ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<compute_displacement_from_forces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L11:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  D12(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L11
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
datatype: f64

tool: D12: 0.001

assistant: ```c
void compute_displacement_from_forces(double *fXYZ, double *charge, double *dXYZ, int nb_xyz) {
  int idPart;
  for (idPart = 0; idPart < nb_xyz; ++idPart) {
    dXYZ[idPart * 3 + 0] = fXYZ[idPart * 3 + 0] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 1] = fXYZ[idPart * 3 + 1] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 2] = fXYZ[idPart * 3 + 2] * 0.001 / charge[idPart];
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<compute_displacement_from_forces>:
  endbr64
  test   %ecx,%ecx
  jle    L10
  mov    %rsi,%rax
  lea    -0x1(%rcx),%ecx
  lea    0x8(%rsi,%rcx,8),%rcx
  movsd  D9(%rip),%xmm1
L18:
  movapd %xmm1,%xmm0
  mulsd  (%rdi),%xmm0
  divsd  (%rax),%xmm0
  movsd  %xmm0,(%rdx)
  movapd %xmm1,%xmm0
  mulsd  0x8(%rdi),%xmm0
  divsd  (%rax),%xmm0
  movsd  %xmm0,0x8(%rdx)
  movapd %xmm1,%xmm0
  mulsd  0x10(%rdi),%xmm0
  divsd  (%rax),%xmm0
  movsd  %xmm0,0x10(%rdx)
  add    $0x18,%rdi
  add    $0x8,%rax
  add    $0x18,%rdx
  cmp    %rcx,%rax
  jne    L18
L10:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: f64

tool: D9: 0.001

assistant: ```c
void compute_displacement_from_forces(double *fXYZ, double *charge, double *dXYZ, int nb_xyz) {
  int idPart;
  for (idPart = 0; idPart < nb_xyz; ++idPart) {
    dXYZ[idPart * 3 + 0] = fXYZ[idPart * 3 + 0] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 1] = fXYZ[idPart * 3 + 1] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 2] = fXYZ[idPart * 3 + 2] * 0.001 / charge[idPart];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compute_displacement_from_forces>:
  endbr64
  test   %ecx,%ecx
  jle    L6
  lea    -0x1(%rcx),%eax
  movsd  D5(%rip),%xmm1
  lea    0x8(%rsi,%rax,8),%rax
  nopl   0x0(%rax,%rax,1)
L13:
  movsd  (%rdi),%xmm0
  add    $0x8,%rsi
  add    $0x18,%rdi
  add    $0x18,%rdx
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,-0x18(%rdx)
  movsd  -0x10(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,-0x10(%rdx)
  movsd  -0x8(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rsi),%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rax,%rsi
  jne    L13
L6:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
type: f64

