ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  xor    %eax,%eax
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L37:
  movzbl (%rdi,%rax,1),%ecx
  movsbl (%rsi,%rax,1),%r8d
  cmp    %r8b,%cl
  jne    L21
  add    $0x1,%rax
  test   %cl,%cl
  je     L1
L16:
  cmp    %rdx,%rax
  jne    L37
L1:
  xor    %eax,%eax
  ret
  xchg   %ax,%ax
L21:
  movsbl %cl,%eax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *str1, const char *str2, size_t n) {
  register const char *p1 = str1;
  register const char *p2 = str2;
  while (n-- > 0) {
    if (*p1 != *p2)
      return (*p1 - *p2);
    else
      p1++, p2++;
    if (!*(p1 - 1))
      break;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ASN1_UNIVERSALSTRING_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L77
  mov    $0x0,%eax
  jmp    L123
L77:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  and    $0x3,%eax
  test   %eax,%eax
  je     L67
  mov    $0x0,%eax
  jmp    L123
L67:
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L39
L54:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  addq   $0x4,-0x8(%rbp)
  addl   $0x4,-0xc(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L54
L71:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jge    L78
  mov    $0x0,%eax
  jmp    L123
L78:
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x3,-0xc(%rbp)
  jmp    L63
L47:
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rcx),%edx
  mov    %dl,(%rax)
  addl   $0x4,-0xc(%rbp)
L63:
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L47
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,0x8(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ASN1_PRINTABLE_type@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x1,%eax
L123:
  leave
  ret
```

assistant: ```c
int ASN1_UNIVERSALSTRING_to_string(ASN1_UNIVERSALSTRING *s) {
  int i;
  unsigned char *p;
  if (s->type != V_ASN1_UNIVERSALSTRING)
    return (0);
  if ((s->length % 4) != 0)
    return (0);
  p = s->data;
  for (i = 0; i < s->length; i += 4) {
    if ((p[0] != '\0') || (p[1] != '\0') || (p[2] != '\0'))
      break;
    else
      p += 4;
  }
  if (i < s->length)
    return (0);
  p = s->data;
  for (i = 3; i < s->length; i += 4) {
    *(p++) = s->data[i];
  }
  *(p) = '\0';
  s->length /= 4;
  s->type = ASN1_PRINTABLE_type(s->data, s->length);
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ASN1_UNIVERSALSTRING_to_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  mov    D9(%rip),%rdx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rbx)
  jne    L55
  mov    0x8(%rbx),%ecx
  test   $0x3,%cl
  jne    L55
  mov    0x10(%rbx),%rdx
  test   %ecx,%ecx
  jle    L42
  mov    $0x0,%eax
L21:
  mov    %eax,%esi
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L37
  cmpb   $0x0,0x1(%rdx,%rax,1)
  jne    L37
  cmpb   $0x0,0x2(%rdx,%rax,1)
  jne    L37
  add    $0x4,%rax
  cmp    %eax,%ecx
  jg     L21
  jmp    L42
L37:
  mov    $0x0,%eax
  cmp    %esi,%ecx
  jg     L55
L42:
  cmp    $0x3,%ecx
  jle    L23
  mov    $0x3,%eax
L71:
  add    $0x1,%rdx
  mov    0x10(%rbx),%rcx
  movzbl (%rcx,%rax,1),%ecx
  mov    %cl,-0x1(%rdx)
  add    $0x4,%rax
  cmp    %eax,0x8(%rbx)
  jg     L71
L23:
  movb   $0x0,(%rdx)
  mov    0x8(%rbx),%eax
  lea    0x3(%rax),%esi
  test   %eax,%eax
  cmovns %eax,%esi
  sar    $0x2,%esi
  mov    %esi,0x8(%rbx)
  mov    0x10(%rbx),%rdi
  call   <ASN1_PRINTABLE_type@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L55:
  pop    %rbx
  ret
```

assistant: ```c
int ASN1_UNIVERSALSTRING_to_string(ASN1_UNIVERSALSTRING *s) {
  int i;
  unsigned char *p;
  if (s->type != V_ASN1_UNIVERSALSTRING)
    return (0);
  if ((s->length % 4) != 0)
    return (0);
  p = s->data;
