ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movl   $0x5,-0x40(%rbp)
  movl   $0x1,-0x44(%rbp)
  jmp    L32
L25:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %eax,%edx
  mov    -0x44(%rbp),%eax
  cltq
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x44(%rbp)
L32:
  cmpl   $0xb,-0x44(%rbp)
  jle    L25
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L53
L65:
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  jmp    L63
L57:
  mov    -0x4c(%rbp),%eax
  mov    -0x44(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x40(%rbp,%rdx,4),%ecx
  cltd
  idiv   %ecx
  add    %eax,-0x48(%rbp)
  addl   $0x1,-0x44(%rbp)
L63:
  cmpl   $0xb,-0x44(%rbp)
  jle    L57
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L53:
  mov    -0x50(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x50(%rbp)
  test   %eax,%eax
  jne    L65
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string

tool: D1: %d

tool: D2: %d


assistant: ```c
int main() {
  int t, n, z, i, p[12] = {5};
  for (i = 1; i < 12; ++i)
    p[i] = 5 * p[i - 1];
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    for (i = z = 0; i < 12; ++i)
      z += n / p[i];
    printf("%d\n", z);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movl   $0x5,0x10(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0x3c(%rsp),%rcx
  mov    %rbp,%rax
L27:
  mov    (%rax),%edx
  lea    (%rdx,%rdx,4),%edx
  mov    %edx,0x4(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L27
  lea    0x8(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L13
  lea    0xc(%rsp),%r14
  lea    D17(%rip),%r13
  lea    0x30(%rbp),%rbx
  lea    D6(%rip),%r12
L6:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rcx
  mov    $0x0,%esi
L47:
  mov    %edi,%eax
  cltd
  idivl  (%rcx)
  add    %eax,%esi
  add    $0x4,%rcx
  cmp    %rbx,%rcx
  jne    L47
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L6
L13:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D17
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string

tool: D17: %d

tool: D6: %d


assistant: ```c
int main() {
  int t, n, z, i, p[12] = {5};
  for (i = 1; i < 12; ++i)
    p[i] = 5 * p[i - 1];
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    for (i = z = 0; i < 12; ++i)
      z += n / p[i];
    printf("%d\n", z);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  lea    0x10(%rsp),%r12
  movl   $0x5,0x10(%rsp)
  lea    0x3c(%rsp),%rcx
  mov    %rbp,%rdx
  mov    $0x5,%eax
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  jmp    L17
  nopl   0x0(%rax)
L63:
  add    $0x4,%rdx
L17:
  lea    (%rax,%rax,4),%eax
  mov    %eax,(%rdx)
  cmp    %rcx,%rdx
  jne    L63
  lea    D15(%rip),%rbx
  lea    0x8(%rsp),%rsi
  mov    %rbx,%rdi
  lea    0x30(%r12),%r14
  lea    0xc(%rsp),%r13
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    D11(%rip),%r12
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L36
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%edi
  mov    %rbp,%rcx
  xor    %r8d,%r8d
  mov    $0x5,%esi
  jmp    L29
  nopl   0x0(%rax)
L3:
  mov    (%rcx),%esi
  add    $0x4,%rcx
L29:
  mov    %edi,%eax
  cltd
  idiv   %esi
  add    %eax,%r8d
  cmp    %r14,%rcx
  jne    L3
  mov    %r8d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  jne    L0
L36:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x50,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D15
data_type: string
name: extract_symbolic_data
arguments: tag: D11
data_type: string

