ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<nis_leaf_of_r>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movb   $0x0,(%rsi)
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L62
  test   %al,%al
  je     L62
  mov    $0x0,%ebx
L46:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  je     L2
  test   %al,%al
  jne    L46
L2:
  cmp    %rbx,%rdx
  setbe  %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L9
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <__mempcpy@plt>
  movb   $0x0,(%rax)
  mov    %r12,%rax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L62:
  mov    $0x0,%ebx
  jmp    L2
L9:
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0x0,%eax
  jmp    L26
```

assistant: ```c
nis_name nis_leaf_of_r(const_nis_name name, char *buffer, size_t buflen) {
  size_t i = 0;
  buffer[0] = '\0';
  while (name[i] != '.' && name[i] != '\0')
    i++;
  if (__builtin_expect(i >= buflen, 0)) {
    __set_errno(ERANGE);
    return NULL;
  }
  *((char *)__mempcpy(buffer, name, i)) = '\0';
  return buffer;
}
```
user: What is the c source code of the assembly code below?

```asm
<nis_leaf_of_r>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  movb   $0x0,(%rsi)
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L3
  test   %al,%al
  je     L3
  nop
L18:
  add    $0x1,%r12
  movzbl 0x0(%rbp,%r12,1),%ecx
  cmp    $0x2e,%cl
  je     L3
  test   %cl,%cl
  jne    L18
L3:
  xor    %edi,%edi
  cmp    %r12,%rdx
  setbe  %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L17
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__mempcpy@plt>
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
nis_name nis_leaf_of_r(const_nis_name name, char *buffer, size_t buflen) {
  size_t i = 0;
  buffer[0] = '\0';
  while (name[i] != '.' && name[i] != '\0')
    i++;
  if (__builtin_expect(i >= buflen, 0)) {
    __set_errno(ERANGE);
    return NULL;
  }
  *((char *)__mempcpy(buffer, name, i)) = '\0';
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nis_leaf_of_r>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  movb   $0x0,(%rsi)
  movzbl (%rdi),%eax
  cmp    $0x2e,%al
  je     L0
  test   %al,%al
  je     L0
  nop
L23:
  add    $0x1,%r12
  movzbl 0x0(%rbp,%r12,1),%ecx
  cmp    $0x2e,%cl
  je     L0
  test   %cl,%cl
  jne    L23
L0:
  xor    %edi,%edi
  cmp    %r12,%rdx
  setbe  %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L49
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__mempcpy@plt>
  movb   $0x0,(%rax)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L49:
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
nis_name nis_leaf_of_r(const_nis_name name, char *buffer, size_t buflen) {
  size_t i = 0;
  buffer[0] = '\0';
  while (name[i] != '.' && name[i] != '\0')
    i++;
  if (__builtin_expect(i >= buflen, 0)) {
    __set_errno(ERANGE);
    return NULL;
  }
  *((char *)__mempcpy(buffer, name, i)) = '\0';
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  or     -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  or     -0x4(%rbp),%eax
  add    %eax,%eax
  or     %edx,%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D26
type_guessed: string
name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D33
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string

tool: D26: Valor de x0 | x2: %d


tool: D13: Valor de x1 | x2: %d


tool: D33: Valor de x1 | x2 << 1: %d


tool: D17: Valor de (x0 | x2) | (x1 | x2) << 1: %d


assistant: ```c
int main(void) {
  int x0 = 0, x1 = 0, x2 = 1;
  printf("Valor de x0 | x2: %d\n", x0 | x2);
  printf("Valor de x1 | x2: %d\n", x1 | x2);
  printf("Valor de x1 | x2 << 1: %d\n", x1 | x2 << 1);
  printf("Valor de (x0 | x2) | (x1 | x2) << 1: %d\n", (x0 | x2) | (x1 | x2) << 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
type: string
name: disassemble_data
arguments: label: D14
type: string
name: disassemble_data
arguments: label: D13
type: string
name: disassemble_data
arguments: label: D8
type: string

tool: D24: Valor de x0 | x2: %d


tool: D14: Valor de x1 | x2: %d


tool: D13: Valor de x1 | x2 << 1: %d


tool: D8: Valor de (x0 | x2) | (x1 | x2) << 1: %d


assistant: ```c
int main(void) {
  int x0 = 0, x1 = 0, x2 = 1;
  printf("Valor de x0 | x2: %d\n", x0 | x2);
  printf("Valor de x1 | x2: %d\n", x1 | x2);
  printf("Valor de x1 | x2 << 1: %d\n", x1 | x2 << 1);
  printf("Valor de (x0 | x2) | (x1 | x2) << 1: %d\n", (x0 | x2) | (x1 | x2) << 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string
name: retrieve_data
arguments: data_tag: D39
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D15: Valor de x0 | x2: %d


tool: D19: Valor de x1 | x2: %d


tool: D39: Valor de x1 | x2 << 1: %d


tool: D2: Valor de (x0 | x2) | (x1 | x2) << 1: %d


assistant: ```c
int main(void) {
  int x0 = 0, x1 = 0, x2 = 1;
  printf("Valor de x0 | x2: %d\n", x0 | x2);
  printf("Valor de x1 | x2: %d\n", x1 | x2);
  printf("Valor de x1 | x2 << 1: %d\n", x1 | x2 << 1);
  printf("Valor de (x0 | x2) | (x1 | x2) << 1: %d\n", (x0 | x2) | (x1 | x2) << 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    $0x3,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D26
datatype: string
name: parse_data
arguments: label: D35
datatype: string

tool: D6: Valor de x0 | x2: %d


tool: D8: Valor de x1 | x2: %d


tool: D26: Valor de x1 | x2 << 1: %d


tool: D35: Valor de (x0 | x2) | (x1 | x2) << 1: %d


assistant: ```c
int main(void) {
  int x0 = 0, x1 = 0, x2 = 1;
  printf("Valor de x0 | x2: %d\n", x0 | x2);
  printf("Valor de x1 | x2: %d\n", x1 | x2);
  printf("Valor de x1 | x2 << 1: %d\n", x1 | x2 << 1);
  printf("Valor de (x0 | x2) | (x1 | x2) << 1: %d\n", (x0 | x2) | (x1 | x2) << 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rdx,0x18(%rsp)
  mov    %ecx,%ebp
  mov    %r8d,0xc(%rsp)
  movl   $0x0,(%rdx)
  call   <strlen@plt>
  mov    %eax,%r13d
  lea    -0x1(%r14),%rbx
  mov    $0x0,%r12d
  jmp    L86
L52:
  add    $0x1,%r12d
L86:
  lea    0x1(%rbx),%rdi
  mov    %r15,%rsi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L52
  or     %r12d,%r13d
  je     L124
  add    $0x1,%r12d
  cmp    %ebp,%r12d
  cmovg  %ebp,%r12d
  lea    0x0(,%r12,8),%edi
  call   <xmalloc@plt>
  mov    %rax,%rbx
  test   %r12d,%r12d
  jle    L99
  mov    $0x0,%r13d
  jmp    L48
L9:
  sub    $0x1,%r13d
  sub    $0x1,%r12d
L128:
  test   %rbp,%rbp
  je     L50
  lea    0x1(%rbp),%r14
  add    $0x1,%r13d
  cmp    %r13d,%r12d
  jle    L21
L48:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L19
  movb   $0x0,(%rax)
L19:
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    0xc(%rsp),%eax
  jg     L9
  test   %eax,%eax
  jle    L9
  movslq %r13d,%rax
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x10(%rsp)
  mov    %r14,%rdi
  call   <xstrdup@plt>
  mov    0x10(%rsp),%rcx
  mov    %rax,(%rcx)
  jmp    L128
L50:
  add    $0x1,%r13d
L21:
  cmp    %r12d,%r13d
  jne    L44
L25:
  mov    0x18(%rsp),%rax
  mov    %r12d,(%rax)
L124:
  mov    %rbx,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L99:
  mov    $0x0,%r13d
  jmp    L21
L44:
  lea    0x0(,%r13,8),%esi
  mov    %rbx,%rdi
  call   <xrealloc@plt>
  mov    %rax,%rbx
  jmp    L25
```

