ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  add    (%rsp),%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D19
type_guessed: string

tool: D2: %d %d

tool: D19: %d

assistant: ```c
int main(int argc, char *argv[]) {
  int a, b;
  scanf("%d %d", &a, &b);
  printf("%d", a + b);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<myAtoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L73
  mov    $0x0,%eax
  jmp    L230
L73:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L202
  mov    $0x0,%eax
  jmp    L230
L202:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L137
L51:
  addq   $0x1,-0x10(%rbp)
L137:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L51
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L51
  movl   $0x0,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L199
  movl   $0x1,-0x1c(%rbp)
  addq   $0x1,-0x10(%rbp)
  jmp    L209
L199:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L209
  addq   $0x1,-0x10(%rbp)
L209:
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L198
L92:
  addq   $0x1,-0x8(%rbp)
L198:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L255
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jle    L92
L255:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L30
  mov    $0x0,%eax
  jmp    L230
L30:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  cmp    $0xa,%rax
  jle    L194
  cmpl   $0x0,-0x1c(%rbp)
  je     L12
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L230
L12:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  jmp    L230
L194:
  movl   $0x0,-0x18(%rbp)
  jmp    L147
L166:
  mov    -0x18(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x18(%rbp)
  addq   $0x1,-0x10(%rbp)
L147:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jb     L166
  cmpl   $0x0,-0x1c(%rbp)
  je     L69
  negl   -0x18(%rbp)
L69:
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jle    L191
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  jmp    L230
L191:
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x18(%rbp)
  jge    L222
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  jmp    L230
L222:
  mov    -0x18(%rbp),%eax
L230:
  leave
  ret
```

assistant: ```c
int myAtoi(const char *s) {
  if (s == NULL)
    return 0;
  int len = strlen(s);
  if (len == 0)
    return 0;
  const char *b = s;
  while (*b == ' ' || *b == '\t')
    b++;
  int minus = 0;
  if (*b == '-') {
    minus = 1;
    b++;
  } else if (*b == '+')
    b++;
  const char *e = b;
  while (*e >= '0' && *e <= '9')
    e++;
  if (e == b)
    return 0;
  if (e - b > 10)
    return minus ? INT_MIN : INT_MAX;
  int64_t result = 0;
  while (b < e) {
    result = (result << 3) + (result << 1) + (*b) - '0';
    b++;
  }
  if (minus)
    result = -result;
  if (result > INT_MAX)
    return INT_MAX;
  else if (result < INT_MIN)
    return INT_MIN;
  return (int)result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<myAtoi>:
  endbr64
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L65
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L127
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L44
  cmp    $0x9,%al
  jne    L24
L44:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0x20,%al
  je     L44
  cmp    $0x9,%al
  je     L44
L24:
  cmp    $0x2d,%al
  je     L208
  mov    $0x0,%esi
  cmp    $0x2b,%al
  je     L72
L40:
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L140
  mov    %rbx,%rdx
L183:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L183
  cmp    %rdx,%rbx
  je     L148
  mov    %rdx,%rax
  sub    %rbx,%rax
  cmp    $0xa,%rax
  jg     L88
  mov    $0x0,%ecx
  cmp    %rdx,%rbx
  jae    L75
L141:
  lea    (%rcx,%rcx,4),%ecx
  movsbl (%rbx),%eax
  lea    -0x30(%rax,%rcx,2),%ecx
  add    $0x1,%rbx
  cmp    %rdx,%rbx
  jne    L141
L75:
  mov    %ecx,%eax
  neg    %eax
  test   %esi,%esi
  cmovne %eax,%ecx
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  cmp    %ecx,%eax
  jl     L127
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%ecx
  cmovge %ecx,%eax
L127:
  pop    %rbx
  ret
L208:
  add    $0x1,%rbx
  mov    $0x1,%esi
  jmp    L40
L72:
  add    $0x1,%rbx
  jmp    L40
L88:
  test   %esi,%esi
  je     L14
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L127
L14:
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  jmp    L127
L140:
  mov    $0x0,%eax
  jmp    L127
L148:
  mov    $0x0,%eax
  jmp    L127
L65:
  ret
```

