ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<ft_atoi>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  movsbl (%rdi),%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  test   %sil,%sil
  je     L60
  lea    -0x1(%rsi),%eax
  mov    %rdi,%rbx
  cmp    $0x1f,%al
  mov    $0x1,%eax
  ja     L12
L13:
  movsbl (%rbx,%rax,1),%esi
  mov    %eax,%ecx
  add    $0x1,%rax
  lea    -0x1(%rsi),%edx
  cmp    $0x1f,%dl
  jbe    L13
  mov    %ecx,0xc(%rsp)
  add    $0x1,%ecx
  movslq %ecx,%rax
L40:
  movq   $0x1,0x10(%rsp)
  movzbl (%rbx,%rax,1),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L34
  movslq %ecx,%rcx
  mov    $0x1,%eax
  lea    0x1(%rbx,%rcx,1),%rcx
  nopl   (%rax)
L73:
  movzbl (%rcx),%edi
  lea    (%rax,%rax,4),%rax
  add    $0x1,%rcx
  add    %rax,%rax
  lea    -0x30(%rdi),%edx
  cmp    $0x9,%dl
  jbe    L73
  mov    %rax,0x10(%rsp)
L34:
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rdi
  call   <is_negative@plt>
  movslq 0xc(%rsp),%rdx
  movzbl (%rbx,%rdx,1),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  ja     L60
  mov    0x10(%rsp),%rcx
  lea    0x1(%rbx,%rdx,1),%rsi
  xor    %r8d,%r8d
  movabs $0x6666666666666667,%rdi
  nopw   0x0(%rax,%rax,1)
L67:
  sub    $0x30,%eax
  add    $0x1,%rsi
  movsbq %al,%rax
  imul   %rcx,%rax
  add    %eax,%r8d
  mov    %rcx,%rax
  imul   %rdi
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rcx
  sub    %rax,%rcx
  movzbl -0x1(%rsi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L67
L29:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  add    $0x20,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L60:
  xor    %r8d,%r8d
  jmp    L29
  nopl   (%rax)
L12:
  mov    $0x1,%ecx
  jmp    L40
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(char *str) {
  int num_start;
  int mult_it;
  long int mult;
  int resault;
  num_start = 0;
  if (str[num_start] == 0)
    return (0);
  while (str[num_start] > 0 && str[num_start] <= 32 && str[num_start] != '-')
    num_start++;
  mult = 1;
  mult_it = num_start;
  while (str[++mult_it] >= '0' && str[mult_it] <= '9')
    mult *= 10;
  is_negative(&mult, str[num_start], &num_start);
  resault = 0;
  while (str[num_start] >= '0' && str[num_start] <= '9') {
    resault += (str[num_start++] - 48) * mult;
    mult /= 10;
  }
  return (resault);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_init@plt>
  movq   $0x0,-0x10(%rbp)
  movl   $0x63,-0x20(%rbp)
  jmp    L11
L13:
  movl   $0x63,-0x1c(%rbp)
  jmp    L33
L78:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <mpz_ui_pow_ui@plt>
  mov    -0x18(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <mpz_sizeinbase@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %edx,%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  ja     L36
  movq   $0x0,-0x8(%rbp)
  jmp    L57
L49:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x18(%rbp),%eax
  mov    $0xa,%ecx
  mov    %eax,%edi
  call   <mpz_tdiv_qr_ui@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <mpz_get_ui@plt>
  add    %rax,-0x8(%rbp)
L57:
  mov    -0x18(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <mpz_cmp_ui@plt>
  test   %rax,%rax
  jne    L49
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L83
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L83
L36:
  nop
L83:
  subl   $0x1,-0x1c(%rbp)
L33:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L78
  subl   $0x1,-0x20(%rbp)
L11:
  cmpl   $0x0,-0x20(%rbp)
  jg     L13
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D0: %zu


