ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jsr_strcat>:
  endbr64
  sub    $0x8,%rsp
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0xf8,%esi
  xor    %edi,%edi
  call   <ldx@plt>
  xor    %eax,%eax
  call   <jsr_inc16@plt>
  xor    %eax,%eax
  call   <jsr_inc_pointer@plt>
L15:
  mov    $0xf8,%esi
  mov    $0x2,%edi
  call   <lda@plt>
  mov    $0xfc,%esi
  mov    $0x2,%edi
  call   <sta@plt>
  xor    %eax,%eax
  call   <beq@plt>
  test   %rax,%rax
  je     L4
  add    $0x8,%rsp
  ret
```

assistant: ```c
void jsr_strcat() {
strcat_loop:
  lda(2, 0xf8);
  sta(2, 0xfc);
  if (beq())
    goto strcat_done;
  ldx(0, 0xf8);
  jsr_inc16();
  jsr_inc_pointer();
  goto strcat_loop;
strcat_done:;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jsr_strcat>:
  endbr64
  sub    $0x8,%rsp
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0xf8,%esi
  xor    %edi,%edi
  call   <ldx@plt>
  xor    %eax,%eax
  call   <jsr_inc16@plt>
  xor    %eax,%eax
  call   <jsr_inc_pointer@plt>
L6:
  mov    $0xf8,%esi
  mov    $0x2,%edi
  call   <lda@plt>
  mov    $0xfc,%esi
  mov    $0x2,%edi
  call   <sta@plt>
  xor    %eax,%eax
  call   <beq@plt>
  test   %rax,%rax
  je     L14
  add    $0x8,%rsp
  ret
```

assistant: ```c
void jsr_strcat() {
strcat_loop:
  lda(2, 0xf8);
  sta(2, 0xfc);
  if (beq())
    goto strcat_done;
  ldx(0, 0xf8);
  jsr_inc16();
  jsr_inc_pointer();
  goto strcat_loop;
strcat_done:;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hanoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %ecx,%eax
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L12
  cmpl   $0x1,-0x4(%rbp)
  jne    L1
  movsbl -0x10(%rbp),%edx
  movsbl -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <print_hanoi@plt>
  jmp    L36
L1:
  movsbl -0xc(%rbp),%ecx
  movsbl -0x10(%rbp),%edx
  movsbl -0x8(%rbp),%eax
  mov    -0x4(%rbp),%esi
  lea    -0x1(%rsi),%edi
  mov    %eax,%esi
  call   <hanoi>
  movsbl -0x10(%rbp),%edx
  movsbl -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <print_hanoi@plt>
  movsbl -0x10(%rbp),%ecx
  movsbl -0x8(%rbp),%edx
  movsbl -0xc(%rbp),%eax
  mov    -0x4(%rbp),%esi
  lea    -0x1(%rsi),%edi
  mov    %eax,%esi
  call   <hanoi>
  jmp    L36
L12:
  nop
L36:
  leave
  ret
```

assistant: ```c
void hanoi(int ceil, char a, char b, char c) {
  if (0 >= ceil)
    return;
  if (1 == ceil)
    print_hanoi(ceil, a, c);
  else {
    hanoi(ceil - 1, a, c, b);
    print_hanoi(ceil, a, c);
    hanoi(ceil - 1, b, a, c);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hanoi>:
  endbr64
  test   %edi,%edi
  jle    L0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  cmp    $0x1,%edi
  je     L15
  movsbl %dl,%r13d
  movsbl %cl,%ebp
  movsbl %sil,%ebx
  lea    -0x1(%rdi),%r14d
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <hanoi>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  call   <print_hanoi@plt>
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <hanoi>
L23:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  movsbl %cl,%edx
  movsbl %sil,%esi
  mov    $0x1,%edi
  call   <print_hanoi@plt>
  jmp    L23
L0:
  ret
```

assistant: ```c
void hanoi(int ceil, char a, char b, char c) {
  if (0 >= ceil)
    return;
  if (1 == ceil)
    print_hanoi(ceil, a, c);
  else {
    hanoi(ceil - 1, a, c, b);
    print_hanoi(ceil, a, c);
    hanoi(ceil - 1, b, a, c);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<hanoi>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %r15
  push   %r14
  push   %r13
  movsbl %cl,%r13d
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %edi,%ebp
  cmp    $0x1,%edi
  je     L4
  movsbl %dl,%r14d
  lea    -0x1(%rdi),%r15d
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %r14d,%ecx
  mov    %r15d,%edi
  call   <hanoi>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <print_hanoi@plt>
  pop    %rbp
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %r14d,%esi
  pop    %r12
  mov    %r15d,%edi
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1120 <hanoi>
  nopl   (%rax)
L4:
  pop    %rbp
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    $0x1,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <print_hanoi@plt>
  nopl   0x0(%rax)
L3:
  ret
```

assistant: ```c
void hanoi(int ceil, char a, char b, char c) {
  if (0 >= ceil)
    return;
