ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L13
  movq   $0x0,-0x8(%rbp)
  jmp    L0
L4:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L4
L13:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gen_fill(double *x, long long int n, double alpha) {
  long long int i;
  if (x) {
    for (i = 0; i < n; ++i)
      *x++ = alpha;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_fill>:
  endbr64
  test   %rdi,%rdi
  je     L11
  test   %rsi,%rsi
  jle    L11
  mov    $0x0,%eax
L15:
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L15
L11:
  ret
```

assistant: ```c
void gen_fill(double *x, long long int n, double alpha) {
  long long int i;
  if (x) {
    for (i = 0; i < n; ++i)
      *x++ = alpha;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gen_fill>:
  endbr64
  test   %rdi,%rdi
  je     L6
  test   %rsi,%rsi
  jle    L6
  xor    %eax,%eax
L28:
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L28
L6:
  ret
```

assistant: ```c
void gen_fill(double *x, long long int n, double alpha) {
  long long int i;
  if (x) {
    for (i = 0; i < n; ++i)
      *x++ = alpha;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_fill>:
  endbr64
  test   %rdi,%rdi
  je     L32
  test   %rsi,%rsi
  jle    L32
  cmp    $0x1,%rsi
  je     L14
  mov    %rsi,%rcx
  movapd %xmm0,%xmm1
  xor    %eax,%eax
  shr    %rcx
  unpcklpd %xmm1,%xmm1
  nopl   0x0(%rax)
L42:
  mov    %rax,%rdx
  add    $0x1,%rax
  shl    $0x4,%rdx
  movups %xmm1,(%rdi,%rdx,1)
  cmp    %rax,%rcx
  jne    L42
  mov    %rsi,%rax
  and    $0xfffffffffffffffe,%rax
  lea    (%rdi,%rax,8),%rdi
  cmp    %rax,%rsi
  je     L32
L14:
  movsd  %xmm0,(%rdi)
L32:
  ret
```

assistant: ```c
void gen_fill(double *x, long long int n, double alpha) {
  long long int i;
  if (x) {
    for (i = 0; i < n; ++i)
      *x++ = alpha;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <theFunc___0@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  theFunc___0(0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <theFunc___0@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  theFunc___0(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <theFunc___0@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  theFunc___0(0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <theFunc___0@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  theFunc___0(0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<uDMAIntClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400ff504,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uDMAIntClear(unsigned long ulChanMask) {
  ;
  ;
  ;
  ;
  (*((volatile unsigned long *)(0x400FF504))) = ulChanMask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uDMAIntClear>:
  endbr64
  mov    %rdi,0x400ff504
  ret
```

assistant: ```c
void uDMAIntClear(unsigned long ulChanMask) {
  ;
  ;
  ;
  ;
  (*((volatile unsigned long *)(0x400FF504))) = ulChanMask;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uDMAIntClear>:
  endbr64
  mov    %rdi,0x400ff504
  ret
```

assistant: ```c
void uDMAIntClear(unsigned long ulChanMask) {
  ;
  ;
  ;
  ;
  (*((volatile unsigned long *)(0x400FF504))) = ulChanMask;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uDMAIntClear>:
  endbr64
  mov    %rdi,0x400ff504
  ret
```

assistant: ```c
void uDMAIntClear(unsigned long ulChanMask) {
  ;
  ;
  ;
  ;
  (*((volatile unsigned long *)(0x400FF504))) = ulChanMask;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cell_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int cell_size(int nSpt, int *SptType) {
  int CellSize = nSpt;
  int i;
  for (i = 0; i < nSpt; i++)
    CellSize += SptType[i];
  return CellSize;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cell_size>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jle    L8
  mov    %rsi,%rdx
  lea    -0x1(%rdi),%ecx
  lea    0x4(%rsi,%rcx,4),%rcx
L10:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L10
L8:
  ret
```

assistant: ```c
int cell_size(int nSpt, int *SptType) {
  int CellSize = nSpt;
  int i;
  for (i = 0; i < nSpt; i++)
    CellSize += SptType[i];
