ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<kbhit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D42(%rip),%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  mov    (%rbx),%edi
  mov    %r15,%rsi
  call   <tcgetattr@plt>
  mov    (%rsp),%eax
  mov    D12(%rip),%r13
  mov    D13(%rip),%rdx
  mov    (%rbx),%edi
  mov    %eax,0x4(%rsp)
  mov    D22(%rip),%rax
  mov    0x0(%r13),%esi
  mov    (%rax),%eax
  or     (%rdx),%eax
  lea    0x4(%rsp),%rdx
  not    %eax
  and    %eax,0x4(%rsp)
  call   <tcsetattr@plt>
  mov    D61(%rip),%rax
  mov    (%rbx),%edi
  xor    %edx,%edx
  mov    (%rax),%esi
  call   <fcntl@plt>
  mov    D58(%rip),%r14
  mov    (%rbx),%edi
  mov    %eax,%r12d
  mov    D3(%rip),%rax
  mov    (%r14),%esi
  mov    (%rax),%edx
  or     %r12d,%edx
  call   <fcntl@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0x0(%r13),%esi
  mov    (%rbx),%edi
  mov    %r15,%rdx
  mov    %eax,%ebp
  call   <tcsetattr@plt>
  mov    (%r14),%esi
  mov    (%rbx),%edi
  mov    %r12d,%edx
  call   <fcntl@plt>
  mov    D63(%rip),%rdx
  xor    %eax,%eax
  cmp    %ebp,(%rdx)
  jne    L18
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L18:
  mov    D45(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ungetc@plt>
  mov    $0x1,%eax
  jmp    L17
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int kbhit(void) {
  struct termios oldt, newt;
  int ch;
  int oldf;
  tcgetattr(STDIN_FILENO, &oldt);
  newt = oldt;
  newt.c_lflag &= ~(ICANON | ECHO);
  tcsetattr(STDIN_FILENO, TCSANOW, &newt);
  oldf = fcntl(STDIN_FILENO, F_GETFL, 0);
  fcntl(STDIN_FILENO, F_SETFL, oldf | O_NONBLOCK);
  ch = getchar();
  tcsetattr(STDIN_FILENO, TCSANOW, &oldt);
  fcntl(STDIN_FILENO, F_SETFL, oldf);
  if (ch != EOF) {
    ungetc(ch, stdin);
    return 1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getPowm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x4(%rbp),%eax
  mov    $0xe9,%edx
  mov    $0x80,%esi
  mov    %eax,%edi
  call   <getPrime@plt>
  mov    -0x38(%rbp),%rsi
  mov    -0x8(%rbp),%eax
  sub    $0x8,%rsp
  push   -0x30(%rbp)
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0xffffffff,%edx
  mov    %eax,%edi
  call   <mpz_import@plt>
  add    $0x10,%rsp
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x24(%rbp),%esi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_powm_sec@plt>
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0xc(%rbp),%edx
  push   %rdx
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0xffffffff,%edx
  mov    %rax,%rdi
  call   <mpz_export@plt>
  add    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_clear@plt>
  nop
  leave
  ret
```

assistant: ```c
void getPowm(unsigned char *res, unsigned long *reslen, const mpz_t base, const unsigned char *chexp, unsigned long len) {
  mpz_t prime;
  mpz_t exp;
  mpz_t ans;
  mpz_init(ans);
  mpz_init(exp);
  mpz_init(prime);
  getPrime(prime, 128, 233);
  mpz_import(exp, len, -1, 1, 1, 0, (void *)chexp);
  mpz_powm_sec(ans, base, exp, prime);
  mpz_export((void *)res, reslen, -1, 1, 1, 0, ans);
  mpz_clear(prime);
  mpz_clear(ans);
  mpz_clear(exp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getPowm>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r13d
  mov    %rcx,%r15
  mov    %r8,%r14
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init@plt>
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <mpz_init@plt>
  mov    $0xe9,%edx
  mov    $0x80,%esi
  mov    %r12d,%edi
  call   <getPrime@plt>
  sub    $0x8,%rsp
  push   %r15
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0xffffffff,%edx
  mov    %r14,%rsi
  mov    %ebx,%edi
  call   <mpz_import@plt>
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %ebp,%edi
  call   <mpz_powm_sec@plt>
  mov    %ebp,(%rsp)
  mov    $0x0,%r9d
  mov    $0x1,%r8d
  mov    $0x1,%ecx
  mov    $0xffffffff,%edx
  mov    0x18(%rsp),%rsi
  mov    0x10(%rsp),%rdi
