ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<err>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err(char *msg) {
  puts(msg);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<SDBMHash_ex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L14
L12:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x6,%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  add    %edx,%eax
  sub    -0x14(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jne    L12
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int SDBMHash_ex(const void *key, const int key_len, const int init_value) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int hash;
  hash = init_value;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    hash = (*pKey) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<SDBMHash_ex>:
  endbr64
  mov    %edx,%eax
  movslq %esi,%rsi
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  je     L6
L5:
  movzbl (%rdi),%ecx
  mov    %eax,%edx
  shl    $0x6,%edx
  add    %edx,%ecx
  mov    %eax,%edx
  shl    $0x10,%edx
  add    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x1,%rdi
  cmp    %rdi,%rsi
  jne    L5
L6:
  ret
```

assistant: ```c
int SDBMHash_ex(const void *key, const int key_len, const int init_value) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int hash;
  hash = init_value;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    hash = (*pKey) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDBMHash_ex>:
  endbr64
  movslq %esi,%rsi
  mov    %edx,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  je     L10
  nopl   0x0(%rax)
L0:
  movzbl (%rdi),%ecx
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x6,%edx
  add    %edx,%ecx
  mov    %eax,%edx
  shl    $0x10,%edx
  add    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  cmp    %rdi,%rsi
  jne    L0
L10:
  ret
```

assistant: ```c
int SDBMHash_ex(const void *key, const int key_len, const int init_value) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int hash;
  hash = init_value;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    hash = (*pKey) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SDBMHash_ex>:
  endbr64
  movslq %esi,%rsi
  mov    %edx,%eax
  add    %rdi,%rsi
  cmp    %rsi,%rdi
  je     L11
  nopl   0x0(%rax)
L17:
  movzbl (%rdi),%ecx
  mov    %eax,%edx
  add    $0x1,%rdi
  shl    $0x6,%edx
  add    %edx,%ecx
  mov    %eax,%edx
  shl    $0x10,%edx
  add    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  cmp    %rdi,%rsi
  jne    L17
L11:
  ret
```

assistant: ```c
int SDBMHash_ex(const void *key, const int key_len, const int init_value) {
  unsigned char *pKey;
  unsigned char *pEnd;
  int hash;
  hash = init_value;
  pEnd = (unsigned char *)key + key_len;
  for (pKey = (unsigned char *)key; pKey != pEnd; pKey++) {
    hash = (*pKey) + (hash << 6) + (hash << 16) - hash;
  }
  return hash;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xfffffffc,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  sarl   -0x8(%rbp)
  cmpl   $0xfffffffe,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpl   $0xfffffffe,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  movl   $0xffffffff,-0x8(%rbp)
  sarl   -0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0xfffffff6,-0x8(%rbp)
  sarl   $0xa,-0x8(%rbp)
  cmpl   $0xffffffff,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = -4, y;
  y = x >> 1;
  x >>= 1;
  assert(x == -2);
  assert(y == -2);
  assert(((-2) >> 1u) == -1);
  x = -1;
  x = x >> 1;
  assert(x == -1);
  x = -10;
  x = x >> 10;
  assert(x == -1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = -4, y;
  y = x >> 1;
  x >>= 1;
  assert(x == -2);
  assert(y == -2);
  assert(((-2) >> 1u) == -1);
  x = -1;
  x = x >> 1;
  assert(x == -1);
  x = -10;
  x = x >> 10;
  assert(x == -1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = -4, y;
  y = x >> 1;
  x >>= 1;
  assert(x == -2);
  assert(y == -2);
  assert(((-2) >> 1u) == -1);
