ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<read_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x1b(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    -0x44(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read_params@plt>
  test   %rax,%rax
  je     L27
  mov    $0x1,%eax
  jmp    L99
L27:
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rcx
  lea    -0x1b(%rbp),%rdx
  lea    -0x24(%rbp),%rsi
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <get_x_init_matrix@plt>
  movl   $0xffffffff,-0x34(%rbp)
  jmp    L81
L10:
  addl   $0x1,-0x34(%rbp)
  cmpl   $0x1,-0x34(%rbp)
  je     L81
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x30(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
L81:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jl     L10
  movl   $0x0,-0x34(%rbp)
  jmp    L14
L8:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x34(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  movl   $0x0,(%rax)
L14:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x34(%rbp)
  jle    L8
  mov    -0x24(%rbp),%eax
  mov    -0x30(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <set_maxxy_with_first_line@plt>
  mov    -0x30(%rbp),%rcx
  lea    -0x1b(%rbp),%rdx
  lea    -0x24(%rbp),%rsi
  mov    -0x44(%rbp),%eax
  mov    %eax,%edi
  call   <set_rest_of_matrix@plt>
  test   %rax,%rax
  je     L88
  mov    $0x1,%eax
  jmp    L99
L88:
  mov    -0x20(%rbp),%esi
  mov    -0x24(%rbp),%eax
  mov    -0x30(%rbp),%rcx
  lea    -0x1b(%rbp),%rdx
  mov    %eax,%edi
  call   <print_finish@plt>
  mov    $0x0,%eax
L99:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int read_write(int fd) {
  char auf[3];
  int xy[2];
  int **matrix;
  int i;
  if (read_params(fd, &xy[1], auf))
    return (1);
  matrix = malloc(sizeof(int *) * (xy[1] + 1));
  get_x_init_matrix(fd, &xy[0], auf, matrix);
  i = -1;
  while (i < xy[1])
    if (++i != 1)
      matrix[i] = malloc(sizeof(int) * (xy[0] + 1));
  i = 0;
  while (i < xy[0] + 1)
    matrix[0][i++] = 0;
  set_maxxy_with_first_line(xy[0], matrix);
  if (set_rest_of_matrix(fd, xy, auf, matrix))
    return (1);
  print_finish(xy[0], xy[1], auf, matrix);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<read_write>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x15(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  call   <read_params@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L51
L59:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L99
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  mov    0x10(%rsp),%eax
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x15(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rax,%rcx
  mov    %r13d,%edi
  call   <get_x_init_matrix@plt>
  cmpl   $0x0,0x10(%rsp)
  js     L106
  mov    %r12,%rbp
  mov    $0xffffffff,%ebx
  jmp    L42
L54:
  add    $0x8,%rbp
  cmp    %ebx,0x10(%rsp)
  jle    L106
L42:
  add    $0x1,%ebx
  cmp    $0x1,%ebx
  je     L54
  mov    0xc(%rsp),%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  jmp    L54
L106:
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  js     L91
  mov    $0x0,%eax
L25:
  mov    (%r12),%rdx
  movl   $0x0,(%rdx,%rax,4)
  mov    0xc(%rsp),%edi
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L25
L91:
  mov    %r12,%rsi
  call   <set_maxxy_with_first_line@plt>
  lea    0x15(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %r12,%rcx
  mov    %r13d,%edi
  call   <set_rest_of_matrix@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L59
  lea    0x15(%rsp),%rdx
  mov    %r12,%rcx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <print_finish@plt>
  mov    $0x0,%eax
  jmp    L59
L99:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_write(int fd) {
  char auf[3];
  int xy[2];
  int **matrix;
  int i;
  if (read_params(fd, &xy[1], auf))
    return (1);
  matrix = malloc(sizeof(int *) * (xy[1] + 1));
  get_x_init_matrix(fd, &xy[0], auf, matrix);
  i = -1;
  while (i < xy[1])
    if (++i != 1)
      matrix[i] = malloc(sizeof(int) * (xy[0] + 1));
  i = 0;
  while (i < xy[0] + 1)
    matrix[0][i++] = 0;
  set_maxxy_with_first_line(xy[0], matrix);
  if (set_rest_of_matrix(fd, xy, auf, matrix))
    return (1);
  print_finish(xy[0], xy[1], auf, matrix);
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<read_write>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x15(%rsp),%r12
