ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pass_space_label>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12
L27:
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <str32_charsearch@plt>
  cmp    $0xffffffff,%eax
  jne    L11
  mov    $0x2e,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <str32_charsearch@plt>
  cmp    $0xffffffff,%eax
  jne    L66
L10:
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  mov    $0x20,%esi
  mov    %r12,%rdi
  call   <str32_charindex@plt>
  cmp    $0xffffffffffffffff,%rax
  je     L55
L61:
  add    %rax,%r12
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <str32_charsearch@plt>
  cmp    $0xffffffff,%eax
  jne    L58
  mov    %r12,%rdi
  mov    $0x20,%esi
  add    $0x1,%r12
  call   <_store_8@plt>
  jmp    L10
L74:
  add    $0x1,%r12
L58:
  mov    $0x20,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <str32_charsearch@plt>
  cmp    $0xffffffff,%eax
  jne    L74
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L55:
  mov    %r12,%rdi
  call   <str32_strlen@plt>
  cmp    $0xffffffffffffffff,%rax
  jne    L61
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *pass_space_label(char *target_str) {
  while (str32_charsearch(target_str, 1, 0x20) != -1) {
    target_str++;
  }
  if (str32_charsearch(target_str, 1, 0x2E) != -1) {
    unsigned long int length_temp = str32_charindex(target_str, 0x20);
    if (length_temp == -1)
      length_temp = str32_strlen(target_str);
    if (length_temp != -1) {
      target_str += length_temp;
      if (str32_charsearch(target_str, 1, 0x20) != -1) {
        while (str32_charsearch(target_str, 1, 0x20) != -1) {
          target_str++;
        }
      } else {
        _store_8((unsigned long int)target_str, 0x20);
        target_str++;
      }
    }
  }
  return target_str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wrapc_getnameuidgid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0xffffffff,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0xffffffff,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wrapc_getnameuidgid(char *name, int *uid, int *gid) {
  *uid = -1;
  *gid = -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wrapc_getnameuidgid>:
  endbr64
  movl   $0xffffffff,(%rsi)
  movl   $0xffffffff,(%rdx)
  ret
```

assistant: ```c
void wrapc_getnameuidgid(char *name, int *uid, int *gid) {
  *uid = -1;
  *gid = -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wrapc_getnameuidgid>:
  endbr64
  movl   $0xffffffff,(%rsi)
  movl   $0xffffffff,(%rdx)
  ret
```

assistant: ```c
void wrapc_getnameuidgid(char *name, int *uid, int *gid) {
  *uid = -1;
  *gid = -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrapc_getnameuidgid>:
  endbr64
  movl   $0xffffffff,(%rsi)
  movl   $0xffffffff,(%rdx)
  ret
```

assistant: ```c
void wrapc_getnameuidgid(char *name, int *uid, int *gid) {
  *uid = -1;
  *gid = -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<softboundmpx_localeconv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <localeconv@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1000(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct lconv *softboundmpx_localeconv(void) {
  struct lconv *temp = localeconv();
  __softboundmpx_store_return_metadata(temp, temp + 1024);
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<softboundmpx_localeconv>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <localeconv@plt>
  mov    %rax,%rbx
  lea    0x1000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct lconv *softboundmpx_localeconv(void) {
  struct lconv *temp = localeconv();
  __softboundmpx_store_return_metadata(temp, temp + 1024);
  return temp;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<softboundmpx_localeconv>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <localeconv@plt>
  mov    %rax,%r12
  lea    0x1000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct lconv *softboundmpx_localeconv(void) {
  struct lconv *temp = localeconv();
  __softboundmpx_store_return_metadata(temp, temp + 1024);
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<softboundmpx_localeconv>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <localeconv@plt>
  mov    %rax,%r12
  lea    0x1000(%rax),%rsi
  mov    %rax,%rdi
  call   <__softboundmpx_store_return_metadata@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__weak__, __always___)) struct lconv *softboundmpx_localeconv(void) {
  struct lconv *temp = localeconv();
  __softboundmpx_store_return_metadata(temp, temp + 1024);
  return temp;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mini>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0xf4240,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L10
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L6
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
L6:
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L4
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mini(int *x, int n) {
  int m_x;
  int i;
  m_x = 1000000;
  for (i = 1; i <= n; i++) {
    if (x[i] < m_x)
      m_x = x[i];
  }
  return m_x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mini>:
  endbr64
  test   %esi,%esi
  jle    L24
  lea    0x4(%rdi),%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,4),%rsi
  mov    $0xf4240,%edx
L7:
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L7
L26:
  mov    %edx,%eax
  ret
L24:
  mov    $0xf4240,%edx
  jmp    L26
```

