ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D45(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jae    L93
  comiss %xmm0,%xmm1
  movss  0x8(%rsp),%xmm2
  jb     L103
  comiss %xmm2,%xmm0
  jae    L66
L103:
  comiss %xmm0,%xmm2
  movss  0xc(%rsp),%xmm1
  ja     L47
L18:
  comiss %xmm0,%xmm1
  movss  0x10(%rsp),%xmm2
  jbe    L21
  comiss %xmm2,%xmm0
  jae    L117
L21:
  comiss %xmm0,%xmm2
  ja     L111
L91:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L122
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L47:
  comiss %xmm1,%xmm0
  jb     L18
  lea    D87(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L93:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L66:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L117:
  lea    D52(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L111:
  lea    D70(%rip),%rdi
  call   <printf@plt>
  jmp    L91
L122:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D45
type_guessed: string
name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D54
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string
name: retrieve_data
arguments: tag: D87
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D52
type_guessed: string
name: retrieve_data
arguments: tag: D70
type_guessed: string

tool: D45: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D24: %f%f%f%f

tool: D54: Thank you. Now enter student score (percent) >

tool: D2: %f

tool: D87: Student has an C grade


tool: D15: Student has an A grade


tool: D8: Student has an B grade


tool: D52: Student has an D grade


tool: D70: Student has failed that course


assistant: ```c
int main(void) {
  float a, b, c, d;
  float percent;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &percent);
  if (percent >= a)
    printf("Student has an A grade\n");
  else if (percent <= a && percent >= b)
    printf("Student has an B grade\n");
  else if (percent < b && percent >= c)
    printf("Student has an C grade\n");
  else if (percent < c && percent >= d)
    printf("Student has an D grade\n");
  else if (percent < d)
    printf("Student has failed that course\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<routine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L3:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x5,-0x4(%rbp)
  jle    L3
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: bleble

assistant: ```c
void *routine(void *data) {
  int i;
  for (i = 0; i < 6; ++i) {
    puts("bleble");
    sleep(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<routine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x6,%ebx
  lea    D9(%rip),%rbp
L3:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string

tool: D9: bleble

assistant: ```c
void *routine(void *data) {
  int i;
  for (i = 0; i < 6; ++i) {
    puts("bleble");
    sleep(1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<routine>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: bleble

assistant: ```c
void *routine(void *data) {
  int i;
  for (i = 0; i < 6; ++i) {
    puts("bleble");
    sleep(1);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<routine>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    $0x6,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  sub    $0x1,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: bleble

assistant: ```c
void *routine(void *data) {
  int i;
  for (i = 0; i < 6; ++i) {
    puts("bleble");
    sleep(1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L4
L2:
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <ft_strdel@plt>
L4:
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strdel@plt>
  nop
  leave
  ret
```

assistant: ```c
void cleanup(char **split, size_t cur) {
  while (cur > 0) {
    cur--;
    ft_strdel(&split[cur]);
  }
  ft_strdel(split);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cleanup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %rsi,%rsi
  je     L17
  mov    %rsi,%rbx
  lea    -0x8(%rdi,%rsi,8),%rbp
L12:
  sub    $0x1,%rbx
  mov    %rbp,%rdi
  call   <ft_strdel@plt>
  sub    $0x8,%rbp
  test   %rbx,%rbx
  jne    L12
L17:
  mov    %r12,%rdi
  call   <ft_strdel@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void cleanup(char **split, size_t cur) {
  while (cur > 0) {
    cur--;
    ft_strdel(&split[cur]);
  }
  ft_strdel(split);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cleanup>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L6
  lea    -0x1(%rsi),%rbx
  lea    (%rdi,%rbx,8),%rbp
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L14:
  sub    $0x1,%rbx
L19:
  mov    %rbp,%rdi
  sub    $0x8,%rbp
  call   <ft_strdel@plt>
  test   %rbx,%rbx
  jne    L14
L6:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_strdel@plt>
```

assistant: ```c
void cleanup(char **split, size_t cur) {
  while (cur > 0) {
    cur--;
    ft_strdel(&split[cur]);
  }
  ft_strdel(split);
}
```
user: What is the c source code of the assembly code below?

