ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<_get_new_sar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <_syscall_malloc@plt>
  mov    %rax,%rdx
  movabs 0x300003000,%rax
  mov    %rdx,(%rax)
  add    %rdx,%rbx
  mov    %rbx,0x8(%rax)
  add    %rdx,%rbp
  mov    %rbp,0x10(%rax)
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *_get_new_sar(long size, long align_size) {
  char *ret;
  long last_element;
  ret = _syscall_malloc(align_size);
  last_element = *(long *)(0x300003000);
  *(char **)last_element = ret;
  *((char **)(last_element + 8)) = ret + align_size;
  *((char **)(last_element + 16)) = ret + size;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_get_new_sar>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <_syscall_malloc@plt>
  mov    %rax,%r8
  movabs 0x300003000,%rax
  add    %r8,%rbx
  add    %r8,%rbp
  mov    %r8,(%rax)
  mov    %rbx,0x8(%rax)
  mov    %rbp,0x10(%rax)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *_get_new_sar(long size, long align_size) {
  char *ret;
  long last_element;
  ret = _syscall_malloc(align_size);
  last_element = *(long *)(0x300003000);
  *(char **)last_element = ret;
  *((char **)(last_element + 8)) = ret + align_size;
  *((char **)(last_element + 16)) = ret + size;
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_get_new_sar>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <_syscall_malloc@plt>
  mov    %rax,%r8
  movabs 0x300003000,%rax
  add    %r8,%rbx
  movq   %r8,%xmm0
  add    %r8,%rbp
  movq   %rbx,%xmm1
  mov    %rbp,0x10(%rax)
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rax)
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *_get_new_sar(long size, long align_size) {
  char *ret;
  long last_element;
  ret = _syscall_malloc(align_size);
  last_element = *(long *)(0x300003000);
  *(char **)last_element = ret;
  *((char **)(last_element + 8)) = ret + align_size;
  *((char **)(last_element + 16)) = ret + size;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  mov    %edx,%eax
  test   %edx,%edx
  je     L56
  test   $0x1,%dil
  je     L70
  lea    0x1(%rsi),%r8
  lea    0x1(%rdi),%rdx
  movzbl (%rsi),%ecx
  mov    %cl,(%rdi)
  sub    $0x1,%eax
  test   $0x1,%sil
  je     L140
L217:
  cmp    $0x2,%eax
  jbe    L184
  test   $0x2,%dl
  je     L137
  movzwl (%r8),%ecx
  mov    %cx,(%rdx)
  sub    $0x2,%eax
  lea    0x2(%r8),%r8
  lea    0x2(%rdx),%rdx
L184:
  test   $0x2,%r8b
  jne    L34
L42:
  mov    %eax,%r9d
  shr    $0x2,%r9d
  je     L50
  mov    %r9d,%r9d
  mov    $0x0,%ecx
L53:
  mov    (%r8,%rcx,8),%rsi
  mov    %rsi,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %r9,%rcx
  jne    L53
  shl    $0x3,%r9
  add    %r9,%r8
  add    %r9,%rdx
L50:
  test   $0x2,%al
  je     L94
  movzwl (%r8),%ecx
  mov    %cx,(%rdx)
  lea    0x2(%r8),%r8
  lea    0x2(%rdx),%rdx
L94:
  test   $0x1,%al
  je     L56
  movzbl (%r8),%eax
  mov    %al,(%rdx)
  jmp    L56
L140:
  mov    %r8,%rsi
  test   %eax,%eax
  jne    L9
  jmp    L56
L206:
  mov    %rdi,%rdx
L9:
  lea    -0x1(%rax),%r8d
  mov    $0x0,%eax
L29:
  movzbl (%rsi,%rax,1),%ecx
  mov    %cl,(%rdx,%rax,1)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %r8,%rcx
  jne    L29
L56:
  mov    %rdi,%rax
  ret
L34:
  mov    %eax,%ecx
  shr    %ecx
  je     L27
L51:
  lea    -0x1(%rcx),%r9d
  lea    0x1(%r9),%r10
  mov    $0x0,%ecx
L166:
  movzwl (%r8,%rcx,2),%esi
  mov    %si,(%rdx,%rcx,2)
  mov    %rcx,%rsi
  add    $0x1,%rcx
  cmp    %r9,%rsi
  jne    L166
  lea    (%r10,%r10,1),%rcx
  add    %rcx,%r8
  add    %rcx,%rdx
L27:
  test   $0x1,%al
  je     L56
  movzbl (%r8),%eax
  mov    %al,(%rdx)
  jmp    L56
L137:
  test   $0x2,%r8b
  je     L42
  mov    %eax,%ecx
  shr    %ecx
  jmp    L51
L70:
  test   $0x1,%sil
  jne    L206
  mov    %rsi,%r8
  mov    %rdi,%rdx
  jmp    L217
```

assistant: ```c
void *memcpy(void *to, const void *from, unsigned int n) {
  void *xto = to;
  unsigned int temp;
  if (!n)
    return xto;
  if ((long)to & 1) {
