user: 这段汇编代码用C语言表示是什么样的？

```asm
<incorrect_tokens>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <reset@plt>
  mov    $0x6d,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D31(%rip),%rsi
  call   <assert@plt>
  mov    $0x77,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D9(%rip),%rsi
  call   <assert@plt>
  mov    $0x64,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D12(%rip),%rsi
  call   <assert@plt>
  mov    $0x3c,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D10(%rip),%rsi
  call   <assert@plt>
  mov    $0x3e,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D37(%rip),%rsi
  call   <assert@plt>
  mov    $0x61,%ebx
  movabs $0x6e20736920272027,%r12
  movabs $0x6c6176206120746f,%r13
  movabs $0x6e656b6f74206469,%r14
  mov    %rsp,%r15
  movabs $0x802010000000005,%rbp
  jmp    L63
L70:
  lea    -0x3c(%rbx),%eax
  bt     %rax,%rbp
  jb     L19
L60:
  mov    %bl,0x1(%rsp)
  mov    $0x0,%eax
  call   <reset@plt>
  mov    %ebx,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  mov    %r15,%rsi
  call   <assert@plt>
  add    $0x1,%ebx
  cmp    $0x7b,%ebx
  je     L35
L63:
  mov    %r12,(%rsp)
  mov    %r13,0x8(%rsp)
  mov    %r14,0x10(%rsp)
  movw   $0x2e,0x18(%rsp)
  cmp    $0x77,%ebx
  jg     L60
  cmp    $0x3b,%ebx
  jg     L70
  lea    -0x2b(%rbx),%eax
  test   $0xfffffffd,%eax
  jne    L60
L19:
  add    $0x1,%ebx
  jmp    L63
L35:
  mov    $0x0,%eax
  call   <reset@plt>
  mov    $0x21,%edi
  call   <syntactically_correct@plt>
  mov    $0x61,%edi
  call   <syntactically_correct@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  lea    D28(%rip),%rsi
  call   <assert@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D31
type_infered: string
name: extract_symbolic_data
arguments: tag: D9
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string
name: extract_symbolic_data
arguments: tag: D37
type_infered: string
name: extract_symbolic_data
arguments: tag: D28
type_infered: string

tool: D31: 'm' is a not valid token with no dwarf or sub

tool: D9: 'w' is a not valid token with no dwarf or sub

tool: D12: 'd' is a not valid token with no dwarf or sub

tool: D10: '>' is a not valid token with no dwarf or sub

tool: D37: '<' is a not valid token with no dwarf or sub

tool: D28: '!a' is not syntactically correct

assistant: ```c
void incorrect_tokens() {
  reset();
  assert(!syntactically_correct('m'), "'m' is a not valid token with no dwarf or sub");
  assert(!syntactically_correct('w'), "'w' is a not valid token with no dwarf or sub");
  assert(!syntactically_correct('d'), "'d' is a not valid token with no dwarf or sub");
  assert(!syntactically_correct('<'), "'>' is a not valid token with no dwarf or sub");
  assert(!syntactically_correct('>'), "'<' is a not valid token with no dwarf or sub");
  for (int i = 'a'; i <= 'z'; i++) {
    char message[26] = "' ' is not a valid token.";
    switch (i) {
    case '+':
    case '-':
    case 'm':
    case 'w':
    case 'd':
    case '<':
    case '>':
      break;
    default:
      message[1] = i;
      reset();
      assert(!syntactically_correct(i), message);
    }
  }
  reset();
  syntactically_correct('!');
  assert(!syntactically_correct('a'), "'!a' is not syntactically correct");
}
```