  call   <mpz_export@plt>
  mov    %r12d,%edi
  call   <mpz_clear@plt>
  mov    %ebp,%edi
  call   <mpz_clear@plt>
  mov    %ebx,%edi
  call   <mpz_clear@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void getPowm(unsigned char *res, unsigned long *reslen, const mpz_t base, const unsigned char *chexp, unsigned long len) {
  mpz_t prime;
  mpz_t exp;
  mpz_t ans;
  mpz_init(ans);
  mpz_init(exp);
  mpz_init(prime);
  getPrime(prime, 128, 233);
  mpz_import(exp, len, -1, 1, 1, 0, (void *)chexp);
  mpz_powm_sec(ans, base, exp, prime);
  mpz_export((void *)res, reslen, -1, 1, 1, 0, ans);
  mpz_clear(prime);
  mpz_clear(ans);
  mpz_clear(exp);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getPowm>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  xor    %ebp,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %r8,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <mpz_init@plt>
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r13d,%edi
  call   <mpz_init@plt>
  mov    %r13d,%edi
  mov    $0xe9,%edx
  mov    $0x80,%esi
  call   <getPrime@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  mov    %ebp,%edi
  mov    0x10(%rsp),%rcx
  mov    $0x1,%r8d
  mov    $0xffffffff,%edx
  push   %rcx
  mov    0x10(%rsp),%rsi
  mov    $0x1,%ecx
  call   <mpz_import@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <mpz_powm_sec@plt>
  mov    %r15,%rsi
  xor    %r9d,%r9d
  mov    $0x1,%ecx
  mov    $0x1,%r8d
  mov    $0xffffffff,%edx
  mov    %r14,%rdi
  mov    %r12d,(%rsp)
  call   <mpz_export@plt>
  mov    %r13d,%edi
  call   <mpz_clear@plt>
  mov    %r12d,%edi
  call   <mpz_clear@plt>
  add    $0x28,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10e0 <mpz_clear@plt>
```

assistant: ```c
void getPowm(unsigned char *res, unsigned long *reslen, const mpz_t base, const unsigned char *chexp, unsigned long len) {
  mpz_t prime;
  mpz_t exp;
  mpz_t ans;
  mpz_init(ans);
  mpz_init(exp);
  mpz_init(prime);
  getPrime(prime, 128, 233);
  mpz_import(exp, len, -1, 1, 1, 0, (void *)chexp);
  mpz_powm_sec(ans, base, exp, prime);
  mpz_export((void *)res, reslen, -1, 1, 1, 0, ans);
  mpz_clear(prime);
  mpz_clear(ans);
  mpz_clear(exp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getPowm>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%edi
  xor    %ebp,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %r8,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <mpz_init@plt>
  mov    %ebp,%edi
  call   <mpz_init@plt>
  mov    %r13d,%edi
  call   <mpz_init@plt>
  mov    %r13d,%edi
  mov    $0xe9,%edx
  mov    $0x80,%esi
  call   <getPrime@plt>
  sub    $0x8,%rsp
  xor    %r9d,%r9d
  mov    %ebp,%edi
  mov    0x10(%rsp),%rcx
  mov    $0x1,%r8d
  mov    $0xffffffff,%edx
  push   %rcx
  mov    0x10(%rsp),%rsi
  mov    $0x1,%ecx
  call   <mpz_import@plt>
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <mpz_powm_sec@plt>
  mov    %r15,%rsi
  xor    %r9d,%r9d
  mov    $0x1,%ecx
  mov    $0x1,%r8d
  mov    $0xffffffff,%edx
  mov    %r14,%rdi
  mov    %r12d,(%rsp)
  call   <mpz_export@plt>
  mov    %r13d,%edi
  call   <mpz_clear@plt>
  mov    %r12d,%edi
  call   <mpz_clear@plt>
  add    $0x28,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10e0 <mpz_clear@plt>
```

assistant: ```c
void getPowm(unsigned char *res, unsigned long *reslen, const mpz_t base, const unsigned char *chexp, unsigned long len) {
  mpz_t prime;
  mpz_t exp;
  mpz_t ans;
  mpz_init(ans);
  mpz_init(exp);
  mpz_init(prime);
  getPrime(prime, 128, 233);
  mpz_import(exp, len, -1, 1, 1, 0, (void *)chexp);
  mpz_powm_sec(ans, base, exp, prime);
  mpz_export((void *)res, reslen, -1, 1, 1, 0, ans);
  mpz_clear(prime);
  mpz_clear(ans);
  mpz_clear(exp);
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcmpi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L40
