ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  lea    D18(%rip),%r13
  lea    0x8(%rsp),%r12
  lea    D1(%rip),%rbp
  lea    0xe(%rsp),%rbx
L8:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    0x8(%rsp),%edi
  call   <fizzbuzz@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  cmpl   $0x0,0x8(%rsp)
  jne    L8
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string

tool: D18: Enter number (0 to exit): 

tool: D1: %d

assistant: ```c
int main() {
  int number = 1;
  char string[10];
  while (number != 0) {
    printf("Enter number (0 to exit): ");
    scanf("%d", &number);
    fizzbuzz(number, string);
    printf("%s\n", string);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  lea    0x8(%rsp),%r12
  lea    0xe(%rsp),%rbx
  xchg   %ax,%ax
L10:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  mov    %rbx,%rsi
  call   <fizzbuzz@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jne    L10
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_infered: string
name: read_data
arguments: tag: D5
type_infered: string

tool: D19: Enter number (0 to exit): 

tool: D5: %d

assistant: ```c
int main() {
  int number = 1;
  char string[10];
  while (number != 0) {
    printf("Enter number (0 to exit): ");
    scanf("%d", &number);
    fizzbuzz(number, string);
    printf("%s\n", string);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x8(%rsp)
  lea    0x8(%rsp),%r12
  lea    0xe(%rsp),%rbx
  xchg   %ax,%ax
L11:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%edi
  mov    %rbx,%rsi
  call   <fizzbuzz@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jne    L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D12
type: string

tool: D2: Enter number (0 to exit): 

tool: D12: %d

assistant: ```c
int main() {
  int number = 1;
  char string[10];
  while (number != 0) {
    printf("Enter number (0 to exit): ");
    scanf("%d", &number);
    fizzbuzz(number, string);
    printf("%s\n", string);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<max_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L14
L7:
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L6
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L6:
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L7
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double max_n(double *x, int n) {
  double out = *x;
  for (int i = 1; i < n; i++)
    if (*(++x) > out)
      out = *x;
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<max_n>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L3
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,8),%rax
L16:
  add    $0x8,%rdi
  movsd  (%rdi),%xmm1
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L16
L3:
  ret
```

assistant: ```c
double max_n(double *x, int n) {
  double out = *x;
  for (int i = 1; i < n; i++)
    if (*(++x) > out)
      out = *x;
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<max_n>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L2:
  movsd  0x8(%rdi),%xmm1
  add    $0x8,%rdi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L2
L13:
  ret
```

