ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matmul>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  lea    0x1c(%rdx),%r11
  add    $0x94,%rdx
  mov    %r11,%rax
L23:
  movl   $0x0,(%rax)
  movl   $0x0,0x4(%rax)
  movl   $0x0,0x8(%rax)
  movl   $0x0,0xc(%rax)
  movl   $0x0,0x10(%rax)
  add    $0x18,%rax
  cmp    %rdx,%rax
  jne    L23
  lea    0x1c(%rdi),%r9
  lea    0x30(%rdi),%r8
  lea    0xa8(%rdi),%rbx
  lea    0x18(%rbp),%r10
L19:
  lea    0x4(%rbp),%rdi
  mov    %r11,%rsi
L24:
  mov    %rdi,%rcx
  mov    %r9,%rax
L1:
  mov    (%rax),%edx
  imul   0x18(%rcx),%edx
  add    %edx,(%rsi)
  add    $0x4,%rax
  add    $0x18,%rcx
  cmp    %r8,%rax
  jne    L1
  add    $0x4,%rdi
  add    $0x4,%rsi
  cmp    %rdi,%r10
  jne    L24
  add    $0x18,%r9
  add    $0x18,%r8
  add    $0x18,%r11
  cmp    %rbx,%r8
  jne    L19
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
matmul(int a[5 + 1][5 + 1], int b[5 + 1][5 + 1], int c[5 + 1][5 + 1]) {
  int i, j, k;
IL0:
  for (i = 1; i <= 5; i++)
  IL1:
    for (j = 1; j <= 5; j++)
      c[i][j] = 0;
CL0:
  for (i = 1; i <= 5; i++)
  CL1:
    for (j = 1; j <= 5; j++)
    CL2:
      for (k = 1; k <= 5; k++)
        c[i][j] += a[i][k] * b[k][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<matmul>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x1c(%rdx),%rbx
  add    $0x94,%rdx
  mov    %rbx,%rax
L6:
  pxor   %xmm0,%xmm0
  movl   $0x0,0x10(%rax)
  add    $0x18,%rax
  movups %xmm0,-0x18(%rax)
  cmp    %rdx,%rax
  jne    L6
  lea    0x1c(%rdi),%r10
  lea    0x30(%rdi),%r8
  lea    0xa8(%rdi),%rbp
  lea    0x4(%rsi),%r12
  lea    0x18(%rsi),%r11
L28:
  mov    %r12,%r9
  mov    %rbx,%rdi
L18:
  mov    (%rdi),%esi
  mov    %r9,%rcx
  mov    %r10,%rax
L16:
  mov    (%rax),%edx
  imul   0x18(%rcx),%edx
  add    $0x4,%rax
  add    $0x18,%rcx
  add    %edx,%esi
  mov    %esi,(%rdi)
  cmp    %r8,%rax
  jne    L16
  add    $0x4,%r9
  add    $0x4,%rdi
  cmp    %r9,%r11
  jne    L18
  lea    0x18(%rax),%r8
  add    $0x18,%r10
  add    $0x18,%rbx
  cmp    %rbp,%r8
  jne    L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
matmul(int a[5 + 1][5 + 1], int b[5 + 1][5 + 1], int c[5 + 1][5 + 1]) {
  int i, j, k;
IL0:
  for (i = 1; i <= 5; i++)
  IL1:
    for (j = 1; j <= 5; j++)
      c[i][j] = 0;
CL0:
  for (i = 1; i <= 5; i++)
  CL1:
    for (j = 1; j <= 5; j++)
    CL2:
      for (k = 1; k <= 5; k++)
        c[i][j] += a[i][k] * b[k][j];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D38(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D67(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D56(%rip),%rdi
  call   <puts@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L23
  jg     L36
  cmp    $0x1,%eax
  je     L88
  cmp    $0x2,%eax
  jne    L7
  mov    0xc(%rsp),%esi
  sub    0x10(%rsp),%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L36:
  cmp    $0x4,%eax
  jne    L7
  mov    0xc(%rsp),%eax
  cltd
  idivl  0x10(%rsp)
  mov    %eax,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L88:
  mov    0x10(%rsp),%esi
  add    0xc(%rsp),%esi
  lea    D71(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L23:
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D58
datatype: string
name: unpack_data
arguments: tag: D38
datatype: string
name: unpack_data
arguments: tag: D67
datatype: string
name: unpack_data
arguments: tag: D56
datatype: string
name: unpack_data
arguments: tag: D54
datatype: string
name: unpack_data
arguments: tag: D22
datatype: string
name: unpack_data
arguments: tag: D59
datatype: string
name: unpack_data
arguments: tag: D71
datatype: string
name: unpack_data
arguments: tag: D34
datatype: string