  if (1 == ceil)
    print_hanoi(ceil, a, c);
  else {
    hanoi(ceil - 1, a, c, b);
    print_hanoi(ceil, a, c);
    hanoi(ceil - 1, b, a, c);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<alloc_re>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <alloc@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L6
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <byte_copy@plt>
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <alloc_free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L6:
  leave
  ret
```

assistant: ```c
int alloc_re(x, m, n)
char **x;
unsigned int m;
unsigned int n;
{
  char *y;
  y = alloc(n);
  if (!y)
    return 0;
  byte_copy(y, m, *x);
  alloc_free(*x);
  *x = y;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<alloc_re>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%edi
  mov    $0x0,%eax
  call   <alloc@plt>
  test   %eax,%eax
  jne    L8
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  movslq %eax,%rbx
  mov    0x0(%rbp),%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <byte_copy@plt>
  mov    0x0(%rbp),%rdi
  mov    $0x0,%eax
  call   <alloc_free@plt>
  mov    %rbx,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L14
```

assistant: ```c
int alloc_re(x, m, n)
char **x;
unsigned int m;
unsigned int n;
{
  char *y;
  y = alloc(n);
  if (!y)
    return 0;
  byte_copy(y, m, *x);
  alloc_free(*x);
  *x = y;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_re>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  call   <alloc@plt>
  test   %eax,%eax
  je     L8
  movslq %eax,%rbx
  mov    0x0(%rbp),%rdx
  mov    %r12d,%esi
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <byte_copy@plt>
  mov    0x0(%rbp),%rdi
  xor    %eax,%eax
  call   <alloc_free@plt>
  mov    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int alloc_re(x, m, n)
char **x;
unsigned int m;
unsigned int n;
{
  char *y;
  y = alloc(n);
  if (!y)
    return 0;
  byte_copy(y, m, *x);
  alloc_free(*x);
  *x = y;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<alloc_re>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %edx,%edi
  push   %rbx
  call   <alloc@plt>
  test   %eax,%eax
  je     L9
  movslq %eax,%rbx
  mov    0x0(%rbp),%rdx
  mov    %r12d,%esi
  xor    %eax,%eax
  mov    %rbx,%rdi
  call   <byte_copy@plt>
  mov    0x0(%rbp),%rdi
  xor    %eax,%eax
  call   <alloc_free@plt>
  mov    %rbx,0x0(%rbp)
  mov    $0x1,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int alloc_re(x, m, n)
char **x;
unsigned int m;
unsigned int n;
{
  char *y;
  y = alloc(n);
  if (!y)
    return 0;
  byte_copy(y, m, *x);
  alloc_free(*x);
  *x = y;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<write_new_certificate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L13
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <i2d_X509_bio@plt>
  jmp    L16
L13:
  cmpl   $0x0,-0x18(%rbp)
  jne    L19
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <X509_print@plt>
L19:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <PEM_write_bio_X509@plt>
L16:
  leave
  ret
```

assistant: ```c
void write_new_certificate(BIO *bp, X509 *x, int output_der, int notext) {
  if (output_der) {
    (void)i2d_X509_bio(bp, x);
    return;
  }
  if (!notext)
    X509_print(bp, x);
  PEM_write_bio_X509(bp, x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_new_certificate>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  test   %edx,%edx
  jne    L27
  test   %ecx,%ecx
  je     L20
L3:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <PEM_write_bio_X509@plt>
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  call   <i2d_X509_bio@plt>
  jmp    L8
L20:
  call   <X509_print@plt>
  jmp    L3
```

assistant: ```c
void write_new_certificate(BIO *bp, X509 *x, int output_der, int notext) {
  if (output_der) {
    (void)i2d_X509_bio(bp, x);
    return;
  }
  if (!notext)
    X509_print(bp, x);
  PEM_write_bio_X509(bp, x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_new_certificate>:
  endbr64
  test   %edx,%edx
  jne    L11
  test   %ecx,%ecx
  je     L6
  jmp    1090 <PEM_write_bio_X509@plt>
  nopl   0x0(%rax)
L6:
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdi,(%rsp)
  call   <X509_print@plt>
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  add    $0x18,%rsp
