ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<Scanf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movzbl (%rdi),%edx
  mov    %rdi,0x8(%rsp)
  test   %dl,%dl
  je     L26
  mov    %rdi,%rax
  lea    0x10(%rsp),%rbp
  jmp    L77
  nopw   0x0(%rax,%rax,1)
L74:
  movzbl 0x1(%rbx),%edx
  lea    0x1(%rbx),%rax
  mov    %rax,0x8(%rsp)
  test   %dl,%dl
  je     L26
L77:
  mov    %rax,%rbx
  cmp    $0x25,%dl
  jne    L74
  movzbl 0x1(%rax),%eax
  add    $0x1,%rbx
  mov    %rbx,0x8(%rsp)
  cmp    $0x64,%al
  je     L10
  cmp    $0x63,%al
  jne    L26
  movslq 0x0(%rbp),%r12
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <ReadChar@plt>
  mov    %al,(%r12)
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  movslq 0x0(%rbp),%r12
  xor    %eax,%eax
  add    $0x8,%rbp
  call   <ReadInt@plt>
  mov    %eax,(%r12)
  jmp    L74
```

assistant: ```c
void Scanf(char *formatSpecifier, ...) {
  char *argPtr = (char *)(&formatSpecifier) + sizeof(char *);
  int *argInt;
  char *argChar;
  while ((*formatSpecifier) != '\0') {
    if ((*formatSpecifier) == '%') {
      formatSpecifier++;
      if ((*formatSpecifier) == 'd') {
        argInt = (int *)(*((int *)argPtr));
        (*argInt) = ReadInt();
        argPtr += sizeof(int *);
      } else if ((*formatSpecifier) == 'c') {
        argChar = (char *)(*((int *)argPtr));
        (*argChar) = ReadChar();
        argPtr += sizeof(char *);
      } else {
        return;
      }
    }
    formatSpecifier++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <xmalloc_stat_dec@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void xfree(void *ptr, struct xmalloc_stat *st) {
  free(ptr);
  if (ptr)
    xmalloc_stat_dec(st);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xfree>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <free@plt>
  test   %rbx,%rbx
  je     L9
  mov    %rbp,%rdi
  call   <xmalloc_stat_dec@plt>
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xfree(void *ptr, struct xmalloc_stat *st) {
  free(ptr);
  if (ptr)
    xmalloc_stat_dec(st);
}
```
user: What is the c source code of the assembly code below?

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <free@plt>
  test   %rbx,%rbx
  je     L0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <xmalloc_stat_dec@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xfree(void *ptr, struct xmalloc_stat *st) {
  free(ptr);
  if (ptr)
    xmalloc_stat_dec(st);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xfree>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <free@plt>
  test   %rbx,%rbx
  je     L0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1070 <xmalloc_stat_dec@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xfree(void *ptr, struct xmalloc_stat *st) {
  free(ptr);
  if (ptr)
    xmalloc_stat_dec(st);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<set_socket_buff_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    D21(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  lea    -0x8(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  mov    D35(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  lea    -0xc(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    $0x4,%r8d
  mov    %eax,%edi
  call   <setsockopt@plt>
  nop
  leave
  ret
```

assistant: ```c
void set_socket_buff_size(int s, unsigned int w_size, unsigned int r_size) {
  setsockopt(s, SOL_SOCKET, SO_SNDBUF, (char *)&w_size, sizeof(int));
  setsockopt(s, SOL_SOCKET, SO_RCVBUF, (char *)&r_size, sizeof(int));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_socket_buff_size>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %esi,0xc(%rsp)
  mov    %edx,0x8(%rsp)
  lea    0xc(%rsp),%rcx
  mov    D2(%rip),%rbp
  mov    $0x4,%r8d
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    0x0(%rbp),%esi
  call   <setsockopt@plt>
  lea    0x8(%rsp),%rcx
  mov    $0x4,%r8d
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    0x0(%rbp),%esi
  mov    %ebx,%edi
  call   <setsockopt@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void set_socket_buff_size(int s, unsigned int w_size, unsigned int r_size) {
  setsockopt(s, SOL_SOCKET, SO_SNDBUF, (char *)&w_size, sizeof(int));
  setsockopt(s, SOL_SOCKET, SO_RCVBUF, (char *)&r_size, sizeof(int));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<set_socket_buff_size>:
  endbr64
  push   %rbp
  mov    $0x4,%r8d
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    D13(%rip),%rbx
  mov    D3(%rip),%rax
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  mov    %edx,0x8(%rsp)
  mov    (%rbx),%esi
  mov    (%rax),%edx
  call   <setsockopt@plt>
  mov    D10(%rip),%rax
  mov    (%rbx),%esi
  mov    %ebp,%edi
  lea    0x8(%rsp),%rcx
  mov    $0x4,%r8d
  mov    (%rax),%edx
