ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<log10_add_pow10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L6
  movsd  -0x10(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  mov    D0(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <log10@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  addsd  -0x8(%rbp),%xmm0
  jmp    L15
L6:
  movsd  -0x8(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  mov    D0(%rip),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <pow@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <log10@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  addsd  -0x10(%rbp),%xmm0
L15:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: f64

tool: D0: 10

assistant: ```c
double log10_add_pow10(double a, double b) {
  if (a > b) {
    return a + log10(1 + (pow(10.0, b - a)));
  } else {
    return b + log10(1 + (pow(10.0, a - b)));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<log10_add_pow10>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  comisd %xmm1,%xmm0
  jbe    L11
  subsd  %xmm0,%xmm1
  movsd  D9(%rip),%xmm0
  call   <pow@plt>
  lea    0x1(%rax),%rdi
  call   <log10@plt>
  addsd  (%rsp),%xmm0
L10:
  add    $0x18,%rsp
  ret
L11:
  movsd  (%rsp),%xmm1
  subsd  0x8(%rsp),%xmm1
  movsd  D9(%rip),%xmm0
  call   <pow@plt>
  lea    0x1(%rax),%rdi
  call   <log10@plt>
  addsd  0x8(%rsp),%xmm0
  jmp    L10
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: f64

tool: D9: 10

assistant: ```c
double log10_add_pow10(double a, double b) {
  if (a > b) {
    return a + log10(1 + (pow(10.0, b - a)));
  } else {
    return b + log10(1 + (pow(10.0, a - b)));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<log10_add_pow10>:
  endbr64
  sub    $0x18,%rsp
  comisd %xmm1,%xmm0
  movapd %xmm0,%xmm3
  jbe    L9
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  movsd  D7(%rip),%xmm0
  call   <pow@plt>
  lea    0x1(%rax),%rdi
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm3
  add    $0x18,%rsp
  addsd  %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L9:
  subsd  %xmm1,%xmm3
  movsd  D7(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm3,%xmm1
  call   <pow@plt>
  lea    0x1(%rax),%rdi
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: f64

tool: D7: 10

assistant: ```c
double log10_add_pow10(double a, double b) {
  if (a > b) {
    return a + log10(1 + (pow(10.0, b - a)));
  } else {
    return b + log10(1 + (pow(10.0, a - b)));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<log10_add_pow10>:
  endbr64
  sub    $0x18,%rsp
  comisd %xmm1,%xmm0
  movapd %xmm0,%xmm3
  jbe    L7
  subsd  %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  movsd  D9(%rip),%xmm0
  call   <pow@plt>
  lea    0x1(%rax),%rdi
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm3
  add    $0x18,%rsp
  addsd  %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L7:
  subsd  %xmm1,%xmm3
  movsd  D9(%rip),%xmm0
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm3,%xmm1
  call   <pow@plt>
  lea    0x1(%rax),%rdi
  call   <log10@plt>
  movsd  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  addsd  %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: f64

tool: D9: 10

assistant: ```c
double log10_add_pow10(double a, double b) {
  if (a > b) {
    return a + log10(1 + (pow(10.0, b - a)));
  } else {
    return b + log10(1 + (pow(10.0, a - b)));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_gfortran_caf_sync_images>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8d,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
L5:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _gfortran_caf_sync_images(int count __attribute__((unused)), int images[] __attribute__((unused)), int *stat, char *errmsg __attribute__((unused)), int errmsg_len __attribute__((unused))) {
  if (stat)
    *stat = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_gfortran_caf_sync_images>:
  endbr64
  test   %rdx,%rdx
  je     L5
  movl   $0x0,(%rdx)
L5:
  ret
```

assistant: ```c
void _gfortran_caf_sync_images(int count __attribute__((unused)), int images[] __attribute__((unused)), int *stat, char *errmsg __attribute__((unused)), int errmsg_len __attribute__((unused))) {
  if (stat)
    *stat = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_gfortran_caf_sync_images>:
  endbr64
  test   %rdx,%rdx
  je     L3
  movl   $0x0,(%rdx)
L3:
  ret
```

assistant: ```c
void _gfortran_caf_sync_images(int count __attribute__((unused)), int images[] __attribute__((unused)), int *stat, char *errmsg __attribute__((unused)), int errmsg_len __attribute__((unused))) {
  if (stat)
    *stat = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_gfortran_caf_sync_images>:
  endbr64
  test   %rdx,%rdx
  je     L1
  movl   $0x0,(%rdx)
L1:
  ret
```

assistant: ```c
void _gfortran_caf_sync_images(int count __attribute__((unused)), int images[] __attribute__((unused)), int *stat, char *errmsg __attribute__((unused)), int errmsg_len __attribute__((unused))) {
  if (stat)
    *stat = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x80000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x1f9,%eax
  je     L18
  mov    $0x0,%eax
  call   <abort@plt>
L18:
  mov    $0x40000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x65,%eax
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (test_qbbc_reg(101, 505, (1u << 19)) != 505)
    abort();
  if (test_qbbc_reg(101, 505, (1u << 18)) != 101)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x1f9,%eax
  jne    L33
L5:
  mov    $0x40000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x65,%eax
  jne    L1
L17:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L33:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L5
L1:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L17
```

