ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strsplitz>:
  endbr64
  test   %rdi,%rdi
  je     L119
  push   %r15
  lea    D5(%rip),%rax
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  cmove  %rax,%rsi
  mov    %rsi,%rdi
  mov    %rsi,0x8(%rsp)
  call   <strlen@plt>
  mov    %r15,%rdi
  movslq %eax,%rbp
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  lea    (%rax,%rax,4),%rdi
  lea    0x0(,%rax,8),%rbx
  add    %rdi,%rdi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L107
  add    %rax,%rbx
  test   %rbp,%rbp
  je     L26
  mov    0x8(%rsp),%rsi
  lea    0x1(%rbx),%r12
  xor    %ecx,%ecx
  xor    %r14d,%r14d
  jmp    L115
  nopl   (%rax)
L25:
  movzbl 0x0(%r13),%eax
  test   %al,%al
  je     L3
  mov    %al,-0x1(%r12)
  add    $0x1,%rcx
L58:
  add    $0x1,%r12
L115:
  lea    (%r15,%rcx,1),%r13
  mov    %rbp,%rdx
  mov    %r8,0x18(%rsp)
  mov    %r13,%rdi
  mov    %rcx,0x10(%rsp)
  mov    %rsi,0x8(%rsp)
  call   <strncmp@plt>
  mov    0x8(%rsp),%rsi
  mov    0x10(%rsp),%rcx
  test   %eax,%eax
  mov    0x18(%rsp),%r8
  jne    L25
L3:
  mov    %rbx,(%r8,%r14,8)
  lea    0x1(%r14),%rax
  lea    0x0(,%r14,8),%rdx
  mov    %r12,%rbx
  movb   $0x0,-0x1(%r12)
  cmpb   $0x0,0x0(%r13)
  je     L87
  add    %rbp,%rcx
  mov    %rax,%r14
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L26:
  movzbl (%r15),%eax
  test   %al,%al
  je     L6
  nopl   0x0(%rax,%rax,1)
L68:
  add    $0x1,%rbp
  mov    %rbx,-0x8(%r8,%rbp,8)
  add    $0x2,%rbx
  mov    %al,-0x2(%rbx)
  movb   $0x0,-0x1(%rbx)
  movzbl (%r15,%rbp,1),%eax
  test   %al,%al
  jne    L68
  lea    (%r8,%rbp,8),%rax
L12:
  movq   $0x0,(%rax)
L116:
  add    $0x28,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L87:
  lea    0x8(%r8,%rdx,1),%rax
  jmp    L12
L107:
  xor    %r8d,%r8d
  jmp    L116
L6:
  mov    %r8,%rax
  jmp    L12
  nopl   0x0(%rax)
L119:
  xor    %eax,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: 

assistant: ```c
char **strsplitz(const char *s, const char *d) {
  if (s == NULL) {
    return (NULL);
  }
  if (d == NULL) {
    d = "";
  }
  unsigned long dlen = strlen(d);
  unsigned long len = strlen(s) + 1;
  unsigned long max_subs = len;
  unsigned long sub = 0;
  unsigned long i;
  char *str = (char *)(max_subs * sizeof(char *));
  char *mem = malloc((unsigned long)str + len * 2);
  if (mem == NULL) {
    return (NULL);
  }
  str += (unsigned long)mem;
  char *t = str;
  if (dlen == 0) {
    for (i = 0; s[i]; i++) {
      ((char **)mem)[sub++] = t;
      *t++ = s[i];
      *t++ = 0;
    }
  } else {
    i = 0;
    while (1) {
      if (!strncmp(s + i, d, dlen) || s[i] == 0) {
        ((char **)mem)[sub++] = t;
        *str = 0;
        if (s[i] == 0) {
          break;
        }
        t = str + 1;
        i += dlen;
      } else {
        *str = s[i++];
      }
      str++;
    }
  }
  ((char **)mem)[sub] = NULL;
  return ((char **)mem);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multMatVec>:
  endbr64
  movsd  (%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x20(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x40(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x60(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x28(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x48(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x68(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x30(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x50(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x70(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x18(%rdi),%xmm0
  mulsd  (%rsi),%xmm0
  movsd  0x38(%rdi),%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x58(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x78(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdx)
  ret
```

assistant: ```c
void multMatVec(const double m[16], const double v[4], double res[4]) {
  res[0] = m[0] * v[0] + m[4] * v[1] + m[8] * v[2] + m[12] * v[3];
  res[1] = m[1] * v[0] + m[5] * v[1] + m[9] * v[2] + m[13] * v[3];
  res[2] = m[2] * v[0] + m[6] * v[1] + m[10] * v[2] + m[14] * v[3];
