ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x51e22cdb,%eax
  and    $0x10e1eca9,%eax
  or     $0xa020002,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] == local1) {
        if (state[0UL] < local1) {
          state[local1] = state[0UL] + state[local1];
          state[local1] |= ((state[0UL] - state[local1]) & 31U) << 4UL;
        } else {
          state[local1] |= (state[local1] & 31U) << 3UL;
          copy11 = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
        }
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 236851714UL) & 451144875U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x51e22cdb,%eax
  and    $0x10e1eca9,%eax
  or     $0xa020002,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = input[0UL] + 1373777115U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] == local1) {
        if (state[0UL] < local1) {
          state[local1] = state[0UL] + state[local1];
          state[local1] |= ((state[0UL] - state[local1]) & 31U) << 4UL;
        } else {
          state[local1] |= (state[local1] & 31U) << 3UL;
          copy11 = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
          *((char *)(&state[local1]) + 2) = copy11;
          copy11 = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 3);
          *((char *)(&state[local1]) + 3) = copy11;
        }
      }
      local1++;
    }
    output[0UL] = (state[0UL] | 236851714UL) & 451144875U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<divide>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    %esi,-0x10(%rbp)
  cmpl   $0x4,-0x10(%rbp)
  je     L37
  cmpl   $0x4,-0x10(%rbp)
  jg     L38
  cmpl   $0x3,-0x10(%rbp)
  je     L10
  cmpl   $0x3,-0x10(%rbp)
  jg     L38
  cmpl   $0x1,-0x10(%rbp)
  je     L6
  cmpl   $0x2,-0x10(%rbp)
  je     L33
  jmp    L38
L37:
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
L10:
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
L33:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  divss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  divss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
L38:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void divide(float *p, float d, int c) {
  switch (c) {
  case 4:
    p[3] /= d;
  case 3:
    p[2] /= d;
  case 2:
    p[1] /= d;
  case 1:
    p[0] /= d;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<divide>:
  endbr64
  cmp    $0x3,%esi
  je     L40
  jg     L18
  cmp    $0x1,%esi
  je     L34
  cmp    $0x2,%esi
  jne    L24
L35:
  movss  0x4(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
L34:
  movss  (%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
L3:
  ret
L24:
  ret
L18:
  cmp    $0x4,%esi
  jne    L3
  movss  0xc(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
L40:
  movss  0x8(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rdi)
  jmp    L35
```

assistant: ```c
void divide(float *p, float d, int c) {
  switch (c) {
  case 4:
    p[3] /= d;
  case 3:
    p[2] /= d;
  case 2:
    p[1] /= d;
  case 1:
    p[0] /= d;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<divide>:
  endbr64
  cmp    $0x3,%esi
  je     L3
  jg     L48
  cmp    $0x1,%esi
  je     L24
  cmp    $0x2,%esi
  jne    L36
L21:
  movss  0x4(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
L24:
  movss  (%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
L10:
  ret
L48:
  cmp    $0x4,%esi
  jne    L10
  movss  0xc(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
L3:
  movss  0x8(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rdi)
  jmp    L21
L36:
  ret
```

assistant: ```c
void divide(float *p, float d, int c) {
  switch (c) {
  case 4:
    p[3] /= d;
  case 3:
    p[2] /= d;
  case 2:
    p[1] /= d;
  case 1:
    p[0] /= d;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divide>:
  endbr64
  cmp    $0x3,%esi
  je     L34
  jg     L44
  cmp    $0x1,%esi
  je     L46
  cmp    $0x2,%esi
  jne    L1
L15:
  movss  0x4(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
L46:
  movss  (%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
L31:
  ret
L44:
  cmp    $0x4,%esi
  jne    L31
  movss  0xc(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
L34:
  movss  0x8(%rdi),%xmm1
  divss  %xmm0,%xmm1
  movss  %xmm1,0x8(%rdi)
  jmp    L15
L1:
  ret
```

assistant: ```c
void divide(float *p, float d, int c) {
  switch (c) {
  case 4:
    p[3] /= d;
  case 3:
    p[2] /= d;
  case 2:
    p[1] /= d;
  case 1:
    p[0] /= d;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    D23(%rip),%rbx
  mov    $0x23,%r12d
  jmp    L7
L39:
  mov    %r12d,%eax
L61:
  mov    %al,(%rsp,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x50,%rdx
  je     L35
L78:
  pxor   %xmm5,%xmm5
  cvtsi2sd %edx,%xmm5
  divsd  %xmm10,%xmm5
  mulsd  %xmm9,%xmm5
  subsd  %xmm8,%xmm5
  mov    $0x64,%eax
  movq   %rbx,%xmm1
  movq   %rbx,%xmm0
  movq   %rbx,%xmm3
  movq   %rbx,%xmm2
L31:
  addsd  %xmm0,%xmm0
  mulsd  %xmm0,%xmm1
  addsd  %xmm6,%xmm1
  subsd  %xmm3,%xmm2
  addsd  %xmm5,%xmm2
  movapd %xmm2,%xmm0
  sub    $0x1,%eax
  je     L39
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  movapd %xmm1,%xmm3
  mulsd  %xmm1,%xmm3
  movapd %xmm2,%xmm4
  addsd  %xmm3,%xmm4
  comisd %xmm4,%xmm7
  ja     L31
  mov    %ecx,%eax
  jmp    L61
L35:
  movb   $0x0,0x50(%rsp)
  mov    %rsp,%rsi
  lea    D78(%rip),%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x28,%ebp
  je     L63
L7:
  pxor   %xmm6,%xmm6
  cvtsi2sd %ebp,%xmm6
  divsd  D74(%rip),%xmm6
  mulsd  D1(%rip),%xmm6
  subsd  D29(%rip),%xmm6
  mov    $0x0,%edx
  movsd  D12(%rip),%xmm10
  movsd  D1(%rip),%xmm9
  movsd  D29(%rip),%xmm8
  movapd %xmm9,%xmm7
  mov    $0x2e,%ecx
  jmp    L78
L63:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
type: f64
name: disassemble_data
arguments: label: D78
type: string
name: disassemble_data
arguments: label: D74
type: byte[8]
name: disassemble_data
arguments: label: D1
type: f64
name: disassemble_data
arguments: label: D29
type: f64
name: disassemble_data
arguments: label: D12
type: byte[8]

tool: D23: 0

tool: D78: %s


tool: {"D74": [0x00,0x00,0x00,0x00,0x00,0x00,0x44,0x40]}

tool: D1: 4

tool: D29: 2

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x54,0x40]}

assistant: ```c
int main(int argc, char *argv[]) {
  int w = 80;
  int h = 40;
  int iter = 100;
  int i, j, k;
  double x0, y0, xx, yy, xx2, yy2;
  char row[80 + 1];
  char c;
  for (i = 0; i < h; i++) {
    y0 = (double)i / (double)h * 4.0 - 2.0;
    for (j = 0; j < w; j++) {
      x0 = (double)j / (double)w * 4.0 - 2.0;
      xx = 0.0;
      yy = 0.0;
      c = '#';
      for (k = 0; k < iter; k++) {
        xx2 = xx * xx;
        yy2 = yy * yy;
        if (xx2 + yy2 < 4.0) {
          yy = 2 * xx * yy + y0;
          xx = xx2 - yy2 + x0;
        } else {
          c = '.';
          break;
        }
      }
      row[j] = c;
    }
    row[j] = (char)0;
    printf("%s\n", row);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm8,%xmm8
  lea    D29(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x60,%rsp
  movsd  D15(%rip),%xmm6
  movsd  D50(%rip),%xmm9
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movsd  D7(%rip),%xmm10
L19:
  pxor   %xmm7,%xmm7
  xor    %edx,%edx
  cvtsi2sd %ebp,%xmm7
  divsd  D27(%rip),%xmm7
  mulsd  %xmm6,%xmm7
  subsd  %xmm9,%xmm7
  nopw   0x0(%rax,%rax,1)
L24:
  pxor   %xmm5,%xmm5
  mov    $0x64,%eax
  movapd %xmm8,%xmm1
  cvtsi2sd %edx,%xmm5
  movapd %xmm8,%xmm0
  movapd %xmm8,%xmm3
  movapd %xmm8,%xmm2
  divsd  %xmm10,%xmm5
  mulsd  %xmm6,%xmm5
  subsd  %xmm9,%xmm5
  nopw   0x0(%rax,%rax,1)
L36:
  addsd  %xmm0,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm1
  addsd  %xmm5,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm7,%xmm1
  sub    $0x1,%eax
  je     L58
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm1,%xmm3
  movapd %xmm2,%xmm4
  addsd  %xmm3,%xmm4
  comisd %xmm4,%xmm6
  ja     L36
  mov    $0x2e,%eax
L23:
  mov    %al,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x50,%rdx
  jne    L24
  mov    %rbx,%rsi
  mov    %r12,%rdi
  movb   $0x0,0x50(%rsp)
  add    $0x1,%ebp
  call   <printf@plt>
  mov    D15(%rip),%rax
  cmp    $0x28,%ebp
  pxor   %xmm8,%xmm8
  movq   %rax,%xmm6
  mov    D50(%rip),%rax
  movq   %rax,%xmm9
  mov    D7(%rip),%rax
  movq   %rax,%xmm10
  jne    L19
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L58:
  mov    $0x23,%eax
  jmp    L23
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: f64
name: unpack_data
arguments: tag: D50
type_guessed: f64
name: unpack_data
arguments: tag: D7
type_guessed: f32[2]
name: unpack_data
arguments: tag: D27
type_guessed: f32[2]

tool: D29: %s


tool: D15: 4

tool: D50: 2

tool: {"D7": [0.0,3.3125]}

tool: {"D27": [0.0,3.0625]}

assistant: ```c
int main(int argc, char *argv[]) {
  int w = 80;
  int h = 40;
  int iter = 100;
  int i, j, k;
  double x0, y0, xx, yy, xx2, yy2;
  char row[80 + 1];
  char c;
  for (i = 0; i < h; i++) {
    y0 = (double)i / (double)h * 4.0 - 2.0;
    for (j = 0; j < w; j++) {
      x0 = (double)j / (double)w * 4.0 - 2.0;
      xx = 0.0;
      yy = 0.0;
      c = '#';
      for (k = 0; k < iter; k++) {
        xx2 = xx * xx;
        yy2 = yy * yy;
        if (xx2 + yy2 < 4.0) {
          yy = 2 * xx * yy + y0;
          xx = xx2 - yy2 + x0;
        } else {
          c = '.';
          break;
        }
      }
      row[j] = c;
    }
    row[j] = (char)0;
    printf("%s\n", row);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm8,%xmm8
  lea    D33(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x60,%rsp
  movsd  D23(%rip),%xmm6
  movsd  D65(%rip),%xmm9
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movsd  D29(%rip),%xmm10
L54:
  pxor   %xmm7,%xmm7
  xor    %edx,%edx
  cvtsi2sd %ebp,%xmm7
  divsd  D31(%rip),%xmm7
  mulsd  %xmm6,%xmm7
  subsd  %xmm9,%xmm7
  nopw   0x0(%rax,%rax,1)
L7:
  pxor   %xmm5,%xmm5
  mov    $0x64,%eax
  movapd %xmm8,%xmm1
  cvtsi2sd %edx,%xmm5
  movapd %xmm8,%xmm0
  movapd %xmm8,%xmm3
  movapd %xmm8,%xmm2
  divsd  %xmm10,%xmm5
  mulsd  %xmm6,%xmm5
  subsd  %xmm9,%xmm5
  nopw   0x0(%rax,%rax,1)
L22:
  addsd  %xmm0,%xmm0
  subsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm1
  addsd  %xmm5,%xmm2
  movapd %xmm2,%xmm0
  addsd  %xmm7,%xmm1
  sub    $0x1,%eax
  je     L44
  movapd %xmm0,%xmm2
  movapd %xmm1,%xmm3
  mulsd  %xmm0,%xmm2
  mulsd  %xmm1,%xmm3
  movapd %xmm2,%xmm4
  addsd  %xmm3,%xmm4
  comisd %xmm4,%xmm6
  ja     L22
  mov    $0x2e,%eax
L46:
  mov    %al,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x50,%rdx
  jne    L7
  mov    %rbx,%rsi
  mov    %r12,%rdi
  movb   $0x0,0x50(%rsp)
  add    $0x1,%ebp
  call   <printf@plt>
  mov    D23(%rip),%rax
  cmp    $0x28,%ebp
  pxor   %xmm8,%xmm8
  movq   %rax,%xmm6
  mov    D65(%rip),%rax
  movq   %rax,%xmm9
  mov    D29(%rip),%rax
  movq   %rax,%xmm10
  jne    L54
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L44:
  mov    $0x23,%eax
  jmp    L46
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type_infered: string
name: extract_symbolic_data
arguments: label: D23
type_infered: f64
name: extract_symbolic_data
arguments: label: D65
type_infered: f64
name: extract_symbolic_data
arguments: label: D29
type_infered: f32[2]
name: extract_symbolic_data
arguments: label: D31
type_infered: f32[2]

tool: D33: %s


tool: D23: 4

tool: D65: 2

tool: {"D29": [0.0,3.3125]}

tool: {"D31": [0.0,3.0625]}

assistant: ```c
