ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<t_one>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3039,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x3337,%eax
  lea    0xd(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %ax,0xa(%rsp)
  movabs $0x3837363534333231,%rax
  movl   $0x61626366,0x6(%rsp)
  movb   $0x0,0xc(%rsp)
  mov    %rax,0xd(%rsp)
  mov    %dx,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <my_strcspn@plt>
  lea    D7(%rip),%rdi
  lea    0x1(%rax),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D7
data_type: string

tool: D7: The first number in str is at position %d. 


assistant: ```c
void t_one() {
  char str[] = "fcba73";
  char keys[] = "1234567890";
  int i;
  i = my_strcspn(str, keys);
  printf("The first number in str is at position %d. \n", i + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<t_one>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x3039,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x3337,%eax
  lea    0xd(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %ax,0xa(%rsp)
  movabs $0x3837363534333231,%rax
  movl   $0x61626366,0x6(%rsp)
  movb   $0x0,0xc(%rsp)
  mov    %rax,0xd(%rsp)
  mov    %dx,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  call   <my_strcspn@plt>
  lea    D2(%rip),%rdi
  lea    0x1(%rax),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string

tool: D2: The first number in str is at position %d. 


assistant: ```c
void t_one() {
  char str[] = "fcba73";
  char keys[] = "1234567890";
  int i;
  i = my_strcspn(str, keys);
  printf("The first number in str is at position %d. \n", i + 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<HEX64_writeHEX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L16:
  movzbl -0x28(%rbp),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_get_hex_char@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  movzbl -0x28(%rbp),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%edx
  and    $0xf,%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <_get_hex_char@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L16
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  leave
  ret
```

assistant: ```c
int HEX64_writeHEX(char *str, unsigned char *buffer, int len, unsigned char caps) {
  int k;
  for (k = 0; k < len; k++) {
    *str = _get_hex_char(buffer[k] >> 4, caps);
    str++;
    *str = _get_hex_char(buffer[k] & 0x0f, caps);
    str++;
  }
  *str = '\0';
  return k * 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<HEX64_writeHEX>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %edx,%edx
  jle    L26
  mov    %edx,%r14d
  mov    %rsi,%rbp
  mov    %edx,%eax
  lea    (%rdi,%rax,2),%r13
  movzbl %cl,%r12d
L7:
  movzbl 0x0(%rbp),%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  mov    %r12d,%esi
  call   <_get_hex_char@plt>
  mov    %al,(%rbx)
  movzbl 0x0(%rbp),%edi
  and    $0xf,%edi
  mov    %r12d,%esi
  call   <_get_hex_char@plt>
  mov    %al,0x1(%rbx)
  add    $0x2,%rbx
  add    $0x1,%rbp
  cmp    %rbx,%r13
  jne    L7
L22:
  movb   $0x0,(%rbx)
  lea    (%r14,%r14,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    $0x0,%r14d
  jmp    L22
```

assistant: ```c
int HEX64_writeHEX(char *str, unsigned char *buffer, int len, unsigned char caps) {
  int k;
  for (k = 0; k < len; k++) {
    *str = _get_hex_char(buffer[k] >> 4, caps);
    str++;
    *str = _get_hex_char(buffer[k] & 0x0f, caps);
    str++;
  }
  *str = '\0';
  return k * 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<HEX64_writeHEX>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %edx,%edx
  jle    L10
  movslq %edx,%rax
  mov    %edx,%r13d
  movzbl %cl,%ebp
  mov    %rsi,%r14
  lea    (%rdi,%rax,2),%r12
