ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prefix_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  mov    %rsi,%r15
  mov    %edx,%ebx
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  cmp    $0x1,%eax
  je     L28
L51:
  test   %ebx,%ebx
  je     L99
  mov    %ebx,%eax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%r12d
  mov    0xc(%rsp),%eax
  add    $0x1,%eax
  mov    %eax,0x8(%rsp)
L85:
  mov    (%r15,%r12,8),%r13
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebp
  mov    0x8(%rsp),%eax
  lea    0x0(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L33
  mov    0xc(%rsp),%r14d
  mov    %r14,%rdx
  mov    0x10(%rsp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x2f,(%rbx,%r14,1)
  mov    %ebp,%edx
  mov    0x8(%rsp),%edi
  add    %rbx,%rdi
  mov    %r13,%rsi
  call   <memmove@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbx,(%r15,%r12,8)
  add    $0x1,%r12
  cmp    0x18(%rsp),%r12
  jne    L85
  mov    $0x0,%eax
L29:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    0x10(%rsp),%rax
  cmpb   $0x2f,(%rax)
  setne  %al
  movzbl %al,%eax
  mov    %eax,0xc(%rsp)
  jmp    L51
L33:
  test   %r12d,%r12d
  je     L27
  lea    -0x1(%r12),%eax
  lea    (%r15,%rax,8),%rbx
L13:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  sub    $0x8,%rbx
  cmp    %r15,%rax
  jne    L13
  mov    $0x1,%eax
  jmp    L29
L99:
  mov    $0x0,%eax
  jmp    L29
L27:
  mov    $0x1,%eax
  jmp    L29
```

assistant: ```c
int prefix_array(dirname, array, n) const char *dirname;
char **array;
unsigned int n;
{
  register unsigned int i;
  unsigned int dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    unsigned int eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == 0) {
      while (i > 0)
        free((void *)array[--i]);
      return 1;
    }
    bcopy((dirname), (new), (dirlen));
    new[dirlen] = '/';
    bcopy((array[i]), (&new[dirlen + 1]), (eltlen));
    free((void *)array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prefix_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebp
  cmp    $0x1,%eax
  jne    L36
  mov    0x8(%rsp),%rax
  xor    %ebp,%ebp
  cmpb   $0x2f,(%rax)
  setne  %bpl
L36:
  lea    0x1(%rbp),%eax
  xor    %r15d,%r15d
  mov    %eax,0x18(%rsp)
  mov    %ebx,%eax
  mov    %rax,0x10(%rsp)
  test   %ebx,%ebx
  je     L64
  nopl   0x0(%rax,%rax,1)
L59:
  mov    (%r12,%r15,8),%r13
  mov    %r15d,0x1c(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    0x18(%rsp),%eax
  lea    (%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L16
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x18(%rsp),%edi
  mov    %ebx,%edx
  mov    %r13,%rsi
  movb   $0x2f,(%r14,%rbp,1)
  add    %r14,%rdi
  call   <memmove@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r14,(%r12,%r15,8)
  add    $0x1,%r15
  cmp    %r15,0x10(%rsp)
  jne    L59
L64:
  xor    %eax,%eax
L61:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L54
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  lea    (%r12,%rax,8),%rbx
L7:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  sub    $0x8,%rbx
  cmp    %rax,%r12
  jne    L7
L54:
  mov    $0x1,%eax
  jmp    L61
```

assistant: ```c
int prefix_array(dirname, array, n) const char *dirname;
char **array;
unsigned int n;
{
  register unsigned int i;
  unsigned int dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    unsigned int eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == 0) {
      while (i > 0)
        free((void *)array[--i]);
      return 1;
    }
    bcopy((dirname), (new), (dirlen));
    new[dirlen] = '/';
    bcopy((array[i]), (&new[dirlen + 1]), (eltlen));
    free((void *)array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prefix_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  call   <strlen@plt>
