ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D28(%rip),%r13
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L3:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L3
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D28
datatype: string
name: disassemble_data
arguments: data_tag: D11
datatype: string
name: disassemble_data
arguments: data_tag: D22
datatype: string

tool: D28: nonfibonacci

tool: D11: # c::%s


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "nonfibonacci");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D15(%rip),%r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L7:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L7
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D15
datatype: string
name: read_data
arguments: tag: D10
datatype: string
name: read_data
arguments: tag: D27
datatype: string

tool: D15: nonfibonacci

tool: D10: # c::%s


tool: D27: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "nonfibonacci");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D56(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %eax,0x8(%rsp)
  jne    L2
L68:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L20
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D56(%rip),%r12
L80:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L80
L20:
  lea    D70(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L27
  lea    0xe0(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D56(%rip),%r12
L43:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L43
L27:
  lea    0xe0(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    0x8(%rsp),%edx
  call   <fnCheckIdentical@plt>
  test   %eax,%eax
  je     L33
  lea    D44(%rip),%rdi
  call   <printf@plt>
L79:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L89
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L68
L33:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L79
L89:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D33
type_guessed: string
name: retrieve_data
arguments: data_tag: D56
type_guessed: string
name: retrieve_data
arguments: data_tag: D20
type_guessed: string
name: retrieve_data
arguments: data_tag: D39
type_guessed: string
name: retrieve_data
arguments: data_tag: D70
type_guessed: string
name: retrieve_data
arguments: data_tag: D44
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: string

