user: 请从给定的汇编指令推导出C源代码：

```asm
<test_floatarr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L5:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L38:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L52
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L52:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  movss  D17(%rip),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x1,-0x34(%rbp)
  jmp    L10
L49:
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm1
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  movslq %edx,%rdx
  movss  (%rax,%rdx,4),%xmm0
  mulss  %xmm0,%xmm1
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D13(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  D26(%rip),%xmm1
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    -0x20(%rbp),%rax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  movss  %xmm0,(%rax,%rdx,4)
  addl   $0x1,-0x34(%rbp)
L10:
  mov    -0x34(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L49
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x34(%rbp)
  jmp    L16
L64:
  mov    -0x30(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x30(%rbp)
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x34(%rbp)
L16:
  mov    -0x34(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L64
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: f32
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D17: 2.5

tool: D13: 1.25

tool: D26: 0.19

tool: D12: arr: 

tool: D3: %08X

assistant: ```c
void test_floatarr(int len) {
  float arr[len];
  unsigned int *iarr = (unsigned int *)&arr;
  int i;
  arr[0] = 2.5;
  for (i = 1; i < len; i++) {
    arr[i] = (arr[i - 1] * arr[i - 1] + arr[0]) / 1.25 - 0.19;
  }
  printf("arr: ");
  for (i = 0; i < len; i++) {
    printf("%08X", *iarr++);
    printf(" ");
  }
  printf("\n");
}
```