ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<ANT_ResetSystem>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x4a,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <msg_send@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char ANT_ResetSystem(void) {
  unsigned char filler = 0;
  return msg_send(0x4a, &filler, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ANT_ResetSystem>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    $0x4a,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  movb   $0x0,0x7(%rsp)
  call   <msg_send@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char ANT_ResetSystem(void) {
  unsigned char filler = 0;
  return msg_send(0x4a, &filler, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Delta_ET>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D38(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D20(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  D41(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D12(%rip),%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm1
  movsd  D33(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D32(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  D68(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D38
type: byte[8]
name: unpack_data
arguments: data_label: D20
type: f64
name: unpack_data
arguments: data_label: D41
type: f64
name: unpack_data
arguments: data_label: D12
type: byte[8]
name: unpack_data
arguments: data_label: D33
type: f64
name: unpack_data
arguments: data_label: D32
type: byte[8]
name: unpack_data
arguments: data_label: D68
type: f64

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D20: 0.747622

tool: D41: 26.465

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D33: 6.283185307179586

tool: {"D32": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: D68: 1.886913

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Delta_ET>:
  endbr64
  push   %rbx
  movq   %xmm0,%rbx
  subsd  D12(%rip),%xmm0
  mulsd  D55(%rip),%xmm0
  divsd  D56(%rip),%xmm0
  call   <sin@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  subsd  D21(%rip),%xmm0
  mulsd  D44(%rip),%xmm0
  addsd  D23(%rip),%xmm0
  mulsd  D50(%rip),%xmm1
  addsd  %xmm1,%xmm0
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D12
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D55
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D56
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D21
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D44
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D23
type_infered: f64
name: extract_symbolic_data
arguments: data_label: D50
type_infered: f64

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D55: 6.283185307179586

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D44: 0.747622

tool: D23: 26.465

tool: D50: 1.886913

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Delta_ET>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  subsd  D18(%rip),%xmm0
  mulsd  D48(%rip),%xmm0
  divsd  D40(%rip),%xmm0
  call   <sin@plt>
  mulsd  D30(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  D57(%rip),%xmm1
  mulsd  D53(%rip),%xmm1
  addsd  D0(%rip),%xmm1
  add    $0x18,%rsp
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D18
datatype: byte[8]
name: parse_data
arguments: label: D48
datatype: f64
name: parse_data
arguments: label: D40
datatype: byte[8]
name: parse_data
arguments: label: D30
datatype: f64
name: parse_data
arguments: label: D57
datatype: byte[8]
name: parse_data
arguments: label: D53
datatype: f64
name: parse_data
arguments: label: D0
datatype: f64

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D48: 6.283185307179586

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: D30: 1.886913

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D53: 0.747622

tool: D0: 26.465

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Delta_ET>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  subsd  D67(%rip),%xmm0
  mulsd  D66(%rip),%xmm0
  divsd  D18(%rip),%xmm0
  call   <sin@plt>
  mulsd  D65(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  subsd  D57(%rip),%xmm1
  mulsd  D36(%rip),%xmm1
  addsd  D64(%rip),%xmm1
  add    $0x18,%rsp
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D67
type_infered: byte[8]
name: read_data
arguments: data_label: D66
type_infered: f64
name: read_data
arguments: data_label: D18
type_infered: byte[8]
name: read_data
arguments: data_label: D65
type_infered: f64
name: read_data
arguments: data_label: D57
type_infered: byte[8]
name: read_data
arguments: data_label: D36
type_infered: f64
name: read_data
arguments: data_label: D64
type_infered: f64

tool: {"D67": [0x00,0x00,0x00,0x00,0x00,0xdc,0x9e,0x40]}

tool: D66: 6.283185307179586

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x80,0x40,0x40]}

tool: D65: 1.886913

tool: {"D57": [0x00,0x00,0x00,0x00,0x00,0x78,0x9e,0x40]}

tool: D36: 0.747622

tool: D64: 26.465

assistant: ```c
double Delta_ET(double year) {
  double delta_et;
  delta_et = 26.465 + 0.747622 * (year - 1950) + 1.886913 * sin(6.28318530717958623 * (year - 1975) / 33);
  return delta_et;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prbits32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  jmp    L33
L9:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L26
  mov    $0x31,%eax
  jmp    L38
L26:
  mov    $0x30,%eax
L38:
  mov    %eax,%edi
  call   <putchar@plt>
L33:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  test   %eax,%eax
  jne    L9
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: 


