ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<bigNN_minus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L34
L31:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L15
  mov    $0xffffffff,%eax
  jmp    L11
L15:
  mov    $0x0,%eax
L11:
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0xa(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bigNN_minus(char *a, char *b, int lim) {
  int i, tmp, c;
  for (c = i = 0; i < lim; ++i) {
    tmp = b[i] - a[i] + c;
    c = (tmp < 0 ? -1 : 0);
    b[i] = (tmp + 10) % 10;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bigNN_minus>:
  endbr64
  test   %edx,%edx
  jle    L0
  mov    %edx,%r9d
  mov    $0x0,%ecx
  mov    $0x0,%r8d
L19:
  movsbl (%rsi,%rcx,1),%eax
  movsbl (%rdi,%rcx,1),%edx
  sub    %edx,%eax
  add    %r8d,%eax
  mov    %eax,%r8d
  sar    $0x1f,%r8d
  add    $0xa,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L19
L0:
  ret
```

assistant: ```c
void bigNN_minus(char *a, char *b, int lim) {
  int i, tmp, c;
  for (c = i = 0; i < lim; ++i) {
    tmp = b[i] - a[i] + c;
    c = (tmp < 0 ? -1 : 0);
    b[i] = (tmp + 10) % 10;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bigNN_minus>:
  endbr64
  test   %edx,%edx
  jle    L0
  movslq %edx,%r9
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L6:
  movsbl (%rdi,%rcx,1),%edx
  movsbl (%rsi,%rcx,1),%eax
  sub    %edx,%eax
  add    %r8d,%eax
  mov    %eax,%r8d
  add    $0xa,%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L6
L0:
  ret
```

assistant: ```c
void bigNN_minus(char *a, char *b, int lim) {
  int i, tmp, c;
  for (c = i = 0; i < lim; ++i) {
    tmp = b[i] - a[i] + c;
    c = (tmp < 0 ? -1 : 0);
    b[i] = (tmp + 10) % 10;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bigNN_minus>:
  endbr64
  test   %edx,%edx
  jle    L5
  movslq %edx,%r9
  xor    %ecx,%ecx
  xor    %r8d,%r8d
L12:
  movsbl (%rdi,%rcx,1),%edx
  movsbl (%rsi,%rcx,1),%eax
  sub    %edx,%eax
  add    %r8d,%eax
  mov    %eax,%r8d
  add    $0xa,%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r8d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %al,(%rsi,%rcx,1)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L12
L5:
  ret
```

assistant: ```c
void bigNN_minus(char *a, char *b, int lim) {
  int i, tmp, c;
  for (c = i = 0; i < lim; ++i) {
    tmp = b[i] - a[i] + c;
    c = (tmp < 0 ? -1 : 0);
    b[i] = (tmp + 10) % 10;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<return_pdu_type_string>:
  endbr64
  push   %r12
  mov    $0x7473,%edx
  mov    $0x55,%ecx
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x6575716552746547,%rax
  movb   $0x0,0x20(%rsp)
  movl   $0x65736e,0x34(%rsp)
  mov    %dx,0x29(%rsp)
  movb   $0x0,0x2b(%rsp)
  mov    %cx,0x14(%rsp)
  mov    %rax,0x16(%rsp)
  mov    $0x7473,%eax
  mov    %ax,0x1e(%rsp)
  movabs $0x6f70736552746547,%rax
  mov    %rax,0x2c(%rsp)
  movabs $0x7478654e746547,%rax
  mov    %rax,0x4(%rsp)
  movabs $0x6575716552746553,%rax
  mov    %rax,0x21(%rsp)
  movabs $0x445020676e6f7277,%rax
  mov    %rax,0xc(%rsp)
  cmp    $0xa2,%dil
  je     L36
  ja     L76
  lea    0x16(%rsp),%rbp
  cmp    $0xa0,%dil
  je     L15
  cmp    $0xa1,%dil
  jne    L3
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%esi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x48,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L76:
  lea    0x21(%rsp),%rbp
  cmp    $0xa3,%dil
  je     L15
L3:
  lea    0xc(%rsp),%rbp
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L36:
  lea    0x2c(%rsp),%rbp
  jmp    L15
