ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<strupr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L3
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L3:
  addl   $0x1,-0x4(%rbp)
L27:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void strupr(char *s) {
  int i = 0;
  while (s[i]) {
    if (islower(s[i]))
      s[i] -= 32;
    i++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L22
L6:
  pop    %rbx
  ret
L38:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L6
L22:
  movsbl %dil,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L38
  subb   $0x20,(%rbx)
  jmp    L38
```

assistant: ```c
void strupr(char *s) {
  int i = 0;
  while (s[i]) {
    if (islower(s[i]))
      s[i] -= 32;
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
L10:
  call   <islower@plt>
  test   %rax,%rax
  je     L24
  subb   $0x20,(%rbx)
L24:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L10
L16:
  pop    %rbx
  ret
```

assistant: ```c
void strupr(char *s) {
  int i = 0;
  while (s[i]) {
    if (islower(s[i]))
      s[i] -= 32;
    i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L20
L36:
  call   <islower@plt>
  test   %rax,%rax
  je     L34
  subb   $0x20,(%rbx)
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L36
L20:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L34:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L36
  pop    %rbx
  ret
```

assistant: ```c
void strupr(char *s) {
  int i = 0;
  while (s[i]) {
    if (islower(s[i]))
      s[i] -= 32;
    i++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<versioncmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <out1fmt@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D19
type: string
name: parse_data
arguments: label: D2
type: string

tool: D19: 13.0.16a

tool: D2: %s


assistant: ```c
int versioncmd(int argc, char **argv) {
  out1fmt("%s\n", "13.0.16a");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<versioncmd>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <out1fmt@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string

tool: D4: 13.0.16a

tool: D13: %s


assistant: ```c
int versioncmd(int argc, char **argv) {
  out1fmt("%s\n", "13.0.16a");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<versioncmd>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <out1fmt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D10
type: string

tool: D4: 13.0.16a

tool: D10: %s


assistant: ```c
int versioncmd(int argc, char **argv) {
  out1fmt("%s\n", "13.0.16a");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<versioncmd>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <out1fmt@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D15
datatype: string
name: retrieve_data
arguments: data_label: D0
datatype: string

tool: D15: 13.0.16a

tool: D0: %s


assistant: ```c
int versioncmd(int argc, char **argv) {
  out1fmt("%s\n", "13.0.16a");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func_b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  addl   $0x2,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int func_b(int b) {
  b = b + 2;
  return b;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func_b>:
  endbr64
  lea    0x2(%rdi),%eax
  ret
```

assistant: ```c
int func_b(int b) {
  b = b + 2;
  return b;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<func_b>:
  endbr64
  lea    0x2(%rdi),%eax
  ret
```

assistant: ```c
int func_b(int b) {
  b = b + 2;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GENERAL_NAME_set0_othername>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <OTHERNAME_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    $0x0,%eax
  jmp    L4
L0:
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <GENERAL_NAME_set0_value@plt>
  mov    $0x1,%eax
L4:
  leave
  ret
```

assistant: ```c
int GENERAL_NAME_set0_othername(GENERAL_NAME *gen, ASN1_OBJECT *oid, ASN1_TYPE *value) {
  OTHERNAME *oth;
  oth = OTHERNAME_new();
  if (!oth)
    return 0;
  oth->type_id = oid;
  oth->value = value;
  GENERAL_NAME_set0_value(gen, GEN_OTHERNAME, oth);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<GENERAL_NAME_set0_othername>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%eax
  call   <OTHERNAME_new@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L8
  mov    %r12,0x8(%rdx)
  mov    %rbp,(%rdx)
  mov    D5(%rip),%rax
  mov    (%rax),%esi
  mov    %rbx,%rdi
  call   <GENERAL_NAME_set0_value@plt>
  mov    $0x1,%eax
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int GENERAL_NAME_set0_othername(GENERAL_NAME *gen, ASN1_OBJECT *oid, ASN1_TYPE *value) {
  OTHERNAME *oth;
  oth = OTHERNAME_new();
  if (!oth)
    return 0;
  oth->type_id = oid;
  oth->value = value;
  GENERAL_NAME_set0_value(gen, GEN_OTHERNAME, oth);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GENERAL_NAME_set0_othername>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <OTHERNAME_new@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L5
  mov    D4(%rip),%rax
  mov    %r12,0x8(%rdx)
  mov    %rbp,%rdi
  mov    %rbx,(%rdx)
  mov    (%rax),%esi
  call   <GENERAL_NAME_set0_value@plt>
  mov    $0x1,%eax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int GENERAL_NAME_set0_othername(GENERAL_NAME *gen, ASN1_OBJECT *oid, ASN1_TYPE *value) {
  OTHERNAME *oth;
  oth = OTHERNAME_new();
  if (!oth)
    return 0;
  oth->type_id = oid;
  oth->value = value;
  GENERAL_NAME_set0_value(gen, GEN_OTHERNAME, oth);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<GENERAL_NAME_set0_othername>:
  endbr64
  push   %rbp
  movq   %rdx,%xmm0
  movq   %rsi,%xmm1
  xor    %eax,%eax
  punpcklqdq %xmm1,%xmm0
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  movaps %xmm0,(%rsp)
  call   <OTHERNAME_new@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L5
  mov    D5(%rip),%rax
  movdqa (%rsp),%xmm0
  mov    %rbp,%rdi
  mov    (%rax),%esi
  movups %xmm0,(%rdx)
  call   <GENERAL_NAME_set0_value@plt>
  mov    $0x1,%eax
L5:
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
int GENERAL_NAME_set0_othername(GENERAL_NAME *gen, ASN1_OBJECT *oid, ASN1_TYPE *value) {
  OTHERNAME *oth;
  oth = OTHERNAME_new();
  if (!oth)
    return 0;
  oth->type_id = oid;
  oth->value = value;
  GENERAL_NAME_set0_value(gen, GEN_OTHERNAME, oth);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_ms_to_timeval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  add    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rcx
  mov    %rcx,%rax
  shr    $0x3,%rax
  movabs $0x20c49ba5e353f7cf,%rdx
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x4,%rax
  imul   $0x3e8,%rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  imul   $0x3e8,%eax,%eax
  add    %esi,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xf4240,%eax
  jle    L9
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    -0xf4240(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
L9:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void add_ms_to_timeval(struct timeval *a, unsigned long interval_ms, struct timeval *result) {
  result->tv_sec = a->tv_sec + (interval_ms / 1000);
  result->tv_usec = a->tv_usec + ((interval_ms % 1000) * 1000);
  if (result->tv_usec > 1000000) {
    result->tv_usec -= 1000000;
    result->tv_sec++;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<add_ms_to_timeval>:
  endbr64
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  shr    $0x3,%rdx
  movabs $0x20c49ba5e353f7cf,%r8
  mov    %rdx,%rax
  mul    %r8
  shr    $0x4,%rdx
  mov    %rdx,%rax
  add    0x8(%rdi),%rax
  mov    %rax,0x8(%rcx)
  imul   $0x3e8,%rdx,%rdx
  sub    %rdx,%rsi
  imul   $0x3e8,%esi,%esi
  add    (%rdi),%esi
  cmp    $0xf4240,%esi
  jg     L6
  mov    %esi,(%rcx)
  ret
L6:
  sub    $0xf4240,%esi
  mov    %esi,(%rcx)
  add    $0x1,%rax
  mov    %rax,0x8(%rcx)
  ret
```

assistant: ```c
void add_ms_to_timeval(struct timeval *a, unsigned long interval_ms, struct timeval *result) {
  result->tv_sec = a->tv_sec + (interval_ms / 1000);
  result->tv_usec = a->tv_usec + ((interval_ms % 1000) * 1000);
  if (result->tv_usec > 1000000) {
    result->tv_usec -= 1000000;
    result->tv_sec++;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<add_ms_to_timeval>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  mul    %r8
  mov    0x8(%rdi),%rax
  shr    $0x4,%rdx
  add    %rdx,%rax
  imul   $0x3e8,%rdx,%rdx
  mov    %rax,0x8(%rcx)
  sub    %rdx,%rsi
  imul   $0x3e8,%esi,%esi
  add    (%rdi),%esi
  cmp    $0xf4240,%esi
  jg     L8
  mov    %esi,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  sub    $0xf4240,%esi
  add    $0x1,%rax
  mov    %esi,(%rcx)
  mov    %rax,0x8(%rcx)
  ret
```

assistant: ```c
void add_ms_to_timeval(struct timeval *a, unsigned long interval_ms, struct timeval *result) {
  result->tv_sec = a->tv_sec + (interval_ms / 1000);
  result->tv_usec = a->tv_usec + ((interval_ms % 1000) * 1000);
  if (result->tv_usec > 1000000) {
    result->tv_usec -= 1000000;
    result->tv_sec++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_ms_to_timeval>:
  endbr64
  movabs $0x20c49ba5e353f7cf,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  shr    $0x3,%rdx
  mov    %rdx,%rax
  mul    %r8
  mov    0x8(%rdi),%rax
  shr    $0x4,%rdx
  add    %rdx,%rax
  imul   $0x3e8,%rdx,%rdx
  mov    %rax,0x8(%rcx)
  sub    %rdx,%rsi
  imul   $0x3e8,%esi,%esi
  add    (%rdi),%esi
  cmp    $0xf4240,%esi
  jg     L8
  mov    %esi,(%rcx)
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  sub    $0xf4240,%esi
  add    $0x1,%rax
  mov    %esi,(%rcx)
  mov    %rax,0x8(%rcx)
  ret
```

assistant: ```c
void add_ms_to_timeval(struct timeval *a, unsigned long interval_ms, struct timeval *result) {
  result->tv_sec = a->tv_sec + (interval_ms / 1000);
  result->tv_usec = a->tv_usec + ((interval_ms % 1000) * 1000);
  if (result->tv_usec > 1000000) {
    result->tv_usec -= 1000000;
    result->tv_sec++;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D82(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x18(%rbp),%rsi
  lea    -0x20(%rbp),%rcx
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D71(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x30(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L80
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L78
L80:
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x28(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L71
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L78
L71:
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L45
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L78
L45:
  movsd  -0x10(%rbp),%xmm0
  movsd  -0x18(%rbp),%xmm1
  comisd %xmm1,%xmm0
  jb     L79
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L78
L79:
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L78:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D82
type: string
name: disassemble_data
arguments: tag: D67
type: string
name: disassemble_data
arguments: tag: D71
