ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int *pa;
  int **ppa;
  int ***pppa;
  pppa = &ppa;
  ppa = &pa;
  pa = &a;
  ***pppa = 5;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x2,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int foo = 4;
  return 1 + 1 + foo;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int main(void) {
  int foo = 4;
  return 1 + 1 + foo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int main(void) {
  int foo = 4;
  return 1 + 1 + foo;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x6,%eax
  ret
```

assistant: ```c
int main(void) {
  int foo = 4;
  return 1 + 1 + foo;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  movslq %eax,%rbx
  mov    $0x0,%edi
  call   <ucc_brk@plt>
  add    %rbx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <brk@plt>
  cmp    $0xffffffff,%eax
  jne    L15
  mov    $0xffffffffffffffff,%rax
  jmp    L5
L15:
  mov    -0x18(%rbp),%rax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void *sbrk(int inc) {
  void *new = (char *)ucc_brk((void *)0) + inc;
  if (brk(new) == -1) {
    return (void *)-1;
  }
  return new;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sbrk>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <ucc_brk@plt>
  mov    %rax,%rbp
  movslq %ebx,%rbx
  lea    (%rbx,%rax,1),%rdi
  call   <brk@plt>
  add    %rbp,%rbx
  cmp    $0xffffffff,%eax
  mov    $0xffffffffffffffff,%rdi
  cmovne %rbx,%rdi
  mov    %rdi,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *sbrk(int inc) {
  void *new = (char *)ucc_brk((void *)0) + inc;
  if (brk(new) == -1) {
    return (void *)-1;
  }
  return new;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sbrk>:
  endbr64
  push   %r12
  movslq %edi,%r12
  xor    %edi,%edi
  call   <ucc_brk@plt>
  add    %rax,%r12
  mov    %r12,%rdi
  call   <brk@plt>
  cmp    $0xffffffff,%eax
  mov    $0xffffffffffffffff,%rax
  cmove  %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *sbrk(int inc) {
  void *new = (char *)ucc_brk((void *)0) + inc;
  if (brk(new) == -1) {
    return (void *)-1;
  }
  return new;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sbrk>:
  endbr64
  push   %r12
  movslq %edi,%r12
  xor    %edi,%edi
  call   <ucc_brk@plt>
  add    %rax,%r12
  mov    %r12,%rdi
  call   <brk@plt>
  cmp    $0xffffffff,%eax
  mov    $0xffffffffffffffff,%rax
  cmove  %rax,%r12
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
void *sbrk(int inc) {
  void *new = (char *)ucc_brk((void *)0) + inc;
  if (brk(new) == -1) {
    return (void *)-1;
  }
  return new;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<flushandreload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <maccess@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <flush@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t flushandreload(void *addr) {
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  flush(addr);
  return delta;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flushandreload>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,%r12
  mov    %rbx,%rdi
  call   <maccess@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  sub    %r12,%rax
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <flush@plt>
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t flushandreload(void *addr) {
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  flush(addr);
  return delta;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<flushandreload>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <rdtsc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <maccess@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    %rbp,%rdi
  sub    %rbx,%rax
  mov    %rax,%r12
  call   <flush@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t flushandreload(void *addr) {
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  flush(addr);
  return delta;
}
```
user: What is the c source code of the assembly code below:

```asm
<flushandreload>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <rdtsc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <maccess@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    %rbp,%rdi
  sub    %rbx,%rax
  mov    %rax,%r12
  call   <flush@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
size_t flushandreload(void *addr) {
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  flush(addr);
  return delta;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x8e,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  int onehundredandfortytwo = 142;
  return onehundredandfortytwo % 100;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int onehundredandfortytwo = 142;
  return onehundredandfortytwo % 100;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int onehundredandfortytwo = 142;
  return onehundredandfortytwo % 100;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x2a,%eax
  ret
```

assistant: ```c
int main(void) {
  int onehundredandfortytwo = 142;
  return onehundredandfortytwo % 100;
}
```
user: What is the c source code of the assembly code below?

