ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <aMethod@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  aMethod();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<slctc_double_tab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L0
L19:
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L25:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x38(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  addl   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L19
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void slctc_double_tab(double **tab1, int x1, int y1, double **tab2, int y2, int *vec) {
  int i, j;
  for (i = 0; i < y2; i++) {
    for (j = 0; j < x1; j++) {
      tab2[j][i] = tab1[j][vec[i]];
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<slctc_double_tab>:
  endbr64
  test   %r8d,%r8d
  jle    L28
  push   %rbx
  mov    %rdi,%r10
  mov    %esi,%ebx
  mov    %rcx,%r11
  mov    %r9,%rsi
  lea    -0x1(%r8),%eax
  lea    0x4(%r9,%rax,4),%r9
  mov    $0x0,%edi
  mov    %ebx,%r8d
  jmp    L14
L8:
  movslq (%rsi),%rcx
  mov    (%r10,%rax,8),%rdx
  movsd  (%rdx,%rcx,8),%xmm0
  mov    (%r11,%rax,8),%rdx
  movsd  %xmm0,(%rdx,%rdi,1)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L8
L48:
  add    $0x4,%rsi
  add    $0x8,%rdi
  cmp    %r9,%rsi
  je     L2
L14:
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L8
  jmp    L48
L2:
  pop    %rbx
  ret
L28:
  ret
```

assistant: ```c
void slctc_double_tab(double **tab1, int x1, int y1, double **tab2, int y2, int *vec) {
  int i, j;
  for (i = 0; i < y2; i++) {
    for (j = 0; j < x1; j++) {
      tab2[j][i] = tab1[j][vec[i]];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<slctc_double_tab>:
  endbr64
  test   %r8d,%r8d
  jle    L0
  push   %rbp
  mov    %rcx,%r10
  movslq %r8d,%rbp
  xor    %r11d,%r11d
  push   %rbx
  movslq %esi,%r8
  mov    %esi,%ebx
  nopl   0x0(%rax)
L24:
  test   %ebx,%ebx
  jle    L33
  movslq (%r9,%r11,4),%rcx
  lea    0x0(,%r11,8),%rsi
  xor    %eax,%eax
  shl    $0x3,%rcx
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    (%rdi,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mov    (%r10,%rax,8),%rdx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%rsi,1)
  cmp    %rax,%r8
  jne    L7
L33:
  add    $0x1,%r11
  cmp    %r11,%rbp
  jne    L24
  pop    %rbx
  pop    %rbp
  ret
L0:
  ret
```

