ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<dump_utimbuf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x1c(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L9
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x1c(%rbp),%eax
  jmp    L25
L9:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  js     L15
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <dump_long_int_from_mem@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <dump_long_int_from_mem@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
L15:
  lea    -0x1c(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <copy_params@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <free_dumped_params@plt>
  mov    -0x1c(%rbp),%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int dump_utimbuf(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_actime = addr;
  unsigned int arm_tracing_modtime = addr + 4;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_long_int_from_mem(arm_tracing_actime, &dumped_type_params[0], target);
    len += dump_long_int_from_mem(arm_tracing_modtime, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dump_utimbuf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L27
  mov    %esi,%ebx
  mov    %rcx,%r12
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    %rax,%rsi
  mov    %ebx,%edi
  call   <dump_long_int_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x8(%rbp),%rsi
  lea    0x4(%rbx),%edi
  mov    %r12,%rdx
  call   <dump_long_int_from_mem@plt>
  add    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <copy_params@plt>
  mov    %rax,0x0(%r13)
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  mov    $0x0,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L25
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_utimbuf(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_actime = addr;
  unsigned int arm_tracing_modtime = addr + 4;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_long_int_from_mem(arm_tracing_actime, &dumped_type_params[0], target);
    len += dump_long_int_from_mem(arm_tracing_modtime, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<dump_utimbuf>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L4
  mov    $0x10,%edi
  mov    %rcx,%r12
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <dump_long_int_from_mem@plt>
  lea    0x8(%rbp),%rsi
  lea    0x4(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_long_int_from_mem@plt>
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %eax,0x4(%rsp)
  mov    $0x2,%esi
  call   <copy_params@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L4:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L26
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_utimbuf(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_actime = addr;
  unsigned int arm_tracing_modtime = addr + 4;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_long_int_from_mem(arm_tracing_actime, &dumped_type_params[0], target);
    len += dump_long_int_from_mem(arm_tracing_modtime, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dump_utimbuf>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  test   %edi,%edi
  js     L3
  mov    $0x10,%edi
  mov    %rcx,%r12
  mov    %esi,%ebx
  call   <malloc@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <dump_long_int_from_mem@plt>
  lea    0x8(%rbp),%rsi
  lea    0x4(%rbx),%edi
  mov    %r12,%rdx
  add    %eax,0x4(%rsp)
  call   <dump_long_int_from_mem@plt>
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %eax,0x4(%rsp)
  mov    $0x2,%esi
  call   <copy_params@plt>
  mov    $0x2,%esi
  mov    %rbp,%rdi
  mov    %rax,0x0(%r13)
  call   <free_dumped_params@plt>
  mov    0x4(%rsp),%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L3:
  xor    %edi,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    0x4(%rsp),%eax
  jmp    L1
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dump_utimbuf(int depth, unsigned int addr, char **dumped_params, struct target *target) {
  char **dumped_type_params;
  unsigned int arm_tracing_actime = addr;
  unsigned int arm_tracing_modtime = addr + 4;
  int len = 0;
  if (depth < 0) {
    *dumped_params = malloc(0);
    return len;
  }
  dumped_type_params = malloc(2 * (sizeof(char *)));
  if (depth >= 0) {
    len += dump_long_int_from_mem(arm_tracing_actime, &dumped_type_params[0], target);
    len += dump_long_int_from_mem(arm_tracing_modtime, &dumped_type_params[1], target);
  }
  *dumped_params = copy_params(dumped_type_params, 2, &len);
  free_dumped_params(dumped_type_params, 2);
  return len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jg     L21
  mov    $0xffffffff,%eax
  jmp    L19
L21:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string

tool: D29: Enter an integer.

tool: D25: %d

assistant: ```c
int main() {
  int n;
  printf("Enter an integer.\n");
  scanf("%d", &n);
  if (n < 1)
    return -1;
  printf("%d", is_prime(n));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L11
  call   <is_prime@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L6:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x18,%rsp
  ret
L11:
  mov    $0xffffffff,%eax
  jmp    L6
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D8: Enter an integer.

