ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<NetlinkGetInterfaceFlags>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0xffff,%edi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x0,%edi
  test   %rbx,%rbx
  je     L9
  mov    D0(%rip),%rsi
  mov    %rbx,%rax
  mov    $0x0,%edx
  divq   (%rsi)
  test   %rdx,%rdx
  sete   %dil
  movzbl %dil,%edi
L9:
  call   <assert@plt>
  test   %r12,%r12
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%r8
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <NlGetIfInfoByIndex@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L12
L35:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  mov    0x10(%rsp),%rax
  mov    (%rax),%eax
  mov    %eax,(%r12)
  mov    $0x1,%eax
  jmp    L35
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool NetlinkGetInterfaceFlags(int32_t nl_len, void *nl_msg, int32_t if_index, uint32_t *ifi_flags) {
  assert(0 <= nl_len && nl_len < (1 << 16));
  assert(nl_msg != NULL && (size_t)nl_msg % NLMSG_ALIGNTO == 0);
  assert(ifi_flags != NULL);
  struct nlmsghdr *nh = (struct nlmsghdr *)nl_msg;
  int32_t rt_len;
  struct ifinfomsg *rt_msg;
  if (NlGetIfInfoByIndex(nl_len, nh, if_index, &rt_len, &rt_msg)) {
    *ifi_flags = rt_msg->ifi_flags;
    return true;
  }
  return false;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<NetlinkGetInterfaceFlags>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0xffff,%edi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  je     L9
  mov    D8(%rip),%rsi
  xor    %edx,%edx
  mov    %rbp,%rax
  xor    %edi,%edi
  divq   (%rsi)
  test   %rdx,%rdx
  sete   %dil
L9:
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  lea    0x10(%rsp),%r8
  mov    %r13d,%edx
  mov    %rbp,%rsi
  lea    0xc(%rsp),%rcx
  mov    %r12d,%edi
  call   <NlGetIfInfoByIndex@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L29
  mov    0x10(%rsp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L29:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool NetlinkGetInterfaceFlags(int32_t nl_len, void *nl_msg, int32_t if_index, uint32_t *ifi_flags) {
  assert(0 <= nl_len && nl_len < (1 << 16));
  assert(nl_msg != NULL && (size_t)nl_msg % NLMSG_ALIGNTO == 0);
  assert(ifi_flags != NULL);
  struct nlmsghdr *nh = (struct nlmsghdr *)nl_msg;
  int32_t rt_len;
  struct ifinfomsg *rt_msg;
  if (NlGetIfInfoByIndex(nl_len, nh, if_index, &rt_len, &rt_msg)) {
    *ifi_flags = rt_msg->ifi_flags;
    return true;
  }
  return false;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<NetlinkGetInterfaceFlags>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0xffff,%edi
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  je     L18
  mov    D3(%rip),%rsi
  xor    %edx,%edx
  mov    %rbp,%rax
  xor    %edi,%edi
  divq   (%rsi)
  test   %rdx,%rdx
  sete   %dil
L18:
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  lea    0x10(%rsp),%r8
  mov    %r13d,%edx
  mov    %rbp,%rsi
  lea    0xc(%rsp),%rcx
  mov    %r12d,%edi
  call   <NlGetIfInfoByIndex@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L28
  mov    0x10(%rsp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L28:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
bool NetlinkGetInterfaceFlags(int32_t nl_len, void *nl_msg, int32_t if_index, uint32_t *ifi_flags) {
  assert(0 <= nl_len && nl_len < (1 << 16));
  assert(nl_msg != NULL && (size_t)nl_msg % NLMSG_ALIGNTO == 0);
  assert(ifi_flags != NULL);
  struct nlmsghdr *nh = (struct nlmsghdr *)nl_msg;
  int32_t rt_len;
  struct ifinfomsg *rt_msg;
  if (NlGetIfInfoByIndex(nl_len, nh, if_index, &rt_len, &rt_msg)) {
    *ifi_flags = rt_msg->ifi_flags;
    return true;
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<expect_line_break_or>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  mov    $0x0,%eax
  call   <expect_line_break@plt>
  test   %rax,%rax
  je     L27
  mov    $0x1,%eax
  jmp    L18
L27:
  mov    $0x0,%eax
  call   <get_char@plt>
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  cmp    -0x14(%rbp),%al
  jne    L0
  mov    $0x1,%eax
  jmp    L18
L0:
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <unget_char@plt>
  mov    $0x0,%eax
L18:
  leave
  ret
```

assistant: ```c
int expect_line_break_or(char expected) {
  if (expect_line_break()) {
    return 1;
  }
  char c = get_char();
  if (c == expected) {
    return 1;
  }
  unget_char(c);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<expect_line_break_or>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <expect_line_break@plt>
  mov    $0x1,%edx
  test   %rax,%rax
  je     L26
L14:
  mov    %edx,%eax
  pop    %rbx
  ret
L26:
  call   <get_char@plt>
  mov    $0x1,%edx
  cmp    %bl,%al
  je     L14
  movsbl %al,%edi
  call   <unget_char@plt>
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
int expect_line_break_or(char expected) {
  if (expect_line_break()) {
    return 1;
  }
  char c = get_char();
  if (c == expected) {
    return 1;
  }
  unget_char(c);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<expect_line_break_or>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <expect_line_break@plt>
  test   %rax,%rax
  je     L13
L18:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  call   <get_char@plt>
  cmp    %bl,%al
  je     L18
  movsbl %al,%edi
  call   <unget_char@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int expect_line_break_or(char expected) {
  if (expect_line_break()) {
    return 1;
  }
  char c = get_char();
  if (c == expected) {
    return 1;
  }
  unget_char(c);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<expect_line_break_or>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <expect_line_break@plt>
  test   %rax,%rax
  je     L7
L18:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  call   <get_char@plt>
  cmp    %bl,%al
  je     L18
  movsbl %al,%edi
  call   <unget_char@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int expect_line_break_or(char expected) {
  if (expect_line_break()) {
    return 1;
  }
  char c = get_char();
  if (c == expected) {
    return 1;
  }
  unget_char(c);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__mulsi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L14:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L25
  mov    -0x18(%rbp),%eax
  add    %eax,-0x4(%rbp)
L25:
  shrl   -0x14(%rbp)
  shll   -0x18(%rbp)
L4:
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int __mulsi3(unsigned int a, unsigned int b) {
  unsigned int r = 0;
  while (a) {
    if (a & 1)
      r += b;
    a >>= 1;
    b <<= 1;
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__mulsi3>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    $0x0,%eax
L8:
  lea    (%rax,%rsi,1),%edx
  test   $0x1,%dil
  cmovne %edx,%eax
  add    %esi,%esi
  shr    %edi
  jne    L8
  ret
L9:
  mov    %edi,%eax
  ret
```

