ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_attr>:
  endbr64
  push   %r13
  xor    %ecx,%ecx
  push   %r12
  mov    %edx,%r12d
  mov    $0x18,%edx
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <pread@plt>
  test   %eax,%eax
  jle    L47
  mov    D4(%rip),%r13
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  movq   $0x0,0x0(%r13)
  call   <strtoll@plt>
  cmpq   $0x0,0x0(%r13)
  mov    %rax,(%rbx)
  jne    L35
  xor    %eax,%eax
L24:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L47:
  movq   $0xffffffffffffffff,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L24
  xchg   %ax,%ax
L35:
  movq   $0xfffffffffffffffe,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L24
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_attr(int fd, long long *val, int base) {
  char data[24];
  ssize_t r = pread(fd, data, sizeof(data), 0);
  if (r < 1) {
    *val = -1;
    return -1;
  }
  errno = 0;
  *val = strtoll(data, NULL, base);
  if (errno) {
    *val = -2;
    return -1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<shortenstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L16
  mov    -0x18(%rbp),%rax
  jmp    L7
L24:
  addq   $0x1,-0x18(%rbp)
L16:
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  sub    -0x1c(%rbp),%edx
  cmp    %edx,%eax
  jl     L24
  mov    -0x18(%rbp),%rax
  movb   $0x2b,(%rax)
  mov    -0x18(%rbp),%rax
L7:
  leave
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int i = 0;
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  while (i++ < (slen - len))
    str++;
  str[0] = '+';
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<shortenstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  mov    %rbx,%rdx
  cmp    %ebp,%eax
  jle    L17
  sub    %ebp,%eax
  lea    0x1(%rax),%ecx
  mov    $0x1,%edx
L8:
  add    $0x1,%edx
  cmp    %ecx,%edx
  jne    L8
  mov    %eax,%eax
  lea    (%rbx,%rax,1),%rdx
  movb   $0x2b,(%rdx)
L17:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int i = 0;
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  while (i++ < (slen - len))
    str++;
  str[0] = '+';
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<shortenstr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  cmp    %ebp,%edx
  jle    L7
  sub    %ebp,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  movb   $0x2b,(%rax)
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int i = 0;
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  while (i++ < (slen - len))
    str++;
  str[0] = '+';
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<shortenstr>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    %rbx,%rax
  cmp    %ebp,%edx
  jle    L8
  sub    %ebp,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  movb   $0x2b,(%rax)
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *shortenstr(char *str, int len) {
  int i = 0;
  int slen = (int)strlen(str);
  if (slen < len + 1)
    return str;
  while (i++ < (slen - len))
    str++;
  str[0] = '+';
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cipher_correct_test@plt>
  mov    $0x0,%eax
  call   <cipher_speed_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  cipher_correct_test();
  cipher_speed_test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cipher_correct_test@plt>
  mov    $0x0,%eax
  call   <cipher_speed_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  cipher_correct_test();
  cipher_speed_test();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cipher_correct_test@plt>
  xor    %eax,%eax
  call   <cipher_speed_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  cipher_correct_test();
  cipher_speed_test();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<c_print_results>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  movsd  %xmm0,-0x38(%rbp)
  movsd  %xmm1,-0x40(%rbp)
  mov    %al,-0x1c(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string

tool: D7: 1000

tool: D18: 

 %s Benchmark Completed


tool: D11:  Time in seconds =             %12.2f


assistant: ```c
void c_print_results(char *name, char class, int n1, int n2, int n3, int niter, double t, double mops, char *optype, int passed_verification, char *npbversion, char *compiletime, char *cc, char *clink, char *c_lib, char *c_inc, char *cflags, char *clinkflags, char *rand) {
  char *evalue = "1000";
  printf("\n\n %s Benchmark Completed\n", name);
  printf(" Time in seconds =             %12.2f\n", t);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<c_print_results>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  movq   %xmm0,%rbx
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   %rbx,%xmm0
  lea    D0(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D0
data_type: string

tool: D1: 

 %s Benchmark Completed


tool: D0:  Time in seconds =             %12.2f


assistant: ```c
void c_print_results(char *name, char class, int n1, int n2, int n3, int niter, double t, double mops, char *optype, int passed_verification, char *npbversion, char *compiletime, char *cc, char *clink, char *c_lib, char *c_inc, char *cflags, char *clinkflags, char *rand) {
  char *evalue = "1000";
  printf("\n\n %s Benchmark Completed\n", name);
  printf(" Time in seconds =             %12.2f\n", t);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<c_print_results>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D14(%rip),%rdi
  add    $0x18,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D15
datatype: string
name: parse_data
arguments: data_label: D14
datatype: string

tool: D15: 