assistant: ```c
void slctc_double_tab(double **tab1, int x1, int y1, double **tab2, int y2, int *vec) {
  int i, j;
  for (i = 0; i < y2; i++) {
    for (j = 0; j < x1; j++) {
      tab2[j][i] = tab1[j][vec[i]];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<slctc_double_tab>:
  endbr64
  test   %r8d,%r8d
  jle    L39
  test   %esi,%esi
  jle    L39
  push   %rbx
  mov    %rdi,%r10
  movslq %r8d,%rbx
  mov    %rcx,%r11
  xor    %r8d,%r8d
  movslq %esi,%rdi
  nopl   (%rax)
L1:
  movslq (%r9,%r8,4),%rcx
  lea    0x0(,%r8,8),%rsi
  xor    %eax,%eax
  shl    $0x3,%rcx
  nopw   0x0(%rax,%rax,1)
L8:
  mov    (%r10,%rax,8),%rdx
  movsd  (%rdx,%rcx,1),%xmm0
  mov    (%r11,%rax,8),%rdx
  add    $0x1,%rax
  movsd  %xmm0,(%rdx,%rsi,1)
  cmp    %rdi,%rax
  jne    L8
  add    $0x1,%r8
  cmp    %r8,%rbx
  jne    L1
  pop    %rbx
  ret
L39:
  ret
```

assistant: ```c
void slctc_double_tab(double **tab1, int x1, int y1, double **tab2, int y2, int *vec) {
  int i, j;
  for (i = 0; i < y2; i++) {
    for (j = 0; j < x1; j++) {
      tab2[j][i] = tab1[j][vec[i]];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ComputeCRC>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xffff,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L11
L4:
  mov    -0x10(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  shll   $0x8,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  sar    $0x4,%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x10(%rbp)
  shll   $0x5,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x10(%rbp)
  shll   $0x7,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L11:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L4
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t ComputeCRC(unsigned char *msg, unsigned int msglen) {
  uint16_t crc = 0xFFFF;
  uint16_t temp, quick;
  unsigned int i;
  for (i = 0; i < msglen; i++) {
    temp = (crc >> 8) ^ msg[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ComputeCRC>:
  endbr64
  test   %esi,%esi
  je     L14
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffff,%eax
L1:
  mov    %eax,%ecx
  sar    $0x8,%ecx
  movzbl (%r8),%edx
  xor    %edx,%ecx
  shl    $0x8,%eax
  mov    %ecx,%edx
  sar    $0x4,%edx
  xor    %ecx,%edx
  xor    %edx,%eax
  mov    %edx,%ecx
  shl    $0x5,%ecx
  xor    %ecx,%eax
  shl    $0xc,%edx
  xor    %edx,%eax
  add    $0x1,%r8
  cmp    %rsi,%r8
  jne    L1
  ret
L14:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
uint16_t ComputeCRC(unsigned char *msg, unsigned int msglen) {
  uint16_t crc = 0xFFFF;
  uint16_t temp, quick;
  unsigned int i;
  for (i = 0; i < msglen; i++) {
    temp = (crc >> 8) ^ msg[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ComputeCRC>:
  endbr64
  test   %esi,%esi
  je     L19
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffff,%eax
  nopl   (%rax)
L14:
  movzbl (%rdi),%edx
  mov    %eax,%ecx
  shl    $0x8,%eax
  add    $0x1,%rdi
  sar    $0x8,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x4,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  xor    %edx,%eax
  shl    $0xc,%edx
  shl    $0x5,%ecx
  xor    %ecx,%eax
  xor    %edx,%eax
  cmp    %rdi,%rsi
  jne    L14
  ret
  nopl   0x0(%rax)
L19:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
uint16_t ComputeCRC(unsigned char *msg, unsigned int msglen) {
  uint16_t crc = 0xFFFF;
  uint16_t temp, quick;
  unsigned int i;
  for (i = 0; i < msglen; i++) {
    temp = (crc >> 8) ^ msg[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ComputeCRC>:
  endbr64
  test   %esi,%esi
  je     L17
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  mov    $0xffff,%eax
  nopl   (%rax)
L13:
  movzbl (%rdi),%edx
  mov    %eax,%ecx
  shl    $0x8,%eax
  add    $0x1,%rdi
  sar    $0x8,%ecx
  xor    %edx,%ecx
  mov    %ecx,%edx
  sar    $0x4,%edx
  xor    %ecx,%edx
  mov    %edx,%ecx
  xor    %edx,%eax
  shl    $0xc,%edx
  shl    $0x5,%ecx
  xor    %ecx,%eax
  xor    %edx,%eax
  cmp    %rdi,%rsi
  jne    L13
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffff,%eax
  ret
```

assistant: ```c
uint16_t ComputeCRC(unsigned char *msg, unsigned int msglen) {
  uint16_t crc = 0xFFFF;
  uint16_t temp, quick;
  unsigned int i;
  for (i = 0; i < msglen; i++) {
    temp = (crc >> 8) ^ msg[i];
    crc <<= 8;
    quick = temp ^ (temp >> 4);
    crc ^= quick;
    quick <<= 5;
    crc ^= quick;
    quick <<= 7;
    crc ^= quick;
  }
  return crc;
}
```
user: What is the c source code of the assembly code below:

```asm
<backup_query>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <rate@plt>
  movsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <rate@plt>
  movsd  D38(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  addsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D31
datatype: string
name: disassemble_data
arguments: data_label: D9
datatype: f64
name: disassemble_data
arguments: data_label: D38
datatype: f64
name: disassemble_data
arguments: data_label: D34
datatype: string

tool: D31: %lld

tool: D9: 0.9

tool: D38: 0.1

tool: D34: %d


assistant: ```c
void backup_query() {
  long long t;
  scanf("%lld", &t);
  printf("%d\n", (int)(rate(t, 0) * 0.9 + rate(t + 1, 0) * 0.1));
}
```
user: What is the c source code of the assembly code below:

```asm
<backup_query>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%esi
  mov    (%rsp),%rdi
  call   <rate@plt>
  movq   %xmm0,%rbx
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdi
  mov    $0x0,%esi
  call   <rate@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  mulsd  D11(%rip),%xmm0
  mulsd  D1(%rip),%xmm1
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: f64
name: retrieve_data
arguments: tag: D1
datatype: f64
name: retrieve_data
arguments: tag: D16
datatype: string

tool: D4: %lld

tool: D11: 0.9

tool: D1: 0.1

tool: D16: %d


assistant: ```c
void backup_query() {
  long long t;
  scanf("%lld", &t);
  printf("%d\n", (int)(rate(t, 0) * 0.9 + rate(t + 1, 0) * 0.1));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<backup_query>:
  endbr64
  sub    $0x28,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  xor    %esi,%esi
  call   <rate@plt>
  mov    0x10(%rsp),%rax
  xor    %esi,%esi
  movsd  %xmm0,0x8(%rsp)
  lea    0x1(%rax),%rdi
  call   <rate@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D6(%rip),%xmm0
  lea    D12(%rip),%rdi
  mulsd  D17(%rip),%xmm1
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D39
type_guessed: string
name: unpack_data
arguments: data_tag: D6
type_guessed: f64
name: unpack_data
arguments: data_tag: D12
type_guessed: string
name: unpack_data
arguments: data_tag: D17
type_guessed: f64

tool: D39: %lld

tool: D6: 0.1

tool: D12: %d


tool: D17: 0.9

assistant: ```c
void backup_query() {
  long long t;
  scanf("%lld", &t);
  printf("%d\n", (int)(rate(t, 0) * 0.9 + rate(t + 1, 0) * 0.1));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<backup_query>:
  endbr64
  sub    $0x28,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  xor    %esi,%esi
  call   <rate@plt>
  mov    0x10(%rsp),%rax
  xor    %esi,%esi
  movsd  %xmm0,0x8(%rsp)
  lea    0x1(%rax),%rdi
  call   <rate@plt>
  movsd  0x8(%rsp),%xmm1
  mulsd  D0(%rip),%xmm0
  lea    D18(%rip),%rdi
  mulsd  D38(%rip),%xmm1
  addsd  %xmm0,%xmm1
  cvttsd2si %xmm1,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D27
type: string
name: read_data
arguments: tag: D0
type: f64
name: read_data
arguments: tag: D18
type: string
name: read_data
arguments: tag: D38
type: f64

tool: D27: %lld

tool: D0: 0.1

tool: D18: %d


tool: D38: 0.9

assistant: ```c
void backup_query() {
  long long t;
  scanf("%lld", &t);
  printf("%d\n", (int)(rate(t, 0) * 0.9 + rate(t + 1, 0) * 0.1));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x100,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D48(%rip),%xmm0
  movsd  %xmm0,-0x100(%rbp)
  movsd  D42(%rip),%xmm0
  movsd  %xmm0,-0xf8(%rbp)
  movsd  D45(%rip),%xmm0
  movsd  %xmm0,-0xf0(%rbp)
  movsd  D17(%rip),%xmm0
  movsd  %xmm0,-0xe8(%rbp)
  movsd  D31(%rip),%xmm0
  movsd  %xmm0,-0xe0(%rbp)
  movsd  D73(%rip),%xmm0
  movsd  %xmm0,-0xd8(%rbp)
  movsd  D29(%rip),%xmm0
  movsd  %xmm0,-0xd0(%rbp)
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0xc8(%rbp)
  movsd  D27(%rip),%xmm0
  movsd  %xmm0,-0xc0(%rbp)
  movsd  D48(%rip),%xmm0
  movsd  %xmm0,-0xb8(%rbp)
  lea    -0xb0(%rbp),%rcx
  lea    -0x100(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy_arr@plt>
  lea    -0xb0(%rbp),%rax
  lea    0x28(%rax),%rcx
  lea    -0x100(%rbp),%rax
  add    $0x28,%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy_arr@plt>
  lea    -0x60(%rbp),%rcx
  lea    -0x100(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy_ptr@plt>
  lea    -0x60(%rbp),%rcx
  add    $0x28,%rcx
  lea    -0x100(%rbp),%rax
  add    $0x28,%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy_ptr@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D48
type: f64
name: retrieve_data
arguments: data_tag: D42
type: f64
name: retrieve_data
arguments: data_tag: D45
type: f64
name: retrieve_data
arguments: data_tag: D17
type: f64
name: retrieve_data
arguments: data_tag: D31
type: f64
name: retrieve_data
arguments: data_tag: D73
type: f64
name: retrieve_data
arguments: data_tag: D29
type: f64
name: retrieve_data
arguments: data_tag: D2
type: f64
name: retrieve_data
arguments: data_tag: D27
type: f64

