ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tx_close>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  mov    (%rbx),%edi
  call   <close@plt>
  movl   $0xffffffff,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int tx_close(void) {
  extern _tx_server;
  close(_tx_server);
  _tx_server = -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tx_close>:
  endbr64
  push   %rbx
  mov    D5(%rip),%rbx
  mov    (%rbx),%edi
  call   <close@plt>
  movl   $0xffffffff,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int tx_close(void) {
  extern _tx_server;
  close(_tx_server);
  _tx_server = -1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<tx_close>:
  endbr64
  push   %rbx
  mov    D4(%rip),%rbx
  mov    (%rbx),%edi
  call   <close@plt>
  movl   $0xffffffff,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int tx_close(void) {
  extern _tx_server;
  close(_tx_server);
  _tx_server = -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cgc_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L8
L6:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0x20(%rbp)
L8:
  cmpl   $0x0,-0x20(%rbp)
  jne    L6
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *cgc_memset(void *str, int ch, unsigned int n) {
  char *ch_ptr = (char *)str;
  while (n > 0) {
    *ch_ptr = (char)ch;
    ch_ptr++;
    n--;
  }
  return str;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cgc_memset>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  je     L0
  mov    %edx,%edx
  lea    (%rdi,%rdx,1),%rcx
  mov    %rdi,%rdx
L15:
  mov    %sil,(%rdx)
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L15
L0:
  ret
```

assistant: ```c
void *cgc_memset(void *str, int ch, unsigned int n) {
  char *ch_ptr = (char *)str;
  while (n > 0) {
    *ch_ptr = (char)ch;
    ch_ptr++;
    n--;
  }
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cgc_memset>:
  endbr64
  test   %edx,%edx
  je     L4
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L4:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *cgc_memset(void *str, int ch, unsigned int n) {
  char *ch_ptr = (char *)str;
  while (n > 0) {
    *ch_ptr = (char)ch;
    ch_ptr++;
    n--;
  }
  return str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cgc_memset>:
  endbr64
  test   %edx,%edx
  je     L1
  sub    $0x8,%rsp
  mov    %edx,%edx
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *cgc_memset(void *str, int ch, unsigned int n) {
  char *ch_ptr = (char *)str;
  while (n > 0) {
    *ch_ptr = (char)ch;
    ch_ptr++;
    n--;
  }
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculate_crc8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L16
L15:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  xor    %eax,-0x14(%rbp)
  movl   $0x8,-0x10(%rbp)
  jmp    L47
L1:
  mov    -0x14(%rbp),%eax
  and    $0x8000,%eax
  test   %eax,%eax
  je     L12
  xorl   $0x8380,-0x14(%rbp)
L12:
  shll   -0x14(%rbp)
  subl   $0x1,-0x10(%rbp)
L47:
  cmpl   $0x0,-0x10(%rbp)
  jne    L1
  subl   $0x1,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
L16:
  cmpl   $0x0,-0xc(%rbp)
  jne    L15
  mov    -0x14(%rbp),%eax
  shr    $0x8,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t calculate_crc8(const void *vptr, int len) {
  const uint8_t *data = vptr;
  unsigned crc = 0;
  int i, j;
  for (j = len; j; j--, data++) {
    crc ^= (*data << 8);
    for (i = 8; i; i--) {
      if (crc & 0x8000)
        crc ^= (0x1070 << 3);
      crc <<= 1;
    }
  }
  return (uint8_t)(crc >> 8);
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculate_crc8>:
  endbr64
  test   %esi,%esi
  je     L15
  mov    %esi,%esi
  lea    (%rdi,%rsi,4),%rsi
  mov    $0x0,%eax
  jmp    L7
L24:
  add    $0x4,%rdi
  cmp    %rsi,%rdi
  je     L26
L7:
  mov    (%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%edx
L46:
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  sub    $0x1,%edx
  jne    L46
  jmp    L24
L15:
  mov    $0x0,%eax
L26:
  shr    $0x8,%eax
  ret
```

