ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<qromb>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  cvtsd2ss %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm1
  push   %r14
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  movq   %xmm0,%r15
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%eax
  movsd  %xmm1,0x8(%rsp)
  lea    0x74(%rsp),%r14
  movl   $0x3f800000,0x84(%rsp)
  lea    0x14(%rsp),%r12
  lea    0x1c(%rsp),%rbp
  call   <trapzd@plt>
  movsd  0x8(%rsp),%xmm1
  movss  %xmm0,0x24(%rsp)
  jmp    L4
  cs nopw 0x0(%rax,%rax,1)
L44:
  mov    %r13d,%esi
  movq   %r15,%xmm0
  mov    %rbx,%rdi
  mov    $0x2,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <trapzd@plt>
  cmp    $0x4,%r13d
  movsd  0x8(%rsp),%xmm1
  movss  %xmm0,0x14(%r12)
  jle    L18
  pxor   %xmm0,%xmm0
  lea    0x18(%rsp),%rcx
  mov    %rbp,%r8
  mov    %r12,%rsi
  mov    $0x5,%edx
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <polint@plt>
  movss  0x18(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm0
  andps  D3(%rip),%xmm0
  movaps %xmm3,%xmm2
  andps  D3(%rip),%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  mulsd  D13(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L30
  movss  0x14(%r12),%xmm0
  movsd  0x8(%rsp),%xmm1
L18:
  add    $0x4,%r14
  add    $0x4,%r12
L4:
  movss  %xmm0,0x14(%r12)
  movss  D24(%rip),%xmm0
  add    $0x1,%r13d
  mulss  0x10(%r14),%xmm0
  movss  %xmm0,0x14(%r14)
  cmp    $0x15,%r13d
  jne    L44
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
L30:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0xe8,%rsp
  movaps %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type: dword[4]
name: unpack_data
arguments: tag: D13
type: byte[8]
name: unpack_data
arguments: tag: D24
type: f32
name: unpack_data
arguments: tag: D2
type: string

tool: {"D3": [0x7fffffff,0x00000000,0x00000000,0x00000000]}

tool: {"D13": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: D24: 0.25

tool: D2: Too many steps in routine QROMB

assistant: ```c
float qromb(func, a, b)
float a, b;
float (*func)();
{
  float ss, dss, trapzd();
  float s[20 + 1 + 1], h[20 + 1 + 1];
  int j;
  void polint(), nrerror();
  h[1] = 1.0;
  for (j = 1; j <= 20; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 0.5e-5 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine QROMB");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<qromb>:
  endbr64
  push   %r15
  mov    $0x1,%esi
  cvtsd2ss %xmm0,%xmm0
  cvtsd2ss %xmm1,%xmm1
  push   %r14
  cvtss2sd %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm0
  movq   %xmm0,%r15
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    $0x2,%eax
  movsd  %xmm1,0x8(%rsp)
  lea    0x74(%rsp),%r14
  movl   $0x3f800000,0x84(%rsp)
  lea    0x14(%rsp),%rbx
  lea    0x1c(%rsp),%r12
  call   <trapzd@plt>
  movsd  0x8(%rsp),%xmm1
  movss  %xmm0,0x24(%rsp)
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L35:
  mov    %r13d,%esi
  movq   %r15,%xmm0
  mov    %rbp,%rdi
  mov    $0x2,%eax
  movsd  %xmm1,0x8(%rsp)
  call   <trapzd@plt>
  cmp    $0x4,%r13d
  movsd  0x8(%rsp),%xmm1
  movss  %xmm0,0x14(%rbx)
  jle    L24
  pxor   %xmm0,%xmm0
  lea    0x18(%rsp),%rcx
  mov    %r12,%r8
  mov    %rbx,%rsi
  mov    $0x5,%edx
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <polint@plt>
  movss  0x18(%rsp),%xmm3
  movss  0x1c(%rsp),%xmm0
  andps  D35(%rip),%xmm0
  movsd  0x8(%rsp),%xmm1
  movaps %xmm3,%xmm2
  andps  D35(%rip),%xmm2
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm2,%xmm2
  mulsd  D41(%rip),%xmm2
  comisd %xmm0,%xmm2
  ja     L21
L24:
  add    $0x4,%r14
  add    $0x4,%rbx
L31:
  movss  0x10(%rbx),%xmm0
  add    $0x1,%r13d
  movss  %xmm0,0x14(%rbx)
  movss  D28(%rip),%xmm0
  mulss  0x10(%r14),%xmm0
  movss  %xmm0,0x14(%r14)
  cmp    $0x15,%r13d
  jne    L35
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <nrerror@plt>
L21:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0xe8,%rsp
  movaps %xmm3,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D35
type_guessed: dword[4]
name: disassemble_data
arguments: tag: D41
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D28
type_guessed: f32
name: disassemble_data
arguments: tag: D13
type_guessed: string

