ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_input_num>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x78,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,0x4(%rsp)
  mov    %ecx,%ebp
  mov    %r8d,(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D32(%rip),%r15
  lea    0x10(%rsp),%r12
  lea    D34(%rip),%r14
  jmp    L34
L40:
  mov    0x4(%rsp),%edi
  call   <showhelp@plt>
  jmp    L34
L104:
  mov    %ebx,%eax
  cmpb   $0x64,0x10(%rsp)
  jne    L23
L56:
  cmp    %ebp,%eax
  jl     L14
  cmp    (%rsp),%eax
  jle    L70
L14:
  mov    (%rsp),%edx
  mov    %ebp,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L34:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  movzbl 0x10(%rsp),%edi
  cmp    $0x78,%dil
  je     L105
  cmp    $0x3f,%dil
  je     L40
  movsbl %dil,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L104
  movzbl 0x10(%rsp),%eax
  cmp    $0x64,%al
  je     L104
  cmp    $0x2d,%al
  je     L104
  mov    (%rsp),%edx
  mov    %ebp,%esi
  lea    D30(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L23:
  mov    %r12,%rdi
  call   <atoi@plt>
  jmp    L56
L70:
  mov    0x8(%rsp),%rcx
  mov    %eax,(%rcx)
  mov    $0x0,%eax
  jmp    L85
L105:
  mov    $0x1,%eax
L85:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L126
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L126:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D32
type: string
name: read_data
arguments: data_label: D34
type: string
name: read_data
arguments: data_label: D30
type: string

tool: D32: 
Please enter %s (default = %d) -> 

tool: D34: %s

tool: D30: Please enter "?", "x", "d" or an integer value between %d and %d.

assistant: ```c
int get_input_num(char *name, int defaultval, int helpnum, int minval, int maxval, int *retval) {
  char str[80];
  int i;
  for (;;) {
    printf("\nPlease enter %s (default = %d) -> ", name, defaultval);
    scanf("%s", str);
    if (str[0] == 'x')
      return 1;
    if (str[0] == '?')
      showhelp(helpnum);
    else if (isdigit(str[0]) || (str[0] == '-') || str[0] == 'd') {
      if (str[0] == 'd')
        i = defaultval;
      else
        i = atoi(str);
      if (i < minval || i > maxval)
        printf("Please enter \"?\", \"x\", \"d\" or an integer value between %d and %d.", minval, maxval);
      else {
        *retval = i;
        return 0;
      }
    } else
      printf("Please enter \"?\", \"x\", \"d\" or an integer value between %d and %d.", minval, maxval);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_input_num>:
  endbr64
  push   %r15
  lea    D9(%rip),%r15
  push   %r14
  lea    D14(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x78,%rsp
  mov    %edx,0x4(%rsp)
  lea    0x10(%rsp),%r12
  mov    %r8d,(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L83:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%edi
  cmp    $0x78,%dil
  je     L45
  cmp    $0x3f,%dil
  je     L22
  call   <isdigit@plt>
  movzbl 0x10(%rsp),%edx
  test   %rax,%rax
  jne    L50
  cmp    $0x64,%dl
  je     L50
  cmp    $0x2d,%dl
  jne    L64
L50:
  mov    %ebx,%eax
  cmp    $0x64,%dl
  je     L109
  mov    %r12,%rdi
  call   <atoi@plt>
L109:
  cmp    %ebp,%eax
  jl     L64
  cmp    (%rsp),%eax
  jle    L0
L64:
  mov    (%rsp),%edx
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L83
  nopl   0x0(%rax)
L22:
  mov    0x4(%rsp),%edi
  call   <showhelp@plt>
  jmp    L83
  cs nopw 0x0(%rax,%rax,1)
L45:
  mov    $0x1,%eax
L85:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L88
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L0:
  mov    0x8(%rsp),%rcx
  mov    %eax,(%rcx)
  xor    %eax,%eax
  jmp    L85
L88:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
data_type: string
name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D22
data_type: string

tool: D9: 
Please enter %s (default = %d) -> 

tool: D14: %s

tool: D22: Please enter "?", "x", "d" or an integer value between %d and %d.

