ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<setDbgLevel>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  je     L9
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
L28:
  pop    %rbx
  ret
L9:
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  mov    $0x2,%edx
  lea    D17(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L18
  mov    0x8(%rbx),%rdi
  call   <isaHexNum@plt>
  test   %eax,%eax
  je     L31
  mov    0x8(%rbx),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L28
L18:
  mov    (%rbx),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  jmp    L28
L31:
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  jmp    L28
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D17
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string
name: retrieve_data
arguments: label: D35
type_infered: string

tool: D0: Parm Error: single 'debugLevel' parameter required

tool: D17: -h

tool: D13: New debug mask is:0x%lx


tool: D2: Usage:  %-10s 

tool: D15: <hex debug mask>


tool: D35: Parm Error: Invalid debugLevel

assistant: ```c
int setDbgLevel(int argc, char **argv) {
  {
    if ((argc == 2) && (strncmp(argv[1], "-h", 2) == 0)) {
      printf("Usage:  %-10s ", argv[0]);
      printf("%s\n", "<hex debug mask>\n");
      return (0);
    }
  };
  if (argc != 2) {
    printf("Parm Error: single 'debugLevel' parameter required\n");
    return (0);
  }
  if (!(isaHexNum(argv[1]))) {
    printf("Parm Error: Invalid debugLevel\n");
    return (-1);
  }
  printf("New debug mask is:0x%lx\n", strtoul((argv[1]), NULL, 16));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<setDbgLevel>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  je     L14
  lea    D36(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  mov    $0x2,%edx
  lea    D50(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L20
  mov    0x8(%rbx),%rdi
  call   <isaHexNum@plt>
  test   %eax,%eax
  je     L24
  mov    0x8(%rbx),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    D31(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nop
L20:
  mov    (%rbx),%rsi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L24:
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D36
type_infered: string
name: unpack_data
arguments: tag: D50
type_infered: string
name: unpack_data
arguments: tag: D31
type_infered: string
name: unpack_data
arguments: tag: D54
type_infered: string
name: unpack_data
arguments: tag: D4
type_infered: string
name: unpack_data
arguments: tag: D45
type_infered: string

tool: D36: Parm Error: single 'debugLevel' parameter required

tool: D50: -h

tool: D31: New debug mask is:0x%lx


tool: D54: Usage:  %-10s 

tool: D4: <hex debug mask>


tool: D45: Parm Error: Invalid debugLevel

assistant: ```c
int setDbgLevel(int argc, char **argv) {
  {
    if ((argc == 2) && (strncmp(argv[1], "-h", 2) == 0)) {
      printf("Usage:  %-10s ", argv[0]);
      printf("%s\n", "<hex debug mask>\n");
      return (0);
    }
  };
  if (argc != 2) {
    printf("Parm Error: single 'debugLevel' parameter required\n");
    return (0);
  }
  if (!(isaHexNum(argv[1]))) {
    printf("Parm Error: Invalid debugLevel\n");
    return (-1);
  }
  printf("New debug mask is:0x%lx\n", strtoul((argv[1]), NULL, 16));
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setDbgLevel>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  je     L17
  lea    D52(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  mov    $0x2,%edx
  lea    D12(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L18
  mov    0x8(%rbx),%rdi
  call   <isaHexNum@plt>
  test   %eax,%eax
  je     L15
  mov    0x8(%rbx),%rdi
  mov    $0x10,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    D17(%rip),%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
  nop
L18:
  mov    (%rbx),%rsi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L15:
  lea    D42(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D52
data_type: string
name: unpack_data
arguments: label: D12
data_type: string
name: unpack_data
arguments: label: D17
data_type: string
name: unpack_data
arguments: label: D49
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D42
data_type: string

