ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<std_char_put>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L31
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0xd,%edx
  mov    $0x1,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  jmp    L10
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x7,%edx
  mov    $0x1,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  jmp    L10
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rcx
  mov    $0xb,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L10:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D38
type_infered: string
name: extract_symbolic_data
arguments: tag: D22
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D38: <char (NULL)>

tool: D22: <char '

tool: D2: '>

tool: D3: <char '\0'>

assistant: ```c
void std_char_put(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (!self)
    fputs("<"
          "char"
          " "
          "(NULL)"
          ">",
          stream);
  else {
    if (*(const char *)self) {
      fputs("<"
            "char"
            " "
            "'",
            stream);
      fputc(*(const char *)self, stream);
      fputs("'"
            ">",
            stream);
    } else
      fputs("<"
            "char"
            " "
            "'\\0'"
            ">",
            stream);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<std_char_put>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  test   %rdi,%rdi
  je     L30
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  je     L14
  mov    %rdx,%rcx
  mov    $0x7,%edx
  mov    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <fwrite@plt>
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  mov    %rbp,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <fwrite@plt>
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    %rdx,%rcx
  mov    $0xd,%edx
  mov    $0x1,%esi
  lea    D15(%rip),%rdi
  call   <fwrite@plt>
  jmp    L17
L14:
  mov    %rdx,%rcx
  mov    $0xb,%edx
  mov    $0x1,%esi
  lea    D36(%rip),%rdi
  call   <fwrite@plt>
  jmp    L17
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_infered: string
name: disassemble_data
arguments: data_label: D11
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D36
type_infered: string

tool: D3: <char '

