ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CRT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L23
L24:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L24
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L45:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edi
  mov    -0x18(%rbp),%eax
  cltd
  idiv   %edi
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%esi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <exgcd@plt>
  mov    -0x20(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x14(%rbp)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L45
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
int CRT(int a[], int m[], int n) {
  int M = 1, ret = 0, i;
  int x, y, tm;
  for (i = 0; i < n; i++)
    M *= m[i];
  for (i = 0; i < n; i++) {
    tm = M / m[i];
    exgcd(tm, m[i], &x, &y);
    ret = (ret + tm * x * a[i]) % M;
  }
  return (ret + M) % M;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CRT>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L42
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %rsi,%rax
  lea    -0x1(%rdx),%ecx
  lea    0x4(%rsi,%rcx,4),%rcx
  mov    $0x1,%ebp
L43:
  imul   (%rax),%ebp
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L43
  mov    %edx,%eax
  mov    %rax,(%rsp)
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
L2:
  mov    (%r14,%r12,4),%esi
  mov    %ebp,%eax
  cltd
  idiv   %esi
  mov    %eax,%ebx
  lea    0x10(%rsp),%rdx
  mov    0x8(%rsp),%rcx
  mov    %eax,%edi
  call   <exgcd@plt>
  imul   0x10(%rsp),%ebx
  imul   (%r15,%r12,4),%ebx
  lea    (%rbx,%r13,1),%eax
  cltd
  idiv   %ebp
  mov    %edx,%r13d
  add    $0x1,%r12
  cmp    (%rsp),%r12
  jne    L2
L40:
  lea    0x0(%rbp,%r13,1),%eax
  cltd
  idiv   %ebp
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %edx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  mov    $0x1,%ebp
  mov    $0x0,%r13d
  jmp    L40
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CRT(int a[], int m[], int n) {
  int M = 1, ret = 0, i;
  int x, y, tm;
  for (i = 0; i < n; i++)
    M *= m[i];
  for (i = 0; i < n; i++) {
    tm = M / m[i];
    exgcd(tm, m[i], &x, &y);
    ret = (ret + tm * x * a[i]) % M;
  }
  return (ret + M) % M;
}
```
user: What is the c source code of the assembly code below:

```asm
<CRT>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L12
  lea    -0x1(%rdx),%ecx
  mov    %rsi,%r15
  mov    %rsi,%rax
  mov    $0x1,%ebx
  lea    0x4(%rsi,%rcx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L9:
  imul   (%rax),%ebx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L9
  mov    %edx,%eax
  lea    0x24(%rsp),%r14
  lea    0x20(%rsp),%r13
  xor    %ebp,%ebp
  mov    %rax,0x18(%rsp)
  movl   $0x0,0xc(%rsp)
  nop
L17:
  mov    (%r15,%rbp,4),%esi
  mov    %ebx,%eax
  mov    %r14,%rcx
  cltd
  idiv   %esi
  mov    %r13,%rdx
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <exgcd@plt>
  mov    0x10(%rsp),%rax
  imul   0x20(%rsp),%r12d
  imul   (%rax,%rbp,4),%r12d
  mov    0xc(%rsp),%eax
  add    $0x1,%rbp
  add    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %edx,0xc(%rsp)
  cmp    %rbp,0x18(%rsp)
  jne    L17
  mov    %edx,%eax
  add    %ebx,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r9d
L40:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x38,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L12:
  xor    %r9d,%r9d
  jmp    L40
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int CRT(int a[], int m[], int n) {
  int M = 1, ret = 0, i;
  int x, y, tm;
  for (i = 0; i < n; i++)
    M *= m[i];
  for (i = 0; i < n; i++) {
    tm = M / m[i];
    exgcd(tm, m[i], &x, &y);
    ret = (ret + tm * x * a[i]) % M;
  }
  return (ret + M) % M;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<CRT>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L9
  lea    -0x1(%rdx),%eax
  mov    %rsi,%r15
  cmp    $0x1a,%eax
  jbe    L21
  mov    %edx,%ecx
  movdqa D1(%rip),%xmm1
  mov    %rsi,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L8:
  movdqu (%rax),%xmm2
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm0
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  cmp    %rcx,%rax
  jne    L8
  movdqa %xmm1,%xmm0
  mov    %edx,%eax
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%eax
  movdqa %xmm0,%xmm2
  psrlq  $0x20,%xmm0
  pmuludq %xmm1,%xmm2
  psrlq  $0x20,%xmm1
  pmuludq %xmm1,%xmm0
  pshufd $0x8,%xmm2,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  pmuludq %xmm1,%xmm0
  movd   %xmm0,%ebx
  test   $0x3,%dl
  je     L48
L50:
  cltq
  nopl   0x0(%rax,%rax,1)
L64:
  imul   (%r15,%rax,4),%ebx
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L64
L48:
  mov    %edx,%eax
  lea    0x24(%rsp),%r14
  lea    0x20(%rsp),%r13
  xor    %ebp,%ebp
  mov    %rax,0x18(%rsp)
  movl   $0x0,0xc(%rsp)
  nopl   0x0(%rax,%rax,1)
L45:
  mov    (%r15,%rbp,4),%esi
  mov    %ebx,%eax
  mov    %r14,%rcx
  cltd
  idiv   %esi
  mov    %r13,%rdx
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <exgcd@plt>
  mov    0x10(%rsp),%rax
  imul   0x20(%rsp),%r12d
  imul   (%rax,%rbp,4),%r12d
  mov    0xc(%rsp),%eax
  add    $0x1,%rbp
  add    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %edx,0xc(%rsp)
  cmp    %rbp,0x18(%rsp)
  jne    L45
  mov    %edx,%eax
  add    %ebx,%eax
  cltd
  idiv   %ebx
  mov    %edx,%r9d
L79:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x38,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L9:
  xor    %r9d,%r9d
  jmp    L79
L21:
  xor    %eax,%eax
  mov    $0x1,%ebx
  jmp    L50
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: byte[16]

tool: {"D1": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int CRT(int a[], int m[], int n) {
  int M = 1, ret = 0, i;
  int x, y, tm;
  for (i = 0; i < n; i++)
    M *= m[i];
  for (i = 0; i < n; i++) {
    tm = M / m[i];
    exgcd(tm, m[i], &x, &y);
    ret = (ret + tm * x * a[i]) % M;
  }
  return (ret + M) % M;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  je     L21
  cmpl   $0x2,-0x8(%rbp)
  jne    L13
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L31
L21:
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D21(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L31
L13:
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%rax
  lea    D27(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
L31:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D4
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string
name: parse_data
arguments: data_tag: D27
datatype: string

tool: D4: %o

tool: D21: %x

tool: D27: %d

assistant: ```c
void num_to_string(int num_conv, int cvt_type, char *str_tmp) {
  switch (cvt_type) {
  case 2:
    sprintf(str_tmp, "%o", num_conv);
    break;
  case 1:
    sprintf(str_tmp, "%x", num_conv);
    break;
  case 0:
  default:
    sprintf(str_tmp, "%d", num_conv);
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<num_to_string>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rdx,%rdi
  cmp    $0x1,%esi
  je     L29
  cmp    $0x2,%esi
  jne    L2
  mov    %eax,%edx
  lea    D21(%rip),%rsi
  call   <sprintf@plt>
L11:
  add    $0x8,%rsp
  ret
L29:
  mov    %eax,%edx
  lea    D26(%rip),%rsi
  call   <sprintf@plt>
  jmp    L11
L2:
  mov    %eax,%edx
  lea    D8(%rip),%rsi
  call   <sprintf@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D26
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D21: %o

