ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<disarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <debug@plt>
  mov    $0x0,%eax
  call   <kill_this_task@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string

tool: D5: Elixer disarmed.

assistant: ```c
void disarm(void) {
  debug("Elixer disarmed.");
  kill_this_task();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<disarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <debug@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <kill_this_task@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: Elixer disarmed.

assistant: ```c
void disarm(void) {
  debug("Elixer disarmed.");
  kill_this_task();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<disarm>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <debug@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <kill_this_task@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type_guessed: string

tool: D0: Elixer disarmed.

assistant: ```c
void disarm(void) {
  debug("Elixer disarmed.");
  kill_this_task();
}
```
user: What is the c source code of the assembly code below:

```asm
<http_log>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L5
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L5:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <http_vlog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void http_log(const char *fmt, ...) {
  va_list vargs;
  va_start(vargs, fmt);
  http_vlog(fmt, vargs);
  va_end(vargs);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<http_log>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <http_vlog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void http_log(const char *fmt, ...) {
  va_list vargs;
  va_start(vargs, fmt);
  http_vlog(fmt, vargs);
  va_end(vargs);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<http_log>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <http_vlog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void http_log(const char *fmt, ...) {
  va_list vargs;
  va_start(vargs, fmt);
  http_vlog(fmt, vargs);
  va_end(vargs);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<http_log>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <http_vlog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((format(printf, 1, 2))) void http_log(const char *fmt, ...) {
  va_list vargs;
  va_start(vargs, fmt);
  http_vlog(fmt, vargs);
  va_end(vargs);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<argvlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L16:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L16
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int argvlen(char const *const *argv) {
  int i = 0;
  while (*argv++)
    i++;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<argvlen>:
  endbr64
  lea    0x8(%rdi),%rax
  cmpq   $0x0,(%rdi)
  je     L2
  mov    $0x0,%edx
L7:
  add    $0x1,%edx
  add    $0x8,%rax
  cmpq   $0x0,-0x8(%rax)
  jne    L7
L8:
  mov    %edx,%eax
  ret
L2:
  mov    $0x0,%edx
  jmp    L8
```

assistant: ```c
int argvlen(char const *const *argv) {
  int i = 0;
  while (*argv++)
    i++;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<argvlen>:
  endbr64
  xor    %r8d,%r8d
  cmpq   $0x0,(%rdi)
  lea    0x8(%rdi),%rax
  je     L8
  nopl   0x0(%rax)
L3:
  add    $0x8,%rax
  add    $0x1,%r8d
  cmpq   $0x0,-0x8(%rax)
  jne    L3
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int argvlen(char const *const *argv) {
  int i = 0;
  while (*argv++)
    i++;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<argvlen>:
  endbr64
  xor    %r8d,%r8d
  cmpq   $0x0,(%rdi)
  lea    0x8(%rdi),%rax
  je     L10
  nopl   0x0(%rax)
L0:
  add    $0x8,%rax
  add    $0x1,%r8d
  cmpq   $0x0,-0x8(%rax)
  jne    L0
L10:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int argvlen(char const *const *argv) {
  int i = 0;
  while (*argv++)
    i++;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pulldown_drop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L45
  cmpl   $0x0,-0x18(%rbp)
  je     L45
  movl   $0x0,-0x4(%rbp)
L45:
  cmpl   $0x4,-0x14(%rbp)
  jne    L59
  cmpl   $0x0,-0x18(%rbp)
  jne    L59
  movl   $0x0,-0x4(%rbp)
L59:
  cmpl   $0x8,-0x14(%rbp)
  jne    L58
  cmpl   $0x0,-0x18(%rbp)
  jne    L58
  movl   $0x0,-0x4(%rbp)
L58:
  cmpl   $0x10,-0x14(%rbp)
  jne    L61
  cmpl   $0x0,-0x18(%rbp)
  je     L61
  movl   $0x0,-0x4(%rbp)
L61:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pulldown_drop(int action, int bottom_field) {
  int ret = 1;
  if (action == (1 << 0) && bottom_field)
    ret = 0;
  if (action == (1 << 2) && !bottom_field)
    ret = 0;
  if (action == (1 << 3) && !bottom_field)
    ret = 0;
  if (action == (1 << 4) && bottom_field)
    ret = 0;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pulldown_drop>:
  endbr64
  test   %esi,%esi
  setne  %cl
  sete   %dl
  cmp    $0x4,%edi
  jne    L36
  mov    $0x0,%eax
  test   %dl,%dl
  jne    L37
L36:
  cmp    $0x8,%edi
  jne    L49
  test   %dl,%dl
  je     L49
  mov    $0x0,%eax
L37:
  ret
L49:
  cmp    $0x1,%edi
  sete   %al
  and    %ecx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  cmp    $0x10,%edi
  jne    L37
  test   %cl,%cl
  mov    $0x0,%edx
  cmovne %edx,%eax
  ret
```

