ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<incbig>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  jne    L88
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L38
L88:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L45
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  jmp    L32
L45:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
L32:
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L71:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L71
  movl   $0x1,-0x8(%rbp)
  jmp    L4
L79:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x8(%rbp)
L4:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L79
  movl   $0x1,-0x8(%rbp)
  jmp    L53
L123:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x9,%eax
  jle    L42
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  sub    $0xa,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
L42:
  addl   $0x1,-0x8(%rbp)
L53:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L123
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L113
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  jmp    L115
L113:
  mov    -0x4(%rbp),%eax
L115:
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  jmp    L139
L38:
  nop
L139:
  pop    %rbp
  ret
```

assistant: ```c
void incbig(int *x, int *n) {
  int a, l;
  if (n[0] == 1 && n[1] == 0)
    return;
  l = x[0] > n[0] ? x[0] + 1 : n[0] + 1;
  for (a = x[0] + 1; a <= l; a++)
    x[a] = 0;
  for (a = 1; a <= n[0]; a++)
    x[a] += n[a];
  for (a = 1; a < l; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  x[0] = x[l] ? l : l - 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<incbig>:
  endbr64
  mov    %rdi,%rdx
  mov    (%rsi),%edi
  cmp    $0x1,%edi
  je     L19
L86:
  mov    (%rdx),%eax
  cmp    %eax,%edi
  jge    L68
  add    $0x1,%eax
  mov    %eax,%edi
L85:
  cltq
L129:
  movl   $0x0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%edi
  jge    L129
  cmpl   $0x0,(%rsi)
  jle    L101
  mov    $0x1,%eax
L95:
  mov    (%rsi,%rax,4),%ecx
  add    %ecx,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,(%rsi)
  jge    L95
L101:
  cmp    $0x1,%edi
  jle    L81
  lea    0x4(%rdx),%rax
  lea    -0x2(%rdi),%ecx
  lea    0x8(%rdx,%rcx,4),%rsi
  jmp    L54
L19:
  cmpl   $0x0,0x4(%rsi)
  jne    L86
  jmp    L10
L68:
  add    $0x1,%edi
  add    $0x1,%eax
  jmp    L85
L43:
  add    $0x4,%rax
  cmp    %rsi,%rax
  je     L81
L54:
  mov    (%rax),%ecx
  cmp    $0x9,%ecx
  jle    L43
  sub    $0xa,%ecx
  mov    %ecx,(%rax)
  addl   $0x1,0x4(%rax)
  jmp    L43
L81:
  movslq %edi,%rax
  cmpl   $0x1,(%rdx,%rax,4)
  sbb    $0x0,%edi
  mov    %edi,(%rdx)
L10:
  ret
```

assistant: ```c
void incbig(int *x, int *n) {
  int a, l;
  if (n[0] == 1 && n[1] == 0)
    return;
  l = x[0] > n[0] ? x[0] + 1 : n[0] + 1;
  for (a = x[0] + 1; a <= l; a++)
    x[a] = 0;
  for (a = 1; a <= n[0]; a++)
    x[a] += n[a];
  for (a = 1; a < l; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  x[0] = x[l] ? l : l - 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<incbig>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%ecx
  mov    %rdi,%rbx
  cmp    $0x1,%ecx
  je     L39
L49:
  mov    (%rbx),%edx
  lea    0x1(%rcx),%r12d
  cmp    %edx,%ecx
  lea    0x1(%rdx),%eax
  cmovl  %eax,%r12d
  cltq
  lea    (%rbx,%rax,4),%rdi
  mov    %r12d,%ecx
  sub    %edx,%ecx
  sub    $0x1,%ecx
  cmp    %r12d,%edx
  mov    $0x4,%edx
  lea    0x4(,%rcx,4),%r8
  cmovge %rdx,%r8
  xor    %esi,%esi
  mov    %r8,%rdx
  call   <memset@plt>
  mov    0x0(%rbp),%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jle    L68
L25:
  mov    0x0(%rbp,%rax,4),%edx
  add    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,0x0(%rbp)
  jge    L25
L68:
  cmp    $0x1,%r12d
  jle    L31
  lea    -0x2(%r12),%edx
