ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<column_number_for_column_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x4(%rbp),%eax
  jmp    L17
L21:
  addl   $0x1,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L20
  mov    $0xffffffff,%eax
L17:
  leave
  ret
```

assistant: ```c
int column_number_for_column_name(char **column_names, char *column_name, int number_of_columns) {
  int i;
  for (i = 0; i < number_of_columns; i++) {
    if (strcmp(column_names[i], column_name) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<column_number_for_column_name>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L13
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
L6:
  mov    %ebx,%r14d
  mov    (%r12,%rbx,8),%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L1
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
  mov    $0xffffffff,%r14d
L1:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    $0xffffffff,%r14d
  jmp    L1
```

assistant: ```c
int column_number_for_column_name(char **column_names, char *column_name, int number_of_columns) {
  int i;
  for (i = 0; i < number_of_columns; i++) {
    if (strcmp(column_names[i], column_name) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<column_number_for_column_name>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L6
  mov    %rdi,%r14
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  jmp    L0
  nopl   (%rax)
L36:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L6
L0:
  mov    (%r14,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L36
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L6:
  mov    $0xffffffff,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int column_number_for_column_name(char **column_names, char *column_name, int number_of_columns) {
  int i;
  for (i = 0; i < number_of_columns; i++) {
    if (strcmp(column_names[i], column_name) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<column_number_for_column_name>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L0
  mov    %rdi,%r14
  mov    %rsi,%r12
  movslq %edx,%rbp
  xor    %ebx,%ebx
  jmp    L1
  nopl   (%rax)
L5:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L0
L1:
  mov    (%r14,%rbx,8),%rdi
  mov    %r12,%rsi
  mov    %ebx,%r13d
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L5
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L0:
  mov    $0xffffffff,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int column_number_for_column_name(char **column_names, char *column_name, int number_of_columns) {
  int i;
  for (i = 0; i < number_of_columns; i++) {
    if (strcmp(column_names[i], column_name) == 0) {
      return i;
    }
  }
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <e_debug_init@plt>
  movl   $0x80800000,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L0
L21:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x20,%rax
  shr    $0x7,%eax
  imul   $0x186a0,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L52
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L52:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <e_debug_write@plt>
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <e_debug_read@plt>
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  je     L2
  mov    -0x18(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L41
L2:
  addl   $0x1,-0x14(%rbp)
L0:
  cmpl   $0x3b9ac9ff,-0x14(%rbp)
  jbe    L21
L41:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
data_type: string
name: parse_data
arguments: tag: D1
data_type: string

tool: D14: LOOP(%d)


tool: D1: LOOP %d: ERROR %08x != %08x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int i;
  unsigned int dstaddr;
  unsigned int data, rdata;
  e_debug_init(0x1);
  dstaddr = 0x80800000;
  for (i = 0; i < 1000000000; i++) {
    data = i;
    if (!(i % 100000)) {
      printf("LOOP(%d)\n", i);
    }
    e_debug_write(dstaddr, data);
    e_debug_read(dstaddr, &rdata);
    if (rdata != data) {
      printf("LOOP %d: ERROR %08x != %08x\n", i, data, rdata);
      break;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <e_debug_init@plt>
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
  jmp    L10
L1:
  mov    %ebx,%esi
  mov    $0x80800000,%edi
  call   <e_debug_write@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x80800000,%edi
  call   <e_debug_read@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebx,%ecx
  jne    L47
  add    $0x1,%ebx
  cmp    $0x3b9aca00,%ebx
  je     L21
L10:
  mov    %ebx,%eax
  shr    $0x5,%eax
  mov    %eax,%eax
  imul   $0xa7c5ac5,%rax,%rax
  shr    $0x27,%rax
  imul   $0x186a0,%eax,%eax
  cmp    %eax,%ebx
  jne    L1
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L47:
  mov    %ebx,%edx
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string

tool: D1: LOOP(%d)


