user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L134:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    $0xc8,%eax
  jg     L134
  test   $0x1,%al
  je     L134
  test   %eax,%eax
  jle    L105
  lea    0x10(%rsp),%r12
  mov    %rbx,%rdi
  lea    0x14(%rsp),%r14
  mov    $0x1,%r13d
  mov    %r12,%rsi
  mov    %r14,%rbp
  call   <scanf@plt>
  nopl   0x0(%rax,%rax,1)
L50:
  mov    0xc(%rsp),%esi
  cmp    %r13d,%esi
  jle    L39
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%edx
  mov    %r12,%rax
  mov    $0x1,%ecx
  jmp    L77
  nopl   (%rax)
L70:
  add    $0x4,%rax
  cmp    %rbp,%rax
  je     L182
L77:
  cmp    (%rax),%edx
  jne    L70
  cmp    $0x2,%ecx
  je     L105
  add    $0x4,%rax
  mov    $0x2,%ecx
  cmp    %rbp,%rax
  jne    L77
L182:
  add    $0x1,%r13d
  add    $0x4,%rbp
  jmp    L50
L91:
  mov    %r8d,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L105:
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L101
  add    $0x340,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  test   %esi,%esi
  jle    L105
  lea    -0x1(%rsi),%eax
  mov    %esi,%r10d
  mov    %r12,%rdi
  mov    %rax,%r11
  lea    (%r14,%rax,4),%rbx
  mov    %esi,%eax
  and    $0xfffffffc,%r10d
  shr    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x20(%rsp,%rax,1),%rcx
  nopw   0x0(%rax,%rax,1)
L23:
  mov    (%rdi),%r8d
  cmp    $0x2,%r11d
  jbe    L166
  movd   %r8d,%xmm3
  mov    %r12,%rax
  pxor   %xmm0,%xmm0
  pshufd $0x0,%xmm3,%xmm2
  xchg   %ax,%ax
L204:
  movdqa %xmm2,%xmm1
  add    $0x10,%rax
  pcmpeqd -0x10(%rax),%xmm1
  psubd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L204
  movdqa %xmm0,%xmm1
  mov    %r10d,%edx
  psrldq $0x8,%xmm1
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%r10d
  je     L20
L1:
  movslq %edx,%r9
  cmp    0x10(%rsp,%r9,4),%r8d
  jne    L184
  add    $0x1,%eax
L184:
  lea    0x1(%rdx),%r9d
  cmp    %r9d,%esi
  jle    L20
  movslq %r9d,%r9
  cmp    0x10(%rsp,%r9,4),%r8d
  jne    L132
  add    $0x1,%eax
L132:
  add    $0x2,%edx
  cmp    %edx,%esi
  jle    L20
  movslq %edx,%rdx
  cmp    0x10(%rsp,%rdx,4),%r8d
  jne    L20
  add    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L20:
  cmp    $0x1,%eax
  je     L91
  add    $0x4,%rdi
  cmp    %rbx,%rdi
  jne    L23
  jmp    L105
L166:
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L1
L101:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D19: %d

tool: D14: %d 


assistant: ```c
int main() {
  int deer[200];
  int i, j, pair, deers;
  do {
    scanf("%d", &deers);
  } while (deers % 2 == 0 || deers > 200);
  for (i = 0; i < deers; i++) {
    scanf("%d", &deer[i]);
    for (j = 0, pair = 1; j < i; j++) {
      if (deer[i] == deer[j]) {
        pair++;
      }
      if (pair > 2) {
        return 0;
      }
    }
  }
  for (i = 0; i < deers; i++) {
    for (j = 0, pair = 0; j < deers; j++) {
      if (deer[i] == deer[j]) {
        pair++;
      }
    }
    if (pair == 1) {
      printf("%d \n", deer[i]);
      break;
    }
  }
  return 0;
}
```