ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<blFgetsany>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <fgetc@plt>
  mov    D1(%rip),%rbp
  cmp    %eax,0x0(%rbp)
  je     L82
  mov    %eax,%edi
  mov    %r13,%rsi
  xor    %r15d,%r15d
  call   <ungetc@plt>
  mov    $0x50,%edi
  call   <malloc@plt>
  movl   $0x50,0xc(%rsp)
  mov    %rax,%r12
  test   %rax,%rax
  jne    L7
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L98:
  mov    %al,(%r12,%r15,1)
  lea    0x1(%r15),%r14d
  cmp    %r14d,0xc(%rsp)
  je     L18
L109:
  add    $0x1,%r15
  cmp    %ebx,0x0(%rbp)
  je     L13
  cmp    $0xa,%ebx
  je     L13
L7:
  mov    %r13,%rdi
  mov    %r15d,0x8(%rsp)
  mov    %r15d,%r14d
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%rbp)
  jne    L98
L13:
  movslq %r14d,%rax
  lea    0x1(%r14),%ecx
  movb   $0x0,(%r12,%rax,1)
  cmp    0xc(%rsp),%ecx
  jl     L59
L24:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  mov    %r15d,%eax
  mov    %r12,%rdi
  add    $0x51,%eax
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L109
L36:
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  jmp    L24
L59:
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L24
  jmp    L36
  cs nopw 0x0(%rax,%rax,1)
L82:
  xor    %r12d,%r12d
  jmp    L24
```

assistant: ```c
char *blFgetsany(FILE *fp) {
  int bufflen = 80, buffpos = 0, ch;
  char *buffer = NULL;
  if ((ch = fgetc(fp)) == EOF)
    return (NULL);
  ungetc(ch, fp);
  if ((buffer = (char *)malloc(bufflen * sizeof(char))) == NULL) {
    errno = ENOMEM;
    return (NULL);
  }
  do {
    ch = fgetc(fp);
    if (ch != EOF) {
      buffer[buffpos] = ch;
      if (++buffpos == bufflen) {
        bufflen += 80;
        if ((buffer = realloc(buffer, bufflen)) == NULL) {
          errno = ENOMEM;
          return (NULL);
        }
      }
    }
  } while ((ch != EOF) && (ch != '\n'));
  buffer[buffpos] = '\0';
  if (++buffpos < bufflen) {
    if ((buffer = realloc(buffer, bufflen)) == NULL) {
      errno = ENOMEM;
      return (NULL);
    }
  }
  return (buffer);
}
```
user: What is the c source code of the assembly code below:

```asm
<blFgetsany>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <fgetc@plt>
  mov    D19(%rip),%rbp
  cmp    %eax,0x0(%rbp)
  je     L48
  mov    %eax,%edi
  mov    %r13,%rsi
  xor    %r15d,%r15d
  call   <ungetc@plt>
  mov    $0x50,%edi
  call   <malloc@plt>
  movl   $0x50,0xc(%rsp)
  mov    %rax,%r12
  test   %rax,%rax
  jne    L10
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L115:
  mov    %al,(%r12,%r15,1)
  lea    0x1(%r15),%r14d
  cmp    %r14d,0xc(%rsp)
  je     L63
L39:
  add    $0x1,%r15
  cmp    %ebx,0x0(%rbp)
  je     L28
  cmp    $0xa,%ebx
  je     L28
L10:
  mov    %r13,%rdi
  mov    %r15d,0x8(%rsp)
  mov    %r15d,%r14d
  call   <fgetc@plt>
  mov    %eax,%ebx
  cmp    %eax,0x0(%rbp)
  jne    L115
L28:
  movslq %r14d,%rax
  lea    0x1(%r14),%ecx
  movb   $0x0,(%r12,%rax,1)
  cmp    0xc(%rsp),%ecx
  jl     L4
L17:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  mov    %r15d,%eax
  mov    %r12,%rdi
  add    $0x51,%eax
  mov    %eax,%esi
  mov    %eax,0xc(%rsp)
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L39
L101:
  mov    D17(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  jmp    L17
L4:
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L17
  jmp    L101
  cs nopw 0x0(%rax,%rax,1)
L48:
  xor    %r12d,%r12d
  jmp    L17
```

assistant: ```c
char *blFgetsany(FILE *fp) {
  int bufflen = 80, buffpos = 0, ch;
  char *buffer = NULL;
  if ((ch = fgetc(fp)) == EOF)
    return (NULL);
  ungetc(ch, fp);
  if ((buffer = (char *)malloc(bufflen * sizeof(char))) == NULL) {
    errno = ENOMEM;
    return (NULL);
  }
  do {
    ch = fgetc(fp);
    if (ch != EOF) {
      buffer[buffpos] = ch;
      if (++buffpos == bufflen) {
        bufflen += 80;
        if ((buffer = realloc(buffer, bufflen)) == NULL) {
          errno = ENOMEM;
          return (NULL);
        }
      }
    }
  } while ((ch != EOF) && (ch != '\n'));
  buffer[buffpos] = '\0';
  if (++buffpos < bufflen) {
    if ((buffer = realloc(buffer, bufflen)) == NULL) {
      errno = ENOMEM;
      return (NULL);
    }
  }
  return (buffer);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<exchange>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void exchange(int a, int b) {
  int tmp = a;
  a = b;
  b = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<exchange>:
  endbr64
  ret
```

assistant: ```c
void exchange(int a, int b) {
  int tmp = a;
  a = b;
  b = tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<exchange>:
  endbr64
  ret
```

assistant: ```c
void exchange(int a, int b) {
  int tmp = a;
  a = b;
  b = tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<exchange>:
  endbr64
  ret
```

assistant: ```c
void exchange(int a, int b) {
  int tmp = a;
  a = b;
  b = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EMACIntClear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  and    $0x4045,%eax
  test   %eax,%eax
  je     L18
  orl    $0x10000,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%eax
  and    $0x27ba,%eax
  test   %eax,%eax
  je     L2
  orl    $0x8000,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  test   %eax,%eax
  je     L32
  mov    -0x4(%rbp),%eax
  add    $0xc14,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,(%rdx)
L32:
  cmpl   $0x0,-0x8(%rbp)
  jns    L37
  mov    -0x4(%rbp),%eax
  add    $0xfd8,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0xfd8,%edx
  movslq %edx,%rdx
  or     $0x1,%eax
  mov    %eax,(%rdx)
L37:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EMACIntClear>:
  endbr64
  mov    %esi,%eax
  or     $0x10000,%eax
  test   $0x4045,%esi
  cmovne %eax,%esi
  mov    %esi,%eax
  or     $0x80,%ah
  test   $0x27ba,%esi
  cmovne %eax,%esi
  test   $0x7fffffff,%esi
  je     L1
  lea    0xc14(%rdi),%eax
  cltq
  mov    %esi,%edx
  and    $0x7fffffff,%edx
  mov    %edx,(%rax)
L1:
  test   %esi,%esi
  js     L26
L0:
  ret
L26:
  add    $0xfd8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  jmp    L0
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<EMACIntClear>:
  endbr64
  mov    %esi,%eax
  or     $0x10000,%eax
  test   $0x4045,%esi
  cmovne %eax,%esi
  mov    %esi,%eax
  or     $0x80,%ah
  test   $0x27ba,%esi
  cmovne %eax,%esi
  mov    %esi,%edx
  and    $0x7fffffff,%edx
  je     L3
  lea    0xc14(%rdi),%eax
  cltq
  mov    %edx,(%rax)
L3:
  test   %esi,%esi
  js     L7
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0xfd8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<EMACIntClear>:
  endbr64
  mov    %esi,%eax
  or     $0x10000,%eax
  test   $0x4045,%esi
  cmovne %eax,%esi
  mov    %esi,%eax
  or     $0x80,%ah
  test   $0x27ba,%esi
  cmovne %eax,%esi
  mov    %esi,%edx
  and    $0x7fffffff,%edx
  je     L18
  lea    0xc14(%rdi),%eax
  cltq
  mov    %edx,(%rax)
L18:
  test   %esi,%esi
  js     L10
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  add    $0xfd8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x1,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void EMACIntClear(uint32_t ui32Base, uint32_t ui32IntFlags) {
  ;
  if (ui32IntFlags & (0x00000001 | 0x00000040 | 0x00004000 | 0x00000004)) {
    ui32IntFlags |= 0x00010000;
  }
  if (ui32IntFlags & (0x00000002 | 0x00000008 | 0x00000010 | 0x00000020 | 0x00000080 | 0x00000100 | 0x00000200 | 0x00000400 | 0x00002000)) {
    ui32IntFlags |= 0x00008000;
  }
  if (ui32IntFlags & ~0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000C14))) = (ui32IntFlags & ~0x80000000);
  }
  if (ui32IntFlags & 0x80000000) {
    (*((volatile uint32_t *)(ui32Base + 0x00000FD8))) |= 0x00000001;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    $0x0,%edi
  call   <setuid@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
type_infered: string

tool: D9: UID: %d


assistant: ```c
int main() {
  sleep(5);
  setuid(0);
  printf("UID: %d\n", getuid());
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <sleep@plt>
  mov    $0x0,%edi
  call   <setuid@plt>
  mov    $0x0,%eax
  call   <getuid@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string

tool: D5: UID: %d


assistant: ```c
int main() {
  sleep(5);
  setuid(0);
  printf("UID: %d\n", getuid());
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <sleep@plt>
  xor    %edi,%edi
  call   <setuid@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
datatype: string

tool: D6: UID: %d


assistant: ```c
int main() {
  sleep(5);
  setuid(0);
  printf("UID: %d\n", getuid());
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <sleep@plt>
  xor    %edi,%edi
  call   <setuid@plt>
  xor    %eax,%eax
  call   <getuid@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: UID: %d


assistant: ```c
int main() {
  sleep(5);
  setuid(0);
  printf("UID: %d\n", getuid());
