ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r12
  call   <scanf@plt>
  mov    %r12,%rbp
  nopw   0x0(%rax,%rax,1)
L15:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L15
  movslq %ebx,%rbx
  shl    $0x2,%rax
  shl    $0x2,%rbx
  lea    (%r12,%rbx,1),%rbp
  lea    -0x4(%r12,%rbx,1),%rbx
  sub    %rax,%rbx
  lea    D5(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L1:
  mov    -0x4(%rbp),%esi
  mov    %r12,%rdi
  sub    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D5
datatype: string

tool: D17: %d

tool: D5: %d


assistant: ```c
int main() {
  int k, o = 0;
  int arr[o];
  scanf("%d", &k);
  do {
    scanf("%d", &arr[o]);
    o++;
  } while (o < k);
  do {
    o--;
    printf("%d\n", arr[o]);
  } while (o > 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r12
  call   <scanf@plt>
  mov    %r12,%rbp
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jg     L29
  movslq %ebx,%rbx
  shl    $0x2,%rax
  shl    $0x2,%rbx
  lea    (%r12,%rbx,1),%rbp
  lea    -0x4(%r12,%rbx,1),%rbx
  sub    %rax,%rbx
  lea    D12(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  mov    -0x4(%rbp),%esi
  mov    %r12,%rdi
  sub    $0x4,%rbp
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L2
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_infered: string
name: unpack_data
arguments: tag: D12
type_infered: string

tool: D6: %d

tool: D12: %d


assistant: ```c
int main() {
  int k, o = 0;
  int arr[o];
  scanf("%d", &k);
  do {
    scanf("%d", &arr[o]);
    o++;
  } while (o < k);
  do {
    o--;
    printf("%d\n", arr[o]);
  } while (o > 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isSubsetSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L4
  mov    $0x1,%eax
  jmp    L76
L4:
  cmpl   $0x0,-0xc(%rbp)
  jne    L79
  cmpl   $0x0,-0x10(%rbp)
  je     L79
  mov    $0x0,%eax
  jmp    L76
L79:
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L31
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <isSubsetSum>
  jmp    L76
L31:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <isSubsetSum>
  test   %eax,%eax
  jne    L22
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x10(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <isSubsetSum>
  test   %eax,%eax
  je     L77
L22:
  mov    $0x1,%eax
  jmp    L76
L77:
  mov    $0x0,%eax
L76:
  leave
  ret
```

assistant: ```c
int isSubsetSum(int set[], int n, int sum) {
  if (sum == 0)
    return 1;
  if (n == 0 && sum != 0)
    return 0;
  if (set[n - 1] > sum)
    return isSubsetSum(set, n - 1, sum);
  return isSubsetSum(set, n - 1, sum) || isSubsetSum(set, n - 1, sum - set[n - 1]);
}
```
user: Translate the below assembly code into C programming language:

```asm
<isSubsetSum>:
  endbr64
  mov    $0x1,%eax
  test   %edx,%edx
  je     L59
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %edx,%ebp
  mov    %esi,%eax
  test   %esi,%esi
  je     L26
  movslq %esi,%rax
  mov    -0x4(%rdi,%rax,4),%r13d
  cmp    %edx,%r13d
  jg     L51
  lea    -0x1(%rsi),%ebx
  mov    %ebx,%esi
  call   <isSubsetSum>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L36
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L51:
  sub    $0x1,%esi
  call   <isSubsetSum>
  jmp    L26
L36:
  mov    %ebp,%edx
  sub    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <isSubsetSum>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L26
L59:
  ret
```

