ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<my_strupcase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L28
L29:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x60,%al
  jle    L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x7a,%al
  jg     L18
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x20(%rax),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L18:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'a' && str[i] <= 'z')
      str[i] = str[i] - 32;
    i++;
  }
  return (str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_strupcase>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L35
  mov    %rdi,%rcx
  jmp    L22
L28:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L35
L22:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L28
  sub    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L28
L35:
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'a' && str[i] <= 'z')
      str[i] = str[i] - 32;
    i++;
  }
  return (str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<my_strupcase>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L26
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L27:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L1
  sub    $0x20,%edx
  mov    %dl,(%rcx)
L1:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L27
L26:
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'a' && str[i] <= 'z')
      str[i] = str[i] - 32;
    i++;
  }
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<my_strupcase>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L15
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L23:
  lea    -0x61(%rdx),%esi
  cmp    $0x19,%sil
  ja     L14
  sub    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L23
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L23
L15:
  ret
```

assistant: ```c
char *my_strupcase(char *str) {
  int i;
  i = 0;
  while (str[i] != '\0') {
    if (str[i] >= 'a' && str[i] <= 'z')
      str[i] = str[i] - 32;
    i++;
  }
  return (str);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L15:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  subq   $0x1,-0x18(%rbp)
  jmp    L33
L16:
  subl   $0x1,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jns    L33
  subq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L41
L33:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
L41:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, int n) {
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  --s1;
  while ((*s1++ = *s2++))
    if (--n < 0) {
      *--s1 = '\0';
      break;
    }
  return (os1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strncat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
L0:
  mov    %rcx,%r9
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L0
  mov    %r9,%rcx
L4:
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rsi),%r8d
  mov    %r8b,-0x1(%rcx)
  test   %r8b,%r8b
  je     L28
  mov    %edx,%r8d
  sub    %ecx,%r8d
  add    %r9d,%r8d
  jns    L4
  movb   $0x0,-0x1(%rcx)
  ret
L28:
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, int n) {
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  --s1;
  while ((*s1++ = *s2++))
    if (--n < 0) {
      *--s1 = '\0';
      break;
    }
  return (os1);
}
```
user: What is the c source code of the assembly code below:

```asm
<strncat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %rcx,%r8
  lea    0x1(%rcx),%rcx
  cmpb   $0x0,(%r8)
  jne    L31
  mov    %r8,%rcx
  jmp    L20
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %edx,%r9d
  sub    %ecx,%r9d
  add    %r8d,%r9d
  js     L33
L20:
  movzbl (%rsi),%r9d
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r9b,-0x1(%rcx)
  test   %r9b,%r9b
  jne    L37
  ret
  nopl   0x0(%rax)
L33:
  movb   $0x0,-0x1(%rcx)
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, int n) {
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  --s1;
  while ((*s1++ = *s2++))
    if (--n < 0) {
      *--s1 = '\0';
      break;
    }
  return (os1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strncat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %rcx,%r8
  lea    0x1(%rcx),%rcx
  cmpb   $0x0,(%r8)
  jne    L17
  mov    %r8,%rcx
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L31:
  mov    %edx,%r9d
  sub    %ecx,%r9d
  add    %r8d,%r9d
  js     L19
L33:
  movzbl (%rsi),%r9d
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r9b,-0x1(%rcx)
  test   %r9b,%r9b
  jne    L31
  ret
  nopl   0x0(%rax)
L19:
  movb   $0x0,-0x1(%rcx)
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, int n) {
  char *os1;
  os1 = s1;
  while (*s1++)
    ;
  --s1;
  while ((*s1++ = *s2++))
    if (--n < 0) {
      *--s1 = '\0';
      break;
    }
  return (os1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <init_files@plt>
  mov    $0x0,%eax
  call   <init_lex@plt>
  mov    $0x0,%eax
  call   <init_types@plt>
  mov    $0x0,%eax
  call   <init_cnst_ast@plt>
  mov    $0x0,%eax
  call   <init_regs@plt>
  mov    $0x0,%eax
  call   <init_spill_loc@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init() {
  init_files();
  init_lex();
  init_types();
  init_cnst_ast();
  init_regs();
  init_spill_loc();
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_files@plt>
  mov    $0x0,%eax
  call   <init_lex@plt>
  mov    $0x0,%eax
  call   <init_types@plt>
  mov    $0x0,%eax
  call   <init_cnst_ast@plt>
  mov    $0x0,%eax
  call   <init_regs@plt>
  mov    $0x0,%eax
  call   <init_spill_loc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init() {
  init_files();
  init_lex();
  init_types();
  init_cnst_ast();
  init_regs();
  init_spill_loc();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_files@plt>
  xor    %eax,%eax
  call   <init_lex@plt>
  xor    %eax,%eax
  call   <init_types@plt>
  xor    %eax,%eax
  call   <init_cnst_ast@plt>
  xor    %eax,%eax
  call   <init_regs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <init_spill_loc@plt>
```

