ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%edi
  call   <reverseAdd@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  int x;
  assert(scanf("%d", &x) == 1);
  reverseAdd(x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jne    L27
  mov    -0xc(%rbp),%edx
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
  test   %eax,%eax
  je     L16
  mov    $0x1,%eax
  jmp    L40
L16:
  mov    $0x0,%eax
  jmp    L40
L27:
  mov    $0xffffffff,%eax
L40:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int isdir(char *path) {
  struct stat s;
  if (stat(path, &s) == 0) {
    if (s.st_mode & S_IFDIR) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isdir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%rdx
  mov    $0xffffffff,%eax
  test   %rdx,%rdx
  jne    L4
  mov    D5(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L4:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isdir(char *path) {
  struct stat s;
  if (stat(path, &s) == 0) {
    if (s.st_mode & S_IFDIR) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isdir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L5
  mov    D6(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isdir(char *path) {
  struct stat s;
  if (stat(path, &s) == 0) {
    if (s.st_mode & S_IFDIR) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isdir>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  mov    %rax,%r8
  mov    $0xffffffff,%eax
  test   %r8,%r8
  jne    L19
  mov    D6(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
  setne  %al
  movzbl %al,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int isdir(char *path) {
  struct stat s;
  if (stat(path, &s) == 0) {
    if (s.st_mode & S_IFDIR) {
      return 1;
    } else {
      return 0;
    }
  } else {
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printThreads>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: Use threads: %2d


assistant: ```c
void printThreads() {
  int count;
#pragma omp parallel
  { count = omp_get_num_threads(); }
  printf("Use threads: %2d\n", count);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printThreads>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: Use threads: %2d


assistant: ```c
void printThreads() {
  int count;
#pragma omp parallel
  { count = omp_get_num_threads(); }
  printf("Use threads: %2d\n", count);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<printThreads>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: Use threads: %2d


assistant: ```c
void printThreads() {
  int count;
#pragma omp parallel
  { count = omp_get_num_threads(); }
  printf("Use threads: %2d\n", count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printThreads>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  lea    D2(%rip),%rdi
  add    $0x8,%rsp
  mov    %eax,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: Use threads: %2d


assistant: ```c
void printThreads() {
  int count;
#pragma omp parallel
  { count = omp_get_num_threads(); }
  printf("Use threads: %2d\n", count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skipword>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  jmp    L32
L7:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jge    L42
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L7
L42:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jge    L45
  mov    -0x8(%rbp),%rax
  jmp    L9
L45:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
char *skipword(char *p, char *buf, int bufsize) {
  for (; (p - buf < bufsize) && (!isspace(*p)); p++)
    ;
  if (p - buf < bufsize)
    return p;
  else
    return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skipword>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdi,%rbp