assistant: ```c
double max_n(double *x, int n) {
  double out = *x;
  for (int i = 1; i < n; i++)
    if (*(++x) > out)
      out = *x;
  return out;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<max_n>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L14:
  movsd  0x8(%rdi),%xmm1
  add    $0x8,%rdi
  maxsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdi,%rax
  jne    L14
L5:
  ret
```

assistant: ```c
double max_n(double *x, int n) {
  double out = *x;
  for (int i = 1; i < n; i++)
    if (*(++x) > out)
      out = *x;
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<angle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <atan2@plt>
  movsd  D21(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  D22(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L80
  cmpl   $0x5a,-0x8(%rbp)
  jg     L80
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5a,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L69
L80:
  cmpl   $0x5a,-0x8(%rbp)
  jle    L61
  cmpl   $0xb4,-0x8(%rbp)
  jg     L61
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1c2,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L69
L61:
  cmpl   $0x0,-0x8(%rbp)
  jns    L71
  cmpl   $0xffffffa6,-0x8(%rbp)
  jl     L71
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fabs@plt>
  add    $0x5a,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L69
L71:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <fabs@plt>
  add    $0x5a,%eax
  mov    %eax,-0x8(%rbp)
L69:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D21
type_infered: f64
name: parse_data
arguments: data_label: D22
type_infered: f64
name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D21: 180

tool: D22: 3.141592654

tool: D2: aaa

tool: D14: bbb

tool: D7: ccc

tool: D3: ddd

assistant: ```c
int angle(int x, int y) {
  float atand = atan2(y, x) * 180.0 / 3.141592654;
  int angle = (int)atand;
  if (angle >= 0 && angle <= 90) {
    printf("aaa");
    angle = 90 - angle;
  } else if (angle > 90 && angle <= 180) {
    printf("bbb");
    angle = 450 - angle;
  } else if (angle < 0 && angle >= -90) {
    printf("ccc");
    angle = fabs(angle) + 90;
  } else {
    printf("ddd");
    angle = fabs(angle) + 90;
  }
  return angle;
}
```
user: Translate the below assembly code into C programming language:

```asm
<angle>:
  endbr64
  push   %rbx
  mov    %edi,%eax
  mov    %esi,%edi
  mov    %eax,%esi
  call   <atan2@plt>
  mulsd  D7(%rip),%xmm0
  divsd  D11(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvttss2si %xmm0,%ebx
  cmp    $0x5a,%ebx
  jbe    L20
  lea    -0x5b(%rbx),%eax
  cmp    $0x59,%eax
  jbe    L3
  cmp    $0xffffffa6,%ebx
  jb     L12
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <fabs@plt>
  add    $0x5a,%eax
  jmp    L0
L20:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x5a,%eax
  sub    %ebx,%eax
L0:
  pop    %rbx
  ret
L3:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x1c2,%eax
  sub    %ebx,%eax
  jmp    L0
L12:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <fabs@plt>
  add    $0x5a,%eax
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: f64
name: disassemble_data
arguments: tag: D11
type_guessed: f64
name: disassemble_data
arguments: tag: D0
type_guessed: string
name: disassemble_data
arguments: tag: D2
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string
name: disassemble_data
arguments: tag: D50
type_guessed: string

tool: D7: 180

tool: D11: 3.141592654

tool: D0: ccc

tool: D2: aaa

tool: D33: bbb

tool: D50: ddd

assistant: ```c
int angle(int x, int y) {
  float atand = atan2(y, x) * 180.0 / 3.141592654;
  int angle = (int)atand;
  if (angle >= 0 && angle <= 90) {
    printf("aaa");
    angle = 90 - angle;
  } else if (angle > 90 && angle <= 180) {
    printf("bbb");
    angle = 450 - angle;
  } else if (angle < 0 && angle >= -90) {
    printf("ccc");
    angle = fabs(angle) + 90;
  } else {
    printf("ddd");
    angle = fabs(angle) + 90;
  }
  return angle;
}
```
user: What is the c source code of the assembly code below?

```asm
<angle>:
  endbr64
  push   %rbp
  mov    %edi,%r8d
  mov    %esi,%edi
  mov    %r8d,%esi
  call   <atan2@plt>
  mulsd  D2(%rip),%xmm0
  divsd  D15(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvttss2si %xmm0,%ebp
  cmp    $0x5a,%ebp
  jbe    L19
  lea    -0x5b(%rbp),%eax
  cmp    $0x59,%eax
  jbe    L6
  cmp    $0xffffffa6,%ebp
  jb     L28
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <fabs@plt>
  pop    %rbp
  add    $0x5a,%eax
  ret
  nopl   0x0(%rax)
L6:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x1c2,%eax
