ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<FF_DestroySemaphore>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <sem_destroy@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void FF_DestroySemaphore(void *pSemaphore) {
  sem_t *pSem = (sem_t *)pSemaphore;
  sem_destroy(pSem);
  free(pSem);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_mm_bswap_epi32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_mm_srli_epi16@plt>
  mov    %eax,%ebx
  mov    -0x24(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <_mm_slli_epi16@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <_mm_or_si128@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <_MM_SHUFFLE@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_shufflelo_epi16@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <_MM_SHUFFLE@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <_mm_shufflehi_epi16@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
__m128i _mm_bswap_epi32(__m128i x) {
  __m128i a = _mm_or_si128(_mm_slli_epi16(x, 8), _mm_srli_epi16(x, 8));
  a = _mm_shufflelo_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  a = _mm_shufflehi_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_mm_bswap_epi32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x8,%esi
  call   <_mm_srli_epi16@plt>
  mov    %eax,%ebp
  mov    $0x8,%esi
  mov    %ebx,%edi
  call   <_mm_slli_epi16@plt>
  mov    %eax,%edi
  mov    %ebp,%esi
  call   <_mm_or_si128@plt>
  mov    %eax,%ebx
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <_MM_SHUFFLE@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <_mm_shufflelo_epi16@plt>
  mov    %eax,%ebx
  mov    $0x1,%ecx
  mov    $0x0,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <_MM_SHUFFLE@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <_mm_shufflehi_epi16@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__m128i _mm_bswap_epi32(__m128i x) {
  __m128i a = _mm_or_si128(_mm_slli_epi16(x, 8), _mm_srli_epi16(x, 8));
  a = _mm_shufflelo_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  a = _mm_shufflehi_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_mm_bswap_epi32>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <_mm_srli_epi16@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  mov    %eax,%r12d
  call   <_mm_slli_epi16@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <_mm_or_si128@plt>
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  mov    %eax,%ebp
  call   <_MM_SHUFFLE@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_mm_shufflelo_epi16@plt>
  mov    $0x3,%esi
  mov    $0x2,%edi
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    %eax,%ebp
  call   <_MM_SHUFFLE@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  mov    %eax,%esi
  pop    %rbp
  pop    %r12
  jmp    10f0 <_mm_shufflehi_epi16@plt>
```

assistant: ```c
__m128i _mm_bswap_epi32(__m128i x) {
  __m128i a = _mm_or_si128(_mm_slli_epi16(x, 8), _mm_srli_epi16(x, 8));
  a = _mm_shufflelo_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  a = _mm_shufflehi_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  return a;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_mm_bswap_epi32>:
  endbr64
  push   %r12
  mov    $0x8,%esi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <_mm_srli_epi16@plt>
  mov    %ebp,%edi
  mov    $0x8,%esi
  mov    %eax,%r12d
  call   <_mm_slli_epi16@plt>
  mov    %r12d,%esi
  mov    %eax,%edi
  call   <_mm_or_si128@plt>
  mov    $0x1,%ecx
  xor    %edx,%edx
  mov    $0x3,%esi
  mov    $0x2,%edi
  mov    %eax,%ebp
  call   <_MM_SHUFFLE@plt>
  mov    %ebp,%edi
  mov    %eax,%esi
  call   <_mm_shufflelo_epi16@plt>
  mov    $0x3,%esi
  mov    $0x2,%edi
  xor    %edx,%edx
  mov    $0x1,%ecx
  mov    %eax,%ebp
  call   <_MM_SHUFFLE@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  mov    %eax,%esi
  pop    %rbp
  pop    %r12
  jmp    10f0 <_mm_shufflehi_epi16@plt>
```

