ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<read_until>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x38(%rbp)
  mov    %al,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  jmp    L9
L55:
  mov    -0x38(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  lea    -0x18(%rbp),%rdx
  mov    -0x24(%rbp),%eax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <receive@plt>
  test   %rax,%rax
  jne    L26
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  jne    L77
L26:
  mov    $0xffffffff,%eax
  jmp    L67
L77:
  mov    -0x18(%rbp),%rdx
  movsbl -0x28(%rbp),%eax
  mov    -0x38(%rbp),%rsi
  mov    -0x10(%rbp),%rcx
  add    %rsi,%rcx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  je     L68
  mov    -0x18(%rbp),%rdx
  movsbl -0x28(%rbp),%eax
  mov    -0x38(%rbp),%rsi
  mov    -0x10(%rbp),%rcx
  add    %rsi,%rcx
  mov    %eax,%esi
  mov    %rcx,%rdi
  call   <memchr@plt>
  movb   $0x0,(%rax)
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %edx,%eax
  jmp    L67
L68:
  mov    -0x18(%rbp),%rax
  add    %rax,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L55
  mov    $0xffffffff,%eax
L67:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  leave
  ret
```

assistant: ```c
int read_until(int fd, size_t n, char terminator, char *buf) {
  size_t cgc_read = 0;
  while (cgc_read < n) {
    size_t tmp_read;
    if (receive(fd, buf + cgc_read, 1, &tmp_read) != 0 || tmp_read == 0)
      return -1;
    if (memchr(buf + cgc_read, terminator, tmp_read) != NULL) {
      *((char *)memchr(buf + cgc_read, terminator, tmp_read)) = '\0';
      return cgc_read + tmp_read;
    } else {
      cgc_read += tmp_read;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_until>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,0x4(%rsp)
  mov    %rcx,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L33
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    $0x0,%ebx
  lea    0x10(%rsp),%r15
L97:
  mov    0x8(%rsp),%rax
  lea    (%rax,%rbx,1),%rbp
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %rbp,%rsi
  mov    0x4(%rsp),%edi
  call   <receive@plt>
  test   %rax,%rax
  jne    L30
  mov    0x10(%rsp),%rdx
  test   %rdx,%rdx
  je     L8
  movsbl %r14b,%r12d
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  jne    L18
  mov    %rbx,%rax
  add    0x10(%rsp),%rax
  mov    %rax,%rbx
  cmp    %rax,%r13
  ja     L97
  mov    $0xffffffff,%eax
  jmp    L95
L18:
  mov    0x10(%rsp),%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <memchr@plt>
  movb   $0x0,(%rax)
  mov    %ebx,%eax
  add    0x10(%rsp),%eax
  jmp    L95
L30:
  mov    $0xffffffff,%eax
L95:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L71
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    $0xffffffff,%eax
  jmp    L95
L33:
  mov    $0xffffffff,%eax
  jmp    L95
L71:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_until(int fd, size_t n, char terminator, char *buf) {
  size_t cgc_read = 0;
  while (cgc_read < n) {
    size_t tmp_read;
    if (receive(fd, buf + cgc_read, 1, &tmp_read) != 0 || tmp_read == 0)
      return -1;
    if (memchr(buf + cgc_read, terminator, tmp_read) != NULL) {
      *((char *)memchr(buf + cgc_read, terminator, tmp_read)) = '\0';
      return cgc_read + tmp_read;
    } else {
      cgc_read += tmp_read;
    }
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_until>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L33
  mov    %edi,%r14d
  mov    %rcx,%r13
  xor    %ebx,%ebx
  movsbl %dl,%ebp
  lea    0x10(%rsp),%r15
  jmp    L68
  xchg   %ax,%ax
L20:
  mov    0x10(%rsp),%rdx
  test   %rdx,%rdx
  je     L33
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  jne    L53
  add    0x10(%rsp),%rbx
  cmp    %rbx,0x8(%rsp)
  jbe    L33
L68:
  lea    0x0(%r13,%rbx,1),%r12
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %r14d,%edi
  mov    %r12,%rsi
  call   <receive@plt>
  test   %rax,%rax
  je     L20
L33:
  mov    $0xffffffff,%eax
L6:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    0x10(%rsp),%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  movb   $0x0,(%rax)
  mov    0x10(%rsp),%eax
  add    %ebx,%eax
  jmp    L6
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_until(int fd, size_t n, char terminator, char *buf) {
  size_t cgc_read = 0;
  while (cgc_read < n) {
    size_t tmp_read;
    if (receive(fd, buf + cgc_read, 1, &tmp_read) != 0 || tmp_read == 0)
      return -1;
    if (memchr(buf + cgc_read, terminator, tmp_read) != NULL) {
      *((char *)memchr(buf + cgc_read, terminator, tmp_read)) = '\0';
      return cgc_read + tmp_read;
    } else {
      cgc_read += tmp_read;
