user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<findRoots>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %r8,-0x40(%rbp)
  mov    %r9,-0x48(%rbp)
  mov    -0x28(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x24(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  lea    0x0(,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  ja     L9
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jp     L18
  pxor   %xmm0,%xmm0
  ucomisd -0x18(%rbp),%xmm0
  jne    L18
L9:
  mov    -0x48(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L68
L18:
  mov    -0x48(%rbp),%rax
  movl   $0x2,(%rax)
L68:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0x24(%rbp)
  je     L78
  cmpl   $0x0,-0x28(%rbp)
  je     L78
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L29
  cmp    $0x2,%eax
  je     L94
  jmp    L79
L29:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  sub    -0x28(%rbp),%eax
  mov    -0x24(%rbp),%edx
  lea    (%rdx,%rdx,1),%esi
  cltd
  idiv   %esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x28(%rbp),%eax
  neg    %eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    -0x24(%rbp),%edx
  lea    (%rdx,%rdx,1),%ebx
  cltd
  idiv   %ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  jmp    L69
L94:
  mov    -0x28(%rbp),%eax
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x24(%rbp),%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x18(%rbp),%xmm0
  movq   D13(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    -0x24(%rbp),%edx
  lea    (%rdx,%rdx,1),%ecx
  cltd
  idiv   %ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0x40(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L69:
  jmp    L79
L78:
  cmpl   $0x0,-0x24(%rbp)
  jne    L32
  mov    -0x2c(%rbp),%eax
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x28(%rbp),%xmm1
  divsd  %xmm1,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  %xmm0,(%rax)
L79:
  nop
L32:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D32
type_infered: string
name: disassemble_data
arguments: data_tag: D9
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D47
type_infered: string
name: disassemble_data
arguments: data_tag: D38
type_infered: string

tool: D32: 
det: %f

tool: D9: 
roc: %d

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D47: 
root1: %f

tool: D38: 
root2: %f

assistant: ```c
void findRoots(int a, int b, int c, double *r1, double *r2, int *roc) {
  double det = (b * b) - (4 * a * c);
  printf("\ndet: %f", det);
  if (det > 0 || det == 0)
    *roc = 1;
  else
    *roc = 2;
  printf("\nroc: %d", *roc);
  if (a != 0 && b != 0) {
    switch (*roc) {
    case 1:
      *r1 = (-b + sqrt(det)) / (2 * a);
      *r2 = (-b - sqrt(det)) / (2 * a);
      break;
    case 2:
      *r1 = (double)-b / (2 * a);
      *r2 = sqrt(-det) / (2 * a);
      printf("\nroot1: %f", *r1);
      printf("\nroot2: %f", *r2);
      break;
    }
  } else if (a == 0)
    *r1 = (double)-c / b;
  return;
}
```