user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x170,%rsp
  mov    %edi,-0x164(%rbp)
  mov    %rsi,-0x170(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xa5f0,-0x110(%rbp)
  movq   $0x7e3c,-0x108(%rbp)
  movq   $0x50ec,-0x100(%rbp)
  movq   $0xaf73,-0xf8(%rbp)
  movq   $0x7e3c,-0xf0(%rbp)
  movq   $0xa5f0,-0xe8(%rbp)
  movq   $0xec50,-0xe0(%rbp)
  movq   $0x73af,-0xd8(%rbp)
  movq   $0x3ca5,-0xd0(%rbp)
  movq   $0xf07e,-0xc8(%rbp)
  movq   $0xc50e,-0xc0(%rbp)
  movq   $0x3af7,-0xb8(%rbp)
  movq   $0x5a0f,-0xb0(%rbp)
  movq   $0xe7c3,-0xa8(%rbp)
  movq   $0xaf73,-0xa0(%rbp)
  movq   $0x50ec,-0x98(%rbp)
  movq   $0x0,-0x90(%rbp)
  movq   $0x1,-0x88(%rbp)
  movq   $0x1,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x1,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x1,-0x58(%rbp)
  movq   $0x2,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x2,-0x38(%rbp)
  movq   $0x1,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    $0xa5f07e3c,%eax
  mov    %rax,-0x150(%rbp)
  movq   $0x7e3ca5f0,-0x148(%rbp)
  movq   $0x3ca5f07e,-0x140(%rbp)
  movq   $0x5a0fe7c3,-0x138(%rbp)
  mov    $0xffff0000,%eax
  mov    %rax,-0x130(%rbp)
  movq   $0xffff,-0x128(%rbp)
  movq   $0xf0f0f0f,-0x120(%rbp)
  mov    $0xf0f0f0f0,%eax
  mov    %rax,-0x118(%rbp)
  movl   $0x0,-0x158(%rbp)
  jmp    L40
L3:
  movl   $0x0,-0x154(%rbp)
  jmp    L5
L12:
  mov    -0x154(%rbp),%eax
  cltq
  mov    -0x130(%rbp,%rax,8),%rdx
  mov    -0x158(%rbp),%eax
  cltq
  mov    -0x150(%rbp,%rax,8),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <do_cntlzdm@plt>
  mov    -0x154(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x158(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    -0x90(%rbp,%rdx,8),%rdx
  cmp    %rdx,%rax
  je     L34
  mov    $0x0,%eax
  call   <abort@plt>
L34:
  addl   $0x1,-0x154(%rbp)
L5:
  cmpl   $0x3,-0x154(%rbp)
  jle    L12
  addl   $0x1,-0x158(%rbp)
L40:
  cmpl   $0x3,-0x158(%rbp)
  jle    L3
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L55
  call   <__stack_chk_fail@plt>
L55:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long long int sources[4], masks[4];
  unsigned long long int intermediates[4][4] = {
      {0x0000a5f0ll, 0x00007e3cll, 0x000050ecll, 0x0000af73ll},
      {0x00007e3cll, 0x0000a5f0ll, 0x0000ec50ll, 0x000073afll},
      {0x00003ca5ll, 0x0000f07ell, 0x0000c50ell, 0x00003af7ll},
      {0x00005a0fll, 0x0000e7c3ll, 0x0000af73ll, 0x000050ecll},
  };
  unsigned long long int results[4][4] = {
      {0, 1, 1, 0},
      {1, 0, 0, 1},
      {2, 0, 0, 2},
      {1, 0, 0, 1},
  };
  sources[0] = 0xa5f07e3cll;
  sources[1] = 0x7e3ca5f0ll;
  sources[2] = 0x3ca5f07ell;
  sources[3] = 0x5a0fe7c3ll;
  masks[0] = 0xffff0000ll;
  masks[1] = 0x0000ffffll;
  masks[2] = 0x0f0f0f0fll;
  masks[3] = 0xf0f0f0f0ll;
  unsigned long long int result;
  for (int i = 0; i < 4; i++) {
    for (int j = 0; j < 4; j++) {
      if (do_cntlzdm(sources[i], masks[j]) != results[i][j])
        abort();
    }
  }
  return 0;
}
```