ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<wm_setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <sigchld@plt>
  xor    %eax,%eax
  call   <dm_check_check@plt>
  xor    %eax,%eax
  call   <dm_cursors_init@plt>
  xor    %eax,%eax
  call   <dm_set_window_properties@plt>
  xor    %eax,%eax
  call   <dm_set_root@plt>
  xor    %eax,%eax
  call   <dm_set_multimonitors@plt>
  xor    %eax,%eax
  call   <wm_load_config@plt>
  xor    %eax,%eax
  call   <wm_grab_keys@plt>
  xor    %eax,%eax
  call   <wm_color_schemes@plt>
  xor    %eax,%eax
  call   <wm_windows_scan@plt>
  xor    %eax,%eax
  call   <wm_run_autostart@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11b0 <urgentbar_create@plt>
```

assistant: ```c
void wm_setup() {
  sigchld(0);
  dm_check_check();
  dm_cursors_init();
  dm_set_window_properties();
  dm_set_root();
  dm_set_multimonitors();
  wm_load_config();
  wm_grab_keys();
  wm_color_schemes();
  wm_windows_scan();
  wm_run_autostart();
  urgentbar_create();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wm_setup>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <sigchld@plt>
  xor    %eax,%eax
  call   <dm_check_check@plt>
  xor    %eax,%eax
  call   <dm_cursors_init@plt>
  xor    %eax,%eax
  call   <dm_set_window_properties@plt>
  xor    %eax,%eax
  call   <dm_set_root@plt>
  xor    %eax,%eax
  call   <dm_set_multimonitors@plt>
  xor    %eax,%eax
  call   <wm_load_config@plt>
  xor    %eax,%eax
  call   <wm_grab_keys@plt>
  xor    %eax,%eax
  call   <wm_color_schemes@plt>
  xor    %eax,%eax
  call   <wm_windows_scan@plt>
  xor    %eax,%eax
  call   <wm_run_autostart@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    11b0 <urgentbar_create@plt>
```

