ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<unpack_integer>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    (%rdx),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movzbl (%rdi,%rdx,1),%ebx
  mov    %ebx,%eax
  sub    $0x1,%ebx
  test   %al,%al
  js     L18
  movslq %ebx,%rbx
  mov    %rbx,(%rsi)
  mov    0x0(%rbp),%rax
  lea    0x1(%rax),%rdx
L33:
  mov    %rdx,0x0(%rbp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L18:
  movzbl 0x1(%rdi,%rdx,1),%ecx
  add    $0x2,%rdx
  mov    %ecx,%eax
  lea    -0x1(%rcx),%r13d
  movslq %r13d,%rcx
  test   %al,%al
  js     L30
L47:
  movslq %ebx,%rax
  mov    %ebx,%esi
  imul   $0xffffffff81020409,%rax,%rax
  sar    $0x1f,%esi
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x6,%eax
  sub    %esi,%eax
  mov    %eax,%esi
  shl    $0x7,%esi
  sub    %eax,%esi
  mov    %rcx,%rax
  sub    %esi,%ebx
  shl    $0x7,%rax
  movslq %ebx,%rbx
  sub    %rcx,%rax
  add    %rax,%rbx
  mov    %rbx,(%r12)
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %rdx,0x10(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rdx
  call   <unpack_integer>
  mov    0x8(%rsp),%rax
  mov    %r13d,%ecx
  sar    $0x1f,%ecx
  mov    %rax,%rdx
  shl    $0x7,%rdx
  sub    %rax,%rdx
  movslq %r13d,%rax
  imul   $0xffffffff81020409,%rax,%rax
  shr    $0x20,%rax
  add    %r13d,%eax
  sar    $0x6,%eax
  sub    %ecx,%eax
  mov    %r13d,%ecx
  mov    %eax,%esi
  shl    $0x7,%esi
  sub    %eax,%esi
  sub    %esi,%ecx
  movslq %ecx,%rcx
  add    %rdx,%rcx
  mov    0x10(%rsp),%rdx
  jmp    L47
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void unpack_integer(const unsigned char *s, unsigned long int *value, size_t *i) {
  if (s[*i] <= 0x7F) {
    *value = s[*i] - 1;
    (*i)++;
  } else {
    unsigned long int val;
    size_t j;
    j = *i + 1;
    unpack_integer(s, &val, &j);
    *value = ((s[*i] - 1) % 0x7F) + (0x7F * val);
    *i = j;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<private_decrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <createRSA@plt>
  mov    %rax,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  mov    -0x8(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rsi
  mov    -0x1c(%rbp),%eax
  mov    %edi,%r8d
  mov    %eax,%edi
  call   <RSA_private_decrypt@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int private_decrypt(unsigned char *enc_data, int data_len, unsigned char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 0);
  int result = RSA_private_decrypt(data_len, enc_data, decrypted, rsa, RSA_PKCS1_PADDING);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<private_decrypt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%rdi
  mov    %rcx,%r12
  mov    $0x0,%esi
  call   <createRSA@plt>
  mov    %rax,%rcx
  mov    D3(%rip),%rax
  mov    (%rax),%r8d
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RSA_private_decrypt@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int private_decrypt(unsigned char *enc_data, int data_len, unsigned char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 0);
  int result = RSA_private_decrypt(data_len, enc_data, decrypted, rsa, RSA_PKCS1_PADDING);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<private_decrypt>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  call   <createRSA@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%rcx
  mov    D1(%rip),%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    (%rax),%r8d
  jmp    1070 <RSA_private_decrypt@plt>
```

assistant: ```c
int private_decrypt(unsigned char *enc_data, int data_len, unsigned char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 0);
  int result = RSA_private_decrypt(data_len, enc_data, decrypted, rsa, RSA_PKCS1_PADDING);
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<private_decrypt>:
  endbr64
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %esi,%ebp
  xor    %esi,%esi
  call   <createRSA@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  mov    %rax,%rcx
  mov    D5(%rip),%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  mov    (%rax),%r8d
  jmp    1070 <RSA_private_decrypt@plt>
```

