ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<zstr_to_second>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x11(%rbp),%rsi
  lea    -0x12(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rsi,%r8
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L53
  cmp    $0x2,%eax
  je     L167
  jmp    L179
L53:
  movb   $0x73,-0x12(%rbp)
L167:
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  jns    L63
  mov    $0x0,%eax
  jmp    L99
L63:
  movzbl -0x12(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <ztolower@plt>
  cmp    $0x77,%eax
  je     L94
  cmp    $0x77,%eax
  jg     L134
  cmp    $0x6d,%eax
  je     L177
  cmp    $0x6d,%eax
  jg     L134
  cmp    $0x64,%eax
  je     L92
  cmp    $0x68,%eax
  je     L140
  jmp    L134
L94:
  mov    -0x10(%rbp),%rax
  imul   $0x93a80,%rax,%rax
  jmp    L99
L92:
  mov    -0x10(%rbp),%rax
  imul   $0x15180,%rax,%rax
  jmp    L99
L140:
  mov    -0x10(%rbp),%rax
  imul   $0xe10,%rax,%rax
  jmp    L99
L177:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  shl    $0x2,%rax
  jmp    L99
L134:
  mov    -0x10(%rbp),%rax
  jmp    L99
L179:
  mov    -0x30(%rbp),%rax
L99:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L162
  call   <__stack_chk_fail@plt>
L162:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type_guessed: string

tool: D8: %ld%c%c

assistant: ```c
long zstr_to_second(const char *s, long def) {
  char unit, junk;
  long intval;
  switch (sscanf(s, "%ld%c%c", &intval, &unit, &junk)) {
  case 1:
    unit = 's';
  case 2:
    if (intval < 0)
      return 0;
    switch (ztolower(unit)) {
    case 'w':
      return (intval * (7 * 24 * 3600));
    case 'd':
      return (intval * (24 * 3600));
    case 'h':
      return (intval * 3600);
    case 'm':
      return (intval * 60);
    case 's':
    default:
      return (intval);
    }
  }
  return def;
}
```
user: Translate the below assembly code into C programming language:

```asm
<zstr_to_second>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xf(%rsp),%r8
  lea    D9(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L100
  cmp    $0x2,%eax
  je     L53
L109:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %rbx,%rax
  add    $0x20,%rsp
  pop    %rbx
  ret
L100:
  movb   $0x73,0xe(%rsp)
L53:
  mov    $0x0,%ebx
  cmpq   $0x0,0x10(%rsp)
  js     L109
  movsbl 0xe(%rsp),%edi
  call   <ztolower@plt>
  cmp    $0x6d,%eax
  je     L0
  jg     L105
  cmp    $0x64,%eax
  je     L90
  cmp    $0x68,%eax
  jne    L93
  imul   $0xe10,0x10(%rsp),%rbx
  jmp    L109
L105:
  cmp    $0x77,%eax
  jne    L93
  imul   $0x93a80,0x10(%rsp),%rbx
  jmp    L109
L90:
  imul   $0x15180,0x10(%rsp),%rbx
  jmp    L109
L0:
  mov    0x10(%rsp),%rax
  mov    %rax,%rbx
  shl    $0x4,%rbx
  sub    %rax,%rbx
  shl    $0x2,%rbx
  jmp    L109
L93:
  mov    0x10(%rsp),%rbx
  jmp    L109
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: %ld%c%c

assistant: ```c
long zstr_to_second(const char *s, long def) {
  char unit, junk;
  long intval;
  switch (sscanf(s, "%ld%c%c", &intval, &unit, &junk)) {
  case 1:
    unit = 's';
  case 2:
    if (intval < 0)
      return 0;
    switch (ztolower(unit)) {
    case 'w':
      return (intval * (7 * 24 * 3600));
    case 'd':
      return (intval * (24 * 3600));
    case 'h':
      return (intval * 3600);
    case 'm':
      return (intval * 60);
    case 's':
    default:
      return (intval);
    }
  }
  return def;
}
```
user: What is the c source code of the assembly code below:

```asm
<zstr_to_second>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D2(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xf(%rsp),%r8
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L44
  cmp    $0x2,%eax
  jne    L35
L16:
  xor    %r12d,%r12d
  cmpq   $0x0,0x10(%rsp)
  js     L35
  movsbl 0xe(%rsp),%edi
  call   <ztolower@plt>
  cmp    $0x6d,%eax
  je     L112
  jg     L61
  cmp    $0x64,%eax
  je     L115
  cmp    $0x68,%eax
  jne    L74
  imul   $0xe10,0x10(%rsp),%r12
  nopl   0x0(%rax)
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  cmp    $0x77,%eax
  jne    L74
  imul   $0x93a80,0x10(%rsp),%r12
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L44:
  movb   $0x73,0xe(%rsp)
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L112:
  mov    0x10(%rsp),%rax
  mov    %rax,%r12
  shl    $0x4,%r12
  sub    %rax,%r12
  shl    $0x2,%r12
  jmp    L35
  nopl   (%rax)
L74:
  mov    0x10(%rsp),%r12
  jmp    L35
  nop
L115:
  imul   $0x15180,0x10(%rsp),%r12
  jmp    L35
L51:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: %ld%c%c

assistant: ```c
long zstr_to_second(const char *s, long def) {
  char unit, junk;
  long intval;
  switch (sscanf(s, "%ld%c%c", &intval, &unit, &junk)) {
  case 1:
    unit = 's';
  case 2:
    if (intval < 0)
      return 0;
    switch (ztolower(unit)) {
    case 'w':
      return (intval * (7 * 24 * 3600));
    case 'd':
      return (intval * (24 * 3600));
    case 'h':
      return (intval * 3600);
    case 'm':
      return (intval * 60);
    case 's':
    default:
      return (intval);
    }
  }
  return def;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zstr_to_second>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D7(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xf(%rsp),%r8
  call   <sscanf@plt>
  cmp    $0x1,%eax
  je     L114
  cmp    $0x2,%eax
  jne    L116
L10:
  xor    %r12d,%r12d
  cmpq   $0x0,0x10(%rsp)
  js     L116
  movsbl 0xe(%rsp),%edi
  call   <ztolower@plt>
  cmp    $0x6d,%eax
  je     L8
  jg     L134
  cmp    $0x64,%eax
  je     L39
  cmp    $0x68,%eax
  jne    L6
  imul   $0xe10,0x10(%rsp),%r12
  nopl   0x0(%rax)
L116:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x20,%rsp
  mov    %r12,%rax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L134:
  cmp    $0x77,%eax
  jne    L6
  imul   $0x93a80,0x10(%rsp),%r12
  jmp    L116
  nopl   0x0(%rax,%rax,1)
L114:
  movb   $0x73,0xe(%rsp)
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L8:
  mov    0x10(%rsp),%rax
  mov    %rax,%r12
  shl    $0x4,%r12
  sub    %rax,%r12
  shl    $0x2,%r12
  jmp    L116
  nopl   (%rax)
L6:
  mov    0x10(%rsp),%r12
  jmp    L116
  nop
L39:
  imul   $0x15180,0x10(%rsp),%r12
  jmp    L116
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string

tool: D7: %ld%c%c

assistant: ```c
long zstr_to_second(const char *s, long def) {
  char unit, junk;
  long intval;
  switch (sscanf(s, "%ld%c%c", &intval, &unit, &junk)) {
  case 1:
    unit = 's';
  case 2:
    if (intval < 0)
      return 0;
    switch (ztolower(unit)) {
    case 'w':
      return (intval * (7 * 24 * 3600));
    case 'd':
      return (intval * (24 * 3600));
    case 'h':
      return (intval * 3600);
    case 'm':
      return (intval * 60);
    case 's':
    default:
      return (intval);
    }
  }
  return def;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpyx2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L15
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L15:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  ja     L10
  mov    -0x24(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int memcpyx2(unsigned char *dst, unsigned char *src, unsigned int len) {
  int x, y;
  for (x = y = 0; (y < len);) {
    dst[y++] = src[x];
    dst[y++] = src[x++];
  }
  return (len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpyx2>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  je     L14
  lea    -0x1(%rdx),%edx
  shr    %edx
  lea    0x1(%rdx),%r9d
  mov    $0x0,%ecx
L10:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rdi,%rcx,2)
  mov    %r8b,0x1(%rdi,%rcx,2)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L10
L14:
  ret
```

assistant: ```c
unsigned int memcpyx2(unsigned char *dst, unsigned char *src, unsigned int len) {
  int x, y;
  for (x = y = 0; (y < len);) {
    dst[y++] = src[x];
    dst[y++] = src[x++];
  }
  return (len);
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpyx2>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  je     L4
  lea    -0x1(%rdx),%edx
  xor    %ecx,%ecx
  shr    %edx
  lea    0x1(%rdx),%r9d
  nopl   (%rax)
L6:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rdi,%rcx,2)
  mov    %r8b,0x1(%rdi,%rcx,2)
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L6
L4:
  ret
```

