ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L17
L30:
  mov    $0x0,%eax
L37:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    $0x31,%eax
  jg     L13
  cmp    %ecx,%eax
  jl     L37
L13:
  cmp    $0x59,%ecx
  jg     L20
L55:
  add    $0x1,%esi
L17:
  mov    %esi,%ecx
  cmp    $0x45,%esi
  jg     L30
  add    %esi,%edx
  jmp    L55
L20:
  mov    %edx,%eax
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 70) {
      int j;
      j = 0;
      while (j < i) {
        if (j >= 50)
          break;
        c = c + j;
        j = j + 1;
      }
      if (i >= 90)
        break;
      i = i + 1;
      continue;
      c = c + 1234567;
    }
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  mov    $0x1,%ecx
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L21
  nop
L2:
  add    %eax,%edx
L8:
  add    $0x1,%eax
  add    $0x1,%ecx
L21:
  cmp    $0x45,%eax
  jbe    L2
  lea    0x4c9(%rdx),%r8d
  mov    %r8d,%edx
  cmp    $0x5a,%eax
  je     L4
  cmp    $0x64,%ecx
  jne    L8
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 70) {
      int j;
      j = 0;
      while (j < i) {
        if (j >= 50)
          break;
        c = c + j;
        j = j + 1;
      }
      if (i >= 90)
        break;
      i = i + 1;
      continue;
      c = c + 1234567;
    }
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  mov    $0x1,%ecx
  xor    %eax,%eax
  xor    %edx,%edx
  jmp    L17
  nop
L23:
  add    %eax,%edx
L19:
  add    $0x1,%eax
  add    $0x1,%ecx
L17:
  cmp    $0x45,%eax
  jbe    L23
  lea    0x4c9(%rdx),%r8d
  mov    %r8d,%edx
  cmp    $0x5a,%eax
  je     L26
  cmp    $0x64,%ecx
  jne    L19
L26:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int f() {
  int i;
  int c;
  i = 0;
  c = 0;
  while (i < 100) {
    if (i >= 70) {
      int j;
      j = 0;
      while (j < i) {
        if (j >= 50)
          break;
        c = c + j;
        j = j + 1;
      }
      if (i >= 90)
        break;
      i = i + 1;
      continue;
      c = c + 1234567;
    }
    c = c + i;
    i = i + 1;
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tagfile_simplify_query>:
  endbr64
  test   %rdi,%rdi
  je     L167
  cmpb   $0x0,(%rdi)
  je     L134
  push   %rbx
  movzbl 0x1(%rdi),%esi
  test   %sil,%sil
  je     L11
  mov    $0x0,%ebx
  lea    D34(%rip),%r8
  lea    0x2(%r8),%r9
  jmp    L143
L91:
  add    $0x2,%rax
  cmp    %rax,%rcx
  je     L37
L163:
  cmp    %dl,(%rax)
  jne    L91
  cmp    %sil,0x1(%rax)
  jne    L91
  jmp    L132
L81:
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L82
  test   %ebx,%ebx
  jle    L109
  mov    %ebx,%edi
  mov    $0x0,%edx
  lea    D34(%rip),%rsi
L65:
  movzbl (%rsi,%rdx,2),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L65
L116:
  lea    -0x1(%rbx),%edx
  movslq %edx,%rdx
  lea    D34(%rip),%rcx
  movzbl 0x1(%rcx,%rdx,2),%ecx
  movslq %ebx,%rdx
  mov    %cl,(%rax,%rdx,1)
  lea    0x1(%rbx),%edx
  movslq %edx,%rdx
  movb   $0x0,(%rax,%rdx,1)
L82:
  pop    %rbx
  ret
L109:
  mov    $0x0,%ebx
  jmp    L116
L167:
  mov    %rdi,%rax
  ret
L134:
  mov    $0x0,%eax
  ret
L11:
  mov    $0x2,%edi
  call   <malloc@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  jne    L116
  jmp    L82
L37:
  movzbl (%rdi),%edx
  movslq %ebx,%rax
  mov    %dl,(%r8,%rax,2)
  mov    %sil,0x1(%r8,%rax,2)
  add    $0x1,%ebx
L132:
  movzbl 0x2(%rdi),%esi
  add    $0x1,%rdi
  cmp    $0x31,%ebx
  jg     L81
  test   %sil,%sil
  je     L81
L143:
  test   %ebx,%ebx
  jle    L37
  movzbl (%rdi),%edx
  lea    D34(%rip),%rax
  lea    -0x1(%rbx),%ecx
  lea    (%r9,%rcx,2),%rcx
  jmp    L163
```

assistant: ```c
char *tagfile_simplify_query(const char *query) {
  static char pairs[50][2];
  int num_pairs = 0;
  int pos = 0;
  int i;
  bool found;
  char *result;
  if (query == NULL || query[0] == 0)
    return NULL;
  while (query[pos + 1] != 0 && num_pairs < 50) {
    found = false;
    for (i = 0; i < num_pairs; ++i) {
      if (pairs[i][0] == query[pos] && pairs[i][1] == query[pos + 1]) {
        found = true;
        break;
      }
    }
    if (!found) {
      pairs[num_pairs][0] = query[pos];
      pairs[num_pairs][1] = query[pos + 1];
      num_pairs++;
    }
    pos++;
  }
  result = malloc(num_pairs + 2);
  if (result) {
    for (i = 0; i < num_pairs; ++i) {
      result[i] = pairs[i][0];
    }
    result[i] = pairs[i - 1][1];
    i++;
    result[i] = 0;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tagfile_simplify_query>:
  endbr64
  test   %rdi,%rdi
  je     L107
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L107
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl 0x1(%rdi),%esi
  test   %sil,%sil
  je     L10
  lea    D5(%rip),%rbp
  xor    %ebx,%ebx
  add    $0x1,%rdi
  lea    0x2(%rbp),%r8
  test   %ebx,%ebx
  je     L117
L44:
  lea    -0x1(%rbx),%ecx
  lea    D5(%rip),%rax
  lea    (%r8,%rcx,2),%rcx
  jmp    L133
L111:
  add    $0x2,%rax
  cmp    %rcx,%rax
  je     L117
L133:
  cmp    %dl,(%rax)
  jne    L111
  cmp    %sil,0x1(%rax)
  jne    L111
  movzbl 0x1(%rdi),%esi
  test   %sil,%sil
  je     L60
L136:
  cmp    $0x32,%ebx
  je     L41
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  test   %ebx,%ebx
  jne    L44
  nopl   0x0(%rax)
L117:
  movslq %ebx,%rax
  add    $0x1,%ebx
  mov    %dl,0x0(%rbp,%rax,2)
  mov    %sil,0x1(%rbp,%rax,2)
  movzbl 0x1(%rdi),%esi
  test   %sil,%sil
  jne    L136
L60:
  lea    0x2(%rbx),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L80
L19:
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L131:
  movzbl 0x0(%rbp,%rdx,2),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L131
  xor    %ecx,%ecx
  lea    -0x1(%rbx),%edx
  test   %ebx,%ebx
  movslq %ebx,%rsi
  cmovle %ecx,%edx
  lea    0x1(%rbx),%ecx
  add    %rax,%rsi
  movslq %ecx,%rcx
L159:
  movslq %edx,%rdx
  movzbl 0x1(%rbp,%rdx,2),%edx
  mov    %dl,(%rsi)
  movb   $0x0,(%rax,%rcx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L41:
  mov    $0x34,%edi
  call   <malloc@plt>
  test   %rax,%rax
  jne    L19
L80:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L107:
  xor    %eax,%eax
  ret
L10:
  mov    $0x2,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L80
  mov    %rax,%rsi
  mov    $0x1,%ecx
  mov    $0xffffffff,%edx
  lea    D5(%rip),%rbp
  jmp    L159
```

