ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%edi
  call   <__print_int@plt>
  mov    $0x2,%edi
  call   <__print_int@plt>
  mov    $0x4,%edi
  call   <__print_int@plt>
  mov    $0x7,%edi
  call   <__print_int@plt>
  mov    $0x4,%edi
  call   <__print_int@plt>
  mov    $0x6,%edi
  call   <__print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a;
  a = 2;
  {} {{}} { __print_int(111); }
  {
    int b;
    b = 4;
    __print_int(a);
    __print_int(b);
    {
      int c;
      c = 7;
      a = 6;
      __print_int(c);
      __print_int(b);
      __print_int(a);
      return 0;
    }
    a = b;
  }
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%edi
  call   <__print_int@plt>
  mov    $0x2,%edi
  call   <__print_int@plt>
  mov    $0x4,%edi
  call   <__print_int@plt>
  mov    $0x7,%edi
  call   <__print_int@plt>
  mov    $0x4,%edi
  call   <__print_int@plt>
  mov    $0x6,%edi
  call   <__print_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a;
  a = 2;
  {} {{}} { __print_int(111); }
  {
    int b;
    b = 4;
    __print_int(a);
    __print_int(b);
    {
      int c;
      c = 7;
      a = 6;
      __print_int(c);
      __print_int(b);
      __print_int(a);
      return 0;
    }
    a = b;
  }
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x28(%rbp)
  jne    L18
  mov    $0x1,%edi
  call   <show_usage@plt>
L18:
  mov    D20(%rip),%rax
  movq   $0x0,(%rax)
  mov    -0x2c(%rbp),%edx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L8
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    D5(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jle    L40
L8:
  mov    $0x1,%edi
  call   <show_usage@plt>
L40:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int get_int(char *str, int base) {
  long v;
  char *endp;
  if (!str)
    show_usage(1);
  errno = 0;
  v = strtol(str, &endp, base);
  if (errno || *endp || v > INT_MAX)
    show_usage(1);
  return (int)v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L32
L59:
  mov    D6(%rip),%r12
  movq   $0x0,(%r12)
  mov    %rsp,%rsi
  mov    %ebp,%edx
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %rax,%rbx
  cmpq   $0x0,(%r12)
  jne    L2
  mov    (%rsp),%rax
  cmpb   $0x0,(%rax)
  jne    L2
  mov    D9(%rip),%rax
  cmp    %rbx,(%rax)
  jge    L10
L2:
  mov    $0x1,%edi
  call   <show_usage@plt>
L10:
  mov    %ebx,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  mov    $0x1,%edi
  call   <show_usage@plt>
  jmp    L59
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_int(char *str, int base) {
  long v;
  char *endp;
  if (!str)
    show_usage(1);
  errno = 0;
  v = strtol(str, &endp, base);
  if (errno || *endp || v > INT_MAX)
    show_usage(1);
  return (int)v;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_int>:
  endbr64
  push   %r12
  mov    %esi,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L49
L21:
  mov    D2(%rip),%r12
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  movq   $0x0,(%r12)
  call   <strtol@plt>
  cmpq   $0x0,(%r12)
  mov    %rax,%rbx
  jne    L11
  mov    0x10(%rsp),%rax
  cmpb   $0x0,(%rax)
  je     L19
L11:
  mov    $0x1,%edi
  call   <show_usage@plt>
L48:
  mov    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    D17(%rip),%rax
  cmp    %rbx,(%rax)
  jge    L48
  jmp    L11
  xchg   %ax,%ax
L49:
  mov    $0x1,%edi
  mov    %esi,0xc(%rsp)
  call   <show_usage@plt>
  mov    0xc(%rsp),%edx
  jmp    L21
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_int(char *str, int base) {
  long v;
  char *endp;
  if (!str)
    show_usage(1);
  errno = 0;
  v = strtol(str, &endp, base);
  if (errno || *endp || v > INT_MAX)
    show_usage(1);
  return (int)v;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_int>:
  endbr64
  push   %r12
  mov    %esi,%edx
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L22
L41:
  mov    D4(%rip),%r12
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  movq   $0x0,(%r12)
  call   <strtol@plt>
  cmpq   $0x0,(%r12)
  mov    %rax,%rbx
  jne    L33
  mov    0x10(%rsp),%rax
  cmpb   $0x0,(%rax)
  je     L26
L33:
  mov    $0x1,%edi
  call   <show_usage@plt>
L35:
  mov    %ebx,%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L55
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    D9(%rip),%rax
  cmp    %rbx,(%rax)
  jge    L35
  jmp    L33
  xchg   %ax,%ax
L22:
  mov    $0x1,%edi
  mov    %esi,0xc(%rsp)
  call   <show_usage@plt>
  mov    0xc(%rsp),%edx
  jmp    L41
L55:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_int(char *str, int base) {
  long v;
  char *endp;
  if (!str)
    show_usage(1);
  errno = 0;
  v = strtol(str, &endp, base);
  if (errno || *endp || v > INT_MAX)
    show_usage(1);
