ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<HMM_Power>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movss  %xmm0,0xc(%rsp)
  mov    %edi,%ebp
  mov    $0x21a,%esi
  lea    D32(%rip),%rdi
  call   <_hmt_count_cover@plt>
  test   %ebp,%ebp
  js     L65
  mov    %ebp,%ebx
  neg    %ebx
  cmovs  %ebp,%ebx
  test   %ebp,%ebp
  je     L39
L48:
  mov    D41(%rip),%ebp
  lea    D32(%rip),%r12
  jmp    L6
L65:
  movss  D41(%rip),%xmm0
  movaps %xmm0,%xmm6
  divss  0xc(%rsp),%xmm6
  movss  %xmm6,0xc(%rsp)
  mov    %ebp,%ebx
  neg    %ebx
  cmovs  %ebp,%ebx
  jmp    L48
L32:
  movss  0xc(%rsp),%xmm2
  movaps %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  movss  %xmm1,0xc(%rsp)
  sar    %ebx
  je     L13
L6:
  test   $0x1,%bl
  je     L32
  mov    $0x223,%esi
  mov    %r12,%rdi
  call   <_hmt_count_cover@plt>
  movd   %ebp,%xmm3
  mulss  0xc(%rsp),%xmm3
  movd   %xmm3,%ebp
  jmp    L32
L39:
  mov    D41(%rip),%ebp
L13:
  movd   %ebp,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D32
data_type: string
name: parse_data
arguments: label: D41
data_type: byte[4]

tool: D32: HMM_Power

tool: {"D41": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float HMM_Power(float Base, int Exponent) {
  { _hmt_count_cover("HMM_Power", 538); };
  float Result = 1.0f;
  float Mul = Exponent < 0 ? 1.f / Base : Base;
  int X = Exponent < 0 ? -Exponent : Exponent;
  while (X) {
    if (X & 1) {
      { _hmt_count_cover("HMM_Power", 547); };
      Result *= Mul;
    }
    Mul *= Mul;
    X >>= 1;
  }
  return (Result);
}
```
user: What is the c source code of the assembly code below?

```asm
<HMM_Power>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  mov    $0x21a,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12,%rdi
  push   %rbx
  mov    %ebp,%ebx
  sub    $0x10,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <_hmt_count_cover@plt>
  neg    %ebx
  movss  D0(%rip),%xmm0
  movss  0x8(%rsp),%xmm1
  cmovs  %ebp,%ebx
  test   %ebp,%ebp
  js     L5
  jne    L44
L32:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  mov    $0x223,%esi
  mov    %r12,%rdi
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <_hmt_count_cover@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  mulss  %xmm1,%xmm0
L19:
  mulss  %xmm1,%xmm1
  sar    %ebx
  je     L32
L44:
  test   $0x1,%bl
  je     L19
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L5:
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  jmp    L44
```

tool_calls: name: read_data
arguments: data_label: D14
type: string
name: read_data
arguments: data_label: D0
type: byte[4]

tool: D14: HMM_Power

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float HMM_Power(float Base, int Exponent) {
  { _hmt_count_cover("HMM_Power", 538); };
  float Result = 1.0f;
  float Mul = Exponent < 0 ? 1.f / Base : Base;
  int X = Exponent < 0 ? -Exponent : Exponent;
  while (X) {
    if (X & 1) {
      { _hmt_count_cover("HMM_Power", 547); };
      Result *= Mul;
    }
    Mul *= Mul;
    X >>= 1;
  }
  return (Result);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<HMM_Power>:
  endbr64
  push   %r12
  lea    D15(%rip),%r12
  mov    $0x21a,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    %r12,%rdi
  push   %rbx
  mov    %ebp,%ebx
  sub    $0x10,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <_hmt_count_cover@plt>
  neg    %ebx
  movss  D10(%rip),%xmm0
  movss  0x8(%rsp),%xmm1
  cmovs  %ebp,%ebx
  test   %ebp,%ebp
  js     L12
  jne    L25
L16:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L42:
  mov    $0x223,%esi
  mov    %r12,%rdi
  movss  %xmm1,0xc(%rsp)
  movss  %xmm0,0x8(%rsp)
  call   <_hmt_count_cover@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  mulss  %xmm1,%xmm0
L46:
  mulss  %xmm1,%xmm1
  sar    %ebx
  je     L16
L25:
  test   $0x1,%bl
  je     L46
  jmp    L42
  nopl   0x0(%rax,%rax,1)
L12:
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movaps %xmm2,%xmm1
  jmp    L25
```

