ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hexrev>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int hexrev(unsigned int x) {
  unsigned int a = x;
  unsigned int a1, a2, a3, a4, ans;
  a1 = a % 0x100;
  a = a / 0x100;
  a2 = a % 0x100;
  a = a / 0x100;
  a3 = a % 0x100;
  a = a / 0x100;
  a4 = a % 0x100;
  ans = a4 + a3 * 0x100 + a2 * 0x10000 + a1 * 0x1000000;
  return ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hexrev>:
  endbr64
  mov    %edi,%edx
  movzbl %dil,%eax
  shl    $0x8,%eax
  movzbl %dh,%ecx
  add    %ecx,%eax
  shl    $0x8,%eax
  mov    %edi,%ecx
  shr    $0x10,%ecx
  movzbl %cl,%ecx
  add    %ecx,%eax
  shl    $0x8,%eax
  shr    $0x18,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int hexrev(unsigned int x) {
  unsigned int a = x;
  unsigned int a1, a2, a3, a4, ans;
  a1 = a % 0x100;
  a = a / 0x100;
  a2 = a % 0x100;
  a = a / 0x100;
  a3 = a % 0x100;
  a = a / 0x100;
  a4 = a % 0x100;
  ans = a4 + a3 * 0x100 + a2 * 0x10000 + a1 * 0x1000000;
  return ans;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hexrev>:
  endbr64
  mov    %edi,%edx
  movzbl %dil,%eax
  movzbl %dh,%ecx
  shl    $0x8,%eax
  add    %ecx,%eax
  mov    %edi,%ecx
  shr    $0x18,%edx
  shr    $0x10,%ecx
  shl    $0x8,%eax
  movzbl %cl,%ecx
  add    %ecx,%eax
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int hexrev(unsigned int x) {
  unsigned int a = x;
  unsigned int a1, a2, a3, a4, ans;
  a1 = a % 0x100;
  a = a / 0x100;
  a2 = a % 0x100;
  a = a / 0x100;
  a3 = a % 0x100;
  a = a / 0x100;
  a4 = a % 0x100;
  ans = a4 + a3 * 0x100 + a2 * 0x10000 + a1 * 0x1000000;
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hexrev>:
  endbr64
  mov    %edi,%edx
  movzbl %dil,%eax
  movzbl %dh,%ecx
  shl    $0x8,%eax
  add    %ecx,%eax
  mov    %edi,%ecx
  shr    $0x18,%edx
  shr    $0x10,%ecx
  shl    $0x8,%eax
  movzbl %cl,%ecx
  add    %ecx,%eax
  shl    $0x8,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int hexrev(unsigned int x) {
  unsigned int a = x;
  unsigned int a1, a2, a3, a4, ans;
  a1 = a % 0x100;
  a = a / 0x100;
  a2 = a % 0x100;
  a = a / 0x100;
  a3 = a % 0x100;
  a = a / 0x100;
  a4 = a % 0x100;
  ans = a4 + a3 * 0x100 + a2 * 0x10000 + a1 * 0x1000000;
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L3
  jmp    L55
L46:
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L79
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L46
  jmp    L79
L11:
  subl   $0x1,-0x8(%rbp)
L79:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L11
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L55
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L55:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L21
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <sort>
L3:
  nop
  leave
  ret
```

assistant: ```c
void sort(char *s, int start, int last) {
  int i, j, pivot;
  pivot = s[start];
  i = start + 1;
  j = last;
  if (start < last) {
    while (i < j) {
      while ((s[i] < pivot) && (i < last))
        i++;
      while ((s[j] >= pivot))
        j--;
      if (i < j) {
        swap(s, i, j);
      }
    }
    swap(s, j, start);
    sort(s, j + 1, last);
    sort(s, start, j - 1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<sort>:
  endbr64
  cmp    %edx,%esi
  jge    L10
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r15d
  mov    %edx,%r14d
  lea    0x1(%rsi),%r12d
  cmp    %edx,%r12d
  jge    L75
  movslq %esi,%rax
  movzbl (%rdi,%rax,1),%ebp
  mov    %edx,%r13d
  jmp    L81
L70:
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
L81:
  movslq %r12d,%rax
  cmp    (%rbx,%rax,1),%bpl
  jle    L94
  cmp    %r12d,%r14d
  setg   %dl
  lea    0x1(%r12),%eax
  cltq
  test   %dl,%dl
  je     L94
L26:
  mov    %eax,%r12d
  cmp    (%rbx,%rax,1),%bpl
  setg   %cl
  cmp    %eax,%r14d
  setg   %dl
  add    $0x1,%rax
  test   %dl,%cl
  jne    L26
L94:
  movslq %r13d,%rax
  cmp    (%rbx,%rax,1),%bpl
  jg     L73
  lea    -0x1(%r13),%eax
  cltq
L62:
  mov    %eax,%r13d
  sub    $0x1,%rax
  cmp    0x1(%rbx,%rax,1),%bpl
  jle    L62
L73:
  cmp    %r13d,%r12d
  jl     L70
L56:
  mov    %r15d,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <swap@plt>
  lea    0x1(%r13),%esi
  mov    %r14d,%edx
  mov    %rbx,%rdi
  call   <sort>
  lea    -0x1(%r13),%edx
