ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rop3_64_1_0>:
  endbr64
  movzbl (%rdi),%ecx
  and    %esi,%edx
  mov    %ecx,%eax
  and    %esi,%ecx
  not    %eax
  and    %edx,%eax
  mov    %esi,%edx
  not    %edx
  and    %edx,%eax
  or     %ecx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_64_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T & stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rop3_64_1_0>:
  endbr64
  movzbl (%rdi),%ecx
  and    %esi,%edx
  mov    %ecx,%eax
  and    %esi,%ecx
  not    %eax
  and    %edx,%eax
  mov    %esi,%edx
  not    %edx
  and    %edx,%eax
  or     %ecx,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_64_1_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  stk3 = ~*D;
  stk2 = S & stk3;
  stk1 = T & stk2;
  *D = (stk1 & (~S)) | (*D & S);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5: 
%d

assistant: ```c
main() {
  int i = 4;
  int j = i | 4 & 2;
  printf("\n%d", j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: 
%d

assistant: ```c
main() {
  int i = 4;
  int j = i | 4 & 2;
  printf("\n%d", j);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: 
%d

assistant: ```c
main() {
  int i = 4;
  int j = i | 4 & 2;
  printf("\n%d", j);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: 
%d

assistant: ```c
main() {
  int i = 4;
  int j = i | 4 & 2;
  printf("\n%d", j);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<arg2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L58
  mov    $0x0,%eax
  jmp    L8
L58:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L65
L74:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rax
  mov    %eax,%edi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L65:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L74
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L35
  mov    $0x0,%eax
  jmp    L8
L35:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L59
L37:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,-0x10(%rbp)
L59:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L37
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: %s 

assistant: ```c
char *arg2str(char **arg) {
  char **p;
  char *str, *sp;
  int len = 0;
  if (arg == NULL)
    return NULL;
  p = arg;
  while (*p)
    len += strlen(*p++) + 1;
  if ((str = (char *)malloc(len + 1)) == NULL)
    return NULL;
  p = arg;
  sp = str;
  while (*p)
    sp += sprintf(sp, "%s ", *p++);
  return str;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arg2str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L31
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L39
  mov    %rbx,%rbp
  mov    $0x0,%r12d
L11:
  add    $0x8,%rbp
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%r12d
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  jne    L11
L17:
  lea    0x1(%r12),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L6
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L73
  mov    %rax,%rbp
  lea    D1(%rip),%r12
L36:
  add    $0x8,%rbx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,%rbp
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  jne    L36
L73:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x0,%r12d
  jmp    L17
L31:
  mov    %rdi,%r13
  jmp    L73
L6:
  mov    $0x0,%r13d
  jmp    L73
```

tool_calls: name: parse_data
arguments: data_label: D1
data_type: string

tool: D1: %s 

assistant: ```c
char *arg2str(char **arg) {
  char **p;
  char *str, *sp;
  int len = 0;
  if (arg == NULL)
    return NULL;
  p = arg;
  while (*p)
    len += strlen(*p++) + 1;
  if ((str = (char *)malloc(len + 1)) == NULL)
    return NULL;
  p = arg;
  sp = str;
  while (*p)
    sp += sprintf(sp, "%s ", *p++);
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arg2str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L34
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L26
  mov    %rbx,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L45:
  call   <strlen@plt>
  mov    0x8(%rbp),%rdi
  add    $0x8,%rbp
  lea    0x1(%r12,%rax,1),%r12d
  test   %rdi,%rdi
  jne    L45
  lea    0x1(%r12),%edi
L56:
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L34
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L9
  mov    %rax,%r13
  lea    D6(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r13,%rdi
  add    $0x8,%rbx
  mov    %rbp,%rsi
  call   <sprintf@plt>
  mov    (%rbx),%rdx
  cltq
  add    %rax,%r13
  test   %rdx,%rdx
  jne    L33
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L26:
  mov    $0x1,%edi
  jmp    L56
```