L17:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%ecx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  je     L40
  mov    $0x1,%eax
  jmp    L42
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L36
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
L36:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L58
L7:
  mov    $0x1,%eax
  jmp    L42
L58:
  mov    $0x0,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int strcmpi(const char *s1, const char *s2) {
  while (*s1 != 0 && *s2 != 0) {
    if (*s1++ != *s2++)
      return 1;
  }
  return !(*s1 == 0 && *s2 == 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<strcmpi>:
  endbr64
L0:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L25
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L20
  add    $0x1,%rdi
  add    $0x1,%rsi
  cmp    %dl,%al
  je     L0
  mov    $0x1,%eax
  ret
L20:
  mov    $0x1,%eax
  ret
L25:
  cmpb   $0x0,(%rsi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int strcmpi(const char *s1, const char *s2) {
  while (*s1 != 0 && *s2 != 0) {
    if (*s1++ != *s2++)
      return 1;
  }
  return !(*s1 == 0 && *s2 == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmpi>:
  endbr64
  xor    %eax,%eax
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L9:
  test   %cl,%cl
  je     L27
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L27
L7:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L9
  xor    %eax,%eax
  test   %cl,%cl
  setne  %al
  ret
L27:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmpi(const char *s1, const char *s2) {
  while (*s1 != 0 && *s2 != 0) {
    if (*s1++ != *s2++)
      return 1;
  }
  return !(*s1 == 0 && *s2 == 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcmpi>:
  endbr64
  xor    %eax,%eax
  jmp    L9
  nopl   0x0(%rax,%rax,1)
L33:
  test   %cl,%cl
  je     L32
  add    $0x1,%rax
  cmp    %dl,%cl
  jne    L32
L9:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rsi,%rax,1),%ecx
  test   %dl,%dl
  jne    L33
  xor    %eax,%eax
  test   %cl,%cl
  setne  %al
  ret
L32:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int strcmpi(const char *s1, const char *s2) {
  while (*s1 != 0 && *s2 != 0) {
    if (*s1++ != *s2++)
      return 1;
  }
  return !(*s1 == 0 && *s2 == 0);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %edi,-0x1c4(%rbp)
  mov    %rsi,-0x1d0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x14,-0x1a8(%rbp)
  movl   $0x0,-0x1b0(%rbp)
  jmp    L70
L65:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1b0(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1b0(%rbp)
L70:
  mov    -0x1b0(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jl     L65
  movl   $0x0,-0x1b0(%rbp)
  jmp    L71
L102:
  mov    -0x1b0(%rbp),%eax
  mov    %eax,-0x1ac(%rbp)
  mov    -0x1b0(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1b4(%rbp)
  jmp    L61
L46:
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jle    L44
  mov    -0x1b4(%rbp),%eax
  mov    %eax,-0x1ac(%rbp)
L44:
  addl   $0x1,-0x1b4(%rbp)
L61:
  mov    -0x1b4(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jl     L46
  mov    -0x1ac(%rbp),%eax
  cmp    -0x1b0(%rbp),%eax
  je     L7
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,-0x1a4(%rbp)
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a4(%rbp),%edx
  mov    %edx,-0x1a0(%rbp,%rax,4)
L7:
  addl   $0x1,-0x1b0(%rbp)
L71:
  mov    -0x1a8(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x1b0(%rbp)
  jl     L102
  movl   $0x0,-0x1b0(%rbp)
  jmp    L78
L33:
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1b0(%rbp)
L78:
  mov    -0x1b0(%rbp),%eax
  cmp    -0x1a8(%rbp),%eax
  jl     L33
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L86
  call   <__stack_chk_fail@plt>
L86:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D16
type_guessed: string

tool: D0: %d

tool: D16: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], i, j, p, t, n = 20;
