ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<TiempoUno>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %r8,0x8(%rsp)
  mov    %r9,0x10(%rsp)
  movsd  %xmm0,(%rsp)
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rax
  movsd  (%rsp),%xmm1
  mov    %r15d,%r9d
  xor    %r8d,%r8d
  mov    0x10(%rsp),%rdx
  mov    0x60(%rsp),%rcx
  sub    $0x8,%rsp
  mov    %r13,%rdi
  movsd  (%rax,%rbx,1),%xmm0
  lea    D7(%rip),%rsi
  mulsd  %xmm1,%xmm0
  addsd  0x0(%rbp,%rbx,1),%xmm0
  movsd  %xmm0,0x8(%rbp,%rbx,1)
  movsd  (%rdx,%rbx,1),%xmm0
  mov    %r12,%rdx
  mulsd  %xmm1,%xmm0
  addsd  (%r12,%rbx,1),%xmm0
  movsd  %xmm0,0x8(%r12,%rbx,1)
  movsd  (%rcx,%rbx,1),%xmm0
  mov    %r14,%rcx
  mulsd  %xmm1,%xmm0
  addsd  (%r14,%rbx,1),%xmm0
  movsd  %xmm0,0x8(%r14,%rbx,1)
  movsd  (%rax,%rbx,1),%xmm2
  movsd  %xmm2,0x20(%rsp)
  push   %rsi
  mov    %rbp,%rsi
  call   <Accel@plt>
  mov    0x18(%rsp),%rax
  mov    %r15d,%r9d
  xor    %r8d,%r8d
  mulsd  0x10(%rsp),%xmm0
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  addsd  0x28(%rsp),%xmm0
  mov    0x20(%rsp),%rdx
  movsd  %xmm0,0x8(%rax,%rbx,1)
  movsd  (%rdx,%rbx,1),%xmm3
  mov    %r12,%rdx
  lea    D6(%rip),%rax
  mov    %rax,(%rsp)
  movsd  %xmm3,0x28(%rsp)
  call   <Accel@plt>
  mov    0x20(%rsp),%rdx
  mov    %r15d,%r9d
  xor    %r8d,%r8d
  mulsd  0x10(%rsp),%xmm0
  mov    %r14,%rcx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  addsd  0x28(%rsp),%xmm0
  mov    0x70(%rsp),%rax
  add    $0x1,%r15d
  movsd  %xmm0,0x8(%rdx,%rbx,1)
  movsd  (%rax,%rbx,1),%xmm4
  mov    %r12,%rdx
  lea    D0(%rip),%rax
  mov    %rax,(%rsp)
  movsd  %xmm4,0x28(%rsp)
  call   <Accel@plt>
  mulsd  0x10(%rsp),%xmm0
  mov    0x70(%rsp),%rax
  addsd  0x28(%rsp),%xmm0
  movsd  %xmm0,0x8(%rax,%rbx,1)
  add    $0x13880,%rbx
  pop    %rax
  pop    %rdx
  cmp    $0xa,%r15d
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D7: x

tool: D6: y

tool: D0: z

assistant: ```c
void TiempoUno(double *masas, double *posX, double *posY, double *posZ, double *velX, double *velY, double *velZ, double dt) {
  for (int i = 0; i < 10; i++) {
    posX[i * 10000 + 1] = posX[i * 10000 + 0] + dt * velX[i * 10000 + 0];
    posY[i * 10000 + 1] = posY[i * 10000 + 0] + dt * velY[i * 10000 + 0];
    posZ[i * 10000 + 1] = posZ[i * 10000 + 0] + dt * velZ[i * 10000 + 0];
    velX[i * 10000 + 1] = velX[i * 10000 + 0] + dt * Accel(masas, posX, posY, posZ, 0, i, "x");
    velY[i * 10000 + 1] = velY[i * 10000 + 0] + dt * Accel(masas, posX, posY, posZ, 0, i, "y");
    velZ[i * 10000 + 1] = velZ[i * 10000 + 0] + dt * Accel(masas, posX, posY, posZ, 0, i, "z");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    D26(%rip),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <link@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D26
datatype: string

