ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  movss  0x4(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D27(%rip),%rdi
  addss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  lea    D48(%rip),%rdi
  movss  D36(%rip),%xmm0
  mulss  0x4(%rsp),%xmm0
  mov    $0x1,%eax
  addss  %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x4(%rsp),%xmm1
  movss  D36(%rip),%xmm0
  lea    D3(%rip),%rdi
  mov    $0x1,%eax
  mulss  %xmm1,%xmm0
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D10
type_infered: string
name: read_data
arguments: data_label: D35
type_infered: string
name: read_data
arguments: data_label: D27
type_infered: string
name: read_data
arguments: data_label: D48
type_infered: string
name: read_data
arguments: data_label: D36
type_infered: f32
name: read_data
arguments: data_label: D3
type_infered: string

tool: D10: Insert circle radius: 

tool: D35: %f

tool: D27: Diameter is %.2f


tool: D48: Circumference is %.2f


tool: D36: 3.14159

tool: D3: Area is %.2f


assistant: ```c
int main(void) {
  float r;
  const float PI = 3.14159;
  printf("Insert circle radius: ");
  scanf("%f", &r);
  printf("Diameter is %.2f\n", 2 * r);
  printf("Circumference is %.2f\n", PI * r * 2);
  printf("Area is %.2f\n", PI * r * r);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<opjump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <outstr@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <printlabel@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string

tool: D4: jp	

assistant: ```c
void opjump(char *cc, int label) {
  ot("jp\t");
  outstr(cc);
  printlabel(label);
  nl();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<opjump>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  lea    D3(%rip),%rdi
  call   <ot@plt>
  mov    %rbp,%rdi
  call   <outstr@plt>
  mov    %ebx,%edi
  call   <printlabel@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: jp	

assistant: ```c
void opjump(char *cc, int label) {
  ot("jp\t");
  outstr(cc);
  printlabel(label);
  nl();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<opjump>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D8(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <ot@plt>
  mov    %r12,%rdi
  call   <outstr@plt>
  mov    %ebp,%edi
  call   <printlabel@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <nl@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8: jp	

assistant: ```c
void opjump(char *cc, int label) {
  ot("jp\t");
  outstr(cc);
  printlabel(label);
  nl();
}
```
user: Translate the below assembly code into C programming language:

```asm
<opjump>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  lea    D6(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x8,%rsp
  call   <ot@plt>
  mov    %r12,%rdi
  call   <outstr@plt>
  mov    %ebp,%edi
  call   <printlabel@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1090 <nl@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: jp	

assistant: ```c
void opjump(char *cc, int label) {
  ot("jp\t");
  outstr(cc);
  printlabel(label);
  nl();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pad_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x5,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  neg    %eax
  and    $0x7,%eax
  pop    %rbp
  ret
```

assistant: ```c
int pad_size(int nof_channels) {
  int bits = 5 + nof_channels * 11;
  return ((8 - (bits & 7)) & 7);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pad_size>:
  endbr64
  lea    (%rdi,%rdi,4),%eax
  lea    0x5(%rdi,%rax,2),%eax
  neg    %eax
  and    $0x7,%eax
  ret
```

assistant: ```c
int pad_size(int nof_channels) {
  int bits = 5 + nof_channels * 11;
  return ((8 - (bits & 7)) & 7);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pad_size>:
  endbr64
  lea    (%rdi,%rdi,4),%eax
  lea    0x5(%rdi,%rax,2),%eax
  neg    %eax
  and    $0x7,%eax
  ret
```

assistant: ```c
int pad_size(int nof_channels) {
  int bits = 5 + nof_channels * 11;
  return ((8 - (bits & 7)) & 7);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__address_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpq   $0x4,-0x8(%rbp)
  je     L1
  cmpq   $0x4,-0x8(%rbp)
  ja     L27
  cmpq   $0x1,-0x8(%rbp)
  je     L58
  cmpq   $0x2,-0x8(%rbp)
  je     L15
  jmp    L27
L1:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <uvisor_write32@plt>
  jmp    L27
L15:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <uvisor_write16@plt>
  jmp    L27
L58:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <uvisor_write8@plt>
  nop
L27:
  nop
  leave
  ret
```

