ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<print>:
  endbr64
  sub    $0x18,%rsp
  sub    $0x1,%edx
  lea    -0x1(%rcx,%rcx,1),%r10d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  test   %r10d,%r10d
  jle    L30
  mov    %rdi,%r9
  mov    %esi,%edi
  lea    0x1(%rcx),%esi
  xor    %ecx,%ecx
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %ecx,%eax
  cltd
  idiv   %esi
  cltq
  mov    (%rsp,%rax,4),%edi
L37:
  mov    %ecx,%eax
  add    %r8d,%edi
  add    $0x1,%ecx
  cltd
  idiv   %esi
  cltq
  mov    %edi,(%rsp,%rax,4)
  movslq (%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    (%r9,%rax,2),%rdx
  movslq 0x4(%rsp),%rax
  movb   $0x3,(%rdx,%rax,1)
  cmp    %r10d,%ecx
  jne    L26
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print(char m[][66], int h, int k, int n, int f) {
  int b[2], y;
  h = h + 1;
  k = k - 1;
  b[0] = h - 1;
  b[1] = k;
  for (y = 0; y < 2 * n - 1; y++) {
    b[y / (n + 1)] = b[y / (n + 1)] + f;
    m[b[0]][b[1]] = 3;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print>:
  endbr64
  sub    $0x1,%edx
  movd   %esi,%xmm0
  lea    -0x1(%rcx,%rcx,1),%r10d
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movd   %edx,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  test   %r10d,%r10d
  jle    L14
  add    %r8d,%esi
  mov    %rdi,%r9
  lea    0x1(%rcx),%edi
  movslq %edx,%rdx
  mov    %esi,(%rsp)
  movslq %esi,%rsi
  mov    $0x1,%ecx
  mov    %rsi,%rax
  shl    $0x5,%rax
  add    %rsi,%rax
  lea    (%r9,%rax,2),%rax
  movb   $0x3,(%rax,%rdx,1)
  cmp    $0x1,%r10d
  je     L14
  nopl   (%rax)
L33:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cltd
  idiv   %edi
  cltq
  add    %r8d,(%rsp,%rax,4)
  movslq (%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    (%r9,%rax,2),%rdx
  movslq 0x4(%rsp),%rax
  movb   $0x3,(%rdx,%rax,1)
  cmp    %r10d,%ecx
  jne    L33
L14:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print(char m[][66], int h, int k, int n, int f) {
  int b[2], y;
  h = h + 1;
  k = k - 1;
  b[0] = h - 1;
  b[1] = k;
  for (y = 0; y < 2 * n - 1; y++) {
    b[y / (n + 1)] = b[y / (n + 1)] + f;
    m[b[0]][b[1]] = 3;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<be64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <be32@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,%rdi
  call   <be32@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x20,%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%ecx
  shl    %cl,%eax
  or     -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint64_t be64(uint8_t *p) {
  uint32_t a, b;
  a = be32(p);
  b = be32(p + 4);
  return ((uint64_t)a << 32) | b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<be64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <be32@plt>
  lea    0x10(%rbx),%rdi
  call   <be32@plt>
  pop    %rbx
  ret
```

assistant: ```c
uint64_t be64(uint8_t *p) {
  uint32_t a, b;
  a = be32(p);
  b = be32(p + 4);
  return ((uint64_t)a << 32) | b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<be64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <be32@plt>
  lea    0x10(%rbx),%rdi
  pop    %rbx
  jmp    1050 <be32@plt>
```

assistant: ```c
uint64_t be64(uint8_t *p) {
  uint32_t a, b;
  a = be32(p);
  b = be32(p + 4);
  return ((uint64_t)a << 32) | b;
}
```
user: What is the c source code of the assembly code below:

```asm
<be64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <be32@plt>
  lea    0x10(%rbx),%rdi
  pop    %rbx
  jmp    1050 <be32@plt>
```

assistant: ```c
uint64_t be64(uint8_t *p) {
  uint32_t a, b;
  a = be32(p);
  b = be32(p + 4);
  return ((uint64_t)a << 32) | b;
}
```
user: What is the c source code of the assembly code below?

```asm
<readLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  mov    $0x51,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L64
L46:
  cmpl   $0x8,-0xc(%rbp)
  jne    L22
  cmpl   $0x0,-0x10(%rbp)
  je     L64
  subl   $0x1,-0x10(%rbp)
  mov    $0x8,%edi
  call   <putchar@plt>
  jmp    L64
L22:
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L64
  cmpl   $0x50,-0x10(%rbp)
  jg     L30
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
L30:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
L64:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xa,-0xc(%rbp)
  jne    L46
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *readLine() {
  int bufferIndex = 0;
  char *buff = malloc(80 + 1);
  int c;
  while ((c = getchar()) != '\n') {
    if (c == '\b') {
      if (bufferIndex != 0) {
        bufferIndex--;
        putchar('\b');
      }
    } else if (c != -1) {
      if (bufferIndex <= 80) {
        buff[bufferIndex++] = c;
      }
      putchar(c);
    }
  }
  buff[bufferIndex] = '\0';
  return buff;
}
```
user: What is the c source code of the assembly code below:

```asm
<readLine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x51,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%ebx
  jmp    L45
L4:
  test   %ebx,%ebx
  je     L45
  sub    $0x1,%ebx
  call   <putchar@plt>
  jmp    L45
L5:
  call   <putchar@plt>
L45:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L13
  cmp    $0x8,%edi
  je     L4
  cmp    $0xffffffff,%edi
  je     L45
  cmp    $0x50,%ebx
  jg     L5
  movslq %ebx,%rax
  mov    %dil,0x0(%rbp,%rax,1)
  lea    0x1(%rbx),%ebx
  jmp    L5
L13:
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *readLine() {
  int bufferIndex = 0;
  char *buff = malloc(80 + 1);
  int c;
  while ((c = getchar()) != '\n') {
    if (c == '\b') {
      if (bufferIndex != 0) {
        bufferIndex--;
        putchar('\b');
      }
    } else if (c != -1) {
      if (bufferIndex <= 80) {
        buff[bufferIndex++] = c;
      }
      putchar(c);
    }
  }
  buff[bufferIndex] = '\0';
  return buff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<readLine>:
  endbr64
  push   %r12
  mov    $0x51,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
L48:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L101
L158:
  cmp    $0x8,%edi
  je     L20
  cmp    $0xffffffff,%edi
  je     L48
  cmp    $0x50,%ebx
  jle    L24
L159:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  jne    L158
L101:
  movslq %ebx,%rbx
  mov    %r12,%rax
  add    %r12,%rbx
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  test   %ebx,%ebx
  je     L134
  mov    $0x8,%edi
  sub    $0x1,%ebx
  call   <putchar@plt>
  jmp    L48
  nopl   0x0(%rax,%rax,1)
L134:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L145
  cmp    $0xffffffff,%eax
  je     L217
  cmp    $0x8,%eax
  je     L217
L2:
  mov    %r12,%rax
  mov    $0x1,%ebx
L213:
  mov    %dil,(%rax)
  jmp    L159
  nopl   (%rax)
L217:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L145
  cmp    $0x8,%eax
  je     L134
  cmp    $0xffffffff,%eax
  jne    L2
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L101
  cmp    $0x8,%eax
  je     L134
  cmp    $0xffffffff,%eax
  je     L63
  nopl   0x0(%rax,%rax,1)
L24:
  movslq %ebx,%rax
  add    $0x1,%ebx
  add    %r12,%rax
  jmp    L213
  nopl   0x0(%rax,%rax,1)
L145:
  mov    %r12,%rbx
  mov    %r12,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
L63:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L101
  cmp    $0x8,%eax
  je     L134
  cmp    $0xffffffff,%eax
  jne    L24
  jmp    L48
```

