ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L5:
  mov    $0x0,%eax
  call   <xgetchar@plt>
  mov    %rax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L31
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L8
L31:
  mov    -0x18(%rbp),%rax
  add    $0xc7,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L5
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movb   $0xa,(%rax)
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
L23:
  mov    $0x0,%eax
  call   <xgetchar@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xa,-0xc(%rbp)
  jne    L23
  mov    -0x18(%rbp),%rax
  sub    $0xc8,%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
type_infered: string

tool: D4: Line too long, truncated to %s


assistant: ```c
void getline(char *s) {
  int c;
  char *p = s;
  while (p < s + 200 - 1)
    if ((*p++ = xgetchar()) == '\n') {
      *p = '\0';
      return;
    }
  p[-1] = '\n';
  p[0] = '\0';
  while ((c = xgetchar()) != '\n')
    ;
  printf("Line too long, truncated to %s\n", s - 200);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0xc7(%rdi),%rbp
  mov    %rdi,%rbx
L2:
  cmp    %rbp,%rbx
  je     L0
  mov    $0x0,%eax
  call   <xgetchar@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%al
  jne    L2
  movb   $0x0,(%rbx)
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  movb   $0xa,-0x1(%rbx)
  movb   $0x0,(%rbx)
L19:
  mov    $0x0,%eax
  call   <xgetchar@plt>
  cmp    $0xa,%eax
  jne    L19
  lea    -0xc8(%r12),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: Line too long, truncated to %s


assistant: ```c
void getline(char *s) {
  int c;
  char *p = s;
  while (p < s + 200 - 1)
    if ((*p++ = xgetchar()) == '\n') {
      *p = '\0';
      return;
    }
  p[-1] = '\n';
  p[0] = '\0';
  while ((c = xgetchar()) != '\n')
    ;
  printf("Line too long, truncated to %s\n", s - 200);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getline>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0xc7(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L0:
  cmp    %rbx,%rbp
  je     L26
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <xgetchar@plt>
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%al
  jne    L0
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  movb   $0xa,-0x1(%rbp)
  movb   $0x0,0xc7(%r12)
  nopl   0x0(%rax)
L20:
  xor    %eax,%eax
  call   <xgetchar@plt>
  cmp    $0xa,%eax
  jne    L20
  pop    %rbx
  lea    -0xc8(%r12),%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: Line too long, truncated to %s


assistant: ```c
void getline(char *s) {
  int c;
  char *p = s;
  while (p < s + 200 - 1)
    if ((*p++ = xgetchar()) == '\n') {
      *p = '\0';
      return;
    }
  p[-1] = '\n';
  p[0] = '\0';
  while ((c = xgetchar()) != '\n')
    ;
  printf("Line too long, truncated to %s\n", s - 200);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getline>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  lea    0xc7(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  nopl   (%rax)
L1:
  cmp    %rbx,%rbp
  je     L21
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <xgetchar@plt>
  mov    %al,-0x1(%rbx)
  cmp    $0xa,%al
  jne    L1
  movb   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  movb   $0xa,-0x1(%rbp)
  movb   $0x0,0xc7(%r12)
  nopl   0x0(%rax)
L16:
  xor    %eax,%eax
  call   <xgetchar@plt>
  cmp    $0xa,%eax
  jne    L16
  pop    %rbx
  lea    -0xc8(%r12),%rsi
  lea    D6(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: Line too long, truncated to %s


assistant: ```c
void getline(char *s) {
  int c;
  char *p = s;
  while (p < s + 200 - 1)
    if ((*p++ = xgetchar()) == '\n') {
      *p = '\0';
      return;
    }
  p[-1] = '\n';
  p[0] = '\0';
  while ((c = xgetchar()) != '\n')
    ;
  printf("Line too long, truncated to %s\n", s - 200);
}
```
user: What is the c source code of the assembly code below:

```asm
<tx_ltrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L16:
  addq   $0x1,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L16
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *tx_ltrim(char *str) {
  char *cptr = str;
  while (isspace(*cptr))
    cptr++;
  return cptr;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tx_ltrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L12
L19:
  add    $0x1,%rbx
L12:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *tx_ltrim(char *str) {
  char *cptr = str;
  while (isspace(*cptr))
    cptr++;
  return cptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tx_ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x1,%r12
L16:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L11
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *tx_ltrim(char *str) {
  char *cptr = str;
  while (isspace(*cptr))
    cptr++;
  return cptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tx_ltrim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L19:
  add    $0x1,%r12
L12:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L19
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *tx_ltrim(char *str) {
  char *cptr = str;
  while (isspace(*cptr))
    cptr++;
  return cptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<search_bitmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L11:
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x8,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L19
  mov    -0x4(%rbp),%eax
  jmp    L12
L19:
  addl   $0x1,-0x4(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L11
  mov    -0x24(%rbp),%eax
L12:
  leave
  ret
```

assistant: ```c
int search_bitmap(unsigned char *bitmap, unsigned char *table, int size) {
  int c;
  for (c = 0; c < size; c++) {
    if (memcmp(&table[c * 8], &bitmap[0], 8) == 0)
      return c;
  }
  return size;
}
```
user: What is the c source code of the assembly code below:

```asm
<search_bitmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%r13d
  test   %edx,%edx
  jle    L5
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    $0x0,%ebp
L9:
  mov    $0x8,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  je     L3
  add    $0x1,%ebp
  add    $0x8,%rbx
  cmp    %ebp,%r13d
  jne    L9
  jmp    L5
L3:
  mov    %ebp,%r13d
L5:
  mov    %r13d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int search_bitmap(unsigned char *bitmap, unsigned char *table, int size) {
  int c;
  for (c = 0; c < size; c++) {
    if (memcmp(&table[c * 8], &bitmap[0], 8) == 0)
      return c;
  }
  return size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<search_bitmap>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L1
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  jmp    L3
L23:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%r13d
  je     L1
L3:
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L23
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  add    $0x8,%rsp
  mov    %r13d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int search_bitmap(unsigned char *bitmap, unsigned char *table, int size) {
  int c;
  for (c = 0; c < size; c++) {
    if (memcmp(&table[c * 8], &bitmap[0], 8) == 0)
      return c;
  }
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<search_bitmap>:
  endbr64
  push   %r13
  mov    %edx,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jle    L3
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  xor    %r12d,%r12d
  jmp    L21
L0:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%r13d
  je     L3
L21:
  mov    $0x8,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L0
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  add    $0x8,%rsp
  mov    %r13d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int search_bitmap(unsigned char *bitmap, unsigned char *table, int size) {
  int c;
  for (c = 0; c < size; c++) {
    if (memcmp(&table[c * 8], &bitmap[0], 8) == 0)
      return c;
  }
  return size;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fprint_addc_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D0(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: ADDC  A, #0x%02X                  

assistant: ```c
void fprint_addc_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "ADDC  A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fprint_addc_data>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%edx
  lea    D8(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string

tool: D8: ADDC  A, #0x%02X                  

assistant: ```c
void fprint_addc_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "ADDC  A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: What is the c source code of the assembly code below?

```asm
<fprint_addc_data>:
  endbr64
  mov    %esi,%edx
  lea    D3(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string

tool: D3: ADDC  A, #0x%02X                  

assistant: ```c
void fprint_addc_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "ADDC  A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fprint_addc_data>:
  endbr64
  mov    %esi,%edx
  lea    D2(%rip),%rsi
  jmp    1050 <fprintf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: ADDC  A, #0x%02X                  

assistant: ```c
void fprint_addc_data(FILE *stream, uint8_t data) {
  fprintf(stream,
          "ADDC  A, #"
          "0x%02X"
          "                  ",
          data);
}
```
user: Translate the below assembly code into C programming language:

```asm
<do_some_work>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L13:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x4(%rbp),%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D29(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x1fff,-0x4(%rbp)
  jle    L13
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: f64
name: extract_symbolic_data
arguments: data_label: D29
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D4
data_type: byte[8]

tool: D13: 10

tool: {"D29": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
void do_some_work() {
  int i;
  for (i = 0; i < 0x2000; i++) {
    i = i * 10.0 / 5 / 2;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_some_work>:
  endbr64
  mov    $0x0,%eax
  movsd  D21(%rip),%xmm3
  movsd  D19(%rip),%xmm2
  movsd  D20(%rip),%xmm1
L7:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  cmp    $0x1fff,%eax
  jle    L7
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D21
data_type: f64
name: retrieve_data
arguments: tag: D19
data_type: byte[8]
name: retrieve_data
arguments: tag: D20
data_type: byte[8]

tool: D21: 10

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D20": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void do_some_work() {
  int i;
  for (i = 0; i < 0x2000; i++) {
    i = i * 10.0 / 5 / 2;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<do_some_work>:
  endbr64
  movsd  D23(%rip),%xmm3
  movsd  D19(%rip),%xmm2
  xor    %eax,%eax
  movsd  D5(%rip),%xmm1
  xchg   %ax,%ax
L6:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  cmp    $0x1fff,%eax
  jle    L6
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D23
type_infered: f64
name: disassemble_data
arguments: tag: D19
type_infered: byte[8]
name: disassemble_data
arguments: tag: D5
type_infered: byte[8]

tool: D23: 10

tool: {"D19": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void do_some_work() {
  int i;
  for (i = 0; i < 0x2000; i++) {
    i = i * 10.0 / 5 / 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<do_some_work>:
  endbr64
  movsd  D29(%rip),%xmm3
  movsd  D14(%rip),%xmm2
  xor    %eax,%eax
  movsd  D9(%rip),%xmm1
  xchg   %ax,%ax
L9:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  add    $0x1,%eax
  cmp    $0x1fff,%eax
  jle    L9
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D29
type: f64
name: parse_data
arguments: data_tag: D14
type: byte[8]
name: parse_data
arguments: data_tag: D9
type: byte[8]

tool: D29: 10

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x14,0x40]}

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
void do_some_work() {
  int i;
  for (i = 0; i < 0x2000; i++) {
    i = i * 10.0 / 5 / 2;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mat_sca_mul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  mov    %rdi,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  mov    %edx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L20:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L28:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mulsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L28
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L20
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mat_sca_mul(double a, double **m, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m[i][j] = a * m[i][j];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mat_sca_mul>:
  endbr64
  test   %esi,%esi
  jle    L16
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rsi
  jmp    L33
L9:
  mov    %rax,%rcx
  add    (%r8),%rcx
  movapd %xmm0,%xmm1
  mulsd  (%rcx),%xmm1
  movsd  %xmm1,(%rcx)
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L9
L55:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L16
L33:
  mov    $0x0,%eax
  test   %edx,%edx
  jg     L9
  jmp    L55
L16:
  ret
```

assistant: ```c
void mat_sca_mul(double a, double **m, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m[i][j] = a * m[i][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat_sca_mul>:
  endbr64
  test   %esi,%esi
  jle    L21
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rsi
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%r8
  nopl   0x0(%rax,%rax,1)
L27:
  test   %edx,%edx
  jle    L30
  mov    (%rdi),%rax
  lea    (%r8,%rax,1),%rcx
  nopl   0x0(%rax,%rax,1)
L33:
  movsd  (%rax),%xmm1
  add    $0x8,%rax
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L33
L30:
  add    $0x8,%rdi
  cmp    %rsi,%rdi
  jne    L27
L21:
  ret
```

