ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<serial_mode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    0x1(%rdi),%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x128,%rsp
  mov    D2(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r14
  nop
L13:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    (%r12),%edi
  call   <fileno@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <select@plt>
  test   %rax,%rax
  js     L67
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L2
L68:
  mov    (%r12),%edi
  call   <fileno@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L13
  mov    (%r12),%edi
  call   <fileno@plt>
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jle    L13
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L68
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <fileno@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L68
  cs nopw 0x0(%rax,%rax,1)
L67:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void serial_mode(int fd) {
  int bytes;
  char buf[256];
  while (1) {
    fd_set fds;
    FD_ZERO(&fds);
    FD_SET(fd, &fds);
    FD_SET(fileno(stdin), &fds);
    if (select(fd + 1, &fds, NULL, NULL, NULL) < 0) {
      return;
    }
    if (FD_ISSET(fd, &fds)) {
      bytes = read(fd, buf, sizeof(buf));
      if (bytes > 0)
        write(fileno(stdout), buf, bytes);
    }
    if (FD_ISSET(fileno(stdin), &fds)) {
      bytes = read(fileno(stdin), buf, sizeof(buf));
      if (bytes > 0)
        write(fd, buf, bytes);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<serial_mode>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    0x1(%rdi),%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x128,%rsp
  mov    D3(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  lea    0x10(%rsp),%r14
  nop
L74:
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_SET@plt>
  mov    (%r12),%edi
  call   <fileno@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <FD_SET@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <select@plt>
  test   %rax,%rax
  js     L5
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  jne    L47
L19:
  mov    (%r12),%edi
  call   <fileno@plt>
  mov    %rbx,%rsi
  mov    %eax,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L74
  mov    (%r12),%edi
  call   <fileno@plt>
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jle    L74
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L47:
  mov    $0x100,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  mov    %eax,%r15d
  test   %eax,%eax
  jle    L19
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <fileno@plt>
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %eax,%edi
  call   <write@plt>
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x128,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void serial_mode(int fd) {
  int bytes;
  char buf[256];
  while (1) {
    fd_set fds;
    FD_ZERO(&fds);
    FD_SET(fd, &fds);
    FD_SET(fileno(stdin), &fds);
    if (select(fd + 1, &fds, NULL, NULL, NULL) < 0) {
      return;
    }
    if (FD_ISSET(fd, &fds)) {
      bytes = read(fd, buf, sizeof(buf));
      if (bytes > 0)
        write(fileno(stdout), buf, bytes);
    }
    if (FD_ISSET(fileno(stdin), &fds)) {
      bytes = read(fileno(stdin), buf, sizeof(buf));
      if (bytes > 0)
        write(fd, buf, bytes);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rcx
  mov    %rsi,%rax
  cmp    %rax,%rcx
  jne    L32
  mov    $0x0,%eax
  jmp    L2
L33:
  mov    %rcx,%rsi
  lea    0x1(%rsi),%rcx
  movzbl (%rsi),%esi
  test   %sil,%sil
  jne    L32
  mov    $0x0,%eax
  jmp    L2
L32:
  sub    $0x1,%edx
  test   %edx,%edx
  js     L13
  movzbl (%rcx),%edi
  mov    %rax,%rsi
  lea    0x1(%rsi),%rax
  movzbl (%rsi),%esi
  cmp    %sil,%dil
  je     L33
L13:
  test   %edx,%edx
  js     L63
  movzbl (%rcx),%edx
  movsbl %dl,%edx
  sub    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  jmp    L2
L63:
  mov    $0x0,%eax
L2:
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
register n;
{
  if (s1 == s2)
    return (0);
  while (--n >= 0 && *s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return ((n < 0) ? 0 : (*s1 - *--s2));
}
```
user: What is the c source code of the assembly code below:

