ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rb_htole32>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t rb_htole32(uint32_t x) {
  uint32_t test = 0x12345678;
  unsigned char *p = (unsigned char *)&test;
  if (p[0] == 0x12) {
    return swap32(x);
  } else {
    return x;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rb_htole32>:
  endbr64
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t rb_htole32(uint32_t x) {
  uint32_t test = 0x12345678;
  unsigned char *p = (unsigned char *)&test;
  if (p[0] == 0x12) {
    return swap32(x);
  } else {
    return x;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<head_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  and    $0xffe00000,%eax
  mov    $0xffe00000,%edx
  cmp    %rdx,%rax
  jne    L13
  mov    -0x8(%rbp),%rax
  shr    $0x11,%rax
  and    $0x3,%eax
  test   %rax,%rax
  je     L13
  mov    -0x8(%rbp),%rax
  shr    $0xc,%rax
  and    $0xf,%eax
  cmp    $0xf,%rax
  je     L13
  mov    -0x8(%rbp),%rax
  shr    $0xc,%rax
  and    $0xf,%eax
  test   %rax,%rax
  je     L13
  mov    -0x8(%rbp),%rax
  shr    $0xa,%rax
  and    $0x3,%eax
  cmp    $0x3,%rax
  jne    L29
L13:
  mov    $0x0,%eax
  jmp    L5
L29:
  mov    $0x1,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int head_check(unsigned long head) {
  if (((head & 0xffe00000) != 0xffe00000) || (!((head >> 17) & 3)) || (((head >> 12) & 0xf) == 0xf) || (((head >> 12) & 0xf) == 0x0) || (((head >> 10) & 0x3) == 0x3)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<head_check>:
  endbr64
  mov    %rdi,%rcx
  and    $0xffe00000,%ecx
  mov    $0x0,%eax
  mov    $0xffe00000,%edx
  cmp    %rdx,%rcx
  jne    L8
  test   $0x60000,%edi
  je     L8
  mov    %rdi,%rdx
  shr    $0xc,%rdx
  and    $0xf,%edx
  mov    $0x8001,%ecx
  bt     %rdx,%rcx
  jb     L8
  xor    $0xc00,%rdi
  test   $0xc00,%edi
  setne  %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int head_check(unsigned long head) {
  if (((head & 0xffe00000) != 0xffe00000) || (!((head >> 17) & 3)) || (((head >> 12) & 0xf) == 0xf) || (((head >> 12) & 0xf) == 0x0) || (((head >> 10) & 0x3) == 0x3)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<head_check>:
  endbr64
  mov    %rdi,%rcx
  mov    $0xffe00000,%edx
  xor    %eax,%eax
  and    $0xffe00000,%ecx
  cmp    %rdx,%rcx
  jne    L21
  test   $0x60000,%edi
  je     L21
  mov    %rdi,%rdx
  mov    $0x8001,%ecx
  shr    $0xc,%rdx
  and    $0xf,%edx
  bt     %rdx,%rcx
  jb     L21
  xor    $0xc00,%rdi
  xor    %eax,%eax
  test   $0xc00,%edi
  setne  %al
L21:
  ret
```

assistant: ```c
int head_check(unsigned long head) {
  if (((head & 0xffe00000) != 0xffe00000) || (!((head >> 17) & 3)) || (((head >> 12) & 0xf) == 0xf) || (((head >> 12) & 0xf) == 0x0) || (((head >> 10) & 0x3) == 0x3)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<head_check>:
  endbr64
  mov    %rdi,%rcx
  mov    $0xffe00000,%edx
  xor    %eax,%eax
  and    $0xffe00000,%ecx
  cmp    %rdx,%rcx
  jne    L16
  test   $0x60000,%edi
  je     L16
  mov    %rdi,%rdx
  mov    $0x8001,%ecx
  shr    $0xc,%rdx
  and    $0xf,%edx
  bt     %rdx,%rcx
  jb     L16
  xor    $0xc00,%rdi
  xor    %eax,%eax
  test   $0xc00,%edi
  setne  %al
L16:
  ret
```

