smunch(pid, bitpattern);
  printf("SMUNCH RETURNED %d \n", ret);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%edi
  mov    $0x100,%esi
  call   <smunch@plt>
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
datatype: string

tool: D3: SMUNCH RETURNED %d 


assistant: ```c
int main(int argc, char **argv) {
  int ret;
  unsigned long bitpattern = 0;
  int pid = atoi(argv[1]);
  bitpattern |= 256;
  ret = smunch(pid, bitpattern);
  printf("SMUNCH RETURNED %d \n", ret);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    $0x100,%esi
  mov    %eax,%edi
  call   <smunch@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: SMUNCH RETURNED %d 


assistant: ```c
int main(int argc, char **argv) {
  int ret;
  unsigned long bitpattern = 0;
  int pid = atoi(argv[1]);
  bitpattern |= 256;
  ret = smunch(pid, bitpattern);
  printf("SMUNCH RETURNED %d \n", ret);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    $0x100,%esi
  mov    %eax,%edi
  call   <smunch@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: SMUNCH RETURNED %d 


assistant: ```c
int main(int argc, char **argv) {
  int ret;
  unsigned long bitpattern = 0;
  int pid = atoi(argv[1]);
  bitpattern |= 256;
  ret = smunch(pid, bitpattern);
  printf("SMUNCH RETURNED %d \n", ret);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ROL_absx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x0,%eax
  call   <ROL_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ROL_absx(void) {
  c64_memAbsoluteAddrX();
  ROL_();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ROL_absx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <c64_memAbsoluteAddrX@plt>
  mov    $0x0,%eax
  call   <ROL_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ROL_absx(void) {
  c64_memAbsoluteAddrX();
  ROL_();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ROL_absx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memAbsoluteAddrX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <ROL_@plt>
```

assistant: ```c
void ROL_absx(void) {
  c64_memAbsoluteAddrX();
  ROL_();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_2D_array_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L21
L13:
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L18
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D7
datatype: string

tool: D1: %s:


tool: D7: %d 

assistant: ```c
void print_2D_array_int(char *label, int **array, int rows, int cols) {
  int i, j;
  printf("%s:\n", label);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      printf("%d ", array[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_2D_array_int>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %ecx,%r14d
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L4
  mov    %r12,%rbp
  lea    -0x1(%rbx),%eax
  lea    0x8(%r12,%rax,8),%r15
  lea    -0x1(%r14),%eax
  lea    0x4(,%rax,4),%r13
  lea    D3(%rip),%r12
  jmp    L57
L9:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L9
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L4
L57:
  mov    $0x0,%ebx
  test   %r14d,%r14d
  jg     L9
  jmp    L21
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D2: %s:


tool: D3: %d 

assistant: ```c
void print_2D_array_int(char *label, int **array, int rows, int cols) {
  int i, j;
  printf("%s:\n", label);
  for (i = 0; i < rows; i++) {
    for (j = 0; j < cols; j++) {
      printf("%d ", array[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```