ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitwise_and_of_range>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  je     L54
  mov    %esi,%r14d
  test   %esi,%esi
  je     L54
  mov    %edi,%ebp
  xor    %r12d,%r12d
  mov    $0x1,%r13d
  jmp    L8
  nopl   0x0(%rax)
L24:
  mov    %r13d,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  sub    %eax,%r14d
  add    %eax,%r12d
  sub    %eax,%ebp
  je     L16
  test   %r14d,%r14d
  je     L16
L8:
  mov    %ebp,%edi
  call   <get_msb@plt>
  mov    %r14d,%edi
  mov    %eax,%ebx
  call   <get_msb@plt>
  cmp    %eax,%ebx
  je     L24
L16:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L54:
  xor    %r12d,%r12d
  jmp    L16
```

assistant: ```c
int bitwise_and_of_range(int srange, int erange) {
  int s_msb = 0;
  int e_msb = 0;
  int result = 0;
  while (srange && erange) {
    s_msb = get_msb(srange);
    e_msb = get_msb(erange);
    if (s_msb == e_msb) {
      srange -= 1 << s_msb;
      erange -= 1 << s_msb;
      result += 1 << s_msb;
    } else {
      break;
    }
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<astGEBuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <Report@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: string

tool: D1: astGEBuf

assistant: ```c
int astGEBuf(void) {
  Report("astGEBuf");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<astGEBuf>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <Report@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: astGEBuf

assistant: ```c
int astGEBuf(void) {
  Report("astGEBuf");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<astGEBuf>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <Report@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: astGEBuf

assistant: ```c
int astGEBuf(void) {
  Report("astGEBuf");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<astGEBuf>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <Report@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D1: astGEBuf

assistant: ```c
int astGEBuf(void) {
  Report("astGEBuf");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%rax
  neg    %rax
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L23
L21:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jg     L11
  mov    $0x0,%edi
  call   <exit@plt>
L11:
  addq   $0x4,-0x10(%rbp)
L23:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L21
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(int *sp, int cnt) {
  int *p, *top;
  top = sp;
  sp -= cnt;
  for (p = sp; p <= top; p++)
    if (*p < 2)
      exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<foo>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movslq %esi,%rsi
  shl    $0x2,%rsi
  mov    %rdi,%rbx
  sub    %rsi,%rbx
  cmp    %rbx,%rdi
  jae    L22
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jb     L8
L22:
  cmpl   $0x1,(%rbx)
  jg     L10
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L10
```

assistant: ```c
void foo(int *sp, int cnt) {
  int *p, *top;
  top = sp;
  sp -= cnt;
  for (p = sp; p <= top; p++)
    if (*p < 2)
      exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  shl    $0x2,%rsi
  mov    %rdi,%rbx
  sub    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rbx,%rdi
  jb     L8
  mov    %rdi,%rbp
  jmp    L23
  nopl   0x0(%rax)
L11:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jb     L8
L23:
  cmpl   $0x1,(%rbx)
  jg     L11
  xor    %edi,%edi
  add    $0x4,%rbx
  call   <exit@plt>
  cmp    %rbx,%rbp
  jae    L23
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void foo(int *sp, int cnt) {
  int *p, *top;
  top = sp;
  sp -= cnt;
  for (p = sp; p <= top; p++)
    if (*p < 2)
      exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  movslq %esi,%rsi
  push   %rbx
  shl    $0x2,%rsi
  mov    %rdi,%rbx
  sub    %rsi,%rbx
  sub    $0x8,%rsp
  cmp    %rbx,%rdi
  jb     L8
  mov    %rdi,%rbp
  jmp    L42
  nopl   0x0(%rax)
L23:
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jb     L8
L42:
  cmpl   $0x1,(%rbx)
  jg     L23
  xor    %edi,%edi
  add    $0x4,%rbx
  call   <exit@plt>
  cmp    %rbx,%rbp
  jae    L42
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void foo(int *sp, int cnt) {
  int *p, *top;
  top = sp;
  sp -= cnt;
  for (p = sp; p <= top; p++)
    if (*p < 2)
      exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,-0x38(%rbp)
  jmp    L10
L29:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    %edx,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x38(%rbp)
L10:
  cmpl   $0x1770,-0x38(%rbp)
  jle    L29
  lea    D27(%rip),%rax
  mov    %rax,%rdx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x34(%rbp)
  jmp    L19
L43:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%edx
  mov    -0x34(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L19:
  cmpl   $0x6,-0x34(%rbp)
  jle    L43
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D27
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string

