ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<map_color>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movss  %xmm2,-0x24(%rbp)
  movss  %xmm3,-0x28(%rbp)
  movss  %xmm4,-0x2c(%rbp)
  movss  %xmm5,-0x30(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x24(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x20(%rbp),%xmm1
  movss  -0x30(%rbp),%xmm0
  subss  -0x2c(%rbp),%xmm0
  mulss  -0x28(%rbp),%xmm0
  addss  -0x2c(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L16
  pxor   %xmm0,%xmm0
  jmp    L12
L16:
  movsd  -0x8(%rbp),%xmm0
  movsd  D12(%rip),%xmm1
  comisd %xmm1,%xmm0
  jbe    L6
  movsd  D12(%rip),%xmm0
  jmp    L12
L6:
  movsd  -0x8(%rbp),%xmm0
L12:
  movsd  D22(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: byte[8]
name: parse_data
arguments: tag: D22
datatype: byte[8]

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

assistant: ```c
unsigned char map_color(double amount, double comp_amount, float color, float luma, float minColor, float maxColor) {
  double val = (comp_amount * color) + amount * (luma * (maxColor - minColor) + minColor);
  return (unsigned char)(255 * (val < 0 ? 0 : (val > 1 ? 1 : val)));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<map_color>:
  endbr64
  subss  %xmm4,%xmm5
  mulss  %xmm3,%xmm5
  addss  %xmm4,%xmm5
  cvtss2sd %xmm5,%xmm5
  mulsd  %xmm0,%xmm5
  cvtss2sd %xmm2,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm5,%xmm1
  addsd  %xmm2,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L24
  comisd D23(%rip),%xmm1
  jbe    L25
  movsd  D23(%rip),%xmm1
  jmp    L25
L24:
  pxor   %xmm1,%xmm1
L25:
  mulsd  D3(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D23
type: byte[16]
name: read_data
arguments: data_label: D3
type: byte[8]

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

assistant: ```c
unsigned char map_color(double amount, double comp_amount, float color, float luma, float minColor, float maxColor) {
  double val = (comp_amount * color) + amount * (luma * (maxColor - minColor) + minColor);
  return (unsigned char)(255 * (val < 0 ? 0 : (val > 1 ? 1 : val)));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<map_color>:
  endbr64
  subss  %xmm4,%xmm5
  cvtss2sd %xmm2,%xmm2
  mulsd  %xmm1,%xmm2
  xor    %eax,%eax
  mulss  %xmm3,%xmm5
  addss  %xmm5,%xmm4
  cvtss2sd %xmm4,%xmm4
  mulsd  %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  movapd %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  ja     L17
  comisd D9(%rip),%xmm1
  mov    $0xffffffff,%eax
  jbe    L0
L17:
  ret
  nopl   0x0(%rax)
L0:
  mulsd  D7(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_infered: byte[16]
name: extract_symbolic_data
arguments: tag: D7
type_infered: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

assistant: ```c
unsigned char map_color(double amount, double comp_amount, float color, float luma, float minColor, float maxColor) {
  double val = (comp_amount * color) + amount * (luma * (maxColor - minColor) + minColor);
  return (unsigned char)(255 * (val < 0 ? 0 : (val > 1 ? 1 : val)));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<map_color>:
  endbr64
  subss  %xmm4,%xmm5
  cvtss2sd %xmm2,%xmm2
  mulsd  %xmm1,%xmm2
  xor    %eax,%eax
  mulss  %xmm3,%xmm5
  addss  %xmm5,%xmm4
  cvtss2sd %xmm4,%xmm4
  mulsd  %xmm0,%xmm4
  pxor   %xmm0,%xmm0
  movapd %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  ja     L8
  comisd D5(%rip),%xmm1
  mov    $0xffffffff,%eax
  jbe    L2
L8:
  ret
  nopl   0x0(%rax)
L2:
  mulsd  D4(%rip),%xmm1
  cvttsd2si %xmm1,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type_infered: byte[16]
name: disassemble_data
arguments: data_tag: D4
type_infered: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