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *return_pdu_type_string(unsigned char pdu_type) {
  char *pdu_type_string = NULL;
  char GetRequest[] = {'G', 'e', 't', 'R', 'e', 'q', 'u', 'e', 's', 't', '\0'};
  char GetResponse[] = {'G', 'e', 't', 'R', 'e', 's', 'p', 'o', 'n', 's', 'e', '\0'};
  char GetNext[] = {'G', 'e', 't', 'N', 'e', 'x', 't', '\0'};
  char SetRequest[] = {'S', 'e', 't', 'R', 'e', 'q', 'u', 'e', 's', 't', '\0'};
  char Error[] = {'w', 'r', 'o', 'n', 'g', 0x20, 'P', 'D', 'U', '\0'};
  switch (pdu_type) {
  case 0xA0:
    pdu_type_string = calloc(1, strlen(GetRequest) + 1);
    strcpy(pdu_type_string, GetRequest);
    break;
  case 0xA1:
    pdu_type_string = calloc(1, strlen(GetNext) + 1);
    strcpy(pdu_type_string, GetNext);
    break;
  case 0xA2:
    pdu_type_string = calloc(1, strlen(GetResponse) + 1);
    strcpy(pdu_type_string, GetResponse);
    break;
  case 0xA3:
    pdu_type_string = calloc(1, strlen(SetRequest) + 1);
    strcpy(pdu_type_string, SetRequest);
    break;
  default:
    pdu_type_string = calloc(1, strlen(Error) + 1);
    strcpy(pdu_type_string, Error);
    break;
  }
  return (unsigned char *)pdu_type_string;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<return_pdu_type_string>:
  endbr64
  push   %r12
  mov    $0x7473,%edx
  mov    $0x55,%ecx
  push   %rbp
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x6575716552746547,%rax
  movb   $0x0,0x20(%rsp)
  movl   $0x65736e,0x34(%rsp)
  mov    %dx,0x29(%rsp)
  movb   $0x0,0x2b(%rsp)
  mov    %cx,0x14(%rsp)
  mov    %rax,0x16(%rsp)
  mov    $0x7473,%eax
  mov    %ax,0x1e(%rsp)
  movabs $0x6f70736552746547,%rax
  mov    %rax,0x2c(%rsp)
  movabs $0x7478654e746547,%rax
  mov    %rax,0x4(%rsp)
  movabs $0x6575716552746553,%rax
  mov    %rax,0x21(%rsp)
  movabs $0x445020676e6f7277,%rax
  mov    %rax,0xc(%rsp)
  cmp    $0xa2,%dil
  je     L77
  ja     L44
  lea    0x16(%rsp),%rbp
  cmp    $0xa0,%dil
  je     L5
  cmp    $0xa1,%dil
  jne    L68
  lea    0x4(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x1,%edi
  lea    0x1(%rax),%esi
  call   <calloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x48,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L44:
  lea    0x21(%rsp),%rbp
  cmp    $0xa3,%dil
  je     L5
L68:
  lea    0xc(%rsp),%rbp
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L77:
  lea    0x2c(%rsp),%rbp
  jmp    L5
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *return_pdu_type_string(unsigned char pdu_type) {
  char *pdu_type_string = NULL;
  char GetRequest[] = {'G', 'e', 't', 'R', 'e', 'q', 'u', 'e', 's', 't', '\0'};
  char GetResponse[] = {'G', 'e', 't', 'R', 'e', 's', 'p', 'o', 'n', 's', 'e', '\0'};
  char GetNext[] = {'G', 'e', 't', 'N', 'e', 'x', 't', '\0'};
  char SetRequest[] = {'S', 'e', 't', 'R', 'e', 'q', 'u', 'e', 's', 't', '\0'};
  char Error[] = {'w', 'r', 'o', 'n', 'g', 0x20, 'P', 'D', 'U', '\0'};
  switch (pdu_type) {
  case 0xA0:
    pdu_type_string = calloc(1, strlen(GetRequest) + 1);
    strcpy(pdu_type_string, GetRequest);
    break;
  case 0xA1:
    pdu_type_string = calloc(1, strlen(GetNext) + 1);
    strcpy(pdu_type_string, GetNext);
    break;
  case 0xA2:
    pdu_type_string = calloc(1, strlen(GetResponse) + 1);
    strcpy(pdu_type_string, GetResponse);
    break;
  case 0xA3:
    pdu_type_string = calloc(1, strlen(SetRequest) + 1);
    strcpy(pdu_type_string, SetRequest);
    break;
  default:
    pdu_type_string = calloc(1, strlen(Error) + 1);
    strcpy(pdu_type_string, Error);
    break;
  }