assistant: ```c
int main(void) {
  mpz_t r, q;
  mpz_init(r);
  mpz_init(q);
  size_t maxsum = 0;
  int a, b;
  for (a = 99; a > 0; --a) {
    for (b = 99; b > 0; --b) {
      mpz_ui_pow_ui(r, a, b);
      if (mpz_sizeinbase(r, 10) * 9 < maxsum)
        continue;
      size_t digsum = 0;
      while (mpz_cmp_ui(r, 0)) {
        mpz_tdiv_qr_ui(r, q, r, 10);
        digsum += mpz_get_ui(q);
      }
      if (digsum > maxsum)
        maxsum = digsum;
    }
  }
  printf("%zu\n", maxsum);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_init@plt>
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <mpz_init@plt>
  movl   $0x63,0xc(%rsp)
  mov    $0x0,%r14d
  jmp    L7
L33:
  mov    $0xa,%ecx
  mov    $0x0,%ebx
  mov    %ebx,%edx
  mov    $0x0,%ebp
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <mpz_tdiv_qr_ui@plt>
  mov    %ebp,%edi
  call   <mpz_get_ui@plt>
  add    %rax,%r12
L29:
  mov    $0x0,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_cmp_ui@plt>
  test   %rax,%rax
  jne    L33
  cmp    %r12,%r14
  cmovb  %r12,%r14
L12:
  sub    $0x1,%r13d
  je     L64
L30:
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <mpz_ui_pow_ui@plt>
  mov    $0xa,%esi
  mov    %ebx,%edi
  call   <mpz_sizeinbase@plt>
  lea    (%rax,%rax,8),%eax
  cltq
  mov    $0x0,%r12d
  cmp    %r14,%rax
  jb     L12
  jmp    L29
L64:
  subl   $0x1,0xc(%rsp)
  je     L45
L7:
  mov    0xc(%rsp),%r15d
  mov    $0x63,%r13d
  jmp    L30
L45:
  mov    %r14,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D6
datatype: string

tool: D6: %zu


assistant: ```c
int main(void) {
  mpz_t r, q;
  mpz_init(r);
  mpz_init(q);
  size_t maxsum = 0;
  int a, b;
  for (a = 99; a > 0; --a) {
    for (b = 99; b > 0; --b) {
      mpz_ui_pow_ui(r, a, b);
      if (mpz_sizeinbase(r, 10) * 9 < maxsum)
        continue;
      size_t digsum = 0;
      while (mpz_cmp_ui(r, 0)) {
        mpz_tdiv_qr_ui(r, q, r, 10);
        digsum += mpz_get_ui(q);
      }
      if (digsum > maxsum)
        maxsum = digsum;
    }
  }
  printf("%zu\n", maxsum);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  mov    $0x63,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <mpz_init@plt>
  xor    %edi,%edi
  call   <mpz_init@plt>
L57:
  mov    $0x63,%r12d
  nopl   (%rax)
L52:
  xor    %edi,%edi
  mov    %r12d,%edx
  mov    %r14d,%esi
  xor    %ebx,%ebx
  mov    %edi,0xc(%rsp)
  call   <mpz_ui_pow_ui@plt>
  mov    0xc(%rsp),%edi
  mov    $0xa,%esi
  call   <mpz_sizeinbase@plt>
  lea    (%rax,%rax,8),%eax
  cltq
  cmp    %r13,%rax
  jae    L54
  sub    $0x1,%r12d
  jne    L52
L26:
  sub    $0x1,%r14d
  jne    L57
  mov    %r13,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L7:
  xor    %edi,%edi
  xor    %ebp,%ebp
  mov    $0xa,%ecx
  mov    %edi,%edx
  mov    %ebp,%esi
  call   <mpz_tdiv_qr_ui@plt>
  mov    %ebp,%edi
  call   <mpz_get_ui@plt>
  add    %rax,%rbx
L54:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <mpz_cmp_ui@plt>
  test   %rax,%rax
  jne    L7
  cmp    %rbx,%r13
  cmovb  %rbx,%r13
  sub    $0x1,%r12d
  jne    L52
  jmp    L26
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
type_guessed: string

