ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_188_0_1>:
  endbr64
  mov    %esi,%ecx
  and    (%rdi),%cl
  not    %ecx
  and    %edx,%ecx
  xor    %esi,%ecx
  mov    %edx,%eax
  not    %eax
  or     %esi,%eax
  and    %ecx,%eax
  not    %esi
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_188_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rop3_188_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  not    %eax
  and    %esi,%ecx
  or     %esi,%eax
  not    %ecx
  and    %edx,%ecx
  xor    %esi,%ecx
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_188_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_188_0_1>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %edx,%eax
  not    %eax
  and    %esi,%ecx
  or     %esi,%eax
  not    %ecx
  and    %edx,%ecx
  xor    %esi,%ecx
  not    %esi
  and    %ecx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_188_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = *D & S;
  stk3 = ~stk3;
  stk2 = T & stk3;
  stk1 = S ^ stk2;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  cmpl   $0x0,-0x8(%rbp)
  jne    L84
  movl   $0x1,-0x4(%rbp)
  jmp    L220
L84:
  cmpl   $0x0,-0x8(%rbp)
  jns    L31
  movl   $0x2,-0x4(%rbp)
  jmp    L220
L31:
  movl   $0x3,-0x4(%rbp)
L220:
  cmpl   $0x0,-0x8(%rbp)
  jne    L132
  movl   $0x3,-0x4(%rbp)
L132:
  cmpl   $0x0,-0x8(%rbp)
  jne    L222
  movl   $0x3,-0x4(%rbp)
  jmp    L42
L14:
  movl   $0x0,-0x4(%rbp)
L222:
  cmpl   $0x3,-0x4(%rbp)
  je     L14
L42:
  cmpl   $0x0,-0x8(%rbp)
  jne    L66
  jmp    L169
L121:
  addl   $0x1,-0x4(%rbp)
L169:
  cmpl   $0x3,-0x4(%rbp)
  jle    L121
  jmp    L10
L66:
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x0,-0x8(%rbp)
  jne    L105
  movl   $0x0,-0x8(%rbp)
  jmp    L135
L20:
  cmpl   $0x3,-0x8(%rbp)
  jle    L71
  addl   $0x1,-0x4(%rbp)
L71:
  addl   $0x1,-0x8(%rbp)
L135:
  cmpl   $0x9,-0x8(%rbp)
  jle    L20
L105:
  cmpl   $0x0,-0x8(%rbp)
  jne    L96
  addl   $0x1,-0x4(%rbp)
  jmp    L32
L96:
  addl   $0x1,-0x4(%rbp)
L32:
  cmpl   $0x0,-0x8(%rbp)
  jne    L118
  jmp    L23
L228:
  movl   $0x1,-0x4(%rbp)
L23:
  cmpl   $0x1,-0x4(%rbp)
  jne    L228
  jmp    L77
L62:
  movl   $0x1,-0x4(%rbp)
L118:
  cmpl   $0x1,-0x4(%rbp)
  jne    L62
L77:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t;
  if (i == 0)
    t = 1;
  else if (i < 0)
    t = 2;
  else
    t = 3;
  if (i == 0)
    ;
  else
    ;
  if (i == 0)
    t = 3;
  if (i == 0)
    t = 3;
  else
    while (t == 3) {
      t = 0;
    }
  if (i == 0)
    while (t < 4)
      t++;
  else
    i++;
  if (i == 0)
    for (i = 0; i < 10; i++)
      if (i > 3)
        t++;
  if (i == 0) {
    t++;
  } else {
    t++;
  }
  if (i == 0) {
    while (t != 1) {
      t = 1;
    }
  } else {
    while (t != 1) {
      t = 1;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t;
  if (i == 0)
    t = 1;
  else if (i < 0)
    t = 2;
  else
    t = 3;
  if (i == 0)
    ;
  else
    ;
  if (i == 0)
    t = 3;
  if (i == 0)
    t = 3;
  else
    while (t == 3) {
      t = 0;
    }
  if (i == 0)
    while (t < 4)
      t++;
  else
    i++;
  if (i == 0)
    for (i = 0; i < 10; i++)
      if (i > 3)
        t++;
  if (i == 0) {
    t++;
  } else {
    t++;
  }
  if (i == 0) {
    while (t != 1) {
      t = 1;
    }
  } else {
    while (t != 1) {
      t = 1;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t;
  if (i == 0)
    t = 1;
  else if (i < 0)
    t = 2;
  else
    t = 3;
  if (i == 0)
    ;
  else
    ;
  if (i == 0)
    t = 3;
  if (i == 0)
    t = 3;
  else
    while (t == 3) {
      t = 0;
    }
  if (i == 0)
    while (t < 4)
      t++;
  else
    i++;
  if (i == 0)
    for (i = 0; i < 10; i++)
