ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<_MM_EXTRACT_EPI16>:
  endbr64
  cmp    $0x7,%esi
  ja     L2
  lea    D8(%rip),%rdx
  mov    %esi,%esi
  movslq (%rdx,%rsi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L2:
  xor    %esi,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopl   0x0(%rax,%rax,1)
  mov    $0x7,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x5,%esi
  jmp    1050 <_mm_extract_epi16@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x6,%esi
  jmp    1050 <_mm_extract_epi16@plt>
```

assistant: ```c
extern __attribute__((__gnu___, __always___, __artificial__)) int _MM_EXTRACT_EPI16(__m128i vec, const int LANE) {
  switch (LANE) {
  case 0:
    return _mm_extract_epi16(vec, 0);
  case 1:
    return _mm_extract_epi16(vec, 1);
  case 2:
    return _mm_extract_epi16(vec, 2);
  case 3:
    return _mm_extract_epi16(vec, 3);
  case 4:
    return _mm_extract_epi16(vec, 4);
  case 5:
    return _mm_extract_epi16(vec, 5);
  case 6:
    return _mm_extract_epi16(vec, 6);
  case 7:
    return _mm_extract_epi16(vec, 7);
  default:
    return _mm_extract_epi16(vec, 0);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L3
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memcpy(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    i[dest] = i[src];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    %edx,%edx
  mov    $0x0,%eax
L15:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
L2:
  ret
```

assistant: ```c
void memcpy(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    i[dest] = i[src];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcpy>:
  endbr64
  test   %edx,%edx
  jle    L15
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L18:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L18
L15:
  ret
```

assistant: ```c
void memcpy(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    i[dest] = i[src];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L37
  lea    0x1(%rsi),%r9
  mov    %edx,%r8d
  lea    -0x1(%rdx),%eax
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L114
  cmp    $0x6,%eax
  jbe    L114
  cmp    $0xe,%eax
  jbe    L138
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  nopl   0x0(%rax,%rax,1)
L3:
  movdqu (%rsi,%rax,1),%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L3
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L37
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L49
L36:
  mov    (%rsi,%rdi,1),%r9
  mov    %r9,(%rcx,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L37
L49:
  movslq %eax,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L37
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L37
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L37
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L37
  movslq %edi,%rdi
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L37
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rsi,%rdi,1),%r8d
  mov    %r8b,(%rcx,%rdi,1)
  cmp    %eax,%edx
  jle    L37
  cltq
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rcx,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L114:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L74:
  movzbl (%rsi,%rax,1),%edi
  mov    %dil,(%rcx,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L74
L37:
  ret
L138:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L36
```

assistant: ```c
void memcpy(char *dest, char *src, int len) {
  int i;
  for (i = 0; i < len; i++)
    i[dest] = i[src];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<WriteRunLog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L28
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x1c(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x14(%rax),%edi
  mov    -0x10(%rbp),%rax
  mov    0x10(%rax),%esi
  mov    -0x10(%rbp),%rax
  mov    0xc(%rax),%r9d
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%r8d
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x76c(%rax),%edx
  mov    -0x18(%rbp),%rax
  push   %rdi
  push   %rsi
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  add    $0x10,%rsp
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L1
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
L1:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  jmp    L29
L28:
  nop
L29:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
type: string
name: parse_data
arguments: data_tag: D12
type: string
name: parse_data
arguments: data_tag: D0
type: string

tool: D10: a+

tool: D12: ./runlog

tool: D0: %04d/%02d/%02d %02d:%02d:%02d 

assistant: ```c
void WriteRunLog(char *_Str) {
  FILE *FH;
  time_t tt;
  struct tm *tm;
  FH = fopen("./runlog", "a+");
  if (FH == NULL) {
    return;
  }
  tt = time(NULL);
  tm = localtime(&tt);
  fprintf(FH, "%04d/%02d/%02d %02d:%02d:%02d ", tm->tm_year + 1900, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  fputs(_Str, FH);
  if (_Str[strlen(_Str) - 1] != '\n')
    fprintf(FH, "\n");
  fclose(FH);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<WriteRunLog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D8(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  mov    0xc(%rax),%r9d
  mov    0x8(%rax),%r8d
  mov    0x4(%rax),%edx
  lea    0x1(%rdx),%ecx
  mov    (%rax),%edx
  add    $0x76c,%edx
  mov    0x14(%rax),%esi
  push   %rsi
  mov    0x10(%rax),%eax
  push   %rax
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <fputs@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  add    $0x10,%rsp
  cmpb   $0xa,-0x1(%rbp,%rax,1)
  jne    L29
L38:
  mov    %rbx,%rdi
  call   <fclose@plt>
L8:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    %rbx,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L38
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D16
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string

