ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nthSuperUglyNumber>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r13
  mov    %edx,%r15d
  lea    0x0(,%rdx,4),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  movslq %ebx,%rsi
  mov    %rsi,0x18(%rsp)
  lea    0x0(,%rbx,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movl   $0x1,(%rax)
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    0x8(%rsp),%rdi
  call   <memset@plt>
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  cmp    $0x1,%ebx
  jle    L36
  lea    0x4(%r12),%rbp
  lea    -0x2(%rbx),%eax
  lea    0x8(%r12,%rax,4),%rbx
  mov    %rbx,0x10(%rsp)
  lea    -0x1(%r15),%eax
  lea    0x4(%r14,%rax,4),%rbx
  sub    %r14,%r13
  mov    0x8(%rsp),%rax
  sub    %r14,%rax
  mov    %rax,0x8(%rsp)
  jmp    L54
L68:
  add    $0x4,%rdx
  cmp    %rbx,%rdx
  je     L26
L75:
  cmp    %eax,(%rdx)
  jne    L68
  mov    0x0(%r13,%rdx,1),%esi
  mov    0x8(%rsp),%rdi
  add    %rdx,%rdi
  mov    (%rdi),%ecx
  add    $0x1,%ecx
  mov    %ecx,(%rdi)
  movslq %ecx,%rcx
  imul   (%r12,%rcx,4),%esi
  mov    %esi,(%rdx)
  jmp    L68
L26:
  add    $0x4,%rbp
  cmp    0x10(%rsp),%rbp
  je     L36
L54:
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <getMin@plt>
  mov    %eax,0x0(%rbp)
  test   %r15d,%r15d
  jle    L26
  mov    %r14,%rdx
  jmp    L75
L36:
  mov    0x18(%rsp),%rax
  mov    -0x4(%r12,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nthSuperUglyNumber(int n, int *primes, int size) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  int *factors = (int *)malloc(sizeof(int) * size);
  int *uglies = (int *)malloc(sizeof(int) * n);
  uglies[0] = 1;
  int min;
  memset(indexes, 0, sizeof(int) * size);
  memcpy(factors, primes, sizeof(int) * size);
  for (int i = 1; i < n; i++) {
    min = getMin(factors, size);
    uglies[i] = min;
    for (int j = 0; j < size; j++)
      if (min == factors[j])
        factors[j] = primes[j] * uglies[++indexes[j]];
  }
  return uglies[n - 1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<nthSuperUglyNumber>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  lea    0x0(,%rdx,4),%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %r14d,%edi
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    %r14d,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  movslq %ebx,%rcx
  lea    0x0(,%rbx,4),%edi
  mov    %rcx,0x18(%rsp)
  mov    %rax,%r12
  call   <malloc@plt>
  mov    0x8(%rsp),%rdi
  xor    %esi,%esi
  mov    %r14d,%edx
  movl   $0x1,(%rax)
  mov    %rax,%r13
  call   <memset@plt>
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  cmp    $0x1,%ebx
  jle    L4
  lea    -0x2(%rbx),%eax
  mov    0x8(%rsp),%r14
  lea    0x4(%r13),%r9
  sub    %r12,%r15
  lea    0x8(%r13,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbp),%eax
  sub    %r12,%r14
  lea    0x4(%r12,%rax,4),%rbx
  nopl   0x0(%rax)
L9:
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %r9,0x8(%rsp)
  call   <getMin@plt>
  mov    0x8(%rsp),%r9
  mov    %eax,%esi
  mov    %eax,(%r9)
  test   %ebp,%ebp
  jle    L30
  mov    %r12,%rax
L14:
  cmp    %esi,(%rax)
  jne    L23
  lea    (%r14,%rax,1),%r10
  mov    (%r15,%rax,1),%edi
  mov    (%r10),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%r10)
  movslq %edx,%rdx
  imul   0x0(%r13,%rdx,4),%edi
  mov    %edi,(%rax)
L23:
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L14
L30:
  add    $0x4,%r9
  cmp    0x10(%rsp),%r9
  jne    L9
L4:
  mov    0x18(%rsp),%rax
  mov    -0x4(%r13,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nthSuperUglyNumber(int n, int *primes, int size) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  int *factors = (int *)malloc(sizeof(int) * size);
  int *uglies = (int *)malloc(sizeof(int) * n);
  uglies[0] = 1;
  int min;
  memset(indexes, 0, sizeof(int) * size);
  memcpy(factors, primes, sizeof(int) * size);
  for (int i = 1; i < n; i++) {
    min = getMin(factors, size);
    uglies[i] = min;
    for (int j = 0; j < size; j++)
      if (min == factors[j])
        factors[j] = primes[j] * uglies[++indexes[j]];
  }