  return (int)v;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<okn_system_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <_okn_time_init@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int okn_system_init(void) {
  _okn_time_init();
  ;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<okn_system_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <_okn_time_init@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int okn_system_init(void) {
  _okn_time_init();
  ;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<okn_system_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_okn_time_init@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int okn_system_init(void) {
  _okn_time_init();
  ;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<okn_system_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <_okn_time_init@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int okn_system_init(void) {
  _okn_time_init();
  ;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_ED_0x6d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  mov    $0x4,%edi
  call   <RETI@plt>
  mov    $0xa,%edi
  call   <T_WAIT_UNTIL@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void op_ED_0x6d(void) {
  RETI(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<op_ED_0x6d>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x4,%edi
  call   <RETI@plt>
  mov    $0xa,%edi
  call   <T_WAIT_UNTIL@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void op_ED_0x6d(void) {
  RETI(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<op_ED_0x6d>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x7,%esi
  call   <RETI@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_ED_0x6d(void) {
  RETI(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_ED_0x6d>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  mov    $0x7,%esi
  call   <RETI@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <T_WAIT_UNTIL@plt>
```

assistant: ```c
void op_ED_0x6d(void) {
  RETI(4, 7);
  T_WAIT_UNTIL(10);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L1:
  mov    -0xc(%rbp),%eax
  imul   $0x989680,%eax,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    $0xe8c,%edx
  mov    %eax,%esi
  mov    $0x4f2e2,%edi
  call   <modOfPower@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L15:
  cmpl   $0x9,-0xc(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type_guessed: string

tool: D1: 324322^(%i) mod 3724 = %i


assistant: ```c
int main(void) {
  for (int i = 1; i < 10; i++) {
    int pow = i * 10000000;
    int value = modOfPower(324322, pow, 3724);
    printf("324322^(%i) mod 3724 = %i\n", pow, value);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x989680,%ebx
  lea    D1(%rip),%rbp
L3:
  mov    $0xe8c,%edx
  mov    %ebx,%esi
  mov    $0x4f2e2,%edi
  call   <modOfPower@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x989680,%ebx
  cmp    $0x5f5e100,%ebx
  jne    L3
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type_infered: string

tool: D1: 324322^(%i) mod 3724 = %i


assistant: ```c
int main(void) {
  for (int i = 1; i < 10; i++) {
    int pow = i * 10000000;
    int value = modOfPower(324322, pow, 3724);
    printf("324322^(%i) mod 3724 = %i\n", pow, value);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x989680,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ebx,%esi
  mov    $0xe8c,%edx
  mov    $0x4f2e2,%edi
  call   <modOfPower@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x989680,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x5f5e100,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type: string

tool: D1: 324322^(%i) mod 3724 = %i


assistant: ```c
int main(void) {
  for (int i = 1; i < 10; i++) {
    int pow = i * 10000000;
    int value = modOfPower(324322, pow, 3724);
    printf("324322^(%i) mod 3724 = %i\n", pow, value);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0x989680,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %ebx,%esi
  mov    $0xe8c,%edx
  mov    $0x4f2e2,%edi
  call   <modOfPower@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x989680,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x5f5e100,%ebx
  jne    L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: 324322^(%i) mod 3724 = %i


assistant: ```c
int main(void) {
  for (int i = 1; i < 10; i++) {
    int pow = i * 10000000;
    int value = modOfPower(324322, pow, 3724);
    printf("324322^(%i) mod 3724 = %i\n", pow, value);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<prod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movss  %xmm0,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  imul   %eax,%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L32