tool: D3: LOOP %d: ERROR %08x != %08x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int i;
  unsigned int dstaddr;
  unsigned int data, rdata;
  e_debug_init(0x1);
  dstaddr = 0x80800000;
  for (i = 0; i < 1000000000; i++) {
    data = i;
    if (!(i % 100000)) {
      printf("LOOP(%d)\n", i);
    }
    e_debug_write(dstaddr, data);
    e_debug_read(dstaddr, &rdata);
    if (rdata != data) {
      printf("LOOP %d: ERROR %08x != %08x\n", i, data, rdata);
      break;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  lea    D15(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <e_debug_init@plt>
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    %ebp,%esi
  mov    $0x80800000,%edi
  call   <e_debug_write@plt>
  mov    %rbx,%rsi
  mov    $0x80800000,%edi
  call   <e_debug_read@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebp,%ecx
  jne    L42
  add    $0x1,%ebp
  cmp    $0x3b9aca00,%ebp
  je     L40
L29:
  imul   $0xbcbe61d,%ebp,%eax
  ror    $0x5,%eax
  cmp    $0xa7c5,%eax
  ja     L23
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %ebp,%edx
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D9
data_type: string

tool: D15: LOOP(%d)


tool: D9: LOOP %d: ERROR %08x != %08x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int i;
  unsigned int dstaddr;
  unsigned int data, rdata;
  e_debug_init(0x1);
  dstaddr = 0x80800000;
  for (i = 0; i < 1000000000; i++) {
    data = i;
    if (!(i % 100000)) {
      printf("LOOP(%d)\n", i);
    }
    e_debug_write(dstaddr, data);
    e_debug_read(dstaddr, &rdata);
    if (rdata != data) {
      printf("LOOP %d: ERROR %08x != %08x\n", i, data, rdata);
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  lea    D13(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  call   <e_debug_init@plt>
  jmp    L35
  cs nopw 0x0(%rax,%rax,1)
L49:
  mov    %ebp,%esi
  mov    $0x80800000,%edi
  call   <e_debug_write@plt>
  mov    %rbx,%rsi
  mov    $0x80800000,%edi
  call   <e_debug_read@plt>
  mov    0x4(%rsp),%ecx
  cmp    %ebp,%ecx
  jne    L29
  add    $0x1,%ebp
  cmp    $0x3b9aca00,%ebp
  je     L19
L35:
  imul   $0xbcbe61d,%ebp,%eax
  ror    $0x5,%eax
  cmp    $0xa7c5,%eax
  ja     L49
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %ebp,%edx
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D19
type_guessed: string

tool: D13: LOOP(%d)


