ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<recv>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %ebp,%ebp
  jle    L1
  test   %rdi,%rdi
  jne    L1
  cmp    $0x201,%ebp
  mov    $0x1fe,%eax
  mov    $0x428,%edi
  mov    %rsi,%r13
  cmovge %rax,%rbp
  mov    %r13,%r15
  call   <SPI_Read@plt>
  mov    $0x429,%edi
  mov    %rax,%rbx
  call   <SPI_Read@plt>
  shl    $0x8,%ebx
  and    $0xff00,%ebx
  lea    (%rax,%rbx,1),%r14
  lea    0x0(%rbp,%r14,1),%r12d
  mov    %r14d,%ebx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  add    $0x1,%ebx
  add    $0x8,%r15
  and    $0x7ff,%edi
  add    $0x6000,%edi
  call   <SPI_Read@plt>
  mov    %rax,-0x8(%r15)
  cmp    %r12d,%ebx
  jne    L8
  movq   $0x0,0x0(%r13,%rbp,8)
  lea    0x0(%rbp,%r14,1),%ebx
  mov    $0x428,%edi
  movzbl %bh,%esi
  call   <SPI_Write@plt>
  movzbl %bl,%esi
  mov    $0x429,%edi
  call   <SPI_Write@plt>
  mov    $0x401,%edi
  mov    $0x40,%esi
  call   <SPI_Write@plt>
  mov    $0x5,%edi
  call   <delay_us@plt>
L1:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
uint16_t recv(uint8_t sock, uint8_t *buf, uint16_t buflen) {
  uint16_t ptr, offaddr, realaddr;
  if (buflen <= 0 || sock != 0)
    return 1;
  if (buflen > 512)
    buflen = 512 - 2;
  ptr = SPI_Read(0x0428);
  offaddr = (((ptr & 0x00FF) << 8) + SPI_Read(0x0428 + 1));
  while (buflen) {
    buflen--;
    realaddr = 0x6000 + (offaddr & 0x07FF);
    *buf = SPI_Read(realaddr);
    offaddr++;
    buf++;
  }
  *buf = '\0';
  SPI_Write(0x0428, (offaddr & 0xFF00) >> 8);
  SPI_Write(0x0428 + 1, (offaddr & 0x00FF));
  SPI_Write(0x0401, 0x40);
  delay_us(5);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getInforNotd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x810,%rsp
  mov    %rdi,-0x7f8(%rbp)
  mov    %rsi,-0x800(%rbp)
  mov    %rdx,-0x808(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    -0x7f8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x7ec(%rbp)
  movl   $0x0,-0x7f0(%rbp)
  movq   $0x0,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rcx
  mov    -0x7ec(%rbp),%eax
  mov    $0x7d0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    -0x7ec(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    -0x800(%rbp),%rdx
  lea    -0x7e0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  mov    %rax,-0x7e8(%rbp)
L20:
  addq   $0x1,-0x7e8(%rbp)
  mov    -0x7e8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L20
  addq   $0x2,-0x7e8(%rbp)
  jmp    L30
L34:
  mov    -0x7f0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x808(%rbp),%rax
  add    %rax,%rdx
  mov    -0x7e8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x7f0(%rbp)
  addq   $0x1,-0x7e8(%rbp)
L30:
  mov    -0x7e8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L34
  mov    -0x7f0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x808(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
void getInforNotd(char *path, char *name, char infor[]) {
  int fd = open(path, O_RDONLY);
  char store[2000];
  int k = 0;
  char *p = NULL;
  read(fd, store, sizeof(store));
  close(fd);
  p = strstr(store, name);
  do {
    p++;
  } while (*p != ':');
  p += 2;
  while (*p != '\n') {
    infor[k] = *p;
    k++;
    p++;
  }
  infor[k] = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getInforNotd>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  mov    %rsp,%r13
  mov    $0x7d0,%edx
  mov    %r13,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
L49:
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x3a,(%rax)
  jne    L49
  movzbl 0x3(%rcx),%edx
  cmp    $0xa,%dl
  je     L37
