ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<WaitLAFrame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %edi,-0x214(%rbp)
  mov    %esi,%eax
  mov    %al,-0x218(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L37:
  nop
L55:
  lea    -0x210(%rbp),%rdx
  mov    -0x214(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <RecvFrame@plt>
  test   %rax,%rax
  js     L55
  movzbl -0x20f(%rbp),%eax
  cmp    $0x4,%al
  jne    L0
  movzbl -0x20e(%rbp),%eax
  movzbl %al,%edx
  mov    -0x214(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <SendLAFrame@plt>
L0:
  movzbl -0x20f(%rbp),%eax
  cmp    $0x5,%al
  jne    L37
  movzbl -0x20e(%rbp),%eax
  cmp    %al,-0x218(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L21
L30:
  mov    $0xffffffff,%eax
L21:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int WaitLAFrame(int newtFd, unsigned char seqNo) {
  unsigned char frame[256 + 256];
  do {
    while (RecvFrame(newtFd, frame) < 0)
      ;
    if (frame[1] == '\x04')
      SendLAFrame(newtFd, frame[2]);
  } while (frame[1] != '\x05');
  if (frame[2] == seqNo)
    return 0;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WaitLAFrame>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x210,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L13
L28:
  cmpb   $0x5,0x1(%rsp)
  je     L33
L13:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RecvFrame@plt>
  test   %rax,%rax
  js     L13
  cmpb   $0x4,0x1(%rsp)
  jne    L28
  movzbl 0x2(%rsp),%esi
  mov    %ebx,%edi
  call   <SendLAFrame@plt>
  jmp    L28
L33:
  cmp    %r12b,0x2(%rsp)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L50
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int WaitLAFrame(int newtFd, unsigned char seqNo) {
  unsigned char frame[256 + 256];
  do {
    while (RecvFrame(newtFd, frame) < 0)
      ;
    if (frame[1] == '\x04')
      SendLAFrame(newtFd, frame[2]);
  } while (frame[1] != '\x05');
  if (frame[2] == seqNo)
    return 0;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<WaitLAFrame>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RecvFrame@plt>
  test   %rax,%rax
  js     L5
  movzbl 0x1(%rsp),%eax
  cmp    $0x4,%al
  je     L40
L18:
  cmp    $0x5,%al
  jne    L5
  xor    %eax,%eax
  cmp    %r12b,0x2(%rsp)
  setne  %al
  neg    %eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L13
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  movzbl 0x2(%rsp),%esi
  mov    %ebx,%edi
  call   <SendLAFrame@plt>
  movzbl 0x1(%rsp),%eax
  jmp    L18
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int WaitLAFrame(int newtFd, unsigned char seqNo) {
  unsigned char frame[256 + 256];
  do {
    while (RecvFrame(newtFd, frame) < 0)
      ;
    if (frame[1] == '\x04')
      SendLAFrame(newtFd, frame[2]);
  } while (frame[1] != '\x05');
  if (frame[2] == seqNo)
    return 0;
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<WaitLAFrame>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <RecvFrame@plt>
  test   %rax,%rax
  js     L2
  movzbl 0x1(%rsp),%eax
  cmp    $0x4,%al
  je     L48
  cmp    $0x5,%al
  jne    L2
L38:
  xor    %eax,%eax
  cmp    %r12b,0x2(%rsp)
  setne  %al
  neg    %eax
  mov    0x208(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x210,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  movzbl 0x2(%rsp),%esi
  mov    %ebx,%edi
  call   <SendLAFrame@plt>
  cmpb   $0x5,0x1(%rsp)
  jne    L2
  jmp    L38
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int WaitLAFrame(int newtFd, unsigned char seqNo) {
  unsigned char frame[256 + 256];
  do {
    while (RecvFrame(newtFd, frame) < 0)
      ;
    if (frame[1] == '\x04')
      SendLAFrame(newtFd, frame[2]);
  } while (frame[1] != '\x05');
  if (frame[2] == seqNo)
    return 0;
  else
    return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%r12
  mov    $0x0,%ebx
  jmp    L12
L16:
  lea    (%rbx,%rbx,1),%edx
  mov    %r12,%rax
  lea    0x1(%rax),%r12
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %edx,%eax
  and    $0x3fff,%eax
  mov    %eax,%ebx
L12:
  movzbl (%r12),%eax
  test   %al,%al
  jne    L16
  movslq %ebx,%rax
  imul   $0xffffffff81e722c3,%rax,%rax
  shr    $0x20,%rax
  add    %ebx,%eax
  sar    $0x9,%eax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x3f1,%eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int hash(key)
char *key;
{
  register char *cp;
  register int k;
  cp = key;
  k = 0;
  while (*cp)
    k = ((k << 1) ^ (*cp++)) & 0x3fff;
  return (k % 1009);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  mov    $0x0,%edx
L19:
  add    $0x1,%rdi
  add    %edx,%edx
  movsbl %al,%eax
  xor    %eax,%edx
  and    $0x3fff,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L19
