ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L23
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D35(%rip),%rbp
  lea    D17(%rip),%rbx
  nopl   0x0(%rax)
L13:
  mov    %r13,%rdx
  xor    %eax,%eax
  mov    %r14,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%edx
  pxor   %xmm2,%xmm2
  pxor   %xmm0,%xmm0
  mov    %edx,%eax
  sub    0xc(%rsp),%eax
  cvtsi2ss %eax,%xmm2
  mov    0x14(%rsp),%eax
  sub    %edx,%eax
  cvtsi2ss %eax,%xmm0
  ucomiss %xmm0,%xmm2
  jp     L1
  pxor   %xmm1,%xmm1
  je     L40
L1:
  addss  %xmm2,%xmm0
  mulss  D41(%rip),%xmm0
  pxor   %xmm3,%xmm3
  subss  %xmm0,%xmm2
  comiss %xmm2,%xmm3
  movaps %xmm2,%xmm1
  jbe    L40
  xorps  D37(%rip),%xmm1
L40:
  movaps %xmm1,%xmm0
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L13
L23:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D35
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string
name: disassemble_data
arguments: tag: D41
data_type: byte[4]
name: disassemble_data
arguments: tag: D37
data_type: byte[16]

tool: D12: %d

tool: D35: %d%d%d

tool: D17: %0.2f


tool: {"D41": [0x00,0x00,0x00,0x3f]}

tool: {"D37": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int t;
  int a, b, c;
  float d1, d2, min;
  scanf("%d", &t);
  while (t--) {
    scanf("%d%d%d", &a, &b, &c);
    d1 = b - a;
    d2 = c - b;
    if (d1 == d2)
      min = 0;
    else {
      min = (d1 + d2) / 2;
      min = b - a - min;
      if (min < 0)
        min = -min;
    }
    printf("%0.2f\n", min);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<qc_game_colour_cvar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <emit_colours_event@plt>
  nop
  leave
  ret
```

assistant: ```c
void qc_game_colour_cvar(int *var, int val) {
  *var = (uint8_t)val;
  emit_colours_event();
}
```
user: Translate the below assembly code into C programming language:

```asm
<qc_game_colour_cvar>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,(%rdi)
  mov    $0x0,%eax
  call   <emit_colours_event@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void qc_game_colour_cvar(int *var, int val) {
  *var = (uint8_t)val;
  emit_colours_event();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<qc_game_colour_cvar>:
  endbr64
  mov    %esi,(%rdi)
  xor    %eax,%eax
  jmp    1050 <emit_colours_event@plt>
```