  mov    $0x1,%eax
L48:
  mov    %dl,-0x1(%rbx,%rax,1)
  mov    %eax,%esi
  add    $0x1,%rax
  movzbl 0x2(%rcx,%rax,1),%edx
  cmp    $0xa,%dl
  jne    L48
L1:
  movslq %esi,%rsi
  movb   $0x0,(%rbx,%rsi,1)
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L37:
  mov    $0x0,%esi
  jmp    L1
L45:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getInforNotd(char *path, char *name, char infor[]) {
  int fd = open(path, O_RDONLY);
  char store[2000];
  int k = 0;
  char *p = NULL;
  read(fd, store, sizeof(store));
  close(fd);
  p = strstr(store, name);
  do {
    p++;
  } while (*p != ':');
  p += 2;
  while (*p != '\n') {
    infor[k] = *p;
    k++;
    p++;
  }
  infor[k] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getInforNotd>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  mov    D2(%rip),%rax
  mov    %rsp,%r13
  mov    (%rax),%esi
  call   <open@plt>
  mov    %r13,%rsi
  mov    $0x7d0,%edx
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <read@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  nopl   0x0(%rax)
L16:
  mov    %rax,%rdx
  lea    0x1(%rax),%rax
  cmpb   $0x3a,0x1(%rdx)
  jne    L16
  movzbl 0x3(%rdx),%ecx
  cmp    $0xa,%cl
  je     L13
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %cl,-0x1(%rbx,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl 0x2(%rdx,%rax,1),%ecx
  cmp    $0xa,%cl
  jne    L25
  add    %rsi,%rbx
L13:
  movb   $0x0,(%rbx)
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getInforNotd(char *path, char *name, char infor[]) {
  int fd = open(path, O_RDONLY);
  char store[2000];
  int k = 0;
  char *p = NULL;
  read(fd, store, sizeof(store));
  close(fd);
  p = strstr(store, name);
  do {
    p++;
  } while (*p != ':');
  p += 2;
  while (*p != '\n') {
    infor[k] = *p;
    k++;
    p++;
  }
  infor[k] = '\0';
}
```
user: Translate the below assembly code into C programming language:

```asm
<getInforNotd>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  mov    D1(%rip),%rax
  mov    %rsp,%r13
  mov    (%rax),%esi
  call   <open@plt>
  mov    %r13,%rsi
  mov    $0x7d0,%edx
  mov    %eax,%ebp
  mov    %eax,%edi
  call   <read@plt>
  mov    %ebp,%edi
  call   <close@plt>
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  nopl   0x0(%rax)
L15:
  mov    %rax,%rdx
  lea    0x1(%rax),%rax
  cmpb   $0x3a,0x1(%rdx)
  jne    L15
  movzbl 0x3(%rdx),%ecx
  cmp    $0xa,%cl
  je     L10
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %cl,-0x1(%rbx,%rax,1)
  movslq %eax,%rsi
  add    $0x1,%rax
  movzbl 0x2(%rdx,%rax,1),%ecx
  cmp    $0xa,%cl
  jne    L5
  add    %rsi,%rbx
L10:
  movb   $0x0,(%rbx)
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x7e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void getInforNotd(char *path, char *name, char infor[]) {
  int fd = open(path, O_RDONLY);
  char store[2000];
  int k = 0;
  char *p = NULL;
  read(fd, store, sizeof(store));
  close(fd);
  p = strstr(store, name);
  do {
    p++;
  } while (*p != ':');
  p += 2;
  while (*p != '\n') {
    infor[k] = *p;
    k++;
    p++;
  }
  infor[k] = '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_combinations_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L27
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x28(%rbp)
  je     L9
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L27:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  call   <print_combinations_aux>
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdi
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rdi,%rdx
  mov    %rax,%rdi
  call   <print_combinations_aux>
  jmp    L39
