ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L23
  lea    0x1(%rdi),%r9
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%eax
  mov    %edx,%r8d
  sub    %r9,%rdi
  cmp    $0xe,%rdi
  jbe    L48
  cmp    $0x6,%eax
  jbe    L48
  cmp    $0xe,%eax
  jbe    L92
  mov    %edx,%edi
  xor    %eax,%eax
  shr    $0x4,%edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L112:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%rsi,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L112
  mov    %edx,%edi
  and    $0xfffffff0,%edi
  mov    %edi,%eax
  cmp    %edi,%edx
  je     L23
  mov    %edx,%r8d
  sub    %edi,%r8d
  lea    -0x1(%r8),%r9d
  cmp    $0x6,%r9d
  jbe    L13
L49:
  mov    (%rcx,%rdi,1),%r9
  mov    %r9,(%rsi,%rdi,1)
  mov    %r8d,%edi
  and    $0xfffffff8,%edi
  add    %edi,%eax
  cmp    %edi,%r8d
  je     L23
L13:
  movslq %eax,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x1(%rax),%edi
  cmp    %edi,%edx
  jle    L23
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x2(%rax),%edi
  cmp    %edi,%edx
  jle    L23
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x3(%rax),%edi
  cmp    %edi,%edx
  jle    L23
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x4(%rax),%edi
  cmp    %edi,%edx
  jle    L23
  movslq %edi,%rdi
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  lea    0x5(%rax),%edi
  cmp    %edi,%edx
  jle    L23
  movslq %edi,%rdi
  add    $0x6,%eax
  movzbl (%rcx,%rdi,1),%r8d
  mov    %r8b,(%rsi,%rdi,1)
  cmp    %eax,%edx
  jle    L23
  cltq
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%rsi,%rax,1)
  ret
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L73:
  movzbl (%rcx,%rax,1),%edi
  mov    %dil,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L73
L23:
  ret
L92:
  xor    %edi,%edi
  xor    %eax,%eax
  jmp    L49
```

assistant: ```c
void memcpy(char *source, char *dest, int nbytes) {
  for (int i = 0; i < nbytes; i++)
    dest[i] = source[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<onlyreload>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <maccess@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <flush@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <maccess@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  sub    -0x10(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t onlyreload(void *addr) {
  maccess(addr);
  flush(addr);
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  return delta;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<onlyreload>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <maccess@plt>
  mov    %rbx,%rdi
  call   <flush@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <maccess@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  sub    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t onlyreload(void *addr) {
  maccess(addr);
  flush(addr);
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  return delta;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<onlyreload>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <maccess@plt>
  mov    %rbp,%rdi
  call   <flush@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <maccess@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  add    $0x8,%rsp
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t onlyreload(void *addr) {
  maccess(addr);
  flush(addr);
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  return delta;
}
```
user: What is the c source code of the assembly code below:

```asm
<onlyreload>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <maccess@plt>
  mov    %rbp,%rdi
  call   <flush@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <maccess@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  add    $0x8,%rsp
  sub    %rbx,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
size_t onlyreload(void *addr) {
  maccess(addr);
  flush(addr);
  size_t time = rdtsc();
  maccess(addr);
  size_t delta = rdtsc() - time;
  return delta;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<XXH32_result>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <XXH32_getIntermediateResult@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int XXH32_result(void *state_in) {
  unsigned int h32 = XXH32_getIntermediateResult(state_in);
  free(state_in);
  return h32;
}
```
user: What is the c source code of the assembly code below:

```asm
<XXH32_result>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <XXH32_getIntermediateResult@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned int XXH32_result(void *state_in) {
  unsigned int h32 = XXH32_getIntermediateResult(state_in);
  free(state_in);
  return h32;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<XXH32_result>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <XXH32_getIntermediateResult@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int XXH32_result(void *state_in) {
  unsigned int h32 = XXH32_getIntermediateResult(state_in);
  free(state_in);
  return h32;
}
```
user: Translate the below assembly code into C programming language:

```asm
<XXH32_result>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <XXH32_getIntermediateResult@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int XXH32_result(void *state_in) {
