ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    -0x9000(%rsp),%r11
L15:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L15
  sub    $0xc60,%rsp
  mov    $0x9c40,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    D16(%rip),%rdi
  movl   $0x2,0x10(%rsp)
  call   <printf@plt>
  lea    D24(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    $0x1,%edi
  cmp    $0x3,%r8d
  jle    L47
  mov    $0x3,%esi
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    $0x2,%ecx
  nopl   (%rax)
L28:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L16
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L28
  movslq %edi,%rax
  add    $0x1,%edi
  mov    %esi,0x10(%rsp,%rax,4)
L16:
  add    $0x1,%esi
  cmp    %r8d,%esi
  jne    L39
L47:
  lea    -0x1(%rdi),%edx
  mov    %rbp,%rsi
  mov    %r8d,%edi
  call   <isPrime@plt>
  cmp    $0x1,%eax
  je     L78
  lea    D2(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x9c60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L78:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string

tool: D16: Enter a number to judge if it is a Prime:

tool: D24: %d

tool: D2: Yes, it is a Prime


tool: D10: Not a Prime


assistant: ```c
int main() {
  int input_num;
  int Primes[10000] = {2};
  int prime_test = 3;
  int cnt = 1;
  printf("Enter a number to judge if it is a Prime:");
  scanf("%d", &input_num);
  while (prime_test < input_num) {
    int judge_Prime = 0;
    for (int i = 2; i < prime_test; i++) {
      if (prime_test % i == 0) {
        judge_Prime = 1;
        break;
      }
    }
    if (judge_Prime == 0) {
      Primes[cnt] = prime_test;
      cnt++;
    }
    prime_test++;
  }
  if (isPrime(input_num, Primes, cnt - 1) == 1) {
    printf("Not a Prime\n");
  } else {
    printf("Yes, it is a Prime\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    -0x9000(%rsp),%r11
L17:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L17
  sub    $0xc60,%rsp
  mov    $0x9c40,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <memset@plt>
  lea    D14(%rip),%rdi
  movl   $0x2,0x10(%rsp)
  call   <printf@plt>
  lea    D6(%rip),%rdi
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  mov    $0x1,%edi
  cmp    $0x3,%r8d
  jle    L56
  mov    $0x3,%esi
  cs nopw 0x0(%rax,%rax,1)
L74:
  mov    $0x2,%ecx
  nopl   (%rax)
L61:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L36
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L61
  movslq %edi,%rax
  add    $0x1,%edi
  mov    %esi,0x10(%rsp,%rax,4)
L36:
  add    $0x1,%esi
  cmp    %r8d,%esi
  jne    L74
L56:
  lea    -0x1(%rdi),%edx
  mov    %rbp,%rsi
  mov    %r8d,%edi
  call   <isPrime@plt>
  cmp    $0x1,%eax
  je     L27
  lea    D15(%rip),%rdi
  call   <printf@plt>
L66:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x9c60,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L27:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type_infered: string
name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D15
type_infered: string
name: unpack_data
arguments: data_tag: D23
type_infered: string

tool: D14: Enter a number to judge if it is a Prime:

tool: D6: %d

tool: D15: Yes, it is a Prime


tool: D23: Not a Prime


assistant: ```c
int main() {
  int input_num;
  int Primes[10000] = {2};
  int prime_test = 3;
  int cnt = 1;
  printf("Enter a number to judge if it is a Prime:");
  scanf("%d", &input_num);
  while (prime_test < input_num) {
    int judge_Prime = 0;
    for (int i = 2; i < prime_test; i++) {
      if (prime_test % i == 0) {
        judge_Prime = 1;
        break;
      }
    }
    if (judge_Prime == 0) {
      Primes[cnt] = prime_test;
      cnt++;
    }
    prime_test++;
  }
  if (isPrime(input_num, Primes, cnt - 1) == 1) {
    printf("Not a Prime\n");
  } else {
    printf("Yes, it is a Prime\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jacobi>:
  endbr64
  test   %ecx,%ecx
  jle    L49
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %ecx,%r13d
  lea    -0x1(%rdx),%edx
  lea    0x0(,%rdx,8),%rax
  lea    0x8(%rdi,%rax,1),%r10
  lea    0x10(,%rdx,8),%rcx
  lea    0x8(%rsi,%rax,1),%r9
  mov    $0x0,%r11d
  movsd  D9(%rip),%xmm2
  movapd %xmm2,%xmm1
  jmp    L77
L87:
  mov    $0x8,%eax
L68:
  mov    0x8(%rdx),%r14
  mov    (%rdx),%rdi
  mov    0x10(%rdx),%rsi
  movsd  (%rdi,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  addsd  -0x8(%r14,%rax,1),%xmm0
  mov    %rax,%rsi
  add    $0x8,%rax
  mov    (%r8),%rdi
  addsd  (%r14,%rax,1),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdi,%rsi,1)
  cmp    %rcx,%rax
  jne    L68
  add    $0x8,%rdx
  add    $0x8,%r8
  cmp    %r10,%rdx
  jne    L87
  lea    0x8(%rbx),%r8
  mov    %rbp,%rdx
L38:
  mov    $0x8,%eax
L0:
  mov    0x8(%rdx),%r14
  mov    (%rdx),%rdi
  mov    0x10(%rdx),%rsi
  movsd  (%rdi,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  addsd  -0x8(%r14,%rax,1),%xmm0
  mov    %rax,%rsi
  add    $0x8,%rax
  mov    (%r8),%rdi
  addsd  (%r14,%rax,1),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rsi,1)
  cmp    %rcx,%rax
  jne    L0
  add    $0x8,%rdx
  add    $0x8,%r8
  cmp    %r9,%rdx
  jne    L38
L85:
  add    $0x1,%r11d
  cmp    %r11d,%r13d
  je     L2
L77:
  lea    0x8(%rbp),%r8
  mov    %rbx,%rdx
  test   %r12d,%r12d
  jg     L87
  jmp    L85
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: f64

tool: D9: 0.25

assistant: ```c
void jacobi(double **grid, double **new, int gridSize, int iter) {
  for (int k = 0; k < iter; k++) {
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        new[i][j] = (grid[i - 1][j] + grid[i + 1][j] + grid[i][j - 1] + grid[i][j + 1]) * 0.25;
      }
    }
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        grid[i][j] = (new[i - 1][j] + new[i + 1][j] + new[i][j - 1] + new[i][j + 1]) * 0.25;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jacobi>:
  endbr64
  movsd  D5(%rip),%xmm1
  test   %ecx,%ecx
  jle    L22
  push   %r12
  mov    %rdi,%r11
  mov    %rsi,%r10
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  add    $0x1,%edx
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%r9d
  test   %ebp,%ebp
  jle    L13
  xchg   %ax,%ax
L64:
  mov    -0x8(%r11,%r9,8),%r8
  mov    0x8(%r11,%r9,8),%rdi
  mov    $0x1,%eax
  mov    (%r11,%r9,8),%rcx
  mov    (%r10,%r9,8),%rsi
  nopw   0x0(%rax,%rax,1)
L49:
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  addsd  -0x8(%rcx,%rax,8),%xmm0
  addsd  0x8(%rcx,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L49
  add    $0x1,%r9
  cmp    %r9,%rdx
  jne    L64
  mov    $0x1,%r9d
  nopl   0x0(%rax,%rax,1)
L60:
  mov    -0x8(%r10,%r9,8),%r8
  mov    0x8(%r10,%r9,8),%rdi
  mov    $0x1,%eax
  mov    (%r10,%r9,8),%rcx
  mov    (%r11,%r9,8),%rsi
  nopw   0x0(%rax,%rax,1)
L68:
  movsd  (%r8,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  addsd  -0x8(%rcx,%rax,8),%xmm0
  addsd  0x8(%rcx,%rax,8),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L68
  add    $0x1,%r9
  cmp    %r9,%rdx
  jne    L60
L13:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L34
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: f64

tool: D5: 0.25

assistant: ```c
void jacobi(double **grid, double **new, int gridSize, int iter) {
  for (int k = 0; k < iter; k++) {
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        new[i][j] = (grid[i - 1][j] + grid[i + 1][j] + grid[i][j - 1] + grid[i][j + 1]) * 0.25;
      }
    }
    for (int i = 1; i < gridSize + 1; i++) {
      for (int j = 1; j < gridSize + 1; j++) {
        grid[i][j] = (new[i - 1][j] + new[i + 1][j] + new[i][j - 1] + new[i][j + 1]) * 0.25;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<vf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vf(volatile struct A *kp) {
  struct A *p = kp;
  (void)p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vf>:
  endbr64
  ret
```

assistant: ```c
void vf(volatile struct A *kp) {
  struct A *p = kp;
  (void)p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<vf>:
  endbr64
  ret
```

assistant: ```c
void vf(volatile struct A *kp) {
  struct A *p = kp;
  (void)p;
}
```
user: What is the c source code of the assembly code below:

```asm
<vf>:
  endbr64
  ret
```

assistant: ```c
void vf(volatile struct A *kp) {
  struct A *p = kp;
  (void)p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<WriteShortLE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzwl -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  movzwl -0x1c(%rbp),%eax
  shr    $0x8,%ax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WriteShortLE(unsigned char **addrPtr, unsigned short data) {
  unsigned char *addr = *addrPtr;
  *addr++ = (unsigned char)data;
  *addr++ = (unsigned char)(data >> 8);
  *addrPtr = addr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WriteShortLE>:
  endbr64
  mov    %esi,%edx
  mov    (%rdi),%rax
  mov    %sil,(%rax)
  movzbl %dh,%ecx
  mov    %cl,0x1(%rax)
  add    $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void WriteShortLE(unsigned char **addrPtr, unsigned short data) {
  unsigned char *addr = *addrPtr;
  *addr++ = (unsigned char)data;
  *addr++ = (unsigned char)(data >> 8);
  *addrPtr = addr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WriteShortLE>:
  endbr64
  mov    (%rdi),%rax
  mov    %si,(%rax)
  add    $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void WriteShortLE(unsigned char **addrPtr, unsigned short data) {
  unsigned char *addr = *addrPtr;
  *addr++ = (unsigned char)data;
  *addr++ = (unsigned char)(data >> 8);
  *addrPtr = addr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WriteShortLE>:
  endbr64
  mov    (%rdi),%rax
  mov    %si,(%rax)
  add    $0x2,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void WriteShortLE(unsigned char **addrPtr, unsigned short data) {
  unsigned char *addr = *addrPtr;
  *addr++ = (unsigned char)data;
  *addr++ = (unsigned char)(data >> 8);
  *addrPtr = addr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itemRgbColumn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2c,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L23
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <bedParseRgb@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <errAbort@plt>
  jmp    L10
L23:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlUnsigned@plt>
  mov    %eax,-0xc(%rbp)
L10:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: ERROR: expecting r,g,b specification, found: '%s'

assistant: ```c
int itemRgbColumn(char *column9) {
  int itemRgb = 0;
  char *comma = strchr(column9, ',');
  if (comma) {
    if (-1 == (itemRgb = bedParseRgb(column9)))
      errAbort("ERROR: expecting r,g,b specification, "
               "found: '%s'",
               column9);
  } else
    itemRgb = sqlUnsigned(column9);
  return itemRgb;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<itemRgbColumn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x2c,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L39
  mov    %rbx,%rdi
  call   <bedParseRgb@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L33
L1:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  mov    %rbx,%rsi
  lea    D8(%rip),%rdi
  call   <errAbort@plt>
  jmp    L1
L39:
  mov    %rbx,%rdi
  call   <sqlUnsigned@plt>
  mov    %eax,%ebp
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8: ERROR: expecting r,g,b specification, found: '%s'

assistant: ```c
int itemRgbColumn(char *column9) {
  int itemRgb = 0;
  char *comma = strchr(column9, ',');
  if (comma) {
    if (-1 == (itemRgb = bedParseRgb(column9)))
      errAbort("ERROR: expecting r,g,b specification, "
               "found: '%s'",
               column9);
  } else
    itemRgb = sqlUnsigned(column9);
  return itemRgb;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itemRgbColumn>:
  endbr64
  push   %r12
  mov    $0x2c,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L2
  call   <bedParseRgb@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L0
L8:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <sqlUnsigned@plt>
L0:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <errAbort@plt>
  jmp    L8
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
datatype: string

tool: D7: ERROR: expecting r,g,b specification, found: '%s'

assistant: ```c
int itemRgbColumn(char *column9) {
  int itemRgb = 0;
  char *comma = strchr(column9, ',');
  if (comma) {
    if (-1 == (itemRgb = bedParseRgb(column9)))
