ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<build_get_query>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdi,%r14
  push   %r13
  push   %r12
  cmpb   $0x2f,(%rsi)
  mov    %rsi,%r12
  sete   %al
  add    %rax,%r12
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    0x41(%r13,%rax,1),%rdi
  call   <malloc@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D11(%rip),%r8
  mov    %rax,%r13
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string

tool: D11: eFJenergy-DataLogger 2.5

tool: D19: GET /%s HTTP/1.0
Host: %s
User-Agent: %s



assistant: ```c
char *build_get_query(char *host, char *page) {
  char *query;
  char *getpage = page;
  char *tpl = "GET /%s HTTP/1.0\r\nHost: %s\r\nUser-Agent: %s\r\n\r\n";
  if (getpage[0] == '/') {
    getpage = getpage + 1;
    ;
  }
  query = (char *)malloc(strlen(host) + strlen(getpage) + strlen("eFJenergy-DataLogger 2.5") + strlen(tpl) - 5);
  sprintf(query, tpl, getpage, host, "eFJenergy-DataLogger 2.5");
  return query;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_putnbrl_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ft_putnbr_fd@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <ft_putchar_fd@plt>
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbrl_fd(int n, int fd) {
  ft_putnbr_fd(n, fd);
  ft_putchar_fd('\n', fd);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_putnbrl_fd>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  call   <ft_putnbr_fd@plt>
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <ft_putchar_fd@plt>
  pop    %rbx
  ret
```

assistant: ```c
void ft_putnbrl_fd(int n, int fd) {
  ft_putnbr_fd(n, fd);
  ft_putchar_fd('\n', fd);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_putnbrl_fd>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <ft_putnbr_fd@plt>
  mov    %ebp,%esi
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <ft_putchar_fd@plt>
```

assistant: ```c
void ft_putnbrl_fd(int n, int fd) {
  ft_putnbr_fd(n, fd);
  ft_putchar_fd('\n', fd);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_putnbrl_fd>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  call   <ft_putnbr_fd@plt>
  mov    %ebp,%esi
  mov    $0xa,%edi
  pop    %rbp
  jmp    1070 <ft_putchar_fd@plt>
```

assistant: ```c
void ft_putnbrl_fd(int n, int fd) {
  ft_putnbr_fd(n, fd);
  ft_putchar_fd('\n', fd);
}
```
user: What is the c source code of the assembly code below:

```asm
<funcX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L11:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0xf,-0x4(%rbp)
  jbe    L11
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void funcX(unsigned char *a, unsigned char *b, unsigned char *outdata) {
  unsigned int i;
  for (i = 0; i < 16; ++i) {
    outdata[i] = a[i] ^ b[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<funcX>:
  endbr64
  mov    $0x0,%eax
L6:
  movzbl (%rdi,%rax,1),%ecx
  xor    (%rsi,%rax,1),%cl
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L6
  ret
```