```asm
<strncmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L0
  mov    %rdi,%rax
  lea    -0x1(%rdx,%rdi,1),%ecx
L18:
  cmp    %eax,%ecx
  js     L26
  movzbl (%rax),%edx
  add    $0x1,%rsi
  cmp    -0x1(%rsi),%dl
  jne    L23
  add    $0x1,%rax
  test   %dl,%dl
  jne    L18
  mov    $0x0,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
L26:
  mov    $0x0,%eax
  ret
L23:
  movsbl (%rax),%eax
  movsbl -0x1(%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
register n;
{
  if (s1 == s2)
    return (0);
  while (--n >= 0 && *s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return ((n < 0) ? 0 : (*s1 - *--s2));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strncmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L13
  xor    %eax,%eax
  lea    -0x1(%rdx),%r8d
  jmp    L49
  nopl   0x0(%rax)
L7:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L31
  add    $0x1,%rax
  test   %dl,%dl
  je     L13
L49:
  cmp    %eax,%r8d
  jns    L7
L13:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L31:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
register n;
{
  if (s1 == s2)
    return (0);
  while (--n >= 0 && *s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return ((n < 0) ? 0 : (*s1 - *--s2));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L9
  xor    %eax,%eax
  lea    -0x1(%rdx),%r8d
  jmp    L16
  nopl   0x0(%rax)
L49:
  movzbl (%rdi,%rax,1),%edx
  movsbl (%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L20
  add    $0x1,%rax
  test   %dl,%dl
  je     L9
L16:
  cmp    %eax,%r8d
  jns    L49
L9:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L20:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strncmp(s1, s2, n)
register char *s1, *s2;
register n;
{
  if (s1 == s2)
    return (0);
  while (--n >= 0 && *s1 == *s2++)
    if (*s1++ == '\0')
      return (0);
  return ((n < 0) ? 0 : (*s1 - *--s2));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L4
L28:
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L64
L41:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L50
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L50:
  addq   $0x1,-0x8(%rbp)
L64:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L46
  cmpq   $0x0,-0x18(%rbp)
  je     L41
L46:
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  cmpq   $0x0,-0x18(%rbp)
  je     L28
L10:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strpbrk(const char *str, const char *accept) {
  char *ret_val = NULL;
  char *s, *t;
  for (s = (char *)str; (*s) && (!ret_val); s++) {
    for (t = (char *)accept; (*t) && (!ret_val); t++) {
      if (*s == *t)
        ret_val = s;
    }
  }
  return ret_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L50
  movzbl (%rsi),%r10d
  mov    $0x0,%r9d
  jmp    L48
L15:
  add    $0x1,%rdi
  movzbl (%rdi),%r8d
  test   %rcx,%rcx
  jne    L9
  test   %r8b,%r8b
  je     L9
L48:
  mov    %rsi,%rax
  mov    %r10d,%edx
  mov    %r9,%rcx
  test   %r10b,%r10b
  je     L15
L35:
  cmp    %r8b,%dl
  mov    %r9,%rcx
  cmove  %rdi,%rcx
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %rcx,%rcx
  jne    L15
  test   %dl,%dl
  jne    L35
  jmp    L15
L50:
  mov    $0x0,%ecx
L9:
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *my_strpbrk(const char *str, const char *accept) {
  char *ret_val = NULL;
  char *s, *t;
  for (s = (char *)str; (*s) && (!ret_val); s++) {
    for (t = (char *)accept; (*t) && (!ret_val); t++) {
      if (*s == *t)
        ret_val = s;
    }
  }
  return ret_val;
}
```
user: What is the c source code of the assembly code below?

```asm
<my_strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%r9
  test   %r8b,%r8b
  je     L4
  movzbl (%rsi),%edi
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rsi,%rax
  mov    %edi,%edx
  test   %dil,%dil
  je     L13
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  mov    %edx,%ecx
  movzbl (%rax),%edx
  cmp    %r8b,%cl
  je     L44
  test   %dl,%dl
  jne    L20
L13:
  movzbl 0x1(%r9),%r8d
  add    $0x1,%r9
  test   %r8b,%r8b
  jne    L6
L4:
  xor    %r9d,%r9d
L44:
  mov    %r9,%rax
  ret
```

assistant: ```c
char *my_strpbrk(const char *str, const char *accept) {
  char *ret_val = NULL;
  char *s, *t;
  for (s = (char *)str; (*s) && (!ret_val); s++) {
    for (t = (char *)accept; (*t) && (!ret_val); t++) {
      if (*s == *t)
        ret_val = s;
    }
  }
  return ret_val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%r9
  test   %r8b,%r8b
  je     L4
  movzbl (%rsi),%edi
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rsi,%rax
  mov    %edi,%edx
  test   %dil,%dil
  je     L24
  nopw   0x0(%rax,%rax,1)
L46:
  add    $0x1,%rax
  mov    %edx,%ecx
  movzbl (%rax),%edx
  cmp    %r8b,%cl
  je     L17
  test   %dl,%dl
  jne    L46
L24:
  movzbl 0x1(%r9),%r8d
  add    $0x1,%r9
  test   %r8b,%r8b
  jne    L14
L4:
  xor    %r9d,%r9d
L17:
  mov    %r9,%rax
  ret
```

assistant: ```c
char *my_strpbrk(const char *str, const char *accept) {
  char *ret_val = NULL;
  char *s, *t;
  for (s = (char *)str; (*s) && (!ret_val); s++) {
    for (t = (char *)accept; (*t) && (!ret_val); t++) {
      if (*s == *t)
        ret_val = s;
    }
  }
  return ret_val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x63,-0x10(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <sched_setscheduler@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L4:
  jmp    L4
```

assistant: ```c
int main() {
  struct sched_param s;
  s.sched_priority = 99;
  int ret = sched_setscheduler(0, SCHED_FIFO, &s);
  assert(ret != -1);
  while (1) {
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x63,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%edi
  call   <sched_setscheduler@plt>
  cmp    $0xffffffff,%eax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
L1:
  jmp    L1
```