assistant: ```c
int myAtoi(const char *s) {
  if (s == NULL)
    return 0;
  int len = strlen(s);
  if (len == 0)
    return 0;
  const char *b = s;
  while (*b == ' ' || *b == '\t')
    b++;
  int minus = 0;
  if (*b == '-') {
    minus = 1;
    b++;
  } else if (*b == '+')
    b++;
  const char *e = b;
  while (*e >= '0' && *e <= '9')
    e++;
  if (e == b)
    return 0;
  if (e - b > 10)
    return minus ? INT_MIN : INT_MAX;
  int64_t result = 0;
  while (b < e) {
    result = (result << 3) + (result << 1) + (*b) - '0';
    b++;
  }
  if (minus)
    result = -result;
  if (result > INT_MAX)
    return INT_MAX;
  else if (result < INT_MIN)
    return INT_MIN;
  return (int)result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<myAtoi>:
  endbr64
  test   %rdi,%rdi
  je     L108
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L122
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L89
  cmp    $0x20,%al
  jne    L107
  nopl   0x0(%rax)
L89:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L89
  cmp    $0x9,%al
  je     L89
L107:
  cmp    $0x2d,%al
  je     L60
  xor    %edi,%edi
  cmp    $0x2b,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
L132:
  movsbl (%rbx),%ecx
  lea    -0x30(%rcx),%eax
  cmp    $0x9,%al
  ja     L122
  mov    %rbx,%rdx
  nopw   0x0(%rax,%rax,1)
L155:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L155
  cmp    %rdx,%rbx
  je     L122
  mov    %rdx,%rax
  sub    %rbx,%rax
  cmp    $0xa,%rax
  jg     L157
  xor    %esi,%esi
  cmp    %rdx,%rbx
  jb     L65
  jmp    L0
  nopl   0x0(%rax)
L52:
  movsbl (%rbx),%ecx
L65:
  lea    (%rsi,%rsi,4),%eax
  add    $0x1,%rbx
  lea    -0x30(%rcx,%rax,2),%esi
  cmp    %rdx,%rbx
  jne    L52
L0:
  mov    %esi,%eax
  neg    %eax
  test   %edi,%edi
  cmovne %eax,%esi
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cmp    %esi,%eax
  jl     L46
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%esi
  cmovge %esi,%eax
L46:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L122:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L108:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L60:
  add    $0x1,%rbx
  mov    $0x1,%edi
  jmp    L132
  cs nopw 0x0(%rax,%rax,1)
L157:
  test   %edi,%edi
  je     L110
  mov    D10(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
  nop
L110:
  mov    D5(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int myAtoi(const char *s) {
  if (s == NULL)
    return 0;
  int len = strlen(s);
  if (len == 0)
    return 0;
  const char *b = s;
  while (*b == ' ' || *b == '\t')
    b++;
  int minus = 0;
  if (*b == '-') {
    minus = 1;
    b++;
  } else if (*b == '+')
    b++;
  const char *e = b;
  while (*e >= '0' && *e <= '9')
    e++;
  if (e == b)
    return 0;
  if (e - b > 10)
    return minus ? INT_MIN : INT_MAX;
  int64_t result = 0;
  while (b < e) {
    result = (result << 3) + (result << 1) + (*b) - '0';
    b++;
  }
  if (minus)
    result = -result;
  if (result > INT_MAX)
    return INT_MAX;
  else if (result < INT_MIN)
    return INT_MIN;
  return (int)result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<myAtoi>:
  endbr64
  test   %rdi,%rdi
  je     L123
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  je     L55
  movzbl (%rbx),%eax
  cmp    $0x9,%al
  je     L139
  cmp    $0x20,%al
  jne    L7
  nopl   0x0(%rax)
L139:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0x20,%al