tool: D17: /sandbox/input.txt

tool: D26: /tmp/output.txt

assistant: ```c
int main() {
  struct stat st_old;
  struct stat st_new;
  assert(0 == stat("/sandbox/input.txt", &st_old));
  assert(0 == link("/sandbox/input.txt", "/tmp/output.txt"));
  assert(0 == stat("/tmp/output.txt", &st_new));
  assert(st_old.st_ino == st_new.st_ino);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    D18(%rip),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <link@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x10(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D1
type: string
name: unpack_data
arguments: label: D18
type: string

tool: D1: /sandbox/input.txt

tool: D18: /tmp/output.txt

assistant: ```c
int main() {
  struct stat st_old;
  struct stat st_new;
  assert(0 == stat("/sandbox/input.txt", &st_old));
  assert(0 == link("/sandbox/input.txt", "/tmp/output.txt"));
  assert(0 == stat("/tmp/output.txt", &st_new));
  assert(st_old.st_ino == st_new.st_ino);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D12(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <stat@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <link@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  mov    0x10(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D12
type_infered: string

tool: D7: /sandbox/input.txt

tool: D12: /tmp/output.txt

assistant: ```c
int main() {
  struct stat st_old;
  struct stat st_new;
  assert(0 == stat("/sandbox/input.txt", &st_old));
  assert(0 == link("/sandbox/input.txt", "/tmp/output.txt"));
  assert(0 == stat("/tmp/output.txt", &st_new));
  assert(st_old.st_ino == st_new.st_ino);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D2(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <stat@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <link@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <stat@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  mov    0x10(%rsp),%rax
  cmp    %rax,0x8(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D2
type: string

tool: D12: /sandbox/input.txt

tool: D2: /tmp/output.txt

assistant: ```c
int main() {
  struct stat st_old;
  struct stat st_new;
  assert(0 == stat("/sandbox/input.txt", &st_old));
  assert(0 == link("/sandbox/input.txt", "/tmp/output.txt"));
  assert(0 == stat("/tmp/output.txt", &st_new));
  assert(st_old.st_ino == st_new.st_ino);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<x11_get_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <xcb_get_setup@plt>
  mov    %eax,%edi
  call   <xcb_setup_roots_iterator@plt>
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L3
L37:
  cmpl   $0x0,-0x2c(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rax
  jmp    L7
L15:
  subl   $0x1,-0x2c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <xcb_screen_next@plt>
L3:
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L37
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

