ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printhash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x40(%rdi),%r12
  lea    D8(%rip),%rbp
L4:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L4
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 64; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printhash>:
  endbr64
  push   %r12
  lea    0x40(%rdi),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L0:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 64; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printhash>:
  endbr64
  push   %r12
  lea    0x40(%rdi),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L3
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: %02X

assistant: ```c
void printhash(unsigned char *hash) {
  int i;
  for (i = 0; i < 64; ++i) {
    printf("%02X", hash[i]);
  }
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<isocket_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int isocket_init(void) {
  int retval = 0;
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isocket_init>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int isocket_init(void) {
  int retval = 0;
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<isocket_init>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int isocket_init(void) {
  int retval = 0;
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isocket_init>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int isocket_init(void) {
  int retval = 0;
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_binary_rep>:
  endbr64
  sub    $0x48,%rsp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    D30(%rip),%rsi
  call   <sprintf@plt>
  movsd  0x8(%rsp),%xmm3
  ucomisd D35(%rip),%xmm3
  setp   %dl
  mov    $0x1,%ecx
  cmovne %ecx,%edx
  test   %dl,%dl
  je     L47
  cmp    $0x21,%rax
  ja     L47
  lea    0xf(%rsp),%rdi
  pxor   %xmm2,%xmm2
  mov    $0x1,%esi
L48:
  movsd  0x8(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  cvttsd2si %xmm0,%ecx
  cmp    $0x1,%ecx
  sete   %dl
  add    $0x30,%edx
  add    $0x1,%rax
  mov    %dl,(%rdi,%rax,1)
  pxor   %xmm1,%xmm1
  cvtsi2sd %ecx,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  ucomisd %xmm2,%xmm0
  setp   %dl
  cmovne %esi,%edx
  test   %dl,%dl
  je     L47
  cmp    $0x21,%rax
  jbe    L48
L47:
  movsd  0x8(%rsp),%xmm4
  ucomisd D35(%rip),%xmm4
  jp     L74
  jne    L74
  movb   $0x0,0x10(%rsp,%rax,1)
L58:
  lea    0x10(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x48,%rsp
  ret
L74:
  lea    0x10(%rsp),%rdi
  lea    D19(%rip),%rsi
  call   <sprintf@plt>
  jmp    L58
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D30
type_guessed: string
name: parse_data
arguments: data_label: D35
type_guessed: byte[8]
name: parse_data
arguments: data_label: D28
type_guessed: string
name: parse_data
arguments: data_label: D19
type_guessed: string

tool: D30: 0.

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D28: %s


tool: D19: ERROR

assistant: ```c
void print_binary_rep(double n) {
  static size_t max_bits = 32;
  char buff[max_bits + 3];
  size_t cursor = 0;
  cursor += sprintf(buff, "0.");
  while (n != 0 && cursor < 34) {
    double new_n = n * 2;
    int new_n_as_int = new_n;
    buff[cursor++] = (new_n_as_int == 1 ? '1' : '0');
    n = new_n - new_n_as_int;
  }
  if (n != 0) {
    sprintf(buff, "ERROR");
  } else {
    buff[cursor] = '\0';
  }
  printf("%s\n", buff);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_binary_rep>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rsi
  sub    $0x40,%rsp
  lea    0x10(%rsp),%rbp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <sprintf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm2,%xmm2
  cmp    $0x21,%rax
  ja     L3
  ucomisd %xmm2,%xmm0
  mov    $0x1,%ecx
  setp   %dl
  cmovne %ecx,%edx
  test   %dl,%dl
  je     L3
  lea    0xf(%rsp),%rdi
  mov    $0x1,%esi
L71:
  addsd  %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvttsd2si %xmm0,%ecx
  cvtsi2sd %ecx,%xmm1
  cmp    $0x1,%ecx
  sete   %dl
  add    $0x1,%rax
  add    $0x30,%edx
  mov    %dl,(%rdi,%rax,1)
  subsd  %xmm1,%xmm0
  ucomisd %xmm2,%xmm0
  setp   %dl
  cmovne %esi,%edx
  test   %dl,%dl
  je     L3
  cmp    $0x21,%rax
  jbe    L71
L3:
  ucomisd %xmm2,%xmm0
  jp     L40
  jne    L40
  movb   $0x0,0x10(%rsp,%rax,1)
L74:
  mov    %rbp,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x40,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  lea    D7(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L74
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D12
datatype: string
name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string

tool: D12: 0.

