ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  test   %rdx,%rdx
  je     L121
  lea    0x1(%rsi),%rdi
  mov    %r8,%rsi
  lea    -0x1(%rdx),%rax
  sub    %rdi,%rsi
  cmp    $0xe,%rsi
  jbe    L105
  cmp    $0x6,%rax
  jbe    L105
  mov    %rdx,%rsi
  cmp    $0xe,%rax
  jbe    L103
  and    $0xfffffffffffffff0,%rsi
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L128:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L128
  mov    %rdx,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%dl
  je     L121
  mov    %rdx,%rsi
  sub    %rax,%rsi
  lea    -0x1(%rsi),%rdi
  cmp    $0x6,%rdi
  jbe    L152
L80:
  mov    (%rcx,%rax,1),%rdi
  mov    %rdi,(%r8,%rax,1)
  mov    %rsi,%rdi
  and    $0xfffffffffffffff8,%rdi
  add    %rdi,%rax
  cmp    %rdi,%rsi
  je     L121
L152:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  lea    0x1(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L121
  movzbl 0x1(%rcx,%rax,1),%esi
  mov    %sil,0x1(%r8,%rax,1)
  lea    0x2(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L121
  movzbl 0x2(%rcx,%rax,1),%esi
  mov    %sil,0x2(%r8,%rax,1)
  lea    0x3(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L121
  movzbl 0x3(%rcx,%rax,1),%esi
  mov    %sil,0x3(%r8,%rax,1)
  lea    0x4(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L121
  movzbl 0x4(%rcx,%rax,1),%esi
  mov    %sil,0x4(%r8,%rax,1)
  lea    0x5(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L121
  movzbl 0x5(%rcx,%rax,1),%esi
  mov    %sil,0x5(%r8,%rax,1)
  lea    0x6(%rax),%rsi
  cmp    %rsi,%rdx
  jbe    L121
  movzbl 0x6(%rcx,%rax,1),%edx
  mov    %dl,0x6(%r8,%rax,1)
L121:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L105:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L108:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L108
  mov    %r8,%rax
  ret
L103:
  xor    %eax,%eax
  jmp    L80
```

assistant: ```c
void *memcpy(void *dest, const void *src, size_t n) {
  size_t i = 0;
  while (i < n) {
    *((char *)dest + i) = *((const char *)src + i);
    i++;
  }
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ivec_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L16
L5:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  sub    %ecx,%edx
  mov    %edx,(%rax)
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ivec_sub(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] -= v2[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ivec_sub>:
  endbr64
  test   %rdx,%rdx
  jle    L0
  mov    $0x0,%eax
L16:
  mov    (%rsi,%rax,4),%ecx
  sub    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L16
L0:
  ret
```

assistant: ```c
void ivec_sub(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] -= v2[i];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ivec_sub>:
  endbr64
  test   %rdx,%rdx
  jle    L13
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L18:
  mov    (%rsi,%rax,4),%ecx
  sub    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L18
L13:
  ret
```

assistant: ```c
void ivec_sub(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] -= v2[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ivec_sub>:
  endbr64
  mov    %rdi,%rcx
  test   %rdx,%rdx
  jle    L95
  lea    0x4(%rsi),%rdi
  mov    %rcx,%rax
  sub    %rdi,%rax
  cmp    $0x8,%rax
  jbe    L85
  cmp    $0x1,%rdx
  je     L85
  lea    -0x1(%rdx),%rax
  mov    %rdx,%r8
  cmp    $0x2,%rax
  jbe    L44
  mov    %rdx,%rdi
  xor    %eax,%eax
  shr    $0x2,%rdi
  shl    $0x4,%rdi
  nopl   0x0(%rax)
L54:
  movdqu (%rcx,%rax,1),%xmm0
  movdqu (%rsi,%rax,1),%xmm2
  psubd  %xmm2,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L54
  mov    %rdx,%rdi
  and    $0xfffffffffffffffc,%rdi
  mov    %rdi,%rax
  cmp    %rdi,%rdx
  je     L95
  sub    %rdi,%rdx
  mov    %rdx,%r8
  cmp    $0x1,%rdx
  je     L43
