ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<strcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L33
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    $0x0,%eax
  jmp    L5
L14:
  addl   $0x1,-0x4(%rbp)
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L31
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    %edx,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int strcmp(char *s, const char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L26
  mov    $0x1,%eax
L3:
  test   %dl,%dl
  je     L24
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movzbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  je     L3
L26:
  movsbl %dl,%eax
  movsbl %cl,%ecx
  sub    %ecx,%eax
  ret
L24:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strcmp(char *s, const char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L36
  mov    $0x1,%eax
  jmp    L17
  nopl   (%rax)
L14:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L36
L17:
  test   %dl,%dl
  jne    L14
  xor    %eax,%eax
  ret
L36:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(char *s, const char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strcmp>:
  endbr64
  movzbl (%rdi),%edx
  movsbl (%rsi),%ecx
  cmp    %cl,%dl
  jne    L34
  mov    $0x1,%eax
  jmp    L5
  nopl   (%rax)
L3:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  movsbl -0x1(%rsi,%rax,1),%ecx
  cmp    %cl,%dl
  jne    L34
L5:
  test   %dl,%dl
  jne    L3
  xor    %eax,%eax
  ret
L34:
  movsbl %dl,%eax
  sub    %ecx,%eax
  ret
```

assistant: ```c
int strcmp(char *s, const char *t) {
  int i;
  for (i = 0; s[i] == t[i]; i++)
    if (s[i] == '\0')
      return 0;
  return s[i] - t[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<trapzd4>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  movsd  %xmm0,(%rsp)
  movq   %xmm1,%rbp
  cmp    $0x1,%esi
  je     L49
  lea    -0x1(%rsi),%edx
  mov    $0x1,%eax
  mov    $0x1,%ebx
  cmp    $0x2,%esi
  jle    L12
L5:
  add    %ebx,%ebx
  add    $0x1,%eax
  cmp    %eax,%edx
  jne    L5
  pxor   %xmm6,%xmm6
  cvtsi2sd %ebx,%xmm6
  movsd  %xmm6,0x18(%rsp)
  movq   %rbp,%xmm5
  movsd  (%rsp),%xmm7
  subsd  %xmm7,%xmm5
  movsd  %xmm5,0x10(%rsp)
  divsd  %xmm6,%xmm5
  movsd  %xmm5,0x8(%rsp)
  movapd %xmm5,%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  %xmm7,%xmm0
  movq   %xmm0,%r14
  test   %ebx,%ebx
  jle    L47
  mov    $0x1,%ebp
  pxor   %xmm1,%xmm1
  movsd  %xmm1,(%rsp)
L76:
  movq   %r14,%xmm0
  call   *%r12
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  add    $0x1,%ebp
  movq   %r14,%xmm2
  addsd  0x8(%rsp),%xmm2
  movq   %xmm2,%r14
  cmp    %ebx,%ebp
  jle    L76
L41:
  movsd  0x10(%rsp),%xmm0
  mulsd  (%rsp),%xmm0
  divsd  0x18(%rsp),%xmm0
  addsd  D76(%rip),%xmm0
  mulsd  D5(%rip),%xmm0
L56:
  movsd  %xmm0,D4(%rip)
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L49:
  movsd  (%rsp),%xmm0
  call   *%rdi
  movq   %xmm0,%rbx
