ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zc_sb_uuid_format>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <zc_sb_v0_uuid_get@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <zc_uuid_format@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *zc_sb_uuid_format(const struct zc_sb_v0 *const sb, char *const buf) {
  uint8_t uuid[16];
  zc_sb_v0_uuid_get(uuid, sb);
  return zc_uuid_format(uuid, buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zc_sb_uuid_format>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdi,%rsi
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <zc_sb_v0_uuid_get@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <zc_uuid_format@plt>
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
const char *zc_sb_uuid_format(const struct zc_sb_v0 *const sb, char *const buf) {
  uint8_t uuid[16];
  zc_sb_v0_uuid_get(uuid, sb);
  return zc_uuid_format(uuid, buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gs2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff91a2b3c5,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0xb,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  imul   $0xe10,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    $0xe10,%eax
  sub    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int gs2() {
  int res;
  time_t nowEpoch;
  time(&nowEpoch);
  res = nowEpoch % 3600;
  return (3600 - res);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gs2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0xffffffff91a2b3c5,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0xe10,%eax,%eax
  sub    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  lea    0xe10(%rax),%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gs2() {
  int res;
  time_t nowEpoch;
  time(&nowEpoch);
  res = nowEpoch % 3600;
  return (3600 - res);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gs2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0xffffffff91a2b3c5,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  sub    %ecx,%eax
  imul   $0xe10,%eax,%eax
  sub    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0xe10,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gs2() {
  int res;
  time_t nowEpoch;
  time(&nowEpoch);
  res = nowEpoch % 3600;
  return (3600 - res);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gs2>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0xffffffff91a2b3c5,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0xb,%eax
  sub    %ecx,%eax
  imul   $0xe10,%eax,%eax
  sub    %edx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0xe10,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int gs2() {
  int res;
  time_t nowEpoch;
  time(&nowEpoch);
  res = nowEpoch % 3600;
  return (3600 - res);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<insert_sort_duo_rev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x1,-0x10(%rbp)
  jmp    L22
L10:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L3
L4:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  subq   $0x1,-0x18(%rbp)
L3:
  cmpq   $0x0,-0x18(%rbp)
  jle    L25
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jg     L4
L25:
  addq   $0x1,-0x10(%rbp)
L22:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insert_sort_duo_rev(uint32_t *liste, uint32_t size, uint32_t *copain) {
  uint32_t d, c = 1, t;
  for (; c < size; ++c) {
    d = c;
    while (d > 0 && (liste)[d] > (liste)[d - 1]) {
      t = (liste)[d];
      (liste)[d] = (liste)[d - 1];
      (liste)[d - 1] = t;
      t = (copain)[d];
      (copain)[d] = (copain)[d - 1];
      (copain)[d - 1] = t;
      d--;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<insert_sort_duo_rev>:
  endbr64
  mov    $0x1,%r9d
  cmp    $0x1,%rsi
  jg     L8
  ret
L53:
  add    $0x1,%r9
  cmp    %r9,%rsi
  je     L13
L8:
  mov    %r9,%rax
  test   %r9,%r9
  jle    L53
L37:
  mov    (%rdi,%rax,8),%r8
  mov    -0x8(%rdi,%rax,8),%rcx
  cmp    %rcx,%r8
  jle    L53
  mov    %rcx,(%rdi,%rax,8)
  mov    %r8,-0x8(%rdi,%rax,8)
  mov    (%rdx,%rax,8),%rcx
  mov    -0x8(%rdx,%rax,8),%r8
  mov    %r8,(%rdx,%rax,8)
  mov    %rcx,-0x8(%rdx,%rax,8)
  sub    $0x1,%rax
  jne    L37
  jmp    L53
L13:
  ret
```

assistant: ```c
void insert_sort_duo_rev(uint32_t *liste, uint32_t size, uint32_t *copain) {
  uint32_t d, c = 1, t;
  for (; c < size; ++c) {
    d = c;
    while (d > 0 && (liste)[d] > (liste)[d - 1]) {
      t = (liste)[d];
      (liste)[d] = (liste)[d - 1];
      (liste)[d - 1] = t;
      t = (copain)[d];
      (copain)[d] = (copain)[d - 1];
      (copain)[d - 1] = t;
      d--;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_sort_duo_rev>:
  endbr64
  mov    $0x1,%r9d
  cmp    $0x1,%rsi
  jle    L18
L20:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%rdi,%rax,8),%r8
  mov    -0x8(%rdi,%rax,8),%rcx
  cmp    %rcx,%r8
  jle    L9
  mov    %rcx,(%rdi,%rax,8)
  mov    %r8,-0x8(%rdi,%rax,8)
  mov    (%rdx,%rax,8),%rcx
  mov    -0x8(%rdx,%rax,8),%r8
  mov    %rcx,-0x8(%rdx,%rax,8)
  mov    %r8,(%rdx,%rax,8)
  sub    $0x1,%rax
  jne    L14
L9:
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L20
  ret
L18:
  ret
```

