ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<CountSortedInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L1
L3:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L29
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
L29:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L3
  addl   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int CountSortedInt(int M, int *sorted, int *sort_idx, int *uni_list, int *uni_i, int *uni_j, int *cnt) {
  int u, m;
  uni_list[0] = sorted[0];
  uni_i[0] = sort_idx[0];
  cnt[0]++;
  uni_j[sort_idx[0]] = 0;
  u = 0;
  for (m = 1; m < M; m++) {
    if (sorted[m] != sorted[m - 1]) {
      u++;
      uni_list[u] = sorted[m];
      uni_i[u] = sort_idx[m];
    }
    cnt[u]++;
    uni_j[sort_idx[m]] = u;
  }
  u++;
  return u;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<CountSortedInt>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    0x18(%rsp),%rdi
  mov    (%rsi),%eax
  mov    %eax,(%rcx)
  mov    (%rdx),%eax
  mov    %eax,(%r8)
  addl   $0x1,(%rdi)
  movslq (%rdx),%rax
  movl   $0x0,(%r9,%rax,4)
  cmp    $0x1,%ebx
  jle    L40
  mov    %rdx,%r10
  mov    %rcx,%rbp
  mov    %ebx,%ebx
  mov    $0x1,%edx
  mov    $0x0,%eax
  jmp    L33
L45:
  movslq %eax,%rcx
  addl   $0x1,(%rdi,%rcx,4)
  movslq (%r10,%rdx,4),%rcx
  mov    %eax,(%r9,%rcx,4)
  add    $0x1,%rdx
  cmp    %rbx,%rdx
  je     L38
L33:
  mov    (%rsi,%rdx,4),%ecx
  cmp    -0x4(%rsi,%rdx,4),%ecx
  je     L45
  add    $0x1,%eax
  movslq %eax,%r11
  mov    %ecx,0x0(%rbp,%r11,4)
  mov    (%r10,%rdx,4),%ecx
  mov    %ecx,(%r8,%r11,4)
  jmp    L45
L40:
  mov    $0x0,%eax
L38:
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int CountSortedInt(int M, int *sorted, int *sort_idx, int *uni_list, int *uni_i, int *uni_j, int *cnt) {
  int u, m;
  uni_list[0] = sorted[0];
  uni_i[0] = sort_idx[0];
  cnt[0]++;
  uni_j[sort_idx[0]] = 0;
  u = 0;
  for (m = 1; m < M; m++) {
    if (sorted[m] != sorted[m - 1]) {
      u++;
      uni_list[u] = sorted[m];
      uni_i[u] = sort_idx[m];
    }
    cnt[u]++;
    uni_j[sort_idx[m]] = u;
  }
  u++;
  return u;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CountSortedInt>:
  endbr64
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  mov    (%rsi),%eax
  mov    0x20(%rsp),%r11
  mov    %eax,(%rcx)
  mov    (%rdx),%eax
  mov    %eax,(%r8)
  addl   $0x1,(%r11)
  movslq (%rdx),%rax
  movl   $0x0,(%r9,%rax,4)
  cmp    $0x1,%ebp
  jle    L25
  mov    %rdx,%rbx
  mov    %rsi,%r10
  mov    %rcx,%r12
  mov    $0x1,%edx
  xor    %eax,%eax
  nopl   (%rax)
L7:
  movslq %eax,%rcx
  mov    (%r10,%rdx,4),%esi
  shl    $0x2,%rcx
  cmp    -0x4(%r10,%rdx,4),%esi
  je     L26
  add    $0x1,%eax
  movslq %eax,%rdi
  mov    %esi,(%r12,%rdi,4)
  mov    (%rbx,%rdx,4),%esi
  lea    0x0(,%rdi,4),%rcx
  mov    %esi,(%r8,%rdi,4)
L26:
  addl   $0x1,(%r11,%rcx,1)
  movslq (%rbx,%rdx,4),%rcx
  add    $0x1,%rdx
  mov    %eax,(%r9,%rcx,4)
  cmp    %rdx,%rbp
  jne    L7
  pop    %rbx
  add    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L25:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int CountSortedInt(int M, int *sorted, int *sort_idx, int *uni_list, int *uni_i, int *uni_j, int *cnt) {
  int u, m;
  uni_list[0] = sorted[0];
  uni_i[0] = sort_idx[0];
  cnt[0]++;
  uni_j[sort_idx[0]] = 0;
  u = 0;
  for (m = 1; m < M; m++) {
    if (sorted[m] != sorted[m - 1]) {
      u++;
      uni_list[u] = sorted[m];
      uni_i[u] = sort_idx[m];
    }
    cnt[u]++;
    uni_j[sort_idx[m]] = u;
  }
  u++;
  return u;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CountSortedInt>:
  endbr64
  push   %rbp
  push   %rbx
  mov    (%rsi),%eax
  movslq %edi,%rbx
  mov    0x18(%rsp),%r10
  mov    %eax,(%rcx)
  mov    (%rdx),%eax
  mov    %eax,(%r8)
  addl   $0x1,(%r10)
  movslq (%rdx),%rax
  movl   $0x0,(%r9,%rax,4)
  cmp    $0x1,%ebx
  jle    L48
  mov    %rdx,%r11
  mov    %rsi,%rdi
  mov    %rcx,%rbp
  mov    $0x1,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L22:
  mov    (%rdi,%rdx,4),%esi
  cmp    -0x4(%rdi,%rdx,4),%esi
  je     L13
  add    $0x1,%eax
  movslq %eax,%rcx
  mov    %esi,0x0(%rbp,%rcx,4)
  mov    (%r11,%rdx,4),%esi
  mov    %esi,(%r8,%rcx,4)
  addl   $0x1,(%r10,%rcx,4)
  movslq (%r11,%rdx,4),%rcx
  add    $0x1,%rdx
  mov    %eax,(%r9,%rcx,4)
  cmp    %rdx,%rbx
  jne    L22
L12:
  add    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  movslq %eax,%rcx
  addl   $0x1,(%r10,%rcx,4)
  movslq (%r11,%rdx,4),%rcx
  add    $0x1,%rdx
  mov    %eax,(%r9,%rcx,4)
  cmp    %rbx,%rdx
  jne    L22
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int CountSortedInt(int M, int *sorted, int *sort_idx, int *uni_list, int *uni_i, int *uni_j, int *cnt) {