tool_calls: name: parse_data
arguments: label: D15
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: byte[4]

tool: D15: HMM_Power

tool: {"D10": [0x00,0x00,0x80,0x3f]}

assistant: ```c
float HMM_Power(float Base, int Exponent) {
  { _hmt_count_cover("HMM_Power", 538); };
  float Result = 1.0f;
  float Mul = Exponent < 0 ? 1.f / Base : Base;
  int X = Exponent < 0 ? -Exponent : Exponent;
  while (X) {
    if (X & 1) {
      { _hmt_count_cover("HMM_Power", 547); };
      Result *= Mul;
    }
    Mul *= Mul;
    X >>= 1;
  }
  return (Result);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_stat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int _stat(const char *path, struct stat *buf) {
  _exit(-1);
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_stat>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _stat(const char *path, struct stat *buf) {
  _exit(-1);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_stat>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _stat(const char *path, struct stat *buf) {
  _exit(-1);
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_stat>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <_exit@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int _stat(const char *path, struct stat *buf) {
  _exit(-1);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L36:
  cmpq   $0x0,-0x30(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x28(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%esi
  mov    -0x28(%rbp),%eax
  mov    %eax,%ecx
  rol    %cl,%esi
  mov    %esi,%eax
  cmp    %eax,%edx
  je     L25
  call   <abort@plt>
L25:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L36
  nop
  nop
  leave
  ret
```

assistant: ```c
void check(unsigned int *p, unsigned int *q, int count, unsigned int *s, int ss) {
  int i;
  for (i = 0; i < count; i++) {
    if (s)
      ss = s[i];
    if (p[i] != ((q[i] << ss) | (q[i] >> (32 - ss))))
      __builtin_abort();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L21
  mov    %rdi,%r10
  mov    %rcx,%r9
  mov    %r8d,%ecx
  mov    %edx,%edx
  mov    $0x0,%eax
  jmp    L54
L36:
  mov    (%r9,%rax,4),%ecx
L14:
  mov    (%rsi,%rax,4),%edi
  rol    %cl,%edi
  cmp    %edi,(%r10,%rax,4)
  jne    L5
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L21
L54:
  test   %r9,%r9
  jne    L36
  jmp    L14
L5:
  sub    $0x8,%rsp
  call   <abort@plt>
L21:
  ret
```

assistant: ```c
void check(unsigned int *p, unsigned int *q, int count, unsigned int *s, int ss) {
  int i;
  for (i = 0; i < count; i++) {
    if (s)
      ss = s[i];
    if (p[i] != ((q[i] << ss) | (q[i] >> (32 - ss))))
      __builtin_abort();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %rcx,%r9
  mov    %rdi,%r10
  mov    %r8d,%ecx
  movslq %edx,%rdx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  test   %r9,%r9
  je     L23
  mov    (%r9,%rax,4),%ecx
L23:
  mov    (%rsi,%rax,4),%edi
  rol    %cl,%edi
  cmp    %edi,(%r10,%rax,4)
  jne    1060 <check.cold>
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L8
L17:
  ret
```

assistant: ```c
void check(unsigned int *p, unsigned int *q, int count, unsigned int *s, int ss) {
  int i;
  for (i = 0; i < count; i++) {
    if (s)
      ss = s[i];
    if (p[i] != ((q[i] << ss) | (q[i] >> (32 - ss))))
      __builtin_abort();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L6
  mov    %rcx,%r9
  movslq %edx,%rdx
  mov    %r8d,%ecx
  xor    %eax,%eax
  test   %r9,%r9
  je     L37
  nopl   0x0(%rax,%rax,1)
L26:
  mov    (%r9,%rax,4),%ecx
  mov    (%rsi,%rax,4),%r10d
  rol    %cl,%r10d
  cmp    %r10d,(%rdi,%rax,4)
  jne    1060 <check.cold>
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
L6:
  ret
  nop
L37:
  mov    (%rsi,%rax,4),%r9d
  rol    %cl,%r9d
  cmp    (%rdi,%rax,4),%r9d
  jne    1060 <check.cold>
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L37
  ret
```