    char *cto = to;
    const char *cfrom = from;
    *cto++ = *cfrom++;
    to = cto;
    from = cfrom;
    n--;
  }
  if ((long)from & 1) {
    char *cto = to;
    const char *cfrom = from;
    for (; n; n--)
      *cto++ = *cfrom++;
    return xto;
  }
  if (n > 2 && (long)to & 2) {
    short *sto = to;
    const short *sfrom = from;
    *sto++ = *sfrom++;
    to = sto;
    from = sfrom;
    n -= 2;
  }
  if ((long)from & 2) {
    short *sto = to;
    const short *sfrom = from;
    temp = n >> 1;
    for (; temp; temp--)
      *sto++ = *sfrom++;
    to = sto;
    from = sfrom;
    if (n & 1) {
      char *cto = to;
      const char *cfrom = from;
      *cto = *cfrom;
    }
    return xto;
  }
  temp = n >> 2;
  if (temp) {
    long *lto = to;
    const long *lfrom = from;
    for (; temp; temp--)
      *lto++ = *lfrom++;
    to = lto;
    from = lfrom;
  }
  if (n & 2) {
    short *sto = to;
    const short *sfrom = from;
    *sto++ = *sfrom++;
    to = sto;
    from = sfrom;
  }
  if (n & 1) {
    char *cto = to;
    const char *cfrom = from;
    *cto = *cfrom;
  }
  return xto;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %edx,%eax
  test   %edx,%edx
  je     L29
  test   $0x1,%dil
  jne    L166
  test   $0x1,%sil
  jne    L191
  mov    %rsi,%rcx
L131:
  cmp    $0x2,%eax
  jbe    L193
  test   $0x2,%dil
  je     L177
  movzwl (%rcx),%edx
  sub    $0x2,%eax
  add    $0x2,%rcx
  add    $0x2,%rdi
  mov    %dx,-0x2(%rdi)
L193:
  test   $0x2,%cl
  jne    L61
L71:
  mov    %eax,%r9d
  shr    $0x2,%r9d
  je     L138
  mov    %r9d,%r9d
  xor    %edx,%edx
  nopl   0x0(%rax,%rax,1)
L128:
  mov    (%rcx,%rdx,8),%rsi
  mov    %rsi,(%rdi,%rdx,8)
  add    $0x1,%rdx
  cmp    %r9,%rdx
  jne    L128
  shl    $0x3,%rdx
  add    %rdx,%rcx
  add    %rdx,%rdi
L138:
  test   $0x2,%al
  jne    L37
L164:
  test   $0x1,%al
  je     L29
  movzbl (%rcx),%eax
  mov    %al,(%rdi)
L29:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L166:
  movzbl (%rsi),%edx
  lea    0x1(%rsi),%rcx
  sub    $0x1,%eax
  and    $0x1,%esi
  lea    0x1(%rdi),%rdi
  mov    %dl,(%r8)
  jne    L131
  mov    %rcx,%rsi
  test   %eax,%eax
  je     L29
L57:
  mov    %eax,%ecx
  xor    %eax,%eax
  nopl   (%rax)
L32:
  movzbl (%rsi,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L32
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L37:
  movzwl (%rcx),%edx
  add    $0x2,%rdi
  add    $0x2,%rcx
  mov    %dx,-0x2(%rdi)
  jmp    L164
  nopl   0x0(%rax)
L177:
  test   $0x2,%cl
  je     L71
  mov    %eax,%r9d
  shr    %r9d
  jmp    L82
  nopl   0x0(%rax)
L191:
  mov    %r8,%rdi
  jmp    L57
  nopl   (%rax)
L61:
  mov    %eax,%r9d
  shr    %r9d
  je     L164
L82:
  mov    %r9d,%r9d
  xor    %edx,%edx
  nopl   0x0(%rax)
L151:
  movzwl (%rcx,%rdx,2),%esi
  mov    %si,(%rdi,%rdx,2)
  add    $0x1,%rdx
  cmp    %r9,%rdx
  jne    L151
  add    %rdx,%rdx
  add    %rdx,%rcx
  add    %rdx,%rdi
  jmp    L164
```

assistant: ```c
void *memcpy(void *to, const void *from, unsigned int n) {
  void *xto = to;
  unsigned int temp;
  if (!n)
    return xto;
  if ((long)to & 1) {
    char *cto = to;
    const char *cfrom = from;
    *cto++ = *cfrom++;
    to = cto;
    from = cfrom;
    n--;
  }
  if ((long)from & 1) {
    char *cto = to;
    const char *cfrom = from;
    for (; n; n--)
      *cto++ = *cfrom++;
    return xto;
  }
  if (n > 2 && (long)to & 2) {
    short *sto = to;
    const short *sfrom = from;
    *sto++ = *sfrom++;
    to = sto;
    from = sfrom;
    n -= 2;
  }
  if ((long)from & 2) {
    short *sto = to;
    const short *sfrom = from;
    temp = n >> 1;
    for (; temp; temp--)
      *sto++ = *sfrom++;
    to = sto;
    from = sfrom;
    if (n & 1) {
      char *cto = to;
      const char *cfrom = from;
      *cto = *cfrom;
    }
    return xto;
  }
  temp = n >> 2;
  if (temp) {
    long *lto = to;
    const long *lfrom = from;
    for (; temp; temp--)
      *lto++ = *lfrom++;
    to = lto;
    from = lfrom;
  }
  if (n & 2) {
