ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<sym_expand_string_value>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  lea    0x1(%rax),%r14d
  movslq %r14d,%r14
  mov    %r14,%rdi
  call   <malloc@plt>
  movb   $0x0,(%rax)
  mov    %rax,%r12
  nopl   (%rax)
L19:
  mov    $0x24,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L70
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    %rsp,%r13
  sub    %ebp,%edx
  lea    0x1(%rbx),%rbp
  mov    %r13,%rbx
  call   <strncat@plt>
  jmp    L31
  nopl   0x0(%rax)
L80:
  mov    %al,(%rbx)
  add    $0x1,%rbx
  add    $0x1,%rbp
L31:
  movsbl 0x0(%rbp),%edi
  call   <isalnum@plt>
  test   %rax,%rax
  movzbl 0x0(%rbp),%eax
  jne    L80
  cmp    $0x5f,%al
  je     L80
  movb   $0x0,(%rbx)
  mov    %r13,%rdi
  lea    D5(%rip),%r15
  call   <sym_find@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L37
  mov    %rax,%rdi
  call   <sym_calc_value@plt>
  mov    %r13,%rdi
  call   <sym_get_string_value@plt>
  mov    %rax,%r15
L37:
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    %rbp,%rdi
  add    %eax,%ebx
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%ebx
  movslq %ebx,%rbx
  cmp    %rbx,%r14
  jb     L35
L36:
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L19
  nopl   (%rax)
L35:
  mov    %r12,%rdi
  mov    %rbx,%rsi
  mov    %rbx,%r14
  call   <realloc@plt>
  mov    %rax,%r12
  jmp    L36
L70:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x118,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: 

assistant: ```c
const char *sym_expand_string_value(const char *in) {
  const char *src;
  char *res;
  size_t reslen;
  reslen = strlen(in) + 1;
  res = malloc(reslen);
  res[0] = '\0';
  while ((src = strchr(in, '$'))) {
    char *p, name[256];
    const char *symval = "";
    struct symbol *sym;
    size_t newlen;
    strncat(res, in, src - in);
    src++;
    p = name;
    while (isalnum(*src) || *src == '_')
      *p++ = *src++;
    *p = '\0';
    sym = sym_find(name);
    if (sym != NULL) {
      sym_calc_value(sym);
      symval = sym_get_string_value(sym);
    }
    newlen = strlen(res) + strlen(symval) + strlen(src) + 1;
    if (newlen > reslen) {
      reslen = newlen;
      res = realloc(res, reslen);
    }
    strcat(res, symval);
    in = src;
  }
  strcat(res, in);
  return res;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_insn_powerpc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
data_type: string

tool: D9: %.8x

assistant: ```c
int print_insn_powerpc(unsigned long insn, unsigned long memaddr) {
  printf("%.8x", insn);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_insn_powerpc>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string

tool: D0: %.8x

assistant: ```c
int print_insn_powerpc(unsigned long insn, unsigned long memaddr) {
  printf("%.8x", insn);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<print_insn_powerpc>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
data_type: string

tool: D7: %.8x

assistant: ```c
int print_insn_powerpc(unsigned long insn, unsigned long memaddr) {
  printf("%.8x", insn);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_insn_powerpc>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: %.8x

assistant: ```c
int print_insn_powerpc(unsigned long insn, unsigned long memaddr) {
  printf("%.8x", insn);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L15:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
L4:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jl     L15
  mov    D2(%rip),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <putc@plt>
  nop
  leave
  ret
```

assistant: ```c
void writeFile(FILE *out, int part, int sizes[], char *str_out[]) {
  int i = 0;
  while (i < sizes[part]) {
    putc(str_out[part][i++], out);
  }
  putc(EOF, out);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<writeFile>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movslq %esi,%rsi
  lea    (%rdx,%rsi,4),%r12
  cmpl   $0x0,(%r12)
  jle    L14
  lea    (%rcx,%rsi,8),%r13
  mov    $0x0,%ebx
L19:
  mov    0x0(%r13),%rax
  movsbl (%rax,%rbx,1),%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x1,%rbx
  cmp    %ebx,(%r12)
  jg     L19
L14:
  mov    D6(%rip),%rax
  movsbl (%rax),%edi
  mov    %rbp,%rsi
  call   <putc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void writeFile(FILE *out, int part, int sizes[], char *str_out[]) {
  int i = 0;
  while (i < sizes[part]) {
    putc(str_out[part][i++], out);
  }
  putc(EOF, out);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writeFile>:
  endbr64
  push   %r13
  movslq %esi,%rsi
  push   %r12
  lea    (%rdx,%rsi,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L17
  lea    (%rcx,%rsi,8),%r13
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L9:
  mov    0x0(%r13),%rax
  mov    %rbp,%rsi
  movsbl (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putc@plt>
  cmp    %ebx,(%r12)
  jg     L9
L17:
  mov    D7(%rip),%rax
  mov    %rbp,%rsi
  movsbl (%rax),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <putc@plt>
```

