ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edi
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  mov    %eax,0x4(%rsp)
  test   %edi,%edi
  je     L46
  lea    0x4(%rsp),%rdx
  xor    %ecx,%ecx
L11:
  cmp    %eax,%ecx
  jae    L43
  movzbl (%rdx),%eax
  movzbl 0x1(%rdx),%r8d
  mov    %al,0x1(%rdx)
  mov    %r8b,(%rdx)
  movzwl 0x6(%rsp),%eax
  movzwl 0x4(%rsp),%r8d
  mov    %ax,0x4(%rsp)
  mov    %r8w,0x6(%rsp)
  mov    0x4(%rsp),%eax
L20:
  add    $0x1,%ecx
  add    $0x4,%rdx
  cmp    %edi,%ecx
  jne    L11
L46:
  shl    $0x5,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
  nopl   (%rax)
L43:
  mov    %eax,%r8d
  shl    $0x4,%r8d
  and    $0x1f0,%r8d
  or     %r8d,%eax
  imul   %eax,%eax
  mov    %eax,(%rdx)
  jmp    L20
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31U) << 4UL;
        state[local1] *= state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<RandomFunc>:
  endbr64
  push   %rbx
  mov    %rsi,%rdx
  sub    $0x10,%rsp
  mov    (%rdi),%esi
  mov    0x4(%rdi),%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3686696a(%rsi),%eax
  xor    $0xce5d000b,%eax
  mov    %eax,0x4(%rsp)
  test   %ecx,%ecx
  je     L19
  cmp    $0x97d696a1,%esi
  je     L68
  mov    %eax,%esi
  shr    $0x10,%eax
  rol    $0x8,%si
  shl    $0x10,%esi
  or     %esi,%eax
  mov    %eax,0x4(%rsp)
  cmp    $0x1,%ecx
  je     L19
  cmp    $0x1,%eax
  jbe    L52
  movzwl 0x4(%rsp),%esi
  movzwl 0x6(%rsp),%eax
  rolw   $0x8,0x8(%rsp)
  shl    $0x10,%esi
  or     %esi,%eax
  mov    %eax,0x4(%rsp)
L61:
  cmp    $0x2,%ecx
  jbe    L19
  lea    0x4(%rsp),%rdi
  mov    $0x2,%esi
L26:
  cmp    %eax,%esi
  jae    L90
  xor    %eax,%eax
  mov    0x9(%rdi),%al
  mov    0x8(%rdi),%ah
  mov    %ax,0x8(%rdi)
  movzwl 0x4(%rsp),%r8d
  movzwl 0x6(%rsp),%eax
  shl    $0x10,%r8d
  or     %r8d,%eax
  mov    %eax,0x4(%rsp)
L83:
  add    $0x1,%esi
  add    $0x4,%rdi
  cmp    %ecx,%esi
  jne    L26
  nopl   (%rax)
L19:
  shl    $0x5,%eax
  mov    %eax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
  cmp    $0x1,%ecx
  je     L19
L52:
  mov    %eax,%esi
  shl    $0x4,%esi
  or     %esi,%eax
  imul   %eax,%eax
  mov    %eax,0x8(%rsp)
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L90:
  mov    %eax,%r8d
  shl    $0x4,%r8d
  and    $0x1f0,%r8d
  or     %r8d,%eax
  imul   %eax,%eax
  mov    %eax,0x8(%rdi)
  jmp    L83
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        copy11 = *((char *)(&state[local1]) + 0);
        *((char *)(&state[local1]) + 0) = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = copy11;
        copy12 = *((unsigned short *)(&state[0UL]) + 1);
        *((unsigned short *)(&state[0UL]) + 1) = *((unsigned short *)(&state[0UL]) + 0);
        *((unsigned short *)(&state[0UL]) + 0) = copy12;
      } else {
        state[0UL] |= (state[0UL] & 31U) << 4UL;
        state[local1] *= state[local1];
      }
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cutItemString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %ecx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L96
L9:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  jne    L84
  addl   $0x1,-0xc(%rbp)
L84:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L34
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L34
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  cmp    %rax,-0x30(%rbp)
  jbe    L34
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L34:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L98
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x24(%rbp)
  je     L73
L98:
  addl   $0x1,-0x8(%rbp)
L96:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  jmp    L37
L73:
  nop
L37:
  mov    -0x4(%rbp),%eax
  cmp    %rax,-0x30(%rbp)
  jbe    L23
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L23:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cutItemString(char *in, char *out, char sep, int num, size_t maxout) {
