ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<combination>:
  endbr64
  test   %esi,%esi
  jle    L24
  movslq %edi,%rdi
  lea    -0x1(%rsi),%esi
  lea    -0x1(%rdi),%rdx
  sub    %rsi,%rdx
  mov    $0x1,%eax
L27:
  imul   %rdi,%rax
  sub    $0x1,%rdi
  cmp    %rdx,%rdi
  jne    L27
  add    $0x2,%rsi
  mov    $0x1,%ecx
L21:
  mov    $0x0,%edx
  div    %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L21
  ret
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long combination(int m, int n) {
  int i;
  unsigned long temp;
  temp = 1;
  for (i = 1; i <= n; i++) {
    temp *= m;
    m--;
  }
  for (i = 1; i <= n; i++)
    temp /= i;
  return temp;
}
```
user: What is the c source code of the assembly code below?

```asm
<combination>:
  endbr64
  test   %esi,%esi
  jle    L18
  movslq %edi,%rdi
  sub    $0x1,%esi
  mov    $0x1,%eax
  lea    -0x1(%rdi),%rdx
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  jmp    L12
  nop
L34:
  sub    $0x1,%rdx
L12:
  imul   %rdi,%rax
  mov    %rdx,%rdi
  cmp    %rcx,%rdx
  jne    L34
  add    $0x2,%rsi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L23:
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L23
  ret
  nop
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long combination(int m, int n) {
  int i;
  unsigned long temp;
  temp = 1;
  for (i = 1; i <= n; i++) {
    temp *= m;
    m--;
  }
  for (i = 1; i <= n; i++)
    temp /= i;
  return temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<combination>:
  endbr64
  test   %esi,%esi
  jle    L17
  movslq %edi,%rdi
  sub    $0x1,%esi
  mov    $0x1,%eax
  lea    -0x1(%rdi),%rdx
  mov    %rdx,%rcx
  sub    %rsi,%rcx
  jmp    L25
  nop
L10:
  sub    $0x1,%rdx
L25:
  imul   %rdi,%rax
  mov    %rdx,%rdi
  cmp    %rcx,%rdx
  jne    L10
  add    $0x2,%rsi
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L20:
  xor    %edx,%edx
  div    %rcx
  add    $0x1,%rcx
  cmp    %rcx,%rsi
  jne    L20
  ret
  nop
L17:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned long combination(int m, int n) {
  int i;
  unsigned long temp;
  temp = 1;
  for (i = 1; i <= n; i++) {
    temp *= m;
    m--;
  }
  for (i = 1; i <= n; i++)
    temp /= i;
  return temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<IsNotDistinct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xb4(%rbp)
  jle    L18
  mov    -0xd0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xb4(%rbp)
L18:
  mov    -0xc8(%rbp),%rdx
  lea    -0xb0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0xd0(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x0,-0xb8(%rbp)
  jmp    L74
L129:
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  cmp    $0x30,%al
  je     L26
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%eax
  cmp    $0x31,%al
  je     L26
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%edx
  mov    -0xb8(%rbp),%eax
  cltq
  mov    %dl,-0x60(%rbp,%rax,1)
  jmp    L101
L26:
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  cmp    $0x30,%al
  je     L101
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  cmp    $0x31,%al
  je     L101
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%edx
  mov    -0xb8(%rbp),%eax
  cltq
  mov    %dl,-0xb0(%rbp,%rax,1)
L101:
  addl   $0x1,-0xb8(%rbp)
L74:
  mov    -0xb8(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L129
  movl   $0x0,-0xb8(%rbp)
  jmp    L47
L100:
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0xb0(%rbp,%rax,1),%edx
  mov    -0xb8(%rbp),%eax
  cltq
  movzbl -0x60(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L50
  mov    $0x0,%eax
  jmp    L13
L50:
  addl   $0x1,-0xb8(%rbp)
L47:
  mov    -0xb8(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L100
  mov    $0x1,%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

assistant: ```c
int IsNotDistinct(char *a, char *b) {
  int t, len;
  char ta[80], tb[80];
  len = strlen(a);
  if (strlen(b) < len)
    len = strlen(b);
