ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<smtp_auth_plain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  lea    (%rdx,%r8,1),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x12(%rbx),%rax
  mov    %rsp,%rdi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L50
L41:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L41
L50:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L11
L47:
  lea    0x1(%rsp),%rdi
  movb   $0x0,(%rsp)
  call   <mempcpy@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <memcpy@plt>
  lea    0x2(%rbx),%rsi
  xor    %edx,%edx
  mov    %rsp,%rdi
  call   <base64_encode@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L10
  mov    $0x1,%edi
  call   <exit@plt>
L10:
  mov    %r13,%rdx
  lea    D4(%rip),%rsi
  mov    %r12,%rdi
  call   <sock_sendmsg@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <smtp_get_msg@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   (%rax)
L11:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L47
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
datatype: string

tool: D4: AUTH PLAIN %s

assistant: ```c
int smtp_auth_plain(struct sock *sock, const char *user, size_t user_size, const char *passwd, size_t passwd_size) {
  const size_t total_size = user_size + passwd_size + 2;
  unsigned char buf[total_size + 1], *p = buf;
  *p++ = '\0';
  p = mempcpy(p, user, user_size);
  *p++ = '\0';
  memcpy(p, passwd, passwd_size);
  char *encoded = base64_encode(buf, total_size, NULL);
  if (!encoded)
    exit(1);
  sock_sendmsg(sock, "AUTH PLAIN %s", encoded);
  free(encoded);
  return smtp_get_msg(sock, 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<smtp_auth_plain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %r8,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  lea    (%rdx,%r8,1),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    0x12(%rbx),%rax
  mov    %rsp,%rdi
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rdi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rdi,%rsp
  je     L1
L25:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rdi,%rsp
  jne    L25
L1:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L49
L2:
  lea    0x1(%rsp),%rdi
  movb   $0x0,(%rsp)
  call   <mempcpy@plt>
  mov    %r13,%rdx
  mov    %r14,%rsi
  movb   $0x0,(%rax)
  lea    0x1(%rax),%rdi
  call   <memcpy@plt>
  lea    0x2(%rbx),%rsi
  xor    %edx,%edx
  mov    %rsp,%rdi
  call   <base64_encode@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L13
  mov    $0x1,%edi
  call   <exit@plt>
L13:
  mov    %r13,%rdx
  lea    D9(%rip),%rsi
  mov    %r12,%rdi
  call   <sock_sendmsg@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <smtp_get_msg@plt>
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   (%rax)
L49:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L2
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D9
datatype: string

