user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  movw   $0x1,-0x64(%rbp)
  movw   $0x0,-0x62(%rbp)
  filds  -0x62(%rbp)
  filds  -0x64(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D96(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movl   $0x1,-0x60(%rbp)
  mov    -0x60(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %eax,-0x5c(%rbp)
  fildl  -0x5c(%rbp)
  fildl  -0x60(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movq   $0x1,-0x50(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x50(%rbp),%xmm1
  movsd  D107(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x48(%rbp)
  fildll -0x48(%rbp)
  fildll -0x50(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movq   $0x1,-0x40(%rbp)
  pxor   %xmm1,%xmm1
  cvtsi2sdq -0x40(%rbp),%xmm1
  movsd  D84(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x38(%rbp)
  fildll -0x38(%rbp)
  fildll -0x40(%rbp)
  fxch   %st(1)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movss  D109(%rip),%xmm0
  movss  %xmm0,-0x58(%rbp)
  movss  -0x58(%rbp),%xmm0
  movss  D67(%rip),%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x54(%rbp)
  flds   -0x58(%rbp)
  flds   -0x54(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D88(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  movsd  D49(%rip),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  D58(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  fldl   -0x30(%rbp)
  fldl   -0x28(%rbp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  lea    D124(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  fldt   0xdef(%rip)        # 20d0 <_fini+0xda8>
  fstpt  -0x20(%rbp)
  movsd  -0x30(%rbp),%xmm0
  movsd  D58(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x78(%rbp)
  fldl   -0x78(%rbp)
  fstpt  -0x10(%rbp)
  push   -0x8(%rbp)
  push   -0x10(%rbp)
  push   -0x18(%rbp)
  push   -0x20(%rbp)
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D96
type: string
name: retrieve_data
arguments: data_label: D75
type: string
name: retrieve_data
arguments: data_label: D107
type: f64
name: retrieve_data
arguments: data_label: D50
type: string
name: retrieve_data
arguments: data_label: D84
type: f64
name: retrieve_data
arguments: data_label: D4
type: string
name: retrieve_data
arguments: data_label: D109
type: f32
name: retrieve_data
arguments: data_label: D67
type: f32
name: retrieve_data
arguments: data_label: D88
type: string
name: retrieve_data
arguments: data_label: D49
type: f64
name: retrieve_data
arguments: data_label: D58
type: f64
name: retrieve_data
arguments: data_label: D124
type: string
name: retrieve_data
arguments: data_label: D27
type: string

tool: D96: Short: %i / 2 = %i


tool: D75: Int: %i / 4 = %i


tool: D107: 0.5

tool: D50: Long: %li + 0.5 = %li


tool: D84: 0.99

tool: D4: Long long: %lli + 0.99 = %lli


tool: D109: 1e-06

tool: D67: 2

tool: D88: Float: %f / 2 = %f


tool: D49: 3e-06

tool: D58: 4

tool: D124: Double: %f / 4 = %f


tool: D27: Long double: %Lf / 4 = %Lf


assistant: ```c
int main() {
  short shr = 1;
  short shr2 = 1 / 2;
  printf("Short: %i / 2 = %i\n", shr, shr2);
  int in = 1;
  int in2 = in / 4;
  printf("Int: %i / 4 = %i\n", in, in2);
  long lg = 1;
  long lg2 = lg + 0.5;
  printf("Long: %li + 0.5 = %li\n", lg, lg2);
  long long llg = 1;
  long long llg2 = llg + 0.99;
  printf("Long long: %lli + 0.99 = %lli\n", llg, llg2);
  float fl = 0.000001;
  float fl2 = fl / 2.0;
  printf("Float: %f / 2 = %f\n", fl, fl2);
  double dl = 0.000003;
  double dl2 = dl / 4.0;
  printf("Double: %f / 4 = %f\n", dl, dl2);
  long double ldl = 0.00000000000000005;
  long double ldl2 = dl / 4.0;
  printf("Long double: %Lf / 4 = %Lf\n", ldl, ldl2);
  return 0;
}
```