ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_key>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x40(%rdi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L57:
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strtol@plt>
  mov    %eax,(%r14)
  test   %eax,%eax
  jne    L7
  cmpb   $0x30,0x5(%rsp)
  jne    L59
  cmpb   $0x30,0x6(%rsp)
  jne    L59
L7:
  add    $0x2,%rbx
  add    $0x4,%r14
  cmp    %r12,%rbx
  jne    L57
  movzbl 0x40(%r13),%eax
  neg    %al
  sbb    %eax,%eax
  jmp    L51
  nopl   0x0(%rax)
L59:
  mov    $0xffffffff,%eax
L51:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_key(const char *ascii, uint8_t key[0x20]) {
  int i;
  for (i = 0; i < 0x20; i++) {
    char byte[3];
    memcpy(byte, &ascii[2 * i], 2);
    byte[2] = '\0';
    key[i] = strtol(byte, NULL, 16);
    if (key[i] == 0 && !(byte[0] == '0' && byte[1] == '0')) {
      return -1;
    }
  }
  if (ascii[2 * i] != '\0') {
    return -1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<parse_key>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    0x40(%rdi),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L55:
  mov    $0x2,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  movb   $0x0,0x7(%rsp)
  call   <strtol@plt>
  mov    %eax,(%r14)
  test   %eax,%eax
  jne    L10
  cmpb   $0x30,0x5(%rsp)
  jne    L17
  cmpb   $0x30,0x6(%rsp)
  jne    L17
L10:
  add    $0x2,%rbx
  add    $0x4,%r14
  cmp    %r12,%rbx
  jne    L55
  movzbl 0x40(%r13),%eax
  neg    %al
  sbb    %eax,%eax
  jmp    L52
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%eax
L52:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_key(const char *ascii, uint8_t key[0x20]) {
  int i;
  for (i = 0; i < 0x20; i++) {
    char byte[3];
    memcpy(byte, &ascii[2 * i], 2);
    byte[2] = '\0';
    key[i] = strtol(byte, NULL, 16);
    if (key[i] == 0 && !(byte[0] == '0' && byte[1] == '0')) {
      return -1;
    }
  }
  if (ascii[2 * i] != '\0') {
    return -1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<err_sys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void err_sys(const char *info) {
  perror(info);
  exit(1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<err_sys>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void err_sys(const char *info) {
  perror(info);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<err_sys>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_sys(const char *info) {
  perror(info);
  exit(1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<err_sys>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
void err_sys(const char *info) {
  perror(info);
  exit(1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<binary_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
L60:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L17
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L60
  jmp    L17
L29:
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <compare@plt>
  cmp    $0x1,%eax
  jne    L19
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L51
L19:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L51:
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  nop
L63:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L17
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L63
L17:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jae    L72
  mov    -0x20(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  ja     L29
L72:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *binary_search(char *front, char *back) {
  char *p;
  p = front + (back - front) / 2;
  while (p < back && *p++ != '\n')
    ;
  ;
  while (p < back && back > front) {
    if (compare(p, back) == 1)
      front = p;
    else
      back = p;
    p = front + (back - front) / 2;
    while (p < back && *p++ != '\n')
      ;
    ;
  }
  return (front);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<binary_search>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rsi,%rax
  sub    %rdi,%rax
  mov    %rax,%rbx
  shr    $0x3f,%rbx
  add    %rax,%rbx
  sar    %rbx
  add    %rdi,%rbx
L4:
  cmp    %rbp,%rbx
  jae    L38
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  jne    L4
L38:
  cmp    %rbx,%rbp
  jbe    L35
  cmp    %r12,%rbp
  ja     L72
L35:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L48:
  cmp    %rbp,%rbx
  jae    L35
  cmp    %rbp,%r12
  jae    L35
L72:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <compare@plt>
  cmp    $0x1,%eax
  cmovne %rbx,%rbp
  cmove  %rbx,%r12
  mov    %rbp,%rax
  sub    %r12,%rax
  mov    %rax,%rbx
  shr    $0x3f,%rbx
  add    %rax,%rbx
  sar    %rbx
  add    %r12,%rbx
L21:
  cmp    %rbx,%rbp
  jbe    L48
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  jne    L21
  jmp    L48
```

assistant: ```c
char *binary_search(char *front, char *back) {
  char *p;
  p = front + (back - front) / 2;
  while (p < back && *p++ != '\n')
    ;
  ;
  while (p < back && back > front) {
    if (compare(p, back) == 1)
      front = p;
    else
      back = p;
    p = front + (back - front) / 2;
    while (p < back && *p++ != '\n')
      ;
    ;
  }
  return (front);
}
```
user: Translate the below assembly code into C programming language:

```asm
<binary_search>:
  endbr64
  mov    %rsi,%rax
  push   %r12
  mov    %rdi,%r12
  sub    %rdi,%rax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rax,%rbx
  shr    $0x3f,%rbx
  add    %rax,%rbx
  sar    %rbx
  add    %rdi,%rbx
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L83:
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  je     L23
L5:
  cmp    %rbp,%rbx
  jb     L83
L23:
  cmp    %r12,%rbp
  jbe    L76
  cmp    %rbx,%rbp
  jbe    L76
  nopl   0x0(%rax)
L93:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <compare@plt>
  cmp    $0x1,%eax
  cmovne %rbx,%rbp
  cmove  %rbx,%r12
  mov    %rbp,%rax
  sub    %r12,%rax
  mov    %rax,%rbx
  shr    $0x3f,%rbx
  add    %rax,%rbx
  sar    %rbx
  add    %r12,%rbx
  jmp    L52
  xchg   %ax,%ax
L51:
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  je     L53
L52:
  cmp    %rbx,%rbp
  ja     L51
L53:
  cmp    %rbp,%rbx
  jae    L76
  cmp    %rbp,%r12
  jb     L93
L76:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *binary_search(char *front, char *back) {
  char *p;
  p = front + (back - front) / 2;
  while (p < back && *p++ != '\n')
    ;
  ;
  while (p < back && back > front) {
    if (compare(p, back) == 1)
      front = p;
    else
      back = p;
    p = front + (back - front) / 2;
    while (p < back && *p++ != '\n')
      ;
    ;
  }
  return (front);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<binary_search>:
  endbr64
  mov    %rsi,%rax
  push   %r12
  mov    %rdi,%r12
  sub    %rdi,%rax
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rax,%rbx
  shr    $0x3f,%rbx
  add    %rax,%rbx
  sar    %rbx
  add    %rdi,%rbx
  jmp    L91
  cs nopw 0x0(%rax,%rax,1)
L88:
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  je     L42
L91:
  cmp    %rbp,%rbx
  jb     L88
L42:
  cmp    %r12,%rbp
  jbe    L68
  cmp    %rbx,%rbp
  jbe    L68
  nopl   0x0(%rax)
L12:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <compare@plt>
  cmp    $0x1,%eax
  cmovne %rbx,%rbp
  cmove  %rbx,%r12
  mov    %rbp,%rax
  sub    %r12,%rax
  mov    %rax,%rbx
  shr    $0x3f,%rbx
  add    %rax,%rbx
  sar    %rbx
  add    %r12,%rbx
  jmp    L33
  xchg   %ax,%ax
L81:
  add    $0x1,%rbx
  cmpb   $0xa,-0x1(%rbx)
  je     L5
L33:
  cmp    %rbx,%rbp
  ja     L81
L5:
  cmp    %rbp,%rbx
  jae    L68
  cmp    %rbp,%r12
  jb     L12
L68:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *binary_search(char *front, char *back) {
  char *p;
  p = front + (back - front) / 2;
  while (p < back && *p++ != '\n')
    ;
  ;
  while (p < back && back > front) {
    if (compare(p, back) == 1)
      front = p;
    else
      back = p;
    p = front + (back - front) / 2;
    while (p < back && *p++ != '\n')
      ;
    ;
  }
  return (front);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xrop3_190_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  xor    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x10(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_190_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_190_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  not    %eax
  or     %edi,%eax
  mov    %edi,%edx
  xor    %esi,%edx
  or     $0xff,%dl
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_190_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xrop3_190_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  xor    %esi,%edx
  not    %eax
  or     $0xff,%dl
  or     %edi,%eax
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_190_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_190_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  mov    %edi,%edx
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  xor    %esi,%edx
  not    %eax
  or     $0xff,%dl
  or     %edi,%eax
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_190_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = T ^ S;
  stk1 = D | stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<integer_log10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L1:
  addl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L7:
  cmpq   $0x9,-0x18(%rbp)
  jg     L1
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int integer_log10(long n) {
  int log_val = 0;
  while (n >= 10) {
    log_val++;
    n /= 10;
  }
  return log_val;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<integer_log10>:
  endbr64
  cmp    $0x9,%rdi
  jle    L3
  mov    $0x0,%ecx
  movabs $0x6666666666666667,%r8
L9:
  add    $0x1,%ecx
  mov    %rdi,%rsi
  mov    %rdi,%rax
  imul   %r8
  sar    $0x2,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rdi
  cmp    $0x63,%rsi
  jg     L9
L20:
  mov    %ecx,%eax
  ret
L3:
  mov    $0x0,%ecx
  jmp    L20
```

