ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<open_queue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L14
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  or     $0x1b0,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <msgget@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L12
  mov    $0xffffffff,%eax
  jmp    L27
L14:
  mov    -0x14(%rbp),%eax
  mov    $0x1b0,%esi
  mov    %eax,%edi
  call   <msgget@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L12
  mov    $0xffffffff,%eax
  jmp    L27
L12:
  mov    -0x4(%rbp),%eax
L27:
  leave
  ret
```

assistant: ```c
int open_queue(key_t keyval, int flag) {
  int qid;
  if (flag == 0) {
    if ((qid = msgget(keyval, IPC_CREAT | IPC_EXCL | 0660)) == -1) {
      return (-1);
    }
  } else {
    if ((qid = msgget(keyval, 0660)) == -1) {
      return (-1);
    }
  }
  return (qid);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<open_queue>:
  endbr64
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L6
  mov    D1(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  or     (%rax),%esi
  or     $0x1b0,%esi
  call   <msgget@plt>
L9:
  add    $0x8,%rsp
  ret
L6:
  mov    $0x1b0,%esi
  call   <msgget@plt>
  jmp    L9
```

assistant: ```c
int open_queue(key_t keyval, int flag) {
  int qid;
  if (flag == 0) {
    if ((qid = msgget(keyval, IPC_CREAT | IPC_EXCL | 0660)) == -1) {
      return (-1);
    }
  } else {
    if ((qid = msgget(keyval, 0660)) == -1) {
      return (-1);
    }
  }
  return (qid);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<open_queue>:
  endbr64
  test   %esi,%esi
  jne    L2
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  or     (%rax),%esi
  or     $0x1b0,%esi
  jmp    1050 <msgget@plt>
  nopl   (%rax)
L2:
  mov    $0x1b0,%esi
  jmp    1050 <msgget@plt>
```

assistant: ```c
int open_queue(key_t keyval, int flag) {
  int qid;
  if (flag == 0) {
    if ((qid = msgget(keyval, IPC_CREAT | IPC_EXCL | 0660)) == -1) {
      return (-1);
    }
  } else {
    if ((qid = msgget(keyval, 0660)) == -1) {
      return (-1);
    }
  }
  return (qid);
}
```
user: What is the c source code of the assembly code below:

```asm
<open_queue>:
  endbr64
  test   %esi,%esi
  jne    L7
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  mov    D6(%rip),%rax
  or     (%rax),%esi
  or     $0x1b0,%esi
  jmp    1050 <msgget@plt>
  nopl   (%rax)
L7:
  mov    $0x1b0,%esi
  jmp    1050 <msgget@plt>
```

assistant: ```c
int open_queue(key_t keyval, int flag) {
  int qid;
  if (flag == 0) {
    if ((qid = msgget(keyval, IPC_CREAT | IPC_EXCL | 0660)) == -1) {
      return (-1);
    }
  } else {
    if ((qid = msgget(keyval, 0660)) == -1) {
      return (-1);
    }
  }
  return (qid);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x60(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  lea    -0x58(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  lea    -0x48(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  movq   $0x0,0x10(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int main() {
  const void *******x;
  const void ********px = &x;
  struct {
    void *foo;
    struct {
      void *bar;
      void *ptr;
    } data;
  } inst, *pinst = &inst, **ppinst = &pinst, ***pppinst = &ppinst, ****ppppinst = &pppinst, *****pppppinst = &ppppinst;
  (****pppppinst)->data.ptr = (void *)0;
  const long val = (long)*******px;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    0x0,%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  const void *******x;
  const void ********px = &x;
  struct {
    void *foo;
    struct {
      void *bar;
      void *ptr;
    } data;
  } inst, *pinst = &inst, **ppinst = &pinst, ***pppinst = &ppinst, ****ppppinst = &pppinst, *****pppppinst = &ppppinst;
  (****pppppinst)->data.ptr = (void *)0;
  const long val = (long)*******px;
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    0x0,%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  const void *******x;
  const void ********px = &x;
  struct {
    void *foo;
    struct {
      void *bar;
      void *ptr;
    } data;
  } inst, *pinst = &inst, **ppinst = &pinst, ***pppinst = &ppinst, ****ppppinst = &pppinst, *****pppppinst = &ppppinst;
  (****pppppinst)->data.ptr = (void *)0;
  const long val = (long)*******px;
  return val;
}
```
user: What is the c source code of the assembly code below:

```asm
<sp_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <signal@plt>
  mov    $0x400,%edi
  call   <epoll_create@plt>
  pop    %rbp
  ret
```

assistant: ```c
int sp_create() {
  signal(SIGPIPE, SIG_IGN);
  return epoll_create(1024);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sp_create>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    $0x400,%edi
  call   <epoll_create@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int sp_create() {
  signal(SIGPIPE, SIG_IGN);
  return epoll_create(1024);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sp_create>:
  endbr64
  sub    $0x8,%rsp
  mov    D15(%rip),%rax
  mov    (%rax),%esi
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    $0x400,%edi
  add    $0x8,%rsp
  jmp    1070 <epoll_create@plt>
```

assistant: ```c
int sp_create() {
  signal(SIGPIPE, SIG_IGN);
  return epoll_create(1024);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sp_create>:
  endbr64
  sub    $0x8,%rsp
  mov    D10(%rip),%rax
  mov    (%rax),%esi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <signal@plt>
  mov    $0x400,%edi
  add    $0x8,%rsp
  jmp    1070 <epoll_create@plt>
```

assistant: ```c
int sp_create() {
  signal(SIGPIPE, SIG_IGN);
  return epoll_create(1024);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bs2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L32
L36:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jle    L23
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L32
L23:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x20(%rbp)
  jge    L61
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L32
L61:
  mov    -0x4(%rbp),%eax
  jmp    L21
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L36
  mov    -0x8(%rbp),%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int bs2(int *a, int len, int to_find) {
  int tree_start = 0;
  int tree_end = len;
  int k;
  while (tree_start < tree_end) {
    k = (tree_start + tree_end) / 2;
    if (a[k] < to_find)
      tree_start = k + 1;
    else if (a[k] > to_find)
      tree_end = k;
    else
      return k;
  }
  return tree_end;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<bs2>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L16
  mov    $0x0,%esi
  jmp    L45
L21:
  jle    L51
  mov    %ecx,%eax
L53:
  cmp    %eax,%esi
  jge    L40
L45:
  lea    (%rsi,%rax,1),%r8d
  mov    %r8d,%ecx
  shr    $0x1f,%ecx
  add    %r8d,%ecx
  sar    %ecx
  movslq %ecx,%r8
  mov    (%rdi,%r8,4),%r8d
  cmp    %edx,%r8d
  jge    L21
  lea    0x1(%rcx),%esi
  jmp    L53
L40:
  ret
L51:
  mov    %ecx,%eax
L16:
  ret
```