  x = -1;
  x = x >> 1;
  assert(x == -1);
  x = -10;
  x = x >> 10;
  assert(x == -1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x = -4, y;
  y = x >> 1;
  x >>= 1;
  assert(x == -2);
  assert(y == -2);
  assert(((-2) >> 1u) == -1);
  x = -1;
  x = x >> 1;
  assert(x == -1);
  x = -10;
  x = x >> 10;
  assert(x == -1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<blurXAlpha>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,%eax
  mov    %r9d,-0x3c(%rbp)
  mov    %al,-0x38(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jle    L30
  mov    0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x3c(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  mov    0x18(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edi
  call   <allocMemory@plt>
  mov    %rax,-0x8(%rbp)
  movzbl -0x38(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <clearMemory@plt>
  movzbl -0x38(%rbp),%eax
  mov    0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    -0x18(%rbp),%edx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <clearMemory@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L11
L28:
  mov    0x18(%rbp),%eax
  sub    -0x18(%rbp),%eax
  mov    -0x34(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x10(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rsi
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <copyMemory@plt>
  mov    -0x14(%rbp),%ecx
  mov    0x18(%rbp),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <boxBlurAlpha@plt>
  mov    -0x2c(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    0x20(%rbp),%eax
  jl     L28
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <freeMemory@plt>
  jmp    L35
L30:
  nop
L35:
  leave
  ret
```

assistant: ```c
void blurXAlpha(unsigned char *img, int width, int height, int distance, unsigned char borderAlpha, int rx, int ry, int rw, int rh) {
  if (distance < 1) {
    return;
  }
  unsigned char *src = img + (ry * width) + rx;
  int dist2 = distance << 1;
  int windowLength = dist2 + 1;
  unsigned char *lineBufferIn = allocMemory(rw + dist2);
  clearMemory(lineBufferIn, borderAlpha, dist2);
  clearMemory(lineBufferIn + rw, borderAlpha, dist2);
  for (int y = 0; y < rh; ++y) {
    copyMemory(lineBufferIn + dist2, src + distance, rw - dist2);
    boxBlurAlpha(src, lineBufferIn, rw, windowLength);
    src += width;
  }
  freeMemory(lineBufferIn);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<blurXAlpha>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    0x58(%rsp),%r12d
  test   %ecx,%ecx
  jle    L28
  mov    %rdi,%rbx
  mov    %esi,%r15d
  mov    %ecx,%r13d
  mov    %r8d,%ebp
  mov    %esi,%eax
  imul   0x50(%rsp),%eax
  cltq
  movslq %r9d,%r9
  add    %r9,%rax
  add    %rax,%rbx
  lea    (%rcx,%rcx,1),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,0x4(%rsp)
  mov    %eax,(%rsp)
  lea    (%rax,%r12,1),%edi
  call   <allocMemory@plt>
  mov    %rax,%r14
  movzbl %bpl,%ebp
  mov    (%rsp),%edx
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <clearMemory@plt>
  movslq %r12d,%rdi
  add    %r14,%rdi
  mov    (%rsp),%edx
  mov    %ebp,%esi
  call   <clearMemory@plt>
  cmpl   $0x0,0x60(%rsp)
  jle    L12
  mov    $0x0,%ebp
  movslq (%rsp),%rax
  add    %r14,%rax
  mov    %rax,0x8(%rsp)
L17:
  mov    %r12d,%edx
  sub    (%rsp),%edx
  movslq %r13d,%rsi
  add    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <copyMemory@plt>
  mov    0x4(%rsp),%ecx
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <boxBlurAlpha@plt>
  movslq %r15d,%rax
  add    %rax,%rbx
  add    $0x1,%ebp
  cmp    %ebp,0x60(%rsp)
  jne    L17
L12:
  mov    %r14,%rdi
  call   <freeMemory@plt>
L28:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void blurXAlpha(unsigned char *img, int width, int height, int distance, unsigned char borderAlpha, int rx, int ry, int rw, int rh) {
  if (distance < 1) {
    return;
  }
  unsigned char *src = img + (ry * width) + rx;
  int dist2 = distance << 1;
