ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  sub    $0xa4d,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L45
L28:
  movw   $0x0,-0xe(%rbp)
  jmp    L22
L43:
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0xf(%rbp)
  lea    -0xa(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0xa(%rbp),%rax
  movzbl -0xf(%rbp),%edx
  mov    %dl,(%rax)
  movzwl -0xe(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%edx
  movzwl -0xc(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dx,-0xa(%rbp,%rax,2)
  movzwl -0xe(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xe(%rbp)
L22:
  cmpw   $0x0,-0xe(%rbp)
  je     L43
  movzwl -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %ax,-0xc(%rbp)
L45:
  cmpw   $0x0,-0xc(%rbp)
  je     L28
  movzwl -0xa(%rbp),%eax
  lea    -0x7496(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] = state[local2] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)30591;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%edx
  sub    $0xa4d,%dx
  mov    %edx,%eax
  movsbl %dh,%ecx
  mov    %dl,%ah
  mov    %cl,%al
  lea    -0x7496(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] = state[local2] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)30591;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0xa4d,%ax
  rol    $0x8,%ax
  lea    -0x7496(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] = state[local2] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)30591;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  sub    $0xa4d,%ax
  rol    $0x8,%ax
  lea    -0x7496(%rax,%rax,1),%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local2;
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned short)29623;
    local1 = 0UL;
    while (local1 < 1UL) {
      local2 = 0UL;
      while (local2 < 1UL) {
        copy11 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy11;
        state[local1] = state[local2] + state[local2];
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] + 1047729131UL) + (unsigned short)30591;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x200(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x204(%rbp)
  jmp    L21
L5:
  mov    -0x204(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L19
  mov    -0x204(%rbp),%eax
  add    $0x1,%eax
  cltq
  movzbl -0x200(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  jmp    L46
L19:
  mov    -0x204(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x200(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L46:
  addl   $0x1,-0x204(%rbp)
L21:
  lea    -0x200(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x204(%rbp)
  jl     L5
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %s

assistant: ```c
main() {
  int i;
  char string[501];
  scanf("%s", &string);
  for (i = 0; i < strlen(string); i++) {
    if (i % 2 == 0)
      printf("%c", string[i + 1]);
    else
      printf("%c", string[i - 1]);
  }
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  mov    %rsp,%rbp
  jmp    L2
L7:
  movsbl -0x1(%rsp,%rbx,1),%edi
  call   <putchar@plt>
L21:
  add    $0x1,%rbx
L2:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L33
  test   $0x1,%bl
  jne    L7
  lea    0x1(%rbx),%eax
  cltq
  movsbl (%rsp,%rax,1),%edi
  call   <putchar@plt>
  jmp    L21
L33:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  mov    $0x0,%eax
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %s

assistant: ```c
main() {
  int i;
  char string[501];
  scanf("%s", &string);
  for (i = 0; i < strlen(string); i++) {
    if (i % 2 == 0)
      printf("%c", string[i + 1]);
    else
      printf("%c", string[i - 1]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1(%rsp),%rbp
  mov    %r12,%rsi
  call   <scanf@plt>
  jmp    L17
  nopl   (%rax)
L24:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
L45:
  add    $0x1,%rbp
L17:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L16
  mov    %ebx,%eax
  add    $0x1,%ebx
  and    $0x1,%eax
  test   %eax,%eax
  je     L24
  movsbl -0x2(%rbp),%edi
  call   <putchar@plt>
  jmp    L45
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
data_type: string

tool: D3: %s

assistant: ```c
main() {
  int i;
  char string[501];
  scanf("%s", &string);
  for (i = 0; i < strlen(string); i++) {
    if (i % 2 == 0)
      printf("%c", string[i + 1]);
    else
      printf("%c", string[i - 1]);
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x200,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x1(%rsp),%rbp
  mov    %r12,%rsi
  call   <scanf@plt>
  jmp    L7
  nopl   (%rax)
L39:
  movsbl 0x0(%rbp),%edi
  call   <putchar@plt>
L49:
  add    $0x1,%rbp
L7:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L36
  mov    %ebx,%eax
  add    $0x1,%ebx
  and    $0x1,%eax
  test   %eax,%eax
  je     L39
  movsbl -0x2(%rbp),%edi
  call   <putchar@plt>
  jmp    L49
L36:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x200,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: %s

assistant: ```c
main() {
  int i;
  char string[501];
  scanf("%s", &string);
  for (i = 0; i < strlen(string); i++) {
    if (i % 2 == 0)
      printf("%c", string[i + 1]);
    else
      printf("%c", string[i - 1]);
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D16
type_guessed: string
name: parse_data
arguments: data_tag: D49
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D24
type_guessed: string
name: parse_data
arguments: data_tag: D50
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D9: Usage: %s <options> [STRING]



tool: D16: Options:

tool: D49:  -b|--bigendian       Bigendian symbols (default little endian)

