ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uart_init_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0xdac0,-0x18(%rbp)
  je     L86
  cmpl   $0xdac0,-0x18(%rbp)
  jg     L215
  cmpl   $0x9600,-0x18(%rbp)
  je     L12
  cmpl   $0x9600,-0x18(%rbp)
  jg     L215
  cmpl   $0x4b00,-0x18(%rbp)
  je     L186
  cmpl   $0x4b00,-0x18(%rbp)
  jg     L215
  cmpl   $0x2580,-0x18(%rbp)
  je     L63
  cmpl   $0x2580,-0x18(%rbp)
  jg     L215
  cmpl   $0x12c0,-0x18(%rbp)
  je     L70
  cmpl   $0x12c0,-0x18(%rbp)
  jg     L215
  cmpl   $0x960,-0x18(%rbp)
  je     L65
  cmpl   $0x960,-0x18(%rbp)
  jg     L215
  cmpl   $0x4b0,-0x18(%rbp)
  je     L265
  cmpl   $0x4b0,-0x18(%rbp)
  jg     L215
  cmpl   $0x96,-0x18(%rbp)
  je     L38
  cmpl   $0x12c,-0x18(%rbp)
  je     L278
  jmp    L215
L86:
  movl   $0x2,-0x4(%rbp)
  jmp    L224
L12:
  movl   $0x3,-0x4(%rbp)
  jmp    L224
L186:
  movl   $0x6,-0x4(%rbp)
  jmp    L224
L63:
  movl   $0xc,-0x4(%rbp)
  jmp    L224
L70:
  movl   $0x18,-0x4(%rbp)
  jmp    L224
L65:
  movl   $0x30,-0x4(%rbp)
  jmp    L224
L265:
  movl   $0x60,-0x4(%rbp)
  jmp    L224
L278:
  movl   $0x180,-0x4(%rbp)
  jmp    L224
L38:
  movl   $0x300,-0x4(%rbp)
  jmp    L224
L215:
  movl   $0xc,-0x4(%rbp)
  nop
L224:
  mov    -0x14(%rbp),%eax
  add    $0x2fb,%eax
  mov    %eax,%esi
  mov    $0x87,%edi
  call   <outb@plt>
  mov    -0x14(%rbp),%eax
  add    $0x2f9,%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <outb@plt>
  mov    -0x14(%rbp),%eax
  lea    0x2f8(%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <outb@plt>
  mov    -0x14(%rbp),%eax
  add    $0x2fb,%eax
  mov    %eax,%esi
  mov    $0x7,%edi
  call   <outb@plt>
  mov    -0x14(%rbp),%eax
  add    $0x2fc,%eax
  mov    %eax,%esi
  mov    $0xf,%edi
  call   <outb@plt>
  movl   $0xa,-0x8(%rbp)
  jmp    L246
L106:
  mov    -0x14(%rbp),%eax
  add    $0x2fd,%eax
  mov    %eax,%edi
  call   <inb@plt>
  test   %rax,%rax
  je     L251
  mov    -0x14(%rbp),%eax
  add    $0x2f8,%eax
  mov    %eax,%edi
  call   <inb@plt>
  subl   $0x1,-0x8(%rbp)
L246:
  cmpl   $0x0,-0x8(%rbp)
  jg     L106
  jmp    L8
L251:
  nop
L8:
  nop
  leave
  ret
```

assistant: ```c
void uart_init_line(int offset, int baud) {
  int i;
  int baudconst;
  switch (baud) {
  case 56000:
    baudconst = 2;
    break;
  case 38400:
    baudconst = 3;
    break;
  case 19200:
    baudconst = 6;
    break;
  case 9600:
    baudconst = 12;
    break;
  case 4800:
    baudconst = 24;
    break;
  case 2400:
    baudconst = 48;
    break;
  case 1200:
    baudconst = 96;
    break;
  case 300:
    baudconst = 384;
    break;
  case 150:
    baudconst = 768;
    break;
  default:
    baudconst = 12;
    break;
  }
  outb(0x87, 0x2fb + offset);
  outb(0, 0x2f9 + offset);
  outb(baudconst, 0x2f8 + offset);
  outb(0x07, 0x2fb + offset);
  outb(0x0F, 0x2fc + offset);
  for (i = 10; i > 0; i--) {
    if (inb(0x2fd + offset) == 0)
      break;
    inb(0x2f8 + offset);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<uart_init_line>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  cmp    $0x12c0,%esi
  je     L0
  jle    L105
  mov    $0x3,%ebx
  cmp    $0x9600,%esi
  je     L30
  jle    L61
  cmp    $0xdac0,%esi
  mov    $0xc,%ebx
  mov    $0x2,%eax
  cmove  %eax,%ebx
  jmp    L30
L105:
  mov    $0x60,%ebx
  cmp    $0x4b0,%esi
  je     L30
  jle    L118
  cmp    $0x960,%esi
  mov    $0xc,%ebx
  mov    $0x30,%eax
  cmove  %eax,%ebx
  jmp    L30
L118:
  mov    $0x300,%ebx
  cmp    $0x96,%esi
  je     L30
  cmp    $0x12c,%esi
  mov    $0xc,%ebx
  mov    $0x180,%eax
  cmove  %eax,%ebx
L30:
  lea    0x2fb(%rbp),%r13d
  mov    %r13d,%esi
  mov    $0x87,%edi
  call   <outb@plt>
  lea    0x2f9(%rbp),%esi
  mov    $0x0,%edi
  call   <outb@plt>
  lea    0x2f8(%rbp),%r12d
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <outb@plt>
  mov    %r13d,%esi
  mov    $0x7,%edi
  call   <outb@plt>
  lea    0x2fc(%rbp),%esi
  mov    $0xf,%edi
  call   <outb@plt>
  mov    $0xa,%ebx
  add    $0x2fd,%ebp
L32:
  mov    %ebp,%edi
  call   <inb@plt>
  test   %rax,%rax
  je     L33
  mov    %r12d,%edi
  call   <inb@plt>
  sub    $0x1,%ebx
  jne    L32
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L61:
  cmp    $0x4b00,%esi
  mov    $0x6,%ebx
  mov    $0xc,%eax
  cmovne %eax,%ebx
  jmp    L30
L0:
  mov    $0x18,%ebx
  jmp    L30
```

