user: 这段汇编代码用C语言表示是什么样的?

```asm
<_get_long_sub_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %esi,-0x9c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x8c(%rbp)
  movl   $0x0,-0x88(%rbp)
  movl   $0x0,-0x84(%rbp)
  movl   $0x0,-0x80(%rbp)
  lea    -0x70(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    -0x98(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x74(%rbp)
  movl   $0x0,-0x7c(%rbp)
  movl   $0x0,-0x78(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L87
L12:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  mov    -0x70(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L96
  addl   $0x1,-0x78(%rbp)
L96:
  addl   $0x1,-0x7c(%rbp)
L87:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L12
  mov    -0x78(%rbp),%eax
  cmp    -0x9c(%rbp),%eax
  jge    L28
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L28:
  movl   $0x0,-0x84(%rbp)
  movl   $0x1,-0x80(%rbp)
  movl   $0x0,-0x8c(%rbp)
  movl   $0x0,-0x88(%rbp)
  mov    -0x98(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  movl   $0x1,-0x7c(%rbp)
  jmp    L15
L90:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x88(%rbp)
  jmp    L45
L53:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0x70(%rbp,%rdx,4),%edx
  sub    $0x1,%edx
  cltq
  mov    %edx,-0x70(%rbp,%rax,4)
  addl   $0x1,-0x8c(%rbp)
L45:
  mov    -0x9c(%rbp),%edx
  lea    -0x70(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <is_valid@plt>
  test   %eax,%eax
  je     L53
  mov    -0x88(%rbp),%eax
  sub    -0x8c(%rbp),%eax
  cmp    %eax,-0x80(%rbp)
  jg     L73
  mov    -0x88(%rbp),%eax
  sub    -0x8c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x80(%rbp)
  mov    -0x8c(%rbp),%eax
  mov    %eax,-0x84(%rbp)
L73:
  addl   $0x1,-0x7c(%rbp)
L15:
  mov    -0x7c(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L90
  mov    -0x80(%rbp),%edx
  mov    -0x84(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x84(%rbp),%edx
  mov    -0x98(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string

tool: D10: 
 Error there are not enough unique characters in the string 

tool: D19: 
Max length sub str of %s starts from %d to %d

assistant: ```c
void _get_long_sub_str(char *str, int k) {
  int curr_start = 0, curr_end = 0, max_wind_start = 0, max_wind_size = 0;
  int count[26] = {};
  int len = strlen(str);
  int i = 0, unique = 0;
  for (i = 0; i < len; i++) {
    if (count[str[i] - 'a'] == 0) {
      unique++;
    }
  }
  if (unique < k) {
    printf("\n Error there are not enough unique characters in the string ");
    exit(-1);
  }
  max_wind_start = 0;
  max_wind_size = 1;
  curr_start = 0;
  curr_end = 0;
  count[str[0] - 'a']++;
  for (i = 1; i < len; i++) {
    count[str[i] - 'a']++;
    curr_end++;
    while (!is_valid(count, k)) {
      count[str[i] - 'a']--;
      curr_start++;
    }
    if ((curr_end - curr_start + 1) > max_wind_size) {
      max_wind_size = curr_end - curr_start + 1;
      max_wind_start = curr_start;
    }
  }
  printf("\nMax length sub str of %s starts from %d to %d", str, max_wind_start, max_wind_size + max_wind_start);
}
```