ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D56
datatype: string
name: unpack_data
arguments: label: D59
datatype: string
name: unpack_data
arguments: label: D2
datatype: string
name: unpack_data
arguments: label: D21
datatype: string
name: unpack_data
arguments: label: D22
datatype: string
name: unpack_data
arguments: label: D30
datatype: string

tool: D56: In c programing language the character data type always take up 1 byte 
but other variable like int ,float, double may take up different valued from system to system.

tool: D59: 
 lets find out the sizes for each data type using sizeof(operand) function.

tool: D2: The size of char is %d bytes. 


tool: D21: The size of int variables is %d bytes. 


tool: D22: The size of float variables is %d bytes. 


tool: D30: The size of double variable is %d bytes. 


assistant: ```c
int main() {
  printf("In c programing language the character data type always take up 1 byte \nbut other variable like int ,float, double may take up different valued from system to system.");
  printf("\n lets find out the sizes for each data type using sizeof(operand) function.\n");
  printf("The size of char is %d bytes. \n", sizeof(char));
  printf("The size of int variables is %d bytes. \n", sizeof(int));
  printf("The size of float variables is %d bytes. \n", sizeof(float));
  printf("The size of double variable is %d bytes. \n", sizeof(double));
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D42
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D28
type_guessed: string
name: disassemble_data
arguments: tag: D14
type_guessed: string
name: disassemble_data
arguments: tag: D56
type_guessed: string
name: disassemble_data
arguments: tag: D33
type_guessed: string

tool: D42: In c programing language the character data type always take up 1 byte 
but other variable like int ,float, double may take up different valued from system to system.

tool: D12: 
 lets find out the sizes for each data type using sizeof(operand) function.

tool: D28: The size of char is %d bytes. 


tool: D14: The size of int variables is %d bytes. 


tool: D56: The size of float variables is %d bytes. 


tool: D33: The size of double variable is %d bytes. 


assistant: ```c
int main() {
  printf("In c programing language the character data type always take up 1 byte \nbut other variable like int ,float, double may take up different valued from system to system.");
  printf("\n lets find out the sizes for each data type using sizeof(operand) function.\n");
  printf("The size of char is %d bytes. \n", sizeof(char));
  printf("The size of int variables is %d bytes. \n", sizeof(int));
  printf("The size of float variables is %d bytes. \n", sizeof(float));
  printf("The size of double variable is %d bytes. \n", sizeof(double));
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D14
datatype: string
name: read_data
arguments: tag: D16
datatype: string

tool: D14: %i %i

tool: D16: %i

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  scanf("%i %i", &a, &b);
  printf("%i", a * b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string
name: retrieve_data
arguments: data_label: D3
type: string

tool: D6: %i %i

tool: D3: %i

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  scanf("%i %i", &a, &b);
  printf("%i", a * b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D12
type: string

tool: D17: %i %i

tool: D12: %i

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  scanf("%i %i", &a, &b);
  printf("%i", a * b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%esi
  imul   0x4(%rsp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string
name: unpack_data
arguments: data_tag: D17
type_infered: string

tool: D7: %i %i

tool: D17: %i

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  scanf("%i %i", &a, &b);
  printf("%i", a * b);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ambapp_has_been_scanned>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L17
  mov    $0x0,%eax
  jmp    L45
L17:
  movl   $0x0,-0x4(%rbp)
  jmp    L65
L36:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L50
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  jne    L59
  mov    $0x1,%eax
  jmp    L45
L59:
  addl   $0x1,-0x4(%rbp)
L65:
  cmpl   $0xf,-0x4(%rbp)
  jle    L36
  jmp    L29
L50:
  nop
L29:
  mov    $0x0,%eax
L45:
  pop    %rbp
  ret
```

assistant: ```c
int ambapp_has_been_scanned(unsigned int *ioareas, unsigned int ioarea) {
  int i;
  if (!ioareas)
    return 0;
  for (i = 0; i < 16; i++) {
    if (ioareas[i] == 0) {
      break;
    } else if (ioareas[i] == ioarea) {
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ambapp_has_been_scanned>:
  endbr64
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rax
  add    $0x40,%rdi
L35:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L5
  cmp    %esi,%edx
  je     L1
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L35
  mov    $0x0,%eax
  ret
L0:
  mov    $0x0,%eax
  ret
L5:
  mov    $0x0,%eax
  ret
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ambapp_has_been_scanned(unsigned int *ioareas, unsigned int ioarea) {
  int i;
  if (!ioareas)
    return 0;
  for (i = 0; i < 16; i++) {
    if (ioareas[i] == 0) {
      break;
    } else if (ioareas[i] == ioarea) {
      return 1;
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ambapp_has_been_scanned>:
  endbr64
  test   %rdi,%rdi
  je     L7
  lea    0x40(%rdi),%rdx
  nopl   (%rax)
L33:
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L7
  cmp    %esi,%eax
  je     L18
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L33
L7:
  xor    %eax,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ambapp_has_been_scanned(unsigned int *ioareas, unsigned int ioarea) {
  int i;
  if (!ioareas)
    return 0;
  for (i = 0; i < 16; i++) {
    if (ioareas[i] == 0) {
      break;
    } else if (ioareas[i] == ioarea) {
      return 1;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ambapp_has_been_scanned>:
  endbr64
  test   %rdi,%rdi
  je     L195
  mov    (%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x4(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x8(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0xc(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x10(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x14(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x18(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x1c(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x20(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x24(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x28(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x2c(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x30(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x34(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x38(%rdi),%ecx
  test   %ecx,%ecx
  je     L195
  cmp    %ecx,%esi
  je     L228
  mov    0x3c(%rdi),%eax
  test   %eax,%eax
  je     L195
  cmp    %esi,%eax
  sete   %al
  movzbl %al,%eax
  ret
  nopl   (%rax)
L228:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L195:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ambapp_has_been_scanned(unsigned int *ioareas, unsigned int ioarea) {
  int i;
  if (!ioareas)
    return 0;
  for (i = 0; i < 16; i++) {
    if (ioareas[i] == 0) {
      break;
    } else if (ioareas[i] == ioarea) {
      return 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b | a;
  return tem1 + tem2;
}
```
user: What is the c source code of the assembly code below?

```asm
<fn3>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b | a;
  return tem1 + tem2;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fn3>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b | a;
  return tem1 + tem2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fn3>:
  endbr64
  lea    (%rdi,%rsi,1),%eax
  ret
```

