ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  lea    D29(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
L12:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L12
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  movb   $0x0,(%rsp)
  jmp    L1
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D29
type_guessed: string

tool: D14: Eingabe:

tool: D0: %[+-01-9]

tool: D29: ...%s..%d..


assistant: ```c
main() {
  char string[30];
  while (1) {
    printf("Eingabe:");
    scanf("%[+-01-9]", string);
    while (getchar() != 10)
      ;
    printf("...%s..%d..\n", string, atoi(string));
    string[0] = '\0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
L3:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L3
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  movb   $0x0,(%rsp)
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
data_type: string
name: retrieve_data
arguments: data_tag: D16
data_type: string
name: retrieve_data
arguments: data_tag: D10
data_type: string

tool: D21: Eingabe:

tool: D16: %[+-01-9]

tool: D10: ...%s..%d..


assistant: ```c
main() {
  char string[30];
  while (1) {
    printf("Eingabe:");
    scanf("%[+-01-9]", string);
    while (getchar() != 10)
      ;
    printf("...%s..%d..\n", string, atoi(string));
    string[0] = '\0';
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L9:
  cmp    %rdx,%rsp
  je     L57
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L9
L57:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L25
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L25:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L46
L1:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L46:
  mov    -0x50(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L1
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x50(%rbp),%edx
  mov    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insertion@plt>
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_infered: string
name: retrieve_data
arguments: label: D18
type_infered: string
name: retrieve_data
arguments: label: D45
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D2: Enter the number of elements


tool: D18: %d

tool: D45: Enter the elements of the array


tool: D29: Sorted array


assistant: ```c
int main() {
  printf("Enter the number of elements\n");
  int n;
  scanf("%d", &n);
  printf("Enter the elements of the array\n");
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Sorted array\n");
  insertion(arr, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  lea    D36(%rip),%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L14:
  cmp    %rcx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L14
L5:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L54
  orq    $0x0,-0x8(%rsp,%rax,1)
L54:
  mov    %rsp,%r14
  test   %edx,%edx
  jle    L45
  mov    %r14,%r12
  mov    $0x0,%ebx
  lea    D36(%rip),%r13
L17:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x2c(%rbp)
  jg     L17
L45:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <insertion@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string
name: retrieve_data
arguments: label: D36
type_guessed: string
name: retrieve_data
arguments: label: D25
type_guessed: string
name: retrieve_data
arguments: label: D32
type_guessed: string

tool: D7: Enter the number of elements


tool: D36: %d

tool: D25: Enter the elements of the array


tool: D32: Sorted array


assistant: ```c
int main() {
  printf("Enter the number of elements\n");
  int n;
  scanf("%d", &n);
  printf("Enter the elements of the array\n");
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Sorted array\n");
  insertion(arr, n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D35(%rip),%rdi
  call   <printf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L16
L39:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L39
L16:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L40
L34:
  mov    %rsp,%r14
  test   %ecx,%ecx
  jle    L55
  mov    %r14,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L51:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L51
L55:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <insertion@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L40:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L34
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
type: string
name: disassemble_data
arguments: tag: D21
type: string
name: disassemble_data
arguments: tag: D35
type: string
name: disassemble_data
arguments: tag: D16
type: string

tool: D19: Enter the number of elements


tool: D21: %d

tool: D35: Enter the elements of the array


tool: D16: Sorted array


assistant: ```c
int main() {
  printf("Enter the number of elements\n");
  int n;
  scanf("%d", &n);
  printf("Enter the elements of the array\n");
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Sorted array\n");
  insertion(arr, n);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  lea    D36(%rip),%r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    -0x2c(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L29
L23:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L23
L29:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L41
L67:
  mov    %rsp,%r14
  test   %ecx,%ecx
  jle    L0
  mov    %r14,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L58:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %ebx,-0x2c(%rbp)
  jg     L58
L0:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%esi
  mov    %r14,%rdi
  call   <insertion@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L41:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L67
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
data_type: string
name: extract_symbolic_data
arguments: data_tag: D36
data_type: string
name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D13
data_type: string

