ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L16
  lea    D26(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L27:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x70,%rsp
  pop    %rbp
  ret
L16:
  mov    %rbp,%rsi
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L27
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_infered: string
name: extract_symbolic_data
arguments: data_label: D35
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string

tool: D4: Hello. Please include your name: 

tool: D35: %s

tool: D26: Error!

tool: D38: Nice to meet you %s


assistant: ```c
int main(void) {
  char name[100];
  printf("Hello. Please include your name: ");
  if (scanf("%s", name) != 1) {
    printf("Error!\n");
    return 1;
  } else {
    printf("Nice to meet you %s\n", name);
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flip_triple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L6
  cmpl   $0x1,-0x4(%rbp)
  setne  %al
  movzbl %al,%eax
  jmp    L31
L6:
  cmpl   $0x2,-0x4(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L31
L13:
  mov    $0x2,%eax
L31:
  pop    %rbp
  ret
```

assistant: ```c
int flip_triple(val, lc)
int val;
int lc;
{
  if (lc)
    return ((val == 1) ? 0 : 1);
  else
    return ((val == 2) ? 0 : 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<flip_triple>:
  endbr64
  test   %esi,%esi
  je     L6
  cmp    $0x1,%edi
  setne  %al
  movzbl %al,%eax
  ret
L6:
  cmp    $0x2,%edi
  setne  %al
  movzbl %al,%eax
  add    %eax,%eax
  ret
```

assistant: ```c
int flip_triple(val, lc)
int val;
int lc;
{
  if (lc)
    return ((val == 1) ? 0 : 1);
  else
    return ((val == 2) ? 0 : 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<flip_triple>:
  endbr64
  test   %esi,%esi
  je     L6
  xor    %eax,%eax
  cmp    $0x1,%edi
  setne  %al
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  cmp    $0x2,%edi
  setne  %al
  add    %eax,%eax
  ret
```

assistant: ```c
int flip_triple(val, lc)
int val;
int lc;
{
  if (lc)
    return ((val == 1) ? 0 : 1);
  else
    return ((val == 2) ? 0 : 2);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<myesc>:
  endbr64
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x48,%dl
  ja     L6
  push   %r12
  push   %rbp
  push   %rbx
  movzbl %dl,%edx
  lea    D0(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0xc,%eax
  jmp    L101
  lea    0x2(%rdi),%rbx
  mov    %rbx,%rbp
L109:
  mov    %rbp,%r12
  movzbl 0x0(%rbp),%edi
  call   <isxdigit@plt>
  add    $0x1,%rbp
  test   %eax,%eax
  jne    L109
  movzbl (%r12),%ebp
  movb   $0x0,(%r12)
  mov    %rbx,%rdi
  call   <htoi@plt>
  mov    %bpl,(%r12)
  jmp    L101
  lea    0x1(%rdi),%rbx
  mov    %rbx,%rbp
L82:
  mov    %rbp,%r12
  movzbl 0x0(%rbp),%edi
  call   <isdigit@plt>
  add    $0x1,%rbp
  test   %eax,%eax
  jne    L82
  movzbl (%r12),%ebp
  movb   $0x0,(%r12)
  mov    %rbx,%rdi
  call   <otoi@plt>
  mov    %bpl,(%r12)
  jmp    L101
  mov    $0xa,%eax
L101:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  mov    $0xd,%eax
  jmp    L101
  mov    $0x9,%eax
  jmp    L101
  mov    $0x7,%eax
  jmp    L101
  mov    $0xb,%eax
  jmp    L101
  mov    $0x8,%eax
  jmp    L101
L6:
  ret
```

