ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmp>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,(%rdi)
  js     L9
  setne  %al
  movzbl %al,%eax
L9:
  ret
```

assistant: ```c
int cmp(const void *a, const void *b) {
  if (*(long long *)a - *(long long *)b < 0)
    return -1;
  if (*(long long *)a - *(long long *)b > 0)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binary_search_tree_node_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <binary_search_tree_structure_legal_p@plt>
  mov    %eax,%edi
  call   <assert_exit@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <memory_cache_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void binary_search_tree_node_destroy(struct binary_search_tree *node) {
  assert_exit(binary_search_tree_structure_legal_p(node));
  memory_cache_free(node);
}
```
user: What is the c source code of the assembly code below:

```asm
<binary_search_tree_node_destroy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <binary_search_tree_structure_legal_p@plt>
  mov    %eax,%edi
  call   <assert_exit@plt>
  mov    %rbx,%rdi
  call   <memory_cache_free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void binary_search_tree_node_destroy(struct binary_search_tree *node) {
  assert_exit(binary_search_tree_structure_legal_p(node));
  memory_cache_free(node);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binary_search_tree_node_destroy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <binary_search_tree_structure_legal_p@plt>
  mov    %eax,%edi
  call   <assert_exit@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <memory_cache_free@plt>
```

assistant: ```c
void binary_search_tree_node_destroy(struct binary_search_tree *node) {
  assert_exit(binary_search_tree_structure_legal_p(node));
  memory_cache_free(node);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binary_search_tree_node_destroy>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <binary_search_tree_structure_legal_p@plt>
  mov    %eax,%edi
  call   <assert_exit@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <memory_cache_free@plt>
```

assistant: ```c
void binary_search_tree_node_destroy(struct binary_search_tree *node) {
  assert_exit(binary_search_tree_structure_legal_p(node));
  memory_cache_free(node);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: argc[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argc[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
L17:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string

tool: D7: argc[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argc[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
datatype: string

tool: D8: argc[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argc[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L9
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L19:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L19
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: argc[%d] = %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    printf("argc[%d] = %s\n", i, argv[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PCX_D>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0xc0,%eax
  jne    L15
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  and    $0x3f,%eax
  mov    %al,-0x19(%rbp)
  subl   $0x1,-0x34(%rbp)
  jmp    L9
L35:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L9:
  movzbl -0x19(%rbp),%eax
  mov    %eax,%edx
  sub    $0x1,%edx
  mov    %dl,-0x19(%rbp)
  test   %al,%al
  jg     L35
  addq   $0x1,-0x18(%rbp)
  subl   $0x1,-0x34(%rbp)
  jmp    L42
L15:
  mov    -0x18(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x34(%rbp)
L42:
  cmpl   $0x0,-0x34(%rbp)
  jne    L32
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int PCX_D(void *src_raw, void *dest_raw, unsigned src_size) {
  char *src = src_raw;
  char *dest = dest_raw;
  char num;
  char *orig_dest = dest;
  do {
    if ((*src & 0xc0) == 0xc0) {
      num = *(src++) & 0x3f;
      src_size--;
      while ((num--) > 0) {
        *(dest++) = *src;
      }
      src++;
      src_size--;
    } else {
      (*dest++) = *(src++);
      src_size--;
    };
  } while (src_size);
  return (dest - orig_dest);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<PCX_D>:
  endbr64
  mov    %rsi,%rax
  jmp    L39
L53:
  and    $0x3f,%ecx
  lea    -0x1(%rcx),%r8d
  test   %cl,%cl
  jle    L0
  movzbl %r8b,%r8d
  lea    0x1(%rax,%r8,1),%r8
L43:
  add    $0x1,%rax
  movzbl 0x1(%rdi),%ecx
  mov    %cl,-0x1(%rax)
  cmp    %r8,%rax
  jne    L43
L26:
  add    $0x2,%rdi
  sub    $0x2,%edx
  mov    %r8,%rax
L58:
  test   %edx,%edx
  je     L20
L39:
  movzbl (%rdi),%ecx
  mov    %ecx,%r8d
