ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<jsr_center_and_print>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <jsr_strlen@plt>
  xor    %eax,%eax
  call   <sec@plt>
  xor    %edi,%edi
  mov    $0x28,%esi
  call   <lda@plt>
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <sbc@plt>
  xor    %eax,%eax
  call   <bmi@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <lsr@plt>
  xor    %eax,%eax
  call   <tax@plt>
  xor    %eax,%eax
  call   <jsr_prblnk@plt>
  xor    %eax,%eax
  call   <jsr_reset_output@plt>
L10:
  mov    $0xf4,%esi
  mov    $0x1,%edi
  call   <ldx@plt>
L5:
  mov    $0xfc,%esi
  mov    $0x2,%edi
  call   <lda@plt>
  xor    %eax,%eax
  call   <jsr_cout1@plt>
  xor    %eax,%eax
  call   <jsr_inc_pointer@plt>
  xor    %eax,%eax
  call   <dex@plt>
  xor    %eax,%eax
  call   <bne@plt>
  test   %rax,%rax
  jne    L5
  add    $0x8,%rsp
  jmp    1130 <jsr_crout@plt>
```

assistant: ```c
void jsr_center_and_print() {
  jsr_strlen();
  sec();
  lda(0, 40);
  sbc(1, 0xf4);
  if (bmi())
    goto no_center;
  lsr(3, 1);
  tax();
  jsr_prblnk();
  jsr_reset_output();
no_center:
  ldx(1, 0xf4);
print_loop:
  lda(2, 0xfc);
  jsr_cout1();
  jsr_inc_pointer();
  dex();
  if (bne())
    goto print_loop;
  jsr_crout();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<setoid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L4
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  lea    D0(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string

tool: D0: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setoid>:
  endbr64
  test   %rdx,%rdx
  je     L6
  sub    $0x8,%rsp
  mov    %rdx,%rcx
  lea    D1(%rip),%rdx
  call   <snprintf@plt>
  add    $0x8,%rsp
  ret
L6:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setoid>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L0
  lea    D4(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string

tool: D4: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: Translate the below assembly code into C programming language:

```asm
<setoid>:
  endbr64
  mov    %rdx,%rcx
  test   %rdx,%rdx
  je     L4
  lea    D4(%rip),%rdx
  jmp    1050 <snprintf@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string

tool: D4: net.%s.debug

assistant: ```c
void setoid(char oid[], size_t oidlen, const char *wlan) {
  if (wlan)
    snprintf(oid, oidlen, "net.%s.debug", wlan);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pi_shutdown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <pi_shutdown_blocking@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void pi_shutdown(int delay) {
  int pid = fork();
  if (pid == 0) {
    pi_shutdown_blocking(delay);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pi_shutdown>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <fork@plt>
  test   %eax,%eax
  je     L11
L15:
  pop    %rbx
  ret
L11:
  mov    %ebx,%edi
  call   <pi_shutdown_blocking@plt>
  jmp    L15
```

assistant: ```c
void pi_shutdown(int delay) {
  int pid = fork();
  if (pid == 0) {
    pi_shutdown_blocking(delay);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pi_shutdown>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <fork@plt>
  test   %eax,%eax
  je     L1
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <pi_shutdown_blocking@plt>
```

