user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D38(%rip),%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rax
  lea    0x1c(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    0x24(%rsp),%r15
  nopl   (%rax)
L3:
  xor    %eax,%eax
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  jle    L155
  mov    0x1c(%rsp),%eax
  add    $0x1,%eax
  lea    0x0(,%rax,4),%edi
  mov    %eax,0x1c(%rsp)
  call   <malloc@plt>
  cmpl   $0x1,0x1c(%rsp)
  mov    %rax,%rbx
  jle    L5
  lea    0x4(%rax),%r14
  mov    $0x1,%r13d
L151:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <scanf@plt>
  add    $0x4,%r14
  cmp    %r13d,0x1c(%rsp)
  jg     L151
L5:
  mov    0x8(%rsp),%rsi
  mov    %r15,%rdx
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x24(%rsp),%eax
  add    $0x1,%eax
  lea    0x0(,%rax,4),%edi
  mov    %eax,0x24(%rsp)
  call   <malloc@plt>
  mov    0x24(%rsp),%esi
  xor    %edx,%edx
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <fillArray@plt>
  cmpl   $0x1,0x24(%rsp)
  jle    L157
  lea    0x4(%r13),%r9
  xor    %r10d,%r10d
  mov    $0x1,%ecx
  nopl   0x0(%rax)
L22:
  mov    0x1c(%rsp),%eax
  cmp    $0x1,%eax
  jle    L61
  sub    $0x2,%eax
  lea    0x4(%rbx),%rdx
  lea    0x8(%rbx,%rax,4),%r8
  jmp    L126
  nop
L85:
  mov    %ecx,%esi
  sub    %eax,%esi
  js     L156
  movslq %esi,%rsi
  mov    0x0(%r13,%rsi,4),%esi
  test   %esi,%esi
  je     L147
L156:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  je     L61
L126:
  mov    (%rdx),%eax
  cmp    %ecx,%eax
  jne    L85
L147:
  movl   $0x1,(%r9)
  cmp    %ecx,0x20(%rsp)
  jle    L165
L83:
  add    $0x1,%ecx
  add    $0x4,%r9
  cmp    %ecx,0x24(%rsp)
  jg     L22
  mov    %r10d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L3
  nop
L61:
  cmp    %ecx,0x20(%rsp)
  jg     L83
  mov    (%r9),%eax
  test   %eax,%eax
  je     L83
  nopl   (%rax)
L165:
  add    $0x1,%r10d
  jmp    L83
L155:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L67
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L157:
  xor    %r10d,%r10d
  lea    D8(%rip),%rdi
  mov    %r10d,%esi
  call   <printf@plt>
  jmp    L3
L67:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D38
type_infered: string
name: read_data
arguments: label: D14
type_infered: string
name: read_data
arguments: label: D8
type_infered: string

tool: D38: %d

tool: D14: %d %d

tool: D8: %d


assistant: ```c
int main() {
  int n, i, j, a, b, sum;
  int *tahy, *kola;
  while (scanf("%d", &n) >= 1) {
    n++;
    tahy = (int *)(malloc(n * sizeof(int)));
    for (i = 1; i < n; i++)
      scanf("%d", &tahy[i]);
    scanf("%d %d", &a, &b);
    b++;
    kola = (int *)(malloc(b * sizeof(int)));
    fillArray(kola, b, 0);
    sum = 0;
    for (i = 1; i < b; i += 1) {
      for (j = 1; j < n; j++) {
        if (i - tahy[j] == 0 || (i - tahy[j] >= 0 && !kola[i - tahy[j]])) {
          kola[i] = 1;
          break;
        }
      }
      if (i >= a && kola[i])
        sum++;
    }
    printf("%d\n", sum);
  }
  return 0;
}
```