assistant: ```c
void insert_sort_duo_rev(uint32_t *liste, uint32_t size, uint32_t *copain) {
  uint32_t d, c = 1, t;
  for (; c < size; ++c) {
    d = c;
    while (d > 0 && (liste)[d] > (liste)[d - 1]) {
      t = (liste)[d];
      (liste)[d] = (liste)[d - 1];
      (liste)[d - 1] = t;
      t = (copain)[d];
      (copain)[d] = (copain)[d - 1];
      (copain)[d - 1] = t;
      d--;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<insert_sort_duo_rev>:
  endbr64
  mov    $0x1,%r9d
  cmp    $0x1,%rsi
  jle    L5
L28:
  mov    %r9,%rcx
  nopl   0x0(%rax,%rax,1)
L35:
  movdqu -0x8(%rdi,%rcx,8),%xmm0
  movhlps %xmm0,%xmm2
  movdqa %xmm0,%xmm1
  movq   %xmm0,%r8
  movq   %xmm2,%rax
  shufpd $0x1,%xmm0,%xmm1
  cmp    %rax,%r8
  jge    L17
  movups %xmm1,-0x8(%rdi,%rcx,8)
  movdqu -0x8(%rdx,%rcx,8),%xmm0
  shufpd $0x1,%xmm0,%xmm0
  movups %xmm0,-0x8(%rdx,%rcx,8)
  sub    $0x1,%rcx
  jne    L35
L17:
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L28
  ret
L5:
  ret
```

assistant: ```c
void insert_sort_duo_rev(uint32_t *liste, uint32_t size, uint32_t *copain) {
  uint32_t d, c = 1, t;
  for (; c < size; ++c) {
    d = c;
    while (d > 0 && (liste)[d] > (liste)[d - 1]) {
      t = (liste)[d];
      (liste)[d] = (liste)[d - 1];
      (liste)[d - 1] = t;
      t = (copain)[d];
      (copain)[d] = (copain)[d - 1];
      (copain)[d - 1] = t;
      d--;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ParsePrompt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x5(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L43
  cmpb   $0x5b,-0x5(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L58
L43:
  cmpb   $0x5d,-0x5(%rbp)
  jne    L18
  movl   $0x1,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L58
L18:
  cmpl   $0x7,-0x14(%rbp)
  jg     L3
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  je     L3
  mov    $0x1,%eax
  jmp    L48
L3:
  mov    $0x0,%eax
L48:
  mov    %eax,-0x4(%rbp)
L58:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
bool ParsePrompt(int32_t length, const uint8_t *data, int32_t *parsed) {
  assert(length > 0);
  assert(data != NULL);
  assert(parsed != NULL);
  *parsed = 0;
  bool sync;
  uint8_t ch = data[length - 1];
  if (length == 1) {
    sync = (ch == '[');
  } else if (ch == ']') {
    sync = true;
    *parsed = length;
  } else {
    sync = (length < 8 && isalnum(ch));
  }
  return sync;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ParsePrompt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  test   %edi,%edi
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movl   $0x0,0x0(%rbp)
  movslq %ebx,%rax
  movzbl -0x1(%r12,%rax,1),%edi
  cmp    $0x1,%ebx
  je     L46
  cmp    $0x5d,%dil
  je     L47
  mov    $0x0,%eax
  cmp    $0x7,%ebx
  jg     L12
  movsbl %dil,%edi
  call   <isalnum@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L12
L46:
  cmp    $0x5b,%dil
  sete   %al
  movzbl %al,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L47:
  mov    %ebx,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L12
```

assistant: ```c
bool ParsePrompt(int32_t length, const uint8_t *data, int32_t *parsed) {
  assert(length > 0);
  assert(data != NULL);
  assert(parsed != NULL);
  *parsed = 0;
  bool sync;
  uint8_t ch = data[length - 1];
  if (length == 1) {
    sync = (ch == '[');
  } else if (ch == ']') {
    sync = true;
    *parsed = length;
  } else {
    sync = (length < 8 && isalnum(ch));
  }
  return sync;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ParsePrompt>:
  endbr64
  push   %r12
  test   %edi,%edi
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  movslq %ebx,%rax
  movl   $0x0,0x0(%rbp)
  movsbl -0x1(%r12,%rax,1),%edi
  cmp    $0x1,%ebx
  je     L23
  cmp    $0x5d,%dil
  je     L22
  xor    %eax,%eax
  cmp    $0x7,%ebx
  jle    L24
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %ebx,0x0(%rbp)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L23:
  xor    %eax,%eax
  cmp    $0x5b,%dil
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  call   <isalnum@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool ParsePrompt(int32_t length, const uint8_t *data, int32_t *parsed) {
  assert(length > 0);
  assert(data != NULL);
  assert(parsed != NULL);
  *parsed = 0;
  bool sync;
  uint8_t ch = data[length - 1];
  if (length == 1) {
    sync = (ch == '[');
  } else if (ch == ']') {
    sync = true;
    *parsed = length;
  } else {
    sync = (length < 8 && isalnum(ch));
  }
  return sync;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ParsePrompt>:
  endbr64
  push   %r12
  test   %edi,%edi
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %edi,%ebx
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  movslq %ebx,%rax
  movl   $0x0,0x0(%rbp)
  movsbl -0x1(%r12,%rax,1),%edi
  cmp    $0x1,%ebx
  je     L11
  cmp    $0x5d,%dil
  je     L7
  xor    %eax,%eax
  cmp    $0x7,%ebx
  jle    L29
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,0x0(%rbp)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  cmp    $0x5b,%dil
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  call   <isalnum@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool ParsePrompt(int32_t length, const uint8_t *data, int32_t *parsed) {
  assert(length > 0);
  assert(data != NULL);
  assert(parsed != NULL);
  *parsed = 0;
  bool sync;
  uint8_t ch = data[length - 1];
  if (length == 1) {
    sync = (ch == '[');
  } else if (ch == ']') {
    sync = true;
    *parsed = length;
  } else {
    sync = (length < 8 && isalnum(ch));
  }
  return sync;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D12(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D16
data_type: string

tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c

tool: D16: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c");
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c

tool: D10: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c");
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
type_guessed: string
name: extract_symbolic_data
arguments: tag: D7
type_guessed: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c

tool: D7: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c");
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c

tool: D16: %s


assistant: ```c
int main(void) {
  printf("%s\n", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mj31508/holbertonschool-low_level_programming/refs/heads/master/0x0C-preprocessor/2-main.c");
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ieee_p_1242562249_sub_16343609080398298574_1035706684>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    0xc(%rcx),%ebp
  test   %ebp,%ebp
  je     L1
  mov    %rsp,%rsi
  call   <ieee_p_1242562249_sub_2177871677178661378_1035706684@plt>
  mov    %rax,%rbp
  mov    0xc(%rsp),%r13d
  mov    %r13d,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %rax,%r12
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%edx
  mov    0x8(%rsp),%eax
  mov    %edx,%ebp
  sub    %ecx,%ebp
  imul   %eax,%ebp
  add    $0x1,%ebp
L12:
  mov    %ecx,(%rbx)
  mov    %edx,0x4(%rbx)
  mov    %eax,0x8(%rbx)
  mov    %ebp,0xc(%rbx)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  mov    0x508(%rdi),%r13
  mov    $0x0,%edi
  call   <xsi_get_transient_memory@plt>
  mov    %rax,%r12
  mov    $0x0,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0xffffffff,%eax
  jmp    L12
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ieee_p_1242562249_sub_16343609080398298574_1035706684(char *t1, char *t2, char *t3, char *t4, int t5) {
  char t7[24];
  char t20[16];
  char *t0;
  char *t8;
  unsigned char t9;
  char *t10;
  char *t11;
  char *t12;
  unsigned int t13;
  unsigned char t14;
  char *t15;
  char *t16;
  char *t17;
  int t18;
  unsigned int t19;
  int t21;
  char *t22;
  int t23;
  char *t24;
  char *t25;
  int t26;
LAB0:
  t8 = (t7 + 4U);
  t9 = (t3 != 0);
  if (t9 == 1)
    goto LAB3;
LAB2:
  t10 = (t7 + 12U);
  *((char **)t10) = t4;
  t11 = (t7 + 20U);
  *((int *)t11) = t5;
  t12 = (t4 + 12U);
  t13 = *((unsigned int *)t12);
  t14 = (t13 < 1);
  if (t14 != 0)
    goto LAB4;
LAB6:
LAB5:
  t12 = ieee_p_1242562249_sub_2177871677178661378_1035706684(t1, t20, t3, t4, t5);
  t15 = (t20 + 12U);
  t13 = *((unsigned int *)t15);
  t13 = (t13 * 1U);
  t0 = xsi_get_transient_memory(t13);
  memcpy(t0, t12, t13);
  t16 = (t20 + 0U);
  t18 = *((int *)t16);
  t17 = (t20 + 4U);
  t21 = *((int *)t17);
  t22 = (t20 + 8U);
  t23 = *((int *)t22);
  t24 = (t2 + 0U);
  t25 = (t24 + 0U);
  *((int *)t25) = t18;
  t25 = (t24 + 4U);
  *((int *)t25) = t21;
  t25 = (t24 + 8U);
  *((int *)t25) = t23;
  t26 = (t21 - t18);
  t19 = (t26 * t23);
  t19 = (t19 + 1);
  t25 = (t24 + 12U);
  *((unsigned int *)t25) = t19;
LAB1:
  return t0;
LAB3:
  *((char **)t8) = t3;
  goto LAB2;
LAB4:
  t15 = (t1 + 1288U);
  t16 = *((char **)t15);
  t0 = xsi_get_transient_memory(0U);
  memcpy(t0, t16, 0U);
  t15 = (t2 + 0U);
  t17 = (t15 + 0U);
  *((int *)t17) = 0;
  t17 = (t15 + 4U);
  *((int *)t17) = 1;
  t17 = (t15 + 8U);
  *((int *)t17) = -1;
  t18 = (1 - 0);
  t19 = (t18 * -1);
  t19 = (t19 + 1);
  t17 = (t15 + 12U);
  *((unsigned int *)t17) = t19;
  goto LAB1;
LAB7:
  goto LAB5;
LAB8:;
}
```