ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getcondition_l_s_ns>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <emit@plt>
  lea    D23(%rip),%rdi
  call   <emit@plt>
  lea    D10(%rip),%rdi
  call   <emit@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <emit@plt>
```

tool_calls: name: read_data
arguments: label: D14
datatype: string
name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D7
datatype: string

tool: D14: push eax


tool: D23: neg al


tool: D10: xor al,ah


tool: D7: pop eax


assistant: ```c
void getcondition_l_s_ns(void) {
  emit("push eax\n");
  emit("neg al\n");
  emit("xor al,ah\n");
  emit("pop eax\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getcondition_l_s_ns>:
  endbr64
  sub    $0x8,%rsp
  lea    D34(%rip),%rdi
  call   <emit@plt>
  lea    D31(%rip),%rdi
  call   <emit@plt>
  lea    D16(%rip),%rdi
  call   <emit@plt>
  lea    D17(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <emit@plt>
```

tool_calls: name: parse_data
arguments: tag: D34
datatype: string
name: parse_data
arguments: tag: D31
datatype: string
name: parse_data
arguments: tag: D16
datatype: string
name: parse_data
arguments: tag: D17
datatype: string

tool: D34: push eax


tool: D31: neg al


tool: D16: xor al,ah


tool: D17: pop eax


assistant: ```c
void getcondition_l_s_ns(void) {
  emit("push eax\n");
  emit("neg al\n");
  emit("xor al,ah\n");
  emit("pop eax\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add_lib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <bproc_libadd@plt>
  test   %rax,%rax
  je     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void add_lib(char *libname) {
  if (bproc_libadd(libname)) {
    perror(libname);
    exit(1);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<add_lib>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <bproc_libadd@plt>
  test   %rax,%rax
  jne    L15
L10:
  pop    %rbx
  ret
L15:
  mov    %rbx,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L10
```

assistant: ```c
void add_lib(char *libname) {
  if (bproc_libadd(libname)) {
    perror(libname);
    exit(1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add_lib>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <bproc_libadd@plt>
  test   %rax,%rax
  jne    L2
  pop    %rbp
  ret
  nopl   0x0(%rax)
L2:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

assistant: ```c
void add_lib(char *libname) {
  if (bproc_libadd(libname)) {
    perror(libname);
    exit(1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<add_lib>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <bproc_libadd@plt>
  test   %rax,%rax
  jne    L1
  pop    %rbp
  ret
  nopl   0x0(%rax)
L1:
  mov    %rbp,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

assistant: ```c
void add_lib(char *libname) {
  if (bproc_libadd(libname)) {
    perror(libname);
    exit(1);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<cmalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc_error@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *cmalloc(size_t n) {
  void *q = malloc(n);
  if (q == NULL)
    malloc_error(n);
  return q;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L17
L19:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    %rbp,%rdi
  call   <malloc_error@plt>
  jmp    L19
```

assistant: ```c
void *cmalloc(size_t n) {
  void *q = malloc(n);
  if (q == NULL)
    malloc_error(n);
  return q;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L18
L8:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L18:
  mov    %rbp,%rdi
  call   <malloc_error@plt>
  jmp    L8
```

assistant: ```c
void *cmalloc(size_t n) {
  void *q = malloc(n);
  if (q == NULL)
    malloc_error(n);
  return q;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cmalloc>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L17
L7:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    %rbp,%rdi
  call   <malloc_error@plt>
  jmp    L7
```

assistant: ```c
void *cmalloc(size_t n) {
  void *q = malloc(n);
  if (q == NULL)
    malloc_error(n);
  return q;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
  jmp    L88
L65:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x5,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x5,%eax
  ja     L35
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D42(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D42(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  call   <create@plt>
  jmp    L76
  mov    $0x0,%eax
  call   <kill@plt>
  jmp    L76
  mov    $0x0,%eax
  call   <block@plt>
  jmp    L76
  mov    $0x0,%eax
  call   <wakeup@plt>
  jmp    L76
  movl   $0x0,-0xc(%rbp)
  jmp    L76
L35:
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L88
  nop
L76:
  cmpl   $0x0,-0xc(%rbp)
  je     L88
  mov    $0x0,%eax
  call   <schedule@plt>
  mov    $0x0,%eax
  call   <display@plt>
L88:
  cmpl   $0x0,-0xc(%rbp)
  jne    L65
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D12
type: string
name: extract_symbolic_data
arguments: label: D41
type: string
name: extract_symbolic_data
arguments: label: D39
type: string
name: extract_symbolic_data
arguments: label: D25
type: string

