ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<t1_init_ctxno_mag>:
  endbr64
  mov    $0xc,%eax
  test   $0x2000,%edi
  jne    L5
  cmp    $0x1,%dil
  mov    $0xa,%eax
  sbb    $0xffffffff,%eax
L5:
  ret
```

assistant: ```c
int t1_init_ctxno_mag(int f) {
  int n;
  if (!(f & 0x2000)) {
    n = (f & ((0x0010 | 0x0001 | 0x0020 | 0x0002 | 0x0040 | 0x0004 | 0x0080 | 0x0008))) ? 1 : 0;
  } else {
    n = 2;
  }
  return (((0 + 1) + 9) + n);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<t1_init_ctxno_mag>:
  endbr64
  mov    $0xc,%eax
  test   $0x2000,%edi
  jne    L8
  cmp    $0x1,%dil
  mov    $0xa,%eax
  sbb    $0xffffffff,%eax
L8:
  ret
```

assistant: ```c
int t1_init_ctxno_mag(int f) {
  int n;
  if (!(f & 0x2000)) {
    n = (f & ((0x0010 | 0x0001 | 0x0020 | 0x0002 | 0x0040 | 0x0004 | 0x0080 | 0x0008))) ? 1 : 0;
  } else {
    n = 2;
  }
  return (((0 + 1) + 9) + n);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trimspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L80
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L76
L39:
  subq   $0x1,-0x8(%rbp)
L76:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L67
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L39
L67:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L84
L89:
  addq   $0x1,-0x10(%rbp)
L84:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L89
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L33
L20:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L79
L80:
  nop
L79:
  leave
  ret
```

assistant: ```c
void trimspace(char *buf) {
  char *p, *q;
  p = buf;
  if (p == NULL)
    return;
  q = p + strlen(p);
  while (q > p && *q == ' ')
    q--;
  *(q + 1) = '\0';
  while (*p == ' ')
    p++;
  q = p;
  while (*q != '\0')
    *p++ = *q++;
  *p = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<trimspace>:
  endbr64
  test   %rdi,%rdi
  je     L13
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jae    L35
L42:
  cmpb   $0x20,(%rax)
  jne    L35
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L42
  mov    %rbx,%rax
L35:
  movb   $0x0,0x1(%rax)
  cmpb   $0x20,(%rbx)
  jne    L17
L1:
  add    $0x1,%rbx
  cmpb   $0x20,(%rbx)
  je     L1
L17:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L53
L74:
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L74
L53:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
L13:
  ret
```

assistant: ```c
void trimspace(char *buf) {
  char *p, *q;
  p = buf;
  if (p == NULL)
    return;
  q = p + strlen(p);
  while (q > p && *q == ' ')
    q--;
  *(q + 1) = '\0';
  while (*p == ' ')
    p++;
  q = p;
  while (*q != '\0')
    *p++ = *q++;
  *p = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trimspace>:
  endbr64
  test   %rdi,%rdi
  je     L60
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jb     L44
  jmp    L53
  xchg   %ax,%ax
L31:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L53
L44:
  cmpb   $0x20,(%rax)
  je     L31
L53:
  movb   $0x0,0x1(%rax)
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L1
  nopl   0x0(%rax)
L3:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L3
L1:
  test   %al,%al
  je     L39
L61:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L61
L39:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L60:
  ret
```

assistant: ```c
void trimspace(char *buf) {
  char *p, *q;
  p = buf;
  if (p == NULL)
    return;
  q = p + strlen(p);
  while (q > p && *q == ' ')
    q--;
  *(q + 1) = '\0';
  while (*p == ' ')
    p++;
  q = p;
  while (*q != '\0')
    *p++ = *q++;
  *p = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trimspace>:
  endbr64
  test   %rdi,%rdi
  je     L88
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  cmp    %rax,%rbx
  jb     L7
  jmp    L3
  xchg   %ax,%ax
L23:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L3
L7:
  cmpb   $0x20,(%rax)
  je     L23
L3:
  movb   $0x0,0x1(%rax)
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  jne    L81
  nopl   0x0(%rax)
L11:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L11
L81:
  test   %al,%al
  je     L43
L75:
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L75
L43:
  movb   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L88:
  ret
```

assistant: ```c
void trimspace(char *buf) {
  char *p, *q;
  p = buf;
  if (p == NULL)
    return;
  q = p + strlen(p);
  while (q > p && *q == ' ')
    q--;
  *(q + 1) = '\0';
  while (*p == ' ')
    p++;
  q = p;
  while (*q != '\0')
    *p++ = *q++;
  *p = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<abort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <raise@plt>
  mov    $0x7f,%edi
  call   <_Exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void abort(void) {
  raise(SIGABRT);
  _Exit(127);
}
```
user: Translate the below assembly code into C programming language:

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  mov    $0x7f,%edi
  call   <_Exit@plt>
```

assistant: ```c
void abort(void) {
  raise(SIGABRT);
  _Exit(127);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  push   %rax
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  mov    $0x7f,%edi
  call   <_Exit@plt>
```

assistant: ```c
void abort(void) {
  raise(SIGABRT);
  _Exit(127);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<abort>:
  endbr64
  push   %rax
  pop    %rax
  push   %rax
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <raise@plt>
  mov    $0x7f,%edi
  call   <_Exit@plt>
```

assistant: ```c
void abort(void) {
  raise(SIGABRT);
  _Exit(127);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L19:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    $0x8,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: The size of ar is %zd bytes.


