ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<SDL_imageFilterDiv>:
  endbr64
  test   %ecx,%ecx
  jle    L8
  sub    $0x8,%rsp
  call   <SDL_imageFilterDivASM@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterDiv(unsigned char *Src1, unsigned char *Src2, unsigned char *Dest, int length) {
  if (length > 0) {
    SDL_imageFilterDivASM(Src1, Src2, Dest, length);
    return (0);
  } else {
    return (-1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SDL_imageFilterDiv>:
  endbr64
  test   %ecx,%ecx
  jle    L4
  sub    $0x8,%rsp
  call   <SDL_imageFilterDivASM@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int SDL_imageFilterDiv(unsigned char *Src1, unsigned char *Src2, unsigned char *Dest, int length) {
  if (length > 0) {
    SDL_imageFilterDivASM(Src1, Src2, Dest, length);
    return (0);
  } else {
    return (-1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<valid_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L55
L34:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L16
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0x1,%eax
  je     L16
  mov    $0x0,%eax
  jmp    L67
L16:
  mov    -0x2c(%rbp),%eax
  sub    $0x2,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L37
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L37
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L37
  mov    $0x0,%eax
  jmp    L67
L37:
  addl   $0x1,-0x14(%rbp)
L55:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L34
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <count@plt>
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <count@plt>
  cmp    %rax,%rbx
  je     L24
  mov    $0x0,%eax
  jmp    L67
L24:
  mov    $0x1,%eax
L67:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
bool valid_row(int a[], int size) {
  for (int i = 0; i < size; i++) {
    if ((a[i] != 0) && (a[i] != 1))
      return false;
    if (i < (size - 2)) {
      if ((a[i] == a[i + 1]) && (a[i] == a[i + 2]))
        return false;
    }
  }
  if ((count(a, 10, 0)) != (count(a, 10, 1)))
    return false;
  return true;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<valid_row>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %esi,%esi
  jle    L80
  mov    %esi,%ecx
  mov    $0x0,%eax
  sub    $0x2,%esi
  jmp    L10
L3:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L80
L10:
  mov    (%rbx,%rax,4),%edx
  cmp    $0x1,%edx
  ja     L15
  cmp    %eax,%esi
  jle    L3
  cmp    0x4(%rbx,%rax,4),%edx
  jne    L3
  cmp    0x8(%rbx,%rax,4),%edx
  jne    L3
  mov    $0x0,%eax
  jmp    L52
L80:
  mov    $0x0,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <count@plt>
  mov    %rax,%rbp
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <count@plt>
  cmp    %rax,%rbp
  sete   %al
  movzbl %al,%eax
L52:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    $0x0,%eax
  jmp    L52
```

assistant: ```c
bool valid_row(int a[], int size) {
  for (int i = 0; i < size; i++) {
    if ((a[i] != 0) && (a[i] != 1))
      return false;
    if (i < (size - 2)) {
      if ((a[i] == a[i + 1]) && (a[i] == a[i + 2]))
        return false;
    }
  }
  if ((count(a, 10, 0)) != (count(a, 10, 1)))
    return false;
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<valid_row>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L16
  movslq %esi,%rcx
  xor    %eax,%eax
  sub    $0x2,%esi
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L16
L11:
  mov    0x0(%rbp,%rax,4),%edx
  cmp    $0x1,%edx
  ja     L53
