ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcmp_natural_tiebroken>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  lea    0x1(%rdi),%r12
  push   %rbp
  lea    0x1(%rsi),%rbp
  push   %rbx
  movzbl 0x1(%rdi),%ebx
  movzbl 0x1(%rsi),%r13d
L80:
  movsbl %bl,%r14d
  mov    %r14d,%edi
  call   <is_not_nzdigit@plt>
  test   %rax,%rax
  je     L162
  movsbl %r13b,%edi
  call   <is_not_nzdigit@plt>
  test   %rax,%rax
  je     L162
L122:
  cmp    %r13b,%bl
  je     L164
  lea    -0x61(%rbx),%edx
  lea    -0x20(%rbx),%eax
  cmp    $0x1a,%dl
  lea    -0x61(%r13),%edx
  cmovb  %eax,%ebx
  lea    -0x20(%r13),%eax
  cmp    $0x1a,%dl
  cmovb  %eax,%r13d
  cmp    %r13b,%bl
  jl     L88
  jg     L46
L53:
  movzbl 0x1(%r12),%ebx
  movzbl 0x1(%rbp),%r13d
  add    $0x1,%r12
  add    $0x1,%rbp
  jmp    L80
  nopl   0x0(%rax)
L162:
  mov    %r14d,%edi
  call   <is_not_nzdigit@plt>
  test   %rax,%rax
  jne    L116
  movsbl %r13b,%edi
  call   <is_not_nzdigit@plt>
  test   %rax,%rax
  je     L41
  jmp    L116
  nopl   0x0(%rax)
L166:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%r13d
  mov    %edi,%ebx
  call   <is_digit@plt>
  test   %rax,%rax
  je     L4
L41:
  cmp    %r13b,%bl
  je     L166
  movsbl %r13b,%edi
  call   <is_digit@plt>
  test   %rax,%rax
  je     L46
  cmp    %r13b,%bl
  jl     L107
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcmp_natural_scan_forward@plt>
  pop    %rbx
  pop    %rbp
  neg    %eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L164:
  test   %bl,%bl
  jne    L53
L88:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  movsbl %r13b,%edi
  call   <is_digit@plt>
  test   %rax,%rax
  je     L122
  jmp    L88
  nopl   0x0(%rax)
L107:
  pop    %rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <strcmp_natural_scan_forward@plt>
L116:
  cmp    %r13b,%bl
  jl     L88
L46:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int strcmp_natural_tiebroken(const char *s1, const char *s2) {
  char c1 = *(++s1);
  char c2 = *(++s2);
  while (is_not_nzdigit(c1) && is_not_nzdigit(c2)) {
  strcmp_natural_tiebroken_state_2:
    if (c1 != c2) {
      if ((c1 >= 'a') && (c1 <= 'z')) {
        c1 -= 32;
      }
      if ((c2 >= 'a') && (c2 <= 'z')) {
        c2 -= 32;
      }
      if (c1 < c2) {
        return -1;
      } else if (c1 > c2) {
        return 1;
      }
    } else if (!c1) {
      return -1;
    }
    c1 = *(++s1);
    c2 = *(++s2);
  }
  if (is_not_nzdigit(c1) || is_not_nzdigit(c2)) {
    return (c1 < c2) ? -1 : 1;
  }
  do {
    if (c1 != c2) {
      if (is_digit(c2)) {
        if (c1 < c2) {
          return strcmp_natural_scan_forward(s1, s2);
        } else {
          return -strcmp_natural_scan_forward(s2, s1);
        }
      }
      return 1;
    }
    c1 = *(++s1);
    c2 = *(++s2);
  } while (is_digit(c1));
  if (is_digit(c2)) {
    return -1;
  }
  goto strcmp_natural_tiebroken_state_2;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D75(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D10
type: string
name: disassemble_data
arguments: data_label: D13
type: string
name: disassemble_data
arguments: data_label: D75
type: string
name: disassemble_data
arguments: data_label: D8
type: string
name: disassemble_data
arguments: data_label: D77
type: string
name: disassemble_data
arguments: data_label: D67
type: string
name: disassemble_data
arguments: data_label: D51
type: string

tool: D10: usage:


tool: D13: 	binaryiris image > iris_of_image.pbm


tool: D75: 


