ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_gethtbyname2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%edi
  call   <_sethtent@plt>
  jmp    L21
L18:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x1c(%rbp)
  je     L27
  jmp    L21
L27:
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L66
  mov    -0x8(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L97
L29:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L51
  addq   $0x8,-0x10(%rbp)
L97:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L29
L21:
  mov    $0x0,%eax
  call   <_gethtent@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  jmp    L44
L66:
  nop
  jmp    L44
L51:
  nop
L44:
  mov    $0x0,%eax
  call   <_endhtent@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct hostent *_gethtbyname2(const char *name, int af) {
  struct hostent *p;
  char **cp;
  _sethtent(0);
  while ((p = _gethtent())) {
    if (p->h_addrtype != af)
      continue;
    if (strcasecmp(p->h_name, name) == 0)
      break;
    for (cp = p->h_aliases; *cp != 0; cp++)
      if (strcasecmp(*cp, name) == 0)
        goto found;
  }
found:
  _endhtent();
  return (p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_gethtbyname2>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    $0x0,%edi
  call   <_sethtent@plt>
L38:
  mov    $0x0,%eax
  call   <_gethtent@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L30
  cmp    %r13d,(%rbx)
  jne    L38
  mov    0x8(%rbx),%rdi
  mov    %r12,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L30
  mov    0x10(%rbx),%rbp
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  je     L38
L3:
  mov    %r12,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L30
  add    $0x8,%rbp
  mov    0x0(%rbp),%rdi
  test   %rdi,%rdi
  jne    L3
  jmp    L38
L30:
  mov    $0x0,%eax
  call   <_endhtent@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct hostent *_gethtbyname2(const char *name, int af) {
  struct hostent *p;
  char **cp;
  _sethtent(0);
  while ((p = _gethtent())) {
    if (p->h_addrtype != af)
      continue;
    if (strcasecmp(p->h_name, name) == 0)
      break;
    for (cp = p->h_aliases; *cp != 0; cp++)
      if (strcasecmp(*cp, name) == 0)
        goto found;
  }
found:
  _endhtent();
  return (p);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_gethtbyname2>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <_sethtent@plt>
  nopl   0x0(%rax,%rax,1)
L60:
  xor    %eax,%eax
  call   <_gethtent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L42
  cmp    %r13d,(%r12)
  jne    L60
  mov    0x8(%r12),%rdi
  mov    %rbp,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L42
  mov    0x10(%r12),%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L56
  jmp    L60
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L60
L56:
  mov    %rbp,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L53
L42:
  xor    %eax,%eax
  call   <_endhtent@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct hostent *_gethtbyname2(const char *name, int af) {
  struct hostent *p;
  char **cp;
  _sethtent(0);
  while ((p = _gethtent())) {
    if (p->h_addrtype != af)
      continue;
    if (strcasecmp(p->h_name, name) == 0)
      break;
    for (cp = p->h_aliases; *cp != 0; cp++)
      if (strcasecmp(*cp, name) == 0)
        goto found;
  }
found:
  _endhtent();
  return (p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_gethtbyname2>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <_sethtent@plt>
  nopl   0x0(%rax,%rax,1)
L69:
  xor    %eax,%eax
  call   <_gethtent@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L66
  cmp    %r13d,(%r12)
  jne    L69
  mov    0x8(%r12),%rdi
  mov    %rbp,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  je     L66
  mov    0x10(%r12),%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L57
  jmp    L69
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  je     L69
L57:
  mov    %rbp,%rsi
  call   <strcasecmp@plt>
  test   %rax,%rax
  jne    L34
L66:
  xor    %eax,%eax
  call   <_endhtent@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
struct hostent *_gethtbyname2(const char *name, int af) {
  struct hostent *p;
  char **cp;
  _sethtent(0);
  while ((p = _gethtent())) {
    if (p->h_addrtype != af)
      continue;
    if (strcasecmp(p->h_name, name) == 0)
      break;
    for (cp = p->h_aliases; *cp != 0; cp++)
      if (strcasecmp(*cp, name) == 0)
        goto found;
  }
found:
  _endhtent();
  return (p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_cgc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <is_cnpj@plt>
  test   %rax,%rax
  je     L6
  movl   $0x2,-0x30(%rbp)
  movl   $0x1,-0x2c(%rbp)
  movl   $0x2,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x2,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  mov    $0xf4240,%esi
  mov    %eax,%edi
  call   <lldiv@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  jmp    L8
L62:
  movl   $0x0,-0x3c(%rbp)
  mov    -0x44(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <lldiv@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x34(%rbp),%edx
  mov    $0x7,%eax
