ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L9
  sub    $0x8,%rsp
  movslq %edx,%rdx
  movzbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L9:
  mov    %rdi,%rax
  ret
```

assistant: ```c
extern void *memset(void *d, unsigned char val, int count) {
  int i;
  unsigned char *dest = d;
  for (i = 0; i < count; i++)
    dest[i] = val;
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hexdump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L14
L11:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L11
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: %02x

assistant: ```c
void hexdump(void *buf, size_t len) {
  uint8_t *p;
  size_t i;
  p = buf;
  for (i = 0; i < len; i++)
    printf("%02x", p[i]);
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hexdump>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L14
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D7(%rip),%r13
L3:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L3
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string

tool: D7: %02x

assistant: ```c
void hexdump(void *buf, size_t len) {
  uint8_t *p;
  size_t i;
  p = buf;
  for (i = 0; i < len; i++)
    printf("%02x", p[i]);
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<hexdump>:
  endbr64
  test   %rsi,%rsi
  je     L8
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L3
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type: string

tool: D2: %02x

assistant: ```c
void hexdump(void *buf, size_t len) {
  uint8_t *p;
  size_t i;
  p = buf;
  for (i = 0; i < len; i++)
    printf("%02x", p[i]);
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hexdump>:
  endbr64
  test   %rsi,%rsi
  je     L5
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L7
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L5:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string

tool: D2: %02x

assistant: ```c
void hexdump(void *buf, size_t len) {
  uint8_t *p;
  size_t i;
  p = buf;
  for (i = 0; i < len; i++)
    printf("%02x", p[i]);
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<t6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  andl   $0xffffffe0,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int t6(int len, void *dummy, short *__restrict x) {
  len = len & ~31;
  int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<t6>:
  endbr64
  and    $0xffffffe0,%edi
  jle    L3
  mov    %rdx,%rax
  lea    -0x1(%rdi),%ecx
  lea    0x2(%rdx,%rcx,2),%rsi
  mov    $0x0,%edx
L21:
  movswl (%rax),%ecx
  add    %ecx,%edx
  add    $0x2,%rax
  cmp    %rsi,%rax
  jne    L21
L23:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L23
```

