ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_double>:
  endbr64
  test   %esi,%esi
  jle    L28
  push   %r15
  lea    D14(%rip),%r15
  xor    %edx,%edx
  xor    %eax,%eax
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  xor    %esi,%esi
  push   %r12
  mov    %rdi,%r12
  mov    %r15,%rdi
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L39:
  movsd  (%r12),%xmm0
  mov    %r14,%rdi
  add    $0x1,%ebp
  add    $0x8,%r12
  mov    $0x1,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x7,%ebp
  jg     L13
  cmp    %ebx,%r13d
  jg     L39
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %ebx,%r13d
  jle    L34
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %ebp,%ebp
  jmp    L39
L34:
  add    $0x8,%rsp
  lea    D21(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
L28:
  lea    D21(%rip),%rdi
  jmp    1080 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
type: string
name: disassemble_data
arguments: data_tag: D20
type: string
name: disassemble_data
arguments: data_tag: D21
type: string

tool: D14: %04X(%5d):	

tool: D20: %10.3f,

tool: 

assistant: ```c
void print_double(double *p, int n) {
  const int w = 8;
  int i = 0;
  while (i < n) {
    int j;
    printf("%04X(%5d):\t", i, i);
    for (j = 0; j < w && i < n; j++) {
      printf("%10.3f,", *p++);
      i++;
    }
    printf("\n");
  }
  puts("");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getLeapYears_Num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L38
L16:
  mov    -0x4(%rbp),%eax
  add    $0x7b2,%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L14
  mov    -0x4(%rbp),%eax
  lea    0x7b2(%rax),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L0
L14:
  mov    -0x4(%rbp),%eax
  lea    0x7b2(%rax),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L34
L0:
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x7b2,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  addl   $0x1,-0x4(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  sub    $0x7b1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L16
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string

tool: D14: 
Printing Leap Years Since 1970 ...... 
 	

tool: D16: %d 

assistant: ```c
int getLeapYears_Num(int currentYear) {
  printf("\nPrinting Leap Years Since 1970 ...... \n \t");
  int leapYears_Num = 0;
  for (int i = 0; i <= (currentYear - 1970); i++) {
    if (((1970 + i) % 4 == 0) && ((1970 + i) % 100 != 0) || ((1970 + i) % 400 == 0)) {
      leapYears_Num++;
      printf("%d ", 1970 + i);
    }
  }
  return leapYears_Num;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getLeapYears_Num>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x7b1,%r12d
  jle    L25
  mov    $0x7b2,%ebx
  mov    $0x0,%ebp
  lea    D4(%rip),%r13
  jmp    L30
L36:
  movslq %esi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %esi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%esi
  jne    L54
L15:
  add    $0x1,%ebp
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L54:
  lea    0x1(%rbx),%eax
  cmp    %ebx,%r12d
  je     L3
  mov    %eax,%ebx
L30:
  mov    %ebx,%esi
  test   $0x3,%bl
  jne    L36
  movslq %ebx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  cmp    %eax,%ebx
  jne    L15
  jmp    L36
L25:
  mov    $0x0,%ebp
L3:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D4
type_guessed: string

tool: D8: 
Printing Leap Years Since 1970 ...... 
 	

tool: D4: %d 

assistant: ```c
int getLeapYears_Num(int currentYear) {
  printf("\nPrinting Leap Years Since 1970 ...... \n \t");
  int leapYears_Num = 0;
  for (int i = 0; i <= (currentYear - 1970); i++) {
    if (((1970 + i) % 4 == 0) && ((1970 + i) % 100 != 0) || ((1970 + i) % 400 == 0)) {
      leapYears_Num++;
      printf("%d ", 1970 + i);
    }
  }
  return leapYears_Num;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getLeapYears_Num>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D10(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    $0x7b1,%ebp
  jle    L62
  mov    $0x7b2,%ebx
  xor    %r13d,%r13d
  lea    D5(%rip),%r12
  jmp    L58
  nopw   0x0(%rax,%rax,1)
L60:
  imul   $0xc28f5c29,%ebx,%eax
  ror    $0x2,%eax
  cmp    $0x28f5c28,%eax
  jbe    L64
L44:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  cmp    %ebp,%ebx
  je     L12
L16:
  mov    %eax,%ebx
L58:
  test   $0x3,%bl
  je     L60
L64:
  imul   $0xc28f5c29,%ebx,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L44
  lea    0x1(%rbx),%eax
  cmp    %ebp,%ebx
  jne    L16
L12:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type: string
name: read_data
arguments: data_tag: D5
type: string

tool: D10: 
Printing Leap Years Since 1970 ...... 
 	

