ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ClearMove>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x31,%esi
  mov    $0x16,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ClearMove() {
  move(22, 49);
  clrtoeol();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ClearMove>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x31,%esi
  mov    $0x16,%edi
  call   <move@plt>
  mov    $0x0,%eax
  call   <clrtoeol@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ClearMove() {
  move(22, 49);
  clrtoeol();
}
```
user: Translate the below assembly code into C programming language:

```asm
<ClearMove>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x31,%esi
  mov    $0x16,%edi
  call   <move@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <clrtoeol@plt>
```

assistant: ```c
void ClearMove() {
  move(22, 49);
  clrtoeol();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ClearMove>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x31,%esi
  mov    $0x16,%edi
  call   <move@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <clrtoeol@plt>
```

assistant: ```c
void ClearMove() {
  move(22, 49);
  clrtoeol();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<build_subject>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <parse_name@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L1
L8:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <X509_REQ_set_subject_name@plt>
  test   %eax,%eax
  jne    L20
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <X509_NAME_free@plt>
  mov    $0x0,%eax
  jmp    L1
L20:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <X509_NAME_free@plt>
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int build_subject(X509_REQ *req, char *subject, unsigned long chtype, int multirdn) {
  X509_NAME *n;
  if (!(n = parse_name(subject, chtype, multirdn)))
    return 0;
  if (!X509_REQ_set_subject_name(req, n)) {
    X509_NAME_free(n);
    return 0;
  }
  X509_NAME_free(n);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<build_subject>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  mov    %ecx,%edx
  call   <parse_name@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L7
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <X509_REQ_set_subject_name@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L6
  mov    %rbx,%rdi
  call   <X509_NAME_free@plt>
  mov    $0x1,%ebp
L7:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rbx,%rdi
  call   <X509_NAME_free@plt>
  jmp    L7
```

assistant: ```c
int build_subject(X509_REQ *req, char *subject, unsigned long chtype, int multirdn) {
  X509_NAME *n;
  if (!(n = parse_name(subject, chtype, multirdn)))
    return 0;
  if (!X509_REQ_set_subject_name(req, n)) {
    X509_NAME_free(n);
    return 0;
  }
  X509_NAME_free(n);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<build_subject>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %r12
  mov    %ecx,%edx
  xor    %r12d,%r12d
  push   %rbp
  call   <parse_name@plt>
  test   %rax,%rax
  je     L8
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <X509_REQ_set_subject_name@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  test   %eax,%eax
  je     L12
  call   <X509_NAME_free@plt>
  mov    $0x1,%r12d
L8:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L12:
  call   <X509_NAME_free@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int build_subject(X509_REQ *req, char *subject, unsigned long chtype, int multirdn) {
  X509_NAME *n;
  if (!(n = parse_name(subject, chtype, multirdn)))
    return 0;
  if (!X509_REQ_set_subject_name(req, n)) {
    X509_NAME_free(n);
    return 0;
  }
  X509_NAME_free(n);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<build_subject>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  push   %r12
  mov    %ecx,%edx
  xor    %r12d,%r12d
  push   %rbp
  call   <parse_name@plt>
  test   %rax,%rax
  je     L2
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%rbp
  call   <X509_REQ_set_subject_name@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  test   %eax,%eax
  je     L10
  call   <X509_NAME_free@plt>
  mov    $0x1,%r12d
L2:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L10:
  call   <X509_NAME_free@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int build_subject(X509_REQ *req, char *subject, unsigned long chtype, int multirdn) {
  X509_NAME *n;
  if (!(n = parse_name(subject, chtype, multirdn)))
    return 0;
  if (!X509_REQ_set_subject_name(req, n)) {
    X509_NAME_free(n);
    return 0;
  }
  X509_NAME_free(n);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  addq   $0x8,-0x30(%rbp)
  lea    -0x14(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <forkpty@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jns    L8
  mov    $0xffffffff,%eax
  jmp    L10
L8:
  cmpq   $0x0,-0x10(%rbp)
