ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_66_1_0>:
  endbr64
  movzbl %dil,%eax
  movzbl %sil,%esi
  mov    %eax,%edi
  mov    %esi,%edx
  shl    $0x8,%edi
  shl    $0x8,%edx
  or     %eax,%edi
  or     %esi,%edx
  mov    %edi,%eax
  xor    $0xff,%dl
  xor    $0xff,%al
  and    %eax,%edx
  mov    %edx,%eax
  xor    $0xff,%al
  and    %edi,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_66_1_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk1 = S ^ D;
  stk2 = T ^ D;
  stk1 = stk1 & stk2;
  return (stk1 & (~S)) | (D & S);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<freeArrayOfObjects_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeArrayOfObjects_free(void **arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    free(arr[i]);
  };
  free(arr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<freeArrayOfObjects_free>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  test   %esi,%esi
  jle    L14
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbp
L11:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L11
L14:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void freeArrayOfObjects_free(void **arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    free(arr[i]);
  };
  free(arr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<freeArrayOfObjects_free>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L9:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L9
L16:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeArrayOfObjects_free(void **arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    free(arr[i]);
  };
  free(arr);
}
```
user: What is the c source code of the assembly code below:

```asm
<freeArrayOfObjects_free>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  lea    0x8(%rdi,%rax,8),%rbp
  nopw   0x0(%rax,%rax,1)
L18:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L18
L8:
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1050 <free@plt>
```

assistant: ```c
void freeArrayOfObjects_free(void **arr, int size) {
  int i;
  for (i = 0; i < size; i++) {
    free(arr[i]);
  };
  free(arr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fp16_exp>:
  endbr64
  mov    $0x10000,%edx
  test   %edi,%edi
  js     L5
L18:
  mov    %edi,%eax
  sub    $0x58b91,%eax
  js     L65
  shl    $0x8,%edx
  mov    %eax,%edi
L65:
  mov    %edi,%eax
  sub    $0x2c5c8,%eax
  js     L96
  shl    $0x4,%edx
  mov    %eax,%edi
L96:
  mov    %edi,%eax
  sub    $0x162e4,%eax
  js     L99
  shl    $0x2,%edx
  mov    %eax,%edi
L99:
  mov    %edi,%eax
  sub    $0xb172,%eax
  js     L60
  add    %edx,%edx
  mov    %eax,%edi
L60:
  mov    %edi,%eax
  sub    $0x67cd,%eax
  js     L0
  mov    %edx,%ecx
  sar    %ecx
  add    %ecx,%edx
  mov    %eax,%edi
L0:
  mov    %edi,%eax
  sub    $0x3920,%eax
  js     L53
  mov    %edx,%ecx
  sar    $0x2,%ecx
  add    %ecx,%edx
  mov    %eax,%edi
L53:
  mov    %edi,%eax
  sub    $0x1e27,%eax
  js     L6
  mov    %edx,%ecx
  sar    $0x3,%ecx
  add    %ecx,%edx
  mov    %eax,%edi
L6:
  mov    %edi,%eax
  sub    $0xf85,%eax
  js     L57
  mov    %edx,%ecx
  sar    $0x4,%ecx
  add    %ecx,%edx
  mov    %eax,%edi
L57:
  mov    %edi,%eax
  sub    $0x7e1,%eax
  js     L51
  mov    %edx,%ecx
  sar    $0x5,%ecx
  add    %ecx,%edx
  mov    %eax,%edi
L51:
  mov    %edi,%eax
  sub    $0x3f8,%eax
  js     L121
  mov    %edx,%ecx
  sar    $0x6,%ecx
  add    %ecx,%edx
  mov    %eax,%edi
L121:
  mov    %edi,%eax
  sub    $0x1fe,%eax
  js     L33
  mov    %edx,%ecx
  sar    $0x7,%ecx
  add    %ecx,%edx
  mov    %eax,%edi
L33:
  mov    %edx,%eax
  sar    $0x8,%eax
  imul   %edi,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  cltq
  ret
L5:
  add    $0xb1721,%edi
  mov    $0x1,%edx
  jmp    L18
```