tool: D15: %d

tool: D11: %d


assistant: ```c
int main() {
  int t, n, z, i, p[12] = {5};
  for (i = 1; i < 12; ++i)
    p[i] = 5 * p[i - 1];
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    for (i = z = 0; i < 12; ++i)
      z += n / p[i];
    printf("%d\n", z);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  lea    D11(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r12
  call   <scanf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L4
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rbp,%rdi
  imul   $0x66666667,%rax,%rsi
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rcx
  sar    $0x1f,%edx
  sar    $0x21,%rsi
  sar    $0x23,%rcx
  sub    %edx,%esi
  sub    %edx,%ecx
  add    %ecx,%esi
  imul   $0x10624dd3,%rax,%rcx
  sar    $0x23,%rcx
  sub    %edx,%ecx
  add    %esi,%ecx
  imul   $0x68db8bad,%rax,%rsi
  sar    $0x28,%rsi
  sub    %edx,%esi
  add    %ecx,%esi
  imul   $0x14f8b589,%rax,%rcx
  sar    $0x28,%rcx
  sub    %edx,%ecx
  add    %esi,%ecx
  imul   $0x431bde83,%rax,%rsi
  sar    $0x2c,%rsi
  sub    %edx,%esi
  add    %ecx,%esi
  imul   $0x6b5fca6b,%rax,%rcx
  sar    $0x2f,%rcx
  sub    %edx,%ecx
  add    %esi,%ecx
  imul   $0x55e63b89,%rax,%rsi
  sar    $0x31,%rsi
  sub    %edx,%esi
  add    %ecx,%esi
  imul   $0x44b82fa1,%rax,%rcx
  sar    $0x33,%rcx
  sub    %edx,%ecx
  add    %esi,%ecx
  imul   $0xdbe6fed,%rax,%rsi
  sar    $0x33,%rsi
  sub    %edx,%esi
  add    %ecx,%esi
  imul   $0x2bfaffc3,%rax,%rcx
  sar    $0x37,%rcx
  sub    %edx,%ecx
  add    %esi,%ecx
  imul   $0x465e6605,%rax,%rsi
  sar    $0x3a,%rsi
  sub    %edx,%esi
  add    %ecx,%esi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L1
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
datatype: string
name: disassemble_data
arguments: tag: D11
datatype: string

tool: D5: %d


tool: D11: %d

assistant: ```c
int main() {
  int t, n, z, i, p[12] = {5};
  for (i = 1; i < 12; ++i)
    p[i] = 5 * p[i - 1];
  scanf("%d", &t);
  while (t--) {
    scanf("%d", &n);
    for (i = z = 0; i < 12; ++i)
      z += n / p[i];
    printf("%d\n", z);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<myStrCat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L0
L21:
  addq   $0x1,-0x8(%rbp)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L21
  jmp    L28
L29:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L28:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void myStrCat(char *pDstStr, char *pSrcStr) {
  while (*pDstStr != '\n')
    pDstStr++;
  while (*pSrcStr != '\n')
    *pDstStr++ = *pSrcStr++;
  *pDstStr = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<myStrCat>:
  endbr64
  cmpb   $0xa,(%rdi)
  je     L25
L17:
  add    $0x1,%rdi
  cmpb   $0xa,(%rdi)
  jne    L17
L25:
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  je     L16
L29:
  add    $0x1,%rsi
  add    $0x1,%rdi
  mov    %al,-0x1(%rdi)
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  jne    L29
L16:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void myStrCat(char *pDstStr, char *pSrcStr) {
  while (*pDstStr != '\n')
    pDstStr++;
  while (*pSrcStr != '\n')
    *pDstStr++ = *pSrcStr++;
  *pDstStr = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<myStrCat>:
  endbr64
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdi
L10:
  cmpb   $0xa,(%rdi)
  jne    L8
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  je     L38
L22:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  jne    L22
L38:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void myStrCat(char *pDstStr, char *pSrcStr) {
  while (*pDstStr != '\n')
    pDstStr++;
  while (*pSrcStr != '\n')
    *pDstStr++ = *pSrcStr++;
  *pDstStr = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<myStrCat>:
  endbr64
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L27:
  add    $0x1,%rdi
L33:
  cmpb   $0xa,(%rdi)
  jne    L27
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  je     L11
L1:
  add    $0x1,%rsi
  mov    %al,(%rdi)
  add    $0x1,%rdi
  movzbl (%rsi),%eax
  cmp    $0xa,%al
  jne    L1
L11:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void myStrCat(char *pDstStr, char *pSrcStr) {
  while (*pDstStr != '\n')
    pDstStr++;
  while (*pSrcStr != '\n')
    *pDstStr++ = *pSrcStr++;
  *pDstStr = '\0';
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  %xmm4,-0x48(%rbp)
  movsd  %xmm5,-0x50(%rbp)
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x48(%rbp),%xmm0
  subsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x50(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double _distance(double x1, double y1, double z1, double x2, double y2, double z2) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  double dz = z2 - z1;
  return sqrt(dx * dx + dy * dy + dz * dz);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_distance>:
  endbr64
  subsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm4
  subsd  %xmm2,%xmm5
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm4
  addsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  mulsd  %xmm5,%xmm5
  addsd  %xmm5,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L7
  sqrtsd %xmm0,%xmm0
  ret
L7:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double _distance(double x1, double y1, double z1, double x2, double y2, double z2) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  double dz = z2 - z1;
  return sqrt(dx * dx + dy * dy + dz * dz);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_distance>:
  endbr64
  subsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm4
  pxor   %xmm1,%xmm1
  subsd  %xmm2,%xmm5
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm4
  mulsd  %xmm5,%xmm5
  addsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  addsd  %xmm5,%xmm0
  ucomisd %xmm0,%xmm1
  ja     L0
  sqrtsd %xmm0,%xmm0
  ret
L0:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double _distance(double x1, double y1, double z1, double x2, double y2, double z2) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  double dz = z2 - z1;
  return sqrt(dx * dx + dy * dy + dz * dz);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_distance>:
  endbr64
  subsd  %xmm0,%xmm3
  subsd  %xmm1,%xmm4
  pxor   %xmm1,%xmm1
  subsd  %xmm2,%xmm5
  mulsd  %xmm3,%xmm3
  mulsd  %xmm4,%xmm4
  mulsd  %xmm5,%xmm5
  addsd  %xmm4,%xmm3
  movapd %xmm3,%xmm0
  addsd  %xmm5,%xmm0
  ucomisd %xmm0,%xmm1
  ja     L4
  sqrtsd %xmm0,%xmm0
  ret
L4:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double _distance(double x1, double y1, double z1, double x2, double y2, double z2) {
  double dx = x2 - x1;
  double dy = y2 - y1;
  double dz = z2 - z1;
  return sqrt(dx * dx + dy * dy + dz * dz);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<logprintdate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  mov    $0xffffffff,%eax
  jmp    L53
L8:
  mov    -0x3c(%rbp),%eax
  mov    %eax,-0x38(%rbp)
  lea    -0x34(%rbp),%rdx
  lea    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  test   %rax,%rax
  jne    L43
  mov    $0xffffffff,%eax
  jmp    L53
L43:
  lea    -0x34(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rcx
  lea    D5(%rip),%rdx
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  test   %rax,%rax
  jne    L63
  mov    $0xffffffff,%eax
  jmp    L53
L63:
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
L53:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string
name: read_data
arguments: data_tag: D8
type: string

