ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L119
  mov    $0xffffffff,%r13d
  mov    $0xffffffff,%ebx
  lea    0x7(%rsp),%rbp
  lea    D15(%rip),%r14
  lea    0x12(%rsp),%r12
  lea    0x1d(%rsp),%r15
  jmp    L89
  nopl   (%rax)
L13:
  add    $0x1,%ebx
L63:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L30
L89:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmp    $0xffffffff,%ebx
  je     L67
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L13
  cmp    $0xffffffff,%r13d
  je     L110
  mov    (%rsp),%eax
  add    $0x1,%r13d
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L89
L30:
  mov    %r12,%rdi
  cmp    %r13d,%ebx
  jle    L119
L114:
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L67:
  mov    $0xb,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <strncpy@plt>
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L110:
  mov    $0xb,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %r13d,%r13d
  call   <strncpy@plt>
  jmp    L63
L119:
  lea    0x1d(%rsp),%rdi
  jmp    L114
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: string
name: unpack_data
arguments: data_label: D15
datatype: string

tool: D12: %d


tool: D15: %s

assistant: ```c
int main() {
  int n, s1 = -1, s2 = -1;
  char b[11], t1[11], t2[11];
  scanf("%d\n", &n);
  while (n--) {
    scanf("%s", b);
    if (s1 < 0) {
      strncpy(t1, b, 11);
      ++s1;
    } else if (!strcmp(b, t1))
      ++s1;
    else if (s2 < 0) {
      strncpy(t2, b, 11);
      ++s2;
    } else
      ++s2;
  }
  printf(s1 > s2 ? t1 : t2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L40
  mov    $0xffffffff,%r13d
  mov    $0xffffffff,%ebx
  lea    0x7(%rsp),%rbp
  lea    D19(%rip),%r14
  lea    0x12(%rsp),%r12
  lea    0x1d(%rsp),%r15
  jmp    L38
  nopl   (%rax)
L74:
  add    $0x1,%ebx
L118:
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L43
L38:
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  cmp    $0xffffffff,%ebx
  je     L99
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L74
  cmp    $0xffffffff,%r13d
  je     L42
  mov    (%rsp),%eax
  add    $0x1,%r13d
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L38
L43:
  mov    %r12,%rdi
  cmp    %r13d,%ebx
  jle    L40
L87:
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L99:
  mov    $0xb,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %ebx,%ebx
  call   <strncpy@plt>
  jmp    L118
  nopw   0x0(%rax,%rax,1)
L42:
  mov    $0xb,%edx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  xor    %r13d,%r13d
  call   <strncpy@plt>
  jmp    L118
L40:
  lea    0x1d(%rsp),%rdi
  jmp    L87
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D10
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D10: %d


