ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dist>:
  endbr64
  test   %edx,%edx
  jle    L12
  pxor   %xmm2,%xmm2
  movslq %edx,%rdx
  xor    %eax,%eax
  movapd %xmm2,%xmm0
  nopl   (%rax)
L5:
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  add    $0x1,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L5
  ucomisd %xmm0,%xmm2
  ja     L16
  sqrtsd %xmm0,%xmm0
  ret
  xchg   %ax,%ax
L12:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L16:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double dist(double *x, double *y, int n) {
  double d = 0;
  for (int i = 0; i < n; i++) {
    double diff = x[i] - y[i];
    d += diff * diff;
  }
  return sqrt(d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dist>:
  endbr64
  test   %edx,%edx
  jle    L8
  cmp    $0x1,%edx
  je     L52
  mov    %edx,%ecx
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  shr    %ecx
  movapd %xmm3,%xmm0
  shl    $0x4,%rcx
  nop
L19:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rsi,%rax,1),%xmm4
  add    $0x10,%rax
  subpd  %xmm4,%xmm1
  mulpd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rcx
  jne    L19
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L4
L18:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
L4:
  ucomisd %xmm0,%xmm3
  ja     L46
  sqrtsd %xmm0,%xmm0
  ret
L8:
  pxor   %xmm0,%xmm0
  sqrtsd %xmm0,%xmm0
  ret
L52:
  pxor   %xmm3,%xmm3
  xor    %eax,%eax
  movapd %xmm3,%xmm0
  jmp    L18
L46:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double dist(double *x, double *y, int n) {
  double d = 0;
  for (int i = 0; i < n; i++) {
    double diff = x[i] - y[i];
    d += diff * diff;
  }
  return sqrt(d);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mystrtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L72
L43:
  movl   $0x0,-0x4(%rbp)
  jmp    L37
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L67
  nop
  addl   $0x1,-0x4(%rbp)
L37:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  jmp    L17
L67:
  nop
L17:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  addl   $0x1,-0x8(%rbp)
L72:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L43
  jmp    L60
L53:
  nop
L60:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mystrtok(char *str, char *delim) {
  int i;
  int j;
  for (i = 0; *(str + i) != '\0'; i++) {
    for (j = 0; *(delim + j) != '\0'; j++) {
      if (*(str + i) == *(delim + j)) {
        break;
      } else {
        continue;
      }
    }
    if (*(str + i) == '\0') {
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mystrtok>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L41
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  sete   %r9b
  lea    0x1(%rdi),%rdx
  jmp    L58
L53:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L41
L58:
  cmp    %al,%r8b
  je     L53
  lea    0x1(%rsi),%rcx
  test   %r9b,%r9b
  jne    L53
L79:
  movzbl (%rcx),%edi
  add    $0x1,%rcx
  cmp    %al,%dil
  je     L53
  test   %dil,%dil
  jne    L79
  jmp    L53
L41:
  ret
```

assistant: ```c
void mystrtok(char *str, char *delim) {
  int i;
  int j;
  for (i = 0; *(str + i) != '\0'; i++) {
    for (j = 0; *(delim + j) != '\0'; j++) {
      if (*(str + i) == *(delim + j)) {
        break;
      } else {
        continue;
      }
    }
    if (*(str + i) == '\0') {
      break;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mystrtok>:
  endbr64
  ret
```

assistant: ```c
void mystrtok(char *str, char *delim) {
  int i;
  int j;
  for (i = 0; *(str + i) != '\0'; i++) {
    for (j = 0; *(delim + j) != '\0'; j++) {
      if (*(str + i) == *(delim + j)) {
        break;
      } else {
        continue;
      }
    }
    if (*(str + i) == '\0') {
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x54(%rbp)
  mov    -0x54(%rbp),%eax
  sub    $0x61,%eax
  cmp    $0x10,%eax
  ja     L66
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D11(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D11(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L28
  mov    $0x0,%eax
  call   <assemble@plt>
  jmp    L28
  mov    $0x0,%eax
  call   <display_header@plt>
  jmp    L28
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
  mov    $0x0,%eax
  call   <dump_memory@plt>
  jmp    L28
L66:
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L28:
  movq   $0x0,-0x68(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L44
  call   <__stack_chk_fail@plt>
L44:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D24
datatype: string
name: parse_data
arguments: data_label: D33
datatype: string

tool: D24: loading...