  call   <setsockopt@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void set_socket_buff_size(int s, unsigned int w_size, unsigned int r_size) {
  setsockopt(s, SOL_SOCKET, SO_SNDBUF, (char *)&w_size, sizeof(int));
  setsockopt(s, SOL_SOCKET, SO_RCVBUF, (char *)&r_size, sizeof(int));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<set_socket_buff_size>:
  endbr64
  push   %rbp
  mov    $0x4,%r8d
  mov    %edi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    D7(%rip),%rbx
  mov    D25(%rip),%rax
  mov    %esi,0xc(%rsp)
  lea    0xc(%rsp),%rcx
  mov    %edx,0x8(%rsp)
  mov    (%rbx),%esi
  mov    (%rax),%edx
  call   <setsockopt@plt>
  mov    D21(%rip),%rax
  mov    (%rbx),%esi
  mov    %ebp,%edi
  lea    0x8(%rsp),%rcx
  mov    $0x4,%r8d
  mov    (%rax),%edx
  call   <setsockopt@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void set_socket_buff_size(int s, unsigned int w_size, unsigned int r_size) {
  setsockopt(s, SOL_SOCKET, SO_SNDBUF, (char *)&w_size, sizeof(int));
  setsockopt(s, SOL_SOCKET, SO_RCVBUF, (char *)&r_size, sizeof(int));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_sec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x10(%rbp),%rax
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
long get_sec(void) {
  struct timeval tv;
  struct timezone tz;
  memset(&tv, 0, sizeof(&tv));
  memset(&tz, 0, sizeof(&tz));
  gettimeofday(&tv, &tz);
  return tv.tv_sec;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_sec>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbx
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  lea    0x10(%rsp),%rbp
  mov    $0x8,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_sec(void) {
  struct timeval tv;
  struct timezone tz;
  memset(&tv, 0, sizeof(&tv));
  memset(&tz, 0, sizeof(&tz));
  gettimeofday(&tv, &tz);
  return tv.tv_sec;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_sec>:
  endbr64
  push   %r12
  mov    $0x8,%edx
  xor    %esi,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_sec(void) {
  struct timeval tv;
  struct timezone tz;
  memset(&tv, 0, sizeof(&tv));
  memset(&tz, 0, sizeof(&tz));
  gettimeofday(&tv, &tz);
  return tv.tv_sec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_sec>:
  endbr64
  push   %r12
  mov    $0x8,%edx
  xor    %esi,%esi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    $0x8,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <memset@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <gettimeofday@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long get_sec(void) {
  struct timeval tv;
  struct timezone tz;
  memset(&tv, 0, sizeof(&tv));
  memset(&tz, 0, sizeof(&tz));
  gettimeofday(&tv, &tz);
  return tv.tv_sec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mv_obstacle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L55:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movzbl (%rdx,%rax,1),%eax
  cmp    $0x48,%al
  jne    L5
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movb   $0x48,(%rdx,%rax,1)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movb   $0x20,(%rdx,%rax,1)
  jmp    L5
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movb   $0x20,(%rdx,%rax,1)
L5:
  addl   $0x1,-0x4(%rbp)
L41:
  cmpl   $0x4,-0x4(%rbp)
  jle    L55
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L36:
  cmpl   $0x4,-0x8(%rbp)
  jle    L41
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
char mv_obstacle(char map[5][5]) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (i < 5) {
    while (j < 5) {
      if (map[i][j] == 'H') {
        if (j - 1 != -1) {
          map[i][j - 1] = 'H';
          map[i][j] = ' ';
        } else
          map[i][j] = ' ';
      }
      j++;
    }
    j = 0;
    i++;
  }
  return (**map);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mv_obstacle>:
  endbr64
  mov    %rdi,%rsi
  lea    0x19(%rdi),%r8
  jmp    L73
L49:
  movb   $0x20,(%rcx)
  jmp    L79
L71:
  cmp    $0x4,%edx
  jg     L10
L79:
  add    $0x1,%rax
  add    $0x1,%edx
L28:
  cmpb   $0x48,(%rcx,%rax,1)
  jne    L71
  test   %eax,%eax
  je     L49
  movb   $0x48,-0x1(%rcx,%rax,1)
  movb   $0x20,(%rcx,%rax,1)
  jmp    L71
L10:
  add    $0x5,%rsi
  cmp    %r8,%rsi
  je     L45
L73:
  mov    %rsi,%rcx
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L28
L45:
  movzbl (%rdi),%eax
  ret
```

assistant: ```c
char mv_obstacle(char map[5][5]) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (i < 5) {
    while (j < 5) {
      if (map[i][j] == 'H') {
        if (j - 1 != -1) {
          map[i][j - 1] = 'H';
          map[i][j] = ' ';
        } else
          map[i][j] = ' ';
      }
      j++;
    }
    j = 0;
    i++;
  }
  return (**map);
}
```
user: What is the c source code of the assembly code below?

