ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<fn66>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
data_type: string

tool: D5: fn66

assistant: ```c
char *fn66() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn66");
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn66>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_infered: string

tool: D5: fn66

assistant: ```c
char *fn66() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn66");
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn66>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: fn66

assistant: ```c
char *fn66() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn66");
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main1(int a) {
  int b;
  int z;
  b = a;
  {
    int g;
    int c;
    c = b;
    g = c;
    z = g + c;
  }
  return z + 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main1>:
  endbr64
  lea    0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int main1(int a) {
  int b;
  int z;
  b = a;
  {
    int g;
    int c;
    c = b;
    g = c;
    z = g + c;
  }
  return z + 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main1>:
  endbr64
  lea    0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int main1(int a) {
  int b;
  int z;
  b = a;
  {
    int g;
    int c;
    c = b;
    g = c;
    z = g + c;
  }
  return z + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main1>:
  endbr64
  lea    0x1(%rdi,%rdi,1),%eax
  ret
```

assistant: ```c
int main1(int a) {
  int b;
  int z;
  b = a;
  {
    int g;
    int c;
    c = b;
    g = c;
    z = g + c;
  }
  return z + 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rdi
  call   <ReverseBit@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D24
type_guessed: string

tool: D13: %i

tool: D4: original number: %08X


tool: D24: after reversing: %08X


assistant: ```c
int main() {
  int num, i;
  scanf("%i", &num);
  printf("original number: %08X\n", num);
  ReverseBit(&num);
  printf("after reversing: %08X\n", num);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <ReverseBit@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D2
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string

tool: D9: %i

tool: D2: original number: %08X


tool: D20: after reversing: %08X


assistant: ```c
int main() {
  int num, i;
  scanf("%i", &num);
  printf("original number: %08X\n", num);
  ReverseBit(&num);
  printf("after reversing: %08X\n", num);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <ReverseBit@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_infered: string
name: extract_symbolic_data
arguments: tag: D11
type_infered: string
name: extract_symbolic_data
arguments: tag: D20
type_infered: string

tool: D23: %i

tool: D11: original number: %08X


tool: D20: after reversing: %08X


assistant: ```c
int main() {
  int num, i;
  scanf("%i", &num);
  printf("original number: %08X\n", num);
  ReverseBit(&num);
  printf("after reversing: %08X\n", num);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <ReverseBit@plt>
  mov    0x4(%rsp),%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D20
type_infered: string
name: parse_data
arguments: data_tag: D24
type_infered: string

tool: D14: %i

tool: D20: original number: %08X


tool: D24: after reversing: %08X


assistant: ```c
int main() {
  int num, i;
  scanf("%i", &num);
  printf("original number: %08X\n", num);
  ReverseBit(&num);
  printf("after reversing: %08X\n", num);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<aP_getgamma_safe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
L2:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  jne    L40
  mov    $0x0,%eax
  jmp    L26
L40:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L3
  mov    $0x0,%eax
  jmp    L26
L3:
  mov    -0xc(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  jne    L79
  mov    $0x0,%eax
  jmp    L26
L79:
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L2
  mov    -0x20(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x1,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
int aP_getgamma_safe(struct APDSSTATE *ud, unsigned int *result) {
  unsigned int bit;
  unsigned int v = 1;
  do {
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
    if (v & 0x80000000) {
      return 0;
    }
    v = (v << 1) + bit;
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
  } while (bit);
  *result = v;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aP_getgamma_safe>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r12
L45:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  je     L3
  test   %ebx,%ebx
  js     L27
  mov    0x4(%rsp),%eax
  lea    (%rax,%rbx,2),%ebx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  je     L3
  cmpl   $0x0,0x4(%rsp)