  strcpy(ta, a);
  strcpy(tb, b);
  for (t = 0; t < len; ++t) {
    if ((ta[t] != '0') && (ta[t] != '1'))
      tb[t] = ta[t];
    else if ((tb[t] != '0') && (tb[t] != '1'))
      ta[t] = tb[t];
  }
  for (t = 0; t < len; ++t)
    if (ta[t] != tb[t])
      return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IsNotDistinct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L67
L41:
  mov    %rsp,%rdi
  mov    %r12,%rsi
  call   <strcpy@plt>
  lea    0x50(%rsp),%rdi
  mov    %rbp,%rsi
  call   <strcpy@plt>
  test   %ebx,%ebx
  jle    L91
  mov    %rsp,%rax
  lea    0x50(%rsp),%rdx
  mov    %ebx,%edi
  lea    -0x1(%rbx),%ecx
  lea    0x1(%rsp,%rcx,1),%r9
  jmp    L103
L67:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L41
L95:
  movzbl (%rdx),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L7
  mov    %cl,(%rax)
L7:
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %r9,%rax
  je     L112
L103:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L95
  mov    %cl,(%rdx)
  jmp    L7
L112:
  mov    %edi,%edx
  mov    $0x0,%eax
  lea    0x50(%rsp),%rcx
L128:
  movzbl (%rcx,%rax,1),%ebx
  cmp    %bl,(%rsp,%rax,1)
  jne    L51
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L128
  mov    $0x1,%eax
  jmp    L56
L91:
  mov    $0x1,%eax
  jmp    L56
L51:
  mov    $0x0,%eax
L56:
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int IsNotDistinct(char *a, char *b) {
  int t, len;
  char ta[80], tb[80];
  len = strlen(a);
  if (strlen(b) < len)
    len = strlen(b);
  strcpy(ta, a);
  strcpy(tb, b);
  for (t = 0; t < len; ++t) {
    if ((ta[t] != '0') && (ta[t] != '1'))
      tb[t] = ta[t];
    else if ((tb[t] != '0') && (tb[t] != '1'))
      ta[t] = tb[t];
  }
  for (t = 0; t < len; ++t)
    if (ta[t] != tb[t])
      return (0);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<IsNotDistinct>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L67
L24:
  mov    %rsp,%r12
  mov    %rbp,%rsi
  lea    0x50(%rsp),%rbp
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  test   %ebx,%ebx
  jle    L5
  lea    -0x1(%rbx),%ecx
  mov    %r12,%rax
  mov    %rbp,%rdx
  lea    0x1(%rsp,%rcx,1),%rdi
  jmp    L125
  nopl   0x0(%rax,%rax,1)
L53:
  mov    %cl,(%rdx)
L77:
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rax
  je     L13
L125:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x1,%sil
  ja     L53
  movzbl (%rdx),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L77
  mov    %cl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rax
  jne    L125
L13:
  mov    %ebx,%edx
  xor    %eax,%eax
  jmp    L16
  nopl   0x0(%rax)
L103:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L5
L16:
  movzbl 0x0(%rbp,%rax,1),%ebx
  cmp    %bl,(%r12,%rax,1)
  je     L103
  xor    %eax,%eax
  jmp    L41
L5:
  mov    $0x1,%eax
L41:
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L43
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L67:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L24
L43:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int IsNotDistinct(char *a, char *b) {
  int t, len;
  char ta[80], tb[80];
  len = strlen(a);
  if (strlen(b) < len)
    len = strlen(b);
  strcpy(ta, a);
  strcpy(tb, b);
  for (t = 0; t < len; ++t) {
    if ((ta[t] != '0') && (ta[t] != '1'))
      tb[t] = ta[t];
    else if ((tb[t] != '0') && (tb[t] != '1'))
      ta[t] = tb[t];
  }
  for (t = 0; t < len; ++t)
    if (ta[t] != tb[t])
      return (0);
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<IsNotDistinct>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0xb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L75
L23:
  mov    %rsp,%r12
  mov    %rbp,%rsi
  lea    0x50(%rsp),%rbp
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  test   %ebx,%ebx
  jle    L37
  lea    -0x1(%rbx),%ecx
  mov    %r12,%rax
  mov    %rbp,%rdx
  lea    0x1(%rsp,%rcx,1),%rdi
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L74:
  mov    %cl,(%rdx)
L32:
