ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<alphaBlendScaledwith>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    $0xff,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  imul   -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  cmpl   $0xff,-0x18(%rbp)
  jle    L7
  movl   $0xff,-0x18(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  imul   -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0xff,-0x14(%rbp)
  jle    L23
  movl   $0xff,-0x14(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  imul   -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0xff,-0x10(%rbp)
  jle    L37
  movl   $0xff,-0x10(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movzbl %al,%eax
  imul   -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0xff,-0x1c(%rbp)
  jle    L34
  movl   $0xff,-0x1c(%rbp)
L34:
  mov    -0x1c(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int alphaBlendScaledwith(int sourceWord, int destinationWord) {
  int a;
  int dstMask;
  int b;
  int g;
  int unAlpha;
  int r;
  int srcMask;
  unAlpha = 255 - (((unsigned)sourceWord) >> 24);
  dstMask = destinationWord;
  srcMask = sourceWord;
  b = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (b > 255) {
    b = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  g = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (g > 255) {
    g = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  r = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (r > 255) {
    r = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  a = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (a > 255) {
    a = 255;
  }
  return (((((a << 8) + r) << 8) + g) << 8) + b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alphaBlendScaledwith>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ecx
  shr    $0x18,%edi
  mov    $0xff,%esi
  sub    %edi,%esi
  mov    %ecx,%eax
  shr    $0x10,%eax
  movzbl %al,%eax
  imul   %esi,%eax
  shr    $0x8,%eax
  mov    %ebx,%edx
  shr    $0x10,%edx
  movzbl %dl,%edx
  add    %edx,%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %ecx,%edx
  shr    $0x18,%edx
  imul   %esi,%edx
  shr    $0x8,%edx
  add    %edi,%edx
  mov    $0xff,%edi
  cmp    %edi,%edx
  cmovg  %edi,%edx
  shl    $0x8,%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl %ch,%edx
  imul   %esi,%edx
  shr    $0x8,%edx
  movzbl %bh,%edi
  add    %edi,%edx
  mov    $0xff,%edi
  cmp    %edi,%edx
  cmovg  %edi,%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl %cl,%edx
  imul   %esi,%edx
  shr    $0x8,%edx
  movzbl %bl,%ebx
  add    %ebx,%edx
  mov    $0xff,%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    %edx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int alphaBlendScaledwith(int sourceWord, int destinationWord) {
  int a;
  int dstMask;
  int b;
  int g;
  int unAlpha;
  int r;
  int srcMask;
  unAlpha = 255 - (((unsigned)sourceWord) >> 24);
  dstMask = destinationWord;
  srcMask = sourceWord;
  b = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (b > 255) {
    b = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  g = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (g > 255) {
    g = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  r = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (r > 255) {
    r = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  a = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (a > 255) {
    a = 255;
  }
  return (((((a << 8) + r) << 8) + g) << 8) + b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<alphaBlendScaledwith>:
  endbr64
  mov    %esi,%ecx
  push   %rbx
  mov    $0xff,%esi
  mov    %edi,%ebx
  mov    %ecx,%eax
  shr    $0x18,%edi
  mov    %ebx,%edx
  shr    $0x10,%eax
  sub    %edi,%esi
  shr    $0x10,%edx
  movzbl %al,%eax
  movzbl %dl,%edx
  imul   %esi,%eax
  shr    $0x8,%eax
  add    %edx,%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %ecx,%edx
  shr    $0x18,%edx
  imul   %esi,%edx
  shr    $0x8,%edx
  add    %edi,%edx
  mov    $0xff,%edi
  cmp    %edi,%edx
  cmovg  %edi,%edx
  movzbl %bh,%edi
  movzbl %bl,%ebx
  shl    $0x8,%edx
  add    %edx,%eax
  movzbl %ch,%edx
  imul   %esi,%edx
  shl    $0x8,%eax
  shr    $0x8,%edx
  add    %edi,%edx
  mov    $0xff,%edi
  cmp    %edi,%edx
  cmovg  %edi,%edx
  add    %edx,%eax
  movzbl %cl,%edx
  mov    $0xff,%ecx
  imul   %esi,%edx
  shl    $0x8,%eax
  shr    $0x8,%edx
  add    %ebx,%edx
