ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<gammln>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  movapd %xmm0,%xmm2
  addsd  D4(%rip),%xmm2
  movapd %xmm0,%xmm1
  addsd  D40(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  divsd  D9(%rip),%xmm1
  movapd %xmm2,%xmm5
  subsd  %xmm1,%xmm5
  lea    D18(%rip),%rax
  lea    0x30(%rax),%rdx
  movapd %xmm0,%xmm3
  movsd  D77(%rip),%xmm2
  movsd  D31(%rip),%xmm4
L6:
  addsd  %xmm4,%xmm3
  movsd  (%rax),%xmm1
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L6
  mulsd  D32(%rip),%xmm2
  divsd  %xmm0,%xmm2
  divsd  D9(%rip),%xmm2
  subsd  %xmm5,%xmm2
  pxor   %xmm0,%xmm0
  cvtsd2ss %xmm2,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_guessed: f64
name: parse_data
arguments: data_label: D40
type_guessed: f64
name: parse_data
arguments: data_label: D9
type_guessed: byte[8]
name: parse_data
arguments: data_label: D18
type_guessed: f64
name: parse_data
arguments: data_label: D77
type_guessed: f64
name: parse_data
arguments: data_label: D31
type_guessed: byte[8]
name: parse_data
arguments: data_label: D32
type_guessed: f64

tool: D4: 5.5

tool: D40: 0.5

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6c,0x40]}

tool: D18: 76.18

tool: D77: 1.000000000190015

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D32: 2.5066282746310007

assistant: ```c
float gammln(float xx) {
  double x, y, tmp, ser;
  static double cof[6] = {76.18, -86.50, 24.01, -1.23, 0.12, -0.53};
  int j;
  y = x = xx;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * tmp / 231;
  ser = 1.000000000190015;
  for (j = 0; j <= 5; j++)
    ser += cof[j] / ++y;
  return -tmp + ((2.5066282746310005 * ser / x) / 231);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gammln>:
  endbr64
  pxor   %xmm5,%xmm5
  movsd  D51(%rip),%xmm1
  movsd  D73(%rip),%xmm7
  lea    D77(%rip),%rax
  cvtss2sd %xmm0,%xmm5
  movsd  D36(%rip),%xmm0
  lea    0x30(%rax),%rdx
  movapd %xmm5,%xmm3
  addsd  %xmm5,%xmm1
  movsd  D48(%rip),%xmm2
  movsd  D66(%rip),%xmm4
  addsd  %xmm5,%xmm0
  movapd %xmm1,%xmm6
  mulsd  %xmm1,%xmm0
  movsd  D5(%rip),%xmm1
  divsd  %xmm7,%xmm0
  subsd  %xmm0,%xmm6
  jmp    L15
  nopl   (%rax)
L10:
  movsd  (%rax),%xmm1
L15:
  addsd  %xmm4,%xmm3
  add    $0x8,%rax
  divsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm2
  cmp    %rax,%rdx
  jne    L10
  mulsd  D59(%rip),%xmm2
  movapd %xmm2,%xmm0
  divsd  %xmm5,%xmm0
  divsd  %xmm7,%xmm0
  subsd  %xmm6,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: label: D51
data_type: f64
name: unpack_data
arguments: label: D73
data_type: byte[8]
name: unpack_data
arguments: label: D77
data_type: f64
name: unpack_data
arguments: label: D36
data_type: f64
name: unpack_data
arguments: label: D48
data_type: f64
name: unpack_data
arguments: label: D66
data_type: byte[8]
name: unpack_data
arguments: label: D5
data_type: f64
name: unpack_data
arguments: label: D59
data_type: f64