assistant: ```c
int head_check(unsigned long head) {
  if (((head & 0xffe00000) != 0xffe00000) || (!((head >> 17) & 3)) || (((head >> 12) & 0xf) == 0xf) || (((head >> 12) & 0xf) == 0x0) || (((head >> 10) & 0x3) == 0x3)) {
    return 0;
  } else {
    return 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cli_prt_prio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x80,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  cmp    $0x61,%al
  je     L3
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %eax,-0xc(%rbp)
L3:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <set_rstp_port_cfg_value@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int cli_prt_prio(int argc, char **argv) {
  int port_index = 0;
  unsigned long value = 128;
  if ('a' != argv[1][0]) {
    port_index = strtoul(argv[1], 0, 10);
  }
  value = strtoul(argv[2], 0, 10);
  set_rstp_port_cfg_value(port_index, value, (1L << 2));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<cli_prt_prio>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  mov    $0x0,%ebp
  cmpb   $0x61,(%rdi)
  jne    L8
L10:
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,%rsi
  mov    $0x4,%edx
  mov    %ebp,%edi
  call   <set_rstp_port_cfg_value@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %eax,%ebp
  jmp    L10
```

assistant: ```c
int cli_prt_prio(int argc, char **argv) {
  int port_index = 0;
  unsigned long value = 128;
  if ('a' != argv[1][0]) {
    port_index = strtoul(argv[1], 0, 10);
  }
  value = strtoul(argv[2], 0, 10);
  set_rstp_port_cfg_value(port_index, value, (1L << 2));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cli_prt_prio>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  cmpb   $0x61,(%rdi)
  je     L1
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %eax,%ebp
L1:
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %ebp,%edi
  mov    $0x4,%edx
  mov    %rax,%rsi
  call   <set_rstp_port_cfg_value@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cli_prt_prio(int argc, char **argv) {
  int port_index = 0;
  unsigned long value = 128;
  if ('a' != argv[1][0]) {
    port_index = strtoul(argv[1], 0, 10);
  }
  value = strtoul(argv[2], 0, 10);
  set_rstp_port_cfg_value(port_index, value, (1L << 2));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cli_prt_prio>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  cmpb   $0x61,(%rdi)
  je     L5
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %eax,%ebp
L5:
  mov    0x10(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  mov    %ebp,%edi
  mov    $0x4,%edx
  mov    %rax,%rsi
  call   <set_rstp_port_cfg_value@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cli_prt_prio(int argc, char **argv) {
  int port_index = 0;
  unsigned long value = 128;
  if ('a' != argv[1][0]) {
    port_index = strtoul(argv[1], 0, 10);
  }
  value = strtoul(argv[2], 0, 10);
  set_rstp_port_cfg_value(port_index, value, (1L << 2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<zf_notify_sys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x1,-0x10(%rbp)
  jne    L22
  mov    $0x0,%eax
  call   <zf_timer_off@plt>
  jmp    L29
L22:
  cmpq   $0x2,-0x10(%rbp)
  jne    L29
  mov    $0x0,%eax
  call   <zf_timer_off@plt>
L29:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int zf_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      zf_timer_off();
    } else if (code == 2UL) {
      zf_timer_off();
    }
    return (0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zf_notify_sys>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%rsi
  je     L3
  cmp    $0x2,%rsi
  je     L23
L39:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <zf_timer_off@plt>
  jmp    L39
L23:
  mov    $0x0,%eax
  call   <zf_timer_off@plt>
  jmp    L39
```