assistant: ```c
char *tagfile_simplify_query(const char *query) {
  static char pairs[50][2];
  int num_pairs = 0;
  int pos = 0;
  int i;
  bool found;
  char *result;
  if (query == NULL || query[0] == 0)
    return NULL;
  while (query[pos + 1] != 0 && num_pairs < 50) {
    found = false;
    for (i = 0; i < num_pairs; ++i) {
      if (pairs[i][0] == query[pos] && pairs[i][1] == query[pos + 1]) {
        found = true;
        break;
      }
    }
    if (!found) {
      pairs[num_pairs][0] = query[pos];
      pairs[num_pairs][1] = query[pos + 1];
      num_pairs++;
    }
    pos++;
  }
  result = malloc(num_pairs + 2);
  if (result) {
    for (i = 0; i < num_pairs; ++i) {
      result[i] = pairs[i][0];
    }
    result[i] = pairs[i - 1][1];
    i++;
    result[i] = 0;
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<arcdie>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L9
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L9:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <vprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
type_guessed: string

tool: D1: 


assistant: ```c
void arcdie(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
  printf("\n");
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<arcdie>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <vprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: 


assistant: ```c
void arcdie(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
  printf("\n");
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arcdie>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D5: 


assistant: ```c
void arcdie(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
  printf("\n");
  exit(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arcdie>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <vprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string

tool: D5: 


