ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculoButterflyLoopBloco>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdx,0x18(%rsp)
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,0x10(%rsp)
  test   %r8,%r8
  je     L5
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rcx,%r13
  mov    %r8,%r15
  lea    (%rsi,%rdx,1),%r12
  mov    $0x1,%r14d
L16:
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    0x18(%rsp),%rdx
  mov    %r13,%rsi
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cvtss2sd (%rbx,%r12,4),%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rbx,%r12,4),%xmm0
  movsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm2,%xmm1
  movsd  0x10(%rsp),%xmm5
  movapd %xmm5,%xmm3
  mulsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm1
  cvtsd2ss %xmm1,%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm5,%xmm2
  addsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  (%rbx,%rbp,4),%xmm2
  subss  %xmm1,%xmm2
  movss  %xmm2,(%rbx,%r12,4)
  movss  0x4(%rbx,%rbp,4),%xmm2
  subss  %xmm0,%xmm2
  movss  %xmm2,0x4(%rbx,%r12,4)
  addss  (%rbx,%rbp,4),%xmm1
  movss  %xmm1,(%rbx,%rbp,4)
  addss  0x4(%rbx,%rbp,4),%xmm0
  movss  %xmm0,0x4(%rbx,%rbp,4)
  add    $0x1,%r14
  add    %r13,%rbp
  add    %r13,%r12
  cmp    %r14,%r15
  jae    L16
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1:           >>> FOR 2 -> wi:%f wr:%f istep:%lu mmax:%lu i:%lu j:%lu


assistant: ```c
void calculoButterflyLoopBloco(float data[], unsigned long m, unsigned long mmax, unsigned long istep, double wr, double wi, unsigned long tamBloco) {
  float tempr, tempi;
  unsigned long j, i, bloco;
  bloco = 1;
  for (i = m; bloco <= tamBloco; i += istep) {
    j = i + mmax;
    printf("          >>> FOR 2 -> wi:%f wr:%f istep:%lu mmax:%lu i:%lu j:%lu\n", wi, wr, istep, mmax, i, j);
    tempr = wr * data[j] - wi * data[j + 1];
    tempi = wr * data[j + 1] + wi * data[j];
    data[j] = data[i] - tempr;
    data[j + 1] = data[i + 1] - tempi;
    data[i] += tempr;
    data[i + 1] += tempi;
    bloco++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculoButterflyLoopBloco>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x18(%rsp)
  test   %r8,%r8
  je     L0
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r13
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm5
  lea    (%rsi,%rdx,1),%r15
  mov    $0x1,%ebp
  nopl   (%rax)
L4:
  movapd %xmm4,%xmm1
  movapd %xmm5,%xmm0
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  movsd  %xmm4,0x10(%rsp)
  add    $0x1,%rbp
  lea    D4(%rip),%rdi
  movsd  %xmm5,0x8(%rsp)
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm5
  pxor   %xmm3,%xmm3
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%r15,4),%xmm3
  movapd %xmm3,%xmm2
  cvtss2sd 0x4(%rbx,%r15,4),%xmm0
  mulsd  %xmm4,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm5,%xmm1
  mulsd  %xmm5,%xmm3
  mulsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm2
  movss  (%rbx,%r14,4),%xmm1
  addsd  %xmm3,%xmm0
  cvtsd2ss %xmm2,%xmm2
  subss  %xmm2,%xmm1
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm1,(%rbx,%r15,4)
  movss  0x4(%rbx,%r14,4),%xmm3
  subss  %xmm0,%xmm3
  movss  %xmm3,0x4(%rbx,%r15,4)
  addss  (%rbx,%r14,4),%xmm2
  add    %r13,%r15
  addss  0x4(%rbx,%r14,4),%xmm0
  movss  %xmm2,(%rbx,%r14,4)
  movss  %xmm0,0x4(%rbx,%r14,4)
  add    %r13,%r14
  cmp    %rbp,0x18(%rsp)
  jae    L4
L0:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D4:           >>> FOR 2 -> wi:%f wr:%f istep:%lu mmax:%lu i:%lu j:%lu


assistant: ```c
void calculoButterflyLoopBloco(float data[], unsigned long m, unsigned long mmax, unsigned long istep, double wr, double wi, unsigned long tamBloco) {
  float tempr, tempi;
  unsigned long j, i, bloco;
  bloco = 1;
  for (i = m; bloco <= tamBloco; i += istep) {
    j = i + mmax;
    printf("          >>> FOR 2 -> wi:%f wr:%f istep:%lu mmax:%lu i:%lu j:%lu\n", wi, wr, istep, mmax, i, j);
    tempr = wr * data[j] - wi * data[j + 1];
    tempi = wr * data[j + 1] + wi * data[j];
    data[j] = data[i] - tempr;
    data[j + 1] = data[i + 1] - tempi;
    data[i] += tempr;
    data[i + 1] += tempi;
    bloco++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calculoButterflyLoopBloco>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %r8,0x18(%rsp)
  test   %r8,%r8
  je     L7
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%r12
  mov    %rcx,%r13
  movapd %xmm0,%xmm4
  movapd %xmm1,%xmm5
  lea    (%rsi,%rdx,1),%r15
  mov    $0x1,%ebp
  nopl   (%rax)
L18:
  movapd %xmm4,%xmm1
  movapd %xmm5,%xmm0
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  movsd  %xmm4,0x10(%rsp)
