ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<do_move>:
  endbr64
  mov    %edx,%r8d
  sar    $0x2,%r8d
  test   %r8d,%r8d
  jle    L3
  movslq %r8d,%r8
  xor    %eax,%eax
  nopl   (%rax)
L27:
  mov    (%rsi,%rax,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L27
  shl    $0x2,%rax
  add    %rax,%rdi
  add    %rax,%rsi
L3:
  and    $0x3,%edx
  je     L33
  xor    %eax,%eax
L24:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L24
L33:
  ret
```

assistant: ```c
void do_move(char *dst, char *src, int len) {
  int i;
  int *ldst, *lsrc;
  ldst = (int *)dst;
  lsrc = (int *)src;
  for (i = 0; i < (len >> 2); i++)
    *ldst++ = *lsrc++;
  dst = (char *)ldst;
  src = (char *)lsrc;
  for (i = 0; i < (len & 3); i++)
    *dst++ = *src++;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_move>:
  endbr64
  mov    %edx,%r8d
  mov    %rdi,%rcx
  sar    $0x2,%r8d
  test   %r8d,%r8d
  jle    L37
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L97
  lea    -0x1(%r8),%eax
  cmp    $0x2,%eax
  jbe    L97
  mov    %r8d,%edi
  xor    %eax,%eax
  shr    $0x2,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L28:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdi
  jne    L28
  mov    %r8d,%r9d
  mov    %r8d,%edi
  and    $0xfffffffc,%r9d
  mov    %r9d,%eax
  shl    $0x2,%rax
  lea    (%rcx,%rax,1),%r10
  add    %rsi,%rax
  cmp    %r9d,%r8d
  je     L4
  mov    (%rax),%r11d
  mov    %r11d,(%r10)
  lea    0x1(%r9),%r11d
  cmp    %r11d,%r8d
  jle    L4
  mov    0x4(%rax),%r11d
  add    $0x2,%r9d
  mov    %r11d,0x4(%r10)
  cmp    %r9d,%r8d
  jle    L4
  mov    0x8(%rax),%eax
  mov    %eax,0x8(%r10)
L4:
  shl    $0x2,%rdi
  add    %rdi,%rcx
  add    %rdi,%rsi
L37:
  and    $0x3,%edx
  je     L25
  movzbl (%rsi),%eax
  mov    %al,(%rcx)
  cmp    $0x1,%edx
  je     L25
  movzbl 0x1(%rsi),%eax
  mov    %al,0x1(%rcx)
  cmp    $0x3,%edx
  jne    L25
  movzbl 0x2(%rsi),%eax
  mov    %al,0x2(%rcx)
L25:
  ret
  nopl   0x0(%rax,%rax,1)
L97:
  mov    %r8d,%edi
  xor    %eax,%eax
  nopl   (%rax)
L112:
  mov    (%rsi,%rax,4),%r8d
  mov    %r8d,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L112
  jmp    L4
```

assistant: ```c
void do_move(char *dst, char *src, int len) {
  int i;
  int *ldst, *lsrc;
  ldst = (int *)dst;
  lsrc = (int *)src;
  for (i = 0; i < (len >> 2); i++)
    *ldst++ = *lsrc++;
  dst = (char *)ldst;
  src = (char *)lsrc;
  for (i = 0; i < (len & 3); i++)
    *dst++ = *src++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CheckZ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  movss  %xmm3,-0x10(%rbp)
  movss  -0x10(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L35
  mov    $0x0,%eax
  jmp    L20
L35:
  movss  -0x8(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L34
  mov    $0x0,%eax
  jmp    L20
L34:
  mov    $0x1,%eax
L20:
  pop    %rbp
  ret
```

assistant: ```c
int CheckZ(float Z, float z, float Z_tile, float z_tile) {
  if (Z < z_tile)
    return 0;
  if (z > Z_tile)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CheckZ>:
  endbr64
  mov    $0x0,%eax
  comiss %xmm0,%xmm3
  ja     L0
  comiss %xmm2,%xmm1
  setbe  %al
  movzbl %al,%eax
L0:
  ret
```

assistant: ```c
int CheckZ(float Z, float z, float Z_tile, float z_tile) {
  if (Z < z_tile)
    return 0;
  if (z > Z_tile)
    return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<CheckZ>:
  endbr64
  xor    %eax,%eax
  comiss %xmm0,%xmm3
  ja     L7
  xor    %eax,%eax
  comiss %xmm2,%xmm1
  setbe  %al
L7:
  ret
```

assistant: ```c
int CheckZ(float Z, float z, float Z_tile, float z_tile) {
  if (Z < z_tile)
    return 0;
  if (z > Z_tile)
    return 0;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CheckZ>:
  endbr64
  xor    %eax,%eax
  comiss %xmm0,%xmm3
  ja     L0
  xor    %eax,%eax
  comiss %xmm2,%xmm1
  setbe  %al
L0:
  ret
```

assistant: ```c
int CheckZ(float Z, float z, float Z_tile, float z_tile) {
  if (Z < z_tile)
    return 0;
  if (z > Z_tile)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <init@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cp@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = atoi(argv[1]);
  double *src = (double *)malloc(n * sizeof(double));
  double *dest = (double *)malloc(n * sizeof(double));
  init(src, n);
  cp(dest, src, n);
  free(src);
  free(dest);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebp
  lea    0x0(,%rax,8),%r12d
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <init@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <cp@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = atoi(argv[1]);