assistant: ```c
void qc_game_colour_cvar(int *var, int val) {
  *var = (uint8_t)val;
  emit_colours_event();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<qc_game_colour_cvar>:
  endbr64
  mov    %esi,(%rdi)
  xor    %eax,%eax
  jmp    1050 <emit_colours_event@plt>
```

assistant: ```c
void qc_game_colour_cvar(int *var, int val) {
  *var = (uint8_t)val;
  emit_colours_event();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x28(%rbp)
  movl   $0x1,-0x40(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x38(%rbp)
  movl   $0xffffffff,-0x3c(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  mov    %eax,-0x44(%rbp)
  cmpl   $0xffffffff,-0x44(%rbp)
  jne    L17
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L15
L17:
  mov    $0x0,%edi
  call   <exit@plt>
L15:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  struct tm ts;
  ts.tm_sec = 0;
  ts.tm_min = 0;
  ts.tm_hour = 0;
  ts.tm_mday = 1;
  ts.tm_mon = 0;
  ts.tm_year = 0;
  ts.tm_isdst = -1;
  {
    time_t t = mktime(&ts);
    if (t == -1)
      exit(1);
    else
      exit(0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x1,(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movl   $0xffffffff,0x4(%rsp)
  mov    %rsp,%rdi
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  je     L0
  mov    $0x0,%edi
  call   <exit@plt>
L1:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x48,%rsp
  ret
L0:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L1
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct tm ts;
  ts.tm_sec = 0;
  ts.tm_min = 0;
  ts.tm_hour = 0;
  ts.tm_mday = 1;
  ts.tm_mon = 0;
  ts.tm_year = 0;
  ts.tm_isdst = -1;
  {
    time_t t = mktime(&ts);
    if (t == -1)
      exit(1);
    else
      exit(0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xffffffff00000001,%rax
  mov    %rsp,%rdi
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    %rax,(%rsp)
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  je     L27
  xor    %edi,%edi
  call   <exit@plt>
L29:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L27:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L29
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  struct tm ts;
  ts.tm_sec = 0;
  ts.tm_min = 0;
  ts.tm_hour = 0;
  ts.tm_mday = 1;
  ts.tm_mon = 0;
  ts.tm_year = 0;
  ts.tm_isdst = -1;
  {
    time_t t = mktime(&ts);
    if (t == -1)
      exit(1);
    else
      exit(0);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rsp,%rdi
  movups %xmm0,0x8(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    %rax,(%rsp)
  movups %xmm0,0x18(%rsp)
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  je     L23
  xor    %edi,%edi
  call   <exit@plt>
L0:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L23:
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L0
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D9
type_infered: byte[8]

tool: {"D9": [0x01,0x00,0x00,0x00,0xff,0xff,0xff,0xff]}

assistant: ```c
int main(int argc, char **argv) {
  struct tm ts;
  ts.tm_sec = 0;
  ts.tm_min = 0;
  ts.tm_hour = 0;
  ts.tm_mday = 1;
  ts.tm_mon = 0;
  ts.tm_year = 0;
  ts.tm_isdst = -1;
  {
    time_t t = mktime(&ts);
    if (t == -1)
      exit(1);
    else
      exit(0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<debug_scanner_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x3,-0x4(%rbp)
  je     L32
  cmpl   $0x3,-0x4(%rbp)
  jg     L2
  cmpl   $0x2,-0x4(%rbp)
  je     L14
  cmpl   $0x2,-0x4(%rbp)
  jg     L2
  cmpl   $0x0,-0x4(%rbp)
  je     L64
  cmpl   $0x1,-0x4(%rbp)
  jmp    L2
L32:
  nop
  jmp    L7
L2:
  nop
  jmp    L7
L14:
  nop
  jmp    L7
L64:
  nop
L7:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void debug_scanner_state(int state) {
  switch (state) {
  case 1:;
    break;
  case 2:;
    break;
  case 3:;
    break;
  case 0:;
    break;
  default:;
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<debug_scanner_state>:
  endbr64
  ret
```

assistant: ```c
void debug_scanner_state(int state) {
  switch (state) {
  case 1:;
    break;
  case 2:;
    break;
  case 3:;
    break;
  case 0:;
    break;
  default:;
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<debug_scanner_state>:
  endbr64
  ret
```

assistant: ```c
void debug_scanner_state(int state) {
  switch (state) {
  case 1:;
    break;
  case 2:;
    break;
  case 3:;
    break;
  case 0:;
    break;
  default:;
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<debug_scanner_state>:
  endbr64
  ret
```

