ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L54
L3:
  cmpb   $0x20,-0x5(%rbp)
  jne    L12
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  jle    L54
  mov    $0x9,%edi
  call   <putchar@plt>
  subl   $0x4,-0x4(%rbp)
  jmp    L54
L5:
  mov    $0x20,%edi
  call   <putchar@plt>
  subl   $0x1,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  jg     L5
  movsbl -0x5(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L54:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L3
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  int bn;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      ++bn;
      if (bn >= 4) {
        putchar('\t');
        bn -= 4;
      }
    } else {
      for (; bn > 0; --bn)
        putchar(' ');
      putchar(c);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L56
L28:
  test   %ebx,%ebx
  jle    L42
L48:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L48
L42:
  movsbl %bpl,%edi
  call   <putchar@plt>
L56:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  mov    D6(%rip),%rax
  cmp    %bpl,(%rax)
  je     L0
  cmp    $0x20,%bpl
  jne    L28
  lea    0x1(%rbx),%eax
  cmp    $0x3,%eax
  jg     L25
  mov    %eax,%ebx
  jmp    L56
L25:
  mov    $0x9,%edi
  call   <putchar@plt>
  sub    $0x3,%ebx
  jmp    L56
L0:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  int bn;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      ++bn;
      if (bn >= 4) {
        putchar('\t');
        bn -= 4;
      }
    } else {
      for (; bn > 0; --bn)
        putchar(' ');
      putchar(c);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    D3(%rip),%r12
  push   %rbp
  push   %rbx
  nop
L2:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %al,(%r12)
  je     L51
L54:
  cmp    $0x20,%bpl
  jne    L13
  lea    0x1(%rbx),%eax
  cmp    $0x3,%eax
  jg     L47
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %al,(%r12)
  jne    L54
L51:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L13:
  test   %ebx,%ebx
  jle    L0
  nopl   0x0(%rax)
L10:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L10
L0:
  movsbl %bpl,%edi
  call   <putchar@plt>
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x9,%edi
  sub    $0x3,%ebx
  call   <putchar@plt>
  jmp    L2
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  int bn;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      ++bn;
      if (bn >= 4) {
        putchar('\t');
        bn -= 4;
      }
    } else {
      for (; bn > 0; --bn)
        putchar(' ');
      putchar(c);
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  mov    D4(%rip),%r12
  push   %rbp
  push   %rbx
  nop
L40:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %al,(%r12)
  je     L8
L6:
  cmp    $0x20,%bpl
  jne    L2
  lea    0x1(%rbx),%eax
  cmp    $0x3,%eax
  jg     L26
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    %al,(%r12)
  jne    L6
L8:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  test   %ebx,%ebx
  jle    L41
  nopl   0x0(%rax)
L53:
  mov    $0x20,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L53
L41:
  movsbl %bpl,%edi
  call   <putchar@plt>
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L26:
  mov    $0x9,%edi
  sub    $0x3,%ebx
  call   <putchar@plt>
  jmp    L40
```

assistant: ```c
int main(int argc, char *argv[]) {
  char c;
  int i;
  int bn;
  while ((c = getchar()) != EOF) {
    if (c == ' ') {
      ++bn;
      if (bn >= 4) {
        putchar('\t');
        bn -= 4;
      }
    } else {
      for (; bn > 0; --bn)
        putchar(' ');
      putchar(c);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MyFlush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