tool: D33: 
Enter the no of elements in the 1st array


tool: D56: %d

tool: D20: 
Enter the no of elements in the 2nd array


tool: D39: 
Enter elements of 1st Array


tool: D70: 
Enter elements of 2nd Array


tool: D44: 
Arrays are Identical


tool: D16: 
Arrays are not Identical


assistant: ```c
int main() {
  int iaArr1[50], iaArr2[50], iLen1, iLen2, i, iFlag;
  int *iptr1, *iptr2;
  printf("\nEnter the no of elements in the 1st array\n");
  scanf("%d", &iLen1);
  printf("\nEnter the no of elements in the 2nd array\n");
  scanf("%d", &iLen2);
  if (iLen1 != iLen2) {
    printf("\nArrays are not Identical\n");
    exit(0);
  }
  printf("\nEnter elements of 1st Array\n");
  for (i = 0; i < iLen1; i++)
    scanf("%d", &iaArr1[i]);
  printf("\nEnter elements of 2nd Array\n");
  for (i = 0; i < iLen2; i++)
    scanf("%d", &iaArr2[i]);
  iptr1 = iaArr1;
  iptr2 = iaArr2;
  iFlag = fnCheckIdentical(iptr1, iptr2, iLen1);
  if (iFlag)
    printf("\nArrays are Identical\n");
  else
    printf("\nArrays are not Identical\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checkChip>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%r9
  mov    %ecx,%eax
  movslq %edx,%rdx
  lea    (%rdx,%rdx,8),%r10
  lea    (%rdi,%r10,1),%rbx
  lea    -0x1(%rcx),%ecx
  movslq %ecx,%rsi
  mov    $0x0,%edx
  cmp    %r8b,(%rbx,%rsi,1)
  je     L47
L159:
  lea    0x9(%rdi,%r10,1),%r11
  movslq %ecx,%rsi
  cmp    %r8b,(%r11,%rsi,1)
  je     L149
L157:
  movslq %eax,%rsi
  cmp    %r8b,(%r11,%rsi,1)
  je     L3
L24:
  lea    0x1(%rax),%esi
  movslq %esi,%rbp
  cmp    %r8b,(%r11,%rbp,1)
  je     L79
L82:
  movslq %esi,%r11
  cmp    %r8b,(%rbx,%r11,1)
  je     L109
L55:
  lea    -0x9(%rdi,%r10,1),%rdi
  movslq %esi,%rsi
  cmp    %r8b,(%rdi,%rsi,1)
  je     L133
L54:
  cltq
  cmp    %r8b,(%rdi,%rax,1)
  je     L138
L30:
  movslq %ecx,%rcx
  cmp    %r8b,(%rdi,%rcx,1)
  je     L93
L106:
  pop    %rbx
  pop    %rbp
  ret
L47:
  movl   $0x1,(%r9)
  mov    $0x1,%edx
  jmp    L159
L149:
  movslq %edx,%rsi
  movl   $0x2,(%r9,%rsi,4)
  add    $0x1,%edx
  jmp    L157
L3:
  movslq %edx,%rsi
  movl   $0x3,(%r9,%rsi,4)
  add    $0x1,%edx
  jmp    L24
L79:
  movslq %edx,%r11
  movl   $0x4,(%r9,%r11,4)
  add    $0x1,%edx
  jmp    L82
L109:
  movslq %edx,%r11
  movl   $0x5,(%r9,%r11,4)
  add    $0x1,%edx
  jmp    L55
L133:
  movslq %edx,%rsi
  movl   $0x6,(%r9,%rsi,4)
  add    $0x1,%edx
  jmp    L54
L138:
  movslq %edx,%rax
  movl   $0x7,(%r9,%rax,4)
  add    $0x1,%edx
  jmp    L30
L93:
  movslq %edx,%rdx
  movl   $0x8,(%r9,%rdx,4)
  jmp    L106
```

assistant: ```c
void checkChip(char grid[9][9], int directs[8], int x, int y, char chip) {
  int i = 0;
  if (grid[x][y - 1] == chip) {
    directs[i] = 1;
    i++;
  }
  if (grid[x + 1][y - 1] == chip) {
    directs[i] = 2;
    i++;
  }
  if (grid[x + 1][y] == chip) {
    directs[i] = 3;
    i++;
  }
  if (grid[x + 1][y + 1] == chip) {
    directs[i] = 4;
    i++;
  }
  if (grid[x][y + 1] == chip) {
    directs[i] = 5;
    i++;
  }
  if (grid[x - 1][y + 1] == chip) {
    directs[i] = 6;
    i++;
  }
  if (grid[x - 1][y] == chip) {
    directs[i] = 7;
    i++;
  }
  if (grid[x - 1][y - 1] == chip) {
    directs[i] = 8;
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<checkChip>:
  endbr64
  movslq %edx,%rdx
  mov    %rdi,%r9
  mov    %ecx,%eax
  sub    $0x1,%ecx
  lea    (%rdx,%rdx,8),%rdx
  mov    %rsi,%rdi
  movslq %ecx,%r11
  push   %rbp
  lea    (%r9,%rdx,1),%rsi
  push   %rbx
  xor    %r10d,%r10d
  cmp    %r8b,(%rsi,%r11,1)
  jne    L10
  movl   $0x1,(%rdi)
  mov    $0x1,%r10d
L10:
  lea    0x9(%r9,%rdx,1),%rcx
  cmp    %r8b,(%rcx,%r11,1)
  jne    L26
  movslq %r10d,%rbx
  add    $0x1,%r10d
  movl   $0x2,(%rdi,%rbx,4)
L26:
  movslq %eax,%rbx
  cmp    %r8b,(%rcx,%rbx,1)
  jne    L16
  movslq %r10d,%rbp
  add    $0x1,%r10d
  movl   $0x3,(%rdi,%rbp,4)
L16:
  add    $0x1,%eax
  cltq
  cmp    %r8b,(%rcx,%rax,1)
  jne    L44
  movslq %r10d,%rcx
  add    $0x1,%r10d
  movl   $0x4,(%rdi,%rcx,4)
L44:
  cmp    %r8b,(%rsi,%rax,1)
  jne    L56
  movslq %r10d,%rcx
  add    $0x1,%r10d
  movl   $0x5,(%rdi,%rcx,4)
L56:
  lea    -0x9(%r9,%rdx,1),%rdx
  cmp    %r8b,(%rdx,%rax,1)
  jne    L40
  movslq %r10d,%rax
  add    $0x1,%r10d
  movl   $0x6,(%rdi,%rax,4)
L40:
  cmp    %r8b,(%rdx,%rbx,1)
  jne    L4
  movslq %r10d,%rax
  add    $0x1,%r10d
  movl   $0x7,(%rdi,%rax,4)
L4:
  cmp    %r8b,(%rdx,%r11,1)
  jne    L65
  movslq %r10d,%rax
  movl   $0x8,(%rdi,%rax,4)
L65:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void checkChip(char grid[9][9], int directs[8], int x, int y, char chip) {
  int i = 0;
  if (grid[x][y - 1] == chip) {
    directs[i] = 1;
    i++;
  }
  if (grid[x + 1][y - 1] == chip) {
    directs[i] = 2;
    i++;
  }
  if (grid[x + 1][y] == chip) {
    directs[i] = 3;
    i++;
  }
  if (grid[x + 1][y + 1] == chip) {
    directs[i] = 4;
    i++;
  }
  if (grid[x][y + 1] == chip) {
    directs[i] = 5;
    i++;
  }
  if (grid[x - 1][y + 1] == chip) {
    directs[i] = 6;
    i++;
  }
  if (grid[x - 1][y] == chip) {
    directs[i] = 7;
    i++;
  }
  if (grid[x - 1][y - 1] == chip) {
    directs[i] = 8;
    i++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checkChip>:
  endbr64
  movslq %edx,%rdx
  push   %r15
  mov    %ecx,%eax
  lea    (%rdx,%rdx,8),%r11
  lea    -0x1(%rcx),%edx
  push   %r14
  movslq %edx,%rdx
  push   %r13
  lea    (%rdi,%r11,1),%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %r8b,0x0(%r13,%rdx,1)
  je     L66
  mov    $0x18,%r12d
  mov    $0x14,%r15d
  mov    $0xc,%ebp
  xor    %ecx,%ecx
  mov    $0x10,%r14d
  mov    $0x8,%r10d
  mov    $0x4,%r9d
L56:
  lea    0x9(%rdi,%r11,1),%rbx
  cmp    %r8b,(%rbx,%rdx,1)
  jne    L46
  movl   $0x2,(%rsi,%rcx,1)
  mov    %r9,%rcx
  mov    %r10,%r9
  mov    %rbp,%r10
  mov    %r14,%rbp
  mov    %r15,%r14
  mov    %r12,%r15
L46:
  movslq %eax,%r12
  cmp    %r8b,(%rbx,%r12,1)
  jne    L18
  movl   $0x3,(%rsi,%rcx,1)
  mov    %r9,%rcx
  mov    %r10,%r9
  mov    %rbp,%r10
  mov    %r14,%rbp
  mov    %r15,%r14
L18:
  add    $0x1,%eax
  cltq
  cmp    %r8b,(%rbx,%rax,1)
  jne    L77
  movl   $0x4,(%rsi,%rcx,1)
  mov    %r9,%rcx
  mov    %r10,%r9
  mov    %rbp,%r10
  mov    %r14,%rbp
L77:
  cmp    %r8b,0x0(%r13,%rax,1)
  jne    L53
  movl   $0x5,(%rsi,%rcx,1)
  mov    %r9,%rcx
  mov    %r10,%r9
  mov    %rbp,%r10
L53:
  lea    -0x9(%rdi,%r11,1),%rdi
  cmp    %r8b,(%rdi,%rax,1)
  jne    L26
  movl   $0x6,(%rsi,%rcx,1)
  mov    %r9,%rcx
  mov    %r10,%r9
L26:
  cmp    %r8b,(%rdi,%r12,1)
  jne    L3
  movl   $0x7,(%rsi,%rcx,1)
  mov    %r9,%rcx
L3:
  cmp    %r8b,(%rdi,%rdx,1)
  jne    L2
  movl   $0x8,(%rsi,%rcx,1)
L2:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L66:
  movl   $0x1,(%rsi)
  mov    $0x10,%ebp
  mov    $0x4,%ecx
  mov    $0x1c,%r12d
  mov    $0x18,%r15d
  mov    $0x14,%r14d
  mov    $0xc,%r10d
  mov    $0x8,%r9d
  jmp    L56
```