assistant: ```c
int integer_log10(long n) {
  int log_val = 0;
  while (n >= 10) {
    log_val++;
    n /= 10;
  }
  return log_val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<integer_log10>:
  endbr64
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  cmp    $0x9,%rdi
  jle    L5
  movabs $0xcccccccccccccccd,%rsi
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L4
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int integer_log10(long n) {
  int log_val = 0;
  while (n >= 10) {
    log_val++;
    n /= 10;
  }
  return log_val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<integer_log10>:
  endbr64
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  cmp    $0x9,%rdi
  jle    L19
  movabs $0xcccccccccccccccd,%rsi
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L8
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int integer_log10(long n) {
  int log_val = 0;
  while (n >= 10) {
    log_val++;
    n /= 10;
  }
  return log_val;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fcitx_utf8_get_nth_char>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  jmp    L12
L34:
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L34
L28:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utf8_get_nth_char(char *s, unsigned int n) {
  unsigned int l = 0;
  while (*s && l < n) {
    int chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fcitx_utf8_get_nth_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L18
  mov    %esi,%ebp
  test   %esi,%esi
  je     L18
  mov    $0x0,%ebx
  lea    0x4(%rsp),%r12
L23:
  mov    %r12,%rsi
  call   <fcitx_utf8_get_char@plt>
  mov    %rax,%rdi
  add    $0x1,%ebx
  cmpb   $0x0,(%rax)
  je     L18
  cmp    %ebx,%ebp
  ja     L23
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    %rdi,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utf8_get_nth_char(char *s, unsigned int n) {
  unsigned int l = 0;
  while (*s && l < n) {
    int chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fcitx_utf8_get_nth_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L55
  mov    %esi,%ebp
  test   %esi,%esi
  je     L55
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  jmp    L59
L21:
  cmp    %ebx,%ebp
  jbe    L55
L59:
  mov    %r12,%rsi
  add    $0x1,%ebx
  call   <fcitx_utf8_get_char@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L21
L55:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utf8_get_nth_char(char *s, unsigned int n) {
  unsigned int l = 0;
  while (*s && l < n) {
    int chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fcitx_utf8_get_nth_char>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L35
  mov    %esi,%ebp
  test   %esi,%esi
  je     L35
  xor    %ebx,%ebx
  lea    0x4(%rsp),%r12
  jmp    L29
L27:
  cmp    %ebx,%ebp
  jbe    L35
L29:
  mov    %r12,%rsi
  add    $0x1,%ebx
  call   <fcitx_utf8_get_char@plt>
  cmpb   $0x0,(%rax)
  mov    %rax,%rdi
  jne    L27
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  mov    %rdi,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((visibility("default"))) char *fcitx_utf8_get_nth_char(char *s, unsigned int n) {
  unsigned int l = 0;
  while (*s && l < n) {
    int chr;
    s = fcitx_utf8_get_char(s, &chr);
    l++;
  }
  return s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<conv_int_to_flt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L9
L16:
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    (%rax),%rcx
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %rcx,%xmm0
  movss  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L16
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int32_t conv_int_to_flt(float *dst, const int32_t *src, int32_t num) {
  int32_t i;
  for (i = 0; i < num; i++) {
    *dst++ = (float)*src++;
  }
  return num;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<conv_int_to_flt>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  jle    L0
  mov    $0x0,%ecx
L2:
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsi,%rcx,8),%xmm0
  movss  %xmm0,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L2
L0:
  ret
```

assistant: ```c
int32_t conv_int_to_flt(float *dst, const int32_t *src, int32_t num) {
  int32_t i;
  for (i = 0; i < num; i++) {
    *dst++ = (float)*src++;
  }
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<conv_int_to_flt>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  jle    L12
  xor    %ecx,%ecx
  xchg   %ax,%ax
L5:
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsi,%rcx,8),%xmm0
  movss  %xmm0,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L5
L12:
  ret
```

