ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  jne    L8
  xor    %eax,%eax
  mov    %rsi,%rbx
  call   <bs_cmd_flag_hif_mode_cmd@plt>
  xor    %eax,%eax
  call   <bs_cmd_wait_dspe_trg@plt>
  xor    %eax,%eax
  call   <bs_cmd_wait_dspe_frend@plt>
  mov    0x8(%rbx),%rdi
  call   <atoi@plt>
  xor    %edx,%edx
  mov    $0xf,%esi
  mov    %eax,%edi
  call   <bs_cmd_upd_full@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L8:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  or     $0xffffffff,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: Usage: bs_disp_full <mode>


assistant: ```c
int main(int argc, char **argv) {
  int lut = 15;
  if (argc != 2) {
    printf("Usage: bs_disp_full <mode>\n\r");
    return (-1);
  }
  bs_cmd_flag_hif_mode_cmd();
  bs_cmd_wait_dspe_trg();
  bs_cmd_wait_dspe_frend();
  bs_cmd_upd_full(atoi(*++argv), lut, 0);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfc1738_unescape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L176
L225:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x2f,-0x10(%rbp)
  jle    L94
  cmpl   $0x39,-0x10(%rbp)
  jg     L94
  subl   $0x30,-0x10(%rbp)
  jmp    L179
L94:
  cmpl   $0x40,-0x10(%rbp)
  jle    L134
  cmpl   $0x46,-0x10(%rbp)
  jg     L134
  subl   $0x37,-0x10(%rbp)
  jmp    L179
L134:
  cmpl   $0x60,-0x10(%rbp)
  jle    L219
  cmpl   $0x66,-0x10(%rbp)
  jg     L219
  subl   $0x57,-0x10(%rbp)
  jmp    L179
L219:
  addq   $0x1,-0x8(%rbp)
  jmp    L176
L179:
  cmpl   $0x2f,-0xc(%rbp)
  jle    L60
  cmpl   $0x39,-0xc(%rbp)
  jg     L60
  subl   $0x30,-0xc(%rbp)
  jmp    L226
L60:
  cmpl   $0x40,-0xc(%rbp)
  jle    L64
  cmpl   $0x46,-0xc(%rbp)
  jg     L64
  subl   $0x37,-0xc(%rbp)
  jmp    L226
L64:
  cmpl   $0x60,-0xc(%rbp)
  jle    L28
  cmpl   $0x66,-0xc(%rbp)
  jg     L28
  subl   $0x57,-0xc(%rbp)
  jmp    L226
L28:
  addq   $0x1,-0x8(%rbp)
  jmp    L176
L226:
  mov    -0x10(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  or     %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    0x3(%rax),%rcx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  addq   $0x1,-0x8(%rbp)
L176:
  cmpq   $0x0,-0x8(%rbp)
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  mov    $0x25,%esi
  mov    %rax,%rdi
  call   <strchr_m@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L225
L4:
  nop
  leave
  ret
```

assistant: ```c
void rfc1738_unescape(char *buf) {
  char *p = buf;
  while (p && *p && (p = strchr_m(p, '%'))) {
    int c1 = p[1];
    int c2 = p[2];
    if (c1 >= '0' && c1 <= '9')
      c1 = c1 - '0';
    else if (c1 >= 'A' && c1 <= 'F')
      c1 = 10 + c1 - 'A';
    else if (c1 >= 'a' && c1 <= 'f')
      c1 = 10 + c1 - 'a';
    else {
      p++;
      continue;
    }
    if (c2 >= '0' && c2 <= '9')
      c2 = c2 - '0';
    else if (c2 >= 'A' && c2 <= 'F')
      c2 = 10 + c2 - 'A';
    else if (c2 >= 'a' && c2 <= 'f')
      c2 = 10 + c2 - 'a';
    else {
      p++;
      continue;
    }
    *p = (c1 << 4) | c2;
    memmove(p + 1, p + 3, strlen(p + 3) + 1);
    p++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rfc1738_unescape>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  test   %rdi,%rdi
  jne    L111
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  lea    -0x41(%rax),%esi
  cmp    $0x5,%esi
  ja     L47
  sub    $0x37,%eax
  jmp    L110
L47:
  lea    -0x61(%rax),%esi
  lea    0x1(%rbx),%rbp