assistant: ```c
void wm_setup() {
  sigchld(0);
  dm_check_check();
  dm_cursors_init();
  dm_set_window_properties();
  dm_set_root();
  dm_set_multimonitors();
  wm_load_config();
  wm_grab_keys();
  wm_color_schemes();
  wm_windows_scan();
  wm_run_autostart();
  urgentbar_create();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<match_tz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  add    $0x1,%rdx
  sub    %rdx,%rax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  jne    L23
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L37
L23:
  cmpl   $0x2,-0x14(%rbp)
  je     L82
  movl   $0x63,-0x1c(%rbp)
  jmp    L37
L82:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L37
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strtoul@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  add    $0x1,%rdx
  sub    %rdx,%rax
  cmp    $0x5,%rax
  je     L37
  movl   $0x63,-0x1c(%rbp)
L37:
  cmpl   $0x3b,-0x1c(%rbp)
  jg     L64
  cmpl   $0x17,-0x20(%rbp)
  jg     L64
  mov    -0x20(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L28
  negl   -0x18(%rbp)
L28:
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
L64:
  mov    -0x10(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int match_tz(const char *date, int *offp) {
  char *end;
  int hour = strtoul(date + 1, &end, 10);
  int n = end - (date + 1);
  int min = 0;
  if (n == 4) {
    min = hour % 100;
    hour = hour / 100;
  } else if (n != 2) {
    min = 99;
  } else if (*end == ':') {
    min = strtoul(end + 1, &end, 10);
    if (end - (date + 1) != 5)
      min = 99;
  }
  if (min < 60 && hour < 24) {
    int offset = hour * 60 + min;
    if (*date == '-')
      offset = -offset;
    *offp = offset;
  }
  return end - date;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<match_tz>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x1(%rdi),%r13
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    %r13,%rdi
  call   <strtoul@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rdi
  mov    %rdi,%rax
  sub    %r13,%rax
  cmp    $0x4,%eax
  je     L14
  cmp    $0x2,%eax
  jne    L36
  mov    $0x0,%eax
  cmpb   $0x3a,(%rdi)
  jne    L38
  mov    %rsp,%rsi
  add    $0x1,%rdi
  mov    $0xa,%edx
  call   <strtoul@plt>
  mov    (%rsp),%rdx
  sub    %r13,%rdx
  cmp    $0x5,%rdx
  jne    L36
  jmp    L38
L14:
  movslq %ebx,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %ebx,%ecx
  sar    $0x1f,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x64,%eax,%esi
  mov    %ebx,%eax
  sub    %esi,%eax
  sub    %ecx,%edx
  mov    %edx,%ebx
L38:
  cmp    $0x3b,%eax
  jg     L36
  cmp    $0x17,%ebx
  jg     L36
  imul   $0x3c,%ebx,%ebx
  add    %eax,%ebx
  mov    %ebx,%eax
  neg    %eax
  cmpb   $0x2d,0x0(%rbp)
  cmove  %eax,%ebx
  mov    %ebx,(%r12)
L36:
  mov    (%rsp),%eax
  sub    %ebp,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match_tz(const char *date, int *offp) {
  char *end;
  int hour = strtoul(date + 1, &end, 10);
  int n = end - (date + 1);
  int min = 0;
  if (n == 4) {
    min = hour % 100;
    hour = hour / 100;
  } else if (n != 2) {
    min = 99;
  } else if (*end == ':') {
    min = strtoul(end + 1, &end, 10);
    if (end - (date + 1) != 5)
      min = 99;
  }
  if (min < 60 && hour < 24) {
    int offset = hour * 60 + min;
    if (*date == '-')
      offset = -offset;
    *offp = offset;
  }
  return end - date;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<match_tz>:
  endbr64
  push   %r14
  mov    $0xa,%edx
  push   %r13
  lea    0x1(%rdi),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rsi
  call   <strtoul@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rax
  mov    %rax,%rdx
  sub    %r13,%rdx
  cmp    $0x4,%edx
  je     L96
  cmp    $0x2,%edx
  je     L95
L78:
  sub    %ebp,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L95:
  xor    %ecx,%ecx
  cmpb   $0x3a,(%rax)
  mov    $0x1,%edx
  je     L44
L5:
  cmp    $0x17,%ebx
  jg     L78
  test   %dl,%dl
  je     L78
  imul   $0x3c,%ebx,%ebx
  add    %ecx,%ebx
  mov    %ebx,%edx
  neg    %edx
  cmpb   $0x2d,0x0(%rbp)
  cmove  %edx,%ebx
  mov    %ebx,(%r12)
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L96:
  movslq %ebx,%rdx
  mov    %ebx,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x25,%rdx
  mov    %edx,%ecx
  sub    %esi,%ecx
  imul   $0x64,%ecx,%edi
  mov    %ebx,%ecx
  mov    %edx,%ebx
  sub    %esi,%ebx
  sub    %edi,%ecx
  cmp    $0x3b,%ecx
  setle  %dl
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L44:
  mov    $0xa,%edx
  lea    0x1(%rax),%rdi
  mov    %r14,%rsi
  call   <strtoul@plt>
  mov    %eax,%ecx
  mov    (%rsp),%rax
  mov    %rax,%rdx
  sub    %r13,%rdx
  cmp    $0x5,%rdx
  jne    L78
  cmp    $0x3b,%ecx
  setle  %dl
  jmp    L5
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match_tz(const char *date, int *offp) {
  char *end;
  int hour = strtoul(date + 1, &end, 10);
  int n = end - (date + 1);
  int min = 0;
  if (n == 4) {
    min = hour % 100;
    hour = hour / 100;
  } else if (n != 2) {
    min = 99;
  } else if (*end == ':') {
    min = strtoul(end + 1, &end, 10);
    if (end - (date + 1) != 5)
      min = 99;
  }
  if (min < 60 && hour < 24) {
    int offset = hour * 60 + min;
    if (*date == '-')
      offset = -offset;
    *offp = offset;
  }
  return end - date;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<match_tz>:
  endbr64
  push   %r14
  mov    $0xa,%edx
  push   %r13
  lea    0x1(%rdi),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13,%rdi
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rsi
  call   <strtoul@plt>
  mov    %eax,%ebx
  mov    (%rsp),%rax
  mov    %rax,%rdx
  sub    %r13,%rdx
  cmp    $0x4,%edx
  je     L66
  cmp    $0x2,%edx
  je     L9
L60:
  sub    %ebp,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  xor    %ecx,%ecx
  cmpb   $0x3a,(%rax)
  mov    $0x1,%edx
  je     L8
L45:
  cmp    $0x17,%ebx
  jg     L60
  test   %dl,%dl
  je     L60
  imul   $0x3c,%ebx,%ebx
  add    %ecx,%ebx
  mov    %ebx,%edx
  neg    %edx
  cmpb   $0x2d,0x0(%rbp)
  cmove  %edx,%ebx
  mov    %ebx,(%r12)
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L66:
  movslq %ebx,%rdx
  mov    %ebx,%esi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x25,%rdx
  mov    %edx,%ecx
  sub    %esi,%ecx
  imul   $0x64,%ecx,%edi
  mov    %ebx,%ecx
  mov    %edx,%ebx
  sub    %esi,%ebx
  sub    %edi,%ecx
  cmp    $0x3b,%ecx
  setle  %dl
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L8:
  mov    $0xa,%edx
  lea    0x1(%rax),%rdi
  mov    %r14,%rsi
  call   <strtoul@plt>
  mov    %eax,%ecx
  mov    (%rsp),%rax
  mov    %rax,%rdx
  sub    %r13,%rdx
  cmp    $0x5,%rdx
  jne    L60
  cmp    $0x3b,%ecx
  setle  %dl
  jmp    L45
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int match_tz(const char *date, int *offp) {
  char *end;
  int hour = strtoul(date + 1, &end, 10);
  int n = end - (date + 1);
  int min = 0;
  if (n == 4) {
    min = hour % 100;
    hour = hour / 100;
  } else if (n != 2) {
    min = 99;
  } else if (*end == ':') {
    min = strtoul(end + 1, &end, 10);
    if (end - (date + 1) != 5)
      min = 99;
  }
  if (min < 60 && hour < 24) {
    int offset = hour * 60 + min;
    if (*date == '-')
      offset = -offset;
    *offp = offset;
  }
  return end - date;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L21
  mov    $0x0,%eax
  call   <abort@plt>
L21:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void check(int *a, int *res, int len) {
  int i;
  for (i = 0; i < len; i++)
    if (a[i] != res[i])
      abort();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L31
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    $0x0,%ebx
  jmp    L9
L46:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L17
L9:
  mov    0x0(%r13,%rbx,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  je     L46
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L46
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  ret
```

assistant: ```c
void check(int *a, int *res, int len) {
  int i;
  for (i = 0; i < len; i++)
    if (a[i] != res[i])
      abort();
}
```
user: Translate the below assembly code into C programming language:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L27
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L6:
  mov    0x0(%r13,%rbx,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  je     L20
  xor    %eax,%eax
  call   <abort@plt>
L20:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L27:
  ret
```

assistant: ```c
void check(int *a, int *res, int len) {
  int i;
  for (i = 0; i < len; i++)
    if (a[i] != res[i])
      abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check>:
  endbr64
  test   %edx,%edx
  jle    L7
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %edx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   (%rax)
L17:
  mov    0x0(%r13,%rbx,4),%eax
  cmp    %eax,(%r12,%rbx,4)
  je     L14
  xor    %eax,%eax
  call   <abort@plt>
L14:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  ret
```

