ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_power>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  jmp    L4
L1:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L1
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int is_power(int x, int ofy) {
  while ((x % ofy) == 0) {
    x /= ofy;
  }
  return x == 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<is_power>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L8
L19:
  mov    %edi,%eax
  cltd
  idiv   %esi
  mov    %eax,%edi
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L19
L8:
  cmp    $0x1,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_power(int x, int ofy) {
  while ((x % ofy) == 0) {
    x /= ofy;
  }
  return x == 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_power>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L1
  nopl   (%rax)
L5:
  mov    %edi,%eax
  cltd
  idiv   %esi
  cltd
  mov    %eax,%edi
  idiv   %esi
  test   %edx,%edx
  je     L5
L1:
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
  ret
```

assistant: ```c
int is_power(int x, int ofy) {
  while ((x % ofy) == 0) {
    x /= ofy;
  }
  return x == 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_power>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  jne    L13
  nopl   (%rax)
L4:
  mov    %edi,%eax
  cltd
  idiv   %esi
  cltd
  mov    %eax,%edi
  idiv   %esi
  test   %edx,%edx
  je     L4
L13:
  xor    %eax,%eax
  cmp    $0x1,%edi
  sete   %al
  ret
```

assistant: ```c
int is_power(int x, int ofy) {
  while ((x % ofy) == 0) {
    x /= ofy;
  }
  return x == 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_square>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x88,%eax
  test   %eax,%eax
  je     L11
  mov    $0x0,%eax
  jmp    L6
L11:
  mov    $0x1,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
int is_square(int x) {
  if (x & 0x88)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_square>:
  endbr64
  test   $0x88,%dil
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_square(int x) {
  if (x & 0x88)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_square>:
  endbr64
  xor    %eax,%eax
  and    $0x88,%edi
  sete   %al
  ret
```

assistant: ```c
int is_square(int x) {
  if (x & 0x88)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_square>:
  endbr64
  xor    %eax,%eax
  and    $0x88,%edi
  sete   %al
  ret
```

assistant: ```c
int is_square(int x) {
  if (x & 0x88)
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x1,-0x8(%rbp)
  jmp    L42
L39:
  movl   $0x1,-0x4(%rbp)
  jmp    L46
L16:
  cmpl   $0x0,-0x8(%rbp)
  je     L27
  cmpl   $0x0,-0x4(%rbp)
  je     L27
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x8,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movl   $0x0,(%rdx,%rax,4)
L27:
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  addl   $0x1,-0x8(%rbp)
L42:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_matrix(int c_size, int r_size, int matrix[255][255]) {
  int i, j;
  matrix[0][0] = 0;
  for (i = 1; i < r_size; i++) {
    for (j = 1; j < c_size; j++) {
      if (i != 0 && j != 0) {
        matrix[i][j] = 0;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<init_matrix>:
  endbr64
  movl   $0x0,(%rdx)
  cmp    $0x1,%esi
  jle    L87
  lea    0x3fc(%rdx),%r9
  mov    $0x1,%edx
  mov    %edi,%ecx
  jmp    L86
L23:
  movl   $0x0,(%r8,%rax,4)
L72:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L73
L50:
  test   %edx,%edx
  je     L72
  test   %eax,%eax
  jne    L23
  jmp    L72
L73:
  add    $0x1,%edx
  add    $0x3fc,%r9
  cmp    %edx,%esi
  je     L87
L86:
  mov    %r9,%r8
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jg     L50
  jmp    L73
L87:
  ret
```

assistant: ```c
void init_matrix(int c_size, int r_size, int matrix[255][255]) {
  int i, j;
  matrix[0][0] = 0;
  for (i = 1; i < r_size; i++) {
    for (j = 1; j < c_size; j++) {
      if (i != 0 && j != 0) {
        matrix[i][j] = 0;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<init_matrix>:
  endbr64
  movl   $0x0,(%rdx)
  cmp    $0x1,%esi
  jle    L25
  sub    $0x2,%esi
  push   %r12
  lea    0x400(%rdx),%rcx
  mov    %rsi,%rax
  push   %rbp
  shl    $0x8,%rax
  push   %rbx
  mov    %edi,%ebx
  sub    %rsi,%rax
  lea    0x7fc(%rdx,%rax,4),%rbp
  lea    -0x2(%rdi),%eax
  lea    0x4(,%rax,4),%r12
  nopl   0x0(%rax)
L9:
  cmp    $0x1,%ebx
  jle    L3
  mov    %rcx,%rdi
  mov    %r12,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
L3:
  add    $0x3fc,%rcx
  cmp    %rbp,%rcx
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  ret
```