tool: D5: 0.001

assistant: ```c
void compute_displacement_from_forces(double *fXYZ, double *charge, double *dXYZ, int nb_xyz) {
  int idPart;
  for (idPart = 0; idPart < nb_xyz; ++idPart) {
    dXYZ[idPart * 3 + 0] = fXYZ[idPart * 3 + 0] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 1] = fXYZ[idPart * 3 + 1] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 2] = fXYZ[idPart * 3 + 2] * 0.001 / charge[idPart];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compute_displacement_from_forces>:
  endbr64
  mov    %ecx,%r9d
  test   %ecx,%ecx
  jle    L52
  movslq %ecx,%rax
  lea    (%rax,%rax,2),%rcx
  lea    (%rsi,%rax,8),%rax
  lea    (%rdx,%rcx,8),%rcx
  cmp    %rcx,%rsi
  setae  %cl
  cmp    %rax,%rdx
  setae  %al
  or     %al,%cl
  je     L10
  lea    0x2f(%rdi),%rax
  sub    %rdx,%rax
  cmp    $0x5e,%rax
  seta   %cl
  cmp    $0x1,%r9d
  setne  %al
  test   %al,%cl
  je     L10
  mov    %r9d,%r10d
  mov    %rdi,%rcx
  mov    %rsi,%r8
  mov    %rdx,%rax
  shr    %r10d
  movapd D26(%rip),%xmm5
  sub    $0x1,%r10d
  shl    $0x4,%r10
  lea    0x10(%rsi,%r10,1),%r10
  nopl   0x0(%rax,%rax,1)
L29:
  movupd (%rcx),%xmm3
  add    $0x10,%r8
  add    $0x30,%rcx
  add    $0x30,%rax
  movupd -0x20(%rcx),%xmm1
  movupd -0x10(%r8),%xmm4
  movapd %xmm3,%xmm2
  movhps -0x18(%rcx),%xmm2
  movapd %xmm3,%xmm0
  unpcklpd %xmm3,%xmm1
  movhps -0x8(%rcx),%xmm1
  shufpd $0x1,%xmm3,%xmm0
  movhpd -0x10(%rcx),%xmm0
  mulpd  %xmm5,%xmm2
  mulpd  %xmm5,%xmm0
  mulpd  %xmm5,%xmm1
  divpd  %xmm4,%xmm2
  divpd  %xmm4,%xmm0
  movapd %xmm2,%xmm3
  movapd %xmm2,%xmm6
  divpd  %xmm4,%xmm1
  unpcklpd %xmm0,%xmm3
  shufpd $0x1,%xmm2,%xmm0
  movups %xmm3,-0x30(%rax)
  movsd  %xmm1,%xmm6
  movsd  %xmm0,%xmm1
  movups %xmm6,-0x20(%rax)
  movups %xmm1,-0x10(%rax)
  cmp    %r10,%r8
  jne    L29
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  and    $0x1,%r9d
  je     L52
  lea    (%rcx,%rcx,2),%eax
  movsd  D26(%rip),%xmm0
  lea    (%rsi,%rcx,8),%rsi
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  lea    0x1(%rax),%rcx
  mulsd  %xmm0,%xmm1
  divsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdx,%rax,8)
  movsd  0x8(%rdi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm1
  divsd  (%rsi),%xmm1
  movsd  %xmm1,(%rdx,%rcx,8)
  mulsd  0x8(%rdi,%rcx,8),%xmm0
  divsd  (%rsi),%xmm0
  movsd  %xmm0,0x8(%rdx,%rcx,8)
  ret
  xchg   %ax,%ax
L10:
  lea    -0x1(%r9),%ecx
  movsd  D26(%rip),%xmm1
  mov    %rsi,%rax
  lea    0x8(%rsi,%rcx,8),%rcx
  nopl   0x0(%rax)
L28:
  movsd  (%rdi),%xmm0
  add    $0x8,%rax
  add    $0x18,%rdi
  add    $0x18,%rdx
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rax),%xmm0
  movsd  %xmm0,-0x18(%rdx)
  movsd  -0x10(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rax),%xmm0
  movsd  %xmm0,-0x10(%rdx)
  movsd  -0x8(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  divsd  -0x8(%rax),%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rax,%rcx
  jne    L28
L52:
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D26
type_infered: f64[2]

tool: {"D26": [0.001,0.001]}

assistant: ```c
void compute_displacement_from_forces(double *fXYZ, double *charge, double *dXYZ, int nb_xyz) {
  int idPart;
  for (idPart = 0; idPart < nb_xyz; ++idPart) {
    dXYZ[idPart * 3 + 0] = fXYZ[idPart * 3 + 0] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 1] = fXYZ[idPart * 3 + 1] * 0.001 / charge[idPart];
    dXYZ[idPart * 3 + 2] = fXYZ[idPart * 3 + 2] * 0.001 / charge[idPart];
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<f2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rax,%rdi
  call   *%rdx
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D28: ==================================

tool: D13: in f2 getted pointer:          %p;


assistant: ```c
void f2(void(f)(char *), char *str2) {
  printf("==================================\n");
  printf("in f2 getted pointer:          %p;\n", str2);
  f(str2);
  printf("==================================\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<f2>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    D16(%rip),%r12
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   *%rbp
  mov    %r12,%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D16: ==================================