assistant: ```c
void prbits32(u_int32_t u) {
  u_int32_t i = 32;
  for (; i--; putchar(u & 1 << i ? '1' : '0'))
    ;
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prbits32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x1f,%ebx
L3:
  mov    %ebp,%edi
  mov    %ebx,%ecx
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L3
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: 


assistant: ```c
void prbits32(u_int32_t u) {
  u_int32_t i = 32;
  for (; i--; putchar(u & 1 << i ? '1' : '0'))
    ;
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prbits32>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1f,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L1:
  mov    %ebx,%ecx
  mov    %ebp,%edi
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L1
  add    $0x8,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: 


assistant: ```c
void prbits32(u_int32_t u) {
  u_int32_t i = 32;
  for (; i--; putchar(u & 1 << i ? '1' : '0'))
    ;
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prbits32>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    $0x1f,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L2:
  mov    %ebx,%ecx
  mov    %ebp,%edi
  sar    %cl,%edi
  and    $0x1,%edi
  add    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jae    L2
  add    $0x8,%rsp
  lea    D8(%rip),%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D8
datatype: string

tool: D8: 


assistant: ```c
void prbits32(u_int32_t u) {
  u_int32_t i = 32;
  for (; i--; putchar(u & 1 << i ? '1' : '0'))
    ;
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sort_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L18:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L35:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L29
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
L29:
  addl   $0x1,-0xc(%rbp)
L0:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L35
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void sort_array(char **strs, int num) {
  int i, j;
  char *tmp = NULL;
  for (i = 0; i < num; i++)
    for (j = i; j < num; j++)
      if (strcmp(strs[i], strs[j]) > 0) {
        tmp = strs[i];
        strs[i] = strs[j];
        strs[j] = tmp;
      }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sort_array>:
  endbr64
  test   %esi,%esi
  jle    L1
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r14d
  lea    -0x1(%rsi),%r15d
  mov    %esi,%eax
  mov    %rax,(%rsp)
  mov    %rdi,%rbp
  mov    $0x0,%r13d
  lea    0x8(%rdi),%rax
  mov    %rax,0x8(%rsp)
  jmp    L6
L73:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L8
L35:
  mov    (%rbx),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L73
  mov    0x0(%rbp),%rax
  mov    (%rbx),%rdx
  mov    %rdx,0x0(%rbp)
  mov    %rax,(%rbx)
  jmp    L73
L8:
  add    $0x1,%r13
  add    $0x8,%rbp
  cmp    (%rsp),%r13
  je     L48
L6:
  cmp    %r13d,%r14d
  jle    L8
  mov    %r15d,%eax
  sub    %r13d,%eax
  add    %r13,%rax
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rax,8),%r12
  mov    %rbp,%rbx
  jmp    L35
L48:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  ret
```

assistant: ```c
void sort_array(char **strs, int num) {
  int i, j;
  char *tmp = NULL;
  for (i = 0; i < num; i++)
    for (j = i; j < num; j++)
      if (strcmp(strs[i], strs[j]) > 0) {
        tmp = strs[i];
        strs[i] = strs[j];
        strs[j] = tmp;
      }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_array>:
  endbr64
  test   %esi,%esi
  jle    L30
  push   %r15
  movslq %esi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L29:
  mov    %r14,%rbx
  nopl   0x0(%rax,%rax,1)
L34:
  mov    (%r12,%rbx,8),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L12
  mov    0x0(%rbp),%rax
  mov    (%r12,%rbx,8),%rdx
  mov    %rdx,0x0(%rbp)
  mov    %rax,(%r12,%rbx,8)
L12:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jg     L34
  add    $0x1,%r14
  add    $0x8,%rbp
  cmp    %r15,%r14
  jne    L29
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  ret
```

