ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xfd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0xfcc(%rbp)
  jmp    L36
L28:
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfcc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xfcc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L21
  movss  -0xfc8(%rbp),%xmm1
  movss  D47(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xfc8(%rbp)
L21:
  mov    -0xfcc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jns    L55
  movss  -0xfc4(%rbp),%xmm1
  movss  D47(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xfc4(%rbp)
L55:
  mov    -0xfcc(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jne    L29
  movss  -0xfc0(%rbp),%xmm1
  movss  D47(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xfc0(%rbp)
L29:
  addl   $0x1,-0xfcc(%rbp)
L36:
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0xfcc(%rbp),%xmm1
  movss  -0xfd0(%rbp),%xmm0
  comiss %xmm1,%xmm0
  ja     L28
  movss  -0xfd0(%rbp),%xmm1
  movss  -0xfc8(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xfbc(%rbp)
  mov    -0xfbc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0xfd0(%rbp),%xmm1
  movss  -0xfc4(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xfb8(%rbp)
  mov    -0xfb8(%rbp),%eax
  movd   %eax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0xfd0(%rbp),%xmm1
  movss  -0xfc0(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xfb4(%rbp)
  mov    -0xfb4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D78
type: string
name: parse_data
arguments: tag: D68
type: string
name: parse_data
arguments: tag: D47
type: byte[4]
name: parse_data
arguments: tag: D2
type: string

tool: D78: %f

tool: D68: %d

tool: {"D47": [0x00,0x00,0x80,0x3f]}

tool: D2: %f


assistant: ```c
int main() {
  int i, a[1000];
  float n, x, y, z, c1, c2, c3;
  scanf("%f", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0) {
      x += 1;
    }
    if (a[i] < 0) {
      y += 1;
    }
    if (a[i] == 0) {
      z += 1;
    }
  }
  c1 = x / n;
  printf("%f\n", c1);
  c2 = y / n;
  printf("%f\n", c2);
  c3 = z / n;
  printf("%f\n", c3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D50(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  comiss D0(%rip),%xmm1
  jbe    L69
  lea    0x10(%rsp),%rbx
  mov    $0x0,%ebp
  lea    D60(%rip),%r12
  jmp    L7
L65:
  movd   %r14d,%xmm2
  addss  D11(%rip),%xmm2
  movd   %xmm2,%r14d
L30:
  add    $0x1,%ebp
  movss  0xc(%rsp),%xmm1
  add    $0x4,%rbx
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebp,%xmm0
  comiss %xmm0,%xmm1
  jbe    L69
L7:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L65
  jns    L24
  movd   %r13d,%xmm4
  addss  D11(%rip),%xmm4
  movd   %xmm4,%r13d
  jmp    L30
L24:
  jne    L30
  movd   %r15d,%xmm3
  addss  D11(%rip),%xmm3
  movd   %xmm3,%r15d
  jmp    L30
L69:
  movd   %r14d,%xmm0
  divss  %xmm1,%xmm0
  lea    D28(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  movd   %r13d,%xmm0
  divss  0xc(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  movd   %r15d,%xmm0
  divss  0xc(%rsp),%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D50
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: byte[4]
name: parse_data
arguments: data_tag: D60
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: byte[4]
name: parse_data
arguments: data_tag: D28
data_type: string

tool: D50: %f

tool: {"D0": [0x00,0x00,0x00,0x00]}

tool: D60: %d

tool: {"D11": [0x00,0x00,0x80,0x3f]}

tool: D28: %f


assistant: ```c
int main() {
  int i, a[1000];
  float n, x, y, z, c1, c2, c3;
  scanf("%f", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0) {
      x += 1;
    }
    if (a[i] < 0) {
      y += 1;
    }
    if (a[i] == 0) {
      z += 1;
    }
  }
  c1 = x / n;
  printf("%f\n", c1);
  c2 = y / n;
  printf("%f\n", c2);
  c3 = z / n;
  printf("%f\n", c3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D28(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  comiss D50(%rip),%xmm1
  jbe    L73
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D6(%rip),%r12
  jmp    L47
  nopl   0x0(%rax)
L53:
  movss  D55(%rip),%xmm2
  movd   %r14d,%xmm5
  addss  %xmm5,%xmm2
  movd   %xmm2,%r14d
L62:
  add    $0x1,%ebp
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  add    $0x4,%rbx
  cvtsi2ss %ebp,%xmm0
  comiss %xmm0,%xmm1
  jbe    L73
L47:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L53
  je     L32
  movss  D55(%rip),%xmm4
  movd   %r13d,%xmm7
  addss  %xmm7,%xmm4
  movd   %xmm4,%r13d
  jmp    L62
L32:
  movss  D55(%rip),%xmm3
  movd   %r15d,%xmm6
  addss  %xmm6,%xmm3
  movd   %xmm3,%r15d
  jmp    L62
  nopl   (%rax)
L73:
  movd   %r14d,%xmm0
  lea    D53(%rip),%rbp
  divss  %xmm1,%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  movd   %r13d,%xmm0
  divss  0xc(%rsp),%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  movd   %r15d,%xmm0
  divss  0xc(%rsp),%xmm0
  call   <printf@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D28
datatype: string
name: disassemble_data
arguments: label: D50
datatype: byte[4]
name: disassemble_data
arguments: label: D6
datatype: string
name: disassemble_data
arguments: label: D55
datatype: byte[4]
name: disassemble_data
arguments: label: D53
datatype: string

