ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0xa,-0x18(%rbp)
  movl   $0x14,-0x14(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L59
L41:
  movq   $0x0,-0x8(%rbp)
  jmp    L35
L25:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jne    L56
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L50
L56:
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  addq   $0x1,-0x8(%rbp)
L35:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jb     L25
  addq   $0x1,-0x10(%rbp)
L59:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jb     L41
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D18
datatype: string
name: retrieve_data
arguments: tag: D0
datatype: string

tool: D18: %c


tool: D0: %c

assistant: ```c
void print_map(char map[10][20]) {
  int i, j, rowLimit = 10, colLimit = 20;
  for (size_t i = 0; i < rowLimit; i++) {
    for (size_t j = 0; j < colLimit; j++) {
      if (j == colLimit - 1)
        printf("%c\n", map[i][j]);
      else
        printf("%c", map[i][j]);
    }
  }
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_map>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x13(%rdi),%rbp
  lea    0xdb(%rdi),%r13
  lea    D9(%rip),%r12
  lea    D13(%rip),%r14
  jmp    L20
L14:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
  movsbl 0x0(%rbp),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x14,%rbp
  cmp    %r13,%rbp
  je     L2
L20:
  lea    -0x13(%rbp),%rbx
  jmp    L14
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D9: %c

tool: D13: %c


assistant: ```c
void print_map(char map[10][20]) {
  int i, j, rowLimit = 10, colLimit = 20;
  for (size_t i = 0; i < rowLimit; i++) {
    for (size_t j = 0; j < colLimit; j++) {
      if (j == colLimit - 1)
        printf("%c\n", map[i][j]);
      else
        printf("%c", map[i][j]);
    }
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_map>:
  endbr64
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  lea    0xdb(%rdi),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  lea    0x13(%rdi),%rbp
  push   %rbx
  nopl   (%rax)
L10:
  lea    -0x13(%rbp),%rbx
  nopl   0x0(%rax)
L9:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L9
  movsbl (%rbx),%esi
  mov    %r14,%rdi
  lea    0x14(%rbx),%rbp
  call   <printf@plt>
  cmp    %r13,%rbp
  jne    L10
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D0
type: string

tool: D3: %c


tool: D0: %c

assistant: ```c
void print_map(char map[10][20]) {
  int i, j, rowLimit = 10, colLimit = 20;
  for (size_t i = 0; i < rowLimit; i++) {
    for (size_t j = 0; j < colLimit; j++) {
      if (j == colLimit - 1)
        printf("%c\n", map[i][j]);
      else
        printf("%c", map[i][j]);
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_map>:
  endbr64
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    0xdb(%rdi),%r13
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  lea    0x13(%rdi),%rbp
  push   %rbx
  nopl   (%rax)
L2:
  lea    -0x13(%rbp),%rbx
  nopl   0x0(%rax)
L1:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L1
  movsbl (%rbx),%esi
  mov    %r14,%rdi
  lea    0x14(%rbx),%rbp
  call   <printf@plt>
  cmp    %r13,%rbp
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string

tool: D1: %c


tool: D7: %c

assistant: ```c
void print_map(char map[10][20]) {
  int i, j, rowLimit = 10, colLimit = 20;
  for (size_t i = 0; i < rowLimit; i++) {
    for (size_t j = 0; j < colLimit; j++) {
      if (j == colLimit - 1)
        printf("%c\n", map[i][j]);
      else
        printf("%c", map[i][j]);
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L7
L37:
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%eax
  lea    -0x10(%rbp),%rdi
  lea    -0xc(%rbp),%rcx
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <findMaxNumBurger@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L26
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
L7:
  lea    -0x1c(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jg     L37
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D3
type_infered: string

tool: D11: %d

tool: D16:  %d

tool: D3: %d %d %d

assistant: ```c
int main(void) {
  int totalTime, timeTypeOne, timeTypeTwo, drinkTime, maxNumBurger;
  while (scanf("%d %d %d", &timeTypeOne, &timeTypeTwo, &totalTime) > 0) {
    findMaxNumBurger(totalTime, timeTypeOne, timeTypeTwo, &maxNumBurger, &drinkTime);
    printf("%d", maxNumBurger);
    if (drinkTime)
      printf(" %d", drinkTime);
    printf("\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  lea    D21(%rip),%rbx
  lea    D15(%rip),%r12
  lea    D3(%rip),%r13
  jmp    L49
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
L49:
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rcx
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L44
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%r8
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    0x4(%rsp),%edi
  call   <findMaxNumBurger@plt>
  mov    0x14(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  je     L17
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L17
L44:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D21: %d %d %d

