ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  cmp    $0xffffffff,%esi
  je     L22
  cmp    $0xffffffff,%edx
  je     L22
  call   <puzzle_move_is_valid@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L57
L93:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  mov    %rbx,%rdi
  call   <puzzle_is_valid@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L93
L57:
  mov    %rbx,%rdi
  call   <puzzle_is_complete@plt>
  cmp    $0x1,%eax
  je     L93
  mov    %rbx,%rdi
  call   <getNextFree@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  test   %edx,%edx
  js     L93
  movslq %edx,%rbp
  imul   $0x38e38e39,%rbp,%rbp
  sar    $0x21,%rbp
  mov    %edx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  mov    %ebp,%r13d
  lea    0x0(%rbp,%rbp,8),%eax
  sub    %eax,%edx
  mov    %edx,%ebp
  mov    $0x1,%r12d
  jmp    L10
L15:
  mov    $0x0,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <puzzle_set@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  je     L1
L10:
  mov    %r12d,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <puzzle_set@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <solve>
  cmp    $0x1,%eax
  jne    L15
  jmp    L93
L1:
  mov    $0x0,%eax
  jmp    L93
```

assistant: ```c
int solve(struct puzzle *p, int x, int y) {
  int nextFree;
  if (x == -1 || y == -1) {
    if (puzzle_is_valid(p) == 0) {
      return (0);
    }
  } else {
    if (puzzle_move_is_valid(p, x, y) == 0) {
      return (0);
    }
  }
  if (puzzle_is_complete(p) == 1) {
    return (1);
  }
  nextFree = getNextFree(p);
  if (nextFree < 0) {
    return (0);
  }
  for (int i = 1; i <= 9; i++) {
    puzzle_set(p, nextFree / 9, nextFree % 9, i);
    if (solve(p, nextFree / 9, nextFree % 9) == 1) {
      return (1);
    }
    puzzle_set(p, nextFree / 9, nextFree % 9, 0);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0xffffffff,%esi
  je     L74
  cmp    $0xffffffff,%edx
  je     L74
  call   <puzzle_move_is_valid@plt>
  test   %rax,%rax
  je     L58
  mov    %rbx,%rdi
  call   <puzzle_is_complete@plt>
  cmp    $0x1,%eax
  je     L8
L11:
  mov    %rbx,%rdi
  call   <getNextFree@plt>
  test   %eax,%eax
  js     L58
  movslq %eax,%rbp
  cltd
  mov    $0x1,%r12d
  imul   $0x38e38e39,%rbp,%rbp
  sar    $0x21,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,8),%edx
  mov    %ebp,%r13d
  sub    %edx,%eax
  mov    %eax,%ebp
L62:
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  mov    %r12d,%ecx
  call   <puzzle_set@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <solve>
  cmp    $0x1,%eax
  je     L8
  xor    %ecx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <puzzle_set@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L62
L58:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L74:
  call   <puzzle_is_valid@plt>
  test   %rax,%rax
  je     L58
  mov    %rbx,%rdi
  call   <puzzle_is_complete@plt>
  cmp    $0x1,%eax
  jne    L11
L8:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int solve(struct puzzle *p, int x, int y) {
  int nextFree;
  if (x == -1 || y == -1) {
    if (puzzle_is_valid(p) == 0) {
      return (0);
    }
  } else {
    if (puzzle_move_is_valid(p, x, y) == 0) {
      return (0);
    }
  }
  if (puzzle_is_complete(p) == 1) {
    return (1);
  }
  nextFree = getNextFree(p);
  if (nextFree < 0) {
    return (0);
  }
  for (int i = 1; i <= 9; i++) {
    puzzle_set(p, nextFree / 9, nextFree % 9, i);
    if (solve(p, nextFree / 9, nextFree % 9) == 1) {
      return (1);
    }
    puzzle_set(p, nextFree / 9, nextFree % 9, 0);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<solve>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cmp    $0xffffffff,%esi
  je     L17
  cmp    $0xffffffff,%edx
  je     L17
  call   <puzzle_move_is_valid@plt>
  test   %rax,%rax
  je     L64
  mov    %rbx,%rdi
  call   <puzzle_is_complete@plt>
  cmp    $0x1,%eax
  je     L84
L7:
  mov    %rbx,%rdi
  call   <getNextFree@plt>
  test   %eax,%eax
  js     L64
  movslq %eax,%rbp
  cltd