tool: D5: in f2 getted pointer:          %p;


assistant: ```c
void f2(void(f)(char *), char *str2) {
  printf("==================================\n");
  printf("in f2 getted pointer:          %p;\n", str2);
  f(str2);
  printf("==================================\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f2>:
  endbr64
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   *%rbx
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_infered: string
name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D10: ==================================

tool: D6: in f2 getted pointer:          %p;


assistant: ```c
void f2(void(f)(char *), char *str2) {
  printf("==================================\n");
  printf("in f2 getted pointer:          %p;\n", str2);
  f(str2);
  printf("==================================\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<f2>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   *%rbx
  pop    %rbx
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D3
type: string

tool: D4: ==================================

tool: D3: in f2 getted pointer:          %p;


assistant: ```c
void f2(void(f)(char *), char *str2) {
  printf("==================================\n");
  printf("in f2 getted pointer:          %p;\n", str2);
  f(str2);
  printf("==================================\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dpl_eventq_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <dpl_eventq_get@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <dpl_event_run@plt>
  nop
  leave
  ret
```

assistant: ```c
void dpl_eventq_run(struct dpl_eventq *evq) {
  struct dpl_event *ev = dpl_eventq_get(evq);
  dpl_event_run(ev);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dpl_eventq_run>:
  endbr64
  sub    $0x8,%rsp
  call   <dpl_eventq_get@plt>
  mov    %rax,%rdi
  call   <dpl_event_run@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void dpl_eventq_run(struct dpl_eventq *evq) {
  struct dpl_event *ev = dpl_eventq_get(evq);
  dpl_event_run(ev);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dpl_eventq_run>:
  endbr64
  sub    $0x8,%rsp
  call   <dpl_eventq_get@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <dpl_event_run@plt>
```

assistant: ```c
void dpl_eventq_run(struct dpl_eventq *evq) {
  struct dpl_event *ev = dpl_eventq_get(evq);
  dpl_event_run(ev);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dpl_eventq_run>:
  endbr64
  sub    $0x8,%rsp
  call   <dpl_eventq_get@plt>
  add    $0x8,%rsp
  mov    %rax,%rdi
  jmp    1070 <dpl_event_run@plt>
```

assistant: ```c
void dpl_eventq_run(struct dpl_eventq *evq) {
  struct dpl_event *ev = dpl_eventq_get(evq);
  dpl_event_run(ev);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <foo@plt>
  addl   $0x2,-0x4(%rbp)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int a = 1;
  foo();
  a += 2;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <foo@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int a = 1;
  foo();
  a += 2;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int a = 1;
  foo();
  a += 2;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <foo@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int a = 1;
  foo();
  a += 2;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_lsbf_int32_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L31:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x8,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x34(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L5
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L20
L5:
  mov    -0x34(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L20:
  mov    -0x14(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  sub    $0x1,%eax
  and    %eax,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  sub    %eax,-0x34(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
L26:
  cmpl   $0x0,-0x34(%rbp)
  jg     L31
  mov    -0x30(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int32_t get_lsbf_int32_t(uint8_t *buf, int32_t *bip, int32_t n) {
  int32_t i = *bip;
  int32_t a = 0;
  int32_t mb;
  int32_t wb;
  int32_t m = 0;
  while (n > 0) {
    mb = 8 - (i % 8);
    if (n > mb) {
      wb = mb;
    } else {
      wb = n;
    }
    a |= (((buf[i / 8] >> (i % 8)) & ((1 << wb) - 1))) << m;
    n -= wb;
    i += wb;
    m += wb;
  }
  (*bip) = i;
  return (a);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_lsbf_int32_t>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%eax
  test   %edx,%edx
  jle    L15
  mov    %rdi,%r10
  mov    %edx,%edi
  mov    $0x0,%r8d
  mov    $0x0,%r9d
  mov    $0x8,%ebp
  mov    $0x1,%r11d
L1:
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ecx
  and    $0x7,%ecx
  sub    %edx,%ecx
  mov    %ebp,%edx
  sub    %ecx,%edx
  cmp    %edi,%edx
  cmovg  %edi,%edx
  lea    0x7(%rax),%esi
  test   %eax,%eax
  cmovns %eax,%esi
  sar    $0x3,%esi
  movslq %esi,%rsi
  mov    %eax,%ecx
  and    $0x7,%ecx
  mov    (%r10,%rsi,4),%esi
  sar    %cl,%esi
  mov    %r11d,%r14d
  mov    %edx,%ecx
  shl    %cl,%r14d
  mov    %r14d,%ecx
  sub    $0x1,%ecx
  and    %ecx,%esi
  mov    %r8d,%ecx
  shl    %cl,%esi
  or     %esi,%r9d
  sub    %edx,%edi
  add    %edx,%eax
  add    %edx,%r8d
  test   %edi,%edi
  jg     L1
L6:
  mov    %eax,(%rbx)
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
L15:
  mov    $0x0,%r9d
  jmp    L6
```

