ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<query_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <extract_paths@plt>
  test   %eax,%eax
  jne    L46
  mov    $0x0,%eax
  jmp    L17
L46:
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L32
  mov    $0x0,%eax
  jmp    L17
L32:
  mov    -0x20(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <query_tagfile@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
  mov    $0x1,%eax
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: rb

assistant: ```c
int query_file(const char *target) {
  char *path, *name, *tagfile;
  if (!extract_paths(target, &path, &name, &tagfile)) {
    return 0;
  }
  FILE *ftags;
  if ((ftags = fopen(tagfile, "rb")) == NULL) {
    return 0;
  }
  query_tagfile(name, ftags);
  fclose(ftags);
  free(name);
  name = NULL;
  free(path);
  path = NULL;
  free(tagfile);
  tagfile = NULL;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<query_file>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <extract_paths@plt>
  test   %eax,%eax
  jne    L1
L34:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x20,%rsp
  pop    %rbx
  ret
L1:
  lea    D1(%rip),%rsi
  mov    0x10(%rsp),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L34
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <query_tagfile@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  movq   $0x0,0x8(%rsp)
  mov    (%rsp),%rdi
  call   <free@plt>
  movq   $0x0,(%rsp)
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L34
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D1
data_type: string

tool: D1: rb

assistant: ```c
int query_file(const char *target) {
  char *path, *name, *tagfile;
  if (!extract_paths(target, &path, &name, &tagfile)) {
    return 0;
  }
  FILE *ftags;
  if ((ftags = fopen(tagfile, "rb")) == NULL) {
    return 0;
  }
  query_tagfile(name, ftags);
  fclose(ftags);
  free(name);
  name = NULL;
  free(path);
  path = NULL;
  free(tagfile);
  tagfile = NULL;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<query_file>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <extract_paths@plt>
  test   %eax,%eax
  jne    L29
L11:
  xor    %eax,%eax
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    0x10(%rsp),%rdi
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L11
  mov    0x8(%rsp),%rdi
  mov    %rax,%rsi
  call   <query_tagfile@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    (%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  movq   $0x0,(%rsp)
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L15
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: rb

assistant: ```c
int query_file(const char *target) {
  char *path, *name, *tagfile;
  if (!extract_paths(target, &path, &name, &tagfile)) {
    return 0;
  }
  FILE *ftags;
  if ((ftags = fopen(tagfile, "rb")) == NULL) {
    return 0;
  }
  query_tagfile(name, ftags);
  fclose(ftags);
  free(name);
  name = NULL;
  free(path);
  path = NULL;
  free(tagfile);
  tagfile = NULL;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<query_file>:
  endbr64
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <extract_paths@plt>
  test   %eax,%eax
  jne    L26
L15:
  xor    %eax,%eax
L32:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    0x10(%rsp),%rdi
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
  mov    0x8(%rsp),%rdi
  mov    %rax,%rsi
  call   <query_tagfile@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    (%rsp),%rdi
  movq   $0x0,0x8(%rsp)
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  movq   $0x0,(%rsp)
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L32
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type_guessed: string