assistant: ```c
void uart_init_line(int offset, int baud) {
  int i;
  int baudconst;
  switch (baud) {
  case 56000:
    baudconst = 2;
    break;
  case 38400:
    baudconst = 3;
    break;
  case 19200:
    baudconst = 6;
    break;
  case 9600:
    baudconst = 12;
    break;
  case 4800:
    baudconst = 24;
    break;
  case 2400:
    baudconst = 48;
    break;
  case 1200:
    baudconst = 96;
    break;
  case 300:
    baudconst = 384;
    break;
  case 150:
    baudconst = 768;
    break;
  default:
    baudconst = 12;
    break;
  }
  outb(0x87, 0x2fb + offset);
  outb(0, 0x2f9 + offset);
  outb(baudconst, 0x2f8 + offset);
  outb(0x07, 0x2fb + offset);
  outb(0x0F, 0x2fc + offset);
  for (i = 10; i > 0; i--) {
    if (inb(0x2fd + offset) == 0)
      break;
    inb(0x2f8 + offset);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<uart_init_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  cmp    $0x12c0,%esi
  je     L67
  jg     L127
  cmp    $0x4b0,%esi
  je     L114
  jle    L94
  cmp    $0x960,%esi
  mov    $0xc,%r12d
  mov    $0x30,%eax
  cmove  %eax,%r12d
L59:
  lea    0x2fb(%rbp),%r14d
  mov    $0x87,%edi
  mov    $0xa,%ebx
  mov    %r14d,%esi
  lea    0x2f8(%rbp),%r13d
  call   <outb@plt>
  lea    0x2f9(%rbp),%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <outb@plt>
  mov    %r14d,%esi
  mov    $0x7,%edi
  call   <outb@plt>
  lea    0x2fc(%rbp),%esi
  mov    $0xf,%edi
  add    $0x2fd,%ebp
  call   <outb@plt>
  nopw   0x0(%rax,%rax,1)
L70:
  mov    %ebp,%edi
  call   <inb@plt>
  test   %rax,%rax
  je     L73
  mov    %r13d,%edi
  call   <inb@plt>
  sub    $0x1,%ebx
  jne    L70
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L94:
  mov    $0x300,%r12d
  cmp    $0x96,%esi
  je     L59
  cmp    $0x12c,%esi
  mov    $0xc,%r12d
  mov    $0x180,%eax
  cmove  %eax,%r12d
  jmp    L59
  nopl   0x0(%rax)
L127:
  mov    $0x3,%r12d
  cmp    $0x9600,%esi
  je     L59
  mov    $0x2,%r12d
  cmp    $0xdac0,%esi
  je     L59
  cmp    $0x4b00,%esi
  mov    $0xc,%r12d
  mov    $0x6,%eax
  cmove  %eax,%r12d
  jmp    L59
  xchg   %ax,%ax
L114:
  mov    $0x60,%r12d
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L67:
  mov    $0x18,%r12d
  jmp    L59
```

assistant: ```c
void uart_init_line(int offset, int baud) {
  int i;
  int baudconst;
  switch (baud) {
  case 56000:
    baudconst = 2;
    break;
  case 38400:
    baudconst = 3;
    break;
  case 19200:
    baudconst = 6;
    break;
  case 9600:
    baudconst = 12;
    break;
  case 4800:
    baudconst = 24;
    break;
  case 2400:
    baudconst = 48;
    break;
  case 1200:
    baudconst = 96;
    break;
  case 300:
    baudconst = 384;
    break;
  case 150:
    baudconst = 768;
    break;
  default:
    baudconst = 12;
    break;
  }
  outb(0x87, 0x2fb + offset);
  outb(0, 0x2f9 + offset);
  outb(baudconst, 0x2f8 + offset);
  outb(0x07, 0x2fb + offset);
  outb(0x0F, 0x2fc + offset);
  for (i = 10; i > 0; i--) {
    if (inb(0x2fd + offset) == 0)
      break;
    inb(0x2f8 + offset);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<uart_init_line>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  cmp    $0x12c0,%esi
  je     L74
  jg     L39
  cmp    $0x4b0,%esi
  je     L34
  jle    L129
  cmp    $0x960,%esi
  mov    $0xc,%r12d
  mov    $0x30,%eax
  cmove  %eax,%r12d
L32:
  lea    0x2fb(%rbp),%r14d
  mov    $0x87,%edi
  mov    $0xa,%ebx
  mov    %r14d,%esi
  lea    0x2f8(%rbp),%r13d
  call   <outb@plt>
  lea    0x2f9(%rbp),%esi
  xor    %edi,%edi
  call   <outb@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <outb@plt>
  mov    %r14d,%esi
  mov    $0x7,%edi
  call   <outb@plt>
  lea    0x2fc(%rbp),%esi
  mov    $0xf,%edi
  add    $0x2fd,%ebp
  call   <outb@plt>
  nopw   0x0(%rax,%rax,1)
L107:
  mov    %ebp,%edi
  call   <inb@plt>
  test   %rax,%rax
  je     L9
  mov    %r13d,%edi
  call   <inb@plt>
  sub    $0x1,%ebx
  jne    L107
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L129:
  mov    $0x300,%r12d
  cmp    $0x96,%esi
  je     L32
  cmp    $0x12c,%esi
  mov    $0xc,%r12d
  mov    $0x180,%eax
  cmove  %eax,%r12d
  jmp    L32
  nopl   0x0(%rax)
L39:
  mov    $0x3,%r12d
  cmp    $0x9600,%esi
  je     L32
  mov    $0x2,%r12d
  cmp    $0xdac0,%esi
  je     L32
  cmp    $0x4b00,%esi
  mov    $0xc,%r12d
  mov    $0x6,%eax
  cmove  %eax,%r12d
  jmp    L32
  xchg   %ax,%ax
L34:
  mov    $0x60,%r12d
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L74:
  mov    $0x18,%r12d
  jmp    L32
```