  sub    -0x40(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   %edx,%eax
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x9,-0x3c(%rbp)
  jle    L45
  mov    -0x3c(%rbp),%eax
  sub    $0x9,%eax
  jmp    L20
L45:
  mov    -0x3c(%rbp),%eax
L20:
  add    %eax,-0x48(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x44(%rbp)
  addl   $0x1,-0x40(%rbp)
L8:
  cmpl   $0x7,-0x40(%rbp)
  jle    L62
  mov    -0x48(%rbp),%eax
  mov    $0xa,%esi
  mov    %eax,%edi
  call   <lldiv@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x34(%rbp),%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L24
L6:
  mov    $0x0,%eax
L24:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int is_cgc(long long cgc_l) {
  if (is_cnpj(cgc_l)) {
    int weights[] = {2, 1, 2, 1, 2, 1, 2, 1};
    int sum = 0, radix = 0, i = 0;
    lldiv_t division;
    division = lldiv(cgc_l, 1000000);
    radix = (int)division.quot;
    for (i = 0; i < 8; i++) {
      int product = 0;
      division = lldiv(radix, 10);
      product = division.rem * weights[7 - i];
      sum += (product > 9) ? product - 9 : product;
      radix = division.quot;
    }
    division = lldiv(sum, 10);
    return !division.rem;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<is_cgc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <is_cnpj@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L19
L42:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x2,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x2,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  mov    $0xf4240,%esi
  mov    %ebx,%edi
  call   <lldiv@plt>
  mov    %eax,%edi
  mov    %rsp,%r12
  lea    0x1c(%rsp),%rbx
  mov    $0x0,%ebp
  jmp    L13
L46:
  mov    %rax,%rbx
L13:
  mov    $0xa,%esi
  call   <lldiv@plt>
  mov    %rax,%rdx
  mov    %eax,%edi
  sar    $0x20,%rdx
  imul   (%rbx),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x9,%edx
  cmovg  %eax,%edx
  add    %edx,%ebp
  lea    -0x4(%rbx),%rax
  cmp    %r12,%rbx
  jne    L46
  mov    $0xa,%esi
  mov    %ebp,%edi
  call   <lldiv@plt>
  sar    $0x20,%rax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L42
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_cgc(long long cgc_l) {
  if (is_cnpj(cgc_l)) {
    int weights[] = {2, 1, 2, 1, 2, 1, 2, 1};
    int sum = 0, radix = 0, i = 0;
    lldiv_t division;
    division = lldiv(cgc_l, 1000000);
    radix = (int)division.quot;
    for (i = 0; i < 8; i++) {
      int product = 0;
      division = lldiv(radix, 10);
      product = division.rem * weights[7 - i];
      sum += (product > 9) ? product - 9 : product;
      radix = division.quot;
    }
    division = lldiv(sum, 10);
    return !division.rem;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<is_cgc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <is_cnpj@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L37
L11:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  mov    %ebx,%edi
  mov    $0xf4240,%esi
  mov    %rsp,%rbp
  xor    %r12d,%r12d
  movabs $0x100000002,%rax
  lea    0x1c(%rsp),%rbx
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x18(%rsp)
  call   <lldiv@plt>
  mov    %eax,%edi
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L45:
  mov    %rax,%rbx
L5:
  mov    $0xa,%esi
  call   <lldiv@plt>
  mov    %rax,%rdx
  mov    %eax,%edi
  sar    $0x20,%rdx
  imul   (%rbx),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x9,%edx
  cmovg  %eax,%edx
  lea    -0x4(%rbx),%rax
  add    %edx,%r12d
  cmp    %rbp,%rbx
  jne    L45
  mov    $0xa,%esi
  mov    %r12d,%edi
  call   <lldiv@plt>
  sar    $0x20,%rax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L11
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int is_cgc(long long cgc_l) {
  if (is_cnpj(cgc_l)) {
    int weights[] = {2, 1, 2, 1, 2, 1, 2, 1};
    int sum = 0, radix = 0, i = 0;
    lldiv_t division;
    division = lldiv(cgc_l, 1000000);
    radix = (int)division.quot;
    for (i = 0; i < 8; i++) {
      int product = 0;
      division = lldiv(radix, 10);
      product = division.rem * weights[7 - i];
      sum += (product > 9) ? product - 9 : product;
      radix = division.quot;
    }
    division = lldiv(sum, 10);
    return !division.rem;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_cgc>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <is_cnpj@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L6
L16:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  movdqa D4(%rip),%xmm0
  mov    %ebx,%edi
  mov    %rsp,%rbp
  xor    %r12d,%r12d
  mov    $0xf4240,%esi
  lea    0x1c(%rsp),%rbx
  movaps %xmm0,(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <lldiv@plt>
  mov    %eax,%edi
  jmp    L19
  nopl   0x0(%rax)
L47:
  mov    %rax,%rbx
L19:
  mov    $0xa,%esi
  call   <lldiv@plt>
  mov    %rax,%rdx
  mov    %eax,%edi
  sar    $0x20,%rdx
  imul   (%rbx),%edx
  lea    -0x9(%rdx),%eax
  cmp    $0x9,%edx
  cmovg  %eax,%edx
  lea    -0x4(%rbx),%rax
  add    %edx,%r12d
  cmp    %rbx,%rbp
  jne    L47
  mov    $0xa,%esi
  mov    %r12d,%edi
  call   <lldiv@plt>
  sar    $0x20,%rax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: byte[16]

