ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Hungary2DownLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L1
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    (%rax,%rax,1),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  test   %r12d,%r12d
  jle    L29
  mov    %rbp,%rdx
  lea    -0x1(%r12),%eax
  lea    0x1(%rbp,%rax,1),%rdi
  mov    $0x0,%eax
  jmp    L57
L1:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rbx
  jmp    L20
L55:
  movslq %eax,%rsi
  mov    %cl,(%rbx,%rsi,1)
  add    $0x1,%eax
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  je     L15
L57:
  movzbl (%rdx),%ecx
  lea    -0x41(%rcx),%esi
  cmp    $0x19,%sil
  ja     L55
  movslq %eax,%rsi
  movb   $0x5f,(%rbx,%rsi,1)
  add    $0x1,%eax
  add    $0x20,%ecx
  jmp    L55
L29:
  mov    $0x0,%eax
L15:
  cltq
  movb   $0x0,(%rbx,%rax,1)
L20:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_guessed: string

tool: D8: src == NULL


assistant: ```c
char *Hungary2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c += 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Hungary2DownLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L59
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    (%rax,%rax,1),%r13d
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L54
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L23:
  movzbl (%rdi),%edx
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L28
  movslq %eax,%rcx
  add    $0x20,%edx
  add    $0x1,%eax
  movb   $0x5f,(%r12,%rcx,1)
L28:
  movslq %eax,%rcx
  add    $0x1,%rdi
  add    $0x1,%eax
  mov    %dl,(%r12,%rcx,1)
  cmp    %rdi,%rsi
  jne    L23
  cltq
  add    %r12,%rax
L4:
  movb   $0x0,(%rax)
L36:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L54:
  mov    %r12,%rax
  jmp    L4
L59:
  lea    D7(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L36
```

tool_calls: name: disassemble_data
arguments: tag: D7
data_type: string

tool: D7: src == NULL


assistant: ```c
char *Hungary2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c += 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Hungary2DownLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L70
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    (%rax,%rax,1),%r13d
  mov    %eax,%ebp
  mov    %r13d,%edi
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <memset@plt>
  test   %ebp,%ebp
  jle    L12
  lea    -0x1(%rbp),%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rsi
  xor    %eax,%eax
  xchg   %ax,%ax
L5:
  movzbl (%rdi),%edx
  lea    -0x41(%rdx),%ecx
  cmp    $0x19,%cl
  movslq %eax,%rcx
  ja     L13
  movb   $0x5f,(%r12,%rcx,1)
  lea    0x1(%rax),%ecx
  add    $0x20,%edx
  add    $0x1,%rdi
  movslq %ecx,%rcx
  add    $0x2,%eax
  mov    %dl,(%r12,%rcx,1)
  cmp    %rsi,%rdi
  jne    L5
L58:
  cltq
  add    %r12,%rax
L45:
  movb   $0x0,(%rax)
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%rdi
  mov    %dl,(%r12,%rcx,1)
  add    $0x1,%eax
  cmp    %rdi,%rsi
  jne    L5
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rax
  jmp    L45
L70:
  lea    D8(%rip),%rdi
  xor    %r12d,%r12d
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: src == NULL


assistant: ```c
char *Hungary2DownLine(const char *src) {
  if (src == NULL) {
    printf("src == NULL\n");
    return NULL;
  }
  int index = 0;
  int length = strlen(src);