```asm
<mv_obstacle>:
  endbr64
  mov    %rdi,%rdx
  lea    0x19(%rdi),%rcx
L36:
  xor    %eax,%eax
  cmpb   $0x48,(%rdx,%rax,1)
  je     L49
L29:
  cmp    $0x4,%rax
  je     L11
L14:
  add    $0x1,%rax
  cmpb   $0x48,(%rdx,%rax,1)
  jne    L29
L49:
  test   %rax,%rax
  je     L13
  movb   $0x48,-0x1(%rdx,%rax,1)
  movb   $0x20,(%rdx,%rax,1)
  cmp    $0x4,%rax
  jne    L14
L11:
  add    $0x5,%rdx
  cmp    %rcx,%rdx
  jne    L36
  movzbl (%rdi),%eax
  ret
  nopl   0x0(%rax)
L13:
  movb   $0x20,(%rdx)
  jmp    L14
```

assistant: ```c
char mv_obstacle(char map[5][5]) {
  int i;
  int j;
  i = 0;
  j = 0;
  while (i < 5) {
    while (j < 5) {
      if (map[i][j] == 'H') {
        if (j - 1 != -1) {
          map[i][j - 1] = 'H';
          map[i][j] = ' ';
        } else
          map[i][j] = ' ';
      }
      j++;
    }
    j = 0;
    i++;
  }
  return (**map);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%eax
  mov    $0x2,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  pxor   %xmm1,%xmm1
  cvtss2sd -0x1c(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D32
type_guessed: string
name: read_data
arguments: data_tag: D34
type_guessed: string

tool: D21: 
 Entre com cateto 1 :

tool: D0: %f

tool: D32: 
 Entre com cateto 2 :

tool: D34: 
 Hipotenusa = %.2f 


assistant: ```c
int main() {
  float c1, c2, hipo;
  printf("\n Entre com cateto 1 :\n");
  scanf("%f", &c1);
  printf("\n Entre com cateto 2 :\n");
  scanf("%f", &c2);
  hipo = sqrt(pow(c1, 2) + pow(c2, 2));
  printf("\n Hipotenusa = %.2f \n", hipo);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D39(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    $0x2,%edi
  movss  (%rsp),%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  mov    $0x2,%edi
  movss  0x4(%rsp),%xmm0
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  cvtss2sd %xmm0,%xmm0
  lea    D15(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D38
type: string
name: disassemble_data
arguments: data_tag: D39
type: string
name: disassemble_data
arguments: data_tag: D8
type: string
name: disassemble_data
arguments: data_tag: D15
type: string

tool: D38: 
 Entre com cateto 1 :

tool: D39: %f

tool: D8: 
 Entre com cateto 2 :

tool: D15: 
 Hipotenusa = %.2f 


assistant: ```c
int main() {
  float c1, c2, hipo;
  printf("\n Entre com cateto 1 :\n");
  scanf("%f", &c1);
  printf("\n Entre com cateto 2 :\n");
  scanf("%f", &c2);
  hipo = sqrt(pow(c1, 2) + pow(c2, 2));
  printf("\n Hipotenusa = %.2f \n", hipo);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rdi
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  lea    D26(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D26
data_type: string

tool: D5: 
 Entre com cateto 1 :

tool: D8: %f

tool: D11: 
 Entre com cateto 2 :

tool: D26: 
 Hipotenusa = %.2f 


assistant: ```c
int main() {
  float c1, c2, hipo;
  printf("\n Entre com cateto 1 :\n");
  scanf("%f", &c1);
  printf("\n Entre com cateto 2 :\n");
  scanf("%f", &c2);
  hipo = sqrt(pow(c1, 2) + pow(c2, 2));
  printf("\n Hipotenusa = %.2f \n", hipo);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x2,%edi
  mov    %rax,%rbx
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D21
type: string
name: retrieve_data
