ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<bswap_64>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t bswap_64(uint64_t x) {
  uint64_t __x = (x);
  return ((uint64_t)((uint64_t)(((uint64_t)(__x) & (uint64_t)0x00000000000000ffULL) << 56) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x000000000000ff00ULL) << 40) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x0000000000ff0000ULL) << 24) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x00000000ff000000ULL) << 8) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x000000ff00000000ULL) >> 8) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x0000ff0000000000ULL) >> 24) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x00ff000000000000ULL) >> 40) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0xff00000000000000ULL) >> 56)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bswap_64>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t bswap_64(uint64_t x) {
  uint64_t __x = (x);
  return ((uint64_t)((uint64_t)(((uint64_t)(__x) & (uint64_t)0x00000000000000ffULL) << 56) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x000000000000ff00ULL) << 40) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x0000000000ff0000ULL) << 24) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x00000000ff000000ULL) << 8) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x000000ff00000000ULL) >> 8) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x0000ff0000000000ULL) >> 24) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0x00ff000000000000ULL) >> 40) | (uint64_t)(((uint64_t)(__x) & (uint64_t)0xff00000000000000ULL) >> 56)));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    $0x1,%eax
  jne    L12
  mov    -0x1c(%rbp),%eax
  cmp    $0x2,%eax
  jne    L12
  mov    -0x18(%rbp),%eax
  cmp    $0x3,%eax
  jne    L12
  mov    -0x14(%rbp),%eax
  cmp    $0x4,%eax
  je     L6
L12:
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
main() {
  int y[][2] = {1, 2, 3, 4};
  if (y[0][0] != 1 || y[0][1] != 2 || y[1][0] != 3 || y[1][1] != 4) {
    abort();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int y[][2] = {1, 2, 3, 4};
  if (y[0][0] != 1 || y[0][1] != 2 || y[1][0] != 3 || y[1][1] != 4) {
    abort();
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int y[][2] = {1, 2, 3, 4};
  if (y[0][0] != 1 || y[0][1] != 2 || y[1][0] != 3 || y[1][1] != 4) {
    abort();
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int y[][2] = {1, 2, 3, 4};
  if (y[0][0] != 1 || y[0][1] != 2 || y[1][0] != 3 || y[1][1] != 4) {
    abort();
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cm_numeric_tests_run>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <get_number_of_digits__positive_number__is_calculated_corectly@plt>
  mov    $0x0,%eax
  call   <get_number_of_digits__negative_number__is_calculated_corectly@plt>
  mov    $0x0,%eax
  call   <double_is_within__is_within__returns_true@plt>
  mov    $0x0,%eax
  call   <double_is_within__is_not_within__returns_false@plt>
  mov    $0x0,%eax
  call   <uint8_is_within__is_within__returns_true@plt>
  mov    $0x0,%eax
  call   <uint8_is_within__is_not_within__returns_false@plt>
  mov    $0x0,%eax
  call   <double_get_min__normal_case__min_returned@plt>
  mov    $0x0,%eax
  call   <double_get_max__normal_case__min_returned@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cm_numeric_tests_run(void) {
  get_number_of_digits__positive_number__is_calculated_corectly();
  get_number_of_digits__negative_number__is_calculated_corectly();
  double_is_within__is_within__returns_true();
  double_is_within__is_not_within__returns_false();
  uint8_is_within__is_within__returns_true();
  uint8_is_within__is_not_within__returns_false();
  double_get_min__normal_case__min_returned();
  double_get_max__normal_case__min_returned();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cm_numeric_tests_run>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <get_number_of_digits__positive_number__is_calculated_corectly@plt>
  mov    $0x0,%eax
  call   <get_number_of_digits__negative_number__is_calculated_corectly@plt>
  mov    $0x0,%eax
  call   <double_is_within__is_within__returns_true@plt>
  mov    $0x0,%eax
  call   <double_is_within__is_not_within__returns_false@plt>
  mov    $0x0,%eax
  call   <uint8_is_within__is_within__returns_true@plt>
  mov    $0x0,%eax
  call   <uint8_is_within__is_not_within__returns_false@plt>
  mov    $0x0,%eax
  call   <double_get_min__normal_case__min_returned@plt>
  mov    $0x0,%eax