assistant: ```c
int isSubsetSum(int set[], int n, int sum) {
  if (sum == 0)
    return 1;
  if (n == 0 && sum != 0)
    return 0;
  if (set[n - 1] > sum)
    return isSubsetSum(set, n - 1, sum);
  return isSubsetSum(set, n - 1, sum) || isSubsetSum(set, n - 1, sum - set[n - 1]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isSubsetSum>:
  endbr64
  test   %edx,%edx
  je     L24
  test   %esi,%esi
  je     L19
  push   %r13
  movslq %esi,%rcx
  push   %r12
  sub    $0x2,%rcx
  mov    %rdi,%r12
  push   %rbp
  mov    %edx,%ebp
  lea    -0x1(%rsi),%edx
  push   %rbx
  movslq %edx,%rax
  mov    %edx,%edx
  sub    %rdx,%rcx
  sub    $0x8,%rsp
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L34:
  sub    $0x1,%rax
  cmp    %rcx,%rax
  je     L49
L8:
  mov    (%r12,%rax,4),%ebx
  mov    %eax,%r13d
  cmp    %ebp,%ebx
  jg     L34
  mov    %ebp,%edx
  mov    %eax,%esi
  mov    %r12,%rdi
  call   <isSubsetSum>
  mov    %eax,%r8d
  mov    $0x1,%eax
  test   %r8d,%r8d
  je     L53
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L49:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L53:
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  sub    %ebx,%edx
  call   <isSubsetSum>
  test   %eax,%eax
  setne  %al
  add    $0x8,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  mov    $0x1,%eax
  ret
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isSubsetSum(int set[], int n, int sum) {
  if (sum == 0)
    return 1;
  if (n == 0 && sum != 0)
    return 0;
  if (set[n - 1] > sum)
    return isSubsetSum(set, n - 1, sum);
  return isSubsetSum(set, n - 1, sum) || isSubsetSum(set, n - 1, sum - set[n - 1]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<isSubsetSum>:
  endbr64
  test   %edx,%edx
  je     L180
  test   %esi,%esi
  je     L6
  push   %r15
  lea    -0x1(%rsi),%ecx
  push   %r14
  movslq %ecx,%rax
  mov    %ecx,%ecx
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  movslq %esi,%rdx
  sub    $0x2,%rdx
  sub    %rcx,%rdx
  sub    $0x18,%rsp
  jmp    L211
  nopl   0x0(%rax,%rax,1)
L9:
  sub    $0x1,%rax
  cmp    %rdx,%rax
  je     L132
L211:
  mov    (%rdi,%rax,4),%ebp
  mov    %eax,%ecx
  cmp    %ebx,%ebp
  jg     L9
  test   %eax,%eax
  je     L131
  lea    -0x1(%rax),%eax
  movslq %ecx,%r13
  movslq %eax,%r15
  sub    $0x2,%r13
  mov    %eax,%eax
  sub    %rax,%r13
  mov    %r15,%rax
  jmp    L171
  nopl   (%rax)
L123:
  sub    $0x1,%rax
  cmp    %rax,%r13
  je     L172
L171:
  mov    (%rdi,%rax,4),%r14d
  mov    %eax,%r12d
  cmp    %r14d,%ebx
  jl     L123
  test   %eax,%eax
  je     L133
  lea    -0x1(%rax),%ecx
  movslq %r12d,%rdx
  movslq %ecx,%rax
  sub    $0x2,%rdx
  mov    %ecx,%ecx
  sub    %rcx,%rdx
  jmp    L213
  nopl   0x0(%rax)
L118:
  sub    $0x1,%rax
  cmp    %rax,%rdx
  je     L133
L213:
  mov    (%rdi,%rax,4),%ecx
  mov    %eax,%esi
  cmp    %ecx,%ebx
  jl     L118
  mov    %ebx,%edx
  mov    %ecx,0xc(%rsp)
  mov    %rdi,(%rsp)
  mov    %eax,0x8(%rsp)
  call   <isSubsetSum>
  mov    (%rsp),%rdi
  mov    0x8(%rsp),%esi
  mov    $0x1,%r9d
  test   %eax,%eax
  mov    0xc(%rsp),%ecx
  jne    L10
  mov    %ebx,%edx
  mov    %r9d,0x8(%rsp)
  sub    %ecx,%edx
  call   <isSubsetSum>
  mov    (%rsp),%rdi
  mov    0x8(%rsp),%r9d
  test   %eax,%eax
  jne    L10
L133:
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rdi,(%rsp)
  sub    %r14d,%edx
  call   <isSubsetSum>
  mov    (%rsp),%rdi
  mov    $0x1,%r9d
  test   %eax,%eax
  jne    L10
  nopl   (%rax)
L172:
  sub    %ebp,%ebx
  jne    L41
  jmp    L53
  cs nopw 0x0(%rax,%rax,1)
L85:
  sub    $0x1,%r15
  cmp    %r15,%r13
  je     L132
L41:
  mov    (%rdi,%r15,4),%ebp
  cmp    %ebp,%ebx
  jl     L85
  mov    %ebx,%edx
  mov    %r15d,%esi
  mov    %rdi,(%rsp)
  call   <isSubsetSum>
  mov    (%rsp),%rdi
  mov    $0x1,%r9d
  test   %eax,%eax
  jne    L10
  sub    %ebp,%ebx
  mov    %r15d,%esi
  mov    %ebx,%edx
  call   <isSubsetSum>
  xor    %r9d,%r9d
  test   %eax,%eax
  setne  %r9b
  jmp    L10
  nopl   0x0(%rax)
L132:
  xor    %r9d,%r9d
L10:
  add    $0x18,%rsp
  mov    %r9d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L180:
  mov    $0x1,%r9d
L13:
  mov    %r9d,%eax
  ret
L6:
  xor    %r9d,%r9d
  jmp    L13
L53:
  mov    $0x1,%r9d
  jmp    L10
L131:
  xor    %r9d,%r9d
  cmp    %ebx,%ebp
  sete   %r9b
  jmp    L10
```

assistant: ```c
int isSubsetSum(int set[], int n, int sum) {
  if (sum == 0)
    return 1;
  if (n == 0 && sum != 0)
    return 0;
  if (set[n - 1] > sum)
    return isSubsetSum(set, n - 1, sum);
  return isSubsetSum(set, n - 1, sum) || isSubsetSum(set, n - 1, sum - set[n - 1]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  movslq -0x1d4(%rbp),%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffffff0,%rdx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L32:
  cmp    %rcx,%rsp
  je     L117
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L32
L117:
  mov    %rdx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L52
  orq    $0x0,-0x8(%rsp,%rax,1)
L52:
  mov    %rsp,%r13
  lea    -0x1d0(%rbp),%rdi
  mov    $0x32,%ecx
  mov    $0x0,%eax
  rep stos %rax,%es:(%rdi)
  lea    D13(%rip),%rbx
L18:
  lea    -0x1d4(%rbp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x1d4(%rbp),%eax
  test   $0x1,%al
  je     L18
  cmp    $0xc8,%eax
  jg     L18
  test   %eax,%eax
  jle    L33
  mov    $0x0,%r14d
  lea    D13(%rip),%r12
L5:
  mov    %r13,%rbx
L9:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  cmp    $0x64,%eax
  jg     L9
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x1d0(%rbp,%rdx,4),%edx
  cmp    $0x1,%edx
  jg     L9
  cltq
  add    $0x1,%edx