tool: D17: %s


tool: D7: ERROR

assistant: ```c
void print_binary_rep(double n) {
  static size_t max_bits = 32;
  char buff[max_bits + 3];
  size_t cursor = 0;
  cursor += sprintf(buff, "0.");
  while (n != 0 && cursor < 34) {
    double new_n = n * 2;
    int new_n_as_int = new_n;
    buff[cursor++] = (new_n_as_int == 1 ? '1' : '0');
    n = new_n - new_n_as_int;
  }
  if (n != 0) {
    sprintf(buff, "ERROR");
  } else {
    buff[cursor] = '\0';
  }
  printf("%s\n", buff);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_binary_rep>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rsi
  sub    $0x40,%rsp
  lea    0x10(%rsp),%rbp
  movsd  %xmm0,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <sprintf@plt>
  movsd  0x8(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cmp    $0x21,%rax
  ja     L52
  ucomisd %xmm1,%xmm0
  mov    $0x1,%ecx
  setp   %dl
  cmovne %ecx,%edx
  test   %dl,%dl
  je     L52
  movsd  D21(%rip),%xmm3
  lea    0xf(%rsp),%rcx
  mov    $0x1,%esi
  nopl   0x0(%rax,%rax,1)
L32:
  addsd  %xmm0,%xmm0
  add    $0x1,%rax
  cvttsd2si %xmm0,%edx
  cmp    $0x1,%edx
  je     L86
  pxor   %xmm2,%xmm2
  movb   $0x30,(%rcx,%rax,1)
  cvtsi2sd %edx,%xmm2
  subsd  %xmm2,%xmm0
  ucomisd %xmm1,%xmm0
  setp   %dl
  cmovne %esi,%edx
  test   %dl,%dl
  je     L52
  cmp    $0x21,%rax
  jbe    L32
L52:
  ucomisd %xmm1,%xmm0
  jp     L109
  jne    L109
  movb   $0x0,0x10(%rsp,%rax,1)
L36:
  mov    %rbp,%rsi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x40,%rsp
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  movb   $0x31,(%rcx,%rax,1)
  subsd  %xmm3,%xmm0
  cmp    $0x21,%rax
  ja     L52
  ucomisd %xmm1,%xmm0
  setp   %dl
  cmovne %esi,%edx
  test   %dl,%dl
  jne    L32
  jmp    L52
  nopw   0x0(%rax,%rax,1)
L109:
  lea    D38(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  jmp    L36
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D21
data_type: byte[8]
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string
name: extract_symbolic_data
arguments: data_tag: D38
data_type: string

tool: D5: 0.

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D18: %s


tool: D38: ERROR

assistant: ```c
void print_binary_rep(double n) {
  static size_t max_bits = 32;
  char buff[max_bits + 3];
  size_t cursor = 0;
  cursor += sprintf(buff, "0.");
  while (n != 0 && cursor < 34) {
    double new_n = n * 2;
    int new_n_as_int = new_n;
    buff[cursor++] = (new_n_as_int == 1 ? '1' : '0');
    n = new_n - new_n_as_int;
  }
  if (n != 0) {
    sprintf(buff, "ERROR");
  } else {
    buff[cursor] = '\0';
  }
  printf("%s\n", buff);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L18:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  D21(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D3(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  D2(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x3ff,-0x4(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
type_infered: f64
name: unpack_data
arguments: tag: D3
type_infered: f64
name: unpack_data
arguments: tag: D2
type_infered: f64

