ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xc,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movl   $0x1,0x8(%rsp)
  mov    $0x2,%edi
  mov    $0x3,%edx
  mov    $0x4,%eax
  mov    $0x0,%r8d
  mov    $0x4,%r9d
  jmp    L37
L93:
  mov    %ecx,%edx
  mov    %esi,%eax
  jmp    L49
L23:
  movslq %edx,%rsi
  movslq %eax,%rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rsi,%rcx
  mov    %edi,(%rsp,%rcx,4)
  cmp    $0x19,%edi
  je     L35
  add    $0x1,%edi
  lea    0x1(%rdx),%ecx
  mov    %eax,%esi
  sub    $0x1,%esi
  jns    L93
  add    $0x1,%eax
  cmp    $0x4,%ecx
  jle    L93
L49:
  test   %eax,%eax
  cmovs  %r9d,%eax
L37:
  cmp    $0x5,%edx
  cmovge %r8d,%edx
  movslq %edx,%rsi
  movslq %eax,%rcx
  lea    (%rcx,%rcx,4),%rcx
  add    %rsi,%rcx
  cmpl   $0x0,(%rsp,%rcx,4)
  je     L23
  add    $0x2,%eax
  sub    $0x1,%edx
  jmp    L23
L35:
  mov    %rsp,%rbp
  lea    0x64(%rsp),%r13
  lea    D8(%rip),%r12
L85:
  mov    $0x0,%ebx
L76:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L76
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x14,%rbp
  cmp    %r13,%rbp
  jne    L85
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string

tool: D8: %3d

assistant: ```c
void main() {
  int a[5][5] = {0}, i = 0, j = 5 / 2, m = 1;
  a[i][j] = m;
  while (m < 5 * 5) {
    m++;
    i--;
    j++;
    if (i < 0 && j > 5 - 1) {
      i += 2;
      j--;
    }
    if (i < 0)
      i = 5 - 1;
    if (j > 5 - 1)
      j = 0;
    if (a[i][j] != 0) {
      i += 2;
      j--;
    }
    a[i][j] = m;
  }
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++)
      printf("%3d", a[i][j]);
    printf("\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%ecx
  mov    $0x1,%esi
  mov    $0x2,%edx
  push   %r12
  mov    $0x4,%r10d
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x8(%rsp)
  movl   $0x0,(%rdi)
  xor    %edi,%edi
  jmp    L3
  xchg   %ax,%ax
L36:
  mov    $0x1,%eax
  mov    $0x4,%edx
L76:
  movslq %eax,%rcx
  movslq %edx,%r9
  lea    (%rcx,%rcx,4),%r8
  add    %r9,%r8
  mov    (%rsp,%r8,4),%r8d
  test   %r8d,%r8d
  je     L66
  add    $0x2,%eax
  sub    $0x1,%edx
  movslq %edx,%r9
  movslq %eax,%rcx
L66:
  lea    (%rcx,%rcx,4),%rcx
  add    %r9,%rcx
  mov    %esi,(%rsp,%rcx,4)
  cmp    $0x19,%esi
  je     L75
L3:
  add    $0x1,%esi
  add    $0x1,%edx
  sub    $0x1,%eax
  jns    L39
  cmp    $0x4,%edx
  jg     L36
L39:
  cmp    $0xffffffff,%eax
  cmove  %r10d,%eax
  cmp    $0x5,%edx
  cmove  %edi,%edx
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L75:
  lea    0x64(%rsp),%r13
  lea    D4(%rip),%r12
L72:
  xor    %ebx,%ebx
L28:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L28
  mov    $0xa,%edi
  add    $0x14,%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L72
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L71
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string

tool: D4: %3d

assistant: ```c
void main() {
  int a[5][5] = {0}, i = 0, j = 5 / 2, m = 1;
  a[i][j] = m;
  while (m < 5 * 5) {
    m++;
    i--;
    j++;
    if (i < 0 && j > 5 - 1) {
      i += 2;
      j--;
    }
    if (i < 0)
      i = 5 - 1;
    if (j > 5 - 1)
      j = 0;
    if (a[i][j] != 0) {
      i += 2;
      j--;
    }
    a[i][j] = m;
  }
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++)
      printf("%3d", a[i][j]);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xc,%ecx
  mov    $0x1,%esi
  mov    $0x4,%r10d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,0x8(%rsp)
  mov    $0x2,%ecx
  movl   $0x0,(%rdi)
  jmp    L57
  nopl   0x0(%rax)
L28:
  mov    $0x3,%edi
  mov    $0x1,%eax
  mov    $0x4,%ecx
L51:
  movslq %eax,%rdx
  movslq %ecx,%r9
  lea    (%rdx,%rdx,4),%r8
