ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x1a0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movq   $0x7369,0xd0(%rsp)
  lea    0xd0(%rsp),%rbp
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0x190(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  movaps %xmm0,0x110(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm0,0x130(%rsp)
  movaps %xmm0,0x140(%rsp)
  movaps %xmm0,0x150(%rsp)
  movaps %xmm0,0x160(%rsp)
  movaps %xmm0,0x170(%rsp)
  movaps %xmm0,0x180(%rsp)
  jmp    L13
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strindex@plt>
  cmp    $0xffffffff,%eax
  jne    L23
L13:
  mov    $0xc8,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  test   %rax,%rax
  jne    L18
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x1a0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L13
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string

tool: D2: %s

assistant: ```c
int main(void) {
  char line[200];
  char pattern[200] = "is";
  while (getline(line, 200) != 0) {
    if (strindex(line, pattern) != -1) {
      printf("%s", line);
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<e_na_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  movss  %xmm0,-0x24(%rbp)
  mov    %edi,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L11:
  mov    -0x14(%rbp),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  movd   %xmm0,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <faktorijel@plt>
  movd   %ebx,%xmm1
  divss  %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L11
  movss  -0x18(%rbp),%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
float e_na_x(float x, int n) {
  float suma = 0;
  int i;
  for (i = 0; i <= n; i++) {
    suma += pow(x, i) / faktorijel(i);
  }
  return suma;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<e_na_x>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  test   %edi,%edi
  js     L7
  mov    %edi,%ebp
  mov    $0x0,%ebx
  pxor   %xmm3,%xmm3
  movss  %xmm3,0x4(%rsp)
L9:
  mov    %ebx,%edi
  movss  0xc(%rsp),%xmm0
  call   <pow@plt>
  movss  %xmm0,0x8(%rsp)
  mov    %ebx,%edi
  call   <faktorijel@plt>
  movaps %xmm0,%xmm1
  movss  0x8(%rsp),%xmm0
  divss  %xmm1,%xmm0
  addss  0x4(%rsp),%xmm0
  movss  %xmm0,0x4(%rsp)
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L9
L28:
  movss  0x4(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  pxor   %xmm4,%xmm4
  movss  %xmm4,0x4(%rsp)
  jmp    L28
```

assistant: ```c
float e_na_x(float x, int n) {
  float suma = 0;
  int i;
  for (i = 0; i <= n; i++) {
    suma += pow(x, i) / faktorijel(i);
  }
  return suma;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<e_na_x>:
  endbr64
  test   %edi,%edi
  js     L7
  push   %r14
  pxor   %xmm2,%xmm2
  movd   %xmm0,%r14d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  nopl   (%rax)
L16:
  mov    %ebx,%edi
  movd   %r14d,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <pow@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  movss  %xmm0,0x8(%rsp)
  call   <faktorijel@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  divss  %xmm0,%xmm1
  addss  %xmm1,%xmm2
  cmp    %ebx,%ebp
  jge    L16
  add    $0x10,%rsp
  movaps %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float e_na_x(float x, int n) {
  float suma = 0;
  int i;
  for (i = 0; i <= n; i++) {
    suma += pow(x, i) / faktorijel(i);
  }
  return suma;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<e_na_x>:
  endbr64
  test   %edi,%edi
  js     L8
  push   %r14
  pxor   %xmm2,%xmm2
  movd   %xmm0,%r14d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  nopl   (%rax)
L6:
  mov    %ebx,%edi
  movd   %r14d,%xmm0
  movss  %xmm2,0xc(%rsp)
  call   <pow@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  movss  %xmm0,0x8(%rsp)
  call   <faktorijel@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  divss  %xmm0,%xmm1
  addss  %xmm1,%xmm2
  cmp    %ebx,%ebp
  jge    L6
  add    $0x10,%rsp
  movaps %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float e_na_x(float x, int n) {
  float suma = 0;
  int i;
  for (i = 0; i <= n; i++) {
    suma += pow(x, i) / faktorijel(i);
  }
  return suma;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<not_ker>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  jg     L18
  mov    $0x1,%eax
  jmp    L58
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x69,%al
  jne    L32
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x6e,%al
  jne    L32
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x74,%al
  jne    L32
  mov    $0x0,%eax
  jmp    L58
L32:
  mov    $0x1,%eax
L58:
  pop    %rbp
  ret
```

