ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x696d61406e696d61,%rax
  mov    %rax,(%rsp)
  movabs $0x2e68616273656d6e,%rax
  mov    %rax,0x8(%rsp)
  movq   $0x6d6f63,0x10(%rsp)
  mov    %rsp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  unsigned long long t = 1, f = 2, u = 9, o = 19, s = 25, c = 4217, e = 7171939, a = 1762195240847, b = 399833425042215739, x[] = {o * b, f * u * s * c * a, t * e};
  puts((char *)x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x696d61406e696d61,%rax
  mov    %rsp,%rdi
  movq   $0x6d6f63,0x10(%rsp)
  mov    %rax,(%rsp)
  movabs $0x2e68616273656d6e,%rax
  mov    %rax,0x8(%rsp)
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  unsigned long long t = 1, f = 2, u = 9, o = 19, s = 25, c = 4217, e = 7171939, a = 1762195240847, b = 399833425042215739, x[] = {o * b, f * u * s * c * a, t * e};
  puts((char *)x);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  movdqa D2(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x6d6f63,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D2
datatype: byte[16]

tool: {"D2": [0x61,0x6d,0x69,0x6e,0x40,0x61,0x6d,0x69,0x6e,0x6d,0x65,0x73,0x62,0x61,0x68,0x2e]}

assistant: ```c
int main(void) {
  unsigned long long t = 1, f = 2, u = 9, o = 19, s = 25, c = 4217, e = 7171939, a = 1762195240847, b = 399833425042215739, x[] = {o * b, f * u * s * c * a, t * e};
  puts((char *)x);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<capitalizeInverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L13:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L9
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  jmp    L16
L9:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L16
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
L16:
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L13
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *capitalizeInverse(char *input) {
  int i = 0;
  while (input[i] != '\0') {
    if (islower(input[i])) {
      input[i] = toupper(input[i]);
    } else if (isupper(input[i])) {
      input[i] = tolower(input[i]);
    }
    i++;
  }
  return input;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<capitalizeInverse>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L20
  mov    %rbp,%rbx
  jmp    L43
L24:
  movsbl (%rbx),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L44
L18:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L20
L43:
  movsbl %dil,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L24
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  jmp    L18
L44:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  jmp    L18
L20:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *capitalizeInverse(char *input) {
  int i = 0;
  while (input[i] != '\0') {
    if (islower(input[i])) {
      input[i] = toupper(input[i]);
    } else if (isupper(input[i])) {
      input[i] = tolower(input[i]);
    }
    i++;
  }
  return input;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<capitalizeInverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L18
  mov    %r12,%rbx
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L33:
  call   <toupper@plt>
  mov    %al,(%rbx)
L29:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L18
L5:
  call   <islower@plt>
  movsbl (%rbx),%edi
  test   %rax,%rax
  jne    L33
  call   <isupper@plt>
  test   %rax,%rax
  je     L29
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L5
L18:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *capitalizeInverse(char *input) {
  int i = 0;
  while (input[i] != '\0') {
    if (islower(input[i])) {
      input[i] = toupper(input[i]);
    } else if (isupper(input[i])) {
      input[i] = tolower(input[i]);
    }
    i++;
  }
  return input;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<capitalizeInverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L23
  mov    %r12,%rbx
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L50:
  call   <toupper@plt>
  mov    %al,(%rbx)
L55:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L23
L12:
  call   <islower@plt>
  movsbl (%rbx),%edi
  test   %rax,%rax
  jne    L50
  call   <isupper@plt>
  test   %rax,%rax
  je     L55
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L12
L23:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *capitalizeInverse(char *input) {
  int i = 0;
  while (input[i] != '\0') {
    if (islower(input[i])) {
      input[i] = toupper(input[i]);
    } else if (isupper(input[i])) {
      input[i] = tolower(input[i]);
    }
    i++;
  }
  return input;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pdu_get_tppid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <gsm_hex2int@plt>
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *pdu_get_tppid(char *body, char *tppid) {