  cmp    %eax,%esi
  jle    L20
  cmp    0x4(%rbp,%rax,4),%edx
  jne    L20
  cmp    0x8(%rbp,%rax,4),%edx
  jne    L20
L53:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <count@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    %rax,%rbx
  call   <count@plt>
  cmp    %rax,%rbx
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool valid_row(int a[], int size) {
  for (int i = 0; i < size; i++) {
    if ((a[i] != 0) && (a[i] != 1))
      return false;
    if (i < (size - 2)) {
      if ((a[i] == a[i + 1]) && (a[i] == a[i + 2]))
        return false;
    }
  }
  if ((count(a, 10, 0)) != (count(a, 10, 1)))
    return false;
  return true;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<valid_row>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L61
  movslq %esi,%rcx
  xor    %eax,%eax
  sub    $0x2,%esi
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L61
L36:
  mov    0x0(%rbp,%rax,4),%edx
  cmp    $0x1,%edx
  ja     L66
  cmp    %eax,%esi
  jle    L1
  cmp    0x4(%rbp,%rax,4),%edx
  jne    L1
  cmp    0x8(%rbp,%rax,4),%edx
  jne    L1
L66:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  xor    %edx,%edx
  mov    %rbp,%rdi
  mov    $0xa,%esi
  call   <count@plt>
  mov    %rbp,%rdi
  mov    $0x1,%edx
  mov    $0xa,%esi
  mov    %rax,%rbx
  call   <count@plt>
  cmp    %rax,%rbx
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
bool valid_row(int a[], int size) {
  for (int i = 0; i < size; i++) {
    if ((a[i] != 0) && (a[i] != 1))
      return false;
    if (i < (size - 2)) {
      if ((a[i] == a[i + 1]) && (a[i] == a[i + 2]))
        return false;
    }
  }
  if ((count(a, 10, 0)) != (count(a, 10, 1)))
    return false;
  return true;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print4d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L74
L62:
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L40:
  movl   $0x0,-0x8(%rbp)
  jmp    L76
L46:
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L56:
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  imul   -0x18(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  imul   -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L56
  addl   $0x1,-0x8(%rbp)
L76:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L46
  addl   $0x1,-0xc(%rbp)
L6:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L40
  addl   $0x1,-0x10(%rbp)
L74:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L62
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D1
type: string

tool: D7: [%2d,%2d,%2d,%2d] = 

tool: D1: %20.14lf 

assistant: ```c
void print4d(int dim1, int dim2, int dim3, int dim4, double *a) {
  for (int i = 0; i < dim1; i++)
    for (int j = 0; j < dim2; j++)
      for (int k = 0; k < dim3; k++)
        for (int l = 0; l < dim4; l++) {
          printf("[%2d,%2d,%2d,%2d] = ", i, j, k, l);
          printf("%20.14lf ", a[i * dim2 * dim3 * dim4 + j * dim3 * dim4 + k * dim4 + l]);
          printf("\n");
        }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print4d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x2c(%rsp)
  mov    %esi,0x1c(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %r8,0x10(%rsp)
  test   %edi,%edi
  jle    L39
  imul   %ecx,%edx
  mov    %edx,0x20(%rsp)
  imul   %edx,%esi
  mov    %esi,0x28(%rsp)
  movl   $0x0,0x24(%rsp)
  mov    $0x0,%r15d
  jmp    L9
L51:
  mov    0x4(%rsp),%r13d
  movslq 0x8(%rsp),%rax
  mov    0x10(%rsp),%rcx
  lea    (%rcx,%rax,8),%r12
  mov    $0x0,%ebx
L29:
  mov    %ebx,%r8d
