ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_commands>:
  endbr64
  sub    $0x8,%rsp
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D91(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: label: D44
type_infered: string
name: read_data
arguments: label: D67
type_infered: string
name: read_data
arguments: label: D91
type_infered: string
name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D22
type_infered: string
name: read_data
arguments: label: D63
type_infered: string
name: read_data
arguments: label: D27
type_infered: string
name: read_data
arguments: label: D66
type_infered: string
name: read_data
arguments: label: D39
type_infered: string

tool: D44: Shell more is experimental.


tool: D67: Commands:


tool: D91: exit, quit    : exit shell.


tool: D4: list          : list files.


tool: D23: format, erase : erase current memory.


tool: D22: memory        : set memory unit.


tool: D63: info          : rio info.


tool: D27: delete        : delete file off current memory unit.


tool: D66: download      : download a file off current memory unit.


tool: D39: help, ?       : print this dialog.


assistant: ```c
void print_commands(void) {
  printf("Shell more is experimental.\n");
  printf("Commands:\n");
  printf("exit, quit    : exit shell.\n");
  printf("list          : list files.\n");
  printf("format, erase : erase current memory.\n");
  printf("memory        : set memory unit.\n");
  printf("info          : rio info.\n");
  printf("delete        : delete file off current memory unit.\n");
  printf("download      : download a file off current memory unit.\n");
  printf("help, ?       : print this dialog.\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_commands>:
  endbr64
  sub    $0x8,%rsp
  lea    D80(%rip),%rdi
  call   <printf@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D20(%rip),%rdi
  call   <printf@plt>
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D80
type_guessed: string
name: disassemble_data
arguments: data_label: D9
type_guessed: string
name: disassemble_data
arguments: data_label: D51
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D48
type_guessed: string
name: disassemble_data
arguments: data_label: D20
type_guessed: string
name: disassemble_data
arguments: data_label: D74
type_guessed: string
name: disassemble_data
arguments: data_label: D57
type_guessed: string
name: disassemble_data
arguments: data_label: D73
type_guessed: string
name: disassemble_data
arguments: data_label: D10
type_guessed: string

tool: D80: Shell more is experimental.


tool: D9: Commands:


tool: D51: exit, quit    : exit shell.


tool: D11: list          : list files.


tool: D48: format, erase : erase current memory.


tool: D20: memory        : set memory unit.


tool: D74: info          : rio info.


tool: D57: delete        : delete file off current memory unit.


tool: D73: download      : download a file off current memory unit.


tool: D10: help, ?       : print this dialog.


assistant: ```c
void print_commands(void) {
  printf("Shell more is experimental.\n");
  printf("Commands:\n");
  printf("exit, quit    : exit shell.\n");
  printf("list          : list files.\n");
  printf("format, erase : erase current memory.\n");
  printf("memory        : set memory unit.\n");
  printf("info          : rio info.\n");
  printf("delete        : delete file off current memory unit.\n");
  printf("download      : download a file off current memory unit.\n");
  printf("help, ?       : print this dialog.\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<original_process>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xa4(%rbp)
  jmp    L5
L11:
  mov    -0xa4(%rbp),%eax
  mov    %eax,%edi
  call   <original_fibo@plt>
  mov    -0xa4(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0xa0(%rbp,%rdx,4)
  addl   $0x1,-0xa4(%rbp)
L5:
  cmpl   $0x22,-0xa4(%rbp)
  jle    L11
  lea    -0xa0(%rbp),%rax
  mov    $0x5704e7,%esi
  mov    %rax,%rdi
  call   <binary_search@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
void original_process() {
  int i = 0;
  int vector[35];
  for (; i < 35; i++)
    vector[i] = original_fibo(i);
  binary_search(vector, 5702887);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<original_process>:
  endbr64
  push   %rbx
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
L13:
  mov    %ebx,%edi
  call   <original_fibo@plt>
  mov    %eax,(%rsp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x23,%rbx
  jne    L13
  mov    %rsp,%rdi
  mov    $0x5704e7,%esi
  call   <binary_search@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0xa0,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void original_process() {
  int i = 0;
  int vector[35];
  for (; i < 35; i++)
    vector[i] = original_fibo(i);
  binary_search(vector, 5702887);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<original_process>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   (%rax)
L15:
  mov    %ebx,%edi
  call   <original_fibo@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x23,%rbx
  jne    L15
  mov    $0x5704e7,%esi
  mov    %rbp,%rdi
  call   <binary_search@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void original_process() {
  int i = 0;
  int vector[35];
  for (; i < 35; i++)
    vector[i] = original_fibo(i);
  binary_search(vector, 5702887);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<original_process>:
  endbr64
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0xa8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x98(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  nopl   (%rax)
L7:
  mov    %ebx,%edi
  call   <original_fibo@plt>
  mov    %eax,0x0(%rbp,%rbx,4)
  add    $0x1,%rbx
  cmp    $0x23,%rbx
  jne    L7
  mov    $0x5704e7,%esi
  mov    %rbp,%rdi
  call   <binary_search@plt>
  mov    0x98(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0xa8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void original_process() {
  int i = 0;
  int vector[35];
  for (; i < 35; i++)
    vector[i] = original_fibo(i);
  binary_search(vector, 5702887);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uninitvar_strtok>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_strtok(void) {
  char *s;
  char *ct;
  (void)strtok(s, ct);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uninitvar_strtok>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <strtok@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void uninitvar_strtok(void) {
  char *s;
  char *ct;
  (void)strtok(s, ct);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<uninitvar_strtok>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <strtok@plt>
```

assistant: ```c
void uninitvar_strtok(void) {
  char *s;
  char *ct;
  (void)strtok(s, ct);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uninitvar_strtok>:
  endbr64
  xor    %esi,%esi
  xor    %edi,%edi
  jmp    1050 <strtok@plt>
```

