ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mill_allocstackmem>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <mill_get_stack_size@plt>
  mov    %eax,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbx
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L0
  xor    %eax,%eax
  call   <mill_get_stack_size@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
void *mill_allocstackmem(void) {
  void *ptr;
  ptr = malloc(mill_get_stack_size());
  if (__builtin_expect(!!(!ptr), 0)) {
    errno = ENOMEM;
    return NULL;
  }
  return (void *)(((char *)ptr) + mill_get_stack_size());
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void lprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<lprintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: Translate the below assembly code into C programming language:

```asm
<lprintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void lprintf(const char *fmt, ...) {
  va_list args;
  va_start(args, fmt);
  vprintf(fmt, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<triad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %rcx,-0x48(%rbp)
  movl   $0x18,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L0
L4:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  movsd  -0x30(%rbp),%xmm1
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <triad_base@plt>
  movq   %xmm0,%rax
  mov    %rax,(%rbx)
  addl   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int triad(int len, double xx, double *a, double *b, double *c) {
  int i, bytes = 24;
  for (i = 0; i < len; i++)
    a[i] = triad_base(b[i], c[i], xx);
  return bytes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<triad>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %rcx,%r15
  mov    %edi,%ebp
  mov    $0x0,%ebx
L14:
  movsd  (%r14,%rbx,8),%xmm0
  movq   %r12,%xmm2
  movsd  (%r15,%rbx,8),%xmm1
  call   <triad_base@plt>
  movsd  %xmm0,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
  mov    $0x18,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  mov    $0x18,%eax
  ret
```

assistant: ```c
int triad(int len, double xx, double *a, double *b, double *c) {
  int i, bytes = 24;
  for (i = 0; i < len; i++)
    a[i] = triad_base(b[i], c[i], xx);
  return bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<triad>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %r14
  movapd %xmm0,%xmm2
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  cs nopw 0x0(%rax,%rax,1)
L1:
  movsd  (%r14,%rbx,8),%xmm0
  movsd  0x0(%r13,%rbx,8),%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <triad_base@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L1
  add    $0x10,%rsp
  mov    $0x18,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L10:
  mov    $0x18,%eax
  ret
```

assistant: ```c
int triad(int len, double xx, double *a, double *b, double *c) {
  int i, bytes = 24;
  for (i = 0; i < len; i++)
    a[i] = triad_base(b[i], c[i], xx);
  return bytes;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<triad>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %r14
  movapd %xmm0,%xmm2
  mov    %rdx,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  cs nopw 0x0(%rax,%rax,1)
L12:
  movsd  (%r14,%rbx,8),%xmm0
  movsd  0x0(%r13,%rbx,8),%xmm1
  movsd  %xmm2,0x8(%rsp)
  call   <triad_base@plt>
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm0,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L12
  add    $0x10,%rsp
  mov    $0x18,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L11:
  mov    $0x18,%eax
  ret
```

assistant: ```c
int triad(int len, double xx, double *a, double *b, double *c) {
  int i, bytes = 24;
  for (i = 0; i < len; i++)
    a[i] = triad_base(b[i], c[i], xx);
  return bytes;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ratval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  mov    %esi,-0x34(%rbp)
  mov    %edx,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x34(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L16:
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x28(%rbp),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0x0,-0x14(%rbp)
  jns    L16
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x38(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L10
L35:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  subl   $0x1,-0x14(%rbp)
L10:
  mov    -0x34(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L35
  movsd  -0x10(%rbp),%xmm1
  movsd  D2(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: f64

tool: D2: 1

assistant: ```c
double ratval(double x, double cof[], int mm, int kk) {
  int j;
  double sumd, sumn;
  for (sumn = cof[mm], j = mm - 1; j >= 0; j--)
    sumn = sumn * x + cof[j];
  for (sumd = 0.0, j = mm + kk; j >= mm + 1; j--)
    sumd = (sumd + cof[j]) * x;
  return sumn / (1.0 + sumd);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ratval>:
  endbr64
  movapd %xmm0,%xmm2
  mov    %rdi,%rcx
  mov    %edx,%edi
  movslq %esi,%rax
  movsd  (%rcx,%rax,8),%xmm0
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L31
  cltq
L48:
  mulsd  %xmm2,%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L48
L31:
  lea    (%rsi,%rdi,1),%eax
  cmp    %eax,%esi
  jge    L29
  cltq
  lea    0x0(,%rax,8),%rsi
  lea    (%rcx,%rsi,1),%rax
  lea    -0x8(%rcx,%rsi,1),%rdx
  lea    -0x1(%rdi),%ecx
  shl    $0x3,%rcx
  sub    %rcx,%rdx
  pxor   %xmm1,%xmm1
L2:
  addsd  (%rax),%xmm1
  mulsd  %xmm2,%xmm1
  sub    $0x8,%rax
  cmp    %rdx,%rax
  jne    L2
L35:
  addsd  D3(%rip),%xmm1
  divsd  %xmm1,%xmm0
  ret
L29:
  pxor   %xmm1,%xmm1
  jmp    L35
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: f64

