ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<memrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L60
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L110:
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L5
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  je     L5
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L5
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  je     L5
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L5
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  je     L5
  subq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L5
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x1c(%rbp),%edx
  cmp    %dl,%al
  je     L5
  jmp    L110
L5:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L60
  mov    -0x10(%rbp),%rax
  jmp    L78
L60:
  mov    $0x0,%eax
L78:
  pop    %rbp
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  if (n > 0) {
    const char *p = (const char *)s;
    const char *q = p + n;
    while (1) {
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
    }
    if (q >= p)
      return (void *)q;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memrchr>:
  endbr64
  mov    $0x0,%r9d
  test   %rdx,%rdx
  je     L10
  add    %rdi,%rdx
  lea    -0x1(%rdx),%rax
  lea    -0x3(%rdx),%r8
  lea    -0x2(%rdx),%rcx
L83:
  mov    %rax,%r9
  cmp    %rax,%rdi
  ja     L110
  cmp    %sil,-0x1(%rdx)
  je     L10
  mov    %rcx,%r9
  cmp    %rcx,%rdi
  ja     L79
  cmp    -0x2(%rdx),%sil
  je     L10
  mov    %r8,%r9
  cmp    %r8,%rdi
  ja     L19
  cmp    -0x3(%rdx),%sil
  je     L10
  sub    $0x4,%rdx
  cmp    %rdx,%rdi
  ja     L49
  sub    $0x4,%rax
  sub    $0x4,%r8
  sub    $0x4,%rcx
  cmp    (%rdx),%sil
  jne    L83
  mov    %rdx,%r9
  jmp    L10
L110:
  mov    $0x0,%r9d
L10:
  mov    %r9,%rax
  ret
L79:
  mov    $0x0,%r9d
  jmp    L10
L19:
  mov    $0x0,%r9d
  jmp    L10
L49:
  mov    $0x0,%r9d
  jmp    L10
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  if (n > 0) {
    const char *p = (const char *)s;
    const char *q = p + n;
    while (1) {
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
    }
    if (q >= p)
      return (void *)q;
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memrchr>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L44
  add    %rdi,%rdx
  lea    -0x1(%rdx),%rcx
  lea    -0x3(%rdx),%r9
  lea    -0x2(%rdx),%r8
  jmp    L4
  nopl   0x0(%rax)
L43:
  cmp    %sil,-0x1(%rdx)
  je     L44
  mov    %r8,%rax
  cmp    %r8,%rdi
  ja     L97
  cmp    -0x2(%rdx),%sil
  je     L44
  mov    %r9,%rax
  cmp    %r9,%rdi
  ja     L97
  cmp    -0x3(%rdx),%sil
  je     L44
  sub    $0x4,%rdx
  cmp    %rdx,%rdi
  ja     L97
  sub    $0x4,%rcx
  lea    -0x4(%r9),%r9
  sub    $0x4,%r8
  cmp    (%rdx),%sil
  je     L90
L4:
  mov    %rcx,%rax
  cmp    %rcx,%rdi
  jbe    L43
L97:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L90:
  mov    %rdx,%rax
L44:
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  if (n > 0) {
    const char *p = (const char *)s;
    const char *q = p + n;
    while (1) {
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
    }
    if (q >= p)
      return (void *)q;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memrchr>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L39
  add    %rdi,%rdx
  lea    -0x1(%rdx),%rcx
  lea    -0x3(%rdx),%r9
  lea    -0x2(%rdx),%r8
  jmp    L33
  nopl   0x0(%rax)
L43:
  cmp    %sil,-0x1(%rdx)
  je     L39
  mov    %r8,%rax
  cmp    %r8,%rdi
  ja     L45
  cmp    -0x2(%rdx),%sil
  je     L39
  mov    %r9,%rax
  cmp    %r9,%rdi
  ja     L45
  cmp    -0x3(%rdx),%sil
  je     L39
  sub    $0x4,%rdx
  cmp    %rdx,%rdi
  ja     L45
  sub    $0x4,%rcx
  lea    -0x4(%r9),%r9
  sub    $0x4,%r8
  cmp    (%rdx),%sil
  je     L66
L33:
  mov    %rcx,%rax
  cmp    %rcx,%rdi
  jbe    L43
L45:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %rdx,%rax
L39:
  ret
```

assistant: ```c
void *memrchr(const void *s, int c, size_t n) {
  if (n > 0) {
    const char *p = (const char *)s;
    const char *q = p + n;
    while (1) {
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
      q--;
      if (q < p || q[0] == (char)c)
        break;
    }
    if (q >= p)
      return (void *)q;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L5:
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _strlen(char *s) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return (i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%eax
L28:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L28
L6:
  mov    %edx,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int _strlen(char *s) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  xchg   %ax,%ax
L5:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L5
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _strlen(char *s) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return (i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L4
  mov    $0x1,%eax
  xchg   %ax,%ax
L16:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L16
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _strlen(char *s) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return (i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<box_move_face>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movabs $0x200000006,%rdi
  sub    $0x148,%rsp
  mov    %rdx,(%rsp)
  lea    0x30(%rsp),%r15
  lea    0x60(%rsp),%r12
  movabs $0x3f800000bf800000,%rdx
  mov    %rcx,0x8(%rsp)
  mov    %r15,%r13
  movabs $0x600000007,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  movabs $0xbf800000bf800000,%rax
  mov    %rcx,0xe8(%rsp)
  movabs $0x400000000,%rcx
  mov    %rcx,0xf0(%rsp)
