ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movsd  D12(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%edx
  movsd  -0x20(%rbp),%xmm1
  movsd  D17(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movq   %xmm0,%rbx
  mov    -0x24(%rbp),%edx
  movsd  D17(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  divsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_infered: byte[8]
name: read_data
arguments: label: D16
type_infered: string
name: read_data
arguments: label: D17
type_infered: byte[8]
name: read_data
arguments: label: D4
type_infered: f64
name: read_data
arguments: label: D63
type_infered: string

tool: {"D12": [0xa8,0xf4,0x97,0x9b,0x77,0xe3,0x01,0x40]}

tool: D16: %d

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D4: 2

tool: D63: %.1lf


assistant: ```c
int main(void) {
  int n;
  double sqrt5 = sqrt(5.0);
  scanf("%d", &n);
  printf("%.1lf\n", (pow((1 + sqrt5) / 2.0, n) - pow((1 - sqrt5) / 2.0, n)) / sqrt5);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    $0x1,%edi
  call   <pow@plt>
  movq   %xmm0,%rbx
  mov    0x4(%rsp),%esi
  mov    $0x0,%edi
  call   <pow@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  divsd  D9(%rip),%xmm0
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
datatype: string

tool: D0: %d

tool: {"D9": [0xa8,0xf4,0x97,0x9b,0x77,0xe3,0x01,0x40]}

tool: D6: %.1lf


assistant: ```c
int main(void) {
  int n;
  double sqrt5 = sqrt(5.0);
  scanf("%d", &n);
  printf("%.1lf\n", (pow((1 + sqrt5) / 2.0, n) - pow((1 - sqrt5) / 2.0, n)) / sqrt5);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    $0x1,%edi
  call   <pow@plt>
  mov    0x14(%rsp),%esi
  xor    %edi,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  lea    D26(%rip),%rdi
  subsd  %xmm0,%xmm1
  divsd  D24(%rip),%xmm1
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D24
type: byte[8]

tool: D2: %d

tool: D26: %.1lf


tool: {"D24": [0xa8,0xf4,0x97,0x9b,0x77,0xe3,0x01,0x40]}

assistant: ```c
int main(void) {
  int n;
  double sqrt5 = sqrt(5.0);
  scanf("%d", &n);
  printf("%.1lf\n", (pow((1 + sqrt5) / 2.0, n) - pow((1 - sqrt5) / 2.0, n)) / sqrt5);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%esi
  mov    $0x1,%edi
  call   <pow@plt>
  mov    0x14(%rsp),%esi
  xor    %edi,%edi
  movsd  %xmm0,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  lea    D13(%rip),%rdi
  subsd  %xmm0,%xmm1
  divsd  D24(%rip),%xmm1
  movapd %xmm1,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D24
type_infered: byte[8]

tool: D3: %d

tool: D13: %.1lf


tool: {"D24": [0xa8,0xf4,0x97,0x9b,0x77,0xe3,0x01,0x40]}

assistant: ```c
int main(void) {
  int n;
  double sqrt5 = sqrt(5.0);
  scanf("%d", &n);
  printf("%.1lf\n", (pow((1 + sqrt5) / 2.0, n) - pow((1 - sqrt5) / 2.0, n)) / sqrt5);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L15:
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L15
L1:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  while ((a %= b) && (b %= a))
    ;
  return a + b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gcd>:
  endbr64
L18:
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  mov    %rdx,%rdi
  test   %rdx,%rdx
  je     L12
  mov    %rsi,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%rsi
  test   %rdx,%rdx
  jne    L18
L12:
  lea    (%rsi,%rdi,1),%rax
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  while ((a %= b) && (b %= a))
    ;
  return a + b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<gcd>:
  endbr64
  mov    %rsi,%r8
  jmp    L25
  nopl   0x0(%rax)
L18:
  mov    %r8,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%r8
  test   %rdx,%rdx
  je     L24
L25:
  mov    %rdi,%rax
  cqto
  idiv   %r8
  mov    %rdx,%rdi
  test   %rdx,%rdx
  jne    L18
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L24:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  while ((a %= b) && (b %= a))
    ;
  return a + b;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<gcd>:
  endbr64
  mov    %rsi,%r8
  jmp    L14
  nopl   0x0(%rax)
L19:
  mov    %r8,%rax
  cqto
  idiv   %rdi
  mov    %rdx,%r8
  test   %rdx,%rdx
  je     L28
L14:
  mov    %rdi,%rax
  cqto
  idiv   %r8
  mov    %rdx,%rdi
  test   %rdx,%rdx
  jne    L19
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L28:
  mov    %rdi,%r8
  mov    %r8,%rax
  ret
```

assistant: ```c
long long gcd(long long a, long long b) {
  while ((a %= b) && (b %= a))
    ;
  return a + b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <somatorio@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
datatype: string

tool: D1: Somatorio: %d

assistant: ```c
int main() {
  int x = 5;
  printf("Somatorio: %d", somatorio(x));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <somatorio@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: Somatorio: %d

assistant: ```c
int main() {
  int x = 5;
  printf("Somatorio: %d", somatorio(x));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <somatorio@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: Somatorio: %d

assistant: ```c
int main() {
  int x = 5;
  printf("Somatorio: %d", somatorio(x));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <somatorio@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: Somatorio: %d

assistant: ```c
int main() {
  int x = 5;
  printf("Somatorio: %d", somatorio(x));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<setperms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <chmod@plt>
  nop
  leave
  ret
```

