ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<man>:
  endbr64
  push   %rbx
  mov    $0x2e65,%edx
  sub    $0x70,%rsp
  movdqa D1(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x22(%rsp)
  lea    0x30(%rsp),%rcx
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movdqa D30(%rip),%xmm0
  mov    %dx,0x20(%rsp)
  mov    $0x49,%edx
  movaps %xmm0,0x10(%rsp)
  xchg   %ax,%ax
L26:
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L26
  movb   $0x0,0x30(%rsp,%rax,1)
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  lea    0x31(%rsp),%rbx
  call   <printf@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x30(%rsp),%edi
  test   %dil,%dil
  je     L2
  nop
L36:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L36
L2:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type: byte[16]
name: parse_data
arguments: label: D30
type: byte[16]
name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D33
type: string

tool: {"D1": [0x49,0x20,0x61,0x6d,0x20,0x61,0x20,0x62,0x6f,0x79,0x2e,0x69,0x20,0x66,0x65,0x61]}

tool: {"D30": [0x72,0x20,0x61,0x62,0x6f,0x75,0x74,0x20,0x6d,0x79,0x20,0x66,0x75,0x74,0x75,0x72]}

tool: D11: string a is :%s


tool: D33: string b is :

assistant: ```c
int man() {
  char a[] = "I am a boy.i fear about my future.", b[50];
  int i = 0;
  for (i = 0; *(a + i) != '\0'; i++) {
    *(b + i) = *(a + i);
  }
  *(b + i) = '\0';
  printf("string a is :%s\n", a);
  printf("string b is :");
  for (i = 0; b[i] != '\0'; i++)
    printf("%c", b[i]);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<man>:
  endbr64
  push   %rbx
  mov    $0x2e65,%edx
  sub    $0x70,%rsp
  movdqa D22(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x22(%rsp)
  lea    0x30(%rsp),%rcx
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  movdqa D36(%rip),%xmm0
  mov    %dx,0x20(%rsp)
  mov    $0x49,%edx
  movaps %xmm0,0x10(%rsp)
  xchg   %ax,%ax
L26:
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L26
  movb   $0x0,0x30(%rsp,%rax,1)
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  lea    0x31(%rsp),%rbx
  call   <printf@plt>
  lea    D34(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsbl 0x30(%rsp),%edi
  test   %dil,%dil
  je     L13
  nop
L3:
  call   <putchar@plt>
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L13:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D22
type: byte[16]
name: read_data
arguments: label: D36
type: byte[16]
name: read_data
arguments: label: D39
type: string
name: read_data
arguments: label: D34
type: string

tool: {"D22": [0x49,0x20,0x61,0x6d,0x20,0x61,0x20,0x62,0x6f,0x79,0x2e,0x69,0x20,0x66,0x65,0x61]}

tool: {"D36": [0x72,0x20,0x61,0x62,0x6f,0x75,0x74,0x20,0x6d,0x79,0x20,0x66,0x75,0x74,0x75,0x72]}

tool: D39: string a is :%s


tool: D34: string b is :

