ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<parse_fd>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L22
  mov    $0x0,%edx
L5:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L26
  add    $0x1,%rdi
  lea    (%rdx,%rdx,4),%edx
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  cmpb   $0x0,(%rdi)
  jne    L5
  jmp    L29
L22:
  mov    $0xffffffff,%edx
  jmp    L29
L26:
  mov    $0xffffffff,%edx
L29:
  mov    %edx,%eax
  ret
```

assistant: ```c
int parse_fd(const char *s) {
  if (!*s) {
    return -1;
  }
  int val = 0;
  do {
    if (*s < '0' || *s > '9') {
      return -1;
    }
    int digit = *s++ - '0';
    val = val * 10 + digit;
  } while (*s);
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_fd>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L24
  xor    %r8d,%r8d
  jmp    L12
L1:
  movsbl %al,%eax
  add    $0x1,%rdi
  lea    (%r8,%r8,4),%edx
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
L12:
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L1
L24:
  mov    $0xffffffff,%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parse_fd(const char *s) {
  if (!*s) {
    return -1;
  }
  int val = 0;
  do {
    if (*s < '0' || *s > '9') {
      return -1;
    }
    int digit = *s++ - '0';
    val = val * 10 + digit;
  } while (*s);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_fd>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L23
  xor    %r8d,%r8d
  jmp    L29
  xchg   %ax,%ax
L15:
  add    $0x1,%rdi
  lea    (%r8,%r8,4),%edx
  movsbl %al,%eax
  cmpb   $0x0,(%rdi)
  lea    (%rax,%rdx,2),%r8d
  je     L22
L29:
  movzbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L15
L23:
  mov    $0xffffffff,%r8d
L22:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int parse_fd(const char *s) {
  if (!*s) {
    return -1;
  }
  int val = 0;
  do {
    if (*s < '0' || *s > '9') {
      return -1;
    }
    int digit = *s++ - '0';
    val = val * 10 + digit;
  } while (*s);
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<btdev_destroy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <del_btdev@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L14
L16:
  nop
L14:
  leave
  ret
```

assistant: ```c
void btdev_destroy(struct btdev *btdev) {
  if (!btdev)
    return;
  del_btdev(btdev);
  free(btdev);
}
```
user: Translate the below assembly code into C programming language:

```asm
<btdev_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %rbx
  mov    %rdi,%rbx
  call   <del_btdev@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
L0:
  ret
```

assistant: ```c
void btdev_destroy(struct btdev *btdev) {
  if (!btdev)
    return;
  del_btdev(btdev);
  free(btdev);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<btdev_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbp
  mov    %rdi,%rbp
  call   <del_btdev@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void btdev_destroy(struct btdev *btdev) {
  if (!btdev)
    return;
  del_btdev(btdev);
  free(btdev);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<btdev_destroy>:
  endbr64
  test   %rdi,%rdi
  je     L9
  push   %rbp
  mov    %rdi,%rbp
  call   <del_btdev@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
void btdev_destroy(struct btdev *btdev) {
  if (!btdev)
    return;
  del_btdev(btdev);
  free(btdev);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<add_double_circle>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x150,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    $0x0,%eax
  mov    $0x40200,%edx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  mov    $0x20400,%eax
  mov    $0x40200,%edx
  mov    %rax,0x20(%rsp)
  mov    %rdx,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  mov    $0x0,%ebx
  mov    %rsp,%r12
  jmp    L45
L4:
  movsbl %al,%eax
  sub    $0x37,%eax
L34:
  movsbl (%rbx,%r12,1),%edx
  or     %edx,%eax
  lea    0x30(%rax),%ecx
  lea    0x37(%rax),%edx
  cmp    $0x9,%eax
  mov    %ecx,%eax
  cmovg  %edx,%eax
  mov    %al,0x40(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x40,%rbx
  je     L14
L45:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%rbp,%rbx,1)
  cmp    $0x39,%al
  jg     L4
  movsbl %al,%eax
  sub    $0x30,%eax
  jmp    L34
L14:
  movb   $0xa,0x80(%rsp)
  movb   $0x0,0x81(%rsp)
  lea    0x40(%rsp),%rsi
  mov    $0x42,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void add_double_circle(char *glyphstring) {
  char newstring[256];