tool: D19: %s

assistant: ```c
int main() {
  int n, s1 = -1, s2 = -1;
  char b[11], t1[11], t2[11];
  scanf("%d\n", &n);
  while (n--) {
    scanf("%s", b);
    if (s1 < 0) {
      strncpy(t1, b, 11);
      ++s1;
    } else if (!strcmp(b, t1))
      ++s1;
    else if (s2 < 0) {
      strncpy(t2, b, 11);
      ++s2;
    } else
      ++s2;
  }
  printf(s1 > s2 ? t1 : t2);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<CalculateNMEAChecksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L27
L4:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L27:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L10
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jne    L4
L10:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int CalculateNMEAChecksum(const char *buf, const char *end) {
  unsigned int ret = 0;
  while (*buf && buf != end) {
    ret ^= (unsigned int)*((unsigned char *)buf);
    ++buf;
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CalculateNMEAChecksum>:
  endbr64
  movzbl (%rdi),%eax
  cmp    %rsi,%rdi
  je     L3
  test   %al,%al
  je     L3
  mov    $0x0,%edx
L35:
  movzbl %al,%eax
  xor    %eax,%edx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    %rdi,%rsi
  je     L25
  test   %al,%al
  jne    L35
L25:
  mov    %edx,%eax
  ret
L3:
  mov    $0x0,%edx
  jmp    L25
```

assistant: ```c
unsigned int CalculateNMEAChecksum(const char *buf, const char *end) {
  unsigned int ret = 0;
  while (*buf && buf != end) {
    ret ^= (unsigned int)*((unsigned char *)buf);
    ++buf;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<CalculateNMEAChecksum>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    %rsi,%rdi
  jne    L5
  jmp    L3
  nopl   0x0(%rax)
L34:
  add    $0x1,%rdi
  xor    %eax,%r8d
  movzbl (%rdi),%eax
  cmp    %rdi,%rsi
  je     L3
L5:
  test   %al,%al
  jne    L34
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int CalculateNMEAChecksum(const char *buf, const char *end) {
  unsigned int ret = 0;
  while (*buf && buf != end) {
    ret ^= (unsigned int)*((unsigned char *)buf);
    ++buf;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CalculateNMEAChecksum>:
  endbr64
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  cmp    %rsi,%rdi
  jne    L5
  jmp    L3
  nopl   0x0(%rax)
L38:
  add    $0x1,%rdi
  xor    %eax,%r8d
  movzbl (%rdi),%eax
  cmp    %rdi,%rsi
  je     L3
L5:
  test   %al,%al
  jne    L38
L3:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int CalculateNMEAChecksum(const char *buf, const char *end) {
  unsigned int ret = 0;
  while (*buf && buf != end) {
    ret ^= (unsigned int)*((unsigned char *)buf);
    ++buf;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L3
L10:
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L10
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int pot(int a, int b) {
  int co = 0, ac = 1;
  while (co < b) {
    co++;
    ac = ac * a;
  }
  return ac;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pot>:
  endbr64
  test   %esi,%esi
  jle    L29
  mov    $0x1,%edx
  mov    $0x0,%eax
L15:
  add    $0x1,%eax
  imul   %edi,%edx
  cmp    %eax,%esi
  jne    L15
L24:
  mov    %edx,%eax
  ret
L29:
  mov    $0x1,%edx
  jmp    L24
```

assistant: ```c
int pot(int a, int b) {
  int co = 0, ac = 1;
  while (co < b) {
    co++;
    ac = ac * a;
  }
  return ac;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pot>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L15
  xor    %eax,%eax
L7:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L7
L15:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int pot(int a, int b) {
  int co = 0, ac = 1;
  while (co < b) {
    co++;
    ac = ac * a;
  }
  return ac;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pot>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  jle    L18
  xor    %eax,%eax
L14:
  add    $0x1,%eax
  imul   %edi,%r8d
  cmp    %eax,%esi
  jne    L14
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int pot(int a, int b) {
  int co = 0, ac = 1;
  while (co < b) {
    co++;
    ac = ac * a;
  }
  return ac;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<rest_prio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <iterator@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x63,-0x4(%rbp)
  jg     L12
  mov    $0x64,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x64,%eax
  sub    -0x4(%rbp),%eax
  jmp    L5
L12:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D0
data_type: string
name: parse_data
arguments: tag: D18
data_type: string

tool: D0: The number of new priorities could be saved is %d.


tool: D18: The memory for priorities is full!

assistant: ```c
int rest_prio(void) {
  int num = iterator();
  if (num < 100) {
    printf("The number of new priorities could be saved is %d.\n", (int)(100 - num));
    return 100 - num;
  } else {
    printf("The memory for priorities is full!");
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<rest_prio>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <iterator@plt>
  cmp    $0x63,%eax
  jg     L1
  mov    $0x64,%ebx
  sub    %eax,%ebx
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    %ebx,%eax
  pop    %rbx
  ret
L1:
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string
name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D9: The number of new priorities could be saved is %d.


tool: D8: The memory for priorities is full!