assistant: ```c
void check(unsigned int *p, unsigned int *q, int count, unsigned int *s, int ss) {
  int i;
  for (i = 0; i < count; i++) {
    if (s)
      ss = s[i];
    if (p[i] != ((q[i] << ss) | (q[i] >> (32 - ss))))
      __builtin_abort();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thumb_rel_count_regs_in_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L3:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x14(%rbp)
  jne    L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int thumb_rel_count_regs_in_map(int map) {
  int c;
  for (c = 0; map != 0; ++c)
    map &= map - 1;
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thumb_rel_count_regs_in_map>:
  endbr64
  test   %edi,%edi
  je     L5
  mov    $0x0,%edx
L6:
  lea    -0x1(%rdi),%eax
  add    $0x1,%edx
  and    %eax,%edi
  jne    L6
L7:
  mov    %edx,%eax
  ret
L5:
  mov    %edi,%edx
  jmp    L7
```

assistant: ```c
int thumb_rel_count_regs_in_map(int map) {
  int c;
  for (c = 0; map != 0; ++c)
    map &= map - 1;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thumb_rel_count_regs_in_map>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L17
  nopl   0x0(%rax,%rax,1)
L14:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L14
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int thumb_rel_count_regs_in_map(int map) {
  int c;
  for (c = 0; map != 0; ++c)
    map &= map - 1;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<thumb_rel_count_regs_in_map>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L17
  nopl   0x0(%rax,%rax,1)
L15:
  lea    -0x1(%rdi),%eax
  add    $0x1,%r8d
  and    %eax,%edi
  jne    L15
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int thumb_rel_count_regs_in_map(int map) {
  int c;
  for (c = 0; map != 0; ++c)
    map &= map - 1;
  return c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMaximumIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L6
L10:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L24
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L24:
  addl   $0x1,-0x10(%rbp)
L6:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getMaximumIndex(double *x, int xlen) {
  int i = 0;
  int maxid = 0;
  double maxvalue = 0;
  for (i = 0; i < xlen; i++) {
    if (maxvalue < x[i]) {
      maxvalue = x[i];
      maxid = i;
    }
  }
  return maxid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getMaximumIndex>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    %esi,%esi
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  mov    $0x0,%edx
L18:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L18
L5:
  mov    %edx,%eax
  ret
L2:
  mov    $0x0,%edx
  jmp    L5
```

assistant: ```c
int getMaximumIndex(double *x, int xlen) {
  int i = 0;
  int maxid = 0;
  double maxvalue = 0;
  for (i = 0; i < xlen; i++) {
    if (maxvalue < x[i]) {
      maxvalue = x[i];
      maxid = i;
    }
  }
  return maxid;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getMaximumIndex>:
  endbr64
  test   %esi,%esi
  jle    L10
  movslq %esi,%rsi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L9:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L9
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getMaximumIndex(double *x, int xlen) {
  int i = 0;
  int maxid = 0;
  double maxvalue = 0;
  for (i = 0; i < xlen; i++) {
    if (maxvalue < x[i]) {
      maxvalue = x[i];
      maxid = i;
    }
  }
  return maxid;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getMaximumIndex>:
  endbr64
  test   %esi,%esi
  jle    L4
  movslq %esi,%rsi
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L15:
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L15
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getMaximumIndex(double *x, int xlen) {
  int i = 0;
  int maxid = 0;
  double maxvalue = 0;
  for (i = 0; i < xlen; i++) {
    if (maxvalue < x[i]) {
      maxvalue = x[i];
      maxid = i;
    }
  }
  return maxid;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Min2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L16
  mov    -0x8(%rbp),%eax
  jmp    L0
L16:
  mov    -0x4(%rbp),%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int Min2(int a, int b) {
  if (b < a)
    return b;
  else
    return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Min2>:
  endbr64
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovle %esi,%eax
  ret
```

assistant: ```c
int Min2(int a, int b) {
  if (b < a)
    return b;
  else
    return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Min2>:
  endbr64
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovle %esi,%eax
  ret
```