  for (i = 0; i < s->length; i += 4) {
    if ((p[0] != '\0') || (p[1] != '\0') || (p[2] != '\0'))
      break;
    else
      p += 4;
  }
  if (i < s->length)
    return (0);
  p = s->data;
  for (i = 3; i < s->length; i += 4) {
    *(p++) = s->data[i];
  }
  *(p) = '\0';
  s->length /= 4;
  s->type = ASN1_PRINTABLE_type(s->data, s->length);
  return (1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ASN1_UNIVERSALSTRING_to_string>:
  endbr64
  mov    D0(%rip),%rdx
  push   %rbx
  mov    %rdi,%rbx
  xor    %eax,%eax
  mov    (%rdx),%rdi
  cmp    %rdi,(%rbx)
  jne    L99
  mov    0x8(%rbx),%ecx
  test   $0x3,%cl
  jne    L99
  mov    0x10(%rbx),%rdx
  test   %ecx,%ecx
  jle    L9
  xor    %eax,%eax
  jmp    L48
  nopl   (%rax)
L13:
  cmpb   $0x0,0x1(%rdx,%rax,1)
  jne    L76
  cmpb   $0x0,0x2(%rdx,%rax,1)
  jne    L76
  add    $0x4,%rax
  cmp    %eax,%ecx
  jle    L9
L48:
  cmpb   $0x0,(%rdx,%rax,1)
  mov    %eax,%esi
  je     L13
L76:
  xor    %eax,%eax
  cmp    %esi,%ecx
  jg     L99
L9:
  cmp    $0x3,%ecx
  jle    L1
  mov    %rdx,%rcx
  mov    $0x3,%eax
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L21:
  mov    0x10(%rbx),%rcx
L59:
  movzbl (%rcx,%rax,1),%ecx
  add    $0x1,%rdx
  add    $0x4,%rax
  mov    %cl,-0x1(%rdx)
  cmp    %eax,0x8(%rbx)
  jg     L21
L1:
  movb   $0x0,(%rdx)
  mov    0x8(%rbx),%eax
  mov    0x10(%rbx),%rdi
  test   %eax,%eax
  lea    0x3(%rax),%esi
  cmovns %eax,%esi
  sar    $0x2,%esi
  mov    %esi,0x8(%rbx)
  call   <ASN1_PRINTABLE_type@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L99:
  pop    %rbx
  ret
```

assistant: ```c
int ASN1_UNIVERSALSTRING_to_string(ASN1_UNIVERSALSTRING *s) {
  int i;
  unsigned char *p;
  if (s->type != V_ASN1_UNIVERSALSTRING)
    return (0);
  if ((s->length % 4) != 0)
    return (0);
  p = s->data;
  for (i = 0; i < s->length; i += 4) {
    if ((p[0] != '\0') || (p[1] != '\0') || (p[2] != '\0'))
      break;
    else
      p += 4;
  }
  if (i < s->length)
    return (0);
  p = s->data;
  for (i = 3; i < s->length; i += 4) {
    *(p++) = s->data[i];
  }
  *(p) = '\0';
  s->length /= 4;
  s->type = ASN1_PRINTABLE_type(s->data, s->length);
  return (1);
}
```
user: What is the c source code of the assembly code below:

```asm
<ASN1_UNIVERSALSTRING_to_string>:
  endbr64
  mov    D8(%rip),%rdx
  push   %rbx
  mov    %rdi,%rbx
  xor    %eax,%eax
  mov    (%rdx),%rdi
  cmp    %rdi,(%rbx)
  jne    L31
  mov    0x8(%rbx),%ecx
  test   $0x3,%cl
  jne    L31
  mov    0x10(%rbx),%rdx
  test   %ecx,%ecx
  jle    L44
  xor    %eax,%eax
  jmp    L90
  nopl   (%rax)
L103:
  cmpb   $0x0,0x1(%rdx,%rax,1)
  jne    L75
  cmpb   $0x0,0x2(%rdx,%rax,1)
  jne    L75
  add    $0x4,%rax
  cmp    %eax,%ecx
  jle    L44
L90:
  cmpb   $0x0,(%rdx,%rax,1)
  mov    %eax,%esi
  je     L103
L75:
  xor    %eax,%eax
  cmp    %esi,%ecx
  jg     L31
L44:
  cmp    $0x3,%ecx
  jle    L96
  movzbl 0x3(%rdx),%eax
  lea    0x1(%rdx),%rcx
  mov    %al,(%rdx)
  cmpl   $0x7,0x8(%rbx)
  mov    $0x7,%eax
  jle    L48
  cs nopw 0x0(%rax,%rax,1)
L40:
  mov    0x10(%rbx),%rdx
  add    $0x1,%rcx
  movzbl (%rdx,%rax,1),%edx
  add    $0x4,%rax
  mov    %dl,-0x1(%rcx)
  cmp    %eax,0x8(%rbx)
  jg     L40
L48:
  movb   $0x0,(%rcx)
  mov    0x8(%rbx),%eax
  mov    0x10(%rbx),%rdi
  test   %eax,%eax
  lea    0x3(%rax),%esi
  cmovns %eax,%esi
  sar    $0x2,%esi
  mov    %esi,0x8(%rbx)
  call   <ASN1_PRINTABLE_type@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
L31:
  pop    %rbx
  ret
L96:
  mov    %rdx,%rcx
  jmp    L48
```

assistant: ```c
int ASN1_UNIVERSALSTRING_to_string(ASN1_UNIVERSALSTRING *s) {
  int i;
  unsigned char *p;
  if (s->type != V_ASN1_UNIVERSALSTRING)
    return (0);
  if ((s->length % 4) != 0)
    return (0);