tool: D1: %d

assistant: ```c
int main() {
  int n;
  printf("Enter an integer.\n");
  scanf("%d", &n);
  if (n < 1)
    return -1;
  printf("%d", is_prime(n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  lea    D16(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L8
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L9:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x10,%rsp
  pop    %rbp
  ret
L8:
  or     $0xffffffff,%eax
  jmp    L9
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string

tool: D19: Enter an integer.

tool: D16: %d

assistant: ```c
int main() {
  int n;
  printf("Enter an integer.\n");
  scanf("%d", &n);
  if (n < 1)
    return -1;
  printf("%d", is_prime(n));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D3(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  test   %edi,%edi
  jle    L9
  call   <is_prime@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
L20:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x10,%rsp
  pop    %rbp
  ret
L9:
  or     $0xffffffff,%eax
  jmp    L20
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D3
type_infered: string

tool: D11: Enter an integer.

tool: D3: %d

assistant: ```c
int main() {
  int n;
  printf("Enter an integer.\n");
  scanf("%d", &n);
  if (n < 1)
    return -1;
  printf("%d", is_prime(n));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getRandomNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D9(%rip),%eax
  test   %eax,%eax
  jne    L4
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,D9(%rip)
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  pop    %rbp
  ret
```

assistant: ```c
int getRandomNumber(void) {
  static int i = 0;
  if (i == 0) {
    srand(time(NULL));
    i = 1;
  }
  return rand();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getRandomNumber>:
  endbr64
  sub    $0x8,%rsp
  cmpl   $0x0,D8(%rip)
  je     L15
L12:
  mov    $0x0,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  ret
L15:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,D8(%rip)
  jmp    L12
```

assistant: ```c
int getRandomNumber(void) {
  static int i = 0;
  if (i == 0) {
    srand(time(NULL));
    i = 1;
  }
  return rand();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getRandomNumber>:
  endbr64
  mov    D2(%rip),%eax
  test   %eax,%eax
  je     L1
  xor    %eax,%eax
  jmp    1090 <rand@plt>
  nopl   (%rax)
L1:
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  movl   $0x1,D2(%rip)
  add    $0x8,%rsp
  jmp    1090 <rand@plt>
```

assistant: ```c
int getRandomNumber(void) {
  static int i = 0;
  if (i == 0) {
    srand(time(NULL));
    i = 1;
  }
  return rand();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getRandomNumber>:
  endbr64
  mov    D11(%rip),%eax
  test   %eax,%eax
  je     L2
  xor    %eax,%eax
  jmp    1090 <rand@plt>
  nopl   (%rax)
L2:
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  movl   $0x1,D11(%rip)
  add    $0x8,%rsp
  jmp    1090 <rand@plt>
```