assistant: ```c
void writeFile(FILE *out, int part, int sizes[], char *str_out[]) {
  int i = 0;
  while (i < sizes[part]) {
    putc(str_out[part][i++], out);
  }
  putc(EOF, out);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<writeFile>:
  endbr64
  push   %r13
  movslq %esi,%rsi
  push   %r12
  lea    (%rdx,%rsi,4),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%r12),%eax
  test   %eax,%eax
  jle    L16
  lea    (%rcx,%rsi,8),%r13
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L15:
  mov    0x0(%r13),%rax
  mov    %rbp,%rsi
  movsbl (%rax,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putc@plt>
  cmp    %ebx,(%r12)
  jg     L15
L16:
  mov    D2(%rip),%rax
  mov    %rbp,%rsi
  movsbl (%rax),%edi
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <putc@plt>
```

assistant: ```c
void writeFile(FILE *out, int part, int sizes[], char *str_out[]) {
  int i = 0;
  while (i < sizes[part]) {
    putc(str_out[part][i++], out);
  }
  putc(EOF, out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<posn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L31
L10:
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L7
  mov    -0x8(%rbp),%eax
  jmp    L14
L7:
  addl   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jb     L10
  mov    $0x0,%eax
L14:
  leave
  ret
```

assistant: ```c
int posn(char set_string[], char data) {
  unsigned int i, n = strlen(set_string);
  for (i = 0; i < n; i++) {
    if (data == set_string[i]) {
      return i;
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<posn>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  call   <strlen@plt>
  test   %eax,%eax
  je     L28
  mov    %eax,%edx
  mov    $0x0,%eax
L26:
  cmp    %bpl,(%rbx,%rax,1)
  je     L13
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L26
  mov    $0x0,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  mov    $0x0,%eax
  jmp    L13
```

assistant: ```c
int posn(char set_string[], char data) {
  unsigned int i, n = strlen(set_string);
  for (i = 0; i < n; i++) {
    if (data == set_string[i]) {
      return i;
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<posn>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L26
  mov    %eax,%edx
  xor    %eax,%eax
  jmp    L14
  xchg   %ax,%ax
L2:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L26
L14:
  cmp    %bpl,(%rbx,%rax,1)
  jne    L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L26:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int posn(char set_string[], char data) {
  unsigned int i, n = strlen(set_string);
  for (i = 0; i < n; i++) {
    if (data == set_string[i]) {
      return i;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<posn>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  je     L19
  mov    %eax,%edx
  xor    %eax,%eax
  jmp    L38
  xchg   %ax,%ax
L3:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L19
L38:
  cmp    %bpl,(%rbx,%rax,1)
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int posn(char set_string[], char data) {
  unsigned int i, n = strlen(set_string);
  for (i = 0; i < n; i++) {
    if (data == set_string[i]) {
      return i;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<key5_event>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <is_screensaver_active@plt>
  test   %rax,%rax
  je     L16
  mov    $0x0,%eax
  call   <screensaver_off@plt>
  jmp    L10
L16:
  mov    $0x0,%eax
  call   <screensaver_off@plt>
L10:
  pop    %rbp
  ret
```

