ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<calloc>:
  endbr64
  push   %r13
  imul   %rsi,%rdi
  push   %r12
  mov    %rdi,%r13
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *calloc(size_t nmemb, size_t size) {
  void *p = malloc(nmemb * size);
  if (p)
    memset(p, 0, nmemb * size);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rws_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L17
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  jmp    L7
L17:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
void *rws_malloc(const size_t size) {
  if (size > 0) {
    void *mem = malloc(size);
    assert(mem);
    return mem;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rws_malloc>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  test   %rdi,%rdi
  jne    L4
L5:
  mov    %rbx,%rax
  pop    %rbx
  ret
L4:
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  jmp    L5
```

assistant: ```c
void *rws_malloc(const size_t size) {
  if (size > 0) {
    void *mem = malloc(size);
    assert(mem);
    return mem;
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rws_malloc>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdi,%rdi
  je     L3
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <assert@plt>
L3:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *rws_malloc(const size_t size) {
  if (size > 0) {
    void *mem = malloc(size);
    assert(mem);
    return mem;
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rws_malloc>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  test   %rdi,%rdi
  je     L0
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <assert@plt>
L0:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *rws_malloc(const size_t size) {
  if (size > 0) {
    void *mem = malloc(size);
    assert(mem);
    return mem;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x4(%rbp),%eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assume@plt>
  jmp    L6
L19:
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x9,-0x4(%rbp)
  jle    L19
  cmpl   $0xa,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x;
  assume(x < 0);
  while (x < 10) {
    x = x + 1;
  }
  assert(x == 10);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  mov    %ebx,%edi
  shr    $0x1f,%edi
  call   <assume@plt>
L3:
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L3
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x;
  assume(x < 0);
  while (x < 10) {
    x = x + 1;
  }
  assert(x == 10);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  assume(x < 0);
  while (x < 10) {
    x = x + 1;
  }
  assert(x == 10);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <assume@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x;
  assume(x < 0);
  while (x < 10) {
    x = x + 1;
  }
  assert(x == 10);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D87(%rip),%rbx
L88:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  ja     L88
  cmp    $0x8,%eax
  ja     L98
  mov    %eax,%eax
  lea    D70(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D88(%rip),%rdi
  call   <printf@plt>
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
  lea    D66(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D81(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D97(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D84(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D77(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D106(%rip),%rdi
  call   <printf@plt>
  jmp    L28
  lea    D86(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L98:
  lea    D68(%rip),%rdi
  call   <printf@plt>
  jmp    L28
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D87
datatype: string
name: extract_symbolic_data
arguments: data_label: D88
datatype: string
name: extract_symbolic_data
arguments: data_label: D66
datatype: string
name: extract_symbolic_data
arguments: data_label: D81
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D97
datatype: string
name: extract_symbolic_data
arguments: data_label: D84
datatype: string
name: extract_symbolic_data
arguments: data_label: D77
datatype: string
name: extract_symbolic_data
arguments: data_label: D106
datatype: string
name: extract_symbolic_data
arguments: data_label: D86
datatype: string
name: extract_symbolic_data
arguments: data_label: D68
datatype: string

tool: D87: %d

tool: D88: zero


tool: D66: one


tool: D81: two


tool: D1: three


tool: D97: four


tool: D84: five


tool: D77: six


tool: D106: seven


tool: D86: eight


tool: D68: nine


assistant: ```c
int main() {
  int i;
  do {
    scanf("%d", &i);
  } while (i < 0 || i > 9);
  if (i == 0)
    printf("zero\n");
  else if (i == 1)
    printf("one\n");
  else if (i == 2)
    printf("two\n");
  else if (i == 3)
    printf("three\n");
  else if (i == 4)
    printf("four\n");
  else if (i == 5)
    printf("five\n");
  else if (i == 6)
    printf("six\n");
  else if (i == 7)
    printf("seven\n");
  else if (i == 8)
    printf("eight\n");
  else
    printf("nine\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D97(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L62:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  ja     L62
  test   %eax,%eax
  je     L22
  cmp    $0x8,%eax
  ja     L10
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L22:
  lea    D28(%rip),%rdi
  call   <printf@plt>