tool: D51: 5.5

tool: {"D73": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6c,0x40]}

tool: D77: 76.18

tool: D36: 0.5

tool: D48: 1.000000000190015

tool: {"D66": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D5: 76.18

tool: D59: 2.5066282746310007

assistant: ```c
float gammln(float xx) {
  double x, y, tmp, ser;
  static double cof[6] = {76.18, -86.50, 24.01, -1.23, 0.12, -0.53};
  int j;
  y = x = xx;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * tmp / 231;
  ser = 1.000000000190015;
  for (j = 0; j <= 5; j++)
    ser += cof[j] / ++y;
  return -tmp + ((2.5066282746310005 * ser / x) / 231);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gammln>:
  endbr64
  movsd  D13(%rip),%xmm1
  pxor   %xmm2,%xmm2
  movsd  D108(%rip),%xmm6
  cvtss2sd %xmm0,%xmm2
  movapd %xmm2,%xmm0
  movsd  D40(%rip),%xmm7
  movsd  D31(%rip),%xmm4
  addsd  %xmm1,%xmm0
  movsd  D61(%rip),%xmm3
  movsd  D71(%rip),%xmm5
  addsd  %xmm2,%xmm4
  addsd  %xmm2,%xmm3
  divsd  %xmm0,%xmm6
  addsd  %xmm1,%xmm0
  mulsd  %xmm4,%xmm3
  divsd  %xmm0,%xmm7
  addsd  %xmm1,%xmm0
  addsd  D107(%rip),%xmm6
  divsd  %xmm5,%xmm3
  addsd  %xmm6,%xmm7
  movsd  D38(%rip),%xmm6
  divsd  %xmm0,%xmm6
  addsd  %xmm1,%xmm0
  subsd  %xmm3,%xmm4
  addsd  %xmm7,%xmm6
  movsd  D101(%rip),%xmm7
  divsd  %xmm0,%xmm7
  addsd  %xmm1,%xmm0
  addsd  %xmm6,%xmm7
  movsd  D70(%rip),%xmm6
  divsd  %xmm0,%xmm6
  addsd  %xmm1,%xmm0
  movsd  D51(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  D113(%rip),%xmm0
  addsd  %xmm7,%xmm6
  addsd  %xmm6,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  %xmm2,%xmm0
  divsd  %xmm5,%xmm0
  subsd  %xmm4,%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: data_label: D13
type_guessed: byte[8]
name: read_data
arguments: data_label: D108
type_guessed: f64
name: read_data
arguments: data_label: D40
type_guessed: byte[8]
name: read_data
arguments: data_label: D31
type_guessed: f64
name: read_data
arguments: data_label: D61
type_guessed: f64
name: read_data
arguments: data_label: D71
type_guessed: byte[8]
name: read_data
arguments: data_label: D107
type_guessed: f64
name: read_data
arguments: data_label: D38
type_guessed: f64
name: read_data
arguments: data_label: D101
type_guessed: byte[8]
name: read_data
arguments: data_label: D70
type_guessed: f64
name: read_data
arguments: data_label: D51
type_guessed: byte[8]
name: read_data
arguments: data_label: D113
type_guessed: f64

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

tool: D108: 76.18

tool: {"D40": [0x00,0x00,0x00,0x00,0x00,0xa0,0x55,0xc0]}

tool: D31: 5.5

tool: D61: 0.5

tool: {"D71": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6c,0x40]}

tool: D107: 1.000000000190015

tool: D38: 24.01

tool: {"D101": [0xae,0x47,0xe1,0x7a,0x14,0xae,0xf3,0xbf]}

tool: D70: 0.12

tool: {"D51": [0xf6,0x28,0x5c,0x8f,0xc2,0xf5,0xe0,0xbf]}

tool: D113: 2.5066282746310007

assistant: ```c
float gammln(float xx) {
  double x, y, tmp, ser;
  static double cof[6] = {76.18, -86.50, 24.01, -1.23, 0.12, -0.53};
  int j;
  y = x = xx;
  tmp = x + 5.5;
  tmp -= (x + 0.5) * tmp / 231;
  ser = 1.000000000190015;
  for (j = 0; j <= 5; j++)
    ser += cof[j] / ++y;
  return -tmp + ((2.5066282746310005 * ser / x) / 231);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x9,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D29
datatype: string
name: unpack_data
arguments: data_label: D24
datatype: string
name: unpack_data
arguments: data_label: D27
datatype: string

tool: D29: __GNUC__ = %d


tool: D24: __GNUC_MINOR__ = %d


tool: D27: __GNUC_PATCHLEVEL__ = %d


assistant: ```c
int main() {
  printf("__GNUC__ = %d\n", 9);
  printf("__GNUC_MINOR__ = %d\n", 4);
  printf("__GNUC_PATCHLEVEL__ = %d\n", 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D17
datatype: string
name: disassemble_data
arguments: tag: D19
datatype: string
name: disassemble_data
arguments: tag: D14
datatype: string

