ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %rcx,-0x68(%rbp)
  mov    %r8d,-0x6c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  lea    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x58(%rbp),%rax
  mov    %rax,%rsi
  mov    %r13d,%edi
  call   <FD_SET@plt>
  cmpl   $0x0,-0x6c(%rbp)
  jne    L27
  movq   $0x0,-0x48(%rbp)
L27:
  mov    %r12d,-0x54(%rbp)
  jmp    L101
L42:
  movl   $0x1e,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    -0x48(%rbp),%rdx
  lea    -0x58(%rbp),%rsi
  mov    %rdx,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %eax,%edi
  call   <select@plt>
  mov    %eax,-0x50(%rbp)
  cmpl   $0x0,-0x50(%rbp)
  jns    L96
  mov    -0x50(%rbp),%eax
  jmp    L83
L96:
  cmpl   $0x0,-0x50(%rbp)
  jne    L47
  mov    -0x68(%rbp),%rdx
  mov    $0x0,%eax
  call   *%rdx
  jmp    L101
L47:
  mov    -0x54(%rbp),%eax
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  mov    %eax,-0x4c(%rbp)
  cmpl   $0x0,-0x4c(%rbp)
  jns    L11
  mov    -0x4c(%rbp),%eax
  jmp    L83
L11:
  cmpl   $0x0,-0x4c(%rbp)
  je     L68
  mov    -0x4c(%rbp),%eax
  sub    %eax,-0x54(%rbp)
  mov    -0x4c(%rbp),%eax
  cltq
  add    %rax,%rbx
L101:
  cmpl   $0x0,-0x54(%rbp)
  jg     L42
  jmp    L3
L68:
  nop
L3:
  mov    %r12d,%eax
  sub    -0x54(%rbp),%eax
L83:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L104
  call   <__stack_chk_fail@plt>
L104:
  add    $0x58,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int _readn(register int fd, register char *ptr, register int nbytes, void (*timeout_function)(), int doselect) {
  int nleft, nread;
  int r;
  fd_set set;
  struct timeval ltspfs_timeout;
  struct timeval *timeout_ptr = &ltspfs_timeout;
  FD_ZERO(&set);
  FD_SET(fd, &set);
  if (!doselect)
    timeout_ptr = NULL;
  nleft = nbytes;
  while (nleft > 0) {
    ltspfs_timeout.tv_sec = 30;
    ltspfs_timeout.tv_usec = 0;
    r = select(FD_SETSIZE, &set, NULL, NULL, timeout_ptr);
    if (r < 0)
      return r;
    else if (r == 0)
      timeout_function();
    else {
      nread = read(fd, ptr, nleft);
      if (nread < 0)
        return (nread);
      else if (nread == 0)
        break;
      nleft -= nread;
      ptr += nread;
    }
  }
  return (nbytes - nleft);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_readn>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    %edx,0xc(%rsp)
  mov    %rcx,%r14
  mov    %r8d,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  mov    %rbp,%rdi
  call   <FD_ZERO@plt>
  mov    %rbp,%rsi
  mov    %r15d,%edi
  call   <FD_SET@plt>
  lea    0x20(%rsp),%rbp
  test   %ebx,%ebx
  mov    $0x0,%eax
  cmove  %rax,%rbp
  test   %r13d,%r13d
  jle    L27
  mov    %r13d,%ebx
  lea    0x1c(%rsp),%r13
  jmp    L87
L88:
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L17
  je     L14
  sub    %eax,%ebx
  cltq
  add    %rax,%r12
L26:
  test   %ebx,%ebx
  jle    L14
L87:
  movl   $0x1e,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    %rbp,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    %r13,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <select@plt>
  test   %eax,%eax
  js     L17
  jne    L88
  call   *%r14
  jmp    L26
L27:
  mov    0xc(%rsp),%ebx
L14:
  mov    0xc(%rsp),%eax
  sub    %ebx,%eax
L17:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _readn(register int fd, register char *ptr, register int nbytes, void (*timeout_function)(), int doselect) {
  int nleft, nread;
  int r;
  fd_set set;
  struct timeval ltspfs_timeout;
  struct timeval *timeout_ptr = &ltspfs_timeout;
  FD_ZERO(&set);
  FD_SET(fd, &set);
  if (!doselect)
    timeout_ptr = NULL;
  nleft = nbytes;
  while (nleft > 0) {
    ltspfs_timeout.tv_sec = 30;
    ltspfs_timeout.tv_usec = 0;
    r = select(FD_SETSIZE, &set, NULL, NULL, timeout_ptr);
    if (r < 0)
      return r;
    else if (r == 0)
      timeout_function();
    else {
      nread = read(fd, ptr, nleft);
      if (nread < 0)
        return (nread);
      else if (nread == 0)
        break;
      nleft -= nread;
      ptr += nread;
    }
  }
  return (nbytes - nleft);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_readn>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x48,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x1c(%rsp),%r12
  lea    0x20(%rsp),%rbp
  mov    %rcx,(%rsp)
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <FD_SET@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  cmove  %rax,%rbp
  test   %r14d,%r14d
