ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mk_ebmlSIntSize>:
  endbr64
  mov    $0x38,%ecx
  mov    %edi,%r8d
  mov    %edi,%edx
  mov    %edi,%eax
  sar    %cl,%r8d
  mov    $0x30,%ecx
  mov    %edi,%esi
  mov    %edi,%r9d
  sar    %cl,%edx
  mov    $0x28,%ecx
  mov    %edi,%r10d
  sar    $0x10,%r9d
  sar    %cl,%eax
  mov    $0x20,%ecx
  sar    $0x8,%r10d
  mov    %eax,%r11d
  mov    %edi,%eax
  sar    %cl,%esi
  sar    $0x18,%eax
  test   %edi,%edi
  js     L233
  test   %r8b,%r8b
  jne    L213
  test   %dl,%dl
  js     L213
  jne    L224
  test   %r11b,%r11b
  js     L224
  jne    L182
  test   %sil,%sil
  js     L182
  jne    L20
  test   %eax,%eax
  js     L20
  test   %al,%al
  jne    L16
  test   %r9b,%r9b
  js     L16
  jne    L191
  test   %r10b,%r10b
  js     L191
  jne    L40
  mov    $0x1,%eax
  test   %dil,%dil
  js     L40
L330:
  ret
  xchg   %ax,%ax
L233:
  cmp    $0xff,%r8b
  jne    L213
  test   %dl,%dl
  jns    L213
  cmp    $0xff,%dl
  jne    L224
  test   %r11b,%r11b
  jns    L224
  cmp    $0xff,%r11b
  jne    L182
  test   %sil,%sil
  jns    L182
  cmp    $0xff,%sil
  jne    L20
  test   %eax,%eax
  jns    L20
  cmp    $0xff,%al
  jne    L16
  test   %r9b,%r9b
  jns    L16
  cmp    $0xff,%r9b
  jne    L191
  test   %r10b,%r10b
  jns    L191
  cmp    $0xff,%r10b
  jne    L40
  mov    $0x1,%eax
  test   %dil,%dil
  js     L330
L40:
  mov    $0x6,%edx
  jmp    L62
  nopl   0x0(%rax)
L182:
  mov    $0x2,%edx
L62:
  mov    $0x8,%eax
  sub    %edx,%eax
  ret
  nopl   (%rax)
L213:
  xor    %edx,%edx
  jmp    L62
  nopl   0x0(%rax)
L224:
  mov    $0x1,%edx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x3,%edx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x4,%edx
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L191:
  mov    $0x5,%edx
  jmp    L62
```

assistant: ```c
unsigned mk_ebmlSIntSize(int64_t si) {
  unsigned char c_si[8] = {(unsigned char)(si >> 56), (unsigned char)(si >> 48), (unsigned char)(si >> 40), (unsigned char)(si >> 32), (unsigned char)(si >> 24), (unsigned char)(si >> 16), (unsigned char)(si >> 8), (unsigned char)si};
  unsigned i = 0;
  if (si < 0)
    while (i < 7 && c_si[i] == 0xff && c_si[i + 1] & 0x80)
      ++i;
  else
    while (i < 7 && c_si[i] == 0 && !(c_si[i + 1] & 0x80))
      ++i;
  return 8 - i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<_gmtime_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <offtime_u@plt>
  leave
  ret
```

assistant: ```c
struct tm *_gmtime_r(const time_t *timep, struct tm *p_tm) {
  tzset();
  return (offtime_u((time_t)*timep, 0L, p_tm));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_gmtime_r>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x0,%eax
  call   <tzset@plt>
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    (%rbx),%rdi
  call   <offtime_u@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct tm *_gmtime_r(const time_t *timep, struct tm *p_tm) {
  tzset();
  return (offtime_u((time_t)*timep, 0L, p_tm));
}
```
user: What is the c source code of the assembly code below:

```asm
<_gmtime_r>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <tzset@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rsp
  mov    %r12,%rdx
  pop    %rbx
  xor    %esi,%esi
  pop    %r12
  jmp    1060 <offtime_u@plt>
```

assistant: ```c
struct tm *_gmtime_r(const time_t *timep, struct tm *p_tm) {
  tzset();
  return (offtime_u((time_t)*timep, 0L, p_tm));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_gmtime_r>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %rsi,%r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <tzset@plt>
  mov    (%rbx),%rdi
  add    $0x8,%rsp
  mov    %r12,%rdx
  pop    %rbx
  xor    %esi,%esi
  pop    %r12
  jmp    1060 <offtime_u@plt>
```

assistant: ```c
struct tm *_gmtime_r(const time_t *timep, struct tm *p_tm) {
  tzset();
  return (offtime_u((time_t)*timep, 0L, p_tm));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fn40>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x14(%rcx),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  shl    $0x2,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1e(%rcx),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D5(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D5
type_guessed: string

tool: D5: fn40

assistant: ```c
char *fn40() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn40");
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fn40>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x23,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  mov    %rbx,%rdi
  call   <realloc@plt>
  mov    %rax,%rbx
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
data_type: string

tool: D9: fn40

assistant: ```c
char *fn40() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn40");
  return result;
}
```
user: What is the c source code of the assembly code below:

```asm
<fn40>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: fn40

assistant: ```c
char *fn40() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn40");
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fn40>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x14(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r12,%rdi
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x23,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  shl    $0x2,%edx
  sub    %edx,%eax
  lea    0x1e(%rax),%esi
  call   <realloc@plt>
  lea    D5(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type_infered: string

tool: D5: fn40

assistant: ```c
char *fn40() {
  char *result;
  result = malloc(20 + rand() % 20);
  result = realloc(result, 30 + rand() % 20);
  strcpy((char *)result, "fn40");
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x64,-0x114(%rbp)
  mov    -0x114(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x114(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <itoa@plt>
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: %d


assistant: ```c
main() {
  int n = 100;
  char s[256];
  printf("%d\n", n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    $0x64,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  mov    $0x64,%edi
  call   <itoa@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x110,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string

tool: D2: %d


assistant: ```c
main() {
  int n = 100;
  char s[256];
  printf("%d\n", n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%esi
  lea    D2(%rip),%rdi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    $0x64,%edi
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D2
type: string

tool: D2: %d


assistant: ```c
main() {
  int n = 100;
  char s[256];
  printf("%d\n", n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x64,%esi
  lea    D2(%rip),%rdi
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    $0x64,%edi
  mov    %rbp,%rsi
  call   <itoa@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x110,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
datatype: string

tool: D2: %d


assistant: ```c
main() {
  int n = 100;
  char s[256];
  printf("%d\n", n);
  itoa(n, s);
  printf("%s\n", s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x14(%rbp)
  jmp    L25
L36:
  pxor   %xmm0,%xmm0
  cvtss2sd -0xc(%rbp),%xmm0
  movapd %xmm0,%xmm1
  addsd  %xmm0,%xmm1
  movsd  D7(%rip),%xmm0
  addsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L17
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fatorial@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  divss  -0xc(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  jmp    L19
L17:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fatorial@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm1
  divss  -0xc(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
L19:
  addl   $0x1,-0x14(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L36
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D22
type_guessed: string
name: disassemble_data
arguments: tag: D7
type_guessed: f64
name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D22: %d