tool: D5: %b %d %T 

tool: D8: %s

assistant: ```c
int logprintdate(FILE *stream) {
  struct timeval tv;
  time_t now;
  struct tm tmnow;
  char buf[32];
  if (gettimeofday(&tv, NULL) == -1)
    return -1;
  now = tv.tv_sec;
  if (localtime_r(&now, &tmnow) == NULL)
    return -1;
  if (strftime(buf, sizeof(buf), "%b %d %T ", &tmnow) == 0)
    return -1;
  return fprintf(stream, "%s", buf);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<logprintdate>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    0x4(%rsp),%eax
  mov    %eax,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <localtime_r@plt>
  test   %rax,%rax
  je     L5
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdi
  lea    D15(%rip),%rdx
  mov    $0x20,%esi
  call   <strftime@plt>
  test   %rax,%rax
  je     L57
  lea    0x10(%rsp),%rdx
  lea    D4(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
L12:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x40,%rsp
  pop    %rbx
  ret
L5:
  mov    $0xffffffff,%eax
  jmp    L12
L57:
  mov    $0xffffffff,%eax
  jmp    L12
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D15
type_infered: string
name: read_data
arguments: label: D4
type_infered: string

tool: D15: %b %d %T 

tool: D4: %s

assistant: ```c
int logprintdate(FILE *stream) {
  struct timeval tv;
  time_t now;
  struct tm tmnow;
  char buf[32];
  if (gettimeofday(&tv, NULL) == -1)
    return -1;
  now = tv.tv_sec;
  if (localtime_r(&now, &tmnow) == NULL)
    return -1;
  if (strftime(buf, sizeof(buf), "%b %d %T ", &tmnow) == 0)
    return -1;
  return fprintf(stream, "%s", buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<logprintdate>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  je     L16
  mov    0x4(%rsp),%eax
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rdi
  mov    %r12,%rsi
  mov    %eax,0x8(%rsp)
  call   <localtime_r@plt>
  test   %rax,%rax
  je     L16
  lea    0x10(%rsp),%r13
  mov    %r12,%rcx
  mov    $0x20,%esi
  lea    D19(%rip),%rdx
  mov    %r13,%rdi
  call   <strftime@plt>
  test   %rax,%rax
  je     L16
  mov    %r13,%rdx
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
L3:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x40,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L16:
  mov    $0xffffffff,%eax
  jmp    L3
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string

