user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0xffffffff,-0x54(%rbp)
  lea    -0x58(%rbp),%rdx
  lea    -0x5c(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x5c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L47:
  cmp    %rdx,%rsp
  je     L60
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L47
L60:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L98
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L98:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L71
L95:
  mov    -0x50(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x50(%rbp)
L71:
  mov    -0x5c(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L95
  mov    -0x5c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  jmp    L4
L75:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x58(%rbp),%eax
  cmp    %eax,%edx
  jne    L1
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x54(%rbp)
L1:
  subl   $0x1,-0x4c(%rbp)
L4:
  cmpl   $0x0,-0x4c(%rbp)
  jg     L75
  cmpl   $0xffffffff,-0x54(%rbp)
  jne    L31
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L31:
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L50
  call   <__stack_chk_fail@plt>
L50:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D25
data_type: string
name: extract_symbolic_data
arguments: data_label: D4
data_type: string
name: extract_symbolic_data
arguments: data_label: D24
data_type: string

tool: D25: %d %d

tool: D4: %d

tool: D24: %i

assistant: ```c
int main() {
  int size, count = -1, term;
  scanf("%d %d", &size, &term);
  int arr[size];
  for (int a = 0; a < size; a++)
    scanf("%d", &arr[a]);
  for (int a = size - 1; a > 0; a--) {
    if (arr[a] == term) {
      printf("%i", a + 1);
      count = 0;
    }
  }
  if (count == -1)
    printf("%i", count);
  return 0;
}
```