user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<step5_lng>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x50(%rsp),%rax
  mov    0x38(%rsp),%rbx
  mov    0x48(%rsp),%r10
  mov    %r8,-0x18(%rsp)
  mov    0x40(%rsp),%r8
  mov    %rax,-0x10(%rsp)
  mov    D6(%rip),%rax
  mov    %rdi,-0x30(%rsp)
  mov    %rdx,-0x28(%rsp)
  mov    (%rax),%rax
  mov    %rcx,-0x20(%rsp)
  test   %r8,%r8
  jle    L87
  mov    %rsi,%r12
  lea    (%r9,%r10,4),%r14
  mov    %rsi,%r13
  xor    %r11d,%r11d
  lea    0x0(,%r8,8),%rdi
  jmp    L8
  nopl   (%rax)
L204:
  lea    0x1(%r11),%rdx
  add    $0x8,%r13
  cmp    %rdx,%r8
  je     L169
L21:
  mov    %rdx,%r11
L8:
  mov    (%rbx,%r11,4),%r15d
  test   %r15d,%r15d
  jne    L204
  test   %r10,%r10
  jle    L204
  mov    %r13,%rcx
  mov    %r9,%rdx
  nopl   0x0(%rax)
L194:
  mov    (%rdx),%ebp
  test   %ebp,%ebp
  jne    L38
  mov    (%rcx),%rbp
  cmp    %rbp,%rax
  cmovg  %rbp,%rax
L38:
  add    $0x4,%rdx
  add    %rdi,%rcx
  cmp    %r14,%rdx
  jne    L194
  lea    0x1(%r11),%rdx
  add    $0x8,%r13
  cmp    %rdx,%r8
  jne    L21
L169:
  xor    %ebp,%ebp
  jmp    L11
  nopl   (%rax)
L80:
  lea    0x1(%rbp),%rdx
  add    $0x8,%r12
  cmp    %rbp,%r11
  je     L87
L89:
  mov    %rdx,%rbp
L11:
  mov    (%rbx,%rbp,4),%ecx
  test   %ecx,%ecx
  je     L80
  test   %r10,%r10
  jle    L80
  mov    %r12,%rdx
  xor    %ecx,%ecx
  nopl   0x0(%rax)
L50:
  add    $0x1,%rcx
  add    %rax,(%rdx)
  add    %rdi,%rdx
  cmp    %rcx,%r10
  jne    L50
  lea    0x1(%rbp),%rdx
  add    $0x8,%r12
  cmp    %rbp,%r11
  jne    L89
L87:
  test   %r10,%r10
  jle    L115
  mov    %r8,%r14
  mov    %r8,%r15
  movq   %rax,%xmm1
  mov    %r9,%rcx
  shr    %r14
  lea    0x0(,%r8,8),%r13
  mov    %rsi,%r11
  xor    %edi,%edi
  lea    (%r9,%r10,4),%r12
  shl    $0x4,%r14
  punpcklqdq %xmm1,%xmm1
  and    $0xfffffffffffffffe,%r15
  jmp    L65
L122:
  add    $0x4,%rcx
  add    %r8,%rdi
  add    %r13,%r11
  cmp    %r12,%rcx
  je     L115
  nopl   0x0(%rax)
L65:
  mov    (%rcx),%edx
  test   %edx,%edx
  jne    L122
  test   %r8,%r8
  jle    L122
  cmp    $0x1,%r8
  je     L74
  lea    (%r14,%r11,1),%rbp
  mov    %r11,%rdx
  nopl   0x0(%rax,%rax,1)
L101:
  movdqu (%rdx),%xmm0
  add    $0x10,%rdx
  psubq  %xmm1,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rdx,%rbp
  jne    L101
  mov    %r15,%rdx
  cmp    %r8,%r15
  je     L122
L4:
  add    %rdi,%rdx
  add    $0x4,%rcx
  add    %r8,%rdi
  add    %r13,%r11
  sub    %rax,(%rsi,%rdx,8)
  cmp    %r12,%rcx
  jne    L65
L115:
  mov    -0x10(%rsp),%rax
  mov    -0x20(%rsp),%rcx
  mov    %r8,0x40(%rsp)
  mov    -0x28(%rsp),%rdx
  mov    -0x18(%rsp),%r8
  mov    %r10,0x48(%rsp)
  mov    -0x30(%rsp),%rdi
  mov    %rax,0x50(%rsp)
  mov    %rbx,0x38(%rsp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <step3_lng@plt>
L74:
  xor    %edx,%edx
  jmp    L4
```

assistant: ```c
void step5_lng(long *assignment, long *distMatrix, bool *starMatrix, bool *newStarMatrix, bool *primeMatrix, bool *coveredColumns, bool *coveredRows, long nOfRows, long nOfColumns, long minDim) {
  long h, value;
  long row, col;
  h = LONG_MAX;
  for (row = 0; row < nOfRows; row++)
    if (!coveredRows[row])
      for (col = 0; col < nOfColumns; col++)
        if (!coveredColumns[col]) {
          value = distMatrix[row + nOfRows * col];
          if (value < h)
            h = value;
        }
  for (row = 0; row < nOfRows; row++)
    if (coveredRows[row])
      for (col = 0; col < nOfColumns; col++)
        distMatrix[row + nOfRows * col] += h;
  for (col = 0; col < nOfColumns; col++)
    if (!coveredColumns[col])
      for (row = 0; row < nOfRows; row++)
        distMatrix[row + nOfRows * col] -= h;
  step3_lng(assignment, distMatrix, starMatrix, newStarMatrix, primeMatrix, coveredColumns, coveredRows, nOfRows, nOfColumns, minDim);
}
```