user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D24(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L80
L72:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L72
L80:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L184
L65:
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <printf@plt>
  mov    -0x2c(%rbp),%r9d
  test   %r9d,%r9d
  jle    L58
  mov    %rbx,%r13
  xor    %r12d,%r12d
  nop
L68:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%r12d
  add    $0x4,%r13
  call   <scanf@plt>
  mov    -0x2c(%rbp),%r9d
  cmp    %r12d,%r9d
  jg     L68
L58:
  mov    %r9d,%edi
  sub    $0x1,%edi
  js     L209
  movslq %edi,%r12
  mov    %r12,%r8
  nopw   0x0(%rax,%rax,1)
L143:
  mov    (%rbx,%r8,4),%r11d
  lea    -0x1(%rdi),%esi
  xor    %eax,%eax
  mov    %rsi,%r10
  mov    %r11d,%ecx
  test   %r8d,%r8d
  jg     L21
  jmp    L44
  nopl   0x0(%rax)
L79:
  mov    %rdx,%rax
L21:
  mov    (%rbx,%rax,4),%edx
  cmp    %edx,%ecx
  jge    L56
  mov    %edx,%ecx
  mov    %eax,%edi
L56:
  lea    0x1(%rax),%rdx
  cmp    %rsi,%rax
  jne    L79
  movslq %edi,%rdi
  mov    %ecx,(%rbx,%r8,4)
  mov    %r11d,(%rbx,%rdi,4)
L208:
  sub    $0x1,%r8
  mov    %r10d,%edi
  jmp    L143
  nopl   0x0(%rax,%rax,1)
L171:
  test   %al,%al
  je     L209
  mov    %r9d,-0x2c(%rbp)
L209:
  mov    -0x2c(%rbp),%eax
  xor    %r12d,%r12d
  lea    D13(%rip),%r13
  test   %eax,%eax
  jle    L139
  nopl   0x0(%rax)
L195:
  mov    (%rbx,%r12,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r12
  call   <printf@plt>
  cmp    %r12d,-0x2c(%rbp)
  jg     L195
L139:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L137
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L44:
  test   %r10d,%r10d
  jns    L208
  movslq %r9d,%rax
  lea    -0x8(%rbx,%rax,4),%rcx
  xor    %eax,%eax
  jmp    L38
  nopl   0x0(%rax)
L25:
  sub    $0x1,%r12
  sub    $0x4,%rcx
  test   %r12d,%r12d
  js     L171
L38:
  mov    (%rcx),%edi
  cmp    %edi,0x4(%rcx)
  jne    L25
  lea    -0x1(%r9),%r13d
  cmp    %r12d,%r9d
  jle    L190
  mov    %r13d,%eax
  lea    0x4(%rcx),%rsi
  mov    %rcx,%rdi
  sub    %r12d,%eax
  lea    0x4(,%rax,4),%rdx
  call   <memmove@plt>
  mov    %rax,%rcx
L190:
  mov    %r13d,%r9d
  mov    $0x1,%eax
  jmp    L25
L184:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L65
L137:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D24
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string
name: disassemble_data
arguments: label: D22
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string

tool: D24: Enter n= 

tool: D1: %d

tool: D22: Enter %d data (divide with space)= 

tool: D13: %d 

assistant: ```c
int main(void) {
  int n;
  printf("Enter n= ");
  scanf("%d", &n);
  int data[n];
  printf("Enter %d data (divide with space)= ", n);
  for (int i = 0; i < n; ++i)
    scanf("%d", &data[i]);
  for (int i = n - 1; i >= 0; --i) {
    int max = i;
    for (int j = 0; j < i; ++j)
      if (data[j] > data[max])
        max = j;
    int tmp = data[i];
    data[i] = data[max];
    data[max] = tmp;
  }
  for (int i = n - 1; i >= 0; --i) {
    if (data[i] == data[i - 1]) {
      for (int j = i; j < n; ++j)
        data[j - 1] = data[j];
      --n;
    }
  }
  for (int i = 0; i < n; ++i)
    printf("%d ", data[i]);
  printf("\n");
  return 0;
}
```