assistant: ```c
unsigned int __mulsi3(unsigned int a, unsigned int b) {
  unsigned int r = 0;
  while (a) {
    if (a & 1)
      r += b;
    a >>= 1;
    b <<= 1;
  }
  return r;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__mulsi3>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L9
  nopw   0x0(%rax,%rax,1)
L14:
  test   $0x1,%dil
  lea    (%rax,%rsi,1),%edx
  cmovne %edx,%eax
  add    %esi,%esi
  shr    %edi
  jne    L14
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
unsigned int __mulsi3(unsigned int a, unsigned int b) {
  unsigned int r = 0;
  while (a) {
    if (a & 1)
      r += b;
    a >>= 1;
    b <<= 1;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__mulsi3>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L11
  nopw   0x0(%rax,%rax,1)
L8:
  test   $0x1,%dil
  lea    (%rax,%rsi,1),%edx
  cmovne %edx,%eax
  add    %esi,%esi
  shr    %edi
  jne    L8
  ret
  nopl   0x0(%rax)
L11:
  ret
```

assistant: ```c
unsigned int __mulsi3(unsigned int a, unsigned int b) {
  unsigned int r = 0;
  while (a) {
    if (a & 1)
      r += b;
    a >>= 1;
    b <<= 1;
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__fls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L19
L10:
  mov    -0x4(%rbp),%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L13
  mov    -0x4(%rbp),%eax
  cltq
  jmp    L15
L13:
  subl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jns    L10
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cltq
L15:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long __fls(unsigned long b) {
  int i;
  for (i = __WORDSIZE - 1; i >= 0; i--)
    if (b & (1UL << i))
      return i;
  return __WORDSIZE;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__fls>:
  endbr64
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L2
  bt     %rdx,%rdi
  jb     L34
L30:
  sub    $0x1,%edx
  cmp    $0xffffffff,%edx
  je     L2
  bt     %rdx,%rdi
  jae    L30
L34:
  movslq %edx,%rax
  ret
L2:
  cltq
  ret
```