  mov    %ebp,%ecx
  mov    %r14d,%edx
  mov    %r15d,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  (%r12,%rbx,8),%xmm0
  lea    D4(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L29
L31:
  add    $0x1,%ebp
  mov    0x4(%rsp),%edx
  add    %edx,0x8(%rsp)
  cmp    %ebp,0xc(%rsp)
  je     L28
L21:
  cmpl   $0x0,0x4(%rsp)
  jg     L51
  jmp    L31
L28:
  add    $0x1,%r14d
  mov    0x20(%rsp),%esi
  add    %esi,0x18(%rsp)
  cmp    %r14d,0x1c(%rsp)
  je     L17
L0:
  mov    0x18(%rsp),%eax
  mov    %eax,0x8(%rsp)
  mov    $0x0,%ebp
  cmpl   $0x0,0xc(%rsp)
  jg     L21
  jmp    L28
L17:
  add    $0x1,%r15d
  mov    0x28(%rsp),%esi
  add    %esi,0x24(%rsp)
  cmp    %r15d,0x2c(%rsp)
  je     L39
L9:
  mov    0x24(%rsp),%eax
  mov    %eax,0x18(%rsp)
  mov    $0x0,%r14d
  cmpl   $0x0,0x1c(%rsp)
  jg     L0
  jmp    L17
L39:
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type_infered: string
name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D15: [%2d,%2d,%2d,%2d] = 

tool: D4: %20.14lf 

assistant: ```c
void print4d(int dim1, int dim2, int dim3, int dim4, double *a) {
  for (int i = 0; i < dim1; i++)
    for (int j = 0; j < dim2; j++)
      for (int k = 0; k < dim3; k++)
        for (int l = 0; l < dim4; l++) {
          printf("[%2d,%2d,%2d,%2d] = ", i, j, k, l);
          printf("%20.14lf ", a[i * dim2 * dim3 * dim4 + j * dim3 * dim4 + k * dim4 + l]);
          printf("\n");
        }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<print4d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x3c(%rsp)
  mov    %esi,0x2c(%rsp)
  mov    %edx,0x20(%rsp)
  mov    %ecx,0x10(%rsp)
  mov    %r8,0x18(%rsp)
  test   %edi,%edi
  jle    L63
  imul   %ecx,%edx
  movl   $0x0,0x34(%rsp)
  xor    %r12d,%r12d
  lea    D9(%rip),%r15
  mov    %r12d,%r14d
  imul   %edx,%esi
  mov    %edx,0x30(%rsp)
  mov    %esi,0x38(%rsp)
L31:
  mov    0x34(%rsp),%eax
  xor    %r13d,%r13d
  mov    %eax,0x28(%rsp)
  mov    0x10(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x24(%rsp)
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L47
  nopl   0x0(%rax)
L34:
  mov    0x28(%rsp),%eax
  mov    0x20(%rsp),%edx
  xor    %ebx,%ebx
  mov    %eax,0x14(%rsp)
  test   %edx,%edx
  jle    L35
  xchg   %ax,%ax
L42:
  mov    0x10(%rsp),%ecx
  test   %ecx,%ecx
  jle    L73
  mov    0x24(%rsp),%eax
  mov    0x18(%rsp),%rsi
  xor    %r12d,%r12d
  mov    %rax,0x8(%rsp)
  movslq 0x14(%rsp),%rax
  lea    (%rsi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r12d,%r8d
  mov    %ebx,%ecx
  mov    %r13d,%edx
  mov    %r14d,%esi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x0(%rbp,%r12,8),%xmm0
  mov    %r15,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %r12,%rax
  add    $0x1,%r12
  cmp    0x8(%rsp),%rax
  jne    L3
L73:
  mov    0x10(%rsp),%ecx
  add    $0x1,%ebx
  add    %ecx,0x14(%rsp)
  cmp    %ebx,0x20(%rsp)
  jne    L42
L35:
  mov    0x30(%rsp),%esi
  add    $0x1,%r13d
  add    %esi,0x28(%rsp)
  cmp    %r13d,0x2c(%rsp)
  jne    L34
L47:
  mov    0x38(%rsp),%ecx
  add    $0x1,%r14d
  add    %ecx,0x34(%rsp)
  cmp    %r14d,0x3c(%rsp)
  jne    L31
L63:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D9
type: string
name: parse_data
arguments: label: D1
type: string

tool: D9: %20.14lf 

tool: D1: [%2d,%2d,%2d,%2d] = 

assistant: ```c
void print4d(int dim1, int dim2, int dim3, int dim4, double *a) {
  for (int i = 0; i < dim1; i++)
    for (int j = 0; j < dim2; j++)
      for (int k = 0; k < dim3; k++)