assistant: ```c
int man() {
  char a[] = "I am a boy.i fear about my future.", b[50];
  int i = 0;
  for (i = 0; *(a + i) != '\0'; i++) {
    *(b + i) = *(a + i);
  }
  *(b + i) = '\0';
  printf("string a is :%s\n", a);
  printf("string b is :");
  for (i = 0; b[i] != '\0'; i++)
    printf("%c", b[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subt_row>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x2c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x2c(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L12
L1:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L12:
  mov    -0x2c(%rbp),%eax
  imul   -0x28(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void subt_row(int init, int term, int order_c, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t1, t;
    t = matrix[i];
    t1 = matrix[i] - matrix[j];
    matrix[i] = t1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<subt_row>:
  endbr64
  sub    $0x1,%edi
  imul   %edx,%edi
  sub    $0x1,%esi
  imul   %edx,%esi
  add    %esi,%edx
  cmp    %edx,%esi
  jge    L12
  movslq %edi,%rdi
  lea    (%rcx,%rdi,8),%rax
  sub    $0x1,%edx
  sub    %esi,%edx
  add    %rdi,%rdx
  lea    0x8(%rcx,%rdx,8),%rcx
  movslq %esi,%rdx
  sub    %rdi,%rdx
L18:
  movsd  (%rax),%xmm0
  subsd  (%rax,%rdx,8),%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L18
L12:
  ret
```

assistant: ```c
void subt_row(int init, int term, int order_c, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t1, t;
    t = matrix[i];
    t1 = matrix[i] - matrix[j];
    matrix[i] = t1;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<subt_row>:
  endbr64
  sub    $0x1,%esi
  sub    $0x1,%edi
  imul   %edx,%esi
  imul   %edx,%edi
  add    %esi,%edx
  cmp    %edx,%esi
  jge    L8
  sub    $0x1,%edx
  movslq %edi,%rdi
  sub    %esi,%edx
  lea    (%rcx,%rdi,8),%rax
  add    %rdi,%rdx
  lea    0x8(%rcx,%rdx,8),%rcx
  movslq %esi,%rdx
  sub    %rdi,%rdx
L7:
  movsd  (%rax),%xmm0
  subsd  (%rax,%rdx,8),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L7
L8:
  ret
```

assistant: ```c
void subt_row(int init, int term, int order_c, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t1, t;
    t = matrix[i];
    t1 = matrix[i] - matrix[j];
    matrix[i] = t1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subt_row>:
  endbr64
  lea    -0x1(%rdi),%eax
  mov    %edx,%r10d
  imul   %edx,%eax
  lea    -0x1(%rsi),%edx
  mov    %edx,%esi
  imul   %r10d,%esi
  lea    (%r10,%rsi,1),%r9d
  cmp    %r9d,%esi
  jge    L52
  movslq %eax,%r11
  push   %rbx
  movslq %esi,%rdi
  lea    -0x1(%r10),%ebx
  mov    %rcx,%r8
  lea    0x0(,%r11,8),%rdx
  mov    %eax,%ecx
  lea    0x8(,%rdi,8),%rax
  cmp    $0x1,%ebx
  jbe    L43
  cmp    %rdx,%rax
  je     L43
  mov    %r10d,%edi
  lea    -0x8(%r8,%rax,1),%r9
  add    %r8,%rdx
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
L21:
  movupd (%rdx,%rax,1),%xmm0
  movupd (%r9,%rax,1),%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L21
  mov    %r10d,%edi
  and    $0xfffffffe,%edi
  lea    (%rcx,%rdi,1),%eax
  lea    (%rsi,%rdi,1),%edx
  cmp    %edi,%r10d
  je     L6
  cltq
  lea    (%r8,%rax,8),%rcx
  movslq %edx,%rax
  movsd  (%rcx),%xmm0
  subsd  (%r8,%rax,8),%xmm0
  movsd  %xmm0,(%rcx)
L6:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L43:
  sub    $0x1,%r9d
  lea    (%r8,%rdx,1),%rax
  sub    %r11,%rdi
  sub    %esi,%r9d
  lea    (%r9,%r11,1),%rdx
  lea    0x8(%r8,%rdx,8),%rdx
  nopw   0x0(%rax,%rax,1)
L53:
  movsd  (%rax),%xmm0
  subsd  (%rax,%rdi,8),%xmm0
  add    $0x8,%rax
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L53
  pop    %rbx
  ret
  nopl   0x0(%rax)
L52:
  ret
```

assistant: ```c
void subt_row(int init, int term, int order_c, double matrix[]) {
  int i, j;
  for (i = ((init - 1) * order_c), j = ((term - 1) * order_c); i <= ((order_c) * (init)) - 1, j <= ((order_c) * (term)) - 1; ++i, ++j) {
    double t1, t;
    t = matrix[i];
    t1 = matrix[i] - matrix[j];
    matrix[i] = t1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flashrom_sector_program>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0xaa,%esi
  mov    $0x5555,%edi
  call   <flashrom_chip_write@plt>
  mov    $0x55,%esi
  mov    $0x2aaa,%edi
  call   <flashrom_chip_write@plt>
  mov    $0xa0,%esi
  mov    $0x5555,%edi
  call   <flashrom_chip_write@plt>
  jmp    L2
L18:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    %edx,%esi
  mov    %eax,%edi
  call   <flashrom_chip_write@plt>
L2:
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  test   %eax,%eax
  jne    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <flashrom_wait_toggle_bit@plt>
  nop
  leave
  ret
```