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdx
  call   <read_params@plt>
  test   %rax,%rax
  je     L44
L38:
  mov    $0x1,%eax
L72:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  mov    0x10(%rsp),%eax
  lea    0xc(%rsp),%r13
  mov    $0xffffffff,%ebx
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %rax,%rcx
  mov    %rax,%r14
  call   <get_x_init_matrix@plt>
L10:
  mov    0x10(%rsp),%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L80:
  add    $0x1,%ebx
  cmp    $0x1,%ebx
  jne    L74
L28:
  cmp    %ebx,%eax
  jg     L80
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  js     L96
  mov    (%r14),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L99:
  movl   $0x0,(%rdx,%rax,4)
  mov    0xc(%rsp),%edi
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L99
L96:
  mov    %r14,%rsi
  call   <set_maxxy_with_first_line@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <set_rest_of_matrix@plt>
  test   %rax,%rax
  jne    L38
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %r14,%rcx
  mov    %r12,%rdx
  call   <print_finish@plt>
  xor    %eax,%eax
  jmp    L72
  xchg   %ax,%ax
L74:
  movslq %ebx,%rax
  lea    (%r14,%rax,8),%r15
  mov    0xc(%rsp),%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  jmp    L10
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_write(int fd) {
  char auf[3];
  int xy[2];
  int **matrix;
  int i;
  if (read_params(fd, &xy[1], auf))
    return (1);
  matrix = malloc(sizeof(int *) * (xy[1] + 1));
  get_x_init_matrix(fd, &xy[0], auf, matrix);
  i = -1;
  while (i < xy[1])
    if (++i != 1)
      matrix[i] = malloc(sizeof(int) * (xy[0] + 1));
  i = 0;
  while (i < xy[0] + 1)
    matrix[0][i++] = 0;
  set_maxxy_with_first_line(xy[0], matrix);
  if (set_rest_of_matrix(fd, xy, auf, matrix))
    return (1);
  print_finish(xy[0], xy[1], auf, matrix);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_write>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x15(%rsp),%r12
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdx
  call   <read_params@plt>
  test   %rax,%rax
  je     L70
L29:
  mov    $0x1,%eax
L78:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L70:
  mov    0x10(%rsp),%eax
  lea    0xc(%rsp),%r13
  mov    $0xffffffff,%ebx
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %rax,%rcx
  mov    %rax,%r14
  call   <get_x_init_matrix@plt>
L6:
  mov    0x10(%rsp),%eax
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%ebx
  cmp    $0x1,%ebx
  jne    L57
L28:
  cmp    %ebx,%eax
  jg     L11
  mov    0xc(%rsp),%edi
  test   %edi,%edi
  js     L18
  mov    (%r14),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L53:
  movl   $0x0,(%rdx,%rax,4)
  mov    0xc(%rsp),%edi
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L53
L18:
  mov    %r14,%rsi
  call   <set_maxxy_with_first_line@plt>
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <set_rest_of_matrix@plt>
  test   %rax,%rax
  jne    L29
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  mov    %r14,%rcx
  mov    %r12,%rdx
  call   <print_finish@plt>
  xor    %eax,%eax
  jmp    L78
  xchg   %ax,%ax
L57:
  movslq %ebx,%rax
  lea    (%r14,%rax,8),%r15
  mov    0xc(%rsp),%eax
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,(%r15)
  jmp    L6
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_write(int fd) {
  char auf[3];
  int xy[2];
  int **matrix;
  int i;
  if (read_params(fd, &xy[1], auf))
    return (1);
  matrix = malloc(sizeof(int *) * (xy[1] + 1));
  get_x_init_matrix(fd, &xy[0], auf, matrix);
  i = -1;
  while (i < xy[1])
    if (++i != 1)
      matrix[i] = malloc(sizeof(int) * (xy[0] + 1));
  i = 0;
  while (i < xy[0] + 1)
    matrix[0][i++] = 0;
  set_maxxy_with_first_line(xy[0], matrix);
  if (set_rest_of_matrix(fd, xy, auf, matrix))
    return (1);
  print_finish(xy[0], xy[1], auf, matrix);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_186_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_186_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return stk1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_186_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  not    %eax
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  and    %edx,%eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_186_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_186_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  not    %eax