  cmp    $0x5,%esi
  ja     L111
  sub    $0x57,%eax
  jmp    L110
L94:
  lea    -0x41(%rdx),%esi
  cmp    $0x5,%esi
  ja     L67
  sub    $0x37,%ecx
L30:
  shl    $0x4,%eax
  or     %ecx,%eax
  mov    %al,(%rbx)
  lea    0x3(%rbx),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx),%rbp
  lea    0x1(%rax),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memmove@plt>
L111:
  cmpb   $0x0,0x0(%rbp)
  je     L16
  mov    $0x25,%esi
  mov    %rbp,%rdi
  call   <strchr_m@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
  movsbl 0x1(%rbx),%eax
  movzbl 0x2(%rbx),%edx
  movsbl %dl,%ecx
  lea    -0x30(%rax),%esi
  cmp    $0x9,%esi
  ja     L7
  mov    %esi,%eax
L110:
  movsbl %dl,%edx
  lea    -0x30(%rdx),%esi
  cmp    $0x9,%esi
  ja     L94
  sub    $0x30,%ecx
  jmp    L30
L67:
  sub    $0x61,%edx
  lea    0x1(%rbx),%rbp
  cmp    $0x5,%edx
  ja     L111
  sub    $0x57,%ecx
  jmp    L30
```

assistant: ```c
void rfc1738_unescape(char *buf) {
  char *p = buf;
  while (p && *p && (p = strchr_m(p, '%'))) {
    int c1 = p[1];
    int c2 = p[2];
    if (c1 >= '0' && c1 <= '9')
      c1 = c1 - '0';
    else if (c1 >= 'A' && c1 <= 'F')
      c1 = 10 + c1 - 'A';
    else if (c1 >= 'a' && c1 <= 'f')
      c1 = 10 + c1 - 'a';
    else {
      p++;
      continue;
    }
    if (c2 >= '0' && c2 <= '9')
      c2 = c2 - '0';
    else if (c2 >= 'A' && c2 <= 'F')
      c2 = 10 + c2 - 'A';
    else if (c2 >= 'a' && c2 <= 'f')
      c2 = 10 + c2 - 'a';
    else {
      p++;
      continue;
    }
    *p = (c1 << 4) | c2;
    memmove(p + 1, p + 3, strlen(p + 3) + 1);
    p++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rfc1738_unescape>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L49
L105:
  cmpb   $0x0,(%r12)
  je     L49
L42:
  mov    $0x25,%esi
  mov    %r12,%rdi
  call   <strchr_m@plt>
  test   %rax,%rax
  je     L49
  movsbl 0x1(%rax),%ecx
  movsbl 0x2(%rax),%esi
  lea    0x1(%rax),%r12
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  jbe    L8
  lea    -0x41(%rcx),%edx
  cmp    $0x5,%edx
  ja     L118
  lea    -0x37(%rcx),%edx
L8:
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%ecx
  jbe    L119
  lea    -0x41(%rsi),%ecx
  cmp    $0x5,%ecx
  ja     L9
  lea    -0x37(%rsi),%ecx
L119:
  shl    $0x4,%edx
  lea    0x3(%rax),%rbp
  or     %ecx,%edx
  mov    %rbp,%rdi
  mov    %dl,(%rax)
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  cmpb   $0x0,(%r12)
  jne    L42
L49:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L118:
  lea    -0x61(%rcx),%edx
  cmp    $0x5,%edx
  ja     L105
  lea    -0x57(%rcx),%edx
  jmp    L8
  nopl   0x0(%rax)
L9:
  lea    -0x61(%rsi),%ecx
  cmp    $0x5,%ecx
  ja     L105
  lea    -0x57(%rsi),%ecx
  jmp    L119
```

assistant: ```c
void rfc1738_unescape(char *buf) {
  char *p = buf;
  while (p && *p && (p = strchr_m(p, '%'))) {
    int c1 = p[1];
    int c2 = p[2];
    if (c1 >= '0' && c1 <= '9')
      c1 = c1 - '0';
    else if (c1 >= 'A' && c1 <= 'F')
      c1 = 10 + c1 - 'A';
    else if (c1 >= 'a' && c1 <= 'f')
      c1 = 10 + c1 - 'a';
    else {
      p++;
      continue;
    }
    if (c2 >= '0' && c2 <= '9')
      c2 = c2 - '0';
    else if (c2 >= 'A' && c2 <= 'F')
      c2 = 10 + c2 - 'A';
    else if (c2 >= 'a' && c2 <= 'f')
      c2 = 10 + c2 - 'a';
    else {
      p++;
      continue;
    }
    *p = (c1 << 4) | c2;
    memmove(p + 1, p + 3, strlen(p + 3) + 1);