tool: {"D35": [0x7fffffff,0x00000000,0x00000000,0x00000000]}

tool: {"D41": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xd4,0x3e]}

tool: D28: 0.25

tool: D13: Too many steps in routine QROMB

assistant: ```c
float qromb(func, a, b)
float a, b;
float (*func)();
{
  float ss, dss, trapzd();
  float s[20 + 1 + 1], h[20 + 1 + 1];
  int j;
  void polint(), nrerror();
  h[1] = 1.0;
  for (j = 1; j <= 20; j++) {
    s[j] = trapzd(func, a, b, j);
    if (j >= 5) {
      polint(&h[j - 5], &s[j - 5], 5, 0.0, &ss, &dss);
      if (fabs(dss) < 0.5e-5 * fabs(ss))
        return ss;
    }
    s[j + 1] = s[j];
    h[j + 1] = 0.25 * h[j];
  }
  nrerror("Too many steps in routine QROMB");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x313ee,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
data_type: string

tool: D4: __STDC_VERSION__ = %ld 


assistant: ```c
int main(void) {
  printf("__STDC_VERSION__ = %ld \n", 201710L);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x313ee,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_infered: string

tool: D3: __STDC_VERSION__ = %ld 


assistant: ```c
int main(void) {
  printf("__STDC_VERSION__ = %ld \n", 201710L);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x313ee,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: __STDC_VERSION__ = %ld 


assistant: ```c
int main(void) {
  printf("__STDC_VERSION__ = %ld \n", 201710L);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x313ee,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: __STDC_VERSION__ = %ld 


assistant: ```c
int main(void) {
  printf("__STDC_VERSION__ = %ld \n", 201710L);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<modp_uitoa10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L0:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strreverse@plt>
  nop
  leave
  ret
```

assistant: ```c
void modp_uitoa10(uint32_t value, char *str) {
  char *wstr = str;
  do
    *wstr++ = (char)(48 + (value % 10));
  while (value /= 10);
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<modp_uitoa10>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%r8
  mov    %rsi,%rdx
L7:
  mov    %rdx,%rsi
  add    $0x1,%rdx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rdx)
  mov    %eax,%edi
  test   %eax,%eax
  jne    L7
  movb   $0x0,(%rdx)
  mov    %r8,%rdi
  call   <strreverse@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void modp_uitoa10(uint32_t value, char *str) {
  char *wstr = str;
  do
    *wstr++ = (char)(48 + (value % 10));
  while (value /= 10);
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<modp_uitoa10>:
  endbr64
  mov    %rsi,%r8
  mov    %rsi,%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rdx)
  mov    %eax,%edi
  test   %eax,%eax
  jne    L1
  movb   $0x0,(%rdx)
  mov    %r8,%rdi
  jmp    1050 <strreverse@plt>
```

