ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movabs $0x8899aabbccddeeff,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  shr    $0x38,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  shr    $0x28,%rax
  and    $0xff00,%eax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shr    $0x18,%rax
  and    $0xff0000,%eax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shr    $0x8,%rax
  and    $0xff000000,%eax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rcx
  movabs $0xff00000000,%rax
  and    %rcx,%rax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x18,%rax
  mov    %rax,%rcx
  movabs $0xff0000000000,%rax
  and    %rcx,%rax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x28,%rax
  mov    %rax,%rcx
  movabs $0xff000000000000,%rax
  and    %rcx,%rax
  or     %rax,%rdx
  mov    -0x10(%rbp),%rax
  shl    $0x38,%rax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0xaabbccdd,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  shr    $0x18,%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  movw   $0xaabb,-0x1c(%rbp)
  movzwl -0x1c(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x1c(%rbp),%eax
  shr    $0x8,%ax
  or     %edx,%eax
  mov    %ax,-0x1a(%rbp)
  movw   $0x0,-0x1a(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned long long int abcdefgh;
  unsigned long long int hgfedcba;
  unsigned int abcd;
  unsigned int dcba;
  unsigned short int ab;
  unsigned short int ba;
  abcdefgh = 0x8899AABBCCDDEEFFULL;
  hgfedcba = (((abcdefgh & 0xFF00000000000000ULL) >> 56) | ((abcdefgh & 0x00FF000000000000ULL) >> 40) | ((abcdefgh & 0x0000FF0000000000ULL) >> 24) | ((abcdefgh & 0x000000FF00000000ULL) >> 8) | ((abcdefgh & 0x00000000FF000000ULL) << 8) | ((abcdefgh & 0x0000000000FF0000ULL) << 24) | ((abcdefgh & 0x000000000000FF00ULL) << 40) | ((abcdefgh & 0x00000000000000FFULL) << 56));
  hgfedcba = 0;
  abcd = 0xAABBCCDD;
  dcba = (((abcd & 0x000000FF) << 24) | ((abcd & 0x0000FF00) << 8) | ((abcd & 0x00FF0000) >> 8) | ((abcd & 0xFF000000) >> 24));
  dcba = 0;
  ab = 0xAABB;
  ba = (((ab & 0x00FF) << 8) | ((ab & 0xFF00) >> 8));
  ba = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long int abcdefgh;
  unsigned long long int hgfedcba;
  unsigned int abcd;
  unsigned int dcba;
  unsigned short int ab;
  unsigned short int ba;
  abcdefgh = 0x8899AABBCCDDEEFFULL;
  hgfedcba = (((abcdefgh & 0xFF00000000000000ULL) >> 56) | ((abcdefgh & 0x00FF000000000000ULL) >> 40) | ((abcdefgh & 0x0000FF0000000000ULL) >> 24) | ((abcdefgh & 0x000000FF00000000ULL) >> 8) | ((abcdefgh & 0x00000000FF000000ULL) << 8) | ((abcdefgh & 0x0000000000FF0000ULL) << 24) | ((abcdefgh & 0x000000000000FF00ULL) << 40) | ((abcdefgh & 0x00000000000000FFULL) << 56));
  hgfedcba = 0;
  abcd = 0xAABBCCDD;
  dcba = (((abcd & 0x000000FF) << 24) | ((abcd & 0x0000FF00) << 8) | ((abcd & 0x00FF0000) >> 8) | ((abcd & 0xFF000000) >> 24));
  dcba = 0;
  ab = 0xAABB;
  ba = (((ab & 0x00FF) << 8) | ((ab & 0xFF00) >> 8));
  ba = 0;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long int abcdefgh;
  unsigned long long int hgfedcba;
  unsigned int abcd;
  unsigned int dcba;
  unsigned short int ab;
  unsigned short int ba;
  abcdefgh = 0x8899AABBCCDDEEFFULL;
  hgfedcba = (((abcdefgh & 0xFF00000000000000ULL) >> 56) | ((abcdefgh & 0x00FF000000000000ULL) >> 40) | ((abcdefgh & 0x0000FF0000000000ULL) >> 24) | ((abcdefgh & 0x000000FF00000000ULL) >> 8) | ((abcdefgh & 0x00000000FF000000ULL) << 8) | ((abcdefgh & 0x0000000000FF0000ULL) << 24) | ((abcdefgh & 0x000000000000FF00ULL) << 40) | ((abcdefgh & 0x00000000000000FFULL) << 56));
  hgfedcba = 0;
