ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LAR_AppendFile>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <iself@plt>
  test   %rax,%rax
  jne    L29
  mov    D16(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L69
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L69
  mov    D6(%rip),%rax
  mov    0x4(%rsp),%esi
  mov    %ebp,%r8d
  xor    %edi,%edi
  xor    %r9d,%r9d
  mov    (%rax),%ecx
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%rbp
  mov    D23(%rip),%rax
  cmp    %rbp,(%rax)
  je     L69
  mov    0x4(%rsp),%edx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %r13,%rcx
  call   <LAR_AppendBuffer@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <munmap@plt>
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x10,%rsp
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <LAR_AppendSelf@plt>
  nopw   0x0(%rax,%rax,1)
L69:
  mov    $0xffffffff,%r12d
  jmp    L39
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int LAR_AppendFile(struct LAR *lar, const char *filename, struct LARAttr *attr) {
  int fd;
  struct stat s;
  char *filep;
  int ret;
  if (iself((char *)filename))
    return LAR_AppendSelf(lar, filename, attr);
  fd = open(filename, O_RDONLY);
  if (fd == -1)
    return -1;
  if (fstat(fd, &s))
    return -1;
  filep = (char *)mmap(0, s.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (filep == MAP_FAILED)
    return -1;
  ret = LAR_AppendBuffer(lar, (unsigned char *)filep, s.st_size, attr);
  munmap(filep, s.st_size);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LAR_AppendFile>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <iself@plt>
  test   %rax,%rax
  jne    L11
  mov    D3(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  cmp    $0xffffffff,%eax
  je     L63
  lea    0x4(%rsp),%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  test   %rax,%rax
  jne    L63
  mov    D15(%rip),%rax
  mov    0x4(%rsp),%esi
  mov    %ebp,%r8d
  xor    %edi,%edi
  xor    %r9d,%r9d
  mov    (%rax),%ecx
  mov    D39(%rip),%rax
  mov    (%rax),%edx
  call   <mmap@plt>
  mov    %rax,%rbp
  mov    D33(%rip),%rax
  cmp    %rbp,(%rax)
  je     L63
  mov    0x4(%rsp),%edx
  mov    %r12,%rdi
  mov    %rbp,%rsi
  mov    %r13,%rcx
  call   <LAR_AppendBuffer@plt>
  mov    0x4(%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <munmap@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10d0 <LAR_AppendSelf@plt>
  nopw   0x0(%rax,%rax,1)
L63:
  mov    $0xffffffff,%r12d
  jmp    L24
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int LAR_AppendFile(struct LAR *lar, const char *filename, struct LARAttr *attr) {
  int fd;
  struct stat s;
  char *filep;
  int ret;
  if (iself((char *)filename))
    return LAR_AppendSelf(lar, filename, attr);
  fd = open(filename, O_RDONLY);
  if (fd == -1)
    return -1;
  if (fstat(fd, &s))
    return -1;
  filep = (char *)mmap(0, s.st_size, PROT_READ, MAP_SHARED, fd, 0);
  if (filep == MAP_FAILED)
    return -1;
  ret = LAR_AppendBuffer(lar, (unsigned char *)filep, s.st_size, attr);
  munmap(filep, s.st_size);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pragerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x400,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1400(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x13ec,%esi
  mov    %rax,%rdi
  call   <readline@plt>
  mov    %eax,%edx
  lea    D0(%rip),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <non_fatal@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
data_type: string

tool: 

assistant: ```c
void pragerror() {
  char msgbuf[5100];
  non_fatal(readline(msgbuf, 5100, 0x0001, 0), "");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pragerror>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x408,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x13f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    $0x13ec,%esi
  call   <readline@plt>
  mov    %eax,%edi
  lea    D2(%rip),%rsi
  call   <non_fatal@plt>
  mov    0x13f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x1408,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: 

assistant: ```c
void pragerror() {
  char msgbuf[5100];
  non_fatal(readline(msgbuf, 5100, 0x0001, 0), "");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pragerror>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x408,%rsp
  xor    %ecx,%ecx
  mov    $0x13ec,%esi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x13f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <readline@plt>
  lea    D9(%rip),%rsi
  mov    %eax,%edi
  call   <non_fatal@plt>
  mov    0x13f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x1408,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type_infered: string