assistant: ```c
int pulldown_drop(int action, int bottom_field) {
  int ret = 1;
  if (action == (1 << 0) && bottom_field)
    ret = 0;
  if (action == (1 << 2) && !bottom_field)
    ret = 0;
  if (action == (1 << 3) && !bottom_field)
    ret = 0;
  if (action == (1 << 4) && bottom_field)
    ret = 0;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pulldown_drop>:
  endbr64
  test   %esi,%esi
  setne  %dl
  cmp    $0x1,%edi
  jne    L18
  xor    %eax,%eax
  test   %dl,%dl
  je     L18
  ret
  nopl   (%rax)
L18:
  test   %esi,%esi
  sete   %al
  cmp    $0x4,%edi
  jne    L32
  test   %al,%al
  je     L32
L14:
  xor    %eax,%eax
  ret
L32:
  cmp    $0x8,%edi
  jne    L21
  test   %al,%al
  jne    L14
L21:
  cmp    $0x10,%edi
  sete   %al
  and    %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int pulldown_drop(int action, int bottom_field) {
  int ret = 1;
  if (action == (1 << 0) && bottom_field)
    ret = 0;
  if (action == (1 << 2) && !bottom_field)
    ret = 0;
  if (action == (1 << 3) && !bottom_field)
    ret = 0;
  if (action == (1 << 4) && bottom_field)
    ret = 0;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pulldown_drop>:
  endbr64
  test   %esi,%esi
  setne  %dl
  cmp    $0x1,%edi
  jne    L14
  xor    %eax,%eax
  test   %dl,%dl
  je     L14
  ret
  nopl   (%rax)
L14:
  test   %esi,%esi
  sete   %al
  cmp    $0x4,%edi
  jne    L52
  test   %al,%al
  je     L52
L56:
  xor    %eax,%eax
  ret
L52:
  cmp    $0x8,%edi
  jne    L28
  test   %al,%al
  jne    L56
L28:
  cmp    $0x10,%edi
  sete   %al
  and    %edx,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
int pulldown_drop(int action, int bottom_field) {
  int ret = 1;
  if (action == (1 << 0) && bottom_field)
    ret = 0;
  if (action == (1 << 2) && !bottom_field)
    ret = 0;
  if (action == (1 << 3) && !bottom_field)
    ret = 0;
  if (action == (1 << 4) && bottom_field)
    ret = 0;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%ebx
  movd   %ebx,%xmm2
  ucomiss D31(%rip),%xmm2
  jp     L45
  je     L10
L45:
  movsd  D69(%rip),%xmm1
  movss  0x20(%rsp),%xmm0
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  D47(%rip),%xmm1
  mulss  0x1c(%rsp),%xmm1
  mulss  0x24(%rsp),%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  comiss %xmm0,%xmm1
  ja     L50
  movd   %ebx,%xmm4
  addss  %xmm4,%xmm4
  movss  %xmm4,0x8(%rsp)
  call   <sqrt@plt>
  mov    0x20(%rsp),%ebx
  movss  %xmm0,0xc(%rsp)
  movd   %ebx,%xmm7
  subss  %xmm7,%xmm0
  divss  0x8(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D35(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movd   %ebx,%xmm6
  xorps  D41(%rip),%xmm6
  movaps %xmm6,%xmm0
  subss  0xc(%rsp),%xmm0
  divss  0x8(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D43(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L10:
  lea    D88(%rip),%rdi
  call   <puts@plt>
  jmp    L0
L50:
  lea    D88(%rip),%rdi
  call   <puts@plt>
  jmp    L0
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D31
type_guessed: byte[4]
name: read_data
arguments: tag: D69
type_guessed: f64
name: read_data
arguments: tag: D47
type_guessed: f32
name: read_data
arguments: tag: D35
type_guessed: string
name: read_data
arguments: tag: D41
type_guessed: byte[16]
name: read_data
arguments: tag: D43
type_guessed: string
name: read_data
arguments: tag: D88
type_guessed: string