  je     L21
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
L21:
  mov    $0x0,%eax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  ++argv;
  int pty;
  pid_t iskid = forkpty(&pty, NULL, NULL, NULL);
  if (iskid < 0)
    return -1;
  if (iskid)
    execvp(argv[0], argv);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <forkpty@plt>
  test   %rax,%rax
  js     L9
  mov    $0x0,%edx
  jne    L21
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L21:
  lea    0x8(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <execvp@plt>
  mov    $0x0,%edx
  jmp    L27
L9:
  mov    $0xffffffff,%edx
  jmp    L27
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  ++argv;
  int pty;
  pid_t iskid = forkpty(&pty, NULL, NULL, NULL);
  if (iskid < 0)
    return -1;
  if (iskid)
    execvp(argv[0], argv);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <forkpty@plt>
  test   %rax,%rax
  js     L10
  mov    $0x0,%r12d
  jne    L19
L1:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L19:
  mov    0x8(%rbx),%rdi
  lea    0x8(%rbx),%rsi
  call   <execvp@plt>
  jmp    L1
L10:
  or     $0xffffffff,%r12d
  jmp    L1
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  ++argv;
  int pty;
  pid_t iskid = forkpty(&pty, NULL, NULL, NULL);
  if (iskid < 0)
    return -1;
  if (iskid)
    execvp(argv[0], argv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  xor    %ecx,%ecx
  xor    %edx,%edx
  push   %rbx
  mov    %rsi,%rbx
  xor    %esi,%esi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <forkpty@plt>
  test   %rax,%rax
  js     L40
  mov    $0x0,%r12d
  jne    L43
L20:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L43:
  mov    0x8(%rbx),%rdi
  lea    0x8(%rbx),%rsi
  call   <execvp@plt>
  jmp    L20
L40:
  or     $0xffffffff,%r12d
  jmp    L20
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  ++argv;
  int pty;
  pid_t iskid = forkpty(&pty, NULL, NULL, NULL);
  if (iskid < 0)
    return -1;
  if (iskid)
    execvp(argv[0], argv);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  -0x10(%rbp),%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: string
name: disassemble_data
arguments: tag: D47
type_infered: string
name: disassemble_data
arguments: tag: D44
type_infered: string
name: disassemble_data
arguments: tag: D31
type_infered: string

tool: D29: ===============================================

tool: D47: Multiplication!
 Please input two numbers:

tool: D44: %lf %lf

tool: D31: %lf * %lf = %lf


assistant: ```c
void multiply() {
  double num1, num2, multi;
  printf("===============================================\n");
  printf("Multiplication!\n Please input two numbers:\n");
  scanf("%lf %lf", &num1, &num2);
  multi = num1 * num2;
  printf("%lf * %lf = %lf\n", num1, num2, multi);
  printf("===============================================\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  lea    D15(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D33
data_type: string
name: parse_data
arguments: label: D0
data_type: string
name: parse_data
arguments: label: D22
data_type: string
name: parse_data
arguments: label: D15
data_type: string

tool: D33: ===============================================

tool: D0: Multiplication!
 Please input two numbers:

tool: D22: %lf %lf

tool: D15: %lf * %lf = %lf


assistant: ```c
void multiply() {
  double num1, num2, multi;
  printf("===============================================\n");
  printf("Multiplication!\n Please input two numbers:\n");
  scanf("%lf %lf", &num1, &num2);
  multi = num1 * num2;
  printf("%lf * %lf = %lf\n", num1, num2, multi);
  printf("===============================================\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  lea    D27(%rip),%rdi
  mov    $0x3,%eax
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D39
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string
name: parse_data
arguments: data_label: D28
datatype: string
name: parse_data
arguments: data_label: D27
datatype: string

tool: D39: ===============================================

tool: D4: Multiplication!
 Please input two numbers:

tool: D28: %lf %lf

tool: D27: %lf * %lf = %lf


assistant: ```c
void multiply() {
  double num1, num2, multi;
  printf("===============================================\n");
  printf("Multiplication!\n Please input two numbers:\n");
  scanf("%lf %lf", &num1, &num2);
  multi = num1 * num2;
  printf("%lf * %lf = %lf\n", num1, num2, multi);
  printf("===============================================\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<multiply>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  movsd  0x8(%rsp),%xmm0
  movsd  0x10(%rsp),%xmm1
  lea    D1(%rip),%rdi
  mov    $0x3,%eax
  movapd %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D18: ===============================================

tool: D7: Multiplication!