tool: D8: 	dumps a characteristic 256x256 image of image


tool: D77: 	the output is created by sweeping over image and collecting bytewise neighbour relationships


tool: D67: 	e.g.:


tool: D51: 		$ binaryiris image > iris_of_image.pbm


assistant: ```c
void usage(void) {
  printf("usage:\n");
  printf("\tbinaryiris image > iris_of_image.pbm\n");
  printf("\n");
  printf("\tdumps a characteristic 256x256 image of image\n");
  printf("\tthe output is created by sweeping over image and collecting bytewise neighbour relationships\n");
  printf("\n");
  printf("\te.g.:\n");
  printf("\t\t$ binaryiris image > iris_of_image.pbm\n");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<usage>:
  endbr64
  push   %rbx
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D0(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D36
type: string
name: unpack_data
arguments: data_label: D4
type: string
name: unpack_data
arguments: data_label: D0
type: string
name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D44
type: string
name: unpack_data
arguments: data_label: D46
type: string
name: unpack_data
arguments: data_label: D64
type: string

tool: D36: usage:


tool: D4: 	binaryiris image > iris_of_image.pbm


tool: D0: 


tool: D15: 	dumps a characteristic 256x256 image of image


tool: D44: 	the output is created by sweeping over image and collecting bytewise neighbour relationships


tool: D46: 	e.g.:


tool: D64: 		$ binaryiris image > iris_of_image.pbm


assistant: ```c
void usage(void) {
  printf("usage:\n");
  printf("\tbinaryiris image > iris_of_image.pbm\n");
  printf("\n");
  printf("\tdumps a characteristic 256x256 image of image\n");
  printf("\tthe output is created by sweeping over image and collecting bytewise neighbour relationships\n");
  printf("\n");
  printf("\te.g.:\n");
  printf("\t\t$ binaryiris image > iris_of_image.pbm\n");
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  lea    D66(%rip),%rbp
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
data_type: string
name: disassemble_data
arguments: data_tag: D66
data_type: string
name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D31
data_type: string
name: disassemble_data
arguments: data_tag: D15
data_type: string
name: disassemble_data
arguments: data_tag: D51
data_type: string
name: disassemble_data
arguments: data_tag: D39
data_type: string

tool: D11: usage:


tool: D66: 


tool: D24: 	binaryiris image > iris_of_image.pbm


tool: D31: 	dumps a characteristic 256x256 image of image


tool: D15: 	the output is created by sweeping over image and collecting bytewise neighbour relationships


tool: D51: 	e.g.:


tool: D39: 		$ binaryiris image > iris_of_image.pbm


assistant: ```c
void usage(void) {
  printf("usage:\n");
  printf("\tbinaryiris image > iris_of_image.pbm\n");
  printf("\n");
  printf("\tdumps a characteristic 256x256 image of image\n");
  printf("\tthe output is created by sweeping over image and collecting bytewise neighbour relationships\n");
  printf("\n");
  printf("\te.g.:\n");
  printf("\t\t$ binaryiris image > iris_of_image.pbm\n");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  lea    D50(%rip),%rbp
  call   <printf@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D50
type: string
name: extract_symbolic_data
arguments: tag: D61
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string
name: extract_symbolic_data
arguments: tag: D39
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D40
type: string

tool: D23: usage:


tool: D50: 


tool: D61: 	binaryiris image > iris_of_image.pbm


tool: D2: 	dumps a characteristic 256x256 image of image


tool: D39: 	the output is created by sweeping over image and collecting bytewise neighbour relationships


tool: D5: 	e.g.:


tool: D40: 		$ binaryiris image > iris_of_image.pbm


assistant: ```c
void usage(void) {
  printf("usage:\n");
  printf("\tbinaryiris image > iris_of_image.pbm\n");
  printf("\n");
  printf("\tdumps a characteristic 256x256 image of image\n");
  printf("\tthe output is created by sweeping over image and collecting bytewise neighbour relationships\n");
  printf("\n");
  printf("\te.g.:\n");
  printf("\t\t$ binaryiris image > iris_of_image.pbm\n");
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x10(%rbp),%rcx
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L1
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  cmp    %rax,%rdx
  jne    L12
L1:
  mov    $0xffffffff,%eax
  jmp    L20
L12:
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  add    %esi,%eax
  mov    %eax,%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x14(%rbp),%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

