ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<recv_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L36
  mov    %edi,%ebp
  mov    %edx,%r12d
  mov    %rsi,%rbx
  xor    %r13d,%r13d
  jmp    L57
  nop
L43:
  test   %eax,%eax
  js     L51
  add    $0x1,%r13d
  add    $0x1,%rbx
  cmp    %r13d,%r12d
  jle    L1
  test   %eax,%eax
  je     L1
L57:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  cmpb   $0xa,(%rbx)
  jne    L43
L1:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L51:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  xor    %r13d,%r13d
  jmp    L1
```

assistant: ```c
int recv_data(int fd, char *buf, int nReadBytes) {
  int cnt = 0;
  int rv = -1;
  while (cnt < nReadBytes && rv) {
    rv = recv(fd, (char *)buf + cnt, 1, 0);
    if (buf[cnt] == '\n') {
      return cnt;
    }
    if (rv < 0) {
      return -1;
    }
    ++cnt;
  }
  return cnt;
}
```
user: Translate the below assembly code into C programming language:

```asm
<recv_data>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L55
  mov    %edi,%ebp
  mov    %edx,%r12d
  mov    %rsi,%rbx
  xor    %r13d,%r13d
  jmp    L29
  nop
L57:
  test   %eax,%eax
  js     L22
  add    $0x1,%r13d
  add    $0x1,%rbx
  cmp    %r13d,%r12d
  jle    L42
  test   %eax,%eax
  je     L42
L29:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <recv@plt>
  cmpb   $0xa,(%rbx)
  jne    L57
L42:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L22:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L55:
  xor    %r13d,%r13d
  jmp    L42
```

assistant: ```c
int recv_data(int fd, char *buf, int nReadBytes) {
  int cnt = 0;
  int rv = -1;
  while (cnt < nReadBytes && rv) {
    rv = recv(fd, (char *)buf + cnt, 1, 0);
    if (buf[cnt] == '\n') {
      return cnt;
    }
    if (rv < 0) {
      return -1;
    }
    ++cnt;
  }
  return cnt;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setvbuf@plt>
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D36(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setvbuf@plt>
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%ecx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setvbuf@plt>
  mov    $0x0,%eax
  call   <test002@plt>
  mov    D65(%rip),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  setvbuf(stdin, NULL, _IONBF, 0);
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
  test002();
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D41(%rip),%rbx
  mov    $0x0,%ecx
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <setvbuf@plt>
  mov    $0x0,%ecx
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    D23(%rip),%rax
  mov    (%rax),%edi
  call   <setvbuf@plt>
  mov    $0x0,%ecx
  mov    (%rbx),%edx
  mov    $0x0,%esi
  mov    D22(%rip),%rax
  mov    (%rax),%edi
  call   <setvbuf@plt>
  mov    $0x0,%eax
  call   <test002@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  setvbuf(stdin, NULL, _IONBF, 0);
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
  test002();
  return EXIT_SUCCESS;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    D47(%rip),%rax
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    D6(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%edx
  call   <setvbuf@plt>
  mov    D40(%rip),%rax
  mov    (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <setvbuf@plt>
  mov    D49(%rip),%rax
  mov    (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <setvbuf@plt>
  xor    %eax,%eax
  call   <test002@plt>
  mov    D36(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(void) {
  setvbuf(stdin, NULL, _IONBF, 0);
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
  test002();
  return EXIT_SUCCESS;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    D26(%rip),%rax
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    D10(%rip),%rbx
  mov    (%rax),%edi
  mov    (%rbx),%edx
  call   <setvbuf@plt>
  mov    D11(%rip),%rax
  mov    (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <setvbuf@plt>
  mov    D13(%rip),%rax
  mov    (%rbx),%edx
  xor    %ecx,%ecx
  xor    %esi,%esi
  mov    (%rax),%edi
  call   <setvbuf@plt>
  xor    %eax,%eax
  call   <test002@plt>
  mov    D5(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main(void) {
  setvbuf(stdin, NULL, _IONBF, 0);
  setvbuf(stdout, NULL, _IONBF, 0);
  setvbuf(stderr, NULL, _IONBF, 0);
  test002();
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<imprimir_dados>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x514a3139,-0xe(%rbp)
  movw   $0x414b,-0xa(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  mov    %al,-0x13(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  mov    %al,-0x12(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  mov    %al,-0x11(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  mov    %al,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  mov    %al,-0xf(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movsbl -0xf(%rbp),%edi
  movsbl -0x10(%rbp),%esi
  movsbl -0x11(%rbp),%ecx
  movsbl -0x12(%rbp),%edx
  movsbl -0x13(%rbp),%eax
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string
name: unpack_data
arguments: data_tag: D26
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string