      if (i > 3)
        t++;
  if (i == 0) {
    t++;
  } else {
    t++;
  }
  if (i == 0) {
    while (t != 1) {
      t = 1;
    }
  } else {
    while (t != 1) {
      t = 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  int i;
  int t;
  if (i == 0)
    t = 1;
  else if (i < 0)
    t = 2;
  else
    t = 3;
  if (i == 0)
    ;
  else
    ;
  if (i == 0)
    t = 3;
  if (i == 0)
    t = 3;
  else
    while (t == 3) {
      t = 0;
    }
  if (i == 0)
    while (t < 4)
      t++;
  else
    i++;
  if (i == 0)
    for (i = 0; i < 10; i++)
      if (i > 3)
        t++;
  if (i == 0) {
    t++;
  } else {
    t++;
  }
  if (i == 0) {
    while (t != 1) {
      t = 1;
    }
  } else {
    while (t != 1) {
      t = 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shellSort1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
  jmp    L84
L41:
  movl   $0x0,-0x14(%rbp)
  jmp    L9
L50:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L46
L90:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L81
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L60
L33:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  add    %ecx,%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x8(%rbp)
L60:
  cmpl   $0x0,-0x8(%rbp)
  js     L18
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L33
L18:
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L81:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L90
  addl   $0x1,-0x14(%rbp)
L9:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L50
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0xc(%rbp)
L84:
  cmpl   $0x0,-0xc(%rbp)
  jg     L41
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void shellSort1(int a[], int n) {
  int i, j, gap;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = 0; i < gap; i++) {
      for (j = i + gap; j < n; j += gap) {
        if (a[j] < a[j - gap]) {
          int temp = a[j];
          int k = j - gap;
          while (k >= 0 && a[k] > temp) {
            a[k + gap] = a[k];
            k -= gap;
          }
          a[k + gap] = temp;
        }
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<shellSort1>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r15
  mov    %esi,%r11d
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  mov    %eax,-0x18(%rsp)
  cmp    $0x1,%esi
  jg     L31
L83:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  add    -0x18(%rsp),%esi
  movslq %esi,%rsi
  mov    %edi,(%r15,%rsi,4)
L4:
  add    %r13d,%ecx
  mov    -0x30(%rsp),%rsi
  add    %rsi,%r12
  mov    -0x28(%rsp),%rax
  add    %rax,%rbx
  add    %rax,%rbp
  add    %rsi,%r8
  lea    (%rcx,%r13,1),%eax
  cmp    %eax,%r11d
  jle    L85
L99:
  mov    (%r14,%r8,1),%edi
  mov    %ecx,%esi
  mov    (%r15,%r8,1),%edx
  cmp    %edx,%edi
  jge    L4
  test   %ecx,%ecx
  js     L40
  mov    %ecx,%eax
  sub    %r13d,%eax
  cltq
  lea    0x0(%rbp,%r8,1),%r9
  add    -0x30(%rsp),%r9
  add    %r15,%r9
  lea    (%r12,%rbx,1),%r10
  add    %r15,%r10
L95:
  mov    %edx,(%r9,%rax,4)
  mov    %eax,%esi
  test   %eax,%eax
  js     L40
  add    -0x38(%rsp),%rax
  mov    (%r10,%rax,4),%edx
  cmp    %edx,%edi
  jl     L95
  jmp    L40
L85:
  addl   $0x1,-0x1c(%rsp)
  mov    -0x1c(%rsp),%eax
  addl   $0x1,-0x14(%rsp)
  subq   $0x4,-0x10(%rsp)
  cmp    -0x18(%rsp),%eax
  je     L63
L86:
  cmp    -0x14(%rsp),%r11d
  jle    L85
  mov    -0x1c(%rsp),%ecx
  mov    -0x10(%rsp),%rbx
  mov    %rbx,%r8
  neg    %r8
  mov    -0x8(%rsp),%r12
  sub    %rbx,%r12
  mov    -0x30(%rsp),%rbp
  add    %rbx,%rbp
  jmp    L99
L63:
  mov    -0x18(%rsp),%ebx
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  cmp    $0x1,%ebx