  char *dst = (char *)malloc(length * 2);
  memset(dst, 0, length * 2);
  for (int i = 0; i < length; i++) {
    char c = src[i];
    if (c >= 'A' && c <= 'Z') {
      dst[index] = '_';
      index++;
      c += 32;
    }
    dst[index] = c;
    index++;
  }
  dst[index] = '\0';
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmemdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *xmemdup(const void *p_, size_t size) {
  void *p = xmalloc(size);
  memcpy(p, p_, size);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xmemdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <xmalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *xmemdup(const void *p_, size_t size) {
  void *p = xmalloc(size);
  memcpy(p, p_, size);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xmemdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <xmalloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xmemdup(const void *p_, size_t size) {
  void *p = xmalloc(size);
  memcpy(p, p_, size);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xmemdup>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <xmalloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *xmemdup(const void *p_, size_t size) {
  void *p = xmalloc(size);
  memcpy(p, p_, size);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hdate_days_from_3744>:
  endbr64
  sub    $0xea0,%edi
  lea    0x0(,%rdi,8),%eax
  sub    %edi,%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  imul   $0x6bca1af3,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,%ecx
  lea    (%rdx,%rdx,8),%esi
  lea    (%rdx,%rsi,2),%esi
  sub    %esi,%eax
  mov    %eax,%edx
  lea    (%rdi,%rdi,2),%eax
  lea    (%rcx,%rax,4),%eax
  imul   $0x9af9,%eax,%ecx
  add    $0x2093,%ecx
  imul   $0x1c,%eax,%eax
  movslq %ecx,%rsi
  imul   $0x50e89cc3,%rsi,%rdi
  sar    $0x2d,%rdi
  mov    %ecx,%r9d
  sar    $0x1f,%r9d
  sub    %r9d,%edi
  add    %edi,%eax
  imul   $0x6540,%edi,%edi
  mov    %ecx,%r8d
  sub    %edi,%r8d
  imul   $0x2e3bc74b,%rsi,%rsi
  sar    $0x2f,%rsi
  sub    %r9d,%esi
  imul   $0x2c4c0,%esi,%esi
  sub    %esi,%ecx
  movslq %ecx,%rsi
  imul   $0x50e89cc3,%rsi,%rsi
  sar    $0x2d,%rsi
  sar    $0x1f,%ecx
  sub    %ecx,%esi
  cmp    $0xb,%edx
  setle  %dil
  cmp    $0x4013,%r8d
  setg   %cl
  test   %cl,%dil
  je     L29
  cmp    $0x3,%esi
  je     L14
L29:
  cmp    $0x6,%edx
  setle  %cl
  cmp    $0x5ae4,%r8d
  setg   %dl
  test   %dl,%cl
  je     L38
  cmp    $0x2,%esi
  je     L14
L38:
  sub    $0x2,%eax
L1:
  lea    0x6(%rsi),%ecx
  mov    $0x1480,%edx
  shr    %cl,%rdx
  and    $0x1,%edx
  add    %edx,%eax
  ret
L14:
  sub    $0x1,%eax
  add    $0x1,%esi
  jmp    L1
```

assistant: ```c
int hdate_days_from_3744(int hebrew_year) {
  int years_from_3744;
  int molad_3744;
  int leap_months;
  int leap_left;
  int months;
  int parts;
  int days;
  int parts_left_in_week;
  int parts_left_in_day;
  int week_day;
  years_from_3744 = hebrew_year - 3744;
  molad_3744 = ((1 + 6) * 1080 + 779);
  leap_months = (years_from_3744 * 7 + 1) / 19;
  leap_left = (years_from_3744 * 7 + 1) % 19;
  months = years_from_3744 * 12 + leap_months;
  parts = months * ((24 * 1080) + ((12) * 1080 + 793)) + molad_3744;
  days = months * 28 + parts / (24 * 1080) - 2;
  parts_left_in_week = parts % (7 * (24 * 1080));
  parts_left_in_day = parts % (24 * 1080);