  return (unsigned char *)pdu_type_string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fwriteHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movb   $0x30,-0x22(%rbp)
  movb   $0x78,-0x21(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L4
L0:
  mov    -0x2c(%rbp),%eax
  shl    $0x2,%eax
  mov    -0x38(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  mov    %eax,-0x28(%rbp)
  mov    $0x9,%eax
  sub    -0x2c(%rbp),%eax
  mov    %eax,%ebx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <hexDigit@plt>
  movslq %ebx,%rdx
  mov    %al,-0x22(%rbp,%rdx,1)
  addl   $0x1,-0x2c(%rbp)
L4:
  cmpl   $0x7,-0x2c(%rbp)
  jle    L0
  lea    -0x22(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void fwriteHex(int f, int v) {
  char s[10];
  s[0] = '0';
  s[1] = 'x';
  int i;
  for (i = 0; i < 8; i++) {
    int h = (v >> (i * 4)) & 0xf;
    s[9 - i] = hexDigit(h);
  }
  write(f, s, 10);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fwriteHex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r13d
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x30,0xe(%rsp)
  movb   $0x78,0xf(%rsp)
  mov    $0x0,%ebx
  lea    0x17(%rsp),%r12
L15:
  mov    %ebx,%ecx
  neg    %ecx
  shl    $0x2,%ecx
  mov    %ebp,%edi
  sar    %cl,%edi
  and    $0xf,%edi
  call   <hexDigit@plt>
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  cmp    $0xfffffffffffffff8,%rbx
  jne    L15
  lea    0xe(%rsp),%rsi
  mov    $0xa,%edx
  mov    %r13d,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fwriteHex(int f, int v) {
  char s[10];
  s[0] = '0';
  s[1] = 'x';
  int i;
  for (i = 0; i < 8; i++) {
    int h = (v >> (i * 4)) & 0xf;
    s[9 - i] = hexDigit(h);
  }
  write(f, s, 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fwriteHex>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x7830,%eax
  lea    0x17(%rsp),%r12
  mov    %ax,0xe(%rsp)
  nopl   0x0(%rax)
L5:
  mov    %ebx,%ecx
  mov    %ebp,%edi
  neg    %ecx
  shl    $0x2,%ecx
  sar    %cl,%edi
  and    $0xf,%edi
  call   <hexDigit@plt>
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  cmp    $0xfffffffffffffff8,%rbx
  jne    L5
  mov    $0xa,%edx
  lea    0xe(%rsp),%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fwriteHex(int f, int v) {
  char s[10];
  s[0] = '0';
  s[1] = 'x';
  int i;
  for (i = 0; i < 8; i++) {
    int h = (v >> (i * 4)) & 0xf;
    s[9 - i] = hexDigit(h);
  }
  write(f, s, 10);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fwriteHex>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x7830,%eax
  lea    0x17(%rsp),%r12
  mov    %ax,0xe(%rsp)
  nopl   0x0(%rax)
L10:
  mov    %ebx,%ecx
  mov    %ebp,%edi
  neg    %ecx
  shl    $0x2,%ecx
  sar    %cl,%edi
  and    $0xf,%edi
  call   <hexDigit@plt>
  mov    %al,(%r12,%rbx,1)
  sub    $0x1,%rbx
  cmp    $0xfffffffffffffff8,%rbx
  jne    L10
  mov    $0xa,%edx
  lea    0xe(%rsp),%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void fwriteHex(int f, int v) {
  char s[10];
  s[0] = '0';
  s[1] = 'x';
  int i;
  for (i = 0; i < 8; i++) {
    int h = (v >> (i * 4)) & 0xf;
    s[9 - i] = hexDigit(h);
  }
  write(f, s, 10);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_coretemp@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test_coretemp();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_coretemp@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_coretemp();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_coretemp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_coretemp();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_coretemp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_coretemp();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<pick_by_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L86