assistant: ```c
int main() {
  struct sched_param s;
  s.sched_priority = 99;
  int ret = sched_setscheduler(0, SCHED_FIFO, &s);
  assert(ret != -1);
  while (1) {
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  lea    0x4(%rsp),%rdx
  movl   $0x63,0x4(%rsp)
  mov    (%rax),%esi
  call   <sched_setscheduler@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  setne  %dil
  call   <assert@plt>
L6:
  jmp    L6
```

assistant: ```c
int main() {
  struct sched_param s;
  s.sched_priority = 99;
  int ret = sched_setscheduler(0, SCHED_FIFO, &s);
  assert(ret != -1);
  while (1) {
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  xor    %edi,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rdx
  movl   $0x63,0x4(%rsp)
  mov    (%rax),%esi
  call   <sched_setscheduler@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  setne  %dil
  call   <assert@plt>
L0:
  jmp    L0
```

assistant: ```c
int main() {
  struct sched_param s;
  s.sched_priority = 99;
  int ret = sched_setscheduler(0, SCHED_FIFO, &s);
  assert(ret != -1);
  while (1) {
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<l_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L19
L2:
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
L19:
  leave
  ret
```

assistant: ```c
void *l_alloc(void *ud, void *ptr, size_t osize, size_t nsize, const char *allocName, unsigned int flags) {
  (void)allocName;
  (void)flags;
  (void)ud;
  (void)osize;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else
    return realloc(ptr, nsize);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<l_alloc>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  test   %rcx,%rcx
  je     L6
  mov    %rcx,%rsi
  call   <realloc@plt>
L12:
  add    $0x8,%rsp
  ret
L6:
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
void *l_alloc(void *ud, void *ptr, size_t osize, size_t nsize, const char *allocName, unsigned int flags) {
  (void)allocName;
  (void)flags;
  (void)ud;
  (void)osize;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else
    return realloc(ptr, nsize);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<l_alloc>:
  endbr64
  mov    %rsi,%rdi
  test   %rcx,%rcx
  je     L1
  mov    %rcx,%rsi
  jmp    1070 <realloc@plt>
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *l_alloc(void *ud, void *ptr, size_t osize, size_t nsize, const char *allocName, unsigned int flags) {
  (void)allocName;
  (void)flags;
  (void)ud;
  (void)osize;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else
    return realloc(ptr, nsize);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<l_alloc>:
  endbr64
  mov    %rsi,%rdi
  test   %rcx,%rcx
  je     L5
  mov    %rcx,%rsi
  jmp    1070 <realloc@plt>
  nopl   0x0(%rax)
L5:
  sub    $0x8,%rsp
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *l_alloc(void *ud, void *ptr, size_t osize, size_t nsize, const char *allocName, unsigned int flags) {
  (void)allocName;
  (void)flags;
  (void)ud;
  (void)osize;
  if (nsize == 0) {
    free(ptr);
    return NULL;
  } else
    return realloc(ptr, nsize);
}
```
user: What is the c source code of the assembly code below:

```asm
<switch_red>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L2
  mov    $0x10,%edi
  call   <turn_led_on_tir@plt>
  jmp    L15
L2:
  mov    $0x10,%edi
  call   <turn_led_off_tir@plt>
L15:
  nop
  leave
  ret
```

assistant: ```c
void switch_red(bool state) {
  if (state) {
    turn_led_on_tir(0x10);
  } else {
    turn_led_off_tir(0x10);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<switch_red>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L18
  mov    $0x10,%edi
  call   <turn_led_on_tir@plt>
L0:
  add    $0x8,%rsp
  ret
L18:
  mov    $0x10,%edi
  call   <turn_led_off_tir@plt>
  jmp    L0
```

assistant: ```c
void switch_red(bool state) {
  if (state) {
    turn_led_on_tir(0x10);
  } else {
    turn_led_off_tir(0x10);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<switch_red>:
  endbr64
  test   %edi,%edi
  mov    $0x10,%edi
  je     L8
  jmp    1060 <turn_led_on_tir@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  jmp    1070 <turn_led_off_tir@plt>
```