tool: D27: Frequency

tool: D9: Face

tool: D23: %s   %s


tool: D24: %d      %d


assistant: ```c
int main() {
  int roll;
  int face;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s   %s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%d      %d\n", face, frequency[face]);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x1770,%ebx
L18:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L18
  lea    D32(%rip),%rdx
  lea    D14(%rip),%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%ebx
  lea    D38(%rip),%rbp
L4:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x7,%rbx
  jne    L4
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D32
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string
name: unpack_data
arguments: data_label: D39
type_guessed: string
name: unpack_data
arguments: data_label: D38
type_guessed: string

tool: D32: Frequency

tool: D14: Face

tool: D39: %s   %s


tool: D38: %d      %d


assistant: ```c
int main() {
  int roll;
  int face;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s   %s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%d      %d\n", face, frequency[face]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  mov    $0x1770,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L10
  lea    D17(%rip),%rdx
  lea    D23(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D12(%rip),%rdi
  mov    %rsp,%r12
  lea    D13(%rip),%rbp
  call   <printf@plt>
  nopl   0x0(%rax)
L22:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L22
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D23
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D17: Frequency

tool: D23: Face

tool: D12: %s   %s


tool: D13: %d      %d


assistant: ```c
int main() {
  int roll;
  int face;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s   %s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%d      %d\n", face, frequency[face]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  mov    $0x1770,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  movq   $0x0,0x10(%rsp)
  movl   $0x0,0x18(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L12
  lea    D27(%rip),%rdx
  lea    D11(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    D30(%rip),%rdi
  mov    %rsp,%r12
  lea    D2(%rip),%rbp
  call   <printf@plt>
  nopl   0x0(%rax)
L2:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L2
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D27
data_type: string
name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D2
data_type: string

tool: D27: Frequency

tool: D11: Face

tool: D30: %s   %s


tool: D2: %d      %d


assistant: ```c
int main() {
  int roll;
  int face;
  int frequency[7] = {0};
  srand(time(NULL));
  for (roll = 1; roll <= 6000; roll++) {
    face = 1 + rand() % 6;
    ++frequency[face];
  }
  printf("%s   %s\n", "Face", "Frequency");
  for (face = 1; face < 7; face++) {
    printf("%d      %d\n", face, frequency[face]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  jle    L54
  mov    -0xc(%rbp),%eax
  cmp    $0xc8,%eax
  jle    L69
L54:
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L2
L69:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L3
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  jmp    L18
L3:
  mov    -0xc(%rbp),%eax
L18:
  mov    %eax,-0xc(%rbp)
  jmp    L49
L99:
  mov    -0xc(%rbp),%eax
  cmp    $0xa,%eax
  jle    L17
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L93
L17:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L93:
  mov    -0xc(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    $0x9,%eax
  jg     L99
  mov    $0x0,%eax
L2:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L89
  call   <__stack_chk_fail@plt>
L89:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D59
type: string
name: disassemble_data
arguments: label: D32
type: string
name: disassemble_data
arguments: label: D45
type: string
name: disassemble_data
arguments: label: D52
type: string
name: disassemble_data
arguments: label: D36
type: string
name: disassemble_data
arguments: label: D55
type: string

tool: D59: Ingrese un numero entre el 11 y el 200: 

tool: D32: %d

tool: D45: El numero ingresado no entra dentro del rango

tool: D52: 
Numeros pares entre el %d y el 10:


tool: D36: %d, 

tool: D55: %d



assistant: ```c
int main() {
  int high;
  printf("Ingrese un numero entre el 11 y el 200: ");
  scanf("%d", &high);
  if (high < 10 || high > 200) {
    printf("El numero ingresado no entra dentro del rango\n");
    return 1;
  }
  printf("\nNumeros pares entre el %d y el 10:\n", high);
  high = (high % 2 == 0) ? high : high - 1;
  while (high >= 10) {
    if (high > 10)
      printf("%d, ", high);
    else
      printf("%d\n\n", high);
    high -= 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0xbe,%eax
  ja     L43
  lea    D43(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0xffffffff,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jle    L23
  lea    D22(%rip),%rbp
  lea    D27(%rip),%rbx
  jmp    L5
L43:
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L33
L60:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L46:
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jle    L84
L5:
  cmp    $0xa,%esi
  jle    L60
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L46
L84:
  mov    $0x0,%eax
L33:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    $0x0,%eax
  jmp    L33
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D46
data_type: string
name: parse_data
arguments: tag: D31
data_type: string
name: parse_data
arguments: tag: D43
data_type: string
name: parse_data
arguments: tag: D22
data_type: string
name: parse_data
arguments: tag: D27
data_type: string
name: parse_data
arguments: tag: D38
data_type: string

