ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D57(%rip),%r15
  push   %r14
  lea    D30(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  lea    D20(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <rand@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%ebx
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  sub    %eax,%ebx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L52:
  jg     L6
  cmp    %eax,%ebx
  je     L18
L33:
  mov    %r14,%rdi
  cmp    %eax,%ebx
  jge    L52
L56:
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  jne    L33
L18:
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r15,%rdi
  jmp    L56
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D57
type: string
name: read_data
arguments: data_tag: D30
type: string
name: read_data
arguments: data_tag: D17
type: string
name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D37
type: string

tool: D57: My number is larger than your guess


tool: D30: My number is smaller than your guess


tool: D17: Please guess again: 

tool: D20: %i

tool: D7: Enter a whole number between 1 and 20, please. 

tool: D37: Well done you guessed correctly!


assistant: ```c
int main() {
  int guess;
  int r = rand() % 20 + 1;
  printf("Enter a whole number between 1 and 20, please. ");
  scanf("%i", &guess);
  do {
    if (guess > r) {
      printf("My number is smaller than your guess\n");
      printf("Please guess again: ");
      scanf("%i", &guess);
    } else if (guess < r) {
      printf("My number is larger than your guess\n");
      printf("Please guess again: ");
      scanf("%i", &guess);
    }
  } while (guess != r);
  if (guess == r) {
    printf("Well done you guessed correctly!\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D38(%rip),%r15
  push   %r14
  lea    D58(%rip),%r14
  push   %r13
  lea    D40(%rip),%r13
  push   %r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <rand@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%ebx
  cltq
  imul   $0x66666667,%rax,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sar    $0x23,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  shl    $0x2,%eax
  sub    %eax,%ebx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L55:
  jg     L36
  cmp    %eax,%ebx
  je     L50
L19:
  mov    %r14,%rdi
  cmp    %eax,%ebx
  jge    L55
L28:
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  jne    L19
L50:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    %r15,%rdi
  jmp    L28
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D38
type_guessed: string
name: unpack_data
arguments: label: D58
type_guessed: string
name: unpack_data
arguments: label: D40
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D53
type_guessed: string

tool: D38: My number is larger than your guess


tool: D58: My number is smaller than your guess


tool: D40: Please guess again: 

tool: D2: %i

tool: D11: Enter a whole number between 1 and 20, please. 

tool: D53: Well done you guessed correctly!


assistant: ```c
int main() {
  int guess;
  int r = rand() % 20 + 1;
  printf("Enter a whole number between 1 and 20, please. ");
  scanf("%i", &guess);
  do {
    if (guess > r) {
      printf("My number is smaller than your guess\n");
      printf("Please guess again: ");
      scanf("%i", &guess);
    } else if (guess < r) {
      printf("My number is larger than your guess\n");
      printf("Please guess again: ");
      scanf("%i", &guess);
    }
  } while (guess != r);
  if (guess == r) {
    printf("Well done you guessed correctly!\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printBinary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L39:
  mov    -0x4(%rbp),%eax
  mov    $0x80000000,%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L5
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L5:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L30:
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x1f,-0x4(%rbp)
  jle    L39
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D25
type_guessed: string
name: retrieve_data
arguments: data_tag: D2
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string

tool: D25: 1

tool: D2: 0

tool: D10: 


assistant: ```c
void printBinary(int num) {
  int i;
  for (i = 0; i < 32; i++) {
    if (num & (1 << (31 - i))) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printBinary>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    $0x0,%ebx
  mov    $0x80000000,%r12d
  lea    D4(%rip),%r14
  lea    D25(%rip),%r13
  jmp    L11
L14:
  mov    %r14,%rdi
  call   <printf@plt>
L36:
  add    $0x1,%ebx
  cmp    $0x20,%ebx
  je     L4
L11:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  shr    %cl,%eax
  test   %ebp,%eax
  je     L14
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L36
L4:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D4
datatype: string
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D0
datatype: string

tool: D4: 0

tool: D25: 1

tool: D0: 


