ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uitodec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L58
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x30,(%rax)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L16
L58:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L20:
  addl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x4(%rbp)
  jne    L20
  mov    -0x8(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rax,-0x20(%rbp)
  jmp    L33
L51:
  mov    -0x14(%rbp),%ecx
  mov    %ecx,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  mov    %eax,%edx
  shr    $0x3,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x20(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    $0xcccccccd,%eax
  imul   %rdx,%rax
  shr    $0x20,%rax
  shr    $0x3,%eax
  mov    %eax,-0x14(%rbp)
L33:
  cmpl   $0x0,-0x14(%rbp)
  jne    L51
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  add    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
L16:
  pop    %rbp
  ret
```

assistant: ```c
void uitodec(unsigned int value, char *str) {
  int length;
  unsigned int tmp;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 10;
  }
  str += length - 1;
  while (value > 0) {
    *(str--) = (value % 10) + '0';
    value /= 10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uitodec>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0x0,%ecx
  mov    $0xcccccccd,%r8d
  test   %edi,%edi
  je     L26
L0:
  add    $0x1,%ecx
  mov    %eax,%edi
  mov    %eax,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  cmp    $0x9,%edi
  ja     L0
  movslq %ecx,%r8
  lea    -0x1(%rsi,%r8,1),%rcx
  mov    $0xcccccccd,%r10d
L5:
  mov    %rcx,%r9
  sub    $0x1,%rcx
  mov    %edx,%eax
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  mov    %edx,%esi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,0x1(%rcx)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  ja     L5
  movb   $0x0,(%r9,%r8,1)
  ret
L26:
  movb   $0x30,(%rsi)
  movb   $0x0,0x1(%rsi)
  ret
```

assistant: ```c
void uitodec(unsigned int value, char *str) {
  int length;
  unsigned int tmp;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 10;
  }
  str += length - 1;
  while (value > 0) {
    *(str--) = (value % 10) + '0';
    value /= 10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uitodec>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0xcccccccd,%r8d
  xor    %edi,%edi
  test   %edx,%edx
  je     L2
  nopl   0x0(%rax)
L20:
  mov    %eax,%eax
  add    $0x1,%edi
  mov    %rax,%rcx
  imul   %r8,%rax
  shr    $0x23,%rax
  cmp    $0x9,%ecx
  ja     L20
  movslq %edi,%r8
  mov    $0xcccccccd,%r10d
  lea    -0x1(%rsi,%r8,1),%rcx
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %edx,%eax
  mov    %edx,%esi
  mov    %rcx,%r9
  sub    $0x1,%rcx
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,0x1(%rcx)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  ja     L27
  movb   $0x0,(%r9,%r8,1)
  ret
L2:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void uitodec(unsigned int value, char *str) {
  int length;
  unsigned int tmp;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 10;
  }
  str += length - 1;
  while (value > 0) {
    *(str--) = (value % 10) + '0';
    value /= 10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uitodec>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  mov    $0xcccccccd,%r8d
  xor    %edi,%edi
  test   %edx,%edx
  je     L12
  nopl   0x0(%rax)
L5:
  mov    %eax,%eax
  add    $0x1,%edi
  mov    %rax,%rcx
  imul   %r8,%rax
  shr    $0x23,%rax
  cmp    $0x9,%ecx
  ja     L5
  movslq %edi,%r8
  mov    $0xcccccccd,%r10d
  lea    -0x1(%rsi,%r8,1),%rcx
  nopl   0x0(%rax,%rax,1)
L23:
  mov    %edx,%eax
  mov    %edx,%esi
  mov    %rcx,%r9
  sub    $0x1,%rcx
  imul   %r10,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edi
  add    %edi,%edi
  sub    %edi,%esi
  add    $0x30,%esi
  mov    %sil,0x1(%rcx)
  mov    %edx,%esi
  mov    %eax,%edx
  cmp    $0x9,%esi
  ja     L23
  movb   $0x0,(%r9,%r8,1)
  ret
L12:
  mov    $0x30,%eax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void uitodec(unsigned int value, char *str) {
  int length;
  unsigned int tmp;
  if (value == 0) {
    *(str++) = '0';
    *str = '\0';
    return;
  }
  tmp = value;
  length = 0;
  while (tmp > 0) {
    length++;
    tmp /= 10;
  }
  str += length - 1;
  while (value > 0) {
    *(str--) = (value % 10) + '0';
    value /= 10;
  }
  str += length + 1;
  *(str) = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sendConnect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x3,%eax
  ja     L14
  mov    $0xffffffff,%eax
  jmp    L3
L14:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <waitforack@plt>
  test   %rax,%rax
  jne    L38
  mov    $0x0,%eax
  jmp    L3
L38:
  mov    $0x1,%eax
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
datatype: string