assistant: ```c
uint8_t calculate_crc8(const void *vptr, int len) {
  const uint8_t *data = vptr;
  unsigned crc = 0;
  int i, j;
  for (j = len; j; j--, data++) {
    crc ^= (*data << 8);
    for (i = 8; i; i--) {
      if (crc & 0x8000)
        crc ^= (0x1070 << 3);
      crc <<= 1;
    }
  }
  return (uint8_t)(crc >> 8);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calculate_crc8>:
  endbr64
  test   %esi,%esi
  je     L5
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,4),%rsi
L16:
  mov    (%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%edx
  nopl   0x0(%rax)
L24:
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  sub    $0x1,%edx
  jne    L24
  add    $0x4,%rdi
  cmp    %rdi,%rsi
  jne    L16
  shr    $0x8,%eax
  ret
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t calculate_crc8(const void *vptr, int len) {
  const uint8_t *data = vptr;
  unsigned crc = 0;
  int i, j;
  for (j = len; j; j--, data++) {
    crc ^= (*data << 8);
    for (i = 8; i; i--) {
      if (crc & 0x8000)
        crc ^= (0x1070 << 3);
      crc <<= 1;
    }
  }
  return (uint8_t)(crc >> 8);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<calculate_crc8>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  je     L5
  mov    %esi,%esi
  xor    %ecx,%ecx
  lea    (%rdi,%rsi,4),%rsi
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rdx),%eax
  shl    $0x8,%eax
  xor    %ecx,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  xor    $0x8380,%ecx
  test   $0x80,%ah
  cmovne %ecx,%eax
  add    $0x4,%rdx
  lea    (%rax,%rax,1),%ecx
  cmp    %rdx,%rsi
  jne    L14
  mov    %ecx,%eax
  shr    $0x8,%eax
  ret
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint8_t calculate_crc8(const void *vptr, int len) {
  const uint8_t *data = vptr;
  unsigned crc = 0;
  int i, j;
  for (j = len; j; j--, data++) {
    crc ^= (*data << 8);
    for (i = 8; i; i--) {
      if (crc & 0x8000)
        crc ^= (0x1070 << 3);
      crc <<= 1;
    }
  }
  return (uint8_t)(crc >> 8);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L23
L10:
  addl   $0x1,-0x44(%rbp)
  addl   $0x1,-0x48(%rbp)
L23:
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L10
  mov    -0x44(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
type_infered: string
name: retrieve_data
arguments: data_label: D4
type_infered: string

tool: D15: Enter string:

tool: D4: 

Length of the string=%d



assistant: ```c
void main() {
  char a[50];
  int i = 0, count = 0;
  printf("Enter string:");
  gets(a);
  while (a[i] != '\0') {
    count = count + 1;
    i++;
  }
  printf("\n\nLength of the string=%d\n\n", count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L32
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdx
L15:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L15
L14:
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x48,%rsp
  ret
L32:
  mov    $0x0,%esi
  jmp    L14
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D5: Enter string:

tool: D10: 

Length of the string=%d



assistant: ```c
void main() {
  char a[50];
  int i = 0, count = 0;
  printf("Enter string:");
  gets(a);
  while (a[i] != '\0') {
    count = count + 1;
    i++;
  }
  printf("\n\nLength of the string=%d\n\n", count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L0
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdx
  nopl   0x0(%rax)
L20:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L20
L17:
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x48,%rsp
  ret
L0:
  xor    %esi,%esi
  jmp    L17
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D19
type_guessed: string
name: parse_data
arguments: data_tag: D17
type_guessed: string

tool: D19: Enter string:

tool: D17: 

Length of the string=%d



assistant: ```c
void main() {
  char a[50];
  int i = 0, count = 0;
  printf("Enter string:");
  gets(a);
  while (a[i] != '\0') {
    count = count + 1;
    i++;
  }
  printf("\n\nLength of the string=%d\n\n", count);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rdi
  call   <gets@plt>
  cmpb   $0x0,(%rsp)
  je     L11
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rdx
  nopl   0x0(%rax)
L31:
  mov    %eax,%esi
  add    $0x1,%rax
  cmpb   $0x0,(%rdx,%rax,1)
  jne    L31
L26:
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x48,%rsp
  ret
L11:
  xor    %esi,%esi
  jmp    L26
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string
name: parse_data
arguments: data_tag: D5
type: string

tool: D6: Enter string:

tool: D5: 