  int u, m;
  uni_list[0] = sorted[0];
  uni_i[0] = sort_idx[0];
  cnt[0]++;
  uni_j[sort_idx[0]] = 0;
  u = 0;
  for (m = 1; m < M; m++) {
    if (sorted[m] != sorted[m - 1]) {
      u++;
      uni_list[u] = sorted[m];
      uni_i[u] = sort_idx[m];
    }
    cnt[u]++;
    uni_j[sort_idx[m]] = u;
  }
  u++;
  return u;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strncasecmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L48
  mov    $0x0,%eax
  jmp    L26
L18:
  cmpq   $0x0,-0x28(%rbp)
  je     L42
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L42
  addq   $0x1,-0x18(%rbp)
  addq   $0x1,-0x20(%rbp)
L48:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  je     L42
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  cmp    %eax,%ebx
  je     L18
L42:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L26:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  if (n == 0) {
    return 0;
  }
  while (n-- != 0 && tolower(*s1) == tolower(*s2)) {
    if (n == 0 || *s1 == '\0' || *s2 == '\0') {
      break;
    }
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: What is the c source code of the assembly code below:

```asm
<strncasecmp>:
  endbr64
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L2
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rdi,%rdx,1),%r13
  jmp    L24
L30:
  add    $0x1,%rbx
  add    $0x1,%rbp
L24:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%r12d
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  cmp    %r13,%rbx
  je     L29
  cmp    %eax,%r12d
  jne    L29
  cmpb   $0x0,(%rbx)
  je     L29
  cmpb   $0x0,0x0(%rbp)
  jne    L30
L29:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %eax,%ebx
  movsbl 0x0(%rbp),%edi
  call   <tolower@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  if (n == 0) {
    return 0;
  }
  while (n-- != 0 && tolower(*s1) == tolower(*s2)) {
    if (n == 0 || *s1 == '\0' || *s2 == '\0') {
      break;
    }
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncasecmp>:
  endbr64
  test   %rdx,%rdx
  je     L14
  push   %r13
  lea    -0x1(%rdi,%rdx,1),%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L34
L50:
  cmp    %eax,%r12d
  jne    L9
  test   %dil,%dil
  je     L9
  cmpb   $0x0,0x0(%rbp)
  je     L9
  add    $0x1,%rbx
  add    $0x1,%rbp
L34:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%r12d
  call   <tolower@plt>
  movsbl (%rbx),%edi
  cmp    %r13,%rbx
  jne    L50
L9:
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  if (n == 0) {
    return 0;
  }
  while (n-- != 0 && tolower(*s1) == tolower(*s2)) {
    if (n == 0 || *s1 == '\0' || *s2 == '\0') {
      break;
    }
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strncasecmp>:
  endbr64
  test   %rdx,%rdx
  je     L4
  push   %r13
  lea    -0x1(%rdi,%rdx,1),%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L58
L25:
  cmp    %eax,%r12d
  jne    L48
  test   %dil,%dil
  je     L48
  cmpb   $0x0,0x0(%rbp)
  je     L48
  add    $0x1,%rbx
  add    $0x1,%rbp
L58:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%r12d
  call   <tolower@plt>
  movsbl (%rbx),%edi
  cmp    %r13,%rbx
  jne    L25
L48:
  call   <tolower@plt>
  movsbl 0x0(%rbp),%edi
  mov    %eax,%ebx
  call   <tolower@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strncasecmp(const char *s1, const char *s2, size_t n) {
  if (n == 0) {
    return 0;
  }
  while (n-- != 0 && tolower(*s1) == tolower(*s2)) {
    if (n == 0 || *s1 == '\0' || *s2 == '\0') {
      break;
    }
    s1++;
    s2++;
  }
  return tolower(*(unsigned char *)s1) - tolower(*(unsigned char *)s2);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tanhf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <isinf@plt>
  test   %rax,%rax
  je     L16
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  mov    $0x1,%edi
  call   <copysignf@plt>
  jmp    L3
L16:
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <sinhf@plt>
  movd   %xmm0,%ebx
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <coshf@plt>
  movaps %xmm0,%xmm1
  movd   %ebx,%xmm0
  divss  %xmm1,%xmm0
L3:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
float tanhf(float x) {
  if (isinf(x)) {
    return copysignf(1, x);
  }
  return sinhf(x) / coshf(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<tanhf>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <isinf@plt>
  test   %rax,%rax
  jne    L10
  movss  0x8(%rsp),%xmm0
  call   <sinhf@plt>
  movss  %xmm0,0xc(%rsp)
  movss  0x8(%rsp),%xmm0
  call   <coshf@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  divss  %xmm1,%xmm0
L3:
  add    $0x18,%rsp
  ret
L10:
  movss  0x8(%rsp),%xmm0
  mov    $0x1,%edi
  call   <copysignf@plt>
  jmp    L3
```

