ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_refc_string>:
  endbr64
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L16
  mov    %rsi,%rdx
  mov    -0x4(%rsi),%ecx
  lea    D13(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
L6:
  add    $0x8,%rsp
  ret
L16:
  mov    %rdi,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <fwrite@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string

tool: D13: %s : %d

tool: D3: <NULL>

assistant: ```c
void print_refc_string(FILE *output, char *obj) {
  if (obj) {
    fprintf(output, "%s : %d", obj, (*(int *)((void *)(((int *)obj) - 1))));
  } else {
    fprintf(output, "<NULL>");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_refc_string>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L1
  mov    -0x4(%rsi),%ecx
  xor    %eax,%eax
  lea    D12(%rip),%rsi
  jmp    1060 <fprintf@plt>
  nopl   (%rax)
L1:
  mov    %rdi,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D14(%rip),%rdi
  jmp    1070 <fwrite@plt>
```

tool_calls: name: parse_data
arguments: data_label: D12
type_infered: string
name: parse_data
arguments: data_label: D14
type_infered: string

tool: D12: %s : %d

tool: D14: <NULL>

assistant: ```c
void print_refc_string(FILE *output, char *obj) {
  if (obj) {
    fprintf(output, "%s : %d", obj, (*(int *)((void *)(((int *)obj) - 1))));
  } else {
    fprintf(output, "<NULL>");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_refc_string>:
  endbr64
  mov    %rsi,%rdx
  test   %rsi,%rsi
  je     L0
  mov    -0x4(%rsi),%ecx
  xor    %eax,%eax
  lea    D10(%rip),%rsi
  jmp    1060 <fprintf@plt>
  nopl   (%rax)
L0:
  mov    %rdi,%rcx
  mov    $0x6,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D1
type: string

tool: D10: %s : %d

tool: D1: <NULL>

assistant: ```c
void print_refc_string(FILE *output, char *obj) {
  if (obj) {
    fprintf(output, "%s : %d", obj, (*(int *)((void *)(((int *)obj) - 1))));
  } else {
    fprintf(output, "<NULL>");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ustrneq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L36
L13:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L39
  mov    $0x0,%eax
  jmp    L14
L39:
  addq   $0x1,-0x8(%rbp)
L36:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L18
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L18
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
L18:
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t ustrneq(const char *string1, const char *string2, uint8_t n) {
  uint8_t utz_i;
  for (utz_i = 0; utz_i < n && string1[utz_i] != '\0' && string2[utz_i] != '\0'; utz_i++) {
    if (string1[utz_i] != string2[utz_i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ustrneq>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L30
L16:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  je     L22
  movzbl (%rsi,%rax,1),%r8d
  test   %r8b,%r8b
  je     L26
  cmp    %r8b,%cl
  jne    L2
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L16
  mov    $0x1,%eax
  ret
L30:
  mov    $0x1,%eax
  ret
L26:
  mov    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
L22:
  mov    $0x1,%eax
  ret
```

