ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<xmalloc>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string

tool: D9: stderr: malloc failed


assistant: ```c
void *xmalloc(int len) {
  void *ptr = malloc(len);
  if (ptr == NULL) {
    printf("stderr: malloc failed\n");
    exit(1);
  }
  return ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x5,-0x20(%rbp)
  movl   $0x9,-0x1c(%rbp)
  movl   $0x15,-0x18(%rbp)
  movl   $0x11,-0x14(%rbp)
  movl   $0x27,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <max@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string

tool: D8: largest number is: %d

assistant: ```c
int main() {
  int nums[5] = {5, 9, 21, 17, 39};
  printf("largest number is: %d", max(nums, 5));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x5,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x15,0x8(%rsp)
  movl   $0x11,0xc(%rsp)
  movl   $0x27,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <max@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type: string

tool: D6: largest number is: %d

assistant: ```c
int main() {
  int nums[5] = {5, 9, 21, 17, 39};
  printf("largest number is: %d", max(nums, 5));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000005,%rax
  mov    %rsp,%rdi
  movl   $0x27,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x1100000015,%rax
  mov    %rax,0x8(%rsp)
  call   <max@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string

tool: D7: largest number is: %d

assistant: ```c
int main() {
  int nums[5] = {5, 9, 21, 17, 39};
  printf("largest number is: %d", max(nums, 5));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D6(%rip),%xmm0
  mov    $0x5,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movl   $0x27,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <max@plt>
  lea    D0(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
datatype: byte[16]
name: parse_data
arguments: tag: D0
datatype: string

tool: {"D6": [0x05,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x15,0x00,0x00,0x00,0x11,0x00,0x00,0x00]}

tool: D0: largest number is: %d

assistant: ```c
int main() {
  int nums[5] = {5, 9, 21, 17, 39};
  printf("largest number is: %d", max(nums, 5));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(int *arr, int i1, int i2) {
  int tmp;
  tmp = arr[i1];
  arr[i1] = arr[i2];
  arr[i2] = tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *arr, int i1, int i2) {
  int tmp;
  tmp = arr[i1];
  arr[i1] = arr[i2];
  arr[i2] = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *arr, int i1, int i2) {
  int tmp;
  tmp = arr[i1];
  arr[i1] = arr[i2];
  arr[i2] = tmp;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
void swap(int *arr, int i1, int i2) {
  int tmp;
  tmp = arr[i1];
  arr[i1] = arr[i2];
  arr[i2] = tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_colindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rcx
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rcx,%rax
  mul    %rdx
  shr    $0x2,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rax,%rax
  sub    %rax,%rcx
  mov    %rcx,%rdx
  test   %rdx,%rdx
  je     L67
  mov    $0x0,%eax
  jmp    L26
L67:
  movl   $0x0,-0x10(%rbp)
  jmp    L9
L20:
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L47:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%eax
  add    $0x5,%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L7
  mov    $0x0,%eax
  jmp    L26
L7:
  addl   $0x1,-0xc(%rbp)
L33:
  cmpl   $0x2,-0xc(%rbp)
  jle    L47
  addl   $0x6,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  ja     L20
  mov    $0x1,%eax
L26:
  leave
  ret
```

assistant: ```c
int find_colindrome(const char *str) {
  size_t len = strlen(str);
  if ((len % 6) != 0) {
    return 0;
  }
  for (int itr1 = 0; itr1 < len; itr1 += 6) {
    for (int itr2 = 0; itr2 < 3; itr2++) {
      if (str[itr1 + itr2] != str[itr1 + 5 - itr2]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_colindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%r8
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  add    %rax,%rax
  mov    $0x0,%ecx
  mov    %r8,%rdx
  sub    %rax,%rdx
  jne    L83
  test   %r8,%r8
  je     L29
  mov    %rbx,%rsi
  mov    %rdx,%rax
  jmp    L57
L87:
  add    $0x6,%rax
  add    $0x6,%rsi
  cmp    %rax,%r8
  jbe    L64
L57:
  mov    %rdx,%rcx
L71:
  mov    %rcx,%rdi
  neg    %rdi
  movzbl 0x5(%rsi,%rdi,1),%ebx
  cmp    %bl,(%rsi,%rcx,1)
  jne    L68
  add    $0x1,%rcx
  cmp    $0x3,%rcx
  jne    L71
  jmp    L87
L29:
  mov    $0x1,%ecx
  jmp    L83
L68:
  mov    $0x0,%ecx
L83:
  mov    %ecx,%eax
  pop    %rbx
  ret
L64:
  mov    $0x1,%ecx
  jmp    L83
```