tool: D33: unknown command


assistant: ```c
void parse_input(char *input) {
  char *args[8];
  int p = input[0];
  switch (p) {
  case 'q':
    exit(0);
    break;
  case 'a':
    assemble();
    break;
  case 'h':
    display_header();
    break;
  case 'l':
    printf("loading...\n");
    break;
  case 'd':
    dump_memory();
    break;
  default:
    printf("unknown command\n");
    break;
  }
  input = 0;
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<parse_input>:
  endbr64
  sub    $0x8,%rsp
  movzbl (%rdi),%eax
  sub    $0x61,%eax
  cmp    $0x10,%al
  ja     L39
  movzbl %al,%eax
  lea    D24(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%edi
  call   <exit@plt>
L11:
  add    $0x8,%rsp
  ret
  mov    $0x0,%eax
  call   <assemble@plt>
  jmp    L11
  mov    $0x0,%eax
  call   <display_header@plt>
  jmp    L11
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L11
  mov    $0x0,%eax
  call   <dump_memory@plt>
  jmp    L11
L39:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D26
type_guessed: string

tool: D9: loading...


tool: D26: unknown command


assistant: ```c
void parse_input(char *input) {
  char *args[8];
  int p = input[0];
  switch (p) {
  case 'q':
    exit(0);
    break;
  case 'a':
    assemble();
    break;
  case 'h':
    display_header();
    break;
  case 'l':
    printf("loading...\n");
    break;
  case 'd':
    dump_memory();
    break;
  default:
    printf("unknown command\n");
    break;
  }
  input = 0;
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<parse_input>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x61,%eax
  cmp    $0x10,%al
  ja     L9
  lea    D12(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D19(%rip),%rdi
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
  xor    %eax,%eax
  jmp    10c0 <assemble@plt>
  nop
  xor    %eax,%eax
  jmp    10a0 <dump_memory@plt>
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  jmp    1090 <display_header@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D25(%rip),%rdi
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
  xor    %edi,%edi
  jmp    10d0 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D19
type_infered: string
name: read_data
arguments: tag: D25
type_infered: string

tool: D19: unknown command


tool: D25: loading...


assistant: ```c
void parse_input(char *input) {
  char *args[8];
  int p = input[0];
  switch (p) {
  case 'q':
    exit(0);
    break;
  case 'a':
    assemble();
    break;
  case 'h':
    display_header();
    break;
  case 'l':
    printf("loading...\n");
    break;
  case 'd':
    dump_memory();
    break;
  default:
    printf("unknown command\n");
    break;
  }
  input = 0;
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_input>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x61,%eax
  cmp    $0x10,%al
  ja     L9
  lea    D13(%rip),%rdx
  movzbl %al,%eax
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D9(%rip),%rdi
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
  xor    %eax,%eax
  jmp    10c0 <assemble@plt>
  nop
  xor    %eax,%eax
  jmp    10a0 <dump_memory@plt>
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  jmp    1090 <display_header@plt>
  nopw   0x0(%rax,%rax,1)
  lea    D27(%rip),%rdi
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
  xor    %edi,%edi
  jmp    10d0 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string
name: parse_data
arguments: data_label: D27
data_type: string

tool: D9: unknown command


tool: D27: loading...