assistant: ```c
int not_ker(s, i)
char *s;
int i;
{
  if (i < 3)
    return 1;
  if (s[i - 3] == 'i' && s[i - 2] == 'n' && s[i - 1] == 't')
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<not_ker>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%esi
  jle    L23
  movslq %esi,%rsi
  cmpb   $0x69,-0x3(%rdi,%rsi,1)
  je     L20
L23:
  ret
L20:
  cmpb   $0x6e,-0x2(%rdi,%rsi,1)
  jne    L23
  cmpb   $0x74,-0x1(%rdi,%rsi,1)
  setne  %al
  movzbl %al,%eax
  jmp    L23
```

assistant: ```c
int not_ker(s, i)
char *s;
int i;
{
  if (i < 3)
    return 1;
  if (s[i - 3] == 'i' && s[i - 2] == 'n' && s[i - 1] == 't')
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<not_ker>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%esi
  jle    L12
  movslq %esi,%rsi
  cmpb   $0x69,-0x3(%rdi,%rsi,1)
  je     L28
L12:
  ret
  nopl   0x0(%rax)
L28:
  cmpb   $0x6e,-0x2(%rdi,%rsi,1)
  jne    L12
  xor    %eax,%eax
  cmpb   $0x74,-0x1(%rdi,%rsi,1)
  setne  %al
  ret
```

