ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<divpwr2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0x1f,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int sign = x >> 31;
  int mask = (1 << n) + (~0);
  int bias = sign & mask;
  return (x + bias) >> n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<divpwr2>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  sub    $0x1,%eax
  mov    %edi,%edx
  sar    $0x1f,%edx
  and    %edx,%eax
  add    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int sign = x >> 31;
  int mask = (1 << n) + (~0);
  int bias = sign & mask;
  return (x + bias) >> n;
}
```
user: What is the c source code of the assembly code below?

```asm
<divpwr2>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  mov    %edi,%edx
  shl    %cl,%eax
  sar    $0x1f,%edx
  sub    $0x1,%eax
  and    %edx,%eax
  add    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int sign = x >> 31;
  int mask = (1 << n) + (~0);
  int bias = sign & mask;
  return (x + bias) >> n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divpwr2>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  mov    %edi,%edx
  shl    %cl,%eax
  sar    $0x1f,%edx
  sub    $0x1,%eax
  and    %edx,%eax
  add    %edi,%eax
  sar    %cl,%eax
  ret
```

assistant: ```c
int divpwr2(int x, int n) {
  int sign = x >> 31;
  int mask = (1 << n) + (~0);
  int bias = sign & mask;
  return (x + bias) >> n;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<expansion_sum_zeroelim2>:
  endbr64
  mov    %edx,%r10d
  mov    %rcx,%r9
  movsd  (%rcx),%xmm1
  test   %edi,%edi
  jle    L47
  mov    %rsi,%rax
  lea    -0x1(%rdi),%edx
  lea    0x8(%rsi,%rdx,8),%rcx
  mov    $0x0,%edx
  pxor   %xmm5,%xmm5
  movapd %xmm5,%xmm6
  jmp    L0
L96:
  movslq %edx,%rsi
  movsd  %xmm0,(%r8,%rsi,8)
  lea    0x1(%rdx),%edx
L146:
  add    $0x8,%rax
  cmp    %rcx,%rax
  je     L117
L0:
  movsd  (%rax),%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm0
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L96
  ucomisd %xmm6,%xmm0
  je     L146
  jmp    L96
L47:
  mov    $0x0,%edx
L117:
  movslq %edx,%rax
  movsd  %xmm1,(%r8,%rax,8)
  cmp    $0x1,%r10d
  jle    L33
  lea    0x8(%r9),%rdi
  lea    -0x2(%r10),%eax
  lea    0x10(%r9,%rax,8),%r9
  mov    $0x0,%r10d
  lea    0x8(%r8),%r11
  pxor   %xmm5,%xmm5
  movapd %xmm5,%xmm6
  jmp    L145
L20:
  movslq %edx,%rsi
  movsd  %xmm0,(%r8,%rsi,8)
  lea    0x1(%rdx),%edx
L93:
  add    $0x8,%rax
  cmp    %rax,%rcx
  je     L126
L45:
  movsd  (%rax),%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  subsd  %xmm0,%xmm3
  movapd %xmm1,%xmm4
  subsd  %xmm3,%xmm4
  subsd  %xmm4,%xmm0
  subsd  %xmm3,%xmm2
  addsd  %xmm2,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L20
  ucomisd %xmm6,%xmm0
  je     L93
  jmp    L20
L58:
  mov    %r10d,%edx
L126:
  movslq %edx,%rax
  movsd  %xmm1,(%r8,%rax,8)
  add    $0x8,%rdi
  cmp    %r9,%rdi
  je     L33
L145:
  movsd  (%rdi),%xmm1
  test   %edx,%edx
  js     L58
  mov    %r8,%rax
  mov    %edx,%edx
  lea    (%r11,%rdx,8),%rcx
  mov    %r10d,%edx
  jmp    L45
L33:
  lea    0x1(%rdx),%eax
  ret
```