assistant: ```c
void uart_init_line(int offset, int baud) {
  int i;
  int baudconst;
  switch (baud) {
  case 56000:
    baudconst = 2;
    break;
  case 38400:
    baudconst = 3;
    break;
  case 19200:
    baudconst = 6;
    break;
  case 9600:
    baudconst = 12;
    break;
  case 4800:
    baudconst = 24;
    break;
  case 2400:
    baudconst = 48;
    break;
  case 1200:
    baudconst = 96;
    break;
  case 300:
    baudconst = 384;
    break;
  case 150:
    baudconst = 768;
    break;
  default:
    baudconst = 12;
    break;
  }
  outb(0x87, 0x2fb + offset);
  outb(0, 0x2f9 + offset);
  outb(baudconst, 0x2f8 + offset);
  outb(0x07, 0x2fb + offset);
  outb(0x0F, 0x2fc + offset);
  for (i = 10; i > 0; i--) {
    if (inb(0x2fd + offset) == 0)
      break;
    inb(0x2f8 + offset);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L8
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L6
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L6:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strbase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L24
L0:
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L78
L48:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    D3(%rip),%rcx
  movzbl (%rdx,%rcx,1),%edx
  cmp    %dl,%al
  jne    L45
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L45:
  addl   $0x1,-0xc(%rbp)
L78:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L48
L6:
  cmpl   $0x0,-0x8(%rbp)
  js     L10
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L7
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L0
  jmp    L7
L10:
  nop
L7:
  mov    -0x38(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: 0123456789ABCDEF

