ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D3(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L17
  lea    D16(%rip),%rbx
  jmp    L31
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %rbx,%rdi
  call   <printf@plt>
L31:
  xor    %eax,%eax
  call   <test_case@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L22
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D16
type_infered: string

tool: D3: %d

tool: D16: 


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int first = 1;
  while (n--) {
    if (first)
      first = 0;
    else
      printf("\n");
    test_case();
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hex2dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x1(%rbp)
  cmpb   $0x61,-0x14(%rbp)
  jle    L36
  movzbl -0x14(%rbp),%eax
  sub    $0x57,%eax
  mov    %al,-0x1(%rbp)
  jmp    L4
L36:
  cmpb   $0x41,-0x14(%rbp)
  jle    L12
  movzbl -0x14(%rbp),%eax
  sub    $0x37,%eax
  mov    %al,-0x1(%rbp)
  jmp    L4
L12:
  movzbl -0x14(%rbp),%eax
  sub    $0x30,%eax
  mov    %al,-0x1(%rbp)
L4:
  movzbl -0x1(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
char hex2dec(char nibble) {
  char val = 0;
  if (nibble > 'a') {
    val = nibble - 'a' + 10;
  } else if (nibble > 'A') {
    val = nibble - 'A' + 10;
  } else {
    val = nibble - '0';
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex2dec>:
  endbr64
  cmp    $0x61,%dil
  jle    L0
  lea    -0x57(%rdi),%eax
  ret
L0:
  lea    -0x37(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x42,%dil
  cmovge %edx,%eax
  ret
```

assistant: ```c
char hex2dec(char nibble) {
  char val = 0;
  if (nibble > 'a') {
    val = nibble - 'a' + 10;
  } else if (nibble > 'A') {
    val = nibble - 'A' + 10;
  } else {
    val = nibble - '0';
  }
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hex2dec>:
  endbr64
  cmp    $0x61,%dil
  jle    L0
  lea    -0x57(%rdi),%eax
  ret
  xchg   %ax,%ax
L0:
  lea    -0x37(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x42,%dil
  cmovge %edx,%eax
  ret
```

assistant: ```c
char hex2dec(char nibble) {
  char val = 0;
  if (nibble > 'a') {
    val = nibble - 'a' + 10;
  } else if (nibble > 'A') {
    val = nibble - 'A' + 10;
  } else {
    val = nibble - '0';
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hex2dec>:
  endbr64
  cmp    $0x61,%dil
  jle    L0
  lea    -0x57(%rdi),%eax
  ret
  xchg   %ax,%ax
L0:
  lea    -0x37(%rdi),%edx
  lea    -0x30(%rdi),%eax
  cmp    $0x42,%dil
  cmovge %edx,%eax
  ret
```

assistant: ```c
char hex2dec(char nibble) {
  char val = 0;
  if (nibble > 'a') {
    val = nibble - 'a' + 10;
  } else if (nibble > 'A') {
    val = nibble - 'A' + 10;
  } else {
    val = nibble - '0';
  }
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<startup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <rcc_init@plt>
  mov    $0x0,%eax
  call   <serial_init@plt>
  mov    $0xd,%edi
  call   <led_init@plt>
L10:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L1
  mov    $0x0,%eax
  call   <led_show@plt>
L1:
  mov    $0x61,%edi
  call   <serial_putc@plt>
  mov    $0x41,%edi
  call   <serial_putc@plt>
  mov    $0x0,%eax
  call   <delay@plt>
  jmp    L10
```

assistant: ```c
void startup(void) {
  int count = 0;
  rcc_init();
  serial_init();
  led_init(13);
  for (;;) {
    if ((++count % 16) == 0)
      led_show();
    serial_putc('a');
    serial_putc('A');
    delay();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<startup>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rcc_init@plt>
  mov    $0x0,%eax
  call   <serial_init@plt>
  mov    $0xd,%edi
  call   <led_init@plt>
  mov    $0x1,%ebx
L8:
  mov    $0x61,%edi
  call   <serial_putc@plt>
  mov    $0x41,%edi
  call   <serial_putc@plt>
  mov    $0x0,%eax
  call   <delay@plt>
  add    $0x1,%ebx
  test   $0xf,%bl
  jne    L8
  mov    $0x0,%eax
