ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<str_allcaps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L20
  mov    $0x0,%eax
  jmp    L53
L20:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L78
  mov    $0x0,%eax
  jmp    L53
L78:
  movl   $0x0,-0x4(%rbp)
  jmp    L74
L51:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L4
  addl   $0x1,-0x4(%rbp)
L4:
  addq   $0x1,-0x18(%rbp)
L74:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L51
  cmpl   $0x0,-0x4(%rbp)
  je     L82
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L82:
  movl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
L53:
  leave
  ret
```

assistant: ```c
int str_allcaps(char *s) {
  int x;
  if (!s)
    return 0;
  if (strlen(s) == 0)
    return 0;
  x = 0;
  while (*s) {
    if (islower(*s))
      x++;
    s++;
  }
  if (x)
    x = 0;
  else
    x = 1;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<str_allcaps>:
  endbr64
  test   %rdi,%rdi
  je     L27
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  mov    $0x0,%eax
  test   %dil,%dil
  je     L5
  mov    $0x0,%ebp
L22:
  movsbl %dil,%edi
  call   <islower@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L22
  test   %ebp,%ebp
  sete   %al
  movzbl %al,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int str_allcaps(char *s) {
  int x;
  if (!s)
    return 0;
  if (strlen(s) == 0)
    return 0;
  x = 0;
  while (*s) {
    if (islower(*s))
      x++;
    s++;
  }
  if (x)
    x = 0;
  else
    x = 1;
  return x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str_allcaps>:
  endbr64
  test   %rdi,%rdi
  je     L22
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
  xor    %ebp,%ebp
  xchg   %ax,%ax
L1:
  call   <islower@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
  xor    %eax,%eax
  test   %ebp,%ebp
  sete   %al
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_allcaps(char *s) {
  int x;
  if (!s)
    return 0;
  if (strlen(s) == 0)
    return 0;
  x = 0;
  while (*s) {
    if (islower(*s))
      x++;
    s++;
  }
  if (x)
    x = 0;
  else
    x = 1;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_allcaps>:
  endbr64
  test   %rdi,%rdi
  je     L21
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L4
  xor    %ebp,%ebp
  xchg   %ax,%ax
L28:
  call   <islower@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L28
  xor    %eax,%eax
  test   %ebp,%ebp
  sete   %al
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  xor    %eax,%eax
  ret
```

assistant: ```c
int str_allcaps(char *s) {
  int x;
  if (!s)
    return 0;
  if (strlen(s) == 0)
    return 0;
  x = 0;
  while (*s) {
    if (islower(*s))
      x++;
    s++;
  }
  if (x)
    x = 0;
  else
    x = 1;
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fvec_inner_product>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L10
L2:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L2
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double fvec_inner_product(const float *v1, const float *v2, long n) {
  long i;
  double res = 0;
  for (i = 0; i < n; i++) {
    res += v1[i] * v2[i];
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fvec_inner_product>:
  endbr64
  test   %rdx,%rdx
  jle    L26
  pxor   %xmm1,%xmm1
  mov    $0x0,%eax
L22:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L22
L13:
  movapd %xmm1,%xmm0
  ret
L26:
  pxor   %xmm1,%xmm1
  jmp    L13
```

assistant: ```c
double fvec_inner_product(const float *v1, const float *v2, long n) {
  long i;
  double res = 0;
  for (i = 0; i < n; i++) {
    res += v1[i] * v2[i];
  }
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fvec_inner_product>:
  endbr64
  pxor   %xmm1,%xmm1
  test   %rdx,%rdx
  jle    L12
  xor    %eax,%eax
  nop
L14:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L14
L12:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double fvec_inner_product(const float *v1, const float *v2, long n) {
  long i;
  double res = 0;
  for (i = 0; i < n; i++) {
    res += v1[i] * v2[i];
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fvec_inner_product>:
  endbr64
  pxor   %xmm1,%xmm1
  test   %rdx,%rdx
  jle    L11
  xor    %eax,%eax
  nop
L12:
  movss  (%rdi,%rax,4),%xmm0
  mulss  (%rsi,%rax,4),%xmm0
  add    $0x1,%rax
  cvtss2sd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  cmp    %rax,%rdx
  jne    L12
L11:
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double fvec_inner_product(const float *v1, const float *v2, long n) {
  long i;
  double res = 0;
  for (i = 0; i < n; i++) {
    res += v1[i] * v2[i];
  }
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  movslq %eax,%rdx
  shl    $0x2,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  shl    $0x2,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L28:
  cmp    %rdx,%rsp
  je     L12
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L28
L12:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L6
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L6:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <bar@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int foo(int i) {
  struct S {
    int ar[1][i];
  } s;
  s.ar[0][0] = 0;
  bar(&s.ar[0][0]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movslq %edi,%rdi
  lea    0xf(,%rdi,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L13:
  cmp    %rdx,%rsp
  je     L1
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L13
L1:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L4
  orq    $0x0,-0x8(%rsp,%rax,1)
L4:
  lea    0x3(%rsp),%rdi
  mov    %rdi,%rax
  shr    $0x2,%rax
  and    $0xfffffffffffffffc,%rdi
  movl   $0x0,0x0(,%rax,4)
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  leave
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int foo(int i) {
  struct S {
    int ar[1][i];
  } s;
  s.ar[0][0] = 0;
  bar(&s.ar[0][0]);
}
```
user: What is the c source code of the assembly code below?

