ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<semap_wait>:
  endbr64
  push   %r12
  neg    %edx
  movd   %esi,%xmm0
  movd   %edx,%xmm1
  mov    $0x1,%edx
  punpckldq %xmm1,%xmm0
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movq   %xmm0,(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <semop@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L6
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L6:
  mov    D7(%rip),%rax
  xor    %edi,%edi
  mov    (%rax),%esi
  call   <kill@plt>
  jmp    L4
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int semap_wait(int sem_id, int nsem, int cnt) {
  struct sembuf op[1];
  op[0].sem_num = nsem;
  op[0].sem_op = -cnt;
  op[0].sem_flg = 0;
  int ret;
  ret = semop(sem_id, op, 1);
  if (ret == -1) {
    kill(0, SIGINT);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<special>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5e,%eax
  jne    L38
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x3f,-0x1(%rbp)
  jne    L37
  movzbl -0x1(%rbp),%eax
  or     $0x40,%eax
  mov    %al,-0x2(%rbp)
  jmp    L6
L37:
  movzbl -0x1(%rbp),%eax
  and    $0x1f,%eax
  mov    %al,-0x2(%rbp)
  jmp    L6
L38:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x2(%rbp)
  nop
L6:
  movzbl -0x2(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char special(char *s) {
  char c;
  char b;
  switch (*s) {
  case '^':
    b = *++s;
    if (b == '?') {
      c = b | 0x40;
    } else {
      c = b & 0x1f;
    }
    break;
  default:
    c = *s;
    break;
  }
  return c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<special>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x5e,%al
  je     L10
L8:
  ret
L10:
  movzbl 0x1(%rdi),%edx
  mov    %edx,%eax
  and    $0x1f,%eax
  cmp    $0x3f,%dl
  mov    $0x7f,%edx
  cmove  %edx,%eax
  jmp    L8
```

assistant: ```c
char special(char *s) {
  char c;
  char b;
  switch (*s) {
  case '^':
    b = *++s;
    if (b == '?') {
      c = b | 0x40;
    } else {
      c = b & 0x1f;
    }
    break;
  default:
    c = *s;
    break;
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<special>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x5e,%al
  je     L0
  ret
  nopl   0x0(%rax)
L0:
  movzbl 0x1(%rdi),%edx
  mov    %edx,%eax
  and    $0x1f,%eax
  cmp    $0x3f,%dl
  mov    $0x7f,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
char special(char *s) {
  char c;
  char b;
  switch (*s) {
  case '^':
    b = *++s;
    if (b == '?') {
      c = b | 0x40;
    } else {
      c = b & 0x1f;
    }
    break;
  default:
    c = *s;
    break;
  }
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<special>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x5e,%al
  je     L8
  ret
  nopl   0x0(%rax)
L8:
  movzbl 0x1(%rdi),%edx
  mov    %edx,%eax
  and    $0x1f,%eax
  cmp    $0x3f,%dl
  mov    $0x7f,%edx
  cmove  %edx,%eax
  ret
```

assistant: ```c
char special(char *s) {
  char c;
  char b;
  switch (*s) {
  case '^':
    b = *++s;
    if (b == '?') {
      c = b | 0x40;
    } else {
      c = b & 0x1f;
    }
    break;
  default:
    c = *s;
    break;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<karma_modified>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <karma_quit@plt>
  mov    $0x0,%eax
  call   <karma_load@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void karma_modified(void) {
  karma_quit();
  karma_load();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<karma_modified>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <karma_quit@plt>
  mov    $0x0,%eax
  call   <karma_load@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void karma_modified(void) {
  karma_quit();
  karma_load();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<karma_modified>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <karma_quit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <karma_load@plt>
```

assistant: ```c
void karma_modified(void) {
  karma_quit();
  karma_load();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<karma_modified>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <karma_quit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <karma_load@plt>
```

assistant: ```c
void karma_modified(void) {
  karma_quit();
  karma_load();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<join_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L24
L30:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    (%rbx,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L37
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L37
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L37:
  addl   $0x1,-0x24(%rbp)
L24:
  cmpl   $0x3e7,-0x24(%rbp)
  jle    L30
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *join_strings(char *output_str_array[]) {
  char *final_str = malloc(strlen(output_str_array[0]));
  final_str = output_str_array[0];
  size_t length_of_prev_strings = strlen(output_str_array[0]);
  for (int i = 1; i < 1000; i++) {
    final_str = realloc(final_str, strlen(final_str) + strlen(output_str_array[i]));
    if (final_str && output_str_array[i] != NULL) {
      strcat(final_str, output_str_array[i]);
    }
  }
  return final_str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<join_strings>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  lea    0x8(%rdi),%r12
  lea    0x1f40(%rdi),%r13
  jmp    L13
L31:
  add    $0x8,%r12
  cmp    %r13,%r12
  je     L21
L13:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    (%r12),%rdi
  call   <strlen@plt>
  lea    0x0(%rbp,%rax,1),%rsi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L31
  mov    (%r12),%rsi
  test   %rsi,%rsi
  je     L31
  mov    %rax,%rdi
  call   <strcat@plt>
  jmp    L31
L21:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *join_strings(char *output_str_array[]) {
  char *final_str = malloc(strlen(output_str_array[0]));
  final_str = output_str_array[0];
  size_t length_of_prev_strings = strlen(output_str_array[0]);
  for (int i = 1; i < 1000; i++) {
    final_str = realloc(final_str, strlen(final_str) + strlen(output_str_array[i]));
    if (final_str && output_str_array[i] != NULL) {
      strcat(final_str, output_str_array[i]);
    }
  }
  return final_str;
}
```
user: What is the c source code of the assembly code below?