tool: D19: LOOP %d: ERROR %08x != %08x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int i;
  unsigned int dstaddr;
  unsigned int data, rdata;
  e_debug_init(0x1);
  dstaddr = 0x80800000;
  for (i = 0; i < 1000000000; i++) {
    data = i;
    if (!(i % 100000)) {
      printf("LOOP(%d)\n", i);
    }
    e_debug_write(dstaddr, data);
    e_debug_read(dstaddr, &rdata);
    if (rdata != data) {
      printf("LOOP %d: ERROR %08x != %08x\n", i, data, rdata);
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mem_inplace_swap32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L11
L8:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <swap32@plt>
  mov    %eax,(%rbx)
  addq   $0x1,-0x18(%rbp)
L11:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L8
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void mem_inplace_swap32(void *mem, size_t n) {
  size_t i;
  for (i = 0; i < n; i++) {
    ((uint32_t *)mem)[i] = swap32(((const uint32_t *)mem)[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_inplace_swap32>:
  endbr64
  test   %rsi,%rsi
  je     L9
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
L4:
  mov    0x0(%rbp,%rbx,4),%edi
  call   <swap32@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L4
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  ret
```

assistant: ```c
void mem_inplace_swap32(void *mem, size_t n) {
  size_t i;
  for (i = 0; i < n; i++) {
    ((uint32_t *)mem)[i] = swap32(((const uint32_t *)mem)[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mem_inplace_swap32>:
  endbr64
  test   %rsi,%rsi
  je     L0
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L14:
  mov    0x0(%rbp,%rbx,4),%edi
  call   <swap32@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void mem_inplace_swap32(void *mem, size_t n) {
  size_t i;
  for (i = 0; i < n; i++) {
    ((uint32_t *)mem)[i] = swap32(((const uint32_t *)mem)[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_inplace_swap32>:
  endbr64
  test   %rsi,%rsi
  je     L6
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L17:
  mov    0x0(%rbp,%rbx,4),%edi
  call   <swap32@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

assistant: ```c
void mem_inplace_swap32(void *mem, size_t n) {
  size_t i;
  for (i = 0; i < n; i++) {
    ((uint32_t *)mem)[i] = swap32(((const uint32_t *)mem)[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L12:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L12
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D4
data_type: string

tool: D4: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L18
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  lea    D1(%rip),%rbp
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L6
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L11:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
data_type: string

tool: D9: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L14
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x4(%rdi,%rax,4),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: %d	

assistant: ```c
void display(int a[], int n) {
  int i;
  for (i = 0; i < n; i++) {
    printf("%d\t", a[i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  cmp    $0x8,%eax
  jle    L5
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0xd(%rbp)
  mov    $0x8,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %al,-0xd(%rbp)
  jmp    L11
L5:
  mov    -0xc(%rbp),%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  and    %edx,%eax
  mov    %al,-0xd(%rbp)
L11:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x24(%rbp),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  movzbl -0xd(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char get_bits(unsigned char block[64], int *off, int n) {
  char ret;
  int boff = *off / 8, bitpos = *off % 8, mask = (1 << n) - 1;
  if (bitpos + n > 8) {
    ret = block[boff % 64] >> bitpos;
    mask >>= 8 - bitpos;
    ret |= (block[(boff + 1) % 64] & mask) << (8 - bitpos);
  } else {
    ret = (block[boff % 64] >> bitpos) & mask;
  }
  *off += n;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_bits>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %edx,%r11d
  mov    (%rsi),%edi
  lea    0x7(%rdi),%edx
  test   %edi,%edi
  cmovns %edi,%edx
  sar    $0x3,%edx
  mov    %edi,%eax
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  lea    (%rdi,%rax,1),%esi
  and    $0x7,%esi
  sub    %eax,%esi
  mov    $0x1,%r10d
  mov    %r11d,%ecx
  shl    %cl,%r10d
  sub    $0x1,%r10d
  lea    (%rsi,%r11,1),%eax
  cmp    $0x8,%eax
  jle    L3
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  shr    $0x1a,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x3f,%eax
  sub    %ecx,%eax
  cltq
  movzbl (%r9,%rax,1),%eax
  mov    %edi,%ecx
  and    $0x7,%ecx
  sar    %cl,%eax
  mov    $0x8,%ecx
  sub    %esi,%ecx
  add    $0x1,%edx
  mov    %edx,%esi
  sar    $0x1f,%esi
  shr    $0x1a,%esi
  add    %esi,%edx
  and    $0x3f,%edx
  sub    %esi,%edx
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%edx
  sar    %cl,%r10d
  and    %edx,%r10d
  shl    %cl,%r10d
  or     %r10d,%eax
L13:
  lea    (%rdi,%r11,1),%ecx
  mov    %ecx,(%r8)
  ret
L3:
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1a,%eax
  add    %eax,%edx
  and    $0x3f,%edx
  sub    %eax,%edx
  movslq %edx,%rdx
  movzbl (%r9,%rdx,1),%eax
  mov    %edi,%ecx
  and    $0x7,%ecx
  sar    %cl,%eax
  and    %r10d,%eax
  jmp    L13
```

