ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dumpdata>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: %d: nblue=%d nred=%d -------------------------


assistant: ```c
void dumpdata(int id, int nblue, int nred, int n) {
  int i, j;
  printf("%d: nblue=%d nred=%d -------------------------\n", id, nblue, nred);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dumpdata>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string

tool: D2: %d: nblue=%d nred=%d -------------------------


assistant: ```c
void dumpdata(int id, int nblue, int nred, int n) {
  int i, j;
  printf("%d: nblue=%d nred=%d -------------------------\n", id, nblue, nred);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dumpdata>:
  endbr64
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8: %d: nblue=%d nred=%d -------------------------


assistant: ```c
void dumpdata(int id, int nblue, int nred, int n) {
  int i, j;
  printf("%d: nblue=%d nred=%d -------------------------\n", id, nblue, nred);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dumpdata>:
  endbr64
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string

tool: D1: %d: nblue=%d nred=%d -------------------------


assistant: ```c
void dumpdata(int id, int nblue, int nred, int n) {
  int i, j;
  printf("%d: nblue=%d nred=%d -------------------------\n", id, nblue, nred);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x3,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movw   $0x201,-0xb(%rbp)
  movb   $0x3,-0x9(%rbp)
  lea    -0xb(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    $0xc,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D37
type_infered: string

tool: D26: sizeof arri[] = %d 

tool: D0: sizeof ptri = %d 

tool: D9: sizeof arrc[] = %d 

tool: D37: sizeof ptrc = %d 

assistant: ```c
int main(int argc, char **argv) {
  int arri[] = {1, 2, 3};
  int *ptri = arri;
  char arrc[] = {1, 2, 3};
  char *ptrc = arrc;
  printf("sizeof arri[] = %d ", sizeof(arri));
  printf("sizeof ptri = %d ", sizeof(ptri));
  printf("sizeof arrc[] = %d ", sizeof(arrc));
  printf("sizeof ptrc = %d ", sizeof(ptrc));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D32
datatype: string
name: retrieve_data
arguments: data_label: D20
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string
name: retrieve_data
arguments: data_label: D11
datatype: string

tool: D32: sizeof arri[] = %d 

tool: D20: sizeof ptri = %d 

tool: D8: sizeof arrc[] = %d 

tool: D11: sizeof ptrc = %d 

assistant: ```c
int main(int argc, char **argv) {
  int arri[] = {1, 2, 3};
  int *ptri = arri;
  char arrc[] = {1, 2, 3};
  char *ptrc = arrc;
  printf("sizeof arri[] = %d ", sizeof(arri));
  printf("sizeof ptri = %d ", sizeof(ptri));
  printf("sizeof arrc[] = %d ", sizeof(arrc));
  printf("sizeof ptrc = %d ", sizeof(ptrc));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D31
type_guessed: string
name: extract_symbolic_data
arguments: label: D35
type_guessed: string

tool: D14: sizeof arri[] = %d 

tool: D32: sizeof ptri = %d 

tool: D31: sizeof arrc[] = %d 

tool: D35: sizeof ptrc = %d 

assistant: ```c
int main(int argc, char **argv) {
  int arri[] = {1, 2, 3};
  int *ptri = arri;
  char arrc[] = {1, 2, 3};
  char *ptrc = arrc;
  printf("sizeof arri[] = %d ", sizeof(arri));
  printf("sizeof ptri = %d ", sizeof(ptri));
  printf("sizeof arrc[] = %d ", sizeof(arrc));
  printf("sizeof ptrc = %d ", sizeof(ptrc));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xc,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D36
data_type: string
name: unpack_data
arguments: tag: D31
data_type: string
name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string

tool: D36: sizeof arri[] = %d 

tool: D31: sizeof ptri = %d 

tool: D2: sizeof arrc[] = %d 

tool: D6: sizeof ptrc = %d 

assistant: ```c
int main(int argc, char **argv) {
  int arri[] = {1, 2, 3};
  int *ptri = arri;
  char arrc[] = {1, 2, 3};
  char *ptrc = arrc;
  printf("sizeof arri[] = %d ", sizeof(arri));
  printf("sizeof ptri = %d ", sizeof(ptri));
  printf("sizeof arrc[] = %d ", sizeof(arrc));
  printf("sizeof ptrc = %d ", sizeof(ptrc));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<encoder_pet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x40,-0x4(%rbp)
  jle    L20
  cmpb   $0x5a,-0x4(%rbp)
  jg     L20
  movzbl -0x4(%rbp),%eax
  or     $0xffffff80,%eax
  jmp    L33
L20:
  cmpb   $0x60,-0x4(%rbp)
  jle    L5
  cmpb   $0x7a,-0x4(%rbp)
  jg     L5
  movzbl -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L33
L5:
  movzbl -0x4(%rbp),%eax
L33:
  pop    %rbp
  ret
```

assistant: ```c
char encoder_pet(char byte) {
  if ((byte >= 'A') && (byte <= 'Z'))
    return ((char)(byte | 0x80));
  if ((byte >= 'a') && (byte <= 'z'))
    return ((char)(byte - 32));
  return (byte);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<encoder_pet>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L6
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
L6:
  mov    %edi,%eax
  or     $0xffffff80,%eax
  ret
```