assistant: ```c
xcb_screen_t *x11_get_screen(xcb_connection_t *xc, int screen) {
  xcb_screen_iterator_t iter;
  iter = xcb_setup_roots_iterator(xcb_get_setup(xc));
  for (; iter.rem; screen--, xcb_screen_next(&iter)) {
    if (screen == 0) {
      return iter.data;
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<x11_get_screen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <xcb_get_setup@plt>
  mov    %eax,%edi
  call   <xcb_setup_roots_iterator@plt>
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  cmpq   $0x0,0x8(%rsp)
  je     L67
  test   %ebx,%ebx
  je     L53
  mov    %rsp,%rbp
L18:
  sub    $0x1,%ebx
  mov    %rbp,%rdi
  call   <xcb_screen_next@plt>
  cmpq   $0x0,0x8(%rsp)
  je     L28
  test   %ebx,%ebx
  jne    L18
L53:
  mov    (%rsp),%rax
L43:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    $0x0,%eax
  jmp    L43
L67:
  mov    $0x0,%eax
  jmp    L43
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
xcb_screen_t *x11_get_screen(xcb_connection_t *xc, int screen) {
  xcb_screen_iterator_t iter;
  iter = xcb_setup_roots_iterator(xcb_get_setup(xc));
  for (; iter.rem; screen--, xcb_screen_next(&iter)) {
    if (screen == 0) {
      return iter.data;
    }
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<x11_get_screen>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <xcb_get_setup@plt>
  mov    %eax,%edi
  call   <xcb_setup_roots_iterator@plt>
  mov    %rdx,0x8(%rsp)
  cmpq   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  je     L33
  test   %ebx,%ebx
  je     L3
  mov    %rsp,%rbp
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L0:
  test   %ebx,%ebx
  je     L3
L64:
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <xcb_screen_next@plt>
  cmpq   $0x0,0x8(%rsp)
  jne    L0
L33:
  xor    %eax,%eax
L53:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    (%rsp),%rax
  jmp    L53
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
xcb_screen_t *x11_get_screen(xcb_connection_t *xc, int screen) {
  xcb_screen_iterator_t iter;
  iter = xcb_setup_roots_iterator(xcb_get_setup(xc));
  for (; iter.rem; screen--, xcb_screen_next(&iter)) {
    if (screen == 0) {
      return iter.data;
    }
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<x11_get_screen>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <xcb_get_setup@plt>
  mov    %eax,%edi
  call   <xcb_setup_roots_iterator@plt>
  mov    %rdx,0x8(%rsp)
  cmpq   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
  je     L46
  test   %ebx,%ebx
  je     L41
  mov    %rsp,%rbp
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L39:
  test   %ebx,%ebx
  je     L41
L47:
  mov    %rbp,%rdi
  sub    $0x1,%ebx
  call   <xcb_screen_next@plt>
  cmpq   $0x0,0x8(%rsp)
  jne    L39
L46:
  xor    %eax,%eax
L42:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L41:
  mov    (%rsp),%rax
  jmp    L42
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
xcb_screen_t *x11_get_screen(xcb_connection_t *xc, int screen) {
  xcb_screen_iterator_t iter;
  iter = xcb_setup_roots_iterator(xcb_get_setup(xc));
  for (; iter.rem; screen--, xcb_screen_next(&iter)) {
    if (screen == 0) {
      return iter.data;
    }
  }
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L69
L36:
  nop
L68:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    (%rbx),%rax
  test   %rax,%rax
  je     L18
  addl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L68
L18:
  mov    -0x1c(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jne    L65
  mov    -0x18(%rbp),%rax
  jmp    L69
L3:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
L65:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L3
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L69:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void *matalloc(int rows, int row_size) {
  void **mat;
  int i = 0;
  if (!(mat = malloc(rows * sizeof(void *))))
    return 0;
  while ((mat[i] = malloc(row_size)) && ++i < rows)
    ;
  if (i == rows)
    return (void *)mat;
  while (--i >= 0)
    free(mat[i]);
  free(mat);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<matalloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r13d
  mov    %esi,%r14d
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %rax,%rbp
  mov    $0x0,%ebx
L40:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L2
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r13d
  jg     L40
L2:
  cmp    %r13d,%ebx
  je     L7
  sub    $0x1,%ebx
  js     L22
  movslq %ebx,%rbx
L45:
  mov    (%r12,%rbx,8),%rdi
  call   <free@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L45
L22:
  mov    %r12,%rdi
  call   <free@plt>
  mov    $0x0,%r12d
L7:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *matalloc(int rows, int row_size) {
  void **mat;
  int i = 0;