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%r14),%edi
  mov    %ebp,%esi
  add    $0x2,%rbx
  add    $0x1,%r14
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <_get_hex_char@plt>
  mov    %ebp,%esi
  mov    %al,-0x2(%rbx)
  movzbl -0x1(%r14),%edi
  and    $0xf,%edi
  call   <_get_hex_char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r12
  jne    L3
  lea    0x0(%r13,%r13,1),%eax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L10:
  movb   $0x0,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int HEX64_writeHEX(char *str, unsigned char *buffer, int len, unsigned char caps) {
  int k;
  for (k = 0; k < len; k++) {
    *str = _get_hex_char(buffer[k] >> 4, caps);
    str++;
    *str = _get_hex_char(buffer[k] & 0x0f, caps);
    str++;
  }
  *str = '\0';
  return k * 2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HEX64_writeHEX>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %edx,%edx
  jle    L6
  movslq %edx,%rax
  mov    %edx,%r13d
  movzbl %cl,%ebp
  mov    %rsi,%r14
  lea    (%rdi,%rax,2),%r12
  nopl   0x0(%rax,%rax,1)
L3:
  movzbl (%r14),%edi
  mov    %ebp,%esi
  add    $0x2,%rbx
  add    $0x1,%r14
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <_get_hex_char@plt>
  mov    %ebp,%esi
  mov    %al,-0x2(%rbx)
  movzbl -0x1(%r14),%edi
  and    $0xf,%edi
  call   <_get_hex_char@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbx,%r12
  jne    L3
  lea    0x0(%r13,%r13,1),%eax
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L6:
  movb   $0x0,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int HEX64_writeHEX(char *str, unsigned char *buffer, int len, unsigned char caps) {
  int k;
  for (k = 0; k < len; k++) {
    *str = _get_hex_char(buffer[k] >> 4, caps);
    str++;
    *str = _get_hex_char(buffer[k] & 0x0f, caps);
    str++;
  }
  *str = '\0';
  return k * 2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<MM_matrix_transpose_r2c>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  lea    0x3(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,0x1c(%rsp)
  cmp    $0x3,%ecx
  jle    L17
  mov    %rdi,%r14
  movslq %edx,%rdx
  shl    $0x2,%rdx
  mov    %rdx,0x20(%rsp)
  mov    %rsi,%rbp
  mov    %eax,%edx
  lea    (%rax,%rax,1),%eax
  cltq
  lea    (%rdi,%rax,4),%r13
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  lea    0x0(%r13,%rdx,1),%r12
  neg    %rax
  shl    $0x3,%rax
  lea    (%r12,%rax,1),%r15
  lea    (%r15,%rdx,1),%rcx
  mov    %rcx,0x28(%rsp)
  add    %rcx,%rdx
  mov    %rdx,0x30(%rsp)
  add    %rdx,%rax
  mov    %rax,0x38(%rsp)
  mov    $0x0,%ebx
L4:
  mov    0x0(%r13,%rbx,4),%esi
  mov    (%r14,%rbx,4),%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,0xc(%rsp)
  mov    (%r12,%rbx,4),%esi
  mov    (%r15,%rbx,4),%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,0x10(%rsp)
  mov    0x28(%rsp),%rcx
  mov    (%rcx,%rbx,4),%esi
  mov    (%r14,%rbx,4),%edi
  call   <_mm_unpackhi_epi32@plt>
  mov    %eax,0x14(%rsp)
  mov    0x30(%rsp),%rdx
  mov    (%rdx,%rbx,4),%esi
  mov    0x38(%rsp),%rcx
  mov    (%rcx,%rbx,4),%edi
  call   <_mm_unpackhi_epi32@plt>
  mov    %eax,0x18(%rsp)
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,0x0(%rbp)
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <_mm_unpackhi_epi32@plt>
  mov    %eax,0x4(%rbp)
  mov    0x18(%rsp),%esi
  mov    0x14(%rsp),%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,0x8(%rbp)
  mov    0x18(%rsp),%esi
  mov    0x14(%rsp),%edi
  call   <_mm_unpackhi_epi32@plt>
  mov    %eax,0xc(%rbp)
  add    $0x1,%rbx
  add    0x20(%rsp),%rbp
  cmp    %ebx,0x1c(%rsp)
  jg     L4
L17:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MM_matrix_transpose_r2c(__m128i *inbuf, __m128i *outbuf, uint32_t rows, uint32_t colums) {