assistant: ```c
void modp_uitoa10(uint32_t value, char *str) {
  char *wstr = str;
  do
    *wstr++ = (char)(48 + (value % 10));
  while (value /= 10);
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<modp_uitoa10>:
  endbr64
  mov    %rsi,%r8
  mov    %rsi,%rdx
  nopw   0x0(%rax,%rax,1)
L1:
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %rdx,%rsi
  add    $0x1,%rdx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rdx)
  mov    %eax,%edi
  test   %eax,%eax
  jne    L1
  movb   $0x0,(%rdx)
  mov    %r8,%rdi
  jmp    1050 <strreverse@plt>
```

assistant: ```c
void modp_uitoa10(uint32_t value, char *str) {
  char *wstr = str;
  do
    *wstr++ = (char)(48 + (value % 10));
  while (value /= 10);
  *wstr = '\0';
  strreverse(str, wstr - 1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_no_inversions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  movl   $0x5,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <count@plt>
  test   %rax,%rax
  jne    L16
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <count_opt@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x1,%eax
  jmp    L11
L16:
  mov    $0x0,%eax
L11:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
int test_no_inversions() {
  int array[] = {1, 2, 3, 4, 5};
  return 0 == count(array, 5) && 0 == count_opt(array, 5);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_no_inversions>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <count@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L27
L15:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L27:
  mov    %rsp,%rdi
  mov    $0x5,%esi
  call   <count_opt@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L15
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_no_inversions() {
  int array[] = {1, 2, 3, 4, 5};
  return 0 == count(array, 5) && 0 == count_opt(array, 5);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_no_inversions>:
  endbr64
  push   %rbp
  mov    $0x5,%esi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x200000001,%rax
  mov    %rsp,%rbp
  movl   $0x5,0x10(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x8(%rsp)
  call   <count@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L20
L22:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <count_opt@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L22
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_no_inversions() {
  int array[] = {1, 2, 3, 4, 5};
  return 0 == count(array, 5) && 0 == count_opt(array, 5);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_no_inversions>:
  endbr64
  push   %rbp
  mov    $0x5,%esi
  sub    $0x20,%rsp
  movdqa D6(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x5,0x10(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  call   <count@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  je     L11
L10:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x20,%rsp
  pop    %rbp
  ret
  nopl   (%rax)
L11:
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <count_opt@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  jmp    L10
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: byte[16]

tool: {"D6": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
int test_no_inversions() {
  int array[] = {1, 2, 3, 4, 5};
  return 0 == count(array, 5) && 0 == count_opt(array, 5);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L31:
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L24:
  addl   $0x1,-0x4(%rbp)
L15:
  cmpl   $0x9,-0x4(%rbp)
  jbe    L24
  addl   $0x1,-0x8(%rbp)
L9:
  cmpl   $0xffffffe,-0x8(%rbp)
  jbe    L31
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 0;
  while (x < 0x0fffffff) {
    y = 0;
    while (y < 10) {
      y++;
    }
    x++;
  }
  __VERIFIER_assert(!(x % 2));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xfffffff,%eax
L3:
  sub    $0x1,%eax
  jne    L3
  mov    $0x0,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 0;
  while (x < 0x0fffffff) {
    y = 0;
    while (y < 10) {
      y++;
    }
    x++;
  }
  __VERIFIER_assert(!(x % 2));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 0;
  while (x < 0x0fffffff) {
    y = 0;
    while (y < 10) {
      y++;
    }
    x++;
  }
  __VERIFIER_assert(!(x % 2));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 0;
  while (x < 0x0fffffff) {
    y = 0;
    while (y < 10) {
      y++;
    }
    x++;
  }
  __VERIFIER_assert(!(x % 2));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_cpuconfig>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <implver@plt>
  lea    D26(%rip),%rdi
  lea    0x4(%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <implver@plt>
  cmp    $0x1,%eax
  je     L8
  cmp    $0x2,%eax
  je     L39
  test   %eax,%eax
  je     L32
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L8:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D97(%rip),%rdi
  call   <puts@plt>
  lea    D45(%rip),%rdi
L30:
  call   <puts@plt>
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D78(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <puts@plt>
  nopl   0x0(%rax)
L32:
  lea    D18(%rip),%rdi
  call   <puts@plt>
  lea    D97(%rip),%rdi
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    D75(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  add    $0x8,%rsp
  jmp    1080 <puts@plt>
  nopl   0x0(%rax)
L39:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D83(%rip),%rdi
  jmp    L30
```

tool_calls: name: read_data
arguments: tag: D26
datatype: string
name: read_data
arguments: tag: D18
datatype: string
name: read_data
arguments: tag: D97
datatype: string
name: read_data
arguments: tag: D45
datatype: string
name: read_data
arguments: tag: D42
datatype: string
name: read_data
arguments: tag: D78
datatype: string
name: read_data
arguments: tag: D8
datatype: string
name: read_data
arguments: tag: D54
datatype: string
name: read_data
arguments: tag: D75
datatype: string
name: read_data
arguments: tag: D21
datatype: string
name: read_data
arguments: tag: D39
datatype: string
name: read_data
arguments: tag: D83
datatype: string

