ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_map>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L21
  mov    %edx,%r12d
  mov    %rdi,%rbp
  lea    D9(%rip),%r13
  xor    %ebx,%ebx
  mov    %r12,%r15
  nopl   0x0(%rax)
L26:
  xor    %r14d,%r14d
  test   %r15d,%r15d
  je     L0
  nopl   0x0(%rax,%rax,1)
L9:
  movsbl 0x0(%rbp,%r14,1),%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%r12
  jne    L9
L0:
  mov    $0xa,%edi
  add    $0x1,%ebx
  add    %r12,%rbp
  call   <putchar@plt>
  cmp    0xc(%rsp),%ebx
  jne    L26
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: [%d - %d : %c]

assistant: ```c
void print_map(char *mbuffer, unsigned int cinema_raws, unsigned int cinema_clmn) {
  int i, j;
  char(*matrix)[cinema_clmn] = (char(*)[cinema_clmn])mbuffer;
  for (i = 0; i < cinema_raws; i++) {
    for (j = 0; j < cinema_clmn; j++) {
      printf("[%d - %d : %c]", i, j, matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_map>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  test   %esi,%esi
  je     L2
  mov    %edx,%r12d
  mov    %rdi,%rbp
  lea    D3(%rip),%r13
  xor    %ebx,%ebx
  mov    %r12,%r15
  nopl   0x0(%rax)
L36:
  xor    %r14d,%r14d
  test   %r15d,%r15d
  je     L25
  nopl   0x0(%rax,%rax,1)
L15:
  movsbl 0x0(%rbp,%r14,1),%ecx
  mov    %r14d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  cmp    %r14,%r12
  jne    L15
L25:
  mov    $0xa,%edi
  add    $0x1,%ebx
  add    %r12,%rbp
  call   <putchar@plt>
  cmp    %ebx,0xc(%rsp)
  jne    L36
L2:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: label: D3
data_type: string

tool: D3: [%d - %d : %c]

assistant: ```c
void print_map(char *mbuffer, unsigned int cinema_raws, unsigned int cinema_clmn) {
  int i, j;
  char(*matrix)[cinema_clmn] = (char(*)[cinema_clmn])mbuffer;
  for (i = 0; i < cinema_raws; i++) {
    for (j = 0; j < cinema_clmn; j++) {
      printf("[%d - %d : %c]", i, j, matrix[i][j]);
    }
    printf("\n");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    $0x3686696a,%eax
  xor    $0xce5d000b,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  shl    $0x5,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[local1]) + 2);
      *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x3686696a,%eax
  shl    $0x5,%eax
  xor    $0xcba00160,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[local1]) + 2);
      *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  add    $0x3686696a,%eax
  shl    $0x5,%eax
  xor    $0xcba00160,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ 3462201355U;
    local1 = 0UL;
    while (local1 < 0U) {
      copy11 = *((char *)(&state[local1]) + 2);
      *((char *)(&state[local1]) + 2) = *((char *)(&state[local1]) + 3);
      *((char *)(&state[local1]) + 3) = copy11;
      local1++;
    }
    output[0UL] = state[0UL] << 5U;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<operacao>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  subl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int operacao(int k) {
  k--;
  return k * k;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<operacao>:
  endbr64
  lea    -0x1(%rdi),%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int operacao(int k) {
  k--;
  return k * k;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<operacao>:
  endbr64
  lea    -0x1(%rdi),%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int operacao(int k) {
  k--;
  return k * k;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<operacao>:
  endbr64
  lea    -0x1(%rdi),%eax
  imul   %eax,%eax
  ret
```

assistant: ```c
int operacao(int k) {
  k--;
  return k * k;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wfile_find_in_path>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    %rsi,%r15
  mov    %rdx,%r12
  movsbl (%rsi),%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  jne    L16
  mov    $0x0,%ebx
  lea    D3(%rip),%r13
  cmpb   $0x3a,0x1(%r15)
  jne    L106
L16:
  mov    %r15,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  sete   %al
  movzbl %al,%eax
  neg    %eax
L126:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L136:
  add    $0x1,%ebx
  movslq %ebx,%rcx
  lea    (%r12,%rcx,1),%rbp
  movzbl 0x0(%rbp),%eax
  lea    -0x3a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L85
  test   %al,%al
  je     L85
  mov    %esi,%edx
L35:
  lea    0x1(%rdx),%esi
  movslq %edx,%rdi
  mov    %al,0x0(%r13,%rdi,1)
  test   %edx,%edx
  jne    L136
  cmpb   $0x3a,0x1(%r12,%rcx,1)
  jne    L136
  add    $0x1,%ebx
  movb   $0x3a,0x1(%r13)
  mov    $0x2,%esi
  jmp    L136
L119:
  mov    $0x0,%esi
L85:
  movslq %esi,%rsi
  movb   $0x0,0x0(%r13,%rsi,1)
  mov    %r13,%rdi
  call   <clean_line@plt>
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <wfile_fullname@plt>
  mov    %r14,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  je     L139
  cmpb   $0x0,0x0(%rbp)
  je     L27
  add    $0x1,%ebx
L106:
  movslq %ebx,%rcx
  lea    (%r12,%rcx,1),%rbp
  movzbl 0x0(%rbp),%eax
  lea    -0x3a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L119
  test   %al,%al
  je     L119
  mov    $0x0,%edx
  jmp    L35
L139:
  mov    $0xffffffff,%eax
  jmp    L126
L27:
  mov    $0x0,%eax
  jmp    L126
```