assistant: ```c
void sort_array(char **strs, int num) {
  int i, j;
  char *tmp = NULL;
  for (i = 0; i < num; i++)
    for (j = i; j < num; j++)
      if (strcmp(strs[i], strs[j]) > 0) {
        tmp = strs[i];
        strs[i] = strs[j];
        strs[j] = tmp;
      }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sort_array>:
  endbr64
  test   %esi,%esi
  jle    L5
  push   %r15
  movslq %esi,%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   (%rax)
L20:
  mov    %r14,%rbx
  nopl   0x0(%rax,%rax,1)
L27:
  mov    (%r12,%rbx,8),%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L10
  mov    0x0(%rbp),%rax
  mov    (%r12,%rbx,8),%rdx
  mov    %rdx,0x0(%rbp)
  mov    %rax,(%r12,%rbx,8)
L10:
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jg     L27
  add    $0x1,%r14
  add    $0x8,%rbp
  cmp    %r15,%r14
  jne    L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  ret
```

assistant: ```c
void sort_array(char **strs, int num) {
  int i, j;
  char *tmp = NULL;
  for (i = 0; i < num; i++)
    for (j = i; j < num; j++)
      if (strcmp(strs[i], strs[j]) > 0) {
        tmp = strs[i];
        strs[i] = strs[j];
        strs[j] = tmp;
      }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  mov    $0x0,%edi
  call   <mergesort@plt>
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  mergesort(0, 8 - 1);
  print();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x0,%edi
  call   <mergesort@plt>
  mov    $0x0,%eax
  call   <print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  mergesort(0, 8 - 1);
  print();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  xor    %edi,%edi
  call   <mergesort@plt>
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  mergesort(0, 8 - 1);
  print();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  xor    %edi,%edi
  call   <mergesort@plt>
  xor    %eax,%eax
  call   <print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  mergesort(0, 8 - 1);
  print();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fold>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L62
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L53:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L53
  jmp    L51
L62:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L52
L59:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  je     L70
  cmpl   $0x9,-0x4(%rbp)
  je     L70
  cmpl   $0xa,-0x4(%rbp)
  je     L70
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L45
L70:
  subl   $0x1,-0xc(%rbp)
L52:
  cmpl   $0x0,-0xc(%rbp)
  jns    L59
L45:
  movl   $0x0,-0xc(%rbp)
  jmp    L79
L32:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0xc(%rbp)
L79:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L32
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    %eax,-0x20(%rbp)
  jmp    L91
L112:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L91:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L112
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <fold>
L51:
  nop
  leave
  ret
```