  add    $0x1,%rbp
  lea    D0(%rip),%rdi
  movsd  %xmm5,0x8(%rsp)
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm4
  movsd  0x8(%rsp),%xmm5
  pxor   %xmm3,%xmm3
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx,%r15,4),%xmm3
  movapd %xmm3,%xmm2
  cvtss2sd 0x4(%rbx,%r15,4),%xmm0
  mulsd  %xmm4,%xmm2
  movapd %xmm0,%xmm1
  mulsd  %xmm5,%xmm1
  mulsd  %xmm5,%xmm3
  mulsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm2
  movss  (%rbx,%r14,4),%xmm1
  addsd  %xmm3,%xmm0
  cvtsd2ss %xmm2,%xmm2
  subss  %xmm2,%xmm1
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm1,(%rbx,%r15,4)
  movss  0x4(%rbx,%r14,4),%xmm3
  subss  %xmm0,%xmm3
  movss  %xmm3,0x4(%rbx,%r15,4)
  addss  (%rbx,%r14,4),%xmm2
  add    %r13,%r15
  addss  0x4(%rbx,%r14,4),%xmm0
  movss  %xmm2,(%rbx,%r14,4)
  movss  %xmm0,0x4(%rbx,%r14,4)
  add    %r13,%r14
  cmp    %rbp,0x18(%rsp)
  jae    L18
L7:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0:           >>> FOR 2 -> wi:%f wr:%f istep:%lu mmax:%lu i:%lu j:%lu


assistant: ```c
void calculoButterflyLoopBloco(float data[], unsigned long m, unsigned long mmax, unsigned long istep, double wr, double wi, unsigned long tamBloco) {
  float tempr, tempi;
  unsigned long j, i, bloco;
  bloco = 1;
  for (i = m; bloco <= tamBloco; i += istep) {
    j = i + mmax;
    printf("          >>> FOR 2 -> wi:%f wr:%f istep:%lu mmax:%lu i:%lu j:%lu\n", wi, wr, istep, mmax, i, j);
    tempr = wr * data[j] - wi * data[j + 1];
    tempi = wr * data[j + 1] + wi * data[j];
    data[j] = data[i] - tempr;
    data[j + 1] = data[i + 1] - tempi;
    data[i] += tempr;
    data[i + 1] += tempi;
    bloco++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<miditones_strlcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L63
  jmp    L68
L6:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L59
L68:
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  jmp    L63
L59:
  nop
L63:
  cmpq   $0x0,-0x8(%rbp)
  jne    L55
  cmpq   $0x0,-0x38(%rbp)
  je     L49
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L49:
  nop
L18:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L18
L55:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t miditones_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<miditones_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L43
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
L30:
  cmp    %rcx,%rdi
  je     L45
  add    $0x1,%rax
  add    $0x1,%rdi
  movzbl -0x1(%rax),%edx
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  jne    L30
  jmp    L39
L43:
  mov    %rsi,%rax
L38:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L38
L39:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
L45:
  movb   $0x0,(%rdi)
  jmp    L38
```

assistant: ```c
size_t miditones_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<miditones_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L50
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L23:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L17
L9:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L23
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
L17:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L3
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t miditones_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<miditones_strlcpy>:
  endbr64
  test   %rdx,%rdx
  je     L54
  lea    -0x1(%rdi,%rdx,1),%rcx
  mov    %rsi,%rax
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L43:
  movzbl -0x1(%rax),%edx
  add    $0x1,%rdi
  mov    %dl,-0x1(%rdi)
  test   %dl,%dl
  je     L27
L34:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rcx,%rdi
  jne    L43
  mov    %rdx,%rax
  movb   $0x0,(%rdi)
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L23
L27:
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  mov    %rsi,%rax
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L23
  sub    %rsi,%rax
  sub    $0x1,%rax
  ret
```

assistant: ```c
size_t miditones_strlcpy(char *dst, const char *src, size_t siz) {
  char *d = dst;
  const char *s = src;
  size_t n = siz;
  if (n != 0) {
    while (--n != 0) {
      if ((*d++ = *s++) == '\0')
        break;
    }
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pswp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pswp(void *A, void *B) {
  void **a = A, **b = B, *p;
  p = *a, *a = *b, *b = p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<pswp>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void pswp(void *A, void *B) {
  void **a = A, **b = B, *p;
