ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<float2_interpolator_c>:
  endbr64
  movss  (%rdi),%xmm5
  movss  (%rsi),%xmm4
  mulss  %xmm0,%xmm5
  mulss  %xmm1,%xmm4
  subss  %xmm5,%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm5,%xmm4
  divss  %xmm3,%xmm4
  movss  %xmm4,(%rdx)
  mulss  0x4(%rdi),%xmm0
  mulss  0x4(%rsi),%xmm1
  subss  %xmm0,%xmm1
  mulss  %xmm1,%xmm2
  addss  %xmm0,%xmm2
  divss  %xmm3,%xmm2
  movss  %xmm2,0x4(%rdx)
  ret
```

assistant: ```c
void float2_interpolator_c(float *s, float s_invw, float *e, float e_invw, float t, float *r, float r_invw) {
  int i;
  for (i = 0; i < 2; i++) {
    float ts = s[i] * s_invw;
    float te = e[i] * e_invw;
    r[i] = (ts + (te - ts) * t) / r_invw;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%eax
  lea    0x76c(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    -0x10(%rbp),%rcx
  mov    (%rcx),%ecx
  lea    0x1(%rcx),%esi
  mov    %edx,%ecx
  mov    %eax,%edx
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string

tool: D3: %i/%i/%i


assistant: ```c
int main() {
  time_t currentTime;
  time(&currentTime);
  struct tm *myTime = localtime(&currentTime);
  printf("%i/%i/%i\n", myTime->tm_mon + 1, myTime->tm_mday, myTime->tm_year + 1900);
  printf("%s\n", ctime(&currentTime));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <localtime@plt>
  mov    0x8(%rax),%edx
  lea    0x76c(%rdx),%ecx
  mov    0x4(%rax),%edx
  mov    (%rax),%esi
  add    $0x1,%esi
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_infered: string

tool: D2: %i/%i/%i


assistant: ```c
int main() {
  time_t currentTime;
  time(&currentTime);
  struct tm *myTime = localtime(&currentTime);
  printf("%i/%i/%i\n", myTime->tm_mon + 1, myTime->tm_mday, myTime->tm_year + 1900);
  printf("%s\n", ctime(&currentTime));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D5(%rip),%rdi
  mov    0x8(%rax),%edx
  mov    (%rax),%esi
  lea    0x76c(%rdx),%ecx
  mov    0x4(%rax),%edx
  add    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
datatype: string

tool: D5: %i/%i/%i


assistant: ```c
int main() {
  time_t currentTime;
  time(&currentTime);
  struct tm *myTime = localtime(&currentTime);
  printf("%i/%i/%i\n", myTime->tm_mon + 1, myTime->tm_mday, myTime->tm_year + 1900);
  printf("%s\n", ctime(&currentTime));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <localtime@plt>
  lea    D4(%rip),%rdi
  mov    0x8(%rax),%edx
  mov    (%rax),%esi
  lea    0x76c(%rdx),%ecx
  mov    0x4(%rax),%edx
  add    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: %i/%i/%i


assistant: ```c
int main() {
  time_t currentTime;
  time(&currentTime);
  struct tm *myTime = localtime(&currentTime);
  printf("%i/%i/%i\n", myTime->tm_mon + 1, myTime->tm_mday, myTime->tm_year + 1900);
  printf("%s\n", ctime(&currentTime));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maximum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L3
  movsd  -0x8(%rbp),%xmm0
  jmp    L16
L3:
  movsd  -0x10(%rbp),%xmm0
L16:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double maximum(double a, double b) {
  if (a > b) {
    return (a);
  }
  return (b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<maximum>:
  endbr64
  maxsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double maximum(double a, double b) {
  if (a > b) {
    return (a);
  }
  return (b);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<maximum>:
  endbr64
  maxsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double maximum(double a, double b) {
  if (a > b) {
    return (a);
  }
  return (b);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ceil_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x20,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L22
  mov    -0xc(%rbp),%eax
  jmp    L39
L22:
  mov    $0x0,%eax
L39:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sarl   %cl,-0x14(%rbp)
  sarl   -0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L34:
  cmpl   $0x5,-0x8(%rbp)
  jle    L7
  mov    -0x10(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: 

assistant: ```c
int ceil_log2(uint64_t x) {
  static const uint64_t t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i, k;