  movq   %rbp,%xmm0
  call   *%r12
  movapd %xmm0,%xmm1
  movq   %rbp,%xmm6
  subsd  (%rsp),%xmm6
  movapd %xmm6,%xmm0
  mulsd  D5(%rip),%xmm0
  movq   %rbx,%xmm7
  addsd  %xmm1,%xmm7
  mulsd  %xmm7,%xmm0
  jmp    L56
L47:
  pxor   %xmm1,%xmm1
  movsd  %xmm1,(%rsp)
  jmp    L41
L12:
  movsd  (%rsp),%xmm6
  subsd  %xmm6,%xmm1
  movsd  %xmm1,0x10(%rsp)
  movapd %xmm1,%xmm0
  mulsd  D5(%rip),%xmm0
  addsd  %xmm6,%xmm0
  call   *%rdi
  addsd  D4(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movsd  D53(%rip),%xmm1
  movsd  %xmm1,0x18(%rsp)
  jmp    L41
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: f64
name: parse_data
arguments: tag: D4
type_infered: f64
name: parse_data
arguments: tag: D53
type_infered: byte[8]

tool: D5: 0.5

tool: D4: 0

tool: {"D53": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double trapzd4(double (*func)(double), double a, double b, int n) {
  double x, tnm, sum, del;
  static double s;
  int it, j;
  if (n == 1) {
    return (s = 0.5 * (b - a) * (((*func)(a)) + ((*func)(b))));
  } else {
    for (it = 1, j = 1; j < n - 1; j++)
      it <<= 1;
    tnm = it;
    del = (b - a) / tnm;
    x = a + 0.5 * del;
    for (sum = 0.0, j = 1; j <= it; j++, x += del)
      sum += ((*func)(x));
    s = 0.5 * (s + (b - a) * sum / tnm);
    return s;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<trapzd4>:
  endbr64
  push   %r12
  movapd %xmm1,%xmm4
  mov    %rdi,%r12
  push   %rbp
  subsd  %xmm0,%xmm4
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm4,0x18(%rsp)
  cmp    $0x1,%esi
  je     L55
  sub    $0x1,%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
  cmp    $0x1,%esi
  jle    L42
  nopl   0x0(%rax)
L20:
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %esi,%edx
  jne    L20
  pxor   %xmm6,%xmm6
  movsd  0x18(%rsp),%xmm5
  movsd  D45(%rip),%xmm7
  cvtsi2sd %eax,%xmm6
  movsd  %xmm7,0x28(%rsp)
  divsd  %xmm6,%xmm5
  movsd  %xmm6,0x20(%rsp)
  movapd %xmm5,%xmm2
  movsd  %xmm5,0x10(%rsp)
  mulsd  %xmm7,%xmm2
  addsd  %xmm0,%xmm2
  test   %eax,%eax
  jle    L11
  lea    0x1(%rax),%ebx
  mov    $0x1,%ebp
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L30:
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  add    $0x1,%ebp
  movsd  %xmm2,(%rsp)
  call   *%r12
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  addsd  0x10(%rsp),%xmm2
  addsd  %xmm0,%xmm1
  cmp    %ebx,%ebp
  jne    L30
L12:
  movsd  0x18(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  0x20(%rsp),%xmm0
  addsd  D42(%rip),%xmm0
  mulsd  0x28(%rsp),%xmm0
L26:
  movsd  %xmm0,D9(%rip)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L55:
  movsd  %xmm1,0x8(%rsp)
  call   *%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   *%r12
  movsd  0x18(%rsp),%xmm6
  mulsd  D45(%rip),%xmm6
  movapd %xmm0,%xmm1
  addsd  (%rsp),%xmm1
  movapd %xmm6,%xmm0
  mulsd  %xmm1,%xmm0
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L11:
  pxor   %xmm1,%xmm1
  jmp    L12
  xchg   %ax,%ax
L42:
  movsd  D45(%rip),%xmm4
  movsd  0x18(%rsp),%xmm1
  mulsd  %xmm4,%xmm1
  movsd  %xmm4,0x28(%rsp)
  addsd  %xmm1,%xmm0
  call   *%rdi
  movsd  D9(%rip),%xmm7
  pxor   %xmm1,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm7,0x20(%rsp)
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_label: D45
type_infered: f64
name: retrieve_data
arguments: data_label: D9
type_infered: f32[2]

tool: D45: 0.5

tool: {"D9": [0.0,1.875]}

assistant: ```c
double trapzd4(double (*func)(double), double a, double b, int n) {
  double x, tnm, sum, del;
  static double s;
  int it, j;
  if (n == 1) {
    return (s = 0.5 * (b - a) * (((*func)(a)) + ((*func)(b))));
  } else {
    for (it = 1, j = 1; j < n - 1; j++)
      it <<= 1;
    tnm = it;
    del = (b - a) / tnm;
    x = a + 0.5 * del;
    for (sum = 0.0, j = 1; j <= it; j++, x += del)
      sum += ((*func)(x));
    s = 0.5 * (s + (b - a) * sum / tnm);
    return s;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<trapzd4>:
  endbr64
  push   %r12
  movapd %xmm1,%xmm4
  mov    %rdi,%r12
  push   %rbp
  subsd  %xmm0,%xmm4
  push   %rbx
  sub    $0x30,%rsp
  movsd  %xmm4,0x18(%rsp)
  cmp    $0x1,%esi
  je     L60
  sub    $0x1,%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
  cmp    $0x1,%esi
  jle    L1
  nopl   0x0(%rax)
L34:
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %esi,%edx
  jne    L34
  pxor   %xmm6,%xmm6
  movsd  0x18(%rsp),%xmm5
  movsd  D21(%rip),%xmm7
  cvtsi2sd %eax,%xmm6
  movsd  %xmm7,0x28(%rsp)
  divsd  %xmm6,%xmm5
  movsd  %xmm6,0x20(%rsp)
  movapd %xmm5,%xmm2
  movsd  %xmm5,0x10(%rsp)
  mulsd  %xmm7,%xmm2
  addsd  %xmm0,%xmm2
  test   %eax,%eax
  jle    L36
  lea    0x1(%rax),%ebx
  mov    $0x1,%ebp
  pxor   %xmm1,%xmm1
  nopl   (%rax)
L69:
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm2,%xmm0
  add    $0x1,%ebp
  movsd  %xmm2,(%rsp)
  call   *%r12
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  addsd  0x10(%rsp),%xmm2
  addsd  %xmm0,%xmm1
  cmp    %ebx,%ebp
  jne    L69
L65:
  movsd  0x18(%rsp),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  0x20(%rsp),%xmm0
  addsd  D59(%rip),%xmm0
  mulsd  0x28(%rsp),%xmm0
L15:
  movsd  %xmm0,D22(%rip)
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L60:
  movsd  %xmm1,0x8(%rsp)
  call   *%rdi
  movsd  0x8(%rsp),%xmm1
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm0
  call   *%r12
  movsd  0x18(%rsp),%xmm6
  mulsd  D21(%rip),%xmm6
  movapd %xmm0,%xmm1
  addsd  (%rsp),%xmm1
  movapd %xmm6,%xmm0
  mulsd  %xmm1,%xmm0
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L36:
  pxor   %xmm1,%xmm1
  jmp    L65
  xchg   %ax,%ax
L1:
  movapd %xmm4,%xmm1
  movsd  D21(%rip),%xmm4
  mulsd  %xmm4,%xmm1
  movsd  %xmm4,0x28(%rsp)
  addsd  %xmm1,%xmm0
  call   *%rdi
  movsd  D22(%rip),%xmm7
  pxor   %xmm1,%xmm1
  addsd  %xmm0,%xmm1
  movsd  %xmm7,0x20(%rsp)
  jmp    L65
```