tool: D17: __GNUC__ = %d


tool: D19: __GNUC_MINOR__ = %d


tool: D14: __GNUC_PATCHLEVEL__ = %d


assistant: ```c
int main() {
  printf("__GNUC__ = %d\n", 9);
  printf("__GNUC_MINOR__ = %d\n", 4);
  printf("__GNUC_PATCHLEVEL__ = %d\n", 0);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D18(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D23
type_guessed: string
name: parse_data
arguments: data_label: D10
type_guessed: string
name: parse_data
arguments: data_label: D18
type_guessed: string

tool: D23: __GNUC__ = %d


tool: D10: __GNUC_MINOR__ = %d


tool: D18: __GNUC_PATCHLEVEL__ = %d


assistant: ```c
int main() {
  printf("__GNUC__ = %d\n", 9);
  printf("__GNUC_MINOR__ = %d\n", 4);
  printf("__GNUC_PATCHLEVEL__ = %d\n", 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %esi,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string
name: disassemble_data
arguments: data_tag: D22
datatype: string

tool: D16: __GNUC__ = %d


tool: D9: __GNUC_MINOR__ = %d


tool: D22: __GNUC_PATCHLEVEL__ = %d


assistant: ```c
int main() {
  printf("__GNUC__ = %d\n", 9);
  printf("__GNUC_MINOR__ = %d\n", 4);
  printf("__GNUC_PATCHLEVEL__ = %d\n", 0);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D28(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rbx
  lea    D90(%rip),%r13
  lea    D4(%rip),%r12
  lea    D47(%rip),%rbp
L13:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  je     L80
  lea    -0x41(%rax),%edx
  cmp    $0x38,%dl
  ja     L0
  movzbl %dl,%edx
  movslq (%rbx,%rdx,4),%rdx
  add    %rbx,%rdx
  notrack jmp *%rdx
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  lea    D96(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  lea    D41(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  lea    D102(%rip),%rdi
  call   <printf@plt>
  jmp    L13
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L13
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L13
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L13
L0:
  movsbl %al,%edi
  call   <putchar@plt>
  jmp    L13
L80:
  lea    D75(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
type_infered: string
name: retrieve_data
arguments: data_tag: D90
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string
name: retrieve_data
arguments: data_tag: D47
type_infered: string
name: retrieve_data
arguments: data_tag: D62
type_infered: string
name: retrieve_data
arguments: data_tag: D96
type_infered: string
name: retrieve_data
arguments: data_tag: D46
type_infered: string
name: retrieve_data
arguments: data_tag: D41
type_infered: string
name: retrieve_data
arguments: data_tag: D102
type_infered: string
name: retrieve_data
arguments: data_tag: D75
type_infered: string

tool: D28: Enter phone number: 

tool: D90: 9

tool: D4: 8

tool: D47: 7

tool: D62: 2

tool: D96: 3

tool: D46: 4

tool: D41: 5

tool: D102: 6

tool: D75: 


assistant: ```c
int main(void) {
  char ch;
  printf("Enter phone number: ");
  while ((ch = getchar()) != '\n') {
    switch (ch) {
    case 'A':
    case 'a':
    case 'B':
    case 'b':
    case 'C':
    case 'c':
      printf("2");
      break;
    case 'D':
    case 'd':
    case 'E':
    case 'e':
    case 'F':
    case 'f':
      printf("3");
      break;
    case 'G':
    case 'g':
    case 'H':
    case 'h':
    case 'I':
    case 'i':
      printf("4");
      break;
    case 'J':
    case 'j':
    case 'K':
    case 'k':
    case 'L':
    case 'l':
      printf("5");
      break;
    case 'M':
    case 'm':
    case 'N':
    case 'n':
    case 'O':
    case 'o':
      printf("6");
      break;
    case 'P':
    case 'p':
    case 'R':
    case 'r':
    case 'S':
    case 's':
      printf("7");
      break;
    case 'T':
    case 't':
    case 'U':
    case 'u':
    case 'V':
    case 'v':
      printf("8");
      break;
    case 'W':
    case 'w':
    case 'X':
    case 'x':
    case 'Y':
    case 'y':
      printf("9");
      break;
    default:
      putchar(ch);
    }
  }
  printf("\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4c(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x48(%rbp)
  jmp    L23
L31:
  lea    -0x30(%rbp),%rcx
  lea    -0x38(%rbp),%rdx
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x30(%rbp),%rax
  add    %rax,%rax
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  lea    (%rdx,%rcx,1),%rsi
  cqto
  idiv   %rsi
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  sub    $0x2,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    -0x40(%rbp),%rdx
  sub    %rdx,%rax
  mov    -0x18(%rbp),%rdx
  lea    -0x3(%rdx),%rcx
  cqto
  idiv   %rcx
  mov    %rax,-0x10(%rbp)
  mov    -0x40(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  add    %rdx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L30
L44:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  add    %rax,-0x28(%rbp)
  addl   $0x1,-0x44(%rbp)
L30:
  mov    -0x44(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  jg     L44
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x48(%rbp)
L23:
  mov    -0x4c(%rbp),%eax
  cmp    %eax,-0x48(%rbp)
  jl     L31
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D32
data_type: string
name: parse_data
arguments: data_tag: D36
data_type: string
name: parse_data
arguments: data_tag: D0
data_type: string
name: parse_data
arguments: data_tag: D28
data_type: string

