user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L133
  mov    (%rsp),%ebx
  test   %ebx,%ebx
  je     L187
  js     L65
  test   %eax,%eax
  js     L73
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  mov    %edx,(%rsp)
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,0x4(%rsp)
L63:
  mov    0x4(%rsp),%edi
  mov    (%rsp),%esi
  cmp    %esi,%edi
  mov    %esi,%ecx
  cmovle %edi,%ecx
  cmp    $0x1,%ecx
  jg     L177
  jmp    L158
L133:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%ebx
  jmp    L56
L187:
  mov    $0x30,%edi
  call   <putchar@plt>
  jmp    L56
L42:
  sub    $0x1,%ecx
  cmp    $0x1,%ecx
  je     L158
L177:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L42
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L42
L158:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%esi
  mov    %eax,(%rsp)
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edi
  mov    %eax,0x4(%rsp)
  mov    %esi,%eax
  cltd
  idiv   %edi
  test   %eax,%eax
  jne    L19
  mov    %esi,%eax
  cltd
  idiv   %edi
  mov    %edx,%ebx
  test   %edx,%edx
  jne    L128
L56:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L138
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L19:
  mov    %eax,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    (%rsp),%eax
  cltd
  idivl  0x4(%rsp)
  mov    %edx,%ebx
  test   %edx,%edx
  je     L56
  mov    $0x20,%edi
  call   <putchar@plt>
L128:
  mov    0x4(%rsp),%edx
  mov    %ebx,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  jmp    L56
L6:
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  mov    %edx,(%rsp)
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,0x4(%rsp)
L8:
  mov    $0x2d,%edi
  call   <putchar@plt>
  jmp    L63
L65:
  test   %eax,%eax
  jns    L6
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  mov    %edx,(%rsp)
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,0x4(%rsp)
  jmp    L63
L73:
  mov    %ebx,%edx
  neg    %edx
  cmovs  %ebx,%edx
  mov    %edx,(%rsp)
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,0x4(%rsp)
  jmp    L8
L138:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D28
data_type: string
name: unpack_data
arguments: data_tag: D39
data_type: string
name: unpack_data
arguments: data_tag: D34
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D28: %d%d

tool: D39: Divide by zero!

tool: D34: %d

tool: D7: %d/%d

assistant: ```c
int main(void) {
  int num, denom, neg = 1, gcd, whole_no, rmdr;
  scanf("%d%d", &num, &denom);
  if (denom == 0) {
    printf("Divide by zero!");
    return -1;
  } else if (num == 0) {
    printf("0");
    return 0;
  }
  if (num < 0)
    neg *= -1;
  if (denom < 0)
    neg *= -1;
  num = abs(num);
  denom = abs(denom);
  if (neg == -1)
    printf("-");
  gcd = (num < denom) ? num : denom;
  while (gcd > 1) {
    if (num % gcd == 0 && denom % gcd == 0)
      break;
    gcd--;
  }
  num /= gcd;
  denom /= gcd;
  whole_no = num / denom;
  if (whole_no != 0)
    printf("%d", whole_no);
  rmdr = num % denom;
  if (whole_no != 0 && rmdr != 0)
    printf(" ");
  if (rmdr != 0)
    printf("%d/%d", rmdr, denom);
  return 0;
}
```