tool_calls: name: disassemble_data
arguments: label: D6
type_infered: string

tool: D6: %s 

assistant: ```c
char *arg2str(char **arg) {
  char **p;
  char *str, *sp;
  int len = 0;
  if (arg == NULL)
    return NULL;
  p = arg;
  while (*p)
    len += strlen(*p++) + 1;
  if ((str = (char *)malloc(len + 1)) == NULL)
    return NULL;
  p = arg;
  sp = str;
  while (*p)
    sp += sprintf(sp, "%s ", *p++);
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arg2str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L61
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L25
  mov    %rbx,%rbp
  xor    %r12d,%r12d
  nopl   0x0(%rax)
L30:
  call   <strlen@plt>
  mov    0x8(%rbp),%rdi
  add    $0x8,%rbp
  lea    0x1(%r12,%rax,1),%r12d
  test   %rdi,%rdi
  jne    L30
  lea    0x1(%r12),%edi
L42:
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L61
  mov    (%rbx),%rdx
  test   %rdx,%rdx
  je     L54
  mov    %rax,%r13
  lea    D0(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %r13,%rdi
  add    $0x8,%rbx
  mov    %rbp,%rsi
  call   <sprintf@plt>
  mov    (%rbx),%rdx
  cltq
  add    %rax,%r13
  test   %rdx,%rdx
  jne    L27
L54:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L25:
  mov    $0x1,%edi
  jmp    L42
```

tool_calls: name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D0: %s 

assistant: ```c
char *arg2str(char **arg) {
  char **p;
  char *str, *sp;
  int len = 0;
  if (arg == NULL)
    return NULL;
  p = arg;
  while (*p)
    len += strlen(*p++) + 1;
  if ((str = (char *)malloc(len + 1)) == NULL)
    return NULL;
  p = arg;
  sp = str;
  while (*p)
    sp += sprintf(sp, "%s ", *p++);
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__assert_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
L0:
  jmp    L0
```

assistant: ```c
void __attribute__((noreturn)) __assert_func(const char *arg1 __attribute__((unused)), int arg2 __attribute__((unused)), const char *arg3 __attribute__((unused)), const char *arg4 __attribute__((unused))) {
  while (1)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__assert_func>:
  endbr64
L7:
  jmp    L7
```

assistant: ```c
void __attribute__((noreturn)) __assert_func(const char *arg1 __attribute__((unused)), int arg2 __attribute__((unused)), const char *arg3 __attribute__((unused)), const char *arg4 __attribute__((unused))) {
  while (1)
    ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__assert_func>:
  endbr64
  nopl   0x0(%rax)
L1:
  jmp    L1
```

assistant: ```c
void __attribute__((noreturn)) __assert_func(const char *arg1 __attribute__((unused)), int arg2 __attribute__((unused)), const char *arg3 __attribute__((unused)), const char *arg4 __attribute__((unused))) {
  while (1)
    ;
}
```
user: What is the c source code of the assembly code below:

```asm
<__assert_func>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
void __attribute__((noreturn)) __assert_func(const char *arg1 __attribute__((unused)), int arg2 __attribute__((unused)), const char *arg3 __attribute__((unused)), const char *arg4 __attribute__((unused))) {
  while (1)
    ;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<arr_float_max_nostride_count_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movw   $0xffff,-0xc(%rbp)
  movw   $0x0,-0xa(%rbp)
  jmp    L49
L44:
  movzwl -0xa(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L40
  movzwl -0xa(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movzwl -0xa(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L40
  movzwl -0xa(%rbp),%eax
  mov    %ax,-0xc(%rbp)
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
L40:
  movzwl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xa(%rbp)
L49:
  movzwl -0xa(%rbp),%eax
  cmp    %rax,-0x30(%rbp)
  ja     L44
  cmpw   $0xffff,-0xc(%rbp)
  je     L46
  mov    -0x18(%rbp),%rax
  movzwl -0xc(%rbp),%edx
  mov    %dx,(%rax)
L46:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arr_float_max_nostride_count_pos(unsigned short int *puIndex, float *pFloat, unsigned char *pCount, unsigned long int n) {
  float fMaxValue = 0;
  unsigned short int uIndex = ((unsigned short int)(0 - 1));
  unsigned short int i;
  for (i = 0; i < n; i++) {
    if (pCount[i] > 0) {
      float v = pFloat[i] / pCount[i];
      if (v > fMaxValue) {
        uIndex = i;
        fMaxValue = v;
      }
    }
  }
  if (uIndex != ((unsigned short int)(0 - 1))) {
    *puIndex = uIndex;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arr_float_max_nostride_count_pos>:
  endbr64
  mov    %rdi,%r10
  test   %rcx,%rcx
  je     L16
  mov    $0x0,%edi
  mov    $0xffffffff,%r9d
  pxor   %xmm1,%xmm1
  mov    $0x0,%eax
  jmp    L26
L28:
  add    $0x1,%edi
  movzwl %di,%eax
  cmp    %rcx,%rax
  jae    L43
L26:
  movzbl (%rdx,%rax,1),%r8d
  test   %r8b,%r8b
  je     L28
  movzbl %r8b,%r8d
  pxor   %xmm2,%xmm2
  cvtsi2ss %r8d,%xmm2
  movss  (%rsi,%rax,4),%xmm0
  divss  %xmm2,%xmm0
  comiss %xmm1,%xmm0
  cmova  %edi,%r9d
  maxss  %xmm1,%xmm0
  movaps %xmm0,%xmm1
  jmp    L28
L43:
  cmp    $0xffff,%r9w
  je     L16
  mov    %r9w,(%r10)
L16:
  ret
```

assistant: ```c
void arr_float_max_nostride_count_pos(unsigned short int *puIndex, float *pFloat, unsigned char *pCount, unsigned long int n) {
  float fMaxValue = 0;
  unsigned short int uIndex = ((unsigned short int)(0 - 1));
  unsigned short int i;
  for (i = 0; i < n; i++) {
    if (pCount[i] > 0) {
      float v = pFloat[i] / pCount[i];
      if (v > fMaxValue) {
        uIndex = i;
        fMaxValue = v;
      }
    }
  }
  if (uIndex != ((unsigned short int)(0 - 1))) {
    *puIndex = uIndex;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<arr_float_max_nostride_count_pos>:
  endbr64
  mov    %rdi,%r10
  test   %rcx,%rcx
  je     L24
  xor    %edi,%edi
  mov    $0xffffffff,%r9d
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl (%rdx,%rax,1),%r8d
  test   %r8b,%r8b
  je     L28
  pxor   %xmm2,%xmm2
  movss  (%rsi,%rax,4),%xmm0
  cvtsi2ss %r8d,%xmm2
  divss  %xmm2,%xmm0
  comiss %xmm1,%xmm0
  maxss  %xmm1,%xmm0
  cmova  %edi,%r9d
  movaps %xmm0,%xmm1
L28:
  add    $0x1,%edi
  movzwl %di,%eax
  cmp    %rcx,%rax
  jb     L13
  cmp    $0xffff,%r9w
  je     L24
  mov    %r9w,(%r10)
L24:
  ret
```

