user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x4847464544434241,%rax
  movabs $0x504f4e4d4c4b4a49,%rdx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movabs $0x5857565554535251,%rax
  mov    %rax,-0x50(%rbp)
  movw   $0x5a59,-0x48(%rbp)
  movb   $0x0,-0x46(%rbp)
  movl   $0x0,-0x6c(%rbp)
  movl   $0x0,-0x68(%rbp)
  lea    -0x84(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x7c(%rbp)
  jmp    L6
L1:
  lea    -0x80(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x6c(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L38
L78:
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x64(%rbp)
  movl   $0x0,-0x70(%rbp)
  movl   $0x0,-0x74(%rbp)
  jmp    L48
L90:
  movl   $0x0,-0x68(%rbp)
  jmp    L71
L83:
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%eax
  cltq
  lea    (%rdx,%rax,1),%rcx
  lea    -0x40(%rbp),%rdx
  mov    -0x74(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L33
  mov    -0x70(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  mov    -0x74(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  mov    -0x78(%rbp),%eax
  add    %eax,-0x6c(%rbp)
  movl   $0x1,-0x68(%rbp)
  movl   $0x0,-0x70(%rbp)
  jmp    L71
L33:
  addl   $0x1,-0x70(%rbp)
L71:
  cmpl   $0x1,-0x68(%rbp)
  jne    L83
  addl   $0x1,-0x74(%rbp)
L48:
  mov    -0x74(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L90
  addl   $0x1,-0x78(%rbp)
L38:
  mov    -0x80(%rbp),%eax
  cmp    %eax,-0x78(%rbp)
  jl     L78
  mov    -0x6c(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x7c(%rbp)
L6:
  mov    -0x84(%rbp),%eax
  cmp    %eax,-0x7c(%rbp)
  jle    L1
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D16
data_type: string
name: disassemble_data
arguments: label: D17
data_type: string
name: disassemble_data
arguments: label: D21
data_type: string

tool: D16: %d

tool: D17: %s

tool: D21: %d


assistant: ```c
int main() {
  char Alfa[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ", String0[51];
  int Cont, N, NLin, Cont2, Lim, Cont3, Cont4, Som = 0, Cond = 0;
  scanf("%d", &N);
  for (Cont = 1; Cont <= N; Cont++) {
    scanf("%d", &NLin);
    Som = 0;
    for (Cont2 = 0; Cont2 < NLin; Cont2++) {
      scanf("%s", String0);
      Lim = strlen(String0) - 1;
      Cont4 = 0;
      for (Cont3 = 0; Cont3 <= Lim; Cont3++) {
        Cond = 0;
        while (Cond != 1) {
          if (strncmp(&String0[Cont3], &Alfa[Cont4], 1) == 0) {
            Som = Som + Cont4;
            Som = Som + Cont3;
            Som = Som + Cont2;
            Cond = 1;
            Cont4 = 0;
          } else
            Cont4++;
        }
      }
    }
    printf("%d\n", Som);
  }
  return 0;
}
```