  char circle[64] = {0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x2, 0x4, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x4, 0x2, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x2, 0x4, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0};
  int digit1, digit2;
  int i;
  for (i = 0; i < 64; i++) {
    glyphstring[i] = toupper(glyphstring[i]);
    digit1 = (glyphstring[i] <= '9') ? (glyphstring[i] - '0') : (glyphstring[i] - 'A' + 0xA);
    digit2 = digit1 | circle[i];
    newstring[i] = (digit2 <= 9) ? ('0' + digit2) : ('A' + digit2 - 0xA);
  }
  newstring[i++] = '\n';
  newstring[i++] = '\0';
  strncpy(glyphstring, newstring, i);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_double_circle>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  movdqa D18(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  lea    0x40(%rsp),%rbp
  movaps %xmm1,0x10(%rsp)
  movdqa D7(%rip),%xmm1
  movaps %xmm0,0x30(%rsp)
  movaps %xmm1,0x20(%rsp)
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl %al,%eax
  sub    $0x30,%eax
L7:
  movsbl (%rbx,%r12,1),%edx
  or     %edx,%eax
  lea    0x30(%rax),%ecx
  cmp    $0x9,%eax
  lea    0x37(%rax),%edx
  mov    %ecx,%eax
  cmovg  %edx,%eax
  mov    %al,0x0(%rbp,%r12,1)
  add    $0x1,%r12
  cmp    $0x40,%r12
  je     L38
L35:
  movsbl 0x0(%r13,%r12,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%r13,%r12,1)
  cmp    $0x39,%al
  jle    L4
  sub    $0x37,%eax
  movsbl %al,%eax
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    $0xa,%eax
  mov    $0x42,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %ax,0x80(%rsp)
  call   <strncpy@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x158,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: byte[16]
name: parse_data
arguments: data_label: D7
data_type: byte[16]

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x04,0x00,0x00,0x00,0x00,0x00]}

tool: {"D7": [0x00,0x04,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x04,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void add_double_circle(char *glyphstring) {
  char newstring[256];
  char circle[64] = {0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x2, 0x4, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x4, 0x2, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x2, 0x4, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0};
  int digit1, digit2;
  int i;
  for (i = 0; i < 64; i++) {
    glyphstring[i] = toupper(glyphstring[i]);
    digit1 = (glyphstring[i] <= '9') ? (glyphstring[i] - '0') : (glyphstring[i] - 'A' + 0xA);
    digit2 = digit1 | circle[i];
    newstring[i] = (digit2 <= 9) ? ('0' + digit2) : ('A' + digit2 - 0xA);
  }
  newstring[i++] = '\n';
  newstring[i++] = '\0';
  strncpy(glyphstring, newstring, i);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<add_double_circle>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x158,%rsp
  movdqa D8(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  lea    0x40(%rsp),%rbp
  movaps %xmm1,0x10(%rsp)
  movdqa D2(%rip),%xmm1
  movaps %xmm0,0x30(%rsp)
  movaps %xmm1,0x20(%rsp)
  nopl   0x0(%rax)
L11:
  movsbl 0x0(%r13,%r12,1),%edi
  call   <toupper@plt>
  mov    %al,0x0(%r13,%r12,1)
  cmp    $0x39,%al
  jg     L56
  movsbl %al,%eax
  sub    $0x30,%eax
L7:
  movsbl (%rbx,%r12,1),%edx
  or     %edx,%eax
  cmp    $0x9,%eax
  jg     L23
  add    $0x30,%eax
  mov    %al,0x0(%rbp,%r12,1)
  add    $0x1,%r12
  cmp    $0x40,%r12
  jne    L11
L31:
  mov    $0xa,%eax
  mov    $0x42,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %ax,0x80(%rsp)
  call   <strncpy@plt>
  mov    0x148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x158,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  add    $0x37,%eax
  mov    %al,0x0(%rbp,%r12,1)
  add    $0x1,%r12
  cmp    $0x40,%r12
  jne    L11
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L56:
  sub    $0x37,%eax
  movsbl %al,%eax
  jmp    L7
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: byte[16]
name: disassemble_data
arguments: data_label: D2
datatype: byte[16]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x04,0x00,0x00,0x00,0x00,0x00]}

tool: {"D2": [0x00,0x04,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x02,0x04,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void add_double_circle(char *glyphstring) {
  char newstring[256];
