ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read8LE>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <getc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <getc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <getc@plt>
  shl    $0x8,%rbx
  mov    %rbp,%rdi
  shl    $0x10,%rax
  or     %rax,%rbx
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %r12,%rbx
  shl    $0x18,%rax
  mov    %rax,%r12
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %rbx,%r12
  shl    $0x20,%rax
  mov    %rax,%rbx
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %r12,%rbx
  shl    $0x28,%rax
  mov    %rax,%r12
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %rbx,%r12
  shl    $0x30,%rax
  mov    %rax,%rbx
  call   <getc@plt>
  or     %r12,%rbx
  shl    $0x38,%rax
  or     %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long read8LE(FILE *fp) {
  unsigned long long val;
  val = getc(fp);
  val |= (unsigned long long)getc(fp) << 8;
  val |= (unsigned long long)getc(fp) << 16;
  val |= (unsigned long long)getc(fp) << 24;
  val |= (unsigned long long)getc(fp) << 32;
  val |= (unsigned long long)getc(fp) << 40;
  val |= (unsigned long long)getc(fp) << 48;
  val |= (unsigned long long)getc(fp) << 56;
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<read8LE>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <getc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <getc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <getc@plt>
  shl    $0x8,%rbx
  mov    %rbp,%rdi
  shl    $0x10,%rax
  or     %rax,%rbx
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %r12,%rbx
  shl    $0x18,%rax
  mov    %rax,%r12
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %rbx,%r12
  shl    $0x20,%rax
  mov    %rax,%rbx
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %r12,%rbx
  shl    $0x28,%rax
  mov    %rax,%r12
  call   <getc@plt>
  mov    %rbp,%rdi
  or     %rbx,%r12
  shl    $0x30,%rax
  mov    %rax,%rbx
  call   <getc@plt>
  or     %r12,%rbx
  shl    $0x38,%rax
  or     %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long long read8LE(FILE *fp) {
  unsigned long long val;
  val = getc(fp);
  val |= (unsigned long long)getc(fp) << 8;
  val |= (unsigned long long)getc(fp) << 16;
  val |= (unsigned long long)getc(fp) << 24;
  val |= (unsigned long long)getc(fp) << 32;
  val |= (unsigned long long)getc(fp) << 40;
  val |= (unsigned long long)getc(fp) << 48;
  val |= (unsigned long long)getc(fp) << 56;
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D14(%rip),%rax
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D14: a

tool: D0: %c


assistant: ```c
int main(void) {
  char a = "a";
  printf("%c\n", a);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  movsbl %sil,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: string
name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D2: a

tool: D1: %c


assistant: ```c
int main(void) {
  char a = "a";
  printf("%c\n", a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  lea    D15(%rip),%rsi
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D11
type_guessed: string

tool: D15: a

tool: D11: %c


assistant: ```c
int main(void) {
  char a = "a";
  printf("%c\n", a);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  lea    D1(%rip),%rsi
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  movsbl %sil,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D6
type: string

tool: D1: a

tool: D6: %c


assistant: ```c
int main(void) {
  char a = "a";
  printf("%c\n", a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<TYPEOF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    (%r11),%rax
  mov    %rax,(%rsp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TYPEOF() {
  asm volatile("movq (%%r11), %%rax\n\t"
               "movq %%rax, (%%rsp)\n\t" ::
                   :);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<TYPEOF>:
  endbr64
  mov    (%r11),%rax
  mov    %rax,(%rsp)
  ret
```

assistant: ```c
void TYPEOF() {
  asm volatile("movq (%%r11), %%rax\n\t"
               "movq %%rax, (%%rsp)\n\t" ::
                   :);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<TYPEOF>:
  endbr64
  mov    (%r11),%rax
  mov    %rax,(%rsp)
  ret
```

assistant: ```c
void TYPEOF() {
  asm volatile("movq (%%r11), %%rax\n\t"
               "movq %%rax, (%%rsp)\n\t" ::
                   :);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<TYPEOF>:
  endbr64
  mov    (%r11),%rax
  mov    %rax,(%rsp)
  ret
```

assistant: ```c
void TYPEOF() {
  asm volatile("movq (%%r11), %%rax\n\t"
               "movq %%rax, (%%rsp)\n\t" ::
                   :);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<INT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void INT(uint8_t *res, int32_t i) {
  res[0] = (i >> 24) & 0xFF;
  res[1] = (i >> 16) & 0xFF;
  res[2] = (i >> 8) & 0xFF;
  res[3] = i & 0xFF;
}
```
user: What is the c source code of the assembly code below:

```asm
<INT>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  shr    $0x18,%edx
  mov    %edx,(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x8(%rdi)
  and    $0xff,%eax
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void INT(uint8_t *res, int32_t i) {
  res[0] = (i >> 24) & 0xFF;
  res[1] = (i >> 16) & 0xFF;
  res[2] = (i >> 8) & 0xFF;
  res[3] = i & 0xFF;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<INT>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  shr    $0x18,%edx
  mov    %edx,(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rdi)
  movzbl %ah,%edx
  and    $0xff,%eax
  mov    %edx,0x8(%rdi)
  mov    %eax,0xc(%rdi)
  ret
```

