ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L10
L49:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  mov    -0x1c(%rbp),%ebx
  cltd
  idiv   %ebx
  mov    %eax,%ebx
  mov    -0x20(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x1c(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <ceil@plt>
  cmp    %eax,%ebx
  jne    L2
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L10
L2:
  mov    -0x20(%rbp),%eax
  mov    -0x20(%rbp),%edx
  mov    %edx,%ecx
  neg    %ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L10:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jg     L49
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D31
type: string
name: read_data
arguments: data_tag: D15
type: string
name: read_data
arguments: data_tag: D26
type: string
name: read_data
arguments: data_tag: D9
type: string

tool: D31: %d

tool: D15: %d%d

tool: D26: 0 %d


tool: D9: %d %d


assistant: ```c
int main() {
  int T;
  int x, k;
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%d%d", &x, &k);
    if (x / k == (int)ceil(1.0 * x / k)) {
      printf("0 %d\n", k);
    } else {
      printf("%d %d\n", -x, x);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L1
  lea    0x14(%rsp),%r12
  lea    D2(%rip),%rbp
  lea    D32(%rip),%r13
  lea    D31(%rip),%r14
  jmp    L3
L41:
  mov    0x14(%rsp),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L35:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L1
L3:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  divsd  %xmm1,%xmm0
  call   <ceil@plt>
  cmp    %eax,%ebx
  je     L41
  mov    0x10(%rsp),%edx
  mov    %edx,%esi
  neg    %esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L35
L1:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D22
data_type: string
name: disassemble_data
arguments: label: D2
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string
name: disassemble_data
arguments: label: D31
data_type: string

tool: D22: %d

tool: D2: %d%d

tool: D32: %d %d


tool: D31: 0 %d


assistant: ```c
int main() {
  int T;
  int x, k;
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%d%d", &x, &k);
    if (x / k == (int)ceil(1.0 * x / k)) {
      printf("0 %d\n", k);
    } else {
      printf("%d %d\n", -x, x);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D31(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L8
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D20(%rip),%rbp
  lea    D34(%rip),%r14
  lea    D28(%rip),%r15
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L9:
  mov    0x10(%rsp),%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %edx,%esi
  neg    %esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L8
L1:
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm0
  mov    %esi,%eax
  cvtsi2sd %ecx,%xmm1
  cltd
  idiv   %ecx
  divsd  %xmm1,%xmm0
  mov    %eax,%ebx
  call   <ceil@plt>
  cmp    %eax,%ebx
  jne    L9
  mov    0x14(%rsp),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L1
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D31
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D34
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string

tool: D31: %d

tool: D20: %d%d

tool: D34: %d %d


tool: D28: 0 %d


assistant: ```c
int main() {
  int T;
  int x, k;
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%d%d", &x, &k);
    if (x / k == (int)ceil(1.0 * x / k)) {
      printf("0 %d\n", k);
    } else {
      printf("%d %d\n", -x, x);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D4(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L15
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D35(%rip),%rbp
  lea    D8(%rip),%r14
  lea    D29(%rip),%r15
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L28:
  mov    0x10(%rsp),%edx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %edx,%esi
  neg    %esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L15
L48:
  mov    %r13,%rdx
  mov    %r12,%rsi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0x14(%rsp),%ecx
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm0
  mov    %esi,%eax
  cvtsi2sd %ecx,%xmm1
  cltd
  idiv   %ecx
  divsd  %xmm1,%xmm0
  mov    %eax,%ebx
  call   <ceil@plt>
  cmp    %eax,%ebx
  jne    L28
  mov    0x14(%rsp),%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L48
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_guessed: string
name: parse_data
arguments: label: D35
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D29
type_guessed: string