tool: D8: CON

assistant: ```c
int sendConnect(int sock) {
  int bsent;
  bsent = write(sock, "CON", sizeof("CON"));
  if (bsent < sizeof("CON"))
    return (-1);
  if (waitforack(sock) == 0)
    return 0;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sendConnect>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edx
  lea    D5(%rip),%rsi
  call   <write@plt>
  mov    %eax,%edx
  mov    $0xffffffff,%eax
  cmp    $0x3,%edx
  ja     L14
L10:
  pop    %rbx
  ret
L14:
  mov    %ebx,%edi
  call   <waitforack@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L10
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: CON

assistant: ```c
int sendConnect(int sock) {
  int bsent;
  bsent = write(sock, "CON", sizeof("CON"));
  if (bsent < sizeof("CON"))
    return (-1);
  if (waitforack(sock) == 0)
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sendConnect>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  lea    D8(%rip),%rsi
  mov    %edi,%ebp
  call   <write@plt>
  mov    %eax,%r8d
  mov    $0xffffffff,%eax
  cmp    $0x3,%r8d
  ja     L9
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %ebp,%edi
  call   <waitforack@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D8
type_guessed: string

tool: D8: CON

assistant: ```c
int sendConnect(int sock) {
  int bsent;
  bsent = write(sock, "CON", sizeof("CON"));
  if (bsent < sizeof("CON"))
    return (-1);
  if (waitforack(sock) == 0)
    return 0;
  else
    return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sendConnect>:
  endbr64
  push   %rbp
  mov    $0x4,%edx
  lea    D4(%rip),%rsi
  mov    %edi,%ebp
  call   <write@plt>
  mov    %eax,%r8d
  mov    $0xffffffff,%eax
  cmp    $0x3,%r8d
  ja     L1
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebp,%edi
  call   <waitforack@plt>
  pop    %rbp
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
datatype: string

tool: D4: CON

assistant: ```c
int sendConnect(int sock) {
  int bsent;
  bsent = write(sock, "CON", sizeof("CON"));
  if (bsent < sizeof("CON"))
    return (-1);
  if (waitforack(sock) == 0)
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L28
L17:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  not    %eax
  mov    %eax,%esi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  jne    L17
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D24
type: string

tool: D21: %d

tool: D14: %u

tool: D24: %u


assistant: ```c
int main() {
  int count = 0;
  scanf("%d", &count);
  uint32_t t = 0;
  while (count--) {
    scanf("%u", &t);
    printf("%u\n", ~t);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  mov    %rsp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movl   $0x0,0x4(%rsp)
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L3
  lea    0x4(%rsp),%r12
  lea    D24(%rip),%rbp
  lea    D23(%rip),%rbx
L28:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  not    %esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L28
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D24
type: string
name: disassemble_data
arguments: label: D23
type: string

tool: D26: %d

tool: D24: %u

tool: D23: %u


assistant: ```c
int main() {
  int count = 0;
  scanf("%d", &count);
  uint32_t t = 0;
  while (count--) {
    scanf("%u", &t);
    printf("%u\n", ~t);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D24(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x0,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  movl   $0x0,0x4(%rsp)
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L5
  lea    0x4(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D27(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L22:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  not    %esi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L22
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D24
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string
name: retrieve_data
arguments: data_tag: D27
type_infered: string