tool: D28: %f

tool: {"D50": [0x00,0x00,0x00,0x00]}

tool: D6: %d

tool: {"D55": [0x00,0x00,0x80,0x3f]}

tool: D53: %f


assistant: ```c
int main() {
  int i, a[1000];
  float n, x, y, z, c1, c2, c3;
  scanf("%f", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0) {
      x += 1;
    }
    if (a[i] < 0) {
      y += 1;
    }
    if (a[i] == 0) {
      z += 1;
    }
  }
  c1 = x / n;
  printf("%f\n", c1);
  c2 = y / n;
  printf("%f\n", c2);
  c3 = z / n;
  printf("%f\n", c3);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D22(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  comiss D6(%rip),%xmm1
  jbe    L3
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  lea    D43(%rip),%r12
  jmp    L51
  nopl   0x0(%rax)
L55:
  movss  D36(%rip),%xmm2
  movd   %r14d,%xmm5
  addss  %xmm5,%xmm2
  movd   %xmm2,%r14d
L61:
  add    $0x1,%ebp
  pxor   %xmm0,%xmm0
  movss  0xc(%rsp),%xmm1
  add    $0x4,%rbx
  cvtsi2ss %ebp,%xmm0
  comiss %xmm0,%xmm1
  jbe    L3
L51:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  jg     L55
  je     L28
  movss  D36(%rip),%xmm4
  movd   %r13d,%xmm7
  addss  %xmm7,%xmm4
  movd   %xmm4,%r13d
  jmp    L61
L28:
  movss  D36(%rip),%xmm3
  movd   %r15d,%xmm6
  addss  %xmm6,%xmm3
  movd   %xmm3,%r15d
  jmp    L61
  nopl   (%rax)
L3:
  movd   %r14d,%xmm0
  lea    D42(%rip),%rbp
  divss  %xmm1,%xmm0
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  movd   %r13d,%xmm0
  divss  0xc(%rsp),%xmm0
  call   <printf@plt>
  mov    %rbp,%rdi
  movd   %r15d,%xmm0
  divss  0xc(%rsp),%xmm0
  call   <printf@plt>
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0xfc8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: byte[4]
name: disassemble_data
arguments: data_tag: D43
data_type: string
name: disassemble_data
arguments: data_tag: D36
data_type: byte[4]
name: disassemble_data
arguments: data_tag: D42
data_type: string

tool: D22: %f

tool: {"D6": [0x00,0x00,0x00,0x00]}

tool: D43: %d

tool: {"D36": [0x00,0x00,0x80,0x3f]}

tool: D42: %f


assistant: ```c
int main() {
  int i, a[1000];
  float n, x, y, z, c1, c2, c3;
  scanf("%f", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
    if (a[i] > 0) {
      x += 1;
    }
    if (a[i] < 0) {
      y += 1;
    }
    if (a[i] == 0) {
      z += 1;
    }
  }
  c1 = x / n;
  printf("%f\n", c1);
  c2 = y / n;
  printf("%f\n", c2);
  c3 = z / n;
  printf("%f\n", c3);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<matprinter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L32:
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L34:
  mov    -0x14(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L34
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L32
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: %f 

assistant: ```c
void matprinter(int m, int n, double *x) {
  int i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%f ", x[i + m * j]);
    putchar('\n');
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<matprinter>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  test   %edi,%edi
  jle    L57
  mov    %esi,%r12d
  mov    %edi,%eax
  mov    %rax,0x8(%rsp)
  movslq %edi,%rdi
  lea    0x0(,%rdi,8),%r13
  mov    $0x0,%r15d
  lea    D4(%rip),%r14
  jmp    L9
L23:
  movsd  0x0(%rbp),%xmm0
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  add    %r13,%rbp
  cmp    %ebx,%r12d
  jne    L23
L28:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15
  cmp    0x8(%rsp),%r15
  je     L57
L9:
  mov    (%rsp),%rax
  lea    (%rax,%r15,8),%rbp
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L23
  jmp    L28
L57:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: %f 

