ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_prime_cut>:
  endbr64
  push   %r13
  add    %edx,%edx
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   $0x1,%sil
  je     L44
  cmp    %edx,%esi
  jge    L30
L7:
  lea    -0x1(%rsi),%ebp
  xor    %eax,%eax
L20:
  movslq %eax,%rbx
  lea    D8(%rip),%r13
  cmp    %ebp,%eax
  jg     L8
L29:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jge    L29
L8:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L44:
  cmp    %edx,%esi
  jle    L7
  mov    %esi,%ebp
  sub    $0x2,%edx
  shr    $0x1f,%ebp
  sar    %edx
  add    %esi,%ebp
  neg    %edx
  sar    %ebp
  lea    -0x1(%rbp,%rdx,1),%eax
  sub    %edx,%ebp
  jmp    L20
  nopl   0x0(%rax)
L30:
  mov    %esi,%ebp
  sub    $0x2,%edx
  shr    $0x1f,%ebp
  sar    %edx
  add    %esi,%ebp
  neg    %edx
  sar    %ebp
  lea    (%rdx,%rbp,1),%eax
  sub    %edx,%ebp
  jmp    L20
```

tool_calls: name: parse_data
arguments: data_label: D8
datatype: string

tool: D8:  %d

assistant: ```c
void print_prime_cut(int primes[], int num_primes, int C) {
  int i, j;
  C = (num_primes & 0x1) ? (2 * C - 1) : (2 * C);
  if (C >= num_primes) {
    i = 0;
    j = num_primes - 1;
  } else if (num_primes & 0x1) {
    i = j = num_primes / 2;
    i = i - (C - 1) / 2;
    j = j + (C - 1) / 2;
  } else {
    i = num_primes / 2 - 1;
    j = num_primes / 2;
    i = i - (C - 2) / 2;
    j = j + (C - 2) / 2;
  }
  for (; i <= j; i++) {
    printf(" %d", primes[i]);
  }
  printf("\n");
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movss  D68(%rip),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D50(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd -0xc(%rbp),%xmm3
  movq   %xmm3,%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  movss  D68(%rip),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L23
  movss  D68(%rip),%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jne    L23
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L22
L23:
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L22:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D68
type_guessed: byte[4]
name: unpack_data
arguments: tag: D50
type_guessed: byte[4]
name: unpack_data
arguments: tag: D39
type_guessed: string
name: unpack_data
arguments: tag: D63
type_guessed: string
name: unpack_data
arguments: tag: D58
type_guessed: string

tool: D6: Machin epsilon

tool: {"D68": [0x00,0x00,0x80,0x3f]}

tool: {"D50": [0x95,0xbf,0x56,0x33]}

tool: D39: Sum: %e + %e = %.7e


tool: D63: Sum == 1.0f

tool: D58: Sum != 1.0f

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Machin epsilon\n");
  float a = 1.0f;
  float e = 0.00000005f;
  float sum = a + e;
  printf("Sum: %e + %e = %.7e\n", a, e, sum);
  if (sum == 1.0f) {
    printf("Sum == 1.0f\n");
  } else {
    printf("Sum != 1.0f\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  movsd  D34(%rip),%xmm0
  movapd %xmm0,%xmm2
  movsd  D2(%rip),%xmm1
  lea    D39(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  lea    D41(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D34
datatype: byte[8]
name: unpack_data
arguments: tag: D2
datatype: byte[8]
name: unpack_data
arguments: tag: D39
datatype: string
name: unpack_data
arguments: tag: D41
datatype: string

tool: D12: Machin epsilon

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D2": [0x00,0x00,0x00,0xa0,0xf2,0xd7,0x6a,0x3e]}

tool: D39: Sum: %e + %e = %.7e


tool: D41: Sum == 1.0f

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Machin epsilon\n");
  float a = 1.0f;
  float e = 0.00000005f;
  float sum = a + e;
  printf("Sum: %e + %e = %.7e\n", a, e, sum);
  if (sum == 1.0f) {
    printf("Sum == 1.0f\n");
  } else {
    printf("Sum != 1.0f\n");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rdi
  call   <puts@plt>
  movsd  D34(%rip),%xmm0
  mov    $0x3,%eax
  movsd  D8(%rip),%xmm1
  lea    D15(%rip),%rdi
  movapd %xmm0,%xmm2
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D26
data_type: string
name: extract_symbolic_data
arguments: data_tag: D34
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D8
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D15
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D26: Machin epsilon

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D8": [0x00,0x00,0x00,0xa0,0xf2,0xd7,0x6a,0x3e]}

tool: D15: Sum: %e + %e = %.7e


tool: D25: Sum == 1.0f

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Machin epsilon\n");
  float a = 1.0f;
  float e = 0.00000005f;
  float sum = a + e;
  printf("Sum: %e + %e = %.7e\n", a, e, sum);
  if (sum == 1.0f) {
    printf("Sum == 1.0f\n");
  } else {
    printf("Sum != 1.0f\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D40(%rip),%rdi
  call   <puts@plt>
  movsd  D43(%rip),%xmm0
  mov    $0x3,%eax
  movsd  D42(%rip),%xmm1
  lea    D44(%rip),%rdi
  movapd %xmm0,%xmm2
  call   <printf@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D40
datatype: string
name: read_data
arguments: data_label: D43
datatype: byte[8]
name: read_data
arguments: data_label: D42
datatype: byte[8]
name: read_data
arguments: data_label: D44
datatype: string
name: read_data
arguments: data_label: D6
datatype: string

tool: D40: Machin epsilon

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D42": [0x00,0x00,0x00,0xa0,0xf2,0xd7,0x6a,0x3e]}

tool: D44: Sum: %e + %e = %.7e


tool: D6: Sum == 1.0f

assistant: ```c
int main(int argc, const char *argv[]) {
  printf("Machin epsilon\n");
  float a = 1.0f;
  float e = 0.00000005f;
  float sum = a + e;
  printf("Sum: %e + %e = %.7e\n", a, e, sum);
  if (sum == 1.0f) {
    printf("Sum == 1.0f\n");
  } else {
    printf("Sum != 1.0f\n");
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_246_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_246_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk1 = T | stk2;
  return stk1;
}
```
user: What is the c source code of the assembly code below?

```asm
<xrop3_246_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  xor    $0xff,%al
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_246_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk1 = T | stk2;
  return stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_246_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  xor    $0xff,%al
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_246_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk1 = T | stk2;
  return stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xrop3_246_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  xor    $0xff,%al
  or     %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_246_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D ^ S;
  stk1 = T | stk2;
  return stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<imagetag_cmdline_ext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <imagetag_cmdline_internal@plt>
  mov    %eax,-0x4(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
L5:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int imagetag_cmdline_ext(int argc, char **argv, struct gengetopt_args_info *args_info, struct imagetag_cmdline_params *params) {
  int result;
  result = imagetag_cmdline_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<imagetag_cmdline_ext>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  mov    $0x0,%r8d
  call   <imagetag_cmdline_internal@plt>
  mov    %eax,%ebx
  mov    D12(%rip),%rax
  cmp    %ebx,(%rax)
  je     L9
L11:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %rbp,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L11
```