tool: D11: '>

tool: D15: <char (NULL)>

tool: D36: <char '\0'>

assistant: ```c
void std_char_put(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (!self)
    fputs("<"
          "char"
          " "
          "(NULL)"
          ">",
          stream);
  else {
    if (*(const char *)self) {
      fputs("<"
            "char"
            " "
            "'",
            stream);
      fputc(*(const char *)self, stream);
      fputs("'"
            ">",
            stream);
    } else
      fputs("<"
            "char"
            " "
            "'\\0'"
            ">",
            stream);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<std_char_put>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  mov    %rdx,%rcx
  je     L4
  mov    $0x7,%edx
  mov    $0x1,%esi
  lea    D29(%rip),%rdi
  call   <fwrite@plt>
  movsbl (%rbx),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    $0x2,%edx
  pop    %rbx
  mov    $0x1,%esi
  lea    D21(%rip),%rdi
  pop    %r12
  jmp    1070 <fwrite@plt>
  nop
L4:
  add    $0x8,%rsp
  mov    $0xb,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D11(%rip),%rdi
  pop    %r12
  jmp    1070 <fwrite@plt>
  nopl   (%rax)
L17:
  add    $0x8,%rsp
  mov    %rdx,%rcx
  mov    $0x1,%esi
  mov    $0xd,%edx
  pop    %rbx
  lea    D38(%rip),%rdi
  pop    %r12
  jmp    1070 <fwrite@plt>
```

tool_calls: name: disassemble_data
arguments: label: D29
type_infered: string
name: disassemble_data
arguments: label: D21
type_infered: string
name: disassemble_data
arguments: label: D11
type_infered: string
name: disassemble_data
arguments: label: D38
type_infered: string

tool: D29: <char '

tool: D21: '>

tool: D11: <char '\0'>

tool: D38: <char (NULL)>

assistant: ```c
void std_char_put(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (!self)
    fputs("<"
          "char"
          " "
          "(NULL)"
          ">",
          stream);
  else {
    if (*(const char *)self) {
      fputs("<"
            "char"
            " "
            "'",
            stream);
      fputc(*(const char *)self, stream);
      fputs("'"
            ">",
            stream);
    } else
      fputs("<"
            "char"
            " "
            "'\\0'"
            ">",
            stream);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<std_char_put>:
  endbr64
  push   %r12
  mov    %rdx,%r12
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L17
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rbx
  mov    %rdx,%rcx
  je     L3
  mov    $0x7,%edx
  mov    $0x1,%esi
  lea    D32(%rip),%rdi
  call   <fwrite@plt>
  movsbl (%rbx),%edi
  mov    %r12,%rsi
  call   <fputc@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    $0x2,%edx
  pop    %rbx
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  pop    %r12
  jmp    1070 <fwrite@plt>
  nop
L3:
  add    $0x8,%rsp
  mov    $0xb,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D19(%rip),%rdi
  pop    %r12
  jmp    1070 <fwrite@plt>
  nopl   (%rax)
L17:
  add    $0x8,%rsp
  mov    %rdx,%rcx
  mov    $0x1,%esi
  mov    $0xd,%edx
  pop    %rbx
  lea    D39(%rip),%rdi
  pop    %r12
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D32
type: string
name: retrieve_data
arguments: data_label: D12
type: string
name: retrieve_data
arguments: data_label: D19
type: string
name: retrieve_data
arguments: data_label: D39
type: string

tool: D32: <char '

tool: D12: '>

tool: D19: <char '\0'>

tool: D39: <char (NULL)>

assistant: ```c
void std_char_put(const void *restrict self, const char *restrict format, FILE *restrict stream) {
  (void)format;
  if (!self)
    fputs("<"
          "char"
          " "
          "(NULL)"
          ">",
          stream);
  else {
    if (*(const char *)self) {
      fputs("<"
            "char"
            " "
            "'",
            stream);
      fputc(*(const char *)self, stream);
      fputs("'"
            ">",
            stream);
    } else
      fputs("<"
            "char"
            " "
            "'\\0'"
            ">",
            stream);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L14
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  mov    $0x8,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string

tool: D0: The size of ar is %u bytes.


assistant: ```c
int sum(int *ar, int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %u bytes.\n", sizeof ar);
  return total;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sum>:
  endbr64
  push   %rbx
  test   %esi,%esi
  jle    L12
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  mov    $0x0,%ebx
L11:
  add    (%rax),%ebx
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L11
L28:
  mov    $0x8,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L12:
  mov    $0x0,%ebx
  jmp    L28
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string

tool: D2: The size of ar is %u bytes.


assistant: ```c
int sum(int *ar, int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %u bytes.\n", sizeof ar);
  return total;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sum>:
  endbr64
  push   %r12
  test   %esi,%esi
  jle    L20
  lea    -0x1(%rsi),%eax
  xor    %r12d,%r12d
  lea    0x4(%rdi,%rax,4),%rax
  nopl   (%rax)
L19:
  add    (%rdi),%r12d
  add    $0x4,%rdi
  cmp    %rax,%rdi
  jne    L19
L2:
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %r12d,%r12d
  jmp    L2
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: The size of ar is %u bytes.


assistant: ```c
int sum(int *ar, int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %u bytes.\n", sizeof ar);
  return total;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  push   %r12
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rdx
  cmp    $0x2,%eax
  jbe    L71
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   (%rax)
L13:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L13
  movdqa %xmm0,%xmm1
  mov    %esi,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%r12d
  test   $0x3,%sil
  je     L15
L24:
  movslq %eax,%rcx
  lea    0x0(,%rcx,4),%rdi
  add    (%rdx,%rcx,4),%r12d
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jle    L15
  add    $0x2,%eax
  add    0x4(%rdx,%rdi,1),%r12d
  cmp    %eax,%esi
  jle    L15
  add    0x8(%rdx,%rdi,1),%r12d
L15:
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L5:
  xor    %r12d,%r12d
  jmp    L15
L71:
  xor    %r12d,%r12d
  xor    %eax,%eax
  jmp    L24
```

tool_calls: name: read_data
arguments: tag: D3
datatype: string

tool: D3: The size of ar is %u bytes.


assistant: ```c
int sum(int *ar, int n) {
  int i;
  int total = 0;
  for (i = 0; i < n; i++)
    total += ar[i];
  printf("The size of ar is %u bytes.\n", sizeof ar);
  return total;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <skipbl@plt>
  mov    %al,-0x1(%rbp)
  jmp    L26
L8:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x2(%rbp)
L26:
  cmpb   $0xa,-0x2(%rbp)
  je     L27
  cmpb   $0x4,-0x2(%rbp)
  jne    L8
L27:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: %s 

assistant: ```c
char ask(char *s) {
  char a, c;
  printf("%s ", s);
  a = skipbl();
  while (c != '\n' && c != 4)
    c = getchar();
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ask>:
  endbr64
  push   %rbx
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <skipbl@plt>
  mov    %eax,%ebx
L15:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L2
  cmp    $0x4,%al
  jne    L15
L2:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: string

tool: D7: %s 

assistant: ```c
char ask(char *s) {
  char a, c;
  printf("%s ", s);
  a = skipbl();
  while (c != '\n' && c != 4)
    c = getchar();
  return a;
}
```
user: What is the c source code of the assembly code below?