  add    %r9,%r8
  mov    (%rsp,%r8,4),%r8d
  test   %r8d,%r8d
  je     L27
  add    $0x2,%eax
  movslq %edi,%r9
  mov    %r9,%rcx
  movslq %eax,%rdx
L27:
  lea    (%rdx,%rdx,4),%rdx
  add    %r9,%rdx
  mov    %esi,(%rsp,%rdx,4)
  cmp    $0x19,%esi
  je     L16
L57:
  add    $0x1,%esi
  lea    0x1(%rcx),%edx
  sub    $0x1,%eax
  jns    L60
  cmp    $0x4,%edx
  jg     L28
L60:
  cmp    $0xffffffff,%eax
  mov    %ecx,%edi
  mov    %edx,%ecx
  cmove  %r10d,%eax
  cmp    $0x5,%edx
  jne    L51
  mov    $0xffffffff,%edi
  xor    %ecx,%ecx
  jmp    L51
  nopl   0x0(%rax)
L16:
  lea    0x64(%rsp),%r13
  lea    D1(%rip),%r12
L96:
  xor    %ebx,%ebx
L9:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L9
  mov    $0xa,%edi
  add    $0x14,%rbp
  call   <putchar@plt>
  cmp    %rbp,%r13
  jne    L96
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: %3d

assistant: ```c
void main() {
  int a[5][5] = {0}, i = 0, j = 5 / 2, m = 1;
  a[i][j] = m;
  while (m < 5 * 5) {
    m++;
    i--;
    j++;
    if (i < 0 && j > 5 - 1) {
      i += 2;
      j--;
    }
    if (i < 0)
      i = 5 - 1;
    if (j > 5 - 1)
      j = 0;
    if (a[i][j] != 0) {
      i += 2;
      j--;
    }
    a[i][j] = m;
  }
  for (i = 0; i < 5; i++) {
    for (j = 0; j < 5; j++)
      printf("%3d", a[i][j]);
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x3,-0x24(%rbp)
  je     L37
  mov    $0x1,%eax
  jmp    L24
L37:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <url_decode@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L30
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  jmp    L24
L30:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L59
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  jmp    L24
L59:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L24:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3)
    return 1;
  char *input = *(argv + 1);
  char *expected = *(argv + 2);
  char *output = url_decode(input);
  if (!output)
    return EXIT_FAILURE;
  int success = !strcmp(output, expected);
  free(output);
  output = NULL;
  return success ? EXIT_SUCCESS : EXIT_FAILURE;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  je     L19
  ret
L19:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rbp
  mov    0x8(%rsi),%rdi
  call   <url_decode@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  test   %ebp,%ebp
  jne    L33
  mov    D21(%rip),%rax
  mov    (%rax),%eax
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  jmp    L1
L33:
  mov    D20(%rip),%rax
  mov    (%rax),%eax
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3)
    return 1;
  char *input = *(argv + 1);
  char *expected = *(argv + 2);
  char *output = url_decode(input);
  if (!output)
    return EXIT_FAILURE;
  int success = !strcmp(output, expected);
  free(output);
  output = NULL;
  return success ? EXIT_SUCCESS : EXIT_FAILURE;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  je     L1
  ret
L1:
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    0x10(%rsi),%r12
  call   <url_decode@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L14
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  test   %ebx,%ebx
  je     L31
L14:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L31:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  jmp    L2
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3)
    return 1;
  char *input = *(argv + 1);
  char *expected = *(argv + 2);
  char *output = url_decode(input);
  if (!output)
    return EXIT_FAILURE;
  int success = !strcmp(output, expected);
  free(output);
  output = NULL;
  return success ? EXIT_SUCCESS : EXIT_FAILURE;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x3,%edi