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D106(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D100(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D118(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  lea    D99(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L10:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D97
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D44
type: string
name: extract_symbolic_data
arguments: data_label: D106
type: string
name: extract_symbolic_data
arguments: data_label: D100
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D118
type: string
name: extract_symbolic_data
arguments: data_label: D69
type: string
name: extract_symbolic_data
arguments: data_label: D99
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string

tool: D97: %d

tool: D28: zero


tool: D16: eight


tool: D44: one


tool: D106: two


tool: D100: three


tool: D27: four


tool: D118: five


tool: D69: six


tool: D99: seven


tool: D4: nine


assistant: ```c
int main() {
  int i;
  do {
    scanf("%d", &i);
  } while (i < 0 || i > 9);
  if (i == 0)
    printf("zero\n");
  else if (i == 1)
    printf("one\n");
  else if (i == 2)
    printf("two\n");
  else if (i == 3)
    printf("three\n");
  else if (i == 4)
    printf("four\n");
  else if (i == 5)
    printf("five\n");
  else if (i == 6)
    printf("six\n");
  else if (i == 7)
    printf("seven\n");
  else if (i == 8)
    printf("eight\n");
  else
    printf("nine\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  cs nopw 0x0(%rax,%rax,1)
L101:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x9,%eax
  ja     L101
  test   %eax,%eax
  je     L45
  cmp    $0x8,%eax
  ja     L112
  lea    D99(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L45:
  lea    D57(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  lea    D70(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D115(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D87(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D74(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D65(%rip),%rdi
  call   <printf@plt>
  jmp    L0
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L112:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string
name: extract_symbolic_data
arguments: tag: D57
type_infered: string
name: extract_symbolic_data
arguments: tag: D70
type_infered: string
name: extract_symbolic_data
arguments: tag: D115
type_infered: string
name: extract_symbolic_data
arguments: tag: D87
type_infered: string
name: extract_symbolic_data
arguments: tag: D74
type_infered: string
name: extract_symbolic_data
arguments: tag: D79
type_infered: string
name: extract_symbolic_data
arguments: tag: D24
type_infered: string
name: extract_symbolic_data
arguments: tag: D65
type_infered: string
name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D39
type_infered: string

tool: D3: %d

tool: D57: zero


tool: D70: eight


tool: D115: one


tool: D87: two


tool: D74: three


tool: D79: four


tool: D24: five


tool: D65: six


tool: D23: seven


tool: D39: nine


assistant: ```c
int main() {
  int i;
  do {
    scanf("%d", &i);
  } while (i < 0 || i > 9);
  if (i == 0)
    printf("zero\n");
  else if (i == 1)
    printf("one\n");
  else if (i == 2)
    printf("two\n");
  else if (i == 3)
    printf("three\n");
  else if (i == 4)
    printf("four\n");
  else if (i == 5)
    printf("five\n");
  else if (i == 6)
    printf("six\n");
  else if (i == 7)
    printf("seven\n");
  else if (i == 8)
    printf("eight\n");
  else
    printf("nine\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0xd,-0x2c(%rbp)
  movl   $0x18,-0x28(%rbp)
  movl   $0x27,-0x24(%rbp)
  movl   $0x29,-0x20(%rbp)
  movl   $0x38,-0x1c(%rbp)
  movl   $0x44,-0x18(%rbp)
  movl   $0x49,-0x14(%rbp)
  movl   $0x52,-0x10(%rbp)
  movl   $0x5f,-0xc(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x34(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L20
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L26
L20:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
data_type: string
name: retrieve_data
arguments: tag: D18
data_type: string
name: retrieve_data
arguments: tag: D21
data_type: string
name: retrieve_data
arguments: tag: D35
data_type: string

tool: D5: Enter The Key To Search: 

tool: D18: %d

tool: D21: Found!!! 


tool: D35: Not Found!!!


assistant: ```c
int main() {
  int key;
  int arr[10] = {1, 13, 24, 39, 41, 56, 68, 73, 82, 95};
  printf("Enter The Key To Search: ");
  scanf("%d", &key);
  if (binarySearch(arr, &key))
    printf("Found!!! \n");
  else
    printf("Not Found!!!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0xd,0x14(%rsp)
  movl   $0x18,0x18(%rsp)
  movl   $0x27,0x1c(%rsp)
  movl   $0x29,0x20(%rsp)
  movl   $0x38,0x24(%rsp)
  movl   $0x44,0x28(%rsp)
  movl   $0x49,0x2c(%rsp)
  movl   $0x52,0x30(%rsp)
  movl   $0x5f,0x34(%rsp)
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rsi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L29
  lea    D32(%rip),%rdi
  call   <printf@plt>
L20:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L29:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D32
type: string
name: extract_symbolic_data
arguments: tag: D24
type: string

tool: D7: Enter The Key To Search: 

tool: D29: %d

tool: D32: Found!!! 


tool: D24: Not Found!!!


