ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  je     L40
  js     L63
  nopw   0x0(%rax,%rax,1)
L1:
  imul   $0x3c,%esi,%esi
  mov    %r15,%rdi
  add    %eax,%esi
  call   <printf@plt>
L69:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%r8
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x10(%rsp),%eax
  mov    %ecx,%esi
  or     %edx,%esi
  or     %eax,%esi
  je     L8
  sub    %ecx,%eax
  mov    %eax,%esi
  mov    0x14(%rsp),%eax
  sub    %edx,%eax
  js     L63
L33:
  lea    0x18(%rsi),%edx
  test   %esi,%esi
  cmovs  %edx,%esi
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L63:
  add    $0x3c,%eax
  sub    $0x1,%esi
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L40:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D10: %d


tool: D4: %d %d %d %d

assistant: ```c
int main(void) {
  int horaInicial, minutoInicial, horaFinal, minutoFinal, dtHora, dtMinuto;
  while (scanf("%d %d %d %d", &horaInicial, &minutoInicial, &horaFinal, &minutoFinal), horaInicial != 0 || minutoInicial != 0 || horaFinal != 0 || minutoFinal != 0) {
    dtHora = horaFinal - horaInicial;
    dtMinuto = minutoFinal - minutoInicial;
    if (dtMinuto < 0) {
      dtMinuto = 60 + dtMinuto;
      dtHora -= 1;
    }
    if (dtHora < 0) {
      dtHora = 24 + dtHora;
    }
    printf("%d\n", dtHora * 60 + dtMinuto);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L26
  lea    0x5(%rsp),%r12
  lea    D4(%rip),%rbp
  lea    D15(%rip),%rbx
  jmp    L46
L79:
  cmp    $0x7,%r8d
  setbe  %r8b
  lea    -0x2f(%rax),%r9d
  cmp    $0x7,%r9b
  ja     L87
  cmp    $0x1,%r8b
  sbb    $0xffffffff,%esi
L87:
  lea    -0x5f(%rdx),%r9d
  cmp    $0x7,%r9d
  ja     L54
  cmp    $0x8,%ecx
  adc    $0x0,%esi
  movsbl %al,%r9d
  sub    $0x32,%r9d
  cmp    $0x8,%r9d
  adc    $0x0,%esi
L54:
  cmp    $0x7,%edi
  ja     L38
  movsbl %al,%edi
  sub    $0x33,%edi
  cmp    $0x8,%edi
  adc    $0x0,%esi
L38:
  lea    -0x33(%rax),%edi
  cmp    $0x7,%dil
  ja     L82
  cmp    $0x1,%r8b
  sbb    $0xffffffff,%esi
L82:
  sub    $0x63,%edx
  cmp    $0x7,%edx
  ja     L1
  cmp    $0x8,%ecx
  adc    $0x0,%esi
  movsbl %al,%eax
  sub    $0x32,%eax
  cmp    $0x8,%eax
  adc    $0x0,%esi
L1:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L26
L46:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0x6(%rsp),%eax
  movsbl %al,%ecx
  sub    $0x30,%ecx
  movsbl 0x5(%rsp),%edx
  lea    -0x60(%rdx),%r8d
  lea    -0x62(%rdx),%edi
  mov    $0x0,%esi
  cmp    $0x7,%edi
  ja     L79
  movsbl %al,%esi
  sub    $0x2f,%esi
  cmp    $0x7,%esi
  setbe  %sil
  movzbl %sil,%esi
  jmp    L79
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D15
type_infered: string