  lea    0x4(%rbx),%rax
  lea    0x8(%rbx,%rdx,4),%rcx
  nopl   0x0(%rax)
L34:
  mov    (%rax),%edx
  cmp    $0x9,%edx
  jle    L55
  sub    $0xa,%edx
  addl   $0x1,0x4(%rax)
  mov    %edx,(%rax)
L55:
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L34
L31:
  movslq %r12d,%rax
  cmpl   $0x1,(%rbx,%rax,4)
  sbb    $0x0,%r12d
  mov    %r12d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L39:
  mov    0x4(%rsi),%esi
  test   %esi,%esi
  jne    L49
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void incbig(int *x, int *n) {
  int a, l;
  if (n[0] == 1 && n[1] == 0)
    return;
  l = x[0] > n[0] ? x[0] + 1 : n[0] + 1;
  for (a = x[0] + 1; a <= l; a++)
    x[a] = 0;
  for (a = 1; a <= n[0]; a++)
    x[a] += n[a];
  for (a = 1; a < l; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  x[0] = x[l] ? l : l - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<incbig>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%ecx
  mov    %rdi,%rbx
  cmp    $0x1,%ecx
  je     L38
L31:
  mov    (%rbx),%edx
  lea    0x1(%rcx),%r12d
  cmp    %edx,%ecx
  lea    0x1(%rdx),%eax
  cmovl  %eax,%r12d
  cltq
  lea    (%rbx,%rax,4),%rdi
  mov    %r12d,%ecx
  sub    %edx,%ecx
  sub    $0x1,%ecx
  cmp    %r12d,%edx
  mov    $0x4,%edx
  lea    0x4(,%rcx,4),%r8
  cmovge %rdx,%r8
  xor    %esi,%esi
  mov    %r8,%rdx
  call   <memset@plt>
  mov    0x0(%rbp),%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jle    L49
L11:
  mov    0x0(%rbp,%rax,4),%edx
  add    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,0x0(%rbp)
  jge    L11
L49:
  cmp    $0x1,%r12d
  jle    L24
  lea    -0x2(%r12),%edx
  lea    0x4(%rbx),%rax
  lea    0x8(%rbx,%rdx,4),%rcx
  nopl   0x0(%rax)
L3:
  mov    (%rax),%edx
  cmp    $0x9,%edx
  jle    L36
  sub    $0xa,%edx
  addl   $0x1,0x4(%rax)
  mov    %edx,(%rax)
L36:
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L3
L24:
  movslq %r12d,%rax
  cmpl   $0x1,(%rbx,%rax,4)
  sbb    $0x0,%r12d
  mov    %r12d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L38:
  mov    0x4(%rsi),%esi
  test   %esi,%esi
  jne    L31
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void incbig(int *x, int *n) {
  int a, l;
  if (n[0] == 1 && n[1] == 0)
    return;
  l = x[0] > n[0] ? x[0] + 1 : n[0] + 1;
  for (a = x[0] + 1; a <= l; a++)
    x[a] = 0;
  for (a = 1; a <= n[0]; a++)
    x[a] += n[a];
  for (a = 1; a < l; a++)
    if (x[a] >= 10) {
      x[a] -= 10;
      x[a + 1]++;
    }
  x[0] = x[l] ? l : l - 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bitmap_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x3f,%eax
  mov    %eax,%eax
  shl    $0x2,%rax
  shr    $0x6,%rax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint64_t *bitmap_alloc(unsigned bits) {
  uint64_t *map = calloc(1, sizeof(uint64_t) * (bits + 63) / 64);
  return map;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bitmap_alloc>:
  endbr64
  sub    $0x8,%rsp
  lea    0x3f(%rdi),%esi
  shr    $0x4,%rsi
  mov    $0x1,%edi
  call   <calloc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint64_t *bitmap_alloc(unsigned bits) {
  uint64_t *map = calloc(1, sizeof(uint64_t) * (bits + 63) / 64);
  return map;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bitmap_alloc>:
  endbr64
  lea    0x3f(%rdi),%esi
  mov    $0x1,%edi
  shr    $0x4,%rsi
  jmp    1050 <calloc@plt>
```

assistant: ```c
uint64_t *bitmap_alloc(unsigned bits) {
  uint64_t *map = calloc(1, sizeof(uint64_t) * (bits + 63) / 64);
  return map;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmap_alloc>:
  endbr64
  lea    0x3f(%rdi),%esi
  mov    $0x1,%edi
  shr    $0x4,%rsi
  jmp    1050 <calloc@plt>
```

assistant: ```c
uint64_t *bitmap_alloc(unsigned bits) {
  uint64_t *map = calloc(1, sizeof(uint64_t) * (bits + 63) / 64);