tool: D2:  -B|--binary          Binary format

tool: D24:  -d|--dashdot         Human readable dash/dot format (default)

tool: D50:  -D|--ditdah          Human readable dit/dah format

tool: D5:  -x|--decode          Switch to decode mode

assistant: ```c
void usage(int argc, char **argv) {
  printf("Usage: %s <options> [STRING]\n\n", argv[0]);
  printf("Options:\n");
  printf(" -b|--bigendian       Bigendian symbols (default little endian)\n");
  printf(" -B|--binary          Binary format\n");
  printf(" -d|--dashdot         Human readable dash/dot format (default)\n");
  printf(" -D|--ditdah          Human readable dit/dah format\n");
  printf(" -x|--decode          Switch to decode mode\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D61(%rip),%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  lea    D69(%rip),%rdi
  call   <puts@plt>
  lea    D67(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
data_type: string
name: parse_data
arguments: label: D31
data_type: string
name: parse_data
arguments: label: D18
data_type: string
name: parse_data
arguments: label: D61
data_type: string
name: parse_data
arguments: label: D15
data_type: string
name: parse_data
arguments: label: D69
data_type: string
name: parse_data
arguments: label: D67
data_type: string

tool: D5: Usage: %s <options> [STRING]



tool: D31: Options:

tool: D18:  -b|--bigendian       Bigendian symbols (default little endian)

tool: D61:  -B|--binary          Binary format

tool: D15:  -d|--dashdot         Human readable dash/dot format (default)

tool: D69:  -D|--ditdah          Human readable dit/dah format

tool: D67:  -x|--decode          Switch to decode mode

assistant: ```c
void usage(int argc, char **argv) {
  printf("Usage: %s <options> [STRING]\n\n", argv[0]);
  printf("Options:\n");
  printf(" -b|--bigendian       Bigendian symbols (default little endian)\n");
  printf(" -B|--binary          Binary format\n");
  printf(" -d|--dashdot         Human readable dash/dot format (default)\n");
  printf(" -D|--ditdah          Human readable dit/dah format\n");
  printf(" -x|--decode          Switch to decode mode\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D48(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D62(%rip),%rdi
  call   <puts@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  lea    D6(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  lea    D53(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: read_data
arguments: label: D48
datatype: string
name: read_data
arguments: label: D62
datatype: string
name: read_data
arguments: label: D46
datatype: string
name: read_data
arguments: label: D6
datatype: string
name: read_data
arguments: label: D43
datatype: string
name: read_data
arguments: label: D22
datatype: string
name: read_data
arguments: label: D53
datatype: string

tool: D48: Usage: %s <options> [STRING]



tool: D62: Options:

tool: D46:  -b|--bigendian       Bigendian symbols (default little endian)

tool: D6:  -B|--binary          Binary format

tool: D43:  -d|--dashdot         Human readable dash/dot format (default)

tool: D22:  -D|--ditdah          Human readable dit/dah format

tool: D53:  -x|--decode          Switch to decode mode

assistant: ```c
void usage(int argc, char **argv) {
  printf("Usage: %s <options> [STRING]\n\n", argv[0]);
  printf("Options:\n");
  printf(" -b|--bigendian       Bigendian symbols (default little endian)\n");
  printf(" -B|--binary          Binary format\n");
  printf(" -d|--dashdot         Human readable dash/dot format (default)\n");
  printf(" -D|--ditdah          Human readable dit/dah format\n");
  printf(" -x|--decode          Switch to decode mode\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D49(%rip),%rdi
  call   <puts@plt>
  lea    D60(%rip),%rdi
  call   <puts@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  lea    D26(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: label: D41
type_guessed: string
name: unpack_data
arguments: label: D36
type_guessed: string
name: unpack_data
arguments: label: D2
type_guessed: string
name: unpack_data
arguments: label: D49
type_guessed: string
name: unpack_data
arguments: label: D60
type_guessed: string
name: unpack_data
arguments: label: D64
type_guessed: string
name: unpack_data
arguments: label: D26
type_guessed: string

tool: D41: Usage: %s <options> [STRING]



tool: D36: Options:

tool: D2:  -b|--bigendian       Bigendian symbols (default little endian)

tool: D49:  -B|--binary          Binary format

tool: D60:  -d|--dashdot         Human readable dash/dot format (default)