assistant: ```c
int fn3(int a, int b) {
  int tem1 = a & b;
  int tem2 = b | a;
  return tem1 + tem2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_ascii_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %eax,%eax
  jne    L10
  mov    $0x0,%eax
  jmp    L4
L10:
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L27
  mov    $0x1,%eax
L4:
  leave
  ret
```

assistant: ```c
int is_ascii_buf(const char *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (!isascii(buf[i]))
      return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<is_ascii_buf>:
  endbr64
  test   %esi,%esi
  jle    L24
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rbp
L4:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  test   %eax,%eax
  je     L12
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L4
  mov    $0x1,%eax
L12:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_ascii_buf(const char *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (!isascii(buf[i]))
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_ascii_buf>:
  endbr64
  test   %esi,%esi
  jle    L13
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L39
L29:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  test   %eax,%eax
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L39:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_ascii_buf(const char *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (!isascii(buf[i]))
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_ascii_buf>:
  endbr64
  test   %esi,%esi
  jle    L36
  push   %rbp
  lea    -0x1(%rsi),%eax
  push   %rbx
  lea    0x1(%rdi,%rax,1),%rbp
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L30
L11:
  movsbl (%rbx),%edi
  call   <isascii@plt>
  test   %eax,%eax
  jne    L31
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L30:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
L36:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int is_ascii_buf(const char *buf, int len) {
  int i;
  for (i = 0; i < len; i++) {
    if (!isascii(buf[i]))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<re_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9,-0x28(%rbp)
  mov    -0x18(%rbp),%edi
  mov    -0x14(%rbp),%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  mov    -0x14(%rbp),%ecx
  push   %rcx
  push   -0x28(%rbp)
  mov    -0x1c(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %rdx,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <re_search_2@plt>
  add    $0x20,%rsp
  leave
  ret
```