      errAbort("ERROR: expecting r,g,b specification, "
               "found: '%s'",
               column9);
  } else
    itemRgb = sqlUnsigned(column9);
  return itemRgb;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<itemRgbColumn>:
  endbr64
  push   %r12
  mov    $0x2c,%esi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strchr@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L23
  call   <bedParseRgb@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L25
L29:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  jmp    1080 <sqlUnsigned@plt>
L25:
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  call   <errAbort@plt>
  jmp    L29
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string

tool: D0: ERROR: expecting r,g,b specification, found: '%s'

assistant: ```c
int itemRgbColumn(char *column9) {
  int itemRgb = 0;
  char *comma = strchr(column9, ',');
  if (comma) {
    if (-1 == (itemRgb = bedParseRgb(column9)))
      errAbort("ERROR: expecting r,g,b specification, "
               "found: '%s'",
               column9);
  } else
    itemRgb = sqlUnsigned(column9);
  return itemRgb;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<iSub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  cmpl   $0x1,-0x28(%rbp)
  jbe    L40
  cmpl   $0x10,-0x28(%rbp)
  jbe    L4
L40:
  mov    $0xffffffff,%eax
  jmp    L42
L4:
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L63
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    -0x8(%rbp),%ecx
  add    %ecx,%eax
  sub    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  cmpl   $0x0,-0x4(%rbp)
  jns    L66
  movl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L58
L66:
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L58:
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L63:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L6
  mov    -0x8(%rbp),%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int iSub(unsigned char *psA, unsigned char *psB, unsigned int uiLen, unsigned int uiBase) {
  int i;
  int iT;
  int iBorrow;
  if (uiBase < 2 || uiBase > 16)
    return (-1);
  for (i = 0, iBorrow = 0; i < (int)uiLen; i++, psA++, psB++) {
    iT = (int)(*psA) - (int)(*psB) - iBorrow;
    *psA -= *psB + iBorrow;
    if (iT < 0) {
      iBorrow = 1;
      *psA = iT + uiBase;
    } else {
      iBorrow = 0;
      *psA = iT;
    }
  }
  return (iBorrow);
}
```
user: What is the c source code of the assembly code below?

```asm
<iSub>:
  endbr64
  mov    %rdi,%r8
  lea    -0x2(%rcx),%eax
  mov    $0xffffffff,%edi
  cmp    $0xe,%eax
  ja     L18
  mov    %rsi,%r10
  test   %edx,%edx
  jle    L15
  push   %rbx
  mov    %edx,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%r11d
  mov    $0x1,%ebx
  jmp    L30
L3:
  mov    %r9b,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  je     L23
L30:
  movzbl (%r8,%rsi,1),%eax
  movzbl (%r10,%rsi,1),%r9d
  sub    %r9d,%eax
  sub    %edi,%eax
  mov    %eax,%r9d
  mov    %r11d,%edi
  jns    L3
  lea    (%rax,%rcx,1),%r9d
  mov    %ebx,%edi
  jmp    L3
L15:
  mov    $0x0,%edi
L18:
  mov    %edi,%eax
  ret
L23:
  mov    %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
int iSub(unsigned char *psA, unsigned char *psB, unsigned int uiLen, unsigned int uiBase) {
  int i;
  int iT;
  int iBorrow;
  if (uiBase < 2 || uiBase > 16)
    return (-1);
  for (i = 0, iBorrow = 0; i < (int)uiLen; i++, psA++, psB++) {
    iT = (int)(*psA) - (int)(*psB) - iBorrow;
    *psA -= *psB + iBorrow;
    if (iT < 0) {
      iBorrow = 1;
      *psA = iT + uiBase;
    } else {
      iBorrow = 0;
      *psA = iT;
    }
  }
  return (iBorrow);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<iSub>:
  endbr64
  lea    -0x2(%rcx),%eax
  mov    %rsi,%r10
  mov    $0xffffffff,%r8d
  cmp    $0xe,%eax
  ja     L18
  test   %edx,%edx
  jle    L15
  mov    %edx,%edx
  xor    %esi,%esi
  xor    %r8d,%r8d
L16:
  movzbl (%r10,%rsi,1),%r9d
  movzbl (%rdi,%rsi,1),%eax
  sub    %r9d,%eax
  sub    %r8d,%eax
  mov    $0x0,%r8d
  mov    %eax,%r9d
  jns    L14
  lea    (%rax,%rcx,1),%r9d
  mov    $0x1,%r8d
L14:
  mov    %r9b,(%rdi,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  jne    L16
L18:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L15:
  xor    %r8d,%r8d
  jmp    L18
```

