ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<_msg_open>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    D10(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  mov    D0(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _msg_open(const char *msgfile, const char *extension) {
  char tmp[32];
  strcpy(tmp, msgfile);
  strcat(tmp, extension);
  return open(tmp, O_CREAT | O_RDWR);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_msg_open>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  mov    %rdi,%rsi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    D0(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  mov    D17(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _msg_open(const char *msgfile, const char *extension) {
  char tmp[32];
  strcpy(tmp, msgfile);
  strcat(tmp, extension);
  return open(tmp, O_CREAT | O_RDWR);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Select_Sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L38
L39:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L34
L6:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L9
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L9:
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  je     L42
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L42:
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Select_Sort(int R[], int n) {
  int i, j, k;
  int temp;
  for (i = 0; i < n; i++) {
    for (k = i, j = i + 1; j < n; j++) {
      if (R[j] < R[k])
        k = j;
    }
    if (k != i) {
      temp = R[i];
      R[i] = R[k];
      R[k] = temp;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Select_Sort>:
  endbr64
  test   %esi,%esi
  jle    L57
  mov    $0x1,%r9d
  mov    $0x0,%r8d
  jmp    L45
L8:
  mov    (%rdi,%r8,4),%ecx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r8,4)
  mov    %ecx,(%rax)
L4:
  add    $0x1,%r8
  add    $0x1,%r9
L45:
  mov    %r8d,%edx
  cmp    %r9d,%esi
  jle    L57
  mov    %r9,%rax
L1:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L1
  cmp    %r8d,%edx
  jne    L8
  jmp    L4
L57:
  ret
```

assistant: ```c
void Select_Sort(int R[], int n) {
  int i, j, k;
  int temp;
  for (i = 0; i < n; i++) {
    for (k = i, j = i + 1; j < n; j++) {
      if (R[j] < R[k])
        k = j;
    }
    if (k != i) {
      temp = R[i];
      R[i] = R[k];
      R[k] = temp;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Select_Sort>:
  endbr64
  test   %esi,%esi
  jle    L38
  mov    $0x1,%r9d
  xor    %r8d,%r8d
  mov    %r8d,%edx
  mov    %r9d,%r10d
  cmp    %esi,%r9d
  jge    L38
  nopl   0x0(%rax)
L36:
  mov    %r9,%rax
  nopl   0x0(%rax,%rax,1)
L44:
  movslq %edx,%rcx
  mov    (%rdi,%rcx,4),%ecx
  cmp    %ecx,(%rdi,%rax,4)
  cmovl  %eax,%edx
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L44
  cmp    %r8d,%edx
  je     L6
  movslq %edx,%rdx
  mov    (%rdi,%r8,4),%ecx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rdi,%r8,4)
  mov    %ecx,(%rax)
  cmp    %esi,%r10d
  jge    L38
L6:
  add    $0x1,%r8
  add    $0x1,%r9
  mov    %r8d,%edx
  mov    %r9d,%r10d
  cmp    %esi,%r9d
  jl     L36
L38:
  ret
```

assistant: ```c
void Select_Sort(int R[], int n) {
  int i, j, k;
  int temp;
  for (i = 0; i < n; i++) {
    for (k = i, j = i + 1; j < n; j++) {
      if (R[j] < R[k])
        k = j;
    }
    if (k != i) {
      temp = R[i];
      R[i] = R[k];
      R[k] = temp;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Select_Sort>:
  endbr64
  test   %esi,%esi
  jle    L73
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  lea    0x1(%rbp),%r11d
  push   %rbx
  lea    0x4(%rdi),%rbx
  cmp    %r11d,%esi
  jle    L47
  nop
L13:
  mov    -0x4(%rbx),%r12d
  mov    %rbx,%rax
  mov    %ebp,%r10d
  mov    %r11d,%edx
  mov    %r12d,%r8d
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L86:
  movslq %r10d,%rcx
  add    $0x1,%edx
  add    $0x4,%rax
  lea    (%rdi,%rcx,4),%r9
  cmp    %edx,%esi
  je     L42
L4:
  mov    (%rax),%ecx
  mov    %rax,%r9
  cmp    %r8d,%ecx
  jge    L86
  mov    %edx,%r10d
  add    $0x1,%edx
  mov    %ecx,%r8d
  add    $0x4,%rax
  cmp    %edx,%esi
  jne    L4
L42:
  cmp    %ebp,%r10d
  je     L51
  mov    %r8d,-0x4(%rbx)
  mov    %r12d,(%r9)
  cmp    %r11d,%esi
  jle    L47
L51:
  mov    %r11d,%ebp
  add    $0x4,%rbx
