ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap_byte_nibbles>:
  endbr64
  test   %esi,%esi
  jle    L5
  mov    %rdi,%rcx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rsi
L14:
  mov    (%rcx),%eax
  mov    %eax,%edx
  sar    $0x4,%edx
  and    $0xf,%edx
  shl    $0x4,%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  cmp    %rsi,%rcx
  jne    L14
L5:
  ret
```

assistant: ```c
void swap_byte_nibbles(uint8_t *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *(buf + i) = ((*(buf + i) & 0xF0) >> 4) | ((*(buf + i) & 0x0F) << 4);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<swap_byte_nibbles>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
L11:
  mov    (%rdi),%eax
  add    $0x4,%rdi
  mov    %eax,%edx
  shl    $0x4,%eax
  sar    $0x4,%edx
  movzbl %al,%eax
  and    $0xf,%edx
  or     %edx,%eax
  mov    %eax,-0x4(%rdi)
  cmp    %rdi,%rcx
  jne    L11
L10:
  ret
```

assistant: ```c
void swap_byte_nibbles(uint8_t *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *(buf + i) = ((*(buf + i) & 0xF0) >> 4) | ((*(buf + i) & 0x0F) << 4);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<swap_byte_nibbles>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L52
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L42
  mov    %esi,%ecx
  movdqa D5(%rip),%xmm3
  movdqa D18(%rip),%xmm2
  mov    %rdi,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nop
L8:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pslld  $0x4,%xmm0
  psrad  $0x4,%xmm1
  pand   %xmm2,%xmm0
  pand   %xmm3,%xmm1
  por    %xmm1,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L8
  mov    %esi,%ecx
  and    $0xfffffffc,%ecx
  mov    %ecx,%eax
  cmp    %ecx,%esi
  je     L61
L62:
  sub    %ecx,%esi
  cmp    $0x1,%esi
  je     L33
  movq   D5(%rip),%xmm2
  lea    (%rdx,%rcx,4),%rcx
  movq   (%rcx),%xmm0
  movdqa %xmm0,%xmm1
  pslld  $0x4,%xmm0
  psrad  $0x4,%xmm1
  pand   %xmm2,%xmm1
  movq   D18(%rip),%xmm2
  pand   %xmm2,%xmm0
  por    %xmm1,%xmm0
  movq   %xmm0,(%rcx)
  mov    %esi,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%eax
  cmp    %ecx,%esi
  je     L52
L33:
  cltq
  lea    (%rdx,%rax,4),%rcx
  mov    (%rcx),%eax
  mov    %eax,%edx
  shl    $0x4,%eax
  sar    $0x4,%edx
  movzbl %al,%eax
  and    $0xf,%edx
  or     %edx,%eax
  mov    %eax,(%rcx)
L52:
  ret
  nopl   0x0(%rax)
L61:
  ret
L42:
  xor    %ecx,%ecx
  xor    %eax,%eax
  jmp    L62
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D18
type_infered: byte[16]

tool: {"D5": [0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: {"D18": [0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00]}