  p = s->data;
  for (i = 0; i < s->length; i += 4) {
    if ((p[0] != '\0') || (p[1] != '\0') || (p[2] != '\0'))
      break;
    else
      p += 4;
  }
  if (i < s->length)
    return (0);
  p = s->data;
  for (i = 3; i < s->length; i += 4) {
    *(p++) = s->data[i];
  }
  *(p) = '\0';
  s->length /= 4;
  s->type = ASN1_PRINTABLE_type(s->data, s->length);
  return (1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L17:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L24:
  cmpl   $0x0,-0x18(%rbp)
  jle    L47
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L17
L47:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L13
  mov    $0xffffffff,%eax
  jmp    L48
L13:
  mov    -0x8(%rbp),%eax
L48:
  leave
  ret
```

assistant: ```c
ssize_t write_all(int fd, char *buff, int len) {
  ssize_t wrote = 0, w = 0;
  while (len > 0 && (w = write(fd, buff + wrote, len)) > 0) {
    wrote += w;
    len -= w;
  }
  if (w == -1) {
    return -1;
  }
  return wrote;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_all>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    $0x0,%ebp
  test   %edx,%edx
  jle    L7
L19:
  movslq %ebp,%rsi
  add    %r12,%rsi
  mov    %ebx,%edx
  mov    %r13d,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L9
  add    %eax,%ebp
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L19
  jmp    L7
L9:
  cmp    $0xffffffff,%eax
  cmove  %eax,%ebp
L7:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_all(int fd, char *buff, int len) {
  ssize_t wrote = 0, w = 0;
  while (len > 0 && (w = write(fd, buff + wrote, len)) > 0) {
    wrote += w;
    len -= w;
  }
  if (w == -1) {
    return -1;
  }
  return wrote;
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_all>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jg     L1
  jmp    L5
  nop
L20:
  sub    %eax,%ebx
  add    %eax,%r13d
  test   %ebx,%ebx
  jle    L5
L1:
  movslq %r13d,%rsi
  mov    %ebx,%edx
  mov    %r12d,%edi
  add    %rbp,%rsi
  call   <write@plt>
  test   %eax,%eax
  jg     L20
  cmp    $0xffffffff,%eax
  mov    $0xffffffff,%eax
  cmove  %eax,%r13d
L5:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_all(int fd, char *buff, int len) {
  ssize_t wrote = 0, w = 0;
  while (len > 0 && (w = write(fd, buff + wrote, len)) > 0) {
    wrote += w;
    len -= w;
  }
  if (w == -1) {
    return -1;
  }
  return wrote;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_all>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %edx,%edx
  jg     L20
  jmp    L18
  nop
L27:
  sub    %eax,%ebx
  add    %eax,%r13d
  test   %ebx,%ebx
  jle    L18
L20:
  movslq %r13d,%rsi
  mov    %ebx,%edx
  mov    %r12d,%edi
  add    %rbp,%rsi
  call   <write@plt>
  test   %eax,%eax
  jg     L27
  cmp    $0xffffffff,%eax
  mov    $0xffffffff,%eax
  cmove  %eax,%r13d
L18:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t write_all(int fd, char *buff, int len) {
  ssize_t wrote = 0, w = 0;
  while (len > 0 && (w = write(fd, buff + wrote, len)) > 0) {
    wrote += w;
    len -= w;
  }
  if (w == -1) {
    return -1;
  }
  return wrote;
}
```
user: What is the c source code of the assembly code below:

```asm
<quick_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L7
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick_sort>
L7:
  nop
  leave
  ret
```

assistant: ```c
void quick_sort(int list[], int left, int right) {
  int i, j;
  if (left < right) {
    int j = partition(list, left, right);
    quick_sort(list, left, j - 1);
    quick_sort(list, j + 1, right);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<quick_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L4
  ret
