ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<get>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
L5:
  mov    $0x0,%eax
  call   <getchar_unlocked@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jle    L5
L6:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <getchar_unlocked@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jg     L6
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int get() {
  int res = 0;
  int c;
  do {
    c = getchar_unlocked();
  } while (c <= 32);
  do {
    res = 10 * res + c - '0';
    c = getchar_unlocked();
  } while (c > 32);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get>:
  endbr64
  push   %rbx
L4:
  mov    $0x0,%eax
  call   <getchar_unlocked@plt>
  cmp    $0x20,%eax
  jle    L4
  mov    $0x0,%ebx
L11:
  lea    (%rbx,%rbx,4),%edx
  lea    -0x30(%rax,%rdx,2),%ebx
  mov    $0x0,%eax
  call   <getchar_unlocked@plt>
  cmp    $0x20,%eax
  jg     L11
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int get() {
  int res = 0;
  int c;
  do {
    c = getchar_unlocked();
  } while (c <= 32);
  do {
    res = 10 * res + c - '0';
    c = getchar_unlocked();
  } while (c > 32);
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<get>:
  endbr64
  push   %r12
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <getchar_unlocked@plt>
  cmp    $0x20,%eax
  jle    L2
  xor    %r12d,%r12d
  nop
L0:
  lea    (%r12,%r12,4),%edx
  lea    -0x30(%rax,%rdx,2),%r12d
  xor    %eax,%eax
  call   <getchar_unlocked@plt>
  cmp    $0x20,%eax
  jg     L0
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int get() {
  int res = 0;
  int c;
  do {
    c = getchar_unlocked();
  } while (c <= 32);
  do {
    res = 10 * res + c - '0';
    c = getchar_unlocked();
  } while (c > 32);
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get>:
  endbr64
  push   %r12
  cs nopw 0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <getchar_unlocked@plt>
  cmp    $0x20,%eax
  jle    L0
  xor    %r12d,%r12d
  nop
L1:
  lea    (%r12,%r12,4),%edx
  lea    -0x30(%rax,%rdx,2),%r12d
  xor    %eax,%eax
  call   <getchar_unlocked@plt>
  cmp    $0x20,%eax
  jg     L1
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int get() {
  int res = 0;
  int c;
  do {
    c = getchar_unlocked();
  } while (c <= 32);
  do {
    res = 10 * res + c - '0';
    c = getchar_unlocked();
  } while (c > 32);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread1_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x230,%rsp
  mov    %rdi,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x214(%rbp)
  jmp    L19
L25:
  mov    -0x228(%rbp),%rcx
  mov    -0x214(%rbp),%edx
  lea    -0x210(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D1(%rip),%rdx
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x210(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <checked_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  addl   $0x1,-0x214(%rbp)
L19:
  cmpl   $0x9,-0x214(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type: string

tool: D1: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    checked_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<thread1_func>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  lea    D8(%rip),%r13
L15:
  mov    %rsp,%rbp
  mov    %r12,%r8
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <checked_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L15
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    checked_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<thread1_func>:
  endbr64
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%ecx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <checked_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  cmp    $0xa,%ebx
  jne    L5
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D1
type_infered: string

tool: D1: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    checked_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread1_func>:
  endbr64
  push   %r13
  lea    D5(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%ecx
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x200,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    %eax,%edx
  call   <checked_write@plt>
  mov    $0x186a0,%edi
  call   <usleep@plt>
  cmp    $0xa,%ebx
  jne    L2
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string

tool: D5: thread1: %d %s


assistant: ```c
void *thread1_func(void *arg) {
  int i;
  char buf[512];
  for (i = 0; i < 10; i++) {
    snprintf(buf, sizeof(buf), "thread1: %d %s\n", i, (char *)arg);
    checked_write(1, buf, strlen(buf));
    usleep(100 * 1000);
  }
  return NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<finddir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <findsub@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L5
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
data_type: string

tool: D2: Directory %u not found in current state

assistant: ```c
struct fsobject *finddir(struct fsobject *rootdir, unsigned id) {
  struct fsobject *ret;
  ret = findsub(rootdir, 1, id);
  if (ret == NULL) {
    die("Directory %u not found in current state", id);
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<finddir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %esi,%edx
  mov    $0x1,%esi
  call   <findsub@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L15:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %ebp,%esi
  lea    D8(%rip),%rdi
  call   <die@plt>
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: Directory %u not found in current state