assistant: ```c
long fp16_exp(int x) {
  int t;
  int y = 0x00010000;
  if (x < 0)
    x += 0xb1721, y >>= 16;
  t = x - 0x58b91;
  if (t >= 0)
    x = t, y <<= 8;
  t = x - 0x2c5c8;
  if (t >= 0)
    x = t, y <<= 4;
  t = x - 0x162e4;
  if (t >= 0)
    x = t, y <<= 2;
  t = x - 0x0b172;
  if (t >= 0)
    x = t, y <<= 1;
  t = x - 0x067cd;
  if (t >= 0)
    x = t, y += y >> 1;
  t = x - 0x03920;
  if (t >= 0)
    x = t, y += y >> 2;
  t = x - 0x01e27;
  if (t >= 0)
    x = t, y += y >> 3;
  t = x - 0x00f85;
  if (t >= 0)
    x = t, y += y >> 4;
  t = x - 0x007e1;
  if (t >= 0)
    x = t, y += y >> 5;
  t = x - 0x003f8;
  if (t >= 0)
    x = t, y += y >> 6;
  t = x - 0x001fe;
  if (t >= 0)
    x = t, y += y >> 7;
  y += ((y >> 8) * x) >> 8;
  return y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fp16_exp>:
  endbr64
  mov    $0x10000,%edx
  test   %edi,%edi
  jns    L36
  add    $0xb1721,%edi
  mov    $0x1,%edx
L36:
  mov    %edi,%eax
  sub    $0x58b91,%eax
  js     L43
  shl    $0x8,%edx
  mov    %eax,%edi
L43:
  mov    %edi,%eax
  sub    $0x2c5c8,%eax
  js     L99
  shl    $0x4,%edx
  mov    %eax,%edi
L99:
  mov    %edi,%eax
  sub    $0x162e4,%eax
  js     L105
  shl    $0x2,%edx
  mov    %eax,%edi
L105:
  mov    %edi,%eax
  sub    $0xb172,%eax
  js     L53
  add    %edx,%edx
  mov    %eax,%edi
L53:
  mov    %edi,%eax
  sub    $0x67cd,%eax
  js     L21
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    %ecx
  add    %ecx,%edx
L21:
  mov    %edi,%eax
  sub    $0x3920,%eax
  js     L98
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    $0x2,%ecx
  add    %ecx,%edx
L98:
  mov    %edi,%eax
  sub    $0x1e27,%eax
  js     L61
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    $0x3,%ecx
  add    %ecx,%edx
L61:
  mov    %edi,%eax
  sub    $0xf85,%eax
  js     L90
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    $0x4,%ecx
  add    %ecx,%edx
L90:
  mov    %edi,%eax
  sub    $0x7e1,%eax
  js     L113
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    $0x5,%ecx
  add    %ecx,%edx
L113:
  mov    %edi,%eax
  sub    $0x3f8,%eax
  js     L106
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    $0x6,%ecx
  add    %ecx,%edx
L106:
  mov    %edi,%eax
  sub    $0x1fe,%eax
  js     L94
  mov    %edx,%ecx
  mov    %eax,%edi
  sar    $0x7,%ecx
  add    %ecx,%edx
L94:
  mov    %edx,%eax
  sar    $0x8,%eax
  imul   %edi,%eax
  sar    $0x8,%eax
  add    %edx,%eax
  cltq
  ret
```

assistant: ```c
long fp16_exp(int x) {
  int t;
  int y = 0x00010000;
  if (x < 0)
    x += 0xb1721, y >>= 16;
  t = x - 0x58b91;
  if (t >= 0)
    x = t, y <<= 8;
  t = x - 0x2c5c8;
  if (t >= 0)
    x = t, y <<= 4;
  t = x - 0x162e4;
  if (t >= 0)
    x = t, y <<= 2;
  t = x - 0x0b172;
  if (t >= 0)
    x = t, y <<= 1;
  t = x - 0x067cd;
  if (t >= 0)
    x = t, y += y >> 1;
  t = x - 0x03920;
  if (t >= 0)
    x = t, y += y >> 2;
  t = x - 0x01e27;
  if (t >= 0)
    x = t, y += y >> 3;
  t = x - 0x00f85;
  if (t >= 0)
    x = t, y += y >> 4;
  t = x - 0x007e1;
  if (t >= 0)
    x = t, y += y >> 5;
  t = x - 0x003f8;
  if (t >= 0)
    x = t, y += y >> 6;
  t = x - 0x001fe;
  if (t >= 0)
    x = t, y += y >> 7;
  y += ((y >> 8) * x) >> 8;
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fp16_exp>:
  endbr64
  mov    $0x1000000,%ecx
  mov    $0x10000,%eax
  test   %edi,%edi
  jns    L13
  add    $0xb1721,%edi
  mov    $0x100,%ecx
  mov    $0x1,%eax
L13:
  mov    %edi,%edx
  sub    $0x58b91,%edx
  jns    L110
  mov    %eax,%ecx
  mov    %edi,%edx
L110:
  mov    %edx,%eax
  sub    $0x2c5c8,%eax
  js     L39
  shl    $0x4,%ecx
  mov    %eax,%edx
L39:
  mov    %edx,%eax
  sub    $0x162e4,%eax
  js     L20
  shl    $0x2,%ecx
  mov    %eax,%edx
L20:
  mov    %edx,%eax
  sub    $0xb172,%eax
  js     L61
  add    %ecx,%ecx
  mov    %eax,%edx
L61:
  mov    %edx,%eax
  sub    $0x67cd,%eax
  js     L112
  mov    %ecx,%edx
  sar    %edx
  add    %edx,%ecx
  mov    %eax,%edx
L112:
  mov    %edx,%eax
  sub    $0x3920,%eax
  js     L41
  mov    %ecx,%edx
  sar    $0x2,%edx
  add    %edx,%ecx
  mov    %eax,%edx
L41:
  mov    %edx,%eax
  sub    $0x1e27,%eax
  js     L46
  mov    %ecx,%edx
  sar    $0x3,%edx
  add    %edx,%ecx
  mov    %eax,%edx
L46:
  mov    %edx,%eax
  sub    $0xf85,%eax
  js     L89
  mov    %ecx,%edx
  sar    $0x4,%edx
  add    %edx,%ecx
  mov    %eax,%edx
L89:
  mov    %edx,%eax
  sub    $0x7e1,%eax
  js     L107
  mov    %ecx,%edx
  sar    $0x5,%edx
  add    %edx,%ecx
  mov    %eax,%edx
L107:
  mov    %edx,%eax
  sub    $0x3f8,%eax
  js     L70
  mov    %ecx,%edx
  sar    $0x6,%edx
  add    %edx,%ecx
  mov    %eax,%edx
L70:
  mov    %edx,%eax
  sub    $0x1fe,%eax
  js     L42
  mov    %ecx,%edx
  sar    $0x7,%edx
  add    %edx,%ecx
  mov    %eax,%edx
L42:
  mov    %ecx,%eax
  sar    $0x8,%eax
  imul   %edx,%eax
  sar    $0x8,%eax
  add    %ecx,%eax
  cltq
  ret
```