assistant: ```c
char *readLine() {
  int bufferIndex = 0;
  char *buff = malloc(80 + 1);
  int c;
  while ((c = getchar()) != '\n') {
    if (c == '\b') {
      if (bufferIndex != 0) {
        bufferIndex--;
        putchar('\b');
      }
    } else if (c != -1) {
      if (bufferIndex <= 80) {
        buff[bufferIndex++] = c;
      }
      putchar(c);
    }
  }
  buff[bufferIndex] = '\0';
  return buff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<readLine>:
  endbr64
  push   %r12
  mov    $0x51,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
L162:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L195
L70:
  cmp    $0x8,%edi
  je     L103
  cmp    $0xffffffff,%edi
  je     L162
  cmp    $0x50,%ebx
  jle    L30
L47:
  call   <putchar@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  jne    L70
L195:
  movslq %ebx,%rbx
  mov    %r12,%rax
  add    %r12,%rbx
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L103:
  test   %ebx,%ebx
  je     L69
  mov    $0x8,%edi
  sub    $0x1,%ebx
  call   <putchar@plt>
  jmp    L162
  nopl   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L31
  cmp    $0xffffffff,%eax
  je     L187
  cmp    $0x8,%eax
  je     L187
L15:
  mov    %r12,%rax
  mov    $0x1,%ebx
L35:
  mov    %dil,(%rax)
  jmp    L47
  nopl   (%rax)
L187:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L31
  cmp    $0x8,%eax
  je     L69
  cmp    $0xffffffff,%eax
  jne    L15
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L195
  cmp    $0x8,%eax
  je     L69
  cmp    $0xffffffff,%eax
  je     L210
  nopl   0x0(%rax,%rax,1)
L30:
  movslq %ebx,%rax
  add    $0x1,%ebx
  add    %r12,%rax
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %r12,%rbx
  mov    %r12,%rax
  movb   $0x0,(%rbx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
L210:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  cmp    $0xa,%eax
  je     L195
  cmp    $0x8,%eax
  je     L69
  cmp    $0xffffffff,%eax
  jne    L30
  jmp    L162
```

assistant: ```c
char *readLine() {
  int bufferIndex = 0;
  char *buff = malloc(80 + 1);
  int c;
  while ((c = getchar()) != '\n') {
    if (c == '\b') {
      if (bufferIndex != 0) {
        bufferIndex--;
        putchar('\b');
      }
    } else if (c != -1) {
      if (bufferIndex <= 80) {
        buff[bufferIndex++] = c;
      }
      putchar(c);
    }
  }
  buff[bufferIndex] = '\0';
  return buff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dentro_ret>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    %r8d,-0x14(%rbp)
  mov    %r9d,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L40
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L40
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jg     L40
  mov    -0x18(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L40
  mov    $0x1,%eax
  jmp    L3
L40:
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
dentro_ret(int x0, int y0, int x1, int y1, int x, int y) {
  if (((x <= x1) && (x >= x0)) && ((y <= y1) && (y >= y0)))
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<dentro_ret>:
  endbr64
  cmp    %edx,%r8d
  jg     L9
  cmp    %edi,%r8d
  jl     L9
  cmp    %ecx,%r9d
  setle  %dl
  cmp    %esi,%r9d
  setge  %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
L9:
  mov    $0x0,%eax
  ret
```

assistant: ```c
dentro_ret(int x0, int y0, int x1, int y1, int x, int y) {
  if (((x <= x1) && (x >= x0)) && ((y <= y1) && (y >= y0)))
    return 1;
  else
    return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dentro_ret>:
  endbr64
  cmp    %edx,%r8d
  jg     L11
  cmp    %edi,%r8d
  jl     L11
  cmp    %ecx,%r9d
  setle  %dl
  xor    %eax,%eax
  cmp    %esi,%r9d
  setge  %al
  and    %edx,%eax
  ret
  nop
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
dentro_ret(int x0, int y0, int x1, int y1, int x, int y) {
  if (((x <= x1) && (x >= x0)) && ((y <= y1) && (y >= y0)))
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dentro_ret>:
  endbr64
  cmp    %edx,%r8d
  jg     L17
  cmp    %edi,%r8d
  jl     L17
  cmp    %ecx,%r9d
  setle  %dl
  xor    %eax,%eax
  cmp    %esi,%r9d
  setge  %al
  and    %edx,%eax
  ret
  nop
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
dentro_ret(int x0, int y0, int x1, int y1, int x, int y) {
  if (((x <= x1) && (x >= x0)) && ((y <= y1) && (y >= y0)))
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L41
L18:
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L46
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L46:
  addl   $0x1,-0x10(%rbp)
L41:
  cmpl   $0x0,-0xc(%rbp)
  jne    L18
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D14
data_type: string
name: disassemble_data
arguments: data_label: D15
data_type: string

tool: D14: %d

tool: D15: %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  int flag = 1;
  i = n;
  while (flag) {
    if (!check_prime(i))
      flag = 0;
    else {
      i++;
    }
  }
  printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  jmp    L25
L8:
  add    $0x1,%ebx
L25:
  mov    %ebx,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L8
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D9
datatype: string

tool: D17: %d

tool: D9: %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  int flag = 1;
  i = n;
  while (flag) {
    if (!check_prime(i))
      flag = 0;
    else {
      i++;
    }
  }
  printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  jmp    L26
L11:
  add    $0x1,%ebp
L26:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L11
  mov    %ebp,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D12
type: string
name: retrieve_data
arguments: data_tag: D13
type: string