 %s Benchmark Completed


tool: D14:  Time in seconds =             %12.2f


assistant: ```c
void c_print_results(char *name, char class, int n1, int n2, int n3, int niter, double t, double mops, char *optype, int passed_verification, char *npbversion, char *compiletime, char *cc, char *clink, char *c_lib, char *c_inc, char *cflags, char *clinkflags, char *rand) {
  char *evalue = "1000";
  printf("\n\n %s Benchmark Completed\n", name);
  printf(" Time in seconds =             %12.2f\n", t);
}
```
user: What is the c source code of the assembly code below?

```asm
<c_print_results>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  movsd  %xmm0,0x8(%rsp)
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D9(%rip),%rdi
  add    $0x18,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D9
type: string

tool: D0: 

 %s Benchmark Completed


tool: D9:  Time in seconds =             %12.2f


assistant: ```c
void c_print_results(char *name, char class, int n1, int n2, int n3, int niter, double t, double mops, char *optype, int passed_verification, char *npbversion, char *compiletime, char *cc, char *clink, char *c_lib, char *c_inc, char *cflags, char *clinkflags, char *rand) {
  char *evalue = "1000";
  printf("\n\n %s Benchmark Completed\n", name);
  printf(" Time in seconds =             %12.2f\n", t);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L34
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L43
L34:
  addq   $0x1,-0x18(%rbp)
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L54
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L183
  addq   $0x1,-0x18(%rbp)
  jmp    L24
L13:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L107
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L70
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jle    L107
L70:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L100
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jle    L107
L100:
  movl   $0x0,-0x4(%rbp)
  jmp    L199
L107:
  addq   $0x1,-0x18(%rbp)
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  jmp    L199
L86:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L129
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jle    L37
L129:
  movl   $0x0,-0x4(%rbp)
  jmp    L199
L37:
  addq   $0x1,-0x18(%rbp)
L183:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L86
  jmp    L199
L138:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L40
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L222
L40:
  movl   $0x0,-0x4(%rbp)
  jmp    L199
L222:
  addq   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L138
L199:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_number(char *s) {
  int r = 1;
  if ((*s == '+') || (*s == '-'))
    s++;
  if (*s == '0') {
    s++;
    if (*s == 'x') {
      for (s++; *s; s++)
        if (((*s < '0') || (*s > '9')) && ((*s < 'a') || (*s > 'f')) && ((*s < 'A') || (*s > 'F'))) {
          r = 0;
          break;
        }
    } else {
      for (; *s; s++)
        if ((*s < '0') || (*s > '7')) {
          r = 0;
          break;
        }
    }
  } else {
    for (; *s; s++)
      if ((*s < '0') || (*s > '9')) {
        r = 0;
        break;
      }
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_number>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x2b,%eax
  and    $0xfffffffd,%eax
  cmp    $0x1,%al
  adc    $0x0,%rdi
  movzbl (%rdi),%eax
  cmp    $0x30,%al
  je     L105
  test   %al,%al
  je     L6
L101:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L44
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L101
  mov    $0x1,%eax
  ret
L6:
  mov    $0x1,%eax
  ret
L105:
  movzbl 0x1(%rdi),%eax
  cmp    $0x78,%al
  je     L99
  add    $0x1,%rdi
  test   %al,%al
  je     L45
L62:
  sub    $0x30,%eax
  cmp    $0x7,%al
  ja     L54
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L62
  mov    $0x1,%eax
  ret
L45:
  mov    $0x1,%eax
  ret
L99:
  lea    0x2(%rdi),%rdx
  movzbl 0x2(%rdi),%eax
  test   %al,%al
  jne    L71
  mov    $0x1,%eax
  ret
L107:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L81
L71:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L107
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x5,%al
  jbe    L107
  mov    $0x0,%eax
  ret
L81:
  mov    $0x1,%eax
  ret
L54:
  mov    $0x0,%eax
  ret
L44:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int is_number(char *s) {
  int r = 1;
  if ((*s == '+') || (*s == '-'))
    s++;
  if (*s == '0') {
    s++;
    if (*s == 'x') {
      for (s++; *s; s++)
        if (((*s < '0') || (*s > '9')) && ((*s < 'a') || (*s > 'f')) && ((*s < 'A') || (*s > 'F'))) {
          r = 0;
          break;
        }
    } else {
      for (; *s; s++)
        if ((*s < '0') || (*s > '7')) {
          r = 0;
          break;
        }
    }
  } else {
    for (; *s; s++)
      if ((*s < '0') || (*s > '9')) {
        r = 0;
        break;
      }
  }
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_number>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  jne    L29
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L29:
  cmp    $0x30,%al
  jne    L109
  jmp    L67
L81:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L27
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L109:
  test   %al,%al
  jne    L81
L147:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L67:
  movzbl 0x1(%rdi),%eax
  cmp    $0x78,%al
  je     L105
  add    $0x1,%rdi
  test   %al,%al
  jne    L49
  jmp    L147
  nopw   0x0(%rax,%rax,1)
L94:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L147
L49:
  sub    $0x30,%eax
  cmp    $0x7,%al
  jbe    L94
L27:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L105:
  movzbl 0x2(%rdi),%eax
  lea    0x2(%rdi),%rdx
  test   %al,%al
  je     L147
  nopl   0x0(%rax)
L21:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L76
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x5,%al
  ja     L27
L76:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L21
  jmp    L147
```

assistant: ```c
int is_number(char *s) {
  int r = 1;
  if ((*s == '+') || (*s == '-'))
    s++;
  if (*s == '0') {
    s++;
    if (*s == 'x') {
      for (s++; *s; s++)
        if (((*s < '0') || (*s > '9')) && ((*s < 'a') || (*s > 'f')) && ((*s < 'A') || (*s > 'F'))) {
          r = 0;
          break;
        }
    } else {
      for (; *s; s++)
        if ((*s < '0') || (*s > '7')) {
          r = 0;
          break;
        }
    }
  } else {
    for (; *s; s++)
      if ((*s < '0') || (*s > '9')) {
        r = 0;
        break;
      }
  }
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_number>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x2b(%rax),%edx
  and    $0xfd,%edx
  jne    L132
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L132:
  cmp    $0x30,%al
  jne    L51
  jmp    L5
L113:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L81
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
L51:
  test   %al,%al
  jne    L113
L125:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L5:
  movzbl 0x1(%rdi),%eax
  cmp    $0x78,%al
  je     L139
  add    $0x1,%rdi
  test   %al,%al
  jne    L44
  jmp    L125
  nopw   0x0(%rax,%rax,1)
L65:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L125
L44:
  sub    $0x30,%eax
  cmp    $0x7,%al
  jbe    L65
L81:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L139:
  movzbl 0x2(%rdi),%eax
  lea    0x2(%rdi),%rdx
  test   %al,%al
  je     L125
  nopl   0x0(%rax)
L73:
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L26
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x5,%al
  ja     L81
L26:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L73
  jmp    L125
```