```asm
<foo>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdi,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L15
L32:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L32
L15:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L48
L13:
  lea    0x3(%rsp),%rdi
  mov    %rdi,%rax
  and    $0xfffffffffffffffc,%rdi
  shr    $0x2,%rax
  movl   $0x0,0x0(,%rax,4)
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  leave
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L48:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L13
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int foo(int i) {
  struct S {
    int ar[1][i];
  } s;
  s.ar[0][0] = 0;
  bar(&s.ar[0][0]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<foo>:
  endbr64
  push   %rbp
  movslq %edi,%rdi
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    0xf(,%rdi,4),%rax
  mov    %rsp,%rcx
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L14
L2:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L2
L14:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L46
L30:
  lea    0x3(%rsp),%rdi
  mov    %rdi,%rax
  and    $0xfffffffffffffffc,%rdi
  shr    $0x2,%rax
  movl   $0x0,0x0(,%rax,4)
  call   <bar@plt>
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  leave
  xor    %eax,%eax
  ret
  nopl   0x0(%rax)
L46:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L30
L49:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
__attribute__((always_)) int foo(int i) {
  struct S {
    int ar[1][i];
  } s;
  s.ar[0][0] = 0;
  bar(&s.ar[0][0]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xstrcasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L32
  mov    $0x0,%eax
  jmp    L0
L32:
  cmpq   $0x0,-0x8(%rbp)
  je     L9
  cmpq   $0x0,-0x10(%rbp)
  jne    L49
L9:
  mov    $0x1,%eax
  jmp    L0
L49:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
L0:
  leave
  ret
```

assistant: ```c
int xstrcasecmp(const char *s1, const char *s2) {
  if (s1 == s2)
    return 0;
  if (s1 == 0 || s2 == 0)
    return 1;
  return strcasecmp(s1, s2);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xstrcasecmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L8
  test   %rdi,%rdi
  je     L4
  test   %rsi,%rsi
  je     L4
  sub    $0x8,%rsp
  call   <strcasecmp@plt>
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  ret
L4:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int xstrcasecmp(const char *s1, const char *s2) {
  if (s1 == s2)
    return 0;
  if (s1 == 0 || s2 == 0)
    return 1;
  return strcasecmp(s1, s2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xstrcasecmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L25
  test   %rdi,%rdi
  je     L10
  test   %rsi,%rsi
  je     L10
  jmp    1050 <strcasecmp@plt>
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xstrcasecmp(const char *s1, const char *s2) {
  if (s1 == s2)
    return 0;
  if (s1 == 0 || s2 == 0)
    return 1;
  return strcasecmp(s1, s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xstrcasecmp>:
  endbr64
  cmp    %rsi,%rdi
  je     L3
  test   %rdi,%rdi
  je     L20
  test   %rsi,%rsi
  je     L20
  jmp    1050 <strcasecmp@plt>
  nopl   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xstrcasecmp(const char *s1, const char *s2) {
  if (s1 == s2)
    return 0;
  if (s1 == 0 || s2 == 0)
    return 1;
  return strcasecmp(s1, s2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ch_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x14(%rbp),%eax
  mov    %al,-0x9(%rbp)
  lea    -0x9(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <asc_str@plt>
  cltq
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char *ch_str(ch)
int ch;
{
  char tmp[1];
  tmp[0] = ch;
  return asc_str(tmp, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ch_str>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  mov    $0x1,%esi
  call   <asc_str@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  cltq
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ch_str(ch)
int ch;
{
  char tmp[1];
  tmp[0] = ch;
  return asc_str(tmp, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ch_str>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  call   <asc_str@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ch_str(ch)
