ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%rax
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap(void *vector[], int source, int target) {
  void *place_holder = vector[source];
  vector[source] = vector[target];
  vector[target] = place_holder;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,8),%rcx
  mov    (%rcx),%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *vector[], int source, int target) {
  void *place_holder = vector[source];
  vector[source] = vector[target];
  vector[target] = place_holder;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *vector[], int source, int target) {
  void *place_holder = vector[source];
  vector[source] = vector[target];
  vector[target] = place_holder;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,8),%rcx
  lea    (%rdi,%rdx,8),%rax
  mov    (%rcx),%rsi
  mov    (%rax),%rdx
  mov    %rdx,(%rcx)
  mov    %rsi,(%rax)
  ret
```

assistant: ```c
void swap(void *vector[], int source, int target) {
  void *place_holder = vector[source];
  vector[source] = vector[target];
  vector[target] = place_holder;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<syscon_write_quaddobl_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x17d,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int syscon_write_quaddobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(381, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below?

```asm
<syscon_write_quaddobl_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x17d,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int syscon_write_quaddobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(381, a, b, c, 0);
  return fail;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<syscon_write_quaddobl_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x17d,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int syscon_write_quaddobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(381, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<syscon_write_quaddobl_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x17d,%edi
  jmp    1050 <_ada_use_c2phc4c@plt>
```

assistant: ```c
int syscon_write_quaddobl_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(381, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dgl_mempush>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L4
  movq   $0x0,-0x8(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L21
  mov    $0x0,%eax
  jmp    L25
L21:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  imul   -0x18(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
L25:
  leave
  ret
```

assistant: ```c
unsigned char *dgl_mempush(unsigned char *pstack, long *istack, long size, void *pv) {
  if (*istack == 0)
    pstack = NULL;
  pstack = realloc(pstack, size * (1 + *istack));
  if (pstack == NULL)
    return NULL;
  memcpy(&pstack[(*istack) * size], pv, size);
  (*istack)++;
  return pstack;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dgl_mempush>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  mov    $0x0,%eax
  cmove  %rax,%rdi
  add    $0x1,%rsi
  imul   %rdx,%rsi
  call   <realloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L9
  mov    %rbp,%rdi
  imul   (%rbx),%rdi
  add    %rax,%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  addq   $0x1,(%rbx)
L9:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *dgl_mempush(unsigned char *pstack, long *istack, long size, void *pv) {
  if (*istack == 0)
    pstack = NULL;
  pstack = realloc(pstack, size * (1 + *istack));
  if (pstack == NULL)
    return NULL;
  memcpy(&pstack[(*istack) * size], pv, size);
  (*istack)++;
  return pstack;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dgl_mempush>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  cmove  %rax,%rdi
  add    $0x1,%rsi
  imul   %rdx,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    (%rbx),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  imul   %r13,%rdi
  add    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x1,(%rbx)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *dgl_mempush(unsigned char *pstack, long *istack, long size, void *pv) {
  if (*istack == 0)
    pstack = NULL;
  pstack = realloc(pstack, size * (1 + *istack));
  if (pstack == NULL)
    return NULL;
  memcpy(&pstack[(*istack) * size], pv, size);
  (*istack)++;
  return pstack;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dgl_mempush>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rsi
  test   %rsi,%rsi
  cmove  %rax,%rdi
  add    $0x1,%rsi
  imul   %rdx,%rsi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    (%rbx),%rdi
  mov    %r13,%rdx
  mov    %rbp,%rsi
  imul   %r13,%rdi
  add    %rax,%rdi
  call   <memcpy@plt>
  addq   $0x1,(%rbx)
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
unsigned char *dgl_mempush(unsigned char *pstack, long *istack, long size, void *pv) {
  if (*istack == 0)
    pstack = NULL;
  pstack = realloc(pstack, size * (1 + *istack));
  if (pstack == NULL)
    return NULL;
  memcpy(&pstack[(*istack) * size], pv, size);
  (*istack)++;
  return pstack;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L40
L27:
  movl   $0x0,-0x10(%rbp)
  jmp    L44
L55:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L44:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L55
  movl   $0x0,-0x10(%rbp)
  jmp    L13
L48:
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L13:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L48
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x2,-0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L40:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L27
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D25
data_type: string
name: unpack_data
arguments: label: D27
data_type: string
name: unpack_data
arguments: label: D1
data_type: string
name: unpack_data
arguments: label: D16
data_type: string

tool: D25: %d

tool: D27:  

tool: D1: #

tool: D16: 


