ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uint_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L4:
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jg     L4
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int uint_n(unsigned const char *p, int n) {
  unsigned int i;
  i = 0;
  while (n-- > 0) {
    i = (i << 8) + *p++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uint_n>:
  endbr64
  test   %esi,%esi
  jle    L2
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rcx
  mov    $0x0,%eax
L14:
  shl    $0x8,%eax
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L14
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int uint_n(unsigned const char *p, int n) {
  unsigned int i;
  i = 0;
  while (n-- > 0) {
    i = (i << 8) + *p++;
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uint_n>:
  endbr64
  test   %esi,%esi
  jle    L1
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
  nopl   0x0(%rax)
L2:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L2
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int uint_n(unsigned const char *p, int n) {
  unsigned int i;
  i = 0;
  while (n-- > 0) {
    i = (i << 8) + *p++;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uint_n>:
  endbr64
  test   %esi,%esi
  jle    L9
  movslq %esi,%rsi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
  nopl   0x0(%rax)
L6:
  movzbl (%rdi),%edx
  shl    $0x8,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L6
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int uint_n(unsigned const char *p, int n) {
  unsigned int i;
  i = 0;
  while (n-- > 0) {
    i = (i << 8) + *p++;
  }
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  putchar('\n');
  va_end(ap);
  exit(2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  putchar('\n');
  va_end(ap);
  exit(2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  putchar('\n');
  va_end(ap);
  exit(2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vprintf(fmt, ap);
  putchar('\n');
  va_end(ap);
  exit(2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<leveldown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L24
L38:
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,-0x18(%rbp)
  jmp    L20
L2:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
L20:
  mov    -0x18(%rbp),%rax
L24:
  leave
  ret
```

assistant: ```c
char *leveldown(char *level) {
  char *p;
  if (level == NULL)
    return NULL;
  p = strrchr(level, '.');
  if (p == NULL) {
    free(level);
    level = NULL;
  } else {
    *p = '\0';
  }
  return level;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<leveldown>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L10
  mov    $0x2e,%esi
  call   <strrchr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L2
  movb   $0x0,(%rax)
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rbx
  jmp    L10
```

assistant: ```c
char *leveldown(char *level) {
  char *p;
  if (level == NULL)
    return NULL;
  p = strrchr(level, '.');
  if (p == NULL) {
    free(level);
    level = NULL;
  } else {
    *p = '\0';
  }
  return level;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<leveldown>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L5
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L6
  movb   $0x0,(%rax)
L5:
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L5
```

assistant: ```c
char *leveldown(char *level) {
  char *p;
  if (level == NULL)
    return NULL;
  p = strrchr(level, '.');
  if (p == NULL) {
    free(level);
    level = NULL;
  } else {
    *p = '\0';
  }
  return level;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<leveldown>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  test   %rdi,%rdi
  je     L3
  mov    $0x2e,%esi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L24
  movb   $0x0,(%rax)
L3:
  mov    %r12,%rax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  jmp    L3
```

assistant: ```c
char *leveldown(char *level) {
  char *p;
  if (level == NULL)
    return NULL;
  p = strrchr(level, '.');
  if (p == NULL) {
    free(level);
    level = NULL;
  } else {
    *p = '\0';
  }
  return level;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <list_init@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <list_reverse@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D12: input length:

tool: D1: %d

assistant: ```c
int main(int argc, char **argv) {
  int ret;
  int len;
  struct list *head = NULL;
  printf("input length:");
  scanf("%d", &len);
  head = list_init(len);
  list_print(head);
  head = list_reverse(head);
  list_print(head);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <list_init@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    %rbx,%rdi
  call   <list_reverse@plt>
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D4
type: string

tool: D3: input length:

tool: D4: %d

assistant: ```c
int main(int argc, char **argv) {
  int ret;
  int len;
  struct list *head = NULL;
  printf("input length:");
  scanf("%d", &len);
  head = list_init(len);
  list_print(head);
  head = list_reverse(head);
  list_print(head);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <list_init@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    %rbp,%rdi
  call   <list_reverse@plt>
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D0: input length:

tool: D2: %d

assistant: ```c
int main(int argc, char **argv) {
  int ret;
  int len;
  struct list *head = NULL;
  printf("input length:");
  scanf("%d", &len);
  head = list_init(len);
  list_print(head);
  head = list_reverse(head);
  list_print(head);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <list_init@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    %rbp,%rdi
  call   <list_reverse@plt>
  mov    %rax,%rdi
  call   <list_print@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D14: input length:

tool: D5: %d

assistant: ```c
int main(int argc, char **argv) {
  int ret;
  int len;
  struct list *head = NULL;
  printf("input length:");
  scanf("%d", &len);
  head = list_init(len);
  list_print(head);
  head = list_reverse(head);
  list_print(head);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<us2si>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x4,-0x28(%rbp)
  je     L143
  cmpl   $0x4,-0x28(%rbp)
  jg     L119
  cmpl   $0x3,-0x28(%rbp)
  je     L105
  cmpl   $0x3,-0x28(%rbp)
  jg     L119
  cmpl   $0x1,-0x28(%rbp)
  je     L90
  cmpl   $0x2,-0x28(%rbp)
  je     L72
  jmp    L119
L90:
  mov    $0x0,%ebx
  jmp    L124
L134:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %eax,%esi
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  add    %esi,%edx
  mov    %edx,(%rax)
  add    $0x1,%ebx
L124:
  cmp    -0x24(%rbp),%ebx
  jl     L134
  jmp    L119
L72:
  mov    $0x0,%ebx
  jmp    L16
L50:
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %eax,%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  add    %esi,%edx
  mov    %edx,(%rax)
  add    $0x1,%ebx
L16:
  cmp    -0x24(%rbp),%ebx
  jl     L50
  jmp    L119
L105:
  mov    $0x0,%ebx
  jmp    L45
L120:
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  mov    %eax,%r12d
  mov    -0x18(%rbp),%rax
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <load24bit@plt>
  add    %r12d,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %ebx,%esi
  mov    %rax,%rdi
  call   <store24bit@plt>
  add    $0x1,%ebx
L45:
  cmp    -0x24(%rbp),%ebx
  jl     L120
  jmp    L119
L143:
  mov    $0x0,%ebx
  jmp    L126
L53:
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  mov    %eax,%ecx
  movslq %ebx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    (%rcx,%rax,1),%edx
  movslq %ebx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,(%rax)
  add    $0x1,%ebx
L126:
  cmp    -0x24(%rbp),%ebx
  jl     L53
  nop
L119:
  nop
  add    $0x20,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
void us2si(void *in, void *out, int len, int bps) {
  register int i;
  switch (bps) {
  case (1):
    for (i = 0; i < len; i++)
      ((int8_t *)out)[i] = (int8_t)(SCHAR_MIN + ((int)((uint8_t *)in)[i]));
    break;
  case (2):
    for (i = 0; i < len; i++)
      ((int16_t *)out)[i] = (int16_t)(SHRT_MIN + ((int)((uint16_t *)in)[i]));
    break;
  case (3):
    for (i = 0; i < len; i++)
      store24bit(out, i, (int32_t)(INT_MIN + (uint32_t)load24bit(in, i)));
    break;
  case (4):
    for (i = 0; i < len; i++)
      ((int32_t *)out)[i] = (int32_t)(INT_MIN + ((uint32_t *)in)[i]);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<us2si>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r13d
  cmp    $0x3,%ecx
  je     L23
  jg     L2
  cmp    $0x1,%ecx
  je     L143
  cmp    $0x2,%ecx
  jne    L97
  mov    %edx,%ecx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L97
  mov    D24(%rip),%rsi
L126:
  mov    (%rsi),%edx
  add    (%rbx,%rax,8),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L126
  jmp    L97
L2:
  cmp    $0x4,%ecx
  jne    L97
  mov    %edx,%ecx
  mov    $0x0,%eax
  test   %edx,%edx
  jle    L97
  mov    D8(%rip),%rsi
L54:
  mov    (%rbx,%rax,8),%rdx
  add    (%rsi),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L54
  jmp    L97
L23:
  mov    $0x0,%r12d
  test   %edx,%edx
  jle    L97
  mov    D8(%rip),%r14
L129:
  mov    (%r14),%r15
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <load24bit@plt>
  lea    (%rax,%r15,1),%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <store24bit@plt>
  add    $0x1,%r12d
  cmp    %r12d,%r13d
  jne    L129
  jmp    L97
L143:
  test   %edx,%edx
  jle    L97
  mov    %edx,%r13d
  mov    $0x0,%eax
  mov    D35(%rip),%rcx
L118:
  mov    (%rcx),%edx
  add    (%rbx,%rax,8),%edx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L118
L97:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void us2si(void *in, void *out, int len, int bps) {
  register int i;
  switch (bps) {
  case (1):
    for (i = 0; i < len; i++)
      ((int8_t *)out)[i] = (int8_t)(SCHAR_MIN + ((int)((uint8_t *)in)[i]));
    break;
  case (2):
    for (i = 0; i < len; i++)
      ((int16_t *)out)[i] = (int16_t)(SHRT_MIN + ((int)((uint16_t *)in)[i]));
    break;
  case (3):
    for (i = 0; i < len; i++)
      store24bit(out, i, (int32_t)(INT_MIN + (uint32_t)load24bit(in, i)));
    break;
  case (4):
    for (i = 0; i < len; i++)