tool: D52: Parm Error: single 'debugLevel' parameter required

tool: D12: -h

tool: D17: New debug mask is:0x%lx


tool: D49: Usage:  %-10s 

tool: D21: <hex debug mask>


tool: D42: Parm Error: Invalid debugLevel

assistant: ```c
int setDbgLevel(int argc, char **argv) {
  {
    if ((argc == 2) && (strncmp(argv[1], "-h", 2) == 0)) {
      printf("Usage:  %-10s ", argv[0]);
      printf("%s\n", "<hex debug mask>\n");
      return (0);
    }
  };
  if (argc != 2) {
    printf("Parm Error: single 'debugLevel' parameter required\n");
    return (0);
  }
  if (!(isaHexNum(argv[1]))) {
    printf("Parm Error: Invalid debugLevel\n");
    return (-1);
  }
  printf("New debug mask is:0x%lx\n", strtoul((argv[1]), NULL, 16));
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<startup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0xd,%edi
  call   <led_init@plt>
L10:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L4:
  mov    $0x0,%eax
  call   <led_on@plt>
  mov    $0x0,%eax
  call   <delay@plt>
  mov    $0x0,%eax
  call   <led_off@plt>
  mov    $0x0,%eax
  call   <delay@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x4,-0x4(%rbp)
  jle    L4
  mov    $0x0,%eax
  call   <big_delay@plt>
  jmp    L10
```

assistant: ```c
void startup(void) {
  int i;
  led_init(13);
  for (;;) {
    for (i = 0; i < 5; i++) {
      led_on();
      delay();
      led_off();
      delay();
    }
    big_delay();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<startup>:
  endbr64
  push   %rbx
  mov    $0xd,%edi
  call   <led_init@plt>
  jmp    L6
L23:
  mov    $0x0,%eax
  call   <big_delay@plt>
L6:
  mov    $0x5,%ebx
L19:
  mov    $0x0,%eax
  call   <led_on@plt>
  mov    $0x0,%eax
  call   <delay@plt>
  mov    $0x0,%eax
  call   <led_off@plt>
  mov    $0x0,%eax
  call   <delay@plt>
  sub    $0x1,%ebx
  jne    L19
  jmp    L23
```

assistant: ```c
void startup(void) {
  int i;
  led_init(13);
  for (;;) {
    for (i = 0; i < 5; i++) {
      led_on();
      delay();
      led_off();
      delay();
    }
    big_delay();
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<startup>:
  endbr64
  push   %rbx
  mov    $0xd,%edi
  call   <led_init@plt>
  nop
L15:
  mov    $0x5,%ebx
L2:
  xor    %eax,%eax
  call   <led_on@plt>
  xor    %eax,%eax
  call   <delay@plt>
  xor    %eax,%eax
  call   <led_off@plt>
  xor    %eax,%eax
  call   <delay@plt>
  sub    $0x1,%ebx
  jne    L2
  xor    %eax,%eax
  call   <big_delay@plt>
  jmp    L15
```

assistant: ```c
void startup(void) {
  int i;
  led_init(13);
  for (;;) {
    for (i = 0; i < 5; i++) {
      led_on();
      delay();
      led_off();
      delay();
    }
    big_delay();
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<startup>:
  endbr64
  push   %rbx
  mov    $0xd,%edi
  call   <led_init@plt>
  nop
L15:
  mov    $0x5,%ebx
L19:
  xor    %eax,%eax
  call   <led_on@plt>
  xor    %eax,%eax
  call   <delay@plt>
  xor    %eax,%eax
  call   <led_off@plt>
  xor    %eax,%eax
  call   <delay@plt>
  sub    $0x1,%ebx
  jne    L19
  xor    %eax,%eax
  call   <big_delay@plt>
  jmp    L15
```

assistant: ```c
void startup(void) {
  int i;
  led_init(13);
  for (;;) {
    for (i = 0; i < 5; i++) {
      led_on();
      delay();
      led_off();
      delay();
    }
    big_delay();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jle    L25
  mov    $0x0,%eax
  jmp    L42
L25:
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L39:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L38
  mov    $0x0,%eax
  jmp    L42
L38:
  addl   $0x1,-0x14(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  mov    $0x1,%eax
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned int _starts_with(char *str, char *n) {
  int i;
  if (strlen(n) > strlen(str))
    return 0;
  for (i = 0; *(n + i) != '\0'; i++)
    if (*(n + i) != *(str + i))
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rdx,%r12
  jg     L9
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L12
  mov    $0x0,%eax
L25:
  cmp    %dl,0x0(%rbp,%rax,1)
  jne    L40
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  jne    L25
  mov    $0x1,%eax
  jmp    L9
L12:
  mov    $0x1,%eax
  jmp    L9
L40:
  mov    $0x0,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int _starts_with(char *str, char *n) {
  int i;
  if (strlen(n) > strlen(str))
    return 0;
  for (i = 0; *(n + i) != '\0'; i++)
    if (*(n + i) != *(str + i))
      return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%r12
  jg     L41
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L29
  xor    %eax,%eax
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L29
L7:
  cmp    %dl,0x0(%rbp,%rax,1)
  je     L0
  xor    %eax,%eax
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L29:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int _starts_with(char *str, char *n) {
  int i;
  if (strlen(n) > strlen(str))
    return 0;
  for (i = 0; *(n + i) != '\0'; i++)
    if (*(n + i) != *(str + i))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_starts_with>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %r8,%r12
  jg     L10
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L25
  xor    %eax,%eax
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L31:
  add    $0x1,%rax
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L25
L21:
  cmp    %dl,0x0(%rbp,%rax,1)
  je     L31
  xor    %eax,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int _starts_with(char *str, char *n) {
  int i;
  if (strlen(n) > strlen(str))
    return 0;
  for (i = 0; *(n + i) != '\0'; i++)
    if (*(n + i) != *(str + i))
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mnem_call>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <outstr@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string