assistant: ```c
void arcdie(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vprintf(format, args);
  va_end(args);
  printf("\n");
  exit(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NRF24_CSN_Test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <NRF24_Enable@plt>
  mov    $0x0,%eax
  call   <NRF24_Disable@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void NRF24_CSN_Test(void) {
  NRF24_Enable();
  NRF24_Disable();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<NRF24_CSN_Test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <NRF24_Enable@plt>
  mov    $0x0,%eax
  call   <NRF24_Disable@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void NRF24_CSN_Test(void) {
  NRF24_Enable();
  NRF24_Disable();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NRF24_CSN_Test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <NRF24_Enable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <NRF24_Disable@plt>
```

assistant: ```c
void NRF24_CSN_Test(void) {
  NRF24_Enable();
  NRF24_Disable();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<NRF24_CSN_Test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <NRF24_Enable@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <NRF24_Disable@plt>
```

assistant: ```c
void NRF24_CSN_Test(void) {
  NRF24_Enable();
  NRF24_Disable();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<decode_ucs2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L56:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  or     %ecx,%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %eax,%esi
  mov    %rdx,%rdi
  call   <wctomb@plt>
  cmp    $0x2,%eax
  jne    L43
  addl   $0x2,-0x10(%rbp)
  jmp    L16
L43:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x8(%rbp)
  addl   $0x2,-0x10(%rbp)
  nop
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L56
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L9:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xac,%al
  jne    L35
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa4,(%rax)
L35:
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int decode_ucs2(char *buffer, int len) {
  int i;
  char *d = buffer;
  int j;
  for (i = 0; i < len;) {
    switch (wctomb(d + i, (*(buffer + i) << 8 | *(buffer + i + 1)))) {
    case 2:
      i += 2;
      break;
    default:
      *(d + i) = *(buffer + i + 1);
      d--;
      i += 2;
      break;
    }
  }
  i = (d - buffer) + len;
  *(buffer + i) = '\0';
  for (j = 0; buffer[j]; j++)
    if (buffer[j] == (char)0xAC)
      buffer[j] = (char)0xA4;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decode_ucs2>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r14d
  test   %esi,%esi
  jle    L75
  mov    %rdi,%r12
  mov    $0x0,%ebp
  jmp    L33
L46:
  lea    0x2(%rbp),%eax
L56:
  add    $0x2,%rbp
  cmp    %r14d,%eax
  jge    L80
L33:
  lea    (%r12,%rbp,1),%r13
  movsbl 0x1(%rbx,%rbp,1),%esi
  mov    %r13,%rdi
  call   <wctomb@plt>
  cmp    $0x2,%eax
  je     L46
  movzbl 0x1(%rbx,%rbp,1),%eax
  mov    %al,0x0(%r13)
  sub    $0x1,%r12
  lea    0x2(%rbp),%eax
  jmp    L56
L75:
  mov    %rdi,%r12
L80:
  sub    %rbx,%r12
  add    %r12d,%r14d
  movslq %r14d,%rax
  movb   $0x0,(%rbx,%rax,1)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L87
L85:
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L28:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L85
L87:
  cmp    $0xac,%al
  jne    L28
  movb   $0xa4,(%rbx)
  jmp    L28
```

assistant: ```c
int decode_ucs2(char *buffer, int len) {
  int i;
  char *d = buffer;
  int j;
  for (i = 0; i < len;) {
    switch (wctomb(d + i, (*(buffer + i) << 8 | *(buffer + i + 1)))) {
    case 2:
      i += 2;
      break;
    default:
      *(d + i) = *(buffer + i + 1);
      d--;
      i += 2;
      break;
    }
  }
  i = (d - buffer) + len;
  *(buffer + i) = '\0';
  for (j = 0; buffer[j]; j++)
    if (buffer[j] == (char)0xAC)
      buffer[j] = (char)0xA4;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<decode_ucs2>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L31
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r12
  xor    %ebp,%ebp
  shr    %eax
  lea    0x1(%rax),%r15d
  add    %r15,%r15
  nopl   (%rax)
L53:
  lea    (%r12,%rbp,1),%r13
  movsbl 0x1(%rbx,%rbp,1),%esi
  mov    %r13,%rdi
  call   <wctomb@plt>
  cmp    $0x2,%eax
  je     L7
  movzbl 0x1(%rbx,%rbp,1),%eax
  sub    $0x1,%r12
  mov    %al,0x0(%r13)
L7:
  add    $0x2,%rbp
  cmp    %rbp,%r15
  jne    L53
  sub    %ebx,%r12d
L35:
  add    %r12d,%r14d
  movslq %r14d,%rax
  movb   $0x0,(%rbx,%rax,1)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L52
L28:
  cmp    $0xac,%al
  jne    L25
  movb   $0xa4,(%rbx)
L25:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L28
L52:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L31:
  xor    %r12d,%r12d
  jmp    L35
```