tool: D23: %f %f %f

tool: {"D31": [0x00,0x00,0x00,0x00]}

tool: D69: 2

tool: D47: 4

tool: D35: R1 = %.5f


tool: {"D41": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D43: R2 = %.5f


tool: D88: Impossivel calcular

assistant: ```c
int main(int argc, char const *argv[]) {
  float a, b, c;
  scanf("%f %f %f", &a, &b, &c);
  if (a == 0) {
    printf("Impossivel calcular\n");
    return 0;
  }
  float base = 2 * a;
  float delta = pow(b, 2.0) - 4 * a * c;
  if (delta < 0) {
    printf("Impossivel calcular\n");
    return 0;
  }
  delta = sqrt(delta);
  float r_1 = (b * -1 + delta) / base;
  float r_2 = (b * -1 + delta * -1) / base;
  printf("R1 = %.5f\n", r_1);
  printf("R2 = %.5f\n", r_2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D60(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  movss  0x1c(%rsp),%xmm2
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L34
  je     L7
L34:
  movsd  D7(%rip),%xmm1
  movss  0x20(%rsp),%xmm0
  movss  %xmm2,0x4(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  movss  D29(%rip),%xmm1
  mulss  0x1c(%rsp),%xmm1
  cvtsi2ss %eax,%xmm0
  mulss  0x24(%rsp),%xmm1
  subss  %xmm1,%xmm0
  comiss %xmm0,%xmm4
  ja     L7
  movss  0x4(%rsp),%xmm2
  addss  %xmm2,%xmm2
  movss  %xmm2,0x4(%rsp)
  call   <sqrt@plt>
  movss  0x20(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D11(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  subss  %xmm1,%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  lea    D16(%rip),%rdi
  xorps  D22(%rip),%xmm1
  mov    $0x1,%eax
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L35
L7:
  lea    D30(%rip),%rdi
  call   <puts@plt>
L35:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D60
data_type: string
name: read_data
arguments: data_label: D7
data_type: f64
name: read_data
arguments: data_label: D29
data_type: f32
name: read_data
arguments: data_label: D11
data_type: string
name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D22
data_type: byte[16]
name: read_data
arguments: data_label: D30
data_type: string

tool: D60: %f %f %f

tool: D7: 2

tool: D29: 4

tool: D11: R1 = %.5f


tool: D16: R2 = %.5f


tool: {"D22": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D30: Impossivel calcular

assistant: ```c
int main(int argc, char const *argv[]) {
  float a, b, c;
  scanf("%f %f %f", &a, &b, &c);
  if (a == 0) {
    printf("Impossivel calcular\n");
    return 0;
  }
  float base = 2 * a;
  float delta = pow(b, 2.0) - 4 * a * c;
  if (delta < 0) {
    printf("Impossivel calcular\n");
    return 0;
  }
  delta = sqrt(delta);
  float r_1 = (b * -1 + delta) / base;
  float r_2 = (b * -1 + delta * -1) / base;
  printf("R1 = %.5f\n", r_1);
  printf("R2 = %.5f\n", r_2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x24(%rsp),%rcx
  lea    0x20(%rsp),%rdx
  lea    0x1c(%rsp),%rsi
  call   <scanf@plt>
  movss  0x1c(%rsp),%xmm2
  pxor   %xmm3,%xmm3
  ucomiss %xmm3,%xmm2
  jp     L47
  je     L49
L47:
  movsd  D12(%rip),%xmm1
  movss  0x20(%rsp),%xmm0
  movss  %xmm2,0x4(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm4,%xmm4
  movss  D47(%rip),%xmm1
  mulss  0x1c(%rsp),%xmm1
  cvtsi2ss %eax,%xmm0
  mulss  0x24(%rsp),%xmm1
  subss  %xmm1,%xmm0
  comiss %xmm0,%xmm4
  ja     L49
  movss  0x4(%rsp),%xmm2
  addss  %xmm2,%xmm2
  movss  %xmm2,0x4(%rsp)
  call   <sqrt@plt>
  movss  0x20(%rsp),%xmm1
  mov    $0x1,%eax
  lea    D1(%rip),%rdi
  movss  %xmm0,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  subss  %xmm1,%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  movss  0x8(%rsp),%xmm1
  movss  0xc(%rsp),%xmm2
  lea    D55(%rip),%rdi
  xorps  D9(%rip),%xmm1
  mov    $0x1,%eax
  movaps %xmm1,%xmm0
  subss  %xmm2,%xmm0
  divss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L35
L49:
  lea    D19(%rip),%rdi
  call   <puts@plt>
L35:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D12
type_guessed: f64
name: read_data
arguments: data_label: D47
type_guessed: f32
name: read_data
arguments: data_label: D1
type_guessed: string
name: read_data
arguments: data_label: D55
type_guessed: string
name: read_data
arguments: data_label: D9
type_guessed: byte[16]
name: read_data
arguments: data_label: D19
type_guessed: string