assistant: ```c
float tanhf(float x) {
  if (isinf(x)) {
    return copysignf(1, x);
  }
  return sinhf(x) / coshf(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tanhf>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <isinf@plt>
  movss  0x8(%rsp),%xmm1
  test   %rax,%rax
  movaps %xmm1,%xmm0
  jne    L7
  movss  %xmm1,0xc(%rsp)
  call   <sinhf@plt>
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  call   <coshf@plt>
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  divss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edi
  add    $0x18,%rsp
  jmp    1090 <copysignf@plt>
```

assistant: ```c
float tanhf(float x) {
  if (isinf(x)) {
    return copysignf(1, x);
  }
  return sinhf(x) / coshf(x);
}
```
user: What is the c source code of the assembly code below:

```asm
<tanhf>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  call   <isinf@plt>
  movss  0x8(%rsp),%xmm1
  test   %rax,%rax
  movaps %xmm1,%xmm0
  jne    L7
  movss  %xmm1,0xc(%rsp)
  call   <sinhf@plt>
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  call   <coshf@plt>
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  divss  %xmm0,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%edi
  add    $0x18,%rsp
  jmp    1090 <copysignf@plt>
```

assistant: ```c
float tanhf(float x) {
  if (isinf(x)) {
    return copysignf(1, x);
  }
  return sinhf(x) / coshf(x);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int_random>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  sar    $0x4,%eax
  xor    -0x4(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  leave
  ret
```

assistant: ```c
uint16_t int_random(uint16_t n) {
  uint16_t t = time(NULL);
  return ((rand() >> 4) ^ t) % n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int_random>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  sar    $0x4,%eax
  xor    %ebp,%eax
  cltd
  idiv   %ebx
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint16_t int_random(uint16_t n) {
  uint16_t t = time(NULL);
  return ((rand() >> 4) ^ t) % n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<int_random>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  sar    $0x4,%eax
  xor    %ebp,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  mov    %edx,%eax
  ret
```