  je     L139
  cmp    $0x9,%al
  je     L139
L7:
  cmp    $0x2d,%al
  je     L15
  xor    %esi,%esi
  cmp    $0x2b,%al
  je     L130
L134:
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L55
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L47:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L47
  cmp    %rdx,%rbx
  je     L55
  mov    %rdx,%rax
  sub    %rbx,%rax
  cmp    $0xa,%rax
  jg     L0
  xor    %ecx,%ecx
  cmp    %rdx,%rbx
  jae    L39
  nopl   0x0(%rax,%rax,1)
L146:
  movsbl (%rbx),%eax
  lea    (%rcx,%rcx,4),%ecx
  add    $0x1,%rbx
  lea    -0x30(%rax,%rcx,2),%ecx
  cmp    %rdx,%rbx
  jne    L146
L39:
  mov    %ecx,%eax
  neg    %eax
  test   %esi,%esi
  cmovne %eax,%ecx
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  cmp    %ecx,%eax
  jl     L119
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%ecx
  cmovge %ecx,%eax
L119:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L55:
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L130:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  jmp    L134
  nopl   (%rax)
L123:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  movzbl 0x1(%rbx),%eax
  mov    $0x1,%esi
  add    $0x1,%rbx
  jmp    L134
  nopw   0x0(%rax,%rax,1)
L0:
  test   %esi,%esi
  je     L4
  mov    D10(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    D21(%rip),%rax
  pop    %rbx
  mov    (%rax),%eax
  ret
```

assistant: ```c
int myAtoi(const char *s) {
  if (s == NULL)
    return 0;
  int len = strlen(s);
  if (len == 0)
    return 0;
  const char *b = s;
  while (*b == ' ' || *b == '\t')
    b++;
  int minus = 0;
  if (*b == '-') {
    minus = 1;
    b++;
  } else if (*b == '+')
    b++;
  const char *e = b;
  while (*e >= '0' && *e <= '9')
    e++;
  if (e == b)
    return 0;
  if (e - b > 10)
    return minus ? INT_MIN : INT_MAX;
  int64_t result = 0;
  while (b < e) {
    result = (result << 3) + (result << 1) + (*b) - '0';
    b++;
  }
  if (minus)
    result = -result;
  if (result > INT_MAX)
    return INT_MAX;
  else if (result < INT_MIN)
    return INT_MIN;
  return (int)result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <print_debug@plt>
  lea    D7(%rip),%rdi
  call   <print_debug@plt>
  mov    $0x0,%edi
  call   <_exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
data_type: string
name: disassemble_data
arguments: label: D7
data_type: string

tool: D5: B


tool: D7: Registered


assistant: ```c
void main(void) {
  static const int value[] = {1};
  const char *str;
  if (value[1]) {
    print_debug("A\r\n");
    str = "Unbuffered\r\n";
  } else {
    print_debug("B\r\n");
    str = "Registered\r\n";
  }
  print_debug(str);
  _exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <print_debug@plt>
  lea    D7(%rip),%rdi
  call   <print_debug@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D7
data_type: string

tool: D4: B


tool: D7: Registered


assistant: ```c
void main(void) {
  static const int value[] = {1};
  const char *str;
  if (value[1]) {
    print_debug("A\r\n");
    str = "Unbuffered\r\n";
  } else {
    print_debug("B\r\n");
    str = "Registered\r\n";
  }
  print_debug(str);
  _exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <print_debug@plt>
  lea    D12(%rip),%rdi
  call   <print_debug@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1060 <_exit@plt>
```