L49:
  movl   $0x0,-0x14(%rbp)
  jmp    L56
L55:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L28
L2:
  mov    -0x18(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L28:
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L2
  mov    -0x18(%rbp),%eax
  imul   -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movss  -0x38(%rbp),%xmm0
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L56:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L55
  addl   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L49
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
float *prod(float *A, float *B, int n, float alpha) {
  float *res = (float *)calloc(n * n, sizeof(float));
  int i, j, k;
  float sum;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      sum = 0;
      for (k = 0; k < n; k++) {
        sum += A[i * n + k] * B[k * n + j];
      }
      res[i * n + j] = alpha * sum;
    }
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prod>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  movss  %xmm0,0xc(%rsp)
  mov    %edx,%edi
  imul   %edx,%edi
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L30
  movslq %ebx,%rcx
  shl    $0x2,%rcx
  mov    %rax,%r10
  sub    %rbp,%r10
  mov    %r12,%r9
  lea    -0x1(%rbx),%eax
  lea    0x4(%r12,%rax,4),%rsi
  mov    $0x0,%r11d
  mov    $0x0,%r12d
  jmp    L27
L3:
  lea    0x1(%r11),%eax
  add    %rcx,%r10
  add    %rcx,%r9
  add    %rcx,%rsi
  cmp    %r8d,%r11d
  je     L30
  mov    %eax,%r11d
L27:
  mov    %rbp,%rdi
  mov    %r12d,%r8d
L49:
  mov    %rdi,%rdx
  mov    %r9,%rax
  pxor   %xmm1,%xmm1
L2:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  addss  %xmm0,%xmm1
  add    $0x4,%rax
  add    %rcx,%rdx
  cmp    %rsi,%rax
  jne    L2
  mulss  0xc(%rsp),%xmm1
  movss  %xmm1,(%rdi,%r10,1)
  lea    0x1(%r8),%eax
  add    $0x4,%rdi
  cmp    %eax,%ebx
  je     L3
  mov    %eax,%r8d
  jmp    L49
L30:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float *prod(float *A, float *B, int n, float alpha) {
  float *res = (float *)calloc(n * n, sizeof(float));
  int i, j, k;
  float sum;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      sum = 0;
      for (k = 0; k < n; k++) {
        sum += A[i * n + k] * B[k * n + j];
      }
      res[i * n + j] = alpha * sum;
    }
  }
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prod>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  imul   %edx,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L30
  mov    %rax,%r10
  movslq %r12d,%rcx
  lea    -0x1(%r12),%eax
  mov    %rbx,%r9
  movss  0xc(%rsp),%xmm2
  shl    $0x2,%rcx
  sub    %rbp,%r10
  xor    %r11d,%r11d
  lea    0x4(%rbx,%rax,4),%rsi
  pxor   %xmm3,%xmm3
  nop
L32:
  mov    %rbp,%rdi
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %rdi,%rdx
  mov    %r9,%rax
  movaps %xmm3,%xmm1
  nopl   0x0(%rax)
L54:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rcx,%rdx
  addss  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L54
  mulss  %xmm2,%xmm1
  lea    0x1(%r8),%eax
  movss  %xmm1,(%r10,%rdi,1)
  add    $0x4,%rdi
  cmp    %eax,%r12d
  je     L42
  mov    %eax,%r8d
  jmp    L18
  nopl   0x0(%rax)
L42:
  lea    0x1(%r11),%eax
  add    %rcx,%r10
  add    %rcx,%r9
  add    %rcx,%rsi
  cmp    %r11d,%r8d
  je     L30
  mov    %eax,%r11d
  jmp    L32
L30:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float *prod(float *A, float *B, int n, float alpha) {
  float *res = (float *)calloc(n * n, sizeof(float));
  int i, j, k;
  float sum;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      sum = 0;
      for (k = 0; k < n; k++) {
        sum += A[i * n + k] * B[k * n + j];
      }
      res[i * n + j] = alpha * sum;
    }
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<prod>:
  endbr64
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x4,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %edx,%edi
  imul   %edx,%edi
  sub    $0x18,%rsp
  movss  %xmm0,0xc(%rsp)
  call   <calloc@plt>
  mov    %rax,%r13
  test   %r12d,%r12d
  jle    L30
  mov    %rax,%r10
  movslq %r12d,%rcx
  lea    -0x1(%r12),%eax
  mov    %rbx,%r9
  movss  0xc(%rsp),%xmm2
  shl    $0x2,%rcx
  sub    %rbp,%r10
  xor    %r11d,%r11d
  lea    0x4(%rbx,%rax,4),%rsi
  pxor   %xmm3,%xmm3
  nop
L42:
  mov    %rbp,%rdi
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    %rdi,%rdx
  mov    %r9,%rax
  movaps %xmm3,%xmm1
  nopl   0x0(%rax)
L25:
  movss  (%rax),%xmm0
  mulss  (%rdx),%xmm0
  add    $0x4,%rax
  add    %rcx,%rdx
  addss  %xmm0,%xmm1
  cmp    %rax,%rsi
  jne    L25
  mulss  %xmm2,%xmm1
  lea    0x1(%r8),%eax
  movss  %xmm1,(%r10,%rdi,1)
  add    $0x4,%rdi
  cmp    %eax,%r12d
