ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  mov    %rsi,%r12
  movslq %edi,%rbp
  lea    D49(%rip),%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L24:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L24
L6:
  lea    D25(%rip),%rax
  lea    D35(%rip),%rcx
  xor    %ebx,%ebx
  mov    %rsp,%r12
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D26(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D39(%rip),%rax
  lea    D36(%rip),%rbp
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L5:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L5
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D49
datatype: string
name: extract_symbolic_data
arguments: data_label: D25
datatype: string
name: extract_symbolic_data
arguments: data_label: D35
datatype: string
name: extract_symbolic_data
arguments: data_label: D26
datatype: string
name: extract_symbolic_data
arguments: data_label: D39
datatype: string
name: extract_symbolic_data
arguments: data_label: D36
datatype: string

tool: D49: arg %d: %s


tool: D25: Orgeon

tool: D35: California

tool: D26: Washington

tool: D39: Texas

tool: D36: state %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("arg %d: %s\n", i, argv[i]);
    i++;
  }
  char *states[] = {"California", "Orgeon", "Washington", "Texas"};
  int num_state = 4;
  i = 0;
  while (i < num_state) {
    printf("state %d: %s\n", i, states[i]);
    i++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ra_conf_mtu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x4ff,-0x4(%rbp)
  jle    L4
  cmpl   $0xffff,-0x4(%rbp)
  jg     L4
  mov    -0x4(%rbp),%eax
  mov    %eax,D1(%rip)
L4:
  mov    D1(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ra_conf_mtu(int newvalue) {
  static int value = 0;
  if (newvalue >= 1280 && newvalue <= 65535)
    value = newvalue;
  return value;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ra_conf_mtu>:
  endbr64
  lea    -0x500(%rdi),%eax
  cmp    $0xfaff,%eax
  ja     L6
  mov    %edi,D1(%rip)
L6:
  mov    D1(%rip),%eax
  ret
```

assistant: ```c
int ra_conf_mtu(int newvalue) {
  static int value = 0;
  if (newvalue >= 1280 && newvalue <= 65535)
    value = newvalue;
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ra_conf_mtu>:
  endbr64
  lea    -0x500(%rdi),%eax
  cmp    $0xfaff,%eax
  jbe    L4
  mov    D16(%rip),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edi,D10(%rip)
  mov    %edi,%eax
  ret
```

assistant: ```c
int ra_conf_mtu(int newvalue) {
  static int value = 0;
  if (newvalue >= 1280 && newvalue <= 65535)
    value = newvalue;
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ra_conf_mtu>:
  endbr64
  lea    -0x500(%rdi),%eax
  cmp    $0xfaff,%eax
  jbe    L2
  mov    D7(%rip),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %edi,D11(%rip)
  mov    %edi,%eax
  ret
```

assistant: ```c
int ra_conf_mtu(int newvalue) {
  static int value = 0;
  if (newvalue >= 1280 && newvalue <= 65535)
    value = newvalue;
  return value;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strcopy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
L9:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strcopy(char *s, char *t) {
  while ((*s++ = *t++) != '\0')
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcopy>:
  endbr64
  mov    $0x0,%eax
L0:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L0
  ret
```

assistant: ```c
void strcopy(char *s, char *t) {
  while ((*s++ = *t++) != '\0')
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strcopy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L1:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L1
  ret
```

assistant: ```c
void strcopy(char *s, char *t) {
  while ((*s++ = *t++) != '\0')
    ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strcopy>:
  endbr64
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L8:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  test   %dl,%dl
  jne    L8
  ret
```