assistant: ```c
void matprinter(int m, int n, double *x) {
  int i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%f ", x[i + m * j]);
    putchar('\n');
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<matprinter>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  test   %edi,%edi
  jle    L10
  movslq %edi,%rax
  mov    %esi,%ebx
  lea    D6(%rip),%rbp
  xor    %r13d,%r13d
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    (%rsp),%rax
  xor    %r14d,%r14d
  lea    (%rax,%r13,8),%r15
  test   %ebx,%ebx
  jle    L0
  nop
L24:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  add    $0x1,%r14d
  add    %r12,%r15
  call   <printf@plt>
  cmp    %r14d,%ebx
  jne    L24
L0:
  mov    $0xa,%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    0x8(%rsp),%r13
  jne    L37
L10:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: %f 

assistant: ```c
void matprinter(int m, int n, double *x) {
  int i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%f ", x[i + m * j]);
    putchar('\n');
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<matprinter>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,(%rsp)
  test   %edi,%edi
  jle    L9
  movslq %edi,%rax
  mov    %esi,%ebx
  lea    D4(%rip),%rbp
  xor    %r13d,%r13d
  mov    %rax,0x8(%rsp)
  lea    0x0(,%rax,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L38:
  mov    (%rsp),%rax
  xor    %r14d,%r14d
  lea    (%rax,%r13,8),%r15
  test   %ebx,%ebx
  jle    L31
  nop
L20:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  add    $0x1,%r14d
  add    %r12,%r15
  call   <printf@plt>
  cmp    %r14d,%ebx
  jne    L20
L31:
  mov    $0xa,%edi
  add    $0x1,%r13
  call   <putchar@plt>
  cmp    %r13,0x8(%rsp)
  jne    L38
L9:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %f 

assistant: ```c
void matprinter(int m, int n, double *x) {
  int i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%f ", x[i + m * j]);
    putchar('\n');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strswap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L1
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L6
  mov    -0x8(%rbp),%rax
  movzbl -0x20(%rbp),%edx
  mov    %dl,(%rax)
L6:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strswap(char *in, char from, char to) {
  char *p = in;
  while (*p) {
    if (*p == from)
      *p = to;
    p++;
  }
  return in;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strswap>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L8
  mov    %rdi,%rcx
  jmp    L6
L18:
  add    $0x1,%rcx
  movzbl (%rcx),%r8d
  test   %r8b,%r8b
  je     L8
L6:
  cmp    %r8b,%sil
  jne    L18
  mov    %dl,(%rcx)
  jmp    L18
L8:
  ret
```

assistant: ```c
char *strswap(char *in, char from, char to) {
  char *p = in;
  while (*p) {
    if (*p == from)
      *p = to;
    p++;
  }
  return in;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strswap>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L2
  mov    %rdi,%rcx
  nopl   0x0(%rax,%rax,1)
L26:
  cmp    %r8b,%sil
  jne    L9
  mov    %dl,(%rcx)
L9:
  movzbl 0x1(%rcx),%r8d
  add    $0x1,%rcx
  test   %r8b,%r8b
  jne    L26
L2:
  ret
```

assistant: ```c
char *strswap(char *in, char from, char to) {
  char *p = in;
  while (*p) {
    if (*p == from)
      *p = to;
    p++;
  }
  return in;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strswap>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L17
  mov    %rdi,%rcx
  nopl   0x0(%rax,%rax,1)
L29:
  cmp    %r8b,%sil
  je     L31
  movzbl 0x1(%rcx),%r8d
  add    $0x1,%rcx
  test   %r8b,%r8b
  jne    L29
L17:
  ret
  nopl   0x0(%rax)
L31:
  mov    %dl,(%rcx)
  movzbl 0x1(%rcx),%r8d
  add    $0x1,%rcx
  test   %r8b,%r8b
  jne    L29
  ret
```

assistant: ```c
char *strswap(char *in, char from, char to) {
  char *p = in;
  while (*p) {
    if (*p == from)
      *p = to;
    p++;
  }
  return in;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usd_get_completion_fd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L25
  cmpq   $0x0,-0x10(%rbp)
  jne    L4
L25:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L26
L4:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <usd_ib_cmd_create_comp_channel@plt>
L26:
  leave
  ret
```