tool: D58: digite o primeiro numero:

tool: D38: %d

tool: D67: digite o segundo numero:

tool: D56: Qual operacao voce deseja ?

tool: D54:  1 Soma
 2 Subtracao
 3 Multiplicacao
 4 Divisao

tool: D22: voce escolheu Subtracao %d

tool: D59: voce escolheu Divisao %d

tool: D71: voce escolheu soma %d

tool: D34: voce escolheu Multiplicacao %d

assistant: ```c
int main() {
  int a, b, operacao;
  printf("digite o primeiro numero:\n");
  scanf("%d", &a);
  printf("digite o segundo numero:\n");
  scanf("%d", &b);
  printf("Qual operacao voce deseja ?\n");
  printf(" 1 Soma\n 2 Subtracao\n 3 Multiplicacao\n 4 Divisao\n");
  scanf("%d", &operacao);
  switch (operacao) {
  case 1:
    printf("voce escolheu soma %d", a + b);
    break;
  case 2:
    printf("voce escolheu Subtracao %d", a - b);
    break;
  case 3:
    printf("voce escolheu Multiplicacao %d", a * b);
    break;
  case 4:
    printf("voce escolheu Divisao %d", a / b);
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D29(%rip),%rdi
  lea    D15(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D54(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D85(%rip),%rdi
  call   <puts@plt>
  lea    D75(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L81
  jg     L21
  cmp    $0x1,%eax
  je     L3
  cmp    $0x2,%eax
  jne    L20
  mov    0xc(%rsp),%esi
  lea    D31(%rip),%rdi
  sub    0x10(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L21:
  cmp    $0x4,%eax
  jne    L20
  mov    0xc(%rsp),%eax
  lea    D66(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L20
L81:
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D89(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L20
L3:
  mov    0x10(%rsp),%esi
  lea    D67(%rip),%rdi
  add    0xc(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L20
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D29
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string
name: retrieve_data
arguments: label: D54
data_type: string
name: retrieve_data
arguments: label: D85
data_type: string
name: retrieve_data
arguments: label: D75
data_type: string
name: retrieve_data
arguments: label: D31
data_type: string
name: retrieve_data
arguments: label: D66
data_type: string
name: retrieve_data
arguments: label: D89
data_type: string
name: retrieve_data
arguments: label: D67
data_type: string

tool: D29: digite o primeiro numero:

tool: D15: %d

tool: D54: digite o segundo numero:

tool: D85: Qual operacao voce deseja ?