    short *sto = to;
    const short *sfrom = from;
    *sto++ = *sfrom++;
    to = sto;
    from = sfrom;
  }
  if (n & 1) {
    char *cto = to;
    const char *cfrom = from;
    *cto = *cfrom;
  }
  return xto;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SumDivisibleBy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    $0x3e7,%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  imul   -0x4(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  pop    %rbp
  ret
```

assistant: ```c
int SumDivisibleBy(int num) {
  int p = 999 / num;
  return num * (p * (p + 1)) / 2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<SumDivisibleBy>:
  endbr64
  mov    $0x3e7,%eax
  cltd
  idiv   %edi
  lea    0x1(%rax),%edx
  imul   %edx,%eax
  imul   %edi,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  ret
```

assistant: ```c
int SumDivisibleBy(int num) {
  int p = 999 / num;
  return num * (p * (p + 1)) / 2;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<SumDivisibleBy>:
  endbr64
  mov    $0x3e7,%eax
  cltd
  idiv   %edi
  lea    0x1(%rax),%edx
  imul   %edx,%eax
  imul   %edi,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  ret
```

assistant: ```c
int SumDivisibleBy(int num) {
  int p = 999 / num;
  return num * (p * (p + 1)) / 2;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<SumDivisibleBy>:
  endbr64
  mov    $0x3e7,%eax
  cltd
  idiv   %edi
  lea    0x1(%rax),%edx
  imul   %edx,%eax
  imul   %edi,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  ret
```

assistant: ```c
int SumDivisibleBy(int num) {
  int p = 999 / num;
  return num * (p * (p + 1)) / 2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gfarm_timeval_normalize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0xf423f,%eax
  jle    L10
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  imul   $0xfff0bdc0,%eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
  jmp    L24
L10:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jns    L24
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x431bde83,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x12,%edx
  sar    $0x1f,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  imul   $0xf4240,%eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    0x8(%rax),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,0x8(%rax)
L24:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gfarm_timeval_normalize(struct timeval *t) {
  long n;
  if (t->tv_usec >= 1000000) {
    n = t->tv_usec / 1000000;
    t->tv_usec -= n * 1000000;
    t->tv_sec += n;
  } else if (t->tv_usec < 0) {
    n = -t->tv_usec / 1000000 + 1;
    t->tv_usec += n * 1000000;
    t->tv_sec -= n;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gfarm_timeval_normalize>:
  endbr64
  mov    (%rdi),%ecx
  cmp    $0xf423f,%ecx
  jle    L5
  movslq %ecx,%rdx
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x32,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  imul   $0xfff0bdc0,%edx,%esi
  add    %esi,%ecx
  mov    %ecx,(%rdi)
  movslq %edx,%rdx
  add    %rdx,0x8(%rdi)
  ret
L5:
  test   %ecx,%ecx
  js     L6
L20:
  ret
L6:
  movslq %ecx,%rsi
  imul   $0x431bde83,%rsi,%rsi
  sar    $0x32,%rsi
  mov    %ecx,%edx
  sar    $0x1f,%edx
  sub    %esi,%edx
  add    $0x1,%edx
  imul   $0xf4240,%edx,%esi
  add    %esi,%ecx
  mov    %ecx,(%rdi)
  movslq %edx,%rdx
  sub    %rdx,0x8(%rdi)
  jmp    L20
```

assistant: ```c
void gfarm_timeval_normalize(struct timeval *t) {
  long n;
  if (t->tv_usec >= 1000000) {
    n = t->tv_usec / 1000000;
    t->tv_usec -= n * 1000000;
    t->tv_sec += n;
  } else if (t->tv_usec < 0) {
    n = -t->tv_usec / 1000000 + 1;
    t->tv_usec += n * 1000000;
    t->tv_sec -= n;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gfarm_timeval_normalize>:
  endbr64
  mov    (%rdi),%ecx
  cmp    $0xf423f,%ecx
  jle    L1
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x32,%rdx
  sub    %esi,%edx
  imul   $0xfff0bdc0,%edx,%esi
