ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<vp8_short_fdct8x4_simd>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <vp8_short_fdct4x4_simd@plt>
  lea    0x20(%rbp),%rsi
  lea    0x8(%rbx),%rdi
  mov    %r12d,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1050 <vp8_short_fdct4x4_simd@plt>
```

assistant: ```c
void vp8_short_fdct8x4_simd(short *input, short *output, int pitch) {
  vp8_short_fdct4x4_simd(input, output, pitch);
  vp8_short_fdct4x4_simd(input + 4, output + 16, pitch);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<GyrCon_lc898122>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  mov    $0x0,%esi
  mov    $0x107,%edi
  call   <RegWriteA_lc898122@plt>
  cmpb   $0x1,-0x4(%rbp)
  jne    L5
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <ClrGyr_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_lc898122@plt>
  jmp    L22
L5:
  cmpb   $0x2,-0x4(%rbp)
  jne    L33
  mov    $0x3f800000,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_lc898122@plt>
  jmp    L22
L33:
  mov    $0x0,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x0,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_lc898122@plt>
L22:
  nop
  leave
  ret
```

assistant: ```c
void GyrCon_lc898122(unsigned char UcGyrCon) {
  RegWriteA_lc898122(0x0107, 0x00);
  if (UcGyrCon == 0x01) {
    ClrGyr_lc898122(0x000E, 0x02);
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else if (UcGyrCon == 0x02) {
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else {
    RamWrite32A_lc898122(0x10B5, 0x00000000);
    RamWrite32A_lc898122(0x11B5, 0x00000000);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<GyrCon_lc898122>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%esi
  mov    $0x107,%edi
  call   <RegWriteA_lc898122@plt>
  cmp    $0x1,%bl
  je     L10
  cmp    $0x2,%bl
  je     L23
  mov    $0x0,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x0,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_lc898122@plt>
L17:
  pop    %rbx
  ret
L10:
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <ClrGyr_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_lc898122@plt>
  jmp    L17
L23:
  mov    $0x3f800000,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x11b5,%edi
  call   <RamWrite32A_lc898122@plt>
  jmp    L17
```

assistant: ```c
void GyrCon_lc898122(unsigned char UcGyrCon) {
  RegWriteA_lc898122(0x0107, 0x00);
  if (UcGyrCon == 0x01) {
    ClrGyr_lc898122(0x000E, 0x02);
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else if (UcGyrCon == 0x02) {
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else {
    RamWrite32A_lc898122(0x10B5, 0x00000000);
    RamWrite32A_lc898122(0x11B5, 0x00000000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GyrCon_lc898122>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %edi,%ebx
  mov    $0x107,%edi
  call   <RegWriteA_lc898122@plt>
  cmp    $0x1,%bl
  je     L2
  cmp    $0x2,%bl
  je     L8
  xor    %esi,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  xor    %esi,%esi
  mov    $0x11b5,%edi
  pop    %rbx
  jmp    1070 <RamWrite32A_lc898122@plt>
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <ClrGyr_lc898122@plt>
L8:
  mov    $0x3f800000,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x11b5,%edi
  pop    %rbx
  jmp    1070 <RamWrite32A_lc898122@plt>
```

assistant: ```c
void GyrCon_lc898122(unsigned char UcGyrCon) {
  RegWriteA_lc898122(0x0107, 0x00);
  if (UcGyrCon == 0x01) {
    ClrGyr_lc898122(0x000E, 0x02);
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else if (UcGyrCon == 0x02) {
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else {
    RamWrite32A_lc898122(0x10B5, 0x00000000);
    RamWrite32A_lc898122(0x11B5, 0x00000000);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<GyrCon_lc898122>:
  endbr64
  push   %rbx
  xor    %esi,%esi
  mov    %edi,%ebx
  mov    $0x107,%edi
  call   <RegWriteA_lc898122@plt>
  cmp    $0x1,%bl
  je     L10
  cmp    $0x2,%bl
  je     L13
  xor    %esi,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  xor    %esi,%esi
  mov    $0x11b5,%edi
  pop    %rbx
  jmp    1070 <RamWrite32A_lc898122@plt>
  cs nopw 0x0(%rax,%rax,1)
L10:
  mov    $0x2,%esi
  mov    $0xe,%edi
  call   <ClrGyr_lc898122@plt>
L13:
  mov    $0x3f800000,%esi
  mov    $0x10b5,%edi
  call   <RamWrite32A_lc898122@plt>
  mov    $0x3f800000,%esi
  mov    $0x11b5,%edi
  pop    %rbx
  jmp    1070 <RamWrite32A_lc898122@plt>
```

assistant: ```c
void GyrCon_lc898122(unsigned char UcGyrCon) {
  RegWriteA_lc898122(0x0107, 0x00);
  if (UcGyrCon == 0x01) {
    ClrGyr_lc898122(0x000E, 0x02);
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else if (UcGyrCon == 0x02) {
