ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<entab>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    D13(%rip),%rax
  movsbl (%rsi),%ebx
  mov    (%rax),%eax
  mov    %ebx,%r13d
  cmp    %ebx,%eax
  je     L76
  lea    0x1(%rsi),%rbp
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  xor    %r12d,%r12d
  xor    %r14d,%r14d
  jmp    L95
L118:
  test   %r12d,%r12d
  je     L121
  movslq %r14d,%rdi
  movslq %r12d,%rdx
  mov    $0x9,%esi
  mov    %ecx,0xc(%rsp)
  add    %r15,%rdi
  mov    %r8d,0x8(%rsp)
  add    %r14d,%r12d
  call   <memset@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%r8d
L7:
  cmp    $0x9,%ebx
  je     L69
  add    $0x1,%ecx
  test   %r8d,%r8d
  je     L17
  movslq %r12d,%rdi
  movslq %r8d,%rdx
  mov    $0x20,%esi
  mov    %ecx,0xc(%rsp)
  add    %r15,%rdi
  mov    %r8d,0x8(%rsp)
  call   <memset@plt>
  mov    0x8(%rsp),%r8d
  mov    0xc(%rsp),%ecx
  add    %r8d,%r12d
L17:
  mov    D13(%rip),%rax
  lea    0x1(%r12),%r14d
  movslq %r12d,%r12
  xor    %r8d,%r8d
  mov    %r13b,(%r15,%r12,1)
  xor    %r12d,%r12d
  mov    (%rax),%eax
L125:
  movsbl 0x0(%rbp),%ebx
  add    $0x1,%rbp
  mov    %ebx,%r13d
  cmp    %eax,%ebx
  je     L120
L95:
  cmp    $0xa,%ebx
  je     L74
  cmp    $0x20,%ebx
  jne    L118
  add    $0x1,%ecx
  add    $0x1,%r8d
  test   $0x7,%cl
  jne    L125
  movsbl 0x0(%rbp),%ebx
  add    $0x1,%r12d
  xor    %r8d,%r8d
  add    $0x1,%rbp
  mov    %ebx,%r13d
  cmp    %eax,%ebx
  jne    L95
  nopl   0x0(%rax)
L120:
  movslq %r14d,%rax
  add    %r15,%rax
L72:
  cmp    $0xa,%ebx
  jne    L111
  jmp    L51
  nopl   (%rax)
L69:
  and    $0xfffffff8,%ecx
  mov    $0x8,%eax
  add    %eax,%ecx
  jmp    L17
  nopl   0x0(%rax)
L74:
  mov    $0xa,%r13d
L51:
  movslq %r14d,%rax
  mov    %r13b,(%r15,%rax,1)
  lea    0x1(%r14),%eax
  cltq
  add    %r15,%rax
L111:
  movb   $0x0,(%rax)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L121:
  mov    %r14d,%r12d
  jmp    L7
L76:
  mov    %rdi,%rax
  xor    %r14d,%r14d
  jmp    L72
```

assistant: ```c
void entab(char to[], char from[]) {
  int c, i, j, tabs, spaces, pos;
  spaces = tabs = 0;
  for (i = j = pos = 0; (c = from[i]) != EOF && c != '\n'; i++, pos++) {
    if (c == ' ') {
      if ((pos + 1) % 8 == 0) {
        tabs++;
        spaces = 0;
      } else {
        spaces++;
      }
    }
    if (c != ' ') {
      for (; tabs > 0; tabs--, j++)
        to[j] = '\t';
      tabs = 0;
      if (c == '\t') {
        spaces = 0;
        pos = pos + (8 - pos % 8) - 1;
      }
      for (; spaces > 0; spaces--, j++)
        to[j] = ' ';
      to[j++] = c;
    }
  }
  if (c == '\n') {
    to[j++] = c;
  }
  to[j] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sceda_func>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %rcx,%rsi
  mov    %r8,%r14
  mov    %r9d,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  mov    $0x10,%edx
  call   <memcpy@plt>
  lea    0x20(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  lea    0x28(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  lea    0x30(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  lea    0x38(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  movb   $0x0,0x40(%rsp)
  test   %r12d,%r12d
  jle    L86
  mov    %r12d,%r12d
  shl    $0x4,%r12
  lea    (%rbx,%r12,1),%r14
  mov    %rsp,%r12
  jmp    L87
L20:
  lea    0x30(%rsp),%rdi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
  jmp    L13
L23:
  lea    0x20(%rsp),%rdi
  mov    $0x10,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
L7:
  addb   $0x1,0x30(%rsp)
  add    $0x10,%rbp
  add    $0x10,%rbx
  cmp    %rbx,%r14
  je     L86
L87:
  lea    0x10(%rsp),%rsi
  mov    $0x31,%edx
  mov    %r12,%rdi
  call   <sceda_digest@plt>
  test   %r13d,%r13d
  je     L20
  lea    0x20(%rsp),%rdi
  mov    $0x10,%edx
  mov    %rbp,%rsi
  call   <memcpy@plt>
L13:
  mov    $0x0,%eax
L68:
  movzbl 0x0(%rbp,%rax,1),%edx
  xor    (%rax,%r12,1),%dl
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L68
  test   %r13d,%r13d
  je     L23
  lea    0x30(%rsp),%rdi
  mov    $0x10,%edx
  mov    %rbx,%rsi
  call   <memcpy@plt>
  jmp    L7
L86:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sceda_func(unsigned char *output, const unsigned char *original, int blockC, const unsigned char *key, const unsigned char *iv, int decrypting) {
  unsigned char blockKey[49], hashedBlockKey[16], *pt2;