assistant: ```c
void parse_input(char *input) {
  char *args[8];
  int p = input[0];
  switch (p) {
  case 'q':
    exit(0);
    break;
  case 'a':
    assemble();
    break;
  case 'h':
    display_header();
    break;
  case 'l':
    printf("loading...\n");
    break;
  case 'd':
    dump_memory();
    break;
  default:
    printf("unknown command\n");
    break;
  }
  input = 0;
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <ptrace@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thread(void *arg) {
  ptrace(PTRACE_TRACEME, 0, 0L, 0L);
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <ptrace@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *arg) {
  ptrace(PTRACE_TRACEME, 0, 0L, 0L);
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <ptrace@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *arg) {
  ptrace(PTRACE_TRACEME, 0, 0L, 0L);
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<thread>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <ptrace@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread(void *arg) {
  ptrace(PTRACE_TRACEME, 0, 0L, 0L);
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<draw_selection>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    %esi,0xc(%rsp)
  mov    %edx,%ebp
  mov    %ecx,%r14d
  mov    %ecx,0x4(%rsp)
  mov    %r8d,%ebx
  mov    $0x2,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attron@plt>
  test   %ebx,%ebx
  jle    L6
  mov    %ebp,%r15d
  lea    (%rbx,%rbp,1),%eax
  mov    %eax,0x8(%rsp)
  add    %r12d,%r14d
  jmp    L83
L57:
  mov    $0x2e,%edi
  call   <addch@plt>
L3:
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  je     L86
L14:
  movslq %ebp,%rbx
  imul   $0xffffffffd20d20d3,%rbx,%rbx
  shr    $0x20,%rbx
  add    %ebp,%ebx
  sar    $0x6,%ebx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  imul   $0x4e,%ebx,%eax
  mov    %ebp,%ebx
  sub    %eax,%ebx
  lea    0x1(%rbx),%esi
  mov    %r12d,%edi
  call   <move@plt>
  add    (%rsp),%ebx
  movslq %ebx,%rbx
  mov    0x0(%r13,%rbx,4),%edi
  test   %edi,%edi
  je     L57
  cmp    $0x1,%edi
  je     L118
  cmp    $0x2,%edi
  je     L107
  call   <addch@plt>
  jmp    L3
L118:
  mov    $0x78,%edi
  call   <addch@plt>
  jmp    L3
L107:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <addch@plt>
  jmp    L3
L86:
  add    $0x1,%r15d
  cmp    0x8(%rsp),%r15d
  je     L6
L83:
  cmpl   $0x0,0x4(%rsp)
  jle    L86
  movslq %r15d,%rax
  imul   $0x6bca1af3,%rax,%rax
  sar    $0x23,%rax
  mov    %r15d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,8),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %r15d,%eax
  sub    %edx,%eax
  lea    0x2(%rax),%r12d
  imul   $0x4e,%eax,%eax
  mov    %eax,(%rsp)
  mov    0xc(%rsp),%ebp
  jmp    L14
L6:
  mov    $0x2,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attroff@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void draw_selection(uint8_t map[], int selectedX, int selectedY, int selectedWidth, int selectedHeight) {
  int i, j;
  attron(COLOR_PAIR(2));
  for (i = 0; i < selectedHeight; i++) {
    for (j = 0; j < selectedWidth; j++) {
      move(2 + ((i + selectedY) % 19), 1 + ((j + selectedX) % 78));
      uint8_t val = map[((i + selectedY) % 19) * 78 + ((j + selectedX) % 78)];
      if (val == 0) {
        addch('.');
      } else if (val == 1) {
        addch('x');
      } else if (val == 2) {
        addch(ACS_CKBOARD);
      } else {
        addch(val);
      }
    }
  }
  attroff(COLOR_PAIR(2));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<draw_selection>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x2,%edi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  mov    %ecx,0x4(%rsp)
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attron@plt>
  test   %ebx,%ebx
  jle    L78
  add    %r14d,%ebx
  mov    %r14d,(%rsp)
  add    %ebp,%r15d
  mov    %ebx,0x8(%rsp)
  mov    %r15d,%r13d
  nopw   0x0(%rax,%rax,1)
L103:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L58
  movslq (%rsp),%rbx
  mov    0xc(%rsp),%r15d
  mov    %rbx,%rcx
  imul   $0x6bca1af3,%rbx,%rbx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sar    $0x23,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,8),%eax
  lea    (%rbx,%rax,2),%eax
  sub    %eax,%ecx
  imul   $0x4e,%ecx,%ebx
  lea    0x2(%rcx),%ebp
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L44:
  cmp    $0x1,%edi
  je     L84
  cmp    $0x2,%edi
  je     L6
  call   <addch@plt>
L10:
  add    $0x1,%r15d
  cmp    %r15d,%r13d
  je     L58
L24:
  movslq %r15d,%rdx
  mov    %r15d,%eax
  mov    %r15d,%r14d
  mov    %ebp,%edi
  imul   $0xffffffffd20d20d3,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  add    %r15d,%edx
  sar    $0x6,%edx
  sub    %eax,%edx
  imul   $0x4e,%edx,%eax
  sub    %eax,%r14d
  lea    0x1(%r14),%esi
  call   <move@plt>
  lea    (%r14,%rbx,1),%edx
  movslq %edx,%rdx
  mov    (%r12,%rdx,4),%edi
  test   %edi,%edi
  jne    L44
  mov    $0x2e,%edi
  add    $0x1,%r15d
  call   <addch@plt>
  cmp    %r15d,%r13d
  jne    L24
L58:
  addl   $0x1,(%rsp)
  mov    (%rsp),%eax
  cmp    0x8(%rsp),%eax
  jne    L103
L78:
  mov    $0x2,%edi
  call   <COLOR_PAIR@plt>
  add    $0x18,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <attroff@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <addch@plt>
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L84:
  mov    $0x78,%edi
  call   <addch@plt>
  jmp    L10
```

assistant: ```c
void draw_selection(uint8_t map[], int selectedX, int selectedY, int selectedWidth, int selectedHeight) {
  int i, j;
  attron(COLOR_PAIR(2));
  for (i = 0; i < selectedHeight; i++) {
    for (j = 0; j < selectedWidth; j++) {
      move(2 + ((i + selectedY) % 19), 1 + ((j + selectedX) % 78));
      uint8_t val = map[((i + selectedY) % 19) * 78 + ((j + selectedX) % 78)];
      if (val == 0) {
        addch('.');
      } else if (val == 1) {
        addch('x');
      } else if (val == 2) {
        addch(ACS_CKBOARD);
      } else {
        addch(val);
      }
    }
  }
  attroff(COLOR_PAIR(2));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<draw_selection>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x2,%edi
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  call   <COLOR_PAIR@plt>
  mov    %eax,%edi
  call   <attron@plt>
  test   %ebx,%ebx
  jle    L79
  test   %ebp,%ebp
  jle    L79
  add    %r14d,%ebx
  mov    %r14d,0x4(%rsp)
  lea    0x0(%rbp,%r15,1),%r13d
  mov    %ebx,0xc(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L42:
  movslq 0x4(%rsp),%rbx
  mov    0x8(%rsp),%r15d
  mov    %rbx,%rcx
  imul   $0x6bca1af3,%rbx,%rbx
  mov    %ecx,%eax
  sar    $0x1f,%eax
  sar    $0x23,%rbx
  sub    %eax,%ebx
  lea    (%rbx,%rbx,8),%eax
  lea    (%rbx,%rax,2),%eax
  sub    %eax,%ecx
  imul   $0x4e,%ecx,%ebx
  lea    0x2(%rcx),%ebp
  jmp    L22
  nop
L4:
  cmp    $0x1,%edi
  je     L3
  cmp    $0x2,%edi
  je     L28
  call   <addch@plt>
L38:
  add    $0x1,%r15d
  cmp    %r13d,%r15d
  je     L7
L22:
  movslq %r15d,%rdx
  mov    %r15d,%eax
  mov    %r15d,%r14d
  mov    %ebp,%edi
  imul   $0xffffffffd20d20d3,%rdx,%rdx
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  add    %r15d,%edx
  sar    $0x6,%edx
  sub    %eax,%edx
  imul   $0x4e,%edx,%eax
  sub    %eax,%r14d
  lea    0x1(%r14),%esi
  call   <move@plt>
  lea    (%r14,%rbx,1),%edx
  movslq %edx,%rdx
  mov    (%r12,%rdx,4),%edi
  test   %edi,%edi
  jne    L4
  mov    $0x2e,%edi
  add    $0x1,%r15d
  call   <addch@plt>
  cmp    %r13d,%r15d
  jne    L22
L7:
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  cmp    %eax,0xc(%rsp)
  jne    L42
L79:
  mov    $0x2,%edi
  call   <COLOR_PAIR@plt>
  add    $0x18,%rsp
  pop    %rbx
  mov    %eax,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10a0 <attroff@plt>
  nopl   0x0(%rax)
L28:
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <addch@plt>
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x78,%edi
  call   <addch@plt>
  jmp    L38
```