tool: D9: %zu


assistant: ```c
int main(void) {
  mpz_t r, q;
  mpz_init(r);
  mpz_init(q);
  size_t maxsum = 0;
  int a, b;
  for (a = 99; a > 0; --a) {
    for (b = 99; b > 0; --b) {
      mpz_ui_pow_ui(r, a, b);
      if (mpz_sizeinbase(r, 10) * 9 < maxsum)
        continue;
      size_t digsum = 0;
      while (mpz_cmp_ui(r, 0)) {
        mpz_tdiv_qr_ui(r, q, r, 10);
        digsum += mpz_get_ui(q);
      }
      if (digsum > maxsum)
        maxsum = digsum;
    }
  }
  printf("%zu\n", maxsum);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  xor    %edi,%edi
  mov    $0x63,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <mpz_init@plt>
  xor    %edi,%edi
  call   <mpz_init@plt>
L26:
  mov    $0x63,%r12d
  nopl   (%rax)
L46:
  xor    %edi,%edi
  mov    %r12d,%edx
  mov    %r14d,%esi
  xor    %ebx,%ebx
  mov    %edi,0xc(%rsp)
  call   <mpz_ui_pow_ui@plt>
  mov    0xc(%rsp),%edi
  mov    $0xa,%esi
  call   <mpz_sizeinbase@plt>
  lea    (%rax,%rax,8),%eax
  cltq
  cmp    %r13,%rax
  jae    L39
  sub    $0x1,%r12d
  jne    L46
L38:
  sub    $0x1,%r14d
  jne    L26
  mov    %r13,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L13:
  xor    %edi,%edi
  xor    %ebp,%ebp
  mov    $0xa,%ecx
  mov    %edi,%edx
  mov    %ebp,%esi
  call   <mpz_tdiv_qr_ui@plt>
  mov    %ebp,%edi
  call   <mpz_get_ui@plt>
  add    %rax,%rbx
L39:
  xor    %esi,%esi
  xor    %edi,%edi
  call   <mpz_cmp_ui@plt>
  test   %rax,%rax
  jne    L13
  cmp    %rbx,%r13
  cmovb  %rbx,%r13
  sub    $0x1,%r12d
  jne    L46
  jmp    L38
```

tool_calls: name: read_data
arguments: data_tag: D3
type_infered: string

tool: D3: %zu


assistant: ```c
int main(void) {
  mpz_t r, q;
  mpz_init(r);
  mpz_init(q);
  size_t maxsum = 0;
  int a, b;
  for (a = 99; a > 0; --a) {
    for (b = 99; b > 0; --b) {
      mpz_ui_pow_ui(r, a, b);
      if (mpz_sizeinbase(r, 10) * 9 < maxsum)
        continue;
      size_t digsum = 0;
      while (mpz_cmp_ui(r, 0)) {
        mpz_tdiv_qr_ui(r, q, r, 10);
        digsum += mpz_get_ui(q);
      }
      if (digsum > maxsum)
        maxsum = digsum;
    }
  }
  printf("%zu\n", maxsum);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<build_heap_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L19:
  mov    -0x1c(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <adjust_heap_min@plt>
  subl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x4(%rbp)
  jns    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void build_heap_min(int matrix[], int length) {
  int i;
  for (i = length / 2 - 1; i >= 0; i--) {
    adjust_heap_min(matrix, i, length);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<build_heap_min>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  sub    $0x1,%ebx
  js     L3
L15:
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <adjust_heap_min@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L15
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_heap_min(int matrix[], int length) {
  int i;
  for (i = length / 2 - 1; i >= 0; i--) {
    adjust_heap_min(matrix, i, length);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<build_heap_min>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  sub    $0x1,%ebx
  js     L13
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <adjust_heap_min@plt>
  sub    $0x1,%ebx
  jae    L10
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_heap_min(int matrix[], int length) {
  int i;
  for (i = length / 2 - 1; i >= 0; i--) {
    adjust_heap_min(matrix, i, length);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<build_heap_min>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  sub    $0x1,%ebx
  js     L16
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ebx,%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <adjust_heap_min@plt>
  sub    $0x1,%ebx
  jae    L15
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void build_heap_min(int matrix[], int length) {
  int i;
  for (i = length / 2 - 1; i >= 0; i--) {
    adjust_heap_min(matrix, i, length);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <decimalBinario@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D27
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string

tool: D0: Introduzca un valor decimal:

tool: D27: %d

tool: D19: 


assistant: ```c
int main() {
  int num;
  printf("Introduzca un valor decimal:");
  scanf("%d", &num);
  decimalBinario(num);
  printf("\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <decimalBinario@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: string
name: retrieve_data
arguments: data_label: D17
type_guessed: string
name: retrieve_data
arguments: data_label: D22
type_guessed: string

tool: D4: Introduzca un valor decimal:

tool: D17: %d

tool: D22: 


assistant: ```c
int main() {
  int num;
  printf("Introduzca un valor decimal:");
  scanf("%d", &num);
  decimalBinario(num);
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D25(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <decimalBinario@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D25
data_type: string
name: parse_data
arguments: tag: D17
data_type: string
name: parse_data
arguments: tag: D8
data_type: string

tool: D25: Introduzca un valor decimal:

tool: D17: %d

tool: D8: 


assistant: ```c
int main() {
  int num;
  printf("Introduzca un valor decimal:");
  scanf("%d", &num);
  decimalBinario(num);
  printf("\n");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <decimalBinario@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D2
data_type: string
name: retrieve_data
arguments: data_label: D9
data_type: string

tool: D21: Introduzca un valor decimal:

tool: D2: %d

tool: D9: 


assistant: ```c
int main() {
  int num;
  printf("Introduzca un valor decimal:");
  scanf("%d", &num);
  decimalBinario(num);
  printf("\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<doTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L6:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: string

tool: D18: failure during test of %s


tool: D4: %s passed tests


assistant: ```c
int doTest(int test, char *methodName) {
  if (test) {
    printf("failure during test of %s\n", methodName);
  } else {
    printf("%s passed tests\n", methodName);
  }
  return test;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<doTest>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  je     L15
  lea    D5(%rip),%rdi
  call   <printf@plt>
L4:
  mov    %ebx,%eax
  pop    %rbx
  ret
L15:
  lea    D1(%rip),%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string
name: unpack_data
arguments: label: D1
datatype: string

tool: D5: failure during test of %s


tool: D1: %s passed tests


assistant: ```c
int doTest(int test, char *methodName) {
  if (test) {
    printf("failure during test of %s\n", methodName);
  } else {
    printf("%s passed tests\n", methodName);
  }
  return test;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<doTest>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  test   %edi,%edi
  je     L2
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L2:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: label: D18
data_type: string
name: read_data
arguments: label: D8
data_type: string

tool: D18: failure during test of %s


tool: D8: %s passed tests


assistant: ```c
int doTest(int test, char *methodName) {
  if (test) {
    printf("failure during test of %s\n", methodName);
  } else {
    printf("%s passed tests\n", methodName);
  }
  return test;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<doTest>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  test   %edi,%edi
  je     L3
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nop
L3:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string

tool: D15: failure during test of %s


tool: D3: %s passed tests


assistant: ```c
int doTest(int test, char *methodName) {
  if (test) {
    printf("failure during test of %s\n", methodName);
  } else {
    printf("%s passed tests\n", methodName);
  }
  return test;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_rc2_pow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L36
  mov    $0x1,%eax
  jmp    L9
L36:
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L15:
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L15
  mov    -0x4(%rbp),%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int _rc2_pow(base, exponent) {
  int i, result;
  if (exponent == 0) {
    return 1;
  }
  result = 1;
  for (i = 0; i < exponent; i++) {
    result = result * base;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_rc2_pow>:
  endbr64
  test   %esi,%esi
  jle    L11
  mov    $0x1,%edx
  mov    $0x0,%eax
L18:
  imul   %edi,%edx
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L18
L9:
  mov    %edx,%eax
  ret
L11:
  mov    $0x1,%edx
  jmp    L9
```

