user: 这段汇编代码用C语言表示是什么样的?

```asm
<exppart>:
  endbr64
  push   %rbp
  mov    %rsi,%r10
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  movslq %r8d,%r14
  push   %r13
  shl    $0x3,%r14
  mov    %rdx,%r13
  mov    %rcx,%rdx
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xf(%r14),%rax
  mov    %rsp,%rsi
  mov    %rax,%r9
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%r9
  and    $0xfffffffffffffff0,%rcx
  sub    %r9,%rsi
  cmp    %rsi,%rsp
  je     L251
L90:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L90
L251:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L176
L76:
  mov    %rax,%rsi
  mov    %rsp,%r9
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%r9
  and    $0xfffffffffffffff0,%rsi
  cmp    %r9,%rsp
  je     L222
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %r9,%rsp
  jne    L28
L222:
  and    $0xfff,%esi
  sub    %rsi,%rsp
  test   %rsi,%rsi
  jne    L175
L264:
  mov    %rsp,%rbx
  test   %r8d,%r8d
  jle    L81
  cmp    $0x1,%r8d
  je     L44
  mov    %r8d,%esi
  xor    %eax,%eax
  shr    %esi
  shl    $0x4,%rsi
  xchg   %ax,%ax
L66:
  movupd (%rdi,%rax,1),%xmm0
  movupd (%rdx,%rax,1),%xmm6
  subpd  %xmm6,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rsi
  jne    L66
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%r8b
  je     L115
L170:
  cltq
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
L115:
  mov    %r8d,%eax
  mov    %r8d,%r12d
  movsd  D5(%rip),%xmm4
  xor    %esi,%esi
  lea    (%rbx,%rax,8),%r15
  mov    %r8d,%eax
  and    $0xfffffffe,%r12d
  mov    %rbx,%r11
  shr    %eax
  mov    %r12d,-0x44(%rbp)
  mov    %r10,%rdi
  pxor   %xmm0,%xmm0
  lea    -0x1(%rax),%r9d
  add    $0x1,%r9
  shl    $0x4,%r9
  nop
L56:
  cmp    $0x1,%r8d
  je     L163
  xor    %eax,%eax
  movapd %xmm0,%xmm2
L27:
  movupd (%rdi,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm5
  add    $0x10,%rax
  mulpd  %xmm5,%xmm1
  addsd  %xmm1,%xmm2
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  cmp    %r9,%rax
  jne    L27
  movslq %r12d,%rax
  cmp    %r8d,%r12d
  je     L130
L54:
  lea    (%rsi,%rax,1),%edx
  movslq %edx,%rdx
  movsd  (%r10,%rdx,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  addsd  %xmm1,%xmm2
L130:
  mulsd  %xmm4,%xmm2
  add    $0x8,%r11
  add    %r8d,%esi
  add    %r14,%rdi
  movsd  %xmm2,-0x8(%r11)
  cmp    %r11,%r15
  jne    L56
  xor    %eax,%eax
  cmp    $0x1,%r8d
  je     L259
  nopl   0x0(%rax)
L125:
  movupd (%rbx,%rax,1),%xmm7
  movupd 0x0(%r13,%rax,1),%xmm1
  addpd  %xmm7,%xmm1
  movups %xmm1,(%rbx,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%r9
  jne    L125
  cmp    %r8d,%r12d
  je     L23
  movslq %r12d,%rax
L259:
  movsd  0x0(%r13,%rax,8),%xmm1
  addsd  (%rbx,%rax,8),%xmm1
  movsd  %xmm1,(%rbx,%rax,8)
  cmp    $0x1,%r8d
  je     L32
L23:
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L172:
  movupd (%rbx,%rax,1),%xmm1
  movupd (%rcx,%rax,1),%xmm4
  add    $0x10,%rax
  mulpd  %xmm4,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%r9
  jne    L172
  cmp    %r8d,%r12d
  jne    L122
  jmp    L7
L176:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L76
  nopl   (%rax)
L32:
  movl   $0x0,-0x44(%rbp)
L122:
  movslq -0x44(%rbp),%rax
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  (%rcx,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
L7:
  mulsd  D7(%rip),%xmm0
L80:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L163:
  movapd %xmm0,%xmm2
  xor    %eax,%eax
  jmp    L54
L81:
  pxor   %xmm0,%xmm0
  jmp    L80
L44:
  xor    %eax,%eax
  jmp    L170
L175:
  orq    $0x0,-0x8(%rsp,%rsi,1)
  jmp    L264
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: f32[2]
name: retrieve_data
arguments: tag: D7
type_infered: byte[8]

tool: {"D5": [0.0,1.75]}

tool: {"D7": [0x18,0x2d,0x44,0x54,0xfb,0x21,0x19,0x40]}

assistant: ```c
double exppart(double *n, double *X, double *x, double *intshift, int g) {
  double tmp1[g];
  double tmp2[g];
  int i, j;
  for (i = 0; i < g; i++)
    tmp1[i] = n[i] - intshift[i];
  double sum;
  for (i = 0; i < g; i++) {
    sum = 0;
    for (j = 0; j < g; j++)
      sum += X[i * g + j] * tmp1[j];
    tmp2[i] = sum / 2.0;
  }
  for (i = 0; i < g; i++)
    tmp2[i] = tmp2[i] + x[i];
  double dot = 0;
  for (i = 0; i < g; i++)
    dot += tmp1[i] * tmp2[i];
  return 2 * 3.14159265358979323846 * dot;
}
```