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rax
  je     L103
L38:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x1,%sil
  ja     L74
  movzbl (%rdx),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x1,%sil
  jbe    L32
  mov    %cl,(%rax)
  add    $0x1,%rax
  add    $0x1,%rdx
  cmp    %rdi,%rax
  jne    L38
L103:
  mov    %ebx,%edx
  xor    %eax,%eax
  jmp    L14
  nopl   0x0(%rax)
L126:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L37
L14:
  movzbl 0x0(%rbp,%rax,1),%ebx
  cmp    %bl,(%r12,%rax,1)
  je     L126
  xor    %eax,%eax
  jmp    L81
L37:
  mov    $0x1,%eax
L81:
  mov    0xa8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0xb8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L75:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  jmp    L23
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int IsNotDistinct(char *a, char *b) {
  int t, len;
  char ta[80], tb[80];
  len = strlen(a);
  if (strlen(b) < len)
    len = strlen(b);
  strcpy(ta, a);
  strcpy(tb, b);
  for (t = 0; t < len; ++t) {
    if ((ta[t] != '0') && (ta[t] != '1'))
      tb[t] = ta[t];
    else if ((tb[t] != '0') && (tb[t] != '1'))
      ta[t] = tb[t];
  }
  for (t = 0; t < len; ++t)
    if (ta[t] != tb[t])
      return (0);
  return (1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<udp_sock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xffffffff,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <socket@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <htons@plt>
  mov    %eax,-0x10(%rbp)
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bind@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0xffffffff,-0x18(%rbp)
  jmp    L7
L5:
  nop
L7:
  cmpl   $0x0,-0x18(%rbp)
  je     L46
  addl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L46
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  movl   $0xffffffff,-0x1c(%rbp)
L46:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
int udp_sock(int port) {
  int fd = -1;
  int rc = 0;
  struct sockaddr_in addr_mine;
  rc = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (rc == -1) {
    goto out;
  }
  fd = rc;
  rc = 0;
  memset((char *)&addr_mine, 0, sizeof(addr_mine));
  addr_mine.sin_family = AF_INET;
  addr_mine.sin_port = htons(port);
  addr_mine.sin_addr.s_addr = htonl(INADDR_ANY);
  rc = bind(fd, (const struct sockaddr *)&addr_mine, sizeof(addr_mine));
  if (rc == -1) {
    goto out;
  }
out:
  if (rc != 0) {
    if (fd -= -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<udp_sock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D24(%rip),%rax
  mov    (%rax),%esi
  mov    D11(%rip),%rax
  mov    (%rax),%edi
  call   <socket@plt>
  mov    $0x0,%ebx
  cmp    $0xffffffff,%eax
  je     L39
  mov    %eax,%ebx
  lea    0xc(%rsp),%r12
  mov    $0xc,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x14(%rsp)
  mov    %ebp,%edi
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  mov    D45(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    %eax,0xc(%rsp)
  mov    $0xc,%edx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <bind@plt>
  test   %eax,%eax
  jne    L32
L39:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    %ebx,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  add    $0x1,%ebx
  je     L39
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0xffffffff,%ebx
  jmp    L39
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udp_sock(int port) {
  int fd = -1;
  int rc = 0;
  struct sockaddr_in addr_mine;
  rc = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (rc == -1) {
    goto out;
  }
  fd = rc;
  rc = 0;
  memset((char *)&addr_mine, 0, sizeof(addr_mine));
  addr_mine.sin_family = AF_INET;
  addr_mine.sin_port = htons(port);
  addr_mine.sin_addr.s_addr = htonl(INADDR_ANY);
  rc = bind(fd, (const struct sockaddr *)&addr_mine, sizeof(addr_mine));
  if (rc == -1) {
    goto out;
  }
out:
  if (rc != 0) {
