ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<_symlink_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L13
L2:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L13:
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
  jmp    L2
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _symlink_exists(char *path) {
  struct stat buf;
  if (lstat(path, &buf)) {
    return 0;
  }
  if (!S_ISLNK(buf.st_mode)) {
    return -1;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_symlink_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L16
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _symlink_exists(char *path) {
  struct stat buf;
  if (lstat(path, &buf)) {
    return 0;
  }
  if (!S_ISLNK(buf.st_mode)) {
    return -1;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_symlink_exists>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <lstat@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L16
  mov    0x4(%rsp),%edi
  call   <S_ISLNK@plt>
  cmp    $0x1,%eax
  sbb    %eax,%eax
  or     $0x1,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _symlink_exists(char *path) {
  struct stat buf;
  if (lstat(path, &buf)) {
    return 0;
  }
  if (!S_ISLNK(buf.st_mode)) {
    return -1;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x4272a,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  cmp    %rax,-0x8(%rbp)
  jne    L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  long int a = 0x4272AL;
  if (foo(a) == a)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4272a,%edi
  call   <foo@plt>
  cmp    $0x4272a,%rax
  je     L7
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L7:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L8
```

assistant: ```c
int main() {
  long int a = 0x4272AL;
  if (foo(a) == a)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4272a,%edi
  call   <foo@plt>
  cmp    $0x4272a,%rax
  je     L15
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L15:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L0
```

assistant: ```c
int main() {
  long int a = 0x4272AL;
  if (foo(a) == a)
    abort();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4272a,%edi
  call   <foo@plt>
  cmp    $0x4272a,%rax
  je     L6
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L6:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L5
```

assistant: ```c
int main() {
  long int a = 0x4272AL;
  if (foo(a) == a)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<order_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L33
L30:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L42
L44:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x4,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L4
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L4:
  addl   $0x1,-0x8(%rbp)
L42:
  cmpl   $0x4,-0x8(%rbp)
  jle    L44
  addl   $0x1,-0xc(%rbp)
L33:
  cmpl   $0x3,-0xc(%rbp)
  jle    L30
  nop
  nop
  leave
  ret
```

assistant: ```c
void order_str(char (*p)[80]) {
  int i, j, k;
  char *temp;
  for (i = 0; i < 5 - 1; i++) {
    k = i;
    for (j = i + 1; j < 5; j++) {
      if (strcmp(*(p + k), *(p + j)) > 0) {
        k = j;
      }
    }
    if (k != i) {
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<order_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    0x50(%rdi),%r15
  mov    $0x0,%ebp
  jmp    L32
L19:
  add    $0x50,%r15
L2:
  mov    %r14d,%ebp
L32:
  lea    0x1(%rbp),%r14d
  cmp    $0x4,%r14d
  jg     L19
  mov    %r15,%r12
  mov    %r14d,%ebx
L14:
  movslq %ebp,%rax
  lea    (%rax,%rax,4),%rdi
  shl    $0x4,%rdi
  add    %r13,%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  cmovg  %ebx,%ebp
  add    $0x1,%ebx
  add    $0x50,%r12
  cmp    $0x5,%ebx
  jne    L14
  add    $0x50,%r15
  cmp    $0x4,%r14d
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void order_str(char (*p)[80]) {
  int i, j, k;
  char *temp;
  for (i = 0; i < 5 - 1; i++) {
    k = i;
    for (j = i + 1; j < 5; j++) {
      if (strcmp(*(p + k), *(p + j)) > 0) {
        k = j;
      }
    }
    if (k != i) {
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<order_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    0x50(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L17:
  mov    %ebx,%r15d
  add    $0x1,%ebx
  mov    %r12,%r14
  mov    %ebx,%r13d
L14:
  movslq %r15d,%rax
  mov    %r14,%rsi
  lea    (%rax,%rax,4),%rdi
  shl    $0x4,%rdi
  add    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  cmovg  %r13d,%r15d
  add    $0x1,%r13d
  add    $0x50,%r14
  cmp    $0x5,%r13d
  jne    L14
  add    $0x50,%r12
  cmp    $0x4,%ebx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void order_str(char (*p)[80]) {
  int i, j, k;
  char *temp;
  for (i = 0; i < 5 - 1; i++) {
    k = i;
    for (j = i + 1; j < 5; j++) {
      if (strcmp(*(p + k), *(p + j)) > 0) {
        k = j;
      }
    }
    if (k != i) {
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<order_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    0x50(%rdi),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
L15:
  mov    %ebx,%r15d
  add    $0x1,%ebx
  mov    %r12,%r14
  mov    %ebx,%r13d
L12:
  movslq %r15d,%rax
  mov    %r14,%rsi
  lea    (%rax,%rax,4),%rdi
  shl    $0x4,%rdi
  add    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  cmovg  %r13d,%r15d
  add    $0x1,%r13d
  add    $0x50,%r14
  cmp    $0x5,%r13d
  jne    L12
  add    $0x50,%r12
  cmp    $0x4,%ebx
  jne    L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void order_str(char (*p)[80]) {
  int i, j, k;
  char *temp;
  for (i = 0; i < 5 - 1; i++) {
    k = i;
    for (j = i + 1; j < 5; j++) {
      if (strcmp(*(p + k), *(p + j)) > 0) {
        k = j;
      }
    }
    if (k != i) {
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fesetround>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0xfffffffe,%eax
  test   %eax,%eax
  je     L5
  mov    $0x1,%eax
  jmp    L16
L5:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_FPU_GETCW@plt>
  andl   $0xfffffffe,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  or     %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_FPU_SETCW@plt>
  mov    $0x0,%eax
L16:
  leave
  ret
```

assistant: ```c
int fesetround(int round) {
  fpu_control_t cw;
  if ((round & ~0x1) != 0)
    return 1;
  _FPU_GETCW(cw);
  cw &= ~0x1;
  cw |= round;
  _FPU_SETCW(cw);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fesetround>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  and    $0xfffffffe,%ebp
  je     L5
  mov    $0x1,%ebp
L2:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <_FPU_GETCW@plt>
  mov    %ebx,%edi
  call   <_FPU_SETCW@plt>
  jmp    L2
```

