ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdx
  lea    D56(%rip),%rsi
  xor    %eax,%eax
  push   %rbx
  lea    D57(%rip),%rdi
  mov    $0x10,%ebx
  lea    D18(%rip),%rbp
  sub    $0x18,%rsp
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L9:
  movsd  D62(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D60(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D4(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L9
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
data_type: string
name: retrieve_data
arguments: data_label: D56
data_type: string
name: retrieve_data
arguments: data_label: D57
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D62
data_type: byte[8]
name: retrieve_data
arguments: data_label: D60
data_type: f64
name: retrieve_data
arguments: data_label: D4
data_type: byte[4]

tool: D13: fahr

tool: D56: celsius

tool: D57: %6s	%3s


tool: D18: %6.1f	%3.0f


tool: {"D62": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D60: 32

tool: {"D4": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  float lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  celsius = lower;
  printf("%6s\t%3s\n", "celsius", "fahr");
  while (celsius <= upper) {
    fahr = celsius * (9.0 / 5.0) + 32.0;
    printf("%6.1f\t%3.0f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdx
  lea    D23(%rip),%rsi
  xor    %eax,%eax
  push   %rbx
  lea    D12(%rip),%rdi
  mov    $0x10,%ebx
  lea    D30(%rip),%rbp
  sub    $0x18,%rsp
  call   <printf@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L2:
  movsd  D29(%rip),%xmm1
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm2,%xmm0
  movss  %xmm2,0xc(%rsp)
  mulsd  %xmm0,%xmm1
  addsd  D52(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  movss  0xc(%rsp),%xmm2
  addss  D26(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_guessed: string
name: unpack_data
arguments: label: D23
type_guessed: string
name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D30
type_guessed: string
name: unpack_data
arguments: label: D29
type_guessed: byte[8]
name: unpack_data
arguments: label: D52
type_guessed: f64
name: unpack_data
arguments: label: D26
type_guessed: byte[4]

tool: D13: fahr

tool: D23: celsius

tool: D12: %6s	%3s


tool: D30: %6.1f	%3.0f


tool: {"D29": [0xcd,0xcc,0xcc,0xcc,0xcc,0xcc,0xfc,0x3f]}

tool: D52: 32

tool: {"D26": [0x00,0x00,0xa0,0x41]}

assistant: ```c
main() {
  float fahr, celsius;
  float lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  celsius = lower;
  printf("%6s\t%3s\n", "celsius", "fahr");
  while (celsius <= upper) {
    fahr = celsius * (9.0 / 5.0) + 32.0;
    printf("%6.1f\t%3.0f\n", celsius, fahr);
    celsius = celsius + step;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_length_arg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x62,%al
  jne    L14
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L30
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x6b,%al
  jne    L30
  shlq   $0xa,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L30:
  cmpq   $0x0,-0x10(%rbp)
  js     L29
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
L29:
  mov    $0x1,%eax
  jmp    L48
L65:
  mov    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x0,%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int get_length_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == 'b') {
    suffix++;
  } else if (*suffix == 'k') {
    t *= 1024;
    suffix++;
  }
  if (t < 0 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_length_arg>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%ecx
  cmp    $0x62,%cl
  je     L1
  cmp    $0x6b,%cl
  je     L43
L31:
  mov    $0x1,%edx
  test   %rax,%rax
  js     L8
  mov    (%rsp),%rcx
  cmpb   $0x0,(%rcx)
  jne    L8
  mov    %rax,(%rbx)
  mov    $0x0,%edx
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L1:
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
  jmp    L31
L43:
  shl    $0xa,%rax
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
  jmp    L31
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_length_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == 'b') {
    suffix++;
  } else if (*suffix == 'k') {
    t *= 1024;
    suffix++;
  }
  if (t < 0 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_length_arg>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%ecx
  cmp    $0x62,%cl
  je     L1
  cmp    $0x6b,%cl
  je     L21
L16:
  mov    $0x1,%r8d
  test   %rax,%rax
  js     L2
  mov    (%rsp),%rdx
  cmpb   $0x0,(%rdx)
  jne    L2
  mov    %rax,(%rbx)
  xor    %r8d,%r8d
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L21:
  shl    $0xa,%rax
L1:
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
  jmp    L16
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_length_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == 'b') {
    suffix++;
  } else if (*suffix == 'k') {
    t *= 1024;
    suffix++;
  }
  if (t < 0 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_length_arg>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  mov    (%rsp),%rdx
  movzbl (%rdx),%ecx
  cmp    $0x62,%cl
  je     L14
  cmp    $0x6b,%cl
  je     L21
L57:
  mov    $0x1,%r8d
  test   %rax,%rax
  js     L16
  cmpb   $0x0,(%rdx)
  jne    L16
  mov    %rax,(%rbx)
  xor    %r8d,%r8d
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L21:
  shl    $0xa,%rax
L14:
  add    $0x1,%rdx
  mov    %rdx,(%rsp)
  jmp    L57
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_length_arg(const char *arg, unsigned long *value) {
  long t;
  char *suffix;
  t = strtol(arg, &suffix, 10);
  if (*suffix == 'b') {
    suffix++;
  } else if (*suffix == 'k') {
    t *= 1024;
    suffix++;
  }
  if (t < 0 || *suffix != 0) {
    return 1;
  }
  *value = (unsigned long)t;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DistributionBlinnPhong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  D10(%rip),%xmm0
  divss  -0x8(%rbp),%xmm0
  movss  D10(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm1
  movss  D10(%rip),%xmm0
  addss  %xmm0,%xmm1
  movss  %xmm1,-0x1c(%rbp)
  mov    D38(%rip),%eax
  movd   %eax,%xmm0
  call   <rcp@plt>
  mulss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  pxor   %xmm1,%xmm1
  movd   %eax,%xmm0
  call   <max@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  mov    %edx,%edi
  call   <pow@plt>
  mulss  -0x1c(%rbp),%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D10
type_guessed: byte[4]
name: retrieve_data
arguments: label: D38
type_guessed: byte[4]

