ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<transitive_closure>:
  endbr64
  lea    0x3e(%rsi),%edx
  mov    %esi,%eax
  add    $0x1f,%eax
  cmovns %eax,%edx
  sar    $0x5,%edx
  imul   %edx,%esi
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r11
  cmp    %r11,%rdi
  jae    L27
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%r10
  mov    %rdi,%rbp
  mov    %rdi,%r12
  mov    $0x0,%ecx
  mov    $0x1,%r15d
  mov    %r10,%r13
  jmp    L86
L66:
  lea    (%rdi,%r10,1),%r9
  cmp    %rdi,%r9
  jbe    L49
  mov    %rbp,%rdx
  mov    %rdi,%rax
L95:
  add    $0x4,%rdx
  add    $0x4,%rax
  mov    -0x4(%rdx),%esi
  or     %esi,-0x4(%rax)
  cmp    %rax,%r9
  ja     L95
  add    %r13,%rdi
L49:
  add    %r10,%r8
  cmp    %r11,%rdi
  jae    L93
L8:
  mov    %ebx,%eax
  and    (%r8),%eax
  jne    L66
  add    %r10,%rdi
  jmp    L49
L93:
  add    $0x1,%ecx
  cmp    $0x1f,%ecx
  jbe    L33
  add    $0x4,%r12
  mov    $0x0,%ecx
L33:
  add    %r10,%rbp
  cmp    %rbp,%r11
  jbe    L78
L86:
  mov    %r15d,%ebx
  shl    %cl,%ebx
  mov    %r12,%r8
  mov    %r14,%rdi
  jmp    L8
L78:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  ret
```

assistant: ```c
transitive_closure(R, n) unsigned *R;
int n;
{
  register int rowsize;
  register unsigned i;
  register unsigned *rowj;
  register unsigned *rp;
  register unsigned *rend;
  register unsigned *ccol;
  register unsigned *relend;
  register unsigned *cword;
  register unsigned *rowi;
  rowsize = (((n) + (32 - 1)) / 32);
  relend = R + n * rowsize;
  cword = R;
  i = 0;
  rowi = R;
  while (rowi < relend) {
    ccol = cword;
    rowj = R;
    while (rowj < relend) {
      if (*ccol & (1 << i)) {
        rp = rowi;
        rend = rowj + rowsize;
        while (rowj < rend)
          *rowj++ |= *rp++;
      } else {
        rowj += rowsize;
      }
      ccol += rowsize;
    }
    if (++i >= 32) {
      i = 0;
      cword++;
    }
    rowi += rowsize;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<transitive_closure>:
  endbr64
  mov    %esi,%eax
  lea    0x3e(%rsi),%edx
  add    $0x1f,%eax
  cmovns %eax,%edx
  sar    $0x5,%edx
  imul   %edx,%esi
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r11
  cmp    %r11,%rdi
  jae    L55
  push   %r15
  movslq %edx,%rdx
  xor    %ecx,%ecx
  mov    $0x1,%r15d
  push   %r14
  lea    0x0(,%rdx,4),%r10
  mov    %rdi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %r10,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xchg   %ax,%ax
L20:
  mov    %r15d,%ebx
  mov    %r14,%r9
  mov    %r13,%r8
  shl    %cl,%ebx
  jmp    L32
  nopl   (%rax)
L37:
  mov    %rdi,%r8
L50:
  add    %r10,%r9
  cmp    %r11,%r8
  jae    L3
L32:
  mov    %ebx,%eax
  and    (%r9),%eax
  lea    (%r8,%r10,1),%rdi
  je     L37
  cmp    %r8,%rdi
  jbe    L50
  mov    %rbp,%rdx
  mov    %r8,%rax
  nopl   0x0(%rax)
L77:
  add    $0x4,%rax
  add    $0x4,%rdx
  mov    -0x4(%rdx),%esi
  or     %esi,-0x4(%rax)
  cmp    %rax,%rdi
  ja     L77
  add    %r12,%r8
  add    %r10,%r9
  cmp    %r11,%r8
  jb     L32
L3:
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L36
  add    $0x4,%r14
  xor    %ecx,%ecx
L36:
  add    %r10,%rbp
  cmp    %rbp,%r11
  ja     L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  ret
```

