ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binseai>:
  endbr64
  mov    %edi,%r8d
  mov    %edx,%eax
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L9:
  lea    (%rcx,%rax,1),%edx
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  movslq %edi,%rdx
  cmp    %r8d,(%rsi,%rdx,4)
  cmovle %edi,%eax
  cmovg  %edi,%ecx
L18:
  mov    %ecx,%edx
  sub    %eax,%edx
  cmp    $0x1,%edx
  jg     L9
  movslq %eax,%rdx
  cmp    %r8d,(%rsi,%rdx,4)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int binseai(int key, int a[], int lo, int hi) {
  while (hi - lo > 1) {
    int mid = (hi + lo) / 2;
    if (key < a[mid]) {
      hi = mid;
    } else {
      lo = mid;
    }
  }
  if (a[lo] == key) {
    return lo;
  } else {
    return ((-1));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getnumsep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int getnumsep(int digits) {
  int separators = (digits - ((digits % 3 == 0) ? 1 : 0)) / 3;
  return separators;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getnumsep>:
  endbr64
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%edi
  sete   %al
  movzbl %al,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  ret
```

assistant: ```c
int getnumsep(int digits) {
  int separators = (digits - ((digits % 3 == 0) ? 1 : 0)) / 3;
  return separators;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getnumsep>:
  endbr64
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  setbe  %al
  movzbl %al,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edi,%eax
  ret
```