  res[3] = m[3] * v[0] + m[7] * v[1] + m[11] * v[2] + m[15] * v[3];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<multMatVec>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x20(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x40(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x60(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  movsd  0x28(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x48(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x68(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x50(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x70(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x18(%rdi),%xmm0
  movsd  0x38(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x58(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x78(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdx)
  ret
```

assistant: ```c
void multMatVec(const double m[16], const double v[4], double res[4]) {
  res[0] = m[0] * v[0] + m[4] * v[1] + m[8] * v[2] + m[12] * v[3];
  res[1] = m[1] * v[0] + m[5] * v[1] + m[9] * v[2] + m[13] * v[3];
  res[2] = m[2] * v[0] + m[6] * v[1] + m[10] * v[2] + m[14] * v[3];
  res[3] = m[3] * v[0] + m[7] * v[1] + m[11] * v[2] + m[15] * v[3];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multMatVec>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x20(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x40(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x60(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx)
  movsd  0x8(%rdi),%xmm0
  movsd  0x28(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x48(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x68(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rdx)
  movsd  0x10(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x50(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x70(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x10(%rdx)
  movsd  0x18(%rdi),%xmm0
  movsd  0x38(%rdi),%xmm1
  mulsd  (%rsi),%xmm0
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x58(%rdi),%xmm1
  mulsd  0x10(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  0x78(%rdi),%xmm1
  mulsd  0x18(%rsi),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x18(%rdx)
  ret
```

assistant: ```c
void multMatVec(const double m[16], const double v[4], double res[4]) {
  res[0] = m[0] * v[0] + m[4] * v[1] + m[8] * v[2] + m[12] * v[3];
  res[1] = m[1] * v[0] + m[5] * v[1] + m[9] * v[2] + m[13] * v[3];
  res[2] = m[2] * v[0] + m[6] * v[1] + m[10] * v[2] + m[14] * v[3];
  res[3] = m[3] * v[0] + m[7] * v[1] + m[11] * v[2] + m[15] * v[3];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kprintHexWord>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <kprintHexByte@plt>
  movzwl -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <kprintHexByte@plt>
  nop
  leave
  ret
```

assistant: ```c
void kprintHexWord(unsigned short wd) {
  kprintHexByte((unsigned char)((wd & 0xFF00) >> 8));
  kprintHexByte((unsigned char)(wd & 0xFF));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<kprintHexWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %bh,%edi
  call   <kprintHexByte@plt>
  movzbl %bl,%edi
  call   <kprintHexByte@plt>
  pop    %rbx
  ret
```

assistant: ```c
void kprintHexWord(unsigned short wd) {
  kprintHexByte((unsigned char)((wd & 0xFF00) >> 8));
  kprintHexByte((unsigned char)(wd & 0xFF));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kprintHexWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %bh,%edi
  call   <kprintHexByte@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <kprintHexByte@plt>
```

assistant: ```c
void kprintHexWord(unsigned short wd) {
  kprintHexByte((unsigned char)((wd & 0xFF00) >> 8));
  kprintHexByte((unsigned char)(wd & 0xFF));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<kprintHexWord>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movzbl %bh,%edi
  call   <kprintHexByte@plt>
  movzbl %bl,%edi
  pop    %rbx
  jmp    1050 <kprintHexByte@plt>
```

assistant: ```c
void kprintHexWord(unsigned short wd) {
  kprintHexByte((unsigned char)((wd & 0xFF00) >> 8));
  kprintHexByte((unsigned char)(wd & 0xFF));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L8:
  cmp    %rdx,%rsp
  je     L15
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L8
L15:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L75
  orq    $0x0,-0x8(%rsp,%rax,1)
L75:
  mov    %rsp,%r14
  test   %r12d,%r12d
  jle    L69
  mov    %r14,%rbx
  mov    %r12d,%eax
  lea    (%r14,%rax,8),%r15
L60:
  mov    $0x0,%eax
  call   <rand_double@plt>
  mulsd  D25(%rip),%xmm0
  subsd  D14(%rip),%xmm0
  movsd  %xmm0,(%rbx)
  add    $0x8,%rbx
  cmp    %r15,%rbx