  return map;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Q_strchrnul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L3
L5:
  addq   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L5
L23:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *Q_strchrnul(const char *s, int c) {
  while (*s && *s != c) {
    s++;
  }
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Q_strchrnul>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
L4:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L13
  add    $0x1,%rax
  movzbl (%rax),%edx
  test   %dl,%dl
  jne    L4
L13:
  ret
L2:
  ret
```

assistant: ```c
char *Q_strchrnul(const char *s, int c) {
  while (*s && *s != c) {
    s++;
  }
  return (char *)s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Q_strchrnul>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L7
  jmp    L38
L30:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L25
L7:
  cmp    %esi,%edx
  jne    L30
L25:
  ret
L38:
  ret
```

assistant: ```c
char *Q_strchrnul(const char *s, int c) {
  while (*s && *s != c) {
    s++;
  }
  return (char *)s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Q_strchrnul>:
  endbr64
  movsbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L29
  jmp    L37
L6:
  movsbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L11
L29:
  cmp    %esi,%edx
  jne    L6
L11:
  ret
L37:
  ret
```

assistant: ```c
char *Q_strchrnul(const char *s, int c) {
  while (*s && *s != c) {
    s++;
  }
  return (char *)s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x1,%edi
  call   <foo@plt>
  jmp    L10
L6:
  addl   $0x1,-0x4(%rbp)
  mov    $0x3,%edi
  call   <foo@plt>
L10:
  cmpl   $0x4,-0x4(%rbp)
  jle    L6
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0, foo(1); i < 5; i++, foo(3))
    ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0, foo(1); i < 5; i++, foo(3))
    ;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  mov    $0x3,%edi
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0, foo(1); i < 5; i++, foo(3))
    ;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edi
  mov    $0x5,%ebx
  call   <foo@plt>
L6:
  mov    $0x3,%edi
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L6
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  int i;
  for (i = 0, foo(1); i < 5; i++, foo(3))
    ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<encode_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x7f,-0x40(%rbp)
  movq   $0x7ff,-0x38(%rbp)
  movq   $0xffff,-0x30(%rbp)
  movq   $0x1fffff,-0x28(%rbp)
  movq   $0x3ffffff,-0x20(%rbp)
  movq   $0x7fffffff,-0x18(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L12
L89:
  mov    -0x48(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,8),%rax
  cmp    %rax,-0x58(%rbp)
  jbe    L35
  addl   $0x1,-0x48(%rbp)
L12:
  mov    D11(%rip),%eax
  cmp    %eax,-0x48(%rbp)
  jl     L89
  jmp    L20
L35:
  nop
L20:
  mov    D11(%rip),%eax
  cmp    %eax,-0x48(%rbp)
  jne    L98
  mov    $0xffffffff,%eax
  jmp    L61
L98:
  cmpl   $0x0,-0x48(%rbp)
  jne    L72
  mov    -0x58(%rbp),%rax
  mov    %eax,%edx
  mov    -0x60(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L76
L72:
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  jmp    L86
L84:
  mov    -0x58(%rbp),%rax
  and    $0x3f,%eax
  mov    %eax,%edx
  mov    -0x44(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x60(%rbp),%rax
  add    %rcx,%rax
  or     $0xffffff80,%edx
  mov    %dl,(%rax)
  shrq   $0x6,-0x58(%rbp)
  subl   $0x1,-0x44(%rbp)
L86:
  cmpl   $0x0,-0x44(%rbp)
  jg     L84
  mov    -0x48(%rbp),%eax
  add    $0x1,%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %al,-0x49(%rbp)
  mov    -0x58(%rbp),%rax
  or     -0x49(%rbp),%al
  mov    %eax,%edx
  mov    -0x60(%rbp),%rax