assistant: ```c
int sum(int ar[], int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %zd bytes.\n", sizeof ar);
  return total;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum>:
  endbr64
  push   %rbx
  test   %esi,%esi
  jle    L2
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  mov    $0x0,%ebx
L21:
  add    (%rax),%ebx
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L21
L20:
  mov    $0x8,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L2:
  mov    $0x0,%ebx
  jmp    L20
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D7: The size of ar is %zd bytes.


assistant: ```c
int sum(int ar[], int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %zd bytes.\n", sizeof ar);
  return total;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum>:
  endbr64
  push   %r12
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  xor    %r12d,%r12d
  lea    0x4(%rdi,%rax,4),%rax
  nopl   (%rax)
L6:
  add    (%rdi),%r12d
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L6
L24:
  mov    $0x8,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L21:
  xor    %r12d,%r12d
  jmp    L24
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: The size of ar is %zd bytes.


assistant: ```c
int sum(int ar[], int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %zd bytes.\n", sizeof ar);
  return total;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  push   %r12
  test   %esi,%esi
  jle    L45
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rdx
  cmp    $0x2,%eax
  jbe    L12
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   (%rax)
L16:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L16
  movdqa %xmm0,%xmm1
  mov    %esi,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%r12d
  test   $0x3,%sil
  je     L11
L5:
  movslq %eax,%rcx
  lea    0x0(,%rcx,4),%rdi
  add    (%rdx,%rcx,4),%r12d
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jle    L11
  add    $0x2,%eax
  add    0x4(%rdx,%rdi,1),%r12d
  cmp    %eax,%esi
  jle    L11
  add    0x8(%rdx,%rdi,1),%r12d
L11:
  mov    $0x8,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L45:
  xor    %r12d,%r12d
  jmp    L11
L12:
  xor    %r12d,%r12d
  xor    %eax,%eax
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D9: The size of ar is %zd bytes.


assistant: ```c
int sum(int ar[], int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %zd bytes.\n", sizeof ar);
  return total;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
L3:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L3
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  D3(%rip),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L10
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L23
L10:
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L23:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D24
datatype: string
name: extract_symbolic_data
arguments: data_tag: D3
datatype: byte[4]
name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D36
datatype: string

tool: D24: %d

tool: {"D3": [0x00,0x00,0xe0,0x40]}

tool: D14: light

tool: D36: heavy

assistant: ```c
int main() {
  int n, i;
  float avg, sum;
  scanf("%d", &n);
  sum = 0;
  i = 0;
  do {
    sum = sum + n % 10;
    n = n / 10;
    i++;
  } while (n / 10 != 0);
  avg = sum / i;
  if (avg < 7) {
    printf("light");
  } else
    printf("heavy");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  mov    $0x0,%esi
L27:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  addss  %xmm1,%xmm0
  mov    %eax,%edx
  add    $0x1,%esi
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L27
  mov    %edx,0x4(%rsp)
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D28(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L26
  lea    D11(%rip),%rdi
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L15
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D25
data_type: string
name: extract_symbolic_data
arguments: tag: D28
data_type: byte[4]
name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D31
data_type: string

tool: D25: %d

tool: {"D28": [0x00,0x00,0xe0,0x40]}

tool: D11: light

tool: D31: heavy

assistant: ```c
int main() {
  int n, i;
  float avg, sum;
  scanf("%d", &n);
  sum = 0;
  i = 0;
  do {
    sum = sum + n % 10;
    n = n / 10;
    i++;
  } while (n / 10 != 0);
  avg = sum / i;
  if (avg < 7) {
    printf("light");
  } else
    printf("heavy");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D31(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L16:
  movslq %edx,%rax
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm1
  mov    %eax,%edx
  lea    0x9(%rax),%eax
  addss  %xmm1,%xmm0
  cmp    $0x12,%eax
  ja     L16
  pxor   %xmm1,%xmm1
  mov    %edx,0x4(%rsp)
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D10(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L31
  lea    D8(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L31:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D31
type_infered: string
name: parse_data
arguments: label: D10
type_infered: byte[4]
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D15
type_infered: string

tool: D31: %d

tool: {"D10": [0x00,0x00,0xe0,0x40]}

tool: D8: light

tool: D15: heavy

assistant: ```c
int main() {
  int n, i;
  float avg, sum;
  scanf("%d", &n);
  sum = 0;
  i = 0;
  do {
    sum = sum + n % 10;
    n = n / 10;
    i++;
  } while (n / 10 != 0);
  avg = sum / i;
  if (avg < 7) {
    printf("light");
  } else
    printf("heavy");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D34(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %edx,%rax
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm1
  mov    %eax,%edx
  lea    0x9(%rax),%eax
  addss  %xmm1,%xmm0
  cmp    $0x12,%eax
  ja     L13
  pxor   %xmm1,%xmm1
  mov    %edx,0x4(%rsp)
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D7(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L8
  lea    D6(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D34
datatype: string
name: read_data
arguments: label: D7
datatype: byte[4]
name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D39
datatype: string

