ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<esmQuaternionToMatrix>:
  endbr64
  movaps %xmm1,%xmm6
  movaps %xmm0,%xmm5
  movaps %xmm1,%xmm7
  movl   $0x0,0xc(%rdi)
  mulss  %xmm1,%xmm6
  movaps %xmm2,%xmm9
  movaps %xmm2,%xmm10
  movss  D5(%rip),%xmm8
  mulss  %xmm2,%xmm9
  movl   $0x0,0x1c(%rdi)
  mulss  %xmm1,%xmm5
  movaps %xmm8,%xmm4
  movss  %xmm8,0x3c(%rdi)
  mulss  %xmm3,%xmm10
  movq   $0x0,0x2c(%rdi)
  mulss  %xmm2,%xmm1
  movq   $0x0,0x34(%rdi)
  addss  %xmm6,%xmm6
  mulss  %xmm3,%xmm7
  addss  %xmm9,%xmm9
  addss  %xmm5,%xmm5
  subss  %xmm6,%xmm4
  addss  %xmm10,%xmm10
  addss  %xmm1,%xmm1
  addss  %xmm7,%xmm7
  subss  %xmm9,%xmm4
  movss  %xmm4,(%rdi)
  movaps %xmm5,%xmm4
  subss  %xmm10,%xmm5
  addss  %xmm10,%xmm4
  movss  %xmm5,0x10(%rdi)
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  movss  %xmm4,0x4(%rdi)
  movaps %xmm0,%xmm4
  mulss  %xmm2,%xmm4
  movaps %xmm1,%xmm2
  mulss  %xmm3,%xmm0
  addss  %xmm5,%xmm5
  addss  %xmm4,%xmm4
  addss  %xmm0,%xmm0
  movaps %xmm5,%xmm10
  movaps %xmm8,%xmm5
  subss  %xmm10,%xmm5
  movaps %xmm4,%xmm11
  addss  %xmm7,%xmm4
  subss  %xmm7,%xmm11
  addss  %xmm0,%xmm2
  subss  %xmm0,%xmm1
  movaps %xmm5,%xmm10
  subss  %xmm6,%xmm5
  movss  %xmm4,0x20(%rdi)
  subss  %xmm9,%xmm10
  movss  %xmm11,0x8(%rdi)
  movss  %xmm2,0x18(%rdi)
  movss  %xmm1,0x24(%rdi)
  movss  %xmm10,0x14(%rdi)
  movss  %xmm5,0x28(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
datatype: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void esmQuaternionToMatrix(float *M, float x, float y, float z, float w) {
  float xsq;
  float ysq;
  float zsq;
  float xy;
  float xz;
  float yz;
  float wx;
  float wy;
  float wz;
  xsq = x * x;
  ysq = y * y;
  zsq = z * z;
  xy = x * y;
  xz = x * z;
  yz = y * z;
  wx = w * x;
  wy = w * y;
  wz = w * z;
  M[0] = 1 - (2 * ysq) - (2 * zsq);
  M[1] = (2 * xy) + (2 * wz);
  M[2] = (2 * xz) - (2 * wy);
  M[3] = 0;
  M[4] = (2 * xy) - (2 * wz);
  M[5] = 1 - (2 * xsq) - (2 * zsq);
  M[6] = (2 * yz) + (2 * wx);
  M[7] = 0;
  M[8] = (2 * xz) + (2 * wy);
  M[9] = (2 * yz) - (2 * wx);
  M[10] = 1 - (2 * xsq) - (2 * ysq);
  M[11] = 0;
  M[12] = 0;
  M[13] = 0;
  M[14] = 0;
  M[15] = 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<esmQuaternionToMatrix>:
  endbr64
  movaps %xmm1,%xmm6
  movaps %xmm0,%xmm5
  movaps %xmm1,%xmm7
  movl   $0x0,0xc(%rdi)
  mulss  %xmm1,%xmm6
  movaps %xmm2,%xmm9
  movaps %xmm2,%xmm10
  movss  D3(%rip),%xmm8
  mulss  %xmm2,%xmm9
  movl   $0x0,0x1c(%rdi)
  mulss  %xmm1,%xmm5
  movaps %xmm8,%xmm4
  movss  %xmm8,0x3c(%rdi)
  mulss  %xmm3,%xmm10
  movq   $0x0,0x2c(%rdi)
  mulss  %xmm2,%xmm1
  movq   $0x0,0x34(%rdi)
  addss  %xmm6,%xmm6
  mulss  %xmm3,%xmm7
  addss  %xmm9,%xmm9
  addss  %xmm5,%xmm5
  subss  %xmm6,%xmm4
  addss  %xmm10,%xmm10
  addss  %xmm1,%xmm1
  addss  %xmm7,%xmm7
  subss  %xmm9,%xmm4
  movss  %xmm4,(%rdi)
  movaps %xmm5,%xmm4
  subss  %xmm10,%xmm5
  addss  %xmm10,%xmm4
  movss  %xmm5,0x10(%rdi)
  movaps %xmm0,%xmm5
  mulss  %xmm0,%xmm5
  movss  %xmm4,0x4(%rdi)
  movaps %xmm0,%xmm4
  mulss  %xmm2,%xmm4
  movaps %xmm1,%xmm2
  mulss  %xmm3,%xmm0
  addss  %xmm5,%xmm5
  addss  %xmm4,%xmm4
  addss  %xmm0,%xmm0
  movaps %xmm5,%xmm10
  movaps %xmm8,%xmm5
  subss  %xmm10,%xmm5
  movaps %xmm4,%xmm11
  addss  %xmm7,%xmm4
  subss  %xmm7,%xmm11
  addss  %xmm0,%xmm2
  subss  %xmm0,%xmm1
  movaps %xmm5,%xmm10
  subss  %xmm6,%xmm5
  movss  %xmm4,0x20(%rdi)
  subss  %xmm9,%xmm10
  movss  %xmm11,0x8(%rdi)
  movss  %xmm2,0x18(%rdi)
  movss  %xmm1,0x24(%rdi)
  movss  %xmm10,0x14(%rdi)
  movss  %xmm5,0x28(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
data_type: byte[4]

