ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ob_strtuc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L29
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L30
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L30:
  addq   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *ob_strtuc(char *str) {
  char *c = str;
  while ((*c) != 0) {
    if (((*c) >= 'a') && ((*c) <= 'z')) {
      (*c) -= ('a' - 'A');
    }
    c++;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ob_strtuc>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
  mov    %rdi,%rcx
  jmp    L15
L49:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L12
L15:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L49
  sub    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L49
L12:
  ret
```

assistant: ```c
char *ob_strtuc(char *str) {
  char *c = str;
  while ((*c) != 0) {
    if (((*c) >= 'a') && ((*c) <= 'z')) {
      (*c) -= ('a' - 'A');
    }
    c++;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ob_strtuc>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L21
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L12:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L26
  sub    $0x20,%edx
  mov    %dl,(%rcx)
L26:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L12
L21:
  ret
```

assistant: ```c
char *ob_strtuc(char *str) {
  char *c = str;
  while ((*c) != 0) {
    if (((*c) >= 'a') && ((*c) <= 'z')) {
      (*c) -= ('a' - 'A');
    }
    c++;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ob_strtuc>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L2
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L18:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L11
  sub    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L18
L2:
  ret
```

assistant: ```c
char *ob_strtuc(char *str) {
  char *c = str;
  while ((*c) != 0) {
    if (((*c) >= 'a') && ((*c) <= 'z')) {
      (*c) -= ('a' - 'A');
    }
    c++;
  }
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strsum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L19:
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int strsum(const char *str) {
  unsigned int sum = 0;
  while (*str)
    sum = (sum << 4) + *(str++);
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strsum>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L0
  mov    $0x0,%eax
L7:
  shl    $0x4,%eax
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L7
  ret
L0:
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned int strsum(const char *str) {
  unsigned int sum = 0;
  while (*str)
    sum = (sum << 4) + *(str++);
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strsum>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L15
  nopl   (%rax)
L11:
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L11
  ret
  nopl   0x0(%rax)
L15:
  ret
```