  p = *a, *a = *b, *b = p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pswp>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void pswp(void *A, void *B) {
  void **a = A, **b = B, *p;
  p = *a, *a = *b, *b = p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pswp>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rsi),%rdx
  mov    %rdx,(%rdi)
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void pswp(void *A, void *B) {
  void **a = A, **b = B, *p;
  p = *a, *a = *b, *b = p;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sg_put_unaligned_be64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x20,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <sg_put_unaligned_be32@plt>
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sg_put_unaligned_be32@plt>
  nop
  leave
  ret
```

assistant: ```c
void sg_put_unaligned_be64(uint64_t val, void *p) {
  sg_put_unaligned_be32(val >> 32, p);
  sg_put_unaligned_be32(val, (uint8_t *)p + 4);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sg_put_unaligned_be64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x20,%ecx
  sar    %cl,%edi
  call   <sg_put_unaligned_be32@plt>
  lea    0x4(%rbx),%rsi
  mov    %ebp,%edi
  call   <sg_put_unaligned_be32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sg_put_unaligned_be64(uint64_t val, void *p) {
  sg_put_unaligned_be32(val >> 32, p);
  sg_put_unaligned_be32(val, (uint8_t *)p + 4);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sg_put_unaligned_be64>:
  endbr64
  push   %rbp
  mov    $0x20,%ecx
  mov    %edi,%ebp
  push   %rbx
  sar    %cl,%edi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sg_put_unaligned_be32@plt>
  add    $0x8,%rsp
  lea    0x4(%rbx),%rsi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <sg_put_unaligned_be32@plt>
```

assistant: ```c
void sg_put_unaligned_be64(uint64_t val, void *p) {
  sg_put_unaligned_be32(val >> 32, p);
  sg_put_unaligned_be32(val, (uint8_t *)p + 4);
}
```
user: What is the c source code of the assembly code below:

```asm
<sg_put_unaligned_be64>:
  endbr64
  push   %rbp
  mov    $0x20,%ecx
  mov    %edi,%ebp
  push   %rbx
  sar    %cl,%edi
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sg_put_unaligned_be32@plt>
  add    $0x8,%rsp
  lea    0x4(%rbx),%rsi
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <sg_put_unaligned_be32@plt>
```

assistant: ```c
void sg_put_unaligned_be64(uint64_t val, void *p) {
  sg_put_unaligned_be32(val >> 32, p);
  sg_put_unaligned_be32(val, (uint8_t *)p + 4);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dump_interfaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L33
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L25
  jmp    L35
L25:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <dump_interface@plt>
L35:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <readdir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
L33:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: /sys/class/net

assistant: ```c
int dump_interfaces(void) {
  DIR *d;
  struct dirent *de;
  d = opendir("/sys/class/net");
  if (d == 0)
    return -1;
  while ((de = readdir(d))) {
    if (de->d_name[0] == '.')
      continue;
    dump_interface(de->d_name);
  }
  closedir(d);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_interfaces>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rdi
  call   <opendir@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L34
  mov    $0xffffffff,%eax
  jmp    L18
L49:
  call   <dump_interface@plt>
L34:
  mov    %rbx,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L30
  mov    (%rax),%rdi
  cmpb   $0x2e,(%rdi)
  jne    L49
  jmp    L34
L30:
  mov    %rbx,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
L18:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: /sys/class/net

assistant: ```c
int dump_interfaces(void) {
  DIR *d;
  struct dirent *de;
  d = opendir("/sys/class/net");
  if (d == 0)
    return -1;
  while ((de = readdir(d))) {
    if (de->d_name[0] == '.')
      continue;
    dump_interface(de->d_name);
  }
  closedir(d);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dump_interfaces>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L7
L30:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L24
L6:
  mov    (%rax),%rdi
  cmpb   $0x2e,(%rdi)
  je     L30
  call   <dump_interface@plt>
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L6
L24:
  mov    %rbp,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D3: /sys/class/net

assistant: ```c
int dump_interfaces(void) {
  DIR *d;
  struct dirent *de;
  d = opendir("/sys/class/net");
  if (d == 0)
    return -1;
  while ((de = readdir(d))) {
    if (de->d_name[0] == '.')