assistant: ```c
__m128i _mm_bswap_epi32(__m128i x) {
  __m128i a = _mm_or_si128(_mm_slli_epi16(x, 8), _mm_srli_epi16(x, 8));
  a = _mm_shufflelo_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  a = _mm_shufflehi_epi16(a, _MM_SHUFFLE(2, 3, 0, 1));
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x830,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x80001000,%eax
  mov    %rax,-0x828(%rbp)
  mov    $0x80001400,%eax
  mov    %rax,-0x820(%rbp)
  mov    $0x80001800,%eax
  mov    %rax,-0x818(%rbp)
  mov    $0x0,%eax
  call   <report_start@plt>
  mov    $0x0,%eax
  call   <base_test@plt>
  mov    $0x0,%eax
  call   <report_end@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
main() {
  int i;
  volatile unsigned long rgmiistatus;
  volatile unsigned long rgmiibuf[256];
  volatile unsigned long *rgmiistatusp = (unsigned long *)0x80001000;
  volatile unsigned long *rgmiiop = (unsigned long *)0x80001400;
  volatile unsigned long *rgmiiip = (unsigned long *)0x80001800;
  report_start();
  base_test();
  report_end();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <report_start@plt>
  mov    $0x0,%eax
  call   <base_test@plt>
  mov    $0x0,%eax
  call   <report_end@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i;
  volatile unsigned long rgmiistatus;
  volatile unsigned long rgmiibuf[256];
  volatile unsigned long *rgmiistatusp = (unsigned long *)0x80001000;
  volatile unsigned long *rgmiiop = (unsigned long *)0x80001400;
  volatile unsigned long *rgmiiip = (unsigned long *)0x80001800;
  report_start();
  base_test();
  report_end();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <report_start@plt>
  xor    %eax,%eax
  call   <base_test@plt>
  xor    %eax,%eax
  call   <report_end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i;
  volatile unsigned long rgmiistatus;
  volatile unsigned long rgmiibuf[256];
  volatile unsigned long *rgmiistatusp = (unsigned long *)0x80001000;
  volatile unsigned long *rgmiiop = (unsigned long *)0x80001400;
  volatile unsigned long *rgmiiip = (unsigned long *)0x80001800;
  report_start();
  base_test();
  report_end();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <report_start@plt>
  xor    %eax,%eax
  call   <base_test@plt>
  xor    %eax,%eax
  call   <report_end@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int i;
  volatile unsigned long rgmiistatus;
  volatile unsigned long rgmiibuf[256];
  volatile unsigned long *rgmiistatusp = (unsigned long *)0x80001000;
  volatile unsigned long *rgmiiop = (unsigned long *)0x80001400;
  volatile unsigned long *rgmiiip = (unsigned long *)0x80001800;
  report_start();
  base_test();
  report_end();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<last3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  lea    -0xb(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L3
L51:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L13
  addl   $0x1,-0x10(%rbp)
  jmp    L19
L13:
  cmpl   $0x3,-0x10(%rbp)
  jne    L19
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0xb(%rbp,%rax,1)
L19:
  addl   $0x1,-0x18(%rbp)
L3:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jl     L51
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

assistant: ```c
int last3(char *ip) {
  int i, j = 0, ct = 0;
  char num[3];
  bzero(num, 3);
  for (i = 0; i < strlen(ip); i++) {
    if (ip[i] == '.') {
      ct++;
      continue;
    }
    if (ct == 3) {
      num[j++] = ip[i];
    }
  }
  return atoi(num);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<last3>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rdi
  mov    $0x3,%esi
  call   <bzero@plt>
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  mov    $0x0,%r13d
  jmp    L52
L43:
  add    $0x1,%r12d
L54:
  add    $0x1,%rbx
L52:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L16
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  je     L43
  cmp    $0x3,%r12d
  jne    L54
  movslq %r13d,%rdx
  mov    %al,0x5(%rsp,%rdx,1)
  lea    0x1(%r13),%r13d
  jmp    L54
L16:
  lea    0x5(%rsp),%rdi
  call   <atoi@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int last3(char *ip) {
  int i, j = 0, ct = 0;
  char num[3];
  bzero(num, 3);
  for (i = 0; i < strlen(ip); i++) {
    if (ip[i] == '.') {
      ct++;
      continue;
    }
    if (ct == 3) {
      num[j++] = ip[i];
    }
  }
  return atoi(num);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<last3>:
  endbr64
  push   %r14
  mov    $0x3,%esi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%r14
  mov    %r14,%rdi
  call   <bzero@plt>
  jmp    L40
  nop
L34:
  cmp    $0x3,%r12d
  jne    L46
  movslq %r13d,%rdx
  add    $0x1,%r13d
  mov    %al,0x5(%rsp,%rdx,1)
L46:
  add    $0x1,%rbx
L40:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L58
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  jne    L34
  add    $0x1,%r12d
  jmp    L46
L58:
  mov    %r14,%rdi
  call   <atoi@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int last3(char *ip) {
  int i, j = 0, ct = 0;
  char num[3];
  bzero(num, 3);
  for (i = 0; i < strlen(ip); i++) {
    if (ip[i] == '.') {
      ct++;
      continue;
    }
    if (ct == 3) {
      num[j++] = ip[i];
    }
  }
  return atoi(num);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<last3>:
  endbr64
  push   %r14
  mov    $0x3,%esi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%r14
  mov    %r14,%rdi
  call   <bzero@plt>
  jmp    L44
  nop
L28:
  cmp    $0x3,%r12d
  jne    L38
  movslq %r13d,%rdx
  add    $0x1,%r13d
  mov    %al,0x5(%rsp,%rdx,1)
L38:
  add    $0x1,%rbx
L44:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L45
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x2e,%al
  jne    L28
  add    $0x1,%r12d
  jmp    L38
L45:
  mov    %r14,%rdi
  call   <atoi@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int last3(char *ip) {
  int i, j = 0, ct = 0;
  char num[3];
  bzero(num, 3);
  for (i = 0; i < strlen(ip); i++) {
    if (ip[i] == '.') {
      ct++;
      continue;
    }
    if (ct == 3) {
      num[j++] = ip[i];
    }
  }
  return atoi(num);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  addq   $0x8,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1ff,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  jns    L5
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printError@plt>
L5:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char *fname = *++argv;
  if (mkdir(fname, 0777) < 0) {
    printError(fname);
  }
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rbx
  mov    $0x1ff,%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  js     L13
L19:
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  pop    %rbx
  ret
L13:
  mov    %rbx,%rdi
  call   <printError@plt>
  jmp    L19
```

assistant: ```c
int main(int argc, char **argv) {
  char *fname = *++argv;
  if (mkdir(fname, 0777) < 0) {
    printError(fname);
  }
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rbp
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  js     L5
L4:
  mov    D0(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
L5:
  mov    %rbp,%rdi
  call   <printError@plt>
  jmp    L4
```