assistant: ```c
void strcopy(char *s, char *t) {
  while ((*s++ = *t++) != '\0')
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L23
L42:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  jmp    L1
L48:
  subl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L25
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L48
L25:
  subl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    %eax,-0x4(%rbp)
L23:
  cmpl   $0x1,-0x8(%rbp)
  jg     L42
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x && __VERIFIER_nondet_int()) {
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  cmp    $0x1,%ebp
  jg     L20
L14:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L42:
  mov    %eax,%ebx
L28:
  sub    $0x2,%ebp
  sub    %ebp,%ebx
  cmp    $0x1,%ebp
  jle    L14
L20:
  lea    -0x1(%rbp),%eax
  add    %eax,%ebx
  cmp    %eax,%ebx
  jl     L28
L6:
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  je     L28
  lea    -0x1(%rbx),%eax
  cmp    %ebx,%ebp
  jg     L42
  mov    %eax,%ebx
  jmp    L6
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x && __VERIFIER_nondet_int()) {
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x1,%ebp
  jle    L26
  mov    %eax,%ebx
  nopl   0x0(%rax)
L22:
  lea    -0x1(%rbp),%eax
  add    %eax,%ebx
  cmp    %eax,%ebx
  jge    L32
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L19:
  lea    -0x1(%rbx),%eax
  cmp    %ebx,%ebp
  mov    %eax,%ebx
  jg     L36
L32:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L19
L36:
  sub    $0x2,%ebp
  sub    %ebp,%ebx
  cmp    $0x1,%ebp
  jg     L22
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x && __VERIFIER_nondet_int()) {
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  sub    $0x8,%rsp
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  cmp    $0x1,%ebp
  jle    L19
  mov    %eax,%ebx
  nopl   0x0(%rax)
L59:
  lea    -0x1(%rbp),%eax
  add    %eax,%ebx
  cmp    %ebx,%eax
  jle    L17
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L33:
  lea    -0x1(%rbx),%eax
  cmp    %ebx,%ebp
  mov    %eax,%ebx
  jg     L32
L17:
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  test   %eax,%eax
  jne    L33
L32:
  sub    $0x2,%ebp
  sub    %ebp,%ebx
  cmp    $0x1,%ebp
  jg     L59
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int x = __VERIFIER_nondet_int();
  int y = __VERIFIER_nondet_int();
  while (x >= 2) {
    x--;
    y = y + x;
    while (y >= x && __VERIFIER_nondet_int()) {
      y--;
    }
    x--;
    y = y - x;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<AppendPrefix_CopyToTheLeft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  neg    %rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *AppendPrefix_CopyToTheLeft(const char *szPrefix, char *szOriginal) {
  int iPreStrSize = strlen(szPrefix);
  char *szDest = szOriginal - iPreStrSize;
  memcpy((void *)szDest, szPrefix, iPreStrSize);
  return szDest;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<AppendPrefix_CopyToTheLeft>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  call   <strlen@plt>
  movslq %eax,%rdx
  sub    %rdx,%rbx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *AppendPrefix_CopyToTheLeft(const char *szPrefix, char *szOriginal) {
  int iPreStrSize = strlen(szPrefix);
  char *szDest = szOriginal - iPreStrSize;
  memcpy((void *)szDest, szPrefix, iPreStrSize);
  return szDest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AppendPrefix_CopyToTheLeft>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  movslq %eax,%rdx
  sub    %rdx,%rbx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *AppendPrefix_CopyToTheLeft(const char *szPrefix, char *szOriginal) {
  int iPreStrSize = strlen(szPrefix);
  char *szDest = szOriginal - iPreStrSize;
  memcpy((void *)szDest, szPrefix, iPreStrSize);
  return szDest;
}
```
user: What is the c source code of the assembly code below?