assistant: ```c
int find_colindrome(const char *str) {
  size_t len = strlen(str);
  if ((len % 6) != 0) {
    return 0;
  }
  for (int itr1 = 0; itr1 < len; itr1 += 6) {
    for (int itr2 = 0; itr2 < 3; itr2++) {
      if (str[itr1 + itr2] != str[itr1 + 5 - itr2]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<find_colindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r9d,%r9d
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rax,%r8
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  add    %rax,%rax
  cmp    %rax,%r8
  jne    L45
  test   %r8,%r8
  je     L27
  mov    %rbx,%rdi
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %edx,%edx
L12:
  mov    %rdx,%rcx
  neg    %rcx
  movzbl 0x5(%rdi,%rcx,1),%eax
  cmp    %al,(%rdi,%rdx,1)
  jne    L34
  add    $0x1,%rdx
  cmp    $0x3,%rdx
  jne    L12
  add    $0x6,%rsi
  add    $0x6,%rdi
  cmp    %rsi,%r8
  ja     L16
L27:
  mov    $0x1,%r9d
L45:
  mov    %r9d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L34:
  xor    %r9d,%r9d
  pop    %rbx
  mov    %r9d,%eax
  ret
```

assistant: ```c
int find_colindrome(const char *str) {
  size_t len = strlen(str);
  if ((len % 6) != 0) {
    return 0;
  }
  for (int itr1 = 0; itr1 < len; itr1 += 6) {
    for (int itr2 = 0; itr2 < 3; itr2++) {
      if (str[itr1 + itr2] != str[itr1 + 5 - itr2]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_colindrome>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  xor    %r8d,%r8d
  movabs $0xaaaaaaaaaaaaaaab,%rdx
  mov    %rax,%rcx
  mul    %rdx
  shr    $0x2,%rdx
  lea    (%rdx,%rdx,2),%rax
  mov    %rcx,%rdx
  add    %rax,%rax
  sub    %rax,%rdx
  jne    L27
  test   %rcx,%rcx
  je     L41
  mov    %rbx,%rdi
  jmp    L8
  nopl   (%rax)
L47:
  movzbl 0x4(%rdi),%eax
  cmp    %al,0x1(%rdi)
  jne    L39
  movzbl 0x3(%rdi),%eax
  cmp    %al,0x2(%rdi)
  jne    L39
  add    $0x6,%rdx
  add    $0x6,%rdi
  cmp    %rdx,%rcx
  jbe    L41
L8:
  movzbl 0x5(%rdi),%eax
  cmp    %al,(%rdi)
  je     L47
L39:
  xor    %r8d,%r8d
L27:
  mov    %r8d,%eax
  pop    %rbx
  ret
  nop
L41:
  mov    $0x1,%r8d
  pop    %rbx
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_colindrome(const char *str) {
  size_t len = strlen(str);
  if ((len % 6) != 0) {
    return 0;
  }
  for (int itr1 = 0; itr1 < len; itr1 += 6) {
    for (int itr2 = 0; itr2 < 3; itr2++) {
      if (str[itr1 + itr2] != str[itr1 + 5 - itr2]) {
        return 0;
      }
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jg     L5
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L5:
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <upkm@plt>
  mov    %eax,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string

tool: D6: Uso: %s input.pkm output.pkm


assistant: ```c
int main(int argc, char **argv) {
  int ret = -1;
  if (argc < 3) {
    printf("Uso: %s input.pkm output.pkm\n", argv[0]);
  } else {
    ret = upkm(argv[1], argv[2]);
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  jle    L8
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <upkm@plt>
L1:
  add    $0x8,%rsp
  ret
L8:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: Uso: %s input.pkm output.pkm


assistant: ```c
int main(int argc, char **argv) {
  int ret = -1;
  if (argc < 3) {
    printf("Uso: %s input.pkm output.pkm\n", argv[0]);
  } else {
    ret = upkm(argv[1], argv[2]);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jle    L5
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  jmp    1070 <upkm@plt>
L5:
  push   %rax
  mov    (%rsi),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  pop    %rdx
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: Uso: %s input.pkm output.pkm


assistant: ```c
int main(int argc, char **argv) {
  int ret = -1;
  if (argc < 3) {
    printf("Uso: %s input.pkm output.pkm\n", argv[0]);
  } else {
    ret = upkm(argv[1], argv[2]);
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  cmp    $0x2,%edi
  jle    L6
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  jmp    1070 <upkm@plt>
L6:
  push   %rax
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  pop    %rdx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string

tool: D6: Uso: %s input.pkm output.pkm