tool: D4: %d

tool: D35: %d%d

tool: D8: %d %d


tool: D29: 0 %d


assistant: ```c
int main() {
  int T;
  int x, k;
  scanf("%d", &T);
  while (T-- > 0) {
    scanf("%d%d", &x, &k);
    if (x / k == (int)ceil(1.0 * x / k)) {
      printf("0 %d\n", k);
    } else {
      printf("%d %d\n", -x, x);
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %edi,-0xd4(%rbp)
  mov    %esi,-0xd8(%rbp)
  mov    %edx,-0xdc(%rbp)
  mov    %ecx,-0xe0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x14,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0xffffffff,-0xc0(%rbp)
  jmp    L137
L2:
  movl   $0xffffffff,-0xbc(%rbp)
  jmp    L135
L126:
  movl   $0xffffffff,-0xb8(%rbp)
  jmp    L7
L28:
  movl   $0xffffffff,-0xb4(%rbp)
  jmp    L59
L23:
  mov    -0xc0(%rbp),%eax
  imul   -0xd4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xbc(%rbp),%eax
  imul   -0xd8(%rbp),%eax
  add    %eax,%edx
  mov    -0xb8(%rbp),%eax
  imul   -0xdc(%rbp),%eax
  add    %eax,%edx
  mov    -0xb4(%rbp),%eax
  imul   -0xe0(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc4(%rbp)
  cmpl   $0x0,-0xc4(%rbp)
  jle    L47
  mov    -0xc4(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0xb0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0xb0(%rbp,%rax,4)
L47:
  mov    -0xb4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xb4(%rbp)
L59:
  mov    -0xb4(%rbp),%eax
  cmp    $0x1,%eax
  jle    L23
  mov    -0xb8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xb8(%rbp)
L7:
  mov    -0xb8(%rbp),%eax
  cmp    $0x1,%eax
  jle    L28
  mov    -0xbc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xbc(%rbp)
L135:
  mov    -0xbc(%rbp),%eax
  cmp    $0x1,%eax
  jle    L126
  mov    -0xc0(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc0(%rbp)
L137:
  mov    -0xc0(%rbp),%eax
  cmp    $0x1,%eax
  jle    L2
  movl   $0x0,-0xc8(%rbp)
  jmp    L34
L133:
  mov    -0xc8(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L79
  mov    $0x0,%eax
  jmp    L42
L79:
  addl   $0x1,-0xc8(%rbp)
L34:
  cmpl   $0x27,-0xc8(%rbp)
  jle    L133
  mov    $0x1,%eax
L42:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L88
  call   <__stack_chk_fail@plt>
L88:
  leave
  ret
```

assistant: ```c
int fun(int a0, int a1, int a2, int a3) {
  int b[4], i, sum, c[40] = {0};
  for (b[0] = -1; b[0] < 2; b[0]++)
    for (b[1] = -1; b[1] < 2; b[1]++)
      for (b[2] = -1; b[2] < 2; b[2]++)
        for (b[3] = -1; b[3] < 2; b[3]++) {
          sum = b[0] * a0 + b[1] * a1 + b[2] * a2 + b[3] * a3;
          if (sum > 0)
            c[sum - 1]++;
        }
  for (i = 0; i < 40; i++)
    if (c[i] == 0)
      return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fun>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %edi,%r11d
  mov    %esi,%ebx
  mov    %edx,%r9d
  mov    %ecx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x14,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %r11d,%r13d
  neg    %r13d
  mov    $0x3,%r12d
  lea    (%r8,%rdx,1),%r14d
  add    %esi,%r14d
  jmp    L127
L14:
  add    %r8d,%eax
  sub    $0x1,%edx
  je     L101
L43:
  test   %eax,%eax
  jle    L14
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  addl   $0x1,(%rsp,%rcx,4)
  jmp    L14
L101:
  add    %r9d,%edi
  sub    $0x1,%esi