```asm
<cleanup>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L8
  lea    -0x1(%rsi),%rbx
  lea    (%rdi,%rbx,8),%rbp
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L23:
  sub    $0x1,%rbx
L11:
  mov    %rbp,%rdi
  sub    $0x8,%rbp
  call   <ft_strdel@plt>
  test   %rbx,%rbx
  jne    L23
L8:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <ft_strdel@plt>
```

assistant: ```c
void cleanup(char **split, size_t cur) {
  while (cur > 0) {
    cur--;
    ft_strdel(&split[cur]);
  }
  ft_strdel(split);
}
```
user: What is the c source code of the assembly code below:

```asm
<pcp_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L12
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L0
L12:
  addq   $0x1,-0x20(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pcp_strndup(const char *s, size_t size) {
  char *ret;
  char *end = memchr(s, 0, size);
  if (end) {
    size = end - s + 1;
  } else {
    size++;
  }
  ret = malloc(size);
  if (ret) {
    memcpy(ret, s, size);
    ret[size - 1] = '\0';
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pcp_strndup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rsi,%rdx
  mov    $0x0,%esi
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %r12,%rdx
  add    $0x1,%rdx
  add    $0x1,%rbx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%rbp,%rbx,1)
L1:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pcp_strndup(const char *s, size_t size) {
  char *ret;
  char *end = memchr(s, 0, size);
  if (end) {
    size = end - s + 1;
  } else {
    size++;
  }
  ret = malloc(size);
  if (ret) {
    memcpy(ret, s, size);
    ret[size - 1] = '\0';
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pcp_strndup>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  add    $0x1,%rbx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L3
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pcp_strndup(const char *s, size_t size) {
  char *ret;
  char *end = memchr(s, 0, size);
  if (end) {
    size = end - s + 1;
  } else {
    size++;
  }
  ret = malloc(size);
  if (ret) {
    memcpy(ret, s, size);
    ret[size - 1] = '\0';
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pcp_strndup>:
  endbr64
  push   %r12
  mov    %rsi,%rdx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  add    $0x1,%rbx
  call   <memchr@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  add    $0x1,%rdx
  test   %rax,%rax
  cmovne %rdx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,-0x1(%r12,%rbx,1)
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *pcp_strndup(const char *s, size_t size) {
  char *ret;
  char *end = memchr(s, 0, size);
  if (end) {
    size = end - s + 1;
  } else {
    size++;
  }
  ret = malloc(size);
  if (ret) {
    memcpy(ret, s, size);
    ret[size - 1] = '\0';
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tcgetattr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D39(%rip),%rax
  test   %rax,%rax
  jne    L10
  mov    $0x0,%eax
  call   <dlopen_libc@plt>
  lea    D39(%rip),%rbx
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <dlsym_@plt>
  mov    %rax,(%rbx)
L10:
  cmpl   $0x0,-0x14(%rbp)
  jne    L18
  movl   $0x2,-0x14(%rbp)
L18:
  mov    D39(%rip),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   *%rcx
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
datatype: string

tool: D4: tcgetattr

assistant: ```c
int tcgetattr(int fd, struct termios *termios_p) {
  static int (*tcgetattr_orig)(int, struct termios *) = ((void *)0);
  if (!tcgetattr_orig) {
    dlopen_libc();
    *(void **)(&tcgetattr_orig) = dlsym_("tcgetattr");
  }
  if (fd == 0)
    fd = 2;
  return tcgetattr_orig(fd, termios_p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stacktrace_rpop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <stacktrace_pop@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *stacktrace_rpop(void *val) {
  stacktrace_pop();
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<stacktrace_rpop>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <stacktrace_pop@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
void *stacktrace_rpop(void *val) {
  stacktrace_pop();
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stacktrace_rpop>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <stacktrace_pop@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *stacktrace_rpop(void *val) {
  stacktrace_pop();
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stacktrace_rpop>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  call   <stacktrace_pop@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *stacktrace_rpop(void *val) {
  stacktrace_pop();
  return val;
}
```
user: What is the c source code of the assembly code below?

```asm
<GetOperatorType>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D36(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L65
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
L65:
  mov    $0x2,%eax
  jmp    L45
L61:
  mov    -0x8(%rbp),%rax
  lea    D50(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L82
L9:
  mov    $0x1,%eax
  jmp    L45
L82:
  mov    -0x8(%rbp),%rax
  lea    D53(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L38
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L74
L38:
  mov    $0x3,%eax
  jmp    L45
L74:
  mov    $0x4,%eax
L45:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D36
type_infered: string
name: disassemble_data
arguments: data_label: D14
type_infered: string
name: disassemble_data
arguments: data_label: D50
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D53
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D36: or

tool: D14: ||

tool: D50: and

tool: D0: &&

tool: D53: not

tool: D18: !

assistant: ```c
int GetOperatorType(const char *operator) {
  if (strcmp(operator, "or") == 0 || strcmp(operator, "||") == 0) {
    return 2;
  }
  if (strcmp(operator, "and") == 0 || strcmp(operator, "&&") == 0) {
    return 1;
  }
  if (strcmp(operator, "not") == 0 || strcmp(operator, "!") == 0) {
    return 3;
  }
  return 4;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetOperatorType>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D53(%rip),%rsi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L4
  lea    D54(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x2,%eax
  test   %rdx,%rdx
  je     L4
  lea    D36(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L50
L4:
  pop    %rbx
  ret
L50:
  lea    D39(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L4
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x3,%eax
  test   %rdx,%rdx
  je     L4
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%rax
  mov    $0x3,%eax
  sbb    $0xffffffff,%eax
  jmp    L4
```

