ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<julian_yyyymmdd_time_hhmm_to_julian>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <julian_get_clean_hhmm@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    $0x8,%eax
  je     L3
L28:
  pxor   %xmm0,%xmm0
L39:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jne    L28
  lea    0x10(%rsp),%r13
  mov    (%rbx),%eax
  movb   $0x0,0x14(%rsp)
  mov    %r13,%rdi
  mov    %eax,0x10(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  movb   $0x0,0x12(%rsp)
  mov    %eax,%r14d
  movzwl 0x4(%rbx),%eax
  mov    %ax,0x10(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  movb   $0x0,0x12(%rsp)
  mov    %eax,%ebp
  movzwl 0x6(%rbx),%eax
  mov    %ax,0x10(%rsp)
  call   <atoi@plt>
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %eax,%r13d
  call   <julian_get_hour_minute@plt>
  mov    0xc(%rsp),%r8d
  mov    0x8(%rsp),%ecx
  mov    %ebp,%edi
  mov    %r14d,%edx
  mov    %r13d,%esi
  pxor   %xmm0,%xmm0
  call   <greg2jul@plt>
  jmp    L39
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double julian_yyyymmdd_time_hhmm_to_julian(char *yyyymmdd, char *hhmm) {
  int year, month, day, hour, minute;
  char buffer[128];
  hhmm = julian_get_clean_hhmm(hhmm);
  if (strlen(yyyymmdd) != 8 || strlen(hhmm) != 4) {
    return 0.0;
  }
  *(buffer + 4) = '\0';
  *buffer = *yyyymmdd;
  *(buffer + 1) = *(yyyymmdd + 1);
  *(buffer + 2) = *(yyyymmdd + 2);
  *(buffer + 3) = *(yyyymmdd + 3);
  year = atoi(buffer);
  *(buffer + 2) = '\0';
  *(buffer) = *(yyyymmdd + 4);
  *(buffer + 1) = *(yyyymmdd + 5);
  month = atoi(buffer);
  *(buffer + 2) = '\0';
  *(buffer) = *(yyyymmdd + 6);
  *(buffer + 1) = *(yyyymmdd + 7);
  day = atoi(buffer);
  julian_get_hour_minute(&hour, &minute, hhmm);
  return greg2jul(month, day, year, hour, minute, 0.0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<julian_yyyymmdd_time_hhmm_to_julian>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  call   <julian_get_clean_hhmm@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  cmp    $0x8,%eax
  je     L38
L30:
  pxor   %xmm0,%xmm0
L39:
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0xa0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L38:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    $0x4,%eax
  jne    L30
  lea    0x10(%rsp),%r13
  mov    (%rbx),%eax
  movb   $0x0,0x14(%rsp)
  mov    %r13,%rdi
  mov    %eax,0x10(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  movb   $0x0,0x12(%rsp)
  mov    %eax,%r14d
  movzwl 0x4(%rbx),%eax
  mov    %ax,0x10(%rsp)
  call   <atoi@plt>
  mov    %r13,%rdi
  movb   $0x0,0x12(%rsp)
  mov    %eax,%ebp
  movzwl 0x6(%rbx),%eax
  mov    %ax,0x10(%rsp)
  call   <atoi@plt>
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %r12,%rdx
  mov    %eax,%r13d
  call   <julian_get_hour_minute@plt>
  mov    0xc(%rsp),%r8d
  mov    0x8(%rsp),%ecx
  mov    %ebp,%edi
  mov    %r14d,%edx
  mov    %r13d,%esi
  pxor   %xmm0,%xmm0
  call   <greg2jul@plt>
  jmp    L39
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double julian_yyyymmdd_time_hhmm_to_julian(char *yyyymmdd, char *hhmm) {
  int year, month, day, hour, minute;
  char buffer[128];
  hhmm = julian_get_clean_hhmm(hhmm);
  if (strlen(yyyymmdd) != 8 || strlen(hhmm) != 4) {
    return 0.0;
  }
  *(buffer + 4) = '\0';
  *buffer = *yyyymmdd;
  *(buffer + 1) = *(yyyymmdd + 1);
  *(buffer + 2) = *(yyyymmdd + 2);
  *(buffer + 3) = *(yyyymmdd + 3);
  year = atoi(buffer);
  *(buffer + 2) = '\0';
  *(buffer) = *(yyyymmdd + 4);
  *(buffer + 1) = *(yyyymmdd + 5);
  month = atoi(buffer);
  *(buffer + 2) = '\0';
  *(buffer) = *(yyyymmdd + 6);
  *(buffer + 1) = *(yyyymmdd + 7);
  day = atoi(buffer);
  julian_get_hour_minute(&hour, &minute, hhmm);
  return greg2jul(month, day, year, hour, minute, 0.0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x65,%edi
  call   <putchar@plt>