  return CellSize;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cell_size>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jle    L17
  lea    -0x1(%rdi),%edx
  lea    0x4(%rsi,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L19:
  add    (%rsi),%eax
  add    $0x4,%rsi
  cmp    %rdx,%rsi
  jne    L19
L17:
  ret
```

assistant: ```c
int cell_size(int nSpt, int *SptType) {
  int CellSize = nSpt;
  int i;
  for (i = 0; i < nSpt; i++)
    CellSize += SptType[i];
  return CellSize;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cell_size>:
  endbr64
  mov    %edi,%edx
  test   %edi,%edi
  jle    L25
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L8
  mov    %edi,%ecx
  mov    %rsi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rsi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L69:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L69
  movdqa %xmm0,%xmm1
  mov    %edx,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  add    %edx,%eax
  test   $0x3,%dl
  je     L22
L5:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rsi,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%edx
  jle    L59
  add    $0x2,%ecx
  add    0x4(%rsi,%r8,1),%eax
  cmp    %ecx,%edx
  jle    L59
  add    0x8(%rsi,%r8,1),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %edi,%eax
L59:
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  ret
L8:
  mov    %edi,%eax
  xor    %ecx,%ecx
  jmp    L5
```

assistant: ```c
int cell_size(int nSpt, int *SptType) {
  int CellSize = nSpt;
  int i;
  for (i = 0; i < nSpt; i++)
    CellSize += SptType[i];
  return CellSize;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    $0x16,%edx
  imul   %edx,%eax
  add    $0x1c,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  nop
  movzbl -0x9(%rbp),%eax
  lea    -0x74(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[local1] = state[0UL] + state[local1];
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)116;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%edx
  mov    %edx,%eax
  mulb   (%rdi)
  sub    $0x58,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[local1] = state[0UL] + state[local1];
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)116;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  sub    $0x58,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[local1] = state[0UL] + state[local1];
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)116;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  mov    $0x16,%eax
  mulb   (%rdi)
  sub    $0x58,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned char)22;
    local1 = 0UL;
    while (local1 < (unsigned char)0) {
      if (state[0UL] < local1) {
        state[local1] = state[0UL] + state[local1];
        state[0UL] = state[local1] - state[0UL];
      } else {
        state[local1] = state[0UL] + state[local1];
        state[local1] += state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] - (unsigned char)116;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_rgb_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L68
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x7,%eax
  jne    L68
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x23,%al
  je     L47
L68:
  mov    $0x0,%eax
  jmp    L36
L47:
  movl   $0x1,-0x4(%rbp)
  jmp    L26
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L78
  mov    $0x0,%eax
  jmp    L36
L78:
  addl   $0x1,-0x4(%rbp)
L26:
  cmpl   $0x6,-0x4(%rbp)
  jle    L20
  mov    $0x1,%eax
L36:
  leave
  ret
```

assistant: ```c
int valid_rgb_color(const char *color) {
  int i;
  if (!color || strlen(color) != 7 || color[0] != '#')
    return 0;
  for (i = 1; i < 7; i++) {
    if (!isxdigit(color[i]))
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_rgb_color>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L18
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x7,%edx
  jne    L34
  cmpb   $0x23,(%rbx)
  jne    L34
  lea    0x1(%rbx),%rbp
  add    $0x7,%rbx
L23:
  movsbl 0x0(%rbp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L34
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L23
  mov    $0x1,%eax
L34:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
