ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calculoMemoria>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x38e38e39,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  add    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L9
  cmpl   $0x0,-0x4(%rbp)
  je     L9
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  jmp    L4
L9:
  cmpl   $0x0,-0x4(%rbp)
  je     L17
  mov    $0x1,%eax
  jmp    L4
L17:
  mov    -0x8(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int calculoMemoria(int *n) {
  int cociente = *n / 9;
  int resto = *n % 9;
  if (cociente && resto)
    return cociente + 1;
  else if (resto)
    return 1;
  return cociente;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<calculoMemoria>:
  endbr64
  mov    (%rdi),%edx
  movslq %edx,%rax
  imul   $0x38e38e39,%rax,%rax
  sar    $0x21,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%ecx
  sub    %ecx,%edx
  test   %eax,%eax
  je     L8
  test   %edx,%edx
  je     L8
  add    $0x1,%eax
  ret
L8:
  test   %edx,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int calculoMemoria(int *n) {
  int cociente = *n / 9;
  int resto = *n % 9;
  if (cociente && resto)
    return cociente + 1;
  else if (resto)
    return 1;
  return cociente;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calculoMemoria>:
  endbr64
  movslq (%rdi),%rax
  mov    %rax,%rdx
  imul   $0x38e38e39,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%ecx
  sub    %ecx,%edx
  test   %eax,%eax
  je     L19
  test   %edx,%edx
  je     L19
  add    $0x1,%eax
  ret
  nopl   (%rax)
L19:
  test   %edx,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int calculoMemoria(int *n) {
  int cociente = *n / 9;
  int resto = *n % 9;
  if (cociente && resto)
    return cociente + 1;
  else if (resto)
    return 1;
  return cociente;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calculoMemoria>:
  endbr64
  movslq (%rdi),%rax
  mov    %rax,%rdx
  imul   $0x38e38e39,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,8),%ecx
  sub    %ecx,%edx
  test   %eax,%eax
  je     L14
  test   %edx,%edx
  je     L14
  add    $0x1,%eax
  ret
  nopl   (%rax)
L14:
  test   %edx,%edx
  mov    $0x1,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int calculoMemoria(int *n) {
  int cociente = *n / 9;
  int resto = *n % 9;
  if (cociente && resto)
    return cociente + 1;
  else if (resto)
    return 1;
  return cociente;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void die(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void die(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(char *msg) {
  perror(msg);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void die(char *msg) {
  perror(msg);
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_inverse>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x40(%rdi),%xmm1
  movsd  %xmm1,0x10(%rsi)
  movsd  (%rdi),%xmm0
  mulsd  0x18(%rdi),%xmm0
  movsd  0x20(%rdi),%xmm2
  mulsd  0x38(%rdi),%xmm2
  addsd  %xmm2,%xmm0
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  movq   D9(%rip),%xmm2
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x48(%rdi),%xmm1
  movsd  %xmm1,0x30(%rsi)
  movsd  0x8(%rdi),%xmm0
  mulsd  0x18(%rdi),%xmm0
  movsd  0x28(%rdi),%xmm3
  mulsd  0x38(%rdi),%xmm3
  addsd  %xmm3,%xmm0
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x48(%rsi)
  movsd  0x50(%rdi),%xmm1
  movsd  %xmm1,0x50(%rsi)
  movsd  0x10(%rdi),%xmm0
  mulsd  0x18(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm3
  mulsd  0x38(%rdi),%xmm3
  addsd  %xmm3,%xmm0
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x58(%rsi)
