ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x21,0x7(%rsp)
  lea    D79(%rip),%rbp
  lea    D8(%rip),%rbx
  lea    D67(%rip),%r13
  lea    D6(%rip),%r12
  jmp    L43
L11:
  cmp    $0x7,%al
  jne    L50
  lea    D44(%rip),%rdi
  call   <puts@plt>
L93:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  lea    D21(%rip),%rdx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L20:
  cmpb   $0x37,0x7(%rsp)
  je     L93
L43:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x7(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x3,%al
  je     L78
  jg     L11
  cmp    $0x1,%al
  je     L32
  cmp    $0x2,%al
  jne    L50
  lea    D2(%rip),%rdx
  mov    $0x2,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L78:
  mov    %r13,%rdx
  mov    $0x3,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L20
L50:
  lea    D33(%rip),%rdi
  call   <puts@plt>
  jmp    L20
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D79
data_type: string
name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D67
data_type: string
name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D44
data_type: string
name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D33
data_type: string

tool: D79: please input a number(1~3), 7 is quit :

tool: D8:  %d

tool: D67: INVALIDKEY

tool: D6: get msg id(%d), name(%s)


tool: D44: quit the function

tool: D21: QUEUEFULL

tool: D2: MULTIKEY

tool: D33: invalid nember

assistant: ```c
int main() {
  char input = '!';
  while (input != '7') {
    printf("please input a number(1~3), 7 is quit :");
    scanf(" %d", &input);
    switch (input) {
    case 7:
      printf("quit the function\n");
      return 0;
      break;
    case 0x01:
      printf("get msg id(%d), name(%s)\n", 0x01, "QUEUEFULL");
      break;
    case 0x02:
      printf("get msg id(%d), name(%s)\n", 0x02, "MULTIKEY");
      break;
    case 0x03:
      printf("get msg id(%d), name(%s)\n", 0x03, "INVALIDKEY");
      break;
    default:
      printf("invalid nember\n");
      continue;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D39(%rip),%r15
  push   %r14
  lea    D36(%rip),%r14
  push   %r13
  lea    D21(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D23(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x21,0x7(%rsp)
  lea    0x7(%rsp),%rbp
L109:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x3,%al
  je     L89
  jg     L40
  cmp    $0x1,%al
  je     L84
  cmp    $0x2,%al
  jne    L62
  lea    D44(%rip),%rdx
  mov    $0x2,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L78:
  cmpb   $0x37,0x7(%rsp)
  jne    L109
  nopl   0x0(%rax,%rax,1)
L76:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  cmp    $0x7,%al
  jne    L62
  lea    D73(%rip),%rdi
  call   <puts@plt>
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L89:
  mov    %r15,%rdx
  mov    $0x3,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L78
  nopl   0x0(%rax)
L62:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L84:
  lea    D58(%rip),%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L78
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D36
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D23
datatype: string
name: extract_symbolic_data
arguments: data_label: D44
datatype: string
name: extract_symbolic_data
arguments: data_label: D73
datatype: string
name: extract_symbolic_data
arguments: data_label: D58
datatype: string

tool: D39: INVALIDKEY

tool: D36: invalid nember

tool: D21: get msg id(%d), name(%s)


tool: D0: please input a number(1~3), 7 is quit :

