ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printInterruptxInfo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D21(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    D8(%rip),%rsi
  lea    0x4(%rsp),%rdx
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D4(%rip),%rdi
  call   <output@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D21
datatype: string
name: read_data
arguments: data_label: D8
datatype: string
name: read_data
arguments: data_label: D4
datatype: string

tool: D21: cpu/interrupt/int

tool: D8: %d

tool: D4: Interrupt %d	0	0	1/s


assistant: ```c
void printInterruptxInfo(const char *cmd) {
  int id;
  sscanf(cmd + strlen("cpu/interrupt/int"), "%d", &id);
  output("Interrupt %d\t0\t0\t1/s\n", id);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printInterruptxInfo>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D11(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    D29(%rip),%rsi
  lea    0x4(%rsp),%rdx
  cltq
  lea    (%rbx,%rax,1),%rdi
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  call   <output@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D11
datatype: string
name: disassemble_data
arguments: tag: D29
datatype: string
name: disassemble_data
arguments: tag: D27
datatype: string

tool: D11: cpu/interrupt/int

tool: D29: %d

tool: D27: Interrupt %d	0	0	1/s


assistant: ```c
void printInterruptxInfo(const char *cmd) {
  int id;
  sscanf(cmd + strlen("cpu/interrupt/int"), "%d", &id);
  output("Interrupt %d\t0\t0\t1/s\n", id);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L6:
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x2,-0xc(%rbp)
  jle    L6
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D22
type: string
name: unpack_data
arguments: label: D12
type: string
name: unpack_data
arguments: label: D16
type: string

tool: D22: rampf

tool: D12: # c::%s


tool: D16: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "rampf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
  lea    D18(%rip),%r12
  lea    D5(%rip),%rbp
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string
name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D4: rampf

tool: D18: # c::%s


tool: D5: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "rampf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D14(%rip),%r13
  push   %r12
  lea    D21(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D11
type_guessed: string

tool: D14: rampf

tool: D21: # c::%s


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "rampf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D6(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D2
type: string
name: unpack_data
arguments: label: D11
type: string

