ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rdx
  add    $0x136ff696,%rdx
  mov    %rdx,%rax
  mov    %rdx,%rsi
  shr    $0x30,%rsi
  mov    %si,%ax
  shl    $0x30,%rdx
  movabs $0xffffffffffff,%rsi
  and    %rsi,%rax
  or     %rax,%rdx
  mov    %rdx,%rax
  je     L2
  mov    %rdx,%rsi
  shl    $0x18,%rsi
  sar    $0x38,%rsi
  mov    %sil,%al
  movzbl %dl,%edx
  shl    $0x20,%rdx
  movabs $0xffffff00ffffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
  mov    %rax,%rdx
  shl    $0x10,%rdx
  mov    %rax,%rsi
  shr    $0x38,%rsi
  shl    $0x28,%rsi
  movabs $0xffff00ffffffffff,%rdi
  and    %rdi,%rax
  or     %rsi,%rax
  shr    $0x38,%rdx
  shl    $0x38,%rdx
  movabs $0xffffffffffffff,%rsi
  and    %rsi,%rax
  or     %rdx,%rax
L2:
  add    $0x32060f04,%rax
  mov    %rax,(%rcx)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffffffffff,%r8
  mov    (%rdi),%rdx
  add    $0x136ff696,%rdx
  mov    %rdx,%rcx
  mov    %rdx,%rax
  mov    %rdx,%rdi
  shr    $0x30,%rcx
  shl    $0x30,%rdi
  mov    %cx,%ax
  and    %r8,%rax
  or     %rdi,%rax
  mov    %rax,%rdi
  je     L5
  mov    %rdx,%rdi
  movzbl %cl,%ecx
  shl    $0x18,%rdi
  shl    $0x20,%rcx
  sar    $0x38,%rdi
  mov    %dil,%al
  movabs $0xffffff00ffffffff,%rdi
  and    %rdi,%rax
  movabs $0xffff00ffffffffff,%rdi
  or     %rcx,%rax
  movzbl %dh,%ecx
  shl    $0x10,%rdx
  shl    $0x28,%rcx
  and    %rdi,%rax
  shr    $0x38,%rdx
  or     %rcx,%rax
  shl    $0x38,%rdx
  movabs $0xffffffffffffff,%rcx
  and    %rcx,%rax
  or     %rdx,%rax
  mov    %rax,%rdi
L5:
  add    $0x32060f04,%rdi
  mov    %rdi,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movabs $0xffffffffffff,%r8
  mov    (%rdi),%rax
  add    $0x136ff696,%rax
  mov    %rax,%rcx
  mov    %rax,%rdx
  shr    $0x30,%rcx
  mov    %cx,%dx
  mov    %ecx,%edi
  mov    %rax,%rcx
  shl    $0x30,%rcx
  and    %r8,%rdx
  or     %rcx,%rdx
  mov    %rdx,%rcx
  je     L9
  mov    %rax,%rcx
  shl    $0x18,%rcx
  sar    $0x38,%rcx
  mov    %cl,%dl
  xor    %ecx,%ecx
  mov    %dil,%cl
  movabs $0xffff0000ffffffff,%rdi
  mov    %ah,%ch
  and    %rdi,%rdx
  shl    $0x10,%rax
  movzwl %cx,%ecx
  shr    $0x38,%rax
  shl    $0x20,%rcx
  shl    $0x38,%rax
  or     %rcx,%rdx
  movabs $0xffffffffffffff,%rcx
  and    %rcx,%rdx
  or     %rax,%rdx
  mov    %rdx,%rcx
L9:
  add    $0x32060f04,%rcx
  mov    %rcx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  unsigned short copy12;
  char copy13;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      if (state[0UL] < local1) {
        copy11 = *((char *)(&state[local1]) + 5);
        *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy11;
        copy11 = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = *((char *)(&state[local1]) + 2);
        *((char *)(&state[local1]) + 2) = copy11;
      } else {
        copy12 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 3);
        *((unsigned short *)(&state[local1]) + 3) = copy12;
      }
      if (state[0UL] <= local1) {
        state[local1] = state[0UL] + state[0UL];
      } else {
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 4);
        *((char *)(&state[0UL]) + 4) = copy13;
        copy13 = *((char *)(&state[0UL]) + 5);
        *((char *)(&state[0UL]) + 5) = *((char *)(&state[0UL]) + 7);
        *((char *)(&state[0UL]) + 7) = copy13;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 839257860UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ser_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__fputc@plt>
  cmpl   $0xa,-0x4(%rbp)
  jne    L7
  mov    $0xd,%edi
  call   <ser_out>
L7:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int ser_out(int c) {
  __fputc(c, 0);
  if (c == '\n')
    ser_out('\r');
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ser_out>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%esi
  call   <__fputc@plt>
  cmp    $0xa,%ebx
  je     L12
L8:
  mov    $0x0,%eax
  pop    %rbx
  ret
L12:
  mov    $0xd,%edi
  call   <ser_out>
  jmp    L8
```

assistant: ```c
int ser_out(int c) {
  __fputc(c, 0);
  if (c == '\n')
    ser_out('\r');
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ser_out>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %edi,%ebx
  call   <__fputc@plt>
  cmp    $0xa,%ebx