tool: D15: %d

tool: D3:  %d

assistant: ```c
int main(void) {
  int totalTime, timeTypeOne, timeTypeTwo, drinkTime, maxNumBurger;
  while (scanf("%d %d %d", &timeTypeOne, &timeTypeTwo, &totalTime) > 0) {
    findMaxNumBurger(totalTime, timeTypeOne, timeTypeTwo, &maxNumBurger, &drinkTime);
    printf("%d", maxNumBurger);
    if (drinkTime)
      printf(" %d", drinkTime);
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r15
  lea    0x14(%rsp),%r14
  jmp    L24
  nopl   0x0(%rax)
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
L24:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L19
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    0x4(%rsp),%edi
  call   <findMaxNumBurger@plt>
  mov    0x14(%rsp),%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  je     L16
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L16
  nopl   0x0(%rax)
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D13
type_guessed: string

tool: D18: %d %d %d

tool: D2: %d

tool: D13:  %d

assistant: ```c
int main(void) {
  int totalTime, timeTypeOne, timeTypeTwo, drinkTime, maxNumBurger;
  while (scanf("%d %d %d", &timeTypeOne, &timeTypeTwo, &totalTime) > 0) {
    findMaxNumBurger(totalTime, timeTypeOne, timeTypeTwo, &maxNumBurger, &drinkTime);
    printf("%d", maxNumBurger);
    if (drinkTime)
      printf(" %d", drinkTime);
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D22(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    0x10(%rsp),%r15
  lea    0x14(%rsp),%r14
  jmp    L38
  nopl   0x0(%rax)
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
L38:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jle    L42
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    0x4(%rsp),%edi
  call   <findMaxNumBurger@plt>
  mov    0x14(%rsp),%esi
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%esi
  test   %esi,%esi
  je     L26
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L26
  nopl   0x0(%rax)
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D22
type_guessed: string
name: retrieve_data
arguments: label: D12
type_guessed: string
name: retrieve_data
arguments: label: D23
type_guessed: string

tool: D22: %d %d %d

tool: D12: %d

tool: D23:  %d

assistant: ```c
int main(void) {
  int totalTime, timeTypeOne, timeTypeTwo, drinkTime, maxNumBurger;
  while (scanf("%d %d %d", &timeTypeOne, &timeTypeTwo, &totalTime) > 0) {
    findMaxNumBurger(totalTime, timeTypeOne, timeTypeTwo, &maxNumBurger, &drinkTime);
    printf("%d", maxNumBurger);
    if (drinkTime)
      printf(" %d", drinkTime);
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L2
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: argv[%d]:%s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; argv[i] != NULL; i++) {
    printf("argv[%d]:%s\n", i, argv[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    (%rsi),%rdx
  test   %rdx,%rdx
  je     L10
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D4(%rip),%r12
L11:
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  mov    0x0(%rbp,%rbx,8),%rdx
  test   %rdx,%rdx
  jne    L11
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0x0,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D4: argv[%d]:%s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; argv[i] != NULL; i++) {
    printf("argv[%d]:%s\n", i, argv[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    (%rsi),%rdx
  test   %rdx,%rdx
  je     L3
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L8:
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdx
  test   %rdx,%rdx
  jne    L8
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  xor    %eax,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_guessed: string

tool: D4: argv[%d]:%s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; argv[i] != NULL; i++) {
    printf("argv[%d]:%s\n", i, argv[i]);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    (%rsi),%rdx
  test   %rdx,%rdx
  je     L8
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L19:
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  mov    0x0(%rbp,%rbx,8),%rdx
  test   %rdx,%rdx
  jne    L19
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  xor    %eax,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: argv[%d]:%s


assistant: ```c
int main(int argc, char **argv) {
  int i;
  for (i = 0; argv[i] != NULL; i++) {
    printf("argv[%d]:%s\n", i, argv[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mat2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  movss  %xmm1,-0x10(%rbp)
  movss  %xmm2,-0x14(%rbp)
  movss  %xmm3,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  -0x10(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *mat2(float *result, float m11, float m12, float m21, float m22) {
  result[0] = m11;
  result[1] = m21;
  result[2] = m12;
  result[3] = m22;
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mat2>:
  endbr64
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  %xmm2,0x4(%rdi)
  movss  %xmm1,0x8(%rdi)
  movss  %xmm3,0xc(%rdi)
  ret
```

assistant: ```c
float *mat2(float *result, float m11, float m12, float m21, float m22) {
  result[0] = m11;
  result[1] = m21;
  result[2] = m12;
  result[3] = m22;
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mat2>:
  endbr64
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  %xmm2,0x4(%rdi)
  movss  %xmm1,0x8(%rdi)
  movss  %xmm3,0xc(%rdi)
  ret
```