tool_calls: name: unpack_data
arguments: label: D17
datatype: string
name: unpack_data
arguments: label: D12
datatype: string

tool: D17: B


tool: D12: Registered


assistant: ```c
void main(void) {
  static const int value[] = {1};
  const char *str;
  if (value[1]) {
    print_debug("A\r\n");
    str = "Unbuffered\r\n";
  } else {
    print_debug("B\r\n");
    str = "Registered\r\n";
  }
  print_debug(str);
  _exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L18
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L2
L18:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L2:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jle    L0
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L50
L0:
  mov    -0xc(%rbp),%eax
  test   %eax,%eax
  jns    L33
  lea    D72(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L50
L33:
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L50:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L53
  call   <__stack_chk_fail@plt>
L53:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string
name: unpack_data
arguments: label: D56
data_type: string
name: unpack_data
arguments: label: D64
data_type: string
name: unpack_data
arguments: label: D43
data_type: string
name: unpack_data
arguments: label: D24
data_type: string
name: unpack_data
arguments: label: D49
data_type: string
name: unpack_data
arguments: label: D50
data_type: string
name: unpack_data
arguments: label: D72
data_type: string
name: unpack_data
arguments: label: D22
data_type: string

tool: D3: Me diga um numero e eu te direi o que ele e!


tool: D56: %d

tool: D64: O numero informado e par ou impar?


tool: D43: Ele e par!


tool: D24: Ele e impar!


tool: D49: O numero e positivo, negativo ou neutro?


tool: D50: O numero e positivo!


tool: D72: O numero e negativo!


tool: D22: Ele e neutro!


assistant: ```c
int main() {
  int numero;
  printf("Me diga um numero e eu te direi o que ele e!\n");
  scanf("%d", &numero);
  printf("O numero informado e par ou impar?\n");
  if ((numero % 2) == 0) {
    printf("Ele e par!\n");
  } else {
    printf("Ele e impar!\n");
  }
  printf("O numero e positivo, negativo ou neutro?\n");
  if (numero > 0) {
    printf("O numero e positivo!\n");
  } else {
    if (numero < 0) {
      printf("O numero e negativo!\n");
    } else {
      printf("Ele e neutro!\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D71(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L1
  lea    D13(%rip),%rdi
  call   <printf@plt>
L7:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L43
  js     L30
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L1:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L43:
  lea    D65(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L30:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D71
type: string
name: unpack_data
arguments: data_label: D20
type: string
name: unpack_data
arguments: data_label: D29
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D48
type: string
name: unpack_data
arguments: data_label: D6
type: string
name: unpack_data
arguments: data_label: D39
type: string
name: unpack_data
arguments: data_label: D65
type: string
name: unpack_data
arguments: data_label: D23
type: string

tool: D71: Me diga um numero e eu te direi o que ele e!


tool: D20: %d

tool: D29: O numero informado e par ou impar?


tool: D13: Ele e par!


tool: D48: O numero e positivo, negativo ou neutro?


tool: D6: Ele e neutro!


tool: D39: Ele e impar!


tool: D65: O numero e positivo!


tool: D23: O numero e negativo!


assistant: ```c
int main() {
  int numero;
  printf("Me diga um numero e eu te direi o que ele e!\n");
  scanf("%d", &numero);
  printf("O numero informado e par ou impar?\n");
  if ((numero % 2) == 0) {
    printf("Ele e par!\n");
  } else {
    printf("Ele e impar!\n");
  }
  printf("O numero e positivo, negativo ou neutro?\n");
  if (numero > 0) {
    printf("O numero e positivo!\n");
  } else {
    if (numero < 0) {
      printf("O numero e negativo!\n");
    } else {
      printf("Ele e neutro!\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D72(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D15(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  call   <printf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L37
  lea    D33(%rip),%rdi
  call   <printf@plt>
L66:
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L3
  jne    L42
  lea    D63(%rip),%rdi
  call   <printf@plt>
L62:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L37:
  lea    D42(%rip),%rdi
  call   <printf@plt>
  jmp    L66
L42:
  lea    D64(%rip),%rdi
  call   <printf@plt>
  jmp    L62
L3:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L62
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D72
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D41
type_guessed: string
name: retrieve_data
arguments: data_label: D33
type_guessed: string
name: retrieve_data
arguments: data_label: D49
type_guessed: string
name: retrieve_data
arguments: data_label: D63
type_guessed: string
name: retrieve_data
arguments: data_label: D42
type_guessed: string
name: retrieve_data
arguments: data_label: D64
type_guessed: string
name: retrieve_data
arguments: data_label: D3
type_guessed: string

tool: D72: Me diga um numero e eu te direi o que ele e!