  call   <double_get_max__normal_case__min_returned@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void cm_numeric_tests_run(void) {
  get_number_of_digits__positive_number__is_calculated_corectly();
  get_number_of_digits__negative_number__is_calculated_corectly();
  double_is_within__is_within__returns_true();
  double_is_within__is_not_within__returns_false();
  uint8_is_within__is_within__returns_true();
  uint8_is_within__is_not_within__returns_false();
  double_get_min__normal_case__min_returned();
  double_get_max__normal_case__min_returned();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cm_numeric_tests_run>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_number_of_digits__positive_number__is_calculated_corectly@plt>
  xor    %eax,%eax
  call   <get_number_of_digits__negative_number__is_calculated_corectly@plt>
  xor    %eax,%eax
  call   <double_is_within__is_within__returns_true@plt>
  xor    %eax,%eax
  call   <double_is_within__is_not_within__returns_false@plt>
  xor    %eax,%eax
  call   <uint8_is_within__is_within__returns_true@plt>
  xor    %eax,%eax
  call   <uint8_is_within__is_not_within__returns_false@plt>
  xor    %eax,%eax
  call   <double_get_min__normal_case__min_returned@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1110 <double_get_max__normal_case__min_returned@plt>
```

assistant: ```c
void cm_numeric_tests_run(void) {
  get_number_of_digits__positive_number__is_calculated_corectly();
  get_number_of_digits__negative_number__is_calculated_corectly();
  double_is_within__is_within__returns_true();
  double_is_within__is_not_within__returns_false();
  uint8_is_within__is_within__returns_true();
  uint8_is_within__is_not_within__returns_false();
  double_get_min__normal_case__min_returned();
  double_get_max__normal_case__min_returned();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cm_numeric_tests_run>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <get_number_of_digits__positive_number__is_calculated_corectly@plt>
  xor    %eax,%eax
  call   <get_number_of_digits__negative_number__is_calculated_corectly@plt>
  xor    %eax,%eax
  call   <double_is_within__is_within__returns_true@plt>
  xor    %eax,%eax
  call   <double_is_within__is_not_within__returns_false@plt>
  xor    %eax,%eax
  call   <uint8_is_within__is_within__returns_true@plt>
  xor    %eax,%eax
  call   <uint8_is_within__is_not_within__returns_false@plt>
  xor    %eax,%eax
  call   <double_get_min__normal_case__min_returned@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1110 <double_get_max__normal_case__min_returned@plt>
```

assistant: ```c
void cm_numeric_tests_run(void) {
  get_number_of_digits__positive_number__is_calculated_corectly();
  get_number_of_digits__negative_number__is_calculated_corectly();
  double_is_within__is_within__returns_true();
  double_is_within__is_not_within__returns_false();
  uint8_is_within__is_within__returns_true();
  uint8_is_within__is_not_within__returns_false();
  double_get_min__normal_case__min_returned();
  double_get_max__normal_case__min_returned();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L17:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char t = *(str + start);
    *(str + start) = *(str + end);
    *(str + end) = t;
    start++;
    end--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L11
  movslq %esi,%rsi
  mov    $0x0,%eax
L0:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L0
L11:
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char t = *(str + start);
    *(str + start) = *(str + end);
    *(str + end) = t;
    start++;
    end--;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L10
  movslq %esi,%rsi
  xor    %eax,%eax
L11:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L11
L10:
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char t = *(str + start);
    *(str + start) = *(str + end);
    *(str + end) = t;
    start++;
    end--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L1
  movslq %esi,%rsi
  xor    %eax,%eax
L0:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  mov    %dl,(%rdi,%rsi,1)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L0
L1:
  ret
```

assistant: ```c
void reverse(char *str, int length) {
  int start = 0;
  int end = length - 1;
  while (start < end) {
    char t = *(str + start);
    *(str + start) = *(str + end);
    *(str + end) = t;
    start++;
    end--;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sortColors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x0,-0x28(%rbp)
  jmp    L40
L47:
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  mov    -0x14(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x14(%rbp,%rax,4)
  addl   $0x1,-0x28(%rbp)
L40:
  mov    -0x28(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L47
  movl   $0x0,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L7
L54:
  movl   $0x0,-0x1c(%rbp)
  jmp    L25
L11:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L25:
  mov    -0x20(%rbp),%eax
  cltq
  mov    -0x14(%rbp,%rax,4),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L11
  addl   $0x1,-0x20(%rbp)
L7:
  cmpl   $0x2,-0x20(%rbp)
  jle    L54
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int cnts[3] = {0, 0, 0};
  int size = numsSize;
  for (int i = 0; i < size; i++) {
    cnts[nums[i]]++;
  }
  int idx = 0;
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < cnts[i]; j++) {
      nums[idx++] = i;
    }
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sortColors>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  test   %esi,%esi
  jle    L36
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
L35:
  movslq (%rax),%rdx
  addl   $0x1,0xc(%rsp,%rdx,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L35
L36:
  mov    $0x0,%esi
  mov    $0x0,%r8d
  lea    0x4(%r9),%r11
L48:
  mov    %esi,%edx
  mov    0xc(%rsp,%rsi,4),%edi
  test   %edi,%edi
  jle    L44
  movslq %r8d,%r10
  lea    (%r9,%r10,4),%rax
  lea    -0x1(%rdi),%ecx
  add    %r10,%rcx
  lea    (%r11,%rcx,4),%rcx
L15:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L15
  add    %edi,%r8d
L44:
  add    $0x1,%rsi
  cmp    $0x3,%rsi
  jne    L48
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x28,%rsp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int cnts[3] = {0, 0, 0};
  int size = numsSize;
  for (int i = 0; i < size; i++) {
    cnts[nums[i]]++;
  }
  int idx = 0;
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < cnts[i]; j++) {
      nums[idx++] = i;
    }
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sortColors>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r9
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  test   %esi,%esi
  jle    L55
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  lea    0x4(%rdi,%rdx,4),%rcx
  nop
L41:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0xc(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L41
  mov    0xc(%rsp),%edi
L29:
  xor    %esi,%esi
  xor    %r8d,%r8d
  lea    0x4(%r9),%r11
L25:
  mov    %esi,%edx
  test   %edi,%edi
  jle    L68
  movslq %r8d,%r10
  lea    -0x1(%rdi),%ecx
  add    %r10,%rcx
  lea    (%r9,%r10,4),%rax
  lea    (%r11,%rcx,4),%rcx
  nopl   (%rax)
L38:
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L38
  add    %edi,%r8d
L68:
  add    $0x1,%rsi
  cmp    $0x3,%rsi
  je     L22
  mov    0xc(%rsp,%rsi,4),%edi
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L53
  add    $0x28,%rsp
  ret
L55:
  xor    %edi,%edi
  jmp    L29
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int cnts[3] = {0, 0, 0};
  int size = numsSize;
  for (int i = 0; i < size; i++) {
    cnts[nums[i]]++;
  }
  int idx = 0;
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < cnts[i]; j++) {
      nums[idx++] = i;
    }
  }
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sortColors>:
  endbr64
  sub    $0x28,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  test   %esi,%esi
  jle    L50
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  lea    0x4(%rdi,%rdx,4),%rcx
  nopl   0x0(%rax,%rax,1)
L83:
  movslq (%rax),%rdx
  add    $0x4,%rax
  addl   $0x1,0x8(%rsp,%rdx,4)
  cmp    %rcx,%rax
  jne    L83
L50:
  xor    %edi,%edi
  xor    %r9d,%r9d
  lea    0x8(%rsp),%r11
L68:
  mov    (%r11,%rdi,4),%esi
  mov    %edi,%r10d
  test   %esi,%esi
  jle    L46
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L106
  movslq %r9d,%rax
  movd   %r10d,%xmm1
  lea    (%r8,%rax,4),%rdx
  mov    %esi,%eax
  pshufd $0x0,%xmm1,%xmm0
  shr    $0x2,%eax
  lea    -0x1(%rax),%ecx
  lea    0x10(%rdx),%rax
  shl    $0x4,%rcx
  add    %rax,%rcx
  jmp    L35
  nopl   0x0(%rax)
L31:
  add    $0x10,%rax
L35:
  movups %xmm0,(%rdx)
  mov    %rax,%rdx
  cmp    %rax,%rcx
  jne    L31
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  lea    (%r9,%rax,1),%edx
  cmp    %eax,%esi
  je     L110
L104:
  movslq %edx,%rdx
  mov    %r10d,(%r8,%rdx,4)
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  cmp    %edx,%esi
  jle    L110
  add    $0x2,%eax
  mov    %r10d,0x4(%r8,%rcx,1)
  cmp    %eax,%esi
  jle    L110
  mov    %r10d,0x8(%r8,%rcx,1)
L110:
  add    %esi,%r9d
L46:
  add    $0x1,%rdi