tool: {"D4": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int is_cgc(long long cgc_l) {
  if (is_cnpj(cgc_l)) {
    int weights[] = {2, 1, 2, 1, 2, 1, 2, 1};
    int sum = 0, radix = 0, i = 0;
    lldiv_t division;
    division = lldiv(cgc_l, 1000000);
    radix = (int)division.quot;
    for (i = 0; i < 8; i++) {
      int product = 0;
      division = lldiv(radix, 10);
      product = division.rem * weights[7 - i];
      sum += (product > 9) ? product - 9 : product;
      radix = division.quot;
    }
    division = lldiv(sum, 10);
    return !division.rem;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L19
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D24
datatype: string
name: disassemble_data
arguments: data_label: D16
datatype: string

tool: D24: %d


tool: D16: 52

assistant: ```c
main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%d\n", atoi(argv[i]));
  printf("%d\n", atoi("52"));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L13
  lea    0x8(%rsi),%rbx
  lea    -0x2(%rdi),%eax
  lea    0x10(%rsi,%rax,8),%r12
  lea    D16(%rip),%rbp
L1:
  mov    (%rbx),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L1
L13:
  lea    D14(%rip),%rdi
  call   <atoi@plt>
  mov    %eax,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D16: %d


tool: D14: 52

assistant: ```c
main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%d\n", atoi(argv[i]));
  printf("%d\n", atoi("52"));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L7
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
L11:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L11
L7:
  lea    D19(%rip),%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string

tool: D6: %d


tool: D19: 52

assistant: ```c
main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%d\n", atoi(argv[i]));
  printf("%d\n", atoi("52"));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  cmp    $0x1,%edi
  jle    L17
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi),%rbx
  lea    0x10(%rsi,%rax,8),%r12
L16:
  mov    (%rbx),%rdi
  add    $0x8,%rbx
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L16
L17:
  lea    D19(%rip),%rdi
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
data_type: string
name: unpack_data
arguments: tag: D19
data_type: string

tool: D5: %d


tool: D19: 52

assistant: ```c
main(int argc, char **argv) {
  int i;
  for (i = 1; i < argc; i++)
    printf("%d\n", atoi(argv[i]));
  printf("%d\n", atoi("52"));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0x8(%rbp)
  movl   $0x4,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ackermann@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string

tool: D9: ackermann(%d, %d) = %d


assistant: ```c
int main() {
  int m = 3;
  int n = 4;
  printf("ackermann(%d, %d) = %d\n", m, n, ackermann(m, n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <ackermann@plt>
  mov    %eax,%ecx
  mov    $0x4,%edx
  mov    $0x3,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type: string

tool: D0: ackermann(%d, %d) = %d


assistant: ```c
int main() {
  int m = 3;
  int n = 4;
  printf("ackermann(%d, %d) = %d\n", m, n, ackermann(m, n));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <ackermann@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string