    RamWrite32A_lc898122(0x10B5, 0x3F800000);
    RamWrite32A_lc898122(0x11B5, 0x3F800000);
  } else {
    RamWrite32A_lc898122(0x10B5, 0x00000000);
    RamWrite32A_lc898122(0x11B5, 0x00000000);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x410(%rbp)
  movq   $0x0,-0x408(%rbp)
  lea    -0x400(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x7e,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x418(%rbp)
  movl   $0x0,-0x414(%rbp)
  jmp    L36
L20:
  addl   $0x1,-0x418(%rbp)
L36:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x418(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x410(%rbp,%rdx,1)
  mov    -0x418(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  jne    L20
  mov    -0x418(%rbp),%eax
  cltq
  movb   $0x0,-0x410(%rbp,%rax,1)
  movl   $0x0,-0x418(%rbp)
  movl   $0x0,-0x418(%rbp)
  jmp    L54
L56:
  mov    -0x418(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L27
  addl   $0x1,-0x414(%rbp)
L27:
  addl   $0x1,-0x418(%rbp)
L54:
  mov    -0x418(%rbp),%eax
  cltq
  movzbl -0x410(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L56
  addl   $0x1,-0x414(%rbp)
  mov    -0x414(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type: string

tool: D5: %d

assistant: ```c
int main() {
  char array[1024] = {};
  int i = 0, count = 0;
  while ('\n' != (array[i] = getchar())) {
    i++;
  }
  array[i] = '\0';
  i = 0;
  for (i = 0; '\0' != array[i]; i++) {
    if (' ' == array[i])
      count += 1;
  }
  count += 1;
  printf("%d", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x418,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x7e,%ecx
  rep stos %rax,%es:(%rdi)
  mov    $0x0,%ebx
L42:
  mov    %ebx,%ebp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L42
  movslq %ebp,%rbp
  movb   $0x0,(%rsp,%rbp,1)
  movzbl (%rsp),%eax
  test   %al,%al
  je     L21
  lea    0x1(%rsp),%rdx
  mov    $0x0,%esi
L46:
  cmp    $0x20,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%esi
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L46
L6:
  add    $0x1,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  mov    $0x0,%eax
  add    $0x418,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  mov    $0x0,%esi
  jmp    L6
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string

tool: D3: %d

assistant: ```c
int main() {
  char array[1024] = {};
  int i = 0, count = 0;
  while ('\n' != (array[i] = getchar())) {
    i++;
  }
  array[i] = '\0';
  i = 0;
  for (i = 0; '\0' != array[i]; i++) {
    if (' ' == array[i])
      count += 1;
  }
  count += 1;
  printf("%d", count);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rsp,%r12
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L10
  movb   $0x0,(%rsp,%rbp,1)
  movzbl (%rsp),%eax
  test   %al,%al
  je     L30
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopl   0x0(%rax)
L17:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%esi
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L17
L32:
  add    $0x1,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  xor    %esi,%esi
  jmp    L32
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: %d

assistant: ```c
int main() {
  char array[1024] = {};
  int i = 0, count = 0;
  while ('\n' != (array[i] = getchar())) {
    i++;
  }
  array[i] = '\0';
  i = 0;
  for (i = 0; '\0' != array[i]; i++) {
    if (' ' == array[i])
      count += 1;
  }
  count += 1;
  printf("%d", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x7e,%ecx
  pxor   %xmm0,%xmm0
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x410,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x408(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  mov    %rsp,%r12
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax)
L19:
  xor    %eax,%eax
  movslq %ebx,%rbp
  call   <getchar@plt>
  mov    %al,(%r12,%rbx,1)
  add    $0x1,%rbx
  cmp    $0xa,%al
  jne    L19
  movb   $0x0,(%rsp,%rbp,1)
  movzbl (%rsp),%eax
  test   %al,%al
  je     L41
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopl   0x0(%rax)
L15:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%esi
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L15
L5:
  add    $0x1,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x408(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x410,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L41:
  xor    %esi,%esi
  jmp    L5
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type: string

tool: D9: %d

assistant: ```c
int main() {
  char array[1024] = {};
  int i = 0, count = 0;
  while ('\n' != (array[i] = getchar())) {
    i++;
  }
  array[i] = '\0';
  i = 0;