tool: D6: rampf

tool: D2: # c::%s


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "rampf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <prime@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  prime();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <prime@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  prime();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <prime@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  prime();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<syscon_dobldobl_drop_variable_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L35:
  cmp    %rdx,%rsp
  je     L39
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L39:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L0
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L0:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L34
L45:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x28(%rbp),%rax
  mov    -0x38(%rbp),%edx
  movslq %edx,%rdx
  mov    %ecx,(%rax,%rdx,4)
  addl   $0x1,-0x38(%rbp)
L34:
  mov    -0x44(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  jl     L45
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  lea    -0x44(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x136,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %rbx,%rsp
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int syscon_dobldobl_drop_variable_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(310, &nc, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<syscon_dobldobl_drop_variable_by_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%ecx
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffffff0,%rdi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L44:
  cmp    %rdx,%rsp
  je     L6
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L44
L6:
  mov    %rdi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L35
  orq    $0x0,-0x8(%rsp,%rax,1)
L35:
  mov    %rsp,%rdi
  test   %ecx,%ecx
  jle    L28
  mov    %ecx,%ecx
  mov    $0x0,%eax
L49:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L49
L28:
  lea    -0x14(%rbp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    %rdi,%rdx
  mov    $0x136,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  leave
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int syscon_dobldobl_drop_variable_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(310, &nc, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<syscon_dobldobl_drop_variable_by_name>:
  endbr64
  push   %rbp
  movslq %edi,%rcx
  mov    %rcx,%rdx
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsp,%r8
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rcx,4),%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rax
  sub    %rax,%r8
  and    $0xfffffffffffffff0,%rdi
  cmp    %r8,%rsp
  je     L38
L44:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r8,%rsp
  jne    L44
L38:
  and    $0xfff,%edi
  sub    %rdi,%rsp
  test   %rdi,%rdi
  jne    L20
L24:
  mov    %rsp,%r9
  test   %edx,%edx
  jle    L51
  xor    %eax,%eax
L67:
  movsbl (%rsi,%rax,1),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L67
L51:
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %r9,%rdx
  mov    $0x136,%edi
  lea    -0x14(%rbp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L61
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  orq    $0x0,-0x8(%rsp,%rdi,1)
  jmp    L24
L61:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int syscon_dobldobl_drop_variable_by_name(int nc, char *s) {
  int fail, i;
  int b[nc];
  double *c;
  for (i = 0; i < nc; i++)
    b[i] = (int)s[i];
  fail = _ada_use_c2phc4c(310, &nc, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<g_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L58
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
L58:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L46
L53:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  subq   $0x1,-0x10(%rbp)
L46:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L20
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L53
  jmp    L20
L31:
  mov    -0x10(%rbp),%rdx
  lea    -0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L20:
  mov    -0x10(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L31
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int g_char(char *a, int alen, char *b) {
  char *x, *y;
  if (alen == 0)
    alen = (int)strlen(a);
  x = a + alen - 1;
  y = b + alen - 1;
  *(y + 1) = 0;
  for (; x >= a && *x == ' '; x--)
    *y-- = 0;
  for (; x >= a; *y-- = *x--)
    ;
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<g_char>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  test   %esi,%esi
  jne    L16
  call   <strlen@plt>
  mov    %eax,%esi
L16:
  movslq %esi,%rax
  sub    $0x1,%rax
  lea    0x0(%rbp,%rax,1),%rdx
  movb   $0x0,0x1(%rdx)
  add    %rbx,%rax
  jb     L5
L20:
  cmpb   $0x20,(%rax)
  jne    L11
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L20
  jmp    L5
L11:
  cmp    %rax,%rbx
  ja     L5
  sub    $0x1,%rbx
  sub    %rax,%rbx
  mov    $0x0,%ecx
L43:
  movzbl (%rax,%rcx,1),%esi
  mov    %sil,(%rdx,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rbx,%rcx
  jne    L43
L5:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int g_char(char *a, int alen, char *b) {
  char *x, *y;
  if (alen == 0)
    alen = (int)strlen(a);
  x = a + alen - 1;
  y = b + alen - 1;
  *(y + 1) = 0;
  for (; x >= a && *x == ' '; x--)
    *y-- = 0;
  for (; x >= a; *y-- = *x--)
    ;
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g_char>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L2
  call   <strlen@plt>
  mov    %eax,%esi
L2:
  movslq %esi,%rax
  sub    $0x1,%rax
  lea    (%rbx,%rax,1),%rdx
  movb   $0x0,0x1(%rdx)
  add    %rbp,%rax
  jae    L53
  jmp    L43
  nopl   0x0(%rax)
L12:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  cmp    %rax,%rbp
  ja     L43
L53:
  movzbl (%rax),%esi
  cmp    $0x20,%sil
  je     L12
  cmp    %rax,%rbp
  ja     L43
  sub    $0x1,%rbp
  xor    %ecx,%ecx
  sub    %rax,%rbp
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L38:
  movzbl (%rax,%rcx,1),%esi
L59:
  mov    %sil,(%rdx,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rbp,%rcx
  jne    L38
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int g_char(char *a, int alen, char *b) {
  char *x, *y;
  if (alen == 0)
    alen = (int)strlen(a);
  x = a + alen - 1;
  y = b + alen - 1;
  *(y + 1) = 0;
  for (; x >= a && *x == ' '; x--)
    *y-- = 0;
  for (; x >= a; *y-- = *x--)
    ;
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g_char>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L53
  call   <strlen@plt>
  mov    %eax,%esi
L53:
  movslq %esi,%rax
  sub    $0x1,%rax
  lea    (%rbx,%rax,1),%rdx
  movb   $0x0,0x1(%rdx)
  add    %rbp,%rax
  jae    L14
  jmp    L19
  nopl   0x0(%rax)
L58:
  sub    $0x1,%rax
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  cmp    %rax,%rbp
  ja     L19
L14:
  cmpb   $0x20,(%rax)
  je     L58
  cmp    %rax,%rbp
  ja     L19
  sub    $0x1,%rbp
  xor    %ecx,%ecx
  sub    %rax,%rbp
  nopl   0x0(%rax)
L62:
  movzbl (%rax,%rcx,1),%esi
  mov    %sil,(%rdx,%rcx,1)
  sub    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L62
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int g_char(char *a, int alen, char *b) {
  char *x, *y;
  if (alen == 0)
    alen = (int)strlen(a);
  x = a + alen - 1;
  y = b + alen - 1;
  *(y + 1) = 0;
  for (; x >= a && *x == ' '; x--)
    *y-- = 0;
  for (; x >= a; *y-- = *x--)
    ;
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_Queue>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  lea    D30(%rip),%r13
  lea    D5(%rip),%r12
  lea    D37(%rip),%r14
  lea    D47(%rip),%rbx
  jmp    L100
  mov    $0x0,%eax
  call   <CreateQueue@plt>
  mov    %rax,%rbp
L126:
  cmpl   $0x0,(%rsp)
  je     L65
L100:
  mov    %r13,%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpl   $0x4,(%rsp)
  ja     L21
  mov    (%rsp),%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rbp,%rbp
  je     L35
L22:
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  call   <EnQueue@plt>
  jmp    L126
L35:
  mov    $0x0,%eax
  call   <CreateQueue@plt>
  mov    %rax,%rbp
  jmp    L22
  test   %rbp,%rbp
  je     L15
  mov    %rbp,%rdi
  call   <DeQueue@plt>
  mov    %eax,0x4(%rsp)
L15:
  mov    0x4(%rsp),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L126
  test   %rbp,%rbp
  je     L100
  mov    %rbp,%rdi
  call   <DeleteQueue@plt>
  mov    $0x0,%ebp
  jmp    L126
  test   %rbp,%rbp
  je     L65
  mov    %rbp,%rdi
  call   <DeleteQueue@plt>
  mov    $0x0,%ebp
  jmp    L126
L21:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L126
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D30
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string
name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string