tool: D12: Enter the number of elements


tool: D36: %d

tool: D5: Enter the elements of the array


tool: D13: Sorted array


assistant: ```c
int main() {
  printf("Enter the number of elements\n");
  int n;
  scanf("%d", &n);
  printf("Enter the elements of the array\n");
  int arr[n];
  for (int i = 0; i < n; i++) {
    scanf("%d", &arr[i]);
  }
  printf("Sorted array\n");
  insertion(arr, n);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<mhash_with_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x850,%rsp
  mov    %rdi,-0x838(%rbp)
  mov    %esi,-0x83c(%rbp)
  mov    %rdx,-0x848(%rbp)
  mov    %rcx,-0x850(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x83c(%rbp),%eax
  mov    %eax,-0x820(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x838(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x81c(%rbp)
  cmpl   $0xffffffff,-0x81c(%rbp)
  jne    L67
  mov    -0x848(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x850(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0xffffffff,%eax
  jmp    L35
L67:
  lea    -0x824(%rbp),%rax
  mov    %rax,%rdi
  call   <MD5_Init@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%rdx
  mov    -0x850(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x850(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x848(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L53
L48:
  mov    -0x820(%rbp),%eax
  cmp    $0x7ff,%eax
  ja     L46
  mov    -0x820(%rbp),%eax
  jmp    L86
L46:
  mov    $0x800,%eax
L86:
  mov    %eax,-0x818(%rbp)
  mov    -0x818(%rbp),%edx
  lea    -0x810(%rbp),%rcx
  mov    -0x81c(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x814(%rbp)
  cmpl   $0x0,-0x814(%rbp)
  jle    L33
  mov    -0x814(%rbp),%edx
  lea    -0x810(%rbp),%rcx
  lea    -0x824(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <MD5_Update@plt>
  mov    -0x814(%rbp),%eax
  sub    %eax,-0x820(%rbp)
L53:
  cmpl   $0x0,-0x820(%rbp)
  jg     L48
  jmp    L7
L33:
  nop
L7:
  mov    -0x848(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x824(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <MD5_Final@plt>
  mov    -0x81c(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
L35:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
int mhash_with_size(const char *fpath, off_t fsize, unsigned char **mhash, size_t *mhash_size) {
  MD5_CTX ctx;
  unsigned char buf[2048];
  off_t na = fsize;
  int fd;
  fd = open(fpath, O_RDONLY);
  if (fd == -1) {
    *mhash = NULL;
    *mhash_size = 0;
    return -1;
  }
  MD5_Init(&ctx);
  *mhash_size = MD5_DIGEST_LENGTH;
  *mhash = malloc(*mhash_size);
  while (na > 0) {
    int n, d;
    d = (na < sizeof(buf) ? na : sizeof(buf));
    n = read(fd, buf, d);
    if (n <= 0) {
      break;
    }
    MD5_Update(&ctx, buf, n);
    na -= n;
  }
  MD5_Final(*mhash, &ctx);
  close(fd);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mhash_with_size>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x820,%rsp
  mov    %esi,%ebp
  mov    %rdx,%r14
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L35
  lea    0xc(%rsp),%rdi
  call   <MD5_Init@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%rdi
  mov    %rdi,(%rbx)
  call   <malloc@plt>
  mov    %rax,(%r14)
  test   %ebp,%ebp
  jle    L30
  mov    $0x800,%r13d
L23:
  cmp    $0x7ff,%ebp
  mov    %r13d,%edx
  cmovbe %ebp,%edx
  lea    0x10(%rsp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L30
  lea    0x10(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    %eax,%edx
  call   <MD5_Update@plt>
  sub    %ebx,%ebp
  test   %ebp,%ebp
  jg     L23
L30:
  lea    0xc(%rsp),%rsi
  mov    (%r14),%rdi
  call   <MD5_Final@plt>
  mov    %r12d,%edi
  call   <close@plt>
  mov    $0x0,%r12d
L55:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    %r12d,%eax
  add    $0x820,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  movq   $0x0,(%r14)
  movq   $0x0,(%rbx)
  jmp    L55
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mhash_with_size(const char *fpath, off_t fsize, unsigned char **mhash, size_t *mhash_size) {
  MD5_CTX ctx;
  unsigned char buf[2048];
  off_t na = fsize;
  int fd;
  fd = open(fpath, O_RDONLY);
  if (fd == -1) {
    *mhash = NULL;
    *mhash_size = 0;
    return -1;
  }
  MD5_Init(&ctx);
  *mhash_size = MD5_DIGEST_LENGTH;
  *mhash = malloc(*mhash_size);
  while (na > 0) {
    int n, d;
    d = (na < sizeof(buf) ? na : sizeof(buf));
    n = read(fd, buf, d);
    if (n <= 0) {
      break;
    }
    MD5_Update(&ctx, buf, n);
    na -= n;
  }
  MD5_Final(*mhash, &ctx);
  close(fd);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<mhash_with_size>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x838,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x828(%rsp)
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L57
  lea    0x1c(%rsp),%r13
  mov    %r13,%rdi
  call   <MD5_Init@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%rdi