  for (i = 0; '\0' != array[i]; i++) {
    if (' ' == array[i])
      count += 1;
  }
  count += 1;
  printf("%d", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%ebx
  jmp    L2
L92:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L18
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  movslq %ebx,%rax
  lea    D25(%rip),%rcx
  mov    %dl,(%rax,%rcx,1)
  add    $0x1,%ebx
L2:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  cmp    $0xfe,%ebx
  jle    L92
  jmp    L14
L18:
  nop
L14:
  movslq %ebx,%rax
  lea    D25(%rip),%rdx
  movb   $0x0,(%rax,%rdx,1)
  test   %ebx,%ebx
  je     L55
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    $0x0,%r12d
  jmp    L40
L70:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movslq %r12d,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  add    $0x1,%ebx
  add    $0x1,%r12d
L40:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
  movslq %r12d,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L44
L55:
  movslq %ebx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L44:
  lea    D25(%rip),%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *strsplit(char *s, char *tok) {
  register i, j;
  static char out[(255) + 1];
  for (i = 0; s[i] && i < (255); i++) {
    if (strchr(tok, s[i]))
      break;
    else
      out[i] = s[i];
  }
  out[i] = 0;
  if (i && s[i]) {
    for (j = 0; s[i]; i++, j++)
      s[j] = s[i];
    s[j] = 0;
  } else if (!s[i])
    *s = 0;
  return out;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strsplit>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%r13
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L108
  lea    D17(%rip),%r12
  mov    %rdi,%rbx
  mov    $0x0,%ebp
L73:
  movsbl %sil,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L55
  movzbl (%rbx),%eax
  mov    %al,(%r12)
  add    $0x1,%ebp
  add    $0x1,%rbx
  movzbl (%rbx),%esi
  add    $0x1,%r12
  cmp    $0xfe,%ebp
  jg     L55
  test   %sil,%sil
  jne    L73
L55:
  movslq %ebp,%rax
  lea    D17(%rip),%rdx
  movb   $0x0,(%rdx,%rax,1)
  test   %ebp,%ebp
  je     L50
  cmpb   $0x0,(%rbx)
  je     L100
  mov    %rax,%rbp
  add    %r14,%rbp
  movzbl 0x0(%rbp),%edx
  test   %dl,%dl
  je     L99
  mov    $0x1,%eax
L92:
  mov    %dl,-0x1(%r14,%rax,1)
  mov    %eax,%ecx
  add    $0x1,%rax
  movzbl -0x1(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L92
L30:
  movslq %ecx,%rcx
  movb   $0x0,(%r14,%rcx,1)
  jmp    L19
L99:
  mov    $0x0,%ecx
  jmp    L30
L108:
  movb   $0x0,D17(%rip)
  mov    %rdi,%rbx
L50:
  cmpb   $0x0,(%rbx)
  jne    L19
L100:
  movb   $0x0,(%r14)
L19:
  lea    D17(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strsplit(char *s, char *tok) {
  register i, j;
  static char out[(255) + 1];
  for (i = 0; s[i] && i < (255); i++) {
    if (strchr(tok, s[i]))
      break;
    else
      out[i] = s[i];
  }
  out[i] = 0;
  if (i && s[i]) {
    for (j = 0; s[i]; i++, j++)
      s[j] = s[i];
    s[j] = 0;
  } else if (!s[i])
    *s = 0;
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L121
  lea    D13(%rip),%r13
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  mov    %r13,%r15
  jmp    L93
  cs nopw 0x0(%rax,%rax,1)
L114:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  add    $0x1,%r14d
  mov    %al,(%r15)
  movsbl (%rbx),%esi
  test   %sil,%sil
  je     L4
  add    $0x1,%r15
  cmp    $0xff,%r14d
  je     L102
L93:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L114
  movslq %r14d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  test   %r14d,%r14d
  jne    L47
L109:
  cmpb   $0x0,(%rbx)
  je     L95
L64:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L4:
  movslq %r14d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
L47:
  cmpb   $0x0,(%rbx)
  je     L95
  movslq %r14d,%r14
  add    %r12,%r14
  movzbl (%r14),%edx
  test   %dl,%dl
  je     L95
  mov    $0x1,%eax
  nopl   0x0(%rax)
L68:
  mov    %dl,-0x1(%r12,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%r14,%rax,1),%edx
  test   %dl,%dl
  jne    L68
  add    %rcx,%r12
L95:
  movb   $0x0,(%r12)
  jmp    L64
L102:
  movb   $0x0,D26(%rip)
  jmp    L47
L121:
  movb   $0x0,D13(%rip)
  mov    %rdi,%rbx
  lea    D13(%rip),%r13
  jmp    L109
```

assistant: ```c
char *strsplit(char *s, char *tok) {
  register i, j;
  static char out[(255) + 1];
  for (i = 0; s[i] && i < (255); i++) {
    if (strchr(tok, s[i]))
      break;
    else
      out[i] = s[i];
  }
  out[i] = 0;
  if (i && s[i]) {
    for (j = 0; s[i]; i++, j++)
      s[j] = s[i];
    s[j] = 0;
  } else if (!s[i])
    *s = 0;
  return out;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%esi
  test   %sil,%sil
  je     L0
