ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<string_trim_right>:
  endbr64
  test   %rsi,%rsi
  push   %r14
  sete   %al
  test   %rdx,%rdx
  push   %r13
  push   %r12
  mov    %rdx,%r12
  sete   %dl
  or     %dl,%al
  push   %rbp
  push   %rbx
  jne    L61
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L61
  mov    %rsi,%r13
  mov    %rdi,%rax
  nopl   (%rax)
L23:
  mov    %rax,%rbx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L23
  mov    %rbx,%r14
  cmp    %rbx,%rbp
  je     L1
  nopl   0x0(%rax)
L29:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  sub    $0x1,%rbx
  call   <strchr@plt>
  test   %rax,%rax
  je     L1
  mov    %rbx,%r14
  cmp    %rbx,%rbp
  jne    L29
L1:
  sub    %rbp,%r14
  mov    %rbp,%rsi
  mov    %r13,%rdi
  lea    0x1(%r14),%edx
  call   <strncpy@plt>
  movb   $0x0,0x1(%r13,%r14,1)
  xor    %eax,%eax
L28:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L61:
  mov    $0xffffffff,%eax
  jmp    L28
```

assistant: ```c
int string_trim_right(const char *src, char *dst, char *module) {
  const char *temp = src;
  char c;
  if (!src || !dst || !module) {
    return -1;
  }
  while (*(++temp) != '\0')
    ;
  while ((--temp) != src) {
    c = *temp;
    if (strchr(module, c) == NULL) {
      break;
    }
  }
  strncpy(dst, src, temp - src + 1);
  dst[temp - src + 1] = '\0';
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_pager>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <value@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L11
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L7
L11:
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <value@plt>
  test   %rax,%rax
  je     L35
  lea    D12(%rip),%rax
  jmp    L24
L35:
  lea    D31(%rip),%rax
L24:
  mov    %rax,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D0
type: string
name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D31
type: string

tool: D29: PAGER

tool: D0: bsdcompat

tool: D12: more

tool: D31: less

assistant: ```c
char *get_pager(void) {
  char *cp;
  cp = value("PAGER");
  if (cp == NULL || *cp == '\0')
    cp = value("bsdcompat") ? "more" : "less";
  return cp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_pager>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  call   <value@plt>
  test   %rax,%rax
  je     L5
  cmpb   $0x0,(%rax)
  jne    L15
L5:
  lea    D31(%rip),%rdi
  call   <value@plt>
  test   %rax,%rax
  lea    D12(%rip),%rax
  lea    D13(%rip),%rdx
  cmove  %rdx,%rax
L15:
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D31
type: string
name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D13
type: string

tool: D36: PAGER

tool: D31: bsdcompat

tool: D12: more

tool: D13: less

assistant: ```c
char *get_pager(void) {
  char *cp;
  cp = value("PAGER");
  if (cp == NULL || *cp == '\0')
    cp = value("bsdcompat") ? "more" : "less";
  return cp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_pager>:
  endbr64
  sub    $0x8,%rsp
  lea    D11(%rip),%rdi
  call   <value@plt>
  test   %rax,%rax
  je     L7
  cmpb   $0x0,(%rax)
  jne    L9
L7:
  lea    D27(%rip),%rdi
  call   <value@plt>
  lea    D17(%rip),%rdx
  test   %rax,%rax
  lea    D37(%rip),%rax
  cmove  %rdx,%rax
L9:
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D27
type_guessed: string
name: unpack_data
arguments: label: D17
type_guessed: string
name: unpack_data
arguments: label: D37
type_guessed: string

tool: D11: PAGER

tool: D27: bsdcompat

tool: D17: less

tool: D37: more

assistant: ```c
char *get_pager(void) {
  char *cp;
  cp = value("PAGER");
  if (cp == NULL || *cp == '\0')
    cp = value("bsdcompat") ? "more" : "less";
  return cp;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_pager>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <value@plt>
  test   %rax,%rax
  je     L2
  cmpb   $0x0,(%rax)
  jne    L0
L2:
  lea    D39(%rip),%rdi
  call   <value@plt>
  lea    D29(%rip),%rdx
  test   %rax,%rax
  lea    D12(%rip),%rax
  cmove  %rdx,%rax
L0:
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D3
data_type: string
name: disassemble_data
arguments: data_label: D39
data_type: string
name: disassemble_data
arguments: data_label: D29
data_type: string
name: disassemble_data
arguments: data_label: D12
data_type: string

tool: D3: PAGER

tool: D39: bsdcompat

tool: D29: less

tool: D12: more

assistant: ```c
char *get_pager(void) {
  char *cp;
  cp = value("PAGER");
  if (cp == NULL || *cp == '\0')
    cp = value("bsdcompat") ? "more" : "less";
  return cp;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<handle_collision_button1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <ramming_speed@plt>
  mov    $0x0,%eax
  call   <raise_probiscus@plt>
  jmp    L14
L11:
  mov    $0x3e8,%edi
  call   <wait1Msec@plt>
L14:
  mov    $0x0,%eax
  call   <get_collision_button@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x0,%eax
  call   <stop_moving@plt>
  mov    $0x0,%eax
  call   <lower_probiscus@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void handle_collision_button1() {
  ramming_speed();
  raise_probiscus();
  while (get_collision_button()) {
    wait1Msec(1000);
  }
  stop_moving();
  lower_probiscus();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<handle_collision_button1>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ramming_speed@plt>
  mov    $0x0,%eax
  call   <raise_probiscus@plt>
  jmp    L15
L17:
  mov    $0x3e8,%edi
  call   <wait1Msec@plt>
L15:
  mov    $0x0,%eax
  call   <get_collision_button@plt>
  test   %rax,%rax
  jne    L17
  call   <stop_moving@plt>
  mov    $0x0,%eax
  call   <lower_probiscus@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void handle_collision_button1() {
  ramming_speed();
  raise_probiscus();
  while (get_collision_button()) {
    wait1Msec(1000);
  }
  stop_moving();
  lower_probiscus();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<handle_collision_button1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ramming_speed@plt>
  xor    %eax,%eax
  call   <raise_probiscus@plt>
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x3e8,%edi
  call   <wait1Msec@plt>
L5:
  xor    %eax,%eax
  call   <get_collision_button@plt>
  test   %rax,%rax
  jne    L0
  call   <stop_moving@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <lower_probiscus@plt>
```