tool: D32: %d

tool: D36: %lld %lld %lld

tool: D0: %llu


tool: D28: %llu 

assistant: ```c
int main() {
  int cases;
  scanf("%d", &cases);
  int i;
  for (i = 0; i < cases; ++i) {
    long long third, lastthird, sum;
    scanf("%lld %lld %lld", &third, &lastthird, &sum);
    long long n = (2 * sum) / (third + lastthird);
    long long lastthirdpos = n - 2;
    long long d = (lastthird - third) / (lastthirdpos - 3);
    long long first = third - (2 * d);
    int a;
    printf("%llu\n", n);
    for (a = 0; a < n; ++a) {
      printf("%llu ", first);
      first = first + d;
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x1c(%rsp)
  jle    L34
  mov    $0x0,%r15d
  lea    0x30(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    D23(%rip),%r14
L42:
  lea    0x28(%rsp),%rdx
  lea    0x20(%rsp),%rsi
  mov    0x8(%rsp),%rcx
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x20(%rsp),%rbx
  mov    0x28(%rsp),%r13
  mov    0x30(%rsp),%rax
  add    %rax,%rax
  lea    (%rbx,%r13,1),%rcx
  cqto
  idiv   %rcx
  mov    %rax,%r12
  sub    %rbx,%r13
  lea    -0x5(%rax),%rcx
  mov    %r13,%rax
  cqto
  idiv   %rcx
  mov    %rax,%r13
  lea    (%rax,%rax,1),%rax
  sub    %rax,%rbx
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12,%r12
  jle    L49
  mov    $0x0,%ebp
L2:
  mov    %rbx,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    %r13,%rbx
  add    $0x1,%rbp
  cmp    %r12,%rbp
  jne    L2
L49:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r15d
  cmp    %r15d,0x1c(%rsp)
  jg     L42
L34:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D33
type_guessed: string
name: disassemble_data
arguments: label: D23
type_guessed: string
name: disassemble_data
arguments: label: D35
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D33: %d

tool: D23: %llu 

tool: D35: %lld %lld %lld

tool: D0: %llu


assistant: ```c
int main() {
  int cases;
  scanf("%d", &cases);
  int i;
  for (i = 0; i < cases; ++i) {
    long long third, lastthird, sum;
    scanf("%lld %lld %lld", &third, &lastthird, &sum);
    long long n = (2 * sum) / (third + lastthird);
    long long lastthirdpos = n - 2;
    long long d = (lastthird - third) / (lastthirdpos - 3);
    long long first = third - (2 * d);
    int a;
    printf("%llu\n", n);
    for (a = 0; a < n; ++a) {
      printf("%llu ", first);
      first = first + d;
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  lea    D24(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L38
  lea    0x40(%rsp),%rax
  xor    %r13d,%r13d
  lea    D32(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    0x38(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L36:
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  mov    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x40(%rsp),%rax
  mov    0x30(%rsp),%rcx
  lea    D17(%rip),%rdi
  mov    0x38(%rsp),%rbx
  add    %rax,%rax
  lea    (%rcx,%rbx,1),%rsi
  cqto
  sub    %rcx,%rbx
  idiv   %rsi
  mov    %rax,%r12
  lea    -0x5(%rax),%rsi
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  mov    %r12,%rsi
  mov    %rax,%rbx
  lea    (%rax,%rax,1),%rax
  sub    %rax,%rcx
  xor    %eax,%eax
  mov    %rcx,%r15
  call   <printf@plt>
  test   %r12,%r12
  jle    L31
  xor    %r14d,%r14d
L1:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  add    %rbx,%r15
  cmp    %r14,%r12
  jne    L1
L31:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,0x2c(%rsp)
  jg     L36
L38:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D24
type_guessed: string
name: retrieve_data
arguments: tag: D32
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D17
type_guessed: string