assistant: ```c
unsigned long __fls(unsigned long b) {
  int i;
  for (i = __WORDSIZE - 1; i >= 0; i--)
    if (b & (1UL << i))
      return i;
  return __WORDSIZE;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__fls>:
  endbr64
  mov    D8(%rip),%rax
  movslq (%rax),%rax
  mov    %eax,%edx
  sub    $0x1,%edx
  jns    L6
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L32:
  sub    $0x1,%edx
  jb     L10
L6:
  bt     %rdx,%rdi
  jae    L32
  movslq %edx,%rax
  ret
  nop
L10:
  ret
```

assistant: ```c
unsigned long __fls(unsigned long b) {
  int i;
  for (i = __WORDSIZE - 1; i >= 0; i--)
    if (b & (1UL << i))
      return i;
  return __WORDSIZE;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__fls>:
  endbr64
  mov    D4(%rip),%rax
  movslq (%rax),%rax
  mov    %eax,%edx
  sub    $0x1,%edx
  jns    L18
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L31:
  sub    $0x1,%edx
  jb     L25
L18:
  bt     %rdx,%rdi
  jae    L31
  movslq %edx,%rax
  ret
  nop
L25:
  ret
```

assistant: ```c
unsigned long __fls(unsigned long b) {
  int i;
  for (i = __WORDSIZE - 1; i >= 0; i--)
    if (b & (1UL << i))
      return i;
  return __WORDSIZE;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L4
L7:
  mov    -0x10(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
L4:
  cmpl   $0x0,-0x10(%rbp)
  jne    L7
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int num, r, rn = 0, print = num;
  while (num) {
    r = num % 10;
    rn = rn * 10 + r;
    num = num / 10;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int num, r, rn = 0, print = num;
  while (num) {
    r = num % 10;
    rn = rn * 10 + r;
    num = num / 10;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int num, r, rn = 0, print = num;
  while (num) {
    r = num % 10;
    rn = rn * 10 + r;
    num = num / 10;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int num, r, rn = 0, print = num;
  while (num) {
    r = num % 10;
    rn = rn * 10 + r;
    num = num / 10;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_ints>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8,%edi
  call   <clzi@plt>
  cmp    $0x1c,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  mov    $0x400,%edi
  call   <clzi@plt>
  cmp    $0x15,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  mov    $0xffffff,%edi
  call   <clzi@plt>
  cmp    $0x8,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  mov    $0xffffffff,%edi
  call   <clzi@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <assertTrue@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D32
type: string
name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D31
type: string

