ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xb,-0x40(%rbp)
  movl   $0xf,-0x3c(%rbp)
  movl   $0x13,-0x38(%rbp)
  movl   $0x17,-0x34(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L50
L1:
  lea    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x54(%rbp),%eax
  cltq
  mov    %rdx,-0x30(%rbp,%rax,8)
  addl   $0x1,-0x54(%rbp)
L50:
  cmpl   $0x3,-0x54(%rbp)
  jle    L1
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x48(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L9
L57:
  mov    -0x50(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x50(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rax
  mov    %rax,(%rdx)
  addq   $0x8,-0x48(%rbp)
L9:
  cmpl   $0x3,-0x50(%rbp)
  jle    L57
  movl   $0x0,-0x4c(%rbp)
  jmp    L17
L47:
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addq   $0x8,-0x48(%rbp)
L17:
  cmpl   $0x3,-0x4c(%rbp)
  jle    L47
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
type: string
name: extract_symbolic_data
arguments: label: D1
type: string

tool: D18: %d


tool: D1: ---------------

assistant: ```c
int main() {
  int **i;
  int *a1[4];
  int b1[4] = {11, 15, 19, 23};
  for (int ii = 0; ii < 4; ii++) {
    a1[ii] = &b1[ii];
  }
  i = (int **)malloc(sizeof(int *));
  for (int ii = 0; ii < 4; i++) {
    *(i + ii) = a1[ii];
  }
  for (int ii = 0; ii < 4; i++) {
    printf("%d\n", *(*(i) + 1));
    printf("%d\n", *(*(i + 1)));
    printf("---------------\n");
  }
  getchar();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xb,(%rsp)
  movl   $0xf,0x4(%rsp)
  movl   $0x13,0x8(%rsp)
  movl   $0x17,0xc(%rsp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rsp,%rdx
L5:
  mov    %rdx,(%rax)
  add    $0x8,%rax
  jmp    L5
```

assistant: ```c
int main() {
  int **i;
  int *a1[4];
  int b1[4] = {11, 15, 19, 23};
  for (int ii = 0; ii < 4; ii++) {
    a1[ii] = &b1[ii];
  }
  i = (int **)malloc(sizeof(int *));
  for (int ii = 0; ii < 4; i++) {
    *(i + ii) = a1[ii];
  }
  for (int ii = 0; ii < 4; i++) {
    printf("%d\n", *(*(i) + 1));
    printf("%d\n", *(*(i + 1)));
    printf("---------------\n");
  }
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x8,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xf0000000b,%rax
  mov    %rax,(%rsp)
  movabs $0x1700000013,%rax
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rsp,%rdx
L0:
  mov    %rdx,(%rax)
  add    $0x8,%rax
  jmp    L0
```

assistant: ```c
int main() {
  int **i;
  int *a1[4];
  int b1[4] = {11, 15, 19, 23};
  for (int ii = 0; ii < 4; ii++) {
    a1[ii] = &b1[ii];
  }
  i = (int **)malloc(sizeof(int *));
  for (int ii = 0; ii < 4; i++) {
    *(i + ii) = a1[ii];
  }
  for (int ii = 0; ii < 4; i++) {
    printf("%d\n", *(*(i) + 1));
    printf("%d\n", *(*(i + 1)));
    printf("---------------\n");
  }
  getchar();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D4(%rip),%xmm0
  mov    $0x8,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movaps %xmm0,(%rsp)
  call   <malloc@plt>
  mov    %rsp,%rdx
  nopl   0x0(%rax)
L5:
  mov    %rdx,(%rax)
  add    $0x8,%rax
  jmp    L5
```

tool_calls: name: read_data
arguments: tag: D4
data_type: byte[16]

tool: {"D4": [0x0b,0x00,0x00,0x00,0x0f,0x00,0x00,0x00,0x13,0x00,0x00,0x00,0x17,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int **i;
  int *a1[4];
  int b1[4] = {11, 15, 19, 23};
  for (int ii = 0; ii < 4; ii++) {
    a1[ii] = &b1[ii];
  }
  i = (int **)malloc(sizeof(int *));
  for (int ii = 0; ii < 4; i++) {
    *(i + ii) = a1[ii];
  }
  for (int ii = 0; ii < 4; i++) {
    printf("%d\n", *(*(i) + 1));
    printf("%d\n", *(*(i + 1)));
    printf("---------------\n");
  }
  getchar();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<locate_forward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L26
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  jae    L3
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    $0x1,%eax
  jmp    L6
L26:
  mov    -0x8(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,(%rax)
L3:
  mov    $0x0,%eax
L6:
  pop    %rbp
  ret
```