assistant: ```c
int expansion_sum_zeroelim2(elen, e, flen, f, h)
int elen;
double *e;
int flen;
double *f;
double *h;
{
  double Q, hh;
  double Qnew;
  int eindex, findex, hindex, hlast;
  double enow;
  double bvirt;
  double avirt, bround, around;
  hindex = 0;
  Q = f[0];
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    hh = around + bround;
    Q = Qnew;
    if (hh != 0.0) {
      h[hindex++] = hh;
    }
  }
  h[hindex] = Q;
  hlast = hindex;
  for (findex = 1; findex < flen; findex++) {
    hindex = 0;
    Q = f[findex];
    for (eindex = 0; eindex <= hlast; eindex++) {
      enow = h[eindex];
      Qnew = (double)(Q + enow);
      bvirt = (double)(Qnew - Q);
      avirt = Qnew - bvirt;
      bround = enow - bvirt;
      around = Q - avirt;
      hh = around + bround;
      Q = Qnew;
      if (hh != 0) {
        h[hindex++] = hh;
      }
    }
    h[hindex] = Q;
    hlast = hindex;
  }
  return hlast + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<expansion_sum_zeroelim2>:
  endbr64
  movsd  (%rcx),%xmm1
  mov    %edx,%r10d
  mov    %rcx,%r9
  test   %edi,%edi
  jle    L8
  lea    -0x1(%rdi),%eax
  xor    %edx,%edx
  pxor   %xmm5,%xmm5
  lea    0x8(%rsi,%rax,8),%rax
  nopl   0x0(%rax)
L93:
  movsd  (%rsi),%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  subsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L98
  je     L34
L98:
  movslq %edx,%rcx
  add    $0x1,%edx
  movsd  %xmm0,(%r8,%rcx,8)
L34:
  add    $0x8,%rsi
  cmp    %rsi,%rax
  jne    L93
  movslq %edx,%rcx
  lea    (%r8,%rcx,8),%rax
L64:
  movsd  %xmm1,(%rax)
  cmp    $0x1,%r10d
  jle    L0
  lea    -0x2(%r10),%eax
  lea    0x8(%r9),%rdi
  pxor   %xmm5,%xmm5
  movslq %edx,%rcx
  lea    0x10(%r9,%rax,8),%r10
  lea    0x8(%r8),%r9
  nopw   0x0(%rax,%rax,1)
L48:
  movsd  (%rdi),%xmm1
  mov    %r8,%rax
  lea    (%r9,%rcx,8),%rcx
  xor    %edx,%edx
  nopl   (%rax)
L10:
  movsd  (%rax),%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  subsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L91
  je     L56
L91:
  movslq %edx,%rsi
  add    $0x1,%edx
  movsd  %xmm0,(%r8,%rsi,8)
L56:
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L10
  movslq %edx,%rcx
  add    $0x8,%rdi
  movsd  %xmm1,(%r8,%rcx,8)
  cmp    %rdi,%r10
  jne    L48
L0:
  lea    0x1(%rdx),%eax
  ret
L8:
  mov    %r8,%rax
  xor    %edx,%edx
  jmp    L64
```

assistant: ```c
int expansion_sum_zeroelim2(elen, e, flen, f, h)
int elen;
double *e;
int flen;
double *f;
double *h;
{
  double Q, hh;
  double Qnew;
  int eindex, findex, hindex, hlast;
  double enow;
  double bvirt;
  double avirt, bround, around;
  hindex = 0;
  Q = f[0];
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    hh = around + bround;
    Q = Qnew;
    if (hh != 0.0) {
      h[hindex++] = hh;
    }
  }
  h[hindex] = Q;
  hlast = hindex;
  for (findex = 1; findex < flen; findex++) {
    hindex = 0;
    Q = f[findex];
    for (eindex = 0; eindex <= hlast; eindex++) {
      enow = h[eindex];
      Qnew = (double)(Q + enow);
      bvirt = (double)(Qnew - Q);
      avirt = Qnew - bvirt;
      bround = enow - bvirt;
      around = Q - avirt;
      hh = around + bround;
      Q = Qnew;
      if (hh != 0) {
        h[hindex++] = hh;
      }
    }
    h[hindex] = Q;
    hlast = hindex;
  }
  return hlast + 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<expansion_sum_zeroelim2>:
  endbr64
  movsd  (%rcx),%xmm1
  mov    %edx,%r10d
  mov    %rcx,%r9
  test   %edi,%edi
  jle    L76
  lea    -0x1(%rdi),%eax
  xor    %edx,%edx
  pxor   %xmm5,%xmm5
  lea    0x8(%rsi,%rax,8),%rax
  nopl   0x0(%rax)
L83:
  movsd  (%rsi),%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  subsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L60
  je     L72
L60:
  movslq %edx,%rcx
  add    $0x1,%edx
  movsd  %xmm0,(%r8,%rcx,8)
L72:
  add    $0x8,%rsi
  cmp    %rsi,%rax
  jne    L83
  movslq %edx,%rcx
  lea    (%r8,%rcx,8),%rax
L15:
  movsd  %xmm1,(%rax)
  cmp    $0x1,%r10d
  jle    L77
  lea    -0x2(%r10),%eax
  lea    0x8(%r9),%rdi
  pxor   %xmm5,%xmm5
  movslq %edx,%rcx
  lea    0x10(%r9,%rax,8),%r10
  lea    0x8(%r8),%r9
  nopw   0x0(%rax,%rax,1)
L84:
  movsd  (%rdi),%xmm1
  mov    %r8,%rax
  lea    (%r9,%rcx,8),%rcx
  xor    %edx,%edx
  nopl   (%rax)
L69:
  movsd  (%rax),%xmm2
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  subsd  %xmm0,%xmm3
  subsd  %xmm3,%xmm4
  subsd  %xmm3,%xmm2
  subsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm0
  ucomisd %xmm5,%xmm0
  jp     L68
  je     L94
L68:
  movslq %edx,%rsi
  add    $0x1,%edx
  movsd  %xmm0,(%r8,%rsi,8)
L94:
  add    $0x8,%rax
  cmp    %rax,%rcx
  jne    L69
  movslq %edx,%rcx
  add    $0x8,%rdi
  movsd  %xmm1,(%r8,%rcx,8)
  cmp    %rdi,%r10
  jne    L84
L77:
  lea    0x1(%rdx),%eax
  ret
L76:
  mov    %r8,%rax
  xor    %edx,%edx
  jmp    L15
```