assistant: ```c
void checkChip(char grid[9][9], int directs[8], int x, int y, char chip) {
  int i = 0;
  if (grid[x][y - 1] == chip) {
    directs[i] = 1;
    i++;
  }
  if (grid[x + 1][y - 1] == chip) {
    directs[i] = 2;
    i++;
  }
  if (grid[x + 1][y] == chip) {
    directs[i] = 3;
    i++;
  }
  if (grid[x + 1][y + 1] == chip) {
    directs[i] = 4;
    i++;
  }
  if (grid[x][y + 1] == chip) {
    directs[i] = 5;
    i++;
  }
  if (grid[x - 1][y + 1] == chip) {
    directs[i] = 6;
    i++;
  }
  if (grid[x - 1][y] == chip) {
    directs[i] = 7;
    i++;
  }
  if (grid[x - 1][y - 1] == chip) {
    directs[i] = 8;
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GO_strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L6:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  cmp    %al,%cl
  jne    L27
  mov    -0x18(%rbp),%rax
  jmp    L25
L27:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  addq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    $0x0,%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
char *GO_strpbrk(char *d, char *s) {
  char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<GO_strpbrk>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L20
L21:
  mov    %rsi,%rdx
L35:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  je     L14
  add    $0x1,%rdx
  cmp    %r8b,%cl
  jne    L35
L46:
  ret
L20:
  mov    $0x0,%eax
  ret
L14:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L21
  mov    $0x0,%eax
  jmp    L46
```

assistant: ```c
char *GO_strpbrk(char *d, char *s) {
  char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return NULL;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GO_strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L34
L19:
  mov    %rsi,%rdx
  jmp    L7
  nopl   (%rax)
L22:
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L38
L7:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L22
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L19
L34:
  xor    %eax,%eax
L38:
  ret
```