tool: D9: AUTH PLAIN %s

assistant: ```c
int smtp_auth_plain(struct sock *sock, const char *user, size_t user_size, const char *passwd, size_t passwd_size) {
  const size_t total_size = user_size + passwd_size + 2;
  unsigned char buf[total_size + 1], *p = buf;
  *p++ = '\0';
  p = mempcpy(p, user, user_size);
  *p++ = '\0';
  memcpy(p, passwd, passwd_size);
  char *encoded = base64_encode(buf, total_size, NULL);
  if (!encoded)
    exit(1);
  sock_sendmsg(sock, "AUTH PLAIN %s", encoded);
  free(encoded);
  return smtp_get_msg(sock, 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L2:
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 1000; i++)
    asm volatile("" ::: "memory");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<foo>:
  endbr64
  mov    $0x3e8,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 1000; i++)
    asm volatile("" ::: "memory");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<foo>:
  endbr64
  mov    $0x3e8,%eax
  nopl   0x0(%rax)
L5:
  sub    $0x1,%eax
  jne    L5
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 1000; i++)
    asm volatile("" ::: "memory");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  mov    $0x3e8,%eax
  nopl   0x0(%rax)
L1:
  sub    $0x1,%eax
  jne    L1
  ret
```

assistant: ```c
void foo(void) {
  int i;
  for (i = 0; i < 1000; i++)
    asm volatile("" ::: "memory");
}
```
user: Translate the below assembly code into C programming language:

```asm
<x_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L10:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L5
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  shl    $0x2,%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  subl   $0x1,-0x4(%rbp)
L5:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L10
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x28(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int x_vector(int x, int *n, int **vector) {
  for (int i = 0; i < *n; i++) {
    if ((*vector)[i] == x) {
      (*vector)[i] = (*vector)[i + 1];
      *n -= 1;
      i--;
    }
  }
  (*vector) = realloc((*vector), *n * sizeof(**vector));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<x_vector>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  mov    (%rsi),%edx
  test   %edx,%edx
  jle    L30
  mov    $0x0,%eax
  jmp    L16
L12:
  add    $0x1,%eax
  mov    (%rsi),%edx
  cmp    %eax,%edx
  jle    L30
L16:
  mov    (%rbx),%r8
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    (%r8,%rdx,1),%rcx
  cmp    %edi,(%rcx)
  jne    L12
  mov    0x4(%r8,%rdx,1),%edx
  mov    %edx,(%rcx)
  subl   $0x1,(%rsi)
  sub    $0x1,%eax
  jmp    L12
L30:
  lea    0x0(,%rdx,4),%esi
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int x_vector(int x, int *n, int **vector) {
  for (int i = 0; i < *n; i++) {
    if ((*vector)[i] == x) {
      (*vector)[i] = (*vector)[i + 1];
      *n -= 1;
      i--;
    }
  }
  (*vector) = realloc((*vector), *n * sizeof(**vector));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<x_vector>:
  endbr64
  push   %rbx
  mov    (%rsi),%eax
  mov    %edi,%r9d
  mov    %rdx,%rbx
  mov    (%rdx),%rdi
  test   %eax,%eax
  jle    L8
  xor    %ecx,%ecx
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L22:
  mov    (%rsi),%eax
  add    $0x1,%ecx
  cmp    %ecx,%eax
  jle    L8
L4:
  movslq %ecx,%rax
  shl    $0x2,%rax
  lea    (%rdi,%rax,1),%r8
  cmp    %r9d,(%r8)
  jne    L22
  mov    0x4(%rdi,%rax,1),%eax
  mov    %eax,(%r8)
  mov    (%rsi),%eax
  sub    $0x1,%eax
  mov    %eax,(%rsi)
  cmp    %ecx,%eax
  jg     L4
L8:
  lea    0x0(,%rax,4),%esi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int x_vector(int x, int *n, int **vector) {
  for (int i = 0; i < *n; i++) {
    if ((*vector)[i] == x) {
      (*vector)[i] = (*vector)[i + 1];
      *n -= 1;
      i--;
    }
  }
  (*vector) = realloc((*vector), *n * sizeof(**vector));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<x_vector>:
  endbr64
  push   %rbx
  mov    (%rsi),%ecx
  mov    %edi,%r11d
  mov    %rdx,%rbx
  mov    (%rdx),%rdi
  test   %ecx,%ecx
  jle    L6
  xor    %eax,%eax
  xor    %r10d,%r10d
  nopl   0x0(%rax)
L14:
  lea    0x0(,%r10,4),%r9
  lea    (%rdi,%r9,1),%r8
  cmp    %r11d,(%r8)
  je     L17
  add    $0x1,%eax
  cmp    %eax,%ecx
  jle    L6
  movslq %eax,%r10
  jmp    L14
  nopl   (%rax)
L17:
  mov    0x4(%rdi,%r9,1),%ecx
  mov    %ecx,(%r8)
  mov    (%rsi),%edx
  lea    -0x1(%rdx),%ecx
  mov    %ecx,(%rsi)
  cmp    %eax,%ecx
  jg     L14
L6:
  lea    0x0(,%rcx,4),%esi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int x_vector(int x, int *n, int **vector) {
  for (int i = 0; i < *n; i++) {
    if ((*vector)[i] == x) {
      (*vector)[i] = (*vector)[i + 1];
      *n -= 1;
      i--;
    }
  }
  (*vector) = realloc((*vector), *n * sizeof(**vector));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<func8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  movl   $0x384,(%rax)
  jmp    L3
L0:
  nop
L3:
  pop    %rbp
  ret
```

assistant: ```c
void func8(int *aptr) {
  if (!aptr) {
    if (1 == 0) {
      int k = 10;
      int l = 20;
    }
    return;
  }
  *aptr = 900;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<func8>:
  endbr64
  test   %rdi,%rdi
  je     L4
  movl   $0x384,(%rdi)
L4:
  ret
```

assistant: ```c
void func8(int *aptr) {
  if (!aptr) {
    if (1 == 0) {
      int k = 10;
      int l = 20;
    }
    return;
  }
  *aptr = 900;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func8>:
  endbr64
  test   %rdi,%rdi
  je     L3
  movl   $0x384,(%rdi)
L3:
  ret
```