  double *src = (double *)malloc(n * sizeof(double));
  double *dest = (double *)malloc(n * sizeof(double));
  init(src, n);
  cp(dest, src, n);
  free(src);
  free(dest);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,8),%r13d
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <init@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <cp@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = atoi(argv[1]);
  double *src = (double *)malloc(n * sizeof(double));
  double *dest = (double *)malloc(n * sizeof(double));
  init(src, n);
  cp(dest, src, n);
  free(src);
  free(dest);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    0x0(,%rax,8),%r13d
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <init@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <cp@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = atoi(argv[1]);
  double *src = (double *)malloc(n * sizeof(double));
  double *dest = (double *)malloc(n * sizeof(double));
  init(src, n);
  cp(dest, src, n);
  free(src);
  free(dest);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xcexp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movq   %xmm0,%rax
  movapd %xmm1,%xmm0
  mov    %rax,%rdx
  movq   %xmm0,%rax
  movq   %rdx,%xmm1
  movq   %rax,%xmm0
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <g0@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <g1@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <g2@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm1,%rax
  movq   %xmm0,%rdx
  movq   %rdx,%xmm1
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
__complex__ double xcexp(__complex__ double x) {
  double r;
  r = g0(__real__ x);
  __real__ x = r * g1(__imag__ x);
  __imag__ x = r * g2(__imag__ x);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<xcexp>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm1,%rbx
  mov    $0x1,%eax
  call   <g0@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  %xmm2,(%rsp)
  movq   %rbx,%xmm0
  mov    $0x1,%eax
  call   <g1@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  (%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  movq   %rbx,%xmm0
  mov    $0x1,%eax
  call   <g2@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  0x8(%rsp),%xmm0
  mulsd  (%rsp),%xmm1
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
__complex__ double xcexp(__complex__ double x) {
  double r;
  r = g0(__real__ x);
  __real__ x = r * g1(__imag__ x);
  __imag__ x = r * g2(__imag__ x);
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xcexp>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%eax
  movsd  %xmm1,0x10(%rsp)
  call   <g0@plt>
  pxor   %xmm3,%xmm3
  movsd  0x10(%rsp),%xmm1
  cvtsi2sd %eax,%xmm3
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <g1@plt>
  pxor   %xmm2,%xmm2
  movsd  0x18(%rsp),%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  0x8(%rsp),%xmm2
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <g2@plt>
  movsd  0x10(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  add    $0x28,%rsp
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
__complex__ double xcexp(__complex__ double x) {
  double r;
  r = g0(__real__ x);
  __real__ x = r * g1(__imag__ x);
  __imag__ x = r * g2(__imag__ x);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xcexp>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x1,%eax
  movsd  %xmm1,0x10(%rsp)
  call   <g0@plt>
  pxor   %xmm3,%xmm3
  movsd  0x10(%rsp),%xmm1
  cvtsi2sd %eax,%xmm3
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <g1@plt>
  pxor   %xmm2,%xmm2
  movsd  0x18(%rsp),%xmm1
  cvtsi2sd %eax,%xmm2
  mulsd  0x8(%rsp),%xmm2
  mov    $0x1,%eax
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <g2@plt>
  movsd  0x10(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  0x8(%rsp),%xmm1
  add    $0x28,%rsp
  movapd %xmm2,%xmm0
  ret
```

assistant: ```c
__complex__ double xcexp(__complex__ double x) {
  double r;
  r = g0(__real__ x);
  __real__ x = r * g1(__imag__ x);
  __imag__ x = r * g2(__imag__ x);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<new_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L10
L16:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
L10:
  leave
  ret
```

assistant: ```c
char *new_str(char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<new_str>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
L3:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *new_str(char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<new_str>:
  endbr64
  test   %rdi,%rdi
  je     L2
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *new_str(char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: What is the c source code of the assembly code below:

```asm
<new_str>:
  endbr64
  test   %rdi,%rdi
  je     L4
  jmp    1050 <strdup@plt>
  xchg   %ax,%ax
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *new_str(char *str) {
  if (!str)
    return NULL;
  return strdup(str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dgemm0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L49
L22:
  movl   $0x0,-0x8(%rbp)
  jmp    L52
L58:
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L34:
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x4(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L34
  addl   $0x1,-0x8(%rbp)
L52:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L58
  addl   $0x1,-0xc(%rbp)
L49:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L22
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void dgemm0(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        c[i * n + j] += a[i * n + k] * b[k * n + j];
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dgemm0>:
  endbr64
  test   %ecx,%ecx
  jle    L12
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %ecx,%r11d
  movslq %ecx,%rsi
  shl    $0x3,%rsi
  mov    %rdi,%r10
  lea    -0x1(%rcx),%edx
  lea    0x8(%rdi,%rdx,8),%rdi
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L13
L10:
  lea    0x1(%r12),%eax
  add    %rsi,%r10
  add    %rsi,%rdi
  add    %rsi,%rbx
  cmp    %r9d,%r12d
  je     L56
  mov    %eax,%r12d
L13:
  mov    %rbp,%r8
  mov    %rbx,%rcx
  mov    %r13d,%r9d
L21:
  mov    %r8,%rdx
  mov    %r10,%rax
L19:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  add    %rsi,%rdx
  cmp    %rdi,%rax
  jne    L19
  lea    0x1(%r9),%eax
  add    $0x8,%r8
  add    $0x8,%rcx
  cmp    %eax,%r11d
  je     L10
  mov    %eax,%r9d
  jmp    L21
L56:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  ret
```

assistant: ```c
void dgemm0(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        c[i * n + j] += a[i * n + k] * b[k * n + j];
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dgemm0>:
  endbr64
  test   %ecx,%ecx
  jle    L3
  push   %r12
  lea    -0x1(%rcx),%eax
  mov    %rdi,%r10
  mov    %ecx,%r11d
  push   %rbp
  mov    %rsi,%rbp
  movslq %ecx,%rsi
  lea    0x8(%rdi,%rax,8),%rdi
  push   %rbx
  shl    $0x3,%rsi
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  xchg   %ax,%ax
L51:
  mov    %rbp,%r8
  mov    %rbx,%rcx
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L9:
  movsd  (%rcx),%xmm1
  mov    %r8,%rdx
  mov    %r10,%rax
  nopw   0x0(%rax,%rax,1)
L15:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rsi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rdi
  jne    L15
  lea    0x1(%r9),%eax
  add    $0x8,%rcx
  add    $0x8,%r8
  cmp    %eax,%r11d
  je     L23
  mov    %eax,%r9d
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L23:
  lea    0x1(%r12),%eax
  add    %rsi,%r10
  add    %rsi,%rdi
  add    %rsi,%rbx
  cmp    %r9d,%r12d
  je     L35
  mov    %eax,%r12d
  jmp    L51
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  ret
```

assistant: ```c
void dgemm0(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        c[i * n + j] += a[i * n + k] * b[k * n + j];
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dgemm0>:
  endbr64
  test   %ecx,%ecx
  jle    L40
  push   %r14
  mov    %rdi,%r10
  movslq %ecx,%r14
  lea    -0x1(%rcx),%eax
  push   %r13
  mov    %ecx,%r11d
  mov    %rdx,%r13
  lea    0x0(,%r14,8),%rdi
  push   %r12
  mov    %rsi,%r12
  lea    0x8(%r10,%rax,8),%rsi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  lea    0x0(%r13,%rbx,8),%rcx
  mov    %r12,%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax,%rax,1)
L23:
  movsd  (%rcx),%xmm1
  mov    %r8,%rdx
  mov    %r10,%rax
  nopw   0x0(%rax,%rax,1)
L20:
  movsd  (%rax),%xmm0
  mulsd  (%rdx),%xmm0
  add    $0x8,%rax
  add    %rdi,%rdx
  addsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx)
  cmp    %rax,%rsi
  jne    L20
  lea    0x1(%r9),%eax
  add    $0x8,%rcx
  add    $0x8,%r8
  cmp    %eax,%r11d
  je     L47
  mov    %eax,%r9d
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L47:
  lea    0x1(%rbp),%eax
  add    %rdi,%r10
  add    %rdi,%rsi
  add    %r14,%rbx
  cmp    %r9d,%ebp
  je     L2
  mov    %eax,%ebp
  jmp    L18
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  ret
```

assistant: ```c