assistant: ```c
bool locate_forward(const char **needle_ptr, char *read_ptr, const char *needle, const char *needle_last) {
  if (**needle_ptr == *read_ptr) {
    (*needle_ptr)++;
    if (*needle_ptr > needle_last) {
      *needle_ptr = (const char *)needle;
      return true;
    }
  } else
    *needle_ptr = (const char *)needle;
  return false;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<locate_forward>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rsi),%esi
  cmp    %sil,(%rax)
  je     L2
  mov    %rdx,(%rdi)
  mov    $0x0,%eax
  ret
L2:
  add    $0x1,%rax
  cmp    %rcx,%rax
  ja     L18
  mov    %rax,(%rdi)
  mov    $0x0,%eax
  ret
L18:
  mov    %rdx,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool locate_forward(const char **needle_ptr, char *read_ptr, const char *needle, const char *needle_last) {
  if (**needle_ptr == *read_ptr) {
    (*needle_ptr)++;
    if (*needle_ptr > needle_last) {
      *needle_ptr = (const char *)needle;
      return true;
    }
  } else
    *needle_ptr = (const char *)needle;
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<locate_forward>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rsi),%esi
  cmp    %sil,(%rax)
  je     L4
  mov    %rdx,(%rdi)
  xor    %eax,%eax
  ret
  nopl   (%rax)
L4:
  add    $0x1,%rax
  cmp    %rcx,%rax
  ja     L1
  mov    %rax,(%rdi)
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  mov    %rdx,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool locate_forward(const char **needle_ptr, char *read_ptr, const char *needle, const char *needle_last) {
  if (**needle_ptr == *read_ptr) {
    (*needle_ptr)++;
    if (*needle_ptr > needle_last) {
      *needle_ptr = (const char *)needle;
      return true;
    }
  } else
    *needle_ptr = (const char *)needle;
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<locate_forward>:
  endbr64
  mov    (%rdi),%rax
  movzbl (%rsi),%esi
  cmp    %sil,(%rax)
  je     L4
  mov    %rdx,(%rdi)
  xor    %eax,%eax
  ret
  nopl   (%rax)
L4:
  add    $0x1,%rax
  cmp    %rcx,%rax
  ja     L15
  mov    %rax,(%rdi)
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rdx,(%rdi)
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool locate_forward(const char **needle_ptr, char *read_ptr, const char *needle, const char *needle_last) {
  if (**needle_ptr == *read_ptr) {
    (*needle_ptr)++;
    if (*needle_ptr > needle_last) {
      *needle_ptr = (const char *)needle;
      return true;
    }
  } else
    *needle_ptr = (const char *)needle;
  return false;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_results>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D35
type: string
name: retrieve_data
arguments: data_label: D13
type: string
name: retrieve_data
arguments: data_label: D42
type: string
name: retrieve_data
arguments: data_label: D44
type: string
name: retrieve_data
arguments: data_label: D47
type: string

tool: D35:   ---

tool: D13:   iterations: %d


tool: D42:   elapsed: %0.9f


tool: D44:   rate: %0.9f


tool: D47:   ...

assistant: ```c
void print_results(int iterations, double elapsed) {
  double rate = (double)iterations / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", iterations);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_results>:
  endbr64
  push   %r14
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movq   %xmm0,%r14
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   %r14,%xmm0
  lea    D11(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  movq   %r14,%xmm1
  divsd  %xmm1,%xmm0
  lea    D8(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D25
type_guessed: string
name: parse_data
arguments: tag: D7
type_guessed: string
name: parse_data
arguments: tag: D11
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D35
type_guessed: string

tool: D25:   ---

tool: D7:   iterations: %d


tool: D11:   elapsed: %0.9f


tool: D8:   rate: %0.9f


tool: D35:   ...

assistant: ```c
void print_results(int iterations, double elapsed) {
  double rate = (double)iterations / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", iterations);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_results>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D19(%rip),%rdi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsi2sd %ebx,%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  lea    D28(%rip),%rdi
  pop    %rbx
  jmp    1060 <puts@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
type: string
name: unpack_data
arguments: data_tag: D40
type: string
name: unpack_data
arguments: data_tag: D24
type: string
name: unpack_data
arguments: data_tag: D39
type: string
name: unpack_data
arguments: data_tag: D28
type: string

tool: D19:   ---

tool: D40:   iterations: %d


tool: D24:   elapsed: %0.9f


tool: D39:   rate: %0.9f


tool: D28:   ...