assistant: ```c
unsigned char map_color(double amount, double comp_amount, float color, float luma, float minColor, float maxColor) {
  double val = (comp_amount * color) + amount * (luma * (maxColor - minColor) + minColor);
  return (unsigned char)(255 * (val < 0 ? 0 : (val > 1 ? 1 : val)));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<size_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L19:
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int size_string(unsigned char *string) {
  int i;
  for (i = 0; string[i] != '\0'; ++i)
    ;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<size_string>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L2
  mov    $0x1,%eax
L25:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L25
L24:
  mov    %edx,%eax
  ret
L2:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int size_string(unsigned char *string) {
  int i;
  for (i = 0; string[i] != '\0'; ++i)
    ;
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<size_string>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L14
  mov    $0x1,%eax
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L2
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int size_string(unsigned char *string) {
  int i;
  for (i = 0; string[i] != '\0'; ++i)
    ;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<size_string>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L7
  mov    $0x1,%eax
  xchg   %ax,%ax
L19:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L19
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int size_string(unsigned char *string) {
  int i;
  for (i = 0; string[i] != '\0'; ++i)
    ;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fd_nrf8001_dispatch_read_dynamic_data_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  je     L35
  cmpl   $0x2,-0x14(%rbp)
  je     L27
  jmp    L29
L35:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <fd_nrf8001_read_dynamic_data_continue@plt>
  jmp    L26
L27:
  mov    $0x0,%eax
  call   <fd_nrf8001_read_dynamic_data_complete@plt>
  jmp    L26
L29:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fd_nrf8001_read_dynamic_data_error@plt>
  nop
L26:
  nop
  leave
  ret
```

assistant: ```c
void fd_nrf8001_dispatch_read_dynamic_data_response(uint8_t status, uint8_t *response_data, uint32_t response_data_length) {
  switch (status) {
  case 0x01: {
    uint8_t sequence_number = response_data[0];
    uint8_t *data = &response_data[1];
    uint32_t length = response_data_length - 1;
    fd_nrf8001_read_dynamic_data_continue(sequence_number, data, length);
  } break;
  case 0x02:
    fd_nrf8001_read_dynamic_data_complete();
    break;
  default:
    fd_nrf8001_read_dynamic_data_error(status);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fd_nrf8001_dispatch_read_dynamic_data_response>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  je     L0
  cmp    $0x2,%edi
  je     L10
  call   <fd_nrf8001_read_dynamic_data_error@plt>
  jmp    L12
L0:
  mov    %rsi,%rax
  sub    $0x1,%edx
  lea    0x4(%rsi),%rsi
  mov    (%rax),%edi
  call   <fd_nrf8001_read_dynamic_data_continue@plt>
L12:
  add    $0x8,%rsp
  ret
L10:
  mov    $0x0,%eax
  call   <fd_nrf8001_read_dynamic_data_complete@plt>
  jmp    L12
```

assistant: ```c
void fd_nrf8001_dispatch_read_dynamic_data_response(uint8_t status, uint8_t *response_data, uint32_t response_data_length) {
  switch (status) {
  case 0x01: {
    uint8_t sequence_number = response_data[0];
    uint8_t *data = &response_data[1];
    uint32_t length = response_data_length - 1;
    fd_nrf8001_read_dynamic_data_continue(sequence_number, data, length);
  } break;
  case 0x02:
    fd_nrf8001_read_dynamic_data_complete();
    break;
  default:
    fd_nrf8001_read_dynamic_data_error(status);
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fd_nrf8001_dispatch_read_dynamic_data_response>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x1,%edi
  je     L9
  cmp    $0x2,%edi
  je     L8
  jmp    1090 <fd_nrf8001_read_dynamic_data_error@plt>
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    (%rax),%edi
  sub    $0x1,%edx
  lea    0x4(%rsi),%rsi
  jmp    1070 <fd_nrf8001_read_dynamic_data_continue@plt>
  xchg   %ax,%ax
L8:
  xor    %eax,%eax
  jmp    1080 <fd_nrf8001_read_dynamic_data_complete@plt>
```

assistant: ```c
void fd_nrf8001_dispatch_read_dynamic_data_response(uint8_t status, uint8_t *response_data, uint32_t response_data_length) {
  switch (status) {
  case 0x01: {
    uint8_t sequence_number = response_data[0];
    uint8_t *data = &response_data[1];
    uint32_t length = response_data_length - 1;
    fd_nrf8001_read_dynamic_data_continue(sequence_number, data, length);
  } break;
  case 0x02:
    fd_nrf8001_read_dynamic_data_complete();
    break;
  default:
    fd_nrf8001_read_dynamic_data_error(status);
    break;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fd_nrf8001_dispatch_read_dynamic_data_response>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x1,%edi
  je     L11
  cmp    $0x2,%edi
  je     L14
  jmp    1090 <fd_nrf8001_read_dynamic_data_error@plt>
  cs nopw 0x0(%rax,%rax,1)
L11:
  mov    (%rax),%edi
  sub    $0x1,%edx
  lea    0x4(%rsi),%rsi
  jmp    1070 <fd_nrf8001_read_dynamic_data_continue@plt>
  xchg   %ax,%ax
L14:
  xor    %eax,%eax
  jmp    1080 <fd_nrf8001_read_dynamic_data_complete@plt>
```

