ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<genDifference>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x28db9c69,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  imul   $0x191,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  sub    $0xc4,%eax
  cmp    $0x8,%eax
  jbe    L1
  lea    -0xc8(%rdx),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int genDifference() {
  int diff = rand() % (200 * 2 + 1);
  diff -= 200;
  if (abs(diff) < 5)
    diff = genDifference();
  return diff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__simplePNG_is_little_endian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
uint8_t __simplePNG_is_little_endian() {
  uint16_t val = 1;
  uint8_t *p = (uint8_t *)&val;
  return p[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__simplePNG_is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint8_t __simplePNG_is_little_endian() {
  uint16_t val = 1;
  uint8_t *p = (uint8_t *)&val;
  return p[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<__simplePNG_is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint8_t __simplePNG_is_little_endian() {
  uint16_t val = 1;
  uint8_t *p = (uint8_t *)&val;
  return p[0];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<__simplePNG_is_little_endian>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint8_t __simplePNG_is_little_endian() {
  uint16_t val = 1;
  uint8_t *p = (uint8_t *)&val;
  return p[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L19
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x18(%rbp)
  jmp    L1
L14:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x18(%rbp)
L1:
  cmpl   $0x0,-0x18(%rbp)
  jne    L14
  mov    -0x4(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int ft_pow(int x, unsigned int y) {
  int tmp;
  if (y == 0)
    return (1);
  tmp = x;
  y--;
  while (y > 0) {
    tmp *= x;
    y--;
  }
  return (tmp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L7
  sub    $0x1,%esi
  je     L5
  mov    %edi,%eax
L1:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L1
  ret
L5:
  mov    %edi,%eax
L7:
  ret
```

assistant: ```c
int ft_pow(int x, unsigned int y) {
  int tmp;
  if (y == 0)
    return (1);
  tmp = x;
  y--;
  while (y > 0) {
    tmp *= x;
    y--;
  }
  return (tmp);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L14
  mov    %edi,%eax
  sub    $0x1,%esi
  je     L14
  nopl   0x0(%rax)
L20:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L20
  ret
  nopl   0x0(%rax)
L14:
  ret
```

assistant: ```c
int ft_pow(int x, unsigned int y) {
  int tmp;
  if (y == 0)
    return (1);
  tmp = x;
  y--;
  while (y > 0) {
    tmp *= x;
    y--;
  }
  return (tmp);
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_pow>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L2
  mov    %edi,%eax
  sub    $0x1,%esi
  je     L2
  nopl   0x0(%rax)
L13:
  imul   %edi,%eax
  sub    $0x1,%esi
  jne    L13
  ret
  nopl   0x0(%rax)
L2:
  ret
```

assistant: ```c
int ft_pow(int x, unsigned int y) {
  int tmp;
  if (y == 0)
    return (1);
  tmp = x;
  y--;
  while (y > 0) {
    tmp *= x;
    y--;
  }
  return (tmp);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<isPalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L15
L1:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L15:
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool isPalindrome(int n) {
  int reversed = 0, tmp = n;
  while (tmp) {
    reversed = 10 * reversed + (tmp % 10);
    tmp /= 10;
  }
  return reversed == n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L12
  mov    %edi,%edx
  mov    $0x0,%ecx
L16:
  lea    (%rcx,%rcx,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L16
L24:
  cmp    %ecx,%edi
  sete   %al
  movzbl %al,%eax
  ret
L12:
  mov    %edi,%ecx
  jmp    L24
```

assistant: ```c
bool isPalindrome(int n) {
  int reversed = 0, tmp = n;
  while (tmp) {
    reversed = 10 * reversed + (tmp % 10);
    tmp /= 10;
  }
  return reversed == n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L7
  mov    %edi,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L16:
  movslq %edx,%rax
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L16
  xor    %eax,%eax
  cmp    %ecx,%edi
  sete   %al
  ret
L7:
  xor    %ecx,%ecx
  xor    %eax,%eax
  cmp    %ecx,%edi
  sete   %al
  ret
```

assistant: ```c
bool isPalindrome(int n) {
  int reversed = 0, tmp = n;
  while (tmp) {
    reversed = 10 * reversed + (tmp % 10);
    tmp /= 10;
  }
  return reversed == n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isPalindrome>:
  endbr64
  test   %edi,%edi
  je     L14
  mov    %edi,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L12:
  movslq %edx,%rax
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L12
  xor    %eax,%eax
  cmp    %ecx,%edi
  sete   %al
  ret
L14:
  xor    %ecx,%ecx
  xor    %eax,%eax
  cmp    %ecx,%edi
  sete   %al
  ret
```