assistant: ```c
int re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return re_search_2(bufp, 0, 0, string, size, startpos, range, regs, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<re_search>:
  endbr64
  sub    $0x10,%rsp
  push   %rdx
  push   %r9
  push   %r8
  mov    %ecx,%r9d
  mov    %edx,%r8d
  mov    %rsi,%rcx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%eax
  call   <re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return re_search_2(bufp, 0, 0, string, size, startpos, range, regs, size);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<re_search>:
  endbr64
  sub    $0x10,%rsp
  xor    %eax,%eax
  push   %rdx
  push   %r9
  mov    %ecx,%r9d
  mov    %rsi,%rcx
  xor    %esi,%esi
  push   %r8
  mov    %edx,%r8d
  xor    %edx,%edx
  call   <re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return re_search_2(bufp, 0, 0, string, size, startpos, range, regs, size);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<re_search>:
  endbr64
  sub    $0x10,%rsp
  xor    %eax,%eax
  push   %rdx
  push   %r9
  mov    %ecx,%r9d
  mov    %rsi,%rcx
  xor    %esi,%esi
  push   %r8
  mov    %edx,%r8d
  xor    %edx,%edx
  call   <re_search_2@plt>
  add    $0x28,%rsp
  ret
```

assistant: ```c
int re_search(bufp, string, size, startpos, range, regs)
struct re_pattern_buffer *bufp;
const char *string;
int size, startpos, range;
struct re_registers *regs;
{
  return re_search_2(bufp, 0, 0, string, size, startpos, range, regs, size);
}
```
user: What is the c source code of the assembly code below?

```asm
<az_count_doubles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L2:
  addl   $0x1,-0x4(%rbp)
  addl   $0x2,-0x1c(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x20(%rbp)
  jle    L17
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  je     L38
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2c,%al
  jne    L17
L38:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L2
L17:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int az_count_doubles(const unsigned char source[], int i, const int length) {
  int c = 0;
  while ((i + 1 < length) && ((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
    c++;
    i += 2;
  }
  return c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<az_count_doubles>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jle    L40
  movslq %esi,%rax
  add    %rax,%rdi
  lea    -0x2(%rdx),%ecx
  sub    %esi,%ecx
  shr    %ecx
  add    $0x1,%ecx
  mov    $0x0,%edx
L22:
  movzbl (%rdi),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  jne    L14
  cmpb   $0x20,0x1(%rdi)
  jne    L14
  add    $0x1,%edx
  add    $0x2,%rdi
  cmp    %ecx,%edx
  jne    L22
  mov    %ecx,%edx
L14:
  mov    %edx,%eax
  ret
L40:
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
int az_count_doubles(const unsigned char source[], int i, const int length) {
  int c = 0;
  while ((i + 1 < length) && ((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
    c++;
    i += 2;
  }
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<az_count_doubles>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jle    L25
  sub    $0x2,%edx
  movslq %esi,%rax
  xor    %r8d,%r8d
  sub    %esi,%edx
  add    %rax,%rdi
  shr    %edx
  add    $0x1,%edx
  jmp    L10
L29:
  cmpb   $0x20,0x1(%rdi)
  jne    L27
  add    $0x1,%r8d
  add    $0x2,%rdi
  cmp    %edx,%r8d
  je     L27
L10:
  movzbl (%rdi),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  je     L29
L27:
  mov    %r8d,%eax
  ret
L25:
  xor    %r8d,%r8d
  jmp    L27
```

assistant: ```c
int az_count_doubles(const unsigned char source[], int i, const int length) {
  int c = 0;
  while ((i + 1 < length) && ((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
    c++;
    i += 2;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<az_count_doubles>:
  endbr64
  lea    0x1(%rsi),%eax
  cmp    %eax,%edx
  jle    L17
  sub    $0x2,%edx
  movslq %esi,%rax
  xor    %r8d,%r8d
  sub    %esi,%edx
  add    %rax,%rdi
  shr    %edx
  add    $0x1,%edx
  jmp    L14
L29:
  cmpb   $0x20,0x1(%rdi)
  jne    L4
  add    $0x1,%r8d
  add    $0x2,%rdi
  cmp    %r8d,%edx
  je     L4
L14:
  movzbl (%rdi),%eax
  and    $0xfffffffd,%eax
  cmp    $0x2c,%al
  je     L29
L4:
  mov    %r8d,%eax
  ret
L17:
  xor    %r8d,%r8d
  jmp    L4
```

assistant: ```c
int az_count_doubles(const unsigned char source[], int i, const int length) {
  int c = 0;
  while ((i + 1 < length) && ((source[i] == '.') || (source[i] == ',')) && (source[i + 1] == ' ')) {
    c++;
    i += 2;
  }
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<DoMessageModeKey>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  jne    L1
  mov    $0x0,%eax
  call   <MacMsgDisplayOff@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void DoMessageModeKey(int key) {
  if (0x08 == key) {
    MacMsgDisplayOff();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<DoMessageModeKey>:
  endbr64
  cmp    $0x8,%edi
  je     L0
  ret
L0:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <MacMsgDisplayOff@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void DoMessageModeKey(int key) {
  if (0x08 == key) {
    MacMsgDisplayOff();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<DoMessageModeKey>:
  endbr64
  cmp    $0x8,%edi
  je     L8
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  jmp    1050 <MacMsgDisplayOff@plt>
```

assistant: ```c
void DoMessageModeKey(int key) {
  if (0x08 == key) {
    MacMsgDisplayOff();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<DoMessageModeKey>:
  endbr64
  cmp    $0x8,%edi
  je     L4
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  jmp    1050 <MacMsgDisplayOff@plt>
```

assistant: ```c
void DoMessageModeKey(int key) {
  if (0x08 == key) {
    MacMsgDisplayOff();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sig_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string

tool: D7: catch SIGXFSZ


assistant: ```c
void sig_int(int signo) {
  printf("catch SIGXFSZ\n");
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sig_int>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: string

tool: D2: catch SIGXFSZ


assistant: ```c
void sig_int(int signo) {
  printf("catch SIGXFSZ\n");
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sig_int>:
  endbr64
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: catch SIGXFSZ


assistant: ```c
void sig_int(int signo) {
  printf("catch SIGXFSZ\n");
  return;
}
```