user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  mov    D16(%rip),%rax
  mov    %rax,0x30(%rsp)
  movsd  D26(%rip),%xmm0
  movsd  %xmm0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movsd  %xmm0,0x48(%rsp)
  mov    D39(%rip),%rax
  mov    %rax,0x50(%rsp)
  lea    0x10(%rsp),%r12
  mov    $0x0,%ebp
  lea    D20(%rip),%r13
L19:
  mov    $0x0,%ebx
L45:
  cvttsd2si (%r12,%rbx,8),%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L45
  add    $0x1,%ebp
  add    $0x18,%r12
  cmp    $0x3,%ebp
  jne    L19
  lea    0x60(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0xa8(%rsp),%rcx
  mov    $0x0,%edi
L71:
  lea    -0x48(%rcx),%rax
  mov    %edi,%r8d
  mov    $0x0,%edx
L83:
  movq   $0x0,(%rax)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  %xmm0,0x8(%rax)
  lea    (%rdx,%rdx,1),%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  movsd  %xmm0,0x10(%rax)
  add    $0x18,%rax
  add    %r8d,%edx
  cmp    %rcx,%rax
  jne    L83
  add    $0x1,%edi
  add    $0x48,%rcx
  cmp    $0x3,%edi
  jne    L71
  mov    $0x0,%r15d
  mov    $0x0,%r13d
  lea    D22(%rip),%r14
  jmp    L1
L85:
  add    $0x1,%ebp
  add    $0x18,%r12
  cmp    $0x3,%ebp
  je     L32
L52:
  mov    $0x0,%ebx
L80:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%ecx
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x3,%rbx
  jne    L80
  jmp    L85
L32:
  add    $0x1,%r13d
  add    $0x48,%r15
  cmp    $0x3,%r13d
  je     L48
L1:
  mov    0x8(%rsp),%rax
  lea    (%r15,%rax,1),%r12
  mov    $0x0,%ebp
  jmp    L52
L48:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
type: byte[8]
name: unpack_data
arguments: data_tag: D26
type: byte[8]
name: unpack_data
arguments: data_tag: D39
type: byte[8]
name: unpack_data
arguments: data_tag: D20
type: string
name: unpack_data
arguments: data_tag: D22
type: string

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: {"D39": [0x00,0x00,0x00,0x00,0x00,0x00,0x10,0x40]}

tool: D20: a[%d][%d]: %f


tool: D22: b[%d][%d][%d]: %f


assistant: ```c
int main() {
  double a[3][3];
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      a[i][j] = i * j;
    }
  }
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      printf("a[%d][%d]: %f\n", i, j, a[i][j]);
    }
  }
  double b[3][3][3];
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      for (int k = 0; k < 3; k++) {
        b[i][j][k] = i * j * k;
      }
    }
  }
  for (int i = 0; i < 3; i++) {
    for (int j = 0; j < 3; j++) {
      for (int k = 0; k < 3; k++) {
        printf("b[%d][%d][%d]: %f\n", i, j, k, b[i][j][k]);
      }
    }
  }
  return 0;
}
```