ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x20(%rbp),%xmm1
  movsd  -0x18(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D4
type_infered: string

tool: D12: %lf %lf %lf

tool: D4: %.2f %.2f %.2f

assistant: ```c
int main() {
  double a, b, c;
  scanf("%lf %lf %lf", &a, &b, &c);
  printf("%.2f %.2f %.2f", c, b, a);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movsd  (%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  movsd  0x10(%rsp),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string
name: retrieve_data
arguments: data_tag: D0
type_guessed: string

tool: D1: %lf %lf %lf

tool: D0: %.2f %.2f %.2f

assistant: ```c
int main() {
  double a, b, c;
  scanf("%lf %lf %lf", &a, &b, &c);
  printf("%.2f %.2f %.2f", c, b, a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  lea    D5(%rip),%rdi
  movsd  0x10(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D5
type_guessed: string

tool: D7: %lf %lf %lf

tool: D5: %.2f %.2f %.2f

assistant: ```c
int main() {
  double a, b, c;
  scanf("%lf %lf %lf", &a, &b, &c);
  printf("%.2f %.2f %.2f", c, b, a);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  movsd  (%rsp),%xmm2
  movsd  0x8(%rsp),%xmm1
  lea    D16(%rip),%rdi
  movsd  0x10(%rsp),%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string

tool: D17: %lf %lf %lf

tool: D16: %.2f %.2f %.2f

assistant: ```c
int main() {
  double a, b, c;
  scanf("%lf %lf %lf", &a, &b, &c);
  printf("%.2f %.2f %.2f", c, b, a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeAsNucleotides>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %ecx,-0x38(%rbp)
  movq   $0x3,-0x18(%rbp)
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  jmp    L13
L85:
  mov    -0x20(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  cltd
  shr    $0x1a,%edx
  add    %edx,%eax
  and    $0x3f,%eax
  sub    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    $0x3e,%eax
  sub    -0x1c(%rbp),%eax
  mov    -0x10(%rbp),%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L72
  mov    -0x28(%rbp),%rax
  lea    D41(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L30
L72:
  cmpq   $0x1,-0x8(%rbp)
  jne    L53
  mov    -0x28(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L30
L53:
  cmpq   $0x2,-0x8(%rbp)
  jne    L18
  mov    -0x28(%rbp),%rax
  lea    D8(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L30
L18:
  cmpq   $0x3,-0x8(%rbp)
  jne    L12
  mov    -0x28(%rbp),%rax
  lea    D32(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  jmp    L30
L12:
  mov    -0x28(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
L30:
  addl   $0x1,-0x20(%rbp)
L13:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x38(%rbp)
  ja     L85
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D41
data_type: string
name: retrieve_data
arguments: data_label: D15
data_type: string
name: retrieve_data
arguments: data_label: D8
data_type: string
name: retrieve_data
arguments: data_label: D32
data_type: string
name: retrieve_data
arguments: data_label: D1
data_type: string