  call   <led_show@plt>
  jmp    L8
```

assistant: ```c
void startup(void) {
  int count = 0;
  rcc_init();
  serial_init();
  led_init(13);
  for (;;) {
    if ((++count % 16) == 0)
      led_show();
    serial_putc('a');
    serial_putc('A');
    delay();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<startup>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <rcc_init@plt>
  xor    %eax,%eax
  call   <serial_init@plt>
  mov    $0xd,%edi
  call   <led_init@plt>
  nopw   0x0(%rax,%rax,1)
L10:
  mov    $0x61,%edi
  add    $0x1,%ebx
  call   <serial_putc@plt>
  mov    $0x41,%edi
  call   <serial_putc@plt>
  xor    %eax,%eax
  call   <delay@plt>
  test   $0xf,%bl
  jne    L10
  xor    %eax,%eax
  call   <led_show@plt>
  jmp    L10
```

assistant: ```c
void startup(void) {
  int count = 0;
  rcc_init();
  serial_init();
  led_init(13);
  for (;;) {
    if ((++count % 16) == 0)
      led_show();
    serial_putc('a');
    serial_putc('A');
    delay();
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<startup>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    $0x1,%ebx
  call   <rcc_init@plt>
  xor    %eax,%eax
  call   <serial_init@plt>
  mov    $0xd,%edi
  call   <led_init@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0x61,%edi
  add    $0x1,%ebx
  call   <serial_putc@plt>
  mov    $0x41,%edi
  call   <serial_putc@plt>
  xor    %eax,%eax
  call   <delay@plt>
  test   $0xf,%bl
  jne    L0
  xor    %eax,%eax
  call   <led_show@plt>
  jmp    L0
```

assistant: ```c
void startup(void) {
  int count = 0;
  rcc_init();
  serial_init();
  led_init(13);
  for (;;) {
    if ((++count % 16) == 0)
      led_show();
    serial_putc('a');
    serial_putc('A');
    delay();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Q_CopyString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <Z_Malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *Q_CopyString(const char *in) {
  char *out;
  out = Z_Malloc(strlen(in) + 1);
  strcpy(out, in);
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Q_CopyString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <Z_Malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *Q_CopyString(const char *in) {
  char *out;
  out = Z_Malloc(strlen(in) + 1);
  strcpy(out, in);
  return out;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Q_CopyString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <Z_Malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *Q_CopyString(const char *in) {
  char *out;
  out = Z_Malloc(strlen(in) + 1);
  strcpy(out, in);
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Q_CopyString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <Z_Malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *Q_CopyString(const char *in) {
  char *out;
  out = Z_Malloc(strlen(in) + 1);
  strcpy(out, in);
  return out;
}
```
user: What is the c source code of the assembly code below:

```asm
<Fatal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Cleanup@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Fatal(void) {
  Cleanup();
  exit(1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Fatal>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Cleanup@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void Fatal(void) {
  Cleanup();
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Fatal>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cleanup@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void Fatal(void) {
  Cleanup();
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<Fatal>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cleanup@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void Fatal(void) {
  Cleanup();
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<calc_padding_ccc>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%r9d
  mov    %rcx,%rsi
  lea    0x7(%rdi),%edx