assistant: ```c
void flashrom_sector_program(unsigned long address, const unsigned char *buffer, unsigned int count) {
  unsigned long prog_address;
  prog_address = address;
  flashrom_chip_write(0x5555, 0xAA);
  flashrom_chip_write(0x2AAA, 0x55);
  flashrom_chip_write(0x5555, 0xA0);
  while (count--) {
    flashrom_chip_write(prog_address++, *(buffer++));
  }
  flashrom_wait_toggle_bit(address);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<flashrom_sector_program>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    $0xaa,%esi
  mov    $0x5555,%edi
  call   <flashrom_chip_write@plt>
  mov    $0x55,%esi
  mov    $0x2aaa,%edi
  call   <flashrom_chip_write@plt>
  mov    $0xa0,%esi
  mov    $0x5555,%edi
  call   <flashrom_chip_write@plt>
  test   %ebx,%ebx
  je     L0
  lea    -0x1(%rbx),%eax
  mov    %eax,%eax
  lea    0x1(%r13,%rax,1),%r12
  mov    %r13,%rbx
  sub    %r13,%rbp
L14:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %ebx,%edi
  call   <flashrom_chip_write@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L14
L0:
  mov    %r13,%rdi
  call   <flashrom_wait_toggle_bit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void flashrom_sector_program(unsigned long address, const unsigned char *buffer, unsigned int count) {
  unsigned long prog_address;
  prog_address = address;
  flashrom_chip_write(0x5555, 0xAA);
  flashrom_chip_write(0x2AAA, 0x55);
  flashrom_chip_write(0x5555, 0xA0);
  while (count--) {
    flashrom_chip_write(prog_address++, *(buffer++));
  }
  flashrom_wait_toggle_bit(address);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flashrom_sector_program>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x5555,%edi
  push   %r12
  mov    %rsi,%r12
  mov    $0xaa,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <flashrom_chip_write@plt>
  mov    $0x55,%esi
  mov    $0x2aaa,%edi
  call   <flashrom_chip_write@plt>
  mov    $0xa0,%esi
  mov    $0x5555,%edi
  call   <flashrom_chip_write@plt>
  test   %ebp,%ebp
  je     L10
  add    %r13,%rbp
  mov    %r13,%rbx
  sub    %r13,%r12
L4:
  movzbl (%r12,%rbx,1),%esi
  mov    %ebx,%edi
  add    $0x1,%rbx
  call   <flashrom_chip_write@plt>
  cmp    %rbp,%rbx
  jne    L4
L10:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <flashrom_wait_toggle_bit@plt>
```

assistant: ```c
void flashrom_sector_program(unsigned long address, const unsigned char *buffer, unsigned int count) {
  unsigned long prog_address;
  prog_address = address;
  flashrom_chip_write(0x5555, 0xAA);
  flashrom_chip_write(0x2AAA, 0x55);
  flashrom_chip_write(0x5555, 0xA0);
  while (count--) {
    flashrom_chip_write(prog_address++, *(buffer++));
  }
  flashrom_wait_toggle_bit(address);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<flashrom_sector_program>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    $0x5555,%edi
  push   %r12
  mov    %rsi,%r12
  mov    $0xaa,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <flashrom_chip_write@plt>
  mov    $0x55,%esi
  mov    $0x2aaa,%edi
  call   <flashrom_chip_write@plt>
  mov    $0xa0,%esi
  mov    $0x5555,%edi
  call   <flashrom_chip_write@plt>
  test   %ebp,%ebp
  je     L9
  add    %r13,%rbp
  mov    %r13,%rbx
  sub    %r13,%r12
L15:
  movzbl (%r12,%rbx,1),%esi
  mov    %ebx,%edi
  add    $0x1,%rbx
  call   <flashrom_chip_write@plt>
  cmp    %rbp,%rbx
  jne    L15
L9:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <flashrom_wait_toggle_bit@plt>
```