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  mov    D15(%rip),%rax
  mov    %rax,0x78(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: byte[8]
name: parse_data
arguments: label: D15
type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void matrix_inverse(double T[4][4], double TIN[4][4]) {
  TIN[0][0] = T[0][0];
  TIN[0][1] = T[1][0];
  TIN[0][2] = T[2][0];
  TIN[0][3] = -(T[0][0] * T[0][3] + T[1][0] * T[1][3] + T[2][0] * T[2][3]);
  TIN[1][0] = T[0][1];
  TIN[1][1] = T[1][1];
  TIN[1][2] = T[2][1];
  TIN[1][3] = -(T[0][1] * T[0][3] + T[1][1] * T[1][3] + T[2][1] * T[2][3]);
  TIN[2][0] = T[0][2];
  TIN[2][1] = T[1][2];
  TIN[2][2] = T[2][2];
  TIN[2][3] = -(T[0][2] * T[0][3] + T[1][2] * T[1][3] + T[2][2] * T[2][3]);
  TIN[3][0] = 0;
  TIN[3][1] = 0;
  TIN[3][2] = 0;
  TIN[3][3] = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<matrix_inverse>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x40(%rdi),%xmm1
  movsd  %xmm1,0x10(%rsi)
  movsd  (%rdi),%xmm0
  movsd  0x20(%rdi),%xmm2
  mulsd  0x18(%rdi),%xmm0
  mulsd  0x38(%rdi),%xmm2
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm2,%xmm0
  movq   D12(%rip),%xmm2
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x48(%rdi),%xmm1
  movsd  %xmm1,0x30(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  0x28(%rdi),%xmm3
  mulsd  0x18(%rdi),%xmm0
  mulsd  0x38(%rdi),%xmm3
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x48(%rsi)
  movsd  0x50(%rdi),%xmm1
  movsd  %xmm1,0x50(%rsi)
  movsd  0x10(%rdi),%xmm0
  mulsd  0x18(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm3
  mulsd  0x38(%rdi),%xmm3
  mulsd  0x58(%rdi),%xmm1
  mov    D1(%rip),%rax
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  mov    %rax,0x78(%rsi)
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x58(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: byte[8]
name: unpack_data
arguments: data_label: D1
datatype: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void matrix_inverse(double T[4][4], double TIN[4][4]) {
  TIN[0][0] = T[0][0];
  TIN[0][1] = T[1][0];
  TIN[0][2] = T[2][0];
  TIN[0][3] = -(T[0][0] * T[0][3] + T[1][0] * T[1][3] + T[2][0] * T[2][3]);
  TIN[1][0] = T[0][1];
  TIN[1][1] = T[1][1];
  TIN[1][2] = T[2][1];
  TIN[1][3] = -(T[0][1] * T[0][3] + T[1][1] * T[1][3] + T[2][1] * T[2][3]);
  TIN[2][0] = T[0][2];
  TIN[2][1] = T[1][2];
  TIN[2][2] = T[2][2];
  TIN[2][3] = -(T[0][2] * T[0][3] + T[1][2] * T[1][3] + T[2][2] * T[2][3]);
  TIN[3][0] = 0;
  TIN[3][1] = 0;
  TIN[3][2] = 0;
  TIN[3][3] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<matrix_inverse>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x40(%rdi),%xmm1
  movsd  %xmm1,0x10(%rsi)
  movsd  (%rdi),%xmm0
  movsd  0x20(%rdi),%xmm2
  mulsd  0x18(%rdi),%xmm0
  mulsd  0x38(%rdi),%xmm2
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm2,%xmm0
  movq   D19(%rip),%xmm2
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x48(%rdi),%xmm1
  movsd  %xmm1,0x30(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  0x28(%rdi),%xmm3
  mulsd  0x18(%rdi),%xmm0
  mulsd  0x38(%rdi),%xmm3
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x48(%rsi)
  movsd  0x50(%rdi),%xmm1
  movsd  %xmm1,0x50(%rsi)
  movsd  0x10(%rdi),%xmm0
  mulsd  0x18(%rdi),%xmm0
  movsd  0x30(%rdi),%xmm3
  mulsd  0x38(%rdi),%xmm3
  mulsd  0x58(%rdi),%xmm1
  addsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  xorpd  %xmm2,%xmm0
  movsd  %xmm0,0x58(%rsi)
  pxor   %xmm0,%xmm0
  movups %xmm0,0x60(%rsi)
  movapd D1(%rip),%xmm0
  movups %xmm0,0x70(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D19
data_type: byte[8]