assistant: ```c
int getRandomNumber(void) {
  static int i = 0;
  if (i == 0) {
    srand(time(NULL));
    i = 1;
  }
  return rand();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ftypelet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISREG@plt>
  test   %rax,%rax
  je     L111
  mov    $0x2d,%eax
  jmp    L113
L111:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L138
  mov    $0x64,%eax
  jmp    L113
L138:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISBLK@plt>
  test   %rax,%rax
  je     L131
  mov    $0x62,%eax
  jmp    L113
L131:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISCHR@plt>
  test   %rax,%rax
  je     L12
  mov    $0x63,%eax
  jmp    L113
L12:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISLNK@plt>
  test   %rax,%rax
  je     L39
  mov    $0x6c,%eax
  jmp    L113
L39:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISFIFO@plt>
  test   %rax,%rax
  je     L87
  mov    $0x70,%eax
  jmp    L113
L87:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISSOCK@plt>
  test   %rax,%rax
  je     L69
  mov    $0x73,%eax
  jmp    L113
L69:
  mov    $0x3f,%eax
L113:
  leave
  ret
```

assistant: ```c
char ftypelet(mode_t bits) {
  if (S_ISREG(bits))
    return '-';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISBLK(bits))
    return 'b';
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISLNK(bits))
    return 'l';
  if (S_ISFIFO(bits))
    return 'p';
  if (S_ISSOCK(bits))
    return 's';
  return '?';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ftypelet>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <S_ISREG@plt>
  mov    %rax,%rdx
  mov    $0x2d,%eax
  test   %rdx,%rdx
  je     L0
L26:
  pop    %rbx
  ret
L0:
  mov    %ebx,%edi
  call   <S_ISDIR@plt>
  mov    %rax,%rdx
  mov    $0x64,%eax
  test   %rdx,%rdx
  jne    L26
  mov    %ebx,%edi
  call   <S_ISBLK@plt>
  mov    %rax,%rdx
  mov    $0x62,%eax
  test   %rdx,%rdx
  jne    L26
  mov    %ebx,%edi
  call   <S_ISCHR@plt>
  mov    %rax,%rdx
  mov    $0x63,%eax
  test   %rdx,%rdx
  jne    L26
  mov    %ebx,%edi
  call   <S_ISLNK@plt>
  mov    %rax,%rdx
  mov    $0x6c,%eax
  test   %rdx,%rdx
  jne    L26
  mov    %ebx,%edi
  call   <S_ISFIFO@plt>
  mov    %rax,%rdx
  mov    $0x70,%eax
  test   %rdx,%rdx
  jne    L26
  mov    %ebx,%edi
  call   <S_ISSOCK@plt>
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xffffffcc,%eax
  add    $0x73,%eax
  jmp    L26
```

assistant: ```c
char ftypelet(mode_t bits) {
  if (S_ISREG(bits))
    return '-';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISBLK(bits))
    return 'b';
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISLNK(bits))
    return 'l';
  if (S_ISFIFO(bits))
    return 'p';
  if (S_ISSOCK(bits))
    return 's';
  return '?';
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ftypelet>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <S_ISREG@plt>
  mov    %rax,%r8
  mov    $0x2d,%eax
  test   %r8,%r8
  je     L43
L41:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %ebp,%edi
  call   <S_ISDIR@plt>
  mov    %rax,%r8
  mov    $0x64,%eax
  test   %r8,%r8
  jne    L41
  mov    %ebp,%edi
  call   <S_ISBLK@plt>
  mov    %rax,%r8
  mov    $0x62,%eax
  test   %r8,%r8
  jne    L41
  mov    %ebp,%edi
  call   <S_ISCHR@plt>
  mov    %rax,%r8
  mov    $0x63,%eax
  test   %r8,%r8
  jne    L41
  mov    %ebp,%edi
  call   <S_ISLNK@plt>
  mov    %rax,%r8
  mov    $0x6c,%eax
  test   %r8,%r8
  jne    L41
  mov    %ebp,%edi
  call   <S_ISFIFO@plt>
  mov    %rax,%r8
  mov    $0x70,%eax
  test   %r8,%r8
  jne    L41
  mov    %ebp,%edi
  call   <S_ISSOCK@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xffffffcc,%eax
  add    $0x73,%eax
  ret
```

assistant: ```c
char ftypelet(mode_t bits) {
  if (S_ISREG(bits))
    return '-';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISBLK(bits))
    return 'b';
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISLNK(bits))
    return 'l';
  if (S_ISFIFO(bits))
    return 'p';
  if (S_ISSOCK(bits))
    return 's';
  return '?';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ftypelet>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <S_ISREG@plt>
  mov    %rax,%r8
  mov    $0x2d,%eax
  test   %r8,%r8
  je     L43
L40:
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %ebp,%edi
  call   <S_ISDIR@plt>
  mov    %rax,%r8
  mov    $0x64,%eax
  test   %r8,%r8
  jne    L40
  mov    %ebp,%edi
  call   <S_ISBLK@plt>
  mov    %rax,%r8
  mov    $0x62,%eax
  test   %r8,%r8
  jne    L40
  mov    %ebp,%edi
  call   <S_ISCHR@plt>
  mov    %rax,%r8
  mov    $0x63,%eax
  test   %r8,%r8
  jne    L40
  mov    %ebp,%edi
  call   <S_ISLNK@plt>
  mov    %rax,%r8
  mov    $0x6c,%eax
  test   %r8,%r8
  jne    L40
  mov    %ebp,%edi
  call   <S_ISFIFO@plt>
  mov    %rax,%r8
  mov    $0x70,%eax
  test   %r8,%r8
  jne    L40
  mov    %ebp,%edi
  call   <S_ISSOCK@plt>
  pop    %rbp
  cmp    $0x1,%rax
  sbb    %eax,%eax
  and    $0xffffffcc,%eax
  add    $0x73,%eax
  ret
```

