ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<adb_is_symlink>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x820,%rsp
  mov    %rdi,-0x818(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x810(%rbp)
  movq   $0x0,-0x808(%rbp)
  lea    -0x800(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xfe,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x818(%rbp),%rdx
  lea    -0x810(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x810(%rbp),%rax
  mov    %rax,%rdi
  call   <adb_condition@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_infered: string

tool: D2: -L %s

assistant: ```c
int adb_is_symlink(const char *path) {
  char buf[2048] = {0};
  sprintf(buf, "-L %s", path);
  return adb_condition(buf);
}
```
user: Translate the below assembly code into C programming language:

```asm
<adb_is_symlink>:
  endbr64
  push   %rbx
  sub    $0x810,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0xfe,%ecx
  rep stos %rax,%es:(%rdi)
  mov    %rsp,%rbx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <adb_condition@plt>
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x810,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
datatype: string

tool: D6: -L %s

assistant: ```c
int adb_is_symlink(const char *path) {
  char buf[2048] = {0};
  sprintf(buf, "-L %s", path);
  return adb_condition(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<adb_is_symlink>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0xfe,%ecx
  pxor   %xmm0,%xmm0
  lea    D1(%rip),%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <adb_condition@plt>
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x810,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: -L %s

assistant: ```c
int adb_is_symlink(const char *path) {
  char buf[2048] = {0};
  sprintf(buf, "-L %s", path);
  return adb_condition(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<adb_is_symlink>:
  endbr64
  push   %rbp
  mov    %rdi,%rdx
  mov    $0xfe,%ecx
  pxor   %xmm0,%xmm0
  lea    D2(%rip),%rsi
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <adb_condition@plt>
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x810,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: -L %s