assistant: ```c
void init_matrix(int c_size, int r_size, int matrix[255][255]) {
  int i, j;
  matrix[0][0] = 0;
  for (i = 1; i < r_size; i++) {
    for (j = 1; j < c_size; j++) {
      if (i != 0 && j != 0) {
        matrix[i][j] = 0;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<init_matrix>:
  endbr64
  movl   $0x0,(%rdx)
  cmp    $0x1,%esi
  jle    L18
  cmp    $0x1,%edi
  jle    L18
  sub    $0x2,%esi
  push   %rbp
  lea    0x400(%rdx),%rcx
  push   %rbx
  mov    %rsi,%rax
  lea    -0x1(%rdi),%ebx
  shl    $0x8,%rax
  shl    $0x2,%rbx
  sub    %rsi,%rax
  sub    $0x8,%rsp
  lea    0x7fc(%rdx,%rax,4),%rbp
  nopl   (%rax)
L20:
  mov    %rcx,%rdi
  mov    %rbx,%rdx
  xor    %esi,%esi
  call   <memset@plt>
  mov    %rax,%rcx
  add    $0x3fc,%rcx
  cmp    %rbp,%rcx
  jne    L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void init_matrix(int c_size, int r_size, int matrix[255][255]) {
  int i, j;
  matrix[0][0] = 0;
  for (i = 1; i < r_size; i++) {
    for (j = 1; j < c_size; j++) {
      if (i != 0 && j != 0) {
        matrix[i][j] = 0;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dcd_kill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <dcd_getpid@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <kill@plt>
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int dcd_kill(int signal) {
  int pid = dcd_getpid();
  int k = 0;
  if (pid != 0)
    k = kill(pid, signal);
  return pid;
}
```
user: What is the c source code of the assembly code below:

```asm
<dcd_kill>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%eax
  call   <dcd_getpid@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jne    L10
L16:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <kill@plt>
  jmp    L16
```

assistant: ```c
int dcd_kill(int signal) {
  int pid = dcd_getpid();
  int k = 0;
  if (pid != 0)
    k = kill(pid, signal);
  return pid;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dcd_kill>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <dcd_getpid@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L1
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <kill@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dcd_kill(int signal) {
  int pid = dcd_getpid();
  int k = 0;
  if (pid != 0)
    k = kill(pid, signal);
  return pid;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dcd_kill>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <dcd_getpid@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L9
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <kill@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int dcd_kill(int signal) {
  int pid = dcd_getpid();
  int k = 0;
  if (pid != 0)
    k = kill(pid, signal);
  return pid;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<update_hg_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x14(%rbp)
  mov    %al,-0x18(%rbp)
  movzbl -0x14(%rbp),%eax
  xor    -0x18(%rbp),%al
  and    $0xf,%eax
  mov    %al,-0x1(%rbp)
  shlb   $0x4,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  or     %al,-0x18(%rbp)
  andb   $0xf0,-0x18(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  movzbl -0x18(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x18(%rbp)
  movzbl -0x18(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char update_hg_mask(unsigned char state, unsigned char mask) {
  unsigned char val;
  ;
  val = (state ^ mask) & 0xF;
  val = val << 4;
  mask |= val;
  mask &= 0xF0;
  mask |= (state & 0xF);
  ;
  return mask;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<update_hg_mask>:
  endbr64
  mov    %esi,%eax
  xor    %edi,%esi
  shl    $0x4,%esi
  or     %eax,%esi
  and    $0xfffffff0,%esi
  and    $0xf,%edi
  mov    %edi,%eax
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned char update_hg_mask(unsigned char state, unsigned char mask) {
  unsigned char val;
  ;
  val = (state ^ mask) & 0xF;
  val = val << 4;
  mask |= val;
  mask &= 0xF0;
  mask |= (state & 0xF);
  ;
  return mask;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<update_hg_mask>:
  endbr64
  mov    %esi,%eax
  xor    %edi,%esi
  and    $0xf,%edi
  shl    $0x4,%esi
  or     %eax,%esi
  mov    %edi,%eax
  and    $0xfffffff0,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned char update_hg_mask(unsigned char state, unsigned char mask) {
  unsigned char val;
  ;
  val = (state ^ mask) & 0xF;
  val = val << 4;
  mask |= val;
  mask &= 0xF0;
  mask |= (state & 0xF);
  ;
  return mask;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<update_hg_mask>:
  endbr64
  mov    %esi,%eax
  xor    %edi,%esi
  and    $0xf,%edi
  shl    $0x4,%esi
  or     %eax,%esi
  mov    %edi,%eax
  and    $0xfffffff0,%esi
  or     %esi,%eax
  ret
```

