ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<irc_allowspeak>:
  endbr64
  test   %cl,%cl
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  je     L8
  lea    D0(%rip),%rsi
  jmp    1050 <do_send@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  lea    D13(%rip),%rsi
  jmp    1050 <do_send@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string

tool: D0: MODE %s +v %s

tool: D13: MODE %s -v %s

assistant: ```c
int irc_allowspeak(int fd, const char *channel, const char *nick, char speak) {
  if (speak)
    return do_send(fd, "MODE %s +v %s", channel, nick);
  else
    return do_send(fd, "MODE %s -v %s", channel, nick);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<irc_allowspeak>:
  endbr64
  test   %cl,%cl
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  je     L9
  lea    D7(%rip),%rsi
  jmp    1050 <do_send@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  lea    D1(%rip),%rsi
  jmp    1050 <do_send@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string
name: disassemble_data
arguments: data_label: D1
data_type: string

tool: D7: MODE %s +v %s

tool: D1: MODE %s -v %s

assistant: ```c
int irc_allowspeak(int fd, const char *channel, const char *nick, char speak) {
  if (speak)
    return do_send(fd, "MODE %s +v %s", channel, nick);
  else
    return do_send(fd, "MODE %s -v %s", channel, nick);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcasestart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L33
L35:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %rax,%rbx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %rax,%rbx
  je     L6
  mov    $0x0,%eax
  jmp    L39
L6:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L35
  mov    -0x38(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L39:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strcasestart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (toupper(*p) != toupper(*q))
      return 0;
    p++;
    q++;
  }
  *ptr = p;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcasestart>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%r13
  cmpb   $0x0,(%rsi)
  je     L9
L0:
  movsbl (%r12),%edi
  call   <toupper@plt>
  mov    %rax,%rbp
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    %rax,%rbp
  jne    L19
  add    $0x1,%r12
  add    $0x1,%rbx
  cmpb   $0x0,(%rbx)
  jne    L0
L9:
  mov    %r12,0x0(%r13)
  mov    $0x1,%eax
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%eax
  jmp    L11
```

assistant: ```c
int strcasestart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (toupper(*p) != toupper(*q))
      return 0;
    p++;
    q++;
  }
  *ptr = p;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strcasestart>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L27
  mov    %rsi,%rbx
  jmp    L31
  xchg   %ax,%ax
L7:
  add    $0x1,%rbx
  add    $0x1,%r12
  cmpb   $0x0,(%rbx)
  je     L27
L31:
  movsbl (%r12),%edi
  call   <toupper@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  je     L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L27:
  mov    %r12,0x0(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strcasestart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (toupper(*p) != toupper(*q))
      return 0;
    p++;
    q++;
  }
  *ptr = p;
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strcasestart>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L21
  mov    %rsi,%rbx
  jmp    L37
  xchg   %ax,%ax
L2:
  add    $0x1,%rbx
  add    $0x1,%r12
  cmpb   $0x0,(%rbx)
  je     L21
L37:
  movsbl (%r12),%edi
  call   <toupper@plt>
  movsbl (%rbx),%edi
  mov    %rax,%rbp
  call   <toupper@plt>
  cmp    %rax,%rbp
  je     L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L21:
  mov    %r12,0x0(%r13)
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int strcasestart(const char *str, const char *val, const char **ptr) {
  const char *p, *q;
  p = str;
  q = val;
  while (*q != '\0') {
    if (toupper(*p) != toupper(*q))
      return 0;
    p++;
    q++;
  }
  *ptr = p;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<jac_chain_nm8_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L2
  mov    -0x8(%rbp),%rax
  movl   $0x2,(%rax)
L2:
  cmpq   $0x0,-0x10(%rbp)
  je     L18
  mov    -0x10(%rbp),%rax
  movl   $0x2,(%rax)
L18:
  cmpq   $0x0,-0x18(%rbp)
  je     L5
  mov    -0x18(%rbp),%rax
  movl   $0x0,(%rax)
L5:
  cmpq   $0x0,-0x20(%rbp)
  je     L14
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
L14:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int jac_chain_nm8_init(int *n_in, int *n_out, int *n_int, int *n_real) {
  if (n_in)
    *n_in = 2;
  if (n_out)
    *n_out = 2;
  if (n_int)
    *n_int = 0;
  if (n_real)
    *n_real = 0;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<jac_chain_nm8_init>:
  endbr64
  test   %rdi,%rdi
  je     L31
  movl   $0x2,(%rdi)
L31:
  test   %rsi,%rsi
  je     L36
  movl   $0x2,(%rsi)
L36:
  test   %rdx,%rdx
  je     L9
  movl   $0x0,(%rdx)
L9:
  test   %rcx,%rcx
  je     L12
  movl   $0x0,(%rcx)
L12:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int jac_chain_nm8_init(int *n_in, int *n_out, int *n_int, int *n_real) {
  if (n_in)
    *n_in = 2;
  if (n_out)
    *n_out = 2;
  if (n_int)
    *n_int = 0;
  if (n_real)
    *n_real = 0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<jac_chain_nm8_init>:
  endbr64
  test   %rdi,%rdi
  je     L39
  movl   $0x2,(%rdi)
L39:
  test   %rsi,%rsi
  je     L23
  movl   $0x2,(%rsi)
L23:
  test   %rdx,%rdx
  je     L19
  movl   $0x0,(%rdx)
L19:
  test   %rcx,%rcx
  je     L12
  movl   $0x0,(%rcx)
L12:
  xor    %eax,%eax
  ret
```