  jle    L83
  mov    %eax,-0x18(%rsp)
L31:
  cmpl   $0x0,-0x18(%rsp)
  jle    L63
  mov    -0x18(%rsp),%ebx
  mov    %ebx,%r13d
  movslq %ebx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    %rcx,-0x30(%rsp)
  mov    %ebx,%eax
  neg    %eax
  cltq
  neg    %rax
  shl    $0x2,%rax
  mov    %rax,-0x8(%rsp)
  neg    %rdx
  lea    0x0(,%rdx,4),%rax
  mov    %rax,-0x28(%rsp)
  lea    (%r15,%rcx,1),%r14
  mov    %ebx,-0x14(%rsp)
  movq   $0x0,-0x10(%rsp)
  movl   $0x0,-0x1c(%rsp)
  neg    %ebx
  mov    %ebx,%eax
  cltq
  mov    %rax,-0x38(%rsp)
  jmp    L86
```

assistant: ```c
void shellSort1(int a[], int n) {
  int i, j, gap;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = 0; i < gap; i++) {
      for (j = i + gap; j < n; j += gap) {
        if (a[j] < a[j - gap]) {
          int temp = a[j];
          int k = j - gap;
          while (k >= 0 && a[k] > temp) {
            a[k + gap] = a[k];
            k -= gap;
          }
          a[k + gap] = temp;
        }
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<shellSort1>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  shr    $0x1f,%eax
  push   %r13
  add    %esi,%eax
  push   %r12
  sar    %eax
  push   %rbp
  push   %rbx
  mov    %rdi,-0x18(%rsp)
  cmp    $0x1,%esi
  jle    L75
  mov    %esi,%r14d
  mov    %eax,%r15d
L10:
  movslq %r15d,%r11
  mov    -0x18(%rsp),%rax
  mov    %r15d,%ebx
  mov    %r15d,-0xc(%rsp)
  lea    0x0(,%r11,4),%rbp
  neg    %ebx
  neg    %r11
  xor    %r13d,%r13d
  add    %rbp,%rax
  mov    %rbp,%r12
  movslq %ebx,%rbx
  shl    $0x3,%r11
  mov    %rax,-0x8(%rsp)
  neg    %r12
  shl    $0x2,%rbx
  nopl   0x0(%rax)
L19:
  mov    -0x8(%rsp),%rsi
  mov    %r13d,%eax
  lea    0x0(%r13,%r15,1),%r9d
  cmp    -0xc(%rsp),%r14d
  jg     L28
  jmp    L101
  xchg   %ax,%ax
L86:
  mov    %r9d,%eax
  add    %r15d,%r9d
  add    %rbp,%rsi
  cmp    %r9d,%r14d
  jle    L101
L28:
  mov    (%rsi),%edi
  mov    (%rsi,%r12,1),%ecx
  mov    %rsi,%rdx
  cmp    %ecx,%edi
  jge    L86
  test   %eax,%eax
  js     L22
  nop
L53:
  mov    %ecx,(%rdx)
  mov    %rdx,%r8
  movslq %eax,%r10
  sub    %r15d,%eax
  js     L88
  mov    (%r8,%r11,1),%ecx
  add    %rbx,%rdx
  cmp    %ecx,%edi
  jl     L53
L88:
  mov    -0x18(%rsp),%rax
  lea    (%rax,%r10,4),%rdx
L22:
  mov    %r9d,%eax
  add    %r15d,%r9d
  mov    %edi,(%rdx)
  add    %rbp,%rsi
  cmp    %r9d,%r14d
  jg     L28
L101:
  add    $0x1,%r13d
  addl   $0x1,-0xc(%rsp)
  addq   $0x4,-0x8(%rsp)
  cmp    %r15d,%r13d
  jl     L19
  sar    %r15d
  jne    L10
L75:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shellSort1(int a[], int n) {
  int i, j, gap;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = 0; i < gap; i++) {
      for (j = i + gap; j < n; j += gap) {
        if (a[j] < a[j - gap]) {
          int temp = a[j];
          int k = j - gap;
          while (k >= 0 && a[k] > temp) {
            a[k + gap] = a[k];
            k -= gap;
          }
          a[k + gap] = temp;
        }
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<shellSort1>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  shr    $0x1f,%eax
  push   %r13
  add    %esi,%eax
  push   %r12
  sar    %eax
  push   %rbp
  push   %rbx
  mov    %rdi,-0x18(%rsp)
  cmp    $0x1,%esi
  jle    L56
  mov    %esi,%r14d
  mov    %eax,%r15d
L61:
  movslq %r15d,%r11
  mov    -0x18(%rsp),%rax
  mov    %r15d,%ebx
  mov    %r15d,-0xc(%rsp)
  lea    0x0(,%r11,4),%rbp
  neg    %ebx
  neg    %r11
  xor    %r13d,%r13d
  add    %rbp,%rax
  mov    %rbp,%r12
  movslq %ebx,%rbx
  shl    $0x3,%r11
  mov    %rax,-0x8(%rsp)
  neg    %r12
  shl    $0x2,%rbx
  nopl   0x0(%rax)
L107:
  mov    -0x8(%rsp),%rsi
  mov    %r13d,%eax