tool: D11: clzi(8) == 28

tool: D32: clzi(1024) == 21

tool: D8: clzi(16777215) == 8

tool: D31: clzi(-1) == 0

assistant: ```c
void test_ints() {
  assertTrue("clzi(8) == 28", clzi(8) == 28);
  assertTrue("clzi(1024) == 21", clzi(1024) == 21);
  assertTrue("clzi(16777215) == 8", clzi(16777215) == 8);
  assertTrue("clzi(-1) == 0", clzi(-1) == 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_ints>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <clzi@plt>
  cmp    $0x1c,%eax
  sete   %sil
  movzbl %sil,%esi
  lea    D32(%rip),%rdi
  call   <assertTrue@plt>
  mov    $0x400,%edi
  call   <clzi@plt>
  cmp    $0x15,%eax
  sete   %sil
  movzbl %sil,%esi
  lea    D4(%rip),%rdi
  call   <assertTrue@plt>
  mov    $0xffffff,%edi
  call   <clzi@plt>
  cmp    $0x8,%eax
  sete   %sil
  movzbl %sil,%esi
  lea    D0(%rip),%rdi
  call   <assertTrue@plt>
  mov    $0xffffffff,%edi
  call   <clzi@plt>
  test   %eax,%eax
  sete   %sil
  movzbl %sil,%esi
  lea    D38(%rip),%rdi
  call   <assertTrue@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D32
type: string
name: retrieve_data
arguments: label: D4
type: string
name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D38
type: string

