ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D72(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  cmpl   $0xd,0x4(%rsp)
  ja     L25
  mov    0x4(%rsp),%eax
  lea    D38(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L25:
  lea    D82(%rip),%rdi
  call   <printf@plt>
  nopl   (%rax)
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L47
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L47
  lea    D80(%rip),%rdi
  call   <printf@plt>
  jmp    L47
  lea    D46(%rip),%rdi
  call   <printf@plt>
  jmp    L47
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L47
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D72
type_guessed: string
name: read_data
arguments: tag: D43
type_guessed: string
name: read_data
arguments: tag: D82
type_guessed: string
name: read_data
arguments: tag: D54
type_guessed: string
name: read_data
arguments: tag: D69
type_guessed: string
name: read_data
arguments: tag: D80
type_guessed: string
name: read_data
arguments: tag: D46
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D72: %d

tool: D43: Digite um numero de um canal de tv:


tool: D82: Canal Invalido

tool: D54: SBT

tool: D69: BAND

tool: D80: REDETV!

tool: D46: RECORD

tool: D16: GLOBO

assistant: ```c
int main(int argc, char const *argv[]) {
  int a;
  scanf("%d", &a);
  printf("Digite um numero de um canal de tv:\n");
  switch (a) {
  case 2:
    printf("SBT");
    break;
  case 4:
    printf("BAND");
    break;
  case 6:
    printf("REDETV!");
    break;
  case 9:
    printf("RECORD");
    break;
  case 13:
    printf("GLOBO");
    break;
  default:
    printf("Canal Invalido");
    break;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L26
L0:
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L38:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x9,-0x8(%rbp)
  jle    L38
  addl   $0x1,-0xc(%rbp)
L26:
  cmpl   $0x9,-0xc(%rbp)
  jle    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i, j;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      sum += 1;
    }
  }
  return sum;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x64,%eax
  ret
```

assistant: ```c
int main() {
  int i, j;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      sum += 1;
    }
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  mov    $0x64,%eax
  ret
```

assistant: ```c
int main() {
  int i, j;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      sum += 1;
    }
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  mov    $0x64,%eax
  ret
```

assistant: ```c
int main() {
  int i, j;
  int sum = 0;
  for (i = 0; i < 10; i++) {
    for (j = 0; j < 10; j++) {
      sum += 1;
    }
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x12(%rbp)
  movw   $0x0,-0xa(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L11
  lea    D29(%rip),%rax
  jmp    L8
L11:
  lea    D7(%rip),%rax
L8:
  lea    -0x12(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcat@plt>
  lea    -0x12(%rbp),%rax
  lea    D13(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D29
type_guessed: string
name: read_data
arguments: label: D7
type_guessed: string
name: read_data
arguments: label: D13
type_guessed: string

tool: D29: r

tool: D7: w

tool: D13: b

assistant: ```c
__attribute__((no, noclone)) char *foo(int r) {
  char buf[10] = "";
  strcat(buf, r ? "r" : "w");
  strcat(buf, "b");
  return strdup(buf);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<foo>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xe(%rsp)
  movw   $0x0,0x16(%rsp)
  test   %edi,%edi
  lea    D11(%rip),%rsi
  lea    D26(%rip),%rax
  cmove  %rax,%rsi
  lea    0xe(%rsp),%rbx
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <strdup@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D11
datatype: string
name: parse_data
arguments: data_label: D26
datatype: string
name: parse_data
arguments: data_label: D3
datatype: string

tool: D11: r

tool: D26: w

tool: D3: b

assistant: ```c
__attribute__((no, noclone)) char *foo(int r) {
  char buf[10] = "";
  strcat(buf, r ? "r" : "w");
  strcat(buf, "b");
  return strdup(buf);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  push   %rbp
  lea    D21(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  test   %edi,%edi
  lea    0xe(%rsp),%rbp
  mov    %ax,0x16(%rsp)
  lea    D13(%rip),%rax
  mov    %rbp,%rdi
  movq   $0x0,0xe(%rsp)
  cmove  %rax,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  lea    D17(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D21
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string

tool: D21: r

tool: D13: w

tool: D17: b

assistant: ```c
__attribute__((no, noclone)) char *foo(int r) {
  char buf[10] = "";
  strcat(buf, r ? "r" : "w");
  strcat(buf, "b");
  return strdup(buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  push   %rbp
  lea    D27(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  xor    %eax,%eax
  test   %edi,%edi
  lea    0xe(%rsp),%rbp
  mov    %ax,0x16(%rsp)
  lea    D28(%rip),%rax
  mov    %rbp,%rdi
  movq   $0x0,0xe(%rsp)
  cmove  %rax,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  lea    D4(%rip),%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <strdup@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x20,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D27
type_guessed: string
name: disassemble_data
arguments: label: D28
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string

tool: D27: r

tool: D28: w

tool: D4: b

assistant: ```c
__attribute__((no, noclone)) char *foo(int r) {
  char buf[10] = "";
  strcat(buf, r ? "r" : "w");
  strcat(buf, "b");
  return strdup(buf);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  nop
  mov    -0xc(%rbp),%eax
  imul   $0x2dbaa164,%eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        state[local1] -= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 767205732UL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  imul   $0x2dbaa164,%eax,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        state[local1] -= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 767205732UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  imul   $0x2dbaa164,%eax,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        state[local1] -= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 767205732UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  imul   $0x2dbaa164,%eax,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy11;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < 0U) {
      if (state[0UL] > local1) {
        if (state[0UL] > local1) {
          copy11 = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = copy11;
          copy11 = *((unsigned short *)(&state[local1]) + 0);
          *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
          *((unsigned short *)(&state[local1]) + 1) = copy11;
        } else {
          state[0UL] += state[0UL];
        }
      } else if (state[0UL] <= local1) {
        state[local1] -= state[0UL];
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] * 767205732UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<portal_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  leave
  ret
```

assistant: ```c
int portal_printf(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  return vfprintf(stderr, format, ap);
}
```
user: What is the c source code of the assembly code below?

