ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L42
L44:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x4c(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%esi
  sar    $0x1f,%esi
  mov    %eax,%ecx
  sub    %esi,%ecx
  mov    %ecx,%eax
  add    %eax,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,%ecx
  lea    0x1(%rcx),%eax
  mov    %eax,-0x48(%rbp)
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x44(%rbp)
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x50(%rbp)
L42:
  cmpl   $0xe0f,-0x50(%rbp)
  jle    L44
  movl   $0x2,-0x50(%rbp)
  jmp    L6
L24:
  mov    -0x50(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    -0x50(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x50(%rbp)
L6:
  cmpl   $0xc,-0x50(%rbp)
  jle    L24
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
datatype: string

tool: D3: %d:%d


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  int n, touzi1, touzi2, sum, counts[13] = {0};
  for (n = 0; n < 3600; n++) {
    touzi1 = rand() % 6 + 1;
    touzi2 = rand() % 6 + 1;
    sum = touzi1 + touzi2;
    counts[sum]++;
  }
  for (n = 2; n <= 12; n++) {
    printf("%d:%d\n", n, counts[n]);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movl   $0x0,0x30(%rsp)
  mov    $0xe10,%ebx
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  movslq %ebp,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %ebp,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%eax
  sub    %eax,%ebp
  movslq %edx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%eax
  add    %eax,%eax
  sub    %eax,%edx
  lea    0x2(%rbp,%rdx,1),%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L3
  mov    $0x2,%ebx
  lea    D0(%rip),%rbp
L27:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0xd,%rbx
  jne    L27
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %d:%d


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  int n, touzi1, touzi2, sum, counts[13] = {0};
  for (n = 0; n < 3600; n++) {
    touzi1 = rand() % 6 + 1;
    touzi2 = rand() % 6 + 1;
    sum = touzi1 + touzi2;
    counts[sum]++;
  }
  for (n = 2; n <= 12; n++) {
    printf("%d:%d\n", n, counts[n]);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  mov    $0xe10,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,0x30(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopl   0x0(%rax)
L26:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  movslq %ebp,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  mov    %eax,%ecx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  movslq %ecx,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  add    %eax,%eax
  sub    %eax,%ebp
  mov    %ecx,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  lea    0x2(%rbp,%rcx,1),%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L26
  mov    $0x2,%ebx
  mov    %rsp,%r12
  lea    D5(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L13:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xd,%rbx
  jne    L13
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: %d:%d


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  int n, touzi1, touzi2, sum, counts[13] = {0};
  for (n = 0; n < 3600; n++) {
    touzi1 = rand() % 6 + 1;
    touzi2 = rand() % 6 + 1;
    sum = touzi1 + touzi2;
    counts[sum]++;
  }
  for (n = 2; n <= 12; n++) {
    printf("%d:%d\n", n, counts[n]);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  xor    %edi,%edi
  push   %rbp
  push   %rbx
  mov    $0xe10,%ebx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x0,0x30(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  movslq %ebp,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  mov    %eax,%ecx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  movslq %ecx,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  add    %eax,%eax
  sub    %eax,%ebp
  mov    %ecx,%eax
  sar    $0x1f,%eax
  shr    $0x20,%rdx
  sub    %eax,%edx
  lea    (%rdx,%rdx,2),%eax
  add    %eax,%eax
  sub    %eax,%ecx
  lea    0x2(%rbp,%rcx,1),%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  sub    $0x1,%ebx
  jne    L16
  mov    $0x2,%ebx
  mov    %rsp,%r12
  lea    D2(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L14:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0xd,%rbx
  jne    L14
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: %d:%d


assistant: ```c
int main(int argc, char const *argv[]) {
  srand(time(NULL));
  int n, touzi1, touzi2, sum, counts[13] = {0};
  for (n = 0; n < 3600; n++) {
    touzi1 = rand() % 6 + 1;
    touzi2 = rand() % 6 + 1;
    sum = touzi1 + touzi2;
    counts[sum]++;
  }
  for (n = 2; n <= 12; n++) {
    printf("%d:%d\n", n, counts[n]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sleep_until>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L15:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jge    L29
  mov    -0x38(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <select@plt>
  jmp    L15
L29:
  nop
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