  mov    %eax,%ebp
  cmp    $0x1,%eax
  jne    L18
  mov    0x8(%rsp),%rax
  xor    %ebp,%ebp
  cmpb   $0x2f,(%rax)
  setne  %bpl
L18:
  lea    0x1(%rbp),%eax
  xor    %r15d,%r15d
  mov    %eax,0x18(%rsp)
  mov    %ebx,%eax
  mov    %rax,0x10(%rsp)
  test   %ebx,%ebx
  je     L22
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%r12,%r15,8),%r13
  mov    %r15d,0x1c(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%ebx
  mov    0x18(%rsp),%eax
  lea    (%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L60
  mov    0x8(%rsp),%rsi
  mov    %rbp,%rdx
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x18(%rsp),%edi
  mov    %ebx,%edx
  mov    %r13,%rsi
  movb   $0x2f,(%r14,%rbp,1)
  add    %r14,%rdi
  call   <memmove@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r14,(%r12,%r15,8)
  add    $0x1,%r15
  cmp    %r15,0x10(%rsp)
  jne    L14
L22:
  xor    %eax,%eax
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L39
  mov    0x1c(%rsp),%eax
  sub    $0x1,%eax
  lea    (%r12,%rax,8),%rbx
L5:
  mov    (%rbx),%rdi
  call   <free@plt>
  mov    %rbx,%rax
  sub    $0x8,%rbx
  cmp    %rax,%r12
  jne    L5
L39:
  mov    $0x1,%eax
  jmp    L12
```

assistant: ```c
int prefix_array(dirname, array, n) const char *dirname;
char **array;
unsigned int n;
{
  register unsigned int i;
  unsigned int dirlen = strlen(dirname);
  if (dirlen == 1 && dirname[0] == '/')
    dirlen = 0;
  for (i = 0; i < n; ++i) {
    unsigned int eltlen = strlen(array[i]) + 1;
    char *new = (char *)malloc(dirlen + 1 + eltlen);
    if (new == 0) {
      while (i > 0)
        free((void *)array[--i]);
      return 1;
    }
    bcopy((dirname), (new), (dirlen));
    new[dirlen] = '/';
    bcopy((array[i]), (&new[dirlen + 1]), (eltlen));
    free((void *)array[i]);
    array[i] = new;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x834,-0x30(%rbp)
  movl   $0x76c,-0x2c(%rbp)
  mov    $0x8,%esi
  mov    $0x3ce1f0,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x8,%esi
  mov    $0x76c,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,-0x20(%rbp)
  mov    $0x8,%esi
  mov    $0x834,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x8,%esi
  mov    $0x76c,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x8,%esi
  mov    $0x834,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdi
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <init_array@plt>
  mov    -0x10(%rbp),%r8
  mov    -0x18(%rbp),%rdi
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  sub    $0x8,%rsp
  push   -0x8(%rbp)
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <kernel_bicg@plt>
  add    $0x10,%rsp
  cmpl   $0x2a,-0x34(%rbp)
  jle    L0
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L0
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%esi
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <print_array@plt>
L0:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2100;
  int m = 1900;
  double(*A)[2100 + 0][1900 + 0];
  A = (double(*)[2100 + 0][1900 + 0]) polybench_alloc_data((2100 + 0) * (1900 + 0), sizeof(double));
  ;
  double(*s)[1900 + 0];
  s = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*q)[2100 + 0];
  q = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  double(*p)[1900 + 0];
  p = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*r)[2100 + 0];
  r = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  init_array(m, n, *A, *r, *p);
  ;
  kernel_bicg(m, n, *A, *s, *q, *p, *r);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(m, n, *s, *q);
  free((void *)A);
  ;
  free((void *)s);
  ;
  free((void *)q);
  ;
  free((void *)p);
  ;
  free((void *)r);
  ;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,0x8(%rsp)
  mov    $0x8,%esi
  mov    $0x3ce1f0,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,%r12
