ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<split_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r12
  lea    D7(%rip),%rsi
  call   <strtok@plt>
  mov    $0x0,%ebp
  test   %rax,%rax
  je     L12
  mov    %rax,(%r12)
  mov    $0x1,%ebx
  lea    D7(%rip),%r13
  jmp    L19
L1:
  mov    %rax,(%r12,%rbx,8)
  add    $0x1,%rbx
L19:
  mov    %ebx,%ebp
  mov    %r13,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  test   %rax,%rax
  jne    L1
L12:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string

tool: D7:  

assistant: ```c
int split_str(char *str, char *tokens[]) {
  int num_tokens = 0;
  char *token;
  token = strtok(str, " ");
  if (token != NULL) {
    tokens[num_tokens++] = token;
  }
  while (token != NULL) {
    token = strtok(NULL, " ");
    if (token != NULL) {
      tokens[num_tokens++] = token;
    }
  }
  return num_tokens;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<split_str>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,0x0(%r13)
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L19:
  xor    %edi,%edi
  mov    %rbp,%rsi
  mov    %ebx,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  jmp    L19
  nopl   (%rax)
L10:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type: string

tool: D8:  

assistant: ```c
int split_str(char *str, char *tokens[]) {
  int num_tokens = 0;
  char *token;
  token = strtok(str, " ");
  if (token != NULL) {
    tokens[num_tokens++] = token;
  }
  while (token != NULL) {
    token = strtok(NULL, " ");
    if (token != NULL) {
      tokens[num_tokens++] = token;
    }
  }
  return num_tokens;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<split_str>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <strtok@plt>
  test   %rax,%rax
  je     L21
  mov    %rax,0x0(%r13)
  mov    $0x1,%ebx
  nopl   0x0(%rax)
L24:
  xor    %edi,%edi
  mov    %rbp,%rsi
  mov    %ebx,%r12d
  call   <strtok@plt>
  test   %rax,%rax
  je     L21
  mov    %rax,0x0(%r13,%rbx,8)
  add    $0x1,%rbx
  jmp    L24
  nopl   (%rax)
L21:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D8:  

assistant: ```c
int split_str(char *str, char *tokens[]) {
  int num_tokens = 0;
  char *token;
  token = strtok(str, " ");
  if (token != NULL) {
    tokens[num_tokens++] = token;
  }
  while (token != NULL) {
    token = strtok(NULL, " ");
    if (token != NULL) {
      tokens[num_tokens++] = token;
    }
  }
  return num_tokens;
}
```
user: What is the c source code of the assembly code below?

```asm
<hee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x40,%rsp
  mov    %edi,-0x1034(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1010(%rbp),%rax
  mov    %rax,-0x1020(%rbp)
  lea    -0x1010(%rbp),%rcx
  mov    -0x1034(%rbp),%eax
  mov    $0x1000,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x1028(%rbp)
  cmpl   $0x0,-0x1028(%rbp)
  jg     L0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  jmp    L1
L0:
  mov    -0x1020(%rbp),%rax
  mov    %rax,-0x1018(%rbp)
  mov    -0x1018(%rbp),%rax
  mov    %rax,%rdi
  call   <evh@plt>
  mov    -0x1018(%rbp),%rax
  mov    (%rax),%eax
  add    $0x4,%eax
  mov    %eax,-0x1024(%rbp)
  mov    -0x1024(%rbp),%eax
  sub    %eax,-0x1028(%rbp)
  cmpl   $0x0,-0x1028(%rbp)
  jle    L8
  mov    -0x1024(%rbp),%eax
  cltq
  add    %rax,-0x1020(%rbp)
  jmp    L0
L8:
  nop
L1:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D9
datatype: string

