ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<array_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L10:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __attribute__((always_)) array_clear(double *peel, int elemc) {
  int i;
  for (i = 0; i < elemc; i++) {
    peel[i] = 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<array_clear>:
  endbr64
  test   %esi,%esi
  jle    L1
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L15:
  movq   $0x0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L15
L1:
  ret
```

assistant: ```c
void __attribute__((always_)) array_clear(double *peel, int elemc) {
  int i;
  for (i = 0; i < elemc; i++) {
    peel[i] = 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<array_clear>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void __attribute__((always_)) array_clear(double *peel, int elemc) {
  int i;
  for (i = 0; i < elemc; i++) {
    peel[i] = 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<array_clear>:
  endbr64
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  lea    0x0(,%rsi,8),%rdx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void __attribute__((always_)) array_clear(double *peel, int elemc) {
  int i;
  for (i = 0; i < elemc; i++) {
    peel[i] = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<use_proto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  call   <proto@plt>
  mov    D6(%rip),%rax
  movq   %rax,%xmm0
  call   <proto@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: f64

tool: D6: 42.1

assistant: ```c
void use_proto() {
  proto(42.1);
  (&proto)(42.1);
}
```
user: What is the c source code of the assembly code below:

```asm
<use_proto>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  call   <proto@plt>
  mov    D7(%rip),%rax
  movq   %rax,%xmm0
  call   <proto@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: f64

tool: D7: 42.1

assistant: ```c
void use_proto() {
  proto(42.1);
  (&proto)(42.1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<use_proto>:
  endbr64
  sub    $0x8,%rsp
  movsd  D4(%rip),%xmm0
  call   <proto@plt>
  mov    D4(%rip),%rax
  add    $0x8,%rsp
  movq   %rax,%xmm0
  jmp    1050 <proto@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: f64

tool: D4: 42.1

assistant: ```c
void use_proto() {
  proto(42.1);
  (&proto)(42.1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<use_proto>:
  endbr64
  sub    $0x8,%rsp
  movsd  D14(%rip),%xmm0
  call   <proto@plt>
  mov    D14(%rip),%rax
  add    $0x8,%rsp
  movq   %rax,%xmm0
  jmp    1050 <proto@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_guessed: f64

tool: D14: 42.1

assistant: ```c
void use_proto() {
  proto(42.1);
  (&proto)(42.1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gotcha_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x8(%rbp)
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D10
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string

tool: D1: 1234567890!a@s#d$f%s^h&j*k(l);

tool: D10: printing a string:

tool: D21: 1234567890!a@s#d$f%s^h&j*k(l)

assistant: ```c
void gotcha_printf(void) {
  char *format = "1234567890!a@s#d$f%s^h&j*k(l);";
  printf("printing a string:\n");
  printf("%s\n", format);
  printf("1234567890!a@s#d$f%s^h&j*k(l)");
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<gotcha_printf>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rdi
  call   <puts@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D14
type_guessed: string

tool: D20: printing a string:

tool: D4: 1234567890!a@s#d$f%s^h&j*k(l);

tool: D14: 1234567890!a@s#d$f%s^h&j*k(l)

assistant: ```c
void gotcha_printf(void) {
  char *format = "1234567890!a@s#d$f%s^h&j*k(l);";
  printf("printing a string:\n");
  printf("%s\n", format);
  printf("1234567890!a@s#d$f%s^h&j*k(l)");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gotcha_printf>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D10(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
type_infered: string
name: extract_symbolic_data
arguments: label: D10
type_infered: string
name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D17: printing a string:

tool: D10: 1234567890!a@s#d$f%s^h&j*k(l);

tool: D8: 1234567890!a@s#d$f%s^h&j*k(l)

assistant: ```c
void gotcha_printf(void) {