  __m128i block[4];
  uint32_t col = colums / 4;
  uint32_t i;
  for (i = 0; i < col; i++) {
    block[0] = _mm_unpacklo_epi32(inbuf[i], inbuf[i + 2 * col]);
    block[1] = _mm_unpacklo_epi32(inbuf[i + col], inbuf[i + 3 * col]);
    block[2] = _mm_unpackhi_epi32(inbuf[i], inbuf[i + 2 * col]);
    block[3] = _mm_unpackhi_epi32(inbuf[i + col], inbuf[i + 3 * col]);
    outbuf[i * rows + 0] = _mm_unpacklo_epi32(block[0], block[1]);
    outbuf[i * rows + 1] = _mm_unpackhi_epi32(block[0], block[1]);
    outbuf[i * rows + 2] = _mm_unpacklo_epi32(block[2], block[3]);
    outbuf[i * rows + 3] = _mm_unpackhi_epi32(block[2], block[3]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MM_matrix_transpose_r2c>:
  endbr64
  push   %r15
  lea    0x3(%rcx),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x3,%ecx
  jle    L17
  movslq %edx,%rdx
  mov    %rdi,%r13
  mov    %rsi,%rbx
  lea    0x0(,%rdx,4),%rcx
  mov    %eax,%edx
  lea    (%rax,%rax,1),%eax
  cltq
  mov    %rcx,0x38(%rsp)
  lea    (%rdi,%rax,4),%rcx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%r12
  neg    %rax
  lea    (%rcx,%r12,1),%rdx
  shl    $0x3,%rax
  mov    %rdx,0x28(%rsp)
  add    %rax,%rdx
  lea    (%rdx,%r12,1),%rdi
  mov    %rdx,0x18(%rsp)
  mov    %r12,%rdx
  xor    %r12d,%r12d
  add    %rdi,%rdx
  mov    %rdi,0x30(%rsp)
  add    %rdx,%rax
  mov    %rdx,0x20(%rsp)
  mov    %rcx,%rdx
  mov    %rax,0x10(%rsp)
L7:
  mov    (%rdx,%r12,4),%esi
  mov    0x0(%r13,%r12,4),%edi
  mov    %rdx,(%rsp)
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,%ebp
  mov    0x28(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  mov    0x18(%rsp),%rax
  mov    (%rax,%r12,4),%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    0x0(%r13,%r12,4),%edi
  mov    %eax,0x8(%rsp)
  mov    0x30(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  call   <_mm_unpackhi_epi32@plt>
  mov    %eax,%r14d
  mov    0x20(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  mov    0x10(%rsp),%rax
  mov    (%rax,%r12,4),%edi
  add    $0x1,%r12
  call   <_mm_unpackhi_epi32@plt>
  mov    0x8(%rsp),%esi
  mov    %ebp,%edi
  mov    %eax,%r15d
  call   <_mm_unpacklo_epi32@plt>
  mov    0x8(%rsp),%esi
  mov    %ebp,%edi
  mov    %eax,(%rbx)
  call   <_mm_unpackhi_epi32@plt>
  mov    %r15d,%esi
  mov    %r14d,%edi
  mov    %eax,0x4(%rbx)
  call   <_mm_unpacklo_epi32@plt>
  mov    %r15d,%esi
  mov    %r14d,%edi
  mov    %eax,0x8(%rbx)
  call   <_mm_unpackhi_epi32@plt>
  mov    (%rsp),%rdx
  mov    %eax,0xc(%rbx)
  add    0x38(%rsp),%rbx
  cmp    %r12d,0xc(%rsp)
  jg     L7
L17:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MM_matrix_transpose_r2c(__m128i *inbuf, __m128i *outbuf, uint32_t rows, uint32_t colums) {
  __m128i block[4];
  uint32_t col = colums / 4;
  uint32_t i;
  for (i = 0; i < col; i++) {
    block[0] = _mm_unpacklo_epi32(inbuf[i], inbuf[i + 2 * col]);
    block[1] = _mm_unpacklo_epi32(inbuf[i + col], inbuf[i + 3 * col]);
    block[2] = _mm_unpackhi_epi32(inbuf[i], inbuf[i + 2 * col]);
    block[3] = _mm_unpackhi_epi32(inbuf[i + col], inbuf[i + 3 * col]);
    outbuf[i * rows + 0] = _mm_unpacklo_epi32(block[0], block[1]);
    outbuf[i * rows + 1] = _mm_unpackhi_epi32(block[0], block[1]);
    outbuf[i * rows + 2] = _mm_unpacklo_epi32(block[2], block[3]);
    outbuf[i * rows + 3] = _mm_unpackhi_epi32(block[2], block[3]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MM_matrix_transpose_r2c>:
  endbr64
  push   %r15
  lea    0x3(%rcx),%eax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x2,%eax
  mov    %eax,0xc(%rsp)
  cmp    $0x3,%ecx
  jle    L14
  movslq %edx,%rdx
  mov    %rdi,%r13
  mov    %rsi,%rbx
  lea    0x0(,%rdx,4),%rcx
  mov    %eax,%edx
  lea    (%rax,%rax,1),%eax
  cltq
