ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ReadWordIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x71(%rbp)
  lea    -0x71(%rbp),%rdx
  mov    -0x88(%rbp),%rcx
  lea    -0x70(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ReadWord@plt>
  movzbl -0x71(%rbp),%eax
  test   %al,%al
  je     L29
  mov    -0x90(%rbp),%rax
  movb   $0x1,(%rax)
  mov    $0xffffffff,%eax
  jmp    L17
L29:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <SearchVocab@plt>
L17:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int ReadWordIndex(FILE *fin, char *eof) {
  char word[100], eof_l = 0;
  ReadWord(word, fin, &eof_l);
  if (eof_l) {
    *eof = 1;
    return -1;
  }
  return SearchVocab(word);
}
```
user: What is the c source code of the assembly code below:

```asm
<ReadWordIndex>:
  endbr64
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  movb   $0x0,0xf(%rsp)
  lea    0xf(%rsp),%rdx
  lea    0x10(%rsp),%rax
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <ReadWord@plt>
  cmpb   $0x0,0xf(%rsp)
  jne    L28
  lea    0x10(%rsp),%rdi
  call   <SearchVocab@plt>
L4:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  ret
L28:
  movb   $0x1,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L4
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadWordIndex(FILE *fin, char *eof) {
  char word[100], eof_l = 0;
  ReadWord(word, fin, &eof_l);
  if (eof_l) {
    *eof = 1;
    return -1;
  }
  return SearchVocab(word);
}
```
user: What is the c source code of the assembly code below?

```asm
<ReadWordIndex>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xf(%rsp),%rdx
  movb   $0x0,0xf(%rsp)
  mov    %rbp,%rdi
  call   <ReadWord@plt>
  cmpb   $0x0,0xf(%rsp)
  jne    L16
  mov    %rbp,%rdi
  call   <SearchVocab@plt>
L3:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  movb   $0x1,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L3
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadWordIndex(FILE *fin, char *eof) {
  char word[100], eof_l = 0;
  ReadWord(word, fin, &eof_l);
  if (eof_l) {
    *eof = 1;
    return -1;
  }
  return SearchVocab(word);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ReadWordIndex>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %rdi,%rsi
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0xf(%rsp),%rdx
  movb   $0x0,0xf(%rsp)
  mov    %rbp,%rdi
  call   <ReadWord@plt>
  cmpb   $0x0,0xf(%rsp)
  jne    L14
  mov    %rbp,%rdi
  call   <SearchVocab@plt>
L4:
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movb   $0x1,(%rbx)
  mov    $0xffffffff,%eax
  jmp    L4
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadWordIndex(FILE *fin, char *eof) {
  char word[100], eof_l = 0;
  ReadWord(word, fin, &eof_l);
  if (eof_l) {
    *eof = 1;
    return -1;
  }
  return SearchVocab(word);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getInput>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L26
L45:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L1
  movl   $0x1,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L26
L1:
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x0,-0x10(%rbp)
  jne    L39
  mov    -0xc(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L45
L39:
  mov    -0x28(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string

tool: D2: -query

assistant: ```c
char *getInput(int ac, char **arg, int *index) {
  int fin = 0;
  int i = 0;
  char *res = NULL;
  while (!fin && i < ac) {
    if (strcmp(arg[i], "-query") == 0) {
      fin = 1;
      i++;
      res = arg[i];
    } else {
      i++;
    }
  }
  *index = i;
  return res;
}
```
user: What is the c source code of the assembly code below:

```asm
<getInput>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r15
  test   %edi,%edi
  jle    L59
  mov    %edi,%r12d
  mov    %rsi,%r14
  mov    %rsi,%rbp
  mov    $0x0,%ebx
  lea    D2(%rip),%r13
  jmp    L27
L4:
  add    $0x1,%ebx
  add    $0x8,%rbp
  cmp    %ebx,%r12d
  je     L21
L27:
  mov    %r13,%rsi
  mov    0x0(%rbp),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  lea    0x1(%rbx),%r12d
  movslq %r12d,%rax
  mov    (%r14,%rax,8),%rax
L57:
  mov    %r12d,(%r15)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  mov    $0x0,%eax
  jmp    L57
L59:
  mov    $0x0,%eax
  mov    $0x0,%r12d
  jmp    L57
```

tool_calls: name: read_data
arguments: tag: D2
type_infered: string

tool: D2: -query

assistant: ```c
char *getInput(int ac, char **arg, int *index) {
  int fin = 0;
  int i = 0;
  char *res = NULL;
  while (!fin && i < ac) {
    if (strcmp(arg[i], "-query") == 0) {
      fin = 1;
      i++;
      res = arg[i];
    } else {
      i++;
    }
  }
  *index = i;
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<getInput>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L33
  mov    %rsi,%r14
  lea    0x1(%rdi),%r12d
  mov    $0x1,%ebx
  lea    D2(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L19:
  mov    -0x8(%r14,%rbx,8),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    %ebx,%edx
  test   %rax,%rax
  jne    L5
  movslq %ebx,%rax
  mov    (%r14,%rax,8),%rax
L15:
  pop    %rbx
  pop    %rbp
  mov    %edx,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L19
  xor    %eax,%eax
  jmp    L15
  nopl   (%rax)
L33:
  xor    %edx,%edx
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  mov    %edx,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string

tool: D2: -query

assistant: ```c
char *getInput(int ac, char **arg, int *index) {
  int fin = 0;
  int i = 0;
  char *res = NULL;
  while (!fin && i < ac) {
    if (strcmp(arg[i], "-query") == 0) {
      fin = 1;
      i++;
      res = arg[i];
    } else {
      i++;
    }
  }
  *index = i;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getInput>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L9
  mov    %rsi,%r14
  lea    0x1(%rdi),%r12d
  mov    $0x1,%ebx
  lea    D1(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    -0x8(%r14,%rbx,8),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  mov    %ebx,%edx
  test   %rax,%rax
  jne    L1
  movslq %ebx,%rax
  mov    (%r14,%rax,8),%rax
L7:
  pop    %rbx
  pop    %rbp
  mov    %edx,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L18
  xor    %eax,%eax
  jmp    L7
  nopl   (%rax)
L9:
  xor    %edx,%edx
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  mov    %edx,0x0(%r13)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
type: string

tool: D1: -query

assistant: ```c
char *getInput(int ac, char **arg, int *index) {
  int fin = 0;
  int i = 0;
  char *res = NULL;
  while (!fin && i < ac) {
    if (strcmp(arg[i], "-query") == 0) {
      fin = 1;
      i++;
      res = arg[i];
    } else {
      i++;
    }
  }
  *index = i;
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ufclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <unlock@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  leave
  ret
```

assistant: ```c
int ufclose(FILE *file, const char *filename) {
  unlock(file, filename);
  return fclose(file);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ufclose>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <unlock@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  pop    %rbx
  ret
```

assistant: ```c
int ufclose(FILE *file, const char *filename) {
  unlock(file, filename);
  return fclose(file);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ufclose>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <unlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
```

assistant: ```c
int ufclose(FILE *file, const char *filename) {
  unlock(file, filename);
  return fclose(file);
}
```
user: What is the c source code of the assembly code below:

```asm
<ufclose>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <unlock@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <fclose@plt>
```

assistant: ```c
int ufclose(FILE *file, const char *filename) {
  unlock(file, filename);
  return fclose(file);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  movl   $0x2,-0x8(%rbp)
  jmp    L31
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L38:
  cmpl   $0x0,-0x4(%rbp)
  jle    L43
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L22
L43:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L17
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jle    L38
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init(const char *str, int next[], int n) {
  int i, k = 0;
  next[1] = 0;
  for (i = 2; i <= n; ++i) {
    while (k > 0 && str[k + 1] != str[i]) {
      k = next[k];
    }
    if (str[k + 1] == str[i]) {
      k = k + 1;
    }
    next[i] = k;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<init>:
  endbr64
  movl   $0x0,0x4(%rsi)
  cmp    $0x1,%edx
  jle    L83
  lea    0x1(%rdx),%r9d
  mov    $0x2,%r8d
  mov    $0x0,%eax
  jmp    L41
L29:
  movslq %eax,%rdx
  movzbl (%rdi,%r8,1),%ecx
  cmp    %cl,0x1(%rdi,%rdx,1)
  je     L57
L14:
  mov    %eax,(%rsi,%r8,4)
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L83
L41:
  test   %eax,%eax
  jle    L29
  movzbl (%rdi,%r8,1),%ecx
L84:
  movslq %eax,%rdx
  cmp    %cl,0x1(%rdi,%rdx,1)
  je     L57
  mov    (%rsi,%rdx,4),%eax
  test   %eax,%eax
  jg     L84
  jmp    L29
L57:
  add    $0x1,%eax
  jmp    L14
L83:
  ret
```