assistant: ```c
int adb_is_symlink(const char *path) {
  char buf[2048] = {0};
  sprintf(buf, "-L %s", path);
  return adb_condition(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<blind_shiftc>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%r10
  mov    %rsi,%r11
  mov    %rdx,%rdi
  mov    %ecx,%esi
  test   %r8d,%r8d
  js     L37
  movslq %r8d,%rax
  lea    (%rdx,%rdx,1),%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    %edx,%ebp
  movslq %edx,%rax
  cmp    %rdi,%rax
  jb     L151
  mov    %esi,%eax
  sub    %r9d,%eax
  mov    %eax,%r9d
  sub    %edi,%ebp
L151:
  movslq %ebp,%rbp
  mov    %rdi,%rax
  sub    %rbp,%rax
  je     L143
  lea    0x0(,%rax,4),%rbx
  lea    (%r10,%rbp,4),%r8
  mov    $0x0,%edx
L102:
  mov    (%r8,%rdx,1),%ecx
  mov    %ecx,(%r11,%rdx,1)
  add    $0x4,%rdx
  cmp    %rdx,%rbx
  jne    L102
L112:
  cltq
  cmp    %rax,%rdi
  jbe    L61
  sub    %rdi,%rbp
  lea    (%r10,%rbp,4),%rcx
L64:
  mov    %esi,%edx
  sub    (%rcx,%rax,4),%edx
  mov    %edx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L64
L61:
  test   %rdi,%rdi
  je     L27
  shl    $0x2,%rdi
  mov    $0x0,%ecx
L108:
  mov    %r9d,%eax
  imul   (%r11,%rcx,1),%eax
  cltd
  idiv   %esi
  mov    %edx,(%r10,%rcx,1)
  add    $0x4,%rcx
  cmp    %rcx,%rdi
  jne    L108
L27:
  pop    %rbx
  pop    %rbp
  ret
L143:
  mov    $0x0,%eax
  jmp    L112
L37:
  neg    %r8d
  movslq %r8d,%rax
  lea    (%rdx,%rdx,1),%rcx
  mov    $0x0,%edx
  div    %rcx
  mov    %edx,%ecx
  movslq %edx,%rax
  cmp    %rdi,%rax
  jb     L82
  mov    %esi,%eax
  sub    %r9d,%eax
  mov    %eax,%r9d
  sub    %edi,%ecx
L82:
  test   %ecx,%ecx
  jle    L77
  mov    %ecx,%ebx
  mov    %ecx,%eax
  neg    %eax
  cltq
  add    %rdi,%rax
  lea    (%r10,%rax,4),%r8
  mov    $0x0,%eax
L69:
  mov    %esi,%edx
  sub    (%r8,%rax,4),%edx
  mov    %edx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L69
  mov    %ecx,%eax
L131:
  cltq
  cmp    %rax,%rdi
  jbe    L61
  movslq %ecx,%rcx
  neg    %rcx
  lea    (%r10,%rcx,4),%rcx
L99:
  mov    (%rcx,%rax,4),%edx
  mov    %edx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L99
  jmp    L61
L77:
  mov    $0x0,%eax
  jmp    L131
```

assistant: ```c
void blind_shiftc(int32_t v[], int32_t t[], size_t n, int32_t q, int st, int32_t c) {
  int i;
  if (st >= 0) {
    st %= 2 * n;
    if (st >= n) {
      c = q - c;
      st -= n;
    }
    for (i = 0; i < n - st; i++)
      t[i] = v[i + st];
    for (; i < n; i++)
      t[i] = q - v[i + st - n];
  } else {
    st = (-st) % (2 * n);
    if (st >= n) {
      c = q - c;
      st -= n;
    }
    for (i = 0; i < st; i++)
      t[i] = q - v[i - st + n];
    for (; i < n; i++)
      t[i] = v[i - st];
  }
  for (i = 0; i < n; i++)
    v[i] = (c * t[i]) % q;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<blind_shiftc>:
  endbr64
  push   %rbp
  mov    %rdi,%r11
  mov    %rdx,%r10
  mov    %rsi,%rdi
  push   %rbx
  mov    %ecx,%esi
  lea    (%rdx,%rdx,1),%rcx
  test   %r8d,%r8d
  js     L51
  movslq %r8d,%rax
  xor    %edx,%edx
  div    %rcx
  cmp    %r10,%rdx
  jae    L62
  mov    %r10,%rcx
  sub    %rdx,%rcx
  je     L11
L54:
  lea    0x0(,%rcx,4),%rbp
  lea    (%r11,%rdx,4),%rbx
  xor    %eax,%eax
  nopl   0x0(%rax)
L61:
  mov    (%rbx,%rax,1),%r8d
  mov    %r8d,(%rdi,%rax,1)
  add    $0x4,%rax
  cmp    %rax,%rbp
  jne    L61
  movslq %ecx,%rax
L178:
  cmp    %rcx,%r10
  jbe    L164
L6:
  sub    %r10,%rdx
  lea    (%r11,%rdx,4),%r8
  jmp    L87
  cs nopw 0x0(%rax,%rax,1)
L203:
  mov    %rcx,%rax
L87:
  mov    %esi,%edx
  sub    (%r8,%rax,4),%edx
  mov    %edx,(%rdi,%rcx,4)
  lea    0x1(%rax),%rcx
  cmp    %rcx,%r10
  ja     L203
L114:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L74:
  mov    (%rdi,%rcx,4),%eax
  imul   %r9d,%eax
  cltd
  idiv   %esi
  mov    %edx,(%r11,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%r10
  ja     L74
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  mov    %esi,%eax
  sub    %r10d,%edx
  mov    %r10,%rcx
  sub    %r9d,%eax
  movslq %edx,%rdx
  mov    %eax,%r9d
  sub    %rdx,%rcx
  jne    L54
  xor    %eax,%eax
  jmp    L178
  xchg   %ax,%ax
L51:
  neg    %r8d
  xor    %edx,%edx
  movslq %r8d,%rax
  div    %rcx
  cmp    %r10,%rdx
  jae    L23
  mov    %edx,%ecx
  xor    %r8d,%r8d
  xor    %eax,%eax
  test   %edx,%edx
  je     L10
L196:
  mov    %ecx,%edx
  movslq %ecx,%rax
  neg    %edx
  movslq %edx,%rdx
  add    %r10,%rdx
  lea    (%r11,%rdx,4),%rbx
  xor    %edx,%edx
  xchg   %ax,%ax
L181:
  mov    %esi,%r8d
  sub    (%rbx,%rdx,4),%r8d
  mov    %r8d,(%rdi,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L181
  movslq %ecx,%r8
L75:
  cmp    %rax,%r10
  jbe    L164
L10:
  neg    %r8
  movslq %ecx,%rdx
  lea    (%r11,%r8,4),%r8
  jmp    L110
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %rax,%rdx
L110:
  mov    (%r8,%rdx,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  lea    0x1(%rdx),%rax
  cmp    %rax,%r10
  ja     L39
  jmp    L114
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %esi,%eax
  mov    %edx,%ecx
  sub    %r9d,%eax
  sub    %r10d,%ecx
  mov    %eax,%r9d
  test   %ecx,%ecx
  jg     L196
  movslq %ecx,%r8
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L75
  nopw   0x0(%rax,%rax,1)
L164:
  test   %r10,%r10
  jne    L114
  pop    %rbx
  pop    %rbp
  ret
L11:
  xor    %eax,%eax
  jmp    L6
```

