ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_char>:
  endbr64
  mov    D29(%rip),%eax
  push   %rbx
  mov    %rdi,%rbx
  test   %eax,%eax
  jne    L51
  jmp    L36
  nopl   0x0(%rax)
L62:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  jne    L65
L36:
  mov    %rbx,%rdi
  call   <getc@plt>
L51:
  cmp    $0x5c,%eax
  je     L62
  cmp    $0x23,%eax
  je     L63
L33:
  lea    -0x9(%rax),%edx
  cmp    $0x1,%edx
  jbe    L17
  pop    %rbx
  ret
  nopl   0x0(%rax)
L30:
  mov    D11(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L33
L63:
  mov    %rbx,%rdi
  call   <getc@plt>
  cmp    $0xa,%eax
  jne    L30
L17:
  mov    $0x20,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  mov    %eax,D23(%rip)
  pop    %rbx
  mov    $0x5c,%eax
  ret
```

assistant: ```c
int read_char(FILE *rfile) {
  static int last;
  int n;
  n = last ? last : getc(rfile);
  while (n == '\\') {
    n = getc(rfile);
    if (n == '\n')
      n = getc(rfile);
    else {
      last = n;
      return (int)'\\';
    }
  }
  if (n == '#')
    while ((n = getc(rfile)) != '\n' && n != EOF)
      ;
  if (n == '\n' || n == '\t')
    return (' ');
  return (n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0xa(%rbp),%eax
  sub    $0x61,%eax
  mov    %al,-0xa(%rbp)
  movzbl -0xa(%rbp),%eax
  mov    %eax,%edx
  mov    $0x7a,%eax
  sub    %edx,%eax
  mov    %al,-0x9(%rbp)
  movsbl -0x9(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: %c

assistant: ```c
int main() {
  char a, b;
  scanf("%c", &a);
  a = a - 'a';
  b = 'z' - a;
  printf("%c", b);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  sub    $0x61,%eax
  mov    %al,0x7(%rsp)
  mov    $0x7a,%esi
  sub    %eax,%esi
  movsbl %sil,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: %c

assistant: ```c
int main() {
  char a, b;
  scanf("%c", &a);
  a = a - 'a';
  b = 'z' - a;
  printf("%c", b);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    $0x7a,%esi
  mov    %rbp,%rdi
  sub    $0x61,%eax
  sub    %eax,%esi
  mov    %al,0x7(%rsp)
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: %c

assistant: ```c
int main() {
  char a, b;
  scanf("%c", &a);
  a = a - 'a';
  b = 'z' - a;
  printf("%c", b);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  mov    $0x7a,%esi
  mov    %rbp,%rdi
  sub    $0x61,%eax
  sub    %eax,%esi
  mov    %al,0x7(%rsp)
  movsbl %sil,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string

tool: D6: %c

assistant: ```c
int main() {
  char a, b;
  scanf("%c", &a);
  a = a - 'a';
  b = 'z' - a;
  printf("%c", b);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L10:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bar@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void foo(int n) {
  int i;
#pragma omp for schedule(guided)
  for (i = 0; i < n; ++i)
    bar(i);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<foo>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L10:
  mov    %ebx,%edi
  call   <bar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void foo(int n) {
  int i;
#pragma omp for schedule(guided)
  for (i = 0; i < n; ++i)
    bar(i);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <bar@plt>
  cmp    %ebx,%ebp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L19:
  ret
```

assistant: ```c
void foo(int n) {
  int i;
#pragma omp for schedule(guided)
  for (i = 0; i < n; ++i)
    bar(i);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  test   %edi,%edi
  jle    L10
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <bar@plt>
  cmp    %ebx,%ebp
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L10:
  ret
```

assistant: ```c
void foo(int n) {
  int i;
#pragma omp for schedule(guided)
  for (i = 0; i < n; ++i)
    bar(i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ILLutil_our_gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L11
  negl   -0x14(%rbp)
L11:
  cmpl   $0x0,-0x18(%rbp)
  jns    L10
  negl   -0x18(%rbp)
L10:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L3
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L3
L21:
  mov    -0x18(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L3:
  cmpl   $0x0,-0x14(%rbp)
