ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<seno>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  mov    $0x0,%ebx
L0:
  mov    %ebx,%esi
  mov    $0xffffffff,%edi
  call   <pot@plt>
  mov    %eax,%r12d
  mov    %ebx,%edi
  call   <calcn@plt>
  mov    %eax,%edi
  call   <fatorial@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <calcn@plt>
  mov    %eax,%esi
  mov    %r13d,%edi
  call   <pot@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebp,%xmm1
  divsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double seno(int x) {
  int n;
  int numerador, denominador, term;
  double result = 0;
  for (n = 0; n < 10; n++) {
    numerador = pot(-1, n);
    denominador = fatorial(calcn(n));
    term = pot(x, calcn(n));
    result += ((double)numerador / (double)denominador) * (double)term;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<seno>:
  endbr64
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%esi
  mov    $0xffffffff,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pot@plt>
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <calcn@plt>
  mov    %eax,%edi
  call   <fatorial@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  mov    %eax,%ebp
  call   <calcn@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <pot@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %ebp,%xmm2
  cvtsi2sd %r12d,%xmm0
  divsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0xa,%ebx
  jne    L9
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double seno(int x) {
  int n;
  int numerador, denominador, term;
  double result = 0;
  for (n = 0; n < 10; n++) {
    numerador = pot(-1, n);
    denominador = fatorial(calcn(n));
    term = pot(x, calcn(n));
    result += ((double)numerador / (double)denominador) * (double)term;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<seno>:
  endbr64
  push   %r13
  pxor   %xmm1,%xmm1
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %ebx,%esi
  mov    $0xffffffff,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pot@plt>
  mov    %ebx,%edi
  mov    %eax,%r12d
  call   <calcn@plt>
  mov    %eax,%edi
  call   <fatorial@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  mov    %eax,%ebp
  call   <calcn@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <pot@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %ebp,%xmm2
  cvtsi2sd %r12d,%xmm0
  divsd  %xmm2,%xmm0
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0xa,%ebx
  jne    L7
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double seno(int x) {
  int n;
  int numerador, denominador, term;
  double result = 0;
  for (n = 0; n < 10; n++) {
    numerador = pot(-1, n);
    denominador = fatorial(calcn(n));
    term = pot(x, calcn(n));
    result += ((double)numerador / (double)denominador) * (double)term;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_specific_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L6
L14:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L7
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  subl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x0,-0x4(%rbp)
  jne    L14
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_specific_char(char c, char *input, int total_size) {
  int count = 0;
  int size = total_size;
  while (size) {
    if (*input == c)
      count++;
    *input++;
    size--;
  }
  return count;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_specific_char>:
  endbr64
  test   %edx,%edx
  je     L6
  mov    %edx,%eax
  lea    (%rsi,%rax,1),%rcx
  mov    $0x0,%eax
L10:
  cmp    %dil,(%rsi)
  sete   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  add    $0x1,%rsi
  cmp    %rcx,%rsi
  jne    L10
  ret
L6:
  mov    %edx,%eax
  ret
```

assistant: ```c
int get_specific_char(char c, char *input, int total_size) {
  int count = 0;
  int size = total_size;
  while (size) {
    if (*input == c)
      count++;
    *input++;
    size--;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_specific_char>:
  endbr64
  test   %edx,%edx
  je     L15
  mov    %edx,%edx
  xor    %eax,%eax
  lea    (%rsi,%rdx,1),%rcx
L14:
  xor    %edx,%edx
  cmp    %dil,(%rsi)
  sete   %dl
  add    $0x1,%rsi
  add    %edx,%eax
  cmp    %rcx,%rsi
  jne    L14
  ret
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int get_specific_char(char c, char *input, int total_size) {
  int count = 0;
  int size = total_size;
  while (size) {
    if (*input == c)
      count++;
    *input++;
    size--;
  }
  return count;
}
```
user: What is the c source code of the assembly code below:

```asm
<blewgap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  add    $0x8,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L17
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L17:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void blewgap(unsigned char **p) {
  int gaplen = (rand() % (16 - 8)) + 8;
  unsigned char *buf = *p;
  (*p) += gaplen;
  while (gaplen--)
    *buf++ = rand() & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<blewgap>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x7,%ebp
  sub    %edx,%ebp
  mov    (%r12),%rbx
  add    $0x8,%ebp
  movslq %ebp,%rax
  add    %rbx,%rax
  mov    %rax,(%r12)
  mov    %ebp,%ebp
  add    %rbx,%rbp
L7:
  mov    $0x0,%eax
  call   <rand@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void blewgap(unsigned char **p) {
  int gaplen = (rand() % (16 - 8)) + 8;
  unsigned char *buf = *p;
  (*p) += gaplen;
  while (gaplen--)
    *buf++ = rand() & 0xff;
}
```
user: What is the c source code of the assembly code below:

```asm
<blewgap>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <rand@plt>
  mov    (%r12),%rbx
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x7,%ebp
  sub    %edx,%ebp
  add    $0x8,%ebp
  movslq %ebp,%rax
  mov    %ebp,%ebp
  add    %rbx,%rax
  add    %rbx,%rbp
  mov    %rax,(%r12)
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rand@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void blewgap(unsigned char **p) {
  int gaplen = (rand() % (16 - 8)) + 8;
  unsigned char *buf = *p;
  (*p) += gaplen;
  while (gaplen--)
    *buf++ = rand() & 0xff;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<blewgap>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <rand@plt>
  mov    (%r12),%rbx
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ebp
  and    $0x7,%ebp
  sub    %edx,%ebp
  add    $0x8,%ebp
  movslq %ebp,%rax
  mov    %ebp,%ebp
  add    %rbx,%rax
  add    %rbx,%rbp
  mov    %rax,(%r12)
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <rand@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void blewgap(unsigned char **p) {
  int gaplen = (rand() % (16 - 8)) + 8;
  unsigned char *buf = *p;
  (*p) += gaplen;
  while (gaplen--)
    *buf++ = rand() & 0xff;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  seta   %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  setb   %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  setae  %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  setbe  %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  lea    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  setne  %al
  movzbl %al,%eax
  add    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main() {
  long adr = 0;
  int sum = 0;
  sum += adr > &adr;
  sum += adr < &adr;
  sum += adr >= &adr;
  sum += adr <= &adr;
  sum += adr == &adr;
  sum += adr != &adr;
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  long adr = 0;
  int sum = 0;
  sum += adr > &adr;
  sum += adr < &adr;
  sum += adr >= &adr;
  sum += adr <= &adr;
  sum += adr == &adr;
  sum += adr != &adr;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  long adr = 0;
  int sum = 0;
  sum += adr > &adr;
  sum += adr < &adr;
  sum += adr >= &adr;
  sum += adr <= &adr;
  sum += adr == &adr;
  sum += adr != &adr;
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  mov    $0x3,%eax
  ret
```

assistant: ```c
int main() {
  long adr = 0;
  int sum = 0;
  sum += adr > &adr;
  sum += adr < &adr;
  sum += adr >= &adr;
  sum += adr <= &adr;
  sum += adr == &adr;
  sum += adr != &adr;
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<glmComputeBarycentricCoordinates3d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %r8,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  mov    %rsi,%rdx
