ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<multiply38>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L4
L32:
  movl   $0x0,-0x3c(%rbp)
  jmp    L22
L3:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L22:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L3
  addl   $0x1,-0x40(%rbp)
L4:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L32
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply38(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<multiply38>:
  endbr64
  test   %edi,%edi
  jle    L18
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L20:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L4:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L4
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L20
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L18:
  ret
```

assistant: ```c
void multiply38(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<multiply38>:
  endbr64
  test   %edi,%edi
  jle    L25
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L14:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L14
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L20
  pop    %rbx
  ret
L25:
  ret
```

assistant: ```c
void multiply38(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<multiply38>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L50
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L83:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L6
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L6
  nopl   0x0(%rax)
L22:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L22
  cmp    -0x24(%rsp),%r11d
  je     L66
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L66
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L66
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L66:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L83
L50:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L85:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L85
  mov    -0x18(%rsp),%r8
  jmp    L66
```

assistant: ```c
void multiply38(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<iskeychar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x3a,%eax
  seta   %dl
  test   %dl,%dl
  jne    L15
  movabs $0x400000000002400,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L15
  mov    $0x0,%eax
  jmp    L12
L15:
  mov    $0x1,%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int iskeychar(int c) {
  switch (c) {
  case '\r':
  case '\n':
  case ':':
    return 0;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<iskeychar>:
  endbr64
  cmp    $0x3a,%edi
  ja     L8
  movabs $0x400000000002400,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  not    %rax
  and    $0x1,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iskeychar(int c) {
  switch (c) {
  case '\r':
  case '\n':
  case ':':
    return 0;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<iskeychar>:
  endbr64
  cmp    $0x3a,%edi
  ja     L4
  movabs $0x400000000002400,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iskeychar(int c) {
  switch (c) {
  case '\r':
  case '\n':
  case ':':
    return 0;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<iskeychar>:
  endbr64
  cmp    $0x3a,%edi
  ja     L1
  movabs $0x400000000002400,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  xor    $0x1,%eax
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int iskeychar(int c) {
  switch (c) {
  case '\r':
  case '\n':
  case ':':
    return 0;
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<db_sqlite3_insert_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <db_sqlite3_lock@plt>
  mov    $0x0,%eax
  call   <db_sqlite3_handle@plt>
  mov    %eax,%edi
  call   <sqlite3_last_insert_rowid@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <db_sqlite3_unlock@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int db_sqlite3_insert_id(void) {
  int result;
  db_sqlite3_lock();
  result = (int)sqlite3_last_insert_rowid(db_sqlite3_handle());
  db_sqlite3_unlock();
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<db_sqlite3_insert_id>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <db_sqlite3_lock@plt>
  mov    $0x0,%eax
  call   <db_sqlite3_handle@plt>
  mov    %eax,%edi
  call   <sqlite3_last_insert_rowid@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <db_sqlite3_unlock@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int db_sqlite3_insert_id(void) {
  int result;
  db_sqlite3_lock();
  result = (int)sqlite3_last_insert_rowid(db_sqlite3_handle());
  db_sqlite3_unlock();
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<db_sqlite3_insert_id>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <db_sqlite3_lock@plt>
  xor    %eax,%eax
  call   <db_sqlite3_handle@plt>
  mov    %eax,%edi
  call   <sqlite3_last_insert_rowid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <db_sqlite3_unlock@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int db_sqlite3_insert_id(void) {
  int result;
  db_sqlite3_lock();
  result = (int)sqlite3_last_insert_rowid(db_sqlite3_handle());
  db_sqlite3_unlock();
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<db_sqlite3_insert_id>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <db_sqlite3_lock@plt>
  xor    %eax,%eax
  call   <db_sqlite3_handle@plt>
  mov    %eax,%edi
  call   <sqlite3_last_insert_rowid@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  call   <db_sqlite3_unlock@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int db_sqlite3_insert_id(void) {
  int result;
  db_sqlite3_lock();
  result = (int)sqlite3_last_insert_rowid(db_sqlite3_handle());
  db_sqlite3_unlock();
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mode_DirSym>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L18:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x24(%rbp),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D14(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L18
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D14(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
type: f64

tool: D14: 1

assistant: ```c
void mode_DirSym(double *th, double al, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    th[i] = 1.0 / (double)dim;
  }
  th[dim] = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mode_DirSym>:
  endbr64
  test   %esi,%esi
  jle    L3
  pxor   %xmm1,%xmm1
  cvtsi2sd %esi,%xmm1
  movsd  D18(%rip),%xmm0
  divsd  %xmm1,%xmm0
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L13:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
L3:
  movslq %esi,%rsi
  mov    D18(%rip),%rax
  mov    %rax,(%rdi,%rsi,8)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
type_infered: f64

tool: D18: 1

assistant: ```c
void mode_DirSym(double *th, double al, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    th[i] = 1.0 / (double)dim;
  }
  th[dim] = 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mode_DirSym>:
  endbr64
  movsd  D14(%rip),%xmm2
  test   %esi,%esi
  jle    L12
  pxor   %xmm1,%xmm1
  movsd  D14(%rip),%xmm2
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  cvtsi2sd %esi,%xmm1
  lea    0x8(%rdi,%rdx,8),%rdx
  movapd %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  nopl   0x0(%rax,%rax,1)
L19:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L19
L12:
  movslq %esi,%rsi
  movsd  %xmm2,(%rdi,%rsi,8)
  ret
```

