user: 这段汇编代码用C语言表示是什么样的?

```asm
<Symmetrize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L67
L45:
  movl   $0x1,-0xc(%rbp)
  jmp    L32
L36:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  ucomiss %xmm1,%xmm0
  jp     L12
  ucomiss %xmm1,%xmm0
  je     L31
L12:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm0,%xmm2
  movq   %xmm2,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  addss  %xmm1,%xmm0
  movss  D7(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  movl   $0x0,-0x8(%rbp)
L31:
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L36
  addl   $0x1,-0x10(%rbp)
L67:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L45
  cmpl   $0x0,-0x8(%rbp)
  jne    L25
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D7
datatype: byte[4]
name: unpack_data
arguments: tag: D28
datatype: string

tool: D14: lig : %d ; col: %d : %f


tool: {"D7": [0x00,0x00,0x00,0x40]}

tool: D28: The matrix is not symmetric

assistant: ```c
int Symmetrize(float **delta, int n) {
  int lig;
  int col;
  float value;
  int symmetric;
  symmetric = 1;
  for (lig = 1; lig <= n; lig++) {
    for (col = 1; col < lig; col++) {
      if (delta[lig][col] != delta[col][lig]) {
        printf("lig : %d ; col: %d : %f\n", lig, col, delta[lig][col]);
        getchar();
        value = (delta[lig][col] + delta[col][lig]) / 2;
        delta[lig][col] = value;
        delta[col][lig] = value;
        symmetric = 0;
      }
    }
  }
  if (!symmetric)
    printf("The matrix is not symmetric");
  return (symmetric);
}
```