user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D209(%rip),%rdi
  xor    %r12d,%r12d
  push   %rbp
  lea    D65(%rip),%rbp
  push   %rbx
  sub    $0x20,%rsp
  call   <puts@plt>
  movsd  D52(%rip),%xmm3
  movsd  D183(%rip),%xmm1
  movsd  %xmm3,0x8(%rsp)
  nopl   0x0(%rax,%rax,1)
L9:
  movsd  0x8(%rsp),%xmm2
  movsd  %xmm1,0x18(%rsp)
  add    $0x1,%r12d
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x10(%rsp)
  call   <Xn@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <Yn@plt>
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movapd %xmm0,%xmm1
  movsd  %xmm0,0x10(%rsp)
  movsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  movsd  D115(%rip),%xmm7
  subsd  0x8(%rsp),%xmm7
  mov    $0x2,%edi
  movapd %xmm7,%xmm0
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm1
  mov    $0x2,%edi
  movsd  D115(%rip),%xmm0
  mov    %rax,%rbx
  subsd  %xmm1,%xmm0
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  comisd D145(%rip),%xmm0
  movsd  0x10(%rsp),%xmm1
  ja     L9
  mov    %r12d,%esi
  lea    D172(%rip),%rdi
  xor    %eax,%eax
  mov    $0x32,%ebp
  call   <printf@plt>
  lea    D107(%rip),%rdi
  call   <puts@plt>
  movsd  D179(%rip),%xmm3
  movsd  D45(%rip),%xmm1
  movapd %xmm3,%xmm0
  call   <Xn@plt>
  mov    D45(%rip),%rax
  movsd  %xmm0,0x10(%rsp)
  movq   %rax,%xmm1
  mov    D179(%rip),%rax
  movq   %rax,%xmm0
  call   <Yn@plt>
  movsd  0x10(%rsp),%xmm2
  mov    $0x2,%edi
  movsd  %xmm0,0x8(%rsp)
  movsd  D115(%rip),%xmm0
  subsd  %xmm2,%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  mov    $0x2,%edi
  movsd  D115(%rip),%xmm0
  mov    %rax,%rbx
  subsd  %xmm1,%xmm0
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm2
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L43:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  call   <Xn@plt>
  movsd  0x10(%rsp),%xmm2
  movsd  0x18(%rsp),%xmm1
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <Yn@plt>
  movsd  D115(%rip),%xmm4
  subsd  0x8(%rsp),%xmm4
  mov    $0x2,%edi
  movsd  %xmm0,0x10(%rsp)
  movapd %xmm4,%xmm0
  call   <pow@plt>
  movsd  0x10(%rsp),%xmm1
  mov    $0x2,%edi
  movsd  D115(%rip),%xmm0
  mov    %rax,%rbx
  subsd  %xmm1,%xmm0
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  sub    $0x1,%ebp
  movsd  0x10(%rsp),%xmm1
  je     L36
  movsd  0x8(%rsp),%xmm2
L23:
  comisd D145(%rip),%xmm0
  ja     L43
L20:
  lea    D188(%rip),%rdi
  call   <system@plt>
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  movsd  0x8(%rsp),%xmm0
  lea    D128(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    D157(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L20
```

tool_calls: name: parse_data
arguments: data_tag: D209
type_guessed: string
name: parse_data
arguments: data_tag: D65
type_guessed: string
name: parse_data
arguments: data_tag: D52
type_guessed: f64
name: parse_data
arguments: data_tag: D183
type_guessed: f64
name: parse_data
arguments: data_tag: D115
type_guessed: f64
name: parse_data
arguments: data_tag: D145
type_guessed: f64[2]
name: parse_data
arguments: data_tag: D172
type_guessed: string
name: parse_data
arguments: data_tag: D107
type_guessed: string
name: parse_data
arguments: data_tag: D179
type_guessed: f64
name: parse_data
arguments: data_tag: D45
type_guessed: f64
name: parse_data
arguments: data_tag: D188
type_guessed: string
name: parse_data
arguments: data_tag: D128
type_guessed: string
name: parse_data
arguments: data_tag: D157
type_guessed: string

tool: D209: apartado a)


tool: D65: x: %lf;y: %lf


tool: D52: 0.5

tool: D183: 0.7

tool: D115: 1

tool: {"D145": [0.001,1.5]}

tool: D172: num iter: %d


tool: D107: 
apartado b)


tool: D179: 0.25

tool: D45: 1.5

tool: D188: PAUSE

tool: D128: la solucion converge a otra sol: x= %lf; y= %lf

tool: D157: 
presione ENTER para continuar

assistant: ```c
int main() {
  double x = 0.5, y = 0.7;
  double aux;
  double error = 10;
  double sx = 1;
  double sy = 1;
  double tol = 0.001;
  printf("apartado a)\n\n");
  int i = 0;
  while (error > tol) {
    i++;
    aux = x;
    x = Xn(x, y);
    y = Yn(aux, y);
    printf("x: %lf;y: %lf\n", x, y);
    error = sqrt(pow(sx - x, 2) + pow(sy - y, 2));
  }
  printf("num iter: %d\n", i);
  printf("\napartado b)\n\n");
  i = 0;
  x = 0.25;
  y = 1.5;
  error = 10;
  while (error > tol) {
    i++;
    aux = x;
    x = Xn(x, y);
    y = Yn(aux, y);
    error = sqrt(pow(sx - x, 2) + pow(sy - y, 2));
    if (i > 50) {
      printf("la solucion converge a otra sol: x= %lf; y= %lf", x, y);
      printf("\npresione ENTER para continuar");
      break;
    }
  }
  system("PAUSE");
}
```