ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x10,%rsp
  mov    $0x8,%r9d
  mov    $0x8,%r8d
  mov    $0x4,%ecx
  push   $0x8
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rdi
  push   $0x10
  push   $0x8
  push   $0x4
  push   $0x8
  call   <printf@plt>
  add    $0x38,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
type_infered: string

tool: D9: // generated by word_size.c

#ifndef WORD_SIZE_H
#define WORD_SIZE_H

#define SIZEOF_CHAR            ( %d )
#define SIZEOF_SHORT           ( %d )
#define SIZEOF_INT             ( %d )
#define SIZEOF_LONG            ( %d )
#define SIZEOF_LONG_LONG       ( %d )
#define SIZEOF_VOID_P          ( %d )
#define SIZEOF_FLOAT           ( %d )
#define SIZEOF_DOUBLE          ( %d )
#define SIZEOF_LONG_DOUBLE     ( %d )

#define SIZEOF_SIZE_T          ( %d )

#endif // WORD_SIZE_H


assistant: ```c
void main() {
  printf("// generated by word_size.c\n\n"
         "#ifndef WORD_SIZE_H\n"
         "#define WORD_SIZE_H\n"
         "\n"
         "#define SIZEOF_CHAR            ( %d )\n"
         "#define SIZEOF_SHORT           ( %d )\n"
         "#define SIZEOF_INT             ( %d )\n"
         "#define SIZEOF_LONG            ( %d )\n"
         "#define SIZEOF_LONG_LONG       ( %d )\n"
         "#define SIZEOF_VOID_P          ( %d )\n"
         "#define SIZEOF_FLOAT           ( %d )\n"
         "#define SIZEOF_DOUBLE          ( %d )\n"
         "#define SIZEOF_LONG_DOUBLE     ( %d )\n"
         "\n"
         "#define SIZEOF_SIZE_T          ( %d )\n"
         "\n"
         "#endif // WORD_SIZE_H\n",
         sizeof(char), sizeof(short), sizeof(int), sizeof(long), sizeof(long long), sizeof(void *), sizeof(float), sizeof(double), sizeof(long double), sizeof(size_t));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<output_screen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <draw_screen@plt>
  mov    $0x0,%eax
  call   <adjust_to_framerate@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void output_screen() {
  draw_screen();
  adjust_to_framerate();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<output_screen>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <draw_screen@plt>
  mov    $0x0,%eax
  call   <adjust_to_framerate@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void output_screen() {
  draw_screen();
  adjust_to_framerate();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<output_screen>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <draw_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <adjust_to_framerate@plt>
```

assistant: ```c
void output_screen() {
  draw_screen();
  adjust_to_framerate();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<output_screen>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <draw_screen@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <adjust_to_framerate@plt>
```

assistant: ```c
void output_screen() {
  draw_screen();
  adjust_to_framerate();
}
```
user: What is the c source code of the assembly code below:

```asm
<strchr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L23
L15:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0xc(%rbp)
  jne    L3
  mov    -0x8(%rbp),%rax
  jmp    L19
L3:
  addq   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
char *strchr(char *str, int ch) {
  for (; *str; str++)
    if (*str == ch)
      return str;
  return (void *)0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strchr>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L12
L14:
  movsbl %dl,%edx
  cmp    %esi,%edx
  je     L22
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  mov    $0x0,%eax
  ret
L12:
  mov    $0x0,%eax
  ret
L22:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(char *str, int ch) {
  for (; *str; str++)
    if (*str == ch)
      return str;
  return (void *)0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strchr>:
  endbr64
  jmp    L26
  cs nopw 0x0(%rax,%rax,1)
L28:
  cmp    %esi,%edx
  je     L16
  add    $0x1,%rdi
L26:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L28
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(char *str, int ch) {
  for (; *str; str++)
    if (*str == ch)
      return str;
  return (void *)0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strchr>:
  endbr64
  jmp    L23
  cs nopw 0x0(%rax,%rax,1)
L12:
  cmp    %esi,%edx
  je     L3
  add    $0x1,%rdi
L23:
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rdi,%rax
  ret
```

assistant: ```c
char *strchr(char *str, int ch) {
  for (; *str; str++)
    if (*str == ch)
      return str;
  return (void *)0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L9
L36:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L21
  mov    $0xffffffff,%eax
  jmp    L2
L21:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0xc(%rbp)
L9:
  cmpl   $0x1dcd64ff,-0xc(%rbp)
  jle    L36
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int main() {
  int i;
  char *c = NULL;
  for (i = 0; i < 500000000; i++) {
    c = (char *)malloc(100);
    if (__builtin_expect(c == NULL, 0))
      return -1;
    free(c);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1dcd6500,%ebp
L4:
  mov    $0x64,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  jne    L1
  mov    %rbx,%rdi
  call   <free@plt>
  sub    $0x1,%ebp
  jne    L4
  mov    $0x0,%eax
  jmp    L15
L1:
  mov    $0xffffffff,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  char *c = NULL;
  for (i = 0; i < 500000000; i++) {
    c = (char *)malloc(100);
    if (__builtin_expect(c == NULL, 0))
      return -1;
    free(c);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x1dcd6500,%ebx
  sub    $0x8,%rsp
  jmp    L33
  nopl   0x0(%rax)
L8:
  mov    %rbp,%rdi
  call   <free@plt>
  sub    $0x1,%ebx
  je     L7
L33:
  mov    $0x64,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L8
  mov    $0xffffffff,%eax
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  xor    %eax,%eax
  jmp    L9
```

assistant: ```c
int main() {
  int i;
  char *c = NULL;
  for (i = 0; i < 500000000; i++) {
    c = (char *)malloc(100);
    if (__builtin_expect(c == NULL, 0))
      return -1;
    free(c);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  mov    $0x1dcd6500,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax)
L29:
  mov    %rbp,%rdi
  call   <free@plt>
  sub    $0x1,%ebx
  je     L26
L17:
  mov    $0x64,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  sete   %dil
  xor    %esi,%esi
  call   <__builtin_expect@plt>
  test   %rax,%rax
  je     L29
  mov    $0xffffffff,%eax
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  xor    %eax,%eax
  jmp    L20
```

assistant: ```c
int main() {
  int i;
  char *c = NULL;
  for (i = 0; i < 500000000; i++) {
    c = (char *)malloc(100);
    if (__builtin_expect(c == NULL, 0))
      return -1;
    free(c);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x65,-0xd(%rbp)
  movb   $0x65,-0xc(%rbp)
  movb   $0x65,-0xb(%rbp)
  movb   $0x31,-0xa(%rbp)
  movb   $0x31,-0x9(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L10:
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0xd(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L7:
  cmpl   $0x4,-0x14(%rbp)
  jle    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: string

tool: D4: %c


assistant: ```c
int main() {
  char a[5];
  a[0] = 'e';
  a[1] = 'e';
  a[2] = 'e';
  a[3] = '1';
  a[4] = '1';
  int i = 0;
  for (i = 0; i < 5; i++) {
    printf("%c\n", a[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x65,0x3(%rsp)
  movb   $0x65,0x4(%rsp)
  movb   $0x65,0x5(%rsp)
  movb   $0x31,0x6(%rsp)
  movb   $0x31,0x7(%rsp)
  lea    0x3(%rsp),%rbx
  lea    0x8(%rsp),%r12
  lea    D2(%rip),%rbp
L0:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: %c


assistant: ```c
int main() {
  char a[5];
  a[0] = 'e';
  a[1] = 'e';
  a[2] = 'e';
  a[3] = '1';
  a[4] = '1';
  int i = 0;
  for (i = 0; i < 5; i++) {
    printf("%c\n", a[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x65,%esi
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x31316565,0x4(%rsp)
  lea    0x3(%rsp),%rbx
  lea    0x8(%rsp),%r12
L11:
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  je     L27
  movsbl (%rbx),%esi
  jmp    L11
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: %c


assistant: ```c
int main() {
  char a[5];
  a[0] = 'e';
  a[1] = 'e';
  a[2] = 'e';
  a[3] = '1';
  a[4] = '1';
  int i = 0;
  for (i = 0; i < 5; i++) {
    printf("%c\n", a[i]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D3(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x31,0x4(%rsp)
  mov    %rsp,%rbx
  lea    0x5(%rsp),%r12
  movl   $0x31656565,(%rsp)
L11:
  movsbl (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
datatype: string

tool: D3: %c


assistant: ```c
int main() {
  char a[5];
  a[0] = 'e';
  a[1] = 'e';
  a[2] = 'e';
  a[3] = '1';
  a[4] = '1';
  int i = 0;
  for (i = 0; i < 5; i++) {
    printf("%c\n", a[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int32_pack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L11
  mov    -0x4(%rbp),%eax
  or     $0x80,%al
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x7,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0xe,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x15,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0xc,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  sar    $0x1c,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  or     $0x80,%dl
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x20,%rax
  movl   $0xff,(%rax)
  mov    -0x10(%rbp),%rdx
  add    $0x1c,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  add    $0x14,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x24,%rax
  movl   $0x1,(%rax)
  mov    $0xa,%eax
  jmp    L2
L11:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <uint32_pack@plt>
L2:
  leave
  ret
```

