ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<__builtin_BitScanForward64>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <__native_ctzll@plt>
  test   %rbx,%rbx
  mov    %eax,%eax
  mov    %rax,0x0(%rbp)
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char __builtin_BitScanForward64(unsigned long *index, unsigned long long mask) {
  unsigned int trailing_zeros;
  trailing_zeros = __native_ctzll((unsigned long long)mask);
  *index = trailing_zeros;
  return (unsigned char)(mask != 0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__builtin_BitScanForward64>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <__native_ctzll@plt>
  test   %rbx,%rbx
  mov    %eax,%eax
  mov    %rax,0x0(%rbp)
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned char __builtin_BitScanForward64(unsigned long *index, unsigned long long mask) {
  unsigned int trailing_zeros;
  trailing_zeros = __native_ctzll((unsigned long long)mask);
  *index = trailing_zeros;
  return (unsigned char)(mask != 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xdr_int32_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x82,%eax
  je     L0
  cmp    $0x82,%eax
  jg     L67
  cmp    $0x80,%eax
  je     L59
  cmp    $0x81,%eax
  jne    L67
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <XDR_PUTINT32@plt>
  jmp    L4
L0:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <XDR_GETINT32@plt>
  jmp    L4
L59:
  mov    $0x1,%eax
  jmp    L4
L67:
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
int xdr_int32_t(XDR *xdrs, int32_t *lp) {
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return XDR_PUTINT32(xdrs, lp);
  case XDR_DECODE:
    return XDR_GETINT32(xdrs, lp);
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<xdr_int32_t>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L26
  cmp    $0x82,%eax
  je     L16
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
L10:
  add    $0x8,%rsp
  ret
L26:
  call   <XDR_PUTINT32@plt>
  jmp    L10
L16:
  call   <XDR_GETINT32@plt>
  jmp    L10
```

assistant: ```c
int xdr_int32_t(XDR *xdrs, int32_t *lp) {
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return XDR_PUTINT32(xdrs, lp);
  case XDR_DECODE:
    return XDR_GETINT32(xdrs, lp);
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xdr_int32_t>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L11
  cmp    $0x82,%eax
  je     L8
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  ret
L11:
  jmp    1060 <XDR_PUTINT32@plt>
  nopl   (%rax)
L8:
  jmp    1070 <XDR_GETINT32@plt>
```

assistant: ```c
int xdr_int32_t(XDR *xdrs, int32_t *lp) {
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return XDR_PUTINT32(xdrs, lp);
  case XDR_DECODE:
    return XDR_GETINT32(xdrs, lp);
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xdr_int32_t>:
  endbr64
  mov    (%rdi),%eax
  cmp    $0x81,%eax
  je     L17
  cmp    $0x82,%eax
  je     L14
  cmp    $0x80,%eax
  sete   %al
  movzbl %al,%eax
  ret
L17:
  jmp    1060 <XDR_PUTINT32@plt>
  nopl   (%rax)
L14:
  jmp    1070 <XDR_GETINT32@plt>
```

assistant: ```c
int xdr_int32_t(XDR *xdrs, int32_t *lp) {
  switch (xdrs->x_op) {
  case XDR_ENCODE:
    return XDR_PUTINT32(xdrs, lp);
  case XDR_DECODE:
    return XDR_GETINT32(xdrs, lp);
  case XDR_FREE:
    return 1;
  default:
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L26
L3:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rsi
  mov    -0x24(%rbp),%eax
  mov    $0x0,%ecx
  mov    %eax,%edi
  call   <send@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L3
  jmp    L20
L19:
  nop
L20:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
ssize_t send_all(int sockfd, const void *buf) {
  size_t len;
  ssize_t pos, ret;
  len = strlen(buf);
  pos = 0;
  while (pos < len) {
    ret = send(sockfd, buf + pos, len - pos, 0);
    if (ret < 0)
      return ret;
    else if (ret == 0)
      break;
    pos += ret;
  }
  return pos;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<send_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L4
  mov    $0x0,%ebx
L0:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    $0x0,%ecx
  mov    %r13d,%edi
  call   <send@plt>
  test   %rax,%rax
  je     L14
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L0
L14:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  mov    %rax,%rbx
  jmp    L14
```