  lea    0x1(%rbp),%r11d
  cmp    %r11d,%esi
  jg     L13
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  ret
```

assistant: ```c
void Select_Sort(int R[], int n) {
  int i, j, k;
  int temp;
  for (i = 0; i < n; i++) {
    for (k = i, j = i + 1; j < n; j++) {
      if (R[j] < R[k])
        k = j;
    }
    if (k != i) {
      temp = R[i];
      R[i] = R[k];
      R[k] = temp;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x8000(%rsp),%r11
L113:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L113
  sub    $0x50,%rsp
  mov    %rdi,-0x8038(%rbp)
  mov    %rsi,-0x8040(%rbp)
  mov    %edx,%eax
  mov    %al,-0x8044(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x8028(%rbp)
  movl   $0x0,-0x8024(%rbp)
  mov    -0x8038(%rbp),%rax
  mov    %rax,-0x8020(%rbp)
  jmp    L53
L27:
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  je     L0
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L65
L0:
  cmpl   $0x0,-0x8028(%rbp)
  js     L115
  mov    -0x8028(%rbp),%eax
  cltq
  movzbl -0x8010(%rbp,%rax,1),%edx
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L98
  subl   $0x1,-0x8028(%rbp)
  jmp    L65
L98:
  addl   $0x1,-0x8028(%rbp)
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8028(%rbp),%eax
  cltq
  mov    %dl,-0x8010(%rbp,%rax,1)
  jmp    L65
L115:
  addl   $0x1,-0x8028(%rbp)
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8028(%rbp),%eax
  cltq
  mov    %dl,-0x8010(%rbp,%rax,1)
L65:
  cmpl   $0x0,-0x8028(%rbp)
  jns    L138
  mov    -0x8040(%rbp),%rax
  mov    %rax,-0x8018(%rbp)
  jmp    L55
L91:
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8018(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L132
  mov    -0x8020(%rbp),%rax
  movzbl -0x8044(%rbp),%edx
  mov    %dl,(%rax)
  movl   $0x1,-0x8024(%rbp)
L132:
  addq   $0x1,-0x8018(%rbp)
L55:
  mov    -0x8018(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L91
L138:
  addq   $0x1,-0x8020(%rbp)
L53:
  mov    -0x8020(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    -0x8024(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
int remove_chars(char *s, char *r, char replace) {
  int inquote = -1;
  int retval = 0;
  char quotes[(4 * 8192)];
  char *p, *q;
  for (p = s; *p; p++) {
    if (*p == '\'' || *p == '"') {
      if (inquote >= 0) {
        if (quotes[inquote] == *p) {
          inquote--;
        } else {
          inquote++;
          quotes[inquote] = *p;
        }
      } else {
        inquote++;
        quotes[inquote] = *p;
      }
    }
    if (inquote < 0) {
      for (q = r; *q; q++) {
        if (*p == *q) {
          *p = replace;
          retval = 1;
        }
      }
    }
  }
  return (retval);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<remove_chars>:
  endbr64
  lea    -0x8000(%rsp),%r11
L75:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L75
  sub    $0x18,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,0x8008(%rsp)
  xor    %ecx,%ecx
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L23
  mov    %rdi,%rax
  mov    $0x0,%r9d
  mov    $0xffffffff,%r8d
  mov    $0x1,%r10d
  jmp    L161
L133:
  sub    $0x1,%r8d
  jmp    L111
L22:
  add    $0x1,%r8d
  movslq %r8d,%rdi
  mov    %cl,(%rsp,%rdi,1)
L111:
  test   %r8d,%r8d
  js     L110
L70:
  add    $0x1,%rax
  movzbl (%rax),%ecx
  test   %cl,%cl
  je     L169
L161:
  cmp    $0x27,%cl
  je     L85
  cmp    $0x22,%cl
  jne    L111
L85:
  test   %r8d,%r8d
  js     L22
  movslq %r8d,%rdi
  cmp    %cl,(%rsp,%rdi,1)
  je     L133
  add    $0x1,%r8d
  movslq %r8d,%rdi
  mov    %cl,(%rsp,%rdi,1)
  jmp    L70
L110:
  movzbl (%rsi),%ecx
  test   %cl,%cl
  je     L70
  mov    %rsi,%rdi
  jmp    L55
L48:
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L70
L55:
  cmp    %cl,(%rax)
  jne    L48
  mov    %dl,(%rax)
  mov    %r10d,%r9d
  jmp    L48
L23:
  mov    $0x0,%r9d
L169:
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L122
  mov    %r9d,%eax
  add    $0x8018,%rsp
  ret
L122:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int remove_chars(char *s, char *r, char replace) {
  int inquote = -1;
  int retval = 0;
  char quotes[(4 * 8192)];
  char *p, *q;
  for (p = s; *p; p++) {
    if (*p == '\'' || *p == '"') {
      if (inquote >= 0) {
        if (quotes[inquote] == *p) {
          inquote--;
        } else {