assistant: ```c
unsigned char myesc(unsigned char *array) {
  unsigned char c, esc_char;
  switch (array[1]) {
  case 'b':
    return '\b';
  case 'f':
    return '\f';
  case 'n':
    return '\n';
  case 'r':
    return '\r';
  case 't':
    return '\t';
  case 'a':
    return '\a';
  case 'v':
    return '\v';
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7': {
    int sptr = 1;
    while (isdigit((unsigned char)array[sptr])) {
      ++sptr;
    }
    c = array[sptr];
    array[sptr] = '\0';
    esc_char = (unsigned char)otoi(array + 1);
    array[sptr] = c;
    return esc_char;
  }
  case 'x': {
    int sptr = 2;
    while (isxdigit((unsigned char)array[sptr])) {
      ++sptr;
    }
    c = array[sptr];
    array[sptr] = '\0';
    esc_char = (unsigned char)htoi(array + 2);
    array[sptr] = c;
    return esc_char;
  }
  default:
    return array[1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<myesc>:
  endbr64
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x48,%dl
  ja     L48
  push   %r13
  lea    D1(%rip),%rcx
  movzbl %dl,%edx
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax)
  lea    0x2(%rdi),%rbp
  mov    %rbp,%rbx
  nop
L1:
  movzbl (%rbx),%edi
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L1
  movzbl (%r12),%ebx
  movb   $0x0,(%r12)
  mov    %rbp,%rdi
  call   <htoi@plt>
  mov    %bl,(%r12)
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L48:
  ret
  nopl   0x0(%rax)
  lea    0x1(%rdi),%r12
  mov    $0x1,%ebp
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L56:
  movzbl (%rbx,%rbp,1),%eax
L46:
  movzbl %al,%edi
  movslq %ebp,%r13
  add    $0x1,%rbp
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L56
  add    %r13,%rbx
  mov    %r12,%rdi
  movzbl (%rbx),%ebp
  movb   $0x0,(%rbx)
  call   <otoi@plt>
  mov    %bpl,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
  add    $0x8,%rsp
  mov    $0x7,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  add    $0x8,%rsp
  mov    $0xa,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  add    $0x8,%rsp
  mov    $0xd,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  add    $0x8,%rsp
  mov    $0x9,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  add    $0x8,%rsp
  mov    $0xb,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  mov    $0x8,%eax
  jmp    L3
  nopw   0x0(%rax,%rax,1)
  mov    $0xc,%eax
  jmp    L3
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: 