  movabs $0x100000005,%rcx
  mov    %rcx,0xf8(%rsp)
  movabs $0x600000002,%rcx
  mov    %rcx,0x100(%rsp)
  movabs $0x300000007,%rcx
  mov    %rdx,0x78(%rsp)
  mov    %rdx,0x98(%rsp)
  mov    %rax,0x70(%rsp)
  mov    %rax,0x80(%rsp)
  add    $0xffffffff80000000,%rax
  mov    %rax,0x88(%rsp)
  mov    %rax,0x90(%rsp)
  mov    %rax,0xb0(%rsp)
  mov    %rax,0xc0(%rsp)
  movabs $0x100000000,%rax
  mov    %rax,0xd0(%rsp)
  movabs $0x300000002,%rax
  mov    %rdx,0xa0(%rsp)
  mov    %rdx,0xa8(%rsp)
  add    $0xffffffff80000000,%rdx
  mov    %rax,0xd8(%rsp)
  movabs $0x400000005,%rax
  mov    %rcx,0x108(%rsp)
  movabs $0x500000001,%rcx
  mov    %rdx,0xb8(%rsp)
  mov    %rdx,0xc8(%rsp)
  movabs $0x200000003,%rdx
  mov    %rax,0xe0(%rsp)
  mov    %rcx,0x110(%rsp)
  movabs $0x300000000,%rcx
  mov    %rdi,0x118(%rsp)
  movabs $0x400000007,%rdi
  mov    %rdi,0x128(%rsp)
  mov    %rbx,%rdi
  mov    %rcx,0x120(%rsp)
  mov    %rdx,0x18(%rsp)
  movq   $0x1,0x10(%rsp)
  mov    %rax,0x20(%rsp)
  call   <box_is_bbox@plt>
  mov    %eax,%edi
  call   <assert@plt>
  movslq 0x10(%rsp,%rbp,4),%rax
  lea    0x70(%rsp),%rbp
  shl    $0x4,%rax
  lea    0xd0(%rsp,%rax,1),%r14
L2:
  movslq (%r14),%rax
  mov    %r13,%rdx
  mov    %rbx,%rdi
  add    $0xc,%r13
  add    $0x4,%r14
  lea    (%rax,%rax,2),%rax
  lea    0x0(%rbp,%rax,4),%rsi
  call   <mat4_mul_vec3@plt>
  cmp    %r12,%r13
  jne    L2
  mov    (%rsp),%rdi
  mov    %r13,%rsi
  call   <vec3_copy@plt>
  mov    0x8(%rsp),%rdi
  mov    %r15,%rdx
  mov    $0x5,%esi
  call   <bbox_from_npoints@plt>
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void box_move_face(const float b[4][4], int f, const float p[3], float out[4][4]) {
  const float PS[8][3] = {
      {-1, -1, -1}, {+1, -1, -1}, {+1, -1, +1}, {-1, -1, +1}, {-1, +1, -1}, {+1, +1, -1}, {+1, +1, +1}, {-1, +1, +1},
  };
  const int FS[6][4] = {{0, 1, 2, 3}, {5, 4, 7, 6}, {0, 4, 5, 1}, {2, 6, 7, 3}, {1, 5, 6, 2}, {0, 3, 7, 4}};
  const int FO[6] = {1, 0, 3, 2, 5, 4};
  float ps[5][3];
  int i;
  assert(box_is_bbox(b));
  f = FO[f];
  for (i = 0; i < 4; i++)
    mat4_mul_vec3(b, PS[FS[f][i]], ps[i]);
  vec3_copy(p, ps[4]);
  bbox_from_npoints(out, 5, ps);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: Usage: %s [OPTION]... COMMAND
OPTION:
	--help     display this message
	--start    start the service
	--stop     stop the service


assistant: ```c
void usage(FILE *fp, const char *const name) {
  const char *const ufmt = "Usage: %s [OPTION]... COMMAND\n"
                           "OPTION:\n"
                           "\t--help     display this message\n"
                           "\t--start    start the service\n"
                           "\t--stop     stop the service\n";
  fprintf(fp, ufmt, name);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  lea    D9(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: Usage: %s [OPTION]... COMMAND
OPTION:
	--help     display this message
	--start    start the service
	--stop     stop the service


assistant: ```c
void usage(FILE *fp, const char *const name) {
  const char *const ufmt = "Usage: %s [OPTION]... COMMAND\n"
                           "OPTION:\n"
                           "\t--help     display this message\n"
                           "\t--start    start the service\n"
                           "\t--stop     stop the service\n";
  fprintf(fp, ufmt, name);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: Usage: %s [OPTION]... COMMAND
OPTION:
	--help     display this message
	--start    start the service
	--stop     stop the service


assistant: ```c
void usage(FILE *fp, const char *const name) {
  const char *const ufmt = "Usage: %s [OPTION]... COMMAND\n"
                           "OPTION:\n"
                           "\t--help     display this message\n"
                           "\t--start    start the service\n"
                           "\t--stop     stop the service\n";
  fprintf(fp, ufmt, name);
}
```
user: What is the c source code of the assembly code below:

```asm
<usage>:
  endbr64
  mov    %rsi,%rdx
  lea    D4(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string

tool: D4: Usage: %s [OPTION]... COMMAND
OPTION:
	--help     display this message
	--start    start the service
	--stop     stop the service


assistant: ```c
void usage(FILE *fp, const char *const name) {
  const char *const ufmt = "Usage: %s [OPTION]... COMMAND\n"
                           "OPTION:\n"
                           "\t--help     display this message\n"
                           "\t--start    start the service\n"
                           "\t--stop     stop the service\n";
  fprintf(fp, ufmt, name);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<X509_check_host>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    %r8,-0x28(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L72
  mov    $0xfffffffe,%eax
  jmp    L10
L72:
  cmpq   $0x0,-0x18(%rbp)
  jne    L90
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L49
L90:
  cmpq   $0x1,-0x18(%rbp)
  jbe    L32
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  jmp    L79
L32:
  mov    -0x18(%rbp),%rax
L79:
  mov    -0x10(%rbp),%rcx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    %rcx,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L49
  mov    $0xfffffffe,%eax
  jmp    L10
L49:
  cmpq   $0x1,-0x18(%rbp)
  jbe    L47
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L47
  subq   $0x1,-0x18(%rbp)
L47:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  mov    -0x28(%rbp),%r8
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %r8,%r9
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <do_x509_check@plt>
L10:
  leave
  ret
```