assistant: ```c
void INT(uint8_t *res, int32_t i) {
  res[0] = (i >> 24) & 0xFF;
  res[1] = (i >> 16) & 0xFF;
  res[2] = (i >> 8) & 0xFF;
  res[3] = i & 0xFF;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<INT>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%edx
  mov    %esi,%eax
  shr    $0x18,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %dl,%edx
  movzbl %ah,%ecx
  movzbl %sil,%eax
  movd   %ecx,%xmm1
  movd   %eax,%xmm2
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void INT(uint8_t *res, int32_t i) {
  res[0] = (i >> 24) & 0xFF;
  res[1] = (i >> 16) & 0xFF;
  res[2] = (i >> 8) & 0xFF;
  res[3] = i & 0xFF;
}
```
user: Translate the below assembly code into C programming language:

```asm
<SVC_Handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L8:
  jmp    L8
```

assistant: ```c
__attribute__((weak)) void SVC_Handler(void) {
  while (1)
    ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SVC_Handler>:
  endbr64
L6:
  jmp    L6
```

assistant: ```c
__attribute__((weak)) void SVC_Handler(void) {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SVC_Handler>:
  endbr64
  nopl   0x0(%rax)
L8:
  jmp    L8
```

assistant: ```c
__attribute__((weak)) void SVC_Handler(void) {
  while (1)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SVC_Handler>:
  endbr64
  nopl   0x0(%rax)
L4:
  jmp    L4
```

assistant: ```c
__attribute__((weak)) void SVC_Handler(void) {
  while (1)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ProceedWithDirEntry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L37
  mov    -0x30(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
L37:
  mov    $0x0,%eax
  jmp    L38
L18:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  add    $0x1,%eax
  cmp    %eax,-0x34(%rbp)
  jg     L43
  mov    $0x0,%eax
  jmp    L38
L43:
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <MALLOC@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <PCGetFileDirType@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <FREE@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L54
  mov    $0x0,%eax
  jmp    L38
L54:
  mov    $0x1,%eax
L38:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
data_type: string
name: unpack_data
arguments: label: D7
data_type: string

tool: D19: .

tool: D7: ..

assistant: ```c
int ProceedWithDirEntry(const char *dirName, const char *filename, int maxPathLength) {
  int dirLen;
  int fnLen;
  int val;
  char *fullpath;
  dirLen = (int)strlen(dirName);
  fnLen = (int)strlen(filename);
  if ((strcmp(filename, ".") == 0) || (strcmp(filename, "..") == 0)) {
    return 0;
  }
  if ((dirLen + fnLen + 2) > maxPathLength) {
    return 0;
  }
  fullpath = (char *)MALLOC(maxPathLength);
  memcpy(fullpath, dirName, dirLen);
  memcpy(fullpath + dirLen, filename, fnLen);
  fullpath[dirLen + fnLen] = '\0';
  val = PCGetFileDirType(fullpath);
  FREE(fullpath);
  if (val == 0) {
    return 0;
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ProceedWithDirEntry>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbx
  mov    %edx,%r14d
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L3
L29:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  lea    D11(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L29
  mov    %ebp,0xc(%rsp)
  add    %r12d,%ebp
  lea    0x1(%rbp),%edx
  cmp    %r14d,%edx
  jge    L29
  mov    %r14d,%edi
  call   <MALLOC@plt>
  mov    %rax,%r14
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %r12d,%rdi
  add    %r14,%rdi
  mov    0xc(%rsp),%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  movslq %ebp,%rbp
  movb   $0x0,(%r14,%rbp,1)
  mov    %r14,%rdi
  call   <PCGetFileDirType@plt>
  mov    %eax,%ebx
  mov    %r14,%rdi
  call   <FREE@plt>
  test   %ebx,%ebx
  setne  %al
  movzbl %al,%eax
  jmp    L29
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string
name: parse_data
arguments: tag: D11
datatype: string

tool: D8: .