assistant: ```c
bool isPalindrome(int n) {
  int reversed = 0, tmp = n;
  while (tmp) {
    reversed = 10 * reversed + (tmp % 10);
    tmp /= 10;
  }
  return reversed == n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x80,-0x824(%rbp)
  movl   $0x0,-0x820(%rbp)
  lea    -0x824(%rbp),%rax
  mov    %rax,-0x818(%rbp)
  movl   $0x0,-0x81c(%rbp)
  jmp    L1
L16:
  mov    -0x818(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x81c(%rbp),%eax
  cltq
  mov    %edx,-0x810(%rbp,%rax,4)
  mov    -0x81c(%rbp),%eax
  cltq
  mov    -0x810(%rbp,%rax,4),%edx
  mov    -0x820(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x820(%rbp)
L1:
  cmpl   $0x200,-0x81c(%rbp)
  jle    L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d ==> %d


assistant: ```c
int main() {
  int tab[512], licznik, liczba = 128, index = 0;
  int *wskaznik = &liczba;
  for (licznik = 0; licznik <= 512; index++) {
    tab[licznik] = *wskaznik;
    printf("%d ==> %d\n", index, tab[licznik]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D9(%rip),%rbp
L5:
  mov    $0x80,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  jmp    L5
```

tool_calls: name: parse_data
arguments: tag: D9
type: string

tool: D9: %d ==> %d


assistant: ```c
int main() {
  int tab[512], licznik, liczba = 128, index = 0;
  int *wskaznik = &liczba;
  for (licznik = 0; licznik <= 512; index++) {
    tab[licznik] = *wskaznik;
    printf("%d ==> %d\n", index, tab[licznik]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: %d ==> %d


assistant: ```c
int main() {
  int tab[512], licznik, liczba = 128, index = 0;
  int *wskaznik = &liczba;
  for (licznik = 0; licznik <= 512; index++) {
    tab[licznik] = *wskaznik;
    printf("%d ==> %d\n", index, tab[licznik]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %ebx,%esi
  mov    $0x80,%edx
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: %d ==> %d


assistant: ```c
int main() {
  int tab[512], licznik, liczba = 128, index = 0;
  int *wskaznik = &liczba;
  for (licznik = 0; licznik <= 512; index++) {
    tab[licznik] = *wskaznik;
    printf("%d ==> %d\n", index, tab[licznik]);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_and_terminate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  movsbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    $0x0,%eax
  jmp    L16
L8:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L16:
  leave
  ret
```

assistant: ```c
char *find_and_terminate(char *str, char find) {
  str = strchr(str, find);
  if (NULL == str) {
    return NULL;
  }
  *str = '\0';
  return str + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_and_terminate>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L7
  movb   $0x0,(%rax)
  add    $0x1,%rax
L7:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *find_and_terminate(char *str, char find) {
  str = strchr(str, find);
  if (NULL == str) {
    return NULL;
  }
  *str = '\0';
  return str + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_and_terminate>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  movb   $0x0,(%rax)
  add    $0x1,%rax
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *find_and_terminate(char *str, char find) {
  str = strchr(str, find);
  if (NULL == str) {
    return NULL;
  }
  *str = '\0';
  return str + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<find_and_terminate>:
  endbr64
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  movb   $0x0,(%rax)
  add    $0x1,%rax
L1:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *find_and_terminate(char *str, char find) {
  str = strchr(str, find);
  if (NULL == str) {
    return NULL;
  }
  *str = '\0';
  return str + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xfffffffb,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xfffffffb,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: string
name: extract_symbolic_data
arguments: tag: D14
data_type: string

tool: D9: ~4=%x


tool: D14: ~4u=%x


assistant: ```c
int main() {
  printf("~4=%x\n", ~4);
  printf("~4u=%x\n", ~4u);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffffb,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffb,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D12: ~4=%x


tool: D19: ~4u=%x


assistant: ```c
int main() {
  printf("~4=%x\n", ~4);
  printf("~4u=%x\n", ~4u);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffffb,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffb,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D8: ~4=%x


tool: D0: ~4u=%x


assistant: ```c
int main() {
  printf("~4=%x\n", ~4);
  printf("~4u=%x\n", ~4u);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffffb,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffb,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D10: ~4=%x


