user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r14
  lea    D45(%rip),%r14
  push   %r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  sub    $0xfc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xfb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%r13
  lea    0x4(%rsp),%rbx
  nopl   (%rax)
L40:
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  cmp    $0x3e8,%eax
  jg     L40
  cmp    0x4(%rsp),%eax
  jl     L40
  lea    D14(%rip),%r12
  mov    %rsp,%rbx
  nopl   (%rax)
L18:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  cmp    0x4(%rsp),%eax
  jl     L18
  cmp    0x8(%rsp),%eax
  jg     L18
  test   %eax,%eax
  jle    L34
  lea    0x10(%rsp),%r12
  xor    %ebx,%ebx
  lea    D24(%rip),%r13
  cs nopw 0x0(%rax,%rax,1)
L66:
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  add    $0x4,%r12
  call   <scanf@plt>
  cmp    %ebx,(%rsp)
  jg     L66
L34:
  lea    D31(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L24
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  lea    D8(%rip),%r12
  nopl   0x0(%rax)
L59:
  mov    0x0(%rbp),%esi
  imul   0xc(%rsp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  mov    %esi,-0x4(%rbp)
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jg     L59
L24:
  mov    0xfb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L52
  add    $0xfc0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L52:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D45
type: string
name: read_data
arguments: tag: D9
type: string
name: read_data
arguments: tag: D21
type: string
name: read_data
arguments: tag: D14
type: string
name: read_data
arguments: tag: D24
type: string
name: read_data
arguments: tag: D31
type: string
name: read_data
arguments: tag: D8
type: string

tool: D45: 
 inseire n2 minore di 1000  

tool: D9: 
 inserire n1 minore di n2  

tool: D21: %d

tool: D14: 
 inserire il vettore dell'array  

tool: D24: 
 inserire un numero  

tool: D31: 
 inserire un numero intero  

tool: D8: %d  

assistant: ```c
main() {
  int vettore[1000];
  int K;
  int n1;
  int n2;
  int NUM;
  int x;
  do {
    printf("\n inseire n2 minore di 1000  ");
    scanf("%d", &n2);
    printf("\n inserire n1 minore di n2  ");
    scanf("%d", &n1);
  } while ((n2 > 1000) || (n1 > n2));
  do {
    printf("\n inserire il vettore dell'array  ");
    scanf("%d", &K);
  } while ((K < n1) || (K > n2));
  x = 0;
  while (x < K) {
    printf("\n inserire un numero  ");
    scanf("%d", &vettore[x]);
    x++;
  }
  printf("\n inserire un numero intero  ");
  scanf("%d", &NUM);
  x = 0;
  while (x < K) {
    vettore[x] = vettore[x] * NUM;
    printf("%d  ", vettore[x]);
    x++;
  }
}
```