  and    $0xc0,%r8d
  cmp    $0xc0,%r8d
  je     L53
  add    $0x1,%rdi
  mov    %cl,(%rax)
  sub    $0x1,%edx
  lea    0x1(%rax),%rax
  jmp    L58
L0:
  mov    %rax,%r8
  jmp    L26
L20:
  sub    %esi,%eax
  ret
```

assistant: ```c
int PCX_D(void *src_raw, void *dest_raw, unsigned src_size) {
  char *src = src_raw;
  char *dest = dest_raw;
  char num;
  char *orig_dest = dest;
  do {
    if ((*src & 0xc0) == 0xc0) {
      num = *(src++) & 0x3f;
      src_size--;
      while ((num--) > 0) {
        *(dest++) = *src;
      }
      src++;
      src_size--;
    } else {
      (*dest++) = *(src++);
      src_size--;
    };
  } while (src_size);
  return (dest - orig_dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PCX_D>:
  endbr64
  mov    %rsi,%rax
  jmp    L11
  nopl   0x0(%rax)
L54:
  sub    $0x1,%edx
  mov    %cl,(%rax)
  add    $0x1,%rdi
  add    $0x1,%rax
  test   %edx,%edx
  je     L40
L11:
  movzbl (%rdi),%ecx
  mov    %ecx,%r8d
  and    $0xc0,%r8d
  cmp    $0xc0,%r8d
  jne    L54
  and    $0x3f,%ecx
  lea    -0x1(%rcx),%r8d
  test   %cl,%cl
  je     L2
  movzbl %r8b,%r8d
  lea    0x1(%rax,%r8,1),%r8
  nopl   0x0(%rax,%rax,1)
L27:
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rax
  mov    %cl,-0x1(%rax)
  cmp    %rax,%r8
  jne    L27
  add    $0x2,%rdi
  sub    $0x2,%edx
  mov    %r8,%rax
L8:
  test   %edx,%edx
  jne    L11
L40:
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L2:
  mov    %rax,%r8
  add    $0x2,%rdi
  sub    $0x2,%edx
  mov    %r8,%rax
  jmp    L8
```

assistant: ```c
int PCX_D(void *src_raw, void *dest_raw, unsigned src_size) {
  char *src = src_raw;
  char *dest = dest_raw;
  char num;
  char *orig_dest = dest;
  do {
    if ((*src & 0xc0) == 0xc0) {
      num = *(src++) & 0x3f;
      src_size--;
      while ((num--) > 0) {
        *(dest++) = *src;
      }
      src++;
      src_size--;
    } else {
      (*dest++) = *(src++);
      src_size--;
    };
  } while (src_size);
  return (dest - orig_dest);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L52
L35:
  addl   $0x1,-0x10(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L52:
  movss  -0x18(%rbp),%xmm0
  movss  D26(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L35
  movss  D26(%rip),%xmm1
  ucomiss %xmm1,%xmm0
  jne    L35
  cmpl   $0x0,-0x10(%rbp)
  jne    L51
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L17
L51:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x10(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L17:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D33
data_type: string
name: retrieve_data
arguments: tag: D68
data_type: string
name: retrieve_data
arguments: tag: D78
data_type: string
name: retrieve_data
arguments: tag: D26
data_type: byte[4]
name: retrieve_data
arguments: tag: D39
data_type: string
name: retrieve_data
arguments: tag: D66
data_type: string

tool: D33: Give a number or give -1 to exit : 

tool: D68: %f

tool: D78: Give a number or give -1 to stop : 

tool: {"D26": [0x00,0x00,0x80,0xbf]}

tool: D39: ERROR!!! We can't div with zero !!!

tool: D66: The avg is %f


assistant: ```c
int main() {
  float avg = 0, sum = 0, tmp = 0;
  int counter = 0;
  printf("Give a number or give -1 to exit : ");
  scanf("%f", &tmp);
  while (tmp != -1) {
    counter++;
    sum += tmp;
    printf("Give a number or give -1 to stop : ");
    scanf("%f", &tmp);
  }
  if (counter == 0) {
    printf("ERROR!!! We can't div with zero !!!\n");
  } else {
    avg = sum / counter;
    printf("The avg is %f\n", avg);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  ucomiss D37(%rip),%xmm0
  jp     L49
  je     L65
L49:
  mov    $0x0,%ebx
  pxor   %xmm3,%xmm3
  movss  %xmm3,0xc(%rsp)
  lea    D19(%rip),%r12
  lea    D43(%rip),%rbp
L13:
  add    $0x1,%ebx
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  ucomiss D37(%rip),%xmm0
  jp     L13
  jne    L13
  test   %ebx,%ebx
  je     L65
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D76(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L22
L65:
  lea    D26(%rip),%rdi
  call   <puts@plt>
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L61
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L61:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
type: string
name: unpack_data
arguments: label: D43
type: string
name: unpack_data
arguments: label: D37
type: byte[4]
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D76
type: string
name: unpack_data
arguments: label: D26
type: string

tool: D8: Give a number or give -1 to exit : 

tool: D43: %f

tool: {"D37": [0x00,0x00,0x80,0xbf]}

tool: D19: Give a number or give -1 to stop : 

tool: D76: The avg is %f


tool: D26: ERROR!!! We can't div with zero !!!