assistant: ```c
int32_t get_lsbf_int32_t(uint8_t *buf, int32_t *bip, int32_t n) {
  int32_t i = *bip;
  int32_t a = 0;
  int32_t mb;
  int32_t wb;
  int32_t m = 0;
  while (n > 0) {
    mb = 8 - (i % 8);
    if (n > mb) {
      wb = mb;
    } else {
      wb = n;
    }
    a |= (((buf[i / 8] >> (i % 8)) & ((1 << wb) - 1))) << m;
    n -= wb;
    i += wb;
    m += wb;
  }
  (*bip) = i;
  return (a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_lsbf_int32_t>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%eax
  test   %edx,%edx
  jle    L9
  mov    %rdi,%r10
  xor    %r8d,%r8d
  mov    %edx,%edi
  xor    %r9d,%r9d
  mov    $0x8,%ebp
  mov    $0x1,%r11d
  nopw   0x0(%rax,%rax,1)
L3:
  cltd
  lea    0x7(%rax),%esi
  mov    %r11d,%r14d
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ecx
  and    $0x7,%ecx
  sub    %edx,%ecx
  mov    %ebp,%edx
  sub    %ecx,%edx
  mov    %eax,%ecx
  cmp    %edi,%edx
  cmovg  %edi,%edx
  test   %eax,%eax
  cmovns %eax,%esi
  and    $0x7,%ecx
  sub    %edx,%edi
  add    %edx,%eax
  sar    $0x3,%esi
  movslq %esi,%rsi
  mov    (%r10,%rsi,4),%esi
  sar    %cl,%esi
  mov    %edx,%ecx
  shl    %cl,%r14d
  mov    %r14d,%ecx
  sub    $0x1,%ecx
  and    %ecx,%esi
  mov    %r8d,%ecx
  add    %edx,%r8d
  shl    %cl,%esi
  or     %esi,%r9d
  test   %edi,%edi
  jg     L3
  mov    %eax,(%rbx)
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  xor    %r9d,%r9d
  mov    %eax,(%rbx)
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
int32_t get_lsbf_int32_t(uint8_t *buf, int32_t *bip, int32_t n) {
  int32_t i = *bip;
  int32_t a = 0;
  int32_t mb;
  int32_t wb;
  int32_t m = 0;
  while (n > 0) {
    mb = 8 - (i % 8);
    if (n > mb) {
      wb = mb;
    } else {
      wb = n;
    }
    a |= (((buf[i / 8] >> (i % 8)) & ((1 << wb) - 1))) << m;
    n -= wb;
    i += wb;
    m += wb;
  }
  (*bip) = i;
  return (a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_lsbf_int32_t>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    (%rsi),%eax
  test   %edx,%edx
  jle    L13
  mov    %rdi,%r10
  xor    %r8d,%r8d
  mov    %edx,%edi
  xor    %r9d,%r9d
  mov    $0x8,%ebp
  mov    $0x1,%r11d
  nopw   0x0(%rax,%rax,1)
L15:
  cltd
  lea    0x7(%rax),%esi
  mov    %r11d,%r14d
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ecx
  and    $0x7,%ecx
  sub    %edx,%ecx
  mov    %ebp,%edx
  sub    %ecx,%edx
  mov    %eax,%ecx
  cmp    %edi,%edx
  cmovg  %edi,%edx
  test   %eax,%eax
  cmovns %eax,%esi
  and    $0x7,%ecx
  sub    %edx,%edi
  add    %edx,%eax
  sar    $0x3,%esi
  movslq %esi,%rsi
  mov    (%r10,%rsi,4),%esi
  sar    %cl,%esi
  mov    %edx,%ecx
  shl    %cl,%r14d
  mov    %r14d,%ecx
  sub    $0x1,%ecx
  and    %ecx,%esi
  mov    %r8d,%ecx
  add    %edx,%r8d
  shl    %cl,%esi
