ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D24(%rip),%r15
  lea    D79(%rip),%r14
  jmp    L27
L34:
  movaps %xmm1,%xmm0
  divss  D21(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    0x10(%rsp),%rsi
  lea    D78(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L27:
  mov    %r15,%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D84(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    %rbx,%rsi
  lea    D23(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L47
  mov    $0x3,%ebp
  mov    D48(%rip),%ebx
  lea    0xc(%rsp),%r13
  lea    D31(%rip),%r12
L23:
  mov    %r14,%rdi
  call   <puts@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movd   %ebx,%xmm1
  addss  0xc(%rsp),%xmm1
  movd   %xmm1,%ebx
  sub    $0x1,%ebp
  jne    L23
  jmp    L34
L47:
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D24
type_infered: string
name: disassemble_data
arguments: data_label: D79
type_infered: string
name: disassemble_data
arguments: data_label: D21
type_infered: f32
name: disassemble_data
arguments: data_label: D78
type_infered: string
name: disassemble_data
arguments: data_label: D84
type_infered: string
name: disassemble_data
arguments: data_label: D23
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: f32
name: disassemble_data
arguments: data_label: D31
type_infered: string
name: disassemble_data
arguments: data_label: D37
type_infered: string

tool: D24: Enter Student Name (use 0 to exit): 

tool: D79: Enter exam grade: 

tool: D21: 3

tool: D78: Average for %s is %f


tool: D84: %s

tool: D23: 0

tool: D48: 0

tool: D31: %f

tool: D37: Exiting program

assistant: ```c
int main() {
  char StudentName[100];
  float ExamValue, Sum, Avg;
  int students, exams;
  while (1) {
    Sum = 0.0;
    printf("Enter Student Name (use 0 to exit): \n");
    scanf("%s", StudentName);
    if (strcmp("0", StudentName) != 0) {
      for (exams = 0; exams < 3; exams++) {
        printf("Enter exam grade: \n");
        scanf("%f", &ExamValue);
        Sum += ExamValue;
      }
      Avg = Sum / 3.0;
      printf("Average for %s is %f\n", StudentName, Avg);
    } else {
      printf("Exiting program\n");
      break;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D37(%rip),%r15
  push   %r14
  push   %r13
  lea    D42(%rip),%r13
  push   %r12
  lea    D53(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D76(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D39(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L26
  mov    $0x3,%r14d
  pxor   %xmm0,%xmm0
  lea    0x1c(%rsp),%rbx
L38:
  mov    %r13,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  sub    $0x1,%r14d
  jne    L38
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  mov    $0x1,%eax
  divss  D14(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L19
  cs nopw 0x0(%rax,%rax,1)
L26:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D37
type_infered: string
name: retrieve_data
arguments: label: D42
type_infered: string
name: retrieve_data
arguments: label: D53
type_infered: string
name: retrieve_data
arguments: label: D76
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string
name: retrieve_data
arguments: label: D10
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: f32
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D37: Enter Student Name (use 0 to exit): 

tool: D42: Enter exam grade: 

tool: D53: %f

tool: D76: %s

tool: D39: 0

tool: D10: Average for %s is %f


tool: D14: 3

tool: D29: Exiting program

assistant: ```c
int main() {
  char StudentName[100];
  float ExamValue, Sum, Avg;
  int students, exams;
  while (1) {
    Sum = 0.0;
    printf("Enter Student Name (use 0 to exit): \n");
    scanf("%s", StudentName);
    if (strcmp("0", StudentName) != 0) {
      for (exams = 0; exams < 3; exams++) {
        printf("Enter exam grade: \n");
        scanf("%f", &ExamValue);
        Sum += ExamValue;
      }
      Avg = Sum / 3.0;
      printf("Average for %s is %f\n", StudentName, Avg);
    } else {
      printf("Exiting program\n");
      break;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D78(%rip),%r15
  push   %r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  lea    D67(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L21:
  mov    %r15,%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %rbp,%rsi
  lea    D20(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L7
  mov    $0x3,%r14d
  pxor   %xmm0,%xmm0
  lea    0x1c(%rsp),%rbx
L2:
  mov    %r13,%rdi
  movss  %xmm0,0xc(%rsp)
  call   <puts@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  addss  0x1c(%rsp),%xmm0
  sub    $0x1,%r14d
  jne    L2
  mov    %rbp,%rsi
  lea    D59(%rip),%rdi
  mov    $0x1,%eax
  divss  D40(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L21
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    D50(%rip),%rdi
  call   <puts@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x98,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D78
data_type: string
name: disassemble_data
arguments: tag: D2
data_type: string
name: disassemble_data
arguments: tag: D67
data_type: string
name: disassemble_data
arguments: tag: D28
data_type: string
name: disassemble_data
arguments: tag: D20
data_type: string
name: disassemble_data
arguments: tag: D59
data_type: string
name: disassemble_data
arguments: tag: D40
data_type: f32
name: disassemble_data
arguments: tag: D50
data_type: string