assistant: ```c
transitive_closure(R, n) unsigned *R;
int n;
{
  register int rowsize;
  register unsigned i;
  register unsigned *rowj;
  register unsigned *rp;
  register unsigned *rend;
  register unsigned *ccol;
  register unsigned *relend;
  register unsigned *cword;
  register unsigned *rowi;
  rowsize = (((n) + (32 - 1)) / 32);
  relend = R + n * rowsize;
  cword = R;
  i = 0;
  rowi = R;
  while (rowi < relend) {
    ccol = cword;
    rowj = R;
    while (rowj < relend) {
      if (*ccol & (1 << i)) {
        rp = rowi;
        rend = rowj + rowsize;
        while (rowj < rend)
          *rowj++ |= *rp++;
      } else {
        rowj += rowsize;
      }
      ccol += rowsize;
    }
    if (++i >= 32) {
      i = 0;
      cword++;
    }
    rowi += rowsize;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x204(%rbp)
  lea    -0x20c(%rbp),%rax
  mov    %rax,%rsi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x208(%rbp)
  jmp    L80
L3:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x208(%rbp)
L80:
  mov    -0x20c(%rbp),%eax
  cmp    %eax,-0x208(%rbp)
  jl     L3
  movl   $0x0,-0x208(%rbp)
  jmp    L78
L48:
  mov    -0x208(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%edx
  mov    -0x208(%rbp),%eax
  cltq
  mov    %edx,-0x200(%rbp,%rax,4)
  mov    -0x208(%rbp),%eax
  cltq
  mov    -0x200(%rbp,%rax,4),%eax
  cmp    $0x7a,%eax
  jg     L61
  mov    -0x208(%rbp),%eax
  cltq
  mov    -0x200(%rbp,%rax,4),%eax
  cmp    $0x2a,%eax
  jg     L83
L61:
  addl   $0x1,-0x204(%rbp)
  jmp    L31
L83:
  nop
L31:
  addl   $0x1,-0x208(%rbp)
L78:
  mov    -0x208(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L48
  cmpl   $0x0,-0x204(%rbp)
  jne    L42
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L20
L42:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D31
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string

tool: D38: %d

tool: D31: %s

tool: D29: YES

tool: D25: NO

assistant: ```c
int main() {
  int t, i, u[99], p = 0;
  char s[99];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("%s", s);
  for (i = 0; s[i] != '\0'; i++) {
    u[i] = s[i];
    if (u[i] <= 122 && u[i] >= 43) {
      continue;
    } else
      p++;
  }
  if (p == 0)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L26
  mov    $0x0,%ebx
  lea    D33(%rip),%rbp
L41:
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L41
L26:
  movzbl 0x10(%rsp),%eax
  test   %al,%al
  je     L48
  lea    0x11(%rsp),%rdx
  mov    $0x0,%ecx
L69:
  movsbl %al,%eax
  sub    $0x2b,%eax
  cmp    $0x50,%eax
  sbb    $0xffffffff,%ecx
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L69
  test   %ecx,%ecx
  je     L48
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L48:
  lea    D34(%rip),%rdi
  call   <printf@plt>
L66:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D22
data_type: string
name: unpack_data
arguments: data_tag: D33
data_type: string
name: unpack_data
arguments: data_tag: D5
data_type: string
name: unpack_data
arguments: data_tag: D34
data_type: string

tool: D22: %d

tool: D33: %s

tool: D5: NO

tool: D34: YES

assistant: ```c
int main() {
  int t, i, u[99], p = 0;
  char s[99];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("%s", s);
  for (i = 0; s[i] != '\0'; i++) {
    u[i] = s[i];
    if (u[i] <= 122 && u[i] >= 43) {
      continue;
    } else
      p++;
  }
  if (p == 0)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L19
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D30(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L67:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L67
L19:
  movsbl 0x10(%rsp),%eax
  test   %al,%al
  je     L58
  lea    0x11(%rsp),%rdx
  xor    %ecx,%ecx
  xchg   %ax,%ax
L53:
  sub    $0x2b,%eax
  cmp    $0x50,%eax
  sbb    $0xffffffff,%ecx
  movsbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L53
  test   %ecx,%ecx
  je     L58
  lea    D6(%rip),%rdi
  call   <printf@plt>
L27:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L27
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D30
type: string
name: disassemble_data
arguments: data_label: D6
type: string
name: disassemble_data
arguments: data_label: D4
type: string