tool: D8: %d

tool: D4: %s

tool: D15: %d


assistant: ```c
int main() {
  int i, j;
  char a[3];
  int n;
  scanf("%d", &n);
  while (n--) {
    scanf("%s", a);
    i = a[0] - 'a' + 1;
    j = a[1] - '0';
    int cnt = 0;
    if (i - 1 >= 1 && i - 1 <= 8 && j + 2 >= 1 && j + 2 <= 8) {
      cnt++;
    }
    if (i + 1 >= 1 && i + 1 <= 8 && j + 2 >= 1 && j + 2 <= 8) {
      cnt++;
    }
    if (i + 2 >= 1 && i + 2 <= 8 && j + 1 >= 1 && j + 1 <= 8) {
      cnt++;
    }
    if (i + 2 >= 1 && i + 2 <= 8 && j - 1 >= 1 && j - 1 <= 8) {
      cnt++;
    }
    if (i - 1 >= 1 && i - 1 <= 8 && j - 2 >= 1 && j - 2 <= 8) {
      cnt++;
    }
    if (i + 1 >= 1 && i + 1 <= 8 && j - 2 >= 1 && j - 2 <= 8) {
      cnt++;
    }
    if (i - 2 >= 1 && i - 2 <= 8 && j + 1 >= 1 && j + 1 <= 8) {
      cnt++;
    }
    if (i - 2 >= 1 && i - 2 <= 8 && j - 1 >= 1 && j - 1 <= 8) {
      cnt++;
    }
    printf("%d\n", cnt);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  lea    D14(%rip),%rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x5(%rsp),%r12
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L82
  nop
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsbl 0x5(%rsp),%eax
  movsbl 0x6(%rsp),%ecx
  xor    %esi,%esi
  lea    -0x62(%rax),%edi
  mov    %ecx,%edx
  lea    -0x30(%rcx),%r9d
  lea    -0x60(%rax),%r8d
  cmp    $0x7,%edi
  ja     L6
  lea    -0x2f(%rcx),%esi
  cmp    $0x7,%esi
  setbe  %sil
  movzbl %sil,%esi
L6:
  cmp    $0x7,%r8d
  lea    -0x2f(%rdx),%r10d
  setbe  %r8b
  cmp    $0x7,%r10b
  ja     L51
  cmp    $0x1,%r8b
  sbb    $0xffffffff,%esi
L51:
  lea    -0x5f(%rax),%r10d
  cmp    $0x7,%r10d
  ja     L84
  cmp    $0x8,%r9d
  lea    -0x32(%rcx),%r10d
  adc    $0x0,%esi
  cmp    $0x8,%r10d
  adc    $0x0,%esi
L84:
  cmp    $0x7,%edi
  ja     L0
  lea    -0x33(%rcx),%edi
  cmp    $0x8,%edi
  adc    $0x0,%esi
L0:
  sub    $0x33,%edx
  cmp    $0x7,%dl
  ja     L47
  cmp    $0x1,%r8b
  sbb    $0xffffffff,%esi
L47:
  sub    $0x63,%eax
  cmp    $0x7,%eax
  ja     L80
  cmp    $0x8,%r9d
  adc    $0x0,%esi
  sub    $0x32,%ecx
  cmp    $0x8,%ecx
  adc    $0x0,%esi
L80:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L5
L82:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: string