tool: D11: ..

assistant: ```c
int ProceedWithDirEntry(const char *dirName, const char *filename, int maxPathLength) {
  int dirLen;
  int fnLen;
  int val;
  char *fullpath;
  dirLen = (int)strlen(dirName);
  fnLen = (int)strlen(filename);
  if ((strcmp(filename, ".") == 0) || (strcmp(filename, "..") == 0)) {
    return 0;
  }
  if ((dirLen + fnLen + 2) > maxPathLength) {
    return 0;
  }
  fullpath = (char *)MALLOC(maxPathLength);
  memcpy(fullpath, dirName, dirLen);
  memcpy(fullpath + dirLen, filename, fnLen);
  fullpath[dirLen + fnLen] = '\0';
  val = PCGetFileDirType(fullpath);
  FREE(fullpath);
  if (val == 0) {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ProceedWithDirEntry>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L23
L11:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L11
  mov    %ebx,%r15d
  add    %r12d,%ebx
  mov    %r12d,0xc(%rsp)
  lea    0x1(%rbx),%eax
  cmp    %r14d,%eax
  jge    L11
  mov    %r14d,%edi
  movslq %ebx,%rbx
  call   <MALLOC@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  movslq %r12d,%rdi
  mov    %r15d,%edx
  mov    %rbp,%rsi
  add    %r14,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rdi
  call   <PCGetFileDirType@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <FREE@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  setne  %al
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string
name: read_data
arguments: data_tag: D4
data_type: string

tool: D2: .

tool: D4: ..

assistant: ```c
int ProceedWithDirEntry(const char *dirName, const char *filename, int maxPathLength) {
  int dirLen;
  int fnLen;
  int val;
  char *fullpath;
  dirLen = (int)strlen(dirName);
  fnLen = (int)strlen(filename);
  if ((strcmp(filename, ".") == 0) || (strcmp(filename, "..") == 0)) {
    return 0;
  }
  if ((dirLen + fnLen + 2) > maxPathLength) {
    return 0;
  }
  fullpath = (char *)MALLOC(maxPathLength);
  memcpy(fullpath, dirName, dirLen);
  memcpy(fullpath + dirLen, filename, fnLen);
  fullpath[dirLen + fnLen] = '\0';
  val = PCGetFileDirType(fullpath);
  FREE(fullpath);
  if (val == 0) {
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ProceedWithDirEntry>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
L9:
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  lea    D6(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    %ebx,%r15d
  add    %r12d,%ebx
  mov    %r12d,0xc(%rsp)
  lea    0x1(%rbx),%eax
  cmp    %r14d,%eax
  jge    L9
  mov    %r14d,%edi
  movslq %ebx,%rbx
  call   <MALLOC@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <memcpy@plt>
  movslq %r12d,%rdi
  mov    %r15d,%edx
  mov    %rbp,%rsi
  add    %r14,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r14,%rdi
  call   <PCGetFileDirType@plt>
  mov    %r14,%rdi
  mov    %eax,%ebx
  call   <FREE@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  setne  %al
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D16: .

tool: D6: ..