  if (!(mat = malloc(rows * sizeof(void *))))
    return 0;
  while ((mat[i] = malloc(row_size)) && ++i < rows)
    ;
  if (i == rows)
    return (void *)mat;
  while (--i >= 0)
    free(mat[i]);
  free(mat);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matalloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  shl    $0x3,%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L86
  mov    %rax,%rbx
  xor    %r14d,%r14d
  jmp    L32
  nopl   0x0(%rax)
L74:
  lea    0x1(%r14),%eax
  add    $0x8,%rbx
  cmp    %eax,%ebp
  jle    L36
  movslq %eax,%r14
L32:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L74
  cmp    %ebp,%r14d
  je     L86
  sub    $0x1,%r14d
  jb     L41
  movslq %r14d,%r14
  mov    0x0(%r13,%r14,8),%rdi
L72:
  lea    0x0(%r13,%r14,8),%rbx
  lea    -0x8(%r13),%rbp
  jmp    L25
L83:
  mov    (%rbx),%rdi
L25:
  call   <free@plt>
  sub    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L83
L41:
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <free@plt>
L86:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  jne    L72
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *matalloc(int rows, int row_size) {
  void **mat;
  int i = 0;
  if (!(mat = malloc(rows * sizeof(void *))))
    return 0;
  while ((mat[i] = malloc(row_size)) && ++i < rows)
    ;
  if (i == rows)
    return (void *)mat;
  while (--i >= 0)
    free(mat[i]);
  free(mat);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<matalloc>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  shl    $0x3,%edi
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L35
  mov    %rax,%rbx
  xor    %r14d,%r14d
  jmp    L52
  nopl   0x0(%rax)
L51:
  lea    0x1(%r14),%eax
  add    $0x8,%rbx
  cmp    %eax,%ebp
  jle    L39
  mov    %eax,%r14d
L52:
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L51
  cmp    %ebp,%r14d
  je     L35
  sub    $0x1,%r14d
  jb     L70
L75:
  movslq %r14d,%r14
  lea    -0x8(%r13),%rbp
  lea    0x0(%r13,%r14,8),%rbx
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    (%rbx),%rdi
  sub    $0x8,%rbx
  call   <free@plt>
  cmp    %rbp,%rbx
  jne    L16
L70:
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <free@plt>
L35:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  jne    L75
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void *matalloc(int rows, int row_size) {
  void **mat;
  int i = 0;
  if (!(mat = malloc(rows * sizeof(void *))))
    return 0;
  while ((mat[i] = malloc(row_size)) && ++i < rows)
    ;
  if (i == rows)
    return (void *)mat;
  while (--i >= 0)
    free(mat[i]);
  free(mat);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x3c(%rbp)
  jle    L74
  mov    $0x0,%r15d
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  lea    D1(%rip),%r13
  jmp    L49
L133:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L95
  orq    $0x0,-0x8(%rsp,%rdx,1)
L95:
  mov    %rsp,%r14
  lea    0xf(%rcx),%rax
  mov    $0x10,%ecx
  mov    $0x0,%edx
  div    %rcx
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L33:
  cmp    %rdx,%rsp
  je     L90
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L33
L90:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L60
  orq    $0x0,-0x8(%rsp,%rdx,1)
L60:
  mov    %rsp,-0x50(%rbp)
  test   %esi,%esi
  jle    L25
  mov    %r14,%r12
  mov    $0x0,%ebx
L53:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x40(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L53
  test   %esi,%esi
  jle    L25
  mov    -0x50(%rbp),%r12
  mov    $0x0,%ebx
L58:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x40(%rbp),%esi
  add    $0x4,%r12
  cmp    %ebx,%esi
  jg     L58
L25:
  mov    %r14,%rdi
  call   <sort@plt>
  mov    -0x40(%rbp),%esi
  mov    -0x50(%rbp),%rbx
  mov    %rbx,%rdi
  call   <sort@plt>
  mov    -0x40(%rbp),%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <sum@plt>
  mov    -0x48(%rbp),%rsp
  add    $0x1,%r15d
  cmp    %r15d,-0x3c(%rbp)
  jle    L74
L49:
  mov    %rsp,-0x48(%rbp)
  mov    -0x58(%rbp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    -0x40(%rbp),%esi
  movslq %esi,%rcx
  shl    $0x2,%rcx
  lea    0xf(%rcx),%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  shl    $0x4,%rax
  mov    %rax,%rdi
  and    $0xfffffffffffff000,%rdi
  mov    %rsp,%rdx
  sub    %rdi,%rdx
L75:
  cmp    %rdx,%rsp
  je     L133
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L75
L74:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d

assistant: ```c
int main() {
  int n, t, i, j;
  scanf("%d", &t);
  for (i = 0; i < t; i++) {
    scanf("%d", &n);
    int a[n], b[n];
    for (j = 0; j < n; j++) {
      scanf("%d", &a[j]);
    }
    for (j = 0; j < n; j++) {
      scanf("%d", &b[j]);
    }
    sort(a, n);
    sort(b, n);
    sum(a, b, n);
  }
  return 0;
}
```