assistant: ```c
int expansion_sum_zeroelim2(elen, e, flen, f, h)
int elen;
double *e;
int flen;
double *f;
double *h;
{
  double Q, hh;
  double Qnew;
  int eindex, findex, hindex, hlast;
  double enow;
  double bvirt;
  double avirt, bround, around;
  hindex = 0;
  Q = f[0];
  for (eindex = 0; eindex < elen; eindex++) {
    enow = e[eindex];
    Qnew = (double)(Q + enow);
    bvirt = (double)(Qnew - Q);
    avirt = Qnew - bvirt;
    bround = enow - bvirt;
    around = Q - avirt;
    hh = around + bround;
    Q = Qnew;
    if (hh != 0.0) {
      h[hindex++] = hh;
    }
  }
  h[hindex] = Q;
  hlast = hindex;
  for (findex = 1; findex < flen; findex++) {
    hindex = 0;
    Q = f[findex];
    for (eindex = 0; eindex <= hlast; eindex++) {
      enow = h[eindex];
      Qnew = (double)(Q + enow);
      bvirt = (double)(Qnew - Q);
      avirt = Qnew - bvirt;
      bround = enow - bvirt;
      around = Q - avirt;
      hh = around + bround;
      Q = Qnew;
      if (hh != 0) {
        h[hindex++] = hh;
      }
    }
    h[hindex] = Q;
    hlast = hindex;
  }
  return hlast + 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<varTest>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  movsd  D80(%rip),%xmm0
  lea    D101(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%esi
  lea    D78(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D98(%rip),%rdi
  call   <puts@plt>
  movl   $0xaa,(%rsp)
  movl   $0x11,0x4(%rsp)
  movl   $0x22,0x8(%rsp)
  movl   $0x33,0x28(%rsp)
  mov    $0x33,%esi
  lea    D72(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D105(%rip),%rdi
  call   <puts@plt>
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%edx
  mov    $0x28,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %rsp,%rsi
  mov    $0x14,%edx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  movl   $0xff,0x14(%rbx)
  mov    $0xff,%esi
  lea    D76(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D84(%rip),%rdi
  call   <puts@plt>
  lea    0xd0(%rsp),%rbp
  lea    D65(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D106(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x108,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D80
type: byte[8]
name: unpack_data
arguments: label: D101
type: string
name: unpack_data
arguments: label: D35
type: string
name: unpack_data
arguments: label: D78
type: string
name: unpack_data
arguments: label: D98
type: string
name: unpack_data
arguments: label: D72
type: string
name: unpack_data
arguments: label: D105
type: string
name: unpack_data
arguments: label: D76
type: string
name: unpack_data
arguments: label: D84
type: string
name: unpack_data
arguments: label: D65
type: string
name: unpack_data
arguments: label: D106
type: string

tool: {"D80": [0x00,0x00,0x00,0x20,0x85,0xeb,0x07,0x40]}

tool: D101: Accessing global_var: %f


tool: D35: Pointers

tool: D78: Accessing pointer: %d


tool: D98: Static Arrays

tool: D72: Accessing array: %d


tool: D105: Dynamic Arrays

tool: D76: Accessing dyn array: %d


tool: D84: Strings

tool: D65: Hello String!

