ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_status_no_robust>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <pthread_mutexattr_setrobust@plt>
  test   %rax,%rax
  je     L10
L26:
  mov    $0x1,%eax
L6:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <pthread_mutex_init@plt>
  test   %rax,%rax
  jne    L26
  mov    %r12,%rdi
  call   <pthread_mutex_lock@plt>
  test   %rax,%rax
  jne    L26
  mov    %r12,%rdi
  call   <pthread_mutex_unlock@plt>
  test   %rax,%rax
  jne    L26
  mov    %r12,%rdi
  call   <pthread_mutex_destroy@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L6
```

assistant: ```c
int test_status_no_robust(pthread_mutex_t *mutex, pthread_mutexattr_t *attr) {
  int result = 1;
  if (pthread_mutexattr_setrobust(attr, PTHREAD_MUTEX_STALLED) == 0 && pthread_mutex_init(mutex, attr) == 0 && pthread_mutex_lock(mutex) == 0 && pthread_mutex_unlock(mutex) == 0 && pthread_mutex_destroy(mutex) == 0)
    result = 0;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Ipilha@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  Ipilha();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Ipilha@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  Ipilha();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Ipilha@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  Ipilha();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Ipilha@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int i;
  Ipilha();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movb   $0x0,-0x10(%rbp)
  lea    -0x30(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x21,%edx
  mov    %rax,%rdi
  call   <NAS_Hash_Hex_Ex@plt>
  mov    -0x44(%rbp),%edx
  lea    -0x30(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int _encrypt(char *data, char *e_data, int e_data_len) {
  char md_str[33] = {'\0'};
  NAS_Hash_Hex_Ex(data, md_str, sizeof(md_str), 1);
  strncpy(e_data, md_str, e_data_len);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_encrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movb   $0x0,0x20(%rsp)
  mov    %rsp,%r12
  mov    $0x1,%ecx
  mov    $0x21,%edx
  mov    %r12,%rsi
  call   <NAS_Hash_Hex_Ex@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _encrypt(char *data, char *e_data, int e_data_len) {
  char md_str[33] = {'\0'};
  NAS_Hash_Hex_Ex(data, md_str, sizeof(md_str), 1);
  strncpy(e_data, md_str, e_data_len);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_encrypt>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    $0x1,%ecx
  push   %r12
  mov    %edx,%r12d
  mov    $0x21,%edx
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movb   $0x0,0x20(%rsp)
  mov    %r13,%rsi
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <NAS_Hash_Hex_Ex@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _encrypt(char *data, char *e_data, int e_data_len) {
  char md_str[33] = {'\0'};
  NAS_Hash_Hex_Ex(data, md_str, sizeof(md_str), 1);
  strncpy(e_data, md_str, e_data_len);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_encrypt>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    $0x1,%ecx
  push   %r12
  mov    %edx,%r12d
  mov    $0x21,%edx
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  movb   $0x0,0x20(%rsp)
  mov    %r13,%rsi
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <NAS_Hash_Hex_Ex@plt>
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _encrypt(char *data, char *e_data, int e_data_len) {
  char md_str[33] = {'\0'};
  NAS_Hash_Hex_Ex(data, md_str, sizeof(md_str), 1);
  strncpy(e_data, md_str, e_data_len);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
L29:
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x5,-0x4(%rbp)
  jg     L21
  jmp    L29
L21:
  nop
  cmpl   $0x2,-0x4(%rbp)
  jmp    L29
```

assistant: ```c
int main() {
  int x = 0;
  while (1) {
    while (2) {
      x += 1;
      if (x > 5) {
        break;
      }
    }
    if (x == 2) {
      continue;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
L4:
  jmp    L4
```

assistant: ```c
int main() {
  int x = 0;
  while (1) {
    while (2) {
      x += 1;
      if (x > 5) {
        break;
      }
    }
    if (x == 2) {
      continue;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
int main() {
  int x = 0;
  while (1) {
    while (2) {
      x += 1;
      if (x > 5) {
        break;
      }
    }
    if (x == 2) {
      continue;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L5:
  jmp    L5
```