tool_calls: name: read_data
arguments: data_label: D53
type_guessed: string
name: read_data
arguments: data_label: D54
type_guessed: string
name: read_data
arguments: data_label: D36
type_guessed: string
name: read_data
arguments: data_label: D39
type_guessed: string
name: read_data
arguments: data_label: D4
type_guessed: string
name: read_data
arguments: data_label: D22
type_guessed: string

tool: D53: or

tool: D54: ||

tool: D36: and

tool: D39: &&

tool: D4: not

tool: D22: !

assistant: ```c
int GetOperatorType(const char *operator) {
  if (strcmp(operator, "or") == 0 || strcmp(operator, "||") == 0) {
    return 2;
  }
  if (strcmp(operator, "and") == 0 || strcmp(operator, "&&") == 0) {
    return 1;
  }
  if (strcmp(operator, "not") == 0 || strcmp(operator, "!") == 0) {
    return 3;
  }
  return 4;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<GetOperatorType>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L22
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L32
  lea    D21(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L13
L32:
  mov    $0x1,%eax
L2:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L22:
  mov    $0x2,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L12
  lea    D25(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  jne    L2
L12:
  mov    $0x3,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
data_type: string
name: parse_data
arguments: tag: D28
data_type: string
name: parse_data
arguments: tag: D27
data_type: string
name: parse_data
arguments: tag: D21
data_type: string
name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D25
data_type: string

tool: D24: or

tool: D28: ||

tool: D27: and

tool: D21: &&

tool: D18: not

tool: D25: !