  movslq %edx,%rdx
  add    %rdx,0x8(%rdi)
  add    %esi,%ecx
  mov    %ecx,(%rdi)
  ret
  nopl   (%rax)
L1:
  test   %ecx,%ecx
  js     L19
  ret
  nopl   (%rax)
L19:
  movslq %ecx,%rsi
  mov    %ecx,%edx
  imul   $0x431bde83,%rsi,%rsi
  sar    $0x1f,%edx
  sar    $0x32,%rsi
  sub    %esi,%edx
  add    $0x1,%edx
  imul   $0xf4240,%edx,%esi
  movslq %edx,%rdx
  sub    %rdx,0x8(%rdi)
  add    %esi,%ecx
  mov    %ecx,(%rdi)
  ret
```

assistant: ```c
void gfarm_timeval_normalize(struct timeval *t) {
  long n;
  if (t->tv_usec >= 1000000) {
    n = t->tv_usec / 1000000;
    t->tv_usec -= n * 1000000;
    t->tv_sec += n;
  } else if (t->tv_usec < 0) {
    n = -t->tv_usec / 1000000 + 1;
    t->tv_usec += n * 1000000;
    t->tv_sec -= n;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gfarm_timeval_normalize>:
  endbr64
  mov    (%rdi),%ecx
  cmp    $0xf423f,%ecx
  jle    L1
  movslq %ecx,%rdx
  mov    %ecx,%esi
  imul   $0x431bde83,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x32,%rdx
  sub    %esi,%edx
  imul   $0xfff0bdc0,%edx,%esi
  movslq %edx,%rdx
  add    %rdx,0x8(%rdi)
  add    %esi,%ecx
  mov    %ecx,(%rdi)
  ret
  nopl   (%rax)
L1:
  test   %ecx,%ecx
  js     L6
  ret
  nopl   (%rax)
L6:
  movslq %ecx,%rsi
  mov    %ecx,%edx
  imul   $0x431bde83,%rsi,%rsi
  sar    $0x1f,%edx
  sar    $0x32,%rsi
  sub    %esi,%edx
  add    $0x1,%edx
  imul   $0xf4240,%edx,%esi
  movslq %edx,%rdx
  sub    %rdx,0x8(%rdi)
  add    %esi,%ecx
  mov    %ecx,(%rdi)
  ret
```

assistant: ```c
void gfarm_timeval_normalize(struct timeval *t) {
  long n;
  if (t->tv_usec >= 1000000) {
    n = t->tv_usec / 1000000;
    t->tv_usec -= n * 1000000;
    t->tv_sec += n;
  } else if (t->tv_usec < 0) {
    n = -t->tv_usec / 1000000 + 1;
    t->tv_usec += n * 1000000;
    t->tv_sec -= n;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pslr_copyright>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D6(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_guessed: string

tool: D6: Copyright (C) 2011-2019 Andras Salamon

Based on:
pslr-shoot (C) 2009 Ramiro Barreiro
PK-Remote (C) 2008 Pontus Lidman 



assistant: ```c
char *pslr_copyright() {
  char *ret = malloc(sizeof(char) * 1024);
  sprintf(ret, "Copyright (C) 2011-2019 Andras Salamon\n\nBased on:\npslr-shoot (C) 2009 Ramiro Barreiro\nPK-Remote (C) 2008 Pontus Lidman \n\n");
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<pslr_copyright>:
  endbr64
  push   %rbx
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: Copyright (C) 2011-2019 Andras Salamon

Based on:
pslr-shoot (C) 2009 Ramiro Barreiro
PK-Remote (C) 2008 Pontus Lidman 



assistant: ```c
char *pslr_copyright() {
  char *ret = malloc(sizeof(char) * 1024);
  sprintf(ret, "Copyright (C) 2011-2019 Andras Salamon\n\nBased on:\npslr-shoot (C) 2009 Ramiro Barreiro\nPK-Remote (C) 2008 Pontus Lidman \n\n");
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<pslr_copyright>:
  endbr64
  push   %r12
  mov    $0x400,%edi
  call   <malloc@plt>
  lea    D2(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D2
datatype: string

tool: D2: Copyright (C) 2011-2019 Andras Salamon

Based on:
pslr-shoot (C) 2009 Ramiro Barreiro
PK-Remote (C) 2008 Pontus Lidman 



assistant: ```c
char *pslr_copyright() {
  char *ret = malloc(sizeof(char) * 1024);
  sprintf(ret, "Copyright (C) 2011-2019 Andras Salamon\n\nBased on:\npslr-shoot (C) 2009 Ramiro Barreiro\nPK-Remote (C) 2008 Pontus Lidman \n\n");
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<pslr_copyright>:
  endbr64
  push   %r12
  mov    $0x400,%edi
  call   <malloc@plt>
  lea    D1(%rip),%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D1
type: string

tool: D1: Copyright (C) 2011-2019 Andras Salamon

Based on:
pslr-shoot (C) 2009 Ramiro Barreiro
PK-Remote (C) 2008 Pontus Lidman 



assistant: ```c
char *pslr_copyright() {
  char *ret = malloc(sizeof(char) * 1024);
  sprintf(ret, "Copyright (C) 2011-2019 Andras Salamon\n\nBased on:\npslr-shoot (C) 2009 Ramiro Barreiro\nPK-Remote (C) 2008 Pontus Lidman \n\n");