  mov    $0x8,%esi
  mov    $0x76c,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,%r14
  mov    $0x8,%esi
  mov    $0x834,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,%r13
  mov    $0x8,%esi
  mov    $0x76c,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,%rbp
  mov    $0x8,%esi
  mov    $0x834,%edi
  call   <polybench_alloc_data@plt>
  mov    %rax,%rbx
  mov    %rbp,%r8
  mov    %rax,%rcx
  mov    %r12,%rdx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <init_array@plt>
  sub    $0x8,%rsp
  push   %rbx
  mov    %rbp,%r9
  mov    %r13,%r8
  mov    %r14,%rcx
  mov    %r12,%rdx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <kernel_bicg@plt>
  add    $0x10,%rsp
  cmp    $0x2a,%r15d
  jle    L0
  mov    0x8(%rsp),%rax
  mov    (%rax),%rax
  cmpb   $0x0,(%rax)
  je     L29
L0:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <print_array@plt>
  jmp    L0
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2100;
  int m = 1900;
  double(*A)[2100 + 0][1900 + 0];
  A = (double(*)[2100 + 0][1900 + 0]) polybench_alloc_data((2100 + 0) * (1900 + 0), sizeof(double));
  ;
  double(*s)[1900 + 0];
  s = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*q)[2100 + 0];
  q = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  double(*p)[1900 + 0];
  p = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*r)[2100 + 0];
  r = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  init_array(m, n, *A, *r, *p);
  ;
  kernel_bicg(m, n, *A, *s, *q, *p, *r);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(m, n, *s, *q);
  free((void *)A);
  ;
  free((void *)s);
  ;
  free((void *)q);
  ;
  free((void *)p);
  ;
  free((void *)r);
  ;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3ce1f0,%edi
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    $0x8,%esi
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x76c,%edi
  mov    %rax,%r13
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x834,%edi
  mov    %rax,%r15
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x76c,%edi
  mov    %rax,%r14
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x834,%edi
  mov    %rax,%r12
  call   <polybench_alloc_data@plt>
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x834,%esi
  mov    %rax,%rcx
  mov    $0x76c,%edi
  mov    %rax,%rbp
  call   <init_array@plt>
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12,%r9
  push   %rbp
  mov    %r14,%r8
  mov    %r15,%rcx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <kernel_bicg@plt>
  pop    %rax
  pop    %rdx
  cmp    $0x2a,%ebx
  jle    L9
  mov    0x8(%rsp),%rax
  mov    (%rax),%rax
  cmpb   $0x0,(%rax)
  je     L1
L9:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  mov    %r14,%rcx
  mov    %r15,%rdx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <print_array@plt>
  jmp    L9
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2100;
  int m = 1900;
  double(*A)[2100 + 0][1900 + 0];
  A = (double(*)[2100 + 0][1900 + 0]) polybench_alloc_data((2100 + 0) * (1900 + 0), sizeof(double));
  ;
  double(*s)[1900 + 0];
  s = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*q)[2100 + 0];
  q = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  double(*p)[1900 + 0];
  p = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*r)[2100 + 0];
  r = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  init_array(m, n, *A, *r, *p);
  ;
  kernel_bicg(m, n, *A, *s, *q, *p, *r);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(m, n, *s, *q);
  free((void *)A);
  ;
  free((void *)s);
  ;
  free((void *)q);
  ;
  free((void *)p);
  ;
  free((void *)r);
  ;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x3ce1f0,%edi
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    $0x8,%esi
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x76c,%edi