assistant: ```c
int main() {
  int x = 0;
  while (1) {
    while (2) {
      x += 1;
      if (x > 5) {
        break;
      }
    }
    if (x == 2) {
      continue;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dns_dnlabels>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L5:
  addl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0x1,%eax
  cltq
  add    %rax,-0x18(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L5
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned dns_dnlabels(const unsigned char *dn) {
  unsigned l = 0;
  while (*dn)
    ++l, dn += 1 + *dn;
  return l;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dns_dnlabels>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L27
  mov    $0x0,%edx
L4:
  add    $0x1,%edx
  movzbl %al,%eax
  lea    0x1(%rdi,%rax,1),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L4
L2:
  mov    %edx,%eax
  ret
L27:
  mov    $0x0,%edx
  jmp    L2
```

assistant: ```c
unsigned dns_dnlabels(const unsigned char *dn) {
  unsigned l = 0;
  while (*dn)
    ++l, dn += 1 + *dn;
  return l;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<dns_dnlabels>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L16
  xchg   %ax,%ax
L18:
  lea    0x1(%rdi,%rax,1),%rdi
  add    $0x1,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned dns_dnlabels(const unsigned char *dn) {
  unsigned l = 0;
  while (*dn)
    ++l, dn += 1 + *dn;
  return l;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dns_dnlabels>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  test   %al,%al
  je     L3
  xchg   %ax,%ax
L2:
  lea    0x1(%rdi,%rax,1),%rdi
  add    $0x1,%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned dns_dnlabels(const unsigned char *dn) {
  unsigned l = 0;
  while (*dn)
    ++l, dn += 1 + *dn;
  return l;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L51:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L54
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L58
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L58
  mov    $0x41,%eax
  jmp    L41
L58:
  mov    $0x61,%eax
L41:
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  sub    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    $0x4f,%ecx
  mov    %ecx,%eax
  imul   %dl
  shr    $0x8,%ax
  sar    $0x3,%al
  mov    %edx,%ecx
  sar    $0x7,%cl
  sub    %ecx,%eax
  mov    $0x1a,%ecx
  imul   %ecx,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L54:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  nop
  nop
  leave
  ret
```

