user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D63(%rip),%rsi
  lea    D35(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L38
L103:
  lea    0x10(%rsp),%rdi
  mov    %rbx,%rdx
  mov    $0x50,%esi
  call   <fgets@plt>
  lea    D55(%rip),%r12
  lea    0x10(%rsp),%rbp
  lea    D85(%rip),%r13
L18:
  mov    $0xb,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L96
  mov    %rbx,%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L18
  mov    %r13,%rdi
  call   <nrerror@plt>
  jmp    L18
L38:
  lea    D82(%rip),%rdi
  call   <nrerror@plt>
  jmp    L103
L96:
  lea    0xc(%rsp),%rdx
  lea    D84(%rip),%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  lea    0x10(%rsp),%rsi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D119(%rip),%rcx
  lea    D103(%rip),%rdx
  lea    D15(%rip),%rsi
  lea    D100(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L75
  mov    $0x1,%ebp
  lea    D62(%rip),%r12
  lea    D71(%rip),%r14
  lea    D19(%rip),%r13
  jmp    L87
L60:
  mov    0x8(%rsp),%edi
  call   <factrl@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  mov    0x8(%rsp),%esi
  mov    %r14,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L54:
  add    $0x1,%ebp
  cmp    %ebp,0xc(%rsp)
  jl     L75
L87:
  lea    0x4(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fscanf@plt>
  movss  D43(%rip),%xmm2
  comiss 0x4(%rsp),%xmm2
  jbe    L60
  mov    0x8(%rsp),%edi
  call   <factrl@plt>
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  mov    0x8(%rsp),%esi
  mov    %r13,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L54
L75:
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D63
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D55
datatype: string
name: parse_data
arguments: data_tag: D85
datatype: string
name: parse_data
arguments: data_tag: D82
datatype: string
name: parse_data
arguments: data_tag: D84
datatype: string
name: parse_data
arguments: data_tag: D9
datatype: string
name: parse_data
arguments: data_tag: D119
datatype: string
name: parse_data
arguments: data_tag: D103
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string
name: parse_data
arguments: data_tag: D100
datatype: string
name: parse_data
arguments: data_tag: D62
datatype: string
name: parse_data
arguments: data_tag: D71
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D43
datatype: f32

tool: D63: r

tool: D35: fncval.dat

tool: D55: N-factorial

tool: D85: Data not found in fncval.dat


tool: D82: Data file fncval.dat not found


tool: D84: %d %*s

tool: D9: 
%s


tool: D119: factrl(n)

tool: D103: actual

tool: D15: n

tool: D100: %6s %18s %20s 


tool: D62: %d %f 

tool: D71: %6d %20e %20e 


tool: D19: %6d %20.0f %20.0f


tool: D43: 10000000000

assistant: ```c
int main(void) {
  char txt[80];
  float actual;
  int i, n, nval;
  FILE *fp;
  if ((fp = fopen("fncval.dat", "r")) == NULL)
    nrerror("Data file fncval.dat not found\n");
  fgets(txt, 80, fp);
  while (strncmp(txt, "N-factorial", 11)) {
    fgets(txt, 80, fp);
    if (feof(fp))
      nrerror("Data not found in fncval.dat\n");
  }
  fscanf(fp, "%d %*s", &nval);
  printf("\n%s\n", txt);
  printf("%6s %18s %20s \n", "n", "actual", "factrl(n)");
  for (i = 1; i <= nval; i++) {
    fscanf(fp, "%d %f ", &n, &actual);
    if (actual < 1.0e10)
      printf("%6d %20.0f %20.0f\n", n, actual, factrl(n));
    else
      printf("%6d %20e %20e \n", n, actual, factrl(n));
  }
  fclose(fp);
  return 0;
}
```