assistant: ```c
int jac_chain_nm8_init(int *n_in, int *n_out, int *n_int, int *n_real) {
  if (n_in)
    *n_in = 2;
  if (n_out)
    *n_out = 2;
  if (n_int)
    *n_int = 0;
  if (n_real)
    *n_real = 0;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<jac_chain_nm8_init>:
  endbr64
  test   %rdi,%rdi
  je     L3
  movl   $0x2,(%rdi)
L3:
  test   %rsi,%rsi
  je     L8
  movl   $0x2,(%rsi)
L8:
  test   %rdx,%rdx
  je     L18
  movl   $0x0,(%rdx)
L18:
  test   %rcx,%rcx
  je     L0
  movl   $0x0,(%rcx)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int jac_chain_nm8_init(int *n_in, int *n_out, int *n_int, int *n_real) {
  if (n_in)
    *n_in = 2;
  if (n_out)
    *n_out = 2;
  if (n_int)
    *n_int = 0;
  if (n_real)
    *n_real = 0;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  add    $0x20,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D31(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D31
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D37
type_infered: string

tool: D10: Enter a temperature in Celsius: 

tool: D5: %d

tool: D31: 1.8

tool: D37: 
Converted Fahrenheit is: %.2f

assistant: ```c
int main(void) {
  int c;
  float f;
  printf("Enter a temperature in Celsius: ");
  scanf("%d", &c);
  f = 1.8 * (c + 32);
  printf("\nConverted Fahrenheit is: %.2f", f);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D26(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  add    $0x20,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  D37(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D26
type: string
name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D37
type: f64
name: parse_data
arguments: tag: D8
type: string

tool: D26: Enter a temperature in Celsius: 

tool: D2: %d

tool: D37: 1.8

tool: D8: 
Converted Fahrenheit is: %.2f

assistant: ```c
int main(void) {
  int c;
  float f;
  printf("Enter a temperature in Celsius: ");
  scanf("%d", &c);
  f = 1.8 * (c + 32);
  printf("\nConverted Fahrenheit is: %.2f", f);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D4(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D21(%rip),%rdi
  add    $0x20,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D17(%rip),%xmm0
  mov    $0x1,%eax
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string
name: parse_data
arguments: tag: D4
data_type: string
name: parse_data
arguments: tag: D21
data_type: string
name: parse_data
arguments: tag: D17
data_type: f64

tool: D0: Enter a temperature in Celsius: 