  jne    L60
L69:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r15
  test   %r13d,%r13d
  jle    L63
  mov    $0x0,%ebx
L48:
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    D23(%rip),%rax
  movq   %rax,%xmm0
  mov    %r12d,%edi
  call   <stdlib_strided_dnanvariance@plt>
  ucomisd %xmm0,%xmm0
  jp     L73
  add    $0x1,%ebx
  cmp    %ebx,%r13d
  jne    L48
L63:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
L25:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  movq   %rbx,%xmm0
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L73:
  lea    D34(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r15,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L25
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
datatype: f64
name: parse_data
arguments: tag: D14
datatype: f64
name: parse_data
arguments: tag: D23
datatype: f64
name: parse_data
arguments: tag: D34
datatype: string

tool: D25: 20000

tool: D14: 10000

tool: D23: 1

tool: D34: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanvariance(len, 1.0, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L34
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L16
L34:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L59
L105:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L48
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L57:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D7(%rip),%xmm0
  subsd  D17(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L57
L48:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L29
  xor    %r14d,%r14d
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L54:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L29
L61:
  mov    D9(%rip),%rax
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  movq   %rax,%xmm0
  call   <stdlib_strided_dnanvariance@plt>
  ucomisd %xmm0,%xmm0
  jnp    L54
  lea    D24(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L63:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L29:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L59:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L105
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: f64
name: disassemble_data
arguments: data_label: D17
type_infered: f64
name: disassemble_data
arguments: data_label: D9
type_infered: f64
name: disassemble_data
arguments: data_label: D24
type_infered: string

tool: D7: 20000

tool: D17: 10000

tool: D9: 1

tool: D24: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanvariance(len, 1.0, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L51
L46:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L46
L51:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L74
L22:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L12
  mov    %ebx,%eax
  mov    %r13,%r15
  lea    0x0(%r13,%rax,8),%r14
  nopl   0x0(%rax)
L35:
  xor    %eax,%eax
  add    $0x8,%r15
  call   <rand_double@plt>
  mulsd  D6(%rip),%xmm0
  subsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x8(%r15)
  cmp    %r14,%r15
  jne    L35
L12:
  xor    %eax,%eax
  call   <tic@plt>
  movsd  %xmm0,-0x48(%rbp)
  test   %r12d,%r12d
  jle    L62
  xor    %r14d,%r14d
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  je     L62
L4:
  mov    D20(%rip),%rax
  mov    $0x1,%edx
  mov    %r13,%rsi
  mov    %ebx,%edi
  movq   %rax,%xmm0
  call   <stdlib_strided_dnanvariance@plt>
  ucomisd %xmm0,%xmm0
  jnp    L40
  lea    D15(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  mov    %r12,%rdi
  movsd  %xmm0,-0x48(%rbp)
  call   <printf@plt>
  movsd  -0x48(%rbp),%xmm0
L6:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopl   (%rax)
L62:
  xor    %eax,%eax
  call   <tic@plt>
  subsd  -0x48(%rbp),%xmm0
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L74:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L22
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: f64
name: parse_data
arguments: tag: D2
type_infered: f64
name: parse_data
arguments: tag: D20
type_infered: f64
name: parse_data
arguments: tag: D15
type_infered: string

tool: D6: 20000

tool: D2: 10000

tool: D20: 1

tool: D15: should not return NaN


assistant: ```c
double benchmark(int iterations, int len) {
  double elapsed;
  double x[len];
  double v;
  double t;
  int i;
  for (i = 0; i < len; i++) {
    x[i] = (rand_double() * 20000.0) - 10000.0;
  }
  v = 0.0;
  t = tic();