assistant: ```c
char encoder_pet(char byte) {
  if ((byte >= 'A') && (byte <= 'Z'))
    return ((char)(byte | 0x80));
  if ((byte >= 'a') && (byte <= 'z'))
    return ((char)(byte - 32));
  return (byte);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<encoder_pet>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L6
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %edi,%eax
  or     $0xffffff80,%eax
  ret
```

assistant: ```c
char encoder_pet(char byte) {
  if ((byte >= 'A') && (byte <= 'Z'))
    return ((char)(byte | 0x80));
  if ((byte >= 'a') && (byte <= 'z'))
    return ((char)(byte - 32));
  return (byte);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<encoder_pet>:
  endbr64
  lea    -0x41(%rdi),%eax
  cmp    $0x19,%al
  jbe    L3
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edi,%eax
  or     $0xffffff80,%eax
  ret
```

assistant: ```c
char encoder_pet(char byte) {
  if ((byte >= 'A') && (byte <= 'Z'))
    return ((char)(byte | 0x80));
  if ((byte >= 'a') && (byte <= 'z'))
    return ((char)(byte - 32));
  return (byte);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0xfa0(%rsp),%rbx
  mov    %rbp,%rax
L60:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rax,%rbx
  jne    L60
  movq   $0x1,0xf98(%rsp)
  mov    $0x3e8,%r12d
  mov    $0x0,%r8d
  movabs $0xcccccccccccccccd,%rdi
L48:
  mov    %rbp,%rax
L14:
  shlq   (%rax)
  add    $0x8,%rax
  cmp    %rax,%rbx
  jne    L14
  lea    0xf98(%rsp),%rsi
  mov    %r8,%rcx
L12:
  mov    %rsi,%r9
  add    (%rsi),%rcx
  mov    %rcx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,(%rsi)
  mov    %rdx,%rcx
  sub    $0x8,%rsi
  cmp    %r9,%rbp
  jne    L12
  sub    $0x1,%r12
  jne    L48
  mov    %rbp,%r13
  lea    D8(%rip),%r14
L2:
  mov    0x0(%r13),%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x8,%r13
  cmp    %r13,%rbx
  jne    L2
L45:
  add    0x0(%rbp),%r12
  add    $0x8,%rbp
  cmp    %rbx,%rbp
  jne    L45
  mov    %r12,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0x0,%eax
  add    $0xfb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D8: %llu 

tool: D10: 
Sum is : %llu

assistant: ```c
int main() {
  unsigned long long int carry, num[(1000 / 2)], sum, temp;
  long long int i, j, k;
  for (k = 0; k < (1000 / 2); k++)
    num[k] = 0;
  num[(1000 / 2) - 1] = 1;
  sum = 0;
  carry = 0;
  for (i = 1; i <= 1000; i++) {
    for (j = 0; j < (1000 / 2); j++) {
      num[j] *= 2;
    }
    carry = 0;
    for (k = (1000 / 2) - 1; k >= 0; k--) {
      num[k] += carry;
      temp = num[k];
      num[k] = temp % 10;
      carry = temp / 10;
    }
    for (; k >= 0 && carry;) {
      num[k--] = carry % 10;
      carry = carry / 10;
    }
  }
  for (j = 0; j < (1000 / 2); j++)
    printf("%llu ", num[j]);
  for (k = k + 1; k < (1000 / 2); k++)
    sum += num[k];
  printf("\nSum is : %llu", sum);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x1f4,%ecx
  push   %r13
  push   %r12
  mov    $0x3e8,%r12d
  push   %rbp
  push   %rbx
  sub    $0xfb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  lea    0xf98(%rsp),%r9
  lea    0xfa0(%rsp),%rbp
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x1,0xf98(%rsp)
  movabs $0xcccccccccccccccd,%rdi
L41:
  mov    %r13,%rbx
  mov    %r13,%rax
  cs nopw 0x0(%rax,%rax,1)
L10:
  shlq   (%rax)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L10
  mov    %r9,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L31:
  add    (%rsi),%rcx
  mov    %rsi,%r10
  sub    $0x8,%rsi
  mov    %rcx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,0x8(%rsi)
  mov    %rdx,%rcx
  cmp    %r13,%r10
  jne    L31
  sub    $0x1,%r12
  jne    L41
  lea    D2(%rip),%r14
L42:
  mov    0x0(%r13),%rsi
  mov    %r14,%rdi
  add    $0x8,%r13
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L42
L23:
  add    (%rbx),%r12
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L23
  mov    %r12,%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0xfb0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D1
type_infered: string