assistant: ```c
int read_number(const char **str, int *pos) {
  char *end;
  int ret = strtol(*str, &end, 10);
  if (!ret || end == *str) {
    return -1;
  }
  *pos += (end - *str);
  *str = end;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_number>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  mov    $0xa,%edx
  mov    (%rdi),%rdi
  call   <strtol@plt>
  test   %eax,%eax
  je     L10
  mov    (%rbx),%rcx
  mov    (%rsp),%rdx
  cmp    %rdx,%rcx
  je     L19
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  add    %esi,0x0(%rbp)
  mov    %rdx,(%rbx)
L45:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L45
L19:
  mov    $0xffffffff,%eax
  jmp    L45
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_number(const char **str, int *pos) {
  char *end;
  int ret = strtol(*str, &end, 10);
  if (!ret || end == *str) {
    return -1;
  }
  *pos += (end - *str);
  *str = end;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_number>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  test   %eax,%eax
  je     L22
  mov    (%rbx),%rcx
  mov    (%rsp),%rdx
  cmp    %rdx,%rcx
  je     L22
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  add    %esi,0x0(%rbp)
  mov    %rdx,(%rbx)
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L22:
  mov    $0xffffffff,%eax
  jmp    L26
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_number(const char **str, int *pos) {
  char *end;
  int ret = strtol(*str, &end, 10);
  if (!ret || end == *str) {
    return -1;
  }
  *pos += (end - *str);
  *str = end;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_number>:
  endbr64
  push   %rbp
  mov    $0xa,%edx
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <strtol@plt>
  test   %eax,%eax
  je     L18
  mov    (%rbx),%rcx
  mov    (%rsp),%rdx
  cmp    %rdx,%rcx
  je     L18
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  add    %esi,0x0(%rbp)
  mov    %rdx,(%rbx)
L7:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  mov    $0xffffffff,%eax
  jmp    L7
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_number(const char **str, int *pos) {
  char *end;
  int ret = strtol(*str, &end, 10);
  if (!ret || end == *str) {
    return -1;
  }
  *pos += (end - *str);
  *str = end;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fileToArray@plt>
  mov    $0x0,%eax
  call   <threadUp@plt>
  mov    $0x0,%eax
  call   <printSortedArray@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  char fileName[sizeof(argv[1])];
  strcpy(fileName, argv[1]);
  fileToArray(fileName);
  threadUp();
  printSortedArray();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    0x8(%rsi),%rsi
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <fileToArray@plt>
  mov    $0x0,%eax
  call   <threadUp@plt>
  mov    $0x0,%eax
  call   <printSortedArray@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char fileName[sizeof(argv[1])];
  strcpy(fileName, argv[1]);
  fileToArray(fileName);
  threadUp();
  printSortedArray();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <fileToArray@plt>
  xor    %eax,%eax
  call   <threadUp@plt>
  xor    %eax,%eax
  call   <printSortedArray@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char fileName[sizeof(argv[1])];
  strcpy(fileName, argv[1]);
  fileToArray(fileName);
  threadUp();
  printSortedArray();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    0x8(%rsi),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  call   <fileToArray@plt>
  xor    %eax,%eax
  call   <threadUp@plt>
  xor    %eax,%eax
  call   <printSortedArray@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  char fileName[sizeof(argv[1])];
  strcpy(fileName, argv[1]);
  fileToArray(fileName);
  threadUp();
  printSortedArray();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strstep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %eax,%ecx
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  add    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <safe_malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L9:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  add    %eax,-0x14(%rbp)
L4:
  mov    -0x18(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L9
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strstep(const char *str, int step) {
  int len = strlen(str);
  int bufferlen = len / step + (len % step == 0 ? 0 : 1);
  char *buffer = safe_malloc(bufferlen + 1);
  for (int i = 0, j = 0; i < bufferlen; i++, j += step) {
