ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<skipWhitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L19
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L19:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void skipWhitespace(const unsigned char **cp) {
  while (isspace(**cp)) {
    ++*cp;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<skipWhitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L15
L0:
  addq   $0x1,(%rbx)
L15:
  mov    (%rbx),%rax
  movzbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void skipWhitespace(const unsigned char **cp) {
  while (isspace(**cp)) {
    ++*cp;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipWhitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  jmp    L0
  nopl   (%rax)
L4:
  mov    (%rbx),%rax
  add    $0x1,%rax
  mov    %rax,(%rbx)
L0:
  movzbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void skipWhitespace(const unsigned char **cp) {
  while (isspace(**cp)) {
    ++*cp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<skipWhitespace>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rax
  jmp    L9
  nopl   (%rax)
L2:
  mov    (%rbx),%rax
  add    $0x1,%rax
  mov    %rax,(%rbx)
L9:
  movzbl (%rax),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
void skipWhitespace(const unsigned char **cp) {
  while (isspace(**cp)) {
    ++*cp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  nop
L0:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t i = 0;
  while (s[i++] != 0)
    ;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  mov    $0x0,%eax
L9:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L9
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t i = 0;
  while (s[i++] != 0)
    ;
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L6
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t i = 0;
  while (s[i++] != 0)
    ;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strlen>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L1
  ret
```

assistant: ```c
size_t strlen(const char *s) {
  size_t i = 0;
  while (s[i++] != 0)
    ;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L33
L19:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x10(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L6
  mov    -0x10(%rbp),%eax
  add    %eax,-0xc(%rbp)
L6:
  addl   $0x1,-0x10(%rbp)
L33:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L19
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
datatype: string

tool: D9: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      shit += i;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L26
  lea    0x1(%rdi),%r8d
  mov    $0x0,%esi
  mov    $0x1,%ecx
L4:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L4
L9:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  mov    $0x0,%esi
  jmp    L9
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      shit += i;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L13
  lea    0x1(%rdi),%r8d
  xor    %esi,%esi
  mov    $0x1,%ecx
L10:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L10
L11:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  xor    %esi,%esi
  jmp    L11
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
type: string

tool: D1: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      shit += i;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L18
  lea    0x1(%rdi),%r8d
  xor    %esi,%esi
  mov    $0x1,%ecx
L0:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  lea    (%rsi,%rcx,1),%eax
  test   %edx,%edx
  cmove  %eax,%esi
  add    $0x1,%ecx
  cmp    %ecx,%r8d
  jne    L0
L25:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L18:
  xor    %esi,%esi
  jmp    L25
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: %i

assistant: ```c
int main(int argc, const char *argv[]) {
  int x, i, shit = 0;
  scanf("%i", &x);
  for (i = 1; i <= x; ++i) {
    if (!(x % i)) {
      shit += i;
    }
  }
  printf("%i", shit);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<game_over>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    $0x0,%eax
  call   <clear_screen@plt>
  mov    $0x0,%eax
  call   <get_level@plt>
  mov    %eax,%r12d
  mov    $0x0,%eax
  call   <get_rows@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <get_score@plt>
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  nop
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D1
type_infered: string

tool: D2: 

	***  GAME OVER  ***
	FINAL SCORE:	%d
	ROWS:		%d
	LEVEL:		%d



tool: D1: << PRESS ENTER TO EXIT >>

assistant: ```c
void game_over() {
  clear_screen();
  printf("\n\n\t***  GAME OVER  ***\n\tFINAL SCORE:\t%d\n\tROWS:\t\t%d\n\tLEVEL:\t\t%d\n\n", get_score(), get_rows(), get_level());
  printf("<< PRESS ENTER TO EXIT >>\n");
  getchar();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<game_over>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clear_screen@plt>
  mov    $0x0,%eax
  call   <get_level@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <get_rows@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <get_score@plt>
  mov    %eax,%esi
  mov    %ebp,%ecx
  mov    %ebx,%edx
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D1: 

	***  GAME OVER  ***
	FINAL SCORE:	%d
	ROWS:		%d
	LEVEL:		%d



tool: D5: << PRESS ENTER TO EXIT >>

assistant: ```c
void game_over() {
  clear_screen();
  printf("\n\n\t***  GAME OVER  ***\n\tFINAL SCORE:\t%d\n\tROWS:\t\t%d\n\tLEVEL:\t\t%d\n\n", get_score(), get_rows(), get_level());
