ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<log_sense_param_is_valid>:
  endbr64
  mov    %rdi,%rax
  xor    %r8d,%r8d
  cmp    %rdi,%rdx
  jb     L5
  push   %rbp
  mov    %rdx,%rdi
  sub    %rax,%rdx
  mov    %esi,%ebp
  push   %rbx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sub    $0x8,%rsp
  cmp    %esi,%eax
  ja     L3
  lea    0x4(%rax),%ebx
  cmp    %esi,%ebx
  ja     L3
  call   <log_sense_param_len@plt>
  xor    %r8d,%r8d
  add    %ebx,%eax
  cmp    %ebp,%eax
  setbe  %r8b
L3:
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L5:
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool log_sense_param_is_valid(uint8_t *data, unsigned data_len, uint8_t *param) {
  if (param < data)
    return false;
  const unsigned param_offset = param - data;
  if (param_offset > data_len)
    return false;
  if (param_offset + 4 > data_len)
    return false;
  if (param_offset + 4 + log_sense_param_len(param) > data_len)
    return false;
  return true;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jg     L24
  mov    $0x1,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L24:
  mov    -0x10(%rbp),%eax
  cmp    $0x3,%eax
  jne    L41
  mov    $0x2,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L41:
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  jne    L37
  mov    $0x4,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%r8d
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x2,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L83
L37:
  mov    -0x10(%rbp),%eax
  cmp    $0x4,%eax
  jle    L83
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L82
L8:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L82:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L8
  movl   $0x2,-0xc(%rbp)
  jmp    L47
L53:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x2,-0xc(%rbp)
L47:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L53
L83:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L117
  call   <__stack_chk_fail@plt>
L117:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D70
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D37
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D17: %d

tool: D70: %d


tool: D37: %d %d


tool: D8: %d %d %d %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n <= 2) {
    printf("%d\n", 1);
    printf("%d\n", 1);
  } else if (n == 3) {
    printf("%d\n", 2);
    printf("%d %d\n", 1, 3);
  } else if (n == 4) {
    printf("%d\n", 4);
    printf("%d %d %d %d\n", 2, 4, 1, 3);
  } else if (n >= 5) {
    printf("%d\n", n);
    int i;
    for (i = 1; i <= n; i += 2) {
      printf("%d\n", i);
    }
    for (i = 2; i <= n; i += 2) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L92
  cmp    $0x3,%esi
  je     L87
  cmp    $0x4,%esi
  je     L31
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L11
  mov    $0x1,%ebx
  lea    D54(%rip),%rbp
L3:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L3
L11:
  cmpl   $0x1,0x4(%rsp)
  jle    L89
  mov    $0x2,%ebx
  lea    D54(%rip),%rbp
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x2,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L10
  jmp    L89
L92:
  mov    $0x1,%esi
  lea    D54(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L89:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L87:
  mov    $0x2,%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L89
L31:
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%r8d
  mov    $0x1,%ecx
  mov    $0x4,%edx
  mov    $0x2,%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L89
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D37
data_type: string
name: parse_data
arguments: data_tag: D54
data_type: string
name: parse_data
arguments: data_tag: D50
data_type: string
name: parse_data
arguments: data_tag: D33
data_type: string

tool: D37: %d

tool: D54: %d


tool: D50: %d %d


tool: D33: %d %d %d %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n <= 2) {
    printf("%d\n", 1);
    printf("%d\n", 1);
  } else if (n == 3) {
    printf("%d\n", 2);
    printf("%d %d\n", 1, 3);
  } else if (n == 4) {
    printf("%d\n", 4);
    printf("%d %d %d %d\n", 2, 4, 1, 3);
  } else if (n >= 5) {
    printf("%d\n", n);
    int i;
    for (i = 1; i <= n; i += 2) {
      printf("%d\n", i);
    }
    for (i = 2; i <= n; i += 2) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L31
  cmp    $0x3,%esi
  je     L59
  cmp    $0x4,%esi
  je     L34
  lea    D39(%rip),%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L96
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L72:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L72
L96:
  cmpl   $0x1,0x4(%rsp)
  jle    L35
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L104:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L104
L35:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L31:
  lea    D39(%rip),%rbp
  mov    $0x1,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L35
L34:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%r8d
  mov    $0x1,%ecx
  xor    %eax,%eax
  mov    $0x4,%edx
  mov    $0x2,%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L59:
  mov    $0x2,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L35
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D39
type_infered: string
name: parse_data
arguments: tag: D34
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string

