ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<timer_start_handler>:
  endbr64
  push   %r13
  lea    D72(%rip),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D27(%rip),%rsi
  sub    $0x8,%rsp
  call   <trace_seq_printf@plt>
  xor    %r9d,%r9d
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D91(%rip),%rcx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <pevent_print_num_field@plt>
  cmp    $0xffffffff,%eax
  je     L9
L4:
  mov    %rbx,%r8
  mov    %r12,%rdx
  xor    %r9d,%r9d
  mov    %rbp,%rdi
  lea    D45(%rip),%rcx
  lea    D47(%rip),%rsi
  call   <pevent_print_func_field@plt>
  lea    D44(%rip),%r13
  mov    %rbp,%rdi
  lea    D14(%rip),%rsi
  call   <trace_seq_printf@plt>
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    $0x1,%r9d
  lea    D24(%rip),%rcx
  mov    %rbp,%rdi
  call   <pevent_print_num_field@plt>
  mov    %rbp,%rdi
  lea    D71(%rip),%rsi
  call   <trace_seq_printf@plt>
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x1,%r9d
  lea    D62(%rip),%rcx
  call   <pevent_print_num_field@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%r9d
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %r13,%rsi
  lea    D49(%rip),%rcx
  mov    %rbp,%rdi
  call   <pevent_print_num_field@plt>
  jmp    L4
```

tool_calls: name: disassemble_data
arguments: data_tag: D72
datatype: string
name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D91
datatype: string
name: disassemble_data
arguments: data_tag: D45
datatype: string
name: disassemble_data
arguments: data_tag: D47
datatype: string
name: disassemble_data
arguments: data_tag: D44
datatype: string
name: disassemble_data
arguments: data_tag: D14
datatype: string
name: disassemble_data
arguments: data_tag: D24
datatype: string
name: disassemble_data
arguments: data_tag: D71
datatype: string
name: disassemble_data
arguments: data_tag: D62
datatype: string
name: disassemble_data
arguments: data_tag: D49
datatype: string

tool: D72: 0x%llx

tool: D27: hrtimer=

tool: D91: timer

tool: D45: function

tool: D47:  function=%s

tool: D44: %llu

tool: D14:  expires=

tool: D24: expires

tool: D71:  softexpires=

tool: D62: softexpires

tool: D49: hrtimer

assistant: ```c
int timer_start_handler(struct trace_seq *s, struct pevent_record *record, struct event_format *event, void *context) {
  trace_seq_printf(s, "hrtimer=");
  if (pevent_print_num_field(s, "0x%llx", event, "timer", record, 0) == -1)
    pevent_print_num_field(s, "0x%llx", event, "hrtimer", record, 1);
  pevent_print_func_field(s, " function=%s", event, "function", record, 0);
  trace_seq_printf(s, " expires=");
  pevent_print_num_field(s, "%llu", event, "expires", record, 1);
  trace_seq_printf(s, " softexpires=");
  pevent_print_num_field(s, "%llu", event, "softexpires", record, 1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<timer_start_handler>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D27(%rip),%rsi
  sub    $0x8,%rsp
  call   <trace_seq_printf@plt>
  xor    %r9d,%r9d
  mov    %rbx,%r8
  mov    %r12,%rdx
  lea    D6(%rip),%rcx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <pevent_print_num_field@plt>
  cmp    $0xffffffff,%eax
  je     L14
L5:
  mov    %rbx,%r8
  mov    %r12,%rdx
  xor    %r9d,%r9d
  mov    %rbp,%rdi
  lea    D15(%rip),%rcx
  lea    D25(%rip),%rsi
  call   <pevent_print_func_field@plt>
  lea    D3(%rip),%r13
  mov    %rbp,%rdi
  lea    D59(%rip),%rsi
  call   <trace_seq_printf@plt>
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    $0x1,%r9d
  lea    D65(%rip),%rcx
  mov    %rbp,%rdi
  call   <pevent_print_num_field@plt>
  mov    %rbp,%rdi
  lea    D78(%rip),%rsi
  call   <trace_seq_printf@plt>
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  mov    $0x1,%r9d
  lea    D42(%rip),%rcx
  call   <pevent_print_num_field@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%r9d
  mov    %rbx,%r8
  mov    %r12,%rdx
  mov    %r13,%rsi
  lea    D108(%rip),%rcx
  mov    %rbp,%rdi
  call   <pevent_print_num_field@plt>
  jmp    L5
```

