ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x20(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm3
  movss  -0x18(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x20(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm2
  subss  %xmm2,%xmm0
  movaps %xmm0,%xmm1
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm3
  movss  -0x18(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x20(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x18(%rbp),%xmm2
  movss  -0x1c(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L1
  ucomiss %xmm1,%xmm0
  je     L21
L1:
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd -0x10(%rbp),%xmm4
  movq   %xmm4,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L14
L21:
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L14:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D3
datatype: string
name: read_data
arguments: tag: D23
datatype: string

tool: D10: %f %f %f %f

tool: D3: (%0.3f,%0.3f)

tool: D23: INF

assistant: ```c
int main() {
  float a1, a2, b1, b2, x, y;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  x = a1 * a2 * (b2 - b1) / (a1 * b2 - a2 * b1);
  y = (a1 - a2) * b1 * b2 / (a1 * b2 - a2 * b1);
  if (a1 * b2 != b1 * a2)
    printf("(%0.3f,%0.3f)", x, y);
  else
    printf("INF");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm6
  movss  0x14(%rsp),%xmm3
  movss  0x10(%rsp),%xmm5
  movaps %xmm0,%xmm2
  mulss  %xmm3,%xmm2
  movaps %xmm6,%xmm4
  mulss  %xmm5,%xmm4
  ucomiss %xmm4,%xmm2
  jp     L33
  jne    L33
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L33:
  subss  %xmm4,%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm6,%xmm1
  mulss  %xmm5,%xmm1
  mulss  %xmm3,%xmm1
  divss  %xmm2,%xmm1
  mulss  %xmm6,%xmm0
  subss  %xmm5,%xmm3
  mulss  %xmm3,%xmm0
  divss  %xmm2,%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D22(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L38:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
datatype: string
name: disassemble_data
arguments: data_label: D27
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string

tool: D15: %f %f %f %f

tool: D27: INF

tool: D22: (%0.3f,%0.3f)

assistant: ```c
int main() {
  float a1, a2, b1, b2, x, y;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  x = a1 * a2 * (b2 - b1) / (a1 * b2 - a2 * b1);
  y = (a1 - a2) * b1 * b2 / (a1 * b2 - a2 * b1);
  if (a1 * b2 != b1 * a2)
    printf("(%0.3f,%0.3f)", x, y);
  else
    printf("INF");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D19(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm5
  movss  0x14(%rsp),%xmm3
  movss  0x10(%rsp),%xmm4
  movaps %xmm2,%xmm0
  movaps %xmm5,%xmm1
  mulss  %xmm3,%xmm0
  mulss  %xmm4,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L5
  jne    L5
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L8:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  subss  %xmm1,%xmm0
  movaps %xmm2,%xmm1
  lea    D3(%rip),%rdi
  mov    $0x2,%eax
  subss  %xmm5,%xmm1
  mulss  %xmm5,%xmm2
  mulss  %xmm4,%xmm1
  mulss  %xmm3,%xmm1
  subss  %xmm4,%xmm3
  mulss  %xmm3,%xmm2
  divss  %xmm0,%xmm1
  divss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  jmp    L8
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D19
type_guessed: string
name: read_data
arguments: data_label: D23
type_guessed: string
name: read_data
arguments: data_label: D3
type_guessed: string

tool: D19: %f %f %f %f

tool: D23: INF

tool: D3: (%0.3f,%0.3f)

assistant: ```c
int main() {
  float a1, a2, b1, b2, x, y;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  x = a1 * a2 * (b2 - b1) / (a1 * b2 - a2 * b1);
  y = (a1 - a2) * b1 * b2 / (a1 * b2 - a2 * b1);
  if (a1 * b2 != b1 * a2)
    printf("(%0.3f,%0.3f)", x, y);
  else
    printf("INF");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D16(%rip),%rdi
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm2
  movss  0xc(%rsp),%xmm5
  movss  0x14(%rsp),%xmm3
  movss  0x10(%rsp),%xmm4
  movaps %xmm2,%xmm0
  movaps %xmm5,%xmm1
  mulss  %xmm3,%xmm0
  mulss  %xmm4,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L7
  jne    L7
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  subss  %xmm1,%xmm0
  movaps %xmm2,%xmm1
  lea    D21(%rip),%rdi
  mov    $0x2,%eax
  subss  %xmm5,%xmm1
  mulss  %xmm5,%xmm2
  mulss  %xmm4,%xmm1
  mulss  %xmm3,%xmm1
  subss  %xmm4,%xmm3
  mulss  %xmm3,%xmm2
  divss  %xmm0,%xmm1
  divss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  jmp    L9
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D21
type: string