  for (i = 0; i < 6; i++) {
    k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ceil_log2>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %edi,%eax
  setne  %sil
  movzbl %sil,%esi
  lea    D6(%rip),%rax
  lea    0x14(%rax),%r8
  mov    $0x20,%edx
  mov    $0x0,%ecx
L11:
  add    %ecx,%esi
  sar    %cl,%edi
  sar    %edx
  cmp    %rax,%r8
  je     L13
  mov    %edi,%ecx
  and    0x4(%rax),%ecx
  cmovne %edx,%ecx
  add    $0x4,%rax
  jmp    L11
L13:
  mov    %esi,%eax
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
type_infered: string

tool: 

assistant: ```c
int ceil_log2(uint64_t x) {
  static const uint64_t t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i, k;
  for (i = 0; i < 6; i++) {
    k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<ceil_log2>:
  endbr64
  lea    -0x1(%rdi),%eax
  xor    %r8d,%r8d
  mov    $0x20,%edx
  test   %edi,%eax
  lea    D6(%rip),%rax
  setne  %r8b
  lea    0x14(%rax),%rsi
  xor    %ecx,%ecx
  jmp    L10
  nopl   0x0(%rax)
L7:
  mov    %edi,%ecx
  and    0x4(%rax),%ecx
  cmovne %edx,%ecx
  add    $0x4,%rax
L10:
  add    %ecx,%r8d
  sar    %cl,%edi
  sar    %edx
  cmp    %rsi,%rax
  jne    L7
  mov    %r8d,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: 

assistant: ```c
int ceil_log2(uint64_t x) {
  static const uint64_t t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i, k;
  for (i = 0; i < 6; i++) {
    k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: What is the c source code of the assembly code below:

```asm
<ceil_log2>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %edi,%eax
  setne  %al
  xor    %ecx,%ecx
  test   $0xffff0000,%edi
  setne  %cl
  movzbl %al,%eax
  shl    $0x4,%ecx
  sar    %cl,%edi
  add    %ecx,%eax
  xor    %ecx,%ecx
  test   $0xff00,%edi
  setne  %cl
  shl    $0x3,%ecx
  sar    %cl,%edi
  add    %ecx,%eax
  xor    %ecx,%ecx
  test   $0xf0,%dil
  setne  %cl
  shl    $0x2,%ecx
  sar    %cl,%edi
  add    %ecx,%eax
  xor    %ecx,%ecx
  test   $0xc,%dil
  setne  %cl
  add    %ecx,%ecx
  lea    (%rax,%rcx,1),%edx
  mov    %edi,%eax
  sar    %cl,%eax
  shr    %eax
  and    $0x1,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int ceil_log2(uint64_t x) {
  static const uint64_t t[6] = {0xFFFFFFFF00000000ull, 0x00000000FFFF0000ull, 0x000000000000FF00ull, 0x00000000000000F0ull, 0x000000000000000Cull, 0x0000000000000002ull};
  int y = (((x & (x - 1)) == 0) ? 0 : 1);
  int j = 32;
  int i, k;
  for (i = 0; i < 6; i++) {
    k = (((x & t[i]) == 0) ? 0 : j);
    y += k;
    x >>= k;
    j >>= 1;
  }
  return y;
}
```
user: What is the c source code of the assembly code below:

```asm
<handle_error>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void handle_error(char *error) {
  ;
  exit(-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<handle_error>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void handle_error(char *error) {
  ;
  exit(-1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<handle_error>:
  endbr64
  mov    $0xffffffff,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void handle_error(char *error) {
  ;
  exit(-1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<handle_error>:
  endbr64
  mov    $0xffffffff,%edi
  jmp    1050 <exit@plt>
```

assistant: ```c
void handle_error(char *error) {
  ;
  exit(-1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_rename@plt>
  mov    $0x0,%eax
  call   <test_eq@plt>
  mov    $0x0,%eax
  call   <test_cpy@plt>
  mov    $0x0,%eax
  call   <test_join@plt>
  mov    $0x0,%eax
  call   <test_project@plt>
  mov    $0x0,%eax
  call   <test_common@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  test_rename();
  test_eq();
  test_cpy();
  test_join();
  test_project();
  test_common();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_rename@plt>
  mov    $0x0,%eax
  call   <test_eq@plt>
  mov    $0x0,%eax
  call   <test_cpy@plt>
  mov    $0x0,%eax
  call   <test_join@plt>
  mov    $0x0,%eax
  call   <test_project@plt>
  mov    $0x0,%eax
  call   <test_common@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_rename();
  test_eq();
  test_cpy();
  test_join();
  test_project();