assistant: ```c
void blind_shiftc(int32_t v[], int32_t t[], size_t n, int32_t q, int st, int32_t c) {
  int i;
  if (st >= 0) {
    st %= 2 * n;
    if (st >= n) {
      c = q - c;
      st -= n;
    }
    for (i = 0; i < n - st; i++)
      t[i] = v[i + st];
    for (; i < n; i++)
      t[i] = q - v[i + st - n];
  } else {
    st = (-st) % (2 * n);
    if (st >= n) {
      c = q - c;
      st -= n;
    }
    for (i = 0; i < st; i++)
      t[i] = q - v[i - st + n];
    for (; i < n; i++)
      t[i] = v[i - st];
  }
  for (i = 0; i < n; i++)
    v[i] = (c * t[i]) % q;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D59(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L30:
  cmp    %rcx,%rsp
  je     L99
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L30
L99:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L6
  orq    $0x0,-0x8(%rsp,%rdx,1)
L6:
  mov    %rsp,%rbx
  test   %eax,%eax
  jle    L24
  mov    D70(%rip),%r14d
  mov    %r14d,-0x38(%rbp)
  mov    %r14d,-0x34(%rbp)
  mov    $0x0,%r12d
  lea    D59(%rip),%r13
  jmp    L96
L104:
  movss  -0x34(%rbp),%xmm3
  addss  D50(%rip),%xmm3
  movss  %xmm3,-0x34(%rbp)
L75:
  add    $0x1,%r12d
  mov    -0x2c(%rbp),%eax
  add    $0x4,%rbx
  cmp    %r12d,%eax
  jle    L31
L96:
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L104
  jne    L17
  movss  -0x38(%rbp),%xmm4
  addss  D50(%rip),%xmm4
  movss  %xmm4,-0x38(%rbp)
  jmp    L75
L17:
  movd   %r14d,%xmm5
  addss  D50(%rip),%xmm5
  movd   %xmm5,%r14d
  jmp    L75
L24:
  mov    D70(%rip),%r14d
  mov    %r14d,-0x38(%rbp)
  mov    %r14d,-0x34(%rbp)
L31:
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  movss  -0x34(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  -0x38(%rbp),%xmm2
  divss  %xmm1,%xmm2
  movd   %r14d,%xmm6
  divss  %xmm1,%xmm6
  movaps %xmm6,%xmm1
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D59
type: string
name: read_data
arguments: tag: D70
type: f32
name: read_data
arguments: tag: D50
type: byte[4]
name: read_data
arguments: tag: D56
type: string