tool: D75:  1 Soma
 2 Subtracao
 3 Multiplicacao
 4 Divisao

tool: D31: voce escolheu Subtracao %d

tool: D66: voce escolheu Divisao %d

tool: D89: voce escolheu Multiplicacao %d

tool: D67: voce escolheu soma %d

assistant: ```c
int main() {
  int a, b, operacao;
  printf("digite o primeiro numero:\n");
  scanf("%d", &a);
  printf("digite o segundo numero:\n");
  scanf("%d", &b);
  printf("Qual operacao voce deseja ?\n");
  printf(" 1 Soma\n 2 Subtracao\n 3 Multiplicacao\n 4 Divisao\n");
  scanf("%d", &operacao);
  switch (operacao) {
  case 1:
    printf("voce escolheu soma %d", a + b);
    break;
  case 2:
    printf("voce escolheu Subtracao %d", a - b);
    break;
  case 3:
    printf("voce escolheu Multiplicacao %d", a * b);
    break;
  case 4:
    printf("voce escolheu Divisao %d", a / b);
    break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D64(%rip),%rdi
  lea    D79(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D52(%rip),%rdi
  call   <puts@plt>
  lea    D66(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    $0x3,%eax
  je     L83
  jg     L68
  cmp    $0x1,%eax
  je     L17
  cmp    $0x2,%eax
  jne    L13
  mov    0xc(%rsp),%esi
  lea    D68(%rip),%rdi
  sub    0x10(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L68:
  cmp    $0x4,%eax
  jne    L13
  mov    0xc(%rsp),%eax
  lea    D28(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L83:
  mov    0xc(%rsp),%esi
  imul   0x10(%rsp),%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L17:
  mov    0x10(%rsp),%esi
  lea    D41(%rip),%rdi
  add    0xc(%rsp),%esi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L13
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D64
data_type: string
name: unpack_data
arguments: tag: D79
data_type: string
name: unpack_data
arguments: tag: D55
data_type: string
name: unpack_data
arguments: tag: D52
data_type: string
name: unpack_data
arguments: tag: D66
data_type: string
name: unpack_data
arguments: tag: D68
data_type: string
name: unpack_data
arguments: tag: D28
data_type: string
name: unpack_data
arguments: tag: D59
data_type: string
name: unpack_data
arguments: tag: D41
data_type: string

tool: D64: digite o primeiro numero:

tool: D79: %d

tool: D55: digite o segundo numero:

tool: D52: Qual operacao voce deseja ?

tool: D66:  1 Soma
 2 Subtracao
 3 Multiplicacao
 4 Divisao

tool: D68: voce escolheu Subtracao %d

tool: D28: voce escolheu Divisao %d

tool: D59: voce escolheu Multiplicacao %d

tool: D41: voce escolheu soma %d

assistant: ```c
int main() {
  int a, b, operacao;
  printf("digite o primeiro numero:\n");
  scanf("%d", &a);
  printf("digite o segundo numero:\n");
  scanf("%d", &b);
  printf("Qual operacao voce deseja ?\n");
  printf(" 1 Soma\n 2 Subtracao\n 3 Multiplicacao\n 4 Divisao\n");
  scanf("%d", &operacao);
  switch (operacao) {
  case 1:
    printf("voce escolheu soma %d", a + b);
    break;
  case 2:
    printf("voce escolheu Subtracao %d", a - b);
    break;
  case 3:
    printf("voce escolheu Multiplicacao %d", a * b);
    break;
  case 4:
    printf("voce escolheu Divisao %d", a / b);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Joy_Cursor_Fire1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L12
  mov    $0x22,%edi
  call   <cpc_key_press@plt>
  jmp    L0
L12:
  mov    $0x22,%edi
  call   <cpc_key_unpress@plt>
L0:
  nop
  leave
  ret
```

assistant: ```c
void Joy_Cursor_Fire1(int value) {
  if (value) {
    cpc_key_press(0x22);
  } else {
    cpc_key_unpress(0x22);
  };
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Joy_Cursor_Fire1>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L12
  mov    $0x22,%edi
  call   <cpc_key_press@plt>
L2:
  add    $0x8,%rsp
  ret
L12:
  mov    $0x22,%edi
  call   <cpc_key_unpress@plt>
  jmp    L2
```

assistant: ```c
void Joy_Cursor_Fire1(int value) {
  if (value) {
    cpc_key_press(0x22);
  } else {
    cpc_key_unpress(0x22);
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Joy_Cursor_Fire1>:
  endbr64
  test   %edi,%edi
  mov    $0x22,%edi
  je     L1
  jmp    1070 <cpc_key_press@plt>
  nopw   0x0(%rax,%rax,1)
L1:
  jmp    1060 <cpc_key_unpress@plt>
```

assistant: ```c
void Joy_Cursor_Fire1(int value) {
  if (value) {
    cpc_key_press(0x22);
  } else {
    cpc_key_unpress(0x22);
  };
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Joy_Cursor_Fire1>:
  endbr64
  test   %edi,%edi
  mov    $0x22,%edi
  je     L3
  jmp    1070 <cpc_key_press@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  jmp    1060 <cpc_key_unpress@plt>
```

