ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<ui_cond_timedwait>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  call   <gettimeofday@plt>
  xor    %edi,%edi
  call   <time@plt>
  mov    %ebx,%edx
  imul   $0x3e8,0xc(%rsp),%ecx
  mov    %rbp,%rdi
  mov    %rax,%r8
  movslq %ebx,%rax
  sar    $0x1f,%edx
  imul   $0x10624dd3,%rax,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x3e8,%eax,%edx
  cltq
  add    %r8,%rax
  sub    %edx,%ebx
  imul   $0xf4240,%ebx,%ebx
  add    %ebx,%ecx
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x44b82fa1,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x3c,%rdx
  sub    %esi,%edx
  movslq %edx,%rsi
  imul   $0x3b9aca00,%edx,%edx
  add    %rsi,%rax
  mov    %r12,%rsi
  mov    %rax,0x18(%rsp)
  sub    %edx,%ecx
  lea    0x10(%rsp),%rdx
  mov    %ecx,0x10(%rsp)
  call   <pthread_cond_timedwait@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ui_cond_timedwait(pthread_cond_t *cnd, pthread_mutex_t *mtx, int timeInMs) {
  struct timeval tv;
  struct timespec ts;
  gettimeofday(&tv, NULL);
  ts.tv_sec = time(NULL) + timeInMs / 1000;
  ts.tv_nsec = tv.tv_usec * 1000 + 1000 * 1000 * (timeInMs % 1000);
  ts.tv_sec += ts.tv_nsec / (1000 * 1000 * 1000);
  ts.tv_nsec %= (1000 * 1000 * 1000);
  return pthread_cond_timedwait(cnd, mtx, &ts);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<le64enc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <le32enc@plt>
  mov    -0x20(%rbp),%rax
  shr    $0x20,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <le32enc@plt>
  nop
  leave
  ret
```

assistant: ```c
extern void le64enc(void *buf, unsigned long long u) {
  unsigned char *p = (unsigned char *)buf;
  le32enc(p, (unsigned long)(u & 0xffffffffULL));
  le32enc(p + 4, (unsigned long)(u >> 32));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<le64enc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %esi,%esi
  call   <le32enc@plt>
  mov    %rbp,%rsi
  shr    $0x20,%rsi
  lea    0x4(%rbx),%rdi
  call   <le32enc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
extern void le64enc(void *buf, unsigned long long u) {
  unsigned char *p = (unsigned char *)buf;
  le32enc(p, (unsigned long)(u & 0xffffffffULL));
  le32enc(p + 4, (unsigned long)(u >> 32));
}
```
user: What is the c source code of the assembly code below?

```asm
<le64enc>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <le32enc@plt>
  mov    %rbp,%rsi
  add    $0x8,%rsp
  lea    0x4(%rbx),%rdi
  shr    $0x20,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <le32enc@plt>
```

assistant: ```c
extern void le64enc(void *buf, unsigned long long u) {
  unsigned char *p = (unsigned char *)buf;
  le32enc(p, (unsigned long)(u & 0xffffffffULL));
  le32enc(p + 4, (unsigned long)(u >> 32));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<le64enc>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %esi,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <le32enc@plt>
  mov    %rbp,%rsi
  add    $0x8,%rsp
  lea    0x4(%rbx),%rdi
  shr    $0x20,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <le32enc@plt>
```

assistant: ```c
extern void le64enc(void *buf, unsigned long long u) {
  unsigned char *p = (unsigned char *)buf;
  le32enc(p, (unsigned long)(u & 0xffffffffULL));
  le32enc(p + 4, (unsigned long)(u >> 32));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<spft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    -0x34(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <circe@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x4(%rbp),%xmm2
  movq   %xmm2,%rax
  mov    -0x38(%rbp),%r8d
  mov    -0x8(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <spf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double spft(z, x, y, k, n, key)
float *x, *y, *k;
int key, n;
double z;
{
  float dx;
  int m;
  m = circe(z, x, n);
  dx = z - *(x + m - 1);