  week_day = parts_left_in_week / (24 * 1080);
  if ((leap_left < 12 && week_day == 3 && parts_left_in_day >= ((9 + 6) * 1080 + 204)) || (leap_left < 7 && week_day == 2 && parts_left_in_day >= ((15 + 6) * 1080 + 589))) {
    days++, week_day++;
  }
  if (week_day == 1 || week_day == 4 || week_day == 6) {
    days++;
  }
  return days;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hdate_days_from_3744>:
  endbr64
  sub    $0xea0,%edi
  lea    0x0(,%rdi,8),%eax
  sub    %edi,%eax
  add    $0x1,%eax
  movslq %eax,%rsi
  cltd
  imul   $0x6bca1af3,%rsi,%rsi
  sar    $0x23,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,8),%ecx
  mov    %esi,%edx
  lea    (%rsi,%rcx,2),%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rdi,%rdi,2),%eax
  lea    (%rdx,%rax,4),%edi
  imul   $0x9af9,%edi,%eax
  imul   $0x1c,%edi,%edi
  add    $0x2093,%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  mov    %eax,%r9d
  imul   $0x50e89cc3,%rdx,%rcx
  sar    $0x1f,%r10d
  imul   $0x2e3bc74b,%rdx,%rdx
  sar    $0x2d,%rcx
  sar    $0x2f,%rdx
  sub    %r10d,%ecx
  sub    %r10d,%edx
  add    %ecx,%edi
  imul   $0x2c4c0,%edx,%edx
  lea    -0x2(%rdi),%r8d
  imul   $0x6540,%ecx,%ecx
  sub    %edx,%eax
  sub    %ecx,%r9d
  movslq %eax,%rcx
  sar    $0x1f,%eax
  imul   $0x50e89cc3,%rcx,%rcx
  sar    $0x2d,%rcx
  sub    %eax,%ecx
  cmp    $0xb,%esi
  jg     L7
  cmp    $0x3,%ecx
  jne    L7
  cmp    $0x4013,%r9d
  jle    L21
  lea    -0x1(%rdi),%r8d
  add    $0x1,%ecx
L10:
  add    $0x6,%ecx
  mov    $0x1480,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  add    %eax,%r8d
L21:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L7:
  cmp    $0x6,%esi
  jg     L10
  cmp    $0x2,%ecx
  jne    L10
  cmp    $0x5ae4,%r9d
  jle    L21
  lea    -0x1(%rdi),%r8d
  add    $0x1,%ecx
  jmp    L10
```

assistant: ```c
int hdate_days_from_3744(int hebrew_year) {
  int years_from_3744;
  int molad_3744;
  int leap_months;
  int leap_left;
  int months;
  int parts;
  int days;
  int parts_left_in_week;
  int parts_left_in_day;
  int week_day;
  years_from_3744 = hebrew_year - 3744;
  molad_3744 = ((1 + 6) * 1080 + 779);
  leap_months = (years_from_3744 * 7 + 1) / 19;
  leap_left = (years_from_3744 * 7 + 1) % 19;
  months = years_from_3744 * 12 + leap_months;
  parts = months * ((24 * 1080) + ((12) * 1080 + 793)) + molad_3744;
  days = months * 28 + parts / (24 * 1080) - 2;
  parts_left_in_week = parts % (7 * (24 * 1080));
  parts_left_in_day = parts % (24 * 1080);
  week_day = parts_left_in_week / (24 * 1080);
  if ((leap_left < 12 && week_day == 3 && parts_left_in_day >= ((9 + 6) * 1080 + 204)) || (leap_left < 7 && week_day == 2 && parts_left_in_day >= ((15 + 6) * 1080 + 589))) {
    days++, week_day++;
  }
  if (week_day == 1 || week_day == 4 || week_day == 6) {
    days++;
  }
  return days;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hdate_days_from_3744>:
  endbr64
  sub    $0xea0,%edi
  lea    0x0(,%rdi,8),%eax
  sub    %edi,%eax
  add    $0x1,%eax
  movslq %eax,%rsi
  cltd
  imul   $0x6bca1af3,%rsi,%rsi
  sar    $0x23,%rsi
  sub    %edx,%esi
  lea    (%rsi,%rsi,8),%ecx
  mov    %esi,%edx
  lea    (%rsi,%rcx,2),%ecx
  sub    %ecx,%eax
  mov    %eax,%esi
  lea    (%rdi,%rdi,2),%eax
  lea    (%rdx,%rax,4),%edi
  imul   $0x9af9,%edi,%eax
  imul   $0x1c,%edi,%edi