  je     L35
  ret
L35:
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    0x10(%rsi),%r12
  call   <url_decode@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L23
  mov    %rax,%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  test   %ebx,%ebx
  je     L10
L23:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  jmp    L3
```

assistant: ```c
int main(int argc, char **argv) {
  if (argc != 3)
    return 1;
  char *input = *(argv + 1);
  char *expected = *(argv + 2);
  char *output = url_decode(input);
  if (!output)
    return EXIT_FAILURE;
  int success = !strcmp(output, expected);
  free(output);
  output = NULL;
  return success ? EXIT_SUCCESS : EXIT_FAILURE;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <fseek@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  fseek(1, 2, 3);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <fseek@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  fseek(1, 2, 3);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <fseek@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  fseek(1, 2, 3);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <fseek@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  fseek(1, 2, 3);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ioctl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x48,%rsp
  mov    %edi,-0xb4(%rbp)
  mov    %esi,-0xb8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int ioctl(int d, int request, ...) {
  errno = ENOSYS;
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<ioctl>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ioctl(int d, int request, ...) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ioctl>:
  endbr64
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ioctl(int d, int request, ...) {
  errno = ENOSYS;
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ioctl>:
  endbr64
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int ioctl(int d, int request, ...) {
  errno = ENOSYS;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WFG6_t2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8,-0x40(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L3
L17:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  imul   -0x30(%rbp),%eax
  mov    -0x34(%rbp),%edx
  lea    -0x1(%rdx),%ebx
  cltd
  idiv   %ebx
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    -0x34(%rbp),%edx
  lea    -0x1(%rdx),%ebx
  cltd
  idiv   %ebx
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x30(%rbp),%eax
  cltd
  idiv   %edi
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x3,%rdx
  lea    -0x8(%rdx),%rdi
  mov    -0x40(%rbp),%rdx
  lea    (%rdi,%rdx,1),%rbx
  mov    %esi,%edx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <r_nonsep@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L3:
  mov    -0x34(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L17
  mov    -0x2c(%rbp),%eax
  sub    -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x2c(%rbp),%eax
  sub    -0x30(%rbp),%eax
  mov    -0x30(%rbp),%ecx
  movslq %ecx,%rcx
  lea    0x0(,%rcx,8),%rsi
  mov    -0x28(%rbp),%rcx
  add    %rsi,%rcx
  mov    -0x34(%rbp),%esi
  movslq %esi,%rsi
  shl    $0x3,%rsi
  lea    -0x8(%rsi),%rdi
  mov    -0x40(%rbp),%rsi
  lea    (%rdi,%rsi,1),%rbx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <r_nonsep@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int WFG6_t2(double *y, int y_size, int k, const int M, double *result) {
  int i;
  for (i = 1; i <= M - 1; i++) {
    const int head = (i - 1) * k / (M - 1);
    const int tail = i * k / (M - 1);
    result[i - 1] = (r_nonsep(y + head, tail - head, k / (M - 1)));