assistant: ```c
void switch_red(bool state) {
  if (state) {
    turn_led_on_tir(0x10);
  } else {
    turn_led_off_tir(0x10);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<switch_red>:
  endbr64
  test   %edi,%edi
  mov    $0x10,%edi
  je     L7
  jmp    1060 <turn_led_on_tir@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  jmp    1070 <turn_led_off_tir@plt>
```

assistant: ```c
void switch_red(bool state) {
  if (state) {
    turn_led_on_tir(0x10);
  } else {
    turn_led_off_tir(0x10);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reallocarr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rcx
  lea    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  cmpq   $0x0,-0x30(%rbp)
  je     L33
  cmpq   $0x0,-0x38(%rbp)
  jne    L62
L33:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    D56(%rip),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  jmp    L93
L62:
  mov    -0x30(%rbp),%rax
  or     -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  shr    %rax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  test   %rax,%rax
  je     L6
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  divq   -0x38(%rbp)
  cmp    %rax,-0x30(%rbp)
  jbe    L6
  mov    $0x1,%eax
  jmp    L105
L6:
  mov    $0x0,%eax
L105:
  mov    %eax,%edi
  call   <__predict_false@plt>
  test   %rax,%rax
  je     L54
  mov    D56(%rip),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  jmp    L93
L54:
  mov    -0x30(%rbp),%rax
  imul   -0x38(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__predict_false@plt>
  test   %rax,%rax
  je     L59
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L95
L59:
  movl   $0x0,-0x20(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L95:
  mov    D56(%rip),%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%eax
L93:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L107
  call   <__stack_chk_fail@plt>
L107:
  leave
  ret
```

assistant: ```c
int reallocarr(void *ptr, size_t number, size_t size) {
  int saved_errno, result;
  void *optr;
  void *nptr;
  saved_errno = errno;
  memcpy(&optr, ptr, sizeof(ptr));
  if (number == 0 || size == 0) {
    free(optr);
    nptr = NULL;
    memcpy(ptr, &nptr, sizeof(ptr));
    errno = saved_errno;
    return 0;
  }
  if (__predict_false((number | size) >= (((size_t)1) << (sizeof(size_t) * CHAR_BIT / 2)) && number > SIZE_MAX / size)) {
    errno = saved_errno;
    return EOVERFLOW;
  }
  nptr = realloc(optr, number * size);
  if (__predict_false(nptr == NULL)) {
    result = errno;
  } else {
    result = 0;
    memcpy(ptr, &nptr, sizeof(ptr));
  }
  errno = saved_errno;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reallocarr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    (%rax),%r13d
  lea    0x8(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  test   %rbx,%rbx
  je     L89
  test   %rbp,%rbp
  je     L89
  mov    %rbx,%rax
  or     %rbp,%rax
  mov    D22(%rip),%rdx
  movslq (%rdx),%rcx
  shl    $0x3,%rcx
  shr    %rcx
  shr    %cl,%rax
  mov    $0x0,%edi
  test   %rax,%rax
  je     L78
  mov    D62(%rip),%rax
  mov    (%rax),%rax
  mov    $0x0,%edx
  div    %rbp
  cmp    %rbx,%rax
  setb   %dil
  movzbl %dil,%edi
L78:
  call   <__predict_false@plt>
  test   %rax,%rax
  je     L88
  mov    D4(%rip),%rax
  mov    %r13d,(%rax)
  mov    D58(%rip),%rax
  mov    (%rax),%eax
L1:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L89:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rsi
  mov    $0x8,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    D4(%rip),%rax
  mov    %r13d,(%rax)
  mov    $0x0,%eax
  jmp    L1
L88:
  imul   %rbp,%rbx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <realloc@plt>
  mov    %rax,0x10(%rsp)
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <__predict_false@plt>
  test   %rax,%rax
  je     L22
  mov    D4(%rip),%rax
  mov    (%rax),%eax
L10:
  mov    D4(%rip),%rdx
  mov    %r13d,(%rdx)
  jmp    L1
L22:
  lea    0x10(%rsp),%rsi
  mov    $0x8,%edx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    $0x0,%eax
  jmp    L10
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int reallocarr(void *ptr, size_t number, size_t size) {
  int saved_errno, result;
  void *optr;
  void *nptr;
  saved_errno = errno;
  memcpy(&optr, ptr, sizeof(ptr));
  if (number == 0 || size == 0) {
    free(optr);
    nptr = NULL;
    memcpy(ptr, &nptr, sizeof(ptr));
    errno = saved_errno;
    return 0;
  }
  if (__predict_false((number | size) >= (((size_t)1) << (sizeof(size_t) * CHAR_BIT / 2)) && number > SIZE_MAX / size)) {
    errno = saved_errno;
    return EOVERFLOW;
  }
  nptr = realloc(optr, number * size);
  if (__predict_false(nptr == NULL)) {
    result = errno;
  } else {
    result = 0;
    memcpy(ptr, &nptr, sizeof(ptr));
  }
  errno = saved_errno;
  return result;
}
```