tool: D48: 1.1

tool: D42: 2.2

tool: D45: 3.3

tool: D17: 4.4

tool: D31: 5.5

tool: D73: 6.6

tool: D29: 7.7

tool: D2: 8.8

tool: D27: 9.9

assistant: ```c
int main(void) {
  double source[2][5] = {{1.1, 2.2, 3.3, 4.4, 5.5}, {6.6, 7.7, 8.8, 9.9, 1.1}};
  double target1[2][5], target2[2][5];
  copy_arr(source[0], target1[0], 5);
  copy_arr(source[1], target1[1], 5);
  copy_ptr(*source, *target2, 5);
  copy_ptr(*(source + 1), *(target2 + 1), 5);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x108,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  movsd  D44(%rip),%xmm0
  movsd  %xmm0,(%rsp)
  mov    D63(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D11(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D58(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D62(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D23(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D54(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D39(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D69(%rip),%rax
  mov    %rax,0x40(%rsp)
  movsd  %xmm0,0x48(%rsp)
  lea    0x50(%rsp),%rsi
  mov    %rsp,%rbp
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <copy_arr@plt>
  lea    0x78(%rsp),%rsi
  lea    0x28(%rsp),%rbx
  mov    $0x5,%edx
  mov    %rbx,%rdi
  call   <copy_arr@plt>
  lea    0xa0(%rsp),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <copy_ptr@plt>
  lea    0xc8(%rsp),%rsi
  mov    $0x5,%edx
  mov    %rbx,%rdi
  call   <copy_ptr@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x108,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D44
type: f64
name: disassemble_data
arguments: data_label: D63
type: f64
name: disassemble_data
arguments: data_label: D11
type: f64
name: disassemble_data
arguments: data_label: D58
type: f64
name: disassemble_data
arguments: data_label: D62
type: f64
name: disassemble_data
arguments: data_label: D23
type: f64
name: disassemble_data
arguments: data_label: D54
type: f64
name: disassemble_data
arguments: data_label: D39
type: f64
name: disassemble_data
arguments: data_label: D69
type: f64

tool: D44: 1.1

tool: D63: 2.2

tool: D11: 3.3

tool: D58: 4.4

tool: D62: 5.5

tool: D23: 6.6

tool: D54: 7.7

tool: D39: 8.8

tool: D69: 9.9

assistant: ```c
int main(void) {
  double source[2][5] = {{1.1, 2.2, 3.3, 4.4, 5.5}, {6.6, 7.7, 8.8, 9.9, 1.1}};
  double target1[2][5], target2[2][5];
  copy_arr(source[0], target1[0], 5);
  copy_arr(source[1], target1[1], 5);
  copy_ptr(*source, *target2, 5);
  copy_ptr(*(source + 1), *(target2 + 1), 5);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  push   %rbp
  sub    $0x108,%rsp
  movsd  D15(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rsi
  lea    0x28(%rsp),%rbp
  mov    D2(%rip),%rax
  mov    %r12,%rdi
  movsd  %xmm0,(%rsp)
  movsd  %xmm0,0x48(%rsp)
  mov    %rax,0x8(%rsp)
  mov    D60(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D52(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D69(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D32(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D9(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D0(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D24(%rip),%rax
  mov    %rax,0x40(%rsp)
  call   <copy_arr@plt>
  lea    0x78(%rsp),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <copy_arr@plt>
  lea    0xa0(%rsp),%rsi
  mov    $0x5,%edx
  mov    %r12,%rdi
  call   <copy_ptr@plt>
  lea    0xc8(%rsp),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <copy_ptr@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D60
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D52
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D69
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D32
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: f64
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: f64