assistant: ```c
char *GO_strpbrk(char *d, char *s) {
  char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<GO_strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L1
L15:
  mov    %rsi,%rdx
  jmp    L24
  nopl   (%rax)
L21:
  add    $0x1,%rdx
  cmp    %r8b,%cl
  je     L38
L24:
  movzbl (%rdx),%ecx
  test   %cl,%cl
  jne    L21
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L15
L1:
  xor    %eax,%eax
L38:
  ret
```

assistant: ```c
char *GO_strpbrk(char *d, char *s) {
  char *bgn = s;
  while ('\0' != *d) {
    while ('\0' != *s)
      if (*d == *s++)
        return d;
    d++;
    s = bgn;
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_callui_notification>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x7,-0x4(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L15
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x5,%edx
  lea    D14(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L7
  movl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x5(%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L15
L7:
  mov    -0x18(%rbp),%rax
  mov    $0x7,%edx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L15
  movl   $0x0,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x7(%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x7,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L15:
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D14
type: string
name: retrieve_data
arguments: data_label: D5
type: string

tool: D14: popup

tool: D5: popdown

assistant: ```c
int parse_callui_notification(char *msg, int *length) {
  static char keywd[] = "callui ";
  int kwdlen = sizeof(keywd) - 1;
  int popup = -1;
  *length = 0;
  if (!strncmp(msg, keywd, kwdlen)) {
    msg += kwdlen;
    if (!strncmp(msg, "popup", 5)) {
      popup = 1;
      *length = kwdlen + 5 + (msg[5] == '\n' ? 1 : 0);
    } else if (!strncmp(msg, "popdown", 7)) {
      popup = 0;
      *length = kwdlen + 7 + (msg[7] == '\n' ? 1 : 0);
    }
  }
  return popup;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<parse_callui_notification>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  movl   $0x0,(%rsi)
  mov    $0x7,%edx
  lea    D29(%rip),%rsi
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0xffffffff,%eax
  test   %edx,%edx
  je     L37
L20:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  lea    0x7(%rbx),%r12
  mov    $0x5,%edx
  lea    D24(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L23
  cmpb   $0xa,0xc(%rbx)
  sete   %al
  movzbl %al,%eax
  add    $0xc,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x1,%eax
  jmp    L20
L23:
  mov    $0x7,%edx
  lea    D7(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L10
  cmpb   $0xa,0xe(%rbx)
  sete   %dl
  movzbl %dl,%edx
  add    $0xe,%edx
  mov    %edx,0x0(%rbp)
  jmp    L20
L10:
  mov    $0xffffffff,%eax
  jmp    L20
```

