ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D37(%rip),%r13
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  push   %r12
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %r13,%rdi
  push   %rbp
  lea    D8(%rip),%r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x61,0x4(%rsp)
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r12,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%r8d
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    $0x3,%ecx
  mov    $0x2,%edx
  mov    $0x1,%esi
  movl   $0x64655a,0x4(%rsp)
  call   <printf@plt>
  movsbl 0x6(%rsp),%ecx
  mov    %r12,%rdi
  xor    %eax,%eax
  movsbl 0x5(%rsp),%edx
  movsbl 0x7(%rsp),%r8d
  movsbl 0x4(%rsp),%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D23(%rip),%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %r8d,%r8d
  xor    %eax,%eax
  mov    $0x64,%ecx
  mov    $0x65,%edx
  mov    $0x5a,%esi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D37
data_type: string
name: unpack_data
arguments: label: D8
data_type: string
name: unpack_data
arguments: label: D68
data_type: string
name: unpack_data
arguments: label: D43
data_type: string
name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D42
data_type: string

tool: D37: numbers: %d %d %d %d


tool: D8: name each: %c %c %c %c


tool: D68: name : %s


tool: D43: name: %s


tool: D23: Zed

tool: D10: another : %s


tool: D42: Another each: %c %c %c %c


assistant: ```c
int main(int argc, char *argv[]) {
  int numbers[4] = {0};
  char name[4] = {'a'};
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name : %s\n", name);
  numbers[0] = 1;
  numbers[1] = 2;
  numbers[2] = 3;
  numbers[3] = 4;
  name[0] = 'Z';
  name[1] = 'e';
  name[2] = 'd';
  name[3] = '\0';
  printf("numbers: %d %d %d %d\n", numbers[0], numbers[1], numbers[2], numbers[3]);
  printf("name each: %c %c %c %c\n", name[0], name[1], name[2], name[3]);
  printf("name: %s\n", name);
  char *another = "Zed";
  printf("another : %s\n", another);
  printf("Another each: %c %c %c %c\n", another[0], another[1], another[2], another[3]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: Hello from prog3.c


assistant: ```c
int main(void) {
  printf("Hello from prog3.c\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
datatype: string

tool: D7: Hello from prog3.c


assistant: ```c
int main(void) {
  printf("Hello from prog3.c\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
data_type: string

tool: D9: Hello from prog3.c


assistant: ```c
int main(void) {
  printf("Hello from prog3.c\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string

tool: D5: Hello from prog3.c


assistant: ```c
int main(void) {
  printf("Hello from prog3.c\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trie_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <trie_root@plt>
  test   %rax,%rax
  je     L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <trie_root@plt>
  mov    %rax,%rdi
  call   <trienode_free@plt>
L5:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void trie_free(struct Trie *trie) {
  if (trie_root(trie) != NULL)
    trienode_free(trie_root(trie));
  free(trie);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trie_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <trie_root@plt>
  test   %rax,%rax
  je     L0
  mov    %rbx,%rdi
  call   <trie_root@plt>
  mov    %rax,%rdi
  call   <trienode_free@plt>
L0:
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void trie_free(struct Trie *trie) {
  if (trie_root(trie) != NULL)
    trienode_free(trie_root(trie));
  free(trie);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<trie_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <trie_root@plt>
  test   %rax,%rax
  je     L3
  mov    %rbp,%rdi
  call   <trie_root@plt>
  mov    %rax,%rdi
  call   <trienode_free@plt>
L3:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