tool: D78: Enter Student Name (use 0 to exit): 

tool: D2: Enter exam grade: 

tool: D67: %f

tool: D28: %s

tool: D20: 0

tool: D59: Average for %s is %f


tool: D40: 3

tool: D50: Exiting program

assistant: ```c
int main() {
  char StudentName[100];
  float ExamValue, Sum, Avg;
  int students, exams;
  while (1) {
    Sum = 0.0;
    printf("Enter Student Name (use 0 to exit): \n");
    scanf("%s", StudentName);
    if (strcmp("0", StudentName) != 0) {
      for (exams = 0; exams < 3; exams++) {
        printf("Enter exam grade: \n");
        scanf("%f", &ExamValue);
        Sum += ExamValue;
      }
      Avg = Sum / 3.0;
      printf("Average for %s is %f\n", StudentName, Avg);
    } else {
      printf("Exiting program\n");
      break;
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__libc_sa_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x80,-0x4(%rbp)
  je     L37
  cmpl   $0x81,-0x4(%rbp)
  jne    L15
  mov    $0x4,%eax
  jmp    L5
L37:
  mov    $0x4,%eax
  jmp    L5
L15:
  mov    $0x0,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__libc_sa_len>:
  endbr64
  add    $0xffffff80,%edi
  cmp    $0x1,%edi
  setbe  %al
  movzbl %al,%eax
  shl    $0x2,%eax
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__libc_sa_len>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x1,%edi
  setbe  %al
  shl    $0x2,%eax
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__libc_sa_len>:
  endbr64
  add    $0xffffff80,%edi
  xor    %eax,%eax
  cmp    $0x1,%edi
  setbe  %al
  shl    $0x2,%eax
  ret
```

assistant: ```c
int __libc_sa_len(sa_family_t af) {
  switch (af) {
  case AF_INET:
    return sizeof(struct sockaddr_in);
  case AF_LOCAL:
    return sizeof(struct sockaddr_un);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_missing_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L35
L10:
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x8,-0x4(%rbp)
  jle    L38
  mov    $0x1,%eax
L35:
  pop    %rbp
  ret
```

