ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<get_uri_reference>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <object_lock@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct uri *get_uri_reference(struct uri *uri) {
  object_lock(uri);
  return uri;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_uri_reference>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <object_lock@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct uri *get_uri_reference(struct uri *uri) {
  object_lock(uri);
  return uri;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xb(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movzbl -0xb(%rbp),%eax
  cmp    $0x4b,%al
  je     L20
  movzbl -0xb(%rbp),%eax
  cmp    $0x51,%al
  je     L20
  movzbl -0xb(%rbp),%eax
  cmp    $0x4a,%al
  jne    L65
L20:
  movl   $0xa,-0x10(%rbp)
  jmp    L10
L65:
  movzbl -0xb(%rbp),%eax
  cmp    $0x41,%al
  jne    L22
  movl   $0xb,-0x10(%rbp)
  jmp    L10
L22:
  lea    -0xb(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D19
data_type: string
name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D20
data_type: string

tool: D19: input car name:

tool: D15: %2s

tool: D20: card number: %i


assistant: ```c
int main() {
  char card_name[3];
  puts("input car name:");
  scanf("%2s", card_name);
  int val = 0;
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
  }
  printf("card number: %i\n", val);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x5(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x5(%rsp),%edx
  lea    -0x4a(%rdx),%eax
  cmp    $0x1,%al
  jbe    L11
  cmp    $0x51,%dl
  jne    L43
L11:
  mov    $0xa,%esi
L0:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L43:
  mov    $0xb,%esi
  cmp    $0x41,%dl
  je     L0
  lea    0x5(%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  jmp    L0
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D1
type_guessed: string
name: unpack_data
arguments: data_label: D23
type_guessed: string

tool: D4: input car name:

tool: D1: %2s

tool: D23: card number: %i


assistant: ```c
int main() {
  char card_name[3];
  puts("input car name:");
  scanf("%2s", card_name);
  int val = 0;
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
  }
  printf("card number: %i\n", val);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x5(%rsp),%edx
  lea    -0x4a(%rdx),%eax
  cmp    $0x1,%al
  jbe    L44
  cmp    $0x51,%dl
  jne    L31
L44:
  mov    $0xa,%esi
L38:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L31:
  mov    $0xb,%esi
  cmp    $0x41,%dl
  je     L38
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  jmp    L38
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
type_guessed: string
name: parse_data
arguments: data_label: D27
type_guessed: string
name: parse_data
arguments: data_label: D13
type_guessed: string

tool: D11: input car name:

tool: D27: %2s

tool: D13: card number: %i


assistant: ```c
int main() {
  char card_name[3];
  puts("input car name:");
  scanf("%2s", card_name);
  int val = 0;
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
  }
  printf("card number: %i\n", val);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x5(%rsp),%rbp
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x5(%rsp),%edx
  lea    -0x4a(%rdx),%eax
  cmp    $0x1,%al
  jbe    L35
  cmp    $0x51,%dl
  jne    L49
L35:
  mov    $0xa,%esi
L36:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L49:
  mov    $0xb,%esi
  cmp    $0x41,%dl
  je     L36
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  jmp    L36
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D24
type_infered: string
name: retrieve_data
arguments: data_tag: D14
type_infered: string

tool: D29: input car name:

tool: D24: %2s

tool: D14: card number: %i


assistant: ```c
int main() {
  char card_name[3];
  puts("input car name:");
  scanf("%2s", card_name);
  int val = 0;
  if (card_name[0] == 'K' || card_name[0] == 'Q' || card_name[0] == 'J') {
    val = 10;
  } else if (card_name[0] == 'A') {
    val = 11;
  } else {
    val = atoi(card_name);
  }
  printf("card number: %i\n", val);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<se>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x30(%rbp),%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  lea    (%rdx,%rax,1),%ecx
  lea    -0x18(%rbp),%rdx
  mov    -0x2c(%rbp),%esi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ParseGolombCode@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0xffffffff,-0x10(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L7
L25:
  mov    -0x38(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%eax
  sar    %eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L27
  negl   -0x14(%rbp)
L27:
  mov    -0x14(%rbp),%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int se(const unsigned char *code, int bits_offset, int total_bits, int *code_bits) {
  int len, info;
  int n, val;
  *code_bits = 0;
  len = ParseGolombCode(code, bits_offset, &info, (total_bits >> 3) + ((total_bits & 0x7) ? 1 : 0));
  if (len == -1)
    return 0;
  *code_bits = len;
  n = (1 << (len >> 1)) + info - 1;
  val = (n + 1) >> 1;
  if ((n & 0x01) == 0)
    val = -val;
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<se>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rcx)
  test   $0x7,%dl
  setne  %cl
  movzbl %cl,%ecx
  sar    $0x3,%edx
  add    %edx,%ecx
  lea    0x4(%rsp),%rdx
  call   <ParseGolombCode@plt>
  mov    $0x0,%edx
  cmp    $0xffffffff,%eax
  je     L9
  mov    %eax,%ecx
  mov    %eax,(%rbx)
  sar    %ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  add    0x4(%rsp),%eax
  mov    %eax,%edx
  sar    %edx
  mov    %edx,%ecx
  neg    %ecx
  test   $0x1,%al
  cmovne %ecx,%edx
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int se(const unsigned char *code, int bits_offset, int total_bits, int *code_bits) {
  int len, info;
  int n, val;
  *code_bits = 0;
  len = ParseGolombCode(code, bits_offset, &info, (total_bits >> 3) + ((total_bits & 0x7) ? 1 : 0));
  if (len == -1)
    return 0;
  *code_bits = len;
  n = (1 << (len >> 1)) + info - 1;
  val = (n + 1) >> 1;
  if ((n & 0x01) == 0)
    val = -val;
  return val;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<se>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rcx)
  xor    %ecx,%ecx
  test   $0x7,%dl
  setne  %cl
  sar    $0x3,%edx
  add    %edx,%ecx
  lea    0x4(%rsp),%rdx
  call   <ParseGolombCode@plt>
  xor    %r8d,%r8d
  cmp    $0xffffffff,%eax
  je     L17
  mov    %eax,%ecx
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  sar    %ecx
  shl    %cl,%eax
  add    0x4(%rsp),%eax
  mov    %eax,%r8d
  sar    %r8d
  mov    %r8d,%edx
  neg    %edx
  test   $0x1,%al
  cmovne %edx,%r8d
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int se(const unsigned char *code, int bits_offset, int total_bits, int *code_bits) {
  int len, info;
  int n, val;
  *code_bits = 0;
  len = ParseGolombCode(code, bits_offset, &info, (total_bits >> 3) + ((total_bits & 0x7) ? 1 : 0));
  if (len == -1)
    return 0;
  *code_bits = len;
  n = (1 << (len >> 1)) + info - 1;
  val = (n + 1) >> 1;
  if ((n & 0x01) == 0)
    val = -val;
  return val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<se>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rcx)
  xor    %ecx,%ecx
  test   $0x7,%dl
  setne  %cl
  sar    $0x3,%edx
  add    %edx,%ecx
  lea    0x4(%rsp),%rdx
  call   <ParseGolombCode@plt>
  xor    %r8d,%r8d
  cmp    $0xffffffff,%eax
  je     L10
  mov    %eax,%ecx
  mov    %eax,(%rbx)
  mov    $0x1,%eax
  sar    %ecx
  shl    %cl,%eax
  add    0x4(%rsp),%eax
  mov    %eax,%r8d
  sar    %r8d
  mov    %r8d,%edx
  neg    %edx
  test   $0x1,%al
  cmovne %edx,%r8d
L10:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  mov    %r8d,%eax
  pop    %rbx
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int se(const unsigned char *code, int bits_offset, int total_bits, int *code_bits) {
  int len, info;
  int n, val;
  *code_bits = 0;
  len = ParseGolombCode(code, bits_offset, &info, (total_bits >> 3) + ((total_bits & 0x7) ? 1 : 0));
  if (len == -1)
    return 0;
  *code_bits = len;
  n = (1 << (len >> 1)) + info - 1;
  val = (n + 1) >> 1;
  if ((n & 0x01) == 0)
    val = -val;
  return val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_16_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  or     -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  notl   -0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  not    %eax
  or     -0x10(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0xc(%rbp),%eax
  and    -0x14(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_16_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_16_0_1>:
  endbr64
  movzbl %dil,%edi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %eax,%edi
  movzbl %sil,%edx
  mov    %edx,%esi
  shl    $0x8,%esi
  or     %edx,%esi
  or     $0xff,%al
  not    %eax
  mov    %edi,%edx
  and    %esi,%edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_16_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_16_0_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%edx
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %eax,%edi
  or     %edx,%esi
  or     $0xff,%al
  mov    %edi,%edx
  not    %edi
  not    %eax
  and    %esi,%edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_16_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_16_0_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%edx
  mov    %edi,%eax
  mov    %edx,%esi
  shl    $0x8,%eax
  shl    $0x8,%esi
  or     %eax,%edi
  or     %edx,%esi
  or     $0xff,%al
  mov    %edi,%edx
  not    %edi
  not    %eax
  and    %esi,%edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_16_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D | S;
  stk2 = ~stk2;
  stk1 = T & stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sys_set_audio_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L13
  mov    $0x0,%eax
  call   <audio_isopen@plt>
  test   %rax,%rax
  jne    L33
  mov    $0x0,%eax
  call   <sys_reopen_audio@plt>
  jmp    L33
L13:
  mov    $0x0,%eax
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L33
  mov    $0x0,%eax
  call   <sys_close_audio@plt>
L33:
  nop
  leave
  ret
```

assistant: ```c
void sys_set_audio_state(int onoff) {
  if (onoff) {
    if (!audio_isopen())
      sys_reopen_audio();
  } else {
    if (audio_isopen())
      sys_close_audio();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sys_set_audio_state>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L35
  mov    $0x0,%eax
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L34
L28:
  add    $0x8,%rsp
  ret
L34:
  call   <sys_reopen_audio@plt>
  jmp    L28
L35:
  mov    $0x0,%eax
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L28
  mov    $0x0,%eax
  call   <sys_close_audio@plt>
  jmp    L28
```