  or     %esi,%r9d
  test   %edi,%edi
  jg     L15
  mov    %eax,(%rbx)
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %r9d,%r9d
  mov    %eax,(%rbx)
  pop    %rbx
  mov    %r9d,%eax
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
int32_t get_lsbf_int32_t(uint8_t *buf, int32_t *bip, int32_t n) {
  int32_t i = *bip;
  int32_t a = 0;
  int32_t mb;
  int32_t wb;
  int32_t m = 0;
  while (n > 0) {
    mb = 8 - (i % 8);
    if (n > mb) {
      wb = mb;
    } else {
      wb = n;
    }
    a |= (((buf[i / 8] >> (i % 8)) & ((1 << wb) - 1))) << m;
    n -= wb;
    i += wb;
    m += wb;
  }
  (*bip) = i;
  return (a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L49
L0:
  movq   $0x0,-0x8(%rbp)
  jmp    L48
L20:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L18
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
L18:
  addq   $0x1,-0x8(%rbp)
L48:
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L20
  addq   $0x1,-0x10(%rbp)
L49:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort(int *array, size_t n) {
  for (size_t i = 0; i < n; ++i) {
    for (size_t j = 0; j < n - 1; ++j) {
      if (array[j] > array[j + 1]) {
        int tmp = array[j];
        array[j] = array[j + 1];
        array[j + 1] = tmp;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bubble_sort>:
  endbr64
  test   %rsi,%rsi
  je     L23
  lea    -0x4(%rdi,%rsi,4),%r8
  mov    $0x0,%r9d
  jmp    L22
L0:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L35
L13:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L0
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L0
L35:
  add    $0x1,%r9
  cmp    %r9,%rsi
  je     L23
L22:
  mov    %rdi,%rax
  cmp    $0x1,%rsi
  jne    L13
  jmp    L35
L23:
  ret
```

assistant: ```c
void bubble_sort(int *array, size_t n) {
  for (size_t i = 0; i < n; ++i) {
    for (size_t j = 0; j < n - 1; ++j) {
      if (array[j] > array[j + 1]) {
        int tmp = array[j];
        array[j] = array[j + 1];
        array[j + 1] = tmp;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<bubble_sort>:
  endbr64
  test   %rsi,%rsi
  je     L20
  lea    -0x4(%rdi,%rsi,4),%r8
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L17:
  mov    %rdi,%rax
  cmp    $0x1,%rsi
  je     L14
  nopl   0x0(%rax)
L43:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L18
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L18:
  add    $0x4,%rax
  cmp    %rax,%r8
  jne    L43
L14:
  add    $0x1,%r9
  cmp    %r9,%rsi
  jne    L17
L20:
  ret
```

assistant: ```c
void bubble_sort(int *array, size_t n) {
  for (size_t i = 0; i < n; ++i) {
    for (size_t j = 0; j < n - 1; ++j) {
      if (array[j] > array[j + 1]) {
        int tmp = array[j];
        array[j] = array[j + 1];
        array[j + 1] = tmp;
      }
    }
  }
}
```