  je     L6
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %esi,%esi
  mov    $0xd,%edi
  call   <__fputc@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ser_out(int c) {
  __fputc(c, 0);
  if (c == '\n')
    ser_out('\r');
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ser_out>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %edi,%ebx
  call   <__fputc@plt>
  cmp    $0xa,%ebx
  je     L0
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %esi,%esi
  mov    $0xd,%edi
  call   <__fputc@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ser_out(int c) {
  __fputc(c, 0);
  if (c == '\n')
    ser_out('\r');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<swap_symbols_for_quaddobl_Laurent_witness_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x8(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x335,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int swap_symbols_for_quaddobl_Laurent_witness_set(int nvr, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(821, &nvr, &dim, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap_symbols_for_quaddobl_Laurent_witness_set>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x335,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int swap_symbols_for_quaddobl_Laurent_witness_set(int nvr, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(821, &nvr, &dim, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<swap_symbols_for_quaddobl_Laurent_witness_set>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x335,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int swap_symbols_for_quaddobl_Laurent_witness_set(int nvr, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(821, &nvr, &dim, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<swap_symbols_for_quaddobl_Laurent_witness_set>:
  endbr64
  sub    $0x18,%rsp
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x335,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int swap_symbols_for_quaddobl_Laurent_witness_set(int nvr, int dim) {
  int fail;
  double *c;
  fail = _ada_use_c2phc4c(821, &nvr, &dim, c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x66726162,-0xf(%rbp)
  movw   $0x6f6f,-0xb(%rbp)
  movb   $0x0,-0x9(%rbp)
  lea    -0xf(%rbp),%rax
  mov    %rax,%rdi
  call   <fn1@plt>
  cmp    $0x4,%eax
  je     L8
  mov    $0x0,%eax
  call   <abort@plt>
L8:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int main(void) {
  char p[] = "barfoo";
  if (fn1(p) != 4)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x66726162,0x1(%rsp)
  movw   $0x6f6f,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  lea    0x1(%rsp),%rdi
  call   <fn1@plt>
  cmp    $0x4,%eax
  jne    L16
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L16:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L21
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char p[] = "barfoo";
  if (fn1(p) != 4)
    abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rdi
  mov    $0x6f6f,%eax
  movl   $0x66726162,0x1(%rsp)
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <fn1@plt>
  cmp    $0x4,%eax
  je     L10
  xor    %eax,%eax
  call   <abort@plt>
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char p[] = "barfoo";
  if (fn1(p) != 4)
    abort();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rsp),%rdi
  mov    $0x6f6f,%eax
  movl   $0x66726162,0x1(%rsp)
  mov    %ax,0x5(%rsp)
  movb   $0x0,0x7(%rsp)
  call   <fn1@plt>
  cmp    $0x4,%eax
  je     L9
  xor    %eax,%eax
  call   <abort@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char p[] = "barfoo";
  if (fn1(p) != 4)
    abort();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L2
L18:
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L18
  mov    -0xc(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D16
data_type: string
name: retrieve_data
arguments: label: D9
data_type: string

tool: D16: Je suis le maitre !

tool: D9: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%ebx
  lea    D15(%rip),%rdi
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L1
  mov    $0x0,%esi
  mov    $0x0,%eax
L25:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L25
L23:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L1:
  mov    $0x0,%esi
  jmp    L23
```