  mov    $0x6c,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main01() {
  putchar('h');
  putchar('e');
  putchar('l');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main01>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x65,%edi
  call   <putchar@plt>
  mov    $0x6c,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main01() {
  putchar('h');
  putchar('e');
  putchar('l');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main01>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x65,%edi
  call   <putchar@plt>
  mov    $0x6c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main01() {
  putchar('h');
  putchar('e');
  putchar('l');
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main01>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x68,%edi
  call   <putchar@plt>
  mov    $0x65,%edi
  call   <putchar@plt>
  mov    $0x6c,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main01() {
  putchar('h');
  putchar('e');
  putchar('l');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<a_clz_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    $0x20,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  test   %eax,%eax
  je     L66
  mov    $0x20,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L66:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x20,-0x4(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  sar    $0x10,%eax
  test   %eax,%eax
  je     L75
  sarl   $0x10,-0x8(%rbp)
  jmp    L1
L75:
  orl    $0x10,-0x4(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  sar    $0x8,%eax
  test   %eax,%eax
  je     L92
  sarl   $0x8,-0x8(%rbp)
  jmp    L31
L92:
  orl    $0x8,-0x4(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  test   %eax,%eax
  je     L18
  sarl   $0x4,-0x8(%rbp)
  jmp    L15
L18:
  orl    $0x4,-0x4(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  sar    $0x2,%eax
  test   %eax,%eax
  je     L65
  sarl   $0x2,-0x8(%rbp)
  jmp    L36
L65:
  orl    $0x2,-0x4(%rbp)
L36:
  mov    -0x8(%rbp),%eax
  sar    %eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  or     -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int a_clz_64(uint64_t x) {
  uint32_t y;
  int r;
  if (x >> 32)
    y = x >> 32, r = 0;
  else
    y = x, r = 32;
  if (y >> 16)
    y >>= 16;
  else
    r |= 16;
  if (y >> 8)
    y >>= 8;
  else
    r |= 8;
  if (y >> 4)
    y >>= 4;
  else
    r |= 4;
  if (y >> 2)
    y >>= 2;
  else
    r |= 2;
  return r | !(y >> 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<a_clz_64>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  test   %eax,%eax
  cmovne %eax,%edi
  cmp    $0x1,%eax
  sbb    %edx,%edx
  and    $0x20,%edx
  mov    %edi,%eax
  sar    $0x10,%eax
  jne    L32
  or     $0x10,%edx
  mov    %edi,%eax
L32:
  mov    %eax,%ecx
  sar    $0x8,%ecx
  jne    L13
  or     $0x8,%edx
  mov    %eax,%ecx
L13:
  mov    %ecx,%eax
  sar    $0x4,%eax
  jne    L1
  or     $0x4,%edx
  mov    %ecx,%eax
L1:
  mov    %eax,%ecx
  sar    $0x2,%ecx
  jne    L33
  or     $0x2,%edx
  mov    %eax,%ecx
L33:
  shr    %ecx
  sete   %al
  movzbl %al,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
int a_clz_64(uint64_t x) {
  uint32_t y;
  int r;
  if (x >> 32)
    y = x >> 32, r = 0;
  else
    y = x, r = 32;
  if (y >> 16)
    y >>= 16;
  else
    r |= 16;
  if (y >> 8)
    y >>= 8;
  else
    r |= 8;
  if (y >> 4)
    y >>= 4;
  else
    r |= 4;
  if (y >> 2)
    y >>= 2;
  else
    r |= 2;
  return r | !(y >> 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<a_clz_64>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  test   %eax,%eax
  cmovne %eax,%edi
  cmp    $0x1,%eax
  sbb    %edx,%edx
  mov    %edi,%eax
  and    $0x20,%edx
  sar    $0x10,%eax
  jne    L20
  or     $0x10,%edx
  mov    %edi,%eax
L20:
  mov    %eax,%ecx
  sar    $0x8,%ecx
  jne    L33
  or     $0x8,%edx
  mov    %eax,%ecx
L33:
  mov    %ecx,%eax
  sar    $0x4,%eax
  jne    L7