tool: {"D10": [0x00,0x00,0x00,0x40]}

tool: {"D38": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
float DistributionBlinnPhong(float roughness, float NdotH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float n = 2.0f / a2 - 2.0f;
  return (n + 2.0f) * rcp(2.0f * 3.141592654f) * pow(max(NdotH, 0.0f), n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<DistributionBlinnPhong>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  mulss  %xmm0,%xmm0
  mulss  %xmm0,%xmm0
  movss  D0(%rip),%xmm3
  divss  %xmm0,%xmm3
  movaps %xmm3,%xmm2
  subss  D0(%rip),%xmm2
  movss  %xmm2,0x4(%rsp)
  movss  D17(%rip),%xmm0
  call   <rcp@plt>
  movss  D0(%rip),%xmm4
  addss  0x4(%rsp),%xmm4
  movaps %xmm4,%xmm5
  mulss  %xmm0,%xmm5
  movss  %xmm5,0x8(%rsp)
  pxor   %xmm1,%xmm1
  movss  0xc(%rsp),%xmm0
  call   <max@plt>
  mov    %eax,%edi
  movss  0x4(%rsp),%xmm0
  call   <pow@plt>
  mulss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
data_type: byte[4]
name: unpack_data
arguments: data_label: D17
data_type: byte[4]

tool: {"D0": [0x00,0x00,0x00,0x40]}

tool: {"D17": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
float DistributionBlinnPhong(float roughness, float NdotH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float n = 2.0f / a2 - 2.0f;
  return (n + 2.0f) * rcp(2.0f * 3.141592654f) * pow(max(NdotH, 0.0f), n);
}
```
user: Translate the below assembly code into C programming language:

```asm
<DistributionBlinnPhong>:
  endbr64
  mulss  %xmm0,%xmm0
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  D23(%rip),%xmm1
  mulss  %xmm0,%xmm0
  divss  %xmm0,%xmm1
  movss  D0(%rip),%xmm0
  subss  D23(%rip),%xmm1
  movss  %xmm1,0x4(%rsp)
  call   <rcp@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movss  D23(%rip),%xmm4
  addss  0x4(%rsp),%xmm4
  movaps %xmm4,%xmm5
  mulss  %xmm0,%xmm5
  movaps %xmm2,%xmm0
  movss  %xmm5,0x8(%rsp)
  call   <max@plt>
  movss  0x4(%rsp),%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  mulss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D23
datatype: byte[4]
name: unpack_data
arguments: data_tag: D0
datatype: byte[4]

tool: {"D23": [0x00,0x00,0x00,0x40]}

tool: {"D0": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
float DistributionBlinnPhong(float roughness, float NdotH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float n = 2.0f / a2 - 2.0f;
  return (n + 2.0f) * rcp(2.0f * 3.141592654f) * pow(max(NdotH, 0.0f), n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<DistributionBlinnPhong>:
  endbr64
  mulss  %xmm0,%xmm0
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  D17(%rip),%xmm1
  mulss  %xmm0,%xmm0
  divss  %xmm0,%xmm1
  movss  D20(%rip),%xmm0
  subss  D17(%rip),%xmm1
  movss  %xmm1,0x4(%rsp)
  call   <rcp@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movss  D17(%rip),%xmm4
  addss  0x4(%rsp),%xmm4
  movaps %xmm4,%xmm5
  mulss  %xmm0,%xmm5
  movaps %xmm2,%xmm0
  movss  %xmm5,0x8(%rsp)
  call   <max@plt>
  movss  0x4(%rsp),%xmm0
  mov    %eax,%edi
  call   <pow@plt>
  mulss  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: byte[4]
name: extract_symbolic_data
arguments: data_label: D20
type_guessed: byte[4]