int ch;
{
  char tmp[1];
  tmp[0] = ch;
  return asc_str(tmp, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ch_str>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %dil,0x7(%rsp)
  lea    0x7(%rsp),%rdi
  call   <asc_str@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  cltq
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ch_str(ch)
int ch;
{
  char tmp[1];
  tmp[0] = ch;
  return asc_str(tmp, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<bitzero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,%rax
  mov    %esi,%ecx
  lea    0x1f(%rcx),%edi
  test   %ecx,%ecx
  cmovs  %edi,%ecx
  sar    $0x5,%ecx
  movslq %ecx,%rcx
  shl    $0x2,%rcx
  add    %rcx,%rax
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  mov    %ecx,%edi
  shr    $0x1b,%edi
  lea    (%rsi,%rdi,1),%ecx
  and    $0x1f,%ecx
  sub    %edi,%ecx
  mov    %ecx,%esi
  lea    (%rsi,%rdx,1),%ecx
  cmp    $0x1f,%ecx
  jle    L17
  mov    (%rax),%edi
  mov    $0x1,%r8d
  mov    %esi,%ecx
  shl    %cl,%r8d
  mov    %r8d,%ecx
  neg    %ecx
  and    %edi,%ecx
  mov    %ecx,(%rax)
  sub    %esi,%edx
  add    $0x4,%rax
  mov    $0x0,%esi
  jmp    L17
L1:
  mov    %rax,%rcx
  lea    0x4(%rcx),%rax
  movl   $0x0,(%rcx)
  sub    $0x20,%edx
L17:
  cmp    $0x1f,%edx
  jg     L1
  test   %edx,%edx
  jle    L15
  mov    (%rax),%edi
  mov    $0x1,%r8d
  mov    %edx,%ecx
  shl    %cl,%r8d
  mov    %r8d,%edx
  sub    $0x1,%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  not    %edx
  and    %edi,%edx
  mov    %edx,(%rax)
L15:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bitzero(register uint *e, register uint p, register uint len) {
  e += p / (32);
  p %= (32);
  if (p + len >= (32)) {
    *e &= ~((1 << p) - 1);
    len -= p;
    e++;
    p = 0;
  }
  while (len >= (32)) {
    *e++ = 0;
    len -= (32);
  }
  if (len > 0)
    *e &= ~(((1 << len) - 1) << p);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bitzero>:
  endbr64
  mov    %esi,%ecx
  mov    %edx,%esi
  lea    0x1f(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rdi,%rax,4),%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  shr    $0x1b,%edi
  lea    (%rcx,%rdi,1),%edx
  and    $0x1f,%edx
  sub    %edi,%edx
  mov    %edx,%edi
  lea    (%rdx,%rsi,1),%r8d
  cmp    $0x1f,%r8d
  jle    L0
  mov    $0x1,%edi
  shl    %cl,%edi
  neg    %edi
  and    %edi,(%rax)
  sub    %edx,%esi
  add    $0x4,%rax
  mov    $0x0,%edi
L0:
  cmp    $0x1f,%esi
  jle    L48
  lea    -0x20(%rsi),%ecx
  shr    $0x5,%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,%edx
  lea    (%rax,%rdx,4),%rdx
L41:
  add    $0x4,%rax
  movl   $0x0,-0x4(%rax)
  cmp    %rdx,%rax
  jne    L41
  neg    %ecx
  shl    $0x5,%ecx
  lea    -0x20(%rsi,%rcx,1),%esi
L6:
  test   %esi,%esi
  jle    L17
  mov    $0x1,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  sub    $0x1,%eax
  mov    %edi,%ecx
  shl    %cl,%eax
  not    %eax
  and    %eax,(%rdx)
L17:
  ret
L48:
  mov    %rax,%rdx
  jmp    L6
```

assistant: ```c
void bitzero(register uint *e, register uint p, register uint len) {
  e += p / (32);
  p %= (32);
  if (p + len >= (32)) {
    *e &= ~((1 << p) - 1);
    len -= p;
    e++;
    p = 0;
  }
  while (len >= (32)) {
    *e++ = 0;
    len -= (32);
  }
  if (len > 0)
    *e &= ~(((1 << len) - 1) << p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitzero>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  lea    0x1f(%rsi),%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  cmovns %esi,%edx
  sar    $0x5,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rdi
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x1b,%edx
  lea    (%rsi,%rdx,1),%ebx
  and    $0x1f,%ebx
  sub    %edx,%ebx
  lea    (%rbx,%r13,1),%edx
  cmp    $0x1f,%edx
  jle    L8
  mov    $0x1,%edx
  mov    %esi,%ecx
  sub    %ebx,%r13d
  xor    %ebx,%ebx
  shl    %cl,%edx
  neg    %edx
  and    %edx,(%rdi)
  add    $0x4,%rdi
L8:
  cmp    $0x1f,%r13d
  jle    L13
  sub    $0x20,%r13d
  xor    %esi,%esi
  mov    %r13d,%r12d
  shr    $0x5,%r12d
  lea    0x1(%r12),%ebp
  shl    $0x5,%r12d
  shl    $0x2,%rbp
  sub    %r12d,%r13d
  mov    %rbp,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %rbp,%rdi
L13:
  test   %r13d,%r13d
  jle    L26
  mov    %r13d,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  mov    %ebx,%ecx