  abcd = 0xAABBCCDD;
  dcba = (((abcd & 0x000000FF) << 24) | ((abcd & 0x0000FF00) << 8) | ((abcd & 0x00FF0000) >> 8) | ((abcd & 0xFF000000) >> 24));
  dcba = 0;
  ab = 0xAABB;
  ba = (((ab & 0x00FF) << 8) | ((ab & 0xFF00) >> 8));
  ba = 0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long long int abcdefgh;
  unsigned long long int hgfedcba;
  unsigned int abcd;
  unsigned int dcba;
  unsigned short int ab;
  unsigned short int ba;
  abcdefgh = 0x8899AABBCCDDEEFFULL;
  hgfedcba = (((abcdefgh & 0xFF00000000000000ULL) >> 56) | ((abcdefgh & 0x00FF000000000000ULL) >> 40) | ((abcdefgh & 0x0000FF0000000000ULL) >> 24) | ((abcdefgh & 0x000000FF00000000ULL) >> 8) | ((abcdefgh & 0x00000000FF000000ULL) << 8) | ((abcdefgh & 0x0000000000FF0000ULL) << 24) | ((abcdefgh & 0x000000000000FF00ULL) << 40) | ((abcdefgh & 0x00000000000000FFULL) << 56));
  hgfedcba = 0;
  abcd = 0xAABBCCDD;
  dcba = (((abcd & 0x000000FF) << 24) | ((abcd & 0x0000FF00) << 8) | ((abcd & 0x00FF0000) >> 8) | ((abcd & 0xFF000000) >> 24));
  dcba = 0;
  ab = 0xAABB;
  ba = (((ab & 0x00FF) << 8) | ((ab & 0xFF00) >> 8));
  ba = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L31
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L74:
  subl   $0x1,-0xc(%rbp)
L72:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jg     L67
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L74
  jmp    L67
L65:
  addl   $0x1,-0x10(%rbp)
L67:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L33
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L65
L33:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L0:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L72
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  jmp    L12
L31:
  nop
L12:
  leave
  ret
```

assistant: ```c
void quick_sort(int *arr, int left, int right) {
  int i, j, t;
  int tmp;
  if (left > right)
    return;
  tmp = arr[left];
  i = left;
  j = right;
  while (i < j) {
    while (arr[j] >= tmp && i < j)
      j--;
    while (arr[i] <= tmp && i < j)
      i++;
    if (i < j) {
      t = arr[i];
      arr[i] = arr[j];
      arr[j] = t;
    }
  }
  arr[left] = arr[i];
  arr[i] = tmp;
  quick_sort(arr, left, i - 1);
  quick_sort(arr, i + 1, right);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jg     L77
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r10d
  mov    %edx,%r12d
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r11
  mov    (%r11),%edi
  mov    %edx,%eax
  mov    %esi,%ebx
  jl     L76
L91:
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%r11)
  mov    %edi,(%rax)
  lea    -0x1(%rbx),%edx
  mov    %r10d,%esi
  mov    %rbp,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick_sort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L102:
  cmp    %eax,%ebx
  jge    L91
  mov    %ecx,(%r9)
  mov    %esi,(%r8)
L76:
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,4),%r8
  mov    (%r8),%ecx
  cmp    %eax,%ebx
  jge    L78
  lea    -0x4(%rbp,%rdx,4),%rdx
  cmp    %ecx,%edi
  jg     L78
L62:
  sub    $0x1,%eax
  mov    %rdx,%r8
  mov    (%rdx),%ecx
  sub    $0x4,%rdx
  cmp    %ebx,%eax
  jle    L78
  cmp    %edi,%ecx
  jge    L62
L78:
  movslq %ebx,%rdx
  shl    $0x2,%rdx
  lea    0x0(%rbp,%rdx,1),%r9
  mov    (%r9),%esi
  cmp    %eax,%ebx
  jge    L102
  cmp    %esi,%edi
  jl     L102
  lea    0x4(%rbp,%rdx,1),%rdx
L104:
  add    $0x1,%ebx
  mov    %rdx,%r9
  mov    (%rdx),%esi
  add    $0x4,%rdx
  cmp    %eax,%ebx
  jge    L102
  cmp    %edi,%esi
  jle    L104
  jmp    L102
L77:
  ret
```

assistant: ```c
void quick_sort(int *arr, int left, int right) {
  int i, j, t;
  int tmp;