assistant: ```c
unsigned char myesc(unsigned char *array) {
  unsigned char c, esc_char;
  switch (array[1]) {
  case 'b':
    return '\b';
  case 'f':
    return '\f';
  case 'n':
    return '\n';
  case 'r':
    return '\r';
  case 't':
    return '\t';
  case 'a':
    return '\a';
  case 'v':
    return '\v';
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7': {
    int sptr = 1;
    while (isdigit((unsigned char)array[sptr])) {
      ++sptr;
    }
    c = array[sptr];
    array[sptr] = '\0';
    esc_char = (unsigned char)otoi(array + 1);
    array[sptr] = c;
    return esc_char;
  }
  case 'x': {
    int sptr = 2;
    while (isxdigit((unsigned char)array[sptr])) {
      ++sptr;
    }
    c = array[sptr];
    array[sptr] = '\0';
    esc_char = (unsigned char)htoi(array + 2);
    array[sptr] = c;
    return esc_char;
  }
  default:
    return array[1];
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<myesc>:
  endbr64
  movzbl 0x1(%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x48,%dl
  ja     L12
  lea    D7(%rip),%rcx
  movzbl %dl,%edx
  push   %r12
  movslq (%rcx,%rdx,4),%rdx
  push   %rbp
  push   %rbx
  add    %rcx,%rdx
  notrack jmp *%rdx
  nopl   0x0(%rax,%rax,1)
  lea    0x2(%rdi),%rbp
  mov    %rbp,%rbx
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl (%rbx),%edi
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L14
  movzbl (%r12),%ebx
  movb   $0x0,(%r12)
  mov    %rbp,%rdi
  call   <htoi@plt>
  mov    %bl,(%r12)
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L12:
  ret
  nopl   0x0(%rax)
  lea    0x1(%rdi),%rbp
  mov    %rbp,%rbx
  nop
L10:
  movzbl (%rbx),%edi
  mov    %rbx,%r12
  add    $0x1,%rbx
  call   <isdigit@plt>
  test   %eax,%eax
  jne    L10
  movzbl (%r12),%ebx
  movb   $0x0,(%r12)
  mov    %rbp,%rdi
  call   <otoi@plt>
  mov    %bl,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
  pop    %rbx
  mov    $0x7,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
  pop    %rbx
  mov    $0xa,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
  pop    %rbx
  mov    $0xd,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
  pop    %rbx
  mov    $0x9,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
  pop    %rbx
  mov    $0xb,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
  mov    $0x8,%eax
  jmp    L35
  nopw   0x0(%rax,%rax,1)
  mov    $0xc,%eax
  jmp    L35
```

assistant: ```c
unsigned char myesc(unsigned char *array) {
  unsigned char c, esc_char;
  switch (array[1]) {
  case 'b':
    return '\b';
  case 'f':
    return '\f';
  case 'n':
    return '\n';
  case 'r':
    return '\r';
  case 't':
    return '\t';
  case 'a':
    return '\a';
  case 'v':
    return '\v';
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7': {
    int sptr = 1;
    while (isdigit((unsigned char)array[sptr])) {
      ++sptr;
    }
    c = array[sptr];
    array[sptr] = '\0';
    esc_char = (unsigned char)otoi(array + 1);
    array[sptr] = c;
    return esc_char;
  }
  case 'x': {
    int sptr = 2;
    while (isxdigit((unsigned char)array[sptr])) {
      ++sptr;
    }
    c = array[sptr];
    array[sptr] = '\0';
    esc_char = (unsigned char)htoi(array + 2);
    array[sptr] = c;
    return esc_char;
  }
  default:
    return array[1];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%esi
  lea    D29(%rip),%r12
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x0,%esi
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edx
  mov    $0x6,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xfffffffc,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D29
data_type: string
name: read_data
arguments: data_tag: D15
data_type: string
name: read_data
arguments: data_tag: D3
data_type: string

tool: D29: %d 
 


tool: D15: %d %d 


tool: D3: %d 


assistant: ```c
int main() {
  int a = 3;
  a = a + 3;
  a = a - 3;
  a = a * 3;
  a = a / 3;
  a = a % 3;
  printf("%d \n \n", a);
  int x = 3, y = 2;
  printf("%d %d \n", x == y, x != y);
  printf("%d %d \n", x > y, x <= y);
  printf("%d \n", (x > y) && (x <= y));
  printf("%d \n", (x > y) || (x <= y));
  printf("%d \n \n", !(x > y));
  printf("%d %d \n", 3 & 1, 3 | 1);
  printf("%d \n", 3 ^ 1);
  printf("%d %d \n", 3 << 1, 3 >> 1);
  printf("%d \n", ~3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  xor    %esi,%esi
  xor    %eax,%eax
  push   %r12
  mov    %r13,%rdi
  lea    D8(%rip),%r12
  push   %rbp
  lea    D14(%rip),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xfffffffc,%esi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D0
type_guessed: string
name: parse_data
arguments: label: D8
type_guessed: string
name: parse_data
arguments: label: D14
type_guessed: string

tool: D0: %d 
 


tool: D8: %d %d 


tool: D14: %d 


assistant: ```c
int main() {
  int a = 3;
  a = a + 3;
  a = a - 3;
  a = a * 3;
  a = a / 3;
  a = a % 3;
  printf("%d \n \n", a);
  int x = 3, y = 2;
  printf("%d %d \n", x == y, x != y);
  printf("%d %d \n", x > y, x <= y);
  printf("%d \n", (x > y) && (x <= y));
  printf("%d \n", (x > y) || (x <= y));
  printf("%d \n \n", !(x > y));
  printf("%d %d \n", 3 & 1, 3 | 1);
  printf("%d \n", 3 ^ 1);
  printf("%d %d \n", 3 << 1, 3 >> 1);
  printf("%d \n", ~3);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%r13
  xor    %esi,%esi
  xor    %eax,%eax
  push   %r12
  mov    %r13,%rdi
  lea    D17(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %edx,%edx
  mov    %r12,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    $0x1,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x1,%edx
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xfffffffc,%esi
  xor    %eax,%eax