assistant: ```c
int zf_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      zf_timer_off();
    } else if (code == 2UL) {
      zf_timer_off();
    }
    return (0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<zf_notify_sys>:
  endbr64
  sub    $0x1,%rsi
  cmp    $0x1,%rsi
  jbe    L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L6:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <zf_timer_off@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int zf_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      zf_timer_off();
    } else if (code == 2UL) {
      zf_timer_off();
    }
    return (0);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zf_notify_sys>:
  endbr64
  sub    $0x1,%rsi
  cmp    $0x1,%rsi
  jbe    L8
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L8:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <zf_timer_off@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int zf_notify_sys(struct notifier_block *this, unsigned long code, void *unused) {
  {
    if (code == 1UL) {
      zf_timer_off();
    } else if (code == 2UL) {
      zf_timer_off();
    }
    return (0);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printData>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L37:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L37
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L34:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L34
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: %4d

assistant: ```c
void printData(int data[], int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%4d", i);
  }
  printf("\n");
  for (i = 0; i < size; i++) {
    printf("%4d", data[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<printData>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L22
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D11(%rip),%r14
L25:
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%r12d
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L25
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13,%rbx
  mov    %r12d,%r12d
  lea    0x4(%r13,%r12,4),%r12
  lea    D11(%rip),%rbp
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L14
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L33
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
data_type: string

tool: D11: %4d

assistant: ```c
void printData(int data[], int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%4d", i);
  }
  printf("\n");
  for (i = 0; i < size; i++) {
    printf("%4d", data[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<printData>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L31
  mov    %rdi,%rbp
  mov    %esi,%r13d
  lea    D1(%rip),%r12
  xor    %ebx,%ebx
  nop
L6:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebx,%r14d
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L6
  mov    $0xa,%edi
  mov    %rbp,%rbx
  lea    0x4(%rbp,%r14,4),%rbp
  call   <putchar@plt>
  nopl   0x0(%rax)
L27:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L27
L10:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L10
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %4d

assistant: ```c
void printData(int data[], int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%4d", i);
  }
  printf("\n");
  for (i = 0; i < size; i++) {
    printf("%4d", data[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printData>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L34
  mov    %rdi,%rbp
  mov    %esi,%r13d
  lea    D0(%rip),%r12
  xor    %ebx,%ebx
  nop
L2:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %ebx,%r14d
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L2
  mov    $0xa,%edi
  mov    %rbp,%rbx
  lea    0x4(%rbp,%r14,4),%rbp
  call   <putchar@plt>
  nopl   0x0(%rax)
L21:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L21
L1:
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L34:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: tag: D0
data_type: string

tool: D0: %4d

assistant: ```c
void printData(int data[], int size) {
  int i;
  for (i = 0; i < size; i++) {
    printf("%4d", i);
  }
  printf("\n");
  for (i = 0; i < size; i++) {
    printf("%4d", data[i]);
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ePar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L7
  mov    $0x1,%eax
  jmp    L9
L7:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <eImpar@plt>
L9:
  leave
  ret
```

assistant: ```c
bool ePar(int numero) {
  if (numero == 0)
    return true;
  else
    return eImpar(numero - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ePar>:
  endbr64
  mov    $0x1,%eax
  test   %edi,%edi
  jne    L1
  ret
L1:
  sub    $0x8,%rsp
  sub    $0x1,%edi
  call   <eImpar@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
bool ePar(int numero) {
  if (numero == 0)
    return true;
  else
    return eImpar(numero - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ePar>:
  endbr64
  test   %edi,%edi
  jne    L3
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L3:
  sub    $0x1,%edi
  jmp    1050 <eImpar@plt>
```