tool_calls: name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D27
type: string
name: parse_data
arguments: label: D6
type: string
name: parse_data
arguments: label: D15
type: string
name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D3
type: string
name: parse_data
arguments: label: D59
type: string
name: parse_data
arguments: label: D65
type: string
name: parse_data
arguments: label: D78
type: string
name: parse_data
arguments: label: D42
type: string
name: parse_data
arguments: label: D108
type: string

tool: D10: 0x%llx

tool: D27: hrtimer=

tool: D6: timer

tool: D15: function

tool: D25:  function=%s

tool: D3: %llu

tool: D59:  expires=

tool: D65: expires

tool: D78:  softexpires=

tool: D42: softexpires

tool: D108: hrtimer

assistant: ```c
int timer_start_handler(struct trace_seq *s, struct pevent_record *record, struct event_format *event, void *context) {
  trace_seq_printf(s, "hrtimer=");
  if (pevent_print_num_field(s, "0x%llx", event, "timer", record, 0) == -1)
    pevent_print_num_field(s, "0x%llx", event, "hrtimer", record, 1);
  pevent_print_func_field(s, " function=%s", event, "function", record, 0);
  trace_seq_printf(s, " expires=");
  pevent_print_num_field(s, "%llu", event, "expires", record, 1);
  trace_seq_printf(s, " softexpires=");
  pevent_print_num_field(s, "%llu", event, "softexpires", record, 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<report_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <get_pid@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <grtestmod_write@plt>
L8:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
report_start() {
  if (!get_pid())
    grtestmod_write(4, 1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<report_start>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_pid@plt>
  test   %eax,%eax
  je     L3
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <grtestmod_write@plt>
  jmp    L11
```

assistant: ```c
report_start() {
  if (!get_pid())
    grtestmod_write(4, 1);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<report_start>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_pid@plt>
  test   %eax,%eax
  je     L9
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <grtestmod_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
report_start() {
  if (!get_pid())
    grtestmod_write(4, 1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<report_start>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_pid@plt>
  test   %eax,%eax
  je     L2
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%esi
  mov    $0x4,%edi
  call   <grtestmod_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
report_start() {
  if (!get_pid())
    grtestmod_write(4, 1);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x42414141,-0x12(%rbp)
  movb   $0x42,-0xe(%rbp)
  movl   $0x42424143,-0xd(%rbp)
  movb   $0x42,-0x9(%rbp)
  lea    -0xd(%rbp),%rdx
  lea    -0x12(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <newhanoi@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  char cur[5] = "AAABB";
  char obj[5] = "CABBB";
  newhanoi(cur, obj);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x42414141,0xe(%rsp)
  movb   $0x42,0x12(%rsp)
  movl   $0x42424143,0x13(%rsp)
  movb   $0x42,0x17(%rsp)
  lea    0x13(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  call   <newhanoi@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char cur[5] = "AAABB";
  char obj[5] = "CABBB";
  newhanoi(cur, obj);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x13(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  movl   $0x42414141,0xe(%rsp)
  movb   $0x42,0x12(%rsp)
  movl   $0x42424143,0x13(%rsp)
  movb   $0x42,0x17(%rsp)
  call   <newhanoi@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char cur[5] = "AAABB";
  char obj[5] = "CABBB";
  newhanoi(cur, obj);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x13(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  movl   $0x42414141,0xe(%rsp)
  movb   $0x42,0x12(%rsp)
  movl   $0x42424143,0x13(%rsp)
  movb   $0x42,0x17(%rsp)
  call   <newhanoi@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  char cur[5] = "AAABB";
  char obj[5] = "CABBB";
  newhanoi(cur, obj);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) int bar(int a, int b) {
  int c;
  c = a % b;
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int bar(int a, int b) {
  int c;
  c = a % b;
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bar>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int bar(int a, int b) {
  int c;
  c = a % b;
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
__attribute__((no)) int bar(int a, int b) {
  int c;
  c = a % b;
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<random_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L18:
  addl   $0x1,-0x4(%rbp)
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    D8(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%edx
  sar    %edx
  cmp    %edx,%eax
  jl     L18
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int random_number(void) {
  int i = 0;
  while (rand() < RAND_MAX / 2)
    ++i;
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<random_number>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  jmp    L16
L7:
  add    $0x1,%ebx
L16:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ecx
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%ecx
  jl     L7
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int random_number(void) {
  int i = 0;
  while (rand() < RAND_MAX / 2)
    ++i;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<random_number>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  mov    D4(%rip),%rbx
  jmp    L13
  nopw   0x0(%rax,%rax,1)
L14:
  add    $0x1,%r12d
L13:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%rbx),%edx
  mov    %eax,%r8d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%r8d
  jl     L14
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int random_number(void) {
  int i = 0;
  while (rand() < RAND_MAX / 2)
    ++i;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<random_number>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  sub    $0x8,%rsp
  mov    D6(%rip),%rbx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L0:
  add    $0x1,%r12d
L15:
  xor    %eax,%eax
  call   <rand@plt>
  mov    (%rbx),%edx
  mov    %eax,%r8d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%r8d
  jl     L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int random_number(void) {
  int i = 0;
  while (rand() < RAND_MAX / 2)
    ++i;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: Pi is about %.5f


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("Pi is about %.5f\n", argv);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
type: string

tool: D5: Pi is about %.5f


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("Pi is about %.5f\n", argv);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Pi is about %.5f


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("Pi is about %.5f\n", argv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: Pi is about %.5f


assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  printf("Pi is about %.5f\n", argv);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<j_rev_dct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L1:
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fast_idct_8@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  cmpl   $0x7,-0x4(%rbp)
  jle    L1
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L30:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <fast_idct_8@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x7,-0x4(%rbp)
  jle    L30
  nop
  leave
  ret
```

