ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reverseNum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L2:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L4:
  cmpl   $0x0,-0x14(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int reverseNum(int num) {
  int reverse = 0;
  while (num) {
    reverse = reverse * 10 + num % 10;
    num /= 10;
  }
  return reverse;
}
```
user: What is the c source code of the assembly code below?

```asm
<reverseNum>:
  endbr64
  test   %edi,%edi
  je     L29
  mov    $0x0,%edx
L25:
  lea    (%rdx,%rdx,4),%ecx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    (%rdi,%rcx,2),%edx
  mov    %eax,%edi
  test   %eax,%eax
  jne    L25
L7:
  mov    %edx,%eax
  ret
L29:
  mov    %edi,%edx
  jmp    L7
```

assistant: ```c
int reverseNum(int num) {
  int reverse = 0;
  while (num) {
    reverse = reverse * 10 + num % 10;
    num /= 10;
  }
  return reverse;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverseNum>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L18
  nopl   0x0(%rax,%rax,1)
L11:
  movslq %edi,%rax
  mov    %edi,%edx
  lea    (%r8,%r8,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    (%rdi,%rcx,2),%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L11
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverseNum(int num) {
  int reverse = 0;
  while (num) {
    reverse = reverse * 10 + num % 10;
    num /= 10;
  }
  return reverse;
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverseNum>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L0
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %edi,%rax
  mov    %edi,%edx
  lea    (%r8,%r8,4),%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%edi
  lea    (%rdi,%rcx,2),%r8d
  mov    %eax,%edi
  test   %eax,%eax
  jne    L13
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int reverseNum(int num) {
  int reverse = 0;
  while (num) {
    reverse = reverse * 10 + num % 10;
    num /= 10;
  }
  return reverse;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rtrim(char *string, int num_chars) {
  int index;
  index = strlen(string) - num_chars;
  string[index] = '\0';
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rtrim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  sub    %ebp,%eax
  cltq
  movb   $0x0,(%rbx,%rax,1)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *rtrim(char *string, int num_chars) {
  int index;
  index = strlen(string) - num_chars;
  string[index] = '\0';
  return string;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    %ebx,%eax
  cltq
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(char *string, int num_chars) {
  int index;
  index = strlen(string) - num_chars;
  string[index] = '\0';
  return string;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<rtrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    %ebx,%eax
  cltq
  movb   $0x0,(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *rtrim(char *string, int num_chars) {
  int index;
  index = strlen(string) - num_chars;
  string[index] = '\0';
  return string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<grabHour>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x4000(%rsp),%r11
L5:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L5
  sub    $0x30,%rsp
  mov    %rdi,-0x4028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4028(%rbp),%rdx
  lea    -0x4010(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x4010(%rbp),%rax
  add    $0x8,%rax
  lea    -0x2010(%rbp),%rcx
  mov    $0x2,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <strncpy@plt>
  movb   $0x0,-0x200e(%rbp)
  lea    -0x4018(%rbp),%rdx
  lea    -0x2010(%rbp),%rax
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x4018(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string

tool: D5: %lu

assistant: ```c
unsigned long grabHour(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long hour;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf + 8, 2);
  buf2[2] = '\0';
  sscanf(buf2, "%lu", &hour);
  return hour;
}
```
user: Translate the below assembly code into C programming language:

```asm
<grabHour>:
  endbr64
  push   %rbp
  push   %rbx
  lea    -0x4000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0x28,%rsp
  mov    %rdi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x4018(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  lea    D2(%rip),%rbp
  mov    %rbp,%rsi
  call   <sprintf@plt>
  lea    0x18(%rsp),%rsi
  lea    0x2010(%rsp),%rbx
  mov    $0x2,%edx
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x2012(%rsp)
  lea    0x8(%rsp),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sscanf@plt>
  mov    0x8(%rsp),%rax
  mov    0x4018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x4028,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: %lu

assistant: ```c
unsigned long grabHour(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long hour;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf + 8, 2);
  buf2[2] = '\0';
  sscanf(buf2, "%lu", &hour);
  return hour;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<grabHour>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L2:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L2
  sub    $0x28,%rsp
  lea    D3(%rip),%r12
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x4018(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  lea    0x2010(%rsp),%rbp
  lea    0x10(%rsp),%rdi
  call   <sprintf@plt>
  lea    0x18(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x2012(%rsp)
  call   <sscanf@plt>
  mov    0x8(%rsp),%rax
  mov    0x4018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x4028,%rsp
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: %lu

assistant: ```c
unsigned long grabHour(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long hour;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf + 8, 2);
  buf2[2] = '\0';
  sscanf(buf2, "%lu", &hour);
  return hour;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<grabHour>:
  endbr64
  push   %r12
  push   %rbp
  lea    -0x4000(%rsp),%r11
L2:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L2
  sub    $0x28,%rsp
  lea    D6(%rip),%r12
  mov    %r12,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x4018(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  lea    0x2010(%rsp),%rbp
  lea    0x10(%rsp),%rdi
  call   <sprintf@plt>
  lea    0x18(%rsp),%rsi
  mov    $0x2,%edx
  mov    %rbp,%rdi
  call   <strncpy@plt>
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movb   $0x0,0x2012(%rsp)
  call   <sscanf@plt>
  mov    0x8(%rsp),%rax
  mov    0x4018(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x4028,%rsp
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: %lu

assistant: ```c
unsigned long grabHour(unsigned long encoding) {
  char buf[8192];
  char buf2[8192];
  unsigned long hour;
  sprintf(buf, "%lu", encoding);
  strncpy(buf2, buf + 8, 2);
  buf2[2] = '\0';
  sscanf(buf2, "%lu", &hour);
  return hour;
}
```
user: What is the c source code of the assembly code below?

```asm
<togglewire>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D7(%rip),%eax
  xor    $0x1,%eax
  mov    %eax,D15(%rip)
  mov    D15(%rip),%eax
  test   %eax,%eax
  je     L3
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  jmp    L12
L3:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
L12:
  mov    D4(%rip),%rdx
  mov    (%rdx),%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <glPolygonMode@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void togglewire(void) {
  static int toggle = 0;
  toggle ^= 1;
  glPolygonMode(GL_FRONT_AND_BACK, toggle ? GL_LINE : GL_FILL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<togglewire>:
  endbr64
  sub    $0x8,%rsp
  mov    D19(%rip),%eax
  mov    %eax,%edx
  xor    $0x1,%edx
  mov    %edx,D22(%rip)
  cmp    $0x1,%eax
  je     L16
  mov    D22(%rip),%rax
  mov    (%rax),%esi
L17:
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <glPolygonMode@plt>
  add    $0x8,%rsp
  ret
L16:
  mov    D35(%rip),%rax
  mov    (%rax),%esi
  jmp    L17
```