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (j = 0; j < n - 1; j++) {
    p = j;
    for (i = j + 1; i < n; i++)
      if (a[p] > a[i])
        p = i;
    if (p != j) {
      t = a[j];
      a[j] = a[p];
      a[p] = t;
    }
  }
  for (j = 0; j < n; j++)
    printf("%d ", a[j]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%rbp
  mov    %rbx,%r12
  lea    D0(%rip),%r13
L3:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%r12
  cmp    %rbp,%r12
  jne    L3
  mov    $0x1,%r8d
  mov    $0x0,%edi
  mov    %rsp,%rsi
  jmp    L40
L87:
  add    $0x1,%rdi
  add    $0x1,%r8
  cmp    $0x14,%r8
  je     L2
L40:
  mov    %edi,%edx
  cmp    $0x13,%r8d
  jg     L87
  mov    %r8,%rax
L69:
  movslq %edx,%rcx
  mov    (%rsi,%rax,4),%r9d
  cmp    %r9d,(%rsp,%rcx,4)
  cmovg  %eax,%edx
  add    $0x1,%rax
  cmp    $0x13,%eax
  jle    L69
  cmp    %edi,%edx
  je     L87
  mov    (%rsi,%rdi,4),%eax
  movslq %edx,%rdx
  mov    (%rsp,%rdx,4),%ecx
  mov    %ecx,(%rsi,%rdi,4)
  mov    %eax,(%rsp,%rdx,4)
  jmp    L87
L2:
  lea    D18(%rip),%r12
L86:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L86
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  mov    $0x0,%eax
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: string
name: retrieve_data
arguments: tag: D18
type_guessed: string

tool: D0: %d

tool: D18: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], i, j, p, t, n = 20;
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (j = 0; j < n - 1; j++) {
    p = j;
    for (i = j + 1; i < n; i++)
      if (a[p] > a[i])
        p = i;
    if (p != j) {
      t = a[j];
      a[j] = a[p];
      a[p] = t;
    }
  }
  for (j = 0; j < n; j++)
    printf("%d ", a[j]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D19(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rbp
  mov    %r12,%rbx
  mov    %r12,%r13
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %rbp,%r13
  jne    L23
  xor    %esi,%esi
  cs nopw 0x0(%rax,%rax,1)
L56:
  mov    %esi,%edx
  mov    %rsi,%rdi
  add    $0x1,%rsi
  mov    %rsi,%rax
  nopl   0x0(%rax)
L10:
  movslq %edx,%rcx
  mov    (%r12,%rax,4),%r8d
  cmp    %r8d,(%rsp,%rcx,4)
  cmovg  %eax,%edx
  add    $0x1,%rax
  cmp    $0x14,%eax
  jne    L10
  cmp    %edi,%edx
  je     L6
  movslq %edx,%rdx
  mov    (%r12,%rdi,4),%eax
  mov    (%rsp,%rdx,4),%ecx
  mov    %ecx,(%r12,%rdi,4)
  mov    %eax,(%rsp,%rdx,4)
L6:
  cmp    $0x13,%rsi
  jne    L56
  lea    D14(%rip),%r12
  nopl   0x0(%rax)
L38:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L38
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_infered: string
name: read_data
arguments: data_label: D14
type_infered: string

tool: D19: %d

tool: D14: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], i, j, p, t, n = 20;
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (j = 0; j < n - 1; j++) {
    p = j;
    for (i = j + 1; i < n; i++)
      if (a[p] > a[i])
        p = i;
    if (p != j) {
      t = a[j];
      a[j] = a[p];
      a[p] = t;
    }
  }
  for (j = 0; j < n; j++)
    printf("%d ", a[j]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x50(%rsp),%r12
  mov    %rbx,%rbp
  mov    %rbx,%r13
  nopl   0x0(%rax,%rax,1)
L64:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %r12,%r13
  jne    L64
  xor    %edi,%edi
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    (%rbx,%rdi,4),%r8d
  movslq %edi,%rsi
  mov    %rdi,%r9
  add    $0x1,%rdi
  mov    %rdi,%rax
  mov    %r8d,%ecx
  nopl   0x0(%rax)
L30:
  mov    (%rbx,%rax,4),%edx
  cmp    %edx,%ecx
  jle    L53
  mov    %edx,%ecx
  movslq %eax,%rsi
L53:
  add    $0x1,%rax
  cmp    $0x14,%eax
  jne    L30
  cmp    %r9d,%esi
  je     L13
  mov    %ecx,(%rbx,%r9,4)
  mov    %r8d,(%rsp,%rsi,4)
L13:
  cmp    $0x13,%rdi
  jne    L39
  lea    D11(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L7
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type_guessed: string