        for (int l = 0; l < dim4; l++) {
          printf("[%2d,%2d,%2d,%2d] = ", i, j, k, l);
          printf("%20.14lf ", a[i * dim2 * dim3 * dim4 + j * dim3 * dim4 + k * dim4 + l]);
          printf("\n");
        }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print4d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,0x3c(%rsp)
  mov    %esi,0x30(%rsp)
  mov    %edx,0x1c(%rsp)
  mov    %r8,0x28(%rsp)
  test   %edi,%edi
  jle    L75
  test   %esi,%esi
  jle    L75
  test   %edx,%edx
  jle    L75
  movslq %ecx,%rax
  test   %eax,%eax
  jle    L75
  imul   %eax,%edx
  mov    %rax,0x8(%rsp)
  shl    $0x3,%rax
  xor    %r13d,%r13d
  mov    %rax,0x10(%rsp)
  lea    D18(%rip),%r15
  movl   $0x0,0x34(%rsp)
  imul   %edx,%esi
  mov    %edx,0x24(%rsp)
  mov    %esi,0x38(%rsp)
L11:
  mov    0x34(%rsp),%eax
  xor    %r12d,%r12d
  mov    %eax,0x20(%rsp)
  nop
L15:
  movslq 0x20(%rsp),%rax
  mov    0x28(%rsp),%rcx
  xor    %ebx,%ebx
  lea    (%rcx,%rax,8),%rbp
L17:
  xor    %r14d,%r14d
  nopl   0x0(%rax,%rax,1)
L68:
  mov    %r14d,%r8d
  mov    %ebx,%ecx
  mov    %r12d,%edx
  mov    %r13d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x0(%rbp,%r14,8),%xmm0
  mov    $0x1,%eax
  lea    D6(%rip),%rdi
  add    $0x1,%r14
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    0x8(%rsp),%r14
  jne    L68
  add    $0x1,%ebx
  add    0x10(%rsp),%rbp
  cmp    %ebx,0x1c(%rsp)
  jne    L17
  mov    0x24(%rsp),%edx
  add    $0x1,%r12d
  add    %edx,0x20(%rsp)
  cmp    %r12d,0x30(%rsp)
  jne    L15
  mov    0x38(%rsp),%esi
  add    $0x1,%r13d
  add    %esi,0x34(%rsp)
  cmp    %r13d,0x3c(%rsp)
  jne    L11
L75:
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D18: [%2d,%2d,%2d,%2d] = 

tool: D6: %20.14lf 

assistant: ```c
void print4d(int dim1, int dim2, int dim3, int dim4, double *a) {
  for (int i = 0; i < dim1; i++)
    for (int j = 0; j < dim2; j++)
      for (int k = 0; k < dim3; k++)
        for (int l = 0; l < dim4; l++) {
          printf("[%2d,%2d,%2d,%2d] = ", i, j, k, l);
          printf("%20.14lf ", a[i * dim2 * dim3 * dim4 + j * dim3 * dim4 + k * dim4 + l]);
          printf("\n");
        }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<utilByteArrayToHexstring>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x2c(%rbp)
  jg     L7
  mov    $0x0,%eax
  jmp    L4
L7:
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L33
L14:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  shr    $0x4,%al
  movzbl %al,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0xf,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <util4BitToHexchar@plt>
  mov    %al,(%rbx)
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <util4BitToHexchar@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L33:
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L14
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    $0x1,%eax
L4:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int utilByteArrayToHexstring(char *str, const int strlen, const unsigned char *arr, const int arrlen) {
  int l, r, p, i;
  if (!((arrlen * 2) < strlen))
    return 0;
  p = 0;
  for (i = 0; i < arrlen; i++) {
    l = ((arr[i] & 0xF0) >> 4);
    r = (arr[i] & 0x0F);
    str[p++] = util4BitToHexchar(l);
    str[p++] = util4BitToHexchar(r);
  }
  str[p++] = '\0';
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<utilByteArrayToHexstring>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    (%rcx,%rcx,1),%r15d
  mov    $0x0,%eax
  cmp    %esi,%r15d