  mov    -0x1c(%rbp),%eax
  jmp    L19
L86:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L67
L53:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L12
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L12:
  addl   $0x1,-0x4(%rbp)
L67:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L53
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L33
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L19
L33:
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L49
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pick_by_sort>
  jmp    L19
L49:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edi
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <pick_by_sort>
L19:
  leave
  ret
```

assistant: ```c
int pick_by_sort(int *x, int l, int u, int n) {
  if (l >= u)
    return (l);
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + (++m), x + i);
  }
  swap(x + l, x + m);
  if (m == (n - 1))
    return (x[m]);
  if (m < (n - 1))
    return (pick_by_sort(x, m + 1, u, n));
  return (pick_by_sort(x, l, m - 1, n));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pick_by_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L60
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r12d
  lea    0x1(%rsi),%ebx
  cmp    %ebx,%edx
  jl     L86
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r15
  movslq %ebx,%rbx
  mov    %esi,%r13d
  jmp    L22
L4:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L39
L22:
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    (%r15),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L4
  add    $0x1,%r13d
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  jmp    L4
L86:
  mov    %esi,%r13d
L39:
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,4),%rbx
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  mov    %rbx,%rsi
  call   <swap@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cmp    %r13d,%eax
  je     L15
  jg     L84
  lea    -0x1(%r13),%edx
  mov    0xc(%rsp),%ecx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <pick_by_sort>
L60:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  mov    (%rbx),%eax
  jmp    L60
L84:
  lea    0x1(%r13),%esi
  mov    0xc(%rsp),%ecx
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <pick_by_sort>
  jmp    L60
```

assistant: ```c
int pick_by_sort(int *x, int l, int u, int n) {
  if (l >= u)
    return (l);
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + (++m), x + i);
  }
  swap(x + l, x + m);
  if (m == (n - 1))
    return (x[m]);
  if (m < (n - 1))
    return (pick_by_sort(x, m + 1, u, n));
  return (pick_by_sort(x, l, m - 1, n));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pick_by_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %edx,%esi
  jge    L72
  lea    -0x1(%rcx),%eax
  mov    %rdi,%rbp
  mov    %edx,%r15d
  mov    %eax,0xc(%rsp)
  nopw   0x0(%rax,%rax,1)
L65:
  movslq %r13d,%rax
  lea    0x1(%r13),%ebx
  lea    0x0(%rbp,%rax,4),%r14
  cmp    %r15d,%ebx
  jg     L47
  movslq %ebx,%rbx
  mov    %r13d,%r12d
  jmp    L59
  nopl   (%rax)
L39:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jl     L12
L59:
  mov    (%r14),%eax
  lea    0x0(%rbp,%rbx,4),%rsi
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L39
  add    $0x1,%r12d
  add    $0x1,%rbx
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  cmp    %ebx,%r15d
