ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<test_MatrixT>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    D41(%rip),%rax
  mov    %rax,(%rsp)
  mov    D95(%rip),%rax
  mov    %rax,0x8(%rsp)
  mov    D116(%rip),%rax
  mov    %rax,0x10(%rsp)
  mov    D13(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    D42(%rip),%rax
  mov    %rax,0x20(%rsp)
  mov    D81(%rip),%rax
  mov    %rax,0x28(%rsp)
  mov    D101(%rip),%rax
  mov    %rax,0x30(%rsp)
  mov    D109(%rip),%rax
  mov    %rax,0x38(%rsp)
  mov    D72(%rip),%rax
  mov    %rax,0x40(%rsp)
  mov    D56(%rip),%rax
  mov    %rax,0x48(%rsp)
  mov    D106(%rip),%rax
  mov    %rax,0x50(%rsp)
  mov    D4(%rip),%rax
  mov    %rax,0x58(%rsp)
  lea    0x60(%rsp),%rcx
  mov    %rsp,%rdi
  mov    $0x3,%edx
  mov    $0x4,%esi
  call   <MatrixT@plt>
  lea    0x80(%rsp),%rbp
  lea    0xe0(%rsp),%r13
  lea    D7(%rip),%r12
L21:
  lea    -0x20(%rbp),%rbx
L23:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L23
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x20,%rbp
  cmp    %r13,%rbp
  jne    L21
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D41
type: byte[8]
name: read_data
arguments: tag: D95
type: byte[8]
name: read_data
arguments: tag: D116
type: byte[8]
name: read_data
arguments: tag: D13
type: byte[8]
name: read_data
arguments: tag: D42
type: byte[8]
name: read_data
arguments: tag: D81
type: byte[8]
name: read_data
arguments: tag: D101
type: byte[8]
name: read_data
arguments: tag: D109
type: byte[8]
name: read_data
arguments: tag: D72
type: byte[8]
name: read_data
arguments: tag: D56
type: byte[8]
name: read_data
arguments: tag: D106
type: byte[8]
name: read_data
arguments: tag: D4
type: byte[8]
name: read_data
arguments: tag: D7
type: string

tool: {"D41": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D95": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D116": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D42": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D81": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D101": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

tool: {"D109": [0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D72": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40]}

tool: {"D56": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D106": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x28,0x40]}

tool: D7: %lf  

assistant: ```c
void test_MatrixT() {
  double a[4][3] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12};
  double c[3][4];
  MatrixT((double *)a, 4, 3, (double *)c);
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%lf  ", c[i][j]);
    }
    printf("\n");
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<test_MatrixT>:
  endbr64
  push   %r13
  mov    $0x3,%edx
  mov    $0x4,%esi
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  movapd D8(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rcx
  mov    %rsp,%rdi
  lea    0x80(%rsp),%rbp
  movaps %xmm0,(%rsp)
  movapd D38(%rip),%xmm0
  lea    0xe0(%rsp),%r13
  movaps %xmm0,0x10(%rsp)
  movapd D60(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  movapd D2(%rip),%xmm0
  movaps %xmm0,0x30(%rsp)
  movapd D58(%rip),%xmm0
  movaps %xmm0,0x40(%rsp)
  movapd D63(%rip),%xmm0
  movaps %xmm0,0x50(%rsp)
  call   <MatrixT@plt>
L7:
  lea    -0x20(%rbp),%rbx
L28:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L28
  mov    $0xa,%edi
  lea    0x20(%rbx),%rbp
  call   <putchar@plt>
  cmp    %r13,%rbp
  jne    L7
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D28
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D38
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D60
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D2
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D58
type_guessed: byte[16]
name: unpack_data
arguments: data_label: D63
type_guessed: byte[16]

tool: D28: %lf  

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D38": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x40]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x40]}

tool: {"D58": [0x00,0x00,0x00,0x00,0x00,0x00,0x22,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: {"D63": [0x00,0x00,0x00,0x00,0x00,0x00,0x26,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x28,0x40]}

assistant: ```c
void test_MatrixT() {
  double a[4][3] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12};
  double c[3][4];
  MatrixT((double *)a, 4, 3, (double *)c);
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      printf("%lf  ", c[i][j]);
    }
    printf("\n");
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_popa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <assem_debug@plt>
  mov    $0x61,%edi
  call   <output_byte@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: popa


assistant: ```c
void emit_popa() {
  assem_debug("popa\n");
  output_byte(0x61);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<emit_popa>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x61,%edi
  call   <output_byte@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: popa


assistant: ```c
void emit_popa() {
  assem_debug("popa\n");
  output_byte(0x61);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<emit_popa>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x61,%edi
  add    $0x8,%rsp
  jmp    1070 <output_byte@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string

tool: D7: popa


assistant: ```c
void emit_popa() {
  assem_debug("popa\n");
  output_byte(0x61);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<emit_popa>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <assem_debug@plt>
  mov    $0x61,%edi
  add    $0x8,%rsp
  jmp    1070 <output_byte@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: D9: popa