tool: D106: Accessing str: %s, str2: %s


assistant: ```c
void varTest() {
  float local_var = 2.99;
  printf("Accessing global_var: %f\n", local_var);
  printf("Pointers\n");
  int x = 10, *x_ptr;
  x_ptr = &x;
  printf("Accessing pointer: %d\n", *x_ptr);
  printf("Static Arrays\n");
  int arr[50];
  arr[0] = 0xAA;
  arr[1] = 0x11;
  arr[2] = 0x22;
  arr[x] = 0x33;
  printf("Accessing array: %d\n", arr[x]);
  printf("Dynamic Arrays\n");
  int *darr = malloc(10 * sizeof(int));
  memset(darr, 10 * sizeof(int), 0);
  memcpy(darr, arr, 5 * sizeof(int));
  darr[5] = 0xFF;
  printf("Accessing dyn array: %d\n", darr[5]);
  printf("Strings\n");
  char *str = "Hello String!", str2[32];
  strcpy(str2, str);
  printf("Accessing str: %s, str2: %s\n", str, str2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ntlm_responses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rcx
  lea    -0x24(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x50(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lm_hash_password@plt>
  lea    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <lm_deshash@plt>
  lea    -0x20(%rbp),%rax
  add    $0x7,%rax
  mov    -0x38(%rbp),%rdx
  lea    0x8(%rdx),%rdi
  lea    -0x24(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  call   <lm_deshash@plt>
  lea    -0x20(%rbp),%rax
  add    $0xe,%rax
  mov    -0x38(%rbp),%rdx
  lea    0x10(%rdx),%rdi
  lea    -0x24(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  call   <lm_deshash@plt>
  mov    -0x50(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <nt_hash_password@plt>
  lea    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rcx
  mov    -0x40(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <lm_deshash@plt>
  lea    -0x20(%rbp),%rax
  add    $0x7,%rax
  mov    -0x40(%rbp),%rdx
  lea    0x8(%rdx),%rdi
  lea    -0x24(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  call   <lm_deshash@plt>
  lea    -0x20(%rbp),%rax
  add    $0xe,%rax
  mov    -0x40(%rbp),%rdx
  lea    0x10(%rdx),%rdi
  lea    -0x24(%rbp),%rcx
  mov    %rax,%rdx
  mov    %rcx,%rsi
  call   <lm_deshash@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x15,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void ntlm_responses(unsigned char *lm_resp, unsigned char *nt_resp, const unsigned char *challenge, const char *secret) {
  unsigned char hash[21];
  DES_cblock nonce;
  memcpy(&nonce, challenge, sizeof nonce);
  lm_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(lm_resp, &nonce, hash);
  lm_deshash(lm_resp + 8, &nonce, hash + 7);
  lm_deshash(lm_resp + 16, &nonce, hash + 14);
  nt_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(nt_resp, &nonce, hash);
  lm_deshash(nt_resp + 8, &nonce, hash + 7);
  lm_deshash(nt_resp + 16, &nonce, hash + 14);
  memset(hash, 0, sizeof hash);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ntlm_responses>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  mov    $0x4,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x20(%rsp),%r13
  mov    %r14,0x8(%rsp)
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <lm_hash_password@plt>
  lea    0x30(%rsp),%r15
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <lm_deshash@plt>
  lea    0x27(%rsp),%r14
  lea    0x8(%r12),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  lea    0x2e(%rsp),%rax
  lea    0x10(%r12),%rdi
  mov    %rax,%r12
  mov    %rax,%rdx
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  mov    0x8(%rsp),%rsi
  mov    %r13,%rdi
  call   <nt_hash_password@plt>
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %r15,%rdi
  call   <memset@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <lm_deshash@plt>
  lea    0x8(%rbx),%rdi
  mov    %r14,%rdx
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  lea    0x10(%rbx),%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  mov    $0x15,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ntlm_responses(unsigned char *lm_resp, unsigned char *nt_resp, const unsigned char *challenge, const char *secret) {
  unsigned char hash[21];
  DES_cblock nonce;
  memcpy(&nonce, challenge, sizeof nonce);
  lm_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(lm_resp, &nonce, hash);
  lm_deshash(lm_resp + 8, &nonce, hash + 7);
  lm_deshash(lm_resp + 16, &nonce, hash + 14);
  nt_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(nt_resp, &nonce, hash);
  lm_deshash(nt_resp + 8, &nonce, hash + 7);
