ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<append_little_endian_uint32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mov    -0xc(%rbp),%edx
  sar    $0x18,%edx
  mov    %edx,(%rax)
  mov    $0x4,%eax
  pop    %rbp
  ret
```

assistant: ```c
size_t append_little_endian_uint32(uint8_t *dst, uint32_t num) {
  dst[0] = num & 0xff;
  dst[1] = (num & (0xff << 8)) >> 8;
  dst[2] = (num & (0xff << 16)) >> 16;
  dst[3] = (num & (0xff << 24)) >> 24;
  return 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<append_little_endian_uint32>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  mov    %edx,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x8(%rdi)
  sar    $0x18,%eax
  mov    %eax,0xc(%rdi)
  mov    $0x4,%eax
  ret
```

assistant: ```c
size_t append_little_endian_uint32(uint8_t *dst, uint32_t num) {
  dst[0] = num & 0xff;
  dst[1] = (num & (0xff << 8)) >> 8;
  dst[2] = (num & (0xff << 16)) >> 16;
  dst[3] = (num & (0xff << 24)) >> 24;
  return 4;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_little_endian_uint32>:
  endbr64
  mov    %esi,%eax
  movzbl %sil,%edx
  mov    %edx,(%rdi)
  movzbl %ah,%edx
  sar    $0x18,%eax
  mov    %edx,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %eax,0xc(%rdi)
  mov    $0x4,%eax
  and    $0xff,%edx
  mov    %edx,0x8(%rdi)
  ret
```

assistant: ```c
size_t append_little_endian_uint32(uint8_t *dst, uint32_t num) {
  dst[0] = num & 0xff;
  dst[1] = (num & (0xff << 8)) >> 8;
  dst[2] = (num & (0xff << 16)) >> 16;
  dst[3] = (num & (0xff << 24)) >> 24;
  return 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<append_little_endian_uint32>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  movzbl %sil,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %ah,%ecx
  sar    $0x18,%eax
  movzbl %dl,%esi
  movd   %eax,%xmm3
  movd   %ecx,%xmm2
  mov    $0x4,%eax
  movd   %esi,%xmm1
  punpckldq %xmm2,%xmm0
  punpckldq %xmm3,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
size_t append_little_endian_uint32(uint8_t *dst, uint32_t num) {
  dst[0] = num & 0xff;
  dst[1] = (num & (0xff << 8)) >> 8;
  dst[2] = (num & (0xff << 16)) >> 16;
  dst[3] = (num & (0xff << 24)) >> 24;
  return 4;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge_assignments>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8,-0x38(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jle    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void merge_assignments(int *assignment, int *subassign, int *subsets, int subnvtxs, int *loc2glob) {
  int i;
  for (i = 1; i <= subnvtxs; i++) {
    assignment[loc2glob[i]] = subsets[subassign[i]];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<merge_assignments>:
  endbr64
  mov    %rsi,%r9
  test   %ecx,%ecx
  jle    L7
  lea    0x1(%rcx),%r10d
  mov    $0x1,%eax
L9:
  movslq (%r9,%rax,4),%rcx
  mov    (%rdx,%rcx,4),%esi
  movslq (%r8,%rax,4),%rcx
  mov    %esi,(%rdi,%rcx,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L9
L7:
  ret
```

assistant: ```c
void merge_assignments(int *assignment, int *subassign, int *subsets, int subnvtxs, int *loc2glob) {
  int i;
  for (i = 1; i <= subnvtxs; i++) {
    assignment[loc2glob[i]] = subsets[subassign[i]];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<merge_assignments>:
  endbr64
  mov    %rsi,%r9
  test   %ecx,%ecx
  jle    L8
  lea    0x1(%rcx),%r10d
  mov    $0x1,%eax
  nopl   0x0(%rax)
L4:
  movslq (%r9,%rax,4),%rcx
  mov    (%rdx,%rcx,4),%esi
  movslq (%r8,%rax,4),%rcx
  add    $0x1,%rax
  mov    %esi,(%rdi,%rcx,4)
  cmp    %rax,%r10
  jne    L4
L8:
  ret
```

assistant: ```c
void merge_assignments(int *assignment, int *subassign, int *subsets, int subnvtxs, int *loc2glob) {
  int i;
  for (i = 1; i <= subnvtxs; i++) {
    assignment[loc2glob[i]] = subsets[subassign[i]];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<merge_assignments>:
  endbr64
  mov    %rsi,%r9
  test   %ecx,%ecx
  jle    L18
  lea    0x1(%rcx),%r10d
  mov    $0x1,%eax
  nopl   0x0(%rax)
L14:
  movslq (%r9,%rax,4),%rcx
  mov    (%rdx,%rcx,4),%esi
  movslq (%r8,%rax,4),%rcx
  add    $0x1,%rax
  mov    %esi,(%rdi,%rcx,4)
  cmp    %rax,%r10
  jne    L14
L18:
  ret
```

