ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<DoShortCountTest>:
  endbr64
  push   %r13
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %esi,%r12d
  mov    $0x100,%esi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rdi,%rdx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r13
  mov    $0xffffffff,%eax
  lea    0xe(%rsp),%rcx
  mov    %r13,%rdi
  mov    %ax,0xe(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movaps %xmm0,0x100(%rsp)
  call   <_snprintf@plt>
  movswl 0xe(%rsp),%edx
  cmp    %r12d,%edx
  je     L26
  mov    %r12d,%esi
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <Fail@plt>
L26:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x1(%rax),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L28
L30:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x120,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <Fail@plt>
  jmp    L30
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type: string
name: unpack_data
arguments: data_tag: D11
type: string

tool: D19: ERROR: Expected count parameter to resolve to %d, got %X


tool: D11: ERROR: Expected "%s" got "%s".


assistant: ```c
void DoShortCountTest(const char *formatstr, int param, const char *checkstr) {
  char buf[256] = {0};
  short int n = -1;
  _snprintf(buf, 256, formatstr, &n);
  if (n != param) {
    Fail("ERROR: Expected count parameter to resolve to %d, got %X\n", param, n);
  }
  if (memcmp(buf, checkstr, strlen(checkstr) + 1) != 0) {
    Fail("ERROR: Expected \"%s\" got \"%s\".\n", checkstr, buf);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<transTableSetup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <factorize@plt>
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cmp    $0x25,%eax
  jle    L12
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L12:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  movl   $0x1,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    -0x20(%rbp),%rdx
  add    $0x4,%rdx
  mov    (%rdx),%edi
  mov    -0x28(%rbp),%rcx
  add    $0x4,%rcx
  cltd
  idiv   %edi
  mov    %eax,(%rcx)
  movl   $0x2,-0x4(%rbp)
  jmp    L9
L20:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rsi
  mov    -0x18(%rbp),%rdx
  add    %rsi,%rdx
  imul   %ecx,%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%edi
  mov    -0x4(%rbp),%ecx
  movslq %ecx,%rcx
  lea    0x0(,%rcx,4),%rsi
  mov    -0x28(%rbp),%rcx
  add    %rsi,%rcx
  cltd
  idiv   %edi
  mov    %eax,(%rcx)
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L20
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string
name: parse_data
arguments: data_label: D11
type: string

tool: D3: 
Prime factor of FFT length too large : %6d

tool: D11: 
Please modify the value of maxPrimeFactor in mixfft.c

assistant: ```c
void transTableSetup(int sofar[], int actual[], int remain[], int *nFact, int *nPoints) {
  int i;
  factorize(*nPoints, nFact, actual);
  if (actual[1] > 37) {
    printf("\nPrime factor of FFT length too large : %6d", actual[1]);
    printf("\nPlease modify the value of maxPrimeFactor in mixfft.c");
    exit(1);
  }
  remain[0] = *nPoints;
  sofar[1] = 1;
  remain[1] = *nPoints / actual[1];
  for (i = 2; i <= *nFact; i++) {
    sofar[i] = sofar[i - 1] * actual[i - 1];
    remain[i] = remain[i - 1] / actual[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transTableSetup>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r13
  mov    %r8,%r14
  mov    %rsi,%rdx
  mov    %rcx,%rsi
  mov    (%r8),%edi
  call   <factorize@plt>
  mov    0x4(%rbx),%esi
  cmp    $0x25,%esi
  jg     L10
L38:
  mov    (%r14),%eax
  mov    %eax,0x0(%rbp)
  movl   $0x1,0x4(%r12)
  mov    (%r14),%eax
  cltd
  idivl  0x4(%rbx)
  mov    %eax,0x4(%rbp)
  cmpl   $0x1,0x0(%r13)
  jle    L11
  mov    $0x2,%ecx
L39:
  mov    -0x4(%r12,%rcx,4),%eax
  imul   -0x4(%rbx,%rcx,4),%eax
  mov    %eax,(%r12,%rcx,4)
  mov    -0x4(%rbp,%rcx,4),%eax
  cltd
  idivl  (%rbx,%rcx,4)
  mov    %eax,0x0(%rbp,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,0x0(%r13)
  jge    L39
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D7: 
Prime factor of FFT length too large : %6d

