ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<format_raw_event>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x410,%rsp
  mov    0xc(%rdi),%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  call   <resolve_pmu@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L31
  mov    0x8(%rbp),%r8d
  mov    %rsp,%r14
  mov    %rax,%rcx
  mov    $0x400,%esi
  lea    D36(%rip),%rdx
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <snprintf@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <free@plt>
  mov    0x4(%rbp),%edx
  test   %edx,%edx
  jne    L44
L55:
  mov    0x0(%rbp),%edx
  test   %edx,%edx
  jne    L30
L24:
  test   %r13,%r13
  je     L20
  movslq %ebx,%rdi
  mov    $0x400,%esi
  mov    %r13,%rcx
  xor    %eax,%eax
  sub    %ebx,%esi
  add    %r14,%rdi
  lea    D10(%rip),%rdx
  call   <snprintf@plt>
  add    %eax,%ebx
L20:
  mov    $0x400,%esi
  movslq %ebx,%rdi
  lea    D21(%rip),%rdx
  xor    %eax,%eax
  sub    %ebx,%esi
  add    %r14,%rdi
  call   <snprintf@plt>
  mov    %r14,%rdi
  call   <strdup@plt>
  mov    %rax,%r12
L31:
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x410,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L30:
  movslq %ebx,%rdi
  lea    D14(%rip),%rsi
  add    %r14,%rdi
  call   <sprintf@plt>
  add    %eax,%ebx
  jmp    L24
  nopl   0x0(%rax)
L44:
  movslq %ebx,%rdi
  lea    D40(%rip),%rsi
  add    %r14,%rdi
  call   <sprintf@plt>
  add    %eax,%ebx
  jmp    L55
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D36
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D21
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D40
type_guessed: string

tool: D36: %s/config=%#llx

tool: D10: ,name=%s

tool: D21: /

tool: D14: ,config2=%#llx

tool: D40: ,config1=%#llx

assistant: ```c
char *format_raw_event(struct perf_event_attr *attr, char *name) {
  char buf[1024];
  int off = 0;
  char *pmu;
  pmu = resolve_pmu(attr->type);
  if (!pmu)
    return NULL;
  off = snprintf(buf, 1024, "%s/config=%#llx", pmu, attr->config);
  free(pmu);
  if (attr->config1)
    off += sprintf(buf + off, ",config1=%#llx", attr->config1);
  if (attr->config2)
    off += sprintf(buf + off, ",config2=%#llx", attr->config2);
  if (name)
    off += snprintf(buf + off, 1024 - off, ",name=%s", name);
  off += snprintf(buf + off, 1024 - off, "/");
  return strdup(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<json_parse_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L7
  mov    $0x0,%eax
  jmp    L17
L7:
  mov    -0x8(%rbp),%rax
L17:
  leave
  ret
```

assistant: ```c
size_t json_parse_literal(const char *line, const char *literal) {
  const size_t len = strlen(literal);
  if (strncmp(line, literal, len) != 0)
    return 0;
  return len;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<json_parse_literal>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %rax,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t json_parse_literal(const char *line, const char *literal) {
  const size_t len = strlen(literal);
  if (strncmp(line, literal, len) != 0)
    return 0;
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<json_parse_literal>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%rdx
  mov    %rax,%r12
  call   <strncmp@plt>
  pop    %rbp
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t json_parse_literal(const char *line, const char *literal) {
  const size_t len = strlen(literal);
  if (strncmp(line, literal, len) != 0)
    return 0;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<json_parse_literal>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    %rax,%rdx
  mov    %rax,%r12
  call   <strncmp@plt>
  pop    %rbp
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
size_t json_parse_literal(const char *line, const char *literal) {
  const size_t len = strlen(literal);
  if (strncmp(line, literal, len) != 0)
    return 0;
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<ieee2flt_nan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x7f,%eax
  test   %eax,%eax
  jne    L14
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  pxor   %xmm0,%xmm0
  jmp    L55
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  shr    $0x7,%al
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0xff,-0xc(%rbp)
  jne    L47
  movss  D3(%rip),%xmm0
  jmp    L55
L47:
  mov    -0x18(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  or     $0xffffff80,%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  add    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L67
