user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <queue_create@plt>
  test   %rax,%rax
  je     L3
  mov    %rax,%rbp
  mov    %rax,%rdi
  lea    D13(%rip),%r14
  call   <queue_pop@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  lea    D15(%rip),%r13
  call   <queue_push@plt>
  mov    $0x5,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  lea    D16(%rip),%r12
  call   <queue_front@plt>
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_back@plt>
  mov    %r12,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x9,%esi
  mov    %rbp,%rdi
  call   <queue_push@plt>
  mov    $0x9,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_front@plt>
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_back@plt>
  mov    %r12,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <queue_push@plt>
  mov    $0x3,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_front@plt>
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_back@plt>
  mov    %r12,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_pop@plt>
  lea    D30(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <queue_front@plt>
  mov    %r13,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_back@plt>
  mov    %r12,%rdi
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <queue_destroy@plt>
  xor    %eax,%eax
L12:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  lea    D40(%rip),%rdi
  call   <puts@plt>
  or     $0xffffffff,%eax
  jmp    L12
```

tool_calls: name: parse_data
arguments: label: D13
data_type: string
name: parse_data
arguments: label: D15
data_type: string
name: parse_data
arguments: label: D16
data_type: string
name: parse_data
arguments: label: D30
data_type: string
name: parse_data
arguments: label: D40
data_type: string

tool: D13: push '%d' into queue


tool: D15: front of the queue is %d


tool: D16: back of the queue is %d


tool: D30: pop the front item of the queue

tool: D40: creating queue failed

assistant: ```c
int main(void) {
  int val;
  void *instance;
  int *tmp;
  instance = queue_create();
  if (instance == NULL) {
    printf("creating queue failed\n");
    return -1;
  }
  queue_pop(instance);
  val = 5;
  queue_push(instance, val);
  printf("push '%d' into queue\n", val);
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  val = 9;
  queue_push(instance, val);
  printf("push '%d' into queue\n", val);
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  val = 3;
  queue_push(instance, val);
  printf("push '%d' into queue\n", val);
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  queue_pop(instance);
  printf("pop the front item of the queue\n");
  tmp = queue_front(instance);
  printf("front of the queue is %d\n", *tmp);
  tmp = queue_back(instance);
  printf("back of the queue is %d\n", *tmp);
  queue_destroy(instance);
  return 0;
}
```