assistant: ```c
int32_t conv_int_to_flt(float *dst, const int32_t *src, int32_t num) {
  int32_t i;
  for (i = 0; i < num; i++) {
    *dst++ = (float)*src++;
  }
  return num;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<conv_int_to_flt>:
  endbr64
  mov    %rdx,%rax
  test   %rdx,%rdx
  jle    L16
  xor    %ecx,%ecx
  xchg   %ax,%ax
L7:
  pxor   %xmm0,%xmm0
  cvtsi2ssq (%rsi,%rcx,8),%xmm0
  movss  %xmm0,(%rdi,%rcx,4)
  add    $0x1,%rcx
  cmp    %rcx,%rax
  jne    L7
L16:
  ret
```

assistant: ```c
int32_t conv_int_to_flt(float *dst, const int32_t *src, int32_t num) {
  int32_t i;
  for (i = 0; i < num; i++) {
    *dst++ = (float)*src++;
  }
  return num;
}
```
user: What is the c source code of the assembly code below:

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L42
L25:
  mov    $0x0,%eax
  call   <rand_double@plt>
  movsd  D19(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <binet@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L2
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L4
L2:
  addl   $0x1,-0x24(%rbp)
L42:
  cmpl   $0xf423f,-0x24(%rbp)
  jle    L25
L4:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  jbe    L8
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D19
type_guessed: f64
name: parse_data
arguments: tag: D24
type_guessed: string

tool: D19: 79

tool: D24: should return a nonnegative number


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  double x;
  double y;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = floor(79.0 * rand_double());
    y = binet(x);
    if (y < 0) {
      printf("should return a nonnegative number\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (y < 0) {
    printf("should return a nonnegative number\n");
  }
  return elapsed;
}
```