ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<sys_getdtablesize>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int sys_getdtablesize(tcp)
struct tcb *tcp;
{
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fts3PrefixCompress>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L8:
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L24
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L8
L24:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  (void)(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: What is the c source code of the assembly code below:

```asm
<fts3PrefixCompress>:
  endbr64
  test   %esi,%esi
  jle    L24
  mov    %esi,%esi
  mov    $0x0,%eax
L34:
  mov    %eax,%ecx
  movzbl (%rdx,%rax,1),%r8d
  cmp    %r8b,(%rdi,%rax,1)
  jne    L35
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L34
L35:
  mov    %ecx,%eax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L35
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  (void)(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fts3PrefixCompress>:
  endbr64
  test   %esi,%esi
  jle    L28
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L34
  nop
L48:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L16
L34:
  movzbl (%rdx,%rax,1),%ecx
  mov    %eax,%r8d
  cmp    %cl,(%rdi,%rax,1)
  je     L48
L16:
  mov    %r8d,%eax
  ret
L28:
  xor    %r8d,%r8d
  jmp    L16
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  (void)(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fts3PrefixCompress>:
  endbr64
  test   %esi,%esi
  jle    L32
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L37
  nop
L8:
  lea    0x1(%rax),%r8d
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L11
L37:
  movzbl (%rdx,%rax,1),%ecx
  mov    %eax,%r8d
  cmp    %cl,(%rdi,%rax,1)
  je     L8
L11:
  mov    %r8d,%eax
  ret
L32:
  xor    %r8d,%r8d
  jmp    L11
```

assistant: ```c
int fts3PrefixCompress(const char *zPrev, int nPrev, const char *zNext, int nNext) {
  int n;
  (void)(nNext);
  for (n = 0; n < nPrev && zPrev[n] == zNext[n]; n++)
    ;
  return n;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0xc,-0x28(%rbp)
  movl   $0x12,-0x24(%rbp)
  movl   $0x1e,-0x20(%rbp)
  movl   $0x2a,-0x1c(%rbp)
  movl   $0x3c,-0x18(%rbp)
  movl   $0x48,-0x14(%rbp)
  movl   $0x66,-0x10(%rbp)
  movl   $0x6c,-0xc(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L4
L10:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L4:
  cmpl   $0x9,-0x34(%rbp)
  jle    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type_infered: string

tool: D3: (%d, %d)


assistant: ```c
int main() {
  int array[10] = {4, 6, 12, 18, 30, 42, 60, 72, 102, 108};
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("(%d, %d)\n", array[i] - 1, array[i] + 1);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x4,(%rsp)
  movl   $0x6,0x4(%rsp)
  movl   $0xc,0x8(%rsp)
  movl   $0x12,0xc(%rsp)
  movl   $0x1e,0x10(%rsp)
  movl   $0x2a,0x14(%rsp)
  movl   $0x3c,0x18(%rsp)
  movl   $0x48,0x1c(%rsp)
  movl   $0x66,0x20(%rsp)
  movl   $0x6c,0x24(%rsp)
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  lea    D9(%rip),%rbp
L6:
  mov    (%rbx),%esi
  lea    0x1(%rsi),%edx
  sub    $0x1,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L6
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D9
type_guessed: string

tool: D9: (%d, %d)


assistant: ```c
int main() {
  int array[10] = {4, 6, 12, 18, 30, 42, 60, 72, 102, 108};
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("(%d, %d)\n", array[i] - 1, array[i] + 1);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%esi
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  lea    0x28(%rsp),%r12
  movabs $0x120000000c,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2a0000001e,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x480000003c,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x6c00000066,%rax
  movl   $0x6,0x4(%rsp)
  mov    %rax,0x20(%rsp)
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L16:
  mov    (%rbx),%esi
  add    $0x4,%rbx
L13:
  lea    0x1(%rsi),%edx
  mov    %rbp,%rdi
  sub    $0x1,%esi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D6
datatype: string

tool: D6: (%d, %d)