assistant: ```c
void init(const char *str, int next[], int n) {
  int i, k = 0;
  next[1] = 0;
  for (i = 2; i <= n; ++i) {
    while (k > 0 && str[k + 1] != str[i]) {
      k = next[k];
    }
    if (str[k + 1] == str[i]) {
      k = k + 1;
    }
    next[i] = k;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init>:
  endbr64
  movl   $0x0,0x4(%rsi)
  cmp    $0x1,%edx
  jle    L9
  lea    0x1(%rdx),%r9d
  mov    $0x2,%r8d
  xor    %eax,%eax
  nopl   0x0(%rax)
L31:
  test   %eax,%eax
  jle    L25
  movzbl (%rdi,%r8,1),%ecx
  jmp    L64
  nopl   0x0(%rax,%rax,1)
L20:
  mov    (%rsi,%rdx,4),%eax
  test   %eax,%eax
  jle    L25
L64:
  movslq %eax,%rdx
  cmp    %cl,0x1(%rdi,%rdx,1)
  jne    L20
  lea    0x1(%rax),%edx
L54:
  mov    %edx,%eax
L78:
  mov    %eax,(%rsi,%r8,4)
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L31
L9:
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  lea    0x1(%rax),%edx
  movzbl (%rdi,%r8,1),%r10d
  movslq %edx,%rcx
  cmp    %r10b,(%rdi,%rcx,1)
  jne    L78
  jmp    L54
```

assistant: ```c
void init(const char *str, int next[], int n) {
  int i, k = 0;
  next[1] = 0;
  for (i = 2; i <= n; ++i) {
    while (k > 0 && str[k + 1] != str[i]) {
      k = next[k];
    }
    if (str[k + 1] == str[i]) {
      k = k + 1;
    }
    next[i] = k;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init>:
  endbr64
  movl   $0x0,0x4(%rsi)
  cmp    $0x1,%edx
  jle    L47
  lea    0x1(%rdx),%r9d
  mov    $0x2,%r8d
  xor    %eax,%eax
  nopl   0x0(%rax)
L42:
  test   %eax,%eax
  jle    L67
  movzbl (%rdi,%r8,1),%ecx
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L45:
  mov    (%rsi,%rdx,4),%eax
  test   %eax,%eax
  jle    L67
L17:
  movslq %eax,%rdx
  cmp    %cl,0x1(%rdi,%rdx,1)
  jne    L45
  lea    0x1(%rax),%edx
L31:
  mov    %edx,%eax
L50:
  mov    %eax,(%rsi,%r8,4)
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L42
L47:
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  lea    0x1(%rax),%edx
  movzbl (%rdi,%r8,1),%r10d
  movslq %edx,%rcx
  cmp    %r10b,(%rdi,%rcx,1)
  jne    L50
  jmp    L31
```

assistant: ```c
void init(const char *str, int next[], int n) {
  int i, k = 0;
  next[1] = 0;
  for (i = 2; i <= n; ++i) {
    while (k > 0 && str[k + 1] != str[i]) {
      k = next[k];
    }
    if (str[k + 1] == str[i]) {
      k = k + 1;
    }
    next[i] = k;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_hex_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x1c(%rbp)
  mov    %al,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L5:
  movsbl -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%esi
  mov    %eax,%ecx
  shr    %cl,%esi
  mov    %esi,%eax
  and    $0xf,%eax
  mov    %eax,%ecx
  lea    D1(%rip),%rax
  movzbl (%rcx,%rax,1),%eax
  movsbl %al,%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_char@plt>
  subl   $0x4,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L5
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: 0123456789ABCDEF