  char *pBegin, *pEnd;
  pBegin = body;
  pEnd = pBegin + 2;
  *tppid = (char)gsm_hex2int(pBegin, 2);
  return pEnd;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pdu_get_tppid>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x2,%esi
  call   <gsm_hex2int@plt>
  mov    %al,0x0(%rbp)
  lea    0x2(%rbx),%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pdu_get_tppid(char *body, char *tppid) {
  char *pBegin, *pEnd;
  pBegin = body;
  pEnd = pBegin + 2;
  *tppid = (char)gsm_hex2int(pBegin, 2);
  return pEnd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pdu_get_tppid>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <gsm_hex2int@plt>
  mov    %al,0x0(%rbp)
  add    $0x8,%rsp
  lea    0x2(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pdu_get_tppid(char *body, char *tppid) {
  char *pBegin, *pEnd;
  pBegin = body;
  pEnd = pBegin + 2;
  *tppid = (char)gsm_hex2int(pBegin, 2);
  return pEnd;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pdu_get_tppid>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x2,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <gsm_hex2int@plt>
  mov    %al,0x0(%rbp)
  add    $0x8,%rsp
  lea    0x2(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *pdu_get_tppid(char *body, char *tppid) {
  char *pBegin, *pEnd;
  pBegin = body;
  pEnd = pBegin + 2;
  *tppid = (char)gsm_hex2int(pBegin, 2);
  return pEnd;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fmix32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0xd,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0xc2b2ae35,%eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t fmix32(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: What is the c source code of the assembly code below?

```asm
<fmix32>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t fmix32(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fmix32>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t fmix32(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fmix32>:
  endbr64
  mov    %edi,%eax
  sar    $0x10,%eax
  xor    %edi,%eax
  imul   $0x85ebca6b,%eax,%eax
  mov    %eax,%edx
  sar    $0xd,%edx
  xor    %eax,%edx
  imul   $0xc2b2ae35,%edx,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
__attribute__((always_)) uint32_t fmix32(uint32_t h) {
  h ^= h >> 16;
  h *= 0x85ebca6b;
  h ^= h >> 13;
  h *= 0xc2b2ae35;
  h ^= h >> 16;
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strclone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strclone(char *src) {
  char *retval = (char *)malloc((strlen(src) + 1) * sizeof(char));
  strcpy(retval, src);
  return retval;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strclone>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strclone(char *src) {
  char *retval = (char *)malloc((strlen(src) + 1) * sizeof(char));
  strcpy(retval, src);
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strclone>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strclone(char *src) {
  char *retval = (char *)malloc((strlen(src) + 1) * sizeof(char));
  strcpy(retval, src);
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strclone>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <strcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strclone(char *src) {
  char *retval = (char *)malloc((strlen(src) + 1) * sizeof(char));
  strcpy(retval, src);
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<SumDigits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L10
  mov    -0x14(%rbp),%eax
  jmp    L2
L10:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ebx
  mov    %ebx,%eax
  shl    $0x2,%eax
  add    %ebx,%eax
  add    %eax,%eax
  mov    %edx,%ebx
  sub    %eax,%ebx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <SumDigits>
  add    %ebx,%eax
L2:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int SumDigits(int number) {
  if (number / 10 == 0)
    return number;
  else
    return number % 10 + SumDigits(number / 10);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SumDigits>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  lea    0x9(%rdi),%eax
  cmp    $0x12,%eax
  ja     L10
L1:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  movslq %edi,%rbp
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  mov    %edi,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  mov    %ebp,%edi
  call   <SumDigits>
  mov    %eax,%edx
  lea    0x0(%rbp,%rbp,4),%eax
  add    %eax,%eax
  sub    %eax,%ebx
  add    %edx,%ebx
  jmp    L1
```

assistant: ```c
int SumDigits(int number) {
  if (number / 10 == 0)
    return number;
  else
    return number % 10 + SumDigits(number / 10);
}
```
user: What is the c source code of the assembly code below?