assistant: ```c
void printBinary(int num) {
  int i;
  for (i = 0; i < 32; i++) {
    if (num & (1 << (31 - i))) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<printBinary>:
  endbr64
  push   %r14
  lea    D13(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  mov    $0x80000000,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x20,%ebx
  je     L2
L12:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  shr    %cl,%eax
  test   %ebp,%eax
  jne    L37
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x20,%ebx
  jne    L12
L2:
  pop    %rbx
  lea    D1(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D11
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string

tool: D13: 0

tool: D11: 1

tool: D1: 


assistant: ```c
void printBinary(int num) {
  int i;
  for (i = 0; i < 32; i++) {
    if (num & (1 << (31 - i))) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printBinary>:
  endbr64
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  lea    D11(%rip),%r13
  push   %r12
  mov    $0x80000000,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  jmp    L38
  cs nopw 0x0(%rax,%rax,1)
L39:
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x20,%ebx
  je     L12
L38:
  mov    %r12d,%eax
  mov    %ebx,%ecx
  shr    %cl,%eax
  test   %ebp,%eax
  jne    L39
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x20,%ebx
  jne    L38
L12:
  pop    %rbx
  lea    D7(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D7
type: string

tool: D2: 0

tool: D11: 1

tool: D7: 


assistant: ```c
void printBinary(int num) {
  int i;
  for (i = 0; i < 32; i++) {
    if (num & (1 << (31 - i))) {
      printf("1");
    } else {
      printf("0");
    }
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sequential>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <guass_seq@plt>
  mov    $0x0,%eax
  call   <print_data@plt>
  mov    $0x0,%eax
  call   <back_sub@plt>
  mov    $0x0,%eax
  call   <print_result@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: 	Executing sequentially.


assistant: ```c
void sequential() {
  printf("\tExecuting sequentially.\n");
  guass_seq();
  print_data();
  back_sub();
  print_result();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sequential>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <guass_seq@plt>
  mov    $0x0,%eax
  call   <print_data@plt>
  mov    $0x0,%eax
  call   <back_sub@plt>
  mov    $0x0,%eax
  call   <print_result@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
data_type: string

tool: D6: 	Executing sequentially.


assistant: ```c
void sequential() {
  printf("\tExecuting sequentially.\n");
  guass_seq();
  print_data();
  back_sub();
  print_result();
}
```
user: What is the c source code of the assembly code below?

```asm
<sequential>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <guass_seq@plt>
  xor    %eax,%eax
  call   <print_data@plt>
  xor    %eax,%eax
  call   <back_sub@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <print_result@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: 	Executing sequentially.


assistant: ```c
void sequential() {
  printf("\tExecuting sequentially.\n");
  guass_seq();
  print_data();
  back_sub();
  print_result();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sequential>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <guass_seq@plt>
  xor    %eax,%eax
  call   <print_data@plt>
  xor    %eax,%eax
  call   <back_sub@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <print_result@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: 	Executing sequentially.