tool: D3: 1

assistant: ```c
double ratval(double x, double cof[], int mm, int kk) {
  int j;
  double sumd, sumn;
  for (sumn = cof[mm], j = mm - 1; j >= 0; j--)
    sumn = sumn * x + cof[j];
  for (sumd = 0.0, j = mm + kk; j >= mm + 1; j--)
    sumd = (sumd + cof[j]) * x;
  return sumn / (1.0 + sumd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ratval>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%rax
  movapd %xmm0,%xmm2
  mov    %edx,%edi
  movsd  (%rcx,%rax,8),%xmm0
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L39
  cltq
  xchg   %ax,%ax
L20:
  mulsd  %xmm2,%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L20
L39:
  lea    (%rsi,%rdi,1),%eax
  cmp    %eax,%esi
  jge    L7
  cltq
  pxor   %xmm1,%xmm1
  lea    0x0(,%rax,8),%rsi
  lea    -0x8(%rcx,%rsi,1),%rdx
  lea    (%rcx,%rsi,1),%rax
  lea    -0x1(%rdi),%ecx
  shl    $0x3,%rcx
  sub    %rcx,%rdx
  nopl   0x0(%rax)
L37:
  addsd  (%rax),%xmm1
  sub    $0x8,%rax
  mulsd  %xmm2,%xmm1
  cmp    %rax,%rdx
  jne    L37
  addsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: f64

tool: D4: 1

assistant: ```c
double ratval(double x, double cof[], int mm, int kk) {
  int j;
  double sumd, sumn;
  for (sumn = cof[mm], j = mm - 1; j >= 0; j--)
    sumn = sumn * x + cof[j];
  for (sumd = 0.0, j = mm + kk; j >= mm + 1; j--)
    sumd = (sumd + cof[j]) * x;
  return sumn / (1.0 + sumd);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ratval>:
  endbr64
  mov    %rdi,%rcx
  movslq %esi,%rax
  movapd %xmm0,%xmm2
  mov    %edx,%edi
  movsd  (%rcx,%rax,8),%xmm0
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L17
  cltq
  xchg   %ax,%ax
L15:
  mulsd  %xmm2,%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L15
L17:
  lea    (%rsi,%rdi,1),%eax
  cmp    %eax,%esi
  jge    L37
  cltq
  pxor   %xmm1,%xmm1
  lea    0x0(,%rax,8),%rsi
  lea    -0x8(%rcx,%rsi,1),%rdx
  lea    (%rcx,%rsi,1),%rax
  lea    -0x1(%rdi),%ecx
  shl    $0x3,%rcx
  sub    %rcx,%rdx
  nopl   0x0(%rax)
L7:
  addsd  (%rax),%xmm1
  sub    $0x8,%rax
  mulsd  %xmm2,%xmm1
  cmp    %rax,%rdx
  jne    L7
  addsd  D5(%rip),%xmm1
  divsd  %xmm1,%xmm0
L37:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type: f64

tool: D5: 1

assistant: ```c
double ratval(double x, double cof[], int mm, int kk) {
  int j;
  double sumd, sumn;
  for (sumn = cof[mm], j = mm - 1; j >= 0; j--)
    sumn = sumn * x + cof[j];
  for (sumd = 0.0, j = mm + kk; j >= mm + 1; j--)
    sumd = (sumd + cof[j]) * x;
  return sumn / (1.0 + sumd);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L11
  mov    $0x0,%eax
  jmp    L35
L11:
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L23
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D10
type_infered: string

tool: D12: %s 

tool: D10: %s

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    return 0;
  }
  for (int i = 1; i < argc - 1; i++) {
    printf("%s ", argv[i]);
  }
  printf("%s", argv[argc - 1]);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  je     L7
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r14
  cmp    $0x2,%edi
  jle    L21
  lea    0x8(%rsi),%rbx
  lea    -0x3(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r13
  lea    D19(%rip),%r12
L0:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L0
L21:
  movslq %ebp,%rbp
  mov    -0x8(%r14,%rbp,8),%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    $0x0,%eax
  ret
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D8
data_type: string

tool: D19: %s 

tool: D8: %s

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    return 0;
  }
  for (int i = 1; i < argc - 1; i++) {
    printf("%s ", argv[i]);
  }
  printf("%s", argv[argc - 1]);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  cmp    $0x1,%ebp
  je     L3
  mov    %rsi,%r14
  cmp    $0x2,%ebp
  jle    L19
  lea    -0x3(%rbp),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  lea    D9(%rip),%r12
  nop
L2:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L2
L19:
  mov    -0x8(%r14,%rbp,8),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D9: %s 