  return uglies[n - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nthSuperUglyNumber>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  lea    0x0(,%rdx,4),%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    %r14d,%edi
  sub    $0x28,%rsp
  call   <malloc@plt>
  mov    %r14d,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  movslq %ebx,%rcx
  lea    0x0(,%rbx,4),%edi
  mov    %rcx,0x18(%rsp)
  mov    %rax,%r12
  call   <malloc@plt>
  mov    0x8(%rsp),%rdi
  xor    %esi,%esi
  mov    %r14d,%edx
  movl   $0x1,(%rax)
  mov    %rax,%r13
  call   <memset@plt>
  mov    %r14d,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  cmp    $0x1,%ebx
  jle    L5
  lea    -0x2(%rbx),%eax
  mov    0x8(%rsp),%r14
  lea    0x4(%r13),%r9
  sub    %r12,%r15
  lea    0x8(%r13,%rax,4),%rax
  mov    %rax,0x10(%rsp)
  lea    -0x1(%rbp),%eax
  sub    %r12,%r14
  lea    0x4(%r12,%rax,4),%rbx
  nopl   0x0(%rax)
L16:
  mov    %ebp,%esi
  mov    %r12,%rdi
  mov    %r9,0x8(%rsp)
  call   <getMin@plt>
  mov    0x8(%rsp),%r9
  mov    %eax,%esi
  mov    %eax,(%r9)
  test   %ebp,%ebp
  jle    L48
  mov    %r12,%rax
L38:
  cmp    %esi,(%rax)
  jne    L15
  lea    (%r14,%rax,1),%r10
  mov    (%r15,%rax,1),%edi
  mov    (%r10),%ecx
  lea    0x1(%rcx),%edx
  mov    %edx,(%r10)
  movslq %edx,%rdx
  imul   0x0(%r13,%rdx,4),%edi
  mov    %edi,(%rax)
L15:
  add    $0x4,%rax
  cmp    %rax,%rbx
  jne    L38
L48:
  add    $0x4,%r9
  cmp    0x10(%rsp),%r9
  jne    L16
L5:
  mov    0x18(%rsp),%rax
  mov    -0x4(%r13,%rax,4),%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int nthSuperUglyNumber(int n, int *primes, int size) {
  int *indexes = (int *)malloc(sizeof(int) * size);
  int *factors = (int *)malloc(sizeof(int) * size);
  int *uglies = (int *)malloc(sizeof(int) * n);
  uglies[0] = 1;
  int min;
  memset(indexes, 0, sizeof(int) * size);
  memcpy(factors, primes, sizeof(int) * size);
  for (int i = 1; i < n; i++) {
    min = getMin(factors, size);
    uglies[i] = min;
    for (int j = 0; j < size; j++)
      if (min == factors[j])
        factors[j] = primes[j] * uglies[++indexes[j]];
  }
  return uglies[n - 1];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<MAIN>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L75
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L82
L75:
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  jmp    L90
L82:
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
L90:
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L119
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L6
L119:
  lea    D98(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  jmp    L10
L6:
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
L10:
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L120
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L120
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  jmp    L27
L120:
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
L27:
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L158
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L158
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  jmp    L166
L158:
  lea    D86(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
L166:
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L101
  mov    $0x0,%eax
  call   <two@plt>
  test   %eax,%eax
  je     L101
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
  jmp    L46
L101:
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
L46:
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L57
  mov    $0x0,%eax
  call   <two@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <zero@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %eax,%eax
  je     L61
L57:
  lea    D94(%rip),%rax
  mov    %rax,%rdi
  call   <write@plt>
L61:
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D94
type: string
name: unpack_data
arguments: data_tag: D80
type: string
name: unpack_data
arguments: data_tag: D98
type: string
name: unpack_data
arguments: data_tag: D89
type: string
name: unpack_data
arguments: data_tag: D86
type: string
name: unpack_data
arguments: data_tag: D20
type: string