tool: D1: rb

assistant: ```c
int query_file(const char *target) {
  char *path, *name, *tagfile;
  if (!extract_paths(target, &path, &name, &tagfile)) {
    return 0;
  }
  FILE *ftags;
  if ((ftags = fopen(tagfile, "rb")) == NULL) {
    return 0;
  }
  query_tagfile(name, ftags);
  fclose(ftags);
  free(name);
  name = NULL;
  free(path);
  path = NULL;
  free(tagfile);
  tagfile = NULL;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6b,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L36
L12:
  movb   $0x0,-0xb(%rbp)
  jmp    L7
L5:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  or     %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  shl    $0x3,%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  addb   $0x2,-0xb(%rbp)
L7:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xb(%rbp)
  jb     L5
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L12
  movzbl -0x9(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local1] |= state[local2];
        state[0UL] |= (state[local2] & (unsigned char)31) << 3UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (787497705UL >> (unsigned char)255);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x6b(%rax),%edx
  movzbl 0x1(%rdi),%edi
  mov    $0x0,%r8d
  test   %dil,%dil
  je     L7
L8:
  mov    $0x0,%eax
L16:
  lea    0x0(,%rdx,8),%ecx
  or     %ecx,%edx
  add    $0x2,%eax
  cmp    %dil,%al
  jb     L16
  add    $0x1,%r8d
  cmp    %dil,%r8b
  jne    L8
L7:
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local1] |= state[local2];
        state[0UL] |= (state[local2] & (unsigned char)31) << 3UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (787497705UL >> (unsigned char)255);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  xor    %r8d,%r8d
  lea    -0x6b(%rax),%edx
  test   %dil,%dil
  je     L19
  cs nopw 0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  lea    0x0(,%rdx,8),%ecx
  add    $0x2,%eax
  or     %ecx,%edx
  cmp    %dil,%al
  jb     L3
  add    $0x1,%r8d
  cmp    %dil,%r8b
  jne    L16
L19:
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local1] |= state[local2];
        state[0UL] |= (state[local2] & (unsigned char)31) << 3UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (787497705UL >> (unsigned char)255);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edi
  xor    %r8d,%r8d
  lea    -0x6b(%rax),%edx
  test   %dil,%dil
  je     L19
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  lea    0x0(,%rdx,8),%ecx
  add    $0x2,%eax
  or     %ecx,%edx
  cmp    %dil,%al
  jb     L27
  add    $0x1,%r8d
  cmp    %dil,%r8b
  jne    L2
L19:
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] - 51238316UL) - (unsigned char)191;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local1] |= state[local2];
        state[0UL] |= (state[local2] & (unsigned char)31) << 3UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = state[0UL] + (787497705UL >> (unsigned char)255);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L58
  jmp    L41
L3:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
L41:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L3
  jmp    L23
L58:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L29
L23:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  if (n != 0) {
    char *d = dst;
    const char *s = src;
    do {
      if ((*d++ = *s++) == 0) {
        while (--n != 0)
          *d++ = 0;
        break;
      }
    } while (--n != 0);
  }
  return (dst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L21
  mov    %rdi,%rcx
L10:
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rsi),%r8d
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L42
  sub    $0x1,%edx
  jne    L10
L21:
  ret
L42:
  cmp    $0x1,%edx
  je     L21
  lea    -0x1(%rdx),%edx
  add    %rcx,%rdx
L44:
  add    $0x1,%rcx
  movb   $0x0,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L44
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  if (n != 0) {
    char *d = dst;
    const char *s = src;
    do {
      if ((*d++ = *s++) == 0) {
        while (--n != 0)
          *d++ = 0;
        break;
      }
    } while (--n != 0);
  }
  return (dst);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %edx,%edx
  jne    L39
L38:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  test   %edx,%edx
  je     L38
L39:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %edx,%ecx
  sub    $0x1,%edx
  mov    %al,-0x1(%rdi)
  test   %al,%al
  jne    L0
  test   %edx,%edx
  je     L38
  lea    -0x2(%rcx),%edx
  xor    %esi,%esi
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  if (n != 0) {
    char *d = dst;
    const char *s = src;
    do {
      if ((*d++ = *s++) == 0) {
        while (--n != 0)
          *d++ = 0;
        break;
      }
    } while (--n != 0);
  }
  return (dst);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %edx,%edx
  jne    L33
L14:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  test   %edx,%edx
  je     L14
L33:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %edx,%ecx
  sub    $0x1,%edx
  mov    %al,-0x1(%rdi)
  test   %al,%al
  jne    L29
  test   %edx,%edx
  je     L14
  lea    -0x2(%rcx),%edx
  xor    %esi,%esi
  add    $0x1,%rdx
  call   <memset@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strncpy(char *dst, const char *src, int n) {
  if (n != 0) {
    char *d = dst;
    const char *s = src;
    do {
      if ((*d++ = *s++) == 0) {
        while (--n != 0)
          *d++ = 0;
        break;
      }
    } while (--n != 0);
  }
  return (dst);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UARTDisableSIR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x30,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x30,%edx
  movslq %edx,%rdx
  and    $0xfffffff9,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UARTDisableSIR>:
  endbr64
  add    $0x30,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffff9,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: Translate the below assembly code into C programming language:

```asm
<UARTDisableSIR>:
  endbr64
  add    $0x30,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffff9,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UARTDisableSIR>:
  endbr64
  add    $0x30,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  and    $0xfffffff9,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void UARTDisableSIR(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000030))) &= ~(0x00000002 | 0x00000004);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fsqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xd9,%edi
  call   <put8@plt>
  mov    $0xfa,%edi
  call   <put8@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fsqrt(void) {
  put8(0xD9);
  put8(0xFA);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fsqrt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd9,%edi
  call   <put8@plt>
  mov    $0xfa,%edi
  call   <put8@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void fsqrt(void) {
  put8(0xD9);
  put8(0xFA);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fsqrt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd9,%edi
  call   <put8@plt>
  mov    $0xfa,%edi
  add    $0x8,%rsp
  jmp    1050 <put8@plt>
```

