ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<USBFrameNumberGet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x40050000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  add    $0xc,%ebx
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t USBFrameNumberGet(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  return ((*((volatile uint16_t *)(ui32Base + 0x0000000C))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<USBFrameNumberGet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  cmp    $0x40050000,%ebx
  sete   %dil
  add    $0xc,%ebx
  call   <ASSERT@plt>
  movslq %ebx,%rbx
  mov    (%rbx),%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t USBFrameNumberGet(uint32_t ui32Base) {
  ASSERT(ui32Base == 0x40050000);
  return ((*((volatile uint16_t *)(ui32Base + 0x0000000C))));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  movl   $0x64,-0x28(%rbp)
  movsd  D42(%rip),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movabs $0x61a800000000,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x28(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x18(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movb   $0x0,-0x29(%rbp)
  movsbl -0x29(%rbp),%eax
  mov    -0x28(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D42
type: f64
name: unpack_data
arguments: label: D45
type: string
name: unpack_data
arguments: label: D16
type: string
name: unpack_data
arguments: label: D40
type: string
name: unpack_data
arguments: label: D18
type: string
name: unpack_data
arguments: label: D38
type: string

tool: D42: 1.2

tool: D45: You have %d bugs at the imaginary rate of %.02f.


tool: D16: The entire universe has %ld bugs.


tool: D40: You have expected to have %.03f bugs.


tool: D18: That is only a %e portion of the universe.


tool: D38: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginary rate of %.02f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 102400L * 102400L * 10240L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You have expected to have %.03f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D38(%rip),%xmm0
  mov    $0x64,%esi
  lea    D12(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x78,%esi
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D38
type_infered: f64
name: unpack_data
arguments: label: D12
type_infered: string
name: unpack_data
arguments: label: D48
type_infered: string
name: unpack_data
arguments: label: D55
type_infered: string
name: unpack_data
arguments: label: D35
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string

tool: D38: 1.2

tool: D12: You have %d bugs at the imaginary rate of %.02f.


tool: D48: The entire universe has %ld bugs.


tool: D55: You have expected to have %.03f bugs.


tool: D35: That is only a %e portion of the universe.


tool: D20: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginary rate of %.02f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 102400L * 102400L * 10240L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You have expected to have %.03f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x1,%eax
  movsd  D19(%rip),%xmm0
  lea    D43(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x78,%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D19
type: f64
name: extract_symbolic_data
arguments: label: D43
type: string
name: extract_symbolic_data
arguments: label: D3
type: string
name: extract_symbolic_data
arguments: label: D21
type: string
name: extract_symbolic_data
arguments: label: D8
type: string
name: extract_symbolic_data
arguments: label: D16
type: string

tool: D19: 1.2

tool: D43: You have %d bugs at the imaginary rate of %.02f.


tool: D3: The entire universe has %ld bugs.


tool: D21: You have expected to have %.03f bugs.


tool: D8: That is only a %e portion of the universe.


tool: D16: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginary rate of %.02f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 102400L * 102400L * 10240L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You have expected to have %.03f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%esi
  mov    $0x1,%eax
  movsd  D24(%rip),%xmm0
  lea    D45(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x78,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %esi,%esi
  lea    D56(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
data_type: f64
name: extract_symbolic_data
arguments: tag: D45
data_type: string
name: extract_symbolic_data
arguments: tag: D26
data_type: string
name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D56
data_type: string

tool: D24: 1.2

tool: D45: You have %d bugs at the imaginary rate of %.02f.


tool: D26: The entire universe has %ld bugs.


tool: D3: You have expected to have %.03f bugs.


tool: D10: That is only a %e portion of the universe.


tool: D56: Which means you should care %d%%.