```asm
<SumDigits>:
  endbr64
  lea    0x9(%rdi),%eax
  xor    %esi,%esi
  cmp    $0x12,%eax
  jbe    L9
  xchg   %ax,%ax
L3:
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%ecx
  mov    %edx,%eax
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edi,%edx
  mov    %eax,%edi
  lea    0x9(%rax),%eax
  add    %edx,%esi
  cmp    $0x12,%eax
  ja     L3
  lea    (%rdi,%rsi,1),%eax
  ret
L9:
  mov    %edi,%eax
  ret
```

assistant: ```c
int SumDigits(int number) {
  if (number / 10 == 0)
    return number;
  else
    return number % 10 + SumDigits(number / 10);
}
```
user: What is the c source code of the assembly code below?

```asm
<SumDigits>:
  endbr64
  lea    0x9(%rdi),%eax
  xor    %esi,%esi
  cmp    $0x12,%eax
  jbe    L6
  xchg   %ax,%ax
L0:
  movslq %edi,%rdx
  mov    %edi,%eax
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%eax
  sar    $0x22,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,4),%ecx
  mov    %edx,%eax
  add    %ecx,%ecx
  sub    %ecx,%edi
  mov    %edi,%edx
  mov    %eax,%edi
  lea    0x9(%rax),%eax
  add    %edx,%esi
  cmp    $0x12,%eax
  ja     L0
  lea    (%rdi,%rsi,1),%eax
  ret
L6:
  mov    %edi,%eax
  ret
```

assistant: ```c
int SumDigits(int number) {
  if (number / 10 == 0)
    return number;
  else
    return number % 10 + SumDigits(number / 10);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quat_mul>:
  endbr64
  movss  0x4(%rsi),%xmm3
  mulss  0x8(%rdx),%xmm3
  movss  0x8(%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  subss  %xmm0,%xmm3
  movss  %xmm3,(%rdi)
  movss  0x8(%rsi),%xmm1
  mulss  (%rdx),%xmm1
  movss  (%rsi),%xmm0
  mulss  0x8(%rdx),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  (%rsi),%xmm0
  mulss  0x4(%rdx),%xmm0
  movss  0x4(%rsi),%xmm2
  mulss  (%rdx),%xmm2
  subss  %xmm2,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdx),%xmm2
  movaps %xmm2,%xmm5
  mulss  0x4(%rsi),%xmm5
  movaps %xmm2,%xmm4
  mulss  0x8(%rsi),%xmm4
  mulss  (%rsi),%xmm2
  addss  %xmm3,%xmm2
  movss  %xmm2,(%rdi)
  addss  %xmm5,%xmm1
  movss  %xmm1,0x4(%rdi)
  addss  %xmm4,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm3
  movaps %xmm3,%xmm5
  mulss  0x4(%rdx),%xmm5
  movaps %xmm3,%xmm4
  mulss  0x8(%rdx),%xmm4
  mulss  (%rdx),%xmm3
  addss  %xmm2,%xmm3
  movss  %xmm3,(%rdi)
  addss  %xmm5,%xmm1
  movss  %xmm1,0x4(%rdi)
  addss  %xmm4,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rsi),%xmm0
  movaps %xmm0,%xmm1
  mulss  0xc(%rdx),%xmm1
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm0
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdx),%xmm2
  addss  %xmm2,%xmm0
  movss  0x8(%rsi),%xmm2
  mulss  0x8(%rdx),%xmm2
  addss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
  ret
```

assistant: ```c
void quat_mul(float *r, float *p, float *q) {
  float tmp[3];
  {
    (r)[0] = (p)[1] * (q)[2] - (p)[2] * (q)[1];
    (r)[1] = (p)[2] * (q)[0] - (p)[0] * (q)[2];