  if (left > right)
    return;
  tmp = arr[left];
  i = left;
  j = right;
  while (i < j) {
    while (arr[j] >= tmp && i < j)
      j--;
    while (arr[i] <= tmp && i < j)
      i++;
    if (i < j) {
      t = arr[i];
      arr[i] = arr[j];
      arr[j] = t;
    }
  }
  arr[left] = arr[i];
  arr[i] = tmp;
  quick_sort(arr, left, i - 1);
  quick_sort(arr, i + 1, right);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jg     L30
  push   %r13
  mov    %esi,%r11d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
L45:
  movslq %r11d,%rax
  mov    %ebp,%ebx
  lea    (%r12,%rax,4),%r13
  mov    %r11d,%eax
  mov    0x0(%r13),%edi
  mov    %edi,%ecx
  cmp    %r11d,%ebp
  jle    L11
  nopl   0x0(%rax)
L109:
  movslq %ebx,%rdx
  lea    (%r12,%rdx,4),%r9
  mov    (%r9),%esi
  cmp    %esi,%edi
  jg     L159
  lea    -0x4(%r12,%rdx,4),%rdx
  cmp    %eax,%ebx
  jg     L105
  jmp    L159
  nopl   0x0(%rax)
L2:
  cmp    %edi,%esi
  jl     L159
L105:
  sub    $0x1,%ebx
  mov    (%rdx),%esi
  mov    %rdx,%r9
  sub    $0x4,%rdx
  cmp    %eax,%ebx
  jg     L2
L159:
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    (%r12,%rdx,1),%r8
  cmp    %ecx,%edi
  jl     L124
  cmp    %eax,%ebx
  jle    L103
  lea    0x4(%r12,%rdx,1),%rdx
  jmp    L131
  xchg   %ax,%ax
L81:
  add    $0x4,%rdx
  cmp    %ebx,%eax
  je     L150
L131:
  mov    (%rdx),%ecx
  mov    %eax,%r10d
  mov    %rdx,%r8
  add    $0x1,%eax
  cmp    %edi,%ecx
  jle    L81
L124:
  cmp    %eax,%ebx
  jle    L6
  mov    %esi,(%r8)
  mov    %ecx,(%r9)
  mov    (%r8),%ecx
  jmp    L109
L103:
  lea    -0x1(%rax),%r10d
  mov    %eax,%ebx
  nopl   0x0(%rax)
L150:
  mov    %ecx,0x0(%r13)
  mov    %r11d,%esi
  mov    %r10d,%edx
  mov    %edi,(%r8)
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r11d
  cmp    %ebp,%r11d
  jle    L45
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  lea    -0x1(%r11),%r10d
  mov    %r13,%r8
  mov    %r11d,%ebx
  jmp    L150
L30:
  ret
L6:
  mov    (%r8),%ecx
  lea    -0x1(%rax),%r10d
  mov    %eax,%ebx
  jmp    L150
```

assistant: ```c
void quick_sort(int *arr, int left, int right) {
  int i, j, t;
  int tmp;
  if (left > right)
    return;
  tmp = arr[left];
  i = left;
  j = right;
  while (i < j) {
    while (arr[j] >= tmp && i < j)
      j--;
    while (arr[i] <= tmp && i < j)
      i++;
    if (i < j) {
      t = arr[i];
      arr[i] = arr[j];
      arr[j] = t;
    }
  }
  arr[left] = arr[i];
  arr[i] = tmp;
  quick_sort(arr, left, i - 1);
  quick_sort(arr, i + 1, right);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jg     L120
  push   %r13
  mov    %esi,%r11d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
L55:
  movslq %r11d,%rax
  mov    %ebp,%ebx
  lea    (%r12,%rax,4),%r13
  mov    %r11d,%eax
  mov    0x0(%r13),%edi
  mov    %edi,%ecx
  cmp    %r11d,%ebp
  jle    L80
  nopl   0x0(%rax)
L97:
  movslq %ebx,%rdx
  lea    (%r12,%rdx,4),%r9
  mov    (%r9),%esi
  cmp    %esi,%edi
  jg     L121
  lea    -0x4(%r12,%rdx,4),%rdx
  cmp    %eax,%ebx
  jg     L50
  jmp    L121
  nopl   0x0(%rax)
L134:
  cmp    %edi,%esi
  jl     L121
L50:
  sub    $0x1,%ebx
  mov    (%rdx),%esi
  mov    %rdx,%r9
  sub    $0x4,%rdx
  cmp    %eax,%ebx
  jg     L134
L121:
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    (%r12,%rdx,1),%r8
  cmp    %ecx,%edi
  jl     L60
  cmp    %eax,%ebx
  jle    L53
  lea    0x4(%r12,%rdx,1),%rdx
  jmp    L105
  xchg   %ax,%ax
L42:
  add    $0x4,%rdx
  cmp    %ebx,%eax
  je     L54
L105:
  mov    (%rdx),%ecx
  mov    %eax,%r10d
  mov    %rdx,%r8
  add    $0x1,%eax
  cmp    %edi,%ecx
  jle    L42
L60:
  cmp    %eax,%ebx