  and    %edx,%eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_186_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_186_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%eax
  shl    $0x8,%edx
  or     %edi,%eax
  or     %esi,%edx
  not    %eax
  and    %edx,%eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_186_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~S;
  stk2 = T & stk3;
  stk1 = D | stk2;
  return stk1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__unserialize_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x7,-0x34(%rbp)
  jg     L20
  mov    $0xffffffff,%eax
  jmp    L32
L20:
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__unserialize_uint32@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L52
  mov    -0x34(%rbp),%eax
  lea    -0x4(%rax),%edx
  mov    -0x30(%rbp),%rax
  lea    0x10(%rax),%rcx
  lea    -0x14(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__unserialize_uint32@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L63
  mov    -0x14(%rbp),%eax
  mov    $0x20,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x8,%eax
  jmp    L32
L52:
  nop
  jmp    L1
L63:
  nop
L1:
  mov    $0xffffffff,%eax
L32:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int __unserialize_uint64(uint64_t *out, const uint8_t *data, int s) {
  if (s < 8)
    return (-1);
  int rc;
  uint32_t l, r;
  rc = __unserialize_uint32(&r, data, s);
  {
    if (rc == -1)
      goto failure;
  };
  rc = __unserialize_uint32(&l, data + 4, s - 4);
  {
    if (rc == -1)
      goto failure;
  };
  *out = ((((uint64_t)l << 32) & 0xFFFFFFFF00000000) | r);
  return (8);
failure:
  return (-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__unserialize_uint64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edx
  jle    L48
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %edx,%ebx
  lea    0x4(%rsp),%rdi
  call   <__unserialize_uint32@plt>
  cmp    $0xffffffff,%eax
  je     L3
  lea    -0x4(%rbx),%edx
  lea    0x10(%r12),%rsi
  mov    %rsp,%rdi
  call   <__unserialize_uint32@plt>
  cmp    $0xffffffff,%eax
  je     L3
  mov    0x4(%rsp),%eax
  mov    %eax,0x0(%rbp)
  mov    $0x8,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L20
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  mov    $0xffffffff,%eax
  jmp    L3
L20:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __unserialize_uint64(uint64_t *out, const uint8_t *data, int s) {
  if (s < 8)
    return (-1);
  int rc;
  uint32_t l, r;
  rc = __unserialize_uint32(&r, data, s);
  {
    if (rc == -1)
      goto failure;
  };
  rc = __unserialize_uint32(&l, data + 4, s - 4);
  {
    if (rc == -1)
      goto failure;
  };
  *out = ((((uint64_t)l << 32) & 0xFFFFFFFF00000000) | r);
  return (8);
failure:
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__unserialize_uint64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edx
  jle    L28
  mov    %rdi,%r12
  lea    0x4(%rsp),%rdi
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <__unserialize_uint32@plt>
  cmp    $0xffffffff,%eax
  je     L28
  lea    -0x4(%rbx),%edx
  lea    0x10(%rbp),%rsi
  mov    %rsp,%rdi
  call   <__unserialize_uint32@plt>
  cmp    $0xffffffff,%eax
  je     L28
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  mov    $0x8,%eax
L39:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0xffffffff,%eax
  jmp    L39
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __unserialize_uint64(uint64_t *out, const uint8_t *data, int s) {
  if (s < 8)
    return (-1);
  int rc;
  uint32_t l, r;
  rc = __unserialize_uint32(&r, data, s);
  {
    if (rc == -1)
      goto failure;
  };
  rc = __unserialize_uint32(&l, data + 4, s - 4);
  {
    if (rc == -1)
      goto failure;
  };
  *out = ((((uint64_t)l << 32) & 0xFFFFFFFF00000000) | r);
  return (8);
failure:
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__unserialize_uint64>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edx
  jle    L8
  mov    %rdi,%r12
  lea    0x4(%rsp),%rdi
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <__unserialize_uint32@plt>
  cmp    $0xffffffff,%eax
  je     L8
  lea    -0x4(%rbx),%edx
  lea    0x10(%rbp),%rsi
  mov    %rsp,%rdi
  call   <__unserialize_uint32@plt>
  cmp    $0xffffffff,%eax
  je     L8
  mov    0x4(%rsp),%eax