  int n;
  unsigned int i, c;
  for (c = 0, n = 0, i = 0; in[i]; i++) {
    if (in[i] == sep)
      n++;
    if (n >= num && in[i] != sep && c + 1 < maxout)
      out[c++] = in[i];
    if (n >= num && in[i + 1] == sep)
      break;
  }
  if (c < maxout)
    out[c] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cutItemString>:
  endbr64
  mov    %rsi,%r11
  mov    %ecx,%r10d
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L167
  mov    $0x1,%eax
  mov    $0x0,%r9d
  mov    $0x0,%esi
  jmp    L164
L134:
  add    $0x1,%esi
  cmp    %r10d,%esi
  jl     L80
L114:
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rcx,1)
  je     L24
L80:
  mov    %eax,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  add    $0x1,%eax
  test   %cl,%cl
  je     L24
  cmp    %cl,%dl
  je     L134
  cmp    %esi,%r10d
  jg     L80
L133:
  lea    0x1(%r9),%ebx
  mov    %ebx,%ebp
  cmp    %r8,%rbp
  jae    L114
  mov    %r9d,%r9d
  mov    %cl,(%r11,%r9,1)
  mov    %ebx,%r9d
  jmp    L114
L167:
  mov    $0x0,%r9d
L49:
  mov    %r9d,%r9d
  cmp    %r8,%r9
  jae    L110
  movb   $0x0,(%r11,%r9,1)
  ret
L24:
  mov    %r9d,%r9d
  cmp    %r8,%r9
  jae    L17
  movb   $0x0,(%r11,%r9,1)
L17:
  pop    %rbx
  pop    %rbp
  ret
L99:
  add    $0x1,%esi
  cmp    %r10d,%esi
  jl     L120
  mov    %eax,%ecx
  cmp    %dl,(%rdi,%rcx,1)
  je     L49
L120:
  mov    %eax,%ecx
  movzbl (%rdi,%rcx,1),%ecx
  add    $0x1,%eax
  test   %cl,%cl
  je     L49
L164:
  cmp    %cl,%dl
  je     L99
  cmp    %esi,%r10d
  jg     L120
  push   %rbp
  push   %rbx
  jmp    L133
L110:
  ret
```

assistant: ```c
void cutItemString(char *in, char *out, char sep, int num, size_t maxout) {
  int n;
  unsigned int i, c;
  for (c = 0, n = 0, i = 0; in[i]; i++) {
    if (in[i] == sep)
      n++;
    if (n >= num && in[i] != sep && c + 1 < maxout)
      out[c++] = in[i];
    if (n >= num && in[i + 1] == sep)
      break;
  }
  if (c < maxout)
    out[c] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cutItemString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L32
  mov    %rdi,%r11
  mov    %ecx,%ebx
  xor    %r9d,%r9d
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L43:
  cmp    %edi,%ebx
  jle    L19
  movzbl (%rcx),%eax
L92:
  test   %al,%al
  je     L78
L49:
  lea    0x1(%rsi),%ecx
  mov    %r9d,%r10d
  mov    %rcx,%rsi
  add    %r11,%rcx
  cmp    %al,%dl
  jne    L43
  movzbl (%rcx),%eax
  add    $0x1,%edi
  mov    %eax,%ecx
  cmp    %ebx,%edi
  jl     L92
L89:
  mov    %ecx,%eax
  cmp    %dl,%cl
  jne    L92
L78:
  cmp    %r10,%r8
  jbe    L58
  movb   $0x0,0x0(%rbp,%r10,1)
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  lea    0x1(%r9),%r13d
  cmp    %r8,%r13
  jae    L28
  mov    %al,0x0(%rbp,%r10,1)
  mov    %r13d,%r9d
  mov    %r13,%r10
L28:
  movzbl (%rcx),%ecx
  jmp    L89
L32:
  xor    %r10d,%r10d
  jmp    L78
```

assistant: ```c
void cutItemString(char *in, char *out, char sep, int num, size_t maxout) {
  int n;
  unsigned int i, c;
  for (c = 0, n = 0, i = 0; in[i]; i++) {
    if (in[i] == sep)
      n++;
    if (n >= num && in[i] != sep && c + 1 < maxout)
      out[c++] = in[i];
    if (n >= num && in[i + 1] == sep)
      break;
  }
  if (c < maxout)
    out[c] = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cutItemString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L63
  mov    %rdi,%r11
  mov    %ecx,%ebx
  xor    %r9d,%r9d
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L36:
  cmp    %edi,%ebx
  jle    L75
  movzbl (%rcx),%eax
L79:
  test   %al,%al
  je     L77
L67:
  lea    0x1(%rsi),%ecx
  mov    %r9d,%r10d
  mov    %rcx,%rsi
  add    %r11,%rcx
  cmp    %al,%dl
  jne    L36
  movzbl (%rcx),%eax
  add    $0x1,%edi
  mov    %eax,%ecx
  cmp    %ebx,%edi
  jl     L79
L100:
  mov    %ecx,%eax
  cmp    %dl,%cl
  jne    L79
L77:
  cmp    %r10,%r8
  jbe    L101
  movb   $0x0,0x0(%rbp,%r10,1)
