user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  lea    D25(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    0x20(%rsp),%edx
  mov    %rax,%rbp
  sub    $0x1,%edx
  js     L10
  movslq %edx,%rax
  mov    %edx,%edx
  shl    $0x2,%rax
  shl    $0x2,%rdx
  lea    0x0(%rbp,%rax,1),%rbx
  sub    $0x4,%rax
  sub    %rdx,%rax
  lea    0x0(%rbp,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L191:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  sub    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r12,%rbx
  jne    L191
L10:
  lea    0x24(%rsp),%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%esi
  mov    $0x4,%edi
  call   <calloc@plt>
  mov    0x24(%rsp),%edx
  mov    %rax,%r12
  sub    $0x1,%edx
  js     L99
  movslq %edx,%rax
  mov    %edx,%edx
  shl    $0x2,%rax
  shl    $0x2,%rdx
  lea    (%r12,%rax,1),%rbx
  sub    $0x4,%rax
  sub    %rdx,%rax
  lea    (%r12,%rax,1),%r13
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  sub    $0x4,%rbx
  call   <scanf@plt>
  cmp    %r13,%rbx
  jne    L34
L99:
  mov    0x20(%rsp),%r13d
  test   %r13d,%r13d
  je     L50
  xor    %r13d,%r13d
  lea    D12(%rip),%rbx
  nopl   0x0(%rax)
L201:
  mov    0x24(%rsp),%eax
  test   %eax,%eax
  je     L166
  cmp    $0x1f5,%r13d
  je     L156
  add    $0x1,%r13d
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  mov    %r13d,%esi
  call   <printf@plt>
  movslq 0x20(%rsp),%rdx
  movslq 0x24(%rsp),%rax
  mov    %rdx,%rdi
  mov    %rax,%rsi
  shl    $0x2,%rdx
  shl    $0x2,%rax
  mov    -0x4(%rbp,%rdx,1),%r15d
  mov    -0x4(%r12,%rax,1),%ecx
  cmp    %ecx,%r15d
  jg     L120
  cmp    $0x1,%esi
  jle    L170
  sub    $0x2,%esi
  mov    %ecx,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0x4(,%rsi,4),%r8
  neg    %rdx
  shl    $0x2,%rdx
  lea    -0x8(%rax,%rdx,1),%rsi
  add    %rdx,%rax
  mov    %r8,%rdx
  add    %r12,%rsi
  lea    (%r12,%rax,1),%rdi
  call   <memmove@plt>
  mov    0xc(%rsp),%ecx
L170:
  mov    %ecx,(%r12)
  movslq 0x20(%rsp),%rdx
  mov    %rdx,%rax
  mov    -0x4(%rbp,%rdx,4),%edx
  addl   $0x1,0x24(%rsp)
  sub    $0x1,%eax
  mov    %edx,0x4(%r12)
  mov    %eax,0x20(%rsp)
L206:
  xor    %r15d,%r15d
  test   %eax,%eax
  jle    L83
  nopw   0x0(%rax,%rax,1)
L97:
  mov    0x0(%rbp,%r15,4),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15d,0x20(%rsp)
  jg     L97
L83:
  mov    $0xa,%edi
  xor    %r15d,%r15d
  call   <putchar@plt>
  mov    0x24(%rsp),%ecx
  test   %ecx,%ecx
  jle    L107
  nop
L200:
  mov    (%r12,%r15,4),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  call   <printf@plt>
  cmp    %r15d,0x24(%rsp)
  jg     L200
L107:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x20(%rsp),%edx
  test   %edx,%edx
  jne    L201
  cmp    $0x1f5,%r13d
  je     L156
L50:
  mov    $0x2,%edx
L167:
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L75:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L120:
  cmp    $0x1,%edi
  jle    L69
  lea    -0x2(%rdi),%ecx
  mov    %rcx,%rax
  lea    0x4(,%rcx,4),%r9
  neg    %rax
  shl    $0x2,%rax
  lea    -0x8(%rdx,%rax,1),%rsi
  add    %rax,%rdx
  lea    0x0(%rbp,%rdx,1),%rdi
  add    %rbp,%rsi
  mov    %r9,%rdx
  call   <memmove@plt>
L69:
  mov    %r15d,0x0(%rbp)
  movslq 0x24(%rsp),%rax
  mov    %rax,%rdx
  mov    -0x4(%r12,%rax,4),%eax
  sub    $0x1,%edx
  mov    %eax,0x4(%rbp)
  mov    0x20(%rsp),%eax
  mov    %edx,0x24(%rsp)
  add    $0x1,%eax
  mov    %eax,0x20(%rsp)
  jmp    L206
L166:
  cmp    $0x1f5,%r13d
  je     L156
  mov    $0x1,%edx
  jmp    L167
L156:
  or     $0xffffffff,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L75
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D25
datatype: string
name: disassemble_data
arguments: label: D12
datatype: string
name: disassemble_data
arguments: label: D36
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string

tool: D25: %d

tool: D12: %d 

tool: D36: turns: %d


tool: D1: 
%d %d

assistant: ```c
int main() {
  int n, k1, k2;
  int *k1_arr, *k2_arr;
  int i;
  int turns = 0;
  scanf("%d", &n);
  scanf("%d", &k1);
  k1_arr = calloc(sizeof(int), n);
  for (i = k1 - 1; i >= 0; i--) {
    scanf("%d", k1_arr + i);
  }
  scanf("%d", &k2);
  k2_arr = calloc(sizeof(int), n);
  for (i = k2 - 1; i >= 0; i--) {
    scanf("%d", k2_arr + i);
  }
  while (k1 != 0 && k2 != 0 && turns < 501) {
    turns++;
    printf("turns: %d\n", turns);
    if (*(k1_arr + k1 - 1) > *(k2_arr + k2 - 1)) {
      int tmp = *(k1_arr + k1 - 1);
      for (i = k1; i > 1; i--) {
        *(k1_arr + i) = *(k1_arr + i - 2);
      }
      *(k1_arr) = tmp;
      *(k1_arr + 1) = *(k2_arr + k2 - 1);
      k1++;
      k2--;
    } else {
      int tmp = *(k2_arr + k2 - 1);
      for (i = k2; i > 1; i--) {
        *(k2_arr + i) = *(k2_arr + i - 2);
      }
      *(k2_arr) = tmp;
      *(k2_arr + 1) = *(k1_arr + k1 - 1);
      k2++;
      k1--;
    }
    for (i = 0; i < k1; i++) {
      printf("%d ", *(k1_arr + i));
    }
    printf("\n");
    for (i = 0; i < k2; i++) {
      printf("%d ", *(k2_arr + i));
    }
    printf("\n");
  }
  if (turns > 500)
    printf("%d", -1);
  else
    printf("\n%d %d", turns, k1 == 0 ? 2 : 1);
  return 0;
}
```