assistant: ```c
int decode_ucs2(char *buffer, int len) {
  int i;
  char *d = buffer;
  int j;
  for (i = 0; i < len;) {
    switch (wctomb(d + i, (*(buffer + i) << 8 | *(buffer + i + 1)))) {
    case 2:
      i += 2;
      break;
    default:
      *(d + i) = *(buffer + i + 1);
      d--;
      i += 2;
      break;
    }
  }
  i = (d - buffer) + len;
  *(buffer + i) = '\0';
  for (j = 0; buffer[j]; j++)
    if (buffer[j] == (char)0xAC)
      buffer[j] = (char)0xA4;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decode_ucs2>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r12
  xor    %ebp,%ebp
  shr    %eax
  lea    0x1(%rax),%r15d
  add    %r15,%r15
  nopl   0x0(%rax)
L30:
  lea    (%r12,%rbp,1),%r13
  movsbl 0x1(%rbx,%rbp,1),%esi
  mov    %r13,%rdi
  call   <wctomb@plt>
  cmp    $0x2,%eax
  je     L17
  movzbl 0x1(%rbx,%rbp,1),%eax
  sub    $0x1,%r12
  mov    %al,0x0(%r13)
L17:
  add    $0x2,%rbp
  cmp    %rbp,%r15
  jne    L30
  sub    %ebx,%r12d
L68:
  add    %r12d,%r14d
  movslq %r14d,%rax
  movb   $0x0,(%rbx,%rax,1)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L41
  nopl   0x0(%rax,%rax,1)
L78:
  cmp    $0xac,%al
  je     L60
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L78
L41:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L60:
  movb   $0xa4,(%rbx)
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L78
  jmp    L41
  nopl   0x0(%rax)
L2:
  xor    %r12d,%r12d
  jmp    L68
```

assistant: ```c
int decode_ucs2(char *buffer, int len) {
  int i;
  char *d = buffer;
  int j;
  for (i = 0; i < len;) {
    switch (wctomb(d + i, (*(buffer + i) << 8 | *(buffer + i + 1)))) {
    case 2:
      i += 2;
      break;
    default:
      *(d + i) = *(buffer + i + 1);
      d--;
      i += 2;
      break;
    }
  }
  i = (d - buffer) + len;
  *(buffer + i) = '\0';
  for (j = 0; buffer[j]; j++)
    if (buffer[j] == (char)0xAC)
      buffer[j] = (char)0xA4;
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<VIDEO_WaitVSync>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L4:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jg     L4
  nop
L0:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jle    L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void VIDEO_WaitVSync(void) {
  while (read16(((0xCC002000) + 0x2C)) >= 200)
    ;
  while (read16(((0xCC002000) + 0x2C)) < 200)
    ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<VIDEO_WaitVSync>:
  endbr64
  sub    $0x8,%rsp
L16:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jg     L16
L0:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jle    L0
  add    $0x8,%rsp
  ret
```

assistant: ```c
void VIDEO_WaitVSync(void) {
  while (read16(((0xCC002000) + 0x2C)) >= 200)
    ;
  while (read16(((0xCC002000) + 0x2C)) < 200)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<VIDEO_WaitVSync>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L15:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jg     L15
  nopl   0x0(%rax)
L14:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jle    L14
  add    $0x8,%rsp
  ret
```

assistant: ```c
void VIDEO_WaitVSync(void) {
  while (read16(((0xCC002000) + 0x2C)) >= 200)
    ;
  while (read16(((0xCC002000) + 0x2C)) < 200)
    ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<VIDEO_WaitVSync>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jg     L3
  nopl   0x0(%rax)
L18:
  mov    $0xcc00202c,%edi
  call   <read16@plt>
  cmp    $0xc7,%eax
  jle    L18
  add    $0x8,%rsp
  ret
```

assistant: ```c
void VIDEO_WaitVSync(void) {
  while (read16(((0xCC002000) + 0x2C)) >= 200)
    ;
  while (read16(((0xCC002000) + 0x2C)) < 200)
    ;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atof_del>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atof@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float atof_del(char *data) {
  float ret = atof(data);
  free(data);
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<atof_del>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  call   <atof@plt>
  movss  %xmm0,0xc(%rsp)
  mov    %rbx,%rdi
  call   <free@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
float atof_del(char *data) {
  float ret = atof(data);
  free(data);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<atof_del>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  call   <atof@plt>
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <free@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
float atof_del(char *data) {
  float ret = atof(data);
  free(data);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atof_del>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  call   <atof@plt>
  mov    %rbp,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <free@plt>
  movss  0xc(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbp
  ret
```

assistant: ```c
float atof_del(char *data) {
  float ret = atof(data);
  free(data);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movq   $0x2a,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L18:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x10(%rbp),%edx
  add    $0x1,%edx
  imul   %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  int counter;
  int len_word = strlen(word);
  long hash_counter = 42;
  for (counter = 0; counter < len_word; counter++) {
    hash_counter += word[counter] * (counter + 1);
  }
  return hash_counter;
}
```