  const unsigned char *pt1;
  int i, j;
  memcpy(blockKey, key, 16);
  memcpy(blockKey + 16, iv, 8);
  memcpy(blockKey + 24, iv, 8);
  memcpy(blockKey + 32, iv, 8);
  memcpy(blockKey + 40, iv, 8);
  blockKey[48] = 0;
  pt1 = original;
  pt2 = output;
  for (i = 0; i < blockC; i++) {
    sceda_digest(hashedBlockKey, blockKey, 49);
    if (decrypting) {
      memcpy(blockKey + 16, pt1, 16);
    } else {
      memcpy(blockKey + 32, pt1, 16);
    }
    for (j = 0; j < 16; j++) {
      pt2[j] = pt1[j] ^ hashedBlockKey[j];
    }
    if (decrypting) {
      memcpy(blockKey + 32, pt2, 16);
    } else {
      memcpy(blockKey + 16, pt2, 16);
    }
    blockKey[32]++;
    pt1 += 16;
    pt2 += 16;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sceda_func>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  mov    %rcx,%rsi
  push   %r12
  mov    %r8,%r12
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x68,%rsp
  mov    %edx,0x8(%rsp)
  lea    0x20(%rsp),%r15
  mov    $0x10,%edx
  lea    0x40(%rsp),%r14
  mov    %r15,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  call   <memcpy@plt>
  lea    0x30(%rsp),%rax
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  call   <memcpy@plt>
  lea    0x38(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  lea    0x48(%rsp),%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  movslq 0x8(%rsp),%r11
  movb   $0x0,0x50(%rsp)
  test   %r11d,%r11d
  jle    L31
  shl    $0x4,%r11
  lea    0x10(%rsp),%r12
  lea    (%rbx,%r11,1),%rax
  mov    %rax,0x8(%rsp)
  xchg   %ax,%ax
L79:
  mov    $0x31,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <sceda_digest@plt>
  mov    $0x10,%edx
  mov    %r13,%rsi
  test   %ebp,%ebp
  je     L30
  mov    (%rsp),%rdi
  call   <memcpy@plt>
L18:
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L52:
  movzbl 0x0(%r13,%rax,1),%edx
  xor    (%r12,%rax,1),%dl
  mov    %dl,(%rbx,%rax,1)
  add    $0x1,%rax
  cmp    $0x10,%rax
  jne    L52
  mov    $0x10,%edx
  mov    %rbx,%rsi
  test   %ebp,%ebp
  je     L39
  mov    %r14,%rdi
  call   <memcpy@plt>
L61:
  addb   $0x1,0x40(%rsp)
  add    $0x10,%r13
  add    $0x10,%rbx
  cmp    %rbx,0x8(%rsp)
  jne    L79
L31:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L39:
  mov    (%rsp),%rdi
  call   <memcpy@plt>
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %r14,%rdi
  call   <memcpy@plt>
  jmp    L18
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sceda_func(unsigned char *output, const unsigned char *original, int blockC, const unsigned char *key, const unsigned char *iv, int decrypting) {
  unsigned char blockKey[49], hashedBlockKey[16], *pt2;
  const unsigned char *pt1;
  int i, j;
  memcpy(blockKey, key, 16);
  memcpy(blockKey + 16, iv, 8);
  memcpy(blockKey + 24, iv, 8);
  memcpy(blockKey + 32, iv, 8);
  memcpy(blockKey + 40, iv, 8);
  blockKey[48] = 0;
  pt1 = original;
  pt2 = output;
  for (i = 0; i < blockC; i++) {
    sceda_digest(hashedBlockKey, blockKey, 49);
    if (decrypting) {
      memcpy(blockKey + 16, pt1, 16);
    } else {
      memcpy(blockKey + 32, pt1, 16);
    }
    for (j = 0; j < 16; j++) {
      pt2[j] = pt1[j] ^ hashedBlockKey[j];
    }
    if (decrypting) {
      memcpy(blockKey + 32, pt2, 16);
    } else {
      memcpy(blockKey + 16, pt2, 16);
    }
    blockKey[32]++;
    pt1 += 16;
    pt2 += 16;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x6,-0x18(%rbp)
  movl   $0x7,-0x14(%rbp)
  movl   $0x8,-0x10(%rbp)
  movl   $0x9,-0xc(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    $0x9,%edi
  call   <binsearch@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    $0x9,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    $0xa,%edx
  mov    %rax,%rsi
  mov    $0xfffffffe,%edi
  call   <binsearch@plt>
  mov    %eax,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,%edx
  mov    $0xfffffffe,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D6: find %d in array %d


assistant: ```c
int main(int argc, char *argv[]) {
  int array[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int index;
  index = binsearch(9, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", 9, index);
  index = binsearch(-2, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", -2, index);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  movl   $0x5,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x7,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x9,0x24(%rsp)