  jne    L45
  mov    %ebx,0x0(%r13)
  mov    $0x1,%eax
  jmp    L3
L27:
  mov    $0x0,%eax
L3:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int aP_getgamma_safe(struct APDSSTATE *ud, unsigned int *result) {
  unsigned int bit;
  unsigned int v = 1;
  do {
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
    if (v & 0x80000000) {
      return 0;
    }
    v = (v << 1) + bit;
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
  } while (bit);
  *result = v;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<aP_getgamma_safe>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L53
L40:
  test   %ebx,%ebx
  js     L59
  mov    0x4(%rsp),%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    (%rax,%rbx,2),%ebx
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  je     L59
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L22
L53:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  jne    L40
L59:
  xor    %eax,%eax
L24:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L58
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L22:
  mov    %ebx,0x0(%r13)
  mov    $0x1,%eax
  jmp    L24
L58:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int aP_getgamma_safe(struct APDSSTATE *ud, unsigned int *result) {
  unsigned int bit;
  unsigned int v = 1;
  do {
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
    if (v & 0x80000000) {
      return 0;
    }
    v = (v << 1) + bit;
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
  } while (bit);
  *result = v;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aP_getgamma_safe>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L10
L6:
  test   %ebx,%ebx
  js     L55
  mov    0x4(%rsp),%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  lea    (%rax,%rbx,2),%ebx
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  je     L55
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L64
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <aP_getbit_safe@plt>
  test   %eax,%eax
  jne    L6
L55:
  xor    %eax,%eax
L53:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L64:
  mov    %ebx,0x0(%r13)
  mov    $0x1,%eax
  jmp    L53
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int aP_getgamma_safe(struct APDSSTATE *ud, unsigned int *result) {
  unsigned int bit;
  unsigned int v = 1;
  do {
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
    if (v & 0x80000000) {
      return 0;
    }
    v = (v << 1) + bit;
    if (!aP_getbit_safe(ud, &bit)) {
      return 0;
    }
  } while (bit);
  *result = v;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <gotoxy@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xbb8,%edi
  call   <usleep@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D4
datatype: string

tool: D5: hello i=%d

tool: D4: hello i-1=%d

assistant: ```c
int main() {
  int i = 0;
  do {
    i = i + 1;
    gotoxy(12, 5);
    printf("hello i=%d\r", i);
    gotoxy(10, 5);
    printf("hello i-1=%d\r", i - 1);
    usleep(3 * 1000);
  } while (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <gotoxy@plt>
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    $0x0,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xbb8,%edi
  call   <usleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D18
data_type: string
name: parse_data
arguments: data_label: D2
data_type: string

tool: D18: hello i=%d

tool: D2: hello i-1=%d

assistant: ```c
int main() {
  int i = 0;
  do {
    i = i + 1;
    gotoxy(12, 5);
    printf("hello i=%d\r", i);
    gotoxy(10, 5);
    printf("hello i-1=%d\r", i - 1);
    usleep(3 * 1000);
  } while (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <gotoxy@plt>
  mov    $0x1,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  xor    %esi,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0xbb8,%edi
  call   <usleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D19
data_type: string
name: read_data
arguments: label: D11
data_type: string

tool: D19: hello i=%d

tool: D11: hello i-1=%d

assistant: ```c
int main() {
  int i = 0;
  do {
    i = i + 1;
    gotoxy(12, 5);
    printf("hello i=%d\r", i);
    gotoxy(10, 5);
    printf("hello i-1=%d\r", i - 1);
    usleep(3 * 1000);
  } while (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%esi
  mov    $0xc,%edi
  call   <gotoxy@plt>
  mov    $0x1,%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  xor    %esi,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0xbb8,%edi
  call   <usleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
type_infered: string
name: extract_symbolic_data
arguments: data_label: D17
type_infered: string

tool: D11: hello i=%d

tool: D17: hello i-1=%d

assistant: ```c
int main() {
  int i = 0;
  do {
    i = i + 1;
    gotoxy(12, 5);
    printf("hello i=%d\r", i);
    gotoxy(10, 5);