assistant: ```c
void uninitvar_strtok(void) {
  char *s;
  char *ct;
  (void)strtok(s, ct);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf_s@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <scanf_s@plt>
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  cmp    $0x31,%eax
  je     L48
  cmp    $0x32,%eax
  je     L49
  jmp    L38
L48:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MAX@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L49:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <MIN@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
L38:
  mov    $0x0,%eax
  call   <main>
  nop
L11:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D53
data_type: string
name: extract_symbolic_data
arguments: data_label: D34
data_type: string
name: extract_symbolic_data
arguments: data_label: D39
data_type: string
name: extract_symbolic_data
arguments: data_label: D22
data_type: string
name: extract_symbolic_data
arguments: data_label: D56
data_type: string
name: extract_symbolic_data
arguments: data_label: D68
data_type: string
name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D53: Dame el primer numero: 

tool: D34: %i

tool: D39: Dame el segundo numero: 

tool: D22: Maximo (1) o Minimo (2)?

tool: D56: El %i es el mayor


tool: D68: El %i es el menor


tool: D0: pause

assistant: ```c
int main() {
  int x, num1 = 1, num2;
  printf("Dame el primer numero: ");
  scanf_s("%i", &num1);
  printf("Dame el segundo numero: ");
  scanf_s("%i", &num2);
  printf("Maximo (1) o Minimo (2)?\n");
  switch (getch()) {
  case '1':
    x = MAX(num1, num2);
    printf("El %i es el mayor\n", x);
    break;
  case '2':
    x = MIN(num1, num2);
    printf("El %i es el menor\n", x);
    break;
  default:
    main();
    break;
  }
  system("pause");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rsi
  lea    D3(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf_s@plt>
  lea    D5(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf_s@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <getch@plt>
  cmp    $0x31,%eax
  je     L38
  cmp    $0x32,%eax
  je     L7
  mov    $0x0,%eax
  call   <main>
  jmp    L31
L38:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <MAX@plt>
  mov    %eax,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L31:
  lea    D48(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <MIN@plt>
  mov    %eax,%esi
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L31
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D10
data_type: string
name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D43
data_type: string
name: disassemble_data
arguments: data_label: D46
data_type: string
name: disassemble_data
arguments: data_label: D48
data_type: string
name: disassemble_data
arguments: data_label: D67
data_type: string

tool: D10: Dame el primer numero: 

tool: D3: %i

tool: D5: Dame el segundo numero: 

tool: D43: Maximo (1) o Minimo (2)?

tool: D46: El %i es el mayor


tool: D48: pause

tool: D67: El %i es el menor


assistant: ```c
int main() {
  int x, num1 = 1, num2;
  printf("Dame el primer numero: ");
  scanf_s("%i", &num1);
  printf("Dame el segundo numero: ");
  scanf_s("%i", &num2);
  printf("Maximo (1) o Minimo (2)?\n");
  switch (getch()) {
  case '1':
    x = MAX(num1, num2);
    printf("El %i es el mayor\n", x);
    break;
  case '2':
    x = MIN(num1, num2);
    printf("El %i es el menor\n", x);
    break;
  default:
    main();
    break;
  }
  system("pause");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rdi
  lea    D56(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf_s@plt>
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf_s@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0x31,%eax
  je     L43
  cmp    $0x32,%eax
  je     L26
  xor    %eax,%eax
  call   <main>
L6:
  lea    D37(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L43:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <MAX@plt>
  lea    D63(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L26:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <MIN@plt>
  lea    D66(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L6
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
type_guessed: string
name: unpack_data
arguments: tag: D56
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D37
type_guessed: string
name: unpack_data
arguments: tag: D63
type_guessed: string
name: unpack_data
arguments: tag: D66
type_guessed: string

tool: D27: Dame el primer numero: 

tool: D56: %i

tool: D18: Dame el segundo numero: 

tool: D17: Maximo (1) o Minimo (2)?