assistant: ```c
int imagetag_cmdline_ext(int argc, char **argv, struct gengetopt_args_info *args_info, struct imagetag_cmdline_params *params) {
  int result;
  result = imagetag_cmdline_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<imagetag_cmdline_ext>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <imagetag_cmdline_internal@plt>
  mov    D9(%rip),%rbx
  mov    %eax,%r12d
  cmp    %eax,(%rbx)
  je     L5
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  mov    %rbp,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    (%rbx),%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imagetag_cmdline_ext(int argc, char **argv, struct gengetopt_args_info *args_info, struct imagetag_cmdline_params *params) {
  int result;
  result = imagetag_cmdline_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<imagetag_cmdline_ext>:
  endbr64
  push   %r12
  xor    %r8d,%r8d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  call   <imagetag_cmdline_internal@plt>
  mov    D3(%rip),%rbx
  mov    %eax,%r12d
  cmp    %eax,(%rbx)
  je     L2
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdi
  call   <imagetag_cmdline_free@plt>
  mov    (%rbx),%edi
  call   <exit@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int imagetag_cmdline_ext(int argc, char **argv, struct gengetopt_args_info *args_info, struct imagetag_cmdline_params *params) {
  int result;
  result = imagetag_cmdline_internal(argc, argv, args_info, params, 0);
  if (result == EXIT_FAILURE) {
    imagetag_cmdline_free(args_info);
    exit(EXIT_FAILURE);
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x34(%rbp),%ebx
  movslq %ebx,%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  movslq %ebx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%edi
  call   <digit_count@plt>
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L36
L34:
  movl   $0x0,-0x20(%rbp)
  jmp    L22
L31:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  movslq %ebx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x20(%rbp)
L22:
  mov    -0x20(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L31
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x24(%rbp)
L36:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L34
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string