tool: D23:  %d

tool: D44: MULTIKEY

tool: D73: quit the function

tool: D58: QUEUEFULL

assistant: ```c
int main() {
  char input = '!';
  while (input != '7') {
    printf("please input a number(1~3), 7 is quit :");
    scanf(" %d", &input);
    switch (input) {
    case 7:
      printf("quit the function\n");
      return 0;
      break;
    case 0x01:
      printf("get msg id(%d), name(%s)\n", 0x01, "QUEUEFULL");
      break;
    case 0x02:
      printf("get msg id(%d), name(%s)\n", 0x02, "MULTIKEY");
      break;
    case 0x03:
      printf("get msg id(%d), name(%s)\n", 0x03, "INVALIDKEY");
      break;
    default:
      printf("invalid nember\n");
      continue;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%r15
  push   %r14
  lea    D18(%rip),%r14
  push   %r13
  lea    D45(%rip),%r13
  push   %r12
  lea    D64(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D70(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x21,0x7(%rsp)
  lea    0x7(%rsp),%rbp
L109:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movzbl 0x7(%rsp),%eax
  cmp    $0x3,%al
  je     L45
  jg     L9
  cmp    $0x1,%al
  je     L32
  cmp    $0x2,%al
  jne    L27
  lea    D55(%rip),%rdx
  mov    $0x2,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L97:
  cmpb   $0x37,0x7(%rsp)
  jne    L109
  nopl   0x0(%rax,%rax,1)
L80:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L102
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L9:
  cmp    $0x7,%al
  jne    L27
  lea    D51(%rip),%rdi
  call   <puts@plt>
  jmp    L80
  nopw   0x0(%rax,%rax,1)
L45:
  mov    %r15,%rdx
  mov    $0x3,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L97
  nopl   0x0(%rax)
L27:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L97
  nopw   0x0(%rax,%rax,1)
L32:
  lea    D33(%rip),%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L97
L102:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D10
type_guessed: string
name: parse_data
arguments: label: D18
type_guessed: string
name: parse_data
arguments: label: D45
type_guessed: string
name: parse_data
arguments: label: D64
type_guessed: string
name: parse_data
arguments: label: D70
type_guessed: string
name: parse_data
arguments: label: D55
type_guessed: string
name: parse_data
arguments: label: D51
type_guessed: string
name: parse_data
arguments: label: D33
type_guessed: string

tool: D10: INVALIDKEY

tool: D18: invalid nember

tool: D45: get msg id(%d), name(%s)


tool: D64: please input a number(1~3), 7 is quit :

tool: D70:  %d

tool: D55: MULTIKEY

tool: D51: quit the function

tool: D33: QUEUEFULL

assistant: ```c
int main() {
  char input = '!';
  while (input != '7') {
    printf("please input a number(1~3), 7 is quit :");
    scanf(" %d", &input);
    switch (input) {
    case 7:
      printf("quit the function\n");
      return 0;
      break;
    case 0x01:
      printf("get msg id(%d), name(%s)\n", 0x01, "QUEUEFULL");
      break;
    case 0x02:
      printf("get msg id(%d), name(%s)\n", 0x02, "MULTIKEY");
      break;
    case 0x03:
      printf("get msg id(%d), name(%s)\n", 0x03, "INVALIDKEY");
      break;
    default:
      printf("invalid nember\n");
      continue;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D9(%rip),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <split@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L20
L23:
  mov    -0x20(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L20:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L23
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type: string
name: parse_data
arguments: data_label: D0
type: string

tool: D9:    foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   

tool: D0: <%s>


assistant: ```c
void main(void) {
  char *f = "   foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   ";
  char *c;
  c = malloc((strlen(f) + 1) * sizeof(char));
  strcpy(c, f);
  int len;
  char **words;
  split(c, &words, &len);
  int i;
  for (i = 0; i < len; i++) {
    printf("<%s>\n", words[i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <split@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L25
  mov    $0x0,%ebx
  lea    D18(%rip),%rbp
L18:
  mov    0x10(%rsp),%rax
  mov    (%rax,%rbx,8),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jg     L18
L25:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string
name: retrieve_data
arguments: tag: D18
type: string

tool: D8:    foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   

tool: D18: <%s>


assistant: ```c
void main(void) {
  char *f = "   foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   ";
  char *c;
  c = malloc((strlen(f) + 1) * sizeof(char));
  strcpy(c, f);
  int len;
  char **words;
  split(c, &words, &len);
  int i;
  for (i = 0; i < len; i++) {
    printf("<%s>\n", words[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L11
  xor    %ebx,%ebx
  lea    D9(%rip),%rbp
  nopl   0x0(%rax)
L4:
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,8),%rsi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L4
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D9
datatype: string