tool: D6: ----- ----- ----- ----- -----

tool: D26: | %c | | %c | | %c | | %c | | %c |


tool: D27:   0     1     2     3     4

assistant: ```c
void imprimir_dados(int *dados) {
  char opciones[6] = {'9', '1', 'J', 'Q', 'K', 'A'};
  char d1, d2, d3, d4, d5;
  d1 = opciones[dados[0]];
  d2 = opciones[dados[1]];
  d3 = opciones[dados[2]];
  d4 = opciones[dados[3]];
  d5 = opciones[dados[4]];
  printf("----- ----- ----- ----- -----\n");
  printf("| %c | | %c | | %c | | %c | | %c |\n", d1, d2, d3, d4, d5);
  printf("----- ----- ----- ----- -----\n");
  printf("  0     1     2     3     4\n");
  printf("\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<imprimir_dados>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x514a3139,0x2(%rsp)
  movw   $0x414b,0x6(%rsp)
  movslq (%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%ebx
  movslq 0x4(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%ebp
  movslq 0x8(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r12d
  movslq 0xc(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r14d
  movslq 0x10(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r15d
  lea    D23(%rip),%r13
  mov    %r13,%rdi
  call   <puts@plt>
  movsbl %r12b,%ecx
  movsbl %bpl,%edx
  movsbl %bl,%esi
  movsbl %r15b,%r9d
  movsbl %r14b,%r8d
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D23
data_type: string
name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D16
data_type: string

tool: D23: ----- ----- ----- ----- -----

tool: D6: | %c | | %c | | %c | | %c | | %c |


tool: D16:   0     1     2     3     4

assistant: ```c
void imprimir_dados(int *dados) {
  char opciones[6] = {'9', '1', 'J', 'Q', 'K', 'A'};
  char d1, d2, d3, d4, d5;
  d1 = opciones[dados[0]];
  d2 = opciones[dados[1]];
  d3 = opciones[dados[2]];
  d4 = opciones[dados[3]];
  d5 = opciones[dados[4]];
  printf("----- ----- ----- ----- -----\n");
  printf("| %c | | %c | | %c | | %c | | %c |\n", d1, d2, d3, d4, d5);
  printf("----- ----- ----- ----- -----\n");
  printf("  0     1     2     3     4\n");
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<imprimir_dados>:
  endbr64
  push   %r15
  lea    D15(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x414b,%eax
  movl   $0x514a3139,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  movslq (%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%ebx
  movslq 0x4(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%ebp
  movslq 0x8(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r14d
  movslq 0xc(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r12d
  movslq 0x10(%rdi),%rax
  mov    %r15,%rdi
  movzbl 0x2(%rsp,%rax,1),%r13d
  call   <puts@plt>
  movsbl %r14b,%ecx
  movsbl %bpl,%edx
  movsbl %bl,%esi
  movsbl %r13b,%r9d
  movsbl %r12b,%r8d
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type: string
name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string

