ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<skip_to>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <ftell@plt>
  cmp    %r12,%rax
  jge    L85
  mov    %r12,%rbx
  sub    %rax,%rbx
  mov    D13(%rip),%rax
  cmp    (%rax),%rbx
  jle    L90
L85:
  mov    D19(%rip),%rax
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    (%rax),%edx
  call   <fseek@plt>
L86:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L91
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L90:
  lea    0xf(%rbx),%rax
  mov    %rsp,%rcx
  mov    %rsp,%r14
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  and    $0xfffffffffffffff0,%rdx
  sub    %rax,%rcx
L49:
  cmp    %rcx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L49
  nopl   0x0(%rax)
L9:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L4
L10:
  mov    %r13,%rcx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <fread@plt>
  cmp    %rbx,%rax
  jne    L73
  mov    %r14,%rsp
  jmp    L85
  cs nopw 0x0(%rax,%rax,1)
L4:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L10
L73:
  mov    %r14,%rsp
  mov    $0xffffffff,%eax
  jmp    L86
L91:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int skip_to(FILE *file, long offset) {
  long old_offset;
  old_offset = ftell(file);
  if (offset > old_offset && offset - old_offset <= BUFSIZ) {
    size_t skip_bytes = offset - old_offset;
    char buf[skip_bytes];
    if (fread(buf, skip_bytes, 1, file) != skip_bytes)
      return -1;
  }
  return fseek(file, offset, SEEK_SET);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <_cleanup@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_exit@plt>
```

assistant: ```c
void exit(code) int code;
{
  _cleanup();
  _exit(code);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <_cleanup@plt>
  mov    %ebx,%edi
  call   <_exit@plt>
```

assistant: ```c
void exit(code) int code;
{
  _cleanup();
  _exit(code);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <_cleanup@plt>
  mov    %ebp,%edi
  call   <_exit@plt>
```

assistant: ```c
void exit(code) int code;
{
  _cleanup();
  _exit(code);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<exit>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <_cleanup@plt>
  mov    %ebp,%edi
  call   <_exit@plt>
```

assistant: ```c
void exit(code) int code;
{
  _cleanup();
  _exit(code);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ztrim_left>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L4:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L3
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L49
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L4
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  jne    L4
L3:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ztrim_left(char *str) {
  char *np;
  for (np = str; *np && (((isascii(*np) && isspace(*np)) || iscntrl(*np))); np++)
    ;
  ;
  return np;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ztrim_left>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L16
L28:
  mov    %rbx,%rax
  pop    %rbx
  ret
L37:
  movsbl (%rbx),%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  je     L28
L41:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L28
L16:
  movsbl %dil,%edi
  call   <isascii@plt>
  test   %rax,%rax
  je     L37
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  jmp    L37
```

assistant: ```c
char *ztrim_left(char *str) {
  char *np;
  for (np = str; *np && (((isascii(*np) && isspace(*np)) || iscntrl(*np))); np++)
    ;
  ;
  return np;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ztrim_left>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L29
  nopl   0x0(%rax)
L8:
  call   <isascii@plt>
  test   %rax,%rax
  je     L17
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
L17:
  movsbl (%r12),%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  je     L29
L14:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L8
L29:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ztrim_left(char *str) {
  char *np;
  for (np = str; *np && (((isascii(*np) && isspace(*np)) || iscntrl(*np))); np++)
    ;
  ;
  return np;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ztrim_left>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L21
  nopl   0x0(%rax)
L41:
  call   <isascii@plt>
  test   %rax,%rax
  je     L48
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L10
L48:
  movsbl (%r12),%edi
  call   <iscntrl@plt>
  test   %rax,%rax
  je     L21
L10:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  jne    L41
L21:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *ztrim_left(char *str) {
  char *np;
  for (np = str; *np && (((isascii(*np) && isspace(*np)) || iscntrl(*np))); np++)
    ;
  ;
  return np;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<putop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <getop@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L26:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L26
  jmp    L8
L25:
  mov    $0x20,%edi
  call   <putchar@plt>
  addl   $0x1,-0x10(%rbp)
L8:
  cmpl   $0x3,-0x10(%rbp)
  jle    L25
  nop
  leave
  ret
```