assistant: ```c
uint16_t int_random(uint16_t n) {
  uint16_t t = time(NULL);
  return ((rand() >> 4) ^ t) % n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_random>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <rand@plt>
  add    $0x8,%rsp
  sar    $0x4,%eax
  xor    %ebp,%eax
  cltd
  idiv   %ebx
  pop    %rbx
  pop    %rbp
  mov    %edx,%eax
  ret
```

assistant: ```c
uint16_t int_random(uint16_t n) {
  uint16_t t = time(NULL);
  return ((rand() >> 4) ^ t) % n;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<toBinaryFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x1,-0x10(%rbp)
  jmp    L12
L16:
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  imul   -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x10(%rbp)
L12:
  cmpl   $0x0,-0x14(%rbp)
  jne    L16
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long toBinaryFunc(int inputNum) {
  unsigned long long result = 0;
  int i = 1;
  while (inputNum != 0) {
    int remainder = inputNum % 2;
    inputNum /= 2;
    result += i * remainder;
    i *= 10;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toBinaryFunc>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    $0x1,%ecx
  mov    $0x0,%esi
L15:
  mov    %edi,%edx
  shr    $0x1f,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %edi,%edx
  shr    $0x1f,%edx
  add    %edi,%edx
  sar    %edx
  mov    %edx,%edi
  imul   %ecx,%eax
  cltq
  add    %rax,%rsi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  test   %edx,%edx
  jne    L15
L29:
  mov    %rsi,%rax
  ret
L9:
  mov    $0x0,%esi
  jmp    L29
```

assistant: ```c
unsigned long long toBinaryFunc(int inputNum) {
  unsigned long long result = 0;
  int i = 1;
  while (inputNum != 0) {
    int remainder = inputNum % 2;
    inputNum /= 2;
    result += i * remainder;
    i *= 10;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<toBinaryFunc>:
  endbr64
  test   %edi,%edi
  je     L9
  mov    $0x1,%edx
  xor    %r8d,%r8d
L18:
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  lea    (%rdi,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %edi,%ecx
  imul   %edx,%eax
  shr    $0x1f,%ecx
  lea    (%rdx,%rdx,4),%edx
  add    %ecx,%edi
  add    %edx,%edx
  cltq
  add    %rax,%r8
  sar    %edi
  jne    L18
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L9:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long long toBinaryFunc(int inputNum) {
  unsigned long long result = 0;
  int i = 1;
  while (inputNum != 0) {
    int remainder = inputNum % 2;
    inputNum /= 2;
    result += i * remainder;
    i *= 10;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<toBinaryFunc>:
  endbr64
  test   %edi,%edi
  je     L5
  mov    $0x1,%edx
  xor    %r8d,%r8d
L3:
  mov    %edi,%ecx
  shr    $0x1f,%ecx
  lea    (%rdi,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %edi,%ecx
  imul   %edx,%eax
  shr    $0x1f,%ecx
  lea    (%rdx,%rdx,4),%edx
  add    %ecx,%edi
  add    %edx,%edx
  cltq
  add    %rax,%r8
  sar    %edi
  jne    L3
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L5:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
unsigned long long toBinaryFunc(int inputNum) {
  unsigned long long result = 0;
  int i = 1;
  while (inputNum != 0) {
    int remainder = inputNum % 2;
    inputNum /= 2;
    result += i * remainder;
    i *= 10;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sigfillset@plt>
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void test(void) {
  sigset_t signal_set;
  int result;
  result = sigfillset(&signal_set);
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <sigfillset@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  sigset_t signal_set;
  int result;
  result = sigfillset(&signal_set);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <sigfillset@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  sigset_t signal_set;
  int result;
  result = sigfillset(&signal_set);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <sigfillset@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void test(void) {
  sigset_t signal_set;
  int result;
  result = sigfillset(&signal_set);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <LerVetor@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ListP@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D12
type_infered: string
name: read_data
arguments: label: D20
type_infered: string

tool: D13: Informe a quantidade de numeros:

tool: D12: %d

tool: D20: Informe o valores:

assistant: ```c
int main() {
  int *n, num, i;
  puts("Informe a quantidade de numeros:");
  scanf("%d", &num);
  n = malloc(sizeof(int) * num);
  puts("Informe o valores:");
  LerVetor(n, num);
  ListP(n, num);
  return 0;
}
```