tool: D15: ----- ----- ----- ----- -----

tool: D18: | %c | | %c | | %c | | %c | | %c |


tool: D0:   0     1     2     3     4

assistant: ```c
void imprimir_dados(int *dados) {
  char opciones[6] = {'9', '1', 'J', 'Q', 'K', 'A'};
  char d1, d2, d3, d4, d5;
  d1 = opciones[dados[0]];
  d2 = opciones[dados[1]];
  d3 = opciones[dados[2]];
  d4 = opciones[dados[3]];
  d5 = opciones[dados[4]];
  printf("----- ----- ----- ----- -----\n");
  printf("| %c | | %c | | %c | | %c | | %c |\n", d1, d2, d3, d4, d5);
  printf("----- ----- ----- ----- -----\n");
  printf("  0     1     2     3     4\n");
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imprimir_dados>:
  endbr64
  push   %r15
  lea    D3(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x414b,%eax
  movl   $0x514a3139,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  movslq (%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%ebx
  movslq 0x4(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%ebp
  movslq 0x8(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r14d
  movslq 0xc(%rdi),%rax
  movzbl 0x2(%rsp,%rax,1),%r12d
  movslq 0x10(%rdi),%rax
  mov    %r15,%rdi
  movzbl 0x2(%rsp,%rax,1),%r13d
  call   <puts@plt>
  movsbl %r14b,%ecx
  movsbl %bpl,%edx
  movsbl %bl,%esi
  movsbl %r13b,%r9d
  movsbl %r12b,%r8d
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r15,%rdi
  call   <puts@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <putchar@plt>
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D21
datatype: string