  je     L8
  mov    %eax,%r8d
  jmp    L26
  nopl   0x0(%rax)
L8:
  lea    0x1(%r11),%eax
  add    %rcx,%r10
  add    %rcx,%r9
  add    %rcx,%rsi
  cmp    %r11d,%r8d
  je     L30
  mov    %eax,%r11d
  jmp    L42
L30:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
float *prod(float *A, float *B, int n, float alpha) {
  float *res = (float *)calloc(n * n, sizeof(float));
  int i, j, k;
  float sum;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      sum = 0;
      for (k = 0; k < n; k++) {
        sum += A[i * n + k] * B[k * n + j];
      }
      res[i * n + j] = alpha * sum;
    }
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<unicode_read_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unicode_code_point_byte_header_utf8@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x4,-0x4(%rbp)
  je     L101
  cmpl   $0x4,-0x4(%rbp)
  jg     L137
  cmpl   $0x3,-0x4(%rbp)
  je     L121
  cmpl   $0x3,-0x4(%rbp)
  jg     L137
  cmpl   $0x1,-0x4(%rbp)
  je     L43
  cmpl   $0x2,-0x4(%rbp)
  je     L63
  jmp    L137
L43:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L116
L63:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x6,%eax
  and    $0xffffffc0,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  and    $0x3f,%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L116
L121:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0xc,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x6,%eax
  and    $0xffffffc0,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  and    $0x3f,%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L116
L101:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x6,%eax
  and    $0xffffffc0,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  and    $0x3f,%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L116
L137:
  mov    $0x0,%eax
  jmp    L11
L116:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <unicode_code_point_byte_requirement_utf8@plt>
  cmp    %eax,-0x4(%rbp)
  jne    L20
  mov    -0x4(%rbp),%eax
  jmp    L11
L20:
  mov    -0x4(%rbp),%eax
  neg    %eax
L11:
  leave
  ret
```

assistant: ```c
int unicode_read_utf8(char *string, uint32_t *code_point) {
  assert(string);
  assert(code_point);
  int width = unicode_code_point_byte_header_utf8(string[0]);
  switch (width) {
  case 1:
    *code_point = string[0];
    break;
  case 2:
    *code_point = ((string[0] & 0x1F) << 6) | (string[1] & 0x3F);
    break;
  case 3:
    *code_point = ((string[0] & 0x0F) << 12) | ((string[1] & 0x3F) << 6) | (string[2] & 0x3F);
    break;
  case 4:
    *code_point = ((string[0] & 0x07) << 18) | ((string[1] & 0x3F) << 12) | ((string[2] & 0x3F) << 6) | (string[3] & 0x3F);
    break;
  default:
    return 0;
  }
  if (unicode_code_point_byte_requirement_utf8(*code_point) == width)
    return width;
  else
    return -width;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<unicode_read_utf8>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <assert@plt>
  movsbl (%r12),%edi
  call   <unicode_code_point_byte_header_utf8@plt>
  mov    %eax,%ebx
  cmp    $0x3,%eax
  je     L11
  jg     L58
  cmp    $0x1,%eax
  je     L26
  cmp    $0x2,%eax
  jne    L44
  movsbl (%r12),%eax
  shl    $0x6,%eax
  movzbl 0x1(%r12),%edi
  and    $0x3f,%edi
  or     %eax,%edi
  jmp    L97
L44:
  mov    $0x0,%ebx
  jmp    L69
L58:
  cmp    $0x4,%eax
  jne    L35
  movsbl 0x2(%r12),%eax
  shl    $0x6,%eax
  movzbl 0x3(%r12),%edi
  and    $0x3f,%edi
  or     %eax,%edi
  jmp    L97
L35:
  mov    $0x0,%ebx
  jmp    L69
L26:
  movzbl (%r12),%edi
L97:
  mov    %dil,0x0(%rbp)
  movsbl %dil,%edi
  call   <unicode_code_point_byte_requirement_utf8@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  neg    %eax
  cmp    %ebx,%edx
  cmovne %eax,%ebx
L69:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  movsbl 0x1(%r12),%eax
  shl    $0x6,%eax
  movzbl 0x2(%r12),%edi
  and    $0x3f,%edi
  or     %eax,%edi
  jmp    L97
```

assistant: ```c
int unicode_read_utf8(char *string, uint32_t *code_point) {
  assert(string);
  assert(code_point);
  int width = unicode_code_point_byte_header_utf8(string[0]);
  switch (width) {
  case 1:
    *code_point = string[0];
    break;
  case 2:
    *code_point = ((string[0] & 0x1F) << 6) | (string[1] & 0x3F);
    break;
  case 3:
    *code_point = ((string[0] & 0x0F) << 12) | ((string[1] & 0x3F) << 6) | (string[2] & 0x3F);
    break;
  case 4:
    *code_point = ((string[0] & 0x07) << 18) | ((string[1] & 0x3F) << 12) | ((string[2] & 0x3F) << 6) | (string[3] & 0x3F);
    break;
  default:
    return 0;
  }
  if (unicode_code_point_byte_requirement_utf8(*code_point) == width)
    return width;
  else
    return -width;
}
```