assistant: ```c
void key5_event() {
  if (is_screensaver_active()) {
    screensaver_off();
    return;
  }
  screensaver_off();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<key5_event>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <is_screensaver_active@plt>
  test   %rax,%rax
  jne    L4
  mov    $0x0,%eax
  call   <screensaver_off@plt>
L18:
  add    $0x8,%rsp
  ret
L4:
  mov    $0x0,%eax
  call   <screensaver_off@plt>
  jmp    L18
```

assistant: ```c
void key5_event() {
  if (is_screensaver_active()) {
    screensaver_off();
    return;
  }
  screensaver_off();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<key5_event>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <is_screensaver_active@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <screensaver_off@plt>
```

assistant: ```c
void key5_event() {
  if (is_screensaver_active()) {
    screensaver_off();
    return;
  }
  screensaver_off();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<key5_event>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <is_screensaver_active@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <screensaver_off@plt>
```

assistant: ```c
void key5_event() {
  if (is_screensaver_active()) {
    screensaver_off();
    return;
  }
  screensaver_off();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rt_par_finish>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rt_par_finish(void) {
  int a = 0;
  return a;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rt_par_finish>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int rt_par_finish(void) {
  int a = 0;
  return a;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rt_par_finish>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int rt_par_finish(void) {
  int a = 0;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rt_par_finish>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int rt_par_finish(void) {
  int a = 0;
  return a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<log_cachedanswer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <string@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <logtype@plt>
  mov    $0x0,%eax
  call   <space@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <name@plt>
  mov    $0x0,%eax
  call   <line@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6:      cc 

assistant: ```c
void log_cachedanswer(const char *q, const char type[2]) {
  string("     cc ");
  logtype(type);
  space();
  name(q);
  line();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<log_cachedanswer>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D1(%rip),%rdi
  call   <string@plt>
  mov    %rbp,%rdi
  call   <logtype@plt>
  mov    $0x0,%eax
  call   <space@plt>
  mov    %rbx,%rdi
  call   <name@plt>
  mov    $0x0,%eax
  call   <line@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1:      cc 

assistant: ```c
void log_cachedanswer(const char *q, const char type[2]) {
  string("     cc ");
  logtype(type);
  space();
  name(q);
  line();
}
```
user: Translate the below assembly code into C programming language:

```asm
<log_cachedanswer>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  sub    $0x8,%rsp
  call   <string@plt>
  mov    %r12,%rdi
  call   <logtype@plt>
  xor    %eax,%eax
  call   <space@plt>
  mov    %rbp,%rdi
  call   <name@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10a0 <line@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0:      cc 

assistant: ```c
void log_cachedanswer(const char *q, const char type[2]) {
  string("     cc ");
  logtype(type);
  space();
  name(q);
  line();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<log_cachedanswer>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D5(%rip),%rdi
  sub    $0x8,%rsp
  call   <string@plt>
  mov    %r12,%rdi
  call   <logtype@plt>
  xor    %eax,%eax
  call   <space@plt>
  mov    %rbp,%rdi
  call   <name@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    10a0 <line@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
data_type: string

tool: D5:      cc 

assistant: ```c
void log_cachedanswer(const char *q, const char type[2]) {
  string("     cc ");
  logtype(type);
  space();
  name(q);
  line();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x4,-0x30(%rbp)
  je     L12
  cmpl   $0x4,-0x30(%rbp)
  jg     L53
  cmpl   $0x1,-0x30(%rbp)
  je     L54
  cmpl   $0x2,-0x30(%rbp)
  je     L52
  jmp    L53
L54:
  mov    -0x18(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L53
L52:
  mov    -0x10(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L53
L12:
  mov    -0x8(%rbp),%rax
  mov    -0x2c(%rbp),%edx
  mov    %edx,(%rax)
  nop
L53:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void write_mem(void *addr, uint32_t value, uint32_t size) {
  int i;
  uint8_t *addr8 = addr;
  uint16_t *addr16 = addr;
  uint32_t *addr32 = addr;
  switch (size) {
  case 1:
    *addr8 = value;
    break;
  case 2:
    *addr16 = value;
    break;
  case 4:
    *addr32 = value;
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_mem>:
  endbr64
  cmp    $0x2,%edx
  je     L20
  cmp    $0x4,%edx
  je     L14
  cmp    $0x1,%edx
  je     L10
L5:
  ret
L10:
  mov    %esi,(%rdi)
  ret
L20:
  mov    %esi,(%rdi)
  ret
L14:
  mov    %esi,(%rdi)
  jmp    L5
```

