ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<prtype>:
  endbr64
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  and    $0xf,%esi
  cmp    $0x4,%esi
  ja     L5
  lea    D55(%rip),%rdx
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L5:
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L48:
  mov    %ebx,%eax
  and    $0x30,%eax
  and    $0x20,%ebx
  jne    L60
  cmp    $0x10,%eax
  je     L11
  pop    %rbx
  ret
  nopl   0x0(%rax)
L60:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  mov    $0x2a,%edi
  pop    %rbx
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
  lea    D69(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L48
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D6
datatype: string
name: read_data
arguments: data_tag: D35
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string
name: read_data
arguments: data_tag: D69
datatype: string
name: read_data
arguments: data_tag: D57
datatype: string

tool: D2: ?type%d 

tool: D6: far *

tool: D35: short 

tool: D7: long 

tool: D69: void 

tool: D57: char 

assistant: ```c
void prtype(int type) {
  switch (type & 0x0f) {
  case 0:
    break;
  case 1:
    printf("void ");
    break;
  case 2:
    printf("char ");
    break;
  case 3:
    printf("short ");
    break;
  case 4:
    printf("long ");
    break;
  default:
    printf("?type%d ", type & 0x0f);
    break;
  }
  switch (type & (0x10 | 0x20)) {
  case 0:
    break;
  case 0x10:
    printf("*");
    break;
  case 0x20:
    printf("far *");
    break;
  case 0x10 | 0x20:
    printf("far *");
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prtype>:
  endbr64
  mov    %edi,%esi
  push   %rbx
  mov    %edi,%ebx
  and    $0xf,%esi
  cmp    $0x4,%esi
  ja     L34
  lea    D4(%rip),%rdx
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L34:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L11:
  mov    %ebx,%eax
  and    $0x30,%eax
  and    $0x20,%ebx
  jne    L58
  cmp    $0x10,%eax
  je     L24
  pop    %rbx
  ret
  nopl   0x0(%rax)
L58:
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L24:
  mov    $0x2a,%edi
  pop    %rbx
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
  lea    D46(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
  lea    D63(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D44
datatype: string
name: disassemble_data
arguments: data_tag: D46
datatype: string
name: disassemble_data
arguments: data_tag: D63
datatype: string
name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D0: ?type%d 

tool: D44: far *

tool: D46: short 

tool: D63: long 

tool: D16: void 

tool: D9: char 

assistant: ```c
void prtype(int type) {
  switch (type & 0x0f) {
  case 0:
    break;
  case 1:
    printf("void ");
    break;
  case 2:
    printf("char ");
    break;
  case 3:
    printf("short ");
    break;
  case 4:
    printf("long ");
    break;
  default:
    printf("?type%d ", type & 0x0f);
    break;
  }
  switch (type & (0x10 | 0x20)) {
  case 0:
    break;
  case 0x10:
    printf("*");
    break;
  case 0x20:
    printf("far *");
    break;
  case 0x10 | 0x20:
    printf("far *");
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fix_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L12
L2:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  and    $0xf,%eax
  test   %rax,%rax
  jne    L2
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int fix_size(size_t size) {
  while ((size & 0x0F) != 0)
    size++;
  return size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fix_size>:
  endbr64
  mov    %rdi,%rax
  test   $0xf,%al
  je     L3
L9:
  add    $0x1,%rax
  test   $0xf,%al
  jne    L9
L3:
  ret
```

assistant: ```c
int fix_size(size_t size) {
  while ((size & 0x0F) != 0)
    size++;
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fix_size>:
  endbr64
  mov    %rdi,%rax
  test   $0xf,%al
  je     L13
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%rax
  test   $0xf,%al
  jne    L6
L13:
  ret
```

assistant: ```c
int fix_size(size_t size) {
  while ((size & 0x0F) != 0)
    size++;
  return size;
}
```
user: What is the c source code of the assembly code below?