```asm
<ask>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <skipbl@plt>
  mov    %eax,%r12d
  nop
L3:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L4
  cmp    $0x4,%al
  jne    L3
L4:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: %s 

assistant: ```c
char ask(char *s) {
  char a, c;
  printf("%s ", s);
  a = skipbl();
  while (c != '\n' && c != 4)
    c = getchar();
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ask>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <skipbl@plt>
  mov    %eax,%r12d
  nop
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L0
  cmp    $0x4,%al
  jne    L12
L0:
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: %s 

assistant: ```c
char ask(char *s) {
  char a, c;
  printf("%s ", s);
  a = skipbl();
  while (c != '\n' && c != 4)
    c = getchar();
  return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fc8300_ppi_longread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x28(%rbp)
  mov    %esi,%edx
  mov    %dx,-0x1c(%rbp)
  mov    %ax,-0x20(%rbp)
  movw   $0x4,-0x2(%rbp)
  movb   $0xc0,-0x3(%rbp)
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  movzwl -0x20(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzwl -0x20(%rbp),%eax
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzbl -0x3(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  movzwl -0x2(%rbp),%eax
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    $0x0,%edi
  call   <inb@plt>
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%edi
  call   <inb@plt>
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%edi
  call   <inb@plt>
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%edi
  call   <inb@plt>
  shl    $0x18,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int fc8300_ppi_longread(void *handle, unsigned short devid, unsigned short addr, unsigned int *data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x40;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  *data = inb(0x00);
  *data |= inb(0x00) << 8;
  *data |= inb(0x00) << 16;
  *data |= inb(0x00) << 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<fc8300_ppi_longread>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebp
  mov    %rcx,%rbx
  mov    $0x0,%eax
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  mov    $0x0,%esi
  call   <outb@plt>
  movzbl %bpl,%edi
  mov    $0x0,%esi
  call   <outb@plt>
  mov    $0x0,%esi
  mov    $0xc0,%edi
  call   <outb@plt>
  mov    $0x0,%esi
  mov    $0x4,%edi
  call   <outb@plt>
  mov    $0x0,%edi
  call   <inb@plt>
  mov    %eax,(%rbx)
  mov    $0x0,%edi
  call   <inb@plt>
  shl    $0x8,%eax
  or     %eax,(%rbx)
  mov    $0x0,%edi
  call   <inb@plt>
  shl    $0x10,%eax
  or     %eax,(%rbx)
  mov    $0x0,%edi
  call   <inb@plt>
  shl    $0x18,%eax
  or     %eax,(%rbx)
  mov    $0x0,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fc8300_ppi_longread(void *handle, unsigned short devid, unsigned short addr, unsigned int *data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x40;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  *data = inb(0x00);
  *data |= inb(0x00) << 8;
  *data |= inb(0x00) << 16;
  *data |= inb(0x00) << 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fc8300_ppi_longread>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edx,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <OAL_OBTAIN_SEMAPHORE@plt>
  mov    %ebp,%eax
  xor    %esi,%esi
  movzbl %ah,%edi
  call   <outb@plt>
  movzbl %bpl,%edi
  xor    %esi,%esi
  call   <outb@plt>
  xor    %esi,%esi
  mov    $0xc0,%edi
  call   <outb@plt>
  xor    %esi,%esi
  mov    $0x4,%edi
  call   <outb@plt>
  xor    %edi,%edi
  call   <inb@plt>
  xor    %edi,%edi
  mov    %eax,(%rbx)
  call   <inb@plt>
  xor    %edi,%edi
  shl    $0x8,%eax
  or     %eax,(%rbx)
  call   <inb@plt>
  xor    %edi,%edi
  shl    $0x10,%eax
  or     %eax,(%rbx)
  call   <inb@plt>
  shl    $0x18,%eax
  or     %eax,(%rbx)
  xor    %eax,%eax