  int windowLength = dist2 + 1;
  unsigned char *lineBufferIn = allocMemory(rw + dist2);
  clearMemory(lineBufferIn, borderAlpha, dist2);
  clearMemory(lineBufferIn + rw, borderAlpha, dist2);
  for (int y = 0; y < rh; ++y) {
    copyMemory(lineBufferIn + dist2, src + distance, rw - dist2);
    boxBlurAlpha(src, lineBufferIn, rw, windowLength);
    src += width;
  }
  freeMemory(lineBufferIn);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<blurXAlpha>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    0x70(%rsp),%ecx
  mov    0x60(%rsp),%eax
  mov    0x68(%rsp),%r12d
  mov    %ecx,0x8(%rsp)
  test   %ebx,%ebx
  jle    L24
  imul   %esi,%eax
  movslq %r9d,%r9
  lea    (%rbx,%rbx,1),%r13d
  mov    %r8d,%r15d
  mov    %esi,0x10(%rsp)
  movzbl %r15b,%r15d
  cltq
  add    %r9,%rax
  lea    (%rdi,%rax,1),%r14
  lea    0x1(%r13),%eax
  lea    0x0(%r13,%r12,1),%edi
  mov    %eax,0xc(%rsp)
  call   <allocMemory@plt>
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <clearMemory@plt>
  movslq %r12d,%rdi
  mov    %r13d,%edx
  mov    %r15d,%esi
  add    %rbp,%rdi
  call   <clearMemory@plt>
  mov    0x8(%rsp),%eax
  mov    0x10(%rsp),%r10d
  test   %eax,%eax
  jle    L8
  movslq %ebx,%rax
  mov    %r12d,%r15d
  movslq %r13d,%rbx
  mov    %rax,0x10(%rsp)
  movslq %r10d,%rax
  sub    %r13d,%r15d
  add    %rbp,%rbx
  mov    %rax,0x18(%rsp)
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L21:
  mov    0x10(%rsp),%rax
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r13d
  lea    (%r14,%rax,1),%rsi
  call   <copyMemory@plt>
  mov    0xc(%rsp),%ecx
  mov    %r14,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <boxBlurAlpha@plt>
  add    0x18(%rsp),%r14
  cmp    %r13d,0x8(%rsp)
  jne    L21
L8:
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <freeMemory@plt>
  nopl   0x0(%rax)
L24:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void blurXAlpha(unsigned char *img, int width, int height, int distance, unsigned char borderAlpha, int rx, int ry, int rw, int rh) {
  if (distance < 1) {
    return;
  }
  unsigned char *src = img + (ry * width) + rx;
  int dist2 = distance << 1;
  int windowLength = dist2 + 1;
  unsigned char *lineBufferIn = allocMemory(rw + dist2);
  clearMemory(lineBufferIn, borderAlpha, dist2);
  clearMemory(lineBufferIn + rw, borderAlpha, dist2);
  for (int y = 0; y < rh; ++y) {
    copyMemory(lineBufferIn + dist2, src + distance, rw - dist2);
    boxBlurAlpha(src, lineBufferIn, rw, windowLength);
    src += width;
  }
  freeMemory(lineBufferIn);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<blurXAlpha>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    0x70(%rsp),%ecx
  mov    0x60(%rsp),%eax
  mov    0x68(%rsp),%r12d
  mov    %ecx,0x8(%rsp)
  test   %ebx,%ebx
  jle    L29
  imul   %esi,%eax
  movslq %r9d,%r9
  lea    (%rbx,%rbx,1),%r13d
  mov    %r8d,%r15d
  mov    %esi,0x10(%rsp)
  movzbl %r15b,%r15d
  cltq
  add    %r9,%rax
  lea    (%rdi,%rax,1),%r14
  lea    0x1(%r13),%eax
  lea    0x0(%r13,%r12,1),%edi
  mov    %eax,0xc(%rsp)
  call   <allocMemory@plt>
  mov    %r13d,%edx
  mov    %r15d,%esi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <clearMemory@plt>
  movslq %r12d,%rdi
  mov    %r13d,%edx
  mov    %r15d,%esi
  add    %rbp,%rdi
  call   <clearMemory@plt>
  mov    0x8(%rsp),%eax
  mov    0x10(%rsp),%r10d
  test   %eax,%eax
  jle    L2
  movslq %ebx,%rax
  mov    %r12d,%r15d
  movslq %r13d,%rbx
  mov    %rax,0x10(%rsp)
  movslq %r10d,%rax
  sub    %r13d,%r15d
  add    %rbp,%rbx
  mov    %rax,0x18(%rsp)
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L17:
  mov    0x10(%rsp),%rax
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r13d
  lea    (%r14,%rax,1),%rsi
  call   <copyMemory@plt>
  mov    0xc(%rsp),%ecx
  mov    %r14,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <boxBlurAlpha@plt>
  add    0x18(%rsp),%r14
  cmp    %r13d,0x8(%rsp)
  jne    L17
L2:
  add    $0x28,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <freeMemory@plt>