assistant: ```c
putop(n) {
  char *p;
  int i, c;
  p = getop(n);
  for (i = 0; (c = *p++) != '\0'; i++)
    putchar(c);
  for (; i < 4; i++)
    putchar(' ');
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<putop>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <getop@plt>
  mov    %eax,%r12d
  cltq
  lea    0x1(%rax),%rbx
  movsbl (%rax),%edi
  test   %edi,%edi
  je     L42
L46:
  call   <putchar@plt>
  mov    %ebx,%ebp
  sub    %r12d,%ebp
  mov    %rbx,%rax
  add    $0x1,%rbx
  movsbl (%rax),%edi
  test   %edi,%edi
  jne    L46
  cmp    $0x3,%ebp
  jg     L35
L12:
  mov    $0x20,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    $0x3,%ebp
  jle    L12
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  mov    %edi,%ebp
  jmp    L12
```

assistant: ```c
putop(n) {
  char *p;
  int i, c;
  p = getop(n);
  for (i = 0; (c = *p++) != '\0'; i++)
    putchar(c);
  for (; i < 4; i++)
    putchar(' ');
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<putop>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <getop@plt>
  mov    %eax,%r12d
  cltq
  movsbl (%rax),%edi
  test   %edi,%edi
  je     L18
  lea    0x1(%rax),%rbx
  nop
L11:
  call   <putchar@plt>
  mov    %rbx,%rax
  mov    %ebx,%ebp
  add    $0x1,%rbx
  movsbl (%rax),%edi
  sub    %r12d,%ebp
  test   %edi,%edi
  jne    L11
  cmp    $0x3,%ebp
  jg     L40
  nopl   (%rax)
L42:
  mov    $0x20,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    $0x4,%ebp
  jne    L42
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  xor    %ebp,%ebp
  jmp    L42
```

assistant: ```c
putop(n) {
  char *p;
  int i, c;
  p = getop(n);
  for (i = 0; (c = *p++) != '\0'; i++)
    putchar(c);
  for (; i < 4; i++)
    putchar(' ');
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<putop>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  call   <getop@plt>
  mov    %eax,%r12d
  cltq
  movsbl (%rax),%edi
  test   %edi,%edi
  je     L27
  lea    0x1(%rax),%rbx
  nop
L16:
  call   <putchar@plt>
  mov    %rbx,%rax
  mov    %ebx,%ebp
  add    $0x1,%rbx
  movsbl (%rax),%edi
  sub    %r12d,%ebp
  test   %edi,%edi
  jne    L16
  cmp    $0x3,%ebp
  jg     L18
  nopl   (%rax)
L14:
  mov    $0x20,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    $0x4,%ebp
  jne    L14
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %ebp,%ebp
  jmp    L14
```

assistant: ```c
putop(n) {
  char *p;
  int i, c;
  p = getop(n);
  for (i = 0; (c = *p++) != '\0'; i++)
    putchar(c);
  for (; i < 4; i++)
    putchar(' ');
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tu_malloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L10
  addq   $0x1,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L18:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type_guessed: string

tool: D0: Out of memory

assistant: ```c
void *tu_malloc(size_t sz) {
  void *m;
  if (!sz)
    sz++;
  if (m = malloc(sz), !m)
    die("Out of memory");
  memset(m, 0, sz);
  return m;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tu_malloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  mov    $0x1,%eax
  cmovne %rdi,%rax
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L11
L5:
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  lea    D6(%rip),%rdi
  call   <die@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: label: D6
type_guessed: string

tool: D6: Out of memory

assistant: ```c
void *tu_malloc(size_t sz) {
  void *m;
  if (!sz)
    sz++;
  if (m = malloc(sz), !m)
    die("Out of memory");
  memset(m, 0, sz);
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tu_malloc>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  cmovne %rdi,%rax
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L5:
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L17:
  lea    D5(%rip),%rdi
  call   <die@plt>
  jmp    L5
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: Out of memory

assistant: ```c
void *tu_malloc(size_t sz) {
  void *m;
  if (!sz)
    sz++;
  if (m = malloc(sz), !m)
    die("Out of memory");
  memset(m, 0, sz);
  return m;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tu_malloc>:
  endbr64
  push   %r13
  mov    $0x1,%eax
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  cmovne %rdi,%rax
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
L4:
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %esi,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
L0:
  lea    D8(%rip),%rdi
  call   <die@plt>
  jmp    L4
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D8: Out of memory

assistant: ```c
void *tu_malloc(size_t sz) {
  void *m;
  if (!sz)
    sz++;
  if (m = malloc(sz), !m)
    die("Out of memory");
  memset(m, 0, sz);
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <config@plt>
  test   %rax,%rax
  je     L16
  mov    $0x1,%eax
  jmp    L19
L16:
  mov    $0xa,%edi
  call   <wi_start@plt>
  mov    $0x0,%eax
  call   <main_loop@plt>
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (config())
    return 1;
  wi_start(10);
  main_loop();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <config@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L15
L7:
  add    $0x8,%rsp
  ret
L15:
  mov    $0xa,%edi
  call   <wi_start@plt>
  mov    $0x0,%eax
  call   <main_loop@plt>
  mov    $0x0,%eax
  jmp    L7
```

