ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<close_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L40
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L16
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L16
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L16
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L16:
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L42
L40:
  nop
L42:
  leave
  ret
```

assistant: ```c
void close_file(void *file) {
  if (*(FILE **)file == NULL)
    return;
  if (!((*(FILE **)file == stdout) || (*(FILE **)file == stdin) || (*(FILE **)file == stderr))) {
    fclose(*(FILE **)file);
  }
  *(FILE **)file = NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<close_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L13
  mov    D8(%rip),%rax
  cmp    (%rax),%rdi
  je     L35
  mov    D13(%rip),%rax
  cmp    (%rax),%rdi
  je     L35
  mov    D2(%rip),%rax
  cmp    (%rax),%rdi
  je     L35
  call   <fclose@plt>
L35:
  movq   $0x0,(%rbx)
L13:
  pop    %rbx
  ret
```

assistant: ```c
void close_file(void *file) {
  if (*(FILE **)file == NULL)
    return;
  if (!((*(FILE **)file == stdout) || (*(FILE **)file == stdin) || (*(FILE **)file == stderr))) {
    fclose(*(FILE **)file);
  }
  *(FILE **)file = NULL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<close_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L19
  mov    D20(%rip),%rax
  cmp    (%rax),%rdi
  je     L1
  mov    D15(%rip),%rax
  cmp    (%rax),%rdi
  je     L1
  mov    D26(%rip),%rax
  cmp    (%rax),%rdi
  je     L1
  call   <fclose@plt>
L1:
  movq   $0x0,(%rbx)
L19:
  pop    %rbx
  ret
```

assistant: ```c
void close_file(void *file) {
  if (*(FILE **)file == NULL)
    return;
  if (!((*(FILE **)file == stdout) || (*(FILE **)file == stdin) || (*(FILE **)file == stderr))) {
    fclose(*(FILE **)file);
  }
  *(FILE **)file = NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<close_file>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L32
  mov    D25(%rip),%rax
  cmp    (%rax),%rdi
  je     L37
  mov    D29(%rip),%rax
  cmp    (%rax),%rdi
  je     L37
  mov    D23(%rip),%rax
  cmp    (%rax),%rdi
  je     L37
  call   <fclose@plt>
L37:
  movq   $0x0,(%rbx)
L32:
  pop    %rbx
  ret
```

assistant: ```c
void close_file(void *file) {
  if (*(FILE **)file == NULL)
    return;
  if (!((*(FILE **)file == stdout) || (*(FILE **)file == stdin) || (*(FILE **)file == stderr))) {
    fclose(*(FILE **)file);
  }
  *(FILE **)file = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Little_End_In_First>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xc,-0xc(%rbp)
  lea    -0xc(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xc,%eax
  jne    L13
  movl   $0x1,-0x1c(%rbp)
  jmp    L26
L13:
  movl   $0x0,-0x1c(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int Little_End_In_First(void) {
  int bStatus;
  unsigned char buf[4] = {0x0C, 0x00, 0x00, 0x00};
  unsigned int *p;
  p = (unsigned int *)buf;
  if (*p == 0x0C)
    bStatus = 1;
  else
    bStatus = 0;
  return bStatus;
}
```
user: What is the c source code of the assembly code below?

```asm
<Little_End_In_First>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Little_End_In_First(void) {
  int bStatus;
  unsigned char buf[4] = {0x0C, 0x00, 0x00, 0x00};
  unsigned int *p;
  p = (unsigned int *)buf;
  if (*p == 0x0C)
    bStatus = 1;
  else
    bStatus = 0;
  return bStatus;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Little_End_In_First>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Little_End_In_First(void) {
  int bStatus;
  unsigned char buf[4] = {0x0C, 0x00, 0x00, 0x00};
  unsigned int *p;
  p = (unsigned int *)buf;
  if (*p == 0x0C)
    bStatus = 1;
  else
    bStatus = 0;
  return bStatus;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Little_End_In_First>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int Little_End_In_First(void) {
  int bStatus;
  unsigned char buf[4] = {0x0C, 0x00, 0x00, 0x00};
  unsigned int *p;
  p = (unsigned int *)buf;
  if (*p == 0x0C)
    bStatus = 1;
  else
    bStatus = 0;
  return bStatus;
}
```
user: What is the c source code of the assembly code below?