  mov    %rax,%r13
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x834,%edi
  mov    %rax,%r15
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x76c,%edi
  mov    %rax,%r14
  call   <polybench_alloc_data@plt>
  mov    $0x8,%esi
  mov    $0x834,%edi
  mov    %rax,%r12
  call   <polybench_alloc_data@plt>
  mov    %r12,%r8
  mov    %r13,%rdx
  mov    $0x834,%esi
  mov    %rax,%rcx
  mov    $0x76c,%edi
  mov    %rax,%rbp
  call   <init_array@plt>
  sub    $0x8,%rsp
  mov    %r13,%rdx
  mov    %r12,%r9
  push   %rbp
  mov    %r14,%r8
  mov    %r15,%rcx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <kernel_bicg@plt>
  pop    %rax
  pop    %rdx
  cmp    $0x2a,%ebx
  jle    L1
  mov    0x8(%rsp),%rax
  mov    (%rax),%rax
  cmpb   $0x0,(%rax)
  je     L28
L1:
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  mov    %r14,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    %r14,%rcx
  mov    %r15,%rdx
  mov    $0x834,%esi
  mov    $0x76c,%edi
  call   <print_array@plt>
  jmp    L1
```

assistant: ```c
int main(int argc, char **argv) {
  int n = 2100;
  int m = 1900;
  double(*A)[2100 + 0][1900 + 0];
  A = (double(*)[2100 + 0][1900 + 0]) polybench_alloc_data((2100 + 0) * (1900 + 0), sizeof(double));
  ;
  double(*s)[1900 + 0];
  s = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*q)[2100 + 0];
  q = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  double(*p)[1900 + 0];
  p = (double(*)[1900 + 0]) polybench_alloc_data(1900 + 0, sizeof(double));
  ;
  double(*r)[2100 + 0];
  r = (double(*)[2100 + 0]) polybench_alloc_data(2100 + 0, sizeof(double));
  ;
  init_array(m, n, *A, *r, *p);
  ;
  kernel_bicg(m, n, *A, *s, *q, *p, *r);
  ;
  ;
  if (argc > 42 && !strcmp(argv[0], ""))
    print_array(m, n, *s, *q);
  free((void *)A);
  ;
  free((void *)s);
  ;
  free((void *)q);
  ;
  free((void *)p);
  ;
  free((void *)r);
  ;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L2:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzwl (%rax),%eax
  movzwl %ax,%eax
  add    %eax,-0xc(%rbp)
  subl   $0x2,-0x1c(%rbp)
L17:
  cmpl   $0x1,-0x1c(%rbp)
  jg     L2
  cmpl   $0x1,-0x1c(%rbp)
  jne    L12
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
L12:
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %ax,-0xe(%rbp)
  movzwl -0xe(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned short checksum(void *netPacket, int len) {
  unsigned short *packetPtr = netPacket, result;
  unsigned int sum = 0;
  for (sum = 0; len > 1; len -= 2) {
    sum += *packetPtr++;
  }
  if (len == 1) {
    sum += *(unsigned char *)packetPtr;
  }
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L14
  lea    -0x2(%rsi),%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  mov    $0x0,%eax
L4:
  add    $0x2,%rdi
  movzwl -0x2(%rdi),%edx
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L4
  neg    %r8d
  lea    -0x2(%rsi,%r8,2),%esi
L6:
  cmp    $0x1,%esi
  je     L39
L1:
  mov    %eax,%edx
  shr    $0x10,%edx
  movzwl %ax,%eax
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
L14:
  mov    %rdi,%rcx
  mov    $0x0,%eax
  jmp    L6
L39:
  movzbl (%rcx),%edx
  add    %edx,%eax
  jmp    L1
```

assistant: ```c
unsigned short checksum(void *netPacket, int len) {
  unsigned short *packetPtr = netPacket, result;
  unsigned int sum = 0;
  for (sum = 0; len > 1; len -= 2) {
    sum += *packetPtr++;
  }
  if (len == 1) {
    sum += *(unsigned char *)packetPtr;
  }
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<checksum>:
  endbr64
  cmp    $0x1,%esi
  jle    L2
  sub    $0x2,%esi
  mov    %esi,%r8d
  shr    %r8d
  lea    0x1(%r8),%eax
  lea    (%rdi,%rax,2),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax)
L4:
  movzwl (%rdi),%edx
  add    $0x2,%rdi
  add    %edx,%eax
  cmp    %rcx,%rdi
  jne    L4