tool: D94: correct: 1


tool: D80: wrongn


tool: D98: correct: 0 1


tool: D89: correct: 1 0


tool: D86: correct: 0


tool: D20: correct: 1 2


assistant: ```c
int MAIN() {
  if (one() || zero()) {
    write("correct: 1\n");
  } else {
    write("wrongn\n");
  }
  if (zero() || one()) {
    write("correct: 0 1\n");
  } else {
    write("wrongn\n");
  }
  if (one() && zero()) {
    write("wrongn\n");
  } else {
    write("correct: 1 0\n");
  }
  if (zero() && one()) {
    write("wrongn\n");
  } else {
    write("correct: 0\n");
  }
  if (one() && two()) {
    write("correct: 1 2\n");
  } else {
    write("wrongn\n");
  }
  if (one() || (two() / zero())) {
    write("correct: 1\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<MAIN>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L118
  call   <zero@plt>
  test   %eax,%eax
  je     L143
L118:
  lea    D77(%rip),%rdi
  call   <write@plt>
L127:
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L44
  call   <one@plt>
  test   %rax,%rax
  je     L101
L44:
  lea    D40(%rip),%rdi
  call   <write@plt>
L23:
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L68
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L22
L68:
  lea    D55(%rip),%rdi
  call   <write@plt>
L4:
  mov    $0x0,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L163
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L110
L163:
  lea    D56(%rip),%rdi
  call   <write@plt>
L105:
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L57
  mov    $0x0,%eax
  call   <two@plt>
  test   %eax,%eax
  jne    L76
L57:
  lea    D12(%rip),%rdi
  call   <write@plt>
L161:
  mov    $0x0,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L125
  call   <two@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <zero@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %eax,%eax
  je     L45
L125:
  lea    D77(%rip),%rdi
  call   <write@plt>
L45:
  pop    %rbx
  ret
L143:
  lea    D12(%rip),%rdi
  call   <write@plt>
  jmp    L127
L101:
  lea    D12(%rip),%rdi
  call   <write@plt>
  jmp    L23
L22:
  lea    D12(%rip),%rdi
  call   <write@plt>
  jmp    L4
L110:
  lea    D12(%rip),%rdi
  call   <write@plt>
  jmp    L105
L76:
  lea    D36(%rip),%rdi
  call   <write@plt>
  jmp    L161
```

tool_calls: name: disassemble_data
arguments: tag: D77
data_type: string
name: disassemble_data
arguments: tag: D40
data_type: string
name: disassemble_data
arguments: tag: D55
data_type: string
name: disassemble_data
arguments: tag: D56
data_type: string
name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D36
data_type: string

tool: D77: correct: 1


tool: D40: correct: 0 1


tool: D55: correct: 1 0


tool: D56: correct: 0


tool: D12: wrongn


tool: D36: correct: 1 2


assistant: ```c
int MAIN() {
  if (one() || zero()) {
    write("correct: 1\n");
  } else {
    write("wrongn\n");
  }
  if (zero() || one()) {
    write("correct: 0 1\n");
  } else {
    write("wrongn\n");
  }
  if (one() && zero()) {
    write("wrongn\n");
  } else {
    write("correct: 1 0\n");
  }
  if (zero() && one()) {
    write("wrongn\n");
  } else {
    write("correct: 0\n");
  }
  if (one() && two()) {
    write("correct: 1 2\n");
  } else {
    write("wrongn\n");
  }
  if (one() || (two() / zero())) {
    write("correct: 1\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<MAIN>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L117
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L137
L117:
  lea    D14(%rip),%rdi
  call   <write@plt>
L22:
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L24
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L123
L24:
  lea    D36(%rip),%rdi
  call   <write@plt>
L91:
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L66
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L53
L66:
  lea    D8(%rip),%rdi
  call   <write@plt>
L89:
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L98
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L147
L98:
  lea    D75(%rip),%rdi
  call   <write@plt>
L104:
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L134
  xor    %eax,%eax
  call   <two@plt>
  test   %eax,%eax
  jne    L114
L134:
  lea    D67(%rip),%rdi
  call   <write@plt>
L44:
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L4
  xor    %eax,%eax
  call   <two@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <zero@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  test   %eax,%eax
  je     L94
L4:
  lea    D14(%rip),%rdi
  pop    %rbx
  jmp    1090 <write@plt>
  nopw   0x0(%rax,%rax,1)
L94:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L114:
  lea    D49(%rip),%rdi
  call   <write@plt>
  jmp    L44
  cs nopw 0x0(%rax,%rax,1)
L137:
  lea    D67(%rip),%rdi
  call   <write@plt>
  jmp    L22
  nopl   0x0(%rax)
L123:
  lea    D67(%rip),%rdi
  call   <write@plt>
  jmp    L91
  nopl   0x0(%rax)
L53:
  lea    D67(%rip),%rdi
  call   <write@plt>
  jmp    L89
  nopl   0x0(%rax)
L147:
  lea    D67(%rip),%rdi
  call   <write@plt>
  jmp    L104
```