assistant: ```c
int private_decrypt(unsigned char *enc_data, int data_len, unsigned char *key, unsigned char *decrypted) {
  RSA *rsa = createRSA(key, 0);
  int result = RSA_private_decrypt(data_len, enc_data, decrypted, rsa, RSA_PKCS1_PADDING);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <printProcList@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <callProc@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int selectedProc;
  printProcList();
  scanf("%d", &selectedProc);
  callProc(selectedProc);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printProcList@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <callProc@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int selectedProc;
  printProcList();
  scanf("%d", &selectedProc);
  callProc(selectedProc);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printProcList@plt>
  lea    D2(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <callProc@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
type: string

tool: D2: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int selectedProc;
  printProcList();
  scanf("%d", &selectedProc);
  callProc(selectedProc);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printProcList@plt>
  lea    D7(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <callProc@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: %d

assistant: ```c
int main(int argc, char const *argv[]) {
  int selectedProc;
  printProcList();
  scanf("%d", &selectedProc);
  callProc(selectedProc);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: Thread: %d


assistant: ```c
int main() {
#pragma omp target parallel num_threads(1)
  printf("Thread: %d\n", omp_get_thread_num());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string

tool: D7: Thread: %d


assistant: ```c
int main() {
#pragma omp target parallel num_threads(1)
  printf("Thread: %d\n", omp_get_thread_num());
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: Thread: %d


assistant: ```c
int main() {
#pragma omp target parallel num_threads(1)
  printf("Thread: %d\n", omp_get_thread_num());
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: Thread: %d


assistant: ```c
int main() {
#pragma omp target parallel num_threads(1)
  printf("Thread: %d\n", omp_get_thread_num());
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<resetMartixDoubleZero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L21:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L26:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L26
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int resetMartixDoubleZero(double **A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      A[i][j] = 0.0;
  return (EXIT_SUCCESS);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<resetMartixDoubleZero>:
  endbr64
  test   %esi,%esi
  jle    L42
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rsi
  jmp    L1
L24:
  mov    (%r8),%rcx
  movq   $0x0,(%rcx,%rax,1)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L24
L12:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L42
L1:
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L24
  jmp    L12
L42:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int resetMartixDoubleZero(double **A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      A[i][j] = 0.0;
  return (EXIT_SUCCESS);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<resetMartixDoubleZero>:
  endbr64
  test   %esi,%esi
  jle    L27
  push   %r13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  lea    -0x1(%rdx),%eax
  push   %rbp
  lea    0x8(,%rax,8),%r13
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L18:
  test   %ebp,%ebp
  jle    L26
  mov    (%rbx),%rdi
  mov    %r13,%rdx
  xor    %esi,%esi
  call   <memset@plt>
L26:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L18
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int resetMartixDoubleZero(double **A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      A[i][j] = 0.0;
  return (EXIT_SUCCESS);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<resetMartixDoubleZero>:
  endbr64
  test   %esi,%esi
  jle    L24
  test   %edx,%edx
  jle    L24
  lea    -0x1(%rsi),%eax
  movslq %edx,%rdx
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    0x0(,%rdx,8),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%rdi
  mov    %rbp,%rdx
  xor    %esi,%esi
  add    $0x8,%rbx
  call   <memset@plt>
  cmp    %rbx,%r12
  jne    L4
  mov    D12(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
L24:
  mov    D12(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int resetMartixDoubleZero(double **A, int n, int m) {
  int i, j;
  for (i = 0; i < n; i++)
    for (j = 0; j < m; j++)
      A[i][j] = 0.0;
  return (EXIT_SUCCESS);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x18000(%rsp),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0x6c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x186b8(%rbp)
  lea    -0x186b0(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x186b0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x186b4(%rbp)
  lea    -0x186bd(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x186bc(%rbp)
  jmp    L79
L68:
  mov    -0x186bc(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%edx
  movzbl -0x186bd(%rbp),%eax
  cmp    %al,%dl
  jne    L57
  mov    -0x186bc(%rbp),%eax
  cltq
  movb   $0x0,-0x186b0(%rbp,%rax,1)
L57:
  addl   $0x1,-0x186bc(%rbp)
L79:
  mov    -0x186bc(%rbp),%eax
  cmp    -0x186b4(%rbp),%eax
  jl     L68
  movl   $0x0,-0x186bc(%rbp)
  jmp    L44
L30:
  mov    -0x186bc(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%eax
  test   %al,%al
  je     L65
  mov    -0x186bc(%rbp),%eax
  cltq
  movzbl -0x186b0(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L65:
  addl   $0x1,-0x186bc(%rbp)
L44:
  mov    -0x186bc(%rbp),%eax
  cmp    -0x186b4(%rbp),%eax
  jl     L30
  lea    -0x186b0(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L66
  call   <__stack_chk_fail@plt>
L66:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: %c