tool: {"D3": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void esmQuaternionToMatrix(float *M, float x, float y, float z, float w) {
  float xsq;
  float ysq;
  float zsq;
  float xy;
  float xz;
  float yz;
  float wx;
  float wy;
  float wz;
  xsq = x * x;
  ysq = y * y;
  zsq = z * z;
  xy = x * y;
  xz = x * z;
  yz = y * z;
  wx = w * x;
  wy = w * y;
  wz = w * z;
  M[0] = 1 - (2 * ysq) - (2 * zsq);
  M[1] = (2 * xy) + (2 * wz);
  M[2] = (2 * xz) - (2 * wy);
  M[3] = 0;
  M[4] = (2 * xy) - (2 * wz);
  M[5] = 1 - (2 * xsq) - (2 * zsq);
  M[6] = (2 * yz) + (2 * wx);
  M[7] = 0;
  M[8] = (2 * xz) + (2 * wy);
  M[9] = (2 * yz) - (2 * wx);
  M[10] = 1 - (2 * xsq) - (2 * ysq);
  M[11] = 0;
  M[12] = 0;
  M[13] = 0;
  M[14] = 0;
  M[15] = 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x1,-0x30(%rbp)
  jmp    L9
L35:
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L75
L5:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <isSquare@plt>
  test   %rax,%rax
  jne    L1
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <isPerfact@plt>
  test   %rax,%rax
  jne    L1
  cmpl   $0x0,-0x2c(%rbp)
  jle    L3
  mov    $0x20,%edi
  call   <putchar@plt>
L3:
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x2c(%rbp)
L1:
  addq   $0x1,-0x20(%rbp)
L75:
  mov    -0x28(%rbp),%rax
  cmp    %rax,-0x20(%rbp)
  jl     L5
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x30(%rbp)
L9:
  mov    -0x34(%rbp),%eax
  cmp    %eax,-0x30(%rbp)
  jle    L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L68
  call   <__stack_chk_fail@plt>
L68:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D23
datatype: string
name: parse_data
arguments: data_tag: D32
datatype: string
name: parse_data
arguments: data_tag: D21
datatype: string