    p++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<rfc1738_unescape>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L102
L22:
  cmpb   $0x0,(%r12)
  je     L102
L1:
  mov    $0x25,%esi
  mov    %r12,%rdi
  call   <strchr_m@plt>
  test   %rax,%rax
  je     L102
  movsbl 0x1(%rax),%ecx
  movsbl 0x2(%rax),%esi
  lea    0x1(%rax),%r12
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  jbe    L99
  lea    -0x41(%rcx),%edx
  cmp    $0x5,%edx
  ja     L35
  lea    -0x37(%rcx),%edx
L99:
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%ecx
  jbe    L49
  lea    -0x41(%rsi),%ecx
  cmp    $0x5,%ecx
  ja     L73
  lea    -0x37(%rsi),%ecx
L49:
  shl    $0x4,%edx
  lea    0x3(%rax),%rbp
  or     %ecx,%edx
  mov    %rbp,%rdi
  mov    %dl,(%rax)
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memmove@plt>
  cmpb   $0x0,(%r12)
  jne    L1
L102:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L35:
  lea    -0x61(%rcx),%edx
  cmp    $0x5,%edx
  ja     L22
  lea    -0x57(%rcx),%edx
  jmp    L99
  nopl   0x0(%rax)
L73:
  lea    -0x61(%rsi),%ecx
  cmp    $0x5,%ecx
  ja     L22
  lea    -0x57(%rsi),%ecx
  jmp    L49
```

assistant: ```c
void rfc1738_unescape(char *buf) {
  char *p = buf;
  while (p && *p && (p = strchr_m(p, '%'))) {
    int c1 = p[1];
    int c2 = p[2];
    if (c1 >= '0' && c1 <= '9')
      c1 = c1 - '0';
    else if (c1 >= 'A' && c1 <= 'F')
      c1 = 10 + c1 - 'A';
    else if (c1 >= 'a' && c1 <= 'f')
      c1 = 10 + c1 - 'a';
    else {
      p++;
      continue;
    }
    if (c2 >= '0' && c2 <= '9')
      c2 = c2 - '0';
    else if (c2 >= 'A' && c2 <= 'F')
      c2 = 10 + c2 - 'A';
    else if (c2 >= 'a' && c2 <= 'f')
      c2 = 10 + c2 - 'a';
    else {
      p++;
      continue;
    }
    *p = (c1 << 4) | c2;
    memmove(p + 1, p + 3, strlen(p + 3) + 1);
    p++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmpHeapAllocationToUnknown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <retPtr@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <retPtrMightAlias@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <clang_analyzer_eval@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int cmpHeapAllocationToUnknown() {
  int zero = 0;
  int *yBefore = retPtr();
  int *m = malloc(8);
  int *yAfter = retPtrMightAlias(m);
  clang_analyzer_eval(yBefore == m);
  clang_analyzer_eval(yAfter == m);
  free(m);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmpHeapAllocationToUnknown>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <retPtr@plt>
  mov    %rax,%r12
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <retPtrMightAlias@plt>
  mov    %rax,%rbp
  cmp    %rbx,%r12
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  cmp    %rbp,%rbx
  sete   %dil
  movzbl %dil,%edi
  call   <clang_analyzer_eval@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmpHeapAllocationToUnknown() {
  int zero = 0;
  int *yBefore = retPtr();
  int *m = malloc(8);
  int *yAfter = retPtrMightAlias(m);
  clang_analyzer_eval(yBefore == m);
  clang_analyzer_eval(yAfter == m);
  free(m);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmpHeapAllocationToUnknown>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <retPtr@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <retPtrMightAlias@plt>
  xor    %edi,%edi
  cmp    %rbp,%r12
  mov    %rax,%rbx
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmp    %rbx,%rbp