assistant: ```c
int mini(int *x, int n) {
  int m_x;
  int i;
  m_x = 1000000;
  for (i = 1; i <= n; i++) {
    if (x[i] < m_x)
      m_x = x[i];
  }
  return m_x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mini>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi),%rax
  mov    $0xf4240,%r8d
  lea    0x8(%rdi,%rdx,4),%rcx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rax),%edx
  cmp    %edx,%r8d
  cmovg  %edx,%r8d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L12
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    $0xf4240,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int mini(int *x, int n) {
  int m_x;
  int i;
  m_x = 1000000;
  for (i = 1; i <= n; i++) {
    if (x[i] < m_x)
      m_x = x[i];
  }
  return m_x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mini>:
  endbr64
  mov    %esi,%edx
  test   %esi,%esi
  jle    L31
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L69
  mov    %esi,%ecx
  movdqa D3(%rip),%xmm0
  lea    0x4(%rdi),%rax
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x14(%rdi,%rcx,1),%rcx
  nopw   0x0(%rax,%rax,1)
L23:
  movdqu (%rax),%xmm1
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm3,%xmm1
  por    %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L23
  movdqa %xmm0,%xmm2
  mov    %edx,%esi
  psrldq $0x8,%xmm2
  and    $0xfffffffc,%esi
  movdqa %xmm2,%xmm1
  lea    0x1(%rsi),%ecx
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  por    %xmm0,%xmm1
  movdqa %xmm1,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm1,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %esi,%edx
  je     L4
L34:
  movslq %ecx,%rsi
  lea    0x0(,%rsi,4),%r8
  mov    (%rdi,%rsi,4),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  lea    0x1(%rcx),%esi
  cmp    %esi,%edx
  jl     L13
  mov    0x4(%rdi,%r8,1),%esi
  cmp    %esi,%eax
  cmovg  %esi,%eax
  add    $0x2,%ecx
  cmp    %ecx,%edx
  jl     L13
  mov    0x8(%rdi,%r8,1),%edx
  cmp    %edx,%eax
  cmovg  %edx,%eax
  ret
  nopl   0x0(%rax)
L31:
  mov    $0xf4240,%eax
L13:
  ret
  xchg   %ax,%ax
L4:
  ret
L69:
  mov    $0x1,%ecx
  mov    $0xf4240,%eax
  jmp    L34
```

tool_calls: name: unpack_data
arguments: label: D3
datatype: byte[16]

tool: {"D3": [0x40,0x42,0x0f,0x00,0x40,0x42,0x0f,0x00,0x40,0x42,0x0f,0x00,0x40,0x42,0x0f,0x00]}

assistant: ```c
int mini(int *x, int n) {
  int m_x;
  int i;
  m_x = 1000000;
  for (i = 1; i <= n; i++) {
    if (x[i] < m_x)
      m_x = x[i];
  }
  return m_x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D39(%rip),%r15
  push   %r14
  push   %r13
  mov    $0x2,%r13d
  push   %r12
  lea    D30(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D21(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  lea    D56(%rip),%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  xchg   %ax,%ax
L9:
  mov    0x14(%rsp),%eax
  lea    -0x1(%r13),%r14d
  cmp    $0x63,%eax
  jbe    L58
  nopl   (%rax)
L10:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x63,%eax
  ja     L10
L58:
  lea    D15(%rip),%rdi
  cmp    %eax,0xc(%rsp)
  jl     L22
  jle    L27
  mov    %r15,%rdi
L22:
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  jmp    L9
L27:
  xor    %eax,%eax
  mov    %r14d,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D30
type_guessed: string
name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D56
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string
name: read_data
arguments: data_tag: D12
type_guessed: string

tool: D39: Your guess is too low. Please enter another number: 

tool: D30: Please only integer guesses between 0-99. Enter new number: 

tool: D21: %d

tool: D56: Please make a guess between 0-99. 

tool: D15: Your guess is too high. Please enter another number: 

tool: D12: Your guess is correct. Congratulations. It took you %d tries to guess the random number.


assistant: ```c
int main() {
  srand(time(NULL));
  int r = rand() % 100;
  int i;
  int status = 0;
  int tries = 1;
  printf("Please make a guess between 0-99. ");
  scanf("%d", &i);
  while (status != 1) {
    while (i < 0 || i > 99) {
      printf("Please only integer guesses between 0-99. Enter new number: ");
      scanf("%d", &i);
    }
    if (i > r) {
      printf("Your guess is too high. Please enter another number: ");
      scanf("%d", &i);
      tries++;
    } else if (i < r) {
      printf("Your guess is too low. Please enter another number: ");
      scanf("%d", &i);
      tries++;
    } else {
      printf("Your guess is correct. Congratulations. It took you %d tries to guess the random number.\n", tries);
      status = 1;
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rdx
  lea    D9(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <ledctl@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string

tool: D9: 0x%x

tool: D12: %x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int mask;
  sscanf(argv[1], "0x%x", &mask);
  printf("%x\n", mask);
  return ledctl(mask);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    0x8(%rsi),%rdi
  lea    D11(%rip),%rsi
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <ledctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D17
type_guessed: string

tool: D11: 0x%x

tool: D17: %x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int mask;
  sscanf(argv[1], "0x%x", &mask);
  printf("%x\n", mask);
  return ledctl(mask);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rdi
  lea    D2(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <ledctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
data_type: string
name: read_data
arguments: tag: D1
data_type: string

tool: D2: 0x%x

tool: D1: %x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int mask;
  sscanf(argv[1], "0x%x", &mask);
  printf("%x\n", mask);
  return ledctl(mask);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    0x8(%rsi),%rdi
  lea    D6(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  call   <sscanf@plt>
  mov    0x4(%rsp),%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <ledctl@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string
name: unpack_data
arguments: label: D7
data_type: string

tool: D6: 0x%x

tool: D7: %x


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned int mask;
  sscanf(argv[1], "0x%x", &mask);
  printf("%x\n", mask);
  return ledctl(mask);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<adjust>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L17:
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <siftdown@plt>
  subl   $0x1,-0xc(%rbp)
L14:
  cmpl   $0x0,-0xc(%rbp)
  jg     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void adjust(int *head, int len) {
  int n = len / 2;
  int min = 0;
  for (int i = n; i > 0; i--) {
    siftdown(head, len, i);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adjust>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L18
L11:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <siftdown@plt>
  sub    $0x1,%ebx
  test   %ebx,%ebx
  jg     L11
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void adjust(int *head, int len) {
  int n = len / 2;
  int min = 0;
  for (int i = n; i > 0; i--) {
    siftdown(head, len, i);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<adjust>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L13
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <siftdown@plt>
  sub    $0x1,%ebx
  jne    L5
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void adjust(int *head, int len) {
  int n = len / 2;
  int min = 0;
  for (int i = n; i > 0; i--) {
    siftdown(head, len, i);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<adjust>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  shr    $0x1f,%ebx
  add    %esi,%ebx
  sar    %ebx
  cmp    $0x1,%esi
  jle    L15
  mov    %rdi,%r12
  mov    %esi,%ebp
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <siftdown@plt>
  sub    $0x1,%ebx
  jne    L19
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void adjust(int *head, int len) {
  int n = len / 2;
  int min = 0;
  for (int i = n; i > 0; i--) {
    siftdown(head, len, i);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<I2CMasterBusBusy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%rax
  and    $0x40,%eax
  test   %rax,%rax
  je     L9
  mov    $0x1,%eax
  jmp    L19
L9:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
bool I2CMasterBusBusy(uint32_t ui32Base) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000004))) & 0x00000040) {
    return (1);
  } else {
    return (0);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<I2CMasterBusBusy>:
  endbr64
  mov    0x4(%rdi),%rax
  shr    $0x6,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool I2CMasterBusBusy(uint32_t ui32Base) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000004))) & 0x00000040) {
    return (1);
  } else {
    return (0);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<I2CMasterBusBusy>:
  endbr64
  mov    0x4(%rdi),%rax
  shr    $0x6,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool I2CMasterBusBusy(uint32_t ui32Base) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000004))) & 0x00000040) {
    return (1);
  } else {
    return (0);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<I2CMasterBusBusy>:
  endbr64
  mov    0x4(%rdi),%rax
  shr    $0x6,%rax
  and    $0x1,%eax
  ret
```