assistant: ```c
void setperms(char *fname, char *mode) {
  int i;
  i = strtol(mode, 0, 8);
  chmod(fname, i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setperms>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  mov    $0x8,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <chmod@plt>
  pop    %rbx
  ret
```

assistant: ```c
void setperms(char *fname, char *mode) {
  int i;
  i = strtol(mode, 0, 8);
  chmod(fname, i);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<setperms>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <chmod@plt>
```

assistant: ```c
void setperms(char *fname, char *mode) {
  int i;
  i = strtol(mode, 0, 8);
  chmod(fname, i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<setperms>:
  endbr64
  push   %rbp
  mov    $0x8,%edx
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  xor    %esi,%esi
  call   <strtol@plt>
  mov    %rbp,%rdi
  pop    %rbp
  mov    %eax,%esi
  jmp    1070 <chmod@plt>
```

assistant: ```c
void setperms(char *fname, char *mode) {
  int i;
  i = strtol(mode, 0, 8);
  chmod(fname, i);
}
```
user: What is the c source code of the assembly code below?

```asm
<a_twist_d_on_corner>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <a_corner_unpack@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x4,%r8d
  mov    $0x7,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <four_cycle@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <a_corner_pack@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int a_twist_d_on_corner(corner)
int corner;
{
  int temp_arr[8];
  a_corner_unpack(corner, temp_arr);
  four_cycle(temp_arr, 5, 6, 7, 4);
  return a_corner_pack(temp_arr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<a_twist_d_on_corner>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <a_corner_unpack@plt>
  mov    $0x4,%r8d
  mov    $0x7,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <four_cycle@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <a_corner_pack@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x30,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int a_twist_d_on_corner(corner)
int corner;
{
  int temp_arr[8];
  a_corner_unpack(corner, temp_arr);
  four_cycle(temp_arr, 5, 6, 7, 4);
  return a_corner_pack(temp_arr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<a_twist_d_on_corner>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <a_corner_unpack@plt>
  mov    $0x6,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%r8d
  mov    $0x7,%ecx
  mov    $0x5,%esi
  call   <four_cycle@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <a_corner_pack@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x30,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int a_twist_d_on_corner(corner)
int corner;
{
  int temp_arr[8];
  a_corner_unpack(corner, temp_arr);
  four_cycle(temp_arr, 5, 6, 7, 4);
  return a_corner_pack(temp_arr);
}
```
user: What is the c source code of the assembly code below?

```asm
<a_twist_d_on_corner>:
  endbr64
  push   %rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <a_corner_unpack@plt>
  mov    $0x6,%edx
  mov    %rbp,%rdi
  xor    %eax,%eax
  mov    $0x4,%r8d
  mov    $0x7,%ecx
  mov    $0x5,%esi
  call   <four_cycle@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <a_corner_pack@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x30,%rsp
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int a_twist_d_on_corner(corner)
int corner;
{
  int temp_arr[8];
  a_corner_unpack(corner, temp_arr);
  four_cycle(temp_arr, 5, 6, 7, 4);
  return a_corner_pack(temp_arr);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<userFunctions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x428(%rbp)
  mov    %esi,-0x42c(%rbp)
  mov    %rdx,-0x438(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x438(%rbp),%rax
  mov    $0x5,%edx
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L13
  mov    -0x42c(%rbp),%edx
  mov    -0x428(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <adminFunctions@plt>
  mov    $0x0,%eax
  jmp    L35
L13:
  mov    -0x42c(%rbp),%eax
  mov    $0xa,%edx
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <writeSock@plt>
  lea    -0x410(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x410(%rbp),%rcx
  mov    -0x42c(%rbp),%eax
  mov    $0x400,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <readSock@plt>
  mov    %rax,-0x418(%rbp)
  movzbl -0x410(%rbp),%eax
  cmp    $0x22,%al
  jne    L21
  lea    -0x410(%rbp),%rdx
  mov    -0x428(%rbp),%rcx
  mov    -0x42c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <listArticles@plt>
  jmp    L13
L21:
  movzbl -0x410(%rbp),%eax
  cmp    $0x23,%al
  jne    L54
  lea    -0x410(%rbp),%rdx
  mov    -0x428(%rbp),%rcx
  mov    -0x42c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <readArticle@plt>
  jmp    L13
L54:
  movzbl -0x410(%rbp),%eax
  cmp    $0x24,%al
  jne    L1
  lea    -0x410(%rbp),%rdx
  mov    -0x428(%rbp),%rcx
  mov    -0x42c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <writeArticle@plt>
  jmp    L13
L1:
  movzbl -0x410(%rbp),%eax
  movsbl %al,%edx