assistant: ```c
int main(int argc, char **argv) {
  int ret = -1;
  if (argc < 3) {
    printf("Uso: %s input.pkm output.pkm\n", argv[0]);
  } else {
    ret = upkm(argv[1], argv[2]);
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ne_test_pssp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  jmp    L11
L25:
  mov    -0x30(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x30(%rbp),%eax
  cltq
  mov    %edx,-0x2c(%rbp,%rax,4)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x30(%rbp),%eax
  cltq
  mov    %edx,-0x20(%rbp,%rax,4)
  mov    -0x30(%rbp),%eax
  cltq
  movl   $0x1,-0x14(%rbp,%rax,4)
  addl   $0x1,-0x30(%rbp)
L11:
  cmpl   $0x2,-0x30(%rbp)
  jle    L25
  lea    -0x14(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x2c(%rbp),%rsi
  mov    -0x34(%rbp),%eax
  mov    %eax,%edi
  call   <ex_put_ss_param_global@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int ne_test_pssp(int fileid) {
  int i, global_ids[3], global_el_cnts[3], global_df_cnts[3];
  for (i = 0; i < 3; i++) {
    global_ids[i] = 3 * (i + 1);
    global_el_cnts[i] = 2 * (i + 1);
    global_df_cnts[i] = 1;
  }
  return (ex_put_ss_param_global(fileid, global_ids, global_el_cnts, global_df_cnts));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ne_test_pssp>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x3,0x4(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x1,0x24(%rsp)
  lea    0x1c(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  call   <ex_put_ss_param_global@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_pssp(int fileid) {
  int i, global_ids[3], global_el_cnts[3], global_df_cnts[3];
  for (i = 0; i < 3; i++) {
    global_ids[i] = 3 * (i + 1);
    global_el_cnts[i] = 2 * (i + 1);
    global_df_cnts[i] = 1;
  }
  return (ex_put_ss_param_global(fileid, global_ids, global_el_cnts, global_df_cnts));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ne_test_pssp>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x600000003,%rax
  lea    0x10(%rsp),%rdx
  lea    0x1c(%rsp),%rcx
  movl   $0x9,0xc(%rsp)
  lea    0x4(%rsp),%rsi
  movl   $0x6,0x18(%rsp)
  movl   $0x1,0x24(%rsp)
  mov    %rax,0x4(%rsp)
  movabs $0x400000002,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000001,%rax
  mov    %rax,0x1c(%rsp)
  call   <ex_put_ss_param_global@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ne_test_pssp(int fileid) {
  int i, global_ids[3], global_el_cnts[3], global_df_cnts[3];
  for (i = 0; i < 3; i++) {
    global_ids[i] = 3 * (i + 1);
    global_el_cnts[i] = 2 * (i + 1);
    global_df_cnts[i] = 1;
  }
  return (ex_put_ss_param_global(fileid, global_ids, global_el_cnts, global_df_cnts));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ne_test_pssp>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rdx
  lea    0x28(%rsp),%rcx
  mov    D7(%rip),%rax
  lea    0x8(%rsp),%rsi
  movl   $0x9,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  mov    D1(%rip),%rax
  movl   $0x6,0x20(%rsp)
  mov    %rax,0x18(%rsp)
  mov    D25(%rip),%rax
  movl   $0x1,0x30(%rsp)
  mov    %rax,0x28(%rsp)
  call   <ex_put_ss_param_global@plt>
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x48,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
type_infered: byte[8]
name: read_data
arguments: tag: D1
type_infered: byte[8]
name: read_data
arguments: tag: D25
type_infered: byte[8]

tool: {"D7": [0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: {"D1": [0x02,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D25": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int ne_test_pssp(int fileid) {
  int i, global_ids[3], global_el_cnts[3], global_df_cnts[3];
  for (i = 0; i < 3; i++) {
    global_ids[i] = 3 * (i + 1);
    global_el_cnts[i] = 2 * (i + 1);
    global_df_cnts[i] = 1;
  }
  return (ex_put_ss_param_global(fileid, global_ids, global_el_cnts, global_df_cnts));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L10:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_len(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    $0x1,%eax
L3:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L3
L6:
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%edx
  jmp    L6
```