tool: D34: %d

tool: {"D7": [0x00,0x00,0xe0,0x40]}

tool: D6: light

tool: D39: heavy

assistant: ```c
int main() {
  int n, i;
  float avg, sum;
  scanf("%d", &n);
  sum = 0;
  i = 0;
  do {
    sum = sum + n % 10;
    n = n / 10;
    i++;
  } while (n / 10 != 0);
  avg = sum / i;
  if (avg < 7) {
    printf("light");
  } else
    printf("heavy");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x20,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L55:
  cmp    %rdx,%rsp
  je     L1
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L55
L1:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L32
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L32:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  jmp    L12
L19:
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jg     L69
  mov    -0x44(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  sub    %edx,%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x34(%rbp),%eax
  sub    -0x38(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  cltq
  movb   $0x31,(%rdx,%rax,1)
  jmp    L67
L69:
  mov    -0x34(%rbp),%eax
  sub    -0x38(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  cltq
  movb   $0x30,(%rdx,%rax,1)
L67:
  subl   $0x1,-0x38(%rbp)
L12:
  cmpl   $0x0,-0x38(%rbp)
  jns    L19
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type: string

tool: D2: %s


assistant: ```c
void binary(int digit) {
  int bits = sizeof(int) * 8;
  char output[bits];
  output[bits] = '\0';
  for (int i = bits; i >= 0; i--) {
    long tmp = pow(2, i);
    if (digit >= tmp) {
      digit -= tmp;
      output[bits - i] = '1';
    } else {
      output[bits - i] = '0';
    }
  }
  printf("%s\n", output);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<binary>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x20(%rsp)
  mov    %rsp,%r12
  lea    0x21(%rsp),%r13
  mov    %r12,%rbx
  add    $0x20,%r12d
  jmp    L1
L0:
  movb   $0x30,(%rbx)
L2:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L30
L1:
  mov    %r12d,%esi
  sub    %ebx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  movslq %ebp,%rdx
  cmp    %rax,%rdx
  jl     L0
  sub    %eax,%ebp
  movb   $0x31,(%rbx)
  jmp    L2
L30:
  mov    %rsp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type: string

tool: D2: %s


assistant: ```c
void binary(int digit) {
  int bits = sizeof(int) * 8;
  char output[bits];
  output[bits] = '\0';
  for (int i = bits; i >= 0; i--) {
    long tmp = pow(2, i);
    if (digit >= tmp) {
      digit -= tmp;
      output[bits - i] = '1';
    } else {
      output[bits - i] = '0';
    }
  }
  printf("%s\n", output);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<binary>:
  endbr64
  push   %r13
  mov    $0x20,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x20(%rsp)
  mov    %rsp,%r12
L21:
  mov    %r13d,%esi
  mov    $0x2,%edi
  sub    %ebx,%esi
  call   <pow@plt>
  movslq %ebp,%rdx
  mov    $0x30,%ecx
  cmp    %rax,%rdx
  jl     L3
  sub    %eax,%ebp
  mov    $0x31,%ecx
L3:
  mov    %cl,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x21,%rbx
  jne    L21
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9: %s


assistant: ```c
void binary(int digit) {
  int bits = sizeof(int) * 8;
  char output[bits];
  output[bits] = '\0';
  for (int i = bits; i >= 0; i--) {
    long tmp = pow(2, i);
    if (digit >= tmp) {
      digit -= tmp;
      output[bits - i] = '1';
    } else {
      output[bits - i] = '0';
    }
  }
  printf("%s\n", output);
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary>:
  endbr64
  push   %r14
  mov    $0x20,%r14d
  push   %r13
  push   %r12
  movslq %edi,%r12
  push   %rbp
  mov    %r12,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x20(%rsp)
  mov    %rsp,%r13
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %r14d,%esi
  mov    $0x2,%edi
  sub    %ebx,%esi
  call   <pow@plt>
  cmp    %rax,%r12
  jl     L39
  movb   $0x31,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  sub    %eax,%ebp
  cmp    $0x21,%rbx
  je     L47
  movslq %ebp,%r12
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L39:
  movb   $0x30,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x21,%rbx
  jne    L25
L47:
  mov    %r13,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string

tool: D9: %s


assistant: ```c
void binary(int digit) {
  int bits = sizeof(int) * 8;
  char output[bits];
  output[bits] = '\0';
  for (int i = bits; i >= 0; i--) {
    long tmp = pow(2, i);
    if (digit >= tmp) {
      digit -= tmp;
      output[bits - i] = '1';
    } else {
      output[bits - i] = '0';
    }
  }
  printf("%s\n", output);
}
```