tool: D19: %b %d %T 

tool: D1: %s

assistant: ```c
int logprintdate(FILE *stream) {
  struct timeval tv;
  time_t now;
  struct tm tmnow;
  char buf[32];
  if (gettimeofday(&tv, NULL) == -1)
    return -1;
  now = tv.tv_sec;
  if (localtime_r(&now, &tmnow) == NULL)
    return -1;
  if (strftime(buf, sizeof(buf), "%b %d %T ", &tmnow) == 0)
    return -1;
  return fprintf(stream, "%s", buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<logprintdate>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <gettimeofday@plt>
  cmp    $0xffffffff,%eax
  je     L15
  mov    0x4(%rsp),%eax
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rdi
  mov    %r12,%rsi
  mov    %eax,0x8(%rsp)
  call   <localtime_r@plt>
  test   %rax,%rax
  je     L15
  lea    0x10(%rsp),%r13
  mov    %r12,%rcx
  mov    $0x20,%esi
  lea    D8(%rip),%rdx
  mov    %r13,%rdi
  call   <strftime@plt>
  test   %rax,%rax
  je     L15
  mov    %r13,%rdx
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
L2:
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L42
  add    $0x40,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L15:
  mov    $0xffffffff,%eax
  jmp    L2
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D17
data_type: string

tool: D8: %b %d %T 

tool: D17: %s

assistant: ```c
int logprintdate(FILE *stream) {
  struct timeval tv;
  time_t now;
  struct tm tmnow;
  char buf[32];
  if (gettimeofday(&tv, NULL) == -1)
    return -1;
  now = tv.tv_sec;
  if (localtime_r(&now, &tmnow) == NULL)
    return -1;
  if (strftime(buf, sizeof(buf), "%b %d %T ", &tmnow) == 0)
    return -1;
  return fprintf(stream, "%s", buf);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<abort_decode_service_request>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L16
  cmpq   $0x0,-0x28(%rbp)
  je     L17
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L17:
  cmpq   $0x0,-0x30(%rbp)
  je     L16
  mov    -0x18(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L16:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int abort_decode_service_request(uint8_t *apdu, unsigned apdu_len, uint8_t *invoke_id, uint8_t *abort_reason) {
  int len = 0;
  if (apdu_len > 0) {
    if (invoke_id)
      *invoke_id = apdu[0];
    if (abort_reason)
      *abort_reason = apdu[1];
  }
  return len;
}
```
user: What is the c source code of the assembly code below?

```asm
<abort_decode_service_request>:
  endbr64
  test   %esi,%esi
  je     L16
  test   %rdx,%rdx
  je     L13
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
L13:
  test   %rcx,%rcx
  je     L16
  mov    0x4(%rdi),%eax
  mov    %eax,(%rcx)
L16:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int abort_decode_service_request(uint8_t *apdu, unsigned apdu_len, uint8_t *invoke_id, uint8_t *abort_reason) {
  int len = 0;
  if (apdu_len > 0) {
    if (invoke_id)
      *invoke_id = apdu[0];
    if (abort_reason)
      *abort_reason = apdu[1];
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<abort_decode_service_request>:
  endbr64
  test   %esi,%esi
  je     L15
  test   %rdx,%rdx
  je     L6
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
L6:
  test   %rcx,%rcx
  je     L15
  mov    0x4(%rdi),%eax
  mov    %eax,(%rcx)
L15:
  xor    %eax,%eax
  ret
```

assistant: ```c
int abort_decode_service_request(uint8_t *apdu, unsigned apdu_len, uint8_t *invoke_id, uint8_t *abort_reason) {
  int len = 0;
  if (apdu_len > 0) {
    if (invoke_id)
      *invoke_id = apdu[0];
    if (abort_reason)
      *abort_reason = apdu[1];
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<abort_decode_service_request>:
  endbr64
  test   %esi,%esi
  je     L7
  test   %rdx,%rdx
  je     L11
  mov    (%rdi),%eax
  mov    %eax,(%rdx)
L11:
  test   %rcx,%rcx
  je     L7
  mov    0x4(%rdi),%eax
  mov    %eax,(%rcx)
L7:
  xor    %eax,%eax
  ret
```

assistant: ```c
int abort_decode_service_request(uint8_t *apdu, unsigned apdu_len, uint8_t *invoke_id, uint8_t *abort_reason) {
  int len = 0;
  if (apdu_len > 0) {
    if (invoke_id)
      *invoke_id = apdu[0];
    if (abort_reason)
      *abort_reason = apdu[1];
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  orl    $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  andl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D35
type_infered: string

tool: D15: before move bit:%d


tool: D35: after move:%d


assistant: ```c
int main() {
  int n = 1;
  int h = 1;
  printf("before move bit:%d\n", n);
  n |= 1 << 2;
  printf("after move:%d\n", n);
  printf("before move bit:%d\n", h);
  h &= 1 << 2;
  printf("after move:%d\n", h);
}
```