user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x11(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x11(%rbp),%eax
  movsbl %al,%eax
  cmp    $0x78,%eax
  je     L62
  cmp    $0x78,%eax
  jg     L125
  cmp    $0x58,%eax
  je     L62
  cmp    $0x58,%eax
  jg     L125
  cmp    $0x2f,%eax
  je     L118
  cmp    $0x2f,%eax
  jg     L125
  cmp    $0x2d,%eax
  je     L104
  cmp    $0x2d,%eax
  jg     L125
  cmp    $0x2a,%eax
  je     L62
  cmp    $0x2b,%eax
  jne    L125
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  addss  %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L103
L104:
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  movq   %xmm3,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L103
L62:
  movss  -0x10(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L103
L118:
  movss  -0xc(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L15
  pxor   %xmm1,%xmm1
  ucomiss %xmm1,%xmm0
  jne    L15
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L103
L15:
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  divss  %xmm1,%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm0,%xmm5
  movq   %xmm5,%rax
  movq   %rax,%xmm0
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  jmp    L103
L125:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
L103:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L150
  call   <__stack_chk_fail@plt>
L150:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D79
datatype: string
name: retrieve_data
arguments: data_label: D25
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string
name: retrieve_data
arguments: data_label: D30
datatype: string
name: retrieve_data
arguments: data_label: D23
datatype: string

tool: D79: Type in your expression.

tool: D25: %f %c %f

tool: D5: %.2f


tool: D30: Division by zero.

tool: D23: Unknown operator.

assistant: ```c
int main(void) {
  float value1, value2;
  char operator;
  printf("Type in your expression.\n");
  scanf("%f %c %f", &value1, &operator, & value2);
  switch (operator) {
  case '+':
    printf("%.2f\n", value1 + value2);
    break;
  case '-':
    printf("%.2f\n", value1 - value2);
    break;
  case '*':
  case 'x':
  case 'X':
    printf("%.2f\n", value1 * value2);
    break;
  case '/':
    if (0 == value2)
      printf("Division by zero.\n");
    else
      printf("%.2f\n", value1 / value2);
    break;
  default:
    printf("Unknown operator.\n");
    break;
  }
  return 0;
}
```