assistant: ```c
unsigned int strsum(const char *str) {
  unsigned int sum = 0;
  while (*str)
    sum = (sum << 4) + *(str++);
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strsum>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L15
  nopl   (%rax)
L7:
  shl    $0x4,%eax
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L7
  ret
  nopl   0x0(%rax)
L15:
  ret
```

assistant: ```c
unsigned int strsum(const char *str) {
  unsigned int sum = 0;
  while (*str)
    sum = (sum << 4) + *(str++);
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x20,-0x15(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pipe@plt>
  call   <fork@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0xffffffff,-0x14(%rbp)
  je     L21
  cmpl   $0x0,-0x14(%rbp)
  je     L19
  jmp    L60
L21:
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  jmp    L48
L19:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  jmp    L65
L61:
  mov    -0xc(%rbp),%eax
  lea    -0x15(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  movzbl -0x15(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x15(%rbp)
L65:
  movzbl -0x15(%rbp),%eax
  test   %al,%al
  jns    L61
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  jmp    L58
L60:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  jmp    L94
L63:
  lea    -0x15(%rbp),%rax
  mov    $0x1,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
L94:
  mov    -0x10(%rbp),%eax
  lea    -0x15(%rbp),%rcx
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %eax,%eax
  jne    L63
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x1,%edx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  nop
L58:
  mov    $0x0,%eax
L48:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D14
type: string

tool: D6: fork failed

tool: D14: 


assistant: ```c
int main(void) {
  unsigned char c = 32;
  int fds[2];
  pipe(fds);
  pid_t child = fork();
  switch (child) {
  case -1:
    perror("fork failed");
    return 1;
  case 0:
    close(fds[0]);
    while (c < 128) {
      write(fds[1], &c, 1);
      c++;
    }
    close(fds[1]);
    break;
  default:
    close(fds[1]);
    while (read(fds[0], &c, 1)) {
      write(1, &c, 1);
    }
    close(fds[0]);
    write(1, "\n", 1);
    break;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x20,0xf(%rsp)
  lea    0x10(%rsp),%rdi
  call   <pipe@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L80
  mov    %eax,%ebx
  test   %eax,%eax
  je     L37
  mov    0x14(%rsp),%edi
  call   <close@plt>
  lea    0xf(%rsp),%rbp
  jmp    L77
L80:
  lea    D4(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%ebx
L82:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    %ebx,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L37:
  mov    0x10(%rsp),%edi
  call   <close@plt>
  cmpb   $0x0,0xf(%rsp)
  js     L24
  lea    0xf(%rsp),%rbp
L45:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    0x14(%rsp),%edi
  mov    $0x0,%eax
  call   <write@plt>
  movzbl 0xf(%rsp),%eax
  add    $0x1,%eax
  mov    %al,0xf(%rsp)
  test   %al,%al
  jns    L45
L24:
  mov    0x14(%rsp),%edi
  call   <close@plt>
  jmp    L82
L39:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
L77:
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    0x10(%rsp),%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L39
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    $0x1,%edx
  lea    D7(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <write@plt>
  jmp    L82
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D4: fork failed

tool: D7: 


assistant: ```c
int main(void) {
  unsigned char c = 32;
  int fds[2];
  pipe(fds);
  pid_t child = fork();
  switch (child) {
  case -1:
    perror("fork failed");
    return 1;
  case 0:
    close(fds[0]);
    while (c < 128) {
      write(fds[1], &c, 1);
      c++;
    }
    close(fds[1]);
    break;
  default:
    close(fds[1]);
    while (read(fds[0], &c, 1)) {
      write(1, &c, 1);
    }
    close(fds[0]);
    write(1, "\n", 1);
    break;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movb   $0x20,0xf(%rsp)
  call   <pipe@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L14
  mov    %eax,%r12d
  test   %eax,%eax
  je     L54
  mov    0x14(%rsp),%edi
  lea    0xf(%rsp),%rbx
  call   <close@plt>
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L82:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <write@plt>
L59:
  mov    0x10(%rsp),%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L82
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    $0x1,%edx
  lea    D18(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <write@plt>
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L14:
  lea    D1(%rip),%rdi
  mov    $0x1,%r12d
  call   <perror@plt>
  jmp    L19
L54:
  mov    0x10(%rsp),%edi
  call   <close@plt>
  cmpb   $0x0,0xf(%rsp)
  js     L27
  lea    0xf(%rsp),%rbx
  nopl   0x0(%rax)
L46:
  mov    0x14(%rsp),%edi
  xor    %eax,%eax
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <write@plt>
  addb   $0x1,0xf(%rsp)
  jns    L46
L27:
  mov    0x14(%rsp),%edi
  call   <close@plt>
  jmp    L19
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D1
data_type: string

tool: D18: 


tool: D1: fork failed

assistant: ```c
int main(void) {
  unsigned char c = 32;
  int fds[2];
  pipe(fds);
  pid_t child = fork();
  switch (child) {
  case -1:
    perror("fork failed");
    return 1;
  case 0:
    close(fds[0]);
    while (c < 128) {
      write(fds[1], &c, 1);
      c++;
    }
    close(fds[1]);
    break;
  default:
    close(fds[1]);
    while (read(fds[0], &c, 1)) {
      write(1, &c, 1);
    }
    close(fds[0]);
    write(1, "\n", 1);
    break;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movb   $0x20,0xf(%rsp)
  call   <pipe@plt>
  call   <fork@plt>
  cmp    $0xffffffff,%eax
  je     L86
  mov    %eax,%r12d
  test   %eax,%eax
  je     L88
  mov    0x14(%rsp),%edi
  lea    0xf(%rsp),%rbx
  call   <close@plt>
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L71:
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <write@plt>
L31:
  mov    0x10(%rsp),%edi
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <read@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L71
  mov    0x10(%rsp),%edi
  call   <close@plt>
  mov    $0x1,%edx
  lea    D5(%rip),%rsi
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <write@plt>
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
L86:
  lea    D7(%rip),%rdi
  mov    $0x1,%r12d
  call   <perror@plt>
  jmp    L2
L88:
  mov    0x10(%rsp),%edi
  call   <close@plt>
  cmpb   $0x0,0xf(%rsp)
  js     L8
  lea    0xf(%rsp),%rbx
  nopl   0x0(%rax)
L46:
  mov    0x14(%rsp),%edi
  xor    %eax,%eax
  mov    $0x1,%edx
  mov    %rbx,%rsi
  call   <write@plt>
  addb   $0x1,0xf(%rsp)
  jns    L46
L8:
  mov    0x14(%rsp),%edi
  call   <close@plt>
  jmp    L2
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string
name: disassemble_data
arguments: data_tag: D7
type: string

tool: D5: 


tool: D7: fork failed

assistant: ```c
int main(void) {
  unsigned char c = 32;
  int fds[2];
  pipe(fds);
  pid_t child = fork();
  switch (child) {
  case -1:
    perror("fork failed");
    return 1;
  case 0:
    close(fds[0]);
    while (c < 128) {
      write(fds[1], &c, 1);
      c++;
    }
    close(fds[1]);
    break;
  default:
    close(fds[1]);
    while (read(fds[0], &c, 1)) {
      write(1, &c, 1);
    }
    close(fds[0]);
    write(1, "\n", 1);
    break;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<builtin_no_leak>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L3
L3:
  leave
  ret
```