assistant: ```c
int rest_prio(void) {
  int num = iterator();
  if (num < 100) {
    printf("The number of new priorities could be saved is %d.\n", (int)(100 - num));
    return 100 - num;
  } else {
    printf("The memory for priorities is full!");
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rest_prio>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <iterator@plt>
  cmp    $0x63,%eax
  jg     L0
  mov    $0x64,%r12d
  lea    D6(%rip),%rdi
  sub    %eax,%r12d
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r12d,%r12d
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D6
type_guessed: string
name: disassemble_data
arguments: label: D17
type_guessed: string

tool: D6: The number of new priorities could be saved is %d.


tool: D17: The memory for priorities is full!

assistant: ```c
int rest_prio(void) {
  int num = iterator();
  if (num < 100) {
    printf("The number of new priorities could be saved is %d.\n", (int)(100 - num));
    return 100 - num;
  } else {
    printf("The memory for priorities is full!");
    return 0;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rest_prio>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <iterator@plt>
  cmp    $0x63,%eax
  jg     L2
  mov    $0x64,%r12d
  lea    D1(%rip),%rdi
  sub    %eax,%r12d
  xor    %eax,%eax
  mov    %r12d,%esi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %r12d,%r12d
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string

tool: D1: The number of new priorities could be saved is %d.


tool: D17: The memory for priorities is full!

assistant: ```c
int rest_prio(void) {
  int num = iterator();
  if (num < 100) {
    printf("The number of new priorities could be saved is %d.\n", (int)(100 - num));
    return 100 - num;
  } else {
    printf("The memory for priorities is full!");
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: usage: 
    ads                 normal usage
    ads --daemon        detach and go to background (daemonizing)
    ads --debug         debug mode (more output)
    
note:
    you must invoke ads as root!



assistant: ```c
void print_usage(void) {
  printf("usage: \n"
         "    ads                 normal usage\n"
         "    ads --daemon        detach and go to background (daemonizing)\n"
         "    ads --debug         debug mode (more output)\n"
         "    \n"
         "note:\n"
         "    you must invoke ads as root!\n\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_usage>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
type: string

tool: D3: usage: 
    ads                 normal usage
    ads --daemon        detach and go to background (daemonizing)
    ads --debug         debug mode (more output)
    
note:
    you must invoke ads as root!



assistant: ```c
void print_usage(void) {
  printf("usage: \n"
         "    ads                 normal usage\n"
         "    ads --daemon        detach and go to background (daemonizing)\n"
         "    ads --debug         debug mode (more output)\n"
         "    \n"
         "note:\n"
         "    you must invoke ads as root!\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
datatype: string

tool: D0: usage: 
    ads                 normal usage
    ads --daemon        detach and go to background (daemonizing)
    ads --debug         debug mode (more output)
    
note:
    you must invoke ads as root!



assistant: ```c
void print_usage(void) {
  printf("usage: \n"
         "    ads                 normal usage\n"
         "    ads --daemon        detach and go to background (daemonizing)\n"
         "    ads --debug         debug mode (more output)\n"
         "    \n"
         "note:\n"
         "    you must invoke ads as root!\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_usage>:
  endbr64
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: usage: 
    ads                 normal usage
    ads --daemon        detach and go to background (daemonizing)
    ads --debug         debug mode (more output)
    
note:
    you must invoke ads as root!