assistant: ```c
void init() {
  init_files();
  init_lex();
  init_types();
  init_cnst_ast();
  init_regs();
  init_spill_loc();
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_files@plt>
  xor    %eax,%eax
  call   <init_lex@plt>
  xor    %eax,%eax
  call   <init_types@plt>
  xor    %eax,%eax
  call   <init_cnst_ast@plt>
  xor    %eax,%eax
  call   <init_regs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <init_spill_loc@plt>
```

assistant: ```c
void init() {
  init_files();
  init_lex();
  init_types();
  init_cnst_ast();
  init_regs();
  init_spill_loc();
  return;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  or     $0xbab5,%ax
  test   $0x8,%cl
  je     L1
  and    $0x6,%ecx
  or     $0x5,%ecx
  shl    %cl,%eax
L1:
  shl    $0x3,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        } else {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        }
      } else if (state[0UL] & (unsigned short)1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      }
    } else {
      copy16 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy17 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy17;
    }
    output[0UL] = state[0UL] << (unsigned short)3;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%edx
  or     $0xbab5,%dx
  mov    %edx,%eax
  and    $0x8,%edx
  je     L7
  and    $0x6,%ecx
  or     $0x5,%ecx
  shl    %cl,%eax
L7:
  shl    $0x3,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        } else {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        }
      } else if (state[0UL] & (unsigned short)1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      }
    } else {
      copy16 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy17 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy17;
    }
    output[0UL] = state[0UL] << (unsigned short)3;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%ecx
  shr    $0x3,%rcx
  mov    %ecx,%eax
  or     $0xbab5,%ax
  test   $0x8,%cl
  je     L9
  and    $0x6,%ecx
  or     $0x5,%ecx
  shl    %cl,%eax
L9:
  shl    $0x3,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  char copy12;
  char copy13;
  char copy16;
  char copy17;
  {
    state[0UL] = (input[0UL] | 51238316UL) >> (unsigned short)3;
    if ((state[0UL] >> (unsigned short)3) & (unsigned short)1) {
      if ((state[0UL] >> (unsigned short)4) & (unsigned short)1) {
        if (state[0UL] & (unsigned short)1) {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        } else {
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
          state[0UL] <<= (state[0UL] & (unsigned short)7) | 1UL;
        }
      } else if (state[0UL] & (unsigned short)1) {
        copy12 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy12;
        copy13 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy13;
        copy13 = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = copy13;
      }
    } else {
      copy16 = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = copy16;
      copy17 = *((char *)(&state[0UL]) + 0);
      *((char *)(&state[0UL]) + 0) = *((char *)(&state[0UL]) + 1);
      *((char *)(&state[0UL]) + 1) = copy17;
    }
    output[0UL] = state[0UL] << (unsigned short)3;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmap_get_buffer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: >>> bitmap_get_buffer 0x%8.8X


assistant: ```c
unsigned char *bitmap_get_buffer(void *bitmap) {
  printf(">>> bitmap_get_buffer 0x%8.8X\n", bitmap);
  return bitmap;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<bitmap_get_buffer>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type_infered: string

tool: D9: >>> bitmap_get_buffer 0x%8.8X


assistant: ```c
unsigned char *bitmap_get_buffer(void *bitmap) {
  printf(">>> bitmap_get_buffer 0x%8.8X\n", bitmap);
  return bitmap;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bitmap_get_buffer>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
data_type: string

tool: D5: >>> bitmap_get_buffer 0x%8.8X


assistant: ```c
unsigned char *bitmap_get_buffer(void *bitmap) {
  printf(">>> bitmap_get_buffer 0x%8.8X\n", bitmap);
  return bitmap;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<bitmap_get_buffer>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
type_guessed: string

tool: D3: >>> bitmap_get_buffer 0x%8.8X


assistant: ```c
unsigned char *bitmap_get_buffer(void *bitmap) {
  printf(">>> bitmap_get_buffer 0x%8.8X\n", bitmap);
  return bitmap;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<quick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jg     L29
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L23
L6:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L26
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L26:
  addl   $0x1,-0x8(%rbp)
L23:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L6
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick>
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quick>
L29:
  nop
  leave
  ret
```