  lea    0x0(%r13,%r15,1),%r9d
  cmp    -0xc(%rsp),%r14d
  jg     L43
  jmp    L28
  xchg   %ax,%ax
L72:
  mov    %r9d,%eax
  add    %r15d,%r9d
  add    %rbp,%rsi
  cmp    %r14d,%r9d
  jge    L28
L43:
  mov    (%rsi),%edi
  mov    (%rsi,%r12,1),%ecx
  mov    %rsi,%rdx
  cmp    %ecx,%edi
  jge    L72
  test   %eax,%eax
  js     L82
  nop
L87:
  mov    %ecx,(%rdx)
  mov    %rdx,%r8
  movslq %eax,%r10
  sub    %r15d,%eax
  js     L74
  mov    (%r8,%r11,1),%ecx
  add    %rbx,%rdx
  cmp    %ecx,%edi
  jl     L87
L74:
  mov    -0x18(%rsp),%rax
  lea    (%rax,%r10,4),%rdx
L82:
  mov    %r9d,%eax
  add    %r15d,%r9d
  mov    %edi,(%rdx)
  add    %rbp,%rsi
  cmp    %r14d,%r9d
  jl     L43
L28:
  add    $0x1,%r13d
  addl   $0x1,-0xc(%rsp)
  addq   $0x4,-0x8(%rsp)
  cmp    %r15d,%r13d
  jl     L107
  sar    %r15d
  jne    L61
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void shellSort1(int a[], int n) {
  int i, j, gap;
  for (gap = n / 2; gap > 0; gap /= 2) {
    for (i = 0; i < gap; i++) {
      for (j = i + gap; j < n; j += gap) {
        if (a[j] < a[j - gap]) {
          int temp = a[j];
          int k = j - gap;
          while (k >= 0 && a[k] > temp) {
            a[k + gap] = a[k];
            k -= gap;
          }
          a[k + gap] = temp;
        }
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<USBEndpointDMAChannel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  mov    $0xf,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x450,%eax
  cltq
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  sar    $0x4,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x450,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void USBEndpointDMAChannel(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32Channel) {
  uint32_t ui32Mask;
  ;

  ;
  ;
  ui32Mask = 0xf << (ui32Channel * 4);
  ui32Mask = (*((volatile unsigned long *)(ui32Base + 0x00000450))) & (~ui32Mask);
  ui32Mask |= (((ui32Endpoint) >> 4)) << (ui32Channel * 4);
  (*((volatile unsigned long *)(ui32Base + 0x00000450))) = ui32Mask;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<USBEndpointDMAChannel>:
  endbr64
  lea    0x0(,%rdx,4),%ecx
  add    $0x450,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rdx
  mov    $0xf,%eax
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  sar    $0x4,%esi
  shl    %cl,%esi
  or     %eax,%esi
  movslq %esi,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void USBEndpointDMAChannel(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32Channel) {
  uint32_t ui32Mask;
  ;

  ;
  ;
  ui32Mask = 0xf << (ui32Channel * 4);
  ui32Mask = (*((volatile unsigned long *)(ui32Base + 0x00000450))) & (~ui32Mask);
  ui32Mask |= (((ui32Endpoint) >> 4)) << (ui32Channel * 4);
  (*((volatile unsigned long *)(ui32Base + 0x00000450))) = ui32Mask;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<USBEndpointDMAChannel>:
  endbr64
  add    $0x450,%edi
  lea    0x0(,%rdx,4),%ecx
  mov    $0xf,%eax
  sar    $0x4,%esi
  shl    %cl,%eax
  movslq %edi,%rdi
  shl    %cl,%esi
  mov    (%rdi),%rdx
  not    %eax
  and    %edx,%eax
  or     %eax,%esi
  movslq %esi,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void USBEndpointDMAChannel(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32Channel) {
  uint32_t ui32Mask;
  ;

  ;
  ;
  ui32Mask = 0xf << (ui32Channel * 4);
  ui32Mask = (*((volatile unsigned long *)(ui32Base + 0x00000450))) & (~ui32Mask);
  ui32Mask |= (((ui32Endpoint) >> 4)) << (ui32Channel * 4);
  (*((volatile unsigned long *)(ui32Base + 0x00000450))) = ui32Mask;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<USBEndpointDMAChannel>:
  endbr64
  add    $0x450,%edi