  mov    %r15d,%esi
  mov    %rbx,%rdi
  call   <sort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L75:
  mov    %edx,%r13d
  jmp    L56
L10:
  ret
```

assistant: ```c
void sort(char *s, int start, int last) {
  int i, j, pivot;
  pivot = s[start];
  i = start + 1;
  j = last;
  if (start < last) {
    while (i < j) {
      while ((s[i] < pivot) && (i < last))
        i++;
      while ((s[j] >= pivot))
        j--;
      if (i < j) {
        swap(s, i, j);
      }
    }
    swap(s, j, start);
    sort(s, j + 1, last);
    sort(s, start, j - 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rax,%rbx
  add    %rdi,%rax
  lea    0x1(%rbx),%ecx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  mov    %ecx,0x4(%rsp)
  cmp    %edx,%ebx
  jge    L54
  movzbl (%rax),%r14d
  mov    %rdi,%r13
  mov    %edx,%r12d
L18:
  mov    0x4(%rsp),%eax
  mov    %r12d,%ebp
  mov    %eax,%r15d
  cmp    %r12d,%eax
  jge    L89
L38:
  movslq %r15d,%rax
  cmp    %r14b,0x0(%r13,%rax,1)
  jge    L11
  cmp    %r12d,%r15d
  lea    0x1(%r15),%eax
  setl   %dl
  cltq
  test   %dl,%dl
  je     L11
  nopw   0x0(%rax,%rax,1)
L67:
  cmp    %r14b,0x0(%r13,%rax,1)
  mov    %eax,%r15d
  setl   %sil
  cmp    %eax,%r12d
  setg   %dl
  add    $0x1,%rax
  test   %dl,%sil
  jne    L67
L11:
  movslq %ebp,%rax
  cmp    %r14b,0x0(%r13,%rax,1)
  jl     L41
  lea    -0x1(%rbp),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %eax,%ebp
  sub    $0x1,%rax
  cmp    %r14b,0x1(%r13,%rax,1)
  jge    L5
L41:
  cmp    %ebp,%r15d
  jl     L62
L89:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  lea    0x1(%rbp),%esi
  mov    %r13,%rdi
  call   <sort>
  lea    -0x1(%rbp),%r12d
  cmp    %ebx,%r12d
  jle    L54
  mov    0x8(%rsp),%rax
  movzbl (%rax),%r14d
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  jmp    L38
L54:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(char *s, int start, int last) {
  int i, j, pivot;
  pivot = s[start];
  i = start + 1;
  j = last;
  if (start < last) {
    while (i < j) {
      while ((s[i] < pivot) && (i < last))
        i++;
      while ((s[j] >= pivot))
        j--;
      if (i < j) {
        swap(s, i, j);
      }
    }
    swap(s, j, start);
    sort(s, j + 1, last);
    sort(s, start, j - 1);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort>:
  endbr64
  push   %r15
  movslq %esi,%rax
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rax,%rbx
  add    %rdi,%rax
  lea    0x1(%rbx),%ecx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  mov    %ecx,0x4(%rsp)
  cmp    %edx,%ebx
  jge    L71
  movzbl (%rax),%r14d
  mov    %rdi,%r13
  mov    %edx,%r12d
L97:
  mov    0x4(%rsp),%eax
  mov    %r12d,%ebp
  mov    %eax,%r15d
  cmp    %r12d,%eax
  jge    L84
L91:
  movslq %r15d,%rax
  cmp    %r14b,0x0(%r13,%rax,1)
  jge    L42
  cmp    %r12d,%r15d
  lea    0x1(%r15),%eax
  setl   %dl
  cltq
  test   %dl,%dl
  je     L42
  nopw   0x0(%rax,%rax,1)
L98:
  cmp    %r14b,0x0(%r13,%rax,1)
  mov    %eax,%r15d
  setl   %sil
  cmp    %eax,%r12d
  setg   %dl
  add    $0x1,%rax
  test   %dl,%sil
  jne    L98
L42:
  movslq %ebp,%rax
  cmp    %r14b,0x0(%r13,%rax,1)
  jl     L49
  lea    -0x1(%rbp),%eax
  cltq
  nopw   0x0(%rax,%rax,1)
L24:
  mov    %eax,%ebp
  sub    $0x1,%rax
  cmp    %r14b,0x1(%r13,%rax,1)
  jge    L24
L49:
  cmp    %ebp,%r15d
  jl     L8
L84:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  lea    0x1(%rbp),%esi
  mov    %r13,%rdi
  call   <sort>
  lea    -0x1(%rbp),%r12d
  cmp    %ebx,%r12d
  jle    L71
  mov    0x8(%rsp),%rax
  movzbl (%rax),%r14d
  jmp    L97
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebp,%edx
  mov    %r15d,%esi
  mov    %r13,%rdi
  call   <swap@plt>
  jmp    L91
L71:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void sort(char *s, int start, int last) {
  int i, j, pivot;
  pivot = s[start];
  i = start + 1;
  j = last;
  if (start < last) {
    while (i < j) {
      while ((s[i] < pivot) && (i < last))
        i++;
      while ((s[j] >= pivot))
        j--;
      if (i < j) {
        swap(s, i, j);
      }
    }
    swap(s, j, start);
    sort(s, j + 1, last);
    sort(s, start, j - 1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_ip_from_hostname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L2:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: Host "%s" not found