  test_common();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_rename@plt>
  xor    %eax,%eax
  call   <test_eq@plt>
  xor    %eax,%eax
  call   <test_cpy@plt>
  xor    %eax,%eax
  call   <test_join@plt>
  xor    %eax,%eax
  call   <test_project@plt>
  xor    %eax,%eax
  call   <test_common@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_rename();
  test_eq();
  test_cpy();
  test_join();
  test_project();
  test_common();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_rename@plt>
  xor    %eax,%eax
  call   <test_eq@plt>
  xor    %eax,%eax
  call   <test_cpy@plt>
  xor    %eax,%eax
  call   <test_join@plt>
  xor    %eax,%eax
  call   <test_project@plt>
  xor    %eax,%eax
  call   <test_common@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  test_rename();
  test_eq();
  test_cpy();
  test_join();
  test_project();
  test_common();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<stopTimer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x50(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  lea    -0x30(%rbp),%rdx
  lea    -0x50(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <setitimer@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void stopTimer(void) {
  struct itimerval value, ovalue;
  value.it_value.tv_sec = 0;
  value.it_value.tv_usec = 0;
  value.it_interval.tv_sec = 0;
  value.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &value, &ovalue);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<stopTimer>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,(%rsp)
  lea    0x20(%rsp),%rdx
  mov    %rsp,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stopTimer(void) {
  struct itimerval value, ovalue;
  value.it_value.tv_sec = 0;
  value.it_value.tv_usec = 0;
  value.it_interval.tv_sec = 0;
  value.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &value, &ovalue);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<stopTimer>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  lea    0x20(%rsp),%rdx
  mov    %rsp,%rsi
  movq   $0x0,0x18(%rsp)
  mov    (%rax),%edi
  movq   $0x0,(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x8(%rsp)
  call   <setitimer@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x58,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stopTimer(void) {
  struct itimerval value, ovalue;
  value.it_value.tv_sec = 0;
  value.it_value.tv_usec = 0;
  value.it_interval.tv_sec = 0;
  value.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &value, &ovalue);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<stopTimer>:
  endbr64
  sub    $0x58,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  lea    0x20(%rsp),%rdx
  movaps %xmm0,0x10(%rsp)
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x58,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void stopTimer(void) {
  struct itimerval value, ovalue;
  value.it_value.tv_sec = 0;
  value.it_value.tv_usec = 0;
  value.it_interval.tv_sec = 0;
  value.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &value, &ovalue);
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L0:
  mov    -0x14(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  cwtl
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    (%rdx,%rdx,1),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <abs@plt>
  mov    %ax,(%rbx)
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x270f,-0x14(%rbp)
  jle    L0
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void test(short *a, short *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x0,%ebx
L7:
  movswl 0x0(%rbp,%rbx,1),%edi
  call   <abs@plt>
  mov    %ax,(%r12,%rbx,1)
  add    $0x2,%rbx
  cmp    $0x4e20,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test(short *a, short *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L1:
  movswl 0x0(%rbp,%rbx,1),%edi
  call   <abs@plt>
  mov    %ax,(%r12,%rbx,1)
  add    $0x2,%rbx
  cmp    $0x4e20,%rbx
  jne    L1
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test(short *a, short *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
L5:
  movswl 0x0(%rbp,%rbx,1),%edi
  call   <abs@plt>
  mov    %ax,(%r12,%rbx,1)
  add    $0x2,%rbx
  cmp    $0x4e20,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test(short *a, short *b) {
