ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<matrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x1(%rax),%edi
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L46
L21:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L9
  sub    %ebx,%r13d
  shl    $0x3,%rbx
  lea    0x1(%r13),%r12d
  neg    %rbx
  lea    D11(%rip),%r13
  shl    $0x3,%r12
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  je     L55
L30:
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L14
L9:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  mov    %r13,%rdi
  call   <nrerror@plt>
  mov    (%r15,%r14,8),%rax
  jmp    L30
L46:
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: label: D11
type_infered: string
name: retrieve_data
arguments: label: D9
type_infered: string

tool: D11: Allocation failure #2 in matrix().

tool: D9: Allocation failure #1 in matrix().

assistant: ```c
double **matrix(nrl, nrh, ncl, nch)
int nrl, nrh, ncl, nch;
{
  int i;
  double **m;
  m = (double **)calloc((unsigned)(nrh - nrl + 1), sizeof(double *));
  if (!m)
    nrerror("Allocation failure #1 in matrix().");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (double *)malloc((unsigned)(nch - ncl + 1) * sizeof(double));
    if (!m[i])
      nrerror("Allocation failure #2 in matrix().");
    m[i] -= ncl;
  }
  return (m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix>:
  endbr64
  push   %r15
  mov    %esi,%eax
  push   %r14
  sub    %edi,%eax
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  lea    0x1(%rax),%edi
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  movslq %edx,%rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L61
L22:
  movslq %r12d,%r14
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r12d,%ebp
  jl     L9
  sub    %ebx,%r13d
  shl    $0x3,%rbx
  lea    0x1(%r13),%r12d
  neg    %rbx
  lea    D6(%rip),%r13
  shl    $0x3,%r12
  nopw   0x0(%rax,%rax,1)
L56:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  je     L41
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L56
L9:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  mov    %r13,%rdi
  call   <nrerror@plt>
  add    %rbx,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L56
  jmp    L9
L61:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
  jmp    L22
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D5
type: string

tool: D6: Allocation failure #2 in matrix().

tool: D5: Allocation failure #1 in matrix().

assistant: ```c
double **matrix(nrl, nrh, ncl, nch)
int nrl, nrh, ncl, nch;
{
  int i;
  double **m;
  m = (double **)calloc((unsigned)(nrh - nrl + 1), sizeof(double *));
  if (!m)
    nrerror("Allocation failure #1 in matrix().");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (double *)malloc((unsigned)(nch - ncl + 1) * sizeof(double));
    if (!m[i])
      nrerror("Allocation failure #2 in matrix().");
    m[i] -= ncl;
  }
  return (m);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_escape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L25
L17:
  subl   $0x1,-0x4(%rbp)
L25:
  cmpl   $0x0,-0x4(%rbp)
  js     L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  je     L17
L1:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  and    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_escape(char *str, int idx) {
  int i;
  for (i = idx; i >= 0 && str[i] == '@'; i--)
    ;
  return (idx - i) & 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_escape>:
  endbr64
  test   %esi,%esi
  js     L30
  movslq %esi,%rax
  add    %rax,%rdi
  mov    %esi,%edx
L13:
  cmpb   $0x40,(%rdi)
  jne    L2
  sub    $0x1,%edx
  sub    $0x1,%rdi
  cmp    $0xffffffff,%edx
  jne    L13
L2:
  sub    %edx,%esi
  mov    %esi,%eax
  and    $0x1,%eax
  ret
L30:
  mov    %esi,%edx
  jmp    L2
```

assistant: ```c
int is_escape(char *str, int idx) {
  int i;
  for (i = idx; i >= 0 && str[i] == '@'; i--)
    ;
  return (idx - i) & 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_escape>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  add    %rax,%rdi
  test   %esi,%esi
  jns    L37
  jmp    L39
  nopw   0x0(%rax,%rax,1)
L13:
  sub    $0x1,%edx
  sub    $0x1,%rdi
  cmp    $0xffffffff,%edx
  je     L38
L37:
  cmpb   $0x40,(%rdi)
  je     L13
  sub    %edx,%esi
  mov    %esi,%eax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L38:
  lea    0x1(%rsi),%eax
  and    $0x1,%eax
  ret
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_escape(char *str, int idx) {
  int i;
  for (i = idx; i >= 0 && str[i] == '@'; i--)
    ;
  return (idx - i) & 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_escape>:
  endbr64
  movslq %esi,%rax
  mov    %esi,%edx
  add    %rax,%rdi
  test   %esi,%esi
  jns    L20
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L33:
  sub    $0x1,%edx
  sub    $0x1,%rdi
  cmp    $0xffffffff,%edx
  je     L0
L20:
  cmpb   $0x40,(%rdi)
  je     L33
  sub    %edx,%esi
  mov    %esi,%eax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L0:
  lea    0x1(%rsi),%eax
  and    $0x1,%eax
  ret
L38:
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_escape(char *str, int idx) {
  int i;
  for (i = idx; i >= 0 && str[i] == '@'; i--)
    ;
  return (idx - i) & 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<small_atoll>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L66
L69:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L120
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jg     L103
L120:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L142
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L142
  addq   $0x1,-0x18(%rbp)
L66:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L69
  jmp    L142
L103:
  nop
L142:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L10
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L42
L10:
  addq   $0x1,-0x18(%rbp)
  jmp    L42
L32:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L95
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L95
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L32
L95:
  cmpl   $0x0,-0xc(%rbp)
  je     L39
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L70
L39:
  mov    -0x8(%rbp),%rax
L70:
  pop    %rbp
  ret
```