assistant: ```c
unsigned char get_bits(unsigned char block[64], int *off, int n) {
  char ret;
  int boff = *off / 8, bitpos = *off % 8, mask = (1 << n) - 1;
  if (bitpos + n > 8) {
    ret = block[boff % 64] >> bitpos;
    mask >>= 8 - bitpos;
    ret |= (block[(boff + 1) % 64] & mask) << (8 - bitpos);
  } else {
    ret = (block[boff % 64] >> bitpos) & mask;
  }
  *off += n;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_bits>:
  endbr64
  mov    %edx,%r10d
  push   %rbx
  mov    (%rsi),%edx
  mov    %rsi,%r8
  mov    %rdi,%r9
  mov    %r10d,%ecx
  mov    $0x1,%r11d
  test   %edx,%edx
  lea    0x7(%rdx),%esi
  mov    %edx,%eax
  cmovns %edx,%esi
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  mov    %esi,%edi
  lea    (%rdx,%rax,1),%ebx
  sar    $0x1f,%esi
  shr    $0x1a,%esi
  sar    $0x3,%edi
  and    $0x7,%ebx
  sub    %eax,%ebx
  lea    (%rdi,%rsi,1),%eax
  shl    %cl,%r11d
  mov    %edx,%ecx
  and    $0x3f,%eax
  and    $0x7,%ecx
  sub    $0x1,%r11d
  sub    %esi,%eax
  cltq
  movzbl (%r9,%rax,1),%esi
  sar    %cl,%esi
  lea    (%rbx,%r10,1),%ecx
  mov    %esi,%eax
  and    %r11d,%eax
  cmp    $0x8,%ecx
  jle    L2
  add    $0x1,%edi
  mov    $0x8,%ecx
  mov    %edi,%eax
  sub    %ebx,%ecx
  sar    $0x1f,%eax
  sar    %cl,%r11d
  shr    $0x1a,%eax
  add    %eax,%edi
  and    $0x3f,%edi
  sub    %eax,%edi
  movslq %edi,%rdi
  movzbl (%r9,%rdi,1),%eax
  and    %r11d,%eax
  shl    %cl,%eax
  or     %esi,%eax
L2:
  add    %r10d,%edx
  pop    %rbx
  mov    %edx,(%r8)
  ret
```

assistant: ```c
unsigned char get_bits(unsigned char block[64], int *off, int n) {
  char ret;
  int boff = *off / 8, bitpos = *off % 8, mask = (1 << n) - 1;
  if (bitpos + n > 8) {
    ret = block[boff % 64] >> bitpos;
    mask >>= 8 - bitpos;
    ret |= (block[(boff + 1) % 64] & mask) << (8 - bitpos);
  } else {
    ret = (block[boff % 64] >> bitpos) & mask;
  }
  *off += n;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_bits>:
  endbr64
  mov    %edx,%r10d
  push   %rbx
  mov    (%rsi),%edx
  mov    %rsi,%r8
  mov    %rdi,%r9
  mov    %r10d,%ecx
  mov    $0x1,%r11d
  test   %edx,%edx
  lea    0x7(%rdx),%esi
  mov    %edx,%eax
  cmovns %edx,%esi
  sar    $0x1f,%eax
  shr    $0x1d,%eax
  mov    %esi,%edi
  lea    (%rdx,%rax,1),%ebx
  sar    $0x1f,%esi
  shr    $0x1a,%esi
  sar    $0x3,%edi
  and    $0x7,%ebx
  sub    %eax,%ebx
  lea    (%rdi,%rsi,1),%eax
  shl    %cl,%r11d
  mov    %edx,%ecx
  and    $0x3f,%eax
  and    $0x7,%ecx
  sub    $0x1,%r11d
  sub    %esi,%eax
  cltq
  movzbl (%r9,%rax,1),%esi
  sar    %cl,%esi
  lea    (%rbx,%r10,1),%ecx
  mov    %esi,%eax
  and    %r11d,%eax
  cmp    $0x8,%ecx
  jle    L3
  add    $0x1,%edi
  mov    $0x8,%ecx
  mov    %edi,%eax
  sub    %ebx,%ecx
  sar    $0x1f,%eax
  sar    %cl,%r11d
  shr    $0x1a,%eax
  add    %eax,%edi
  and    $0x3f,%edi
  sub    %eax,%edi
  movslq %edi,%rdi
  movzbl (%r9,%rdi,1),%eax
  and    %r11d,%eax
  shl    %cl,%eax
  or     %esi,%eax
L3:
  add    %r10d,%edx
  pop    %rbx
  mov    %edx,(%r8)
  ret
```

assistant: ```c
unsigned char get_bits(unsigned char block[64], int *off, int n) {
  char ret;
  int boff = *off / 8, bitpos = *off % 8, mask = (1 << n) - 1;
  if (bitpos + n > 8) {
    ret = block[boff % 64] >> bitpos;
    mask >>= 8 - bitpos;
    ret |= (block[(boff + 1) % 64] & mask) << (8 - bitpos);
  } else {
    ret = (block[boff % 64] >> bitpos) & mask;
  }
  *off += n;
  return ret;
}
```