tool: D12: ######ProcessSimulation:  menu #####
1. create process  2. kill process
3. block process   4. wakeup process
5. just run        0. exit


tool: D41: ##########-->

tool: D39: %d

tool: D25: input error! Don't test my robustness ,,,


assistant: ```c
int main() {
  int run = 1;
  while (run) {
    printf("######ProcessSimulation:  menu #####\n1. create process  2. kill process\n3. block process   4. wakeup process\n5. just run        0. exit\n");
    printf("##########-->");
    int choice = 5;
    scanf("%d", &choice);
    switch (choice) {
    case 1: {
      create();
      break;
    }
    case 2: {
      kill();
      break;
    }
    case 3: {
      block();
      break;
    }
    case 4: {
      wakeup();
      break;
    }
    case 5: {
      break;
    }
    case 0: {
      run = 0;
      break;
    }
    default: {
      printf("input error! Don't test my robustness ,,,\n");
      continue;
      break;
    }
    }
    if (run) {
      schedule();
      display();
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D43(%rip),%r12
  lea    D35(%rip),%rbp
  lea    D49(%rip),%rbx
  lea    D31(%rip),%r13
  jmp    L73
  mov    $0x0,%eax
  call   <create@plt>
L8:
  mov    $0x0,%eax
  call   <schedule@plt>
  mov    $0x0,%eax
  call   <display@plt>
  mov    $0x1,%eax
L16:
  test   %eax,%eax
  je     L65
L73:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  movl   $0x5,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x5,%eax
  ja     L75
  mov    %eax,%edx
  lea    D25(%rip),%rcx
  movslq (%rcx,%rdx,4),%rdx
  add    %rcx,%rdx
  notrack jmp *%rdx
  mov    $0x0,%eax
  call   <kill@plt>
  jmp    L8
  mov    $0x0,%eax
  call   <block@plt>
  jmp    L8
  mov    $0x0,%eax
  call   <wakeup@plt>
  jmp    L8
L75:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L16
L65:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D43
type_infered: string
name: unpack_data
arguments: data_label: D35
type_infered: string
name: unpack_data
arguments: data_label: D49
type_infered: string
name: unpack_data
arguments: data_label: D31
type_infered: string

tool: D43: ######ProcessSimulation:  menu #####
1. create process  2. kill process
3. block process   4. wakeup process
5. just run        0. exit


tool: D35: ##########-->

tool: D49: %d

tool: D31: input error! Don't test my robustness ,,,


assistant: ```c
int main() {
  int run = 1;
  while (run) {
    printf("######ProcessSimulation:  menu #####\n1. create process  2. kill process\n3. block process   4. wakeup process\n5. just run        0. exit\n");
    printf("##########-->");
    int choice = 5;
    scanf("%d", &choice);
    switch (choice) {
    case 1: {
      create();
      break;
    }
    case 2: {
      kill();
      break;
    }
    case 3: {
      block();
      break;
    }
    case 4: {
      wakeup();
      break;
    }
    case 5: {
      break;
    }
    case 0: {
      run = 0;
      break;
    }
    default: {
      printf("input error! Don't test my robustness ,,,\n");
      continue;
      break;
    }
    }
    if (run) {
      schedule();
      display();
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D13(%rip),%r15
  push   %r14
  lea    D30(%rip),%r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  lea    D31(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x5,0x4(%rsp)
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L53
  mov    0x4(%rsp),%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <create@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L63
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <wakeup@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L63
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <block@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L63
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <kill@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L63
  nopw   0x0(%rax,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L63
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D13
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D22
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D11
type_infered: string

tool: D13: input error! Don't test my robustness ,,,


tool: D30: ######ProcessSimulation:  menu #####
1. create process  2. kill process
3. block process   4. wakeup process
5. just run        0. exit