assistant: ```c
int ProceedWithDirEntry(const char *dirName, const char *filename, int maxPathLength) {
  int dirLen;
  int fnLen;
  int val;
  char *fullpath;
  dirLen = (int)strlen(dirName);
  fnLen = (int)strlen(filename);
  if ((strcmp(filename, ".") == 0) || (strcmp(filename, "..") == 0)) {
    return 0;
  }
  if ((dirLen + fnLen + 2) > maxPathLength) {
    return 0;
  }
  fullpath = (char *)MALLOC(maxPathLength);
  memcpy(fullpath, dirName, dirLen);
  memcpy(fullpath + dirLen, filename, fnLen);
  fullpath[dirLen + fnLen] = '\0';
  val = PCGetFileDirType(fullpath);
  FREE(fullpath);
  if (val == 0) {
    return 0;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rk31sdk_get_sdmmc0_pin_io_voltage>:
  endbr64
  mov    $0xce4,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdmmc0_pin_io_voltage(void) {
  int voltage;
  voltage = 3300;
  return voltage;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %r9d,-0x34(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L58
L44:
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L18:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L30
L39:
  mov    -0x28(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x34(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jb     L39
  mov    -0x34(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jb     L18
  addl   $0x1,-0x8(%rbp)
L58:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L44
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *mul(float *__restrict dst, const float *const __restrict lhs, const unsigned nrows_lhs, const unsigned ncols_lhs, const float *const __restrict rhs, const unsigned ncols_rhs) {
  unsigned i, j, k;
  for (k = 0; k < nrows_lhs; ++k) {
    for (j = 0; j < ncols_rhs; ++j) {
      float s = 0.0f;
      for (i = 0; i < ncols_lhs; ++i) {
        s += lhs[ncols_lhs * k + i] * rhs[ncols_rhs * i + j];
      }
      dst[ncols_rhs * k + j] = s;
    }
  }
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<mul>:
  endbr64
  mov    %rdi,%r11
  test   %edx,%edx
  je     L14
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %edx,%ebp
  mov    %ecx,%ebx
  mov    %r9d,%esi
  mov    %ecx,%edi
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%r14d
  jmp    L84
L75:
  mov    %r9d,%edx
  mov    %r13d,%eax
  pxor   %xmm1,%xmm1
L47:
  mov    %eax,%r15d
  mov    %edx,%ecx
  movss  (%r10,%r15,4),%xmm0
  mulss  (%r8,%rcx,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%eax
  add    %esi,%edx
  cmp    %edi,%eax
  jne    L47
L13:
  lea    (%r12,%r9,1),%eax
  movss  %xmm1,(%r11,%rax,4)
  add    $0x1,%r9d
  cmp    %r9d,%esi
  je     L66
L39:
  pxor   %xmm1,%xmm1
  test   %ebx,%ebx
  jne    L75
  jmp    L13
L66:
  add    $0x1,%r14d
  add    %esi,%r12d
  add    %ebx,%r13d
  add    %ebx,%edi
  cmp    %r14d,%ebp
  je     L78
L84:
  mov    $0x0,%r9d
  test   %esi,%esi
  jne    L39
  jmp    L66
L78:
  mov    %r11,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  mov    %rdi,%rax
  ret
```

assistant: ```c
float *mul(float *__restrict dst, const float *const __restrict lhs, const unsigned nrows_lhs, const unsigned ncols_lhs, const float *const __restrict rhs, const unsigned ncols_rhs) {
  unsigned i, j, k;
  for (k = 0; k < nrows_lhs; ++k) {
    for (j = 0; j < ncols_rhs; ++j) {
      float s = 0.0f;
      for (i = 0; i < ncols_lhs; ++i) {
        s += lhs[ncols_lhs * k + i] * rhs[ncols_rhs * i + j];
      }
      dst[ncols_rhs * k + j] = s;
    }
  }
  return dst;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mul>:
  endbr64
  mov    %rdi,%r11
  test   %edx,%edx
  je     L7
  push   %r15
  mov    %rsi,%r10
  mov    %ecx,%edi
  mov    %r9d,%esi
  push   %r14
  pxor   %xmm2,%xmm2
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %ecx,%ebx
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %r9d,%r9d
  test   %esi,%esi
  je     L16
  nop
L10:
  mov    %r9d,%edx
  mov    %r13d,%eax
  movaps %xmm2,%xmm1
  test   %ebx,%ebx
  je     L35
  nopl   (%rax)
L31:
  mov    %eax,%r15d
  mov    %edx,%ecx
  add    $0x1,%eax
  add    %esi,%edx
  movss  (%r10,%r15,4),%xmm0
  mulss  (%r8,%rcx,4),%xmm0
  addss  %xmm0,%xmm1
  cmp    %edi,%eax
  jne    L31
L35:
  lea    (%r9,%r12,1),%eax
  add    $0x1,%r9d
  movss  %xmm1,(%r11,%rax,4)
  cmp    %r9d,%esi
  jne    L10
L16:
  add    $0x1,%r14d
  add    %esi,%r12d
  add    %ebx,%r13d
  add    %ebx,%edi
  cmp    %r14d,%ebp
  jne    L47
  pop    %rbx
  mov    %r11,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  mov    %rdi,%rax
  ret
```

assistant: ```c
float *mul(float *__restrict dst, const float *const __restrict lhs, const unsigned nrows_lhs, const unsigned ncols_lhs, const float *const __restrict rhs, const unsigned ncols_rhs) {
  unsigned i, j, k;
  for (k = 0; k < nrows_lhs; ++k) {
    for (j = 0; j < ncols_rhs; ++j) {
      float s = 0.0f;
      for (i = 0; i < ncols_lhs; ++i) {
        s += lhs[ncols_lhs * k + i] * rhs[ncols_rhs * i + j];
      }
      dst[ncols_rhs * k + j] = s;
    }
  }
  return dst;
}
```