  call   <printf@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D27
type_infered: string

tool: D13: %d 
 


tool: D17: %d %d 


tool: D27: %d 


assistant: ```c
int main() {
  int a = 3;
  a = a + 3;
  a = a - 3;
  a = a * 3;
  a = a / 3;
  a = a % 3;
  printf("%d \n \n", a);
  int x = 3, y = 2;
  printf("%d %d \n", x == y, x != y);
  printf("%d %d \n", x > y, x <= y);
  printf("%d \n", (x > y) && (x <= y));
  printf("%d \n", (x > y) || (x <= y));
  printf("%d \n \n", !(x > y));
  printf("%d %d \n", 3 & 1, 3 | 1);
  printf("%d \n", 3 ^ 1);
  printf("%d %d \n", 3 << 1, 3 >> 1);
  printf("%d \n", ~3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<filt_r_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L0
  addq   $0x1,-0x10(%rbp)
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  lea    D27(%rip),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  add    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x200,%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  lea    D2(%rip),%rdx
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  jmp    L14
L0:
  nop
L14:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string
name: disassemble_data
arguments: data_tag: D2
type_guessed: string

tool: D25: Jul 27 14:50:37 

tool: D27: %s

tool: D2:  PPPoE access success


assistant: ```c
void filt_r_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  if (!p1)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  snprintf(cur - 1, msg + 512 - cur, " PPPoE access success\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<filt_r_message>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x3e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  mov    %rax,%rbx
  lea    D19(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rbx),%rcx
  lea    D17(%rip),%rdx
  mov    %eax,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <snprintf@plt>
  movslq %ebp,%rbp
  lea    -0x1(%r12,%rbp,1),%rdi
  lea    D26(%rip),%rdx
  mov    $0x200,%esi
  sub    %ebp,%esi
  mov    $0x0,%eax
  call   <snprintf@plt>
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string
name: retrieve_data
arguments: tag: D26
type_infered: string

tool: D19: Jul 27 14:50:37 

tool: D17: %s

tool: D26:  PPPoE access success


assistant: ```c
void filt_r_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  if (!p1)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  snprintf(cur - 1, msg + 512 - cur, " PPPoE access success\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<filt_r_message>:
  endbr64
  push   %r12
  mov    $0x3e,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L0
  lea    D21(%rip),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  lea    0x1(%rbx),%rcx
  lea    D26(%rip),%rdx
  movslq %eax,%rbp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <snprintf@plt>
  mov    $0x200,%esi
  lea    -0x1(%r12,%rbp,1),%rdi
  pop    %rbx
  sub    %ebp,%esi
  lea    D14(%rip),%rdx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1090 <snprintf@plt>
  nopl   0x0(%rax)
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D21
data_type: string
name: read_data
arguments: data_label: D26
data_type: string
name: read_data
arguments: data_label: D14
data_type: string

tool: D21: Jul 27 14:50:37 

tool: D26: %s

tool: D14:  PPPoE access success


assistant: ```c
void filt_r_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  if (!p1)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  snprintf(cur - 1, msg + 512 - cur, " PPPoE access success\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<filt_r_message>:
  endbr64
  push   %r12
  mov    $0x3e,%esi
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L4
  lea    D18(%rip),%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  lea    0x1(%rbx),%rcx
  lea    D2(%rip),%rdx
  movslq %eax,%rbp
  xor    %eax,%eax
  mov    %ebp,%esi
  call   <snprintf@plt>
  mov    $0x200,%esi
  lea    -0x1(%r12,%rbp,1),%rdi
  pop    %rbx
  sub    %ebp,%esi
  lea    D23(%rip),%rdx
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1090 <snprintf@plt>
  nopl   0x0(%rax)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string
name: retrieve_data
arguments: data_label: D23
data_type: string

tool: D18: Jul 27 14:50:37 

tool: D2: %s

tool: D23:  PPPoE access success


assistant: ```c
void filt_r_message(char *msg, char *keycat) {
  char *cur = msg;
  char *p1, *p2, *p3;
  p1 = strchr(cur, '>');
  if (!p1)
    return;
  p1 += 1;
  p2 = p1 + strlen("Jul 27 14:50:37 ");
  snprintf(cur, p2 - p1, "%s", p1);
  cur += p2 - p1;
  snprintf(cur - 1, msg + 512 - cur, " PPPoE access success\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L17
L67:
  movl   $0x1,-0x10(%rbp)
  jmp    L21
L48:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L48
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L24:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L24
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L17:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L67
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: string
name: retrieve_data
arguments: label: D19
type_infered: string
name: retrieve_data
arguments: label: D13
type_infered: string
name: retrieve_data
arguments: label: D16
type_infered: string
name: retrieve_data
arguments: label: D47
type_infered: string

tool: D4: Enter n:

tool: D19: %d

tool: D13:   

tool: D16: * 

tool: D47: 


assistant: ```c
int main() {
  int n, i = 1, s = 0, p = 0;
  printf("Enter n:");
  scanf("%d", &n);
  for (i = 1; i <= n; i++) {
    for (s = 1; s <= n - i; s++)
      printf("  ");
    for (p = 0; p != 2 * i - 1;) {
      printf("* ");
      p++;
    }
    printf("\n");
  }
}
```