L4:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quick_sort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quick_sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quick_sort(int list[], int left, int right) {
  int i, j;
  if (left < right) {
    int j = partition(list, left, right);
    quick_sort(list, left, j - 1);
    quick_sort(list, j + 1, right);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printPadding>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  movl   $0x8,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L79
  movl   $0x0,-0x1c(%rbp)
  jmp    L73
L79:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
L73:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L3
  movl   $0x0,-0x18(%rbp)
  jmp    L54
L52:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L52
  jmp    L53
L3:
  movl   $0x0,-0x14(%rbp)
  jmp    L41
L62:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L41:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L62
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L65
L20:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x2c(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L65:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L20
L53:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *printPadding(char *string, char padding) {
  int size = 8;
  char *result = (char *)calloc(size + 1, sizeof(char));
  int sizeString;
  if (string == NULL) {
    sizeString = 0;
  } else {
    sizeString = strlen(string);
  }
  if (size < sizeString) {
    for (int i = 0; i < size; i++) {
      *(result + i) = *(string + i);
    }
  } else {
    for (int i = 0; i < sizeString; i++) {
      *(result + i) = *(string + i);
    }
    for (int i = sizeString; i < size; i++) {
      *(result + i) = padding;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printPadding>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    $0x1,%esi
  mov    $0x9,%edi
  call   <calloc@plt>
  mov    %rax,%rbp
  test   %r12,%r12
  je     L37
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x8,%eax
  jle    L40
  lea    0x8(%rbp),%rcx
  mov    %rbp,%rax
  mov    %r12,%rsi
  sub    %rbp,%rsi
L86:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L86
  jmp    L65
L40:
  test   %eax,%eax
  jle    L60
  lea    -0x1(%rax),%edx
  lea    0x1(%rbp,%rdx,1),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  sub    %rbp,%rsi
L18:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L18
L60:
  cmp    $0x7,%eax
  jle    L84
  jmp    L65
L37:
  mov    $0x0,%eax
L84:
  movslq %eax,%rcx
  lea    (%rcx,%rbp,1),%rdx
  lea    0x1(%rbp,%rcx,1),%rcx
  mov    $0x7,%esi
  sub    %eax,%esi
  lea    (%rcx,%rsi,1),%rax
L47:
  mov    %bl,(%rdx)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L47
L65:
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *printPadding(char *string, char padding) {
  int size = 8;
  char *result = (char *)calloc(size + 1, sizeof(char));
  int sizeString;
  if (string == NULL) {
    sizeString = 0;
  } else {
    sizeString = strlen(string);
  }
  if (size < sizeString) {
    for (int i = 0; i < size; i++) {
      *(result + i) = *(string + i);
    }
  } else {
    for (int i = 0; i < sizeString; i++) {
      *(result + i) = *(string + i);
    }
    for (int i = sizeString; i < size; i++) {
      *(result + i) = padding;
    }
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printPadding>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x9,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rbx,%rbx
  je     L54
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x8,%eax
  jg     L44
  test   %eax,%eax
  jle    L61
  lea    -0x1(%rax),%edx
  sub    %r12,%rbx
  lea    0x1(%r12,%rdx,1),%rsi
  mov    %rbx,%rdi
  mov    %r12,%rdx
  nopw   0x0(%rax,%rax,1)