  unsigned int h32 = XXH32_getIntermediateResult(state_in);
  free(state_in);
  return h32;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<SUB_HOST_REG_IMM_B>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x10,%eax
  test   %eax,%eax
  je     L10
  mov    $0x66,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L31
  mov    $0x41,%edi
  call   <addbyte@plt>
L31:
  mov    $0x81,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  or     $0xe8,%al
  mov    %eax,%edi
  call   <addbyte@plt>
  mov    -0x8(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edi
  call   <addword@plt>
  jmp    L22
L10:
  mov    -0x4(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L12
  mov    $0x41,%edi
  call   <addbyte@plt>
L12:
  mov    $0x80,%edi
  call   <addbyte@plt>
  mov    -0x4(%rbp),%eax
  and    $0x7,%eax
  or     $0xe8,%al
  mov    %eax,%edi
  call   <addbyte@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <addbyte@plt>
L22:
  nop
  leave
  ret
```

assistant: ```c
void SUB_HOST_REG_IMM_B(int host_reg, uint8_t imm) {
  if (host_reg & 0x10) {
    addbyte(0x66);
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x81);
    addbyte(0xE8 | (host_reg & 7));
    addword(imm << 8);
  } else {
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x80);
    addbyte(0xE8 | (host_reg & 7));
    addbyte(imm);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<SUB_HOST_REG_IMM_B>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  test   $0x10,%dil
  jne    L30
  test   $0x8,%dil
  jne    L50
L22:
  mov    $0x80,%edi
  call   <addbyte@plt>
  and    $0x7,%ebx
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  mov    %ebp,%edi
  call   <addbyte@plt>
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    $0x66,%edi
  call   <addbyte@plt>
  test   $0x8,%bl
  jne    L0
L1:
  mov    $0x81,%edi
  call   <addbyte@plt>
  and    $0x7,%ebx
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  mov    %ebp,%edi
  shl    $0x8,%edi
  call   <addword@plt>
  jmp    L6
L0:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L1
L50:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L22
```

assistant: ```c
void SUB_HOST_REG_IMM_B(int host_reg, uint8_t imm) {
  if (host_reg & 0x10) {
    addbyte(0x66);
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x81);
    addbyte(0xE8 | (host_reg & 7));
    addword(imm << 8);
  } else {
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x80);
    addbyte(0xE8 | (host_reg & 7));
    addbyte(imm);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<SUB_HOST_REG_IMM_B>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  and    $0x8,%r12d
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  and    $0x10,%edi
  jne    L31
  test   %r12d,%r12d
  jne    L34
L30:
  mov    $0x80,%edi
  and    $0x7,%ebx
  call   <addbyte@plt>
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <addbyte@plt>
L34:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L30
  nopl   0x0(%rax)
L31:
  mov    $0x66,%edi
  call   <addbyte@plt>
  test   %r12d,%r12d
  jne    L12
L13:
  mov    $0x81,%edi
  and    $0x7,%ebx
  call   <addbyte@plt>
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  shl    $0x8,%edi
  pop    %r12
  jmp    1070 <addword@plt>
  nopl   (%rax)
L12:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L13
```

assistant: ```c
void SUB_HOST_REG_IMM_B(int host_reg, uint8_t imm) {
  if (host_reg & 0x10) {
    addbyte(0x66);
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x81);
    addbyte(0xE8 | (host_reg & 7));
    addword(imm << 8);
  } else {
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x80);
    addbyte(0xE8 | (host_reg & 7));
    addbyte(imm);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<SUB_HOST_REG_IMM_B>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  and    $0x8,%r12d
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  and    $0x10,%edi
  jne    L38
  test   %r12d,%r12d
  jne    L11
L22:
  mov    $0x80,%edi
  and    $0x7,%ebx
  call   <addbyte@plt>
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <addbyte@plt>
L11:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L22
  nopl   0x0(%rax)
L38:
  mov    $0x66,%edi
  call   <addbyte@plt>
  test   %r12d,%r12d
  jne    L46
L39:
  mov    $0x81,%edi
  and    $0x7,%ebx
  call   <addbyte@plt>
  mov    %ebx,%edi
  or     $0xe8,%dil
  call   <addbyte@plt>
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  shl    $0x8,%edi
  pop    %r12
  jmp    1070 <addword@plt>
  nopl   (%rax)
L46:
  mov    $0x41,%edi
  call   <addbyte@plt>
  jmp    L39
```

assistant: ```c
void SUB_HOST_REG_IMM_B(int host_reg, uint8_t imm) {
  if (host_reg & 0x10) {
    addbyte(0x66);
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x81);
    addbyte(0xE8 | (host_reg & 7));
    addword(imm << 8);
  } else {
    if (host_reg & 8)
      addbyte(0x41);
    addbyte(0x80);
    addbyte(0xE8 | (host_reg & 7));
    addbyte(imm);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %r14
  push   %r13
  lea    -0x2(%rdi),%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%r13d
  jle    L27
  mov    $0x1,%ebp