assistant: ```c
__attribute__((always_)) void __address_write(size_t sizeof_type, volatile uint32_t *addr, uint32_t val) {
  switch (sizeof_type) {
  case 4:
    uvisor_write32((volatile uint32_t *)addr, (uint32_t)val);
    break;
  case 2:
    uvisor_write16((volatile uint16_t *)addr, (uint16_t)val);
    break;
  case 1:
    uvisor_write8((volatile uint8_t *)addr, (uint8_t)val);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__address_write>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %edx,%esi
  cmp    $0x2,%rax
  je     L51
  cmp    $0x4,%rax
  je     L10
  cmp    $0x1,%rax
  je     L36
L55:
  add    $0x8,%rsp
  ret
L10:
  call   <uvisor_write32@plt>
  jmp    L55
L51:
  call   <uvisor_write16@plt>
  jmp    L55
L36:
  call   <uvisor_write8@plt>
  jmp    L55
```

assistant: ```c
__attribute__((always_)) void __address_write(size_t sizeof_type, volatile uint32_t *addr, uint32_t val) {
  switch (sizeof_type) {
  case 4:
    uvisor_write32((volatile uint32_t *)addr, (uint32_t)val);
    break;
  case 2:
    uvisor_write16((volatile uint16_t *)addr, (uint16_t)val);
    break;
  case 1:
    uvisor_write8((volatile uint8_t *)addr, (uint8_t)val);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__address_write>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %edx,%esi
  cmp    $0x2,%rax
  je     L6
  cmp    $0x4,%rax
  je     L21
  cmp    $0x1,%rax
  je     L28
  ret
  nop
L6:
  jmp    1080 <uvisor_write16@plt>
  nopl   (%rax)
L28:
  jmp    1090 <uvisor_write8@plt>
  nopl   (%rax)
L21:
  jmp    1070 <uvisor_write32@plt>
```

assistant: ```c
__attribute__((always_)) void __address_write(size_t sizeof_type, volatile uint32_t *addr, uint32_t val) {
  switch (sizeof_type) {
  case 4:
    uvisor_write32((volatile uint32_t *)addr, (uint32_t)val);
    break;
  case 2:
    uvisor_write16((volatile uint16_t *)addr, (uint16_t)val);
    break;
  case 1:
    uvisor_write8((volatile uint8_t *)addr, (uint8_t)val);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__address_write>:
  endbr64
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %edx,%esi
  cmp    $0x2,%rax
  je     L23
  cmp    $0x4,%rax
  je     L3
  cmp    $0x1,%rax
  je     L12
  ret
  nop
L23:
  jmp    1080 <uvisor_write16@plt>
  nopl   (%rax)
L12:
  jmp    1090 <uvisor_write8@plt>
  nopl   (%rax)
L3:
  jmp    1070 <uvisor_write32@plt>
```

assistant: ```c
__attribute__((always_)) void __address_write(size_t sizeof_type, volatile uint32_t *addr, uint32_t val) {
  switch (sizeof_type) {
  case 4:
    uvisor_write32((volatile uint32_t *)addr, (uint32_t)val);
    break;
  case 2:
    uvisor_write16((volatile uint16_t *)addr, (uint16_t)val);
    break;
  case 1:
    uvisor_write8((volatile uint8_t *)addr, (uint8_t)val);
    break;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setPercHarmonicFromMIDI>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpb   $0x3f,-0x1c(%rbp)
  seta   %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <setPercussionFirst@plt>
  nop
  leave
  ret
```

assistant: ```c
void setPercHarmonicFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionFirst(t, u < 64 ? 0 : 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<setPercHarmonicFromMIDI>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3f,%sil
  seta   %sil
  movzbl %sil,%esi
  call   <setPercussionFirst@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void setPercHarmonicFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionFirst(t, u < 64 ? 0 : 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<setPercHarmonicFromMIDI>:
  endbr64
  cmp    $0x3f,%sil
  seta   %sil
  movzbl %sil,%esi
  jmp    1050 <setPercussionFirst@plt>
```

assistant: ```c
void setPercHarmonicFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionFirst(t, u < 64 ? 0 : 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<setPercHarmonicFromMIDI>:
  endbr64
  cmp    $0x3f,%sil
  seta   %sil
  movzbl %sil,%esi
  jmp    1050 <setPercussionFirst@plt>
```