assistant: ```c
j_rev_dct(short *data) {
  int i, j, k, id;
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i * 8, 1);
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i, 8);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<j_rev_dct>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x80(%rdi),%r12
  mov    %rdi,%rbp
L18:
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <fast_idct_8@plt>
  add    $0x10,%rbp
  cmp    %r12,%rbp
  jne    L18
  lea    0x10(%rbx),%rbp
L7:
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <fast_idct_8@plt>
  add    $0x2,%rbx
  cmp    %rbp,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
j_rev_dct(short *data) {
  int i, j, k, id;
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i * 8, 1);
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i, 8);
}
```
user: What is the c source code of the assembly code below:

```asm
<j_rev_dct>:
  endbr64
  push   %r12
  lea    0x80(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L6:
  mov    %rbp,%rdi
  mov    $0x1,%esi
  add    $0x10,%rbp
  call   <fast_idct_8@plt>
  cmp    %r12,%rbp
  jne    L6
  lea    0x10(%rbx),%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbx,%rdi
  mov    $0x8,%esi
  add    $0x2,%rbx
  call   <fast_idct_8@plt>
  cmp    %rbp,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
j_rev_dct(short *data) {
  int i, j, k, id;
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i * 8, 1);
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i, 8);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<j_rev_dct>:
  endbr64
  push   %r12
  lea    0x80(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L5:
  mov    %rbp,%rdi
  mov    $0x1,%esi
  add    $0x10,%rbp
  call   <fast_idct_8@plt>
  cmp    %r12,%rbp
  jne    L5
  lea    0x10(%rbx),%rbp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rbx,%rdi
  mov    $0x8,%esi
  add    $0x2,%rbx
  call   <fast_idct_8@plt>
  cmp    %rbx,%rbp
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
j_rev_dct(short *data) {
  int i, j, k, id;
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i * 8, 1);
  for (i = 0; i < 8; i++)
    fast_idct_8(data + i, 8);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<kol_board_puti>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jle    L7
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <kol_board_puti>
L7:
  mov    -0x24(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  mov    %al,-0x11(%rbp)
  mov    $0x3f,%eax
  mov    $0x1,%esi
  movzbl -0x11(%rbp),%edx
  mov    %esi,%ebx
  mov    %edx,%ecx
  int    $0x40
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void kol_board_puti(int n) {
  char c;
  if (n > 1)
    kol_board_puti(n / 10);
  c = n % 10 + '0';
  asm volatile("int $0x40" ::"a"(63), "b"(1), "c"(c));
}
```
user: Translate the below assembly code into C programming language:

```asm
<kol_board_puti>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L4
L12:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  lea    0x30(%rbx),%ecx
  mov    $0x3f,%eax
  mov    $0x1,%ebx
  int    $0x40
  pop    %rbx
  ret
L4:
  movslq %edi,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <kol_board_puti>
  jmp    L12
```

assistant: ```c
void kol_board_puti(int n) {
  char c;
  if (n > 1)
    kol_board_puti(n / 10);
  c = n % 10 + '0';
  asm volatile("int $0x40" ::"a"(63), "b"(1), "c"(c));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<kol_board_puti>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%r12d
  jg     L16
L18:
  imul   $0x66666667,%r12,%rax
  mov    %ebp,%edx
  mov    $0x1,%ebx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  mov    $0x3f,%eax
  lea    0x30(%rbp),%ecx
  int    $0x40
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L16:
  imul   $0x66666667,%r12,%r13
  mov    %r12d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%r13
  sub    %eax,%r13d
  mov    %r13d,%r14d
  cmp    $0x13,%r12d
  jg     L39
L42:
  mov    $0xcccccccd,%eax
  mov    $0x1,%ebx
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  mov    $0x3f,%eax
  lea    0x30(%r13),%ecx
  int    $0x40
  jmp    L18
  nopl   0x0(%rax)
L39:
  mov    $0xcccccccd,%edi
  mov    %r14,%rbx
  imul   %rdi,%rbx
  shr    $0x23,%rbx
  mov    %ebx,%r15d
  cmp    $0xc7,%r12d
  jle    L4
  imul   %r15,%rdi
  shr    $0x23,%rdi
  call   <kol_board_puti>
L4:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    $0x3f,%eax
  lea    0x30(%rbx),%ecx
  mov    $0x1,%ebx
  int    $0x40
  jmp    L42
```

assistant: ```c
void kol_board_puti(int n) {
  char c;
  if (n > 1)
    kol_board_puti(n / 10);
  c = n % 10 + '0';
  asm volatile("int $0x40" ::"a"(63), "b"(1), "c"(c));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kol_board_puti>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%r12d
  jg     L34
L37:
  imul   $0x66666667,%r12,%rax
  mov    %ebp,%edx
  mov    $0x1,%ebx
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  mov    $0x3f,%eax
  lea    0x30(%rbp),%ecx
  int    $0x40
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L34:
  imul   $0x66666667,%r12,%r13
  mov    %r12d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%r13
  sub    %eax,%r13d
  mov    %r13d,%r14d
  cmp    $0x13,%r12d
  jg     L31
L40:
  mov    $0xcccccccd,%eax
  mov    $0x1,%ebx
  imul   %r14,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%r13d
  mov    $0x3f,%eax
  lea    0x30(%r13),%ecx
  int    $0x40
  jmp    L37
  nopl   0x0(%rax)
L31:
  mov    $0xcccccccd,%edi
  mov    %r14,%rbx
  imul   %rdi,%rbx
  shr    $0x23,%rbx
  mov    %ebx,%r15d
  cmp    $0xc7,%r12d
  jle    L20
  imul   %r15,%rdi
  shr    $0x23,%rdi
  call   <kol_board_puti>
L20:
  mov    $0xcccccccd,%eax
  imul   %r15,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  mov    $0x3f,%eax
  lea    0x30(%rbx),%ecx
  mov    $0x1,%ebx
  int    $0x40
  jmp    L40
```

assistant: ```c
void kol_board_puti(int n) {
  char c;
  if (n > 1)
    kol_board_puti(n / 10);
  c = n % 10 + '0';
  asm volatile("int $0x40" ::"a"(63), "b"(1), "c"(c));
}
```