assistant: ```c
void togglewire(void) {
  static int toggle = 0;
  toggle ^= 1;
  glPolygonMode(GL_FRONT_AND_BACK, toggle ? GL_LINE : GL_FILL);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<togglewire>:
  endbr64
  xorl   $0x1,D35(%rip)
  je     L0
  mov    D43(%rip),%rax
  mov    (%rax),%esi
  mov    D32(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <glPolygonMode@plt>
  nopl   0x0(%rax)
L0:
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  mov    D32(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <glPolygonMode@plt>
```

assistant: ```c
void togglewire(void) {
  static int toggle = 0;
  toggle ^= 1;
  glPolygonMode(GL_FRONT_AND_BACK, toggle ? GL_LINE : GL_FILL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<togglewire>:
  endbr64
  xorl   $0x1,D19(%rip)
  je     L4
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <glPolygonMode@plt>
  nopl   0x0(%rax)
L4:
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  jmp    1050 <glPolygonMode@plt>
```

assistant: ```c
void togglewire(void) {
  static int toggle = 0;
  toggle ^= 1;
  glPolygonMode(GL_FRONT_AND_BACK, toggle ? GL_LINE : GL_FILL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<concatStringVector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L2
L4:
  mov    -0x8(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D4:  

assistant: ```c
char *concatStringVector(char **inputVector, int size) {
  int i;
  int resultSize;
  char *result;
  resultSize = 3 * size + 1;
  result = calloc(resultSize, sizeof(char));
  strcpy(result, inputVector[0]);
  for (i = 1; i < size; i++) {
    strcat(result, " ");
    strcat(result, (const char *)inputVector[i]);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<concatStringVector>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  lea    0x1(%rsi,%rsi,2),%edi
  mov    $0x1,%esi
  call   <calloc@plt>
  mov    %rax,%rbp
  mov    0x0(%r13),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmp    $0x1,%r12d
  jle    L10
  lea    0x8(%r13),%rbx
  lea    -0x2(%r12),%eax
  lea    0x10(%r13,%rax,8),%r13
  lea    D1(%rip),%r12
L8:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L8
L10:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1:  