assistant: ```c
void sys_set_audio_state(int onoff) {
  if (onoff) {
    if (!audio_isopen())
      sys_reopen_audio();
  } else {
    if (audio_isopen())
      sys_close_audio();
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sys_set_audio_state>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  test   %edi,%edi
  je     L23
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L22
L24:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L23:
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L24
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sys_close_audio@plt>
  nopl   (%rax)
L22:
  add    $0x8,%rsp
  jmp    1080 <sys_reopen_audio@plt>
```

assistant: ```c
void sys_set_audio_state(int onoff) {
  if (onoff) {
    if (!audio_isopen())
      sys_reopen_audio();
  } else {
    if (audio_isopen())
      sys_close_audio();
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sys_set_audio_state>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  test   %edi,%edi
  je     L8
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L11
L3:
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L8:
  call   <audio_isopen@plt>
  test   %rax,%rax
  je     L3
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <sys_close_audio@plt>
  nopl   (%rax)
L11:
  add    $0x8,%rsp
  jmp    1080 <sys_reopen_audio@plt>
```

assistant: ```c
void sys_set_audio_state(int onoff) {
  if (onoff) {
    if (!audio_isopen())
      sys_reopen_audio();
  } else {
    if (audio_isopen())
      sys_close_audio();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bbob2009_reshape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L7
L29:
  movq   $0x0,-0x8(%rbp)
  jmp    L14
L21:
  mov    -0x8(%rbp),%rax
  imul   -0x28(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L21
  addq   $0x1,-0x10(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L29
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
double **bbob2009_reshape(double **B, double *vector, size_t m, size_t n) {
  size_t i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      B[i][j] = vector[j * m + i];
    }
  }
  return B;
}
```
user: What is the c source code of the assembly code below?

