ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  mov    0x4(%rdi),%r10d
  mov    %rsi,%r9
  add    $0x136ff696,%eax
  test   %r10d,%r10d
  je     L26
  push   %rbx
  mov    %eax,%r8d
  xor    %edx,%edx
L19:
  mov    %r8d,%esi
  mov    %r8d,%ecx
  lea    (%rdx,%rdx,1),%r11d
  shr    $0x10,%esi
  cmp    %eax,%edx
  cmova  %esi,%ecx
  cmova  %r8d,%esi
  movzwl %cx,%ecx
  shl    $0x10,%esi
  or     %esi,%ecx
  cmp    %eax,%edx
  setbe  %dil
  sete   %sil
  mov    %ecx,%r8d
  and    %dil,%sil
  cmovne %r11d,%r8d
  cmp    %eax,%edx
  setne  %bl
  test   %dil,%bl
  je     L22
  mov    %eax,%ecx
L0:
  test   %sil,%sil
  mov    %ecx,%eax
  cmovne %r11d,%eax
  add    $0x2,%edx
  cmp    %r10d,%edx
  jb     L19
  sub    $0x3fecb4f1,%eax
  pop    %rbx
  mov    %eax,(%r9)
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  cmp    %eax,%edx
  cmovbe %eax,%ecx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L26:
  sub    $0x3fecb4f1,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] + state[0UL];
        } else {
          copy11 = *((unsigned short *)(&state[0UL]) + 0);
          *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
          *((unsigned short *)(&state[0UL]) + 1) = copy11;
        }
      } else if (state[0UL] <= local1) {
        state[0UL] += state[local1];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 495116725UL) + 3717606596U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insert_spr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  shl    $0x10,%rax
  and    $0x1f0000,%eax
  or     -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x6,%rax
  and    $0xf800,%eax
  or     %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long insert_spr(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{ return insn | ((value & 0x1f) << 16) | ((value & 0x3e0) << 6); }
```
user: What would the C source look like for the assembly code provided here?

```asm
<insert_spr>:
  endbr64
  mov    %rsi,%rax
  shl    $0x10,%rax
  and    $0x1f0000,%eax
  shl    $0x6,%rsi
  and    $0xf800,%esi
  or     %rsi,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long insert_spr(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{ return insn | ((value & 0x1f) << 16) | ((value & 0x3e0) << 6); }
```
user: What would the C source look like for the assembly code provided here:

```asm
<insert_spr>:
  endbr64
  mov    %rsi,%rax
  shl    $0x6,%rsi
  shl    $0x10,%rax
  and    $0xf800,%esi
  and    $0x1f0000,%eax
  or     %rsi,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long insert_spr(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{ return insn | ((value & 0x1f) << 16) | ((value & 0x3e0) << 6); }
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<insert_spr>:
  endbr64
  mov    %rsi,%rax
  shl    $0x6,%rsi
  shl    $0x10,%rax
  and    $0xf800,%esi
  and    $0x1f0000,%eax
  or     %rsi,%rax
  or     %rdi,%rax
  ret
```

assistant: ```c
unsigned long insert_spr(insn, value, errmsg)
unsigned long insn;
long value;
const char **errmsg;
{ return insn | ((value & 0x1f) << 16) | ((value & 0x3e0) << 6); }
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<natif32VersBig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  je     L7
  mov    -0x4(%rbp),%eax
  jmp    L2
L7:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <barriereNatif32@plt>
L2:
  leave
  ret
```

assistant: ```c
int natif32VersBig(int natif) {
  if (systemeBigEndian()) {
    return natif;
  } else {
    return barriereNatif32(natif);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<natif32VersBig>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  je     L5
L6:
  mov    %ebx,%eax
  pop    %rbx
  ret
L5:
  mov    %ebx,%edi
  call   <barriereNatif32@plt>
  mov    %eax,%ebx
  jmp    L6
```

assistant: ```c
int natif32VersBig(int natif) {
  if (systemeBigEndian()) {
    return natif;
  } else {
    return barriereNatif32(natif);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<natif32VersBig>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  je     L4
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12d,%edi
  pop    %r12
  jmp    1070 <barriereNatif32@plt>
```