assistant: ```c
int X509_check_host(X509 *x, const char *chk, size_t chklen, unsigned int flags, char **peername) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen > 1 ? chklen - 1 : chklen))
    return -2;
  if (chklen > 1 && chk[chklen - 1] == '\0')
    --chklen;
  return do_x509_check(x, chk, chklen, flags, GEN_DNS, peername);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<X509_check_host>:
  endbr64
  test   %rsi,%rsi
  je     L71
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  mov    %r8,%r14
  test   %rdx,%rdx
  jne    L74
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  cmp    $0x1,%rax
  jbe    L38
L41:
  cmpb   $0x1,-0x1(%rbp,%rbx,1)
  sbb    $0x0,%rbx
L38:
  mov    %r14,%r9
  mov    D1(%rip),%rax
  mov    (%rax),%r8d
  mov    %r13d,%ecx
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <do_x509_check@plt>
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L74:
  cmp    $0x1,%rdx
  jbe    L9
  lea    -0x1(%rdx),%rdx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L41
  mov    $0xfffffffe,%eax
  jmp    L54
L71:
  mov    $0xfffffffe,%eax
  ret
L9:
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L38
  mov    $0xfffffffe,%eax
  jmp    L54
```

assistant: ```c
int X509_check_host(X509 *x, const char *chk, size_t chklen, unsigned int flags, char **peername) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen > 1 ? chklen - 1 : chklen))
    return -2;
  if (chklen > 1 && chk[chklen - 1] == '\0')
    --chklen;
  return do_x509_check(x, chk, chklen, flags, GEN_DNS, peername);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<X509_check_host>:
  endbr64
  test   %rsi,%rsi
  je     L29
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L1
  cmp    $0x1,%rdx
  je     L5
  lea    -0x1(%rdx),%rbp
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rbp,%rdx
  call   <memchr@plt>
  test   %rax,%rax
  jne    L38
L40:
  cmpb   $0x0,(%r15,%rbp,1)
  cmove  %rbp,%r12
L27:
  mov    D1(%rip),%rax
  mov    %rbx,%r9
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    (%rax),%r8d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <do_x509_check@plt>
L1:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  lea    -0x1(%rax),%rbp
  cmp    $0x1,%rax
  ja     L40
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %esi,%esi
  mov    $0x1,%edx
  mov    %r15,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L27
L38:
  add    $0x8,%rsp
  mov    $0xfffffffe,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int X509_check_host(X509 *x, const char *chk, size_t chklen, unsigned int flags, char **peername) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen > 1 ? chklen - 1 : chklen))
    return -2;
  if (chklen > 1 && chk[chklen - 1] == '\0')
    --chklen;
  return do_x509_check(x, chk, chklen, flags, GEN_DNS, peername);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<X509_check_host>:
  endbr64
  test   %rsi,%rsi
  je     L63
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L52
  cmp    $0x1,%rdx
  je     L37
  lea    -0x1(%rdx),%rbp
  xor    %esi,%esi
  mov    %r15,%rdi
  mov    %rbp,%rdx
  call   <memchr@plt>
  test   %rax,%rax
  jne    L8
L4:
  cmpb   $0x0,(%r15,%rbp,1)
  cmove  %rbp,%r12
L22:
  mov    D8(%rip),%rax
  mov    %rbx,%r9
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    (%rax),%r8d
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <do_x509_check@plt>
L52:
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  lea    -0x1(%rax),%rbp
  cmp    $0x1,%rax
  ja     L4
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L37:
  xor    %esi,%esi
  mov    $0x1,%edx
  mov    %r15,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L22
L8:
  add    $0x8,%rsp
  mov    $0xfffffffe,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  mov    $0xfffffffe,%eax
  ret
```

