ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strip_color>:
  endbr64
  mov    D23(%rip),%eax
  mov    %rdi,%rdx
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  mov    %ecx,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%esi
  sar    $0x21,%rax
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  mov    %ecx,%eax
  lea    D20(%rip),%rcx
  sub    %esi,%eax
  mov    %eax,D2(%rip)
  cltq
  shl    $0xb,%rax
  lea    (%rax,%rcx,1),%r8
  movzbl (%rdi),%eax
  mov    %r8,%rcx
  test   %al,%al
  jne    L49
  jmp    L62
  nop
L25:
  mov    %al,(%rcx)
  mov    %rdx,%rax
  add    $0x1,%rcx
L59:
  lea    0x1(%rax),%rdx
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L62
L49:
  cmp    $0x7e,%al
  jne    L25
  movzbl 0x1(%rdx),%eax
  test   %al,%al
  je     L62
  cmp    $0x21,%al
  je     L1
  lea    0x1(%rdx),%rax
  lea    0x1(%rax),%rdx
  movzbl 0x1(%rax),%eax
  test   %al,%al
  jne    L49
L62:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L1:
  cmpb   $0x0,0x2(%rdx)
  lea    0x2(%rdx),%rax
  jne    L59
  mov    %r8,%rax
  ret
```

assistant: ```c
const char *strip_color(const char *str) {
  static char out[5][2048];
  static int i = 0;
  char *res = NULL;
  ++i, i %= 5;
  res = out[i];
  for (const char *pstr = str; *pstr != 0; pstr++) {
    if (*pstr != '~') {
      *res++ = *pstr;
      continue;
    }
    if (*(++pstr) == 0) {
      break;
    }
    if (*pstr == '!') {
      pstr++;
    } else {
      continue;
    }
    if (*pstr == 0) {
      break;
    }
  }
  return out[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L16:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: %s, 

assistant: ```c
void print_buf(char **buf, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s, ", buf[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_buf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %esi,%esi
  jle    L16
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    D1(%rip),%rbp
L6:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L6
L16:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
datatype: string

tool: D1: %s, 

assistant: ```c
void print_buf(char **buf, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s, ", buf[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_buf>:
  endbr64
  test   %esi,%esi
  jle    L13
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L13:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: %s, 

assistant: ```c
void print_buf(char **buf, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s, ", buf[i]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_buf>:
  endbr64
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L15:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L15
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L0:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_infered: string

tool: D3: %s, 

assistant: ```c
void print_buf(char **buf, int n) {
  int i = 0;
  for (i = 0; i < n; i++) {
    printf("%s, ", buf[i]);
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<TopLevelImp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L5
L39:
  movl   $0x0,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jne    L25
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  jmp    L54
L25:
  mov    -0x10(%rbp),%edx
  lea    -0x24(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <get_topabs@plt>
L54:
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <first_Construct@plt>
  jmp    L102
L93:
  mov    -0x1c(%rbp),%edx
  lea    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <val_ext@plt>
  mov    -0x18(%rbp),%eax
  cmp    $0x3,%eax
  jne    L48
  mov    -0x1c(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <def_inc_ipt@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L48
  mov    -0x24(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  lea    -0x14(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <member_inc_ipt@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L48
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L5
L48:
  mov    -0x1c(%rbp),%ecx
  mov    -0x20(%rbp),%edx
  lea    -0x1c(%rbp),%rsi
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <next_Construct@plt>
L102:
  mov    -0x20(%rbp),%eax
  test   %eax,%eax
  jne    L93
L5:
  cmpl   $0x0,-0xc(%rbp)
  jne    L39
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

assistant: ```c