assistant: ```c
void debug_scanner_state(int state) {
  switch (state) {
  case 1:;
    break;
  case 2:;
    break;
  case 3:;
    break;
  case 0:;
    break;
  default:;
    break;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L54:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jbe    L28
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L28:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L17
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L54
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (*s1 && *s2 && (*s1 == *s2) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return *s1 - *s2;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncmp>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L6
  lea    0x1(%rdx),%r9
  mov    $0x1,%ecx
  jmp    L53
L64:
  movzbl (%rdi),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L6
L53:
  movzbl (%rsi),%r8d
  cmp    %al,%r8b
  jne    L6
  test   %r8b,%r8b
  je     L6
  cmp    %r9,%rcx
  je     L6
  cmp    %rcx,%rdx
  jbe    L64
  add    $0x1,%rdi
  add    $0x1,%rsi
  jmp    L64
L6:
  movsbl %al,%eax
  movsbl (%rsi),%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (*s1 && *s2 && (*s1 == *s2) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return *s1 - *s2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  test   %al,%al
  je     L66
  lea    0x1(%rdx),%r9
  mov    $0x1,%ecx
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L56:
  cmp    %r8b,%al
  jne    L0
  cmp    %rcx,%r9
  je     L0
  cmp    %rcx,%rdx
  jbe    L20
  movsbl 0x1(%rsi),%r8d
  add    $0x1,%rdi
  add    $0x1,%rsi
L20:
  movsbl (%rdi),%eax
  add    $0x1,%rcx
  test   %al,%al
  je     L66
L11:
  test   %r8b,%r8b
  jne    L56
L0:
  sub    %r8d,%eax
  ret
L66:
  xor    %eax,%eax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (*s1 && *s2 && (*s1 == *s2) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return *s1 - *s2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strncmp>:
  endbr64
  movsbl (%rdi),%eax
  movsbl (%rsi),%r8d
  test   %al,%al
  je     L60
  lea    0x1(%rdx),%r9
  mov    $0x1,%ecx
  nopl   0x0(%rax,%rax,1)
L5:
  test   %r8b,%r8b
  je     L67
L78:
  cmp    %r8b,%al
  jne    L67
  cmp    %rcx,%r9
  je     L67
  cmp    %rcx,%rdx
  jbe    L17
  movsbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%r11
  lea    0x1(%rsi),%r10
  add    $0x1,%rcx
  movsbl 0x1(%rsi),%r8d
  test   %al,%al
  je     L60
  mov    %r11,%rdi
  mov    %r10,%rsi
  test   %r8b,%r8b
  jne    L78
L67:
  sub    %r8d,%eax
  ret
  nopl   0x0(%rax)
L17:
  add    $0x1,%rcx
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L60:
  xor    %eax,%eax
  sub    %r8d,%eax
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t len) {
  int p = 0;
  while (*s1 && *s2 && (*s1 == *s2) && p < len) {
    p++;
    if (p < len) {
      s1++;
      s2++;
    }
  }
  return *s1 - *s2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<vp8_dc_only_idct_add_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %ax,-0x14(%rbp)
  movswl -0x14(%rbp),%eax
  add    $0x4,%eax
  sar    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L41
L18:
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L53:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L48
  movl   $0x0,-0x8(%rbp)
L48:
  cmpl   $0xff,-0x8(%rbp)
  jle    L40
  movl   $0xff,-0x8(%rbp)
L40:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x3,-0xc(%rbp)
  jle    L53
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rax,-0x28(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  addl   $0x1,-0x10(%rbp)
L41:
  cmpl   $0x3,-0x10(%rbp)
  jle    L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void vp8_dc_only_idct_add_c(short input_dc, unsigned char *pred_ptr, int pred_stride, unsigned char *dst_ptr, int dst_stride) {
  int a1 = ((input_dc + 4) >> 3);
  int r, c;
  for (r = 0; r < 4; r++) {
    for (c = 0; c < 4; c++) {
      int a = a1 + pred_ptr[c];
      if (a < 0)
        a = 0;
      if (a > 255)
        a = 255;
      dst_ptr[c] = (unsigned char)a;
    }
    dst_ptr += dst_stride;
    pred_ptr += pred_stride;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vp8_dc_only_idct_add_c>:
  endbr64
  mov    %rsi,%r10
  mov    %rcx,%r9
  movswl %di,%edi
  add    $0x4,%edi
  sar    $0x3,%edi
  mov    $0x4,%r11d
  movslq %r8d,%r8
  movslq %edx,%rdx
L0:
  mov    $0x0,%ecx
L10:
  movzbl (%r10,%rcx,1),%eax
  add    %edi,%eax
  mov    $0xff,%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  test   %eax,%eax
  mov    $0x0,%esi
  cmovs  %esi,%eax
  mov    %al,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    $0x4,%rcx
  jne    L10
  add    %r8,%r9
  add    %rdx,%r10
  sub    $0x1,%r11d
  jne    L0
  ret
```

assistant: ```c
void vp8_dc_only_idct_add_c(short input_dc, unsigned char *pred_ptr, int pred_stride, unsigned char *dst_ptr, int dst_stride) {
  int a1 = ((input_dc + 4) >> 3);
  int r, c;
  for (r = 0; r < 4; r++) {
    for (c = 0; c < 4; c++) {
      int a = a1 + pred_ptr[c];
      if (a < 0)
        a = 0;
      if (a > 255)
        a = 255;
      dst_ptr[c] = (unsigned char)a;
    }
    dst_ptr += dst_stride;
    pred_ptr += pred_stride;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<vp8_dc_only_idct_add_c>:
  endbr64
  movswl %di,%edi
  mov    %rsi,%r10
  mov    %rcx,%r9
  movslq %r8d,%r8
  add    $0x4,%edi
  movslq %edx,%rdx
  mov    $0x4,%r11d
  sar    $0x3,%edi
L19:
  xor    %ecx,%ecx
L15:
  movzbl (%r10,%rcx,1),%eax
  mov    $0xff,%esi
  add    %edi,%eax
  cmp    %esi,%eax
  cmovg  %esi,%eax
  xor    %esi,%esi
  test   %eax,%eax
  cmovs  %esi,%eax
  mov    %al,(%r9,%rcx,1)
  add    $0x1,%rcx
  cmp    $0x4,%rcx
  jne    L15
  add    %r8,%r9
  add    %rdx,%r10
  sub    $0x1,%r11d
  jne    L19
  ret
```