tool: D59: %d

tool: D70: 0

tool: {"D50": [0x00,0x00,0x80,0x3f]}

tool: D56: %0.3f
%0.3f
%0.3f


assistant: ```c
int main() {
  int n, i;
  float countp = 0, countz = 0, countn = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0)
      countp++;
    else if (a[i] == 0)
      countz++;
    else
      countn++;
  }
  printf("%0.3f\n%0.3f\n%0.3f\n", countp / n, countn / n, countz / n);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D6(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L118
L32:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L32
L118:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L111
L30:
  mov    %rsp,%rbx
  test   %eax,%eax
  jle    L58
  pxor   %xmm7,%xmm7
  xor    %r13d,%r13d
  movss  %xmm7,-0x44(%rbp)
  movd   %xmm7,%r15d
  movd   %xmm7,%r14d
  jmp    L101
  nopl   0x0(%rax)
L50:
  movss  D3(%rip),%xmm3
  movd   %r14d,%xmm4
  addss  %xmm4,%xmm3
  movd   %xmm3,%r14d
L19:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  cmp    %r13d,%eax
  jle    L123
L101:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L50
  jne    L62
  movd   %r15d,%xmm2
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  movss  D3(%rip),%xmm5
  addss  %xmm2,%xmm5
  movd   %xmm5,%r15d
  cmp    %r13d,%eax
  jg     L101
  nop
L123:
  pxor   %xmm1,%xmm1
  movss  -0x44(%rbp),%xmm5
  movd   %r14d,%xmm0
  movd   %r15d,%xmm2
  cvtsi2ss %eax,%xmm1
  lea    D5(%rip),%rdi
  divss  %xmm1,%xmm5
  divss  %xmm1,%xmm0
  divss  %xmm1,%xmm2
  movaps %xmm5,%xmm1
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L62:
  movss  D3(%rip),%xmm6
  addss  -0x44(%rbp),%xmm6
  movss  %xmm6,-0x44(%rbp)
  jmp    L19
L111:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L30
L58:
  pxor   %xmm6,%xmm6
  movss  %xmm6,-0x44(%rbp)
  movd   %xmm6,%r15d
  movd   %xmm6,%r14d
  jmp    L123
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: byte[4]
name: parse_data
arguments: tag: D5
type_guessed: string

tool: D6: %d

tool: {"D3": [0x00,0x00,0x80,0x3f]}

tool: D5: %0.3f
%0.3f
%0.3f


assistant: ```c
int main() {
  int n, i;
  float countp = 0, countz = 0, countn = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0)
      countp++;
    else if (a[i] == 0)
      countz++;
    else
      countn++;
  }
  printf("%0.3f\n%0.3f\n%0.3f\n", countp / n, countn / n, countz / n);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  lea    D30(%rip),%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rdx
  mov    %rsp,%rsi
  mov    %rdx,%rax
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L40
L37:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L37
L40:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L10
L101:
  mov    %rsp,%rbx
  test   %eax,%eax
  jle    L120
  pxor   %xmm7,%xmm7
  xor    %r13d,%r13d
  movss  %xmm7,-0x44(%rbp)
  movd   %xmm7,%r15d
  movd   %xmm7,%r14d
  jmp    L18
  nopl   0x0(%rax)
L52:
  movss  D40(%rip),%xmm3
  movd   %r14d,%xmm4
  addss  %xmm4,%xmm3
  movd   %xmm3,%r14d
L91:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  cmp    %r13d,%eax
  jle    L65
L18:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L52
  jne    L84
  movd   %r15d,%xmm2
  mov    -0x3c(%rbp),%eax
  add    $0x1,%r13d
  add    $0x4,%rbx
  movss  D40(%rip),%xmm5
  addss  %xmm2,%xmm5
  movd   %xmm5,%r15d
  cmp    %r13d,%eax
  jg     L18
  nop
L65:
  pxor   %xmm1,%xmm1
  movss  -0x44(%rbp),%xmm5
  movd   %r14d,%xmm0
  movd   %r15d,%xmm2
  cvtsi2ss %eax,%xmm1
  lea    D7(%rip),%rdi
  divss  %xmm1,%xmm5
  divss  %xmm1,%xmm0
  divss  %xmm1,%xmm2
  movaps %xmm5,%xmm1
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L129
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L84:
  movss  D40(%rip),%xmm6
  addss  -0x44(%rbp),%xmm6
  movss  %xmm6,-0x44(%rbp)
  jmp    L91
L10:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L101
L120:
  pxor   %xmm6,%xmm6
  movss  %xmm6,-0x44(%rbp)
  movd   %xmm6,%r15d
  movd   %xmm6,%r14d
  jmp    L65
L129:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D30
type: string
name: parse_data
arguments: tag: D40
type: byte[4]
name: parse_data
arguments: tag: D7
type: string