tool: D9: read/ino

assistant: ```c
void hee(int ino) {
  char buf[4096], *s = buf;
  int r;
  if ((r = read(ino, buf, 4096)) <= 0) {
    perror("read/ino");
    return;
  }
  while (1) {
    struct inotify_event *ev = (struct inotify_event *)s;
    evh(ev);
    int l = (sizeof(struct inotify_event)) + ev->len;
    if ((r -= l) <= 0)
      return;
    else
      s += l;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hee>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0x1000,%edx
  call   <read@plt>
  mov    %eax,%ebp
  mov    %rsp,%rbx
  test   %eax,%eax
  jg     L18
  lea    D4(%rip),%rdi
  call   <perror@plt>
  jmp    L7
L35:
  cltq
  add    %rax,%rbx
L18:
  mov    %rbx,%rdi
  call   <evh@plt>
  mov    (%rbx),%eax
  add    $0x4,%eax
  sub    %eax,%ebp
  test   %ebp,%ebp
  jg     L35
L7:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: read/ino

assistant: ```c
void hee(int ino) {
  char buf[4096], *s = buf;
  int r;
  if ((r = read(ino, buf, 4096)) <= 0) {
    perror("read/ino");
    return;
  }
  while (1) {
    struct inotify_event *ev = (struct inotify_event *)s;
    evh(ev);
    int l = (sizeof(struct inotify_event)) + ev->len;
    if ((r -= l) <= 0)
      return;
    else
      s += l;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hee>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1000,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <read@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L37
  jmp    L8
  nopl   0x0(%rax)
L36:
  cltq
  add    %rax,%rbx
L37:
  mov    %rbx,%rdi
  call   <evh@plt>
  mov    (%rbx),%eax
  add    $0x4,%eax
  sub    %eax,%ebp
  test   %ebp,%ebp
  jg     L36
L5:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L8:
  lea    D2(%rip),%rdi
  call   <perror@plt>
  jmp    L5
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type: string

tool: D2: read/ino

assistant: ```c
void hee(int ino) {
  char buf[4096], *s = buf;
  int r;
  if ((r = read(ino, buf, 4096)) <= 0) {
    perror("read/ino");
    return;
  }
  while (1) {
    struct inotify_event *ev = (struct inotify_event *)s;
    evh(ev);
    int l = (sizeof(struct inotify_event)) + ev->len;
    if ((r -= l) <= 0)
      return;
    else
      s += l;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hee>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x18,%rsp
  mov    $0x1000,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x1008(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  call   <read@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jg     L34
  jmp    L36
  nopl   0x0(%rax)
L42:
  cltq
  add    %rax,%rbx
L34:
  mov    %rbx,%rdi
  call   <evh@plt>
  mov    (%rbx),%eax
  add    $0x4,%eax
  sub    %eax,%ebp
  test   %ebp,%ebp
  jg     L42
L31:
  mov    0x1008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x1018,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   (%rax)
L36:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  jmp    L31
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
datatype: string

tool: D7: read/ino

assistant: ```c
void hee(int ino) {
  char buf[4096], *s = buf;
  int r;
  if ((r = read(ino, buf, 4096)) <= 0) {
    perror("read/ino");
    return;
  }
  while (1) {
    struct inotify_event *ev = (struct inotify_event *)s;
    evh(ev);
    int l = (sizeof(struct inotify_event)) + ev->len;
    if ((r -= l) <= 0)
      return;
    else
      s += l;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<byte_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L1:
  cmpl   $0x0,-0x1c(%rbp)
  je     L38
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L77
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L37
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L54
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  subl   $0x1,-0x1c(%rbp)
  jmp    L1
L38:
  nop
  jmp    L68
L77:
  nop
  jmp    L68
L37:
  nop
  jmp    L68
L54:
  nop
L68:
  pop    %rbp
  ret
```

assistant: ```c
void byte_copy(void *To, unsigned int n, const void *From) {
  char *to = To;
  const char *from = From;
  for (;;) {
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<byte_copy>:
  endbr64
  test   %esi,%esi
  je     L67
  movzbl (%rdx),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%esi
  je     L67
  movzbl 0x1(%rdx),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%esi
  je     L67
  movzbl 0x2(%rdx),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%esi
  je     L15
L5:
  add    $0x4,%rdx
  add    $0x4,%rdi
  movzbl -0x1(%rdx),%eax
  mov    %al,-0x1(%rdi)
  sub    $0x4,%esi
  je     L67
  movzbl (%rdx),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%esi
  je     L67
  movzbl 0x1(%rdx),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%esi
  je     L67
  movzbl 0x2(%rdx),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%esi
  jne    L5
L67:
  ret
L15:
  ret
```