assistant: ```c
char *get_ip_from_hostname(char *hostname) {
  struct hostent *he = gethostbyname(hostname);
  if (he == NULL) {
    printf("Host \"%s\" not found\n", hostname);
    exit(1);
  }
  struct in_addr **addr_list = (struct in_addr **)he->h_addr_list;
  return inet_ntoa(*addr_list[0]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_ip_from_hostname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <gethostbyname@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L4:
  mov    (%rbx),%rax
  mov    (%rax),%rax
  mov    (%rax),%edi
  call   <inet_ntoa@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Host "%s" not found


assistant: ```c
char *get_ip_from_hostname(char *hostname) {
  struct hostent *he = gethostbyname(hostname);
  if (he == NULL) {
    printf("Host \"%s\" not found\n", hostname);
    exit(1);
  }
  struct in_addr **addr_list = (struct in_addr **)he->h_addr_list;
  return inet_ntoa(*addr_list[0]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_ip_from_hostname>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <gethostbyname@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L18
L2:
  mov    (%rbx),%rax
  mov    (%rax),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <inet_ntoa@plt>
  nopl   (%rax)
L18:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string

tool: D7: Host "%s" not found


assistant: ```c
char *get_ip_from_hostname(char *hostname) {
  struct hostent *he = gethostbyname(hostname);
  if (he == NULL) {
    printf("Host \"%s\" not found\n", hostname);
    exit(1);
  }
  struct in_addr **addr_list = (struct in_addr **)he->h_addr_list;
  return inet_ntoa(*addr_list[0]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ip_from_hostname>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <gethostbyname@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L6
L12:
  mov    (%rbx),%rax
  mov    (%rax),%rax
  mov    (%rax),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <inet_ntoa@plt>
  nopl   (%rax)
L6:
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L12
```

tool_calls: name: disassemble_data
arguments: tag: D5
data_type: string

tool: D5: Host "%s" not found


assistant: ```c
char *get_ip_from_hostname(char *hostname) {
  struct hostent *he = gethostbyname(hostname);
  if (he == NULL) {
    printf("Host \"%s\" not found\n", hostname);
    exit(1);
  }
  struct in_addr **addr_list = (struct in_addr **)he->h_addr_list;
  return inet_ntoa(*addr_list[0]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sendResponseToClient>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  lea    -0x10(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L4
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <fatalError@plt>
L4:
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  jne    L53
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L72
L53:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <fatalError@plt>
L72:
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  je     L46
  mov    -0x10(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L57
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <fatalError@plt>
L57:
  lea    -0x14(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x4,-0xc(%rbp)
  jne    L65
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L46
L65:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <fatalError@plt>
L46:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D23
type_infered: string
name: retrieve_data
arguments: label: D26
type_infered: string
name: retrieve_data
arguments: label: D33
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string

tool: D23: Response sending error 1

tool: D26: Response sending error 2

tool: D33: Response sending error 3

tool: D0: Response sending error 4

assistant: ```c
int sendResponseToClient(int socketFD, char *answer) {
  int serverResponse = 0;
  int answerLength = strlen(answer) + 1;
  int n = 0;
  if (write(socketFD, &answerLength, 4) == -1)
    fatalError("Response sending error 1");
  n = read(socketFD, &serverResponse, 4);
  if (n != 4 || serverResponse != 0)
    fatalError("Response sending error 2");
  if (answerLength != 1) {
    if ((n = write(socketFD, answer, answerLength)) == -1)