assistant: ```c
int bs2(int *a, int len, int to_find) {
  int tree_start = 0;
  int tree_end = len;
  int k;
  while (tree_start < tree_end) {
    k = (tree_start + tree_end) / 2;
    if (a[k] < to_find)
      tree_start = k + 1;
    else if (a[k] > to_find)
      tree_end = k;
    else
      return k;
  }
  return tree_end;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bs2>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L10
  xor    %esi,%esi
  jmp    L11
  xchg   %ax,%ax
L30:
  lea    0x1(%rcx),%esi
L24:
  cmp    %esi,%eax
  jle    L19
L11:
  lea    (%rsi,%rax,1),%ecx
  sar    %ecx
  movslq %ecx,%r8
  cmp    %edx,(%rdi,%r8,4)
  jl     L30
  mov    %ecx,%eax
  jg     L24
L10:
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
int bs2(int *a, int len, int to_find) {
  int tree_start = 0;
  int tree_end = len;
  int k;
  while (tree_start < tree_end) {
    k = (tree_start + tree_end) / 2;
    if (a[k] < to_find)
      tree_start = k + 1;
    else if (a[k] > to_find)
      tree_end = k;
    else
      return k;
  }
  return tree_end;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bs2>:
  endbr64
  mov    %esi,%eax
  test   %esi,%esi
  jle    L43
  xor    %esi,%esi
  jmp    L30
  xchg   %ax,%ax
L41:
  lea    0x1(%rcx),%esi
L48:
  cmp    %esi,%eax
  jle    L0
L30:
  lea    (%rsi,%rax,1),%ecx
  sar    %ecx
  movslq %ecx,%r8
  cmp    %edx,(%rdi,%r8,4)
  jl     L41
  mov    %ecx,%eax
  jg     L48
L43:
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
int bs2(int *a, int len, int to_find) {
  int tree_start = 0;
  int tree_end = len;
  int k;
  while (tree_start < tree_end) {
    k = (tree_start + tree_end) / 2;
    if (a[k] < to_find)
      tree_start = k + 1;
    else if (a[k] > to_find)
      tree_end = k;
    else
      return k;
  }
  return tree_end;
}
```
user: What is the c source code of the assembly code below:

```asm
<arrayReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L17
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
  subl   $0x1,-0x8(%rbp)
L17:
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void arrayReverse(int array[], int size) {
  for (int i = 0, j = size - 1; i < j; i++, j--) {
    int exchange = array[i];
    array[i] = array[j];
    array[j] = exchange;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arrayReverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L11
  movslq %esi,%rsi
  mov    $0x0,%eax
L12:
  mov    (%rdi,%rax,4),%edx
  mov    (%rdi,%rsi,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  mov    %edx,(%rdi,%rsi,4)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L12
L11:
  ret
```

assistant: ```c
void arrayReverse(int array[], int size) {
  for (int i = 0, j = size - 1; i < j; i++, j--) {
    int exchange = array[i];
    array[i] = array[j];
    array[j] = exchange;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<arrayReverse>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L7
  movslq %esi,%rsi
  xor    %eax,%eax
L18:
  mov    (%rdi,%rax,4),%edx
  mov    (%rdi,%rsi,4),%ecx
  mov    %ecx,(%rdi,%rax,4)
  add    $0x1,%rax
  mov    %edx,(%rdi,%rsi,4)
  sub    $0x1,%rsi
  cmp    %eax,%esi
  jg     L18
L7:
  ret
```