assistant: ```c
void swap_byte_nibbles(uint8_t *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *(buf + i) = ((*(buf + i) & 0xF0) >> 4) | ((*(buf + i) & 0x0F) << 4);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<filesystem_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <setfsent@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L7
  mov    $0x0,%eax
  jmp    L0
L7:
  mov    $0x0,%eax
  call   <getfsent@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <endfsent@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L0
L25:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
L0:
  leave
  ret
```

assistant: ```c
char *filesystem_type(void) {
  int ret = setfsent();
  if (ret != 1)
    return NULL;
  struct fstab *file_system = getfsent();
  endfsent();
  if (!file_system)
    return NULL;
  return file_system->fs_vfstype;
}
```
user: What is the c source code of the assembly code below?

```asm
<filesystem_type>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <setfsent@plt>
  mov    $0x0,%ebx
  cmp    $0x1,%eax
  jne    L2
  mov    $0x0,%eax
  call   <getfsent@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <endfsent@plt>
  test   %rbx,%rbx
  je     L2
  mov    (%rbx),%rbx
L2:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *filesystem_type(void) {
  int ret = setfsent();
  if (ret != 1)
    return NULL;
  struct fstab *file_system = getfsent();
  endfsent();
  if (!file_system)
    return NULL;
  return file_system->fs_vfstype;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filesystem_type>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <setfsent@plt>
  cmp    $0x1,%eax
  jne    L7
  xor    %eax,%eax
  call   <getfsent@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <endfsent@plt>
  test   %rbx,%rbx
  je     L7
  mov    (%rbx),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *filesystem_type(void) {
  int ret = setfsent();
  if (ret != 1)
    return NULL;
  struct fstab *file_system = getfsent();
  endfsent();
  if (!file_system)
    return NULL;
  return file_system->fs_vfstype;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filesystem_type>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <setfsent@plt>
  cmp    $0x1,%eax
  jne    L0
  xor    %eax,%eax
  call   <getfsent@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <endfsent@plt>
  test   %rbx,%rbx
  je     L0
  mov    (%rbx),%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char *filesystem_type(void) {
  int ret = setfsent();
  if (ret != 1)
    return NULL;
  struct fstab *file_system = getfsent();
  endfsent();
  if (!file_system)
    return NULL;
  return file_system->fs_vfstype;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<monikor_vlog_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <_format_mod_log_message@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L13
L11:
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <monikor_vlog@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
int monikor_vlog_mod(int prio, const char *mod_name, const char *message, va_list ap) {
  int ret;
  char *full_msg;
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  free(full_msg);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<monikor_vlog_mod>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%r12d
  call   <_format_mod_log_message@plt>
  test   %rax,%rax
  je     L16
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rax,%rsi
  mov    %ebp,%edi
  call   <monikor_vlog@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
L0:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    $0xffffffff,%ebp
  jmp    L0
```

assistant: ```c
int monikor_vlog_mod(int prio, const char *mod_name, const char *message, va_list ap) {
  int ret;
  char *full_msg;
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  free(full_msg);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<monikor_vlog_mod>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbp
  call   <_format_mod_log_message@plt>
  test   %rax,%rax
  je     L11
  mov    %r12d,%edi
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    %rax,%rsi
  call   <monikor_vlog@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L5:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0xffffffff,%r12d
  jmp    L5
```

assistant: ```c
int monikor_vlog_mod(int prio, const char *mod_name, const char *message, va_list ap) {
  int ret;
  char *full_msg;
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  free(full_msg);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<monikor_vlog_mod>:
  endbr64
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %rbp
  call   <_format_mod_log_message@plt>
  test   %rax,%rax
  je     L14
  mov    %r12d,%edi
  mov    %rax,%rbp
  mov    %r13d,%edx
  mov    %rax,%rsi
  call   <monikor_vlog@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
L12:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  mov    $0xffffffff,%r12d
  jmp    L12
```

assistant: ```c
int monikor_vlog_mod(int prio, const char *mod_name, const char *message, va_list ap) {
  int ret;
  char *full_msg;
  if (!(full_msg = _format_mod_log_message(mod_name, message)))
    return -1;
  ret = monikor_vlog(prio, full_msg, ap);
  free(full_msg);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compWordLetters>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L45
L48:
  movl   $0x0,-0xc(%rbp)
  jmp    L25
L39:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L24
  addl   $0x1,-0x14(%rbp)
  jmp    L16
L24:
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L39
L16:
  addl   $0x1,-0x10(%rbp)
L45:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L48
  mov    -0x14(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L70
  mov    $0x1,%eax
  jmp    L40
L70:
  mov    $0x0,%eax
L40:
  leave
  ret
```

assistant: ```c
int compWordLetters(char *word, char *letters) {
  int wordLen = strlen(word);
  int numOfLet = strlen(letters);
  int valid = 0;
  for (int i = 0; i < wordLen; i++) {
    for (int p = 0; p < numOfLet; p++) {
      if (word[i] == letters[p]) {
        valid += 1;
        break;
      }
    }
  }
  if (valid == wordLen) {
    return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compWordLetters>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %ebp,%ebp
  jle    L41
  mov    %r12,%rdi
  lea    -0x1(%rbp),%edx
  lea    0x1(%r12,%rdx,1),%r9
  mov    $0x0,%r8d
  lea    -0x1(%rax),%edx
  lea    0x1(%rbx,%rdx,1),%rsi
  jmp    L14
L18:
  add    $0x1,%r8d
L23:
  add    $0x1,%rdi
  cmp    %r9,%rdi
  je     L17
L14:
  test   %eax,%eax
  jle    L23
  movzbl (%rdi),%ecx
  mov    %rbx,%rdx
L51:
  cmp    (%rdx),%cl
  je     L18
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L51
  jmp    L23
L41:
  mov    $0x0,%r8d
L17:
  cmp    %r8d,%ebp
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int compWordLetters(char *word, char *letters) {
  int wordLen = strlen(word);
  int numOfLet = strlen(letters);
  int valid = 0;
  for (int i = 0; i < wordLen; i++) {
    for (int p = 0; p < numOfLet; p++) {
      if (word[i] == letters[p]) {
        valid += 1;
        break;
      }
    }
  }
  if (valid == wordLen) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compWordLetters>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  test   %r12d,%r12d
  jle    L46
  lea    -0x1(%r12),%edx
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  lea    0x1(%rbx,%rdx,1),%r9
  lea    -0x1(%rax),%edx
  lea    0x1(%rbp,%rdx,1),%rsi
  nopl   0x0(%rax,%rax,1)
L49:
  test   %eax,%eax
  jle    L47
  movzbl (%rdi),%ecx
  mov    %rbp,%rdx
  jmp    L25
  nopl   0x0(%rax)
L29:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L47
L25:
  cmp    (%rdx),%cl
  jne    L29
  add    $0x1,%r8d
L47:
  add    $0x1,%rdi
  cmp    %r9,%rdi
  jne    L49
  xor    %eax,%eax
  cmp    %r8d,%r12d
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
L46:
  xor    %r8d,%r8d
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  cmp    %r8d,%r12d
  pop    %r12
  sete   %al
  ret
```

