ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ft_range>:
  endbr64
  cmp    %esi,%edi
  jge    L0
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    %edi,%ebx
  lea    0x0(,%rbx,4),%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r8
  test   %rax,%rax
  je     L67
  lea    -0x1(%rbx),%eax
  cmp    $0x2,%eax
  jbe    L4
  mov    %ebx,%edx
  movd   %ebp,%xmm3
  movdqa D2(%rip),%xmm2
  mov    %r8,%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm3,%xmm0
  paddd  D3(%rip),%xmm0
  shl    $0x4,%rdx
  add    %r8,%rdx
  nopl   0x0(%rax)
L76:
  movdqa %xmm0,%xmm1
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rdx
  jne    L76
  mov    %ebx,%edx
  and    $0xfffffffc,%edx
  add    %edx,%ebp
  cmp    %edx,%ebx
  je     L27
L45:
  movslq %edx,%rax
  lea    0x1(%rbp),%esi
  mov    %ebp,(%r8,%rax,4)
  lea    0x0(,%rax,4),%rcx
  lea    0x1(%rdx),%eax
  cmp    %ebx,%eax
  jge    L27
  add    $0x2,%edx
  mov    %esi,0x4(%r8,%rcx,1)
  lea    0x2(%rbp),%eax
  cmp    %edx,%ebx
  jle    L27
  mov    %eax,0x8(%r8,%rcx,1)
L27:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L67:
  add    $0x8,%rsp
  xor    %r8d,%r8d
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %edx,%edx
  jmp    L45
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type: byte[16]
name: unpack_data
arguments: data_tag: D3
type: byte[16]

tool: {"D2": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D3": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