assistant: ```c
int Min2(int a, int b) {
  if (b < a)
    return b;
  else
    return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Min2>:
  endbr64
  cmp    %edi,%esi
  mov    %edi,%eax
  cmovle %esi,%eax
  ret
```

assistant: ```c
int Min2(int a, int b) {
  if (b < a)
    return b;
  else
    return a;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<lendian2byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lendian2byte(unsigned int a, unsigned char *b) {
  b[0] = a;
  b[1] = a >> 8;
  b[2] = a >> 16;
  b[3] = a >> 24;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lendian2byte>:
  endbr64
  mov    %edi,%eax
  mov    %dil,(%rsi)
  movzbl %ah,%ecx
  mov    %cl,0x1(%rsi)
  mov    %edi,%edx
  shr    $0x10,%edx
  mov    %dl,0x2(%rsi)
  shr    $0x18,%eax
  mov    %al,0x3(%rsi)
  ret
```

assistant: ```c
void lendian2byte(unsigned int a, unsigned char *b) {
  b[0] = a;
  b[1] = a >> 8;
  b[2] = a >> 16;
  b[3] = a >> 24;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lendian2byte>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void lendian2byte(unsigned int a, unsigned char *b) {
  b[0] = a;
  b[1] = a >> 8;
  b[2] = a >> 16;
  b[3] = a >> 24;
}
```
user: What is the c source code of the assembly code below?

```asm
<lendian2byte>:
  endbr64
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void lendian2byte(unsigned int a, unsigned char *b) {
  b[0] = a;
  b[1] = a >> 8;
  b[2] = a >> 16;
  b[3] = a >> 24;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lex_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x22,-0x20(%rbp)
  movl   $0x1,-0x2c(%rbp)
  addq   $0x1,-0x38(%rbp)
  jmp    L38
L25:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x2c(%rbp)
  addq   $0x1,-0x38(%rbp)
L38:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L29
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L29
  cmpl   $0x13,-0x2c(%rbp)
  jle    L25
L29:
  mov    -0x2c(%rbp),%eax
  cltq
  movb   $0x22,-0x20(%rbp,%rax,1)
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
  addq   $0x1,-0x38(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x14,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <lex@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string

tool: D4: String

assistant: ```c
void lex_string(char *str) {
  char token[20];
  char *toktype;
  token[0] = '"';
  int i = 1;
  str++;
  while ((*str != '\"') && *str != '\0' && i < 20) {
    token[i] = *str;
    i++;
    str++;
  }
  token[i] = '"';
  token[i + 1] = '\0';
  str++;
  toktype = "String";
  parse(token, toktype);
  memset(&token[0], 0, sizeof(token));
  lex(str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lex_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x22,(%rsp)
  lea    0x1(%rdi),%rbx
  movzbl 0x1(%rdi),%edx
  cmp    $0x22,%dl
  je     L48
  test   %dl,%dl
  je     L48
  mov    $0x2,%eax
  lea    -0x1(%rsp),%r8
L41:
  mov    %dl,(%r8,%rax,1)
  mov    %eax,%edi
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  cmp    $0x22,%dl
  setne  %cl
  test   %dl,%dl
  setne  %sil
  and    %esi,%ecx
  cmp    $0x13,%eax
  setle  %sil
  add    $0x1,%rax
  test   %sil,%cl
  jne    L41
L20:
  movslq %edi,%rax
  movb   $0x22,(%rsp,%rax,1)
  add    $0x1,%edi
  movslq %edi,%rdi
  movb   $0x0,(%rsp,%rdi,1)
  mov    %rsp,%rbp
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  call   <parse@plt>
  mov    $0x14,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    0x1(%rbx),%rdi
  call   <lex@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  mov    $0x1,%edi
  jmp    L20
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
type: string

