ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  push   %r9
  mov    %r8d,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  push   $0x0
  push   0x68(%rsp)
  push   0x68(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movss  %xmm0,0x24(%rsp)
  call   <foo_1@plt>
  add    $0x20,%rsp
  mov    %r12d,%ecx
  mov    %r13d,%r9d
  movsd  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  push   %r14
  mov    %ebp,%edi
  push   $0x1
  fldt   0x60(%rsp)
  mov    %ebx,%r8d
  mov    %r12d,%edx
  xorpd  D16(%rip),%xmm1
  mov    %r15d,%esi
  neg    %ecx
  xorps  D15(%rip),%xmm0
  fchs
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <foo_1@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type: byte[16]
name: extract_symbolic_data
arguments: tag: D15
type: byte[16]

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D15": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void __attribute__((__no__)) foo(float f, double d, long double ld, int res_unord, int res_isnan, int res_isinf, int res_isfin, int res_isnorm, int classification) {
  foo_1(f, d, ld, res_unord, res_isnan, res_isinf, res_isinf, res_isfin, res_isnorm, 0, classification);
  foo_1(-f, -d, -ld, res_unord, res_isnan, res_isinf, -res_isinf, res_isfin, res_isnorm, 1, classification);
}
```
user: Translate the below assembly code into C programming language:

```asm
<foo>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %r8d,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x18,%rsp
  push   %r9
  mov    %r8d,%r9d
  mov    %ecx,%r8d
  mov    %edx,%ecx
  push   $0x0
  push   0x68(%rsp)
  push   0x68(%rsp)
  movsd  %xmm1,0x28(%rsp)
  movss  %xmm0,0x24(%rsp)
  call   <foo_1@plt>
  add    $0x20,%rsp
  mov    %r12d,%ecx
  mov    %r13d,%r9d
  movsd  0x8(%rsp),%xmm1
  movss  0x4(%rsp),%xmm0
  push   %r14
  mov    %ebp,%edi
  push   $0x1
  fldt   0x60(%rsp)
  mov    %ebx,%r8d
  mov    %r12d,%edx
  xorpd  D11(%rip),%xmm1
  mov    %r15d,%esi
  neg    %ecx
  xorps  D16(%rip),%xmm0
  fchs
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <foo_1@plt>
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D11
type: byte[16]
name: disassemble_data
arguments: label: D16
type: byte[16]