  mov    %rcx,%rsi
  mov    %r12,%rdi
  call   <glmMakeVector3d@plt>
  lea    0x40(%rsp),%rbp
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <glmMakeVector3d@plt>
  mov    %r12,%rsi
  mov    %r12,%rdi
  call   <glmDotProduct3d@plt>
  movsd  %xmm0,(%rsp)
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <glmDotProduct3d@plt>
  movsd  %xmm0,0x8(%rsp)
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <glmDotProduct3d@plt>
  movsd  %xmm0,0x10(%rsp)
  lea    0x60(%rsp),%r14
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <glmMakeVector3d@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <glmDotProduct3d@plt>
  movsd  %xmm0,0x18(%rsp)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <glmDotProduct3d@plt>
  movsd  (%rsp),%xmm1
  mulsd  0x10(%rsp),%xmm1
  movsd  0x8(%rsp),%xmm5
  movapd %xmm5,%xmm2
  mulsd  %xmm5,%xmm2
  subsd  %xmm2,%xmm1
  ucomisd D10(%rip),%xmm1
  jp     L12
  je     L29
L12:
  movsd  D8(%rip),%xmm3
  movapd %xmm3,%xmm4
  divsd  %xmm1,%xmm4
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm7
  mulsd  %xmm7,%xmm1
  movsd  0x8(%rsp),%xmm6
  movapd %xmm6,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  %xmm7,%xmm6
  mulsd  (%rsp),%xmm0
  subsd  %xmm6,%xmm0
  mulsd  %xmm4,%xmm0
  subsd  %xmm1,%xmm3
  movapd %xmm3,%xmm2
  subsd  %xmm0,%xmm2
L11:
  movsd  %xmm1,(%rbx)
  movsd  %xmm0,0x8(%rbx)
  movsd  %xmm2,0x10(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  movapd %xmm1,%xmm2
  jmp    L11
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
type_guessed: byte[8]
name: extract_symbolic_data
arguments: label: D8
type_guessed: f64

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D8: 1

assistant: ```c
void glmComputeBarycentricCoordinates3d(double result[3], const double v1[3], const double v2[3], const double v3[3], const double p[3]) {
  double a, b, c, u, v, D;
  double tv1[3], tv2[3], tv3[3];
  glmMakeVector3d(tv1, v3, v1);
  glmMakeVector3d(tv2, v3, v2);
  a = glmDotProduct3d(tv1, tv1);
  b = glmDotProduct3d(tv2, tv1);
  c = glmDotProduct3d(tv2, tv2);
  glmMakeVector3d(tv3, v3, p);
  u = glmDotProduct3d(tv3, tv1);
  v = glmDotProduct3d(tv3, tv2);
  D = a * c - b * b;
  if (D == 0) {
    result[0] = 0;
    result[1] = 0;
    result[2] = 0;
    return;
  }
  D = 1.0 / D;
  result[0] = (c * u - b * v) * D;
  result[1] = (-b * u + a * v) * D;
  result[2] = 1 - result[0] - result[1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmComputeBarycentricCoordinates3d>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %rsi,%rdx
  mov    %rcx,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r12
  lea    0x40(%rsp),%rbp
  mov    %r12,%rdi
  call   <glmMakeVector3d@plt>
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <glmMakeVector3d@plt>
  mov    %r12,%rsi
  mov    %r12,%rdi
  lea    0x60(%rsp),%r13
  call   <glmDotProduct3d@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movsd  %xmm0,0x18(%rsp)
  call   <glmDotProduct3d@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  movsd  %xmm0,0x10(%rsp)
  call   <glmDotProduct3d@plt>
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <glmMakeVector3d@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <glmDotProduct3d@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  movsd  %xmm0,(%rsp)
  call   <glmDotProduct3d@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x18(%rsp),%xmm2
  pxor   %xmm7,%xmm7
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm5
  movsd  (%rsp),%xmm6
  movapd %xmm2,%xmm4
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm4
  mulsd  %xmm3,%xmm0
  subsd  %xmm0,%xmm4
  ucomisd %xmm7,%xmm4
  jp     L5
  je     L0
L5:
  movsd  D4(%rip),%xmm0
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm2
  movapd %xmm0,%xmm7
  divsd  %xmm4,%xmm7
  movapd %xmm3,%xmm4
  mulsd  %xmm5,%xmm4
  mulsd  %xmm6,%xmm3
  subsd  %xmm4,%xmm1
  subsd  %xmm3,%xmm2
  mulsd  %xmm7,%xmm1
  mulsd  %xmm7,%xmm2
  subsd  %xmm1,%xmm0
  subsd  %xmm2,%xmm0
L36:
  movsd  %xmm1,(%rbx)
  movsd  %xmm2,0x8(%rbx)