    }
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_until>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L0
  mov    %edi,%r14d
  mov    %rcx,%r13
  xor    %ebx,%ebx
  movsbl %dl,%ebp
  lea    0x10(%rsp),%r15
  jmp    L68
  xchg   %ax,%ax
L42:
  mov    0x10(%rsp),%rdx
  test   %rdx,%rdx
  je     L0
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  test   %rax,%rax
  jne    L71
  add    0x10(%rsp),%rbx
  cmp    %rbx,0x8(%rsp)
  jbe    L0
L68:
  lea    0x0(%r13,%rbx,1),%r12
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %r14d,%edi
  mov    %r12,%rsi
  call   <receive@plt>
  test   %rax,%rax
  je     L42
L0:
  mov    $0xffffffff,%eax
L55:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L10
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L71:
  mov    0x10(%rsp),%rdx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <memchr@plt>
  movb   $0x0,(%rax)
  mov    0x10(%rsp),%eax
  add    %ebx,%eax
  jmp    L55
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int read_until(int fd, size_t n, char terminator, char *buf) {
  size_t cgc_read = 0;
  while (cgc_read < n) {
    size_t tmp_read;
    if (receive(fd, buf + cgc_read, 1, &tmp_read) != 0 || tmp_read == 0)
      return -1;
    if (memchr(buf + cgc_read, terminator, tmp_read) != NULL) {
      *((char *)memchr(buf + cgc_read, terminator, tmp_read)) = '\0';
      return cgc_read + tmp_read;
    } else {
      cgc_read += tmp_read;
    }
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x9,-0x8(%rbp)
  jg     L19
  mov    $0x1,%eax
  jmp    L4
L19:
  mov    -0x8(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rdi
  call   <getSize>
  add    $0x1,%eax
L4:
  leave
  ret
```

assistant: ```c
unsigned int getSize(const long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getSize>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x9,%rdi
  jg     L9
  ret
L9:
  sub    $0x8,%rsp
  movabs $0x6666666666666667,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x2,%rdx
  sar    $0x3f,%rdi
  sub    %rdi,%rdx
  mov    %rdx,%rdi
  call   <getSize>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
unsigned int getSize(const long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: What is the c source code of the assembly code below?

```asm
<getSize>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%r8d
  movabs $0xcccccccccccccccd,%rsi
  cmp    $0x9,%rdi
  jle    L4
  nopl   (%rax)
L8:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L8
L4:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int getSize(const long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getSize>:
  endbr64
  mov    %rdi,%rdx
  mov    $0x1,%r8d
  movabs $0xcccccccccccccccd,%rsi
  cmp    $0x9,%rdi
  jle    L17
  nopl   (%rax)
L16:
  mov    %rdx,%rax
  mov    %rdx,%rcx
  add    $0x1,%r8d
  mul    %rsi
  shr    $0x3,%rdx
  cmp    $0x63,%rcx
  jg     L16
L17:
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int getSize(const long int num) {
  if (num < 10)
    return 1;
  return 1 + getSize(num / 10);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1d(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void f() {
  char a;
  int b;
  void *data1 = &a;
  void *data2 = data1;
  b = *(int *)(data2);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f() {
  char a;
  int b;
  void *data1 = &a;
  void *data2 = data1;
  b = *(int *)(data2);
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f() {
  char a;
  int b;
  void *data1 = &a;
  void *data2 = data1;
  b = *(int *)(data2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f() {
  char a;
  int b;
  void *data1 = &a;
  void *data2 = data1;
  b = *(int *)(data2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uuid_str_vrsprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L6
  mov    $0xffffffff,%eax
  jmp    L15
L6:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L32
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <uuid_str_vasprintf@plt>
  mov    -0x18(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  jmp    L46
L32:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <uuid_str_vsnprintf@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L57
  mov    $0xffffffff,%eax
  jmp    L15
L57:
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rdi
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  call   <uuid_str_vsnprintf@plt>
L46:
  mov    -0xc(%rbp),%eax
L15:
  leave
  ret
```

assistant: ```c
int uuid_str_vrsprintf(char **str, const char *fmt, va_list ap) {
  int rv;
  size_t n;
  if (str == NULL)
    return -1;
  if (*str == NULL) {
    *str = uuid_str_vasprintf(fmt, ap);
