ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_ptr_not_equal_pass>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x1c(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    %rax,%rdx
  mov    $0x36,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <assert_ptr_not_equal_@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c

assistant: ```c
void test_ptr_not_equal_pass() {
  int x = 1, y = 2;
  int *p1 = &x, *p2 = &y;
  assert_ptr_not_equal_("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c", 54, (p1), (p2));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test_ptr_not_equal_pass>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  mov    $0x36,%esi
  lea    D5(%rip),%rdi
  call   <assert_ptr_not_equal_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c

assistant: ```c
void test_ptr_not_equal_pass() {
  int x = 1, y = 2;
  int *p1 = &x, *p2 = &y;
  assert_ptr_not_equal_("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c", 54, (p1), (p2));
}
```
user: What is the c source code of the assembly code below:

```asm
<test_ptr_not_equal_pass>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x36,%esi
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <assert_ptr_not_equal_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c

assistant: ```c
void test_ptr_not_equal_pass() {
  int x = 1, y = 2;
  int *p1 = &x, *p2 = &y;
  assert_ptr_not_equal_("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c", 54, (p1), (p2));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test_ptr_not_equal_pass>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x36,%esi
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rcx
  mov    %rsp,%rdx
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  call   <assert_ptr_not_equal_@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
datatype: string

tool: D6: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c

assistant: ```c
void test_ptr_not_equal_pass() {
  int x = 1, y = 2;
  int *p1 = &x, *p2 = &y;
  assert_ptr_not_equal_("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/hughbien/assertive/refs/heads/master/test/pass_test.c", 54, (p1), (p2));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sectors_to_MB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  shlq   $0x9,-0x38(%rbp)
  movq   $0xf4240,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  je     L7
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rax,-0x20(%rbp)
L7:
  mov    -0x10(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  divl   -0x18(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long sectors_to_MB(unsigned long long n) {
  n <<= 9;
  ({
    unsigned long __upper, __low, __high, __mod, __base;
    __base = (1000000);
    asm("" : "=a"(__low), "=d"(__high) : "A"(n));
    __upper = __high;
    if (__high) {
      __upper = __high % (__base);
      __high = __high / (__base);
    }
    asm("divl %2" : "=a"(__low), "=d"(__mod) : "rm"(__base), "0"(__low), "1"(__upper));
    asm("" : "=A"(n) : "a"(__low), "d"(__high));
    __mod;
  });
  return n;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumelement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  jmp    L13
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  -0x4(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L9
  movss  -0x4(%rbp),%xmm0
  cvttss2si %xmm0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int sumelement(int array[], int size) {
  int i = 0;
  float sum = 0;
  for (; i < size; i++)
    sum += array[i];
  return sum;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sumelement>:
  endbr64
  test   %esi,%esi
  jle    L10
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
L9:
  pxor   %xmm1,%xmm1
  cvtsi2ssl (%rax),%xmm1
  addss  %xmm1,%xmm0
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L9
L19:
  cvttss2si %xmm0,%eax
  ret
L10:
  pxor   %xmm0,%xmm0
  jmp    L19
```

assistant: ```c
int sumelement(int array[], int size) {
  int i = 0;
  float sum = 0;
  for (; i < size; i++)
    sum += array[i];
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sumelement>:
  endbr64
  test   %esi,%esi
  jle    L18
  lea    -0x1(%rsi),%eax
  pxor   %xmm0,%xmm0
  lea    0x4(%rdi,%rax,4),%rax
  nopl   0x0(%rax)
L0:
  pxor   %xmm1,%xmm1
  add    $0x4,%rdi
  cvtsi2ssl -0x4(%rdi),%xmm1
  addss  %xmm1,%xmm0
  cmp    %rax,%rdi
  jne    L0
  cvttss2si %xmm0,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sumelement(int array[], int size) {
  int i = 0;
  float sum = 0;
  for (; i < size; i++)
    sum += array[i];
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sumelement>:
  endbr64
  test   %esi,%esi
  jle    L31
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L56
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L1:
  movdqu (%rax),%xmm3
  add    $0x10,%rax
  cvtdq2ps %xmm3,%xmm0
  addss  %xmm0,%xmm1
  movaps %xmm0,%xmm2
  shufps $0x55,%xmm0,%xmm2
  addss  %xmm2,%xmm1
  movaps %xmm0,%xmm2
  unpckhps %xmm0,%xmm2
  shufps $0xff,%xmm0,%xmm0
  addss  %xmm2,%xmm1
  addss  %xmm0,%xmm1
  cmp    %rdx,%rax
  jne    L1
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  test   $0x3,%sil
  je     L3
L51:
  movslq %eax,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2ssl (%rdi,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%rcx
  lea    0x1(%rax),%edx
  addss  %xmm0,%xmm1
  cmp    %edx,%esi
  jle    L3
  pxor   %xmm0,%xmm0
  add    $0x2,%eax
  cvtsi2ssl 0x4(%rdi,%rcx,1),%xmm0
  addss  %xmm0,%xmm1
  cmp    %eax,%esi
  jle    L3
  pxor   %xmm0,%xmm0
  cvtsi2ssl 0x8(%rdi,%rcx,1),%xmm0
  addss  %xmm0,%xmm1
L3:
  cvttss2si %xmm1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  xor    %eax,%eax
  ret
L56:
  pxor   %xmm1,%xmm1
  xor    %eax,%eax
  jmp    L51
```