  mov    %edx,-0x1d0(%rbp,%rax,4)
  add    $0x1,%r14d
  add    $0x4,%r13
  cmp    %r14d,-0x1d4(%rbp)
  jg     L5
L33:
  mov    $0x0,%eax
  lea    -0x1d0(%rbp),%rdx
L3:
  cmpl   $0x1,(%rdx,%rax,4)
  je     L47
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L3
  jmp    L4
L47:
  lea    0x1(%rax),%r15d
L4:
  mov    %r15d,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D12
type_infered: string

tool: D13: %d

tool: D12: Rudolf is: %d 


assistant: ```c
int main() {
  int n;
  int deers[n];
  int s[100] = {0};
  int k = 0, Rudolf, i;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n >= 201);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &deers[i]);
      if ((deers[i] - 1) < 100) {
        if (s[deers[i] - 1] < 2) {
          s[deers[i] - 1]++;
          k = 1;
        }
      }
    } while (k == 0);
    k = 0;
  }
  for (i = 0; i < 100; i++) {
    if (s[i] == 1) {
      Rudolf = i + 1;
      break;
    }
  }
  printf("Rudolf is: %d \n", Rudolf);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq -0x1c4(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L26
L7:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L7
L26:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L71
L131:
  lea    -0x1c0(%rbp),%r13
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r13,%rdi
  lea    -0x1c4(%rbp),%r12
  lea    D16(%rip),%rbx
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax,%rax,1)
L111:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x1c4(%rbp),%eax
  test   $0x1,%al
  je     L111
  cmp    $0xc8,%eax
  jg     L111
  test   %eax,%eax
  jle    L130
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L62:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%r14),%eax
  cmp    $0x64,%eax
  jg     L62
  sub    $0x1,%eax
  cltq
  mov    -0x1c0(%rbp,%rax,4),%edx
  cmp    $0x1,%edx
  jg     L62
  add    $0x1,%edx
  add    $0x1,%r12d
  add    $0x4,%r14
  mov    %edx,-0x1c0(%rbp,%rax,4)
  cmp    %r12d,-0x1c4(%rbp)
  jg     L62
L130:
  mov    $0x1,%eax
  jmp    L39
  xchg   %ax,%ax
L33:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L133
L39:
  cmpl   $0x1,-0x4(%r13,%rax,4)
  mov    %eax,%esi
  jne    L33
L133:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L71:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L131
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D16
datatype: string
name: unpack_data
arguments: data_tag: D9
datatype: string

tool: D16: %d

tool: D9: Rudolf is: %d 


assistant: ```c
int main() {
  int n;
  int deers[n];
  int s[100] = {0};
  int k = 0, Rudolf, i;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n >= 201);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &deers[i]);
      if ((deers[i] - 1) < 100) {
        if (s[deers[i] - 1] < 2) {
          s[deers[i] - 1]++;
          k = 1;
        }
      }
    } while (k == 0);
    k = 0;
  }
  for (i = 0; i < 100; i++) {
    if (s[i] == 1) {
      Rudolf = i + 1;
      break;
    }
  }
  printf("Rudolf is: %d \n", Rudolf);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq -0x1c4(%rbp),%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L65
L9:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L9
L65:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L111
L39:
  lea    -0x1c0(%rbp),%r13
  mov    $0x32,%ecx
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %r13,%rdi
  lea    -0x1c4(%rbp),%r12
  lea    D18(%rip),%rbx
  rep stos %rax,%es:(%rdi)
  nopl   0x0(%rax,%rax,1)
L33:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    -0x1c4(%rbp),%eax
  test   $0x1,%al
  je     L33
  cmp    $0xc8,%eax
  jg     L33
  test   %eax,%eax
  jle    L95
  xor    %r12d,%r12d
  nopl   0x0(%rax,%rax,1)
L120:
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    (%r14),%eax
  cmp    $0x64,%eax
  jg     L120
  sub    $0x1,%eax
  cltq
  mov    -0x1c0(%rbp,%rax,4),%edx
  cmp    $0x1,%edx
  jg     L120
  add    $0x1,%edx
  add    $0x1,%r12d
  add    $0x4,%r14
  mov    %edx,-0x1c0(%rbp,%rax,4)
  cmp    %r12d,-0x1c4(%rbp)
  jg     L120
L95:
  mov    $0x1,%eax
  jmp    L20
  xchg   %ax,%ax
L11:
  add    $0x1,%rax
  cmp    $0x65,%rax
  je     L98
L20:
  cmpl   $0x1,-0x4(%r13,%rax,4)
  mov    %eax,%esi
  jne    L11
L98:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L111:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L39
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D18
type_infered: string
name: parse_data
arguments: data_tag: D0
type_infered: string

tool: D18: %d

tool: D0: Rudolf is: %d 


assistant: ```c
int main() {
  int n;
  int deers[n];
  int s[100] = {0};
  int k = 0, Rudolf, i;
  do {
    scanf("%d", &n);
  } while (n % 2 == 0 || n >= 201);
  for (i = 0; i < n; i++) {
    do {
      scanf("%d", &deers[i]);
      if ((deers[i] - 1) < 100) {
        if (s[deers[i] - 1] < 2) {
          s[deers[i] - 1]++;
          k = 1;
        }
      }
    } while (k == 0);
    k = 0;
  }
  for (i = 0; i < 100; i++) {
    if (s[i] == 1) {
      Rudolf = i + 1;
      break;
    }
  }
  printf("Rudolf is: %d \n", Rudolf);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<wcslen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L3
L13:
  addq   $0x8,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x3,%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t wcslen(const wchar_t *s) {
  const wchar_t *p;
  p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<wcslen>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L26
  mov    %rdi,%rax
L27:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L27
L8:
  sub    %rdi,%rax
  sar    $0x3,%rax
  ret
L26:
  mov    %rdi,%rax
  jmp    L8
```