tool: D15: %d

tool: D41: O numero informado e par ou impar?


tool: D33: Ele e par!


tool: D49: O numero e positivo, negativo ou neutro?


tool: D63: Ele e neutro!


tool: D42: Ele e impar!


tool: D64: O numero e negativo!


tool: D3: O numero e positivo!


assistant: ```c
int main() {
  int numero;
  printf("Me diga um numero e eu te direi o que ele e!\n");
  scanf("%d", &numero);
  printf("O numero informado e par ou impar?\n");
  if ((numero % 2) == 0) {
    printf("Ele e par!\n");
  } else {
    printf("Ele e impar!\n");
  }
  printf("O numero e positivo, negativo ou neutro?\n");
  if (numero > 0) {
    printf("O numero e positivo!\n");
  } else {
    if (numero < 0) {
      printf("O numero e negativo!\n");
    } else {
      printf("Ele e neutro!\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D72(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D32(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  testb  $0x1,0x4(%rsp)
  jne    L38
  lea    D76(%rip),%rdi
  call   <printf@plt>
L68:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jg     L25
  jne    L19
  lea    D63(%rip),%rdi
  call   <printf@plt>
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L38:
  lea    D61(%rip),%rdi
  call   <printf@plt>
  jmp    L68
L19:
  lea    D51(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L25:
  lea    D53(%rip),%rdi
  call   <printf@plt>
  jmp    L0
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D72
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D68
datatype: string
name: parse_data
arguments: data_tag: D76
datatype: string
name: parse_data
arguments: data_tag: D26
datatype: string
name: parse_data
arguments: data_tag: D63
datatype: string
name: parse_data
arguments: data_tag: D61
datatype: string
name: parse_data
arguments: data_tag: D51
datatype: string
name: parse_data
arguments: data_tag: D53
datatype: string

tool: D72: Me diga um numero e eu te direi o que ele e!


tool: D32: %d

tool: D68: O numero informado e par ou impar?


tool: D76: Ele e par!


tool: D26: O numero e positivo, negativo ou neutro?


tool: D63: Ele e neutro!


tool: D61: Ele e impar!


tool: D51: O numero e negativo!


tool: D53: O numero e positivo!


assistant: ```c
int main() {
  int numero;
  printf("Me diga um numero e eu te direi o que ele e!\n");
  scanf("%d", &numero);
  printf("O numero informado e par ou impar?\n");
  if ((numero % 2) == 0) {
    printf("Ele e par!\n");
  } else {
    printf("Ele e impar!\n");
  }
  printf("O numero e positivo, negativo ou neutro?\n");
  if (numero > 0) {
    printf("O numero e positivo!\n");
  } else {
    if (numero < 0) {
      printf("O numero e negativo!\n");
    } else {
      printf("Ele e neutro!\n");
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L21:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L12
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L41
L2:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jge    L2
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L45
L12:
  addl   $0x1,-0xc(%rbp)
L26:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L21
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
L45:
  pop    %rbp
  ret
```

assistant: ```c
void insert(int *arr, int a, int n) {
  int i;
  int key = a;
  for (i = 0; i < n; i++) {
    if (key < arr[i]) {
      int j;
      for (j = n - 1; j >= i; j--) {
        arr[j + 1] = arr[j];
      }
      arr[i] = key;
      return;
    }
  }
  arr[n] = key;
  return;
}
```