ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_movement>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rsi
  mov    $0x1,%edx
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <read@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L16
  movzbl 0x7(%rsp),%eax
  sub    $0x17,%eax
  and    $0xfffffffb,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  or     $0x1,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_movement(char *command, int cmd_len, int num_times) {
  char c;
  while (read(STDIN_FILENO, &c, 1)) {
    if (c >= '1' && c <= '9') {
    }
    switch (c) {
    case '\033':
    case '\027':
      return -1;
    case 'h':
    case 'j':
    case 'k':
    case 'l':
    case 'H':
    case 'M':
    case 'L':
    case 'w':
    case 'W':
    case 'b':
    case 'B':
    case 'e':
    case 'E':
    case '(':
    case ')':
    case '{':
    case '}':
    case '0':
    case '$':
    case 'G':
    case ':':
    case 'f':
    case 'F':
    case '%':
    default:
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_movement>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  lea    0x7(%rsp),%rsi
  mov    (%rax),%edi
  call   <read@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L11
  movzbl 0x7(%rsp),%eax
  sub    $0x17,%eax
  and    $0xfffffffb,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  or     $0x1,%eax
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_movement(char *command, int cmd_len, int num_times) {
  char c;
  while (read(STDIN_FILENO, &c, 1)) {
    if (c >= '1' && c <= '9') {
    }
    switch (c) {
    case '\033':
    case '\027':
      return -1;
    case 'h':
    case 'j':
    case 'k':
    case 'l':
    case 'H':
    case 'M':
    case 'L':
    case 'w':
    case 'W':
    case 'b':
    case 'B':
    case 'e':
    case 'E':
    case '(':
    case ')':
    case '{':
    case '}':
    case '0':
    case '$':
    case 'G':
    case ':':
    case 'f':
    case 'F':
    case '%':
    default:
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_movement>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x7(%rsp),%rsi
  mov    (%rax),%edi
  call   <read@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L19
  movzbl 0x7(%rsp),%eax
  sub    $0x17,%eax
  and    $0xfffffffb,%eax
  cmp    $0x1,%al
  sbb    %eax,%eax
  or     $0x1,%eax
L19:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_movement(char *command, int cmd_len, int num_times) {
  char c;
  while (read(STDIN_FILENO, &c, 1)) {
    if (c >= '1' && c <= '9') {
    }
    switch (c) {
    case '\033':
    case '\027':
      return -1;
    case 'h':
    case 'j':
    case 'k':
    case 'l':
    case 'H':
    case 'M':
    case 'L':
    case 'w':
    case 'W':
    case 'b':
    case 'B':
    case 'e':
    case 'E':
    case '(':
    case ')':
    case '{':
    case '}':
    case '0':
    case '$':
    case 'G':
    case ':':
    case 'f':
    case 'F':
    case '%':
    default:
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<skip_blanks>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L21
L4:
  addq   $0x1,-0x8(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L8
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L4
L8:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *skip_blanks(string)
char *string;
{
  while (*string && isspace(*string))
    string++;
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skip_blanks>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    %rbx,%rax
  test   %dil,%dil
  je     L30
L29:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L12
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L29
  mov    %rbx,%rax
  jmp    L30
L12:
  mov    %rbx,%rax
L30:
  pop    %rbx
  ret
```

assistant: ```c
char *skip_blanks(string)
char *string;
{
  while (*string && isspace(*string))
    string++;
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<skip_blanks>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L2
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L19
L2:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L7
L19:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_blanks(string)
char *string;
{
  while (*string && isspace(*string))
    string++;
  return string;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<skip_blanks>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L4
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L37:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L21
L4:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L37
L21:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *skip_blanks(string)
char *string;
{
  while (*string && isspace(*string))
    string++;
  return string;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<leCoeficiente>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D11: 
%s: 

tool: D7: %lf

assistant: ```c
double leCoeficiente(char *msg) {
  double el;
  printf("\n%s: ", msg);
  scanf("%lf", &el);
  return el;
}
```
user: Translate the below assembly code into C programming language:

```asm
<leCoeficiente>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string

tool: D2: 
%s: 

tool: D7: %lf

assistant: ```c
double leCoeficiente(char *msg) {
  double el;
  printf("\n%s: ", msg);
  scanf("%lf", &el);
  return el;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<leCoeficiente>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  lea    D10(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D10: 
%s: 

tool: D0: %lf

assistant: ```c
double leCoeficiente(char *msg) {
  double el;
  printf("\n%s: ", msg);
  scanf("%lf", &el);
  return el;
}
```
user: What is the c source code of the assembly code below?

```asm
<leCoeficiente>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
type: string
name: retrieve_data
arguments: data_tag: D6
type: string

tool: D5: 
%s: 

tool: D6: %lf

assistant: ```c
double leCoeficiente(char *msg) {
  double el;
  printf("\n%s: ", msg);
  scanf("%lf", &el);
  return el;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<store48>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x18(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    $0x20,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x20(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  mov    $0x28,%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x28(%rax),%rdx
  movslq %ecx,%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void store48(void *dst, uint64_t w) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)(w >> 0);
  p[1] = (uint8_t)(w >> 8);
  p[2] = (uint8_t)(w >> 16);
  p[3] = (uint8_t)(w >> 24);
  p[4] = (uint8_t)(w >> 32);
  p[5] = (uint8_t)(w >> 40);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<store48>:
  endbr64
  movslq %esi,%rax
  mov    %rax,(%rdi)
  mov    %esi,%eax
  sar    $0x8,%eax
  cltq
  mov    %rax,0x8(%rdi)
  mov    %esi,%eax
  sar    $0x10,%eax
  cltq
  mov    %rax,0x10(%rdi)
  mov    %esi,%eax
  sar    $0x18,%eax
  cltq
  mov    %rax,0x18(%rdi)
  mov    %esi,%eax
  mov    $0x20,%ecx
  sar    %cl,%eax
  cltq
  mov    %rax,0x20(%rdi)
  mov    $0x28,%ecx
  sar    %cl,%esi
  movslq %esi,%rsi
  mov    %rsi,0x28(%rdi)
  ret
```

