ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<copy_pic>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  mov    %rsi,%r12
  mov    %rdi,%rdx
  push   %rbp
  lea    D3(%rip),%rsi
  mov    %rdi,%rbp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <lprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <p_CopyFile@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string

tool: D3: Copy %s to %s


assistant: ```c
int copy_pic(char *source, char *target) {
  lprintf(1, "Copy %s to %s\n", source, target);
  return p_CopyFile(source, target);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<copy_pic>:
  endbr64
  push   %r12
  mov    %rsi,%rcx
  mov    %rsi,%r12
  mov    %rdi,%rdx
  push   %rbp
  lea    D3(%rip),%rsi
  mov    %rdi,%rbp
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <lprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <p_CopyFile@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: Copy %s to %s


assistant: ```c
int copy_pic(char *source, char *target) {
  lprintf(1, "Copy %s to %s\n", source, target);
  return p_CopyFile(source, target);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x4d2,-0x10(%rbp)
  jmp    L57
L36:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <isOk@plt>
  test   %rax,%rax
  je     L48
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x181cd,-0xc(%rbp)
  jg     L42
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <isOk2@plt>
  test   %rax,%rax
  je     L42
  mov    -0x14(%rbp),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L48:
  nop
  jmp    L21
L42:
  nop
L21:
  addl   $0x1,-0x10(%rbp)
L57:
  cmpl   $0x181cc,-0x10(%rbp)
  jle    L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L52
  call   <__stack_chk_fail@plt>
L52:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D17
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string

tool: D17: %d

tool: D10: %d/%d=%d


assistant: ```c
int main() {
  int n, i, m;
  scanf("%d", &n);
  for (i = 1234; i < 98765; ++i) {
    if (isOk(i))
      ;
    else
      continue;
    m = i * n;
    if (m <= 98765 && isOk2(m, i))
      printf("%d/%d=%d\n", m, i, n);
    else
      continue;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    $0x4d2,%ebx
  lea    D13(%rip),%r12
  jmp    L65
L47:
  add    $0x1,%ebx
  cmp    $0x181cd,%ebx
  je     L49
L65:
  mov    %ebx,%edi
  call   <isOk@plt>
  test   %rax,%rax
  je     L47
  mov    %ebx,%ebp
  imul   0x4(%rsp),%ebp
  cmp    $0x181cd,%ebp
  jg     L47
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <isOk2@plt>
  test   %rax,%rax
  je     L47
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L47
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D13
type_infered: string

tool: D19: %d

tool: D13: %d/%d=%d


assistant: ```c
int main() {
  int n, i, m;
  scanf("%d", &n);
  for (i = 1234; i < 98765; ++i) {
    if (isOk(i))
      ;
    else
      continue;
    m = i * n;
    if (m <= 98765 && isOk2(m, i))
      printf("%d/%d=%d\n", m, i, n);
    else
      continue;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D11(%rip),%rdi
  lea    D6(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x4d2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  nopl   0x0(%rax)
L44:
  mov    %ebx,%edi
  call   <isOk@plt>
  test   %rax,%rax
  je     L19
  mov    0x4(%rsp),%ebp
  imul   %ebx,%ebp
  cmp    $0x181cd,%ebp
  jg     L19
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <isOk2@plt>
  test   %rax,%rax
  je     L19
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L19:
  add    $0x1,%ebx
  cmp    $0x181cd,%ebx
  jne    L44
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D6
type_infered: string