assistant: ```c
void emit_popa() {
  assem_debug("popa\n");
  output_byte(0x61);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *copy_string(char *s) {
  char *copy = malloc(strlen(s) + 1);
  strncpy(copy, s, strlen(s) + 1);
  return copy;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<copy_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *copy_string(char *s) {
  char *copy = malloc(strlen(s) + 1);
  strncpy(copy, s, strlen(s) + 1);
  return copy;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(char *s) {
  char *copy = malloc(strlen(s) + 1);
  strncpy(copy, s, strlen(s) + 1);
  return copy;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_string>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <strncpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *copy_string(char *s) {
  char *copy = malloc(strlen(s) + 1);
  strncpy(copy, s, strlen(s) + 1);
  return copy;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x74206120616c6f48,%rax
  mov    %rax,-0xdd(%rbp)
  movl   $0x736f646f,-0xd5(%rbp)
  movb   $0x0,-0xd1(%rbp)
  lea    -0xdd(%rbp),%rax
  mov    %rax,-0xf0(%rbp)
  lea    -0xd0(%rbp),%rax
  mov    %rax,-0xe8(%rbp)
  lea    -0xdd(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xf0(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <longitud_string@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xd0(%rbp),%rax
  movabs $0x62696c207265656c,%rdx
  movabs $0x6572207920736f72,%rcx
  mov    %rdx,(%rax)
  mov    %rcx,0x8(%rax)
  movl   $0x74736976,0x10(%rax)
  movw   $0x7361,0x14(%rax)
  movb   $0x0,0x16(%rax)
  lea    -0xd0(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xe8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <longitud_string@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string
name: parse_data
arguments: data_label: D5
datatype: string
name: parse_data
arguments: data_label: D8
datatype: string

tool: D2: cadena: %s


tool: D5: longitud cadena: %d


tool: D8: cadena2: %s


assistant: ```c
int main(void) {
  char string1[] = "Hola a todos";
  char string2[200];
  char *ap_string1, *ap_string2;
  ap_string1 = &string1;
  ap_string2 = &string2;
  printf("cadena: %s\n", string1);
  printf("longitud cadena: %d\n", longitud_string(ap_string1));
  strcpy(string2, "leer libros y revistas");
  printf("cadena2: %s\n", string2);
  printf("longitud cadena: %d\n", longitud_string(ap_string2));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  movabs $0x74206120616c6f48,%rax
  mov    %rax,0x3(%rsp)
  movl   $0x736f646f,0xb(%rsp)
  movb   $0x0,0xf(%rsp)
  lea    0x3(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <longitud_string@plt>
  mov    %eax,%esi
  lea    D14(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  movabs $0x62696c207265656c,%rax
  movabs $0x6572207920736f72,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movl   $0x74736976,0x20(%rsp)
  movw   $0x7361,0x24(%rsp)
  movb   $0x0,0x26(%rsp)
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <longitud_string@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D2
type_guessed: string

tool: D6: cadena: %s


tool: D14: longitud cadena: %d


tool: D2: cadena2: %s


assistant: ```c
int main(void) {
  char string1[] = "Hola a todos";
  char string2[200];
  char *ap_string1, *ap_string2;
  ap_string1 = &string1;
  ap_string2 = &string2;
  printf("cadena: %s\n", string1);
  printf("longitud cadena: %d\n", longitud_string(ap_string1));
  strcpy(string2, "leer libros y revistas");
  printf("cadena2: %s\n", string2);
  printf("longitud cadena: %d\n", longitud_string(ap_string2));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  lea    D39(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  movabs $0x74206120616c6f48,%rax
  lea    0x3(%rsp),%rbp
  movl   $0x736f646f,0xb(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x3(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D7(%rip),%rbp
  call   <longitud_string@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movdqa D32(%rip),%xmm0
  mov    %r12,%rsi
  mov    $0x7361,%eax
  mov    %ax,0x24(%rsp)
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movl   $0x74736976,0x20(%rsp)
  movb   $0x0,0x26(%rsp)
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <longitud_string@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D39
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D32
type: byte[16]
name: extract_symbolic_data
arguments: tag: D18
type: string

tool: D39: cadena: %s


tool: D7: longitud cadena: %d


tool: {"D32": [0x6c,0x65,0x65,0x72,0x20,0x6c,0x69,0x62,0x72,0x6f,0x73,0x20,0x79,0x20,0x72,0x65]}

