ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<g>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x0,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <h@plt>
  mov    (%rsp),%edx
  mov    %eax,%ebx
  test   %edx,%edx
  jne    L22
L0:
  cmpl   $0x2,0x4(%rsp)
  je     L10
  xor    %eax,%eax
  call   <link_error@plt>
L10:
  mov    %ebx,%edi
  call   <g1@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jne    L23
L58:
  cmpl   $0x2,0x4(%rsp)
  je     L59
  xor    %eax,%eax
  call   <link_error@plt>
L59:
  xor    %eax,%eax
  cmp    $0x2,%ebx
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L63
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %eax,%eax
  call   <link_error@plt>
  jmp    L58
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  call   <link_error@plt>
  jmp    L0
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int g(void) {
  int t = 0, t1 = 2;
  int t2 = h(&t, &t1);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  g1(t2);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  return t2 == 2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<g>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  movl   $0x0,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <h@plt>
  mov    (%rsp),%edx
  mov    %eax,%ebx
  test   %edx,%edx
  jne    L61
L56:
  cmpl   $0x2,0x4(%rsp)
  je     L46
  xor    %eax,%eax
  call   <link_error@plt>
L46:
  mov    %ebx,%edi
  call   <g1@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jne    L68
L43:
  cmpl   $0x2,0x4(%rsp)
  je     L8
  xor    %eax,%eax
  call   <link_error@plt>
L8:
  xor    %eax,%eax
  cmp    $0x2,%ebx
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x10,%rsp
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
  call   <link_error@plt>
  jmp    L43
  nopl   0x0(%rax)
L61:
  xor    %eax,%eax
  call   <link_error@plt>
  jmp    L56
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int g(void) {
  int t = 0, t1 = 2;
  int t2 = h(&t, &t1);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  g1(t2);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  return t2 == 2;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<s2n_kyber_512_r3_sha3_512>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1d0,%rsp
  mov    %rdi,-0x1b8(%rbp)
  mov    %rsi,-0x1c0(%rbp)
  mov    %rdx,-0x1c8(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c8(%rbp),%rcx
  mov    -0x1c0(%rbp),%rdx
  lea    -0x1a0(%rbp),%rax
  mov    $0x6,%r8d
  mov    $0x48,%esi
  mov    %rax,%rdi
  call   <keccak_absorb@plt>
  lea    -0x1a0(%rbp),%rdx
  lea    -0x130(%rbp),%rax
  mov    $0x48,%ecx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <keccak_squeezeblocks@plt>
  movq   $0x0,-0x1a8(%rbp)
  jmp    L20
L14:
  mov    -0x1a8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x1b8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1a8(%rbp),%rax
  mov    -0x130(%rbp,%rax,4),%eax
  mov    %eax,(%rdx)
  addq   $0x1,-0x1a8(%rbp)
L20:
  cmpq   $0x3f,-0x1a8(%rbp)
  jbe    L14
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void s2n_kyber_512_r3_sha3_512(uint8_t *output, const uint8_t *input, size_t inlen) {
  uint64_t s[25];
  uint8_t t[72];
  keccak_absorb(s, 72, input, inlen, 0x06);
  keccak_squeezeblocks(t, 1, s, 72);
  for (size_t i = 0; i < 64; i++) {
    output[i] = t[i];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<s2n_kyber_512_r3_sha3_512>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x6,%r8d
  mov    %rsi,%rdx
  mov    $0x48,%esi
  mov    %rbp,%rdi
  call   <keccak_absorb@plt>
  lea    0x70(%rsp),%rdi
  mov    $0x48,%ecx
  mov    %rbp,%rdx
  mov    $0x1,%esi
  call   <keccak_squeezeblocks@plt>
  mov    $0x0,%eax
L9:
  mov    0x70(%rsp,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    $0x40,%rax
  jne    L9
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void s2n_kyber_512_r3_sha3_512(uint8_t *output, const uint8_t *input, size_t inlen) {
  uint64_t s[25];
  uint8_t t[72];
  keccak_absorb(s, 72, input, inlen, 0x06);
  keccak_squeezeblocks(t, 1, s, 72);
  for (size_t i = 0; i < 64; i++) {
    output[i] = t[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<s2n_kyber_512_r3_sha3_512>:
  endbr64
  push   %r12
  mov    %rdx,%rcx
  mov    $0x6,%r8d
  mov    %rsi,%rdx
  push   %rbx
  mov    $0x48,%esi
  mov    %rdi,%rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <keccak_absorb@plt>
