ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hatfldc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r14
  mov    %edx,0xc(%rsp)
  movsd  (%rdi),%xmm0
  subsd  D16(%rip),%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x2,%edx
  jle    L24
  lea    0x8(%rsi),%rbp
  lea    0x8(%rdi),%rbx
  lea    -0x3(%rdx),%eax
  lea    0x10(%rsi,%rax,8),%r13
L17:
  mov    -0x8(%rbx),%r12
  movsd  (%rbx),%xmm0
  pxor   %xmm2,%xmm2
  ucomisd %xmm0,%xmm2
  ja     L3
  sqrtsd %xmm0,%xmm0
L10:
  movq   %r12,%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,0x0(%rbp)
  add    $0x8,%rbp
  add    $0x8,%rbx
  cmp    %r13,%rbp
  jne    L17
L24:
  movslq 0xc(%rsp),%rax
  shl    $0x3,%rax
  movsd  -0x8(%r15,%rax,1),%xmm0
  subsd  D16(%rip),%xmm0
  movsd  %xmm0,-0x8(%r14,%rax,1)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <sqrt@plt>
  jmp    L10
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: f64

tool: D16: 1

assistant: ```c
void hatfldc(double *p, double *x, int m, int n, void *data) {
  register int i;
  x[0] = p[0] - 1.0;
  for (i = 1; i < m - 1; ++i)
    x[i] = p[i - 1] - sqrt(p[i]);
  x[m - 1] = p[m - 1] - 1.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hatfldc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  (%rdi),%xmm0
  movsd  D1(%rip),%xmm3
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x2,%edx
  jle    L18
  lea    -0x3(%rdx),%eax
  lea    0x8(%rsi),%rbp
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L26:
  movsd  (%rbx),%xmm0
  movsd  -0x8(%rbx),%xmm1
  ucomisd %xmm0,%xmm2
  ja     L32
  sqrtsd %xmm0,%xmm0
L37:
  subsd  %xmm0,%xmm1
  add    $0x8,%rbp
  add    $0x8,%rbx
  movsd  %xmm1,-0x8(%rbp)
  cmp    %r12,%rbp
  jne    L26
L18:
  movslq %edx,%rdx
  shl    $0x3,%rdx
  movsd  -0x8(%rdi,%rdx,1),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm0,-0x8(%rsi,%rdx,1)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  mov    %edx,0x1c(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdi,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <sqrt@plt>
  mov    D1(%rip),%rax
  mov    0x1c(%rsp),%edx
  pxor   %xmm2,%xmm2
  mov    0x10(%rsp),%rsi
  mov    0x8(%rsp),%rdi
  movsd  (%rsp),%xmm1
  movq   %rax,%xmm3
  jmp    L37
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: f64

tool: D1: 1

assistant: ```c
void hatfldc(double *p, double *x, int m, int n, void *data) {
  register int i;
  x[0] = p[0] - 1.0;
  for (i = 1; i < m - 1; ++i)
    x[i] = p[i - 1] - sqrt(p[i]);
  x[m - 1] = p[m - 1] - 1.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<hatfldc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movsd  (%rdi),%xmm0
  movsd  D4(%rip),%xmm3
  subsd  %xmm3,%xmm0
  movsd  %xmm0,(%rsi)
  cmp    $0x2,%edx
  jle    L18
  lea    -0x3(%rdx),%eax
  lea    0x8(%rsi),%rbp
  pxor   %xmm2,%xmm2
  lea    0x8(%rdi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
  nopl   0x0(%rax)
L42:
  movsd  (%rbx),%xmm0
  movsd  -0x8(%rbx),%xmm1
  ucomisd %xmm0,%xmm2
  ja     L43
  sqrtsd %xmm0,%xmm0
  add    $0x8,%rbp
  add    $0x8,%rbx
  subsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rbp)
  cmp    %r12,%rbp
  jne    L42
L18:
  movslq %edx,%rdx
  shl    $0x3,%rdx
  movsd  -0x8(%rdi,%rdx,1),%xmm0
  subsd  %xmm3,%xmm0
  movsd  %xmm0,-0x8(%rsi,%rdx,1)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L43:
  mov    %edx,0x1c(%rsp)
  add    $0x8,%rbp
  add    $0x8,%rbx
  mov    %rsi,0x10(%rsp)
  mov    %rdi,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm1