  sete   %dil
  call   <clang_analyzer_eval@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmpHeapAllocationToUnknown() {
  int zero = 0;
  int *yBefore = retPtr();
  int *m = malloc(8);
  int *yAfter = retPtrMightAlias(m);
  clang_analyzer_eval(yBefore == m);
  clang_analyzer_eval(yAfter == m);
  free(m);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmpHeapAllocationToUnknown>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <retPtr@plt>
  mov    $0x8,%edi
  mov    %rax,%r12
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <retPtrMightAlias@plt>
  xor    %edi,%edi
  cmp    %rbp,%r12
  mov    %rax,%rbx
  sete   %dil
  call   <clang_analyzer_eval@plt>
  xor    %edi,%edi
  cmp    %rbx,%rbp
  sete   %dil
  call   <clang_analyzer_eval@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cmpHeapAllocationToUnknown() {
  int zero = 0;
  int *yBefore = retPtr();
  int *m = malloc(8);
  int *yAfter = retPtrMightAlias(m);
  clang_analyzer_eval(yBefore == m);
  clang_analyzer_eval(yAfter == m);
  free(m);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xffffffff,%eax
  xchg   %al,-0xb(%rbp)
  mov    %al,-0xb(%rbp)
  mov    $0xffffffff,%eax
  xchg   %al,-0x9(%rbp)
  mov    %al,-0x9(%rbp)
  mov    $0xffffffff,%eax
  xchg   %ax,-0x66(%rbp)
  mov    %ax,-0x66(%rbp)
  mov    $0xffffffff,%eax
  xchg   %ax,-0x62(%rbp)
  mov    %ax,-0x62(%rbp)
  mov    $0xffffffff,%eax
  xchg   %eax,-0x5c(%rbp)
  mov    %eax,-0x5c(%rbp)
  mov    $0xffffffff,%eax
  xchg   %eax,-0x54(%rbp)
  mov    %eax,-0x54(%rbp)
  mov    $0xffffffffffffffff,%rax
  xchg   %rax,-0x48(%rbp)
  mov    %rax,-0x48(%rbp)
  mov    $0xffffffffffffffff,%rax
  xchg   %rax,-0x38(%rbp)
  mov    %rax,-0x38(%rbp)
  mov    $0xffffffffffffffff,%rax
  xchg   %rax,-0x28(%rbp)
  mov    %rax,-0x28(%rbp)
  mov    $0xffffffffffffffff,%rax
  xchg   %rax,-0x18(%rbp)
  mov    %rax,-0x18(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void test_lock(void) {
  signed char sc[2];
  unsigned char uc[2];
  signed short ss[2];
  unsigned short us[2];
  signed int si[2];
  unsigned int ui[2];
  signed long sl[2];
  unsigned long ul[2];
  signed long long sll[2];
  unsigned long long ull[2];
  sc[1] = __sync_lock_test_and_set(&sc[1], -1);
  uc[1] = __sync_lock_test_and_set(&uc[1], -1);
  ss[1] = __sync_lock_test_and_set(&ss[1], -1);
  us[1] = __sync_lock_test_and_set(&us[1], -1);
  si[1] = __sync_lock_test_and_set(&si[1], -1);
  ui[1] = __sync_lock_test_and_set(&ui[1], -1);
  sl[1] = __sync_lock_test_and_set(&sl[1], -1);
  ul[1] = __sync_lock_test_and_set(&ul[1], -1);
  sll[1] = __sync_lock_test_and_set(&sll[1], -1);
  ull[1] = __sync_lock_test_and_set(&ull[1], -1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_lock>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %dl,0x65(%rsp)
  mov    %dl,0x65(%rsp)
  xchg   %al,0x67(%rsp)
  mov    %al,0x67(%rsp)
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %dx,0xa(%rsp)
  mov    %dx,0xa(%rsp)
  xchg   %ax,0xe(%rsp)
  mov    %ax,0xe(%rsp)
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %edx,0x14(%rsp)
  mov    %edx,0x14(%rsp)
  xchg   %eax,0x1c(%rsp)
  mov    %eax,0x1c(%rsp)
  mov    $0xffffffffffffffff,%rax
  mov    %rax,%rdx
  xchg   %rdx,0x28(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rax,%rdx
  xchg   %rdx,0x38(%rsp)
  mov    %rdx,0x38(%rsp)
  mov    %rax,%rdx
