user: What would the C source look like for the assembly code provided here?

```asm
<dfft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %esi,-0x58(%rbp)
  mov    %rdx,-0x60(%rbp)
  mov    %rcx,-0x68(%rbp)
  mov    -0x68(%rbp),%rdx
  mov    -0x60(%rbp),%rcx
  mov    -0x54(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <cft1st@plt>
  movl   $0x4,-0x4c(%rbp)
  movl   $0x8,-0x48(%rbp)
  jmp    L52
L71:
  mov    -0x68(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  mov    -0x48(%rbp),%esi
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <cftmd1@plt>
  addl   $0x2,-0x4c(%rbp)
  shll   $0x2,-0x48(%rbp)
L52:
  mov    -0x58(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4c(%rbp)
  jle    L71
  jmp    L69
L9:
  mov    -0x68(%rbp),%rcx
  mov    -0x60(%rbp),%rdx
  mov    -0x48(%rbp),%esi
  mov    -0x54(%rbp),%eax
  mov    %eax,%edi
  call   <cftmd2@plt>
  addl   $0x2,-0x4c(%rbp)
  shll   $0x2,-0x48(%rbp)
L69:
  mov    -0x58(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jg     L9
  mov    -0x68(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x48(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%eax
  shl    $0x2,%eax
  cmp    %eax,-0x54(%rbp)
  jne    L83
  movl   $0x0,-0x44(%rbp)
  jmp    L20
L14:
  mov    -0x28(%rbp),%r8
  mov    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x60(%rbp),%rsi
  movsd  D6(%rip),%xmm1
  movsd  D6(%rip),%xmm0
  mov    D6(%rip),%rdi
  mov    -0x44(%rbp),%eax
  pxor   %xmm5,%xmm5
  movapd %xmm1,%xmm4
  pxor   %xmm3,%xmm3
  movapd %xmm0,%xmm2
  pxor   %xmm1,%xmm1
  movq   %rdi,%xmm0
  mov    %eax,%edi
  call   <btrfly@plt>
  addl   $0x2,-0x44(%rbp)
L20:
  mov    -0x44(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L14
  jmp    L18
L83:
  movl   $0x0,-0x44(%rbp)
  jmp    L5
L12:
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x44(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x60(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x44(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x2,-0x44(%rbp)
L5:
  mov    -0x44(%rbp),%eax
  cmp    -0x48(%rbp),%eax
  jl     L12
L18:
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: f64

tool: D6: 1

assistant: ```c
void dfft(int n, int logn, double *a, double *w) {
  int i, l, j;
  double *v, *b, *c, *d;
  cft1st(n, a, w);
  i = 4;
  l = 8;
  for (; i <= logn / 2; i += 2, l *= 4)
    cftmd1(n, l, a, w);
  for (; i <= logn - 1; i += 2, l *= 4)
    cftmd2(n, l, a, w);
  v = w + 1;
  b = a + l;
  c = a + l + l;
  d = a + l + l + l;
  if ((l << 2) == n) {
#pragma mta use 100 streams
#pragma mta assert no dependence
    for (j = 0; j < l; j += 2)
      btrfly(j, 1.0, 0.0, 1.0, 0.0, 1.0, 0.0, a, b, c, d);
  } else {
#pragma mta use 100 streams
#pragma mta assert no dependence
    for (j = 0; j < l; j += 2) {
      double x0r = a[j];
      double x0i = a[j + 1];
      double x1r = b[j];
      double x1i = b[j + 1];
      a[j] = x0r + x1r;
      a[j + 1] = x0i + x1i;
      b[j] = x0r - x1r;
      b[j + 1] = x0i - x1i;
    }
  }
}
```