assistant: ```c
void sleep_until(time_t stoptime) {
  struct timeval tv;
  while (1) {
    time_t current = time(0);
    if (current >= stoptime)
      break;
    tv.tv_sec = stoptime - current;
    tv.tv_usec = 0;
    select(0, 0, 0, 0, &tv);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sleep_until>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L0
L17:
  mov    %rbx,%rdx
  sub    %rax,%rdx
  mov    %rdx,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    %rbp,%r8
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <select@plt>
L0:
  mov    $0x0,%edi
  call   <time@plt>
  cmp    %rbx,%rax
  jl     L17
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_until(time_t stoptime) {
  struct timeval tv;
  while (1) {
    time_t current = time(0);
    if (current >= stoptime)
      break;
    tv.tv_sec = stoptime - current;
    tv.tv_usec = 0;
    select(0, 0, 0, 0, &tv);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<sleep_until>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L11:
  mov    %rbx,%rdx
  mov    %rbp,%r8
  xor    %ecx,%ecx
  xor    %esi,%esi
  sub    %rax,%rdx
  xor    %edi,%edi
  movq   $0x0,(%rsp)
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  call   <select@plt>
L2:
  xor    %edi,%edi
  call   <time@plt>
  cmp    %rbx,%rax
  jl     L11
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_until(time_t stoptime) {
  struct timeval tv;
  while (1) {
    time_t current = time(0);
    if (current >= stoptime)
      break;
    tv.tv_sec = stoptime - current;
    tv.tv_usec = 0;
    select(0, 0, 0, 0, &tv);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sleep_until>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbx,%rdx
  mov    %rbp,%r8
  xor    %ecx,%ecx
  xor    %esi,%esi
  sub    %rax,%rdx
  xor    %edi,%edi
  movq   $0x0,(%rsp)
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  call   <select@plt>
L11:
  xor    %edi,%edi
  call   <time@plt>
  cmp    %rbx,%rax
  jl     L0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_until(time_t stoptime) {
  struct timeval tv;
  while (1) {
    time_t current = time(0);
    if (current >= stoptime)
      break;
    tv.tv_sec = stoptime - current;
    tv.tv_usec = 0;
    select(0, 0, 0, 0, &tv);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x12c,-0xc(%rbp)
  movl   $0x14,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L13
L16:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fahr2celsius@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  add    %eax,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L16
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahr2celsius(fahr);
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D6(%rip),%rbp
L5:
  mov    %ebx,%edi
  call   <fahr2celsius@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  cmp    $0x140,%ebx
  jne    L5
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D6
type: string

tool: D6: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahr2celsius(fahr);
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  call   <fahr2celsius@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahr2celsius(fahr);
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  call   <fahr2celsius@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  mov    %eax,%edx
  call   <printf@plt>
  cmp    $0x140,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: %d	%d