  nopw   0x0(%rax,%rax,1)
L61:
  mov    $0x1,%ebx
  nopl   (%rax)
L9:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L9
  mov    $0x1,%edi
  lea    0x2(%rbp),%r14d
  lea    0x3(%rbp),%ebx
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %r14d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %r14d,%edi
  call   <hash@plt>
  cmp    %r12d,%ebx
  jg     L62
  nop
L22:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L22
L62:
  add    $0x1,%ebp
  cmp    %r13d,%ebp
  jne    L61
L27:
  cmp    $0x2,%r12d
  jle    L80
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jne    L13
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
L80:
  lea    -0x1(%r12),%ebp
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L45
  nopw   0x0(%rax,%rax,1)
L50:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L50
L45:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  lea    0x2(%rbp),%edi
  add    $0x1,%ebp
  call   <hash@plt>
  cmp    %ebp,%r12d
  jge    L25
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void test(int M) {
  int i, j;
  for (i = 1; i <= M - 3; i++) {
    for (j = 1; j <= i + 1; j++) {
      {
        hash(1);
        hash(i);
        hash(j);
      };
    }
    j = i + 2;
    {
      hash(1);
      hash(i);
      hash(i + 2);
    };
    {
      hash(2);
      hash(i);
      hash(i + 2);
    };
    for (j = i + 3; j <= M; j++) {
      {
        hash(1);
        hash(i);
        hash(j);
      };
    }
  }
  if (M >= 3) {
    i = M - 2;
    for (j = 1; j <= M - 1; j++) {
      {
        hash(1);
        hash(M - 2);
        hash(j);
      };
    }
    {
      hash(1);
      hash(M - 2);
      hash(M);
    };
    {
      hash(2);
      hash(M - 2);
      hash(M);
    };
  }
  for (i = M - 1; i <= M; i++) {
    for (j = 1; j <= M; j++) {
      {
        hash(1);
        hash(i);
        hash(j);
      };
    }
    j = i + 2;
    {
      hash(2);
      hash(i);
      hash(i + 2);
    };
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test>:
  endbr64
  push   %r14
  push   %r13
  lea    -0x2(%rdi),%r13d
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  cmp    $0x1,%r13d
  jle    L2
  mov    $0x1,%ebp
  nopw   0x0(%rax,%rax,1)
L95:
  mov    $0x1,%ebx
  nopl   (%rax)
L59:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  call   <hash@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %ebp,%eax
  jle    L59
  mov    $0x1,%edi
  lea    0x2(%rbp),%r14d
  lea    0x3(%rbp),%ebx
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %r14d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %r14d,%edi
  call   <hash@plt>
  cmp    %r12d,%ebx
  jg     L88
  nop
L71:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L71
L88:
  add    $0x1,%ebp
  cmp    %r13d,%ebp
  jne    L95
L2:
  cmp    $0x2,%r12d
  jle    L97
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L75:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jne    L75
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %r13d,%edi
  call   <hash@plt>
  mov    %r12d,%edi
  call   <hash@plt>
L97:
  lea    -0x1(%r12),%ebp
  nopw   0x0(%rax,%rax,1)
L28:
  mov    $0x1,%ebx
  test   %r12d,%r12d
  jle    L53
  nopw   0x0(%rax,%rax,1)
L67:
  mov    $0x1,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <hash@plt>
  cmp    %ebx,%r12d
  jge    L67
L53:
  mov    $0x2,%edi
  call   <hash@plt>
  mov    %ebp,%edi
  call   <hash@plt>
  lea    0x2(%rbp),%edi
  add    $0x1,%ebp
  call   <hash@plt>
  cmp    %ebp,%r12d
  jge    L28
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void test(int M) {
  int i, j;
  for (i = 1; i <= M - 3; i++) {
    for (j = 1; j <= i + 1; j++) {
      {
        hash(1);
        hash(i);
        hash(j);
      };
    }
    j = i + 2;
    {
      hash(1);
      hash(i);
      hash(i + 2);
    };
    {
      hash(2);
      hash(i);
      hash(i + 2);
    };
    for (j = i + 3; j <= M; j++) {
      {
        hash(1);
        hash(i);
        hash(j);
      };
    }
  }
  if (M >= 3) {
    i = M - 2;
    for (j = 1; j <= M - 1; j++) {
      {
        hash(1);
        hash(M - 2);
        hash(j);
      };
    }
    {
      hash(1);
      hash(M - 2);
      hash(M);
    };
    {
      hash(2);
      hash(M - 2);
      hash(M);
    };
  }
  for (i = M - 1; i <= M; i++) {
    for (j = 1; j <= M; j++) {
      {
        hash(1);
        hash(i);
        hash(j);
      };
    }
    j = i + 2;
    {
      hash(2);
      hash(i);
      hash(i + 2);
    };
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getLocalTime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L27
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  movl   $0x1,-0xc(%rbp)
L27:
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <localtime_r@plt>
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  lea    D15(%rip),%rax
  mov    %rax,%rcx
  mov    $0x1,%edx
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1d,%edi
  call   <_DEBUG@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L10:
  cmpl   $0x0,-0xc(%rbp)
  je     L9
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L9:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D18
datatype: string

tool: D15: Memory allocation failed.