L53:
  lea    (%rcx,%rdi,4),%rdx
  movq   (%rsi,%rdi,4),%xmm1
  movq   (%rdx),%xmm0
  psubd  %xmm1,%xmm0
  movq   %xmm0,(%rdx)
  mov    %r8,%rdx
  and    $0xfffffffffffffffe,%rdx
  add    %rdx,%rax
  cmp    %rdx,%r8
  je     L95
L43:
  mov    (%rsi,%rax,4),%edx
  sub    %edx,(%rcx,%rax,4)
  ret
  nopl   0x0(%rax)
L85:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  mov    (%rsi,%rax,4),%edi
  sub    %edi,(%rcx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L6
L95:
  ret
L44:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L53
```

assistant: ```c
void ivec_sub(int *v1, const int *v2, long n) {
  long i = 0;
  for (i = 0; i < n; i++) {
    v1[i] -= v2[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  mov    $0x56000050,%eax
  movq   $0x1500,(%rax)
L19:
  mov    $0xbb8,%edi
  call   <delay@plt>
  mov    -0x8(%rbp),%rax
  shl    $0x4,%rax
  mov    $0x56000054,%edx
  not    %rax
  mov    %rax,(%rdx)
  addq   $0x1,-0x8(%rbp)
  cmpq   $0x8,-0x8(%rbp)
  jne    L19
  movq   $0x0,-0x8(%rbp)
  jmp    L19
```

assistant: ```c
int main(void) {
  unsigned long i = 0;
  (*(volatile unsigned long *)0x56000050) = (1 << (4 * 2)) | (1 << (5 * 2)) | (1 << (6 * 2));
  while (1) {
    delay(3000);
    (*(volatile unsigned long *)0x56000054) = ~(i << 4);
    if (++i == 8) {
      i = 0;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   $0x1500,0x56000050
  mov    $0xbb8,%edi
  call   <delay@plt>
  movq   $0xffffffffffffffff,0x56000054
  mov    $0x1,%ebx
  mov    $0x0,%ebp
L5:
  mov    $0xbb8,%edi
  call   <delay@plt>
  mov    %rbx,%rax
  shl    $0x4,%rax
  not    %rax
  mov    %rax,0x56000054
  add    $0x1,%rbx
  cmp    $0x8,%rbx
  cmove  %rbp,%rbx
  jmp    L5
```

assistant: ```c
int main(void) {
  unsigned long i = 0;
  (*(volatile unsigned long *)0x56000050) = (1 << (4 * 2)) | (1 << (5 * 2)) | (1 << (6 * 2));
  while (1) {
    delay(3000);
    (*(volatile unsigned long *)0x56000054) = ~(i << 4);
    if (++i == 8) {
      i = 0;
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  movq   $0x1500,0x56000050
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0xbb8,%edi
  call   <delay@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  shl    $0x4,%rax
  cmp    $0x8,%rbx
  not    %rax
  cmove  %rbp,%rbx
  mov    %rax,0x56000054
  jmp    L9
```

assistant: ```c
int main(void) {
  unsigned long i = 0;
  (*(volatile unsigned long *)0x56000050) = (1 << (4 * 2)) | (1 << (5 * 2)) | (1 << (6 * 2));
  while (1) {
    delay(3000);
    (*(volatile unsigned long *)0x56000054) = ~(i << 4);
    if (++i == 8) {
      i = 0;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  movq   $0x1500,0x56000050
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0xbb8,%edi
  call   <delay@plt>
  mov    %rbx,%rax
  add    $0x1,%rbx
  shl    $0x4,%rax
  cmp    $0x8,%rbx
  not    %rax
  cmove  %rbp,%rbx
  mov    %rax,0x56000054
  jmp    L1
```

assistant: ```c
int main(void) {
  unsigned long i = 0;
  (*(volatile unsigned long *)0x56000050) = (1 << (4 * 2)) | (1 << (5 * 2)) | (1 << (6 * 2));
  while (1) {
    delay(3000);
    (*(volatile unsigned long *)0x56000054) = ~(i << 4);
    if (++i == 8) {
      i = 0;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<display_getch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <display_refresh@plt>
  mov    $0x0,%eax
  call   <device_getch@plt>
  pop    %rbp
  ret
```

assistant: ```c
int display_getch(void) {
  display_refresh();
  return device_getch();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<display_getch>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <display_refresh@plt>
  mov    $0x0,%eax
  call   <device_getch@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int display_getch(void) {
  display_refresh();