assistant: ```c
void *builtin_no_leak(size_t s) {
  char *str = malloc(sizeof(s));
  if (str) {
    return memset(str, 0, s);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<builtin_no_leak>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L8
L10:
  pop    %rbx
  ret
L8:
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  jmp    L10
```

assistant: ```c
void *builtin_no_leak(size_t s) {
  char *str = malloc(sizeof(s));
  if (str) {
    return memset(str, 0, s);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<builtin_no_leak>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L1
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  pop    %r12
  jmp    1060 <memset@plt>
```

assistant: ```c
void *builtin_no_leak(size_t s) {
  char *str = malloc(sizeof(s));
  if (str) {
    return memset(str, 0, s);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<builtin_no_leak>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x8,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L1
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  pop    %r12
  jmp    1060 <memset@plt>
```

assistant: ```c
void *builtin_no_leak(size_t s) {
  char *str = malloc(sizeof(s));
  if (str) {
    return memset(str, 0, s);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<domagadd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  addsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void domagadd(int N, double *mag, double addval) {
  int i;
  for (i = 0; i < N; i++)
    mag[i] += addval;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<domagadd>:
  endbr64
  test   %edi,%edi
  jle    L2
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rdx
L14:
  movapd %xmm0,%xmm1
  addsd  (%rax),%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L14
L2:
  ret
```

assistant: ```c
void domagadd(int N, double *mag, double addval) {
  int i;
  for (i = 0; i < N; i++)
    mag[i] += addval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<domagadd>:
  endbr64
  test   %edi,%edi
  jle    L15
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rax
L18:
  movsd  (%rsi),%xmm1
  add    $0x8,%rsi
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rsi)
  cmp    %rax,%rsi
  jne    L18
L15:
  ret
```

assistant: ```c
void domagadd(int N, double *mag, double addval) {
  int i;
  for (i = 0; i < N; i++)
    mag[i] += addval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<domagadd>:
  endbr64
  test   %edi,%edi
  jle    L40
  cmp    $0x1,%edi
  je     L14
  mov    %edi,%edx
  movapd %xmm0,%xmm2
  mov    %rsi,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L1:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  addpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L1
  mov    %edi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edi
  je     L32
L16:
  cltq
  lea    (%rsi,%rax,8),%rax
  addsd  (%rax),%xmm0
  movsd  %xmm0,(%rax)
L40:
  ret
  xchg   %ax,%ax
L32:
  ret
L14:
  xor    %eax,%eax
  jmp    L16
```