      fatalError("Response sending error 3");
    n = read(socketFD, &serverResponse, 4);
    if (n != 4 || serverResponse != 0)
      fatalError("Response sending error 4");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sendResponseToClient>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    %rsi,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L31
L59:
  mov    %rsp,%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x4,%eax
  jne    L7
  cmpl   $0x0,(%rsp)
  je     L85
L7:
  lea    D6(%rip),%rdi
  call   <fatalError@plt>
L85:
  mov    0x4(%rsp),%edx
  cmp    $0x1,%edx
  jne    L45
L75:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  lea    D12(%rip),%rdi
  call   <fatalError@plt>
  jmp    L59
L45:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L10
L0:
  mov    %rsp,%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  call   <read@plt>
  cmp    $0x4,%eax
  jne    L14
  cmpl   $0x0,(%rsp)
  je     L75
L14:
  lea    D20(%rip),%rdi
  call   <fatalError@plt>
  jmp    L75
L10:
  lea    D37(%rip),%rdi
  call   <fatalError@plt>
  jmp    L0
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D12
type: string
name: parse_data
arguments: data_label: D20
type: string
name: parse_data
arguments: data_label: D37
type: string

tool: D6: Response sending error 2

tool: D12: Response sending error 1

tool: D20: Response sending error 4

tool: D37: Response sending error 3

assistant: ```c
int sendResponseToClient(int socketFD, char *answer) {
  int serverResponse = 0;
  int answerLength = strlen(answer) + 1;
  int n = 0;
  if (write(socketFD, &answerLength, 4) == -1)
    fatalError("Response sending error 1");
  n = read(socketFD, &serverResponse, 4);
  if (n != 4 || serverResponse != 0)
    fatalError("Response sending error 2");
  if (answerLength != 1) {
    if ((n = write(socketFD, answer, answerLength)) == -1)
      fatalError("Response sending error 3");
    n = read(socketFD, &serverResponse, 4);
    if (n != 4 || serverResponse != 0)
      fatalError("Response sending error 4");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sendResponseToClient>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rsi,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  call   <strlen@plt>
  lea    0x4(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebp,%edi
  add    $0x1,%eax
  mov    %eax,0x4(%rsp)
  xor    %eax,%eax
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L88
L95:
  mov    %rsp,%r13
  mov    $0x4,%edx
  mov    %ebp,%edi
  mov    %r13,%rsi
  call   <read@plt>
  cmp    $0x4,%eax
  jne    L106
  mov    (%rsp),%edx
  test   %edx,%edx
  jne    L106
  mov    0x4(%rsp),%edx
  cmp    $0x1,%edx
  jne    L104
  nopl   0x0(%rax,%rax,1)
L66:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L106:
  lea    D8(%rip),%rdi
  call   <fatalError@plt>
  mov    0x4(%rsp),%edx
  cmp    $0x1,%edx
  je     L66
L104:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L62
L14:
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %ebp,%edi
  call   <read@plt>
  cmp    $0x4,%eax
  jne    L99
  mov    (%rsp),%eax
  test   %eax,%eax
  je     L66
L99:
  lea    D7(%rip),%rdi
  call   <fatalError@plt>
  jmp    L66
  nop
L88:
  lea    D3(%rip),%rdi
  call   <fatalError@plt>
  jmp    L95
  nopl   0x0(%rax)
L62:
  lea    D28(%rip),%rdi
  call   <fatalError@plt>
  jmp    L14
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string
name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D28
data_type: string

tool: D8: Response sending error 2

tool: D7: Response sending error 4

tool: D3: Response sending error 1

tool: D28: Response sending error 3

assistant: ```c
int sendResponseToClient(int socketFD, char *answer) {
  int serverResponse = 0;
  int answerLength = strlen(answer) + 1;
  int n = 0;
  if (write(socketFD, &answerLength, 4) == -1)
    fatalError("Response sending error 1");
  n = read(socketFD, &serverResponse, 4);
  if (n != 4 || serverResponse != 0)
    fatalError("Response sending error 2");
  if (answerLength != 1) {
    if ((n = write(socketFD, answer, answerLength)) == -1)
      fatalError("Response sending error 3");
    n = read(socketFD, &serverResponse, 4);
    if (n != 4 || serverResponse != 0)
      fatalError("Response sending error 4");
  }
  return 0;
}
```