tool: D21: 4

tool: D3: 1

tool: D2: 2

assistant: ```c
void __attribute__((no, noclone)) foo(double *b, double *d, double *f) {
  int i;
  for (i = 0; i < 1024; i++) {
    d[2 * i] = 2. * d[2 * i];
    d[2 * i + 1] = 4. * d[2 * i + 1];
    b[i] = d[2 * i] - 1.;
    f[i] = d[2 * i + 1] + 2.;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  mov    $0x0,%eax
  movsd  D23(%rip),%xmm4
  movsd  D1(%rip),%xmm3
  movsd  D22(%rip),%xmm2
L6:
  movsd  (%rsi),%xmm0
  addsd  %xmm0,%xmm0
  movsd  %xmm0,(%rsi)
  movapd %xmm4,%xmm1
  mulsd  0x8(%rsi),%xmm1
  movsd  %xmm1,0x8(%rsi)
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%rdi,%rax,1)
  movapd %xmm2,%xmm0
  addsd  0x8(%rsi),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x10,%rsi
  add    $0x8,%rax
  cmp    $0x2000,%rax
  jne    L6
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D23
data_type: f64
name: disassemble_data
arguments: tag: D1
data_type: f64
name: disassemble_data
arguments: tag: D22
data_type: f64

tool: D23: 4

tool: D1: 1

tool: D22: 2

assistant: ```c
void __attribute__((no, noclone)) foo(double *b, double *d, double *f) {
  int i;
  for (i = 0; i < 1024; i++) {
    d[2 * i] = 2. * d[2 * i];
    d[2 * i + 1] = 4. * d[2 * i + 1];
    b[i] = d[2 * i] - 1.;
    f[i] = d[2 * i + 1] + 2.;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  movsd  D11(%rip),%xmm4
  movsd  D29(%rip),%xmm3
  xor    %eax,%eax
  movsd  D28(%rip),%xmm2
  xchg   %ax,%ax
L0:
  movsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  add    $0x10,%rsi
  addsd  %xmm0,%xmm0
  mulsd  %xmm4,%xmm1
  movsd  %xmm0,-0x10(%rsi)
  subsd  %xmm3,%xmm0
  movsd  %xmm1,-0x8(%rsi)
  movsd  %xmm0,(%rdi,%rax,1)
  movsd  -0x8(%rsi),%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x2000,%rax
  jne    L0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D11
type_guessed: f64
name: disassemble_data
arguments: data_label: D29
type_guessed: f64
name: disassemble_data
arguments: data_label: D28
type_guessed: f64

