ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<point_lies_seg>:
  endbr64
  sub    $0x38,%rsp
  movsd  %xmm0,0x18(%rsp)
  subsd  %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm4,(%rsp)
  movsd  %xmm5,0x28(%rsp)
  movsd  %xmm2,0x20(%rsp)
  call   <fabs@plt>
  test   %eax,%eax
  jle    L183
  movsd  0x8(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jle    L207
  movsd  (%rsp),%xmm7
  comisd 0x18(%rsp),%xmm7
  jb     L146
  movsd  0x20(%rsp),%xmm3
  comisd %xmm7,%xmm3
  jae    L181
L146:
  movsd  0x18(%rsp),%xmm7
  movsd  (%rsp),%xmm6
  comisd %xmm6,%xmm7
  jb     L35
  comisd 0x20(%rsp),%xmm6
  jb     L35
L181:
  movsd  0x28(%rsp),%xmm1
  comisd 0x8(%rsp),%xmm1
  jb     L115
  movsd  0x10(%rsp),%xmm7
  comisd %xmm1,%xmm7
  jae    L124
L115:
  movsd  0x8(%rsp),%xmm6
  movsd  0x28(%rsp),%xmm5
  comisd %xmm5,%xmm6
  jb     L35
  comisd 0x10(%rsp),%xmm5
  jae    L124
L35:
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L183:
  movsd  (%rsp),%xmm0
  subsd  0x20(%rsp),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L35
  movsd  0x28(%rsp),%xmm4
  comisd 0x8(%rsp),%xmm4
  jb     L160
  movsd  0x10(%rsp),%xmm1
  comisd %xmm4,%xmm1
  jae    L124
L160:
  movsd  0x8(%rsp),%xmm4
  movsd  0x28(%rsp),%xmm3
  comisd %xmm3,%xmm4
  jb     L35
  comisd 0x10(%rsp),%xmm3
  jb     L35
L124:
  mov    $0x1,%eax
  add    $0x38,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L207:
  movsd  0x28(%rsp),%xmm0
  subsd  0x10(%rsp),%xmm0
  call   <fabs@plt>
  test   %eax,%eax
  jg     L35
  movsd  (%rsp),%xmm5
  comisd 0x18(%rsp),%xmm5
  jb     L185
  movsd  0x20(%rsp),%xmm4
  comisd %xmm5,%xmm4
  jae    L124
L185:
  movsd  0x18(%rsp),%xmm7
  movsd  (%rsp),%xmm3
  comisd %xmm3,%xmm7
  jb     L35
  comisd 0x20(%rsp),%xmm3
  jb     L35
  jmp    L124
```

assistant: ```c
int point_lies_seg(double p1x, double p1y, double p2x, double p2y, double x, double y) {
  if (fabs(p1x - p2x) < 1e-6) {
    if ((fabs(x - p2x) < 1e-6) && (((y >= p1y) && (y <= p2y)) || ((y <= p1y) && (y >= p2y)))) {
      return 1;
    }
  } else if (fabs(p1y - p2y) < 1e-6) {
    if ((fabs(y - p2y) < 1e-6) && (((x >= p1x) && (x <= p2x)) || ((x <= p1x) && (x >= p2x)))) {
      return 1;
    }
  } else if ((((x >= p1x) && (x <= p2x)) || ((x <= p1x) && (x >= p2x))) && (((y >= p1y) && (y <= p2y)) || ((y <= p1y) && (y >= p2y)))) {
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<psvec4_floor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vec4_floor@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4_floor(struct vec4 *result, struct vec4 *a) {
  vec4_floor((float *)result, (float *)a);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<psvec4_floor>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <vec4_floor@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4_floor(struct vec4 *result, struct vec4 *a) {
  vec4_floor((float *)result, (float *)a);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<psvec4_floor>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4_floor@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4_floor(struct vec4 *result, struct vec4 *a) {
  vec4_floor((float *)result, (float *)a);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psvec4_floor>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <vec4_floor@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((always_)) struct vec4 *psvec4_floor(struct vec4 *result, struct vec4 *a) {
  vec4_floor((float *)result, (float *)a);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<analize_board>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0x2(%rdi),%edx
  movsbl 0x1(%rdi),%esi
  movsbl (%rdi),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  je     L66
L58:
  pop    %rbx
  ret
L66:
  movsbl 0x5(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x3(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L58
  movsbl 0x8(%rbx),%edx
  movsbl 0x7(%rbx),%esi
  movsbl 0x6(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L58
  movsbl 0x6(%rbx),%edx
  movsbl 0x3(%rbx),%esi
  movsbl (%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L58
  movsbl 0x7(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x1(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L58
  movsbl 0x8(%rbx),%edx
  movsbl 0x5(%rbx),%esi
  movsbl 0x2(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L58
  movsbl 0x8(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl (%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L58
  movsbl 0x6(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x2(%rbx),%edi
  call   <calculate_winner@plt>
  jmp    L58
```