assistant: ```c
void funcX(unsigned char *a, unsigned char *b, unsigned char *outdata) {
  unsigned int i;
  for (i = 0; i < 16; ++i) {
    outdata[i] = a[i] ^ b[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<funcX>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L5:
  movzbl (%rdi,%rax,1),%ecx
  xor    (%rsi,%rax,1),%cl
  mov    %cl,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L5
  ret
```

assistant: ```c
void funcX(unsigned char *a, unsigned char *b, unsigned char *outdata) {
  unsigned int i;
  for (i = 0; i < 16; ++i) {
    outdata[i] = a[i] ^ b[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<funcX>:
  endbr64
  lea    0x1(%rdi),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L13
  lea    0x1(%rsi),%rcx
  mov    %rax,%rdx
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L13
  movdqu (%rdi),%xmm0
  movdqu (%rsi),%xmm1
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rax)
  ret
  nopl   0x0(%rax)
L13:
  movzbl (%rdi),%edx
  xor    (%rsi),%dl
  mov    %dl,(%rax)
  movzbl 0x1(%rdi),%edx
  xor    0x1(%rsi),%dl
  mov    %dl,0x1(%rax)
  movzbl 0x2(%rdi),%edx
  xor    0x2(%rsi),%dl
  mov    %dl,0x2(%rax)
  movzbl 0x3(%rdi),%edx
  xor    0x3(%rsi),%dl
  mov    %dl,0x3(%rax)
  movzbl 0x4(%rdi),%edx
  xor    0x4(%rsi),%dl
  mov    %dl,0x4(%rax)
  movzbl 0x5(%rdi),%edx
  xor    0x5(%rsi),%dl
  mov    %dl,0x5(%rax)
  movzbl 0x6(%rdi),%edx
  xor    0x6(%rsi),%dl
  mov    %dl,0x6(%rax)
  movzbl 0x7(%rdi),%edx
  xor    0x7(%rsi),%dl
  mov    %dl,0x7(%rax)
  movzbl 0x8(%rdi),%edx
  xor    0x8(%rsi),%dl
  mov    %dl,0x8(%rax)
  movzbl 0x9(%rdi),%edx
  xor    0x9(%rsi),%dl
  mov    %dl,0x9(%rax)
  movzbl 0xa(%rdi),%edx
  xor    0xa(%rsi),%dl
  mov    %dl,0xa(%rax)
  movzbl 0xb(%rdi),%edx
  xor    0xb(%rsi),%dl
  mov    %dl,0xb(%rax)
  movzbl 0xc(%rdi),%edx
  xor    0xc(%rsi),%dl
  mov    %dl,0xc(%rax)
  movzbl 0xd(%rdi),%edx
  xor    0xd(%rsi),%dl
  mov    %dl,0xd(%rax)
  movzbl 0xe(%rdi),%edx
  xor    0xe(%rsi),%dl
  mov    %dl,0xe(%rax)
  movzbl 0xf(%rdi),%edx
  xor    0xf(%rsi),%dl
  mov    %dl,0xf(%rax)
  ret
```

assistant: ```c
void funcX(unsigned char *a, unsigned char *b, unsigned char *outdata) {
  unsigned int i;
  for (i = 0; i < 16; ++i) {
    outdata[i] = a[i] ^ b[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  jmp    L7
L5:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd>
L7:
  leave
  ret
```

assistant: ```c
int gcd(int x, int y) {
  if (y == 0) {
    return x;
  } else {
    return gcd(y, (x % y));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  test   %esi,%esi
  jne    L7
  ret
L7:
  sub    $0x8,%rsp
  mov    %esi,%edi
  cltd
  idiv   %esi
  mov    %edx,%esi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gcd(int x, int y) {
  if (y == 0) {
    return x;
  } else {
    return gcd(y, (x % y));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  test   %esi,%esi
  jne    L3
  jmp    L20
  nop
L28:
  mov    %edx,%r8d
L3:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L28
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int x, int y) {
  if (y == 0) {
    return x;
  } else {
    return gcd(y, (x % y));
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%r8d
  test   %esi,%esi
  jne    L0
  jmp    L11
  nop
L3:
  mov    %edx,%r8d
L0:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L3
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %edi,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int gcd(int x, int y) {
  if (y == 0) {
    return x;
  } else {
    return gcd(y, (x % y));
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bfunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D23(%rip),%eax
  xor    $0x1,%eax
  mov    %eax,D29(%rip)
  mov    D29(%rip),%eax
  test   %eax,%eax
  je     L1
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glEnable@plt>
  jmp    L4
L1:
  mov    D29(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glDisable@plt>
L4:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bfunc(void) {
  static int state;
  if (state ^= 1)
    glEnable(GL_BLEND);
  else
    glDisable(GL_BLEND);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bfunc>:
  endbr64
  sub    $0x8,%rsp
  mov    D37(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D15(%rip)
  cmp    $0x1,%eax
  je     L1
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <glEnable@plt>
L2:
  add    $0x8,%rsp
  ret
L1:
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <glDisable@plt>
  jmp    L2
```

assistant: ```c
void bfunc(void) {
  static int state;
  if (state ^= 1)
    glEnable(GL_BLEND);
  else
    glDisable(GL_BLEND);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bfunc>:
  endbr64
  mov    D28(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D29(%rip)
  mov    D29(%rip),%rdx
  mov    (%rdx),%edi
  cmp    $0x1,%eax
  je     L0
  jmp    1070 <glEnable@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  jmp    1060 <glDisable@plt>
```

assistant: ```c
void bfunc(void) {
  static int state;
  if (state ^= 1)
    glEnable(GL_BLEND);
  else
    glDisable(GL_BLEND);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bfunc>:
  endbr64
  mov    D17(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D6(%rip)
  mov    D6(%rip),%rdx
  mov    (%rdx),%edi
  cmp    $0x1,%eax
  je     L3
  jmp    1070 <glEnable@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  jmp    1060 <glDisable@plt>
```