  je     L79
L129:
  mov    %edi,%eax
  mov    $0x3,%edx
  jmp    L43
L79:
  add    %ebx,%ebp
  sub    $0x1,%r10d
  je     L97
L90:
  mov    %ebp,%edi
  mov    $0x3,%esi
  jmp    L129
L97:
  add    %r11d,%r13d
  sub    $0x1,%r12d
  je     L60
L127:
  mov    %r13d,%ebp
  sub    %r14d,%ebp
  mov    $0x3,%r10d
  jmp    L90
L60:
  mov    %rsp,%rax
  lea    0xa0(%rsp),%rcx
L107:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L72
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L107
  mov    $0x1,%edx
L72:
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %edx,%eax
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fun(int a0, int a1, int a2, int a3) {
  int b[4], i, sum, c[40] = {0};
  for (b[0] = -1; b[0] < 2; b[0]++)
    for (b[1] = -1; b[1] < 2; b[1]++)
      for (b[2] = -1; b[2] < 2; b[2]++)
        for (b[3] = -1; b[3] < 2; b[3]++) {
          sum = b[0] * a0 + b[1] * a1 + b[2] * a2 + b[3] * a3;
          if (sum > 0)
            c[sum - 1]++;
        }
  for (i = 0; i < 40; i++)
    if (c[i] == 0)
      return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<fun>:
  endbr64
  push   %r15
  mov    %ecx,%r8d
  mov    $0x14,%ecx
  mov    %edx,%r10d
  push   %r14
  lea    (%r8,%rdx,1),%r15d
  push   %r13
  add    %esi,%r15d
  mov    $0x3,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %ebx,%r14d
  neg    %r14d
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  mov    %r9,%rdi
  rep stos %rax,%es:(%rdi)
L68:
  mov    %r14d,%r12d
  mov    $0x3,%r11d
  sub    %r15d,%r12d
L90:
  mov    %r12d,%edi
  mov    $0x3,%esi
L57:
  mov    %edi,%eax
  mov    $0x3,%edx
L96:
  test   %eax,%eax
  jle    L81
  lea    -0x1(%rax),%ecx
  movslq %ecx,%rcx
  addl   $0x1,(%rsp,%rcx,4)
L81:
  add    %r8d,%eax
  sub    $0x1,%edx
  jne    L96
  add    %r10d,%edi
  sub    $0x1,%esi
  jne    L57
  add    %ebp,%r12d
  sub    $0x1,%r11d
  jne    L90
  add    %ebx,%r14d
  sub    $0x1,%r13d
  jne    L68
  lea    0xa0(%rsp),%rdx
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L47:
  add    $0x4,%r9
  cmp    %r9,%rdx
  je     L6
L75:
  mov    (%r9),%eax
  test   %eax,%eax
  jne    L47
L13:
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L87
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    $0x1,%eax
  jmp    L13
L87:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fun(int a0, int a1, int a2, int a3) {
  int b[4], i, sum, c[40] = {0};
  for (b[0] = -1; b[0] < 2; b[0]++)
    for (b[1] = -1; b[1] < 2; b[1]++)
      for (b[2] = -1; b[2] < 2; b[2]++)
        for (b[3] = -1; b[3] < 2; b[3]++) {
          sum = b[0] * a0 + b[1] * a1 + b[2] * a2 + b[3] * a3;
          if (sum > 0)
            c[sum - 1]++;
        }
  for (i = 0; i < 40; i++)
    if (c[i] == 0)
      return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<WaitCDSPBitRelease>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %esi,%eax
  mov    %rcx,-0x48(%rbp)
  mov    %r8,-0x50(%rbp)
  mov    %edi,%ecx
  mov    %cl,-0x34(%rbp)
  mov    %ax,-0x38(%rbp)
  mov    %edx,%eax
  mov    %al,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0xfffffffffffffffe,-0x18(%rbp)
  movb   $0x30,-0xa(%rbp)
  movzwl -0x38(%rbp),%eax
  mov    %al,-0x9(%rbp)
  jmp    L7
L18:
  movzbl -0x34(%rbp),%eax