void dgemm0(double *a, double *b, double *c, int n) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        c[i * n + j] += a[i * n + k] * b[k * n + j];
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<findMajority>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  shr    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L15:
  movl   $0x0,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L11
L45:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L53
  addl   $0x1,-0x8(%rbp)
L53:
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L45
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jbe    L65
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x1,%eax
  jmp    L42
L65:
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x1c(%rbp),%eax
  shr    %eax
  cmp    %eax,-0x10(%rbp)
  jbe    L15
  mov    $0x0,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
char findMajority(char m[], unsigned size, char *majority) {
  unsigned i, j, cnt, size2 = size / 2;
  for (i = 0; i <= size / 2; i++) {
    for (cnt = 0, j = i; j < size; j++)
      if (m[i] == m[j])
        cnt++;
    if (cnt > size2) {
      *majority = m[i];
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<findMajority>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r11d
  mov    %rdx,%r12
  mov    %esi,%r10d
  shr    %r10d
  mov    %rdi,%r9
  mov    $0x0,%r8d
  lea    -0x1(%rsi),%ebp
  jmp    L56
L8:
  lea    0x1(%r8),%eax
  add    $0x1,%r9
  cmp    %r8d,%r10d
  je     L25
  mov    %eax,%r8d
L56:
  cmp    %r8d,%r11d
  jbe    L8
  movzbl (%r9),%edi
  mov    %ebp,%eax
  sub    %r8d,%eax
  lea    0x1(%r9,%rax,1),%rsi
  mov    %r9,%rax
  mov    $0x0,%edx
L2:
  cmp    (%rax),%dil
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
  cmp    %r10d,%edx
  jbe    L8
  mov    %r8d,%r8d
  movzbl (%rbx,%r8,1),%eax
  mov    %al,(%r12)
  mov    $0x1,%eax
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    $0x0,%eax
  jmp    L20
```

assistant: ```c
char findMajority(char m[], unsigned size, char *majority) {
  unsigned i, j, cnt, size2 = size / 2;
  for (i = 0; i <= size / 2; i++) {
    for (cnt = 0, j = i; j < size; j++)
      if (m[i] == m[j])
        cnt++;
    if (cnt > size2) {
      *majority = m[i];
      return 1;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<findMajority>:
  endbr64
  mov    %esi,%r10d
  mov    %esi,%r11d
  xor    %r9d,%r9d
  push   %rbp
  shr    %r10d
  push   %rbx
  lea    -0x1(%rsi),%ebp
  mov    %rdx,%rbx
  cmp    %r9d,%r11d
  jbe    L64
  nopl   (%rax)
L29:
  movzbl (%rdi),%r8d
  mov    %ebp,%esi
  add    $0x1,%rdi
  xor    %edx,%edx
  sub    %r9d,%esi
  mov    %rdi,%rax
  add    %rdi,%rsi
  mov    %r8d,%ecx
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L13:
  movzbl (%rax),%ecx
  add    $0x1,%rax
L42:
  cmp    %cl,%r8b
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  cmp    %rsi,%rax
  jne    L13
  cmp    %r10d,%edx
  ja     L25
  lea    0x1(%r9),%eax
  cmp    %r9d,%r10d
  je     L16
L5:
  mov    %eax,%r9d
  cmp    %r9d,%r11d
  ja     L29
L64:
  add    $0x1,%rdi
  lea    0x1(%r9),%eax
  cmp    %r9d,%r10d
  jne    L5
L16:
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    %r8b,(%rbx)
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char findMajority(char m[], unsigned size, char *majority) {
  unsigned i, j, cnt, size2 = size / 2;
  for (i = 0; i <= size / 2; i++) {
    for (cnt = 0, j = i; j < size; j++)
      if (m[i] == m[j])
        cnt++;
    if (cnt > size2) {
      *majority = m[i];
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<wcp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %rsi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  jmp    L7
L1:
  mov    %rbx,%rax
  lea    0x1(%rax),%rbx
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x77,%eax
  je     L56
  cmp    $0x77,%eax
  jg     L7
  cmp    $0x63,%eax
  je     L3
  cmp    $0x6c,%eax
  jne    L7
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ipr@plt>
  jmp    L7
L56:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ipr@plt>
  jmp    L7
L3:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ipr@plt>
  nop
L7:
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L1
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
wcp(wd, charct, wordct, linect) register char *wd;
long charct;
long wordct;
long linect;
{
  while (*wd)
    switch (*wd++) {
    case 'l':
      ipr(linect);
      break;
    case 'w':
      ipr(wordct);
      break;
    case 'c':
      ipr(charct);
      break;
    }
}
```