  char *format = "1234567890!a@s#d$f%s^h&j*k(l);";
  printf("printing a string:\n");
  printf("%s\n", format);
  printf("1234567890!a@s#d$f%s^h&j*k(l)");
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gotcha_printf>:
  endbr64
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  add    $0x8,%rsp
  jmp    1070 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D29
datatype: string
name: retrieve_data
arguments: label: D3
datatype: string

tool: D16: printing a string:

tool: D29: 1234567890!a@s#d$f%s^h&j*k(l);

tool: D3: 1234567890!a@s#d$f%s^h&j*k(l)

assistant: ```c
void gotcha_printf(void) {
  char *format = "1234567890!a@s#d$f%s^h&j*k(l);";
  printf("printing a string:\n");
  printf("%s\n", format);
  printf("1234567890!a@s#d$f%s^h&j*k(l)");
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: xstrdup failed


assistant: ```c
char *xstrdup(const char *s) {
  char *p = strdup(s);
  if (!p)
    die("xstrdup failed\n");
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
L10:
  mov    %rbx,%rax
  pop    %rbx
  ret
L6:
  lea    D4(%rip),%rdi
  call   <die@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: xstrdup failed


assistant: ```c
char *xstrdup(const char *s) {
  char *p = strdup(s);
  if (!p)
    die("xstrdup failed\n");
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L18:
  mov    %r12,%rax
  pop    %r12
  ret
L14:
  lea    D2(%rip),%rdi
  call   <die@plt>
  jmp    L18
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: xstrdup failed


assistant: ```c
char *xstrdup(const char *s) {
  char *p = strdup(s);
  if (!p)
    die("xstrdup failed\n");
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L3:
  mov    %r12,%rax
  pop    %r12
  ret
L2:
  lea    D4(%rip),%rdi
  call   <die@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D4: xstrdup failed


assistant: ```c
char *xstrdup(const char *s) {
  char *p = strdup(s);
  if (!p)
    die("xstrdup failed\n");
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<binbuf_doopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x400,%rsp
  mov    %rdi,-0x3f8(%rbp)
  mov    %esi,-0x3fc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sys_bashfilename@plt>
  mov    -0x3fc(%rbp),%edx
  lea    -0x3f0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int binbuf_doopen(char *s, int mode) {
  char namebuf[1000];
  sys_bashfilename(s, namebuf);
  return (open(namebuf, mode));
}
```
user: What is the c source code of the assembly code below:

```asm
<binbuf_doopen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %esi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <sys_bashfilename@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <open@plt>
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binbuf_doopen(char *s, int mode) {
  char namebuf[1000];
  sys_bashfilename(s, namebuf);
  return (open(namebuf, mode));
}
```
user: What is the c source code of the assembly code below:

```asm
<binbuf_doopen>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <sys_bashfilename@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <open@plt>
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x3f8,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binbuf_doopen(char *s, int mode) {
  char namebuf[1000];
  sys_bashfilename(s, namebuf);
  return (open(namebuf, mode));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<binbuf_doopen>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <sys_bashfilename@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <open@plt>
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x3f8,%rsp
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int binbuf_doopen(char *s, int mode) {
  char namebuf[1000];
  sys_bashfilename(s, namebuf);
  return (open(namebuf, mode));
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<convert_filename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L65
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L51
L65:
  mov    -0x48(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L57
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L51
L57:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L23
L32:
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addq   $0x1,-0x20(%rbp)
L23:
  mov    -0x48(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  jmp    L58
L33:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    (%rax,%rdx,1),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L58:
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L51:
  leave
  ret
```

assistant: ```c
char *convert_filename(char *name, char *src, char *dst) {
  size_t src_len = strlen(src);
  size_t dst_len = strlen(dst);
  size_t name_len = strlen(name) - src_len + dst_len;
  char *real_name = NULL;
  size_t i = 0;
  if (name_len < 1) {
    return strdup(name);
  }
  if (!strcmp(src, dst)) {
    return strdup(name);
  }
  real_name = malloc(name_len + 1);
  while (dst[i]) {
    real_name[i] = dst[i];
    i++;
  }
  while (name[src_len]) {
    real_name[i++] = name[src_len++];
  }
  real_name[i--] = 0;
  return real_name;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convert_filename>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    (%rax,%r14,1),%rdi
  sub    %rbp,%rdi
  je     L96
  mov    %rdi,%r14
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L38
  lea    0x1(%r14),%rdi
  call   <malloc@plt>
  movzbl (%r12),%ecx
  test   %cl,%cl
  je     L16
  mov    $0x0,%edx
L83:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%r12,%rdx,1),%ecx
  test   %cl,%cl
  jne    L83
L1:
  movzbl (%rbx,%rbp,1),%esi
  test   %sil,%sil
  je     L6
  mov    %rdx,%rcx
  sub    %rdx,%rbp
  add    %rbp,%rbx
L53:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rax,%rcx,1)
  movzbl (%rbx,%rcx,1),%esi
  test   %sil,%sil
  jne    L53
L56:
  movb   $0x0,(%rax,%rcx,1)
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L96:
  mov    %rbx,%rdi
  call   <strdup@plt>
  jmp    L24
L38:
  mov    %rbx,%rdi
  call   <strdup@plt>
  jmp    L24
L16:
  mov    $0x0,%edx
  jmp    L1
L6:
  mov    %rdx,%rcx
  jmp    L56
```

assistant: ```c
char *convert_filename(char *name, char *src, char *dst) {
  size_t src_len = strlen(src);
  size_t dst_len = strlen(dst);
  size_t name_len = strlen(name) - src_len + dst_len;
  char *real_name = NULL;
  size_t i = 0;
  if (name_len < 1) {
    return strdup(name);
  }
  if (!strcmp(src, dst)) {
    return strdup(name);
  }
  real_name = malloc(name_len + 1);
  while (dst[i]) {
    real_name[i] = dst[i];
    i++;
  }
  while (name[src_len]) {
    real_name[i++] = name[src_len++];
  }
  real_name[i--] = 0;
  return real_name;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<convert_filename>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    (%rax,%r13,1),%rdi
  sub    %rbx,%rdi
  je     L53
  mov    %rdi,%r13
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L53
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  movzbl (%r12),%ecx
  test   %cl,%cl
  je     L61
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%r12,%rdx,1),%ecx
  test   %cl,%cl
  jne    L33
  lea    (%rax,%rdx,1),%rsi
L1:
  movzbl 0x0(%rbp,%rbx,1),%ecx
  test   %cl,%cl
  je     L26
  sub    %rdx,%rbx
  add    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L21:
  add    $0x1,%rdx
  mov    %cl,-0x1(%rax,%rdx,1)
  movzbl 0x0(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L21
  lea    (%rax,%rdx,1),%rsi
L26:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L53:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax,%rax,1)
L61:
  mov    %rax,%rsi
  xor    %edx,%edx
  jmp    L1
```

assistant: ```c
char *convert_filename(char *name, char *src, char *dst) {
  size_t src_len = strlen(src);
  size_t dst_len = strlen(dst);
  size_t name_len = strlen(name) - src_len + dst_len;
  char *real_name = NULL;
  size_t i = 0;
  if (name_len < 1) {
    return strdup(name);
  }
  if (!strcmp(src, dst)) {
    return strdup(name);
  }
  real_name = malloc(name_len + 1);
  while (dst[i]) {
    real_name[i] = dst[i];
    i++;
  }
  while (name[src_len]) {
    real_name[i++] = name[src_len++];
  }
  real_name[i--] = 0;
  return real_name;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<convert_filename>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r13
  call   <strlen@plt>
  lea    (%rax,%r13,1),%rdi
  sub    %rbx,%rdi
  je     L39
  mov    %rdi,%r13
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L39
  lea    0x1(%r13),%rdi
  call   <malloc@plt>
  movzbl (%r12),%ecx
  test   %cl,%cl
  je     L47