  jle    L53
  mov    %esi,(%r8)
  mov    %ecx,(%r9)
  mov    (%r8),%ecx
  jmp    L97
L53:
  lea    -0x1(%rax),%r10d
  mov    %eax,%ebx
  nopl   0x0(%rax)
L54:
  mov    %ecx,0x0(%r13)
  mov    %r11d,%esi
  mov    %r10d,%edx
  mov    %edi,(%r8)
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbx),%r11d
  cmp    %ebp,%r11d
  jle    L55
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L80:
  lea    -0x1(%r11),%r10d
  mov    %r13,%r8
  mov    %r11d,%ebx
  jmp    L54
L120:
  ret
```

assistant: ```c
void quick_sort(int *arr, int left, int right) {
  int i, j, t;
  int tmp;
  if (left > right)
    return;
  tmp = arr[left];
  i = left;
  j = right;
  while (i < j) {
    while (arr[j] >= tmp && i < j)
      j--;
    while (arr[i] <= tmp && i < j)
      i++;
    if (i < j) {
      t = arr[i];
      arr[i] = arr[j];
      arr[j] = t;
    }
  }
  arr[left] = arr[i];
  arr[i] = tmp;
  quick_sort(arr, left, i - 1);
  quick_sort(arr, i + 1, right);
}
```
user: What is the c source code of the assembly code below:

```asm
<case_insensitive_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L20
  cmpq   $0x0,-0x20(%rbp)
  jne    L54
L20:
  mov    $0x1,%eax
  jmp    L11
L54:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L37
  mov    $0x0,%eax
  jmp    L11
L76:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L42
  mov    $0x0,%eax
  jmp    L11
L42:
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L76
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int case_insensitive_strcmp(const unsigned char *string1, const unsigned char *string2) {
  if ((string1 == NULL) || (string2 == NULL)) {
    return 1;
  }
  if (string1 == string2) {
    return 0;
  }
  for (; tolower(*string1) == tolower(*string2); (void)string1++, string2++) {
    if (*string1 == '\0') {
      return 0;
    }
  }
  return tolower(*string1) - tolower(*string2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<case_insensitive_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L73
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L58
  cmp    %rsi,%rdi
  jne    L26
  mov    $0x0,%eax
  jmp    L14
L71:
  add    $0x1,%rbx
  add    $0x1,%r12
L26:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebp
  movzbl (%r12),%edi
  call   <tolower@plt>
  cmp    %eax,%ebp
  jne    L31
  cmpb   $0x0,(%rbx)
  jne    L71
  mov    $0x0,%eax
  jmp    L14
L31:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movzbl (%r12),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  jmp    L14
L58:
  mov    $0x1,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L73:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int case_insensitive_strcmp(const unsigned char *string1, const unsigned char *string2) {
  if ((string1 == NULL) || (string2 == NULL)) {
    return 1;
  }
  if (string1 == string2) {
    return 0;
  }
  for (; tolower(*string1) == tolower(*string2); (void)string1++, string2++) {
    if (*string1 == '\0') {
      return 0;
    }
  }
  return tolower(*string1) - tolower(*string2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<case_insensitive_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L32
  mov    %rdi,%rbx
  cmp    %rsi,%rdi
  jne    L30
  jmp    L50
  nopl   0x0(%rax,%rax,1)
L20:
  cmpb   $0x0,(%rbx)
  je     L50
  add    $0x1,%rbx
  add    $0x1,%r12
L30:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L20
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L50:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int case_insensitive_strcmp(const unsigned char *string1, const unsigned char *string2) {
  if ((string1 == NULL) || (string2 == NULL)) {
