ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<rand_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <frand@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L2
L26:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0x8(%rbp),%xmm0
  comiss -0x4(%rbp),%xmm0
  jb     L6
  mov    -0xc(%rbp),%eax
  jmp    L13
L6:
  addl   $0x1,-0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    $0xffffffff,%eax
L13:
  leave
  ret
```

assistant: ```c
int rand_vector(float *Pi, int size) {
  int i;
  float r = frand();
  float sum = 0;
  for (i = 0; i < size; i++) {
    sum += Pi[i];
    if (r <= sum) {
      return i;
    }
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rand_vector>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    $0x0,%eax
  call   <frand@plt>
  test   %ebx,%ebx
  jle    L27
  mov    %ebx,%esi
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L16:
  mov    %eax,%edx
  addss  0x0(%rbp,%rax,4),%xmm1
  comiss %xmm0,%xmm1
  jae    L7
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L16
  mov    $0xffffffff,%edx
L7:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    $0xffffffff,%edx
  jmp    L7
```

assistant: ```c
int rand_vector(float *Pi, int size) {
  int i;
  float r = frand();
  float sum = 0;
  for (i = 0; i < size; i++) {
    sum += Pi[i];
    if (r <= sum) {
      return i;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rand_vector>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <frand@plt>
  test   %ebx,%ebx
  jle    L11
  movslq %ebx,%rsi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  jmp    L20
  nopl   (%rax)
L37:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L11
L20:
  addss  0x0(%rbp,%rax,4),%xmm1
  mov    %eax,%r8d
  comiss %xmm0,%xmm1
  jb     L37
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L11:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rand_vector(float *Pi, int size) {
  int i;
  float r = frand();
  float sum = 0;
  for (i = 0; i < size; i++) {
    sum += Pi[i];
    if (r <= sum) {
      return i;
    }
  }
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rand_vector>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <frand@plt>
  test   %ebx,%ebx
  jle    L3
  movslq %ebx,%rsi
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  jmp    L31
  nopl   (%rax)
L19:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L3
L31:
  addss  0x0(%rbp,%rax,4),%xmm1
  mov    %eax,%r8d
  comiss %xmm0,%xmm1
  jb     L19
  add    $0x8,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  add    $0x8,%rsp
  mov    $0xffffffff,%r8d
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rand_vector(float *Pi, int size) {
  int i;
  float r = frand();
  float sum = 0;
  for (i = 0; i < size; i++) {
    sum += Pi[i];
    if (r <= sum) {
      return i;
    }
  }
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<destroy_service>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L18
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L1
L18:
  nop
L1:
  leave
  ret
```

assistant: ```c
void destroy_service(struct service **s) {
  if (*s == NULL) {
    return;
  }
  free((void *)*s);
  *s = NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<destroy_service>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  call   <free@plt>
  movq   $0x0,(%rbx)
L4:
  pop    %rbx
  ret
```