tool_calls: name: unpack_data
arguments: data_label: D21
datatype: f64
name: unpack_data
arguments: data_label: D22
datatype: f32[2]

tool: D21: 0.5

tool: {"D22": [0.0,1.875]}

assistant: ```c
double trapzd4(double (*func)(double), double a, double b, int n) {
  double x, tnm, sum, del;
  static double s;
  int it, j;
  if (n == 1) {
    return (s = 0.5 * (b - a) * (((*func)(a)) + ((*func)(b))));
  } else {
    for (it = 1, j = 1; j < n - 1; j++)
      it <<= 1;
    tnm = it;
    del = (b - a) / tnm;
    x = a + 0.5 * del;
    for (sum = 0.0, j = 1; j <= it; j++, x += del)
      sum += ((*func)(x));
    s = 0.5 * (s + (b - a) * sum / tnm);
    return s;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_0xdf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%edx
  mov    $0x5,%esi
  mov    $0x18,%edi
  call   <RST@plt>
  mov    $0xb,%edi
  call   <T_WAIT_UNTIL@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op_0xdf(void) {
  RST(0x18, 5, 8);
  T_WAIT_UNTIL(11);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<op_0xdf>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edx
  mov    $0x5,%esi
  mov    $0x18,%edi
  call   <RST@plt>
  mov    $0xb,%edi
  call   <T_WAIT_UNTIL@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op_0xdf(void) {
  RST(0x18, 5, 8);
  T_WAIT_UNTIL(11);
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<op_0xdf>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x18,%edi
  mov    $0x8,%edx
  mov    $0x5,%esi
  call   <RST@plt>
  mov    $0xb,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_0xdf(void) {
  RST(0x18, 5, 8);
  T_WAIT_UNTIL(11);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<op_0xdf>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x18,%edi
  mov    $0x8,%edx
  mov    $0x5,%esi
  call   <RST@plt>
  mov    $0xb,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_0xdf(void) {
  RST(0x18, 5, 8);
  T_WAIT_UNTIL(11);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L19
L4:
  addq   $0x1,-0x8(%rbp)
L19:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L4
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i = 0;
  while (str[i] != 0)
    i++;
  return i;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
  mov    $0x0,%eax
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L19
  ret
L7:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i = 0;
  while (str[i] != 0)
    i++;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L7
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L15
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i = 0;
  while (str[i] != 0)
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L13
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L11
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
size_t strlen(const char *str) {
  size_t i = 0;
  while (str[i] != 0)
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<append_to_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L15
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    0x200(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L7
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L21
L7:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x1,%eax
L21:
  leave
  ret
```

assistant: ```c
int append_to_buf(char **buf, int *buflen, int *i, int c) {
  char *tmp_buf;
  if (*i >= *buflen) {
    *buflen += 512;
    tmp_buf = realloc(*buf, (sizeof(**buf) * *buflen));
    if (NULL == tmp_buf) {
      free(*buf);
      *buf = NULL;
      return (0);
    } else {
      *buf = tmp_buf;
    }
    *buf = tmp_buf;
  }
  (*buf)[*i] = (char)c;
  (*i)++;
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<append_to_buf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r12d
  mov    (%rsi),%eax
  cmp    %eax,(%rdx)
  jge    L11
L26:
  movslq (%rbx),%rax
  mov    0x0(%rbp),%rdx
  mov    %r12b,(%rdx,%rax,1)
  addl   $0x1,(%rbx)
  mov    $0x1,%eax
L33:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  add    $0x200,%eax
  mov    %eax,(%rsi)
  mov    %eax,%esi
  mov    (%rdi),%rdi
  call   <realloc@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,0x0(%rbp)
  jmp    L26
L10:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  mov    $0x0,%eax
  jmp    L33
```

assistant: ```c
int append_to_buf(char **buf, int *buflen, int *i, int c) {
  char *tmp_buf;
  if (*i >= *buflen) {
    *buflen += 512;
    tmp_buf = realloc(*buf, (sizeof(**buf) * *buflen));
    if (NULL == tmp_buf) {
      free(*buf);
      *buf = NULL;
      return (0);
    } else {
      *buf = tmp_buf;
    }
    *buf = tmp_buf;
  }
  (*buf)[*i] = (char)c;
  (*i)++;
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<append_to_buf>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rsi),%eax
  movslq (%rdx),%rdx
  mov    (%rdi),%rdi
  cmp    %eax,%edx
  jge    L5
L19:
  mov    %r12b,(%rdi,%rdx,1)
  mov    $0x1,%eax
  addl   $0x1,(%rbx)
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L5:
  lea    0x200(%rax),%r8d
  mov    %r8d,(%rsi)
  mov    %r8d,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L10
  mov    %rax,0x0(%rbp)
  movslq (%rbx),%rdx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  xor    %eax,%eax
  jmp    L37
```

assistant: ```c
int append_to_buf(char **buf, int *buflen, int *i, int c) {
  char *tmp_buf;
  if (*i >= *buflen) {
    *buflen += 512;
    tmp_buf = realloc(*buf, (sizeof(**buf) * *buflen));
    if (NULL == tmp_buf) {
      free(*buf);
      *buf = NULL;
      return (0);
    } else {
      *buf = tmp_buf;
    }
    *buf = tmp_buf;
  }
  (*buf)[*i] = (char)c;
  (*i)++;
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<append_to_buf>:
  endbr64
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rsi),%eax
  movslq (%rdx),%rdx
  mov    (%rdi),%rdi
  cmp    %eax,%edx
  jge    L33
L34:
  mov    %r12b,(%rdi,%rdx,1)
  mov    $0x1,%eax
  addl   $0x1,(%rbx)
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L33:
  lea    0x200(%rax),%r8d
  mov    %r8d,(%rsi)
  mov    %r8d,%esi
  call   <realloc@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L11
  mov    %rax,0x0(%rbp)
  movslq (%rbx),%rdx
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  movq   $0x0,0x0(%rbp)
  xor    %eax,%eax
  jmp    L21
```