tool: D6: %*d

assistant: ```c
void print_table(int width, int table[][width]) {
  int padding = digit_count(table[width - 1][width - 1]) + 1;
  for (int row = 0; row < width; ++row) {
    for (int col = 0; col < width; ++col) {
      printf("%*d", padding, table[row][col]);
    }
    printf("\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_table>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  movslq %edi,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    %rcx,(%rsp)
  cltq
  imul   %rax,%rcx
  lea    (%rsi,%rax,4),%rax
  mov    (%rax,%rcx,1),%edi
  call   <digit_count@plt>
  test   %r15d,%r15d
  jle    L12
  lea    0x1(%rax),%r12d
  lea    -0x1(%r15),%eax
  lea    0x4(%rbx,%rax,4),%rbp
  mov    $0x0,%r14d
  mov    %r15d,%eax
  neg    %rax
  shl    $0x2,%rax
  mov    %rax,0x8(%rsp)
  lea    D4(%rip),%r13
L0:
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbp,1),%rbx
L15:
  mov    (%rbx),%edx
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L15
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  add    (%rsp),%rbp
  cmp    %r14d,%r15d
  jne    L0
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: %*d

assistant: ```c
void print_table(int width, int table[][width]) {
  int padding = digit_count(table[width - 1][width - 1]) + 1;
  for (int row = 0; row < width; ++row) {
    for (int col = 0; col < width; ++col) {
      printf("%*d", padding, table[row][col]);
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_table>:
  endbr64
  push   %r15
  movslq %edi,%r15
  push   %r14
  lea    0x0(,%r15,4),%rax
  push   %r13
  mov    %rax,%rdx
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%r15),%ebx
  sub    $0x18,%rsp
  mov    %rax,(%rsp)
  movslq %ebx,%rax
  imul   %rax,%rdx
  lea    (%rsi,%rax,4),%rax
  mov    (%rax,%rdx,1),%edi
  call   <digit_count@plt>
  test   %r15d,%r15d
  jle    L11
  lea    0x1(%rax),%ebp
  mov    %ebx,%eax
  mov    $0xfffffffffffffffc,%rdx
  mov    %r15,%r14
  shl    $0x2,%rax
  xor    %r13d,%r13d
  sub    %rax,%rdx
  lea    0x4(%r12,%rax,1),%rbx
  lea    D9(%rip),%r12
  mov    %rdx,0x8(%rsp)
  nopl   (%rax)
L7:
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbx,1),%r15
  nopl   0x0(%rax)
L21:
  mov    (%r15),%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L21
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  add    (%rsp),%rbx
  cmp    %r13d,%r14d
  jne    L7
L11:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: %*d

assistant: ```c
void print_table(int width, int table[][width]) {
  int padding = digit_count(table[width - 1][width - 1]) + 1;
  for (int row = 0; row < width; ++row) {
    for (int col = 0; col < width; ++col) {
      printf("%*d", padding, table[row][col]);
    }
    printf("\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_table>:
  endbr64
  push   %r15
  movslq %edi,%r15
  push   %r14
  lea    0x0(,%r15,4),%rax
  push   %r13
  mov    %rax,%rdx
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  lea    -0x1(%r15),%ebx
  sub    $0x18,%rsp
  mov    %rax,(%rsp)
  movslq %ebx,%rax
  imul   %rax,%rdx
  lea    (%rsi,%rax,4),%rax
  mov    (%rax,%rdx,1),%edi
  call   <digit_count@plt>
  test   %r15d,%r15d
  jle    L20
  lea    0x1(%rax),%ebp
  mov    %ebx,%eax
  mov    $0xfffffffffffffffc,%rdx
  mov    %r15,%r14
  shl    $0x2,%rax
  xor    %r13d,%r13d
  sub    %rax,%rdx
  lea    0x4(%r12,%rax,1),%rbx
  lea    D0(%rip),%r12
  mov    %rdx,0x8(%rsp)
  nopl   (%rax)
L3:
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbx,1),%r15
  nopl   0x0(%rax)
L15:
  mov    (%r15),%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x4,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L15
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  add    (%rsp),%rbx
  cmp    %r13d,%r14d
  jne    L3
L20:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: %*d