assistant: ```c
int main(int argc, char *argv[]) {
  int bugs = 100;
  double bug_rate = 1.2;
  printf("You have %d bugs at the imaginary rate of %.02f.\n", bugs, bug_rate);
  long universe_of_defects = 1L * 102400L * 102400L * 10240L;
  printf("The entire universe has %ld bugs.\n", universe_of_defects);
  double expected_bugs = bugs * bug_rate;
  printf("You have expected to have %.03f bugs.\n", expected_bugs);
  double part_of_universe = expected_bugs / universe_of_defects;
  printf("That is only a %e portion of the universe.\n", part_of_universe);
  char nul_byte = '\0';
  int care_percentage = bugs * nul_byte;
  printf("Which means you should care %d%%.\n", care_percentage);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wpa_key_mgmt_txt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x8,-0x4(%rbp)
  je     L41
  cmpl   $0x8,-0x4(%rbp)
  jg     L0
  cmpl   $0x4,-0x4(%rbp)
  je     L12
  cmpl   $0x4,-0x4(%rbp)
  jg     L0
  cmpl   $0x1,-0x4(%rbp)
  je     L21
  cmpl   $0x2,-0x4(%rbp)
  je     L104
  jmp    L0
L21:
  cmpl   $0x2,-0x8(%rbp)
  jne    L119
  lea    D69(%rip),%rax
  jmp    L34
L119:
  lea    D31(%rip),%rax
  jmp    L34
L104:
  cmpl   $0x2,-0x8(%rbp)
  jne    L130
  lea    D5(%rip),%rax
  jmp    L34
L130:
  lea    D2(%rip),%rax
  jmp    L34
L12:
  lea    D43(%rip),%rax
  jmp    L34
L41:
  lea    D56(%rip),%rax
  jmp    L34
L0:
  lea    D8(%rip),%rax
L34:
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D69
type_infered: string
name: unpack_data
arguments: data_tag: D31
type_infered: string
name: unpack_data
arguments: data_tag: D5
type_infered: string
name: unpack_data
arguments: data_tag: D2
type_infered: string
name: unpack_data
arguments: data_tag: D43
type_infered: string
name: unpack_data
arguments: data_tag: D56
type_infered: string
name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D69: WPA2/IEEE 802.1X/EAP

tool: D31: WPA/IEEE 802.1X/EAP

tool: D5: WPA2-PSK

tool: D2: WPA-PSK

tool: D43: NONE

tool: D56: IEEE 802.1X (no WPA)

tool: D8: UNKNOWN

assistant: ```c
const char *wpa_key_mgmt_txt(int key_mgmt, int proto) {
  switch (key_mgmt) {
  case (1 << (0)):
    return proto == (1 << (1)) ? "WPA2/IEEE 802.1X/EAP" : "WPA/IEEE 802.1X/EAP";
  case (1 << (1)):
    return proto == (1 << (1)) ? "WPA2-PSK" : "WPA-PSK";
  case (1 << (2)):
    return "NONE";
  case (1 << (3)):
    return "IEEE 802.1X (no WPA)";
  default:
    return "UNKNOWN";
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wpa_key_mgmt_txt>:
  endbr64
  lea    D59(%rip),%rax
  cmp    $0x4,%edi
  je     L1
  jg     L32
  cmp    $0x1,%edi
  je     L17
  cmp    $0x2,%edi
  jne    L7
  cmp    $0x2,%esi
  lea    D35(%rip),%rax
  lea    D14(%rip),%rdx
  cmovne %rdx,%rax
L1:
  ret
L7:
  lea    D49(%rip),%rax
  ret
L32:
  cmp    $0x8,%edi
  lea    D49(%rip),%rax
  lea    D8(%rip),%rdx
  cmove  %rdx,%rax
  ret
L17:
  cmp    $0x2,%esi
  lea    D40(%rip),%rax
  lea    D69(%rip),%rdx
  cmovne %rdx,%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D59
type: string
name: extract_symbolic_data
arguments: data_label: D35
type: string
name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D49
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D40
type: string
name: extract_symbolic_data
arguments: data_label: D69
type: string

tool: D59: NONE

tool: D35: WPA2-PSK

tool: D14: WPA-PSK

tool: D49: UNKNOWN

tool: D8: IEEE 802.1X (no WPA)

tool: D40: WPA2/IEEE 802.1X/EAP

tool: D69: WPA/IEEE 802.1X/EAP

assistant: ```c
const char *wpa_key_mgmt_txt(int key_mgmt, int proto) {
  switch (key_mgmt) {
  case (1 << (0)):
    return proto == (1 << (1)) ? "WPA2/IEEE 802.1X/EAP" : "WPA/IEEE 802.1X/EAP";
  case (1 << (1)):
    return proto == (1 << (1)) ? "WPA2-PSK" : "WPA-PSK";
  case (1 << (2)):
    return "NONE";
  case (1 << (3)):
    return "IEEE 802.1X (no WPA)";
  default:
    return "UNKNOWN";
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<wpa_key_mgmt_txt>:
  endbr64
  lea    D59(%rip),%rax
  cmp    $0x4,%edi
  je     L26
  jg     L16
  cmp    $0x1,%edi
  je     L35
  cmp    $0x2,%edi
  jne    L10
  cmp    $0x2,%esi
  lea    D3(%rip),%rax
  lea    D40(%rip),%rdx
  cmovne %rdx,%rax
L26:
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  cmp    $0x8,%edi
  lea    D5(%rip),%rdx
  lea    D46(%rip),%rax
  cmove  %rdx,%rax
  ret
  xchg   %ax,%ax
L35:
  cmp    $0x2,%esi
  lea    D55(%rip),%rdx
  lea    D14(%rip),%rax
  cmovne %rdx,%rax
  ret
L10:
  lea    D46(%rip),%rax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D59
datatype: string
name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D40
datatype: string
name: extract_symbolic_data
arguments: tag: D5
datatype: string
name: extract_symbolic_data
arguments: tag: D46
datatype: string
name: extract_symbolic_data
arguments: tag: D55
datatype: string
name: extract_symbolic_data
arguments: tag: D14
datatype: string