          inquote++;
          quotes[inquote] = *p;
        }
      } else {
        inquote++;
        quotes[inquote] = *p;
      }
    }
    if (inquote < 0) {
      for (q = r; *q; q++) {
        if (*p == *q) {
          *p = replace;
          retval = 1;
        }
      }
    }
  }
  return (retval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<remove_chars>:
  endbr64
  lea    -0x8000(%rsp),%r11
L55:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L55
  sub    $0x18,%rsp
  xor    %r9d,%r9d
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L114
  mov    $0xffffffff,%r8d
  jmp    L143
  cs nopw 0x0(%rax,%rax,1)
L118:
  cmp    $0xffffffff,%r8d
  je     L30
L93:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L114
L143:
  cmp    $0x27,%al
  je     L133
  cmp    $0x22,%al
  jne    L118
L133:
  cmp    $0xffffffff,%r8d
  je     L56
  movslq %r8d,%rcx
  cmp    %al,(%rsp,%rcx,1)
  je     L136
  add    $0x1,%r8d
  add    $0x1,%rdi
  movslq %r8d,%rcx
  mov    %al,(%rsp,%rcx,1)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L143
  nopl   (%rax)
L114:
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  mov    %r9d,%eax
  add    $0x8018,%rsp
  ret
  xchg   %ax,%ax
L56:
  mov    %al,(%rsp)
  xor    %r8d,%r8d
  jmp    L93
  nopl   0x0(%rax,%rax,1)
L30:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L93
  mov    %rsi,%rcx
  nopw   0x0(%rax,%rax,1)
L91:
  cmp    %al,(%rdi)
  jne    L87
  mov    %dl,(%rdi)
  mov    $0x1,%r9d
L87:
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  jne    L91
  jmp    L93
  nopl   (%rax)
L136:
  sub    $0x1,%r8d
  jmp    L118
L65:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int remove_chars(char *s, char *r, char replace) {
  int inquote = -1;
  int retval = 0;
  char quotes[(4 * 8192)];
  char *p, *q;
  for (p = s; *p; p++) {
    if (*p == '\'' || *p == '"') {
      if (inquote >= 0) {
        if (quotes[inquote] == *p) {
          inquote--;
        } else {
          inquote++;
          quotes[inquote] = *p;
        }
      } else {
        inquote++;
        quotes[inquote] = *p;
      }
    }
    if (inquote < 0) {
      for (q = r; *q; q++) {
        if (*p == *q) {
          *p = replace;
          retval = 1;
        }
      }
    }
  }
  return (retval);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<remove_chars>:
  endbr64
  lea    -0x8000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x18,%rsp
  xor    %r10d,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x8008(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %al,%al
  je     L147
  mov    $0xffffffff,%r8d
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    $0xffffffff,%r8d
  je     L170
L45:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L147
L6:
  cmp    $0x27,%al
  je     L173
  cmp    $0x22,%al
  jne    L7
L173:
  cmp    $0xffffffff,%r8d
  je     L111
  movslq %r8d,%rcx
  cmp    %al,(%rsp,%rcx,1)
  je     L155
  add    $0x1,%r8d
  add    $0x1,%rdi
  movslq %r8d,%rcx
  mov    %al,(%rsp,%rcx,1)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
  nopl   0x0(%rax)
L147:
  mov    0x8008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %r10d,%eax
  add    $0x8018,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L111:
  mov    %al,(%rsp)
  xor    %r8d,%r8d
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L170:
  movzbl (%rsi),%eax
  test   %al,%al
  je     L45
  movzbl (%rdi),%r9d
  mov    %rsi,%rcx
L48:
  cmp    %al,%r9b
  je     L87
L130:
  movzbl 0x1(%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L45
  cmp    %al,%r9b
  jne    L130
L87:
  add    $0x1,%rcx
  mov    %dl,(%rdi)
  movzbl (%rcx),%eax
  test   %al,%al
  je     L182
  mov    %edx,%r9d
  mov    $0x1,%r10d
  jmp    L48
  nopl   0x0(%rax)
L155:
  sub    $0x1,%r8d
  jmp    L7
  nopl   0x0(%rax)
L182:
  mov    $0x1,%r10d
  jmp    L45
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int remove_chars(char *s, char *r, char replace) {
  int inquote = -1;
  int retval = 0;
  char quotes[(4 * 8192)];
  char *p, *q;
  for (p = s; *p; p++) {
    if (*p == '\'' || *p == '"') {
      if (inquote >= 0) {
        if (quotes[inquote] == *p) {
          inquote--;
        } else {
          inquote++;
          quotes[inquote] = *p;
        }
      } else {
        inquote++;