assistant: ```c
int analize_board(char board[][3]) {
  int winner = 0;
  winner = calculate_winner(board[0][0], board[0][1], board[0][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[1][0], board[1][1], board[1][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[2][0], board[2][1], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][0], board[1][0], board[2][0]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][1], board[1][1], board[2][1]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][2], board[1][2], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][0], board[1][1], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][2], board[1][1], board[2][0]);
  if (winner != 0)
    return winner;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<analize_board>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0x2(%rdi),%edx
  movsbl 0x1(%rdi),%esi
  movsbl (%rdi),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  je     L36
L39:
  pop    %rbx
  ret
  xchg   %ax,%ax
L36:
  movsbl 0x5(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x3(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L39
  movsbl 0x8(%rbx),%edx
  movsbl 0x7(%rbx),%esi
  movsbl 0x6(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L39
  movsbl 0x6(%rbx),%edx
  movsbl 0x3(%rbx),%esi
  movsbl (%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L39
  movsbl 0x7(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x1(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L39
  movsbl 0x8(%rbx),%edx
  movsbl 0x5(%rbx),%esi
  movsbl 0x2(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L39
  movsbl 0x8(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl (%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L39
  movsbl 0x6(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x2(%rbx),%edi
  pop    %rbx
  jmp    1050 <calculate_winner@plt>
```

assistant: ```c
int analize_board(char board[][3]) {
  int winner = 0;
  winner = calculate_winner(board[0][0], board[0][1], board[0][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[1][0], board[1][1], board[1][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[2][0], board[2][1], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][0], board[1][0], board[2][0]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][1], board[1][1], board[2][1]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][2], board[1][2], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][0], board[1][1], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][2], board[1][1], board[2][0]);
  if (winner != 0)
    return winner;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<analize_board>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl 0x2(%rdi),%edx
  movsbl 0x1(%rdi),%esi
  movsbl (%rdi),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  je     L35
L64:
  pop    %rbx
  ret
  xchg   %ax,%ax
L35:
  movsbl 0x5(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x3(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L64
  movsbl 0x8(%rbx),%edx
  movsbl 0x7(%rbx),%esi
  movsbl 0x6(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L64
  movsbl 0x6(%rbx),%edx
  movsbl 0x3(%rbx),%esi
  movsbl (%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L64
  movsbl 0x7(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x1(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L64
  movsbl 0x8(%rbx),%edx
  movsbl 0x5(%rbx),%esi
  movsbl 0x2(%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L64
  movsbl 0x8(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl (%rbx),%edi
  call   <calculate_winner@plt>
  test   %eax,%eax
  jne    L64
  movsbl 0x6(%rbx),%edx
  movsbl 0x4(%rbx),%esi
  movsbl 0x2(%rbx),%edi
  pop    %rbx
  jmp    1050 <calculate_winner@plt>
```