name: unpack_data
arguments: label: D11
type_guessed: string

tool: D13: %d

tool: D11: %d 

assistant: ```c
int main(int argc, const char *argv[]) {
  int a[100], i, j, p, t, n = 20;
  for (j = 0; j < n; j++)
    scanf("%d", &a[j]);
  for (j = 0; j < n - 1; j++) {
    p = j;
    for (i = j + 1; i < n; i++)
      if (a[p] > a[i])
        p = i;
    if (p != j) {
      t = a[j];
      a[j] = a[p];
      a[p] = t;
    }
  }
  for (j = 0; j < n; j++)
    printf("%d ", a[j]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<res_mailok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    $0x1,%eax
  jmp    L98
L12:
  cmpl   $0x20,-0x4(%rbp)
  jle    L27
  cmpl   $0x7e,-0x4(%rbp)
  jle    L36
L27:
  mov    $0x0,%eax
  jmp    L98
L36:
  cmpl   $0x0,-0x8(%rbp)
  jne    L128
  cmpl   $0x2e,-0x4(%rbp)
  je     L90
L128:
  cmpl   $0x0,-0x8(%rbp)
  je     L96
  movl   $0x0,-0x8(%rbp)
  jmp    L8
L96:
  cmpl   $0x5c,-0x4(%rbp)
  jne    L8
  movl   $0x1,-0x8(%rbp)
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L12
  jmp    L71
L90:
  nop
L71:
  cmpl   $0x2e,-0x4(%rbp)
  jne    L15
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <res_hnok@plt>
  jmp    L98
L15:
  mov    $0x0,%eax
L98:
  leave
  ret
```

assistant: ```c
int res_mailok(const char *dn) {
  int ch, escaped = 0;
  if (*dn == '\0')
    return (1);
  while ((ch = *dn++) != '\0') {
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
    if (!escaped && ((ch) == 0x2e))
      break;
    if (escaped)
      escaped = 0;
    else if (((ch) == 0x5c))
      escaped = 1;
  }
  if (((ch) == 0x2e))
    return (res_hnok(dn));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<res_mailok>:
  endbr64
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  je     L48
  add    $0x1,%rdi
  movsbl %dl,%eax
  test   %eax,%eax
  je     L48
  mov    $0x0,%ecx
  mov    $0x0,%esi
  jmp    L63
L78:
  mov    %esi,%ecx
L62:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  movsbl %dl,%eax
  test   %eax,%eax
  je     L2
L63:
  movsbl %dl,%edx
  sub    $0x21,%edx
  cmp    $0x5d,%edx
  ja     L55
  test   %ecx,%ecx
  jne    L51
  cmp    $0x2e,%eax
  je     L38
L51:
  test   %ecx,%ecx
  jne    L78
  cmp    $0x5c,%eax
  sete   %cl
  movzbl %cl,%ecx
  jmp    L62
L2:
  ret
L55:
  mov    $0x0,%eax
  ret
L38:
  sub    $0x8,%rsp
  call   <res_hnok@plt>
  add    $0x8,%rsp
  ret
L48:
  ret
```

assistant: ```c
int res_mailok(const char *dn) {
  int ch, escaped = 0;
  if (*dn == '\0')
    return (1);
  while ((ch = *dn++) != '\0') {
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
    if (!escaped && ((ch) == 0x2e))
      break;
    if (escaped)
      escaped = 0;
    else if (((ch) == 0x5c))
      escaped = 1;
  }
  if (((ch) == 0x2e))
    return (res_hnok(dn));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<res_mailok>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L67
  add    $0x1,%rdi
  mov    %eax,%r8d
  test   %eax,%eax
  je     L27
  xor    %edx,%edx
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L60:
  test   %edx,%edx
  jne    L14
  cmp    $0x2e,%eax
  je     L35
L14:
  cmp    $0x5c,%eax
  sete   %al
  xor    $0x1,%edx
  add    $0x1,%rdi
  and    %eax,%edx
  movsbl -0x1(%rdi),%eax
  mov    %eax,%r8d
  test   %eax,%eax
  je     L27
L47:
  lea    -0x21(%rax),%ecx
  cmp    $0x5d,%ecx
  jbe    L60
  xor    %r8d,%r8d
L27:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L67:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  jmp    1050 <res_hnok@plt>
```

assistant: ```c
int res_mailok(const char *dn) {
  int ch, escaped = 0;
  if (*dn == '\0')
    return (1);
  while ((ch = *dn++) != '\0') {
    if (!((ch) > 0x20 && (ch) < 0x7f))
      return (0);
    if (!escaped && ((ch) == 0x2e))
      break;
    if (escaped)
      escaped = 0;
    else if (((ch) == 0x5c))
      escaped = 1;
  }
  if (((ch) == 0x2e))
    return (res_hnok(dn));
  return (0);
}
```