assistant: ```c
size_t int32_pack(int32_t value, uint8_t *out) {
  if (value < 0) {
    out[0] = value | 0x80;
    out[1] = (value >> 7) | 0x80;
    out[2] = (value >> 14) | 0x80;
    out[3] = (value >> 21) | 0x80;
    out[4] = (value >> 28) | 0x80;
    out[5] = out[6] = out[7] = out[8] = 0xff;
    out[9] = 0x01;
    return 10;
  } else {
    return uint32_pack(value, out);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<int32_pack>:
  endbr64
  test   %edi,%edi
  js     L5
  sub    $0x8,%rsp
  call   <uint32_pack@plt>
  add    $0x8,%rsp
  ret
L5:
  mov    %edi,%eax
  or     $0x80,%al
  mov    %eax,(%rsi)
  mov    %edi,%eax
  sar    $0x7,%eax
  or     $0x80,%al
  mov    %eax,0x4(%rsi)
  mov    %edi,%eax
  sar    $0xe,%eax
  or     $0x80,%al
  mov    %eax,0x8(%rsi)
  mov    %edi,%eax
  sar    $0x15,%eax
  or     $0x80,%al
  mov    %eax,0xc(%rsi)
  sar    $0x1c,%edi
  or     $0x80,%dil
  mov    %edi,0x10(%rsi)
  movl   $0xff,0x20(%rsi)
  movl   $0xff,0x1c(%rsi)
  movl   $0xff,0x18(%rsi)
  movl   $0xff,0x14(%rsi)
  movl   $0x1,0x24(%rsi)
  mov    $0xa,%eax
  ret
```

assistant: ```c
size_t int32_pack(int32_t value, uint8_t *out) {
  if (value < 0) {
    out[0] = value | 0x80;
    out[1] = (value >> 7) | 0x80;
    out[2] = (value >> 14) | 0x80;
    out[3] = (value >> 21) | 0x80;
    out[4] = (value >> 28) | 0x80;
    out[5] = out[6] = out[7] = out[8] = 0xff;
    out[9] = 0x01;
    return 10;
  } else {
    return uint32_pack(value, out);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<int32_pack>:
  endbr64
  test   %edi,%edi
  js     L5
  jmp    1050 <uint32_pack@plt>
  nopl   (%rax)
L5:
  mov    %edi,%eax
  movl   $0x1,0x24(%rsi)
  or     $0x80,%al
  mov    %eax,(%rsi)
  mov    %edi,%eax
  sar    $0x7,%eax
  or     $0x80,%al
  mov    %eax,0x4(%rsi)
  mov    %edi,%eax
  sar    $0xe,%eax
  or     $0x80,%al
  mov    %eax,0x8(%rsi)
  mov    %edi,%eax
  sar    $0x1c,%edi
  sar    $0x15,%eax
  mov    %edi,0x10(%rsi)
  or     $0x80,%al
  mov    %eax,0xc(%rsi)
  movabs $0xff000000ff,%rax
  mov    %rax,0x14(%rsi)
  mov    %rax,0x1c(%rsi)
  mov    $0xa,%eax
  ret
```