assistant: ```c
void setPercHarmonicFromMIDI(void *d, unsigned char u) {
  struct b_tonegen *t = (struct b_tonegen *)d;
  setPercussionFirst(t, u < 64 ? 0 : 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jg     L48
  mov    $0x1,%eax
  jmp    L1
L48:
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L45
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
L45:
  mov    $0x1,%eax
  jmp    L1
L33:
  mov    $0x0,%eax
L1:
  leave
  ret
```

assistant: ```c
int subdir(const char *p, const char *dir) {
  int l;
  l = strlen(dir);
  if (l <= 1)
    return (1);
  if ((strncmp(p, dir, l) == 0) && (p[l] == '/' || p[l] == '\0'))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<subdir>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    $0x1,%eax
  cmp    $0x1,%ebx
  jle    L13
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L13
  movslq %ebx,%rbx
  movzbl (%r12,%rbx,1),%edx
  cmp    $0x2f,%dl
  sete   %al
  test   %dl,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int subdir(const char *p, const char *dir) {
  int l;
  l = strlen(dir);
  if (l <= 1)
    return (1);
  if ((strncmp(p, dir, l) == 0) && (p[l] == '/' || p[l] == '\0'))
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<subdir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rbx
  mov    $0x1,%eax
  cmp    $0x1,%ebx
  jle    L6
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L6
  movzbl (%r12,%rbx,1),%edx
  cmp    $0x2f,%dl
  sete   %al
  test   %dl,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int subdir(const char *p, const char *dir) {
  int l;
  l = strlen(dir);
  if (l <= 1)
    return (1);
  if ((strncmp(p, dir, l) == 0) && (p[l] == '/' || p[l] == '\0'))
    return (1);
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<subdir>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  movslq %eax,%rbx
  mov    $0x1,%eax
  cmp    $0x1,%ebx
  jle    L9
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L9
  movzbl (%r12,%rbx,1),%edx
  cmp    $0x2f,%dl
  sete   %al
  test   %dl,%dl
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L9:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int subdir(const char *p, const char *dir) {
  int l;
  l = strlen(dir);
  if (l <= 1)
    return (1);
  if ((strncmp(p, dir, l) == 0) && (p[l] == '/' || p[l] == '\0'))
    return (1);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<starMemInitFort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <starMemIsInitialised@plt>
  test   %rax,%rax
  jne    L10
  mov    $0x0,%edi
  call   <starMemInitPrivate@plt>
  jmp    L16
L10:
  nop
L16:
  pop    %rbp
  ret
```

assistant: ```c
void starMemInitFort() {
  if (starMemIsInitialised())
    return;
  starMemInitPrivate(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<starMemInitFort>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <starMemIsInitialised@plt>
  test   %rax,%rax
  je     L7
L2:
  add    $0x8,%rsp
  ret
L7:
  mov    $0x0,%edi
  call   <starMemInitPrivate@plt>
  jmp    L2
```

assistant: ```c
void starMemInitFort() {
  if (starMemIsInitialised())
    return;
  starMemInitPrivate(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<starMemInitFort>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <starMemIsInitialised@plt>
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L5:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <starMemInitPrivate@plt>
```

assistant: ```c
void starMemInitFort() {
  if (starMemIsInitialised())
    return;
  starMemInitPrivate(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<starMemInitFort>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <starMemIsInitialised@plt>
  test   %rax,%rax
  je     L7
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L7:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <starMemInitPrivate@plt>
```

assistant: ```c
void starMemInitFort() {
  if (starMemIsInitialised())
    return;
  starMemInitPrivate(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<DDI32BitsSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x80,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void DDI32BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint32_t ui32Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000080;
  (*((volatile unsigned long *)(ui32Base + ui32RegOffset + ui32Reg))) = ui32Val;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<DDI32BitsSet>:
  endbr64
  lea    0x80(%rdi,%rsi,1),%rax
  mov    %rdx,(%rax)
  ret
```

assistant: ```c
void DDI32BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint32_t ui32Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000080;
  (*((volatile unsigned long *)(ui32Base + ui32RegOffset + ui32Reg))) = ui32Val;
}
```
user: What is the c source code of the assembly code below:

```asm
<DDI32BitsSet>:
  endbr64
  lea    0x80(%rdi,%rsi,1),%rax
  mov    %rdx,(%rax)
  ret
```

assistant: ```c
void DDI32BitsSet(uint32_t ui32Base, uint32_t ui32Reg, uint32_t ui32Val) {
  uint32_t ui32RegOffset;
  ;
  ;
  ui32RegOffset = 0x00000080;
  (*((volatile unsigned long *)(ui32Base + ui32RegOffset + ui32Reg))) = ui32Val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<parse_long>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <parse_unit@plt>
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
unsigned long parse_long(const char *arg) {
  unsigned long ret;
  char *end;
  ret = strtoul(arg, &end, 10);
  ret *= parse_unit(end);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<parse_long>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  call   <strtoul@plt>
  mov    %rax,%rbx
  mov    (%rsp),%rdi
  call   <parse_unit@plt>
  imul   %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long parse_long(const char *arg) {
  unsigned long ret;
  char *end;
  ret = strtoul(arg, &end, 10);
  ret *= parse_unit(end);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parse_long>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoul@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rbx
  call   <parse_unit@plt>
  imul   %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long parse_long(const char *arg) {
  unsigned long ret;
  char *end;
  ret = strtoul(arg, &end, 10);
  ret *= parse_unit(end);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<parse_long>:
  endbr64
  push   %rbx
  mov    $0xa,%edx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtoul@plt>
  mov    (%rsp),%rdi
  mov    %rax,%rbx
  call   <parse_unit@plt>
  imul   %rbx,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned long parse_long(const char *arg) {
  unsigned long ret;
  char *end;
  ret = strtoul(arg, &end, 10);
  ret *= parse_unit(end);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<normalizeAngle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x18(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L6
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x18(%rbp),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L23
L6:
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L23
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
L23:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double normalizeAngle(double ang) {
  double result = ang;
  if (ang > 2 * M_PI) {
    ang = (ang - 2 * M_PI);
  } else if (ang < 0.0) {
    ang = (2 * M_PI - ang);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<normalizeAngle>:
  endbr64
  ret
```

assistant: ```c
double normalizeAngle(double ang) {
  double result = ang;
  if (ang > 2 * M_PI) {
    ang = (ang - 2 * M_PI);
  } else if (ang < 0.0) {
    ang = (2 * M_PI - ang);
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<normalizeAngle>:
  endbr64
  ret
```

assistant: ```c
double normalizeAngle(double ang) {
  double result = ang;
  if (ang > 2 * M_PI) {
    ang = (ang - 2 * M_PI);
  } else if (ang < 0.0) {
    ang = (2 * M_PI - ang);
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<normalizeAngle>:
  endbr64
  ret
```

assistant: ```c
double normalizeAngle(double ang) {
  double result = ang;
  if (ang > 2 * M_PI) {
    ang = (ang - 2 * M_PI);
  } else if (ang < 0.0) {
    ang = (2 * M_PI - ang);
  }
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_memalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L37
  mov    $0x0,%eax
  jmp    L1
L37:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L23
  mov    $0x0,%eax
  jmp    L1
L23:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
  mov    -0x8(%rbp),%rax
L1:
  leave
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *mem;
  if (!size)
    return (NULL);
  if (!(mem = malloc(size)))
    return (NULL);
  ft_bzero(mem, size);
  return (mem);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_memalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L10
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L10:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *mem;
  if (!size)
    return (NULL);
  if (!(mem = malloc(size)))
    return (NULL);
  ft_bzero(mem, size);
  return (mem);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_memalloc>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L12
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L12
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ft_bzero@plt>
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *ft_memalloc(size_t size) {
  void *mem;
  if (!size)
    return (NULL);
  if (!(mem = malloc(size)))
    return (NULL);
  ft_bzero(mem, size);
  return (mem);
}
```