tool: D4: %d

tool: D21: 
Converted Fahrenheit is: %.2f

tool: D17: 1.8

assistant: ```c
int main(void) {
  int c;
  float f;
  printf("Enter a temperature in Celsius: ");
  scanf("%d", &c);
  f = 1.8 * (c + 32);
  printf("\nConverted Fahrenheit is: %.2f", f);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D21(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D18(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D27(%rip),%rdi
  add    $0x20,%eax
  cvtsi2sd %eax,%xmm0
  mulsd  D8(%rip),%xmm0
  mov    $0x1,%eax
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D21
type_guessed: string
name: disassemble_data
arguments: label: D18
type_guessed: string
name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: f64

tool: D21: Enter a temperature in Celsius: 

tool: D18: %d

tool: D27: 
Converted Fahrenheit is: %.2f

tool: D8: 1.8

assistant: ```c
int main(void) {
  int c;
  float f;
  printf("Enter a temperature in Celsius: ");
  scanf("%d", &c);
  f = 1.8 * (c + 32);
  printf("\nConverted Fahrenheit is: %.2f", f);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uio_mem_alloc_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %ecx,-0x24(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L14
L13:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,(%rax)
  addl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L13
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int uio_mem_alloc_to(pid_t *owners, int offset, int count, pid_t pid) {
  pid_t *p = &owners[offset];
  int i;
  for (i = 0; i < count; i++)
    *p++ = pid;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uio_mem_alloc_to>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  test   %edx,%edx
  jle    L5
  mov    %edx,%edx
  lea    (%rax,%rdx,4),%rdx
L3:
  add    $0x4,%rax
  mov    %ecx,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L3
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int uio_mem_alloc_to(pid_t *owners, int offset, int count, pid_t pid) {
  pid_t *p = &owners[offset];
  int i;
  for (i = 0; i < count; i++)
    *p++ = pid;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uio_mem_alloc_to>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rax
  test   %edx,%edx
  jle    L10
  movslq %edx,%rdx
  lea    (%rax,%rdx,4),%rdx
  cs nopw 0x0(%rax,%rax,1)
L4:
  add    $0x4,%rax
  mov    %ecx,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L4
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int uio_mem_alloc_to(pid_t *owners, int offset, int count, pid_t pid) {
  pid_t *p = &owners[offset];
  int i;
  for (i = 0; i < count; i++)
    *p++ = pid;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uio_mem_alloc_to>:
  endbr64
  mov    %rdi,%r9
  movslq %esi,%rsi
  mov    %ecx,%r8d
  mov    %edx,%edi
  lea    (%r9,%rsi,4),%rcx
  test   %edx,%edx
  jle    L50
  lea    -0x1(%rdx),%eax
  cmp    $0x2,%eax
  jbe    L63
  shr    $0x2,%edx
  movd   %r8d,%xmm1
  mov    %rcx,%rax
  shl    $0x4,%rdx
  pshufd $0x0,%xmm1,%xmm0
  add    %rcx,%rdx
  cs nopw 0x0(%rax,%rax,1)
L27:
  movups %xmm0,(%rax)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L27
  mov    %edi,%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  lea    (%rcx,%rdx,4),%rcx
  cmp    %eax,%edi
  je     L50
L36:
  lea    0x1(%rax),%edx
  mov    %r8d,(%rcx)
  cmp    %edx,%edi
  jle    L50
  add    $0x2,%eax
  mov    %r8d,0x4(%rcx)
  cmp    %eax,%edi
  jle    L50
  mov    %r8d,0x8(%rcx)
L50:
  xor    %eax,%eax
  ret
L63:
  xor    %eax,%eax
  jmp    L36
```

assistant: ```c
int uio_mem_alloc_to(pid_t *owners, int offset, int count, pid_t pid) {
  pid_t *p = &owners[offset];
  int i;
  for (i = 0; i < count; i++)
    *p++ = pid;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<interrupt_acknowledge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1f,-0x4(%rbp)
  jle    L1
  mov    -0x4(%rbp),%eax
  sub    $0x20,%eax
  mov    %eax,%edi
  call   <pic_acknowledge@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void interrupt_acknowledge(int i) {
  if (i < 32) {
  } else {
    pic_acknowledge(i - 32);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<interrupt_acknowledge>:
  endbr64
  cmp    $0x1f,%edi
  jg     L1
  ret
L1:
  sub    $0x8,%rsp
  sub    $0x20,%edi
  call   <pic_acknowledge@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void interrupt_acknowledge(int i) {
  if (i < 32) {
  } else {
    pic_acknowledge(i - 32);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<interrupt_acknowledge>:
  endbr64
  cmp    $0x1f,%edi
  jg     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  sub    $0x20,%edi
  jmp    1050 <pic_acknowledge@plt>
```