assistant: ```c
int get_input_num(char *name, int defaultval, int helpnum, int minval, int maxval, int *retval) {
  char str[80];
  int i;
  for (;;) {
    printf("\nPlease enter %s (default = %d) -> ", name, defaultval);
    scanf("%s", str);
    if (str[0] == 'x')
      return 1;
    if (str[0] == '?')
      showhelp(helpnum);
    else if (isdigit(str[0]) || (str[0] == '-') || str[0] == 'd') {
      if (str[0] == 'd')
        i = defaultval;
      else
        i = atoi(str);
      if (i < minval || i > maxval)
        printf("Please enter \"?\", \"x\", \"d\" or an integer value between %d and %d.", minval, maxval);
      else {
        *retval = i;
        return 0;
      }
    } else
      printf("Please enter \"?\", \"x\", \"d\" or an integer value between %d and %d.", minval, maxval);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_input_num>:
  endbr64
  push   %r15
  lea    D20(%rip),%r15
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x78,%rsp
  mov    %edx,0x4(%rsp)
  lea    0x10(%rsp),%r12
  mov    %r8d,(%rsp)
  mov    %r9,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  nopl   0x0(%rax)
L11:
  mov    %ebx,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%edi
  cmp    $0x78,%dil
  je     L92
  cmp    $0x3f,%dil
  je     L43
  call   <isdigit@plt>
  movzbl 0x10(%rsp),%edx
  test   %rax,%rax
  jne    L47
  cmp    $0x64,%dl
  je     L47
  cmp    $0x2d,%dl
  jne    L24
L47:
  mov    %ebx,%eax
  cmp    $0x64,%dl
  je     L74
  mov    %r12,%rdi
  call   <atoi@plt>
L74:
  cmp    %ebp,%eax
  jl     L24
  cmp    (%rsp),%eax
  jle    L21
L24:
  mov    (%rsp),%edx
  mov    %ebp,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L11
  nopl   0x0(%rax)
L43:
  mov    0x4(%rsp),%edi
  call   <showhelp@plt>
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L92:
  mov    $0x1,%eax
L33:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x78,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L21:
  mov    0x8(%rsp),%rcx
  mov    %eax,(%rcx)
  xor    %eax,%eax
  jmp    L33
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D20
datatype: string
name: read_data
arguments: tag: D21
datatype: string
name: read_data
arguments: tag: D6
datatype: string

tool: D20: 
Please enter %s (default = %d) -> 

tool: D21: %s

tool: D6: Please enter "?", "x", "d" or an integer value between %d and %d.

assistant: ```c
int get_input_num(char *name, int defaultval, int helpnum, int minval, int maxval, int *retval) {
  char str[80];
  int i;
  for (;;) {
    printf("\nPlease enter %s (default = %d) -> ", name, defaultval);
    scanf("%s", str);
    if (str[0] == 'x')
      return 1;
    if (str[0] == '?')
      showhelp(helpnum);
    else if (isdigit(str[0]) || (str[0] == '-') || str[0] == 'd') {
      if (str[0] == 'd')
        i = defaultval;
      else
        i = atoi(str);
      if (i < minval || i > maxval)
        printf("Please enter \"?\", \"x\", \"d\" or an integer value between %d and %d.", minval, maxval);
      else {
        *retval = i;
        return 0;
      }
    } else
      printf("Please enter \"?\", \"x\", \"d\" or an integer value between %d and %d.", minval, maxval);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<write_dmatrix_number_k>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    %r9,-0x30(%rbp)
  mov    0x18(%rbp),%eax
  mov    %eax,%ecx
  mov    0x10(%rbp),%rdx
  lea    D14(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x30(%rbp),%r9
  mov    -0x28(%rbp),%r8
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x8(%rbp),%rax
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  push   %rdi
  mov    %rax,%rdi
  call   <write_dmatrix_number@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D14
datatype: string