assistant: ```c
void destroy_service(struct service **s) {
  if (*s == NULL) {
    return;
  }
  free((void *)*s);
  *s = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_service>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L0
  call   <free@plt>
  movq   $0x0,(%rbx)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void destroy_service(struct service **s) {
  if (*s == NULL) {
    return;
  }
  free((void *)*s);
  *s = NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<destroy_service>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  call   <free@plt>
  movq   $0x0,(%rbx)
L9:
  pop    %rbx
  ret
```

assistant: ```c
void destroy_service(struct service **s) {
  if (*s == NULL) {
    return;
  }
  free((void *)*s);
  *s = NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<invert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x20,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  lea    -0x1(%rax),%edx
  mov    -0x8(%rbp),%eax
  sub    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  xor    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int invert(unsigned int x, int p, int n) {
  int bits;
  unsigned int y;
  bits = sizeof(int) * 8;
  y = (int)(pow(2, n) - 1) << (bits - p - n);
  x = ~y & x | (~x & y);
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invert>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    %edx,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  sub    $0x1,%eax
  mov    $0x20,%ecx
  sub    %r12d,%ecx
  sub    %ebp,%ecx
  shl    %cl,%eax
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int invert(unsigned int x, int p, int n) {
  int bits;
  unsigned int y;
  bits = sizeof(int) * 8;
  y = (int)(pow(2, n) - 1) << (bits - p - n);
  x = ~y & x | (~x & y);
  return x;
}
```
user: What is the c source code of the assembly code below?

```asm
<invert>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x20,%ecx
  sub    %r12d,%ecx
  sub    $0x1,%eax
  sub    %ebp,%ecx
  shl    %cl,%eax
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int invert(unsigned int x, int p, int n) {
  int bits;
  unsigned int y;
  bits = sizeof(int) * 8;
  y = (int)(pow(2, n) - 1) << (bits - p - n);
  x = ~y & x | (~x & y);
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<invert>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  mov    %edx,%esi
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x2,%edi
  call   <pow@plt>
  mov    $0x20,%ecx
  sub    %r12d,%ecx
  sub    $0x1,%eax
  sub    %ebp,%ecx
  shl    %cl,%eax
  xor    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int invert(unsigned int x, int p, int n) {
  int bits;
  unsigned int y;
  bits = sizeof(int) * 8;
  y = (int)(pow(2, n) - 1) << (bits - p - n);
  x = ~y & x | (~x & y);
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x6b,-0x19(%rbp)
  lea    -0x19(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
long main() {
  char a;
  char *f;
  long m;
  a = 'k';
  f = &a;
  m = f;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
long main() {
  char a;
  char *f;
  long m;
  a = 'k';
  f = &a;
  m = f;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
long main() {
  char a;
  char *f;
  long m;
  a = 'k';
  f = &a;
  m = f;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  ret
```

assistant: ```c
long main() {
  char a;
  char *f;
  long m;
  a = 'k';
  f = &a;
  m = f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rrp_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <die@plt>
L2:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: Could not duplicate %s


assistant: ```c
void *rrp_strdup(const char *string) {
  void *p = strdup(string);
  if (!p)
    die("Could not duplicate %s\n", string);
  return p;
}
```
user: What is the c source code of the assembly code below:

```asm
<rrp_strdup>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L15:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <die@plt>
  jmp    L15
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: Could not duplicate %s


assistant: ```c
void *rrp_strdup(const char *string) {
  void *p = strdup(string);
  if (!p)
    die("Could not duplicate %s\n", string);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rrp_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L2:
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <die@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: Could not duplicate %s


assistant: ```c
void *rrp_strdup(const char *string) {
  void *p = strdup(string);
  if (!p)
    die("Could not duplicate %s\n", string);
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rrp_strdup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L14
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  call   <die@plt>
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: Could not duplicate %s


assistant: ```c
void *rrp_strdup(const char *string) {
  void *p = strdup(string);
  if (!p)
    die("Could not duplicate %s\n", string);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ideaLevel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movswl -0x4(%rbp),%eax
  cmp    $0x3,%eax
  je     L88
  cmp    $0x3,%eax
  jg     L90
  cmp    $0x2,%eax
  je     L37
  cmp    $0x2,%eax
  jg     L90
  test   %eax,%eax
  je     L15
  cmp    $0x1,%eax
  je     L83
  jmp    L90
L15:
  lea    D36(%rip),%rax
  jmp    L104
L83:
  lea    D45(%rip),%rax
  jmp    L104
L37:
  lea    D1(%rip),%rax
  jmp    L104
L88:
  lea    D8(%rip),%rax
  jmp    L104
L90:
  lea    D27(%rip),%rax
L104:
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D36
type: string
name: extract_symbolic_data
arguments: tag: D45
type: string
name: extract_symbolic_data
arguments: tag: D1
type: string
name: extract_symbolic_data
arguments: tag: D8
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string

tool: D36: nothing

tool: D45: good

tool: D1: great

tool: D8: phenomenal

tool: D27: unknown??

assistant: ```c
const char *ideaLevel(short type) {
  switch (type) {
  case 0:
    return "nothing";
    break;
  case 1:
    return "good";
    break;
  case 2:
    return "great";
    break;
  case 3:
    return "phenomenal";
    break;
  default:
    return "unknown??";
    break;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ideaLevel>:
  endbr64
  lea    D53(%rip),%rax
  cmp    $0x2,%di
  je     L26
  jg     L9
  lea    D44(%rip),%rax
  test   %di,%di
  je     L26
  cmp    $0x1,%di
  lea    D22(%rip),%rax
  lea    D38(%rip),%rdx
  cmove  %rdx,%rax
  ret
L9:
  cmp    $0x3,%di
  lea    D22(%rip),%rax
  lea    D23(%rip),%rdx
  cmove  %rdx,%rax
L26:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D53
data_type: string
name: disassemble_data
arguments: tag: D44
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string
name: disassemble_data
arguments: tag: D38
data_type: string
name: disassemble_data
arguments: tag: D23
data_type: string

tool: D53: great

tool: D44: nothing

tool: D22: unknown??