assistant: ```c
int fesetround(int round) {
  fpu_control_t cw;
  if ((round & ~0x1) != 0)
    return 1;
  _FPU_GETCW(cw);
  cw &= ~0x1;
  cw |= round;
  _FPU_SETCW(cw);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fesetround>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  and    $0xfffffffe,%r12d
  je     L4
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L4:
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <_FPU_GETCW@plt>
  mov    %ebx,%edi
  call   <_FPU_SETCW@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int fesetround(int round) {
  fpu_control_t cw;
  if ((round & ~0x1) != 0)
    return 1;
  _FPU_GETCW(cw);
  cw &= ~0x1;
  cw |= round;
  _FPU_SETCW(cw);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fesetround>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbx
  sub    $0x8,%rsp
  and    $0xfffffffe,%r12d
  je     L8
  mov    $0x1,%r12d
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L8:
  mov    %edi,%ebx
  xor    %edi,%edi
  call   <_FPU_GETCW@plt>
  mov    %ebx,%edi
  call   <_FPU_SETCW@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int fesetround(int round) {
  fpu_control_t cw;
  if ((round & ~0x1) != 0)
    return 1;
  _FPU_GETCW(cw);
  cw &= ~0x1;
  cw |= round;
  _FPU_SETCW(cw);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D13(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  lea    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  movq   %rax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <vymen@plt>
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: f64
name: retrieve_data
arguments: data_label: D26
type_guessed: f64
name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D43
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string

tool: D13: 1.5

tool: D26: 3.3

tool: D9: X=%lf @ %p


tool: D43: Y=%lf @ %p


tool: D4: X=%lf


tool: D36: Y=%lf


assistant: ```c
int main() {
  double x = 1.5;
  double y = 3.3;
  printf("X=%lf @ %p\n", x, &x);
  printf("Y=%lf @ %p\n", y, &y);
  vymen(&x, &y);
  printf("X=%lf\n", x);
  printf("Y=%lf\n", y);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movsd  D25(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    D23(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    0x8(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  movsd  0x10(%rsp),%xmm0
  lea    D20(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <vymen@plt>
  movsd  0x8(%rsp),%xmm0
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  lea    D55(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D25
type_guessed: f64
name: parse_data
arguments: data_label: D23
type_guessed: f64
name: parse_data
arguments: data_label: D17
type_guessed: string
name: parse_data
arguments: data_label: D20
type_guessed: string
name: parse_data
arguments: data_label: D12
type_guessed: string
name: parse_data
arguments: data_label: D55
type_guessed: string