tool: 

assistant: ```c
void pragerror() {
  char msgbuf[5100];
  non_fatal(readline(msgbuf, 5100, 0x0001, 0), "");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pragerror>:
  endbr64
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x408,%rsp
  xor    %ecx,%ecx
  mov    $0x13ec,%esi
  mov    $0x1,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x13f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <readline@plt>
  lea    D6(%rip),%rsi
  mov    %eax,%edi
  call   <non_fatal@plt>
  mov    0x13f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x1408,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string

tool: 

assistant: ```c
void pragerror() {
  char msgbuf[5100];
  non_fatal(readline(msgbuf, 5100, 0x0001, 0), "");
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_sieve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <print@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <sieve@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <printi@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <print@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string
name: disassemble_data
arguments: label: D12
datatype: string

tool: D8: : 

tool: D12: 


assistant: ```c
void test_sieve(const char *msg, char *data, int size) {
  int r;
  print(msg);
  print(": ");
  r = sieve(data, size);
  printi(r);
  print("\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_sieve>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  mov    %edx,%ebp
  call   <print@plt>
  lea    D7(%rip),%rdi
  call   <print@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <sieve@plt>
  mov    %eax,%edi
  call   <printi@plt>
  lea    D19(%rip),%rdi
  call   <print@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string

tool: D7: : 

tool: D19: 


assistant: ```c
void test_sieve(const char *msg, char *data, int size) {
  int r;
  print(msg);
  print(": ");
  r = sieve(data, size);
  printi(r);
  print("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_sieve>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <print@plt>
  lea    D8(%rip),%rdi
  call   <print@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <sieve@plt>
  mov    %eax,%edi
  call   <printi@plt>
  add    $0x8,%rsp
  lea    D7(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <print@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: string

tool: D8: : 

tool: D7: 


assistant: ```c
void test_sieve(const char *msg, char *data, int size) {
  int r;
  print(msg);
  print(": ");
  r = sieve(data, size);
  printi(r);
  print("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_sieve>:
  endbr64
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <print@plt>
  lea    D12(%rip),%rdi
  call   <print@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <sieve@plt>
  mov    %eax,%edi
  call   <printi@plt>
  add    $0x8,%rsp
  lea    D4(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <print@plt>
```

tool_calls: name: read_data
arguments: tag: D12
data_type: string
name: read_data
arguments: tag: D4
data_type: string

tool: D12: : 

tool: D4: 


assistant: ```c
void test_sieve(const char *msg, char *data, int size) {
  int r;
  print(msg);
  print(": ");
  r = sieve(data, size);
  printi(r);
  print("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ccitt_crc16_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x1c(%rbp)
  movswl -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ccitt_crc16@plt>
  test   %rax,%rax
  jne    L19
  movb   $0x1,-0x1(%rbp)
  jmp    L11
L19:
  movb   $0x0,-0x1(%rbp)
L11:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char ccitt_crc16_test(unsigned char *message, short length) {
  char result;
  if (ccitt_crc16(message, length) == 0)
    result = 1;
  else
    result = 0;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ccitt_crc16_test>:
  endbr64
  sub    $0x8,%rsp
  movswl %si,%esi
  call   <ccitt_crc16@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char ccitt_crc16_test(unsigned char *message, short length) {
  char result;
  if (ccitt_crc16(message, length) == 0)
    result = 1;
  else
    result = 0;
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ccitt_crc16_test>:
  endbr64
  sub    $0x8,%rsp
  movswl %si,%esi
  call   <ccitt_crc16@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char ccitt_crc16_test(unsigned char *message, short length) {
  char result;
  if (ccitt_crc16(message, length) == 0)
    result = 1;
  else
    result = 0;
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ccitt_crc16_test>:
  endbr64
  sub    $0x8,%rsp
  movswl %si,%esi
  call   <ccitt_crc16@plt>
  test   %rax,%rax
  sete   %al
  add    $0x8,%rsp
  ret
```