tool: D11: %d

tool: D39: %d


tool: D34: %d %d %d %d


tool: D29: %d %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n <= 2) {
    printf("%d\n", 1);
    printf("%d\n", 1);
  } else if (n == 3) {
    printf("%d\n", 2);
    printf("%d %d\n", 1, 3);
  } else if (n == 4) {
    printf("%d\n", 4);
    printf("%d %d %d %d\n", 2, 4, 1, 3);
  } else if (n >= 5) {
    printf("%d\n", n);
    int i;
    for (i = 1; i <= n; i += 2) {
      printf("%d\n", i);
    }
    for (i = 2; i <= n; i += 2) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D61(%rip),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  cmp    $0x2,%esi
  jle    L71
  cmp    $0x3,%esi
  je     L74
  cmp    $0x4,%esi
  je     L62
  lea    D26(%rip),%rbp
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L99
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L24
L99:
  cmpl   $0x1,0x4(%rsp)
  jle    L73
  mov    $0x2,%ebx
  nopl   0x0(%rax)
L31:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x2,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L31
L73:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L71:
  lea    D26(%rip),%rbp
  mov    $0x1,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L73
L62:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%r8d
  mov    $0x1,%ecx
  xor    %eax,%eax
  mov    $0x4,%edx
  mov    $0x2,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L73
L74:
  mov    $0x2,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x1,%esi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L73
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D61
type_guessed: string
name: parse_data
arguments: label: D26
type_guessed: string
name: parse_data
arguments: label: D24
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D61: %d

tool: D26: %d


tool: D24: %d %d %d %d


tool: D10: %d %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  if (n <= 2) {
    printf("%d\n", 1);
    printf("%d\n", 1);
  } else if (n == 3) {
    printf("%d\n", 2);
    printf("%d %d\n", 1, 3);
  } else if (n == 4) {
    printf("%d\n", 4);
    printf("%d %d %d %d\n", 2, 4, 1, 3);
  } else if (n >= 5) {
    printf("%d\n", n);
    int i;
    for (i = 1; i <= n; i += 2) {
      printf("%d\n", i);
    }
    for (i = 2; i <= n; i += 2) {
      printf("%d\n", i);
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<allowedOp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  cmpl   $0x41,-0x4(%rbp)
  je     L15
  cmpl   $0x44,-0x4(%rbp)
  jle    L46
  cmpl   $0x49,-0x4(%rbp)
  jle    L15
L46:
  cmpl   $0x42,-0x4(%rbp)
  jne    L41
L15:
  mov    $0x1,%eax
  jmp    L5
L41:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int allowedOp(int op) {
  assert(70 > 69 && 70 < 73);
  assert(72 > 69 && 72 < 73);
  assert(71 > 69 && 71 < 73);
  assert(73 == 69 + 4);
  return op == 65 || (op >= 69 && op <= 73) || op == 66;
}
```
user: Translate the below assembly code into C programming language:

```asm
<allowedOp>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  lea    -0x45(%rbx),%eax
  cmp    $0x4,%eax
  setbe  %al
  sub    $0x41,%ebx
  cmp    $0x1,%ebx
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
int allowedOp(int op) {
  assert(70 > 69 && 70 < 73);
  assert(72 > 69 && 72 < 73);
  assert(71 > 69 && 71 < 73);
  assert(73 == 69 + 4);
  return op == 65 || (op >= 69 && op <= 73) || op == 66;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<allowedOp>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  lea    -0x45(%rbx),%eax
  cmp    $0x4,%eax
  setbe  %al
  sub    $0x41,%ebx
  cmp    $0x1,%ebx
  pop    %rbx
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int allowedOp(int op) {
  assert(70 > 69 && 70 < 73);
  assert(72 > 69 && 72 < 73);
  assert(71 > 69 && 71 < 73);
  assert(73 == 69 + 4);
  return op == 65 || (op >= 69 && op <= 73) || op == 66;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<allowedOp>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  lea    -0x45(%rbx),%eax
  cmp    $0x4,%eax
  setbe  %al
  sub    $0x41,%ebx
  cmp    $0x1,%ebx
  pop    %rbx
  setbe  %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int allowedOp(int op) {
  assert(70 > 69 && 70 < 73);
  assert(72 > 69 && 72 < 73);
  assert(71 > 69 && 71 < 73);
  assert(73 == 69 + 4);
  return op == 65 || (op >= 69 && op <= 73) || op == 66;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x6a,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L39
L18:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jbe    L33
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jne    L62
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  sub    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L21
L62:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L21
L33:
  movzbl -0x9(%rbp),%eax
  cmp    %al,-0xa(%rbp)
  jbe    L9
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0x9(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%ecx
  movzbl -0xa(%rbp),%eax
  sub    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L21
L9:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L21:
  addb   $0x2,-0xa(%rbp)
L39:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L18
  movzbl -0x9(%rbp),%eax
  lea    -0x40(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] -= state[0UL];
          state[local1] = state[0UL] + state[local1];
        } else {
          state[0UL] = state[local1] + state[local1];
          state[local1] = state[0UL] + state[local1];
        }
      } else if (state[0UL] < local1) {
        state[0UL] = state[local1] + state[0UL];
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 845313252UL) - (unsigned char)36;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x6a(%rax),%edx
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L12
  mov    $0x0,%eax
L16:
  shl    $0x2,%edx
  add    $0x2,%eax
  cmp    %cl,%al
  jb     L16
L12:
  sub    $0x40,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] -= state[0UL];
          state[local1] = state[0UL] + state[local1];
        } else {
          state[0UL] = state[local1] + state[local1];
          state[local1] = state[0UL] + state[local1];
        }
      } else if (state[0UL] < local1) {
        state[0UL] = state[local1] + state[0UL];
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 845313252UL) - (unsigned char)36;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  lea    -0x6a(%rax),%edx
  test   %cl,%cl
  je     L14
  xor    %eax,%eax
  nopl   0x0(%rax)
L1:
  add    $0x2,%eax
  shl    $0x2,%edx
  cmp    %cl,%al
  jb     L1
L14:
  sub    $0x40,%edx
  mov    %dl,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 51238316UL) + (unsigned char)234;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] < local1) {
        if (state[0UL] == local1) {
          state[local1] -= state[0UL];
          state[local1] = state[0UL] + state[local1];
        } else {
          state[0UL] = state[local1] + state[local1];
          state[local1] = state[0UL] + state[local1];
        }
      } else if (state[0UL] < local1) {
        state[0UL] = state[local1] + state[0UL];
        state[local1] = state[0UL] - state[local1];
      } else {
        state[0UL] += state[0UL];
        state[0UL] += state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] + 845313252UL) - (unsigned char)36;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdz_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L18
L13:
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L13
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *rdz_strndup(char *s, size_t n) {
  char *r = calloc(n + 1, sizeof(char));
  for (size_t i = 0; i < n; i++)
    r[i] = s[i];
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdz_strndup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  call   <calloc@plt>
  test   %rbx,%rbx
  je     L11
  mov    $0x0,%edx
L12:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L12
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *rdz_strndup(char *s, size_t n) {
  char *r = calloc(n + 1, sizeof(char));
  for (size_t i = 0; i < n; i++)
    r[i] = s[i];
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rdz_strndup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  lea    0x1(%rsi),%rdi
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  test   %rbx,%rbx
  je     L8
  xor    %edx,%edx
  nopl   (%rax)
L15:
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L15
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *rdz_strndup(char *s, size_t n) {
  char *r = calloc(n + 1, sizeof(char));
  for (size_t i = 0; i < n; i++)
    r[i] = s[i];
  return r;
}
```
user: What is the c source code of the assembly code below?