assistant: ```c
uint8_t ustrneq(const char *string1, const char *string2, uint8_t n) {
  uint8_t utz_i;
  for (utz_i = 0; utz_i < n && string1[utz_i] != '\0' && string2[utz_i] != '\0'; utz_i++) {
    if (string1[utz_i] != string2[utz_i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ustrneq>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L46
  jmp    L30
  nopl   (%rax)
L22:
  movzbl (%rsi,%rax,1),%r8d
  test   %r8b,%r8b
  je     L30
  cmp    %r8b,%cl
  jne    L54
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L30
L46:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L22
L30:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L54:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t ustrneq(const char *string1, const char *string2, uint8_t n) {
  uint8_t utz_i;
  for (utz_i = 0; utz_i < n && string1[utz_i] != '\0' && string2[utz_i] != '\0'; utz_i++) {
    if (string1[utz_i] != string2[utz_i]) {
      return 0;
    }
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<ustrneq>:
  endbr64
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L46
  jmp    L41
  nopl   (%rax)
L50:
  movzbl (%rsi,%rax,1),%r8d
  test   %r8b,%r8b
  je     L41
  cmp    %r8b,%cl
  jne    L3
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L41
L46:
  movzbl (%rdi,%rax,1),%ecx
  test   %cl,%cl
  jne    L50
L41:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t ustrneq(const char *string1, const char *string2, uint8_t n) {
  uint8_t utz_i;
  for (utz_i = 0; utz_i < n && string1[utz_i] != '\0' && string2[utz_i] != '\0'; utz_i++) {
    if (string1[utz_i] != string2[utz_i]) {
      return 0;
    }
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_capture_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int _capture_pos(int w, int x, int y) {
  int pos = 0;
  pos = y * (w + 1) + x;
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_capture_pos>:
  endbr64
  add    $0x1,%edi
  imul   %edx,%edi
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int _capture_pos(int w, int x, int y) {
  int pos = 0;
  pos = y * (w + 1) + x;
  return pos;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_capture_pos>:
  endbr64
  add    $0x1,%edi
  imul   %edx,%edi
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int _capture_pos(int w, int x, int y) {
  int pos = 0;
  pos = y * (w + 1) + x;
  return pos;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_capture_pos>:
  endbr64
  add    $0x1,%edi
  imul   %edx,%edi
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int _capture_pos(int w, int x, int y) {
  int pos = 0;
  pos = y * (w + 1) + x;
  return pos;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<HuffmanCodeLengthsToCodes>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  mov    %esi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  movaps %xmm0,(%rsp)
  setne  %dil
  movaps %xmm0,0x10(%rsp)
  movzbl %dil,%edi
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <assert@plt>
  xor    %edi,%edi
  test   %r12d,%r12d
  setg   %dil
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  test   %r12d,%r12d
  jle    L19
  lea    -0x1(%r12),%eax
  mov    %rbx,%rsi
  xor    %edx,%edx
  lea    0x4(%rbx,%rax,4),%rdi
  mov    %rbx,%rax
  nopl   (%rax)
L0:
  movslq (%rax),%rcx
  cmp    %ecx,%edx
  cmovl  %rcx,%rdx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L0
  xor    %eax,%eax
  cmp    $0xf,%edx
  jg     L93
  nopl   (%rax)
L57:
  movslq (%rsi),%rax
  add    $0x4,%rsi
  addl   $0x1,(%rsp,%rax,4)
  cmp    %rdi,%rsi
  jne    L57
  movl   $0x0,(%rsp)
  movl   $0xffffffff,0x40(%rsp)
  test   %edx,%edx
  je     L74
  mov    $0x1,%ecx
  xor    %esi,%esi
  lea    0x40(%rsp),%rdi
  xor    %eax,%eax
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L41:
  mov    (%rsp,%rcx,4),%esi
  add    $0x1,%rcx
L66:
  add    %esi,%eax
  add    %eax,%eax
  mov    %eax,(%rdi,%rcx,4)
  cmp    %rcx,%rdx
  jne    L41
L74:
  mov    %r12d,%r12d
  xor    %eax,%eax
L9:
  movslq (%rbx,%rax,4),%rdx
  mov    $0xffffffff,%ecx
  test   %edx,%edx
  jle    L8
  mov    0x40(%rsp,%rdx,4),%ecx
  lea    0x1(%rcx),%esi
  mov    %esi,0x40(%rsp,%rdx,4)
L8:
  mov    %ecx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    %r12,%rax
  jne    L9
L19:
  mov    $0x1,%eax
L93:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int HuffmanCodeLengthsToCodes(const int *const code_lengths, int code_lengths_size, int *const huff_codes) {
  int symbol;
  int code_len;
  int code_length_hist[15 + 1] = {0};
  int curr_code;
  int next_codes[15 + 1] = {0};
  int max_code_length = 0;
  assert(code_lengths != NULL);
  assert(code_lengths_size > 0);
  assert(huff_codes != NULL);
  for (symbol = 0; symbol < code_lengths_size; ++symbol) {
    if (code_lengths[symbol] > max_code_length) {
      max_code_length = code_lengths[symbol];
    }
  }
  if (max_code_length > 15)
    return 0;
  for (symbol = 0; symbol < code_lengths_size; ++symbol) {
    ++code_length_hist[code_lengths[symbol]];
  }
  code_length_hist[0] = 0;
  curr_code = 0;
  next_codes[0] = -1;
  for (code_len = 1; code_len <= max_code_length; ++code_len) {
    curr_code = (curr_code + code_length_hist[code_len - 1]) << 1;
    next_codes[code_len] = curr_code;
  }
  for (symbol = 0; symbol < code_lengths_size; ++symbol) {
    if (code_lengths[symbol] > 0) {
      huff_codes[symbol] = next_codes[code_lengths[symbol]]++;
    } else {
      huff_codes[symbol] = (-1);
    }
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L23
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  imul   %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    $0x1,%rdx
  imul   %rdx,%rax
  mov    -0x18(%rbp),%rdx
  add    $0x1,%rdx
  imul   %rdx,%rax
  lea    0x3(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L4
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string
name: unpack_data
arguments: tag: D1
type: string

tool: D0: %lld


tool: D1: %lld

assistant: ```c
int main() {
  long long int a, b;
  while (scanf("%lld", &a) == 1) {
    b = a * a * (a + 1) * (a + 1) / 4;
    printf("%lld\n", b);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D10(%rip),%rbx
  lea    D18(%rip),%r12
  jmp    L12
L13:
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  imul   %rdx,%rax
  imul   %rax,%rax
  lea    0x3(%rax),%rsi
  test   %rax,%rax
  cmovns %rax,%rsi
  sar    $0x2,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D18
type_infered: string