assistant: ```c
void print_table(int width, int table[][width]) {
  int padding = digit_count(table[width - 1][width - 1]) + 1;
  for (int row = 0; row < width; ++row) {
    for (int col = 0; col < width; ++col) {
      printf("%*d", padding, table[row][col]);
    }
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trampoline_take_addr_and_gen_cfg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  lea    D6(%rip),%r11
  mov    %r11,%fs:0x20
  jmp    *%gs:0x100d0
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) long trampoline_take_addr_and_gen_cfg(unsigned long n1) {
  long ret;
  __asm__ __volatile__("leaq 1f(%%rip), %%r11\n\t"
                       "movq %%r11, %%fs:0x20\n\t"
                       "jmpq *%%gs:0x10000+"
                       "0xD0"
                       "\n\t"
                       "1:\n\t"
                       : "=a"(ret)
                       : "D"(n1)
                       : "memory");
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trampoline_take_addr_and_gen_cfg>:
  endbr64
  lea    D5(%rip),%r11
  mov    %r11,%fs:0x20
  jmp    *%gs:0x100d0
  ret
```

assistant: ```c
__attribute__((no)) long trampoline_take_addr_and_gen_cfg(unsigned long n1) {
  long ret;
  __asm__ __volatile__("leaq 1f(%%rip), %%r11\n\t"
                       "movq %%r11, %%fs:0x20\n\t"
                       "jmpq *%%gs:0x10000+"
                       "0xD0"
                       "\n\t"
                       "1:\n\t"
                       : "=a"(ret)
                       : "D"(n1)
                       : "memory");
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trampoline_take_addr_and_gen_cfg>:
  endbr64
  lea    D3(%rip),%r11
  mov    %r11,%fs:0x20
  jmp    *%gs:0x100d0
  ret
```

assistant: ```c
__attribute__((no)) long trampoline_take_addr_and_gen_cfg(unsigned long n1) {
  long ret;
  __asm__ __volatile__("leaq 1f(%%rip), %%r11\n\t"
                       "movq %%r11, %%fs:0x20\n\t"
                       "jmpq *%%gs:0x10000+"
                       "0xD0"
                       "\n\t"
                       "1:\n\t"
                       : "=a"(ret)
                       : "D"(n1)
                       : "memory");
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trampoline_take_addr_and_gen_cfg>:
  endbr64
  lea    D3(%rip),%r11
  mov    %r11,%fs:0x20
  jmp    *%gs:0x100d0
  ret
```

assistant: ```c
__attribute__((no)) long trampoline_take_addr_and_gen_cfg(unsigned long n1) {
  long ret;
  __asm__ __volatile__("leaq 1f(%%rip), %%r11\n\t"
                       "movq %%r11, %%fs:0x20\n\t"
                       "jmpq *%%gs:0x10000+"
                       "0xD0"
                       "\n\t"
                       "1:\n\t"
                       : "=a"(ret)
                       : "D"(n1)
                       : "memory");
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<res_query>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x150,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %esi,-0x13c(%rbp)
  mov    %edx,-0x140(%rbp)
  mov    %rcx,-0x148(%rbp)
  mov    %r8d,-0x14c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x140(%rbp),%ecx
  mov    -0x13c(%rbp),%edx
  mov    -0x138(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x118
  lea    -0x120(%rbp),%rsi
  push   %rsi
  push   $0x0
  mov    $0x0,%r9d
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <__res_mkquery@plt>
  add    $0x20,%rsp
  mov    %eax,-0x124(%rbp)
  cmpl   $0x0,-0x124(%rbp)
  jns    L3
  mov    -0x124(%rbp),%eax
  jmp    L1
L3:
  mov    -0x14c(%rbp),%ecx
  mov    -0x148(%rbp),%rdx
  mov    -0x124(%rbp),%esi
  lea    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <__res_send@plt>
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int res_query(const char *name, int class, int type, unsigned char *dest, int len) {
  unsigned char q[280];
  int ql = __res_mkquery(0, name, class, type, 0, 0, 0, q, sizeof q);
  if (ql < 0)
    return ql;
  return __res_send(q, ql, dest, len);
}
```