assistant: ```c
void fd_nrf8001_dispatch_read_dynamic_data_response(uint8_t status, uint8_t *response_data, uint32_t response_data_length) {
  switch (status) {
  case 0x01: {
    uint8_t sequence_number = response_data[0];
    uint8_t *data = &response_data[1];
    uint32_t length = response_data_length - 1;
    fd_nrf8001_read_dynamic_data_continue(sequence_number, data, length);
  } break;
  case 0x02:
    fd_nrf8001_read_dynamic_data_complete();
    break;
  default:
    fd_nrf8001_read_dynamic_data_error(status);
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L39
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D69(%rip),%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L36
  lea    D100(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L39:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  movsd  %xmm0,0x10(%rsp)
L36:
  movsd  0x10(%rsp),%xmm1
  movapd %xmm1,%xmm0
  subsd  D60(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  addsd  D96(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  subsd  D110(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm1,%xmm3
  addsd  D33(%rip),%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm2
  subsd  D36(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm0
  lea    D57(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  lea    D27(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  lea    D99(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movsd  (%rsp),%xmm4
  divsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm0
  lea    D47(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D18
datatype: string
name: disassemble_data
arguments: label: D69
datatype: string
name: disassemble_data
arguments: label: D100
datatype: string
name: disassemble_data
arguments: label: D60
datatype: byte[8]
name: disassemble_data
arguments: label: D96
datatype: byte[8]
name: disassemble_data
arguments: label: D110
datatype: f64
name: disassemble_data
arguments: label: D33
datatype: f64
name: disassemble_data
arguments: label: D36
datatype: f64
name: disassemble_data
arguments: label: D57
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D99
datatype: string
name: disassemble_data
arguments: label: D47
datatype: string

tool: D18: 
Please Input x value:


tool: D69: %lf

tool: D100: &MAIN ERROR: Inputs

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D96": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D110: 6.3

tool: D33: 0.05005

tool: D36: 3.14

tool: D57: 
x value = %g


tool: D27: f1(x) = %g 

tool: D99:  f2(x) = %g


tool: D47: f(x) = %g


assistant: ```c
int main(int argc, char *argv[]) {
  double f, f1, f2, x;
  int s;
  if (argc != 2) {
    printf("\nPlease Input x value:\n\n");
    s = scanf("%lf", &x);
    if (s != 1)
      printf("&MAIN ERROR: Inputs");
  } else
    x = atoi(argv[1]);
  f1 = ((x - 2) * x + 1) * x - 6.3;
  f2 = (x + 0.05005) * x - 3.14;
  f = f1 / f2;
  printf("\nx value = %g\n", x);
  printf("f1(x) = %g ", f1);
  printf(" f2(x) = %g\n", f2);
  printf("f(x) = %g\n", f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L45
  lea    D48(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D113(%rip),%rdi
  call   <scanf@plt>
  sub    $0x1,%eax
  jne    L48
L1:
  movsd  0x10(%rsp),%xmm1
  movsd  D82(%rip),%xmm3
  mov    $0x1,%eax
  lea    D44(%rip),%rdi
  movapd %xmm1,%xmm0
  subsd  D80(%rip),%xmm0
  addsd  %xmm1,%xmm3
  mulsd  %xmm1,%xmm0
  addsd  D30(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  subsd  D59(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm2
  subsd  D34(%rip),%xmm2
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  mov    $0x1,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  movsd  (%rsp),%xmm4
  mov    $0x1,%eax
  divsd  0x8(%rsp),%xmm4
  lea    D60(%rip),%rdi
  movapd %xmm4,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L48:
  lea    D85(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L1
L45:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  movsd  %xmm0,0x10(%rsp)
  jmp    L1
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D48
type_infered: string
name: parse_data
arguments: data_label: D113
type_infered: string
name: parse_data
arguments: data_label: D82
type_infered: f64
name: parse_data
arguments: data_label: D44
type_infered: string
name: parse_data
arguments: data_label: D80
type_infered: byte[8]
name: parse_data
arguments: data_label: D30
type_infered: byte[8]
name: parse_data
arguments: data_label: D59
type_infered: f64
name: parse_data
arguments: data_label: D34
type_infered: f64
name: parse_data
arguments: data_label: D26
type_infered: string
name: parse_data
arguments: data_label: D38
type_infered: string
name: parse_data
arguments: data_label: D60
type_infered: string
name: parse_data
arguments: data_label: D85
type_infered: string