int TopLevelImp(cc, cc_0)
int cc, cc_0;
{
  int cc_top, cc_top_0, loc_itr, cc_itr, another_level_found, ext, bb;
  cc_top = cc;
  another_level_found = 1;
  while (another_level_found) {
    another_level_found = 0;
    if (cc_top == cc)
      cc_top_0 = cc_0;
    else
      get_topabs(&cc_top_0, cc_top);
    first_Construct(&loc_itr, &cc_itr);
    while (loc_itr) {
      val_ext(&ext, cc_itr);
      if (ext == 3) {
        def_inc_ipt(&bb, cc_itr);
        if (bb) {
          member_inc_ipt(&bb, cc_itr, cc_top_0);
          if (bb) {
            cc_top = cc_itr;
            another_level_found = 1;
            break;
          }
        }
      }
      next_Construct(&loc_itr, &cc_itr, loc_itr, cc_itr);
    }
  }
  return (cc_top);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<TopLevelImp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%r12d
  lea    0x4(%rsp),%r14
L87:
  cmp    %r12d,%ebp
  jne    L15
  mov    %r13d,0x4(%rsp)
L32:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    $0x0,%eax
  call   <first_Construct@plt>
  cmpl   $0x0,0x8(%rsp)
  je     L93
  lea    0x10(%rsp),%rbx
  jmp    L38
L15:
  mov    %r12d,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <get_topabs@plt>
  jmp    L32
L74:
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    $0x0,%eax
  call   <next_Construct@plt>
  cmpl   $0x0,0x8(%rsp)
  je     L93
L38:
  mov    0xc(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <val_ext@plt>
  cmpl   $0x3,0x10(%rsp)
  jne    L74
  lea    0x14(%rsp),%rdi
  mov    0xc(%rsp),%esi
  mov    $0x0,%eax
  call   <def_inc_ipt@plt>
  cmpl   $0x0,0x14(%rsp)
  je     L74
  lea    0x14(%rsp),%rdi
  mov    0x4(%rsp),%edx
  mov    0xc(%rsp),%esi
  mov    $0x0,%eax
  call   <member_inc_ipt@plt>
  cmpl   $0x0,0x14(%rsp)
  je     L74
  mov    0xc(%rsp),%r12d
  jmp    L87
L93:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    %r12d,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int TopLevelImp(cc, cc_0)
int cc, cc_0;
{
  int cc_top, cc_top_0, loc_itr, cc_itr, another_level_found, ext, bb;
  cc_top = cc;
  another_level_found = 1;
  while (another_level_found) {
    another_level_found = 0;
    if (cc_top == cc)
      cc_top_0 = cc_0;
    else
      get_topabs(&cc_top_0, cc_top);
    first_Construct(&loc_itr, &cc_itr);
    while (loc_itr) {
      val_ext(&ext, cc_itr);
      if (ext == 3) {
        def_inc_ipt(&bb, cc_itr);
        if (bb) {
          member_inc_ipt(&bb, cc_itr, cc_top_0);
          if (bb) {
            cc_top = cc_itr;
            another_level_found = 1;
            break;
          }
        }
      }
      next_Construct(&loc_itr, &cc_itr, loc_itr, cc_itr);
    }
  }
  return (cc_top);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<TopLevelImp>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0x4(%rsp)
  lea    0x1c(%rsp),%rbp
  lea    0x18(%rsp),%rbx
  lea    0x20(%rsp),%r12
  lea    0x24(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  cmp    %r15d,%r14d
  jne    L7
L29:
  mov    0x4(%rsp),%eax
  mov    %eax,0x14(%rsp)
L19:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <first_Construct@plt>
  mov    0x18(%rsp),%esi
  test   %esi,%esi
  jne    L97
  jmp    L70
  nopl   (%rax)
L31:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <next_Construct@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  je     L70
L97:
  mov    0x1c(%rsp),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <val_ext@plt>
  cmpl   $0x3,0x20(%rsp)
  jne    L31
  mov    0x1c(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <def_inc_ipt@plt>
  mov    0x24(%rsp),%ecx
  test   %ecx,%ecx
  je     L31
  mov    0x14(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <member_inc_ipt@plt>
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  je     L31
  mov    0x1c(%rsp),%r15d
  cmp    %r15d,%r14d
  je     L29
  nopl   0x0(%rax,%rax,1)
L7:
  mov    0x8(%rsp),%rdi
  mov    %r15d,%esi
  xor    %eax,%eax
  call   <get_topabs@plt>
  jmp    L19
  nopl   0x0(%rax)
L70:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int TopLevelImp(cc, cc_0)
int cc, cc_0;
{
  int cc_top, cc_top_0, loc_itr, cc_itr, another_level_found, ext, bb;
  cc_top = cc;
  another_level_found = 1;
  while (another_level_found) {
    another_level_found = 0;
    if (cc_top == cc)
      cc_top_0 = cc_0;
    else
      get_topabs(&cc_top_0, cc_top);