assistant: ```c
int sumelement(int array[], int size) {
  int i = 0;
  float sum = 0;
  for (; i < size; i++)
    sum += array[i];
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<MoveRobotRelative>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %r8d,-0x34(%rbp)
  mov    %r9d,-0x38(%rbp)
  mov    $0xb,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,-0x14(%rbp)
  mov    $0xc,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,-0x10(%rbp)
  mov    $0xd,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0xe,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0xf,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x4(%rbp),%eax
  lea    (%rdx,%rax,1),%r8d
  mov    -0x30(%rbp),%edx
  mov    -0x8(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x2c(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0x28(%rbp),%esi
  mov    -0xc(%rbp),%eax
  add    %eax,%esi
  mov    -0x24(%rbp),%edi
  mov    -0x14(%rbp),%eax
  add    %edi,%eax
  mov    -0x38(%rbp),%edi
  mov    %edi,%r9d
  mov    %eax,%edi
  call   <MoveRobot@plt>
  leave
  ret
```

assistant: ```c
int MoveRobotRelative(int a1, int a2, int a3, int a4, int a5, int mode) {
  int b1, b2, b3, b4, b5;
  b1 = getNormalizedInput(0 + 11);
  b3 = getNormalizedInput(1 + 11);
  b2 = getNormalizedInput(2 + 11);
  b4 = getNormalizedInput(3 + 11);
  b5 = getNormalizedInput(4 + 11);
  return MoveRobot(a1 + b1, a2 + b2, a3 + b3, a4 + b4, a5 + b5, mode);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MoveRobotRelative>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x8(%rsp)
  mov    %esi,0xc(%rsp)
  mov    %edx,%r14d
  mov    %ecx,%r15d
  mov    %r8d,%r12d
  mov    %r9d,%r13d
  mov    $0xb,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,(%rsp)
  mov    $0xc,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,%ebx
  mov    $0xd,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,0x4(%rsp)
  mov    $0xe,%edi
  call   <getNormalizedInput@plt>
  mov    %eax,%ebp
  mov    $0xf,%edi
  call   <getNormalizedInput@plt>
  lea    0x0(%rbp,%r15,1),%ecx
  lea    (%rbx,%r14,1),%edx
  mov    0x4(%rsp),%ebx
  add    0xc(%rsp),%ebx
  mov    %ebx,%esi
  mov    (%rsp),%ebx
  add    0x8(%rsp),%ebx
  mov    %ebx,%edi
  mov    %r13d,%r9d
  lea    (%rax,%r12,1),%r8d
  call   <MoveRobot@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int MoveRobotRelative(int a1, int a2, int a3, int a4, int a5, int mode) {
  int b1, b2, b3, b4, b5;
  b1 = getNormalizedInput(0 + 11);
  b3 = getNormalizedInput(1 + 11);
  b2 = getNormalizedInput(2 + 11);
  b4 = getNormalizedInput(3 + 11);
  b5 = getNormalizedInput(4 + 11);
  return MoveRobot(a1 + b1, a2 + b2, a3 + b3, a4 + b4, a5 + b5, mode);
}
```
user: What is the c source code of the assembly code below:

```asm
<MoveRobotRelative>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  mov    $0xb,%edi
  mov    %r8d,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  call   <getNormalizedInput@plt>
  mov    $0xc,%edi
  mov    %eax,(%rsp)
  call   <getNormalizedInput@plt>
  mov    $0xd,%edi
  mov    %eax,%ebp
  call   <getNormalizedInput@plt>
  mov    $0xe,%edi
  mov    %eax,%ebx
  call   <getNormalizedInput@plt>
  mov    $0xf,%edi
  mov    %eax,%r12d
  call   <getNormalizedInput@plt>
  mov    0xc(%rsp),%r8d
  lea    (%rbx,%r13,1),%esi
  mov    0x8(%rsp),%r9d
  mov    (%rsp),%ebx
  add    0x4(%rsp),%ebx
  add    $0x18,%rsp
  lea    (%r12,%r15,1),%ecx
  lea    0x0(%rbp,%r14,1),%edx
  mov    %ebx,%edi
  add    %eax,%r8d
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <MoveRobot@plt>
```