assistant: ```c
char **split_string(char *str, const char *div_str, int *substrings, int max_substrings, int max_substring_sz) {
  int i = 0, strings = 0, str_len = 0, buf_len;
  char *buf, **splitted = 0, *p;
  *substrings = 0;
  str_len = strlen(str);
  buf = str - 1;
  while ((buf = strstr((const char *)buf + 1, div_str)))
    strings++;
  if (!strings && !str_len)
    return 0;
  strings++;
  if (strings > max_substrings)
    strings = max_substrings;
  splitted = (char **)xmalloc(sizeof(char *) * strings);
  buf = str;
  for (i = 0; i < strings; i++) {
    p = strstr((const char *)buf, div_str);
    if (p)
      *p = 0;
    buf_len = strlen(buf);
    if (buf_len <= max_substring_sz && buf_len > 0)
      splitted[i] = xstrdup(buf);
    else {
      i--;
      strings--;
      buf = p + 1;
    }
    if (!p) {
      i++;
      break;
    }
    buf = p + 1;
  }
  if (i != strings)
    splitted = (char **)xrealloc(splitted, sizeof(char *) * i);
  *substrings = strings;
  return splitted;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<split_string>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    -0x1(%rbp),%r14
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  movl   $0x0,(%rdx)
  mov    %rdx,0x18(%rsp)
  mov    %r8d,0xc(%rsp)
  call   <strlen@plt>
  mov    %eax,%r13d
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebx
L60:
  lea    0x1(%r14),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L17
  mov    %r13d,%eax
  or     %ebx,%eax
  je     L97
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  cmovg  %r15d,%ebx
  xor    %r15d,%r15d
  lea    0x0(,%rbx,8),%edi
  call   <xmalloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jg     L108
  jmp    L103
  nopl   0x0(%rax)
L50:
  test   %eax,%eax
  jle    L0
  movslq %r15d,%rax
  mov    %rbp,%rdi
  add    $0x1,%r15d
  lea    (%r14,%rax,8),%rcx
  mov    %rcx,0x10(%rsp)
  call   <xstrdup@plt>
  mov    0x10(%rsp),%rcx
  mov    %rax,(%rcx)
  test   %r13,%r13
  je     L103
L72:
  lea    0x1(%r13),%rbp
  cmp    %r15d,%ebx
  jle    L103
L108:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L112
  movb   $0x0,(%rax)
L112:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    0xc(%rsp),%eax
  jle    L50
L0:
  sub    $0x1,%ebx
  test   %r13,%r13
  jne    L72
L103:
  cmp    %ebx,%r15d
  jne    L110
  mov    0x18(%rsp),%rax
  mov    %ebx,(%rax)
L97:
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L110:
  mov    %r14,%rdi
  lea    0x0(,%r15,8),%esi
  call   <xrealloc@plt>
  mov    %rax,%r14
  mov    0x18(%rsp),%rax
  mov    %ebx,(%rax)
  jmp    L97
```

assistant: ```c
char **split_string(char *str, const char *div_str, int *substrings, int max_substrings, int max_substring_sz) {
  int i = 0, strings = 0, str_len = 0, buf_len;
  char *buf, **splitted = 0, *p;
  *substrings = 0;
  str_len = strlen(str);
  buf = str - 1;
  while ((buf = strstr((const char *)buf + 1, div_str)))
    strings++;
  if (!strings && !str_len)
    return 0;
  strings++;
  if (strings > max_substrings)
    strings = max_substrings;
  splitted = (char **)xmalloc(sizeof(char *) * strings);
  buf = str;
  for (i = 0; i < strings; i++) {
    p = strstr((const char *)buf, div_str);
    if (p)
      *p = 0;
    buf_len = strlen(buf);
    if (buf_len <= max_substring_sz && buf_len > 0)
      splitted[i] = xstrdup(buf);
    else {
      i--;
      strings--;
      buf = p + 1;
    }
    if (!p) {
      i++;
      break;
    }
    buf = p + 1;
  }
  if (i != strings)
    splitted = (char **)xrealloc(splitted, sizeof(char *) * i);
  *substrings = strings;
  return splitted;
}
```
user: What is the c source code of the assembly code below?

```asm
<split_string>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    -0x1(%rbp),%r14
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  movl   $0x0,(%rdx)
  mov    %rdx,0x18(%rsp)
  mov    %r8d,0xc(%rsp)
  call   <strlen@plt>
  mov    %eax,%r13d
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L93:
  add    $0x1,%ebx
L11:
  lea    0x1(%r14),%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L93
  mov    %r13d,%eax
  or     %ebx,%eax
  je     L91
  add    $0x1,%ebx
  cmp    %r15d,%ebx
  cmovg  %r15d,%ebx
  xor    %r15d,%r15d
  lea    0x0(,%rbx,8),%edi
  call   <xmalloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jg     L22
  jmp    L126
  nopl   0x0(%rax)
L67:
  test   %eax,%eax
  jle    L1
  movslq %r15d,%rax
  mov    %rbp,%rdi
  add    $0x1,%r15d
  lea    (%r14,%rax,8),%rcx
  mov    %rcx,0x10(%rsp)
  call   <xstrdup@plt>
  mov    0x10(%rsp),%rcx
  mov    %rax,(%rcx)
  test   %r13,%r13
  je     L126
L74:
  lea    0x1(%r13),%rbp
  cmp    %r15d,%ebx
  jle    L126
L22:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L83
  movb   $0x0,(%rax)
L83:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    0xc(%rsp),%eax
  jle    L67
L1:
  sub    $0x1,%ebx
  test   %r13,%r13
  jne    L74
L126:
  cmp    %ebx,%r15d
  jne    L20
  mov    0x18(%rsp),%rax
  mov    %ebx,(%rax)
L91:
  add    $0x28,%rsp
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L20:
  mov    %r14,%rdi
  lea    0x0(,%r15,8),%esi
  call   <xrealloc@plt>
  mov    %rax,%r14
  mov    0x18(%rsp),%rax
  mov    %ebx,(%rax)
  jmp    L91
```