assistant: ```c
void check(int *a, int *res, int len) {
  int i;
  for (i = 0; i < len; i++)
    if (a[i] != res[i])
      abort();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SetButtonValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%ecx
  mov    %esi,%eax
  mov    %cx,-0x4(%rbp)
  mov    %ax,-0x8(%rbp)
  mov    %edx,%eax
  mov    %al,-0xc(%rbp)
  mov    $0xee,%edi
  call   <SendChar@plt>
  mov    $0xb1,%edi
  call   <SendChar@plt>
  mov    $0x10,%edi
  call   <SendChar@plt>
  movzwl -0x4(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x4(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x8(%rbp),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzwl -0x8(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  movzbl -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  nop
  leave
  ret
```

assistant: ```c
void SetButtonValue(unsigned short int screen_id, unsigned short int control_id, unsigned char state) {
  SendChar((0XEE) & 0xFF);
  SendChar((0xB1) & 0xFF);
  SendChar((0x10) & 0xFF);
  SendChar(((screen_id) >> 8) & 0xFF);
  SendChar((screen_id)&0xFF);
  SendChar(((control_id) >> 8) & 0xFF);
  SendChar((control_id)&0xFF);
  SendChar((state)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<SetButtonValue>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %edx,%r12d
  mov    $0xee,%edi
  call   <SendChar@plt>
  mov    $0xb1,%edi
  call   <SendChar@plt>
  mov    $0x10,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  movzbl %r12b,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void SetButtonValue(unsigned short int screen_id, unsigned short int control_id, unsigned char state) {
  SendChar((0XEE) & 0xFF);
  SendChar((0xB1) & 0xFF);
  SendChar((0x10) & 0xFF);
  SendChar(((screen_id) >> 8) & 0xFF);
  SendChar((screen_id)&0xFF);
  SendChar(((control_id) >> 8) & 0xFF);
  SendChar((control_id)&0xFF);
  SendChar((state)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Translate the below assembly code into C programming language:

```asm
<SetButtonValue>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    $0xee,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <SendChar@plt>
  mov    $0xb1,%edi
  call   <SendChar@plt>
  mov    $0x10,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  movzbl %r12b,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  pop    %rbx
  mov    $0xff,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <SendChar@plt>
```

assistant: ```c
void SetButtonValue(unsigned short int screen_id, unsigned short int control_id, unsigned char state) {
  SendChar((0XEE) & 0xFF);
  SendChar((0xB1) & 0xFF);
  SendChar((0x10) & 0xFF);
  SendChar(((screen_id) >> 8) & 0xFF);
  SendChar((screen_id)&0xFF);
  SendChar(((control_id) >> 8) & 0xFF);
  SendChar((control_id)&0xFF);
  SendChar((state)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SetButtonValue>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %edi,%ebp
  mov    $0xee,%edi
  push   %rbx
  mov    %esi,%ebx
  call   <SendChar@plt>
  mov    $0xb1,%edi
  call   <SendChar@plt>
  mov    $0x10,%edi
  call   <SendChar@plt>
  mov    %ebp,%eax
  movzbl %ah,%edi
  call   <SendChar@plt>
  movzbl %bpl,%edi
  call   <SendChar@plt>
  movzbl %bh,%edi
  call   <SendChar@plt>
  movzbl %bl,%edi
  call   <SendChar@plt>
  movzbl %r12b,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  mov    $0xfc,%edi
  call   <SendChar@plt>
  mov    $0xff,%edi
  call   <SendChar@plt>
  pop    %rbx
  mov    $0xff,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <SendChar@plt>
```

assistant: ```c
void SetButtonValue(unsigned short int screen_id, unsigned short int control_id, unsigned char state) {
  SendChar((0XEE) & 0xFF);
  SendChar((0xB1) & 0xFF);
  SendChar((0x10) & 0xFF);
  SendChar(((screen_id) >> 8) & 0xFF);
  SendChar((screen_id)&0xFF);
  SendChar(((control_id) >> 8) & 0xFF);
  SendChar((control_id)&0xFF);
  SendChar((state)&0xFF);
  SendChar((((0XFFFCFFFF) >> 16) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) >> 16) & 0xFF);
  SendChar((((0XFFFCFFFF) & 0xFFFF) >> 8) & 0xFF);
  SendChar(((0XFFFCFFFF) & 0xFFFF) & 0xFF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chkcir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  movapd %xmm0,%xmm2
  subsd  -0x18(%rbp),%xmm2
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm2
  mulsd  %xmm0,%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L18
  mov    $0x0,%eax
  jmp    L14
L18:
  mov    $0x1,%eax
L14:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: f64

tool: D2: 0.5

assistant: ```c
bool chkcir(const double x, const double y) {
  const double x_c = 0.5;
  const double y_c = 0.5;
  const double r = 0.5;
  const double f = (x - x_c) * (x - x_c) + (y - y_c) * (y - y_c) - r * r;
  if (f > 0.0) {
    return false;
  } else {
    return true;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chkcir>:
  endbr64
  movsd  D2(%rip),%xmm2
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D22(%rip),%xmm0
  comisd D12(%rip),%xmm0
  setbe  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
data_type: f64
name: disassemble_data
arguments: tag: D22
data_type: f32[2]
name: disassemble_data
arguments: tag: D12
data_type: f32

tool: D2: 0.5

tool: {"D22": [0.0,1.625]}

tool: D12: 0

assistant: ```c
bool chkcir(const double x, const double y) {
  const double x_c = 0.5;
  const double y_c = 0.5;
  const double r = 0.5;
  const double f = (x - x_c) * (x - x_c) + (y - y_c) * (y - y_c) - r * r;
  if (f > 0.0) {
    return false;
  } else {
    return true;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chkcir>:
  endbr64
  movsd  D21(%rip),%xmm2
  xor    %eax,%eax
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D15(%rip),%xmm0
  comisd D18(%rip),%xmm0
  setbe  %al
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type_infered: f64
name: retrieve_data
arguments: data_tag: D15
type_infered: f32[2]
name: retrieve_data
arguments: data_tag: D18
type_infered: f32

tool: D21: 0.5

tool: {"D15": [0.0,1.625]}

tool: D18: 0

assistant: ```c
bool chkcir(const double x, const double y) {
  const double x_c = 0.5;
  const double y_c = 0.5;
  const double r = 0.5;
  const double f = (x - x_c) * (x - x_c) + (y - y_c) * (y - y_c) - r * r;
  if (f > 0.0) {
    return false;
  } else {
    return true;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<chkcir>:
  endbr64
  movsd  D26(%rip),%xmm2
  xor    %eax,%eax
  subsd  %xmm2,%xmm0
  subsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  subsd  D2(%rip),%xmm0
  comisd D23(%rip),%xmm0
  setbe  %al
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D26
data_type: f64
name: unpack_data
arguments: data_label: D2
data_type: f32[2]
name: unpack_data
arguments: data_label: D23
data_type: f32

tool: D26: 0.5

tool: {"D2": [0.0,1.625]}

tool: D23: 0

assistant: ```c
bool chkcir(const double x, const double y) {
  const double x_c = 0.5;
  const double y_c = 0.5;
  const double r = 0.5;
  const double f = (x - x_c) * (x - x_c) + (y - y_c) * (y - y_c) - r * r;
  if (f > 0.0) {
    return false;
  } else {
    return true;
  }
}
```