assistant: ```c
bool ePar(int numero) {
  if (numero == 0)
    return true;
  else
    return eImpar(numero - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ePar>:
  endbr64
  test   %edi,%edi
  jne    L3
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L3:
  sub    $0x1,%edi
  jmp    1050 <eImpar@plt>
```

assistant: ```c
bool ePar(int numero) {
  if (numero == 0)
    return true;
  else
    return eImpar(numero - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<A>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <B@plt>
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string

tool: D18: enter A


tool: D14: exit A


assistant: ```c
int A(void) {
  printf("enter A\n");
  B();
  printf("exit A\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<A>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <B@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
type: string
name: parse_data
arguments: data_tag: D11
type: string

tool: D13: enter A


tool: D11: exit A


assistant: ```c
int A(void) {
  printf("enter A\n");
  B();
  printf("exit A\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<A>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <B@plt>
  lea    D15(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D16
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string

tool: D16: enter A


tool: D15: exit A


assistant: ```c
int A(void) {
  printf("enter A\n");
  B();
  printf("exit A\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<A>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <B@plt>
  lea    D15(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string
name: extract_symbolic_data
arguments: label: D15
type: string

tool: D7: enter A


tool: D15: exit A


assistant: ```c
int A(void) {
  printf("enter A\n");
  B();
  printf("exit A\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void calc_sum(int one, double *two, double *three, double *four) {
  int i = 0;
  while (i != one) {
    *(four + i) = *(two + i) + *(three + i);
    i++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calc_sum>:
  endbr64
  test   %edi,%edi
  je     L15
  mov    %edi,%edi
  mov    $0x0,%eax
L3:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L3
L15:
  ret
```

assistant: ```c
void calc_sum(int one, double *two, double *three, double *four) {
  int i = 0;
  while (i != one) {
    *(four + i) = *(two + i) + *(three + i);
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<calc_sum>:
  endbr64
  test   %edi,%edi
  je     L13
  mov    %edi,%edi
  xor    %eax,%eax
  nopl   0x0(%rax)
L0:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L0
L13:
  ret
```

assistant: ```c
void calc_sum(int one, double *two, double *three, double *four) {
  int i = 0;
  while (i != one) {
    *(four + i) = *(two + i) + *(three + i);
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<calc_sum>:
  endbr64
  mov    %edi,%r8d
  mov    %rdx,%rdi
  mov    %rcx,%rdx
  test   %r8d,%r8d
  je     L56
  lea    0x8(%rdi),%rax
  cmp    %rax,%rcx
  lea    0x8(%rsi),%rax
  setne  %cl
  cmp    %rax,%rdx
  setne  %al
  test   %al,%cl
  je     L4
  lea    -0x1(%r8),%eax
  cmp    $0x1,%eax
  jbe    L4
  mov    %r8d,%ecx
  xor    %eax,%eax
  shr    %ecx
  shl    $0x4,%rcx
  nopw   0x0(%rax,%rax,1)
L54:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rdi,%rax,1),%xmm1
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L54
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r8d
  je     L56
  cltq
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  ret
  nopl   0x0(%rax)
L4:
  mov    %r8d,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L47:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L47
L56:
  ret
```

assistant: ```c
void calc_sum(int one, double *two, double *three, double *four) {
  int i = 0;
  while (i != one) {
    *(four + i) = *(two + i) + *(three + i);
    i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <BN_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_mod_sqr@plt>
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rsi
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_mod_sqr@plt>
  mov    -0x50(%rbp),%rdi
  mov    -0x48(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <BN_mod_mul@plt>
  mov    -0x50(%rbp),%rdi
  mov    -0x48(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <BN_mod_sub@plt>
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BN_kronecker@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BN_free@plt>
  mov    -0x24(%rbp),%eax
  leave
  ret
```

assistant: ```c
int gt(const BIGNUM *a, BIGNUM *const *f, const BIGNUM *N, BN_CTX *ctx) {
  BIGNUM *t1 = BN_new();
  BIGNUM *t2 = BN_new();
  BIGNUM *t3 = BN_new();
  BIGNUM *t4 = BN_new();
  int gt_v;
  BN_mod_sqr(t1, f[0], N, ctx);
  BN_mod_sqr(t2, f[1], N, ctx);
  BN_mod_mul(t3, t2, a, N, ctx);
  BN_mod_sub(t4, t1, t3, N, ctx);
  gt_v = BN_kronecker(t4, N, ctx);
  BN_free(t1);
  BN_free(t2);
  BN_free(t3);
  BN_free(t4);
  return gt_v;
}
```