assistant: ```c
int wfile_find_in_path(char *dest, char *src, char *path) {
  static char dir[512];
  int i, j;
  if (wfile_eitherslash(src[0]) || src[1] == ':')
    return (wfile_status(src) == 1 ? -1 : 0);
  for (i = 0; 1; i++) {
    for (j = 0; path[i] != '\0' && path[i] != ':' && path[i] != ';'; i++) {
      dir[j++] = path[i];
      if (j == 1 && path[i + 1] == ':') {
        i++;
        dir[j++] = path[i];
        continue;
      }
    }
    dir[j] = '\0';
    clean_line(dir);
    wfile_fullname(dest, dir, src);
    if (wfile_status(dest) == 1)
      return (-1);
    if (path[i] == '\0')
      break;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wfile_find_in_path>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  jne    L16
  xor    %ebx,%ebx
  cmpb   $0x3a,0x1(%r12)
  lea    D0(%rip),%r15
  je     L16
  nopl   0x0(%rax)
L37:
  movslq %ebx,%rcx
  lea    (%r14,%rcx,1),%r13
  movzbl 0x0(%r13),%eax
  lea    -0x3a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L26
  test   %al,%al
  je     L26
  xor    %edx,%edx
  jmp    L93
  nopl   0x0(%rax)
L46:
  add    $0x1,%ebx
  movslq %ebx,%rcx
  lea    (%r14,%rcx,1),%r13
  movzbl 0x0(%r13),%eax
  lea    -0x3a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L44
  test   %al,%al
  je     L44
  mov    %esi,%edx
L93:
  movslq %edx,%rdi
  lea    0x1(%rdx),%esi
  mov    %al,(%r15,%rdi,1)
  test   %edx,%edx
  jne    L46
  cmpb   $0x3a,0x1(%r14,%rcx,1)
  jne    L46
  movb   $0x3a,D13(%rip)
  add    $0x1,%ebx
  mov    $0x2,%esi
  jmp    L46
  nopl   0x0(%rax)
L26:
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L44:
  movslq %esi,%rsi
  mov    %r15,%rdi
  movb   $0x0,(%r15,%rsi,1)
  call   <clean_line@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <wfile_fullname@plt>
  mov    %rbp,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  je     L120
  cmpb   $0x0,0x0(%r13)
  je     L86
  add    $0x1,%ebx
  jmp    L37
L16:
  mov    %r12,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L120:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L86:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int wfile_find_in_path(char *dest, char *src, char *path) {
  static char dir[512];
  int i, j;
  if (wfile_eitherslash(src[0]) || src[1] == ':')
    return (wfile_status(src) == 1 ? -1 : 0);
  for (i = 0; 1; i++) {
    for (j = 0; path[i] != '\0' && path[i] != ':' && path[i] != ';'; i++) {
      dir[j++] = path[i];
      if (j == 1 && path[i + 1] == ':') {
        i++;
        dir[j++] = path[i];
        continue;
      }
    }
    dir[j] = '\0';