name: parse_data
arguments: data_tag: D1
data_type: byte[16]

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void matrix_inverse(double T[4][4], double TIN[4][4]) {
  TIN[0][0] = T[0][0];
  TIN[0][1] = T[1][0];
  TIN[0][2] = T[2][0];
  TIN[0][3] = -(T[0][0] * T[0][3] + T[1][0] * T[1][3] + T[2][0] * T[2][3]);
  TIN[1][0] = T[0][1];
  TIN[1][1] = T[1][1];
  TIN[1][2] = T[2][1];
  TIN[1][3] = -(T[0][1] * T[0][3] + T[1][1] * T[1][3] + T[2][1] * T[2][3]);
  TIN[2][0] = T[0][2];
  TIN[2][1] = T[1][2];
  TIN[2][2] = T[2][2];
  TIN[2][3] = -(T[0][2] * T[0][3] + T[1][2] * T[1][3] + T[2][2] * T[2][3]);
  TIN[3][0] = 0;
  TIN[3][1] = 0;
  TIN[3][2] = 0;
  TIN[3][3] = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<forkme>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L12
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
L12:
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int forkme() {
  int pid;
  pid = fork();
  if (pid != 0)
    pid = fork();
  if (pid != 0)
    pid = fork();
  return pid;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<forkme>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  mov    %eax,%edx
  test   %eax,%eax
  jne    L0
L3:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L0:
  call   <fork@plt>
  mov    %eax,%edx
  test   %eax,%eax
  je     L3
  call   <fork@plt>
  mov    %eax,%edx
  jmp    L3
```

assistant: ```c
int forkme() {
  int pid;
  pid = fork();
  if (pid != 0)
    pid = fork();
  if (pid != 0)
    pid = fork();
  return pid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<forkme>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %eax,%eax
  jne    L10
L14:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  call   <fork@plt>
  test   %eax,%eax
  je     L14
  add    $0x8,%rsp
  jmp    1050 <fork@plt>
```

assistant: ```c
int forkme() {
  int pid;
  pid = fork();
  if (pid != 0)
    pid = fork();
  if (pid != 0)
    pid = fork();
  return pid;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<forkme>:
  endbr64
  sub    $0x8,%rsp
  call   <fork@plt>
  test   %eax,%eax
  jne    L14
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  call   <fork@plt>
  test   %eax,%eax
  je     L0
  add    $0x8,%rsp
  jmp    1050 <fork@plt>
```

assistant: ```c
int forkme() {
  int pid;
  pid = fork();
  if (pid != 0)
    pid = fork();
  if (pid != 0)
    pid = fork();
  return pid;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <Parse_UART2_Received_Message@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
data_type: string
name: parse_data
arguments: data_tag: D18
data_type: string

tool: D6: $FIN 0x02:12 STATe?!

tool: D18: Current result : %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *sSimulationTestingCmdMesg = "$FIN 0x02:12 STATe?!";
  int iResult = 0;
  iResult = Parse_UART2_Received_Message(sSimulationTestingCmdMesg);
  printf("Current result : %d\n", iResult);
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <Parse_UART2_Received_Message@plt>
  mov    %eax,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
type: string
name: parse_data
arguments: tag: D15
type: string

tool: D14: $FIN 0x02:12 STATe?!

tool: D15: Current result : %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *sSimulationTestingCmdMesg = "$FIN 0x02:12 STATe?!";
  int iResult = 0;
  iResult = Parse_UART2_Received_Message(sSimulationTestingCmdMesg);
  printf("Current result : %d\n", iResult);
  getchar();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <Parse_UART2_Received_Message@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D19
type: string

tool: D0: $FIN 0x02:12 STATe?!