  sub    %rsi,%rbp
  movslq %edx,%r12
  cmp    %r12,%rbp
  jge    L20
L0:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L2
  add    $0x1,%rbx
  mov    %rbx,%rbp
  sub    %r13,%rbp
  cmp    %r12,%rbp
  jl     L0
L20:
  mov    $0x0,%ebx
  jmp    L18
L2:
  cmp    %rbp,%r12
  mov    $0x0,%eax
  cmovle %rax,%rbx
L18:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *skipword(char *p, char *buf, int bufsize) {
  for (; (p - buf < bufsize) && (!isspace(*p)); p++)
    ;
  if (p - buf < bufsize)
    return p;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipword>:
  endbr64
  mov    %rdi,%rax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    %rsi,%rax
  movslq %edx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    %rax,%rbp
  jg     L4
  jmp    L24
  xchg   %ax,%ax
L9:
  add    $0x1,%rbx
  mov    %rbx,%rax
  sub    %r12,%rax
  cmp    %rbp,%rax
  jge    L24
L4:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L9
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *skipword(char *p, char *buf, int bufsize) {
  for (; (p - buf < bufsize) && (!isspace(*p)); p++)
    ;
  if (p - buf < bufsize)
    return p;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<skipword>:
  endbr64
  mov    %rdi,%rax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    %rsi,%rax
  movslq %edx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    %rax,%rbp
  jg     L13
  jmp    L37
  xchg   %ax,%ax
L15:
  add    $0x1,%rbx
  mov    %rbx,%rax
  sub    %r12,%rax
  cmp    %rbp,%rax
  jge    L37
L13:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L15
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *skipword(char *p, char *buf, int bufsize) {
  for (; (p - buf < bufsize) && (!isspace(*p)); p++)
    ;
  if (p - buf < bufsize)
    return p;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<db_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int db_read(wchar_t *buffer, size_t max) {
  int ok = 0;
  return ok;
}
```
user: Translate the below assembly code into C programming language:

```asm
<db_read>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int db_read(wchar_t *buffer, size_t max) {
  int ok = 0;
  return ok;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<db_read>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int db_read(wchar_t *buffer, size_t max) {
  int ok = 0;
  return ok;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<db_read>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int db_read(wchar_t *buffer, size_t max) {
  int ok = 0;
  return ok;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tsk_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L9:
  nop
  leave
  ret
```

assistant: ```c
void tsk_free(void **ptr) {
  if (ptr && *ptr) {
    free(*ptr);
    *ptr = 0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tsk_free>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L18
  call   <free@plt>
  movq   $0x0,(%rbx)
L18:
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void tsk_free(void **ptr) {
  if (ptr && *ptr) {
    free(*ptr);
    *ptr = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<tsk_free>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L13
  call   <free@plt>
  movq   $0x0,(%rbx)
L13:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void tsk_free(void **ptr) {
  if (ptr && *ptr) {
    free(*ptr);
    *ptr = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tsk_free>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  call   <free@plt>
  movq   $0x0,(%rbx)
L4:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void tsk_free(void **ptr) {
  if (ptr && *ptr) {
