user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  lea    -0x3c(%rbp),%rsi
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x3c(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,8),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L132
L61:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L61
L132:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L176
L102:
  mov    $0x32,%edi
  mov    %rsp,%r14
  call   <malloc@plt>
  cmpl   $0x0,-0x3c(%rbp)
  mov    %rax,-0x48(%rbp)
  mov    -0x3c(%rbp),%eax
  jle    L139
  xor    %ebx,%ebx
  nop
L138:
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,(%r14,%rbx,8)
  mov    -0x3c(%rbp),%eax
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L138
  test   %eax,%eax
  jle    L139
  xor    %ebx,%ebx
  lea    D22(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L66:
  mov    (%r14,%rbx,8),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    -0x3c(%rbp),%eax
  cmp    %ebx,%eax
  jg     L66
  cmp    $0x1,%eax
  jle    L30
L147:
  xor    %r13d,%r13d
  lea    -0x1(%rax),%edx
  nopl   0x0(%rax)
L118:
  cmp    %r13d,%edx
  jle    L162
  mov    (%r14),%r12
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L117:
  mov    %r12,%r15
  mov    0x8(%r14,%rbx,8),%r12
  mov    %r15,%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jle    L82
  mov    -0x48(%rbp),%rdi
  mov    %r15,%rsi
  call   <strcpy@plt>
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  mov    -0x48(%rbp),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L82:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%rbx
  lea    -0x1(%rax),%edx
  mov    %edx,%ecx
  sub    %r13d,%ecx
  cmp    %ebx,%ecx
  jg     L117
L162:
  add    $0x1,%r13d
  cmp    %edx,%r13d
  jl     L118
L30:
  xor    %ebx,%ebx
  lea    D25(%rip),%r12
  test   %eax,%eax
  jle    L76
  nopl   0x0(%rax)
L143:
  mov    (%r14,%rbx,8),%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,-0x3c(%rbp)
  jg     L143
L76:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L124
  lea    -0x28(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L176:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L102
L139:
  cmp    $0x1,%eax
  jg     L147
  jmp    L76
L124:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D22
type: string
name: retrieve_data
arguments: label: D25
type: string

tool: D13: %d

tool: D22: %s

tool: D25: %s 

assistant: ```c
int main() {
  int n, i, j;
  scanf("%d", &n);
  char *str[n], *temp = malloc(50);
  for (i = 0; i < n; i++) {
    str[i] = malloc(50);
  }
  for (i = 0; i < n; i++) {
    scanf("%s", str[i]);
  }
  for (i = 0; i < n - 1; i++) {
    for (j = 0; j < n - 1 - i; j++) {
      if (strcmp(str[j], str[j + 1]) > 0) {
        strcpy(temp, str[j]);
        strcpy(str[j], str[j + 1]);
        strcpy(str[j + 1], temp);
      }
    }
  }
  for (i = 0; i < n; i++) {
    printf("%s ", str[i]);
  }
  printf("\n");
  return 0;
}
```