  call   <OAL_RELEASE_SEMAPHORE@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int fc8300_ppi_longread(void *handle, unsigned short devid, unsigned short addr, unsigned int *data) {
  unsigned short length = 4;
  unsigned char command = 0x80 | 0x40;
  OAL_OBTAIN_SEMAPHORE();
  outb((addr & 0xff00) >> 8, 0x00);
  outb(addr & 0xff, 0x00);
  outb(command, 0x00);
  outb(length & 0xff, 0x00);
  *data = inb(0x00);
  *data |= inb(0x00) << 8;
  *data |= inb(0x00) << 16;
  *data |= inb(0x00) << 24;
  OAL_RELEASE_SEMAPHORE();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<select_retry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
L22:
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <select@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L18
  mov    D11(%rip),%rax
  mov    (%rax),%rdx
  mov    D17(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L6
L18:
  mov    -0x4(%rbp),%eax
  jmp    L1
L6:
  nop
  jmp    L22
L1:
  leave
  ret
```

assistant: ```c
int select_retry(int fdmax, fd_set *rfds, fd_set *wfds, fd_set *xfds, struct timeval *timeout) {
  int rv;
  while (1) {
    rv = select(fdmax, rfds, wfds, xfds, timeout);
    if ((rv == -1) && (errno == EINTR))
      continue;
    return rv;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<select_retry>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8,%rbx
L18:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  jne    L16
  mov    D19(%rip),%rcx
  mov    D3(%rip),%rdx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L18
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int select_retry(int fdmax, fd_set *rfds, fd_set *wfds, fd_set *xfds, struct timeval *timeout) {
  int rv;
  while (1) {
    rv = select(fdmax, rfds, wfds, xfds, timeout);
    if ((rv == -1) && (errno == EINTR))
      continue;
    return rv;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<select_retry>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %r14,%r8
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  jne    L9
  mov    D13(%rip),%rdx
  mov    D6(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L19
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int select_retry(int fdmax, fd_set *rfds, fd_set *wfds, fd_set *xfds, struct timeval *timeout) {
  int rv;
  while (1) {
    rv = select(fdmax, rfds, wfds, xfds, timeout);
    if ((rv == -1) && (errno == EINTR))
      continue;
    return rv;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<select_retry>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rcx,%rbx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %r14,%r8
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <select@plt>
  cmp    $0xffffffff,%eax
  jne    L1
  mov    D17(%rip),%rdx
  mov    D1(%rip),%rcx
  mov    (%rdx),%rsi
  cmp    %rsi,(%rcx)
  je     L14
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int select_retry(int fdmax, fd_set *rfds, fd_set *wfds, fd_set *xfds, struct timeval *timeout) {
  int rv;
  while (1) {
    rv = select(fdmax, rfds, wfds, xfds, timeout);
    if ((rv == -1) && (errno == EINTR))
      continue;
    return rv;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<toupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x7a,-0x4(%rbp)
  ja     L14
  cmpb   $0x60,-0x4(%rbp)
  jbe    L14
  movzbl -0x4(%rbp),%eax
  sub    $0x20,%eax
  jmp    L19
L14:
  movzbl -0x4(%rbp),%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char toupper(unsigned char c) {
  if (c <= 'z' && c >= 'a')
    return (c - 32);
  return (c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned char toupper(unsigned char c) {
  if (c <= 'z' && c >= 'a')
    return (c - 32);
  return (c);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned char toupper(unsigned char c) {
  if (c <= 'z' && c >= 'a')
    return (c - 32);
  return (c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<toupper>:
  endbr64
  lea    -0x61(%rdi),%edx
  lea    -0x20(%rdi),%eax
  cmp    $0x1a,%dl
  cmovae %edi,%eax
  ret
```

assistant: ```c
unsigned char toupper(unsigned char c) {
  if (c <= 'z' && c >= 'a')
    return (c - 32);
  return (c);
}
```