tool: D7: %d

tool: D14: %s

tool: D11: %d


assistant: ```c
int main() {
  int i, j;
  char a[3];
  int n;
  scanf("%d", &n);
  while (n--) {
    scanf("%s", a);
    i = a[0] - 'a' + 1;
    j = a[1] - '0';
    int cnt = 0;
    if (i - 1 >= 1 && i - 1 <= 8 && j + 2 >= 1 && j + 2 <= 8) {
      cnt++;
    }
    if (i + 1 >= 1 && i + 1 <= 8 && j + 2 >= 1 && j + 2 <= 8) {
      cnt++;
    }
    if (i + 2 >= 1 && i + 2 <= 8 && j + 1 >= 1 && j + 1 <= 8) {
      cnt++;
    }
    if (i + 2 >= 1 && i + 2 <= 8 && j - 1 >= 1 && j - 1 <= 8) {
      cnt++;
    }
    if (i - 1 >= 1 && i - 1 <= 8 && j - 2 >= 1 && j - 2 <= 8) {
      cnt++;
    }
    if (i + 1 >= 1 && i + 1 <= 8 && j - 2 >= 1 && j - 2 <= 8) {
      cnt++;
    }
    if (i - 2 >= 1 && i - 2 <= 8 && j + 1 >= 1 && j + 1 <= 8) {
      cnt++;
    }
    if (i - 2 >= 1 && i - 2 <= 8 && j - 1 >= 1 && j - 1 <= 8) {
      cnt++;
    }
    printf("%d\n", cnt);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  lea    D4(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x5(%rsp),%r12
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L49
  nop
L42:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movsbl 0x5(%rsp),%eax
  movsbl 0x6(%rsp),%ecx
  xor    %esi,%esi
  lea    -0x62(%rax),%edi
  mov    %ecx,%edx
  lea    -0x30(%rcx),%r9d
  lea    -0x60(%rax),%r8d
  cmp    $0x7,%edi
  ja     L68
  lea    -0x2f(%rcx),%esi
  cmp    $0x7,%esi
  setbe  %sil
  movzbl %sil,%esi
L68:
  cmp    $0x7,%r8d
  lea    -0x2f(%rdx),%r10d
  setbe  %r8b
  cmp    $0x7,%r10b
  ja     L82
  cmp    $0x1,%r8b
  sbb    $0xffffffff,%esi
L82:
  lea    -0x5f(%rax),%r10d
  cmp    $0x7,%r10d
  ja     L7
  cmp    $0x8,%r9d
  lea    -0x32(%rcx),%r10d
  adc    $0x0,%esi
  cmp    $0x8,%r10d
  adc    $0x0,%esi
L7:
  cmp    $0x7,%edi
  ja     L4
  lea    -0x33(%rcx),%edi
  cmp    $0x8,%edi
  adc    $0x0,%esi
L4:
  sub    $0x33,%edx
  cmp    $0x7,%dl
  ja     L38
  cmp    $0x1,%r8b
  sbb    $0xffffffff,%esi
L38:
  sub    $0x63,%eax
  cmp    $0x7,%eax
  ja     L3
  cmp    $0x8,%r9d
  adc    $0x0,%esi
  sub    $0x32,%ecx
  cmp    $0x8,%ecx
  adc    $0x0,%esi
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L42
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D27
type_infered: string
name: parse_data
arguments: tag: D4
type_infered: string