```asm
<portal_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int portal_printf(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  return vfprintf(stderr, format, ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<portal_printf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int portal_printf(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  return vfprintf(stderr, format, ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<portal_printf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int portal_printf(const char *format, ...) {
  va_list ap;
  va_start(ap, format);
  return vfprintf(stderr, format, ap);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x1,-0x10(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L7
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L7:
  movl   $0x1,-0x14(%rbp)
  jmp    L25
L49:
  mov    -0x14(%rbp),%eax
  cltq
  mov    -0x10(%rbp),%rdx
  imul   %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L25:
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jle    L49
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
type: string
name: read_data
arguments: data_tag: D2
type: string
name: read_data
arguments: data_tag: D39
type: string
name: read_data
arguments: data_tag: D19
type: string

tool: D12: Enter an integer: 

tool: D2: %d

tool: D39: Error!!! Factorial of negative number doesn't exist.

tool: D19: Factorial = %lu

assistant: ```c
int main() {
  int n, count;
  unsigned long long int factorial = 1;
  printf("Enter an integer: ");
  scanf("%d", &n);
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu", factorial);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L8
  mov    $0x1,%esi
  jle    L9
  lea    0x1(%rax),%edx
  mov    $0x1,%eax
  mov    $0x1,%esi
L15:
  imul   %rax,%rsi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L15
L9:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L36:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L36
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string
name: disassemble_data
arguments: data_tag: D1
type: string
name: disassemble_data
arguments: data_tag: D6
type: string
name: disassemble_data
arguments: data_tag: D12
type: string

tool: D2: Enter an integer: 

tool: D1: %d

tool: D6: Factorial = %lu

tool: D12: Error!!! Factorial of negative number doesn't exist.

assistant: ```c
int main() {
  int n, count;
  unsigned long long int factorial = 1;
  printf("Enter an integer: ");
  scanf("%d", &n);
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu", factorial);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L45
  mov    $0x1,%esi
  je     L35
  lea    0x1(%rax),%edx
  mov    $0x1,%esi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L46:
  imul   %rax,%rsi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L46
L35:
  lea    D7(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L28:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L45:
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L28
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
type_infered: string
name: extract_symbolic_data
arguments: tag: D34
type_infered: string
name: extract_symbolic_data
arguments: tag: D7
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D19: Enter an integer: 

tool: D34: %d

tool: D7: Factorial = %lu

tool: D0: Error!!! Factorial of negative number doesn't exist.

assistant: ```c
int main() {
  int n, count;
  unsigned long long int factorial = 1;
  printf("Enter an integer: ");
  scanf("%d", &n);
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu", factorial);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L24
  mov    $0x1,%esi
  je     L18
  lea    0x1(%rax),%edx
  mov    $0x1,%esi
  mov    $0x1,%eax
  nopl   0x0(%rax)
L2:
  imul   %rax,%rsi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
L18:
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L33:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L24:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L33
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D24
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string

tool: D5: Enter an integer: 

tool: D24: %d

tool: D32: Factorial = %lu

tool: D38: Error!!! Factorial of negative number doesn't exist.

assistant: ```c
int main() {
  int n, count;
  unsigned long long int factorial = 1;
  printf("Enter an integer: ");
  scanf("%d", &n);
  if (n < 0)
    printf("Error!!! Factorial of negative number doesn't exist.");
  else {
    for (count = 1; count <= n; ++count) {
      factorial *= count;
    }
    printf("Factorial = %lu", factorial);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
L5:
  mov    -0x8(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L5
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  int i = 1;
  do {
    result = result * i;
    i = i + 1;
  } while (i <= n);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  mov    $0x1,%edx
L2:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %edi,%eax
  jle    L2
  mov    %edx,%eax
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  int i = 1;
  do {
    result = result * i;
    i = i + 1;
  } while (i <= n);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  mov    $0x1,%r8d
  nop
L5:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jle    L5
  mov    %r8d,%eax
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  int i = 1;
  do {
    result = result * i;
    i = i + 1;
  } while (i <= n);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<factorial>:
  endbr64
  mov    $0x1,%eax
  mov    $0x1,%r8d
  nop
L2:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %edi,%eax
  jle    L2
  mov    %r8d,%eax
  ret
```

assistant: ```c
int factorial(int n) {
  int result = 1;
  int i = 1;
  do {
    result = result * i;
    i = i + 1;
  } while (i <= n);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <getValue@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string

tool: D1: INCREMENT

tool: D19: El valor es: %s


assistant: ```c
int main(void) {
  char *value;
  value = getValue("INCREMENT");
  printf("El valor es: %s\n", value);
  return 0;
}
```