tool: D46: Ingrese un numero entre el 11 y el 200: 

tool: D31: %d

tool: D43: 
Numeros pares entre el %d y el 10:


tool: D22: %d



tool: D27: %d, 

tool: D38: El numero ingresado no entra dentro del rango

assistant: ```c
int main() {
  int high;
  printf("Ingrese un numero entre el 11 y el 200: ");
  scanf("%d", &high);
  if (high < 10 || high > 200) {
    printf("El numero ingresado no entra dentro del rango\n");
    return 1;
  }
  printf("\nNumeros pares entre el %d y el 10:\n", high);
  high = (high % 2 == 0) ? high : high - 1;
  while (high >= 10) {
    if (high > 10)
      printf("%d, ", high);
    else
      printf("%d\n\n", high);
    high -= 2;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0xbe,%eax
  ja     L48
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0xffffffff,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jle    L16
  lea    D38(%rip),%rbp
  lea    D11(%rip),%rbx
  jmp    L72
  nop
L24:
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jle    L16
L72:
  cmp    $0xa,%esi
  jne    L24
  mov    $0xa,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jg     L72
L16:
  xor    %eax,%eax
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L48:
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L39
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D13
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D36
type_infered: string
name: unpack_data
arguments: data_tag: D38
type_infered: string
name: unpack_data
arguments: data_tag: D11
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D13: Ingrese un numero entre el 11 y el 200: 

tool: D43: %d

tool: D36: 
Numeros pares entre el %d y el 10:


tool: D38: %d



tool: D11: %d, 

tool: D17: El numero ingresado no entra dentro del rango

assistant: ```c
int main() {
  int high;
  printf("Ingrese un numero entre el 11 y el 200: ");
  scanf("%d", &high);
  if (high < 10 || high > 200) {
    printf("El numero ingresado no entra dentro del rango\n");
    return 1;
  }
  printf("\nNumeros pares entre el %d y el 10:\n", high);
  high = (high % 2 == 0) ? high : high - 1;
  while (high >= 10) {
    if (high > 10)
      printf("%d, ", high);
    else
      printf("%d\n\n", high);
    high -= 2;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    -0xa(%rsi),%eax
  cmp    $0xbe,%eax
  ja     L57
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    %esi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0xffffffff,%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jle    L38
  lea    D5(%rip),%rbp
  lea    D59(%rip),%rbx
  nopl   0x0(%rax)
L48:
  mov    %rbx,%rdi
  cmp    $0xa,%esi
  jne    L23
  mov    $0xa,%esi
  mov    %rbp,%rdi
L23:
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x2(%rax),%esi
  mov    %esi,0x4(%rsp)
  cmp    $0x9,%esi
  jg     L48
L38:
  xor    %eax,%eax
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L57:
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L31
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D19
datatype: string
name: retrieve_data
arguments: tag: D46
datatype: string
name: retrieve_data
arguments: tag: D3
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D59
datatype: string
name: retrieve_data
arguments: tag: D43
datatype: string

tool: D19: Ingrese un numero entre el 11 y el 200: 

tool: D46: %d

tool: D3: 
Numeros pares entre el %d y el 10:


tool: D5: %d



tool: D59: %d, 

tool: D43: El numero ingresado no entra dentro del rango

assistant: ```c
int main() {
  int high;
  printf("Ingrese un numero entre el 11 y el 200: ");
  scanf("%d", &high);
  if (high < 10 || high > 200) {
    printf("El numero ingresado no entra dentro del rango\n");
    return 1;
  }
  printf("\nNumeros pares entre el %d y el 10:\n", high);
  high = (high % 2 == 0) ? high : high - 1;
  while (high >= 10) {
    if (high > 10)
      printf("%d, ", high);
    else
      printf("%d\n\n", high);
    high -= 2;
  }
  return 0;
}
```