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_intron_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L53
L73:
  lea    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jne    L64
  jmp    L22
L72:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L91
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L11
L91:
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x20(%rbp)
L22:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L72
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  jmp    L11
L64:
  mov    D13(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jg     L118
  mov    D10(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x10(%rbp)
  jge    L42
L118:
  mov    $0x0,%eax
  jmp    L11
L42:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L53:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L25
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L73
L25:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L96
  call   <__stack_chk_fail@plt>
L96:
  leave
  ret
```

assistant: ```c
int parse_intron_list(char *s, int *list, int *count) {
  long t;
  char *p, *q;
  *count = 0;
  p = q = s;
  while (*q != '\0' && *q != '\n') {
    t = strtol(p, &q, 10);
    if (q == p) {
      while (*q != '\0') {
        if (!isspace(*q)) {
          *count = 0;
          return 0;
        }
        q++;
      }
      return *count;
    }
    if (t > INT_MAX || t < INT_MIN) {
      return 0;
    }
    list[*count] = t;
    (*count)++;
    p = q;
  }
  return *count;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_intron_list>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdx)
  mov    %rdi,(%rsp)
  movzbl (%rdi),%eax
  test   %al,%al
  je     L145
  mov    %rdi,%rbx
  mov    %rsi,%r12
  cmp    $0xa,%al
  je     L145
  mov    %rsp,%r13
L111:
  mov    $0xa,%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strtol@plt>
  mov    %rbx,%rdx
  mov    (%rsp),%rbx
  cmp    %rdx,%rbx
  je     L143
  mov    D19(%rip),%rdx
  cmp    %rax,(%rdx)
  jl     L148
  mov    D16(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L97
  movslq 0x0(%rbp),%rdx
  mov    %eax,(%r12,%rdx,4)
  addl   $0x1,0x0(%rbp)
  movzbl (%rbx),%eax
  test   %al,%al
  je     L145
  cmp    $0xa,%al
  jne    L111
L145:
  mov    0x0(%rbp),%eax
L117:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L78
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L143:
  movzbl (%rdx),%edi
  test   %dil,%dil
  je     L17
L65:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L64
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  movzbl 0x1(%rax),%edi
  test   %dil,%dil
  jne    L65
L17:
  mov    0x0(%rbp),%eax
  jmp    L117
L64:
  movl   $0x0,0x0(%rbp)
  jmp    L117
L148:
  mov    $0x0,%eax
  jmp    L117
L97:
  mov    $0x0,%eax
  jmp    L117
L78:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_intron_list(char *s, int *list, int *count) {
  long t;
  char *p, *q;
  *count = 0;
  p = q = s;
  while (*q != '\0' && *q != '\n') {
    t = strtol(p, &q, 10);
    if (q == p) {
      while (*q != '\0') {
        if (!isspace(*q)) {
          *count = 0;
          return 0;
        }
        q++;
      }
      return *count;
    }
    if (t > INT_MAX || t < INT_MIN) {
      return 0;
    }
    list[*count] = t;
    (*count)++;
    p = q;
  }
  return *count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_intron_list>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdx)
  movzbl (%rdi),%eax
  mov    %rdi,(%rsp)
  test   %al,%al
  je     L27
  cmp    $0xa,%al
  je     L27
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rsp,%r12
  jmp    L33
  nopl   0x0(%rax)
L21:
  mov    D7(%rip),%rdx
  cmp    %rax,(%rdx)
  jl     L27
  mov    D4(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L27
  movslq 0x0(%r13),%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  mov    0x0(%r13),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L35
  cmp    $0xa,%dl
  je     L35
L33:
  mov    $0xa,%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  call   <strtol@plt>
  mov    %rbx,%rdx
  mov    (%rsp),%rbx
  cmp    %rdx,%rbx
  jne    L21
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L117
  jmp    L128
  nopl   (%rax)
L46:
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L128
L117:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L46
  movl   $0x0,0x0(%r13)
  xchg   %ax,%ax
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L118