        quotes[inquote] = *p;
      }
    }
    if (inquote < 0) {
      for (q = r; *q; q++) {
        if (*p == *q) {
          *p = replace;
          retval = 1;
        }
      }
    }
  }
  return (retval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getPositiveFloat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetFloat@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comiss -0x8(%rbp),%xmm0
  ja     L7
  movss  -0x8(%rbp),%xmm1
  movss  D29(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <roundf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D25
type_infered: string
name: read_data
arguments: data_tag: D29
type_infered: byte[4]

tool: D10: O hai! 

tool: D25: How much change is owed?


tool: {"D29": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int getPositiveFloat(void) {
  float n;
  printf("O hai! ");
  do {
    printf("How much change is owed?\n");
    n = GetFloat();
  } while (n < 0);
  n = n * 100;
  int posInt = (int)roundf(n);
  return posInt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getPositiveFloat>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rbx
L6:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetFloat@plt>
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L6
  mulss  D14(%rip),%xmm0
  call   <roundf@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type: string
name: extract_symbolic_data
arguments: data_tag: D18
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: byte[4]

tool: D7: O hai! 

tool: D18: How much change is owed?


tool: {"D14": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int getPositiveFloat(void) {
  float n;
  printf("O hai! ");
  do {
    printf("How much change is owed?\n");
    n = GetFloat();
  } while (n < 0);
  n = n * 100;
  int posInt = (int)roundf(n);
  return posInt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getPositiveFloat>:
  endbr64
  push   %rbx
  lea    D19(%rip),%rdi
  lea    D27(%rip),%rbx
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetFloat@plt>
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L1
  mulss  D5(%rip),%xmm0
  call   <roundf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D27
data_type: string
name: disassemble_data
arguments: tag: D5
data_type: byte[4]

tool: D19: O hai! 

tool: D27: How much change is owed?


tool: {"D5": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int getPositiveFloat(void) {
  float n;
  printf("O hai! ");
  do {
    printf("How much change is owed?\n");
    n = GetFloat();
  } while (n < 0);
  n = n * 100;
  int posInt = (int)roundf(n);
  return posInt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getPositiveFloat>:
  endbr64
  push   %rbx
  lea    D28(%rip),%rdi
  lea    D15(%rip),%rbx
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetFloat@plt>
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L1
  mulss  D14(%rip),%xmm0
  call   <roundf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: byte[4]

tool: D28: O hai! 

tool: D15: How much change is owed?


tool: {"D14": [0x00,0x00,0xc8,0x42]}

assistant: ```c
int getPositiveFloat(void) {
  float n;
  printf("O hai! ");
  do {
    printf("How much change is owed?\n");
    n = GetFloat();
  } while (n < 0);
  n = n * 100;
  int posInt = (int)roundf(n);
  return posInt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L18
L7:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L38:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L2:
  cmpl   $0x2,-0x14(%rbp)
  jle    L38
  addl   $0x1,-0x18(%rbp)
L18:
  cmpl   $0x6,-0x18(%rbp)
  jle    L7
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string

tool: D21: dnanvariancetk

tool: D13: # c::%s:len=%d


tool: D23: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanvariancetk", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D8(%rip),%r15
  jmp    L29
L11:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L27
L29:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L20:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L20
  jmp    L11
L27:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D24
datatype: string

tool: D8: dnanvariancetk

tool: D0: # c::%s:len=%d


tool: D24: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dnanvariancetk", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```