tool: D0: %s

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    return 0;
  }
  for (int i = 1; i < argc - 1; i++) {
    printf("%s ", argv[i]);
  }
  printf("%s", argv[argc - 1]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  cmp    $0x1,%ebp
  je     L22
  mov    %rsi,%r14
  cmp    $0x2,%ebp
  jle    L15
  lea    -0x3(%rbp),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r13
  lea    D6(%rip),%r12
  nop
L23:
  mov    (%rbx),%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L23
L15:
  mov    -0x8(%r14,%rbp,8),%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L22:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D5
type_guessed: string

tool: D6: %s 

tool: D5: %s

assistant: ```c
int main(int argc, char **argv) {
  if (argc == 1) {
    return 0;
  }
  for (int i = 1; i < argc - 1; i++) {
    printf("%s ", argv[i]);
  }
  printf("%s", argv[argc - 1]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: %d

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  i = is_prime(num);
  printf("%d", i);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: %d

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  i = is_prime(num);
  printf("%d", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_guessed: string

tool: D0: %d

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  i = is_prime(num);
  printf("%d", i);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D3: %d

assistant: ```c
int main() {
  int num, i;
  scanf("%d", &num);
  i = is_prime(num);
  printf("%d", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_128>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  lea    D66(%rip),%r8
  lea    D86(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <print_bytes_sep@plt>
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  lea    D66(%rip),%r8
  lea    D86(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <print_bytes_sep@plt>
  mov    -0x10(%rbp),%rax
  add    $0x20,%rax
  lea    D66(%rip),%r8
  lea    D86(%rip),%rdx
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    %rax,%rsi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <print_bytes_sep@plt>
  mov    -0x10(%rbp),%rax
  lea    0x30(%rax),%rsi
  mov    -0x18(%rbp),%rax
  lea    D66(%rip),%r8
  mov    %rax,%rcx
  mov    $0x4,%edx
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <print_bytes_sep@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D66
datatype: string
name: retrieve_data
arguments: label: D86
datatype: string

tool: 

tool: D86: _

assistant: ```c
void print_128(const char m[], const uint8_t a[16], const char m2[]) {
  print_bytes_sep(m, a, 4, "_", "");
  print_bytes_sep("", a + 4, 4, "_", "");
  print_bytes_sep("", a + 8, 4, "_", "");
  print_bytes_sep("", a + 12, 4, m2, "");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_128>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  lea    D24(%rip),%r8
  lea    D20(%rip),%r13
  mov    %r13,%rcx
  mov    $0x4,%edx
  call   <print_bytes_sep@plt>
  lea    0x10(%rbx),%rsi
  lea    D24(%rip),%r8
  mov    %r13,%rcx
  mov    $0x4,%edx
  mov    %r8,%rbp
  mov    %r8,%rdi
  call   <print_bytes_sep@plt>
  lea    0x20(%rbx),%rsi
  mov    %rbp,%r8
  mov    %r13,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <print_bytes_sep@plt>
  lea    0x30(%rbx),%rsi
  mov    %rbp,%r8
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <print_bytes_sep@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D24
data_type: string
name: unpack_data
arguments: label: D20
data_type: string

tool: 

tool: D20: _

assistant: ```c
void print_128(const char m[], const uint8_t a[16], const char m2[]) {
  print_bytes_sep(m, a, 4, "_", "");
  print_bytes_sep("", a + 4, 4, "_", "");
  print_bytes_sep("", a + 8, 4, "_", "");
  print_bytes_sep("", a + 12, 4, m2, "");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_128>:
  endbr64
  push   %r13
  lea    D29(%rip),%r13
  lea    D6(%rip),%r8
  push   %r12
  mov    %r13,%rcx
  mov    %rdx,%r12
  mov    $0x4,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <print_bytes_sep@plt>
  lea    D6(%rip),%r8
  lea    0x10(%rbx),%rsi
  mov    %r13,%rcx
  mov    %r8,%rbp
  mov    %r8,%rdi
  mov    $0x4,%edx
  call   <print_bytes_sep@plt>
  lea    0x20(%rbx),%rsi
  mov    %rbp,%r8
  mov    %r13,%rcx
  mov    %rbp,%rdi
  mov    $0x4,%edx
  call   <print_bytes_sep@plt>
  add    $0x8,%rsp
  lea    0x30(%rbx),%rsi
  mov    %rbp,%r8
  pop    %rbx
  mov    %r12,%rcx
  mov    %rbp,%rdi
  mov    $0x4,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <print_bytes_sep@plt>
```

tool_calls: name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D6
data_type: string

tool: D29: _

tool: 

assistant: ```c
void print_128(const char m[], const uint8_t a[16], const char m2[]) {
  print_bytes_sep(m, a, 4, "_", "");
  print_bytes_sep("", a + 4, 4, "_", "");
  print_bytes_sep("", a + 8, 4, "_", "");
  print_bytes_sep("", a + 12, 4, m2, "");
}
```