ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<last_digit_to_word>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,(%rsp)
  lea    D63(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D74(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D19(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D67(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D35(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D5(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D75(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D16(%rip),%rax
  mov    %rax,0x48(%rsp)
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  movslq %edi,%rdi
  mov    (%rsp,%rdi,8),%rax
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x68,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string
name: disassemble_data
arguments: data_label: D63
type_infered: string
name: disassemble_data
arguments: data_label: D74
type_infered: string
name: disassemble_data
arguments: data_label: D19
type_infered: string
name: disassemble_data
arguments: data_label: D67
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string
name: disassemble_data
arguments: data_label: D75
type_infered: string
name: disassemble_data
arguments: data_label: D16
type_infered: string

tool: D6: zero

tool: D63: one

tool: D74: two

tool: D19: three

tool: D67: four

tool: D35: five

tool: D0: six

tool: D5: seven

tool: D75: eight

tool: D16: nine

assistant: ```c
char *last_digit_to_word(int num) {
  char *words[] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
  int lastDigit;
  lastDigit = num % 10;
  return (words[lastDigit]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<last_digit_to_word>:
  endbr64
  sub    $0x68,%rsp
  mov    %edi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  lea    D8(%rip),%rax
  sar    $0x1f,%edx
  mov    %rax,(%rsp)
  lea    D12(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D52(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D77(%rip),%rax
  mov    %rax,0x18(%rsp)
  lea    D34(%rip),%rax
  mov    %rax,0x20(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x28(%rsp)
  lea    D69(%rip),%rax
  mov    %rax,0x30(%rsp)
  lea    D57(%rip),%rax
  mov    %rax,0x38(%rsp)
  lea    D90(%rip),%rax
  mov    %rax,0x40(%rsp)
  lea    D1(%rip),%rax
  mov    %rax,0x48(%rsp)
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edi
  movslq %edi,%rdi
  mov    (%rsp,%rdi,8),%rax
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x68,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type: string
name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D52
type: string
name: read_data
arguments: data_label: D77
type: string
name: read_data
arguments: data_label: D34
type: string
name: read_data
arguments: data_label: D0
type: string
name: read_data
arguments: data_label: D69
type: string
name: read_data
arguments: data_label: D57
type: string
name: read_data
arguments: data_label: D90
type: string
name: read_data
arguments: data_label: D1
type: string

tool: D8: zero

tool: D12: one

tool: D52: two

tool: D77: three

tool: D34: four

tool: D0: five

tool: D69: six

tool: D57: seven

tool: D90: eight

tool: D1: nine

assistant: ```c
char *last_digit_to_word(int num) {
  char *words[] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
  int lastDigit;
  lastDigit = num % 10;
  return (words[lastDigit]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<last_digit_to_word>:
  endbr64
  sub    $0x68,%rsp
  lea    D36(%rip),%rsi
  mov    %edi,%eax
  mov    %fs:0x28,%rdx
  mov    %rdx,0x58(%rsp)
  lea    D56(%rip),%rdx
  movq   %rsi,%xmm0
  lea    D1(%rip),%rsi
  lea    D16(%rip),%rdi
  lea    D6(%rip),%rcx
  movq   %rdx,%xmm1
  lea    D52(%rip),%rdx
  punpcklqdq %xmm1,%xmm0
  movq   %rdx,%xmm2
  lea    D0(%rip),%rdx
  movaps %xmm0,(%rsp)
  movq   %rsi,%xmm0
  movq   %rdx,%xmm3
  lea    D66(%rip),%rdx
  punpcklqdq %xmm2,%xmm0
  movq   %rdx,%xmm4
  lea    D80(%rip),%rdx
  movaps %xmm0,0x10(%rsp)
  movq   %rdi,%xmm0
  movq   %rdx,%xmm5
  lea    D79(%rip),%rsi
  punpcklqdq %xmm3,%xmm0
  movslq %eax,%rdx
  movaps %xmm0,0x20(%rsp)
  imul   $0x66666667,%rdx,%rdx
  movq   %rsi,%xmm0
  punpcklqdq %xmm4,%xmm0
  movaps %xmm0,0x30(%rsp)
  movq   %rcx,%xmm0
  mov    %eax,%ecx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  punpcklqdq %xmm5,%xmm0
  sub    %ecx,%edx
  movaps %xmm0,0x40(%rsp)
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  cltq
  mov    (%rsp,%rax,8),%rax
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x68,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D36
datatype: string
name: parse_data
arguments: tag: D56
datatype: string
name: parse_data
arguments: tag: D1
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D6
datatype: string
name: parse_data
arguments: tag: D52
datatype: string
name: parse_data
arguments: tag: D0
datatype: string
name: parse_data
arguments: tag: D66
datatype: string
name: parse_data
arguments: tag: D80
datatype: string
name: parse_data
arguments: tag: D79
datatype: string