  return spf(dx, x, y, k, m, key);
}
```
user: What is the c source code of the assembly code below:

```asm
<spft>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movq   %xmm0,%rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %ecx,%esi
  mov    %r8d,%r14d
  mov    $0x1,%eax
  call   <circe@plt>
  mov    %eax,%ecx
  cltq
  pxor   %xmm1,%xmm1
  cvtss2sd -0x4(%rbp,%rax,4),%xmm1
  movq   %rbx,%xmm0
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %r14d,%r8d
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <spf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double spft(z, x, y, k, n, key)
float *x, *y, *k;
int key, n;
double z;
{
  float dx;
  int m;
  m = circe(z, x, n);
  dx = z - *(x + m - 1);
  return spf(dx, x, y, k, m, key);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<spft>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %ecx,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <circe@plt>
  pxor   %xmm1,%xmm1
  mov    %ebx,%r8d
  mov    %r13,%rdx
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ecx
  cltq
  mov    %r12,%rsi
  cvtss2sd -0x4(%rbp,%rax,4),%xmm1
  mov    %rbp,%rdi
  mov    $0x1,%eax
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <spf@plt>
  add    $0x18,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  cvtsi2sd %eax,%xmm0
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double spft(z, x, y, k, n, key)
float *x, *y, *k;
int key, n;
double z;
{
  float dx;
  int m;
  m = circe(z, x, n);
  dx = z - *(x + m - 1);
  return spf(dx, x, y, k, m, key);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<spft>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  mov    %ecx,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <circe@plt>
  pxor   %xmm1,%xmm1
  mov    %ebx,%r8d
  mov    %r13,%rdx
  movsd  0x8(%rsp),%xmm0
  mov    %eax,%ecx
  cltq
  mov    %r12,%rsi
  cvtss2sd -0x4(%rbp,%rax,4),%xmm1
  mov    %rbp,%rdi
  mov    $0x1,%eax
  subsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <spf@plt>
  add    $0x18,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  cvtsi2sd %eax,%xmm0
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double spft(z, x, y, k, n, key)
float *x, *y, *k;
int key, n;
double z;
{
  float dx;
  int m;
  m = circe(z, x, n);
  dx = z - *(x + m - 1);
  return spf(dx, x, y, k, m, key);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%dx
  sub    $0x2e4,%dx
  mov    $0x0,%eax
  mov    %dl,%ah
  movsbl %dh,%edx
  mov    %dl,%al
  imul   $0xd80a,%ax,%ax
  add    $0x40ec,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy11;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    if (state[0UL] & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          state[0UL] *= state[0UL];
        } else {
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        state[0UL] += state[0UL];
      }
    } else {
      copy15 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy15;
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] * 674032645UL + (unsigned short)16620;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  sub    $0x2e4,%ax
  rol    $0x8,%ax
  imul   $0xd80a,%ax,%ax
  add    $0x40ec,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy11;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    if (state[0UL] & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          state[0UL] *= state[0UL];
        } else {
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        state[0UL] += state[0UL];
      }
    } else {
      copy15 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy15;
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] * 674032645UL + (unsigned short)16620;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  imul   $0xfb16,(%rdi),%ax
  sub    $0x2e4,%ax
  rol    $0x8,%ax
  imul   $0xd80a,%ax,%ax
  add    $0x40ec,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy11;
  char copy13;