tool: D38: good

tool: D23: phenomenal

assistant: ```c
const char *ideaLevel(short type) {
  switch (type) {
  case 0:
    return "nothing";
    break;
  case 1:
    return "good";
    break;
  case 2:
    return "great";
    break;
  case 3:
    return "phenomenal";
    break;
  default:
    return "unknown??";
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ideaLevel>:
  endbr64
  lea    D24(%rip),%rax
  cmp    $0x2,%di
  je     L18
  jg     L24
  lea    D48(%rip),%rax
  test   %di,%di
  je     L18
  cmp    $0x1,%di
  lea    D51(%rip),%rdx
  lea    D40(%rip),%rax
  cmove  %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  cmp    $0x3,%di
  lea    D40(%rip),%rax
  lea    D50(%rip),%rdx
  cmove  %rdx,%rax
L18:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D24
type_infered: string
name: disassemble_data
arguments: label: D48
type_infered: string
name: disassemble_data
arguments: label: D51
type_infered: string
name: disassemble_data
arguments: label: D40
type_infered: string
name: disassemble_data
arguments: label: D50
type_infered: string

tool: D24: great

tool: D48: nothing

tool: D51: good

tool: D40: unknown??

tool: D50: phenomenal

assistant: ```c
const char *ideaLevel(short type) {
  switch (type) {
  case 0:
    return "nothing";
    break;
  case 1:
    return "good";
    break;
  case 2:
    return "great";
    break;
  case 3:
    return "phenomenal";
    break;
  default:
    return "unknown??";
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ideaLevel>:
  endbr64
  lea    D21(%rip),%rax
  cmp    $0x2,%di
  je     L22
  jg     L13
  lea    D20(%rip),%rax
  test   %di,%di
  je     L22
  cmp    $0x1,%di
  lea    D44(%rip),%rdx
  lea    D15(%rip),%rax
  cmove  %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmp    $0x3,%di
  lea    D15(%rip),%rax
  lea    D59(%rip),%rdx
  cmove  %rdx,%rax
L22:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D44
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D59
data_type: string

tool: D21: great

tool: D20: nothing

tool: D44: good

tool: D15: unknown??