  sub    %ebp,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    $0x5a,%eax
  sub    %ebp,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L28:
  lea    D55(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <fabs@plt>
  pop    %rbp
  add    $0x5a,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: f64
name: retrieve_data
arguments: label: D15
type_guessed: f64
name: retrieve_data
arguments: label: D30
type_guessed: string
name: retrieve_data
arguments: label: D18
type_guessed: string
name: retrieve_data
arguments: label: D27
type_guessed: string
name: retrieve_data
arguments: label: D55
type_guessed: string

tool: D2: 180

tool: D15: 3.141592654

tool: D30: ccc

tool: D18: bbb

tool: D27: aaa

tool: D55: ddd

assistant: ```c
int angle(int x, int y) {
  float atand = atan2(y, x) * 180.0 / 3.141592654;
  int angle = (int)atand;
  if (angle >= 0 && angle <= 90) {
    printf("aaa");
    angle = 90 - angle;
  } else if (angle > 90 && angle <= 180) {
    printf("bbb");
    angle = 450 - angle;
  } else if (angle < 0 && angle >= -90) {
    printf("ccc");
    angle = fabs(angle) + 90;
  } else {
    printf("ddd");
    angle = fabs(angle) + 90;
  }
  return angle;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<angle>:
  endbr64
  push   %rbp
  mov    %edi,%r8d
  mov    %esi,%edi
  mov    %r8d,%esi
  call   <atan2@plt>
  mulsd  D9(%rip),%xmm0
  divsd  D42(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvttss2si %xmm0,%ebp
  cmp    $0x5a,%ebp
  jbe    L10
  lea    -0x5b(%rbp),%eax
  cmp    $0x59,%eax
  jbe    L5
  cmp    $0xffffffa6,%ebp
  jb     L2
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <fabs@plt>
  pop    %rbp
  add    $0x5a,%eax
  ret
  nopl   0x0(%rax)
L5:
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x1c2,%eax
  sub    %ebp,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    $0x5a,%eax
  sub    %ebp,%eax
  pop    %rbp
  ret
  nopl   (%rax)
L2:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <fabs@plt>
  pop    %rbp
  add    $0x5a,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_guessed: f64
name: retrieve_data
arguments: label: D42
type_guessed: f64
name: retrieve_data
arguments: label: D10
type_guessed: string
name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D59
type_guessed: string
name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D9: 180

tool: D42: 3.141592654

tool: D10: ccc

tool: D22: bbb

tool: D59: aaa

tool: D3: ddd

assistant: ```c
int angle(int x, int y) {
  float atand = atan2(y, x) * 180.0 / 3.141592654;
  int angle = (int)atand;
  if (angle >= 0 && angle <= 90) {
    printf("aaa");
    angle = 90 - angle;
  } else if (angle > 90 && angle <= 180) {
    printf("bbb");
    angle = 450 - angle;
  } else if (angle < 0 && angle >= -90) {
    printf("ccc");
    angle = fabs(angle) + 90;
  } else {
    printf("ddd");
    angle = fabs(angle) + 90;
  }
  return angle;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L10
L11:
  mov    -0x18(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void strReverse(char *str, int begin, int len) {
  char *first = str + begin;
  int middle = len / 2 - 1;
  char *end = str + begin + len - 1;
  int i = 0;
  for (; i <= middle; i++) {
    swap(first + i, end - i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strReverse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%r12
  mov    %edx,%ebp
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  movslq %edx,%rax
  lea    -0x1(%r12,%rax,1),%r14
  cmp    $0x1,%edx
  jle    L0
  mov    %rdi,%r13
  mov    $0x0,%ebx
  add    %rdi,%r14
L15:
  mov    %r14,%rsi
  sub    %rbx,%rsi
  lea    (%r12,%r13,1),%rdi
  add    %rbx,%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jg     L15
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void strReverse(char *str, int begin, int len) {
  char *first = str + begin;
  int middle = len / 2 - 1;
  char *end = str + begin + len - 1;
  int i = 0;
  for (; i <= middle; i++) {
    swap(first + i, end - i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strReverse>:
  endbr64
  push   %r13
  movslq %esi,%rsi
  movslq %edx,%rax
  push   %r12
  lea    -0x1(%rsi,%rax,1),%rax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x8,%rsp
  cmp    $0x1,%edx
  jle    L19
  xor    %ebx,%ebx
  lea    (%rax,%rdi,1),%r13
  lea    (%rsi,%rdi,1),%r12
  nopl   0x0(%rax)
L13:
  mov    %r13,%rsi
  lea    (%r12,%rbx,1),%rdi
  sub    %rbx,%rsi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %ebx,%ebp
  jg     L13
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strReverse(char *str, int begin, int len) {