  mov    %rdi,(%rbx)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x8(%rsp),%rax
  mov    %rdi,(%rax)
  test   %r15d,%r15d
  jle    L68
  lea    0x20(%rsp),%rbp
  mov    $0x800,%r14d
  jmp    L44
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %ebx,%r15d
  call   <MD5_Update@plt>
  test   %r15d,%r15d
  jle    L56
L44:
  cmp    $0x7ff,%r15d
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  cmovle %r15d,%edx
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L27
L56:
  mov    0x8(%rsp),%rax
  mov    (%rax),%rdi
L68:
  mov    %r13,%rsi
  call   <MD5_Final@plt>
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <close@plt>
L17:
  mov    0x828(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x838,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  mov    0x8(%rsp),%rax
  movq   $0x0,(%rax)
  movq   $0x0,(%rbx)
  jmp    L17
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mhash_with_size(const char *fpath, off_t fsize, unsigned char **mhash, size_t *mhash_size) {
  MD5_CTX ctx;
  unsigned char buf[2048];
  off_t na = fsize;
  int fd;
  fd = open(fpath, O_RDONLY);
  if (fd == -1) {
    *mhash = NULL;
    *mhash_size = 0;
    return -1;
  }
  MD5_Init(&ctx);
  *mhash_size = MD5_DIGEST_LENGTH;
  *mhash = malloc(*mhash_size);
  while (na > 0) {
    int n, d;
    d = (na < sizeof(buf) ? na : sizeof(buf));
    n = read(fd, buf, d);
    if (n <= 0) {
      break;
    }
    MD5_Update(&ctx, buf, n);
    na -= n;
  }
  MD5_Final(*mhash, &ctx);
  close(fd);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mhash_with_size>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x838,%rsp
  mov    %rdx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x828(%rsp)
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%r12d
  cmp    $0xffffffff,%eax
  je     L53
  lea    0x1c(%rsp),%r13
  mov    %r13,%rdi
  call   <MD5_Init@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%rdi
  mov    %rdi,(%rbx)
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    0x8(%rsp),%rax
  mov    %rdi,(%rax)
  test   %r15d,%r15d
  jle    L36
  lea    0x20(%rsp),%rbp
  mov    $0x800,%r14d
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L60:
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  sub    %ebx,%r15d
  call   <MD5_Update@plt>
  test   %r15d,%r15d
  jle    L24
L49:
  cmp    $0x7ff,%r15d
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  cmovle %r15d,%edx
  call   <read@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L60
L24:
  mov    0x8(%rsp),%rax
  mov    (%rax),%rdi
L36:
  mov    %r13,%rsi
  call   <MD5_Final@plt>
  mov    %r12d,%edi
  xor    %r12d,%r12d
  call   <close@plt>
L65:
  mov    0x828(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x838,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  mov    0x8(%rsp),%rax
  movq   $0x0,(%rax)
  movq   $0x0,(%rbx)
  jmp    L65
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mhash_with_size(const char *fpath, off_t fsize, unsigned char **mhash, size_t *mhash_size) {
  MD5_CTX ctx;
  unsigned char buf[2048];
  off_t na = fsize;
  int fd;
  fd = open(fpath, O_RDONLY);
  if (fd == -1) {
    *mhash = NULL;
    *mhash_size = 0;
    return -1;
  }
  MD5_Init(&ctx);
  *mhash_size = MD5_DIGEST_LENGTH;
  *mhash = malloc(*mhash_size);
  while (na > 0) {
    int n, d;
    d = (na < sizeof(buf) ? na : sizeof(buf));
    n = read(fd, buf, d);
    if (n <= 0) {
      break;
    }
    MD5_Update(&ctx, buf, n);
    na -= n;
  }
  MD5_Final(*mhash, &ctx);
  close(fd);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L5
L14:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L40
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,-0x10(%rbp)
  jmp    L5
L40:
  addl   $0x1,-0xc(%rbp)
L5:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jg     L14
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
type: string
name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D18: %d

tool: D12: %d=

tool: D3:  %d

assistant: ```c
int main() {
  int a, i = 2;
  scanf("%d", &a);
  printf("%d=", a);
  while (a > 1) {
    if (a % i == 0) {
      printf(" %d", i);
      a /= i;
    } else
      i++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jle    L40
  mov    $0x2,%ebx
  lea    D6(%rip),%rbp
  jmp    L20
L56:
  add    $0x1,%ebx
L47:
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  jle    L40
L20:
  cltd
  idiv   %ebx
  test   %edx,%edx
  jne    L56
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cltd
  idiv   %ebx
  mov    %eax,0x4(%rsp)
  jmp    L47
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
datatype: string
name: read_data
arguments: data_label: D24
datatype: string
name: read_data
arguments: data_label: D6
datatype: string

tool: D15: %d

tool: D24: %d=

tool: D6:  %d

assistant: ```c
int main() {
  int a, i = 2;
  scanf("%d", &a);
  printf("%d=", a);
  while (a > 1) {
    if (a % i == 0) {
      printf(" %d", i);
      a /= i;
    } else
      i++;
  }
  return 0;
}
```