L3:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  setne  %al
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  je     L6
  mov    D6(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L3
L6:
  nop
  leave
  ret
```

assistant: ```c
void MyFlush() {
  char ch;
  while ((ch = getchar() != '\n') && ch != EOF)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MyFlush>:
  endbr64
  sub    $0x8,%rsp
L4:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L10
  mov    D2(%rip),%rax
  cmpb   $0x1,(%rax)
  jne    L4
L10:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MyFlush() {
  char ch;
  while ((ch = getchar() != '\n') && ch != EOF)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MyFlush>:
  endbr64
  sub    $0x8,%rsp
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L16:
  mov    D0(%rip),%rax
  cmpb   $0x1,(%rax)
  je     L29
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L16
L29:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MyFlush() {
  char ch;
  while ((ch = getchar() != '\n') && ch != EOF)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MyFlush>:
  endbr64
  sub    $0x8,%rsp
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L20:
  mov    D1(%rip),%rax
  cmpb   $0x1,(%rax)
  je     L25
L17:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L20
L25:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void MyFlush() {
  char ch;
  while ((ch = getchar() != '\n') && ch != EOF)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmpci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L44
L92:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xa(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x60,-0xa(%rbp)
  jle    L71
  cmpb   $0x7a,-0xa(%rbp)
  jg     L71
  movzbl -0xa(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0xa(%rbp)
L71:
  cmpb   $0x60,-0x9(%rbp)
  jle    L85
  cmpb   $0x7a,-0x9(%rbp)
  jg     L85
  movzbl -0x9(%rbp),%eax
  sub    $0x20,%eax
  mov    %al,-0x9(%rbp)
L85:
  movzbl -0xa(%rbp),%eax
  cmp    -0x9(%rbp),%al
  je     L23
  movl   $0x0,-0x4(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L41
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jb     L92
L41:
  mov    -0x24(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  je     L34
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L93
L34:
  movl   $0x0,-0x4(%rbp)
L93:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strcmpci(char *str1, char *str2, int m) {
  unsigned int i;
  char c1, c2;
  int r;
  r = 1;
  for (i = 0; str1[i] != 0 && i < m; i++) {
    c1 = str1[i];
    c2 = str2[i];
    if (c1 > 96 && c1 < 123)
      c1 = c1 - 32;
    if (c2 > 96 && c2 < 123)
      c2 = c2 - 32;
    if (c1 != c2)
      r = 0;
  }
  if ((i == m) || (str2[i] != 0))
    r = 0;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcmpci>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %edx,%ebx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L17
  mov    %rdi,%r9
  test   %edx,%edx
  je     L84
  lea    -0x1(%rdx),%r11d
  add    $0x2,%r11
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    $0x0,%ebp
  jmp    L39
L49:
  mov    %rdx,%rcx
L39:
  movzbl -0x1(%r10,%rcx,1),%edx
  lea    -0x61(%rax),%r8d
  lea    -0x20(%rax),%edi
  cmp    $0x1a,%r8b
  cmovb  %edi,%eax
  lea    -0x61(%rdx),%r8d
  lea    -0x20(%rdx),%edi
  cmp    $0x1a,%r8b
  cmovb  %edi,%edx
  cmp    %dl,%al
  cmovne %ebp,%esi
  mov    %ecx,%edi
  movzbl (%r9,%rcx,1),%eax
  test   %al,%al
  je     L26
  lea    0x1(%rcx),%rdx
  cmp    %r11,%rdx
  jne    L49
L26:
  cmp    %edi,%ebx
  je     L53