assistant: ```c
void trie_free(struct Trie *trie) {
  if (trie_root(trie) != NULL)
    trienode_free(trie_root(trie));
  free(trie);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<trie_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <trie_root@plt>
  test   %rax,%rax
  je     L7
  mov    %rbp,%rdi
  call   <trie_root@plt>
  mov    %rax,%rdi
  call   <trienode_free@plt>
L7:
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1080 <free@plt>
```

assistant: ```c
void trie_free(struct Trie *trie) {
  if (trie_root(trie) != NULL)
    trienode_free(trie_root(trie));
  free(trie);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x12000000,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    %eax,%esi
  mov    $0xff000000,%edi
  call   <expect@plt>
  mov    $0x345678,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    %eax,%esi
  mov    $0xffffff,%edi
  call   <expect@plt>
  mov    $0x12345678,%esi
  mov    $0x78,%edi
  call   <do_compare@plt>
  mov    %eax,%esi
  mov    $0xff,%edi
  call   <expect@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  expect(0xff000000, do_compare(0x12345678, 0x12000000));
  expect(0x00ffffff, do_compare(0x12345678, 0x00345678));
  expect(0x000000ff, do_compare(0x00000078, 0x12345678));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x12000000,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    %eax,%esi
  mov    $0xff000000,%edi
  call   <expect@plt>
  mov    $0x345678,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    %eax,%esi
  mov    $0xffffff,%edi
  call   <expect@plt>
  mov    $0x12345678,%esi
  mov    $0x78,%edi
  call   <do_compare@plt>
  mov    %eax,%esi
  mov    $0xff,%edi
  call   <expect@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  expect(0xff000000, do_compare(0x12345678, 0x12000000));
  expect(0x00ffffff, do_compare(0x12345678, 0x00345678));
  expect(0x000000ff, do_compare(0x00000078, 0x12345678));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x12000000,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    $0xff000000,%edi
  mov    %eax,%esi
  call   <expect@plt>
  mov    $0x345678,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    $0xffffff,%edi
  mov    %eax,%esi
  call   <expect@plt>
  mov    $0x12345678,%esi
  mov    $0x78,%edi
  call   <do_compare@plt>
  mov    $0xff,%edi
  mov    %eax,%esi
  call   <expect@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  expect(0xff000000, do_compare(0x12345678, 0x12000000));
  expect(0x00ffffff, do_compare(0x12345678, 0x00345678));
  expect(0x000000ff, do_compare(0x00000078, 0x12345678));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x12000000,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    $0xff000000,%edi
  mov    %eax,%esi
  call   <expect@plt>
  mov    $0x345678,%esi
  mov    $0x12345678,%edi
  call   <do_compare@plt>
  mov    $0xffffff,%edi
  mov    %eax,%esi
  call   <expect@plt>
  mov    $0x12345678,%esi
  mov    $0x78,%edi
  call   <do_compare@plt>
  mov    $0xff,%edi
  mov    %eax,%esi
  call   <expect@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  expect(0xff000000, do_compare(0x12345678, 0x12000000));
  expect(0x00ffffff, do_compare(0x12345678, 0x00345678));
  expect(0x000000ff, do_compare(0x00000078, 0x12345678));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<insertion_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L49:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L9
L31:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  subl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0x0,-0x8(%rbp)
  jle    L46
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x28(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  test   %eax,%eax
  jne    L31
L46:
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  ja     L49
  nop
  nop
  leave
  ret
```