tool: D16: %f %f %f %f

tool: D17: INF

tool: D21: (%0.3f,%0.3f)

assistant: ```c
int main() {
  float a1, a2, b1, b2, x, y;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  x = a1 * a2 * (b2 - b1) / (a1 * b2 - a2 * b1);
  y = (a1 - a2) * b1 * b2 / (a1 * b2 - a2 * b1);
  if (a1 * b2 != b1 * a2)
    printf("(%0.3f,%0.3f)", x, y);
  else
    printf("INF");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<calc_check_digit>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    (%rdi,%rdi,4),%rax
  lea    (%rax,%rax,4),%r12
  shl    $0x2,%r12
  mov    $0x2,%ebx
  mov    $0x0,%ebp
L19:
  mov    $0xa,%esi
  call   <lldiv@plt>
  mov    %rdx,%rdi
  imul   %ebx,%eax
  add    %eax,%ebp
  add    $0x1,%ebx
  cmp    $0xb,%ebx
  jne    L19
  movslq %ebp,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  mov    $0xb,%edx
  sub    %eax,%edx
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmovg  %edx,%eax
  lea    (%rax,%rax,4),%ebx
  add    %ebx,%ebx
  movslq %ebx,%rbx
  add    %r12,%rbx
  movabs $0x6666666666666667,%rdx
  mov    %rbx,%rax
  imul   %rdx
  sar    $0x2,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rdi
  sub    %rax,%rdi
  mov    $0x2,%ebp
  mov    $0x0,%r12d
L13:
  mov    $0xa,%esi
  call   <lldiv@plt>
  mov    %rdx,%rdi
  imul   %ebp,%eax
  add    %eax,%r12d
  add    $0x1,%ebp
  cmp    $0xc,%ebp
  jne    L13
  movslq %r12d,%rax
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x21,%rax
  mov    %r12d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %r12d,%eax
  sub    %edx,%eax
  mov    $0xb,%edx
  sub    %eax,%edx
  cmp    $0x1,%eax
  mov    $0x0,%eax
  cmovg  %edx,%eax
  cltq
  add    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
long long calc_check_digit(long long raiz) {
  int produto = 0, i, digito;
  long long aux = raiz, cpf;
  lldiv_t divisao;
  cpf = (long long)raiz * 100;
  for (i = 0; i <= 8; i++) {
    divisao = lldiv(aux, 10);
    produto += divisao.rem * (i + 2);
    aux = divisao.quot;
  }
  digito = produto % 11 < 2 ? 0 : 11 - (produto % 11);
  cpf += (digito * 10);
  produto = 0;
  aux = (long long)cpf / 10;
  for (i = 0; i <= 9; i++) {
    divisao = lldiv(aux, 10);
    produto += divisao.rem * (i + 2);
    aux = divisao.quot;
  }
  digito = produto % 11 < 2 ? 0 : 11 - (produto % 11);
  cpf += digito;
  return cpf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<calc_check_digit>:
  endbr64
  push   %r13
  lea    (%rdi,%rdi,4),%rax
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    (%rax,%rax,4),%rbp
  push   %rbx
  shl    $0x2,%rbp
  mov    $0x2,%ebx
  mov    %rbp,%r12
  sub    $0x8,%rsp
  nopl   (%rax)
L29:
  mov    $0xa,%esi
  call   <lldiv@plt>
  imul   %ebx,%eax
  add    $0x1,%ebx
  mov    %rdx,%rdi
  add    %eax,%r13d
  cmp    $0xb,%ebx
  jne    L29
  movslq %r13d,%rax
  mov    %r13d,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %r13d,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jle    L24
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%r12d
  add    %r12d,%r12d
  movslq %r12d,%r12
  add    %rbp,%r12
L24:
  mov    %r12,%rax
  mov    $0x2,%ebx
  xor    %ebp,%ebp
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %r12,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rdi
  sub    %rax,%rdi
L18:
  mov    $0xa,%esi
  call   <lldiv@plt>
  imul   %ebx,%eax
  add    $0x1,%ebx
  mov    %rdx,%rdi
  add    %eax,%ebp