assistant: ```c
void byte_copy(void *To, unsigned int n, const void *From) {
  char *to = To;
  const char *from = From;
  for (;;) {
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<byte_copy>:
  endbr64
  test   %esi,%esi
  je     L21
  movzbl (%rdx),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%esi
  je     L21
  movzbl 0x1(%rdx),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%esi
  je     L21
  movzbl 0x2(%rdx),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%esi
  jne    L84
  jmp    L39
  nopl   0x0(%rax)
L69:
  movzbl (%rdx),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%esi
  je     L21
  movzbl 0x1(%rdx),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%esi
  je     L21
  movzbl 0x2(%rdx),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%esi
  je     L21
L84:
  movzbl 0x3(%rdx),%eax
  add    $0x4,%rdx
  add    $0x4,%rdi
  mov    %al,-0x1(%rdi)
  sub    $0x4,%esi
  jne    L69
L21:
  ret
L39:
  ret
```

assistant: ```c
void byte_copy(void *To, unsigned int n, const void *From) {
  char *to = To;
  const char *from = From;
  for (;;) {
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<byte_copy>:
  endbr64
  test   %esi,%esi
  je     L89
  movzbl (%rdx),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%esi
  je     L89
  movzbl 0x1(%rdx),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%esi
  je     L89
  movzbl 0x2(%rdx),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%esi
  jne    L71
  jmp    L59
  nopl   0x0(%rax)
L88:
  movzbl (%rdx),%eax
  mov    %al,(%rdi)
  cmp    $0x1,%esi
  je     L89
  movzbl 0x1(%rdx),%eax
  mov    %al,0x1(%rdi)
  cmp    $0x2,%esi
  je     L89
  movzbl 0x2(%rdx),%eax
  mov    %al,0x2(%rdi)
  cmp    $0x3,%esi
  je     L89
L71:
  movzbl 0x3(%rdx),%eax
  add    $0x4,%rdx
  add    $0x4,%rdi
  mov    %al,-0x1(%rdi)
  sub    $0x4,%esi
  jne    L88
L89:
  ret
L59:
  ret
```

assistant: ```c
void byte_copy(void *To, unsigned int n, const void *From) {
  char *to = To;
  const char *from = From;
  for (;;) {
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
    if (!n)
      return;
    *to++ = *from++;
    --n;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x23,-0x1(%rbp)
  movsbl -0x1(%rbp),%edx
  movsbl -0x1(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: 
%d %c


assistant: ```c
int main() {
  char a = 291;
  printf("\n%d %c\n", a, a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%edx
  mov    $0x23,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: 
%d %c


assistant: ```c
int main() {
  char a = 291;
  printf("\n%d %c\n", a, a);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%edx
  mov    $0x23,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
type_guessed: string

tool: D7: 
%d %c


assistant: ```c
int main() {
  char a = 291;
  printf("\n%d %c\n", a, a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%edx
  mov    $0x23,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D6: 
%d %c