```asm
<fix_size>:
  endbr64
  mov    %rdi,%rax
  test   $0xf,%al
  je     L19
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x1,%rax
  test   $0xf,%al
  jne    L2
L19:
  ret
```

assistant: ```c
int fix_size(size_t size) {
  while ((size & 0x0F) != 0)
    size++;
  return size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    $0x38,%edi
  call   <foo@plt>
  cmp    $0x1a,%eax
  je     L9
  mov    $0x0,%eax
  call   <abort@plt>
L9:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_infered: string

tool: D6: abc

assistant: ```c
int main() {
  if (foo(56, "abc") != 26)
    abort();
  exit(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rsi
  mov    $0x38,%edi
  call   <foo@plt>
  cmp    $0x1a,%eax
  jne    L5
L9:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L5:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L9
```

tool_calls: name: read_data
arguments: label: D2
datatype: string

tool: D2: abc

assistant: ```c
int main() {
  if (foo(56, "abc") != 26)
    abort();
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rsi
  mov    $0x38,%edi
  call   <foo@plt>
  cmp    $0x1a,%eax
  je     L4
  xor    %eax,%eax
  call   <abort@plt>
L4:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string

tool: D3: abc

assistant: ```c
int main() {
  if (foo(56, "abc") != 26)
    abort();
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rsi
  mov    $0x38,%edi
  call   <foo@plt>
  cmp    $0x1a,%eax
  je     L9
  xor    %eax,%eax
  call   <abort@plt>
L9:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
data_type: string

tool: D6: abc

assistant: ```c
int main() {
  if (foo(56, "abc") != 26)
    abort();
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<send_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <fflush@plt>
  nop
  leave
  ret
```

assistant: ```c
void send_line(const char *str, void *arg) {
  fputs(str, stdout);
  fflush(stdout);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<send_line>:
  endbr64
  push   %rbx
  mov    D8(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputs@plt>
  mov    (%rbx),%edi
  call   <fflush@plt>
  pop    %rbx
  ret
```

assistant: ```c
void send_line(const char *str, void *arg) {
  fputs(str, stdout);
  fflush(stdout);
}
```
user: What is the c source code of the assembly code below:

```asm
<send_line>:
  endbr64
  push   %rbx
  mov    D6(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputs@plt>
  mov    (%rbx),%edi
  pop    %rbx
  jmp    1070 <fflush@plt>
```

assistant: ```c
void send_line(const char *str, void *arg) {
  fputs(str, stdout);
  fflush(stdout);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<send_line>:
  endbr64
  push   %rbx
  mov    D7(%rip),%rbx
  mov    (%rbx),%esi
  call   <fputs@plt>
  mov    (%rbx),%edi
  pop    %rbx
  jmp    1070 <fflush@plt>
```

assistant: ```c
void send_line(const char *str, void *arg) {
  fputs(str, stdout);
  fflush(stdout);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L28
L3:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L20
L9:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L20:
  cmpl   $0x2,-0x14(%rbp)
  jle    L9
  addl   $0x1,-0x18(%rbp)
L28:
  cmpl   $0x6,-0x18(%rbp)
  jle    L3
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string
name: read_data
arguments: label: D29
data_type: string
name: read_data
arguments: label: D11
data_type: string

tool: D6: dmidrange

tool: D29: # c::%s:len=%d


tool: D11: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmidrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D15(%rip),%r15
  jmp    L9
L24:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L16
L9:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L4:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L4
  jmp    L24
L16:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D25
type: string
name: read_data
arguments: tag: D12
type: string

tool: D15: dmidrange

tool: D25: # c::%s:len=%d


tool: D12: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmidrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D22(%rip),%r15
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L18:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L6:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L6
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L18
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
datatype: string
name: extract_symbolic_data
arguments: data_label: D1
datatype: string
name: extract_symbolic_data
arguments: data_label: D25
datatype: string

tool: D22: dmidrange

tool: D1: # c::%s:len=%d


tool: D25: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmidrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D18(%rip),%r15
  push   %r14
  lea    D29(%rip),%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L7:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L0:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L0
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L7
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D29
type_infered: string
name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D18: dmidrange