tool: D59: phenomenal

assistant: ```c
const char *ideaLevel(short type) {
  switch (type) {
  case 0:
    return "nothing";
    break;
  case 1:
    return "good";
    break;
  case 2:
    return "great";
    break;
  case 3:
    return "phenomenal";
    break;
  default:
    return "unknown??";
    break;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<is_c>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <test@plt>
  cmp    $0x1,%eax
  je     L15
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <test@plt>
  test   %eax,%eax
  jne    L25
L15:
  mov    $0x0,%eax
  jmp    L29
L25:
  mov    $0x1,%eax
L29:
  leave
  ret
```

assistant: ```c
int is_c(unsigned char *seq, int n) {
  int ndx = n * 2;
  if (test(seq, ndx) == 1 || test(seq, ndx + 1) == 0)
    return 0;
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_c>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    (%rsi,%rsi,1),%ebx
  mov    %ebx,%esi
  call   <test@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0x1,%edx
  je     L4
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <test@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_c(unsigned char *seq, int n) {
  int ndx = n * 2;
  if (test(seq, ndx) == 1 || test(seq, ndx + 1) == 0)
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_c>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    (%rsi,%rsi,1),%ebx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <test@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  je     L5
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <test@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_c(unsigned char *seq, int n) {
  int ndx = n * 2;
  if (test(seq, ndx) == 1 || test(seq, ndx + 1) == 0)
    return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<is_c>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    (%rsi,%rsi,1),%ebx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <test@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x1,%r8d
  je     L2
  lea    0x1(%rbx),%esi
  mov    %rbp,%rdi
  call   <test@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int is_c(unsigned char *seq, int n) {
  int ndx = n * 2;
  if (test(seq, ndx) == 1 || test(seq, ndx + 1) == 0)
    return 0;
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mg_base64_update>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %al,-0x24(%rbp)
  mov    -0x28(%rbp),%eax
  and    $0x3,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  jne    L2
  movzbl -0x24(%rbp),%eax
  shr    $0x2,%al
  movzbl %al,%eax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <mg_b64idx@plt>
  mov    %al,(%rbx)
  movzbl -0x24(%rbp),%eax
  shl    $0x4,%eax
  mov    %eax,%ecx
  addl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  and    $0x30,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L29
L2:
  cmpb   $0x1,-0x11(%rbp)
  jne    L5
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl -0x24(%rbp),%eax
  shr    $0x4,%al
  or     %edx,%eax
  movzbl %al,%eax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <mg_b64idx@plt>
  mov    %al,(%rbx)
  movzbl -0x24(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,%ecx
  addl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  and    $0x3c,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L29
L5:
  mov    -0x28(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movzbl -0x24(%rbp),%eax
  shr    $0x6,%al
  or     %edx,%eax
  movzbl %al,%eax
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <mg_b64idx@plt>
  mov    %al,(%rbx)
  movzbl -0x24(%rbp),%eax
  and    $0x3f,%eax
  addl   $0x1,-0x28(%rbp)
  mov    -0x28(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <mg_b64idx@plt>
  mov    %al,(%rbx)
  addl   $0x1,-0x28(%rbp)
L29:
  mov    -0x28(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int mg_base64_update(unsigned char ch, char *to, int n) {
  unsigned char rem = (n & 3) % 3;
  if (rem == 0) {
    to[n] = mg_b64idx(ch >> 2);
    to[++n] = (ch & 3) << 4;
  } else if (rem == 1) {
    to[n] = mg_b64idx(to[n] | (ch >> 4));
    to[++n] = (ch & 15) << 2;
  } else {
    to[n] = mg_b64idx(to[n] | (ch >> 6));
    to[++n] = mg_b64idx(ch & 63);
    n++;
  }
  return n;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mg_base64_update>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %edx,%ebx
  and    $0x3,%edx
  mov    %ebx,%eax
  and    $0x3,%eax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  lea    (%rax,%rax,2),%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  cmp    %al,%dl
  je     L39
  cmp    $0x1,%cl
  je     L30
  movslq %ebx,%r13
  add    %rsi,%r13
  shr    $0x6,%dil
  or     0x0(%r13),%dil
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  lea    0x1(%rbx),%eax
  cltq
  add    %rax,%r12
  mov    %ebp,%edi
  and    $0x3f,%edi
  call   <mg_b64idx@plt>
  mov    %al,(%r12)
  lea    0x2(%rbx),%eax
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  movslq %ebx,%r13
  add    %rsi,%r13
  shr    $0x2,%dil
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  lea    0x1(%rbx),%eax
  movslq %eax,%rdx
  shl    $0x4,%ebp
  and    $0x30,%ebp
  mov    %bpl,(%r12,%rdx,1)
  jmp    L0
L30:
  movslq %ebx,%r13
  add    %rsi,%r13
  shr    $0x4,%dil
  or     0x0(%r13),%dil
  movzbl %dil,%edi
  call   <mg_b64idx@plt>
  mov    %al,0x0(%r13)
  lea    0x1(%rbx),%eax
  movslq %eax,%rdx
  shl    $0x2,%ebp
  and    $0x3c,%ebp
  mov    %bpl,(%r12,%rdx,1)
  jmp    L0
```

assistant: ```c
int mg_base64_update(unsigned char ch, char *to, int n) {
  unsigned char rem = (n & 3) % 3;
  if (rem == 0) {
    to[n] = mg_b64idx(ch >> 2);
    to[++n] = (ch & 3) << 4;
  } else if (rem == 1) {
    to[n] = mg_b64idx(to[n] | (ch >> 4));
    to[++n] = (ch & 15) << 2;
  } else {
    to[n] = mg_b64idx(to[n] | (ch >> 6));
    to[++n] = mg_b64idx(ch & 63);
    n++;
  }
  return n;
}
```