assistant: ```c
void bfunc(void) {
  static int state;
  if (state ^= 1)
    glEnable(GL_BLEND);
  else
    glDisable(GL_BLEND);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<routeaddr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L97
L133:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x3e,%eax
  je     L36
  cmp    $0x3e,%eax
  jg     L75
  cmp    $0x3c,%eax
  je     L89
  cmp    $0x3c,%eax
  jg     L75
  cmp    $0x22,%eax
  je     L4
  cmp    $0x28,%eax
  jne    L75
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <skip_comment@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x10(%rbp)
  jmp    L75
L127:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L125
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L4
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L127
  jmp    L75
L125:
  nop
  jmp    L75
L89:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L75
L36:
  mov    -0x8(%rbp),%rax
  jmp    L17
L75:
  addq   $0x1,-0x10(%rbp)
L97:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L133
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
char *routeaddr(const char *name) {
  const char *np, *rp = NULL;
  for (np = name; *np; np++) {
    switch (*np) {
    case '(':
      np = skip_comment(&np[1]) - 1;
      break;
    case '"':
      while (*np) {
        if (*++np == '"')
          break;
        if (*np == '\\' && np[1])
          np++;
      }
      break;
    case '<':
      rp = np;
      break;
    case '>':
      return (char *)rp;
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<routeaddr>:
  endbr64
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L158
  mov    $0x0,%ebx
  jmp    L181
L204:
  mov    %rdi,%rax
  jmp    L124
L37:
  cmp    $0x3e,%al
  jne    L161
L52:
  mov    %rbx,%rax
  pop    %rbx
  ret
L161:
  mov    %rdi,%rax
L124:
  lea    0x1(%rax),%rdi
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L121
L181:
  cmp    $0x3c,%al
  je     L94
  cmp    $0x3c,%al
  jg     L37
  cmp    $0x22,%al
  je     L0
  cmp    $0x28,%al
  jne    L204
  add    $0x1,%rdi
  call   <skip_comment@plt>
  sub    $0x1,%eax
  cltq
  jmp    L124
L0:
  mov    %rdi,%rax
  cmpb   $0x0,(%rdi)
  jne    L147
  jmp    L124
L10:
  cmpb   $0x0,0x2(%rdi)
  je     L62
  add    $0x2,%rdi
L48:
  cmpb   $0x0,(%rdi)
  je     L9
L147:
  lea    0x1(%rdi),%rax
  movzbl 0x1(%rdi),%edx
  cmp    $0x22,%dl
  je     L124
  cmp    $0x5c,%dl
  je     L10
  mov    %rax,%rdi
  jmp    L48
L62:
  mov    %rax,%rdi
  jmp    L48
L9:
  mov    %rdi,%rax
  jmp    L124
L94:
  mov    %rdi,%rbx
  mov    %rdi,%rax
  jmp    L124
L121:
  mov    $0x0,%ebx
  jmp    L52
L158:
  mov    $0x0,%ebx
  jmp    L52
```

assistant: ```c
char *routeaddr(const char *name) {
  const char *np, *rp = NULL;
  for (np = name; *np; np++) {
    switch (*np) {
    case '(':
      np = skip_comment(&np[1]) - 1;
      break;
    case '"':
      while (*np) {
        if (*++np == '"')
          break;
        if (*np == '\\' && np[1])
          np++;
      }
      break;
    case '<':
      rp = np;
      break;
    case '>':
      return (char *)rp;
    }
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<routeaddr>:
  endbr64
  push   %r12
  movzbl (%rdi),%eax
  xor    %r12d,%r12d
  test   %al,%al
  je     L150
L9:
  cmp    $0x3c,%al
  je     L141
  jg     L35
  cmp    $0x22,%al
  je     L130
  cmp    $0x28,%al
  jne    L71
  add    $0x1,%rdi
  call   <skip_comment@plt>
  lea    -0x1(%rax),%edi
  movslq %edi,%rdi
L71:
  movzbl 0x1(%rdi),%eax
L88:
  add    $0x1,%rdi
  test   %al,%al
  jne    L9
L150:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  cmp    $0x3e,%al
  jne    L71
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L130:
  movzbl 0x1(%rdi),%edx
  cmpb   $0x0,(%rdi)
  mov    %edx,%eax
  jne    L59
  jmp    L88
  nopl   (%rax)
L55:
  movzbl 0x2(%rdi),%eax
  test   %dl,%dl
  je     L138
L85:
  mov    %eax,%edx
  mov    %rcx,%rdi
L59:
  lea    0x1(%rdi),%rcx
  cmp    $0x22,%dl
  je     L27
  cmp    $0x5c,%dl
  jne    L55
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  je     L14
  movzbl 0x3(%rdi),%eax
  lea    0x2(%rdi),%rcx
  jmp    L85
  nopl   (%rax)
L14:
  lea    0x2(%rdi),%rax
  mov    %rcx,%rdi
  mov    %rax,%rcx
  movzbl 0x2(%rdi),%eax
  test   %dl,%dl
  jne    L85
L138:
  mov    %rcx,%rdi
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L141:
  movzbl 0x1(%rdi),%eax
  mov    %rdi,%r12
  jmp    L88
  nopl   0x0(%rax)
L27:
  movzbl 0x2(%rdi),%eax
  mov    %rcx,%rdi
  jmp    L88
```