  mov    0x8(%rsp),%rdi
  pxor   %xmm2,%xmm2
  mov    D4(%rip),%rax
  mov    0x10(%rsp),%rsi
  subsd  %xmm0,%xmm1
  mov    0x1c(%rsp),%edx
  movq   %rax,%xmm3
  movsd  %xmm1,-0x8(%rbp)
  cmp    %r12,%rbp
  jne    L42
  jmp    L18
```

tool_calls: name: parse_data
arguments: label: D4
data_type: f64

tool: D4: 1

assistant: ```c
void hatfldc(double *p, double *x, int m, int n, void *data) {
  register int i;
  x[0] = p[0] - 1.0;
  for (i = 1; i < m - 1; ++i)
    x[i] = p[i - 1] - sqrt(p[i]);
  x[m - 1] = p[m - 1] - 1.0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L25
L9:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x18(%rbp)
L25:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L9
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x14(%rbp)
  jmp    L44
L19:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L44:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D14
data_type: string
name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D53
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D21
data_type: string

tool: D14: Tamanho do vetor: 

tool: D15: %d

tool: D53: 
Entre com os elementos do vetor:

tool: D7: Elementos do vetor:

tool: D21: %d 

assistant: ```c
int main() {
  int tam;
  printf("Tamanho do vetor: ");
  scanf("%d", &tam);
  int *vet = malloc(tam * sizeof(int));
  printf("\nEntre com os elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    scanf("%d", &vet[i]);
  printf("Elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    printf("%d ", vet[i]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D46(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    D33(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L0
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D46(%rip),%r13
L8:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jg     L8
L0:
  lea    D9(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L4
  mov    $0x0,%ebx
  lea    D35(%rip),%rbp
L31:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0x4(%rsp)
  jg     L31
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D58
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: string
name: extract_symbolic_data
arguments: label: D33
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string
name: extract_symbolic_data
arguments: label: D35
type_guessed: string

tool: D58: Tamanho do vetor: 

tool: D46: %d

tool: D33: 
Entre com os elementos do vetor:

tool: D9: Elementos do vetor:

tool: D35: %d 

assistant: ```c
int main() {
  int tam;
  printf("Tamanho do vetor: ");
  scanf("%d", &tam);
  int *vet = malloc(tam * sizeof(int));
  printf("\nEntre com os elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    scanf("%d", &vet[i]);
  printf("Elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    printf("%d ", vet[i]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdi
  lea    D37(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D6(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L28
  mov    %r12,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L24
L28:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L27
  xor    %ebx,%ebx
  lea    D2(%rip),%rbp
  nopl   (%rax)
L40:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L40
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D37
datatype: string
name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D33
datatype: string
name: disassemble_data
arguments: tag: D2
datatype: string

tool: D17: Tamanho do vetor: 