tool: D5: %d

tool: D30: %s

tool: D6: NO

tool: D4: YES

assistant: ```c
int main() {
  int t, i, u[99], p = 0;
  char s[99];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("%s", s);
  for (i = 0; s[i] != '\0'; i++) {
    u[i] = s[i];
    if (u[i] <= 122 && u[i] >= 43) {
      continue;
    } else
      p++;
  }
  if (p == 0)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L51
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D22(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L21
L51:
  movsbl 0x10(%rsp),%eax
  test   %al,%al
  je     L43
  lea    0x11(%rsp),%rdx
  xor    %ecx,%ecx
  xchg   %ax,%ax
L59:
  sub    $0x2b,%eax
  cmp    $0x50,%eax
  sbb    $0xffffffff,%ecx
  movsbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L59
  test   %ecx,%ecx
  je     L43
  lea    D39(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D39
datatype: string
name: unpack_data
arguments: label: D31
datatype: string

tool: D5: %d

tool: D22: %s

tool: D39: NO

tool: D31: YES

assistant: ```c
int main() {
  int t, i, u[99], p = 0;
  char s[99];
  scanf("%d", &t);
  for (i = 0; i < t; i++)
    scanf("%s", s);
  for (i = 0; s[i] != '\0'; i++) {
    u[i] = s[i];
    if (u[i] <= 122 && u[i] >= 43) {
      continue;
    } else
      p++;
  }
  if (p == 0)
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<gen_int64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x40,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <print_type@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: long

assistant: ```c
void gen_int64() {
  if (sizeof(long) == 8)
    print_type("long", 64);
  else if (sizeof(long long) == 8)
    print_type("long long", 64);
  else
    print_error("long long", sizeof(long long));
}
```
user: What is the c source code of the assembly code below:

```asm
<gen_int64>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x40,%esi
  lea    D2(%rip),%rdi
  call   <print_type@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: long

assistant: ```c
void gen_int64() {
  if (sizeof(long) == 8)
    print_type("long", 64);
  else if (sizeof(long long) == 8)
    print_type("long long", 64);
  else
    print_error("long long", sizeof(long long));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_int64>:
  endbr64
  mov    $0x40,%esi
  lea    D0(%rip),%rdi
  jmp    1050 <print_type@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type: string

tool: D0: long

assistant: ```c
void gen_int64() {
  if (sizeof(long) == 8)
    print_type("long", 64);
  else if (sizeof(long long) == 8)
    print_type("long long", 64);
  else
    print_error("long long", sizeof(long long));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_int64>:
  endbr64
  mov    $0x40,%esi
  lea    D3(%rip),%rdi
  jmp    1050 <print_type@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string

tool: D3: long

assistant: ```c
void gen_int64() {
  if (sizeof(long) == 8)
    print_type("long", 64);
  else if (sizeof(long long) == 8)
    print_type("long long", 64);
  else
    print_error("long long", sizeof(long long));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D29(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D10(%rip)
  mov    D10(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count() {
  static int c = 0;
  return ++c;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<count>:
  endbr64
  mov    D11(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D18(%rip)
  ret
```

assistant: ```c
int count() {
  static int c = 0;
  return ++c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<count>:
  endbr64
  mov    D5(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D11(%rip)
  ret
```

assistant: ```c
int count() {
  static int c = 0;
  return ++c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count>:
  endbr64
  mov    D16(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D19(%rip)
  ret
```

assistant: ```c
int count() {
  static int c = 0;
  return ++c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<step_ok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x7c,-0x4(%rbp)
  je     L26
  cmpl   $0x7c,-0x4(%rbp)
  jg     L1
  cmpl   $0x20,-0x4(%rbp)
  je     L26
  cmpl   $0x2d,-0x4(%rbp)
  jne    L1
L26:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L16
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L16:
  leave
  ret
```