  jne    L21
  mov    -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ILLutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ILLutil_our_gcd>:
  endbr64
  mov    %edi,%ecx
  neg    %ecx
  cmovs  %edi,%ecx
  mov    %esi,%eax
  neg    %eax
  cmovs  %esi,%eax
  cmp    %eax,%ecx
  jle    L23
  mov    %ecx,%edx
  mov    %eax,%ecx
  mov    %edx,%eax
L23:
  test   %ecx,%ecx
  jne    L8
  mov    %eax,%ecx
  jmp    L31
L13:
  mov    %edx,%ecx
L8:
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  test   %edx,%edx
  jne    L13
L31:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int ILLutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ILLutil_our_gcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  neg    %r8d
  cmovs  %edi,%r8d
  neg    %eax
  cmovs  %esi,%eax
  cmp    %r8d,%eax
  jge    L7
  mov    %r8d,%edx
  mov    %eax,%r8d
  mov    %edx,%eax
L7:
  test   %r8d,%r8d
  jne    L0
  jmp    L33
  nopl   0x0(%rax)
L38:
  mov    %edx,%r8d
L0:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L38
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ILLutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ILLutil_our_gcd>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%eax
  neg    %r8d
  cmovs  %edi,%r8d
  neg    %eax
  cmovs  %esi,%eax
  cmp    %r8d,%eax
  jge    L5
  mov    %r8d,%edx
  mov    %eax,%r8d
  mov    %edx,%eax
L5:
  test   %r8d,%r8d
  jne    L15
  jmp    L18
  nopl   0x0(%rax)
L22:
  mov    %edx,%r8d
L15:
  cltd
  idiv   %r8d
  mov    %r8d,%eax
  test   %edx,%edx
  jne    L22
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ILLutil_our_gcd(int a, int b) {
  int c;
  if (a < 0)
    a = -a;
  if (b < 0)
    b = -b;
  if (a > b)
    (((c) = (a)), ((a) = (b)), ((b) = (c)));
  while (a) {
    c = b % a;
    b = a;
    a = c;
  }
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ml_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ml_mod(int n1, int n2) {
  int mod, q;
  q = n1 / n2;
  mod = n1 - (n2 * q);
  return mod;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ml_mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int ml_mod(int n1, int n2) {
  int mod, q;
  q = n1 / n2;
  mod = n1 - (n2 * q);
  return mod;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ml_mod>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %edx,%eax
  ret
```

assistant: ```c
int ml_mod(int n1, int n2) {
  int mod, q;
  q = n1 / n2;
  mod = n1 - (n2 * q);
  return mod;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sample_uniform>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  movsd  %xmm0,-0x38(%rbp)
  mov    %rdi,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x48(%rbp),%xmm0
  movsd  D0(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  -0x38(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  mulsd  -0x48(%rbp),%xmm0
  movsd  D0(%rip),%xmm1
  divsd  %xmm1,%xmm0
  addsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm4
  movsd  %xmm4,-0x50(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x58(%rbp)
  mov    $0x0,%eax
  call   <rndu@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  -0x50(%rbp),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm1
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <reflect@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_infered: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
double sample_uniform(double x, double range[2], double finetune) {
  double w[2], xnew;
  w[0] = x - (range[1] - range[0]) * finetune / 2;
  w[1] = x + (range[1] - range[0]) * finetune / 2;
  xnew = ((w[0]) + ((w[1]) - (w[0])) * rndu());
  xnew = reflect(xnew, range[0], range[1]);
  return (xnew);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sample_uniform>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  movsd  0x8(%rdi),%xmm2
  subsd  (%rdi),%xmm2
  mulsd  %xmm2,%xmm1
  mulsd  D0(%rip),%xmm1
  movapd %xmm0,%xmm3
  subsd  %xmm1,%xmm3
  addsd  %xmm0,%xmm1
  movsd  %xmm3,(%rsp)
  subsd  %xmm3,%xmm1
  movsd  %xmm1,0x8(%rsp)
  mov    $0x0,%eax
  call   <rndu@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  movsd  0x8(%rbx),%xmm2
  movsd  (%rbx),%xmm1
  mov    $0x3,%eax