assistant: ```c
int MoveRobotRelative(int a1, int a2, int a3, int a4, int a5, int mode) {
  int b1, b2, b3, b4, b5;
  b1 = getNormalizedInput(0 + 11);
  b3 = getNormalizedInput(1 + 11);
  b2 = getNormalizedInput(2 + 11);
  b4 = getNormalizedInput(3 + 11);
  b5 = getNormalizedInput(4 + 11);
  return MoveRobot(a1 + b1, a2 + b2, a3 + b3, a4 + b4, a5 + b5, mode);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<MoveRobotRelative>:
  endbr64
  push   %r15
  mov    %ecx,%r15d
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,0x4(%rsp)
  mov    $0xb,%edi
  mov    %r8d,0xc(%rsp)
  mov    %r9d,0x8(%rsp)
  call   <getNormalizedInput@plt>
  mov    $0xc,%edi
  mov    %eax,(%rsp)
  call   <getNormalizedInput@plt>
  mov    $0xd,%edi
  mov    %eax,%ebp
  call   <getNormalizedInput@plt>
  mov    $0xe,%edi
  mov    %eax,%ebx
  call   <getNormalizedInput@plt>
  mov    $0xf,%edi
  mov    %eax,%r12d
  call   <getNormalizedInput@plt>
  mov    0xc(%rsp),%r8d
  lea    (%rbx,%r13,1),%esi
  mov    0x8(%rsp),%r9d
  mov    (%rsp),%ebx
  add    0x4(%rsp),%ebx
  add    $0x18,%rsp
  lea    (%r12,%r15,1),%ecx
  lea    0x0(%rbp,%r14,1),%edx
  mov    %ebx,%edi
  add    %eax,%r8d
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <MoveRobot@plt>
```

assistant: ```c
int MoveRobotRelative(int a1, int a2, int a3, int a4, int a5, int mode) {
  int b1, b2, b3, b4, b5;
  b1 = getNormalizedInput(0 + 11);
  b3 = getNormalizedInput(1 + 11);
  b2 = getNormalizedInput(2 + 11);
  b4 = getNormalizedInput(3 + 11);
  b5 = getNormalizedInput(4 + 11);
  return MoveRobot(a1 + b1, a2 + b2, a3 + b3, a4 + b4, a5 + b5, mode);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cbm_iec_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <cbmarch_iec_wait@plt>
  leave
  ret
```