tool: {"D17": [0x00,0x00,0x00,0x40]}

tool: {"D20": [0xdb,0x0f,0xc9,0x40]}

assistant: ```c
float DistributionBlinnPhong(float roughness, float NdotH) {
  float a = roughness * roughness;
  float a2 = a * a;
  float n = 2.0f / a2 - 2.0f;
  return (n + 2.0f) * rcp(2.0f * 3.141592654f) * pow(max(NdotH, 0.0f), n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<UARTIntDisable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  jne    L7
  mov    $0x570,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <AssertFailure@plt>
L7:
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%rcx
  mov    -0x10(%rbp),%rax
  not    %rax
  mov    %rax,%rsi
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  mov    %rax,%rdx
  mov    %rcx,%rax
  and    %rsi,%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
void UARTIntDisable(unsigned long ulBase, unsigned long ulIntFlags) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c", 1392);
    }
  };
  (*((volatile unsigned long *)(ulBase + 0x00000038))) &= ~(ulIntFlags);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<UARTIntDisable>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  je     L5
L10:
  mov    0x38(%rbp),%rax
  not    %rbx
  and    %rax,%rbx
  mov    %rbx,0x38(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x570,%esi
  lea    D4(%rip),%rdi
  call   <AssertFailure@plt>
  jmp    L10
```

tool_calls: name: parse_data
arguments: label: D4
data_type: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
void UARTIntDisable(unsigned long ulBase, unsigned long ulIntFlags) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c", 1392);
    }
  };
  (*((volatile unsigned long *)(ulBase + 0x00000038))) &= ~(ulIntFlags);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UARTIntDisable>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  je     L14
L13:
  mov    0x38(%rbp),%rax
  not    %rbx
  and    %rax,%rbx
  mov    %rbx,0x38(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L14:
  mov    $0x570,%esi
  lea    D5(%rip),%rdi
  call   <AssertFailure@plt>
  jmp    L13
```

tool_calls: name: read_data
arguments: data_tag: D5
type_infered: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
void UARTIntDisable(unsigned long ulBase, unsigned long ulIntFlags) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c", 1392);
    }
  };
  (*((volatile unsigned long *)(ulBase + 0x00000038))) &= ~(ulIntFlags);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<UARTIntDisable>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <UARTBaseValid@plt>
  test   %eax,%eax
  je     L11
L6:
  mov    0x38(%rbp),%rax
  not    %rbx
  and    %rax,%rbx
  mov    %rbx,0x38(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L11:
  mov    $0x570,%esi
  lea    D9(%rip),%rdi
  call   <AssertFailure@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_tag: D9
type_guessed: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c

