user: What would the C source look like for the assembly code provided here?

```asm
<BFS>:
  endbr64
  push   %rbp
  movslq %ecx,%r9
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  movslq %r8d,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  mov    %rsi,%rbx
  movslq %edi,%rsi
  lea    0x0(,%rsi,4),%r8
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(%r8),%rax
  mov    %rsp,%rcx
  mov    %rax,%r10
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%r10
  and    $0xfffffffffffffff0,%rdx
  sub    %r10,%rcx
  cmp    %rcx,%rsp
  je     L162
L16:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L16
L162:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L157
L48:
  mov    %rax,%rcx
  mov    %rsp,%r10
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%r10
  and    $0xfffffffffffffff0,%rcx
  cmp    %r10,%rsp
  je     L130
L15:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r10,%rsp
  jne    L15
L130:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L60
L115:
  lea    0x3(%rsp),%r11
  mov    %r11,%r10
  and    $0xfffffffffffffffc,%r11
  shr    $0x2,%r10
  test   %edi,%edi
  jle    L164
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L158
  mov    %edi,%ecx
  movdqa D3(%rip),%xmm0
  mov    %rdx,%rax
  shr    $0x2,%ecx
  shl    $0x4,%rcx
  add    %rdx,%rcx
  nopl   (%rax)
L133:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rcx,%rax
  jne    L133
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%dil
  je     L0
L160:
  movslq %eax,%rcx
  lea    0x1(%rax),%r14d
  lea    (%rdx,%rcx,4),%rcx
  movl   $0x1,(%rcx)
  cmp    %r14d,%edi
  jle    L0
  add    $0x2,%eax
  movl   $0x1,0x4(%rcx)
  cmp    %eax,%edi
  jle    L0
  movl   $0x1,0x8(%rcx)
L0:
  movl   $0x0,(%rdx,%r9,4)
  xor    %edi,%edi
  movl   $0xffffffff,(%r12,%r9,4)
  mov    %r9d,0x0(,%r10,4)
  mov    $0xffffffffffffffff,%r10
  nopl   0x0(%rax,%rax,1)
L68:
  movslq 0x4(%r11,%r10,4),%rcx
  xor    %eax,%eax
  mov    %rcx,%r9
  imul   %r8,%rcx
  add    %rbx,%rcx
  nopl   0x0(%rax)
L208:
  mov    (%rdx,%rax,4),%r14d
  test   %r14d,%r14d
  je     L95
  mov    (%rcx,%rax,4),%r14d
  test   %r14d,%r14d
  jle    L95
  add    $0x1,%edi
  movl   $0x0,(%rdx,%rax,4)
  movslq %edi,%r14
  mov    %r9d,(%r12,%rax,4)
  mov    %eax,(%r11,%r14,4)
L95:
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L208
  add    $0x1,%r10
  cmp    %r10d,%edi
  jg     L68
L98:
  mov    (%rdx,%r13,4),%edx
  xor    %eax,%eax
  test   %edx,%edx
  sete   %al
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L157:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L48
L164:
  movl   $0x0,(%rdx,%r9,4)
  movl   $0xffffffff,(%r12,%r9,4)
  jmp    L98
L158:
  xor    %eax,%eax
  jmp    L160
L60:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L115
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: byte[16]

tool: {"D3": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int BFS(int n, int rG[n][n], int parent[n], int S, int T) {
  int visited[n], Queue[n], front = -1, rear = -1;
  for (int i = 0; i < n; i++) {
    visited[i] = 1;
  }
  Queue[++rear] = S;
  visited[S] = 0;
  parent[S] = -1;
  while (front < rear) {
    int u = Queue[++front];
    for (int v = 0; v < n; v++) {
      if (visited[v] && rG[u][v] > 0) {
        Queue[++rear] = v;
        visited[v] = 0;
        parent[v] = u;
      }
    }
  }
  return !visited[T];
}
```