assistant: ```c
char *concatStringVector(char **inputVector, int size) {
  int i;
  int resultSize;
  char *result;
  resultSize = 3 * size + 1;
  result = calloc(resultSize, sizeof(char));
  strcpy(result, inputVector[0]);
  for (i = 1; i < size; i++) {
    strcat(result, " ");
    strcat(result, (const char *)inputVector[i]);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<concatStringVector>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rsi,%rsi,2),%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    0x0(%r13),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  cmp    $0x1,%ebp
  jle    L10
  lea    -0x2(%rbp),%eax
  lea    0x8(%r13),%rbx
  lea    D9(%rip),%rbp
  lea    0x10(%r13,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strcat@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  cmp    %r13,%rbx
  jne    L14
L10:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
data_type: string

tool: D9:  

assistant: ```c
char *concatStringVector(char **inputVector, int size) {
  int i;
  int resultSize;
  char *result;
  resultSize = 3 * size + 1;
  result = calloc(resultSize, sizeof(char));
  strcpy(result, inputVector[0]);
  for (i = 1; i < size; i++) {
    strcat(result, " ");
    strcat(result, (const char *)inputVector[i]);
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<concatStringVector>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  lea    0x1(%rsi,%rsi,2),%edi
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0x1,%esi
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    0x0(%r13),%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  cmp    $0x1,%ebp
  jle    L15
  lea    -0x2(%rbp),%eax
  lea    0x8(%r13),%rbx
  lea    D6(%rip),%rbp
  lea    0x10(%r13,%rax,8),%r13
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x8,%rbx
  call   <strcat@plt>
  mov    -0x8(%rbx),%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  cmp    %r13,%rbx
  jne    L12
L15:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string

tool: D6:  

assistant: ```c
char *concatStringVector(char **inputVector, int size) {
  int i;
  int resultSize;
  char *result;
  resultSize = 3 * size + 1;
  result = calloc(resultSize, sizeof(char));
  strcpy(result, inputVector[0]);
  for (i = 1; i < size; i++) {
    strcat(result, " ");
    strcat(result, (const char *)inputVector[i]);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<apply_r_mod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy_str@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <split_ext@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int apply_r_mod(const char *path, char *buf, size_t buf_len) {
  int root_len;
  const char *ext_pos;
  copy_str(buf, buf_len, path);
  split_ext(buf, &root_len, &ext_pos);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<apply_r_mod>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  mov    %rbx,%rdi
  call   <copy_str@plt>
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <split_ext@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int apply_r_mod(const char *path, char *buf, size_t buf_len) {
  int root_len;
  const char *ext_pos;
  copy_str(buf, buf_len, path);
  split_ext(buf, &root_len, &ext_pos);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<apply_r_mod>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rdi,%rdx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <copy_str@plt>
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <split_ext@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int apply_r_mod(const char *path, char *buf, size_t buf_len) {
  int root_len;
  const char *ext_pos;
  copy_str(buf, buf_len, path);
  split_ext(buf, &root_len, &ext_pos);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<apply_r_mod>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  mov    %rdi,%rdx
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <copy_str@plt>
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <split_ext@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int apply_r_mod(const char *path, char *buf, size_t buf_len) {
  int root_len;
  const char *ext_pos;
  copy_str(buf, buf_len, path);
  split_ext(buf, &root_len, &ext_pos);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0xffffffffffffffff,-0x10(%rbp)
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L24
  mov    -0x10(%rbp),%rax
  jmp    L20
L24:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

assistant: ```c
unsigned long get_file_size(const char *path) {
  unsigned long filesize = -1;
  struct stat statbuff;
  if (stat(path, &statbuff) < 0) {
    return filesize;
  } else {
    filesize = statbuff.st_size;
  }
  return filesize;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovns (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_file_size(const char *path) {
  unsigned long filesize = -1;
  struct stat statbuff;
  if (stat(path, &statbuff) < 0) {
    return filesize;
  } else {
    filesize = statbuff.st_size;
  }
  return filesize;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovns (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_file_size(const char *path) {
  unsigned long filesize = -1;
  struct stat statbuff;
  if (stat(path, &statbuff) < 0) {
    return filesize;
  } else {
    filesize = statbuff.st_size;
  }
  return filesize;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  mov    $0xffffffffffffffff,%rax
  cmovns (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long get_file_size(const char *path) {
  unsigned long filesize = -1;
  struct stat statbuff;
  if (stat(path, &statbuff) < 0) {
    return filesize;
  } else {
    filesize = statbuff.st_size;
  }
  return filesize;
}
```