L43:
  movzbl (%rdi,%rdx,1),%ecx
  add    $0x1,%rdx
  mov    %cl,-0x1(%rdx)
  cmp    %rsi,%rdx
  jne    L43
L61:
  cmp    $0x8,%eax
  je     L5
L66:
  mov    $0x8,%edx
  movsbl %bpl,%esi
  sub    %eax,%edx
  cltq
  lea    (%r12,%rax,1),%rdi
  call   <memset@plt>
L5:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L44:
  sub    %r12,%rbx
  lea    0x8(%r12),%rcx
  mov    %r12,%rax
  mov    %rbx,%rdi
  cs nopw 0x0(%rax,%rax,1)
L15:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rcx
  jne    L15
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L54:
  xor    %eax,%eax
  jmp    L66
```

assistant: ```c
char *printPadding(char *string, char padding) {
  int size = 8;
  char *result = (char *)calloc(size + 1, sizeof(char));
  int sizeString;
  if (string == NULL) {
    sizeString = 0;
  } else {
    sizeString = strlen(string);
  }
  if (size < sizeString) {
    for (int i = 0; i < size; i++) {
      *(result + i) = *(string + i);
    }
  } else {
    for (int i = 0; i < sizeString; i++) {
      *(result + i) = *(string + i);
    }
    for (int i = sizeString; i < size; i++) {
      *(result + i) = padding;
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printPadding>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x9,%edi
  push   %rbx
  mov    %esi,%ebx
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rbp,%rbp
  je     L0
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rdi
  cmp    $0x8,%edi
  jg     L119
  test   %edi,%edi
  jle    L142
  lea    0x1(%rbp),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x6,%rax
  jbe    L18
  lea    -0x1(%rdi),%eax
  cmp    $0x6,%eax
  jbe    L18
L27:
  mov    0x0(%rbp),%rax
  mov    %rax,(%r12)
L72:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L119:
  lea    0x1(%rbp),%rdx
  mov    %r12,%rax
  sub    %rdx,%rax
  cmp    $0x6,%rax
  ja     L27
  movzbl 0x0(%rbp),%eax
  mov    %al,(%r12)
  movzbl 0x1(%rbp),%eax
  mov    %al,0x1(%r12)
  movzbl 0x2(%rbp),%eax
  mov    %al,0x2(%r12)
  movzbl 0x3(%rbp),%eax
  mov    %al,0x3(%r12)
  movzbl 0x4(%rbp),%eax
  mov    %al,0x4(%r12)
  movzbl 0x5(%rbp),%eax
  mov    %al,0x5(%r12)
  movzbl 0x6(%rbp),%eax
  mov    %al,0x6(%r12)
  movzbl 0x7(%rbp),%eax
  mov    %al,0x7(%r12)
  jmp    L72
  nopl   0x0(%rax)
L0:
  xor    %edi,%edi
L102:
  mov    $0x8,%edx
  movsbl %bl,%esi
  sub    %edi,%edx
  add    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L142:
  cmp    $0x8,%edi
  jne    L102
  jmp    L72
  cs nopw 0x0(%rax,%rax,1)
L18:
  movzbl 0x0(%rbp),%eax
  mov    %al,(%r12)
  cmp    $0x1,%edi
  je     L102
  movzbl 0x1(%rbp),%eax
  mov    %al,0x1(%r12)
  cmp    $0x2,%edi
  je     L102
  movzbl 0x2(%rbp),%eax
  mov    %al,0x2(%r12)
  cmp    $0x3,%edi
  je     L102
  movzbl 0x3(%rbp),%eax
  mov    %al,0x3(%r12)
  cmp    $0x4,%edi
  je     L102
  movzbl 0x4(%rbp),%eax
  mov    %al,0x4(%r12)
  cmp    $0x5,%edi
  je     L102
  movzbl 0x5(%rbp),%eax
  mov    %al,0x5(%r12)
  cmp    $0x6,%edi
  je     L102
  movzbl 0x6(%rbp),%eax
  mov    %al,0x6(%r12)
  cmp    $0x8,%edi
  jne    L74
  movzbl 0x7(%rbp),%eax
  mov    %al,0x7(%r12)
  jmp    L72
L74:
  mov    $0x7,%edi
  jmp    L102
```

assistant: ```c
char *printPadding(char *string, char padding) {
  int size = 8;
  char *result = (char *)calloc(size + 1, sizeof(char));
  int sizeString;
  if (string == NULL) {
    sizeString = 0;
  } else {
    sizeString = strlen(string);
  }
  if (size < sizeString) {
    for (int i = 0; i < size; i++) {
      *(result + i) = *(string + i);
    }
  } else {
    for (int i = 0; i < sizeString; i++) {
      *(result + i) = *(string + i);
    }
    for (int i = sizeString; i < size; i++) {
      *(result + i) = padding;
    }
  }
  return result;
}
```