assistant: ```c
void vp8_dc_only_idct_add_c(short input_dc, unsigned char *pred_ptr, int pred_stride, unsigned char *dst_ptr, int dst_stride) {
  int a1 = ((input_dc + 4) >> 3);
  int r, c;
  for (r = 0; r < 4; r++) {
    for (c = 0; c < 4; c++) {
      int a = a1 + pred_ptr[c];
      if (a < 0)
        a = 0;
      if (a > 255)
        a = 255;
      dst_ptr[c] = (unsigned char)a;
    }
    dst_ptr += dst_stride;
    pred_ptr += pred_stride;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L6
L12:
  mov    -0x38(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L0
L27:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    %rax,-0x18(%rbp)
L6:
  mov    -0x10(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jb     L12
  mov    -0x10(%rbp),%rax
L0:
  leave
  ret
```

assistant: ```c
int xread(int sd, void *buf, size_t len) {
  char *p = (char *)buf;
  size_t nrecv = 0;
  size_t rv;
  while (nrecv < len) {
    rv = read(sd, p, len - nrecv);
    if (0 > rv && errno == EINTR)
      continue;
    if (0 > rv)
      return -1;
    if (0 == rv)
      return 0;
    nrecv += rv;
    p += rv;
  }
  return nrecv;
}
```
user: What is the c source code of the assembly code below:

```asm
<xread>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r12
  test   %rdx,%rdx
  je     L49
  mov    %edi,%r13d
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L41:
  mov    %r12,%rdx
  sub    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L36
  add    %rax,%rbx
  add    %rax,%rbp
  cmp    %rbx,%r12
  ja     L41
L0:
  mov    %ebx,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  mov    %rdx,%rbx
  jmp    L0
L36:
  mov    $0x0,%eax
  jmp    L15
```