L24:
  movslq %edx,%rax
  imul   $0xffffffff81e722c3,%rax,%rax
  shr    $0x20,%rax
  add    %edx,%eax
  sar    $0x9,%eax
  imul   $0x3f1,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
L28:
  mov    $0x0,%edx
  jmp    L24
```

assistant: ```c
int hash(key)
char *key;
{
  register char *cp;
  register int k;
  cp = key;
  k = 0;
  while (*cp)
    k = ((k << 1) ^ (*cp++)) & 0x3fff;
  return (k % 1009);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L8
  xor    %edx,%edx
  nopl   (%rax)
L17:
  add    $0x1,%rdi
  add    %edx,%edx
  xor    %eax,%edx
  movsbl (%rdi),%eax
  and    $0x3fff,%edx
  test   %al,%al
  jne    L17
  mov    %edx,%ecx
  mov    %edx,%eax
  imul   $0x3ce4585,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x9,%eax
  imul   $0x3f1,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(key)
char *key;
{
  register char *cp;
  register int k;
  cp = key;
  k = 0;
  while (*cp)
    k = ((k << 1) ^ (*cp++)) & 0x3fff;
  return (k % 1009);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  movsbl (%rdi),%eax
  test   %al,%al
  je     L5
  xor    %edx,%edx
  nopl   (%rax)
L19:
  add    $0x1,%rdi
  add    %edx,%edx
  xor    %eax,%edx
  movsbl (%rdi),%eax
  and    $0x3fff,%edx
  test   %al,%al
  jne    L19
  mov    %edx,%ecx
  mov    %edx,%eax
  imul   $0x3ce4585,%rcx,%rcx
  shr    $0x20,%rcx
  sub    %ecx,%eax
  shr    %eax
  add    %ecx,%eax
  shr    $0x9,%eax
  imul   $0x3f1,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hash(key)
char *key;
{
  register char *cp;
  register int k;
  cp = key;
  k = 0;
  while (*cp)
    k = ((k << 1) ^ (*cp++)) & 0x3fff;
  return (k % 1009);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L19:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L20
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
L20:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && isspace(*p)) {
    *p = '\0';
    p--;
  }
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chomp>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  ja     L21
L8:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L21
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jbe    L8
L21:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && isspace(*p)) {
    *p = '\0';
    p--;
  }
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<chomp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jbe    L16
  jmp    L13
  nopl   0x0(%rax)
L29:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L13
L16:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L29
L13:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && isspace(*p)) {
    *p = '\0';
    p--;
  }
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chomp>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    %rbx,%r12
  jbe    L11
  jmp    L33
  nopl   0x0(%rax)
L14:
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  cmp    %rbx,%r12
  ja     L33
L11:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L14
L33:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && isspace(*p)) {
    *p = '\0';
    p--;
  }
  return str;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_ZN10Subsmall_X11BadIfNotAnaEPi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned char *_ZN10Subsmall_X11BadIfNotAnaEPi(struct l_class_OC_Subsmall_X *llvm_cbe_this, unsigned int *llvm_cbe_p) {
  unsigned char *llvm_cbe_retval;
  struct l_class_OC_Subsmall_X *llvm_cbe_this_2e_addr;
  unsigned int *llvm_cbe_p_2e_addr;
  struct l_class_OC_Subsmall_X *llvm_cbe_this1;
  unsigned char *llvm_cbe_tmp__17;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_2e_addr) = llvm_cbe_p;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  *(&llvm_cbe_retval) = ((unsigned char *)0);
  llvm_cbe_tmp__17 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__17;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ZN10Subsmall_X11BadIfNotAnaEPi>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
unsigned char *_ZN10Subsmall_X11BadIfNotAnaEPi(struct l_class_OC_Subsmall_X *llvm_cbe_this, unsigned int *llvm_cbe_p) {
  unsigned char *llvm_cbe_retval;
  struct l_class_OC_Subsmall_X *llvm_cbe_this_2e_addr;
  unsigned int *llvm_cbe_p_2e_addr;
  struct l_class_OC_Subsmall_X *llvm_cbe_this1;
  unsigned char *llvm_cbe_tmp__17;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_2e_addr) = llvm_cbe_p;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  *(&llvm_cbe_retval) = ((unsigned char *)0);
  llvm_cbe_tmp__17 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__17;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ZN10Subsmall_X11BadIfNotAnaEPi>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *_ZN10Subsmall_X11BadIfNotAnaEPi(struct l_class_OC_Subsmall_X *llvm_cbe_this, unsigned int *llvm_cbe_p) {