  jge    L7
  mov    %rdi,%r14
  test   %ecx,%ecx
  jle    L16
  mov    %rdx,%r12
  lea    0x1(%rdi),%rbp
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdx,%rax,1),%r13
L15:
  movzbl (%r12),%ebx
  mov    %ebx,%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <util4BitToHexchar@plt>
  mov    %al,-0x1(%rbp)
  mov    %ebx,%edi
  and    $0xf,%edi
  call   <util4BitToHexchar@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%r12
  add    $0x2,%rbp
  cmp    %r13,%r12
  jne    L15
L0:
  movslq %r15d,%r15
  movb   $0x0,(%r14,%r15,1)
  mov    $0x1,%eax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    $0x0,%r15d
  jmp    L0
```

assistant: ```c
int utilByteArrayToHexstring(char *str, const int strlen, const unsigned char *arr, const int arrlen) {
  int l, r, p, i;
  if (!((arrlen * 2) < strlen))
    return 0;
  p = 0;
  for (i = 0; i < arrlen; i++) {
    l = ((arr[i] & 0xF0) >> 4);
    r = (arr[i] & 0x0F);
    str[p++] = util4BitToHexchar(l);
    str[p++] = util4BitToHexchar(r);
  }
  str[p++] = '\0';
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utilByteArrayToHexstring>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  lea    (%rcx,%rcx,1),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%r14d
  jge    L8
  mov    %rdi,%r13
  test   %ecx,%ecx
  jle    L2
  lea    -0x1(%rcx),%eax
  mov    %rdx,%r15
  lea    0x1(%rdi),%rbp
  lea    0x1(%rdx,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl (%r15),%ebx
  add    $0x1,%r15
  add    $0x2,%rbp
  mov    %ebx,%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <util4BitToHexchar@plt>
  mov    %ebx,%edi
  mov    %al,-0x3(%rbp)
  and    $0xf,%edi
  call   <util4BitToHexchar@plt>
  mov    %al,-0x2(%rbp)
  cmp    %r15,%r12
  jne    L29
  movslq %r14d,%r14
  add    %r14,%r13
L2:
  movb   $0x0,0x0(%r13)
  mov    $0x1,%eax
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int utilByteArrayToHexstring(char *str, const int strlen, const unsigned char *arr, const int arrlen) {
  int l, r, p, i;
  if (!((arrlen * 2) < strlen))
    return 0;
  p = 0;
  for (i = 0; i < arrlen; i++) {
    l = ((arr[i] & 0xF0) >> 4);
    r = (arr[i] & 0x0F);
    str[p++] = util4BitToHexchar(l);
    str[p++] = util4BitToHexchar(r);
  }
  str[p++] = '\0';
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utilByteArrayToHexstring>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  lea    (%rcx,%rcx,1),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %esi,%r14d
  jge    L23
  mov    %rdi,%r13
  test   %ecx,%ecx
  jle    L27
  lea    -0x1(%rcx),%eax
  mov    %rdx,%r15
  lea    0x1(%rdi),%rbp
  lea    0x1(%rdx,%rax,1),%r12
  nopl   0x0(%rax,%rax,1)
L28:
  movzbl (%r15),%ebx
  add    $0x1,%r15
  add    $0x2,%rbp
  mov    %ebx,%edi
  shr    $0x4,%dil
  movzbl %dil,%edi
  call   <util4BitToHexchar@plt>
  mov    %ebx,%edi
  mov    %al,-0x3(%rbp)
  and    $0xf,%edi
  call   <util4BitToHexchar@plt>
  mov    %al,-0x2(%rbp)
  cmp    %r15,%r12
  jne    L28
  movslq %r14d,%r14
  add    %r14,%r13
L27:
  movb   $0x0,0x0(%r13)
  mov    $0x1,%eax
L23:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int utilByteArrayToHexstring(char *str, const int strlen, const unsigned char *arr, const int arrlen) {
  int l, r, p, i;
  if (!((arrlen * 2) < strlen))
    return 0;
  p = 0;
  for (i = 0; i < arrlen; i++) {
    l = ((arr[i] & 0xF0) >> 4);
    r = (arr[i] & 0x0F);
    str[p++] = util4BitToHexchar(l);
    str[p++] = util4BitToHexchar(r);
  }
  str[p++] = '\0';
  return 1;
}
```