ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<softboundmpx_calloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  imul   %rbp,%rbx
  mov    %rax,%rdi
  lea    (%rax,%rbx,1),%rsi
  call   <__softboundmpx_store_return_metadata@plt>
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  xor    %eax,%eax
  call   <__softboundmpx_store_null_return_metadata@plt>
  jmp    L1
```

assistant: ```c
__attribute__((__weak__, __always___)) void *softboundmpx_calloc(size_t nmemb, size_t size) {
  void *ret_ptr = calloc(nmemb, size);
  if (ret_ptr != NULL) {
    __softboundmpx_store_return_metadata(ret_ptr, ((char *)(ret_ptr) + (nmemb * size)));
  } else {
    __softboundmpx_store_null_return_metadata();
  }
  return ret_ptr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rax,-0x20(%rbp)
  movl   $0x1f,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  sarl   -0x14(%rbp)
  subl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x0,-0x4(%rbp)
  jns    L10
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *int2bin(int a, char *buffer, int buf_size) {
  buffer += (buf_size - 1);
  for (int i = 31; i >= 0; i--) {
    *buffer-- = (a & 1) + '0';
    a >>= 1;
  }
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<int2bin>:
  endbr64
  movslq %edx,%rdx
  lea    -0x1(%rdx,%rsi,1),%rax
  lea    -0x20(%rax),%rcx
L3:
  sub    $0x1,%rax
  mov    %edi,%edx
  and    $0x1,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  sar    %edi
  cmp    %rax,%rcx
  jne    L3
  mov    %rcx,%rax
  ret
```

assistant: ```c
char *int2bin(int a, char *buffer, int buf_size) {
  buffer += (buf_size - 1);
  for (int i = 31; i >= 0; i--) {
    *buffer-- = (a & 1) + '0';
    a >>= 1;
  }
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<int2bin>:
  endbr64
  movslq %edx,%rdx
  lea    -0x1(%rdx,%rsi,1),%rax
  lea    -0x20(%rax),%r8
L7:
  mov    %edi,%edx
  sub    $0x1,%rax
  sar    %edi
  and    $0x1,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  cmp    %rax,%r8
  jne    L7
  mov    %r8,%rax
  ret
```

assistant: ```c
char *int2bin(int a, char *buffer, int buf_size) {
  buffer += (buf_size - 1);
  for (int i = 31; i >= 0; i--) {
    *buffer-- = (a & 1) + '0';
    a >>= 1;
  }
  return buffer;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<int2bin>:
  endbr64
  movslq %edx,%rdx
  lea    -0x1(%rdx,%rsi,1),%rax
  lea    -0x20(%rax),%rcx
L2:
  mov    %edi,%edx
  sub    $0x1,%rax
  sar    %edi
  and    $0x1,%edx
  add    $0x30,%edx
  mov    %dl,0x1(%rax)
  cmp    %rcx,%rax
  jne    L2
  ret
```

assistant: ```c
char *int2bin(int a, char *buffer, int buf_size) {
  buffer += (buf_size - 1);
  for (int i = 31; i >= 0; i--) {
    *buffer-- = (a & 1) + '0';
    a >>= 1;
  }
  return buffer;
}
```
user: What is the c source code of the assembly code below:

```asm
<hash_plugin_detailed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string

tool: D7: sha256 - A simple sha256 plugin
------------------------
Use this module to crack simple sha256 hashes
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Zikula 1.02, Snitz Forums 2000

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("sha256 - A simple sha256 plugin\n"
          "------------------------\n"
          "Use this module to crack simple sha256 hashes\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Zikula 1.02, Snitz Forums 2000\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D8(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: sha256 - A simple sha256 plugin
------------------------
Use this module to crack simple sha256 hashes
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Zikula 1.02, Snitz Forums 2000

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("sha256 - A simple sha256 plugin\n"
          "------------------------\n"
          "Use this module to crack simple sha256 hashes\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Zikula 1.02, Snitz Forums 2000\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
datatype: string

tool: D3: sha256 - A simple sha256 plugin
------------------------
Use this module to crack simple sha256 hashes
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Zikula 1.02, Snitz Forums 2000

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("sha256 - A simple sha256 plugin\n"
          "------------------------\n"
          "Use this module to crack simple sha256 hashes\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Zikula 1.02, Snitz Forums 2000\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hash_plugin_detailed>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: sha256 - A simple sha256 plugin
------------------------
Use this module to crack simple sha256 hashes
Input should be in form: 'user:hash' or just 'hash'
Known software that uses this password hashing method:
Zikula 1.02, Snitz Forums 2000