```asm
<extract>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <auxv_base_addr@plt>
  mov    %rax,-0x18(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <auxv_read@plt>
  mov    %rax,-0x10(%rbp)
  addq   $0x4,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <extract_elf@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pt_load@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <load_interp@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  movabs $0xffff400000,%rax
  mov    %rax,%rdi
  call   <_munmap@plt>
  nop
  leave
  ret
```

assistant: ```c
void extract(void *stack) {
  Elf64_Ehdr *elf_hdr;
  Elf64_Phdr *phdr;
  void *auxv;
  auxv = auxv_base_addr(stack);
  phdr = (Elf64_Phdr *)auxv_read(auxv, AT_PHDR);
  ++phdr;
  elf_hdr = extract_elf(phdr);
  pt_load(elf_hdr);
  load_interp(elf_hdr);
  _munmap((void *)(0xffff400000), phdr->p_memsz);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<extract>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <auxv_base_addr@plt>
  mov    %rax,%rdi
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  call   <auxv_read@plt>
  mov    %rax,%rbx
  lea    0x4(%rax),%rdi
  call   <extract_elf@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <pt_load@plt>
  mov    %rbp,%rdi
  call   <load_interp@plt>
  mov    0x4(%rbx),%esi
  movabs $0xffff400000,%rdi
  call   <_munmap@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void extract(void *stack) {
  Elf64_Ehdr *elf_hdr;
  Elf64_Phdr *phdr;
  void *auxv;
  auxv = auxv_base_addr(stack);
  phdr = (Elf64_Phdr *)auxv_read(auxv, AT_PHDR);
  ++phdr;
  elf_hdr = extract_elf(phdr);
  pt_load(elf_hdr);
  load_interp(elf_hdr);
  _munmap((void *)(0xffff400000), phdr->p_memsz);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<extract>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <auxv_base_addr@plt>
  mov    %rax,%rdi
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  call   <auxv_read@plt>
  lea    0x4(%rax),%rdi
  mov    %rax,%rbx
  call   <extract_elf@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <pt_load@plt>
  mov    %rbp,%rdi
  call   <load_interp@plt>
  mov    0x4(%rbx),%esi
  add    $0x8,%rsp
  movabs $0xffff400000,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <_munmap@plt>
```

assistant: ```c
void extract(void *stack) {
  Elf64_Ehdr *elf_hdr;
  Elf64_Phdr *phdr;
  void *auxv;
  auxv = auxv_base_addr(stack);
  phdr = (Elf64_Phdr *)auxv_read(auxv, AT_PHDR);
  ++phdr;
  elf_hdr = extract_elf(phdr);
  pt_load(elf_hdr);
  load_interp(elf_hdr);
  _munmap((void *)(0xffff400000), phdr->p_memsz);
}
```
user: What is the c source code of the assembly code below:

```asm
<extract>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <auxv_base_addr@plt>
  mov    %rax,%rdi
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <auxv_read@plt>
  lea    0x4(%rax),%rdi
  mov    %rax,%rbx
  call   <extract_elf@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <pt_load@plt>
  mov    %rbp,%rdi
  call   <load_interp@plt>
  mov    0x4(%rbx),%esi
  add    $0x8,%rsp
  movabs $0xffff400000,%rdi
  pop    %rbx
  pop    %rbp
  jmp    10b0 <_munmap@plt>
```

assistant: ```c
void extract(void *stack) {
  Elf64_Ehdr *elf_hdr;
  Elf64_Phdr *phdr;
  void *auxv;
  auxv = auxv_base_addr(stack);
  phdr = (Elf64_Phdr *)auxv_read(auxv, AT_PHDR);
  ++phdr;
  elf_hdr = extract_elf(phdr);
  pt_load(elf_hdr);
  load_interp(elf_hdr);
  _munmap((void *)(0xffff400000), phdr->p_memsz);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L1:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L1
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: bees 

assistant: ```c
void main(void) {
  while (1) {
    printf("bees ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_infered: string

tool: D6: bees 

assistant: ```c
void main(void) {
  while (1) {
    printf("bees ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  nopl   0x0(%rax)
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
datatype: string

tool: D6: bees 

assistant: ```c
void main(void) {
  while (1) {
    printf("bees ");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: string

tool: D7: bees 

assistant: ```c
void main(void) {
  while (1) {
    printf("bees ");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x28(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  D23(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x18(%rbp),%xmm2
  movsd  D26(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D15(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D41
type_infered: string
name: parse_data
arguments: data_tag: D23
type_infered: byte[8]
name: parse_data
arguments: data_tag: D26
type_infered: byte[8]
name: parse_data
arguments: data_tag: D15
type_infered: byte[8]
name: parse_data
arguments: data_tag: D11
type_infered: string

tool: D41: %lf

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D15": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D11: MEDIA = %.1f


assistant: ```c
int main() {
  double nota_1, nota_2, nota_3, MEDIA_TOTAL;
  scanf("%lf", &nota_1);
  scanf("%lf", &nota_2);
  scanf("%lf", &nota_3);
  MEDIA_TOTAL = (((((nota_1 * 2) + (nota_2 * 3)) + (nota_3 * 5))) / 10);
  printf("MEDIA = %.1f\n", MEDIA_TOTAL);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  addsd  %xmm0,%xmm0
  movsd  D12(%rip),%xmm1
  mulsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  D45(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D34(%rip),%xmm0
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_infered: string
name: unpack_data
arguments: data_tag: D12
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D45
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D34
type_infered: byte[8]
name: unpack_data
arguments: data_tag: D15
type_infered: string

tool: D6: %lf

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: {"D45": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D34": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

tool: D15: MEDIA = %.1f


assistant: ```c
int main() {
  double nota_1, nota_2, nota_3, MEDIA_TOTAL;
  scanf("%lf", &nota_1);
  scanf("%lf", &nota_2);
  scanf("%lf", &nota_3);
  MEDIA_TOTAL = (((((nota_1 * 2) + (nota_2 * 3)) + (nota_3 * 5))) / 10);
  printf("MEDIA = %.1f\n", MEDIA_TOTAL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  movsd  D48(%rip),%xmm1
  lea    D17(%rip),%rdi
  mulsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D21(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D39(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D13
datatype: string
name: disassemble_data
arguments: tag: D48
datatype: byte[8]
name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: byte[8]
name: disassemble_data
arguments: tag: D39
datatype: byte[8]

tool: D13: %lf

tool: {"D48": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D17: MEDIA = %.1f


tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
int main() {
  double nota_1, nota_2, nota_3, MEDIA_TOTAL;
  scanf("%lf", &nota_1);
  scanf("%lf", &nota_2);
  scanf("%lf", &nota_3);
  MEDIA_TOTAL = (((((nota_1 * 2) + (nota_2 * 3)) + (nota_3 * 5))) / 10);
  printf("MEDIA = %.1f\n", MEDIA_TOTAL);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  lea    0x8(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %rbp,%rdi
  lea    0x10(%rsp),%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm0
  movsd  D24(%rip),%xmm1
  lea    D36(%rip),%rdi
  mulsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  movsd  D3(%rip),%xmm1
  mulsd  0x10(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  divsd  D2(%rip),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D33
type: string
name: extract_symbolic_data
arguments: label: D24
type: byte[8]
name: extract_symbolic_data
arguments: label: D36
type: string
name: extract_symbolic_data
arguments: label: D3
type: byte[8]
name: extract_symbolic_data
arguments: label: D2
type: byte[8]

tool: D33: %lf

tool: {"D24": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0x40]}

tool: D36: MEDIA = %.1f


tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x24,0x40]}

assistant: ```c
int main() {
  double nota_1, nota_2, nota_3, MEDIA_TOTAL;
  scanf("%lf", &nota_1);
  scanf("%lf", &nota_2);
  scanf("%lf", &nota_3);
  MEDIA_TOTAL = (((((nota_1 * 2) + (nota_2 * 3)) + (nota_3 * 5))) / 10);
  printf("MEDIA = %.1f\n", MEDIA_TOTAL);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%eax
  call   <clr@plt>
  jmp    L8
L25:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x9,-0xc(%rbp)
  jle    L25
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string
name: retrieve_data
arguments: data_label: D30
type_guessed: string
name: retrieve_data
arguments: data_label: D9
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D7: 
Enter number: 

tool: D30: %d

tool: D9: -----

tool: D15: | %d | 

assistant: ```c
int main() {
  int i = 0;
  int number;
  clr();
  while (i < 10) {
    printf("\nEnter number: ");
    scanf("%d", &number);
    gotoxy(10, 10);
    printf("-----\n");
    printf("| %d | ", i * number);
    i++;
  };
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <clr@plt>
  mov    $0x0,%ebx
  lea    D35(%rip),%r14
  lea    D36(%rip),%r13
  lea    D19(%rip),%r12
  lea    D30(%rip),%rbp
L8:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %ebx,%esi
  imul   0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D35
type_infered: string
name: read_data
arguments: label: D36
type_infered: string
name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D30
type_infered: string

tool: D35: 
Enter number: 

tool: D36: %d

tool: D19: -----

tool: D30: | %d | 

assistant: ```c
int main() {
  int i = 0;
  int number;
  clr();
  while (i < 10) {
    printf("\nEnter number: ");
    scanf("%d", &number);
    gotoxy(10, 10);
    printf("-----\n");
    printf("| %d | ", i * number);
    i++;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%r15
  push   %r14
  push   %r13
  lea    D34(%rip),%r13
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r14
  call   <clr@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    $0xa,%esi
  mov    $0xa,%edi
  call   <gotoxy@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  imul   %ebx,%esi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
datatype: string
name: unpack_data
arguments: tag: D34
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D6
datatype: string

tool: D10: 
Enter number: 

tool: D34: %d

tool: D22: -----

tool: D6: | %d | 

assistant: ```c
int main() {
  int i = 0;
  int number;
  clr();
  while (i < 10) {
    printf("\nEnter number: ");
    scanf("%d", &number);
    gotoxy(10, 10);
    printf("-----\n");
    printf("| %d | ", i * number);
    i++;
  };
}
```