  return device_getch();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<display_getch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <display_refresh@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <device_getch@plt>
```

assistant: ```c
int display_getch(void) {
  display_refresh();
  return device_getch();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<display_getch>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <display_refresh@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <device_getch@plt>
```

assistant: ```c
int display_getch(void) {
  display_refresh();
  return device_getch();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<freopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    D1(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  jne    L11
  mov    $0x0,%eax
  jmp    L1
L11:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_fpopen@plt>
L1:
  leave
  ret
```

assistant: ```c
FILE *freopen(const char *restrict name, const char *restrict mode, FILE *restrict fp) {
  if (fclose(fp) == EOF)
    return NULL;
  return _fpopen(name, mode, fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<freopen>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <fclose@plt>
  mov    D3(%rip),%rdx
  cmp    (%rdx),%rax
  je     L17
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <_fpopen@plt>
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    $0x0,%eax
  jmp    L10
```

assistant: ```c
FILE *freopen(const char *restrict name, const char *restrict mode, FILE *restrict fp) {
  if (fclose(fp) == EOF)
    return NULL;
  return _fpopen(name, mode, fp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<freopen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  call   <fclose@plt>
  mov    D9(%rip),%rdx
  cmp    (%rdx),%rax
  je     L8
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <_fpopen@plt>
  nopl   0x0(%rax)
L8:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
FILE *freopen(const char *restrict name, const char *restrict mode, FILE *restrict fp) {
  if (fclose(fp) == EOF)
    return NULL;
  return _fpopen(name, mode, fp);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<freopen>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rdx,%rdi
  call   <fclose@plt>
  mov    D1(%rip),%rdx
  cmp    (%rdx),%rax
  je     L9
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <_fpopen@plt>
  nopl   0x0(%rax)
L9:
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
FILE *freopen(const char *restrict name, const char *restrict mode, FILE *restrict fp) {
  if (fclose(fp) == EOF)
    return NULL;
  return _fpopen(name, mode, fp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa40,%rsp
  mov    %edi,-0xa34(%rbp)
  mov    %rsi,-0xa40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa24(%rbp)
  movl   $0x0,-0xa20(%rbp)
  movl   $0x0,-0xa1c(%rbp)
  movl   $0x0,-0xa18(%rbp)
  movl   $0x0,-0xa14(%rbp)
  movq   $0x0,-0x810(%rbp)
  movq   $0x0,-0x808(%rbp)
  lea    -0x800(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x0,-0x610(%rbp)
  movq   $0x0,-0x608(%rbp)
  lea    -0x600(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movq   $0x0,-0x210(%rbp)
  movq   $0x0,-0x208(%rbp)
  lea    -0x200(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x3e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x410(%rbp),%r9
  lea    -0x610(%rbp),%r8
  lea    -0x810(%rbp),%rcx
  lea    -0xa10(%rbp),%rdx
  mov    -0xa40(%rbp),%rsi
  mov    -0xa34(%rbp),%eax
  lea    -0xa18(%rbp),%rdi
  push   %rdi
  lea    -0xa14(%rbp),%rdi
  push   %rdi
  lea    -0xa1c(%rbp),%rdi
  push   %rdi
  lea    -0x210(%rbp),%rdi
  push   %rdi
  mov    %eax,%edi
  call   <analyse_param_pca@plt>
  add    $0x20,%rsp
  mov    -0xa18(%rbp),%r8d
  mov    -0xa14(%rbp),%edi
  lea    -0xa24(%rbp),%r9
  lea    -0x210(%rbp),%r10
  lea    -0x410(%rbp),%rcx