tool: D3:    foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   

tool: D9: <%s>


assistant: ```c
void main(void) {
  char *f = "   foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   ";
  char *c;
  c = malloc((strlen(f) + 1) * sizeof(char));
  strcpy(c, f);
  int len;
  char **words;
  split(c, &words, &len);
  int i;
  for (i = 0; i < len; i++) {
    printf("<%s>\n", words[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    0xc(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <split@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L0
  xor    %ebx,%ebx
  lea    D16(%rip),%rbp
  nopl   0x0(%rax)
L21:
  mov    0x10(%rsp),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,8),%rsi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,0xc(%rsp)
  jg     L21
L0:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D7
type_infered: string
name: retrieve_data
arguments: data_tag: D16
type_infered: string

tool: D7:    foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   

tool: D16: <%s>


assistant: ```c
void main(void) {
  char *f = "   foo bar baz  quux   a bb ccc ddd eeee     adsfad sfd dafsfdsfddffd   ";
  char *c;
  c = malloc((strlen(f) + 1) * sizeof(char));
  strcpy(c, f);
  int len;
  char **words;
  split(c, &words, &len);
  int i;
  for (i = 0; i < len; i++) {
    printf("<%s>\n", words[i]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_header_to_fix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  mov    (%rax),%eax
  and    $0x3f,%eax
  test   %eax,%eax
  je     L6
  mov    $0x1,%eax
  jmp    L1
L6:
  mov    $0x0,%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int is_header_to_fix(uint8_t *header_buffer) {
  if (header_buffer[7] & 0x3F)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<is_header_to_fix>:
  endbr64
  testb  $0x3f,0x1c(%rdi)
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_header_to_fix(uint8_t *header_buffer) {
  if (header_buffer[7] & 0x3F)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<is_header_to_fix>:
  endbr64
  xor    %eax,%eax
  testb  $0x3f,0x1c(%rdi)
  setne  %al
  ret
```

assistant: ```c
int is_header_to_fix(uint8_t *header_buffer) {
  if (header_buffer[7] & 0x3F)
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<is_header_to_fix>:
  endbr64
  xor    %eax,%eax
  testb  $0x3f,0x1c(%rdi)
  setne  %al
  ret
```

assistant: ```c
int is_header_to_fix(uint8_t *header_buffer) {
  if (header_buffer[7] & 0x3F)
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__ffssi2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L21
L36:
  movl   $0x1,-0x4(%rbp)
  jmp    L35
L39:
  mov    -0x18(%rbp),%rax
  shr    %eax
  mov    %eax,%eax
  mov    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L39
  mov    -0x4(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int __ffssi2(long i) {
  int b;
  if (i == 0)
    return 0;
  for (b = 1; !(i & 1); ++b)
    i = (unsigned int)i >> 1;
  return b;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__ffssi2>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  je     L32
  test   $0x1,%dil
  jne    L37
  mov    $0x1,%edx
L3:
  mov    %edi,%eax
  shr    %eax
  mov    %eax,%edi
  add    $0x1,%edx
  test   $0x1,%al
  je     L3
L32:
  mov    %edx,%eax
  ret
L37:
  mov    $0x1,%edx
  jmp    L32
```

assistant: ```c
int __ffssi2(long i) {
  int b;
  if (i == 0)
    return 0;
  for (b = 1; !(i & 1); ++b)
    i = (unsigned int)i >> 1;
  return b;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__ffssi2>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L21
  mov    $0x1,%r8d
  test   $0x1,%dil
  jne    L21
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edi,%eax
  add    $0x1,%r8d
  shr    %eax
  mov    %eax,%edi
  test   $0x1,%al
  je     L2
L21:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int __ffssi2(long i) {
  int b;
  if (i == 0)
    return 0;
  for (b = 1; !(i & 1); ++b)
    i = (unsigned int)i >> 1;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__ffssi2>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L18
  mov    $0x1,%r8d
  test   $0x1,%dil
  jne    L18
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %edi,%eax
  add    $0x1,%r8d
  shr    %eax
  mov    %eax,%edi
  test   $0x1,%al
  je     L19
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int __ffssi2(long i) {
  int b;
  if (i == 0)
    return 0;
  for (b = 1; !(i & 1); ++b)
    i = (unsigned int)i >> 1;
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wb_list_prepend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <wb_list_new_elem@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct wb_str_list *wb_list_prepend(struct wb_str_list *list, const char *str) {
  struct wb_str_list *new;
  new = wb_list_new_elem(strdup(str), list);
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wb_list_prepend>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <strdup@plt>
  mov    %eax,%edi
  mov    %rbx,%rsi
  call   <wb_list_new_elem@plt>
  pop    %rbx
  ret
```