assistant: ```c
int natif32VersBig(int natif) {
  if (systemeBigEndian()) {
    return natif;
  } else {
    return barriereNatif32(natif);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<natif32VersBig>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %edi,%r12d
  call   <systemeBigEndian@plt>
  test   %rax,%rax
  je     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %r12d,%edi
  pop    %r12
  jmp    1070 <barriereNatif32@plt>
```

assistant: ```c
int natif32VersBig(int natif) {
  if (systemeBigEndian()) {
    return natif;
  } else {
    return barriereNatif32(natif);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L7
L14:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L22
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fatal@plt>
L22:
  mov    -0x4(%rbp),%eax
  cltq
  sub    %rax,-0x28(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
L7:
  cmpq   $0x0,-0x28(%rbp)
  jne    L14
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: write() failed

assistant: ```c
void write2(int fd, const char *buf, size_t len) {
  while (len > 0) {
    ssize_t count = write(fd, buf, len);
    if (count == -1) {
      fatal("write() failed");
    }
    len -= count;
    buf += count;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<write2>:
  endbr64
  test   %rdx,%rdx
  je     L4
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  lea    D8(%rip),%r14
  jmp    L43
L24:
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %rax,%rbp
  je     L15
L43:
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L24
  mov    %r14,%rdi
  call   <fatal@plt>
  jmp    L24
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: write() failed

assistant: ```c
void write2(int fd, const char *buf, size_t len) {
  while (len > 0) {
    ssize_t count = write(fd, buf, len);
    if (count == -1) {
      fatal("write() failed");
    }
    len -= count;
    buf += count;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write2>:
  endbr64
  test   %rdx,%rdx
  je     L24
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L14:
  movslq %ebx,%rax
  add    %rax,%r14
  sub    %rax,%rbp
  je     L1
L40:
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L14
  mov    %r13,%rdi
  call   <fatal@plt>
  movslq %ebx,%rax
  add    %rax,%r14
  sub    %rax,%rbp
  jne    L40
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: write() failed

assistant: ```c
void write2(int fd, const char *buf, size_t len) {
  while (len > 0) {
    ssize_t count = write(fd, buf, len);
    if (count == -1) {
      fatal("write() failed");
    }
    len -= count;
    buf += count;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write2>:
  endbr64
  test   %rdx,%rdx
  je     L14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L31
  cltq
  add    %rax,%r13
  sub    %rax,%rbx
  jne    L24
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L31:
  mov    %r12,%rdi
  sub    $0x1,%r13
  call   <fatal@plt>
  add    $0x1,%rbx
  jne    L24
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L14:
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: string

tool: D7: write() failed

assistant: ```c
void write2(int fd, const char *buf, size_t len) {
  while (len > 0) {
    ssize_t count = write(fd, buf, len);
    if (count == -1) {
      fatal("write() failed");
    }
    len -= count;
    buf += count;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<BrzUnaryFunc_ackdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  nop
  leave
  ret
```

assistant: ```c
void BrzUnaryFunc_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(0, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BrzUnaryFunc_ackdown>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <SEND_ACKDOWN_DELAYED@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void BrzUnaryFunc_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(0, 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<BrzUnaryFunc_ackdown>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <SEND_ACKDOWN_DELAYED@plt>
```

assistant: ```c
void BrzUnaryFunc_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(0, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BrzUnaryFunc_ackdown>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <SEND_ACKDOWN_DELAYED@plt>
```

assistant: ```c
void BrzUnaryFunc_ackdown(struct comp *comp, int port) {
  struct BrzUnaryFunc_ *c = (struct BrzUnaryFunc_ *)comp;
  SEND_ACKDOWN_DELAYED(0, 0);
}
```
user: What is the c source code of the assembly code below:

```asm
<decode_bch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %edi,-0x84(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  lea    -0x50(%rbp),%rdx
  mov    -0x90(%rbp),%rcx
  mov    -0x84(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <syndrome@plt>
  lea    -0x70(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    -0x84(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <berlekamp@plt>
  mov    %eax,-0x74(%rbp)
  mov    -0x84(%rbp),%eax
  mov    $0x4,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cmp    %eax,-0x74(%rbp)
  jg     L10
  mov    -0x98(%rbp),%rcx
  lea    -0x70(%rbp),%rdx
  mov    -0x74(%rbp),%esi
  mov    -0x84(%rbp),%eax
  mov    %eax,%edi
  call   <chien@plt>
  mov    %eax,-0x74(%rbp)
L10:
  mov    -0x74(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int decode_bch(int select_4_8, unsigned char *ecc, unsigned int *err_loc) {
  int no_of_err;
  unsigned int syn[16] = {
      0,
  };
  unsigned int err_poly[8] = {
      0,
  };
  syndrome(select_4_8, ecc, syn);
  no_of_err = berlekamp(select_4_8, syn, err_poly);
  if (no_of_err <= (4 << select_4_8))
    no_of_err = chien(select_4_8, no_of_err, err_poly, err_loc);
  return no_of_err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_bch>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %edi,%ebx
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  lea    0x20(%rsp),%r12
  mov    %r12,%rdx
  call   <syndrome@plt>
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <berlekamp@plt>
  mov    $0x4,%edx
  mov    %ebx,%ecx
  shl    %cl,%edx
  cmp    %eax,%edx
  jge    L0
L1:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  mov    %rsp,%rdx
  mov    %rbp,%rcx
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <chien@plt>
  jmp    L1
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_bch(int select_4_8, unsigned char *ecc, unsigned int *err_loc) {
  int no_of_err;
  unsigned int syn[16] = {
      0,
  };
  unsigned int err_poly[8] = {
      0,
  };
  syndrome(select_4_8, ecc, syn);
  no_of_err = berlekamp(select_4_8, syn, err_poly);
  if (no_of_err <= (4 << select_4_8))
    no_of_err = chien(select_4_8, no_of_err, err_poly, err_loc);
  return no_of_err;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decode_bch>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    %rsp,%r14
  movaps %xmm0,0x20(%rsp)
  mov    %rbp,%rdx
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <syndrome@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <berlekamp@plt>
  mov    $0x4,%edx
  mov    %r12d,%ecx
  shl    %cl,%edx
  cmp    %eax,%edx
  jge    L29
L4:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L29:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %eax,%esi
  mov    %r12d,%edi
  call   <chien@plt>
  jmp    L4
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_bch(int select_4_8, unsigned char *ecc, unsigned int *err_loc) {
  int no_of_err;
  unsigned int syn[16] = {
      0,
  };
  unsigned int err_poly[8] = {
      0,
  };
  syndrome(select_4_8, ecc, syn);
  no_of_err = berlekamp(select_4_8, syn, err_poly);
  if (no_of_err <= (4 << select_4_8))
    no_of_err = chien(select_4_8, no_of_err, err_poly, err_loc);
  return no_of_err;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<decode_bch>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  mov    %rsp,%r14
  movaps %xmm0,0x20(%rsp)
  mov    %rbp,%rdx
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <syndrome@plt>
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <berlekamp@plt>
  mov    $0x4,%edx
  mov    %r12d,%ecx
  shl    %cl,%edx
  cmp    %eax,%edx
  jge    L15
L14:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L15:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %eax,%esi
  mov    %r12d,%edi
  call   <chien@plt>
  jmp    L14
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decode_bch(int select_4_8, unsigned char *ecc, unsigned int *err_loc) {
  int no_of_err;
  unsigned int syn[16] = {
      0,
  };
  unsigned int err_poly[8] = {
      0,
  };
  syndrome(select_4_8, ecc, syn);
  no_of_err = berlekamp(select_4_8, syn, err_poly);
  if (no_of_err <= (4 << select_4_8))
    no_of_err = chien(select_4_8, no_of_err, err_poly, err_loc);
  return no_of_err;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L26:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movswl %ax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzwl (%rax),%eax
  cwtl
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L14
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L14:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L26
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string