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L66:
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  movzbl (%r12,%rdx,1),%ecx
  test   %cl,%cl
  jne    L66
  lea    (%rax,%rdx,1),%rsi
L45:
  movzbl 0x0(%rbp,%rbx,1),%ecx
  test   %cl,%cl
  je     L49
  sub    %rdx,%rbx
  add    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rdx
  mov    %cl,-0x1(%rax,%rdx,1)
  movzbl 0x0(%rbp,%rdx,1),%ecx
  test   %cl,%cl
  jne    L31
  lea    (%rax,%rdx,1),%rsi
L49:
  movb   $0x0,(%rsi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L39:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <strdup@plt>
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %rax,%rsi
  xor    %edx,%edx
  jmp    L45
```

assistant: ```c
char *convert_filename(char *name, char *src, char *dst) {
  size_t src_len = strlen(src);
  size_t dst_len = strlen(dst);
  size_t name_len = strlen(name) - src_len + dst_len;
  char *real_name = NULL;
  size_t i = 0;
  if (name_len < 1) {
    return strdup(name);
  }
  if (!strcmp(src, dst)) {
    return strdup(name);
  }
  real_name = malloc(name_len + 1);
  while (dst[i]) {
    real_name[i] = dst[i];
    i++;
  }
  while (name[src_len]) {
    real_name[i++] = name[src_len++];
  }
  real_name[i--] = 0;
  return real_name;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fltrep_widen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x17,%eax
  and    $0xff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x80000000,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L9
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  jmp    L6
L9:
  cmpl   $0xff,-0x8(%rbp)
  jne    L33
  mov    -0x4(%rbp),%eax
  or     $0x7ff00000,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  jmp    L6
L33:
  mov    -0x8(%rbp),%eax
  add    $0x380,%eax
  shl    $0x14,%eax
  or     -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shr    $0x3,%eax
  and    $0xfffff,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  shl    $0x1d,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %edx,(%rax)
L6:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fltrep_widen(e, d) int e[1];
int d[2];
{
  unsigned int e0 = e[0];
  int x = (e0 >> 23) & 0xff;
  int s = e0 & 0x80000000;
  if (x == 0)
    d[0] = s, d[1] = 0;
  else if (x == 0xff)
    d[0] = s | 0x7ff00000, d[1] = 0;
  else
    d[0] = s | ((x - 0x7f + 0x3ff) << 20) | ((e0 & 0x7fffff) >> 3), d[1] = e0 << 29;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fltrep_widen>:
  endbr64
  mov    (%rdi),%ecx
  mov    %ecx,%eax
  shr    $0x17,%eax
  mov    %ecx,%edx
  and    $0x80000000,%edx
  and    $0xff,%eax
  je     L12
  cmp    $0xff,%eax
  je     L17
  mov    %ecx,%edi
  shr    $0x3,%edi
  and    $0xfffff,%edi
  or     %edi,%edx
  add    $0x380,%eax
  shl    $0x14,%eax
  or     %eax,%edx
  mov    %ecx,%eax
  shl    $0x1d,%eax
L12:
  mov    %edx,(%rsi)
  mov    %eax,0x4(%rsi)
  ret
L17:
  or     $0x7ff00000,%edx
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
void fltrep_widen(e, d) int e[1];
int d[2];
{
  unsigned int e0 = e[0];
  int x = (e0 >> 23) & 0xff;
  int s = e0 & 0x80000000;
  if (x == 0)
    d[0] = s, d[1] = 0;
  else if (x == 0xff)
    d[0] = s | 0x7ff00000, d[1] = 0;
  else
    d[0] = s | ((x - 0x7f + 0x3ff) << 20) | ((e0 & 0x7fffff) >> 3), d[1] = e0 << 29;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fltrep_widen>:
  endbr64
  mov    (%rdi),%ecx
  mov    %ecx,%eax
  mov    %ecx,%edx
  shr    $0x17,%eax
  and    $0x80000000,%edx
  and    $0xff,%eax
  je     L15
  cmp    $0xff,%eax
  je     L17
  mov    %ecx,%edi
  add    $0x380,%eax
  shr    $0x3,%edi
  shl    $0x14,%eax
  and    $0xfffff,%edi
  or     %edi,%edx
  or     %eax,%edx
  mov    %ecx,%eax
  shl    $0x1d,%eax
L15:
  mov    %edx,(%rsi)
  mov    %eax,0x4(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  or     $0x7ff00000,%edx
  xor    %eax,%eax
  mov    %edx,(%rsi)
  mov    %eax,0x4(%rsi)
  ret
```

assistant: ```c
void fltrep_widen(e, d) int e[1];
int d[2];
{
  unsigned int e0 = e[0];
  int x = (e0 >> 23) & 0xff;
  int s = e0 & 0x80000000;
  if (x == 0)
    d[0] = s, d[1] = 0;
  else if (x == 0xff)
    d[0] = s | 0x7ff00000, d[1] = 0;
  else
    d[0] = s | ((x - 0x7f + 0x3ff) << 20) | ((e0 & 0x7fffff) >> 3), d[1] = e0 << 29;
}
```