assistant: ```c
void print_results(int iterations, double elapsed) {
  double rate = (double)iterations / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", iterations);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_results>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D7(%rip),%rdi
  sub    $0x10,%rsp
  movsd  %xmm0,0x8(%rsp)
  call   <puts@plt>
  mov    %ebx,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  movsd  0x8(%rsp),%xmm0
  mov    $0x1,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  cvtsi2sd %ebx,%xmm0
  divsd  0x8(%rsp),%xmm0
  call   <printf@plt>
  add    $0x10,%rsp
  lea    D35(%rip),%rdi
  pop    %rbx
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D10
type: string
name: disassemble_data
arguments: data_label: D32
type: string
name: disassemble_data
arguments: data_label: D35
type: string

tool: D7:   ---

tool: D26:   iterations: %d


tool: D10:   elapsed: %0.9f


tool: D32:   rate: %0.9f


tool: D35:   ...

assistant: ```c
void print_results(int iterations, double elapsed) {
  double rate = (double)iterations / elapsed;
  printf("  ---\n");
  printf("  iterations: %d\n", iterations);
  printf("  elapsed: %0.9f\n", elapsed);
  printf("  rate: %0.9f\n", rate);
  printf("  ...\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x5,-0x4(%rbp)
  jmp    L70
L21:
  cmpl   $0x0,-0x4(%rbp)
  je     L29
  cmpl   $0x1,-0x4(%rbp)
  je     L3
  cmpl   $0x2,-0x4(%rbp)
  je     L7
  cmpl   $0x3,-0x4(%rbp)
  je     L86
L70:
  cmpl   $0x3e8,-0x4(%rbp)
  jle    L21
  jmp    L40
L29:
  nop
  jmp    L40
L3:
  nop
  jmp    L40
L7:
  nop
  jmp    L40
L86:
  nop
L40:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int k = 5;
  while (k <= 1000) {
    if (k == 0) {
      break;
    }
    if (k == 1) {
      break;
    } else if (k == 2) {
      break;
    } else if (k == 3) {
      break;
    }
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
L3:
  jmp    L3
```

assistant: ```c
int main(void) {
  int k = 5;
  while (k <= 1000) {
    if (k == 0) {
      break;
    }
    if (k == 1) {
      break;
    } else if (k == 2) {
      break;
    } else if (k == 3) {
      break;
    }
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L7:
  jmp    L7
```

assistant: ```c
int main(void) {
  int k = 5;
  while (k <= 1000) {
    if (k == 0) {
      break;
    }
    if (k == 1) {
      break;
    } else if (k == 2) {
      break;
    } else if (k == 3) {
      break;
    }
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  nopl   0x0(%rax)
L6:
  jmp    L6
```

assistant: ```c
int main(void) {
  int k = 5;
  while (k <= 1000) {
    if (k == 0) {
      break;
    }
    if (k == 1) {
      break;
    } else if (k == 2) {
      break;
    } else if (k == 3) {
      break;
    }
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aclpolicy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  mov    $0x1,%eax
  jmp    L27
L8:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  jne    L39
  mov    $0x2,%eax
  jmp    L27
L39:
  mov    $0xffffffff,%eax
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D2
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D2: accept

tool: D14: reject

assistant: ```c
unsigned char aclpolicy(char *p) {
  if (strcmp(p, "accept") == 0)
    return (1);
  if (strcmp(p, "reject") == 1)
    return (2);
  return (255);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<aclpolicy>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D12(%rip),%rsi
  call   <strcmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L3
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
L3:
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D12
datatype: string
name: retrieve_data
arguments: tag: D9
datatype: string

tool: D12: accept

tool: D9: reject

assistant: ```c
unsigned char aclpolicy(char *p) {
  if (strcmp(p, "accept") == 0)
    return (1);
  if (strcmp(p, "reject") == 1)
    return (2);
  return (255);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aclpolicy>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L4
  lea    D12(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
L4:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string

tool: D11: accept

tool: D12: reject

assistant: ```c
unsigned char aclpolicy(char *p) {
  if (strcmp(p, "accept") == 0)
    return (1);
  if (strcmp(p, "reject") == 1)
    return (2);
  return (255);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aclpolicy>:
  endbr64
  push   %rbp
  lea    D9(%rip),%rsi
  mov    %rdi,%rbp
  call   <strcmp@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L3
  lea    D4(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  cmp    $0x1,%eax
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
L3:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string
name: disassemble_data
arguments: tag: D4
type_infered: string

tool: D9: accept

tool: D4: reject

assistant: ```c
unsigned char aclpolicy(char *p) {
  if (strcmp(p, "accept") == 0)
    return (1);
  if (strcmp(p, "reject") == 1)
    return (2);
  return (255);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deref_after_null_check_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L8
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
L8:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void deref_after_null_check_bad(int *x) {
  if (x == 0) {
    *x = 1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<deref_after_null_check_bad>:
  endbr64
  test   %rdi,%rdi
  je     L13
L9:
  ret
L13:
  movl   $0x1,0x0
  jmp    L9
```