assistant: ```c
int analize_board(char board[][3]) {
  int winner = 0;
  winner = calculate_winner(board[0][0], board[0][1], board[0][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[1][0], board[1][1], board[1][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[2][0], board[2][1], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][0], board[1][0], board[2][0]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][1], board[1][1], board[2][1]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][2], board[1][2], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][0], board[1][1], board[2][2]);
  if (winner != 0)
    return winner;
  winner = calculate_winner(board[0][2], board[1][1], board[2][0]);
  if (winner != 0)
    return winner;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<parse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L40
  mov    %eax,%r13d
  xor    %ebx,%ebx
  xor    %edi,%edi
  mov    %rsp,%r14
  nopl   (%rax)
L6:
  movslq %edi,%rsi
  add    %rbp,%rsi
  movzbl (%rsi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x1,%al
  jbe    L28
  cmp    $0x20,%dl
  je     L28
  movslq %ebx,%r11
  lea    (%r11,%r11,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r14,%rax,4),%r10
  mov    $0x1,%eax
  jmp    L72
  nopl   0x0(%rax,%rax,1)
L11:
  cmp    $0x20,%dl
  je     L108
L72:
  mov    %dl,-0x1(%r10,%rax,1)
  movzbl (%rsi,%rax,1),%edx
  movslq %eax,%r8
  lea    (%rdi,%rax,1),%r9d
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  ja     L11
L108:
  lea    (%r11,%r11,4),%rdx
  movslq %r8d,%rax
  add    $0x1,%ebx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x2720(%rsp,%rdx,4),%rdx
  movb   $0x0,-0x2720(%rax,%rdx,1)
L36:
  lea    0x1(%r9),%edi
  cmp    %edi,%r13d
  jg     L6
  movslq %ebx,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x2720(%rsp,%rax,4),%rax
  movb   $0x0,-0x2720(%r8,%rax,1)
  test   %ebx,%ebx
  je     L40
  lea    -0x1(%rbx),%eax
  mov    %rsp,%r13
  xor    %edx,%edx
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x64(%rsp,%rax,4),%r14
  nopl   (%rax)
L80:
  movslq %edx,%rbp
  xor    %ebx,%ebx
  lea    0x1(%rdx),%r15d
  add    %r12,%rbp
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L27:
  movzbl 0x0(%r13,%rbx,1),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
L2:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    (%r15,%rbx,1),%edx
  cmp    %ebx,%eax
  jg     L27
  add    $0x64,%r13
  movb   $0x20,0x0(%rbp)
  cmp    %r13,%r14
  jne    L80
  movslq %edx,%rdx
  add    %rdx,%r12
L40:
  movb   $0x0,(%r12)
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x2728,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L28:
  mov    %edi,%r9d
  xor    %r8d,%r8d
  jmp    L36
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void parse(char a[], char test[]) {
  int i, j;
  char sec_str[100][100];
  int sec_ptr = 0;
  int len = strlen(a);
  j = 0;
  for (i = 0; i < len; i++) {
    j = 0;
    int check = 0;
    while (a[i] != ' ' && a[i] != '\t' && a[i] != '\n') {
      sec_str[sec_ptr][j++] = a[i];
      i++;
      check = 1;
    }
    if (check == 1) {
      sec_str[sec_ptr][j] = '\0';
      sec_ptr++;
    }
  }
  sec_str[sec_ptr][j] = '\0';
  int test_ptr = 0;
  for (i = 0; i < sec_ptr; i++) {
    for (j = 0; j < strlen(sec_str[i]); j++) {
      test[test_ptr++] = sec_str[i][j];
    }
    test[test_ptr++] = ' ';
  }
  test[test_ptr] = '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x728,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2718(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  test   %eax,%eax
  jle    L23
  mov    %eax,%r13d
  xor    %ebx,%ebx
  xor    %edi,%edi
  mov    %rsp,%r14
  nopl   (%rax)
L72:
  movslq %edi,%rsi
  add    %rbp,%rsi
  movzbl (%rsi),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x1,%al
  jbe    L63
  cmp    $0x20,%dl
  je     L63
  movslq %ebx,%r11
  lea    (%r11,%r11,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    (%r14,%rax,4),%r10
  mov    $0x1,%eax
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L57:
  cmp    $0x20,%dl
  je     L34
L33:
  mov    %dl,-0x1(%r10,%rax,1)
  movzbl (%rsi,%rax,1),%edx
  movslq %eax,%r8
  lea    (%rdi,%rax,1),%r9d
  add    $0x1,%rax
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  ja     L57
L34:
  lea    (%r11,%r11,4),%rdx
  movslq %r8d,%rax
  add    $0x1,%ebx
  lea    (%rdx,%rdx,4),%rdx
  lea    0x2720(%rsp,%rdx,4),%rdx
  movb   $0x0,-0x2720(%rax,%rdx,1)
L110:
  lea    0x1(%r9),%edi
  cmp    %edi,%r13d
  jg     L72
  movslq %ebx,%rax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x2720(%rsp,%rax,4),%rax
  movb   $0x0,-0x2720(%r8,%rax,1)
  test   %ebx,%ebx
  je     L23
  lea    -0x1(%rbx),%eax
  mov    %rsp,%r13
  xor    %edx,%edx
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x64(%rsp,%rax,4),%r14
  nopl   (%rax)
L24:
  movslq %edx,%rbp
  xor    %ebx,%ebx
  lea    0x1(%rdx),%r15d
  add    %r12,%rbp
  jmp    L14
  cs nopw 0x0(%rax,%rax,1)
L126:
  movzbl 0x0(%r13,%rbx,1),%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbp)
L14:
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    (%r15,%rbx,1),%edx
  cmp    %ebx,%eax
  jg     L126
  add    $0x64,%r13
  movb   $0x20,0x0(%rbp)
  cmp    %r13,%r14
  jne    L24
  movslq %edx,%rdx
  add    %rdx,%r12
L23:
  movb   $0x0,(%r12)
  mov    0x2718(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L117
  add    $0x2728,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L63:
  mov    %edi,%r9d
  xor    %r8d,%r8d
  jmp    L110
L117:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void parse(char a[], char test[]) {
  int i, j;
  char sec_str[100][100];
  int sec_ptr = 0;
  int len = strlen(a);
  j = 0;
  for (i = 0; i < len; i++) {
    j = 0;
    int check = 0;
    while (a[i] != ' ' && a[i] != '\t' && a[i] != '\n') {
      sec_str[sec_ptr][j++] = a[i];
      i++;
      check = 1;
    }
    if (check == 1) {
      sec_str[sec_ptr][j] = '\0';
      sec_ptr++;
    }
  }
  sec_str[sec_ptr][j] = '\0';
  int test_ptr = 0;
  for (i = 0; i < sec_ptr; i++) {
    for (j = 0; j < strlen(sec_str[i]); j++) {
      test[test_ptr++] = sec_str[i][j];
    }
    test[test_ptr++] = ' ';
  }
  test[test_ptr] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmatrix_all_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void fmatrix_all_free(float **m) {
  float *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fmatrix_all_free>:
  endbr64
  push   %rbx
  mov    (%rdi),%rbx
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fmatrix_all_free(float **m) {
  float *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fmatrix_all_free>:
  endbr64
  push   %rbp
  mov    (%rdi),%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void fmatrix_all_free(float **m) {
  float *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fmatrix_all_free>:
  endbr64
  push   %rbp
  mov    (%rdi),%rbp
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void fmatrix_all_free(float **m) {
  float *a;
  a = m[0];
  free(m);
  free(a);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<some_func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D7(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int some_func() {
  static int some_static;
  return some_static;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<some_func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int some_func() {
  static int some_static;
  return some_static;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<some_func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int some_func() {
  static int some_static;
  return some_static;
}
```
user: What is the c source code of the assembly code below?