assistant: ```c
long fp16_exp(int x) {
  int t;
  int y = 0x00010000;
  if (x < 0)
    x += 0xb1721, y >>= 16;
  t = x - 0x58b91;
  if (t >= 0)
    x = t, y <<= 8;
  t = x - 0x2c5c8;
  if (t >= 0)
    x = t, y <<= 4;
  t = x - 0x162e4;
  if (t >= 0)
    x = t, y <<= 2;
  t = x - 0x0b172;
  if (t >= 0)
    x = t, y <<= 1;
  t = x - 0x067cd;
  if (t >= 0)
    x = t, y += y >> 1;
  t = x - 0x03920;
  if (t >= 0)
    x = t, y += y >> 2;
  t = x - 0x01e27;
  if (t >= 0)
    x = t, y += y >> 3;
  t = x - 0x00f85;
  if (t >= 0)
    x = t, y += y >> 4;
  t = x - 0x007e1;
  if (t >= 0)
    x = t, y += y >> 5;
  t = x - 0x003f8;
  if (t >= 0)
    x = t, y += y >> 6;
  t = x - 0x001fe;
  if (t >= 0)
    x = t, y += y >> 7;
  y += ((y >> 8) * x) >> 8;
  return y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x34(%rbp),%rdx
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul_pre@plt>
  mov    %rax,-0x28(%rbp)
L32:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <digit_value@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jae    L12
  mov    -0x34(%rbp),%eax
  cltq
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x14(%rbp),%eax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L32
L12:
  nop
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  je     L7
  negq   -0x10(%rbp)
L7:
  cmpq   $0x0,-0x30(%rbp)
  je     L30
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
L30:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