assistant: ```c
char **split_string(char *str, const char *div_str, int *substrings, int max_substrings, int max_substring_sz) {
  int i = 0, strings = 0, str_len = 0, buf_len;
  char *buf, **splitted = 0, *p;
  *substrings = 0;
  str_len = strlen(str);
  buf = str - 1;
  while ((buf = strstr((const char *)buf + 1, div_str)))
    strings++;
  if (!strings && !str_len)
    return 0;
  strings++;
  if (strings > max_substrings)
    strings = max_substrings;
  splitted = (char **)xmalloc(sizeof(char *) * strings);
  buf = str;
  for (i = 0; i < strings; i++) {
    p = strstr((const char *)buf, div_str);
    if (p)
      *p = 0;
    buf_len = strlen(buf);
    if (buf_len <= max_substring_sz && buf_len > 0)
      splitted[i] = xstrdup(buf);
    else {
      i--;
      strings--;
      buf = p + 1;
    }
    if (!p) {
      i++;
      break;
    }
    buf = p + 1;
  }
  if (i != strings)
    splitted = (char **)xrealloc(splitted, sizeof(char *) * i);
  *substrings = strings;
  return splitted;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<udp_send>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <parse@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L44
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  jmp    L19
L44:
  lea    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x4,%r9d
  mov    %rcx,%r8
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <sendto@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L39
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0xfffffffd,%eax
  jmp    L19
L39:
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string