```asm
<AppendPrefix_CopyToTheLeft>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  movslq %eax,%rdx
  sub    %rdx,%rbx
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *AppendPrefix_CopyToTheLeft(const char *szPrefix, char *szOriginal) {
  int iPreStrSize = strlen(szPrefix);
  char *szDest = szOriginal - iPreStrSize;
  memcpy((void *)szDest, szPrefix, iPreStrSize);
  return szDest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_cntwrd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L23:
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L54:
  movl   $0x1,-0x4(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  jmp    L14
L51:
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L54
  cmpl   $0x1,-0x4(%rbp)
  jne    L46
  addl   $0x1,-0x8(%rbp)
L46:
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L23
  mov    -0x8(%rbp),%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int ft_cntwrd(char const *s, char c) {
  unsigned int i;
  int w;
  int m;
  w = 0;
  i = 0;
  while (s[i] != '\0') {
    m = 0;
    while (s[i] != c) {
      m = 1;
      if (s[i] == '\0')
        return (w + 1);
      i++;
    }
    if (m == 1)
      w++;
    i++;
  }
  return (w);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_cntwrd>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%eax
  cmpb   $0x0,(%rdi)
  je     L51
L42:
  mov    %eax,%edx
  movzbl (%rdi,%rdx,1),%edx
  cmp    %dl,%sil
  je     L7
L40:
  test   %dl,%dl
  je     L2
  add    $0x1,%eax
  mov    %eax,%edx
  movzbl (%rdi,%rdx,1),%edx
  cmp    %sil,%dl
  jne    L40
  add    $0x1,%ecx
L7:
  add    $0x1,%eax
  mov    %eax,%edx
  cmpb   $0x0,(%rdi,%rdx,1)
  jne    L42
  jmp    L51
L2:
  add    $0x1,%ecx
L51:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int ft_cntwrd(char const *s, char c) {
  unsigned int i;
  int w;
  int m;
  w = 0;
  i = 0;
  while (s[i] != '\0') {
    m = 0;
    while (s[i] != c) {
      m = 1;
      if (s[i] == '\0')
        return (w + 1);
      i++;
    }
    if (m == 1)
      w++;
    i++;
  }
  return (w);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ft_cntwrd>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  xor    %eax,%eax
  test   %dl,%dl
  je     L13
L6:
  cmp    %dl,%sil
  je     L55
  nopl   (%rax)
L28:
  lea    0x1(%rax),%edx
  mov    %rdx,%rax
  movzbl (%rdi,%rdx,1),%edx
  cmp    %sil,%dl
  je     L37
  test   %dl,%dl
  jne    L28
  add    $0x1,%r8d
L13:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  add    $0x1,%r8d
L55:
  lea    0x1(%rax),%edx
  mov    %rdx,%rax
  movzbl (%rdi,%rdx,1),%edx
  test   %dl,%dl
  jne    L6
  jmp    L13
```

assistant: ```c
int ft_cntwrd(char const *s, char c) {
  unsigned int i;
  int w;
  int m;
  w = 0;
  i = 0;
  while (s[i] != '\0') {
    m = 0;
    while (s[i] != c) {
      m = 1;
      if (s[i] == '\0')
        return (w + 1);
      i++;
    }
    if (m == 1)
      w++;
    i++;
  }
  return (w);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_cntwrd>:
  endbr64
  movzbl (%rdi),%edx
  xor    %r8d,%r8d
  xor    %eax,%eax
  test   %dl,%dl
  je     L37
L57:
  cmp    %dl,%sil
  je     L41
  nopl   (%rax)
L29:
  lea    0x1(%rax),%edx
  mov    %rdx,%rax
  movzbl (%rdi,%rdx,1),%edx
  cmp    %sil,%dl
  je     L35
  test   %dl,%dl
  jne    L29
  add    $0x1,%r8d
L37:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r8d
L41:
  lea    0x1(%rax),%edx
  mov    %rdx,%rax
  movzbl (%rdi,%rdx,1),%edx
  test   %dl,%dl
  jne    L57
  jmp    L37
```