assistant: ```c
void handle_collision_button1() {
  ramming_speed();
  raise_probiscus();
  while (get_collision_button()) {
    wait1Msec(1000);
  }
  stop_moving();
  lower_probiscus();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<handle_collision_button1>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ramming_speed@plt>
  xor    %eax,%eax
  call   <raise_probiscus@plt>
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0x3e8,%edi
  call   <wait1Msec@plt>
L7:
  xor    %eax,%eax
  call   <get_collision_button@plt>
  test   %rax,%rax
  jne    L10
  call   <stop_moving@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    10b0 <lower_probiscus@plt>
```

assistant: ```c
void handle_collision_button1() {
  ramming_speed();
  raise_probiscus();
  while (get_collision_button()) {
    wait1Msec(1000);
  }
  stop_moving();
  lower_probiscus();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arithmetic>:
  endbr64
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    D9(%rip),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0xc0]}

assistant: ```c
void arithmetic() {
  int a;
  int b;
  int c;
  a = 6;
  b = 9;
  double aa = 6, bb = 9, cc;
  double fortyfive = 45, sixty = 60, thirty = 30;
  c = a + b;
  c = a - b;
  c = a * b;
  c = a / b;
  c = b / a;
  c = a % b;
  c = b % a;
  c = -a + b;
  c = -a - b;
  c = -a * b;
  c = -a / b;
  c = -b / a;
  c = -a % b;
  c = -b % a;
  c = pow(a, b);
  c = pow(b, a);
  c = pow(-a, b);
  c = pow(-b, a);
  c = pow(a, -b);
  c = pow(b, -a);
  c = pow(-a, -b);
  c = pow(-b, -a);
  c = sqrt(a);
  c = sqrt(-a);
  c = log(a);
  c = log(-a);
  c = log2(a);
  c = log2(-a);
  c = log10(a);
  c = log10(-a);
  cc = aa + bb;
  cc = aa - bb;
  cc = aa * bb;
  cc = aa / bb;
  cc = bb / aa;
  cc = -aa + bb;
  cc = -aa - bb;
  cc = -aa * bb;
  cc = -aa / bb;
  cc = -bb / aa;
  cc = pow(aa, bb);
  cc = pow(bb, aa);
  cc = pow(-aa, bb);
  cc = pow(-bb, aa);
  cc = pow(aa, -bb);
  cc = pow(bb, -aa);
  cc = pow(-aa, -bb);
  cc = pow(-bb, -aa);
  cc = sqrt(aa);
  cc = sqrt(-aa);
  cc = log(aa);
  cc = log(-aa);
  cc = log2(aa);
  cc = log2(-aa);
  cc = log10(aa);
  cc = log10(-aa);
  cc = sin(aa * 3.14159265);
  cc = sin(bb * 3.14159265);
  cc = sin(thirty * 3.14159265 / 180.0);
  cc = sin(fortyfive * 3.14159265 / 180.0);
  cc = sin(sixty * 3.14159265 / 180.0);
  cc = cos(aa * 3.14159265);
  cc = cos(bb * 3.14159265);
  cc = cos(thirty * 3.14159265 / 180.0);
  cc = cos(fortyfive * 3.14159265 / 180.0);
  cc = cos(sixty * 3.14159265 / 180.0);
  cc = tan(thirty * 3.14159265 / 180.0);
  cc = tan(fortyfive * 3.14159265 / 180.0);
  cc = tan(sixty * 3.14159265 / 180.0);
  cc = atan(aa / aa) * 180 / 3.14159265;
  cc = atan(bb / bb) * 180 / 3.14159265;
  cc = atan(aa / bb) * 180 / 3.14159265;
  cc = atan(bb / aa) * 180 / 3.14159265 + 0;
  cc = atan(bb / -aa) * 180 / 3.14159265 + 180;
  cc = atan(bb / aa) * 180 / 3.14159265 + 180;
  cc = atan(-bb / aa) * 180 / 3.14159265 + 360;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arithmetic>:
  endbr64
  sub    $0x8,%rsp
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    D47(%rip),%rax
  add    $0x8,%rsp
  movq   %rax,%xmm0
  jmp    10a0 <log10@plt>
```