L9:
  nop
L39:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: %s


assistant: ```c
void print_combinations_aux(const char *str, size_t str_sz, size_t str_i, char *buff, size_t buff_i) {
  if (str_i == str_sz) {
    buff[buff_i] = '\0';
    if (buff_i != 0) {
      printf("%s\n", buff);
    }
    return;
  }
  print_combinations_aux(str, str_sz, str_i + 1, buff, buff_i);
  buff[buff_i] = str[str_i];
  print_combinations_aux(str, str_sz, str_i + 1, buff, buff_i + 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_combinations_aux>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rcx,%rbp
  mov    %r8,%rbx
  cmp    %rsi,%rdx
  je     L16
  mov    %rdi,%r14
  mov    %rsi,%r12
  mov    %rdx,%r13
  lea    0x1(%rdx),%r15
  mov    %r15,%rdx
  call   <print_combinations_aux>
  movzbl (%r14,%r13,1),%eax
  mov    %al,0x0(%rbp,%rbx,1)
  lea    0x1(%rbx),%r8
  mov    %rbp,%rcx
  mov    %r15,%rdx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <print_combinations_aux>
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  movb   $0x0,(%rcx,%r8,1)
  test   %r8,%r8
  je     L27
  mov    %rcx,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L27
```

tool_calls: name: read_data
arguments: data_label: D2
datatype: string

tool: D2: %s


assistant: ```c
void print_combinations_aux(const char *str, size_t str_sz, size_t str_i, char *buff, size_t buff_i) {
  if (str_i == str_sz) {
    buff[buff_i] = '\0';
    if (buff_i != 0) {
      printf("%s\n", buff);
    }
    return;
  }
  print_combinations_aux(str, str_sz, str_i + 1, buff, buff_i);
  buff[buff_i] = str[str_i];
  print_combinations_aux(str, str_sz, str_i + 1, buff, buff_i + 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_combinations_aux>:
  endbr64
  push   %r15
  mov    %r8,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,0x8(%rsp)
  cmp    %rsi,%rdx
  je     L11
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %r8,%rbp
  mov    %rdx,%rbx
L18:
  add    $0x1,%rbx
  mov    %rbp,%r8
  mov    %r12,%rcx
  mov    %r14,%rsi
  mov    %rbx,%rdx
  mov    %r13,%rdi
  call   <print_combinations_aux>
  movzbl -0x1(%r13,%rbx,1),%edx
  mov    %dl,(%r12,%rbp,1)
  add    $0x1,%rbp
  cmp    %r14,%rbx
  jne    L18
  add    %r15,%rbx
  sub    0x8(%rsp),%rbx
  mov    %rbx,%r15
L11:
  movb   $0x0,(%r12,%r15,1)
  test   %r15,%r15
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L7:
  add    $0x18,%rsp
  mov    %r12,%rsi
  lea    D6(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: %s


assistant: ```c
void print_combinations_aux(const char *str, size_t str_sz, size_t str_i, char *buff, size_t buff_i) {
  if (str_i == str_sz) {
    buff[buff_i] = '\0';
    if (buff_i != 0) {
      printf("%s\n", buff);
    }
    return;
  }
  print_combinations_aux(str, str_sz, str_i + 1, buff, buff_i);
  buff[buff_i] = str[str_i];
  print_combinations_aux(str, str_sz, str_i + 1, buff, buff_i + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rrotate1_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  jmp    L15
L2:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L25
L22:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  shl    $0x2,%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L22
  addl   $0x1,-0x10(%rbp)
L15:
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rrotate1_imatrix(int **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  int t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[i][j];
      S[i][j] = S[n - j][i];
      S[n - j][i] = t;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rrotate1_imatrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rax