  lea    0x70(%rsp),%rdi
  mov    $0x48,%ecx
  mov    %r12,%rdx
  mov    $0x1,%esi
  call   <keccak_squeezeblocks@plt>
  movdqa 0x70(%rsp),%xmm0
  movdqa 0x80(%rsp),%xmm1
  movdqa 0x90(%rsp),%xmm2
  movdqa 0xa0(%rsp),%xmm3
  movdqa 0xb0(%rsp),%xmm4
  movups %xmm0,(%rbx)
  movdqa 0xc0(%rsp),%xmm5
  movdqa 0xd0(%rsp),%xmm6
  movups %xmm1,0x10(%rbx)
  movdqa 0xe0(%rsp),%xmm7
  movdqa 0xf0(%rsp),%xmm0
  movups %xmm2,0x20(%rbx)
  movdqa 0x100(%rsp),%xmm1
  movdqa 0x110(%rsp),%xmm2
  movups %xmm3,0x30(%rbx)
  movdqa 0x120(%rsp),%xmm3
  movups %xmm4,0x40(%rbx)
  movdqa 0x130(%rsp),%xmm4
  movups %xmm5,0x50(%rbx)
  movdqa 0x140(%rsp),%xmm5
  movups %xmm6,0x60(%rbx)
  movdqa 0x150(%rsp),%xmm6
  movups %xmm7,0x70(%rbx)
  movdqa 0x160(%rsp),%xmm7
  movups %xmm0,0x80(%rbx)
  movups %xmm1,0x90(%rbx)
  movups %xmm2,0xa0(%rbx)
  movups %xmm3,0xb0(%rbx)
  movups %xmm4,0xc0(%rbx)
  movups %xmm5,0xd0(%rbx)
  movups %xmm6,0xe0(%rbx)
  movups %xmm7,0xf0(%rbx)
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void s2n_kyber_512_r3_sha3_512(uint8_t *output, const uint8_t *input, size_t inlen) {
  uint64_t s[25];
  uint8_t t[72];
  keccak_absorb(s, 72, input, inlen, 0x06);
  keccak_squeezeblocks(t, 1, s, 72);
  for (size_t i = 0; i < 64; i++) {
    output[i] = t[i];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<s2n_kyber_512_r3_sha3_512>:
  endbr64
  push   %r12
  mov    %rdx,%rcx
  mov    $0x6,%r8d
  mov    %rsi,%rdx
  push   %rbx
  mov    $0x48,%esi
  mov    %rdi,%rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <keccak_absorb@plt>
  lea    0x70(%rsp),%rdi
  mov    $0x48,%ecx
  mov    %r12,%rdx
  mov    $0x1,%esi
  call   <keccak_squeezeblocks@plt>
  movdqa 0x70(%rsp),%xmm0
  movdqa 0x80(%rsp),%xmm1
  movdqa 0x90(%rsp),%xmm2
  movdqa 0xa0(%rsp),%xmm3
  movdqa 0xb0(%rsp),%xmm4
  movups %xmm0,(%rbx)
  movdqa 0xc0(%rsp),%xmm5
  movdqa 0xd0(%rsp),%xmm6
  movups %xmm1,0x10(%rbx)
  movdqa 0xe0(%rsp),%xmm7
  movdqa 0xf0(%rsp),%xmm0
  movups %xmm2,0x20(%rbx)
  movdqa 0x100(%rsp),%xmm1
  movdqa 0x110(%rsp),%xmm2
  movups %xmm3,0x30(%rbx)
  movdqa 0x120(%rsp),%xmm3
  movups %xmm4,0x40(%rbx)
  movdqa 0x130(%rsp),%xmm4
  movups %xmm5,0x50(%rbx)
  movdqa 0x140(%rsp),%xmm5
  movups %xmm6,0x60(%rbx)
  movdqa 0x150(%rsp),%xmm6
  movups %xmm7,0x70(%rbx)
  movdqa 0x160(%rsp),%xmm7
  movups %xmm0,0x80(%rbx)
  movups %xmm1,0x90(%rbx)
  movups %xmm2,0xa0(%rbx)
  movups %xmm3,0xb0(%rbx)
  movups %xmm4,0xc0(%rbx)
  movups %xmm5,0xd0(%rbx)
  movups %xmm6,0xe0(%rbx)
  movups %xmm7,0xf0(%rbx)
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void s2n_kyber_512_r3_sha3_512(uint8_t *output, const uint8_t *input, size_t inlen) {
  uint64_t s[25];
  uint8_t t[72];
  keccak_absorb(s, 72, input, inlen, 0x06);
  keccak_squeezeblocks(t, 1, s, 72);
  for (size_t i = 0; i < 64; i++) {
    output[i] = t[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<guard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L27
  mov    -0x8(%rbp),%eax
  jmp    L34
L27:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L28
  mov    -0xc(%rbp),%eax
  jmp    L34
L28:
  mov    -0x4(%rbp),%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int guard(int x, int min, int max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<guard>:
  endbr64
  cmp    %edx,%edi
  cmovle %edi,%edx
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int guard(int x, int min, int max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<guard>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int guard(int x, int min, int max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<guard>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int guard(int x, int min, int max) {
  if (x < min)
    return min;
  if (x > max)
    return max;
  return x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getc_asciiz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int getc_asciiz(void *context) {
  unsigned char **c = (unsigned char **)context;
  return *(*c)++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getc_asciiz>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%eax
  ret
```

assistant: ```c
int getc_asciiz(void *context) {
  unsigned char **c = (unsigned char **)context;
  return *(*c)++;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getc_asciiz>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%eax
  ret
```