assistant: ```c
int main() {
  if (config())
    return 1;
  wi_start(10);
  main_loop();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <config@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L3
  mov    $0xa,%edi
  call   <wi_start@plt>
  xor    %eax,%eax
  call   <main_loop@plt>
  xor    %eax,%eax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (config())
    return 1;
  wi_start(10);
  main_loop();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <config@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  jne    L3
  mov    $0xa,%edi
  call   <wi_start@plt>
  xor    %eax,%eax
  call   <main_loop@plt>
  xor    %eax,%eax
L3:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (config())
    return 1;
  wi_start(10);
  main_loop();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L27
L20:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  comisd %xmm1,%xmm0
  jbe    L38
  mov    -0x8(%rbp),%eax
  jmp    L23
L38:
  mov    -0x4(%rbp),%eax
L23:
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double find_min(double *array, int n) {
  int i;
  int j = 0;
  for (i = 0; i < n; i++) {
    j = (array[j] > array[i]) ? i : j;
  }
  return array[j];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<find_min>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %esi,%esi
  mov    $0x0,%eax
  mov    $0x0,%edx
L26:
  movslq %edx,%rcx
  movsd  (%rdi,%rcx,8),%xmm0
  ucomisd (%rdi,%rax,8),%xmm0
  cmova  %eax,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L26
L1:
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm0
  ret
L16:
  mov    $0x0,%edx
  jmp    L1
```

assistant: ```c
double find_min(double *array, int n) {
  int i;
  int j = 0;
  for (i = 0; i < n; i++) {
    j = (array[j] > array[i]) ? i : j;
  }
  return array[j];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<find_min>:
  endbr64
  movsd  (%rdi),%xmm0
  test   %esi,%esi
  jle    L12
  add    $0x8,%rdi
  lea    -0x1(%rsi),%eax
  lea    (%rdi,%rax,8),%rax
  jmp    L24
  nopl   0x0(%rax)
L15:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
L24:
  cmp    %rdi,%rax
  jne    L15
L12:
  ret
```

assistant: ```c
double find_min(double *array, int n) {
  int i;
  int j = 0;
  for (i = 0; i < n; i++) {
    j = (array[j] > array[i]) ? i : j;
  }
  return array[j];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_min>:
  endbr64
  movsd  (%rdi),%xmm0
  test   %esi,%esi
  jle    L19
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  nopl   0x0(%rax)
L15:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L15
L19:
  ret
```

assistant: ```c
double find_min(double *array, int n) {
  int i;
  int j = 0;
  for (i = 0; i < n; i++) {
    j = (array[j] > array[i]) ? i : j;
  }
  return array[j];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<auto_indent>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L11:
  mov    $0x9,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void auto_indent(int levels) {
  for (int i = 0; i < levels; i++)
    putchar('\t');
}
```
user: What is the c source code of the assembly code below?

```asm
<auto_indent>:
  endbr64
  test   %edi,%edi
  jle    L19
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L18:
  mov    $0x9,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L18
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  ret
```

assistant: ```c
void auto_indent(int levels) {
  for (int i = 0; i < levels; i++)
    putchar('\t');
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<auto_indent>:
  endbr64
  test   %edi,%edi
  jle    L14
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x9,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L14:
  ret
```

assistant: ```c
void auto_indent(int levels) {
  for (int i = 0; i < levels; i++)
    putchar('\t');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<auto_indent>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x9,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  ret
```