    first_Construct(&loc_itr, &cc_itr);
    while (loc_itr) {
      val_ext(&ext, cc_itr);
      if (ext == 3) {
        def_inc_ipt(&bb, cc_itr);
        if (bb) {
          member_inc_ipt(&bb, cc_itr, cc_top_0);
          if (bb) {
            cc_top = cc_itr;
            another_level_found = 1;
            break;
          }
        }
      }
      next_Construct(&loc_itr, &cc_itr, loc_itr, cc_itr);
    }
  }
  return (cc_top);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<TopLevelImp>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %edi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %esi,0x4(%rsp)
  lea    0x1c(%rsp),%rbp
  lea    0x18(%rsp),%rbx
  lea    0x20(%rsp),%r12
  lea    0x24(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rax
  mov    %rax,0x8(%rsp)
  cmp    %r15d,%r14d
  jne    L49
L94:
  mov    0x4(%rsp),%eax
  mov    %eax,0x14(%rsp)
L9:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <first_Construct@plt>
  mov    0x18(%rsp),%esi
  test   %esi,%esi
  jne    L88
  jmp    L74
  nopl   (%rax)
L35:
  mov    0x1c(%rsp),%ecx
  mov    0x18(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <next_Construct@plt>
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  je     L74
L88:
  mov    0x1c(%rsp),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <val_ext@plt>
  cmpl   $0x3,0x20(%rsp)
  jne    L35
  mov    0x1c(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <def_inc_ipt@plt>
  mov    0x24(%rsp),%ecx
  test   %ecx,%ecx
  je     L35
  mov    0x14(%rsp),%edx
  mov    0x1c(%rsp),%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <member_inc_ipt@plt>
  mov    0x24(%rsp),%edx
  test   %edx,%edx
  je     L35
  mov    0x1c(%rsp),%r15d
  cmp    %r15d,%r14d
  je     L94
  nopl   0x0(%rax,%rax,1)
L49:
  mov    0x8(%rsp),%rdi
  mov    %r15d,%esi
  xor    %eax,%eax
  call   <get_topabs@plt>
  jmp    L9
  nopl   0x0(%rax)
L74:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x38,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int TopLevelImp(cc, cc_0)
int cc, cc_0;
{
  int cc_top, cc_top_0, loc_itr, cc_itr, another_level_found, ext, bb;
  cc_top = cc;
  another_level_found = 1;
  while (another_level_found) {
    another_level_found = 0;
    if (cc_top == cc)
      cc_top_0 = cc_0;
    else
      get_topabs(&cc_top_0, cc_top);
    first_Construct(&loc_itr, &cc_itr);
    while (loc_itr) {
      val_ext(&ext, cc_itr);
      if (ext == 3) {
        def_inc_ipt(&bb, cc_itr);
        if (bb) {
          member_inc_ipt(&bb, cc_itr, cc_top_0);
          if (bb) {
            cc_top = cc_itr;
            another_level_found = 1;
            break;
          }
        }
      }
      next_Construct(&loc_itr, &cc_itr, loc_itr, cc_itr);
    }
  }
  return (cc_top);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_assertDeepEqual>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x2,%edx
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <assertDeepEqual@plt>
  test   %eax,%eax
  jne    L18
  lea    D10(%rip),%rax
  jmp    L0
L18:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type_infered: string

tool: D10: e: test_assertDeepEqual

assistant: ```c
char *test_assertDeepEqual() {
  static int a[2] = {1, 2};
  static int b[2] = {1, 2};
  do {
    if (!(assertDeepEqual(a, b, 2)))
      return "e: test_assertDeepEqual";
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_assertDeepEqual>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  lea    D26(%rip),%rsi
  lea    D24(%rip),%rdi
  call   <assertDeepEqual@plt>
  test   %eax,%eax
  lea    D3(%rip),%rax
  mov    $0x0,%edx
  cmovne %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: string

tool: D3: e: test_assertDeepEqual

assistant: ```c
char *test_assertDeepEqual() {
  static int a[2] = {1, 2};
  static int b[2] = {1, 2};
  do {
    if (!(assertDeepEqual(a, b, 2)))
      return "e: test_assertDeepEqual";
  } while (0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_assertDeepEqual>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  lea    D4(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <assertDeepEqual@plt>
  mov    $0x0,%edx
  test   %eax,%eax
  lea    D27(%rip),%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D27
type_guessed: string

tool: D27: e: test_assertDeepEqual

assistant: ```c
char *test_assertDeepEqual() {
  static int a[2] = {1, 2};
  static int b[2] = {1, 2};