    rv = strlen(*str);
  } else {
    n = strlen(*str);
    rv = uuid_str_vsnprintf(NULL, 0, fmt, ap);
    if ((*str = (char *)realloc(*str, n + rv + 1)) == NULL)
      return -1;
    uuid_str_vsnprintf((*str) + n, rv + 1, fmt, ap);
  }
  return rv;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uuid_str_vrsprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L3
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %edx,%r13d
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L4
  call   <strlen@plt>
  mov    %rax,%r14
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <uuid_str_vsnprintf@plt>
  mov    %eax,%ebp
  cltq
  lea    0x1(%r14,%rax,1),%rsi
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L45
  lea    0x1(%rbp),%esi
  lea    (%rax,%r14,1),%rdi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  call   <uuid_str_vsnprintf@plt>
L34:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  mov    %edx,%esi
  mov    %r12,%rdi
  call   <uuid_str_vasprintf@plt>
  mov    %rax,%rdi
  mov    %rax,(%rbx)
  call   <strlen@plt>
  mov    %eax,%ebp
  jmp    L34
L3:
  mov    $0xffffffff,%ebp
  jmp    L34
L45:
  mov    $0xffffffff,%ebp
  jmp    L34
```

assistant: ```c
int uuid_str_vrsprintf(char **str, const char *fmt, va_list ap) {
  int rv;
  size_t n;
  if (str == NULL)
    return -1;
  if (*str == NULL) {
    *str = uuid_str_vasprintf(fmt, ap);
    rv = strlen(*str);
  } else {
    n = strlen(*str);
    rv = uuid_str_vsnprintf(NULL, 0, fmt, ap);
    if ((*str = (char *)realloc(*str, n + rv + 1)) == NULL)
      return -1;
    uuid_str_vsnprintf((*str) + n, rv + 1, fmt, ap);
  }
  return rv;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<uuid_str_vrsprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L36
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  mov    %rsi,%r13
  mov    %edx,%r14d
  test   %rdi,%rdi
  je     L6
  call   <strlen@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <uuid_str_vsnprintf@plt>
  mov    (%rbx),%rdi
  mov    %eax,%r12d
  cltq
  lea    0x1(%rbp,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L36
  lea    0x1(%r12),%esi
  lea    (%rax,%rbp,1),%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <uuid_str_vsnprintf@plt>
L3:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r13,%rdi
  mov    %edx,%esi
  call   <uuid_str_vasprintf@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strlen@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L36:
  mov    $0xffffffff,%r12d
  jmp    L3
```

assistant: ```c
int uuid_str_vrsprintf(char **str, const char *fmt, va_list ap) {
  int rv;
  size_t n;
  if (str == NULL)
    return -1;
  if (*str == NULL) {
    *str = uuid_str_vasprintf(fmt, ap);
    rv = strlen(*str);
  } else {
    n = strlen(*str);
    rv = uuid_str_vsnprintf(NULL, 0, fmt, ap);
    if ((*str = (char *)realloc(*str, n + rv + 1)) == NULL)
      return -1;
    uuid_str_vsnprintf((*str) + n, rv + 1, fmt, ap);
  }
  return rv;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uuid_str_vrsprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L28
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  mov    %rsi,%r13
  mov    %edx,%r14d
  test   %rdi,%rdi
  je     L7
  call   <strlen@plt>
  mov    %r14d,%ecx
  mov    %r13,%rdx
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <uuid_str_vsnprintf@plt>
  mov    (%rbx),%rdi
  mov    %eax,%r12d
  cltq
  lea    0x1(%rbp,%rax,1),%rsi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L28
  lea    0x1(%r12),%esi
  lea    (%rax,%rbp,1),%rdi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  call   <uuid_str_vsnprintf@plt>
L33:
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %r13,%rdi
  mov    %edx,%esi
  call   <uuid_str_vasprintf@plt>
  mov    %rax,(%rbx)
  mov    %rax,%rdi
  call   <strlen@plt>
  pop    %rbx
  pop    %rbp
  mov    %eax,%r12d
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L28:
  mov    $0xffffffff,%r12d
  jmp    L33
```

assistant: ```c
int uuid_str_vrsprintf(char **str, const char *fmt, va_list ap) {
  int rv;
  size_t n;
  if (str == NULL)
    return -1;
  if (*str == NULL) {
    *str = uuid_str_vasprintf(fmt, ap);
    rv = strlen(*str);
  } else {
    n = strlen(*str);
    rv = uuid_str_vsnprintf(NULL, 0, fmt, ap);
    if ((*str = (char *)realloc(*str, n + rv + 1)) == NULL)
      return -1;
    uuid_str_vsnprintf((*str) + n, rv + 1, fmt, ap);
  }
  return rv;
}
```
user: What is the c source code of the assembly code below:

```asm
<Led_On>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0xe0200280,%eax
  movq   $0x1111,(%rax)
  mov    $0xe0200284,%eax
  movq   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Led_On() {