assistant: ```c
void merge_assignments(int *assignment, int *subassign, int *subsets, int subnvtxs, int *loc2glob) {
  int i;
  for (i = 1; i <= subnvtxs; i++) {
    assignment[loc2glob[i]] = subsets[subassign[i]];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: Hello World 


assistant: ```c
int main() {
  printf("Hello World \n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
datatype: string

tool: D9: Hello World 


assistant: ```c
int main() {
  printf("Hello World \n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_infered: string

tool: D5: Hello World 


assistant: ```c
int main() {
  printf("Hello World \n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: Hello World 


assistant: ```c
int main() {
  printf("Hello World \n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x74(%rbp)
  lea    -0x7c(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L95
L0:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L53
L10:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x41,%al
  je     L9
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x44,%al
  je     L9
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x4f,%al
  je     L9
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x50,%al
  je     L9
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x51,%al
  je     L9
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x52,%al
  jne    L33
L9:
  addl   $0x1,-0x74(%rbp)
L33:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x42,%al
  jne    L110
  addl   $0x2,-0x74(%rbp)
L110:
  addl   $0x1,-0x78(%rbp)
L53:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L10
  mov    -0x74(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x74(%rbp)
  movl   $0x0,-0x78(%rbp)
L95:
  mov    -0x7c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x7c(%rbp)
  test   %eax,%eax
  jne    L0
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L87
  call   <__stack_chk_fail@plt>
L87:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D10
datatype: string

tool: D14: %d

tool: D2: %s

tool: D10: %d


assistant: ```c
int main(void) {
  int testCases;
  int ch = 0;
  int count = 0;
  char str[100];
  scanf("%d", &testCases);
  while (testCases--) {
    scanf("%s", &str);
    while (str[ch] != '\0') {
      if (str[ch] == 'A' || str[ch] == 'D' || str[ch] == 'O' || str[ch] == 'P' || str[ch] == 'Q' || str[ch] == 'R')
        count += 1;
      if (str[ch] == 'B')
        count += 2;
      ch++;
    }
    printf("%d\n", count);
    count = 0;
    ch = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L34
  lea    D24(%rip),%r12
  mov    $0x3c009,%ebx
  lea    D8(%rip),%rbp
  jmp    L17
L88:
  lea    0x2(%rsi),%edx
  cmp    $0x42,%al
  cmove  %edx,%esi
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  je     L4
L83:
  lea    -0x41(%rax),%ecx
  cmp    $0x11,%cl
  ja     L88
  mov    %rbx,%rdx
  shr    %cl,%rdx
  and    $0x1,%edx
  add    %edx,%esi
  jmp    L88
L18:
  mov    $0x0,%esi
L4:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L34
L17:
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L18
  lea    0x11(%rsp),%rdi
  mov    $0x0,%esi
  jmp    L83
L34:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D25
type_guessed: string
name: unpack_data
arguments: tag: D24
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D25: %d