tool: D37: pause

tool: D63: El %i es el mayor


tool: D66: El %i es el menor


assistant: ```c
int main() {
  int x, num1 = 1, num2;
  printf("Dame el primer numero: ");
  scanf_s("%i", &num1);
  printf("Dame el segundo numero: ");
  scanf_s("%i", &num2);
  printf("Maximo (1) o Minimo (2)?\n");
  switch (getch()) {
  case '1':
    x = MAX(num1, num2);
    printf("El %i es el mayor\n", x);
    break;
  case '2':
    x = MIN(num1, num2);
    printf("El %i es el menor\n", x);
    break;
  default:
    main();
    break;
  }
  system("pause");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rdi
  lea    D30(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  call   <printf@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf_s@plt>
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf_s@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  call   <getch@plt>
  cmp    $0x31,%eax
  je     L35
  cmp    $0x32,%eax
  je     L34
  xor    %eax,%eax
  call   <main>
L3:
  lea    D3(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L35:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <MAX@plt>
  lea    D17(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L34:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  call   <MIN@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D30
type: string
name: extract_symbolic_data
arguments: tag: D58
type: string
name: extract_symbolic_data
arguments: tag: D55
type: string
name: extract_symbolic_data
arguments: tag: D3
type: string
name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string

tool: D21: Dame el primer numero: 

tool: D30: %i

tool: D58: Dame el segundo numero: 

tool: D55: Maximo (1) o Minimo (2)?

tool: D3: pause

tool: D17: El %i es el mayor


tool: D23: El %i es el menor


assistant: ```c
int main() {
  int x, num1 = 1, num2;
  printf("Dame el primer numero: ");
  scanf_s("%i", &num1);
  printf("Dame el segundo numero: ");
  scanf_s("%i", &num2);
  printf("Maximo (1) o Minimo (2)?\n");
  switch (getch()) {
  case '1':
    x = MAX(num1, num2);
    printf("El %i es el mayor\n", x);
    break;
  case '2':
    x = MIN(num1, num2);
    printf("El %i es el menor\n", x);
    break;
  default:
    main();
    break;
  }
  system("pause");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<index_strichr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L31:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%eax
  cmp    -0x6(%rbp),%al
  jne    L33
  mov    -0x4(%rbp),%eax
  jmp    L39
L33:
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0xffffffff,%eax
L39:
  leave
  ret
```

assistant: ```c
int index_strichr(const char *str, int ch) {
  int idx;
  char up_str_char;
  char up_ch;
  up_ch = toupper(ch);
  for (idx = 0; str[idx]; idx++) {
    up_str_char = toupper(str[idx]);
    if (up_str_char == up_ch) {
      return (idx);
    }
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<index_strichr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movsbl %sil,%edi
  call   <toupper@plt>
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L3
  mov    %eax,%r12d
  mov    $0x0,%ebx
L2:
  mov    %ebx,%r13d
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    %al,%r12b
  je     L5
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L2
  mov    $0xffffffff,%r13d
L5:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  mov    $0xffffffff,%r13d
  jmp    L5
```

assistant: ```c
int index_strichr(const char *str, int ch) {
  int idx;
  char up_str_char;
  char up_ch;
  up_ch = toupper(ch);
  for (idx = 0; str[idx]; idx++) {
    up_str_char = toupper(str[idx]);
    if (up_str_char == up_ch) {
      return (idx);
    }
  }
  return (-1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<index_strichr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  movsbl %sil,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L12
  mov    %eax,%r12d
  xor    %ebx,%ebx
  jmp    L26
  nopw   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L12
L26:
  mov    %ebx,%r13d
  call   <toupper@plt>
  cmp    %al,%r12b
  jne    L20
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L12:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int index_strichr(const char *str, int ch) {
  int idx;
  char up_str_char;
  char up_ch;
  up_ch = toupper(ch);
  for (idx = 0; str[idx]; idx++) {
    up_str_char = toupper(str[idx]);
    if (up_str_char == up_ch) {
      return (idx);
    }
  }
  return (-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<index_strichr>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  movsbl %sil,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <toupper@plt>
  movsbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L31
  mov    %eax,%r12d
  xor    %ebx,%ebx
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L31
L12:
  mov    %ebx,%r13d
  call   <toupper@plt>
  cmp    %al,%r12b
  jne    L29
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L31:
  add    $0x8,%rsp
  mov    $0xffffffff,%r13d
  pop    %rbx
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int index_strichr(const char *str, int ch) {
  int idx;
  char up_str_char;
  char up_ch;
  up_ch = toupper(ch);
  for (idx = 0; str[idx]; idx++) {
    up_str_char = toupper(str[idx]);
    if (up_str_char == up_ch) {
      return (idx);
    }
  }
  return (-1);
}
```