assistant: ```c
int usd_get_completion_fd(struct usd_device *dev, int *comp_fd_o) {
  if (dev == NULL || comp_fd_o == NULL)
    return -EINVAL;
  return usd_ib_cmd_create_comp_channel(dev, comp_fd_o);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usd_get_completion_fd>:
  endbr64
  test   %rdi,%rdi
  je     L9
  test   %rsi,%rsi
  je     L9
  sub    $0x8,%rsp
  call   <usd_ib_cmd_create_comp_channel@plt>
  add    $0x8,%rsp
  ret
L9:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int usd_get_completion_fd(struct usd_device *dev, int *comp_fd_o) {
  if (dev == NULL || comp_fd_o == NULL)
    return -EINVAL;
  return usd_ib_cmd_create_comp_channel(dev, comp_fd_o);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usd_get_completion_fd>:
  endbr64
  test   %rdi,%rdi
  je     L6
  test   %rsi,%rsi
  je     L6
  jmp    1050 <usd_ib_cmd_create_comp_channel@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int usd_get_completion_fd(struct usd_device *dev, int *comp_fd_o) {
  if (dev == NULL || comp_fd_o == NULL)
    return -EINVAL;
  return usd_ib_cmd_create_comp_channel(dev, comp_fd_o);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usd_get_completion_fd>:
  endbr64
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  je     L10
  jmp    1050 <usd_ib_cmd_create_comp_channel@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  ret
```

assistant: ```c
int usd_get_completion_fd(struct usd_device *dev, int *comp_fd_o) {
  if (dev == NULL || comp_fd_o == NULL)
    return -EINVAL;
  return usd_ib_cmd_create_comp_channel(dev, comp_fd_o);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<y2doy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L10
  movl   $0x16e,-0x4(%rbp)
  jmp    L32
L10:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L0
  movl   $0x16d,-0x4(%rbp)
  jmp    L32
L0:
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L16
  movl   $0x16e,-0x4(%rbp)
  jmp    L32
L16:
  movl   $0x16d,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int y2doy(int y) {
  int doy;
  if ((y % 400) == 0) {
    doy = 366;
  } else if ((y % 100) == 0) {
    doy = 365;
  } else if ((y % 4) == 0) {
    doy = 366;
  } else {
    doy = 365;
  }
  return (doy);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<y2doy>:
  endbr64
  movslq %edi,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x27,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x190,%edx,%edx
  mov    $0x16e,%eax
  cmp    %edx,%edi
  je     L10
  movslq %edi,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x64,%edx,%edx
  mov    $0x16d,%eax
  cmp    %edx,%edi
  je     L10
  mov    %edi,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  mov    $0x16d,%eax
  adc    $0x0,%eax
L10:
  ret
```

assistant: ```c
int y2doy(int y) {
  int doy;
  if ((y % 400) == 0) {
    doy = 366;
  } else if ((y % 100) == 0) {
    doy = 365;
  } else if ((y % 4) == 0) {
    doy = 366;
  } else {
    doy = 365;
  }
  return (doy);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<y2doy>:
  endbr64
  imul   $0xc28f5c29,%edi,%edx
  mov    $0x16e,%eax
  add    $0x51eb850,%edx
  mov    %edx,%ecx
  ror    $0x4,%ecx
  cmp    $0xa3d70a,%ecx
  jbe    L18
  ror    $0x2,%edx
  mov    $0x16d,%eax
  cmp    $0x28f5c28,%edx
  ja     L16
L18:
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %edi,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  mov    $0x16d,%eax
  adc    $0x0,%eax
  ret
```

assistant: ```c
int y2doy(int y) {
  int doy;
  if ((y % 400) == 0) {
    doy = 366;
  } else if ((y % 100) == 0) {
    doy = 365;
  } else if ((y % 4) == 0) {
    doy = 366;
  } else {
    doy = 365;
  }
  return (doy);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<y2doy>:
  endbr64
  imul   $0xc28f5c29,%edi,%edx
  mov    $0x16e,%eax
  add    $0x51eb850,%edx
  mov    %edx,%ecx
  ror    $0x4,%ecx
  cmp    $0xa3d70a,%ecx
  jbe    L2
  ror    $0x2,%edx
  mov    $0x16d,%eax
  cmp    $0x28f5c28,%edx
  ja     L10
L2:
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %edi,%eax
  and    $0x3,%eax
  cmp    $0x1,%eax
  mov    $0x16d,%eax
  adc    $0x0,%eax
  ret
```

assistant: ```c
int y2doy(int y) {
  int doy;
  if ((y % 400) == 0) {
    doy = 366;
  } else if ((y % 100) == 0) {
    doy = 365;
  } else if ((y % 4) == 0) {
    doy = 366;
  } else {
    doy = 365;
  }
  return (doy);
}
```