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void __attribute__((__no__)) foo(float f, double d, long double ld, int res_unord, int res_isnan, int res_isinf, int res_isfin, int res_isnorm, int classification) {
  foo_1(f, d, ld, res_unord, res_isnan, res_isinf, res_isinf, res_isfin, res_isnorm, 0, classification);
  foo_1(-f, -d, -ld, res_unord, res_isnan, res_isinf, -res_isinf, res_isfin, res_isnorm, 1, classification);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L5
  mov    -0x14(%rbp),%eax
  jmp    L0
L5:
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fibonacci>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fibonacci>
  add    %ebx,%eax
L0:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fibonacci(int n) {
  if (n < 2) {
    return n;
  }
  return fibonacci(n - 2) + fibonacci(n - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fibonacci>:
  endbr64
  mov    %edi,%eax
  cmp    $0x1,%edi
  jle    L7
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    -0x2(%rdi),%edi
  call   <fibonacci>
  mov    %eax,%ebp
  lea    -0x1(%rbx),%edi
  call   <fibonacci>
  add    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  ret
```

assistant: ```c
int fibonacci(int n) {
  if (n < 2) {
    return n;
  }
  return fibonacci(n - 2) + fibonacci(n - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L1:
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <test@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x9,-0x4(%rbp)
  jle    L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void bar(int parm1, int parm2) {
  int i;
  for (i = 0; i < 10; i++) {
    test(0, 0, parm1, parm2, i);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bar>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %esi,%ebp
  mov    $0x0,%ebx
L1:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <test@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bar(int parm1, int parm2) {
  int i;
  for (i = 0; i < 10; i++) {
    test(0, 0, parm1, parm2, i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nop
L8:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x1,%ebx
  call   <test@plt>
  cmp    $0xa,%ebx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bar(int parm1, int parm2) {
  int i;
  for (i = 0; i < 10; i++) {
    test(0, 0, parm1, parm2, i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bar>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nop
L4:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r12d,%edx
  xor    %esi,%esi
  xor    %edi,%edi
  add    $0x1,%ebx
  call   <test@plt>
  cmp    $0xa,%ebx
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void bar(int parm1, int parm2) {
  int i;
  for (i = 0; i < 10; i++) {
    test(0, 0, parm1, parm2, i);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<check_uninstall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %rdi,-0x128(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x128(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x118(%rbp)
  cmpq   $0x0,-0x118(%rbp)
  je     L2
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  mov    -0x118(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  lea    -0x110(%rbp),%rax
  lea    D17(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L2:
  mov    $0x0,%eax
L16:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string

tool: D3: r

tool: D17: #### UNINSTALL SCRIPT

assistant: ```c
int check_uninstall(const char *path) {
  FILE *f = fopen(path, "r");
  if (f) {
    char line[256];
    fgets(line, sizeof(line), f);
    fgets(line, sizeof(line), f);
    fclose(f);
    return strstr(line, "#### UNINSTALL SCRIPT") == NULL;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_uninstall>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  jne    L29
L16:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    %rsp,%rbp
  mov    %rbx,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D7: r

tool: D19: #### UNINSTALL SCRIPT

assistant: ```c
int check_uninstall(const char *path) {
  FILE *f = fopen(path, "r");
  if (f) {
    char line[256];
    fgets(line, sizeof(line), f);
    fgets(line, sizeof(line), f);
    fclose(f);
    return strstr(line, "#### UNINSTALL SCRIPT") == NULL;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<check_uninstall>:
  endbr64
  push   %r12
  lea    D4(%rip),%rsi
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  test   %rbp,%rbp
  je     L1
  mov    %rsp,%r12
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L1:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D4: r

tool: D2: #### UNINSTALL SCRIPT

assistant: ```c
int check_uninstall(const char *path) {
  FILE *f = fopen(path, "r");
  if (f) {
    char line[256];
    fgets(line, sizeof(line), f);
    fgets(line, sizeof(line), f);
    fclose(f);
    return strstr(line, "#### UNINSTALL SCRIPT") == NULL;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_uninstall>:
  endbr64
  push   %r12
  lea    D0(%rip),%rsi
  push   %rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  test   %rbp,%rbp
  je     L0
  mov    %rsp,%r12
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdx
  mov    $0x100,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D6(%rip),%rsi
  mov    %r12,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L0:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D0: r

tool: D6: #### UNINSTALL SCRIPT

assistant: ```c
int check_uninstall(const char *path) {
  FILE *f = fopen(path, "r");
  if (f) {
    char line[256];
    fgets(line, sizeof(line), f);
    fgets(line, sizeof(line), f);
    fclose(f);
    return strstr(line, "#### UNINSTALL SCRIPT") == NULL;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<my_tmpnam>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <tmpnam@plt>
  mov    %rax,-0x40(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%ecx
  mov    -0x48(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
  jmp    L10
L1:
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x38(%rbp),%rax
L10:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: /tmp/%s.%d

assistant: ```c
char *my_tmpnam(char *base) {
  char *tmp;
  char *result;
  tmp = tmpnam((char *)NULL);
  if (tmp == NULL) {
    char str[40];
    sprintf(str, "/tmp/%s.%d", base, (int)getpid());
    result = (char *)malloc((strlen(str) + 1) * sizeof(char));
    strcpy(result, str);
    return result;
  }
  result = (char *)malloc((strlen(tmp) + 1) * sizeof(char));
  strcpy(result, tmp);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<my_tmpnam>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <tmpnam@plt>
  test   %rax,%rax
  je     L18
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L2:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    %rbp,%rax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %rsp,%rbx
  mov    %eax,%ecx
  mov    %rbp,%rdx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L2
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D9
type: string

tool: D9: /tmp/%s.%d

assistant: ```c
char *my_tmpnam(char *base) {
  char *tmp;
  char *result;
  tmp = tmpnam((char *)NULL);
  if (tmp == NULL) {
    char str[40];
    sprintf(str, "/tmp/%s.%d", base, (int)getpid());
    result = (char *)malloc((strlen(str) + 1) * sizeof(char));
    strcpy(result, str);
    return result;
  }
  result = (char *)malloc((strlen(tmp) + 1) * sizeof(char));
  strcpy(result, tmp);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_tmpnam>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <tmpnam@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L17
L29:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x38,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <getpid@plt>
  mov    %r12,%rdx
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <sprintf@plt>
  jmp    L29
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4: /tmp/%s.%d

assistant: ```c
char *my_tmpnam(char *base) {
  char *tmp;
  char *result;
  tmp = tmpnam((char *)NULL);
  if (tmp == NULL) {
    char str[40];
    sprintf(str, "/tmp/%s.%d", base, (int)getpid());
    result = (char *)malloc((strlen(str) + 1) * sizeof(char));
    strcpy(result, str);
    return result;
  }
  result = (char *)malloc((strlen(tmp) + 1) * sizeof(char));
  strcpy(result, tmp);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<my_tmpnam>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <tmpnam@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
L11:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <getpid@plt>
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%ecx
  call   <sprintf@plt>
  jmp    L11
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string

tool: D0: /tmp/%s.%d

assistant: ```c
char *my_tmpnam(char *base) {
  char *tmp;
  char *result;
  tmp = tmpnam((char *)NULL);
  if (tmp == NULL) {
    char str[40];
    sprintf(str, "/tmp/%s.%d", base, (int)getpid());
    result = (char *)malloc((strlen(str) + 1) * sizeof(char));
    strcpy(result, str);
    return result;
  }
  result = (char *)malloc((strlen(tmp) + 1) * sizeof(char));
  strcpy(result, tmp);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<USED_IN_BOX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L28:
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L36:
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%eax
  add    %ecx,%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x24(%rbp)
  jne    L57
  mov    $0x1,%eax
  jmp    L44
L57:
  addl   $0x1,-0x4(%rbp)
L27:
  cmpl   $0x2,-0x4(%rbp)
  jle    L36
  addl   $0x1,-0x8(%rbp)
L0:
  cmpl   $0x2,-0x8(%rbp)
  jle    L28
  mov    $0x0,%eax
L44:
  pop    %rbp
  ret
```