    free(*ptr);
    *ptr = 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hashCode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L17:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hashCode(unsigned char *buf, int32_t count) {
  int32_t h = 0;
  int32_t i;
  for (i = 0; i < count; i++)
    h = 31 * h + buf[i];
  return h;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hashCode>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0x0,%eax
L13:
  mov    %eax,%ecx
  shl    $0x5,%ecx
  sub    %eax,%ecx
  movzbl (%rdx),%eax
  add    %ecx,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L13
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int hashCode(unsigned char *buf, int32_t count) {
  int32_t h = 0;
  int32_t i;
  for (i = 0; i < count; i++)
    h = 31 * h + buf[i];
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hashCode>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %eax,%edx
  movzbl -0x1(%rdi),%eax
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L16
  ret
  nop
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hashCode(unsigned char *buf, int32_t count) {
  int32_t h = 0;
  int32_t i;
  for (i = 0; i < count; i++)
    h = 31 * h + buf[i];
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hashCode>:
  endbr64
  test   %esi,%esi
  jle    L15
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %eax,%edx
  movzbl -0x1(%rdi),%eax
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L14
  ret
  nop
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int hashCode(unsigned char *buf, int32_t count) {
  int32_t h = 0;
  int32_t i;
  for (i = 0; i < count; i++)
    h = 31 * h + buf[i];
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_number>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  mov    (%rcx),%edx
  movslq %edx,%rax
  movzbl (%r8,%rax,1),%eax
  cmp    $0x2a,%al
  je     L56
  sub    $0x31,%eax
  mov    $0xffffffff,%edx
  cmp    $0x8,%al
  jbe    L4
L40:
  mov    %edx,%eax
  ret
L56:
  add    $0x1,%edx
  mov    %edx,(%rcx)
  movslq %edx,%rdx
  movzbl (%r8,%rdx,1),%eax
  sub    $0x31,%eax
  cmp    $0x8,%al
  jbe    L27
  mov    (%rdi),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  mov    $0x1,%edx
  jmp    L40
L27:
  movl   $0x0,(%rsi)
  mov    (%rcx),%r10d
  movslq %r10d,%rax
  movzbl (%r8,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L31
  add    $0x1,%r10d
  movslq %r10d,%rdx
L73:
  mov    %edx,%r10d
  mov    (%rsi),%r9d
  lea    (%r9,%r9,4),%r9d
  movsbl %al,%eax
  lea    -0x30(%rax,%r9,2),%eax
  mov    %eax,(%rsi)
  movzbl (%r8,%rdx,1),%eax
  add    $0x1,%rdx
  lea    -0x30(%rax),%r9d
  cmp    $0x9,%r9b
  jbe    L73
L31:
  cmp    $0x24,%al
  je     L33
  mov    (%rdi),%eax
  lea    0x1(%rax),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%rsi)
  mov    $0x1,%edx
  jmp    L40
L33:
  add    $0x1,%r10d
  mov    %r10d,(%rcx)
  mov    $0x1,%edx
  je     L40
  subl   $0x1,(%rsi)
  jmp    L40
L4:
  movl   $0x0,(%rsi)
  mov    (%rcx),%edx
  movslq %edx,%rax
  add    %r8,%rax
  movzbl (%rax),%edi
  sub    $0x30,%edi
  cmp    $0x9,%dil
  ja     L28
L2:
  mov    (%rsi),%edi
  lea    (%rdi,%rdi,4),%edi
  add    $0x1,%edx
  mov    %edx,(%rcx)
  movsbl (%rax),%eax
  lea    -0x30(%rax,%rdi,2),%eax
  mov    %eax,(%rsi)
  mov    (%rcx),%edx
  movslq %edx,%rax
  add    %r8,%rax
  movzbl (%rax),%edi
  sub    $0x30,%edi
  cmp    $0x9,%dil
  jbe    L2
  mov    $0x0,%edx
  jmp    L40
L28:
  mov    $0x0,%edx
  jmp    L40
```

assistant: ```c
int parse_number(const char *format, int *number, int *arg_number, int *pos) {
  int tmp;
  if (format[*pos] == '*') {
    if (format[++(*pos)] >= '1' && format[*pos] <= '9') {
      *number = 0;