assistant: ```c
char ftypelet(mode_t bits) {
  if (S_ISREG(bits))
    return '-';
  if (S_ISDIR(bits))
    return 'd';
  if (S_ISBLK(bits))
    return 'b';
  if (S_ISCHR(bits))
    return 'c';
  if (S_ISLNK(bits))
    return 'l';
  if (S_ISFIFO(bits))
    return 'p';
  if (S_ISSOCK(bits))
    return 's';
  return '?';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<compressx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L43
L66:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L97
  ucomisd %xmm1,%xmm0
  je     L23
  jmp    L97
L23:
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L21
L67:
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L4
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L4
  ucomisd %xmm1,%xmm0
  je     L67
L4:
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L118
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L118:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jl     L2
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L64
L97:
  nop
L64:
  addl   $0x1,-0xc(%rbp)
L43:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L66
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void compressx(double *x, int *n) {
  int delta, i, j;
  for (i = 0; i < (*n) - 1; i++) {
    if (x[i] != x[i + 1])
      continue;
    for (j = i + 2; j < (*n) && x[j] == x[i]; j++)
      ;
    delta = j - i - 1;
    for (; j < (*n); j++)
      x[j - delta] = x[j];
    (*n) -= delta;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compressx>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%r9
  mov    (%rsi),%r8d
  cmp    $0x1,%r8d
  jle    L82
  mov    $0x2,%r10d
  mov    $0x0,%edi
  jmp    L10
L57:
  mov    %eax,%esi
  sub    %r11d,%esi
  lea    -0x1(%rsi),%r8d
  mov    (%r9),%edx
  cmp    %eax,%edx
  jle    L61
  cltq
  movslq %esi,%rsi
  neg    %rsi
  lea    (%rcx,%rsi,8),%rsi
L30:
  movsd  (%rcx,%rax,8),%xmm0
  movsd  %xmm0,0x8(%rsi,%rax,8)
  mov    (%r9),%edx
  add    $0x1,%rax
  cmp    %eax,%edx
  jg     L30
L61:
  sub    %r8d,%edx
  mov    %edx,(%r9)
L109:
  mov    (%r9),%r8d
  add    $0x1,%rdi
  add    $0x1,%r10d
  lea    -0x1(%r8),%eax
  cmp    %edi,%eax
  jle    L82
L10:
  mov    %edi,%r11d
  movsd  (%rcx,%rdi,8),%xmm0
  ucomisd 0x8(%rcx,%rdi,8),%xmm0
  jp     L109
  jne    L109
  mov    %r10d,%eax
  cmp    %r8d,%r10d
  jge    L57
  movslq %r10d,%rdx
L104:
  mov    %edx,%esi
  mov    %edx,%eax
  ucomisd (%rcx,%rdx,8),%xmm0
  jp     L57
  jne    L57
  lea    0x1(%rsi),%eax
  add    $0x1,%rdx
  cmp    %edx,%r8d
  jg     L104
  jmp    L57
L82:
  ret
```

assistant: ```c
void compressx(double *x, int *n) {
  int delta, i, j;
  for (i = 0; i < (*n) - 1; i++) {
    if (x[i] != x[i + 1])
      continue;
    for (j = i + 2; j < (*n) && x[j] == x[i]; j++)
      ;
    delta = j - i - 1;
    for (; j < (*n); j++)
      x[j - delta] = x[j];
    (*n) -= delta;
  }
}
```