user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L122
L46:
  nop
L116:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L116
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L122:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  jne    L46
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L46
  movss  -0x10(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  comisd D15(%rip),%xmm0
  jbe    L66
  movss  -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D8(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L66
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L113
  lea    D79(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L45
L113:
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L45
L66:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L4
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <my_power@plt>
  mov    %eax,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L45
L4:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jne    L19
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L45
L19:
  mov    -0xc(%rbp),%eax
  neg    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <my_power@plt>
  mov    %eax,%ecx
  mov    $0x1,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D78(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L45:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L78
  call   <__stack_chk_fail@plt>
L78:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D75
type_infered: string
name: retrieve_data
arguments: data_tag: D41
type_infered: string
name: retrieve_data
arguments: data_tag: D89
type_infered: string
name: retrieve_data
arguments: data_tag: D15
type_infered: byte[16]
name: retrieve_data
arguments: data_tag: D8
type_infered: byte[8]
name: retrieve_data
arguments: data_tag: D79
type_infered: string
name: retrieve_data
arguments: data_tag: D63
type_infered: string
name: retrieve_data
arguments: data_tag: D78
type_infered: string
name: retrieve_data
arguments: data_tag: D46
type_infered: string

tool: D75: Pls input the base and power number(e.g. 3.14, 2):

tool: D41: input invalid!

tool: D89: %f,%d

tool: {"D15": [0xe4,0x78,0xaa,0x9d,0xfb,0x38,0x0b,0xb8,0xe4,0x78,0xaa,0x9d,0xfb,0x38,0x0b,0x38]}

tool: {"D8": [0xe4,0x78,0xaa,0x9d,0xfb,0x38,0x0b,0x38]}

tool: D79: forbiden!

tool: D63: answer: 0

tool: D78: answer: %.6f


tool: D46: answer: 1

assistant: ```c
int main(void) {
  float num;
  int pow;
  printf("Pls input the base and power number(e.g. 3.14, 2):");
  while (scanf("%f,%d", &num, &pow) != 2 || getchar() != '\n') {
    while (getchar() != '\n')
      ;
    printf("input invalid!\n");
    printf("Pls input the base and power number(e.g. 3.14, 2):");
  }
  if (num > -1e-38 && num < 1e-38) {
    if (pow == 0)
      printf("forbiden!\n");
    else
      printf("answer: 0\n");
  } else {
    if (pow > 0)
      printf("answer: %.6f\n", my_power(num, pow));
    else if (pow == 0)
      printf("answer: 1\n");
    else {
      pow *= -1;
      printf("answer: %.6f\n", 1 / my_power(num, pow));
    }
  }
  return 0;
}
```