```asm
<join_strings>:
  endbr64
  push   %r13
  lea    0x1f40(%rdi),%r13
  push   %r12
  lea    0x8(%rdi),%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  nopl   0x0(%rax)
L24:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%r12),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    (%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L6
  mov    (%r12),%rsi
  test   %rsi,%rsi
  je     L6
  mov    %rax,%rdi
  call   <strcat@plt>
L6:
  add    $0x8,%r12
  cmp    %r12,%r13
  jne    L24
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *join_strings(char *output_str_array[]) {
  char *final_str = malloc(strlen(output_str_array[0]));
  final_str = output_str_array[0];
  size_t length_of_prev_strings = strlen(output_str_array[0]);
  for (int i = 1; i < 1000; i++) {
    final_str = realloc(final_str, strlen(final_str) + strlen(output_str_array[i]));
    if (final_str && output_str_array[i] != NULL) {
      strcat(final_str, output_str_array[i]);
    }
  }
  return final_str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<join_strings>:
  endbr64
  push   %r13
  lea    0x1f40(%rdi),%r13
  push   %r12
  lea    0x8(%rdi),%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  nopl   0x0(%rax)
L13:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    (%r12),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  lea    (%rbx,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L11
  mov    (%r12),%rsi
  test   %rsi,%rsi
  je     L11
  mov    %rax,%rdi
  call   <strcat@plt>
L11:
  add    $0x8,%r12
  cmp    %r12,%r13
  jne    L13
  add    $0x8,%rsp
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *join_strings(char *output_str_array[]) {
  char *final_str = malloc(strlen(output_str_array[0]));
  final_str = output_str_array[0];
  size_t length_of_prev_strings = strlen(output_str_array[0]);
  for (int i = 1; i < 1000; i++) {
    final_str = realloc(final_str, strlen(final_str) + strlen(output_str_array[i]));
    if (final_str && output_str_array[i] != NULL) {
      strcat(final_str, output_str_array[i]);
    }
  }
  return final_str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<averageConnectionTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L18
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double averageConnectionTime(int a[], int n) {
  int sum = 0;
  int i = 0;
  for (i = 1; i <= n; i++)
    sum = sum + a[i];
  return (double)sum / n;
}
```
user: What is the c source code of the assembly code below:

```asm
<averageConnectionTime>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    0x4(%rdi),%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L15:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
L24:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L21:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
double averageConnectionTime(int a[], int n) {
  int sum = 0;
  int i = 0;
  for (i = 1; i <= n; i++)
    sum = sum + a[i];
  return (double)sum / n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<averageConnectionTime>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi),%rax
  lea    0x8(%rdi,%rdx,4),%rcx
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L0
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %edx,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
L8:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double averageConnectionTime(int a[], int n) {
  int sum = 0;
  int i = 0;
  for (i = 1; i <= n; i++)
    sum = sum + a[i];
  return (double)sum / n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<averageConnectionTime>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L59
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L45
  mov    %esi,%ecx
  lea    0x4(%rdi),%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x14(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L58:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L58
  movdqa %xmm0,%xmm1
  mov    %edx,%esi
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%esi
  paddd  %xmm1,%xmm0
  lea    0x1(%rsi),%ecx
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edx
  je     L37
L11:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  add    (%rdi,%rsi,4),%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jl     L37
  add    $0x2,%ecx
  add    0x4(%rdi,%r8,1),%eax
  cmp    %ecx,%edx
  jl     L37
  add    0x8(%rdi,%r8,1),%eax
L37:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm0
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  ret
  xchg   %ax,%ax
L59:
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm1
  divsd  %xmm1,%xmm0
  ret
L45:
  mov    $0x1,%ecx
  xor    %eax,%eax
  jmp    L11
```

assistant: ```c
double averageConnectionTime(int a[], int n) {
  int sum = 0;
  int i = 0;
  for (i = 1; i <= n; i++)
    sum = sum + a[i];
  return (double)sum / n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<consommateur>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L6:
  mov    $0x0,%eax
  call   <consommer@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: (%ld) - %d


assistant: ```c
long consommateur(long thrdID) {
  while (1) {
    int donnee = consommer();
    printf("(%ld) - %d\n", thrdID, donnee);
  }
  return thrdID;
}
```
user: Translate the below assembly code into C programming language:

```asm
<consommateur>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    D3(%rip),%rbp
L4:
  mov    $0x0,%eax
  call   <consommer@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: (%ld) - %d


assistant: ```c
long consommateur(long thrdID) {
  while (1) {
    int donnee = consommer();
    printf("(%ld) - %d\n", thrdID, donnee);
  }
  return thrdID;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<consommateur>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  call   <consommer@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2: (%ld) - %d


assistant: ```c
long consommateur(long thrdID) {
  while (1) {
    int donnee = consommer();
    printf("(%ld) - %d\n", thrdID, donnee);
  }
  return thrdID;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<consommateur>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  xor    %eax,%eax
  call   <consommer@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: (%ld) - %d


assistant: ```c
long consommateur(long thrdID) {
  while (1) {
    int donnee = consommer();
    printf("(%ld) - %d\n", thrdID, donnee);
  }
  return thrdID;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_multicast_ether_addr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_multicast_ether_addr(const void *addr) {
  const uint8_t *addr_bytes = addr;
  return (addr_bytes[0] & 0x01);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_multicast_ether_addr>:
  endbr64
  mov    (%rdi),%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int is_multicast_ether_addr(const void *addr) {
  const uint8_t *addr_bytes = addr;
  return (addr_bytes[0] & 0x01);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_multicast_ether_addr>:
  endbr64
  mov    (%rdi),%eax
  and    $0x1,%eax
  ret
```