  cmp    $0x3,%rdi
  jne    L68
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x28,%rsp
  ret
L106:
  mov    %r9d,%edx
  xor    %eax,%eax
  jmp    L104
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sortColors(int *nums, int numsSize) {
  int cnts[3] = {0, 0, 0};
  int size = numsSize;
  for (int i = 0; i < size; i++) {
    cnts[nums[i]]++;
  }
  int idx = 0;
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < cnts[i]; j++) {
      nums[idx++] = i;
    }
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_fun>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  jmp    L44
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L38
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L38:
  addq   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  jmp    L0
L3:
  nop
L0:
  pop    %rbp
  ret
```

assistant: ```c
void my_fun(char *p) {
  if (p == NULL)
    return;
  for (; *p != '\0'; p++)
    if (*p >= 'A' && *p <= 'Z')
      *p = *p - 'A' + 'a';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_fun>:
  endbr64
  test   %rdi,%rdi
  je     L49
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L23
L49:
  ret
L40:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L49
L23:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L40
  add    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L40
```

assistant: ```c
void my_fun(char *p) {
  if (p == NULL)
    return;
  for (; *p != '\0'; p++)
    if (*p >= 'A' && *p <= 'Z')
      *p = *p - 'A' + 'a';
}
```
user: What is the c source code of the assembly code below:

```asm
<my_fun>:
  endbr64
  test   %rdi,%rdi
  jne    L31
  jmp    L38
  nopl   0x0(%rax,%rax,1)
L20:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L4
  add    $0x20,%eax
  mov    %al,(%rdi)
L4:
  add    $0x1,%rdi
L31:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L20
L38:
  ret
```

assistant: ```c
void my_fun(char *p) {
  if (p == NULL)
    return;
  for (; *p != '\0'; p++)
    if (*p >= 'A' && *p <= 'Z')
      *p = *p - 'A' + 'a';
}
```
user: What is the c source code of the assembly code below:

```asm
<my_fun>:
  endbr64
  test   %rdi,%rdi
  je     L35
  movzbl (%rdi),%eax
  test   %al,%al
  je     L35
L12:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L23
  add    $0x20,%eax
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L12
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L12
L35:
  ret
```

assistant: ```c
void my_fun(char *p) {
  if (p == NULL)
    return;
  for (; *p != '\0'; p++)
    if (*p >= 'A' && *p <= 'Z')
      *p = *p - 'A' + 'a';
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: Usage:
flockend path


assistant: ```c
void usage() {
  printf("Usage:\n"
         "flockend path\n");
  exit(-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_guessed: string

tool: D5: Usage:
flockend path


assistant: ```c
void usage() {
  printf("Usage:\n"
         "flockend path\n");
  exit(-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
type: string

tool: D1: Usage:
flockend path


assistant: ```c
void usage() {
  printf("Usage:\n"
         "flockend path\n");
  exit(-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D7
type_guessed: string

tool: D7: Usage:
flockend path


assistant: ```c
void usage() {
  printf("Usage:\n"
         "flockend path\n");
  exit(-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmultiply_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <__assume_aligned@plt>
  mov    -0x28(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <__assume_aligned@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x40,%esi
  mov    %rax,%rdi
  call   <__assume_aligned@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L26:
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L53:
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L59:
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm2,%xmm0
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0xf,-0x4(%rbp)
  jle    L59
  addl   $0x1,-0x8(%rbp)
L33:
  cmpl   $0xf,-0x8(%rbp)
  jle    L53
  addl   $0x1,-0xc(%rbp)
L9:
  cmpl   $0xf,-0xc(%rbp)
  jle    L26
  nop
  nop
  leave
  ret
```

assistant: ```c
void cmultiply_(float *restrict C, float *restrict A, float *restrict B) {
  __assume_aligned(A, 64);
  __assume_aligned(B, 64);
  __assume_aligned(C, 64);
  int i, j, k;
#pragma ivdep
#pragma vector aligned
#pragma vector always
  for (i = 0; i < 16; i++) {
    for (j = 0; j < 16; j++) {
      for (k = 0; k < 16; k++) {
        C[i + j * 16] += A[i + k * 16] * B[k + j * 16];
      }
    }
  }
}
```