user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D21(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x358,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x348(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rdx
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  lea    0x20(%rsp),%rbp
  mov    0x18(%rsp),%esi
  mov    0x1c(%rsp),%edx
  mov    %rbp,%rdi
  call   <read_into_matrix@plt>
  mov    0x18(%rsp),%esi
  test   %esi,%esi
  jle    L171
  mov    0x1c(%rsp),%eax
  mov    %rbp,(%rsp)
  lea    0x1b0(%rsp),%rbx
  mov    %rbx,0x8(%rsp)
  mov    %rbx,%r12
  xor    %ebx,%ebx
  mov    %eax,%edx
  nopl   0x0(%rax,%rax,1)
L107:
  xor    %r15d,%r15d
  test   %eax,%eax
  jg     L81
  jmp    L75
  nopl   0x0(%rax)
L161:
  mov    %ecx,(%r12,%r15,4)
  add    $0x1,%r15
  mov    %eax,%edx
  cmp    %r15d,%eax
  jle    L16
L81:
  mov    (%rsp),%rdi
  mov    %r15d,%r13d
  mov    (%rdi,%r15,4),%ecx
  test   %ecx,%ecx
  je     L161
  movl   $0x1,(%r12,%r15,4)
  mov    $0x1,%r14d
  jmp    L44
  xchg   %ax,%ax
L177:
  add    $0x1,%r14d
L44:
  mov    %r14d,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <goodness@plt>
  test   %rax,%rax
  jne    L177
  mov    0x1c(%rsp),%eax
  lea    -0x1(%r14),%ecx
  mov    %ecx,(%r12,%r15,4)
  add    $0x1,%r15
  mov    %eax,%edx
  cmp    %r15d,%eax
  jg     L81
L16:
  mov    0x18(%rsp),%esi
L75:
  add    $0x1,%ebx
  addq   $0x28,(%rsp)
  add    $0x28,%r12
  cmp    %ebx,%esi
  jg     L107
L101:
  mov    0x8(%rsp),%r14
  mov    %r14,%rdi
  call   <max_matrix@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%ebx
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  je     L57
  mov    0x18(%rsp),%r8d
  test   %r8d,%r8d
  jle    L117
  mov    0x1c(%rsp),%edi
  xor    %esi,%esi
  lea    0x1(%rdi),%ecx
L139:
  mov    $0x1,%eax
  test   %edi,%edi
  jg     L125
  jmp    L48
  nopl   0x0(%rax)
L12:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L48
L125:
  mov    %eax,%edx
  cmp    %ebx,-0x4(%r14,%rax,4)
  jne    L12
  add    $0x1,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L117:
  mov    0x348(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L150
  add    $0x358,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  add    $0x1,%esi
  add    $0x28,%r14
  cmp    %esi,%r8d
  jne    L139
  jmp    L117
L57:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L117
L171:
  lea    0x1b0(%rsp),%rax
  mov    0x1c(%rsp),%edx
  mov    %rax,0x8(%rsp)
  jmp    L101
L150:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D29
type: string
name: extract_symbolic_data
arguments: tag: D26
type: string

tool: D21: %d %d

tool: D29: %d 

tool: D26: -1 -1

assistant: ```c
int main() {
  int a[10][10], m, n;
  int b[10][10];
  scanf("%d %d", &m, &n);
  read_into_matrix(a, m, n);
  for (int i = 0; i <= m - 1; i++) {
    for (int j = 0; j <= n - 1; j++) {
      if (a[i][j] == 0) {
        b[i][j] = 0;
      } else {
        b[i][j] = 1;
        int t = 1;
        while (goodness(a, i, j, t) != 0) {
          t++;
        }
        b[i][j] = t - 1;
      }
    }
  }
  int bmax = max_matrix(b, m, n);
  printf("%d ", bmax);
  if (bmax == 0) {
    printf("-1 -1");
  } else {
    for (int i = 0; i <= m - 1; i++) {
      for (int j = 0; j <= n - 1; j++) {
        if (b[i][j] == bmax) {
          printf("%d %d", i + 1, j + 1);
          goto end;
        }
      }
    }
  }
end:
  return 0;
}
```