tool: D37: %d

tool: D6: 
Entre com os elementos do vetor:

tool: D33: Elementos do vetor:

tool: D2: %d 

assistant: ```c
int main() {
  int tam;
  printf("Tamanho do vetor: ");
  scanf("%d", &tam);
  int *vet = malloc(tam * sizeof(int));
  printf("\nEntre com os elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    scanf("%d", &vet[i]);
  printf("Elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    printf("%d ", vet[i]);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdi
  lea    D9(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D26(%rip),%rdi
  mov    %rax,%r12
  call   <puts@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L41
  mov    %r12,%rbp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L43:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L43
L41:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L6
  xor    %ebx,%ebx
  lea    D44(%rip),%rbp
  nopl   (%rax)
L25:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L25
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D36
type_infered: string
name: extract_symbolic_data
arguments: data_label: D44
type_infered: string

tool: D17: Tamanho do vetor: 

tool: D9: %d

tool: D26: 
Entre com os elementos do vetor:

tool: D36: Elementos do vetor:

tool: D44: %d 

assistant: ```c
int main() {
  int tam;
  printf("Tamanho do vetor: ");
  scanf("%d", &tam);
  int *vet = malloc(tam * sizeof(int));
  printf("\nEntre com os elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    scanf("%d", &vet[i]);
  printf("Elementos do vetor:\n");
  for (int i = 0; i < tam; i++)
    printf("%d ", vet[i]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x5c,-0x405(%rbp)
  movl   $0x0,-0x404(%rbp)
  movl   $0x3e9,-0x400(%rbp)
  movss  D4(%rip),%xmm0
  movss  %xmm0,-0x3fc(%rbp)
  movsd  D5(%rip),%xmm0
  movsd  %xmm0,-0x3f8(%rbp)
  movabs $0x3a676e696e726177,%rax
  mov    %rax,-0x3f0(%rbp)
  movw   $0x20,-0x3e8(%rbp)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: byte[4]
name: unpack_data
arguments: label: D5
type_guessed: f64

tool: {"D4": [0xac,0xc5,0x27,0x37]}

tool: D5: 2.71828182845905

assistant: ```c
main() {
  int lower, upper, step;
  char c, line[1000];
  char esc = '\\';
  int i = 0;
  int limit = 1000 + 1;
  float eps = 1.0e-5;
  const double e = 2.71828182845905;
  const char msg[] = "warning: ";
  int strlen(const char[]);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int lower, upper, step;
  char c, line[1000];
  char esc = '\\';
  int i = 0;
  int limit = 1000 + 1;
  float eps = 1.0e-5;
  const double e = 2.71828182845905;
  const char msg[] = "warning: ";
  int strlen(const char[]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int lower, upper, step;
  char c, line[1000];
  char esc = '\\';
  int i = 0;
  int limit = 1000 + 1;
  float eps = 1.0e-5;
  const double e = 2.71828182845905;
  const char msg[] = "warning: ";
  int strlen(const char[]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int lower, upper, step;
  char c, line[1000];
  char esc = '\\';
  int i = 0;
  int limit = 1000 + 1;
  float eps = 1.0e-5;
  const double e = 2.71828182845905;
  const char msg[] = "warning: ";
  int strlen(const char[]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<gemm_nt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movss  %xmm0,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9,-0x38(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L16:
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L24:
  pxor   %xmm2,%xmm2
  movaps %xmm2,%xmm5
  movl   $0x0,-0x4(%rbp)
  jmp    L46
L13:
  mov    -0xc(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movaps %xmm0,%xmm1
  mulss  -0x20(%rbp),%xmm1
  mov    -0x8(%rbp),%eax
  imul   0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movaps %xmm5,%xmm3
  addss  %xmm3,%xmm0
  movaps %xmm0,%xmm5
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    -0xc(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  movaps %xmm5,%xmm4
  addss  %xmm4,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  addl   $0x1,-0xc(%rbp)
L4:
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L16
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gemm_nt(int M, int N, int K, float ALPHA, float *A, int lda, float *B, int ldb, float *C, int ldc) {
  int i, j, k;
#pragma omp parallel for
  for (i = 0; i < M; ++i) {
    for (j = 0; j < N; ++j) {
      register float sum = 0;
      for (k = 0; k < K; ++k) {
        sum += ALPHA * A[i * lda + k] * B[j * ldb + k];
      }
      C[i * ldc + j] += sum;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gemm_nt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,-0x18(%rsp)
  mov    %rcx,-0x10(%rsp)
  mov    %r8d,-0x14(%rsp)
  mov    0x38(%rsp),%r11d
  test   %edi,%edi
  jle    L64
  mov    %esi,%ebp
  mov    %edx,%r10d
  movaps %xmm0,%xmm2
  mov    %r9,%rbx
  mov    $0x0,%r14d
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  lea    -0x1(%rsi),%eax
  mov    %rax,-0x8(%rsp)
  mov    0x40(%rsp),%rax
  lea    0x4(%rax),%r15
  mov    %edx,%esi
  jmp    L75
L18:
  movslq %r8d,%rax
  lea    (%rbx,%rax,4),%rdx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L69:
  movaps %xmm2,%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  mulss  (%rdx,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L69
L65:
  addss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  add    $0x4,%rdi
  add    %r11d,%r8d
  cmp    %r9,%rdi
  je     L88
L1:
  pxor   %xmm1,%xmm1
  test   %r10d,%r10d
  jg     L18
  jmp    L65
L88:
  add    $0x1,%r12d
  add    0x48(%rsp),%r13d
  add    -0x14(%rsp),%r14d
  cmp    %r12d,-0x18(%rsp)
  je     L64
L75:
  test   %ebp,%ebp
  jle    L88
  movslq %r13d,%rax
  mov    0x40(%rsp),%rdi
  lea    (%rdi,%rax,4),%rdi
  add    -0x8(%rsp),%rax
  lea    (%r15,%rax,4),%r9
  movslq %r14d,%rax
  mov    -0x10(%rsp),%rdx
  lea    (%rdx,%rax,4),%rcx
  mov    $0x0,%r8d
  jmp    L1
L64:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void gemm_nt(int M, int N, int K, float ALPHA, float *A, int lda, float *B, int ldb, float *C, int ldc) {
  int i, j, k;
#pragma omp parallel for
  for (i = 0; i < M; ++i) {
    for (j = 0; j < N; ++j) {
      register float sum = 0;
      for (k = 0; k < K; ++k) {
        sum += ALPHA * A[i * lda + k] * B[j * ldb + k];
      }
      C[i * ldc + j] += sum;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gemm_nt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r11d
  mov    %edi,-0x1c(%rsp)
  mov    %rcx,-0x18(%rsp)
  test   %edi,%edi
  jle    L29
  lea    -0x1(%rsi),%eax
  mov    %esi,%ebp
  mov    %edx,%r10d
  mov    %r8d,%r14d
  mov    %rax,-0x10(%rsp)
  mov    0x40(%rsp),%rax
  mov    %r9,%rbx
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  xor    %r12d,%r12d
  pxor   %xmm3,%xmm3
  movslq %edx,%rsi
  add    $0x4,%rax
  mov    %rax,-0x8(%rsp)
  nopl   (%rax)
L48:
  test   %ebp,%ebp
  jle    L46
  mov    0x40(%rsp),%rdi
  mov    -0x8(%rsp),%rdx