assistant: ```c
int compWordLetters(char *word, char *letters) {
  int wordLen = strlen(word);
  int numOfLet = strlen(letters);
  int valid = 0;
  for (int i = 0; i < wordLen; i++) {
    for (int p = 0; p < numOfLet; p++) {
      if (word[i] == letters[p]) {
        valid += 1;
        break;
      }
    }
  }
  if (valid == wordLen) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<compWordLetters>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  test   %r12d,%r12d
  jle    L5
  lea    -0x1(%r12),%edx
  mov    %rbx,%rdi
  xor    %r8d,%r8d
  lea    0x1(%rbx,%rdx,1),%r9
  lea    -0x1(%rax),%edx
  lea    0x1(%rbp,%rdx,1),%rsi
  nopl   0x0(%rax,%rax,1)
L55:
  test   %eax,%eax
  jle    L25
  movzbl (%rdi),%ecx
  mov    %rbp,%rdx
  jmp    L35
  nopl   0x0(%rax)
L41:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L25
L35:
  cmp    (%rdx),%cl
  jne    L41
  add    $0x1,%r8d
L25:
  add    $0x1,%rdi
  cmp    %r9,%rdi
  jne    L55
  xor    %eax,%eax
  cmp    %r8d,%r12d
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
L5:
  xor    %r8d,%r8d
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  cmp    %r8d,%r12d
  pop    %r12
  sete   %al
  ret
```

assistant: ```c
int compWordLetters(char *word, char *letters) {
  int wordLen = strlen(word);
  int numOfLet = strlen(letters);
  int valid = 0;
  for (int i = 0; i < wordLen; i++) {
    for (int p = 0; p < numOfLet; p++) {
      if (word[i] == letters[p]) {
        valid += 1;
        break;
      }
    }
  }
  if (valid == wordLen) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CE_pHP_CO3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  D7(%rip),%xmm0
  subsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%edx
  mov    D15(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x40(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x4,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movsd  -0x38(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movq   D5(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  movsd  -0x20(%rbp),%xmm0
  mulsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x38(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movq   D5(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x28(%rbp),%xmm2
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm2
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  divsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: byte[8]
name: read_data
arguments: data_label: D15
type_infered: byte[8]
name: read_data
arguments: data_label: D5
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CE_pHP_CO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K2 * K1 * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O) / H3O;
  return t0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<CE_pHP_CO3>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm6
  movq   %xmm1,%rbx
  movq   %xmm2,%r13
  movq   %xmm3,%rbp
  movq   %xmm4,%r12
  movq   %xmm5,%r14
  movsd  D25(%rip),%xmm0
  subsd  %xmm6,%xmm0
  cvttsd2si %xmm0,%edi
  movsd  D6(%rip),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm7
  movq   %r14,%xmm0
  divsd  %xmm0,%xmm7
  movsd  %xmm7,(%rsp)
  mov    $0x2,%edi
  call   <pow@plt>
  movq   %r13,%xmm6
  divsd  %xmm0,%xmm6
  movsd  %xmm6,0x8(%rsp)
  mov    $0x4,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm5
  divsd  %xmm0,%xmm5
  movq   %xmm5,%rbp
  mov    $0x2,%edi
  movq   %r14,%xmm0
  call   <pow@plt>
  movq   %rbp,%xmm3
  xorpd  D22(%rip),%xmm3
  mulsd  0x8(%rsp),%xmm3
  movsd  (%rsp),%xmm7
  movapd %xmm7,%xmm2
  mulsd  %xmm7,%xmm2
  movq   %rbx,%xmm4
  mulsd  %xmm7,%xmm4
  movq   %r12,%xmm1
  divsd  %xmm0,%xmm1
  subsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm3
  divsd  %xmm3,%xmm0
  divsd  %xmm7,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D25