  jmp    1090 <PEM_write_bio_X509@plt>
  nopl   0x0(%rax)
L11:
  jmp    1080 <i2d_X509_bio@plt>
```

assistant: ```c
void write_new_certificate(BIO *bp, X509 *x, int output_der, int notext) {
  if (output_der) {
    (void)i2d_X509_bio(bp, x);
    return;
  }
  if (!notext)
    X509_print(bp, x);
  PEM_write_bio_X509(bp, x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_new_certificate>:
  endbr64
  test   %edx,%edx
  jne    L8
  test   %ecx,%ecx
  je     L14
  jmp    1090 <PEM_write_bio_X509@plt>
  nopl   0x0(%rax)
L14:
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %rdi,(%rsp)
  call   <X509_print@plt>
  mov    0x8(%rsp),%rsi
  mov    (%rsp),%rdi
  add    $0x18,%rsp
  jmp    1090 <PEM_write_bio_X509@plt>
  nopl   0x0(%rax)
L8:
  jmp    1080 <i2d_X509_bio@plt>
```

assistant: ```c
void write_new_certificate(BIO *bp, X509 *x, int output_der, int notext) {
  if (output_der) {
    (void)i2d_X509_bio(bp, x);
    return;
  }
  if (!notext)
    X509_print(bp, x);
  PEM_write_bio_X509(bp, x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  setg   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sort_int(const void *a, const void *b) {
  long *a1, *b1;
  a1 = (long *)a;
  b1 = (long *)b;
  return (*a1 > *b1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sort_int>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int sort_int(const void *a, const void *b) {
  long *a1, *b1;
  a1 = (long *)a;
  b1 = (long *)b;
  return (*a1 > *b1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort_int>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int sort_int(const void *a, const void *b) {
  long *a1, *b1;
  a1 = (long *)a;
  b1 = (long *)b;
  return (*a1 > *b1);
}
```
user: What is the c source code of the assembly code below:

```asm
<sort_int>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  setg   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int sort_int(const void *a, const void *b) {
  long *a1, *b1;
  a1 = (long *)a;
  b1 = (long *)b;
  return (*a1 > *b1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  nop
  leave
  ret
```

assistant: ```c
void swap(void *a, void *b, void *buf, size_t element_size) {
  memcpy(buf, b, element_size);
  memcpy(b, a, element_size);
  memcpy(a, buf, element_size);
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbx
  mov    %rcx,%rdx
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void swap(void *a, void *b, void *buf, size_t element_size) {
  memcpy(buf, b, element_size);
  memcpy(b, a, element_size);
  memcpy(a, buf, element_size);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %rcx,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void swap(void *a, void *b, void *buf, size_t element_size) {
  memcpy(buf, b, element_size);
  memcpy(b, a, element_size);
  memcpy(a, buf, element_size);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  mov    %rcx,%rdx
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  sub    $0x8,%rsp
  call   <memcpy@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <memcpy@plt>
```

assistant: ```c
void swap(void *a, void *b, void *buf, size_t element_size) {
  memcpy(buf, b, element_size);
  memcpy(b, a, element_size);
  memcpy(a, buf, element_size);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x30(%rbp)
  movl   $0xa,-0x2c(%rbp)
  movl   $0x6,-0x28(%rbp)
  movl   $0x19,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x59,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <asctime@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int main() {
  struct tm t;
  t.tm_sec = 10;
  t.tm_min = 10;
  t.tm_hour = 6;
  t.tm_mday = 25;
  t.tm_mon = 2;
  t.tm_year = 89;
  t.tm_wday = 6;
  puts(asctime(&t));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0xa,(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x6,0x8(%rsp)
  movl   $0x19,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x59,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  mov    %rsp,%rdi
  call   <asctime@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct tm t;
  t.tm_sec = 10;
  t.tm_min = 10;
  t.tm_hour = 6;
  t.tm_mday = 25;
  t.tm_mon = 2;
  t.tm_year = 89;
  t.tm_wday = 6;
  puts(asctime(&t));
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xa0000000a,%rax
  mov    %rsp,%rdi
  movl   $0x6,0x18(%rsp)
  mov    %rax,(%rsp)