assistant: ```c
unsigned char update_hg_mask(unsigned char state, unsigned char mask) {
  unsigned char val;
  ;
  val = (state ^ mask) & 0xF;
  val = val << 4;
  mask |= val;
  mask &= 0xF0;
  mask |= (state & 0xF);
  ;
  return mask;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0x696a,%ax
  xor    $0xb,%eax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L46
L33:
  movw   $0x0,-0xe(%rbp)
  jmp    L27
L37:
  movzwl -0xe(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %eax,%edx
  movzwl -0xe(%rbp),%eax
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  addw   $0x2,-0xe(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xe(%rbp)
  jb     L37
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L46:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L33
  movzwl -0xa(%rbp),%eax
  shr    %ax
  mov    %eax,%edx
  movzwl -0xa(%rbp),%eax
  movzwl %ax,%eax
  shl    $0xf,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] |= (state[0UL] & (unsigned short)63) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)1) | (state[0UL] << (unsigned short)15);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  lea    0x696a(%rax),%ecx
  xor    $0xb,%ecx
  movzwl 0x2(%rdi),%edi
  mov    $0x0,%r8d
  test   %di,%di
  je     L26
L6:
  mov    $0x0,%edx
L11:
  mov    %ecx,%eax
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %eax,%ecx
  add    $0x2,%edx
  cmp    %di,%dx
  jb     L11
  add    $0x1,%r8d
  cmp    %di,%r8w
  jne    L6
L26:
  ror    %cx
  mov    %cx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] |= (state[0UL] & (unsigned short)63) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)1) | (state[0UL] << (unsigned short)15);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  xor    %r8d,%r8d
  lea    0x696a(%rax),%ecx
  xor    $0xb,%ecx
  test   %di,%di
  je     L9
  nopl   0x0(%rax)
L7:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ecx,%eax
  add    $0x2,%edx
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %eax,%ecx
  cmp    %di,%dx
  jb     L10
  add    $0x1,%r8d
  cmp    %di,%r8w
  jne    L7
L9:
  ror    %cx
  mov    %cx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] |= (state[0UL] & (unsigned short)63) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)1) | (state[0UL] << (unsigned short)15);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%edi
  xor    %r8d,%r8d
  lea    0x696a(%rax),%ecx
  xor    $0xb,%ecx
  test   %di,%di
  je     L28
  nopl   0x0(%rax)
L8:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ecx,%eax
  add    $0x2,%edx
  shl    $0x4,%eax
  and    $0x3f0,%ax
  or     %eax,%ecx
  cmp    %di,%dx
  jb     L18
  add    $0x1,%r8d
  cmp    %di,%r8w
  jne    L8
L28:
  ror    %cx
  mov    %cx,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        state[local2] |= (state[0UL] & (unsigned short)63) << 4UL;
        local2 += 2UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] >> (unsigned short)1) | (state[0UL] << (unsigned short)15);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<MSG_HTML_Header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D29
datatype: string
name: read_data
arguments: data_tag: D33
datatype: string
name: read_data
arguments: data_tag: D11
datatype: string
name: read_data
arguments: data_tag: D3
datatype: string