  nopl   0x0(%rax)
L29:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void blurXAlpha(unsigned char *img, int width, int height, int distance, unsigned char borderAlpha, int rx, int ry, int rw, int rh) {
  if (distance < 1) {
    return;
  }
  unsigned char *src = img + (ry * width) + rx;
  int dist2 = distance << 1;
  int windowLength = dist2 + 1;
  unsigned char *lineBufferIn = allocMemory(rw + dist2);
  clearMemory(lineBufferIn, borderAlpha, dist2);
  clearMemory(lineBufferIn + rw, borderAlpha, dist2);
  for (int y = 0; y < rh; ++y) {
    copyMemory(lineBufferIn + dist2, src + distance, rw - dist2);
    boxBlurAlpha(src, lineBufferIn, rw, windowLength);
    src += width;
  }
  freeMemory(lineBufferIn);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myle16toh>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t myle16toh(void *le) {
  uint8_t *p = (uint8_t *)le;
  return ((uint16_t)p[1] << 8) | (uint16_t)p[0];
}
```
user: Translate the below assembly code into C programming language:

```asm
<myle16toh>:
  endbr64
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint16_t myle16toh(void *le) {
  uint8_t *p = (uint8_t *)le;
  return ((uint16_t)p[1] << 8) | (uint16_t)p[0];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<myle16toh>:
  endbr64
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint16_t myle16toh(void *le) {
  uint8_t *p = (uint8_t *)le;
  return ((uint16_t)p[1] << 8) | (uint16_t)p[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<myle16toh>:
  endbr64
  mov    0x8(%rdi),%eax
  shl    $0x8,%eax
  or     (%rdi),%eax
  ret
```

assistant: ```c
uint16_t myle16toh(void *le) {
  uint8_t *p = (uint8_t *)le;
  return ((uint16_t)p[1] << 8) | (uint16_t)p[0];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kl_sprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <kl_malloc@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    -0xb8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vsprintf@plt>
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *kl_sprintf(char const *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  char *dest = kl_malloc(vsnprintf(NULL, 0, fmt, argv) + 1);
  va_end(argv);
  va_start(argv, fmt);
  vsprintf(dest, fmt, argv);
  va_end(argv);
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kl_sprintf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%ecx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <vsnprintf@plt>
  lea    0x1(%rax),%rdi
  call   <kl_malloc@plt>
  mov    %rax,%r12
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *kl_sprintf(char const *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  char *dest = kl_malloc(vsnprintf(NULL, 0, fmt, argv) + 1);
  va_end(argv);
  va_start(argv, fmt);
  vsprintf(dest, fmt, argv);
  va_end(argv);
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<kl_sprintf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  lea    0x1(%rax),%rdi
  call   <kl_malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <va_end@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *kl_sprintf(char const *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  char *dest = kl_malloc(vsnprintf(NULL, 0, fmt, argv) + 1);
  va_end(argv);
  va_start(argv, fmt);
  vsprintf(dest, fmt, argv);
  va_end(argv);
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<kl_sprintf>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %r12,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  call   <vsnprintf@plt>
  lea    0x1(%rax),%rdi
  call   <kl_malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <va_end@plt>
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <vsprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *kl_sprintf(char const *fmt, ...) {
  va_list argv;
  va_start(argv, fmt);
  char *dest = kl_malloc(vsnprintf(NULL, 0, fmt, argv) + 1);
  va_end(argv);
  va_start(argv, fmt);
  vsprintf(dest, fmt, argv);
  va_end(argv);
  return dest;
}
```