assistant: ```c
size_t wcslen(const wchar_t *s) {
  const wchar_t *p;
  p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wcslen>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L1
  mov    %rdi,%rax
  nopl   (%rax)
L9:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L9
  sub    %rdi,%rax
  sar    $0x3,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t wcslen(const wchar_t *s) {
  const wchar_t *p;
  p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wcslen>:
  endbr64
  cmpq   $0x0,(%rdi)
  je     L19
  mov    %rdi,%rax
  nopl   (%rax)
L15:
  add    $0x8,%rax
  cmpq   $0x0,(%rax)
  jne    L15
  sub    %rdi,%rax
  sar    $0x3,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t wcslen(const wchar_t *s) {
  const wchar_t *p;
  p = s;
  while (*p)
    p++;
  return p - s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mvEthRxCoalSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x9e4f580,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%eax
  imul   $0x431bde83,%rax,%rax
  shr    $0x20,%rax
  shr    $0x12,%eax
  imul   -0x14(%rbp),%eax
  shr    $0x6,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L25
  mov    $0x7241c,%eax
  jmp    L37
L25:
  mov    $0x8241c,%eax
L37:
  mov    %eax,%edi
  call   <mv_reg_read@plt>
  mov    %eax,-0x4(%rbp)
  andl   $0xffe0007f,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  shl    $0x7,%eax
  and    $0x1fff80,%eax
  or     %eax,-0x4(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L13
  mov    $0x7241c,%edx
  jmp    L15
L13:
  mov    $0x8241c,%edx
L15:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  mov    %edx,%edi
  call   <mv_reg_write@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int mvEthRxCoalSet(unsigned int uSec) {
  unsigned int port = 0;
  unsigned int Tclk = 166000000;
  unsigned int coal = ((uSec * (Tclk / 1000000)) / 64);
  unsigned int portSdmaCfgReg;
  portSdmaCfgReg = mv_reg_read(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c));
  portSdmaCfgReg &= ~(0x3fff << 7);
  portSdmaCfgReg |= ((((coal) << 7) & (0x3fff << 7)));
  mv_reg_write(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c), portSdmaCfgReg);
  return coal;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mvEthRxCoalSet>:
  endbr64
  push   %rbx
  imul   $0xa6,%edi,%ebx
  shr    $0x6,%ebx
  mov    $0x7241c,%edi
  call   <mv_reg_read@plt>
  and    $0xffe0007f,%eax
  mov    %ebx,%esi
  shl    $0x7,%esi
  and    $0x1fff80,%esi
  or     %eax,%esi
  mov    $0x7241c,%edi
  call   <mv_reg_write@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int mvEthRxCoalSet(unsigned int uSec) {
  unsigned int port = 0;
  unsigned int Tclk = 166000000;
  unsigned int coal = ((uSec * (Tclk / 1000000)) / 64);
  unsigned int portSdmaCfgReg;
  portSdmaCfgReg = mv_reg_read(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c));
  portSdmaCfgReg &= ~(0x3fff << 7);
  portSdmaCfgReg |= ((((coal) << 7) & (0x3fff << 7)));
  mv_reg_write(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c), portSdmaCfgReg);
  return coal;
}
```
user: What is the c source code of the assembly code below?