  lea    -0x610(%rbp),%rdx
  lea    -0x810(%rbp),%rsi
  lea    -0xa10(%rbp),%rax
  push   %r8
  push   %rdi
  lea    -0xa1c(%rbp),%rdi
  push   %rdi
  lea    -0xa20(%rbp),%rdi
  push   %rdi
  mov    %r10,%r8
  mov    %rax,%rdi
  call   <pca@plt>
  add    $0x20,%rsp
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int L = 0;
  int K = 0;
  int s = 0;
  int c = 0;
  char input_file[512];
  char output_eva_file[512] = "";
  char output_eve_file[512] = "";
  char output_sdev_file[512] = "";
  char output_x_file[512] = "";
  analyse_param_pca(argc, argv, input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &K, &c, &s);
  pca(input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &n, &L, &K, c, s);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa38,%rsp
  mov    %edi,%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0xa28(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movq   $0x0,0x220(%rsp)
  movq   $0x0,0x228(%rsp)
  lea    0x230(%rsp),%rdi
  mov    $0x3e,%ecx
  rep stos %rax,%es:(%rdi)
  movq   $0x0,0x420(%rsp)
  movq   $0x0,0x428(%rsp)
  lea    0x430(%rsp),%rdi
  mov    $0x3e,%ecx
  rep stos %rax,%es:(%rdi)
  movq   $0x0,0x620(%rsp)
  movq   $0x0,0x628(%rsp)
  lea    0x630(%rsp),%rdi
  mov    $0x3e,%ecx
  rep stos %rax,%es:(%rdi)
  movq   $0x0,0x820(%rsp)
  movq   $0x0,0x828(%rsp)
  lea    0x830(%rsp),%rdi
  mov    $0x3e,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x620(%rsp),%r13
  lea    0x420(%rsp),%r12
  lea    0x220(%rsp),%rbp
  lea    0x20(%rsp),%rbx
  lea    0x18(%rsp),%rax
  push   %rax
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x24(%rsp),%r15
  push   %r15
  lea    0x838(%rsp),%r14
  push   %r14
  mov    %r13,%r9
  mov    %r12,%r8
  mov    %rbp,%rcx
  mov    %rbx,%rdx
  mov    %r10d,%edi
  call   <analyse_param_pca@plt>
  add    $0x20,%rsp
  mov    0x18(%rsp),%eax
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  push   %r15
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  mov    %r14,%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <pca@plt>
  add    $0x20,%rsp
  mov    0xa28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xa38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int L = 0;
  int K = 0;
  int s = 0;
  int c = 0;
  char input_file[512];
  char output_eva_file[512] = "";
  char output_eve_file[512] = "";
  char output_sdev_file[512] = "";
  char output_x_file[512] = "";
  analyse_param_pca(argc, argv, input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &K, &c, &s);
  pca(input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &n, &L, &K, c, s);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  mov    %edi,%r10d
  mov    $0x3e,%ecx
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa28(%rsp)
  xor    %eax,%eax
  lea    0x230(%rsp),%rdi
  movaps %xmm0,0x220(%rsp)
  lea    0x620(%rsp),%r14
  movaps %xmm0,0x420(%rsp)
  lea    0x20(%rsp),%rbp
  mov    %r14,%r9
  lea    0x420(%rsp),%r13
  movaps %xmm0,0x620(%rsp)
  mov    %r13,%r8
  mov    %rbp,%rdx
  lea    0x220(%rsp),%r12
  movaps %xmm0,0x820(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x430(%rsp),%rdi
  mov    $0x3e,%ecx
  movl   $0x0,0x14(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x630(%rsp),%rdi
  mov    $0x3e,%ecx
  movl   $0x0,0x18(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x830(%rsp),%rdi
  mov    $0x3e,%ecx
  movl   $0x0,0x1c(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x18(%rsp),%rax
  mov    %r10d,%edi
  mov    %r12,%rcx
  push   %rax
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x24(%rsp),%r15
  push   %r15
  lea    0x838(%rsp),%rbx
  push   %rbx
  call   <analyse_param_pca@plt>
  mov    0x38(%rsp),%eax
  add    $0x20,%rsp
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  push   %r15
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  call   <pca@plt>