assistant: ```c
struct wb_str_list *wb_list_prepend(struct wb_str_list *list, const char *str) {
  struct wb_str_list *new;
  new = wb_list_new_elem(strdup(str), list);
  return new;
}
```
user: What is the c source code of the assembly code below:

```asm
<wb_list_prepend>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <strdup@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <wb_list_new_elem@plt>
```

assistant: ```c
struct wb_str_list *wb_list_prepend(struct wb_str_list *list, const char *str) {
  struct wb_str_list *new;
  new = wb_list_new_elem(strdup(str), list);
  return new;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wb_list_prepend>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <strdup@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <wb_list_new_elem@plt>
```

assistant: ```c
struct wb_str_list *wb_list_prepend(struct wb_str_list *list, const char *str) {
  struct wb_str_list *new;
  new = wb_list_new_elem(strdup(str), list);
  return new;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<help03>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_guessed: string
name: extract_symbolic_data
arguments: label: D28
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string

tool: D14:   u                 unassemble 16 instrs starting at PC


tool: D28:   u  <addr>         unassemble 16 instrs starting at <addr>


tool: D23:   u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>


assistant: ```c
void help03(void) {
  printf("  u                 unassemble 16 instrs starting at PC\n");
  printf("  u  <addr>         unassemble 16 instrs starting at <addr>\n");
  printf("  u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<help03>:
  endbr64
  sub    $0x8,%rsp
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D24
datatype: string
name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D24:   u                 unassemble 16 instrs starting at PC


tool: D4:   u  <addr>         unassemble 16 instrs starting at <addr>


tool: D5:   u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>


assistant: ```c
void help03(void) {
  printf("  u                 unassemble 16 instrs starting at PC\n");
  printf("  u  <addr>         unassemble 16 instrs starting at <addr>\n");
  printf("  u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<help03>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D18
type: string
name: extract_symbolic_data
arguments: data_label: D5
type: string

tool: D17:   u                 unassemble 16 instrs starting at PC


tool: D18:   u  <addr>         unassemble 16 instrs starting at <addr>


tool: D5:   u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>


assistant: ```c
void help03(void) {
  printf("  u                 unassemble 16 instrs starting at PC\n");
  printf("  u  <addr>         unassemble 16 instrs starting at <addr>\n");
  printf("  u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<help03>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D16
data_type: string

tool: D8:   u                 unassemble 16 instrs starting at PC


tool: D1:   u  <addr>         unassemble 16 instrs starting at <addr>


tool: D16:   u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>


assistant: ```c
void help03(void) {
  printf("  u                 unassemble 16 instrs starting at PC\n");
  printf("  u  <addr>         unassemble 16 instrs starting at <addr>\n");
  printf("  u  <addr> <cnt>   unassemble <cnt> instrs starting at <addr>\n");
}
```