  mov    -0x428(%rbp),%rax
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <logData@plt>
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L73
  call   <__stack_chk_fail@plt>
L73:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type_infered: string
name: extract_symbolic_data
arguments: label: D13
type_infered: string
name: extract_symbolic_data
arguments: label: D20
type_infered: string

tool: D19: admin

tool: D13: AA READY!

tool: D20: unknown action %x

assistant: ```c
int userFunctions(FILE *logfile, int sock, char *user) {
  char action[1024];
  size_t len;
  if (0 == strncmp(user, "admin", 5)) {
    adminFunctions(logfile, sock);
    return 0;
  }
  while (1) {
    writeSock(sock, "\x41\x41 READY!", sizeof("\x41\x41 READY!"));
    memset(action, 0, sizeof(action));
    len = readSock(sock, action, sizeof(action));
    if (action[0] == 0x22) {
      listArticles(sock, logfile, action);
    } else if (action[0] == 0x23) {
      readArticle(sock, logfile, action);
    } else if (action[0] == 0x24) {
      writeArticle(sock, logfile, action);
    } else {
      logData(logfile, "unknown action %x", action[0]);
      return;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<userFunctions>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %rdx,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    $0x5,%edx
  lea    D18(%rip),%rsi
  call   <strncmp@plt>
  lea    D17(%rip),%r13
  test   %rax,%rax
  jne    L20
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <adminFunctions@plt>
  mov    $0x0,%eax
  jmp    L53
L66:
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <listArticles@plt>
L20:
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <writeSock@plt>
  mov    %rsp,%rbp
  mov    $0x400,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x400,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <readSock@plt>
  movzbl (%rsp),%edx
  cmp    $0x22,%dl
  je     L66
  cmp    $0x23,%dl
  je     L30
  cmp    $0x24,%dl
  jne    L13
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <writeArticle@plt>
  jmp    L20
L30:
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <readArticle@plt>
  jmp    L20
L13:
  movsbl %dl,%edx
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <logData@plt>
L53:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type_infered: string
name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string

tool: D18: admin

tool: D17: AA READY!

tool: D14: unknown action %x

assistant: ```c
int userFunctions(FILE *logfile, int sock, char *user) {
  char action[1024];
  size_t len;
  if (0 == strncmp(user, "admin", 5)) {
    adminFunctions(logfile, sock);
    return 0;
  }
  while (1) {
    writeSock(sock, "\x41\x41 READY!", sizeof("\x41\x41 READY!"));
    memset(action, 0, sizeof(action));
    len = readSock(sock, action, sizeof(action));
    if (action[0] == 0x22) {
      listArticles(sock, logfile, action);
    } else if (action[0] == 0x23) {
      readArticle(sock, logfile, action);
    } else if (action[0] == 0x24) {
      writeArticle(sock, logfile, action);
    } else {
      logData(logfile, "unknown action %x", action[0]);
      return;
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<userFunctions>:
  endbr64
  push   %r13
  lea    D18(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  mov    $0x5,%edx
  push   %rbp
  mov    %esi,%ebp
  lea    D6(%rip),%rsi
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L48
L75:
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <writeSock@plt>
  mov    $0x400,%edx
  xor    %esi,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <readSock@plt>
  movsbl (%rsp),%edx
  cmp    $0x22,%dl
  je     L56
  cmp    $0x23,%dl
  je     L17
  cmp    $0x24,%dl
  jne    L55
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <writeArticle@plt>
  jmp    L75
  nop
L56:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <listArticles@plt>
  jmp    L75
  nop
L17:
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <readArticle@plt>
  jmp    L75
  nop
L55:
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <logData@plt>
L23:
  mov    0x408(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L84
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <adminFunctions@plt>
  xor    %eax,%eax
  jmp    L23
L84:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D18: AA READY!

tool: D6: admin

tool: D4: unknown action %x

assistant: ```c
int userFunctions(FILE *logfile, int sock, char *user) {
  char action[1024];
  size_t len;
  if (0 == strncmp(user, "admin", 5)) {
    adminFunctions(logfile, sock);
    return 0;
  }
  while (1) {
    writeSock(sock, "\x41\x41 READY!", sizeof("\x41\x41 READY!"));
    memset(action, 0, sizeof(action));
    len = readSock(sock, action, sizeof(action));
    if (action[0] == 0x22) {
      listArticles(sock, logfile, action);
    } else if (action[0] == 0x23) {
      readArticle(sock, logfile, action);
    } else if (action[0] == 0x24) {
      writeArticle(sock, logfile, action);
    } else {
      logData(logfile, "unknown action %x", action[0]);
      return;
    }
  }
  return 0;
}
```