Length of the string=%d



assistant: ```c
void main() {
  char a[50];
  int i = 0, count = 0;
  printf("Enter string:");
  gets(a);
  while (a[i] != '\0') {
    count = count + 1;
    i++;
  }
  printf("\n\nLength of the string=%d\n\n", count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x510,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x510(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x50c(%rbp)
  jmp    L6
L91:
  movl   $0x1,-0x508(%rbp)
  jmp    L75
L83:
  lea    -0x4d0(%rbp),%rdx
  mov    -0x508(%rbp),%eax
  cltq
  imul   $0x66,%rax,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x500(%rbp),%rdx
  mov    -0x508(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x508(%rbp)
L75:
  cmpl   $0xa,-0x508(%rbp)
  jle    L83
  mov    -0x4fc(%rbp),%eax
  mov    %eax,-0x504(%rbp)
  movl   $0x1,-0x508(%rbp)
  jmp    L29
L12:
  mov    -0x508(%rbp),%eax
  cltq
  mov    -0x500(%rbp,%rax,4),%eax
  cmp    %eax,-0x504(%rbp)
  jge    L69
  mov    -0x508(%rbp),%eax
  cltq
  mov    -0x500(%rbp,%rax,4),%eax
  mov    %eax,-0x504(%rbp)
L69:
  addl   $0x1,-0x508(%rbp)
L29:
  cmpl   $0xa,-0x508(%rbp)
  jle    L12
  mov    -0x50c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x508(%rbp)
  jmp    L55
L35:
  mov    -0x508(%rbp),%eax
  cltq
  mov    -0x500(%rbp,%rax,4),%eax
  cmp    %eax,-0x504(%rbp)
  jne    L23
  lea    -0x4d0(%rbp),%rdx
  mov    -0x508(%rbp),%eax
  cltq
  imul   $0x66,%rax,%rax
  add    %rdx,%rax
  mov    %rax,%rdi
  call   <puts@plt>
L23:
  addl   $0x1,-0x508(%rbp)
L55:
  cmpl   $0xa,-0x508(%rbp)
  jle    L35
  addl   $0x1,-0x50c(%rbp)
L6:
  mov    -0x510(%rbp),%eax
  cmp    %eax,-0x50c(%rbp)
  jle    L91
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D34
type_guessed: string
name: read_data
arguments: tag: D37
type_guessed: string
name: read_data
arguments: tag: D20
type_guessed: string

tool: D34: %d

tool: D37: %s

tool: D20: Case #%d:


assistant: ```c
int main() {
  char s[12][102];
  int t, i, ara[12], j, max;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    for (j = 1; j <= 10; j++) {
      scanf("%s", s[j]);
      scanf("%d", &ara[j]);
    }
    max = ara[1];
    for (j = 1; j <= 10; j++) {
      if (ara[j] > max)
        max = ara[j];
    }
    printf("Case #%d:\n", i);
    for (j = 1; j <= 10; j++) {
      if (ara[j] == max) {
        printf("%s\n", s[j]);
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x528,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x518(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D38(%rip),%rdi
  call   <scanf@plt>
  movl   $0x1,0xc(%rsp)
  lea    0x4b2(%rsp),%r14
  lea    D21(%rip),%r15
  cmpl   $0x0,0x1c(%rsp)
  jg     L36
L87:
  mov    0x518(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x528,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  add    $0x4,%r12
  add    $0x66,%rbp
  cmp    %r14,%rbp
  je     L7
L76:
  cmp    %ebx,(%r12)
  jne    L12
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L12
L7:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x1c(%rsp)
  jl     L87
L36:
  lea    0xb6(%rsp),%rbp
  lea    0x24(%rsp),%r12
  mov    %r12,%r13
  mov    %rbp,%rbx
L9:
  mov    %rbx,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %r13,%rsi
  lea    D38(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x66,%rbx
  add    $0x4,%r13
  cmp    %r14,%rbx
  jne    L9
  mov    0x24(%rsp),%ebx
  lea    0x4c(%rsp),%rcx
  mov    %r12,%rax
L23:
  mov    (%rax),%edx
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L23
  mov    0xc(%rsp),%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D38
type_infered: string
name: parse_data
arguments: tag: D21
type_infered: string
name: parse_data
arguments: tag: D24
type_infered: string

tool: D38: %d

tool: D21: %s

tool: D24: Case #%d:


assistant: ```c
int main() {
  char s[12][102];
  int t, i, ara[12], j, max;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    for (j = 1; j <= 10; j++) {
      scanf("%s", s[j]);
      scanf("%d", &ara[j]);
    }
    max = ara[1];
    for (j = 1; j <= 10; j++) {
      if (ara[j] > max)
        max = ara[j];
    }
    printf("Case #%d:\n", i);
    for (j = 1; j <= 10; j++) {
      if (ara[j] == max) {
        printf("%s\n", s[j]);
      }
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x558,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x548(%rsp)
  xor    %eax,%eax
  lea    0x4c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4c(%rsp),%eax
  test   %eax,%eax
  jle    L81
  lea    0xe6(%rsp),%rax
  movl   $0x1,0xc(%rsp)
  lea    D9(%rip),%r14
  mov    %rax,0x20(%rsp)
  lea    0x54(%rsp),%rax
  mov    %rax,0x30(%rsp)
  lea    0x4e2(%rsp),%rax
  mov    %rax,0x10(%rsp)
  lea    0x58(%rsp),%rax
  mov    %rax,0x38(%rsp)
  lea    0x7c(%rsp),%rax
  mov    %rax,0x28(%rsp)
  nop
L70:
  mov    0x20(%rsp),%r13
  mov    0x30(%rsp),%rbx
  mov    0x10(%rsp),%rbp
  mov    %r13,0x18(%rsp)
  mov    %rbx,%r15
  nopw   0x0(%rax,%rax,1)
L71:
  mov    %r13,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x66,%r13
  call   <scanf@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%r13
  jne    L71
  mov    0x54(%rsp),%ebx
  mov    0x18(%rsp),%r13
  mov    0x38(%rsp),%rax
  mov    0x28(%rsp),%rcx
  mov    %ebx,%edx
  jmp    L19
  xchg   %ax,%ax
L49:
  mov    (%rax),%edx
  add    $0x4,%rax
L19:
  cmp    %edx,%ebx
  cmovl  %edx,%ebx
  cmp    %rcx,%rax
  jne    L49
  mov    0xc(%rsp),%esi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rbp
  jmp    L30
  nopl   0x0(%rax)
L35:
  add    $0x66,%r13
  add    $0x4,%r15
  cmp    %rbp,%r13
  je     L54
L30:
  cmp    %ebx,(%r15)
  jne    L35
  mov    %r13,%rdi
  add    $0x66,%r13
  add    $0x4,%r15
  call   <puts@plt>
  cmp    %rbp,%r13
  jne    L30
L54:
  addl   $0x1,0xc(%rsp)
  mov    0xc(%rsp),%eax
  cmp    %eax,0x4c(%rsp)
  jge    L70
L81:
  mov    0x548(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x558,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string
name: read_data
arguments: label: D9
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string

tool: D12: %d

tool: D9: %s

tool: D24: Case #%d:


assistant: ```c
int main() {
  char s[12][102];
  int t, i, ara[12], j, max;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    for (j = 1; j <= 10; j++) {
      scanf("%s", s[j]);
      scanf("%d", &ara[j]);
    }
    max = ara[1];
    for (j = 1; j <= 10; j++) {
      if (ara[j] > max)
        max = ara[j];
    }
    printf("Case #%d:\n", i);
    for (j = 1; j <= 10; j++) {
      if (ara[j] == max) {
        printf("%s\n", s[j]);
      }
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  sub    $0x99f4bb,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L46
L23:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  addq   $0x2,-0x18(%rbp)
L46:
  cmpq   $0x0,-0x18(%rbp)
  je     L23
  movq   $0x0,-0x18(%rbp)
  jmp    L28
L3:
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  addq   $0x2,-0x18(%rbp)
L28:
  cmpq   $0x0,-0x18(%rbp)
  je     L3
  mov    -0x10(%rbp),%rax
  lea    -0x44edc2d1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 255873917UL) - 900558676UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    -0x475595bd(,%rax,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 255873917UL) - 900558676UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    -0x475595bd(,%rax,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 255873917UL) - 900558676UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  lea    -0x475595bd(,%rax,4),%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    local1 = 0UL;
    while (local1 < 1UL) {
      state[local1] += state[local1];
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 255873917UL) - 900558676UL;
  }
}
```