tool: D23: %d

tool: D32: %lld

tool: D21: Case %d: 

assistant: ```c
int main() {
  int t, i, temp;
  long long n, denu, numa, pre, x;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lld", &n);
    temp = 0;
    x = sqrt(n - 1);
    printf("Case %d: ", i);
    while (x < n) {
      numa = x;
      denu = n - x;
      if (isSquare(denu) == 0) {
        denu = sqrt(denu);
        if (isPerfact(numa, denu) == 0) {
          if (temp > 0)
            printf(" ");
          printf("%lld", x);
          temp++;
        }
      }
      x++;
    }
    printf("\n");
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L10
  mov    $0x1,%r13d
  lea    0x10(%rsp),%r15
  lea    D22(%rip),%r14
  jmp    L76
L40:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%r12d
L90:
  add    $0x1,%rbp
  mov    0x10(%rsp),%rbx
  cmp    %rbp,%rbx
  jle    L11
L2:
  sub    %rbp,%rbx
  mov    %rbx,%rdi
  call   <isSquare@plt>
  test   %rax,%rax
  jne    L90
  mov    %rbx,%rdi
  call   <sqrt@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <isPerfact@plt>
  test   %rax,%rax
  jne    L90
  test   %r12d,%r12d
  jle    L40
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L40
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r13d
  cmp    %r13d,0xc(%rsp)
  jl     L10
L76:
  mov    %r15,%rsi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdi
  call   <sqrt@plt>
  mov    %rax,%rbp
  mov    %r13d,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rbx
  cmp    %rbx,%rbp
  jge    L11
  mov    $0x0,%r12d
  jmp    L2
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
data_type: string
name: extract_symbolic_data
arguments: data_tag: D22
data_type: string
name: extract_symbolic_data
arguments: data_tag: D25
data_type: string

tool: D17: %d

tool: D22: %lld

tool: D25: Case %d: 

assistant: ```c
int main() {
  int t, i, temp;
  long long n, denu, numa, pre, x;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lld", &n);
    temp = 0;
    x = sqrt(n - 1);
    printf("Case %d: ", i);
    while (x < n) {
      numa = x;
      denu = n - x;
      if (isSquare(denu) == 0) {
        denu = sqrt(denu);
        if (isPerfact(numa, denu) == 0) {
          if (temp > 0)
            printf(" ");
          printf("%lld", x);
          temp++;
        }
      }
      x++;
    }
    printf("\n");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  lea    D10(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L5
  mov    $0x1,%ebp
  lea    0x10(%rsp),%r14
  lea    D23(%rip),%r12
L55:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdi
  call   <sqrt@plt>
  lea    D7(%rip),%rdi
  mov    %ebp,%esi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  cmp    %rdi,%r13
  jge    L60
  xor    %ebx,%ebx
  jmp    L22
  nopl   0x0(%rax)
L71:
  mov    0x10(%rsp),%rdi
  add    $0x1,%r13
  cmp    %r13,%rdi
  jle    L60
L22:
  sub    %r13,%rdi
  mov    %rdi,%r15
  call   <isSquare@plt>
  test   %rax,%rax
  jne    L71
  mov    %r15,%rdi
  call   <sqrt@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <isPerfact@plt>
  test   %rax,%rax
  jne    L71
  test   %ebx,%ebx
  je     L51
  mov    $0x20,%edi
  call   <putchar@plt>
L51:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  add    $0x1,%ebx
  cmp    %r13,%rdi
  jg     L22
  nopw   0x0(%rax,%rax,1)
L60:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0xc(%rsp)
  jge    L55
L5:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type: string
name: unpack_data
arguments: label: D23
type: string
name: unpack_data
arguments: label: D7
type: string

tool: D10: %d

tool: D23: %lld

tool: D7: Case %d: 