assistant: ```c
int not_ker(s, i)
char *s;
int i;
{
  if (i < 3)
    return 1;
  if (s[i - 3] == 'i' && s[i - 2] == 'n' && s[i - 1] == 't')
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<not_ker>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x2,%esi
  jle    L13
  movslq %esi,%rsi
  cmpb   $0x69,-0x3(%rdi,%rsi,1)
  je     L5
L13:
  ret
  nopl   0x0(%rax)
L5:
  cmpb   $0x6e,-0x2(%rdi,%rsi,1)
  jne    L13
  xor    %eax,%eax
  cmpb   $0x74,-0x1(%rdi,%rsi,1)
  setne  %al
  ret
```

assistant: ```c
int not_ker(s, i)
char *s;
int i;
{
  if (i < 3)
    return 1;
  if (s[i - 3] == 'i' && s[i - 2] == 'n' && s[i - 1] == 't')
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x220(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L51
L38:
  addl   $0x1,-0x220(%rbp)
L51:
  lea    -0x210(%rbp),%rdx
  mov    -0x220(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L38
  mov    -0x210(%rbp),%eax
  mov    %eax,-0x21c(%rbp)
  movl   $0x0,-0x218(%rbp)
  movl   $0x0,-0x214(%rbp)
  jmp    L0
L29:
  mov    -0x214(%rbp),%eax
  cltq
  mov    -0x210(%rbp,%rax,4),%eax
  add    %eax,-0x218(%rbp)
  mov    -0x218(%rbp),%eax
  cmp    -0x21c(%rbp),%eax
  jle    L19
  mov    -0x218(%rbp),%eax
  mov    %eax,-0x21c(%rbp)
  jmp    L26
L19:
  cmpl   $0x0,-0x218(%rbp)
  jns    L26
  movl   $0x0,-0x218(%rbp)
L26:
  addl   $0x1,-0x214(%rbp)
L0:
  mov    -0x214(%rbp),%eax
  cmp    -0x220(%rbp),%eax
  jl     L29
  mov    -0x21c(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D28
datatype: string
name: parse_data
arguments: label: D29
datatype: string
name: parse_data
arguments: label: D0
datatype: string

tool: D28: pls input some integers('#' to terminate): 

tool: D29: %d

tool: D0: max sub-array's sum: %d


assistant: ```c
int main(void) {
  int a[128];
  int len = 0;
  printf("pls input some"
         " integers('#' to terminate): ");
  while (scanf("%d", &a[len]) != 0)
    len++;
  int max = a[0], sum = 0;
  int i;
  for (i = 0; i < len; i++) {
    sum += a[i];
    if (sum > max)
      max = sum;
    else if (sum < 0)
      sum = 0;
  }
  printf("max sub-array's sum: %d\n", max);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rbp
  mov    $0x0,%r12d
  lea    D24(%rip),%r13
  jmp    L64
L35:
  add    $0x1,%r12d
L64:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x4,%rbp
  test   %rax,%rax
  jne    L35
  mov    (%rsp),%esi
  test   %r12d,%r12d
  jle    L31
  lea    -0x1(%r12),%eax
  lea    0x4(%rbx,%rax,4),%rcx
  mov    $0x0,%edx
  jmp    L33
L27:
  mov    %eax,%esi
L76:
  add    $0x4,%rbx
  cmp    %rcx,%rbx
  je     L31
L33:
  mov    %edx,%eax
  add    (%rbx),%eax
  mov    %eax,%edx
  cmp    %esi,%eax
  jg     L27
  test   %eax,%eax
  mov    $0x0,%edx
  cmovns %eax,%edx
  jmp    L76
L31:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D24
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string

tool: D8: pls input some integers('#' to terminate): 

tool: D24: %d

tool: D2: max sub-array's sum: %d


assistant: ```c
int main(void) {
  int a[128];
  int len = 0;
  printf("pls input some"
         " integers('#' to terminate): ");
  while (scanf("%d", &a[len]) != 0)
    len++;
  int max = a[0], sum = 0;
  int i;
  for (i = 0; i < len; i++) {
    sum += a[i];
    if (sum > max)
      max = sum;
    else if (sum < 0)
      sum = 0;
  }
  printf("max sub-array's sum: %d\n", max);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%rdi
  lea    D12(%rip),%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rbx
  call   <printf@plt>
  jmp    L42
  nopl   0x0(%rax)
L77:
  add    $0x1,%ebp
L42:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  test   %rax,%rax
  jne    L77
  mov    (%rsp),%ecx
  test   %ebp,%ebp
  je     L81
  lea    -0x1(%rbp),%eax
  lea    0x4(%rsp),%rdx
  mov    %ecx,%esi
  lea    0x4(%r12,%rax,4),%rdi
  xor    %eax,%eax
  jmp    L26
  nopl   0x0(%rax)
L33:
  xor    %ecx,%ecx
  test   %eax,%eax
  cmovs  %ecx,%eax
  cmp    %rdi,%rdx
  je     L3
L29:
  mov    (%rdx),%ecx
  add    $0x4,%rdx
L26:
  add    %ecx,%eax
  cmp    %esi,%eax
  jle    L33
  mov    %eax,%esi
  cmp    %rdi,%rdx
  jne    L29
L3:
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L81:
  mov    %ecx,%esi
  jmp    L3
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string
name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D0: pls input some integers('#' to terminate): 

tool: D12: %d

tool: D6: max sub-array's sum: %d


assistant: ```c
int main(void) {
  int a[128];
  int len = 0;
  printf("pls input some"
         " integers('#' to terminate): ");
  while (scanf("%d", &a[len]) != 0)
    len++;
  int max = a[0], sum = 0;
  int i;
  for (i = 0; i < len; i++) {
    sum += a[i];
    if (sum > max)
      max = sum;
    else if (sum < 0)
      sum = 0;
  }
  printf("max sub-array's sum: %d\n", max);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D8(%rip),%rdi
  lea    D24(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rbx
  call   <printf@plt>
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x1,%r12d
L38:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  test   %rax,%rax
  jne    L40
  mov    (%rsp),%esi
  test   %r12d,%r12d
  je     L7
  lea    -0x1(%r12),%eax
  lea    0x4(%rbp),%rdx
  lea    (%rdx,%rax,4),%rcx
  xor    %eax,%eax
  jmp    L70
  nopl   0x0(%rax)
L55:
  xor    %edi,%edi
  test   %eax,%eax
  mov    %rdx,%rbp
  cmovs  %edi,%eax
  cmp    %rcx,%rdx
  je     L7
L11:
  add    $0x4,%rdx
L70:
  add    0x0(%rbp),%eax
  cmp    %eax,%esi
  jge    L55
  mov    %eax,%esi
  mov    %rdx,%rbp
  cmp    %rcx,%rdx
  jne    L11
L7:
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x218,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D24
data_type: string
name: parse_data
arguments: data_tag: D22
data_type: string

tool: D8: pls input some integers('#' to terminate): 

tool: D24: %d

tool: D22: max sub-array's sum: %d


assistant: ```c
int main(void) {
  int a[128];
  int len = 0;
  printf("pls input some"
         " integers('#' to terminate): ");
  while (scanf("%d", &a[len]) != 0)
    len++;
  int max = a[0], sum = 0;
  int i;
  for (i = 0; i < len; i++) {
    sum += a[i];
    if (sum > max)
      max = sum;
    else if (sum < 0)
      sum = 0;
  }
  printf("max sub-array's sum: %d\n", max);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strspn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <__get_array_size@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <__get_array_size@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  js     L9
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L13
L9:
  jmp    L9
L13:
  mov    -0xc(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  int size_s1;
  int size_s2;
  int res;
  res = __infer_nondet_int();
  size_s1 = __get_array_size(s1);
  size_s2 = __get_array_size(s2);
  if (res < 0 || res > size_s1)
    while (1)
      ;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strspn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <__infer_nondet_int@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <__get_array_size@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <__get_array_size@plt>
  test   %ebx,%ebx
  js     L14
  cmp    %r12d,%ebx
  jg     L14
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  jmp    L14
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  int size_s1;
  int size_s2;
  int res;
  res = __infer_nondet_int();
  size_s1 = __get_array_size(s1);
  size_s2 = __get_array_size(s2);
  if (res < 0 || res > size_s1)
    while (1)
      ;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strspn>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <__infer_nondet_int@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <__get_array_size@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <__get_array_size@plt>
  test   %ebx,%ebx
  js     L23
  cmp    %r12d,%ebx
  jg     L23
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  jmp    L23
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  int size_s1;
  int size_s2;
  int res;
  res = __infer_nondet_int();
  size_s1 = __get_array_size(s1);
  size_s2 = __get_array_size(s2);
  if (res < 0 || res > size_s1)
    while (1)
      ;
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strspn>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <__infer_nondet_int@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <__get_array_size@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <__get_array_size@plt>
  test   %ebx,%ebx
  js     L3
  cmp    %r12d,%ebx
  jg     L3
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  jmp    L3
```