assistant: ```c
float *mat2(float *result, float m11, float m12, float m21, float m22) {
  result[0] = m11;
  result[1] = m21;
  result[2] = m12;
  result[3] = m22;
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<mat2>:
  endbr64
  unpcklps %xmm3,%xmm1
  unpcklps %xmm2,%xmm0
  mov    %rdi,%rax
  movlhps %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
float *mat2(float *result, float m11, float m12, float m21, float m22) {
  result[0] = m11;
  result[1] = m21;
  result[2] = m12;
  result[3] = m22;
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<hbCreateDecodeTables>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rcx,%rsi
  mov    0x28(%rsp),%r12d
  cmp    %r9d,%r8d
  jg     L11
  mov    %rdx,%rbp
  lea    0x1(%r9),%r13d
  mov    %r8d,%ecx
  mov    $0x0,%edi
  mov    %r12d,%r10d
  jmp    L16
L67:
  add    $0x1,%rax
  cmp    %r10,%rax
  je     L109
L40:
  movzbl (%rsi,%rax,1),%edx
  cmp    %ecx,%edx
  jne    L67
  movslq %edi,%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  add    $0x1,%edi
  jmp    L67
L109:
  add    $0x1,%ecx
  cmp    %r13d,%ecx
  je     L11
L16:
  mov    $0x0,%eax
  test   %r12d,%r12d
  jg     L40
  jmp    L109
L11:
  mov    %rbx,%rax
  lea    0x5c(%rbx),%rdx
L135:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L135
  test   %r12d,%r12d
  jle    L21
  mov    %rsi,%rax
  lea    -0x1(%r12),%ecx
  lea    0x1(%rsi,%rcx,1),%rsi
L160:
  movzbl (%rax),%ecx
  addl   $0x1,0x4(%rbx,%rcx,4)
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L160
L21:
  lea    0x4(%rbx),%rax
L94:
  mov    -0x4(%rax),%ecx
  add    %ecx,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L94
  mov    %r11,%rax
  lea    0x5c(%r11),%rdx
L52:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L52
  cmp    %r9d,%r8d
  jg     L17
  movslq %r8d,%rdx
  mov    $0x0,%eax
L99:
  add    0x4(%rbx,%rdx,4),%eax
  sub    (%rbx,%rdx,4),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,(%r11,%rdx,4)
  add    %eax,%eax
  add    $0x1,%rdx
  cmp    %edx,%r9d
  jge    L99
L17:
  lea    0x1(%r8),%eax
  cmp    %eax,%r9d
  jl     L3
  cltq
L28:
  mov    -0x4(%r11,%rax,4),%edx
  lea    0x2(%rdx,%rdx,1),%edx
  sub    (%rbx,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L28
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void hbCreateDecodeTables(int *limit, int *base, int *perm, unsigned char *length, int minLen, int maxLen, int alphaSize) {
  int pp, i, j, vec;
  pp = 0;
  for (i = minLen; i <= maxLen; i++)
    for (j = 0; j < alphaSize; j++)
      if (length[j] == i) {
        perm[pp] = j;
        pp++;
      };
  for (i = 0; i < 23; i++)
    base[i] = 0;
  for (i = 0; i < alphaSize; i++)
    base[length[i] + 1]++;
  for (i = 1; i < 23; i++)
    base[i] += base[i - 1];
  for (i = 0; i < 23; i++)
    limit[i] = 0;
  vec = 0;
  for (i = minLen; i <= maxLen; i++) {
    vec += (base[i + 1] - base[i]);
    limit[i] = vec - 1;
    vec <<= 1;
  }
  for (i = minLen + 1; i <= maxLen; i++)
    base[i] = ((limit[i - 1] + 1) << 1) - base[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hbCreateDecodeTables>:
  endbr64
  push   %r13
  mov    %rsi,%r11
  mov    %rdi,%r10
  mov    %rcx,%rsi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %r8d,%ebx
  mov    0x28(%rsp),%ebp
  cmp    %r9d,%r8d
  jg     L43
  mov    %r8d,%ecx
  mov    %rdx,%r12