Author: Milen Rangelov <gat3way@gat3way.eu>


assistant: ```c
char *hash_plugin_detailed(void) {
  return ("sha256 - A simple sha256 plugin\n"
          "------------------------\n"
          "Use this module to crack simple sha256 hashes\n"
          "Input should be in form: \'user:hash\' or just \'hash\'\n"
          "Known software that uses this password hashing method:\n"
          "Zikula 1.02, Snitz Forums 2000\n"
          "\nAuthor: Milen Rangelov <gat3way@gat3way.eu>\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<free_pimatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_pimatrix(int **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: What is the c source code of the assembly code below:

```asm
<free_pimatrix>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_pimatrix(int **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<free_pimatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_pimatrix(int **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: What is the c source code of the assembly code below:

```asm
<free_pimatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_pimatrix(int **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigterm_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <terminate@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void sigterm_handler(int sig) {
  terminate();
  exit(2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sigterm_handler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <terminate@plt>
  mov    $0x2,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void sigterm_handler(int sig) {
  terminate();
  exit(2);
}
```
user: What is the c source code of the assembly code below?

```asm
<sigterm_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <terminate@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sigterm_handler(int sig) {
  terminate();
  exit(2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sigterm_handler>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <terminate@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void sigterm_handler(int sig) {
  terminate();
  exit(2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<index_to_uint64_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L7:
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <pop_1st_bit@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L1
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  or     %rax,-0x8(%rbp)
L1:
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint64_t index_to_uint64_t(int index, int bits, uint64_t m) {
  int i, j, k;
  uint64_t result = 0ULL;
  for (i = 0; i < bits; i++) {
    j = pop_1st_bit(&m);
    if (index & (1 << i))
      result |= (1ULL << j);
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<index_to_uint64_t>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  jle    L4
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  lea    0x8(%rsp),%r14
  jmp    L47
L41:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L17
L47:
  mov    %r14,%rdi
  call   <pop_1st_bit@plt>
  bt     %ebx,%r12d
  jae    L41
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  or     %rdx,%r13
  jmp    L41
L4:
  mov    $0x0,%r13d
L17:
  mov    %r13,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
uint64_t index_to_uint64_t(int index, int bits, uint64_t m) {
  int i, j, k;
  uint64_t result = 0ULL;
  for (i = 0; i < bits; i++) {
    j = pop_1st_bit(&m);
    if (index & (1 << i))
      result |= (1ULL << j);
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<index_to_uint64_t>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  jle    L36
  mov    %edi,%r12d
  mov    %esi,%ebp
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  lea    0x8(%rsp),%r14
  mov    $0x1,%r15d
L35:
  mov    %r14,%rdi
  call   <pop_1st_bit@plt>
  bt     %ebx,%r12d
  jae    L2
  mov    %r15,%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  or     %rdx,%r13
L2:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L35
L39:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %r13d,%r13d
  jmp    L39
```

assistant: ```c
uint64_t index_to_uint64_t(int index, int bits, uint64_t m) {
  int i, j, k;
  uint64_t result = 0ULL;
  for (i = 0; i < bits; i++) {
    j = pop_1st_bit(&m);
    if (index & (1 << i))
      result |= (1ULL << j);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<index_to_uint64_t>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  test   %esi,%esi
  jle    L16
  mov    %edi,%r12d
  mov    %esi,%ebp
  xor    %r13d,%r13d
  xor    %ebx,%ebx
  lea    0x8(%rsp),%r14
  mov    $0x1,%r15d
L29:
  mov    %r14,%rdi
  call   <pop_1st_bit@plt>
  bt     %ebx,%r12d
  jae    L37
  mov    %r15,%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  or     %rdx,%r13
L37:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L29
L36:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r13d,%r13d
  jmp    L36
```