  printf("<< PRESS ENTER TO EXIT >>\n");
  getchar();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<game_over>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  sub    $0x8,%rsp
  call   <clear_screen@plt>
  xor    %eax,%eax
  call   <get_level@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <get_rows@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <get_score@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10e0 <getchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D10
data_type: string

tool: D19: 

	***  GAME OVER  ***
	FINAL SCORE:	%d
	ROWS:		%d
	LEVEL:		%d



tool: D10: << PRESS ENTER TO EXIT >>

assistant: ```c
void game_over() {
  clear_screen();
  printf("\n\n\t***  GAME OVER  ***\n\tFINAL SCORE:\t%d\n\tROWS:\t\t%d\n\tLEVEL:\t\t%d\n\n", get_score(), get_rows(), get_level());
  printf("<< PRESS ENTER TO EXIT >>\n");
  getchar();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<game_over>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  sub    $0x8,%rsp
  call   <clear_screen@plt>
  xor    %eax,%eax
  call   <get_level@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <get_rows@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <get_score@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10e0 <getchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
datatype: string
name: extract_symbolic_data
arguments: tag: D13
datatype: string

tool: D6: 

	***  GAME OVER  ***
	FINAL SCORE:	%d
	ROWS:		%d
	LEVEL:		%d



tool: D13: << PRESS ENTER TO EXIT >>

assistant: ```c
void game_over() {
  clear_screen();
  printf("\n\n\t***  GAME OVER  ***\n\tFINAL SCORE:\t%d\n\tROWS:\t\t%d\n\tLEVEL:\t\t%d\n\n", get_score(), get_rows(), get_level());
  printf("<< PRESS ENTER TO EXIT >>\n");
  getchar();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <Cria_lista@plt>
L39:
  mov    $0x0,%eax
  call   <Menu@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xb,-0x4(%rbp)
  ja     L39
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D6(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D6(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <InserirCarro@plt>
  jmp    L42
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <InserirVaga@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <ApagarCarroPorChassi@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <ApagarVagaPorId@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <ImprimirVagasOcupadas@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <ImprimirVagasLivres@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <ImprimirFilaDeCarros@plt>
  jmp    L42
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <SalvarVagas@plt>
  jmp    L42
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <SalvarCarros@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <EstacionarCarro@plt>
  jmp    L42
  mov    $0x0,%eax
  call   <ListarCarros@plt>
  jmp    L42
  mov    $0x0,%edi
  call   <exit@plt>
  nop
L42:
  jmp    L39
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type: string
name: disassemble_data
arguments: data_tag: D37
type: string
name: disassemble_data
arguments: data_tag: D49
type: string
name: disassemble_data
arguments: data_tag: D48
type: string

tool: D15: veiculos.txt

tool: D37: vagas.txt

tool: D49: VagasSalvas.txt

tool: D48: CarrosSalvos.txt

assistant: ```c
int main(void) {
  int escolha;
  Cria_lista();
  for (;;) {
    escolha = Menu();
    switch (escolha) {
    case 1:
      InserirCarro("veiculos.txt");
      break;
    case 2:
      InserirVaga("vagas.txt");
      break;
    case 3:
      ApagarCarroPorChassi();
      break;
    case 4:
      ApagarVagaPorId();
      break;
    case 5:
      ImprimirVagasOcupadas();
      break;
    case 6:
      ImprimirVagasLivres();
      break;
    case 7:
      ImprimirFilaDeCarros();
      break;
    case 8:
      SalvarVagas("VagasSalvas.txt");
      break;
    case 9:
      SalvarCarros("CarrosSalvos.txt");
      break;
    case 10:
      EstacionarCarro();
      break;
    case 11:
      ListarCarros();
      break;
    case 0:
      exit(0);
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  lea    D39(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D49(%rip),%r12
  push   %rbp
  lea    D33(%rip),%rbp
  push   %rbx
  lea    D16(%rip),%rbx
  call   <Cria_lista@plt>
  cs nopw 0x0(%rax,%rax,1)
L92:
  xor    %eax,%eax
  call   <Menu@plt>
  cmp    $0xb,%eax
  ja     L92
  mov    %eax,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <EstacionarCarro@plt>
  jmp    L92
  nopl   0x0(%rax)
  mov    %rbp,%rdi
  call   <SalvarCarros@plt>
  jmp    L92
  nopw   0x0(%rax,%rax,1)
  mov    %r12,%rdi
  call   <SalvarVagas@plt>
  jmp    L92
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <ImprimirFilaDeCarros@plt>
  jmp    L92
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ImprimirVagasLivres@plt>
  jmp    L92
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ImprimirVagasOcupadas@plt>
  jmp    L92
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ApagarVagaPorId@plt>
  jmp    L92
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ApagarCarroPorChassi@plt>
  jmp    L92
  nopl   0x0(%rax)
  mov    %r13,%rdi
  call   <InserirVaga@plt>
  jmp    L92
  nopl   (%rax)
  mov    %r14,%rdi
  call   <InserirCarro@plt>
  jmp    L92
  nopl   (%rax)
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L92
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ListarCarros@plt>
  jmp    L92
```