assistant: ```c
void quick(int a[], int low, int high) {
  if (low <= high) {
    int temp = a[low];
    int p = low;
    for (int i = low; i <= high; i++) {
      if (a[i] < temp) {
        p++;
        swap(a, i, p);
      }
    }
    swap(a, low, p);
    quick(a, low, p - 1);
    quick(a, p + 1, high);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<quick>:
  endbr64
  cmp    %edx,%esi
  jg     L32
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%r12d
  movslq %esi,%rax
  mov    (%rdi,%rax,4),%r15d
  lea    0x1(%rsi),%ebx
  movslq %ebx,%rbx
  mov    %esi,%r13d
  jmp    L17
L49:
  add    $0x1,%rbx
L17:
  mov    %ebx,%esi
  cmp    %ebx,%r12d
  jl     L2
  cmp    %r15d,0x0(%rbp,%rbx,4)
  jge    L49
  add    $0x1,%r13d
  mov    %r13d,%edx
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L49
L2:
  mov    %r13d,%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r13),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <quick>
  lea    0x1(%r13),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <quick>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L32:
  ret
```

assistant: ```c
void quick(int a[], int low, int high) {
  if (low <= high) {
    int temp = a[low];
    int p = low;
    for (int i = low; i <= high; i++) {
      if (a[i] < temp) {
        p++;
        swap(a, i, p);
      }
    }
    swap(a, low, p);
    quick(a, low, p - 1);
    quick(a, p + 1, high);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<quick>:
  endbr64
  cmp    %esi,%edx
  jl     L55
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
L28:
  movslq %r13d,%rax
  lea    0x1(%r13),%ebp
  mov    %r13d,%edx
  mov    (%r12,%rax,4),%r15d
  movslq %ebp,%rbx
  jmp    L31
  cs nopw 0x0(%rax,%rax,1)
L50:
  cmp    %r15d,(%r12,%rbx,4)
  jge    L54
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %ebp,%edx
  add    $0x1,%ebp
L54:
  add    $0x1,%rbx
L31:
  mov    %ebx,%esi
  cmp    %ebx,%r14d
  jge    L50
  mov    %r13d,%esi
  mov    %r12,%rdi
  mov    %edx,0xc(%rsp)
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  sub    $0x1,%edx
  call   <quick>
  cmp    %r14d,%ebp
  jg     L59
  mov    %ebp,%r13d
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L59:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L55:
  ret
```

assistant: ```c
void quick(int a[], int low, int high) {
  if (low <= high) {
    int temp = a[low];
    int p = low;
    for (int i = low; i <= high; i++) {
      if (a[i] < temp) {
        p++;
        swap(a, i, p);
      }
    }
    swap(a, low, p);
    quick(a, low, p - 1);
    quick(a, p + 1, high);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdi
  lea    -0x18(%rbp),%rsi
  lea    -0x1c(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x24(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x24(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  subss  %xmm2,%xmm0
  mulss  %xmm0,%xmm1
  movss  -0x20(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm3
  movaps %xmm0,%xmm2
  subss  %xmm3,%xmm2
  movss  -0x20(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm3
  subss  %xmm3,%xmm0
  mulss  %xmm2,%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrtf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movss  -0x1c(%rbp),%xmm0
  ucomiss -0xc(%rbp),%xmm0
  jp     L40
  ucomiss -0xc(%rbp),%xmm0
  jne    L40
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L40:
  movss  -0x1c(%rbp),%xmm1
  movss  -0xc(%rbp),%xmm0
  comiss %xmm1,%xmm0
  jbe    L22
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L22:
  movss  -0x1c(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  jbe    L9
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
datatype: string
name: parse_data
arguments: tag: D24
datatype: string
name: parse_data
arguments: tag: D11
datatype: string
name: parse_data
arguments: tag: D36
datatype: string

tool: D13: %f %f %f %f %f

tool: D24: Point is on the Circle.

tool: D11: Point is outside the Circle.

tool: D36: Point is inside the Circle.

assistant: ```c
int main() {
  float x, y, r, x1, y1;
  scanf("%f %f %f %f %f", &x, &y, &r, &x1, &y1);
  float m = (x - x1) * (x - x1) + (y - y1) * (y - y1);
  float d = sqrtf(m);
  if (d == r) {
    printf("Point is on the Circle.");
  } else if (d > r) {
    printf("Point is outside the Circle.");
  } else if (d < r) {
    printf("Point is inside the Circle.");
  }
  return 0;
}
```