user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x30(%rbp)
  jmp    L153
L192:
  lea    -0x34(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  jne    L1
  movl   $0x0,-0x2c(%rbp)
  jmp    L195
L193:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L195:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jl     L193
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L156
L1:
  mov    -0x38(%rbp),%eax
  cmp    $0x1,%eax
  jne    L120
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L156
L120:
  mov    -0x34(%rbp),%eax
  cmp    $0x1,%eax
  jne    L119
  mov    -0x38(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L119
  movl   $0x0,-0x28(%rbp)
  jmp    L77
L132:
  mov    -0x28(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x28(%rbp)
L77:
  mov    -0x38(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x28(%rbp)
  jl     L132
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L156
L119:
  mov    -0x38(%rbp),%eax
  mov    -0x34(%rbp),%edx
  lea    (%rdx,%rdx,1),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L216
  mov    -0x38(%rbp),%eax
  mov    -0x34(%rbp),%edx
  lea    (%rdx,%rdx,1),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L34
L97:
  mov    -0x34(%rbp),%eax
  imul   -0x24(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  imul   %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L155
L51:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L155:
  mov    -0x20(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L51
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L145
L138:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
L145:
  mov    -0x1c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L138
  addl   $0x1,-0x24(%rbp)
L34:
  mov    -0x24(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L97
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L156
L216:
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L156:
  addl   $0x1,-0x30(%rbp)
L153:
  mov    -0x3c(%rbp),%eax
  cmp    %eax,-0x30(%rbp)
  jl     L192
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D64
datatype: string
name: retrieve_data
arguments: data_label: D8
datatype: string
name: retrieve_data
arguments: data_label: D57
datatype: string
name: retrieve_data
arguments: data_label: D27
datatype: string
name: retrieve_data
arguments: data_label: D76
datatype: string

tool: D26: %d

tool: D64: %d %d

tool: D8: %d 

tool: D57: 1

tool: D27: %d %d 

tool: D76: -1

assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  for (int a0 = 0; a0 < t; a0++) {
    int n;
    int k;
    scanf("%d %d", &n, &k);
    if (k == 0) {
      for (int i = 0; i < n; i++) {
        printf("%d ", i + 1);
      }
      printf("\n");
    } else {
      if (n == 1) {
        printf("1\n");
      } else {
        if (k == 1 && n % 2 == 0) {
          for (int i = 0; i < n / 2; i++) {
            printf("%d %d ", 2 * i + 2, 2 * i + 1);
          }
          printf("\n");
        } else if (n % (2 * k) == 0) {
          int partitions = n / (2 * k);
          for (int i = 0; i < partitions; i++) {
            int start = 2 * k * i;
            int end = 2 * k * (i + 1);
            int mid = start + k;
            for (int j = mid; j < end; j++) {
              printf("%d ", j + 1);
            }
            for (int j = start; j < mid; j++) {
              printf("%d ", j + 1);
            }
          }
          printf("\n");
        } else {
          printf("-1\n");
        }
      }
    }
  }
  return 0;
}
```