assistant: ```c
char ccitt_crc16_test(unsigned char *message, short length) {
  char result;
  if (ccitt_crc16(message, length) == 0)
    result = 1;
  else
    result = 0;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<buffsizes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getbuffsize@plt>
  mov    -0x10(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <getbuffsize@plt>
  mov    -0x18(%rbp),%rdx
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void buffsizes(int sfd, int *srb, int *ssb) {
  *srb = getbuffsize(sfd, SO_RCVBUF);
  *ssb = getbuffsize(sfd, SO_SNDBUF);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<buffsizes>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    D11(%rip),%rax
  mov    (%rax),%esi
  call   <getbuffsize@plt>
  mov    %eax,(%r12)
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <getbuffsize@plt>
  mov    %eax,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void buffsizes(int sfd, int *srb, int *ssb) {
  *srb = getbuffsize(sfd, SO_RCVBUF);
  *ssb = getbuffsize(sfd, SO_SNDBUF);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<buffsizes>:
  endbr64
  mov    D18(%rip),%rax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%esi
  mov    %rdx,%rbx
  call   <getbuffsize@plt>
  mov    %ebp,%edi
  mov    %eax,(%r12)
  mov    D17(%rip),%rax
  mov    (%rax),%esi
  call   <getbuffsize@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void buffsizes(int sfd, int *srb, int *ssb) {
  *srb = getbuffsize(sfd, SO_RCVBUF);
  *ssb = getbuffsize(sfd, SO_SNDBUF);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<buffsizes>:
  endbr64
  mov    D2(%rip),%rax
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%esi
  mov    %rdx,%rbx
  call   <getbuffsize@plt>
  mov    %ebp,%edi
  mov    %eax,(%r12)
  mov    D14(%rip),%rax
  mov    (%rax),%esi
  call   <getbuffsize@plt>
  mov    %eax,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void buffsizes(int sfd, int *srb, int *ssb) {
  *srb = getbuffsize(sfd, SO_RCVBUF);
  *ssb = getbuffsize(sfd, SO_SNDBUF);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lee_matriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  jmp    L21
L6:
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L36:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L36
  addl   $0x1,-0x18(%rbp)
L21:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L46
  call   <__stack_chk_fail@plt>
L46:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D12
type_infered: string

tool: D13: Dar el elemento [%d][%d]

tool: D12: %lf

assistant: ```c
void lee_matriz(double **m, int filas, int columnas) {
  int i, j;
  double dato;
  for (i = 0; i < filas; i++) {
    for (j = 0; j < columnas; j++) {
      printf("Dar el elemento [%d][%d]", i + 1, j + 1);
      scanf("%lf", &dato);
      m[i][j] = dato;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<lee_matriz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,0x14(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L0
  mov    %rdi,%rbp
  lea    0x1(%rsi),%eax
  mov    %rax,0x18(%rsp)
  movq   $0x1,0x8(%rsp)
  lea    D3(%rip),%r15
  lea    0x20(%rsp),%r14
  jmp    L18
L66:
  lea    0x1(%rbx),%edx
  mov    %r12d,%esi
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%rax
  movsd  0x20(%rsp),%xmm0
  movsd  %xmm0,(%rax,%rbx,8)
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L66
L57:
  addq   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%rax
  add    $0x8,%rbp
  cmp    0x18(%rsp),%rax
  je     L0
L18:
  mov    0x14(%rsp),%eax
  mov    %eax,%r13d
  mov    $0x0,%ebx
  mov    0x8(%rsp),%r12d
  test   %eax,%eax
  jg     L66
  jmp    L57
L0:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string

tool: D3: Dar el elemento [%d][%d]

tool: D1: %lf

assistant: ```c
void lee_matriz(double **m, int filas, int columnas) {
  int i, j;
  double dato;
  for (i = 0; i < filas; i++) {
    for (j = 0; j < columnas; j++) {
      printf("Dar el elemento [%d][%d]", i + 1, j + 1);
      scanf("%lf", &dato);
      m[i][j] = dato;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<lee_matriz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0x8(%rsp)
  mov    %edx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L45
  movslq %edx,%rax
  mov    %rdi,%r15
  lea    D7(%rip),%r13
  xor    %ebx,%ebx
  mov    %rax,(%rsp)
  lea    0x10(%rsp),%r12
  lea    D1(%rip),%rbp
  nopl   (%rax)
L38:
  mov    0xc(%rsp),%eax
  add    $0x1,%ebx
  xor    %r14d,%r14d
  test   %eax,%eax
  jle    L9
  xchg   %ax,%ax
L34:
  lea    0x1(%r14),%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%r15),%rax
  movsd  0x10(%rsp),%xmm0
  movsd  %xmm0,(%rax,%r14,8)
  add    $0x1,%r14
  cmp    (%rsp),%r14
  jne    L34
L9:
  add    $0x8,%r15
  cmp    0x8(%rsp),%ebx
  jne    L38
L45:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
datatype: string
name: disassemble_data
arguments: label: D1
datatype: string