assistant: ```c
int strbase(char *str, int base, int max, int *skip) {
  int i, ret = 0, len = strlen(str);
  for (i = 0; i < len && i < max; i++) {
    int j, digit = -1;
    for (j = 0; j < base; j++) {
      if (toupper(str[i]) == "0123456789ABCDEF"[j]) {
        digit = j;
        break;
      }
    }
    if (digit < 0)
      break;
    ret = (ret * base) + digit;
  }
  *skip = i;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strbase>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %esi,0xc(%rsp)
  mov    %edx,%ebx
  mov    %rcx,0x18(%rsp)
  call   <strlen@plt>
  cmp    %ebx,%eax
  cmovle %eax,%ebx
  mov    %ebx,0x14(%rsp)
  test   %ebx,%ebx
  jle    L82
  movl   $0x0,0x10(%rsp)
  mov    $0x0,%r15d
  lea    D7(%rip),%r14
  jmp    L14
L41:
  test   %ebx,%ebx
  js     L73
  mov    0x10(%rsp),%eax
  imul   0xc(%rsp),%eax
  add    %ebx,%eax
  mov    %eax,0x10(%rsp)
  add    $0x1,%r15d
  add    $0x1,%rbp
  cmp    0x14(%rsp),%r15d
  je     L48
L14:
  cmpl   $0x0,0xc(%rsp)
  jle    L24
  mov    0xc(%rsp),%r13d
  mov    $0x0,%ebx
L50:
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  cmp    (%r14,%rbx,1),%al
  je     L41
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L50
L24:
  mov    %r15d,0x14(%rsp)
L48:
  mov    0x18(%rsp),%rax
  mov    0x14(%rsp),%ecx
  mov    %ecx,(%rax)
  mov    0x10(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L82:
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  jmp    L48
L73:
  mov    %r15d,0x14(%rsp)
  jmp    L48
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: 0123456789ABCDEF

assistant: ```c
int strbase(char *str, int base, int max, int *skip) {
  int i, ret = 0, len = strlen(str);
  for (i = 0; i < len && i < max; i++) {
    int j, digit = -1;
    for (j = 0; j < base; j++) {
      if (toupper(str[i]) == "0123456789ABCDEF"[j]) {
        digit = j;
        break;
      }
    }
    if (digit < 0)
      break;
    ret = (ret * base) + digit;
  }
  *skip = i;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strbase>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    D3(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  call   <strlen@plt>
  movl   $0x0,0x10(%rsp)
  cmp    %ebp,%eax
  movl   $0x0,0xc(%rsp)
  cmovle %eax,%ebp
  mov    %ebp,0x14(%rsp)
  test   %ebp,%ebp
  jle    L38
  nopl   0x0(%rax,%rax,1)
L2:
  test   %r14d,%r14d
  jle    L38
  movslq %r14d,%r12
  xor    %r15d,%r15d
  jmp    L35
  nopl   (%rax)
L50:
  add    $0x1,%r15
  cmp    %r12,%r15
  je     L38
L35:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    0x0(%r13,%r15,1),%al
  jne    L50
  mov    0x10(%rsp),%eax
  addl   $0x1,0xc(%rsp)
  add    $0x1,%rbx
  imul   %r14d,%eax
  add    %r15d,%eax
  mov    %eax,0x10(%rsp)
  mov    0xc(%rsp),%eax
  cmp    0x14(%rsp),%eax
  jne    L2
L38:
  mov    0x18(%rsp),%rax
  mov    0xc(%rsp),%ecx
  mov    %ecx,(%rax)
  mov    0x10(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
datatype: string