tool: D9: ~4u=%x


assistant: ```c
int main() {
  printf("~4=%x\n", ~4);
  printf("~4u=%x\n", ~4u);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zeroMatrixOfFloats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void zeroMatrixOfFloats(float *matrix, int numberOfElements) {
  for (int i = 0; i < numberOfElements; i++) {
    matrix[i] = (float)0.0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<zeroMatrixOfFloats>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L15:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L15
L18:
  ret
```

assistant: ```c
void zeroMatrixOfFloats(float *matrix, int numberOfElements) {
  for (int i = 0; i < numberOfElements; i++) {
    matrix[i] = (float)0.0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<zeroMatrixOfFloats>:
  endbr64
  test   %esi,%esi
  jle    L8
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
void zeroMatrixOfFloats(float *matrix, int numberOfElements) {
  for (int i = 0; i < numberOfElements; i++) {
    matrix[i] = (float)0.0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<zeroMatrixOfFloats>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  lea    0x0(,%rsi,4),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void zeroMatrixOfFloats(float *matrix, int numberOfElements) {
  for (int i = 0; i < numberOfElements; i++) {
    matrix[i] = (float)0.0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_file_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_file_len@plt>
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    D6(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L83
  cmpl   $0xffffffff,-0x18(%rbp)
  jne    L30
L83:
  mov    $0x0,%eax
  jmp    L4
L8:
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L4
L1:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1d(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L30:
  lea    -0x1d(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  cmpl   $0x0,-0x14(%rbp)
  jne    L79
  cmpl   $0x0,-0x1c(%rbp)
  jne    L79
  mov    $0x0,%eax
  jmp    L4
L79:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x10(%rbp),%rax
L4:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
char *ft_file_to_str(char *argv) {
  int i;
  int fd;
  char *temp;
  char c;
  int ret;
  i = 0;
  temp = (char *)malloc(sizeof(temp) * ft_file_len(argv));
  fd = open(argv, O_RDONLY, S_IRUSR);
  if (!temp || fd == -1)
    return (0);
  while ((ret = read(fd, &c, 1))) {
    if (ret == -1)
      return (0);
    temp[i] = c;
    i++;
  }
  if (!ret && i == 0) {
    return (0);
  }
  temp[i] = '\0';
  close(fd);
  return (temp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_file_to_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ft_file_len@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%r15
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <open@plt>
  test   %rbp,%rbp
  je     L79
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L79
  mov    $0x0,%ebx
  lea    0x7(%rsp),%r14
L97:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  je     L82
  add    $0x1,%rbx
  cmp    $0xffffffff,%eax
  je     L60
  movzbl 0x7(%rsp),%eax
  mov    %al,-0x1(%rbp,%rbx,1)
  jmp    L97
L82:
  test   %ebx,%ebx
  je     L32
  movslq %ebx,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
  mov    %r12d,%edi
  call   <close@plt>
  jmp    L87
L79:
  mov    $0x0,%r15d
  jmp    L87
L60:
  mov    $0x0,%r15d
L87:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %r15,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  mov    $0x0,%r15d
  jmp    L87
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ft_file_to_str(char *argv) {
  int i;
  int fd;
  char *temp;
  char c;
  int ret;
  i = 0;
  temp = (char *)malloc(sizeof(temp) * ft_file_len(argv));
  fd = open(argv, O_RDONLY, S_IRUSR);
  if (!temp || fd == -1)
    return (0);
  while ((ret = read(fd, &c, 1))) {
    if (ret == -1)
      return (0);
    temp[i] = c;
    i++;
  }
  if (!ret && i == 0) {
    return (0);
  }
  temp[i] = '\0';
  close(fd);
  return (temp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_file_to_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <ft_file_len@plt>
  lea    0x0(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  mov    %rax,%r13
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  test   %rbx,%rbx
  je     L12
  mov    %eax,%r15d
  xor    %r14d,%r14d
  lea    0x7(%rsp),%r12
  cmp    $0xffffffff,%eax
  jne    L25
  jmp    L12
  nopl   (%rax)
L59:
  add    $0x1,%r14
  cmp    $0xffffffff,%eax
  je     L12
  movzbl 0x7(%rsp),%eax
  mov    %al,-0x1(%rbx,%r14,1)
L25:
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %r15d,%edi
  movslq %r14d,%rbp
  call   <read@plt>
  test   %eax,%eax
  jne    L59
  test   %ebp,%ebp
  je     L12
  movb   $0x0,(%rbx,%rbp,1)
  mov    %r15d,%edi
  call   <close@plt>
  jmp    L48
  nopl   0x0(%rax)
L12:
  xor    %r13d,%r13d
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ft_file_to_str(char *argv) {
  int i;
  int fd;
  char *temp;
  char c;
  int ret;
  i = 0;
  temp = (char *)malloc(sizeof(temp) * ft_file_len(argv));
  fd = open(argv, O_RDONLY, S_IRUSR);
  if (!temp || fd == -1)
    return (0);
  while ((ret = read(fd, &c, 1))) {
    if (ret == -1)
      return (0);
    temp[i] = c;
    i++;
  }
  if (!ret && i == 0) {
    return (0);
  }
  temp[i] = '\0';
  close(fd);
  return (temp);
}
```