    if (fd -= -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<udp_sock>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    D15(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%edx
  mov    D34(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L31
  lea    0xc(%rsp),%r13
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %ebp,%edi
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  mov    D28(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  test   %eax,%eax
  jne    L15
L41:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  add    $0x1,%r12d
  jne    L48
L31:
  xor    %r12d,%r12d
  jmp    L41
L48:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L41
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udp_sock(int port) {
  int fd = -1;
  int rc = 0;
  struct sockaddr_in addr_mine;
  rc = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (rc == -1) {
    goto out;
  }
  fd = rc;
  rc = 0;
  memset((char *)&addr_mine, 0, sizeof(addr_mine));
  addr_mine.sin_family = AF_INET;
  addr_mine.sin_port = htons(port);
  addr_mine.sin_addr.s_addr = htonl(INADDR_ANY);
  rc = bind(fd, (const struct sockaddr *)&addr_mine, sizeof(addr_mine));
  if (rc == -1) {
    goto out;
  }
out:
  if (rc != 0) {
    if (fd -= -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<udp_sock>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    D27(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    (%rbx),%edi
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    (%rax),%esi
  call   <socket@plt>
  cmp    $0xffffffff,%eax
  je     L32
  lea    0xc(%rsp),%r13
  xor    %esi,%esi
  mov    $0xc,%edx
  mov    %eax,%r12d
  mov    %r13,%rdi
  call   <memset@plt>
  mov    (%rbx),%eax
  mov    %ebp,%edi
  mov    %eax,0x14(%rsp)
  call   <htons@plt>
  mov    %eax,0x10(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <htonl@plt>
  mov    $0xc,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  mov    %eax,0xc(%rsp)
  call   <bind@plt>
  test   %eax,%eax
  jne    L28
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L28:
  add    $0x1,%r12d
  jne    L52
L32:
  xor    %r12d,%r12d
  jmp    L30
L52:
  mov    %r12d,%edi
  mov    $0xffffffff,%r12d
  call   <close@plt>
  jmp    L30
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int udp_sock(int port) {
  int fd = -1;
  int rc = 0;
  struct sockaddr_in addr_mine;
  rc = socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP);
  if (rc == -1) {
    goto out;
  }
  fd = rc;
  rc = 0;
  memset((char *)&addr_mine, 0, sizeof(addr_mine));
  addr_mine.sin_family = AF_INET;
  addr_mine.sin_port = htons(port);
  addr_mine.sin_addr.s_addr = htonl(INADDR_ANY);
  rc = bind(fd, (const struct sockaddr *)&addr_mine, sizeof(addr_mine));
  if (rc == -1) {
    goto out;
  }
out:
  if (rc != 0) {
    if (fd -= -1) {
      close(fd);
      fd = -1;
    }
  }
  return fd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  jmp    L25
L46:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    %eax,%edx
  mov    %edx,%ebx
  test   %ebx,%ebx
  jne    L8
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L46
L8:
  test   %ebx,%ebx
  jns    L57
  mov    $0xffffffff,%ebx
  jmp    L58
L57:
  test   %ebx,%ebx
  jle    L58
  mov    $0x1,%ebx
L58:
  mov    %ebx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcmp(char *asrc, char *adst) {
  register int ret = 0;
  while (!(ret = *asrc - *adst) && *adst)
    ++asrc, ++adst;
  if (ret < 0)
    ret = -1;
  else if (ret > 0)
    ret = 1;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  movzbl (%rsi),%edx
  movsbl (%rdi),%eax
  movsbl %dl,%ecx
  sub    %ecx,%eax
  test   %dl,%dl
  je     L28
  test   %eax,%eax
  jne    L28
  mov    $0x1,%edx
L19:
  movzbl (%rsi,%rdx,1),%ecx
  movsbl (%rdi,%rdx,1),%eax
  movsbl %cl,%r8d
  sub    %r8d,%eax
  add    $0x1,%rdx
  test   %cl,%cl
  je     L28
  test   %eax,%eax
  je     L19
L28:
  test   %eax,%eax
  mov    $0x1,%edx
  cmovg  %edx,%eax
  test   %eax,%eax