tool: D41: A

tool: D15: G

tool: D8: C

tool: D32: T

tool: D1: E

assistant: ```c
void writeAsNucleotides(FILE *file, unsigned long long int *sequence, unsigned int startNucleotidePosition, unsigned int endNucleotidePosition) {
  const unsigned long long int MASK = 0x3;
  for (int i = startNucleotidePosition; i < endNucleotidePosition; i++) {
    unsigned long long int currentSequence = sequence[i / 32];
    unsigned int position = (i * 2) % 64;
    unsigned long long int nucleotide = (currentSequence >> (62 - position)) & MASK;
    if (nucleotide == 0x0) {
      fprintf(file, "A");
    } else if (nucleotide == 0x1) {
      fprintf(file, "G");
    } else if (nucleotide == 0x2) {
      fprintf(file, "C");
    } else if (nucleotide == 0x3) {
      fprintf(file, "T");
    } else {
      fprintf(file, "E");
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeAsNucleotides>:
  endbr64
  cmp    %ecx,%edx
  jae    L52
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %ecx,%ebp
  mov    %edx,%ebx
  lea    D1(%rip),%r15
  lea    D32(%rip),%r14
  jmp    L60
L51:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
L25:
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jae    L79
L60:
  lea    0x1f(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rbx,%rbx,1),%ecx
  mov    %ecx,%edx
  sar    $0x1f,%edx
  shr    $0x1a,%edx
  add    %edx,%ecx
  and    $0x3f,%ecx
  sub    %ecx,%edx
  lea    0x3e(%rdx),%ecx
  mov    (%r12,%rax,8),%rax
  shr    %cl,%rax
  and    $0x3,%eax
  je     L51
  cmp    $0x1,%rax
  je     L82
  cmp    $0x2,%rax
  je     L16
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
  jmp    L25
L82:
  lea    D36(%rip),%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
  jmp    L25
L16:
  lea    D0(%rip),%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
  jmp    L25
L79:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  ret
```

tool_calls: name: unpack_data
arguments: label: D1
type_infered: string
name: unpack_data
arguments: label: D32
type_infered: string
name: unpack_data
arguments: label: D36
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string

tool: D1: T

tool: D32: A

tool: D36: G

tool: D0: C

assistant: ```c
void writeAsNucleotides(FILE *file, unsigned long long int *sequence, unsigned int startNucleotidePosition, unsigned int endNucleotidePosition) {
  const unsigned long long int MASK = 0x3;
  for (int i = startNucleotidePosition; i < endNucleotidePosition; i++) {
    unsigned long long int currentSequence = sequence[i / 32];
    unsigned int position = (i * 2) % 64;
    unsigned long long int nucleotide = (currentSequence >> (62 - position)) & MASK;
    if (nucleotide == 0x0) {
      fprintf(file, "A");
    } else if (nucleotide == 0x1) {
      fprintf(file, "G");
    } else if (nucleotide == 0x2) {
      fprintf(file, "C");
    } else if (nucleotide == 0x3) {
      fprintf(file, "T");
    } else {
      fprintf(file, "E");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<writeAsNucleotides>:
  endbr64
  cmp    %ecx,%edx
  jae    L31
  push   %r15
  mov    %edx,%r15d
  push   %r14
  lea    D34(%rip),%r14
  push   %r13
  lea    D35(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  jmp    L71
  nopl   (%rax)
L45:
  cmp    $0x1,%rax
  je     L26
  cmp    $0x2,%rax
  je     L29
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
L56:
  add    $0x1,%r15d
  cmp    %r15d,%ebx
  jbe    L64
L71:
  lea    (%r15,%r15,1),%esi
  test   %r15d,%r15d
  lea    0x1f(%r15),%eax
  mov    %esi,%ecx
  cmovns %r15d,%eax
  sar    $0x1f,%ecx
  shr    $0x1a,%ecx
  sar    $0x5,%eax
  add    %ecx,%esi
  cltq
  and    $0x3f,%esi
  mov    0x0(%rbp,%rax,8),%rax
  sub    %esi,%ecx
  add    $0x3e,%ecx
  shr    %cl,%rax
  and    $0x3,%eax
  jne    L45
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <fprintf@plt>
  cmp    %r15d,%ebx
  ja     L71
L64:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  lea    D24(%rip),%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  jmp    L56
  nopl   0x0(%rax)
L26:
  lea    D28(%rip),%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  jmp    L56
  nopl   0x0(%rax)
L31:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D34
type: string
name: read_data
arguments: data_tag: D35
type: string
name: read_data
arguments: data_tag: D24
type: string
name: read_data
arguments: data_tag: D28
type: string

tool: D34: A

tool: D35: T

tool: D24: C

tool: D28: G

assistant: ```c
void writeAsNucleotides(FILE *file, unsigned long long int *sequence, unsigned int startNucleotidePosition, unsigned int endNucleotidePosition) {