tool: D64:  -D|--ditdah          Human readable dit/dah format

tool: D26:  -x|--decode          Switch to decode mode

assistant: ```c
void usage(int argc, char **argv) {
  printf("Usage: %s <options> [STRING]\n\n", argv[0]);
  printf("Options:\n");
  printf(" -b|--bigendian       Bigendian symbols (default little endian)\n");
  printf(" -B|--binary          Binary format\n");
  printf(" -d|--dashdot         Human readable dash/dot format (default)\n");
  printf(" -D|--ditdah          Human readable dit/dah format\n");
  printf(" -x|--decode          Switch to decode mode\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverseBits_fun_uint64_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x3f,-0x4(%rbp)
  jmp    L1
L5:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L1:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x4(%rbp),%eax
  mov    -0x8(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint64_t reverseBits_fun_uint64_t(uint64_t x) {
  uint64_t r = x;
  int i = 63;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverseBits_fun_uint64_t>:
  endbr64
  mov    %edi,%eax
  mov    %edi,%edx
  sar    %edx
  je     L10
  mov    $0x3f,%ecx
L15:
  add    %eax,%eax
  mov    %edx,%esi
  and    $0x1,%esi
  or     %esi,%eax
  sub    $0x1,%ecx
  sar    %edx
  jne    L15
L3:
  shl    %cl,%eax
  ret
L10:
  mov    $0x3f,%ecx
  jmp    L3
```

assistant: ```c
uint64_t reverseBits_fun_uint64_t(uint64_t x) {
  uint64_t r = x;
  int i = 63;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverseBits_fun_uint64_t>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0x3f,%ecx
  sar    %edx
  je     L3
  nopl   0x0(%rax)
L16:
  mov    %edx,%esi
  add    %eax,%eax
  sub    $0x1,%ecx
  and    $0x1,%esi
  or     %esi,%eax
  sar    %edx
  jne    L16
L3:
  shl    %cl,%eax
  ret
```

assistant: ```c
uint64_t reverseBits_fun_uint64_t(uint64_t x) {
  uint64_t r = x;
  int i = 63;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<reverseBits_fun_uint64_t>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0x3f,%ecx
  sar    %edx
  je     L0
  nopl   0x0(%rax)
L19:
  mov    %edx,%esi
  add    %eax,%eax
  sub    $0x1,%ecx
  and    $0x1,%esi
  or     %esi,%eax
  sar    %edx
  jne    L19
L0:
  shl    %cl,%eax
  ret
```

assistant: ```c
uint64_t reverseBits_fun_uint64_t(uint64_t x) {
  uint64_t r = x;
  int i = 63;
  while (x >>= 1) {
    r = (r << 1) | (x & 1);
    --i;
  }
  return r << i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x70(%rbp)
  movl   $0x2,-0x6c(%rbp)
  movl   $0x0,-0x68(%rbp)
  movl   $0x6,-0x64(%rbp)
  movl   $0x0,-0x60(%rbp)
  movl   $0x2,-0x5c(%rbp)
  movl   $0x0,-0x58(%rbp)
  movl   $0x3,-0x54(%rbp)
  movl   $0x8,-0x50(%rbp)
  movl   $0x5,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x3,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0x6,-0x34(%rbp)
  movl   $0x8,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x7,-0x18(%rbp)
  movl   $0x9,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <primMST@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int main() {
  int graph[5][5] = {
      {0, 2, 0, 6, 0}, {2, 0, 3, 8, 5}, {0, 3, 0, 0, 7}, {6, 8, 0, 0, 9}, {0, 5, 7, 9, 0},
  };
  primMST(graph);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x0,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x0,0x18(%rsp)
  movl   $0x3,0x1c(%rsp)
  movl   $0x8,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  movl   $0x0,0x28(%rsp)
  movl   $0x3,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  movl   $0x7,0x38(%rsp)
  movl   $0x6,0x3c(%rsp)
  movl   $0x8,0x40(%rsp)
  movl   $0x0,0x44(%rsp)
  movl   $0x0,0x48(%rsp)
  movl   $0x9,0x4c(%rsp)
  movl   $0x0,0x50(%rsp)
  movl   $0x5,0x54(%rsp)
  movl   $0x7,0x58(%rsp)
  movl   $0x9,0x5c(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rsp,%rdi
  call   <primMST@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x78,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int graph[5][5] = {
      {0, 2, 0, 6, 0}, {2, 0, 3, 8, 5}, {0, 3, 0, 0, 7}, {6, 8, 0, 0, 9}, {0, 5, 7, 9, 0},
  };
  primMST(graph);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  movabs $0x600000000,%rdx
  sub    $0x78,%rsp
  movabs $0x500000008,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  movabs $0x200000000,%rax
  mov    %rsp,%rdi
  mov    %rdx,0x8(%rsp)
  mov    %rcx,0x20(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x8,0x40(%rsp)
  movl   $0x0,0x60(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x10(%rsp)
  movabs $0x300000000,%rax
  mov    %rax,0x18(%rsp)
  mov    %rax,0x28(%rsp)
  movabs $0x600000007,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x900000000,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x500000000,%rax
  mov    %rax,0x50(%rsp)
  movabs $0x900000007,%rax
  mov    %rax,0x58(%rsp)
  call   <primMST@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x78,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int graph[5][5] = {
      {0, 2, 0, 6, 0}, {2, 0, 3, 8, 5}, {0, 3, 0, 0, 7}, {6, 8, 0, 0, 9}, {0, 5, 7, 9, 0},
  };
  primMST(graph);
  return 0;
}
```