tool: D0: String

assistant: ```c
void lex_string(char *str) {
  char token[20];
  char *toktype;
  token[0] = '"';
  int i = 1;
  str++;
  while ((*str != '\"') && *str != '\0' && i < 20) {
    token[i] = *str;
    i++;
    str++;
  }
  token[i] = '"';
  token[i + 1] = '\0';
  str++;
  toktype = "String";
  parse(token, toktype);
  memset(&token[0], 0, sizeof(token));
  lex(str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lex_string>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x28,%rsp
  movzbl 0x1(%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x22,(%rsp)
  cmp    $0x22,%dl
  je     L46
  test   %dl,%dl
  je     L46
  mov    $0x2,%eax
  lea    -0x1(%rsp),%rsi
  nopl   0x0(%rax)
L53:
  mov    %dl,(%rsi,%rax,1)
  movzbl (%rdi,%rax,1),%edx
  movslq %eax,%rcx
  lea    (%rdi,%rax,1),%rbx
  cmp    $0x22,%dl
  je     L71
  test   %dl,%dl
  je     L71
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L53
  mov    $0x14,%ecx
L50:
  mov    %rsp,%rbp
  cltq
  lea    D3(%rip),%rsi
  movb   $0x22,(%rsp,%rcx,1)
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rax,1)
  call   <parse@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    $0x14,%edx
  call   <memset@plt>
  lea    0x1(%rbx),%rdi
  call   <lex@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L71:
  lea    0x1(%rcx),%eax
  jmp    L50
L46:
  mov    $0x2,%eax
  mov    $0x1,%ecx
  jmp    L50
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: String

assistant: ```c
void lex_string(char *str) {
  char token[20];
  char *toktype;
  token[0] = '"';
  int i = 1;
  str++;
  while ((*str != '\"') && *str != '\0' && i < 20) {
    token[i] = *str;
    i++;
    str++;
  }
  token[i] = '"';
  token[i + 1] = '\0';
  str++;
  toktype = "String";
  parse(token, toktype);
  memset(&token[0], 0, sizeof(token));
  lex(str);
}
```
user: What is the c source code of the assembly code below:

```asm
<lex_string>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x1(%rdi),%rbx
  sub    $0x28,%rsp
  movzbl 0x1(%rdi),%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x22,(%rsp)
  cmp    $0x22,%dl
  je     L62
  test   %dl,%dl
  je     L62
  mov    $0x2,%eax
  lea    -0x1(%rsp),%rsi
  nopl   0x0(%rax)
L5:
  mov    %dl,(%rsi,%rax,1)
  movzbl (%rdi,%rax,1),%edx
  movslq %eax,%rcx
  lea    (%rdi,%rax,1),%rbx
  cmp    $0x22,%dl
  je     L78
  test   %dl,%dl
  je     L78
  add    $0x1,%rax
  cmp    $0x15,%rax
  jne    L5
  mov    $0x14,%ecx
L35:
  mov    %rsp,%rbp
  cltq
  lea    D8(%rip),%rsi
  movb   $0x22,(%rsp,%rcx,1)
  mov    %rbp,%rdi
  movb   $0x0,(%rsp,%rax,1)
  call   <parse@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    $0x14,%edx
  call   <memset@plt>
  lea    0x1(%rbx),%rdi
  call   <lex@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L78:
  lea    0x1(%rcx),%eax
  jmp    L35
L62:
  mov    $0x2,%eax
  mov    $0x1,%ecx
  jmp    L35
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: String

assistant: ```c
void lex_string(char *str) {
  char token[20];
  char *toktype;
  token[0] = '"';
  int i = 1;
  str++;
  while ((*str != '\"') && *str != '\0' && i < 20) {
    token[i] = *str;
    i++;
    str++;
  }
  token[i] = '"';
  token[i + 1] = '\0';
  str++;
  toktype = "String";
  parse(token, toktype);
  memset(&token[0], 0, sizeof(token));
  lex(str);
}
```