user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0xc8,0x10(%rsp)
  movl   $0x64,0x14(%rsp)
  movl   $0x32,0x18(%rsp)
  movl   $0x14,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  lea    D99(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D108(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  D90(%rip),%xmm0
  movaps %xmm0,%xmm1
  mulss  0x8(%rsp),%xmm1
  cvttss2si %xmm1,%ecx
  mulss  0xc(%rsp),%xmm0
  cvttss2si %xmm0,%eax
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edx
  mov    %ecx,%esi
  sub    %edx,%esi
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x21,%rdx
  mov    %eax,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edi
  mov    %eax,%edx
  sub    %edi,%edx
  or     %edx,%esi
  je     L33
  lea    D86(%rip),%rdi
  call   <puts@plt>
L67:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  test   %ecx,%ecx
  jle    L120
  cmp    %eax,%ecx
  jge    L120
  sub    %ecx,%eax
  mov    %eax,%ebx
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D5(%rip),%xmm0
  lea    D14(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0xc8,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,0x30(%rsp)
  mov    %edx,%eax
  mov    $0x1,%ecx
  mov    %edx,%ebp
  test   %edx,%edx
  je     L41
L9:
  mov    %ecx,%ebp
  cltd
  idivl  0x10(%rsp,%rcx,4)
  mov    %eax,0x30(%rsp,%rcx,4)
  mov    %edx,%eax
  test   %edx,%edx
  je     L41
  lea    0x1(%rcx),%ebp
  add    $0x1,%rcx
  cmp    $0x6,%rcx
  jne    L9
L41:
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r14
  lea    D52(%rip),%r13
  lea    D2(%rip),%r12
  jmp    L13
L120:
  lea    D91(%rip),%rdi
  call   <puts@plt>
  jmp    L67
L2:
  add    $0x1,%rbx
  cmp    $0x6,%rbx
  je     L67
L13:
  mov    0x30(%rsp,%rbx,4),%esi
  test   %esi,%esi
  je     L2
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%r14,%rbx,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  divsd  D5(%rip),%xmm0
  mov    %r13,%rdx
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L2
  jmp    L67
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D99
type_infered: string
name: extract_symbolic_data
arguments: data_label: D108
type_infered: string
name: extract_symbolic_data
arguments: data_label: D20
type_infered: string
name: extract_symbolic_data
arguments: data_label: D90
type_infered: f32
name: extract_symbolic_data
arguments: data_label: D86
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D14
type_infered: string
name: extract_symbolic_data
arguments: data_label: D52
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D91
type_infered: string

tool: D99: 

	Preu de la beguda ==>

tool: D108: %f

tool: D20: 	Diners introduits ==>

tool: D90: 100

tool: D86: No hi ha canvi suficient.

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x59,0x40]}

tool: D14: 
Canvi a tornar ==> %.2f


tool: D52: monedes de

tool: D2: 	%d %s %.2f euros.


tool: D91: No hi han suficient diners.

assistant: ```c
int main() {
  int moneda[] = {200, 100, 50, 20, 10, 5};
  int canvi[6], preu, pagat, diferencia;
  int i = 0;
  int check = 0;
  float Preu, Pagat;
  printf("\n\n\tPreu de la beguda ==>");
  scanf("%f", &Preu);
  printf("\tDiners introduits ==>");
  scanf("%f", &Pagat);
  preu = (int)(Preu * 100);
  pagat = (int)(Pagat * 100);
  if (!(preu % 5 == 0 && pagat % 5 == 0)) {
    printf("No hi ha canvi suficient.\n");
  } else {
    if (!(preu > 0 && preu < pagat)) {
      printf("No hi han suficient diners.\n");
    } else {
      check = 1;
    }
  }
  if (check) {
    diferencia = pagat - preu;
    printf("\nCanvi a tornar ==> %.2f\n", (float)diferencia / 100.0);
    for (i = 0; i < 6; i++) {
      canvi[i] = diferencia / (moneda[i]);
      if (diferencia % moneda[i]) {
        diferencia = diferencia % moneda[i];
      } else {
        break;
      }
    }
    for (int j = 0; j < 6; j++) {
      if (canvi[j] != 0) {
        printf("\t%d %s %.2f euros.\n", canvi[j], "monedes de", (float)moneda[j] / 100.0);
        if (j == i) {
          break;
        }
      }
    }
  }
  return 0;
}
```