assistant: ```c
int t6(int len, void *dummy, short *__restrict x) {
  len = len & ~31;
  int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<t6>:
  endbr64
  and    $0xffffffe0,%edi
  jle    L7
  lea    -0x1(%rdi),%eax
  lea    0x2(%rdx,%rax,2),%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  movswl (%rdx),%ecx
  add    $0x2,%rdx
  add    %ecx,%eax
  cmp    %rsi,%rdx
  jne    L13
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int t6(int len, void *dummy, short *__restrict x) {
  len = len & ~31;
  int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<t6>:
  endbr64
  and    $0xffffffe0,%edi
  jle    L14
  shr    $0x3,%edi
  pxor   %xmm1,%xmm1
  pxor   %xmm4,%xmm4
  lea    -0x1(%rdi),%eax
  shl    $0x4,%rax
  lea    0x10(%rdx,%rax,1),%rax
L9:
  movdqu (%rdx),%xmm0
  movdqa %xmm4,%xmm2
  add    $0x10,%rdx
  pcmpgtw %xmm0,%xmm2
  movdqa %xmm0,%xmm3
  punpcklwd %xmm2,%xmm3
  punpckhwd %xmm2,%xmm0
  paddd  %xmm3,%xmm1
  paddd  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L9
  movdqa %xmm1,%xmm0
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int t6(int len, void *dummy, short *__restrict x) {
  len = len & ~31;
  int result = 0;
  __asm volatile("");
  for (int i = 0; i < len; i++)
    result += x[i];
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<magic>:
  endbr64
  test   %edi,%edi
  jle    L68
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movslq %edi,%r8
  shl    $0x2,%r8
  mov    %rsi,%r10
  mov    %rsi,%r11
  mov    $0x0,%ecx
  mov    $0x0,%r9d
  mov    %edi,%edx
  jmp    L57
L68:
  mov    $0x0,%eax
  ret
L51:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L58
L146:
  cmp    %eax,%ecx
  jne    L51
  add    (%rsi,%rax,4),%r9d
  jmp    L51
L58:
  lea    0x1(%rcx),%eax
  add    %r8,%r11
  cmp    %eax,%edi
  je     L3
  mov    %eax,%ecx
L57:
  mov    %r11,%rsi
  mov    $0x0,%eax
  jmp    L146
L3:
  mov    %ecx,%r11d
  lea    0x4(%rbx,%r11,4),%rbx
  mov    %rbx,%rsi
  mov    $0x0,%edi
  not    %r11
  shl    $0x2,%r11
  mov    $0x0,%ebp
  jmp    L81
L61:
  cmp    %edx,%r9d
  jne    L94
  lea    0x1(%rdi),%eax
  add    %r8,%rsi
  cmp    %edi,%ecx
  je     L94
  mov    %eax,%edi
L81:
  lea    (%r11,%rsi,1),%rax
  mov    %ebp,%edx
L95:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L95
  jmp    L61
L170:
  cmp    %esi,%r9d
  jne    L19
  add    $0x4,%r10
  cmp    %rbx,%r10
  je     L174
L72:
  mov    %r10,%rdx
  mov    $0x0,%eax
  mov    %r11d,%esi
L120:
  add    (%rdx),%esi
  mov    %eax,%edi
  add    $0x1,%eax
  add    %r8,%rdx
  cmp    %edi,%ecx
  jne    L120
  jmp    L170
L174:
  mov    $0x1,%eax
  jmp    L56
L94:
  mov    $0x0,%r11d
  jmp    L72
L19:
  mov    $0x0,%eax
L56:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int magic(int size, int number[size][size]) {
  int s, s1, s2;
  int flag = 0;
  int row, column = 0;
  s = 0;
  row = 0;
  while (row < size) {
    for (column = 0; column < size; column++) {
      if (row == column)
        s = s + number[row][column];
    }
    row++;
  }
  row = 0;
  while (row < size) {
    s1 = 0;
    for (column = 0; column < size; column++) {
      s1 = s1 + number[row][column];
    }
    if (s == s1)
      flag = 1;
    else {
      flag = 0;
      break;
    }
    row++;
  }
  row = 0;
  while (row < size) {
    s2 = 0;
    for (column = 0; column < size; column++) {
      s2 = s2 + number[column][row];
    }
    if (s == s2)
      flag = 1;
    else {
      flag = 0;
      break;
    }
    row++;
  }
  if (flag == 1)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<magic>:
  endbr64
  test   %edi,%edi
  jle    L30
  movslq %edi,%r9
  push   %rbx
  mov    %rsi,%r11
  mov    %rsi,%rcx
  shl    $0x2,%r9
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  mov    %edi,%edx
  lea    -0x1(%rdi),%ebx
  nopl   (%rax)
L33:
  xor    %eax,%eax
  jmp    L49
  nopl   0x0(%rax)
L13:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L15
L49:
  cmp    %eax,%r8d
  jne    L13
  add    (%rcx,%rax,4),%r10d
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L49
L15:
  lea    0x1(%r8),%eax
  add    %r9,%rcx
  cmp    %eax,%edi
  je     L65
  mov    %eax,%r8d
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L65:
  lea    0x4(%rsi,%rbx,4),%rdi
  nopl   (%rax)
L41:
  mov    %r11,%rdx
  xor    %eax,%eax
  xor    %ecx,%ecx
  nop
L46:
  mov    %eax,%esi
  add    (%rdx),%ecx
  add    $0x1,%eax
  add    %r9,%rdx
  cmp    %esi,%r8d
  jne    L46
  cmp    %ecx,%r10d
  jne    L56
  add    $0x4,%r11
  cmp    %r11,%rdi
  jne    L41
  mov    $0x1,%eax
  pop    %rbx
  ret
L56:
  xor    %eax,%eax
  pop    %rbx
  ret
L30:
  xor    %eax,%eax
  ret
```

assistant: ```c
int magic(int size, int number[size][size]) {
  int s, s1, s2;
  int flag = 0;
  int row, column = 0;
  s = 0;
  row = 0;
  while (row < size) {
    for (column = 0; column < size; column++) {
      if (row == column)
        s = s + number[row][column];
    }
    row++;
  }
  row = 0;
  while (row < size) {
    s1 = 0;
    for (column = 0; column < size; column++) {
      s1 = s1 + number[row][column];
    }
    if (s == s1)
      flag = 1;
    else {
      flag = 0;
      break;
    }
    row++;
  }
  row = 0;
  while (row < size) {
    s2 = 0;
    for (column = 0; column < size; column++) {
      s2 = s2 + number[column][row];
    }
    if (s == s2)
      flag = 1;
    else {
      flag = 0;
      break;
    }
    row++;
  }
  if (flag == 1)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<magic>:
  endbr64
  test   %edi,%edi
  jle    L33
  movslq %edi,%r9
  push   %rbx
  mov    %rsi,%r11
  mov    %rsi,%rcx
  shl    $0x2,%r9
  xor    %r8d,%r8d
  xor    %r10d,%r10d
  mov    %edi,%edx
  lea    -0x1(%rdi),%ebx
  nopl   (%rax)
L10:
  xor    %eax,%eax
  jmp    L96
  nopl   0x0(%rax)
L90:
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L9
L96:
  cmp    %eax,%r8d
  jne    L90
  add    (%rcx,%rax,4),%r10d
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L96
L9:
  lea    0x1(%r8),%eax
  add    %r9,%rcx
  cmp    %eax,%edi
  je     L15
  mov    %eax,%r8d
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L15:
  lea    0x4(%rsi,%rbx,4),%rdi
  nopl   (%rax)
L53:
  mov    %r11,%rdx
  xor    %eax,%eax
  xor    %ecx,%ecx
  nop
L38:
  mov    %eax,%esi
  add    (%rdx),%ecx
  add    $0x1,%eax
  add    %r9,%rdx
  cmp    %esi,%r8d
  jne    L38
  cmp    %ecx,%r10d
  jne    L87
  add    $0x4,%r11
  cmp    %rdi,%r11
  jne    L53
  mov    $0x1,%eax
  pop    %rbx
  ret
L87:
  xor    %eax,%eax
  pop    %rbx
  ret
L33:
  xor    %eax,%eax
  ret
```