assistant: ```c
unsigned int memcpyx2(unsigned char *dst, unsigned char *src, unsigned int len) {
  int x, y;
  for (x = y = 0; (y < len);) {
    dst[y++] = src[x];
    dst[y++] = src[x++];
  }
  return (len);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fn1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fn1(int a, int b) {
  int tem1 = a | b;
  int tem2 = a & b;
  return tem1 - tem2;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fn1>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
int fn1(int a, int b) {
  int tem1 = a | b;
  int tem2 = a & b;
  return tem1 - tem2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fn1>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
int fn1(int a, int b) {
  int tem1 = a | b;
  int tem2 = a & b;
  return tem1 - tem2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fn1>:
  endbr64
  mov    %edi,%eax
  xor    %esi,%eax
  ret
```

assistant: ```c
int fn1(int a, int b) {
  int tem1 = a | b;
  int tem2 = a & b;
  return tem1 - tem2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__bail>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L3
  mov    $0x0,%eax
  call   <abort@plt>
L3:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int __bail(int for_realz) {
  if (for_realz) {
    abort();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__bail>:
  endbr64
  test   %edi,%edi
  jne    L5
  mov    $0x0,%eax
  ret
L5:
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <abort@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __bail(int for_realz) {
  if (for_realz) {
    abort();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__bail>:
  endbr64
  test   %edi,%edi
  jne    L3
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __bail(int for_realz) {
  if (for_realz) {
    abort();
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__bail>:
  endbr64
  test   %edi,%edi
  jne    L7
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <abort@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __bail(int for_realz) {
  if (for_realz) {
    abort();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fscore>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x360,%rsp
  mov    %edi,-0x354(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x340(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jne    L31
  movl   $0x0,-0x348(%rbp)
  jmp    L13
L10:
  mov    -0x348(%rbp),%eax
  cltq
  movzbl -0x14(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x348(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x14(%rbp,%rdx,1)
  addl   $0x1,-0x348(%rbp)
L13:
  cmpl   $0x3,-0x348(%rbp)
  jle    L10
  mov    -0x354(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x354(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <inscriptionScore@plt>
  lea    -0x340(%rbp),%rdx
  lea    -0x1b0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lectureScore@plt>
  mov    %eax,-0x344(%rbp)
  mov    -0x344(%rbp),%edx
  lea    -0x340(%rbp),%rcx
  lea    -0x1b0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <triScore@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type: string
name: read_data
arguments: data_label: D7
type: string

tool: D1: Votre Pseudo (3 caracteres): 

tool: D7: 

Votre score est: %d



assistant: ```c
void fscore(int scorePlayer) {
  int score[100] = {0}, maxi, i;
  char name[12];
  char pseudo[100][4];
  printf("Votre Pseudo (3 caracteres): ");
  do {
    gets(name);
  } while (strlen(name) != 3);
  for (i = 0; i < 4; i++) {
    name[i] = toupper(name[i]);
  }
  printf("\n\nVotre score est: %d\n\n", scorePlayer);
  inscriptionScore(name, scorePlayer);
  maxi = lectureScore(pseudo, score);
  triScore(pseudo, score, maxi);
}
```
user: What is the c source code of the assembly code below?

```asm
<fscore>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x32,%ecx
  rep stos %rax,%es:(%rdi)
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    0x32c(%rsp),%rbx
L26:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jne    L26
  lea    0x32c(%rsp),%rbx
  lea    0x330(%rsp),%r12
L29:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L29
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x32c(%rsp),%rdi
  mov    %ebp,%esi
  call   <inscriptionScore@plt>
  mov    %rsp,%rbp
  lea    0x190(%rsp),%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <lectureScore@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <triScore@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x340,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D0
type: string
name: parse_data
arguments: label: D5
type: string

tool: D0: Votre Pseudo (3 caracteres): 

tool: D5: 

Votre score est: %d



assistant: ```c
void fscore(int scorePlayer) {
  int score[100] = {0}, maxi, i;
  char name[12];
  char pseudo[100][4];
  printf("Votre Pseudo (3 caracteres): ");
  do {
    gets(name);
  } while (strlen(name) != 3);
  for (i = 0; i < 4; i++) {
    name[i] = toupper(name[i]);
  }
  printf("\n\nVotre score est: %d\n\n", scorePlayer);
  inscriptionScore(name, scorePlayer);
  maxi = lectureScore(pseudo, score);
  triScore(pseudo, score, maxi);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fscore>:
  endbr64
  push   %r14
  mov    $0x32,%ecx
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x32c(%rsp),%rbp
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D17(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jne    L14