tool: D11: %d

tool: D6: %d/%d=%d


assistant: ```c
int main() {
  int n, i, m;
  scanf("%d", &n);
  for (i = 1234; i < 98765; ++i) {
    if (isOk(i))
      ;
    else
      continue;
    m = i * n;
    if (m <= 98765 && isOk2(m, i))
      printf("%d/%d=%d\n", m, i, n);
    else
      continue;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D0(%rip),%rdi
  lea    D19(%rip),%r12
  push   %rbp
  push   %rbx
  mov    $0x4d2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  nopl   0x0(%rax)
L17:
  mov    %ebx,%edi
  call   <isOk@plt>
  test   %rax,%rax
  je     L14
  mov    0x4(%rsp),%ebp
  imul   %ebx,%ebp
  cmp    $0x181cd,%ebp
  jg     L14
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <isOk2@plt>
  test   %rax,%rax
  je     L14
  mov    0x4(%rsp),%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L14:
  add    $0x1,%ebx
  cmp    $0x181cd,%ebx
  jne    L17
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D19
type: string

tool: D0: %d

tool: D19: %d/%d=%d


assistant: ```c
int main() {
  int n, i, m;
  scanf("%d", &n);
  for (i = 1234; i < 98765; ++i) {
    if (isOk(i))
      ;
    else
      continue;
    m = i * n;
    if (m <= 98765 && isOk2(m, i))
      printf("%d/%d=%d\n", m, i, n);
    else
      continue;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L62:
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L69:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L32:
  cmpl   $0x9,-0xc(%rbp)
  jbe    L69
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L22:
  movl   $0x0,-0xc(%rbp)
  jmp    L20
L64:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L20:
  cmpl   $0x9,-0xc(%rbp)
  jbe    L64
  addl   $0x1,-0x4(%rbp)
L6:
  cmpl   $0x10,-0x4(%rbp)
  jbe    L22
  addl   $0x1,-0x8(%rbp)
L26:
  cmpl   $0x8,-0x8(%rbp)
  jbe    L62
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((no)) void calculate(const double *__restrict__ A, const double *__restrict__ B, double *__restrict__ C) {
  unsigned int m = 0;
  unsigned int n = 0;
  unsigned int k = 0;
  A = (const double *)__builtin_assume_aligned(A, 16);
  B = (const double *)__builtin_assume_aligned(B, 16);
  C = (double *)__builtin_assume_aligned(C, 16);
  for (n = 0; n < 9; n++) {
    for (m = 0; m < 10; m++) {
      C[(n * 10) + m] = 0.0;
    }
    for (k = 0; k < 17; k++) {
#pragma simd
      for (m = 0; m < 10; m++) {
        C[(n * 10) + m] += A[(k * 20) + m] * B[(n * 20) + k];
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calculate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r9
  mov    %rsi,%rbp
  mov    %rdx,%r8
  mov    $0xa,%edi
  mov    $0x0,%r11d
  mov    $0xa,%r13d
  mov    $0x15e,%r12d
  jmp    L30
L18:
  add    $0x1,%r10d
  add    $0x14,%esi
  cmp    %ebx,%esi
  je     L36
L29:
  mov    %r10d,%eax
  movsd  0x0(%rbp,%rax,8),%xmm1
  mov    %r11d,%eax
L10:
  mov    %eax,%edx
  lea    (%r8,%rdx,8),%rdx
  lea    (%rsi,%rax,1),%ecx
  movapd %xmm1,%xmm0
  mulsd  (%r9,%rcx,8),%xmm0
  addsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L10
  jmp    L18
L36:
  add    $0xa,%r11d
  add    $0xa,%edi
  cmp    $0x64,%edi
  je     L61
L30:
  mov    %r11d,%eax
L39:
  mov    %eax,%edx
  movq   $0x0,(%r8,%rdx,8)
  add    $0x1,%eax
  cmp    %edi,%eax
  jne    L39
  lea    (%r11,%r11,1),%r10d