tool_calls: name: unpack_data
arguments: tag: D14
data_type: f64

tool: D14: 1

assistant: ```c
void mode_DirSym(double *th, double al, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    th[i] = 1.0 / (double)dim;
  }
  th[dim] = 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mode_DirSym>:
  endbr64
  movsd  D3(%rip),%xmm2
  test   %esi,%esi
  jle    L38
  pxor   %xmm1,%xmm1
  movsd  D3(%rip),%xmm2
  cvtsi2sd %esi,%xmm1
  movapd %xmm2,%xmm0
  divsd  %xmm1,%xmm0
  cmp    $0x1,%esi
  je     L37
  mov    %esi,%edx
  movapd %xmm0,%xmm1
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm1,%xmm1
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L2:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L2
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%sil
  je     L38
L13:
  cltq
  movsd  %xmm0,(%rdi,%rax,8)
L38:
  movslq %esi,%rsi
  movsd  %xmm2,(%rdi,%rsi,8)
  ret
L37:
  xor    %eax,%eax
  jmp    L13
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: f64

tool: D3: 1

assistant: ```c
void mode_DirSym(double *th, double al, int dim) {
  int i;
  for (i = 0; i < dim; i++) {
    th[i] = 1.0 / (double)dim;
  }
  th[dim] = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rdx
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x28(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L26
L1:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L26:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L1
  movl   $0x0,-0x18(%rbp)
  jmp    L78
L30:
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L7:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L60
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x10(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    -0x24(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L60
  addl   $0x1,-0x20(%rbp)
L60:
  addl   $0x1,-0x14(%rbp)
L32:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jl     L7
  addl   $0x1,-0x18(%rbp)
L78:
  mov    -0x28(%rbp),%eax
  cmp    %eax,-0x18(%rbp)
  jl     L30
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L83
  call   <__stack_chk_fail@plt>
L83:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D29
type: string

tool: D4: %d %d

tool: D29: %d

assistant: ```c
int main() {
  int n;
  int k;
  int count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i < j) {
        if (((a[i] + a[j]) % k) == 0) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  cmpl   $0x0,(%rsp)
  jle    L1
  mov    %rax,%rbx
  mov    %rax,%r13
  mov    $0x0,%r12d
  lea    D24(%rip),%r14
L91:
  mov    %r13,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    (%rsp),%edi
  add    $0x4,%r13
  cmp    %r12d,%edi
  jg     L91
  test   %edi,%edi
  jle    L1
  mov    0x4(%rsp),%r8d
  mov    %edi,%edi
  mov    $0x0,%esi
  jmp    L58
L92:
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  je     L8
L9:
  cmp    %esi,%ecx
  jle    L92
  mov    (%rbx,%rcx,4),%eax
  add    (%rbx,%rsi,4),%eax
  cltd
  idiv   %r8d
  cmp    $0x1,%edx
  adc    $0x0,%ebp
  jmp    L92
L8:
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  je     L1
L58:
  mov    $0x0,%ecx
  jmp    L9
L1:
  mov    %ebp,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L64:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: tag: D24
type_guessed: string