      continue;
    dump_interface(de->d_name);
  }
  closedir(d);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dump_interfaces>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  call   <opendir@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L31
L19:
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  je     L27
L37:
  mov    (%rax),%rdi
  cmpb   $0x2e,(%rdi)
  je     L19
  call   <dump_interface@plt>
  mov    %rbp,%rdi
  call   <readdir@plt>
  test   %rax,%rax
  jne    L37
L27:
  mov    %rbp,%rdi
  call   <closedir@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
L31:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: string

tool: D4: /sys/class/net

assistant: ```c
int dump_interfaces(void) {
  DIR *d;
  struct dirent *de;
  d = opendir("/sys/class/net");
  if (d == 0)
    return -1;
  while ((de = readdir(d))) {
    if (de->d_name[0] == '.')
      continue;
    dump_interface(de->d_name);
  }
  closedir(d);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quadro_ausente_lru>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L29:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L26
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x2c(%rbp),%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
  jmp    L7
L26:
  addl   $0x1,-0x4(%rbp)
L20:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L29
  mov    $0x1,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int quadro_ausente_lru(int valor_quadro, int *vetor_quadros, int numero_de_quadros, int *vetor_acesso, int acesso) {
  int cont = 0;
  for (cont = 0; cont < numero_de_quadros; cont++) {
    if (vetor_quadros[cont] == valor_quadro) {
      vetor_acesso[cont] = acesso;
      return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quadro_ausente_lru>:
  endbr64
  test   %edx,%edx
  jle    L4
  mov    %edx,%edx
  shl    $0x2,%rdx
  mov    $0x0,%eax
L14:
  cmp    %edi,(%rsi,%rax,1)
  je     L16
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L14
  mov    $0x1,%eax
  ret
L16:
  mov    %r8d,(%rcx,%rax,1)
  mov    $0x0,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int quadro_ausente_lru(int valor_quadro, int *vetor_quadros, int numero_de_quadros, int *vetor_acesso, int acesso) {
  int cont = 0;
  for (cont = 0; cont < numero_de_quadros; cont++) {
    if (vetor_quadros[cont] == valor_quadro) {
      vetor_acesso[cont] = acesso;
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quadro_ausente_lru>:
  endbr64
  test   %edx,%edx
  jle    L22
  movslq %edx,%rdx
  xor    %eax,%eax
  shl    $0x2,%rdx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L22
L12:
  cmp    %edi,(%rsi,%rax,1)
  jne    L37
  mov    %r8d,(%rcx,%rax,1)
  xor    %eax,%eax
  ret
  nopl   (%rax)
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int quadro_ausente_lru(int valor_quadro, int *vetor_quadros, int numero_de_quadros, int *vetor_acesso, int acesso) {
  int cont = 0;
  for (cont = 0; cont < numero_de_quadros; cont++) {
    if (vetor_quadros[cont] == valor_quadro) {
      vetor_acesso[cont] = acesso;
      return 0;
    }
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<quadro_ausente_lru>:
  endbr64
  test   %edx,%edx
  jle    L33
  movslq %edx,%rdx
  xor    %eax,%eax
  shl    $0x2,%rdx
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x4,%rax
  cmp    %rdx,%rax
  je     L33
L38:
  cmp    %edi,(%rsi,%rax,1)
  jne    L23
  mov    %r8d,(%rcx,%rax,1)
  xor    %eax,%eax
  ret
  nopl   (%rax)
L33:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int quadro_ausente_lru(int valor_quadro, int *vetor_quadros, int numero_de_quadros, int *vetor_acesso, int acesso) {
  int cont = 0;
  for (cont = 0; cont < numero_de_quadros; cont++) {
    if (vetor_quadros[cont] == valor_quadro) {
      vetor_acesso[cont] = acesso;
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_item>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void insert_item(char *item, char **shared_buffer, char *shared_start) {
  int n = strlen(item);
  memcpy(*shared_buffer, item, n);
  *shared_buffer = *shared_buffer + n;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<insert_item>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %r12,%rsi
  mov    0x0(%rbp),%rdi
  call   <memcpy@plt>
  movslq %ebx,%rbx
  add    %rbx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_item(char *item, char **shared_buffer, char *shared_start) {
  int n = strlen(item);
  memcpy(*shared_buffer, item, n);
  *shared_buffer = *shared_buffer + n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_item>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    0x0(%rbp),%rdi
  mov    %r12,%rsi
  movslq %eax,%rbx
  mov    %ebx,%edx
  call   <memcpy@plt>
  add    %rbx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void insert_item(char *item, char **shared_buffer, char *shared_start) {
  int n = strlen(item);
  memcpy(*shared_buffer, item, n);
  *shared_buffer = *shared_buffer + n;
}
```