  cmpb   $0x0,(%r10,%rcx,1)
  mov    $0x0,%eax
  cmovne %eax,%esi
L76:
  mov    %esi,%eax
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x1,%esi
  mov    $0x0,%edi
  mov    $0x0,%ecx
  jmp    L26
L84:
  mov    $0x0,%esi
  jmp    L76
L53:
  mov    $0x0,%esi
  jmp    L76
```

assistant: ```c
int strcmpci(char *str1, char *str2, int m) {
  unsigned int i;
  char c1, c2;
  int r;
  r = 1;
  for (i = 0; str1[i] != 0 && i < m; i++) {
    c1 = str1[i];
    c2 = str2[i];
    if (c1 > 96 && c1 < 123)
      c1 = c1 - 32;
    if (c2 > 96 && c2 < 123)
      c2 = c2 - 32;
    if (c1 != c2)
      r = 0;
  }
  if ((i == m) || (str2[i] != 0))
    r = 0;
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcmpci>:
  endbr64
  push   %rbp
  mov    %rsi,%r10
  push   %rbx
  movzbl (%rdi),%eax
  mov    %edx,%ebx
  test   %al,%al
  je     L47
  test   %edx,%edx
  je     L22
  lea    -0x1(%rdx),%r11d
  mov    %rdi,%r9
  mov    $0x1,%ecx
  xor    %ebp,%ebp
  add    $0x2,%r11
  mov    $0x1,%r8d
  jmp    L7
L57:
  lea    0x1(%rcx),%rdx
  cmp    %r11,%rdx
  je     L35
  mov    %rdx,%rcx
L7:
  movzbl -0x1(%r10,%rcx,1),%edx
  lea    -0x61(%rax),%edi
  lea    -0x20(%rax),%esi
  cmp    $0x1a,%dil
  lea    -0x61(%rdx),%edi
  cmovb  %esi,%eax
  lea    -0x20(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  mov    %ecx,%esi
  cmp    %dl,%al
  movzbl (%r9,%rcx,1),%eax
  cmovne %ebp,%r8d
  test   %al,%al
  jne    L57
L35:
  cmp    %ebx,%esi
  je     L22
  xor    %eax,%eax
  cmpb   $0x0,(%r10,%rcx,1)
  pop    %rbx
  cmovne %eax,%r8d
  pop    %rbp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
L47:
  mov    $0x1,%r8d
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L35
```

assistant: ```c
int strcmpci(char *str1, char *str2, int m) {
  unsigned int i;
  char c1, c2;
  int r;
  r = 1;
  for (i = 0; str1[i] != 0 && i < m; i++) {
    c1 = str1[i];
    c2 = str2[i];
    if (c1 > 96 && c1 < 123)
      c1 = c1 - 32;
    if (c2 > 96 && c2 < 123)
      c2 = c2 - 32;
    if (c1 != c2)
      r = 0;
  }
  if ((i == m) || (str2[i] != 0))
    r = 0;
  return r;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strcmpci>:
  endbr64
  push   %rbp
  mov    %rsi,%r10
  push   %rbx
  movzbl (%rdi),%eax
  mov    %edx,%ebx
  test   %al,%al
  je     L30
  test   %edx,%edx
  je     L19
  lea    -0x1(%rdx),%r11d
  mov    %rdi,%r9
  mov    $0x1,%ecx
  xor    %ebp,%ebp
  add    $0x2,%r11
  mov    $0x1,%r8d
  jmp    L39
L34:
  lea    0x1(%rcx),%rdx
  cmp    %r11,%rdx
  je     L8
  mov    %rdx,%rcx
L39:
  movzbl -0x1(%r10,%rcx,1),%edx
  lea    -0x61(%rax),%edi
  lea    -0x20(%rax),%esi
  cmp    $0x1a,%dil
  lea    -0x61(%rdx),%edi
  cmovb  %esi,%eax
  lea    -0x20(%rdx),%esi
  cmp    $0x1a,%dil
  cmovb  %esi,%edx
  mov    %ecx,%esi
  cmp    %dl,%al
  movzbl (%r9,%rcx,1),%eax
  cmovne %ebp,%r8d
  test   %al,%al
  jne    L34
L8:
  cmp    %ebx,%esi
  je     L19
  xor    %eax,%eax
  cmpb   $0x0,(%r10,%rcx,1)
  pop    %rbx
  cmovne %eax,%r8d
  pop    %rbp
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8d,%eax
  ret
L30:
  mov    $0x1,%r8d
  xor    %esi,%esi
  xor    %ecx,%ecx
  jmp    L8
```

assistant: ```c
int strcmpci(char *str1, char *str2, int m) {
  unsigned int i;
  char c1, c2;
  int r;
  r = 1;
  for (i = 0; str1[i] != 0 && i < m; i++) {
    c1 = str1[i];
    c2 = str2[i];
    if (c1 > 96 && c1 < 123)
      c1 = c1 - 32;
    if (c2 > 96 && c2 < 123)
      c2 = c2 - 32;
    if (c1 != c2)
      r = 0;
  }
  if ((i == m) || (str2[i] != 0))
    r = 0;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BiSearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L51:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L58