tool: D23: %d

tool: D27: %s

tool: D4: %d


assistant: ```c
int main() {
  int i, j;
  char a[3];
  int n;
  scanf("%d", &n);
  while (n--) {
    scanf("%s", a);
    i = a[0] - 'a' + 1;
    j = a[1] - '0';
    int cnt = 0;
    if (i - 1 >= 1 && i - 1 <= 8 && j + 2 >= 1 && j + 2 <= 8) {
      cnt++;
    }
    if (i + 1 >= 1 && i + 1 <= 8 && j + 2 >= 1 && j + 2 <= 8) {
      cnt++;
    }
    if (i + 2 >= 1 && i + 2 <= 8 && j + 1 >= 1 && j + 1 <= 8) {
      cnt++;
    }
    if (i + 2 >= 1 && i + 2 <= 8 && j - 1 >= 1 && j - 1 <= 8) {
      cnt++;
    }
    if (i - 1 >= 1 && i - 1 <= 8 && j - 2 >= 1 && j - 2 <= 8) {
      cnt++;
    }
    if (i + 1 >= 1 && i + 1 <= 8 && j - 2 >= 1 && j - 2 <= 8) {
      cnt++;
    }
    if (i - 2 >= 1 && i - 2 <= 8 && j + 1 >= 1 && j + 1 <= 8) {
      cnt++;
    }
    if (i - 2 >= 1 && i - 2 <= 8 && j - 1 >= 1 && j - 1 <= 8) {
      cnt++;
    }
    printf("%d\n", cnt);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strings_from_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <strings_alloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl -0x14(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strings_from_char(char c) {
  assert(c);
  char *ret = strings_alloc(2);
  ret[0] = c;
  ret[1] = '\0';
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strings_from_char>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <strings_alloc@plt>
  mov    %bl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *strings_from_char(char c) {
  assert(c);
  char *ret = strings_alloc(2);
  ret[0] = c;
  ret[1] = '\0';
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<strings_from_char>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <strings_alloc@plt>
  mov    %bl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *strings_from_char(char c) {
  assert(c);
  char *ret = strings_alloc(2);
  ret[0] = c;
  ret[1] = '\0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strings_from_char>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  movsbl %dil,%edi
  call   <assert@plt>
  mov    $0x2,%edi
  call   <strings_alloc@plt>
  mov    %bl,(%rax)
  movb   $0x0,0x1(%rax)
  pop    %rbx
  ret
```

assistant: ```c
char *strings_from_char(char c) {
  assert(c);
  char *ret = strings_alloc(2);
  ret[0] = c;
  ret[1] = '\0';
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gen_unsigned_greater_or_equal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gen_pop@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <gen_call@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: D8: ccuge

assistant: ```c
gen_unsigned_greater_or_equal() {
  gen_pop();
  gen_call("ccuge");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gen_unsigned_greater_or_equal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gen_pop@plt>
  lea    D9(%rip),%rdi
  call   <gen_call@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D9: ccuge

assistant: ```c
gen_unsigned_greater_or_equal() {
  gen_pop();
  gen_call("ccuge");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gen_unsigned_greater_or_equal>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gen_pop@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <gen_call@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: ccuge

assistant: ```c
gen_unsigned_greater_or_equal() {
  gen_pop();
  gen_call("ccuge");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gen_unsigned_greater_or_equal>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gen_pop@plt>
  lea    D9(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <gen_call@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: ccuge

assistant: ```c
gen_unsigned_greater_or_equal() {
  gen_pop();
  gen_call("ccuge");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<imprimirSequencia>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <tamanhoDaSequencia@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L8:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L29
  mov    $0x20,%edi
  call   <putchar@plt>
L29:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: %d

assistant: ```c
void imprimirSequencia(int numero) {
  int i, n = tamanhoDaSequencia(numero);
  for (i = 0; i < n; i++) {
    printf("%d", numero);
    if (i < n - 1) {
      printf(" ");
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<imprimirSequencia>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  call   <tamanhoDaSequencia@plt>
  test   %eax,%eax
  jle    L22
  mov    %eax,%ebp
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
  jmp    L28
L5:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L22
L28:
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbp),%eax
  cmp    %ebx,%eax
  jle    L5
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L5
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
datatype: string

tool: D9: %d