tool: D5: %d 

assistant: ```c
int getLeapYears_Num(int currentYear) {
  printf("\nPrinting Leap Years Since 1970 ...... \n \t");
  int leapYears_Num = 0;
  for (int i = 0; i <= (currentYear - 1970); i++) {
    if (((1970 + i) % 4 == 0) && ((1970 + i) % 100 != 0) || ((1970 + i) % 400 == 0)) {
      leapYears_Num++;
      printf("%d ", 1970 + i);
    }
  }
  return leapYears_Num;
}
```
user: What is the c source code of the assembly code below:

```asm
<getLeapYears_Num>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  lea    D13(%rip),%rdi
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  cmp    $0x7b1,%ebp
  jle    L3
  mov    $0x7b2,%ebx
  xor    %r13d,%r13d
  lea    D17(%rip),%r12
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L49:
  imul   $0xc28f5c29,%ebx,%eax
  ror    $0x2,%eax
  cmp    $0x28f5c28,%eax
  jbe    L60
L38:
  mov    %ebx,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  lea    0x1(%rbx),%eax
  cmp    %ebp,%ebx
  je     L46
L54:
  mov    %eax,%ebx
L33:
  test   $0x3,%bl
  je     L49
L60:
  imul   $0xc28f5c29,%ebx,%eax
  ror    $0x4,%eax
  cmp    $0xa3d70a,%eax
  jbe    L38
  lea    0x1(%rbx),%eax
  cmp    %ebp,%ebx
  jne    L54
L46:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x8,%rsp
  xor    %r13d,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string

tool: D13: 
Printing Leap Years Since 1970 ...... 
 	

tool: D17: %d 

assistant: ```c
int getLeapYears_Num(int currentYear) {
  printf("\nPrinting Leap Years Since 1970 ...... \n \t");
  int leapYears_Num = 0;
  for (int i = 0; i <= (currentYear - 1970); i++) {
    if (((1970 + i) % 4 == 0) && ((1970 + i) % 100 != 0) || ((1970 + i) % 400 == 0)) {
      leapYears_Num++;
      printf("%d ", 1970 + i);
    }
  }
  return leapYears_Num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_pointer_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L15
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L15
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L41
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  movzbl -0x9(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L24
  jmp    L19
L15:
  nop
L19:
  leave
  ret
```

assistant: ```c
void test_pointer_string(char *c) {
  char temp, *end_ptr;
  if (c == NULL || !(*c))
    return;
  end_ptr = c + strlen(c) - 1;
  while (end_ptr > c) {
    temp = *c;
    *c = *end_ptr;
    *end_ptr = temp;
    c++;
    end_ptr--;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_pointer_string>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L25
L6:
  pop    %rbx
  ret
L25:
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jae    L6
L46:
  movzbl (%rbx),%edx
  movzbl (%rax),%ecx
  mov    %cl,(%rbx)
  mov    %dl,(%rax)
  add    $0x1,%rbx
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jb     L46
  jmp    L6
L18:
  ret
```

assistant: ```c
void test_pointer_string(char *c) {
  char temp, *end_ptr;
  if (c == NULL || !(*c))
    return;
  end_ptr = c + strlen(c) - 1;
  while (end_ptr > c) {
    temp = *c;
    *c = *end_ptr;
    *end_ptr = temp;
    c++;
    end_ptr--;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<test_pointer_string>:
  endbr64
  test   %rdi,%rdi
  je     L24
  cmpb   $0x0,(%rdi)
  push   %rbx
  mov    %rdi,%rbx
  jne    L6
L16:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jae    L16
  nopl   0x0(%rax)
L35:
  movzbl (%rbx),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rbx
  sub    $0x1,%rax
  mov    %cl,-0x1(%rbx)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rbx
  jb     L35
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  ret
```

assistant: ```c
void test_pointer_string(char *c) {
  char temp, *end_ptr;
  if (c == NULL || !(*c))
    return;
  end_ptr = c + strlen(c) - 1;
  while (end_ptr > c) {
    temp = *c;
    *c = *end_ptr;
    *end_ptr = temp;
    c++;
    end_ptr--;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<test_pointer_string>:
  endbr64
  test   %rdi,%rdi
  je     L14
  cmpb   $0x0,(%rdi)
  push   %rbx
  mov    %rdi,%rbx
  jne    L26
L22:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L26:
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jae    L22
  nopl   0x0(%rax)
L33:
  movzbl (%rbx),%edx
  movzbl (%rax),%ecx
  add    $0x1,%rbx
  sub    $0x1,%rax
  mov    %cl,-0x1(%rbx)
  mov    %dl,0x1(%rax)
  cmp    %rax,%rbx
  jb     L33
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  ret
```