tool: D3: ----- ----- ----- ----- -----

tool: D9: | %c | | %c | | %c | | %c | | %c |


tool: D21:   0     1     2     3     4

assistant: ```c
void imprimir_dados(int *dados) {
  char opciones[6] = {'9', '1', 'J', 'Q', 'K', 'A'};
  char d1, d2, d3, d4, d5;
  d1 = opciones[dados[0]];
  d2 = opciones[dados[1]];
  d3 = opciones[dados[2]];
  d4 = opciones[dados[3]];
  d5 = opciones[dados[4]];
  printf("----- ----- ----- ----- -----\n");
  printf("| %c | | %c | | %c | | %c | | %c |\n", d1, d2, d3, d4, d5);
  printf("----- ----- ----- ----- -----\n");
  printf("  0     1     2     3     4\n");
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D2(%rip),%rax
  mov    %rax,-0x8(%rbp)
L5:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *itoa(unsigned i) {
  static char a[3 * sizeof(int)];
  char *p = a + sizeof(a) - 1;
  do {
    *--p = '0' + i % 10;
  } while ((i /= 10) > 0);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<itoa>:
  endbr64
  lea    D4(%rip),%rsi
  mov    $0xcccccccd,%r8d
L7:
  sub    $0x1,%rsi
  mov    %edi,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edi,%edx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%rsi)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  ja     L7
  mov    %rsi,%rax
  ret
```

assistant: ```c
char *itoa(unsigned i) {
  static char a[3 * sizeof(int)];
  char *p = a + sizeof(a) - 1;
  do {
    *--p = '0' + i % 10;
  } while ((i /= 10) > 0);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<itoa>:
  endbr64
  lea    D8(%rip),%r8
  mov    $0xcccccccd,%esi
L0:
  mov    %edi,%eax
  mov    %edi,%edx
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  ja     L0
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(unsigned i) {
  static char a[3 * sizeof(int)];
  char *p = a + sizeof(a) - 1;
  do {
    *--p = '0' + i % 10;
  } while ((i /= 10) > 0);
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<itoa>:
  endbr64
  lea    D4(%rip),%r8
  mov    $0xcccccccd,%esi
L3:
  mov    %edi,%eax
  mov    %edi,%edx
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %edi,%edx
  mov    %eax,%edi
  cmp    $0x9,%edx
  ja     L3
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(unsigned i) {
  static char a[3 * sizeof(int)];
  char *p = a + sizeof(a) - 1;
  do {
    *--p = '0' + i % 10;
  } while ((i /= 10) > 0);
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<precentile_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  D7(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L47
L29:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  movsd  -0x28(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jb     L6
  addl   $0x1,-0xc(%rbp)
  jmp    L3
L6:
  mov    -0xc(%rbp),%eax
  jmp    L28
L3:
  addl   $0x1,-0x10(%rbp)
L47:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L29
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
L28:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: f64

tool: D7: 1

assistant: ```c
int precentile_index(double *array, int size, double target_percentile) {
  double percentage_each = 1.0 / size;
  int i;
  int count = 0;
  for (i = 1; i <= size; i++) {
    if (i * percentage_each <= target_percentile) {
      count++;
    } else {
      return count;
    }
  }
  return size - 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<precentile_index>:
  endbr64
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movsd  D9(%rip),%xmm2
  divsd  %xmm1,%xmm2
  test   %esi,%esi
  jle    L35
  mov    $0x1,%eax
  mov    $0x0,%edx
  comisd %xmm2,%xmm0
  jb     L6
L42:
  mov    %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jl     L35
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jae    L42
  jmp    L6
L35:
  lea    -0x1(%rsi),%edx
L6:
  mov    %edx,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: f64

tool: D9: 1

assistant: ```c
int precentile_index(double *array, int size, double target_percentile) {
  double percentage_each = 1.0 / size;
  int i;
  int count = 0;
  for (i = 1; i <= size; i++) {
    if (i * percentage_each <= target_percentile) {
      count++;
    } else {
      return count;
    }
  }
  return size - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<precentile_index>:
  endbr64
  pxor   %xmm1,%xmm1
  movsd  D7(%rip),%xmm2
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm2
  test   %esi,%esi
  jle    L30
  xor    %r8d,%r8d
  comisd %xmm2,%xmm0
  mov    $0x1,%eax
  jae    L48
  jmp    L10
  nopl   0x0(%rax)
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jb     L10
L48:
  mov    %eax,%r8d
  add    $0x1,%eax
  cmp    %eax,%esi
  jge    L15
L30:
  lea    -0x1(%rsi),%r8d
L10:
  mov    %r8d,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: f64

tool: D7: 1

assistant: ```c
int precentile_index(double *array, int size, double target_percentile) {
  double percentage_each = 1.0 / size;
  int i;
  int count = 0;
  for (i = 1; i <= size; i++) {
    if (i * percentage_each <= target_percentile) {
      count++;
    } else {
      return count;
    }
  }
  return size - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<precentile_index>:
  endbr64
  pxor   %xmm1,%xmm1
  movsd  D6(%rip),%xmm2
  cvtsi2sd %esi,%xmm1
  divsd  %xmm1,%xmm2
  test   %esi,%esi
  jle    L33
  xor    %r8d,%r8d
  comisd %xmm2,%xmm0
  mov    $0x1,%eax
  jae    L23
  jmp    L49
  nopl   0x0(%rax)
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  mulsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jb     L49
L23:
  mov    %eax,%r8d
  add    $0x1,%eax
  cmp    %eax,%esi
  jge    L15
L33:
  lea    -0x1(%rsi),%r8d
L49:
  mov    %r8d,%eax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: f64

tool: D6: 1

assistant: ```c
int precentile_index(double *array, int size, double target_percentile) {
  double percentage_each = 1.0 / size;
  int i;
  int count = 0;
  for (i = 1; i <= size; i++) {
    if (i * percentage_each <= target_percentile) {
      count++;
    } else {
      return count;
    }
  }
  return size - 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<htoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L50
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L108
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L50
L108:
  movl   $0x2,-0x8(%rbp)
  jmp    L101
L50:
  movl   $0x0,-0x8(%rbp)
L101:
  movl   $0x0,-0x4(%rbp)
L71:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L76
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L93
L76:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L5
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x66,%al
  jg     L5
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x57,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L93
L5:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L13
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x46,%al
  jg     L13
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x37,%eax
  add    %ecx,%eax
  mov    %eax,-0x4(%rbp)
L93:
  addl   $0x1,-0x8(%rbp)
  jmp    L71
L13:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int htoi(char s[]) {
  int i, n;
  if (s[0] == '0' && (s[1] == 'x' || s[1] == 'X'))
    i = 2;
  else
    i = 0;
  n = 0;
  while (1) {
    if (isdigit(s[i]))
      n = n * 16 + (s[i] - '0');
    else if (s[i] >= 'a' && s[i] <= 'f')
      n = n * 16 + (s[i] - 'a' + 10);
    else if (s[i] >= 'A' && s[i] <= 'F')
      n = n * 16 + (s[i] - 'A' + 10);
    else
      break;
    i++;
  }
  return n;
}
```