tool: D25: 1.5

tool: D23: 3.3

tool: D17: X=%lf @ %p


tool: D20: Y=%lf @ %p


tool: D12: X=%lf


tool: D55: Y=%lf


assistant: ```c
int main() {
  double x = 1.5;
  double y = 3.3;
  printf("X=%lf @ %p\n", x, &x);
  printf("Y=%lf @ %p\n", y, &y);
  vymen(&x, &y);
  printf("X=%lf\n", x);
  printf("Y=%lf\n", y);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  movsd  D57(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D39(%rip),%rax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  movsd  %xmm0,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %r12,%rsi
  lea    D44(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vymen@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string
name: disassemble_data
arguments: label: D57
type_guessed: f64
name: disassemble_data
arguments: label: D39
type_guessed: f64
name: disassemble_data
arguments: label: D44
type_guessed: string
name: disassemble_data
arguments: label: D14
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string

tool: D7: X=%lf @ %p


tool: D57: 1.5

tool: D39: 3.3

tool: D44: Y=%lf @ %p


tool: D14: X=%lf


tool: D17: Y=%lf


assistant: ```c
int main() {
  double x = 1.5;
  double y = 3.3;
  printf("X=%lf @ %p\n", x, &x);
  printf("Y=%lf @ %p\n", y, &y);
  vymen(&x, &y);
  printf("X=%lf\n", x);
  printf("Y=%lf\n", y);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D29(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  movsd  D59(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D2(%rip),%rax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  movsd  %xmm0,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    %r12,%rsi
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <vymen@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movsd  0x10(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D59
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D7
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string