tool_calls: name: retrieve_data
arguments: data_label: D39
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D49
type_guessed: string
name: retrieve_data
arguments: data_label: D33
type_guessed: string

tool: D39: veiculos.txt

tool: D17: vagas.txt

tool: D49: VagasSalvas.txt

tool: D33: CarrosSalvos.txt

assistant: ```c
int main(void) {
  int escolha;
  Cria_lista();
  for (;;) {
    escolha = Menu();
    switch (escolha) {
    case 1:
      InserirCarro("veiculos.txt");
      break;
    case 2:
      InserirVaga("vagas.txt");
      break;
    case 3:
      ApagarCarroPorChassi();
      break;
    case 4:
      ApagarVagaPorId();
      break;
    case 5:
      ImprimirVagasOcupadas();
      break;
    case 6:
      ImprimirVagasLivres();
      break;
    case 7:
      ImprimirFilaDeCarros();
      break;
    case 8:
      SalvarVagas("VagasSalvas.txt");
      break;
    case 9:
      SalvarCarros("CarrosSalvos.txt");
      break;
    case 10:
      EstacionarCarro();
      break;
    case 11:
      ListarCarros();
      break;
    case 0:
      exit(0);
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  lea    D27(%rip),%r14
  push   %r13
  lea    D1(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  lea    D23(%rip),%rbx
  call   <Cria_lista@plt>
  cs nopw 0x0(%rax,%rax,1)
L111:
  xor    %eax,%eax
  call   <Menu@plt>
  cmp    $0xb,%eax
  ja     L111
  mov    %eax,%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <EstacionarCarro@plt>
  jmp    L111
  nopl   0x0(%rax)
  mov    %rbp,%rdi
  call   <SalvarCarros@plt>
  jmp    L111
  nopw   0x0(%rax,%rax,1)
  mov    %r12,%rdi
  call   <SalvarVagas@plt>
  jmp    L111
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <ImprimirFilaDeCarros@plt>
  jmp    L111
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ImprimirVagasLivres@plt>
  jmp    L111
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ImprimirVagasOcupadas@plt>
  jmp    L111
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ApagarVagaPorId@plt>
  jmp    L111
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ApagarCarroPorChassi@plt>
  jmp    L111
  nopl   0x0(%rax)
  mov    %r13,%rdi
  call   <InserirVaga@plt>
  jmp    L111
  nopl   (%rax)
  mov    %r14,%rdi
  call   <InserirCarro@plt>
  jmp    L111
  nopl   (%rax)
  xor    %edi,%edi
  call   <exit@plt>
  jmp    L111
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <ListarCarros@plt>
  jmp    L111
```

tool_calls: name: parse_data
arguments: label: D27
data_type: string
name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D8
data_type: string

tool: D27: veiculos.txt

tool: D1: vagas.txt

tool: D12: VagasSalvas.txt

tool: D8: CarrosSalvos.txt

assistant: ```c
int main(void) {
  int escolha;
  Cria_lista();
  for (;;) {
    escolha = Menu();
    switch (escolha) {
    case 1:
      InserirCarro("veiculos.txt");
      break;
    case 2:
      InserirVaga("vagas.txt");
      break;
    case 3:
      ApagarCarroPorChassi();
      break;
    case 4:
      ApagarVagaPorId();
      break;
    case 5:
      ImprimirVagasOcupadas();
      break;
    case 6:
      ImprimirVagasLivres();
      break;
    case 7:
      ImprimirFilaDeCarros();
      break;
    case 8:
      SalvarVagas("VagasSalvas.txt");
      break;
    case 9:
      SalvarCarros("CarrosSalvos.txt");
      break;
    case 10:
      EstacionarCarro();
      break;
    case 11:
      ListarCarros();
      break;
    case 0:
      exit(0);
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<quadric_keyboard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0x1b,%eax
  jne    L10
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L5
L10:
  nop
L5:
  nop
  leave
  ret
```