assistant: ```c
void arrayReverse(int array[], int size) {
  for (int i = 0, j = size - 1; i < j; i++, j--) {
    int exchange = array[i];
    array[i] = array[j];
    array[j] = exchange;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<arrayReverse>:
  endbr64
  lea    -0x1(%rsi),%eax
  test   %eax,%eax
  jle    L85
  lea    -0x2(%rsi),%r8d
  movslq %esi,%rsi
  mov    %r8d,%r10d
  lea    0x0(,%rsi,4),%rcx
  shr    %r10d
  mov    %rcx,%rsi
  lea    0x1(%r10),%edx
  mov    %rdx,%r9
  shl    $0x2,%rdx
  sub    %rdx,%rsi
  cmp    %rsi,%rdx
  setle  %dl
  test   %rcx,%rcx
  setle  %sil
  or     %sil,%dl
  je     L71
  cmp    $0x1,%r8d
  jbe    L71
  cmp    $0x5,%r8d
  jbe    L11
  mov    %r9d,%r8d
  mov    %rdi,%rdx
  lea    -0x10(%rdi,%rcx,1),%rsi
  shr    $0x2,%r8d
  sub    $0x1,%r8d
  shl    $0x4,%r8
  lea    0x10(%rdi,%r8,1),%r8
  nopl   0x0(%rax,%rax,1)
L44:
  movdqu (%rsi),%xmm2
  movdqu (%rdx),%xmm0
  add    $0x10,%rdx
  sub    $0x10,%rsi
  pshufd $0x1b,%xmm2,%xmm1
  pshufd $0x1b,%xmm0,%xmm0
  movups %xmm1,-0x10(%rdx)
  movups %xmm0,0x10(%rsi)
  cmp    %r8,%rdx
  jne    L44
  mov    %r9d,%esi
  and    $0xfffffffc,%esi
  mov    %esi,%edx
  sub    %esi,%eax
  cmp    %esi,%r9d
  je     L21
L34:
  sub    %esi,%r9d
  cmp    %esi,%r10d
  je     L89
  shl    $0x2,%rsi
  sub    $0x8,%rcx
  sub    %rsi,%rcx
  lea    (%rdi,%rsi,1),%r8
  add    %rdi,%rcx
  movq   (%r8),%xmm0
  movq   (%rcx),%xmm1
  pshufd $0xe1,%xmm0,%xmm0
  pshufd $0xe1,%xmm1,%xmm1
  movq   %xmm1,(%r8)
  movq   %xmm0,(%rcx)
  mov    %r9d,%ecx
  and    $0xfffffffe,%ecx
  add    %ecx,%edx
  sub    %ecx,%eax
  cmp    %ecx,%r9d
  je     L85
L89:
  movslq %edx,%rdx
  cltq
  lea    (%rdi,%rdx,4),%rdx
  lea    (%rdi,%rax,4),%rax
  mov    (%rdx),%ecx
  mov    (%rax),%esi
  mov    %esi,(%rdx)
  mov    %ecx,(%rax)
  ret
  nopl   (%rax)
L71:
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax)
L67:
  mov    (%rdi,%rdx,4),%ecx
  mov    (%rdi,%rax,4),%esi
  mov    %esi,(%rdi,%rdx,4)
  add    $0x1,%rdx
  mov    %ecx,(%rdi,%rax,4)
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L67
L85:
  ret
  nopl   0x0(%rax)
L21:
  ret
L11:
  xor    %esi,%esi
  xor    %edx,%edx
  jmp    L34
```

assistant: ```c
void arrayReverse(int array[], int size) {
  for (int i = 0, j = size - 1; i < j; i++, j--) {
    int exchange = array[i];
    array[i] = array[j];
    array[j] = exchange;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<arith_shift_right>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L10
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  jmp    L18
L10:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int32_t __attribute__((always_)) arith_shift_right(int32_t x, int shift) {
  if (x >= 0)
    return x >> shift;
  return ~((~x) >> shift);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<arith_shift_right>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  sar    %cl,%eax
  ret
```

assistant: ```c
int32_t __attribute__((always_)) arith_shift_right(int32_t x, int shift) {
  if (x >= 0)
    return x >> shift;
  return ~((~x) >> shift);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<arith_shift_right>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  sar    %cl,%eax
  ret
```

assistant: ```c
int32_t __attribute__((always_)) arith_shift_right(int32_t x, int shift) {
  if (x >= 0)
    return x >> shift;
  return ~((~x) >> shift);
}
```
user: What is the c source code of the assembly code below?

```asm
<arith_shift_right>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%ecx
  sar    %cl,%eax
  ret
```