tool: D14: %s%02d.txt

assistant: ```c
void write_dmatrix_number_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_dmatrix_number_k>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r9,%r14
  mov    0x58(%rsp),%ecx
  mov    0x50(%rsp),%rdx
  lea    D3(%rip),%rsi
  lea    D15(%rip),%r15
  mov    %r15,%rdi
  call   <sprintf@plt>
  sub    $0x8,%rsp
  push   %r15
  mov    %r14,%r9
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    0x18(%rsp),%rdi
  call   <write_dmatrix_number@plt>
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D3
type_guessed: string

tool: D3: %s%02d.txt

assistant: ```c
void write_dmatrix_number_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_dmatrix_number_k>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D22(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D12(%rip),%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%ecx
  mov    0x40(%rsp),%rdx
  call   <sprintf@plt>
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    D12(%rip),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rdi,0x40(%rsp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <write_dmatrix_number@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D22
datatype: string

tool: D22: %s%02d.txt

assistant: ```c
void write_dmatrix_number_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_dmatrix_number_k>:
  endbr64
  push   %r15
  mov    %r9,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  lea    D24(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    D28(%rip),%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    0x48(%rsp),%ecx
  mov    0x40(%rsp),%rdx
  call   <sprintf@plt>
  mov    %r15,%r9
  mov    %rbx,%r8
  mov    %r14,%rcx
  lea    D28(%rip),%rdi
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rdi,0x40(%rsp)
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <write_dmatrix_number@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
type_infered: string

tool: D24: %s%02d.txt

assistant: ```c
void write_dmatrix_number_k(double **m, long nrl, long nrh, long ncl, long nch, char *format, char *filename, int k) {
  static char filename_k[256];
  sprintf(filename_k, "%s%02d.txt", filename, k);
  write_dmatrix_number(m, nrl, nrh, ncl, nch, format, filename_k);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bachk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L58
  mov    $0xffffffff,%eax
  jmp    L117
L58:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x11,%eax
  je     L63
  mov    $0xffffffff,%eax
  jmp    L117
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L104
  mov    $0xffffffff,%eax
  jmp    L117
L104:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L34
  mov    $0xffffffff,%eax
  jmp    L117
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L56
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  je     L63
  mov    $0xffffffff,%eax
  jmp    L117
L63:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  jmp    L23
L56:
  nop
L23:
  mov    $0x0,%eax
L117:
  leave
  ret
```

assistant: ```c
int bachk(const char *str) {
  if (!str)
    return -1;
  if (strlen(str) != 17)
    return -1;
  while (*str) {
    if (!isxdigit(*str++))
      return -1;
    if (!isxdigit(*str++))
      return -1;
    if (*str == 0)
      break;
    if (*str++ != ':')
      return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bachk>:
  endbr64
  test   %rdi,%rdi
  je     L4
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x11,%eax
  jne    L89
L94:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L22
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L40
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L108
  movzbl 0x2(%rbx),%eax
  test   %al,%al
  je     L5
  add    $0x3,%rbx
  cmp    $0x3a,%al
  je     L94
  mov    $0xffffffff,%eax
  jmp    L60
L22:
  mov    $0x0,%eax
L60:
  pop    %rbx
  ret
L4:
  mov    $0xffffffff,%eax
  ret
L89:
  mov    $0xffffffff,%eax
  jmp    L60
L40:
  mov    $0xffffffff,%eax
  jmp    L60
L108:
  mov    $0xffffffff,%eax
  jmp    L60
L5:
  mov    $0x0,%eax
  jmp    L60
```