int valid_rgb_color(const char *color) {
  int i;
  if (!color || strlen(color) != 7 || color[0] != '#')
    return 0;
  for (i = 1; i < 7; i++) {
    if (!isxdigit(color[i]))
      return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<valid_rgb_color>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x7,%eax
  je     L27
L15:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L27:
  cmpb   $0x23,(%rbx)
  jne    L15
  lea    0x1(%rbx),%rbp
  add    $0x7,%rbx
L30:
  movsbl 0x0(%rbp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L15
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L30
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int valid_rgb_color(const char *color) {
  int i;
  if (!color || strlen(color) != 7 || color[0] != '#')
    return 0;
  for (i = 1; i < 7; i++) {
    if (!isxdigit(color[i]))
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<valid_rgb_color>:
  endbr64
  test   %rdi,%rdi
  je     L24
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x7,%eax
  je     L20
L29:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L20:
  cmpb   $0x23,(%rbx)
  jne    L29
  lea    0x1(%rbx),%rbp
  add    $0x7,%rbx
L14:
  movsbl 0x0(%rbp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L29
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L14
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
```

assistant: ```c
int valid_rgb_color(const char *color) {
  int i;
  if (!color || strlen(color) != 7 || color[0] != '#')
    return 0;
  for (i = 1; i < 7; i++) {
    if (!isxdigit(color[i]))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L1
L37:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x114(%rbp)
  movl   $0x0,-0x118(%rbp)
  jmp    L65
L71:
  addl   $0x1,-0x118(%rbp)
L110:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jge    L95
  mov    -0x118(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L71
L95:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jge    L22
  mov    -0x118(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L119
  mov    -0x118(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L119
  mov    -0x118(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x118(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x110(%rbp,%rdx,1)
  addl   $0x1,-0x118(%rbp)
  jmp    L119
L102:
  addl   $0x1,-0x118(%rbp)
L119:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jge    L84
  mov    -0x118(%rbp),%eax
  cltq
  movzbl -0x110(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L102
L84:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jge    L35
L65:
  mov    -0x118(%rbp),%eax
  cmp    -0x114(%rbp),%eax
  jl     L110
  jmp    L69
L22:
  nop
  jmp    L69
L35:
  nop
L69:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L1:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L105
  call   <__stack_chk_fail@plt>
L105:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D5: %s


assistant: ```c
int main() {
  char line[256];
  int i, j, k;
  int n;
  while (gets(line) != NULL) {
    n = strlen(line);
    i = 0;
    while (i < n) {
      while (i < n && line[i] == ' ')
        i++;
      if (i >= n)
        break;
      if (isalpha(line[i]) && islower(line[i])) {
        line[i] = toupper(line[i]);
        i++;
      }
      while (i < n && line[i] != ' ')
        i++;
      if (i >= n)
        break;
    }
    printf("%s\n", line);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%r12
  jmp    L86
L139:
  cmp    %eax,%ebx
  jle    L120
  cltq
  movsbl (%rsp,%rax,1),%edi
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L83
L129:
  movslq %r13d,%rdx
L133:
  mov    %edx,%eax
  cmpb   $0x20,(%rdx,%rbp,1)
  je     L42
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L133
  jmp    L120
L83:
  movslq %r13d,%rax
  movsbl (%rsp,%rax,1),%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L129
  movslq %r13d,%r14
  movsbl (%rsp,%r14,1),%edi
  call   <toupper@plt>
  mov    %al,(%rsp,%r14,1)
  add    $0x1,%r13d
  cmp    %r13d,%ebx
  jle    L120
  jmp    L129
L42:
  cmp    %edx,%ebx
  jle    L120
L124:
  cmp    %ebx,%eax
  jge    L120
  cltq
L110:
  mov    %eax,%r13d
  cmpb   $0x20,(%rax,%rbp,1)
  jne    L139
  add    $0x1,%rax
  cmp    %eax,%ebx
  jg     L110
L120:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L86:
  mov    %rsp,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L49
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  mov    %rsp,%rbp
  jmp    L124
L49:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8: %s


assistant: ```c
int main() {
  char line[256];
  int i, j, k;
  int n;
  while (gets(line) != NULL) {
    n = strlen(line);
    i = 0;
    while (i < n) {
      while (i < n && line[i] == ' ')
        i++;
      if (i >= n)
        break;
      if (isalpha(line[i]) && islower(line[i])) {
        line[i] = toupper(line[i]);
        i++;
      }
      while (i < n && line[i] != ' ')
        i++;
      if (i >= n)
        break;
    }
    printf("%s\n", line);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L129
  nopl   (%rax)
L144:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  nopl   (%rax)
L31:
  cmp    %r12d,%eax
  jge    L36
  nopl   (%rax)
L90:
  movsbl 0x0(%r13,%rax,1),%edi
  mov    %eax,%ebx
  cmp    $0x20,%dil
  jne    L137
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L90
L36:
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L144
L129:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L137:
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L134
L59:
  cmp    %ebx,%r12d
  jle    L36
  movslq %ebx,%rdx
  jmp    L113
  nopl   0x0(%rax)
L139:
  add    $0x1,%rdx
  cmp    %edx,%r12d
  jle    L36
L113:
  cmpb   $0x20,0x0(%r13,%rdx,1)
  movslq %edx,%rax
  jne    L139
  cmp    %eax,%r12d
  jg     L31
  jmp    L36
  nopw   0x0(%rax,%rax,1)
L134:
  movslq %ebx,%r14
  movsbl (%rsp,%r14,1),%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L59
  movsbl (%rsp,%r14,1),%edi
  add    $0x1,%ebx
  call   <toupper@plt>
  mov    %al,(%rsp,%r14,1)
  jmp    L59
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: %s


assistant: ```c
int main() {
  char line[256];
  int i, j, k;
  int n;
  while (gets(line) != NULL) {
    n = strlen(line);
    i = 0;
    while (i < n) {
      while (i < n && line[i] == ' ')
        i++;
      if (i >= n)
        break;
      if (isalpha(line[i]) && islower(line[i])) {
        line[i] = toupper(line[i]);
        i++;
      }
      while (i < n && line[i] != ' ')
        i++;
      if (i >= n)
        break;
    }
    printf("%s\n", line);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <gets@plt>
  test   %rax,%rax
  je     L29
  nopl   (%rax)
L112:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  nopl   (%rax)
L53:
  cmp    %r12d,%eax
  jge    L0
  nopl   (%rax)
L107:
  movsbl 0x0(%r13,%rax,1),%edi
  mov    %eax,%ebx
  cmp    $0x20,%dil
  jne    L126
  add    $0x1,%rax
  cmp    %eax,%r12d
  jg     L107
L0:
  mov    %rbp,%rdi
  mov    %r13,%rsi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <gets@plt>
  test   %rax,%rax
  jne    L112
L29:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L126:
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L137
L134:
  cmp    %ebx,%r12d
  jle    L0
  movslq %ebx,%rdx
  jmp    L95
  nopl   0x0(%rax)
L60:
  add    $0x1,%rdx
  cmp    %edx,%r12d
  jle    L0
L95:
  cmpb   $0x20,0x0(%r13,%rdx,1)
  movslq %edx,%rax
  jne    L60
  cmp    %eax,%r12d
  jg     L53
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L137:
  movslq %ebx,%r14
  movsbl (%rsp,%r14,1),%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L134
  movsbl (%rsp,%r14,1),%edi
  add    $0x1,%ebx
  call   <toupper@plt>
  mov    %al,(%rsp,%r14,1)
  jmp    L134
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: %s


assistant: ```c
int main() {
  char line[256];
  int i, j, k;
  int n;
  while (gets(line) != NULL) {
    n = strlen(line);
    i = 0;
    while (i < n) {
      while (i < n && line[i] == ' ')
        i++;
      if (i >= n)
        break;
      if (isalpha(line[i]) && islower(line[i])) {
        line[i] = toupper(line[i]);
        i++;
      }
      while (i < n && line[i] != ' ')
        i++;
      if (i >= n)
        break;
    }
    printf("%s\n", line);
  }
  return 0;
}
```