tool_calls: name: retrieve_data
arguments: label: D47
type_guessed: byte[8]

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0xc0]}

assistant: ```c
void arithmetic() {
  int a;
  int b;
  int c;
  a = 6;
  b = 9;
  double aa = 6, bb = 9, cc;
  double fortyfive = 45, sixty = 60, thirty = 30;
  c = a + b;
  c = a - b;
  c = a * b;
  c = a / b;
  c = b / a;
  c = a % b;
  c = b % a;
  c = -a + b;
  c = -a - b;
  c = -a * b;
  c = -a / b;
  c = -b / a;
  c = -a % b;
  c = -b % a;
  c = pow(a, b);
  c = pow(b, a);
  c = pow(-a, b);
  c = pow(-b, a);
  c = pow(a, -b);
  c = pow(b, -a);
  c = pow(-a, -b);
  c = pow(-b, -a);
  c = sqrt(a);
  c = sqrt(-a);
  c = log(a);
  c = log(-a);
  c = log2(a);
  c = log2(-a);
  c = log10(a);
  c = log10(-a);
  cc = aa + bb;
  cc = aa - bb;
  cc = aa * bb;
  cc = aa / bb;
  cc = bb / aa;
  cc = -aa + bb;
  cc = -aa - bb;
  cc = -aa * bb;
  cc = -aa / bb;
  cc = -bb / aa;
  cc = pow(aa, bb);
  cc = pow(bb, aa);
  cc = pow(-aa, bb);
  cc = pow(-bb, aa);
  cc = pow(aa, -bb);
  cc = pow(bb, -aa);
  cc = pow(-aa, -bb);
  cc = pow(-bb, -aa);
  cc = sqrt(aa);
  cc = sqrt(-aa);
  cc = log(aa);
  cc = log(-aa);
  cc = log2(aa);
  cc = log2(-aa);
  cc = log10(aa);
  cc = log10(-aa);
  cc = sin(aa * 3.14159265);
  cc = sin(bb * 3.14159265);
  cc = sin(thirty * 3.14159265 / 180.0);
  cc = sin(fortyfive * 3.14159265 / 180.0);
  cc = sin(sixty * 3.14159265 / 180.0);
  cc = cos(aa * 3.14159265);
  cc = cos(bb * 3.14159265);
  cc = cos(thirty * 3.14159265 / 180.0);
  cc = cos(fortyfive * 3.14159265 / 180.0);
  cc = cos(sixty * 3.14159265 / 180.0);
  cc = tan(thirty * 3.14159265 / 180.0);
  cc = tan(fortyfive * 3.14159265 / 180.0);
  cc = tan(sixty * 3.14159265 / 180.0);
  cc = atan(aa / aa) * 180 / 3.14159265;
  cc = atan(bb / bb) * 180 / 3.14159265;
  cc = atan(aa / bb) * 180 / 3.14159265;
  cc = atan(bb / aa) * 180 / 3.14159265 + 0;
  cc = atan(bb / -aa) * 180 / 3.14159265 + 180;
  cc = atan(bb / aa) * 180 / 3.14159265 + 180;
  cc = atan(-bb / aa) * 180 / 3.14159265 + 360;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<arithmetic>:
  endbr64
  sub    $0x8,%rsp
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mov    D47(%rip),%rax
  movq   %rax,%xmm0
  call   <log2@plt>
  mov    D47(%rip),%rax
  add    $0x8,%rsp
  movq   %rax,%xmm0
  jmp    10a0 <log10@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D47
type_guessed: byte[8]