assistant: ```c
void quadric_keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case 27:
    exit(0);
    break;
  default:
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quadric_keyboard>:
  endbr64
  cmp    $0x1b,%dil
  je     L3
  ret
L3:
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void quadric_keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case 27:
    exit(0);
    break;
  default:
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<quadric_keyboard>:
  endbr64
  cmp    $0x1b,%dil
  je     L7
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void quadric_keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case 27:
    exit(0);
    break;
  default:
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<quadric_keyboard>:
  endbr64
  cmp    $0x1b,%dil
  je     L3
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  xor    %edi,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void quadric_keyboard(unsigned char key, int x, int y) {
  switch (key) {
  case 27:
    exit(0);
    break;
  default:
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmd_send_pulse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L24
  mov    $0xffffffffffffffff,%rax
  jmp    L7
L24:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
L20:
  mov    -0x1c(%rbp),%eax
  movzwl %ax,%eax
  or     $0xb0000,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <conv32network_endian@plt>
  mov    $0x4,%eax
L7:
  leave
  ret
```

assistant: ```c
size_t cmd_send_pulse(uint32_t **bufio, uint32_t mask) {
  uint32_t *buf;
  buf = *bufio;
  if (buf == NULL) {
    buf = (uint32_t *)calloc(1, sizeof(uint32_t));
    if (buf == NULL)
      return -1;
    *bufio = buf;
  }
  buf[0] = 0x000b0000 | (0x0000ffff & mask);
  conv32network_endian(buf, 1);
  return 1 * sizeof(uint32_t);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmd_send_pulse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
L28:
  movzwl %bx,%esi
  or     $0xb0000,%esi
  mov    %esi,(%rdi)
  mov    $0x1,%esi
  call   <conv32network_endian@plt>
  mov    $0x4,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <calloc@plt>
  mov    %rax,%rdx
  mov    $0xffffffffffffffff,%rax
  test   %rdx,%rdx
  je     L18
  mov    %rdx,%rdi
  mov    %rdx,0x0(%rbp)
  jmp    L28
```

assistant: ```c
size_t cmd_send_pulse(uint32_t **bufio, uint32_t mask) {
  uint32_t *buf;
  buf = *bufio;
  if (buf == NULL) {
    buf = (uint32_t *)calloc(1, sizeof(uint32_t));
    if (buf == NULL)
      return -1;
    *bufio = buf;
  }
  buf[0] = 0x000b0000 | (0x0000ffff & mask);
  conv32network_endian(buf, 1);
  return 1 * sizeof(uint32_t);
}
```