tool: D24: %d

tool: D18: %u

tool: D27: %u


assistant: ```c
int main() {
  int count = 0;
  scanf("%d", &count);
  uint32_t t = 0;
  while (count--) {
    scanf("%u", &t);
    printf("%u\n", ~t);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D23(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x0,(%rsp)
  call   <scanf@plt>
  mov    (%rsp),%eax
  movl   $0x0,0x4(%rsp)
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  je     L5
  lea    0x4(%rsp),%r12
  lea    D21(%rip),%rbp
  lea    D27(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  mov    %rbx,%rdi
  not    %esi
  call   <printf@plt>
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L4
L5:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
datatype: string
name: retrieve_data
arguments: data_tag: D21
datatype: string
name: retrieve_data
arguments: data_tag: D27
datatype: string

tool: D23: %d

tool: D21: %u

tool: D27: %u


assistant: ```c
int main() {
  int count = 0;
  scanf("%d", &count);
  uint32_t t = 0;
  while (count--) {
    scanf("%u", &t);
    printf("%u\n", ~t);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dwmonitor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x40(%rbp)
  mov    -0x68(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x30(%rbp)
  movsd  D4(%rip),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  movl   $0x0,-0x54(%rbp)
  jmp    L79
L46:
  mov    -0x54(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x70(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x38(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x40(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x40(%rbp)
  movsd  -0x38(%rbp),%xmm0
  mulsd  -0x30(%rbp),%xmm0
  movsd  %xmm0,-0x38(%rbp)
  addl   $0x1,-0x54(%rbp)
L79:
  cmpl   $0x2,-0x54(%rbp)
  jle    L46
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x48(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L53
L23:
  mov    -0x50(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x28(%rbp)
  mov    -0x50(%rbp),%eax
  add    $0x3,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x68(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x28(%rbp),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jb     L43
  movsd  -0x18(%rbp),%xmm0
  jmp    L48
L43:
  movsd  -0x18(%rbp),%xmm0
  movq   D11(%rip),%xmm1
  xorpd  %xmm1,%xmm0
L48:
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x48(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L4
  movsd  -0x48(%rbp),%xmm0
  jmp    L8
L4:
  movsd  -0x10(%rbp),%xmm0
L8:
  movsd  %xmm0,-0x48(%rbp)
  addl   $0x1,-0x50(%rbp)
L53:
  cmpl   $0x1,-0x50(%rbp)
  jle    L23
  movsd  -0x48(%rbp),%xmm0
  comisd -0x40(%rbp),%xmm0
  setae  %al
  movzbl %al,%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x4c(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_infered: f64
name: unpack_data
arguments: label: D11
type_infered: f32[2]

tool: D4: 1

tool: {"D11": [0.0,-0.0]}

assistant: ```c
int dwmonitor(const double *X, const double *D) {
  double q3, q4, s1, s4, s5, s6, s7, s8, w1;
  int w2;
  s5 = 0.0;
  s8 = X[0];
  s7 = 1.0;
  for (int i5 = 0; i5 <= 2; i5++) {
    s4 = (s7 * D[i5]);
    s5 = (s5 + s4);
    s7 = (s7 * s8);
  }
  s1 = 0.0;
  for (int i3 = 0; i3 <= 1; i3++) {
    q3 = X[(i3 + 1)];
    q4 = X[(3 + i3)];
    w1 = (q3 - q4);
    s6 = ((((w1 >= 0))) ? (w1) : (-(w1)));
    s1 = ((((s1 >= s6))) ? (s1) : (s6));
  }
  w2 = ((s1 >= s5));
  return w2;
}
```
user: What is the c source code of the assembly code below:

```asm
<dwmonitor>:
  endbr64
  movsd  (%rdi),%xmm0
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  addsd  (%rsi),%xmm2
  movapd %xmm0,%xmm1
  mulsd  0x8(%rsi),%xmm1
  addsd  %xmm2,%xmm1
  mulsd  %xmm0,%xmm0
  mulsd  0x10(%rsi),%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm2
  subsd  0x18(%rdi),%xmm2
  comisd %xmm3,%xmm2
  jb     L17
L49:
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  jb     L44
  movapd %xmm0,%xmm2
L44:
  movsd  0x10(%rdi),%xmm0
  subsd  0x20(%rdi),%xmm0
  comisd D4(%rip),%xmm0
  jb     L15
L22:
  movapd %xmm0,%xmm3
  cmpnlesd %xmm2,%xmm3
  andpd  %xmm3,%xmm0
  andnpd %xmm2,%xmm3
  orpd   %xmm3,%xmm0
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  ret
L17:
  xorpd  D1(%rip),%xmm2
  jmp    L49
L15:
  xorpd  D1(%rip),%xmm0
  jmp    L22
```

tool_calls: name: read_data
arguments: data_label: D4
type: f64
name: read_data
arguments: data_label: D1
type: byte[16]

tool: D4: 0

tool: {"D1": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int dwmonitor(const double *X, const double *D) {
  double q3, q4, s1, s4, s5, s6, s7, s8, w1;
  int w2;
  s5 = 0.0;
  s8 = X[0];
  s7 = 1.0;
  for (int i5 = 0; i5 <= 2; i5++) {
    s4 = (s7 * D[i5]);
    s5 = (s5 + s4);
    s7 = (s7 * s8);
  }
  s1 = 0.0;
  for (int i3 = 0; i3 <= 1; i3++) {
    q3 = X[(i3 + 1)];
    q4 = X[(3 + i3)];
    w1 = (q3 - q4);
    s6 = ((((w1 >= 0))) ? (w1) : (-(w1)));
    s1 = ((((s1 >= s6))) ? (s1) : (s6));
  }
  w2 = ((s1 >= s5));
  return w2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<dwmonitor>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rsi),%xmm1
  pxor   %xmm3,%xmm3
  movsd  (%rsi),%xmm2
  mulsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  0x10(%rsi),%xmm0
  addsd  %xmm2,%xmm1
  movsd  0x8(%rdi),%xmm2
  subsd  0x18(%rdi),%xmm2
  comisd %xmm3,%xmm2
  addsd  %xmm0,%xmm1
  jae    L16
  xorpd  D9(%rip),%xmm2
L16:
  movapd %xmm2,%xmm0
  cmpnlesd %xmm3,%xmm0
  andpd  %xmm0,%xmm2
  movsd  0x10(%rdi),%xmm0
  subsd  0x20(%rdi),%xmm0
  comisd %xmm3,%xmm0
  jae    L4
  xorpd  D9(%rip),%xmm0
L4:
  movapd %xmm0,%xmm3
  xor    %eax,%eax
  cmpnlesd %xmm2,%xmm3
  andpd  %xmm3,%xmm0
  andnpd %xmm2,%xmm3
  orpd   %xmm3,%xmm0
  comisd %xmm1,%xmm0
  setae  %al
  ret
```

tool_calls: name: parse_data
arguments: label: D9
datatype: f32[4]