  (*(volatile unsigned long *)0xE0200280) = 0x00001111;
  (*(volatile unsigned long *)0xE0200284) = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<Led_On>:
  endbr64
  mov    $0xe0200280,%eax
  movq   $0x1111,(%rax)
  lea    0x4(%rax),%rax
  movq   $0x0,(%rax)
  ret
```

assistant: ```c
void Led_On() {
  (*(volatile unsigned long *)0xE0200280) = 0x00001111;
  (*(volatile unsigned long *)0xE0200284) = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Led_On>:
  endbr64
  mov    $0xe0200280,%eax
  movq   $0x1111,(%rax)
  movq   $0x0,0x4(%rax)
  ret
```

assistant: ```c
void Led_On() {
  (*(volatile unsigned long *)0xE0200280) = 0x00001111;
  (*(volatile unsigned long *)0xE0200284) = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Led_On>:
  endbr64
  mov    $0xe0200280,%eax
  movq   $0x1111,(%rax)
  movq   $0x0,0x4(%rax)
  ret
```

assistant: ```c
void Led_On() {
  (*(volatile unsigned long *)0xE0200280) = 0x00001111;
  (*(volatile unsigned long *)0xE0200284) = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xstrdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  lea    D2(%rip),%rax
  mov    %rax,%rsi
  mov    $0x68,%edi
  call   <err@plt>
L0:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
type_guessed: string

tool: D2: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *dup = strdup(s);
  if (dup == NULL)
    err(104, "strdup");
  return dup;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xstrdup>:
  endbr64
  push   %rbx
  call   <strdup@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L8:
  mov    %rbx,%rax
  pop    %rbx
  ret
L16:
  lea    D5(%rip),%rsi
  mov    $0x68,%edi
  call   <err@plt>
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *dup = strdup(s);
  if (dup == NULL)
    err(104, "strdup");
  return dup;
}
```
user: Translate the below assembly code into C programming language:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
L6:
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  lea    D3(%rip),%rsi
  mov    $0x68,%edi
  call   <err@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D3
type: string

tool: D3: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *dup = strdup(s);
  if (dup == NULL)
    err(104, "strdup");
  return dup;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xstrdup>:
  endbr64
  push   %r12
  call   <strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L0
L6:
  mov    %r12,%rax
  pop    %r12
  ret
L0:
  lea    D8(%rip),%rsi
  mov    $0x68,%edi
  call   <err@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: strdup

assistant: ```c
char *xstrdup(const char *s) {
  char *dup = strdup(s);
  if (dup == NULL)
    err(104, "strdup");
  return dup;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ana_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L20
L71:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L4
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L4
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  movzbl (%rcx),%edx
  cltq
  mov    %dl,-0x23(%rbp,%rax,1)
  jmp    L44
L4:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  je     L53
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  je     L53
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L53
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L44
L53:
  mov    -0x38(%rbp),%eax
  cltq
  movb   $0x0,-0x23(%rbp,%rax,1)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%ebx
  lea    -0x23(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  lea    -0x30(%rbp),%rax
  mov    %ebx,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
  movl   $0x0,-0x38(%rbp)
L44:
  addl   $0x1,-0x34(%rbp)
L20:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L71
  cmpl   $0x0,-0x38(%rbp)
  jne    L1
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
L1:
  mov    -0x38(%rbp),%eax
  cltq
  movb   $0x0,-0x23(%rbp,%rax,1)
  lea    -0x23(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%ecx
  lea    -0x30(%rbp),%rax
  mov    $0x30,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <insert@plt>
L2:
  mov    -0x30(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct Calentry *ana_str(const char *in) {
  struct Calentry *head = NULL;
  char num[11];
  int Cn = 0;
  for (int i = 0; in[i] != '\0'; ++i) {
    if (in[i] >= '0' && in[i] <= '9') {
      num[Cn++] = in[i];
    } else if (in[i] == '+' || in[i] == '-' || in[i] == '*' || in[i] == '/') {
      num[Cn] = '\0';
      insert(&head, atoi(num), in[i]);
      Cn = 0;
    }
  }
  if (Cn == 0)
    exit(1);
  else {
    num[Cn] = '\0';
    insert(&head, atoi(num), '0');
  }
  return head;
}
```