tool: D19: Current result : %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *sSimulationTestingCmdMesg = "$FIN 0x02:12 STATe?!";
  int iResult = 0;
  iResult = Parse_UART2_Received_Message(sSimulationTestingCmdMesg);
  printf("Current result : %d\n", iResult);
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D13(%rip),%rdi
  call   <Parse_UART2_Received_Message@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
data_type: string
name: unpack_data
arguments: tag: D15
data_type: string

tool: D13: $FIN 0x02:12 STATe?!

tool: D15: Current result : %d


assistant: ```c
int main(int argc, char *argv[]) {
  char *sSimulationTestingCmdMesg = "$FIN 0x02:12 STATe?!";
  int iResult = 0;
  iResult = Parse_UART2_Received_Message(sSimulationTestingCmdMesg);
  printf("Current result : %d\n", iResult);
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x8,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string

tool: D9: %d

assistant: ```c
void fun(char a[]) {
  int res = sizeof(a) / sizeof(a[0]);
  printf("%d", res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fun>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d

assistant: ```c
void fun(char a[]) {
  int res = sizeof(a) / sizeof(a[0]);
  printf("%d", res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fun>:
  endbr64
  mov    $0x8,%esi
  lea    D9(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_infered: string

tool: D9: %d

assistant: ```c
void fun(char a[]) {
  int res = sizeof(a) / sizeof(a[0]);
  printf("%d", res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fun>:
  endbr64
  mov    $0x8,%esi
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type: string

tool: D5: %d

assistant: ```c
void fun(char a[]) {
  int res = sizeof(a) / sizeof(a[0]);
  printf("%d", res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<iterate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x28(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L5
L18:
  movss  -0x10(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  mulss  %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x8(%rbp),%xmm0
  addss  -0x4(%rbp),%xmm0
  comiss D0(%rip),%xmm0
  ja     L11
  movss  -0x10(%rbp),%xmm0
  addss  %xmm0,%xmm0
  mulss  -0xc(%rbp),%xmm0
  movss  -0x28(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x8(%rbp),%xmm0
  subss  -0x4(%rbp),%xmm0
  movss  -0x24(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L5:
  cmpl   $0xd,-0x14(%rbp)
  jle    L18
  jmp    L2
L11:
  nop
L2:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: f32

tool: D0: 4

assistant: ```c
int iterate(float cr, float ci) {
  int niter;
  float zr, zi;
  float zr2, zi2;
  zr = cr;
  zi = ci;
  for (niter = 0; niter < 14; niter++) {
    zr2 = zr * zr;
    zi2 = zi * zi;
    if (zr2 + zi2 > 4.0)
      break;
    zi = 2 * zr * zi + ci;
    zr = zr2 - zi2 + cr;
  }
  return (niter);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<iterate>:
  endbr64
  movaps %xmm1,%xmm3
  movaps %xmm0,%xmm2
  mov    $0x0,%eax
L6:
  movaps %xmm2,%xmm4
  mulss  %xmm2,%xmm4
  movaps %xmm3,%xmm5
  mulss  %xmm3,%xmm5
  movaps %xmm4,%xmm6
  addss  %xmm5,%xmm6
  comiss D2(%rip),%xmm6
  ja     L15
  addss  %xmm2,%xmm2
  mulss  %xmm2,%xmm3
  addss  %xmm1,%xmm3
  subss  %xmm5,%xmm4
  movaps %xmm4,%xmm2
  addss  %xmm0,%xmm2
  add    $0x1,%eax
  cmp    $0xe,%eax
  jne    L6
L15:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: f32

tool: D2: 4

assistant: ```c
int iterate(float cr, float ci) {