assistant: ```c
void print_usage(void) {
  printf("usage: \n"
         "    ads                 normal usage\n"
         "    ads --daemon        detach and go to background (daemonizing)\n"
         "    ads --debug         debug mode (more output)\n"
         "    \n"
         "note:\n"
         "    you must invoke ads as root!\n\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rax
  lea    0x130(%rsp),%rdx
L148:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L148
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    $0x1,%r14d
L132:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L48
L77:
  cmp    $0x20,%eax
  jne    L103
L24:
  cmp    $0x1,%ebp
  je     L69
L48:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    D7(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L45
  cmp    $0xa,%eax
  jg     L77
  cmp    $0x8,%eax
  jg     L24
L103:
  add    $0x1,%ebx
  mov    %r14d,%ebp
  jmp    L48
L69:
  movslq %ebx,%rdx
  mov    (%rsp,%rdx,4),%eax
  add    $0x1,%eax
  mov    %eax,(%rsp,%rdx,4)
  cmp    %eax,%r13d
  cmovl  %eax,%r13d
  cmp    %ebx,%r12d
  cmovl  %ebx,%r12d
  jmp    L132
L45:
  mov    $0x4b,%r14d
  cmp    %r14d,%r12d
  cmovle %r12d,%r14d
  mov    $0x1,%ebp
  mov    %rsp,%r15
  test   %r13d,%r13d
  jg     L113
L131:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  mov    $0x0,%eax
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L163:
  mov    $0x20,%edi
  call   <putchar@plt>
L99:
  add    $0x1,%rbx
  cmp    %ebx,%r14d
  jl     L47
L92:
  cmp    %ebp,(%r15,%rbx,4)
  jl     L163
  mov    $0x7c,%edi
  call   <putchar@plt>
  jmp    L99
L47:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  cmp    %r13d,%ebp
  jg     L131
L113:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jg     L92
  jmp    L47
L62:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int ch, prevstate, state;
  int i, j, wordlen, maxwordlen, maxwordfreq;
  int wordfreq[75 + 1];
  wordlen = maxwordlen = maxwordfreq = 0;
  for (i = 0; i < (75 + 1); ++i)
    wordfreq[i] = 0;
  prevstate = state = 0;
  while ((ch = getchar()) != EOF) {
    if (ch == ' ' || ch == '\t' || ch == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      ++wordlen;
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      ++wordfreq[wordlen];
      if (wordfreq[wordlen] > maxwordfreq)
        maxwordfreq = wordfreq[wordlen];
      if (wordlen > maxwordlen)
        maxwordlen = wordlen;
      wordlen = 0;
    }
  }
  if (maxwordlen > 75)
    maxwordlen = 75;
  for (j = 1; j <= maxwordfreq; ++j) {
    for (i = 1; i <= maxwordlen; ++i) {
      if (wordfreq[i] >= j)
        putchar('|');
      else
        putchar(' ');
    }
    putchar('\n');
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x26,%ecx
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    D2(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
L61:
  xor    %ebx,%ebx
  xor    %r15d,%r15d
L107:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  je     L56
L130:
  cmp    $0xa,%eax
  jg     L48
  cmp    $0x8,%eax
  jg     L65
L38:
  xor    %eax,%eax
  add    $0x1,%ebx
  mov    $0x1,%r15d
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L130
L56:
  mov    $0x4b,%r15d
  mov    $0x1,%r12d
  cmp    %r15d,%r13d
  cmovle %r13d,%r15d
  test   %r14d,%r14d
  je     L95
  nopl   (%rax)
L116:
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jne    L35
  jmp    L19
  nopl   0x0(%rax)
L110:
  mov    $0x7c,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r15d
  jl     L19
L35:
  cmp    0x0(%rbp,%rbx,4),%r12d
  jle    L110
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r15d
  jge    L35
L19:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r14d,%r12d
  jle    L116