tool: D36: zero

tool: D56: one

tool: D1: two

tool: D16: four

tool: D6: eight

tool: D52: three

tool: D0: five

tool: D66: seven

tool: D80: nine

tool: D79: six

assistant: ```c
char *last_digit_to_word(int num) {
  char *words[] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
  int lastDigit;
  lastDigit = num % 10;
  return (words[lastDigit]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isIpv4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L67:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L29
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L14
  addl   $0x1,-0xc(%rbp)
L14:
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L67
  cmpl   $0x0,-0x10(%rbp)
  jne    L66
  cmpl   $0x0,-0xc(%rbp)
  jne    L66
  mov    $0xffffffff,%eax
  jmp    L89
L66:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L46
  mov    $0x1,%eax
  jmp    L89
L46:
  mov    $0x0,%eax
L89:
  leave
  ret
```

assistant: ```c
int isIpv4(char *buf) {
  int len = strlen(buf);
  int dot_count = 0, colon_count = 0, i;
  for (i = 0; i < len; i++) {
    if (buf[i] == '.')
      dot_count++;
    if (buf[i] == ':')
      colon_count++;
  }
  if (dot_count == 0 && colon_count == 0)
    return -1;
  if (dot_count > colon_count)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isIpv4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L7
  mov    %rbx,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edi
  jmp    L52
L4:
  add    $0x1,%edi
L49:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L55
L52:
  movzbl (%rdx),%eax
  cmp    $0x2e,%al
  je     L4
  cmp    $0x3a,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%ecx
  jmp    L49
L55:
  mov    $0xffffffff,%eax
  mov    %ecx,%ebx
  or     %edi,%ebx
  je     L38
  cmp    %edi,%ecx
  setl   %al
  movzbl %al,%eax
L38:
  pop    %rbx
  ret
L7:
  mov    $0xffffffff,%eax
  jmp    L38
```

assistant: ```c
int isIpv4(char *buf) {
  int len = strlen(buf);
  int dot_count = 0, colon_count = 0, i;
  for (i = 0; i < len; i++) {
    if (buf[i] == '.')
      dot_count++;
    if (buf[i] == ':')
      colon_count++;
  }
  if (dot_count == 0 && colon_count == 0)
    return -1;
  if (dot_count > colon_count)
    return 1;
  else
    return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isIpv4>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L54
  sub    $0x1,%eax
  mov    %rbx,%rdi
  xor    %edx,%edx
  xor    %esi,%esi
  lea    0x1(%rbx,%rax,1),%rcx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    $0x3a,%al
  sete   %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%edx
  cmp    %rcx,%rdi
  je     L12
L19:
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  jne    L57
  add    $0x1,%rdi
  add    $0x1,%esi
  cmp    %rcx,%rdi
  jne    L19
L12:
  mov    %edx,%ebx
  mov    $0xffffffff,%eax
  or     %esi,%ebx
  je     L41
  xor    %eax,%eax
  cmp    %esi,%edx
  setl   %al
L41:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int isIpv4(char *buf) {
  int len = strlen(buf);
  int dot_count = 0, colon_count = 0, i;
  for (i = 0; i < len; i++) {
    if (buf[i] == '.')
      dot_count++;
    if (buf[i] == ':')
      colon_count++;
  }
  if (dot_count == 0 && colon_count == 0)
    return -1;
  if (dot_count > colon_count)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L2
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L22
L2:
  mov    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  mov    -0x18(%rbp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L22:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D26
data_type: string
name: parse_data
arguments: data_tag: D12
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string

tool: D26: Enter two LONG numbers:

tool: D12: %ld %ld

tool: D4: Error: Denominator cannot be Zero.