assistant: ```c
void store48(void *dst, uint64_t w) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)(w >> 0);
  p[1] = (uint8_t)(w >> 8);
  p[2] = (uint8_t)(w >> 16);
  p[3] = (uint8_t)(w >> 24);
  p[4] = (uint8_t)(w >> 32);
  p[5] = (uint8_t)(w >> 40);
}
```
user: What is the c source code of the assembly code below?

```asm
<store48>:
  endbr64
  movslq %esi,%rax
  mov    $0x20,%ecx
  mov    %rax,(%rdi)
  mov    %esi,%eax
  sar    $0x8,%eax
  cltq
  mov    %rax,0x8(%rdi)
  mov    %esi,%eax
  sar    $0x10,%eax
  cltq
  mov    %rax,0x10(%rdi)
  mov    %esi,%eax
  sar    $0x18,%eax
  cltq
  mov    %rax,0x18(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x28,%ecx
  sar    %cl,%esi
  cltq
  movslq %esi,%rsi
  mov    %rax,0x20(%rdi)
  mov    %rsi,0x28(%rdi)
  ret
```

assistant: ```c
void store48(void *dst, uint64_t w) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)(w >> 0);
  p[1] = (uint8_t)(w >> 8);
  p[2] = (uint8_t)(w >> 16);
  p[3] = (uint8_t)(w >> 24);
  p[4] = (uint8_t)(w >> 32);
  p[5] = (uint8_t)(w >> 40);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<store48>:
  endbr64
  mov    %esi,%edx
  mov    %esi,%eax
  movd   %esi,%xmm0
  mov    $0x20,%ecx
  sar    $0x10,%edx
  sar    $0x8,%eax
  movd   %edx,%xmm1
  mov    %esi,%edx
  movd   %eax,%xmm4
  mov    %esi,%eax
  sar    $0x18,%edx
  punpckldq %xmm4,%xmm0
  sar    %cl,%eax
  mov    $0x28,%ecx
  movd   %edx,%xmm3
  sar    %cl,%esi
  cltq
  punpckldq %xmm3,%xmm1
  movslq %esi,%rsi
  punpcklqdq %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  movq   %rsi,%xmm5
  pcmpgtd %xmm0,%xmm1
  movdqa %xmm0,%xmm2
  punpckhdq %xmm1,%xmm0
  punpckldq %xmm1,%xmm2
  movups %xmm0,0x10(%rdi)
  movq   %rax,%xmm0
  punpcklqdq %xmm5,%xmm0
  movups %xmm2,(%rdi)
  movups %xmm0,0x20(%rdi)
  ret
```

assistant: ```c
void store48(void *dst, uint64_t w) {
  uint8_t *p = (uint8_t *)dst;
  p[0] = (uint8_t)(w >> 0);
  p[1] = (uint8_t)(w >> 8);
  p[2] = (uint8_t)(w >> 16);
  p[3] = (uint8_t)(w >> 24);
  p[4] = (uint8_t)(w >> 32);
  p[5] = (uint8_t)(w >> 40);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void func0(int var1, int var2) {
  var1 = var2;
  var1 = var2;
  var1 = var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<func0>:
  endbr64
  ret
```

assistant: ```c
void func0(int var1, int var2) {
  var1 = var2;
  var1 = var2;
  var1 = var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func0>:
  endbr64
  ret
```