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L58:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L7
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L8
L7:
  mov    -0x4(%rbp),%eax
  jmp    L3
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L51
  mov    -0xc(%rbp),%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
int BiSearch(int *b, int max, int w) {
  int left = 0;
  int right = max - 1;
  int mid;
  while (left <= right) {
    mid = left + (right - left) / 2;
    if (b[mid] > w)
      right = mid - 1;
    else if (b[mid] < w)
      left = mid + 1;
    else
      return mid;
  }
  return left;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BiSearch>:
  endbr64
  sub    $0x1,%esi
  js     L12
  mov    $0x0,%ecx
  jmp    L41
L68:
  jge    L17
  lea    0x1(%rax),%ecx
L1:
  cmp    %esi,%ecx
  jg     L28
L41:
  mov    %esi,%r8d
  sub    %ecx,%r8d
  mov    %r8d,%eax
  shr    $0x1f,%eax
  add    %r8d,%eax
  sar    %eax
  add    %ecx,%eax
  movslq %eax,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %edx,%r8d
  jle    L68
  lea    -0x1(%rax),%esi
  jmp    L1
L12:
  mov    $0x0,%ecx
  jmp    L28
L17:
  mov    %eax,%ecx
L28:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int BiSearch(int *b, int max, int w) {
  int left = 0;
  int right = max - 1;
  int mid;
  while (left <= right) {
    mid = left + (right - left) / 2;
    if (b[mid] > w)
      right = mid - 1;
    else if (b[mid] < w)
      left = mid + 1;
    else
      return mid;
  }
  return left;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BiSearch>:
  endbr64
  xor    %r8d,%r8d
  sub    $0x1,%esi
  jns    L7
  jmp    L12
  xchg   %ax,%ax
L53:
  lea    -0x1(%rax),%esi
  cmp    %r8d,%esi
  jl     L12
L7:
  mov    %esi,%eax
  sub    %r8d,%eax
  sar    %eax
  add    %r8d,%eax
  movslq %eax,%rcx
  cmp    %edx,(%rdi,%rcx,4)
  jg     L53
  jge    L3
  lea    0x1(%rax),%r8d
  cmp    %r8d,%esi
  jge    L7
L12:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L3:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int BiSearch(int *b, int max, int w) {
  int left = 0;
  int right = max - 1;
  int mid;
  while (left <= right) {
    mid = left + (right - left) / 2;
    if (b[mid] > w)
      right = mid - 1;
    else if (b[mid] < w)
      left = mid + 1;
    else
      return mid;
  }
  return left;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BiSearch>:
  endbr64
  xor    %r8d,%r8d
  sub    $0x1,%esi
  jns    L2
  jmp    L6
  xchg   %ax,%ax
L48:
  lea    -0x1(%rax),%esi
  cmp    %r8d,%esi
  jl     L6
L2:
  mov    %esi,%eax
  sub    %r8d,%eax
  sar    %eax
  add    %r8d,%eax
  movslq %eax,%rcx
  cmp    %edx,(%rdi,%rcx,4)
  jg     L48
  jge    L26
  lea    0x1(%rax),%r8d
  cmp    %r8d,%esi
  jge    L2
L6:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L26:
  mov    %eax,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int BiSearch(int *b, int max, int w) {
  int left = 0;
  int right = max - 1;
  int mid;
  while (left <= right) {
    mid = left + (right - left) / 2;
    if (b[mid] > w)
      right = mid - 1;
    else if (b[mid] < w)
      left = mid + 1;
    else
      return mid;
  }
  return left;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: hola!


assistant: ```c
int main(void) {
  printf("hola!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string

tool: D7: hola!


assistant: ```c
int main(void) {
  printf("hola!\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type_infered: string

tool: D1: hola!


assistant: ```c
int main(void) {
  printf("hola!\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: hola!