```asm
<rdz_strndup>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x1(%rsi),%rdi
  mov    $0x1,%esi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r8
  test   %rbp,%rbp
  je     L100
  lea    0x1(%rbx),%rcx
  mov    %r8,%rdx
  lea    -0x1(%rbp),%rax
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L126
  cmp    $0x6,%rax
  jbe    L126
  mov    %rbp,%rdx
  cmp    $0xe,%rax
  jbe    L66
  and    $0xfffffffffffffff0,%rdx
  xor    %eax,%eax
  nop
L147:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L147
  mov    %rbp,%rax
  and    $0xfffffffffffffff0,%rax
  test   $0xf,%bpl
  je     L100
  mov    %rbp,%rdx
  sub    %rax,%rdx
  lea    -0x1(%rdx),%rcx
  cmp    $0x6,%rcx
  jbe    L53
L23:
  mov    (%rbx,%rax,1),%rcx
  mov    %rcx,(%r8,%rax,1)
  mov    %rdx,%rcx
  and    $0xfffffffffffffff8,%rcx
  add    %rcx,%rax
  cmp    %rcx,%rdx
  je     L100
L53:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  lea    0x1(%rax),%rdx
  cmp    %rdx,%rbp
  jbe    L100
  movzbl 0x1(%rbx,%rax,1),%edx
  mov    %dl,0x1(%r8,%rax,1)
  lea    0x2(%rax),%rdx
  cmp    %rdx,%rbp
  jbe    L100
  movzbl 0x2(%rbx,%rax,1),%edx
  mov    %dl,0x2(%r8,%rax,1)
  lea    0x3(%rax),%rdx
  cmp    %rdx,%rbp
  jbe    L100
  movzbl 0x3(%rbx,%rax,1),%edx
  mov    %dl,0x3(%r8,%rax,1)
  lea    0x4(%rax),%rdx
  cmp    %rdx,%rbp
  jbe    L100
  movzbl 0x4(%rbx,%rax,1),%edx
  mov    %dl,0x4(%r8,%rax,1)
  lea    0x5(%rax),%rdx
  cmp    %rdx,%rbp
  jbe    L100
  movzbl 0x5(%rbx,%rax,1),%edx
  mov    %dl,0x5(%r8,%rax,1)
  lea    0x6(%rax),%rdx
  cmp    %rdx,%rbp
  jbe    L100
  movzbl 0x6(%rbx,%rax,1),%edx
  mov    %dl,0x6(%r8,%rax,1)
L100:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nop
L126:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L27:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rax,%rbp
  jne    L27
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
L66:
  xor    %eax,%eax
  jmp    L23
```

assistant: ```c
char *rdz_strndup(char *s, size_t n) {
  char *r = calloc(n + 1, sizeof(char));
  for (size_t i = 0; i < n; i++)
    r[i] = s[i];
  return r;
}
```