assistant: ```c
void domagadd(int N, double *mag, double addval) {
  int i;
  for (i = 0; i < N; i++)
    mag[i] += addval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readnb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L32
L53:
  cmpq   $0x0,-0x20(%rbp)
  jne    L95
  mov    $0x0,%eax
  jmp    L32
L95:
  cmpq   $0x0,-0x28(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L32
L13:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <rewind@plt>
L119:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <read4k@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L82
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  jmp    L107
L82:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jae    L77
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  jmp    L107
L77:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jbe    L107
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
L107:
  cmpl   $0x0,-0x8(%rbp)
  je     L69
  cmpl   $0x0,-0x4(%rbp)
  jne    L119
L69:
  mov    -0xc(%rbp),%eax
L32:
  leave
  ret
```

assistant: ```c
unsigned int readnb(unsigned int n, FILE *fp, char *copybuf) {
  unsigned int read = 0, read_bytes = 0;
  unsigned int remaining = n;
  if (!n)
    return 0;
  if (!fp)
    return 0;
  if (!copybuf)
    return 0;
  rewind(fp);
  do {
    read_bytes = read4k(fp, copybuf);
    if (read_bytes == remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = remaining - read_bytes;
    } else if (read_bytes < remaining) {
      ;
      ("%.*s", read_bytes, copybuf);
      read = read + read_bytes;
      remaining = remaining - read_bytes;
    } else if (read_bytes > remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = 0;
    }
  } while (remaining && read_bytes);
  return read;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readnb>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L37
  mov    %edi,%ebx
  mov    %rsi,%rbp
  test   %edi,%edi
  je     L37
  mov    %rsi,%rdi
  call   <rewind@plt>
  mov    $0x0,%r12d
  jmp    L51
L103:
  add    %ebx,%r12d
L38:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L105:
  jae    L36
  add    %ebx,%r12d
  jmp    L38
L36:
  test   %ebx,%ebx
  je     L38
  test   %eax,%eax
  je     L38
L51:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <read4k@plt>
  cmp    %eax,%ebx
  je     L103
  jbe    L105
  add    %eax,%r12d
  sub    %eax,%ebx
  jmp    L36
L37:
  mov    $0x0,%r12d
  jmp    L38
```

assistant: ```c
unsigned int readnb(unsigned int n, FILE *fp, char *copybuf) {
  unsigned int read = 0, read_bytes = 0;
  unsigned int remaining = n;
  if (!n)
    return 0;
  if (!fp)
    return 0;
  if (!copybuf)
    return 0;
  rewind(fp);
  do {
    read_bytes = read4k(fp, copybuf);
    if (read_bytes == remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = remaining - read_bytes;
    } else if (read_bytes < remaining) {
      ;
      ("%.*s", read_bytes, copybuf);
      read = read + read_bytes;
      remaining = remaining - read_bytes;
    } else if (read_bytes > remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = 0;
    }
  } while (remaining && read_bytes);
  return read;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readnb>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %dl,%al
  jne    L42
  mov    %edi,%ebx
  test   %edi,%edi
  je     L42
  mov    %rsi,%rdi
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  call   <rewind@plt>
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L73:
  jbe    L78
  add    %eax,%r12d
  sub    %eax,%ebx
L54:
  test   %eax,%eax
  je     L46
L31:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <read4k@plt>
  cmp    %eax,%ebx
  jne    L73
  add    %ebx,%r12d
L41:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  xor    %r12d,%r12d
L46:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L78:
  jae    L54
  add    %ebx,%r12d
  jmp    L41
```

assistant: ```c
unsigned int readnb(unsigned int n, FILE *fp, char *copybuf) {
  unsigned int read = 0, read_bytes = 0;
  unsigned int remaining = n;
  if (!n)
    return 0;
  if (!fp)
    return 0;
  if (!copybuf)
    return 0;
  rewind(fp);
  do {
    read_bytes = read4k(fp, copybuf);
    if (read_bytes == remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = remaining - read_bytes;
    } else if (read_bytes < remaining) {
      ;
      ("%.*s", read_bytes, copybuf);
      read = read + read_bytes;
      remaining = remaining - read_bytes;
    } else if (read_bytes > remaining) {
      ;
      ("%.*s", remaining, copybuf);
      read = read + remaining;
      remaining = 0;
    }
  } while (remaining && read_bytes);
  return read;
}
```