  test   %edi,%edi
  cmovns %edi,%edx
  sar    $0x3,%edx
  and    $0x7,%edi
  cmp    $0x1,%edi
  sbb    $0xffffffff,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rax,2),%eax
  add    %eax,%eax
  sub    %eax,%edx
  add    %ecx,%edx
  mov    $0x7,%ecx
  cmp    $0x500,%edx
  jg     L10
  cmp    $0x280,%edx
  jg     L12
  cmp    $0x140,%edx
  jg     L37
  cmp    $0xa0,%edx
  jg     L73
  cmp    $0x28,%edx
  setg   %cl
  movzbl %cl,%ecx
  add    $0x2,%ecx
L10:
  mov    %ecx,(%rsi)
  add    $0x2,%ecx
  mov    $0x1,%eax
  mov    $0x1,%edi
L55:
  add    %edi,%edi
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L55
  lea    0x3(%rdx,%rdi,1),%esi
  sub    $0x3e,%r9d
  movslq %r9d,%rcx
  imul   $0x78787879,%rcx,%rcx
  sar    $0x23,%rcx
  sar    $0x1f,%r9d
  sub    %r9d,%ecx
L65:
  add    $0x1,%ecx
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r9d
  cmp    $0x5a,%eax
  jg     L65
  mov    %ecx,(%r8)
  mov    %esi,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  sbb    $0xffffffff,%r9d
  imul   %r9d,%ecx
  mov    $0x0,%eax
  cmp    $0x3a0,%ecx
  jg     L98
  sub    %edi,%ecx
  sub    $0x3,%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  lea    (%rax,%rax,4),%eax
  sub    %eax,%ecx
  lea    (%rcx,%rdx,2),%eax
  shl    $0x3,%eax
  ret
L73:
  mov    $0x4,%ecx
  jmp    L10
L37:
  mov    $0x5,%ecx
  jmp    L10
L12:
  mov    $0x6,%ecx
  jmp    L10
L98:
  ret
```

assistant: ```c
int calc_padding_ccc(int binary_length, int *cc_width, int lin_width, int *ecc) {
  int target_bitsize = 0;
  int byte_length, codewords_used, ecc_level, ecc_codewords, rows;
  int codewords_total, target_codewords, target_bytesize;
  int i;
  byte_length = binary_length / 8;
  if (binary_length % 8 != 0) {
    byte_length++;
  }
  codewords_used = (byte_length / 6) * 5;
  codewords_used += byte_length % 6;
  ecc_level = 7;
  if (codewords_used <= 1280) {
    ecc_level = 6;
  }
  if (codewords_used <= 640) {
    ecc_level = 5;
  }
  if (codewords_used <= 320) {
    ecc_level = 4;
  }
  if (codewords_used <= 160) {
    ecc_level = 3;
  }
  if (codewords_used <= 40) {
    ecc_level = 2;
  }
  *(ecc) = ecc_level;
  ecc_codewords = 1;
  for (i = 1; i <= (ecc_level + 1); i++) {
    ecc_codewords *= 2;
  }
  codewords_used += ecc_codewords;
  codewords_used += 3;
  *(cc_width) = (lin_width - 62) / 17;
  do {
    *(cc_width) = *(cc_width) + 1;
    rows = codewords_used / *(cc_width);
  } while (rows > 90);
  if (codewords_used % *(cc_width) != 0) {
    rows++;
  }
  codewords_total = *(cc_width)*rows;
  if (codewords_total > 928) {
    return 0;
  }
  target_codewords = codewords_total - ecc_codewords;
  target_codewords -= 3;
  target_bytesize = 6 * (target_codewords / 5);
  target_bytesize += target_codewords % 5;
  target_bitsize = 8 * target_bytesize;
  return target_bitsize;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<calc_padding_ccc>:
  endbr64
  test   %edi,%edi
  mov    %edx,%r9d
  lea    0x7(%rdi),%edx
  mov    %rsi,%r8
  cmovns %edi,%edx
  and    $0x7,%edi
  mov    %rcx,%rsi
  sar    $0x3,%edx
  cmp    $0x1,%edi
  sbb    $0xffffffff,%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x2aaaaaab,%rax,%rax
  sar    $0x1f,%ecx
  shr    $0x20,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  lea    (%rax,%rax,2),%eax
  add    %eax,%eax
  sub    %eax,%edx
  add    %ecx,%edx
  mov    $0x7,%ecx
  cmp    $0x500,%edx
  jg     L2
  cmp    $0x280,%edx
  jg     L46
  cmp    $0x140,%edx
  jg     L39
  cmp    $0xa0,%edx
  jg     L25
  xor    %ecx,%ecx
  cmp    $0x28,%edx
  setg   %cl
  add    $0x2,%ecx
L2:
  mov    %ecx,(%rsi)
  mov    $0x1,%eax
  add    $0x2,%ecx
  mov    $0x1,%edi
  nopl   (%rax)
L63:
  add    $0x1,%eax
  add    %edi,%edi
  cmp    %ecx,%eax
  jne    L63
  sub    $0x3e,%r9d
  lea    0x3(%rdx,%rdi,1),%esi
  movslq %r9d,%rcx
  sar    $0x1f,%r9d