assistant: ```c
int getnumsep(int digits) {
  int separators = (digits - ((digits % 3 == 0) ? 1 : 0)) / 3;
  return separators;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getnumsep>:
  endbr64
  imul   $0xaaaaaaab,%edi,%eax
  add    $0x2aaaaaaa,%eax
  cmp    $0x55555554,%eax
  setbe  %al
  movzbl %al,%eax
  sub    %eax,%edi
  movslq %edi,%rax
  sar    $0x1f,%edi
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edi,%eax
  ret
```

assistant: ```c
int getnumsep(int digits) {
  int separators = (digits - ((digits % 3 == 0) ? 1 : 0)) / 3;
  return separators;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<convert_weights>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <validate_input@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  je     L8
  cmp    $0x2,%eax
  jg     L38
  test   %eax,%eax
  je     L62
  cmp    $0x1,%eax
  je     L11
  jmp    L38
L11:
  mov    $0x0,%eax
  call   <weight_to_metric@plt>
  jmp    L38
L8:
  mov    $0x0,%eax
  call   <weight_to_us@plt>
  jmp    L38
L62:
  nop
L38:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D17
type_guessed: string
name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D17: Would you like to go convert from:


tool: D0: 	 1. Pounds/Ounces to Kilograms/Grams
	 2. Kilograms/Grams to Pounds/Ounces
	 0. Go back
 Selection: 

tool: D10: %d

assistant: ```c
void convert_weights() {
  int user_input, scanf_return;
  printf("Would you like to go convert from:\n");
  printf("\t 1. Pounds/Ounces to Kilograms/Grams\n\t 2. Kilograms/Grams to Pounds/Ounces\n\t 0. Go back\n Selection: ");
  scanf_return = scanf("%d", &user_input);
  user_input = validate_input(user_input, scanf_return);
  switch (user_input) {
  case 0:
    break;
  case 1:
    weight_to_metric();
    break;
  case 2:
    weight_to_us();
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convert_weights>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    %eax,%esi
  mov    0x4(%rsp),%edi
  call   <validate_input@plt>
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%eax
  je     L47
  cmp    $0x2,%eax
  je     L38
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x18,%rsp
  ret
L47:
  mov    $0x0,%eax
  call   <weight_to_metric@plt>
  jmp    L19
L38:
  mov    $0x0,%eax
  call   <weight_to_us@plt>
  jmp    L19
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D21: Would you like to go convert from:


tool: D29: 	 1. Pounds/Ounces to Kilograms/Grams
	 2. Kilograms/Grams to Pounds/Ounces
	 0. Go back
 Selection: 

tool: D9: %d

assistant: ```c
void convert_weights() {
  int user_input, scanf_return;
  printf("Would you like to go convert from:\n");
  printf("\t 1. Pounds/Ounces to Kilograms/Grams\n\t 2. Kilograms/Grams to Pounds/Ounces\n\t 0. Go back\n Selection: ");
  scanf_return = scanf("%d", &user_input);
  user_input = validate_input(user_input, scanf_return);
  switch (user_input) {
  case 0:
    break;
  case 1:
    weight_to_metric();
    break;
  case 2:
    weight_to_us();
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convert_weights>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  call   <validate_input@plt>
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%eax
  je     L17
  cmp    $0x2,%eax
  jne    L37
  xor    %eax,%eax
  call   <weight_to_us@plt>
L37:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <weight_to_metric@plt>
  jmp    L37
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_guessed: string
name: parse_data
arguments: data_tag: D1
type_guessed: string
name: parse_data
arguments: data_tag: D3
type_guessed: string

tool: D18: Would you like to go convert from:


tool: D1: 	 1. Pounds/Ounces to Kilograms/Grams
	 2. Kilograms/Grams to Pounds/Ounces
	 0. Go back
 Selection: 

tool: D3: %d

assistant: ```c
void convert_weights() {
  int user_input, scanf_return;
  printf("Would you like to go convert from:\n");
  printf("\t 1. Pounds/Ounces to Kilograms/Grams\n\t 2. Kilograms/Grams to Pounds/Ounces\n\t 0. Go back\n Selection: ");
  scanf_return = scanf("%d", &user_input);
  user_input = validate_input(user_input, scanf_return);
  switch (user_input) {
  case 0:
    break;
  case 1:
    weight_to_metric();
    break;
  case 2:
    weight_to_us();
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<convert_weights>:
  endbr64
  sub    $0x18,%rsp
  lea    D8(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  mov    %eax,%esi
  call   <validate_input@plt>
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%eax
  je     L7
  cmp    $0x2,%eax
  jne    L31
  xor    %eax,%eax
  call   <weight_to_us@plt>
L31:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <weight_to_metric@plt>
  jmp    L31
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D24
datatype: string

tool: D8: Would you like to go convert from:


tool: D2: 	 1. Pounds/Ounces to Kilograms/Grams
	 2. Kilograms/Grams to Pounds/Ounces
	 0. Go back
 Selection: 

tool: D24: %d

assistant: ```c
void convert_weights() {
  int user_input, scanf_return;
  printf("Would you like to go convert from:\n");
  printf("\t 1. Pounds/Ounces to Kilograms/Grams\n\t 2. Kilograms/Grams to Pounds/Ounces\n\t 0. Go back\n Selection: ");
  scanf_return = scanf("%d", &user_input);
  user_input = validate_input(user_input, scanf_return);
  switch (user_input) {
  case 0:
    break;
  case 1:
    weight_to_metric();
    break;
  case 2:
    weight_to_us();
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lc_strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L90
  mov    $0xffffffff,%eax
  jmp    L45
L90:
  cmpq   $0x0,-0x30(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L45
L15:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L41:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jge    L91
  mov    $0xffffffff,%eax
  jmp    L45
L91:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %rax,%rbx
  jle    L38
  mov    $0x1,%eax
  jmp    L45
L38:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    $0x0,%eax
  jmp    L45
L33:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
  jmp    L41
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int lc_strcmp(const char *A, const char *B) {
  if (A == NULL)
    return -1;
  if (B == NULL)
    return 1;
  const char *a = A;
  const char *b = B;
  for (;;) {
    if (tolower(*a) < tolower(*b))
      return -1;
    if (tolower(*a) > tolower(*b))
      return 1;
    if (*a == '\0')
      return 0;
    a++;
    b++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lc_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L63
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L59
L41:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %rax,%r12
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  cmp    %rax,%r12
  jl     L17
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %rax,%r12
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  cmp    %rax,%r12
  jg     L49
  cmpb   $0x0,(%rbx)
  je     L25
  add    $0x1,%rbx
  add    $0x1,%rbp
  jmp    L41
L63:
  mov    $0xffffffff,%eax
  ret
L59:
  mov    $0x1,%eax
  jmp    L10
L17:
  mov    $0xffffffff,%eax
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  mov    $0x1,%eax
  jmp    L10
L25:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
int lc_strcmp(const char *A, const char *B) {
  if (A == NULL)
    return -1;
  if (B == NULL)
    return 1;
  const char *a = A;
  const char *b = B;
  for (;;) {
    if (tolower(*a) < tolower(*b))
      return -1;
    if (tolower(*a) > tolower(*b))
      return 1;
    if (*a == '\0')
      return 0;
    a++;
    b++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lc_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L16
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L18
  jmp    L41
  xchg   %ax,%ax
L32:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jg     L41
  cmpb   $0x0,(%rbx)
  je     L21
  add    $0x1,%rbx
  add    $0x1,%rbp
L18:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jge    L32
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lc_strcmp(const char *A, const char *B) {
  if (A == NULL)
    return -1;
  if (B == NULL)
    return 1;
  const char *a = A;
  const char *b = B;
  for (;;) {
    if (tolower(*a) < tolower(*b))
      return -1;
    if (tolower(*a) > tolower(*b))
      return 1;
    if (*a == '\0')
      return 0;
    a++;
    b++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lc_strcmp>:
  endbr64
  test   %rdi,%rdi
  je     L58
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rsi,%rsi
  jne    L44
  jmp    L26
  xchg   %ax,%ax
L55:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jg     L26
  cmpb   $0x0,(%rbx)
  je     L27
  add    $0x1,%rbx
  add    $0x1,%rbp
L44:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  call   <tolower@plt>
  cmp    %rax,%r12
  jge    L55
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L26:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int lc_strcmp(const char *A, const char *B) {
  if (A == NULL)
    return -1;
  if (B == NULL)
    return 1;
  const char *a = A;
  const char *b = B;
  for (;;) {
    if (tolower(*a) < tolower(*b))
      return -1;
    if (tolower(*a) > tolower(*b))
      return 1;
    if (*a == '\0')
      return 0;
    a++;
    b++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<at_headland_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <at_init@plt>
  mov    $0x0,%eax
  call   <ide_init@plt>
  mov    $0x0,%eax
  call   <headland_init@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void at_headland_init() {
  at_init();
  ide_init();
  headland_init();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<at_headland_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <at_init@plt>
  mov    $0x0,%eax
  call   <ide_init@plt>
  mov    $0x0,%eax
  call   <headland_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void at_headland_init() {
  at_init();
  ide_init();
  headland_init();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<at_headland_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <at_init@plt>
  xor    %eax,%eax
  call   <ide_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <headland_init@plt>
```