tool_calls: name: unpack_data
arguments: data_tag: D14
datatype: string
name: unpack_data
arguments: data_tag: D36
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D75
datatype: string
name: unpack_data
arguments: data_tag: D67
datatype: string
name: unpack_data
arguments: data_tag: D49
datatype: string

tool: D14: correct: 1


tool: D36: correct: 0 1


tool: D8: correct: 1 0


tool: D75: correct: 0


tool: D67: wrongn


tool: D49: correct: 1 2


assistant: ```c
int MAIN() {
  if (one() || zero()) {
    write("correct: 1\n");
  } else {
    write("wrongn\n");
  }
  if (zero() || one()) {
    write("correct: 0 1\n");
  } else {
    write("wrongn\n");
  }
  if (one() && zero()) {
    write("wrongn\n");
  } else {
    write("correct: 1 0\n");
  }
  if (zero() && one()) {
    write("wrongn\n");
  } else {
    write("correct: 0\n");
  }
  if (one() && two()) {
    write("correct: 1 2\n");
  } else {
    write("wrongn\n");
  }
  if (one() || (two() / zero())) {
    write("correct: 1\n");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<MAIN>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L70
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L153
L70:
  lea    D47(%rip),%rdi
  call   <write@plt>
L151:
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L129
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L34
L129:
  lea    D61(%rip),%rdi
  call   <write@plt>
L112:
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L166
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  jne    L115
L166:
  lea    D94(%rip),%rdi
  call   <write@plt>
L53:
  xor    %eax,%eax
  call   <zero@plt>
  test   %eax,%eax
  je     L143
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L138
L143:
  lea    D89(%rip),%rdi
  call   <write@plt>
L1:
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  je     L61
  xor    %eax,%eax
  call   <two@plt>
  test   %eax,%eax
  jne    L11
L61:
  lea    D49(%rip),%rdi
  call   <write@plt>
L52:
  xor    %eax,%eax
  call   <one@plt>
  test   %rax,%rax
  jne    L163
  xor    %eax,%eax
  call   <two@plt>
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <zero@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  cltd
  idiv   %r8d
  test   %eax,%eax
  je     L79
L163:
  lea    D47(%rip),%rdi
  pop    %rbx
  jmp    1090 <write@plt>
  nopw   0x0(%rax,%rax,1)
L79:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  lea    D16(%rip),%rdi
  call   <write@plt>
  jmp    L52
  cs nopw 0x0(%rax,%rax,1)
L153:
  lea    D49(%rip),%rdi
  call   <write@plt>
  jmp    L151
  nopl   0x0(%rax)
L34:
  lea    D49(%rip),%rdi
  call   <write@plt>
  jmp    L112
  nopl   0x0(%rax)
L115:
  lea    D49(%rip),%rdi
  call   <write@plt>
  jmp    L53
  nopl   0x0(%rax)
L138:
  lea    D49(%rip),%rdi
  call   <write@plt>
  jmp    L1
```

tool_calls: name: retrieve_data
arguments: data_label: D47
datatype: string
name: retrieve_data
arguments: data_label: D61
datatype: string
name: retrieve_data
arguments: data_label: D94
datatype: string
name: retrieve_data
arguments: data_label: D89
datatype: string
name: retrieve_data
arguments: data_label: D49
datatype: string
name: retrieve_data
arguments: data_label: D16
datatype: string

tool: D47: correct: 1


tool: D61: correct: 0 1


tool: D94: correct: 1 0


tool: D89: correct: 0


tool: D49: wrongn


tool: D16: correct: 1 2


assistant: ```c
int MAIN() {
  if (one() || zero()) {
    write("correct: 1\n");
  } else {
    write("wrongn\n");
  }
  if (zero() || one()) {
    write("correct: 0 1\n");
  } else {
    write("wrongn\n");
  }
  if (one() && zero()) {
    write("wrongn\n");
  } else {
    write("correct: 1 0\n");
  }
  if (zero() && one()) {
    write("wrongn\n");
  } else {
    write("correct: 0\n");
  }
  if (one() && two()) {
    write("correct: 1 2\n");
  } else {