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  xor    %eax,%eax
  jmp    L35
  nopl   0x0(%rax)
L128:
  mov    0x0(%r13),%eax
  jmp    L35
L118:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_intron_list(char *s, int *list, int *count) {
  long t;
  char *p, *q;
  *count = 0;
  p = q = s;
  while (*q != '\0' && *q != '\n') {
    t = strtol(p, &q, 10);
    if (q == p) {
      while (*q != '\0') {
        if (!isspace(*q)) {
          *count = 0;
          return 0;
        }
        q++;
      }
      return *count;
    }
    if (t > INT_MAX || t < INT_MIN) {
      return 0;
    }
    list[*count] = t;
    (*count)++;
    p = q;
  }
  return *count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_intron_list>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rdx)
  movzbl (%rdi),%eax
  mov    %rdi,(%rsp)
  test   %al,%al
  je     L1
  cmp    $0xa,%al
  je     L1
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %rsp,%r12
  jmp    L46
  nopl   0x0(%rax)
L84:
  mov    D12(%rip),%rdx
  cmp    %rax,(%rdx)
  jl     L1
  mov    D5(%rip),%rdx
  cmp    %rax,(%rdx)
  jg     L1
  movslq 0x0(%r13),%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
  mov    0x0(%r13),%eax
  add    $0x1,%eax
  mov    %eax,0x0(%r13)
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L137
  cmp    $0xa,%dl
  je     L137
L46:
  mov    $0xa,%edx
  mov    %rbx,%rdi
  mov    %r12,%rsi
  call   <strtol@plt>
  mov    %rbx,%rdx
  mov    (%rsp),%rbx
  cmp    %rdx,%rbx
  jne    L84
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L86
  jmp    L71
  nopl   (%rax)
L144:
  mov    (%rsp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%rsp)
  movsbl 0x1(%rax),%edi
  test   %dil,%dil
  je     L71
L86:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L144
  movl   $0x0,0x0(%r13)
  xchg   %ax,%ax
L137:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L114
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  jmp    L137
  nopl   0x0(%rax)
L71:
  mov    0x0(%r13),%eax
  jmp    L137
L114:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int parse_intron_list(char *s, int *list, int *count) {
  long t;
  char *p, *q;
  *count = 0;
  p = q = s;
  while (*q != '\0' && *q != '\n') {
    t = strtol(p, &q, 10);
    if (q == p) {
      while (*q != '\0') {
        if (!isspace(*q)) {
          *count = 0;
          return 0;
        }
        q++;
      }
      return *count;
    }
    if (t > INT_MAX || t < INT_MIN) {
      return 0;
    }
    list[*count] = t;
    (*count)++;
    p = q;
  }
  return *count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__make_fd_async>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D29(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L18
  mov    $0xffffffff,%eax
  jmp    L15
L18:
  mov    D15(%rip),%rax
  mov    (%rax),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L15
L33:
  mov    $0x0,%eax
L15:
  leave
  ret
```

assistant: ```c
int __make_fd_async(int fd) {
  int current_flags = fcntl(fd, F_GETFL, 0);
  if ((current_flags) == -1) {
    return -1;
  };
  int new_flags = current_flags | O_NONBLOCK;
  if ((fcntl(fd, F_SETFL, new_flags)) == -1) {
    return -1;
  };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__make_fd_async>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%edx
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L9
  mov    D11(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D28(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L9:
  pop    %rbx
  ret
```

assistant: ```c
int __make_fd_async(int fd) {
  int current_flags = fcntl(fd, F_GETFL, 0);
  if ((current_flags) == -1) {
    return -1;
  };
  int new_flags = current_flags | O_NONBLOCK;
  if ((fcntl(fd, F_SETFL, new_flags)) == -1) {
    return -1;
  };
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__make_fd_async>:
  endbr64
  mov    D15(%rip),%rax
  push   %rbp
  xor    %edx,%edx
  mov    %edi,%ebp
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L8
  mov    D4(%rip),%rdx
  mov    %ebp,%edi
  or     (%rdx),%eax
  mov    %eax,%edx
  mov    D26(%rip),%rax
  mov    (%rax),%esi
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L8:
  pop    %rbp
  ret
```

assistant: ```c
int __make_fd_async(int fd) {
  int current_flags = fcntl(fd, F_GETFL, 0);
  if ((current_flags) == -1) {
    return -1;
  };
  int new_flags = current_flags | O_NONBLOCK;
  if ((fcntl(fd, F_SETFL, new_flags)) == -1) {
    return -1;
  };
  return 0;
}
```