L95:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x148,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L48:
  cmp    $0x20,%eax
  jne    L38
L65:
  test   %r15d,%r15d
  je     L107
  movslq %ebx,%rdx
  mov    (%rsp,%rdx,4),%eax
  add    $0x1,%eax
  cmp    %eax,%r14d
  mov    %eax,(%rsp,%rdx,4)
  cmovl  %eax,%r14d
  cmp    %ebx,%r13d
  cmovl  %ebx,%r13d
  jmp    L61
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int ch, prevstate, state;
  int i, j, wordlen, maxwordlen, maxwordfreq;
  int wordfreq[75 + 1];
  wordlen = maxwordlen = maxwordfreq = 0;
  for (i = 0; i < (75 + 1); ++i)
    wordfreq[i] = 0;
  prevstate = state = 0;
  while ((ch = getchar()) != EOF) {
    if (ch == ' ' || ch == '\t' || ch == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      ++wordlen;
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      ++wordfreq[wordlen];
      if (wordfreq[wordlen] > maxwordfreq)
        maxwordfreq = wordfreq[wordlen];
      if (wordlen > maxwordlen)
        maxwordlen = wordlen;
      wordlen = 0;
    }
  }
  if (maxwordlen > 75)
    maxwordlen = 75;
  for (j = 1; j <= maxwordfreq; ++j) {
    for (i = 1; i <= maxwordlen; ++i) {
      if (wordfreq[i] >= j)
        putchar('|');
      else
        putchar(' ');
    }
    putchar('\n');
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x26,%ecx
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    D0(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
L54:
  xor    %ebx,%ebx
  xor    %r15d,%r15d
L103:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    %eax,(%r12)
  je     L62
L42:
  cmp    $0xa,%eax
  jg     L124
  cmp    $0x8,%eax
  jg     L122
L89:
  xor    %eax,%eax
  add    $0x1,%ebx
  mov    $0x1,%r15d
  call   <getchar@plt>
  cmp    %eax,(%r12)
  jne    L42
L62:
  mov    $0x4b,%r15d
  mov    $0x1,%r12d
  cmp    %r15d,%r13d
  cmovle %r13d,%r15d
  test   %r14d,%r14d
  je     L69
  nopl   (%rax)
L145:
  mov    $0x1,%ebx
  test   %r13d,%r13d
  jne    L136
  jmp    L27
  nopl   0x0(%rax)
L13:
  mov    $0x7c,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r15d
  jl     L27
L136:
  cmp    0x0(%rbp,%rbx,4),%r12d
  jle    L13
  mov    $0x20,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %ebx,%r15d
  jge    L136
L27:
  mov    $0xa,%edi
  add    $0x1,%r12d
  call   <putchar@plt>
  cmp    %r14d,%r12d
  jle    L145
L69:
  mov    0x138(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L47
  add    $0x148,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L124:
  cmp    $0x20,%eax
  jne    L89
L122:
  test   %r15d,%r15d
  je     L103
  movslq %ebx,%rdx
  mov    (%rsp,%rdx,4),%eax
  add    $0x1,%eax
  cmp    %eax,%r14d
  mov    %eax,(%rsp,%rdx,4)
  cmovl  %eax,%r14d
  cmp    %ebx,%r13d
  cmovl  %ebx,%r13d
  jmp    L54
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int ch, prevstate, state;
  int i, j, wordlen, maxwordlen, maxwordfreq;
  int wordfreq[75 + 1];
  wordlen = maxwordlen = maxwordfreq = 0;
  for (i = 0; i < (75 + 1); ++i)
    wordfreq[i] = 0;
  prevstate = state = 0;
  while ((ch = getchar()) != EOF) {
    if (ch == ' ' || ch == '\t' || ch == '\n') {
      prevstate = state;
      state = 0;
    } else {
      prevstate = state;
      state = 1;
      ++wordlen;
    }
    if (prevstate == 1 && state == 0) {
      prevstate = state;
      state = 0;
      ++wordfreq[wordlen];
      if (wordfreq[wordlen] > maxwordfreq)
        maxwordfreq = wordfreq[wordlen];
      if (wordlen > maxwordlen)
        maxwordlen = wordlen;
      wordlen = 0;
    }
  }
  if (maxwordlen > 75)
    maxwordlen = 75;
  for (j = 1; j <= maxwordfreq; ++j) {
    for (i = 1; i <= maxwordlen; ++i) {
      if (wordfreq[i] >= j)
        putchar('|');
      else
        putchar(' ');
    }
    putchar('\n');
  }
  return 0;
}
```