ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<xawrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %edx,%ebx
  test   %edx,%edx
  je     L14
L13:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xwrite@plt>
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L13
L14:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xawrite(int fd, const void *buf, size_t count) {
  int nwritten, remain;
  for (remain = count; remain; remain -= nwritten)
    buf += (nwritten = xwrite(fd, buf, remain));
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xawrite>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L15
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  nopl   (%rax)
L6:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xwrite@plt>
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L6
L15:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xawrite(int fd, const void *buf, size_t count) {
  int nwritten, remain;
  for (remain = count; remain; remain -= nwritten)
    buf += (nwritten = xwrite(fd, buf, remain));
  return count;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xawrite>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  je     L1
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  nopl   (%rax)
L9:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <xwrite@plt>
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  jne    L9
L1:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t xawrite(int fd, const void *buf, size_t count) {
  int nwritten, remain;
  for (remain = count; remain; remain -= nwritten)
    buf += (nwritten = xwrite(fd, buf, remain));
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<OSDQuery>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int OSDQuery(int dev) {
  osd_cmd_t dc;
  dc.cmd = OSD_Query;
  return ioctl(dev, OSD_SEND_CMD, &dc);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<OSDQuery>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int OSDQuery(int dev) {
  osd_cmd_t dc;
  dc.cmd = OSD_Query;
  return ioctl(dev, OSD_SEND_CMD, &dc);
}
```
user: Translate the below assembly code into C programming language:

```asm
<OSDQuery>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D0(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int OSDQuery(int dev) {
  osd_cmd_t dc;
  dc.cmd = OSD_Query;
  return ioctl(dev, OSD_SEND_CMD, &dc);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<OSDQuery>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D2(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%eax
  mov    %eax,0x4(%rsp)
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int OSDQuery(int dev) {
  osd_cmd_t dc;
  dc.cmd = OSD_Query;
  return ioctl(dev, OSD_SEND_CMD, &dc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <lenum@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <lenum@plt>
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  lea    -0xc(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <verificamaior@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D4: Maior numero e: %d

assistant: ```c
main() {
  int num1, num2, maior;
  lenum(&num1);
  lenum(&num2);
  verificamaior(num1, num2, &maior);
  printf("Maior numero e: %d", maior);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <lenum@plt>
  lea    0x10(%rsp),%rdi
  call   <lenum@plt>
  lea    0x14(%rsp),%rdx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <verificamaior@plt>
  mov    0x14(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
datatype: string

tool: D3: Maior numero e: %d

assistant: ```c
main() {
  int num1, num2, maior;
  lenum(&num1);
  lenum(&num2);
  verificamaior(num1, num2, &maior);
  printf("Maior numero e: %d", maior);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <lenum@plt>
  lea    0x10(%rsp),%rdi
  call   <lenum@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  lea    0x14(%rsp),%rdx
  call   <verificamaior@plt>
  mov    0x14(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: Maior numero e: %d

assistant: ```c
main() {
  int num1, num2, maior;
  lenum(&num1);
  lenum(&num2);
  verificamaior(num1, num2, &maior);
  printf("Maior numero e: %d", maior);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <lenum@plt>
  lea    0x10(%rsp),%rdi
  call   <lenum@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  lea    0x14(%rsp),%rdx
  call   <verificamaior@plt>
  mov    0x14(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D7: Maior numero e: %d