assistant: ```c
ssize_t send_all(int sockfd, const void *buf) {
  size_t len;
  ssize_t pos, ret;
  len = strlen(buf);
  pos = 0;
  while (pos < len) {
    ret = send(sockfd, buf + pos, len - pos, 0);
    if (ret < 0)
      return ret;
    else if (ret == 0)
      break;
    pos += ret;
  }
  return pos;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_all>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L46
  mov    %rax,%rbx
  xor    %r12d,%r12d
  jmp    L0
  nopl   0x0(%rax)
L11:
  add    %rax,%r12
  cmp    %r12,%rbx
  jbe    L26
L0:
  mov    %rbx,%rdx
  xor    %ecx,%ecx
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %r13d,%edi
  sub    %r12,%rdx
  call   <send@plt>
  test   %rax,%rax
  jne    L11
L26:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  xor    %r12d,%r12d
  jmp    L26
```

assistant: ```c
ssize_t send_all(int sockfd, const void *buf) {
  size_t len;
  ssize_t pos, ret;
  len = strlen(buf);
  pos = 0;
  while (pos < len) {
    ret = send(sockfd, buf + pos, len - pos, 0);
    if (ret < 0)
      return ret;
    else if (ret == 0)
      break;
    pos += ret;
  }
  return pos;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<send_all>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L48
  mov    %rax,%rbx
  xor    %r12d,%r12d
  jmp    L31
  nopl   0x0(%rax)
L0:
  add    %rax,%r12
  cmp    %r12,%rbx
  jbe    L33
L31:
  mov    %rbx,%rdx
  xor    %ecx,%ecx
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %r13d,%edi
  sub    %r12,%rdx
  call   <send@plt>
  test   %rax,%rax
  jne    L0
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  xor    %r12d,%r12d
  jmp    L33
```

assistant: ```c
ssize_t send_all(int sockfd, const void *buf) {
  size_t len;
  ssize_t pos, ret;
  len = strlen(buf);
  pos = 0;
  while (pos < len) {
    ret = send(sockfd, buf + pos, len - pos, 0);
    if (ret < 0)
      return ret;
    else if (ret == 0)
      break;
    pos += ret;
  }
  return pos;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <domathl@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  domathl();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <domathl@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  domathl();
  exit(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <domathl@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  domathl();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <domathl@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  domathl();
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<naturalNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D15(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D2(%rip)
  pop    %rbp
  ret
```

assistant: ```c
int naturalNumber() {
  static int b = -1;
  return b++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<naturalNumber>:
  endbr64
  mov    D4(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D17(%rip)
  ret
```

assistant: ```c
int naturalNumber() {
  static int b = -1;
  return b++;
}
```
user: What is the c source code of the assembly code below?

```asm
<naturalNumber>:
  endbr64
  mov    D16(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D2(%rip)
  ret
```

assistant: ```c
int naturalNumber() {
  static int b = -1;
  return b++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<naturalNumber>:
  endbr64
  mov    D3(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D4(%rip)
  ret
```