assistant: ```c
int USED_IN_BOX(int grid[9][9], int star_row, int start_col, int num) {
  int row, col;
  for (row = 0; row < 3; row++)
    for (col = 0; col < 3; col++)
      if (grid[row + star_row][col + start_col] == num)
        return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<USED_IN_BOX>:
  endbr64
  movslq %esi,%rsi
  lea    (%rsi,%rsi,8),%rax
  movslq %edx,%rdx
  add    %rax,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    0x6c(%rdi,%rdx,1),%rsi
L33:
  mov    %rax,%rdx
  cmp    (%rax),%ecx
  je     L37
  cmp    0x4(%rax),%ecx
  je     L36
  cmp    %ecx,0x8(%rdx)
  je     L39
  add    $0x24,%rax
  cmp    %rsi,%rax
  jne    L33
  mov    $0x0,%eax
  ret
L36:
  mov    $0x1,%eax
  ret
L39:
  mov    $0x1,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int USED_IN_BOX(int grid[9][9], int star_row, int start_col, int num) {
  int row, col;
  for (row = 0; row < 3; row++)
    for (col = 0; col < 3; col++)
      if (grid[row + star_row][col + start_col] == num)
        return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<USED_IN_BOX>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rsi,%rsi,8),%rax
  add    %rax,%rdx
  shl    $0x2,%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    0x6c(%rdi,%rdx,1),%rdx
L6:
  cmp    %ecx,(%rax)
  je     L34
  cmp    0x4(%rax),%ecx
  je     L34
  cmp    %ecx,0x8(%rax)
  je     L34
  add    $0x24,%rax
  cmp    %rdx,%rax
  jne    L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int USED_IN_BOX(int grid[9][9], int star_row, int start_col, int num) {
  int row, col;
  for (row = 0; row < 3; row++)
    for (col = 0; col < 3; col++)
      if (grid[row + star_row][col + start_col] == num)
        return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<USED_IN_BOX>:
  endbr64
  movslq %esi,%rsi
  mov    %rdi,%rax
  movslq %edx,%rdx
  lea    (%rsi,%rsi,8),%rdi
  shl    $0x2,%rdx
  shl    $0x2,%rdi
  lea    (%rdi,%rdx,1),%rsi
  add    %rax,%rsi
  cmp    (%rsi),%ecx
  je     L26
  cmp    0x4(%rsi),%ecx
  je     L26
  cmp    0x8(%rsi),%ecx
  je     L26
  lea    0x24(%rdx,%rdi,1),%rsi
  add    %rax,%rsi
  cmp    (%rsi),%ecx
  je     L26
  cmp    0x4(%rsi),%ecx
  je     L26
  cmp    0x8(%rsi),%ecx
  je     L26
  lea    0x48(%rdx,%rdi,1),%rdx
  add    %rdx,%rax
  cmp    (%rax),%ecx
  je     L26
  cmp    0x4(%rax),%ecx
  je     L26
  cmp    %ecx,0x8(%rax)
  sete   %al
  movzbl %al,%eax
  ret
  nop
L26:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int USED_IN_BOX(int grid[9][9], int star_row, int start_col, int num) {
  int row, col;
  for (row = 0; row < 3; row++)
    for (col = 0; col < 3; col++)
      if (grid[row + star_row][col + start_col] == num)
        return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<tempFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
data_type: string

tool: D6: tempFunction is called, a = %d, b = %d /n

assistant: ```c
int tempFunction(int a, int b) {
  printf("tempFunction is called, a = %d, b = %d /n", a, b);
  return (a + b);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tempFunction>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %esi,%edx
  mov    %edi,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    (%rbx,%rbp,1),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
data_type: string

tool: D0: tempFunction is called, a = %d, b = %d /n

assistant: ```c
int tempFunction(int a, int b) {
  printf("tempFunction is called, a = %d, b = %d /n", a, b);
  return (a + b);
}
```
user: What is the c source code of the assembly code below?

```asm
<tempFunction>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    D9(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string

tool: D9: tempFunction is called, a = %d, b = %d /n

assistant: ```c
int tempFunction(int a, int b) {
  printf("tempFunction is called, a = %d, b = %d /n", a, b);
  return (a + b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tempFunction>:
  endbr64
  push   %rbp
  mov    %esi,%edx
  mov    %esi,%ebp
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  lea    D5(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  lea    (%rbx,%rbp,1),%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: tempFunction is called, a = %d, b = %d /n

assistant: ```c
int tempFunction(int a, int b) {
  printf("tempFunction is called, a = %d, b = %d /n", a, b);
  return (a + b);
}
```