assistant: ```c
void sequential() {
  printf("\tExecuting sequentially.\n");
  guass_seq();
  print_data();
  back_sub();
  print_result();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fil__stresccpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L22
L21:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L5
  addq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x18(%rbp)
L5:
  cmpq   $0x0,-0x18(%rbp)
  je     L47
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L47
  subq   $0x1,-0x18(%rbp)
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L22:
  cmpq   $0x0,-0x18(%rbp)
  jne    L21
L47:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fil__stresccpy(char *dest, const char *src, size_t len) {
  while (len > 0) {
    if (*src == '\\') {
      src++;
      len--;
    }
    if (!(len > 0) || *src == 0)
      break;
    len--;
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fil__stresccpy>:
  endbr64
  test   %rdx,%rdx
  jne    L6
L39:
  movb   $0x0,(%rdi)
  ret
L36:
  test   %rdx,%rdx
  je     L39
  movzbl (%rsi),%eax
  test   %al,%al
  je     L39
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  sub    $0x1,%rdx
  je     L39
L6:
  cmpb   $0x5c,(%rsi)
  jne    L36
  add    $0x1,%rsi
  sub    $0x1,%rdx
  jmp    L36
```

assistant: ```c
void fil__stresccpy(char *dest, const char *src, size_t len) {
  while (len > 0) {
    if (*src == '\\') {
      src++;
      len--;
    }
    if (!(len > 0) || *src == 0)
      break;
    len--;
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<fil__stresccpy>:
  endbr64
  test   %rdx,%rdx
  jne    L13
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L21:
  test   %al,%al
  je     L23
L68:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %al,-0x1(%rdi)
  sub    $0x1,%rdx
  je     L23
L13:
  movzbl (%rsi),%eax
  cmp    $0x5c,%al
  jne    L21
  lea    0x1(%rsi),%rcx
  sub    $0x1,%rdx
  je     L23
  movzbl 0x1(%rsi),%eax
  mov    %rcx,%rsi
  test   %al,%al
  jne    L68
L23:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fil__stresccpy(char *dest, const char *src, size_t len) {
  while (len > 0) {
    if (*src == '\\') {
      src++;
      len--;
    }
    if (!(len > 0) || *src == 0)
      break;
    len--;
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fil__stresccpy>:
  endbr64
  test   %rdx,%rdx
  jne    L45
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L2:
  test   %al,%al
  je     L66
L40:
  add    $0x1,%rdi
  add    $0x1,%rsi
  mov    %al,-0x1(%rdi)
  sub    $0x1,%rdx
  je     L66
L45:
  movzbl (%rsi),%eax
  cmp    $0x5c,%al
  jne    L2
  lea    0x1(%rsi),%rcx
  sub    $0x1,%rdx
  je     L66
  movzbl 0x1(%rsi),%eax
  mov    %rcx,%rsi
  test   %al,%al
  jne    L40
L66:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void fil__stresccpy(char *dest, const char *src, size_t len) {
  while (len > 0) {
    if (*src == '\\') {
      src++;
      len--;
    }
    if (!(len > 0) || *src == 0)
      break;
    len--;
    *dest++ = *src++;
  }
  *dest = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<make_ao_ident>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x2,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L11
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L24:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   %edx,%eax
  imul   $0x147,%ax,%dx
  mov    -0xc(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0xc(%rbp)
L12:
  cmpl   $0x1f,-0xc(%rbp)
  jle    L24
L11:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
short *make_ao_ident(int ao_ident) {
  short *ids = calloc(32, sizeof(short));
  if (ao_ident) {
    int ic;
    for (ic = 0; ic < 32; ++ic) {
      ids[ic] = ic * (32768 / 100) * ao_ident;
    }
  }
  return ids;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<make_ao_ident>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%esi
  mov    $0x20,%edi
  call   <calloc@plt>
  test   %ebx,%ebx
  je     L5
  imul   $0x147,%bx,%si
  mov    %rax,%rdx
  lea    0x40(%rax),%rdi
  mov    $0x0,%ecx
L13:
  mov    %cx,(%rdx)
  add    %esi,%ecx
  add    $0x2,%rdx
  cmp    %rdi,%rdx
  jne    L13
L5:
  pop    %rbx
  ret
```