assistant: ```c
struct fsobject *finddir(struct fsobject *rootdir, unsigned id) {
  struct fsobject *ret;
  ret = findsub(rootdir, 1, id);
  if (ret == NULL) {
    die("Directory %u not found in current state", id);
  }
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<finddir>:
  endbr64
  push   %r12
  mov    %esi,%edx
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <findsub@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <die@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: Directory %u not found in current state

assistant: ```c
struct fsobject *finddir(struct fsobject *rootdir, unsigned id) {
  struct fsobject *ret;
  ret = findsub(rootdir, 1, id);
  if (ret == NULL) {
    die("Directory %u not found in current state", id);
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<finddir>:
  endbr64
  push   %r12
  mov    %esi,%edx
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <findsub@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  mov    %ebp,%esi
  lea    D1(%rip),%rdi
  call   <die@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string

tool: D1: Directory %u not found in current state

assistant: ```c
struct fsobject *finddir(struct fsobject *rootdir, unsigned id) {
  struct fsobject *ret;
  ret = findsub(rootdir, 1, id);
  if (ret == NULL) {
    die("Directory %u not found in current state", id);
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_upto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void print_upto(char *str, int idx) {
  for (int i = 0; i <= idx; i++)
    printf("%c", str[i]);
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_upto>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  js     L18
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
L5:
  movsbl (%r12,%rbx,1),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L5
L18:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void print_upto(char *str, int idx) {
  for (int i = 0; i <= idx; i++)
    printf("%c", str[i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_upto>:
  endbr64
  test   %esi,%esi
  js     L4
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L18:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L18
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void print_upto(char *str, int idx) {
  for (int i = 0; i <= idx; i++)
    printf("%c", str[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_upto>:
  endbr64
  test   %esi,%esi
  js     L4
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L13:
  movsbl (%r12,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L13
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void print_upto(char *str, int idx) {
  for (int i = 0; i <= idx; i++)
    printf("%c", str[i]);
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x1e8000(%rsp),%r11
L0:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L0
  sub    $0x490,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1e8490(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x1e8490(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
type_guessed: string
name: disassemble_data
arguments: label: D12
type_guessed: string

tool: D3: %s

tool: D12: Hello %s!


assistant: ```c
int main() {
  char s[2000000];
  scanf("%s", s);
  printf("Hello %s!\n", s);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    -0x1e8000(%rsp),%r11
L16:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L16
  sub    $0x490,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8488(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x1e8488(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x1e8490,%rsp
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D14
type: string
name: parse_data
arguments: tag: D11
type: string

tool: D14: %s

tool: D11: Hello %s!


assistant: ```c
int main() {
  char s[2000000];
  scanf("%s", s);
  printf("Hello %s!\n", s);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    -0x1e8000(%rsp),%r11
L8:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L8
  sub    $0x490,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8488(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x1e8488(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1e8490,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D13
datatype: string

tool: D5: %s

tool: D13: Hello %s!


assistant: ```c
int main() {
  char s[2000000];
  scanf("%s", s);
  printf("Hello %s!\n", s);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    -0x1e8000(%rsp),%r11
L5:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L5
  sub    $0x490,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8488(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x1e8488(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x1e8490,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string

tool: D12: %s

tool: D16: Hello %s!


assistant: ```c
int main() {
  char s[2000000];
  scanf("%s", s);
  printf("Hello %s!\n", s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<domake>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L6
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mktemp@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <pbstr@plt>
L6:
  nop
  leave
  ret
```

assistant: ```c
domake(ap, c) char **ap;
{
  if (c > 0)
    pbstr(mktemp(ap[1]));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<domake>:
  endbr64
  test   %esi,%esi
  jg     L7
  ret
L7:
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdi
  mov    $0x0,%eax
  call   <mktemp@plt>
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <pbstr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
domake(ap, c) char **ap;
{
  if (c > 0)
    pbstr(mktemp(ap[1]));
}
```
user: What is the c source code of the assembly code below:

```asm
<domake>:
  endbr64
  test   %esi,%esi
  jg     L4
  ret
  nopl   0x0(%rax)
L4:
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdi
  xor    %eax,%eax
  call   <mktemp@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1060 <pbstr@plt>
```