assistant: ```c
int X509_check_host(X509 *x, const char *chk, size_t chklen, unsigned int flags, char **peername) {
  if (chk == NULL)
    return -2;
  if (chklen == 0)
    chklen = strlen(chk);
  else if (memchr(chk, '\0', chklen > 1 ? chklen - 1 : chklen))
    return -2;
  if (chklen > 1 && chk[chklen - 1] == '\0')
    --chklen;
  return do_x509_check(x, chk, chklen, flags, GEN_DNS, peername);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<log_request_plain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L8:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printLog@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  mov    -0x18(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printLog@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D11
datatype: string
name: read_data
arguments: label: D17
datatype: string

tool: D11: %c

tool: D17: 


assistant: ```c
void log_request_plain(FILE *logfile, char *headers, int headers_len) {
  int i = 0;
  for (; i < headers_len; i++) {
    printLog(logfile, "%c", headers[i]);
  }
  printLog(logfile, "\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log_request_plain>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %edx,%edx
  jle    L13
  mov    %rsi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x1(%rsi,%rax,1),%r13
  lea    D2(%rip),%r12
L17:
  movsbl (%rbx),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printLog@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L17
L13:
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printLog@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_guessed: string
name: read_data
arguments: data_label: D16
type_guessed: string

tool: D2: %c

tool: D16: 


assistant: ```c
void log_request_plain(FILE *logfile, char *headers, int headers_len) {
  int i = 0;
  for (; i < headers_len; i++) {
    printLog(logfile, "%c", headers[i]);
  }
  printLog(logfile, "\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<log_request_plain>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L6
  lea    -0x1(%rdx),%eax
  mov    %rsi,%rbx
  lea    D17(%rip),%r12
  lea    0x1(%rsi,%rax,1),%r13
  nopw   0x0(%rax,%rax,1)
L16:
  movsbl (%rbx),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printLog@plt>
  cmp    %r13,%rbx
  jne    L16
L6:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printLog@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D9
type_guessed: string

tool: D17: %c

tool: D9: 


assistant: ```c
void log_request_plain(FILE *logfile, char *headers, int headers_len) {
  int i = 0;
  for (; i < headers_len; i++) {
    printLog(logfile, "%c", headers[i]);
  }
  printLog(logfile, "\n");
}
```