user: 这段汇编代码用C语言表示是什么样的？

```asm
<kruskal>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  mov    %edi,%eax
  sub    $0x1,%edi
  movl   $0x0,0x1c(%rsp)
  mov    %edi,0x18(%rsp)
  movl   $0x0,0x8(%rsp)
  lea    0x1(%rax),%r12d
  test   %edi,%edi
  jle    L56
  nopw   0x0(%rax,%rax,1)
L73:
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L114
  lea    0x28(%r15),%rdi
  mov    $0x1,%r8d
  mov    $0x3e7,%ecx
  mov    %r12d,%r9d
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%eax
  nopl   (%rax)
L51:
  mov    (%rdi,%rax,4),%edx
  cmp    %ecx,%edx
  jge    L112
  test   %edx,%edx
  setne  %sil
  test   %sil,%sil
  cmovne %eax,%ebp
  cmovne %r8d,%ebx
  cmovne %edx,%ecx
L112:
  add    $0x1,%rax
  cmp    %rax,%r9
  jne    L51
  add    $0x1,%r8d
  add    $0x28,%rdi
  cmp    %r12d,%r8d
  jne    L20
L114:
  mov    %r14,%rsi
  mov    %ebx,%edi
  movslq %ebp,%r13
  call   <find@plt>
  mov    %r14,%rsi
  mov    %ebp,%edi
  mov    %eax,(%rsp)
  call   <find@plt>
  movslq %ebx,%r9
  mov    (%rsp),%r8d
  mov    %eax,%esi
  lea    (%r9,%r9,4),%rax
  lea    (%r15,%rax,8),%r11
  cmp    %esi,%r8d
  je     L100
  movslq 0x8(%rsp),%rax
  mov    0xc(%rsp),%ecx
  mov    %r14,%rdx
  mov    %r11,(%rsp)
  mov    %r9,0x10(%rsp)
  mov    %rax,%rdi
  mov    %ebx,0x20(%rsp,%rax,8)
  add    $0x1,%edi
  mov    %ebp,0x24(%rsp,%rax,8)
  mov    %edi,0x8(%rsp)
  mov    (%r11,%r13,4),%edi
  add    %edi,0x1c(%rsp)
  mov    %r8d,%edi
  call   <unionij@plt>
  mov    0x10(%rsp),%r9
  mov    (%rsp),%r11
L100:
  lea    0x0(%r13,%r13,4),%rax
  mov    0x18(%rsp),%edi
  lea    (%r15,%rax,8),%rax
  movl   $0x3e7,(%rax,%r9,4)
  movl   $0x3e7,(%r11,%r13,4)
  cmp    %edi,0x8(%rsp)
  jl     L73
  cmpl   $0x3e6,0x1c(%rsp)
  jle    L70
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x88,%rsp
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    10b0 <printf@plt>
L70:
  lea    D3(%rip),%rdi
  lea    0x20(%rsp),%rbx
  call   <puts@plt>
  mov    0x1c(%rsp),%esi
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  lea    D50(%rip),%rbp
  call   <printf@plt>
  lea    D69(%rip),%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%eax
  sub    $0x2,%eax
  lea    0x28(%rsp,%rax,8),%r12
L63:
  mov    0x4(%rbx),%edx
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L63
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  xor    %esi,%esi
  xor    %eax,%eax
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L90
  add    $0x88,%rsp
  lea    D69(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <puts@plt>
L90:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string
name: disassemble_data
arguments: data_label: D3
type: string
name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D50
type: string
name: disassemble_data
arguments: data_label: D69
type: string

tool: D4: spannig tree does not exist

tool: D3: spannig tree exist

tool: D24: the sum of cost is%d


tool: D50: 	%d->%d


tool: D69: the edges are

assistant: ```c
void kruskal(int n, int cost[10][10], int r[10]) {
  int count = 0, select[10][2], k = 0;
  int sum = 0, min, i, j, u, v;
  while (count < n - 1) {
    min = 999;
    for (i = 1; i <= n; i++) {
      for (j = 1; j <= n; j++) {
        if (min > cost[i][j] && cost[i][j] != 0) {
          min = cost[i][j];
          u = i;
          v = j;
        }
      }
    }
    i = find(u, r);
    j = find(v, r);
    if (i != j) {
      select[k][0] = u;
      select[k][1] = v;
      count++;
      k++;
      sum = sum + cost[u][v];
      unionij(i, j, r, n);
    }
    cost[u][v] = cost[v][u] = 999;
  }
  if (sum < 999) {
    printf("spannig tree exist\n");
    printf("the sum of cost is%d\n", sum);
    printf("the edges are\n");
    for (i = 0; i < n - 1; i++) {
      printf("\t%d->%d\n", select[i][0], select[i][1]);
    }
  } else
    printf("spannig tree does not exist");
}
```