tool: D48: 
Please Input x value:


tool: D113: %lf

tool: D82: 0.05005

tool: D44: 
x value = %g


tool: {"D80": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D30": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D59: 6.3

tool: D34: 3.14

tool: D26: f1(x) = %g 

tool: D38:  f2(x) = %g


tool: D60: f(x) = %g


tool: D85: &MAIN ERROR: Inputs

assistant: ```c
int main(int argc, char *argv[]) {
  double f, f1, f2, x;
  int s;
  if (argc != 2) {
    printf("\nPlease Input x value:\n\n");
    s = scanf("%lf", &x);
    if (s != 1)
      printf("&MAIN ERROR: Inputs");
  } else
    x = atoi(argv[1]);
  f1 = ((x - 2) * x + 1) * x - 6.3;
  f2 = (x + 0.05005) * x - 3.14;
  f = f1 / f2;
  printf("\nx value = %g\n", x);
  printf("f1(x) = %g ", f1);
  printf(" f2(x) = %g\n", f2);
  printf("f(x) = %g\n", f);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x2,%edi
  je     L16
  lea    D119(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  lea    D90(%rip),%rdi
  call   <scanf@plt>
  sub    $0x1,%eax
  jne    L11
L31:
  movsd  0x10(%rsp),%xmm1
  movsd  D89(%rip),%xmm3
  mov    $0x1,%eax
  lea    D91(%rip),%rdi
  movapd %xmm1,%xmm0
  subsd  D58(%rip),%xmm0
  addsd  %xmm1,%xmm3
  mulsd  %xmm1,%xmm0
  addsd  D43(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  subsd  D47(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  movapd %xmm3,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm0,%xmm2
  subsd  D8(%rip),%xmm2
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  movsd  (%rsp),%xmm0
  mov    $0x1,%eax
  lea    D41(%rip),%rdi
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D97(%rip),%rdi
  call   <printf@plt>
  movsd  (%rsp),%xmm4
  mov    $0x1,%eax
  divsd  0x8(%rsp),%xmm4
  lea    D93(%rip),%rdi
  movapd %xmm4,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L11:
  lea    D112(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L31
L16:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  movsd  %xmm0,0x10(%rsp)
  jmp    L31
L47:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D119
type_guessed: string
name: disassemble_data
arguments: data_tag: D90
type_guessed: string
name: disassemble_data
arguments: data_tag: D89
type_guessed: f64
name: disassemble_data
arguments: data_tag: D91
type_guessed: string
name: disassemble_data
arguments: data_tag: D58
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D43
type_guessed: byte[8]
name: disassemble_data
arguments: data_tag: D47
type_guessed: f64
name: disassemble_data
arguments: data_tag: D8
type_guessed: f64
name: disassemble_data
arguments: data_tag: D41
type_guessed: string
name: disassemble_data
arguments: data_tag: D97
type_guessed: string
name: disassemble_data
arguments: data_tag: D93
type_guessed: string
name: disassemble_data
arguments: data_tag: D112
type_guessed: string

tool: D119: 
Please Input x value:


tool: D90: %lf

tool: D89: 0.05005

tool: D91: 
x value = %g


tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D43": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D47: 6.3