assistant: ```c
int GetOperatorType(const char *operator) {
  if (strcmp(operator, "or") == 0 || strcmp(operator, "||") == 0) {
    return 2;
  }
  if (strcmp(operator, "and") == 0 || strcmp(operator, "&&") == 0) {
    return 1;
  }
  if (strcmp(operator, "not") == 0 || strcmp(operator, "!") == 0) {
    return 3;
  }
  return 4;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GetOperatorType>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  lea    D48(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L48
  lea    D26(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L18
  lea    D37(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L51
L18:
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    $0x2,%eax
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L51:
  lea    D59(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L55
  lea    D11(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  mov    $0x4,%eax
  test   %r8,%r8
  jne    L0
L55:
  mov    $0x3,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D48
type_infered: string
name: extract_symbolic_data
arguments: tag: D26
type_infered: string
name: extract_symbolic_data
arguments: tag: D37
type_infered: string
name: extract_symbolic_data
arguments: tag: D59
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string

tool: D4: or

tool: D48: ||

tool: D26: and

tool: D37: &&

tool: D59: not

tool: D11: !

assistant: ```c
int GetOperatorType(const char *operator) {
  if (strcmp(operator, "or") == 0 || strcmp(operator, "||") == 0) {
    return 2;
  }
  if (strcmp(operator, "and") == 0 || strcmp(operator, "&&") == 0) {
    return 1;
  }
  if (strcmp(operator, "not") == 0 || strcmp(operator, "!") == 0) {
    return 3;
  }
  return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<showHelp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string

tool: D5: Argumenty programu:
	--help vypise napovedu
	--test skontroluje ci zadany subor obsahuje validnu bitovu mapu
	--hline v danem obrazku nalezne a vytiskne pocatecni a
		koncovou souradnici prvni nejdelsi horizontalni usecky.
	--vline v danem obrazku nalezne a vytiskne pocatecni a
		koncovou souradnici prvni nejdelsi vertikalni usecky.
	--square v danem obrazku nalezne a vytiskne pocatecni a
		koncovou souradnici prvniho nejvetsiho ctverce.


assistant: ```c
void showHelp() {
  printf("Argumenty programu:\n"
         "\t--help vypise napovedu\n"
         "\t--test skontroluje ci zadany subor obsahuje validnu bitovu mapu\n"
         "\t--hline v danem obrazku nalezne a vytiskne pocatecni a\n\t\tkoncovou souradnici prvni nejdelsi horizontalni usecky.\n"
         "\t--vline v danem obrazku nalezne a vytiskne pocatecni a\n\t\tkoncovou souradnici prvni nejdelsi vertikalni usecky.\n"
         "\t--square v danem obrazku nalezne a vytiskne pocatecni a\n\t\tkoncovou souradnici prvniho nejvetsiho ctverce.\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<showHelp>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
data_type: string

tool: D9: Argumenty programu:
	--help vypise napovedu
	--test skontroluje ci zadany subor obsahuje validnu bitovu mapu
	--hline v danem obrazku nalezne a vytiskne pocatecni a
		koncovou souradnici prvni nejdelsi horizontalni usecky.
	--vline v danem obrazku nalezne a vytiskne pocatecni a
		koncovou souradnici prvni nejdelsi vertikalni usecky.
	--square v danem obrazku nalezne a vytiskne pocatecni a
		koncovou souradnici prvniho nejvetsiho ctverce.


assistant: ```c
void showHelp() {
  printf("Argumenty programu:\n"
         "\t--help vypise napovedu\n"
         "\t--test skontroluje ci zadany subor obsahuje validnu bitovu mapu\n"
         "\t--hline v danem obrazku nalezne a vytiskne pocatecni a\n\t\tkoncovou souradnici prvni nejdelsi horizontalni usecky.\n"
         "\t--vline v danem obrazku nalezne a vytiskne pocatecni a\n\t\tkoncovou souradnici prvni nejdelsi vertikalni usecky.\n"
         "\t--square v danem obrazku nalezne a vytiskne pocatecni a\n\t\tkoncovou souradnici prvniho nejvetsiho ctverce.\n");
}
```