  int i;
  for (i = 0; i < 10000; ++i)
    a[i] = abs(b[i]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x2faf0000(%rsp),%r11
L133:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L133
  sub    $0x820,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x2faf0818(%rbp)
  jmp    L55
L36:
  movl   $0x0,-0x2faf0814(%rbp)
  jmp    L124
L102:
  mov    -0x2faf0818(%rbp),%eax
  imul   -0x2faf0814(%rbp),%eax
  mov    -0x2faf0814(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x2faf0818(%rbp),%edx
  movslq %edx,%rdx
  imul   $0x2710,%rdx,%rdx
  add    %rcx,%rdx
  mov    %eax,-0x2faf0810(%rbp,%rdx,4)
  addl   $0x1,-0x2faf0814(%rbp)
L124:
  cmpl   $0x270f,-0x2faf0814(%rbp)
  jle    L102
  addl   $0x1,-0x2faf0818(%rbp)
L55:
  cmpl   $0x270f,-0x2faf0818(%rbp)
  jle    L36
  movl   $0x1,-0x2faf0814(%rbp)
  jmp    L139
L0:
  movl   $0x0,-0x2faf0818(%rbp)
  jmp    L49
L93:
  mov    -0x2faf0814(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x2faf0818(%rbp),%eax
  cltq
  imul   $0x2710,%rax,%rax
  add    %rdx,%rax
  mov    -0x2faf0810(%rbp,%rax,4),%edx
  mov    -0x2faf0814(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x2faf0818(%rbp),%eax
  cltq
  imul   $0x2710,%rax,%rax
  add    %rcx,%rax
  mov    -0x17d78410(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x2faf0814(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x2faf0818(%rbp),%eax
  cltq
  imul   $0x2710,%rax,%rax
  add    %rcx,%rax
  mov    %edx,-0x2faf0810(%rbp,%rax,4)
  addl   $0x1,-0x2faf0818(%rbp)
L49:
  cmpl   $0x270f,-0x2faf0818(%rbp)
  jle    L93
  addl   $0x1,-0x2faf0814(%rbp)
L139:
  cmpl   $0x270f,-0x2faf0814(%rbp)
  jle    L0
  movl   $0x0,-0x2faf0818(%rbp)
  jmp    L35
L78:
  movl   $0x0,-0x2faf0814(%rbp)
  jmp    L23
L135:
  mov    -0x2faf0814(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x2faf0818(%rbp),%eax
  cltq
  imul   $0x2710,%rax,%rax
  add    %rdx,%rax
  mov    -0x2faf0810(%rbp,%rax,4),%eax
  mov    %eax,%edi
  call   <foo@plt>
  addl   $0x1,-0x2faf0814(%rbp)
L23:
  cmpl   $0x270f,-0x2faf0814(%rbp)
  jle    L135
  addl   $0x1,-0x2faf0818(%rbp)
L35:
  cmpl   $0x270f,-0x2faf0818(%rbp)
  jle    L78
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int test() {
  int a[10000][10000];
  int b[10000][10000];
  int i, j;
  for (i = 0; i < 10000; i++)
    for (j = 0; j < 10000; j++)
      a[i][j] = i * j;
  for (j = 1; j < 10000; j++)
    for (i = 0; i < 10000; i++)
      a[i][j] = a[i][j - 1] + b[i][j];
  for (i = 0; i < 10000; i++)
    for (j = 0; j < 10000; j++)
      foo(a[i][j]);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x2faf0000(%rsp),%r11
L45:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L45
  sub    $0x810,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2faf0808(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x9c40(%rsp),%rbp
  mov    %rbp,%rcx
  mov    $0x0,%edi
L6:
  mov    %edi,%esi
  lea    -0x9c40(%rcx),%rax
  mov    $0x0,%edx
L60:
  mov    %edx,(%rax)
  add    %esi,%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L60
  add    $0x1,%edi
  add    $0x9c40,%rcx
  cmp    $0x2710,%edi
  jne    L6
  lea    0x2faf0804(%rsp),%rsi
  lea    0x2fafa440(%rsp),%r8
  mov    %r12,%rdi
L18:
  lea    -0x17d78400(%rsi),%rdx
  mov    %rdi,%rax
L43:
  mov    (%rdx),%ecx
  add    (%rax),%ecx
  mov    %ecx,0x4(%rax)
  add    $0x9c40,%rdx
  add    $0x9c40,%rax
  cmp    %rsi,%rdx
  jne    L43
  add    $0x4,%rdi
  add    $0x4,%rsi
  cmp    %r8,%rsi
  jne    L18
  add    $0x17d82040,%r12
L37:
  lea    -0x9c40(%rbp),%rbx
L51:
  mov    (%rbx),%edi
  call   <foo@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L51
  add    $0x9c40,%rbp
  cmp    %rbp,%r12
  jne    L37
  mov    0x2faf0808(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    $0x0,%eax
  add    $0x2faf0810,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test() {
  int a[10000][10000];
  int b[10000][10000];
  int i, j;
  for (i = 0; i < 10000; i++)
    for (j = 0; j < 10000; j++)
      a[i][j] = i * j;
  for (j = 1; j < 10000; j++)
    for (i = 0; i < 10000; i++)
      a[i][j] = a[i][j - 1] + b[i][j];
  for (i = 0; i < 10000; i++)
    for (j = 0; j < 10000; j++)
      foo(a[i][j]);
}
```