  imul   $0x78787879,%rcx,%rcx
  sar    $0x23,%rcx
  sub    %r9d,%ecx
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %esi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  cmp    $0x5a,%eax
  jg     L6
  cmp    $0x1,%edx
  mov    %ecx,(%r8)
  sbb    $0xffffffff,%eax
  imul   %eax,%ecx
  xor    %eax,%eax
  cmp    $0x3a0,%ecx
  jg     L88
  sub    %edi,%ecx
  sub    $0x3,%ecx
  movslq %ecx,%rax
  mov    %ecx,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,2),%edx
  lea    (%rax,%rax,4),%eax
  sub    %eax,%ecx
  lea    (%rcx,%rdx,2),%eax
  shl    $0x3,%eax
L88:
  ret
L46:
  mov    $0x6,%ecx
  jmp    L2
L25:
  mov    $0x4,%ecx
  jmp    L2
L39:
  mov    $0x5,%ecx
  jmp    L2
```

assistant: ```c
int calc_padding_ccc(int binary_length, int *cc_width, int lin_width, int *ecc) {
  int target_bitsize = 0;
  int byte_length, codewords_used, ecc_level, ecc_codewords, rows;
  int codewords_total, target_codewords, target_bytesize;
  int i;
  byte_length = binary_length / 8;
  if (binary_length % 8 != 0) {
    byte_length++;
  }
  codewords_used = (byte_length / 6) * 5;
  codewords_used += byte_length % 6;
  ecc_level = 7;
  if (codewords_used <= 1280) {
    ecc_level = 6;
  }
  if (codewords_used <= 640) {
    ecc_level = 5;
  }
  if (codewords_used <= 320) {
    ecc_level = 4;
  }
  if (codewords_used <= 160) {
    ecc_level = 3;
  }
  if (codewords_used <= 40) {
    ecc_level = 2;
  }
  *(ecc) = ecc_level;
  ecc_codewords = 1;
  for (i = 1; i <= (ecc_level + 1); i++) {
    ecc_codewords *= 2;
  }
  codewords_used += ecc_codewords;
  codewords_used += 3;
  *(cc_width) = (lin_width - 62) / 17;
  do {
    *(cc_width) = *(cc_width) + 1;
    rows = codewords_used / *(cc_width);
  } while (rows > 90);
  if (codewords_used % *(cc_width) != 0) {
    rows++;
  }
  codewords_total = *(cc_width)*rows;
  if (codewords_total > 928) {
    return 0;
  }
  target_codewords = codewords_total - ecc_codewords;
  target_codewords -= 3;
  target_bytesize = 6 * (target_codewords / 5);
  target_bytesize += target_codewords % 5;
  target_bitsize = 8 * target_bytesize;
  return target_bitsize;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_opt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  je     L16
  nop
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L9
L16:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char read_opt() {
  char c = getchar();
  if (c != '\n') {
    while (getchar() != '\n')
      ;
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<read_opt>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%al
  je     L17
L11:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L11
L17:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char read_opt() {
  char c = getchar();
  if (c != '\n') {
    while (getchar() != '\n')
      ;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_opt>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0xa,%al
  je     L17
  nopl   0x0(%rax)
L18:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L18
L17:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char read_opt() {
  char c = getchar();
  if (c != '\n') {
    while (getchar() != '\n')
      ;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_opt>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%r12d
  cmp    $0xa,%al
  je     L6
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L15
L6:
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char read_opt() {
  char c = getchar();
  if (c != '\n') {
    while (getchar() != '\n')
      ;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<PrintSumm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    %ecx,-0x14(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L16
  mov    -0x10(%rbp),%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L16:
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  cmpl   $0x0,-0x14(%rbp)