assistant: ```c
long long small_atoll(char *s) {
  long long rv = 0;
  int sign = 0;
  while (*s) {
    if (*s <= '9' && *s >= '0')
      break;
    if (*s == '-' || *s == '+')
      break;
    s++;
  }
  sign = (*s == '-');
  if (*s == '-' || *s == '+')
    s++;
  while (*s && *s >= '0' && *s <= '9') {
    rv = (rv * 10) + (*s - '0');
    s++;
  }
  return (sign ? -rv : rv);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<small_atoll>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L83
  movabs $0x3ff280000000000,%rcx
  jmp    L20
L9:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
L20:
  mov    %eax,%edx
  cmp    $0x39,%al
  ja     L9
  bt     %rax,%rcx
  jae    L9
  cmp    $0x2d,%al
  sete   %sil
  sub    $0x2b,%edx
  and    $0xfffffffd,%edx
  cmp    $0x1,%dl
  adc    $0x0,%rdi
L82:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L4
  mov    $0x0,%edx
L94:
  lea    (%rdx,%rdx,4),%rdx
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  lea    (%rax,%rdx,2),%rdx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L94
L85:
  mov    %rdx,%rax
  neg    %rax
  test   %sil,%sil
  cmovne %rax,%rdx
  mov    %rdx,%rax
  ret
L17:
  mov    $0x0,%esi
  jmp    L82
L83:
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L85
L4:
  mov    $0x0,%edx
  jmp    L85
```

assistant: ```c
long long small_atoll(char *s) {
  long long rv = 0;
  int sign = 0;
  while (*s) {
    if (*s <= '9' && *s >= '0')
      break;
    if (*s == '-' || *s == '+')
      break;
    s++;
  }
  sign = (*s == '-');
  if (*s == '-' || *s == '+')
    s++;
  while (*s && *s >= '0' && *s <= '9') {
    rv = (rv * 10) + (*s - '0');
    s++;
  }
  return (sign ? -rv : rv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<small_atoll>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L97
  movabs $0x3ff280000000000,%rax
  nopl   (%rax)
L26:
  cmp    $0x39,%dl
  ja     L58
  bt     %rdx,%rax
  jae    L58
  lea    -0x2b(%rdx),%eax
  test   $0xfd,%al
  jne    L79
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L44
L62:
  xor    %r8d,%r8d
  xchg   %ax,%ax
L52:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rsi
  add    $0x1,%rcx
  movsbq %al,%rax
  lea    (%rax,%rsi,2),%r8
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L52
L51:
  mov    %r8,%rax
  neg    %rax
  cmp    $0x2d,%dl
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
L58:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L26
L97:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L79:
  movzbl (%rdi),%eax
  mov    %rdi,%rcx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L62
  jmp    L97
L44:
  xor    %r8d,%r8d
  jmp    L51
```