  movsd  -0x8(%rbp),%xmm0
  movq   D8(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L67:
  mov    -0xc(%rbp),%eax
  lea    -0x96(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <ldexp@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
L55:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: f32
name: read_data
arguments: data_label: D8
data_type: f32[2]

tool: D3: 9.999e+20

tool: {"D8": [0.0,-0.0]}

assistant: ```c
float ieee2flt_nan(unsigned char *ieee) {
  double fmant;
  int exp;
  if ((ieee[0] & 127) == 0 && ieee[1] == 0 && ieee[2] == 0 && ieee[3] == 0)
    return (float)0.0;
  exp = ((ieee[0] & 127) << 1) + (ieee[1] >> 7);
  if (exp == 255)
    return (float)9.999e20;
  fmant = (double)((int)ieee[3] + (int)(ieee[2] << 8) + (int)((ieee[1] | 128) << 16));
  if (ieee[0] & 128)
    fmant = -fmant;
  return (float)(ldexp(fmant, (int)(exp - 128 - 22)));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ieee2flt_nan>:
  endbr64
  movzbl (%rdi),%esi
  movzbl %sil,%eax
  test   $0x7f,%sil
  jne    L69
  movzbl 0x1(%rdi),%edx
  test   %dl,%dl
  jne    L69
  cmpb   $0x0,0x2(%rdi)
  jne    L47
  pxor   %xmm0,%xmm0
  cmpb   $0x0,0x3(%rdi)
  je     L53
L47:
  add    %eax,%eax
  movzbl %al,%eax
  jmp    L26
L53:
  ret
L69:
  movzbl 0x1(%rdi),%edx
  add    %eax,%eax
  movzbl %al,%eax
  mov    %edx,%ecx
  shr    $0x7,%cl
  movzbl %cl,%ecx
  add    %ecx,%eax
  cmp    $0xff,%eax
  je     L11
L26:
  sub    $0x8,%rsp
  movzbl 0x2(%rdi),%ecx
  shl    $0x8,%ecx
  movzbl 0x3(%rdi),%edi
  add    %edi,%ecx
  or     $0xffffff80,%edx
  movzbl %dl,%edx
  shl    $0x10,%edx
  add    %ecx,%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  test   %sil,%sil
  js     L2
L29:
  lea    -0x96(%rax),%edi
  call   <ldexp@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %rax,%xmm0
  add    $0x8,%rsp
  ret
L2:
  xorpd  D11(%rip),%xmm0
  jmp    L29
L11:
  movss  D13(%rip),%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D11
datatype: f32[4]
name: retrieve_data
arguments: data_tag: D13
datatype: f32

tool: {"D11": [0.0,-0.0,0.0,0.0]}

tool: D13: 9.999e+20

assistant: ```c
float ieee2flt_nan(unsigned char *ieee) {
  double fmant;
  int exp;
  if ((ieee[0] & 127) == 0 && ieee[1] == 0 && ieee[2] == 0 && ieee[3] == 0)
    return (float)0.0;
  exp = ((ieee[0] & 127) << 1) + (ieee[1] >> 7);
  if (exp == 255)
    return (float)9.999e20;
  fmant = (double)((int)ieee[3] + (int)(ieee[2] << 8) + (int)((ieee[1] | 128) << 16));
  if (ieee[0] & 128)
    fmant = -fmant;
  return (float)(ldexp(fmant, (int)(exp - 128 - 22)));
}
```
user: Translate the below assembly code into C programming language:

```asm
<ieee2flt_nan>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  mov    %eax,%ecx
  mov    %eax,%esi
  and    $0x7f,%ecx
  or     %dl,%cl
  jne    L13
  movzbl 0x2(%rdi),%ecx
  movzbl 0x3(%rdi),%edi
  pxor   %xmm0,%xmm0
  mov    %ecx,%r8d
  or     %dil,%r8b
  je     L58
  add    %eax,%eax
  movzbl %al,%eax
  jmp    L23
  nopl   (%rax)
L13:
  mov    %edx,%ecx
  add    %eax,%eax
  shr    $0x7,%cl
  movzbl %al,%eax
  movzbl %cl,%ecx
  add    %ecx,%eax
  cmp    $0xff,%eax
  je     L24
  movzbl 0x2(%rdi),%ecx
  movzbl 0x3(%rdi),%edi
L23:
  or     $0xffffff80,%edx
  shl    $0x8,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  movzbl %dl,%edx
  add    %edi,%ecx
  shl    $0x10,%edx
  add    %ecx,%edx
  cvtsi2sd %edx,%xmm0
  test   %sil,%sil
  js     L21
L1:
  lea    -0x96(%rax),%edi
  call   <ldexp@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %rax,%xmm0
  ret
L21:
  xorpd  D14(%rip),%xmm0
  jmp    L1
  nopw   0x0(%rax,%rax,1)
L24:
  movss  D9(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L58:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
datatype: f32[4]
name: parse_data
arguments: data_label: D9
datatype: f32

tool: {"D14": [0.0,-0.0,0.0,0.0]}

tool: D9: 9.999e+20

assistant: ```c
float ieee2flt_nan(unsigned char *ieee) {
  double fmant;
  int exp;
  if ((ieee[0] & 127) == 0 && ieee[1] == 0 && ieee[2] == 0 && ieee[3] == 0)
    return (float)0.0;
  exp = ((ieee[0] & 127) << 1) + (ieee[1] >> 7);
  if (exp == 255)
    return (float)9.999e20;
  fmant = (double)((int)ieee[3] + (int)(ieee[2] << 8) + (int)((ieee[1] | 128) << 16));
  if (ieee[0] & 128)
    fmant = -fmant;
  return (float)(ldexp(fmant, (int)(exp - 128 - 22)));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ieee2flt_nan>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%edx