tool: D24: %d

tool: D32: %llu 

tool: D16: %lld %lld %lld

tool: D17: %llu


assistant: ```c
int main() {
  int cases;
  scanf("%d", &cases);
  int i;
  for (i = 0; i < cases; ++i) {
    long long third, lastthird, sum;
    scanf("%lld %lld %lld", &third, &lastthird, &sum);
    long long n = (2 * sum) / (third + lastthird);
    long long lastthirdpos = n - 2;
    long long d = (lastthird - third) / (lastthirdpos - 3);
    long long first = third - (2 * d);
    int a;
    printf("%llu\n", n);
    for (a = 0; a < n; ++a) {
      printf("%llu ", first);
      first = first + d;
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D29(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x2c(%rsp),%rsi
  call   <scanf@plt>
  mov    0x2c(%rsp),%eax
  test   %eax,%eax
  jle    L19
  lea    0x40(%rsp),%rax
  xor    %r13d,%r13d
  lea    D12(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    0x38(%rsp),%rax
  mov    %rax,0x8(%rsp)
  lea    0x30(%rsp),%rax
  mov    %rax,0x18(%rsp)
  nopw   0x0(%rax,%rax,1)
L13:
  mov    0x10(%rsp),%rcx
  mov    0x8(%rsp),%rdx
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  mov    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x40(%rsp),%rax
  mov    0x30(%rsp),%rcx
  lea    D25(%rip),%rdi
  mov    0x38(%rsp),%rbx
  add    %rax,%rax
  lea    (%rcx,%rbx,1),%rsi
  cqto
  sub    %rcx,%rbx
  idiv   %rsi
  mov    %rax,%r12
  lea    -0x5(%rax),%rsi
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  mov    %r12,%rsi
  mov    %rax,%rbx
  lea    (%rax,%rax,1),%rax
  sub    %rax,%rcx
  xor    %eax,%eax
  mov    %rcx,%r15
  call   <printf@plt>
  test   %r12,%r12
  jle    L23
  xor    %r14d,%r14d
L44:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r14
  call   <printf@plt>
  add    %rbx,%r15
  cmp    %r14,%r12
  jne    L44
L23:
  mov    $0xa,%edi
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r13d,0x2c(%rsp)
  jg     L13
L19:
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D29
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D25
type: string

tool: D29: %d

tool: D12: %llu 

tool: D18: %lld %lld %lld

tool: D25: %llu


assistant: ```c
int main() {
  int cases;
  scanf("%d", &cases);
  int i;
  for (i = 0; i < cases; ++i) {
    long long third, lastthird, sum;
    scanf("%lld %lld %lld", &third, &lastthird, &sum);
    long long n = (2 * sum) / (third + lastthird);
    long long lastthirdpos = n - 2;
    long long d = (lastthird - third) / (lastthirdpos - 3);
    long long first = third - (2 * d);
    int a;
    printf("%llu\n", n);
    for (a = 0; a < n; ++a) {
      printf("%llu ", first);
      first = first + d;
    }
    printf("\n");
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_vRcSLE4442_Close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x23f2,%edx
  lea    D5(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  cmpl   $0x0,-0xc(%rbp)
  je     L1
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <vWriteLogTxt@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
datatype: string
name: parse_data
arguments: tag: D9
datatype: string

tool: D5: %u()

tool: D9: _SLE4442_Close iDoRemoteFunc ret = %d

assistant: ```c
void _vRcSLE4442_Close(void) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u()", 9202);
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 1);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_SLE4442_Close iDoRemoteFunc ret = %d", uiRet);
  }
}
```