  pop    %rbx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int alphaBlendScaledwith(int sourceWord, int destinationWord) {
  int a;
  int dstMask;
  int b;
  int g;
  int unAlpha;
  int r;
  int srcMask;
  unAlpha = 255 - (((unsigned)sourceWord) >> 24);
  dstMask = destinationWord;
  srcMask = sourceWord;
  b = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (b > 255) {
    b = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  g = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (g > 255) {
    g = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  r = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (r > 255) {
    r = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  a = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (a > 255) {
    a = 255;
  }
  return (((((a << 8) + r) << 8) + g) << 8) + b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<alphaBlendScaledwith>:
  endbr64
  mov    %esi,%ecx
  push   %rbx
  mov    $0xff,%esi
  mov    %edi,%ebx
  mov    %ecx,%eax
  shr    $0x18,%edi
  mov    %ebx,%edx
  shr    $0x10,%eax
  sub    %edi,%esi
  shr    $0x10,%edx
  movzbl %al,%eax
  movzbl %dl,%edx
  imul   %esi,%eax
  shr    $0x8,%eax
  add    %edx,%eax
  mov    $0xff,%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  mov    %ecx,%edx
  shr    $0x18,%edx
  imul   %esi,%edx
  shr    $0x8,%edx
  add    %edi,%edx
  mov    $0xff,%edi
  cmp    %edi,%edx
  cmovg  %edi,%edx
  movzbl %bh,%edi
  movzbl %bl,%ebx
  shl    $0x8,%edx
  add    %edx,%eax
  movzbl %ch,%edx
  imul   %esi,%edx
  shl    $0x8,%eax
  shr    $0x8,%edx
  add    %edi,%edx
  mov    $0xff,%edi
  cmp    %edi,%edx
  cmovg  %edi,%edx
  add    %edx,%eax
  movzbl %cl,%edx
  mov    $0xff,%ecx
  imul   %esi,%edx
  shl    $0x8,%eax
  shr    $0x8,%edx
  add    %ebx,%edx
  pop    %rbx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
int alphaBlendScaledwith(int sourceWord, int destinationWord) {
  int a;
  int dstMask;
  int b;
  int g;
  int unAlpha;
  int r;
  int srcMask;
  unAlpha = 255 - (((unsigned)sourceWord) >> 24);
  dstMask = destinationWord;
  srcMask = sourceWord;
  b = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (b > 255) {
    b = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  g = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (g > 255) {
    g = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  r = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (r > 255) {
    r = 255;
  }
  dstMask = ((unsigned)dstMask) >> 8;
  srcMask = ((unsigned)srcMask) >> 8;
  a = (((unsigned)((dstMask & 255) * unAlpha)) >> 8) + (srcMask & 255);
  if (a > 255) {
    a = 255;
  }
  return (((((a << 8) + r) << 8) + g) << 8) + b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stink_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x7573207369207349,%rax
  movabs $0x74206465736f7070,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x206c6c656d73206f,%rax
  movabs $0x7961772074616874,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x3f,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  jmp    L20
L2:
  mov    -0x38(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L20:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void stink_2(void) {
  char string[] = "Is is supposed to smell that way?";
  char *s;
  s = string;
  while (*s) {
    putchar(*s++);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<stink_2>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x7573207369207349,%rax
  movabs $0x74206465736f7070,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movabs $0x206c6c656d73206f,%rax
  movabs $0x7961772074616874,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movw   $0x3f,0x20(%rsp)
  mov    $0x49,%edi
  mov    %rsp,%rbx
L1:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x30,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stink_2(void) {
  char string[] = "Is is supposed to smell that way?";
  char *s;
  s = string;
  while (*s) {
    putchar(*s++);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<stink_2>:
  endbr64
  push   %rbx
  mov    $0x49,%edi
  sub    $0x30,%rsp
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x3f,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  movdqa D5(%rip),%xmm0
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L3:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: byte[16]
name: parse_data
arguments: tag: D5
type_guessed: byte[16]