assistant: ```c
void fsqrt(void) {
  put8(0xD9);
  put8(0xFA);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fsqrt>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xd9,%edi
  call   <put8@plt>
  mov    $0xfa,%edi
  add    $0x8,%rsp
  jmp    1050 <put8@plt>
```

assistant: ```c
void fsqrt(void) {
  put8(0xD9);
  put8(0xFA);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isComment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L5
  mov    $0x0,%eax
  jmp    L60
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3b,%al
  jne    L49
  addq   $0x1,-0x18(%rbp)
  jmp    L55
L11:
  addq   $0x1,-0x18(%rbp)
L55:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L11
L57:
  cmpq   $0x0,-0x20(%rbp)
  je     L37
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L37:
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  jmp    L60
L49:
  mov    $0x0,%eax
L60:
  leave
  ret
```

assistant: ```c
int isComment(const char *c, char *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == ';') {
    c++;
    while (*c != '\0' && *c != '\n')
      c++;
    if (value != NULL) {
      strncpy(value, start, c - start);
      value[c - start] = '\0';
    }
    return c - start;
  } else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isComment>:
  endbr64
  test   %rdi,%rdi
  je     L63
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%eax
  cmpb   $0x3b,(%rdi)
  je     L46
L69:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  lea    0x1(%rdi),%rbx
  movzbl 0x1(%rdi),%eax
  test   %al,%al
  je     L75
  cmp    $0xa,%al
  je     L75
L2:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L75
  cmp    $0xa,%al
  jne    L2
L75:
  test   %r12,%r12
  je     L13
  mov    %rbx,%r13
  sub    %rbp,%r13
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%r13,1)
L13:
  mov    %ebx,%eax
  sub    %ebp,%eax
  jmp    L69
L63:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isComment(const char *c, char *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == ';') {
    c++;
    while (*c != '\0' && *c != '\n')
      c++;
    if (value != NULL) {
      strncpy(value, start, c - start);
      value[c - start] = '\0';
    }
    return c - start;
  } else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isComment>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L58
  cmpb   $0x3b,(%rdi)
  je     L47
L58:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L47:
  movzbl 0x1(%rdi),%edx
  mov    %rsi,%rbp
  lea    0x1(%rdi),%rax
  test   %dl,%dl
  je     L77
  cmp    $0xa,%dl
  je     L77
  nopl   0x0(%rax)
L7:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L70
  cmp    $0xa,%dl
  jne    L7
L70:
  sub    %rdi,%rax
  mov    %rax,%rbx
  mov    %eax,%r12d
L72:
  test   %rbp,%rbp
  je     L58
  mov    %r12d,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L77:
  mov    $0x1,%r12d
  mov    $0x1,%ebx
  jmp    L72
```

assistant: ```c
int isComment(const char *c, char *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == ';') {
    c++;
    while (*c != '\0' && *c != '\n')
      c++;
    if (value != NULL) {
      strncpy(value, start, c - start);
      value[c - start] = '\0';
    }
    return c - start;
  } else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isComment>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L26
  cmpb   $0x3b,(%rdi)
  je     L36
L26:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L36:
  movzbl 0x1(%rdi),%edx
  mov    %rsi,%rbp
  lea    0x1(%rdi),%rax
  test   %dl,%dl
  je     L30
  cmp    $0xa,%dl
  je     L30
  nopl   0x0(%rax)
L62:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L79
  cmp    $0xa,%dl
  jne    L62
L79:
  sub    %rdi,%rax
  mov    %rax,%rbx
  mov    %eax,%r12d
L31:
  test   %rbp,%rbp
  je     L26
  mov    %r12d,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    $0x1,%r12d
  mov    $0x1,%ebx
  jmp    L31
```

assistant: ```c
int isComment(const char *c, char *value) {
  const char *start = c;
  if (c == NULL)
    return 0;
  if (*c == ';') {
    c++;
    while (*c != '\0' && *c != '\n')
      c++;
    if (value != NULL) {
      strncpy(value, start, c - start);
      value[c - start] = '\0';
    }
    return c - start;
  } else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_rand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L35
L0:
  call   <get_rand>
  mov    %eax,-0x4(%rbp)
L35:
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L0
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L0
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L0
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get_rand(void) {
  int r;
  r = rand();
  while ((r == SIG_BLOCK) || (r == SIG_SETMASK) || (r == SIG_UNBLOCK)) {
    r = get_rand();
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_rand>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  mov    D22(%rip),%rbx
L32:
  cmp    %eax,(%rbx)
  je     L9
  mov    D2(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L9
  mov    D26(%rip),%rdx
  cmp    %eax,(%rdx)
  jne    L5
L9:
  call   <get_rand>
  jmp    L32
L5:
  pop    %rbx
  ret
```

assistant: ```c
int get_rand(void) {
  int r;
  r = rand();
  while ((r == SIG_BLOCK) || (r == SIG_SETMASK) || (r == SIG_UNBLOCK)) {
    r = get_rand();
  }
  return r;
}
```