assistant: ```c
void flashrom_sector_program(unsigned long address, const unsigned char *buffer, unsigned int count) {
  unsigned long prog_address;
  prog_address = address;
  flashrom_chip_write(0x5555, 0xAA);
  flashrom_chip_write(0x2AAA, 0x55);
  flashrom_chip_write(0x5555, 0xA0);
  while (count--) {
    flashrom_chip_write(prog_address++, *(buffer++));
  }
  flashrom_wait_toggle_bit(address);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L22
L0:
  addq   $0x1,-0x8(%rbp)
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L5
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L0
L5:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_chars(char *in_line) {
  while (in_line[0] && (!isspace(in_line[0])))
    in_line++;
  return in_line;
}
```
user: What is the c source code of the assembly code below:

```asm
<skip_chars>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    %rbx,%rax
  test   %dil,%dil
  je     L25
L13:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L33
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L13
  mov    %rbx,%rax
  jmp    L25
L33:
  mov    %rbx,%rax
L25:
  pop    %rbx
  ret
```

assistant: ```c
char *skip_chars(char *in_line) {
  while (in_line[0] && (!isspace(in_line[0])))
    in_line++;
  return in_line;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skip_chars>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L28
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L11:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L24
L28:
  call   <isspace@plt>
  test   %eax,%eax
  je     L11
L24:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_chars(char *in_line) {
  while (in_line[0] && (!isspace(in_line[0])))
    in_line++;
  return in_line;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skip_chars>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L31
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L22:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L0
L31:
  call   <isspace@plt>
  test   %eax,%eax
  je     L22
L0:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_chars(char *in_line) {
  while (in_line[0] && (!isspace(in_line[0])))
    in_line++;
  return in_line;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x5,%edi
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D85(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D83(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D95(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdx
  mov    $0x2c,%esi
  mov    $0x1,%edi
  call   <ACUTE_assert@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdx
  mov    $0x2d,%esi
  mov    $0x0,%edi
  call   <ACUTE_assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  lea    D53(%rip),%rdx
  mov    $0x2f,%esi
  mov    %eax,%edi
  call   <ACUTE_assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  lea    D41(%rip),%rdx
  mov    $0x30,%esi
  mov    %eax,%edi
  call   <ACUTE_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D65
datatype: string
name: parse_data
arguments: label: D85
datatype: string
name: parse_data
arguments: label: D83
datatype: string
name: parse_data
arguments: label: D9
datatype: string
name: parse_data
arguments: label: D95
datatype: string
name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D53
datatype: string
name: parse_data
arguments: label: D41
datatype: string

tool: D65: Size of char = %d


tool: D85: Size of int = %d


tool: D83: Size of short = %d


tool: D9: Size of long = %d


tool: D95: Size of double = %d


tool: D24: Size of float = %d


tool: D1: ACUTE Exception: Condition has not been met

tool: D53: ACUTE Exception: Pointer is NOT Null

tool: D41: ACUTE Exception: Pointer is NULL

assistant: ```c
int main(int argc, char **argv) {
  char *cPointer = NULL;
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  ACUTE_assert((2 > 0), 44, "ACUTE Exception: Condition has not been met");
  ACUTE_assert((2 < 0), 45, "ACUTE Exception: Condition has not been met");
  ACUTE_assert((cPointer == NULL), 47, "ACUTE Exception: Pointer is NOT Null");
