user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D49(%rip),%r13
  push   %r12
  lea    D56(%rip),%r12
  push   %rbp
  lea    D57(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L43:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark1@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L43
  lea    D3(%rip),%r13
L55:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark2@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x6,%ebx
  jne    L55
  lea    D35(%rip),%r13
L7:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark3@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x9,%ebx
  jne    L7
  lea    D48(%rip),%r13
L27:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark4@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xc,%ebx
  jne    L27
  lea    D47(%rip),%r13
L0:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark5@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0xf,%ebx
  jne    L0
  lea    D34(%rip),%r13
L35:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark6@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    $0x12,%ebx
  jne    L35
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D49
type_guessed: string
name: retrieve_data
arguments: tag: D56
type_guessed: string
name: retrieve_data
arguments: tag: D57
type_guessed: string
name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D35
type_guessed: string
name: retrieve_data
arguments: tag: D48
type_guessed: string
name: retrieve_data
arguments: tag: D47
type_guessed: string
name: retrieve_data
arguments: tag: D34
type_guessed: string

tool: D49: # c::%s::instantiation


tool: D56: ok %d benchmark finished


tool: D57: base/mt19937

tool: D3: # c::%s:next


tool: D35: # c::%s:normalized


tool: D48: # c::%s::get:seed


tool: D47: # c::%s::get:state


tool: D34: # c::%s::set:state


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int i;
  count = 0;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    count += 1;
    printf("# c::%s::instantiation\n", "base/mt19937");
    elapsed = benchmark1();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", count);
  }
  for (i = 0; i < 3; i++) {
    count += 1;
    printf("# c::%s:next\n", "base/mt19937");
    elapsed = benchmark2();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", count);
  }
  for (i = 0; i < 3; i++) {
    count += 1;
    printf("# c::%s:normalized\n", "base/mt19937");
    elapsed = benchmark3();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", count);
  }
  for (i = 0; i < 3; i++) {
    count += 1;
    printf("# c::%s::get:seed\n", "base/mt19937");
    elapsed = benchmark4();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", count);
  }
  for (i = 0; i < 3; i++) {
    count += 1;
    printf("# c::%s::get:state\n", "base/mt19937");
    elapsed = benchmark5();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", count);
  }
  for (i = 0; i < 3; i++) {
    count += 1;
    printf("# c::%s::set:state\n", "base/mt19937");
    elapsed = benchmark6();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", count);
  }
  print_summary(count, count);
}
```