  add    $0x20,%rsp
  mov    0xa28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xa38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int L = 0;
  int K = 0;
  int s = 0;
  int c = 0;
  char input_file[512];
  char output_eva_file[512] = "";
  char output_eve_file[512] = "";
  char output_sdev_file[512] = "";
  char output_x_file[512] = "";
  analyse_param_pca(argc, argv, input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &K, &c, &s);
  pca(input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &n, &L, &K, c, s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    %edi,%r10d
  mov    $0x3e,%ecx
  pxor   %xmm0,%xmm0
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xa38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa28(%rsp)
  xor    %eax,%eax
  lea    0x230(%rsp),%rdi
  movaps %xmm0,0x220(%rsp)
  lea    0x620(%rsp),%r14
  movaps %xmm0,0x420(%rsp)
  lea    0x20(%rsp),%rbp
  mov    %r14,%r9
  lea    0x420(%rsp),%r13
  movaps %xmm0,0x620(%rsp)
  mov    %r13,%r8
  mov    %rbp,%rdx
  lea    0x220(%rsp),%r12
  movaps %xmm0,0x820(%rsp)
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x430(%rsp),%rdi
  mov    $0x3e,%ecx
  movl   $0x0,0x14(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x630(%rsp),%rdi
  mov    $0x3e,%ecx
  movl   $0x0,0x18(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x830(%rsp),%rdi
  mov    $0x3e,%ecx
  movl   $0x0,0x1c(%rsp)
  rep stos %rax,%es:(%rdi)
  lea    0x18(%rsp),%rax
  mov    %r10d,%edi
  mov    %r12,%rcx
  push   %rax
  lea    0x24(%rsp),%rax
  push   %rax
  lea    0x24(%rsp),%r15
  push   %r15
  lea    0x838(%rsp),%rbx
  push   %rbx
  call   <analyse_param_pca@plt>
  mov    0x38(%rsp),%eax
  add    $0x20,%rsp
  mov    %rbx,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  push   %rax
  mov    0x24(%rsp),%eax
  push   %rax
  push   %r15
  lea    0x28(%rsp),%rax
  push   %rax
  lea    0x2c(%rsp),%r9
  call   <pca@plt>
  add    $0x20,%rsp
  mov    0xa28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0xa38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int n = 0;
  int L = 0;
  int K = 0;
  int s = 0;
  int c = 0;
  char input_file[512];
  char output_eva_file[512] = "";
  char output_eve_file[512] = "";
  char output_sdev_file[512] = "";
  char output_x_file[512] = "";
  analyse_param_pca(argc, argv, input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &K, &c, &s);
  pca(input_file, output_eva_file, output_eve_file, output_sdev_file, output_x_file, &n, &L, &K, c, s);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void test_4(void *q, void *r) {
  void *p = malloc(1024);
  bar(p, q, r);
  bar(p, q, r);
  free(p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <bar@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <bar@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test_4(void *q, void *r) {
  void *p = malloc(1024);
  bar(p, q, r);
  bar(p, q, r);
  free(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_4>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x400,%edi
  push   %rbp
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <bar@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
```

assistant: ```c
void test_4(void *q, void *r) {
  void *p = malloc(1024);
  bar(p, q, r);
  bar(p, q, r);
  free(p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_4>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  mov    $0x400,%edi
  push   %rbp
  call   <malloc@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <bar@plt>
  mov    %rbp,%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  call   <bar@plt>
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <free@plt>
```

assistant: ```c
void test_4(void *q, void *r) {
  void *p = malloc(1024);
  bar(p, q, r);
  bar(p, q, r);
  free(p);
}
```