ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<gleIntLoad_Version_3_3>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <gleIntClear@plt>
  xor    %eax,%eax
  call   <gleIntLoadCore_1_1_Version_3_1@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gleIntLoadCore_1_2_Version_3_1@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L2
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L2:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <gleIntLoadCore_1_3_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_4_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_5_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_1_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_3_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int gleIntLoad_Version_3_3() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_3_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gleIntLoad_Version_3_3>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <gleIntClear@plt>
  xor    %eax,%eax
  call   <gleIntLoadCore_1_1_Version_3_1@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <gleIntLoadCore_1_2_Version_3_1@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  je     L7
  xor    %r12d,%r12d
  test   %ebx,%ebx
  setne  %r12b
L7:
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <gleIntLoadCore_1_3_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_4_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_1_5_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_2_1_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_0_Version_3_1@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_1_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_2_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  xor    %eax,%eax
  call   <gleIntLoadCore_3_3_Base@plt>
  test   %eax,%eax
  cmove  %ebx,%r12d
  add    $0x8,%rsp
  pop    %rbx
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int gleIntLoad_Version_3_3() {
  int bIsLoaded = 1;
  gleIntClear();
  if (!gleIntLoadCore_1_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_2_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_3_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_4_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_1_5_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_2_1_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_0_Version_3_1())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_1_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_2_Base())
    bIsLoaded = 0;
  if (!gleIntLoadCore_3_3_Base())
    bIsLoaded = 0;
  return bIsLoaded;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: dir

assistant: ```c
int main(int argc, char *argv[]) {
  system("dir");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <system@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: dir

assistant: ```c
int main(int argc, char *argv[]) {
  system("dir");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: dir

assistant: ```c
int main(int argc, char *argv[]) {
  system("dir");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <system@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_guessed: string

tool: D7: dir

assistant: ```c
int main(int argc, char *argv[]) {
  system("dir");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8:  %d

assistant: ```c
void print(int nums[], int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf(" %d", nums[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D0(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D0:  %d

assistant: ```c
void print(int nums[], int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf(" %d", nums[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L4:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_guessed: string

tool: D6:  %d

assistant: ```c
void print(int nums[], int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf(" %d", nums[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print>:
  endbr64
  test   %esi,%esi
  jle    L11
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9:  %d

assistant: ```c
void print(int nums[], int length) {
  int i;
  for (i = 0; i < length; i++) {
    printf(" %d", nums[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D54(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x10(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%ecx
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D53
data_type: string
name: unpack_data
arguments: data_tag: D67
data_type: string
name: unpack_data
arguments: data_tag: D24
data_type: string
name: unpack_data
arguments: data_tag: D54
data_type: f64
name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D28
data_type: string

tool: D53: enter the length of base in m :

tool: D67: %d

tool: D24: enter the length of height in m :

tool: D54: 0.5

tool: D15: the area of the triangle with base %d
 and height %d is %d meter square


tool: D28: done

assistant: ```c
int main(void) {
  int base, height, area;
  printf("enter the length of base in m :");
  scanf("%d", &base);
  printf("enter the length of height in m :");
  scanf("%d", &height);
  area = 0.5 * base * height;
  printf("the area of the triangle with base %d\n and height %d is %d meter square\n", base, height, area);
  printf("done\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D59(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  mulsd  D6(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  lea    D58(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D57
type: string
name: disassemble_data
arguments: data_label: D59
type: string
name: disassemble_data
arguments: data_label: D52
type: string
name: disassemble_data
arguments: data_label: D6
type: f64
name: disassemble_data
arguments: data_label: D58
type: string
name: disassemble_data
arguments: data_label: D15
type: string

tool: D57: enter the length of base in m :

tool: D59: %d

tool: D52: enter the length of height in m :

tool: D6: 0.5

tool: D58: the area of the triangle with base %d
 and height %d is %d meter square


tool: D15: done

assistant: ```c
int main(void) {
  int base, height, area;
  printf("enter the length of base in m :");
  scanf("%d", &base);
  printf("enter the length of height in m :");
  scanf("%d", &height);
  area = 0.5 * base * height;
  printf("the area of the triangle with base %d\n and height %d is %d meter square\n", base, height, area);
  printf("done\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D35(%rip),%rdi
  lea    D34(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D51(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  cvtsi2sd %esi,%xmm0
  mulsd  D46(%rip),%xmm0
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D35
datatype: string
name: parse_data
arguments: label: D34
datatype: string
name: parse_data
arguments: label: D51
datatype: string
name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D46
datatype: f64
name: parse_data
arguments: label: D31
datatype: string

tool: D35: enter the length of base in m :

tool: D34: %d

tool: D51: enter the length of height in m :

tool: D11: the area of the triangle with base %d
 and height %d is %d meter square


tool: D46: 0.5

tool: D31: done

assistant: ```c
int main(void) {
  int base, height, area;
  printf("enter the length of base in m :");
  scanf("%d", &base);
  printf("enter the length of height in m :");
  scanf("%d", &height);
  area = 0.5 * base * height;
  printf("the area of the triangle with base %d\n and height %d is %d meter square\n", base, height, area);
  printf("done\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D31(%rip),%rdi
  lea    D4(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  cvtsi2sd %esi,%xmm0
  mulsd  D33(%rip),%xmm0
  cvtsi2sd %edx,%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D31
data_type: string
name: parse_data
arguments: label: D4
data_type: string
name: parse_data
arguments: label: D22
data_type: string
name: parse_data
arguments: label: D39
data_type: string
name: parse_data
arguments: label: D33
data_type: f64
name: parse_data
arguments: label: D14
data_type: string

tool: D31: enter the length of base in m :

tool: D4: %d

tool: D22: enter the length of height in m :