  or     $0x4,%edx
  mov    %ecx,%eax
L7:
  mov    %eax,%ecx
  sar    $0x2,%ecx
  jne    L28
  or     $0x2,%edx
  mov    %eax,%ecx
L28:
  xor    %eax,%eax
  shr    %ecx
  sete   %al
  or     %edx,%eax
  ret
```

assistant: ```c
int a_clz_64(uint64_t x) {
  uint32_t y;
  int r;
  if (x >> 32)
    y = x >> 32, r = 0;
  else
    y = x, r = 32;
  if (y >> 16)
    y >>= 16;
  else
    r |= 16;
  if (y >> 8)
    y >>= 8;
  else
    r |= 8;
  if (y >> 4)
    y >>= 4;
  else
    r |= 4;
  if (y >> 2)
    y >>= 2;
  else
    r |= 2;
  return r | !(y >> 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<a_clz_64>:
  endbr64
  mov    %edi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  test   %eax,%eax
  cmovne %eax,%edi
  cmp    $0x1,%eax
  sbb    %edx,%edx
  and    $0x20,%edx
  mov    %edi,%ecx
  add    $0x10,%edx
  cmp    $0x1,%eax
  sbb    %eax,%eax
  and    $0x20,%eax
  sar    $0x10,%ecx
  cmovne %ecx,%edi
  cmovne %eax,%edx
  mov    %edi,%ecx
  sar    $0x8,%ecx
  jne    L11
  or     $0x8,%edx
  mov    %edi,%ecx
L11:
  mov    %ecx,%eax
  sar    $0x4,%eax
  jne    L13
  or     $0x4,%edx
  mov    %ecx,%eax
L13:
  mov    %eax,%ecx
  sar    $0x2,%ecx
  jne    L9
  or     $0x2,%edx
  mov    %eax,%ecx
L9:
  xor    %eax,%eax
  shr    %ecx
  sete   %al
  or     %edx,%eax
  ret
```

assistant: ```c
int a_clz_64(uint64_t x) {
  uint32_t y;
  int r;
  if (x >> 32)
    y = x >> 32, r = 0;
  else
    y = x, r = 32;
  if (y >> 16)
    y >>= 16;
  else
    r |= 16;
  if (y >> 8)
    y >>= 8;
  else
    r |= 8;
  if (y >> 4)
    y >>= 4;
  else
    r |= 4;
  if (y >> 2)
    y >>= 2;
  else
    r |= 2;
  return r | !(y >> 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_persistent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L83
L49:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L46
  mov    D24(%rip),%rax
  mov    (%rax),%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L76
  mov    D24(%rip),%rax
  mov    (%rax),%rdx
  mov    D21(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L10
L76:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  jmp    L83
L10:
  mov    -0x4(%rbp),%eax
  jmp    L81
L46:
  cmpl   $0x0,-0x4(%rbp)
  je     L23
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L83:
  cmpl   $0x0,-0x18(%rbp)
  jg     L49
  jmp    L3
L23:
  nop
L3:
  mov    -0x8(%rbp),%eax
L81:
  leave
  ret
```

assistant: ```c
int write_persistent(const int fd, const void *p, int sz) {
  int rd = 0;
  int rt;
  while (sz > 0) {
    rt = write(fd, p, sz);
    if (rt < 0) {
      if (errno == EAGAIN || errno == EWOULDBLOCK) {
        usleep(1000);
        continue;
      }
      return rt;
    }
    if (rt == 0)
      break;
    assert(rt <= sz);
    p = (const void *)((const char *)p + rt);
    sz -= rt;
    rd += rt;
  }
  return rd;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_persistent>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L16
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%r14d
  jmp    L28
L60:
  mov    D24(%rip),%rax
  mov    (%rax),%rax
  mov    D26(%rip),%rdx
  cmp    (%rdx),%rax
  je     L40
  mov    D20(%rip),%rdx
  cmp    (%rdx),%rax
  je     L40
L25:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  mov    $0x3e8,%edi
  call   <usleep@plt>
L80:
  test   %ebp,%ebp
  jle    L75
L28:
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L60
  je     L39
  cmp    %ebp,%eax
  setle  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movslq %ebx,%rax
  add    %rax,%r12
  sub    %ebx,%ebp
  add    %ebx,%r14d
  jmp    L80
L75:
  mov    %r14d,%ebx
  jmp    L25
L16:
  mov    $0x0,%ebx
  jmp    L25
L39:
  mov    %r14d,%ebx
  jmp    L25
```

assistant: ```c
int write_persistent(const int fd, const void *p, int sz) {
  int rd = 0;
  int rt;
  while (sz > 0) {
    rt = write(fd, p, sz);
    if (rt < 0) {
      if (errno == EAGAIN || errno == EWOULDBLOCK) {
        usleep(1000);
        continue;