tool: D15: %f %f %f

tool: D12: 2

tool: D47: 4

tool: D1: R1 = %.5f


tool: D55: R2 = %.5f


tool: {"D9": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D19: Impossivel calcular

assistant: ```c
int main(int argc, char const *argv[]) {
  float a, b, c;
  scanf("%f %f %f", &a, &b, &c);
  if (a == 0) {
    printf("Impossivel calcular\n");
    return 0;
  }
  float base = 2 * a;
  float delta = pow(b, 2.0) - 4 * a * c;
  if (delta < 0) {
    printf("Impossivel calcular\n");
    return 0;
  }
  delta = sqrt(delta);
  float r_1 = (b * -1 + delta) / base;
  float r_2 = (b * -1 + delta * -1) / base;
  printf("R1 = %.5f\n", r_1);
  printf("R2 = %.5f\n", r_2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
uint64_t read_uint64(FILE *in) {
  uint64_t x;
  assert(fread(&x, sizeof(uint64_t), 1, in) == 1);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_uint64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t read_uint64(FILE *in) {
  uint64_t x;
  assert(fread(&x, sizeof(uint64_t), 1, in) == 1);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_uint64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t read_uint64(FILE *in) {
  uint64_t x;
  assert(fread(&x, sizeof(uint64_t), 1, in) == 1);
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_uint64>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t read_uint64(FILE *in) {
  uint64_t x;
  assert(fread(&x, sizeof(uint64_t), 1, in) == 1);
  return x;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <FD_ZERO@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <FD_SET@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <FD_SET@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <FD_SET@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x7,%edi
  call   <FD_SET@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <FD_CLR@plt>
  mov    $0x4,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string

tool: D0: isset = %d


tool: D5: fdset sizeof is %ld


assistant: ```c
int main() {
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(1, &fdset);
  FD_SET(2, &fdset);
  FD_SET(3, &fdset);
  FD_SET(7, &fdset);
  int isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  FD_CLR(3, &fdset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <FD_ZERO@plt>
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <FD_SET@plt>
  mov    %rbx,%rsi
  mov    $0x2,%edi
  call   <FD_SET@plt>
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <FD_SET@plt>
  mov    %rbx,%rsi
  mov    $0x7,%edi
  call   <FD_SET@plt>
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D0(%rip),%r12
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <FD_CLR@plt>
  mov    $0x4,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    $0x3,%edi
  call   <FD_ISSET@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D0
type: string

tool: D1: isset = %d


tool: D0: fdset sizeof is %ld


assistant: ```c
int main() {
  fd_set fdset;
  FD_ZERO(&fdset);
  FD_SET(1, &fdset);
  FD_SET(2, &fdset);
  FD_SET(3, &fdset);
  FD_SET(7, &fdset);
  int isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  FD_CLR(3, &fdset);
  printf("fdset sizeof is %ld\n", sizeof(fdset));
  isset = FD_ISSET(3, &fdset);
  printf("isset = %d\n", isset);
  return 0;
}
```