  for (i = 0; i < iterations; i++) {
    v = stdlib_strided_dnanvariance(len, 1.0, x, 1);
    if (v != v) {
      printf("should not return NaN\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (v != v) {
    printf("should not return NaN\n");
  }
  return elapsed;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<file_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *file_path(struct file *file, char *buf, int count) {
  char *a;
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<file_path>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *file_path(struct file *file, char *buf, int count) {
  char *a;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<file_path>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *file_path(struct file *file, char *buf, int count) {
  char *a;
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<file_path>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
char *file_path(struct file *file, char *buf, int count) {
  char *a;
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<test_getNext>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <getNext@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L27
L15:
  addq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getNext@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0xd6bf94d5e57a42bd,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x17,%rax
  imul   $0x989680,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  test   %rax,%rax
  jne    L27
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L27:
  cmpq   $0x0,-0x8(%rbp)
  jne    L15
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D10: num %llu  ip   %s


tool: D7: %llu

assistant: ```c
void test_getNext() {
  unsigned long long int counta = 0;
  char *ip = getNext();
  while (ip != NULL) {
    counta++;
    free(ip);
    ip = getNext();
    if (counta % 10000000 == 0) {
      printf("num %llu  ip   %s\n", counta, ip);
    }
  }
  printf("%llu", counta);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_getNext>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getNext@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L32
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getNext@plt>
  mov    %rax,%rbx
  mov    $0x1,%ebp
  movabs $0xd6bf94d5e57a42bd,%r12
  lea    D3(%rip),%r13
L1:
  test   %rbx,%rbx
  je     L32
  add    $0x1,%rbp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  call   <getNext@plt>
  mov    %rax,%rbx
  mov    %rbp,%rax
  mul    %r12
  shr    $0x17,%rdx
  imul   $0x989680,%rdx,%rdx
  cmp    %rdx,%rbp
  jne    L1
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L1
L32:
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type_infered: string
name: parse_data
arguments: tag: D9
type_infered: string

tool: D3: num %llu  ip   %s


tool: D9: %llu

assistant: ```c
void test_getNext() {
  unsigned long long int counta = 0;
  char *ip = getNext();
  while (ip != NULL) {
    counta++;
    free(ip);
    ip = getNext();
    if (counta % 10000000 == 0) {
      printf("num %llu  ip   %s\n", counta, ip);
    }
  }
  printf("%llu", counta);
  exit(0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_getNext>:
  endbr64
  push   %r14
  xor    %eax,%eax
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <getNext@plt>
  test   %rax,%rax
  je     L36
  mov    %rax,%rdi
  mov    $0x1,%r14d
  movabs $0xe5032477ae8d46a5,%r12
  movabs $0x1ad7f29abca,%rbx
  call   <free@plt>
  xor    %eax,%eax
  lea    D12(%rip),%r13
  call   <getNext@plt>
  mov    %rax,%rbp
  xchg   %ax,%ax
L19:
  test   %rbp,%rbp
  je     L36
L27:
  mov    %rbp,%rdi
  add    $0x1,%r14
  call   <free@plt>
  xor    %eax,%eax
  call   <getNext@plt>
  mov    %rax,%rbp
  mov    %r14,%rax
  imul   %r12,%rax
  ror    $0x7,%rax
  cmp    %rbx,%rax
  ja     L19
  xor    %eax,%eax
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  jne    L27
L36:
  mov    %r14,%rsi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10a0 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D15
data_type: string

tool: D12: num %llu  ip   %s


tool: D15: %llu

assistant: ```c
void test_getNext() {
  unsigned long long int counta = 0;
  char *ip = getNext();
  while (ip != NULL) {
    counta++;
    free(ip);
    ip = getNext();
    if (counta % 10000000 == 0) {
      printf("num %llu  ip   %s\n", counta, ip);
    }
  }
  printf("%llu", counta);
  exit(0);
}
```