int main(int argc, char *argv[]) {
  int w = 80;
  int h = 40;
  int iter = 100;
  int i, j, k;
  double x0, y0, xx, yy, xx2, yy2;
  char row[80 + 1];
  char c;
  for (i = 0; i < h; i++) {
    y0 = (double)i / (double)h * 4.0 - 2.0;
    for (j = 0; j < w; j++) {
      x0 = (double)j / (double)w * 4.0 - 2.0;
      xx = 0.0;
      yy = 0.0;
      c = '#';
      for (k = 0; k < iter; k++) {
        xx2 = xx * xx;
        yy2 = yy * yy;
        if (xx2 + yy2 < 4.0) {
          yy = 2 * xx * yy + y0;
          xx = xx2 - yy2 + x0;
        } else {
          c = '.';
          break;
        }
      }
      row[j] = c;
    }
    row[j] = (char)0;
    printf("%s\n", row);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <jupiter_print@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D2
type_infered: string

tool: D2: Hello

assistant: ```c
int main(int argc, char *argv[]) {
  const char *salutation = "Hello";
  jupiter_print(salutation, argv[0]);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <jupiter_print@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string

tool: D6: Hello

assistant: ```c
int main(int argc, char *argv[]) {
  const char *salutation = "Hello";
  jupiter_print(salutation, argv[0]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D8(%rip),%rdi
  call   <jupiter_print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: Hello

assistant: ```c
int main(int argc, char *argv[]) {
  const char *salutation = "Hello";
  jupiter_print(salutation, argv[0]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D7(%rip),%rdi
  call   <jupiter_print@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: Hello

assistant: ```c
int main(int argc, char *argv[]) {
  const char *salutation = "Hello";
  jupiter_print(salutation, argv[0]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Difsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <Spsum@plt>
  add    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <Spsum@plt>
  add    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L16
L3:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <presum@plt>
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L3
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long int Difsum(long long int x, long long int y, int d1, int d2) {
  long long int s = 0;
  int i;
  s = s + Spsum(x, (pow(10, d1) - 1));
  s = s + Spsum(pow(10, d2 - 1), y);
  for (i = d1 + 1; i < d2; i++)
    s = s + presum(i);
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Difsum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %edx,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  lea    -0x1(%rax),%rsi
  mov    %rbp,%rdi
  call   <Spsum@plt>
  mov    %rax,%rbp
  lea    -0x1(%r12),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rax,%rdi
  mov    %r13,%rsi
  call   <Spsum@plt>
  add    %rax,%rbp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jle    L7
L10:
  mov    %ebx,%edi
  call   <presum@plt>
  add    %rax,%rbp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L10
L7:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long long int Difsum(long long int x, long long int y, int d1, int d2) {
  long long int s = 0;
  int i;
  s = s + Spsum(x, (pow(10, d1) - 1));
  s = s + Spsum(pow(10, d2 - 1), y);
  for (i = d1 + 1; i < d2; i++)
    s = s + presum(i);
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<Difsum>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%esi
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  add    $0x1,%ebx
  sub    $0x8,%rsp
  call   <pow@plt>
  mov    %r12,%rdi
  lea    -0x1(%rax),%rsi
  call   <Spsum@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %rax,%r12
  call   <pow@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <Spsum@plt>
  add    %rax,%r12
  cmp    %ebx,%ebp
  jle    L5
  nopl   (%rax)