assistant: ```c
int naturalNumber() {
  static int b = -1;
  return b++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<romanToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L41:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <value@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <value@plt>
  test   %eax,%eax
  je     L19
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <value@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L52
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x10(%rbp)
  jmp    L23
L52:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
  jmp    L23
L19:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x10(%rbp)
L23:
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L41
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int romanToInt(char *s) {
  int sum = 0;
  int i = 0;
  int val1;
  int val2;
  while (s[i]) {
    val1 = value(s[i]);
    if (value(s[i + 1])) {
      val2 = value(s[i + 1]);
      if (val1 < val2) {
        sum -= val1;
      } else {
        sum += val1;
      }
    } else {
      sum += val1;
    }
    i++;
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<romanToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L35
  lea    0x1(%rdi),%rbx
  mov    $0x0,%r12d
  jmp    L37
L10:
  add    %ebp,%r12d
L48:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  je     L1
L37:
  movsbl %al,%edi
  call   <value@plt>
  mov    %eax,%ebp
  movsbl (%rbx),%edi
  call   <value@plt>
  test   %eax,%eax
  je     L10
  movsbl (%rbx),%edi
  call   <value@plt>
  mov    %eax,%edx
  mov    %r12d,%eax
  sub    %ebp,%eax
  add    %ebp,%r12d
  cmp    %edx,%ebp
  cmovl  %eax,%r12d
  jmp    L48
L35:
  mov    $0x0,%r12d
L1:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int romanToInt(char *s) {
  int sum = 0;
  int i = 0;
  int val1;
  int val2;
  while (s[i]) {
    val1 = value(s[i]);
    if (value(s[i + 1])) {
      val2 = value(s[i + 1]);
      if (val1 < val2) {
        sum -= val1;
      } else {
        sum += val1;
      }
    } else {
      sum += val1;
    }
    i++;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<romanToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L44
  lea    0x1(%rdi),%rbx
  xor    %r12d,%r12d
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L34:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  add    %ebp,%r12d
  test   %al,%al
  je     L37
L49:
  movsbl %al,%edi
  call   <value@plt>
  movsbl (%rbx),%edi
  mov    %eax,%ebp
  call   <value@plt>
  test   %eax,%eax
  je     L34
  movsbl (%rbx),%edi
  call   <value@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  add    %ebp,%r12d
  sub    %ebp,%eax
  cmp    %r8d,%ebp
  cmovl  %eax,%r12d
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L49
L37:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L44:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int romanToInt(char *s) {
  int sum = 0;
  int i = 0;
  int val1;
  int val2;
  while (s[i]) {
    val1 = value(s[i]);
    if (value(s[i + 1])) {
      val2 = value(s[i + 1]);
      if (val1 < val2) {
        sum -= val1;
      } else {
        sum += val1;
      }
    } else {
      sum += val1;
    }
    i++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<romanToInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L10
  lea    0x1(%rdi),%rbx
  xor    %r12d,%r12d
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L40:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  add    %ebp,%r12d
  test   %al,%al
  je     L5
L21:
  movsbl %al,%edi
  call   <value@plt>
  movsbl (%rbx),%edi
  mov    %eax,%ebp
  call   <value@plt>
  test   %eax,%eax
  je     L40
  movsbl (%rbx),%edi
  call   <value@plt>
  mov    %eax,%r8d
  mov    %r12d,%eax
  add    %ebp,%r12d
  sub    %ebp,%eax
  cmp    %r8d,%ebp
  cmovl  %eax,%r12d
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L21
L5:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int romanToInt(char *s) {
  int sum = 0;
  int i = 0;
  int val1;
  int val2;
  while (s[i]) {
    val1 = value(s[i]);
    if (value(s[i + 1])) {
      val2 = value(s[i + 1]);
      if (val1 < val2) {
        sum -= val1;
      } else {
        sum += val1;
      }
    } else {
      sum += val1;
    }
    i++;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L68
L64:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L0
  addl   $0x1,-0x10(%rbp)
  addl   $0x64,-0xc(%rbp)
  jmp    L83
L0:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L44
  cmpl   $0x3,-0x10(%rbp)
  jle    L83
  addl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  jmp    L83
L44:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  cmp    %eax,-0xc(%rbp)
  jle    L83
  mov    -0x10(%rbp),%eax
  imul   $0x64,%eax,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L83
  negl   -0xc(%rbp)
L83:
  addl   $0x1,-0x4(%rbp)
  addl   $0xa,-0x8(%rbp)
L68:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L64
  cmpl   $0x3,-0x10(%rbp)
  jle    L60
  cmpl   $0x2,-0xc(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
L60:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  int z = 0;
  int w = 0;
  while (__VERIFIER_nondet_int()) {
    if (__VERIFIER_nondet_int()) {
      x++;
      y = y + 100;
    } else if (__VERIFIER_nondet_int()) {
      if (x >= 4) {
        x = x + 1;
        y = y + 1;
      }
    } else if (y > 10 * w)
      if (z >= 100 * x)
        y = -y;
    w = w + 1;
    z = z + 10;
  }
  if (x >= 4)
    assert(y > 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  jmp    L99
L49:
  add    $0x1,%r12d
  add    $0x64,%ebp
L43:
  add    $0xa,%ebx
L99:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L51
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L49
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L31
  cmp    $0x3,%r12d
  jle    L43
  add    $0x1,%r12d
  add    $0x1,%ebp
  jmp    L43
L31:
  cmp    %ebx,%ebp
  jle    L43
  imul   $0x64,%r12d,%edx
  mov    %ebp,%eax
  neg    %eax
  cmp    %ebx,%edx
  cmovle %eax,%ebp
  jmp    L43
L51:
  cmp    $0x3,%r12d
  jg     L92
L7:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L92:
  cmp    $0x2,%ebp
  setg   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  jmp    L7
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  int z = 0;
  int w = 0;
  while (__VERIFIER_nondet_int()) {
    if (__VERIFIER_nondet_int()) {
      x++;
      y = y + 100;
    } else if (__VERIFIER_nondet_int()) {
      if (x >= 4) {
        x = x + 1;
        y = y + 1;
      }
    } else if (y > 10 * w)
      if (z >= 100 * x)
        y = -y;
    w = w + 1;
    z = z + 10;
  }
  if (x >= 4)
    assert(y > 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L83
  nopl   0x0(%rax)
L69:
  add    $0x1,%r12d
  add    $0x64,%ebp
L40:
  add    $0xa,%ebx
L83:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L39
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L69
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L89
  cmp    $0x3,%r12d
  jle    L40
  add    $0x1,%r12d
  add    $0x1,%ebp
  jmp    L40
  nopl   (%rax)
L89:
  cmp    %ebx,%ebp
  jle    L40
  imul   $0x64,%r12d,%edx
  mov    %ebp,%eax
  neg    %eax
  cmp    %ebx,%edx
  cmovle %eax,%ebp
  jmp    L40
  nopl   0x0(%rax,%rax,1)
L39:
  cmp    $0x3,%r12d
  jg     L3
L14:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  xor    %edi,%edi
  cmp    $0x2,%ebp
  setg   %dil
  call   <assert@plt>
  jmp    L14
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  int z = 0;
  int w = 0;
  while (__VERIFIER_nondet_int()) {
    if (__VERIFIER_nondet_int()) {
      x++;
      y = y + 100;
    } else if (__VERIFIER_nondet_int()) {
      if (x >= 4) {
        x = x + 1;
        y = y + 1;
      }
    } else if (y > 10 * w)
      if (z >= 100 * x)
        y = -y;
    w = w + 1;
    z = z + 10;
  }
  if (x >= 4)
    assert(y > 2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L86
  nopl   0x0(%rax)
L54:
  add    $0x1,%r12d
  add    $0x64,%ebp
L79:
  add    $0xa,%ebx
L86:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L9
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  jne    L54
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %rax,%rax
  je     L11
  cmp    $0x3,%r12d
  jle    L79
  add    $0x1,%r12d
  add    $0x1,%ebp
  jmp    L79
  nopl   (%rax)
L11:
  cmp    %ebx,%ebp
  jle    L79
  imul   $0x64,%r12d,%edx
  mov    %ebp,%eax
  neg    %eax
  cmp    %ebx,%edx
  cmovle %eax,%ebp
  jmp    L79
  nopl   0x0(%rax,%rax,1)
L9:
  cmp    $0x3,%r12d
  jg     L15
L75:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L15:
  xor    %edi,%edi
  cmp    $0x2,%ebp
  setg   %dil
  call   <assert@plt>
  jmp    L75
```

assistant: ```c
int main() {
  int x = 0;
  int y = 0;
  int z = 0;
  int w = 0;
  while (__VERIFIER_nondet_int()) {
    if (__VERIFIER_nondet_int()) {
      x++;
      y = y + 100;
    } else if (__VERIFIER_nondet_int()) {
      if (x >= 4) {
        x = x + 1;
        y = y + 1;
      }
    } else if (y > 10 * w)
      if (z >= 100 * x)
        y = -y;
    w = w + 1;
    z = z + 10;
  }
  if (x >= 4)
    assert(y > 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    D8(%rip),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(int a) {
  static int b = 1;
  return b + a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  lea    0x1(%rdi),%eax
  ret
```