  do {
    if (!(assertDeepEqual(a, b, 2)))
      return "e: test_assertDeepEqual";
  } while (0);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_assertDeepEqual>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  lea    D28(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <assertDeepEqual@plt>
  mov    $0x0,%edx
  test   %eax,%eax
  lea    D1(%rip),%rax
  cmovne %rdx,%rax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string

tool: D1: e: test_assertDeepEqual

assistant: ```c
char *test_assertDeepEqual() {
  static int a[2] = {1, 2};
  static int b[2] = {1, 2};
  do {
    if (!(assertDeepEqual(a, b, 2)))
      return "e: test_assertDeepEqual";
  } while (0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<max_ones>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <start_div@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%edi
  call   <count_ones@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L11
L5:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %eax,%edi
  call   <count_ones@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L15
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L11:
  cmpl   $0x0,-0xc(%rbp)
  jne    L5
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int max_ones(int n) {
  int div = start_div(n);
  int most = count_ones(n / div);
  div /= 10;
  while (div) {
    int next = count_ones(n / div);
    if (next > most)
      most = next;
    div /= 10;
  }
  return most;
}
```
user: What is the c source code of the assembly code below?

```asm
<max_ones>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  call   <start_div@plt>
  mov    %eax,%r13d
  mov    %r12d,%eax
  cltd
  idiv   %r13d
  mov    %eax,%edi
  call   <count_ones@plt>
  mov    %eax,%ebp
  movslq %r13d,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  sar    $0x1f,%r13d
  sub    %r13d,%ebx
  je     L0
L9:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  call   <count_ones@plt>
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  movslq %ebx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ebx
  sub    %ebx,%edx
  mov    %edx,%ebx
  jne    L9
L0:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int max_ones(int n) {
  int div = start_div(n);
  int most = count_ones(n / div);
  div /= 10;
  while (div) {
    int next = count_ones(n / div);
    if (next > most)
      most = next;
    div /= 10;
  }
  return most;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<max_ones>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <start_div@plt>
  movslq %eax,%rbx
  mov    %r12d,%eax
  cltd
  mov    %rbx,%rbp
  idiv   %ebx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%ebp
  sar    $0x22,%rbx
  mov    %eax,%edi
  call   <count_ones@plt>
  mov    %eax,%r13d
  sub    %ebp,%ebx
  je     L6
  xchg   %ax,%ax
L15:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  call   <count_ones@plt>
  movslq %ebx,%rdx
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  imul   $0x66666667,%rdx,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  mov    %edx,%ebx
  sub    %eax,%ebx
  jne    L15
L6:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int max_ones(int n) {
  int div = start_div(n);
  int most = count_ones(n / div);
  div /= 10;
  while (div) {
    int next = count_ones(n / div);
    if (next > most)
      most = next;
    div /= 10;
  }
  return most;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<max_ones>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <start_div@plt>
  movslq %eax,%rbx
  mov    %r12d,%eax
  cltd
  mov    %rbx,%rbp
  idiv   %ebx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x1f,%ebp
  sar    $0x22,%rbx
  mov    %eax,%edi
  call   <count_ones@plt>
  mov    %eax,%r13d
  sub    %ebp,%ebx
  je     L17
  xchg   %ax,%ax
L13:
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  mov    %eax,%edi
  call   <count_ones@plt>
  movslq %ebx,%rdx
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  imul   $0x66666667,%rdx,%rdx
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  mov    %edx,%ebx
  sub    %eax,%ebx
  jne    L13
L17:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int max_ones(int n) {
  int div = start_div(n);
  int most = count_ones(n / div);
  div /= 10;
  while (div) {
    int next = count_ones(n / div);
    if (next > most)
      most = next;
    div /= 10;
  }
  return most;
}
```