assistant: ```c
int main(int argc, char **argv) {
  if (test_qbbc_reg(101, 505, (1u << 19)) != 505)
    abort();
  if (test_qbbc_reg(101, 505, (1u << 18)) != 101)
    abort();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x1f9,%eax
  je     L19
  xor    %eax,%eax
  call   <abort@plt>
L19:
  mov    $0x40000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x65,%eax
  je     L10
  xor    %eax,%eax
  call   <abort@plt>
L10:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (test_qbbc_reg(101, 505, (1u << 19)) != 505)
    abort();
  if (test_qbbc_reg(101, 505, (1u << 18)) != 101)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x80000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x1f9,%eax
  je     L13
  xor    %eax,%eax
  call   <abort@plt>
L13:
  mov    $0x40000,%edx
  mov    $0x1f9,%esi
  mov    $0x65,%edi
  call   <test_qbbc_reg@plt>
  cmp    $0x65,%eax
  je     L5
  xor    %eax,%eax
  call   <abort@plt>
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (test_qbbc_reg(101, 505, (1u << 19)) != 505)
    abort();
  if (test_qbbc_reg(101, 505, (1u << 18)) != 101)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L48:
  addl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <foo@plt>
  cmpl   $0x63,-0x4(%rbp)
  jbe    L23
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  cmpl   $0x64,-0x8(%rbp)
  je     L38
  mov    $0x0,%eax
  call   <foo@plt>
  test   %rax,%rax
  je     L4
  mov    $0x0,%eax
  call   <bla@plt>
  jmp    L48
L4:
  mov    $0x0,%eax
  call   <bar@plt>
  jmp    L48
L23:
  nop
  jmp    L48
L38:
  nop
  nop
  leave
  ret
```

assistant: ```c
void test5(void) {
  unsigned i, j;
  i = j = 0;
  while (1) {
    j++;
    foo();
    if (j < 100)
      continue;
    j = 0;
    i++;
    if (i == 100)
      break;
    if (foo())
      bla();
    else
      bar();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test5>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x64,%ebp
  jmp    L22
L47:
  mov    $0x0,%eax
  call   <bar@plt>
L22:
  mov    $0x64,%ebx
L29:
  mov    $0x0,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L29
  sub    $0x1,%ebp
  je     L48
  mov    $0x0,%eax
  call   <foo@plt>
  test   %rax,%rax
  je     L47
  mov    $0x0,%eax
  call   <bla@plt>
  jmp    L22
L48:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test5(void) {
  unsigned i, j;
  i = j = 0;
  while (1) {
    j++;
    foo();
    if (j < 100)
      continue;
    j = 0;
    i++;
    if (i == 100)
      break;
    if (foo())
      bla();
    else
      bar();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test5>:
  endbr64
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nop
L36:
  mov    $0x64,%ebx
L5:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L5
  sub    $0x1,%ebp
  je     L45
  xor    %eax,%eax
  call   <foo@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L27
  call   <bla@plt>
  mov    $0x64,%ebx
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L27:
  call   <bar@plt>
  jmp    L36
  nop
L45:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test5(void) {
  unsigned i, j;
  i = j = 0;
  while (1) {
    j++;
    foo();
    if (j < 100)
      continue;
    j = 0;
    i++;
    if (i == 100)
      break;
    if (foo())
      bla();
    else
      bar();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test5>:
  endbr64
  push   %rbp
  mov    $0x64,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nop
L1:
  mov    $0x64,%ebx
L7:
  xor    %eax,%eax
  call   <foo@plt>
  sub    $0x1,%ebx
  jne    L7
  sub    $0x1,%ebp
  je     L28
  xor    %eax,%eax
  call   <foo@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  je     L11
  call   <bla@plt>
  mov    $0x64,%ebx
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L11:
  call   <bar@plt>
  jmp    L1
  nop
L28:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void test5(void) {
  unsigned i, j;
  i = j = 0;
  while (1) {
    j++;
    foo();
    if (j < 100)
      continue;
    j = 0;
    i++;
    if (i == 100)
      break;
    if (foo())
      bla();
    else
      bar();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<qr_diran>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  jmp    L6
L19:
  mov    -0xc(%rbp),%eax
  and    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L16
  lea    D2(%rip),%rax
  jmp    L5
L16:
  lea    D5(%rip),%rax
L5:
  mov    -0x8(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <concat@plt>
  sarl   -0x10(%rbp)
L6:
  cmpl   $0x0,-0x10(%rbp)
  jne    L19
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D2: 1

tool: D5: 0

assistant: ```c
void qr_diran(char *binary, int data, int h) {
  for (; h; h >>= 1) {
    concat(binary, data & h ? "1" : "0");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<qr_diran>:
  endbr64
  test   %edx,%edx
  je     L9
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%ebx
  lea    D6(%rip),%r14
  lea    D18(%rip),%r13
L16:
  test   %ebx,%r12d
  mov    %r13,%rsi
  cmovne %r14,%rsi
  mov    %rbp,%rdi
  call   <concat@plt>
  sar    %ebx
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string

tool: D6: 1

tool: D18: 0

assistant: ```c
void qr_diran(char *binary, int data, int h) {
  for (; h; h >>= 1) {
    concat(binary, data & h ? "1" : "0");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<qr_diran>:
  endbr64
  test   %edx,%edx
  je     L11
  push   %r14
  lea    D7(%rip),%r14
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L9:
  test   %ebx,%r12d
  mov    %r13,%rsi
  mov    %rbp,%rdi
  cmovne %r14,%rsi
  call   <concat@plt>
  sar    %ebx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L11:
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D10
datatype: string

tool: D7: 1

tool: D10: 0

assistant: ```c
void qr_diran(char *binary, int data, int h) {
  for (; h; h >>= 1) {
    concat(binary, data & h ? "1" : "0");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qr_diran>:
  endbr64
  test   %edx,%edx
  je     L33
  push   %r14
  lea    D10(%rip),%r14
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L26:
  test   %ebx,%r12d
  je     L25
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <concat@plt>
  sar    %ebx
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L25:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <concat@plt>
  sar    %ebx
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_guessed: string
name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D10: 0

tool: D6: 1

assistant: ```c
void qr_diran(char *binary, int data, int h) {
  for (; h; h >>= 1) {
    concat(binary, data & h ? "1" : "0");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L38
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L5
L38:
  mov    -0x4(%rbp),%eax
  jmp    L24
L5:
  addq   $0x1,-0x18(%rbp)
  jmp    L29
L24:
  pop    %rbp
  ret
```