assistant: ```c
int is_number(char *s) {
  int r = 1;
  if ((*s == '+') || (*s == '-'))
    s++;
  if (*s == '0') {
    s++;
    if (*s == 'x') {
      for (s++; *s; s++)
        if (((*s < '0') || (*s > '9')) && ((*s < 'a') || (*s > 'f')) && ((*s < 'A') || (*s > 'F'))) {
          r = 0;
          break;
        }
    } else {
      for (; *s; s++)
        if ((*s < '0') || (*s > '7')) {
          r = 0;
          break;
        }
    }
  } else {
    for (; *s; s++)
      if ((*s < '0') || (*s > '9')) {
        r = 0;
        break;
      }
  }
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    $0x0,%r15d
  lea    D52(%rip),%r14
  lea    D65(%rip),%r13
  lea    D12(%rip),%r12
  lea    D34(%rip),%rbx
  jmp    L40
L17:
  add    $0x1,%r15d
L13:
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jne    L47
L40:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  je     L17
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebp
  jmp    L13
L47:
  lea    0x0(%rbp,%r15,1),%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %r15d,%xmm0
  movss  %xmm1,0xc(%rsp)
  divss  %xmm1,%xmm0
  mulss  D35(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  divss  0xc(%rsp),%xmm0
  mulss  D35(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D21(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D52
datatype: string
name: unpack_data
arguments: data_tag: D65
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D34
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D35
datatype: byte[4]
name: unpack_data
arguments: data_tag: D4
datatype: string
name: unpack_data
arguments: data_tag: D21
datatype: string