assistant: ```c
int get_len(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    $0x1,%eax
  xchg   %ax,%ax
L18:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L18
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_len(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_len>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L1
  mov    $0x1,%eax
  xchg   %ax,%ax
L7:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L7
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_len(char s[]) {
  int i = 0;
  while (s[i] != '\0')
    i++;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <split_get_size@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L27:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
L45:
  addl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L37
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L45
L37:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L12
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **split(char *buffer, int delimeter) {
  int size = split_get_size(buffer, delimeter);
  char **res = (char **)malloc(sizeof(char *) * (size + 1));
  int i = 0;
  int p = 0;
  while (buffer[i] != 0) {
    res[p++] = buffer + i;
    do {
      i++;
    } while (buffer[i] != 0 && buffer[i] != delimeter);
    if (buffer[i] != 0) {
      buffer[i] = 0;
      i++;
    }
  }
  res[p] = 0;
  return res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<split>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <split_get_size@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r10
  cmpb   $0x0,0x0(%rbp)
  je     L51
  mov    %rax,%r8
  mov    %rbp,%rax
  mov    $0x0,%r9d
  mov    $0x0,%ecx
  jmp    L44
L5:
  movb   $0x0,(%rdi)
  lea    0x2(%rsi),%ecx
  movslq %ecx,%rax
  add    %rbp,%rax
  add    $0x8,%r8
  cmpb   $0x0,(%rax)
  je     L29
L44:
  add    $0x1,%r9d
  mov    %rax,(%r8)
  movslq %ecx,%rax
  lea    0x1(%rbp,%rax,1),%rdx
  mov    %rdx,%rax
  sub    %edx,%ecx
L46:
  lea    (%rcx,%rax,1),%esi
  mov    %rax,%rdi
  movzbl (%rax),%edx
  test   %dl,%dl
  je     L29
  add    $0x1,%rax
  movsbl %dl,%edx
  cmp    %ebx,%edx
  jne    L46
  jmp    L5
L51:
  mov    $0x0,%r9d
L29:
  movslq %r9d,%r9
  movq   $0x0,(%r10,%r9,8)
  mov    %r10,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char **split(char *buffer, int delimeter) {
  int size = split_get_size(buffer, delimeter);
  char **res = (char **)malloc(sizeof(char *) * (size + 1));
  int i = 0;
  int p = 0;
  while (buffer[i] != 0) {
    res[p++] = buffer + i;
    do {
      i++;
    } while (buffer[i] != 0 && buffer[i] != delimeter);
    if (buffer[i] != 0) {
      buffer[i] = 0;
      i++;
    }
  }
  res[p] = 0;
  return res;
}
```