assistant: ```c
long long small_atoll(char *s) {
  long long rv = 0;
  int sign = 0;
  while (*s) {
    if (*s <= '9' && *s >= '0')
      break;
    if (*s == '-' || *s == '+')
      break;
    s++;
  }
  sign = (*s == '-');
  if (*s == '-' || *s == '+')
    s++;
  while (*s && *s >= '0' && *s <= '9') {
    rv = (rv * 10) + (*s - '0');
    s++;
  }
  return (sign ? -rv : rv);
}
```
user: Translate the below assembly code into C programming language:

```asm
<small_atoll>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  movabs $0x3ff280000000000,%rax
  nopl   (%rax)
L97:
  cmp    $0x39,%dl
  ja     L45
  bt     %rdx,%rax
  jae    L45
  lea    -0x2b(%rdx),%eax
  test   $0xfd,%al
  jne    L72
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  ja     L95
L81:
  xor    %r8d,%r8d
  xchg   %ax,%ax
L36:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%rsi
  add    $0x1,%rcx
  movsbq %al,%rax
  lea    (%rax,%rsi,2),%r8
  movzbl (%rcx),%eax
  lea    -0x30(%rax),%esi
  cmp    $0x9,%sil
  jbe    L36
L39:
  mov    %r8,%rax
  neg    %rax
  cmp    $0x2d,%dl
  cmove  %rax,%r8
  mov    %r8,%rax
  ret
L45:
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  test   %dl,%dl
  jne    L97
L15:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
L72:
  lea    -0x30(%rdx),%esi
  mov    %edx,%eax
  mov    %rdi,%rcx
  cmp    $0x9,%sil
  jbe    L81
  jmp    L15
L95:
  xor    %r8d,%r8d
  jmp    L39
```

assistant: ```c
long long small_atoll(char *s) {
  long long rv = 0;
  int sign = 0;
  while (*s) {
    if (*s <= '9' && *s >= '0')
      break;
    if (*s == '-' || *s == '+')
      break;
    s++;
  }
  sign = (*s == '-');
  if (*s == '-' || *s == '+')
    s++;
  while (*s && *s >= '0' && *s <= '9') {
    rv = (rv * 10) + (*s - '0');
    s++;
  }
  return (sign ? -rv : rv);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<basicBothIntakes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <basicHorizontalIntake@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <basicVerticalIntake@plt>
  nop
  leave
  ret
```

assistant: ```c
void basicBothIntakes(int power) {
  basicHorizontalIntake(power);
  basicVerticalIntake(power);
}
```
user: What is the c source code of the assembly code below?

```asm
<basicBothIntakes>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <basicHorizontalIntake@plt>
  mov    %ebx,%edi
  call   <basicVerticalIntake@plt>
  pop    %rbx
  ret
```

assistant: ```c
void basicBothIntakes(int power) {
  basicHorizontalIntake(power);
  basicVerticalIntake(power);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<basicBothIntakes>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <basicHorizontalIntake@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <basicVerticalIntake@plt>
```

assistant: ```c
void basicBothIntakes(int power) {
  basicHorizontalIntake(power);
  basicVerticalIntake(power);
}
```
user: What is the c source code of the assembly code below:

```asm
<basicBothIntakes>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <basicHorizontalIntake@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <basicVerticalIntake@plt>
```

assistant: ```c
void basicBothIntakes(int power) {
  basicHorizontalIntake(power);
  basicVerticalIntake(power);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hputc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %edi,%eax
  sar    $0x4,%eax
  cltq
  lea    D0(%rip),%r12
  movsbl (%r12,%rax,1),%edi
  call   <putc@plt>
  and    $0xf,%ebx
  movsbl (%r12,%rbx,1),%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string

tool: D0: 0123456789abcdef

assistant: ```c
int hputc(int ch, FILE *out) {
  static char *hex = "0123456789abcdef";
  putc(hex[ch >> 4], out);
  putc(hex[ch & 0xf], out);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hputc>:
  endbr64
  mov    %edi,%eax
  push   %r12
  lea    D5(%rip),%r12
  sar    $0x4,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cltq
  mov    %edi,%ebx
  movsbl (%r12,%rax,1),%edi
  and    $0xf,%ebx
  call   <putc@plt>
  movsbl (%r12,%rbx,1),%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: 0123456789abcdef

assistant: ```c
int hputc(int ch, FILE *out) {
  static char *hex = "0123456789abcdef";
  putc(hex[ch >> 4], out);
  putc(hex[ch & 0xf], out);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hputc>:
  endbr64
  mov    %edi,%eax
  push   %r12
  lea    D9(%rip),%r12
  sar    $0x4,%eax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  cltq
  mov    %edi,%ebx
  movsbl (%r12,%rax,1),%edi
  and    $0xf,%ebx
  call   <putc@plt>
  movsbl (%r12,%rbx,1),%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: string

tool: D9: 0123456789abcdef

assistant: ```c
int hputc(int ch, FILE *out) {
  static char *hex = "0123456789abcdef";
  putc(hex[ch >> 4], out);
  putc(hex[ch & 0xf], out);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<calculateMinimumHP>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L46
L17:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jle    L17
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L19
L52:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L48
L49:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  sub    %edx,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    $0x1,%ecx
  test   %eax,%eax
  cmovle %ecx,%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
L48:
  cmpl   $0x0,-0xc(%rbp)
  jns    L49
  subl   $0x1,-0x10(%rbp)
L19:
  cmpl   $0x0,-0x10(%rbp)
  jns    L52
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int calculateMinimumHP(int **dungeon, int rSize, int cSize) {
  int *mins = (int *)malloc(sizeof(int) * (cSize + 1));
  for (int i = 0; i <= cSize; i++)
    mins[i] = INT_MAX;
  mins[cSize - 1] = 1;
  for (int i = rSize - 1; i >= 0; i--)
    for (int j = cSize - 1; j >= 0; j--)
      mins[j] = ((1) > (((mins[j]) < (mins[j + 1]) ? (mins[j]) : (mins[j + 1])) - dungeon[i][j]) ? (1) : (((mins[j]) < (mins[j + 1]) ? (mins[j]) : (mins[j + 1])) - dungeon[i][j]));
  return mins[0];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<calculateMinimumHP>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %edx,%ebx
  lea    0x4(,%rdx,4),%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  test   %ebx,%ebx
  js     L25
  lea    0x1(%rbx),%edx