tool: {"D17": [0x49,0x73,0x20,0x69,0x73,0x20,0x73,0x75,0x70,0x70,0x6f,0x73,0x65,0x64,0x20,0x74]}

tool: {"D5": [0x6f,0x20,0x73,0x6d,0x65,0x6c,0x6c,0x20,0x74,0x68,0x61,0x74,0x20,0x77,0x61,0x79]}

assistant: ```c
void stink_2(void) {
  char string[] = "Is is supposed to smell that way?";
  char *s;
  s = string;
  while (*s) {
    putchar(*s++);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<stink_2>:
  endbr64
  push   %rbx
  mov    $0x49,%edi
  sub    $0x30,%rsp
  movdqa D18(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x3f,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  movdqa D0(%rip),%xmm0
  mov    %ax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L0:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L0
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x30,%rsp
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
datatype: byte[16]
name: unpack_data
arguments: label: D0
datatype: byte[16]

tool: {"D18": [0x49,0x73,0x20,0x69,0x73,0x20,0x73,0x75,0x70,0x70,0x6f,0x73,0x65,0x64,0x20,0x74]}

tool: {"D0": [0x6f,0x20,0x73,0x6d,0x65,0x6c,0x6c,0x20,0x74,0x68,0x61,0x74,0x20,0x77,0x61,0x79]}

assistant: ```c
void stink_2(void) {
  char string[] = "Is is supposed to smell that way?";
  char *s;
  s = string;
  while (*s) {
    putchar(*s++);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<doubles_dot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L0
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L13
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double doubles_dot(const double *a, const double *b, int len) {
  double acc = 0;
  for (int i = 0; i < len; i++)
    acc += a[i] * b[i];
  return acc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<doubles_dot>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L10:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L10
L11:
  movapd %xmm1,%xmm0
  ret
L9:
  pxor   %xmm1,%xmm1
  jmp    L11
```

assistant: ```c
double doubles_dot(const double *a, const double *b, int len) {
  double acc = 0;
  for (int i = 0; i < len; i++)
    acc += a[i] * b[i];
  return acc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<doubles_dot>:
  endbr64
  test   %edx,%edx
  jle    L1
  movslq %edx,%rdx
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopl   0x0(%rax)
L6:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L6
  movapd %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L1:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double doubles_dot(const double *a, const double *b, int len) {
  double acc = 0;
  for (int i = 0; i < len; i++)
    acc += a[i] * b[i];
  return acc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<doubles_dot>:
  endbr64
  test   %edx,%edx
  jle    L20
  cmp    $0x1,%edx
  je     L8
  mov    %edx,%ecx
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shr    %ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax,%rax,1)
L19:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm3
  add    $0x10,%rax
  mulpd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L19
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L4
L18:
  cltq
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L4:
  ret
  nopl   0x0(%rax)
L20:
  pxor   %xmm0,%xmm0
  ret
L8:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L18
```

