user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x3a0,%rsp
  lea    D41(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x1398(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbx
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L179
  lea    D40(%rip),%r14
  lea    D8(%rip),%r13
  lea    D24(%rip),%r12
  lea    D26(%rip),%rbp
  jmp    L202
  nopl   0x0(%rax)
L208:
  mov    %rbp,%rdi
  call   <printf@plt>
L104:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L179
L202:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmpb   $0x68,0x10(%rsp)
  jne    L17
  cmpb   $0x61,0x11(%rsp)
  jne    L17
  cmpb   $0x63,0x12(%rsp)
  jne    L17
  cmpb   $0x6b,0x13(%rsp)
  jne    L17
  cmpb   $0x65,0x14(%rsp)
  jne    L17
  cmpb   $0x72,0x15(%rsp)
  jne    L17
  cmpb   $0x72,0x16(%rsp)
  jne    L17
  cmpb   $0x61,0x17(%rsp)
  jne    L17
  cmpb   $0x6e,0x18(%rsp)
  jne    L17
  lea    -0x1(%rax),%edx
  xor    %ecx,%ecx
  cmpb   $0x6b,0x19(%rsp)
  movslq %edx,%rdx
  setne  %cl
  cmpb   $0x6b,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x2(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x6e,0x10(%rsp,%rdx,1)
  jne    L254
L159:
  lea    -0x3(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x61,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x4(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x72,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x5(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x72,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x6(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x65,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x7(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x6b,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x8(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x63,0x10(%rsp,%rdx,1)
  jne    L254
  lea    -0x9(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x61,0x10(%rsp,%rdx,1)
  jne    L254
  sub    $0xa,%eax
  cltq
  cmpb   $0x68,0x10(%rsp,%rax,1)
  jne    L254
  test   %ecx,%ecx
  je     L208
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L202
  nopl   0x0(%rax)
L179:
  mov    0x1398(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L214
  add    $0x13a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L17:
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmpb   $0x6b,0x10(%rsp,%rdx,1)
  jne    L150
  lea    -0x2(%rax),%edx
  mov    $0x1,%ecx
  movslq %edx,%rdx
  cmpb   $0x6e,0x10(%rsp,%rdx,1)
  je     L159
  nopl   0x0(%rax,%rax,1)
L150:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L104
  nopl   (%rax)
L254:
  cmp    $0x1,%ecx
  je     L150
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L104
L214:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D41
type_guessed: string
name: read_data
arguments: data_tag: D40
type_guessed: string
name: read_data
arguments: data_tag: D8
type_guessed: string
name: read_data
arguments: data_tag: D24
type_guessed: string
name: read_data
arguments: data_tag: D26
type_guessed: string

tool: D41: %d

tool: D40: -1


tool: D8: 1


tool: D24: 2


tool: D26: 0


assistant: ```c
int main() {
  int i, j, k, t, n, flag1, flag2;
  char str[5000];
  char str1[10] = {'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k'};
  scanf("%d", &t);
  gets(str);
  while (t--) {
    flag1 = 0;
    flag2 = 0;
    gets(str);
    n = strlen(str);
    for (i = 0; i < 10; i++) {
      if (str[i] == str1[i]) {
      } else {
        flag1 = 1;
        break;
      }
    }
    for (i = n - 1, j = 9; i >= (n - 10), j >= 0; i--, j--) {
      if (str[i] == str1[j]) {
      } else {
        flag2 = 1;
        break;
      }
    }
    if (flag1 == 0 && flag2 == 0)
      printf("0\n");
    else if (flag1 == 0 && flag2 == 1)
      printf("1\n");
    else if (flag1 == 1 && flag2 == 0)
      printf("2\n");
    else
      printf("-1\n");
  }
  return 0;
}
```