assistant: ```c
void write_mem(void *addr, uint32_t value, uint32_t size) {
  int i;
  uint8_t *addr8 = addr;
  uint16_t *addr16 = addr;
  uint32_t *addr32 = addr;
  switch (size) {
  case 1:
    *addr8 = value;
    break;
  case 2:
    *addr16 = value;
    break;
  case 4:
    *addr32 = value;
    break;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_mem>:
  endbr64
  cmp    $0x2,%edx
  jg     L15
  test   %edx,%edx
  jg     L18
L13:
  ret
  xchg   %ax,%ax
L15:
  cmp    $0x4,%edx
  jne    L13
L18:
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_mem(void *addr, uint32_t value, uint32_t size) {
  int i;
  uint8_t *addr8 = addr;
  uint16_t *addr16 = addr;
  uint32_t *addr32 = addr;
  switch (size) {
  case 1:
    *addr8 = value;
    break;
  case 2:
    *addr16 = value;
    break;
  case 4:
    *addr32 = value;
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_mem>:
  endbr64
  cmp    $0x2,%edx
  jg     L1
  test   %edx,%edx
  jg     L11
L18:
  ret
  xchg   %ax,%ax
L1:
  cmp    $0x4,%edx
  jne    L18
L11:
  mov    %esi,(%rdi)
  ret
```

assistant: ```c
void write_mem(void *addr, uint32_t value, uint32_t size) {
  int i;
  uint8_t *addr8 = addr;
  uint16_t *addr16 = addr;
  uint32_t *addr32 = addr;
  switch (size) {
  case 1:
    *addr8 = value;
    break;
  case 2:
    *addr16 = value;
    break;
  case 4:
    *addr32 = value;
    break;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ResetISR>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe000ed88,%eax
  mov    (%rax),%edx
  mov    $0xe000ed88,%eax
  or     $0xf00000,%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <__iar_program_start@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ResetISR(void) {
  (*((volatile uint32_t *)(0xE000ED88))) = (((*((volatile uint32_t *)(0xE000ED88))) & ~(0x00300000 | 0x00C00000)) | 0x00300000 | 0x00C00000);
  __iar_program_start();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x40(%rbp)
  movl   $0x1e,-0x3c(%rbp)
  movl   $0x3c,-0x38(%rbp)
  movl   $0x64,-0x34(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x7,-0x28(%rbp)
  movl   $0x9,-0x24(%rbp)
  movl   $0x50,-0x20(%rbp)
  movl   $0x28,-0x1c(%rbp)
  movl   $0x37,-0x18(%rbp)
  movl   $0x16,-0x14(%rbp)
  movl   $0x63,-0x10(%rbp)
  movl   $0xd,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L11
L20:
  mov    -0x48(%rbp),%edx
  mov    -0x44(%rbp),%eax
  lea    -0x1(%rax),%esi
  lea    -0x40(%rbp),%rax
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <findRank@plt>
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x48(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L11:
  mov    -0x48(%rbp),%eax
  cmp    $0x3e8,%eax
  jne    L20
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D33
type: string
name: unpack_data
arguments: data_tag: D5
type: string
name: unpack_data
arguments: data_tag: D32
type: string
name: unpack_data
arguments: data_tag: D4
type: string

tool: D33: Try Ranks Below %d


tool: D5: Print 1000 to Quit!!

tool: D32: %d

tool: D4: 
 The element with rank %d is %d


assistant: ```c
int main(int argc, char *argv[]) {
  int a[] = {10, 30, 60, 100, 1, 2, 7, 9, 80, 40, 55, 22, 99};
  int size = sizeof(a) / sizeof(a[0]);
  int rank;
  printf("Try Ranks Below %d\n", size + 1);
  printf("Print 1000 to Quit!!\n");
  scanf("%d", &rank);
  while (rank != 1000) {
    printf("\n The element with rank %d is %d\n", rank, a[findRank(a, 0, size - 1, rank)]);
    scanf("%d", &rank);
  }
  printf("\n");
  return 0;
}
```