assistant: ```c
int magic(int size, int number[size][size]) {
  int s, s1, s2;
  int flag = 0;
  int row, column = 0;
  s = 0;
  row = 0;
  while (row < size) {
    for (column = 0; column < size; column++) {
      if (row == column)
        s = s + number[row][column];
    }
    row++;
  }
  row = 0;
  while (row < size) {
    s1 = 0;
    for (column = 0; column < size; column++) {
      s1 = s1 + number[row][column];
    }
    if (s == s1)
      flag = 1;
    else {
      flag = 0;
      break;
    }
    row++;
  }
  row = 0;
  while (row < size) {
    s2 = 0;
    for (column = 0; column < size; column++) {
      s2 = s2 + number[column][row];
    }
    if (s == s2)
      flag = 1;
    else {
      flag = 0;
      break;
    }
    row++;
  }
  if (flag == 1)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<knapsack>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L0
  mov    %edi,%ebp
  cvttss2si %xmm0,%edx
  lea    0x10(%rsp),%rax
  lea    -0x1(%rdi),%edi
  lea    0x14(%rsp,%rdi,4),%rdi
L21:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L21
  mov    %ebp,%r8d
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movss  D17(%rip),%xmm3
L27:
  mov    %eax,%edi
  movss  (%rsi,%rax,4),%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2ss %edx,%xmm0
  comiss %xmm0,%xmm1
  ja     L8
  movss  %xmm3,0x10(%rsp,%rax,4)
  addss  (%rcx,%rax,4),%xmm2
  subss  %xmm1,%xmm0
  cvttss2si %xmm0,%edx
  lea    0x1(%rax),%edi
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L27
  movslq %edi,%rdi
  movss  (%rcx,%rdi,4),%xmm0
  mulss  0x10(%rsp,%rdi,4),%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,0xc(%rsp)
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L8:
  cmp    %eax,%ebp
  jle    L49
  cltq
  divss  (%rsi,%rax,4),%xmm0
  movss  %xmm0,0x10(%rsp,%rax,4)
L49:
  movslq %edi,%rdi
  movss  (%rcx,%rdi,4),%xmm0
  mulss  0x10(%rsp,%rdi,4),%xmm0
  addss  %xmm2,%xmm0
  movss  %xmm0,0xc(%rsp)
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  lea    0x10(%rsp),%rbx
  lea    -0x1(%rbp),%eax
  lea    0x14(%rsp,%rax,4),%r12
  lea    D50(%rip),%rbp
L60:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rbx),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbx,%r12
  jne    L60
L57:
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  lea    D36(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  movss  0x10(%rsp),%xmm0
  mulss  (%rdx),%xmm0
  addss  D46(%rip),%xmm0
  movss  %xmm0,0xc(%rsp)
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L57
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type: f32
name: retrieve_data
arguments: tag: D33
type: string
name: retrieve_data
arguments: tag: D50
type: string
name: retrieve_data
arguments: tag: D36
type: string
name: retrieve_data
arguments: tag: D46
type: f32