  char *first = str + begin;
  int middle = len / 2 - 1;
  char *end = str + begin + len - 1;
  int i = 0;
  for (; i <= middle; i++) {
    swap(first + i, end - i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strReverse>:
  endbr64
  push   %r13
  movslq %esi,%rsi
  movslq %edx,%rax
  push   %r12
  lea    -0x1(%rsi,%rax,1),%rax
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x8,%rsp
  cmp    $0x1,%edx
  jle    L12
  xor    %ebx,%ebx
  lea    (%rdi,%rax,1),%r13
  lea    (%rsi,%rdi,1),%r12
  nopl   0x0(%rax)
L15:
  mov    %r13,%rsi
  lea    (%r12,%rbx,1),%rdi
  sub    %rbx,%rsi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %ebx,%ebp
  jg     L15
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void strReverse(char *str, int begin, int len) {
  char *first = str + begin;
  int middle = len / 2 - 1;
  char *end = str + begin + len - 1;
  int i = 0;
  for (; i <= middle; i++) {
    swap(first + i, end - i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strnlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strndup(const char *src, size_t max) {
  size_t len = strnlen(src, max);
  char *dup;
  dup = malloc(len + 1);
  if (dup) {
    memcpy(dup, src, len);
    dup[len] = '\0';
  }
  return dup;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strnlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%rbp,1)
L6:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *src, size_t max) {
  size_t len = strnlen(src, max);
  char *dup;
  dup = malloc(len + 1);
  if (dup) {
    memcpy(dup, src, len);
    dup[len] = '\0';
  }
  return dup;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strnlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L4:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *src, size_t max) {
  size_t len = strnlen(src, max);
  char *dup;
  dup = malloc(len + 1);
  if (dup) {
    memcpy(dup, src, len);
    dup[len] = '\0';
  }
  return dup;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strndup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strnlen@plt>
  lea    0x1(%rax),%rdi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
L2:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strndup(const char *src, size_t max) {
  size_t len = strnlen(src, max);
  char *dup;
  dup = malloc(len + 1);
  if (dup) {
    memcpy(dup, src, len);
    dup[len] = '\0';
  }
  return dup;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<robust_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L27:
  mov    -0x18(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L38
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  jmp    L1
L38:
  mov    -0xc(%rbp),%eax
L1:
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L50
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  cmp    %eax,-0x4(%rbp)
  je     L50
  mov    -0x4(%rbp),%eax
  jmp    L6
L50:
  cmpl   $0x0,-0x4(%rbp)
  jne    L27
  mov    -0x18(%rbp),%eax
  sub    -0xc(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int robust_write(int fd, char *buf, int buf_size) {
  int bytes_remain, bytes_written;
  int buf_offset;
  bytes_remain = buf_size;
  while (true) {
    buf_offset = buf_size - bytes_remain;
    bytes_written = write(fd, buf + buf_offset, bytes_remain);
    bytes_remain = (bytes_written > 0) ? bytes_remain - bytes_written : bytes_remain;
    if (bytes_written < 0 && bytes_written != -EINTR) {
      return bytes_written;
    } else if (bytes_written == 0) {
      return buf_size - bytes_remain;
    }
  }
  assert(false);
  return -EINVAL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<robust_write>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %edx,%r12d
  mov    %edx,%ebx
  jmp    L33
L23:
  sub    %eax,%ebx
L33:
  mov    %r12d,%ebp
  sub    %ebx,%ebp
  movslq %ebp,%rsi
  add    %r13,%rsi
  mov    %ebx,%edx
  mov    %r14d,%edi
  call   <write@plt>
  test   %eax,%eax
  jg     L23
  jns    L29
  mov    D5(%rip),%rdx
  mov    %eax,%ecx
  add    (%rdx),%ecx
  je     L33
  mov    %eax,%ebp
L29:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int robust_write(int fd, char *buf, int buf_size) {
  int bytes_remain, bytes_written;
  int buf_offset;
  bytes_remain = buf_size;
  while (true) {
    buf_offset = buf_size - bytes_remain;
    bytes_written = write(fd, buf + buf_offset, bytes_remain);
    bytes_remain = (bytes_written > 0) ? bytes_remain - bytes_written : bytes_remain;
    if (bytes_written < 0 && bytes_written != -EINTR) {
      return bytes_written;
    } else if (bytes_written == 0) {
      return buf_size - bytes_remain;
    }
  }
  assert(false);
  return -EINVAL;
}
```