assistant: ```c
void auto_indent(int levels) {
  for (int i = 0; i < levels; i++)
    putchar('\t');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<AstAlg_mean_solar_longitude>:
  endbr64
  ucomisd D30(%rip),%xmm0
  jp     L11
  movsd  D54(%rip),%xmm1
  je     L21
L11:
  movapd %xmm0,%xmm2
  subsd  D66(%rip),%xmm2
  divsd  D102(%rip),%xmm2
  pxor   %xmm3,%xmm3
  movapd %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  subsd  D91(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  D113(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D51(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D68(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D60(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D122(%rip),%xmm1
  cvttsd2si %xmm1,%rcx
  pxor   %xmm2,%xmm2
  cvtsi2sd %rcx,%xmm2
  subsd  %xmm2,%xmm1
  movabs $0x2d82d82d82d82d83,%rdx
  mov    %rcx,%rax
  imul   %rdx
  sar    $0x6,%rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  imul   $0x168,%rdx,%rdx
  sub    %rdx,%rcx
  pxor   %xmm2,%xmm2
  cvtsi2sd %rcx,%xmm2
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm3
  ja     L9
L28:
  movsd  %xmm0,D3(%rip)
  movsd  %xmm1,D3(%rip)
L21:
  movapd %xmm1,%xmm0
  ret
L9:
  addsd  D3(%rip),%xmm1
  jmp    L28
```

tool_calls: name: read_data
arguments: tag: D66
type_infered: f64
name: read_data
arguments: tag: D102
type_infered: f64
name: read_data
arguments: tag: D91
type_infered: byte[8]
name: read_data
arguments: tag: D113
type_infered: byte[8]
name: read_data
arguments: tag: D51
type_infered: byte[8]
name: read_data
arguments: tag: D68
type_infered: f64
name: read_data
arguments: tag: D60
type_infered: f64
name: read_data
arguments: tag: D122
type_infered: f64
name: read_data
arguments: tag: D3
type_infered: f64

tool: D66: 2451545

tool: D102: 365250

tool: {"D91": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xa0,0x3e]}

tool: {"D113": [0x5d,0x6b,0x55,0x44,0x33,0x22,0x11,0x3f]}

tool: {"D51": [0x07,0x1e,0x33,0xd0,0x20,0x00,0xf5,0x3e]}

tool: D68: 0.03032028

tool: D60: 360007.6982779

tool: D122: 280.4664567

tool: D3: 360

assistant: ```c
double AstAlg_mean_solar_longitude(double jd) {
  static double last_jd, last_sl;
  static const double coefs[] = {280.4664567, 360007.6982779, 0.03032028, 2.00276381406e-5, -6.53594771242e-5, -0.50e-6};
  double tau, sl;
  int i;
  if (jd == last_jd)
    return last_sl;
  tau = (jd - (2451545.0)) / 365250.0;
  sl = 0.0;
  for (i = 5; i >= 0; i--) {
    sl = tau * sl + coefs[i];
  }
  sl = ((double)((((long)sl) % ((long)360)) + (sl - (long)sl)));
  if (sl < 0.0)
    sl = sl + 360.0;
  last_jd = jd;
  last_sl = sl;
  return sl;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<AstAlg_mean_solar_longitude>:
  endbr64
  ucomisd D43(%rip),%xmm0
  jp     L13
  movsd  D68(%rip),%xmm1
  je     L14
L13:
  pxor   %xmm3,%xmm3
  movapd %xmm0,%xmm2
  subsd  D67(%rip),%xmm2
  divsd  D87(%rip),%xmm2
  movabs $0x2d82d82d82d82d83,%rdx
  movapd %xmm2,%xmm1
  mulsd  %xmm3,%xmm1
  subsd  D117(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  D104(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D36(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D72(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  D96(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  addsd  D25(%rip),%xmm1
  cvttsd2si %xmm1,%rcx
  mov    %rcx,%rax
  cvtsi2sd %rcx,%xmm2
  imul   %rdx
  mov    %rcx,%rax
  sar    $0x3f,%rax
  sar    $0x6,%rdx
  subsd  %xmm2,%xmm1
  pxor   %xmm2,%xmm2
  sub    %rax,%rdx
  imul   $0x168,%rdx,%rdx
  sub    %rdx,%rcx
  cvtsi2sd %rcx,%xmm2
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm3
  ja     L37
L19:
  movsd  %xmm0,D69(%rip)
  movsd  %xmm1,D69(%rip)
L14:
  movapd %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  addsd  D69(%rip),%xmm1
  jmp    L19
```

tool_calls: name: read_data
arguments: data_label: D67
data_type: f64
name: read_data
arguments: data_label: D87
data_type: f64
name: read_data
arguments: data_label: D117
data_type: byte[8]
name: read_data
arguments: data_label: D104
data_type: byte[8]
name: read_data
arguments: data_label: D36
data_type: byte[8]
name: read_data
arguments: data_label: D72
data_type: f64
name: read_data
arguments: data_label: D96
data_type: f64
name: read_data
arguments: data_label: D25
data_type: f64
name: read_data
arguments: data_label: D69
data_type: f64

tool: D67: 2451545

tool: D87: 365250

tool: {"D117": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xa0,0x3e]}

tool: {"D104": [0x5d,0x6b,0x55,0x44,0x33,0x22,0x11,0x3f]}

tool: {"D36": [0x07,0x1e,0x33,0xd0,0x20,0x00,0xf5,0x3e]}

tool: D72: 0.03032028

tool: D96: 360007.6982779

tool: D25: 280.4664567

tool: D69: 360

assistant: ```c
double AstAlg_mean_solar_longitude(double jd) {
  static double last_jd, last_sl;
  static const double coefs[] = {280.4664567, 360007.6982779, 0.03032028, 2.00276381406e-5, -6.53594771242e-5, -0.50e-6};
  double tau, sl;
  int i;
  if (jd == last_jd)
    return last_sl;
  tau = (jd - (2451545.0)) / 365250.0;
  sl = 0.0;
  for (i = 5; i >= 0; i--) {
    sl = tau * sl + coefs[i];
  }
  sl = ((double)((((long)sl) % ((long)360)) + (sl - (long)sl)));
  if (sl < 0.0)
    sl = sl + 360.0;
  last_jd = jd;
  last_sl = sl;
  return sl;
}
```