  mov    %eax,%ecx
  mov    %eax,%esi
  and    $0x7f,%ecx
  or     %dl,%cl
  jne    L41
  movzbl 0x2(%rdi),%ecx
  movzbl 0x3(%rdi),%edi
  pxor   %xmm0,%xmm0
  mov    %ecx,%r8d
  or     %dil,%r8b
  je     L19
  add    %eax,%eax
  movzbl %al,%eax
  jmp    L54
  nopl   (%rax)
L41:
  mov    %edx,%ecx
  add    %eax,%eax
  shr    $0x7,%cl
  movzbl %al,%eax
  movzbl %cl,%ecx
  add    %ecx,%eax
  cmp    $0xff,%eax
  je     L17
  movzbl 0x2(%rdi),%ecx
  movzbl 0x3(%rdi),%edi
L54:
  or     $0xffffff80,%edx
  shl    $0x8,%ecx
  pxor   %xmm0,%xmm0
  sub    $0x8,%rsp
  movzbl %dl,%edx
  add    %edi,%ecx
  shl    $0x10,%edx
  add    %ecx,%edx
  cvtsi2sd %edx,%xmm0
  test   %sil,%sil
  js     L32
L2:
  lea    -0x96(%rax),%edi
  call   <ldexp@plt>
  pxor   %xmm0,%xmm0
  add    $0x8,%rsp
  cvtsi2ss %rax,%xmm0
  ret
L32:
  xorpd  D8(%rip),%xmm0
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L17:
  movss  D9(%rip),%xmm0
  ret
  nopl   0x0(%rax)
L19:
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: f32[4]
name: read_data
arguments: tag: D9
type: f32

tool: {"D8": [0.0,-0.0,0.0,0.0]}

tool: D9: 9.999e+20

assistant: ```c
float ieee2flt_nan(unsigned char *ieee) {
  double fmant;
  int exp;
  if ((ieee[0] & 127) == 0 && ieee[1] == 0 && ieee[2] == 0 && ieee[3] == 0)
    return (float)0.0;
  exp = ((ieee[0] & 127) << 1) + (ieee[1] >> 7);
  if (exp == 255)
    return (float)9.999e20;
  fmant = (double)((int)ieee[3] + (int)(ieee[2] << 8) + (int)((ieee[1] | 128) << 16));
  if (ieee[0] & 128)
    fmant = -fmant;
  return (float)(ldexp(fmant, (int)(exp - 128 - 22)));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  mov    D15(%rip),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <prime_sieve@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x20(%rbp)
  jmp    L9
L40:
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rcx
  movabs $0x8be589eac7,%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  test   %rax,%rax
  jne    L46
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L33
L46:
  subl   $0x1,-0x20(%rbp)
L9:
  cmpl   $0x0,-0x20(%rbp)
  jg     L40
L33:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
datatype: byte[8]
name: disassemble_data
arguments: label: D16
datatype: string

tool: {"D15": [0xa3,0x8e,0xcd,0x32,0xd4,0xa7,0x27,0x41]}

tool: D16: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, np;
  char *sieve;
  int *primes;
  np = prime_sieve(sqrt(600851475143LL), &sieve, &primes);
  for (i = np - 1; i > 0; i--) {
    if (600851475143LL % primes[i] == 0) {
      printf("%d\n", primes[i]);
      break;
    }
  }
  free(sieve);
  free(primes);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  movsd  D10(%rip),%xmm0
  mov    $0x1,%eax
  call   <prime_sieve@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L44
  mov    0x10(%rsp),%r9
  movslq %ecx,%rcx
  movabs $0x8be589eac7,%rdi
L35:
  mov    (%r9,%rcx,4),%r8d
  movslq %r8d,%rsi
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  je     L40
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jg     L35
  jmp    L44
L40:
  mov    %r8d,%esi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L44:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type: byte[8]
name: unpack_data
arguments: data_tag: D6
type: string

tool: {"D10": [0xa3,0x8e,0xcd,0x32,0xd4,0xa7,0x27,0x41]}

tool: D6: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, np;
  char *sieve;
  int *primes;
  np = prime_sieve(sqrt(600851475143LL), &sieve, &primes);
  for (i = np - 1; i > 0; i--) {
    if (600851475143LL % primes[i] == 0) {
      printf("%d\n", primes[i]);
      break;
    }
  }
  free(sieve);
  free(primes);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movsd  D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%eax
  call   <prime_sieve@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L47
  mov    0x10(%rsp),%r9
  movslq %ecx,%rcx
  movabs $0x8be589eac7,%rdi
  jmp    L40
  nop
L30:
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jle    L47
L40:
  mov    %rdi,%rax
  movslq (%r9,%rcx,4),%rsi
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L30
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L47:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
datatype: byte[8]
name: unpack_data
arguments: tag: D18
datatype: string

tool: {"D1": [0xa3,0x8e,0xcd,0x32,0xd4,0xa7,0x27,0x41]}