L101:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  lea    0x1(%r9),%r13d
  cmp    %r8,%r13
  jae    L92
  mov    %al,0x0(%rbp,%r10,1)
  mov    %r13d,%r9d
  mov    %r13,%r10
L92:
  movzbl (%rcx),%ecx
  jmp    L100
L63:
  xor    %r10d,%r10d
  jmp    L77
```

assistant: ```c
void cutItemString(char *in, char *out, char sep, int num, size_t maxout) {
  int n;
  unsigned int i, c;
  for (c = 0, n = 0, i = 0; in[i]; i++) {
    if (in[i] == sep)
      n++;
    if (n >= num && in[i] != sep && c + 1 < maxout)
      out[c++] = in[i];
    if (n >= num && in[i + 1] == sep)
      break;
  }
  if (c < maxout)
    out[c] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fix_truncated_utf8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x2,-0x10(%rbp)
  jbe    L10
  mov    -0x10(%rbp),%rax
  lea    -0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jns    L16
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L30
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movb   $0x0,(%rax)
  jmp    L60
L30:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  jne    L7
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  jmp    L60
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf0,%eax
  cmp    $0xf0,%eax
  jne    L60
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L60
L10:
  nop
  jmp    L60
L16:
  nop
L60:
  leave
  ret
```

assistant: ```c
void fix_truncated_utf8(char *str) {
  size_t len = strlen(str);
  if (len < 3) {
    return;
  }
  char *b = str + len - 3;
  if ((b[2] & 0x80) == 0) {
    return;
  }
  if (b[2] & 0x40) {
    b[2] = 0;
  } else if ((b[1] & 0xe0) == 0xe0) {
    b[1] = 0;
  } else if ((b[0] & 0xf0) == 0xf0) {
    b[0] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fix_truncated_utf8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x2,%rax
  jbe    L9
  lea    -0x3(%rbx,%rax,1),%rax
  movzbl 0x2(%rax),%edx
  test   %dl,%dl
  jns    L9
  test   $0x40,%dl
  je     L52
  movb   $0x0,0x2(%rax)
L9:
  pop    %rbx
  ret
L52:
  movsbl 0x1(%rax),%edx
  and    $0xe0,%edx
  cmp    $0xe0,%edx
  je     L40
  movsbl (%rax),%edx
  and    $0xf0,%edx
  cmp    $0xf0,%edx
  jne    L9
  movb   $0x0,(%rax)
  jmp    L9
L40:
  movb   $0x0,0x1(%rax)
  jmp    L9
```

assistant: ```c
void fix_truncated_utf8(char *str) {
  size_t len = strlen(str);
  if (len < 3) {
    return;
  }
  char *b = str + len - 3;
  if ((b[2] & 0x80) == 0) {
    return;
  }
  if (b[2] & 0x40) {
    b[2] = 0;
  } else if ((b[1] & 0xe0) == 0xe0) {
    b[1] = 0;
  } else if ((b[0] & 0xf0) == 0xf0) {
    b[0] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fix_truncated_utf8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x2,%rax
  jbe    L3
  lea    -0x3(%rbx,%rax,1),%rax
  movzbl 0x2(%rax),%edx
  test   %dl,%dl
  jns    L3
  and    $0x40,%edx
  jne    L4
  movsbl 0x1(%rax),%edx
  and    $0xe0,%edx
  cmp    $0xe0,%edx
  je     L9
  movsbl (%rax),%edx
  and    $0xf0,%edx
  cmp    $0xf0,%edx
  je     L18
L3:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  movb   $0x0,0x2(%rax)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L9:
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  movb   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void fix_truncated_utf8(char *str) {
  size_t len = strlen(str);
  if (len < 3) {
    return;
  }
  char *b = str + len - 3;
  if ((b[2] & 0x80) == 0) {
    return;
  }
  if (b[2] & 0x40) {
    b[2] = 0;
  } else if ((b[1] & 0xe0) == 0xe0) {
    b[1] = 0;
  } else if ((b[0] & 0xf0) == 0xf0) {
    b[0] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fix_truncated_utf8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x2,%rax
  jbe    L35
  lea    -0x3(%rbx,%rax,1),%rax
  movzbl 0x2(%rax),%edx
  test   %dl,%dl
  jns    L35
  and    $0x40,%edx
  jne    L20
  movsbl 0x1(%rax),%edx
  and    $0xe0,%edx
  cmp    $0xe0,%edx
  je     L11
  movsbl (%rax),%edx
  and    $0xf0,%edx
  cmp    $0xf0,%edx