assistant: ```c
int fold(char chunk[], int limit, int length) {
  int counter;
  if (!(length > limit)) {
    counter = 0;
    while (chunk[counter] != '\0') {
      putchar(chunk[counter]);
      ++counter;
    }
  } else {
    int lastCharIdx, character;
    counter = limit - 1;
    while (counter >= 0) {
      character = chunk[counter];
      if (character != ' ' && character != '\t' && character != '\n') {
        lastCharIdx = counter;
        break;
      }
      --counter;
    }
    counter = 0;
    while (counter <= lastCharIdx) {
      putchar(chunk[counter]);
      ++counter;
    }
    putchar('\n');
    counter = 0;
    length = length - limit;
    while (counter < length) {
      chunk[counter] = chunk[counter + limit];
      ++counter;
    }
    chunk[length] = '\0';
    fold(chunk, limit, length);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fold>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  cmp    %esi,%edx
  jg     L114
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L13
  add    $0x1,%rbx
L102:
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L102
  jmp    L13
L114:
  mov    %esi,%r12d
  mov    %edx,%r13d
  mov    %esi,%eax
  sub    $0x1,%eax
  js     L90
  cltq
  jmp    L39
L16:
  sub    $0x1,%rax
  test   %eax,%eax
  js     L90
L39:
  mov    %eax,%ebp
  movzbl (%rbx,%rax,1),%edx
  lea    -0x9(%rdx),%ecx
  cmp    $0x1,%cl
  jbe    L16
  cmp    $0x20,%dl
  je     L16
L90:
  test   %ebp,%ebp
  js     L55
  mov    $0x0,%r14d
L113:
  movsbl (%rbx,%r14,1),%edi
  call   <putchar@plt>
  add    $0x1,%r14
  cmp    %r14d,%ebp
  jge    L113
L55:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r13d,%edx
  sub    %r12d,%edx
  mov    %rbx,%rax
  lea    -0x1(%rdx),%ecx
  lea    0x1(%rbx,%rcx,1),%rdi
  movslq %r12d,%rsi
L28:
  movzbl (%rax,%rsi,1),%ecx
  mov    %cl,(%rax)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L28
  movslq %edx,%rax
  movb   $0x0,(%rbx,%rax,1)
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <fold>
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int fold(char chunk[], int limit, int length) {
  int counter;
  if (!(length > limit)) {
    counter = 0;
    while (chunk[counter] != '\0') {
      putchar(chunk[counter]);
      ++counter;
    }
  } else {
    int lastCharIdx, character;
    counter = limit - 1;
    while (counter >= 0) {
      character = chunk[counter];
      if (character != ' ' && character != '\t' && character != '\n') {
        lastCharIdx = counter;
        break;
      }
      --counter;
    }
    counter = 0;
    while (counter <= lastCharIdx) {
      putchar(chunk[counter]);
      ++counter;
    }
    putchar('\n');
    counter = 0;
    length = length - limit;
    while (counter < length) {
      chunk[counter] = chunk[counter + limit];
      ++counter;
    }
    chunk[length] = '\0';
    fold(chunk, limit, length);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fold>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  cmp    %esi,%edx
  jle    L7
  lea    -0x1(%rsi),%eax
  mov    %edx,%ebp
  movslq %esi,%rbx
  movslq %edx,%rdx
  mov    %eax,0xc(%rsp)
  mov    %esi,%eax
  sub    %esi,%ebp
  sub    %rbx,%rdx
  neg    %eax
  movslq %ebp,%rbp
  mov    %esi,%r12d
  cltq
  sub    %rbp,%rdx
  mov    %rax,(%rsp)
  lea    0x1(%rdi),%rax
  mov    %rax,0x18(%rsp)
  lea    (%rdi,%rdx,1),%rax
  mov    %rax,0x10(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L3:
  movslq 0xc(%rsp),%rax
  test   %eax,%eax
  js     L49
  nopl   0x0(%rax)
L0:
  movzbl (%r15,%rax,1),%edx
  mov    %eax,%r14d
  lea    -0x9(%rdx),%esi
  cmp    $0x1,%sil
  jbe    L1
  cmp    $0x20,%dl
  jne    L49
L1:
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L0
L49:
  xor    %r13d,%r13d
  nopl   0x0(%rax)
L93:
  movsbl (%r15,%r13,1),%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r13d,%r14d
  jge    L93
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    -0x1(%rbp),%esi
  mov    %r15,%rax
  add    0x18(%rsp),%rsi
L16:
  movzbl (%rax,%rbx,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmp    %rax,%rsi
  jne    L16
  mov    0x10(%rsp),%rax
  movb   $0x0,(%rax,%rbp,1)
  add    (%rsp),%rbp
  lea    (%r12,%rbp,1),%eax
  cmp    %eax,%r12d
  jl     L3
L7:
  movsbl (%r15),%edi
  test   %dil,%dil
  je     L63
  add    $0x1,%r15
  nopw   0x0(%rax,%rax,1)
L38:
  call   <putchar@plt>
  movsbl (%r15),%edi
  add    $0x1,%r15
  test   %dil,%dil
  jne    L38
L63:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int fold(char chunk[], int limit, int length) {
  int counter;
  if (!(length > limit)) {
    counter = 0;
    while (chunk[counter] != '\0') {
      putchar(chunk[counter]);
      ++counter;
    }
  } else {
    int lastCharIdx, character;
    counter = limit - 1;
    while (counter >= 0) {
      character = chunk[counter];
      if (character != ' ' && character != '\t' && character != '\n') {
        lastCharIdx = counter;
        break;
      }
      --counter;
    }
    counter = 0;
    while (counter <= lastCharIdx) {
      putchar(chunk[counter]);
      ++counter;
    }
    putchar('\n');
    counter = 0;
    length = length - limit;
    while (counter < length) {
      chunk[counter] = chunk[counter + limit];
      ++counter;
    }
    chunk[length] = '\0';
    fold(chunk, limit, length);
  }
}
```