assistant: ```c
void Joy_Cursor_Fire1(int value) {
  if (value) {
    cpc_key_press(0x22);
  } else {
    cpc_key_unpress(0x22);
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rrand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L8
  mov    $0x0,%eax
  jmp    L27
L8:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0x8(%rbp)
L1:
  mov    $0x0,%eax
  call   <getrand@plt>
  mov    %eax,-0x4(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  sub    -0x8(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L1
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
L27:
  leave
  ret
```

assistant: ```c
int rrand(int m) {
  int i, k;
  if (m <= 0)
    return 0;
  k = RAND_MAX % m;
  do {
    i = getrand();
  } while (i >= (RAND_MAX - k));
  return i % m;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rrand>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  jle    L9
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  cltd
  idiv   %edi
  mov    %edx,%ebx
L15:
  mov    $0x0,%eax
  call   <getrand@plt>
  mov    D5(%rip),%rdx
  mov    (%rdx),%edx
  sub    %ebx,%edx
  cmp    %eax,%edx
  jle    L15
  cltd
  idiv   %ebp
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  mov    %edx,%eax
  ret
```

assistant: ```c
int rrand(int m) {
  int i, k;
  if (m <= 0)
    return 0;
  k = RAND_MAX % m;
  do {
    i = getrand();
  } while (i >= (RAND_MAX - k));
  return i % m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rrand>:
  endbr64
  test   %edi,%edi
  jle    L4
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    D3(%rip),%rbx
  mov    (%rbx),%eax
  cltd
  idiv   %edi
  mov    %edx,%ebp
  nopl   (%rax)
L16:
  xor    %eax,%eax
  call   <getrand@plt>
  mov    (%rbx),%ecx
  sub    %ebp,%ecx
  cmp    %eax,%ecx
  jle    L16
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rrand(int m) {
  int i, k;
  if (m <= 0)
    return 0;
  k = RAND_MAX % m;
  do {
    i = getrand();
  } while (i >= (RAND_MAX - k));
  return i % m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rrand>:
  endbr64
  test   %edi,%edi
  jle    L13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    D2(%rip),%rbx
  mov    (%rbx),%eax
  cltd
  idiv   %edi
  mov    %edx,%ebp
  nopl   (%rax)
L6:
  xor    %eax,%eax
  call   <getrand@plt>
  mov    (%rbx),%ecx
  sub    %ebp,%ecx
  cmp    %eax,%ecx
  jle    L6
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rrand(int m) {
  int i, k;
  if (m <= 0)
    return 0;
  k = RAND_MAX % m;
  do {
    i = getrand();
  } while (i >= (RAND_MAX - k));
  return i % m;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_num_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  jg     L4
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <print_num_reverse>
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L4:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D8: %d 

assistant: ```c
void print_num_reverse(int begin) {
  if (begin < 10) {
    begin++;
    print_num_reverse(begin);
    printf("%d ", begin);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_num_reverse>:
  endbr64
  cmp    $0x9,%edi
  jle    L3
  ret
L3:
  push   %rbx
  lea    0x1(%rdi),%ebx
  mov    %ebx,%edi
  call   <print_num_reverse>
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
datatype: string

tool: D9: %d 

assistant: ```c
void print_num_reverse(int begin) {
  if (begin < 10) {
    begin++;
    print_num_reverse(begin);
    printf("%d ", begin);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_num_reverse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x9,%edi
  jle    L39
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L39:
  lea    0x1(%rdi),%r13d
  lea    D3(%rip),%r12
  jne    L29
L37:
  add    $0x8,%rsp
  mov    %r13d,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L29:
  lea    0x2(%rdi),%r14d
  cmp    $0x8,%edi
  jne    L8
L34:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L37
  xchg   %ax,%ax
L8:
  lea    0x3(%rdi),%ebp
  mov    %ebp,%edi
  call   <print_num_reverse>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L34
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: %d 