assistant: ```c
int ft_cntwrd(char const *s, char c) {
  unsigned int i;
  int w;
  int m;
  w = 0;
  i = 0;
  while (s[i] != '\0') {
    m = 0;
    while (s[i] != c) {
      m = 1;
      if (s[i] == '\0')
        return (w + 1);
      i++;
    }
    if (m == 1)
      w++;
    i++;
  }
  return (w);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<set_co_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_cf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <set_of@plt>
  cmpl   $0x0,-0x4(%rbp)
  jne    L1
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <wait@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void set_co_mul(int carry) {
  set_cf(carry);
  set_of(carry);
  if (!carry)
    wait(1, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_co_mul>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <set_cf@plt>
  mov    %ebx,%edi
  call   <set_of@plt>
  test   %ebx,%ebx
  je     L18
L17:
  pop    %rbx
  ret
L18:
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <wait@plt>
  jmp    L17
```

assistant: ```c
void set_co_mul(int carry) {
  set_cf(carry);
  set_of(carry);
  if (!carry)
    wait(1, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<set_co_mul>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <set_cf@plt>
  mov    %ebx,%edi
  call   <set_of@plt>
  test   %ebx,%ebx
  je     L6
  pop    %rbx
  ret
  nopl   0x0(%rax)
L6:
  xor    %esi,%esi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1090 <wait@plt>
```

assistant: ```c
void set_co_mul(int carry) {
  set_cf(carry);
  set_of(carry);
  if (!carry)
    wait(1, 0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<set_co_mul>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <set_cf@plt>
  mov    %ebx,%edi
  call   <set_of@plt>
  test   %ebx,%ebx
  je     L5
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  xor    %esi,%esi
  mov    $0x1,%edi
  pop    %rbx
  jmp    1090 <wait@plt>
```

assistant: ```c
void set_co_mul(int carry) {
  set_cf(carry);
  set_of(carry);
  if (!carry)
    wait(1, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rotate1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L9
  mov    -0x20(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L52
  cmpl   $0x0,-0x20(%rbp)
  jns    L90
  mov    -0x1c(%rbp),%eax
  add    %eax,-0x20(%rbp)
L90:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L68
  movl   $0x0,-0xc(%rbp)
  jmp    L63
L3:
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L63:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L3
  jmp    L23
L0:
  mov    -0xc(%rbp),%eax
  sub    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L23:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L100
L9:
  nop
  jmp    L100
L52:
  nop
  jmp    L100
L68:
  nop
L100:
  leave
  ret
```