  const unsigned long long int MASK = 0x3;
  for (int i = startNucleotidePosition; i < endNucleotidePosition; i++) {
    unsigned long long int currentSequence = sequence[i / 32];
    unsigned int position = (i * 2) % 64;
    unsigned long long int nucleotide = (currentSequence >> (62 - position)) & MASK;
    if (nucleotide == 0x0) {
      fprintf(file, "A");
    } else if (nucleotide == 0x1) {
      fprintf(file, "G");
    } else if (nucleotide == 0x2) {
      fprintf(file, "C");
    } else if (nucleotide == 0x3) {
      fprintf(file, "T");
    } else {
      fprintf(file, "E");
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writeAsNucleotides>:
  endbr64
  cmp    %ecx,%edx
  jae    L19
  push   %r15
  mov    %edx,%r15d
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    D30(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x8,%rsp
  jmp    L83
  nopl   (%rax)
L55:
  cmp    $0x1,%rax
  je     L64
  cmp    $0x2,%rax
  je     L32
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
L15:
  add    $0x1,%r15d
  cmp    %r15d,%ebx
  jbe    L9
L83:
  lea    (%r15,%r15,1),%esi
  test   %r15d,%r15d
  lea    0x1f(%r15),%eax
  mov    %esi,%ecx
  cmovns %r15d,%eax
  sar    $0x1f,%ecx
  shr    $0x1a,%ecx
  sar    $0x5,%eax
  add    %ecx,%esi
  cltq
  and    $0x3f,%esi
  mov    0x0(%rbp,%rax,8),%rax
  sub    %esi,%ecx
  add    $0x3e,%ecx
  shr    %cl,%rax
  and    $0x3,%eax
  jne    L55
  mov    %r14,%rsi
  mov    %r12,%rdi
  add    $0x1,%r15d
  call   <fprintf@plt>
  cmp    %r15d,%ebx
  ja     L83
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  lea    D24(%rip),%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  jmp    L15
  nopl   0x0(%rax)
L64:
  lea    D26(%rip),%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  jmp    L15
  nopl   0x0(%rax)
L19:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string
name: extract_symbolic_data
arguments: data_label: D30
type_infered: string
name: extract_symbolic_data
arguments: data_label: D24
type_infered: string
name: extract_symbolic_data
arguments: data_label: D26
type_infered: string

tool: D8: A

tool: D30: T

tool: D24: C

tool: D26: G

assistant: ```c
void writeAsNucleotides(FILE *file, unsigned long long int *sequence, unsigned int startNucleotidePosition, unsigned int endNucleotidePosition) {
  const unsigned long long int MASK = 0x3;
  for (int i = startNucleotidePosition; i < endNucleotidePosition; i++) {
    unsigned long long int currentSequence = sequence[i / 32];
    unsigned int position = (i * 2) % 64;
    unsigned long long int nucleotide = (currentSequence >> (62 - position)) & MASK;
    if (nucleotide == 0x0) {
      fprintf(file, "A");
    } else if (nucleotide == 0x1) {
      fprintf(file, "G");
    } else if (nucleotide == 0x2) {
      fprintf(file, "C");
    } else if (nucleotide == 0x3) {
      fprintf(file, "T");
    } else {
      fprintf(file, "E");
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pack8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L9:
  mov    -0x10(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzwl (%rax),%eax
  shr    $0x2,%ax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzwl %cx,%edx
  mov    %edx,(%rax)
L0:
  mov    -0x28(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L9
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t *pack8(uint8_t *outbuf, unsigned short int *inbuf, size_t count) {
  unsigned short int *inp = inbuf;
  uint8_t *outp = outbuf;
  while (inp < (inbuf + count)) {
    *outp++ = *inp++ >> 2;
  }
  return outp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pack8>:
  endbr64
  add    %rdx,%rdx
  lea    (%rsi,%rdx,1),%r9
  cmp    %r9,%rsi
  jae    L13
  mov    %rdi,%r8
L2:
  add    $0x2,%rsi
  add    $0x4,%r8
  movzwl -0x2(%rsi),%ecx
  shr    $0x2,%cx
  movzwl %cx,%ecx
  mov    %ecx,-0x4(%r8)
  cmp    %r9,%rsi
  jb     L2
  lea    (%rdi,%rdx,2),%rax
  ret
L13:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint8_t *pack8(uint8_t *outbuf, unsigned short int *inbuf, size_t count) {
  unsigned short int *inp = inbuf;
  uint8_t *outp = outbuf;
  while (inp < (inbuf + count)) {
    *outp++ = *inp++ >> 2;
  }
  return outp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pack8>:
  endbr64
  add    %rdx,%rdx
  lea    (%rsi,%rdx,1),%r9
  cmp    %r9,%rsi
  jae    L10
  mov    %rdi,%r8
  nopl   0x0(%rax,%rax,1)
L1:
  movzwl (%rsi),%ecx
  add    $0x2,%rsi
  add    $0x4,%r8
  shr    $0x2,%cx
  movzwl %cx,%ecx
  mov    %ecx,-0x4(%r8)
  cmp    %r9,%rsi
  jb     L1
  lea    (%rdi,%rdx,2),%rax
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rdi,%rax
  ret
```

