user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D123(%rip),%r14
  push   %r13
  lea    D167(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbp
  nopl   0x0(%rax)
L45:
  add    $0x1,%ebx
  mov    %r14,%rdi
  xor    %eax,%eax
  mov    %ebx,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    $0xf,%ebx
  jne    L45
  lea    0x40(%rsp),%r13
  lea    0x3c(%r12),%r14
  nopl   (%rax)
L189:
  mov    (%r12),%edi
  mov    $0x1,%ebx
  xor    %ebp,%ebp
  jmp    L113
  nopl   (%rax)
L324:
  mov    (%r12),%edi
  xor    %ecx,%ecx
  mov    %edi,%eax
  cmp    $0x1,%edi
  sete   %cl
  cltd
  idiv   %ebx
  cmp    $0x1,%edx
  adc    %ecx,%ebp
  add    $0x1,%ebx
L113:
  call   <sqrt@plt>
  cmp    %ebx,%eax
  jge    L324
  cmp    $0x1,%ebp
  je     L129
  add    $0x4,%r12
  movl   $0x0,0x0(%r13)
  add    $0x4,%r13
  cmp    %r14,%r12
  jne    L189
L318:
  lea    D115(%rip),%rdi
  call   <puts@plt>
  mov    0x40(%rsp),%esi
  test   %esi,%esi
  jne    L375
L77:
  mov    0x44(%rsp),%esi
  test   %esi,%esi
  jne    L226
L114:
  mov    0x48(%rsp),%esi
  test   %esi,%esi
  jne    L338
L147:
  mov    0x4c(%rsp),%esi
  test   %esi,%esi
  jne    L271
L162:
  mov    0x50(%rsp),%esi
  test   %esi,%esi
  jne    L311
L353:
  mov    0x54(%rsp),%esi
  test   %esi,%esi
  jne    L87
L36:
  mov    0x58(%rsp),%esi
  test   %esi,%esi
  jne    L277
L92:
  mov    0x5c(%rsp),%esi
  test   %esi,%esi
  jne    L119
L130:
  mov    0x60(%rsp),%esi
  test   %esi,%esi
  jne    L138
L153:
  mov    0x64(%rsp),%esi
  test   %esi,%esi
  jne    L131
L231:
  mov    0x68(%rsp),%esi
  test   %esi,%esi
  jne    L98
L235:
  mov    0x6c(%rsp),%esi
  test   %esi,%esi
  jne    L53
L243:
  mov    0x70(%rsp),%esi
  test   %esi,%esi
  jne    L136
L371:
  mov    0x74(%rsp),%esi
  test   %esi,%esi
  jne    L343
L264:
  mov    0x78(%rsp),%esi
  test   %esi,%esi
  jne    L122
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L252
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L129:
  mov    (%r12),%eax
  add    $0x4,%r12
  add    $0x4,%r13
  mov    %eax,-0x4(%r13)
  cmp    %r14,%r12
  jne    L189
  jmp    L318
L375:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L77
L122:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L343:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L264
L136:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L371
L53:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L243
L98:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L235
L131:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L231
L138:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L153
L119:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L130
L277:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L92
L87:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L36
L311:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L353
L271:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L162
L338:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L147
L226:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L114
L252:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D123
type: string
name: parse_data
arguments: data_tag: D167
type: string
name: parse_data
arguments: data_tag: D115
type: string
name: parse_data
arguments: data_tag: D6
type: string

tool: D123: Informe o valor da posicao %d: 

tool: D167: %d

tool: D115: Vetor P:

tool: D6: %d 

assistant: ```c
void main() {
  int K[15], vzs = 0, P[15];
  for (int i = 0; i < 15; i++) {
    printf("Informe o valor da posicao %d: ", i + 1);
    scanf("%d", &K[i]);
  }
  for (int i = 0; i < 15; i++) {
    for (int j = 1; j <= sqrt(K[i]); j++) {
      if (K[i] == 1) {
        vzs++;
      }
      if (K[i] % j == 0) {
        vzs++;
      }
    }
    if (vzs == 1) {
      P[i] = K[i];
    } else {
      P[i] = 0;
    }
    vzs = 0;
  }
  printf("Vetor P:\n");
  for (int i = 0; i < 15; i++) {
    if (P[i] != 0) {
      printf("%d ", P[i]);
    }
  }
  printf("\n");
}
```