ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<de>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <decrypt@plt>
  cmpl   $0x0,-0x28(%rbp)
  je     L9
  subl   $0x1,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  nop
L3:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  je     L6
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  je     L3
L6:
  addl   $0x1,-0x24(%rbp)
L9:
  mov    -0x24(%rbp),%eax
  leave
  ret
```

assistant: ```c
char de(char *buf, char *key, int len, int atEOF) {
  char l;
  decrypt(buf, key);
  if (atEOF) {
    l = buf[--len];
    while (len-- && buf[len] == (char)l)
      ;
    ++len;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<de>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %edx,%ebx
  mov    %ecx,%r12d
  call   <decrypt@plt>
  test   %r12d,%r12d
  je     L1
  lea    -0x1(%rbx),%eax
  cltq
  movzbl 0x0(%rbp,%rax,1),%ecx
L14:
  mov    %eax,%ebx
  test   %eax,%eax
  je     L1
  sub    $0x1,%rax
  cmp    %cl,0x0(%rbp,%rax,1)
  je     L14
L1:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char de(char *buf, char *key, int len, int atEOF) {
  char l;
  decrypt(buf, key);
  if (atEOF) {
    l = buf[--len];
    while (len-- && buf[len] == (char)l)
      ;
    ++len;
  }
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<de>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <decrypt@plt>
  mov    %ebp,%eax
  test   %r12d,%r12d
  je     L2
  sub    $0x1,%ebp
  movslq %ebp,%rax
  movzbl (%rbx,%rax,1),%ecx
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L32:
  lea    -0x1(%rax),%rdx
  cmp    %cl,-0x1(%rbx,%rax,1)
  jne    L2
  mov    %rdx,%rax
L27:
  test   %eax,%eax
  jne    L32
  xor    %eax,%eax
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char de(char *buf, char *key, int len, int atEOF) {
  char l;
  decrypt(buf, key);
  if (atEOF) {
    l = buf[--len];
    while (len-- && buf[len] == (char)l)
      ;
    ++len;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<de>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <decrypt@plt>
  mov    %ebp,%eax
  test   %r12d,%r12d
  je     L23
  sub    $0x1,%ebp
  movslq %ebp,%rax
  movzbl (%rbx,%rax,1),%ecx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L5:
  lea    -0x1(%rax),%rdx
  cmp    %cl,-0x1(%rbx,%rax,1)
  jne    L23
  mov    %rdx,%rax
L12:
  test   %eax,%eax
  jne    L5
  xor    %eax,%eax
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char de(char *buf, char *key, int len, int atEOF) {
  char l;
  decrypt(buf, key);
  if (atEOF) {
    l = buf[--len];
    while (len-- && buf[len] == (char)l)
      ;
    ++len;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strends>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jge    L14
  mov    $0x0,%eax
  jmp    L18
L14:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  mov    %rbx,%rdx
  sub    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L18:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool strends(const char *a, const char *b) {
  if (strlen(a) < strlen(b))
    return false;
  return (strcmp((a + strlen(a) - strlen(b)), (b)) == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strends>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    %edx,%ebp
  jge    L5
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %ebp,%rbp
  cltq
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L8
```

assistant: ```c
bool strends(const char *a, const char *b) {
  if (strlen(a) < strlen(b))
    return false;
  return (strcmp((a + strlen(a) - strlen(b)), (b)) == 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strends>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebp
  jl     L7
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  mov    %r12,%rsi
  cltq
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool strends(const char *a, const char *b) {
  if (strlen(a) < strlen(b))
    return false;
  return (strcmp((a + strlen(a) - strlen(b)), (b)) == 0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strends>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    %r8d,%ebp
  jl     L1
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  mov    %r12,%rsi
  cltq
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
bool strends(const char *a, const char *b) {
  if (strlen(a) < strlen(b))
    return false;
  return (strcmp((a + strlen(a) - strlen(b)), (b)) == 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FreeFloatCube>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L14:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L0:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L14
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void FreeFloatCube(float ***Cube, int M, int N) {
  int m, n;
  for (m = 0; m < M; m++) {
    for (n = 0; n < N; n++)
      free(Cube[m][n]);
    free(Cube[m]);
  }
  free(Cube);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<FreeFloatCube>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r15
  test   %esi,%esi
  jle    L24
  mov    %edx,%r13d
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r14
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%r12
  jmp    L14
L10:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L10
L58:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  add    $0x8,%rbp
  cmp    %r14,%rbp
  je     L24
L14:
  mov    $0x0,%ebx
  test   %r13d,%r13d
  jg     L10
  jmp    L58
L24:
  mov    %r15,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void FreeFloatCube(float ***Cube, int M, int N) {
  int m, n;
  for (m = 0; m < M; m++) {
    for (n = 0; n < N; n++)
      free(Cube[m][n]);
    free(Cube[m]);
  }
  free(Cube);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FreeFloatCube>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  mov    %edx,%r12d
  mov    %rdi,%r15
  lea    0x8(%rdi,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L29
  nop
L37:
  mov    (%r15),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L37
L29:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <free@plt>
  cmp    %r13,%r15
  jne    L10
L6:
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <free@plt>
```

assistant: ```c
void FreeFloatCube(float ***Cube, int M, int N) {
  int m, n;
  for (m = 0; m < M; m++) {
    for (n = 0; n < N; n++)
      free(Cube[m][n]);
    free(Cube[m]);
  }
  free(Cube);
}
```
user: What is the c source code of the assembly code below?