tool: D4: 
Please modify the value of maxPrimeFactor in mixfft.c

assistant: ```c
void transTableSetup(int sofar[], int actual[], int remain[], int *nFact, int *nPoints) {
  int i;
  factorize(*nPoints, nFact, actual);
  if (actual[1] > 37) {
    printf("\nPrime factor of FFT length too large : %6d", actual[1]);
    printf("\nPlease modify the value of maxPrimeFactor in mixfft.c");
    exit(1);
  }
  remain[0] = *nPoints;
  sofar[1] = 1;
  remain[1] = *nPoints / actual[1];
  for (i = 2; i <= *nFact; i++) {
    sofar[i] = sofar[i - 1] * actual[i - 1];
    remain[i] = remain[i - 1] / actual[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<transTableSetup>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    (%r8),%edi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rsi,%rdx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  call   <factorize@plt>
  mov    0x4(%rbx),%esi
  cmp    $0x25,%esi
  jg     L39
L24:
  mov    (%r14),%eax
  mov    %eax,0x0(%rbp)
  movl   $0x1,0x4(%r12)
  mov    (%r14),%eax
  cltd
  idivl  0x4(%rbx)
  mov    %eax,0x4(%rbp)
  cmpl   $0x1,0x0(%r13)
  jle    L26
  mov    $0x2,%ecx
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    -0x4(%r12,%rcx,4),%eax
  imul   -0x4(%rbx,%rcx,4),%eax
  mov    %eax,(%r12,%rcx,4)
  mov    -0x4(%rbp,%rcx,4),%eax
  cltd
  idivl  (%rbx,%rcx,4)
  mov    %eax,0x0(%rbp,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,0x0(%r13)
  jge    L9
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L39:
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L24
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D13: 
Prime factor of FFT length too large : %6d