assistant: ```c
void imprimirSequencia(int numero) {
  int i, n = tamanhoDaSequencia(numero);
  for (i = 0; i < n; i++) {
    printf("%d", numero);
    if (i < n - 1) {
      printf(" ");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<imprimirSequencia>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  call   <tamanhoDaSequencia@plt>
  test   %eax,%eax
  jle    L21
  mov    %eax,%ebp
  lea    -0x1(%rax),%r14d
  lea    D2(%rip),%r13
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    %ebx,%r14d
  jle    L20
  mov    $0x20,%edi
  call   <putchar@plt>
L20:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L28
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: %d

assistant: ```c
void imprimirSequencia(int numero) {
  int i, n = tamanhoDaSequencia(numero);
  for (i = 0; i < n; i++) {
    printf("%d", numero);
    if (i < n - 1) {
      printf(" ");
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<imprimirSequencia>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  call   <tamanhoDaSequencia@plt>
  test   %eax,%eax
  jle    L34
  mov    %eax,%ebx
  mov    %eax,%r14d
  sub    $0x1,%ebx
  jne    L24
  lea    D10(%rip),%r13
  nopl   0x0(%rax)
L6:
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%r14d
  jg     L6
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L24:
  xor    %ebp,%ebp
  lea    D10(%rip),%r13
  nopl   0x0(%rax)
L1:
  mov    %r12d,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebp
  call   <printf@plt>
  mov    $0x20,%edi
  call   <putchar@plt>
  cmp    %ebp,%ebx
  jg     L1
  mov    %ebp,%ebx
  cmp    %ebp,%r14d
  jg     L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: string

tool: D10: %d

assistant: ```c
void imprimirSequencia(int numero) {
  int i, n = tamanhoDaSequencia(numero);
  for (i = 0; i < n; i++) {
    printf("%d", numero);
    if (i < n - 1) {
      printf(" ");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zera>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L7
L38:
  movl   $0x0,-0x14(%rbp)
  jmp    L67
L15:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L62
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  divsd  %xmm1,%xmm0
  movq   D17(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L52
L5:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L52:
  mov    -0x2c(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L5
L62:
  addl   $0x1,-0x14(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L15
  addl   $0x1,-0x10(%rbp)
L7:
  mov    -0x2c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L38
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <imprime@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
datatype: byte[8]
name: disassemble_data
arguments: data_label: D19
datatype: string

tool: {"D17": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D19: 

Matriz Triangular Superior:


assistant: ```c
void zera(double **M, int dim) {
  int i, j, k;
  double num;
  for (j = 0; j < (dim + 1); j++) {
    for (i = 0; i < dim; i++) {
      if (i > j) {
        num = -(M[i][j] / M[j][j]);
        for (k = 0; k < (dim + 1); k++) {
          M[i][k] = num * M[j][k] + M[i][k];
        }
      }
    }
  }
  printf("\n\nMatriz Triangular Superior:\n");
  imprime(M, dim);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<zera>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   %esi,%esi
  js     L66
  mov    %rdi,%r11
  lea    0x1(%rsi),%r13d
  lea    0x0(,%r13,8),%r8
  mov    $0x0,%r9d
  mov    %esi,%r10d
  movq   D16(%rip),%xmm2
  jmp    L40
L69:
  add    $0x1,%rdx
  cmp    %r10,%rdx
  je     L83
L63:
  cmp    %r9d,%edx
  jle    L69
  mov    %r11,%rdi
  mov    (%rbx,%rdx,8),%rcx
  mov    (%r11),%rax
  movsd  (%rcx,%r12,1),%xmm1
  divsd  (%rax,%r12,1),%xmm1
  xorpd  %xmm2,%xmm1
  mov    $0x0,%eax
L3:
  mov    %rax,%rcx
  add    (%rbx,%rdx,8),%rcx
  mov    (%rdi),%rsi
  movapd %xmm1,%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  (%rcx),%xmm0
  movsd  %xmm0,(%rcx)
  add    $0x8,%rax
  cmp    %rax,%r8
  jne    L3
  jmp    L69
L83:
  add    $0x1,%r9
  add    $0x8,%r11
  cmp    %r13,%r9
  je     L66
L40:
  lea    0x0(,%r9,8),%r12
  mov    $0x0,%edx
  test   %ebp,%ebp
  jg     L63
  jmp    L83
L66:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <imprime@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: byte[8]
name: unpack_data
arguments: data_label: D4
type_infered: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: D4: 

Matriz Triangular Superior:


assistant: ```c
void zera(double **M, int dim) {
  int i, j, k;
  double num;
  for (j = 0; j < (dim + 1); j++) {
    for (i = 0; i < dim; i++) {
      if (i > j) {
        num = -(M[i][j] / M[j][j]);
        for (k = 0; k < (dim + 1); k++) {
          M[i][k] = num * M[j][k] + M[i][k];
        }
      }
    }
  }
  printf("\n\nMatriz Triangular Superior:\n");
  imprime(M, dim);
}
```