tool: D0: ackermann(%d, %d) = %d


assistant: ```c
int main() {
  int m = 3;
  int n = 4;
  printf("ackermann(%d, %d) = %d\n", m, n, ackermann(m, n));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x3,%edi
  call   <ackermann@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  lea    D6(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string

tool: D6: ackermann(%d, %d) = %d


assistant: ```c
int main() {
  int m = 3;
  int n = 4;
  printf("ackermann(%d, %d) = %d\n", m, n, ackermann(m, n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<PECIDomainConfigSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  cmpq   $0x400b0000,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <PECIDomainValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpq   $0xffff,-0x18(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmpq   $0xffff,-0x20(%rbp)
  setbe  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  seta   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  mov    -0x18(%rbp),%rax
  shl    $0x10,%rax
  mov    %eax,%esi
  mov    -0x20(%rbp),%rax
  movzwl %ax,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  add    $0x10,%rax
  mov    %rax,%rdx
  mov    %rsi,%rax
  or     %rcx,%rax
  mov    %rax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void PECIDomainConfigSet(unsigned long ulBase, unsigned long ulDomain, unsigned long ulHigh, unsigned long ulLow) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(PECIDomainValid(ulDomain));
  DEBUG_ASSERT(ulHigh <= 0xFFFF);
  DEBUG_ASSERT(ulLow <= 0xFFFF);
  DEBUG_ASSERT(ulHigh > ulLow);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulDomain * 4)))) = (((ulHigh << 16) & 0xFFFF0000) | ((ulLow << 0) & 0x0000FFFF));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PECIDomainConfigSet>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  cmp    $0x400b0000,%rdi
  sete   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  mov    %r13,%rdi
  call   <PECIDomainValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  cmp    $0xffff,%rbx
  setbe  %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  cmp    $0xffff,%rbp
  setbe  %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  cmp    %rbp,%rbx
  seta   %dil
  movzbl %dil,%edi
  call   <DEBUG_ASSERT@plt>
  lea    0x10(%r12,%r13,4),%rax
  shl    $0x10,%rbx
  mov    %ebx,%ebx
  movzwl %bp,%ebp
  or     %rbp,%rbx
  mov    %rbx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void PECIDomainConfigSet(unsigned long ulBase, unsigned long ulDomain, unsigned long ulHigh, unsigned long ulLow) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(PECIDomainValid(ulDomain));
  DEBUG_ASSERT(ulHigh <= 0xFFFF);
  DEBUG_ASSERT(ulLow <= 0xFFFF);
  DEBUG_ASSERT(ulHigh > ulLow);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulDomain * 4)))) = (((ulHigh << 16) & 0xFFFF0000) | ((ulLow << 0) & 0x0000FFFF));
}
```
user: What is the c source code of the assembly code below:

```asm
<PECIDomainConfigSet>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  xor    %edi,%edi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  cmp    $0x400b0000,%r12
  sete   %dil
  call   <DEBUG_ASSERT@plt>
  mov    %r13,%rdi
  call   <PECIDomainValid@plt>
  mov    %eax,%edi
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0xffff,%rbx
  setbe  %dil
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    $0xffff,%rbp
  setbe  %dil
  call   <DEBUG_ASSERT@plt>
  xor    %edi,%edi
  cmp    %rbp,%rbx
  movzwl %bp,%ebp
  seta   %dil
  shl    $0x10,%rbx
  call   <DEBUG_ASSERT@plt>
  mov    %ebx,%ebx
  lea    0x10(%r12,%r13,4),%rax
  or     %rbp,%rbx
  mov    %rbx,(%rax)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void PECIDomainConfigSet(unsigned long ulBase, unsigned long ulDomain, unsigned long ulHigh, unsigned long ulLow) {
  DEBUG_ASSERT(ulBase == 0x400B0000);
  DEBUG_ASSERT(PECIDomainValid(ulDomain));
  DEBUG_ASSERT(ulHigh <= 0xFFFF);
  DEBUG_ASSERT(ulLow <= 0xFFFF);
  DEBUG_ASSERT(ulHigh > ulLow);
  (*((volatile unsigned long *)(ulBase + 0x00000010 + (ulDomain * 4)))) = (((ulHigh << 16) & 0xFFFF0000) | ((ulLow << 0) & 0x0000FFFF));
}
```