assistant: ```c
main() {
  int num1, num2, maior;
  lenum(&num1);
  lenum(&num2);
  verificamaior(num1, num2, &maior);
  printf("Maior numero e: %d", maior);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strrchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L22
L1:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L22
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L15
  mov    -0x8(%rbp),%rax
  jmp    L41
L15:
  mov    -0x10(%rbp),%rax
L41:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strrchr(const char *str, int c) {
  char *result;
  char *tail;
  result = NULL;
  tail = (char *)str;
  while (*tail)
    if (*tail++ == c)
      result = tail - 1;
  if (*tail == c)
    return (tail);
  return (result);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strrchr>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
  mov    $0x0,%edx
L4:
  mov    %rdi,%rcx
  add    $0x1,%rdi
  movsbl %al,%eax
  cmp    %esi,%eax
  cmove  %rcx,%rdx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
L27:
  test   %esi,%esi
  cmove  %rdi,%rdx
  mov    %rdx,%rax
  ret
L23:
  mov    $0x0,%edx
  jmp    L27
```

assistant: ```c
char *ft_strrchr(const char *str, int c) {
  char *result;
  char *tail;
  result = NULL;
  tail = (char *)str;
  while (*tail)
    if (*tail++ == c)
      result = tail - 1;
  if (*tail == c)
    return (tail);
  return (result);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strrchr>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L16
  xchg   %ax,%ax
L14:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  cmp    %esi,%eax
  movsbl (%rdi),%eax
  cmove  %rdx,%r8
  test   %al,%al
  jne    L14
L16:
  test   %esi,%esi
  cmove  %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strrchr(const char *str, int c) {
  char *result;
  char *tail;
  result = NULL;
  tail = (char *)str;
  while (*tail)
    if (*tail++ == c)
      result = tail - 1;
  if (*tail == c)
    return (tail);
  return (result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_strrchr>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L19
  xchg   %ax,%ax
L15:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  cmp    %eax,%esi
  movsbl (%rdi),%eax
  cmove  %rdx,%r8
  test   %al,%al
  jne    L15
L19:
  test   %esi,%esi
  cmove  %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strrchr(const char *str, int c) {
  char *result;
  char *tail;
  result = NULL;
  tail = (char *)str;
  while (*tail)
    if (*tail++ == c)
      result = tail - 1;
  if (*tail == c)
    return (tail);
  return (result);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<callback>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L2
L13:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: %.2f 

assistant: ```c
void callback(double *x, size_t xlen) {
  size_t i;
  for (i = 0; i < xlen; i++) {
    printf("%.2f ", x[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<callback>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L2
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L0:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L0
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: %.2f 

assistant: ```c
void callback(double *x, size_t xlen) {
  size_t i;
  for (i = 0; i < xlen; i++) {
    printf("%.2f ", x[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<callback>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L18:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L18
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: %.2f 

assistant: ```c
void callback(double *x, size_t xlen) {
  size_t i;
  for (i = 0; i < xlen; i++) {
    printf("%.2f ", x[i]);
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<callback>:
  endbr64
  test   %rsi,%rsi
  je     L0
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L8:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L8
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: %.2f 

assistant: ```c
void callback(double *x, size_t xlen) {
  size_t i;
  for (i = 0; i < xlen; i++) {
    printf("%.2f ", x[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cox_deboor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x1,%eax
  call   <find_span@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x18(%rbp),%edx
  sub    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  mov    -0x18(%rbp),%edx
  sub    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%esi
  mov    -0x18(%rbp),%edi
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <cox_deboor_i@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double cox_deboor(unsigned int n, unsigned int p, const double t[n + 1], const double v[n + 1 - p], double x) {
  int i = find_span(n, t, x);
  return cox_deboor_i(x, p, p, t + i - p, v + i - p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cox_deboor>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %rdx,%rbx
  mov    %rcx,%r12
  movq   %xmm0,%r13
  mov    %rdx,%rsi
  mov    $0x1,%eax
  call   <find_span@plt>
  cltq
  mov    %ebp,%edx
  sub    %rdx,%rax
  shl    $0x3,%rax
  lea    (%r12,%rax,1),%rcx
  lea    (%rbx,%rax,1),%rdx
  mov    %ebp,%esi
  mov    %ebp,%edi
  movq   %r13,%xmm0
  mov    $0x1,%eax
  call   <cox_deboor_i@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double cox_deboor(unsigned int n, unsigned int p, const double t[n + 1], const double v[n + 1 - p], double x) {