assistant: ```c
int main(int argc, char **argv) {
  char *fname = *++argv;
  if (mkdir(fname, 0777) < 0) {
    printError(fname);
  }
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    0x8(%rsi),%rbp
  mov    $0x1ff,%esi
  mov    %rbp,%rdi
  call   <mkdir@plt>
  test   %rax,%rax
  js     L12
L8:
  mov    D7(%rip),%rax
  pop    %rbp
  mov    (%rax),%eax
  ret
L12:
  mov    %rbp,%rdi
  call   <printError@plt>
  jmp    L8
```

assistant: ```c
int main(int argc, char **argv) {
  char *fname = *++argv;
  if (mkdir(fname, 0777) < 0) {
    printError(fname);
  }
  return EXIT_SUCCESS;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo_s64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  neg    %rax
  cmp    %rax,-0x8(%rbp)
  jge    L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  nop
  leave
  ret
```

assistant: ```c
void __attribute__((no)) foo_s64(long long a, long long b) {
  if (a < -b)
    abort();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo_s64>:
  endbr64
  neg    %rsi
  cmp    %rdi,%rsi
  jg     L3
  ret
L3:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void __attribute__((no)) foo_s64(long long a, long long b) {
  if (a < -b)
    abort();
}
```
user: What is the c source code of the assembly code below?

```asm
<foo_s64>:
  endbr64
  neg    %rsi
  cmp    %rdi,%rsi
  jg     L3
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) foo_s64(long long a, long long b) {
  if (a < -b)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<foo_s64>:
  endbr64
  neg    %rsi
  cmp    %rdi,%rsi
  jg     L8
  ret
  nopl   (%rax)
L8:
  xor    %eax,%eax
  jmp    1050 <abort@plt>
```

assistant: ```c
void __attribute__((no)) foo_s64(long long a, long long b) {
  if (a < -b)
    abort();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<FlashSectorSizeGet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x40032430,%eax
  mov    (%rax),%rax
  and    $0xf,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xa,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t FlashSectorSizeGet(void) {
  uint32_t ui32SectorSizeInKbyte;
  ui32SectorSizeInKbyte = ((*((volatile unsigned long *)(0x40030000 + 0x00002430))) & 0x0000000F) >> 0;
  return (ui32SectorSizeInKbyte * 1024);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<FlashSectorSizeGet>:
  endbr64
  mov    0x40032430,%rax
  and    $0xf,%eax
  shl    $0xa,%eax
  ret
```

assistant: ```c
uint32_t FlashSectorSizeGet(void) {
  uint32_t ui32SectorSizeInKbyte;
  ui32SectorSizeInKbyte = ((*((volatile unsigned long *)(0x40030000 + 0x00002430))) & 0x0000000F) >> 0;
  return (ui32SectorSizeInKbyte * 1024);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FlashSectorSizeGet>:
  endbr64
  mov    0x40032430,%rax
  and    $0xf,%eax
  shl    $0xa,%eax
  ret
```

assistant: ```c
uint32_t FlashSectorSizeGet(void) {
  uint32_t ui32SectorSizeInKbyte;
  ui32SectorSizeInKbyte = ((*((volatile unsigned long *)(0x40030000 + 0x00002430))) & 0x0000000F) >> 0;
  return (ui32SectorSizeInKbyte * 1024);
}
```
user: What is the c source code of the assembly code below?

```asm
<FlashSectorSizeGet>:
  endbr64
  mov    0x40032430,%rax
  and    $0xf,%eax
  shl    $0xa,%eax
  ret
```