    clean_line(dir);
    wfile_fullname(dest, dir, src);
    if (wfile_status(dest) == 1)
      return (-1);
    if (path[i] == '\0')
      break;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wfile_find_in_path>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rsi),%edi
  call   <wfile_eitherslash@plt>
  test   %rax,%rax
  jne    L1
  xor    %ebx,%ebx
  cmpb   $0x3a,0x1(%r12)
  lea    D4(%rip),%r15
  je     L1
  nopl   0x0(%rax)
L46:
  movslq %ebx,%rcx
  lea    (%r14,%rcx,1),%r13
  movzbl 0x0(%r13),%eax
  lea    -0x3a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L43
  test   %al,%al
  je     L43
  xor    %edx,%edx
  jmp    L48
  nopl   0x0(%rax)
L112:
  add    $0x1,%ebx
  movslq %ebx,%rcx
  lea    (%r14,%rcx,1),%r13
  movzbl 0x0(%r13),%eax
  lea    -0x3a(%rax),%edx
  cmp    $0x1,%dl
  jbe    L85
  test   %al,%al
  je     L85
  mov    %esi,%edx
L48:
  movslq %edx,%rdi
  lea    0x1(%rdx),%esi
  mov    %al,(%r15,%rdi,1)
  test   %edx,%edx
  jne    L112
  cmpb   $0x3a,0x1(%r14,%rcx,1)
  jne    L112
  movb   $0x3a,D5(%rip)
  add    $0x1,%ebx
  mov    $0x2,%esi
  jmp    L112
  nopl   0x0(%rax)
L43:
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L85:
  movslq %esi,%rsi
  mov    %r15,%rdi
  movb   $0x0,(%r15,%rsi,1)
  call   <clean_line@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  mov    %r15,%rsi
  call   <wfile_fullname@plt>
  mov    %rbp,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  je     L42
  cmpb   $0x0,0x0(%r13)
  je     L123
  add    $0x1,%ebx
  jmp    L46
L1:
  mov    %r12,%rdi
  call   <wfile_status@plt>
  cmp    $0x1,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L123:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int wfile_find_in_path(char *dest, char *src, char *path) {
  static char dir[512];
  int i, j;
  if (wfile_eitherslash(src[0]) || src[1] == ':')
    return (wfile_status(src) == 1 ? -1 : 0);
  for (i = 0; 1; i++) {
    for (j = 0; path[i] != '\0' && path[i] != ':' && path[i] != ';'; i++) {
      dir[j++] = path[i];
      if (j == 1 && path[i + 1] == ':') {
        i++;
        dir[j++] = path[i];
        continue;
      }
    }
    dir[j] = '\0';
    clean_line(dir);
    wfile_fullname(dest, dir, src);
    if (wfile_status(dest) == 1)
      return (-1);
    if (path[i] == '\0')
      break;
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sethomefile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%esi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %esi,%edx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: home/%c/%s/%s

