user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  lea    D152(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edx
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  movss  D100(%rip),%xmm9
  movsd  D40(%rip),%xmm8
  movss  D119(%rip),%xmm7
  movaps %xmm9,%xmm6
  movapd %xmm8,%xmm5
  movss  D97(%rip),%xmm4
  movaps %xmm9,%xmm3
  movapd %xmm8,%xmm2
  movss  D62(%rip),%xmm1
  jmp    L140
L14:
  addss  %xmm4,%xmm0
  subss  %xmm3,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm2,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    %edx,%esi
  add    $0x1,%eax
L152:
  add    $0x1,%edx
  comiss %xmm0,%xmm1
  jbe    L129
L140:
  cmp    $0x1,%eax
  je     L14
  cmp    $0x5,%eax
  jne    L105
  subss  %xmm7,%xmm0
  subss  %xmm6,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm5,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    %edx,%esi
  mov    $0x6,%eax
  jmp    L152
L105:
  subss  %xmm9,%xmm0
  cvtss2sd %xmm0,%xmm0
  mulsd  %xmm8,%xmm0
  cvtsd2ss %xmm0,%xmm0
  mov    %edx,%esi
  add    $0x1,%eax
  cmp    $0x1f,%eax
  jne    L152
  mov    $0x1,%eax
  jmp    L152
L129:
  movslq %esi,%rax
  imul   $0xffffffffb38cf9b1,%rax,%rcx
  shr    $0x20,%rcx
  add    %esi,%ecx
  sar    $0x8,%ecx
  mov    %esi,%edi
  sar    $0x1f,%edi
  sub    %edi,%ecx
  imul   $0xffffffff88888889,%rax,%rdx
  shr    $0x20,%rdx
  add    %esi,%edx
  sar    $0x4,%edx
  sub    %edi,%edx
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1c41,%edx
  mov    $0x14dc,%esi
  lea    D79(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1c41,%eax
  mov    $0x14dc,%ebx
  jmp    L2
L92:
  sub    %ebx,%eax
L139:
  cmp    %ebx,%eax
  je     L78
L2:
  cmp    %eax,%ebx
  jle    L92
  sub    %eax,%ebx
  jmp    L139
L78:
  mov    %ebx,%esi
  lea    D158(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x1,%ebx
  je     L54
L161:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x2,%esi
  mov    $0x7,%ecx
L116:
  add    $0x1,%esi
  mov    %ecx,%eax
  cltd
  idiv   %esi
  test   %edx,%edx
  je     L119
  cmp    $0x6,%esi
  jle    L116
L119:
  cmp    $0x7,%esi
  je     L82
  mov    $0x7,%edx
  lea    D99(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L145:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x10e5,%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  mov    $0x0,%esi
  mov    $0x10e5,%edx
L148:
  lea    (%rsi,%rsi,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%esi
  mov    %eax,%edx
  sub    $0x1,%edi
  jne    L148
  lea    D158(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L54:
  lea    D142(%rip),%rdi
  call   <puts@plt>
  jmp    L161
L82:
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L145
```

tool_calls: name: retrieve_data
arguments: tag: D152
type_guessed: string
name: retrieve_data
arguments: tag: D100
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D40
type_guessed: f64
name: retrieve_data
arguments: tag: D119
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D97
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D62
type_guessed: byte[4]
name: retrieve_data
arguments: tag: D19
type_guessed: string
name: retrieve_data
arguments: tag: D8
type_guessed: string
name: retrieve_data
arguments: tag: D79
type_guessed: string
name: retrieve_data
arguments: tag: D158
type_guessed: string
name: retrieve_data
arguments: tag: D99
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D142
type_guessed: string
name: retrieve_data
arguments: tag: D50
type_guessed: string

tool: D152: Problema do milionario:

tool: {"D100": [0x00,0x00,0x20,0x41]}

tool: D40: 1.001

tool: {"D119": [0x00,0x00,0x16,0x43]}

tool: {"D97": [0x00,0x00,0xfa,0x43]}

tool: {"D62": [0x00,0x24,0x74,0x49]}

tool: D19: Em %d dias (%d meses, %d anos) ficarei milionario!


tool: D8: ----

tool: D79: MDC(%d, %d)=

tool: D158: %d


tool: D99: %d eh divisor de %d


tool: D15: Vou inverter %d: 

tool: D142: Primos entre si!

tool: D50: %d eh primo!


assistant: ```c
int main() {
  printf("Problema do milionario:\n");
  int contar_dias = 0;
  int dia = 1;
  float conta = 0;
  while (conta < 1000000) {
    if (dia == 1) {
      conta = conta + 500;
    }
    if (dia == 5) {
      conta = conta - 150;
    }
    conta = conta - 10;
    conta = conta * 1.001;
    contar_dias = contar_dias + 1;
    dia = dia + 1;
    if (dia == 31) {
      dia = 1;
    }
  }
  printf("Em %d dias (%d meses, %d anos) ficarei milionario!\n", contar_dias, contar_dias / 30, contar_dias / 365);
  printf("----\n");
  int A, B;
  A = 5340;
  B = 7233;
  printf("MDC(%d, %d)=", A, B);
  while (A != B) {
    if (A > B)
      A = A - B;
    else
      B = B - A;
  }
  printf("%d\n", A);
  if (A == 1)
    printf("Primos entre si!\n");
  printf("----\n");
  A = 7;
  B = 2;
  while (((A % B) != 0) && (B < A)) {
    B = B + 1;
  }
  if (B == A) {
    printf("%d eh primo!\n", A);
  } else {
    printf("%d eh divisor de %d\n", B, A);
  }
  printf("----\n");
  A = 4325;
  B = 0;
  printf("Vou inverter %d: ", A);
  while (A > 0) {
    B = (B * 10) + (A % 10);
    A = A / 10;
  }
  printf("%d\n", B);
  printf("----\n");
  return 0;
}
```