assistant: ```c
int _rc2_pow(base, exponent) {
  int i, result;
  if (exponent == 0) {
    return 1;
  }
  result = 1;
  for (i = 0; i < exponent; i++) {
    result = result * base;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_rc2_pow>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L16
  xor    %eax,%eax
L10:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L10
L16:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _rc2_pow(base, exponent) {
  int i, result;
  if (exponent == 0) {
    return 1;
  }
  result = 1;
  for (i = 0; i < exponent; i++) {
    result = result * base;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_rc2_pow>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L13
  xor    %eax,%eax
L10:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L10
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int _rc2_pow(base, exponent) {
  int i, result;
  if (exponent == 0) {
    return 1;
  }
  result = 1;
  for (i = 0; i < exponent; i++) {
    result = result * base;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0x70,%eax
  je     L67
  cmp    $0x70,%eax
  jg     L36
  cmp    $0x1b,%eax
  je     L11
  cmp    $0x68,%eax
  je     L6
  jmp    L36
L67:
  mov    $0x0,%eax
  call   <pfunc@plt>
  jmp    L44
L6:
  mov    $0x0,%eax
  call   <help@plt>
  jmp    L44
L11:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <exit@plt>
  jmp    L44
L36:
  nop
L44:
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  nop
  leave
  ret
```

assistant: ```c
void key(unsigned char key, int x, int y) {
  switch (key) {
  case 'p':
    pfunc();
    break;
  case 'h':
    help();
    break;
  case '\033':
    exit(EXIT_SUCCESS);
    break;
  default:
    break;
  }
  glutPostRedisplay();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<key>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x68,%dil
  je     L49
  cmp    $0x70,%dil
  je     L1
  cmp    $0x1b,%dil
  je     L23
L0:
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  add    $0x8,%rsp
  ret
L1:
  mov    $0x0,%eax
  call   <pfunc@plt>
  jmp    L0
L49:
  mov    $0x0,%eax
  call   <help@plt>
  jmp    L0
L23:
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <exit@plt>
  jmp    L0
```

assistant: ```c
void key(unsigned char key, int x, int y) {
  switch (key) {
  case 'p':
    pfunc();
    break;
  case 'h':
    help();
    break;
  case '\033':
    exit(EXIT_SUCCESS);
    break;
  default:
    break;
  }
  glutPostRedisplay();
}
```