  lea    (%rax,%rdx,4),%rsi
  mov    D2(%rip),%rcx
L29:
  mov    (%rcx),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L29
L25:
  movslq %ebx,%rdx
  movl   $0x1,-0x4(%rdi,%rdx,4)
  mov    %ebp,%eax
  sub    $0x1,%eax
  js     L8
  cltq
  shl    $0x3,%rax
  lea    (%r12,%rax,1),%r8
  lea    -0x8(%r12,%rax,1),%r10
  lea    -0x1(%rbp),%eax
  shl    $0x3,%rax
  sub    %rax,%r10
  lea    -0x1(%rbx),%eax
  movslq %eax,%r11
  shl    $0x2,%r11
  mov    %eax,%eax
  sub    %rax,%rdx
  lea    -0x8(,%rdx,4),%r9
L17:
  test   %ebx,%ebx
  jle    L19
  mov    %r11,%rdx
L13:
  lea    (%rdx,%rdi,1),%rcx
  mov    0x4(%rdx,%rdi,1),%eax
  mov    (%rcx),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  mov    (%r8),%rsi
  sub    (%rsi,%rdx,1),%eax
  test   %eax,%eax
  mov    $0x1,%esi
  cmovle %esi,%eax
  mov    %eax,(%rcx)
  sub    $0x4,%rdx
  cmp    %r9,%rdx
  jne    L13
L19:
  sub    $0x8,%r8
  cmp    %r10,%r8
  jne    L17
L8:
  mov    (%rdi),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int calculateMinimumHP(int **dungeon, int rSize, int cSize) {
  int *mins = (int *)malloc(sizeof(int) * (cSize + 1));
  for (int i = 0; i <= cSize; i++)
    mins[i] = INT_MAX;
  mins[cSize - 1] = 1;
  for (int i = rSize - 1; i >= 0; i--)
    for (int j = cSize - 1; j >= 0; j--)
      mins[j] = ((1) > (((mins[j]) < (mins[j + 1]) ? (mins[j]) : (mins[j + 1])) - dungeon[i][j]) ? (1) : (((mins[j]) < (mins[j + 1]) ? (mins[j]) : (mins[j + 1])) - dungeon[i][j]));
  return mins[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<calculateMinimumHP>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x4(,%rdx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r10
  test   %r12d,%r12d
  js     L0
  mov    %rax,%rcx
  mov    D5(%rip),%rdi
  movslq %r12d,%rax
  lea    0x4(%r10,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L60:
  mov    (%rdi),%esi
  add    $0x4,%rcx
  mov    %esi,-0x4(%rcx)
  cmp    %r8,%rcx
  jne    L60
L6:
  shl    $0x2,%rax
  movl   $0x1,-0x4(%r10,%rax,1)
  sub    $0x1,%ebp
  js     L11
  lea    -0x1(%r12),%r9d
  sub    $0x8,%rax
  movslq %ebp,%r8
  movslq %r9d,%rdx
  lea    (%r10,%rdx,4),%r11
  mov    %r9d,%edx
  shl    $0x2,%rdx
  sub    %rdx,%rax
  lea    (%rax,%r10,1),%rdi
  nopl   0x0(%rax)
L67:
  test   %r9d,%r9d
  js     L57
  mov    (%rbx,%r8,8),%rsi
  mov    %r11,%rdx
  sub    %r10,%rsi
  nopw   0x0(%rax,%rax,1)
L59:
  mov    (%rdx),%ecx
  mov    0x4(%rdx),%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  sub    (%rsi,%rdx,1),%eax
  mov    $0x1,%ecx
  test   %eax,%eax
  cmovle %ecx,%eax
  sub    $0x4,%rdx
  mov    %eax,0x4(%rdx)
  cmp    %rdx,%rdi
  jne    L59
L57:
  sub    $0x1,%r8
  test   %r8d,%r8d
  jns    L67
L11:
  pop    %rbx
  mov    (%r10),%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  movslq %r12d,%rax
  jmp    L6
```

assistant: ```c
int calculateMinimumHP(int **dungeon, int rSize, int cSize) {
  int *mins = (int *)malloc(sizeof(int) * (cSize + 1));
  for (int i = 0; i <= cSize; i++)
    mins[i] = INT_MAX;
  mins[cSize - 1] = 1;
  for (int i = rSize - 1; i >= 0; i--)
    for (int j = cSize - 1; j >= 0; j--)
      mins[j] = ((1) > (((mins[j]) < (mins[j + 1]) ? (mins[j]) : (mins[j + 1])) - dungeon[i][j]) ? (1) : (((mins[j]) < (mins[j + 1]) ? (mins[j]) : (mins[j + 1])) - dungeon[i][j]));
  return mins[0];
}
```