tool: D29: <HTML>
<HEAD>

tool: D33: <TITLE>%s: %s</TITLE>


tool: D11: <CENTER><H2>%s: %s</H2></CENTER>


tool: D3: <HR><p></HEAD><BODY>

assistant: ```c
void MSG_HTML_Header(char *title, char *msg) {
  printf("<HTML>\n<HEAD>\n");
  printf("<TITLE>%s: %s</TITLE>\n", title, msg);
  printf("<CENTER><H2>%s: %s</H2></CENTER>\n", title, msg);
  printf("<HR><p></HEAD><BODY>\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MSG_HTML_Header>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D38
datatype: string
name: disassemble_data
arguments: data_label: D10
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D26
datatype: string

tool: D38: <HTML>
<HEAD>

tool: D10: <TITLE>%s: %s</TITLE>


tool: D1: <CENTER><H2>%s: %s</H2></CENTER>


tool: D26: <HR><p></HEAD><BODY>

assistant: ```c
void MSG_HTML_Header(char *title, char *msg) {
  printf("<HTML>\n<HEAD>\n");
  printf("<TITLE>%s: %s</TITLE>\n", title, msg);
  printf("<CENTER><H2>%s: %s</H2></CENTER>\n", title, msg);
  printf("<HR><p></HEAD><BODY>\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<MSG_HTML_Header>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D37(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D0(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: label: D37
datatype: string
name: disassemble_data
arguments: label: D2
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D37: <HTML>
<HEAD>

tool: D2: <TITLE>%s: %s</TITLE>


tool: D1: <CENTER><H2>%s: %s</H2></CENTER>


tool: D0: <HR><p></HEAD><BODY>

assistant: ```c
void MSG_HTML_Header(char *title, char *msg) {
  printf("<HTML>\n<HEAD>\n");
  printf("<TITLE>%s: %s</TITLE>\n", title, msg);
  printf("<CENTER><H2>%s: %s</H2></CENTER>\n", title, msg);
  printf("<HR><p></HEAD><BODY>\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MSG_HTML_Header>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D24(%rip),%rdi
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  lea    D17(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: label: D24
type_guessed: string
name: unpack_data
arguments: label: D32
type_guessed: string
name: unpack_data
arguments: label: D38
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: string

tool: D24: <HTML>
<HEAD>

tool: D32: <TITLE>%s: %s</TITLE>


tool: D38: <CENTER><H2>%s: %s</H2></CENTER>


tool: D17: <HR><p></HEAD><BODY>

assistant: ```c
void MSG_HTML_Header(char *title, char *msg) {
  printf("<HTML>\n<HEAD>\n");
  printf("<TITLE>%s: %s</TITLE>\n", title, msg);
  printf("<CENTER><H2>%s: %s</H2></CENTER>\n", title, msg);
  printf("<HR><p></HEAD><BODY>\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<simple_strtoull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L10
  movl   $0xa,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L10
  movl   $0x8,-0x24(%rbp)
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  jne    L10
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L10
  addq   $0x1,-0x18(%rbp)
  movl   $0x10,-0x24(%rbp)
  jmp    L10
L68:
  mov    -0x24(%rbp),%eax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L92
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L59
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  jmp    L13
L59:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L28
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
  jmp    L13
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  cltq
L13:
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  jb     L68
L92:
  cmpq   $0x0,-0x20(%rbp)
  je     L113
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L113:
  mov    -0x10(%rbp),%rax
  leave
  ret
```

assistant: ```c
unsigned long long simple_strtoull(const char *cp, char **endp, unsigned int base) {
  unsigned long long result = 0, value;
  if (!base) {
    base = 10;
    if (*cp == '0') {
      base = 8;
      cp++;
      if ((*cp == 'x') && isxdigit(cp[1])) {
        cp++;
        base = 16;
      }
    }
  }
  while (isxdigit(*cp) && (value = isdigit(*cp) ? *cp - '0' : (islower(*cp) ? toupper(*cp) : *cp) - 'A' + 10) < base) {
    result = result * base + value;
    cp++;
  }
  if (endp)
    *endp = (char *)cp;
  return result;
}
```