assistant: ```c
void UARTIntDisable(unsigned long ulBase, unsigned long ulIntFlags) {
  {
    if (!(UARTBaseValid(ulBase))) {
      AssertFailure("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/AmesianX/OpenBLT/refs/heads/master/Target/Demo/ARMCM3_LM3S_EK_LM3S8962_Crossworks/Boot/lib/driverlib/uartlib.c", 1392);
    }
  };
  (*((volatile unsigned long *)(ulBase + 0x00000038))) &= ~(ulIntFlags);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<level_to_prl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  cmp    $0x7,%eax
  ja     L14
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D12(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x1f,%eax
  jmp    L12
  mov    $0x0,%eax
  jmp    L12
  mov    $0x1,%eax
  jmp    L12
  mov    $0x4,%eax
  jmp    L12
  mov    $0x5,%eax
  jmp    L12
  mov    $0x6,%eax
  jmp    L12
L14:
  mov    $0xffffffff,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int level_to_prl(int level) {
  switch (level) {
  case (-1):
    return 0x1f;
  case 0:
    return 0x00;
  case 1:
    return 0x01;
  case 4:
    return 0x04;
  case 5:
    return 0x05;
  case 6:
    return 0x06;
  default:
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<level_to_prl>:
  endbr64
  lea    0x1(%rdi),%eax
  cmp    $0x7,%eax
  ja     L6
  mov    %eax,%eax
  lea    D5(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    %edi,%eax
  ret
  mov    %edi,%eax
  ret
  mov    %edi,%eax
  ret
  mov    %edi,%eax
  ret
  mov    %edi,%eax
  ret
L6:
  mov    $0xffffffff,%eax
  ret
  mov    $0x1f,%eax
  ret
```

assistant: ```c
int level_to_prl(int level) {
  switch (level) {
  case (-1):
    return 0x1f;
  case 0:
    return 0x00;
  case 1:
    return 0x01;
  case 4:
    return 0x04;
  case 5:
    return 0x05;
  case 6:
    return 0x06;
  default:
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<level_to_prl>:
  endbr64
  add    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x7,%edi
  ja     L0
  lea    D0(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L0:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: 

assistant: ```c
int level_to_prl(int level) {
  switch (level) {
  case (-1):
    return 0x1f;
  case 0:
    return 0x00;
  case 1:
    return 0x01;
  case 4:
    return 0x04;
  case 5:
    return 0x05;
  case 6:
    return 0x06;
  default:
    return -1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<level_to_prl>:
  endbr64
  add    $0x1,%edi
  mov    $0xffffffff,%eax
  cmp    $0x7,%edi
  ja     L3
  lea    D6(%rip),%rax
  mov    (%rax,%rdi,4),%eax
L3:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D6: 

assistant: ```c
int level_to_prl(int level) {
  switch (level) {
  case (-1):
    return 0x1f;
  case 0:
    return 0x00;
  case 1:
    return 0x01;
  case 4:
    return 0x04;
  case 5:
    return 0x05;
  case 6:
    return 0x06;
  default:
    return -1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<utf8_prev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L6:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x7f,-0xc(%rbp)
  jbe    L34
  cmpl   $0xbf,-0xc(%rbp)
  jbe    L27
L34:
  mov    -0x8(%rbp),%rax
  jmp    L30
L27:
  subq   $0x1,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L6
  mov    -0x18(%rbp),%rax
L30:
  pop    %rbp
  ret
```

assistant: ```c
const char *utf8_prev(const char *s, const char *e) {
  const char *look = e - 1;
  while (s <= look) {
    unsigned ch = (unsigned char)*look;
    if (ch < 0x80 || ch >= 0xC0)
      return look;
    --look;
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<utf8_prev>:
  endbr64
  mov    %rdi,%rax
  sub    $0x1,%rsi
  cmp    %rdi,%rsi
  jb     L12
  lea    -0x1(%rdi),%rcx
L22:
  movzbl (%rsi),%edx
  add    $0xffffff80,%edx
  cmp    $0x3f,%edx
  ja     L26
  sub    $0x1,%rsi
  cmp    %rcx,%rsi
  jne    L22
  ret
L26:
  mov    %rsi,%rax
L12:
  ret
```

assistant: ```c
const char *utf8_prev(const char *s, const char *e) {
  const char *look = e - 1;
  while (s <= look) {
    unsigned ch = (unsigned char)*look;
    if (ch < 0x80 || ch >= 0xC0)
      return look;
    --look;
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utf8_prev>:
  endbr64
  sub    $0x1,%rsi
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  jb     L14
  lea    -0x1(%rdi),%rcx
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L10:
  sub    $0x1,%rsi
  cmp    %rcx,%rsi
  je     L4
L24:
  movzbl (%rsi),%edx
  add    $0xffffff80,%edx
  cmp    $0x3f,%edx
  jbe    L10
  mov    %rsi,%rax
L14:
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  ret
```

assistant: ```c
const char *utf8_prev(const char *s, const char *e) {
  const char *look = e - 1;
  while (s <= look) {
    unsigned ch = (unsigned char)*look;
    if (ch < 0x80 || ch >= 0xC0)
      return look;
    --look;
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utf8_prev>:
  endbr64
  sub    $0x1,%rsi
  mov    %rdi,%rax
  cmp    %rdi,%rsi
  jb     L8
  lea    -0x1(%rdi),%rcx
  jmp    L7
  cs nopw 0x0(%rax,%rax,1)
L26:
  sub    $0x1,%rsi
  cmp    %rcx,%rsi
  je     L9
L7:
  movzbl (%rsi),%edx
  add    $0xffffff80,%edx
  cmp    $0x3f,%edx
  jbe    L26
  mov    %rsi,%rax
L8:
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  ret
```

assistant: ```c
const char *utf8_prev(const char *s, const char *e) {
  const char *look = e - 1;
  while (s <= look) {
    unsigned ch = (unsigned char)*look;
    if (ch < 0x80 || ch >= 0xC0)
      return look;
    --look;
  }
  return s;
}
```