assistant: ```c
int main() {
  int key;
  int arr[10] = {1, 13, 24, 39, 41, 56, 68, 73, 82, 95};
  printf("Enter The Key To Search: ");
  scanf("%d", &key);
  if (binarySearch(arr, &key))
    printf("Found!!! \n");
  else
    printf("Not Found!!!\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D34(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xd00000001,%rax
  lea    0xc(%rsp),%rbp
  mov    %rax,0x10(%rsp)
  movabs $0x2700000018,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x3800000029,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x4900000044,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x5f00000052,%rax
  mov    %rax,0x30(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L8
  lea    D24(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D34
datatype: string
name: read_data
arguments: tag: D31
datatype: string
name: read_data
arguments: tag: D24
datatype: string
name: read_data
arguments: tag: D18
datatype: string

tool: D34: Enter The Key To Search: 

tool: D31: %d

tool: D24: Found!!! 


tool: D18: Not Found!!!


assistant: ```c
int main() {
  int key;
  int arr[10] = {1, 13, 24, 39, 41, 56, 68, 73, 82, 95};
  printf("Enter The Key To Search: ");
  scanf("%d", &key);
  if (binarySearch(arr, &key))
    printf("Found!!! \n");
  else
    printf("Not Found!!!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D25(%rip),%rdi
  sub    $0x40,%rsp
  movdqa D35(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D45(%rip),%rax
  lea    0xc(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  movdqa D37(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D60(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  call   <binarySearch@plt>
  test   %rax,%rax
  je     L14
  lea    D9(%rip),%rdi
  call   <printf@plt>
L3:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L14:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L3
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D25
type: string
name: unpack_data
arguments: label: D35
type: byte[16]
name: unpack_data
arguments: label: D45
type: byte[8]
name: unpack_data
arguments: label: D37
type: byte[16]
name: unpack_data
arguments: label: D60
type: string
name: unpack_data
arguments: label: D9
type: string
name: unpack_data
arguments: label: D36
type: string

tool: D25: Enter The Key To Search: 

tool: {"D35": [0x01,0x00,0x00,0x00,0x0d,0x00,0x00,0x00,0x18,0x00,0x00,0x00,0x27,0x00,0x00,0x00]}

tool: {"D45": [0x52,0x00,0x00,0x00,0x5f,0x00,0x00,0x00]}

tool: {"D37": [0x29,0x00,0x00,0x00,0x38,0x00,0x00,0x00,0x44,0x00,0x00,0x00,0x49,0x00,0x00,0x00]}

tool: D60: %d

tool: D9: Found!!! 


tool: D36: Not Found!!!


assistant: ```c
int main() {
  int key;
  int arr[10] = {1, 13, 24, 39, 41, 56, 68, 73, 82, 95};
  printf("Enter The Key To Search: ");
  scanf("%d", &key);
  if (binarySearch(arr, &key))
    printf("Found!!! \n");
  else
    printf("Not Found!!!\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<stb_suffixi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L6
  mov    -0x10(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L19
L6:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int stb_suffixi(char *s, char *t) {
  size_t n = strlen(s);
  size_t m = strlen(t);
  if (m <= n)
    return 0 == strcasecmp(s + n - m, t);
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stb_suffixi>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %rax,%rbp
  jae    L18
L2:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  sub    %rax,%rbp
  lea    (%rbx,%rbp,1),%rdi
  mov    %r12,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  sete   %dl
  movzbl %dl,%edx
  jmp    L2
```

assistant: ```c
int stb_suffixi(char *s, char *t) {
  size_t n = strlen(s);
  size_t m = strlen(t);
  if (m <= n)
    return 0 == strcasecmp(s + n - m, t);
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<stb_suffixi>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %rax,%rbp
  jae    L3
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L3:
  sub    %rax,%rbp
  mov    %r12,%rsi
  lea    (%rbx,%rbp,1),%rdi
  call   <strcasecmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int stb_suffixi(char *s, char *t) {
  size_t n = strlen(s);
  size_t m = strlen(t);
  if (m <= n)
    return 0 == strcasecmp(s + n - m, t);
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stb_suffixi>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  xor    %r8d,%r8d
  cmp    %rax,%rbp
  jae    L9
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L9:
  sub    %rax,%rbp
  mov    %r12,%rsi
  lea    (%rbx,%rbp,1),%rdi
  call   <strcasecmp@plt>
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %r8b
  mov    %r8d,%eax
  ret
```

assistant: ```c
int stb_suffixi(char *s, char *t) {
  size_t n = strlen(s);
  size_t m = strlen(t);
  if (m <= n)
    return 0 == strcasecmp(s + n - m, t);
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<randowm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1869f,-0xc(%rbp)
  jmp    L17
L1:
  movl   $0x0,-0x8(%rbp)
  jmp    L36
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L25
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L25:
  addl   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L18
  subl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x0,-0xc(%rbp)
  jns    L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void randowm(int a[]) {
  int i, j, n, k, l;
  for (i = 99999; i >= 0; i--) {
    for (j = 0; j < i; j++) {
      if (a[i] < a[j]) {
        l = a[j];
        a[j] = a[i];
        a[i] = l;
      }
    }
  }
}
```