  mov    %r13d,%esi
  sub    %edi,%esi
  mov    %r12d,%ebx
  sub    %edi,%ebx
  jmp    L29
L61:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
__attribute__((no)) void calculate(const double *__restrict__ A, const double *__restrict__ B, double *__restrict__ C) {
  unsigned int m = 0;
  unsigned int n = 0;
  unsigned int k = 0;
  A = (const double *)__builtin_assume_aligned(A, 16);
  B = (const double *)__builtin_assume_aligned(B, 16);
  C = (double *)__builtin_assume_aligned(C, 16);
  for (n = 0; n < 9; n++) {
    for (m = 0; m < 10; m++) {
      C[(n * 10) + m] = 0.0;
    }
    for (k = 0; k < 17; k++) {
#pragma simd
      for (m = 0; m < 10; m++) {
        C[(n * 10) + m] += A[(k * 20) + m] * B[(n * 20) + k];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<calculate>:
  endbr64
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    0x2d0(%rdx),%r10
L18:
  pxor   %xmm0,%xmm0
  mov    %r9,%rcx
  mov    %r8,%rdi
  xor    %esi,%esi
  movups %xmm0,(%rdx)
  movups %xmm0,0x10(%rdx)
  movups %xmm0,0x20(%rdx)
  movups %xmm0,0x30(%rdx)
  movups %xmm0,0x40(%rdx)
L29:
  movsd  (%rdi),%xmm1
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L0:
  movsd  (%rcx,%rax,1),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  (%rdx,%rax,1),%xmm0
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    $0x50,%rax
  jne    L0
  add    $0x14,%esi
  add    $0x8,%rdi
  add    $0xa0,%rcx
  cmp    $0x154,%esi
  jne    L29
  add    $0x50,%rdx
  add    $0xa0,%r8
  cmp    %rdx,%r10
  jne    L18
  ret
```

assistant: ```c
__attribute__((no)) void calculate(const double *__restrict__ A, const double *__restrict__ B, double *__restrict__ C) {
  unsigned int m = 0;
  unsigned int n = 0;
  unsigned int k = 0;
  A = (const double *)__builtin_assume_aligned(A, 16);
  B = (const double *)__builtin_assume_aligned(B, 16);
  C = (double *)__builtin_assume_aligned(C, 16);
  for (n = 0; n < 9; n++) {
    for (m = 0; m < 10; m++) {
      C[(n * 10) + m] = 0.0;
    }
    for (k = 0; k < 17; k++) {
#pragma simd
      for (m = 0; m < 10; m++) {
        C[(n * 10) + m] += A[(k * 20) + m] * B[(n * 20) + k];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<calculate>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  pxor   %xmm7,%xmm7
  mov    %rdx,%rsi
  lea    0x5a0(%rdi),%r9
  lea    0xaa0(%r8),%rcx
L0:
  pxor   %xmm5,%xmm5
  movaps %xmm7,0x20(%rsi)
  movapd 0x20(%rsi),%xmm2
  mov    %r8,%rax
  movaps %xmm7,0x30(%rsi)
  movapd 0x30(%rsi),%xmm1
  mov    %rdi,%rdx
  movapd %xmm5,%xmm4
  movaps %xmm7,(%rsi)
  movapd %xmm5,%xmm3
  movaps %xmm7,0x10(%rsi)
  nopw   0x0(%rax,%rax,1)
L9:
  movsd  (%rdx),%xmm0
  movapd (%rax),%xmm6
  add    $0xa0,%rax
  add    $0x8,%rdx
  unpcklpd %xmm0,%xmm0
  mulpd  %xmm0,%xmm6
  addpd  %xmm6,%xmm3
  movapd -0x90(%rax),%xmm6
  mulpd  %xmm0,%xmm6
  addpd  %xmm6,%xmm4
  movapd -0x80(%rax),%xmm6
  mulpd  %xmm0,%xmm6
  addpd  %xmm6,%xmm2
  movapd -0x70(%rax),%xmm6
  mulpd  %xmm0,%xmm6
  mulpd  -0x60(%rax),%xmm0
  addpd  %xmm6,%xmm1
  addpd  %xmm0,%xmm5
  cmp    %rax,%rcx
  jne    L9
  add    $0xa0,%rdi
  movaps %xmm3,(%rsi)
  add    $0x50,%rsi
  movaps %xmm4,-0x40(%rsi)
  movaps %xmm2,-0x30(%rsi)
  movaps %xmm1,-0x20(%rsi)
  movaps %xmm5,-0x10(%rsi)
  cmp    %rdi,%r9
  jne    L0
  ret
```