  je     L31
L35:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  movb   $0x0,0x2(%rax)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L31:
  movb   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void fix_truncated_utf8(char *str) {
  size_t len = strlen(str);
  if (len < 3) {
    return;
  }
  char *b = str + len - 3;
  if ((b[2] & 0x80) == 0) {
    return;
  }
  if (b[2] & 0x40) {
    b[2] = 0;
  } else if ((b[1] & 0xe0) == 0xe0) {
    b[1] = 0;
  } else if ((b[0] & 0xf0) == 0xf0) {
    b[0] = 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jle    L23
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L34
L23:
  mov    $0xffffffff,%eax
  jmp    L16
L34:
  cmpl   $0x7,-0x10(%rbp)
  jg     L46
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <select@plt>
  jmp    L16
L46:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <pick_by_sort@plt>
L16:
  leave
  ret
```

assistant: ```c
int pick(int *x, int len, int n) {
  if (n < 1 || n > len)
    return (-1);
  if (n < 8)
    return (select(x, len, n));
  return (pick_by_sort(x, 0, len - 1, n));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pick>:
  endbr64
  test   %edx,%edx
  jle    L34
  mov    %edx,%ecx
  cmp    %esi,%edx
  jg     L34
  sub    $0x8,%rsp
  cmp    $0x7,%edx
  jle    L4
  lea    -0x1(%rsi),%edx
  mov    $0x0,%esi
  call   <pick_by_sort@plt>
L32:
  add    $0x8,%rsp
  ret
L4:
  call   <select@plt>
  jmp    L32
L34:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pick(int *x, int len, int n) {
  if (n < 1 || n > len)
    return (-1);
  if (n < 8)
    return (select(x, len, n));
  return (pick_by_sort(x, 0, len - 1, n));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pick>:
  endbr64
  mov    %edx,%ecx
  test   %edx,%edx
  jle    L5
  cmp    %esi,%edx
  jg     L5
  cmp    $0x7,%edx
  jle    L9
  lea    -0x1(%rsi),%edx
  xor    %esi,%esi
  jmp    1060 <pick_by_sort@plt>
  nopl   (%rax)
L9:
  jmp    1070 <select@plt>
  nopl   (%rax)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pick(int *x, int len, int n) {
  if (n < 1 || n > len)
    return (-1);
  if (n < 8)
    return (select(x, len, n));
  return (pick_by_sort(x, 0, len - 1, n));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pick>:
  endbr64
  mov    %edx,%ecx
  test   %edx,%edx
  jle    L3
  cmp    %esi,%edx
  jg     L3
  cmp    $0x7,%edx
  jle    L8
  lea    -0x1(%rsi),%edx
  xor    %esi,%esi
  jmp    1060 <pick_by_sort@plt>
  nopl   (%rax)
L8:
  jmp    1070 <select@plt>
  nopl   (%rax)
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int pick(int *x, int len, int n) {
  if (n < 1 || n > len)
    return (-1);
  if (n < 8)
    return (select(x, len, n));
  return (pick_by_sort(x, 0, len - 1, n));
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L14:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    puts(argv[i]);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x8(%rsi,%rax,8),%rbp
L10:
  mov    (%rbx),%rdi
  call   <puts@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    puts(argv[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L14
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    puts(argv[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x8(%rsi,%rax,8),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L6:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <puts@plt>
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 0; i < argc; i++) {
    puts(argv[i]);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ddot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L9:
  subl   $0x1,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L9
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double ddot(unsigned int n, const double *dx1, const double *dx2) {
  double sum = 0.0;
  do {
    --n;
    sum += dx1[n] * dx2[n];
  } while (n);
  return sum;
}
```
user: What is the c source code of the assembly code below?