assistant: ```c
void rotate1(int nums[], int n, int k) {
  int i;
  int *nums_dup;
  if (n <= 1)
    return;
  k %= n;
  if (k == 0)
    return;
  if (k < 0)
    k += n;
  nums_dup = (int *)malloc(sizeof(int) * n);
  if (nums_dup == NULL)
    return;
  for (i = 0; i < k; ++i)
    nums_dup[i] = nums[n - k + i];
  for (; i < n; ++i)
    nums_dup[i] = nums[i - k];
  memcpy(nums, nums_dup, sizeof(int) * n);
  free(nums_dup);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rotate1>:
  endbr64
  cmp    $0x1,%esi
  jle    L65
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%eax
  cltd
  idiv   %esi
  mov    %edx,%ebp
  test   %edx,%edx
  je     L36
  lea    (%rdx,%rsi,1),%eax
  cmovs  %eax,%ebp
  movslq %esi,%r15
  lea    0x0(,%rsi,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L36
  test   %ebp,%ebp
  jle    L6
  lea    -0x1(%rbp),%edx
  lea    0x4(%rax,%rdx,4),%rsi
  movslq %ebp,%rdx
  neg    %rdx
  shl    $0x2,%rdx
  sub    %rax,%rdx
  lea    (%rdx,%r15,4),%rcx
  add    %r13,%rcx
L37:
  mov    (%rcx,%rax,1),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L37
  cmp    %ebx,%ebp
  jge    L40
  mov    %ebp,%edx
L34:
  movslq %edx,%rax
  lea    (%r12,%rax,4),%rax
  movslq %ebp,%rbp
  neg    %rbp
  lea    0x0(%r13,%rbp,4),%rsi
  sub    %r12,%rsi
L70:
  mov    (%rsi,%rax,1),%ecx
  mov    %ecx,(%rax)
  add    $0x1,%edx
  add    $0x4,%rax
  cmp    %edx,%ebx
  jg     L70
L40:
  mov    %r14d,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r12,%rdi
  call   <free@plt>
L36:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    $0x0,%edx
  jmp    L34
L65:
  ret
```

assistant: ```c
void rotate1(int nums[], int n, int k) {
  int i;
  int *nums_dup;
  if (n <= 1)
    return;
  k %= n;
  if (k == 0)
    return;
  if (k < 0)
    k += n;
  nums_dup = (int *)malloc(sizeof(int) * n);
  if (nums_dup == NULL)
    return;
  for (i = 0; i < k; ++i)
    nums_dup[i] = nums[n - k + i];
  for (; i < n; ++i)
    nums_dup[i] = nums[i - k];
  memcpy(nums, nums_dup, sizeof(int) * n);
  free(nums_dup);
}
```
user: What is the c source code of the assembly code below:

```asm
<rotate1>:
  endbr64
  cmp    $0x1,%esi
  jle    L43
  mov    %edx,%eax
  push   %r14
  cltd
  push   %r13
  idiv   %esi
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  test   %edx,%edx
  je     L2
  lea    0x0(,%rsi,4),%r14d
  lea    (%rdx,%rsi,1),%ebp
  mov    %rdi,%r12
  mov    %r14d,%edi
  cmovns %edx,%ebp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L2
  test   %ebp,%ebp
  jle    L45
  lea    -0x1(%rbp),%edx
  lea    0x4(%rax,%rdx,4),%rsi
  mov    %ebx,%edx
  sub    %ebp,%edx
  movslq %edx,%rdx
  lea    (%r12,%rdx,4),%rdx
  sub    %rax,%rdx
  nopw   0x0(%rax,%rax,1)
L71:
  mov    (%rdx,%rax,1),%ecx
  add    $0x4,%rax
  mov    %ecx,-0x4(%rax)
  cmp    %rax,%rsi
  jne    L71
  mov    %ebp,%ecx
  cmp    %ebx,%ebp
  jge    L26
L24:
  movslq %ebp,%rbp
  movslq %ecx,%rax
  neg    %rbp
  lea    0x0(%r13,%rax,4),%rax
  lea    (%r12,%rbp,4),%rsi
  sub    %r13,%rsi
  nopw   0x0(%rax,%rax,1)
L30:
  mov    (%rsi,%rax,1),%edx
  add    $0x1,%ecx
  add    $0x4,%rax
  mov    %edx,-0x4(%rax)
  cmp    %ecx,%ebx
  jg     L30
L26:
  mov    %r12,%rdi
  mov    %r14d,%edx
  mov    %r13,%rsi
  call   <memcpy@plt>
  pop    %rbx
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <free@plt>
  nop
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L43:
  ret
  nopl   0x0(%rax)
L45:
  xor    %ecx,%ecx
  jmp    L24
```

assistant: ```c
void rotate1(int nums[], int n, int k) {
  int i;
  int *nums_dup;
  if (n <= 1)
    return;
  k %= n;
  if (k == 0)
    return;
  if (k < 0)
    k += n;
  nums_dup = (int *)malloc(sizeof(int) * n);
  if (nums_dup == NULL)
    return;
  for (i = 0; i < k; ++i)
    nums_dup[i] = nums[n - k + i];
  for (; i < n; ++i)
    nums_dup[i] = nums[i - k];
  memcpy(nums, nums_dup, sizeof(int) * n);
  free(nums_dup);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maxof2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L11
  mov    -0x4(%rbp),%eax
  jmp    L9
L11:
  mov    -0x8(%rbp),%eax
L9:
  pop    %rbp
  ret
```

assistant: ```c
int maxof2(int x, int y) {
  if (x > y)
    return x;
  return y;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<maxof2>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int maxof2(int x, int y) {
  if (x > y)
    return x;
  return y;
}
```