tool: D29: X=%lf @ %p


tool: D59: 1.5

tool: D2: 3.3

tool: D15: Y=%lf @ %p


tool: D7: X=%lf


tool: D28: Y=%lf


assistant: ```c
int main() {
  double x = 1.5;
  double y = 3.3;
  printf("X=%lf @ %p\n", x, &x);
  printf("Y=%lf @ %p\n", y, &y);
  vymen(&x, &y);
  printf("X=%lf\n", x);
  printf("Y=%lf\n", y);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<baudrate_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x1c200,-0x18(%rbp)
  je     L90
  cmpq   $0x1c200,-0x18(%rbp)
  ja     L21
  cmpq   $0xe100,-0x18(%rbp)
  je     L237
  cmpq   $0xe100,-0x18(%rbp)
  ja     L21
  cmpq   $0x9600,-0x18(%rbp)
  je     L274
  cmpq   $0x9600,-0x18(%rbp)
  ja     L21
  cmpq   $0x4b00,-0x18(%rbp)
  je     L33
  cmpq   $0x4b00,-0x18(%rbp)
  ja     L21
  cmpq   $0x2580,-0x18(%rbp)
  je     L128
  cmpq   $0x2580,-0x18(%rbp)
  ja     L21
  cmpq   $0x12c0,-0x18(%rbp)
  je     L30
  cmpq   $0x12c0,-0x18(%rbp)
  ja     L21
  cmpq   $0x960,-0x18(%rbp)
  je     L257
  cmpq   $0x960,-0x18(%rbp)
  ja     L21
  cmpq   $0x4b0,-0x18(%rbp)
  je     L115
  cmpq   $0x4b0,-0x18(%rbp)
  ja     L21
  cmpq   $0x6e,-0x18(%rbp)
  je     L137
  cmpq   $0x12c,-0x18(%rbp)
  je     L228
  jmp    L21
L137:
  mov    D93(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L228:
  mov    D69(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L115:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L257:
  mov    D45(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L30:
  mov    D39(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L128:
  mov    D68(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L33:
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L274:
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L237:
  mov    D89(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L90:
  mov    D25(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L147
L21:
  movl   $0x0,-0x4(%rbp)
  nop
L147:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
speed_t baudrate_map(unsigned long b) {
  speed_t retval;
  switch (b) {
  case 110:
    retval = B110;
    break;
  case 300:
    retval = B300;
    break;
  case 1200:
    retval = B1200;
    break;
  case 2400:
    retval = B2400;
    break;
  case 4800:
    retval = B4800;
    break;
  case 9600:
    retval = B9600;
    break;
  case 19200:
    retval = B19200;
    break;
  case 38400:
    retval = B38400;
    break;
  case 57600:
    retval = B57600;
    break;
  case 115200:
    retval = B115200;
    break;
  default:
    retval = 0;
    break;
  }
  return (retval);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<baudrate_map>:
  endbr64
  cmp    $0x2580,%rdi
  je     L76
  ja     L62
  cmp    $0x4b0,%rdi
  je     L126
  jbe    L73
  cmp    $0x960,%rdi
  je     L85
  cmp    $0x12c0,%rdi
  jne    L127
  mov    D44(%rip),%rax
  mov    (%rax),%eax
  ret
L73:
  cmp    $0x6e,%rdi
  je     L44
  cmp    $0x12c,%rdi
  jne    L12
  mov    D80(%rip),%rax
  mov    (%rax),%eax
  ret
L12:
  mov    $0x0,%eax
  ret
L127:
  mov    $0x0,%eax
  ret
L62:
  cmp    $0xe100,%rdi
  je     L100
  jbe    L71
  cmp    $0x1c200,%rdi
  jne    L93
  mov    D92(%rip),%rax
  mov    (%rax),%eax
  ret
L71:
  cmp    $0x4b00,%rdi
  je     L14
  cmp    $0x9600,%rdi
  jne    L115
  mov    D69(%rip),%rax
  mov    (%rax),%eax
  ret
L115:
  mov    $0x0,%eax
  ret
L93:
  mov    $0x0,%eax
  ret
L44:
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  ret
L126:
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  ret
L85:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  ret
L76:
  mov    D87(%rip),%rax
  mov    (%rax),%eax
  ret
L14:
  mov    D47(%rip),%rax
  mov    (%rax),%eax
  ret
L100:
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
speed_t baudrate_map(unsigned long b) {
  speed_t retval;
  switch (b) {
  case 110:
    retval = B110;
    break;
  case 300:
    retval = B300;
    break;
  case 1200:
    retval = B1200;
    break;
  case 2400:
    retval = B2400;
    break;
  case 4800:
    retval = B4800;
    break;
  case 9600:
    retval = B9600;
    break;
  case 19200:
    retval = B19200;
    break;
  case 38400:
    retval = B38400;
    break;
  case 57600:
    retval = B57600;
    break;
  case 115200:
    retval = B115200;
    break;
  default:
    retval = 0;
    break;
  }
  return (retval);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<baudrate_map>:
  endbr64
  cmp    $0x2580,%rdi
  je     L17
  ja     L72
  cmp    $0x4b0,%rdi
  je     L112
  jbe    L36
  cmp    $0x960,%rdi
  je     L128
  cmp    $0x12c0,%rdi
  jne    L108
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  ret
  xchg   %ax,%ax
L72:
  cmp    $0xe100,%rdi
  je     L30
  jbe    L107
  cmp    $0x1c200,%rdi
  jne    L108
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
  xchg   %ax,%ax
L36:
  cmp    $0x6e,%rdi
  je     L41
  cmp    $0x12c,%rdi
  jne    L108
  mov    D53(%rip),%rax
  mov    (%rax),%eax
  ret
  nopl   0x0(%rax)
L107:
  cmp    $0x4b00,%rdi
  je     L63
  cmp    $0x9600,%rdi
  jne    L108
  mov    D75(%rip),%rax
  mov    (%rax),%eax
  ret
  nopl   0x0(%rax)
L108:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L128:
  mov    D67(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    D62(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  mov    D99(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  mov    D91(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L112:
  mov    D58(%rip),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
speed_t baudrate_map(unsigned long b) {
  speed_t retval;
  switch (b) {
  case 110:
    retval = B110;
    break;
  case 300:
    retval = B300;
    break;
  case 1200:
    retval = B1200;
    break;
  case 2400:
    retval = B2400;
    break;
  case 4800:
    retval = B4800;
    break;
  case 9600:
    retval = B9600;
    break;
  case 19200:
    retval = B19200;
    break;
  case 38400:
    retval = B38400;
    break;
  case 57600:
    retval = B57600;
    break;
  case 115200:
    retval = B115200;
    break;
  default:
    retval = 0;
    break;
  }
  return (retval);
}
```