assistant: ```c
uint8_t *pack8(uint8_t *outbuf, unsigned short int *inbuf, size_t count) {
  unsigned short int *inp = inbuf;
  uint8_t *outp = outbuf;
  while (inp < (inbuf + count)) {
    *outp++ = *inp++ >> 2;
  }
  return outp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pack8>:
  endbr64
  add    %rdx,%rdx
  mov    %rdi,%rax
  mov    %rsi,%rcx
  lea    (%rsi,%rdx,1),%r8
  cmp    %r8,%rsi
  jae    L82
  sub    $0x1,%rdx
  mov    %rdx,%rdi
  shr    %rdi
  add    $0x1,%rdi
  cmp    $0xd,%rdx
  jbe    L83
  mov    %rdi,%rsi
  xor    %edx,%edx
  pxor   %xmm1,%xmm1
  shr    $0x3,%rsi
  shl    $0x4,%rsi
  nopl   0x0(%rax,%rax,1)
L75:
  movdqu (%rcx,%rdx,1),%xmm0
  psrlw  $0x2,%xmm0
  movdqa %xmm0,%xmm2
  punpckhwd %xmm1,%xmm0
  punpcklwd %xmm1,%xmm2
  movups %xmm0,0x10(%rax,%rdx,2)
  movups %xmm2,(%rax,%rdx,2)
  add    $0x10,%rdx
  cmp    %rsi,%rdx
  jne    L75
  mov    %rdi,%rsi
  and    $0xfffffffffffffff8,%rsi
  lea    (%rcx,%rsi,2),%rcx
  lea    (%rax,%rsi,4),%rdx
  cmp    %rsi,%rdi
  je     L94
L77:
  movzwl (%rcx),%esi
  shr    $0x2,%si
  movzwl %si,%esi
  mov    %esi,(%rdx)
  lea    0x2(%rcx),%rsi
  cmp    %rsi,%r8
  jbe    L94
  movzwl 0x2(%rcx),%esi
  shr    $0x2,%si
  movzwl %si,%esi
  mov    %esi,0x4(%rdx)
  lea    0x4(%rcx),%rsi
  cmp    %rsi,%r8
  jbe    L94
  movzwl 0x4(%rcx),%esi
  shr    $0x2,%si
  movzwl %si,%esi
  mov    %esi,0x8(%rdx)
  lea    0x6(%rcx),%rsi
  cmp    %rsi,%r8
  jbe    L94
  movzwl 0x6(%rcx),%esi
  shr    $0x2,%si
  movzwl %si,%esi
  mov    %esi,0xc(%rdx)
  lea    0x8(%rcx),%rsi
  cmp    %rsi,%r8
  jbe    L94
  movzwl 0x8(%rcx),%esi
  shr    $0x2,%si
  movzwl %si,%esi
  mov    %esi,0x10(%rdx)
  lea    0xa(%rcx),%rsi
  cmp    %rsi,%r8
  jbe    L94
  movzwl 0xa(%rcx),%esi
  shr    $0x2,%si
  movzwl %si,%esi
  mov    %esi,0x14(%rdx)
  lea    0xc(%rcx),%rsi
  cmp    %rsi,%r8
  jbe    L94
  movzwl 0xc(%rcx),%ecx
  shr    $0x2,%cx
  movzwl %cx,%ecx
  mov    %ecx,0x18(%rdx)
L94:
  lea    (%rax,%rdi,4),%rax
  ret
  nopw   0x0(%rax,%rax,1)
L82:
  ret
L83:
  mov    %rax,%rdx
  jmp    L77
```

assistant: ```c
uint8_t *pack8(uint8_t *outbuf, unsigned short int *inbuf, size_t count) {
  unsigned short int *inp = inbuf;
  uint8_t *outp = outbuf;
  while (inp < (inbuf + count)) {
    *outp++ = *inp++ >> 2;
  }
  return outp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<compute_CNo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %rdi,-0x208(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1f0(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    $0x3c,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  movb   $0x0,-0x1f5(%rbp)
  movb   $0x3c,-0x1f5(%rbp)
  movl   $0x0,-0x1f4(%rbp)
  jmp    L36
L29:
  mov    -0x1f4(%rbp),%eax
  cltq
  mov    -0x1f0(%rbp,%rax,8),%rax
  cmp    %rax,-0x208(%rbp)
  jae    L9
  mov    -0x1f4(%rbp),%eax
  mov    %al,-0x1f5(%rbp)
  jmp    L0
L9:
  addl   $0x1,-0x1f4(%rbp)
L36:
  cmpl   $0x3c,-0x1f4(%rbp)
  jle    L29
L0:
  movzbl -0x1f5(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string

tool: D9: 

assistant: ```c
unsigned char compute_CNo(unsigned long avg) {
  const unsigned long CNo_table[60] = {1, 249, 280, 314, 352, 395, 443, 497, 557, 625, 702, 787, 883, 991, 1112, 1247, 1399, 1570, 1762, 1976, 2217, 2488, 2792, 3132, 3514, 3943, 4424, 4964, 5569, 6249, 7011, 7867, 8826, 9903, 11112, 12467, 13989, 15695, 17611, 19759, 22170, 24875, 27911, 31316, 35137, 39425, 44235, 49632, 55688, 62483, 70107, 78662, 88260, 99029, 111112, 124670, 139882, 156950, 176101, 197589};
  int i;
  unsigned char CNo = 0;
  CNo = 60;
  for (i = 0; i < 61; i++) {
    if (avg < CNo_table[i]) {