assistant: ```c
domake(ap, c) char **ap;
{
  if (c > 0)
    pbstr(mktemp(ap[1]));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<domake>:
  endbr64
  test   %esi,%esi
  jg     L2
  ret
  nopl   0x0(%rax)
L2:
  sub    $0x8,%rsp
  mov    0x8(%rdi),%rdi
  xor    %eax,%eax
  call   <mktemp@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1060 <pbstr@plt>
```

assistant: ```c
domake(ap, c) char **ap;
{
  if (c > 0)
    pbstr(mktemp(ap[1]));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ConvertMD5Hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0xf,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x48(%rbp),%rax
  add    $0xe,%rax
  movzbl (%rax),%eax
  movzbl %al,%esi
  mov    -0x48(%rbp),%rax
  add    $0xd,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x54(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0xc,%rax
  movzbl (%rax),%eax
  movzbl %al,%ebx
  mov    %ebx,-0x58(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0xb,%rax
  movzbl (%rax),%eax
  movzbl %al,%r15d
  mov    -0x48(%rbp),%rax
  add    $0xa,%rax
  movzbl (%rax),%eax
  movzbl %al,%r14d
  mov    -0x48(%rbp),%rax
  add    $0x9,%rax
  movzbl (%rax),%eax
  movzbl %al,%r13d
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  movzbl (%rax),%eax
  movzbl %al,%r12d
  mov    -0x48(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rax),%eax
  movzbl %al,%ebx
  mov    -0x48(%rbp),%rax
  add    $0x6,%rax
  movzbl (%rax),%eax
  movzbl %al,%r11d
  mov    -0x48(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  movzbl %al,%r10d
  mov    -0x48(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movzbl %al,%r9d
  mov    -0x48(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%r8d
  mov    -0x48(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %ecx,-0x5c(%rbp)
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x50(%rbp),%rdi
  sub    $0x8,%rsp
  push   %rdx
  push   %rsi
  mov    -0x54(%rbp),%edx
  push   %rdx
  mov    -0x58(%rbp),%esi
  push   %rsi
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  push   %r11
  push   %r10
  push   %r9
  push   %r8
  mov    -0x5c(%rbp),%r9d
  mov    %ecx,%r8d
  mov    %eax,%ecx
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0x21,%esi
  call   <snprintf@plt>
  add    $0x70,%rsp
  cltq
  add    %rax,-0x50(%rbp)
  mov    -0x50(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: %02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x

assistant: ```c
char *ConvertMD5Hash(const unsigned char *md5, char *result) {
  int i;
  int tlen;
  char *start;
  start = result;
  result += snprintf(result, 33, "%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x", md5[0], md5[1], md5[2], md5[3], md5[4], md5[5], md5[6], md5[7], md5[8], md5[9], md5[10], md5[11], md5[12], md5[13], md5[14], md5[15]);
  *result = '\0';
  return start;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ConvertMD5Hash>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  movzbl (%rdi),%ecx
  sub    $0x8,%rsp
  movzbl 0xf(%rdi),%edx
  push   %rdx
  movzbl 0xe(%rdi),%edx
  push   %rdx
  movzbl 0xd(%rdi),%edx
  push   %rdx
  movzbl 0xc(%rdi),%edx
  push   %rdx
  movzbl 0xb(%rdi),%edx
  push   %rdx
  movzbl 0xa(%rdi),%edx
  push   %rdx
  movzbl 0x9(%rdi),%edx
  push   %rdx
  movzbl 0x8(%rdi),%edx
  push   %rdx
  movzbl 0x7(%rdi),%edx
  push   %rdx
  movzbl 0x6(%rdi),%edx
  push   %rdx
  movzbl 0x5(%rdi),%edx
  push   %rdx
  movzbl 0x4(%rdi),%edx
  push   %rdx
  movzbl 0x3(%rdi),%edx
  push   %rdx
  movzbl 0x2(%rdi),%r9d
  movzbl 0x1(%rdi),%r8d
  lea    D8(%rip),%rdx
  mov    $0x21,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  cltq
  movb   $0x0,(%rbx,%rax,1)
  add    $0x70,%rsp
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D8: %02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x

assistant: ```c
char *ConvertMD5Hash(const unsigned char *md5, char *result) {
  int i;
  int tlen;
  char *start;
  start = result;
  result += snprintf(result, 33, "%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x%02x", md5[0], md5[1], md5[2], md5[3], md5[4], md5[5], md5[6], md5[7], md5[8], md5[9], md5[10], md5[11], md5[12], md5[13], md5[14], md5[15]);
  *result = '\0';
  return start;
}
```