tool: D7: Dar el elemento [%d][%d]

tool: D1: %lf

assistant: ```c
void lee_matriz(double **m, int filas, int columnas) {
  int i, j;
  double dato;
  for (i = 0; i < filas; i++) {
    for (j = 0; j < columnas; j++) {
      printf("Dar el elemento [%d][%d]", i + 1, j + 1);
      scanf("%lf", &dato);
      m[i][j] = dato;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lee_matriz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %esi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jle    L34
  test   %edx,%edx
  jle    L34
  movslq %edx,%rax
  mov    %rdi,%r15
  lea    D3(%rip),%r14
  xor    %ebx,%ebx
  mov    %rax,(%rsp)
  lea    0x10(%rsp),%r13
  lea    D17(%rip),%r12
  nopl   (%rax)
L46:
  add    $0x1,%ebx
  xor    %ebp,%ebp
  nopl   (%rax)
L0:
  lea    0x1(%rbp),%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    (%r15),%rax
  movsd  0x10(%rsp),%xmm0
  movsd  %xmm0,(%rax,%rbp,8)
  add    $0x1,%rbp
  cmp    %rbp,(%rsp)
  jne    L0
  add    $0x8,%r15
  cmp    %ebx,0xc(%rsp)
  jne    L46
L34:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string
name: extract_symbolic_data
arguments: data_label: D17
datatype: string

tool: D3: Dar el elemento [%d][%d]

tool: D17: %lf

assistant: ```c
void lee_matriz(double **m, int filas, int columnas) {
  int i, j;
  double dato;
  for (i = 0; i < filas; i++) {
    for (j = 0; j < columnas; j++) {
      printf("Dar el elemento [%d][%d]", i + 1, j + 1);
      scanf("%lf", &dato);
      m[i][j] = dato;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bzeroAligned8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x7,%eax
  test   %eax,%eax
  jne    L34
  cmpl   $0x0,-0x1c(%rbp)
  jle    L34
  mov    $0x1,%eax
  jmp    L33
L34:
  mov    $0x0,%eax
L33:
  mov    %eax,%edi
  call   <assert@plt>
L21:
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addq   $0x8,-0x8(%rbp)
  subl   $0x8,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jne    L21
  nop
  nop
  leave
  ret
```

assistant: ```c
void bzeroAligned8(void *dest, int size) {
  int *p = (int *)dest;
  assert((size & 7) == 0 && size > 0);
  do {
    p[0] = p[1] = 0;
    p += 2;
    size -= 8;
  } while (size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bzeroAligned8>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  test   $0x7,%sil
  sete   %al
  test   %esi,%esi
  setg   %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  lea    -0x8(%rbp),%eax
  lea    0x8(%rbx,%rax,1),%rax
L5:
  movl   $0x0,0x4(%rbx)
  movl   $0x0,(%rbx)
  add    $0x8,%rbx
  cmp    %rax,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bzeroAligned8(void *dest, int size) {
  int *p = (int *)dest;
  assert((size & 7) == 0 && size > 0);
  do {
    p[0] = p[1] = 0;
    p += 2;
    size -= 8;
  } while (size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bzeroAligned8>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   $0x7,%sil
  sete   %al
  xor    %edi,%edi
  test   %esi,%esi
  setg   %dil
  and    %eax,%edi
  call   <assert@plt>
  lea    -0x8(%rbp),%eax
  lea    0x8(%rbx,%rax,1),%rax
  nopl   (%rax)
L8:
  movl   $0x0,0x4(%rbx)
  add    $0x8,%rbx
  movl   $0x0,-0x8(%rbx)
  cmp    %rax,%rbx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bzeroAligned8(void *dest, int size) {
  int *p = (int *)dest;
  assert((size & 7) == 0 && size > 0);
  do {
    p[0] = p[1] = 0;
    p += 2;
    size -= 8;
  } while (size);
}
```