assistant: ```c
void print_hex_size(unsigned int num, char attr, int hexdigits) {
  int i;
  for (i = (hexdigits - 1) * 4; i >= 0; i -= 4)
    print_char("0123456789ABCDEF"[(num >> i) & 0xF], attr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_hex_size>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4(,%rdx,4),%ebx
  test   %ebx,%ebx
  js     L5
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    $0xfffffffc,%r14d
  lea    D6(%rip),%r13
L19:
  movsbl %r12b,%esi
  mov    %ebp,%eax
  mov    %ebx,%ecx
  shr    %cl,%eax
  and    $0xf,%eax
  movsbl 0x0(%r13,%rax,1),%edi
  call   <print_char@plt>
  sub    $0x4,%ebx
  cmp    %r14d,%ebx
  jne    L19
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
type_guessed: string

tool: D6: 0123456789ABCDEF

assistant: ```c
void print_hex_size(unsigned int num, char attr, int hexdigits) {
  int i;
  for (i = (hexdigits - 1) * 4; i >= 0; i -= 4)
    print_char("0123456789ABCDEF"[(num >> i) & 0xF], attr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_hex_size>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4(,%rdx,4),%ebx
  test   %ebx,%ebx
  js     L12
  mov    %edi,%r12d
  movsbl %sil,%ebp
  mov    $0xfffffffc,%r14d
  lea    D3(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%ecx
  mov    %r12d,%eax
  mov    %ebp,%esi
  sub    $0x4,%ebx
  shr    %cl,%eax
  and    $0xf,%eax
  movsbl 0x0(%r13,%rax,1),%edi
  call   <print_char@plt>
  cmp    %ebx,%r14d
  jne    L10
L12:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: 0123456789ABCDEF

assistant: ```c
void print_hex_size(unsigned int num, char attr, int hexdigits) {
  int i;
  for (i = (hexdigits - 1) * 4; i >= 0; i -= 4)
    print_char("0123456789ABCDEF"[(num >> i) & 0xF], attr);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_hex_size>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x4(,%rdx,4),%ebx
  test   %ebx,%ebx
  js     L8
  mov    %edi,%r12d
  movsbl %sil,%ebp
  mov    $0xfffffffc,%r14d
  lea    D6(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebx,%ecx
  mov    %r12d,%eax
  mov    %ebp,%esi
  sub    $0x4,%ebx
  shr    %cl,%eax
  and    $0xf,%eax
  movsbl 0x0(%r13,%rax,1),%edi
  call   <print_char@plt>
  cmp    %ebx,%r14d
  jne    L9
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: 0123456789ABCDEF

assistant: ```c
void print_hex_size(unsigned int num, char attr, int hexdigits) {
  int i;
  for (i = (hexdigits - 1) * 4; i >= 0; i -= 4)
    print_char("0123456789ABCDEF"[(num >> i) & 0xF], attr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: Congratulations, you rolled a %d!


assistant: ```c
int main() {
  int x;
  srand(time(NULL));
  x = rand() % 6 + 1;
  printf("Congratulations, you rolled a %d!\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D9
type_infered: string

tool: D9: Congratulations, you rolled a %d!


assistant: ```c
int main() {
  int x;
  srand(time(NULL));
  x = rand() % 6 + 1;
  printf("Congratulations, you rolled a %d!\n", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D3(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: Congratulations, you rolled a %d!


assistant: ```c
int main() {
  int x;
  srand(time(NULL));
  x = rand() % 6 + 1;
  printf("Congratulations, you rolled a %d!\n", x);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D1(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%edx
  add    %edx,%edx
  sub    %edx,%eax
  lea    0x1(%rax),%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: D1: Congratulations, you rolled a %d!


assistant: ```c
int main() {
  int x;
  srand(time(NULL));
  x = rand() % 6 + 1;
  printf("Congratulations, you rolled a %d!\n", x);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_ivect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    $0x7b,%edi
  call   <putchar@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L18:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L18
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string

tool: D3: %d  

tool: D11: %d}


assistant: ```c
void print_ivect(m, rsize1, rsize2) int *m;
int rsize1, rsize2;
{
  int i;
  putchar('{');
  for (i = rsize1; i < rsize2; i++)
    printf("%d  ", m[i]);
  printf("%d}\n", m[rsize2]);
}
```