  char copy14;
  char copy15;
  {
    state[0UL] = (input[0UL] + 914778474UL) * (unsigned short)64278;
    if (state[0UL] & (unsigned short)1) {
      if (state[0UL] & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          copy11 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy11;
          copy11 = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = copy11;
          state[0UL] *= state[0UL];
        } else {
          copy13 = *((char *)(&state[0UL]) + 0);
          *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
          *((char *)(&state[0UL]) + 1) = copy13;
        }
      } else {
        copy14 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy14;
        copy14 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy14;
        state[0UL] += state[0UL];
      }
    } else {
      copy15 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy15;
      state[0UL] += state[0UL];
    }
    output[0UL] = state[0UL] * 674032645UL + (unsigned short)16620;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<neoscrypt_blkxor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L19
L16:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x3,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x4,-0x14(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x34(%rbp),%edx
  movslq %edx,%rdx
  shr    $0x2,%rdx
  cmp    %rdx,%rax
  jb     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void neoscrypt_blkxor(void *dstp, const void *srcp, uint len) {
  ulong *dst = (ulong *)dstp;
  ulong *src = (ulong *)srcp;
  uint i;
  for (i = 0; i < (len / sizeof(ulong)); i += 4) {
    dst[i] ^= src[i];
    dst[i + 1] ^= src[i + 1];
    dst[i + 2] ^= src[i + 2];
    dst[i + 3] ^= src[i + 3];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<neoscrypt_blkxor>:
  endbr64
  movslq %edx,%rdx
  mov    %rdx,%rcx
  shr    $0x2,%rcx
  cmp    $0x3,%rdx
  jbe    L17
  mov    $0x0,%eax
L19:
  mov    (%rsi,%rax,4),%edx
  xor    %edx,(%rdi)
  mov    0x4(%rsi,%rax,4),%edx
  xor    %edx,0x4(%rdi)
  mov    0x8(%rsi,%rax,4),%edx
  xor    %edx,0x8(%rdi)
  mov    0xc(%rsi,%rax,4),%edx
  xor    %edx,0xc(%rdi)
  add    $0x4,%rax
  add    $0x10,%rdi
  cmp    %rcx,%rax
  jb     L19
L17:
  ret
```

assistant: ```c
void neoscrypt_blkxor(void *dstp, const void *srcp, uint len) {
  ulong *dst = (ulong *)dstp;
  ulong *src = (ulong *)srcp;
  uint i;
  for (i = 0; i < (len / sizeof(ulong)); i += 4) {
    dst[i] ^= src[i];
    dst[i + 1] ^= src[i + 1];
    dst[i + 2] ^= src[i + 2];
    dst[i + 3] ^= src[i + 3];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<neoscrypt_blkxor>:
  endbr64
  movslq %edx,%rdx
  shr    $0x2,%rdx
  je     L9
  lea    -0x4(,%rdx,4),%rax
  and    $0xfffffffffffffff0,%rax
  lea    0x10(%rdi,%rax,1),%rdx
  xchg   %ax,%ax
L5:
  mov    (%rsi),%eax
  xor    %eax,(%rdi)
  add    $0x10,%rsi
  mov    -0xc(%rsi),%eax
  xor    %eax,0x4(%rdi)
  mov    -0x8(%rsi),%eax
  xor    %eax,0x8(%rdi)
  mov    -0x4(%rsi),%eax
  xor    %eax,0xc(%rdi)
  add    $0x10,%rdi
  cmp    %rdx,%rdi
  jne    L5
L9:
  ret
```

assistant: ```c
void neoscrypt_blkxor(void *dstp, const void *srcp, uint len) {
  ulong *dst = (ulong *)dstp;
  ulong *src = (ulong *)srcp;
  uint i;
  for (i = 0; i < (len / sizeof(ulong)); i += 4) {
    dst[i] ^= src[i];
    dst[i + 1] ^= src[i + 1];
    dst[i + 2] ^= src[i + 2];
    dst[i + 3] ^= src[i + 3];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<neoscrypt_blkxor>:
  endbr64
  movslq %edx,%rdx
  shr    $0x2,%rdx
  je     L38
  lea    0xf(%rdi),%rax
  sub    %rsi,%rax
  cmp    $0x1e,%rax
  jbe    L17
  sub    $0x1,%rdx
  xor    %eax,%eax
  shr    $0x2,%rdx
  lea    0x1(%rdx),%rcx
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L2:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm1
  add    $0x1,%rdx
  pxor   %xmm1,%xmm0
  movups %xmm0,(%rdi,%rax,1)
  add    $0x10,%rax