assistant: ```c
void interrupt_acknowledge(int i) {
  if (i < 32) {
  } else {
    pic_acknowledge(i - 32);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<interrupt_acknowledge>:
  endbr64
  cmp    $0x1f,%edi
  jg     L6
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x20,%edi
  jmp    1050 <pic_acknowledge@plt>
```

assistant: ```c
void interrupt_acknowledge(int i) {
  if (i < 32) {
  } else {
    pic_acknowledge(i - 32);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L8:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L29
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L38
L29:
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L8
L38:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
data_type: string
name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D47
data_type: string
name: disassemble_data
arguments: data_label: D38
data_type: string
name: disassemble_data
arguments: data_label: D41
data_type: string

tool: D7: -- The GCD Finder --

tool: D3: Enter two positive numbers: 

tool: D47: %d %d

tool: D38: 
Wrong input!

tool: D41: The GCD of given numbers is: %d


assistant: ```c
int main() {
  int a, b;
  printf("-- The GCD Finder --\n");
  while (1) {
    printf("Enter two positive numbers: ");
    scanf("%d %d", &a, &b);
    if (a >= 1 && b >= 1)
      break;
    else
      printf("\nWrong input!\n");
  }
  printf("The GCD of given numbers is: %d\n", gcd(a, b));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    D5(%rip),%r12
  lea    0x4(%rsp),%rbp
  lea    D22(%rip),%rbx
  lea    D9(%rip),%r13
  jmp    L16
L39:
  mov    %r13,%rdi
  call   <puts@plt>
L16:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%rsp),%edi
  test   %edi,%edi
  jle    L39
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L39
  call   <gcd@plt>
  mov    %eax,%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D5
type: string
name: disassemble_data
arguments: data_label: D22
type: string
name: disassemble_data
arguments: data_label: D9
type: string
name: disassemble_data
arguments: data_label: D13
type: string

tool: D8: -- The GCD Finder --

tool: D5: Enter two positive numbers: 

tool: D22: %d %d

tool: D9: 
Wrong input!

tool: D13: The GCD of given numbers is: %d


assistant: ```c
int main() {
  int a, b;
  printf("-- The GCD Finder --\n");
  while (1) {
    printf("Enter two positive numbers: ");
    scanf("%d %d", &a, &b);
    if (a >= 1 && b >= 1)
      break;
    else
      printf("\nWrong input!\n");
  }
  printf("The GCD of given numbers is: %d\n", gcd(a, b));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D44(%rip),%rdi
  lea    D16(%rip),%r14
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D25(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %rsp,%rbp
  call   <puts@plt>
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %r14,%rdi
  call   <puts@plt>
L13:
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%edi
  test   %edi,%edi
  jle    L27
  mov    0x4(%rsp),%esi
  test   %esi,%esi
  jle    L27
  call   <gcd@plt>
  lea    D42(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D44
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D42
type_infered: string

tool: D44: -- The GCD Finder --

tool: D16: 
Wrong input!

tool: D9: Enter two positive numbers: 

tool: D25: %d %d

tool: D42: The GCD of given numbers is: %d


assistant: ```c
int main() {
  int a, b;
  printf("-- The GCD Finder --\n");
  while (1) {
    printf("Enter two positive numbers: ");
    scanf("%d %d", &a, &b);
    if (a >= 1 && b >= 1)
      break;
    else
      printf("\nWrong input!\n");
  }
  printf("The GCD of given numbers is: %d\n", gcd(a, b));
  return 0;
}
```