tool: D1: Error parsing url '%s'


tool: D8: send error

assistant: ```c
int udp_send(int udpsocket, char *msg, int msglen, char *announce) {
  struct sockaddr_in sa;
  int err;
  err = parse(announce, &sa);
  if (err) {
    printf("Error parsing url '%s'\n", announce);
    return err;
  }
  err = sendto(udpsocket, msg, msglen, 0, (struct sockaddr *)&sa, sizeof(sa));
  if (err == -1) {
    perror("send error");
    return -3;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<udp_send>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rcx,%rdi
  call   <parse@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L35
  mov    $0x4,%r9d
  lea    0x4(%rsp),%r8
  mov    $0x0,%ecx
  mov    %r14d,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L2
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L22
L2:
  lea    D3(%rip),%rdi
  call   <perror@plt>
  mov    $0xfffffffd,%ebx
  jmp    L22
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
data_type: string
name: unpack_data
arguments: data_tag: D3
data_type: string

tool: D15: Error parsing url '%s'


tool: D3: send error

assistant: ```c
int udp_send(int udpsocket, char *msg, int msglen, char *announce) {
  struct sockaddr_in sa;
  int err;
  err = parse(announce, &sa);
  if (err) {
    printf("Error parsing url '%s'\n", announce);
    return err;
  }
  err = sendto(udpsocket, msg, msglen, 0, (struct sockaddr *)&sa, sizeof(sa));
  if (err == -1) {
    perror("send error");
    return -3;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<udp_send>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  mov    %rcx,%rdi
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <parse@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L46
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %rbx,%r8
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L31
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L46:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L1
L31:
  lea    D4(%rip),%rdi
  mov    $0xfffffffd,%r12d
  call   <perror@plt>
  jmp    L1
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string
name: parse_data
arguments: label: D4
type_guessed: string

tool: D7: Error parsing url '%s'


tool: D4: send error

assistant: ```c
int udp_send(int udpsocket, char *msg, int msglen, char *announce) {
  struct sockaddr_in sa;
  int err;
  err = parse(announce, &sa);
  if (err) {
    printf("Error parsing url '%s'\n", announce);
    return err;
  }
  err = sendto(udpsocket, msg, msglen, 0, (struct sockaddr *)&sa, sizeof(sa));
  if (err == -1) {
    perror("send error");
    return -3;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<udp_send>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %edi,%r13d
  mov    %rcx,%rdi
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  call   <parse@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L2
  xor    %ecx,%ecx
  mov    $0x4,%r9d
  mov    %rbx,%r8
  mov    %r15d,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  call   <sendto@plt>
  cmp    $0xffffffff,%eax
  je     L28
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L2:
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L28:
  lea    D2(%rip),%rdi
  mov    $0xfffffffd,%r12d
  call   <perror@plt>
  jmp    L39
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D11: Error parsing url '%s'


tool: D2: send error

assistant: ```c
int udp_send(int udpsocket, char *msg, int msglen, char *announce) {
  struct sockaddr_in sa;
  int err;
  err = parse(announce, &sa);
  if (err) {
    printf("Error parsing url '%s'\n", announce);
    return err;
  }
  err = sendto(udpsocket, msg, msglen, 0, (struct sockaddr *)&sa, sizeof(sa));
  if (err == -1) {
    perror("send error");
    return -3;
  }
  return 0;
}
```