```asm
<some_func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int some_func() {
  static int some_static;
  return some_static;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L27
L9:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x14(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L9
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <find_winner@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: tag: D32
type_guessed: string

tool: D7: Enter the size of array :

tool: D9: %d

tool: D32: Enter value of k : 

assistant: ```c
int main() {
  int *a;
  int N, i, k;
  printf("Enter the size of array :");
  scanf("%d", &N);
  a = (int *)calloc(N, sizeof(int));
  for (i = 0; i < N; i++)
    scanf("%d", &a[i]);
  printf("Enter value of k : ");
  scanf("%d", &k);
  find_winner(a, N, k);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    $0x4,%esi
  mov    (%rsp),%edi
  call   <calloc@plt>
  mov    %rax,%r13
  cmpl   $0x0,(%rsp)
  jle    L9
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D35(%rip),%r12
L11:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,(%rsp)
  jg     L11
L9:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %r13,%rdi
  call   <find_winner@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D25
type_infered: string
name: read_data
arguments: tag: D35
type_infered: string
name: read_data
arguments: tag: D42
type_infered: string

tool: D25: Enter the size of array :

tool: D35: %d

tool: D42: Enter value of k : 

assistant: ```c
int main() {
  int *a;
  int N, i, k;
  printf("Enter the size of array :");
  scanf("%d", &N);
  a = (int *)calloc(N, sizeof(int));
  for (i = 0; i < N; i++)
    scanf("%d", &a[i]);
  printf("Enter value of k : ");
  scanf("%d", &k);
  find_winner(a, N, k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L5
  mov    %r13,%rbp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L4
L5:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %r13,%rdi
  call   <find_winner@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D18
type: string
name: read_data
arguments: data_tag: D16
type: string

tool: D11: Enter the size of array :

tool: D18: %d

tool: D16: Enter value of k : 

assistant: ```c
int main() {
  int *a;
  int N, i, k;
  printf("Enter the size of array :");
  scanf("%d", &N);
  a = (int *)calloc(N, sizeof(int));
  for (i = 0; i < N; i++)
    scanf("%d", &a[i]);
  printf("Enter value of k : ");
  scanf("%d", &k);
  find_winner(a, N, k);
}
```