assistant: ```c
void at_headland_init() {
  at_init();
  ide_init();
  headland_init();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<at_headland_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <at_init@plt>
  xor    %eax,%eax
  call   <ide_init@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <headland_init@plt>
```

assistant: ```c
void at_headland_init() {
  at_init();
  ide_init();
  headland_init();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<set_up_mqs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2000,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <mq_open_default@plt>
  mov    $0x2000,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <mq_open_default@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D7: /mq_build_histogram_in

tool: D15: /mq_build_histogram_out

assistant: ```c
void set_up_mqs(void) {
  mq_open_default("/mq_build_histogram_in", (8 * 1024));
  mq_open_default("/mq_build_histogram_out", (8 * 1024));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_up_mqs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2000,%esi
  lea    D14(%rip),%rdi
  call   <mq_open_default@plt>
  mov    $0x2000,%esi
  lea    D2(%rip),%rdi
  call   <mq_open_default@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D14: /mq_build_histogram_in

tool: D2: /mq_build_histogram_out

assistant: ```c
void set_up_mqs(void) {
  mq_open_default("/mq_build_histogram_in", (8 * 1024));
  mq_open_default("/mq_build_histogram_out", (8 * 1024));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<set_up_mqs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2000,%esi
  lea    D5(%rip),%rdi
  call   <mq_open_default@plt>
  mov    $0x2000,%esi
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <mq_open_default@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D14
type: string

tool: D5: /mq_build_histogram_in

tool: D14: /mq_build_histogram_out

assistant: ```c
void set_up_mqs(void) {
  mq_open_default("/mq_build_histogram_in", (8 * 1024));
  mq_open_default("/mq_build_histogram_out", (8 * 1024));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<set_up_mqs>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2000,%esi
  lea    D4(%rip),%rdi
  call   <mq_open_default@plt>
  mov    $0x2000,%esi
  lea    D19(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <mq_open_default@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D19
type: string

tool: D4: /mq_build_histogram_in

tool: D19: /mq_build_histogram_out

assistant: ```c
void set_up_mqs(void) {
  mq_open_default("/mq_build_histogram_in", (8 * 1024));
  mq_open_default("/mq_build_histogram_out", (8 * 1024));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L5
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L5:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <read_eof@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type_infered: string

tool: D9: You must pass a filename to the test 


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("You must pass a filename to the test \n");
    exit(1);
  }
  char *filename = argv[1];
  read_eof(filename);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L12
L0:
  mov    0x8(%rbx),%rdi
  call   <read_eof@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L0
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string

tool: D4: You must pass a filename to the test 


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("You must pass a filename to the test \n");
    exit(1);
  }
  char *filename = argv[1];
  read_eof(filename);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L4
L14:
  mov    0x8(%rbx),%rdi
  call   <read_eof@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L4:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L14
```

tool_calls: name: read_data
arguments: tag: D3
data_type: string

tool: D3: You must pass a filename to the test 


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("You must pass a filename to the test \n");
    exit(1);
  }
  char *filename = argv[1];
  read_eof(filename);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L8
L3:
  mov    0x8(%rbx),%rdi
  call   <read_eof@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L3
```

tool_calls: name: unpack_data
arguments: data_label: D4
data_type: string

tool: D4: You must pass a filename to the test 


assistant: ```c
int main(int argc, char **argv) {
  if (argc < 2) {
    printf("You must pass a filename to the test \n");
    exit(1);
  }
  char *filename = argv[1];
  read_eof(filename);
  return 0;
}
```