assistant: ```c
uint64_t index_to_uint64_t(int index, int bits, uint64_t m) {
  int i, j, k;
  uint64_t result = 0ULL;
  for (i = 0; i < bits; i++) {
    j = pop_1st_bit(&m);
    if (index & (1 << i))
      result |= (1ULL << j);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ht_get_head_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L5
L13:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x6,%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  shl    $0x10,%rax
  add    %rdx,%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L13
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int ht_get_head_num(char *key, unsigned int max_size) {
  unsigned long int hash = 0;
  int c;
  while ((c = *key++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash % max_size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ht_get_head_num>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L16
  mov    $0x0,%eax
L15:
  imul   $0x1003f,%rax,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L15
L27:
  mov    %esi,%esi
  mov    $0x0,%edx
  div    %rsi
  mov    %edx,%eax
  ret
L16:
  mov    $0x0,%eax
  jmp    L27
```

assistant: ```c
unsigned int ht_get_head_num(char *key, unsigned int max_size) {
  unsigned long int hash = 0;
  int c;
  while ((c = *key++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash % max_size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ht_get_head_num>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    %esi,%esi
  test   %dl,%dl
  je     L1
  xor    %eax,%eax
  nopl   0x0(%rax)
L12:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L12
  xor    %edx,%edx
  div    %rsi
  mov    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int ht_get_head_num(char *key, unsigned int max_size) {
  unsigned long int hash = 0;
  int c;
  while ((c = *key++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash % max_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ht_get_head_num>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    %esi,%esi
  test   %dl,%dl
  je     L1
  xor    %eax,%eax
  nopl   0x0(%rax)
L7:
  imul   $0x1003f,%rax,%rax
  add    $0x1,%rcx
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L7
  xor    %edx,%edx
  div    %rsi
  mov    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int ht_get_head_num(char *key, unsigned int max_size) {
  unsigned long int hash = 0;
  int c;
  while ((c = *key++))
    hash = c + (hash << 6) + (hash << 16) - hash;
  return hash % max_size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L8
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo2(distance, i, j)
int distance;
int i, j;
{
  int t = distance;
  if (t <= 0)
    t = ((t) >= 0 ? (t) : -(t));
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<foo2>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  neg    %edx
  cmovs  %edi,%edx
  test   %edi,%edi
  cmovle %edx,%eax
  ret
```

assistant: ```c
int foo2(distance, i, j)
int distance;
int i, j;
{
  int t = distance;
  if (t <= 0)
    t = ((t) >= 0 ? (t) : -(t));
  return t;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<foo2>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  ret
```

assistant: ```c
int foo2(distance, i, j)
int distance;
int i, j;
{
  int t = distance;
  if (t <= 0)
    t = ((t) >= 0 ? (t) : -(t));
  return t;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<delay>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  jmp    L19
L15:
  nop
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jg     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void delay(int nops) {
  while (nops > 0) {
    asm("nop");
    nops--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<delay>:
  endbr64
  test   %edi,%edi
  jle    L7
L4:
  nop
  sub    $0x1,%edi
  jne    L4
L7:
  ret
```

assistant: ```c
void delay(int nops) {
  while (nops > 0) {
    asm("nop");
    nops--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<delay>:
  endbr64
  test   %edi,%edi
  jle    L10
  nopl   0x0(%rax,%rax,1)
L1:
  nop
  sub    $0x1,%edi
  jne    L1
L10:
  ret
```

assistant: ```c
void delay(int nops) {
  while (nops > 0) {
    asm("nop");
    nops--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<delay>:
  endbr64
  test   %edi,%edi
  jle    L18
  nopl   0x0(%rax,%rax,1)
L3:
  nop
  sub    $0x1,%edi
  jne    L3
L18:
  ret
```

assistant: ```c
void delay(int nops) {
  while (nops > 0) {
    asm("nop");
    nops--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list ap;
  va_start(ap, errstr);
  vfprintf(stderr, errstr, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list ap;
  va_start(ap, errstr);
  vfprintf(stderr, errstr, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list ap;
  va_start(ap, errstr);
  vfprintf(stderr, errstr, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D19(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(const char *errstr, ...) {
  va_list ap;
  va_start(ap, errstr);
  vfprintf(stderr, errstr, ap);
  va_end(ap);
  exit(EXIT_FAILURE);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<populate_array_seq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
  mov    %eax,(%rcx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void populate_array_seq(int *v, int n) {
  for (int i = 0; i < n; ++i) {
    v[i] = rand() % n;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<populate_array_seq>:
  endbr64
  test   %esi,%esi
  jle    L4
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  ret
```

assistant: ```c
void populate_array_seq(int *v, int n) {
  for (int i = 0; i < n; ++i) {
    v[i] = rand() % n;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<populate_array_seq>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <rand@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void populate_array_seq(int *v, int n) {
  for (int i = 0; i < n; ++i) {
    v[i] = rand() % n;
  }
}
```