tool: D24: %s

tool: D8: %d


assistant: ```c
int main(void) {
  int testCases;
  int ch = 0;
  int count = 0;
  char str[100];
  scanf("%d", &testCases);
  while (testCases--) {
    scanf("%s", &str);
    while (str[ch] != '\0') {
      if (str[ch] == 'A' || str[ch] == 'D' || str[ch] == 'O' || str[ch] == 'P' || str[ch] == 'Q' || str[ch] == 'R')
        count += 1;
      if (str[ch] == 'B')
        count += 2;
      ch++;
    }
    printf("%d\n", count);
    count = 0;
    ch = 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L64
  lea    0x10(%rsp),%r12
  lea    D7(%rip),%rbp
  mov    $0x3c009,%r13d
  lea    D23(%rip),%rbx
  xchg   %ax,%ax
L56:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L24
  lea    0x11(%rsp),%rdi
  xor    %esi,%esi
  nopl   (%rax)
L2:
  lea    -0x41(%rax),%ecx
  cmp    $0x11,%cl
  ja     L33
  mov    %r13,%rdx
  shr    %cl,%rdx
  and    $0x1,%edx
  cmp    $0x1,%dl
  sbb    $0xffffffff,%esi
  cmp    $0x42,%al
  lea    0x2(%rsi),%edx
  cmove  %edx,%esi
L33:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L2
L25:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L56
L64:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L24:
  xor    %esi,%esi
  jmp    L25
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: string
name: parse_data
arguments: data_tag: D7
datatype: string
name: parse_data
arguments: data_tag: D23
datatype: string

tool: D14: %d

tool: D7: %s

tool: D23: %d


assistant: ```c
int main(void) {
  int testCases;
  int ch = 0;
  int count = 0;
  char str[100];
  scanf("%d", &testCases);
  while (testCases--) {
    scanf("%s", &str);
    while (str[ch] != '\0') {
      if (str[ch] == 'A' || str[ch] == 'D' || str[ch] == 'O' || str[ch] == 'P' || str[ch] == 'Q' || str[ch] == 'R')
        count += 1;
      if (str[ch] == 'B')
        count += 2;
      ch++;
    }
    printf("%d\n", count);
    count = 0;
    ch = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D19(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L38
  lea    0x10(%rsp),%r12
  lea    D27(%rip),%rbp
  mov    $0x3c009,%r13d
  lea    D5(%rip),%rbx
  xchg   %ax,%ax
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L66
  lea    0x11(%rsp),%rdi
  xor    %esi,%esi
  nopl   (%rax)
L40:
  lea    -0x41(%rax),%ecx
  cmp    $0x11,%cl
  ja     L53
  mov    %r13,%rdx
  shr    %cl,%rdx
  and    $0x1,%edx
  cmp    $0x1,%dl
  sbb    $0xffffffff,%esi
  cmp    $0x42,%al
  lea    0x2(%rsi),%edx
  cmove  %edx,%esi
L53:
  movzbl (%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L40
L5:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L10
L38:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L66:
  xor    %esi,%esi
  jmp    L5
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string
name: retrieve_data
arguments: data_tag: D5
type_infered: string

tool: D19: %d

tool: D27: %s

tool: D5: %d


assistant: ```c
int main(void) {
  int testCases;
  int ch = 0;
  int count = 0;
  char str[100];
  scanf("%d", &testCases);
  while (testCases--) {
    scanf("%s", &str);
    while (str[ch] != '\0') {
      if (str[ch] == 'A' || str[ch] == 'D' || str[ch] == 'O' || str[ch] == 'P' || str[ch] == 'Q' || str[ch] == 'R')
        count += 1;
      if (str[ch] == 'B')
        count += 2;
      ch++;
    }
    printf("%d\n", count);
    count = 0;
    ch = 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BSD_erand48>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BSD_dorand48@plt>
  mov    -0x8(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rax
  mov    $0xffffffd0,%edi
  movq   %rax,%xmm0
  call   <BSD_ldexp@plt>
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  pxor   %xmm3,%xmm3
  cvtsi2sd %eax,%xmm3
  movq   %xmm3,%rax
  mov    $0xffffffe0,%edi
  movq   %rax,%xmm0
  call   <BSD_ldexp@plt>
  movapd %xmm0,%xmm1
  addsd  -0x10(%rbp),%xmm1
  movsd  %xmm1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm5
  movq   %xmm5,%rax
  mov    $0xfffffff0,%edi
  movq   %rax,%xmm0
  call   <BSD_ldexp@plt>
  addsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double BSD_erand48(unsigned short xseed[3]) {
  BSD_dorand48(xseed);
  return BSD_ldexp((double)xseed[0], -48) + BSD_ldexp((double)xseed[1], -32) + BSD_ldexp((double)xseed[2], -16);
}
```
user: What is the c source code of the assembly code below?