assistant: ```c
int step_ok(int ch) {
  switch (ch) {
  case ' ':
  case '|':
  case '-':
    return FALSE;
  default:
    return (!isalpha(ch));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<step_ok>:
  endbr64
  cmp    $0x2d,%edi
  je     L2
  cmp    $0x7c,%edi
  je     L2
  cmp    $0x20,%edi
  je     L2
  sub    $0x8,%rsp
  call   <isalpha@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
L2:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int step_ok(int ch) {
  switch (ch) {
  case ' ':
  case '|':
  case '-':
    return FALSE;
  default:
    return (!isalpha(ch));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<step_ok>:
  endbr64
  cmp    $0x2d,%edi
  je     L29
  cmp    $0x7c,%edi
  je     L29
  cmp    $0x20,%edi
  je     L29
  sub    $0x8,%rsp
  call   <isalpha@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L29:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int step_ok(int ch) {
  switch (ch) {
  case ' ':
  case '|':
  case '-':
    return FALSE;
  default:
    return (!isalpha(ch));
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<step_ok>:
  endbr64
  cmp    $0x2d,%edi
  je     L6
  cmp    $0x7c,%edi
  je     L6
  cmp    $0x20,%edi
  je     L6
  sub    $0x8,%rsp
  call   <isalpha@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int step_ok(int ch) {
  switch (ch) {
  case ' ':
  case '|':
  case '-':
    return FALSE;
  default:
    return (!isalpha(ch));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <read_matrix@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%ecx
  mov    -0x10(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <print_matrix@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <clean_matrix@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D17
datatype: string

tool: D10: Informe as dimensoes da matriz: 


tool: D3: %d %d

tool: D17: Entre com os valores da matriz: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int m, n;
  float **p;
  printf("Informe as dimensoes da matriz: \n");
  scanf("%d %d", &m, &n);
  printf("Entre com os valores da matriz: \n");
  p = read_matrix(m, n);
  print_matrix(p, m, n);
  clean_matrix(p, m);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <read_matrix@plt>
  mov    %rax,%rbx
  mov    0x4(%rsp),%edx
  mov    (%rsp),%esi
  mov    %rax,%rdi
  call   <print_matrix@plt>
  mov    (%rsp),%esi
  mov    %rbx,%rdi
  call   <clean_matrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type: string
name: read_data
arguments: data_tag: D14
type: string
name: read_data
arguments: data_tag: D2
type: string

tool: D11: Informe as dimensoes da matriz: 


tool: D14: %d %d

tool: D2: Entre com os valores da matriz: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int m, n;
  float **p;
  printf("Informe as dimensoes da matriz: \n");
  scanf("%d %d", &m, &n);
  printf("Entre com os valores da matriz: \n");
  p = read_matrix(m, n);
  print_matrix(p, m, n);
  clean_matrix(p, m);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <read_matrix@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <print_matrix@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <clean_matrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D20
type_infered: string
name: unpack_data
arguments: data_label: D23
type_infered: string

tool: D13: Informe as dimensoes da matriz: 


tool: D20: %d %d

tool: D23: Entre com os valores da matriz: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int m, n;
  float **p;
  printf("Informe as dimensoes da matriz: \n");
  scanf("%d %d", &m, &n);
  printf("Entre com os valores da matriz: \n");
  p = read_matrix(m, n);
  print_matrix(p, m, n);
  clean_matrix(p, m);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <read_matrix@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%edx
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <print_matrix@plt>
  mov    (%rsp),%esi
  mov    %rbp,%rdi
  call   <clean_matrix@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D9
data_type: string
name: read_data
arguments: label: D3
data_type: string
name: read_data
arguments: label: D14
data_type: string

tool: D9: Informe as dimensoes da matriz: 


tool: D3: %d %d

tool: D14: Entre com os valores da matriz: 


assistant: ```c
int main(int argc, const char *argv[]) {
  int m, n;
  float **p;
  printf("Informe as dimensoes da matriz: \n");
  scanf("%d %d", &m, &n);
  printf("Entre com os valores da matriz: \n");
  p = read_matrix(m, n);
  print_matrix(p, m, n);
  clean_matrix(p, m);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x322,-0x10(%rbp)
  movl   $0xb6f,-0xc(%rbp)
  movl   $0x552,-0x8(%rbp)
  movl   $0x3e8,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  sub    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: string

tool: D18: %d


assistant: ```c
int main() {
  int16_t m = 802, x1 = 2927, y1 = 1362, ICONST = 1000;
  printf("%d\n", (int16_t)(((int16_t)((int16_t)(m * x1) / ICONST)) - y1));
  printf("%d\n", -(int16_t)(((int16_t)((int16_t)(m * x1) / ICONST)) - y1));
  printf("%d\n", (int16_t)(y1 - (int16_t)((int16_t)(m * x1) / ICONST)));
  return 0;
}
```