      CNo = i;
      break;
    }
  }
  return CNo;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<compute_CNo>:
  endbr64
  sub    $0x1f8,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    D8(%rip),%rsi
  mov    $0x3c,%ecx
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    $0x0,%edx
  mov    %rsp,%rcx
L0:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %r8,-0x8(%rcx,%rdx,8)
  jbe    L0
  mov    0x1e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x1f8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: 

assistant: ```c
unsigned char compute_CNo(unsigned long avg) {
  const unsigned long CNo_table[60] = {1, 249, 280, 314, 352, 395, 443, 497, 557, 625, 702, 787, 883, 991, 1112, 1247, 1399, 1570, 1762, 1976, 2217, 2488, 2792, 3132, 3514, 3943, 4424, 4964, 5569, 6249, 7011, 7867, 8826, 9903, 11112, 12467, 13989, 15695, 17611, 19759, 22170, 24875, 27911, 31316, 35137, 39425, 44235, 49632, 55688, 62483, 70107, 78662, 88260, 99029, 111112, 124670, 139882, 156950, 176101, 197589};
  int i;
  unsigned char CNo = 0;
  CNo = 60;
  for (i = 0; i < 61; i++) {
    if (avg < CNo_table[i]) {
      CNo = i;
      break;
    }
  }
  return CNo;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_CNo>:
  endbr64
  sub    $0x1f8,%rsp
  mov    %rdi,%r8
  mov    $0x3c,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  lea    D5(%rip),%rsi
  mov    %r9,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  test   %r8,%r8
  je     L6
  mov    $0x1,%edx
L1:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %r8,-0x8(%r9,%rdx,8)
  jbe    L1
L6:
  mov    0x1e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x1f8,%rsp
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: 

assistant: ```c
unsigned char compute_CNo(unsigned long avg) {
  const unsigned long CNo_table[60] = {1, 249, 280, 314, 352, 395, 443, 497, 557, 625, 702, 787, 883, 991, 1112, 1247, 1399, 1570, 1762, 1976, 2217, 2488, 2792, 3132, 3514, 3943, 4424, 4964, 5569, 6249, 7011, 7867, 8826, 9903, 11112, 12467, 13989, 15695, 17611, 19759, 22170, 24875, 27911, 31316, 35137, 39425, 44235, 49632, 55688, 62483, 70107, 78662, 88260, 99029, 111112, 124670, 139882, 156950, 176101, 197589};
  int i;
  unsigned char CNo = 0;
  CNo = 60;
  for (i = 0; i < 61; i++) {
    if (avg < CNo_table[i]) {
      CNo = i;
      break;
    }
  }
  return CNo;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<compute_CNo>:
  endbr64
  sub    $0x1f8,%rsp
  mov    %rdi,%r8
  mov    $0x3c,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x1e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r9
  lea    D5(%rip),%rsi
  mov    %r9,%rdi
  rep movsq %ds:(%rsi),%es:(%rdi)
  test   %r8,%r8
  je     L24
  mov    $0x1,%edx
L16:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmp    %r8,-0x8(%r9,%rdx,8)
  jbe    L16
L24:
  mov    0x1e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x1f8,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
datatype: string

tool: D5: 

assistant: ```c
unsigned char compute_CNo(unsigned long avg) {
  const unsigned long CNo_table[60] = {1, 249, 280, 314, 352, 395, 443, 497, 557, 625, 702, 787, 883, 991, 1112, 1247, 1399, 1570, 1762, 1976, 2217, 2488, 2792, 3132, 3514, 3943, 4424, 4964, 5569, 6249, 7011, 7867, 8826, 9903, 11112, 12467, 13989, 15695, 17611, 19759, 22170, 24875, 27911, 31316, 35137, 39425, 44235, 49632, 55688, 62483, 70107, 78662, 88260, 99029, 111112, 124670, 139882, 156950, 176101, 197589};
  int i;
  unsigned char CNo = 0;
  CNo = 60;
  for (i = 0; i < 61; i++) {
    if (avg < CNo_table[i]) {
      CNo = i;
      break;
    }
  }
  return CNo;
}
```