user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x84(%rbp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    -0x84(%rbp),%eax
  test   %eax,%eax
  jle    L2
  lea    -0x80(%rbp),%r13
  mov    $0x0,%r12d
  lea    D1(%rip),%r14
L123:
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x84(%rbp),%ebx
  add    $0x4,%r13
  cmp    %r12d,%ebx
  jg     L123
  movslq %ebx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L4:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L4
L38:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L113
  orq    $0x0,-0x8(%rsp,%rax,1)
L113:
  lea    0x3(%rsp),%r9
  mov    %r9,%r12
  shr    $0x2,%r12
  and    $0xfffffffffffffffc,%r9
  mov    %ebx,%r10d
  test   %ebx,%ebx
  jle    L22
  movl   $0x1,0x0(,%r12,4)
  lea    0x4(%r9),%r11
  mov    $0x4,%ecx
  mov    $0x0,%r10d
  jmp    L26
L171:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L191
L177:
  cmp    (%rax,%rsi,1),%edi
  jle    L171
  mov    (%r9,%rax,1),%edx
  cmp    (%r8),%edx
  jl     L171
  add    $0x1,%edx
  mov    %edx,(%r8)
  jmp    L171
L191:
  add    $0x4,%r11
  add    $0x4,%rcx
L26:
  add    $0x1,%r10d
  cmp    %r10d,%ebx
  je     L22
  mov    %r11,%r8
  movl   $0x1,(%r11)
  test   %r10d,%r10d
  jle    L191
  mov    -0x80(%rbp,%rcx,1),%edi
  mov    $0x0,%eax
  lea    -0x80(%rbp),%rsi
  jmp    L177
L22:
  mov    0x0(,%r12,4),%esi
  cmp    $0x1,%r10d
  jle    L197
  lea    0x4(%r9),%rax
  lea    -0x2(%r10),%edx
  lea    0x8(%r9,%rdx,4),%rcx
L136:
  mov    (%rax),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L136
L197:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L2:
  cltq
  lea    0xf(,%rax,4),%rdx
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L169:
  cmp    %rcx,%rsp
  je     L10
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L169
L10:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L104
  orq    $0x0,-0x8(%rsp,%rdx,1)
L104:
  mov    (%rsp),%esi
  jmp    L197
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string

tool: D1: %d

assistant: ```c
int main() {
  int A[20];
  int N;
  int big;
  int a, i, j, k;
  scanf("%d", &N);
  for (a = 0; a < N; a++) {
    scanf("%d", &A[a]);
  }
  int Maxtill[N];
  for (i = 0; i < N; i++) {
    Maxtill[i] = 1;
    for (j = 0; j < i; j++) {
      if (A[i] > A[j]) {
        if ((1 + Maxtill[j]) > Maxtill[i]) {
          Maxtill[i] = Maxtill[j] + 1;
        }
      }
    }
  }
  big = Maxtill[0];
  for (k = 1; k < N; k++) {
    if (Maxtill[k] > big)
      big = Maxtill[k];
  }
  printf("%d", big);
  return 0;
}
```