assistant: ```c
int main(void) {
  printf("hola!\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<read_small_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  js     L81
  mov    -0x10(%rbp),%edx
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  and    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L34
L81:
  mov    $0x0,%eax
  jmp    L27
L34:
  movl   $0xffffffff,-0x1c(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L17
  mov    D10(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  js     L17
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    -0xc(%rbp),%edx
  cmp    %edx,%eax
  je     L12
L17:
  cmpq   $0x0,-0x18(%rbp)
  je     L49
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L49:
  cmpl   $0x0,-0x1c(%rbp)
  js     L77
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L77:
  mov    $0x0,%eax
  jmp    L27
L12:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L27:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

assistant: ```c
char *read_small_file(char *filename) {
  int fd;
  char *buffer;
  struct stat sbuf;
  if (stat(filename, &sbuf) < 0 || (sbuf.st_mode & __S_IFMT) != __S_IFREG)
    return NULL;
  fd = -1;
  buffer = NULL;
  if ((buffer = (char *)malloc(sbuf.st_size + 1)) == NULL || (fd = open(filename, O_RDONLY)) < 0 || read(fd, buffer, sbuf.st_size) != sbuf.st_size) {
    if (buffer != NULL)
      free(buffer);
    if (fd >= 0)
      close(fd);
    return NULL;
  }
  close(fd);
  buffer[sbuf.st_size] = '\0';
  return buffer;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_small_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L10
  mov    D11(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  mov    $0x0,%ebp
  mov    D8(%rip),%rdx
  cmp    (%rdx),%eax
  jne    L13
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L13
  mov    %rax,%rbp
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L2
  mov    0x4(%rsp),%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    0x4(%rsp),%eax
  jne    L2
  mov    %ebx,%edi
  call   <close@plt>
  movslq 0x4(%rsp),%rax
  movb   $0x0,(%r12,%rax,1)
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L93
  mov    %rbp,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0x0,%ebp
  jmp    L13
L2:
  mov    %r12,%rdi
  call   <free@plt>
  test   %ebx,%ebx
  js     L40
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%ebp
  jmp    L13
L40:
  mov    $0x0,%ebp
  jmp    L13
L93:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_small_file(char *filename) {
  int fd;
  char *buffer;
  struct stat sbuf;
  if (stat(filename, &sbuf) < 0 || (sbuf.st_mode & __S_IFMT) != __S_IFREG)
    return NULL;
  fd = -1;
  buffer = NULL;
  if ((buffer = (char *)malloc(sbuf.st_size + 1)) == NULL || (fd = open(filename, O_RDONLY)) < 0 || read(fd, buffer, sbuf.st_size) != sbuf.st_size) {
    if (buffer != NULL)
      free(buffer);
    if (fd >= 0)
      close(fd);
    return NULL;
  }
  close(fd);
  buffer[sbuf.st_size] = '\0';
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_small_file>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L64
  mov    D6(%rip),%rdx
  mov    (%rsp),%eax
  and    (%rdx),%eax
  mov    D18(%rip),%rdx
  cmp    (%rdx),%eax
  jne    L64
  mov    0x4(%rsp),%eax
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L64
  mov    D20(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L57
  mov    0x4(%rsp),%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  call   <read@plt>
  cmp    0x4(%rsp),%eax
  jne    L59
  mov    %ebp,%edi
  call   <close@plt>
  movslq 0x4(%rsp),%rax
  movb   $0x0,(%r12,%rax,1)
  jmp    L3
  nopl   0x0(%rax)
L57:
  mov    %r12,%rdi
  call   <free@plt>
L64:
  xor    %r12d,%r12d
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L59:
  mov    %r12,%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L3
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *read_small_file(char *filename) {
  int fd;
  char *buffer;
  struct stat sbuf;
  if (stat(filename, &sbuf) < 0 || (sbuf.st_mode & __S_IFMT) != __S_IFREG)
    return NULL;
  fd = -1;
  buffer = NULL;
  if ((buffer = (char *)malloc(sbuf.st_size + 1)) == NULL || (fd = open(filename, O_RDONLY)) < 0 || read(fd, buffer, sbuf.st_size) != sbuf.st_size) {
    if (buffer != NULL)
      free(buffer);
    if (fd >= 0)
      close(fd);
    return NULL;
  }
  close(fd);
  buffer[sbuf.st_size] = '\0';
  return buffer;
}
```