user: 下面的汇编指令对应的C源代码是什么：

```asm
<gauss>:
  endbr64
  imul   %edi,%r8d
  mov    %rsi,%r9
  mov    %rdx,%rsi
  movsd  D16(%rip),%xmm0
  movsd  D38(%rip),%xmm2
  movsd  D35(%rip),%xmm3
  mov    %ecx,%eax
  lea    (%r8,%rcx,1),%edx
  movslq %edx,%rdx
  addsd  (%r9,%rdx,8),%xmm0
  movapd %xmm0,%xmm1
  andpd  %xmm2,%xmm1
  ucomisd %xmm1,%xmm3
  jbe    L114
  cvttsd2si %xmm0,%rdx
  pxor   %xmm1,%xmm1
  movsd  D12(%rip),%xmm4
  andnpd %xmm0,%xmm2
  cvtsi2sd %rdx,%xmm1
  movapd %xmm1,%xmm3
  cmpnlesd %xmm0,%xmm3
  andpd  %xmm4,%xmm3
  subsd  %xmm3,%xmm1
  orpd   %xmm2,%xmm1
  movapd %xmm1,%xmm0
L114:
  cvttsd2si %xmm0,%r10d
  test   %r10d,%r10d
  je     L100
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %eax,%edi
  jle    L118
  mov    %edi,%ecx
  movslq %eax,%rdx
  mov    %edi,%ebp
  movslq %r8d,%r12
  imul   %eax,%ecx
  lea    (%r12,%rdx,1),%r13
  pxor   %xmm2,%xmm2
  sub    %eax,%ebp
  cvtsi2sd %r10d,%xmm2
  lea    0x0(,%r13,8),%r11
  movslq %ecx,%rbx
  lea    0x1(%rdx,%rbx,1),%rdx
  shl    $0x3,%rdx
  cmp    $0x1,%ebp
  je     L9
  cmp    %rdx,%r11
  je     L9
  mov    %ebp,%ebx
  movapd %xmm2,%xmm3
  lea    -0x8(%r9,%rdx,1),%r12
  add    %r9,%r11
  shr    %ebx
  unpcklpd %xmm3,%xmm3
  xor    %edx,%edx
  shl    $0x4,%rbx
  xchg   %ax,%ax
L150:
  movupd (%r12,%rdx,1),%xmm1
  movupd (%r11,%rdx,1),%xmm0
  mulpd  %xmm3,%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%r11,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%rbx
  jne    L150
  mov    %ebp,%edx
  and    $0xfffffffe,%edx
  lea    (%rdx,%rax,1),%ebx
  cmp    %edx,%ebp
  je     L118
  lea    (%r8,%rbx,1),%edx
  movslq %edx,%rdx
  lea    (%r9,%rdx,8),%r11
  lea    (%rcx,%rbx,1),%edx
  movslq %edx,%rdx
  movsd  (%r11),%xmm0
  mulsd  (%r9,%rdx,8),%xmm2
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%r11)
L118:
  test   %edi,%edi
  jle    L40
  imul   %edi,%eax
  pxor   %xmm2,%xmm2
  cvtsi2sd %r10d,%xmm2
  movslq %r8d,%r10
  lea    0x0(,%r10,8),%rcx
  movslq %eax,%rdx
  lea    0x8(,%rdx,8),%r9
  cmp    %rcx,%r9
  je     L106
  cmp    $0x1,%edi
  je     L106
  lea    -0x8(%rsi,%r9,1),%r10
  mov    %edi,%r9d
  movapd %xmm2,%xmm3
  add    %rsi,%rcx
  shr    %r9d
  unpcklpd %xmm3,%xmm3
  xor    %edx,%edx
  shl    $0x4,%r9
  nopw   0x0(%rax,%rax,1)
L111:
  movupd (%r10,%rdx,1),%xmm1
  movupd (%rcx,%rdx,1),%xmm0
  mulpd  %xmm3,%xmm1
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rdx,1)
  add    $0x10,%rdx
  cmp    %rdx,%r9
  jne    L111
  mov    %edi,%ecx
  and    $0xfffffffe,%ecx
  and    $0x1,%edi
  je     L40
  add    %ecx,%eax
  add    %ecx,%r8d
  cltq
  movslq %r8d,%r8
  mulsd  (%rsi,%rax,8),%xmm2
  lea    (%rsi,%r8,8),%rdx
  movsd  (%rdx),%xmm0
  subsd  %xmm2,%xmm0
  movsd  %xmm0,(%rdx)
L40:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L100:
  ret
  nopl   0x0(%rax)
L106:
  lea    (%rsi,%rcx,1),%rax
  lea    -0x1(%rdi),%ecx
  sub    %r10,%rdx
  add    %r10,%rcx
  lea    0x8(%rsi,%rcx,8),%rcx
  nopw   0x0(%rax,%rax,1)
L57:
  movsd  (%rax,%rdx,8),%xmm1
  movsd  (%rax),%xmm0
  add    $0x8,%rax
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rcx
  jne    L57
  jmp    L40
  nopl   0x0(%rax)
L9:
  lea    -0x1(%rbp),%ecx
  lea    (%r9,%r11,1),%rdx
  sub    %r12,%rbx
  add    %r13,%rcx
  lea    0x8(%r9,%rcx,8),%rcx
  nopw   0x0(%rax,%rax,1)
L67:
  movsd  (%rdx,%rbx,8),%xmm1
  movsd  (%rdx),%xmm0
  add    $0x8,%rdx
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rcx,%rdx
  jne    L67
  jmp    L118
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: f64
name: retrieve_data
arguments: label: D38
datatype: byte[8]
name: retrieve_data
arguments: label: D35
datatype: byte[8]
name: retrieve_data
arguments: label: D12
datatype: byte[8]

tool: D16: 0.5

tool: {"D38": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: {"D35": [0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x43]}

tool: {"D12": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void gauss(int n, double *L, double *Z, int i, int j) {
  int k, mu;
  if ((mu = (int)(floor((L[i + j * n]) + 0.5))) != 0) {
    for (k = i; k < n; k++)
      L[k + n * j] -= (double)mu * L[k + i * n];
    for (k = 0; k < n; k++)
      Z[k + n * j] -= (double)mu * Z[k + i * n];
  }
}
```