  lea    0x0(,%rdx,4),%ecx
  mov    $0xf,%eax
  sar    $0x4,%esi
  shl    %cl,%eax
  movslq %edi,%rdi
  shl    %cl,%esi
  mov    (%rdi),%rdx
  not    %eax
  and    %edx,%eax
  or     %eax,%esi
  movslq %esi,%rsi
  mov    %rsi,(%rdi)
  ret
```

assistant: ```c
void USBEndpointDMAChannel(uint32_t ui32Base, uint32_t ui32Endpoint, uint32_t ui32Channel) {
  uint32_t ui32Mask;
  ;

  ;
  ;
  ui32Mask = 0xf << (ui32Channel * 4);
  ui32Mask = (*((volatile unsigned long *)(ui32Base + 0x00000450))) & (~ui32Mask);
  ui32Mask |= (((ui32Endpoint) >> 4)) << (ui32Channel * 4);
  (*((volatile unsigned long *)(ui32Base + 0x00000450))) = ui32Mask;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x58(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L40:
  cmp    %rdx,%rsp
  je     L49
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L40
L49:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L3
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L3:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x64(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L39:
  cmp    %rdx,%rsp
  je     L31
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L39
L31:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L6
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L6:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x64(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  mov    %rax,%rsi
  call   <memcpy@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  float x[argc];
  float y[argc];
  return 0 == __builtin_memcpy(y, x, argc * sizeof(*x));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  float x[argc];
  float y[argc];
  return 0 == __builtin_memcpy(y, x, argc * sizeof(*x));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  float x[argc];
  float y[argc];
  return 0 == __builtin_memcpy(y, x, argc * sizeof(*x));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  float x[argc];
  float y[argc];
  return 0 == __builtin_memcpy(y, x, argc * sizeof(*x));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<diag_raise>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <diag_get@plt>
  mov    %eax,%edi
  call   <diag_last_error@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <error_raise@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void diag_raise(void) {
  struct error *e = diag_last_error(diag_get());
  if (e)
    error_raise(e);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<diag_raise>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <diag_get@plt>
  mov    %eax,%edi
  call   <diag_last_error@plt>
  test   %rax,%rax
  je     L0
  mov    %rax,%rdi
  call   <error_raise@plt>
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void diag_raise(void) {
  struct error *e = diag_last_error(diag_get());
  if (e)
    error_raise(e);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<diag_raise>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <diag_get@plt>
  mov    %eax,%edi
  call   <diag_last_error@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1090 <error_raise@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void diag_raise(void) {
  struct error *e = diag_last_error(diag_get());
  if (e)
    error_raise(e);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<diag_raise>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <diag_get@plt>
  mov    %eax,%edi
  call   <diag_last_error@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%rdi
  add    $0x8,%rsp
  jmp    1090 <error_raise@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void diag_raise(void) {
  struct error *e = diag_last_error(diag_get());
  if (e)
    error_raise(e);
}
```