assistant: ```c
size_t int32_pack(int32_t value, uint8_t *out) {
  if (value < 0) {
    out[0] = value | 0x80;
    out[1] = (value >> 7) | 0x80;
    out[2] = (value >> 14) | 0x80;
    out[3] = (value >> 21) | 0x80;
    out[4] = (value >> 28) | 0x80;
    out[5] = out[6] = out[7] = out[8] = 0xff;
    out[9] = 0x01;
    return 10;
  } else {
    return uint32_pack(value, out);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<int32_pack>:
  endbr64
  test   %edi,%edi
  js     L1
  jmp    1050 <uint32_pack@plt>
  nopl   (%rax)
L1:
  mov    %edi,%eax
  mov    %edi,%ecx
  mov    %edi,%edx
  movl   $0x1,0x24(%rsi)
  sar    $0x7,%eax
  sar    $0xe,%ecx
  movd   %edi,%xmm0
  sar    $0x15,%edx
  movd   %eax,%xmm3
  movd   %ecx,%xmm1
  sar    $0x1c,%edi
  movd   %edx,%xmm2
  punpckldq %xmm3,%xmm0
  mov    %edi,0x10(%rsi)
  mov    $0xa,%eax
  punpckldq %xmm2,%xmm1
  punpcklqdq %xmm1,%xmm0
  por    D7(%rip),%xmm0
  movups %xmm0,(%rsi)
  movdqa D2(%rip),%xmm0
  movups %xmm0,0x14(%rsi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D2
data_type: byte[16]

tool: {"D7": [0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00]}

tool: {"D2": [0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00,0xff,0x00,0x00,0x00]}

assistant: ```c
size_t int32_pack(int32_t value, uint8_t *out) {
  if (value < 0) {
    out[0] = value | 0x80;
    out[1] = (value >> 7) | 0x80;
    out[2] = (value >> 14) | 0x80;
    out[3] = (value >> 21) | 0x80;
    out[4] = (value >> 28) | 0x80;
    out[5] = out[6] = out[7] = out[8] = 0xff;
    out[9] = 0x01;
    return 10;
  } else {
    return uint32_pack(value, out);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<Strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    D47(%rip),%rax
  test   %rax,%rax
  je     L20
  mov    D47(%rip),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movq   $0x0,D47(%rip)
L20:
  cmpq   $0x0,-0x28(%rbp)
  jne    L21
  mov    D4(%rip),%r12
  jmp    L53
L21:
  mov    -0x28(%rbp),%r12
L53:
  test   %r12,%r12
  jne    L12
  mov    $0x0,%eax
  jmp    L73
L12:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <strspn@plt>
  cltq
  lea    (%r12,%rax,1),%r13
  movzbl 0x0(%r13),%eax
  test   %al,%al
  jne    L40
  mov    $0x0,%eax
  jmp    L73
L40:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %r13,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbx
  test   %rbx,%rbx
  jne    L84
  movq   $0x0,D4(%rip)
  jmp    L34
L84:
  mov    %rbx,%rax
  sub    %r13,%rax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,D114(%rip)
  mov    D114(%rip),%rax
  test   %rax,%rax
  je     L126
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  cltq
  lea    (%rbx,%rax,1),%r12
  cmp    %rbx,%r12
  ja     L132
  lea    0x1(%rbx),%rax
  jmp    L16
L132:
  mov    %r12,%rax
L16:
  mov    %rax,D114(%rip)
  mov    %rbx,%rax
  sub    %r13,%rax
  mov    %eax,%edx
  mov    D114(%rip),%rax
  mov    %r13,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    D114(%rip),%rdx
  mov    %rbx,%rax
  sub    %r13,%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    D114(%rip),%r13
  jmp    L34
L126:
  movb   $0x0,(%rbx)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  cltq
  lea    (%rbx,%rax,1),%r12
  cmp    %rbx,%r12
  jbe    L129
  add    $0x1,%r12
  mov    %r12,%rax
  jmp    L44
L129:
  add    $0x1,%rbx
  mov    %rbx,%rax
L44:
  mov    %rax,D114(%rip)
L34:
  mov    %r13,%rax
L73:
  add    $0x18,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