 Please input two numbers:

tool: D12: %lf %lf

tool: D1: %lf * %lf = %lf


assistant: ```c
void multiply() {
  double num1, num2, multi;
  printf("===============================================\n");
  printf("Multiplication!\n Please input two numbers:\n");
  scanf("%lf %lf", &num1, &num2);
  multi = num1 * num2;
  printf("%lf * %lf = %lf\n", num1, num2, multi);
  printf("===============================================\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x430,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %esi,-0x42c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x414(%rbp)
  jmp    L13
L3:
  mov    -0x414(%rbp),%edx
  mov    -0x428(%rbp),%rax
  add    %rdx,%rax
  mov    -0x414(%rbp),%edx
  lea    -0x410(%rbp),%rcx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x414(%rbp)
L13:
  mov    -0x414(%rbp),%eax
  cmp    -0x42c(%rbp),%eax
  jb     L3
  lea    -0x410(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
void my_memcpy(void *q, unsigned int n) {
  unsigned i;
  char p[1024];
  for (i = 0; i < n; ++i)
    ((char *)p)[i] = ((char *)q)[i];
  foo(p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_memcpy>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  je     L21
  mov    %esi,%esi
L19:
  movzbl (%rdi,%rax,1),%edx
  mov    %dl,(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L19
L21:
  mov    %rsp,%rdi
  call   <foo@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x418,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_memcpy(void *q, unsigned int n) {
  unsigned i;
  char p[1024];
  for (i = 0; i < n; ++i)
    ((char *)p)[i] = ((char *)q)[i];
  foo(p);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_memcpy>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  test   %esi,%esi
  je     L5
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    %rax,%r8
L5:
  mov    %r8,%rdi
  call   <foo@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x418,%rsp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_memcpy(void *q, unsigned int n) {
  unsigned i;
  char p[1024];
  for (i = 0; i < n; ++i)
    ((char *)p)[i] = ((char *)q)[i];
  foo(p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_memcpy>:
  endbr64
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r8
  test   %esi,%esi
  je     L8
  mov    %esi,%edx
  mov    %rdi,%rsi
  mov    %r8,%rdi
  call   <memcpy@plt>
  mov    %rax,%r8
L8:
  mov    %r8,%rdi
  call   <foo@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x418,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void my_memcpy(void *q, unsigned int n) {
  unsigned i;
  char p[1024];
  for (i = 0; i < n; ++i)
    ((char *)p)[i] = ((char *)q)[i];
  foo(p);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  jne    L21
  mov    $0xffffffff,%eax
  jmp    L67
L21:
  mov    -0x1c(%rbp),%eax
  sar    $0x6,%eax
  and    $0x3,%eax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  and    $0x1f,%eax
  cmp    $0x1f,%eax
  je     L73
  mov    -0x1c(%rbp),%eax
  cltq
  and    $0x1f,%eax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  jmp    L67
L73:
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L67
L16:
  mov    -0x10(%rbp),%rax
  shl    $0x7,%rax
  mov    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  and    $0x7f,%al
  cltq
  or     %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L73
  cmpq   $0x8,-0x18(%rbp)
  jbe    L71
  mov    D11(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L67
L71:
  mov    -0x30(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x1,%eax
L67:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
ssize_t get_id(struct ber *b, unsigned long *tag, int *class, int *cstruct) {
  u_char u;
  size_t i = 0;
  unsigned long t = 0;
  if (ber_getc(b, &u) == -1)
    return -1;
  *class = (u >> 6) & 0x3;
  *cstruct = (u & 0x20) == 0x20;
  if ((u & 0x1f) != 0x1f) {
    *tag = u & 0x1f;
    return 1;
  }
  do {
    if (ber_getc(b, &u) == -1)
      return -1;
    t = (t << 7) | (u & ~0x80);
    i++;
  } while (u & 0x80);
  if (i > sizeof(unsigned long)) {
    errno = ERANGE;
    return -1;
  }
  *tag = t;
  return i + 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_id>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r14
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  je     L70
  mov    0x4(%rsp),%eax
  mov    %eax,%edx
  sar    $0x6,%edx
  and    $0x3,%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,%edx
  shr    $0x5,%edx
  and    $0x1,%edx
  mov    %edx,(%rbx)
  and    $0x1f,%eax
  cmp    $0x1f,%eax
  je     L52
  cltq
  mov    %rax,(%r14)
  mov    $0x1,%eax
L70:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    0x4(%rsp),%r13
L26:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <ber_getc@plt>
  cmp    $0xffffffff,%eax
  je     L70
  shl    $0x7,%rbx
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  and    $0x7f,%al
  cltq
  or     %rax,%rbx
  add    $0x1,%rbp
  test   $0x80,%dl
  jne    L26
  cmp    $0x8,%rbp
  ja     L4
  mov    %rbx,(%r14)
  lea    0x1(%rbp),%eax
  jmp    L70
L4:
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L70
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
ssize_t get_id(struct ber *b, unsigned long *tag, int *class, int *cstruct) {
  u_char u;
  size_t i = 0;
  unsigned long t = 0;
  if (ber_getc(b, &u) == -1)
    return -1;
  *class = (u >> 6) & 0x3;
  *cstruct = (u & 0x20) == 0x20;
  if ((u & 0x1f) != 0x1f) {
    *tag = u & 0x1f;
    return 1;
  }
  do {
    if (ber_getc(b, &u) == -1)
      return -1;
    t = (t << 7) | (u & ~0x80);
    i++;
  } while (u & 0x80);
  if (i > sizeof(unsigned long)) {
    errno = ERANGE;
    return -1;
  }
  *tag = t;
  return i + 1;
}
```