  neg    %r8d
  lea    (%rsi,%r8,2),%esi
L3:
  cmp    $0x1,%esi
  jne    L33
  movzbl (%rcx),%edx
  add    %edx,%eax
L33:
  mov    %eax,%edx
  movzwl %ax,%eax
  shr    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %rdi,%rcx
  xor    %eax,%eax
  jmp    L3
```

assistant: ```c
unsigned short checksum(void *netPacket, int len) {
  unsigned short *packetPtr = netPacket, result;
  unsigned int sum = 0;
  for (sum = 0; len > 1; len -= 2) {
    sum += *packetPtr++;
  }
  if (len == 1) {
    sum += *(unsigned char *)packetPtr;
  }
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<checksum>:
  endbr64
  mov    %rdi,%rdx
  cmp    $0x1,%esi
  jle    L61
  lea    -0x2(%rsi),%r10d
  mov    %r10d,%r9d
  shr    %r9d
  lea    0x1(%r9),%ecx
  cmp    $0xd,%r10d
  jbe    L56
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %ecx,%edi
  shr    $0x3,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rdx,%rdi,1),%rdi
  nopl   0x0(%rax)
L3:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm3
  punpckhwd %xmm2,%xmm0
  punpcklwd %xmm2,%xmm3
  paddd  %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L3
  movdqa %xmm1,%xmm0
  mov    %ecx,%r8d
  psrldq $0x8,%xmm0
  and    $0xfffffff8,%r8d
  paddd  %xmm0,%xmm1
  mov    %r8d,%edi
  movdqa %xmm1,%xmm0
  neg    %edi
  psrldq $0x4,%xmm0
  lea    (%rsi,%rdi,2),%esi
  mov    %r8d,%edi
  paddd  %xmm0,%xmm1
  lea    (%rdx,%rdi,2),%rdi
  movd   %xmm1,%eax
  cmp    %ecx,%r8d
  je     L116
L64:
  movzwl (%rdi),%r8d
  add    %r8d,%eax
  lea    -0x2(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L116
  movzwl 0x2(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x4(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L116
  movzwl 0x4(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x6(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L116
  movzwl 0x6(%rdi),%r8d
  add    %r8d,%eax
  lea    -0x8(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L116
  movzwl 0x8(%rdi),%r8d
  add    %r8d,%eax
  lea    -0xa(%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L116
  movzwl 0xa(%rdi),%r8d
  add    %r8d,%eax
  cmp    $0xd,%esi
  jle    L116
  movzwl 0xc(%rdi),%esi
  add    %esi,%eax
L116:
  mov    %ecx,%esi
  mov    %r9d,%ecx
  neg    %ecx
  lea    (%rdx,%rsi,2),%rdx
  lea    (%r10,%rcx,2),%esi
L32:
  cmp    $0x1,%esi
  jne    L81
  movzbl (%rdx),%edx
  add    %edx,%eax
L81:
  mov    %eax,%edx
  movzwl %ax,%eax
  shr    $0x10,%edx
  add    %eax,%edx
  mov    %edx,%eax
  shr    $0x10,%eax
  add    %edx,%eax
  not    %eax
  ret
  nopl   0x0(%rax,%rax,1)
L61:
  xor    %eax,%eax
  jmp    L32
L56:
  xor    %eax,%eax
  jmp    L64
```

assistant: ```c
unsigned short checksum(void *netPacket, int len) {
  unsigned short *packetPtr = netPacket, result;
  unsigned int sum = 0;
  for (sum = 0; len > 1; len -= 2) {
    sum += *packetPtr++;
  }
  if (len == 1) {
    sum += *(unsigned char *)packetPtr;
  }
  sum = (sum >> 16) + (sum & 0xFFFF);
  sum += (sum >> 16);
  result = ~sum;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmp_long_asc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L13
  mov    $0xffffffff,%eax
  jmp    L23
L13:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jle    L17
  mov    $0x1,%eax
  jmp    L23
L17:
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int cmp_long_asc(const void *x, const void *y) {
  if (*(long *)x < *(long *)y) {
    return -1;
  } else if (*(long *)x > *(long *)y) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<cmp_long_asc>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jl     L8
  setg   %al
  movzbl %al,%eax
L8:
  ret
```

assistant: ```c
int cmp_long_asc(const void *x, const void *y) {
  if (*(long *)x < *(long *)y) {
    return -1;
  } else if (*(long *)x > *(long *)y) {
    return 1;
  }
  return 0;
}
```