assistant: ```c
int bachk(const char *str) {
  if (!str)
    return -1;
  if (strlen(str) != 17)
    return -1;
  while (*str) {
    if (!isxdigit(*str++))
      return -1;
    if (!isxdigit(*str++))
      return -1;
    if (*str == 0)
      break;
    if (*str++ != ':')
      return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bachk>:
  endbr64
  test   %rdi,%rdi
  je     L18
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x11,%eax
  je     L9
  jmp    L78
  nopl   0x0(%rax)
L58:
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L78
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L78
  movzbl 0x2(%rbx),%eax
  test   %al,%al
  je     L12
  add    $0x3,%rbx
  cmp    $0x3a,%al
  jne    L78
L9:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L58
L12:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L78:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L18:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int bachk(const char *str) {
  if (!str)
    return -1;
  if (strlen(str) != 17)
    return -1;
  while (*str) {
    if (!isxdigit(*str++))
      return -1;
    if (!isxdigit(*str++))
      return -1;
    if (*str == 0)
      break;
    if (*str++ != ':')
      return -1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bachk>:
  endbr64
  test   %rdi,%rdi
  je     L23
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cmp    $0x11,%eax
  je     L34
  jmp    L36
  nopl   0x0(%rax)
L17:
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L36
  movsbl 0x1(%rbx),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L36
  movzbl 0x2(%rbx),%eax
  test   %al,%al
  je     L76
  add    $0x3,%rbx
  cmp    $0x3a,%al
  jne    L36
L34:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
L76:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int bachk(const char *str) {
  if (!str)
    return -1;
  if (strlen(str) != 17)
    return -1;
  while (*str) {
    if (!isxdigit(*str++))
      return -1;
    if (!isxdigit(*str++))
      return -1;
    if (*str == 0)
      break;
    if (*str++ != ':')
      return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Mfopen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L6
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  jmp    L13
L6:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <tcFopen@plt>
L13:
  leave
  ret
```

assistant: ```c
int Mfopen(int nargs, int *args) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *filename = (char *)args[0];
  char *mode = (char *)args[1];
  return tcFopen(filename, mode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Mfopen>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L16
  movslq 0x4(%rsi),%rax
  movslq (%rsi),%rdi
  mov    %rax,%rsi
  call   <tcFopen@plt>
L19:
  add    $0x8,%rsp
  ret
L16:
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int Mfopen(int nargs, int *args) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *filename = (char *)args[0];
  char *mode = (char *)args[1];
  return tcFopen(filename, mode);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Mfopen>:
  endbr64
  cmp    $0x1,%edi
  jle    L7
  movslq 0x4(%rsi),%r8
  movslq (%rsi),%rdi
  mov    %r8,%rsi
  jmp    1060 <tcFopen@plt>
L7:
  sub    $0x8,%rsp
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Mfopen(int nargs, int *args) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *filename = (char *)args[0];
  char *mode = (char *)args[1];
  return tcFopen(filename, mode);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Mfopen>:
  endbr64
  cmp    $0x1,%edi
  jle    L3
  movslq 0x4(%rsi),%r8
  movslq (%rsi),%rdi
  mov    %r8,%rsi
  jmp    1060 <tcFopen@plt>
L3:
  sub    $0x8,%rsp
  mov    $0x15,%edi
  call   <eset@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int Mfopen(int nargs, int *args) {
  if (nargs < 2) {
    eset(21);
    return -1;
  }
  char *filename = (char *)args[0];
  char *mode = (char *)args[1];
  return tcFopen(filename, mode);
}
```
user: Translate the below assembly code into C programming language:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L23
  mov    -0x20(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <f@plt>
  jmp    L19
L23:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void g(int *x, int *y) {
  int z;
  z = *y;
  if (z > 0)
    f(&z, y);
  else
    *x = z;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<g>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L0
  mov    %eax,(%rdi)
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L0:
  lea    0x4(%rsp),%rdi
  call   <f@plt>
  jmp    L28
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void g(int *x, int *y) {
  int z;
  z = *y;
  if (z > 0)
    f(&z, y);
  else
    *x = z;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L18
  mov    %eax,(%rdi)
L21:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  lea    0x4(%rsp),%rdi
  call   <f@plt>
  jmp    L21
L27:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void g(int *x, int *y) {
  int z;
  z = *y;
  if (z > 0)
    f(&z, y);
  else
    *x = z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<g>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rsi),%eax
  mov    %eax,0x4(%rsp)
  test   %eax,%eax
  jg     L24
  mov    %eax,(%rdi)
L6:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  lea    0x4(%rsp),%rdi
  call   <f@plt>
  jmp    L6
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void g(int *x, int *y) {
  int z;
  z = *y;
  if (z > 0)
    f(&z, y);
  else
    *x = z;
}
```