  movabs $0x1900000006,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x5900000002,%rax
  mov    %rax,0x10(%rsp)
  call   <asctime@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  struct tm t;
  t.tm_sec = 10;
  t.tm_min = 10;
  t.tm_hour = 6;
  t.tm_mday = 25;
  t.tm_mon = 2;
  t.tm_year = 89;
  t.tm_wday = 6;
  puts(asctime(&t));
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movdqa D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    %rsp,%rdi
  movl   $0x6,0x18(%rsp)
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <asctime@plt>
  mov    %eax,%edi
  call   <puts@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D8
type_infered: byte[16]
name: parse_data
arguments: label: D11
type_infered: byte[8]

tool: {"D8": [0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x19,0x00,0x00,0x00]}

tool: {"D11": [0x02,0x00,0x00,0x00,0x59,0x00,0x00,0x00]}

assistant: ```c
int main() {
  struct tm t;
  t.tm_sec = 10;
  t.tm_min = 10;
  t.tm_hour = 6;
  t.tm_mday = 25;
  t.tm_mon = 2;
  t.tm_year = 89;
  t.tm_wday = 6;
  puts(asctime(&t));
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_fill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L6:
  mov    -0x18(%rbp),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L15
  mov    D5(%rip),%rax
  mov    (%rax),%rdx
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L29
  mov    -0x8(%rbp),%eax
  jmp    L9
L29:
  movl   $0x0,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L6
  mov    -0x18(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int write_fill(int fd, unsigned char *buf, int len) {
  int i;
  unsigned int done = 0;
  do {
    if ((i = write(fd, (char *)(buf + done), len - done)) < 0) {
      if (errno != EINTR)
        return (i);
      i = 0;
    }
    done += i;
  } while (done < len);
  return (len);
}
```
user: What is the c source code of the assembly code below?

```asm
<write_fill>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%ebx
  mov    %edx,%r14d
  jmp    L41
L28:
  add    %eax,%ebx
  cmp    %ebx,%r14d
  jbe    L3
L41:
  mov    %ebp,%edx
  sub    %ebx,%edx
  mov    %ebx,%esi
  add    %r12,%rsi
  mov    %r13d,%edi
  call   <write@plt>
  test   %eax,%eax
  jns    L28
  mov    D6(%rip),%rcx
  mov    D10(%rip),%rdx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rcx)
  jne    L11
  mov    $0x0,%eax
  jmp    L28
L11:
  mov    %eax,%ebp
L3:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int write_fill(int fd, unsigned char *buf, int len) {
  int i;
  unsigned int done = 0;
  do {
    if ((i = write(fd, (char *)(buf + done), len - done)) < 0) {
      if (errno != EINTR)
        return (i);
      i = 0;
    }
    done += i;
  } while (done < len);
  return (len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_fill>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L23:
  add    %eax,%ebx
L4:
  cmp    %ebx,%r13d
  jbe    L9
L11:
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  sub    %ebx,%edx
  add    %rbp,%rsi
  call   <write@plt>
  test   %eax,%eax
  jns    L23
  mov    D8(%rip),%rdx
  mov    D19(%rip),%rcx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rcx)
  je     L4
  mov    %eax,%r13d
L9:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_fill(int fd, unsigned char *buf, int len) {
  int i;
  unsigned int done = 0;
  do {
    if ((i = write(fd, (char *)(buf + done), len - done)) < 0) {
      if (errno != EINTR)
        return (i);
      i = 0;
    }
    done += i;
  } while (done < len);
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<write_fill>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L3:
  add    %eax,%ebx
L6:
  cmp    %ebx,%r13d
  jbe    L24
L21:
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12d,%edi
  sub    %ebx,%edx
  add    %rbp,%rsi
  call   <write@plt>
  test   %eax,%eax
  jns    L3
  mov    D6(%rip),%rdx
  mov    D17(%rip),%rcx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rcx)
  je     L6
  mov    %eax,%r13d
L24:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int write_fill(int fd, unsigned char *buf, int len) {
  int i;
  unsigned int done = 0;
  do {
    if ((i = write(fd, (char *)(buf + done), len - done)) < 0) {
      if (errno != EINTR)
        return (i);
      i = 0;
    }
    done += i;
  } while (done < len);
  return (len);
}
```