user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1,%edx
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  mov    $0x1,%esi
  push   %rbp
  mov    %edi,%ebp
  mov    $0x378,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <ioperm@plt>
  test   %rax,%rax
  jne    L199
  mov    $0x378,%edi
  call   <inb@plt>
  mov    %eax,%ebx
  cmp    $0x3,%ebp
  je     L4
  cmp    $0x2,%ebp
  je     L66
L124:
  movsbl %bl,%ebx
  mov    $0x378,%esi
  mov    $0x1,%r12d
  mov    $0x10,%r14d
  mov    %ebx,%edi
  lea    D22(%rip),%r15
  lea    D6(%rip),%r13
  call   <outb@plt>
  lea    D2(%rip),%rbp
L169:
  mov    %r12d,%ecx
  mov    %r14d,%eax
  mov    %ebx,%edx
  mov    %r12d,%esi
  sar    %cl,%eax
  mov    %r15,%rdi
  and    %eax,%edx
  cmp    %edx,%eax
  mov    %rbp,%rdx
  cmove  %r13,%rdx
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    $0x5,%r12d
  jne    L169
  xor    %eax,%eax
L179:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L199:
  lea    D56(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L179
L66:
  mov    0x8(%r12),%rsi
  lea    D67(%rip),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  mov    $0x0,%eax
  cmove  %eax,%ebx
  jmp    L124
L4:
  mov    0x10(%r12),%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  jne    L124
  mov    0x8(%r12),%rbp
  lea    D6(%rip),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L198
  mov    0x10(%r12),%rax
  movzbl (%rax),%eax
  cmp    $0x33,%al
  je     L156
  jg     L267
  cmp    $0x31,%al
  je     L132
  cmp    $0x32,%al
  jne    L124
  or     $0x4,%ebx
  jmp    L124
L198:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L124
  mov    0x10(%r12),%rax
  movzbl (%rax),%eax
  cmp    $0x33,%al
  je     L91
  jg     L95
  cmp    $0x31,%al
  je     L183
  cmp    $0x32,%al
  jne    L124
  and    $0xfffffffb,%ebx
  jmp    L124
L267:
  cmp    $0x34,%al
  jne    L124
  or     $0x1,%ebx
  jmp    L124
L95:
  cmp    $0x34,%al
  jne    L124
  and    $0xfffffffe,%ebx
  jmp    L124
L132:
  or     $0x8,%ebx
  jmp    L124
L156:
  or     $0x2,%ebx
  jmp    L124
L91:
  and    $0xfffffffd,%ebx
  jmp    L124
L183:
  and    $0xfffffff7,%ebx
  jmp    L124
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D2
data_type: string
name: disassemble_data
arguments: data_tag: D56
data_type: string
name: disassemble_data
arguments: data_tag: D67
data_type: string

tool: D22: relay%d: %s


tool: D6: on

tool: D2: off

tool: D56: Cannot open LPT port

tool: D67: reset

assistant: ```c
int main(int argc, char **argv) {
  char buf, i;
  if (ioperm(0x378, 1, 1)) {
    printf("Cannot open LPT port\n");
    return 1;
  }
  buf = inb(0x378);
  if (argc == 3) {
    if (strlen(argv[2]) == 1) {
      if (!strcmp("on", argv[1])) {
        switch (argv[2][0]) {
        case '4':
          buf |= 1;
          break;
        case '3':
          buf |= 2;
          break;
        case '2':
          buf |= 4;
          break;
        case '1':
          buf |= 8;
          break;
        }
      } else if (!strcmp("off", argv[1])) {
        switch (argv[2][0]) {
        case '4':
          buf &= 254;
          break;
        case '3':
          buf &= 253;
          break;
        case '2':
          buf &= 251;
          break;
        case '1':
          buf &= 247;
          break;
        }
      }
    }
  } else if (argc == 2 && !strcmp("reset", argv[1]))
    buf = 0;
  outb(buf, 0x378);
  for (i = 1; i != 5; i++)
    printf("relay%d: %s\n", i, (buf & (16 >> i)) == (16 >> i) ? "on" : "off");
  return 0;
}
```