assistant: ```c
int ft_missing_c(int k, int sudoku[9][9], int j) {
  int i;
  i = 0;
  while (i < 9) {
    if (sudoku[i][j] == k)
      return (0);
    i++;
  }
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_missing_c>:
  endbr64
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rsi,%rdx,1),%rax
  lea    0x144(%rsi,%rdx,1),%rdx
L18:
  cmp    %edi,(%rax)
  je     L13
  add    $0x24,%rax
  cmp    %rdx,%rax
  jne    L18
  mov    $0x1,%eax
  ret
L13:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int ft_missing_c(int k, int sudoku[9][9], int j) {
  int i;
  i = 0;
  while (i < 9) {
    if (sudoku[i][j] == k)
      return (0);
    i++;
  }
  return (1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_missing_c>:
  endbr64
  movslq %edx,%rdx
  shl    $0x2,%rdx
  lea    (%rsi,%rdx,1),%rax
  lea    0x144(%rsi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    %edi,(%rax)
  je     L4
  add    $0x24,%rax
  cmp    %rdx,%rax
  jne    L8
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_missing_c(int k, int sudoku[9][9], int j) {
  int i;
  i = 0;
  while (i < 9) {
    if (sudoku[i][j] == k)
      return (0);
    i++;
  }
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_missing_c>:
  endbr64
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rax
  cmp    (%rsi,%rdx,4),%edi
  je     L68
  cmp    0x24(%rsi,%rax,1),%edi
  je     L68
  cmp    0x48(%rsi,%rax,1),%edi
  je     L68
  cmp    0x6c(%rsi,%rax,1),%edi
  je     L68
  cmp    0x90(%rsi,%rax,1),%edi
  je     L68
  cmp    0xb4(%rsi,%rax,1),%edi
  je     L68
  cmp    0xd8(%rsi,%rax,1),%edi
  je     L68
  cmp    0xfc(%rsi,%rax,1),%edi
  je     L68
  cmp    %edi,0x120(%rsi,%rax,1)
  setne  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_missing_c(int k, int sudoku[9][9], int j) {
  int i;
  i = 0;
  while (i < 9) {
    if (sudoku[i][j] == k)
      return (0);
    i++;
  }
  return (1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n | m;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n | m;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n | m;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n | m;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<writestr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L5
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string

tool: D7: write

assistant: ```c
void writestr(int fd, const char *s) {
  int r;
  r = write(fd, s, strlen(s));
  if (r <= 0) {
    perror("write");
    abort();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<writestr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  test   %eax,%eax
  jle    L15
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: write

assistant: ```c
void writestr(int fd, const char *s) {
  int r;
  r = write(fd, s, strlen(s));
  if (r <= 0) {
    perror("write");
    abort();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<writestr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %eax,%eax
  jle    L5
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  lea    D6(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <abort@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6: write

assistant: ```c
void writestr(int fd, const char *s) {
  int r;
  r = write(fd, s, strlen(s));
  if (r <= 0) {
    perror("write");
    abort();
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<writestr>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12d,%edi
  mov    %eax,%edx
  call   <write@plt>
  test   %eax,%eax
  jle    L0
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  lea    D0(%rip),%rdi
  call   <perror@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1080 <abort@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
data_type: string

tool: D0: write

assistant: ```c
void writestr(int fd, const char *s) {
  int r;
  r = write(fd, s, strlen(s));
  if (r <= 0) {
    perror("write");
    abort();
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utmpname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int utmpname(const char *file) {
  errno = ENOSYS;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<utmpname>:
  endbr64
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utmpname(const char *file) {
  errno = ENOSYS;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<utmpname>:
  endbr64
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utmpname(const char *file) {
  errno = ENOSYS;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<utmpname>:
  endbr64
  mov    D8(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int utmpname(const char *file) {
  errno = ENOSYS;
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<min>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L29
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L13
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
L13:
  addl   $0x1,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double min(double *ar, int len) {
  int i;
  double MinEntry;
  MinEntry = ar[0];
  for (i = 1; i < len; i++) {
    if (ar[i] < MinEntry) {
      MinEntry = ar[i];
    }
  }
  return MinEntry;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<min>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L18
  lea    0x8(%rdi),%rax
  lea    -0x2(%rsi),%edx
  lea    0x10(%rdi,%rdx,8),%rdx
L11:
  movsd  (%rax),%xmm1
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L11
L18:
  ret
```

assistant: ```c
double min(double *ar, int len) {
  int i;
  double MinEntry;
  MinEntry = ar[0];
  for (i = 1; i < len; i++) {
    if (ar[i] < MinEntry) {
      MinEntry = ar[i];
    }
  }
  return MinEntry;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L13
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L9:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L9
L13:
  ret
```

assistant: ```c
double min(double *ar, int len) {
  int i;
  double MinEntry;
  MinEntry = ar[0];
  for (i = 1; i < len; i++) {
    if (ar[i] < MinEntry) {
      MinEntry = ar[i];
    }
  }
  return MinEntry;
}
```
user: Translate the below assembly code into C programming language:

```asm
<min>:
  endbr64
  movsd  (%rdi),%xmm0
  cmp    $0x1,%esi
  jle    L19
  lea    -0x2(%rsi),%edx
  lea    0x8(%rdi),%rax
  lea    0x10(%rdi,%rdx,8),%rdx
  nopl   0x0(%rax)
L18:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  minsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  cmp    %rdx,%rax
  jne    L18
L19:
  ret
```

assistant: ```c
double min(double *ar, int len) {
  int i;
  double MinEntry;
  MinEntry = ar[0];
  for (i = 1; i < len; i++) {
    if (ar[i] < MinEntry) {
      MinEntry = ar[i];
    }
  }
  return MinEntry;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_memdel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L5
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L3
L5:
  nop
L3:
  leave
  ret
```

assistant: ```c
void ft_memdel(void **ap) {
  if (!ap)
    return;
  free(*ap);
  *ap = NULL;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_memdel>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
L8:
  ret
```

assistant: ```c
void ft_memdel(void **ap) {
  if (!ap)
    return;
  free(*ap);
  *ap = NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_memdel>:
  endbr64
  test   %rdi,%rdi
  je     L8
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L8:
  ret
```

assistant: ```c
void ft_memdel(void **ap) {
  if (!ap)
    return;
  free(*ap);
  *ap = NULL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_memdel>:
  endbr64
  test   %rdi,%rdi
  je     L6
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  pop    %rbx
  ret
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void ft_memdel(void **ap) {
  if (!ap)
    return;
  free(*ap);
  *ap = NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ang180>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x4(%rbp)
  jmp    L61
L17:
  movss  -0x4(%rbp),%xmm0
  comiss D41(%rip),%xmm0
  jb     L41
  movss  -0x4(%rbp),%xmm0
  movss  D12(%rip),%xmm1
  subss  %xmm1,%xmm0
  jmp    L51
L41:
  movss  -0x4(%rbp),%xmm0
L51:
  movss  %xmm0,-0x4(%rbp)
  movss  D13(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  jbe    L63
  movss  -0x4(%rbp),%xmm1
  movss  D12(%rip),%xmm0
  addss  %xmm1,%xmm0
  jmp    L57
L63:
  movss  -0x4(%rbp),%xmm0
L57:
  movss  %xmm0,-0x4(%rbp)
L61:
  movss  D13(%rip),%xmm0
  comiss -0x4(%rbp),%xmm0
  ja     L17
  movss  -0x4(%rbp),%xmm0
  comiss D41(%rip),%xmm0
  jae    L17
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D41
type_guessed: f32
name: parse_data
arguments: data_label: D12
type_guessed: f32
name: parse_data
arguments: data_label: D13
type_guessed: byte[4]

tool: D41: 180

tool: D12: 360

tool: {"D13": [0x00,0x00,0x34,0xc3]}

assistant: ```c
float ang180(float ang) {
  for (; ang < -180.0 || ang >= 180.0;) {
    ang = ang >= 180.0 ? ang - 360.0 : ang;
    ang = ang < -180.0 ? ang + 360.0 : ang;
  }
  return ang;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ang180>:
  endbr64
  movss  D28(%rip),%xmm1
  movss  D4(%rip),%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm3,%xmm4
  jmp    L22
L21:
  addss  %xmm4,%xmm0
  jmp    L22
L7:
  comiss D16(%rip),%xmm0
  jb     L21
L23:
  subss  %xmm3,%xmm0
  comiss %xmm0,%xmm2
  ja     L21
L22:
  comiss %xmm0,%xmm1
  ja     L7
  comiss D16(%rip),%xmm0
  jae    L23
  ret
```

tool_calls: name: parse_data
arguments: label: D28
type_guessed: byte[4]
name: parse_data
arguments: label: D4
type_guessed: f32
name: parse_data
arguments: label: D16
type_guessed: f32

tool: {"D28": [0x00,0x00,0x34,0xc3]}

tool: D4: 360

tool: D16: 180

assistant: ```c
float ang180(float ang) {
  for (; ang < -180.0 || ang >= 180.0;) {
    ang = ang >= 180.0 ? ang - 360.0 : ang;
    ang = ang < -180.0 ? ang + 360.0 : ang;
  }
  return ang;
}
```