assistant: ```c
void arr_float_max_nostride_count_pos(unsigned short int *puIndex, float *pFloat, unsigned char *pCount, unsigned long int n) {
  float fMaxValue = 0;
  unsigned short int uIndex = ((unsigned short int)(0 - 1));
  unsigned short int i;
  for (i = 0; i < n; i++) {
    if (pCount[i] > 0) {
      float v = pFloat[i] / pCount[i];
      if (v > fMaxValue) {
        uIndex = i;
        fMaxValue = v;
      }
    }
  }
  if (uIndex != ((unsigned short int)(0 - 1))) {
    *puIndex = uIndex;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arr_float_max_nostride_count_pos>:
  endbr64
  mov    %rdi,%r10
  test   %rcx,%rcx
  je     L10
  xor    %edi,%edi
  mov    $0xffffffff,%r9d
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L21:
  movzbl (%rdx,%rax,1),%r8d
  test   %r8b,%r8b
  je     L33
  pxor   %xmm2,%xmm2
  movss  (%rsi,%rax,4),%xmm0
  cvtsi2ss %r8d,%xmm2
  divss  %xmm2,%xmm0
  comiss %xmm1,%xmm0
  maxss  %xmm1,%xmm0
  cmova  %edi,%r9d
  movaps %xmm0,%xmm1
L33:
  add    $0x1,%edi
  movzwl %di,%eax
  cmp    %rcx,%rax
  jb     L21
  cmp    $0xffff,%r9w
  je     L10
  mov    %r9w,(%r10)
L10:
  ret
```

assistant: ```c
void arr_float_max_nostride_count_pos(unsigned short int *puIndex, float *pFloat, unsigned char *pCount, unsigned long int n) {
  float fMaxValue = 0;
  unsigned short int uIndex = ((unsigned short int)(0 - 1));
  unsigned short int i;
  for (i = 0; i < n; i++) {
    if (pCount[i] > 0) {
      float v = pFloat[i] / pCount[i];
      if (v > fMaxValue) {
        uIndex = i;
        fMaxValue = v;
      }
    }
  }
  if (uIndex != ((unsigned short int)(0 - 1))) {
    *puIndex = uIndex;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<isAnagram>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L6
  mov    $0x0,%eax
  jmp    L16
L6:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <mergeSort@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <mergeSort@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L5
L27:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L15
  mov    $0x0,%eax
  jmp    L16
L15:
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L27
  mov    $0x1,%eax
L16:
  leave
  ret
```