  mov    %r8,%rbx
  lea    (%rsi,%rdx,1),%ecx
  movslq %esi,%r8
  cmp    %r8,%rdx
  jl     L24
  mov    %r8,%rsi
  lea    (%rdi,%r8,8),%r10
  shl    $0x2,%rsi
  lea    0x4(,%rdx,4),%rbp
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%r13
  movslq %ecx,%rcx
  sub    %rdx,%rcx
  lea    (%rdi,%rcx,8),%r12
  lea    0x4(,%rbx,4),%r11
  mov    %rdx,%r8
L35:
  cmp    %r8,%rbx
  jl     L19
  mov    %r12,%rdx
  mov    %r13,%rax
L15:
  mov    %rax,%rcx
  add    (%r10),%rcx
  mov    (%rcx),%edi
  mov    (%rdx),%r9
  mov    (%r9,%rsi,1),%r9d
  mov    %r9d,(%rcx)
  mov    (%rdx),%rcx
  mov    %edi,(%rcx,%rsi,1)
  add    $0x4,%rax
  sub    $0x8,%rdx
  cmp    %r11,%rax
  jne    L15
L19:
  add    $0x8,%r10
  add    $0x4,%rsi
  cmp    %rbp,%rsi
  jne    L35
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rrotate1_imatrix(int **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  int t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[i][j];
      S[i][j] = S[n - j][i];
      S[n - j][i] = t;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rrotate1_imatrix>:
  endbr64
  lea    (%rsi,%rdx,1),%eax
  movslq %esi,%rsi
  cmp    %rsi,%rdx
  jl     L17
  push   %r14
  cltq
  movslq %ecx,%r14
  mov    %rdi,%r11
  push   %r13
  sub    %r14,%rax
  mov    %r8,%r13
  lea    0x0(,%rsi,4),%r9
  push   %r12
  lea    0x4(,%rdx,4),%r8
  lea    0x0(,%r14,4),%r12
  push   %rbp
  lea    (%rdi,%rax,8),%rbp
  push   %rbx
  lea    0x4(,%r13,4),%rbx
  nopl   (%rax)
L0:
  cmp    %r14,%r13
  jl     L13
  mov    (%r11,%r9,2),%r10
  mov    %rbp,%rdx
  lea    (%r10,%r12,1),%rax
  add    %rbx,%r10
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rdx),%rcx
  mov    (%rax),%esi
  add    $0x4,%rax
  sub    $0x8,%rdx
  add    %r9,%rcx
  mov    (%rcx),%edi
  mov    %edi,-0x4(%rax)
  mov    %esi,(%rcx)
  cmp    %rax,%r10
  jne    L2
L13:
  add    $0x4,%r9
  cmp    %r8,%r9
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  ret
```

assistant: ```c
void rrotate1_imatrix(int **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  int t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[i][j];
      S[i][j] = S[n - j][i];
      S[n - j][i] = t;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rrotate1_imatrix>:
  endbr64
  mov    %rdi,%r10
  lea    (%rsi,%rdx,1),%edi
  movslq %esi,%rsi
  cmp    %rsi,%rdx
  jl     L27
  movslq %ecx,%rax
  cmp    %rax,%r8
  jl     L27
  movslq %edi,%rdi
  push   %r12
  lea    0x0(,%rsi,4),%r9
  lea    0x4(,%rdx,4),%r12
  sub    %rax,%rdi
  push   %rbp
  lea    0x4(,%r8,4),%r11
  lea    0x0(,%rax,4),%rbp
  push   %rbx
  lea    (%r10,%rdi,8),%rbx
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%r10,%r9,2),%r8
  mov    %rbx,%rdx
  lea    (%r8,%rbp,1),%rax
  add    %r11,%r8
  xchg   %ax,%ax
L34:
  mov    (%rdx),%rcx
  mov    (%rax),%esi
  add    $0x4,%rax
  sub    $0x8,%rdx
  add    %r9,%rcx
  mov    (%rcx),%edi
  mov    %edi,-0x4(%rax)
  mov    %esi,(%rcx)
  cmp    %r8,%rax
  jne    L34
  add    $0x4,%r9
  cmp    %r9,%r12
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  ret
```

assistant: ```c
void rrotate1_imatrix(int **S, long nrl, long nrh, long ncl, long nch) {
  int i, j, n = nrl + nrh;
  int t;
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      t = S[i][j];
      S[i][j] = S[n - j][i];
      S[n - j][i] = t;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squeeze>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x1c(%rbp)
  je     L22
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L22:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void squeeze(char s[], int c) {