  xchg   %rdx,0x48(%rsp)
  mov    %rdx,0x48(%rsp)
  xchg   %rax,0x58(%rsp)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x78,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_lock(void) {
  signed char sc[2];
  unsigned char uc[2];
  signed short ss[2];
  unsigned short us[2];
  signed int si[2];
  unsigned int ui[2];
  signed long sl[2];
  unsigned long ul[2];
  signed long long sll[2];
  unsigned long long ull[2];
  sc[1] = __sync_lock_test_and_set(&sc[1], -1);
  uc[1] = __sync_lock_test_and_set(&uc[1], -1);
  ss[1] = __sync_lock_test_and_set(&ss[1], -1);
  us[1] = __sync_lock_test_and_set(&us[1], -1);
  si[1] = __sync_lock_test_and_set(&si[1], -1);
  ui[1] = __sync_lock_test_and_set(&ui[1], -1);
  sl[1] = __sync_lock_test_and_set(&sl[1], -1);
  ul[1] = __sync_lock_test_and_set(&ul[1], -1);
  sll[1] = __sync_lock_test_and_set(&sll[1], -1);
  ull[1] = __sync_lock_test_and_set(&ull[1], -1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_lock>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %dl,0x65(%rsp)
  mov    %dl,0x65(%rsp)
  xchg   %al,0x67(%rsp)
  mov    %al,0x67(%rsp)
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %dx,0xa(%rsp)
  mov    %dx,0xa(%rsp)
  xchg   %ax,0xe(%rsp)
  mov    %ax,0xe(%rsp)
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %edx,0x14(%rsp)
  mov    %edx,0x14(%rsp)
  xchg   %eax,0x1c(%rsp)
  mov    %eax,0x1c(%rsp)
  mov    $0xffffffffffffffff,%rax
  mov    %rax,%rdx
  xchg   %rdx,0x28(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rax,%rdx
  xchg   %rdx,0x38(%rsp)
  mov    %rdx,0x38(%rsp)
  mov    %rax,%rdx
  xchg   %rdx,0x48(%rsp)
  mov    %rdx,0x48(%rsp)
  xchg   %rax,0x58(%rsp)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x78,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_lock(void) {
  signed char sc[2];
  unsigned char uc[2];
  signed short ss[2];
  unsigned short us[2];
  signed int si[2];
  unsigned int ui[2];
  signed long sl[2];
  unsigned long ul[2];
  signed long long sll[2];
  unsigned long long ull[2];
  sc[1] = __sync_lock_test_and_set(&sc[1], -1);
  uc[1] = __sync_lock_test_and_set(&uc[1], -1);
  ss[1] = __sync_lock_test_and_set(&ss[1], -1);
  us[1] = __sync_lock_test_and_set(&us[1], -1);
  si[1] = __sync_lock_test_and_set(&si[1], -1);
  ui[1] = __sync_lock_test_and_set(&ui[1], -1);
  sl[1] = __sync_lock_test_and_set(&sl[1], -1);
  ul[1] = __sync_lock_test_and_set(&ul[1], -1);
  sll[1] = __sync_lock_test_and_set(&sll[1], -1);
  ull[1] = __sync_lock_test_and_set(&ull[1], -1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_lock>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %dl,0x65(%rsp)
  mov    %dl,0x65(%rsp)
  xchg   %al,0x67(%rsp)
  mov    %al,0x67(%rsp)
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %dx,0xa(%rsp)
  mov    %dx,0xa(%rsp)
  xchg   %ax,0xe(%rsp)
  mov    %ax,0xe(%rsp)
  mov    $0xffffffff,%eax
  mov    %eax,%edx
  xchg   %edx,0x14(%rsp)
  mov    %edx,0x14(%rsp)
  xchg   %eax,0x1c(%rsp)
  mov    %eax,0x1c(%rsp)
  mov    $0xffffffffffffffff,%rax
  mov    %rax,%rdx
  xchg   %rdx,0x28(%rsp)
  mov    %rdx,0x28(%rsp)
  mov    %rax,%rdx
  xchg   %rdx,0x38(%rsp)
  mov    %rdx,0x38(%rsp)
  mov    %rax,%rdx
  xchg   %rdx,0x48(%rsp)
  mov    %rdx,0x48(%rsp)
  xchg   %rax,0x58(%rsp)
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x78,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test_lock(void) {
  signed char sc[2];