assistant: ```c
int isAnagram(char str1[], char str2[]) {
  int length1 = strlen(str1);
  int length2 = strlen(str2);
  if (length1 != length2) {
    return 0;
  }
  mergeSort(str1, 0, length1 - 1);
  mergeSort(str2, 0, length2 - 1);
  for (int i = 0; i < length1; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isAnagram>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  cmp    %r12d,%r13d
  je     L26
L61:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  lea    -0x1(%r13),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <mergeSort@plt>
  lea    -0x1(%r12),%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <mergeSort@plt>
  test   %r13d,%r13d
  jle    L35
  lea    -0x1(%r13),%ecx
  mov    $0x0,%eax
  jmp    L16
L69:
  mov    %rdx,%rax
L16:
  movzbl 0x0(%rbp,%rax,1),%esi
  cmp    %sil,(%rbx,%rax,1)
  jne    L45
  lea    0x1(%rax),%rdx
  cmp    %rcx,%rax
  jne    L69
  mov    $0x1,%eax
  jmp    L61
L35:
  mov    $0x1,%eax
  jmp    L61
L45:
  mov    $0x0,%eax
  jmp    L61
```

assistant: ```c
int isAnagram(char str1[], char str2[]) {
  int length1 = strlen(str1);
  int length2 = strlen(str2);
  if (length1 != length2) {
    return 0;
  }
  mergeSort(str1, 0, length1 - 1);
  mergeSort(str2, 0, length2 - 1);
  for (int i = 0; i < length1; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isAnagram>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L2
L24:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L2:
  lea    -0x1(%rbx),%r13d
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  call   <mergeSort@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <mergeSort@plt>
  test   %ebx,%ebx
  jle    L3
  movslq %ebx,%rax
  xor    %edx,%edx
  jmp    L12
  nopl   0x0(%rax)
L51:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L3
L12:
  movzbl (%r12,%rdx,1),%ecx
  cmp    %cl,0x0(%rbp,%rdx,1)
  je     L51
  jmp    L24
  xchg   %ax,%ax
L3:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int isAnagram(char str1[], char str2[]) {
  int length1 = strlen(str1);
  int length2 = strlen(str2);
  if (length1 != length2) {
    return 0;
  }
  mergeSort(str1, 0, length1 - 1);
  mergeSort(str2, 0, length2 - 1);
  for (int i = 0; i < length1; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isAnagram>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  cmp    %eax,%ebx
  je     L45
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L45:
  lea    -0x1(%rbx),%r13d
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %r13d,%edx
  call   <mergeSort@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %r12,%rdi
  call   <mergeSort@plt>
  test   %ebx,%ebx
  jle    L29
  movslq %ebx,%rax
  xor    %edx,%edx
  jmp    L35
  nopl   0x0(%rax)
L54:
  add    $0x1,%rdx
  cmp    %rax,%rdx
  je     L29
L35:
  movzbl (%r12,%rdx,1),%ecx
  cmp    %cl,0x0(%rbp,%rdx,1)
  je     L54
  jmp    L11
  xchg   %ax,%ax
L29:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int isAnagram(char str1[], char str2[]) {
  int length1 = strlen(str1);
  int length2 = strlen(str2);
  if (length1 != length2) {
    return 0;
  }
  mergeSort(str1, 0, length1 - 1);
  mergeSort(str2, 0, length2 - 1);
  for (int i = 0; i < length1; i++) {
    if (str1[i] != str2[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L31:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L31
  jmp    L8
L5:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rdx,%rax
  sub    $0x30,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L5
  cmpq   $0x0,-0x20(%rbp)
  je     L13
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L13:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long strtoul(const char *str, char **endptr, int base) {
  unsigned long ret = 0;
  char *p = (char *)str;
  while (isspace(*p))
    p++;
  while (isdigit(*p)) {
    ret = ret * 10 + *p - '0';
    p++;
  }
  if (endptr)
    *endptr = p;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strtoul>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  jmp    L40
L8:
  add    $0x1,%rbx
L40:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L8
  mov    $0x0,%ebp
  jmp    L31
L10:
  lea    0x0(%rbp,%rbp,4),%rdx
  movsbq (%rbx),%rax
  lea    -0x30(%rax,%rdx,2),%rbp
  add    $0x1,%rbx
L31:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L10
  test   %r12,%r12
  je     L49
  mov    %rbx,(%r12)
L49:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long strtoul(const char *str, char **endptr, int base) {
  unsigned long ret = 0;
  char *p = (char *)str;
  while (isspace(*p))
    p++;
  while (isdigit(*p)) {
    ret = ret * 10 + *p - '0';
    p++;
  }
  if (endptr)
    *endptr = p;
  return ret;
}
```