tool: {"D47": [0x00,0x00,0x00,0x00,0x00,0x00,0x18,0xc0]}

assistant: ```c
void arithmetic() {
  int a;
  int b;
  int c;
  a = 6;
  b = 9;
  double aa = 6, bb = 9, cc;
  double fortyfive = 45, sixty = 60, thirty = 30;
  c = a + b;
  c = a - b;
  c = a * b;
  c = a / b;
  c = b / a;
  c = a % b;
  c = b % a;
  c = -a + b;
  c = -a - b;
  c = -a * b;
  c = -a / b;
  c = -b / a;
  c = -a % b;
  c = -b % a;
  c = pow(a, b);
  c = pow(b, a);
  c = pow(-a, b);
  c = pow(-b, a);
  c = pow(a, -b);
  c = pow(b, -a);
  c = pow(-a, -b);
  c = pow(-b, -a);
  c = sqrt(a);
  c = sqrt(-a);
  c = log(a);
  c = log(-a);
  c = log2(a);
  c = log2(-a);
  c = log10(a);
  c = log10(-a);
  cc = aa + bb;
  cc = aa - bb;
  cc = aa * bb;
  cc = aa / bb;
  cc = bb / aa;
  cc = -aa + bb;
  cc = -aa - bb;
  cc = -aa * bb;
  cc = -aa / bb;
  cc = -bb / aa;
  cc = pow(aa, bb);
  cc = pow(bb, aa);
  cc = pow(-aa, bb);
  cc = pow(-bb, aa);
  cc = pow(aa, -bb);
  cc = pow(bb, -aa);
  cc = pow(-aa, -bb);
  cc = pow(-bb, -aa);
  cc = sqrt(aa);
  cc = sqrt(-aa);
  cc = log(aa);
  cc = log(-aa);
  cc = log2(aa);
  cc = log2(-aa);
  cc = log10(aa);
  cc = log10(-aa);
  cc = sin(aa * 3.14159265);
  cc = sin(bb * 3.14159265);
  cc = sin(thirty * 3.14159265 / 180.0);
  cc = sin(fortyfive * 3.14159265 / 180.0);
  cc = sin(sixty * 3.14159265 / 180.0);
  cc = cos(aa * 3.14159265);
  cc = cos(bb * 3.14159265);
  cc = cos(thirty * 3.14159265 / 180.0);
  cc = cos(fortyfive * 3.14159265 / 180.0);
  cc = cos(sixty * 3.14159265 / 180.0);
  cc = tan(thirty * 3.14159265 / 180.0);
  cc = tan(fortyfive * 3.14159265 / 180.0);
  cc = tan(sixty * 3.14159265 / 180.0);
  cc = atan(aa / aa) * 180 / 3.14159265;
  cc = atan(bb / bb) * 180 / 3.14159265;
  cc = atan(aa / bb) * 180 / 3.14159265;
  cc = atan(bb / aa) * 180 / 3.14159265 + 0;
  cc = atan(bb / -aa) * 180 / 3.14159265 + 180;
  cc = atan(bb / aa) * 180 / 3.14159265 + 180;
  cc = atan(-bb / aa) * 180 / 3.14159265 + 360;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D8(%rip),%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x4,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sha1@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L8
L13:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
L8:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L13
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
data_type: string
name: disassemble_data
arguments: data_tag: D18
data_type: string

tool: D8: Hello World!