tool: D29: # c::%s:len=%d


tool: D8: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dmidrange", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<recover_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movb   $0x0,-0x1d(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_next_line_from_file@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L25
L3:
  movzbl -0x1d(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%ebx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get_bit_from_blank@plt>
  or     %ebx,%eax
  mov    %al,-0x1d(%rbp)
  addl   $0x1,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x7,-0x1c(%rbp)
  jg     L25
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <get_next_line_from_file@plt>
  mov    %rax,-0x18(%rbp)
L25:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L47
  cmpq   $0x0,-0x18(%rbp)
  je     L47
  cmpl   $0x7,-0x1c(%rbp)
  jle    L3
L47:
  movzbl -0x1d(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned char recover_byte(FILE *input_fp) {
  unsigned char retval = 0;
  char *line = NULL;
  int b = 0;
  line = get_next_line_from_file(input_fp);
  while (!feof(input_fp) && line != NULL && b < 8) {
    retval = retval << 1 | get_bit_from_blank(line[strlen(line) - 1]);
    b++;
    free(line);
    if (b < 8) {
      line = get_next_line_from_file(input_fp);
    }
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<recover_byte>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  call   <get_next_line_from_file@plt>
  mov    %rax,%rbx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
L22:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L43
  test   %rbx,%rbx
  je     L43
  cmp    $0x7,%r12d
  jg     L43
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <get_bit_from_blank@plt>
  add    %ebp,%ebp
  or     %eax,%ebp
  add    $0x1,%r12d
  mov    %rbx,%rdi
  call   <free@plt>
  cmp    $0x7,%r12d
  jg     L22
  mov    %r13,%rdi
  call   <get_next_line_from_file@plt>
  mov    %rax,%rbx
  jmp    L22
L43:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char recover_byte(FILE *input_fp) {
  unsigned char retval = 0;
  char *line = NULL;
  int b = 0;
  line = get_next_line_from_file(input_fp);
  while (!feof(input_fp) && line != NULL && b < 8) {
    retval = retval << 1 | get_bit_from_blank(line[strlen(line) - 1]);
    b++;
    free(line);
    if (b < 8) {
      line = get_next_line_from_file(input_fp);
    }
  }
  return retval;
}
```
user: What is the c source code of the assembly code below?

```asm
<recover_byte>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <get_next_line_from_file@plt>
  mov    %rax,%rbx
  xchg   %ax,%ax
L32:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L49
L13:
  test   %rbx,%rbx
  je     L49
  cmp    $0x7,%ebp
  jg     L49
  mov    %rbx,%rdi
  add    %r12d,%r12d
  add    $0x1,%ebp
  call   <strlen@plt>
  cltq
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <get_bit_from_blank@plt>
  mov    %rbx,%rdi
  or     %eax,%r12d
  call   <free@plt>
  cmp    $0x8,%ebp
  je     L32
  mov    %r13,%rdi
  call   <get_next_line_from_file@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <feof@plt>
  test   %eax,%eax
  je     L13
L49:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char recover_byte(FILE *input_fp) {
  unsigned char retval = 0;
  char *line = NULL;
  int b = 0;
  line = get_next_line_from_file(input_fp);
  while (!feof(input_fp) && line != NULL && b < 8) {
    retval = retval << 1 | get_bit_from_blank(line[strlen(line) - 1]);
    b++;
    free(line);
    if (b < 8) {
      line = get_next_line_from_file(input_fp);
    }
  }
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<recover_byte>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  call   <get_next_line_from_file@plt>
  mov    %rax,%rbx
  xchg   %ax,%ax
L47:
  mov    %r13,%rdi
  call   <feof@plt>
  test   %eax,%eax
  jne    L30
L16:
  test   %rbx,%rbx
  je     L30
  cmp    $0x7,%ebp
  jg     L30
  mov    %rbx,%rdi
  add    %r12d,%r12d
  add    $0x1,%ebp
  call   <strlen@plt>
  cltq
  movsbl -0x1(%rbx,%rax,1),%edi
  call   <get_bit_from_blank@plt>
  mov    %rbx,%rdi
  or     %eax,%r12d
  call   <free@plt>
  cmp    $0x8,%ebp
  je     L47
  mov    %r13,%rdi
  call   <get_next_line_from_file@plt>
  mov    %r13,%rdi
  mov    %rax,%rbx
  call   <feof@plt>
  test   %eax,%eax
  je     L16
L30:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char recover_byte(FILE *input_fp) {
  unsigned char retval = 0;
  char *line = NULL;
  int b = 0;
  line = get_next_line_from_file(input_fp);
  while (!feof(input_fp) && line != NULL && b < 8) {
    retval = retval << 1 | get_bit_from_blank(line[strlen(line) - 1]);
    b++;
    free(line);
    if (b < 8) {
      line = get_next_line_from_file(input_fp);
    }
  }
  return retval;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aligned_alloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <posix_memalign@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x10(%rbp),%rax
  jmp    L26
L5:
  mov    $0x0,%eax
L26:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void *aligned_alloc(size_t alignment, size_t size) {
  void *ptr;
  int n = posix_memalign(&ptr, alignment, size);
  return n == 0 ? ptr : NULL;
}
```