assistant: ```c
int main() {
  char a = 291;
  printf("\n%d %c\n", a, a);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<init_8259>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xff,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0x20,%edi
  call   <io_out8@plt>
  mov    $0x20,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x4,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0xa0,%edi
  call   <io_out8@plt>
  mov    $0x28,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x2,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0xfb,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x0,%eax
  call   <io_sti@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_8259(void) {
  io_out8(0x0021, 0xff);
  io_out8(0x00a1, 0xff);
  io_out8(0x0020, 0x11);
  io_out8(0x0021, 0x20);
  io_out8(0x0021, 1 << 2);
  io_out8(0x0021, 0x01);
  io_out8(0x00a0, 0x11);
  io_out8(0x00a1, 0x28);
  io_out8(0x00a1, 2);
  io_out8(0x00a1, 0x01);
  io_out8(0x0021, 0xfb);
  io_out8(0x00a1, 0xff);
  io_sti();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<init_8259>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0x20,%edi
  call   <io_out8@plt>
  mov    $0x20,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x4,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0xa0,%edi
  call   <io_out8@plt>
  mov    $0x28,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x2,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0xfb,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x0,%eax
  call   <io_sti@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void init_8259(void) {
  io_out8(0x0021, 0xff);
  io_out8(0x00a1, 0xff);
  io_out8(0x0020, 0x11);
  io_out8(0x0021, 0x20);
  io_out8(0x0021, 1 << 2);
  io_out8(0x0021, 0x01);
  io_out8(0x00a0, 0x11);
  io_out8(0x00a1, 0x28);
  io_out8(0x00a1, 2);
  io_out8(0x00a1, 0x01);
  io_out8(0x0021, 0xfb);
  io_out8(0x00a1, 0xff);
  io_sti();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<init_8259>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0x20,%edi
  call   <io_out8@plt>
  mov    $0x20,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x4,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0xa0,%edi
  call   <io_out8@plt>
  mov    $0x28,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x2,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0xfb,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <io_sti@plt>
```

assistant: ```c
void init_8259(void) {
  io_out8(0x0021, 0xff);
  io_out8(0x00a1, 0xff);
  io_out8(0x0020, 0x11);
  io_out8(0x0021, 0x20);
  io_out8(0x0021, 1 << 2);
  io_out8(0x0021, 0x01);
  io_out8(0x00a0, 0x11);
  io_out8(0x00a1, 0x28);
  io_out8(0x00a1, 2);
  io_out8(0x00a1, 0x01);
  io_out8(0x0021, 0xfb);
  io_out8(0x00a1, 0xff);
  io_sti();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<init_8259>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xff,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0x20,%edi
  call   <io_out8@plt>
  mov    $0x20,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x4,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0x11,%esi
  mov    $0xa0,%edi
  call   <io_out8@plt>
  mov    $0x28,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x2,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0x1,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  mov    $0xfb,%esi
  mov    $0x21,%edi
  call   <io_out8@plt>
  mov    $0xff,%esi
  mov    $0xa1,%edi
  call   <io_out8@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <io_sti@plt>
```

assistant: ```c
void init_8259(void) {
  io_out8(0x0021, 0xff);
  io_out8(0x00a1, 0xff);
  io_out8(0x0020, 0x11);
  io_out8(0x0021, 0x20);
  io_out8(0x0021, 1 << 2);
  io_out8(0x0021, 0x01);
  io_out8(0x00a0, 0x11);
  io_out8(0x00a1, 0x28);
  io_out8(0x00a1, 2);
  io_out8(0x00a1, 0x01);
  io_out8(0x0021, 0xfb);
  io_out8(0x00a1, 0xff);
  io_sti();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<name_to_uid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  cmpq   $0x0,-0x68(%rbp)
  jne    L25
  mov    $0xffffffff,%eax
  jmp    L81
L25:
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <sysconf@plt>
  mov    %rax,-0x50(%rbp)
  cmpq   $0xffffffffffffffff,-0x50(%rbp)
  jne    L56
  mov    $0xffffffff,%eax
  jmp    L81
L56:
  mov    -0x50(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,%r14
  mov    $0x0,%r15d
  mov    -0x50(%rbp),%rax
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    -0x50(%rbp),%rax
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L5:
  cmp    %rdx,%rsp
  je     L60
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L5
L60:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L16
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L16:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  lea    -0x58(%rbp),%rdi
  mov    -0x50(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  lea    -0x5c(%rbp),%rsi
  mov    -0x68(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <getpwnam_r@plt>
  test   %rax,%rax
  jne    L0
  mov    -0x58(%rbp),%rax
  test   %rax,%rax
  jne    L80
L0:
  mov    $0xffffffff,%eax
  jmp    L81
L80:
  mov    -0x58(%rbp),%rax
  mov    (%rax),%eax
L81:
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
uid_t name_to_uid(char const *name) {
  if (!name) {
    return -1;
  }
  long const buflen = sysconf(_SC_GETPW_R_SIZE_MAX);
  if (buflen == -1) {
    return -1;
  }
  char buf[buflen];
  struct passwd pwbuf, *pwbufp;
  if (0 != getpwnam_r(name, &pwbuf, buf, buflen, &pwbufp) || !pwbufp) {
    return -1;
  }
  return pwbufp->pw_uid;
}
```