tool: D2: %llu 

tool: D1: 
Sum is : %llu

assistant: ```c
int main() {
  unsigned long long int carry, num[(1000 / 2)], sum, temp;
  long long int i, j, k;
  for (k = 0; k < (1000 / 2); k++)
    num[k] = 0;
  num[(1000 / 2) - 1] = 1;
  sum = 0;
  carry = 0;
  for (i = 1; i <= 1000; i++) {
    for (j = 0; j < (1000 / 2); j++) {
      num[j] *= 2;
    }
    carry = 0;
    for (k = (1000 / 2) - 1; k >= 0; k--) {
      num[k] += carry;
      temp = num[k];
      num[k] = temp % 10;
      carry = temp / 10;
    }
    for (; k >= 0 && carry;) {
      num[k--] = carry % 10;
      carry = carry / 10;
    }
  }
  for (j = 0; j < (1000 / 2); j++)
    printf("%llu ", num[j]);
  for (k = k + 1; k < (1000 / 2); k++)
    sum += num[k];
  printf("\nSum is : %llu", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0x1f4,%ecx
  mov    $0x3e8,%r9d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfb8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0xf98(%rsp),%r10
  lea    0xfa0(%rsp),%rbp
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x1,0xf98(%rsp)
  movabs $0xcccccccccccccccd,%rdi
L53:
  mov    %r12,%rbx
  mov    %r12,%rax
  nopl   0x0(%rax)
L25:
  shlq   (%rax)
  add    $0x8,%rax
  cmp    %rbp,%rax
  jne    L25
  mov    %r10,%rsi
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L12:
  add    (%rsi),%rcx
  mov    %rsi,%r11
  sub    $0x8,%rsi
  mov    %rcx,%rax
  mul    %rdi
  shr    $0x3,%rdx
  lea    (%rdx,%rdx,4),%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,0x8(%rsi)
  mov    %rdx,%rcx
  cmp    %r12,%r11
  jne    L12
  sub    $0x1,%r9
  jne    L53
  lea    D8(%rip),%r13
L41:
  mov    (%r12),%rsi
  mov    %r13,%rdi
  add    $0x8,%r12
  call   <printf@plt>
  cmp    %rbp,%r12
  jne    L41
  pxor   %xmm0,%xmm0
L47:
  paddq  (%rbx),%xmm0
  add    $0x10,%rbx
  cmp    %rbp,%rbx
  jne    L47
  movdqa %xmm0,%xmm1
  lea    D4(%rip),%rdi
  psrldq $0x8,%xmm1
  paddq  %xmm1,%xmm0
  movq   %xmm0,%rsi
  call   <printf@plt>
  mov    0xfa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0xfb8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string

tool: D8: %llu 

tool: D4: 
Sum is : %llu

assistant: ```c
int main() {
  unsigned long long int carry, num[(1000 / 2)], sum, temp;
  long long int i, j, k;
  for (k = 0; k < (1000 / 2); k++)
    num[k] = 0;
  num[(1000 / 2) - 1] = 1;
  sum = 0;
  carry = 0;
  for (i = 1; i <= 1000; i++) {
    for (j = 0; j < (1000 / 2); j++) {
      num[j] *= 2;
    }
    carry = 0;
    for (k = (1000 / 2) - 1; k >= 0; k--) {
      num[k] += carry;
      temp = num[k];
      num[k] = temp % 10;
      carry = temp / 10;
    }
    for (; k >= 0 && carry;) {
      num[k--] = carry % 10;
      carry = carry / 10;
    }
  }
  for (j = 0; j < (1000 / 2); j++)
    printf("%llu ", num[j]);
  for (k = k + 1; k < (1000 / 2); k++)
    sum += num[k];
  printf("\nSum is : %llu", sum);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<submatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %r8,-0x58(%rbp)
  mov    %r9,-0x60(%rbp)
  mov    -0x48(%rbp),%rax
  sub    -0x40(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x50(%rbp),%rax
  sub    0x10(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <runtimeError@plt>
L14:
  addq   $0x8,-0x8(%rbp)
  mov    -0x60(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  jmp    L16
L3:
  mov    -0x28(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x28(%rbp)
  addq   $0x1,-0x20(%rbp)
L16:
  mov    -0x28(%rbp),%rax
  cmp    -0x48(%rbp),%rax
  jle    L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8: allocation failure in submatrix()