```asm
<FreeFloatCube>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  mov    %edx,%r12d
  mov    %rdi,%r15
  lea    0x8(%rdi,%rax,8),%r13
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L34
  nop
L36:
  mov    (%r15),%rax
  mov    (%rax,%rbx,1),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbx,%rbp
  jne    L36
L34:
  mov    (%r15),%rdi
  add    $0x8,%r15
  call   <free@plt>
  cmp    %r15,%r13
  jne    L24
L9:
  add    $0x8,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <free@plt>
```

assistant: ```c
void FreeFloatCube(float ***Cube, int M, int N) {
  int m, n;
  for (m = 0; m < M; m++) {
    for (n = 0; n < N; n++)
      free(Cube[m][n]);
    free(Cube[m]);
  }
  free(Cube);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<listSiblingRefs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <prj_find_package@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L27
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <prj_get_language_for@plt>
  mov    %eax,%edx
  lea    D5(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <matches@plt>
  test   %rax,%rax
  je     L27
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <prj_get_relativetarget_for@plt>
  jmp    L20
L27:
  mov    $0x0,%eax
L20:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: c#

assistant: ```c
const char *listSiblingRefs(const char *name) {
  int i = prj_find_package(name);
  if (i >= 0) {
    if (matches(prj_get_language_for(i), "c#")) {
      return prj_get_relativetarget_for(i);
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<listSiblingRefs>:
  endbr64
  push   %rbx
  call   <prj_find_package@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  test   %ebx,%ebx
  js     L14
  mov    %ebx,%edi
  call   <prj_get_language_for@plt>
  mov    %eax,%edi
  lea    D8(%rip),%rsi
  call   <matches@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L26
L14:
  pop    %rbx
  ret
L26:
  mov    %ebx,%edi
  call   <prj_get_relativetarget_for@plt>
  jmp    L14
```

tool_calls: name: parse_data
arguments: tag: D8
data_type: string

tool: D8: c#

assistant: ```c
const char *listSiblingRefs(const char *name) {
  int i = prj_find_package(name);
  if (i >= 0) {
    if (matches(prj_get_language_for(i), "c#")) {
      return prj_get_relativetarget_for(i);
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<listSiblingRefs>:
  endbr64
  push   %rbp
  call   <prj_find_package@plt>
  test   %eax,%eax
  js     L2
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <prj_get_language_for@plt>
  lea    D3(%rip),%rsi
  mov    %eax,%edi
  call   <matches@plt>
  test   %rax,%rax
  jne    L7
L2:
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L7:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1080 <prj_get_relativetarget_for@plt>
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: c#

assistant: ```c
const char *listSiblingRefs(const char *name) {
  int i = prj_find_package(name);
  if (i >= 0) {
    if (matches(prj_get_language_for(i), "c#")) {
      return prj_get_relativetarget_for(i);
    }
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<listSiblingRefs>:
  endbr64
  push   %rbp
  call   <prj_find_package@plt>
  test   %eax,%eax
  js     L5
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <prj_get_language_for@plt>
  lea    D1(%rip),%rsi
  mov    %eax,%edi
  call   <matches@plt>
  test   %rax,%rax
  jne    L0
L5:
  xor    %eax,%eax
  pop    %rbp
  ret
  xchg   %ax,%ax
L0:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1080 <prj_get_relativetarget_for@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: string

tool: D1: c#

assistant: ```c
const char *listSiblingRefs(const char *name) {
  int i = prj_find_package(name);
  if (i >= 0) {
    if (matches(prj_get_language_for(i), "c#")) {
      return prj_get_relativetarget_for(i);
    }
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<fc8180_spib_bulkread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movb   $0xc0,-0x5(%rbp)
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl -0x20(%rbp),%edi
  movzbl -0x5(%rbp),%edx
  movzwl -0x1c(%rbp),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <spi_bulkread@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
signed int fc8180_spib_bulkread(void *handle, unsigned short addr, unsigned char *data, unsigned short length) {
  signed int res;
  unsigned char command = 0x40 | 0x80;
  OAL_OBTAIN_SEMAPHORE();
  res = spi_bulkread(handle, addr, command, data, length);
  OAL_RELEASE_SEMAPHORE();
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fc8180_spib_bulkread>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl %bx,%esi
  movzwl %r13w,%r8d
  mov    %r12,%rcx
  mov    $0xc0,%edx
  mov    %rbp,%rdi
  call   <spi_bulkread@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