  cmp    $0xc,%ebx
  jne    L18
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jle    L8
  mov    $0xb,%edx
  sub    %eax,%edx
  movslq %edx,%rax
  add    %rax,%r12
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long long calc_check_digit(long long raiz) {
  int produto = 0, i, digito;
  long long aux = raiz, cpf;
  lldiv_t divisao;
  cpf = (long long)raiz * 100;
  for (i = 0; i <= 8; i++) {
    divisao = lldiv(aux, 10);
    produto += divisao.rem * (i + 2);
    aux = divisao.quot;
  }
  digito = produto % 11 < 2 ? 0 : 11 - (produto % 11);
  cpf += (digito * 10);
  produto = 0;
  aux = (long long)cpf / 10;
  for (i = 0; i <= 9; i++) {
    divisao = lldiv(aux, 10);
    produto += divisao.rem * (i + 2);
    aux = divisao.quot;
  }
  digito = produto % 11 < 2 ? 0 : 11 - (produto % 11);
  cpf += digito;
  return cpf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_check_digit>:
  endbr64
  push   %r13
  lea    (%rdi,%rdi,4),%rax
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  lea    (%rax,%rax,4),%rbp
  push   %rbx
  shl    $0x2,%rbp
  mov    $0x2,%ebx
  mov    %rbp,%r12
  sub    $0x8,%rsp
  nopl   (%rax)
L7:
  mov    $0xa,%esi
  call   <lldiv@plt>
  imul   %ebx,%eax
  add    $0x1,%ebx
  mov    %rdx,%rdi
  add    %eax,%r13d
  cmp    $0xb,%ebx
  jne    L7
  movslq %r13d,%rax
  mov    %r13d,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %r13d,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jle    L15
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%r12d
  add    %r12d,%r12d
  movslq %r12d,%r12
  add    %rbp,%r12
L15:
  mov    %r12,%rax
  mov    $0x2,%ebx
  xor    %ebp,%ebp
  movabs $0x6666666666666667,%rdx
  imul   %rdx
  mov    %r12,%rax
  sar    $0x3f,%rax
  sar    $0x2,%rdx
  mov    %rdx,%rdi
  sub    %rax,%rdi
L9:
  mov    $0xa,%esi
  call   <lldiv@plt>
  imul   %ebx,%eax
  add    $0x1,%ebx
  mov    %rdx,%rdi
  add    %eax,%ebp
  cmp    $0xc,%ebx
  jne    L9
  movslq %ebp,%rax
  mov    %ebp,%edx
  imul   $0x2e8ba2e9,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%edx
  lea    (%rax,%rdx,2),%edx
  mov    %ebp,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jle    L28
  mov    $0xb,%edx
  sub    %eax,%edx
  movslq %edx,%rax
  add    %rax,%r12
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long long calc_check_digit(long long raiz) {
  int produto = 0, i, digito;
  long long aux = raiz, cpf;
  lldiv_t divisao;
  cpf = (long long)raiz * 100;
  for (i = 0; i <= 8; i++) {
    divisao = lldiv(aux, 10);
    produto += divisao.rem * (i + 2);
    aux = divisao.quot;
  }
  digito = produto % 11 < 2 ? 0 : 11 - (produto % 11);
  cpf += (digito * 10);
  produto = 0;
  aux = (long long)cpf / 10;
  for (i = 0; i <= 9; i++) {
    divisao = lldiv(aux, 10);
    produto += divisao.rem * (i + 2);
    aux = divisao.quot;
  }
  digito = produto % 11 < 2 ? 0 : 11 - (produto % 11);
  cpf += digito;
  return cpf;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_builtin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L21
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <call_exit@plt>
  jmp    L1
L21:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  movl   $0x1,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <call_history@plt>
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type: string
name: read_data
arguments: data_label: D0
type: string