assistant: ```c
int main() {
  int array[10] = {4, 6, 12, 18, 30, 42, 60, 72, 102, 108};
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("(%d, %d)\n", array[i] - 1, array[i] + 1);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D32(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D14(%rip),%rax
  mov    %rsp,%rbx
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D17(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  lea    0x1(%rsi),%edx
  sub    $0x1,%esi
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D10
type_infered: string
name: read_data
arguments: data_tag: D32
type_infered: byte[16]
name: read_data
arguments: data_tag: D14
type_infered: byte[8]
name: read_data
arguments: data_tag: D17
type_infered: byte[16]

tool: D10: (%d, %d)


tool: {"D32": [0x04,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x12,0x00,0x00,0x00]}

tool: {"D14": [0x66,0x00,0x00,0x00,0x6c,0x00,0x00,0x00]}

tool: {"D17": [0x1e,0x00,0x00,0x00,0x2a,0x00,0x00,0x00,0x3c,0x00,0x00,0x00,0x48,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int array[10] = {4, 6, 12, 18, 30, 42, 60, 72, 102, 108};
  int i = 0;
  for (i = 0; i < 10; i++) {
    printf("(%d, %d)\n", array[i] - 1, array[i] + 1);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_bcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x21,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_bcopy@plt>
  lea    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x21,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__builtin_bcopy@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <sink@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void test_bcopy(const void *s) {
  char d[33];
  __builtin_bcopy(s, d, sizeof d);
  __builtin_bcopy(s, d, sizeof d);
  sink(d);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_bcopy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x21,%edx
  mov    %rbp,%rsi
  call   <__builtin_bcopy@plt>
  mov    $0x21,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <__builtin_bcopy@plt>
  mov    %rbp,%rdi
  call   <sink@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_bcopy(const void *s) {
  char d[33];
  __builtin_bcopy(s, d, sizeof d);
  __builtin_bcopy(s, d, sizeof d);
  sink(d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_bcopy>:
  endbr64
  push   %r12
  mov    $0x21,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <__builtin_bcopy@plt>
  mov    %rbp,%rdi
  mov    $0x21,%edx
  mov    %r12,%rsi
  call   <__builtin_bcopy@plt>
  mov    %r12,%rdi
  call   <sink@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_bcopy(const void *s) {
  char d[33];
  __builtin_bcopy(s, d, sizeof d);
  __builtin_bcopy(s, d, sizeof d);
  sink(d);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_bcopy>:
  endbr64
  push   %r12
  mov    $0x21,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <__builtin_bcopy@plt>
  mov    %rbp,%rdi
  mov    $0x21,%edx
  mov    %r12,%rsi
  call   <__builtin_bcopy@plt>
  mov    %r12,%rdi
  call   <sink@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_bcopy(const void *s) {
  char d[33];
  __builtin_bcopy(s, d, sizeof d);
  __builtin_bcopy(s, d, sizeof d);
  sink(d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<process_undef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  nop
L25:
  cmpl   $0xa,-0x3f4(%rbp)
  je     L26
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getnexttoken@plt>
  mov    %eax,-0x3f4(%rbp)
  mov    -0x3f4(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L25
L26:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <undef@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void process_undef(void) {
  int c;
  char token[1000];
  while (c != '\n' && isspace(c = getnexttoken(token, 1000)))
    ;
  undef(token);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<process_undef>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
L25:
  cmp    $0xa,%ebx
  je     L9
  mov    $0x3e8,%esi
  mov    %rbp,%rdi
  call   <getnexttoken@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L25
L9:
  mov    %rsp,%rdi
  call   <undef@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void process_undef(void) {
  int c;
  char token[1000];
  while (c != '\n' && isspace(c = getnexttoken(token, 1000)))
    ;
  undef(token);
}
```
user: Translate the below assembly code into C programming language:

```asm
<process_undef>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L7
  nopl   (%rax)
L2:
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  call   <getnexttoken@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  je     L11
L7:
  cmp    $0xa,%ebx
  jne    L2
L11:
  mov    %rbp,%rdi
  call   <undef@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void process_undef(void) {
  int c;
  char token[1000];
  while (c != '\n' && isspace(c = getnexttoken(token, 1000)))
    ;
  undef(token);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<process_undef>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L38
  nopl   (%rax)
L31:
  mov    %rbp,%rdi
  mov    $0x3e8,%esi
  call   <getnexttoken@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  je     L3
L38:
  cmp    $0xa,%ebx
  jne    L31
L3:
  mov    %rbp,%rdi
  call   <undef@plt>
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void process_undef(void) {
  int c;
  char token[1000];
  while (c != '\n' && isspace(c = getnexttoken(token, 1000)))
    ;
  undef(token);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strftime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  cmpq   $0x0,-0x28(%rbp)
  je     L11
  mov    -0x28(%rbp),%rax
  jmp    L1
L11:
  lea    D0(%rip),%rax
L1:
  mov    -0x18(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    %rax,%rdi
  call   <_fmt@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jne    L9
  mov    $0x0,%eax
  jmp    L33
L9:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
L33:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: %c

assistant: ```c
size_t strftime(char *const s, const size_t maxsize, const char *const format, const struct tm *const t) {
  char *p;
  p = _fmt(((format == NULL) ? "%c" : format), t, s, s + maxsize);
  if (p == s + maxsize)
    return 0;
  *p = '\0';
  return p - s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strftime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  mov    %rcx,%rax
  lea    (%rbx,%rsi,1),%rbp
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %rax,%rsi
  call   <_fmt@plt>
  cmp    %rax,%rbp
  je     L11
  movb   $0x0,(%rax)
  sub    %rbx,%rax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  mov    $0x0,%eax
  jmp    L19
```

assistant: ```c
size_t strftime(char *const s, const size_t maxsize, const char *const format, const struct tm *const t) {
  char *p;
  p = _fmt(((format == NULL) ? "%c" : format), t, s, s + maxsize);
  if (p == s + maxsize)
    return 0;
  *p = '\0';
  return p - s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strftime>:
  endbr64
  push   %rbp
  mov    %rcx,%r8
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  lea    (%rbx,%rsi,1),%rbp
  mov    %rbx,%rdx
  mov    %r8,%rsi
  mov    %rbp,%rcx
  sub    $0x8,%rsp
  call   <_fmt@plt>
  cmp    %rax,%rbp
  je     L3
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t strftime(char *const s, const size_t maxsize, const char *const format, const struct tm *const t) {
  char *p;
  p = _fmt(((format == NULL) ? "%c" : format), t, s, s + maxsize);
  if (p == s + maxsize)
    return 0;
  *p = '\0';
  return p - s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strftime>:
  endbr64
  push   %rbp
  mov    %rcx,%r8
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdx,%rdi
  lea    (%rbx,%rsi,1),%rbp
  mov    %rbx,%rdx
  mov    %r8,%rsi
  mov    %rbp,%rcx
  sub    $0x8,%rsp
  call   <_fmt@plt>
  cmp    %rax,%rbp
  je     L9
  movb   $0x0,(%rax)
  add    $0x8,%rsp
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t strftime(char *const s, const size_t maxsize, const char *const format, const struct tm *const t) {
  char *p;
  p = _fmt(((format == NULL) ? "%c" : format), t, s, s + maxsize);
  if (p == s + maxsize)
    return 0;
  *p = '\0';
  return p - s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<local1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int local1() {
  int x;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<local1>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int local1() {
  int x;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<local1>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int local1() {
  int x;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<local1>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int local1() {
  int x;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PicocCleanup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <PlatformCleanup@plt>
  mov    $0x0,%eax
  call   <IncludeCleanup@plt>
  mov    $0x0,%eax
  call   <ParseCleanup@plt>
  mov    $0x0,%eax
  call   <LexCleanup@plt>
  mov    $0x0,%eax
  call   <VariableCleanup@plt>
  mov    $0x0,%eax
  call   <TypeCleanup@plt>
  mov    $0x0,%eax
  call   <TableStrFree@plt>
  mov    $0x0,%eax
  call   <HeapCleanup@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PicocCleanup() {
  PlatformCleanup();
  IncludeCleanup();
  ParseCleanup();
  LexCleanup();
  VariableCleanup();
  TypeCleanup();
  TableStrFree();
  HeapCleanup();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<PicocCleanup>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <PlatformCleanup@plt>
  mov    $0x0,%eax
  call   <IncludeCleanup@plt>
  mov    $0x0,%eax
  call   <ParseCleanup@plt>
  mov    $0x0,%eax
  call   <LexCleanup@plt>
  mov    $0x0,%eax
  call   <VariableCleanup@plt>
  mov    $0x0,%eax
  call   <TypeCleanup@plt>
  mov    $0x0,%eax
  call   <TableStrFree@plt>
  mov    $0x0,%eax
  call   <HeapCleanup@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void PicocCleanup() {
  PlatformCleanup();
  IncludeCleanup();
  ParseCleanup();
  LexCleanup();
  VariableCleanup();
  TypeCleanup();
  TableStrFree();
  HeapCleanup();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<PicocCleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PlatformCleanup@plt>
  xor    %eax,%eax
  call   <IncludeCleanup@plt>
  xor    %eax,%eax
  call   <ParseCleanup@plt>
  xor    %eax,%eax
  call   <LexCleanup@plt>
  xor    %eax,%eax
  call   <VariableCleanup@plt>
  xor    %eax,%eax
  call   <TypeCleanup@plt>
  xor    %eax,%eax
  call   <TableStrFree@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1110 <HeapCleanup@plt>
```