  movsd  %xmm0,0x10(%rbx)
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L0:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm1,%xmm0
  jmp    L36
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
void glmComputeBarycentricCoordinates3d(double result[3], const double v1[3], const double v2[3], const double v3[3], const double p[3]) {
  double a, b, c, u, v, D;
  double tv1[3], tv2[3], tv3[3];
  glmMakeVector3d(tv1, v3, v1);
  glmMakeVector3d(tv2, v3, v2);
  a = glmDotProduct3d(tv1, tv1);
  b = glmDotProduct3d(tv2, tv1);
  c = glmDotProduct3d(tv2, tv2);
  glmMakeVector3d(tv3, v3, p);
  u = glmDotProduct3d(tv3, tv1);
  v = glmDotProduct3d(tv3, tv2);
  D = a * c - b * b;
  if (D == 0) {
    result[0] = 0;
    result[1] = 0;
    result[2] = 0;
    return;
  }
  D = 1.0 / D;
  result[0] = (c * u - b * v) * D;
  result[1] = (-b * u + a * v) * D;
  result[2] = 1 - result[0] - result[1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vfprintf(stderr, fmt, v);
  fflush(stderr);
  va_end(v);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<die>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D1(%rip),%r12
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    (%r12),%edi
  call   <vfprintf@plt>
  mov    (%r12),%edi
  call   <fflush@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vfprintf(stderr, fmt, v);
  fflush(stderr);
  va_end(v);
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D3(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vfprintf(stderr, fmt, v);
  fflush(stderr);
  va_end(v);
  exit(1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  push   %rbx
  call   <va_start@plt>
  mov    D6(%rip),%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <vfprintf@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void die(char *fmt, ...) {
  va_list v;
  va_start(v, fmt);
  vfprintf(stderr, fmt, v);
  fflush(stderr);
  va_end(v);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<WhichSide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  movsd  %xmm3,-0x30(%rbp)
  movsd  %xmm4,-0x38(%rbp)
  movsd  %xmm5,-0x40(%rbp)
  movsd  -0x20(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x30(%rbp),%xmm1
  movsd  -0x38(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x40(%rbp),%xmm1
  movapd %xmm1,%xmm2
  subsd  -0x30(%rbp),%xmm2
  movsd  -0x18(%rbp),%xmm1
  subsd  -0x28(%rbp),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L10
  mov    $0xffffffff,%eax
  jmp    L27
L10:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L37
  mov    $0x1,%eax
  jmp    L27
L37:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int WhichSide(double x, double y, double x1, double y1, double x2, double y2) {
  double dist;
  dist = (y - y1) * (x2 - x1) - (y2 - y1) * (x - x1);
  if (dist > 0)
    return (-1);
  else if (dist < 0)
    return (1);
  else
    return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WhichSide>:
  endbr64
  subsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm1
  mov    $0xffffffff,%eax
  subsd  %xmm2,%xmm4
  subsd  %xmm3,%xmm5
  mulsd  %xmm4,%xmm1
  mulsd  %xmm0,%xmm5
  pxor   %xmm0,%xmm0
  subsd  %xmm5,%xmm1
  comisd %xmm0,%xmm1
  ja     L8
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L8:
  ret
```

assistant: ```c
int WhichSide(double x, double y, double x1, double y1, double x2, double y2) {
  double dist;
  dist = (y - y1) * (x2 - x1) - (y2 - y1) * (x - x1);
  if (dist > 0)
    return (-1);
  else if (dist < 0)
    return (1);
  else
    return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<WhichSide>:
  endbr64
  subsd  %xmm2,%xmm0
  subsd  %xmm3,%xmm1
  mov    $0xffffffff,%eax
  subsd  %xmm2,%xmm4
  subsd  %xmm3,%xmm5
  mulsd  %xmm4,%xmm1
  mulsd  %xmm0,%xmm5
  pxor   %xmm0,%xmm0
  subsd  %xmm5,%xmm1
  comisd %xmm0,%xmm1
  ja     L6
  xor    %eax,%eax
  comisd %xmm1,%xmm0
  seta   %al
L6:
  ret
```

assistant: ```c
int WhichSide(double x, double y, double x1, double y1, double x2, double y2) {
  double dist;
  dist = (y - y1) * (x2 - x1) - (y2 - y1) * (x - x1);
  if (dist > 0)
    return (-1);
  else if (dist < 0)
    return (1);
  else
    return (0);
}
```