assistant: ```c
void pi_shutdown(int delay) {
  int pid = fork();
  if (pid == 0) {
    pi_shutdown_blocking(delay);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pi_shutdown>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <fork@plt>
  test   %eax,%eax
  je     L3
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <pi_shutdown_blocking@plt>
```

assistant: ```c
void pi_shutdown(int delay) {
  int pid = fork();
  if (pid == 0) {
    pi_shutdown_blocking(delay);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x24(%rbp)
  movl   $0x100000,-0x20(%rbp)
  mov    -0x40(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%ecx
  or     %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    $0x1b6,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x1c(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <lseek@plt>
  lea    -0x24(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int zero = 0;
  const int megabyte = 1024 * 1024;
  char *filename = argv[1];
  size_t length = (size_t)atoi(argv[2]) * megabyte;
  int fd = open(filename, O_WRONLY | O_CREAT | O_EXCL, 0666);
  lseek(fd, length - 1, SEEK_SET);
  write(fd, &zero, 1);
  close(fd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    0x8(%rsi),%rbp
  mov    0x10(%rsi),%rdi
  call   <atoi@plt>
  mov    %rax,%rbx
  mov    D35(%rip),%rax
  mov    (%rax),%esi
  mov    D32(%rip),%rax
  or     (%rax),%esi
  mov    D23(%rip),%rax
  or     (%rax),%esi
  mov    $0x1b6,%edx
  mov    %rbp,%rdi
  call   <open@plt>
  mov    %eax,%ebp
  shl    $0x14,%rbx
  lea    -0x1(%rbx),%rsi
  mov    D33(%rip),%rax
  mov    (%rax),%edx
  mov    %ebp,%edi
  call   <lseek@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <write@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int zero = 0;
  const int megabyte = 1024 * 1024;
  char *filename = argv[1];
  size_t length = (size_t)atoi(argv[2]) * megabyte;
  int fd = open(filename, O_WRONLY | O_CREAT | O_EXCL, 0666);
  lseek(fd, length - 1, SEEK_SET);
  write(fd, &zero, 1);
  close(fd);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x10(%rsi),%rdi
  mov    0x8(%rsi),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    $0x1b6,%edx
  mov    %rax,%rbx
  mov    D26(%rip),%rax
  shl    $0x14,%rbx
  mov    (%rax),%esi
  mov    D15(%rip),%rax
  or     (%rax),%esi
  mov    D28(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  lea    -0x1(%rbx),%rsi
  mov    %eax,%ebp
  mov    D24(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    %ebp,%edi
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int zero = 0;
  const int megabyte = 1024 * 1024;
  char *filename = argv[1];
  size_t length = (size_t)atoi(argv[2]) * megabyte;
  int fd = open(filename, O_WRONLY | O_CREAT | O_EXCL, 0666);
  lseek(fd, length - 1, SEEK_SET);
  write(fd, &zero, 1);
  close(fd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x10(%rsi),%rdi
  mov    0x8(%rsi),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    $0x1b6,%edx
  mov    %rax,%rbx
  mov    D17(%rip),%rax
  shl    $0x14,%rbx
  mov    (%rax),%esi
  mov    D0(%rip),%rax
  or     (%rax),%esi
  mov    D12(%rip),%rax
  or     (%rax),%esi
  call   <open@plt>
  lea    -0x1(%rbx),%rsi
  mov    %eax,%ebp
  mov    D3(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    %ebp,%edi
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edx
  call   <write@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int zero = 0;
  const int megabyte = 1024 * 1024;
  char *filename = argv[1];
  size_t length = (size_t)atoi(argv[2]) * megabyte;
  int fd = open(filename, O_WRONLY | O_CREAT | O_EXCL, 0666);
  lseek(fd, length - 1, SEEK_SET);
  write(fd, &zero, 1);
  close(fd);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<byte_zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L14
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  subq   $0x1,-0x20(%rbp)
L14:
  cmpq   $0x0,-0x20(%rbp)
  jg     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void byte_zero(void *yv, long long ylen) {
  char *y = yv;
  while (ylen > 0) {
    *y++ = 0;
    --ylen;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<byte_zero>:
  endbr64
  test   %rsi,%rsi
  jle    L15
  add    %rdi,%rsi
L16:
  add    $0x1,%rdi
  movb   $0x0,-0x1(%rdi)
  cmp    %rdi,%rsi
  jne    L16
L15:
  ret
```

assistant: ```c
void byte_zero(void *yv, long long ylen) {
  char *y = yv;
  while (ylen > 0) {
    *y++ = 0;
    --ylen;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<byte_zero>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  jle    L3
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
void byte_zero(void *yv, long long ylen) {
  char *y = yv;
  while (ylen > 0) {
    *y++ = 0;
    --ylen;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<byte_zero>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  jle    L5
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void byte_zero(void *yv, long long ylen) {
  char *y = yv;
  while (ylen > 0) {
    *y++ = 0;
    --ylen;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<write_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x7f,%al
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    $0x2,%ecx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <spi_comms@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int write_byte(uint8_t reg, uint8_t value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg & ~0x80;
  tx_buf[0] = shift_reg;
  tx_buf[1] = value;
  return spi_comms(tx_buf, 2, rx_buf, 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_byte>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  and    $0x7f,%dil
  mov    %edi,0x8(%rsp)
  mov    %esi,0xc(%rsp)
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rdi
  mov    $0x2,%ecx
  mov    $0x2,%esi
  call   <spi_comms@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_byte(uint8_t reg, uint8_t value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg & ~0x80;
  tx_buf[0] = shift_reg;
  tx_buf[1] = value;
  return spi_comms(tx_buf, 2, rx_buf, 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_byte>:
  endbr64
  sub    $0x28,%rsp
  and    $0x7f,%dil
  mov    $0x2,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  mov    %edi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  mov    %esi,0xc(%rsp)
  mov    $0x2,%esi
  movq   $0x0,0x10(%rsp)
  call   <spi_comms@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_byte(uint8_t reg, uint8_t value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg & ~0x80;
  tx_buf[0] = shift_reg;
  tx_buf[1] = value;
  return spi_comms(tx_buf, 2, rx_buf, 2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_byte>:
  endbr64
  and    $0x7f,%dil
  sub    $0x28,%rsp
  movd   %esi,%xmm1
  mov    $0x2,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movd   %edi,%xmm0
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rdi
  punpckldq %xmm1,%xmm0
  mov    $0x2,%esi
  movq   $0x0,0x10(%rsp)
  movq   %xmm0,0x8(%rsp)
  call   <spi_comms@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_byte(uint8_t reg, uint8_t value) {
  uint8_t tx_buf[2] = {0};
  uint8_t rx_buf[2] = {0};
  uint8_t shift_reg = reg & ~0x80;
  tx_buf[0] = shift_reg;
  tx_buf[1] = value;
  return spi_comms(tx_buf, 2, rx_buf, 2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<free_pdmatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void free_pdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<free_pdmatrix>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void free_pdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<free_pdmatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_pdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<free_pdmatrix>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void free_pdmatrix(double **m) {
  free((char *)(m[0]));
  free((char *)(m));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x19,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movss  D35(%rip),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D9(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   -0xc(%rbp),%eax
  add    $0x6,%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  imul   -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x8(%rbp),%xmm0
  divss  -0x4(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  neg    %eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D35
data_type: f32
name: extract_symbolic_data
arguments: label: D9
data_type: f32
name: extract_symbolic_data
arguments: label: D52
data_type: string
name: extract_symbolic_data
arguments: label: D16
data_type: string
name: extract_symbolic_data
arguments: label: D45
data_type: string
name: extract_symbolic_data
arguments: label: D10
data_type: string