tool: D22: ##########-->

tool: D11: %d

assistant: ```c
int main() {
  int run = 1;
  while (run) {
    printf("######ProcessSimulation:  menu #####\n1. create process  2. kill process\n3. block process   4. wakeup process\n5. just run        0. exit\n");
    printf("##########-->");
    int choice = 5;
    scanf("%d", &choice);
    switch (choice) {
    case 1: {
      create();
      break;
    }
    case 2: {
      kill();
      break;
    }
    case 3: {
      block();
      break;
    }
    case 4: {
      wakeup();
      break;
    }
    case 5: {
      break;
    }
    case 0: {
      run = 0;
      break;
    }
    default: {
      printf("input error! Don't test my robustness ,,,\n");
      continue;
      break;
    }
    }
    if (run) {
      schedule();
      display();
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D31(%rip),%r15
  push   %r14
  lea    D38(%rip),%r14
  push   %r13
  lea    D46(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  lea    D34(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  movl   $0x5,0x4(%rsp)
  call   <scanf@plt>
  cmpl   $0x5,0x4(%rsp)
  ja     L4
  mov    0x4(%rsp),%eax
  movslq (%rbx,%rax,4),%rax
  add    %rbx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
  xor    %eax,%eax
  call   <create@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <wakeup@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <block@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <kill@plt>
  xor    %eax,%eax
  call   <schedule@plt>
  xor    %eax,%eax
  call   <display@plt>
  jmp    L13
  nopw   0x0(%rax,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L13
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D31
data_type: string
name: unpack_data
arguments: data_tag: D38
data_type: string
name: unpack_data
arguments: data_tag: D46
data_type: string
name: unpack_data
arguments: data_tag: D12
data_type: string

tool: D31: input error! Don't test my robustness ,,,


tool: D38: ######ProcessSimulation:  menu #####
1. create process  2. kill process
3. block process   4. wakeup process
5. just run        0. exit


tool: D46: ##########-->

tool: D12: %d

assistant: ```c
int main() {
  int run = 1;
  while (run) {
    printf("######ProcessSimulation:  menu #####\n1. create process  2. kill process\n3. block process   4. wakeup process\n5. just run        0. exit\n");
    printf("##########-->");
    int choice = 5;
    scanf("%d", &choice);
    switch (choice) {
    case 1: {
      create();
      break;
    }
    case 2: {
      kill();
      break;
    }
    case 3: {
      block();
      break;
    }
    case 4: {
      wakeup();
      break;
    }
    case 5: {
      break;
    }
    case 0: {
      run = 0;
      break;
    }
    default: {
      printf("input error! Don't test my robustness ,,,\n");
      continue;
      break;
    }
    }
    if (run) {
      schedule();
      display();
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<colorcube>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <draw_polygon@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    $0x0,%edi
  call   <draw_polygon@plt>
  mov    $0x5,%ecx
  mov    $0x6,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <draw_polygon@plt>
  mov    $0x2,%ecx
  mov    $0x6,%edx
  mov    $0x7,%esi
  mov    $0x3,%edi
  call   <draw_polygon@plt>
  mov    $0x7,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    $0x4,%edi
  call   <draw_polygon@plt>
  mov    $0x4,%ecx
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <draw_polygon@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void colorcube() {
  draw_polygon(0, 3, 2, 1);
  draw_polygon(0, 4, 7, 3);
  draw_polygon(1, 2, 6, 5);
  draw_polygon(3, 7, 6, 2);
  draw_polygon(4, 5, 6, 7);
  draw_polygon(0, 1, 5, 4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<colorcube>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x2,%edx
  mov    $0x3,%esi
  mov    $0x0,%edi
  call   <draw_polygon@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  mov    $0x4,%esi
  mov    $0x0,%edi
  call   <draw_polygon@plt>
  mov    $0x5,%ecx
  mov    $0x6,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <draw_polygon@plt>
  mov    $0x2,%ecx
  mov    $0x6,%edx
  mov    $0x7,%esi
  mov    $0x3,%edi
  call   <draw_polygon@plt>
  mov    $0x7,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    $0x4,%edi
  call   <draw_polygon@plt>
  mov    $0x4,%ecx
  mov    $0x5,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <draw_polygon@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void colorcube() {
  draw_polygon(0, 3, 2, 1);
  draw_polygon(0, 4, 7, 3);
  draw_polygon(1, 2, 6, 5);
  draw_polygon(3, 7, 6, 2);
  draw_polygon(4, 5, 6, 7);
  draw_polygon(0, 1, 5, 4);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<colorcube>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x2,%edx
  xor    %edi,%edi
  mov    $0x3,%esi
  call   <draw_polygon@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  xor    %edi,%edi
  mov    $0x4,%esi
  call   <draw_polygon@plt>
  mov    $0x5,%ecx
  mov    $0x6,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <draw_polygon@plt>
  mov    $0x2,%ecx
  mov    $0x6,%edx
  mov    $0x7,%esi
  mov    $0x3,%edi
  call   <draw_polygon@plt>
  mov    $0x7,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    $0x4,%edi
  call   <draw_polygon@plt>
  mov    $0x4,%ecx
  xor    %edi,%edi
  add    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x1,%esi
  jmp    1050 <draw_polygon@plt>
```

assistant: ```c
void colorcube() {
  draw_polygon(0, 3, 2, 1);
  draw_polygon(0, 4, 7, 3);
  draw_polygon(1, 2, 6, 5);
  draw_polygon(3, 7, 6, 2);
  draw_polygon(4, 5, 6, 7);
  draw_polygon(0, 1, 5, 4);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<colorcube>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%ecx
  mov    $0x2,%edx
  xor    %edi,%edi
  mov    $0x3,%esi
  call   <draw_polygon@plt>
  mov    $0x3,%ecx
  mov    $0x7,%edx
  xor    %edi,%edi
  mov    $0x4,%esi
  call   <draw_polygon@plt>
  mov    $0x5,%ecx
  mov    $0x6,%edx
  mov    $0x2,%esi
  mov    $0x1,%edi
  call   <draw_polygon@plt>
  mov    $0x2,%ecx
  mov    $0x6,%edx
  mov    $0x7,%esi
  mov    $0x3,%edi
  call   <draw_polygon@plt>
  mov    $0x7,%ecx
  mov    $0x6,%edx
  mov    $0x5,%esi
  mov    $0x4,%edi
  call   <draw_polygon@plt>
  mov    $0x4,%ecx
  xor    %edi,%edi
  add    $0x8,%rsp
  mov    $0x5,%edx
  mov    $0x1,%esi
  jmp    1050 <draw_polygon@plt>
```