    (r)[2] = (p)[0] * (q)[1] - (p)[1] * (q)[0];
  };
  {
    (tmp)[0] = (p)[0] * (q[3]);
    (tmp)[1] = (p)[1] * (q[3]);
    (tmp)[2] = (p)[2] * (q[3]);
  };
  {
    (r)[0] = (r)[0] + (tmp)[0];
    (r)[1] = (r)[1] + (tmp)[1];
    (r)[2] = (r)[2] + (tmp)[2];
  };
  {
    (tmp)[0] = (q)[0] * (p[3]);
    (tmp)[1] = (q)[1] * (p[3]);
    (tmp)[2] = (q)[2] * (p[3]);
  };
  {
    (r)[0] = (r)[0] + (tmp)[0];
    (r)[1] = (r)[1] + (tmp)[1];
    (r)[2] = (r)[2] + (tmp)[2];
  };
  r[3] = p[3] * q[3] - ((p)[0] * (q)[0] + (p)[1] * (q)[1] + (p)[2] * (q)[2]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<quat_mul>:
  endbr64
  movss  0x4(%rsi),%xmm3
  movss  0x8(%rsi),%xmm0
  mulss  0x8(%rdx),%xmm3
  mulss  0x4(%rdx),%xmm0
  subss  %xmm0,%xmm3
  movss  %xmm3,(%rdi)
  movss  0x8(%rsi),%xmm1
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm1
  mulss  0x8(%rdx),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdx),%xmm0
  mulss  (%rdx),%xmm2
  subss  %xmm2,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdx),%xmm2
  movss  0x4(%rsi),%xmm5
  movss  0x8(%rsi),%xmm4
  mulss  %xmm2,%xmm5
  mulss  %xmm2,%xmm4
  mulss  (%rsi),%xmm2
  addss  %xmm5,%xmm1
  addss  %xmm4,%xmm0
  addss  %xmm3,%xmm2
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  movss  %xmm2,(%rdi)
  movss  0xc(%rsi),%xmm3
  movss  0x4(%rdx),%xmm5
  movss  0x8(%rdx),%xmm4
  mulss  %xmm3,%xmm5
  mulss  %xmm3,%xmm4
  mulss  (%rdx),%xmm3
  addss  %xmm5,%xmm1
  addss  %xmm4,%xmm0
  addss  %xmm2,%xmm3
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  movss  %xmm3,(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  0xc(%rdx),%xmm1
  mulss  %xmm0,%xmm1
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm0
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdx),%xmm2
  addss  %xmm2,%xmm0
  movss  0x8(%rsi),%xmm2
  mulss  0x8(%rdx),%xmm2
  addss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
  ret
```

assistant: ```c
void quat_mul(float *r, float *p, float *q) {
  float tmp[3];
  {
    (r)[0] = (p)[1] * (q)[2] - (p)[2] * (q)[1];
    (r)[1] = (p)[2] * (q)[0] - (p)[0] * (q)[2];
    (r)[2] = (p)[0] * (q)[1] - (p)[1] * (q)[0];
  };
  {
    (tmp)[0] = (p)[0] * (q[3]);
    (tmp)[1] = (p)[1] * (q[3]);
    (tmp)[2] = (p)[2] * (q[3]);
  };
  {
    (r)[0] = (r)[0] + (tmp)[0];
    (r)[1] = (r)[1] + (tmp)[1];
    (r)[2] = (r)[2] + (tmp)[2];
  };
  {
    (tmp)[0] = (q)[0] * (p[3]);
    (tmp)[1] = (q)[1] * (p[3]);
    (tmp)[2] = (q)[2] * (p[3]);
  };
  {
    (r)[0] = (r)[0] + (tmp)[0];
    (r)[1] = (r)[1] + (tmp)[1];
    (r)[2] = (r)[2] + (tmp)[2];
  };
  r[3] = p[3] * q[3] - ((p)[0] * (q)[0] + (p)[1] * (q)[1] + (p)[2] * (q)[2]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<quat_mul>:
  endbr64
  movss  0x4(%rsi),%xmm3
  movss  0x8(%rsi),%xmm0
  mulss  0x8(%rdx),%xmm3
  mulss  0x4(%rdx),%xmm0
  subss  %xmm0,%xmm3
  movss  %xmm3,(%rdi)
  movss  0x8(%rsi),%xmm1