tool: D59: NONE

tool: D3: WPA2-PSK

tool: D40: WPA-PSK

tool: D5: IEEE 802.1X (no WPA)

tool: D46: UNKNOWN

tool: D55: WPA/IEEE 802.1X/EAP

tool: D14: WPA2/IEEE 802.1X/EAP

assistant: ```c
const char *wpa_key_mgmt_txt(int key_mgmt, int proto) {
  switch (key_mgmt) {
  case (1 << (0)):
    return proto == (1 << (1)) ? "WPA2/IEEE 802.1X/EAP" : "WPA/IEEE 802.1X/EAP";
  case (1 << (1)):
    return proto == (1 << (1)) ? "WPA2-PSK" : "WPA-PSK";
  case (1 << (2)):
    return "NONE";
  case (1 << (3)):
    return "IEEE 802.1X (no WPA)";
  default:
    return "UNKNOWN";
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<wpa_key_mgmt_txt>:
  endbr64
  lea    D0(%rip),%rax
  cmp    $0x4,%edi
  je     L3
  jg     L2
  cmp    $0x1,%edi
  je     L0
  cmp    $0x2,%edi
  jne    L16
  cmp    $0x2,%esi
  lea    D46(%rip),%rax
  lea    D30(%rip),%rdx
  cmovne %rdx,%rax
L3:
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  cmp    $0x8,%edi
  lea    D7(%rip),%rdx
  lea    D62(%rip),%rax
  cmove  %rdx,%rax
  ret
  xchg   %ax,%ax
L0:
  cmp    $0x2,%esi
  lea    D9(%rip),%rdx
  lea    D13(%rip),%rax
  cmovne %rdx,%rax
  ret
L16:
  lea    D62(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D46
type_infered: string
name: parse_data
arguments: data_label: D30
type_infered: string
name: parse_data
arguments: data_label: D7
type_infered: string
name: parse_data
arguments: data_label: D62
type_infered: string
name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D13
type_infered: string

tool: D0: NONE

tool: D46: WPA2-PSK

tool: D30: WPA-PSK

tool: D7: IEEE 802.1X (no WPA)

tool: D62: UNKNOWN

tool: D9: WPA/IEEE 802.1X/EAP

tool: D13: WPA2/IEEE 802.1X/EAP

assistant: ```c
const char *wpa_key_mgmt_txt(int key_mgmt, int proto) {
  switch (key_mgmt) {
  case (1 << (0)):
    return proto == (1 << (1)) ? "WPA2/IEEE 802.1X/EAP" : "WPA/IEEE 802.1X/EAP";
  case (1 << (1)):
    return proto == (1 << (1)) ? "WPA2-PSK" : "WPA-PSK";
  case (1 << (2)):
    return "NONE";
  case (1 << (3)):
    return "IEEE 802.1X (no WPA)";
  default:
    return "UNKNOWN";
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fdevent_fcntl_set_nb_cloexec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fdevent_setfd_cloexec@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fdevent_fcntl_set_nb@plt>
  leave
  ret
```

assistant: ```c
int fdevent_fcntl_set_nb_cloexec(int fd) {
  fdevent_setfd_cloexec(fd);
  return fdevent_fcntl_set_nb(fd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fdevent_fcntl_set_nb_cloexec>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <fdevent_setfd_cloexec@plt>
  mov    %ebx,%edi
  call   <fdevent_fcntl_set_nb@plt>
  pop    %rbx
  ret
```

assistant: ```c
int fdevent_fcntl_set_nb_cloexec(int fd) {
  fdevent_setfd_cloexec(fd);
  return fdevent_fcntl_set_nb(fd);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fdevent_fcntl_set_nb_cloexec>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <fdevent_setfd_cloexec@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <fdevent_fcntl_set_nb@plt>
```

assistant: ```c
int fdevent_fcntl_set_nb_cloexec(int fd) {
  fdevent_setfd_cloexec(fd);
  return fdevent_fcntl_set_nb(fd);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fdevent_fcntl_set_nb_cloexec>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <fdevent_setfd_cloexec@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1060 <fdevent_fcntl_set_nb@plt>
```