  mov    $0xffffffff,%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int strcmp(char *asrc, char *adst) {
  register int ret = 0;
  while (!(ret = *asrc - *adst) && *adst)
    ++asrc, ++adst;
  if (ret < 0)
    ret = -1;
  else if (ret > 0)
    ret = 1;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcmp>:
  endbr64
  movsbl (%rsi),%edx
  movsbl (%rdi),%eax
  mov    $0x1,%ecx
  sub    %edx,%eax
  mov    %edx,%r8d
  mov    %eax,%edx
  je     L19
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L17:
  movsbl (%rsi,%rcx,1),%r9d
  movsbl (%rdi,%rcx,1),%edx
  add    $0x1,%rcx
  mov    %r9d,%r8d
  sub    %r9d,%edx
  jne    L18
L19:
  test   %r8b,%r8b
  jne    L17
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  setne  %al
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int strcmp(char *asrc, char *adst) {
  register int ret = 0;
  while (!(ret = *asrc - *adst) && *adst)
    ++asrc, ++adst;
  if (ret < 0)
    ret = -1;
  else if (ret > 0)
    ret = 1;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcmp>:
  endbr64
  movsbl (%rsi),%edx
  movsbl (%rdi),%eax
  mov    $0x1,%ecx
  sub    %edx,%eax
  mov    %edx,%r8d
  mov    %eax,%edx
  je     L4
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L36:
  movsbl (%rsi,%rcx,1),%r9d
  movsbl (%rdi,%rcx,1),%edx
  add    $0x1,%rcx
  mov    %r9d,%r8d
  sub    %r9d,%edx
  jne    L9
L4:
  test   %r8b,%r8b
  jne    L36
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  test   %edx,%edx
  mov    $0xffffffff,%edx
  setne  %al
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int strcmp(char *asrc, char *adst) {
  register int ret = 0;
  while (!(ret = *asrc - *adst) && *adst)
    ++asrc, ++adst;
  if (ret < 0)
    ret = -1;
  else if (ret > 0)
    ret = 1;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kstrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L8
L59:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L56
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L37
  mov    $0x0,%eax
  jmp    L42
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jge    L2
  mov    $0xffffffff,%eax
  jmp    L42
L2:
  mov    $0x1,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int kstrcmp(char *str1, char *str2) {
  while ((*str1 == *str2) && *str1 && *str2) {
    str1++;
    str2++;
  }
  if (*str1 == *str2)
    return 0;
  if (*str1 < *str2)
    return -1;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<kstrcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  test   %dl,%dl
  setne  %r8b
  cmp    %cl,%dl
  sete   %al
  test   %al,%r8b
  je     L27
  test   %cl,%cl
  je     L27
  mov    $0x1,%eax
L14:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  add    $0x1,%rax
  test   %dl,%dl
  setne  %r9b
  cmp    %cl,%dl
  sete   %r8b
  test   %r8b,%r9b
  je     L27
  test   %cl,%cl
  jne    L14
L27:
  mov    $0x0,%eax
  cmp    %cl,%dl
  je     L37
  setge  %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
L37:
  ret
```

assistant: ```c
int kstrcmp(char *str1, char *str2) {
  while ((*str1 == *str2) && *str1 && *str2) {
    str1++;
    str2++;
  }
  if (*str1 == *str2)
    return 0;
  if (*str1 < *str2)
    return -1;
  else
    return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kstrcmp>:
  endbr64
  movzbl (%rdi),%ecx
  movzbl (%rsi),%edx
  mov    $0x1,%eax
  cmp    %cl,%dl
  je     L31
  jmp    L7
  nopl   (%rax)
L30:
  test   %dl,%dl
  je     L7
  movzbl (%rdi,%rax,1),%ecx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%edx
  cmp    %dl,%cl
  jne    L7
L31:
  test   %cl,%cl
  jne    L30
  xor    %eax,%eax
  test   %dl,%dl
  jne    L7
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  cmp    %dl,%cl
  setge  %al
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int kstrcmp(char *str1, char *str2) {
  while ((*str1 == *str2) && *str1 && *str2) {
    str1++;
    str2++;
  }
  if (*str1 == *str2)
    return 0;
  if (*str1 < *str2)
    return -1;
  else
    return 1;
}
```