tool: D19: The result is: %lf

assistant: ```c
main() {
  long int a, b;
  double c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  if (b == 0) {
    printf("Error: Denominator cannot be Zero.");
  } else {
    c = (float)a / b;
    printf("The result is: %lf", c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D30(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  jne    L14
  lea    D1(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L14:
  pxor   %xmm0,%xmm0
  cvtsi2ssq 0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %rax,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L0
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D30
data_type: string
name: extract_symbolic_data
arguments: tag: D5
data_type: string
name: extract_symbolic_data
arguments: tag: D1
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D30: Enter two LONG numbers:

tool: D5: %ld %ld

tool: D1: Error: Denominator cannot be Zero.

tool: D14: The result is: %lf

assistant: ```c
main() {
  long int a, b;
  double c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  if (b == 0) {
    printf("Error: Denominator cannot be Zero.");
  } else {
    c = (float)a / b;
    printf("The result is: %lf", c);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  jne    L21
  lea    D22(%rip),%rdi
  call   <printf@plt>
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L21:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D10(%rip),%rdi
  cvtsi2ss %rax,%xmm1
  mov    $0x1,%eax
  cvtsi2ssq 0x8(%rsp),%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L10
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D37
data_type: string
name: extract_symbolic_data
arguments: data_tag: D26
data_type: string
name: extract_symbolic_data
arguments: data_tag: D22
data_type: string
name: extract_symbolic_data
arguments: data_tag: D10
data_type: string

tool: D37: Enter two LONG numbers:

tool: D26: %ld %ld

tool: D22: Error: Denominator cannot be Zero.

tool: D10: The result is: %lf

assistant: ```c
main() {
  long int a, b;
  double c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  if (b == 0) {
    printf("Error: Denominator cannot be Zero.");
  } else {
    c = (float)a / b;
    printf("The result is: %lf", c);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D32(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  test   %rax,%rax
  jne    L8
  lea    D31(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  lea    D16(%rip),%rdi
  cvtsi2ss %rax,%xmm1
  mov    $0x1,%eax
  cvtsi2ssq 0x8(%rsp),%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L0
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D32
type: string
name: extract_symbolic_data
arguments: tag: D31
type: string
name: extract_symbolic_data
arguments: tag: D16
type: string

tool: D18: Enter two LONG numbers:

tool: D32: %ld %ld

tool: D31: Error: Denominator cannot be Zero.

tool: D16: The result is: %lf

assistant: ```c
main() {
  long int a, b;
  double c;
  printf("Enter two LONG numbers:\n");
  scanf("%ld %ld", &a, &b);
  if (b == 0) {
    printf("Error: Denominator cannot be Zero.");
  } else {
    c = (float)a / b;
    printf("The result is: %lf", c);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<keyup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L5
  mov    -0x4(%rbp),%eax
  mov    $0x6,%edx
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  lea    D11(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
L5:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D7: keyup 

tool: D11: 


assistant: ```c
void keyup(int xte_fd, char *key, int *state) {
  if (*state) {
    write(xte_fd, "keyup ", 6);
    write(xte_fd, key, strlen(key));
    write(xte_fd, "\n", 1);
    *state = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<keyup>:
  endbr64
  cmpl   $0x0,(%rdx)
  jne    L3
  ret
L3:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    $0x6,%edx
  lea    D8(%rip),%rsi
  call   <write@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <write@plt>
  mov    $0x1,%edx
  lea    D5(%rip),%rsi
  mov    %r12d,%edi
  call   <write@plt>
  movl   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string

tool: D8: keyup 

tool: D5: 


assistant: ```c
void keyup(int xte_fd, char *key, int *state) {
  if (*state) {
    write(xte_fd, "keyup ", 6);
    write(xte_fd, key, strlen(key));
    write(xte_fd, "\n", 1);
    *state = 0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<keyup>:
  endbr64
  mov    (%rdx),%eax
  test   %eax,%eax
  jne    L1
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  push   %r12
  mov    %rsi,%r12
  lea    D14(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x6,%edx
  call   <write@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    %ebp,%edi
  mov    $0x1,%edx
  lea    D1(%rip),%rsi
  call   <write@plt>
  movl   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string

tool: D14: keyup 

tool: D1: 


assistant: ```c
void keyup(int xte_fd, char *key, int *state) {
  if (*state) {
    write(xte_fd, "keyup ", 6);
    write(xte_fd, key, strlen(key));
    write(xte_fd, "\n", 1);
    *state = 0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<keyup>:
  endbr64
  mov    (%rdx),%eax
  test   %eax,%eax
  jne    L6
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  push   %r12
  mov    %rsi,%r12
  lea    D5(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  mov    $0x6,%edx
  call   <write@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %eax,%edx
  call   <write@plt>
  mov    %ebp,%edi
  mov    $0x1,%edx
  lea    D10(%rip),%rsi
  call   <write@plt>
  movl   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_infered: string
name: disassemble_data
arguments: label: D10
type_infered: string