tool: D26: %x

tool: D8: %d

assistant: ```c
void num_to_string(int num_conv, int cvt_type, char *str_tmp) {
  switch (cvt_type) {
  case 2:
    sprintf(str_tmp, "%o", num_conv);
    break;
  case 1:
    sprintf(str_tmp, "%x", num_conv);
    break;
  case 0:
  default:
    sprintf(str_tmp, "%d", num_conv);
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<num_to_string>:
  endbr64
  mov    %edi,%r8d
  mov    %rdx,%rdi
  mov    %r8d,%edx
  cmp    $0x1,%esi
  je     L18
  cmp    $0x2,%esi
  jne    L4
  lea    D24(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   0x0(%rax,%rax,1)
L18:
  lea    D19(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   0x0(%rax)
L4:
  lea    D6(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D19
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D24: %o

tool: D19: %x

tool: D6: %d

assistant: ```c
void num_to_string(int num_conv, int cvt_type, char *str_tmp) {
  switch (cvt_type) {
  case 2:
    sprintf(str_tmp, "%o", num_conv);
    break;
  case 1:
    sprintf(str_tmp, "%x", num_conv);
    break;
  case 0:
  default:
    sprintf(str_tmp, "%d", num_conv);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<num_to_string>:
  endbr64
  mov    %edi,%r8d
  mov    %rdx,%rdi
  mov    %r8d,%edx
  cmp    $0x1,%esi
  je     L6
  cmp    $0x2,%esi
  jne    L5
  lea    D21(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  lea    D2(%rip),%rsi
  jmp    1050 <sprintf@plt>
  nopl   0x0(%rax)
L5:
  lea    D13(%rip),%rsi
  jmp    1050 <sprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: string

tool: D21: %o

tool: D2: %x

tool: D13: %d

assistant: ```c
void num_to_string(int num_conv, int cvt_type, char *str_tmp) {
  switch (cvt_type) {
  case 2:
    sprintf(str_tmp, "%o", num_conv);
    break;
  case 1:
    sprintf(str_tmp, "%x", num_conv);
    break;
  case 0:
  default:
    sprintf(str_tmp, "%d", num_conv);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xc_log_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <closelog@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void xc_log_exit(void) {
  closelog();
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xc_log_exit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <closelog@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void xc_log_exit(void) {
  closelog();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xc_log_exit>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <closelog@plt>
```

assistant: ```c
void xc_log_exit(void) {
  closelog();
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xc_log_exit>:
  endbr64
  xor    %eax,%eax
  jmp    1050 <closelog@plt>
```

assistant: ```c
void xc_log_exit(void) {
  closelog();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<path_040_expected_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void path_040_expected_1(int y) {
  do {
    y++;
  } while (1 - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<path_040_expected_1>:
  endbr64
  ret
```

assistant: ```c
void path_040_expected_1(int y) {
  do {
    y++;
  } while (1 - 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<path_040_expected_1>:
  endbr64
  ret
```