assistant: ```c
int main() {
  char str[100000], s;
  int i, k, k1, j, m = 0;
  gets(str);
  k = strlen(str);
  scanf("%c", &s);
  for (i = 0; i < k; i++) {
    if (str[i] == s)
      str[i] = 0;
  }
  for (i = 0; i < k; i++)
    if (str[i] != 0)
      printf("%c", str[i]);
  puts(str);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L36:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L36
  sub    $0x6c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x186b8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0xf(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  test   %ebp,%ebp
  jle    L3
  movzbl 0xf(%rsp),%edx
  lea    -0x1(%rbp),%eax
  lea    0x11(%rsp,%rax,1),%rbp
  mov    %rbx,%rax
  jmp    L91
L17:
  add    $0x1,%rax
  cmp    %rbp,%rax
  je     L96
L91:
  cmp    %dl,(%rax)
  jne    L17
  movb   $0x0,(%rax)
  jmp    L17
L96:
  lea    D3(%rip),%r12
  jmp    L70
L53:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L3
L70:
  movzbl (%rbx),%esi
  test   %sil,%sil
  je     L53
  movsbl %sil,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L53
L3:
  lea    0x10(%rsp),%rdi
  call   <puts@plt>
  mov    0x186b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x186c0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: %c

assistant: ```c
int main() {
  char str[100000], s;
  int i, k, k1, j, m = 0;
  gets(str);
  k = strlen(str);
  scanf("%c", &s);
  for (i = 0; i < k; i++) {
    if (str[i] == s)
      str[i] = 0;
  }
  for (i = 0; i < k; i++)
    if (str[i] != 0)
      printf("%c", str[i]);
  puts(str);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L53:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L53
  sub    $0x6c8,%rsp
  lea    D0(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x186b8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0xf(%rsp),%rsi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <scanf@plt>
  test   %r13d,%r13d
  jle    L50
  lea    -0x1(%r13),%eax
  movzbl 0xf(%rsp),%edx
  mov    %rbp,%rbx
  lea    0x11(%rsp,%rax,1),%r13
  mov    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L72:
  cmp    %dl,(%rax)
  jne    L4
  movb   $0x0,(%rax)
L4:
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L72
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L39
L42:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L50
L75:
  movsbl (%rbx),%esi
  test   %sil,%sil
  je     L42
L39:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L75
L50:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x186b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x186c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: %c

assistant: ```c
int main() {
  char str[100000], s;
  int i, k, k1, j, m = 0;
  gets(str);
  k = strlen(str);
  scanf("%c", &s);
  for (i = 0; i < k; i++) {
    if (str[i] == s)
      str[i] = 0;
  }
  for (i = 0; i < k; i++)
    if (str[i] != 0)
      printf("%c", str[i]);
  puts(str);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L57:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L57
  sub    $0x6c8,%rsp
  lea    D7(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x186b8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0xf(%rsp),%rsi
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <scanf@plt>
  test   %r13d,%r13d
  jle    L8
  lea    -0x1(%r13),%eax
  movzbl 0xf(%rsp),%edx
  mov    %rbp,%rbx
  lea    0x11(%rsp,%rax,1),%r13
  mov    %rbp,%rax
  nopw   0x0(%rax,%rax,1)
L72:
  cmp    %dl,(%rax)
  jne    L85
  movb   $0x0,(%rax)
L85:
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L72
  movsbl (%rbx),%esi
  test   %sil,%sil
  jne    L74
L36:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L8
L4:
  movsbl (%rbx),%esi
  test   %sil,%sil
  je     L36
L74:
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L4
L8:
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x186b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x186c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: %c