assistant: ```c
int32_t __attribute__((always_)) arith_shift_right(int32_t x, int shift) {
  if (x >= 0)
    return x >> shift;
  return ~((~x) >> shift);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0xffffffffffffffff,-0x8(%rbp)
  movabs $0x7fffffffffffffff,%rax
  cmp    %rax,-0x8(%rbp)
  je     L3
  cmpq   $0xffffffffffffffff,-0x8(%rbp)
  jne    L12
  mov    $0x1,%eax
  jmp    L15
L3:
  mov    $0x2,%eax
  jmp    L15
L12:
  mov    $0x3,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  unsigned long test = -1L >> 1;
  switch (test) {
  case (char)-1:
    return 1;
  case ((unsigned long)-1L >> 1):
    return 2;
  default:
    return 3;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long test = -1L >> 1;
  switch (test) {
  case (char)-1:
    return 1;
  case ((unsigned long)-1L >> 1):
    return 2;
  default:
    return 3;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long test = -1L >> 1;
  switch (test) {
  case (char)-1:
    return 1;
  case ((unsigned long)-1L >> 1):
    return 2;
  default:
    return 3;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int main() {
  unsigned long test = -1L >> 1;
  switch (test) {
  case (char)-1:
    return 1;
  case ((unsigned long)-1L >> 1):
    return 2;
  default:
    return 3;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L31:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L44
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  jne    L3
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <char_to_int@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  jmp    L10
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <char_to_int@plt>
  add    %eax,-0x4(%rbp)
L10:
  addl   $0x1,-0x8(%rbp)
L44:
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L31
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  mov    $0xa,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int check_sum(char *isbn) {
  int i, evenodd = 0, sum = 0;
  for (i = 0; i < strlen(isbn) - 1; i++) {
    if (isbn[i] != '-') {
      if (evenodd % 2 == 1) {
        sum = sum + (char_to_int(isbn[i]) * 3);
      } else {
        sum = sum + (char_to_int(isbn[i]) * 1);
      }
      evenodd++;
    }
  }
  sum = sum % 10;
  sum = 10 - sum;
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_sum>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  mov    $0x0,%ebp
  jmp    L3
L9:
  movsbl %dil,%edi
  call   <char_to_int@plt>
  lea    (%rax,%rax,2),%eax
  add    %eax,%r13d
L31:
  add    $0x1,%ebp
L48:
  add    $0x1,%rbx
L3:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L26
  movzbl (%r12,%rbx,1),%edi
  cmp    $0x2d,%dil
  je     L48
  mov    %ebp,%edx
  shr    $0x1f,%edx
  lea    0x0(%rbp,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  cmp    $0x1,%eax
  je     L9
  movsbl %dil,%edi
  call   <char_to_int@plt>
  add    %eax,%r13d
  jmp    L31
L26:
  movslq %r13d,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %r13d,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %r13d,%eax
  lea    0xa(%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int check_sum(char *isbn) {
  int i, evenodd = 0, sum = 0;
  for (i = 0; i < strlen(isbn) - 1; i++) {
    if (isbn[i] != '-') {
      if (evenodd % 2 == 1) {
        sum = sum + (char_to_int(isbn[i]) * 3);
      } else {
        sum = sum + (char_to_int(isbn[i]) * 1);
      }
      evenodd++;
    }
  }
  sum = sum % 10;
  sum = 10 - sum;
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<check_sum>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L30
  nopl   0x0(%rax,%rax,1)
L22:
  call   <char_to_int@plt>
  add    %eax,%r13d
L17:
  add    $0x1,%r12d
L11:
  add    $0x1,%rbx
L30:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jle    L33
  movsbl 0x0(%rbp,%rbx,1),%edi
  cmp    $0x2d,%dil
  je     L11
  test   $0x1,%r12b
  je     L22
  call   <char_to_int@plt>
  lea    (%rax,%rax,2),%eax
  add    %eax,%r13d
  jmp    L17
  nopl   (%rax)
L33:
  movslq %r13d,%rax
  mov    %r13d,%edx
  add    $0x8,%rsp
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  sar    $0x22,%rax
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %r13d,%eax
  pop    %r13
  add    $0xa,%eax
  ret
```

assistant: ```c
int check_sum(char *isbn) {
  int i, evenodd = 0, sum = 0;
  for (i = 0; i < strlen(isbn) - 1; i++) {
    if (isbn[i] != '-') {
      if (evenodd % 2 == 1) {
        sum = sum + (char_to_int(isbn[i]) * 3);
      } else {
        sum = sum + (char_to_int(isbn[i]) * 1);
      }
      evenodd++;
    }
  }
  sum = sum % 10;
  sum = 10 - sum;
  return sum;
}
```