assistant: ```c
void path_040_expected_1(int y) {
  do {
    y++;
  } while (1 - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<path_040_expected_1>:
  endbr64
  ret
```

assistant: ```c
void path_040_expected_1(int y) {
  do {
    y++;
  } while (1 - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <makeList@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printList@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <removeDuplicates@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printList@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  struct node *listHead = makeList();
  printList(listHead);
  removeDuplicates(listHead);
  printList(listHead);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <makeList@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <printList@plt>
  mov    %rbx,%rdi
  call   <removeDuplicates@plt>
  mov    %rbx,%rdi
  call   <printList@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  struct node *listHead = makeList();
  printList(listHead);
  removeDuplicates(listHead);
  printList(listHead);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <makeList@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <printList@plt>
  mov    %rbp,%rdi
  call   <removeDuplicates@plt>
  mov    %rbp,%rdi
  call   <printList@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  struct node *listHead = makeList();
  printList(listHead);
  removeDuplicates(listHead);
  printList(listHead);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <makeList@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <printList@plt>
  mov    %rbp,%rdi
  call   <removeDuplicates@plt>
  mov    %rbp,%rdi
  call   <printList@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  struct node *listHead = makeList();
  printList(listHead);
  removeDuplicates(listHead);
  printList(listHead);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L2:
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0xff,-0x4(%rbp)
  jle    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %c%10d


assistant: ```c
int main() {
  int g;
  for (g = 0; g <= 255; g++) {
    printf("%c%10d\n", g, g);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L5:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: string

tool: D8: %c%10d


assistant: ```c
int main() {
  int g;
  for (g = 0; g <= 255; g++) {
    printf("%c%10d\n", g, g);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: %c%10d


assistant: ```c
int main() {
  int g;
  for (g = 0; g <= 255; g++) {
    printf("%c%10d\n", g, g);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_infered: string

tool: D7: %c%10d


assistant: ```c
int main() {
  int g;
  for (g = 0; g <= 255; g++) {
    printf("%c%10d\n", g, g);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fcitx_dict_item_default_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  cmp    %rax,%rdx
  cmovbe %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L20
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jae    L6
  movl   $0xffffffff,-0xc(%rbp)
  jmp    L20
L6:
  mov    -0x20(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jbe    L20
  movl   $0x1,-0xc(%rbp)
L20:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fcitx_dict_item_default_compare(const char *keyA, size_t keyALen, const void *dataA, const char *keyB, size_t keyBLen, const void *dataB, void *userData) {
  (void)(dataA);
  (void)(dataB);
  (void)(userData);
  size_t size = (keyALen < keyBLen) ? keyALen : keyBLen;
  int result = memcmp(keyA, keyB, size);
  if (result == 0) {
    if (keyALen < keyBLen) {
      result = -1;
    } else if (keyALen > keyBLen) {
      result = 1;
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fcitx_dict_item_default_compare>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    %r8,%rbp
  cmp    %rbx,%r8
  mov    %rbx,%rdx
  cmovbe %r8,%rdx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L10
  cmp    %rbx,%rbp
  ja     L25
  setb   %al
  movzbl %al,%eax
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0xffffffff,%eax
  jmp    L10
```

assistant: ```c
int fcitx_dict_item_default_compare(const char *keyA, size_t keyALen, const void *dataA, const char *keyB, size_t keyBLen, const void *dataB, void *userData) {
  (void)(dataA);
  (void)(dataB);
  (void)(userData);
  size_t size = (keyALen < keyBLen) ? keyALen : keyBLen;
  int result = memcmp(keyA, keyB, size);
  if (result == 0) {
    if (keyALen < keyBLen) {
      result = -1;
    } else if (keyALen > keyBLen) {
      result = 1;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fcitx_dict_item_default_compare>:
  endbr64
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    %rbx,%rdx
  sub    $0x8,%rsp
  cmp    %rbx,%r8
  cmovbe %r8,%rdx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L3
  cmp    %rbx,%rbp
  ja     L17
  setb   %al
  movzbl %al,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int fcitx_dict_item_default_compare(const char *keyA, size_t keyALen, const void *dataA, const char *keyB, size_t keyBLen, const void *dataB, void *userData) {
  (void)(dataA);
  (void)(dataB);
  (void)(userData);
  size_t size = (keyALen < keyBLen) ? keyALen : keyBLen;
  int result = memcmp(keyA, keyB, size);
  if (result == 0) {
    if (keyALen < keyBLen) {
      result = -1;
    } else if (keyALen > keyBLen) {
      result = 1;
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fcitx_dict_item_default_compare>:
  endbr64
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    %rbx,%rdx
  sub    $0x8,%rsp
  cmp    %rbx,%r8
  cmovbe %r8,%rdx
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L3
  cmp    %rbx,%rbp
  ja     L26
  setb   %al
  movzbl %al,%eax
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int fcitx_dict_item_default_compare(const char *keyA, size_t keyALen, const void *dataA, const char *keyB, size_t keyBLen, const void *dataB, void *userData) {
  (void)(dataA);
  (void)(dataB);
  (void)(userData);
  size_t size = (keyALen < keyBLen) ? keyALen : keyBLen;
  int result = memcmp(keyA, keyB, size);
  if (result == 0) {
    if (keyALen < keyBLen) {
      result = -1;
    } else if (keyALen > keyBLen) {
      result = 1;
    }
  }
  return result;
}
```