tool: D11: 4

tool: D29: 1

tool: D28: 2

assistant: ```c
void __attribute__((no, noclone)) foo(double *b, double *d, double *f) {
  int i;
  for (i = 0; i < 1024; i++) {
    d[2 * i] = 2. * d[2 * i];
    d[2 * i + 1] = 4. * d[2 * i + 1];
    b[i] = d[2 * i] - 1.;
    f[i] = d[2 * i + 1] + 2.;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  lea    0x2000(%rdx),%rax
  lea    0x4000(%rsi),%r8
  mov    %rdi,%rcx
  cmp    %rax,%rsi
  setae  %dil
  cmp    %r8,%rdx
  setae  %al
  or     %eax,%edi
  lea    0x2000(%rcx),%rax
  cmp    %rax,%rsi
  setae  %al
  cmp    %r8,%rcx
  setae  %r8b
  or     %r8d,%eax
  test   %al,%dil
  je     L20
  lea    0x8(%rcx),%rax
  cmp    %rax,%rdx
  je     L20
  movapd D28(%rip),%xmm3
  movapd D3(%rip),%xmm5
  xor    %eax,%eax
  movapd D50(%rip),%xmm4
  nopl   0x0(%rax,%rax,1)
L37:
  movupd (%rsi),%xmm0
  movupd 0x10(%rsi),%xmm1
  add    $0x20,%rsi
  mulpd  %xmm3,%xmm0
  mulpd  %xmm3,%xmm1
  movapd %xmm0,%xmm2
  movups %xmm0,-0x20(%rsi)
  unpcklpd %xmm1,%xmm2
  unpckhpd %xmm1,%xmm0
  movups %xmm1,-0x10(%rsi)
  addpd  %xmm5,%xmm2
  addpd  %xmm4,%xmm0
  movups %xmm2,(%rcx,%rax,1)
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    $0x2000,%rax
  jne    L37
  ret
L20:
  movsd  D31(%rip),%xmm4
  movsd  D58(%rip),%xmm3
  xor    %eax,%eax
  movsd  D28(%rip),%xmm2
  nopl   0x0(%rax,%rax,1)
L15:
  movsd  (%rsi),%xmm0
  movsd  0x8(%rsi),%xmm1
  add    $0x10,%rsi
  addsd  %xmm0,%xmm0
  mulsd  %xmm4,%xmm1
  movsd  %xmm0,-0x10(%rsi)
  subsd  %xmm3,%xmm0
  movsd  %xmm1,-0x8(%rsi)
  movsd  %xmm0,(%rcx,%rax,1)
  movsd  -0x8(%rsi),%xmm0
  addsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x2000,%rax
  jne    L15
  ret
```

tool_calls: name: parse_data
arguments: tag: D28
type_guessed: f64[2]
name: parse_data
arguments: tag: D3
type_guessed: byte[16]
name: parse_data
arguments: tag: D50
type_guessed: f64[2]
name: parse_data
arguments: tag: D31
type_guessed: f64
name: parse_data
arguments: tag: D58
type_guessed: f64

tool: {"D28": [2.0,4.0]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0xbf]}

tool: {"D50": [2.0,2.0]}

tool: D31: 4

tool: D58: 1

assistant: ```c
void __attribute__((no, noclone)) foo(double *b, double *d, double *f) {
  int i;
  for (i = 0; i < 1024; i++) {
    d[2 * i] = 2. * d[2 * i];
    d[2 * i + 1] = 4. * d[2 * i + 1];
    b[i] = d[2 * i] - 1.;
    f[i] = d[2 * i + 1] + 2.;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  lea    0x20(%rsp),%rbx
  mov    0xc(%rsp),%r8d
  mov    0x8(%rsp),%ecx
  lea    D66(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x10(%rsp),%rdi
  call   <pipe@plt>
  lea    0x18(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  je     L30
  js     L24
L49:
  lea    0x20(%rsp),%rbx
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    0x14(%rsp),%edi
  call   <write@plt>
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  call   <close@plt>
  mov    $0x400,%edx
  mov    %rbx,%rsi
  mov    0x18(%rsp),%edi
  call   <read@plt>
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x438,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    $0x0,%esi
  mov    0x10(%rsp),%edi
  call   <dup2@plt>
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    $0x1,%esi
  mov    0x1c(%rsp),%edi
  call   <dup2@plt>
  mov    0x18(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  call   <close@plt>
  mov    $0x0,%ecx
  lea    D18(%rip),%rdx
  lea    D46(%rip),%rdi
  mov    %rdi,%rsi
  call   <execlp@plt>
  lea    D36(%rip),%rdi
  call   <die@plt>
  jmp    L49
L24:
  lea    D42(%rip),%rdi
  call   <die@plt>
  jmp    L49
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D6
type_infered: string
name: read_data
arguments: label: D66
type_infered: string
name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D18