```asm
<bbob2009_reshape>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdx,%rdx
  je     L30
  mov    %rdi,%r9
  lea    0x0(,%rdx,8),%r10
  mov    $0x0,%r11d
  jmp    L39
L6:
  movsd  (%rdi),%xmm0
  mov    (%r9),%r8
  movsd  %xmm0,(%r8,%rax,8)
  add    $0x1,%rax
  add    %r10,%rdi
  cmp    %rax,%rcx
  jne    L6
L36:
  add    $0x1,%r11
  add    $0x8,%rsi
  add    $0x8,%r9
  cmp    %r11,%rdx
  je     L30
L39:
  mov    %rsi,%rdi
  mov    $0x0,%eax
  test   %rcx,%rcx
  jne    L6
  jmp    L36
L30:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
double **bbob2009_reshape(double **B, double *vector, size_t m, size_t n) {
  size_t i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      B[i][j] = vector[j * m + i];
    }
  }
  return B;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bbob2009_reshape>:
  endbr64
  mov    %rdi,%r11
  test   %rdx,%rdx
  je     L19
  push   %rbx
  lea    0x0(,%rdx,8),%r9
  xor    %r10d,%r10d
  lea    0x0(,%rcx,8),%rbx
L29:
  test   %rcx,%rcx
  je     L8
  mov    (%r11,%r10,8),%rax
  mov    %rsi,%rdi
  lea    (%rax,%rbx,1),%r8
L32:
  movsd  (%rdi),%xmm0
  add    $0x8,%rax
  add    %r9,%rdi
  movsd  %xmm0,-0x8(%rax)
  cmp    %r8,%rax
  jne    L32
L8:
  add    $0x1,%r10
  add    $0x8,%rsi
  cmp    %r10,%rdx
  jne    L29
  mov    %r11,%rax
  pop    %rbx
  ret
L19:
  mov    %rdi,%rax
  ret
```

assistant: ```c
double **bbob2009_reshape(double **B, double *vector, size_t m, size_t n) {
  size_t i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      B[i][j] = vector[j * m + i];
    }
  }
  return B;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<bbob2009_reshape>:
  endbr64
  mov    %rdi,%r11
  test   %rdx,%rdx
  je     L31
  test   %rcx,%rcx
  je     L31
  lea    0x0(,%rdx,8),%r8
  lea    0x0(,%rcx,8),%r10
  xor    %r9d,%r9d
  nopl   0x0(%rax)
L10:
  mov    (%r11,%r9,8),%rax
  mov    %rsi,%rcx
  lea    (%r10,%rax,1),%rdi
  nopl   0x0(%rax,%rax,1)
L28:
  movsd  (%rcx),%xmm0
  add    $0x8,%rax
  add    %r8,%rcx
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdi
  jne    L28
  add    $0x1,%r9
  add    $0x8,%rsi
  cmp    %r9,%rdx
  jne    L10
L31:
  mov    %r11,%rax
  ret
```

assistant: ```c
double **bbob2009_reshape(double **B, double *vector, size_t m, size_t n) {
  size_t i, j;
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      B[i][j] = vector[j * m + i];
    }
  }
  return B;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<om_text_print_numkeybar_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %r8d,-0x1c(%rbp)
  mov    %r9d,-0x20(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%esi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  push   $0x20
  mov    $0x23,%r9d
  mov    $0x2c,%r8d
  mov    %rax,%rdi
  call   <om_text_print_bar@plt>
  add    $0x10,%rsp
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
type: string

tool: D9:    %-12s: %-9d |

assistant: ```c
void om_text_print_numkeybar_entry(FILE *fp, char *key, int max, int tot, int this, int time_delta) {
  (void)time_delta;
  fprintf(fp, "   %-12s: %-9d |", key, this);
  om_text_print_bar(fp, max, tot, this, 44, '#', ' ');
  fprintf(fp, "\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<om_text_print_numkeybar_entry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %r8d,%ebp
  mov    %r8d,%ecx
  mov    %rsi,%rdx
  lea    D2(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  sub    $0x8,%rsp
  push   $0x20
  mov    $0x23,%r9d
  mov    $0x2c,%r8d
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <om_text_print_bar@plt>
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string

tool: D2:    %-12s: %-9d |

assistant: ```c
void om_text_print_numkeybar_entry(FILE *fp, char *key, int max, int tot, int this, int time_delta) {
  (void)time_delta;
  fprintf(fp, "   %-12s: %-9d |", key, this);
  om_text_print_bar(fp, max, tot, this, 44, '#', ' ');
  fprintf(fp, "\n");
}
```