user: 请将以下的汇编代码转换成C语言代码：

```asm
<process>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1d8,%rsp
  mov    %edi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x1c8(%rsp)
  xor    %eax,%eax
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L118
  add    $0x1,%rsi
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  mov    $0x0,%r9d
  jmp    L222
L18:
  lea    0x1(%rax),%edi
  mov    %r11d,%edx
  mov    %r9d,%r8d
L180:
  movslq %ecx,%rcx
  cltq
  shl    $0x6,%rax
  lea    0x1d0(%rax),%rax
  add    %rsp,%rax
  mov    %dl,-0x1d0(%rcx,%rax,1)
  cmp    $0x6,%edi
  jg     L134
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%edx
  test   %dl,%dl
  je     L214
  mov    %r8d,%ecx
  mov    %edi,%eax
L222:
  cmp    $0x20,%dl
  je     L18
  cmp    $0xa,%dl
  je     L121
  cmp    $0xd,%dl
  je     L121
  lea    0x1(%rcx),%r8d
  mov    %eax,%edi
  jmp    L180
L121:
  movslq %ecx,%rdi
  movslq %eax,%rsi
  shl    $0x6,%rsi
  lea    0x1d0(%rsi),%rbx
  lea    (%rsp,%rbx,1),%rsi
  movb   $0x0,-0x1d0(%rdi,%rsi,1)
  lea    0x1(%rax),%edi
  test   %dl,%dl
  jne    L80
  mov    %ecx,%r8d
  jmp    L214
L134:
  mov    %r10d,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L215
L223:
  lea    D44(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L215
L161:
  lea    0x1(%r11),%r8d
  add    $0x40,%r10
  sub    $0x40,%rsi
  add    $0x40,%rdi
  cmp    $0x6,%r11d
  jne    L65
  mov    %r9d,%esi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x1c0(%rbx),%r12
  lea    D12(%rip),%rbp
L61:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x40,%rbx
  cmp    %rbx,%r12
  jne    L61
  mov    $0xa,%edi
  call   <putchar@plt>
L215:
  mov    0x1c8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L174
  add    $0x1d8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  add    $0x1,%r8d
  add    $0x40,%rcx
  cmp    $0x6,%r8d
  jg     L161
L9:
  test   %r9d,%r9d
  jle    L74
  mov    %r10,%rax
L95:
  lea    (%rax,%rsi,1),%rdx
  movzbl (%rdx,%rcx,1),%edx
  cmp    %dl,(%rax)
  jne    L48
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L95
L74:
  add    $0x1,%r9d
  add    $0x1,%rbp
  cmp    $0x40,%r9d
  je     L223
L69:
  mov    %rsp,%rbx
  lea    0x0(%r13,%rbp,1),%rdi
  mov    %rbx,%r10
  mov    $0x0,%esi
  mov    $0x1,%r8d
L65:
  mov    %r8d,%r11d
  mov    %r12,%rcx
  sub    %rsi,%rcx
  jmp    L9
L118:
  mov    $0x0,%r8d
  mov    $0x0,%edi
L214:
  movslq %r8d,%r8
  movslq %edi,%rax
  shl    $0x6,%rax
  lea    0x1d0(%rax),%rax
  add    %rsp,%rax
  movb   $0x0,-0x1d0(%r8,%rax,1)
  add    $0x1,%edi
L80:
  mov    $0x0,%ebp
  mov    $0x1,%r9d
  lea    0x1(%rsp),%r13
  mov    $0x40,%r12d
  cmp    $0x6,%edi
  jg     L69
  mov    %r10d,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L215
L174:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D44
data_type: string
name: parse_data
arguments: data_label: D40
data_type: string
name: parse_data
arguments: data_label: D12
data_type: string

tool: D9: There aren't 7 days in line %d


tool: D44: Failed to find uniqueness within the bounds.

tool: D40: %2d 

tool: D12:  %s

assistant: ```c
void process(int lineNum, char buffer[]) {
  char days[7][64];
  int i = 0, d = 0, j = 0;
  while (buffer[i] != 0) {
    if (buffer[i] == ' ') {
      days[d][j] = '\0';
      ++d;
      j = 0;
    } else if (buffer[i] == '\n' || buffer[i] == '\r') {
      days[d][j] = '\0';
      ++d;
      break;
    } else {
      days[d][j] = buffer[i];
      ++j;
    }
    if (d >= 7) {
      printf("There aren't 7 days in line %d\n", lineNum);
      return;
    }
    ++i;
  }
  if (buffer[i] == '\0') {
    days[d][j] = '\0';
    ++d;
  }
  if (d < 7) {
    printf("There aren't 7 days in line %d\n", lineNum);
    return;
  } else {
    int len = 0;
    for (len = 1; len < 64; ++len) {
      int d1;
      for (d1 = 0; d1 < 7; ++d1) {
        int d2;
        for (d2 = d1 + 1; d2 < 7; ++d2) {
          int unique = 0;
          for (i = 0; i < len; ++i) {
            if (days[d1][i] != days[d2][i]) {
              unique = 1;
              break;
            }
          }
          if (!unique) {
            goto next_length;
          }
        }
      }
      printf("%2d ", len);
      for (i = 0; i < 7; ++i) {
        printf(" %s", days[i]);
      }
      printf("\n");
      return;
    next_length : {}
    }
  }
  printf("Failed to find uniqueness within the bounds.");
}
```