assistant: ```c
void rotN(char *string, int n) {
  char *p;
  char sub;
  for (p = string; *p != 0; p++) {
    if (isalpha(*p)) {
      sub = (*p >= 65 && *p <= 90) ? 'A' : 'a';
      *p -= sub;
      *p += n;
      *p %= 26;
      *p += sub;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotN>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L43
  mov    %esi,%ebp
  mov    $0x4f,%r12d
  jmp    L38
L28:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L43
L38:
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L28
  movzbl (%rbx),%edx
  lea    -0x41(%rdx),%eax
  cmp    $0x1a,%al
  sbb    %ecx,%ecx
  and    $0xffffffe0,%ecx
  add    $0x61,%ecx
  add    %ebp,%edx
  sub    %ecx,%edx
  mov    %edx,%eax
  imul   %r12b
  sar    $0xb,%ax
  mov    %edx,%esi
  sar    $0x7,%sil
  sub    %esi,%eax
  mov    $0x1a,%esi
  imul   %esi,%eax
  sub    %eax,%edx
  add    %ecx,%edx
  mov    %dl,(%rbx)
  jmp    L28
L43:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rotN(char *string, int n) {
  char *p;
  char sub;
  for (p = string; *p != 0; p++) {
    if (isalpha(*p)) {
      sub = (*p >= 65 && *p <= 90) ? 'A' : 'a';
      *p -= sub;
      *p += n;
      *p %= 26;
      *p += sub;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotN>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L26
  mov    %esi,%ebx
  mov    $0x4f,%ebp
  nopw   0x0(%rax,%rax,1)
L11:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L3
  movzbl (%r12),%edx
  lea    -0x41(%rdx),%eax
  cmp    $0x1a,%al
  sbb    %ecx,%ecx
  add    %ebx,%edx
  and    $0xffffffe0,%ecx
  add    $0x61,%ecx
  sub    %ecx,%edx
  mov    %edx,%eax
  mov    %edx,%esi
  imul   %bpl
  sar    $0x7,%sil
  sar    $0xb,%ax
  sub    %esi,%eax
  mov    $0x1a,%esi
  imul   %esi,%eax
  sub    %eax,%edx
  add    %ecx,%edx
  mov    %dl,(%r12)
L3:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L11
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rotN(char *string, int n) {
  char *p;
  char sub;
  for (p = string; *p != 0; p++) {
    if (isalpha(*p)) {
      sub = (*p >= 65 && *p <= 90) ? 'A' : 'a';
      *p -= sub;
      *p += n;
      *p %= 26;
      *p += sub;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rotN>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L1
  mov    %esi,%ebx
  mov    $0x4f,%ebp
  nopw   0x0(%rax,%rax,1)
L23:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L6
  movzbl (%r12),%edx
  lea    -0x41(%rdx),%eax
  cmp    $0x1a,%al
  sbb    %ecx,%ecx
  add    %ebx,%edx
  and    $0xffffffe0,%ecx
  add    $0x61,%ecx
  sub    %ecx,%edx
  mov    %edx,%eax
  mov    %edx,%esi
  imul   %bpl
  sar    $0x7,%sil
  sar    $0xb,%ax
  sub    %esi,%eax
  mov    $0x1a,%esi
  imul   %esi,%eax
  sub    %eax,%edx
  add    %ecx,%edx
  mov    %dl,(%r12)
L6:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L23
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rotN(char *string, int n) {
  char *p;
  char sub;
  for (p = string; *p != 0; p++) {
    if (isalpha(*p)) {
      sub = (*p >= 65 && *p <= 90) ? 'A' : 'a';
      *p -= sub;
      *p += n;
      *p %= 26;
      *p += sub;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x1d4(%rbp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    -0x1d4(%rbp),%esi
  movslq %esi,%rdx
  lea    0xf(,%rdx,4),%rcx
  mov    %rcx,%rax
  and    $0xfffffffffffffff0,%rax
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdi
  sub    %rcx,%rdi
L85:
  cmp    %rdi,%rsp
  je     L52
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L85
L52:
  mov    %rax,%rcx
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  je     L44
  orq    $0x0,-0x8(%rsp,%rcx,1)
L44:
  mov    %rsp,%r13
  lea    -0x1d0(%rbp),%rbx
  lea    -0x40(%rbp),%r12
  mov    %rbx,%rax
L34:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %r12,%rax
  jne    L34
  lea    0xf(%rdx),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L8:
  cmp    %rcx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L8
L54:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L88
  orq    $0x0,-0x8(%rsp,%rax,1)
L88:
  mov    %rsp,-0x1e8(%rbp)
  test   %esi,%esi
  jle    L41
  mov    $0x0,%r14d
  lea    D9(%rip),%r15
L99:
  mov    -0x1e8(%rbp),%rax
  lea    (%rax,%r14,1),%rdx
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movslq 0x0(%r13),%rax
  addl   $0x1,-0x1d0(%rbp,%rax,4)
  add    $0x1,%r14
  add    $0x4,%r13
  cmp    %r14d,-0x1d4(%rbp)
  jg     L99
L41:
  mov    $0x0,%r13d
  lea    D19(%rip),%r14
  jmp    L62
L64:
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L64
  add    %edx,%r13d
L38:
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L76
L62:
  mov    (%rbx),%edx
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L64
  jmp    L38
L76:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D17: %d

tool: D9: %d %s

tool: D19: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int a[n], i, count[100];
  for (i = 0; i < 100; i++)
    count[i] = 0;
  char b[n];
  for (i = 0; i < n; i++) {
    scanf("%d %s", &a[i], &b[i]);
    count[a[i]]++;
  }
  int count1 = 0, j;
  for (i = 0; i < 100; i++) {
    for (j = 0; j < count[i]; j++)
      count1++;
    printf("%d ", count1);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D28(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x1d4(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x1d4(%rbp),%rdx
  mov    %rsp,%rdi
  lea    0xf(,%rdx,4),%rcx
  mov    %rdx,%rsi
  mov    %rcx,%rax
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rdi
  and    $0xfffffffffffffff0,%rax
  cmp    %rdi,%rsp
  je     L63
L10:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L10
L63:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L68
L20:
  lea    -0x1d0(%rbp),%r12
  xor    %eax,%eax
  add    $0xf,%rdx
  mov    %rsp,%rbx
  mov    $0x32,%ecx
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdx,%rax
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rdx
  and    $0xfffffffffffffff0,%rax
  sub    %rdx,%rcx
L72:
  cmp    %rcx,%rsp
  je     L102
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L72
L68:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L20
L102:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L28
L42:
  mov    %rsp,%r14
  xor    %r13d,%r13d
  lea    D12(%rip),%r15
  test   %esi,%esi
  jle    L53
L22:
  lea    (%r14,%r13,1),%rdx
  mov    %rbx,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq (%rbx),%rax
  add    $0x1,%r13
  add    $0x4,%rbx
  addl   $0x1,-0x1d0(%rbp,%rax,4)
  cmp    %r13d,-0x1d4(%rbp)
  jg     L22
L53:
  lea    -0x40(%rbp),%r14
  xor    %ebx,%ebx
  lea    D2(%rip),%r13
  nopl   0x0(%rax)
L66:
  mov    (%r12),%eax
  mov    %r13,%rdi
  test   %eax,%eax
  lea    (%rbx,%rax,1),%edx
  cmovg  %edx,%ebx
  add    $0x4,%r12
  mov    %ebx,%esi
  call   <printf@plt>
  cmp    %r12,%r14
  jne    L66
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L28:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L42
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D28
type_guessed: string
name: parse_data
arguments: tag: D12
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string