  jge    L59
L12:
  movslq %r12d,%rax
  lea    0x0(%rbp,%rax,4),%rbx
L74:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <swap@plt>
  cmp    0xc(%rsp),%r12d
  je     L13
  jge    L11
  lea    0x1(%r12),%r13d
L29:
  cmp    %r13d,%r15d
  jg     L65
L72:
  add    $0x18,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L11:
  lea    -0x1(%r12),%r15d
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %r14,%rbx
  mov    %r13d,%r12d
  jmp    L74
L13:
  mov    (%rbx),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int pick_by_sort(int *x, int l, int u, int n) {
  if (l >= u)
    return (l);
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + (++m), x + i);
  }
  swap(x + l, x + m);
  if (m == (n - 1))
    return (x[m]);
  if (m < (n - 1))
    return (pick_by_sort(x, m + 1, u, n));
  return (pick_by_sort(x, l, m - 1, n));
}
```
user: Translate the below assembly code into C programming language:

```asm
<pick_by_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    %edx,%esi
  jge    L49
  lea    -0x1(%rcx),%eax
  mov    %rdi,%rbp
  mov    %edx,%r15d
  mov    %eax,0xc(%rsp)
  lea    0x1(%rsi),%eax
  mov    %eax,0x8(%rsp)
  movslq %esi,%rax
  mov    %rax,(%rsp)
  nopl   0x0(%rax,%rax,1)
L80:
  mov    (%rsp),%rax
  lea    0x0(%rbp,%rax,4),%r13
  mov    0x8(%rsp),%eax
  cmp    %r15d,%eax
  jg     L22
  movslq %eax,%rbx
  mov    %r12d,%r14d
  jmp    L0
  xchg   %ax,%ax
L100:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jl     L102
L0:
  mov    0x0(%r13),%eax
  lea    0x0(%rbp,%rbx,4),%rsi
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L100
  add    $0x1,%r14d
  add    $0x1,%rbx
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%rdi
  call   <swap@plt>
  cmp    %ebx,%r15d
  jge    L0
L102:
  movslq %r14d,%rax
  lea    0x0(%rbp,%rax,4),%rbx
L54:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  cmp    0xc(%rsp),%r14d
  je     L105
  jge    L48
  lea    0x1(%r14),%r12d
  cmp    %r15d,%r12d
  jge    L49
  lea    0x2(%r14),%eax
  mov    %eax,0x8(%rsp)
  movslq %r12d,%rax
  mov    %rax,(%rsp)
  jmp    L80
  nopl   0x0(%rax,%rax,1)
L48:
  lea    -0x1(%r14),%r15d
  cmp    %r12d,%r15d
  jg     L80
L49:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L22:
  mov    %r13,%rbx
  mov    %r12d,%r14d
  jmp    L54
L105:
  mov    (%rbx),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int pick_by_sort(int *x, int l, int u, int n) {
  if (l >= u)
    return (l);
  int m, i;
  m = l;
  for (i = l + 1; i <= u; i++) {
    if (x[i] < x[l])
      swap(x + (++m), x + i);
  }
  swap(x + l, x + m);
  if (m == (n - 1))
    return (x[m]);
  if (m < (n - 1))
    return (pick_by_sort(x, m + 1, u, n));
  return (pick_by_sort(x, l, m - 1, n));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<djb2Hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L10:
  mov    -0x10(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L10
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int djb2Hash(void *k) {
  unsigned long h = 0;
  int c;
  char *key = (char *)k;
  while ((c = *key++)) {
    h = ((h << 5) + h) + c;
  }
  return h;
}
```
user: What is the c source code of the assembly code below:

```asm
<djb2Hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L11
  mov    $0x0,%eax
L7:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L7
  ret
L11:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int djb2Hash(void *k) {
  unsigned long h = 0;
  int c;
  char *key = (char *)k;
  while ((c = *key++)) {
    h = ((h << 5) + h) + c;
  }
  return h;
}
```