  lea    -0x1(%rdx),%eax
  shl    %cl,%eax
  not    %eax
  and    %eax,(%rdi)
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bitzero(register uint *e, register uint p, register uint len) {
  e += p / (32);
  p %= (32);
  if (p + len >= (32)) {
    *e &= ~((1 << p) - 1);
    len -= p;
    e++;
    p = 0;
  }
  while (len >= (32)) {
    *e++ = 0;
    len -= (32);
  }
  if (len > 0)
    *e &= ~(((1 << len) - 1) << p);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitzero>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  lea    0x1f(%rsi),%edx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  cmovns %esi,%edx
  sar    $0x5,%edx
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rdi
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x1b,%edx
  lea    (%rsi,%rdx,1),%ebx
  and    $0x1f,%ebx
  sub    %edx,%ebx
  lea    (%rbx,%r13,1),%edx
  cmp    $0x1f,%edx
  jle    L25
  mov    $0x1,%edx
  mov    %esi,%ecx
  sub    %ebx,%r13d
  xor    %ebx,%ebx
  shl    %cl,%edx
  neg    %edx
  and    %edx,(%rdi)
  add    $0x4,%rdi
L25:
  cmp    $0x1f,%r13d
  jle    L14
  sub    $0x20,%r13d
  xor    %esi,%esi
  mov    %r13d,%r12d
  shr    $0x5,%r12d
  lea    0x1(%r12),%ebp
  shl    $0x5,%r12d
  shl    $0x2,%rbp
  sub    %r12d,%r13d
  mov    %rbp,%rdx
  call   <memset@plt>
  mov    %rax,%rdi
  add    %rbp,%rdi
L14:
  test   %r13d,%r13d
  jle    L9
  mov    %r13d,%ecx
  mov    $0x1,%edx
  shl    %cl,%edx
  mov    %ebx,%ecx
  lea    -0x1(%rdx),%eax
  shl    %cl,%eax
  not    %eax
  and    %eax,(%rdi)
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void bitzero(register uint *e, register uint p, register uint len) {
  e += p / (32);
  p %= (32);
  if (p + len >= (32)) {
    *e &= ~((1 << p) - 1);
    len -= p;
    e++;
    p = 0;
  }
  while (len >= (32)) {
    *e++ = 0;
    len -= (32);
  }
  if (len > 0)
    *e &= ~(((1 << len) - 1) << p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strpbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L54
L31:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L12
L7:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L52
  mov    -0x18(%rbp),%rax
  jmp    L3
L52:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
  addq   $0x1,-0x18(%rbp)
L54:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0x0,%eax
L3:
  pop    %rbp
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  char *p;
  while (*s1) {
    for (p = s2; *p; p++)
      if (*s1 == *p)
        return s1;
    s1++;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strpbrk>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%r8d
  test   %r8b,%r8b
  je     L18
  movzbl (%rsi),%edi
L29:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  je     L10
L13:
  cmp    %r8b,%dl
  je     L20
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L13
L10:
  add    $0x1,%rax
  movzbl (%rax),%r8d
  test   %r8b,%r8b
  jne    L29
  mov    $0x0,%eax
L20:
  ret
L18:
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  char *p;
  while (*s1) {
    for (p = s2; *p; p++)
      if (*s1 == *p)
        return s1;
    s1++;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L8
  movzbl (%rsi),%edi
L23:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L11
  jmp    L44
  nop
L56:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L44
L11:
  cmp    %r8b,%dl
  jne    L56
  ret
  nopw   0x0(%rax,%rax,1)
L44:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L23
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  char *p;
  while (*s1) {
    for (p = s2; *p; p++)
      if (*s1 == *p)
        return s1;
    s1++;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%r8d
  mov    %rdi,%rax
  test   %r8b,%r8b
  je     L55
  movzbl (%rsi),%edi
L19:
  mov    %rsi,%rcx
  mov    %edi,%edx
  test   %dil,%dil
  jne    L57
  jmp    L7
  nop
L52:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L7
L57:
  cmp    %r8b,%dl
  jne    L52
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  movzbl 0x1(%rax),%r8d
  add    $0x1,%rax
  test   %r8b,%r8b
  jne    L19
L55:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s1, const char *s2) {
  char *p;
  while (*s1) {
    for (p = s2; *p; p++)
      if (*s1 == *p)
        return s1;
    s1++;
  }
  return 0;
}
```