  }
  result[M - 1] = (r_nonsep(y + k, y_size - k, y_size - k));
  return M;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WFG6_t2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %esi,0x10(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %r8,0x18(%rsp)
  cmp    $0x1,%ecx
  jle    L6
  lea    -0x1(%rcx),%ebp
  mov    %edx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%r15d
  mov    %r8,%r12
  lea    -0x2(%rcx),%eax
  lea    0x8(%r8,%rax,8),%r14
  mov    $0x0,%ebx
L7:
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  mov    %eax,%ecx
  add    0xc(%rsp),%ebx
  mov    %ebx,%eax
  cltd
  idiv   %ebp
  sub    %ecx,%eax
  mov    %eax,%esi
  movslq %ecx,%rcx
  lea    0x0(%r13,%rcx,8),%rdi
  mov    %r15d,%edx
  call   <r_nonsep@plt>
  movsd  %xmm0,(%r12)
  add    $0x8,%r12
  cmp    %r14,%r12
  jne    L7
L6:
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edx
  sub    %edx,%esi
  mov    0x14(%rsp),%r14d
  movslq %r14d,%rax
  mov    0x18(%rsp),%rdi
  lea    -0x8(%rdi,%rax,8),%rbx
  movslq %edx,%rax
  lea    0x0(%r13,%rax,8),%rdi
  mov    %esi,%edx
  call   <r_nonsep@plt>
  movsd  %xmm0,(%rbx)
  mov    %r14d,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int WFG6_t2(double *y, int y_size, int k, const int M, double *result) {
  int i;
  for (i = 1; i <= M - 1; i++) {
    const int head = (i - 1) * k / (M - 1);
    const int tail = i * k / (M - 1);
    result[i - 1] = (r_nonsep(y + head, tail - head, k / (M - 1)));
  }
  result[M - 1] = (r_nonsep(y + k, y_size - k, y_size - k));
  return M;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<WFG6_t2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x10(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %r8,0x18(%rsp)
  cmp    $0x1,%ecx
  jle    L19
  mov    %ebp,%eax
  lea    -0x1(%rcx),%ebx
  mov    %r8,%r14
  xor    %r15d,%r15d
  cltd
  idiv   %ebx
  mov    %eax,%r13d
  lea    -0x2(%rcx),%eax
  lea    0x8(%r8,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %r15d,%eax
  add    %ebp,%r15d
  add    $0x8,%r14
  cltd
  idiv   %ebx
  movslq %eax,%rdi
  mov    %r15d,%eax
  cltd
  idiv   %ebx
  mov    %r13d,%edx
  sub    %edi,%eax
  lea    (%r12,%rdi,8),%rdi
  mov    %eax,%esi
  call   <r_nonsep@plt>
  movsd  %xmm0,-0x8(%r14)
  cmp    0x8(%rsp),%r14
  jne    L12
L19:
  mov    0x10(%rsp),%esi
  movslq 0x14(%rsp),%rax
  lea    (%r12,%rbp,8),%rdi
  mov    0x18(%rsp),%rcx
  sub    %ebp,%esi
  mov    %rax,%r14
  mov    %esi,%edx
  lea    -0x8(%rcx,%rax,8),%rbx
  call   <r_nonsep@plt>
  mov    %r14d,%eax
  movsd  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int WFG6_t2(double *y, int y_size, int k, const int M, double *result) {
  int i;
  for (i = 1; i <= M - 1; i++) {
    const int head = (i - 1) * k / (M - 1);
    const int tail = i * k / (M - 1);
    result[i - 1] = (r_nonsep(y + head, tail - head, k / (M - 1)));
  }
  result[M - 1] = (r_nonsep(y + k, y_size - k, y_size - k));
  return M;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<WFG6_t2>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x10(%rsp)
  mov    %ecx,0x14(%rsp)
  mov    %r8,0x18(%rsp)
  cmp    $0x1,%ecx
  jle    L16
  mov    %ebp,%eax
  lea    -0x1(%rcx),%ebx
  mov    %r8,%r14
  xor    %r15d,%r15d
  cltd
  idiv   %ebx
  mov    %eax,%r13d
  lea    -0x2(%rcx),%eax
  lea    0x8(%r8,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r15d,%eax
  add    %ebp,%r15d
  add    $0x8,%r14
  cltd
  idiv   %ebx
  movslq %eax,%rdi
  mov    %r15d,%eax
  cltd
  idiv   %ebx
  mov    %r13d,%edx
  sub    %edi,%eax
  lea    (%r12,%rdi,8),%rdi
  mov    %eax,%esi
  call   <r_nonsep@plt>
  movsd  %xmm0,-0x8(%r14)
  cmp    0x8(%rsp),%r14
  jne    L4
L16:
  mov    0x10(%rsp),%esi
  movslq 0x14(%rsp),%rax
  lea    (%r12,%rbp,8),%rdi
  mov    0x18(%rsp),%rcx
  sub    %ebp,%esi
  mov    %rax,%r14
  mov    %esi,%edx
  lea    -0x8(%rcx,%rax,8),%rbx
  call   <r_nonsep@plt>
  mov    %r14d,%eax
  movsd  %xmm0,(%rbx)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int WFG6_t2(double *y, int y_size, int k, const int M, double *result) {
  int i;
  for (i = 1; i <= M - 1; i++) {
    const int head = (i - 1) * k / (M - 1);
    const int tail = i * k / (M - 1);
    result[i - 1] = (r_nonsep(y + head, tail - head, k / (M - 1)));
  }
  result[M - 1] = (r_nonsep(y + k, y_size - k, y_size - k));
  return M;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<GPIODebounceFuncControl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x150,%eax
  mov    %eax,%eax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  add    $0x150,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %esi,%eax
  and    %ecx,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  add    $0x150,%eax
  mov    %eax,%eax
  mov    (%rax),%esi
  mov    -0x8(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%ecx
  mov    -0x4(%rbp),%eax
  add    $0x150,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    %esi,%eax
  or     %ecx,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void GPIODebounceFuncControl(unsigned int baseAdd, unsigned int pinNumber, unsigned int controlFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x150)))) &= ~(1 << pinNumber);
  (*((volatile unsigned int *)(baseAdd + (0x150)))) |= (controlFlag << pinNumber);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GPIODebounceFuncControl>:
  endbr64
  mov    %esi,%ecx
  mov    0x150(%edi),%eax
  btr    %esi,%eax
  mov    %eax,0x150(%edi)
  mov    0x150(%edi),%eax
  shl    %cl,%edx
  or     %eax,%edx
  mov    %edx,0x150(%edi)
  ret
```

assistant: ```c
void GPIODebounceFuncControl(unsigned int baseAdd, unsigned int pinNumber, unsigned int controlFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x150)))) &= ~(1 << pinNumber);
  (*((volatile unsigned int *)(baseAdd + (0x150)))) |= (controlFlag << pinNumber);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<GPIODebounceFuncControl>:
  endbr64
  mov    0x150(%edi),%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  btr    %esi,%eax
  mov    %eax,0x150(%edi)
  mov    0x150(%edi),%eax
  or     %eax,%edx
  mov    %edx,0x150(%edi)
  ret
```

assistant: ```c
void GPIODebounceFuncControl(unsigned int baseAdd, unsigned int pinNumber, unsigned int controlFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x150)))) &= ~(1 << pinNumber);
  (*((volatile unsigned int *)(baseAdd + (0x150)))) |= (controlFlag << pinNumber);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<GPIODebounceFuncControl>:
  endbr64
  mov    0x150(%edi),%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  btr    %esi,%eax
  mov    %eax,0x150(%edi)
  mov    0x150(%edi),%eax
  or     %eax,%edx
  mov    %edx,0x150(%edi)
  ret
```

assistant: ```c
void GPIODebounceFuncControl(unsigned int baseAdd, unsigned int pinNumber, unsigned int controlFlag) {
  (*((volatile unsigned int *)(baseAdd + (0x150)))) &= ~(1 << pinNumber);
  (*((volatile unsigned int *)(baseAdd + (0x150)))) |= (controlFlag << pinNumber);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(char *msg) {
  perror(msg);
  exit(errno);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void error(char *msg) {
  perror(msg);
  exit(errno);
}
```
user: What is the c source code of the assembly code below:

```asm
<error>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void error(char *msg) {
  perror(msg);
  exit(errno);
}
```