tool: D17: 1

tool: D33: 
The result vector is: 
 

tool: D50: %f	

tool: D36: 
Maximum profit is: %f 


tool: D46: 0

assistant: ```c
void knapsack(int n, float weight[], float profit[], float m) {
  float x[20], tp = 0;
  int i, j, u;
  u = m;
  for (i = 0; i < n; i++)
    x[i] = 0.0;
  for (i = 0; i < n; i++) {
    if (weight[i] > u)
      break;
    else {
      x[i] = 1.0;
      tp = tp + profit[i];
      u = u - weight[i];
    }
  }
  if (i < n)
    x[i] = u / weight[i];
  tp = tp + (x[i] * profit[i]);
  printf("\nThe result vector is: \n ");
  for (i = 0; i < n; i++)
    printf("%f\t", x[i]);
  printf("\nMaximum profit is: %f \n", tp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<knapsack>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L57
  movslq %edi,%r15
  mov    %rsp,%rbp
  mov    %edi,%r12d
  mov    %rsi,%r13
  lea    0x0(,%r15,4),%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  cvttss2si %xmm0,%ebx
  call   <memset@plt>
  mov    %r14,%rdx
  xor    %eax,%eax
  pxor   %xmm2,%xmm2
  movss  D6(%rip),%xmm4
  jmp    L50
  nopw   0x0(%rax,%rax,1)
L26:
  subss  %xmm1,%xmm0
  movss  %xmm4,0x0(%rbp,%rax,4)
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  addss  %xmm3,%xmm2
  add    $0x4,%rdx
  cvttss2si %xmm0,%ebx
  cmp    %r15,%rax
  je     L89
L50:
  pxor   %xmm0,%xmm0
  movss  0x0(%r13,%rax,4),%xmm1
  movss  (%rdx),%xmm3
  movslq %eax,%rcx
  cvtsi2ss %ebx,%xmm0
  comiss %xmm0,%xmm1
  jbe    L26
  cmp    %ecx,%r12d
  jle    L61
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rsp,%rcx,4)
  mulss  %xmm3,%xmm0
L20:
  addss  %xmm2,%xmm0
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  movd   %xmm0,%r14d
  call   <printf@plt>
L59:
  xor    %ebx,%ebx
  lea    D69(%rip),%r13
  nop
L73:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm0
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L73
L52:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x68,%rsp
  movd   %r14d,%xmm5
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  pop    %rbx
  lea    D3(%rip),%rdi
  pop    %rbp
  cvtss2sd %xmm5,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <printf@plt>
L89:
  movslq %ecx,%rcx
  movss  (%r14,%rcx,4),%xmm0
  mulss  (%rsp,%rcx,4),%xmm0
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L57:
  movss  (%rsp),%xmm2
  mulss  (%rdx),%xmm2
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  addss  D8(%rip),%xmm2
  movd   %xmm2,%r14d
  call   <printf@plt>
  jmp    L52
L61:
  mulss  (%rsp,%rcx,4),%xmm3
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  addss  %xmm2,%xmm3
  movd   %xmm3,%r14d
  call   <printf@plt>
  jmp    L59
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: f32
name: disassemble_data
arguments: tag: D14
data_type: string
name: disassemble_data
arguments: tag: D69
data_type: string
name: disassemble_data
arguments: tag: D3
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: f32

tool: D6: 1

tool: D14: 
The result vector is: 
 