  lea    D29(%rip),%r13
  mov    %rdi,%rbx
  xor    %r14d,%r14d
  mov    %r13,%r15
  jmp    L105
  cs nopw 0x0(%rax,%rax,1)
L47:
  movzbl (%rbx),%eax
  add    $0x1,%rbx
  add    $0x1,%r14d
  mov    %al,(%r15)
  movsbl (%rbx),%esi
  test   %sil,%sil
  je     L51
  add    $0x1,%r15
  cmp    $0xff,%r14d
  je     L35
L105:
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L47
  movslq %r14d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
  test   %r14d,%r14d
  jne    L59
L83:
  cmpb   $0x0,(%rbx)
  je     L71
L109:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L51:
  movslq %r14d,%rax
  movb   $0x0,0x0(%r13,%rax,1)
L59:
  cmpb   $0x0,(%rbx)
  je     L71
  movslq %r14d,%r14
  add    %r12,%r14
  movzbl (%r14),%edx
  test   %dl,%dl
  je     L71
  mov    $0x1,%eax
  nopl   0x0(%rax)
L85:
  mov    %dl,-0x1(%r12,%rax,1)
  movslq %eax,%rcx
  add    $0x1,%rax
  movzbl -0x1(%r14,%rax,1),%edx
  test   %dl,%dl
  jne    L85
  add    %rcx,%r12
L71:
  movb   $0x0,(%r12)
  jmp    L109
L35:
  movb   $0x0,D24(%rip)
  jmp    L59
L0:
  movb   $0x0,D29(%rip)
  mov    %rdi,%rbx
  lea    D29(%rip),%r13
  jmp    L83
```

assistant: ```c
char *strsplit(char *s, char *tok) {
  register i, j;
  static char out[(255) + 1];
  for (i = 0; s[i] && i < (255); i++) {
    if (strchr(tok, s[i]))
      break;
    else
      out[i] = s[i];
  }
  out[i] = 0;
  if (i && s[i]) {
    for (j = 0; s[i]; i++, j++)
      s[j] = s[i];
    s[j] = 0;
  } else if (!s[i])
    *s = 0;
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L4
L18:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x38(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  mov    %eax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L4:
  mov    -0x1c(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *temp;
  i = 0;
  temp = (int *)malloc(sizeof(*tab) * length);
  while (i < length) {
    temp[i] = f(tab[i]);
    i++;
  }
  return (temp);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_map>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %rdx,%r12
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %ebx,%ebx
  jle    L18
  mov    %ebx,%ebx
  lea    (%rax,%rbx,4),%r13
  mov    %rax,%rbx
  sub    %rax,%rbp
L13:
  mov    0x0(%rbp,%rbx,1),%edi
  call   *%r12
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L13
L18:
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *temp;
  i = 0;
  temp = (int *)malloc(sizeof(*tab) * length);
  while (i < length) {
    temp[i] = f(tab[i]);
    i++;
  }
  return (temp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_map>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L19
  lea    (%rax,%rbx,4),%r12
  sub    %rax,%r14
  mov    %rax,%rbx
  nopl   0x0(%rax)
L14:
  mov    (%r14,%rbx,1),%edi
  add    $0x4,%rbx
  call   *%rbp
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L14
L19:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *temp;
  i = 0;
  temp = (int *)malloc(sizeof(*tab) * length);
  while (i < length) {
    temp[i] = f(tab[i]);
    i++;
  }
  return (temp);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_map>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %esi,%ebx
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L8
  lea    (%rax,%rbx,4),%r12
  sub    %rax,%r14
  mov    %rax,%rbx
  nopl   0x0(%rax)
L10:
  mov    (%r14,%rbx,1),%edi
  add    $0x4,%rbx
  call   *%rbp
  mov    %eax,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L10
L8:
  pop    %rbx
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *ft_map(int *tab, int length, int (*f)(int)) {
  int i;
  int *temp;
  i = 0;
  temp = (int *)malloc(sizeof(*tab) * length);
  while (i < length) {
    temp[i] = f(tab[i]);
    i++;
  }
  return (temp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bbm_com_hostif_select>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bbm_hostif_select@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
signed int bbm_com_hostif_select(void *handle, unsigned int hostif) {
  signed int res;
  res = bbm_hostif_select(handle, hostif);
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bbm_com_hostif_select>:
  endbr64
  sub    $0x8,%rsp
  call   <bbm_hostif_select@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed int bbm_com_hostif_select(void *handle, unsigned int hostif) {
  signed int res;
  res = bbm_hostif_select(handle, hostif);
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<bbm_com_hostif_select>:
  endbr64
  jmp    1050 <bbm_hostif_select@plt>
```

assistant: ```c
signed int bbm_com_hostif_select(void *handle, unsigned int hostif) {
  signed int res;
  res = bbm_hostif_select(handle, hostif);
  return res;
}
```