  int i = find_span(n, t, x);
  return cox_deboor_i(x, p, p, t + i - p, v + i - p);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cox_deboor>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  mov    %esi,%r12d
  mov    %rdx,%rsi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <find_span@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  cltq
  movsd  0x8(%rsp),%xmm0
  sub    %rdx,%rax
  shl    $0x3,%rax
  lea    0x0(%rbp,%rax,1),%rcx
  lea    (%rbx,%rax,1),%rdx
  mov    $0x1,%eax
  call   <cox_deboor_i@plt>
  add    $0x10,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double cox_deboor(unsigned int n, unsigned int p, const double t[n + 1], const double v[n + 1 - p], double x) {
  int i = find_span(n, t, x);
  return cox_deboor_i(x, p, p, t + i - p, v + i - p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cox_deboor>:
  endbr64
  push   %r12
  mov    $0x1,%eax
  mov    %esi,%r12d
  mov    %rdx,%rsi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <find_span@plt>
  mov    %r12d,%edx
  mov    %r12d,%esi
  mov    %r12d,%edi
  cltq
  movsd  0x8(%rsp),%xmm0
  sub    %rdx,%rax
  shl    $0x3,%rax
  lea    0x0(%rbp,%rax,1),%rcx
  lea    (%rbx,%rax,1),%rdx
  mov    $0x1,%eax
  call   <cox_deboor_i@plt>
  add    $0x10,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double cox_deboor(unsigned int n, unsigned int p, const double t[n + 1], const double v[n + 1 - p], double x) {
  int i = find_span(n, t, x);
  return cox_deboor_i(x, p, p, t + i - p, v + i - p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_testd2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  movsd  %xmm2,-0x48(%rbp)
  movsd  %xmm3,-0x50(%rbp)
  movsd  %xmm4,-0x58(%rbp)
  movsd  %xmm5,-0x60(%rbp)
  movsd  %xmm6,-0x68(%rbp)
  movsd  %xmm7,-0x70(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  -0x40(%rbp),%xmm0
  cvttsd2si %xmm0,%rdx
  movsd  -0x38(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  movsd  -0x50(%rbp),%xmm0
  mov    -0x48(%rbp),%rcx
  movapd %xmm0,%xmm1
  movq   %rcx,%xmm0
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  -0x60(%rbp),%xmm0
  cvttsd2si %xmm0,%rdx
  movsd  -0x58(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  movsd  -0x70(%rbp),%xmm0
  mov    -0x68(%rbp),%rcx
  movapd %xmm0,%xmm1
  movq   %rcx,%xmm0
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  movsd  0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rdx
  movsd  0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    0x20(%rbp),%rcx
  movq   %rcx,%xmm0
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x30(%rbp),%rdx
  mov    0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D36(%rip),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D52
type_infered: string
name: unpack_data
arguments: data_label: D36
type_infered: f64

tool: D27: %ld %ld %ld


tool: D26: %lf %lf %lf %lf


tool: D20: %lf %lf %lf


tool: D52: %ld %ld


tool: D36: 1.23456

assistant: ```c
double test_testd2(long i0, long i1, long i2, long i3, long i4, long i5, double d0, double d1, double d2, double d3, double d4, double d5, double d6, double d7, double d8, double d9, double d10, long i6, long i7) {
  printf("%ld %ld %ld\n", i0, i1, i2);
  printf("%ld %ld %ld\n", i3, i4, i5);
  printf("%lf %lf %lf %lf\n", d0, d1, d2, d3);
  printf("%lf %lf %lf %lf\n", d4, d5, d6, d7);
  printf("%lf %lf %lf\n", d8, d9, d10);
  printf("%ld %ld\n", i6, i7);
  return 1.23456;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_testd2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,0x10(%rsp)
  movq   %xmm3,%rbp
  movsd  %xmm4,0x18(%rsp)
  movsd  %xmm5,0x20(%rsp)
  movsd  %xmm6,0x28(%rsp)
  movq   %xmm7,%rbx
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  mov    %rdi,%rsi
  lea    D25(%rip),%r15
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cvttsd2si 0x8(%rsp),%rdx
  cvttsd2si (%rsp),%rsi
  movq   %rbp,%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D31(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  cvttsd2si 0x20(%rsp),%rdx
  cvttsd2si 0x18(%rsp),%rsi
  movq   %rbx,%xmm1
  movsd  0x28(%rsp),%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  cvttsd2si 0x78(%rsp),%rdx
  cvttsd2si 0x70(%rsp),%rsi
  movsd  0x80(%rsp),%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x90(%rsp),%rdx
  mov    0x88(%rsp),%rsi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D7(%rip),%xmm0
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D25
type_guessed: string
name: unpack_data
arguments: data_label: D31
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string
name: unpack_data
arguments: data_label: D45
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: f64

tool: D25: %ld %ld %ld


tool: D31: %lf %lf %lf %lf


tool: D3: %lf %lf %lf


tool: D45: %ld %ld


tool: D7: 1.23456

assistant: ```c
double test_testd2(long i0, long i1, long i2, long i3, long i4, long i5, double d0, double d1, double d2, double d3, double d4, double d5, double d6, double d7, double d8, double d9, double d10, long i6, long i7) {
  printf("%ld %ld %ld\n", i0, i1, i2);
  printf("%ld %ld %ld\n", i3, i4, i5);
  printf("%lf %lf %lf %lf\n", d0, d1, d2, d3);
  printf("%lf %lf %lf %lf\n", d4, d5, d6, d7);
  printf("%lf %lf %lf\n", d8, d9, d10);
  printf("%ld %ld\n", i6, i7);
  return 1.23456;
}
```