type: string
name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D75
type: string
name: disassemble_data
arguments: tag: D88
type: string
name: disassemble_data
arguments: tag: D48
type: string
name: disassemble_data
arguments: tag: D52
type: string

tool: D82: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D67: %lf%lf%lf%lf

tool: D71: Thank you. Now enter student score (percent) >

tool: D33: %lf

tool: D8: Student has an A grade


tool: D75: Student has an B grade


tool: D88: Student has an C grade


tool: D48: Student has an D grade


tool: D52: Student has an F grade


assistant: ```c
int main(void) {
  double grade_a, grade_b, grade_c, grade_d, student_score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf%lf%lf%lf", &grade_a, &grade_b, &grade_c, &grade_d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &student_score);
  if (student_score >= grade_a) {
    printf("Student has an A grade\n");
  } else if (student_score >= grade_b) {
    printf("Student has an B grade\n");
  } else if (student_score >= grade_c) {
    printf("Student has an C grade\n");
  } else if (student_score >= grade_d) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D49(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x18(%rsp),%r8
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D80(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  comisd (%rsp),%xmm0
  jae    L45
  comisd 0x8(%rsp),%xmm0
  jae    L38
  comisd 0x10(%rsp),%xmm0
  jae    L72
  comisd 0x18(%rsp),%xmm0
  jb     L39
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L45:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L41:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L38:
  lea    D59(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L72:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L39:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D49
type_infered: string
name: unpack_data
arguments: tag: D5
type_infered: string
name: unpack_data
arguments: tag: D80
type_infered: string
name: unpack_data
arguments: tag: D48
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string
name: unpack_data
arguments: tag: D59
type_infered: string
name: unpack_data
arguments: tag: D26
type_infered: string
name: unpack_data
arguments: tag: D14
type_infered: string

tool: D49: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D5: %lf%lf%lf%lf

tool: D80: Thank you. Now enter student score (percent) >

tool: D48: %lf

tool: D27: Student has an D grade


tool: D12: Student has an A grade


tool: D59: Student has an B grade


tool: D26: Student has an C grade


tool: D14: Student has an F grade


assistant: ```c
int main(void) {
  double grade_a, grade_b, grade_c, grade_d, student_score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf%lf%lf%lf", &grade_a, &grade_b, &grade_c, &grade_d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &student_score);
  if (student_score >= grade_a) {
    printf("Student has an A grade\n");
  } else if (student_score >= grade_b) {
    printf("Student has an B grade\n");
  } else if (student_score >= grade_c) {
    printf("Student has an C grade\n");
  } else if (student_score >= grade_d) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D64(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x18(%rsp),%r8
  lea    D66(%rip),%rdi
  call   <scanf@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  comisd (%rsp),%xmm0
  jae    L17
  comisd 0x8(%rsp),%xmm0
  jae    L16
  comisd 0x10(%rsp),%xmm0
  jae    L4
  comisd 0x18(%rsp),%xmm0
  jb     L79
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L16:
  lea    D30(%rip),%rdi
  call   <printf@plt>
L55:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L17:
  lea    D61(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L79:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L4:
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L55
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D64
type: string
name: extract_symbolic_data
arguments: data_tag: D66
type: string
name: extract_symbolic_data
arguments: data_tag: D37
type: string
name: extract_symbolic_data
arguments: data_tag: D34
type: string
name: extract_symbolic_data
arguments: data_tag: D53
type: string
name: extract_symbolic_data
arguments: data_tag: D30
type: string
name: extract_symbolic_data
arguments: data_tag: D61
type: string
name: extract_symbolic_data
arguments: data_tag: D15
type: string
name: extract_symbolic_data
arguments: data_tag: D75
type: string

tool: D64: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D66: %lf%lf%lf%lf

tool: D37: Thank you. Now enter student score (percent) >

tool: D34: %lf

tool: D53: Student has an D grade


tool: D30: Student has an B grade


tool: D61: Student has an A grade


tool: D15: Student has an F grade


tool: D75: Student has an C grade


assistant: ```c
int main(void) {
  double grade_a, grade_b, grade_c, grade_d, student_score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf%lf%lf%lf", &grade_a, &grade_b, &grade_c, &grade_d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &student_score);
  if (student_score >= grade_a) {
    printf("Student has an A grade\n");
  } else if (student_score >= grade_b) {
    printf("Student has an B grade\n");
  } else if (student_score >= grade_c) {
    printf("Student has an C grade\n");
  } else if (student_score >= grade_d) {
    printf("Student has an D grade\n");
  } else {
    printf("Student has an F grade\n");
  }
  return 0;
}
```