assistant: ```c
char *routeaddr(const char *name) {
  const char *np, *rp = NULL;
  for (np = name; *np; np++) {
    switch (*np) {
    case '(':
      np = skip_comment(&np[1]) - 1;
      break;
    case '"':
      while (*np) {
        if (*++np == '"')
          break;
        if (*np == '\\' && np[1])
          np++;
      }
      break;
    case '<':
      rp = np;
      break;
    case '>':
      return (char *)rp;
    }
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<routeaddr>:
  endbr64
  push   %r12
  movzbl (%rdi),%eax
  xor    %r12d,%r12d
  test   %al,%al
  je     L57
L109:
  cmp    $0x3c,%al
  je     L95
  jg     L94
  cmp    $0x22,%al
  je     L157
  cmp    $0x28,%al
  jne    L86
  add    $0x1,%rdi
  call   <skip_comment@plt>
  lea    -0x1(%rax),%edi
  movslq %edi,%rdi
L86:
  movzbl 0x1(%rdi),%eax
L54:
  add    $0x1,%rdi
  test   %al,%al
  jne    L109
L57:
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L94:
  cmp    $0x3e,%al
  jne    L86
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L157:
  movzbl 0x1(%rdi),%edx
  jmp    L106
  cs nopw 0x0(%rax,%rax,1)
L53:
  movzbl 0x2(%rdi),%eax
  test   %dl,%dl
  je     L44
L93:
  mov    %eax,%edx
  mov    %rcx,%rdi
L106:
  lea    0x1(%rdi),%rcx
  cmp    $0x22,%dl
  je     L152
  cmp    $0x5c,%dl
  jne    L53
  movzbl 0x2(%rdi),%edx
  test   %dl,%dl
  je     L3
  movzbl 0x3(%rdi),%eax
  lea    0x2(%rdi),%rcx
  jmp    L93
  nopl   (%rax)
L3:
  lea    0x2(%rdi),%rax
  mov    %rcx,%rdi
  mov    %rax,%rcx
  movzbl 0x2(%rdi),%eax
  test   %dl,%dl
  jne    L93
L44:
  mov    %rcx,%rdi
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L95:
  movzbl 0x1(%rdi),%eax
  mov    %rdi,%r12
  jmp    L54
  nopl   0x0(%rax)
L152:
  movzbl 0x2(%rdi),%eax
  mov    %rcx,%rdi
  jmp    L54
```

assistant: ```c
char *routeaddr(const char *name) {
  const char *np, *rp = NULL;
  for (np = name; *np; np++) {
    switch (*np) {
    case '(':
      np = skip_comment(&np[1]) - 1;
      break;
    case '"':
      while (*np) {
        if (*++np == '"')
          break;
        if (*np == '\\' && np[1])
          np++;
      }
      break;
    case '<':
      rp = np;
      break;
    case '>':
      return (char *)rp;
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<focusJoueurIAEnnemi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <determinerNbTourFocusEnnemi@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void focusJoueurIAEnnemi(unsigned int *modeFocus, int *nbTourFocus, int *nbTourAttendreFocus, const unsigned int niveauIA) {
  *modeFocus = 1;
  *nbTourFocus = determinerNbTourFocusEnnemi(niveauIA);
  *nbTourAttendreFocus = -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<focusJoueurIAEnnemi>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%edi
  movl   $0x1,(%rax)
  call   <determinerNbTourFocusEnnemi@plt>
  mov    %eax,0x0(%rbp)
  movl   $0xffffffff,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void focusJoueurIAEnnemi(unsigned int *modeFocus, int *nbTourFocus, int *nbTourAttendreFocus, const unsigned int niveauIA) {
  *modeFocus = 1;
  *nbTourFocus = determinerNbTourFocusEnnemi(niveauIA);
  *nbTourAttendreFocus = -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<focusJoueurIAEnnemi>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %ecx,%edi