  mov    %dl,(%rax)
L76:
  mov    -0x48(%rbp),%eax
  add    $0x1,%eax
L61:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
data_type: byte[4]

tool: {"D11": [0x06,0x00,0x00,0x00]}

assistant: ```c
int encode_utf8(unsigned long u, unsigned char *buf) {
  int i;
  unsigned long max_val[6] = {0x0000007ful, 0x000007fful, 0x0000fffful, 0x001ffffful, 0x03fffffful, 0x7ffffffful};
  static const int MAX_VAL_SZ = sizeof(max_val) / sizeof(max_val[0]);
  for (i = 0; i < MAX_VAL_SZ; ++i) {
    if (u <= max_val[i])
      break;
  }
  if (i == MAX_VAL_SZ) {
    return -1;
  }
  if (i == 0) {
    buf[0] = u;
  } else {
    signed int j;
    for (j = i; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> (i + 1));
    buf[0] = mask | u;
  }
  return i + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<encode_utf8>:
  endbr64
  sub    $0x48,%rsp
  mov    %rdi,%rdx
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x7f,(%rsp)
  movq   $0x7ff,0x8(%rsp)
  movq   $0xffff,0x10(%rsp)
  movq   $0x1fffff,0x18(%rsp)
  movq   $0x3ffffff,0x20(%rsp)
  movq   $0x7fffffff,0x28(%rsp)
  mov    %rsp,%rcx
L89:
  cmp    %rdx,(%rcx)
  jae    L1
  add    $0x1,%eax
  add    $0x8,%rcx
  cmp    $0x6,%eax
  jne    L89
  mov    $0xffffffff,%eax
  jmp    L67
L1:
  cmp    $0x6,%eax
  je     L55
  mov    %edx,%ecx
  test   %eax,%eax
  je     L46
  jle    L12
  movslq %eax,%rsi
  lea    (%r8,%rsi,1),%rcx
  lea    -0x1(%r8,%rsi,1),%rdi
  lea    -0x1(%rax),%esi
  sub    %rsi,%rdi
L21:
  mov    %edx,%esi
  and    $0x3f,%esi
  or     $0xffffff80,%esi
  mov    %sil,(%rcx)
  shr    $0x6,%rdx
  sub    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L21
L12:
  lea    0x1(%rax),%ecx
  mov    $0xff,%esi
  sar    %cl,%esi
  mov    %esi,%ecx
  not    %ecx
  or     %edx,%ecx
L46:
  mov    %cl,(%r8)
  add    $0x1,%eax
L67:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L49
  add    $0x48,%rsp
  ret
L55:
  mov    $0xffffffff,%eax
  jmp    L67
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int encode_utf8(unsigned long u, unsigned char *buf) {
  int i;
  unsigned long max_val[6] = {0x0000007ful, 0x000007fful, 0x0000fffful, 0x001ffffful, 0x03fffffful, 0x7ffffffful};
  static const int MAX_VAL_SZ = sizeof(max_val) / sizeof(max_val[0]);
  for (i = 0; i < MAX_VAL_SZ; ++i) {
    if (u <= max_val[i])
      break;
  }
  if (i == MAX_VAL_SZ) {
    return -1;
  }
  if (i == 0) {
    buf[0] = u;
  } else {
    signed int j;
    for (j = i; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> (i + 1));
    buf[0] = mask | u;
  }
  return i + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<encode_utf8>:
  endbr64
  sub    $0x48,%rsp
  xor    %edx,%edx
  mov    $0x7f,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  movq   $0x7f,(%rsp)
  lea    0x1(%rdx),%eax
  movq   $0x7ff,0x8(%rsp)
  movq   $0xffff,0x10(%rsp)
  movq   $0x1fffff,0x18(%rsp)
  movq   $0x3ffffff,0x20(%rsp)
  movq   $0x7fffffff,0x28(%rsp)
  cmp    %r8,%rdi
  jbe    L77
L19:
  add    $0x8,%rcx
  cmp    $0x6,%eax
  je     L28
  mov    (%rcx),%r8
  movslq %eax,%rdx
  lea    0x1(%rdx),%eax
  cmp    %r8,%rdi
  ja     L19
L77:
  mov    %edi,%ecx
  test   %edx,%edx
  jne    L4
L32:
  mov    %cl,(%rsi)
L57:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x48,%rsp
  ret
  nopl   0x0(%rax)
L4:
  mov    %edi,%ecx
  shr    $0x6,%rdi
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rsi,%rdx,1)
  sub    $0x1,%rdx
  test   %edx,%edx
  jne    L4
  mov    %eax,%ecx
  mov    $0xff,%edx
  sar    %cl,%edx
  mov    %edx,%ecx
  not    %ecx
  or     %edi,%ecx
  jmp    L32
L28:
  mov    $0xffffffff,%eax
  jmp    L57
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int encode_utf8(unsigned long u, unsigned char *buf) {
  int i;