assistant: ```c
void func8(int *aptr) {
  if (!aptr) {
    if (1 == 0) {
      int k = 10;
      int l = 20;
    }
    return;
  }
  *aptr = 900;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func8>:
  endbr64
  test   %rdi,%rdi
  je     L9
  movl   $0x384,(%rdi)
L9:
  ret
```

assistant: ```c
void func8(int *aptr) {
  if (!aptr) {
    if (1 == 0) {
      int k = 10;
      int l = 20;
    }
    return;
  }
  *aptr = 900;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x7869d624,-0x8(%rbp)
  jmp    L34
L33:
  movl   $0x2,-0x4(%rbp)
  jmp    L14
L3:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L31
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x8(%rbp)
  jge    L3
  jmp    L54
L31:
  nop
L54:
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L40
  subl   $0x1,-0x8(%rbp)
  nop
L34:
  cmpl   $0x0,-0x8(%rbp)
  jg     L33
  jmp    L74
L40:
  nop
L74:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int prime() {
  int i = 2020202020;
  while (i > 0) {
    int j = 2;
    while (j * j <= i) {
      if (i % j == 0)
        break;
      j = j + 1;
    }
    if (i % j == 0) {
      i = i - 1;
      continue;
    }
    break;
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prime>:
  endbr64
  mov    $0x7869d623,%r8d
  mov    $0x7869d624,%edi
L63:
  mov    %edi,%esi
  cmp    $0x3,%edi
  jle    L20
  test   $0x1,%dil
  je     L65
  mov    $0x2,%ecx
L51:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %esi,%eax
  jg     L81
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L51
L65:
  mov    %r8d,%esi
  test   %r8d,%r8d
  jle    L18
L79:
  sub    $0x1,%edi
  sub    $0x1,%r8d
  jmp    L63
L20:
  test   $0x1,%dil
  jne    L18
  jmp    L65
L81:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L79
L18:
  mov    %esi,%eax
  ret
```

assistant: ```c
int prime() {
  int i = 2020202020;
  while (i > 0) {
    int j = 2;
    while (j * j <= i) {
      if (i % j == 0)
        break;
      j = j + 1;
    }
    if (i % j == 0) {
      i = i - 1;
      continue;
    }
    break;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime>:
  endbr64
  mov    $0x7869d623,%edi
  mov    $0x7869d624,%esi
L36:
  mov    %esi,%eax
  mov    %esi,%r8d
  and    $0x1,%eax
  cmp    $0x3,%esi
  jle    L2
  test   %eax,%eax
  je     L62
  mov    $0x2,%ecx
  jmp    L17
  cs nopw 0x0(%rax,%rax,1)
L71:
  test   %edx,%edx
  je     L62
L17:
  mov    %esi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %esi,%eax
  jle    L71
  test   %edx,%edx
  je     L56
L50:
  mov    %r8d,%eax
  ret
L2:
  test   %eax,%eax
  jne    L50
  nopl   0x0(%rax)
L62:
  test   %edi,%edi
  je     L84
L56:
  sub    $0x1,%esi
  sub    $0x1,%edi
  jmp    L36
L84:
  xor    %r8d,%r8d
  jmp    L50
```

assistant: ```c
int prime() {
  int i = 2020202020;
  while (i > 0) {
    int j = 2;
    while (j * j <= i) {
      if (i % j == 0)
        break;
      j = j + 1;
    }
    if (i % j == 0) {
      i = i - 1;
      continue;
    }
    break;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prime>:
  endbr64
  mov    $0x7869d623,%edi
  mov    $0x7869d624,%esi
L33:
  mov    %esi,%eax
  mov    %esi,%r8d
  and    $0x1,%eax
  cmp    $0x3,%esi
  jle    L87
  test   %eax,%eax
  je     L99
  mov    $0x2,%ecx
  jmp    L63
  cs nopw 0x0(%rax,%rax,1)
L31:
  test   %edx,%edx
  je     L99
L63:
  mov    %esi,%eax
  add    $0x1,%ecx
  cltd
  idiv   %ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %esi,%eax
  jle    L31
  test   %edx,%edx
  je     L22
L48:
  mov    %r8d,%eax
  ret
L87:
  test   %eax,%eax
  jne    L48
  nopl   0x0(%rax)
L99:
  test   %edi,%edi
  je     L16
L22:
  sub    $0x1,%esi
  sub    $0x1,%edi
  jmp    L33
L16:
  xor    %r8d,%r8d
  jmp    L48
```