assistant: ```c
short *make_ao_ident(int ao_ident) {
  short *ids = calloc(32, sizeof(short));
  if (ao_ident) {
    int ic;
    for (ic = 0; ic < 32; ++ic) {
      ids[ic] = ic * (32768 / 100) * ao_ident;
    }
  }
  return ids;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<make_ao_ident>:
  endbr64
  push   %rbx
  mov    $0x2,%esi
  mov    %edi,%ebx
  mov    $0x20,%edi
  call   <calloc@plt>
  test   %ebx,%ebx
  je     L6
  imul   $0x147,%bx,%si
  mov    %rax,%rdx
  lea    0x40(%rax),%rdi
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %cx,(%rdx)
  add    $0x2,%rdx
  add    %esi,%ecx
  cmp    %rdi,%rdx
  jne    L16
L6:
  pop    %rbx
  ret
```

assistant: ```c
short *make_ao_ident(int ao_ident) {
  short *ids = calloc(32, sizeof(short));
  if (ao_ident) {
    int ic;
    for (ic = 0; ic < 32; ++ic) {
      ids[ic] = ic * (32768 / 100) * ao_ident;
    }
  }
  return ids;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<make_ao_ident>:
  endbr64
  push   %rbx
  mov    $0x2,%esi
  mov    %edi,%ebx
  mov    $0x20,%edi
  call   <calloc@plt>
  test   %ebx,%ebx
  je     L1
  movd   %ebx,%xmm0
  movdqa D39(%rip),%xmm1
  punpcklwd %xmm0,%xmm0
  pshufd $0x0,%xmm0,%xmm0
  pmullw %xmm0,%xmm1
  movups %xmm1,(%rax)
  movdqa D37(%rip),%xmm1
  pmullw %xmm0,%xmm1
  movups %xmm1,0x10(%rax)
  movdqa D34(%rip),%xmm1
  pmullw %xmm0,%xmm1
  pmullw D15(%rip),%xmm0
  movups %xmm0,0x30(%rax)
  movups %xmm1,0x20(%rax)
L1:
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D39
type_infered: byte[16]
name: disassemble_data
arguments: label: D37
type_infered: byte[16]
name: disassemble_data
arguments: label: D34
type_infered: byte[16]
name: disassemble_data
arguments: label: D15
type_infered: byte[16]

tool: {"D39": [0x00,0x00,0x47,0x01,0x8e,0x02,0xd5,0x03,0x1c,0x05,0x63,0x06,0xaa,0x07,0xf1,0x08]}

tool: {"D37": [0x38,0x0a,0x7f,0x0b,0xc6,0x0c,0x0d,0x0e,0x54,0x0f,0x9b,0x10,0xe2,0x11,0x29,0x13]}

tool: {"D34": [0x70,0x14,0xb7,0x15,0xfe,0x16,0x45,0x18,0x8c,0x19,0xd3,0x1a,0x1a,0x1c,0x61,0x1d]}

tool: {"D15": [0xa8,0x1e,0xef,0x1f,0x36,0x21,0x7d,0x22,0xc4,0x23,0x0b,0x25,0x52,0x26,0x99,0x27]}

assistant: ```c
short *make_ao_ident(int ao_ident) {
  short *ids = calloc(32, sizeof(short));
  if (ao_ident) {
    int ic;
    for (ic = 0; ic < 32; ++ic) {
      ids[ic] = ic * (32768 / 100) * ao_ident;
    }
  }
  return ids;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <get_sum@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    -0xc(%rbp),%esi
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D5: %d %d %d

tool: D13: %d+%d+%d = %d


assistant: ```c
int main() {
  int x, y, z, sum;
  scanf("%d %d %d", &x, &y, &z);
  sum = get_sum(x, y, z);
  printf("%d+%d+%d = %d\n", x, y, z, sum);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <get_sum@plt>
  mov    %eax,%r8d
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_infered: string
name: retrieve_data
arguments: data_label: D15
type_infered: string

tool: D11: %d %d %d

tool: D15: %d+%d+%d = %d


assistant: ```c
int main() {
  int x, y, z, sum;
  scanf("%d %d %d", &x, &y, &z);
  sum = get_sum(x, y, z);
  printf("%d+%d+%d = %d\n", x, y, z, sum);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <get_sum@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D19(%rip),%rdi
  mov    0xc(%rsp),%esi
  mov    %eax,%r8d
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D14
type: string
name: parse_data
arguments: label: D19
type: string

tool: D14: %d %d %d

tool: D19: %d+%d+%d = %d


assistant: ```c
int main() {
  int x, y, z, sum;
  scanf("%d %d %d", &x, &y, &z);
  sum = get_sum(x, y, z);
  printf("%d+%d+%d = %d\n", x, y, z, sum);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <get_sum@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D17(%rip),%rdi
  mov    0xc(%rsp),%esi
  mov    %eax,%r8d
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D10
type_infered: string
name: disassemble_data
arguments: tag: D17
type_infered: string

tool: D10: %d %d %d

tool: D17: %d+%d+%d = %d


assistant: ```c
int main() {
  int x, y, z, sum;
  scanf("%d %d %d", &x, &y, &z);
  sum = get_sum(x, y, z);
  printf("%d+%d+%d = %d\n", x, y, z, sum);
  return 0;
}
```