tool: D18: cadena2: %s


assistant: ```c
int main(void) {
  char string1[] = "Hola a todos";
  char string2[200];
  char *ap_string1, *ap_string2;
  ap_string1 = &string1;
  ap_string2 = &string2;
  printf("cadena: %s\n", string1);
  printf("longitud cadena: %d\n", longitud_string(ap_string1));
  strcpy(string2, "leer libros y revistas");
  printf("cadena2: %s\n", string2);
  printf("longitud cadena: %d\n", longitud_string(ap_string2));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D22(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  movabs $0x74206120616c6f48,%rax
  lea    0x3(%rsp),%rbp
  movl   $0x736f646f,0xb(%rsp)
  lea    0x10(%rsp),%r12
  mov    %rbp,%rsi
  movb   $0x0,0xf(%rsp)
  mov    %rax,0x3(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D23(%rip),%rbp
  call   <longitud_string@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  movdqa D2(%rip),%xmm0
  mov    %r12,%rsi
  mov    $0x7361,%eax
  mov    %ax,0x24(%rsp)
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movl   $0x74736976,0x20(%rsp)
  movb   $0x0,0x26(%rsp)
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <longitud_string@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D22
type_guessed: string
name: read_data
arguments: label: D23
type_guessed: string
name: read_data
arguments: label: D2
type_guessed: byte[16]
name: read_data
arguments: label: D33
type_guessed: string

tool: D22: cadena: %s


tool: D23: longitud cadena: %d


tool: {"D2": [0x6c,0x65,0x65,0x72,0x20,0x6c,0x69,0x62,0x72,0x6f,0x73,0x20,0x79,0x20,0x72,0x65]}

tool: D33: cadena2: %s


assistant: ```c
int main(void) {
  char string1[] = "Hola a todos";
  char string2[200];
  char *ap_string1, *ap_string2;
  ap_string1 = &string1;
  ap_string2 = &string2;
  printf("cadena: %s\n", string1);
  printf("longitud cadena: %d\n", longitud_string(ap_string1));
  strcpy(string2, "leer libros y revistas");
  printf("cadena2: %s\n", string2);
  printf("longitud cadena: %d\n", longitud_string(ap_string2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L2
  mov    $0x0,%eax
  jmp    L16
L2:
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <tailFact@plt>
L16:
  leave
  ret
```

assistant: ```c
unsigned long long int fact(int n) {
  if (n < 0)
    return 0;
  else
    return tailFact(n, 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fact>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  jns    L8
  ret
L8:
  sub    $0x8,%rsp
  mov    $0x1,%esi
  call   <tailFact@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned long long int fact(int n) {
  if (n < 0)
    return 0;
  else
    return tailFact(n, 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fact>:
  endbr64
  test   %edi,%edi
  jns    L7
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%esi
  jmp    1050 <tailFact@plt>
```

assistant: ```c
unsigned long long int fact(int n) {
  if (n < 0)
    return 0;
  else
    return tailFact(n, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fact>:
  endbr64
  test   %edi,%edi
  jns    L8
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    $0x1,%esi
  jmp    1050 <tailFact@plt>
```

assistant: ```c
unsigned long long int fact(int n) {
  if (n < 0)
    return 0;
  else
    return tailFact(n, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mlMatrixLoadLookAt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mlVectorSubTo@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <mlVectorNormalTo@plt>
  mov    -0x40(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <mlMatrixLoadLook@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void mlMatrixLoadLookAt(float *a, const float *eye, const float *center, const float *up) {
  float tmp[3], forward[3];
  mlVectorSubTo(center, eye, tmp);
  mlVectorNormalTo(tmp, forward);
  mlMatrixLoadLook(a, eye, forward, up);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mlMatrixLoadLookAt>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%rdi
  mov    %rcx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r14,%rdx
  call   <mlVectorSubTo@plt>
  lea    0xc(%rsp),%r13
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <mlVectorNormalTo@plt>
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <mlMatrixLoadLook@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mlMatrixLoadLookAt(float *a, const float *eye, const float *center, const float *up) {
  float tmp[3], forward[3];
  mlVectorSubTo(center, eye, tmp);
  mlVectorNormalTo(tmp, forward);
  mlMatrixLoadLook(a, eye, forward, up);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mlMatrixLoadLookAt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0xc(%rsp),%r14
  mov    %r15,%rdx
  call   <mlVectorSubTo@plt>
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <mlVectorNormalTo@plt>
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mlMatrixLoadLook@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mlMatrixLoadLookAt(float *a, const float *eye, const float *center, const float *up) {
  float tmp[3], forward[3];
  mlVectorSubTo(center, eye, tmp);
  mlVectorNormalTo(tmp, forward);
  mlMatrixLoadLook(a, eye, forward, up);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mlMatrixLoadLookAt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r15
  lea    0xc(%rsp),%r14
  mov    %r15,%rdx
  call   <mlVectorSubTo@plt>
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <mlVectorNormalTo@plt>
  mov    %r13,%rcx
  mov    %r14,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <mlMatrixLoadLook@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void mlMatrixLoadLookAt(float *a, const float *eye, const float *center, const float *up) {
  float tmp[3], forward[3];
  mlVectorSubTo(center, eye, tmp);
  mlVectorNormalTo(tmp, forward);
  mlMatrixLoadLook(a, eye, forward, up);
}
```