assistant: ```c
unsigned long strtoul(const char *string, char **endp, int base) {
  unsigned long value = 0;
  unsigned int digit;
  int negate;
  string = strtoul_pre(string, &negate, &base);
  for (;; string++) {
    digit = digit_value(*string);
    if (digit >= (unsigned int)base)
      break;
    value = ((value * base) + digit);
  }
  if (negate)
    value = -value;
  if (endp)
    *endp = ((char *)string);
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strtoul>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbp
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  call   <strtoul_pre@plt>
  mov    %rax,%rbx
  mov    $0x0,%r12d
  jmp    L42
L22:
  movslq %edx,%rdx
  imul   %r12,%rdx
  mov    %eax,%eax
  lea    (%rax,%rdx,1),%r12
  add    $0x1,%rbx
L42:
  movsbl (%rbx),%edi
  call   <digit_value@plt>
  mov    0xc(%rsp),%edx
  cmp    %eax,%edx
  ja     L22
  cmpl   $0x0,0x14(%rsp)
  je     L38
  neg    %r12
L38:
  test   %rbp,%rbp
  je     L48
  mov    %rbx,0x0(%rbp)
L48:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    %r12,%rax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long strtoul(const char *string, char **endp, int base) {
  unsigned long value = 0;
  unsigned int digit;
  int negate;
  string = strtoul_pre(string, &negate, &base);
  for (;; string++) {
    digit = digit_value(*string);
    if (digit >= (unsigned int)base)
      break;
    value = ((value * base) + digit);
  }
  if (negate)
    value = -value;
  if (endp)
    *endp = ((char *)string);
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strtoul>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x14(%rsp),%rsi
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strtoul_pre@plt>
  mov    %rax,%rbp
  jmp    L37
  nopw   0x0(%rax,%rax,1)
L1:
  imul   %r12,%rdx
  mov    %eax,%eax
  add    $0x1,%rbp
  lea    (%rax,%rdx,1),%r12
L37:
  movsbl 0x0(%rbp),%edi
  call   <digit_value@plt>
  movslq 0xc(%rsp),%rdx
  cmp    %eax,%edx
  ja     L1
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L14
  neg    %r12
L14:
  test   %rbx,%rbx
  je     L28
  mov    %rbp,(%rbx)
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long strtoul(const char *string, char **endp, int base) {
  unsigned long value = 0;
  unsigned int digit;
  int negate;
  string = strtoul_pre(string, &negate, &base);
  for (;; string++) {
    digit = digit_value(*string);
    if (digit >= (unsigned int)base)
      break;
    value = ((value * base) + digit);
  }
  if (negate)
    value = -value;
  if (endp)
    *endp = ((char *)string);
  return value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strtoul>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x20,%rsp
  mov    %edx,0xc(%rsp)
  lea    0x14(%rsp),%rsi
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strtoul_pre@plt>
  mov    %rax,%rbp
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L19:
  imul   %r12,%rdx
  mov    %eax,%eax
  add    $0x1,%rbp
  lea    (%rax,%rdx,1),%r12
L44:
  movsbl 0x0(%rbp),%edi
  call   <digit_value@plt>
  movslq 0xc(%rsp),%rdx
  cmp    %eax,%edx
  ja     L19
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L9
  neg    %r12
L9:
  test   %rbx,%rbx
  je     L8
  mov    %rbp,(%rbx)
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long strtoul(const char *string, char **endp, int base) {
  unsigned long value = 0;
  unsigned int digit;
  int negate;
  string = strtoul_pre(string, &negate, &base);
  for (;; string++) {
    digit = digit_value(*string);
    if (digit >= (unsigned int)base)
      break;
    value = ((value * base) + digit);
  }
  if (negate)
    value = -value;
  if (endp)
    *endp = ((char *)string);
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cxvec_sinc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jp     L13
  pxor   %xmm0,%xmm0
  ucomiss -0x4(%rbp),%xmm0
  jne    L13
  movss  D25(%rip),%xmm0
  jmp    L10
L13:
  movss  -0x4(%rbp),%xmm1
  movss  D18(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  movd   %xmm0,%eax
  movss  -0x4(%rbp),%xmm1
  movss  D18(%rip),%xmm0
  mulss  %xmm0,%xmm1
  movd   %eax,%xmm0
  divss  %xmm1,%xmm0
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D25
type_guessed: byte[4]
name: parse_data
arguments: data_tag: D18
type_guessed: byte[4]

tool: {"D25": [0x00,0x00,0x80,0x3f]}

tool: {"D18": [0xdb,0x0f,0x49,0x40]}

assistant: ```c
float cxvec_sinc(float x) {
  if (x == 0.0f)
    return .9999999999;
  return sin((3.14159265358979323846264338327f) * x) / ((3.14159265358979323846264338327f) * x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cxvec_sinc>:
  endbr64
  movaps %xmm0,%xmm1
  ucomiss D17(%rip),%xmm0
  jp     L9
  movss  D29(%rip),%xmm0
  jne    L9
  ret
L9:
  sub    $0x18,%rsp
  mulss  D23(%rip),%xmm1
  movss  %xmm1,0xc(%rsp)
  movaps %xmm1,%xmm0
  call   <sin@plt>
  divss  0xc(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
type_infered: byte[4]
name: unpack_data
arguments: tag: D29
type_infered: byte[4]
name: unpack_data
arguments: tag: D23
type_infered: byte[4]