      }
      return rt;
    }
    if (rt == 0)
      break;
    assert(rt <= sz);
    p = (const void *)((const char *)p + rt);
    sz -= rt;
    rd += rt;
  }
  return rd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_persistent>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L19
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  xor    %r14d,%r14d
L59:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L11
  je     L40
  xor    %edi,%edi
  cmp    %ebx,%eax
  setle  %dil
  sub    %r12d,%ebx
  add    %r12d,%r14d
  call   <assert@plt>
  movslq %r12d,%rax
  add    %rax,%rbp
  test   %ebx,%ebx
  jg     L59
L40:
  mov    %r14d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  mov    D22(%rip),%rax
  mov    D14(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L1
  mov    D2(%rip),%rdx
  cmp    (%rdx),%rax
  je     L1
L65:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  jmp    L59
  nop
L19:
  xor    %r12d,%r12d
  jmp    L65
```

assistant: ```c
int write_persistent(const int fd, const void *p, int sz) {
  int rd = 0;
  int rt;
  while (sz > 0) {
    rt = write(fd, p, sz);
    if (rt < 0) {
      if (errno == EAGAIN || errno == EWOULDBLOCK) {
        usleep(1000);
        continue;
      }
      return rt;
    }
    if (rt == 0)
      break;
    assert(rt <= sz);
    p = (const void *)((const char *)p + rt);
    sz -= rt;
    rd += rt;
  }
  return rd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_persistent>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edx,%edx
  jle    L71
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  xor    %r14d,%r14d
L7:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L38
  je     L1
  xor    %edi,%edi
  cmp    %ebx,%eax
  setle  %dil
  sub    %r12d,%ebx
  add    %r12d,%r14d
  call   <assert@plt>
  movslq %r12d,%rax
  add    %rax,%rbp
  test   %ebx,%ebx
  jg     L7
L1:
  mov    %r14d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L38:
  mov    D24(%rip),%rax
  mov    D7(%rip),%rdx
  mov    (%rax),%rax
  cmp    (%rdx),%rax
  je     L43
  mov    D3(%rip),%rdx
  cmp    (%rdx),%rax
  je     L43
L5:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L43:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  jmp    L7
  nop
L71:
  xor    %r12d,%r12d
  jmp    L5
```

assistant: ```c
int write_persistent(const int fd, const void *p, int sz) {
  int rd = 0;
  int rt;
  while (sz > 0) {
    rt = write(fd, p, sz);
    if (rt < 0) {
      if (errno == EAGAIN || errno == EWOULDBLOCK) {
        usleep(1000);
        continue;
      }
      return rt;
    }
    if (rt == 0)
      break;
    assert(rt <= sz);
    p = (const void *)((const char *)p + rt);
    sz -= rt;
    rd += rt;
  }
  return rd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x14,%ecx
  mov    %rax,%rdx
  mov    $0x29,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <bytes_to_base16hex@plt>
  leave
  ret
```

assistant: ```c
const char *str_id(const uint8_t id[]) {
  static char hexbuf[(2 * 20) + 1];
  return bytes_to_base16hex(hexbuf, sizeof(hexbuf), id, 20);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_id>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rdx
  mov    $0x14,%ecx
  mov    $0x29,%esi
  lea    D1(%rip),%rdi
  call   <bytes_to_base16hex@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
const char *str_id(const uint8_t id[]) {
  static char hexbuf[(2 * 20) + 1];
  return bytes_to_base16hex(hexbuf, sizeof(hexbuf), id, 20);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_id>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x14,%ecx
  mov    $0x29,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <bytes_to_base16hex@plt>
```

assistant: ```c
const char *str_id(const uint8_t id[]) {
  static char hexbuf[(2 * 20) + 1];
  return bytes_to_base16hex(hexbuf, sizeof(hexbuf), id, 20);
}
```
user: What is the c source code of the assembly code below?

