user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r15d
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq %esi,%rbx
  lea    (%rdi,%rbx,4),%r9
  mov    (%r9),%edi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  shl    $0x2,%rax
  lea    0xf(%rax),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L182:
  cmp    %rcx,%rsp
  je     L139
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L182
L139:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L149
  orq    $0x0,-0x8(%rsp,%rdx,1)
L149:
  mov    %rsp,%r8
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L115:
  cmp    %rdx,%rsp
  je     L84
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L115
L84:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L161
  orq    $0x0,-0x8(%rsp,%rax,1)
L161:
  mov    %rsp,%rsi
  lea    0x1(%r15),%eax
  cmp    %eax,%r12d
  jl     L62
  cltq
  mov    $0x0,%r14d
  mov    $0x0,%ecx
  jmp    L104
L45:
  jge    L184
  movslq %r14d,%r10
  mov    %edx,(%r8,%r10,4)
  lea    0x1(%r14),%r14d
L184:
  add    $0x1,%rax
  cmp    %eax,%r12d
  jl     L95
L104:
  mov    0x0(%r13,%rax,4),%edx
  cmp    %edi,%edx
  jle    L45
  movslq %ecx,%r10
  mov    %edx,(%rsi,%r10,4)
  lea    0x1(%rcx),%ecx
  jmp    L184
L95:
  test   %r14d,%r14d
  jle    L86
  mov    %r14d,%r10d
  mov    $0x0,%eax
L154:
  mov    (%r8,%rax,4),%edx
  mov    %edx,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L154
L86:
  add    %r15d,%r14d
  movslq %r14d,%rax
  lea    0x0(%r13,%rax,4),%r8
  mov    %edi,(%r8)
  test   %ecx,%ecx
  jle    L159
  mov    %ecx,%ecx
  mov    $0x0,%eax
L157:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,0x4(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L157
L159:
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    %r12d,%r15d
  jg     L137
  lea    D5(%rip),%r15
L46:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jge    L46
L137:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L119
  mov    %r14d,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L62:
  movslq %r15d,%rax
  mov    %edi,0x0(%r13,%rax,4)
  mov    %r15d,%r14d
  jmp    L159
L119:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %d 

assistant: ```c
int Partition(int a[], int start, int end) {
  int pos = 0, val = a[start];
  int b[end - start], c[end - start], k = 0, l = 0, i = 0, m = 0;
  for (i = start + 1; i <= end; i++) {
    if (a[i] > val)
      c[k++] = a[i];
    else if (a[i] < val)
      b[l++] = a[i];
  }
  for (i = 0, m = start; i < l; i++, m++)
    a[m] = b[i];
  pos = start + l;
  a[pos] = val;
  for (i = 0, m = pos + 1; i < k; i++, m++)
    a[m] = c[i];
  printf("\n");
  for (i = start; i <= end; i++)
    printf("%d ", a[i]);
  return pos;
}
```