tool: D39: the area of the triangle with base %d
 and height %d is %d meter square


tool: D33: 0.5

tool: D14: done

assistant: ```c
int main(void) {
  int base, height, area;
  printf("enter the length of base in m :");
  scanf("%d", &base);
  printf("enter the length of height in m :");
  scanf("%d", &height);
  area = 0.5 * base * height;
  printf("the area of the triangle with base %d\n and height %d is %d meter square\n", base, height, area);
  printf("done\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L3:
  nop
L35:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x64,-0x8(%rbp)
  jle    L6
  nop
L2:
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L6:
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x9,-0x8(%rbp)
  jle    L3
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    res++;
    if (i > 100) {
    L1:
      i = 0;
      goto L2;
    }
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    res++;
    if (i > 100) {
    L1:
      i = 0;
      goto L2;
    }
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    res++;
    if (i > 100) {
    L1:
      i = 0;
      goto L2;
    }
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    $0xa,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int res = 0;
  goto L1;
  for (i = 0; i < 10; i++) {
  L2:
    res++;
    if (i > 100) {
    L1:
      i = 0;
      goto L2;
    }
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_and_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  sar    $0x5,%eax
  cltq
  shl    $0x2,%rax
  add    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <local_irq_save@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  and    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <local_irq_restore@plt>
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  retval = (mask & *a) != 0;
  *a &= ~mask;
  local_irq_restore(flags);
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_and_clear_bit>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ecx
  mov    %edi,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rsi,%rax,4),%rbp
  mov    $0x1,%ebx
  shl    %cl,%ebx
  mov    $0x0,%r12d
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <local_irq_save@plt>
  mov    0x0(%rbp),%r13d
  mov    0x0(%rbp),%edx
  mov    %ebx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,0x0(%rbp)
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <local_irq_restore@plt>
  test   %r13d,%ebx
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  retval = (mask & *a) != 0;
  *a &= ~mask;
  local_irq_restore(flags);
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_and_clear_bit>:
  endbr64
  push   %r13
  mov    %edi,%eax
  mov    %edi,%ecx
  push   %r12
  sar    $0x5,%eax
  xor    %r12d,%r12d
  push   %rbp
  cltq
  mov    %r12,%rdi
  push   %rbx
  mov    $0x1,%ebx
  lea    (%rsi,%rax,4),%rbp
  xor    %eax,%eax
  shl    %cl,%ebx
  sub    $0x8,%rsp
  call   <local_irq_save@plt>
  mov    0x0(%rbp),%r13d
  mov    %ebx,%eax
  mov    0x0(%rbp),%edx
  not    %eax
  mov    %r12,%rdi
  and    %edx,%eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <local_irq_restore@plt>
  xor    %eax,%eax
  test   %r13d,%ebx
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  retval = (mask & *a) != 0;
  *a &= ~mask;
  local_irq_restore(flags);
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_and_clear_bit>:
  endbr64
  push   %r13
  mov    %edi,%eax
  mov    %edi,%ecx
  push   %r12
  sar    $0x5,%eax
  xor    %r12d,%r12d
  push   %rbp
  cltq
  mov    %r12,%rdi
  push   %rbx
  mov    $0x1,%ebx
  lea    (%rsi,%rax,4),%rbp
  xor    %eax,%eax
  shl    %cl,%ebx
  sub    $0x8,%rsp
  call   <local_irq_save@plt>
  mov    0x0(%rbp),%r13d
  mov    %ebx,%eax
  mov    0x0(%rbp),%edx
  not    %eax
  mov    %r12,%rdi
  and    %edx,%eax
  mov    %eax,0x0(%rbp)
  xor    %eax,%eax
  call   <local_irq_restore@plt>
  xor    %eax,%eax
  test   %r13d,%ebx
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile void *addr) {
  int mask, retval;
  volatile unsigned int *a = addr;
  unsigned long flags;
  a += nr >> 5;
  mask = 1 << (nr & 0x1f);
  local_irq_save(flags);
  retval = (mask & *a) != 0;
  *a &= ~mask;
  local_irq_restore(flags);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tskip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  jmp    L20
L22:
  add    $0x1,%rax
L20:
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L8
  movzbl (%rax),%edx
  cmp    $0x3a,%dl
  jne    L22
L8:
  movzbl (%rax),%edx
  cmp    $0x3a,%dl
  jne    L30
  add    $0x1,%rax
L30:
  pop    %rbp
  ret
```

assistant: ```c
char *tskip(bp)
register char *bp;
{
  while (*bp && *bp != ':')
    bp++;
  if (*bp == ':')
    bp++;
  return (bp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tskip>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L20
  cmp    $0x3a,%dl
  je     L20
L35:
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L20
  cmp    $0x3a,%dl
  jne    L35
L20:
  cmp    $0x3a,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  ret
```

assistant: ```c
char *tskip(bp)
register char *bp;
{
  while (*bp && *bp != ':')
    bp++;
  if (*bp == ':')
    bp++;
  return (bp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tskip>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L9
  jmp    L36
L6:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L36
L9:
  cmp    $0x3a,%dl
  jne    L6
L36:
  cmp    $0x3a,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  ret
```

assistant: ```c
char *tskip(bp)
register char *bp;
{
  while (*bp && *bp != ':')
    bp++;
  if (*bp == ':')
    bp++;
  return (bp);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tskip>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L31
  jmp    L3
L22:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L3
L31:
  cmp    $0x3a,%dl
  jne    L22
L3:
  cmp    $0x3a,%dl
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  ret
```

assistant: ```c
char *tskip(bp)
register char *bp;
{
  while (*bp && *bp != ':')
    bp++;
  if (*bp == ':')
    bp++;
  return (bp);
}
```