tool: D28: %d

tool: D12: %d %s

tool: D2: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int a[n], i, count[100];
  for (i = 0; i < 100; i++)
    count[i] = 0;
  char b[n];
  for (i = 0; i < n; i++) {
    scanf("%d %s", &a[i], &b[i]);
    count[a[i]]++;
  }
  int count1 = 0, j;
  for (i = 0; i < 100; i++) {
    for (j = 0; j < count[i]; j++)
      count1++;
    printf("%d ", count1);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x1d4(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x1d4(%rbp),%rdx
  mov    %rsp,%rdi
  lea    0xf(,%rdx,4),%rcx
  mov    %rdx,%rsi
  mov    %rcx,%rax
  and    $0xfffffffffffff000,%rcx
  sub    %rcx,%rdi
  and    $0xfffffffffffffff0,%rax
  cmp    %rdi,%rsp
  je     L0
L112:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L112
L0:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L50
L98:
  lea    -0x1d0(%rbp),%rbx
  xor    %eax,%eax
  add    $0xf,%rdx
  mov    %rsp,%r12
  mov    $0x32,%ecx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdx,%rax
  mov    %rsp,%rcx
  and    $0xfffffffffffff000,%rdx
  and    $0xfffffffffffffff0,%rax
  sub    %rdx,%rcx
L41:
  cmp    %rcx,%rsp
  je     L128
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L50:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L98
L128:
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  jne    L80
L125:
  mov    %rsp,%r14
  xor    %r13d,%r13d
  lea    D13(%rip),%r15
  test   %esi,%esi
  jle    L79
L96:
  lea    (%r14,%r13,1),%rdx
  mov    %r12,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movslq (%r12),%rax
  add    $0x1,%r13
  add    $0x4,%r12
  addl   $0x1,-0x1d0(%rbp,%rax,4)
  cmp    %r13d,-0x1d4(%rbp)
  jg     L96
L79:
  lea    -0x40(%rbp),%r14
  xor    %r12d,%r12d
  lea    D10(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L48:
  mov    (%rbx),%eax
  test   %eax,%eax
  jle    L119
  add    %eax,%r12d
L119:
  mov    %r12d,%esi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r14
  jne    L48
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L80:
  orq    $0x0,-0x8(%rsp,%rax,1)
  jmp    L125
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D4: %d

tool: D13: %d %s

tool: D10: %d 

assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int a[n], i, count[100];
  for (i = 0; i < 100; i++)
    count[i] = 0;
  char b[n];
  for (i = 0; i < n; i++) {
    scanf("%d %s", &a[i], &b[i]);
    count[a[i]]++;
  }
  int count1 = 0, j;
  for (i = 0; i < 100; i++) {
    for (j = 0; j < count[i]; j++)
      count1++;
    printf("%d ", count1);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L13
L45:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L40:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L17
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x1,-0x8(%rbp)
L17:
  addl   $0x1,-0x4(%rbp)
L36:
  cmpl   $0x6,-0x4(%rbp)
  jle    L40
L13:
  cmpl   $0x1,-0x8(%rbp)
  je     L45
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubble_sort(int paramArr[]) {
  int swapCounter = 1;
  while (swapCounter == 1) {
    swapCounter = 0;
    for (int i = 0; i < 8 - 1; i++) {
      if (paramArr[i + 0] > paramArr[i + 1]) {
        swap(&paramArr[i + 0], &paramArr[i + 1]);
        swapCounter = 1;
      }
    }
  }
}
```