  mov    $0x1,%r12d
  imul   $0x38e38e39,%rbp,%rbp
  sar    $0x21,%rbp
  sub    %edx,%ebp
  lea    0x0(%rbp,%rbp,8),%edx
  mov    %ebp,%r13d
  sub    %edx,%eax
  mov    %eax,%ebp
L12:
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  mov    %r12d,%ecx
  call   <puzzle_set@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <solve>
  cmp    $0x1,%eax
  je     L84
  xor    %ecx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <puzzle_set@plt>
  add    $0x1,%r12d
  cmp    $0xa,%r12d
  jne    L12
L64:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L17:
  call   <puzzle_is_valid@plt>
  test   %rax,%rax
  je     L64
  mov    %rbx,%rdi
  call   <puzzle_is_complete@plt>
  cmp    $0x1,%eax
  jne    L7
L84:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int solve(struct puzzle *p, int x, int y) {
  int nextFree;
  if (x == -1 || y == -1) {
    if (puzzle_is_valid(p) == 0) {
      return (0);
    }
  } else {
    if (puzzle_move_is_valid(p, x, y) == 0) {
      return (0);
    }
  }
  if (puzzle_is_complete(p) == 1) {
    return (1);
  }
  nextFree = getNextFree(p);
  if (nextFree < 0) {
    return (0);
  }
  for (int i = 1; i <= 9; i++) {
    puzzle_set(p, nextFree / 9, nextFree % 9, i);
    if (solve(p, nextFree / 9, nextFree % 9) == 1) {
      return (1);
    }
    puzzle_set(p, nextFree / 9, nextFree % 9, 0);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b_findMsb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L21:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L20
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L9
L20:
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L21
L9:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int b_findMsb(const unsigned *xs, int size) {
  int i = 0, idx = size - 1;
  while (i < size) {
    if (xs[i]) {
      idx = i;
      break;
    }
    i++;
  }
  return idx;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<b_findMsb>:
  endbr64
  lea    -0x1(%rsi),%ecx
  test   %esi,%esi
  jle    L14
  mov    %esi,%esi
  mov    $0x0,%eax
L25:
  cmpl   $0x0,(%rdi,%rax,4)
  jne    L24
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L25
  jmp    L14
L24:
  mov    %eax,%ecx
L14:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int b_findMsb(const unsigned *xs, int size) {
  int i = 0, idx = size - 1;
  while (i < size) {
    if (xs[i]) {
      idx = i;
      break;
    }
    i++;
  }
  return idx;
}
```
user: Translate the below assembly code into C programming language:

```asm
<b_findMsb>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L0
L32:
  mov    (%rdi,%rax,4),%edx
  test   %edx,%edx
  je     L9
  mov    %eax,%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int b_findMsb(const unsigned *xs, int size) {
  int i = 0, idx = size - 1;
  while (i < size) {
    if (xs[i]) {
      idx = i;
      break;
    }
    i++;
  }
  return idx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<b_findMsb>:
  endbr64
  lea    -0x1(%rsi),%r8d
  test   %esi,%esi
  jle    L0
  movslq %esi,%rsi
  xor    %eax,%eax
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L0
L37:
  mov    (%rdi,%rax,4),%edx
  test   %edx,%edx
  je     L20
  mov    %eax,%r8d
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int b_findMsb(const unsigned *xs, int size) {
  int i = 0, idx = size - 1;
  while (i < size) {
    if (xs[i]) {
      idx = i;
      break;
    }
    i++;
  }
  return idx;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<KeyExpansion>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x8,0xc(%rsp)
  movl   $0x10,0x10(%rsp)
  movl   $0x20,0x14(%rsp)
  movl   $0x40,0x18(%rsp)
  movl   $0x80,0x1c(%rsp)
  movl   $0x1b,0x20(%rsp)
  movl   $0x36,0x24(%rsp)
  movl   $0x6c,0x28(%rsp)
  movl   $0xd8,0x2c(%rsp)
  movl   $0xab,0x30(%rsp)
  movl   $0x4d,0x34(%rsp)
  movl   $0x9a,0x38(%rsp)
  cmp    $0xc0,%edx
  je     L53
  cmp    $0x100,%edx
  je     L49
  mov    $0x4,%ebx
  mov    $0xa,%edi
  cmp    $0x80,%edx
  je     L119
L13:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L53:
  mov    $0x6,%ebx
  mov    $0xc,%edi
  jmp    L119
L49:
  mov    $0x8,%ebx
  mov    $0xe,%edi
L119:
  mov    $0x0,%edx
L86:
  movzbl 0x1(%rcx,%rdx,4),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rcx,%rdx,4),%esi
  shl    $0x10,%esi
  or     %esi,%eax
  movzbl (%rcx,%rdx,4),%esi
  or     %esi,%eax
  movzbl 0x3(%rcx,%rdx,4),%esi
  shl    $0x18,%esi
  or     %esi,%eax
  mov    %eax,0x0(%rbp,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%ebx
  jg     L86
  lea    0x4(,%rdi,4),%r14d
  movslq %ebx,%r12
  mov    %r12,%rax
  neg    %rax
  lea    0x0(%rbp,%rax,4),%r13
  jmp    L51
L42:
  ror    $0x8,%edi
  call   <SubWord@plt>
  mov    %eax,%edi
  lea    -0x1(%r12),%eax
  cltd
  idiv   %ebx
  cltq
  xor    (%rsp,%rax,4),%edi
L35:
  xor    0x0(%r13,%r12,4),%edi
  mov    %edi,0x0(%rbp,%r12,4)
  add    $0x1,%r12
  cmp    %r12d,%r14d
  jle    L13
L51:
  mov    -0x4(%rbp,%r12,4),%edi
  mov    %r12d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L42
  cmp    $0x4,%edx
  jne    L35
  cmp    $0x6,%ebx
  jle    L35
  call   <SubWord@plt>
  mov    %eax,%edi
  jmp    L35
L90:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void KeyExpansion(unsigned char key[], unsigned int w[], int keysize) {
  int Nb = 4, Nr, Nk, idx;
  unsigned int temp, Rcon[] = {0x00000001, 0x00000002, 0x00000004, 0x00000008, 0x00000010, 0x00000020, 0x00000040, 0x00000080, 0x0000001b, 0x00000036, 0x0000006c, 0x000000d8, 0x000000ab, 0x0000004d, 0x0000009a};
  switch (keysize) {
  case 128:
    Nr = 10;
    Nk = 4;
    break;
  case 192:
    Nr = 12;
    Nk = 6;
    break;
  case 256:
    Nr = 14;
    Nk = 8;
    break;
  default:
    return;
  }
  for (idx = 0; idx < Nk; ++idx) {
    w[idx] = ((key[4 * idx])) | ((key[4 * idx + 1]) << 8) | ((key[4 * idx + 2]) << 16) | ((key[4 * idx + 3]) << 24);
  }
  for (idx = Nk; idx < Nb * (Nr + 1); ++idx) {
    temp = w[idx - 1];
    if ((idx % Nk) == 0) {
      temp = (((temp) >> 8) | ((temp) << 24));
      temp = SubWord(temp);
      temp ^= Rcon[(idx - 1) / Nk];
    } else if (Nk > 6 && (idx % Nk) == 4)
      temp = SubWord(temp);
    w[idx] = w[idx - Nk] ^ temp;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<KeyExpansion>:
  endbr64
  push   %r14
  mov    %rdi,%rcx
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  movabs $0x200000001,%rax
  movl   $0x9a,0x38(%rsp)
  mov    %rax,(%rsp)
  movabs $0x800000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x2000000010,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x8000000040,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x360000001b,%rax
  mov    %rax,0x20(%rsp)
  movabs $0xd80000006c,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x4d000000ab,%rax
  mov    %rax,0x30(%rsp)
  cmp    $0xc0,%edx
  je     L2
  cmp    $0x100,%edx
  je     L15
  mov    $0x2c,%r13d
  mov    $0x4,%ebp
  cmp    $0x80,%edx
  je     L79
L109:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L15:
  mov    $0x3c,%r13d
  mov    $0x8,%ebp
L79:
  xor    %edx,%edx
  nopl   (%rax)
L87:
  movzbl 0x1(%rcx,%rdx,4),%eax
  movzbl 0x2(%rcx,%rdx,4),%esi
  shl    $0x8,%eax
  shl    $0x10,%esi
  or     %esi,%eax
  movzbl (%rcx,%rdx,4),%esi
  or     %esi,%eax
  movzbl 0x3(%rcx,%rdx,4),%esi
  shl    $0x18,%esi
  or     %esi,%eax
  mov    %eax,(%r12,%rdx,4)
  add    $0x1,%rdx
  cmp    %edx,%ebp
  jg     L87
  movslq %ebp,%rbx
  mov    %rbx,%rax
  neg    %rax
  lea    (%r12,%rax,4),%r14
  jmp    L76
  nopl   (%rax)
L126:
  cmp    $0x6,%ebp
  jle    L124
  cmp    $0x4,%edx
  je     L4
L124:
  xor    (%r14,%rbx,4),%edi
  mov    %edi,(%r12,%rbx,4)
  add    $0x1,%rbx
  cmp    %ebx,%r13d
  jle    L109
L76:
  mov    %ebx,%eax
  mov    -0x4(%r12,%rbx,4),%edi
  cltd
  idiv   %ebp
  test   %edx,%edx
  jne    L126
  ror    $0x8,%edi
  call   <SubWord@plt>
  mov    %eax,%edi
  lea    -0x1(%rbx),%eax
  cltd
  idiv   %ebp
  cltq
  xor    (%rsp,%rax,4),%edi
  jmp    L124
  nopl   0x0(%rax)
L4:
  call   <SubWord@plt>
  mov    %eax,%edi
  jmp    L124