tool: D11: 
Please modify the value of maxPrimeFactor in mixfft.c

assistant: ```c
void transTableSetup(int sofar[], int actual[], int remain[], int *nFact, int *nPoints) {
  int i;
  factorize(*nPoints, nFact, actual);
  if (actual[1] > 37) {
    printf("\nPrime factor of FFT length too large : %6d", actual[1]);
    printf("\nPlease modify the value of maxPrimeFactor in mixfft.c");
    exit(1);
  }
  remain[0] = *nPoints;
  sofar[1] = 1;
  remain[1] = *nPoints / actual[1];
  for (i = 2; i <= *nFact; i++) {
    sofar[i] = sofar[i - 1] * actual[i - 1];
    remain[i] = remain[i - 1] / actual[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<transTableSetup>:
  endbr64
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    (%r8),%edi
  push   %rbp
  mov    %rdx,%rbp
  mov    %rsi,%rdx
  push   %rbx
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  call   <factorize@plt>
  mov    0x4(%rbx),%esi
  cmp    $0x25,%esi
  jg     L2
L37:
  mov    (%r14),%eax
  mov    %eax,0x0(%rbp)
  movl   $0x1,0x4(%r12)
  mov    (%r14),%eax
  cltd
  idivl  0x4(%rbx)
  mov    %eax,0x4(%rbp)
  cmpl   $0x1,0x0(%r13)
  jle    L28
  mov    $0x2,%ecx
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    -0x4(%r12,%rcx,4),%eax
  imul   -0x4(%rbx,%rcx,4),%eax
  mov    %eax,(%r12,%rcx,4)
  mov    -0x4(%rbp,%rcx,4),%eax
  cltd
  idivl  (%rbx,%rcx,4)
  mov    %eax,0x0(%rbp,%rcx,4)
  add    $0x1,%rcx
  cmp    %ecx,0x0(%r13)
  jge    L32
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L2:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L37
```

tool_calls: name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D5
datatype: string

tool: D14: 
Prime factor of FFT length too large : %6d

tool: D5: 
Please modify the value of maxPrimeFactor in mixfft.c

assistant: ```c
void transTableSetup(int sofar[], int actual[], int remain[], int *nFact, int *nPoints) {
  int i;
  factorize(*nPoints, nFact, actual);
  if (actual[1] > 37) {
    printf("\nPrime factor of FFT length too large : %6d", actual[1]);
    printf("\nPlease modify the value of maxPrimeFactor in mixfft.c");
    exit(1);
  }
  remain[0] = *nPoints;
  sofar[1] = 1;
  remain[1] = *nPoints / actual[1];
  for (i = 2; i <= *nFact; i++) {
    sofar[i] = sofar[i - 1] * actual[i - 1];
    remain[i] = remain[i - 1] / actual[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<aapatterns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x2c(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  mov    -0x24(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  jg     L33
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <aapatternnum@plt>
  mov    %eax,-0x28(%rbp)
L33:
  mov    -0x28(%rbp),%eax
  sub    $0xb,%eax
  cmp    $0x1c,%eax
  ja     L0
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D9(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D9(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    -0x2c(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <aapattern1124@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L36
  mov    -0x2c(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <aapattern19@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L36
  mov    -0x2c(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <aapattern20@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L36
  mov    -0x2c(%rbp),%edi
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <aapattern39@plt>
  mov    %eax,-0x8(%rbp)
  jmp    L36
  cmpl   $0x0,-0x4(%rbp)
  je     L19
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  jmp    L70
L19:
  mov    $0x0,%eax
L70:
  mov    %eax,-0x8(%rbp)
  jmp    L36
L0:
  nop
L36:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int aapatterns(struct raster_struct *rp, int irow, int icol, int gridnum, int patternum, int grayscale) {
  int aaval = (-1);
  int iscenter = (gridnum & 1);
  int aapatternnum(), aapattern1124(), aapattern19(), aapattern20(), aapattern39();
  if (1) {
    if (patternum < 1)
      patternum = aapatternnum(gridnum);
    switch (patternum) {
    default:
      break;
    case 11:
    case 24:
      aaval = aapattern1124(rp, irow, icol, gridnum, grayscale);
      break;
    case 19:
      aaval = aapattern19(rp, irow, icol, gridnum, grayscale);
      break;
    case 20:
      aaval = aapattern20(rp, irow, icol, gridnum, grayscale);
      break;
    case 39:
      aaval = aapattern39(rp, irow, icol, gridnum, grayscale);
      break;
    case 29:
      aaval = (iscenter ? grayscale - 1 : 0);
      break;
    }
  }
  return (aaval);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<aapatterns>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%r14d
  mov    %ecx,%ebx
  mov    %r9d,%ebp
  test   %r8d,%r8d
  jle    L16
L52:
  sub    $0xb,%r8d
  cmp    $0x1c,%r8d
  ja     L7
  mov    %r8d,%r8d
  lea    D4(%rip),%rdx
  movslq (%rdx,%r8,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L16:
  mov    %ecx,%edi
  mov    $0x0,%eax
  call   <aapatternnum@plt>
  mov    %eax,%r8d
  jmp    L52
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <aapattern1124@plt>
  jmp    L71
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <aapattern19@plt>
  jmp    L71
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <aapattern20@plt>
  jmp    L71
  mov    %ebp,%r8d
  mov    %ebx,%ecx
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <aapattern39@plt>
  jmp    L71
  sub    $0x1,%ebp
  mov    %ebx,%eax
  and    $0x1,%eax
  cmovne %ebp,%eax
  jmp    L71
L7:
  mov    $0xffffffff,%eax
L71:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int aapatterns(struct raster_struct *rp, int irow, int icol, int gridnum, int patternum, int grayscale) {
  int aaval = (-1);
  int iscenter = (gridnum & 1);
  int aapatternnum(), aapattern1124(), aapattern19(), aapattern20(), aapattern39();
  if (1) {
    if (patternum < 1)
      patternum = aapatternnum(gridnum);
    switch (patternum) {
    default:
      break;
    case 11:
    case 24:
      aaval = aapattern1124(rp, irow, icol, gridnum, grayscale);
      break;
    case 19:
      aaval = aapattern19(rp, irow, icol, gridnum, grayscale);
      break;
    case 20:
      aaval = aapattern20(rp, irow, icol, gridnum, grayscale);
      break;
    case 39:
      aaval = aapattern39(rp, irow, icol, gridnum, grayscale);
      break;
    case 29:
      aaval = (iscenter ? grayscale - 1 : 0);
      break;
    }
  }
  return (aaval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aapatterns>:
  endbr64
  push   %r14
  mov    %r8d,%eax
  mov    %edx,%r14d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x10,%rsp
  test   %r8d,%r8d
  jle    L27
L16:
  sub    $0xb,%eax
  cmp    $0x1c,%eax
  ja     L1
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x10,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  xchg   %ax,%ax
L27:
  mov    %ecx,%edi
  xor    %eax,%eax
  mov    %esi,0xc(%rsp)
  mov    %ecx,0x8(%rsp)
  call   <aapatternnum@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%ecx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    10a0 <aapattern1124@plt>
  nopl   0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    10b0 <aapattern19@plt>
  nopl   0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    1090 <aapattern20@plt>
  nopl   0x0(%rax,%rax,1)
  mov    %ecx,%eax
  lea    -0x1(%rbx),%r9d
  and    $0x1,%eax
  cmovne %r9d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    10d0 <aapattern39@plt>
```