  call   <reflect@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double sample_uniform(double x, double range[2], double finetune) {
  double w[2], xnew;
  w[0] = x - (range[1] - range[0]) * finetune / 2;
  w[1] = x + (range[1] - range[0]) * finetune / 2;
  xnew = ((w[0]) + ((w[1]) - (w[0])) * rndu());
  xnew = reflect(xnew, range[0], range[1]);
  return (xnew);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sample_uniform>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  0x8(%rdi),%xmm2
  subsd  (%rdi),%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  D8(%rip),%xmm1
  subsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <rndu@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  movsd  (%rbx),%xmm1
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  mov    $0x3,%eax
  addsd  %xmm2,%xmm0
  movsd  0x8(%rbx),%xmm2
  call   <reflect@plt>
  pxor   %xmm0,%xmm0
  add    $0x10,%rsp
  cvtsi2sd %eax,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double sample_uniform(double x, double range[2], double finetune) {
  double w[2], xnew;
  w[0] = x - (range[1] - range[0]) * finetune / 2;
  w[1] = x + (range[1] - range[0]) * finetune / 2;
  xnew = ((w[0]) + ((w[1]) - (w[0])) * rndu());
  xnew = reflect(xnew, range[0], range[1]);
  return (xnew);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sample_uniform>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  movsd  0x8(%rdi),%xmm2
  subsd  (%rdi),%xmm2
  mulsd  %xmm2,%xmm1
  movapd %xmm0,%xmm2
  mulsd  D2(%rip),%xmm1
  subsd  %xmm1,%xmm2
  addsd  %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <rndu@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  movsd  (%rbx),%xmm1
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  mov    $0x3,%eax
  addsd  %xmm2,%xmm0
  movsd  0x8(%rbx),%xmm2
  call   <reflect@plt>
  pxor   %xmm0,%xmm0
  add    $0x10,%rsp
  cvtsi2sd %eax,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double sample_uniform(double x, double range[2], double finetune) {
  double w[2], xnew;
  w[0] = x - (range[1] - range[0]) * finetune / 2;
  w[1] = x + (range[1] - range[0]) * finetune / 2;
  xnew = ((w[0]) + ((w[1]) - (w[0])) * rndu());
  xnew = reflect(xnew, range[0], range[1]);
  return (xnew);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getNumOfSubstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L28:
  addl   $0x1,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L54
L48:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L21
  subl   $0x1,-0xc(%rbp)
  jmp    L32
L21:
  addl   $0x1,-0x4(%rbp)
L54:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
L32:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getNumOfSubstring(char a[], char b[]) {
  int counter = 0;
  for (int i = 0; a[i] != 0; i++) {
    counter++;
    for (int j = i; b[j - i] != 0; j++) {
      if (a[j] != b[j - i]) {
        counter--;
        break;
      }
    }
  }
  return counter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getNumOfSubstring>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  movzbl (%rsi),%r8d
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  jmp    L52
L54:
  mov    %r10d,%r9d
L53:
  movzbl 0x1(%rdi,%rcx,1),%eax
  add    $0x1,%rcx
  sub    $0x1,%rsi
  test   %al,%al
  je     L10
L52:
  lea    0x1(%r9),%r10d
  test   %r8b,%r8b
  je     L54
  mov    %rcx,%rax
  mov    %r8d,%edx
L13:
  cmp    %dl,(%rdi,%rax,1)
  jne    L53
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L13
  mov    %r10d,%r9d
  jmp    L53
L16:
  mov    $0x0,%r9d
L10:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int getNumOfSubstring(char a[], char b[]) {
  int counter = 0;
  for (int i = 0; a[i] != 0; i++) {
    counter++;
    for (int j = i; b[j - i] != 0; j++) {
      if (a[j] != b[j - i]) {
        counter--;
        break;
      }
    }
  }
  return counter;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getNumOfSubstring>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L58
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L8:
  lea    0x1(%r9),%r10d
  test   %r8b,%r8b
  je     L36
  mov    %rcx,%rax
  mov    %r8d,%edx
  jmp    L62
  nopl   0x0(%rax)