tool: D30: %d

tool: {"D40": [0x00,0x00,0x80,0x3f]}

tool: D7: %0.3f
%0.3f
%0.3f


assistant: ```c
int main() {
  int n, i;
  float countp = 0, countz = 0, countn = 0;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0)
      countp++;
    else if (a[i] == 0)
      countz++;
    else
      countn++;
  }
  printf("%0.3f\n%0.3f\n%0.3f\n", countp / n, countn / n, countz / n);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmd_getbasedir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <PHYSFS_getBaseDir@plt>
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Base dir is [%s].


assistant: ```c
int cmd_getbasedir(char *args) {
  printf("Base dir is [%s].\n", PHYSFS_getBaseDir());
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cmd_getbasedir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <PHYSFS_getBaseDir@plt>
  mov    %rax,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
datatype: string

tool: D6: Base dir is [%s].


assistant: ```c
int cmd_getbasedir(char *args) {
  printf("Base dir is [%s].\n", PHYSFS_getBaseDir());
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmd_getbasedir>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PHYSFS_getBaseDir@plt>
  lea    D1(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_infered: string

tool: D1: Base dir is [%s].


assistant: ```c
int cmd_getbasedir(char *args) {
  printf("Base dir is [%s].\n", PHYSFS_getBaseDir());
  return (1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_getbasedir>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PHYSFS_getBaseDir@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string

tool: D7: Base dir is [%s].


assistant: ```c
int cmd_getbasedir(char *args) {
  printf("Base dir is [%s].\n", PHYSFS_getBaseDir());
  return (1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_tag_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L25
L26:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0xa,%rax
  mov    %rax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L29
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0xa,%rax
  mov    %rax,%rbx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  jmp    L23
L29:
  addl   $0x1,-0x14(%rbp)
L25:
  cmpl   $0xe,-0x14(%rbp)
  jle    L26
  mov    $0x0,%eax
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *get_tag_value(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return tags[i] + strlen(tag);
    }
    i++;
  }
  return NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_tag_value>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L8:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  lea    (%r12,%rbx,1),%rdi
  mov    %rbp,%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L25
  add    $0x400,%rbx
  cmp    $0x3c00,%rbx
  jne    L8
  mov    $0x0,%eax
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  add    %r12,%rax
  jmp    L0
```

assistant: ```c
char *get_tag_value(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return tags[i] + strlen(tag);
    }
    i++;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_tag_value>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L3:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L18
  add    $0x400,%rbx
  cmp    $0x3c00,%rbx
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  add    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *get_tag_value(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return tags[i] + strlen(tag);
    }
    i++;
  }
  return NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_tag_value>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L9:
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    (%r12,%rbx,1),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  je     L4
  add    $0x400,%rbx
  cmp    $0x3c00,%rbx
  jne    L9
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  add    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *get_tag_value(char tags[15][1024], char *tag) {
  int i = 0;
  while (i < 15) {
    if (strncmp(tags[i], tag, strlen(tag)) == 0) {
      return tags[i] + strlen(tag);
    }
    i++;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<removeuser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <delpasswd@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L0
  mov    -0x4(%rbp),%eax
  jmp    L24
L0:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <delshadow@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x4(%rbp),%eax
  jmp    L24
L6:
  mov    $0x0,%eax
L24:
  leave
  ret
```

assistant: ```c
int removeuser(char *user) {
  int i;
  if ((i = delpasswd(user)) != 0) {
    return i;
  }
  if ((i = delshadow(user)) != 0) {
    return i;
  }
  return 0;
}
```