  mov    %rbp,%rbx
  lea    0x330(%rsp),%r14
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %r14,%rbx
  jne    L19
  mov    %r13d,%esi
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r13d,%esi
  lea    0x190(%rsp),%rbp
  call   <inscriptionScore@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lectureScore@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <triScore@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x340,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D17
data_type: string
name: read_data
arguments: label: D15
data_type: string

tool: D17: Votre Pseudo (3 caracteres): 

tool: D15: 

Votre score est: %d



assistant: ```c
void fscore(int scorePlayer) {
  int score[100] = {0}, maxi, i;
  char name[12];
  char pseudo[100][4];
  printf("Votre Pseudo (3 caracteres): ");
  do {
    gets(name);
  } while (strlen(name) != 3);
  for (i = 0; i < 4; i++) {
    name[i] = toupper(name[i]);
  }
  printf("\n\nVotre score est: %d\n\n", scorePlayer);
  inscriptionScore(name, scorePlayer);
  maxi = lectureScore(pseudo, score);
  triScore(pseudo, score, maxi);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fscore>:
  endbr64
  push   %r14
  mov    $0x32,%ecx
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x340,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x338(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x32c(%rsp),%rbp
  mov    %r12,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D3(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x3,%eax
  jne    L1
  mov    %rbp,%rbx
  lea    0x330(%rsp),%r14
L12:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  cmp    %r14,%rbx
  jne    L12
  mov    %r13d,%esi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    %r13d,%esi
  lea    0x190(%rsp),%rbp
  call   <inscriptionScore@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <lectureScore@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <triScore@plt>
  mov    0x338(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x340,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D3: Votre Pseudo (3 caracteres): 

tool: D9: 

Votre score est: %d



assistant: ```c
void fscore(int scorePlayer) {
  int score[100] = {0}, maxi, i;
  char name[12];
  char pseudo[100][4];
  printf("Votre Pseudo (3 caracteres): ");
  do {
    gets(name);
  } while (strlen(name) != 3);
  for (i = 0; i < 4; i++) {
    name[i] = toupper(name[i]);
  }
  printf("\n\nVotre score est: %d\n\n", scorePlayer);
  inscriptionScore(name, scorePlayer);
  maxi = lectureScore(pseudo, score);
  triScore(pseudo, score, maxi);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_read_frame_extended>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L1
L40:
  mov    -0x1c(%rbp),%eax
  sub    $0x3fff0,%eax
  mov    %eax,%eax
  movzbl (%rax),%edx
  mov    -0x1c(%rbp),%eax
  cltq
  mov    %dl,-0x15(%rbp,%rax,1)
  addl   $0x1,-0x1c(%rbp)
L1:
  cmpl   $0xc,-0x1c(%rbp)
  jle    L40
  movl   $0x0,-0x1c(%rbp)
  jmp    L12
L55:
  mov    -0x1c(%rbp),%eax
  cltq
  movzbl -0x15(%rbp,%rax,1),%edx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L35
  mov    $0x0,%eax
  jmp    L53
L35:
  addl   $0x1,-0x1c(%rbp)
L12:
  cmpl   $0xc,-0x1c(%rbp)
  jle    L55
  mov    $0x1,%eax
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

assistant: ```c
int test_read_frame_extended(unsigned char write_field[]) {
  unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((unsigned char *)(0xfffc0000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_read_frame_extended>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0xfffc0010,%eax
  movabs $0xffffffff0003fff0,%rdx
  lea    0xb(%rsp,%rdx,1),%rsi
  mov    $0xfffc001d,%ecx
L26:
  movzbl (%rax),%edx
  mov    %dl,(%rax,%rsi,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L26
  mov    $0x0,%eax
L22:
  movzbl (%rdi,%rax,1),%ecx
  cmp    %cl,0xb(%rsp,%rax,1)
  jne    L15
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L22
  mov    $0x1,%eax
L44:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x28,%rsp
  ret
L15:
  mov    $0x0,%eax
  jmp    L44
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_read_frame_extended(unsigned char write_field[]) {
  unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((unsigned char *)(0xfffc0000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_read_frame_extended>:
  endbr64
  sub    $0x28,%rsp
  mov    $0xfffc001d,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  mov    $0xfffc0010,%eax
  lea    0xb(%rsp),%r8
  mov    %r8,%rsi
  sub    %rax,%rsi
  nopl   0x0(%rax,%rax,1)
L46:
  movzbl (%rax),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax,%rsi,1)
  cmp    %rcx,%rax
  jne    L46
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl (%rdi,%rax,1),%ecx
  cmp    %cl,(%r8,%rax,1)
  jne    L25
  add    $0x1,%rax
  cmp    $0xd,%rax
  jne    L19
  mov    $0x1,%eax
L40:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L29
  add    $0x28,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  jmp    L40
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_read_frame_extended(unsigned char write_field[]) {
  unsigned char read_field[13];
  int i = 0;
  for (i = 0; i < 13; i++) {
    read_field[i] = *((unsigned char *)(0xfffc0000 + 0x0010 + i));
  }
  for (i = 0; i < 13; i++) {
    if (read_field[i] != write_field[i]) {
      return 0;
    }
  }
  return 1;
}
```