  char circle[64] = {0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x2, 0x4, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x4, 0x2, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x2, 0x4, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0, 0x0};
  int digit1, digit2;
  int i;
  for (i = 0; i < 64; i++) {
    glyphstring[i] = toupper(glyphstring[i]);
    digit1 = (glyphstring[i] <= '9') ? (glyphstring[i] - '0') : (glyphstring[i] - 'A' + 0xA);
    digit2 = digit1 | circle[i];
    newstring[i] = (digit2 <= 9) ? ('0' + digit2) : ('A' + digit2 - 0xA);
  }
  newstring[i++] = '\n';
  newstring[i++] = '\0';
  strncpy(glyphstring, newstring, i);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <tcgetattr@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    D56(%rip),%rax
  mov    (%rax),%ecx
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%ecx
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  mov    D33(%rip),%rax
  mov    (%rax),%ecx
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  lea    -0x14(%rbp),%rdx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <tcsetattr@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int getch(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    D21(%rip),%rbx
  mov    %rbp,%rsi
  mov    (%rbx),%edi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    D14(%rip),%rdx
  or     (%rdx),%eax
  not    %eax
  and    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    D19(%rip),%r13
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdx
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %r12d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D24(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D23(%rip),%rbp
  mov    D34(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D1(%rip),%rax
  mov    0x0(%rbp),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getch>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D25(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    (%rbx),%edi
  mov    %r13,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D13(%rip),%rbp
  mov    D4(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D26(%rip),%rax
  mov    0x0(%rbp),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%rbp),%esi
  mov    (%rbx),%edi
  mov    %r13,%rdx
  mov    %eax,%r12d
  call   <tcsetattr@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getch(void) {
  struct termios oldattr, newattr;
  int ch;
  tcgetattr(STDIN_FILENO, &oldattr);
  newattr = oldattr;
  newattr.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newattr);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldattr);
  return ch;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L109
L68:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L85
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jg     L82
L85:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x47,%al
  jne    L13
  shlq   $0x1e,-0x8(%rbp)
  jmp    L41
L13:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L23
  shlq   $0x14,-0x8(%rbp)
  jmp    L41
L23:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4b,%al
  jne    L86
  shlq   $0xa,-0x8(%rbp)
  jmp    L41
L86:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x42,%al
  jmp    L41
L82:
  addq   $0x1,-0x10(%rbp)
L109:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
L41:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t get_size(char *buf) {
  char *p;
  size_t size;
  size = atoi(buf);
  for (p = buf; *p != '\0'; p++) {
    if (*p > '9' || *p < '0') {
      if (*p == 'G') {
        size *= 1024 * 1024 * 1024;
        break;
      } else if (*p == 'M') {
        size *= 1024 * 1024;
        break;
      } else if (*p == 'K') {
        size *= 1024;
        break;
      } else if (*p == 'B') {
        break;
      } else {
        break;
      }
    }
  }
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_size>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <atoi@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L38
L39:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L8
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L39
L38:
  pop    %rbx
  ret
L8:
  cmp    $0x47,%dl
  je     L20
  cmp    $0x4d,%dl
  je     L76
  mov    %rax,%rcx
  shl    $0xa,%rcx
  cmp    $0x4b,%dl
  cmove  %rcx,%rax
  jmp    L38
L20:
  shl    $0x1e,%rax
  jmp    L38
L76:
  shl    $0x14,%rax
  jmp    L38
```

assistant: ```c
size_t get_size(char *buf) {
  char *p;
  size_t size;
  size = atoi(buf);
  for (p = buf; *p != '\0'; p++) {
    if (*p > '9' || *p < '0') {