  nopl   0x0(%rax)
L2:
  mov    $0x34,%r13d
  mov    $0x6,%ebp
  jmp    L79
L103:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void KeyExpansion(unsigned char key[], unsigned int w[], int keysize) {
  int Nb = 4, Nr, Nk, idx;
  unsigned int temp, Rcon[] = {0x00000001, 0x00000002, 0x00000004, 0x00000008, 0x00000010, 0x00000020, 0x00000040, 0x00000080, 0x0000001b, 0x00000036, 0x0000006c, 0x000000d8, 0x000000ab, 0x0000004d, 0x0000009a};
  switch (keysize) {
  case 128:
    Nr = 10;
    Nk = 4;
    break;
  case 192:
    Nr = 12;
    Nk = 6;
    break;
  case 256:
    Nr = 14;
    Nk = 8;
    break;
  default:
    return;
  }
  for (idx = 0; idx < Nk; ++idx) {
    w[idx] = ((key[4 * idx])) | ((key[4 * idx + 1]) << 8) | ((key[4 * idx + 2]) << 16) | ((key[4 * idx + 3]) << 24);
  }
  for (idx = Nk; idx < Nb * (Nr + 1); ++idx) {
    temp = w[idx - 1];
    if ((idx % Nk) == 0) {
      temp = (((temp) >> 8) | ((temp) << 24));
      temp = SubWord(temp);
      temp ^= Rcon[(idx - 1) / Nk];
    } else if (Nk > 6 && (idx % Nk) == 4)
      temp = SubWord(temp);
    w[idx] = w[idx - Nk] ^ temp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fsop_path_exec_group>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  test   %rax,%rax
  jns    L23
  mov    $0xffffffff,%eax
  jmp    L21
L23:
  mov    -0xc(%rbp),%edx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  and    %edx,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int fsop_path_exec_group(const char *path) {
  struct stat st;
  if (stat(path, &st) < 0)
    return -1;
  return (st.st_mode & S_IXGRP);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fsop_path_exec_group>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L5
  mov    D0(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x18,%rsp
  ret
L5:
  mov    $0xffffffff,%eax
  jmp    L14
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fsop_path_exec_group(const char *path) {
  struct stat st;
  if (stat(path, &st) < 0)
    return -1;
  return (st.st_mode & S_IXGRP);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fsop_path_exec_group>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L26
  mov    D9(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
L12:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  ret
L26:
  mov    $0xffffffff,%eax
  jmp    L12
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fsop_path_exec_group(const char *path) {
  struct stat st;
  if (stat(path, &st) < 0)
    return -1;
  return (st.st_mode & S_IXGRP);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fsop_path_exec_group>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  test   %rax,%rax
  js     L1
  mov    D5(%rip),%rdx
  mov    0x4(%rsp),%eax
  and    (%rdx),%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L1:
  mov    $0xffffffff,%eax
  jmp    L14
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fsop_path_exec_group(const char *path) {
  struct stat st;
  if (stat(path, &st) < 0)
    return -1;
  return (st.st_mode & S_IXGRP);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x280,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x5,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0x6,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0x13(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0x7,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0x12(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0x8,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0x11(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0xf,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0x10(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0x10,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0xf(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0x11,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0xe(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  movb   $0x12,-0x271(%rbp)
  movzbl -0x271(%rbp),%eax