  lm_deshash(nt_resp + 16, &nonce, hash + 14);
  memset(hash, 0, sizeof hash);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ntlm_responses>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    $0x4,%edx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  lea    0x20(%rsp),%r13
  mov    %rbp,%rdi
  lea    0x2e(%rsp),%r15
  call   <memcpy@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <lm_hash_password@plt>
  lea    0x30(%rsp),%r9
  xor    %esi,%esi
  mov    $0x5,%edx
  mov    %r9,%rdi
  mov    %r9,0x8(%rsp)
  call   <memset@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <lm_deshash@plt>
  lea    0x27(%rsp),%r8
  lea    0x8(%r12),%rdi
  mov    %rbp,%rsi
  mov    %r8,%rdx
  mov    %r8,(%rsp)
  call   <lm_deshash@plt>
  mov    %r15,%rdx
  lea    0x10(%r12),%rdi
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <nt_hash_password@plt>
  mov    0x8(%rsp),%rdi
  xor    %esi,%esi
  mov    $0x5,%edx
  call   <memset@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <lm_deshash@plt>
  mov    (%rsp),%rdx
  lea    0x8(%rbx),%rdi
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  lea    0x10(%rbx),%rdi
  mov    %r15,%rdx
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  xor    %esi,%esi
  mov    $0x15,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ntlm_responses(unsigned char *lm_resp, unsigned char *nt_resp, const unsigned char *challenge, const char *secret) {
  unsigned char hash[21];
  DES_cblock nonce;
  memcpy(&nonce, challenge, sizeof nonce);
  lm_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(lm_resp, &nonce, hash);
  lm_deshash(lm_resp + 8, &nonce, hash + 7);
  lm_deshash(lm_resp + 16, &nonce, hash + 14);
  nt_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(nt_resp, &nonce, hash);
  lm_deshash(nt_resp + 8, &nonce, hash + 7);
  lm_deshash(nt_resp + 16, &nonce, hash + 14);
  memset(hash, 0, sizeof hash);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ntlm_responses>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    $0x4,%edx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rbp
  lea    0x20(%rsp),%r13
  mov    %rbp,%rdi
  lea    0x2e(%rsp),%r15
  call   <memcpy@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <lm_hash_password@plt>
  lea    0x30(%rsp),%r9
  xor    %esi,%esi
  mov    $0x5,%edx
  mov    %r9,%rdi
  mov    %r9,0x8(%rsp)
  call   <memset@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <lm_deshash@plt>
  lea    0x27(%rsp),%r8
  lea    0x8(%r12),%rdi
  mov    %rbp,%rsi
  mov    %r8,%rdx
  mov    %r8,(%rsp)
  call   <lm_deshash@plt>
  mov    %r15,%rdx
  lea    0x10(%r12),%rdi
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <nt_hash_password@plt>
  mov    0x8(%rsp),%rdi
  xor    %esi,%esi
  mov    $0x5,%edx
  call   <memset@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <lm_deshash@plt>
  mov    (%rsp),%rdx
  lea    0x8(%rbx),%rdi
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  lea    0x10(%rbx),%rdi
  mov    %r15,%rdx
  mov    %rbp,%rsi
  call   <lm_deshash@plt>
  xor    %esi,%esi
  mov    $0x15,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ntlm_responses(unsigned char *lm_resp, unsigned char *nt_resp, const unsigned char *challenge, const char *secret) {
  unsigned char hash[21];
  DES_cblock nonce;
  memcpy(&nonce, challenge, sizeof nonce);
  lm_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(lm_resp, &nonce, hash);
  lm_deshash(lm_resp + 8, &nonce, hash + 7);
  lm_deshash(lm_resp + 16, &nonce, hash + 14);
  nt_hash_password(hash, secret);
  memset(hash + 16, 0, 5);
  lm_deshash(nt_resp, &nonce, hash);
  lm_deshash(nt_resp + 8, &nonce, hash + 7);
  lm_deshash(nt_resp + 16, &nonce, hash + 14);
  memset(hash, 0, sizeof hash);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_wifi_5g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D1
data_type: string

tool: D8: echo '{"method":"pref-set","arguments":{"confs":{"wl_band":"5GHz"}}}' | /web/rpc.cgi >/dev/null 2>&1

tool: D1: echo '{"method":"revalidate","arguments":{"wl":{"action":"restart"}}}' | /web/rpc.cgi >/dev/null 2>&1

assistant: ```c
void set_wifi_5g() {
  system("echo '{\"method\":\"pref-set\",\"arguments\":{\"confs\":{\"wl_"
         "band\":\"5GHz\"}}}' | /web/rpc.cgi >/dev/null 2>&1");
  system("echo '{\"method\":\"revalidate\",\"arguments\":{\"wl\":{\"act"
         "ion\":\"restart\"}}}' | /web/rpc.cgi >/dev/null 2>&1");
}
```