assistant: ```c
char *sethomefile(char *buf, const char *userid, const char *filename) {
  sprintf(buf, "home/%c/%s/%s", toupper(userid[0]), userid, filename);
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sethomefile>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  movsbl (%rsi),%edi
  call   <toupper@plt>
  mov    %eax,%edx
  mov    %r12,%r8
  mov    %rbp,%rcx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string

tool: D6: home/%c/%s/%s

assistant: ```c
char *sethomefile(char *buf, const char *userid, const char *filename) {
  sprintf(buf, "home/%c/%s/%s", toupper(userid[0]), userid, filename);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sethomefile>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  movsbl (%rsi),%edi
  mov    %rdx,%rbx
  call   <toupper@plt>
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdi
  mov    %eax,%edx
  lea    D9(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D9
datatype: string

tool: D9: home/%c/%s/%s

assistant: ```c
char *sethomefile(char *buf, const char *userid, const char *filename) {
  sprintf(buf, "home/%c/%s/%s", toupper(userid[0]), userid, filename);
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sethomefile>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  movsbl (%rsi),%edi
  mov    %rdx,%rbx
  call   <toupper@plt>
  mov    %rbx,%r8
  mov    %r13,%rcx
  mov    %r12,%rdi
  mov    %eax,%edx
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: home/%c/%s/%s

assistant: ```c
char *sethomefile(char *buf, const char *userid, const char *filename) {
  sprintf(buf, "home/%c/%s/%s", toupper(userid[0]), userid, filename);
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<crypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L15
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L15
  mov    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L15
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__md5_crypt@plt>
  jmp    L0
L15:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__des_crypt@plt>
L0:
  leave
  ret
```

assistant: ```c
extern char *crypt(const char *key, const char *salt) {
  if (salt[0] == '$' && salt[1] == '1' && salt[2] == '$')
    return __md5_crypt(key, salt);
  else
    return __des_crypt(key, salt);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<crypt>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x24,(%rsi)
  jne    L38
  cmpb   $0x31,0x1(%rsi)
  jne    L38
  cmpb   $0x24,0x2(%rsi)
  je     L21
L38:
  call   <__des_crypt@plt>
L16:
  add    $0x8,%rsp
  ret
L21:
  call   <__md5_crypt@plt>
  jmp    L16
```

assistant: ```c
extern char *crypt(const char *key, const char *salt) {
  if (salt[0] == '$' && salt[1] == '1' && salt[2] == '$')
    return __md5_crypt(key, salt);
  else
    return __des_crypt(key, salt);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<crypt>:
  endbr64
  cmpb   $0x24,(%rsi)
  jne    L23
  cmpb   $0x31,0x1(%rsi)
  jne    L23
  cmpb   $0x24,0x2(%rsi)
  je     L26
L23:
  jmp    1060 <__des_crypt@plt>
  nopw   0x0(%rax,%rax,1)
L26:
  jmp    1070 <__md5_crypt@plt>
```

assistant: ```c
extern char *crypt(const char *key, const char *salt) {
  if (salt[0] == '$' && salt[1] == '1' && salt[2] == '$')
    return __md5_crypt(key, salt);
  else
    return __des_crypt(key, salt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<crypt>:
  endbr64
  cmpb   $0x24,(%rsi)
  jne    L7
  cmpb   $0x31,0x1(%rsi)
  jne    L7
  cmpb   $0x24,0x2(%rsi)
  je     L28
L7:
  jmp    1060 <__des_crypt@plt>
  nopw   0x0(%rax,%rax,1)
L28:
  jmp    1070 <__md5_crypt@plt>
```