tool: D8: a+

tool: D16: ./runlog

tool: D26: %04d/%02d/%02d %02d:%02d:%02d 

assistant: ```c
void WriteRunLog(char *_Str) {
  FILE *FH;
  time_t tt;
  struct tm *tm;
  FH = fopen("./runlog", "a+");
  if (FH == NULL) {
    return;
  }
  tt = time(NULL);
  tm = localtime(&tt);
  fprintf(FH, "%04d/%02d/%02d %02d:%02d:%02d ", tm->tm_year + 1900, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  fputs(_Str, FH);
  if (_Str[strlen(_Str) - 1] != '\n')
    fprintf(FH, "\n");
  fclose(FH);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WriteRunLog>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    D19(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L18
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %rbp,%rdi
  mov    0x4(%rax),%edx
  mov    0x14(%rax),%esi
  mov    0xc(%rax),%r9d
  mov    0x8(%rax),%r8d
  lea    0x1(%rdx),%ecx
  mov    (%rax),%edx
  push   %rsi
  lea    D17(%rip),%rsi
  mov    0x10(%rax),%eax
  add    $0x76c,%edx
  push   %rax
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rdx
  pop    %rcx
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  jne    L24
L35:
  mov    %rbp,%rdi
  call   <fclose@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L24:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L35
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D17
data_type: string

tool: D6: a+

tool: D19: ./runlog

tool: D17: %04d/%02d/%02d %02d:%02d:%02d 

assistant: ```c
void WriteRunLog(char *_Str) {
  FILE *FH;
  time_t tt;
  struct tm *tm;
  FH = fopen("./runlog", "a+");
  if (FH == NULL) {
    return;
  }
  tt = time(NULL);
  tm = localtime(&tt);
  fprintf(FH, "%04d/%02d/%02d %02d:%02d:%02d ", tm->tm_year + 1900, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  fputs(_Str, FH);
  if (_Str[strlen(_Str) - 1] != '\n')
    fprintf(FH, "\n");
  fclose(FH);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<WriteRunLog>:
  endbr64
  push   %rbp
  lea    D22(%rip),%rsi
  push   %rbx
  mov    %rdi,%rbx
  lea    D17(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <fopen@plt>
  test   %rax,%rax
  je     L9
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  mov    %rbp,%rdi
  mov    0x4(%rax),%edx
  mov    0x14(%rax),%esi
  mov    0xc(%rax),%r9d
  mov    0x8(%rax),%r8d
  lea    0x1(%rdx),%ecx
  mov    (%rax),%edx
  push   %rsi
  lea    D20(%rip),%rsi
  mov    0x10(%rax),%eax
  add    $0x76c,%edx
  push   %rax
  xor    %eax,%eax
  call   <fprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fputs@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  pop    %rdx
  pop    %rcx
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  jne    L31
L15:
  mov    %rbp,%rdi
  call   <fclose@plt>
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L31:
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  jmp    L15
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D22
data_type: string
name: unpack_data
arguments: data_label: D17
data_type: string
name: unpack_data
arguments: data_label: D20
data_type: string

tool: D22: a+

tool: D17: ./runlog

tool: D20: %04d/%02d/%02d %02d:%02d:%02d 

assistant: ```c
void WriteRunLog(char *_Str) {
  FILE *FH;
  time_t tt;
  struct tm *tm;
  FH = fopen("./runlog", "a+");
  if (FH == NULL) {
    return;
  }
  tt = time(NULL);
  tm = localtime(&tt);
  fprintf(FH, "%04d/%02d/%02d %02d:%02d:%02d ", tm->tm_year + 1900, tm->tm_mon + 1, tm->tm_mday, tm->tm_hour, tm->tm_min, tm->tm_sec);
  fputs(_Str, FH);
  if (_Str[strlen(_Str) - 1] != '\n')
    fprintf(FH, "\n");
  fclose(FH);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gser>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  movss  %xmm1,-0x20(%rbp)
  mov    %rsi,-0x28(%rbp)
  mov    -0x1c(%rbp),%eax
  movd   %eax,%xmm0
  call   <gammln@plt>
  movd   %xmm0,%eax
  mov    -0x28(%rbp),%rdx
  mov    %eax,(%rdx)
  pxor   %xmm0,%xmm0
  comiss -0x20(%rbp),%xmm0
  jb     L32
  pxor   %xmm0,%xmm0
  comiss -0x20(%rbp),%xmm0
  jbe    L59
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L59:
  mov    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  jmp    L58
L32:
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  D7(%rip),%xmm0
  divss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0xc(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L28
L23:
  movss  -0x4(%rbp),%xmm1
  movss  D7(%rip),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x20(%rbp),%xmm0
  divss  -0x4(%rbp),%xmm0
  movss  -0x8(%rbp),%xmm1
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movss  -0xc(%rbp),%xmm0
  addss  -0x8(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movsd  %xmm0,-0x30(%rbp)
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  call   <fabs@plt>
  movsd  D9(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L38
  mov    -0x20(%rbp),%eax
  movd   %eax,%xmm0
  call   <log@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x1c(%rbp),%xmm0
  subss  -0x20(%rbp),%xmm0
  mov    -0x28(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  call   <exp@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0xc(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  jmp    L58
L38:
  addl   $0x1,-0x10(%rbp)
L28:
  cmpl   $0x64,-0x10(%rbp)
  jle    L23
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
  nop
L58:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string
name: read_data
arguments: tag: D7
type_infered: f32
name: read_data
arguments: tag: D9
type_infered: byte[8]
name: read_data
arguments: tag: D36
type_infered: string