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mcoulont/cpige_month/refs/heads/master/mytime.c

assistant: ```c
struct tm *getLocalTime(time_t *when) {
  struct tm *mytime;
  int free_when = 0;
  if (when == NULL) {
    when = malloc(sizeof(time_t));
    *when = time((time_t *)NULL);
    free_when = 1;
  }
  mytime = (struct tm *)malloc(sizeof(struct tm));
  localtime_r(when, mytime);
  if (mytime == NULL) {
    _DEBUG(29, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mcoulont/cpige_month/refs/heads/master/mytime.c", 1, "Memory allocation failed.");
    exit(1);
  }
  if (free_when)
    free(when);
  return mytime;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getLocalTime>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L19
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  test   %rbx,%rbx
  je     L10
L16:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x0(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <localtime_r@plt>
  test   %rbx,%rbx
  je     L21
L26:
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L16
L21:
  lea    D23(%rip),%rcx
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  mov    $0x1d,%edi
  call   <_DEBUG@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L26
L10:
  lea    D23(%rip),%rcx
  mov    $0x1,%edx
  lea    D6(%rip),%rsi
  mov    $0x1d,%edi
  call   <_DEBUG@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: disassemble_data
arguments: tag: D23
type: string
name: disassemble_data
arguments: tag: D6
type: string

tool: D23: Memory allocation failed.

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mcoulont/cpige_month/refs/heads/master/mytime.c

assistant: ```c
struct tm *getLocalTime(time_t *when) {
  struct tm *mytime;
  int free_when = 0;
  if (when == NULL) {
    when = malloc(sizeof(time_t));
    *when = time((time_t *)NULL);
    free_when = 1;
  }
  mytime = (struct tm *)malloc(sizeof(struct tm));
  localtime_r(when, mytime);
  if (mytime == NULL) {
    _DEBUG(29, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mcoulont/cpige_month/refs/heads/master/mytime.c", 1, "Memory allocation failed.");
    exit(1);
  }
  if (free_when)
    free(when);
  return mytime;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<getLocalTime>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L6
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <localtime_r@plt>
  test   %r12,%r12
  je     L43
L35:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nop
L6:
  mov    $0x4,%edi
  call   <malloc@plt>
  xor    %edi,%edi
  mov    %rax,%rbp
  call   <time@plt>
  mov    $0x4,%edi
  mov    %eax,0x0(%rbp)
  call   <malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <localtime_r@plt>
  test   %r12,%r12
  je     L36
L41:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L36:
  lea    D6(%rip),%rcx
  mov    $0x1,%edx
  mov    $0x1d,%edi
  lea    D18(%rip),%rsi
  call   <_DEBUG@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L41
L43:
  lea    D6(%rip),%rcx
  mov    $0x1,%edx
  mov    $0x1d,%edi
  lea    D18(%rip),%rsi
  call   <_DEBUG@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L35
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string

tool: D6: Memory allocation failed.

tool: D18: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mcoulont/cpige_month/refs/heads/master/mytime.c

assistant: ```c
struct tm *getLocalTime(time_t *when) {
  struct tm *mytime;
  int free_when = 0;
  if (when == NULL) {
    when = malloc(sizeof(time_t));
    *when = time((time_t *)NULL);
    free_when = 1;
  }
  mytime = (struct tm *)malloc(sizeof(struct tm));
  localtime_r(when, mytime);
  if (mytime == NULL) {
    _DEBUG(29, "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mcoulont/cpige_month/refs/heads/master/mytime.c", 1, "Memory allocation failed.");
    exit(1);
  }
  if (free_when)
    free(when);
  return mytime;
}
```