tool: D7: 1

tool: D6: %.2lf


assistant: ```c
int main() {
  int i, n;
  float serie = 0.0, x = 0.0;
  scanf("%d", &n);
  for (i = 1; i <= n; ++i) {
    x = (x * 2.0) + 1.0;
    if (i % 2 != 0)
      serie += fatorial(i) / x;
    else
      serie -= fatorial(i) / x;
  }
  printf("%.2lf\n", serie);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x14(%rsp)
  jle    L50
  pxor   %xmm5,%xmm5
  movss  %xmm5,0x8(%rsp)
  movss  %xmm5,0xc(%rsp)
  mov    $0x1,%ebx
  jmp    L41
L27:
  mov    %ebx,%edi
  call   <fatorial@plt>
  divss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm2
  subss  %xmm0,%xmm2
  movss  %xmm2,0xc(%rsp)
L20:
  add    $0x1,%ebx
  cmp    %ebx,0x14(%rsp)
  jl     L59
L41:
  pxor   %xmm0,%xmm0
  cvtss2sd 0x8(%rsp),%xmm0
  addsd  %xmm0,%xmm0
  addsd  D20(%rip),%xmm0
  pxor   %xmm1,%xmm1
  cvtsd2ss %xmm0,%xmm1
  movss  %xmm1,0x8(%rsp)
  test   $0x1,%bl
  je     L27
  mov    %ebx,%edi
  call   <fatorial@plt>
  divss  0x8(%rsp),%xmm0
  addss  0xc(%rsp),%xmm0
  movss  %xmm0,0xc(%rsp)
  jmp    L20
L50:
  pxor   %xmm6,%xmm6
  movss  %xmm6,0xc(%rsp)
L59:
  movss  0xc(%rsp),%xmm0
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D0
type_infered: string
name: disassemble_data
arguments: tag: D20
type_infered: f64
name: disassemble_data
arguments: tag: D1
type_infered: string

tool: D0: %d

tool: D20: 1

tool: D1: %.2lf


assistant: ```c
int main() {
  int i, n;
  float serie = 0.0, x = 0.0;
  scanf("%d", &n);
  for (i = 1; i <= n; ++i) {
    x = (x * 2.0) + 1.0;
    if (i % 2 != 0)
      serie += fatorial(i) / x;
    else
      serie -= fatorial(i) / x;
  }
  printf("%.2lf\n", serie);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D12(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L25
  pxor   %xmm1,%xmm1
  mov    $0x1,%ebx
  movaps %xmm1,%xmm2
  jmp    L44
  nopl   0x0(%rax)
L17:
  call   <fatorial@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  add    $0x1,%ebx
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm2
  cmp    %ebx,0x14(%rsp)
  jl     L19
L44:
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm1
  movss  %xmm2,0x8(%rsp)
  mov    %ebx,%edi
  addsd  D24(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0xc(%rsp)
  test   $0x1,%bl
  jne    L17
  call   <fatorial@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  add    $0x1,%ebx
  divss  %xmm1,%xmm0
  subss  %xmm0,%xmm2
  cmp    %ebx,0x14(%rsp)
  jge    L44
L19:
  movaps %xmm2,%xmm0
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L25:
  pxor   %xmm2,%xmm2
  jmp    L19
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D24
type_guessed: f64
name: disassemble_data
arguments: tag: D23
type_guessed: string

tool: D12: %d

tool: D24: 1

tool: D23: %.2lf


assistant: ```c
int main() {
  int i, n;
  float serie = 0.0, x = 0.0;
  scanf("%d", &n);
  for (i = 1; i <= n; ++i) {
    x = (x * 2.0) + 1.0;
    if (i % 2 != 0)
      serie += fatorial(i) / x;
    else
      serie -= fatorial(i) / x;
  }
  printf("%.2lf\n", serie);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  lea    D28(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  test   %eax,%eax
  jle    L34
  pxor   %xmm1,%xmm1
  mov    $0x1,%ebx
  movaps %xmm1,%xmm2
  nopw   0x0(%rax,%rax,1)
L32:
  cvtss2sd %xmm1,%xmm1
  addsd  %xmm1,%xmm1
  movss  %xmm2,0x8(%rsp)
  mov    %ebx,%edi
  addsd  D23(%rip),%xmm1
  cvtsd2ss %xmm1,%xmm1
  movss  %xmm1,0xc(%rsp)
  test   $0x1,%bl
  je     L29
  call   <fatorial@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  add    $0x1,%ebx
  divss  %xmm1,%xmm0
  addss  %xmm0,%xmm2
  cmp    0x14(%rsp),%ebx
  jle    L32
L65:
  movaps %xmm2,%xmm0
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  call   <fatorial@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  add    $0x1,%ebx
  divss  %xmm1,%xmm0
  subss  %xmm0,%xmm2
  cmp    %ebx,0x14(%rsp)
  jge    L32
  jmp    L65
L34:
  pxor   %xmm2,%xmm2
  jmp    L65
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: f64
name: retrieve_data
arguments: data_tag: D26
type_guessed: string