tool: D6: x less than 0 in routine gser

tool: D7: 1

tool: {"D9": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D36: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(float *gamser, float a, float x, float *gln) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  int n;
  float sum, del, ap;
  *gln = gammln(a);
  if (x <= 0.0) {
    if (x < 0.0)
      nrerror("x less than 0 in routine gser");
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    nrerror("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gser>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  movss  %xmm0,0x1c(%rsp)
  movss  %xmm1,0x18(%rsp)
  mov    %rsi,%rbp
  call   <gammln@plt>
  movss  %xmm0,0x0(%rbp)
  pxor   %xmm0,%xmm0
  comiss 0x18(%rsp),%xmm0
  jae    L56
  movss  D34(%rip),%xmm0
  movaps %xmm0,%xmm7
  movss  0x1c(%rsp),%xmm1
  divss  %xmm1,%xmm7
  movss  %xmm7,0xc(%rsp)
  movss  %xmm1,0x10(%rsp)
  movss  %xmm7,0x14(%rsp)
  mov    $0x64,%ebx
L65:
  movss  D34(%rip),%xmm2
  addss  0x10(%rsp),%xmm2
  movss  %xmm2,0x10(%rsp)
  movss  0x18(%rsp),%xmm0
  divss  %xmm2,%xmm0
  mulss  0x14(%rsp),%xmm0
  movss  %xmm0,0x14(%rsp)
  movss  0xc(%rsp),%xmm3
  addss  %xmm0,%xmm3
  movss  %xmm3,0xc(%rsp)
  call   <fabs@plt>
  movq   %xmm0,%r14
  movss  0xc(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D27(%rip),%xmm0
  movq   %r14,%xmm6
  comisd %xmm6,%xmm0
  ja     L6
  sub    $0x1,%ebx
  jne    L65
  lea    D22(%rip),%rdi
  call   <nrerror@plt>
  jmp    L12
L56:
  ja     L55
L38:
  movl   $0x0,(%r12)
  jmp    L12
L55:
  lea    D17(%rip),%rdi
  call   <nrerror@plt>
  jmp    L38
L6:
  movss  0x18(%rsp),%xmm0
  call   <log@plt>
  mulss  0x1c(%rsp),%xmm0
  subss  0x18(%rsp),%xmm0
  subss  0x0(%rbp),%xmm0
  call   <exp@plt>
  mulss  0xc(%rsp),%xmm0
  movss  %xmm0,(%r12)
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D34
type_guessed: f32
name: disassemble_data
arguments: tag: D27
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D22
type_guessed: string
name: disassemble_data
arguments: tag: D17
type_guessed: string

tool: D34: 1

tool: {"D27": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D22: a too large, ITMAX too small in routine gser

tool: D17: x less than 0 in routine gser

assistant: ```c
void gser(float *gamser, float a, float x, float *gln) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  int n;
  float sum, del, ap;
  *gln = gammln(a);
  if (x <= 0.0) {
    if (x < 0.0)
      nrerror("x less than 0 in routine gser");
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    nrerror("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gser>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  movss  %xmm0,0x1c(%rsp)
  movss  %xmm1,0x18(%rsp)
  call   <gammln@plt>
  movss  %xmm0,(%r12)
  pxor   %xmm0,%xmm0
  comiss 0x18(%rsp),%xmm0
  jae    L57
  movss  D30(%rip),%xmm1
  movss  0x1c(%rsp),%xmm2
  mov    $0x64,%ebx
  divss  %xmm2,%xmm1
  movss  %xmm1,0x4(%rsp)
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L18:
  sub    $0x1,%ebx
  je     L13
L40:
  addss  D30(%rip),%xmm2
  movss  0x18(%rsp),%xmm0
  movss  0x4(%rsp),%xmm3
  divss  %xmm2,%xmm0
  movss  %xmm2,0x14(%rsp)
  mulss  %xmm0,%xmm1
  addss  %xmm1,%xmm3
  movaps %xmm1,%xmm0
  movss  %xmm1,0x10(%rsp)
  movss  %xmm3,0x4(%rsp)
  call   <fabs@plt>
  movsd  %xmm0,0x8(%rsp)
  movss  0x4(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D11(%rip),%xmm0
  movss  0x10(%rsp),%xmm1
  comisd 0x8(%rsp),%xmm0
  movss  0x14(%rsp),%xmm2
  jbe    L18
  movss  0x18(%rsp),%xmm0
  call   <log@plt>
  mulss  0x1c(%rsp),%xmm0
  subss  0x18(%rsp),%xmm0
  subss  (%r12),%xmm0
  call   <exp@plt>
  mulss  0x4(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  ja     L5
L31:
  movl   $0x0,0x0(%rbp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  lea    D2(%rip),%rdi
  call   <nrerror@plt>
  jmp    L31
L13:
  add    $0x20,%rsp
  lea    D10(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10c0 <nrerror@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D30
type_infered: f32
name: extract_symbolic_data
arguments: data_label: D11
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string