assistant: ```c
int main() {
  int i, j, count, n;
  scanf("%d", &n);
  count = n * 2 - 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++)
      printf(" ");
    for (j = 0; j < count; j++)
      printf("#");
    printf("\n");
    count -= 2;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax,%rax,1),%ebp
  mov    $0x0,%r12d
  lea    D9(%rip),%r14
  lea    D36(%rip),%r13
  test   %eax,%eax
  jg     L53
L57:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L9:
  mov    $0x0,%ebx
L3:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%r12d
  jne    L3
L59:
  mov    %r15d,%r12d
L53:
  test   %ebp,%ebp
  jle    L74
  mov    $0x0,%ebx
L24:
  mov    %r14,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L24
L74:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  sub    $0x2,%ebp
  lea    0x1(%r12),%r15d
  cmp    %r15d,0x4(%rsp)
  jle    L57
  test   %r15d,%r15d
  jg     L9
  jmp    L59
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string
name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D36
data_type: string
name: disassemble_data
arguments: label: D32
data_type: string

tool: D0: %d

tool: D9: #

tool: D36:  

tool: D32: 


assistant: ```c
int main() {
  int i, j, count, n;
  scanf("%d", &n);
  count = n * 2 - 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++)
      printf(" ");
    for (j = 0; j < count; j++)
      printf("#");
    printf("\n");
    count -= 2;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D21(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L44
  lea    -0x1(%rax,%rax,1),%ebp
  xor    %r12d,%r12d
  lea    D10(%rip),%r14
  lea    D29(%rip),%r13
L28:
  test   %ebp,%ebp
  jle    L64
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L15
L64:
  lea    D38(%rip),%rdi
  sub    $0x2,%ebp
  lea    0x1(%r12),%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jle    L44
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L57:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r15d,%eax
  add    $0x1,%r15d
  cmp    %eax,%r12d
  jne    L57
  mov    %ebx,%r12d
  jmp    L28
  nopl   0x0(%rax)
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
data_type: string
name: unpack_data
arguments: data_label: D10
data_type: string
name: unpack_data
arguments: data_label: D29
data_type: string
name: unpack_data
arguments: data_label: D38
data_type: string

tool: D21: %d

tool: D10: #

tool: D29:  

tool: D38: 


assistant: ```c
int main() {
  int i, j, count, n;
  scanf("%d", &n);
  count = n * 2 - 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++)
      printf(" ");
    for (j = 0; j < count; j++)
      printf("#");
    printf("\n");
    count -= 2;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D9(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L61
  lea    -0x1(%rax,%rax,1),%ebp
  xor    %r12d,%r12d
  lea    D35(%rip),%r14
  lea    D21(%rip),%r13
L46:
  test   %ebp,%ebp
  jle    L66
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,%ebp
  jne    L8
L66:
  lea    D26(%rip),%rdi
  sub    $0x2,%ebp
  lea    0x1(%r12),%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jle    L61
  xor    %r15d,%r15d
  nopl   0x0(%rax)
L9:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r15d,%eax
  add    $0x1,%r15d
  cmp    %eax,%r12d
  jne    L9
  mov    %ebx,%r12d
  jmp    L46
  nopl   0x0(%rax)
L61:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string
name: extract_symbolic_data
arguments: data_label: D35
datatype: string
name: extract_symbolic_data
arguments: data_label: D21
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string

tool: D9: %d

tool: D35: #

tool: D21:  

tool: D26: 


assistant: ```c
int main() {
  int i, j, count, n;
  scanf("%d", &n);
  count = n * 2 - 1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < i; j++)
      printf(" ");
    for (j = 0; j < count; j++)
      printf("#");
    printf("\n");
    count -= 2;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tputs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  jmp    L8
L6:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %eax,%edi
  mov    $0x0,%eax
  call   *%rdx
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  nop
  leave
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)()) {
  while (*string)
    outfun(*string++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tputs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdx,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L3
L7:
  add    $0x1,%rbx
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   *%rbp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L7
L3:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)()) {
  while (*string)
    outfun(*string++);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tputs>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L15
  mov    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbx
  xor    %eax,%eax
  call   *%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L11
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)()) {
  while (*string)
    outfun(*string++);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tputs>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L16
  mov    %rdx,%rbp
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rbx
  xor    %eax,%eax
  call   *%rbp
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L19
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tputs(char *string, int nlines, int (*outfun)()) {
  while (*string)
    outfun(*string++);
}
```
user: What is the c source code of the assembly code below:

```asm
<average>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L37
  pxor   %xmm0,%xmm0
  jmp    L28
L37:
  movl   $0x0,-0x8(%rbp)
  jmp    L24
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L24:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L25
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x4(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  divss  %xmm1,%xmm0
L28:
  pop    %rbp
  ret
```

assistant: ```c
float average(float *arr, int count) {
  float Sum = 0.0;
  int j, n = 0;
  if (count == 0) {
    return 0.0;
  }
  for (j = 0; j < count; j++) {
    Sum += arr[j];
    n++;
  }
  return Sum / n;
}
```
user: What is the c source code of the assembly code below?

```asm
<average>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  je     L6
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
L4:
  addss  (%rax),%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
L14:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
L6:
  ret
L10:
  mov    $0x0,%esi
  pxor   %xmm0,%xmm0
  jmp    L14
```

assistant: ```c
float average(float *arr, int count) {
  float Sum = 0.0;
  int j, n = 0;
  if (count == 0) {
    return 0.0;
  }
  for (j = 0; j < count; j++) {
    Sum += arr[j];
    n++;
  }
  return Sum / n;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<average>:
  endbr64
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  je     L15
  jle    L9
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  cs nopw 0x0(%rax,%rax,1)
L14:
  addss  (%rdi),%xmm0
  add    $0x4,%rdi
  cmp    %rdi,%rax
  jne    L14
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
L6:
  divss  %xmm1,%xmm0
L15:
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  movaps %xmm0,%xmm1
  jmp    L6
```

assistant: ```c
float average(float *arr, int count) {
  float Sum = 0.0;
  int j, n = 0;
  if (count == 0) {
    return 0.0;
  }
  for (j = 0; j < count; j++) {
    Sum += arr[j];
    n++;
  }
  return Sum / n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<average>:
  endbr64
  mov    %rdi,%rdx
  pxor   %xmm0,%xmm0
  test   %esi,%esi
  je     L77
  jle    L58
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L23
  mov    %esi,%ecx
  mov    %rdi,%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax)
L2:
  movups (%rax),%xmm1
  add    $0x10,%rax
  addss  %xmm1,%xmm0
  movaps %xmm1,%xmm2
  shufps $0x55,%xmm1,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm1,%xmm2
  unpckhps %xmm1,%xmm2
  shufps $0xff,%xmm1,%xmm1
  addss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L2
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L71
L1:
  movslq %eax,%rcx
  addss  (%rdx,%rcx,4),%xmm0
  lea    0x0(,%rcx,4),%rdi
  lea    0x1(%rax),%ecx
  cmp    %ecx,%esi
  jle    L71
  add    $0x2,%eax
  addss  0x4(%rdx,%rdi,1),%xmm0
  cmp    %eax,%esi
  jle    L71
  addss  0x8(%rdx,%rdi,1),%xmm0
L71:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
L63:
  divss  %xmm1,%xmm0
L77:
  ret
  nop
L58:
  movaps %xmm0,%xmm1
  jmp    L63
L23:
  xor    %eax,%eax
  jmp    L1
```

assistant: ```c
float average(float *arr, int count) {
  float Sum = 0.0;
  int j, n = 0;
  if (count == 0) {
    return 0.0;
  }
  for (j = 0; j < count; j++) {
    Sum += arr[j];
    n++;
  }
  return Sum / n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fetch_proxy_settings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,%eax
  mov    %r9d,%edx
  mov    %al,-0x44(%rbp)
  mov    %edx,%eax
  mov    %al,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpb   $0x0,-0x44(%rbp)
  je     L13
  lea    D18(%rip),%rax
  jmp    L20
L13:
  lea    D5(%rip),%rax
L20:
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L15
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movsbl -0x44(%rbp),%r9d
  movsbl -0x48(%rbp),%r8d
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  lea    -0x20(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  sub    $0x8,%rsp
  push   -0x30(%rbp)
  push   -0x28(%rbp)
  lea    -0x18(%rbp),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <interpret_url@plt>
  add    $0x20,%rsp
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L15:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_infered: string
name: disassemble_data
arguments: data_label: D5
type_infered: string

tool: D18: https_proxy

tool: D5: http_proxy

assistant: ```c
void fetch_proxy_settings(char **proxy_user, char **proxy_password, char **proxy_host, int *proxy_port, char use_ssl, char use_ipv6) {
  char *str = getenv(use_ssl ? "https_proxy" : "http_proxy");
  if (!str) {
  }
  if (str) {
    char *path = NULL, *url = NULL;
    interpret_url(str, &path, proxy_host, proxy_port, use_ipv6, use_ssl, &url, proxy_user, proxy_password);
    free(url);
    free(path);
  }
}
```