assistant: ```c
uint32_t FlashSectorSizeGet(void) {
  uint32_t ui32SectorSizeInKbyte;
  ui32SectorSizeInKbyte = ((*((volatile unsigned long *)(0x40030000 + 0x00002430))) & 0x0000000F) >> 0;
  return (ui32SectorSizeInKbyte * 1024);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getLocaleInfo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void getLocaleInfo(char **locale, char **encoding) {
  *locale = NULL;
  *encoding = NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getLocaleInfo>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
void getLocaleInfo(char **locale, char **encoding) {
  *locale = NULL;
  *encoding = NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getLocaleInfo>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
void getLocaleInfo(char **locale, char **encoding) {
  *locale = NULL;
  *encoding = NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getLocaleInfo>:
  endbr64
  movq   $0x0,(%rdi)
  movq   $0x0,(%rsi)
  ret
```

assistant: ```c
void getLocaleInfo(char **locale, char **encoding) {
  *locale = NULL;
  *encoding = NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<uninitvar_strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_strstr(void) {
  char *cs;
  char *ct;
  (void)strstr(cs, ct);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uninitvar_strstr>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <strstr@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_strstr(void) {
  char *cs;
  char *ct;
  (void)strstr(cs, ct);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<uninitvar_strstr>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <strstr@plt>
```

assistant: ```c
void uninitvar_strstr(void) {
  char *cs;
  char *ct;
  (void)strstr(cs, ct);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uninitvar_strstr>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <strstr@plt>
```

assistant: ```c
void uninitvar_strstr(void) {
  char *cs;
  char *ct;
  (void)strstr(cs, ct);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hdSurEncPhase2_D2_0F_11_sub>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,%eax
  mov    %al,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x22(%rbp)
  jmp    L18
L3:
  movzbl -0x44(%rbp),%edx
  movzbl -0x22(%rbp),%ecx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  movzbl -0x22(%rbp),%ebx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hdSurEncCryptLookup_D2_0F_11@plt>
  movslq %ebx,%rdx
  mov    %al,-0x20(%rbp,%rdx,1)
  addb   $0x1,-0x22(%rbp)
L18:
  cmpb   $0x7,-0x22(%rbp)
  jbe    L3
  movzbl -0x19(%rbp),%eax
  mov    %al,-0x21(%rbp)
  movb   $0x7,-0x22(%rbp)
  jmp    L35
L46:
  movzbl -0x1f(%rbp),%eax
  shr    $0x4,%al
  mov    %eax,%edx
  movzbl -0x22(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%eax
  movzbl %al,%eax
  shl    $0x4,%eax
  or     %eax,%edx
  movzbl -0x22(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  subb   $0x1,-0x22(%rbp)
L35:
  cmpb   $0x0,-0x22(%rbp)
  jne    L46
  movzbl -0x20(%rbp),%eax
  shr    $0x4,%al
  mov    %eax,%edx
  movzbl -0x21(%rbp),%eax
  shl    $0x4,%eax
  or     %edx,%eax
  mov    %al,-0x20(%rbp)
  movb   $0x0,-0x22(%rbp)
  jmp    L60
L59:
  movzbl -0x22(%rbp),%edx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  movzbl -0x22(%rbp),%eax
  cltq
  movzbl -0x20(%rbp,%rax,1),%edx
  movzbl -0x22(%rbp),%esi
  mov    -0x38(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %dl,(%rax)
  addb   $0x1,-0x22(%rbp)
L60:
  cmpb   $0x7,-0x22(%rbp)
  jbe    L59
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L42
  call   <__stack_chk_fail@plt>
L42:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void hdSurEncPhase2_D2_0F_11_sub(unsigned char *CWa, unsigned char *CWb, unsigned char AddrInd) {
  unsigned char Buffer[8];
  unsigned char tmp, i;
  for (i = 0; i <= 7; ++i) {
    Buffer[i] = hdSurEncCryptLookup_D2_0F_11(CWb[i], AddrInd);
  }
  tmp = Buffer[7];
  for (i = 7; i >= 1; --i) {
    Buffer[i] = ((Buffer[1] >> 4) & 0xFF) | ((Buffer[i - 1] << 4) & 0xFF);
  }
  Buffer[0] = ((Buffer[0] >> 4) & 0xFF) | ((tmp << 4) & 0xFF);
  for (i = 0; i <= 7; ++i) {
    CWa[i] = CWa[i] ^ Buffer[i];
  }
}
```