assistant: ```c
void PicocCleanup() {
  PlatformCleanup();
  IncludeCleanup();
  ParseCleanup();
  LexCleanup();
  VariableCleanup();
  TypeCleanup();
  TableStrFree();
  HeapCleanup();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PicocCleanup>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PlatformCleanup@plt>
  xor    %eax,%eax
  call   <IncludeCleanup@plt>
  xor    %eax,%eax
  call   <ParseCleanup@plt>
  xor    %eax,%eax
  call   <LexCleanup@plt>
  xor    %eax,%eax
  call   <VariableCleanup@plt>
  xor    %eax,%eax
  call   <TypeCleanup@plt>
  xor    %eax,%eax
  call   <TableStrFree@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1110 <HeapCleanup@plt>
```

assistant: ```c
void PicocCleanup() {
  PlatformCleanup();
  IncludeCleanup();
  ParseCleanup();
  LexCleanup();
  VariableCleanup();
  TypeCleanup();
  TableStrFree();
  HeapCleanup();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<SysCtlGPIOAHBEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    $0x400fe06c,%eax
  mov    (%rax),%rsi
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  cltq
  mov    $0x400fe06c,%edx
  or     %rsi,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void SysCtlGPIOAHBEnable(uint32_t ui32GPIOPeripheral) {

  ;
  (*((volatile unsigned long *)(0x400FE06C))) |= (1 << (ui32GPIOPeripheral & 0xF));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<SysCtlGPIOAHBEnable>:
  endbr64
  mov    0x400fe06c,%rdx
  mov    %edi,%ecx
  and    $0xf,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  cltq
  or     %rdx,%rax
  mov    %rax,0x400fe06c
  ret
```

assistant: ```c
void SysCtlGPIOAHBEnable(uint32_t ui32GPIOPeripheral) {

  ;
  (*((volatile unsigned long *)(0x400FE06C))) |= (1 << (ui32GPIOPeripheral & 0xF));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SysCtlGPIOAHBEnable>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  mov    0x400fe06c,%rdx
  and    $0xf,%ecx
  shl    %cl,%eax
  cltq
  or     %rdx,%rax
  mov    %rax,0x400fe06c
  ret
```

assistant: ```c
void SysCtlGPIOAHBEnable(uint32_t ui32GPIOPeripheral) {

  ;
  (*((volatile unsigned long *)(0x400FE06C))) |= (1 << (ui32GPIOPeripheral & 0xF));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<SysCtlGPIOAHBEnable>:
  endbr64
  mov    %edi,%ecx
  mov    $0x1,%eax
  mov    0x400fe06c,%rdx
  and    $0xf,%ecx
  shl    %cl,%eax
  cltq
  or     %rdx,%rax
  mov    %rax,0x400fe06c
  ret
```

assistant: ```c
void SysCtlGPIOAHBEnable(uint32_t ui32GPIOPeripheral) {

  ;
  (*((volatile unsigned long *)(0x400FE06C))) |= (1 << (ui32GPIOPeripheral & 0xF));
}
```