  int niter;
  float zr, zi;
  float zr2, zi2;
  zr = cr;
  zi = ci;
  for (niter = 0; niter < 14; niter++) {
    zr2 = zr * zr;
    zi2 = zi * zi;
    if (zr2 + zi2 > 4.0)
      break;
    zi = 2 * zr * zi + ci;
    zr = zr2 - zi2 + cr;
  }
  return (niter);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<iterate>:
  endbr64
  movaps %xmm1,%xmm3
  movaps %xmm0,%xmm2
  xor    %eax,%eax
  nopl   0x0(%rax)
L14:
  movaps %xmm2,%xmm4
  movaps %xmm3,%xmm5
  mulss  %xmm2,%xmm4
  mulss  %xmm3,%xmm5
  movaps %xmm4,%xmm6
  addss  %xmm5,%xmm6
  comiss D5(%rip),%xmm6
  ja     L4
  addss  %xmm2,%xmm2
  subss  %xmm5,%xmm4
  add    $0x1,%eax
  mulss  %xmm2,%xmm3
  movaps %xmm4,%xmm2
  addss  %xmm0,%xmm2
  addss  %xmm1,%xmm3
  cmp    $0xe,%eax
  jne    L14
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: f32

tool: D5: 4

assistant: ```c
int iterate(float cr, float ci) {
  int niter;
  float zr, zi;
  float zr2, zi2;
  zr = cr;
  zi = ci;
  for (niter = 0; niter < 14; niter++) {
    zr2 = zr * zr;
    zi2 = zi * zi;
    if (zr2 + zi2 > 4.0)
      break;
    zi = 2 * zr * zi + ci;
    zr = zr2 - zi2 + cr;
  }
  return (niter);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<binseai>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
  jmp    L35
L19:
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jge    L31
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L35
L31:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
L35:
  mov    -0x24(%rbp),%eax
  sub    -0x18(%rbp),%eax
  cmp    $0x1,%eax
  jg     L19
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L20
  mov    -0x18(%rbp),%eax
  jmp    L36
L20:
  mov    $0xffffffff,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int binseai(int key, int a[], int lo, int hi) {
  while (hi - lo > 1) {
    int mid = (hi + lo) / 2;
    if (key < a[mid]) {
      hi = mid;
    } else {
      lo = mid;
    }
  }
  if (a[lo] == key) {
    return lo;
  } else {
    return ((-1));
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<binseai>:
  endbr64
  mov    %edi,%r8d
  mov    %edx,%eax
  jmp    L14
L7:
  lea    (%rcx,%rax,1),%edx
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  movslq %edi,%rdx
  cmp    %r8d,(%rsi,%rdx,4)
  cmovle %edi,%eax
  cmovg  %edi,%ecx
L14:
  mov    %ecx,%edx
  sub    %eax,%edx
  cmp    $0x1,%edx
  jg     L7
  movslq %eax,%rdx
  cmp    %r8d,(%rsi,%rdx,4)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int binseai(int key, int a[], int lo, int hi) {
  while (hi - lo > 1) {
    int mid = (hi + lo) / 2;
    if (key < a[mid]) {
      hi = mid;
    } else {
      lo = mid;
    }
  }
  if (a[lo] == key) {
    return lo;
  } else {
    return ((-1));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<binseai>:
  endbr64
  mov    %edi,%r8d
  mov    %edx,%eax
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L17:
  lea    (%rcx,%rax,1),%edx
  mov    %edx,%edi
  shr    $0x1f,%edi
  add    %edx,%edi
  sar    %edi
  movslq %edi,%rdx
  cmp    %r8d,(%rsi,%rdx,4)
  cmovle %edi,%eax
  cmovg  %edi,%ecx
L10:
  mov    %ecx,%edx
  sub    %eax,%edx
  cmp    $0x1,%edx
  jg     L17
  movslq %eax,%rdx
  cmp    %r8d,(%rsi,%rdx,4)
  mov    $0xffffffff,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int binseai(int key, int a[], int lo, int hi) {
  while (hi - lo > 1) {
    int mid = (hi + lo) / 2;
    if (key < a[mid]) {
      hi = mid;
    } else {
      lo = mid;
    }
  }
  if (a[lo] == key) {
    return lo;
  } else {
    return ((-1));
  }
}
```