assistant: ```c
int fdevent_fcntl_set_nb_cloexec(int fd) {
  fdevent_setfd_cloexec(fd);
  return fdevent_fcntl_set_nb(fd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L35:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jne    L40
  mov    -0x4(%rbp),%eax
  jmp    L7
L40:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L55
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L16
L55:
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L35
  mov    $0xffffffff,%eax
L7:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type: string

tool: D7: STATE: l, u, m: %d, %d, %d


assistant: ```c
int binsearch(int a[], int n, int x) {
  int l, u, m;
  l = 0;
  u = n - 1;
  while (l < u) {
    m = (l + u) / 2;
    printf("STATE: l, u, m: %d, %d, %d\n", l, u, m);
    if (a[m] == x) {
      return m;
    } else if (a[m] < x) {
      l = m + 1;
    } else {
      u = m - 1;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  lea    -0x1(%rsi),%ebp
  test   %ebp,%ebp
  jle    L15
  mov    %rdi,%r14
  mov    %edx,%r13d
  mov    $0x0,%r12d
  lea    D4(%rip),%r15
  jmp    L63
L68:
  lea    -0x1(%rbx),%ebp
L59:
  cmp    %ebp,%r12d
  jge    L57
L63:
  lea    (%r12,%rbp,1),%eax
  mov    %eax,%ebx
  shr    $0x1f,%ebx
  add    %eax,%ebx
  sar    %ebx
  mov    %ebx,0xc(%rsp)
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  movslq %ebx,%rax
  mov    (%r14,%rax,4),%eax
  cmp    %r13d,%eax
  je     L22
  jge    L68
  lea    0x1(%rbx),%r12d
  jmp    L59
L57:
  movl   $0xffffffff,0xc(%rsp)
L22:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: STATE: l, u, m: %d, %d, %d


assistant: ```c
int binsearch(int a[], int n, int x) {
  int l, u, m;
  l = 0;
  u = n - 1;
  while (l < u) {
    m = (l + u) / 2;
    printf("STATE: l, u, m: %d, %d, %d\n", l, u, m);
    if (a[m] == x) {
      return m;
    } else if (a[m] < x) {
      l = m + 1;
    } else {
      u = m - 1;
    }
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<binsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L9
  mov    %rdi,%rbp
  mov    %edx,%r13d
  lea    D6(%rip),%r14
  xor    %r15d,%r15d
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L58:
  lea    0x1(%r12),%r15d
  cmp    %r15d,%ebx
  jle    L9
L5:
  lea    (%r15,%rbx,1),%r12d
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  sar    %r12d
  mov    %r12d,%ecx
  call   <printf@plt>
  movslq %r12d,%rax
  cmp    %r13d,0x0(%rbp,%rax,4)
  je     L16
  jl     L58
  lea    -0x1(%r12),%ebx
  cmp    %r15d,%ebx
  jg     L5
L9:
  mov    $0xffffffff,%r12d
L16:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
data_type: string

tool: D6: STATE: l, u, m: %d, %d, %d


assistant: ```c
int binsearch(int a[], int n, int x) {
  int l, u, m;
  l = 0;
  u = n - 1;
  while (l < u) {
    m = (l + u) / 2;
    printf("STATE: l, u, m: %d, %d, %d\n", l, u, m);
    if (a[m] == x) {
      return m;
    } else if (a[m] < x) {
      l = m + 1;
    } else {
      u = m - 1;
    }
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<binsearch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  sub    $0x8,%rsp
  test   %ebx,%ebx
  jle    L18
  mov    %rdi,%rbp
  mov    %edx,%r13d
  lea    D2(%rip),%r14
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L5:
  lea    (%r15,%rbx,1),%r12d
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  sar    %r12d
  mov    %r12d,%ecx
  call   <printf@plt>
  movslq %r12d,%rax
  cmp    %r13d,0x0(%rbp,%rax,4)
  je     L51
  jge    L2
  lea    0x1(%r12),%r15d
  cmp    %ebx,%r15d
  jl     L5
L18:
  mov    $0xffffffff,%r12d
L51:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L2:
  lea    -0x1(%r12),%ebx
  cmp    %r15d,%ebx
  jg     L5
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
datatype: string

tool: D2: STATE: l, u, m: %d, %d, %d


assistant: ```c
int binsearch(int a[], int n, int x) {
  int l, u, m;
  l = 0;
  u = n - 1;
  while (l < u) {
    m = (l + u) / 2;
    printf("STATE: l, u, m: %d, %d, %d\n", l, u, m);
    if (a[m] == x) {
      return m;
    } else if (a[m] < x) {
      l = m + 1;
    } else {
      u = m - 1;
    }
  }
  return -1;
}
```