  jle    L15
  mov    %r14d,%ebx
  mov    D1(%rip),%r14
  xchg   %ax,%ax
L20:
  mov    (%r14),%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%r8
  mov    %r12,%rsi
  movl   $0x1e,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  call   <select@plt>
  test   %eax,%eax
  js     L49
  jne    L0
  mov    (%rsp),%rcx
  xor    %eax,%eax
  call   *%rcx
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L49
  je     L43
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jg     L20
L43:
  mov    0xc(%rsp),%eax
  sub    %ebx,%eax
L49:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L84
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  xor    %eax,%eax
  jmp    L49
L84:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _readn(register int fd, register char *ptr, register int nbytes, void (*timeout_function)(), int doselect) {
  int nleft, nread;
  int r;
  fd_set set;
  struct timeval ltspfs_timeout;
  struct timeval *timeout_ptr = &ltspfs_timeout;
  FD_ZERO(&set);
  FD_SET(fd, &set);
  if (!doselect)
    timeout_ptr = NULL;
  nleft = nbytes;
  while (nleft > 0) {
    ltspfs_timeout.tv_sec = 30;
    ltspfs_timeout.tv_usec = 0;
    r = select(FD_SETSIZE, &set, NULL, NULL, timeout_ptr);
    if (r < 0)
      return r;
    else if (r == 0)
      timeout_function();
    else {
      nread = read(fd, ptr, nleft);
      if (nread < 0)
        return (nread);
      else if (nread == 0)
        break;
      nleft -= nread;
      ptr += nread;
    }
  }
  return (nbytes - nleft);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_readn>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  sub    $0x48,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x1c(%rsp),%r12
  lea    0x20(%rsp),%rbp
  mov    %rcx,(%rsp)
  mov    %r12,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <FD_ZERO@plt>
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <FD_SET@plt>
  xor    %eax,%eax
  test   %ebx,%ebx
  cmove  %rax,%rbp
  test   %r14d,%r14d
  jle    L76
  mov    %r14d,%ebx
  mov    D7(%rip),%r14
  xchg   %ax,%ax
L38:
  mov    (%r14),%edi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%r8
  mov    %r12,%rsi
  movl   $0x1e,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  call   <select@plt>
  test   %eax,%eax
  js     L18
  jne    L39
  mov    (%rsp),%rcx
  xor    %eax,%eax
  call   *%rcx
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L18
  je     L86
  sub    %eax,%ebx
  cltq
  add    %rax,%r13
  test   %ebx,%ebx
  jg     L38
L86:
  mov    0xc(%rsp),%eax
  sub    %ebx,%eax
L18:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L76:
  xor    %eax,%eax
  jmp    L18
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _readn(register int fd, register char *ptr, register int nbytes, void (*timeout_function)(), int doselect) {
  int nleft, nread;
  int r;
  fd_set set;
  struct timeval ltspfs_timeout;
  struct timeval *timeout_ptr = &ltspfs_timeout;
  FD_ZERO(&set);
  FD_SET(fd, &set);
  if (!doselect)
    timeout_ptr = NULL;
  nleft = nbytes;
  while (nleft > 0) {
    ltspfs_timeout.tv_sec = 30;
    ltspfs_timeout.tv_usec = 0;
    r = select(FD_SETSIZE, &set, NULL, NULL, timeout_ptr);
    if (r < 0)
      return r;
    else if (r == 0)
      timeout_function();
    else {
      nread = read(fd, ptr, nleft);
      if (nread < 0)
        return (nread);
      else if (nread == 0)
        break;
      nleft -= nread;
      ptr += nread;
    }
  }
  return (nbytes - nleft);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<smaunch_fs_save_database_compiled>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    $0x0,%eax
  call   <smaunch_fs_has_database@plt>
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <save_compiled_database@plt>
  leave
  ret
```

assistant: ```c
int smaunch_fs_save_database_compiled(const char *path) {
  assert(path);
  assert(smaunch_fs_has_database());
  return save_compiled_database(path);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smaunch_fs_save_database_compiled>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    $0x0,%eax
  call   <smaunch_fs_has_database@plt>
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <save_compiled_database@plt>
  pop    %rbx
  ret
```

assistant: ```c
int smaunch_fs_save_database_compiled(const char *path) {
  assert(path);
  assert(smaunch_fs_has_database());
  return save_compiled_database(path);
}
```
user: What is the c source code of the assembly code below?