assistant: ```c
int append_to_buf(char **buf, int *buflen, int *i, int c) {
  char *tmp_buf;
  if (*i >= *buflen) {
    *buflen += 512;
    tmp_buf = realloc(*buf, (sizeof(**buf) * *buflen));
    if (NULL == tmp_buf) {
      free(*buf);
      *buf = NULL;
      return (0);
    } else {
      *buf = tmp_buf;
    }
    *buf = tmp_buf;
  }
  (*buf)[*i] = (char)c;
  (*i)++;
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xfc4(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xfb4(%rbp)
  movl   $0x2,-0xfc0(%rbp)
  jmp    L19
L50:
  movl   $0x0,-0xfbc(%rbp)
  movl   $0x1,-0xfb8(%rbp)
  jmp    L26
L43:
  mov    -0xfbc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%ecx
  mov    -0xfc0(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %edx,-0xfb8(%rbp)
  addl   $0x1,-0xfbc(%rbp)
L26:
  mov    -0xfbc(%rbp),%eax
  cmp    -0xfb4(%rbp),%eax
  jge    L66
  cmpl   $0x0,-0xfb8(%rbp)
  jne    L43
L66:
  cmpl   $0x0,-0xfb8(%rbp)
  je     L37
  mov    -0xfc0(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x3e7,-0xfb4(%rbp)
  jg     L37
  mov    -0xfb4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xfb4(%rbp)
  cltq
  mov    -0xfc0(%rbp),%edx
  mov    %edx,-0xfb0(%rbp,%rax,4)
L37:
  addl   $0x1,-0xfc0(%rbp)
L19:
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfc0(%rbp)
  jle    L50
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D21
data_type: string
name: unpack_data
arguments: label: D17
data_type: string

tool: D25: Enter value of N > 

tool: D21: %d

tool: D17: %12d


assistant: ```c
int main(void) {
  int n;
  int i, j;
  int flag;
  int primes[1000];
  int level;
  printf("Enter value of N > ");
  scanf("%d", &n);
  level = 0;
  for (i = 2; i <= n; i++) {
    for (j = 0, flag = 1; j < level && flag; j++)
      flag = (i % primes[j]);
    if (flag) {
      printf("%12d\n", i);
      if (level < 1000)
        primes[level++] = i;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebp
  mov    $0x2,%ebx
  lea    D27(%rip),%r12
  cmpl   $0x1,0xc(%rsp)
  jg     L10
L32:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0xfc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jl     L32
L10:
  mov    $0x1,%ecx
  lea    0x10(%rsp),%rsi
  test   %ebp,%ebp
  jle    L67
L8:
  mov    %ebx,%eax
  cltd
  idivl  -0x4(%rsi,%rcx,4)
  cmp    %ecx,%ebp
  setg   %dil
  test   %edx,%edx
  setne  %al
  add    $0x1,%rcx
  test   %al,%dil
  jne    L8
  test   %edx,%edx
  je     L2
L67:
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3e7,%ebp
  jg     L2
  movslq %ebp,%rax
  mov    %ebx,0x10(%rsp,%rax,4)
  lea    0x1(%rbp),%ebp
  jmp    L2
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type_guessed: string
name: retrieve_data
arguments: data_label: D6
type_guessed: string
name: retrieve_data
arguments: data_label: D27
type_guessed: string

tool: D21: Enter value of N > 

tool: D6: %d

tool: D27: %12d


assistant: ```c
int main(void) {
  int n;
  int i, j;
  int flag;
  int primes[1000];
  int level;
  printf("Enter value of N > ");
  scanf("%d", &n);
  level = 0;
  for (i = 2; i <= n; i++) {
    for (j = 0, flag = 1; j < level && flag; j++)
      flag = (i % primes[j]);
    if (flag) {
      printf("%12d\n", i);
      if (level < 1000)
        primes[level++] = i;
    }
  }
}
```