assistant: ```c
double doubles_dot(const double *a, const double *b, int len) {
  double acc = 0;
  for (int i = 0; i < len; i++)
    acc += a[i] * b[i];
  return acc;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<io_fileexists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L25
  mov    -0xc(%rbp),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L23
  mov    $0x0,%eax
  jmp    L16
L23:
  mov    $0x1,%eax
  jmp    L16
L25:
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int io_fileexists(const char *path) {
  struct stat buf;
  if (stat(path, &buf) == 0) {
    if (buf.st_mode & S_IFDIR)
      return 0;
    else
      return 1;
  } else {
    return 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<io_fileexists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
  mov    D1(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  sete   %al
  movzbl %al,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int io_fileexists(const char *path) {
  struct stat buf;
  if (stat(path, &buf) == 0) {
    if (buf.st_mode & S_IFDIR)
      return 0;
    else
      return 1;
  } else {
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<io_fileexists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L17
  mov    D6(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  sete   %al
  movzbl %al,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int io_fileexists(const char *path) {
  struct stat buf;
  if (stat(path, &buf) == 0) {
    if (buf.st_mode & S_IFDIR)
      return 0;
    else
      return 1;
  } else {
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<io_fileexists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L14
  mov    D3(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  sete   %al
  movzbl %al,%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int io_fileexists(const char *path) {
  struct stat buf;
  if (stat(path, &buf) == 0) {
    if (buf.st_mode & S_IFDIR)
      return 0;
    else
      return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<do_socket>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
L2:
  lea    -0x14(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <poll@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    -0xc(%rbp),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L7
  mov    -0xc(%rbp),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L2
L7:
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <sigio@plt>
  jmp    L2
```

assistant: ```c
int do_socket(int sock) {
  struct pollfd plist;
  plist.fd = sock;
  plist.events = POLLIN | POLLPRI;
  while (1) {
    if (poll(&plist, 1, -1) != -1) {
      if ((plist.revents & POLLIN) == POLLIN || (plist.revents & POLLPRI) == POLLPRI) {
        sigio(sock);
      }
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<do_socket>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    D14(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,0x10(%rsp)
  lea    0xc(%rsp),%rbx
  jmp    L36
L46:
  mov    %ebp,%edi
  call   <sigio@plt>
L36:
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <poll@plt>
  cmp    $0xffffffff,%eax
  je     L36
  mov    0x14(%rsp),%eax
  mov    D9(%rip),%rdx
  mov    (%rdx),%edx
  mov    %eax,%ecx
  and    %edx,%ecx
  cmp    %ecx,%edx
  je     L46
  mov    D14(%rip),%rdx
  mov    (%rdx),%edx
  and    %edx,%eax
  cmp    %eax,%edx
  jne    L36
  jmp    L46
```

assistant: ```c
int do_socket(int sock) {
  struct pollfd plist;
  plist.fd = sock;
  plist.events = POLLIN | POLLPRI;
  while (1) {
    if (poll(&plist, 1, -1) != -1) {
      if ((plist.revents & POLLIN) == POLLIN || (plist.revents & POLLPRI) == POLLPRI) {
        sigio(sock);
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<do_socket>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D19(%rip),%rbp
  mov    D3(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbx
  mov    0x0(%rbp),%eax
  or     (%r12),%eax
  mov    %eax,0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <poll@plt>
  cmp    $0xffffffff,%eax
  je     L5
  mov    0x14(%rsp),%eax
  mov    0x0(%rbp),%edx
  mov    %eax,%ecx
  and    %edx,%ecx
  cmp    %ecx,%edx
  je     L18
  mov    (%r12),%edx
  and    %edx,%eax
  cmp    %eax,%edx
  jne    L5
L18:
  mov    %r13d,%edi
  call   <sigio@plt>
  jmp    L5
```

assistant: ```c
int do_socket(int sock) {
  struct pollfd plist;
  plist.fd = sock;
  plist.events = POLLIN | POLLPRI;
  while (1) {
    if (poll(&plist, 1, -1) != -1) {
      if ((plist.revents & POLLIN) == POLLIN || (plist.revents & POLLPRI) == POLLPRI) {
        sigio(sock);
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_socket>:
  endbr64
  push   %r13
  movd   %edi,%xmm0
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    D12(%rip),%rbp
  mov    D9(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbx
  mov    0x0(%rbp),%eax
  or     (%r12),%eax
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x8(%rsp)
  nopl   (%rax)
L12:
  mov    $0xffffffff,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <poll@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    0x10(%rsp),%eax
  mov    0x0(%rbp),%edx
  mov    %eax,%ecx
  and    %edx,%ecx
  cmp    %ecx,%edx
  je     L13
  mov    (%r12),%edx
  and    %edx,%eax
  cmp    %eax,%edx
  jne    L12
L13:
  mov    %r13d,%edi
  call   <sigio@plt>
  jmp    L12
```

assistant: ```c
int do_socket(int sock) {
  struct pollfd plist;
  plist.fd = sock;
  plist.events = POLLIN | POLLPRI;
  while (1) {
    if (poll(&plist, 1, -1) != -1) {
      if ((plist.revents & POLLIN) == POLLIN || (plist.revents & POLLPRI) == POLLPRI) {
        sigio(sock);
      }
    }
  }
  return 0;
}
```