```asm
<smaunch_fs_save_database_compiled>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  xor    %eax,%eax
  call   <smaunch_fs_has_database@plt>
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <save_compiled_database@plt>
```

assistant: ```c
int smaunch_fs_save_database_compiled(const char *path) {
  assert(path);
  assert(smaunch_fs_has_database());
  return save_compiled_database(path);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<smaunch_fs_save_database_compiled>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  xor    %eax,%eax
  call   <smaunch_fs_has_database@plt>
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1090 <save_compiled_database@plt>
```

assistant: ```c
int smaunch_fs_save_database_compiled(const char *path) {
  assert(path);
  assert(smaunch_fs_has_database());
  return save_compiled_database(path);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2CFIFODataPut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L0:
  mov    -0x8(%rbp),%rax
  add    $0xf08,%rax
  mov    (%rax),%rax
  and    $0x2,%eax
  test   %rax,%rax
  jne    L0
  mov    -0x8(%rbp),%rax
  add    $0xf00,%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void I2CFIFODataPut(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  while ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<I2CFIFODataPut>:
  endbr64
L3:
  mov    0xf08(%rdi),%rax
  test   $0x2,%al
  jne    L3
  mov    %rsi,0xf00(%rdi)
  ret
```

assistant: ```c
void I2CFIFODataPut(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  while ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<I2CFIFODataPut>:
  endbr64
  lea    0xf08(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  mov    (%rdx),%rax
  test   $0x2,%al
  jne    L7
  mov    %rsi,0xf00(%rdi)
  ret
```

assistant: ```c
void I2CFIFODataPut(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  while ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<I2CFIFODataPut>:
  endbr64
  lea    0xf08(%rdi),%rdx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rdx),%rax
  test   $0x2,%al
  jne    L2
  mov    %rsi,0xf00(%rdi)
  ret
```

assistant: ```c
void I2CFIFODataPut(uint32_t ui32Base, uint8_t ui8Data) {
  ;
  while ((*((volatile unsigned long *)(ui32Base + 0x00000F08))) & 0x00000002) {
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000F00))) = ui8Data;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strucmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  jmp    L49
L7:
  movzbl (%r12),%eax
  test   %al,%al
  je     L44
  movzbl (%rbx),%eax
  test   %al,%al
  je     L44
L49:
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <my_toupper@plt>
  mov    %eax,%r13d
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <my_toupper@plt>
  cmp    %eax,%r13d
  je     L7
L44:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L1
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L1
  mov    $0x0,%eax
  jmp    L18
L1:
  mov    $0x1,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
int strucmp(s, t)
register char *s, *t;
{
  while (my_toupper(*s++) == my_toupper(*t++))
    if (!*s || !*t)
      break;
  if (!*s && !*t)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strucmp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
L20:
  add    $0x1,%rbx
  movsbl -0x1(%rbx),%edi
  mov    $0x0,%eax
  call   <my_toupper@plt>
  mov    %eax,%r12d
  add    $0x1,%rbp
  movsbl -0x1(%rbp),%edi
  mov    $0x0,%eax
  call   <my_toupper@plt>
  cmp    %eax,%r12d
  jne    L19
  cmpb   $0x0,(%rbx)
  je     L25
  cmpb   $0x0,0x0(%rbp)
  jne    L20
  mov    $0x1,%eax
  jmp    L12
L19:
  mov    $0x1,%eax
  cmpb   $0x0,(%rbx)
  jne    L12
L25:
  cmpb   $0x0,0x0(%rbp)
  setne  %al
  movzbl %al,%eax
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strucmp(s, t)
register char *s, *t;
{
  while (my_toupper(*s++) == my_toupper(*t++))
    if (!*s || !*t)
      break;
  if (!*s && !*t)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strucmp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  movsbl (%rdi),%edi
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L31:
  movsbl (%r12),%edi
  test   %dil,%dil
  je     L10
  cmpb   $0x0,(%rbx)
  je     L4
L17:
  xor    %eax,%eax
  add    $0x1,%rbx
  add    $0x1,%r12
  call   <my_toupper@plt>
  movsbl -0x1(%rbx),%edi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <my_toupper@plt>
  cmp    %eax,%ebp
  je     L31
  cmpb   $0x0,(%r12)
  mov    $0x1,%eax
  jne    L1
L10:
  xor    %eax,%eax
  cmpb   $0x0,(%rbx)
  setne  %al
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strucmp(s, t)
register char *s, *t;
{
  while (my_toupper(*s++) == my_toupper(*t++))
    if (!*s || !*t)
      break;
  if (!*s && !*t)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strucmp>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L5
L3:
  cmpb   $0x0,(%rbx)
  je     L32
  cmpb   $0x0,0x0(%rbp)
  je     L1
L5:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  add    $0x1,%rbp
  add    $0x1,%rbx
  call   <my_toupper@plt>
  movsbl -0x1(%rbp),%edi
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <my_toupper@plt>
  cmp    %eax,%r12d
  je     L3
  cmpb   $0x0,(%rbx)
  je     L32
L1:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nop
L32:
  xor    %eax,%eax
  cmpb   $0x0,0x0(%rbp)
  pop    %rbx
  setne  %al
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int strucmp(s, t)
register char *s, *t;
{
  while (my_toupper(*s++) == my_toupper(*t++))
    if (!*s || !*t)
      break;
  if (!*s && !*t)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <even@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: %d

assistant: ```c
void main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", even(n));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <even@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string

tool: D9: %d

assistant: ```c
void main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", even(n));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <even@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: %d

assistant: ```c
void main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", even(n));
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <even@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
void main(void) {
  int n;
  scanf("%d", &n);
  printf("%d", even(n));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ncopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  cmp    %rdx,%rax
  cmova  %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t ncopy(char *dst, size_t dlen, char const *src, size_t slen) {
  assert(dlen > 0);
  size_t len = (dlen - 1 < slen) ? dlen - 1 : slen;
  memcpy(dst, src, len);
  dst[len] = '\0';
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ncopy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r13
  mov    %rcx,%r12
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  cmova  %r12,%rbx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t ncopy(char *dst, size_t dlen, char const *src, size_t slen) {
  assert(dlen > 0);
  size_t len = (dlen - 1 < slen) ? dlen - 1 : slen;
  memcpy(dst, src, len);
  dst[len] = '\0';
  return len;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ncopy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  sub    $0x1,%r12
  call   <assert@plt>
  cmp    %rbp,%r12
  mov    %r13,%rsi
  mov    %rbx,%rdi
  cmova  %rbp,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t ncopy(char *dst, size_t dlen, char const *src, size_t slen) {
  assert(dlen > 0);
  size_t len = (dlen - 1 < slen) ? dlen - 1 : slen;
  memcpy(dst, src, len);
  dst[len] = '\0';
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ncopy>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  test   %rsi,%rsi
  setne  %dil
  sub    $0x1,%r12
  call   <assert@plt>
  cmp    %rbp,%r12
  mov    %r13,%rsi
  mov    %rbx,%rdi
  cmova  %rbp,%r12
  mov    %r12,%rdx
  call   <memcpy@plt>
  movb   $0x0,(%rbx,%r12,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t ncopy(char *dst, size_t dlen, char const *src, size_t slen) {
  assert(dlen > 0);
  size_t len = (dlen - 1 < slen) ? dlen - 1 : slen;
  memcpy(dst, src, len);
  dst[len] = '\0';
  return len;
}
```