assistant: ```c
int main() {
  int fahr, celsius;
  int lower, upper, step;
  lower = 0;
  upper = 300;
  step = 20;
  fahr = lower;
  while (fahr <= upper) {
    celsius = fahr2celsius(fahr);
    printf("%d\t%d\n", fahr, celsius);
    fahr = fahr + step;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
int die(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int die(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int die(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<die>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int die(const char *format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  va_end(args);
  exit(1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mem_put_be16_as_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mem_put_be16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 8) & 0xff);
  mem[1] = (unsigned char)((val >> 0) & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_put_be16_as_int>:
  endbr64
  mov    %esi,%eax
  movzbl %ah,%edx
  mov    %dl,(%rdi)
  mov    %sil,0x1(%rdi)
  ret
```

assistant: ```c
void mem_put_be16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 8) & 0xff);
  mem[1] = (unsigned char)((val >> 0) & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mem_put_be16_as_int>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void mem_put_be16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 8) & 0xff);
  mem[1] = (unsigned char)((val >> 0) & 0xff);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mem_put_be16_as_int>:
  endbr64
  rol    $0x8,%si
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void mem_put_be16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 8) & 0xff);
  mem[1] = (unsigned char)((val >> 0) & 0xff);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_XcmsModuloF>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L42
  movsd  -0x18(%rbp),%xmm0
  movq   D7(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  jmp    L66
L42:
  movsd  -0x18(%rbp),%xmm0
L66:
  movapd %xmm0,%xmm2
  movapd %xmm2,%xmm4
  comisd D29(%rip),%xmm2
  jb     L16
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L11
L16:
  movsd  D29(%rip),%xmm0
  movapd %xmm4,%xmm3
  addsd  %xmm3,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D29(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd %xmm3,%xmm0
  jbe    L53
  movsd  -0x8(%rbp),%xmm0
  movsd  D49(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L53:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L59
  movsd  -0x8(%rbp),%xmm0
  movq   D7(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  jmp    L18
L59:
  movsd  -0x8(%rbp),%xmm0
L18:
  movsd  %xmm0,-0x8(%rbp)
L11:
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  movsd  -0x18(%rbp),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: f32[2]
name: read_data
arguments: tag: D29
type: byte[16]
name: read_data
arguments: tag: D49
type: f64

tool: {"D7": [0.0,-0.0]}

tool: {"D29": [0x00,0x00,0xc0,0xff,0xff,0xff,0x3f,0x43,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D49: 1

assistant: ```c
double _XcmsModuloF(val, dp)
double val;
register double *dp;
{
  register double abs;
  double ip;
  abs = ((val) < 0.0 ? -(val) : (val));
  if (abs >= ((double)(0x7FFFFFFF) * (1L << (((8 * (int)sizeof(double)) - 11) - (8 * (int)sizeof(int)) + 1)))) {
    ip = val;
  } else {
    ip = abs + ((double)(0x7FFFFFFF) * (1L << (((8 * (int)sizeof(double)) - 11) - (8 * (int)sizeof(int)) + 1)));
    ip -= ((double)(0x7FFFFFFF) * (1L << (((8 * (int)sizeof(double)) - 11) - (8 * (int)sizeof(int)) + 1)));
    if (ip > abs)
      ip -= 1.0;
    ip = ((ip) < 0.0 ? -(ip) : (ip));
  }
  *dp = ip;
  return (val - ip);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_XcmsModuloF>:
  endbr64
  pxor   %xmm3,%xmm3
  movapd %xmm0,%xmm1
  xorpd  D32(%rip),%xmm1
  movapd %xmm0,%xmm2
  cmpltsd %xmm3,%xmm2
  andpd  %xmm2,%xmm1
  andnpd %xmm0,%xmm2
  orpd   %xmm2,%xmm1
  movapd %xmm0,%xmm2
  comisd D18(%rip),%xmm1
  jae    L19
  movsd  D18(%rip),%xmm3
  movapd %xmm1,%xmm2
  addsd  %xmm3,%xmm2
  subsd  %xmm3,%xmm2
  comisd %xmm1,%xmm2
  jbe    L5
  subsd  D38(%rip),%xmm2
L5:
  pxor   %xmm1,%xmm1
  comisd %xmm2,%xmm1
  ja     L33
L19:
  movsd  %xmm2,(%rdi)
  subsd  %xmm2,%xmm0
  ret
L33:
  xorpd  D32(%rip),%xmm2
  jmp    L19
```

tool_calls: name: parse_data
arguments: tag: D32
type_infered: f32[4]
name: parse_data
arguments: tag: D18
type_infered: byte[16]
name: parse_data
arguments: tag: D38
type_infered: f64

tool: {"D32": [0.0,-0.0,0.0,0.0]}

tool: {"D18": [0x00,0x00,0xc0,0xff,0xff,0xff,0x3f,0x43,0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D38: 1

assistant: ```c
double _XcmsModuloF(val, dp)
double val;
register double *dp;
{
  register double abs;
  double ip;
  abs = ((val) < 0.0 ? -(val) : (val));
  if (abs >= ((double)(0x7FFFFFFF) * (1L << (((8 * (int)sizeof(double)) - 11) - (8 * (int)sizeof(int)) + 1)))) {
    ip = val;
  } else {
    ip = abs + ((double)(0x7FFFFFFF) * (1L << (((8 * (int)sizeof(double)) - 11) - (8 * (int)sizeof(int)) + 1)));
    ip -= ((double)(0x7FFFFFFF) * (1L << (((8 * (int)sizeof(double)) - 11) - (8 * (int)sizeof(int)) + 1)));
    if (ip > abs)
      ip -= 1.0;
    ip = ((ip) < 0.0 ? -(ip) : (ip));
  }
  *dp = ip;
  return (val - ip);
}
```