tool: {"D9": [0.0,-0.0,0.0,0.0]}

assistant: ```c
int dwmonitor(const double *X, const double *D) {
  double q3, q4, s1, s4, s5, s6, s7, s8, w1;
  int w2;
  s5 = 0.0;
  s8 = X[0];
  s7 = 1.0;
  for (int i5 = 0; i5 <= 2; i5++) {
    s4 = (s7 * D[i5]);
    s5 = (s5 + s4);
    s7 = (s7 * s8);
  }
  s1 = 0.0;
  for (int i3 = 0; i3 <= 1; i3++) {
    q3 = X[(i3 + 1)];
    q4 = X[(3 + i3)];
    w1 = (q3 - q4);
    s6 = ((((w1 >= 0))) ? (w1) : (-(w1)));
    s1 = ((((s1 >= s6))) ? (s1) : (s6));
  }
  w2 = ((s1 >= s5));
  return w2;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dwmonitor>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  0x8(%rsi),%xmm1
  pxor   %xmm3,%xmm3
  movsd  (%rsi),%xmm2
  mulsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm2
  mulsd  %xmm0,%xmm0
  mulsd  0x10(%rsi),%xmm0
  addsd  %xmm2,%xmm1
  movsd  0x8(%rdi),%xmm2
  subsd  0x18(%rdi),%xmm2
  comisd %xmm3,%xmm2
  addsd  %xmm0,%xmm1
  jae    L12
  xorpd  D12(%rip),%xmm2
L12:
  movapd %xmm2,%xmm0
  cmpnlesd %xmm3,%xmm0
  andpd  %xmm0,%xmm2
  movsd  0x10(%rdi),%xmm0
  subsd  0x20(%rdi),%xmm0
  comisd %xmm3,%xmm0
  jae    L5
  xorpd  D12(%rip),%xmm0
L5:
  movapd %xmm0,%xmm3
  xor    %eax,%eax
  cmpnlesd %xmm2,%xmm3
  andpd  %xmm3,%xmm0
  andnpd %xmm2,%xmm3
  orpd   %xmm3,%xmm0
  comisd %xmm1,%xmm0
  setae  %al
  ret
```

tool_calls: name: unpack_data
arguments: tag: D12
type_guessed: f32[4]

tool: {"D12": [0.0,-0.0,0.0,0.0]}

assistant: ```c
int dwmonitor(const double *X, const double *D) {
  double q3, q4, s1, s4, s5, s6, s7, s8, w1;
  int w2;
  s5 = 0.0;
  s8 = X[0];
  s7 = 1.0;
  for (int i5 = 0; i5 <= 2; i5++) {
    s4 = (s7 * D[i5]);
    s5 = (s5 + s4);
    s7 = (s7 * s8);
  }
  s1 = 0.0;
  for (int i3 = 0; i3 <= 1; i3++) {
    q3 = X[(i3 + 1)];
    q4 = X[(3 + i3)];
    w1 = (q3 - q4);
    s6 = ((((w1 >= 0))) ? (w1) : (-(w1)));
    s1 = ((((s1 >= s6))) ? (s1) : (s6));
  }
  w2 = ((s1 >= s5));
  return w2;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<moveZeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L11
L33:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  je     L12
  mov    -0x8(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L20
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L20:
  addl   $0x1,-0xc(%rbp)
L12:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L33
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int zeroAt, i, temp;
  for (i = zeroAt = 0; i < numsSize; i++) {
    if (*(nums + i)) {
      if (i != zeroAt) {
        temp = *(nums + i);
        *(nums + i) = *(nums + zeroAt);
        *(nums + zeroAt) = temp;
      }
      zeroAt++;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<moveZeroes>:
  endbr64
  test   %esi,%esi
  jle    L20
  mov    %esi,%esi
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L48
L14:
  add    $0x1,%ecx
L18:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L20
L48:
  mov    (%rdi,%rax,4),%edx
  test   %edx,%edx
  je     L18
  cmp    %eax,%ecx
  je     L14
  movslq %ecx,%r8
  lea    (%rdi,%r8,4),%r8
  mov    (%r8),%r9d
  mov    %r9d,(%rdi,%rax,4)
  mov    %edx,(%r8)
  jmp    L14
L20:
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int zeroAt, i, temp;
  for (i = zeroAt = 0; i < numsSize; i++) {
    if (*(nums + i)) {
      if (i != zeroAt) {
        temp = *(nums + i);
        *(nums + i) = *(nums + zeroAt);
        *(nums + zeroAt) = temp;
      }
      zeroAt++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<moveZeroes>:
  endbr64
  test   %esi,%esi
  jle    L17
  movslq %esi,%rsi
  xor    %eax,%eax
  xor    %ecx,%ecx
  nop
L7:
  mov    (%rdi,%rax,4),%edx
  test   %edx,%edx
  je     L32
  cmp    %eax,%ecx
  je     L27
  movslq %ecx,%r8
  lea    (%rdi,%r8,4),%r8
  mov    (%r8),%r9d
  mov    %r9d,(%rdi,%rax,4)
  mov    %edx,(%r8)
L27:
  add    $0x1,%ecx
L32:
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L7
L17:
  ret
```

assistant: ```c
void moveZeroes(int *nums, int numsSize) {
  int zeroAt, i, temp;
  for (i = zeroAt = 0; i < numsSize; i++) {
    if (*(nums + i)) {
      if (i != zeroAt) {
        temp = *(nums + i);
        *(nums + i) = *(nums + zeroAt);
        *(nums + zeroAt) = temp;
      }
      zeroAt++;
    }
  }
}
```