  lea    0x1(%r9),%r13d
  xor    %edi,%edi
  movslq %ebp,%r8
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  test   %ebp,%ebp
  jle    L108
  cs nopw 0x0(%rax,%rax,1)
L90:
  movzbl (%rsi,%rax,1),%edx
  cmp    %ecx,%edx
  jne    L49
  movslq %edi,%rdx
  add    $0x1,%edi
  mov    %eax,(%r12,%rdx,4)
L49:
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L90
L108:
  add    $0x1,%ecx
  cmp    %r13d,%ecx
  jne    L1
L43:
  lea    0x8(%r11),%rdi
  mov    %r11,%rcx
  xor    %eax,%eax
  movq   $0x0,(%r11)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x54(%r11)
  sub    %rdi,%rcx
  add    $0x5c,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  test   %ebp,%ebp
  jle    L17
  lea    -0x1(%rbp),%eax
  lea    0x1(%rsi,%rax,1),%rdx
  nopw   0x0(%rax,%rax,1)
L104:
  movzbl (%rsi),%eax
  add    $0x1,%rsi
  addl   $0x1,0x4(%r11,%rax,4)
  cmp    %rsi,%rdx
  jne    L104
L17:
  lea    0x4(%r11),%rax
  lea    0x5c(%r11),%rcx
  nopw   0x0(%rax,%rax,1)
L105:
  mov    -0x4(%rax),%edx
  add    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rax,%rcx
  jne    L105
  lea    0x8(%r10),%rdi
  mov    %r10,%rcx
  xor    %eax,%eax
  movq   $0x0,(%r10)
  and    $0xfffffffffffffff8,%rdi
  movq   $0x0,0x54(%r10)
  sub    %rdi,%rcx
  add    $0x5c,%ecx
  shr    $0x3,%ecx
  rep stos %rax,%es:(%rdi)
  cmp    %r9d,%ebx
  jg     L94
  movslq %ebx,%rdx
  xchg   %ax,%ax
L73:
  add    0x4(%r11,%rdx,4),%eax
  sub    (%r11,%rdx,4),%eax
  lea    -0x1(%rax),%ecx
  add    %eax,%eax
  mov    %ecx,(%r10,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%r9d
  jge    L73
L94:
  lea    0x1(%rbx),%eax
  cmp    %eax,%r9d
  jl     L6
  cltq
  nopl   (%rax)
L71:
  mov    -0x4(%r10,%rax,4),%edx
  lea    0x2(%rdx,%rdx,1),%edx
  sub    (%r11,%rax,4),%edx
  mov    %edx,(%r11,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%r9d
  jge    L71
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void hbCreateDecodeTables(int *limit, int *base, int *perm, unsigned char *length, int minLen, int maxLen, int alphaSize) {
  int pp, i, j, vec;
  pp = 0;
  for (i = minLen; i <= maxLen; i++)
    for (j = 0; j < alphaSize; j++)
      if (length[j] == i) {
        perm[pp] = j;
        pp++;
      };
  for (i = 0; i < 23; i++)
    base[i] = 0;
  for (i = 0; i < alphaSize; i++)
    base[length[i] + 1]++;
  for (i = 1; i < 23; i++)
    base[i] += base[i - 1];
  for (i = 0; i < 23; i++)
    limit[i] = 0;
  vec = 0;
  for (i = minLen; i <= maxLen; i++) {
    vec += (base[i + 1] - base[i]);
    limit[i] = vec - 1;
    vec <<= 1;
  }
  for (i = minLen + 1; i <= maxLen; i++)
    base[i] = ((limit[i - 1] + 1) << 1) - base[i];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x4(%rbp)
  jmp    L0
L15:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0xa,-0x4(%rbp)
  jle    L15
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
type_guessed: string
name: extract_symbolic_data
arguments: tag: D1
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: tag: D31
type_guessed: string

tool: D34: Table of Powers of Two


tool: D1:  n  n squared

tool: D24: --- ---------

tool: D31: %3i %9i


assistant: ```c
int main(void) {
  int n;
  printf("Table of Powers of Two\n\n");
  printf(" n  n squared\n");
  printf("--- ---------\n");
  for (n = 1; n <= 10; n++)
    printf("%3i %9i\n", n, n * n);
  return 0;
}
```