  lea    -0xa(%rbp),%rcx
  mov    $0x2,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <McSrv_WriteI2C@plt>
  movzbl -0x34(%rbp),%eax
  mov    $0x19,%esi
  mov    %eax,%edi
  call   <McSrv_ReadI2C@plt>
  mov    %al,-0x21(%rbp)
  movzbl -0x21(%rbp),%eax
  and    -0x3c(%rbp),%al
  test   %al,%al
  jne    L38
  movq   $0x0,-0x18(%rbp)
  jmp    L39
L38:
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <McSrv_Sleep@plt>
  addq   $0x1,-0x20(%rbp)
L7:
  mov    -0x20(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  jb     L18
L39:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
signed long WaitCDSPBitRelease(unsigned char bSlaveAddr, unsigned short wRegAddr, unsigned char bBit, unsigned long dCycleTime, unsigned long dTimeOut) {
  unsigned char bData;
  unsigned long dCycles;
  signed long sdRet;
  unsigned char abWriteData[2];
  dCycles = 0;
  sdRet = (-2);
  abWriteData[0] = (24) << 1;
  abWriteData[1] = (unsigned char)wRegAddr;
  while (dCycles < dTimeOut) {
    McSrv_WriteI2C(bSlaveAddr, abWriteData, 2);
    bData = McSrv_ReadI2C(bSlaveAddr, (25));
    if (0 == (bData & bBit)) {
      sdRet = ((signed long)0);
      break;
    }
    McSrv_Sleep(dCycleTime);
    dCycles++;
  }
  return sdRet;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<WaitCDSPBitRelease>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x30,0x6(%rsp)
  mov    %sil,0x7(%rsp)
  test   %r8,%r8
  je     L53
  mov    %rcx,%r14
  mov    %r8,%r12
  mov    %edx,%r13d
  mov    $0x0,%ebx
  movzbl %dil,%ebp
L35:
  lea    0x6(%rsp),%rsi
  mov    $0x2,%edx
  mov    %ebp,%edi
  call   <McSrv_WriteI2C@plt>
  mov    $0x19,%esi
  mov    %ebp,%edi
  call   <McSrv_ReadI2C@plt>
  test   %r13b,%al
  je     L9
  mov    %r14,%rdi
  call   <McSrv_Sleep@plt>
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L35
  mov    $0xfffffffffffffffe,%rax
  jmp    L41
L53:
  mov    $0xfffffffffffffffe,%rax
  jmp    L41
L9:
  mov    $0x0,%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed long WaitCDSPBitRelease(unsigned char bSlaveAddr, unsigned short wRegAddr, unsigned char bBit, unsigned long dCycleTime, unsigned long dTimeOut) {
  unsigned char bData;
  unsigned long dCycles;
  signed long sdRet;
  unsigned char abWriteData[2];
  dCycles = 0;
  sdRet = (-2);
  abWriteData[0] = (24) << 1;
  abWriteData[1] = (unsigned char)wRegAddr;
  while (dCycles < dTimeOut) {
    McSrv_WriteI2C(bSlaveAddr, abWriteData, 2);
    bData = McSrv_ReadI2C(bSlaveAddr, (25));
    if (0 == (bData & bBit)) {
      sdRet = ((signed long)0);
      break;
    }
    McSrv_Sleep(dCycleTime);
    dCycles++;
  }
  return sdRet;
}
```
user: What is the c source code of the assembly code below:

```asm
<WaitCDSPBitRelease>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x30,0x6(%rsp)
  mov    %sil,0x7(%rsp)
  test   %r8,%r8
  je     L1
  mov    %rcx,%r14
  mov    %r8,%r12
  mov    %edx,%r13d
  movzbl %dil,%ebp
  xor    %ebx,%ebx
  lea    0x6(%rsp),%r15
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L44:
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <McSrv_Sleep@plt>
  cmp    %rbx,%r12
  je     L1
L41:
  mov    %r15,%rsi
  mov    %ebp,%edi
  mov    $0x2,%edx
  call   <McSrv_WriteI2C@plt>
  mov    $0x19,%esi