  cmp    %rcx,%rdx
  jb     L2
  ret
L17:
  lea    -0x4(,%rdx,4),%rax
  and    $0xfffffffffffffff0,%rax
  lea    0x10(%rdi,%rax,1),%rdx
  nopl   0x0(%rax)
L3:
  mov    (%rsi),%eax
  xor    %eax,(%rdi)
  add    $0x10,%rsi
  mov    -0xc(%rsi),%eax
  xor    %eax,0x4(%rdi)
  mov    -0x8(%rsi),%eax
  xor    %eax,0x8(%rdi)
  mov    -0x4(%rsi),%eax
  xor    %eax,0xc(%rdi)
  add    $0x10,%rdi
  cmp    %rdi,%rdx
  jne    L3
L38:
  ret
```

assistant: ```c
void neoscrypt_blkxor(void *dstp, const void *srcp, uint len) {
  ulong *dst = (ulong *)dstp;
  ulong *src = (ulong *)srcp;
  uint i;
  for (i = 0; i < (len / sizeof(ulong)); i += 4) {
    dst[i] ^= src[i];
    dst[i + 1] ^= src[i + 1];
    dst[i + 2] ^= src[i + 2];
    dst[i + 3] ^= src[i + 3];
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<common_depth>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
L8:
  mov    -0x28(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L118
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L107
L118:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
L107:
  mov    -0x30(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L73
  mov    -0x8(%rbp),%rax
  sub    -0x30(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L126
L73:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
L126:
  cmpl   $0x0,-0x10(%rbp)
  je     L44
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L44
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L97
L44:
  mov    -0x14(%rbp),%eax
  jmp    L108
L97:
  mov    -0x10(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  jmp    L83
L115:
  addq   $0x1,-0x28(%rbp)
L83:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L115
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x30(%rbp)
  jmp    L109
L84:
  addq   $0x1,-0x30(%rbp)
L109:
  mov    -0x30(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L84
  addl   $0x1,-0x14(%rbp)
  jmp    L8
L108:
  leave
  ret
```

assistant: ```c
int common_depth(char *a, char *b) {
  int depth = 0;
  while (1) {
    char *c;
    int al, bl;
    c = strchr(a, '/');
    if (c)
      al = c - a;
    else
      al = strlen(a);
    c = strchr(b, '/');
    if (c)
      bl = c - b;
    else
      bl = strlen(b);
    if (al == 0 || al != bl || strncmp(a, b, al) != 0)
      return depth;
    a += al;
    while (*a == '/')
      a++;
    b += bl;
    while (*b == '/')
      b++;
    depth++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<common_depth>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    $0x0,%r14d
  jmp    L119
L73:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  jmp    L17
L33:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  jmp    L25
L34:
  add    $0x1,%r14d
L119:
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L73
  sub    %ebp,%r12d
L17:
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strchr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L33
  sub    %ebx,%r13d
L25:
  test   %r12d,%r12d
  je     L39
  cmp    %r13d,%r12d
  jne    L39
  mov    %r12d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L39
  movslq %r12d,%r12
  add    %r12,%rbp
  cmpb   $0x2f,0x0(%rbp)
  jne    L116
L46:
  add    $0x1,%rbp
  cmpb   $0x2f,0x0(%rbp)
  je     L46
L116:
  movslq %r13d,%r13
  add    %r13,%rbx
  cmpb   $0x2f,(%rbx)
  jne    L34
L101:
  add    $0x1,%rbx
  cmpb   $0x2f,(%rbx)
  je     L101
  jmp    L34
L39:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int common_depth(char *a, char *b) {
  int depth = 0;
  while (1) {
    char *c;
    int al, bl;
    c = strchr(a, '/');
    if (c)
      al = c - a;
    else
      al = strlen(a);
    c = strchr(b, '/');
    if (c)
      bl = c - b;
    else
      bl = strlen(b);
    if (al == 0 || al != bl || strncmp(a, b, al) != 0)
      return depth;
    a += al;
    while (*a == '/')
      a++;
    b += bl;
    while (*b == '/')
      b++;
    depth++;
  }
}
```