assistant: ```c
int *ft_range(int min, int max) {
  int array_len;
  int i;
  int nb;
  int *range;
  if (min >= max)
    return (NULL);
  i = 0;
  nb = min;
  array_len = max - min;
  if (array_len < 0)
    return (NULL);
  range = malloc(array_len * sizeof(int));
  if (range == NULL)
    return (NULL);
  while (i < array_len)
    range[i++] = nb++;
  return (range);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%r8
  test   %r8,%r8
  je     L45
  mov    %rsp,%rdx
  mov    $0x0,%eax
L60:
  mov    (%rsp),%rdi
  cmp    %rax,%rdi
  jbe    L13
  movzbl 0x5(%rdx),%ecx
  movzbl 0x1(%rdx),%edi
  mov    %dil,0x5(%rdx)
  mov    %cl,0x1(%rdx)
L11:
  add    $0x1,%rax
  add    $0x8,%rdx
  cmp    %r8,%rax
  jne    L60
L45:
  mov    (%rsp),%rax
  rol    $0xf,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  ret
L13:
  je     L56
  mov    %rdi,%rcx
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  mov    %rdi,%r9
  shl    %cl,%r9
  mov    %r9,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rdi,%rcx
  mov    %rcx,(%rdx)
  jmp    L11
L56:
  mov    %rax,%rcx
  shr    $0x2,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  mov    %rax,%rdi
  ror    %cl,%rdi
  mov    %rdi,(%rdx)
  jmp    L11
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
      } else if (state[0UL] == local1) {
        state[local1] = (state[local1] >> (((state[local1] >> 2UL) & 15UL) | 1UL)) | (state[local1] << (64 - (((state[local1] >> 2UL) & 15UL) | 1UL)));
      } else {
        state[local1] |= ((state[local1] << (((state[local1] >> 2UL) & 7UL) | 1UL)) & 63UL) << 4UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 15UL) | (state[0UL] >> 49UL);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  add    $0x3686696a,%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,(%rsp)
  test   %rdi,%rdi
  je     L21
  mov    %rsp,%rdx
  xor    %esi,%esi
L66:
  cmp    %rax,%rsi
  jae    L0
  movzbl 0x5(%rdx),%eax
  movzbl 0x1(%rdx),%ecx
  mov    %al,0x1(%rdx)
  mov    %cl,0x5(%rdx)
  mov    (%rsp),%rax
L59:
  add    $0x1,%rsi
  add    $0x8,%rdx
  cmp    %rdi,%rsi
  jne    L66
L21:
  rol    $0xf,%rax
  mov    %rax,(%r8)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  je     L57
  mov    %rax,%rcx
  mov    %rax,%r9
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%r9
  mov    %r9,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
  mov    %rax,(%rdx)
  jmp    L59
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %rsi,%rcx
  mov    %rsi,%rax
  shr    $0x2,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%rax
  mov    %rax,(%rdx)
  jmp    L59
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
      } else if (state[0UL] == local1) {
        state[local1] = (state[local1] >> (((state[local1] >> 2UL) & 15UL) | 1UL)) | (state[local1] << (64 - (((state[local1] >> 2UL) & 15UL) | 1UL)));
      } else {
        state[local1] |= ((state[local1] << (((state[local1] >> 2UL) & 7UL) | 1UL)) & 63UL) << 4UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 15UL) | (state[0UL] >> 49UL);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    (%rdi),%rdx
  mov    0x8(%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x3686696a(%rdx),%rax
  xor    $0xffffffffce5d000b,%rax
  mov    %rax,(%rsp)
  test   %rdi,%rdi
  je     L47
  cmp    $0xffffffff97d696a1,%rdx
  je     L114
  mov    %ah,0x5(%rsp)
  shl    $0x10,%rax
  sar    $0x38,%rax
  mov    %al,0x1(%rsp)
  mov    (%rsp),%rax
  cmp    $0x1,%rdi
  je     L47
  cmp    $0x1,%rax
  jbe    L72
  movzbl 0xd(%rsp),%edx
  movzbl 0x9(%rsp),%ecx
  mov    %dl,0x9(%rsp)
  mov    %cl,0xd(%rsp)
L83:
  cmp    $0x2,%rdi
  jbe    L47
  mov    %rsp,%rdx
  mov    $0x2,%r8d
L44:
  cmp    %rax,%r8
  jae    L138
  movzbl 0x15(%rdx),%eax
  movzbl 0x11(%rdx),%ecx
  mov    %al,0x11(%rdx)
  mov    %cl,0x15(%rdx)
  mov    (%rsp),%rax
L33:
  add    $0x1,%r8
  add    $0x8,%rdx
  cmp    %rdi,%r8
  jne    L44
  nopl   0x0(%rax,%rax,1)
L47:
  rol    $0xf,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L118
  add    $0x18,%rsp
  ret
L114:
  xor    %eax,%eax
  cmp    $0x1,%rdi
  je     L47
L54:
  movq   $0x0,0x8(%rsp)
  xor    %eax,%eax
  jmp    L83
  nopl   (%rax)
L72:
  jne    L54
  movabs $0x8000000000000000,%rax
  mov    %rax,0x8(%rsp)
  jmp    L83
  xchg   %ax,%ax
L138:
  je     L93
  mov    %rax,%rcx
  mov    %rax,%r9
  shr    $0x2,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%r9
  mov    %r9,%rcx
  shl    $0x4,%rcx
  and    $0x3f0,%ecx
  or     %rcx,%rax
  mov    %rax,0x10(%rdx)
  jmp    L33
  xchg   %ax,%ax
L93:
  mov    %r8,%rcx
  mov    %r8,%rax
  shr    $0x2,%rcx
  and    $0xe,%ecx
  or     $0x1,%ecx
  ror    %cl,%rax
  mov    %rax,0x10(%rdx)
  jmp    L33
L118:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 0xffffffffce5d000bUL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
        } else {
          copy11 = *((char *)(&state[local1]) + 5);
          *((char *)(&state[local1]) + 5) = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = copy11;
        }
      } else if (state[0UL] == local1) {
        state[local1] = (state[local1] >> (((state[local1] >> 2UL) & 15UL) | 1UL)) | (state[local1] << (64 - (((state[local1] >> 2UL) & 15UL) | 1UL)));
      } else {
        state[local1] |= ((state[local1] << (((state[local1] >> 2UL) & 7UL) | 1UL)) & 63UL) << 4UL;
      }
      local1++;
    }
    output[0UL] = (state[0UL] << 15UL) | (state[0UL] >> 49UL);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<msg_identify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D29(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcaseeq@plt>
  test   %rax,%rax
  je     L4
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <msgreply@plt>
  mov    $0x0,%eax
  jmp    L10
L4:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <UpdateAccess@plt>
  mov    -0x10(%rbp),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <msguser@plt>
  mov    $0x0,%eax
L10:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D29
type_infered: string
name: retrieve_data
arguments: data_label: D0
type_infered: string
name: retrieve_data
arguments: data_label: D19
type_infered: string