assistant: ```c
void func0(int var1, int var2) {
  var1 = var2;
  var1 = var2;
  var1 = var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func0>:
  endbr64
  ret
```

assistant: ```c
void func0(int var1, int var2) {
  var1 = var2;
  var1 = var2;
  var1 = var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 + var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 - var2;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 < var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 > var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 * var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 / var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
  var1 = var2 % var1;
}
```
user: What is the c source code of the assembly code below?

```asm
<usage_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string

tool: D2: Usage:  %s (-h)
  data to stdin and stats to stdout.


assistant: ```c
void usage_error(char *name) {
  printf("Usage:  %s (-h)\n  data to stdin and stats to stdout.\n", name);
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string

tool: D2: Usage:  %s (-h)
  data to stdin and stats to stdout.


assistant: ```c
void usage_error(char *name) {
  printf("Usage:  %s (-h)\n  data to stdin and stats to stdout.\n", name);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Usage:  %s (-h)
  data to stdin and stats to stdout.


assistant: ```c
void usage_error(char *name) {
  printf("Usage:  %s (-h)\n  data to stdin and stats to stdout.\n", name);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<usage_error>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: Usage:  %s (-h)
  data to stdin and stats to stdout.


assistant: ```c
void usage_error(char *name) {
  printf("Usage:  %s (-h)\n  data to stdin and stats to stdout.\n", name);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<fnPlace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L34
L18:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x28(%rbp)
  je     L24
  mov    -0x14(%rbp),%eax
  sub    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  mov    %rax,%rbx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <abs@plt>
  cmp    %rax,%rbx
  jne    L4
L24:
  mov    $0x0,%eax
  jmp    L35
L4:
  addl   $0x1,-0x14(%rbp)
L34:
  mov    -0x24(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L18
  mov    $0x1,%eax
L35:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int fnPlace(int iK, int iI, int iX[10]) {
  int iJ;
  for (iJ = 1; iJ <= iK - 1; iJ++) {
    if (iX[iJ] == iI || abs(iJ - iK) == abs(iX[iJ] - iI))
      return 0;
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fnPlace>:
  endbr64
  cmp    $0x1,%edi
  jle    L53
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  lea    0x4(%rdx),%rbx
  mov    $0x1,%ebp
  sub    %edi,%ebp
L0:
  cmp    %r13d,(%rbx)
  je     L49
  mov    %ebp,%edi
  call   <abs@plt>
  mov    %rax,%r12
  mov    (%rbx),%edi
  sub    %r13d,%edi
  call   <abs@plt>
  cmp    %rax,%r12
  je     L19
  add    $0x4,%rbx
  add    $0x1,%ebp
  jne    L0
  mov    $0x1,%eax
  jmp    L22
L53:
  mov    $0x1,%eax
  ret
L49:
  mov    $0x0,%eax
L22:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  mov    $0x0,%eax
  jmp    L22
```

assistant: ```c
int fnPlace(int iK, int iI, int iX[10]) {
  int iJ;
  for (iJ = 1; iJ <= iK - 1; iJ++) {
    if (iX[iJ] == iI || abs(iJ - iK) == abs(iX[iJ] - iI))
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fnPlace>:
  endbr64
  cmp    $0x1,%edi
  jle    L44
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    %edi,%ebp
  lea    0x4(%rdx),%rbx
  sub    $0x8,%rsp
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L34:
  mov    %ebp,%edi
  call   <abs@plt>
  mov    (%rbx),%edi
  mov    %rax,%r13
  sub    %r12d,%edi
  call   <abs@plt>
  cmp    %rax,%r13
  je     L38
  add    $0x4,%rbx
  add    $0x1,%ebp
  je     L15
L37:
  cmp    %r12d,(%rbx)
  jne    L34
L38:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fnPlace(int iK, int iI, int iX[10]) {
  int iJ;
  for (iJ = 1; iJ <= iK - 1; iJ++) {
    if (iX[iJ] == iI || abs(iJ - iK) == abs(iX[iJ] - iI))
      return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fnPlace>:
  endbr64
  cmp    $0x1,%edi
  jle    L0
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    %edi,%ebp
  lea    0x4(%rdx),%rbx
  sub    $0x8,%rsp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %ebp,%edi
  call   <abs@plt>
  mov    (%rbx),%edi
  mov    %rax,%r13
  sub    %r12d,%edi
  call   <abs@plt>
  cmp    %rax,%r13
  je     L43
  add    $0x4,%rbx
  add    $0x1,%ebp
  je     L5
L19:
  cmp    %r12d,(%rbx)
  jne    L40
L43:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L5:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int fnPlace(int iK, int iI, int iX[10]) {
  int iJ;
  for (iJ = 1; iJ <= iK - 1; iJ++) {
    if (iX[iJ] == iI || abs(iJ - iK) == abs(iX[iJ] - iI))
      return 0;
  }
  return 1;
}
```