tool: D32: clzi(8) == 28

tool: D4: clzi(1024) == 21

tool: D0: clzi(16777215) == 8

tool: D38: clzi(-1) == 0

assistant: ```c
void test_ints() {
  assertTrue("clzi(8) == 28", clzi(8) == 28);
  assertTrue("clzi(1024) == 21", clzi(1024) == 21);
  assertTrue("clzi(16777215) == 8", clzi(16777215) == 8);
  assertTrue("clzi(-1) == 0", clzi(-1) == 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_ints>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D20(%rip),%rdi
  cmp    $0x1c,%eax
  sete   %sil
  call   <assertTrue@plt>
  mov    $0x400,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D23(%rip),%rdi
  cmp    $0x15,%eax
  sete   %sil
  call   <assertTrue@plt>
  mov    $0xffffff,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D21(%rip),%rdi
  cmp    $0x8,%eax
  sete   %sil
  call   <assertTrue@plt>
  mov    $0xffffffff,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D28(%rip),%rdi
  test   %eax,%eax
  sete   %sil
  add    $0x8,%rsp
  jmp    1060 <assertTrue@plt>
```

tool_calls: name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D21
type_infered: string
name: unpack_data
arguments: label: D28
type_infered: string

tool: D20: clzi(8) == 28

tool: D23: clzi(1024) == 21

tool: D21: clzi(16777215) == 8

tool: D28: clzi(-1) == 0

assistant: ```c
void test_ints() {
  assertTrue("clzi(8) == 28", clzi(8) == 28);
  assertTrue("clzi(1024) == 21", clzi(1024) == 21);
  assertTrue("clzi(16777215) == 8", clzi(16777215) == 8);
  assertTrue("clzi(-1) == 0", clzi(-1) == 0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_ints>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D16(%rip),%rdi
  cmp    $0x1c,%eax
  sete   %sil
  call   <assertTrue@plt>
  mov    $0x400,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D35(%rip),%rdi
  cmp    $0x15,%eax
  sete   %sil
  call   <assertTrue@plt>
  mov    $0xffffff,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D24(%rip),%rdi
  cmp    $0x8,%eax
  sete   %sil
  call   <assertTrue@plt>
  mov    $0xffffffff,%edi
  call   <clzi@plt>
  xor    %esi,%esi
  lea    D36(%rip),%rdi
  test   %eax,%eax
  sete   %sil
  add    $0x8,%rsp
  jmp    1060 <assertTrue@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D35
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string
name: unpack_data
arguments: tag: D36
type_infered: string

tool: D16: clzi(8) == 28

tool: D35: clzi(1024) == 21

tool: D24: clzi(16777215) == 8

tool: D36: clzi(-1) == 0

assistant: ```c
void test_ints() {
  assertTrue("clzi(8) == 28", clzi(8) == 28);
  assertTrue("clzi(1024) == 21", clzi(1024) == 21);
  assertTrue("clzi(16777215) == 8", clzi(16777215) == 8);
  assertTrue("clzi(-1) == 0", clzi(-1) == 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xfd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L0:
  lea    -0xfbc(%rbp),%rcx
  lea    -0xfc0(%rbp),%rdx
  lea    -0xfc4(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xfc4(%rbp),%eax
  test   %eax,%eax
  jne    L37
  mov    -0xfc0(%rbp),%eax
  test   %eax,%eax
  jne    L37
  mov    -0xfbc(%rbp),%eax
  test   %eax,%eax
  je     L88
L37:
  movl   $0x0,-0xfb8(%rbp)
  movl   $0x0,-0xfb4(%rbp)
  jmp    L73
L30:
  lea    -0xfb0(%rbp),%rdx
  mov    -0xfb4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xfb4(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  add    %eax,-0xfb8(%rbp)
  addl   $0x1,-0xfb4(%rbp)
L73:
  mov    -0xfc4(%rbp),%eax
  cmp    %eax,-0xfb4(%rbp)
  jl     L30
  mov    -0xfc0(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L6
  mov    -0xfbc(%rbp),%edx
  mov    $0x64,%eax
  sub    %edx,%eax
  imul   -0xfb8(%rbp),%eax
  mov    -0xfc0(%rbp),%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  mov    -0xfb0(%rbp,%rdx,4),%ecx
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L0
L6:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L0
L88:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D28
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string
name: extract_symbolic_data
arguments: label: D1
datatype: string

tool: D28: %d %d %d

tool: D21: %d

tool: D5: %d


tool: D1: 0

assistant: ```c
int main(void) {
  int num, first, percent, gold[1000], sum, i;
  while (1) {
    scanf("%d %d %d", &num, &first, &percent);
    if (num == 0 && first == 0 && percent == 0)
      break;
    sum = 0;
    for (i = 0; i < num; i++) {
      scanf("%d", &gold[i]);
      sum += gold[i];
    }
    if (gold[first - 1] != 0) {
      printf("%d\n", sum * (100 - percent) / gold[first - 1]);
    } else {
      printf("0\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xfc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    D13(%rip),%r14
  lea    D1(%rip),%r13
  lea    D12(%rip),%r15
  jmp    L88
L77:
  jle    L23
  mov    $0x0,%ebx
  mov    $0x0,%r12d
L46:
  lea    0x10(%rsp),%rbp
  lea    0x0(%rbp,%rbx,4),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    0x0(%rbp,%rbx,4),%r12d
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jg     L46
L84:
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  cltq
  mov    0x10(%rsp,%rax,4),%ecx
  test   %ecx,%ecx
  je     L19
  mov    $0x64,%eax
  sub    0xc(%rsp),%eax
  imul   %r12d,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L88:
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x4(%rsp),%r12d
  test   %r12d,%r12d
  jne    L77
  mov    0x8(%rsp),%eax
  or     0xc(%rsp),%eax
  jne    L84
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xfc8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  mov    $0x0,%r12d
  jmp    L84
L19:
  mov    %r15,%rdi
  call   <puts@plt>
  jmp    L88
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D13
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D37
data_type: string

tool: D13: %d %d %d

tool: D1: %d

tool: D12: 0

tool: D37: %d


assistant: ```c
int main(void) {
  int num, first, percent, gold[1000], sum, i;
  while (1) {
    scanf("%d %d %d", &num, &first, &percent);
    if (num == 0 && first == 0 && percent == 0)
      break;
    sum = 0;
    for (i = 0; i < num; i++) {
      scanf("%d", &gold[i]);
      sum += gold[i];
    }
    if (gold[first - 1] != 0) {
      printf("%d\n", sum * (100 - percent) / gold[first - 1]);
    } else {
      printf("0\n");
    }
  }
  return 0;
}
```