signed int fc8180_spib_bulkread(void *handle, unsigned short addr, unsigned char *data, unsigned short length) {
  signed int res;
  unsigned char command = 0x40 | 0x80;
  OAL_OBTAIN_SEMAPHORE();
  res = spi_bulkread(handle, addr, command, data, length);
  OAL_RELEASE_SEMAPHORE();
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fc8180_spib_bulkread>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl %bx,%esi
  movzwl %bp,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdi
  mov    $0xc0,%edx
  call   <spi_bulkread@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
signed int fc8180_spib_bulkread(void *handle, unsigned short addr, unsigned char *data, unsigned short length) {
  signed int res;
  unsigned char command = 0x40 | 0x80;
  OAL_OBTAIN_SEMAPHORE();
  res = spi_bulkread(handle, addr, command, data, length);
  OAL_RELEASE_SEMAPHORE();
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fc8180_spib_bulkread>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl %bx,%esi
  movzwl %bp,%r8d
  mov    %r13,%rcx
  mov    %r12,%rdi
  mov    $0xc0,%edx
  call   <spi_bulkread@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
signed int fc8180_spib_bulkread(void *handle, unsigned short addr, unsigned char *data, unsigned short length) {
  signed int res;
  unsigned char command = 0x40 | 0x80;
  OAL_OBTAIN_SEMAPHORE();
  res = spi_bulkread(handle, addr, command, data, length);
  OAL_RELEASE_SEMAPHORE();
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<stdlib_isoneof>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L11
L21:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L28
  mov    $0x1,%eax
  jmp    L5
L28:
  addq   $0x1,-0x20(%rbp)
L11:
  mov    -0x20(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L21
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int stdlib_isoneof(char c, char *from, int fsize) {
  char *fend = from + fsize;
  while (from < fend) {
    if (c == *from)
      return 1;
    from++;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stdlib_isoneof>:
  endbr64
  movslq %edx,%rdx
  add    %rsi,%rdx
  cmp    %rdx,%rsi
  jae    L27
L26:
  cmp    %dil,(%rsi)
  je     L16
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  jne    L26
  mov    $0x0,%eax
  ret
L27:
  mov    $0x0,%eax
  ret
L16:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int stdlib_isoneof(char c, char *from, int fsize) {
  char *fend = from + fsize;
  while (from < fend) {
    if (c == *from)
      return 1;
    from++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stdlib_isoneof>:
  endbr64
  movslq %edx,%rdx
  add    %rsi,%rdx
  cmp    %rdx,%rsi
  jb     L10
  jmp    L1
  nopl   0x0(%rax)
L19:
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  je     L1
L10:
  cmp    %dil,(%rsi)
  jne    L19
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int stdlib_isoneof(char c, char *from, int fsize) {
  char *fend = from + fsize;
  while (from < fend) {
    if (c == *from)
      return 1;
    from++;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stdlib_isoneof>:
  endbr64
  movslq %edx,%rdx
  add    %rsi,%rdx
  cmp    %rdx,%rsi
  jb     L27
  jmp    L24
  nopl   0x0(%rax)
L10:
  add    $0x1,%rsi
  cmp    %rsi,%rdx
  je     L24
L27:
  cmp    %dil,(%rsi)
  jne    L10
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int stdlib_isoneof(char c, char *from, int fsize) {
  char *fend = from + fsize;
  while (from < fend) {
    if (c == *from)
      return 1;
    from++;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<activities>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L18
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L18:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D2
type_infered: string

tool: D15: Selected Activities are:

tool: D2: A%d 

assistant: ```c
void activities(int s[], int f[], int n) {
  int i, j;
  printf("Selected Activities are:\n");
  i = 1;
  printf("A%d ", i);
  for (j = 1; j < n; j++) {
    if (s[j] >= f[i]) {
      printf("A%d ", j + 1);
      i = j;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<activities>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%ebp
  jle    L32
  mov    %ebp,%ebp
  mov    $0x1,%ebx
  mov    $0x1,%edx
  lea    D26(%rip),%r14
  jmp    L42
L13:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L32
L42:
  movslq %edx,%rax
  mov    0x0(%r13,%rax,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  jl     L13
  lea    0x1(%rbx),%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edx
  jmp    L13
L32:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string

tool: D8: Selected Activities are:

tool: D26: A%d 

assistant: ```c
void activities(int s[], int f[], int n) {
  int i, j;
  printf("Selected Activities are:\n");
  i = 1;
  printf("A%d ", i);
  for (j = 1; j < n; j++) {
    if (s[j] >= f[i]) {
      printf("A%d ", j + 1);
      i = j;
    }
  }
}
```