  ACUTE_assert((cPointer != NULL), 48, "ACUTE Exception: Pointer is NULL");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x5,%edi
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D81(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rbx
  mov    %rbx,%rdx
  mov    $0x2c,%esi
  mov    $0x1,%edi
  call   <ACUTE_assert@plt>
  mov    %rbx,%rdx
  mov    $0x2d,%esi
  mov    $0x0,%edi
  call   <ACUTE_assert@plt>
  lea    D37(%rip),%rdx
  mov    $0x2f,%esi
  mov    $0x1,%edi
  call   <ACUTE_assert@plt>
  lea    D23(%rip),%rdx
  mov    $0x30,%esi
  mov    $0x0,%edi
  call   <ACUTE_assert@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D35
datatype: string
name: unpack_data
arguments: data_label: D62
datatype: string
name: unpack_data
arguments: data_label: D59
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D81
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string
name: unpack_data
arguments: data_label: D12
datatype: string
name: unpack_data
arguments: data_label: D37
datatype: string
name: unpack_data
arguments: data_label: D23
datatype: string

tool: D35: Size of char = %d


tool: D62: Size of int = %d


tool: D59: Size of short = %d


tool: D14: Size of long = %d


tool: D81: Size of double = %d


tool: D15: Size of float = %d


tool: D12: ACUTE Exception: Condition has not been met

tool: D37: ACUTE Exception: Pointer is NOT Null

tool: D23: ACUTE Exception: Pointer is NULL

assistant: ```c
int main(int argc, char **argv) {
  char *cPointer = NULL;
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  ACUTE_assert((2 > 0), 44, "ACUTE Exception: Condition has not been met");
  ACUTE_assert((2 < 0), 45, "ACUTE Exception: Condition has not been met");
  ACUTE_assert((cPointer == NULL), 47, "ACUTE Exception: Pointer is NOT Null");
  ACUTE_assert((cPointer != NULL), 48, "ACUTE Exception: Pointer is NULL");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edi
  lea    D48(%rip),%r12
  call   <test_variable_args@plt>
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D62(%rip),%rdi
  call   <printf@plt>
  mov    $0x2,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D76(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdx
  mov    $0x2c,%esi
  mov    $0x1,%edi
  call   <ACUTE_assert@plt>
  mov    %r12,%rdx
  mov    $0x2d,%esi
  xor    %edi,%edi
  call   <ACUTE_assert@plt>
  mov    $0x2f,%esi
  mov    $0x1,%edi
  lea    D7(%rip),%rdx
  call   <ACUTE_assert@plt>
  lea    D59(%rip),%rdx
  mov    $0x30,%esi
  xor    %edi,%edi
  call   <ACUTE_assert@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D48
type: string
name: read_data
arguments: data_label: D4
type: string
name: read_data
arguments: data_label: D62
type: string
name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D76
type: string
name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D24
type: string
name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D59
type: string

tool: D48: ACUTE Exception: Condition has not been met

tool: D4: Size of char = %d


tool: D62: Size of int = %d


tool: D16: Size of short = %d


tool: D76: Size of long = %d


tool: D1: Size of double = %d


tool: D24: Size of float = %d


tool: D7: ACUTE Exception: Pointer is NOT Null

tool: D59: ACUTE Exception: Pointer is NULL

assistant: ```c
int main(int argc, char **argv) {
  char *cPointer = NULL;
  test_variable_args(5);
  printf("Size of char = %d\n", sizeof(char));
  printf("Size of int = %d\n", sizeof(int));
  printf("Size of short = %d\n", sizeof(short));
  printf("Size of long = %d\n", sizeof(long));
  printf("Size of double = %d\n", sizeof(double));
  printf("Size of float = %d\n", sizeof(float));
  ACUTE_assert((2 > 0), 44, "ACUTE Exception: Condition has not been met");
  ACUTE_assert((2 < 0), 45, "ACUTE Exception: Condition has not been met");
  ACUTE_assert((cPointer == NULL), 47, "ACUTE Exception: Pointer is NOT Null");
  ACUTE_assert((cPointer != NULL), 48, "ACUTE Exception: Pointer is NULL");
  return 0;
}
```