tool: D3: exit

tool: D0: history

assistant: ```c
int do_builtin(char **shArgs) {
  int isBuiltIn = 0;
  if (strcmp("exit", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_exit(shArgs);
  } else if (strcmp("history", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_history(shArgs);
  }
  return isBuiltIn;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<do_builtin>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rsi
  lea    D17(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbx,%rdi
  call   <call_exit@plt>
  mov    $0x1,%eax
L27:
  pop    %rbx
  ret
L1:
  mov    (%rbx),%rsi
  lea    D16(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L27
  mov    %rbx,%rdi
  call   <call_history@plt>
  mov    $0x1,%eax
  jmp    L27
```

tool_calls: name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D16
type: string

tool: D17: exit

tool: D16: history

assistant: ```c
int do_builtin(char **shArgs) {
  int isBuiltIn = 0;
  if (strcmp("exit", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_exit(shArgs);
  } else if (strcmp("history", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_history(shArgs);
  }
  return isBuiltIn;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<do_builtin>:
  endbr64
  push   %rbp
  mov    (%rdi),%rsi
  mov    %rdi,%rbp
  lea    D8(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L6
  mov    %rbp,%rdi
  call   <call_exit@plt>
  mov    $0x1,%eax
L10:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    0x0(%rbp),%rsi
  lea    D12(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L10
  mov    %rbp,%rdi
  call   <call_history@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string

tool: D8: exit

tool: D12: history

assistant: ```c
int do_builtin(char **shArgs) {
  int isBuiltIn = 0;
  if (strcmp("exit", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_exit(shArgs);
  } else if (strcmp("history", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_history(shArgs);
  }
  return isBuiltIn;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_builtin>:
  endbr64
  push   %rbp
  mov    (%rdi),%rsi
  mov    %rdi,%rbp
  lea    D4(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  mov    %rbp,%rdi
  call   <call_exit@plt>
  mov    $0x1,%eax
L2:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    0x0(%rbp),%rsi
  lea    D5(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L2
  mov    %rbp,%rdi
  call   <call_history@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
data_type: string
name: unpack_data
arguments: label: D5
data_type: string

tool: D4: exit

tool: D5: history

assistant: ```c
int do_builtin(char **shArgs) {
  int isBuiltIn = 0;
  if (strcmp("exit", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_exit(shArgs);
  } else if (strcmp("history", shArgs[0]) == 0) {
    isBuiltIn = 1;
    call_history(shArgs);
  }
  return isBuiltIn;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getBytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L12
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffffffffffff,%rax
  jmp    L0
L12:
  mov    -0x10(%rbp),%rax
L0:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D5: 
Error al usar stat sobre el fichero


assistant: ```c
long getBytes(char *path) {
  struct stat buff;
  if (stat(path, &buff) < 0) {
    printf("\nError al usar stat sobre el fichero\n");
    return -1;
  } else {
    return buff.st_size;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getBytes>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L15
  mov    (%rsp),%rax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  ret
L15:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffffffffffff,%rax
  jmp    L9
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
type: string

tool: D5: 
Error al usar stat sobre el fichero


assistant: ```c
long getBytes(char *path) {
  struct stat buff;
  if (stat(path, &buff) < 0) {
    printf("\nError al usar stat sobre el fichero\n");
    return -1;
  } else {
    return buff.st_size;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getBytes>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L1
  mov    (%rsp),%rax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x18,%rsp
  ret
L1:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffffffffffff,%rax
  jmp    L26
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D5: 
Error al usar stat sobre el fichero


assistant: ```c
long getBytes(char *path) {
  struct stat buff;
  if (stat(path, &buff) < 0) {
    printf("\nError al usar stat sobre el fichero\n");
    return -1;
  } else {
    return buff.st_size;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getBytes>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L2
  mov    (%rsp),%rax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x18,%rsp
  ret
L2:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffffffffffff,%rax
  jmp    L5
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
datatype: string

tool: D0: 
Error al usar stat sobre el fichero


assistant: ```c
long getBytes(char *path) {
  struct stat buff;
  if (stat(path, &buff) < 0) {
    printf("\nError al usar stat sobre el fichero\n");
    return -1;
  } else {
    return buff.st_size;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type: string

tool: D5: 
Usage: %s <get | set>
  get - display the MAC address of the first Wi-Fi STA that connects to
        the router after it came out from the factory to 'stdout'.
  set xx:xx:xx:xx:xx:xx - record specified MAC address to POT partition,
        if thers is a MAC address existed yet, just display
        it without any write action.


assistant: ```c
void usage(char *name) {
  printf("\nUsage: %s <get | set>\n"
         "  get - display the MAC address of the first Wi-Fi STA that connects to\n"
         "        the router after it came out from the factory to 'stdout'.\n"
         "  set xx:xx:xx:xx:xx:xx - record specified MAC address to POT partition,\n"
         "        if thers is a MAC address existed yet, just display\n"
         "        it without any write action.\n",
         name);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string

tool: D5: 
Usage: %s <get | set>
  get - display the MAC address of the first Wi-Fi STA that connects to
        the router after it came out from the factory to 'stdout'.
  set xx:xx:xx:xx:xx:xx - record specified MAC address to POT partition,
        if thers is a MAC address existed yet, just display
        it without any write action.


assistant: ```c
void usage(char *name) {
  printf("\nUsage: %s <get | set>\n"
         "  get - display the MAC address of the first Wi-Fi STA that connects to\n"
         "        the router after it came out from the factory to 'stdout'.\n"
         "  set xx:xx:xx:xx:xx:xx - record specified MAC address to POT partition,\n"
         "        if thers is a MAC address existed yet, just display\n"
         "        it without any write action.\n",
         name);
  exit(0);
}
```