  unsigned long max_val[6] = {0x0000007ful, 0x000007fful, 0x0000fffful, 0x001ffffful, 0x03fffffful, 0x7ffffffful};
  static const int MAX_VAL_SZ = sizeof(max_val) / sizeof(max_val[0]);
  for (i = 0; i < MAX_VAL_SZ; ++i) {
    if (u <= max_val[i])
      break;
  }
  if (i == MAX_VAL_SZ) {
    return -1;
  }
  if (i == 0) {
    buf[0] = u;
  } else {
    signed int j;
    for (j = i; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> (i + 1));
    buf[0] = mask | u;
  }
  return i + 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<encode_utf8>:
  endbr64
  mov    %rdi,%rdx
  mov    %rsi,%rdi
  cmp    $0x7f,%rdx
  jbe    L79
  cmp    $0x7ff,%rdx
  jbe    L21
  cmp    $0xffff,%rdx
  jbe    L129
  cmp    $0x1fffff,%rdx
  jbe    L30
  cmp    $0x3ffffff,%rdx
  jbe    L35
  cmp    $0x7fffffff,%rdx
  jbe    L59
  mov    $0xffffffff,%eax
  ret
  nop
L79:
  mov    %dl,(%rdi)
  mov    $0x1,%eax
  ret
L21:
  mov    %edx,%eax
  shr    $0x6,%rdx
  and    $0x3f,%eax
  or     $0xffffff80,%eax
  mov    %al,0x1(%rsi)
  mov    %rdx,%rsi
  mov    $0x2,%eax
L45:
  mov    %eax,%ecx
  mov    $0xff,%edx
  sar    %cl,%edx
  not    %edx
  or     %esi,%edx
  mov    %dl,(%rdi)
  ret
L129:
  mov    $0x3,%eax
  mov    $0x2,%r8d
L93:
  mov    %edx,%ecx
  movslq %r8d,%rsi
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rdi,%rsi,1)
  mov    %rdx,%rcx
  lea    -0x1(%r8),%esi
  shr    $0x6,%rcx
  movslq %esi,%rsi
  and    $0x3f,%ecx
  or     $0xffffff80,%ecx
  mov    %cl,(%rdi,%rsi,1)
  mov    %rdx,%rsi
  mov    %r8d,%ecx
  shr    $0xc,%rsi
  sub    $0x2,%ecx
  je     L45
  and    $0x3f,%esi
  movslq %ecx,%rcx
  or     $0xffffff80,%esi
  mov    %sil,(%rdi,%rcx,1)
  mov    %rdx,%rsi
  shr    $0x12,%rsi
  sub    $0x3,%r8d
  je     L45
  and    $0x3f,%esi
  movslq %r8d,%rcx
  or     $0xffffff80,%esi
  mov    %sil,(%rdi,%rcx,1)
  mov    %rdx,%rsi
  shr    $0x18,%rsi
  cmp    $0x1,%r8d
  je     L45
  and    $0x3f,%esi
  shr    $0x1e,%rdx
  or     $0xffffff80,%esi
  mov    %sil,0x1(%rdi)
  mov    %rdx,%rsi
  jmp    L45
L30:
  mov    $0x4,%eax
  mov    $0x3,%r8d
  jmp    L93
L35:
  mov    $0x5,%eax
  mov    $0x4,%r8d
  jmp    L93
L59:
  mov    $0x6,%eax
  mov    $0x5,%r8d
  jmp    L93
```

assistant: ```c
int encode_utf8(unsigned long u, unsigned char *buf) {
  int i;
  unsigned long max_val[6] = {0x0000007ful, 0x000007fful, 0x0000fffful, 0x001ffffful, 0x03fffffful, 0x7ffffffful};
  static const int MAX_VAL_SZ = sizeof(max_val) / sizeof(max_val[0]);
  for (i = 0; i < MAX_VAL_SZ; ++i) {
    if (u <= max_val[i])
      break;
  }
  if (i == MAX_VAL_SZ) {
    return -1;
  }
  if (i == 0) {
    buf[0] = u;
  } else {
    signed int j;
    for (j = i; j > 0; --j) {
      buf[j] = 0x80 | (u & 0x3f);
      u >>= 6;
    }
    unsigned char mask = ~(0xFF >> (i + 1));
    buf[0] = mask | u;
  }
  return i + 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <foo@plt>
  cmp    $0x3,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  int a = 3;
  int *b = &a;
  assert(foo(&b) == 3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x3,0xc(%rsp)
  lea    0xc(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  call   <foo@plt>
  cmp    $0x3,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a = 3;
  int *b = &a;
  assert(foo(&b) == 3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%rax
  movl   $0x3,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  call   <foo@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a = 3;
  int *b = &a;
  assert(foo(&b) == 3);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    0xc(%rsp),%rax
  movl   $0x3,0xc(%rsp)
  mov    %rax,0x10(%rsp)
  call   <foo@plt>
  xor    %edi,%edi
  cmp    $0x3,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int a = 3;
  int *b = &a;
  assert(foo(&b) == 3);
  return 0;
}
```