    return 1;
  }
  if (string1 == string2) {
    return 0;
  }
  for (; tolower(*string1) == tolower(*string2); (void)string1++, string2++) {
    if (*string1 == '\0') {
      return 0;
    }
  }
  return tolower(*string1) - tolower(*string2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<case_insensitive_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  test   %rsi,%rsi
  je     L38
  mov    %rdi,%rbx
  cmp    %rsi,%rdi
  jne    L15
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L32:
  cmpb   $0x0,(%rbx)
  je     L2
  add    $0x1,%rbx
  add    $0x1,%r12
L15:
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebp
  call   <tolower@plt>
  cmp    %eax,%ebp
  je     L32
  movzbl (%rbx),%edi
  call   <tolower@plt>
  movzbl (%r12),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L2:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L38:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int case_insensitive_strcmp(const unsigned char *string1, const unsigned char *string2) {
  if ((string1 == NULL) || (string2 == NULL)) {
    return 1;
  }
  if (string1 == string2) {
    return 0;
  }
  for (; tolower(*string1) == tolower(*string2); (void)string1++, string2++) {
    if (*string1 == '\0') {
      return 0;
    }
  }
  return tolower(*string1) - tolower(*string2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<f1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((hot)) f1(int x) {
  register float f asm("%xmm0") = x;
  asm volatile("" ::"x"(f));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f1>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  ret
```

assistant: ```c
void __attribute__((hot)) f1(int x) {
  register float f asm("%xmm0") = x;
  asm volatile("" ::"x"(f));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f1>:
  endbr64
  pxor   %xmm0,%xmm0
  cvtsi2ss %edi,%xmm0
  ret
```

assistant: ```c
void __attribute__((hot)) f1(int x) {
  register float f asm("%xmm0") = x;
  asm volatile("" ::"x"(f));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dev_printer_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void dev_printer_destroy(void *dev) {
  struct dev_printer *printer = dev;
  free(printer);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dev_printer_destroy>:
  endbr64
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dev_printer_destroy(void *dev) {
  struct dev_printer *printer = dev;
  free(printer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dev_printer_destroy>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void dev_printer_destroy(void *dev) {
  struct dev_printer *printer = dev;
  free(printer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<dev_printer_destroy>:
  endbr64
  jmp    1050 <free@plt>
```

assistant: ```c
void dev_printer_destroy(void *dev) {
  struct dev_printer *printer = dev;
  free(printer);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<KmlStringCopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *KmlStringCopy(const char *str) {
  char *res;
  res = (char *)malloc((strlen(str) + 1) * sizeof(char));
  strcpy(res, str);
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<KmlStringCopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *KmlStringCopy(const char *str) {
  char *res;
  res = (char *)malloc((strlen(str) + 1) * sizeof(char));
  strcpy(res, str);
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<KmlStringCopy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *KmlStringCopy(const char *str) {
  char *res;
  res = (char *)malloc((strlen(str) + 1) * sizeof(char));
  strcpy(res, str);
  return res;
}
```