tool: D0: CALL 

assistant: ```c
mnem_call(sname) char *sname;
{
  ot("CALL ");
  outstr(sname);
  nl();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mnem_call>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <ot@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <outstr@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: CALL 

assistant: ```c
mnem_call(sname) char *sname;
{
  ot("CALL ");
  outstr(sname);
  nl();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mnem_call>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  call   <ot@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <outstr@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1080 <nl@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: CALL 

assistant: ```c
mnem_call(sname) char *sname;
{
  ot("CALL ");
  outstr(sname);
  nl();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mnem_call>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <ot@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <outstr@plt>
  xor    %eax,%eax
  pop    %rbp
  jmp    1080 <nl@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: CALL 

assistant: ```c
mnem_call(sname) char *sname;
{
  ot("CALL ");
  outstr(sname);
  nl();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<step>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L66:
  cmpq   $0x989680,-0x8(%rbp)
  jg     L5
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L5
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L34
L5:
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L47
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L47:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x8(%rbp)
L14:
  addl   $0x1,-0xc(%rbp)
L38:
  cmpq   $0x1,-0x8(%rbp)
  jne    L66
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int step(long long num, int *t) {
  long long n = num;
  int nt, i = 0;
  while (n != 1) {
    if (n <= 10000000 && t[n] != -1) {
      t[num] = t[n] + i;
      return t[num];
    }
    if (n % 2)
      n = (n * 3) + 1;
    else
      n /= 2;
    i++;
  }
  t[num] = i + 1;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<step>:
  endbr64
  cmp    $0x1,%rdi
  je     L8
  mov    %rdi,%rax
  mov    $0x0,%edx
  jmp    L60
L59:
  test   $0x1,%al
  je     L52
  lea    0x1(%rax,%rax,2),%rax
L25:
  add    $0x1,%edx
  cmp    $0x1,%rax
  je     L29
L60:
  cmp    $0x989680,%rax
  jg     L59
  mov    (%rsi,%rax,4),%ecx
  cmp    $0xffffffff,%ecx
  je     L59
  add    %ecx,%edx
  mov    %edx,(%rsi,%rdi,4)
  jmp    L24
L52:
  mov    %rax,%rcx
  shr    $0x3f,%rcx
  add    %rcx,%rax
  sar    %rax
  jmp    L25
L8:
  mov    $0x0,%edx
L29:
  lea    0x1(%rdx),%eax
  mov    %eax,(%rsi,%rdi,4)
L24:
  mov    %edx,%eax
  ret
```

assistant: ```c
int step(long long num, int *t) {
  long long n = num;
  int nt, i = 0;
  while (n != 1) {
    if (n <= 10000000 && t[n] != -1) {
      t[num] = t[n] + i;
      return t[num];
    }
    if (n % 2)
      n = (n * 3) + 1;
    else
      n /= 2;
    i++;
  }
  t[num] = i + 1;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<step>:
  endbr64
  cmp    $0x1,%rdi
  je     L27
  mov    %rdi,%rdx
  xor    %ecx,%ecx
  jmp    L57
  nopl   0x0(%rax)
L36:
  lea    0x1(%rdx,%rdx,2),%rdx
  lea    0x1(%rcx),%eax
  cmp    $0x1,%rdx
  je     L30
L51:
  mov    %eax,%ecx
L57:
  cmp    $0x989680,%rdx
  jg     L17
  mov    (%rsi,%rdx,4),%eax
  cmp    $0xffffffff,%eax
  jne    L38
L17:
  test   $0x1,%dl
  jne    L36
  mov    %rdx,%rax
  shr    $0x3f,%rax
  add    %rax,%rdx
  lea    0x1(%rcx),%eax
  sar    %rdx
  cmp    $0x1,%rdx
  jne    L51
L30:
  add    $0x2,%ecx
L48:
  mov    %ecx,(%rsi,%rdi,4)
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  add    %ecx,%eax
  mov    %eax,(%rsi,%rdi,4)
  ret
L27:
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
int step(long long num, int *t) {
  long long n = num;
  int nt, i = 0;
  while (n != 1) {
    if (n <= 10000000 && t[n] != -1) {
      t[num] = t[n] + i;
      return t[num];
    }
    if (n % 2)
      n = (n * 3) + 1;
    else
      n /= 2;
    i++;
  }
  t[num] = i + 1;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<step>:
  endbr64
  cmp    $0x1,%rdi
  je     L21
  mov    %rdi,%rax
  xor    %r8d,%r8d
L46:
  cmp    $0x989680,%rax
  jg     L27
  mov    (%rsi,%rax,4),%edx
  cmp    $0xffffffff,%edx
  jne    L41
L27:
  test   $0x1,%al
  je     L17
  lea    0x1(%rax,%rax,2),%rax
  add    $0x1,%r8d
  cmp    $0x989680,%rax
  jg     L27
  mov    (%rsi,%rax,4),%edx
  cmp    $0xffffffff,%edx
  je     L27
L41:
  add    %edx,%r8d
  mov    %r8d,(%rsi,%rdi,4)
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    %rax,%rdx
  add    $0x1,%r8d
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  cmp    $0x1,%rax
  jne    L46
  lea    0x1(%r8),%eax
L42:
  mov    %eax,(%rsi,%rdi,4)
  mov    %r8d,%eax
  ret
L21:
  mov    $0x1,%eax
  xor    %r8d,%r8d
  jmp    L42
```