assistant: ```c
void draw_selection(uint8_t map[], int selectedX, int selectedY, int selectedWidth, int selectedHeight) {
  int i, j;
  attron(COLOR_PAIR(2));
  for (i = 0; i < selectedHeight; i++) {
    for (j = 0; j < selectedWidth; j++) {
      move(2 + ((i + selectedY) % 19), 1 + ((j + selectedX) % 78));
      uint8_t val = map[((i + selectedY) % 19) * 78 + ((j + selectedX) % 78)];
      if (val == 0) {
        addch('.');
      } else if (val == 1) {
        addch('x');
      } else if (val == 2) {
        addch(ACS_CKBOARD);
      } else {
        addch(val);
      }
    }
  }
  attroff(COLOR_PAIR(2));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
data_type: string
name: retrieve_data
arguments: label: D13
data_type: string

tool: D11: IN SWAP: 

tool: D13: addr of a = %u, addr of b = %u



assistant: ```c
void swap(int *pa, int *pb) {
  printf("IN SWAP: \n");
  printf("addr of a = %u, addr of b = %u\n\n", pa, pb);
  int temp = *pa;
  *pa = *pb;
  *pb = temp;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D1(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x0(%rbp),%eax
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D1: IN SWAP: 

tool: D0: addr of a = %u, addr of b = %u



assistant: ```c
void swap(int *pa, int *pb) {
  printf("IN SWAP: \n");
  printf("addr of a = %u, addr of b = %u\n\n", pa, pb);
  int temp = *pa;
  *pa = *pb;
  *pb = temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D18(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x0(%rbp),%eax
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
datatype: string
name: parse_data
arguments: data_label: D6
datatype: string

tool: D18: IN SWAP: 

tool: D6: addr of a = %u, addr of b = %u



assistant: ```c
void swap(int *pa, int *pb) {
  printf("IN SWAP: \n");
  printf("addr of a = %u, addr of b = %u\n\n", pa, pb);
  int temp = *pa;
  *pa = *pb;
  *pb = temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x0(%rbp),%eax
  mov    (%rbx),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string

tool: D13: IN SWAP: 

tool: D0: addr of a = %u, addr of b = %u



assistant: ```c
void swap(int *pa, int *pb) {
  printf("IN SWAP: \n");
  printf("addr of a = %u, addr of b = %u\n\n", pa, pb);
  int temp = *pa;
  *pa = *pb;
  *pb = temp;
}
```