  unsigned char *llvm_cbe_retval;
  struct l_class_OC_Subsmall_X *llvm_cbe_this_2e_addr;
  unsigned int *llvm_cbe_p_2e_addr;
  struct l_class_OC_Subsmall_X *llvm_cbe_this1;
  unsigned char *llvm_cbe_tmp__17;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_2e_addr) = llvm_cbe_p;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  *(&llvm_cbe_retval) = ((unsigned char *)0);
  llvm_cbe_tmp__17 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__17;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_ZN10Subsmall_X11BadIfNotAnaEPi>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *_ZN10Subsmall_X11BadIfNotAnaEPi(struct l_class_OC_Subsmall_X *llvm_cbe_this, unsigned int *llvm_cbe_p) {
  unsigned char *llvm_cbe_retval;
  struct l_class_OC_Subsmall_X *llvm_cbe_this_2e_addr;
  unsigned int *llvm_cbe_p_2e_addr;
  struct l_class_OC_Subsmall_X *llvm_cbe_this1;
  unsigned char *llvm_cbe_tmp__17;
  *(&llvm_cbe_this_2e_addr) = llvm_cbe_this;
  *(&llvm_cbe_p_2e_addr) = llvm_cbe_p;
  llvm_cbe_this1 = *(&llvm_cbe_this_2e_addr);
  *(&llvm_cbe_retval) = ((unsigned char *)0);
  llvm_cbe_tmp__17 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__17;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<save_preferences>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <video_get_resolution@plt>
  mov    %eax,%edi
  call   <preferences_set_videoresolution@plt>
  mov    $0x0,%eax
  call   <video_is_fullscreen@plt>
  mov    %eax,%edi
  call   <preferences_set_fullscreen@plt>
  mov    $0x0,%eax
  call   <video_is_smooth@plt>
  mov    %eax,%edi
  call   <preferences_set_smooth@plt>
  mov    $0x0,%eax
  call   <video_is_fps_visible@plt>
  mov    %eax,%edi
  call   <preferences_set_showfps@plt>
  mov    $0x0,%eax
  call   <input_is_joystick_ignored@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <preferences_set_usegamepad@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void save_preferences() {
  preferences_set_videoresolution(video_get_resolution());
  preferences_set_fullscreen(video_is_fullscreen());
  preferences_set_smooth(video_is_smooth());
  preferences_set_showfps(video_is_fps_visible());
  preferences_set_usegamepad(!input_is_joystick_ignored());
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<save_preferences>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <video_get_resolution@plt>
  mov    %eax,%edi
  call   <preferences_set_videoresolution@plt>
  mov    $0x0,%eax
  call   <video_is_fullscreen@plt>
  mov    %eax,%edi
  call   <preferences_set_fullscreen@plt>
  mov    $0x0,%eax
  call   <video_is_smooth@plt>
  mov    %eax,%edi
  call   <preferences_set_smooth@plt>
  mov    $0x0,%eax
  call   <video_is_fps_visible@plt>
  mov    %eax,%edi
  call   <preferences_set_showfps@plt>
  mov    $0x0,%eax
  call   <input_is_joystick_ignored@plt>
  test   %eax,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <preferences_set_usegamepad@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void save_preferences() {
  preferences_set_videoresolution(video_get_resolution());
  preferences_set_fullscreen(video_is_fullscreen());
  preferences_set_smooth(video_is_smooth());
  preferences_set_showfps(video_is_fps_visible());
  preferences_set_usegamepad(!input_is_joystick_ignored());
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<save_preferences>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <video_get_resolution@plt>
  mov    %eax,%edi
  call   <preferences_set_videoresolution@plt>
  xor    %eax,%eax
  call   <video_is_fullscreen@plt>
  mov    %eax,%edi
  call   <preferences_set_fullscreen@plt>
  xor    %eax,%eax
  call   <video_is_smooth@plt>
  mov    %eax,%edi
  call   <preferences_set_smooth@plt>
  xor    %eax,%eax
  call   <video_is_fps_visible@plt>
  mov    %eax,%edi
  call   <preferences_set_showfps@plt>
  xor    %eax,%eax
  call   <input_is_joystick_ignored@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1120 <preferences_set_usegamepad@plt>
```

assistant: ```c
void save_preferences() {
  preferences_set_videoresolution(video_get_resolution());
  preferences_set_fullscreen(video_is_fullscreen());
  preferences_set_smooth(video_is_smooth());
  preferences_set_showfps(video_is_fps_visible());
  preferences_set_usegamepad(!input_is_joystick_ignored());
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<save_preferences>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <video_get_resolution@plt>
  mov    %eax,%edi
  call   <preferences_set_videoresolution@plt>
  xor    %eax,%eax
  call   <video_is_fullscreen@plt>
  mov    %eax,%edi
  call   <preferences_set_fullscreen@plt>