tool: D30: 1

tool: {"D11": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D2: x less than 0 in routine gser

tool: D10: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(float *gamser, float a, float x, float *gln) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  int n;
  float sum, del, ap;
  *gln = gammln(a);
  if (x <= 0.0) {
    if (x < 0.0)
      nrerror("x less than 0 in routine gser");
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    nrerror("a too large, ITMAX too small in routine gser");
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gser>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x20,%rsp
  movss  %xmm0,0x1c(%rsp)
  movss  %xmm1,0x18(%rsp)
  call   <gammln@plt>
  movss  %xmm0,(%r12)
  pxor   %xmm0,%xmm0
  comiss 0x18(%rsp),%xmm0
  jae    L18
  movss  D41(%rip),%xmm1
  movss  0x1c(%rsp),%xmm2
  mov    $0x64,%ebx
  divss  %xmm2,%xmm1
  movss  %xmm1,0x4(%rsp)
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L38:
  sub    $0x1,%ebx
  je     L59
L49:
  addss  D41(%rip),%xmm2
  movss  0x18(%rsp),%xmm0
  movss  0x4(%rsp),%xmm3
  divss  %xmm2,%xmm0
  movss  %xmm2,0x14(%rsp)
  mulss  %xmm0,%xmm1
  addss  %xmm1,%xmm3
  movaps %xmm1,%xmm0
  movss  %xmm1,0x10(%rsp)
  movss  %xmm3,0x4(%rsp)
  call   <fabs@plt>
  movsd  %xmm0,0x8(%rsp)
  movss  0x4(%rsp),%xmm0
  call   <fabs@plt>
  mulsd  D3(%rip),%xmm0
  movss  0x10(%rsp),%xmm1
  comisd 0x8(%rsp),%xmm0
  movss  0x14(%rsp),%xmm2
  jbe    L38
  movss  0x18(%rsp),%xmm0
  call   <log@plt>
  mulss  0x1c(%rsp),%xmm0
  subss  0x18(%rsp),%xmm0
  subss  (%r12),%xmm0
  call   <exp@plt>
  mulss  0x4(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  ja     L51
L58:
  movl   $0x0,0x0(%rbp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L51:
  lea    D26(%rip),%rdi
  call   <nrerror@plt>
  jmp    L58
L59:
  add    $0x20,%rsp
  lea    D9(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10c0 <nrerror@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D41
datatype: f32
name: retrieve_data
arguments: data_label: D3
datatype: byte[8]
name: retrieve_data
arguments: data_label: D26
datatype: string
name: retrieve_data
arguments: data_label: D9
datatype: string

tool: D41: 1

tool: {"D3": [0x76,0x83,0x0d,0xf4,0xf5,0x21,0x94,0x3e]}

tool: D26: x less than 0 in routine gser

tool: D9: a too large, ITMAX too small in routine gser

assistant: ```c
void gser(float *gamser, float a, float x, float *gln) {
  float gammln(float xx);
  void nrerror(char error_text[]);
  int n;
  float sum, del, ap;
  *gln = gammln(a);
  if (x <= 0.0) {
    if (x < 0.0)
      nrerror("x less than 0 in routine gser");
    *gamser = 0.0;
    return;
  } else {
    ap = a;
    del = sum = 1.0 / a;
    for (n = 1; n <= 100; n++) {
      ++ap;
      del *= x / ap;
      sum += del;
      if (fabs(del) < fabs(sum) * 3.0e-7) {
        *gamser = sum * exp(-x + a * log(x) - (*gln));
        return;
      }
    }
    nrerror("a too large, ITMAX too small in routine gser");
    return;
  }
}
```