  add    $0x2093,%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  mov    %eax,%r9d
  imul   $0x50e89cc3,%rdx,%rcx
  sar    $0x1f,%r10d
  imul   $0x2e3bc74b,%rdx,%rdx
  sar    $0x2d,%rcx
  sar    $0x2f,%rdx
  sub    %r10d,%ecx
  sub    %r10d,%edx
  add    %ecx,%edi
  imul   $0x2c4c0,%edx,%edx
  lea    -0x2(%rdi),%r8d
  imul   $0x6540,%ecx,%ecx
  sub    %edx,%eax
  sub    %ecx,%r9d
  movslq %eax,%rcx
  sar    $0x1f,%eax
  imul   $0x50e89cc3,%rcx,%rcx
  sar    $0x2d,%rcx
  sub    %eax,%ecx
  cmp    $0xb,%esi
  jg     L14
  cmp    $0x3,%ecx
  jne    L14
  cmp    $0x4013,%r9d
  jle    L59
  lea    -0x1(%rdi),%r8d
  add    $0x1,%ecx
L64:
  add    $0x6,%ecx
  mov    $0x1480,%eax
  shr    %cl,%rax
  and    $0x1,%eax
  add    %eax,%r8d
L59:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L14:
  cmp    $0x6,%esi
  jg     L64
  cmp    $0x2,%ecx
  jne    L64
  cmp    $0x5ae4,%r9d
  jle    L59
  lea    -0x1(%rdi),%r8d
  add    $0x1,%ecx
  jmp    L64
```

assistant: ```c
int hdate_days_from_3744(int hebrew_year) {
  int years_from_3744;
  int molad_3744;
  int leap_months;
  int leap_left;
  int months;
  int parts;
  int days;
  int parts_left_in_week;
  int parts_left_in_day;
  int week_day;
  years_from_3744 = hebrew_year - 3744;
  molad_3744 = ((1 + 6) * 1080 + 779);
  leap_months = (years_from_3744 * 7 + 1) / 19;
  leap_left = (years_from_3744 * 7 + 1) % 19;
  months = years_from_3744 * 12 + leap_months;
  parts = months * ((24 * 1080) + ((12) * 1080 + 793)) + molad_3744;
  days = months * 28 + parts / (24 * 1080) - 2;
  parts_left_in_week = parts % (7 * (24 * 1080));
  parts_left_in_day = parts % (24 * 1080);
  week_day = parts_left_in_week / (24 * 1080);
  if ((leap_left < 12 && week_day == 3 && parts_left_in_day >= ((9 + 6) * 1080 + 204)) || (leap_left < 7 && week_day == 2 && parts_left_in_day >= ((15 + 6) * 1080 + 589))) {
    days++, week_day++;
  }
  if (week_day == 1 || week_day == 4 || week_day == 6) {
    days++;
  }
  return days;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zapolnenie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L11:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0x64,%edx,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,(%rcx)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void zapolnenie(int *ar, int size) {
  srand(time(NULL));
  int i;
  for (i = 0; i < size; i++)
    *(ar + i) = rand() % 100;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zapolnenie>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebp,%ebp
  jle    L17
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x4(%r12,%rax,4),%rbp
L6:
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L6
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void zapolnenie(int *ar, int size) {
  srand(time(NULL));
  int i;
  for (i = 0; i < size; i++)
    *(ar + i) = rand() % 100;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zapolnenie>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L17
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%rbx
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L4
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void zapolnenie(int *ar, int size) {
  srand(time(NULL));
  int i;
  for (i = 0; i < size; i++)
    *(ar + i) = rand() % 100;
}
```
user: What is the c source code of the assembly code below?