assistant: ```c
int is_multicast_ether_addr(const void *addr) {
  const uint8_t *addr_bytes = addr;
  return (addr_bytes[0] & 0x01);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type: string

tool: D9: %f 

assistant: ```c
void Print_vector(double b[], int n, char title[]) {
  int i;
  printf("%s\n", title);
  for (i = 0; i < n; i++)
    printf("%f ", b[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<Print_vector>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L12
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D4(%rip),%rbp
L0:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L0
L12:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
datatype: string

tool: D4: %f 

assistant: ```c
void Print_vector(double b[], int n, char title[]) {
  int i;
  printf("%s\n", title);
  for (i = 0; i < n; i++)
    printf("%f ", b[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Print_vector>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L15
  lea    -0x1(%rbp),%eax
  lea    D9(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L17:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L17
L15:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: %f 

assistant: ```c
void Print_vector(double b[], int n, char title[]) {
  int i;
  printf("%s\n", title);
  for (i = 0; i < n; i++)
    printf("%f ", b[i]);
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Print_vector>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  call   <puts@plt>
  test   %ebp,%ebp
  jle    L9
  lea    -0x1(%rbp),%eax
  lea    D1(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L1
L9:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <putchar@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: %f 

assistant: ```c
void Print_vector(double b[], int n, char title[]) {
  int i;
  printf("%s\n", title);
  for (i = 0; i < n; i++)
    printf("%f ", b[i]);
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_print_usage_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: Usage: %s [OPTION]... [FILE]
Read a list and retrieve some data out of it.


assistant: ```c
void _print_usage_header(const char *command) {
  printf("Usage: %s [OPTION]... [FILE]\n"
         "Read a list and retrieve some data out of it.\n",
         command);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_print_usage_header>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: Usage: %s [OPTION]... [FILE]
Read a list and retrieve some data out of it.


assistant: ```c
void _print_usage_header(const char *command) {
  printf("Usage: %s [OPTION]... [FILE]\n"
         "Read a list and retrieve some data out of it.\n",
         command);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_print_usage_header>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: Usage: %s [OPTION]... [FILE]
Read a list and retrieve some data out of it.


assistant: ```c
void _print_usage_header(const char *command) {
  printf("Usage: %s [OPTION]... [FILE]\n"
         "Read a list and retrieve some data out of it.\n",
         command);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_print_usage_header>:
  endbr64
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: Usage: %s [OPTION]... [FILE]
Read a list and retrieve some data out of it.


assistant: ```c
void _print_usage_header(const char *command) {
  printf("Usage: %s [OPTION]... [FILE]\n"
         "Read a list and retrieve some data out of it.\n",
         command);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movabs $0x10000000000,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x61,(%rax)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(1024ULL * 1024ULL * 1024ULL * 1024ULL);
  x[0] = 'a';
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(1024ULL * 1024ULL * 1024ULL * 1024ULL);
  x[0] = 'a';
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(1024ULL * 1024ULL * 1024ULL * 1024ULL);
  x[0] = 'a';
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char *x = malloc(1024ULL * 1024ULL * 1024ULL * 1024ULL);
  x[0] = 'a';
  return 0;
}
```