tool: D15: 1.1

tool: D2: 2.2

tool: D60: 3.3

tool: D52: 4.4

tool: D69: 5.5

tool: D32: 6.6

tool: D9: 7.7

tool: D0: 8.8

tool: D24: 9.9

assistant: ```c
int main(void) {
  double source[2][5] = {{1.1, 2.2, 3.3, 4.4, 5.5}, {6.6, 7.7, 8.8, 9.9, 1.1}};
  double target1[2][5], target2[2][5];
  copy_arr(source[0], target1[0], 5);
  copy_arr(source[1], target1[1], 5);
  copy_ptr(*source, *target2, 5);
  copy_ptr(*(source + 1), *(target2 + 1), 5);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  push   %rbp
  sub    $0x108,%rsp
  movapd D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xf8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x50(%rsp),%rsi
  lea    0x28(%rsp),%rbp
  movaps %xmm0,(%rsp)
  movapd D47(%rip),%xmm0
  mov    %r12,%rdi
  movaps %xmm0,0x10(%rsp)
  movapd D34(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movapd D40(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movapd D18(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  call   <copy_arr@plt>
  lea    0x78(%rsp),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <copy_arr@plt>
  lea    0xa0(%rsp),%rsi
  mov    $0x5,%edx
  mov    %r12,%rdi
  call   <copy_ptr@plt>
  lea    0xc8(%rsp),%rsi
  mov    $0x5,%edx
  mov    %rbp,%rdi
  call   <copy_ptr@plt>
  mov    0xf8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x108,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
datatype: f64[2]
name: parse_data
arguments: data_tag: D47
datatype: f64[2]
name: parse_data
arguments: data_tag: D34
datatype: f64[2]
name: parse_data
arguments: data_tag: D40
datatype: f64[2]
name: parse_data
arguments: data_tag: D18
datatype: f64[2]

tool: {"D17": [1.1,2.2]}

tool: {"D47": [3.3,4.4]}

tool: {"D34": [5.5,6.6]}

tool: {"D40": [7.7,8.8]}

tool: {"D18": [9.9,1.1]}

assistant: ```c
int main(void) {
  double source[2][5] = {{1.1, 2.2, 3.3, 4.4, 5.5}, {6.6, 7.7, 8.8, 9.9, 1.1}};
  double target1[2][5], target2[2][5];
  copy_arr(source[0], target1[0], 5);
  copy_arr(source[1], target1[1], 5);
  copy_ptr(*source, *target2, 5);
  copy_ptr(*(source + 1), *(target2 + 1), 5);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WriteEscaped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L29
L28:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L10
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x5c,%edi
  call   <fputc@plt>
L10:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fputc@plt>
  addq   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L28
  nop
  nop
  leave
  ret
```

assistant: ```c
void WriteEscaped(FILE *F, const char *Name) {
  while (*Name) {
    if (*Name == ' ') {
      fputc('\\', F);
    }
    fputc(*Name, F);
    ++Name;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<WriteEscaped>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L38
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L33:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  call   <fputc@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L37
L38:
  cmp    $0x20,%al
  jne    L33
  mov    %rbp,%rsi
  mov    $0x5c,%edi
  call   <fputc@plt>
  jmp    L33
```

assistant: ```c
void WriteEscaped(FILE *F, const char *Name) {
  while (*Name) {
    if (*Name == ' ') {
      fputc('\\', F);
    }
    fputc(*Name, F);
    ++Name;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WriteEscaped>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L16
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  jmp    L33
  nopl   0x0(%rax)
L26:
  movsbl (%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <fputc@plt>
  movzbl (%rbx),%eax
  test   %al,%al
  je     L31
L33:
  cmp    $0x20,%al
  jne    L26
  mov    %rbp,%rsi
  mov    $0x5c,%edi
  call   <fputc@plt>
  jmp    L26
  nopl   0x0(%rax)
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void WriteEscaped(FILE *F, const char *Name) {
  while (*Name) {
    if (*Name == ' ') {
      fputc('\\', F);
    }
    fputc(*Name, F);
    ++Name;
  }
}
```