```asm
<o_binCoeff>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L3
  mov    $0x0,%eax
  jmp    L47
L3:
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L39
L6:
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L6
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L29
L57:
  mov    -0x10(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L57
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
L47:
  pop    %rbp
  ret
```

assistant: ```c
int o_binCoeff(int k, int n) {
  int num, den, i, j;
  if (n < k) {
    return (0);
  } else {
    den = 1;
    num = 1;
    for (i = 1; i <= k; i = i + 1)
      den = den * i;
    for (j = n - k + 1; j <= n; j = j + 1)
      num = num * j;
    return (num / den);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<o_binCoeff>:
  endbr64
  mov    $0x0,%eax
  cmp    %edi,%esi
  jl     L5
  test   %edi,%edi
  jle    L69
  lea    0x1(%rdi),%edx
  mov    $0x1,%eax
  mov    $0x1,%ecx
L27:
  imul   %eax,%ecx
  add    $0x1,%eax
  cmp    %edx,%eax
  jne    L27
L46:
  mov    %esi,%edx
  sub    %edi,%edx
  add    $0x1,%edx
  cmp    %edx,%esi
  jl     L7
  add    $0x1,%esi
  mov    $0x1,%eax
L47:
  imul   %edx,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L47
L29:
  cltd
  idiv   %ecx
L5:
  ret
L69:
  mov    $0x1,%ecx
  jmp    L46
L7:
  mov    $0x1,%eax
  jmp    L29
```

assistant: ```c
int o_binCoeff(int k, int n) {
  int num, den, i, j;
  if (n < k) {
    return (0);
  } else {
    den = 1;
    num = 1;
    for (i = 1; i <= k; i = i + 1)
      den = den * i;
    for (j = n - k + 1; j <= n; j = j + 1)
      num = num * j;
    return (num / den);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<o_binCoeff>:
  endbr64
  xor    %eax,%eax
  cmp    %edi,%esi
  jl     L23
  test   %edi,%edi
  jle    L11
  lea    0x1(%rdi),%edx
  mov    $0x1,%eax
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L18:
  imul   %eax,%ecx
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L18
L25:
  mov    %esi,%edx
  sub    %edi,%edx
  add    $0x1,%edx
  cmp    %edx,%esi
  jl     L32
  add    $0x1,%esi
  mov    $0x1,%eax
  nopl   (%rax)
L48:
  imul   %edx,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L48
L60:
  cltd
  idiv   %ecx
L23:
  ret
  xchg   %ax,%ax
L11:
  mov    $0x1,%ecx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L32:
  mov    $0x1,%eax
  jmp    L60
```

assistant: ```c
int o_binCoeff(int k, int n) {
  int num, den, i, j;
  if (n < k) {
    return (0);
  } else {
    den = 1;
    num = 1;
    for (i = 1; i <= k; i = i + 1)
      den = den * i;
    for (j = n - k + 1; j <= n; j = j + 1)
      num = num * j;
    return (num / den);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<o_binCoeff>:
  endbr64
  xor    %eax,%eax
  cmp    %edi,%esi
  jl     L34
  test   %edi,%edi
  jle    L52
  lea    0x1(%rdi),%edx
  mov    $0x1,%eax
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L29:
  imul   %eax,%ecx
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L29
L37:
  mov    %esi,%edx
  sub    %edi,%edx
  add    $0x1,%edx
  cmp    %edx,%esi
  jl     L44
  add    $0x1,%esi
  mov    $0x1,%eax
  nopl   (%rax)
L25:
  imul   %edx,%eax
  add    $0x1,%edx
  cmp    %edx,%esi
  jne    L25
L64:
  cltd
  idiv   %ecx
L34:
  ret
  xchg   %ax,%ax
L52:
  mov    $0x1,%ecx
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L44:
  mov    $0x1,%eax
  jmp    L64
```

assistant: ```c
int o_binCoeff(int k, int n) {
  int num, den, i, j;
  if (n < k) {
    return (0);
  } else {
    den = 1;
    num = 1;
    for (i = 1; i <= k; i = i + 1)
      den = den * i;
    for (j = n - k + 1; j <= n; j = j + 1)
      num = num * j;
    return (num / den);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_input_flag>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <check_input@plt>
  test   %rax,%rax
  je     L0
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  or     -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L0:
  nop
  leave
  ret
```

assistant: ```c
void check_input_flag(char *response, const char *check_string, int *flags, int check_flag) {
  if (check_input(response, check_string)) {
    *flags |= check_flag;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<check_input_flag>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  call   <check_input@plt>
  test   %rax,%rax
  je     L2
  or     %ebp,(%rbx)
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void check_input_flag(char *response, const char *check_string, int *flags, int check_flag) {
  if (check_input(response, check_string)) {
    *flags |= check_flag;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<check_input_flag>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <check_input@plt>
  test   %rax,%rax
  je     L5