tool: D3: 0123456789ABCDEF

assistant: ```c
int strbase(char *str, int base, int max, int *skip) {
  int i, ret = 0, len = strlen(str);
  for (i = 0; i < len && i < max; i++) {
    int j, digit = -1;
    for (j = 0; j < base; j++) {
      if (toupper(str[i]) == "0123456789ABCDEF"[j]) {
        digit = j;
        break;
      }
    }
    if (digit < 0)
      break;
    ret = (ret * base) + digit;
  }
  *skip = i;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strbase>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %rcx,0x18(%rsp)
  call   <strlen@plt>
  movl   $0x0,0x10(%rsp)
  cmp    %ebp,%eax
  movl   $0x0,0xc(%rsp)
  cmovle %eax,%ebp
  mov    %ebp,0x14(%rsp)
  test   %ebp,%ebp
  jle    L27
  nopl   0x0(%rax,%rax,1)
L50:
  test   %r14d,%r14d
  jle    L27
  movslq %r14d,%r12
  xor    %r15d,%r15d
  jmp    L17
  nopl   (%rax)
L42:
  add    $0x1,%r15
  cmp    %r12,%r15
  je     L27
L17:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    0x0(%r13,%r15,1),%al
  jne    L42
  mov    0x10(%rsp),%eax
  addl   $0x1,0xc(%rsp)
  add    $0x1,%rbx
  imul   %r14d,%eax
  add    %r15d,%eax
  mov    %eax,0x10(%rsp)
  mov    0xc(%rsp),%eax
  cmp    0x14(%rsp),%eax
  jne    L50
L27:
  mov    0x18(%rsp),%rax
  mov    0xc(%rsp),%ecx
  mov    %ecx,(%rax)
  mov    0x10(%rsp),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_infered: string

tool: D7: 0123456789ABCDEF

assistant: ```c
int strbase(char *str, int base, int max, int *skip) {
  int i, ret = 0, len = strlen(str);
  for (i = 0; i < len && i < max; i++) {
    int j, digit = -1;
    for (j = 0; j < base; j++) {
      if (toupper(str[i]) == "0123456789ABCDEF"[j]) {
        digit = j;
        break;
      }
    }
    if (digit < 0)
      break;
    ret = (ret * base) + digit;
  }
  *skip = i;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <PrintSmallLetters@plt>
  mov    $0x0,%eax
  call   <PrintBigLetters@plt>
  mov    $0x0,%eax
  call   <PrintDigits@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  PrintSmallLetters();
  PrintBigLetters();
  PrintDigits();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <PrintSmallLetters@plt>
  mov    $0x0,%eax
  call   <PrintBigLetters@plt>
  mov    $0x0,%eax
  call   <PrintDigits@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  PrintSmallLetters();
  PrintBigLetters();
  PrintDigits();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PrintSmallLetters@plt>
  xor    %eax,%eax
  call   <PrintBigLetters@plt>
  xor    %eax,%eax
  call   <PrintDigits@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  PrintSmallLetters();
  PrintBigLetters();
  PrintDigits();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PrintSmallLetters@plt>
  xor    %eax,%eax
  call   <PrintBigLetters@plt>
  xor    %eax,%eax
  call   <PrintDigits@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  PrintSmallLetters();
  PrintBigLetters();
  PrintDigits();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crc32_update_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L18:
  mov    -0x18(%rbp),%eax
  and    $0x1,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <crc32_update_bit@plt>
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
  sarl   -0x18(%rbp)
L8:
  cmpl   $0x7,-0x4(%rbp)
  jle    L18
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t crc32_update_byte(uint32_t remainder, uint8_t next_byte) {
  for (int j = 0; j < 8; j++, next_byte >>= 1)
    remainder = crc32_update_bit(remainder, next_byte & 1);
  return remainder;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<crc32_update_byte>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebx
  mov    $0x8,%ebp
L0:
  mov    %ebx,%esi
  and    $0x1,%esi
  call   <crc32_update_bit@plt>
  mov    %eax,%edi
  sar    %ebx
  sub    $0x1,%ebp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t crc32_update_byte(uint32_t remainder, uint8_t next_byte) {
  for (int j = 0; j < 8; j++, next_byte >>= 1)
    remainder = crc32_update_bit(remainder, next_byte & 1);
  return remainder;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<crc32_update_byte>:
  endbr64
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L0:
  mov    %ebx,%esi
  sar    %ebx
  and    $0x1,%esi
  call   <crc32_update_bit@plt>
  mov    %eax,%edi
  sub    $0x1,%ebp
  jne    L0
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t crc32_update_byte(uint32_t remainder, uint8_t next_byte) {
  for (int j = 0; j < 8; j++, next_byte >>= 1)
    remainder = crc32_update_bit(remainder, next_byte & 1);
  return remainder;
}
```
user: Translate the below assembly code into C programming language:

```asm
<crc32_update_byte>:
  endbr64
  push   %rbp
  mov    $0x8,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L3:
  mov    %ebx,%esi
  sar    %ebx
  and    $0x1,%esi
  call   <crc32_update_bit@plt>
  mov    %eax,%edi
  sub    $0x1,%ebp
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t crc32_update_byte(uint32_t remainder, uint8_t next_byte) {
  for (int j = 0; j < 8; j++, next_byte >>= 1)
    remainder = crc32_update_bit(remainder, next_byte & 1);
  return remainder;
}
```