assistant: ```c
char *Strtok(const char *string, const char *sepset) {
  register char *p, *q, *r;
  static char *savept;
  static char *hold;
  if (hold != NULL) {
    free(hold);
    hold = NULL;
  }
  if (string == NULL)
    p = savept;
  else
    p = (char *)string;
  if (p == NULL)
    return (NULL);
  q = p + strspn(p, sepset);
  if (*q == '\0')
    return (NULL);
  if ((r = strpbrk(q, sepset)) == NULL)
    savept = 0;
  else {
    hold = (char *)malloc((unsigned)(r - q) + 1);
    if (hold) {
      p = r + strspn(r, sepset);
      savept = (p > r) ? p : r + 1;
      (void)memcpy(hold, q, (unsigned)(r - q));
      hold[r - q] = '\0';
      q = hold;
    } else {
      *r = '\0';
      p = r + strspn(r, sepset);
      savept = (p > r) ? ++p : ++r;
    }
  }
  return (q);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Strtok>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    D15(%rip),%rdi
  test   %rdi,%rdi
  je     L3
  call   <free@plt>
  movq   $0x0,D15(%rip)
L3:
  test   %rbx,%rbx
  je     L13
L92:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strspn@plt>
  cltq
  add    %rax,%rbx
  cmpb   $0x0,(%rbx)
  je     L44
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L99
  mov    %rax,%r13
  sub    %rbx,%r13
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  mov    %rax,D68(%rip)
  test   %rax,%rax
  je     L5
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strspn@plt>
  cltq
  add    %r12,%rax
  lea    0x1(%r12),%rdx
  cmp    %rax,%r12
  cmovae %rdx,%rax
  mov    %rax,D68(%rip)
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    D68(%rip),%rdi
  call   <memcpy@plt>
  mov    D68(%rip),%rbx
  movb   $0x0,(%rbx,%r13,1)
  jmp    L39
L13:
  mov    D68(%rip),%rbx
  test   %rbx,%rbx
  je     L39
  jmp    L92
L99:
  movq   $0x0,D68(%rip)
L39:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  movb   $0x0,(%r12)
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strspn@plt>
  cltq
  add    %r12,%rax
  lea    0x1(%rax),%rcx
  lea    0x1(%r12),%rdx
  cmp    %rax,%r12
  mov    %rcx,%rax
  cmovae %rdx,%rax
  mov    %rax,D64(%rip)
  jmp    L39
L44:
  mov    $0x0,%ebx
  jmp    L39
```

assistant: ```c
char *Strtok(const char *string, const char *sepset) {
  register char *p, *q, *r;
  static char *savept;
  static char *hold;
  if (hold != NULL) {
    free(hold);
    hold = NULL;
  }
  if (string == NULL)
    p = savept;
  else
    p = (char *)string;
  if (p == NULL)
    return (NULL);
  q = p + strspn(p, sepset);
  if (*q == '\0')
    return (NULL);
  if ((r = strpbrk(q, sepset)) == NULL)
    savept = 0;
  else {
    hold = (char *)malloc((unsigned)(r - q) + 1);
    if (hold) {
      p = r + strspn(r, sepset);
      savept = (p > r) ? p : r + 1;
      (void)memcpy(hold, q, (unsigned)(r - q));
      hold[r - q] = '\0';
      q = hold;
    } else {
      *r = '\0';
      p = r + strspn(r, sepset);
      savept = (p > r) ? ++p : ++r;
    }
  }
  return (q);
}
```