tool: D28: %d

tool: D23: 1

tool: D26: %.2lf


assistant: ```c
int main() {
  int i, n;
  float serie = 0.0, x = 0.0;
  scanf("%d", &n);
  for (i = 1; i <= n; ++i) {
    x = (x * 2.0) + 1.0;
    if (i % 2 != 0)
      serie += fatorial(i) / x;
    else
      serie -= fatorial(i) / x;
  }
  printf("%.2lf\n", serie);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L2
L3:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   %edx,%eax
  cltq
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rcx
  movabs $0xffff0000ffff0001,%rdx
  mov    %rcx,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  mov    %rax,%rdx
  shl    $0x10,%rdx
  add    %rax,%rdx
  mov    %rcx,%rax
  sub    %rdx,%rax
  leave
  ret
```

assistant: ```c
size_t ft_hash(char *keyword) {
  int len;
  int i;
  size_t ret;
  ret = 0;
  i = 0;
  len = ft_strlen(keyword);
  while (keyword[i] != '\0') {
    ret += (len * keyword[i] * keyword[i]);
    i++;
  }
  return (ret % 65537);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L26
  lea    0x1(%rbx),%rdi
  mov    $0x0,%esi
L11:
  movsbl %dl,%edx
  mov    %edx,%ecx
  imul   %eax,%ecx
  imul   %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rsi
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L11
L23:
  movabs $0xffff0000ffff0001,%rdx
  mov    %rsi,%rax
  mul    %rdx
  mov    %rdx,%rax
  shr    $0x10,%rax
  mov    $0x0,%dx
  add    %rax,%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  pop    %rbx
  ret
L26:
  mov    $0x0,%esi
  jmp    L23
```

assistant: ```c
size_t ft_hash(char *keyword) {
  int len;
  int i;
  size_t ret;
  ret = 0;
  i = 0;
  len = ft_strlen(keyword);
  while (keyword[i] != '\0') {
    ret += (len * keyword[i] * keyword[i]);
    i++;
  }
  return (ret % 65537);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L12
  lea    0x1(%rbx),%rdi
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %edx,%ecx
  add    $0x1,%rdi
  imul   %eax,%ecx
  imul   %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rsi
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L3
  movabs $0xffff0000ffff0001,%rdx
  mov    %rsi,%rax
  pop    %rbx
  mul    %rdx
  mov    %rdx,%rax
  xor    %dx,%dx
  shr    $0x10,%rax
  add    %rax,%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  ret
  nop
L12:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t ft_hash(char *keyword) {
  int len;
  int i;
  size_t ret;
  ret = 0;
  i = 0;
  len = ft_strlen(keyword);
  while (keyword[i] != '\0') {
    ret += (len * keyword[i] * keyword[i]);
    i++;
  }
  return (ret % 65537);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_hash>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  movsbl (%rbx),%edx
  test   %dl,%dl
  je     L17
  lea    0x1(%rbx),%rdi
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %edx,%ecx
  add    $0x1,%rdi
  imul   %eax,%ecx
  imul   %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rsi
  movsbl -0x1(%rdi),%edx
  test   %dl,%dl
  jne    L9
  movabs $0xffff0000ffff0001,%rdx
  mov    %rsi,%rax
  pop    %rbx
  mul    %rdx
  mov    %rdx,%rax
  xor    %dx,%dx
  shr    $0x10,%rax
  add    %rax,%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  ret
  nop
L17:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t ft_hash(char *keyword) {
  int len;
  int i;
  size_t ret;
  ret = 0;
  i = 0;
  len = ft_strlen(keyword);
  while (keyword[i] != '\0') {
    ret += (len * keyword[i] * keyword[i]);
    i++;
  }
  return (ret % 65537);
}
```