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  movl   $0x1,(%r8)
  call   <determinerNbTourFocusEnnemi@plt>
  mov    %eax,0x0(%rbp)
  movl   $0xffffffff,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void focusJoueurIAEnnemi(unsigned int *modeFocus, int *nbTourFocus, int *nbTourAttendreFocus, const unsigned int niveauIA) {
  *modeFocus = 1;
  *nbTourFocus = determinerNbTourFocusEnnemi(niveauIA);
  *nbTourAttendreFocus = -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<focusJoueurIAEnnemi>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  mov    %ecx,%edi
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  movl   $0x1,(%r8)
  call   <determinerNbTourFocusEnnemi@plt>
  mov    %eax,0x0(%rbp)
  movl   $0xffffffff,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void focusJoueurIAEnnemi(unsigned int *modeFocus, int *nbTourFocus, int *nbTourAttendreFocus, const unsigned int niveauIA) {
  *modeFocus = 1;
  *nbTourFocus = determinerNbTourFocusEnnemi(niveauIA);
  *nbTourAttendreFocus = -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  cmp    $0xffffffff,%eax
  jne    L39
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L39:
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  test   %rax,%rax
  jne    L0
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L0:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,-0x414(%rbp)
  cmpl   $0xffffffff,-0x414(%rbp)
  jne    L25
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L38
L25:
  cmpl   $0x0,-0x414(%rbp)
  jne    L18
  lea    -0x410(%rbp),%rax
  mov    $0x400,%esi
  mov    %rax,%rdi
  call   <getcwd@plt>
  test   %rax,%rax
  jne    L19
  lea    D69(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L19:
  lea    -0x410(%rbp),%rax
  mov    %rax,%rsi
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L38
L18:
  mov    $0x0,%edi
  call   <wait@plt>
  cmp    $0xffffffff,%eax
  jne    L38
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L38:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D60
data_type: string
name: extract_symbolic_data
arguments: data_label: D72
data_type: string
name: extract_symbolic_data
arguments: data_label: D69
data_type: string
name: extract_symbolic_data
arguments: data_label: D23
data_type: string
name: extract_symbolic_data
arguments: data_label: D58
data_type: string
name: extract_symbolic_data
arguments: data_label: D57
data_type: string
name: extract_symbolic_data
arguments: data_label: D45
data_type: string

tool: D60: ./test-dir

tool: D72: fail to change dir

tool: D69: fail to get pwd

tool: D23: the parent : %s


tool: D58: fail to fork

tool: D57: the child : %s


tool: D45: fail to wait

assistant: ```c
int main(void) {
  pid_t pid;
  char buf[1024];
  if (chdir("./test-dir") == -1) {
    perror("fail to change dir");
    exit(1);
  }
  if (getcwd(buf, 1024) == NULL) {
    perror("fail to get pwd");
    exit(1);
  }
  printf("the parent : %s\n", buf);
  pid = fork();
  if (pid == -1) {
    perror("fail to fork");
    exit(1);
  } else if (pid == 0) {
    if (getcwd(buf, 1024) == NULL) {
      perror("fail to get pwd");
      exit(1);
    }
    printf("the child : %s\n", buf);
  } else {
    if (wait(NULL) == -1) {
      perror("fail to wait");
      exit(1);
    }
  }
  return 0;
}
```