  or     %ebp,(%rbx)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void check_input_flag(char *response, const char *check_string, int *flags, int check_flag) {
  if (check_input(response, check_string)) {
    *flags |= check_flag;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_input_flag>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <check_input@plt>
  test   %rax,%rax
  je     L0
  or     %ebp,(%rbx)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void check_input_flag(char *response, const char *check_string, int *flags, int check_flag) {
  if (check_input(response, check_string)) {
    *flags |= check_flag;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  jmp    L18
L15:
  mov    $0x0,%eax
  call   <produce@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cmp    %eax,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  cmp    $0xc,%eax
  jbe    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D11
datatype: string
name: read_data
arguments: tag: D8
datatype: string

tool: D11: %d


tool: 

assistant: ```c
int main(void) {
  static const int expect[] = {0, 1, 2, 3, 4, 5, 5, 5, 4, 3, 2, 1, 0};
  int i;
  for (i = 0; i < (sizeof(expect) / sizeof((expect)[0])); i++) {
    const int v = produce();
    printf("%d\n", v);
    assert(v == expect[i]);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D17(%rip),%rbp
  lea    0x34(%rbp),%r13
  lea    D12(%rip),%r12
L2:
  mov    $0x0,%eax
  call   <produce@plt>
  mov    %eax,%ebx
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebx,0x0(%rbp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x4,%rbp
  cmp    %r13,%rbp
  jne    L2
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
data_type: string
name: disassemble_data
arguments: label: D12
data_type: string

tool: 

tool: D12: %d


assistant: ```c
int main(void) {
  static const int expect[] = {0, 1, 2, 3, 4, 5, 5, 5, 4, 3, 2, 1, 0};
  int i;
  for (i = 0; i < (sizeof(expect) / sizeof((expect)[0])); i++) {
    const int v = produce();
    printf("%d\n", v);
    assert(v == expect[i]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  lea    0x34(%rbp),%r13
  sub    $0x8,%rsp
L4:
  xor    %eax,%eax
  call   <produce@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebx
  call   <printf@plt>
  xor    %edi,%edi
  cmp    %ebx,0x0(%rbp)
  sete   %dil
  add    $0x4,%rbp
  call   <assert@plt>
  cmp    %r13,%rbp
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string

tool: D5: %d


tool: 

assistant: ```c
int main(void) {
  static const int expect[] = {0, 1, 2, 3, 4, 5, 5, 5, 4, 3, 2, 1, 0};
  int i;
  for (i = 0; i < (sizeof(expect) / sizeof((expect)[0])); i++) {
    const int v = produce();
    printf("%d\n", v);
    assert(v == expect[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D13(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  lea    0x34(%rbp),%r13
  sub    $0x8,%rsp
L1:
  xor    %eax,%eax
  call   <produce@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  mov    %eax,%ebx
  call   <printf@plt>
  xor    %edi,%edi
  cmp    %ebx,0x0(%rbp)
  sete   %dil
  add    $0x4,%rbp
  call   <assert@plt>
  cmp    %r13,%rbp
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type_infered: string
name: disassemble_data
arguments: data_tag: D16
type_infered: string

tool: D13: %d


tool: 

assistant: ```c
int main(void) {
  static const int expect[] = {0, 1, 2, 3, 4, 5, 5, 5, 4, 3, 2, 1, 0};
  int i;
  for (i = 0; i < (sizeof(expect) / sizeof((expect)[0])); i++) {
    const int v = produce();
    printf("%d\n", v);
    assert(v == expect[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<QuickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  jmp    L7
L19:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <Partiton@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <QuickSort>
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void QuickSort(int p, int r, int *A) {
  int q;
  while (p < r) {
    q = Partiton(p, r, A);
    QuickSort(p, q, A);
    p = q + 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<QuickSort>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %rdx,%r13
  cmp    %esi,%edi
  jge    L19
L3:
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <Partiton@plt>
  mov    %eax,%ebp
  mov    %r13,%rdx
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <QuickSort>
  lea    0x1(%rbp),%ebx
  cmp    %ebx,%r12d
  jg     L3
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void QuickSort(int p, int r, int *A) {
  int q;
  while (p < r) {
    q = Partiton(p, r, A);
    QuickSort(p, q, A);
    p = q + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<QuickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x14(%rsp)
  cmp    %esi,%edi
  jge    L90
  mov    %edi,%r14d
  mov    %rdx,%rbp
L111:
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,0x8(%rsp)
  cmp    %r14d,%eax
  jle    L77
L138:
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,0xc(%rsp)
  cmp    %r14d,%eax
  jle    L143
L9:
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,0x10(%rsp)
  cmp    %r14d,%eax
  jle    L102
L82:
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%r12d
  cmp    %r14d,%eax
  jle    L172
L148:
  mov    %rbp,%rdx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%ebx
  cmp    %r14d,%eax
  jle    L141
L11:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%r13d
  cmp    %eax,%r14d
  jge    L39
L127:
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%r15d
  cmp    %r14d,%eax
  jle    L15
L16:
  mov    %rbp,%rdx
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%ecx
  cmp    %r14d,%eax
  jle    L88
L65:
  mov    %ecx,%esi
  mov    %r14d,%edi
  mov    %rbp,%rdx
  mov    %ecx,0x1c(%rsp)
  call   <Partiton@plt>
  mov    %r14d,%edi
  mov    %rbp,%rdx
  mov    %eax,%esi
  mov    %eax,0x18(%rsp)
  call   <QuickSort>
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%ecx
  lea    0x1(%rax),%r14d
  cmp    %r14d,%ecx
  jg     L65
L88:
  lea    0x1(%rcx),%r14d
  cmp    %r14d,%r15d
  jg     L16
L15:
  lea    0x1(%r15),%r14d
  cmp    %r14d,%r13d
  jg     L127
L39:
  lea    0x1(%r13),%r14d
  cmp    %r14d,%ebx
  jg     L11
L141:
  lea    0x1(%rbx),%r14d
  cmp    %r14d,%r12d
  jg     L148
L172:
  lea    0x1(%r12),%r14d
  cmp    %r14d,0x10(%rsp)
  jg     L82
L102:
  mov    0x10(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0xc(%rsp)
  jg     L9
L143:
  mov    0xc(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jg     L138
L77:
  mov    0x8(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0x14(%rsp)
  jg     L111
L90:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QuickSort(int p, int r, int *A) {
  int q;
  while (p < r) {
    q = Partiton(p, r, A);
    QuickSort(p, q, A);
    p = q + 1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<QuickSort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x14(%rsp)
  cmp    %esi,%edi
  jge    L42
  mov    %edi,%r14d
  mov    %rdx,%rbp
L54:
  mov    0x14(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,0x8(%rsp)
  cmp    %r14d,%eax
  jle    L13
L107:
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,0xc(%rsp)
  cmp    %r14d,%eax
  jle    L155
L53:
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,0x10(%rsp)
  cmp    %r14d,%eax
  jle    L138
L75:
  mov    0x10(%rsp),%esi
  mov    %rbp,%rdx
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%r12d
  cmp    %r14d,%eax
  jle    L102
L118:
  mov    %rbp,%rdx
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%ebx
  cmp    %r14d,%eax
  jle    L3
L108:
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%r13d
  cmp    %eax,%r14d
  jge    L47
L43:
  mov    %rbp,%rdx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%r15d
  cmp    %r14d,%eax
  jle    L156
L126:
  mov    %rbp,%rdx
  mov    %r15d,%esi
  mov    %r14d,%edi
  call   <Partiton@plt>
  mov    %eax,%ecx
  cmp    %r14d,%eax
  jle    L174
L27:
  mov    %ecx,%esi
  mov    %r14d,%edi
  mov    %rbp,%rdx
  mov    %ecx,0x1c(%rsp)
  call   <Partiton@plt>
  mov    %r14d,%edi
  mov    %rbp,%rdx
  mov    %eax,%esi
  mov    %eax,0x18(%rsp)
  call   <QuickSort>
  mov    0x18(%rsp),%eax
  mov    0x1c(%rsp),%ecx
  lea    0x1(%rax),%r14d
  cmp    %r14d,%ecx
  jg     L27
L174:
  lea    0x1(%rcx),%r14d
  cmp    %r14d,%r15d
  jg     L126
L156:
  lea    0x1(%r15),%r14d
  cmp    %r14d,%r13d
  jg     L43
L47:
  lea    0x1(%r13),%r14d
  cmp    %r14d,%ebx
  jg     L108
L3:
  lea    0x1(%rbx),%r14d
  cmp    %r14d,%r12d
  jg     L118
L102:
  lea    0x1(%r12),%r14d
  cmp    %r14d,0x10(%rsp)
  jg     L75
L138:
  mov    0x10(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0xc(%rsp)
  jg     L53
L155:
  mov    0xc(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0x8(%rsp)
  jg     L107
L13:
  mov    0x8(%rsp),%r14d
  add    $0x1,%r14d
  cmp    %r14d,0x14(%rsp)
  jg     L54
L42:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void QuickSort(int p, int r, int *A) {
  int q;
  while (p < r) {
    q = Partiton(p, r, A);
    QuickSort(p, q, A);
    p = q + 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <make_deamon@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  make_deamon();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <make_deamon@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  make_deamon();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <make_deamon@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  make_deamon();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <make_deamon@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  make_deamon();
  return 0;
}
```