  jle    L21
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L21:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D15
type: string

tool: D29: %3s driver: %d out of %d tests failed to pass the threshold


tool: D10: All tests for %3s driver passed the threshold (%6d tests run)


tool: D15: %6d error messages recorded


assistant: ```c
void PrintSumm(char *type, int nfail, int nrun, int nerrs) {
  if (nfail > 0)
    printf("%3s driver: %d out of %d tests failed to pass the threshold\n", type, nfail, nrun);
  else
    printf("All tests for %3s driver passed the threshold (%6d tests run)\n", type, nrun);
  if (nerrs > 0)
    printf("%6d error messages recorded\n", nerrs);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<PrintSumm>:
  endbr64
  push   %rbx
  mov    %ecx,%ebx
  test   %esi,%esi
  jle    L8
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  test   %ebx,%ebx
  jg     L26
L38:
  pop    %rbx
  ret
L8:
  mov    %rdi,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L4
L26:
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D26
type: string
name: retrieve_data
arguments: data_label: D20
type: string

tool: D13: %3s driver: %d out of %d tests failed to pass the threshold


tool: D26: All tests for %3s driver passed the threshold (%6d tests run)


tool: D20: %6d error messages recorded


assistant: ```c
void PrintSumm(char *type, int nfail, int nrun, int nerrs) {
  if (nfail > 0)
    printf("%3s driver: %d out of %d tests failed to pass the threshold\n", type, nfail, nrun);
  else
    printf("All tests for %3s driver passed the threshold (%6d tests run)\n", type, nrun);
  if (nerrs > 0)
    printf("%6d error messages recorded\n", nerrs);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<PrintSumm>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  test   %esi,%esi
  jle    L15
  mov    %edx,%ecx
  xor    %eax,%eax
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L20:
  test   %ebp,%ebp
  jg     L16
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L15:
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L20
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string
name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: string

tool: D5: %3s driver: %d out of %d tests failed to pass the threshold


tool: D18: %6d error messages recorded


tool: D23: All tests for %3s driver passed the threshold (%6d tests run)


assistant: ```c
void PrintSumm(char *type, int nfail, int nrun, int nerrs) {
  if (nfail > 0)
    printf("%3s driver: %d out of %d tests failed to pass the threshold\n", type, nfail, nrun);
  else
    printf("All tests for %3s driver passed the threshold (%6d tests run)\n", type, nrun);
  if (nerrs > 0)
    printf("%6d error messages recorded\n", nerrs);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrintSumm>:
  endbr64
  push   %rbp
  mov    %ecx,%ebp
  test   %esi,%esi
  jle    L18
  mov    %edx,%ecx
  xor    %eax,%eax
  mov    %esi,%edx
  mov    %rdi,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
L4:
  test   %ebp,%ebp
  jg     L15
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  pop    %rbp
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L18:
  mov    %rdi,%rsi
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D22
type_guessed: string

tool: D24: %3s driver: %d out of %d tests failed to pass the threshold


tool: D10: %6d error messages recorded


tool: D22: All tests for %3s driver passed the threshold (%6d tests run)


assistant: ```c
void PrintSumm(char *type, int nfail, int nrun, int nerrs) {
  if (nfail > 0)
    printf("%3s driver: %d out of %d tests failed to pass the threshold\n", type, nfail, nrun);
  else
    printf("All tests for %3s driver passed the threshold (%6d tests run)\n", type, nrun);
  if (nerrs > 0)
    printf("%6d error messages recorded\n", nerrs);
}
```