tool: D18: %02x 

assistant: ```c
int main() {
  char *msg = "Hello World!\n";
  int len = 4;
  unsigned char *digest = malloc(len);
  sha1(msg, strlen(msg), digest, len);
  for (int i = 0; i < len; i++) {
    printf("%02x ", digest[i]);
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  lea    D5(%rip),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    $0x4,%ecx
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <sha1@plt>
  mov    %rbp,%rbx
  add    $0x4,%rbp
  lea    D1(%rip),%r12
L8:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L8
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
type_infered: string
name: parse_data
arguments: data_label: D1
type_infered: string

tool: D5: Hello World!


tool: D1: %02x 

assistant: ```c
int main() {
  char *msg = "Hello World!\n";
  int len = 4;
  unsigned char *digest = malloc(len);
  sha1(msg, strlen(msg), digest, len);
  for (int i = 0; i < len; i++) {
    printf("%02x ", digest[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  mov    %rbx,%rdx
  mov    %eax,%esi
  lea    0x4(%rbx),%r12
  lea    D14(%rip),%rbp
  call   <sha1@plt>
L5:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D14
datatype: string

tool: D5: Hello World!


tool: D14: %02x 

assistant: ```c
int main() {
  char *msg = "Hello World!\n";
  int len = 4;
  unsigned char *digest = malloc(len);
  sha1(msg, strlen(msg), digest, len);
  for (int i = 0; i < len; i++) {
    printf("%02x ", digest[i]);
  }
  printf("\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    $0x4,%ecx
  mov    %rbx,%rdx
  mov    %eax,%esi
  lea    0x4(%rbx),%r12
  lea    D17(%rip),%rbp
  call   <sha1@plt>
L5:
  movzbl (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L5
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string

tool: D0: Hello World!


tool: D17: %02x 

assistant: ```c
int main() {
  char *msg = "Hello World!\n";
  int len = 4;
  unsigned char *digest = malloc(len);
  sha1(msg, strlen(msg), digest, len);
  for (int i = 0; i < len; i++) {
    printf("%02x ", digest[i]);
  }
  printf("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xconfigGetDefaultProjectRoot>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D5(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L36
L19:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  lea    -0x28(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L7
  mov    -0x28(%rbp),%eax
  mov    %eax,%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L25
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  jmp    L46
L7:
  nop
L25:
  addl   $0x1,-0x24(%rbp)
L36:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,8),%rax
  test   %rax,%rax
  jne    L19
  mov    -0x20(%rbp),%rax
L46:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string
name: parse_data
arguments: label: D13
datatype: string

tool: D5: /usr/X11R6

tool: D13: /usr/X11

assistant: ```c
char *xconfigGetDefaultProjectRoot(void) {
  char *paths[] = {"/usr/X11R6", "/usr/X11", NULL};
  struct stat stat_buf;
  int i;
  for (i = 0; paths[i]; i++) {
    if (stat(paths[i], &stat_buf) == -1) {
      continue;
    }
    if (S_ISDIR(stat_buf.st_mode)) {
      return paths[i];
    }
  }
  return paths[0];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xconfigGetDefaultProjectRoot>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D3(%rip),%rbx
  mov    %rbx,0x10(%rsp)
  lea    D7(%rip),%rax
  mov    %rax,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  lea    0x10(%rsp),%rbp
  lea    0xc(%rsp),%r12
  jmp    L23
L48:
  add    $0x8,%rbp
  mov    0x0(%rbp),%rbx
  test   %rbx,%rbx
  je     L34
L23:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  je     L48
  mov    0xc(%rsp),%edi
  call   <S_ISDIR@plt>
  test   %rax,%rax
  je     L48
  jmp    L43
L34:
  lea    D3(%rip),%rbx
L43:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    %rbx,%rax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
data_type: string
name: parse_data
arguments: data_label: D7
data_type: string

tool: D3: /usr/X11R6

tool: D7: /usr/X11

assistant: ```c
char *xconfigGetDefaultProjectRoot(void) {
  char *paths[] = {"/usr/X11R6", "/usr/X11", NULL};
  struct stat stat_buf;
  int i;
  for (i = 0; paths[i]; i++) {
    if (stat(paths[i], &stat_buf) == -1) {
      continue;
    }
    if (S_ISDIR(stat_buf.st_mode)) {
      return paths[i];
    }
  }
  return paths[0];
}
```