assistant: ```c
size_t strspn(const char *s1, const char *s2) {
  int size_s1;
  int size_s2;
  int res;
  res = __infer_nondet_int();
  size_s1 = __get_array_size(s1);
  size_s2 = __get_array_size(s2);
  if (res < 0 || res > size_s1)
    while (1)
      ;
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toupper_fast>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L13
  cmpl   $0x7a,-0x4(%rbp)
  jg     L13
  subl   $0x20,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int toupper_fast(int c) {
  if ((c >= 'a') && (c <= 'z'))
    c = c - ('a' - 'A');
  return c;
}
```
user: What is the c source code of the assembly code below:

```asm
<toupper_fast>:
  endbr64
  mov    %edi,%eax
  lea    -0x61(%rdi),%ecx
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper_fast(int c) {
  if ((c >= 'a') && (c <= 'z'))
    c = c - ('a' - 'A');
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toupper_fast>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper_fast(int c) {
  if ((c >= 'a') && (c <= 'z'))
    c = c - ('a' - 'A');
  return c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<toupper_fast>:
  endbr64
  lea    -0x61(%rdi),%ecx
  mov    %edi,%eax
  lea    -0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int toupper_fast(int c) {
  if ((c >= 'a') && (c <= 'z'))
    c = c - ('a' - 'A');
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<driver_get_window_class>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  lea    D0(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D0: UNIMPLEMENTED

assistant: ```c
char *driver_get_window_class(void *handle) {
  static char class[256];
  return "UNIMPLEMENTED";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<driver_get_window_class>:
  endbr64
  lea    D7(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: UNIMPLEMENTED

assistant: ```c
char *driver_get_window_class(void *handle) {
  static char class[256];
  return "UNIMPLEMENTED";
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<driver_get_window_class>:
  endbr64
  lea    D3(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: UNIMPLEMENTED

assistant: ```c
char *driver_get_window_class(void *handle) {
  static char class[256];
  return "UNIMPLEMENTED";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<driver_get_window_class>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: UNIMPLEMENTED

assistant: ```c
char *driver_get_window_class(void *handle) {
  static char class[256];
  return "UNIMPLEMENTED";
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<list_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <list_del@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <list_add_after@plt>
  nop
  leave
  ret
```

assistant: ```c
void list_move(struct list_head *head, struct list_head *list) {
  list_del(list);
  list_add_after(head, list);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<list_move>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <list_del@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <list_add_after@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void list_move(struct list_head *head, struct list_head *list) {
  list_del(list);
  list_add_after(head, list);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<list_move>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <list_del@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <list_add_after@plt>
```

assistant: ```c
void list_move(struct list_head *head, struct list_head *list) {
  list_del(list);
  list_add_after(head, list);
}
```
user: Translate the below assembly code into C programming language:

```asm
<list_move>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <list_del@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <list_add_after@plt>
```

assistant: ```c
void list_move(struct list_head *head, struct list_head *list) {
  list_del(list);
  list_add_after(head, list);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stress_mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int stress_mkdir(const int dir_fd, const char *path, const int mode) {
  int ret;
  ret = mkdir(path, mode);
  (void)dir_fd;
  return ret;
}
```