user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  lea    0x10(%rsp),%rbx
  jmp    L178
L24:
  movsbl %al,%esi
  mov    %rbx,%rdi
  call   <append@plt>
L178:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L24
  lea    D14(%rip),%r12
  lea    D12(%rip),%r13
  lea    0x10(%rsp),%r14
L179:
  mov    0x10(%rsp),%rdi
  call   <length@plt>
  sub    $0x2,%eax
  mov    %eax,%ebp
  js     L5
  movl   $0x1,0xc(%rsp)
  mov    $0x0,%r15d
  jmp    L85
L156:
  lea    0x1(%rbp),%esi
  mov    0x10(%rsp),%rdi
  call   <valueAt@plt>
  cmp    $0x29,%al
  jne    L12
L168:
  lea    0x1(%rbp),%esi
  mov    %r14,%rdi
  call   <deleteAt@plt>
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <deleteAt@plt>
  sub    $0x1,%ebp
  mov    %r15d,0xc(%rsp)
  jmp    L38
L198:
  mov    %ebp,%esi
  mov    0x10(%rsp),%rdi
  call   <valueAt@plt>
  cmp    $0x7b,%al
  je     L126
L38:
  sub    $0x1,%ebp
  js     L100
L85:
  mov    0x10(%rsp),%rdi
  call   <show@plt>
  test   %ebp,%ebp
  jle    L63
  mov    $0x0,%ebx
L145:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L145
L63:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    0x10(%rsp),%rdi
  call   <valueAt@plt>
  cmp    $0x28,%al
  je     L156
L12:
  mov    %ebp,%esi
  mov    0x10(%rsp),%rdi
  call   <valueAt@plt>
  cmp    $0x5b,%al
  jne    L198
  lea    0x1(%rbp),%esi
  mov    0x10(%rsp),%rdi
  call   <valueAt@plt>
  cmp    $0x5d,%al
  jne    L198
  jmp    L168
L126:
  lea    0x1(%rbp),%esi
  mov    0x10(%rsp),%rdi
  call   <valueAt@plt>
  cmp    $0x7d,%al
  jne    L38
  jmp    L168
L100:
  cmpl   $0x0,0xc(%rsp)
  je     L179
L5:
  mov    0x10(%rsp),%rdi
  call   <show@plt>
  mov    0x10(%rsp),%rdi
  call   <length@plt>
  test   %eax,%eax
  jne    L101
  lea    D37(%rip),%rdi
  call   <printf@plt>
L153:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L101:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L153
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: string
name: parse_data
arguments: data_label: D12
datatype: string
name: parse_data
arguments: data_label: D37
datatype: string
name: parse_data
arguments: data_label: D1
datatype: string

tool: D14:  

tool: D12: ^^


tool: D37: correct


tool: D1: wrong


assistant: ```c
int main(void) {
  struct string_node *head = NULL;
  char c;
  int is_break;
  int i, j;
  while ((c = getchar()) != '\n') {
    append(&head, c);
  }
  while (1) {
    is_break = 1;
    for (i = length(head) - 2; 0 <= i; i--) {
      show(head);
      for (j = 0; j < i; j++) {
        printf(" ");
      }
      printf("^^\n");
      if ((valueAt(head, i) == '(' && valueAt(head, i + 1) == ')') || (valueAt(head, i) == '[' && valueAt(head, i + 1) == ']') || (valueAt(head, i) == '{' && valueAt(head, i + 1) == '}')) {
        deleteAt(&head, i + 1);
        deleteAt(&head, i);
        is_break = 0;
        i--;
      }
    }
    if (is_break)
      break;
  }
  show(head);
  if (length(head) == 0) {
    printf("correct\n");
  } else {
    printf("wrong\n");
  }
  return 0;
}
```