tool: D52: 1-Candidato 1 

tool: D65: 2-Candidato 2 

tool: D12: Escolha voto 

tool: D34: %d

tool: D15: 
 Deseja continuar(1-s/0-n)

tool: {"D35": [0x00,0x00,0xc8,0x42]}

tool: D4: 
Candidato 1 com %.2f%%

tool: D21: 
Candidato 2 com %.2f%% 


assistant: ```c
int main() {
  float perc1, perc2;
  int votos1 = 0, votos2 = 0, voto;
  int continuar;
  float total = 0.00;
  do {
    printf("1-Candidato 1 \n");
    printf("2-Candidato 2 \n");
    printf("Escolha voto \n");
    scanf("%d", &voto);
    if (voto == 1) {
      votos1++;
    }
    if (voto == 2) {
      votos2++;
    }
    printf("\n Deseja continuar(1-s/0-n)");
    scanf("%d", &continuar);
  } while (continuar == 1);
  total = votos1 + votos2;
  perc1 = (votos1 / total);
  perc2 = (votos2 / total);
  printf("\nCandidato 1 com %.2f%%", perc1 * 100);
  printf("\nCandidato 2 com %.2f%% \n", perc2 * 100);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  lea    D49(%rip),%r15
  push   %r14
  lea    D76(%rip),%r14
  push   %r13
  lea    D72(%rip),%r13
  push   %r12
  push   %rbp
  lea    D53(%rip),%rbp
  push   %rbx
  lea    D47(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  lea    0x10(%rsp),%r12
  movl   $0x0,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %rax,(%rsp)
  jmp    L13
  nopl   (%rax)
L23:
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  add    %eax,0x8(%rsp)
L32:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    (%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpl   $0x1,0x14(%rsp)
  jne    L33
L13:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  cmp    $0x1,%eax
  jne    L23
  addl   $0x1,0xc(%rsp)
  jmp    L32
  nopl   (%rax)
L33:
  mov    0x8(%rsp),%ebx
  mov    0xc(%rsp),%ecx
  pxor   %xmm1,%xmm1
  pxor   %xmm0,%xmm0
  lea    D29(%rip),%rdi
  mov    %ebx,%eax
  cvtsi2ss %ecx,%xmm0
  add    %ecx,%eax
  cvtsi2ss %eax,%xmm1
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  movss  %xmm1,(%rsp)
  mulss  D0(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  movss  (%rsp),%xmm1
  cvtsi2ss %ebx,%xmm0
  lea    D58(%rip),%rdi
  mov    $0x1,%eax
  divss  %xmm1,%xmm0
  mulss  D0(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D49
datatype: string
name: unpack_data
arguments: label: D76
datatype: string
name: unpack_data
arguments: label: D72
datatype: string
name: unpack_data
arguments: label: D53
datatype: string
name: unpack_data
arguments: label: D47
datatype: string
name: unpack_data
arguments: label: D29
datatype: string
name: unpack_data
arguments: label: D0
datatype: byte[4]
name: unpack_data
arguments: label: D58
datatype: string

tool: D49: 1-Candidato 1 

tool: D76: 2-Candidato 2 

tool: D72: Escolha voto 

tool: D53: 
 Deseja continuar(1-s/0-n)

tool: D47: %d

tool: D29: 
Candidato 1 com %.2f%%

tool: {"D0": [0x00,0x00,0xc8,0x42]}

tool: D58: 
Candidato 2 com %.2f%% 


assistant: ```c
int main() {
  float perc1, perc2;
  int votos1 = 0, votos2 = 0, voto;
  int continuar;
  float total = 0.00;
  do {
    printf("1-Candidato 1 \n");
    printf("2-Candidato 2 \n");
    printf("Escolha voto \n");
    scanf("%d", &voto);
    if (voto == 1) {
      votos1++;
    }
    if (voto == 2) {
      votos2++;
    }
    printf("\n Deseja continuar(1-s/0-n)");
    scanf("%d", &continuar);
  } while (continuar == 1);
  total = votos1 + votos2;
  perc1 = (votos1 / total);
  perc2 = (votos2 / total);
  printf("\nCandidato 1 com %.2f%%", perc1 * 100);
  printf("\nCandidato 2 com %.2f%% \n", perc2 * 100);
  return 0;
}
```