    write("wrongn\n");
  }
  if (one() || (two() / zero())) {
    write("correct: 1\n");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RunTest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <SetupTest@plt>
  mov    -0x8(%rbp),%rax
  call   *%rax
  mov    $0x0,%eax
  call   <CleanupTest@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type_guessed: string
name: extract_symbolic_data
arguments: tag: D0
type_guessed: string

tool: D17: Running test: %s...

tool: D0: SUCCESS!

assistant: ```c
void RunTest(void (*testFunction)(void), char *testName) {
  printf("Running test: %s...", testName);
  SetupTest();
  testFunction();
  CleanupTest();
  printf("SUCCESS!\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RunTest>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <SetupTest@plt>
  call   *%rbx
  mov    $0x0,%eax
  call   <CleanupTest@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string

tool: D8: Running test: %s...

tool: D3: SUCCESS!

assistant: ```c
void RunTest(void (*testFunction)(void), char *testName) {
  printf("Running test: %s...", testName);
  SetupTest();
  testFunction();
  CleanupTest();
  printf("SUCCESS!\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<RunTest>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <SetupTest@plt>
  call   *%rbx
  xor    %eax,%eax
  call   <CleanupTest@plt>
  lea    D19(%rip),%rdi
  pop    %rbx
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
type: string
name: retrieve_data
arguments: label: D19
type: string

tool: D10: Running test: %s...

tool: D19: SUCCESS!

assistant: ```c
void RunTest(void (*testFunction)(void), char *testName) {
  printf("Running test: %s...", testName);
  SetupTest();
  testFunction();
  CleanupTest();
  printf("SUCCESS!\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RunTest>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %rdi,%rbx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <SetupTest@plt>
  call   *%rbx
  xor    %eax,%eax
  call   <CleanupTest@plt>
  lea    D13(%rip),%rdi
  pop    %rbx
  jmp    1080 <puts@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string

tool: D1: Running test: %s...

tool: D13: SUCCESS!

assistant: ```c
void RunTest(void (*testFunction)(void), char *testName) {
  printf("Running test: %s...", testName);
  SetupTest();
  testFunction();
  CleanupTest();
  printf("SUCCESS!\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%r8d
  mov    $0xffff,%ecx
  mov    $0x7,%edx
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <do_exec@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D28
type_guessed: string
name: read_data
arguments: data_tag: D32
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D36
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D28: ready to swap

tool: 

tool: D25: command.com

tool: D36: rc = %d


tool: D4: done swap

assistant: ```c
int main() {
  int rc;
  printf("ready to swap\n");
  rc = do_exec("command.com", "", 0x01 | 0x02 | 0x04, 0xffff, NULL);
  printf("rc = %d\n", rc);
  printf("done swap\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r8d
  mov    $0xffff,%ecx
  mov    $0x7,%edx
  lea    D44(%rip),%rsi
  lea    D41(%rip),%rdi
  call   <do_exec@plt>
  mov    %eax,%esi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
type_guessed: string
name: extract_symbolic_data
arguments: label: D44
type_guessed: string
name: extract_symbolic_data
arguments: label: D41
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D46
type_guessed: string

tool: D8: ready to swap

tool: 

tool: D41: command.com

tool: D32: rc = %d


tool: D46: done swap

assistant: ```c
int main() {
  int rc;
  printf("ready to swap\n");
  rc = do_exec("command.com", "", 0x01 | 0x02 | 0x04, 0xffff, NULL);
  printf("rc = %d\n", rc);
  printf("done swap\n");
  return 0;
}
```