tool: D29: help

tool: D0: Useage: identify <password>

tool: D19: Identification complete

assistant: ```c
int msg_identify(const char *replyto, struct userlist *user, const char *data) {
  if (strcaseeq(data, "help")) {
    msgreply(user, replyto, "Useage: identify <password>");
    return (0);
  }
  UpdateAccess(user, data);
  msguser(user, "Identification complete");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<msg_identify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  lea    D16(%rip),%rsi
  mov    %rdx,%rdi
  call   <strcaseeq@plt>
  test   %rax,%rax
  jne    L13
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <UpdateAccess@plt>
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <msguser@plt>
L17:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    D9(%rip),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <msgreply@plt>
  jmp    L17
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string
name: unpack_data
arguments: data_tag: D9
type_guessed: string

tool: D16: help

tool: D13: Identification complete

tool: D9: Useage: identify <password>

assistant: ```c
int msg_identify(const char *replyto, struct userlist *user, const char *data) {
  if (strcaseeq(data, "help")) {
    msgreply(user, replyto, "Useage: identify <password>");
    return (0);
  }
  UpdateAccess(user, data);
  msguser(user, "Identification complete");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<msg_identify>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D14(%rip),%rsi
  call   <strcaseeq@plt>
  test   %rax,%rax
  jne    L8
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <UpdateAccess@plt>
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  call   <msguser@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    D1(%rip),%rdx
  call   <msgreply@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D15
data_type: string
name: read_data
arguments: label: D1
data_type: string

tool: D14: help

tool: D15: Identification complete

tool: D1: Useage: identify <password>

assistant: ```c
int msg_identify(const char *replyto, struct userlist *user, const char *data) {
  if (strcaseeq(data, "help")) {
    msgreply(user, replyto, "Useage: identify <password>");
    return (0);
  }
  UpdateAccess(user, data);
  msguser(user, "Identification complete");
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<msg_identify>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  mov    %rdx,%rdi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  lea    D15(%rip),%rsi
  call   <strcaseeq@plt>
  test   %rax,%rax
  jne    L9
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <UpdateAccess@plt>
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  call   <msguser@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  lea    D19(%rip),%rdx
  call   <msgreply@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D15
type: string
name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D19
type: string

tool: D15: help

tool: D1: Identification complete

tool: D19: Useage: identify <password>

assistant: ```c
int msg_identify(const char *replyto, struct userlist *user, const char *data) {
  if (strcaseeq(data, "help")) {
    msgreply(user, replyto, "Useage: identify <password>");
    return (0);
  }
  UpdateAccess(user, data);
  msguser(user, "Identification complete");
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_islower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x60,-0x4(%rbp)
  jle    L3
  cmpl   $0x7a,-0x4(%rbp)
  jg     L3
  mov    $0x1,%eax
  jmp    L7
L3:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int _islower(int c) {
  if (c >= 'a' && c <= 'z') {
    return (1);
  } else {
    return (0);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_islower>:
  endbr64
  sub    $0x61,%edi
  cmp    $0x19,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int _islower(int c) {
  if (c >= 'a' && c <= 'z') {
    return (1);
  } else {
    return (0);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_islower>:
  endbr64
  sub    $0x61,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int _islower(int c) {
  if (c >= 'a' && c <= 'z') {
    return (1);
  } else {
    return (0);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_islower>:
  endbr64
  sub    $0x61,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int _islower(int c) {
  if (c >= 'a' && c <= 'z') {
    return (1);
  } else {
    return (0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void error(const char *s, ...) {
  va_list va;
  va_start(va, s);
  vfprintf(stderr, s, va);
  va_end(va);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<error>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void error(const char *s, ...) {
  va_list va;
  va_start(va, s);
  vfprintf(stderr, s, va);
  va_end(va);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(const char *s, ...) {
  va_list va;
  va_start(va, s);
  vfprintf(stderr, s, va);
  va_end(va);
}
```
user: Translate the below assembly code into C programming language:

```asm
<error>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error(const char *s, ...) {
  va_list va;
  va_start(va, s);
  vfprintf(stderr, s, va);
  va_end(va);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<AND_zpx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <c64_memZeroX@plt>
  mov    $0x0,%eax
  call   <AND_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AND_zpx(void) {
  c64_memZeroX();
  AND_();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<AND_zpx>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <c64_memZeroX@plt>
  mov    $0x0,%eax
  call   <AND_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void AND_zpx(void) {
  c64_memZeroX();
  AND_();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AND_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memZeroX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <AND_@plt>
```

assistant: ```c
void AND_zpx(void) {
  c64_memZeroX();
  AND_();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<AND_zpx>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memZeroX@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <AND_@plt>
```

assistant: ```c
void AND_zpx(void) {
  c64_memZeroX();
  AND_();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gusto_stop_clock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  mov    -0x28(%rbp),%rax
  movsd  0x8(%rax),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x10(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x18(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
data_type: byte[8]

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double gusto_stop_clock(void *clock_s) {
  struct timeval *T0 = (struct timeval *)clock_s;
  struct timeval *T1 = (struct timeval *)malloc(sizeof(struct timeval));
  gettimeofday(T1, NULL);
  double ds = T1->tv_sec - T0->tv_sec;
  double du = T1->tv_usec - T0->tv_usec;
  double dt = ds + 1e-6 * du;
  free(T0);
  free(T1);
  return dt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gusto_stop_clock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rbx),%xmm0
  subsd  0x8(%rbp),%xmm0
  mulsd  D0(%rip),%xmm0
  movsd  (%rbx),%xmm1
  subsd  0x0(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: byte[8]

tool: {"D0": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double gusto_stop_clock(void *clock_s) {
  struct timeval *T0 = (struct timeval *)clock_s;
  struct timeval *T1 = (struct timeval *)malloc(sizeof(struct timeval));
  gettimeofday(T1, NULL);
  double ds = T1->tv_sec - T0->tv_sec;
  double du = T1->tv_usec - T0->tv_usec;
  double dt = ds + 1e-6 * du;
  free(T0);
  free(T1);
  return dt;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gusto_stop_clock>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x10,%edi
  push   %rbp
  sub    $0x18,%rsp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rbp),%xmm0
  movsd  0x0(%rbp),%xmm1
  mov    %r12,%rdi
  subsd  0x8(%r12),%xmm0
  mulsd  D4(%rip),%xmm0
  subsd  (%r12),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: byte[8]

tool: {"D4": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double gusto_stop_clock(void *clock_s) {
  struct timeval *T0 = (struct timeval *)clock_s;
  struct timeval *T1 = (struct timeval *)malloc(sizeof(struct timeval));
  gettimeofday(T1, NULL);
  double ds = T1->tv_sec - T0->tv_sec;
  double du = T1->tv_usec - T0->tv_usec;
  double dt = ds + 1e-6 * du;
  free(T0);
  free(T1);
  return dt;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gusto_stop_clock>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x10,%edi
  push   %rbp
  sub    $0x18,%rsp
  call   <malloc@plt>
  xor    %esi,%esi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  movsd  0x8(%rbp),%xmm0
  movsd  0x0(%rbp),%xmm1
  mov    %r12,%rdi
  subsd  0x8(%r12),%xmm0
  mulsd  D9(%rip),%xmm0
  subsd  (%r12),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: byte[8]

tool: {"D9": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

assistant: ```c
double gusto_stop_clock(void *clock_s) {
  struct timeval *T0 = (struct timeval *)clock_s;
  struct timeval *T1 = (struct timeval *)malloc(sizeof(struct timeval));
  gettimeofday(T1, NULL);
  double ds = T1->tv_sec - T0->tv_sec;
  double du = T1->tv_usec - T0->tv_usec;
  double dt = ds + 1e-6 * du;
  free(T0);
  free(T1);
  return dt;
}
```