  unsigned char uc[2];
  signed short ss[2];
  unsigned short us[2];
  signed int si[2];
  unsigned int ui[2];
  signed long sl[2];
  unsigned long ul[2];
  signed long long sll[2];
  unsigned long long ull[2];
  sc[1] = __sync_lock_test_and_set(&sc[1], -1);
  uc[1] = __sync_lock_test_and_set(&uc[1], -1);
  ss[1] = __sync_lock_test_and_set(&ss[1], -1);
  us[1] = __sync_lock_test_and_set(&us[1], -1);
  si[1] = __sync_lock_test_and_set(&si[1], -1);
  ui[1] = __sync_lock_test_and_set(&ui[1], -1);
  sl[1] = __sync_lock_test_and_set(&sl[1], -1);
  ul[1] = __sync_lock_test_and_set(&ul[1], -1);
  sll[1] = __sync_lock_test_and_set(&sll[1], -1);
  ull[1] = __sync_lock_test_and_set(&ull[1], -1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mul(double *row, double a, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    row[i] *= a;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mul>:
  endbr64
  test   %esi,%esi
  jle    L0
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L2:
  movapd %xmm0,%xmm1
  mulsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L2
L0:
  ret
```

assistant: ```c
void mul(double *row, double a, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    row[i] *= a;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mul>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L14:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L14
L1:
  ret
```

assistant: ```c
void mul(double *row, double a, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    row[i] *= a;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mul>:
  endbr64
  test   %esi,%esi
  jle    L43
  cmp    $0x1,%esi
  je     L42
  mov    %esi,%edx
  movapd %xmm0,%xmm2
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L5:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L5
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L39
L48:
  cltq
  lea    (%rdi,%rax,8),%rax
  mulsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L43:
  ret
  xchg   %ax,%ax
L39:
  ret
L42:
  xor    %eax,%eax
  jmp    L48
```

assistant: ```c
void mul(double *row, double a, int n) {
  int i;
  for (i = 0; i < n; ++i) {
    row[i] *= a;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Ackerman>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L6
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  jmp    L17
L6:
  cmpl   $0x0,-0x8(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <Ackerman>
  jmp    L17
L16:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Ackerman>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <Ackerman>
L17:
  leave
  ret
```

assistant: ```c
int Ackerman(int m, int n) {
  if (m == 0)
    return n + 1;
  else if (n == 0)
    return Ackerman(m - 1, 1);
  else
    return Ackerman(m - 1, Ackerman(m, n - 1));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Ackerman>:
  endbr64
  test   %edi,%edi
  je     L9
  push   %rbx
  mov    %edi,%ebx
  test   %esi,%esi
  jne    L4
  lea    -0x1(%rdi),%edi
  mov    $0x1,%esi
  call   <Ackerman>
L13:
  pop    %rbx
  ret
L9:
  lea    0x1(%rsi),%eax
  ret
L4:
  sub    $0x1,%esi
  call   <Ackerman>
  mov    %eax,%esi
  lea    -0x1(%rbx),%edi
  call   <Ackerman>
  jmp    L13
```

assistant: ```c
int Ackerman(int m, int n) {
  if (m == 0)
    return n + 1;
  else if (n == 0)
    return Ackerman(m - 1, 1);
  else
    return Ackerman(m - 1, Ackerman(m, n - 1));
}
```