  xor    %eax,%eax
  call   <video_is_smooth@plt>
  mov    %eax,%edi
  call   <preferences_set_smooth@plt>
  xor    %eax,%eax
  call   <video_is_fps_visible@plt>
  mov    %eax,%edi
  call   <preferences_set_showfps@plt>
  xor    %eax,%eax
  call   <input_is_joystick_ignored@plt>
  xor    %edi,%edi
  test   %eax,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1120 <preferences_set_usegamepad@plt>
```

assistant: ```c
void save_preferences() {
  preferences_set_videoresolution(video_get_resolution());
  preferences_set_fullscreen(video_is_fullscreen());
  preferences_set_smooth(video_is_smooth());
  preferences_set_showfps(video_is_fps_visible());
  preferences_set_usegamepad(!input_is_joystick_ignored());
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<arcsin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L3
L14:
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <ffact@plt>
  pxor   %xmm2,%xmm2
  cvtsi2sd %rax,%xmm2
  movsd  %xmm2,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <dpow@plt>
  mulsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  mov    %eax,%edi
  call   <ffact@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L3:
  cmpl   $0x1d,-0xc(%rbp)
  jle    L14
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double arcsin(double n) {
  double sum = n;
  int i;
  for (i = 1; i < 30; i++) {
    sum += (double)ffact(2 * i - 1) * (dpow(n, 2 * i + 1)) / ((double)ffact(2 * i) * (2 * i + 1));
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<arcsin>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm0,%r12
  movsd  %xmm0,(%rsp)
  mov    $0x1,%ebx
L2:
  lea    0x1(%rbx),%r13d
  mov    %ebx,%edi
  call   <ffact@plt>
  mov    %rax,%rbp
  add    $0x2,%ebx
  mov    %ebx,%edi
  movq   %r12,%xmm0
  call   <dpow@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  mov    %r13d,%edi
  call   <ffact@plt>
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rsp),%xmm0
  divsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x3b,%ebx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double arcsin(double n) {
  double sum = n;
  int i;
  for (i = 1; i < 30; i++) {
    sum += (double)ffact(2 * i - 1) * (dpow(n, 2 * i + 1)) / ((double)ffact(2 * i) * (2 * i + 1));
  }
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arcsin>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  nopl   (%rax)
L0:
  mov    %ebx,%edi
  lea    0x1(%rbx),%r12d
  add    $0x2,%ebx
  call   <ffact@plt>
  mov    %ebx,%edi
  movq   %r14,%xmm0
  mov    %rax,%rbp
  call   <dpow@plt>
  mov    %r12d,%edi
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <ffact@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  cvtsi2sd %ebx,%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x3b,%ebx
  jne    L0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
double arcsin(double n) {
  double sum = n;
  int i;
  for (i = 1; i < 30; i++) {
    sum += (double)ffact(2 * i - 1) * (dpow(n, 2 * i + 1)) / ((double)ffact(2 * i) * (2 * i + 1));
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arcsin>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  movsd  %xmm0,(%rsp)
  nopl   (%rax)
L3:
  mov    %ebx,%edi
  lea    0x1(%rbx),%r12d
  add    $0x2,%ebx
  call   <ffact@plt>
  mov    %ebx,%edi
  movq   %r14,%xmm0
  mov    %rax,%rbp
  call   <dpow@plt>
  mov    %r12d,%edi
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtsi2sd %rbp,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <ffact@plt>
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  movsd  0x8(%rsp),%xmm0
  cvtsi2sd %rax,%xmm1
  cvtsi2sd %ebx,%xmm2
  mulsd  %xmm2,%xmm1
  divsd  %xmm1,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  cmp    $0x3b,%ebx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
double arcsin(double n) {
  double sum = n;
  int i;
  for (i = 1; i < 30; i++) {
    sum += (double)ffact(2 * i - 1) * (dpow(n, 2 * i + 1)) / ((double)ffact(2 * i) * (2 * i + 1));
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<re_match_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    %r9d,-0x34(%rbp)
  mov    -0x34(%rbp),%r9d
  mov    -0x28(%rbp),%r8d
  mov    -0x30(%rbp),%rcx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    0x18(%rbp),%edi
  push   %rdi
  push   0x10(%rbp)
  mov    %rax,%rdi
  call   <byte_re_match_2_internal@plt>
  add    $0x10,%rsp
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int re_match_2(struct re_pattern_buffer *bufp, const char *string1, int size1, const char *string2, int size2, int pos, struct re_registers *regs, int stop) {
  int result;
  result = byte_re_match_2_internal(bufp, string1, size1, string2, size2, pos, regs, stop);
  return result;
}
```