tool: D18: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, np;
  char *sieve;
  int *primes;
  np = prime_sieve(sqrt(600851475143LL), &sieve, &primes);
  for (i = np - 1; i > 0; i--) {
    if (600851475143LL % primes[i] == 0) {
      printf("%d\n", primes[i]);
      break;
    }
  }
  free(sieve);
  free(primes);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movsd  D7(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x1,%eax
  call   <prime_sieve@plt>
  lea    -0x1(%rax),%ecx
  test   %ecx,%ecx
  jle    L0
  mov    0x10(%rsp),%r9
  movslq %ecx,%rcx
  movabs $0x8be589eac7,%rdi
  jmp    L9
  nop
L16:
  sub    $0x1,%rcx
  test   %ecx,%ecx
  jle    L0
L9:
  mov    %rdi,%rax
  movslq (%r9,%rcx,4),%rsi
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L16
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rdi
  call   <free@plt>
  mov    0x10(%rsp),%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
datatype: byte[8]
name: extract_symbolic_data
arguments: data_label: D16
datatype: string

tool: {"D7": [0xa3,0x8e,0xcd,0x32,0xd4,0xa7,0x27,0x41]}

tool: D16: %d


assistant: ```c
int main(int argc, char **argv) {
  int i, np;
  char *sieve;
  int *primes;
  np = prime_sieve(sqrt(600851475143LL), &sieve, &primes);
  for (i = np - 1; i > 0; i--) {
    if (600851475143LL % primes[i] == 0) {
      printf("%d\n", primes[i]);
      break;
    }
  }
  free(sieve);
  free(primes);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L70:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L70
L12:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L55
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L55:
  mov    %rsp,%rax
  add    $0x7,%rax
  shr    $0x3,%rax
  shl    $0x3,%rax
  mov    %rax,-0x20(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L2
L57:
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x2c(%rbp),%ecx
  movslq %ecx,%rcx
  mov    %rax,(%rdx,%rcx,8)
  addl   $0x1,-0x2c(%rbp)
L2:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L57
  movl   $0x0,-0x2c(%rbp)
  jmp    L76
L31:
  mov    -0x20(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,8),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x2c(%rbp)
L76:
  mov    -0x2c(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L31
  mov    %rbx,%rsp
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void foo(int n_alloc, int n_free) {
  void *a[n_alloc];
  int i;
  for (i = 0; i < n_alloc; ++i)
    a[i] = malloc(i);
  for (i = 0; i < n_free; ++i)
    free(a[i]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %edi,%rax
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L7:
  cmp    %rdx,%rsp
  je     L24
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L7
L24:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L18
  orq    $0x0,-0x8(%rsp,%rax,1)
L18:
  mov    %rsp,%r12
  test   %edi,%edi
  jle    L19
  mov    %edi,%r14d
  mov    $0x0,%ebx
L16:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
  cmp    %r14,%rbx
  jne    L16
L19:
  test   %r13d,%r13d
  jle    L11
  mov    %r12,%rbx
  mov    %r13d,%r13d
  lea    (%r12,%r13,8),%r12
L12:
  mov    (%rbx),%rdi
  call   <free@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L12
L11:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int n_alloc, int n_free) {
  void *a[n_alloc];
  int i;
  for (i = 0; i < n_alloc; ++i)
    a[i] = malloc(i);
  for (i = 0; i < n_free; ++i)
    free(a[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  movslq %edi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0xf(,%r14,8),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L45
L21:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L21
L45:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L71
L69:
  mov    %rsp,%rbx
  test   %edi,%edi
  jle    L2
  xor    %r12d,%r12d
  nopl   (%rax)
L37:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx,%r12,8)
  add    $0x1,%r12
  cmp    %r14,%r12
  jne    L37
L2:
  test   %r13d,%r13d
  jle    L24
  lea    (%rbx,%r13,8),%r12
  cs nopw 0x0(%rax,%rax,1)
L74:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <free@plt>
  cmp    %r12,%rbx
  jne    L74
L24:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   (%rax)
L71:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L69
L89:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void foo(int n_alloc, int n_free) {
  void *a[n_alloc];
  int i;
  for (i = 0; i < n_alloc; ++i)
    a[i] = malloc(i);
  for (i = 0; i < n_free; ++i)
    free(a[i]);
}
```