tool: D30: Enter Operation: (1) Create; (2): Enqueue; (3): DeQueue; (4) DeleteQ; (0): Exit

tool: D5: %d

tool: D37: Wrong Operation Selected

tool: D20: Enter Queue Element

tool: D15: Dequeued Element: %d


assistant: ```c
void test_Queue() {
  struct Queue *Q;
  int ans, data = 0;
  do {
    printf("Enter Operation: (1) Create; (2): Enqueue; (3): DeQueue; (4) DeleteQ; (0): Exit\n");
    scanf("%d", &ans);
    switch (ans) {
    case 1:
      Q = CreateQueue();
      break;
    case 2:
      printf("Enter Queue Element\n");
      scanf("%d", &data);
      if (!Q)
        Q = CreateQueue();
      EnQueue(Q, data);
      break;
    case 3:
      if (Q)
        data = DeQueue(Q);
      printf("Dequeued Element: %d\n", data);
      break;
    case 4:
      if (Q) {
        DeleteQueue(Q);
        Q = NULL;
      }
      break;
    case 0:
      if (Q) {
        DeleteQueue(Q);
        Q = NULL;
      }
      break;
    default:
      printf("Wrong Operation Selected\n");
    }
  } while (ans != 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x1(%rbp)
  jmp    L13
L21:
  cmpb   $0x63,-0x1(%rbp)
  je     L33
  movzbl -0x1(%rbp),%eax
  jmp    L8
L33:
  mov    $0x6f,%eax
L8:
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %al,-0x1(%rbp)
L13:
  mov    D5(%rip),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  jne    L21
  nop
  nop
  leave
  ret
```

assistant: ```c
void copy(FILE *in_file, FILE *out_file) {
  char cursor;
  for (cursor = fgetc(in_file); cursor != EOF; cursor = fgetc(in_file)) {
    cursor = (cursor == 'c') ? 'o' : cursor;
    fputc(cursor, out_file);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <fgetc@plt>
  mov    D6(%rip),%rdx
  cmp    (%rdx),%al
  je     L16
  mov    $0x6f,%r12d
L17:
  cmp    $0x63,%al
  cmove  %r12d,%eax
  movsbl %al,%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %rbx,%rdi
  call   <fgetc@plt>
  mov    D6(%rip),%rdx
  cmp    %al,(%rdx)
  jne    L17
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void copy(FILE *in_file, FILE *out_file) {
  char cursor;
  for (cursor = fgetc(in_file); cursor != EOF; cursor = fgetc(in_file)) {
    cursor = (cursor == 'c') ? 'o' : cursor;
    fputc(cursor, out_file);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <fgetc@plt>
  mov    D3(%rip),%r12
  cmp    (%r12),%al
  je     L18
  mov    $0x6f,%r13d
  nopl   0x0(%rax)
L4:
  cmp    $0x63,%al
  mov    %rbp,%rsi
  cmove  %r13d,%eax
  movsbl %al,%edi
  call   <fputc@plt>
  mov    %rbx,%rdi
  call   <fgetc@plt>
  cmp    %al,(%r12)
  jne    L4
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void copy(FILE *in_file, FILE *out_file) {
  char cursor;
  for (cursor = fgetc(in_file); cursor != EOF; cursor = fgetc(in_file)) {
    cursor = (cursor == 'c') ? 'o' : cursor;
    fputc(cursor, out_file);
  }
}
```