assistant: ```c
void mat_sca_mul(double a, double **m, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m[i][j] = a * m[i][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<mat_sca_mul>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  jle    L21
  test   %edx,%edx
  jle    L21
  lea    -0x1(%rsi),%eax
  movapd %xmm0,%xmm2
  mov    %edx,%esi
  lea    0x8(%rdi,%rax,8),%r10
  mov    %edx,%eax
  unpcklpd %xmm2,%xmm2
  and    $0xfffffffe,%esi
  shr    %eax
  lea    -0x1(%rax),%r9d
  add    $0x1,%r9
  shl    $0x4,%r9
  nopl   0x0(%rax)
L12:
  mov    (%rdi),%rdx
  mov    %rdx,%rax
  lea    (%r9,%rdx,1),%rcx
  cmp    $0x1,%r8d
  je     L51
  nopl   0x0(%rax,%rax,1)
L42:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  mulpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L42
  movslq %esi,%rax
  cmp    %esi,%r8d
  je     L24
L37:
  lea    (%rdx,%rax,8),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
L24:
  add    $0x8,%rdi
  cmp    %r10,%rdi
  jne    L12
L21:
  ret
L51:
  xor    %eax,%eax
  jmp    L37
```

assistant: ```c
void mat_sca_mul(double a, double **m, int x, int y) {
  int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      m[i][j] = a * m[i][j];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ieee_isnan>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x7fffffff,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  neg    %eax
  or     -0x4(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x7ff00000,%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  shr    $0x1f,%eax
  pop    %rbp
  ret
```

assistant: ```c
int ieee_isnan(double x) {
  int hx, lx;
  hx = (*(int *)&x & 0x7fffffff);
  lx = *(1 + (int *)&x);
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ieee_isnan>:
  endbr64
  movq   %xmm0,%rax
  movd   %xmm0,%ecx
  and    $0x7fffffff,%ecx
  sar    $0x20,%rax
  mov    %eax,%edx
  neg    %edx
  or     %eax,%edx
  shr    $0x1f,%edx
  or     %ecx,%edx
  mov    $0x7ff00000,%eax
  sub    %edx,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int ieee_isnan(double x) {
  int hx, lx;
  hx = (*(int *)&x & 0x7fffffff);
  lx = *(1 + (int *)&x);
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ieee_isnan>:
  endbr64
  movq   %xmm0,%rax
  movd   %xmm0,%ecx
  sar    $0x20,%rax
  and    $0x7fffffff,%ecx
  mov    %eax,%edx
  neg    %edx
  or     %eax,%edx
  mov    $0x7ff00000,%eax
  shr    $0x1f,%edx
  or     %ecx,%edx
  sub    %edx,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int ieee_isnan(double x) {
  int hx, lx;
  hx = (*(int *)&x & 0x7fffffff);
  lx = *(1 + (int *)&x);
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ieee_isnan>:
  endbr64
  movq   %xmm0,%rax
  movd   %xmm0,%ecx
  sar    $0x20,%rax
  and    $0x7fffffff,%ecx
  mov    %eax,%edx
  neg    %edx
  or     %eax,%edx
  mov    $0x7ff00000,%eax
  shr    $0x1f,%edx
  or     %ecx,%edx
  sub    %edx,%eax
  shr    $0x1f,%eax
  ret
```

assistant: ```c
int ieee_isnan(double x) {
  int hx, lx;
  hx = (*(int *)&x & 0x7fffffff);
  lx = *(1 + (int *)&x);
  hx |= (unsigned)(lx | (-lx)) >> 31;
  hx = 0x7ff00000 - hx;
  return ((unsigned)(hx)) >> 31;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L24
L6:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <imin@plt>
  mov    %eax,%ecx
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L24:
  lea    -0xc(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x2,%eax
  je     L6
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D12
type_guessed: string
name: unpack_data
arguments: label: D22
type_guessed: string
name: unpack_data
arguments: label: D44
type_guessed: string
name: unpack_data
arguments: label: D13
type_guessed: string

tool: D12: Enter a pair of integers (q to quit):

tool: D22: The lesser of %d and %d is %d.


tool: D44: %d %d

tool: D13: Bye.

assistant: ```c
int main(void) {
  int evil1, evil2;
  printf("Enter a pair of integers (q to quit):\n");
  while (scanf("%d %d", &evil1, &evil2) == 2) {
    printf("The lesser of %d and %d is %d.\n", evil1, evil2, imin(evil1, evil2));
    printf("Enter a pair of integers (q to quit):\n");
  }
  printf("Bye.\n");
  return 0;
}
```