assistant: ```c
int aapatterns(struct raster_struct *rp, int irow, int icol, int gridnum, int patternum, int grayscale) {
  int aaval = (-1);
  int iscenter = (gridnum & 1);
  int aapatternnum(), aapattern1124(), aapattern19(), aapattern20(), aapattern39();
  if (1) {
    if (patternum < 1)
      patternum = aapatternnum(gridnum);
    switch (patternum) {
    default:
      break;
    case 11:
    case 24:
      aaval = aapattern1124(rp, irow, icol, gridnum, grayscale);
      break;
    case 19:
      aaval = aapattern19(rp, irow, icol, gridnum, grayscale);
      break;
    case 20:
      aaval = aapattern20(rp, irow, icol, gridnum, grayscale);
      break;
    case 39:
      aaval = aapattern39(rp, irow, icol, gridnum, grayscale);
      break;
    case 29:
      aaval = (iscenter ? grayscale - 1 : 0);
      break;
    }
  }
  return (aaval);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aapatterns>:
  endbr64
  push   %r14
  mov    %r8d,%eax
  mov    %edx,%r14d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x10,%rsp
  test   %r8d,%r8d
  jle    L29
L18:
  sub    $0xb,%eax
  cmp    $0x1c,%eax
  ja     L2
  lea    D7(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  cs nopw 0x0(%rax,%rax,1)
L2:
  add    $0x10,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  xchg   %ax,%ax
L29:
  mov    %ecx,%edi
  xor    %eax,%eax
  mov    %esi,0xc(%rsp)
  mov    %ecx,0x8(%rsp)
  call   <aapatternnum@plt>
  mov    0xc(%rsp),%esi
  mov    0x8(%rsp),%ecx
  jmp    L18
  nopl   0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    10a0 <aapattern1124@plt>
  nopl   0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    10b0 <aapattern19@plt>
  nopl   0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    1090 <aapattern20@plt>
  nopl   0x0(%rax,%rax,1)
  mov    %ecx,%eax
  lea    -0x1(%rbx),%r9d
  and    $0x1,%eax
  cmovne %r9d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
  add    $0x10,%rsp
  mov    %ebx,%r8d
  mov    %r14d,%edx
  mov    %rbp,%rdi
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r14
  jmp    10d0 <aapattern39@plt>
```

assistant: ```c
int aapatterns(struct raster_struct *rp, int irow, int icol, int gridnum, int patternum, int grayscale) {
  int aaval = (-1);
  int iscenter = (gridnum & 1);
  int aapatternnum(), aapattern1124(), aapattern19(), aapattern20(), aapattern39();
  if (1) {
    if (patternum < 1)
      patternum = aapatternnum(gridnum);
    switch (patternum) {
    default:
      break;
    case 11:
    case 24:
      aaval = aapattern1124(rp, irow, icol, gridnum, grayscale);
      break;
    case 19:
      aaval = aapattern19(rp, irow, icol, gridnum, grayscale);
      break;
    case 20:
      aaval = aapattern20(rp, irow, icol, gridnum, grayscale);
      break;
    case 39:
      aaval = aapattern39(rp, irow, icol, gridnum, grayscale);
      break;
    case 29:
      aaval = (iscenter ? grayscale - 1 : 0);
      break;
    }
  }
  return (aaval);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__VERIFIER_atomic_acquire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assume@plt>
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void __VERIFIER_atomic_acquire(int *m) {
  __VERIFIER_assume(*m == 0);
  *m = 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__VERIFIER_atomic_acquire>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  cmpl   $0x0,(%rdi)
  sete   %dil
  movzbl %dil,%edi
  call   <__VERIFIER_assume@plt>
  movl   $0x1,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void __VERIFIER_atomic_acquire(int *m) {
  __VERIFIER_assume(*m == 0);
  *m = 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__VERIFIER_atomic_acquire>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  mov    (%rbx),%eax
  test   %eax,%eax
  sete   %dil
  call   <__VERIFIER_assume@plt>
  movl   $0x1,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void __VERIFIER_atomic_acquire(int *m) {
  __VERIFIER_assume(*m == 0);
  *m = 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__VERIFIER_atomic_acquire>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  mov    (%rbx),%eax
  test   %eax,%eax
  sete   %dil
  call   <__VERIFIER_assume@plt>
  movl   $0x1,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void __VERIFIER_atomic_acquire(int *m) {
  __VERIFIER_assume(*m == 0);
  *m = 1;
}
```