tool: D8: 3.14

tool: D41: f1(x) = %g 

tool: D97:  f2(x) = %g


tool: D93: f(x) = %g


tool: D112: &MAIN ERROR: Inputs

assistant: ```c
int main(int argc, char *argv[]) {
  double f, f1, f2, x;
  int s;
  if (argc != 2) {
    printf("\nPlease Input x value:\n\n");
    s = scanf("%lf", &x);
    if (s != 1)
      printf("&MAIN ERROR: Inputs");
  } else
    x = atoi(argv[1]);
  f1 = ((x - 2) * x + 1) * x - 6.3;
  f2 = (x + 0.05005) * x - 3.14;
  f = f1 / f2;
  printf("\nx value = %g\n", x);
  printf("f1(x) = %g ", f1);
  printf(" f2(x) = %g\n", f2);
  printf("f(x) = %g\n", f);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dotconf_continue_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x1,-0x20(%rbp)
  jbe    L60
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L92
L60:
  mov    $0x0,%eax
  jmp    L75
L92:
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L15
  cmpq   $0x2,-0x20(%rbp)
  jbe    L15
  subq   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L82
  mov    $0x0,%eax
  jmp    L75
L82:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L64
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L80
L64:
  mov    $0x1,%eax
  jmp    L75
L80:
  mov    $0x0,%eax
L75:
  pop    %rbp
  ret
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length;
  if (length < 2 || *(--cp1) != '\n')
    return 0;
  if (*(--cp1) == '\r' && length >= 3)
    cp1--;
  if (*cp1 != '\\')
    return 0;
  *cp1 = '\0';
  return (cp1 <= buffer || *(cp1 - 1) != '\\');
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<dotconf_continue_line>:
  endbr64
  mov    $0x0,%eax
  cmp    $0x1,%rsi
  jbe    L58
  lea    (%rdi,%rsi,1),%rdx
  cmpb   $0xa,-0x1(%rdx)
  jne    L58
  lea    -0x2(%rdx),%r8
  movzbl -0x2(%rdx),%ecx
  cmp    $0x2,%rsi
  jbe    L56
  cmp    $0xd,%cl
  je     L5
L56:
  mov    $0x0,%eax
  cmp    $0x5c,%cl
  jne    L58
  movb   $0x0,(%r8)
  mov    $0x1,%eax
  cmp    %rdi,%r8
  jbe    L58
  cmpb   $0x5c,-0x1(%r8)
  setne  %al
  movzbl %al,%eax
L58:
  ret
L5:
  lea    -0x3(%rdx),%r8
  movzbl -0x3(%rdx),%ecx
  jmp    L56
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length;
  if (length < 2 || *(--cp1) != '\n')
    return 0;
  if (*(--cp1) == '\r' && length >= 3)
    cp1--;
  if (*cp1 != '\\')
    return 0;
  *cp1 = '\0';
  return (cp1 <= buffer || *(cp1 - 1) != '\\');
}
```
user: Translate the below assembly code into C programming language:

```asm
<dotconf_continue_line>:
  endbr64
  xor    %eax,%eax
  cmp    $0x1,%rsi
  jbe    L9
  lea    (%rdi,%rsi,1),%rdx
  cmpb   $0xa,-0x1(%rdx)
  jne    L9
  movzbl -0x2(%rdx),%ecx
  cmp    $0xd,%cl
  je     L51
  lea    -0x2(%rdx),%rsi
L4:
  xor    %eax,%eax
  cmp    $0x5c,%cl
  jne    L9
  movb   $0x0,(%rsi)
  mov    $0x1,%eax
  cmp    %rdi,%rsi
  jbe    L9
  xor    %eax,%eax
  cmpb   $0x5c,-0x1(%rsi)
  setne  %al
L9:
  ret
  nopl   0x0(%rax)
L51:
  cmp    $0x2,%rsi
  je     L9
  movzbl -0x3(%rdx),%ecx
  lea    -0x3(%rdx),%rsi
  jmp    L4
```

assistant: ```c
int dotconf_continue_line(char *buffer, size_t length) {
  char *cp1 = buffer + length;
  if (length < 2 || *(--cp1) != '\n')
    return 0;
  if (*(--cp1) == '\r' && length >= 3)
    cp1--;
  if (*cp1 != '\\')
    return 0;
  *cp1 = '\0';
  return (cp1 <= buffer || *(cp1 - 1) != '\\');
}
```