assistant: ```c
void colorcube() {
  draw_polygon(0, 3, 2, 1);
  draw_polygon(0, 4, 7, 3);
  draw_polygon(1, 2, 6, 5);
  draw_polygon(3, 7, 6, 2);
  draw_polygon(4, 5, 6, 7);
  draw_polygon(0, 1, 5, 4);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<series>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D11(%rip),%eax
  add    $0x2,%eax
  mov    %eax,D21(%rip)
  mov    D21(%rip),%eax
  pop    %rbp
  ret
```

assistant: ```c
int series() {
  static int x = 0;
  x += 2;
  return x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<series>:
  endbr64
  mov    D12(%rip),%eax
  add    $0x2,%eax
  mov    %eax,D19(%rip)
  ret
```

assistant: ```c
int series() {
  static int x = 0;
  x += 2;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<series>:
  endbr64
  mov    D17(%rip),%eax
  add    $0x2,%eax
  mov    %eax,D3(%rip)
  ret
```

assistant: ```c
int series() {
  static int x = 0;
  x += 2;
  return x;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<series>:
  endbr64
  mov    D6(%rip),%eax
  add    $0x2,%eax
  mov    %eax,D18(%rip)
  ret
```

assistant: ```c
int series() {
  static int x = 0;
  x += 2;
  return x;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  cmpl   $0x6,-0x4(%rbp)
  ja     L3
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D12(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D12(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L3:
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type: string
name: extract_symbolic_data
arguments: data_label: D77
type: string
name: extract_symbolic_data
arguments: data_label: D74
type: string
name: extract_symbolic_data
arguments: data_label: D59
type: string
name: extract_symbolic_data
arguments: data_label: D20
type: string
name: extract_symbolic_data
arguments: data_label: D27
type: string
name: extract_symbolic_data
arguments: data_label: D80
type: string

tool: D0: 1


tool: D77: 2


tool: D74: 3


tool: D59: 4


tool: D20: 5


tool: D27: 6


tool: D80: default


assistant: ```c
int main() {
  int i = 001;
  switch (i) {
  case 1:
    printf("1\n");
  case 2:
    printf("2\n");
  case 3:
    printf("3\n");
  case 4:
    printf("4\n");
  case 5:
    printf("5\n");
  case 6:
    printf("6\n");
  default:
    printf("default\n");
  }
  return 0;
}
```