user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pencil_dgemm_ttt>:
  endbr64
  movslq %esi,%rsi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x40(%rsp),%r11
  test   %esi,%esi
  jle    L84
  mov    %edi,%ecx
  test   %ecx,%ecx
  jle    L84
  mov    %ecx,%eax
  movslq %edx,%rbx
  mov    %ecx,%r9d
  mov    %r8,%r10
  shr    %eax
  movapd %xmm1,%xmm3
  mov    %rsi,%rdi
  mov    %rbx,%rbp
  lea    -0x1(%rax),%r12d
  mov    %r11,%rdx
  and    $0xfffffffe,%r9d
  xor    %r8d,%r8d
  add    $0x1,%r12
  lea    0x0(,%rsi,8),%r13
  unpcklpd %xmm3,%xmm3
  shl    $0x4,%r12
  nop
L46:
  lea    (%r12,%rdx,1),%r14
  mov    %rdx,%rax
  cmp    $0x1,%ecx
  je     L22
L100:
  movupd (%rax),%xmm2
  add    $0x10,%rax
  mulpd  %xmm3,%xmm2
  movups %xmm2,-0x10(%rax)
  cmp    %r14,%rax
  jne    L100
  movslq %r9d,%rax
  cmp    %r9d,%ecx
  je     L78
L14:
  movsd  (%rdx,%rax,8),%xmm2
  mulsd  %xmm1,%xmm2
  movsd  %xmm2,(%rdx,%rax,8)
L78:
  add    $0x1,%r8d
  add    %r13,%rdx
  cmp    %r8d,%edi
  jne    L46
  test   %ebp,%ebp
  jle    L84
  mov    0x30(%rsp),%r9
  lea    -0x1(%rbp),%eax
  shl    $0x3,%rbx
  shl    $0x3,%rsi
  lea    0x0(,%rcx,8),%r8
  lea    0x8(%r9,%rax,8),%rbp
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L89:
  movsd  (%r10,%r12,1),%xmm2
  lea    (%r11,%r12,1),%rax
  mov    %r9,%rcx
  xor    %edx,%edx
  mulsd  %xmm0,%xmm2
  nopl   0x0(%rax,%rax,1)
L1:
  movsd  (%rcx),%xmm1
  add    $0x1,%edx
  add    %rsi,%rcx
  mulsd  %xmm2,%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    %rsi,%rax
  cmp    %edx,%edi
  jne    L1
  add    $0x8,%r12
  cmp    %r12,%r8
  jne    L89
  add    $0x8,%r9
  add    %rbx,%r10
  cmp    %rbp,%r9
  jne    L12
L84:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  xor    %eax,%eax
  jmp    L14
```

assistant: ```c
void pencil_dgemm_ttt(int m_3367_3469, int n_3368_3470, int k_3369_3471, double alpha_3370_3472, int ldA_3371_3473, double A_3372_3474[restrict const m_3367_3469][k_3369_3471], int ldB_3373_3475, double B_3374_3476[restrict const k_3369_3471][n_3368_3470], double beta_3375_3477, int ldC_3376_3478, double C_3377_3479[restrict const m_3367_3469][n_3368_3470]) {
#pragma scop
  {
#pragma pencil independent
    for (int i_1003_972_2194_5003 = 0; i_1003_972_2194_5003 <= (n_3368_3470 - 1); i_1003_972_2194_5003 += 1) {
#pragma pencil independent
      for (int i_1002_973_2195_5004 = 0; i_1002_973_2195_5004 <= (m_3367_3469 - 1); i_1002_973_2195_5004 += 1) {
        C_3377_3479[i_1003_972_2194_5003][i_1002_973_2195_5004] = (C_3377_3479[i_1003_972_2194_5003][i_1002_973_2195_5004] * beta_3375_3477);
      }
    }
    for (int i_1005_974_2196_5007 = 0; i_1005_974_2196_5007 <= (k_3369_3471 - 1); i_1005_974_2196_5007 += 1) {
      for (int i_1004_975_2197_5006 = 0; i_1004_975_2197_5006 <= (m_3367_3469 - 1); i_1004_975_2197_5006 += 1) {
        for (int i_1006_976_2198_5005 = 0; i_1006_976_2198_5005 <= (n_3368_3470 - 1); i_1006_976_2198_5005 += 1) {
          C_3377_3479[i_1006_976_2198_5005][i_1004_975_2197_5006] = (C_3377_3479[i_1006_976_2198_5005][i_1004_975_2197_5006] + ((alpha_3370_3472 * A_3372_3474[i_1005_974_2196_5007][i_1004_975_2197_5006]) * B_3374_3476[i_1006_976_2198_5005][i_1005_974_2196_5007]));
        }
      }
    }
  }
#pragma endscop
}
```