tool: D17: (%d, %d)

tool: D1: , 

assistant: ```c
int result(short *to, short *from, int count) {
  int i;
  for (i = 0; i < count; ++i) {
    printf("(%d, %d)", to[i], from[i]);
    if (i < count - 1) {
      printf(", ");
    }
  }
  printf("\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<result>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L38
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%r15d
  mov    $0x0,%ebx
  lea    D2(%rip),%r14
  lea    -0x1(%rdx),%ebp
  jmp    L37
L20:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L38
L37:
  movswl 0x0(%r13,%rbx,2),%edx
  movswl (%r12,%rbx,2),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jle    L20
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L38:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D2: (%d, %d)

tool: D12: , 

assistant: ```c
int result(short *to, short *from, int count) {
  int i;
  for (i = 0; i < count; ++i) {
    printf("(%d, %d)", to[i], from[i]);
    if (i < count - 1) {
      printf(", ");
    }
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<result>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L2
  mov    %rdi,%rbp
  mov    %rsi,%r12
  lea    -0x1(%rdx),%r14d
  movslq %edx,%rbx
  xor    %r15d,%r15d
  lea    D0(%rip),%r13
  nopl   (%rax)
L27:
  movswl (%r12,%r15,2),%edx
  movswl 0x0(%rbp,%r15,2),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %r15d,%r14d
  jle    L17
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L17:
  add    $0x1,%r15
  cmp    %r15,%rbx
  jne    L27
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D10
datatype: string

tool: D0: (%d, %d)

tool: D10: , 

assistant: ```c
int result(short *to, short *from, int count) {
  int i;
  for (i = 0; i < count; ++i) {
    printf("(%d, %d)", to[i], from[i]);
    if (i < count - 1) {
      printf(", ");
    }
  }
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<result>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  jle    L7
  mov    %edx,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%r14d
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  jne    L19
  lea    D2(%rip),%r13
L53:
  movslq 0xc(%rsp),%rbx
  cs nopw 0x0(%rax,%rax,1)
L45:
  movswl (%r12,%rbx,2),%edx
  movswl 0x0(%rbp,%rbx,2),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r14d
  jg     L45
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  xor    %ebx,%ebx
  lea    D2(%rip),%r13
  lea    D24(%rip),%r15
L12:
  movswl (%r12,%rbx,2),%edx
  movswl 0x0(%rbp,%rbx,2),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L12
  mov    %eax,0xc(%rsp)
  cmp    %eax,%r14d
  jg     L53
  jmp    L7
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D24
type_guessed: string

tool: D2: (%d, %d)

tool: D24: , 

assistant: ```c
int result(short *to, short *from, int count) {
  int i;
  for (i = 0; i < count; ++i) {
    printf("(%d, %d)", to[i], from[i]);
    if (i < count - 1) {
      printf(", ");
    }
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int test5() {
  const int s[5];
  int t[5];
  return &s == &t;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test5>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int test5() {
  const int s[5];
  int t[5];
  return &s == &t;
}
```
user: What is the c source code of the assembly code below?

```asm
<test5>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test5() {
  const int s[5];
  int t[5];
  return &s == &t;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test5>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int test5() {
  const int s[5];
  int t[5];
  return &s == &t;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int f2(int i) {
  assert(i != 2);
  return i;
}
```