data_type: byte[8]
name: parse_data
arguments: label: D6
data_type: byte[8]
name: parse_data
arguments: label: D22
data_type: byte[16]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_CO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K2 * K1 * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O) / H3O;
  return t0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CE_pHP_CO3>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D21(%rip),%xmm0
  movsd  %xmm1,0x38(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x30(%rsp)
  movsd  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D0(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm6
  divsd  %xmm5,%xmm6
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x20(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm6
  movsd  0x38(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm3
  divsd  %xmm0,%xmm4
  movapd %xmm6,%xmm2
  xorpd  D8(%rip),%xmm3
  mulsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm2
  mulsd  0x8(%rsp),%xmm3
  add    $0x48,%rsp
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm3
  divsd  %xmm3,%xmm0
  divsd  %xmm6,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D21
type_infered: byte[8]
name: disassemble_data
arguments: tag: D0
type_infered: byte[8]
name: disassemble_data
arguments: tag: D8
type_infered: byte[16]

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_CO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K2 * K1 * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O) / H3O;
  return t0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CE_pHP_CO3>:
  endbr64
  sub    $0x48,%rsp
  movapd %xmm0,%xmm6
  movsd  D25(%rip),%xmm0
  movsd  %xmm1,0x38(%rsp)
  subsd  %xmm6,%xmm0
  movsd  %xmm4,0x28(%rsp)
  movsd  %xmm3,0x30(%rsp)
  movsd  %xmm2,0x18(%rsp)
  cvttsd2si %xmm0,%edi
  movsd  D1(%rip),%xmm0
  movsd  %xmm5,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm5
  mov    $0x2,%edi
  movapd %xmm0,%xmm6
  divsd  %xmm5,%xmm6
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x20(%rsp)
  call   <pow@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm5
  mov    $0x4,%edi
  divsd  %xmm0,%xmm2
  movapd %xmm5,%xmm0
  movsd  %xmm5,0x18(%rsp)
  movsd  %xmm2,0x8(%rsp)
  call   <pow@plt>
  movsd  0x30(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm5
  mov    $0x2,%edi
  divsd  %xmm0,%xmm3
  movapd %xmm5,%xmm0
  movsd  %xmm3,0x10(%rsp)
  call   <pow@plt>
  movsd  0x28(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm6
  movsd  0x38(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm3
  divsd  %xmm0,%xmm4
  movapd %xmm6,%xmm2
  xorpd  D11(%rip),%xmm3
  mulsd  %xmm6,%xmm1
  mulsd  %xmm6,%xmm2
  mulsd  0x8(%rsp),%xmm3
  add    $0x48,%rsp
  subsd  %xmm4,%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm3
  divsd  %xmm3,%xmm0
  divsd  %xmm6,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D25
type_guessed: byte[8]
name: parse_data
arguments: label: D1
type_guessed: byte[8]
name: parse_data
arguments: label: D11
type_guessed: byte[16]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
double CE_pHP_CO3(double pH, double P, double K1, double K2, double Kw, double f) {
  double H3O, t0;
  H3O = pow(10, (3 - pH)) / f;
  K1 = K1 / pow(f, 2);
  K2 = K2 / pow(f, 4);
  Kw = Kw / pow(f, 2);
  t0 = -K2 * K1 * (P * H3O - Kw + H3O * H3O) / (-K2 * K1 + H3O * H3O) / H3O;
  return t0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L20:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L33
  mov    $0x1,%eax
  jmp    L38
L33:
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L20
  mov    $0x0,%eax
L38:
  pop    %rbp
  ret
```

assistant: ```c
int contains(const char c, const char *matrix, int len) {
  for (unsigned int x = 0; x < len; x++)
    if ((char)matrix[x] == c)
      return 1;
  return 0;
}
```