assistant: ```c
__attribute__((no)) void calculate(const double *__restrict__ A, const double *__restrict__ B, double *__restrict__ C) {
  unsigned int m = 0;
  unsigned int n = 0;
  unsigned int k = 0;
  A = (const double *)__builtin_assume_aligned(A, 16);
  B = (const double *)__builtin_assume_aligned(B, 16);
  C = (double *)__builtin_assume_aligned(C, 16);
  for (n = 0; n < 9; n++) {
    for (m = 0; m < 10; m++) {
      C[(n * 10) + m] = 0.0;
    }
    for (k = 0; k < 17; k++) {
#pragma simd
      for (m = 0; m < 10; m++) {
        C[(n * 10) + m] += A[(k * 20) + m] * B[(n * 20) + k];
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L7:
  mov    -0x4(%rbp),%eax
  mov    %al,-0x5(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0xff,-0x4(%rbp)
  jle    L7
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string

tool: D3: 
 %d %c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n %d %c", i, i);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L5:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D8: 
 %d %c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n %d %c", i, i);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: 
 %d %c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n %d %c", i, i);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x100,%ebx
  jne    L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D2: 
 %d %c

assistant: ```c
int main() {
  int i = 0;
  char c;
  for (i = 0; i <= 255; i++) {
    c = i;
    printf("\n %d %c", i, i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<write_segment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x30,%rsp
  mov    %edi,-0x2044(%rbp)
  mov    %rsi,%r12
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movl   $0x2000,-0x2038(%rbp)
  movl   $0x2000,-0x2034(%rbp)
  lea    -0x2030(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%eax
  mov    $0x400,%edx
  mov    %rsi,%rdi
  mov    %rdx,%rcx
  rep stos %rax,%es:(%rdi)
  jmp    L24
L56:
  mov    %r12,%rax
  mov    %eax,%edx
  mov    -0x2038(%rbp),%eax
  add    %eax,%edx
  mov    -0x2038(%rbp),%eax
  neg    %eax
  and    %edx,%eax
  mov    %r12,%rdx
  sub    %edx,%eax
  mov    %eax,%ebx
  movslq %ebx,%rax
  mov    %r13,%rdx
  sub    %r12,%rdx
  cmp    %rdx,%rax
  jle    L57
  mov    %r13,%rax
  sub    %r12,%rax
  mov    %eax,%ebx
L57:
  mov    -0x2044(%rbp),%eax
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    %eax,%r14d
  cmp    $0xffffffff,%r14d
  jne    L43
  cmp    -0x2034(%rbp),%ebx
  jle    L42
  mov    -0x2034(%rbp),%ebx
L42:
  lea    -0x2030(%rbp),%rcx
  mov    -0x2044(%rbp),%eax
  mov    %ebx,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
L43:
  movslq %ebx,%rax
  add    %rax,%r12
L24:
  cmp    %r13,%r12
  jb     L56
  nop
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  add    $0x2030,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
write_segment(new, ptr, end) int new;
register char *ptr, *end;
{
  register int i, nwrite, ret;
  char buf[80];
  extern int errno;
  int writesize = 1 << 13;
  int pagesize = 8192;
  char zeros[1 << 13];
  bzero(zeros, sizeof(zeros));
  for (i = 0; ptr < end;) {
    nwrite = (((int)ptr + writesize) & -writesize) - (int)ptr;
    if (nwrite > end - ptr)
      nwrite = end - ptr;
    ret = write(new, ptr, nwrite);
    if (ret == -1) {
      if (nwrite > pagesize)
        nwrite = pagesize;
      write(new, zeros, nwrite);