```asm
<zapolnenie>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  test   %ebx,%ebx
  jle    L19
  lea    -0x1(%rbx),%eax
  lea    0x4(%rbp,%rax,4),%rbx
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmp    %rbx,%rbp
  jne    L18
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void zapolnenie(int *ar, int size) {
  srand(time(NULL));
  int i;
  for (i = 0; i < size; i++)
    *(ar + i) = rand() % 100;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L1:
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L10:
  cmpl   $0x15bd,-0x4(%rbp)
  jle    L1
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bar() {
  int result = 0;
  for (int i = 0; i < 5566; ++i) {
    result += 1;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bar>:
  endbr64
  mov    $0x15be,%eax
L7:
  sub    $0x1,%eax
  jne    L7
  mov    $0x15be,%eax
  ret
```

assistant: ```c
int bar() {
  int result = 0;
  for (int i = 0; i < 5566; ++i) {
    result += 1;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bar>:
  endbr64
  mov    $0x15be,%eax
  ret
```

assistant: ```c
int bar() {
  int result = 0;
  for (int i = 0; i < 5566; ++i) {
    result += 1;
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bar>:
  endbr64
  mov    $0x15be,%eax
  ret
```

assistant: ```c
int bar() {
  int result = 0;
  for (int i = 0; i < 5566; ++i) {
    result += 1;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<erase_sector_stm50>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x1000,-0x10(%rbp)
  jne    L3
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <stm50_erase_sector@plt>
  jmp    L15
L3:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <erase_block_82802ab@plt>
L15:
  leave
  ret
```

assistant: ```c
int erase_sector_stm50(struct flashctx *flash, unsigned int addr, unsigned int len) {
  if (len == 4096)
    return stm50_erase_sector(flash, addr);
  else
    return erase_block_82802ab(flash, addr, len);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<erase_sector_stm50>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1000,%edx
  je     L17
  call   <erase_block_82802ab@plt>
L0:
  add    $0x8,%rsp
  ret
L17:
  call   <stm50_erase_sector@plt>
  jmp    L0
```

assistant: ```c
int erase_sector_stm50(struct flashctx *flash, unsigned int addr, unsigned int len) {
  if (len == 4096)
    return stm50_erase_sector(flash, addr);
  else
    return erase_block_82802ab(flash, addr, len);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<erase_sector_stm50>:
  endbr64
  cmp    $0x1000,%edx
  je     L3
  jmp    1060 <erase_block_82802ab@plt>
  nopl   0x0(%rax)
L3:
  jmp    1070 <stm50_erase_sector@plt>
```

assistant: ```c
int erase_sector_stm50(struct flashctx *flash, unsigned int addr, unsigned int len) {
  if (len == 4096)
    return stm50_erase_sector(flash, addr);
  else
    return erase_block_82802ab(flash, addr, len);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<erase_sector_stm50>:
  endbr64
  cmp    $0x1000,%edx
  je     L8
  jmp    1060 <erase_block_82802ab@plt>
  nopl   0x0(%rax)
L8:
  jmp    1070 <stm50_erase_sector@plt>
```

assistant: ```c
int erase_sector_stm50(struct flashctx *flash, unsigned int addr, unsigned int len) {
  if (len == 4096)
    return stm50_erase_sector(flash, addr);
  else
    return erase_block_82802ab(flash, addr, len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__lets_play>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L21
L52:
  mov    -0x20(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L44
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rsi
  mov    %rdx,%rcx
  mov    %rcx,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  mov    %dl,-0x1a(%rbp,%rax,1)
  jmp    L35
L44:
  mov    -0x20(%rbp),%eax
  cltq
  movb   $0x0,-0x1a(%rbp,%rax,1)
L35:
  addl   $0x1,-0x20(%rbp)
L21:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbx
  jb     L52
  lea    -0x1a(%rbp),%rax
  test   %eax,%eax
  jns    L3
  mov    $0x0,%eax
  jmp    L33
L3:
  mov    $0x1,%eax
L33:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int __lets_play(char *param) {
  int i = 0;
  char buffer[2];
  for (i = 0; i < strlen(param); i++) {
    if (i % 2)
      buffer[i] = param[rand() % strlen(param)];
    else
      buffer[i] = '\0';
  }
  if ((int)buffer < 0)
    return 0;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__lets_play>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L25
L2:
  mov    %al,0x6(%rsp,%rbx,1)
  add    $0x1,%rbx
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %rbx,%rax
  jbe    L39
  mov    %r13d,%eax
  test   $0x1,%bl
  je     L2
  call   <rand@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rcx
  mov    %r12,%rax
  mov    $0x0,%edx
  div    %rcx
  movzbl 0x0(%rbp,%rdx,1),%eax
  jmp    L2
L39:
  lea    0x6(%rsp),%rax
  not    %eax
  shr    $0x1f,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __lets_play(char *param) {
  int i = 0;
  char buffer[2];
  for (i = 0; i < strlen(param); i++) {
    if (i % 2)
      buffer[i] = param[rand() % strlen(param)];
    else
      buffer[i] = '\0';
  }
  if ((int)buffer < 0)
    return 0;
  return 1;
}
```