assistant: ```c
extern char *crypt(const char *key, const char *salt) {
  if (salt[0] == '$' && salt[1] == '1' && salt[2] == '$')
    return __md5_crypt(key, salt);
  else
    return __des_crypt(key, salt);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  jmp    L3
L6:
  mov    $0x0,%eax
  call   <calc_parse@plt>
L3:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L6
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  while (!feof(stdin)) {
    calc_parse();
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D3(%rip),%rbx
  jmp    L4
L12:
  mov    $0x0,%eax
  call   <calc_parse@plt>
L4:
  mov    (%rbx),%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L12
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  while (!feof(stdin)) {
    calc_parse();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  mov    D9(%rip),%rbx
  jmp    L19
  xchg   %ax,%ax
L16:
  xor    %eax,%eax
  call   <calc_parse@plt>
L19:
  mov    (%rbx),%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L16
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  while (!feof(stdin)) {
    calc_parse();
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    D2(%rip),%rbx
  jmp    L13
  xchg   %ax,%ax
L12:
  xor    %eax,%eax
  call   <calc_parse@plt>
L13:
  mov    (%rbx),%edi
  call   <feof@plt>
  test   %eax,%eax
  je     L12
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(void) {
  while (!feof(stdin)) {
    calc_parse();
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_sbrk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    D61(%rip),%rax
  mov    (%rax),%rax
  mov    D4(%rip),%rcx
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  sub    %rdx,%rax
  cmp    $0x10000,%rax
  jle    L15
  mov    D4(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    D4(%rip),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,D24(%rip)
  mov    -0x8(%rbp),%rax
  jmp    L1
L15:
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D36(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rax
L1:
  pop    %rbp
  ret
```

assistant: ```c
void *_sbrk(int nbytes) {
  extern int end;
  extern void *stack;
  static void *heap_ptr = (void *)&end;
  if ((stack - (heap_ptr + nbytes)) > 65536) {
    void *base = heap_ptr;
    heap_ptr += nbytes;
    return base;
  } else {
    errno = ENOMEM;
    return (void *)-1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_sbrk>:
  endbr64
  mov    D24(%rip),%rdx
  movslq %edi,%rdi
  add    %rdx,%rdi
  mov    D30(%rip),%rax
  mov    (%rax),%rax
  sub    %rdi,%rax
  cmp    $0x10000,%rax
  jle    L6
  mov    %rdi,D2(%rip)
L8:
  mov    %rdx,%rax
  ret
L6:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffffffffffff,%rdx
  jmp    L8
```

assistant: ```c
void *_sbrk(int nbytes) {
  extern int end;
  extern void *stack;
  static void *heap_ptr = (void *)&end;
  if ((stack - (heap_ptr + nbytes)) > 65536) {
    void *base = heap_ptr;
    heap_ptr += nbytes;
    return base;
  } else {
    errno = ENOMEM;
    return (void *)-1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_sbrk>:
  endbr64
  mov    D18(%rip),%rax
  mov    D16(%rip),%r8
  movslq %edi,%rdi
  mov    (%rax),%rax
  add    %r8,%rdi
  sub    %rdi,%rax
  cmp    $0x10000,%rax
  jle    L0
  mov    %rdi,D21(%rip)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L0:
  mov    D21(%rip),%rax
  mov    $0xffffffffffffffff,%r8
  mov    (%rax),%edx
  mov    D22(%rip),%rax
  mov    %edx,(%rax)
  mov    %r8,%rax
  ret
```

assistant: ```c
void *_sbrk(int nbytes) {
  extern int end;
  extern void *stack;
  static void *heap_ptr = (void *)&end;
  if ((stack - (heap_ptr + nbytes)) > 65536) {
    void *base = heap_ptr;
    heap_ptr += nbytes;
    return base;
  } else {
    errno = ENOMEM;
    return (void *)-1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_sbrk>:
  endbr64
  mov    D32(%rip),%rax
  mov    D27(%rip),%r8
  movslq %edi,%rdi
  mov    (%rax),%rax
  add    %r8,%rdi
  sub    %rdi,%rax
  cmp    $0x10000,%rax
  jle    L3
  mov    %rdi,D14(%rip)
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L3:
  mov    D14(%rip),%rax
  mov    $0xffffffffffffffff,%r8
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    %r8,%rax
  ret
```

assistant: ```c
void *_sbrk(int nbytes) {
  extern int end;
  extern void *stack;
  static void *heap_ptr = (void *)&end;
  if ((stack - (heap_ptr + nbytes)) > 65536) {
    void *base = heap_ptr;
    heap_ptr += nbytes;
    return base;
  } else {
    errno = ENOMEM;
    return (void *)-1;
  }
}
```