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm1
  mulss  0x8(%rdx),%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdx),%xmm0
  mulss  (%rdx),%xmm2
  subss  %xmm2,%xmm0
  movss  %xmm0,0x8(%rdi)
  movss  0xc(%rdx),%xmm2
  movss  0x4(%rsi),%xmm5
  movss  0x8(%rsi),%xmm4
  mulss  %xmm2,%xmm5
  mulss  %xmm2,%xmm4
  mulss  (%rsi),%xmm2
  addss  %xmm5,%xmm1
  addss  %xmm4,%xmm0
  addss  %xmm3,%xmm2
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  movss  %xmm2,(%rdi)
  movss  0xc(%rsi),%xmm3
  movss  0x4(%rdx),%xmm5
  movss  0x8(%rdx),%xmm4
  mulss  %xmm3,%xmm5
  mulss  %xmm3,%xmm4
  mulss  (%rdx),%xmm3
  addss  %xmm5,%xmm1
  addss  %xmm4,%xmm0
  addss  %xmm2,%xmm3
  movss  %xmm1,0x4(%rdi)
  movss  %xmm0,0x8(%rdi)
  movss  %xmm3,(%rdi)
  movss  0xc(%rsi),%xmm0
  movss  0xc(%rdx),%xmm1
  mulss  %xmm0,%xmm1
  movss  (%rsi),%xmm0
  mulss  (%rdx),%xmm0
  movss  0x4(%rsi),%xmm2
  mulss  0x4(%rdx),%xmm2
  addss  %xmm2,%xmm0
  movss  0x8(%rsi),%xmm2
  mulss  0x8(%rdx),%xmm2
  addss  %xmm2,%xmm0
  subss  %xmm0,%xmm1
  movss  %xmm1,0xc(%rdi)
  ret
```

assistant: ```c
void quat_mul(float *r, float *p, float *q) {
  float tmp[3];
  {
    (r)[0] = (p)[1] * (q)[2] - (p)[2] * (q)[1];
    (r)[1] = (p)[2] * (q)[0] - (p)[0] * (q)[2];
    (r)[2] = (p)[0] * (q)[1] - (p)[1] * (q)[0];
  };
  {
    (tmp)[0] = (p)[0] * (q[3]);
    (tmp)[1] = (p)[1] * (q[3]);
    (tmp)[2] = (p)[2] * (q[3]);
  };
  {
    (r)[0] = (r)[0] + (tmp)[0];
    (r)[1] = (r)[1] + (tmp)[1];
    (r)[2] = (r)[2] + (tmp)[2];
  };
  {
    (tmp)[0] = (q)[0] * (p[3]);
    (tmp)[1] = (q)[1] * (p[3]);
    (tmp)[2] = (q)[2] * (p[3]);
  };
  {
    (r)[0] = (r)[0] + (tmp)[0];
    (r)[1] = (r)[1] + (tmp)[1];
    (r)[2] = (r)[2] + (tmp)[2];
  };
  r[3] = p[3] * q[3] - ((p)[0] * (q)[0] + (p)[1] * (q)[1] + (p)[2] * (q)[2]);
}
```
user: What is the c source code of the assembly code below:

```asm
<case_lowers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  jmp    L16
L13:
  subb   $0x41,-0x1(%rbp)
  cmpb   $0x19,-0x1(%rbp)
  ja     L11
  movzbl -0x1(%rbp),%eax
  add    $0x61,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
L11:
  addq   $0x1,-0x18(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0x0,-0x1(%rbp)
  jne    L13
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void case_lowers(s) char *s;
{
  unsigned char x;
  while (x = *s) {
    x -= 'A';
    if (x <= 'Z' - 'A')
      *s = x + 'a';
    ++s;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<case_lowers>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L28
L3:
  ret
L39:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L3
L28:
  lea    -0x41(%rax),%edx
  cmp    $0x19,%dl
  ja     L39
  add    $0x20,%eax
  mov    %al,(%rdi)
  jmp    L39
```

assistant: ```c
void case_lowers(s) char *s;
{
  unsigned char x;
  while (x = *s) {
    x -= 'A';
    if (x <= 'Z' - 'A')
      *s = x + 'a';
    ++s;
  }
}
```