assistant: ```c
int xread(int sd, void *buf, size_t len) {
  char *p = (char *)buf;
  size_t nrecv = 0;
  size_t rv;
  while (nrecv < len) {
    rv = read(sd, p, len - nrecv);
    if (0 > rv && errno == EINTR)
      continue;
    if (0 > rv)
      return -1;
    if (0 == rv)
      return 0;
    nrecv += rv;
    p += rv;
  }
  return nrecv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xread>:
  endbr64
  test   %rdx,%rdx
  je     L13
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L25
L10:
  add    %rax,%rbx
  add    %rax,%rbp
  cmp    %rbx,%r13
  jbe    L39
L25:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  sub    %rbx,%rdx
  call   <read@plt>
  test   %rax,%rax
  jne    L10
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L39:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xread(int sd, void *buf, size_t len) {
  char *p = (char *)buf;
  size_t nrecv = 0;
  size_t rv;
  while (nrecv < len) {
    rv = read(sd, p, len - nrecv);
    if (0 > rv && errno == EINTR)
      continue;
    if (0 > rv)
      return -1;
    if (0 == rv)
      return 0;
    nrecv += rv;
    p += rv;
  }
  return nrecv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xread>:
  endbr64
  test   %rdx,%rdx
  je     L25
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L29
L4:
  add    %rax,%rbx
  add    %rax,%rbp
  cmp    %rbx,%r13
  jbe    L15
L29:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  sub    %rbx,%rdx
  call   <read@plt>
  test   %rax,%rax
  jne    L4
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L15:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xread(int sd, void *buf, size_t len) {
  char *p = (char *)buf;
  size_t nrecv = 0;
  size_t rv;
  while (nrecv < len) {
    rv = read(sd, p, len - nrecv);
    if (0 > rv && errno == EINTR)
      continue;
    if (0 > rv)
      return -1;
    if (0 == rv)
      return 0;
    nrecv += rv;
    p += rv;
  }
  return nrecv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<zipPrevEncodeLengthForceLarge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L16
  mov    -0x8(%rbp),%rax
  movb   $0xfe,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  jmp    L19
L16:
  nop
L19:
  leave
  ret
```

assistant: ```c
void zipPrevEncodeLengthForceLarge(unsigned char *p, unsigned int len) {
  if (p == NULL)
    return;
  p[0] = 254;
  memcpy(p + 1, &len, sizeof(len));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zipPrevEncodeLengthForceLarge>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %rdi,%rdi
  je     L8
  movb   $0xfe,(%rdi)
  lea    0xc(%rsp),%rsi
  add    $0x1,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
L8:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void zipPrevEncodeLengthForceLarge(unsigned char *p, unsigned int len) {
  if (p == NULL)
    return;
  p[0] = 254;
  memcpy(p + 1, &len, sizeof(len));
}
```
user: What is the c source code of the assembly code below?

```asm
<zipPrevEncodeLengthForceLarge>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %rdi,%rdi
  je     L8
  movb   $0xfe,(%rdi)
  lea    0xc(%rsp),%rsi
  add    $0x1,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
L8:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void zipPrevEncodeLengthForceLarge(unsigned char *p, unsigned int len) {
  if (p == NULL)
    return;
  p[0] = 254;
  memcpy(p + 1, &len, sizeof(len));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zipPrevEncodeLengthForceLarge>:
  endbr64
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %rdi,%rdi
  je     L8
  movb   $0xfe,(%rdi)
  lea    0xc(%rsp),%rsi
  add    $0x1,%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
L8:
  add    $0x18,%rsp
  ret
```

assistant: ```c
void zipPrevEncodeLengthForceLarge(unsigned char *p, unsigned int len) {
  if (p == NULL)
    return;
  p[0] = 254;
  memcpy(p + 1, &len, sizeof(len));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L14
L10:
  addl   $0x1,-0x4(%rbp)
L14:
  cmpl   $0xffffffe,-0x4(%rbp)
  jbe    L10
  cmpl   $0xfffffff,-0x4(%rbp)
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int x;
  while (x < 0x0fffffff) {
    x++;
  }
  __VERIFIER_assert(x > 0x0fffffff);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
L4:
  add    $0x1,%eax
  cmp    $0xfffffff,%eax
  jne    L4
  mov    $0x0,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x;
  while (x < 0x0fffffff) {
    x++;
  }
  __VERIFIER_assert(x > 0x0fffffff);
}
```