  mov    %ebp,%edi
  call   <McSrv_ReadI2C@plt>
  test   %r13b,%al
  jne    L44
  xor    %eax,%eax
  jmp    L57
  nopl   (%rax)
L1:
  mov    $0xfffffffffffffffe,%rax
L57:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed long WaitCDSPBitRelease(unsigned char bSlaveAddr, unsigned short wRegAddr, unsigned char bBit, unsigned long dCycleTime, unsigned long dTimeOut) {
  unsigned char bData;
  unsigned long dCycles;
  signed long sdRet;
  unsigned char abWriteData[2];
  dCycles = 0;
  sdRet = (-2);
  abWriteData[0] = (24) << 1;
  abWriteData[1] = (unsigned char)wRegAddr;
  while (dCycles < dTimeOut) {
    McSrv_WriteI2C(bSlaveAddr, abWriteData, 2);
    bData = McSrv_ReadI2C(bSlaveAddr, (25));
    if (0 == (bData & bBit)) {
      sdRet = ((signed long)0);
      break;
    }
    McSrv_Sleep(dCycleTime);
    dCycles++;
  }
  return sdRet;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<WaitCDSPBitRelease>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x30,0x6(%rsp)
  mov    %sil,0x7(%rsp)
  test   %r8,%r8
  je     L35
  mov    %rcx,%r14
  mov    %r8,%r12
  mov    %edx,%r13d
  movzbl %dil,%ebp
  xor    %ebx,%ebx
  lea    0x6(%rsp),%r15
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <McSrv_Sleep@plt>
  cmp    %rbx,%r12
  je     L35
L39:
  mov    %r15,%rsi
  mov    %ebp,%edi
  mov    $0x2,%edx
  call   <McSrv_WriteI2C@plt>
  mov    $0x19,%esi
  mov    %ebp,%edi
  call   <McSrv_ReadI2C@plt>
  test   %r13b,%al
  jne    L27
  xor    %eax,%eax
  jmp    L23
  nopl   (%rax)
L35:
  mov    $0xfffffffffffffffe,%rax
L23:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
signed long WaitCDSPBitRelease(unsigned char bSlaveAddr, unsigned short wRegAddr, unsigned char bBit, unsigned long dCycleTime, unsigned long dTimeOut) {
  unsigned char bData;
  unsigned long dCycles;
  signed long sdRet;
  unsigned char abWriteData[2];
  dCycles = 0;
  sdRet = (-2);
  abWriteData[0] = (24) << 1;
  abWriteData[1] = (unsigned char)wRegAddr;
  while (dCycles < dTimeOut) {
    McSrv_WriteI2C(bSlaveAddr, abWriteData, 2);
    bData = McSrv_ReadI2C(bSlaveAddr, (25));
    if (0 == (bData & bBit)) {
      sdRet = ((signed long)0);
      break;
    }
    McSrv_Sleep(dCycleTime);
    dCycles++;
  }
  return sdRet;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string

tool: D1: your login name is: '%s'


assistant: ```c
int main(int argc, char **argv) {
  printf("your login name is: '%s'\n", getlogin());
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getlogin@plt>
  mov    %rax,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D0: your login name is: '%s'


assistant: ```c
int main(int argc, char **argv) {
  printf("your login name is: '%s'\n", getlogin());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getlogin@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: your login name is: '%s'


assistant: ```c
int main(int argc, char **argv) {
  printf("your login name is: '%s'\n", getlogin());
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getlogin@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
data_type: string

tool: D0: your login name is: '%s'


assistant: ```c
int main(int argc, char **argv) {
  printf("your login name is: '%s'\n", getlogin());
  return 0;
}
```