      ((int32_t *)out)[i] = (int32_t)(INT_MIN + ((uint32_t *)in)[i]);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<us2si>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  cmp    $0x3,%ecx
  je     L13
  jg     L60
  cmp    $0x1,%ecx
  je     L105
  cmp    $0x2,%ecx
  jne    L43
  test   %ebx,%ebx
  jle    L43
  mov    D5(%rip),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L118:
  mov    (%rcx),%edx
  add    0x0(%rbp,%rax,8),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L118
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  cmp    $0x4,%ecx
  jne    L43
  test   %ebx,%ebx
  jle    L43
  mov    D39(%rip),%rax
  mov    (%rax),%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L39:
  mov    0x0(%rbp,%rax,8),%edx
  add    %ecx,%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L39
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L105:
  test   %ebx,%ebx
  jle    L43
  mov    D2(%rip),%rcx
  xor    %eax,%eax
  nopl   (%rax)
L25:
  mov    (%rcx),%edx
  add    0x0(%rbp,%rax,8),%edx
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L25
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  test   %ebx,%ebx
  jle    L43
  mov    D39(%rip),%r14
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L93:
  mov    %r13d,%esi
  mov    (%r14),%r15
  mov    %rbp,%rdi
  call   <load24bit@plt>
  mov    %r13d,%esi
  mov    %r12,%rdi
  add    $0x1,%r13d
  lea    (%rax,%r15,1),%edx
  call   <store24bit@plt>
  cmp    %r13d,%ebx
  jne    L93
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void us2si(void *in, void *out, int len, int bps) {
  register int i;
  switch (bps) {
  case (1):
    for (i = 0; i < len; i++)
      ((int8_t *)out)[i] = (int8_t)(SCHAR_MIN + ((int)((uint8_t *)in)[i]));
    break;
  case (2):
    for (i = 0; i < len; i++)
      ((int16_t *)out)[i] = (int16_t)(SHRT_MIN + ((int)((uint16_t *)in)[i]));
    break;
  case (3):
    for (i = 0; i < len; i++)
      store24bit(out, i, (int32_t)(INT_MIN + (uint32_t)load24bit(in, i)));
    break;
  case (4):
    for (i = 0; i < len; i++)
      ((int32_t *)out)[i] = (int32_t)(INT_MIN + ((uint32_t *)in)[i]);
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<seof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L24:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  movzwl -0x1c(%rbp),%eax
  cmp    %eax,%edx
  jne    L0
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  jmp    L30
L0:
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    $0xffffffff,%eax
L30:
  pop    %rbp
  ret
```

assistant: ```c
int seof(char *buf, unsigned short int stop) {
  char *pBuf;
  int pos = 0;
  for (pBuf = buf; pBuf[pos] != '\0'; pos++) {
    if (pBuf[pos] == stop) {
      return pos + 1;
    }
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<seof>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L11
  mov    $0x0,%ecx
  movzwl %si,%esi
L7:
  mov    %ecx,%eax
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L13
  add    $0x1,%rcx
  movzbl (%rdi,%rcx,1),%edx
  test   %dl,%dl
  jne    L7
  mov    $0xffffffff,%eax
  ret
L13:
  add    $0x1,%eax
  ret
L11:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int seof(char *buf, unsigned short int stop) {
  char *pBuf;
  int pos = 0;
  for (pBuf = buf; pBuf[pos] != '\0'; pos++) {
    if (pBuf[pos] == stop) {
      return pos + 1;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<seof>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L9
  movzwl %si,%esi
  mov    $0x1,%edx
  jmp    L30
  nopl   (%rax)
L16:
  add    $0x1,%rdx
  movsbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  je     L9
L30:
  mov    %edx,%r8d
  cmp    %esi,%eax
  jne    L16
  mov    %r8d,%eax
  ret
L9:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int seof(char *buf, unsigned short int stop) {
  char *pBuf;
  int pos = 0;
  for (pBuf = buf; pBuf[pos] != '\0'; pos++) {
    if (pBuf[pos] == stop) {
      return pos + 1;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<seof>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L0
  movzwl %si,%esi
  mov    $0x1,%edx
  jmp    L5
  nopl   (%rax)
L14:
  add    $0x1,%rdx
  movsbl -0x1(%rdi,%rdx,1),%eax
  test   %al,%al
  je     L0
L5:
  mov    %edx,%r8d
  cmp    %esi,%eax
  jne    L14
  mov    %r8d,%eax
  ret
L0:
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int seof(char *buf, unsigned short int stop) {
  char *pBuf;
  int pos = 0;
  for (pBuf = buf; pBuf[pos] != '\0'; pos++) {
    if (pBuf[pos] == stop) {
      return pos + 1;
    }
  }
  return -1;
}
```