assistant: ```c
int prime() {
  int i = 2020202020;
  while (i > 0) {
    int j = 2;
    while (j * j <= i) {
      if (i % j == 0)
        break;
      j = j + 1;
    }
    if (i % j == 0) {
      i = i - 1;
      continue;
    }
    break;
  }
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb8(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb8(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    -0xc8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %eax,-0xb4(%rbp)
  mov    -0xb8(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list va;
  va_start(va, fmt);
  int rv = vfprintf(f, fmt, va);
  va_end(va);
  return rv;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list va;
  va_start(va, fmt);
  int rv = vfprintf(f, fmt, va);
  va_end(va);
  return rv;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list va;
  va_start(va, fmt);
  int rv = vfprintf(f, fmt, va);
  va_end(va);
  return rv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<fprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fprintf(FILE *f, const char *fmt, ...) {
  va_list va;
  va_start(va, fmt);
  int rv = vfprintf(f, fmt, va);
  va_end(va);
  return rv;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calcHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L19
L5:
  mov    -0x8(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <rol@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <towupper@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    $0x2,%eax
  imul   -0x10(%rbp),%eax
  xor    %edx,%eax
  cltq
  xor    %rax,-0x8(%rbp)
  mov    $0xffffffff,%eax
  and    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
  addq   $0x4,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L5
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  shl    $0x18,%rax
  mov    %rax,%rdx
  movabs $0xff000000000,%rax
  and    %rdx,%rax
  xor    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int calcHash(wchar_t *name) {
  unsigned long hash = 0;
  int i = 0;
  while (*name) {
    hash = rol(hash, 5);
    wchar_t c = towupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++;
    name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<calcHash>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpl   $0x0,(%rdi)
  je     L3
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x0,%edi
L0:
  mov    $0x5,%esi
  call   <rol@plt>
  mov    %rax,%r12
  mov    0x0(%rbp,%rbx,4),%edi
  call   <towupper@plt>
  lea    0x2(%rax),%edi
  imul   %eax,%edi
  lea    0x2(%rbx),%eax
  imul   %ebx,%eax
  xor    %eax,%edi
  xor    %r12d,%edi
  add    $0x1,%rbx
  cmpl   $0x0,0x0(%rbp,%rbx,4)
  jne    L0
L8:
  lea    0x2(%rdi),%rdx
  imul   %rdi,%rdx
  mov    %rdx,%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  mov    $0x0,%edi
  jmp    L8
```

assistant: ```c
int calcHash(wchar_t *name) {
  unsigned long hash = 0;
  int i = 0;
  while (*name) {
    hash = rol(hash, 5);
    wchar_t c = towupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++;
    name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calcHash>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L8
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L18:
  mov    $0x5,%esi
  call   <rol@plt>
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %rax,%r12
  call   <towupper@plt>
  lea    0x2(%rax),%edi
  imul   %eax,%edi
  lea    0x2(%rbx),%eax
  imul   %ebx,%eax
  add    $0x1,%rbx
  xor    %eax,%edi
  mov    0x0(%rbp,%rbx,4),%eax
  xor    %r12d,%edi
  test   %eax,%eax
  jne    L18
  lea    0x2(%rdi),%rdx
  pop    %rbx
  pop    %rbp
  imul   %rdi,%rdx
  pop    %r12
  mov    %rdx,%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  ret
```

assistant: ```c
int calcHash(wchar_t *name) {
  unsigned long hash = 0;
  int i = 0;
  while (*name) {
    hash = rol(hash, 5);
    wchar_t c = towupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++;
    name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<calcHash>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  je     L13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  xor    %ebx,%ebx
  nopl   (%rax)
L12:
  mov    $0x5,%esi
  call   <rol@plt>
  mov    0x0(%rbp,%rbx,4),%edi
  mov    %rax,%r12
  call   <towupper@plt>
  lea    0x2(%rax),%edi
  imul   %eax,%edi
  lea    0x2(%rbx),%eax
  imul   %ebx,%eax
  add    $0x1,%rbx
  xor    %eax,%edi
  mov    0x0(%rbp,%rbx,4),%eax
  xor    %r12d,%edi
  test   %eax,%eax
  jne    L12
  lea    0x2(%rdi),%rdx
  pop    %rbx
  pop    %rbp
  imul   %rdi,%rdx
  pop    %r12
  mov    %rdx,%rax
  shl    $0xc,%rax
  and    $0xfff000,%eax
  xor    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
int calcHash(wchar_t *name) {
  unsigned long hash = 0;
  int i = 0;
  while (*name) {
    hash = rol(hash, 5);
    wchar_t c = towupper(*name);
    hash ^= (c * (c + 2)) ^ (i * (i + 2));
    hash &= 0xffffffff;
    i++;
    name++;
  }
  hash = hash * (hash + 2);
  hash ^= (hash & 0xfff) << 12;
  hash ^= (hash & 0xff000) << 24;
  return hash;
}
```