L51:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L36
L62:
  cmp    %dl,(%rdi,%rax,1)
  je     L51
L40:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L8
  mov    %r9d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    %r10d,%r9d
  jmp    L40
L58:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int getNumOfSubstring(char a[], char b[]) {
  int counter = 0;
  for (int i = 0; a[i] != 0; i++) {
    counter++;
    for (int j = i; b[j - i] != 0; j++) {
      if (a[j] != b[j - i]) {
        counter--;
        break;
      }
    }
  }
  return counter;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getNumOfSubstring>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L36
  movzbl (%rsi),%r8d
  xor    %ecx,%ecx
  xor    %r9d,%r9d
  nopw   0x0(%rax,%rax,1)
L15:
  lea    0x1(%r9),%r10d
  test   %r8b,%r8b
  je     L53
  mov    %rcx,%rax
  mov    %r8d,%edx
  jmp    L6
  nopl   0x0(%rax)
L57:
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  je     L53
L6:
  cmp    %dl,(%rdi,%rax,1)
  je     L57
L22:
  movzbl 0x1(%rdi,%rcx,1),%eax
  sub    $0x1,%rsi
  add    $0x1,%rcx
  test   %al,%al
  jne    L15
  mov    %r9d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    %r10d,%r9d
  jmp    L22
L36:
  xor    %r9d,%r9d
  mov    %r9d,%eax
  ret
```

assistant: ```c
int getNumOfSubstring(char a[], char b[]) {
  int counter = 0;
  for (int i = 0; a[i] != 0; i++) {
    counter++;
    for (int j = i; b[j - i] != 0; j++) {
      if (a[j] != b[j - i]) {
        counter--;
        break;
      }
    }
  }
  return counter;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_lock@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **args) {
  test_lock();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_lock@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **args) {
  test_lock();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_lock@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **args) {
  test_lock();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_lock@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **args) {
  test_lock();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ext_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  jmp    L18
L2:
  mov    -0x8(%rbp),%eax
  mov    $0x20,%edx
  sub    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    -0x4(%rbp),%esi
  mov    %edx,%ecx
  sar    %cl,%esi
  mov    %esi,%edx
  mov    %edx,(%rax)
  nop
L18:
  pop    %rbp
  ret
```

assistant: ```c
void ext_shift(uint64_t ch, uint8_t pos, uint64_t retval[2]) {
  retval[0] = ch << pos;
  if (pos == 0)
    retval[1] = 0;
  else
    retval[1] = ch >> ((sizeof(uint64_t) * 8) - pos);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ext_shift>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  mov    %eax,(%rdx)
  test   %esi,%esi
  je     L3
  mov    $0x20,%ecx
  sub    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%esi
L3:
  mov    %esi,0x4(%rdx)
  ret
```

assistant: ```c
void ext_shift(uint64_t ch, uint8_t pos, uint64_t retval[2]) {
  retval[0] = ch << pos;
  if (pos == 0)
    retval[1] = 0;
  else
    retval[1] = ch >> ((sizeof(uint64_t) * 8) - pos);
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ext_shift>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  mov    %eax,(%rdx)
  test   %esi,%esi
  je     L7
  mov    $0x20,%ecx
  sub    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%esi
L7:
  mov    %esi,0x4(%rdx)
  ret
```

assistant: ```c
void ext_shift(uint64_t ch, uint8_t pos, uint64_t retval[2]) {
  retval[0] = ch << pos;
  if (pos == 0)
    retval[1] = 0;
  else
    retval[1] = ch >> ((sizeof(uint64_t) * 8) - pos);
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<ext_shift>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  mov    %eax,(%rdx)
  test   %esi,%esi
  je     L3
  mov    $0x20,%ecx
  sub    %esi,%ecx
  sar    %cl,%edi
  mov    %edi,%esi
L3:
  mov    %esi,0x4(%rdx)
  ret
```

assistant: ```c
void ext_shift(uint64_t ch, uint8_t pos, uint64_t retval[2]) {
  retval[0] = ch << pos;
  if (pos == 0)
    retval[1] = 0;
  else
    retval[1] = ch >> ((sizeof(uint64_t) * 8) - pos);
  return;
}
```