tool: D10: %lld

tool: D18: %lld


assistant: ```c
int main() {
  long long int a, b;
  while (scanf("%lld", &a) == 1) {
    b = a * a * (a + 1) * (a + 1) / 4;
    printf("%lld\n", b);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D3(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L5
  nop
L19:
  mov    (%rsp),%rax
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  imul   %rdx,%rax
  imul   %rax,%rax
  test   %rax,%rax
  lea    0x3(%rax),%rsi
  cmovns %rax,%rsi
  sar    $0x2,%rsi
  call   <printf@plt>
L5:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L19
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D7: %lld


tool: D3: %lld

assistant: ```c
int main() {
  long long int a, b;
  while (scanf("%lld", &a) == 1) {
    b = a * a * (a + 1) * (a + 1) / 4;
    printf("%lld\n", b);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D17(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L6
  nop
L22:
  mov    (%rsp),%rax
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  imul   %rdx,%rax
  imul   %rax,%rax
  test   %rax,%rax
  lea    0x3(%rax),%rsi
  cmovns %rax,%rsi
  sar    $0x2,%rsi
  call   <printf@plt>
L6:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L22
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D19: %lld


tool: D17: %lld

assistant: ```c
int main() {
  long long int a, b;
  while (scanf("%lld", &a) == 1) {
    b = a * a * (a + 1) * (a + 1) / 4;
    printf("%lld\n", b);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PIOINT3_IRQHandler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <gpioIntStatus@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <gpioIntClear@plt>
  nop
L7:
  nop
  leave
  ret
```

assistant: ```c
void PIOINT3_IRQHandler(void) {
  uint32_t regVal;
  regVal = gpioIntStatus(3, 1);
  if (regVal) {
    gpioIntClear(3, 1);
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PIOINT3_IRQHandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <gpioIntStatus@plt>
  test   %rax,%rax
  jne    L6
L17:
  add    $0x8,%rsp
  ret
L6:
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <gpioIntClear@plt>
  jmp    L17
```

assistant: ```c
void PIOINT3_IRQHandler(void) {
  uint32_t regVal;
  regVal = gpioIntStatus(3, 1);
  if (regVal) {
    gpioIntClear(3, 1);
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PIOINT3_IRQHandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <gpioIntStatus@plt>
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  mov    $0x1,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1070 <gpioIntClear@plt>
```

assistant: ```c
void PIOINT3_IRQHandler(void) {
  uint32_t regVal;
  regVal = gpioIntStatus(3, 1);
  if (regVal) {
    gpioIntClear(3, 1);
  }
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<PIOINT3_IRQHandler>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x3,%edi
  call   <gpioIntStatus@plt>
  test   %rax,%rax
  jne    L5
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x1,%esi
  mov    $0x3,%edi
  add    $0x8,%rsp
  jmp    1070 <gpioIntClear@plt>
```

assistant: ```c
void PIOINT3_IRQHandler(void) {
  uint32_t regVal;
  regVal = gpioIntStatus(3, 1);
  if (regVal) {
    gpioIntClear(3, 1);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cfgReadFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %rdi,-0x238(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x224(%rbp)
  mov    -0x238(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x218(%rbp)
  mov    $0x0,%eax
  call   <cfgReset@plt>
  cmpq   $0x0,-0x218(%rbp)
  je     L41
  jmp    L108
L32:
  lea    -0x210(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,-0x210(%rbp,%rax,1)
  movzbl -0x210(%rbp),%eax
  test   %al,%al
  je     L108
  movzbl -0x210(%rbp),%eax
  cmp    $0x3b,%al
  je     L108
  movzbl -0x210(%rbp),%eax
  cmp    $0x23,%al
  je     L108
  lea    -0x210(%rbp),%rax
  mov    %rax,-0x220(%rbp)
  jmp    L94
L8:
  addq   $0x1,-0x220(%rbp)
L94:
  mov    -0x220(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L79
  mov    -0x220(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  jne    L8
L79:
  mov    -0x220(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L108
  mov    -0x220(%rbp),%rax
  movb   $0x0,(%rax)
  addq   $0x1,-0x220(%rbp)
  mov    -0x220(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L108
  mov    -0x220(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <cfgAddOption@plt>
  addl   $0x1,-0x224(%rbp)
L108:
  mov    -0x218(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L32
  mov    -0x218(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
L41:
  mov    -0x224(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: r