      if (*p == 'G') {
        size *= 1024 * 1024 * 1024;
        break;
      } else if (*p == 'M') {
        size *= 1024 * 1024;
        break;
      } else if (*p == 'K') {
        size *= 1024;
        break;
      } else if (*p == 'B') {
        break;
      } else {
        break;
      }
    }
  }
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_size>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <atoi@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L1
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L53:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  je     L9
L1:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L53
  cmp    $0x47,%dl
  je     L3
  cmp    $0x4d,%dl
  je     L33
  mov    %rax,%rcx
  shl    $0xa,%rcx
  cmp    $0x4b,%dl
  cmove  %rcx,%rax
L9:
  pop    %rbx
  ret
  xchg   %ax,%ax
L3:
  shl    $0x1e,%rax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  shl    $0x14,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t get_size(char *buf) {
  char *p;
  size_t size;
  size = atoi(buf);
  for (p = buf; *p != '\0'; p++) {
    if (*p > '9' || *p < '0') {
      if (*p == 'G') {
        size *= 1024 * 1024 * 1024;
        break;
      } else if (*p == 'M') {
        size *= 1024 * 1024;
        break;
      } else if (*p == 'K') {
        size *= 1024;
        break;
      } else if (*p == 'B') {
        break;
      } else {
        break;
      }
    }
  }
  return size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_size>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <atoi@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L36
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L39:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  je     L23
L36:
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  jbe    L39
  cmp    $0x47,%dl
  je     L44
  cmp    $0x4d,%dl
  je     L5
  mov    %rax,%rcx
  shl    $0xa,%rcx
  cmp    $0x4b,%dl
  cmove  %rcx,%rax
L23:
  pop    %rbx
  ret
  xchg   %ax,%ax
L44:
  shl    $0x1e,%rax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  shl    $0x14,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t get_size(char *buf) {
  char *p;
  size_t size;
  size = atoi(buf);
  for (p = buf; *p != '\0'; p++) {
    if (*p > '9' || *p < '0') {
      if (*p == 'G') {
        size *= 1024 * 1024 * 1024;
        break;
      } else if (*p == 'M') {
        size *= 1024 * 1024;
        break;
      } else if (*p == 'K') {
        size *= 1024;
        break;
      } else if (*p == 'B') {
        break;
      } else {
        break;
      }
    }
  }
  return size;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<section_start>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mgetsize@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L2
  mov    $0x0,%eax
  call   <msynch@plt>
  mov    $0x0,%eax
  call   <mgetuleb128@plt>
  mov    %eax,%edi
  call   <mputuleb128@plt>
  mov    $0x0,%eax
  call   <msynch@plt>
  add    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <msetsize@plt>
  add    %rax,-0x18(%rbp)
  jmp    L10
L2:
  mov    $0x0,%eax
  call   <msynch@plt>
  add    %rax,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
long section_start() {
  unsigned long off0, off1;
  unsigned long len;
  long delta = 0;
  len = mgetsize(&off0, &off1);
  if (len) {
    msynch();
    mputuleb128(mgetuleb128());
    delta += msynch();
    delta += msetsize(off0, off1, delta);
  } else {
    delta += msynch();
  }
  return delta;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<section_start>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <mgetsize@plt>
  test   %rax,%rax
  je     L24
  mov    $0x0,%eax
  call   <msynch@plt>
  mov    $0x0,%eax
  call   <mgetuleb128@plt>
  mov    %eax,%edi
  call   <mputuleb128@plt>
  mov    $0x0,%eax
  call   <msynch@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  call   <msetsize@plt>
  add    %rbx,%rax
L4:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x20,%rsp
  pop    %rbx
  ret
L24:
  mov    $0x0,%eax
  call   <msynch@plt>
  jmp    L4
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long section_start() {
  unsigned long off0, off1;
  unsigned long len;
  long delta = 0;
  len = mgetsize(&off0, &off1);
  if (len) {
    msynch();
    mputuleb128(mgetuleb128());
    delta += msynch();
    delta += msetsize(off0, off1, delta);
  } else {
    delta += msynch();
  }
  return delta;
}
```