type_infered: string
name: read_data
arguments: label: D46
type_infered: string
name: read_data
arguments: label: D36
type_infered: string
name: read_data
arguments: label: D42
type_infered: string

tool: D6: %d%d

tool: D66: %d + %d


tool: D12: %s

tool: D18: --quiet

tool: D46: /usr/bin/bc

tool: D36: execlp failed

tool: D42: fork failed

assistant: ```c
int main(void) {
  int a, b, blen, pid;
  char buf[1024];
  int fd1[2], fd2[2];
  scanf("%d%d", &a, &b);
  snprintf(buf, sizeof(buf), "%d + %d\n", a, b);
  blen = strlen(buf);
  if (pipe(fd1) < 0) {
  }
  if (pipe(fd2) < 0) {
  }
  if (!(pid = fork())) {
    dup2(fd1[0], 0);
    close(fd1[0]);
    close(fd1[1]);
    dup2(fd2[1], 1);
    close(fd2[0]);
    close(fd2[1]);
    execlp("/usr/bin/bc", "/usr/bin/bc", "--quiet", NULL);
    die("execlp failed");
  } else if (pid < 0) {
    die("fork failed");
  }
  write(fd1[1], buf, blen);
  close(fd1[0]);
  close(fd1[1]);
  close(fd2[1]);
  blen = read(fd2[0], buf, sizeof(buf));
  buf[blen] = 0;
  printf("%s", buf);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D62(%rip),%rdi
  push   %rbp
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rbp
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%r8d
  lea    D34(%rip),%rdx
  mov    $0x400,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x10(%rsp),%rdi
  mov    %eax,%r12d
  call   <pipe@plt>
  lea    0x18(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  test   %eax,%eax
  je     L11
  js     L38
L22:
  mov    0x14(%rsp),%edi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <write@plt>
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  call   <close@plt>
  mov    0x18(%rsp),%edi
  mov    %rbp,%rsi
  mov    $0x400,%edx
  call   <read@plt>
  mov    %rbp,%rsi
  lea    D32(%rip),%rdi
  cltq
  movb   $0x0,0x20(%rsp,%rax,1)
  call   <printf@plt>
  mov    0x428(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x438,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    0x10(%rsp),%edi
  xor    %esi,%esi
  call   <dup2@plt>
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    0x14(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  mov    $0x1,%esi
  call   <dup2@plt>
  mov    0x18(%rsp),%edi
  call   <close@plt>
  mov    0x1c(%rsp),%edi
  call   <close@plt>
  lea    D0(%rip),%rdi
  xor    %ecx,%ecx
  lea    D8(%rip),%rdx
  mov    %rdi,%rsi
  call   <execlp@plt>
  lea    D57(%rip),%rdi
  call   <die@plt>
  jmp    L22
L38:
  lea    D21(%rip),%rdi
  call   <die@plt>
  jmp    L22
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D62
type: string
name: retrieve_data
arguments: label: D34
type: string
name: retrieve_data
arguments: label: D32
type: string
name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D8
type: string
name: retrieve_data
arguments: label: D57
type: string
name: retrieve_data
arguments: label: D21
type: string

tool: D62: %d%d

tool: D34: %d + %d


tool: D32: %s

tool: D0: /usr/bin/bc

tool: D8: --quiet

tool: D57: execlp failed

tool: D21: fork failed

assistant: ```c
int main(void) {
  int a, b, blen, pid;
  char buf[1024];
  int fd1[2], fd2[2];
  scanf("%d%d", &a, &b);
  snprintf(buf, sizeof(buf), "%d + %d\n", a, b);
  blen = strlen(buf);
  if (pipe(fd1) < 0) {
  }
  if (pipe(fd2) < 0) {
  }
  if (!(pid = fork())) {
    dup2(fd1[0], 0);
    close(fd1[0]);
    close(fd1[1]);
    dup2(fd2[1], 1);
    close(fd2[0]);
    close(fd2[1]);
    execlp("/usr/bin/bc", "/usr/bin/bc", "--quiet", NULL);
    die("execlp failed");
  } else if (pid < 0) {
    die("fork failed");
  }
  write(fd1[1], buf, blen);
  close(fd1[0]);
  close(fd1[1]);
  close(fd2[1]);
  blen = read(fd2[0], buf, sizeof(buf));
  buf[blen] = 0;
  printf("%s", buf);
  return 0;
}
```