  mov    %rcx,0x38(%rsp)
  lea    (%rdi,%rax,4),%rcx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%r12
  neg    %rax
  lea    (%rcx,%r12,1),%rdx
  shl    $0x3,%rax
  mov    %rdx,0x28(%rsp)
  add    %rax,%rdx
  lea    (%rdx,%r12,1),%rdi
  mov    %rdx,0x18(%rsp)
  mov    %r12,%rdx
  xor    %r12d,%r12d
  add    %rdi,%rdx
  mov    %rdi,0x30(%rsp)
  add    %rdx,%rax
  mov    %rdx,0x20(%rsp)
  mov    %rcx,%rdx
  mov    %rax,0x10(%rsp)
L1:
  mov    (%rdx,%r12,4),%esi
  mov    0x0(%r13,%r12,4),%edi
  mov    %rdx,(%rsp)
  call   <_mm_unpacklo_epi32@plt>
  mov    %eax,%ebp
  mov    0x28(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  mov    0x18(%rsp),%rax
  mov    (%rax,%r12,4),%edi
  call   <_mm_unpacklo_epi32@plt>
  mov    0x0(%r13,%r12,4),%edi
  mov    %eax,0x8(%rsp)
  mov    0x30(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  call   <_mm_unpackhi_epi32@plt>
  mov    %eax,%r14d
  mov    0x20(%rsp),%rax
  mov    (%rax,%r12,4),%esi
  mov    0x10(%rsp),%rax
  mov    (%rax,%r12,4),%edi
  add    $0x1,%r12
  call   <_mm_unpackhi_epi32@plt>
  mov    0x8(%rsp),%esi
  mov    %ebp,%edi
  mov    %eax,%r15d
  call   <_mm_unpacklo_epi32@plt>
  mov    0x8(%rsp),%esi
  mov    %ebp,%edi
  mov    %eax,(%rbx)
  call   <_mm_unpackhi_epi32@plt>
  mov    %r15d,%esi
  mov    %r14d,%edi
  mov    %eax,0x4(%rbx)
  call   <_mm_unpacklo_epi32@plt>
  mov    %r15d,%esi
  mov    %r14d,%edi
  mov    %eax,0x8(%rbx)
  call   <_mm_unpackhi_epi32@plt>
  mov    (%rsp),%rdx
  mov    %eax,0xc(%rbx)
  add    0x38(%rsp),%rbx
  cmp    %r12d,0xc(%rsp)
  jg     L1
L14:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void MM_matrix_transpose_r2c(__m128i *inbuf, __m128i *outbuf, uint32_t rows, uint32_t colums) {
  __m128i block[4];
  uint32_t col = colums / 4;
  uint32_t i;
  for (i = 0; i < col; i++) {
    block[0] = _mm_unpacklo_epi32(inbuf[i], inbuf[i + 2 * col]);
    block[1] = _mm_unpacklo_epi32(inbuf[i + col], inbuf[i + 3 * col]);
    block[2] = _mm_unpackhi_epi32(inbuf[i], inbuf[i + 2 * col]);
    block[3] = _mm_unpackhi_epi32(inbuf[i + col], inbuf[i + 3 * col]);
    outbuf[i * rows + 0] = _mm_unpacklo_epi32(block[0], block[1]);
    outbuf[i * rows + 1] = _mm_unpackhi_epi32(block[0], block[1]);
    outbuf[i * rows + 2] = _mm_unpacklo_epi32(block[2], block[3]);
    outbuf[i * rows + 3] = _mm_unpackhi_epi32(block[2], block[3]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiply_naive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L27:
  movl   $0x0,-0x8(%rbp)
  jmp    L35
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L42:
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L42
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L30
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L27
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void multiply_naive(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < n; k++)
        c[i * n + j] += a[i * n + k] * b[k * n + j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply_naive>:
  endbr64
  test   %ecx,%ecx
  jle    L16
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r11d
  movslq %ecx,%rsi
  shl    $0x3,%rsi
  mov    %rdi,%r10
  lea    -0x1(%rcx),%edx
  lea    0x8(%rdi,%rdx,8),%rdi
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L30
L1:
  lea    0x1(%r12),%eax
  add    %rsi,%r10
  add    %rsi,%rdi
  add    %rsi,%rbx
  cmp    %r9d,%r12d
  je     L56
  mov    %eax,%r12d
L30:
  mov    %rbp,%r8
  mov    %rbx,%rcx
  mov    %r13d,%r9d
L33:
  mov    %r8,%rdx
  mov    %r10,%rax
L45:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  add    %rsi,%rdx
  cmp    %rdi,%rax
  jne    L45
  lea    0x1(%r9),%eax
  add    $0x8,%r8
  add    $0x8,%rcx
  cmp    %eax,%r11d
  je     L1
  mov    %eax,%r9d