assistant: ```c
int foo(int a) {
  static int b = 1;
  return b + a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  lea    0x1(%rdi),%eax
  ret
```

assistant: ```c
int foo(int a) {
  static int b = 1;
  return b + a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  lea    0x1(%rdi),%eax
  ret
```

assistant: ```c
int foo(int a) {
  static int b = 1;
  return b + a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arr_uint16_sum_nostride>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movw   $0x0,-0xa(%rbp)
  jmp    L0
L1:
  movzwl -0xa(%rbp),%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %rax,-0x8(%rbp)
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L0:
  movzwl -0xa(%rbp),%eax
  cmp    %rax,-0x28(%rbp)
  ja     L1
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arr_uint16_sum_nostride(unsigned long int *pSum, unsigned short int *pSrc, unsigned long int num) {
  unsigned short int i;
  unsigned long int uSum = 0;
  for (i = 0; i < num; i++) {
    uSum += pSrc[i];
  }
  *pSum = uSum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arr_uint16_sum_nostride>:
  endbr64
  test   %rdx,%rdx
  je     L27
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%eax
L23:
  movzwl (%rsi,%rax,2),%eax
  add    %rax,%r8
  add    $0x1,%ecx
  movzwl %cx,%eax
  cmp    %rdx,%rax
  jb     L23
L1:
  mov    %r8,(%rdi)
  ret
L27:
  mov    %rdx,%r8
  jmp    L1
```

assistant: ```c
void arr_uint16_sum_nostride(unsigned long int *pSum, unsigned short int *pSrc, unsigned long int num) {
  unsigned short int i;
  unsigned long int uSum = 0;
  for (i = 0; i < num; i++) {
    uSum += pSrc[i];
  }
  *pSum = uSum;
}
```