```asm
<str_id>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x14,%ecx
  mov    $0x29,%esi
  lea    D8(%rip),%rdi
  jmp    1050 <bytes_to_base16hex@plt>
```

assistant: ```c
const char *str_id(const uint8_t id[]) {
  static char hexbuf[(2 * 20) + 1];
  return bytes_to_base16hex(hexbuf, sizeof(hexbuf), id, 20);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UARTSpaceAvail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  add    $0x18,%eax
  cltq
  mov    (%rax),%eax
  and    $0x20,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
bool UARTSpaceAvail(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  return (((*((volatile uint32_t *)(ui32Base + 0x00000018))) & 0x00000020) ? false : true);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<UARTSpaceAvail>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  add    $0x18,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  test   $0x20,%al
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
bool UARTSpaceAvail(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  return (((*((volatile uint32_t *)(ui32Base + 0x00000018))) & 0x00000020) ? false : true);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<UARTSpaceAvail>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  add    $0x18,%ebx
  movslq %ebx,%rbx
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    (%rbx),%eax
  pop    %rbx
  test   $0x20,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool UARTSpaceAvail(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  return (((*((volatile uint32_t *)(ui32Base + 0x00000018))) & 0x00000020) ? false : true);
}
```
user: What is the c source code of the assembly code below:

```asm
<UARTSpaceAvail>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  add    $0x18,%ebx
  movslq %ebx,%rbx
  call   <_UARTBaseValid@plt>
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    (%rbx),%eax
  pop    %rbx
  test   $0x20,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool UARTSpaceAvail(uint32_t ui32Base) {
  ASSERT(_UARTBaseValid(ui32Base));
  return (((*((volatile uint32_t *)(ui32Base + 0x00000018))) & 0x00000020) ? false : true);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jle    L18
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <create_ods2@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <close@plt>
  mov    $0x0,%eax
  jmp    L14
L18:
  mov    $0x0,%eax
L14:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
type: string

tool: D1: wb

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  if (argc > 3) {
    FILE *fout = fopen(argv[1], "wb");
    create_ods2(fout, argv[2], atoi(argv[3]));
    close(fout);
    return 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  cmp    $0x3,%edi
  jg     L8
  mov    $0x0,%eax
  ret
L8:
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rdi
  lea    D0(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    0x18(%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    0x10(%rbx),%rsi
  mov    %rbp,%rdi
  call   <create_ods2@plt>
  mov    %rbp,%rdi
  call   <close@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: wb

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  if (argc > 3) {
    FILE *fout = fopen(argv[1], "wb");
    create_ods2(fout, argv[2], atoi(argv[3]));
    close(fout);
    return 0;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  cmp    $0x3,%edi
  jg     L3
  xor    %eax,%eax
  ret
L3:
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  push   %rax
  mov    0x8(%rsi),%rdi
  lea    D2(%rip),%rsi
  call   <fopen@plt>
  mov    0x18(%rbx),%rdi
  mov    %rax,%rbp
  call   <atoi@plt>
  mov    0x10(%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <create_ods2@plt>
  mov    %rbp,%rdi
  call   <close@plt>
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D2: wb

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  if (argc > 3) {
    FILE *fout = fopen(argv[1], "wb");
    create_ods2(fout, argv[2], atoi(argv[3]));
    close(fout);
    return 0;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  cmp    $0x3,%edi
  jg     L2
  xor    %eax,%eax
  ret
L2:
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  push   %rax
  mov    0x8(%rsi),%rdi
  lea    D1(%rip),%rsi
  call   <fopen@plt>
  mov    0x18(%rbx),%rdi
  mov    %rax,%rbp
  call   <atoi@plt>
  mov    0x10(%rbx),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <create_ods2@plt>
  mov    %rbp,%rdi
  call   <close@plt>
  pop    %rdx
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: wb

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  if (argc > 3) {
    FILE *fout = fopen(argv[1], "wb");
    create_ods2(fout, argv[2], atoi(argv[3]));
    close(fout);
    return 0;
  }
  return 0;
}
```