assistant: ```c
void insertion_sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  int j;
  int temp;
  for (int i = 0; i < size; i++) {
    for (j = i; j > 0 && comp(*(collection + j), *(collection + j - 1)); j--) {
      swap(collection, j - 1, j);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<insertion_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L2
  mov    %rdi,%r13
  mov    %rdx,%r14
  mov    $0x0,%r15d
L13:
  add    $0x1,%r15d
  cmp    0xc(%rsp),%r15d
  je     L2
  test   %r15d,%r15d
  jle    L13
  movslq %r15d,%rax
  lea    -0x4(%r13,%rax,4),%rbx
  mov    %r15d,%r12d
L49:
  mov    0x4(%rbx),%edi
  mov    (%rbx),%esi
  call   *%r14
  test   %eax,%eax
  je     L13
  lea    -0x1(%r12),%ebp
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  sub    $0x4,%rbx
  test   %ebp,%ebp
  je     L13
  mov    %ebp,%r12d
  jmp    L49
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insertion_sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  int j;
  int temp;
  for (int i = 0; i < size; i++) {
    for (j = i; j > 0 && comp(*(collection + j), *(collection + j - 1)); j--) {
      swap(collection, j - 1, j);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<insertion_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L8
  xor    %r13d,%r13d
  mov    %rdi,(%rsp)
  mov    %rdi,%r12
  mov    %rdx,%rbp
  add    $0x1,%r13d
  cmp    0xc(%rsp),%r13d
  je     L8
  nopw   0x0(%rax,%rax,1)
L25:
  mov    (%rsp),%rbx
  mov    %r13d,%r15d
  jmp    L47
  nopl   0x0(%rax)
L7:
  lea    -0x1(%r15),%r14d
  mov    %r15d,%edx
  mov    %r12,%rdi
  sub    $0x4,%rbx
  mov    %r14d,%esi
  call   <swap@plt>
  test   %r14d,%r14d
  je     L57
  mov    %r14d,%r15d
L47:
  mov    0x4(%rbx),%edi
  mov    (%rbx),%esi
  call   *%rbp
  test   %eax,%eax
  jne    L7
L57:
  addq   $0x4,(%rsp)
  add    $0x1,%r13d
  cmp    0xc(%rsp),%r13d
  jne    L25
L8:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void insertion_sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  int j;
  int temp;
  for (int i = 0; i < size; i++) {
    for (j = i; j > 0 && comp(*(collection + j), *(collection + j - 1)); j--) {
      swap(collection, j - 1, j);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertion_sort>:
  endbr64
  cmp    $0x1,%esi
  jbe    L24
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %r13,%rbx
  jmp    L40
  nopl   (%rax)
L43:
  lea    -0x1(%rbx),%esi
  mov    %r15d,%edx
  mov    %rbp,%rdi
  sub    $0x1,%rbx
  call   <swap@plt>
  test   %ebx,%ebx
  je     L37
L40:
  mov    -0x4(%rbp,%rbx,4),%esi
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %ebx,%r15d
  call   *%r12
  test   %eax,%eax
  jne    L43
L37:
  add    $0x1,%r13
  cmp    %r13,%r14
  jne    L46
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  ret
```

assistant: ```c
void insertion_sort(int *collection, unsigned int size, int (*comp)(int, int)) {
  int j;
  int temp;
  for (int i = 0; i < size; i++) {
    for (j = i; j > 0 && comp(*(collection + j), *(collection + j - 1)); j--) {
      swap(collection, j - 1, j);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<flott_file_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L19
  movl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

assistant: ```c
int flott_file_exists(char *filename) {
  int ret_val = 0;
  struct stat info;
  if (stat(filename, &info) == 0 && S_ISREG(info.st_mode)) {
    ret_val = 1;
  }
  return ret_val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<flott_file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L26
L15:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x18,%rsp
  ret
L26:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L15
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int flott_file_exists(char *filename) {
  int ret_val = 0;
  struct stat info;
  if (stat(filename, &info) == 0 && S_ISREG(info.st_mode)) {
    ret_val = 1;
  }
  return ret_val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flott_file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L15
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L15:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L4
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int flott_file_exists(char *filename) {
  int ret_val = 0;
  struct stat info;
  if (stat(filename, &info) == 0 && S_ISREG(info.st_mode)) {
    ret_val = 1;
  }
  return ret_val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flott_file_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L4
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L4:
  mov    0x4(%rsp),%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L17
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int flott_file_exists(char *filename) {
  int ret_val = 0;
  struct stat info;
  if (stat(filename, &info) == 0 && S_ISREG(info.st_mode)) {
    ret_val = 1;
  }
  return ret_val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_string_append>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1f,%eax
  jne    L4
  mov    -0x20(%rbp),%rax
  add    $0x1f,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L24
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scat@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  jmp    L11
L24:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scopy@plt>
  cltq
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
L11:
  mov    -0x28(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x20(%rbp),%rax
  movzbl -0x2c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L18
L4:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x28(%rbp),%rdx
  mov    %ecx,(%rdx)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x2c(%rbp),%eax
  mov    %al,(%rdx)
  mov    $0x1,%eax
L18:
  leave
  ret
```