assistant: ```c
bool I2CMasterBusBusy(uint32_t ui32Base) {
  ;
  if ((*((volatile unsigned long *)(ui32Base + 0x00000004))) & 0x00000040) {
    return (1);
  } else {
    return (0);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<copy_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L35
L2:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L39
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L61
L39:
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L35
L61:
  movl   $0x31,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L52
L40:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L81
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L52:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L40
  jmp    L80
L81:
  nop
L80:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D15
type: string

tool: D4: ''

tool: D15: ""

assistant: ```c
void copy_name(const char *source, char *dest) {
  int i, len;
  if (!source) {
    dest[0] = '\0';
    return;
  }
  if ((0 == strcmp("''", source)) || (0 == strcmp("\"\"", source))) {
    dest[0] = '\0';
    return;
  }
  len = 50 - 1;
  for (i = 0; i < len; i++) {
    if (!source[i])
      break;
    dest[i] = source[i];
  }
  dest[i] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<copy_name>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L13
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D11(%rip),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L26
L67:
  movb   $0x0,0x0(%rbp)
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  movb   $0x0,(%rsi)
  jmp    L5
L26:
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <strcmp@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L67
L39:
  mov    %eax,%ecx
  movzbl (%rbx,%rax,1),%edx
  test   %dl,%dl
  je     L58
  mov    %dl,0x0(%rbp,%rax,1)
  lea    0x1(%rax),%ecx
  add    $0x1,%rax
  cmp    $0x31,%rax
  jne    L39
L58:
  movslq %ecx,%rcx
  movb   $0x0,0x0(%rbp,%rcx,1)
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: string
name: extract_symbolic_data
arguments: label: D5
datatype: string

tool: D11: ''

tool: D5: ""

assistant: ```c
void copy_name(const char *source, char *dest) {
  int i, len;
  if (!source) {
    dest[0] = '\0';
    return;
  }
  if ((0 == strcmp("''", source)) || (0 == strcmp("\"\"", source))) {
    dest[0] = '\0';
    return;
  }
  len = 50 - 1;
  for (i = 0; i < len; i++) {
    if (!source[i])
      break;
    dest[i] = source[i];
  }
  dest[i] = '\0';
}
```