assistant: ```c
float **submatrix(float **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    runtimeError("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<submatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %r9,%r13
  sub    0x40(%rsp),%rcx
  mov    %rcx,%r14
  mov    %rdx,%rax
  sub    %rsi,%rax
  lea    0x10(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L12
L14:
  mov    $0x1,%eax
  sub    %r13,%rax
  lea    (%r15,%rax,8),%rdi
  cmp    %rbx,%rbp
  jl     L25
  lea    0x0(,%r14,4),%rcx
  lea    0x1(%rbp),%rdx
  sub    %rbx,%r13
  lea    (%rdi,%r13,8),%rsi
L10:
  mov    %rcx,%rax
  add    (%r12,%rbx,8),%rax
  mov    %rax,(%rsi,%rbx,8)
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L10
L25:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  lea    D1(%rip),%rdi
  call   <runtimeError@plt>
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string

tool: D1: allocation failure in submatrix()

assistant: ```c
float **submatrix(float **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    runtimeError("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<submatrix>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  push   %r14
  sub    %rsi,%rax
  mov    %r9,%r14
  push   %r13
  mov    %rdi,%r13
  lea    0x10(,%rax,8),%rdi
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  sub    0x40(%rsp),%rcx
  mov    %rcx,%r12
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L8
L0:
  mov    $0x1,%eax
  sub    %r14,%rax
  lea    (%r15,%rax,8),%r8
  cmp    %rbx,%rbp
  jl     L32
  sub    %rbx,%r14
  lea    0x0(,%r12,4),%rcx
  lea    0x1(%rbp),%rdx
  lea    (%r8,%r14,8),%rsi
  nopl   (%rax)
L36:
  mov    0x0(%r13,%rbx,8),%rax
  add    %rcx,%rax
  mov    %rax,(%rsi,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rdx
  jne    L36
L32:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L8:
  lea    D8(%rip),%rdi
  call   <runtimeError@plt>
  jmp    L0
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: allocation failure in submatrix()

assistant: ```c
float **submatrix(float **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    runtimeError("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<submatrix>:
  endbr64
  push   %r15
  mov    %rdx,%rax
  mov    %r9,%r15
  push   %r14
  sub    %rsi,%rax
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  lea    0x10(,%rax,8),%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  sub    0x40(%rsp),%rbx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L64
L77:
  mov    $0x1,%eax
  sub    %r15,%rax
  lea    (%r14,%rax,8),%r8
  cmp    %rbp,%r13
  jl     L13
  lea    0x1(%rbp),%rcx
  mov    %r13,%rsi
  lea    0x8(%r14),%rax
  lea    0x0(,%rcx,8),%r9
  lea    0x0(,%rbx,4),%rdx
  sub    %rbp,%rsi
  lea    (%r12,%r9,1),%rdi
  cmp    %rdi,%rax
  je     L22
  cmp    $0x2,%rsi
  jbe    L22
  lea    0x1(%rsi),%rcx
  movq   %rdx,%xmm1
  mov    %rcx,%rsi
  punpcklqdq %xmm1,%xmm1
  shr    %rsi
  shl    $0x4,%rsi
  lea    0x8(%r14,%rsi,1),%rdi
  mov    %r12,%rsi
  sub    %r14,%rsi
  lea    -0x8(%rsi,%r9,1),%rsi
  cs nopw 0x0(%rax,%rax,1)
L86:
  movdqu -0x8(%rax,%rsi,1),%xmm0
  add    $0x10,%rax
  paddq  %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rax,%rdi
  jne    L86
  mov    %rcx,%rax
  and    $0xfffffffffffffffe,%rax
  add    %rax,%rbp
  lea    (%r15,%rax,1),%r9
  cmp    %rax,%rcx
  je     L13
  mov    (%r12,%rbp,8),%rax
  add    %rdx,%rax
  mov    %rax,(%r8,%r9,8)
L13:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  lea    D3(%rip),%rdi
  call   <runtimeError@plt>
  jmp    L77
  nopl   0x0(%rax)
L22:
  sub    %rbp,%r15
  add    $0x1,%r13
  lea    (%r8,%r15,8),%rsi
  jmp    L93
  nopl   (%rax)
L52:
  add    $0x1,%rcx
L93:
  mov    (%r12,%rbp,8),%rax
  add    %rdx,%rax
  mov    %rax,(%rsi,%rbp,8)
  mov    %rcx,%rbp
  cmp    %r13,%rcx
  jne    L52
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_label: D3
data_type: string

tool: D3: allocation failure in submatrix()

assistant: ```c
float **submatrix(float **a, long oldrl, long oldrh, long oldcl, long oldch, long newrl, long newcl) {
  long i, j, nrow = oldrh - oldrl + 1, ncol = oldcl - newcl;
  float **m;
  m = (float **)malloc((size_t)((nrow + 1) * sizeof(float *)));
  if (!m)
    runtimeError("allocation failure in submatrix()");
  m += 1;
  m -= newrl;
  for (i = oldrl, j = newrl; i <= oldrh; i++, j++)
    m[j] = a[i] + ncol;
  return m;
}
```