  mov    %rsp,%rbp
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    $0x9,%edi
  call   <binsearch@plt>
  mov    %eax,%edx
  mov    $0x9,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xa,%edx
  mov    %rbp,%rsi
  mov    $0xfffffffe,%edi
  call   <binsearch@plt>
  mov    %eax,%edx
  mov    $0xfffffffe,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: find %d in array %d


assistant: ```c
int main(int argc, char *argv[]) {
  int array[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int index;
  index = binsearch(9, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", 9, index);
  index = binsearch(-2, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", -2, index);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  mov    $0x9,%edi
  push   %rbp
  lea    D8(%rip),%rbp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x100000000,%rax
  mov    %rsp,%r12
  mov    %r12,%rsi
  mov    %rax,(%rsp)
  movabs $0x300000002,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x700000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x900000008,%rax
  mov    %rax,0x20(%rsp)
  call   <binsearch@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0xa,%edx
  mov    %r12,%rsi
  mov    $0xfffffffe,%edi
  call   <binsearch@plt>
  mov    $0xfffffffe,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: D8: find %d in array %d


assistant: ```c
int main(int argc, char *argv[]) {
  int array[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int index;
  index = binsearch(9, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", 9, index);
  index = binsearch(-2, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", -2, index);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xa,%edx
  mov    $0x9,%edi
  push   %rbp
  lea    D7(%rip),%rbp
  sub    $0x38,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    D31(%rip),%rax
  movaps %xmm0,(%rsp)
  movdqa D4(%rip),%xmm0
  mov    %r12,%rsi
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <binsearch@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    $0xa,%edx
  mov    %r12,%rsi
  mov    $0xfffffffe,%edi
  call   <binsearch@plt>
  mov    $0xfffffffe,%esi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string
name: parse_data
arguments: data_tag: D12
type_infered: byte[16]
name: parse_data
arguments: data_tag: D31
type_infered: byte[8]
name: parse_data
arguments: data_tag: D4
type_infered: byte[16]

tool: D7: find %d in array %d


tool: {"D12": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D31": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D4": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
int main(int argc, char *argv[]) {
  int array[] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
  int index;
  index = binsearch(9, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", 9, index);
  index = binsearch(-2, array, (sizeof array) / (sizeof array[0]));
  printf("find %d in array %d\n", -2, index);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<CmdLT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <Pop@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <Pop@plt>
  cmp    %eax,-0x4(%rbp)
  setg   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <Push@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int CmdLT(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() < operand2);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<CmdLT>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <Pop@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <Pop@plt>
  cmp    %ebx,%eax
  setl   %dil
  movzbl %dil,%edi
  call   <Push@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int CmdLT(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() < operand2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CmdLT>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <Pop@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <Pop@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  setl   %dil
  call   <Push@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int CmdLT(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() < operand2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<CmdLT>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <Pop@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <Pop@plt>