assistant: ```c
int main() {
  char str[100000], s;
  int i, k, k1, j, m = 0;
  gets(str);
  k = strlen(str);
  scanf("%c", &s);
  for (i = 0; i < k; i++) {
    if (str[i] == s)
      str[i] = 0;
  }
  for (i = 0; i < k; i++)
    if (str[i] != 0)
      printf("%c", str[i]);
  puts(str);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L7
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copy(int b[], int start, int end, int a[]) {
  int k = 0;
  for (k = start; k < end; k++) {
    a[k] = b[k];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy>:
  endbr64
  cmp    %edx,%esi
  jge    L18
  movslq %esi,%rsi
L3:
  mov    (%rdi,%rsi,4),%eax
  mov    %eax,(%rcx,%rsi,4)
  add    $0x1,%rsi
  cmp    %esi,%edx
  jg     L3
L18:
  ret
```

assistant: ```c
void copy(int b[], int start, int end, int a[]) {
  int k = 0;
  for (k = start; k < end; k++) {
    a[k] = b[k];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<copy>:
  endbr64
  cmp    %edx,%esi
  jge    L17
  movslq %esi,%rsi
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rdi,%rsi,4),%eax
  mov    %eax,(%rcx,%rsi,4)
  add    $0x1,%rsi
  cmp    %esi,%edx
  jg     L18
L17:
  ret
```

assistant: ```c
void copy(int b[], int start, int end, int a[]) {
  int k = 0;
  for (k = start; k < end; k++) {
    a[k] = b[k];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<copy>:
  endbr64
  cmp    %edx,%esi
  jge    L84
  movslq %esi,%rax
  mov    %edx,%r11d
  mov    %edx,%r8d
  push   %rbx
  lea    0x0(,%rax,4),%rdx
  mov    %rcx,%r9
  sub    %esi,%r11d
  lea    (%rcx,%rdx,1),%r10
  lea    0x4(%rdi,%rdx,1),%rbx
  mov    %r10,%rcx
  sub    %rbx,%rcx
  cmp    $0x8,%rcx
  jbe    L76
  lea    -0x1(%r11),%ecx
  cmp    $0x2,%ecx
  jbe    L76
  mov    %r11d,%ecx
  add    %rdi,%rdx
  xor    %eax,%eax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  nopl   0x0(%rax)
L20:
  movdqu (%rdx,%rax,1),%xmm0
  movups %xmm0,(%r10,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rcx
  jne    L20
  mov    %r11d,%eax
  and    $0xfffffffc,%eax
  add    %eax,%esi
  cmp    %eax,%r11d
  je     L64
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%r9,%rax,4)
  lea    0x1(%rsi),%eax
  cmp    %eax,%r8d
  jle    L64
  cltq
  add    $0x2,%esi
  mov    (%rdi,%rax,4),%ecx
  lea    0x0(,%rax,4),%rdx
  mov    %ecx,(%r9,%rax,4)
  cmp    %esi,%r8d
  jle    L64
  mov    0x4(%rdi,%rdx,1),%eax
  mov    %eax,0x4(%r9,%rdx,1)
L64:
  pop    %rbx
  ret
  xchg   %ax,%ax
L76:
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jle    L64
  mov    (%rdi,%rax,4),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r8d
  jg     L76
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L84:
  ret
```

assistant: ```c
void copy(int b[], int start, int end, int a[]) {
  int k = 0;
  for (k = start; k < end; k++) {
    a[k] = b[k];
  }
}
```