tool: D5: keyup 

tool: D10: 


assistant: ```c
void keyup(int xte_fd, char *key, int *state) {
  if (*state) {
    write(xte_fd, "keyup ", 6);
    write(xte_fd, key, strlen(key));
    write(xte_fd, "\n", 1);
    *state = 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<float_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x24(%rbp)
  movl   $0x28,-0x8(%rbp)
  movss  D0(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L15:
  movss  -0x24(%rbp),%xmm0
  divss  -0x14(%rbp),%xmm0
  addss  -0x14(%rbp),%xmm0
  movss  D7(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
L29:
  movss  -0x10(%rbp),%xmm0
  subss  -0x24(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L5
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  cmp    %eax,-0x8(%rbp)
  jg     L15
L5:
  movss  -0x14(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
datatype: f32
name: read_data
arguments: tag: D7
datatype: byte[4]

tool: D0: 0.001

tool: {"D7": [0x00,0x00,0x00,0x40]}

assistant: ```c
float float_sqrt(const float num) {
  const int MAX_STEPS = 40;
  const float MAX_ERROR = 0.001;
  float answer = num;
  float ans_sqr = answer * answer;
  int step = 0;
  while ((ans_sqr - num > MAX_ERROR) && (step++ < MAX_STEPS)) {
    answer = (answer + (num / answer)) / 2;
    ans_sqr = answer * answer;
  }
  return answer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<float_sqrt>:
  endbr64
  movaps %xmm0,%xmm2
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  subss  %xmm0,%xmm1
  mov    $0x28,%eax
  movss  D19(%rip),%xmm3
  comiss D27(%rip),%xmm1
  jbe    L14
L26:
  movaps %xmm2,%xmm1
  divss  %xmm0,%xmm1
  addss  %xmm1,%xmm0
  mulss  %xmm3,%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  subss  %xmm2,%xmm1
  comiss D27(%rip),%xmm1
  jbe    L14
  sub    $0x1,%eax
  jne    L26
  ret
L14:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D19
type: byte[4]
name: disassemble_data
arguments: data_tag: D27
type: f32

tool: {"D19": [0x00,0x00,0x00,0x3f]}

tool: D27: 0.001

assistant: ```c
float float_sqrt(const float num) {
  const int MAX_STEPS = 40;
  const float MAX_ERROR = 0.001;
  float answer = num;
  float ans_sqr = answer * answer;
  int step = 0;
  while ((ans_sqr - num > MAX_ERROR) && (step++ < MAX_STEPS)) {
    answer = (answer + (num / answer)) / 2;
    ans_sqr = answer * answer;
  }
  return answer;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<float_sqrt>:
  endbr64
  movaps %xmm0,%xmm2
  mulss  %xmm0,%xmm0
  subss  %xmm2,%xmm0
  comiss D25(%rip),%xmm0
  movaps %xmm2,%xmm0
  jbe    L37
  movss  D14(%rip),%xmm3
  mov    $0x28,%eax
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L18:
  sub    $0x1,%eax
  je     L13
L19:
  movaps %xmm2,%xmm1
  divss  %xmm0,%xmm1
  addss  %xmm1,%xmm0
  mulss  %xmm3,%xmm0
  movaps %xmm0,%xmm1
  mulss  %xmm0,%xmm1
  subss  %xmm2,%xmm1
  comiss D25(%rip),%xmm1
  ja     L18
L37:
  ret
  nopl   0x0(%rax)
L13:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
type_infered: f32
name: disassemble_data
arguments: label: D14
type_infered: byte[4]

tool: D25: 0.001

tool: {"D14": [0x00,0x00,0x00,0x3f]}

assistant: ```c
float float_sqrt(const float num) {
  const int MAX_STEPS = 40;
  const float MAX_ERROR = 0.001;
  float answer = num;
  float ans_sqr = answer * answer;
  int step = 0;
  while ((ans_sqr - num > MAX_ERROR) && (step++ < MAX_STEPS)) {
    answer = (answer + (num / answer)) / 2;
    ans_sqr = answer * answer;
  }
  return answer;
}
```