tool_calls: name: disassemble_data
arguments: tag: D15
type: string
name: disassemble_data
arguments: tag: D10
type: string

tool: D15: Je suis le maitre !

tool: D10: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  xor    %esi,%esi
  test   %ebx,%ebx
  jle    L19
  xor    %eax,%eax
  nopl   0x0(%rax)
L10:
  add    %eax,%esi
  add    $0x1,%eax
  cmp    %eax,%ebx
  jne    L10
L19:
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D3
type: string

tool: D15: Je suis le maitre !

tool: D3: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%ebx
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L92
  lea    -0x1(%rbx),%eax
  cmp    $0x9,%eax
  jbe    L23
  mov    %ebx,%edx
  movdqa D23(%rip),%xmm1
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movdqa D3(%rip),%xmm3
  shr    $0x2,%edx
  nopl   0x0(%rax,%rax,1)
L120:
  movdqa %xmm1,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm1
  paddd  %xmm2,%xmm0
  cmp    %eax,%edx
  jne    L120
  movdqa %xmm0,%xmm1
  mov    %ebx,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  test   $0x3,%bl
  je     L29
L44:
  lea    0x1(%rax),%edx
  add    %eax,%esi
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x6(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x7(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    %edx,%esi
  lea    0x8(%rax),%edx
  cmp    %edx,%ebx
  jle    L29
  add    $0x9,%eax
  add    %edx,%esi
  cmp    %eax,%ebx
  jle    L29
  add    %eax,%esi
L29:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L92:
  xor    %esi,%esi
  jmp    L29
L23:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L44
```

tool_calls: name: read_data
arguments: data_label: D18
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: byte[16]
name: read_data
arguments: data_label: D3
type_guessed: byte[16]
name: read_data
arguments: data_label: D17
type_guessed: string

tool: D18: Je suis le maitre !

tool: {"D23": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D3": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D17: sum = %d


assistant: ```c
int main(int argc, char **argv) {
  int N = atoi(argv[1]);
  int sum = 0;
#pragma omp parallel shared(sum, N)
  {
    int i, sum_loc = 0;
#pragma omp master
    { printf("Je suis le maitre !\n"); }
    for (i = 0; i < N; i++) {
      sum_loc += i;
    }
#pragma omp critical
    { sum += sum_loc; }
  }
  printf("sum = %d\n", sum);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  D9(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D36(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x10(%rbp),%xmm1
  movsd  D6(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsd  -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: f64
name: read_data
arguments: data_tag: D36
datatype: f64
name: read_data
arguments: data_tag: D6
datatype: f64
name: read_data
arguments: data_tag: D22
datatype: string
name: read_data
arguments: data_tag: D10
datatype: string

tool: D9: 0.333

tool: D36: 9

tool: D6: 7.31

tool: D22: Shoe size (men's)    foot length

tool: D10: %10.1f %15.2f inches


assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  shoe = 9.0;
  foot = SCALE * shoe + 7.31;
  printf("Shoe size (men's)    foot length\n");
  printf("%10.1f %15.2f inches\n", shoe, foot);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  call   <puts@plt>
  movsd  D26(%rip),%xmm1
  movsd  D23(%rip),%xmm0
  lea    D11(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D34
datatype: string
name: parse_data
arguments: data_label: D26
datatype: byte[8]
name: parse_data
arguments: data_label: D23
datatype: f64
name: parse_data
arguments: data_label: D11
datatype: string

tool: D34: Shoe size (men's)    foot length

tool: {"D26": [0x77,0xbe,0x9f,0x1a,0x2f,0x9d,0x24,0x40]}

tool: D23: 9

tool: D11: %10.1f %15.2f inches


assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  shoe = 9.0;
  foot = SCALE * shoe + 7.31;
  printf("Shoe size (men's)    foot length\n");
  printf("%10.1f %15.2f inches\n", shoe, foot);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D18(%rip),%rdi
  call   <puts@plt>
  movsd  D8(%rip),%xmm1
  mov    $0x2,%eax
  movsd  D22(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D8
type_guessed: byte[8]
name: extract_symbolic_data
arguments: tag: D22
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D15
type_guessed: string

tool: D18: Shoe size (men's)    foot length

tool: {"D8": [0x77,0xbe,0x9f,0x1a,0x2f,0x9d,0x24,0x40]}

tool: D22: 9

tool: D15: %10.1f %15.2f inches


assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  shoe = 9.0;
  foot = SCALE * shoe + 7.31;
  printf("Shoe size (men's)    foot length\n");
  printf("%10.1f %15.2f inches\n", shoe, foot);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <puts@plt>
  movsd  D20(%rip),%xmm1
  mov    $0x2,%eax
  movsd  D12(%rip),%xmm0
  lea    D31(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D20
type: byte[8]
name: read_data
arguments: data_label: D12
type: f64
name: read_data
arguments: data_label: D31
type: string

tool: D1: Shoe size (men's)    foot length

tool: {"D20": [0x77,0xbe,0x9f,0x1a,0x2f,0x9d,0x24,0x40]}

tool: D12: 9

tool: D31: %10.1f %15.2f inches


assistant: ```c
int main(void) {
  const double SCALE = 0.333;
  double shoe, foot;
  shoe = 9.0;
  foot = SCALE * shoe + 7.31;
  printf("Shoe size (men's)    foot length\n");
  printf("%10.1f %15.2f inches\n", shoe, foot);
  return 0;
}
```