user: 请从给定的汇编指令推导出C源代码：

```asm
<string_get_col>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rsi,%rdi
  push   %r13
  mov    %edx,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  call   <string_get@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbx
  cs nopw 0x0(%rax,%rax,1)
L149:
  mov    %rbp,%rsi
  call   <check_char_class@plt>
  test   %rax,%rax
  je     L261
L236:
  cmpb   $0x0,(%rbx)
  je     L173
  movsbl 0x1(%rbx),%edi
  mov    %rbp,%rsi
  add    $0x1,%rbx
  call   <check_char_class@plt>
  test   %rax,%rax
  jne    L236
L261:
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L173
  cmp    %r13d,%r12d
  je     L88
  cmp    $0x22,%dil
  jne    L216
  jmp    L66
  nopl   0x0(%rax,%rax,1)
L86:
  cmpb   $0x0,(%rbx)
  je     L173
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L216:
  mov    %rbp,%rsi
  call   <check_char_class@plt>
  test   %rax,%rax
  je     L86
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L173
L230:
  add    $0x1,%r12d
  jmp    L149
  nopl   0x0(%rax,%rax,1)
L66:
  mov    %rbx,%rdx
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  je     L173
  cmp    $0x22,%al
  jne    L66
  test   %al,%al
  je     L173
  movsbl 0x2(%rdx),%edi
  lea    0x2(%rdx),%rbx
  jmp    L230
L136:
  movzbl 0x1(%rbx),%eax
  cmp    $0x22,%al
  je     L173
  test   %al,%al
  je     L173
  lea    0x1(%rbx),%rbp
  mov    %eax,%edx
  mov    %rbp,%r12
  jmp    L214
  nopl   0x0(%rax,%rax,1)
L77:
  cmp    $0x22,%dl
  je     L89
  movzbl 0x1(%rbp),%edx
  mov    %rbp,%rbx
  add    $0x1,%rbp
L214:
  test   %dl,%dl
  jne    L77
L173:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L88:
  mov    %r14,%rdi
  lea    D1(%rip),%rsi
  call   <string_set@plt>
  movsbl (%rbx),%edi
  cmp    $0x22,%dil
  jne    L53
  jmp    L136
  nopl   0x0(%rax)
L85:
  mov    %rbp,%rsi
  call   <check_char_class@plt>
  test   %rax,%rax
  jne    L223
  movsbl (%rbx),%esi
  mov    %r14,%rdi
  add    $0x1,%rbx
  call   <string_append_char@plt>
  movsbl (%rbx),%edi
L53:
  test   %dil,%dil
  jne    L85
L223:
  xor    %eax,%eax
L58:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L89:
  test   %dl,%dl
  je     L173
  cmp    %r12,%rbx
  jae    L94
  jmp    L223
  nopw   0x0(%rax,%rax,1)
L0:
  movzbl (%r12),%eax
L94:
  add    $0x1,%r12
  movsbl %al,%esi
  mov    %r14,%rdi
  call   <string_append_char@plt>
  cmp    %r12,%rbp
  jne    L0
  xor    %eax,%eax
  jmp    L58
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: 

assistant: ```c
int string_get_col(struct string *dst, struct string const *src, unsigned col_no, char const *delim) {
  unsigned cur_col = 0;
  char const *strp = string_get(src);
  for (;;) {
    while (check_char_class(*strp, delim) && *strp)
      strp++;
    if (!*strp)
      return -1;
    if (cur_col == col_no)
      break;
    if (*strp == '"') {
      do {
        strp++;
      } while (*strp && *strp != '"');
      if (!*strp)
        return -1;
      strp++;
    } else {
      while (!check_char_class(*strp, delim) && *strp)
        strp++;
      if (!*strp)
        return -1;
    }
    cur_col++;
  }
  string_set(dst, "");
  if (*strp == '"') {
    if (strp[1] == '"' || !strp[1])
      return -1;
    char const *last;
    char const *first = strp + 1;
    do {
      last = strp;
      strp++;
    } while (*strp && *strp != '"');
    if (!*strp)
      return -1;
    while (first <= last)
      string_append_char(dst, *first++);
  } else {
    while (*strp && !check_char_class(*strp, delim))
      string_append_char(dst, *strp++);
  }
  return 0;
}
```