```asm
<BSD_erand48>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  call   <BSD_dorand48@plt>
  movzwl (%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0xffffffd0,%edi
  call   <BSD_ldexp@plt>
  movq   %xmm0,%r14
  movzwl 0x2(%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0xffffffe0,%edi
  call   <BSD_ldexp@plt>
  movq   %r14,%xmm2
  addsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movzwl 0x4(%rbx),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    $0xfffffff0,%edi
  call   <BSD_ldexp@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
double BSD_erand48(unsigned short xseed[3]) {
  BSD_dorand48(xseed);
  return BSD_ldexp((double)xseed[0], -48) + BSD_ldexp((double)xseed[1], -32) + BSD_ldexp((double)xseed[2], -16);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<BSD_erand48>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  call   <BSD_dorand48@plt>
  movzwl (%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    $0xffffffd0,%edi
  cvtsi2sd %eax,%xmm0
  call   <BSD_ldexp@plt>
  movzwl 0x2(%rbx),%eax
  mov    $0xffffffe0,%edi
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  call   <BSD_ldexp@plt>
  movsd  0x8(%rsp),%xmm1
  movzwl 0x4(%rbx),%eax
  mov    $0xfffffff0,%edi
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <BSD_ldexp@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double BSD_erand48(unsigned short xseed[3]) {
  BSD_dorand48(xseed);
  return BSD_ldexp((double)xseed[0], -48) + BSD_ldexp((double)xseed[1], -32) + BSD_ldexp((double)xseed[2], -16);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BSD_erand48>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  call   <BSD_dorand48@plt>
  movzwl (%rbx),%eax
  pxor   %xmm0,%xmm0
  mov    $0xffffffd0,%edi
  cvtsi2sd %eax,%xmm0
  call   <BSD_ldexp@plt>
  movzwl 0x2(%rbx),%eax
  mov    $0xffffffe0,%edi
  movsd  %xmm0,0x8(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  call   <BSD_ldexp@plt>
  movsd  0x8(%rsp),%xmm1
  movzwl 0x4(%rbx),%eax
  mov    $0xfffffff0,%edi
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <BSD_ldexp@plt>
  addsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
double BSD_erand48(unsigned short xseed[3]) {
  BSD_dorand48(xseed);
  return BSD_ldexp((double)xseed[0], -48) + BSD_ldexp((double)xseed[1], -32) + BSD_ldexp((double)xseed[2], -16);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0xbb8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  mov    $0xbb8,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: What is the c source code of the assembly code below?

```asm
<rk31sdk_get_sdio_wifi_voltage>:
  endbr64
  mov    $0xbb8,%eax
  ret
```

assistant: ```c
int rk31sdk_get_sdio_wifi_voltage(void) {
  int voltage;
  voltage = 3000;
  return voltage;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L20
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L46
L20:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L16
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L46
L16:
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L46:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D24
datatype: string
name: unpack_data
arguments: label: D9
datatype: string
name: unpack_data
arguments: label: D4
datatype: string

tool: D2: %d

tool: D24: The number is positive.


tool: D9: The number is negative.


tool: D4: The number is zero!.


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n > 0) {
    printf("The number is positive.\n");
  } else if (n < 0) {
    printf("The number is negative.\n");
  } else {
    printf("The number is zero!.\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L48
  js     L44
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L48:
  lea    D18(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L44:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type_infered: string
name: disassemble_data
arguments: data_tag: D31
type_infered: string
name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D10
type_infered: string

tool: D23: %d

tool: D31: The number is zero!.


tool: D18: The number is positive.


tool: D10: The number is negative.


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n > 0) {
    printf("The number is positive.\n");
  } else if (n < 0) {
    printf("The number is negative.\n");
  } else {
    printf("The number is zero!.\n");
  }
  return 0;
}
```