      tmp = *pos;
      while (format[tmp] >= '0' && format[tmp] <= '9')
        *number = (*number) * 10 + format[tmp++] - '0';
      (format[tmp] == '$') ? ((*pos = tmp + 1) && --(*number)) : (*number = (*arg_number)++);
    } else
      *number = (*arg_number)++;
    return (1);
  }
  if (format[*pos] >= '1' && format[*pos] <= '9') {
    *number = 0;
    while (format[*pos] >= '0' && format[*pos] <= '9')
      *number = (*number) * 10 + format[(*pos)++] - '0';
    return (0);
  }
  return (-1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_number>:
  endbr64
  movslq (%rcx),%rax
  mov    %rdi,%r8
  mov    %rdx,%rdi
  mov    %rsi,%r9
  mov    %rcx,%rsi
  mov    %rax,%rdx
  movzbl (%r8,%rax,1),%eax
  cmp    $0x2a,%al
  je     L11
  sub    $0x31,%eax
  mov    $0xffffffff,%r10d
  cmp    $0x8,%al
  jbe    L39
L58:
  mov    %r10d,%eax
  ret
L39:
  movl   $0x0,(%r9)
  movslq (%rcx),%rax
  mov    %rax,%rdx
  add    %r8,%rax
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%edi
  xor    %ecx,%ecx
  cmp    $0x9,%dil
  ja     L98
  xchg   %ax,%ax
L1:
  add    $0x1,%edx
  mov    %edx,(%rsi)
  movsbl (%rax),%eax
  lea    (%rcx,%rcx,4),%edx
  lea    -0x30(%rax,%rdx,2),%ecx
  mov    %ecx,(%r9)
  movslq (%rsi),%rax
  mov    %rax,%rdx
  add    %r8,%rax
  movzbl (%rax),%edi
  sub    $0x30,%edi
  cmp    $0x9,%dil
  jbe    L1
L98:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
  xchg   %ax,%ax
L11:
  add    $0x1,%edx
  mov    %edx,(%rcx)
  movslq %edx,%rdx
  movzbl (%r8,%rdx,1),%eax
  sub    $0x31,%eax
  cmp    $0x8,%al
  jbe    L18
L9:
  mov    (%rdi),%eax
  mov    $0x1,%r10d
  lea    0x1(%rax),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%r9)
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movl   $0x0,(%r9)
  movslq (%rcx),%rax
  mov    %rax,%r11
  movsbl (%r8,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L32
  add    $0x1,%r11d
  xor    %edx,%edx
  movslq %r11d,%rcx
  nopl   0x0(%rax,%rax,1)
L24:
  lea    (%rdx,%rdx,4),%edx
  mov    %ecx,%r11d
  lea    -0x30(%rax,%rdx,2),%edx
  mov    %edx,(%r9)
  movsbl (%r8,%rcx,1),%eax
  add    $0x1,%rcx
  lea    -0x30(%rax),%r10d
  cmp    $0x9,%r10b
  jbe    L24
L32:
  cmp    $0x24,%al
  jne    L9
  add    $0x1,%r11d
  mov    $0x1,%r10d
  mov    %r11d,(%rsi)
  je     L58
  subl   $0x1,(%r9)
  jmp    L58
```

assistant: ```c
int parse_number(const char *format, int *number, int *arg_number, int *pos) {
  int tmp;
  if (format[*pos] == '*') {
    if (format[++(*pos)] >= '1' && format[*pos] <= '9') {
      *number = 0;
      tmp = *pos;
      while (format[tmp] >= '0' && format[tmp] <= '9')
        *number = (*number) * 10 + format[tmp++] - '0';
      (format[tmp] == '$') ? ((*pos = tmp + 1) && --(*number)) : (*number = (*arg_number)++);
    } else
      *number = (*arg_number)++;
    return (1);
  }
  if (format[*pos] >= '1' && format[*pos] <= '9') {
    *number = 0;
    while (format[*pos] >= '0' && format[*pos] <= '9')
      *number = (*number) * 10 + format[(*pos)++] - '0';
    return (0);
  }
  return (-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_number>:
  endbr64
  movslq (%rcx),%rax
  mov    %rdi,%r8
  mov    %rdx,%rdi
  mov    %rsi,%r9
  mov    %rcx,%rsi
  mov    %rax,%rdx
  movzbl (%r8,%rax,1),%eax
  cmp    $0x2a,%al
  je     L85
  sub    $0x31,%eax
  mov    $0xffffffff,%r10d
  cmp    $0x8,%al
  jbe    L38
L40:
  mov    %r10d,%eax
  ret
L38:
  movl   $0x0,(%r9)
  movslq (%rcx),%rax
  mov    %rax,%rdx
  add    %r8,%rax
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%edi
  xor    %ecx,%ecx
  cmp    $0x9,%dil
  ja     L70
  xchg   %ax,%ax
L8:
  add    $0x1,%edx
  mov    %edx,(%rsi)
  movsbl (%rax),%eax
  lea    (%rcx,%rcx,4),%edx