assistant: ```c
int getc_asciiz(void *context) {
  unsigned char **c = (unsigned char **)context;
  return *(*c)++;
}
```
user: What is the c source code of the assembly code below?

```asm
<getc_asciiz>:
  endbr64
  mov    (%rdi),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rdi)
  movzbl (%rax),%eax
  ret
```

assistant: ```c
int getc_asciiz(void *context) {
  unsigned char **c = (unsigned char **)context;
  return *(*c)++;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4c4000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0xb50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int main(void) {
  char huge_block[5000 * 1000];
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(void) {
  char huge_block[5000 * 1000];
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char huge_block[5000 * 1000];
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char huge_block[5000 * 1000];
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getchar1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  jmp    L3
L27:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  mov    -0x10(%rbp),%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
L3:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L32
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <getc@plt>
  mov    %eax,-0x10(%rbp)
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  je     L32
  cmpl   $0xa,-0x10(%rbp)
  jne    L27
L32:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  movzbl -0x9(%rbp),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int getchar1(void) {
  char s[1];
  int c, i = 0, maxLength = 2;
  while ((--maxLength > 0) && ((c = getc(stdin)) != EOF) && (c != '\n'))
    s[i++] = c;
  fflush(stdin);
  return s[0];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getchar1>:
  endbr64
  push   %rbx
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <getc@plt>
  mov    D6(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L2
  cmp    $0xa,%eax
  mov    $0x0,%ebx
  cmovne %eax,%ebx
L2:
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <fflush@plt>
  movsbl %bl,%eax
  pop    %rbx
  ret
```

assistant: ```c
int getchar1(void) {
  char s[1];
  int c, i = 0, maxLength = 2;
  while ((--maxLength > 0) && ((c = getc(stdin)) != EOF) && (c != '\n'))
    s[i++] = c;
  fflush(stdin);
  return s[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getchar1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D15(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <getc@plt>
  mov    D9(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L0
  xor    %ebx,%ebx
  cmp    $0xa,%eax
  cmovne %eax,%ebx
L0:
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  add    $0x8,%rsp
  movsbl %bl,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int getchar1(void) {
  char s[1];
  int c, i = 0, maxLength = 2;
  while ((--maxLength > 0) && ((c = getc(stdin)) != EOF) && (c != '\n'))
    s[i++] = c;
  fflush(stdin);
  return s[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getchar1>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    D13(%rip),%rbp
  mov    0x0(%rbp),%edi
  call   <getc@plt>
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L8
  xor    %ebx,%ebx
  cmp    $0xa,%eax
  cmovne %eax,%ebx
L8:
  mov    0x0(%rbp),%edi
  call   <fflush@plt>
  add    $0x8,%rsp
  movsbl %bl,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int getchar1(void) {
  char s[1];
  int c, i = 0, maxLength = 2;
  while ((--maxLength > 0) && ((c = getc(stdin)) != EOF) && (c != '\n'))
    s[i++] = c;
  fflush(stdin);
  return s[0];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D2: %d 


assistant: ```c
int main1() {
  for (;;) {
    printf("%d \n", clock());
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main1>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
L6:
  mov    $0x0,%eax
  call   <clock@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: %d 


assistant: ```c
int main1() {
  for (;;) {
    printf("%d \n", clock());
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main1>:
  endbr64
  push   %rbx
  lea    D9(%rip),%rbx
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <clock@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D9: %d 


assistant: ```c
int main1() {
  for (;;) {
    printf("%d \n", clock());
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main1>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rbx
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  call   <clock@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: %d 


