user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x6b63,%ecx
  mov    $0x736f,%edx
  mov    $0x4,%esi
  lea    D33(%rip),%rdi
  lea    D69(%rip),%rbp
  sub    $0x30,%rsp
  movdqa D63(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %cx,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  mov    %dx,0xd(%rsp)
  movl   $0x6c726143,0x9(%rsp)
  movb   $0x0,0xf(%rsp)
  movb   $0x0,0x22(%rsp)
  call   <printf@plt>
  mov    $0x14,%esi
  lea    D25(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x5,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xc,%edx
  mov    $0xa,%esi
  xor    %eax,%eax
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  lea    D47(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x7,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x13,%esi
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x13,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x9(%rsp),%rsi
  lea    D70(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D33
datatype: string
name: unpack_data
arguments: tag: D69
datatype: string
name: unpack_data
arguments: tag: D63
datatype: byte[16]
name: unpack_data
arguments: tag: D25
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string
name: unpack_data
arguments: tag: D37
datatype: string
name: unpack_data
arguments: tag: D28
datatype: string
name: unpack_data
arguments: tag: D47
datatype: string
name: unpack_data
arguments: tag: D14
datatype: string
name: unpack_data
arguments: tag: D70
datatype: string

tool: D33: The size of an int: %ld


tool: D69: The number of chars: %ld


tool: {"D63": [0x43,0x61,0x72,0x6c,0x6f,0x73,0x20,0x45,0x2e,0x20,0x4b,0x69,0x6c,0x6c,0x70,0x61]}

tool: D25: The size of areas (int[]): %ld


tool: D16: The number of ints in areas: %ld


tool: D37: The first area is %d, the 2nd is %d.


tool: D28: The size of a char: %ld


tool: D47: The size of name (char[]): %ld


tool: D14: The size of full_name (char[]): %ld


tool: D70: name="%s" and full_name="%s"


assistant: ```c
int main(int argc, char *argv[]) {
  int areas[] = {10, 12, 13, 14, 20};
  char name[] = "Carlos";
  char full_name[] = {'C', 'a', 'r', 'l', 'o', 's', ' ', 'E', '.', ' ', 'K', 'i', 'l', 'l', 'p', 'a', 'c', 'k', '\0'};
  printf("The size of an int: %ld\n", sizeof(int));
  printf("The size of areas (int[]): %ld\n", sizeof(areas));
  printf("The number of ints in areas: %ld\n", sizeof(areas) / sizeof(int));
  printf("The first area is %d, the 2nd is %d.\n", areas[0], areas[1]);
  printf("The size of a char: %ld\n", sizeof(char));
  printf("The size of name (char[]): %ld\n", sizeof(name));
  printf("The number of chars: %ld\n", sizeof(name) / sizeof(char));
  printf("The size of full_name (char[]): %ld\n", sizeof(full_name));
  printf("The number of chars: %ld\n", sizeof(full_name) / sizeof(char));
  printf("name=\"%s\" and full_name=\"%s\"\n", name, full_name);
  return 0;
}
```