    printf("hello i-1=%d\r", i - 1);
    usleep(3 * 1000);
  } while (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<BTIC2D_TransDCT4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x90(%rbp),%rsi
  mov    -0xa8(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %rax,%rdi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x90(%rbp),%rax
  add    $0x10,%rax
  mov    -0xa8(%rbp),%rdx
  lea    0x10(%rdx),%rdi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %rax,%rsi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x90(%rbp),%rax
  add    $0x20,%rax
  mov    -0xa8(%rbp),%rdx
  lea    0x20(%rdx),%rdi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %rax,%rsi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x90(%rbp),%rax
  add    $0x30,%rax
  mov    -0xa8(%rbp),%rdx
  lea    0x30(%rdx),%rdi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %rax,%rsi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x50(%rbp),%rsi
  lea    -0x90(%rbp),%rax
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x50(%rbp),%rsi
  add    $0x4,%rsi
  lea    -0x90(%rbp),%rax
  add    $0x4,%rax
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x50(%rbp),%rsi
  add    $0x8,%rsi
  lea    -0x90(%rbp),%rax
  add    $0x8,%rax
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    -0x50(%rbp),%rsi
  add    $0xc,%rsi
  lea    -0x90(%rbp),%rax
  add    $0xc,%rax
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    %rax,%rdi
  call   <BTIC2D_TransDCT_Stride4@plt>
  movl   $0x0,-0x98(%rbp)
  jmp    L12
L22:
  movl   $0x0,-0x94(%rbp)
  jmp    L42
L44:
  mov    -0x98(%rbp),%eax
  lea    0x0(,%rax,4),%edx
  mov    -0x94(%rbp),%eax
  add    %edx,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  lea    0x8000(%rax),%edx
  mov    -0x98(%rbp),%eax
  lea    0x0(,%rax,4),%ecx
  mov    -0x94(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0xb0(%rbp),%rax
  add    %rcx,%rax
  sar    $0x10,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x94(%rbp)
L42:
  cmpl   $0x3,-0x94(%rbp)
  jle    L44
  addl   $0x1,-0x98(%rbp)
L12:
  cmpl   $0x3,-0x98(%rbp)
  jle    L22
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
void BTIC2D_TransDCT4(int *iblk, int *oblk) {
  int s[16], t[16];
  int i, j;
  BTIC2D_TransDCT_Stride4(iblk + 4 * 0, s + 4 * 0, 1, 1);
  BTIC2D_TransDCT_Stride4(iblk + 4 * 1, s + 4 * 1, 1, 1);
  BTIC2D_TransDCT_Stride4(iblk + 4 * 2, s + 4 * 2, 1, 1);
  BTIC2D_TransDCT_Stride4(iblk + 4 * 3, s + 4 * 3, 1, 1);
  BTIC2D_TransDCT_Stride4(s + 0, t + 0, 4, 4);
  BTIC2D_TransDCT_Stride4(s + 1, t + 1, 4, 4);
  BTIC2D_TransDCT_Stride4(s + 2, t + 2, 4, 4);
  BTIC2D_TransDCT_Stride4(s + 3, t + 3, 4, 4);
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++) {
      oblk[i * 4 + j] = (t[i * 4 + j] + 32768) >> 16;
    }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<BTIC2D_TransDCT4>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    $0x1,%ecx
  mov    $0x1,%edx
  mov    %r12,%rsi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x10(%rsp),%rsi
  lea    0x10(%rbx),%rdi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x20(%rsp),%rsi
  lea    0x20(%rbx),%rdi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x30(%rsp),%rsi
  lea    0x30(%rbx),%rdi
  mov    $0x1,%ecx
  mov    $0x1,%edx
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x40(%rsp),%rbx
  mov    $0x4,%ecx
  mov    $0x4,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x44(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%ecx
  mov    $0x4,%edx
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x48(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x4,%ecx
  mov    $0x4,%edx
  call   <BTIC2D_TransDCT_Stride4@plt>
  lea    0x4c(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    $0x4,%ecx
  mov    $0x4,%edx
  call   <BTIC2D_TransDCT_Stride4@plt>
  mov    %rbx,%rcx
  mov    %rbp,%rsi
  mov    $0x0,%edi
L1:
  mov    $0x0,%edx
L22:
  mov    (%rcx,%rdx,1),%eax
  add    $0x8000,%eax
  sar    $0x10,%eax
  mov    %eax,(%rsi,%rdx,1)
  add    $0x4,%rdx
  cmp    $0x10,%rdx
  jne    L22
  add    $0x4,%edi
  add    $0x10,%rcx
  add    $0x10,%rsi
  cmp    $0x10,%edi
  jne    L1
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void BTIC2D_TransDCT4(int *iblk, int *oblk) {
  int s[16], t[16];
  int i, j;
  BTIC2D_TransDCT_Stride4(iblk + 4 * 0, s + 4 * 0, 1, 1);
  BTIC2D_TransDCT_Stride4(iblk + 4 * 1, s + 4 * 1, 1, 1);
  BTIC2D_TransDCT_Stride4(iblk + 4 * 2, s + 4 * 2, 1, 1);
  BTIC2D_TransDCT_Stride4(iblk + 4 * 3, s + 4 * 3, 1, 1);
  BTIC2D_TransDCT_Stride4(s + 0, t + 0, 4, 4);
  BTIC2D_TransDCT_Stride4(s + 1, t + 1, 4, 4);
  BTIC2D_TransDCT_Stride4(s + 2, t + 2, 4, 4);
  BTIC2D_TransDCT_Stride4(s + 3, t + 3, 4, 4);
  for (i = 0; i < 4; i++)
    for (j = 0; j < 4; j++) {
      oblk[i * 4 + j] = (t[i * 4 + j] + 32768) >> 16;
    }
}
```