assistant: ```c
int main() {
  float avg = 0, sum = 0, tmp = 0;
  int counter = 0;
  printf("Give a number or give -1 to exit : ");
  scanf("%f", &tmp);
  while (tmp != -1) {
    counter++;
    sum += tmp;
    printf("Give a number or give -1 to stop : ");
    scanf("%f", &tmp);
  }
  if (counter == 0) {
    printf("ERROR!!! We can't div with zero !!!\n");
  } else {
    avg = sum / counter;
    printf("The avg is %f\n", avg);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  lea    D20(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  ucomiss D58(%rip),%xmm1
  jp     L42
  je     L31
L42:
  xor    %ebx,%ebx
  pxor   %xmm0,%xmm0
  lea    D69(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L21:
  addss  %xmm1,%xmm0
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  ucomiss D58(%rip),%xmm1
  movss  0xc(%rsp),%xmm0
  jp     L21
  jne    L21
  pxor   %xmm1,%xmm1
  lea    D68(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  lea    D1(%rip),%rdi
  call   <puts@plt>
  jmp    L36
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D22
data_type: string
name: read_data
arguments: tag: D20
data_type: string
name: read_data
arguments: tag: D58
data_type: byte[4]
name: read_data
arguments: tag: D69
data_type: string
name: read_data
arguments: tag: D68
data_type: string
name: read_data
arguments: tag: D1
data_type: string

tool: D22: Give a number or give -1 to exit : 

tool: D20: %f

tool: {"D58": [0x00,0x00,0x80,0xbf]}

tool: D69: Give a number or give -1 to stop : 

tool: D68: The avg is %f


tool: D1: ERROR!!! We can't div with zero !!!

assistant: ```c
int main() {
  float avg = 0, sum = 0, tmp = 0;
  int counter = 0;
  printf("Give a number or give -1 to exit : ");
  scanf("%f", &tmp);
  while (tmp != -1) {
    counter++;
    sum += tmp;
    printf("Give a number or give -1 to stop : ");
    scanf("%f", &tmp);
  }
  if (counter == 0) {
    printf("ERROR!!! We can't div with zero !!!\n");
  } else {
    avg = sum / counter;
    printf("The avg is %f\n", avg);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D27(%rip),%rdi
  push   %r12
  lea    D61(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  movl   $0x0,0x14(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  ucomiss D63(%rip),%xmm1
  jp     L40
  je     L50
L40:
  xor    %ebx,%ebx
  pxor   %xmm0,%xmm0
  lea    D51(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L35:
  addss  %xmm1,%xmm0
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  movss  %xmm0,0xc(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm1
  ucomiss D63(%rip),%xmm1
  movss  0xc(%rsp),%xmm0
  jp     L35
  jne    L35
  pxor   %xmm1,%xmm1
  lea    D41(%rip),%rdi
  mov    $0x1,%eax
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L18:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  lea    D22(%rip),%rdi
  call   <puts@plt>
  jmp    L18
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D27
type_infered: string
name: retrieve_data
arguments: data_label: D61
type_infered: string
name: retrieve_data
arguments: data_label: D63
type_infered: byte[4]
name: retrieve_data
arguments: data_label: D51
type_infered: string
name: retrieve_data
arguments: data_label: D41
type_infered: string
name: retrieve_data
arguments: data_label: D22
type_infered: string

tool: D27: Give a number or give -1 to exit : 

tool: D61: %f

tool: {"D63": [0x00,0x00,0x80,0xbf]}

tool: D51: Give a number or give -1 to stop : 

tool: D41: The avg is %f


tool: D22: ERROR!!! We can't div with zero !!!

assistant: ```c
int main() {
  float avg = 0, sum = 0, tmp = 0;
  int counter = 0;
  printf("Give a number or give -1 to exit : ");
  scanf("%f", &tmp);
  while (tmp != -1) {
    counter++;
    sum += tmp;
    printf("Give a number or give -1 to stop : ");
    scanf("%f", &tmp);
  }
  if (counter == 0) {
    printf("ERROR!!! We can't div with zero !!!\n");
  } else {
    avg = sum / counter;
    printf("The avg is %f\n", avg);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x8,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L0
L7:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x10(%rbp)
L0:
  cmpq   $0x63,-0x10(%rbp)
  jbe    L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  volatile double *a;
  a = calloc(100, sizeof *a);
  for (size_t i = 0; i < 100; ++i) {
    a[i] = a[i];
  }
  free((void *)a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0x64,%edi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rdx
  lea    0x320(%rax),%rcx
L2:
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L2
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  volatile double *a;
  a = calloc(100, sizeof *a);
  for (size_t i = 0; i < 100; ++i) {
    a[i] = a[i];
  }
  free((void *)a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x64,%edi
  sub    $0x8,%rsp
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rdx
  lea    0x320(%rax),%rcx
  nopl   0x0(%rax)
L3:
  movsd  (%rdx),%xmm0
  add    $0x8,%rdx
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rcx,%rdx
  jne    L3
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  volatile double *a;
  a = calloc(100, sizeof *a);
  for (size_t i = 0; i < 100; ++i) {
    a[i] = a[i];
  }
  free((void *)a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x64,%edi
  sub    $0x8,%rsp
  mov    $0x8,%esi
  call   <calloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rdx
  lea    0x320(%rax),%rcx
  nopl   0x0(%rax)
L2:
  movsd  (%rdx),%xmm0
  add    $0x8,%rdx
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rcx,%rdx
  jne    L2
  call   <free@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  volatile double *a;
  a = calloc(100, sizeof *a);
  for (size_t i = 0; i < 100; ++i) {
    a[i] = a[i];
  }
  free((void *)a);
}
```