arguments: tag: D10
type: string
name: retrieve_data
arguments: tag: D25
type: string
name: retrieve_data
arguments: tag: D3
type: string

tool: D21: 
 Entre com cateto 1 :

tool: D10: %f

tool: D25: 
 Entre com cateto 2 :

tool: D3: 
 Hipotenusa = %.2f 


assistant: ```c
int main() {
  float c1, c2, hipo;
  printf("\n Entre com cateto 1 :\n");
  scanf("%f", &c1);
  printf("\n Entre com cateto 2 :\n");
  scanf("%f", &c2);
  hipo = sqrt(pow(c1, 2) + pow(c2, 2));
  printf("\n Hipotenusa = %.2f \n", hipo);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x6(%rbp)
  movzbl -0x6(%rbp),%eax
  mov    %al,-0x5(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L1:
  movzbl -0x5(%rbp),%eax
  add    $0x2,%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x6(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x6(%rbp)
  shll   -0x4(%rbp)
L19:
  cmpb   $0x9,-0x6(%rbp)
  jle    L1
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char i, a;
  a = i = 0;
  int c = 1;
  while (i < 10) {
    a = a + 2;
    ++i;
    c = c * 2;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char i, a;
  a = i = 0;
  int c = 1;
  while (i < 10) {
    a = a + 2;
    ++i;
    c = c * 2;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char i, a;
  a = i = 0;
  int c = 1;
  while (i < 10) {
    a = a + 2;
    ++i;
    c = c * 2;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  char i, a;
  a = i = 0;
  int c = 1;
  while (i < 10) {
    a = a + 2;
    ++i;
    c = c * 2;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mrcore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mpz_set_ui@plt>
  mov    0x18(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %edx,%ecx
  mov    0x10(%rbp),%edx
  mov    %eax,%edi
  call   <mpz_powm@plt>
  mov    -0x2c(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mpz_cmp_ui@plt>
  test   %rax,%rax
  je     L69
  mov    -0x14(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jne    L19
L69:
  mov    $0x1,%eax
  jmp    L52
L19:
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_set@plt>
  movq   $0x1,-0x8(%rbp)
  jmp    L80
L18:
  mov    0x18(%rbp),%edx
  mov    -0x30(%rbp),%esi
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    %eax,%edi
  call   <mpz_powm_ui@plt>
  mov    -0x30(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <mpz_cmp_ui@plt>
  test   %rax,%rax
  jne    L7
  mov    $0x0,%eax
  jmp    L52
L7:
  mov    -0x14(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <mpz_cmp@plt>
  test   %rax,%rax
  jne    L32
  mov    $0x1,%eax
  jmp    L52
L32:
  addq   $0x1,-0x8(%rbp)
L80:
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  cmp    %rax,-0x8(%rbp)
  jbe    L18
  mov    $0x0,%eax
L52:
  leave
  ret
```

assistant: ```c
int mrcore(mpz_t min_one, mpz_t a, unsigned long int a_given, unsigned long int k, mpz_t b0, mpz_t b, mpz_t m, mpz_t n) {
  unsigned long int i;
  mpz_set_ui(a, a_given);
  mpz_powm(b0, a, m, n);
  if (mpz_cmp_ui(b0, 1) == 0 || mpz_cmp(b0, min_one) == 0) {
    return 1;
  }
  mpz_set(b, b0);
  for (i = 1; i <= k - 1; i++) {
    mpz_powm_ui(b, b, 2, n);
    if (mpz_cmp_ui(b, 1) == 0) {
      return 0;
    } else if (mpz_cmp(b, min_one) == 0) {
      return 1;
    }
  }
  return 0;
}
```