```asm
<mvEthRxCoalSet>:
  endbr64
  push   %r12
  imul   $0xa6,%edi,%r12d
  mov    $0x7241c,%edi
  call   <mv_reg_read@plt>
  shr    $0x6,%r12d
  mov    $0x7241c,%edi
  mov    %r12d,%esi
  and    $0xffe0007f,%eax
  shl    $0x7,%esi
  and    $0x1fff80,%esi
  or     %eax,%esi
  call   <mv_reg_write@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned int mvEthRxCoalSet(unsigned int uSec) {
  unsigned int port = 0;
  unsigned int Tclk = 166000000;
  unsigned int coal = ((uSec * (Tclk / 1000000)) / 64);
  unsigned int portSdmaCfgReg;
  portSdmaCfgReg = mv_reg_read(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c));
  portSdmaCfgReg &= ~(0x3fff << 7);
  portSdmaCfgReg |= ((((coal) << 7) & (0x3fff << 7)));
  mv_reg_write(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c), portSdmaCfgReg);
  return coal;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mvEthRxCoalSet>:
  endbr64
  push   %r12
  imul   $0xa6,%edi,%r12d
  mov    $0x7241c,%edi
  call   <mv_reg_read@plt>
  shr    $0x6,%r12d
  mov    $0x7241c,%edi
  mov    %r12d,%esi
  and    $0xffe0007f,%eax
  shl    $0x7,%esi
  and    $0x1fff80,%esi
  or     %eax,%esi
  call   <mv_reg_write@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
unsigned int mvEthRxCoalSet(unsigned int uSec) {
  unsigned int port = 0;
  unsigned int Tclk = 166000000;
  unsigned int coal = ((uSec * (Tclk / 1000000)) / 64);
  unsigned int portSdmaCfgReg;
  portSdmaCfgReg = mv_reg_read(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c));
  portSdmaCfgReg &= ~(0x3fff << 7);
  portSdmaCfgReg |= ((((coal) << 7) & (0x3fff << 7)));
  mv_reg_write(((((port) == 0) ? 0x72000 : 0x82000) + 0x41c), portSdmaCfgReg);
  return coal;
}
```