assistant: ```c
int _string_append(char **p, char *tmp, int *tmplen, char c) {
  char *tmp2;
  if (*tmplen == 32 - 1) {
    tmp[32 - 1] = '\0';
    if (*p != ((void *)0)) {
      tmp2 = scat(*p, tmp);
      free(*p);
      *p = tmp2;
    } else {
      *p = scopy(tmp);
    }
    *tmplen = 1;
    tmp[0] = c;
    return *p != ((void *)0);
  } else {
    tmp[(*tmplen)++] = c;
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_string_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r13d
  mov    (%rdx),%eax
  cmp    $0x1f,%eax
  je     L20
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  cltq
  mov    %cl,0x0(%rbp,%rax,1)
  mov    $0x1,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  mov    %rdi,%r12
  movb   $0x0,0x1f(%rsi)
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L13
  mov    $0x0,%eax
  call   <scat@plt>
  movslq %eax,%r14
  mov    (%r12),%rdi
  call   <free@plt>
L22:
  mov    %r14,(%r12)
  movl   $0x1,(%rbx)
  mov    %r13b,0x0(%rbp)
  cmpq   $0x0,(%r12)
  setne  %al
  movzbl %al,%eax
  jmp    L12
L13:
  mov    %rsi,%rdi
  mov    $0x0,%eax
  call   <scopy@plt>
  movslq %eax,%r14
  jmp    L22
```

assistant: ```c
int _string_append(char **p, char *tmp, int *tmplen, char c) {
  char *tmp2;
  if (*tmplen == 32 - 1) {
    tmp[32 - 1] = '\0';
    if (*p != ((void *)0)) {
      tmp2 = scat(*p, tmp);
      free(*p);
      *p = tmp2;
    } else {
      *p = scopy(tmp);
    }
    *tmplen = 1;
    tmp[0] = c;
    return *p != ((void *)0);
  } else {
    tmp[(*tmplen)++] = c;
    return 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_string_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq (%rdx),%rax
  mov    %rdx,%rbx
  cmp    $0x1f,%eax
  je     L21
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  pop    %rbx
  mov    %cl,0x0(%rbp,%rax,1)
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L21:
  movb   $0x0,0x1f(%rsi)
  mov    %rdi,%r13
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L2
  xor    %eax,%eax
  call   <scat@plt>
  mov    0x0(%r13),%rdi
  movslq %eax,%r14
  call   <free@plt>
L4:
  mov    %r14,0x0(%r13)
  xor    %eax,%eax
  movl   $0x1,(%rbx)
  pop    %rbx
  mov    %r12b,0x0(%rbp)
  cmpq   $0x0,0x0(%r13)
  pop    %rbp
  setne  %al
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rsi,%rdi
  xor    %eax,%eax
  call   <scopy@plt>
  movslq %eax,%r14
  jmp    L4
```

assistant: ```c
int _string_append(char **p, char *tmp, int *tmplen, char c) {
  char *tmp2;
  if (*tmplen == 32 - 1) {
    tmp[32 - 1] = '\0';
    if (*p != ((void *)0)) {
      tmp2 = scat(*p, tmp);
      free(*p);
      *p = tmp2;
    } else {
      *p = scopy(tmp);
    }
    *tmplen = 1;
    tmp[0] = c;
    return *p != ((void *)0);
  } else {
    tmp[(*tmplen)++] = c;
    return 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_string_append>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movslq (%rdx),%rax
  mov    %rdx,%rbx
  cmp    $0x1f,%eax
  je     L7
  lea    0x1(%rax),%edx
  mov    %edx,(%rbx)
  pop    %rbx
  mov    %cl,0x0(%rbp,%rax,1)
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L7:
  movb   $0x0,0x1f(%rsi)
  mov    %rdi,%r13
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L26
  xor    %eax,%eax
  call   <scat@plt>
  mov    0x0(%r13),%rdi
  movslq %eax,%r14
  call   <free@plt>
L24:
  mov    %r14,0x0(%r13)
  xor    %eax,%eax
  movl   $0x1,(%rbx)
  pop    %rbx
  mov    %r12b,0x0(%rbp)
  cmpq   $0x0,0x0(%r13)
  pop    %rbp
  setne  %al
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %rsi,%rdi
  xor    %eax,%eax
  call   <scopy@plt>
  movslq %eax,%r14
  jmp    L24
```

assistant: ```c
int _string_append(char **p, char *tmp, int *tmplen, char c) {
  char *tmp2;
  if (*tmplen == 32 - 1) {
    tmp[32 - 1] = '\0';
    if (*p != ((void *)0)) {
      tmp2 = scat(*p, tmp);
      free(*p);
      *p = tmp2;
    } else {
      *p = scopy(tmp);
    }
    *tmplen = 1;
    tmp[0] = c;
    return *p != ((void *)0);
  } else {
    tmp[(*tmplen)++] = c;
    return 1;
  }
}
```