assistant: ```c
int cfgReadFile(char *pszFile) {
  int i = 0;
  FILE *f = fopen(pszFile, "r");
  char szBuffer[512];
  cfgReset();
  if (f != NULL) {
    while (fgets(szBuffer, sizeof(szBuffer), f)) {
      szBuffer[strlen(szBuffer) - 1] = 0;
      if (*szBuffer && *szBuffer != ';' && *szBuffer != '#') {
        char *pszSplit = szBuffer;
        while (*pszSplit && *pszSplit != '=') {
          ++pszSplit;
        }
        if (*pszSplit) {
          *pszSplit = 0;
          ++pszSplit;
          if (*pszSplit) {
            cfgAddOption(szBuffer, pszSplit);
            ++i;
          }
        }
      }
    }
    fclose(f);
  }
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cfgReadFile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <cfgReset@plt>
  mov    $0x0,%r12d
  movabs $0x800000800000001,%rbp
  test   %rbx,%rbx
  je     L103
L86:
  mov    %rsp,%rdi
  mov    %rbx,%rdx
  mov    $0x200,%esi
  call   <fgets@plt>
  test   %rax,%rax
  je     L78
  mov    %rsp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  movzbl (%rsp),%eax
  cmp    $0x3b,%al
  ja     L102
  bt     %rax,%rbp
  jb     L86
  mov    %rsp,%rsi
  jmp    L67
L78:
  mov    %rbx,%rdi
  call   <fclose@plt>
L103:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    %r12d,%eax
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L102:
  mov    %rsp,%rsi
  cmp    $0x3d,%al
  je     L21
L67:
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  test   %al,%al
  je     L25
  cmp    $0x3d,%al
  jne    L67
L25:
  test   %al,%al
  je     L86
L21:
  movb   $0x0,(%rsi)
  cmpb   $0x0,0x1(%rsi)
  je     L86
  add    $0x1,%rsi
  mov    %rsp,%rdi
  call   <cfgAddOption@plt>
  add    $0x1,%r12d
  jmp    L86
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: r

assistant: ```c
int cfgReadFile(char *pszFile) {
  int i = 0;
  FILE *f = fopen(pszFile, "r");
  char szBuffer[512];
  cfgReset();
  if (f != NULL) {
    while (fgets(szBuffer, sizeof(szBuffer), f)) {
      szBuffer[strlen(szBuffer) - 1] = 0;
      if (*szBuffer && *szBuffer != ';' && *szBuffer != '#') {
        char *pszSplit = szBuffer;
        while (*pszSplit && *pszSplit != '=') {
          ++pszSplit;
        }
        if (*pszSplit) {
          *pszSplit = 0;
          ++pszSplit;
          if (*pszSplit) {
            cfgAddOption(szBuffer, pszSplit);
            ++i;
          }
        }
      }
    }
    fclose(f);
  }
  return (i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cfgReadFile>:
  endbr64
  push   %r13
  lea    D2(%rip),%rsi
  xor    %r13d,%r13d
  push   %r12
  movabs $0xf7fffff7fffffffe,%r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  call   <fopen@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <cfgReset@plt>
  test   %rbp,%rbp
  je     L100
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %rbp,%rdx
  mov    $0x200,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L66
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  movzbl (%rsp),%eax
  cmp    $0x3b,%al
  jbe    L37
  mov    %rbx,%rsi
  cmp    $0x3d,%al
  je     L51
L2:
  movzbl 0x1(%rsi),%eax
  add    $0x1,%rsi
  test   %al,%al
  je     L73
  cmp    $0x3d,%al
  jne    L2
  test   %al,%al
  je     L73
L51:
  cmpb   $0x0,0x1(%rsi)
  movb   $0x0,(%rsi)
  je     L73
  add    $0x1,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r13d
  call   <cfgAddOption@plt>
  jmp    L73
  nopl   0x0(%rax)
L37:
  bt     %rax,%r12
  jae    L73
  mov    %rbx,%rsi
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %rbp,%rdi
  call   <fclose@plt>
L100:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  add    $0x218,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_infered: string

tool: D2: r

assistant: ```c
int cfgReadFile(char *pszFile) {
  int i = 0;
  FILE *f = fopen(pszFile, "r");
  char szBuffer[512];
  cfgReset();
  if (f != NULL) {
    while (fgets(szBuffer, sizeof(szBuffer), f)) {
      szBuffer[strlen(szBuffer) - 1] = 0;
      if (*szBuffer && *szBuffer != ';' && *szBuffer != '#') {
        char *pszSplit = szBuffer;
        while (*pszSplit && *pszSplit != '=') {
          ++pszSplit;
        }
        if (*pszSplit) {
          *pszSplit = 0;
          ++pszSplit;
          if (*pszSplit) {
            cfgAddOption(szBuffer, pszSplit);
            ++i;
          }
        }
      }
    }
    fclose(f);
  }
  return (i);
}
```