tool: D69: %f	

tool: D3: 
Maximum profit is: %f 


tool: D8: 0

assistant: ```c
void knapsack(int n, float weight[], float profit[], float m) {
  float x[20], tp = 0;
  int i, j, u;
  u = m;
  for (i = 0; i < n; i++)
    x[i] = 0.0;
  for (i = 0; i < n; i++) {
    if (weight[i] > u)
      break;
    else {
      x[i] = 1.0;
      tp = tp + profit[i];
      u = u - weight[i];
    }
  }
  if (i < n)
    x[i] = u / weight[i];
  tp = tp + (x[i] * profit[i]);
  printf("\nThe result vector is: \n ");
  for (i = 0; i < n; i++)
    printf("%f\t", x[i]);
  printf("\nMaximum profit is: %f \n", tp);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<knapsack>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L83
  movslq %edi,%r15
  mov    %rsp,%rbp
  mov    %edi,%r12d
  mov    %rsi,%r13
  lea    0x0(,%r15,4),%rdx
  xor    %esi,%esi
  mov    %rbp,%rdi
  cvttss2si %xmm0,%ebx
  call   <memset@plt>
  mov    %r14,%rdx
  xor    %eax,%eax
  pxor   %xmm2,%xmm2
  movss  D68(%rip),%xmm4
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L36:
  subss  %xmm1,%xmm0
  movss  %xmm4,0x0(%rbp,%rax,4)
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  addss  %xmm3,%xmm2
  add    $0x4,%rdx
  cvttss2si %xmm0,%ebx
  cmp    %r15,%rax
  je     L17
L20:
  pxor   %xmm0,%xmm0
  movss  0x0(%r13,%rax,4),%xmm1
  movss  (%rdx),%xmm3
  movslq %eax,%rcx
  cvtsi2ss %ebx,%xmm0
  comiss %xmm0,%xmm1
  jbe    L36
  cmp    %ecx,%r12d
  jle    L56
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rsp,%rcx,4)
  mulss  %xmm3,%xmm0
L85:
  addss  %xmm2,%xmm0
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  movd   %xmm0,%r14d
  call   <printf@plt>
L50:
  xor    %ebx,%ebx
  lea    D37(%rip),%r13
  nop
L90:
  pxor   %xmm0,%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  cvtss2sd 0x0(%rbp,%rbx,4),%xmm0
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jg     L90
L42:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x68,%rsp
  movd   %r14d,%xmm5
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  pop    %rbx
  lea    D66(%rip),%rdi
  pop    %rbp
  cvtss2sd %xmm5,%xmm0
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <printf@plt>
L17:
  movslq %ecx,%rcx
  movss  (%r14,%rcx,4),%xmm0
  mulss  (%rsp,%rcx,4),%xmm0
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L83:
  movss  (%rdx),%xmm2
  mulss  (%rsp),%xmm2
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  addss  D57(%rip),%xmm2
  movd   %xmm2,%r14d
  call   <printf@plt>
  jmp    L42
L56:
  mulss  (%rsp,%rcx,4),%xmm3
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  addss  %xmm2,%xmm3
  movd   %xmm3,%r14d
  call   <printf@plt>
  jmp    L50
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D68
datatype: f32
name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D37
datatype: string
name: parse_data
arguments: label: D66
datatype: string
name: parse_data
arguments: label: D57
datatype: f32

tool: D68: 1

tool: D19: 
The result vector is: 
 

tool: D37: %f	

tool: D66: 
Maximum profit is: %f 


tool: D57: 0

assistant: ```c
void knapsack(int n, float weight[], float profit[], float m) {
  float x[20], tp = 0;
  int i, j, u;
  u = m;
  for (i = 0; i < n; i++)
    x[i] = 0.0;
  for (i = 0; i < n; i++) {
    if (weight[i] > u)
      break;
    else {
      x[i] = 1.0;
      tp = tp + profit[i];
      u = u - weight[i];
    }
  }
  if (i < n)
    x[i] = u / weight[i];
  tp = tp + (x[i] * profit[i]);
  printf("\nThe result vector is: \n ");
  for (i = 0; i < n; i++)
    printf("%f\t", x[i]);
  printf("\nMaximum profit is: %f \n", tp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L20
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L12
L20:
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D23
type: string
name: retrieve_data
arguments: label: D5
type: string
name: retrieve_data
arguments: label: D6
type: string
name: retrieve_data
arguments: label: D34
type: string

tool: D23: Enter number: 


tool: D5: %d

tool: D6: 1

tool: D34: 0

assistant: ```c
int main() {
  int n, prime;
  printf("Enter number: \n");
  scanf("%d", &n);
  prime = is_prime(n);
  if (prime == 1) {
    printf("1");
  } else {
    printf("0");
  }
  return 0;
}
```