assistant: ```c
void test_pointer_string(char *c) {
  char temp, *end_ptr;
  if (c == NULL || !(*c))
    return;
  end_ptr = c + strlen(c) - 1;
  while (end_ptr > c) {
    temp = *c;
    *c = *end_ptr;
    *end_ptr = temp;
    c++;
    end_ptr--;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<all_tcl_tests>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_tcl_comments@plt>
  mov    $0x0,%eax
  call   <test_tcl_comment_entities@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void all_tcl_tests() {
  test_tcl_comments();
  test_tcl_comment_entities();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<all_tcl_tests>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_tcl_comments@plt>
  mov    $0x0,%eax
  call   <test_tcl_comment_entities@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void all_tcl_tests() {
  test_tcl_comments();
  test_tcl_comment_entities();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<all_tcl_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_tcl_comments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <test_tcl_comment_entities@plt>
```

assistant: ```c
void all_tcl_tests() {
  test_tcl_comments();
  test_tcl_comment_entities();
}
```
user: What is the c source code of the assembly code below?

```asm
<all_tcl_tests>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_tcl_comments@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <test_tcl_comment_entities@plt>
```

assistant: ```c
void all_tcl_tests() {
  test_tcl_comments();
  test_tcl_comment_entities();
}
```
user: Translate the below assembly code into C programming language:

```asm
<IS_NAN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7f800000,%eax
  cmp    $0x7f800000,%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int IS_NAN(float x) {
  union {
    float f;
    int i;
  } num;
  num.f = x;
  return ((num.i & (255 << 23)) == (255 << 23));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<IS_NAN>:
  endbr64
  movd   %xmm0,%eax
  and    $0x7f800000,%eax
  cmp    $0x7f800000,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int IS_NAN(float x) {
  union {
    float f;
    int i;
  } num;
  num.f = x;
  return ((num.i & (255 << 23)) == (255 << 23));
}
```
user: Translate the below assembly code into C programming language:

```asm
<IS_NAN>:
  endbr64
  movd   %xmm0,-0x4(%rsp)
  mov    $0x7f800000,%eax
  and    -0x4(%rsp),%eax
  cmp    $0x7f800000,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int IS_NAN(float x) {
  union {
    float f;
    int i;
  } num;
  num.f = x;
  return ((num.i & (255 << 23)) == (255 << 23));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<IS_NAN>:
  endbr64
  movd   %xmm0,-0x4(%rsp)
  mov    $0x7f800000,%eax
  and    -0x4(%rsp),%eax
  cmp    $0x7f800000,%eax
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int IS_NAN(float x) {
  union {
    float f;
    int i;
  } num;
  num.f = x;
  return ((num.i & (255 << 23)) == (255 << 23));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test14_head>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D13
data_type: string
name: disassemble_data
arguments: tag: D7
data_type: string

tool: D13: test14

tool: 

assistant: ```c
void test14_head() {
  do {
    printf("test14");
    puts("");
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test14_head>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D17
data_type: string
name: unpack_data
arguments: label: D12
data_type: string

tool: D17: test14

tool: 

assistant: ```c
void test14_head() {
  do {
    printf("test14");
    puts("");
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test14_head>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D16: test14

tool: 

assistant: ```c
void test14_head() {
  do {
    printf("test14");
    puts("");
  } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test14_head>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D19
type_guessed: string
name: read_data
arguments: label: D12
type_guessed: string

tool: D19: test14

tool: 

assistant: ```c
void test14_head() {
  do {
    printf("test14");
    puts("");
  } while (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<_memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _memcpy(char *dest, const char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    dest[i] = src[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_memcpy>:
  endbr64
  test   %edx,%edx
  jle    L15
  mov    %edx,%edx
  mov    $0x0,%eax
L13:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L13
L15:
  ret
```

assistant: ```c
void _memcpy(char *dest, const char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    dest[i] = src[i];
}
```
user: Translate the below assembly code into C programming language:

```asm
<_memcpy>:
  endbr64
  test   %edx,%edx
  jle    L4
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L9:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L9
L4:
  ret
```