    buffer[i] = str[j];
  }
  buffer[bufferlen] = '\0';
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strstep>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  call   <strlen@plt>
  cltd
  idiv   %r12d
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <safe_malloc@plt>
  test   %ebp,%ebp
  jle    L9
  movslq %r12d,%rdi
  mov    %rbx,%rcx
  mov    %rax,%rdx
  lea    -0x1(%rbp),%esi
  lea    0x1(%rax,%rsi,1),%r8
L12:
  movzbl (%rcx),%esi
  mov    %sil,(%rdx)
  add    %rdi,%rcx
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L12
L9:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstep(const char *str, int step) {
  int len = strlen(str);
  int bufferlen = len / step + (len % step == 0 ? 0 : 1);
  char *buffer = safe_malloc(bufferlen + 1);
  for (int i = 0, j = 0; i < bufferlen; i++, j += step) {
    buffer[i] = str[j];
  }
  buffer[bufferlen] = '\0';
  return buffer;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strstep>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltd
  idiv   %ebp
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  movslq %eax,%r12
  lea    0x1(%r12),%edi
  call   <safe_malloc@plt>
  test   %r12d,%r12d
  jle    L16
  lea    -0x1(%r12),%ecx
  movslq %ebp,%rsi
  mov    %rbx,%rdi
  mov    %rax,%rdx
  lea    0x1(%rax,%rcx,1),%r8
L17:
  movzbl (%rdi),%ecx
  add    $0x1,%rdx
  add    %rsi,%rdi
  mov    %cl,-0x1(%rdx)
  cmp    %r8,%rdx
  jne    L17
L16:
  movb   $0x0,(%rax,%r12,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strstep(const char *str, int step) {
  int len = strlen(str);
  int bufferlen = len / step + (len % step == 0 ? 0 : 1);
  char *buffer = safe_malloc(bufferlen + 1);
  for (int i = 0, j = 0; i < bufferlen; i++, j += step) {
    buffer[i] = str[j];
  }
  buffer[bufferlen] = '\0';
  return buffer;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strstep>:
  endbr64
  push   %r12
  movslq %esi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltd
  idiv   %r12d
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  lea    0x1(%rax),%edi
  mov    %eax,%ebp
  call   <safe_malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L0
  cmp    $0x1,%r12d
  jne    L44
  lea    0x1(%rbx),%rsi
  mov    %r8,%rdx
  lea    -0x1(%rbp),%eax
  mov    %ebp,%ecx
  sub    %rsi,%rdx
  cmp    $0xe,%rdx
  jbe    L41
  cmp    $0x6,%eax
  jbe    L41
  cmp    $0xe,%eax
  jbe    L137
  mov    %ebp,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nopw   0x0(%rax,%rax,1)
L159:
  movdqu (%rbx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L159
  mov    %ebp,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebp
  je     L0
  mov    %ebp,%ecx
  sub    %edx,%ecx
  lea    -0x1(%rcx),%esi
  cmp    $0x6,%esi
  jbe    L3
L43:
  mov    (%rbx,%rdx,1),%rsi
  mov    %rsi,(%r8,%rdx,1)
  mov    %ecx,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%ecx
  je     L0
L3:
  movslq %eax,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebp
  jle    L0
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebp
  jle    L0
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebp
  jle    L0
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebp
  jle    L0
  movslq %edx,%rdx
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebp
  jle    L0
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%ebp
  jle    L0
  cltq
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L0:
  movslq %ebp,%rbp
  mov    %r8,%rax
  movb   $0x0,(%r8,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L44:
  lea    -0x1(%rbp),%edx
  lea    0x1(%rax,%rdx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl (%rbx),%edx
  add    $0x1,%rax
  add    %r12,%rbx
  mov    %dl,-0x1(%rax)
  cmp    %rcx,%rax
  jne    L29
  movslq %ebp,%rbp
  mov    %r8,%rax
  movb   $0x0,(%r8,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  mov    %ebp,%ecx
  xor    %eax,%eax
  nopl   0x0(%rax)
L8:
  movzbl (%rbx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L8
  movslq %ebp,%rbp
  mov    %r8,%rax
  movb   $0x0,(%r8,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L137:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L43
```

assistant: ```c
char *strstep(const char *str, int step) {
  int len = strlen(str);
  int bufferlen = len / step + (len % step == 0 ? 0 : 1);
  char *buffer = safe_malloc(bufferlen + 1);
  for (int i = 0, j = 0; i < bufferlen; i++, j += step) {
    buffer[i] = str[j];
  }
  buffer[bufferlen] = '\0';
  return buffer;
}
```