  movslq %r13d,%rax
  xor    %r8d,%r8d
  lea    (%rdi,%rax,4),%rdi
  add    -0x10(%rsp),%rax
  lea    (%rdx,%rax,4),%r9
  mov    -0x18(%rsp),%rdx
  movslq %r15d,%rax
  lea    (%rdx,%rax,4),%rcx
  nopl   (%rax)
L21:
  movaps %xmm3,%xmm2
  test   %r10d,%r10d
  jle    L49
  movslq %r8d,%rax
  movaps %xmm3,%xmm2
  lea    (%rbx,%rax,4),%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L26:
  movss  (%rcx,%rax,4),%xmm1
  mulss  %xmm0,%xmm1
  mulss  (%rdx,%rax,4),%xmm1
  add    $0x1,%rax
  addss  %xmm1,%xmm2
  cmp    %rax,%rsi
  jne    L26
L49:
  addss  (%rdi),%xmm2
  add    $0x4,%rdi
  add    %r11d,%r8d
  movss  %xmm2,-0x4(%rdi)
  cmp    %r9,%rdi
  jne    L21
L46:
  add    $0x1,%r12d
  add    0x48(%rsp),%r13d
  add    %r14d,%r15d
  cmp    %r12d,-0x1c(%rsp)
  jne    L48
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void gemm_nt(int M, int N, int K, float ALPHA, float *A, int lda, float *B, int ldb, float *C, int ldc) {
  int i, j, k;
#pragma omp parallel for
  for (i = 0; i < M; ++i) {
    for (j = 0; j < N; ++j) {
      register float sum = 0;
      for (k = 0; k < K; ++k) {
        sum += ALPHA * A[i * lda + k] * B[j * ldb + k];
      }
      C[i * ldc + j] += sum;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<esmQuaternionToMatrix>:
  endbr64
  movaps %xmm1,%xmm6
  mulss  %xmm1,%xmm6
  addss  %xmm6,%xmm6
  movaps %xmm2,%xmm9
  mulss  %xmm2,%xmm9
  addss  %xmm9,%xmm9
  movss  D4(%rip),%xmm8
  movaps %xmm8,%xmm4
  subss  %xmm6,%xmm4
  subss  %xmm9,%xmm4
  movss  %xmm4,(%rdi)
  movaps %xmm0,%xmm5
  mulss  %xmm1,%xmm5
  addss  %xmm5,%xmm5
  movaps %xmm2,%xmm10
  mulss  %xmm3,%xmm10
  addss  %xmm10,%xmm10
  movaps %xmm5,%xmm4
  addss  %xmm10,%xmm4
  movss  %xmm4,0x4(%rdi)
  movaps %xmm0,%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm4,%xmm4
  movaps %xmm1,%xmm7
  mulss  %xmm3,%xmm7
  addss  %xmm7,%xmm7
  movaps %xmm4,%xmm11
  subss  %xmm7,%xmm11
  movss  %xmm11,0x8(%rdi)
  movl   $0x0,0xc(%rdi)
  subss  %xmm10,%xmm5
  movss  %xmm5,0x10(%rdi)
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  addss  %xmm5,%xmm5
  movaps %xmm5,%xmm10
  movaps %xmm8,%xmm5
  subss  %xmm10,%xmm5
  movaps %xmm5,%xmm10
  subss  %xmm9,%xmm10
  movss  %xmm10,0x14(%rdi)
  mulss  %xmm2,%xmm1
  addss  %xmm1,%xmm1
  mulss  %xmm3,%xmm0
  addss  %xmm0,%xmm0
  movaps %xmm1,%xmm2
  addss  %xmm0,%xmm2
  movss  %xmm2,0x18(%rdi)
  movl   $0x0,0x1c(%rdi)
  addss  %xmm7,%xmm4
  movss  %xmm4,0x20(%rdi)
  subss  %xmm0,%xmm1
  movss  %xmm1,0x24(%rdi)
  subss  %xmm6,%xmm5
  movss  %xmm5,0x28(%rdi)
  movl   $0x0,0x2c(%rdi)
  movl   $0x0,0x30(%rdi)
  movl   $0x0,0x34(%rdi)
  movl   $0x0,0x38(%rdi)
  movss  %xmm8,0x3c(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: byte[4]

tool: {"D4": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void esmQuaternionToMatrix(float *M, float x, float y, float z, float w) {
  float xsq;
  float ysq;
  float zsq;
  float xy;
  float xz;
  float yz;
  float wx;
  float wy;
  float wz;
  xsq = x * x;
  ysq = y * y;
  zsq = z * z;
  xy = x * y;
  xz = x * z;
  yz = y * z;
  wx = w * x;
  wy = w * y;
  wz = w * z;
  M[0] = 1 - (2 * ysq) - (2 * zsq);
  M[1] = (2 * xy) + (2 * wz);
  M[2] = (2 * xz) - (2 * wy);
  M[3] = 0;
  M[4] = (2 * xy) - (2 * wz);
  M[5] = 1 - (2 * xsq) - (2 * zsq);
  M[6] = (2 * yz) + (2 * wx);
  M[7] = 0;
  M[8] = (2 * xz) + (2 * wy);
  M[9] = (2 * yz) - (2 * wx);
  M[10] = 1 - (2 * xsq) - (2 * ysq);
  M[11] = 0;
  M[12] = 0;
  M[13] = 0;
  M[14] = 0;
  M[15] = 1;
}
```