  lea    -0x30(%rax,%rdx,2),%ecx
  mov    %ecx,(%r9)
  movslq (%rsi),%rax
  mov    %rax,%rdx
  add    %r8,%rax
  movzbl (%rax),%edi
  sub    $0x30,%edi
  cmp    $0x9,%dil
  jbe    L8
L70:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
  xchg   %ax,%ax
L85:
  add    $0x1,%edx
  mov    %edx,(%rcx)
  movslq %edx,%rdx
  movzbl (%r8,%rdx,1),%eax
  sub    $0x31,%eax
  cmp    $0x8,%al
  jbe    L74
L62:
  mov    (%rdi),%eax
  mov    $0x1,%r10d
  lea    0x1(%rax),%edx
  mov    %edx,(%rdi)
  mov    %eax,(%r9)
  mov    %r10d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L74:
  movl   $0x0,(%r9)
  movslq (%rcx),%rax
  mov    %rax,%r11
  movsbl (%r8,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L65
  add    $0x1,%r11d
  xor    %edx,%edx
  movslq %r11d,%rcx
  nopl   0x0(%rax,%rax,1)
L26:
  lea    (%rdx,%rdx,4),%edx
  mov    %ecx,%r11d
  lea    -0x30(%rax,%rdx,2),%edx
  mov    %edx,(%r9)
  movsbl (%r8,%rcx,1),%eax
  add    $0x1,%rcx
  lea    -0x30(%rax),%r10d
  cmp    $0x9,%r10b
  jbe    L26
L65:
  cmp    $0x24,%al
  jne    L62
  add    $0x1,%r11d
  mov    $0x1,%r10d
  mov    %r11d,(%rsi)
  je     L40
  subl   $0x1,(%r9)
  jmp    L40
```

assistant: ```c
int parse_number(const char *format, int *number, int *arg_number, int *pos) {
  int tmp;
  if (format[*pos] == '*') {
    if (format[++(*pos)] >= '1' && format[*pos] <= '9') {
      *number = 0;
      tmp = *pos;
      while (format[tmp] >= '0' && format[tmp] <= '9')
        *number = (*number) * 10 + format[tmp++] - '0';
      (format[tmp] == '$') ? ((*pos = tmp + 1) && --(*number)) : (*number = (*arg_number)++);
    } else
      *number = (*arg_number)++;
    return (1);
  }
  if (format[*pos] >= '1' && format[*pos] <= '9') {
    *number = 0;
    while (format[*pos] >= '0' && format[*pos] <= '9')
      *number = (*number) * 10 + format[(*pos)++] - '0';
    return (0);
  }
  return (-1);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <initscr@plt>
  mov    $0x0,%eax
  call   <noecho@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <curs_set@plt>
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    $0x1,%edi
  call   <init_pair@plt>
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attron@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    D24(%rip),%rax
  mov    (%rax),%edi
  call   <getmaxyx@plt>
L4:
  mov    $0x9c40,%edi
  call   <usleep@plt>
  mov    $0x0,%eax
  call   <refresh@plt>
  jmp    L4
```

assistant: ```c
int main(void) {
  srand(time(NULL));
  char chars[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};
  int total_chars = sizeof(chars);
  initscr();
  noecho();
  curs_set(FALSE);
  start_color();
  init_pair(1, COLOR_GREEN, COLOR_BLACK);
  attron(COLOR_PAIR(1));
  int max_x = 0, max_y = 0;
  getmaxyx(stdscr, max_y, max_x);
  int columns_row[max_x];
  int columns_active[max_x];
  int i;
  for (i = 0; i < max_x; i++) {
    columns_row[i] = -1;
    columns_active[i] = 0;
  }
  while (1) {
    for (i = 0; i < max_x; i++) {
      if (columns_row[i] == -1) {
        columns_row[i] = get_rand_in_range(0, max_y);
        columns_active[i] = get_rand_in_range(0, 1);
      }
    }
    for (i = 0; i < max_x; i++) {
      if (columns_active[i] == 1) {
        int char_index = get_rand_in_range(0, total_chars);
        mvprintw(columns_row[i], i, "%c", chars[char_index]);
      } else {
        mvprintw(columns_row[i], i, " ");
      }
      columns_row[i]++;
      if (columns_row[i] >= max_y) {
        columns_row[i] = -1;
      }
      if (get_rand_in_range(0, 1000) == 0) {
        columns_active[i] = (columns_active[i] == 0) ? 1 : 0;
      }
    }
    usleep(40000);
    refresh();
  }
  endwin();
  return 0;
}
```