assistant: ```c
int step(long long num, int *t) {
  long long n = num;
  int nt, i = 0;
  while (n != 1) {
    if (n <= 10000000 && t[n] != -1) {
      t[num] = t[n] + i;
      return t[num];
    }
    if (n % 2)
      n = (n * 3) + 1;
    else
      n /= 2;
    i++;
  }
  t[num] = i + 1;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0xc3000(%rsp),%r11
L53:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L53
  sub    $0x540,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc3534(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L25
L48:
  movq   $0x1,-0xc3520(%rbp)
  lea    -0xc352c(%rbp),%rdx
  lea    -0xc3530(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xc3528(%rbp)
  jmp    L24
L20:
  lea    -0xc3510(%rbp),%rdx
  mov    -0xc3528(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0xc3528(%rbp)
L24:
  mov    -0xc3530(%rbp),%eax
  cmp    %eax,-0xc3528(%rbp)
  jl     L20
  movl   $0x0,-0xc3528(%rbp)
  jmp    L87
L79:
  lea    -0xc3510(%rbp),%rdx
  mov    -0xc3528(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    $0x4,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc352c(%rbp),%eax
  mov    -0xc3528(%rbp),%edx
  movslq %edx,%rdx
  mov    -0xc3510(%rbp,%rdx,8),%ecx
  cltd
  idiv   %ecx
  cltq
  mov    %rax,-0xc3518(%rbp)
  mov    -0xc3528(%rbp),%eax
  cltq
  mov    -0xc350c(%rbp,%rax,8),%eax
  cltq
  mov    -0xc3518(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0xc3518(%rbp)
  mov    -0xc3520(%rbp),%rax
  cmp    -0xc3518(%rbp),%rax
  jae    L13
  mov    -0xc3518(%rbp),%rax
  mov    %rax,-0xc3520(%rbp)
  mov    -0xc3528(%rbp),%eax
  mov    %eax,-0xc3524(%rbp)
L13:
  addl   $0x1,-0xc3528(%rbp)
L87:
  mov    -0xc3530(%rbp),%eax
  cmp    %eax,-0xc3528(%rbp)
  jl     L79
  mov    -0xc3520(%rbp),%rax
  mov    %rax,%rsi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L25:
  mov    -0xc3534(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc3534(%rbp)
  test   %eax,%eax
  jne    L48
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D47
data_type: string
name: unpack_data
arguments: label: D42
data_type: string

tool: D13: %d

tool: D47: %d%d

tool: D42: %lld


assistant: ```c
int main() {
  int t, N, K, i, min, pos;
  unsigned long long int max, temp;
  int arr[100001][2];
  scanf("%d", &t);
  while (t--) {
    max = 1;
    scanf("%d%d", &N, &K);
    for (i = 0; i < N; i++) {
      scanf("%d", &arr[i][0]);
    }
    for (i = 0; i < N; i++) {
      scanf("%d", &arr[i][1]);
      temp = K / arr[i][0];
      temp *= arr[i][1];
      if (max < temp) {
        max = temp;
        pos = i;
      }
    }
    printf("%lld\n", max);
  }
  return 0;
}
```