assistant: ```c
int main() {
  int t, i, temp;
  long long n, denu, numa, pre, x;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lld", &n);
    temp = 0;
    x = sqrt(n - 1);
    printf("Case %d: ", i);
    while (x < n) {
      numa = x;
      denu = n - x;
      if (isSquare(denu) == 0) {
        denu = sqrt(denu);
        if (isPerfact(numa, denu) == 0) {
          if (temp > 0)
            printf(" ");
          printf("%lld", x);
          temp++;
        }
      }
      x++;
    }
    printf("\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  lea    D12(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L59
  mov    $0x1,%ebp
  lea    0x10(%rsp),%r14
  lea    D20(%rip),%r12
L1:
  mov    %r14,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  lea    -0x1(%rax),%rdi
  call   <sqrt@plt>
  lea    D8(%rip),%rdi
  mov    %ebp,%esi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  cmp    %rdi,%r13
  jge    L29
  xor    %ebx,%ebx
  jmp    L91
  nopl   0x0(%rax)
L71:
  mov    0x10(%rsp),%rdi
  add    $0x1,%r13
  cmp    %r13,%rdi
  jle    L29
L91:
  sub    %r13,%rdi
  mov    %rdi,%r15
  call   <isSquare@plt>
  test   %rax,%rax
  jne    L71
  mov    %r15,%rdi
  call   <sqrt@plt>
  mov    %r13,%rdi
  mov    %rax,%rsi
  call   <isPerfact@plt>
  test   %rax,%rax
  jne    L71
  test   %ebx,%ebx
  je     L20
  mov    $0x20,%edi
  call   <putchar@plt>
L20:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  mov    0x10(%rsp),%rdi
  add    $0x1,%ebx
  cmp    %r13,%rdi
  jg     L91
  nopw   0x0(%rax,%rax,1)
L29:
  mov    $0xa,%edi
  add    $0x1,%ebp
  call   <putchar@plt>
  cmp    %ebp,0xc(%rsp)
  jge    L1
L59:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D12
type: string
name: parse_data
arguments: label: D20
type: string
name: parse_data
arguments: label: D8
type: string

tool: D12: %d

tool: D20: %lld

tool: D8: Case %d: 

assistant: ```c
int main() {
  int t, i, temp;
  long long n, denu, numa, pre, x;
  scanf("%d", &t);
  for (i = 1; i <= t; i++) {
    scanf("%lld", &n);
    temp = 0;
    x = sqrt(n - 1);
    printf("Case %d: ", i);
    while (x < n) {
      numa = x;
      denu = n - x;
      if (isSquare(denu) == 0) {
        denu = sqrt(denu);
        if (isPerfact(numa, denu) == 0) {
          if (temp > 0)
            printf(" ");
          printf("%lld", x);
          temp++;
        }
      }
      x++;
    }
    printf("\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vrRead>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  or     $0xfc530000,%eax
  mov    $0xac1c,%esi
  mov    %eax,%edi
  call   <outl@plt>
  mov    $0xac1e,%edi
  call   <inw@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint16_t vrRead(uint16_t wClassIndex) {
  uint16_t wData;
  outl(((uint32_t)0xFC53 << 16) | wClassIndex, 0xAC1C);
  wData = inw(0xAC1E);
  return wData;
}
```
user: Translate the below assembly code into C programming language:

```asm
<vrRead>:
  endbr64
  sub    $0x8,%rsp
  or     $0xfc530000,%edi
  mov    $0xac1c,%esi
  call   <outl@plt>
  mov    $0xac1e,%edi
  call   <inw@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint16_t vrRead(uint16_t wClassIndex) {
  uint16_t wData;
  outl(((uint32_t)0xFC53 << 16) | wClassIndex, 0xAC1C);
  wData = inw(0xAC1E);
  return wData;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vrRead>:
  endbr64
  sub    $0x8,%rsp
  or     $0xfc530000,%edi
  mov    $0xac1c,%esi
  call   <outl@plt>
  mov    $0xac1e,%edi
  add    $0x8,%rsp
  jmp    1060 <inw@plt>
```

assistant: ```c
uint16_t vrRead(uint16_t wClassIndex) {
  uint16_t wData;
  outl(((uint32_t)0xFC53 << 16) | wClassIndex, 0xAC1C);
  wData = inw(0xAC1E);
  return wData;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vrRead>:
  endbr64
  sub    $0x8,%rsp
  or     $0xfc530000,%edi
  mov    $0xac1c,%esi
  call   <outl@plt>
  mov    $0xac1e,%edi
  add    $0x8,%rsp
  jmp    1060 <inw@plt>
```

assistant: ```c
uint16_t vrRead(uint16_t wClassIndex) {
  uint16_t wData;
  outl(((uint32_t)0xFC53 << 16) | wClassIndex, 0xAC1C);
  wData = inw(0xAC1E);
  return wData;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<db_drop_jes_table_sql>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
data_type: string

tool: D2: DROP TABLE jes

assistant: ```c
const char *db_drop_jes_table_sql(void) {
  static const char *query = "DROP TABLE jes";
  return query;
}
```
user: Translate the below assembly code into C programming language:

```asm
<db_drop_jes_table_sql>:
  endbr64
  lea    D1(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_guessed: string

tool: D1: DROP TABLE jes

assistant: ```c
const char *db_drop_jes_table_sql(void) {
  static const char *query = "DROP TABLE jes";
  return query;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<db_drop_jes_table_sql>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: DROP TABLE jes

assistant: ```c
const char *db_drop_jes_table_sql(void) {
  static const char *query = "DROP TABLE jes";
  return query;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,-0x10(%rbp)
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D33
type_guessed: string
name: unpack_data
arguments: data_tag: D25
type_guessed: string
name: unpack_data
arguments: data_tag: D48
type_guessed: string
name: unpack_data
arguments: data_tag: D27
type_guessed: string
name: unpack_data
arguments: data_tag: D42
type_guessed: string

tool: D33: Input: 

tool: D25: %d

tool: D48: Input was: %d


tool: D27: GetChar: 

tool: D42: Got char: 

assistant: ```c
int main() {
  printf("\n");
  int x = 0;
  printf("Input: ");
  scanf("%d", &x);
  printf("Input was: %d\n", x);
  getchar();
  printf("GetChar: ");
  int x2;
  x2 = getchar();
  printf("Got char: ");
  putchar(x2);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%edi
  call   <putchar@plt>
  movl   $0x0,0x4(%rsp)
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D39
type_infered: string
name: parse_data
arguments: data_tag: D10
type_infered: string
name: parse_data
arguments: data_tag: D19
type_infered: string
name: parse_data
arguments: data_tag: D32
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: string

tool: D39: Input: 

tool: D10: %d

tool: D19: Input was: %d


tool: D32: GetChar: 

tool: D26: Got char: 

assistant: ```c
int main() {
  printf("\n");
  int x = 0;
  printf("Input: ");
  scanf("%d", &x);
  printf("Input was: %d\n", x);
  getchar();
  printf("GetChar: ");
  int x2;
  x2 = getchar();
  printf("Got char: ");
  putchar(x2);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <putchar@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D20(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string
name: extract_symbolic_data
arguments: tag: D37
type: string
name: extract_symbolic_data
arguments: tag: D30
type: string
name: extract_symbolic_data
arguments: tag: D20
type: string

tool: D21: Input: 

tool: D0: %d

tool: D37: Input was: %d


tool: D30: GetChar: 

tool: D20: Got char: 

assistant: ```c
int main() {
  printf("\n");
  int x = 0;
  printf("Input: ");
  scanf("%d", &x);
  printf("Input was: %d\n", x);
  getchar();
  printf("GetChar: ");
  int x2;
  x2 = getchar();
  printf("Got char: ");
  putchar(x2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xa,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <putchar@plt>
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebp,%edi
  call   <putchar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D26
type_guessed: string
name: parse_data
arguments: data_tag: D25
type_guessed: string
name: parse_data
arguments: data_tag: D2
type_guessed: string
name: parse_data
arguments: data_tag: D6
type_guessed: string
name: parse_data
arguments: data_tag: D15
type_guessed: string

tool: D26: Input: 

tool: D25: %d

tool: D2: Input was: %d


tool: D6: GetChar: 

tool: D15: Got char: 

assistant: ```c
int main() {
  printf("\n");
  int x = 0;
  printf("Input: ");
  scanf("%d", &x);
  printf("Input was: %d\n", x);
  getchar();
  printf("GetChar: ");
  int x2;
  x2 = getchar();
  printf("Got char: ");
  putchar(x2);
  return 0;
}
```