assistant: ```c
int main1() {
  for (;;) {
    printf("%d \n", clock());
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %rsi,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L13:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x111(%rbp)
  cmpb   $0x2f,-0x111(%rbp)
  jle    L18
  cmpb   $0x39,-0x111(%rbp)
  jg     L18
  movzbl -0x111(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x111(%rbp)
  movsbl -0x111(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L11
L18:
  mov    $0x78,%edi
  call   <putchar@plt>
L11:
  jmp    L13
```

assistant: ```c
int main(int argc, char **argv) {
  char buff[255];
  char c;
  int f, t;
  int x;
  while (1) {
    c = getchar();
    if ((c >= '0') && (c <= '9'))
      putchar(++c);
    else
      putchar('x');
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  jmp    L20
L24:
  add    $0x1,%eax
  movsbl %al,%edi
  call   <putchar@plt>
L20:
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L24
  mov    $0x78,%edi
  call   <putchar@plt>
  jmp    L20
```

assistant: ```c
int main(int argc, char **argv) {
  char buff[255];
  char c;
  int f, t;
  int x;
  while (1) {
    c = getchar();
    if ((c >= '0') && (c <= '9'))
      putchar(++c);
    else
      putchar('x');
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L26
L27:
  add    $0x1,%eax
  movzbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L27
L26:
  mov    $0x78,%edi
  call   <putchar@plt>
  jmp    L13
```

assistant: ```c
int main(int argc, char **argv) {
  char buff[255];
  char c;
  int f, t;
  int x;
  while (1) {
    c = getchar();
    if ((c >= '0') && (c <= '9'))
      putchar(++c);
    else
      putchar('x');
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L22
L25:
  add    $0x1,%eax
  movzbl %al,%edi
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L25
L22:
  mov    $0x78,%edi
  call   <putchar@plt>
  jmp    L0
```

assistant: ```c
int main(int argc, char **argv) {
  char buff[255];
  char c;
  int f, t;
  int x;
  while (1) {
    c = getchar();
    if ((c >= '0') && (c <= '9'))
      putchar(++c);
    else
      putchar('x');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<inststr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r12
  mov    %rdx,%r14
  mov    %rcx,%r13
  mov    %rcx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    (%r12),%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jg     L104
  mov    (%r12),%rax
  cmpb   $0x0,(%rax)
  je     L54
L114:
  add    $0x1,%rax
  movb   $0x0,-0x1(%rax)
  cmpb   $0x0,(%rax)
  jne    L114
L54:
  mov    %r13,%rsi
  mov    (%r12),%rdi
  call   <strcpy@plt>
L142:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L104:
  mov    (%r12),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  cmp    $0x1,%r15d
  jle    L156
  lea    0x8(%r12),%rbx
  lea    -0x2(%r15),%eax
  lea    0x10(%r12,%rax,8),%r15
  jmp    L18
L29:
  add    $0x8,%rbx
  cmp    %r15,%rbx
  je     L156
L18:
  lea    0x1(%rbp),%rdi
  cmp    %rdi,(%rbx)
  jne    L29
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  jmp    L29
L156:
  mov    (%r14),%rax
  lea    0x1(%rbp),%rdx
  cmp    %rdx,%rax
  je     L117
L140:
  mov    (%r12),%rcx
  cmp    %rcx,%rbp
  jb     L2
  lea    0x1(%rbp),%rdx
  mov    %rcx,%rax
L121:
  movb   $0x0,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L121
  sub    %rcx,%rbp
  lea    0x1(%rbp),%edx
L78:
  mov    %r13,%rsi
  mov    (%r12),%rdi
  call   <strncpy@plt>
  jmp    L142
L117:
  add    $0x8,%r14
  jmp    L135
L119:
  add    $0x8,%r14
  mov    -0x8(%r14),%rax
  test   %rax,%rax
  je     L140
L135:
  lea    0x1(%rbp),%rdi
  cmp    %rax,%rdi
  jne    L119
  call   <strlen@plt>
  cltq
  add    %rax,%rbp
  jmp    L119
L2:
  mov    $0x0,%edx
  jmp    L78
```

assistant: ```c
void inststr(int argc, char **argv, char **environ, char *src) {
  if (strlen(src) <= strlen(argv[0])) {
    char *ptr;
    for (ptr = argv[0]; *ptr; *(ptr++) = '\0')
      ;
    strcpy(argv[0], src);
  } else {
    char *ptr, *ptr2;
    int count;
    ptr = argv[0] + strlen(argv[0]);
    for (count = 1; count < argc; count++) {
      if (argv[count] == ptr + 1)
        ptr += strlen(ptr + 1);
    }
    if (environ[0] == ptr + 1) {
      for (count = 0; environ[count]; count++)
        if (environ[count] == ptr + 1)
          ptr += strlen(ptr + 1);
    }
    count = 0;
    for (ptr2 = argv[0]; ptr2 <= ptr; ptr2++) {
      *ptr2 = '\0';
      count++;
    }
    strncpy(argv[0], src, count);
  }
}
```