  xor    %edi,%edi
  cmp    %ebx,%eax
  setl   %dil
  call   <Push@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int CmdLT(void) {
  int operand2;
  operand2 = Pop();
  Push(Pop() < operand2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nlopt_compute_rescaling>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  mov    $0x0,%eax
  jmp    L56
L38:
  movl   $0x0,-0xc(%rbp)
  jmp    L80
L118:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L80:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L118
  cmpl   $0x1,-0x14(%rbp)
  jne    L12
  mov    -0x8(%rbp),%rax
  jmp    L56
L12:
  movl   $0x1,-0xc(%rbp)
  jmp    L98
L114:
  addl   $0x1,-0xc(%rbp)
L98:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jae    L125
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L125
  ucomisd %xmm1,%xmm0
  je     L114
L125:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jae    L112
  movl   $0x1,-0xc(%rbp)
  jmp    L25
L41:
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L41
L112:
  mov    -0x8(%rbp),%rax
L56:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type: f64

tool: D8: 1

assistant: ```c
double *nlopt_compute_rescaling(unsigned n, const double *dx) {
  double *s = (double *)malloc(sizeof(double) * n);
  unsigned i;
  if (!s)
    return NULL;
  for (i = 0; i < n; ++i)
    s[i] = 1.0;
  if (n == 1)
    return s;
  for (i = 1; i < n && dx[i] == dx[i - 1]; ++i)
    ;
  if (i < n) {
    for (i = 1; i < n; ++i)
      s[i] = dx[i] / dx[0];
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nlopt_compute_rescaling>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L85
  mov    %rax,%rdi
  test   %ebp,%ebp
  je     L61
  mov    %ebp,%edx
  lea    (%rax,%rdx,8),%rcx
  mov    %rax,%rdx
  movsd  D4(%rip),%xmm0
L91:
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L91
  cmp    $0x1,%ebp
  je     L61
  lea    -0x2(%rbp),%r8d
  mov    %ebp,%esi
  mov    $0x1,%edx
L97:
  mov    %edx,%ecx
  movsd  (%rbx,%rdx,8),%xmm0
  ucomisd -0x8(%rbx,%rdx,8),%xmm0
  jp     L109
  jne    L109
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L97
L61:
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L85:
  mov    $0x0,%edi
  jmp    L61
L109:
  cmp    %ecx,%ebp
  jbe    L61
  lea    0x8(%rax),%rdx
  lea    0x10(%rax,%r8,8),%rsi
  mov    %rbx,%rcx
  sub    %rax,%rcx
L43:
  movsd  (%rcx,%rdx,1),%xmm0
  divsd  (%rbx),%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L43
  jmp    L61
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: f64

tool: D4: 1

assistant: ```c
double *nlopt_compute_rescaling(unsigned n, const double *dx) {
  double *s = (double *)malloc(sizeof(double) * n);
  unsigned i;
  if (!s)
    return NULL;
  for (i = 0; i < n; ++i)
    s[i] = 1.0;
  if (n == 1)
    return s;
  for (i = 1; i < n && dx[i] == dx[i - 1]; ++i)
    ;
  if (i < n) {
    for (i = 1; i < n; ++i)
      s[i] = dx[i] / dx[0];
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nlopt_compute_rescaling>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  shl    $0x3,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rax,%rax
  je     L19
  test   %ebp,%ebp
  je     L19
  mov    %ebp,%esi
  movsd  D2(%rip),%xmm0
  mov    %rax,%rdx
  lea    (%rax,%rsi,8),%rcx
  nopl   (%rax)
L27:
  movsd  %xmm0,(%rdx)
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L27
  cmp    $0x1,%ebp
  je     L19
  lea    -0x2(%rbp),%edi
  mov    $0x1,%edx
  jmp    L55
  nopl   0x0(%rax)
L20:
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L19
L55:
  movsd  (%rbx,%rdx,8),%xmm0
  ucomisd -0x8(%rbx,%rdx,8),%xmm0
  mov    %edx,%ecx
  jp     L59
  je     L20
L59:
  cmp    %ebp,%ecx
  jae    L19
  mov    %rbx,%rcx
  lea    0x8(%rax),%rdx
  lea    0x10(%rax,%rdi,8),%rsi
  sub    %rax,%rcx
  nopl   (%rax)
L86:
  movsd  (%rcx,%rdx,1),%xmm0
  add    $0x8,%rdx
  divsd  (%rbx),%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rdx,%rsi
  jne    L86
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: f64

tool: D2: 1

assistant: ```c
double *nlopt_compute_rescaling(unsigned n, const double *dx) {
  double *s = (double *)malloc(sizeof(double) * n);
  unsigned i;
  if (!s)
    return NULL;
  for (i = 0; i < n; ++i)
    s[i] = 1.0;
  if (n == 1)
    return s;
  for (i = 1; i < n && dx[i] == dx[i - 1]; ++i)
    ;
  if (i < n) {
    for (i = 1; i < n; ++i)
      s[i] = dx[i] / dx[0];
  }
  return s;
}
```