assistant: ```c
void _memcpy(char *dest, const char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    dest[i] = src[i];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L144
  lea    0x1(%rsi),%r9
  mov    %edx,%r8d
  lea    -0x1(%rdx),%eax
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L24
  cmp    $0x6,%eax
  jbe    L24
  cmp    $0xe,%eax
  jbe    L88
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L26:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L26
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L144
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L132
L43:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rcx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L144
L132:
  movslq %eax,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L144
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L144
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L144
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L144
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L144
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L144
  cltq
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L37:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L37
L144:
  ret
L88:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L43
```

assistant: ```c
void _memcpy(char *dest, const char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    dest[i] = src[i];
}
```
user: What is the c source code of the assembly code below:

```asm
<__kernel_sin>:
  endbr64
  movapd %xmm0,%xmm4
  mov    %edi,%edx
  movq   %xmm0,%rax
  sar    $0x20,%rax
  and    $0x7fffffff,%eax
  cmp    $0x3e3fffff,%eax
  jg     L21
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  je     L3
L21:
  movapd %xmm4,%xmm3
  mulsd  %xmm4,%xmm3
  movapd %xmm3,%xmm5
  mulsd  %xmm4,%xmm5
  movapd %xmm3,%xmm2
  mulsd  D73(%rip),%xmm2
  subsd  D19(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  D68(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  D45(%rip),%xmm2
  mulsd  %xmm3,%xmm2
  addsd  D79(%rip),%xmm2
  test   %edx,%edx
  jne    L19
  mulsd  %xmm2,%xmm3
  movapd %xmm3,%xmm0
  subsd  D75(%rip),%xmm0
  mulsd  %xmm5,%xmm0
  addsd  %xmm4,%xmm0
  ret
L19:
  movapd %xmm1,%xmm0
  mulsd  D48(%rip),%xmm0
  mulsd  %xmm5,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm3,%xmm0
  subsd  %xmm1,%xmm0
  mulsd  D75(%rip),%xmm5
  movapd %xmm0,%xmm1
  addsd  %xmm5,%xmm1
  subsd  %xmm1,%xmm4
  movapd %xmm4,%xmm0
L3:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D73
type_guessed: byte[8]
name: retrieve_data
arguments: label: D19
type_guessed: byte[8]
name: retrieve_data
arguments: label: D68
type_guessed: byte[8]
name: retrieve_data
arguments: label: D45
type_guessed: byte[8]
name: retrieve_data
arguments: label: D79
type_guessed: byte[8]
name: retrieve_data
arguments: label: D75
type_guessed: byte[8]
name: retrieve_data
arguments: label: D48
type_guessed: byte[8]

tool: {"D73": [0x7c,0xd5,0xcf,0x5a,0x3a,0xd9,0xe5,0x3d]}

tool: {"D19": [0xeb,0x9c,0x2b,0x8a,0xe6,0xe5,0x5a,0x3e]}

tool: {"D68": [0x7d,0xfe,0xb1,0x57,0xe3,0x1d,0xc7,0x3e]}

tool: {"D45": [0xd5,0x61,0xc1,0x19,0xa0,0x01,0x2a,0x3f]}

tool: {"D79": [0xa6,0xf8,0x10,0x11,0x11,0x11,0x81,0x3f]}

tool: {"D75": [0x49,0x55,0x55,0x55,0x55,0x55,0xc5,0x3f]}

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double __kernel_sin(double x, double y, int iy) {
  double z, r, v;
  int ix;
  ix = *(1 + (const int *)&x) & 0x7fffffff;
  if (ix < 0x3e400000) {
    if ((int)x == 0) {
      return x;
    }
  }
  z = x * x;
  v = z * x;
  r = 8.33333333332248946124e-03 + z * (-1.98412698298579493134e-04 + z * (2.75573137070700676789e-06 + z * (-2.50507602534068634195e-08 + z * 1.58969099521155010221e-10)));
  if (iy == 0) {
    return x + v * (-1.66666666666666324348e-01 + z * r);
  } else {
    return x - ((z * (5.00000000000000000000e-01 * y - v * r) - y) - v * -1.66666666666666324348e-01);
  }
}
```