tool: D26: #define EV%d


tool: D18: #define L1_DATA_SIZE 16384

tool: D97: #define L1_DATA_LINESIZE 32

tool: D45: #define L2_SIZE 2097152

tool: D42: #define L2_LINESIZE 64

tool: D78: #define DTB_DEFAULT_ENTRIES 64

tool: D8: #define DTB_SIZE 8192

tool: D54: #define L2_LINESIZE 32

tool: D75: #define DTB_DEFAULT_ENTRIES 32

tool: D21: #define L1_DATA_SIZE 32768

tool: D39: #define L1_DATA_LINESIZE 64

tool: D83: #define L2_SIZE 4194304

assistant: ```c
void get_cpuconfig(void) {
  printf("#define EV%d\n", implver() + 4);
  switch (implver()) {
  case 0:
    printf("#define L1_DATA_SIZE 16384\n");
    printf("#define L1_DATA_LINESIZE 32\n");
    printf("#define L2_SIZE 2097152\n");
    printf("#define L2_LINESIZE 32\n");
    printf("#define DTB_DEFAULT_ENTRIES 32\n");
    printf("#define DTB_SIZE 8192\n");
    break;
  case 1:
    printf("#define L1_DATA_SIZE 16384\n");
    printf("#define L1_DATA_LINESIZE 32\n");
    printf("#define L2_SIZE 2097152\n");
    printf("#define L2_LINESIZE 64\n");
    printf("#define DTB_DEFAULT_ENTRIES 64\n");
    printf("#define DTB_SIZE 8192\n");
    break;
  case 2:
    printf("#define L1_DATA_SIZE 32768\n");
    printf("#define L1_DATA_LINESIZE 64\n");
    printf("#define L2_SIZE 4194304\n");
    printf("#define L2_LINESIZE 64\n");
    printf("#define DTB_DEFAULT_ENTRIES 64\n");
    printf("#define DTB_SIZE 8192\n");
    break;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_config_file_name>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%r12
  lea    D29(%rip),%rdi
  call   <getenv@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L60
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    D7(%rip),%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebx
  test   %r13,%r13
  je     L11
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebx
L11:
  test   %r12,%r12
  je     L22
  mov    %r12,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
L22:
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L23
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D12(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    $0x1fd,%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
  test   %r13,%r13
  je     L74
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    $0x1fd,%esi
  mov    %rbx,%rdi
  call   <mkdir@plt>
L74:
  lea    D47(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  test   %r12,%r12
  je     L73
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
L73:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L60:
  lea    D43(%rip),%rdi
  call   <print_error@plt>
  mov    %rbp,%rbx
  jmp    L73
L23:
  lea    D53(%rip),%rdi
  call   <print_error@plt>
  jmp    L73
```

tool_calls: name: disassemble_data
arguments: tag: D29
datatype: string
name: disassemble_data
arguments: tag: D7
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D47
datatype: string
name: disassemble_data
arguments: tag: D43
datatype: string
name: disassemble_data
arguments: tag: D53
datatype: string

tool: D29: HOME

tool: D7: /.clamz/

tool: D12: /.clamz

tool: D47: /

tool: D43: $HOME not defined

tool: D53: Out of memory

assistant: ```c
char *get_config_file_name(const char *subdir, const char *base, const char *suffix) {
  char *home = getenv("HOME");
  char *s;
  int n;
  if (!home) {
    print_error("$HOME not defined");
    return NULL;
  }
  n = strlen(home) + strlen("/.clamz/") + strlen(base) + 1;
  if (subdir)
    n += strlen(subdir) + 1;
  if (suffix)
    n += strlen(suffix);
  s = malloc(n * sizeof(char));
  if (!s) {
    print_error("Out of memory");
    return NULL;
  }
  strcpy(s, home);
  strcat(s, "/.clamz");
  mkdir(s, 0775);
  if (subdir) {
    strcat(s, "/");
    strcat(s, subdir);
    mkdir(s, 0775);
  }
  strcat(s, "/");
  strcat(s, base);
  if (suffix)
    strcat(s, suffix);
  return s;
}
```