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<run_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L8
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <run_start@plt>
  jmp    L3
L8:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L37
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <run_interactive@plt>
  jmp    L3
L37:
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L3:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
data_type: string
name: parse_data
arguments: data_tag: D23
data_type: string
name: parse_data
arguments: data_tag: D27
data_type: string

tool: D8: run

tool: D23: interactive

tool: D27: There is no command '%s'


assistant: ```c
int run_command(int argc, char **argv) {
  if (!strcmp("run", argv[1]))
    return run_start(argc, argv);
  if (!strcmp("interactive", argv[1]))
    return run_interactive(argc, argv);
  printf("There is no command '%s'\n", argv[1]);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<run_command>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L33
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L37
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <run_start@plt>
  jmp    L36
L37:
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <run_interactive@plt>
  jmp    L36
```

tool_calls: name: retrieve_data
arguments: data_tag: D10
datatype: string
name: retrieve_data
arguments: data_tag: D4
datatype: string
name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D10: run

tool: D4: interactive

tool: D2: There is no command '%s'


assistant: ```c
int run_command(int argc, char **argv) {
  if (!strcmp("run", argv[1]))
    return run_start(argc, argv);
  if (!strcmp("interactive", argv[1]))
    return run_interactive(argc, argv);
  printf("There is no command '%s'\n", argv[1]);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<run_command>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  lea    D10(%rip),%rdi
  push   %r12
  push   %rbp
  mov    0x8(%rsi),%r12
  mov    %rsi,%rbp
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L13
  mov    %r12,%rsi
  lea    D12(%rip),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L14
  mov    %r12,%rsi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <run_interactive@plt>
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <run_start@plt>
```

tool_calls: name: parse_data
arguments: label: D10
data_type: string
name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D11
data_type: string

tool: D10: run

tool: D12: interactive

tool: D11: There is no command '%s'


assistant: ```c
int run_command(int argc, char **argv) {
  if (!strcmp("run", argv[1]))
    return run_start(argc, argv);
  if (!strcmp("interactive", argv[1]))
    return run_interactive(argc, argv);
  printf("There is no command '%s'\n", argv[1]);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<run_command>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  mov    0x8(%rsi),%r12
  mov    %rsi,%rbp
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L8
  mov    %r12,%rsi
  lea    D20(%rip),%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L18
  mov    %r12,%rsi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  pop    %rbp
  mov    $0x1,%eax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1090 <run_interactive@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %rbp,%rsi
  mov    %r13d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <run_start@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string
name: retrieve_data
arguments: tag: D24
type_infered: string

tool: D2: run

tool: D20: interactive

tool: D24: There is no command '%s'


assistant: ```c
int run_command(int argc, char **argv) {
  if (!strcmp("run", argv[1]))
    return run_start(argc, argv);
  if (!strcmp("interactive", argv[1]))
    return run_interactive(argc, argv);
  printf("There is no command '%s'\n", argv[1]);
  return 1;
}
```