```asm
<ddot>:
  endbr64
  lea    -0x1(%rdi),%eax
  shl    $0x3,%rax
  pxor   %xmm1,%xmm1
L8:
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  sub    $0x8,%rax
  cmp    $0xfffffffffffffff8,%rax
  jne    L8
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double ddot(unsigned int n, const double *dx1, const double *dx2) {
  double sum = 0.0;
  do {
    --n;
    sum += dx1[n] * dx2[n];
  } while (n);
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ddot>:
  endbr64
  lea    -0x1(%rdi),%eax
  pxor   %xmm1,%xmm1
  shl    $0x3,%rax
  nop
L0:
  movsd  (%rsi,%rax,1),%xmm0
  mulsd  (%rdx,%rax,1),%xmm0
  sub    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    $0xfffffffffffffff8,%rax
  jne    L0
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double ddot(unsigned int n, const double *dx1, const double *dx2) {
  double sum = 0.0;
  do {
    --n;
    sum += dx1[n] * dx2[n];
  } while (n);
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ddot>:
  endbr64
  mov    %edi,%r9d
  mov    %rsi,%rdi
  cmp    $0x1,%r9d
  je     L35
  lea    -0x1(%r9),%eax
  lea    -0x2(%r9),%esi
  pxor   %xmm0,%xmm0
  xor    %ecx,%ecx
  lea    -0x8(,%rax,8),%r8
  shr    %esi
  xor    %eax,%eax
  lea    (%rdi,%r8,1),%r10
  add    $0x1,%esi
  add    %rdx,%r8
  nopl   0x0(%rax,%rax,1)
L12:
  movupd (%r10,%rax,1),%xmm1
  movupd (%r8,%rax,1),%xmm2
  add    $0x1,%ecx
  sub    $0x10,%rax
  shufpd $0x1,%xmm1,%xmm1
  shufpd $0x1,%xmm2,%xmm2
  mulpd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %ecx,%esi
  ja     L12
  add    %esi,%esi
  mov    %r9d,%eax
  sub    %esi,%eax
  cmp    %esi,%r9d
  je     L4
L24:
  sub    $0x1,%eax
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  (%rdi,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  nop
L4:
  ret
  nopl   0x0(%rax)
L35:
  mov    $0x1,%eax
  pxor   %xmm0,%xmm0
  jmp    L24
```

assistant: ```c
double ddot(unsigned int n, const double *dx1, const double *dx2) {
  double sum = 0.0;
  do {
    --n;
    sum += dx1[n] * dx2[n];
  } while (n);
  return sum;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<timer_interval_start_minutes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  imul   $0x3e8,%rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <timer_interval_start@plt>
  nop
  leave
  ret
```

assistant: ```c
void timer_interval_start_minutes(struct itimer *t, uint32_t minutes) {
  uint32_t interval = minutes;
  interval *= 1000L;
  interval *= 60L;
  timer_interval_start(t, interval);
}
```