  int i, j;
  for (i = j = 0; s[i] != '\0'; i++)
    if (s[i] != c)
      s[j++] = s[i];
  s[j] = '\0';
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<squeeze>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L21
  lea    0x1(%rdi),%rdx
  mov    $0x0,%ecx
  jmp    L33
L41:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L29
L33:
  movsbl %al,%r8d
  cmp    %esi,%r8d
  je     L41
  movslq %ecx,%r8
  mov    %al,(%rdi,%r8,1)
  lea    0x1(%rcx),%ecx
  jmp    L41
L21:
  mov    $0x0,%ecx
L29:
  movslq %ecx,%rcx
  movb   $0x0,(%rdi,%rcx,1)
  ret
```

assistant: ```c
void squeeze(char s[], int c) {
  int i, j;
  for (i = j = 0; s[i] != '\0'; i++)
    if (s[i] != c)
      s[j++] = s[i];
  s[j] = '\0';
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<squeeze>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  lea    0x1(%rdi),%rdx
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L26:
  movsbl %al,%r8d
  cmp    %esi,%r8d
  je     L27
  movslq %ecx,%r8
  add    $0x1,%ecx
  mov    %al,(%rdi,%r8,1)
L27:
  movzbl (%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L26
  movslq %ecx,%rcx
  add    %rcx,%rdi
L3:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void squeeze(char s[], int c) {
  int i, j;
  for (i = j = 0; s[i] != '\0'; i++)
    if (s[i] != c)
      s[j++] = s[i];
  s[j] = '\0';
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<squeeze>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
  lea    0x1(%rdi),%rcx
  xor    %edx,%edx
L34:
  movsbl %al,%r8d
  cmp    %esi,%r8d
  je     L38
L29:
  add    $0x1,%rcx
  mov    %al,(%rdi,%rdx,1)
  lea    0x1(%rdx),%r8d
  movzbl -0x1(%rcx),%eax
  test   %al,%al
  je     L4
  movslq %r8d,%rdx
  movsbl %al,%r8d
  cmp    %esi,%r8d
  jne    L29
L38:
  movzbl (%rcx),%eax
  add    $0x1,%rcx
  test   %al,%al
  jne    L34
  mov    %edx,%r8d
L4:
  movslq %r8d,%r8
  add    %r8,%rdi
L3:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void squeeze(char s[], int c) {
  int i, j;
  for (i = j = 0; s[i] != '\0'; i++)
    if (s[i] != c)
      s[j++] = s[i];
  s[j] = '\0';
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<putlong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <putc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void putlong(FILE *file, int val) {
  putc((val >> 24) & 0xff, file);
  putc((val >> 16) & 0xff, file);
  putc((val >> 8) & 0xff, file);
  putc(val & 0xff, file);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<putlong>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  shr    $0x18,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  mov    %ebx,%edi
  sar    $0x10,%edi
  movzbl %dil,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  movzbl %bl,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void putlong(FILE *file, int val) {
  putc((val >> 24) & 0xff, file);
  putc((val >> 16) & 0xff, file);
  putc((val >> 8) & 0xff, file);
  putc(val & 0xff, file);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<putlong>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  shr    $0x18,%edi
  mov    %esi,%ebx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <putc@plt>
  mov    %ebx,%edi
  mov    %rbp,%rsi
  sar    $0x10,%edi
  movzbl %dil,%edi
  call   <putc@plt>
  movzbl %bh,%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  movzbl %bl,%edi
  mov    %rbp,%rsi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putc@plt>
```

assistant: ```c
void putlong(FILE *file, int val) {
  putc((val >> 24) & 0xff, file);
  putc((val >> 16) & 0xff, file);
  putc((val >> 8) & 0xff, file);
  putc(val & 0xff, file);
}
```