    }
    i += nwrite;
    ptr += nwrite;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<write_segment>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    %edi,%r13d
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x400,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  cmp    %r12,%rsi
  jae    L52
  mov    %rsi,%rbp
  mov    %rsp,%r14
  jmp    L56
L12:
  movslq %ebx,%rbx
  add    %rbx,%rbp
  cmp    %rbp,%r12
  jbe    L52
L56:
  lea    0x2000(%rbp),%eax
  and    $0xffffe000,%eax
  mov    %eax,%ebx
  sub    %ebp,%ebx
  mov    %r12,%rdx
  sub    %rbp,%rdx
  movslq %ebx,%rbx
  sub    %ebp,%eax
  cmp    %rdx,%rbx
  cmovg  %edx,%eax
  mov    %eax,%ebx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L12
  mov    $0x2000,%eax
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  mov    %ebx,%edx
  mov    %r14,%rsi
  mov    %r13d,%edi
  mov    $0x0,%eax
  call   <write@plt>
  jmp    L12
L52:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    $0x0,%eax
  add    $0x2010,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
write_segment(new, ptr, end) int new;
register char *ptr, *end;
{
  register int i, nwrite, ret;
  char buf[80];
  extern int errno;
  int writesize = 1 << 13;
  int pagesize = 8192;
  char zeros[1 << 13];
  bzero(zeros, sizeof(zeros));
  for (i = 0; ptr < end;) {
    nwrite = (((int)ptr + writesize) & -writesize) - (int)ptr;
    if (nwrite > end - ptr)
      nwrite = end - ptr;
    ret = write(new, ptr, nwrite);
    if (ret == -1) {
      if (nwrite > pagesize)
        nwrite = pagesize;
      write(new, zeros, nwrite);
    }
    i += nwrite;
    ptr += nwrite;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<write_segment>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x10,%rsp
  mov    $0x400,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x2008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %edi,%r12d
  mov    %r13,%rdi
  rep stos %rax,%es:(%rdi)
  cmp    %rdx,%rsi
  jae    L4
  mov    %rsi,%r14
  mov    %rdx,%rbp
  jmp    L23
  nopl   0x0(%rax)
L54:
  movslq %ebx,%rbx
  add    %rbx,%r14
  cmp    %r14,%rbp
  jbe    L4
L23:
  lea    0x2000(%r14),%ebx
  mov    %rbp,%rax
  mov    %r14,%rsi
  mov    %r12d,%edi
  and    $0xffffe000,%ebx
  sub    %r14,%rax
  sub    %r14d,%ebx
  movslq %ebx,%rdx
  cmp    %rax,%rdx
  cmovg  %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%edx
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L54
  mov    $0x2000,%eax
  mov    %r13,%rsi
  mov    %r12d,%edi
  cmp    %eax,%ebx
  cmovg  %eax,%ebx
  xor    %eax,%eax
  mov    %ebx,%edx
  movslq %ebx,%rbx
  call   <write@plt>
  add    %rbx,%r14
  cmp    %r14,%rbp
  ja     L23
  nopw   0x0(%rax,%rax,1)
L4:
  mov    0x2008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x2010,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
write_segment(new, ptr, end) int new;
register char *ptr, *end;
{
  register int i, nwrite, ret;
  char buf[80];
  extern int errno;
  int writesize = 1 << 13;
  int pagesize = 8192;
  char zeros[1 << 13];
  bzero(zeros, sizeof(zeros));
  for (i = 0; ptr < end;) {
    nwrite = (((int)ptr + writesize) & -writesize) - (int)ptr;
    if (nwrite > end - ptr)
      nwrite = end - ptr;
    ret = write(new, ptr, nwrite);
    if (ret == -1) {
      if (nwrite > pagesize)
        nwrite = pagesize;
      write(new, zeros, nwrite);
    }
    i += nwrite;
    ptr += nwrite;
  }
}
```