assistant: ```c
void deref_after_null_check_bad(int *x) {
  if (x == 0) {
    *x = 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<deref_after_null_check_bad>:
  endbr64
  test   %rdi,%rdi
  je     L0
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void deref_after_null_check_bad(int *x) {
  if (x == 0) {
    *x = 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deref_after_null_check_bad>:
  endbr64
  test   %rdi,%rdi
  je     L7
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movl   $0x0,0x0
  ud2
```

assistant: ```c
void deref_after_null_check_bad(int *x) {
  if (x == 0) {
    *x = 1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_in>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L41
L15:
  addq   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L20
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L15
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L28
  mov    -0x8(%rbp),%rax
  sub    -0x20(%rbp),%rax
  jmp    L4
L28:
  mov    $0xffffffff,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int is_in(char i, char const *str) {
  char const *p = str;
  while (*p != '\0' && *p != i)
    p++;
  return (*p == '\0' ? -1 : p - str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_in>:
  endbr64
  mov    %edi,%ecx
  movzbl (%rsi),%edx
  cmp    %dil,%dl
  je     L31
  test   %dl,%dl
  je     L31
  mov    %rsi,%rax
L47:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    %cl,%dl
  je     L5
  test   %dl,%dl
  jne    L47
L5:
  test   %dl,%dl
  je     L0
  sub    %esi,%eax
  ret
L31:
  mov    %rsi,%rax
  jmp    L5
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int is_in(char i, char const *str) {
  char const *p = str;
  while (*p != '\0' && *p != i)
    p++;
  return (*p == '\0' ? -1 : p - str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_in>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rsi,%rax
  test   %dl,%dl
  jne    L32
  jmp    L20
L6:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L20
L32:
  cmp    %dl,%dil
  jne    L6
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int is_in(char i, char const *str) {
  char const *p = str;
  while (*p != '\0' && *p != i)
    p++;
  return (*p == '\0' ? -1 : p - str);
}
```
user: What is the c source code of the assembly code below?

```asm
<is_in>:
  endbr64
  movzbl (%rsi),%edx
  mov    %rsi,%rax
  test   %dl,%dl
  jne    L1
  jmp    L20
L25:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  test   %dl,%dl
  je     L20
L1:
  cmp    %dl,%dil
  jne    L25
  sub    %esi,%eax
  ret
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int is_in(char i, char const *str) {
  char const *p = str;
  while (*p != '\0' && *p != i)
    p++;
  return (*p == '\0' ? -1 : p - str);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hasnoun@plt>
  test   %eax,%eax
  jne    L26
  mov    $0x0,%eax
  jmp    L13
L26:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L50
L40:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <hasadjective@plt>
  test   %eax,%eax
  jne    L6
  mov    $0x0,%eax
  jmp    L13
L6:
  addq   $0x4,-0x8(%rbp)
L50:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L40
  mov    $0x1,%eax
L13:
  leave
  ret
```

assistant: ```c
int match(int obj, int noun, int *adjs) {
  int *aptr;
  if (!hasnoun(obj, noun))
    return (0);
  for (aptr = adjs; *aptr != 0; aptr++)
    if (!hasadjective(obj, *aptr))
      return (0);
  return (1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<match>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rdx,%rbx
  call   <hasnoun@plt>
  test   %eax,%eax
  je     L18
  mov    (%rbx),%esi
  test   %esi,%esi
  je     L31
L22:
  mov    %ebp,%edi
  call   <hasadjective@plt>
  test   %eax,%eax
  je     L18
  add    $0x4,%rbx
  mov    (%rbx),%esi
  test   %esi,%esi
  jne    L22
  mov    $0x1,%eax
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L31:
  mov    $0x1,%eax
  jmp    L18
```

assistant: ```c
int match(int obj, int noun, int *adjs) {
  int *aptr;
  if (!hasnoun(obj, noun))
    return (0);
  for (aptr = adjs; *aptr != 0; aptr++)
    if (!hasadjective(obj, *aptr))
      return (0);
  return (1);
}
```