assistant: ```c
void print_num_reverse(int begin) {
  if (begin < 10) {
    begin++;
    print_num_reverse(begin);
    printf("%d ", begin);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<print_num_reverse>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  cmp    $0x9,%edi
  jle    L36
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  lea    0x1(%rdi),%r13d
  lea    D8(%rip),%r12
  jne    L4
L39:
  add    $0x8,%rsp
  mov    %r13d,%esi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  lea    0x2(%rdi),%r14d
  cmp    $0x8,%edi
  jne    L15
L44:
  mov    %r14d,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L39
  xchg   %ax,%ax
L15:
  lea    0x3(%rdi),%ebp
  mov    %ebp,%edi
  call   <print_num_reverse>
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L44
```

tool_calls: name: retrieve_data
arguments: tag: D8
type_guessed: string

tool: D8: %d 

assistant: ```c
void print_num_reverse(int begin) {
  if (begin < 10) {
    begin++;
    print_num_reverse(begin);
    printf("%d ", begin);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<setup_ball_radii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %edi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <init_for@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L16
L8:
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <set_atom_ball@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <next_for@plt>
  mov    %eax,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void setup_ball_radii(double ball_radius, int atom_set) {
  int o;
  for (o = init_for(atom_set); o != 0; o = next_for(atom_set)) {
    set_atom_ball(o, ball_radius);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<setup_ball_radii>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movq   %xmm0,%rbp
  mov    %edi,%ebx
  call   <init_for@plt>
  mov    %eax,%edi
  test   %eax,%eax
  je     L11
L2:
  movq   %rbp,%xmm0
  call   <set_atom_ball@plt>
  mov    %ebx,%edi
  call   <next_for@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L2
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void setup_ball_radii(double ball_radius, int atom_set) {
  int o;
  for (o = init_for(atom_set); o != 0; o = next_for(atom_set)) {
    set_atom_ball(o, ball_radius);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<setup_ball_radii>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <init_for@plt>
  test   %eax,%eax
  je     L8
  mov    %eax,%edi
  nopl   (%rax)
L3:
  movq   %r14,%xmm0
  call   <set_atom_ball@plt>
  mov    %ebx,%edi
  call   <next_for@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L3
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
void setup_ball_radii(double ball_radius, int atom_set) {
  int o;
  for (o = init_for(atom_set); o != 0; o = next_for(atom_set)) {
    set_atom_ball(o, ball_radius);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<setup_ball_radii>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %rbx
  mov    %edi,%ebx
  sub    $0x8,%rsp
  call   <init_for@plt>
  test   %eax,%eax
  je     L16
  mov    %eax,%edi
  nopl   (%rax)
L1:
  movq   %r14,%xmm0
  call   <set_atom_ball@plt>
  mov    %ebx,%edi
  call   <next_for@plt>
  mov    %eax,%edi
  test   %eax,%eax
  jne    L1
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %r14
  ret
```

assistant: ```c
void setup_ball_radii(double ball_radius, int atom_set) {
  int o;
  for (o = init_for(atom_set); o != 0; o = next_for(atom_set)) {
    set_atom_ball(o, ball_radius);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<starts_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L31
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L48
  mov    $0x0,%eax
  jmp    L43
L48:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L30
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
L30:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int starts_with(const char *input, const char *test) {
  while (*input && *test) {
    if (*input != *test)
      return 0;
    ++input;
    ++test;
  }
  return *test == '\0';
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<starts_with>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L15
L6:
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L15
  cmp    %al,%dl
  jne    L25
  add    $0x1,%rdi
  add    $0x1,%rsi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L15:
  cmpb   $0x0,(%rsi)
  sete   %al
  movzbl %al,%eax
  ret
L25:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int starts_with(const char *input, const char *test) {
  while (*input && *test) {
    if (*input != *test)
      return 0;
    ++input;
    ++test;
  }
  return *test == '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<starts_with>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L37
  jmp    L42
  nopl   (%rax)
L10:
  cmp    %dl,%al
  jne    L47
  movzbl 0x1(%rdi),%edx
  add    $0x1,%rdi
  lea    0x1(%rsi),%rax
  test   %dl,%dl
  je     L9
  mov    %rax,%rsi
L37:
  movzbl (%rsi),%eax
  test   %al,%al
  jne    L10
L57:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl 0x1(%rsi),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
L42:
  movzbl (%rsi),%eax
  jmp    L57
```

assistant: ```c
int starts_with(const char *input, const char *test) {
  while (*input && *test) {
    if (*input != *test)
      return 0;
    ++input;
    ++test;
  }
  return *test == '\0';
}
```