  mov    %al,-0xd(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x20a(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x20a(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void f(void) {
  unsigned char c, ca[15], caa[20][30];
#pragma acc data copyin(c)
  {
    c = 5;
    ca[3] = c;
    caa[3][12] = ca[3] + caa[3][12];
#pragma acc data copyin(ca [2:4])
    {
      c = 6;
      ca[4] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc parallel copyout(ca [3:4])
    {
      c = 7;
      ca[5] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc kernels copy(ca [4:4])
    {
      c = 8;
      ca[6] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc data pcopy(ca [5:7])
    {
      c = 15;
      ca[7] = c;
      caa[3][12] = ca[3] + caa[3][12];
#pragma acc data pcopyin(caa [3:7] [0:30])
      {
        c = 16;
        ca[8] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc parallel pcopyout(caa [3:7] [0:30])
      {
        c = 17;
        ca[9] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc kernels pcopy(caa [3:7] [0:30])
      {
        c = 18;
        ca[10] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  unsigned char c, ca[15], caa[20][30];
#pragma acc data copyin(c)
  {
    c = 5;
    ca[3] = c;
    caa[3][12] = ca[3] + caa[3][12];
#pragma acc data copyin(ca [2:4])
    {
      c = 6;
      ca[4] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc parallel copyout(ca [3:4])
    {
      c = 7;
      ca[5] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc kernels copy(ca [4:4])
    {
      c = 8;
      ca[6] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc data pcopy(ca [5:7])
    {
      c = 15;
      ca[7] = c;
      caa[3][12] = ca[3] + caa[3][12];
#pragma acc data pcopyin(caa [3:7] [0:30])
      {
        c = 16;
        ca[8] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc parallel pcopyout(caa [3:7] [0:30])
      {
        c = 17;
        ca[9] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc kernels pcopy(caa [3:7] [0:30])
      {
        c = 18;
        ca[10] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  unsigned char c, ca[15], caa[20][30];
#pragma acc data copyin(c)
  {
    c = 5;
    ca[3] = c;
    caa[3][12] = ca[3] + caa[3][12];
#pragma acc data copyin(ca [2:4])
    {
      c = 6;
      ca[4] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc parallel copyout(ca [3:4])
    {
      c = 7;
      ca[5] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc kernels copy(ca [4:4])
    {
      c = 8;
      ca[6] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc data pcopy(ca [5:7])
    {
      c = 15;
      ca[7] = c;
      caa[3][12] = ca[3] + caa[3][12];
#pragma acc data pcopyin(caa [3:7] [0:30])
      {
        c = 16;
        ca[8] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc parallel pcopyout(caa [3:7] [0:30])
      {
        c = 17;
        ca[9] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc kernels pcopy(caa [3:7] [0:30])
      {
        c = 18;
        ca[10] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  unsigned char c, ca[15], caa[20][30];
#pragma acc data copyin(c)
  {
    c = 5;
    ca[3] = c;
    caa[3][12] = ca[3] + caa[3][12];
#pragma acc data copyin(ca [2:4])
    {
      c = 6;
      ca[4] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc parallel copyout(ca [3:4])
    {
      c = 7;
      ca[5] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc kernels copy(ca [4:4])
    {
      c = 8;
      ca[6] = c;
      caa[3][12] = ca[3] + caa[3][12];
    }
#pragma acc data pcopy(ca [5:7])
    {
      c = 15;
      ca[7] = c;
      caa[3][12] = ca[3] + caa[3][12];
#pragma acc data pcopyin(caa [3:7] [0:30])
      {
        c = 16;
        ca[8] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc parallel pcopyout(caa [3:7] [0:30])
      {
        c = 17;
        ca[9] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
#pragma acc kernels pcopy(caa [3:7] [0:30])
      {
        c = 18;
        ca[10] = c;
        caa[3][12] = ca[3] + caa[3][12];
      }
    }
  }
}
```