tool: D12: %d

tool: D13: %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  int flag = 1;
  i = n;
  while (flag) {
    if (!check_prime(i))
      flag = 0;
    else {
      i++;
    }
  }
  printf("%d\n", i);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D18(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebp
  jmp    L13
L15:
  add    $0x1,%ebp
L13:
  mov    %ebp,%edi
  call   <check_prime@plt>
  test   %eax,%eax
  jne    L15
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string

tool: D18: %d

tool: D10: %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  int flag = 1;
  i = n;
  while (flag) {
    if (!check_prime(i))
      flag = 0;
    else {
      i++;
    }
  }
  printf("%d\n", i);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
datatype: string
name: parse_data
arguments: data_tag: D8
datatype: string
name: parse_data
arguments: data_tag: D4
datatype: string

tool: D1: exmasr v%d.%d


tool: D8: usage: exhaust [opts] warriors...

tool: D4: opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,
			-p <maxprocs>, -d <minsep>, -bk

assistant: ```c
void usage(void) {
  printf("exmasr v%d.%d\n", 1, 0);
  printf("usage: exhaust [opts] warriors...\n");
  printf("opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,\n"
         "			-p <maxprocs>, -d <minsep>, -bk\n");
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edx
  mov    $0x1,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D12
type_guessed: string
name: read_data
arguments: label: D10
type_guessed: string
name: read_data
arguments: label: D17
type_guessed: string

tool: D12: exmasr v%d.%d


tool: D10: usage: exhaust [opts] warriors...

tool: D17: opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,
			-p <maxprocs>, -d <minsep>, -bk

assistant: ```c
void usage(void) {
  printf("exmasr v%d.%d\n", 1, 0);
  printf("usage: exhaust [opts] warriors...\n");
  printf("opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,\n"
         "			-p <maxprocs>, -d <minsep>, -bk\n");
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D20
type: string

tool: D15: exmasr v%d.%d


tool: D12: usage: exhaust [opts] warriors...

tool: D20: opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,
			-p <maxprocs>, -d <minsep>, -bk

assistant: ```c
void usage(void) {
  printf("exmasr v%d.%d\n", 1, 0);
  printf("usage: exhaust [opts] warriors...\n");
  printf("opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,\n"
         "			-p <maxprocs>, -d <minsep>, -bk\n");
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  xor    %edx,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1090 <exit@plt>
```

tool_calls: name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D8
data_type: string
name: parse_data
arguments: label: D21
data_type: string

tool: D12: exmasr v%d.%d


tool: D8: usage: exhaust [opts] warriors...

tool: D21: opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,
			-p <maxprocs>, -d <minsep>, -bk

assistant: ```c
void usage(void) {
  printf("exmasr v%d.%d\n", 1, 0);
  printf("usage: exhaust [opts] warriors...\n");
  printf("opts: -r <rounds>, -c <cycles>, -F <pos>, -s <coresize>,\n"
         "			-p <maxprocs>, -d <minsep>, -bk\n");
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isvaliddigit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x31,-0x4(%rbp)
  jle    L14
  cmpl   $0x39,-0x4(%rbp)
  jle    L25
L14:
  mov    $0x0,%eax
  jmp    L0
L25:
  mov    $0x1,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int isvaliddigit(int c) {
  if (c < 50 || c > 57)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<isvaliddigit>:
  endbr64
  sub    $0x32,%edi
  cmp    $0x7,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isvaliddigit(int c) {
  if (c < 50 || c > 57)
    return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<isvaliddigit>:
  endbr64
  sub    $0x32,%edi
  xor    %eax,%eax
  cmp    $0x7,%edi
  setbe  %al
  ret
```

assistant: ```c
int isvaliddigit(int c) {
  if (c < 50 || c > 57)
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<isvaliddigit>:
  endbr64
  sub    $0x32,%edi
  xor    %eax,%eax
  cmp    $0x7,%edi
  setbe  %al
  ret
```

assistant: ```c
int isvaliddigit(int c) {
  if (c < 50 || c > 57)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setup_video>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x0,%eax
  call   <check_cable@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <init_video@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <clrscr@plt>
  nop
  leave
  ret
```

assistant: ```c
void setup_video(unsigned int mode, unsigned int color) {
  init_video(check_cable(), mode);
  clrscr(color);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<setup_video>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <check_cable@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <init_video@plt>
  mov    %ebx,%edi
  call   <clrscr@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void setup_video(unsigned int mode, unsigned int color) {
  init_video(check_cable(), mode);
  clrscr(color);
}
```