tool: {"D17": [0x00,0x00,0x00,0x00]}

tool: {"D29": [0x00,0x00,0x80,0x3f]}

tool: {"D23": [0xdb,0x0f,0x49,0x40]}

assistant: ```c
float cxvec_sinc(float x) {
  if (x == 0.0f)
    return .9999999999;
  return sin((3.14159265358979323846264338327f) * x) / ((3.14159265358979323846264338327f) * x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cxvec_sinc>:
  endbr64
  ucomiss D3(%rip),%xmm0
  jp     L0
  movss  D22(%rip),%xmm2
  jne    L0
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  sub    $0x18,%rsp
  movss  D16(%rip),%xmm1
  mulss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <sin@plt>
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
data_type: byte[4]
name: retrieve_data
arguments: data_label: D22
data_type: byte[4]
name: retrieve_data
arguments: data_label: D16
data_type: byte[4]

tool: {"D3": [0x00,0x00,0x00,0x00]}

tool: {"D22": [0x00,0x00,0x80,0x3f]}

tool: {"D16": [0xdb,0x0f,0x49,0x40]}

assistant: ```c
float cxvec_sinc(float x) {
  if (x == 0.0f)
    return .9999999999;
  return sin((3.14159265358979323846264338327f) * x) / ((3.14159265358979323846264338327f) * x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cxvec_sinc>:
  endbr64
  ucomiss D16(%rip),%xmm0
  jp     L16
  movss  D13(%rip),%xmm2
  jne    L16
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  sub    $0x18,%rsp
  movss  D9(%rip),%xmm1
  mulss  %xmm0,%xmm1
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <sin@plt>
  movss  0xc(%rsp),%xmm1
  add    $0x18,%rsp
  movaps %xmm0,%xmm2
  divss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D13
type_infered: byte[4]
name: extract_symbolic_data
arguments: tag: D9
type_infered: byte[4]

tool: {"D16": [0x00,0x00,0x00,0x00]}

tool: {"D13": [0x00,0x00,0x80,0x3f]}

tool: {"D9": [0xdb,0x0f,0x49,0x40]}

assistant: ```c
float cxvec_sinc(float x) {
  if (x == 0.0f)
    return .9999999999;
  return sin((3.14159265358979323846264338327f) * x) / ((3.14159265358979323846264338327f) * x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_value_with_base_strtoul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <make_string_strtoul@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <test_string_strtoul@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_value_with_base_strtoul(unsigned long value, int base) {
  const char *s;
  s = make_string_strtoul(value, base);
  test_string_strtoul(s, value, base);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_value_with_base_strtoul>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <make_string_strtoul@plt>
  mov    %rax,%rdi
  mov    %ebp,%edx
  mov    %rbx,%rsi
  call   <test_string_strtoul@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test_value_with_base_strtoul(unsigned long value, int base) {
  const char *s;
  s = make_string_strtoul(value, base);
  test_string_strtoul(s, value, base);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_value_with_base_strtoul>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <make_string_strtoul@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <test_string_strtoul@plt>
```

assistant: ```c
void test_value_with_base_strtoul(unsigned long value, int base) {
  const char *s;
  s = make_string_strtoul(value, base);
  test_string_strtoul(s, value, base);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_value_with_base_strtoul>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <make_string_strtoul@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <test_string_strtoul@plt>
```

assistant: ```c
void test_value_with_base_strtoul(unsigned long value, int base) {
  const char *s;
  s = make_string_strtoul(value, base);
  test_string_strtoul(s, value, base);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<devredir_cvt_from_unicode_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  addl   $0x2,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L12
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void devredir_cvt_from_unicode_len(char *path, char *unicode, int len) {
  int i;
  int j;
  for (i = 0, j = 0; i < len; i += 2) {
    path[j++] = unicode[i];
  }
  path[j] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<devredir_cvt_from_unicode_len>:
  endbr64
  test   %edx,%edx
  jle    L23
  sub    $0x1,%edx
  shr    %edx
  lea    0x1(%rdx),%r8d
  mov    $0x0,%eax
L17:
  movzbl (%rsi,%rax,2),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L17
  add    $0x1,%edx
L7:
  movslq %edx,%rdx
  movb   $0x0,(%rdi,%rdx,1)
  ret
L23:
  mov    $0x0,%edx
  jmp    L7
```

assistant: ```c
void devredir_cvt_from_unicode_len(char *path, char *unicode, int len) {
  int i;
  int j;
  for (i = 0, j = 0; i < len; i += 2) {
    path[j++] = unicode[i];
  }
  path[j] = 0;
}
```