assistant: ```c
int atoi(const char *str) {
  int val = 0;
  for (;; str++) {
    switch (*str) {
    case '0' ... '9':
      val = 10 * val + (*str - '0');
      break;
    default:
      return val;
    }
  }
  return val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L0
  mov    $0x0,%edx
L7:
  lea    (%rdx,%rdx,4),%edx
  lea    -0x30(%rax,%rdx,2),%edx
  add    $0x1,%rdi
  movsbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  jbe    L7
L25:
  mov    %edx,%eax
  ret
L0:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
int atoi(const char *str) {
  int val = 0;
  for (;; str++) {
    switch (*str) {
    case '0' ... '9':
      val = 10 * val + (*str - '0');
      break;
    default:
      return val;
    }
  }
  return val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L15
  nopw   0x0(%rax,%rax,1)
L6:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L6
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(const char *str) {
  int val = 0;
  for (;; str++) {
    switch (*str) {
    case '0' ... '9':
      val = 10 * val + (*str - '0');
      break;
    default:
      return val;
    }
  }
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<atoi>:
  endbr64
  movsbl (%rdi),%eax
  xor    %r8d,%r8d
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L8
  nopw   0x0(%rax,%rax,1)
L5:
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%r8d
  movsbl (%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L5
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(const char *str) {
  int val = 0;
  for (;; str++) {
    switch (*str) {
    case '0' ... '9':
      val = 10 * val + (*str - '0');
      break;
    default:
      return val;
    }
  }
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<polymod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <fls64@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x3f,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shll   %cl,-0x1c(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L45
  cmpl   $0x0,-0x14(%rbp)
  jns    L67
  mov    -0x1c(%rbp),%eax
  xor    %eax,-0x14(%rbp)
L67:
  movl   $0x3e,-0x8(%rbp)
  jmp    L5
L43:
  mov    -0x8(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L62
  mov    $0x3f,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x18(%rbp)
L62:
  subl   $0x1,-0x8(%rbp)
L5:
  cmpl   $0x0,-0x8(%rbp)
  jns    L43
L45:
  movl   $0x3f,-0x8(%rbp)
  jmp    L60
L22:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L55
  mov    $0x3f,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x1c(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  xor    %eax,-0x18(%rbp)
L55:
  subl   $0x1,-0x8(%rbp)
L60:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L22
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
u_int64_t polymod(u_int64_t nh, u_int64_t nl, u_int64_t d) {
  int i;
  int k = fls64(d) - 1;
  d <<= 63 - k;
  if (nh) {
    if (nh & 0x8000000000000000LL)
      nh ^= d;
    for (i = 62; i >= 0; i--)
      if (nh & ((u_int64_t)1) << i) {
        nh ^= d >> (63 - i);
        nl ^= d << (i + 1);
      }
  }
  for (i = 63; i >= k; i--) {
    if (nl & 1LL << i)
      nl ^= d >> (63 - i);
  }
  return nl;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<polymod>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %edx,%r12d
  mov    %edx,%edi
  call   <fls64@plt>
  mov    %eax,%edi
  lea    -0x1(%rax),%r8d
  mov    $0x3f,%ecx
  sub    %r8d,%ecx
  mov    %r12d,%edx
  shl    %cl,%edx
  test   %ebx,%ebx
  je     L91
  mov    %ebx,%eax
  xor    %edx,%eax
  test   %ebx,%ebx
  cmovs  %eax,%ebx
  mov    $0x3e,%eax
  mov    $0x3f,%esi
  jmp    L35
L29:
  sub    $0x1,%eax
  cmp    $0xffffffff,%eax
  je     L91
L35:
  bt     %eax,%ebx
  jae    L29
  mov    %esi,%ecx
  sub    %eax,%ecx
  mov    %edx,%r9d
  sar    %cl,%r9d
  xor    %r9d,%ebx
  lea    0x1(%rax),%ecx
  mov    %edx,%r10d
  shl    %cl,%r10d
  xor    %r10d,%ebp
  jmp    L29
L91:
  cmp    $0x3f,%r8d
  jg     L82
  sub    $0x2,%edi
  mov    %ebp,%eax
  mov    $0x3f,%esi
  mov    $0x3f,%r8d
  jmp    L23
L97:
  sub    $0x1,%esi
  cmp    %esi,%edi
  je     L41
L23:
  movslq %eax,%rcx
  bt     %rsi,%rcx
  jae    L97
  mov    %r8d,%ecx
  sub    %esi,%ecx
  mov    %edx,%ebx
  sar    %cl,%ebx
  xor    %ebx,%eax
  jmp    L97
L82:
  mov    %ebp,%eax
L41:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
u_int64_t polymod(u_int64_t nh, u_int64_t nl, u_int64_t d) {
  int i;
  int k = fls64(d) - 1;
  d <<= 63 - k;
  if (nh) {
    if (nh & 0x8000000000000000LL)
      nh ^= d;
    for (i = 62; i >= 0; i--)
      if (nh & ((u_int64_t)1) << i) {
        nh ^= d >> (63 - i);
        nl ^= d << (i + 1);
      }
  }
  for (i = 63; i >= k; i--) {
    if (nl & 1LL << i)
      nl ^= d >> (63 - i);
  }
  return nl;
}
```
user: Translate the below assembly code into C programming language:

```asm
<polymod>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %edx,%edi
  call   <fls64@plt>
  mov    $0x3f,%ecx
  mov    %r12d,%edx
  lea    -0x1(%rax),%r8d
  mov    %eax,%edi
  sub    %r8d,%ecx
  shl    %cl,%edx
  test   %ebx,%ebx
  je     L57
  mov    %ebx,%eax
  mov    $0x3f,%esi
  xor    %edx,%eax
  test   %ebx,%ebx
  cmovs  %eax,%ebx
  mov    $0x3e,%eax
L54:
  bt     %eax,%ebx
  jae    L23
  mov    %esi,%ecx
  mov    %edx,%r9d
  mov    %edx,%r10d
  sub    %eax,%ecx
  sar    %cl,%r9d
  lea    0x1(%rax),%ecx
  shl    %cl,%r10d
  xor    %r9d,%ebx
  xor    %r10d,%ebp
L23:
  sub    $0x1,%eax
  jae    L54
L57:
  cmp    $0x3f,%r8d
  jg     L36
  sub    $0x2,%edi
  mov    %ebp,%eax
  mov    $0x3f,%esi
  mov    $0x3f,%r8d
  nopl   0x0(%rax)
L10:
  movslq %eax,%rcx
  bt     %rsi,%rcx
  jae    L5
  mov    %r8d,%ecx
  mov    %edx,%ebx
  sub    %esi,%ecx
  sar    %cl,%ebx
  xor    %ebx,%eax
L5:
  sub    $0x1,%esi
  cmp    %esi,%edi
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
u_int64_t polymod(u_int64_t nh, u_int64_t nl, u_int64_t d) {
  int i;
  int k = fls64(d) - 1;
  d <<= 63 - k;
  if (nh) {
    if (nh & 0x8000000000000000LL)
      nh ^= d;
    for (i = 62; i >= 0; i--)
      if (nh & ((u_int64_t)1) << i) {
        nh ^= d >> (63 - i);
        nl ^= d << (i + 1);
      }
  }
  for (i = 63; i >= k; i--) {
    if (nl & 1LL << i)
      nl ^= d >> (63 - i);
  }
  return nl;
}
```