L17:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <presum@plt>
  add    %rax,%r12
  cmp    %ebx,%ebp
  jne    L17
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long long int Difsum(long long int x, long long int y, int d1, int d2) {
  long long int s = 0;
  int i;
  s = s + Spsum(x, (pow(10, d1) - 1));
  s = s + Spsum(pow(10, d2 - 1), y);
  for (i = d1 + 1; i < d2; i++)
    s = s + presum(i);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Difsum>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%esi
  push   %r12
  mov    %rdi,%r12
  mov    $0xa,%edi
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %edx,%ebx
  add    $0x1,%ebx
  sub    $0x8,%rsp
  call   <pow@plt>
  mov    %r12,%rdi
  lea    -0x1(%rax),%rsi
  call   <Spsum@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %rax,%r12
  call   <pow@plt>
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <Spsum@plt>
  add    %rax,%r12
  cmp    %ebx,%ebp
  jle    L9
  nopl   (%rax)
L17:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <presum@plt>
  add    %rax,%r12
  cmp    %ebx,%ebp
  jne    L17
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long long int Difsum(long long int x, long long int y, int d1, int d2) {
  long long int s = 0;
  int i;
  s = s + Spsum(x, (pow(10, d1) - 1));
  s = s + Spsum(pow(10, d2 - 1), y);
  for (i = d1 + 1; i < d2; i++)
    s = s + presum(i);
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L15:
  mov    -0x8(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L15
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int power(int n, int p) {
  int ans = 1;
  for (int i = 0; i < p; i++)
    ans *= n;
  return ans;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    $0x0,%eax
  mov    $0x1,%edx
L18:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L18
L28:
  mov    %edx,%eax
  ret
L29:
  mov    $0x1,%edx
  jmp    L28
```

assistant: ```c
int power(int n, int p) {
  int ans = 1;
  for (int i = 0; i < p; i++)
    ans *= n;
  return ans;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L17
  xor    %eax,%eax
  mov    $0x1,%r8d
L5:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L5
  mov    %r8d,%eax
  ret
  nop
L17:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int n, int p) {
  int ans = 1;
  for (int i = 0; i < p; i++)
    ans *= n;
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<power>:
  endbr64
  test   %esi,%esi
  jle    L14
  xor    %eax,%eax
  mov    $0x1,%r8d
L6:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L6
  mov    %r8d,%eax
  ret
  nop
L14:
  mov    $0x1,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int power(int n, int p) {
  int ans = 1;
  for (int i = 0; i < p; i++)
    ans *= n;
  return ans;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_date_folder_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  jne    L24
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <get_local_time@plt>
  jmp    L19
L24:
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    (%rax),%rdx
  mov    %rdx,-0x14(%rbp)
  mov    0x8(%rax),%eax
  mov    %eax,-0xc(%rbp)
L19:
  mov    -0x14(%rbp),%eax
  add    $0x76c,%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x10(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edi
  mov    -0x1c(%rbp),%esi
  mov    -0x20(%rbp),%ecx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %edi,%r9d
  mov    %esi,%r8d
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %s/%4d%02d%02d

assistant: ```c
int get_date_folder_name(char *foldername, char *path, time_t t) {
  struct tm tm;
  int year, month, day;
  if (!t)
    get_local_time(&tm);
  else
    tm = *localtime(&t);
  year = tm.tm_year + 1900;
  month = tm.tm_mon + 1;
  day = tm.tm_mday;
  sprintf(foldername, "%s/%4d%02d%02d", path, year, month, day);
  return 0;
}
```