  jmp    L33
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  ret
```

assistant: ```c
void multiply_naive(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < n; k++)
        c[i * n + j] += a[i * n + k] * b[k * n + j];
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply_naive>:
  endbr64
  test   %ecx,%ecx
  jle    L20
  push   %r12
  lea    -0x1(%rcx),%eax
  mov    %rdi,%r10
  mov    %ecx,%r11d
  push   %rbp
  mov    %rsi,%rbp
  movslq %ecx,%rsi
  lea    0x8(%rdi,%rax,8),%rdi
  push   %rbx
  shl    $0x3,%rsi
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L11:
  mov    %rbp,%r8
  mov    %rbx,%rcx
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L10:
  movsd  (%rcx),%xmm1
  mov    %r8,%rdx
  mov    %r10,%rax
  nopw   0x0(%rax,%rax,1)
L47:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rdi
  jne    L47
  lea    0x1(%r9),%eax
  add    $0x8,%rcx
  add    $0x8,%r8
  cmp    %eax,%r11d
  je     L39
  mov    %eax,%r9d
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L39:
  lea    0x1(%r12),%eax
  add    %rsi,%r10
  add    %rsi,%rdi
  add    %rsi,%rbx
  cmp    %r9d,%r12d
  je     L59
  mov    %eax,%r12d
  jmp    L11
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  ret
```

assistant: ```c
void multiply_naive(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < n; k++)
        c[i * n + j] += a[i * n + k] * b[k * n + j];
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply_naive>:
  endbr64
  test   %ecx,%ecx
  jle    L58
  push   %r14
  mov    %rdi,%r10
  movslq %ecx,%r14
  lea    -0x1(%rcx),%eax
  push   %r13
  mov    %ecx,%r11d
  mov    %rdx,%r13
  lea    0x0(,%r14,8),%rdi
  push   %r12
  mov    %rsi,%r12
  lea    0x8(%r10,%rax,8),%rsi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L49:
  lea    0x0(%r13,%rbx,8),%rcx
  mov    %r12,%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L26:
  movsd  (%rcx),%xmm1
  mov    %r8,%rdx
  mov    %r10,%rax
  nopw   0x0(%rax,%rax,1)
L32:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L32
  lea    0x1(%r9),%eax
  add    $0x8,%rcx
  add    $0x8,%r8
  cmp    %eax,%r11d
  je     L42
  mov    %eax,%r9d
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L42:
  lea    0x1(%rbp),%eax
  add    %rdi,%r10
  add    %rdi,%rsi
  add    %r14,%rbx
  cmp    %r9d,%ebp
  je     L25
  mov    %eax,%ebp
  jmp    L49
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  ret
```

assistant: ```c
void multiply_naive(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
      for (k = 0; k < n; k++)
        c[i * n + j] += a[i * n + k] * b[k * n + j];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<open_dump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D10
datatype: string

tool: D14: r+

tool: D10: Failed to open : %s


assistant: ```c
FILE *open_dump(char *path) {
  FILE *file = fopen(path, "r+");
  if (file == NULL) {
    printf("Failed to open : %s\r\n", path);
  }
  return file;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<open_dump>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D7(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L4
L8:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string

tool: D7: r+

tool: D17: Failed to open : %s


assistant: ```c
FILE *open_dump(char *path) {
  FILE *file = fopen(path, "r+");
  if (file == NULL) {
    printf("Failed to open : %s\r\n", path);
  }
  return file;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<open_dump>:
  endbr64
  push   %r12
  lea    D19(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D19: r+

tool: D4: Failed to open : %s


assistant: ```c
FILE *open_dump(char *path) {
  FILE *file = fopen(path, "r+");
  if (file == NULL) {
    printf("Failed to open : %s\r\n", path);
  }
  return file;
}
```