assistant: ```c
int iSub(unsigned char *psA, unsigned char *psB, unsigned int uiLen, unsigned int uiBase) {
  int i;
  int iT;
  int iBorrow;
  if (uiBase < 2 || uiBase > 16)
    return (-1);
  for (i = 0, iBorrow = 0; i < (int)uiLen; i++, psA++, psB++) {
    iT = (int)(*psA) - (int)(*psB) - iBorrow;
    *psA -= *psB + iBorrow;
    if (iT < 0) {
      iBorrow = 1;
      *psA = iT + uiBase;
    } else {
      iBorrow = 0;
      *psA = iT;
    }
  }
  return (iBorrow);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iSub>:
  endbr64
  mov    %rsi,%r10
  lea    -0x2(%rcx),%esi
  mov    %rdi,%r8
  mov    $0xffffffff,%eax
  cmp    $0xe,%esi
  ja     L45
  test   %edx,%edx
  jle    L59
  mov    %edx,%edx
  xor    %esi,%esi
  nop
L1:
  xor    %edi,%edi
L21:
  movzbl (%r8,%rsi,1),%eax
  movzbl (%r10,%rsi,1),%r9d
  sub    %r9d,%eax
  sub    %edi,%eax
  js     L49
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  jne    L1
L59:
  xor    %eax,%eax
L45:
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  add    %ecx,%eax
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%rsi
  cmp    %rdx,%rsi
  je     L7
  mov    $0x1,%edi
  jmp    L21
  xchg   %ax,%ax
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iSub(unsigned char *psA, unsigned char *psB, unsigned int uiLen, unsigned int uiBase) {
  int i;
  int iT;
  int iBorrow;
  if (uiBase < 2 || uiBase > 16)
    return (-1);
  for (i = 0, iBorrow = 0; i < (int)uiLen; i++, psA++, psB++) {
    iT = (int)(*psA) - (int)(*psB) - iBorrow;
    *psA -= *psB + iBorrow;
    if (iT < 0) {
      iBorrow = 1;
      *psA = iT + uiBase;
    } else {
      iBorrow = 0;
      *psA = iT;
    }
  }
  return (iBorrow);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<egg_secure_strclear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <egg_secure_clear@plt>
  jmp    L13
L19:
  nop
L13:
  leave
  ret
```

assistant: ```c
void egg_secure_strclear(char *str) {
  if (!str)
    return;
  egg_secure_clear((unsigned char *)str, strlen(str));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<egg_secure_strclear>:
  endbr64
  test   %rdi,%rdi
  je     L5
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <egg_secure_clear@plt>
  pop    %rbx
  ret
L5:
  ret
```

assistant: ```c
void egg_secure_strclear(char *str) {
  if (!str)
    return;
  egg_secure_clear((unsigned char *)str, strlen(str));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<egg_secure_strclear>:
  endbr64
  test   %rdi,%rdi
  je     L3
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <egg_secure_clear@plt>
  nopl   (%rax)
L3:
  ret
```

assistant: ```c
void egg_secure_strclear(char *str) {
  if (!str)
    return;
  egg_secure_clear((unsigned char *)str, strlen(str));
}
```
user: Translate the below assembly code into C programming language:

```asm
<egg_secure_strclear>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <egg_secure_clear@plt>
  nopl   (%rax)
L8:
  ret
```

assistant: ```c
void egg_secure_strclear(char *str) {
  if (!str)
    return;
  egg_secure_clear((unsigned char *)str, strlen(str));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<m68k_write_memory_32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void m68k_write_memory_32(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<m68k_write_memory_32>:
  endbr64
  ret
```

assistant: ```c
void m68k_write_memory_32(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<m68k_write_memory_32>:
  endbr64
  ret
```

assistant: ```c
void m68k_write_memory_32(unsigned int address, unsigned int value) {
  (void)address;
  (void)value;
}
```