tool_calls: name: parse_data
arguments: data_label: D24
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D24: popup

tool: D7: popdown

assistant: ```c
int parse_callui_notification(char *msg, int *length) {
  static char keywd[] = "callui ";
  int kwdlen = sizeof(keywd) - 1;
  int popup = -1;
  *length = 0;
  if (!strncmp(msg, keywd, kwdlen)) {
    msg += kwdlen;
    if (!strncmp(msg, "popup", 5)) {
      popup = 1;
      *length = kwdlen + 5 + (msg[5] == '\n' ? 1 : 0);
    } else if (!strncmp(msg, "popdown", 7)) {
      popup = 0;
      *length = kwdlen + 7 + (msg[7] == '\n' ? 1 : 0);
    }
  }
  return popup;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_callui_notification>:
  endbr64
  push   %r12
  mov    $0x7,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  lea    D17(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L27
L10:
  mov    $0xffffffff,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  lea    0x7(%rbx),%r12
  mov    $0x5,%edx
  lea    D16(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L30
  xor    %eax,%eax
  cmpb   $0xa,0xc(%rbx)
  pop    %rbx
  sete   %al
  add    $0xc,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L30:
  mov    $0x7,%edx
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L10
  xor    %edx,%edx
  cmpb   $0xa,0xe(%rbx)
  sete   %dl
  add    $0xe,%edx
  mov    %edx,0x0(%rbp)
  jmp    L21
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string

tool: D16: popup

tool: D10: popdown

assistant: ```c
int parse_callui_notification(char *msg, int *length) {
  static char keywd[] = "callui ";
  int kwdlen = sizeof(keywd) - 1;
  int popup = -1;
  *length = 0;
  if (!strncmp(msg, keywd, kwdlen)) {
    msg += kwdlen;
    if (!strncmp(msg, "popup", 5)) {
      popup = 1;
      *length = kwdlen + 5 + (msg[5] == '\n' ? 1 : 0);
    } else if (!strncmp(msg, "popdown", 7)) {
      popup = 0;
      *length = kwdlen + 7 + (msg[7] == '\n' ? 1 : 0);
    }
  }
  return popup;
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_callui_notification>:
  endbr64
  push   %r12
  mov    $0x7,%edx
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  movl   $0x0,(%rsi)
  lea    D15(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L0
L6:
  mov    $0xffffffff,%eax
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  lea    0x7(%rbx),%r12
  mov    $0x5,%edx
  lea    D21(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L38
  xor    %eax,%eax
  cmpb   $0xa,0xc(%rbx)
  pop    %rbx
  sete   %al
  add    $0xc,%eax
  mov    %eax,0x0(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L38:
  mov    $0x7,%edx
  lea    D17(%rip),%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L6
  xor    %edx,%edx
  cmpb   $0xa,0xe(%rbx)
  sete   %dl
  add    $0xe,%edx
  mov    %edx,0x0(%rbp)
  jmp    L21
```

tool_calls: name: disassemble_data
arguments: data_label: D21
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string

tool: D21: popup

tool: D17: popdown

assistant: ```c
int parse_callui_notification(char *msg, int *length) {
  static char keywd[] = "callui ";
  int kwdlen = sizeof(keywd) - 1;
  int popup = -1;
  *length = 0;
  if (!strncmp(msg, keywd, kwdlen)) {
    msg += kwdlen;
    if (!strncmp(msg, "popup", 5)) {
      popup = 1;
      *length = kwdlen + 5 + (msg[5] == '\n' ? 1 : 0);
    } else if (!strncmp(msg, "popdown", 7)) {
      popup = 0;
      *length = kwdlen + 7 + (msg[7] == '\n' ? 1 : 0);
    }
  }
  return popup;
}
```