  mov    %eax,(%r12)
  mov    $0x8,%eax
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  jmp    L28
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __unserialize_uint64(uint64_t *out, const uint8_t *data, int s) {
  if (s < 8)
    return (-1);
  int rc;
  uint32_t l, r;
  rc = __unserialize_uint32(&r, data, s);
  {
    if (rc == -1)
      goto failure;
  };
  rc = __unserialize_uint32(&l, data + 4, s - 4);
  {
    if (rc == -1)
      goto failure;
  };
  *out = ((((uint64_t)l << 32) & 0xFFFFFFFF00000000) | r);
  return (8);
failure:
  return (-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L49
L32:
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L1:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L41
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L41:
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L1
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L32
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort(int *arr, int arr_len) {
  int i, j, swap;
  for (i = 0; i < (arr_len - 1); i++) {
    for (j = 0; j < arr_len - i - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        swap = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = swap;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %r8d,%r8d
  jle    L42
  lea    0x4(%rdi),%r9
  jmp    L33
L4:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L8
L36:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L4
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L4
L8:
  sub    $0x1,%r8d
  je     L42
L33:
  test   %r8d,%r8d
  jle    L8
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L36
L42:
  ret
```

assistant: ```c
void bubble_sort(int *arr, int arr_len) {
  int i, j, swap;
  for (i = 0; i < (arr_len - 1); i++) {
    for (j = 0; j < arr_len - i - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        swap = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = swap;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%edx
  test   %edx,%edx
  jle    L29
  lea    0x4(%rdi),%r9
  nop
L33:
  sub    $0x1,%edx
  mov    %rdi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rsi
  nopl   (%rax)
L25:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L36
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L36:
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L25
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L33
L29:
  ret
```

assistant: ```c
void bubble_sort(int *arr, int arr_len) {
  int i, j, swap;
  for (i = 0; i < (arr_len - 1); i++) {
    for (j = 0; j < arr_len - i - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        swap = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = swap;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L9
  lea    0x4(%rdi),%r9
  nop
L13:
  sub    $0x1,%eax
  mov    %rdi,%rdx
  mov    %rax,%r8
  lea    (%r9,%rax,4),%rsi
  nopl   (%rax)
L11:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L22
  movq   %xmm1,(%rdx)
L22:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L11
  mov    %r8d,%eax
  test   %r8d,%r8d
  jne    L13
L9:
  ret
```

assistant: ```c
void bubble_sort(int *arr, int arr_len) {
  int i, j, swap;
  for (i = 0; i < (arr_len - 1); i++) {
    for (j = 0; j < arr_len - i - 1; j++) {
      if (arr[j] > arr[j + 1]) {
        swap = arr[j];
        arr[j] = arr[j + 1];
        arr[j + 1] = swap;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pexit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void pexit(const char *fname) {
  perror(fname);
  exit(EXIT_FAILURE);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pexit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pexit(const char *fname) {
  perror(fname);
  exit(EXIT_FAILURE);
}
```
user: What is the c source code of the assembly code below:

```asm
<pexit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void pexit(const char *fname) {
  perror(fname);
  exit(EXIT_FAILURE);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pexit>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void pexit(const char *fname) {
  perror(fname);
  exit(EXIT_FAILURE);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cgi_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string

tool: D5: <h1>Error</h1>

assistant: ```c
void cgi_error(const char *reason) {
  printf("<h1>Error</h1>\n");
  printf("%s\n", reason);
  exit(0);
}
```