tool: D15: %d %d

tool: D24: %d

assistant: ```c
int main() {
  int n;
  int k;
  int count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i < j) {
        if (((a[i] + a[j]) % k) == 0) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r14
  lea    D16(%rip),%rdi
  push   %r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L61
  mov    %rax,%rbx
  mov    %rax,%r14
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <scanf@plt>
  movslq (%rsp),%rdi
  add    $0x4,%r14
  cmp    %r13d,%edi
  jg     L3
  test   %edi,%edi
  jle    L61
  mov    0x4(%rsp),%r8d
  xor    %esi,%esi
  nopl   0x0(%rax)
L65:
  mov    $0x1,%ecx
  jmp    L79
  nopw   0x0(%rax,%rax,1)
L78:
  cmp    %esi,%ecx
  jle    L19
  mov    (%rbx,%rcx,4),%eax
  add    (%rbx,%rsi,4),%eax
  cltd
  idiv   %r8d
  cmp    $0x1,%edx
  adc    $0x0,%ebp
L19:
  add    $0x1,%rcx
L79:
  cmp    %rdi,%rcx
  jne    L78
  add    $0x1,%rsi
  cmp    %rdi,%rsi
  jne    L65
L61:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D16: %d %d

tool: D2: %d

assistant: ```c
int main() {
  int n;
  int k;
  int count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i < j) {
        if (((a[i] + a[j]) % k) == 0) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r14
  lea    D15(%rip),%rdi
  push   %r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    (%rsp),%edx
  test   %edx,%edx
  jle    L29
  mov    %rax,%rbx
  mov    %rax,%r14
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L64:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <scanf@plt>
  mov    (%rsp),%r9d
  add    $0x4,%r14
  cmp    %r13d,%r9d
  jg     L64
  test   %r9d,%r9d
  jle    L29
  lea    -0x2(%r9),%r8d
  mov    0x4(%rsp),%edi
  movslq %r9d,%r10
  xor    %esi,%esi
  add    $0x2,%r8
  nopl   0x0(%rax)
L62:
  mov    $0x1,%ecx
  cmp    $0x1,%r9d
  je     L7
  nopl   0x0(%rax,%rax,1)
L67:
  cmp    %esi,%ecx
  jle    L23
  mov    (%rbx,%rcx,4),%eax
  add    (%rbx,%rsi,4),%eax
  cltd
  idiv   %edi
  cmp    $0x1,%edx
  adc    $0x0,%ebp
L23:
  add    $0x1,%rcx
  cmp    %rcx,%r8
  jne    L67
L7:
  add    $0x1,%rsi
  cmp    %r10,%rsi
  jne    L62
L29:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D15: %d %d

tool: D0: %d

assistant: ```c
int main() {
  int n;
  int k;
  int count;
  scanf("%d %d", &n, &k);
  int *a = malloc(sizeof(int) * n);
  for (int a_i = 0; a_i < n; a_i++) {
    scanf("%d", &a[a_i]);
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (i < j) {
        if (((a[i] + a[j]) % k) == 0) {
          count++;
        }
      }
    }
  }
  printf("%d", count);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<spread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <pread@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <die_if_readerr@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int spread(int fd, void *buf, size_t size, off_t offset) {
  int ret = pread(fd, buf, size, offset);
  die_if_readerr(ret, size);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<spread>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbp
  call   <pread@plt>
  mov    %eax,%ebx
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <die_if_readerr@plt>
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int spread(int fd, void *buf, size_t size, off_t offset) {
  int ret = pread(fd, buf, size, offset);
  die_if_readerr(ret, size);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<spread>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  sub    $0x8,%rsp
  call   <pread@plt>
  mov    %rbp,%rsi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <die_if_readerr@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int spread(int fd, void *buf, size_t size, off_t offset) {
  int ret = pread(fd, buf, size, offset);
  die_if_readerr(ret, size);
  return ret;
}
```