tool: D35: 25

tool: D9: 2

tool: D52: 6 + a / 5 * b = %i


tool: D16: a / b * b = %i


tool: D45: c / d * d = %f


tool: D10: -a = %i


assistant: ```c
int main(void) {
  int a = 25;
  int b = 2;
  float c = 25.0;
  float d = 2.0;
  printf("6 + a / 5 * b = %i\n", 6 + a / 5 * b);
  printf("a / b * b = %i\n", a / b * b);
  printf("c / d * d = %f\n", c / d * d);
  printf("-a = %i\n", -a);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x19,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffe7,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D21: 6 + a / 5 * b = %i


tool: D4: a / b * b = %i


tool: D16: c / d * d = %f


tool: D9: -a = %i


assistant: ```c
int main(void) {
  int a = 25;
  int b = 2;
  float c = 25.0;
  float d = 2.0;
  printf("6 + a / 5 * b = %i\n", 6 + a / 5 * b);
  printf("a / b * b = %i\n", a / b * b);
  printf("c / d * d = %f\n", c / d * d);
  printf("-a = %i\n", -a);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x19,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffe7,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D29
type_guessed: string
name: disassemble_data
arguments: data_tag: D28
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string

tool: D3: 6 + a / 5 * b = %i


tool: D29: a / b * b = %i


tool: D28: c / d * d = %f


tool: D15: -a = %i


assistant: ```c
int main(void) {
  int a = 25;
  int b = 2;
  float c = 25.0;
  float d = 2.0;
  printf("6 + a / 5 * b = %i\n", 6 + a / 5 * b);
  printf("a / b * b = %i\n", a / b * b);
  printf("c / d * d = %f\n", c / d * d);
  printf("-a = %i\n", -a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x10,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x18,%esi
  lea    D36(%rip),%rdi
  call   <printf@plt>
  mov    $0x19,%esi
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffe7,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D36
type: string
name: disassemble_data
arguments: data_label: D28
type: string
name: disassemble_data
arguments: data_label: D39
type: string

tool: D5: 6 + a / 5 * b = %i


tool: D36: a / b * b = %i


tool: D28: c / d * d = %f


tool: D39: -a = %i


assistant: ```c
int main(void) {
  int a = 25;
  int b = 2;
  float c = 25.0;
  float d = 2.0;
  printf("6 + a / 5 * b = %i\n", 6 + a / 5 * b);
  printf("a / b * b = %i\n", a / b * b);
  printf("c / d * d = %f\n", c / d * d);
  printf("-a = %i\n", -a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L35
  movl   $0x0,-0x8(%rbp)
  jmp    L22
L33:
  movl   $0x0,-0x4(%rbp)
  jmp    L34
L43:
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rsi
  mov    -0x1c(%rbp),%eax
  sub    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rax,%rsi
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdi
  mov    -0x18(%rbp),%rax
  add    %rdi,%rax
  mov    (%rax),%rdi
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdi,%rax
  mov    %rax,%rdi
  call   <rotate4@plt>
  addl   $0x1,-0x4(%rbp)
L34:
  mov    -0x1c(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sar    %eax
  cmp    %eax,%edx
  jl     L43
  addl   $0x1,-0x8(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  sar    %eax
  cmp    %eax,-0x8(%rbp)
  jl     L33
  jmp    L59
L35:
  nop
L59:
  leave
  ret
```

assistant: ```c
void rotate(int **matrix, int matrixRowSize, int matrixColSize) {
  if (matrixRowSize <= 1)
    return;
  int i, j;
  for (i = 0; i < (matrixRowSize >> 1); i++) {
    for (j = 0; j - (matrixRowSize & 1) < (matrixRowSize >> 1); j++) {
      rotate4(&matrix[i][j], &matrix[j][matrixRowSize - i - 1], &matrix[matrixRowSize - i - 1][matrixRowSize - j - 1], &matrix[matrixRowSize - j - 1][i]);
    }
  }
}
```