assistant: ```c
int cbm_iec_wait(int HandleDevice, int Line, int State) {
  ;
  return cbmarch_iec_wait(HandleDevice, Line, State);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<cbm_iec_wait>:
  endbr64
  sub    $0x8,%rsp
  call   <cbmarch_iec_wait@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int cbm_iec_wait(int HandleDevice, int Line, int State) {
  ;
  return cbmarch_iec_wait(HandleDevice, Line, State);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<cbm_iec_wait>:
  endbr64
  jmp    1050 <cbmarch_iec_wait@plt>
```

assistant: ```c
int cbm_iec_wait(int HandleDevice, int Line, int State) {
  ;
  return cbmarch_iec_wait(HandleDevice, Line, State);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cbm_iec_wait>:
  endbr64
  jmp    1050 <cbmarch_iec_wait@plt>
```

assistant: ```c
int cbm_iec_wait(int HandleDevice, int Line, int State) {
  ;
  return cbmarch_iec_wait(HandleDevice, Line, State);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dict_hash_dobbs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L10:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xa,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0x6,%eax
  xor    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L10
  mov    -0xc(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shr    $0xb,%eax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0xf,%eax
  add    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned dict_hash_dobbs(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dict_hash_dobbs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L22
  mov    %rbx,%rcx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x0,%eax
L12:
  movsbl (%rcx),%edx
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  add    $0x1,%rcx
  cmp    %rsi,%rcx
  jne    L12
L9:
  lea    (%rax,%rax,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  pop    %rbx
  ret
L22:
  mov    $0x0,%eax
  jmp    L9
```

assistant: ```c
unsigned dict_hash_dobbs(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<dict_hash_dobbs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L15
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L0:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L0
  lea    (%rax,%rax,8),%eax
  pop    %rbx
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nop
L15:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned dict_hash_dobbs(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dict_hash_dobbs>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L3
  sub    $0x1,%eax
  mov    %rbx,%rdi
  lea    0x1(%rbx,%rax,1),%rcx
  xor    %eax,%eax
  xchg   %ax,%ax
L13:
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %eax,%edx
  mov    %edx,%eax
  shl    $0xa,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %edx,%eax
  cmp    %rdi,%rcx
  jne    L13
  lea    (%rax,%rax,8),%eax
  pop    %rbx
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nop
L3:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned dict_hash_dobbs(char *key) {
  int len;
  unsigned hash;
  int i;
  len = strlen(key);
  for (hash = 0, i = 0; i < len; i++) {
    hash += (unsigned)key[i];
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rcx
  mov    %rcx,-0x38(%rbp)
  xor    %ecx,%ecx
  mov    %rsp,%rcx
  mov    %rcx,%r15
  movq   $0x2,-0x58(%rbp)
  mov    -0x58(%rbp),%rcx
  mov    -0x58(%rbp),%rbx
  lea    -0x1(%rcx),%r12
  mov    %r12,-0x50(%rbp)
  mov    %rcx,%r12
  mov    %r12,%r13
  mov    $0x0,%r14d
  mov    %rcx,%r12
  shl    $0x2,%r12
  lea    -0x1(%rbx),%r13
  mov    %r13,-0x48(%rbp)
  mov    %rcx,%r13
  mov    %r13,%r10
  mov    $0x0,%r11d
  mov    %rbx,%r13
  mov    %r13,%rax
  mov    $0x0,%edx
  mov    %r11,%r14
  imul   %rax,%r14
  mov    %rdx,%r13
  imul   %r10,%r13
  add    %r14,%r13
  mul    %r10
  lea    0x0(%r13,%rdx,1),%r10
  mov    %r10,%rdx
  mov    %rcx,%rax
  mov    %rax,%r8
  mov    $0x0,%r9d
  mov    %rbx,%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  mov    %r9,%rdx
  imul   %rsi,%rdx
  mov    %rdi,%rax
  imul   %r8,%rax
  lea    (%rdx,%rax,1),%r10
  mov    %r8,%rax
  mul    %rsi
  lea    (%r10,%rdx,1),%rsi
  mov    %rsi,%rdx
  mov    %rcx,%rdx
  mov    %rbx,%rax
  imul   %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L4:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L4
L29:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L34
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L34:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  mov    %r12,%rcx
  shr    $0x2,%rcx
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rsi
  mov    -0x40(%rbp),%rax
  imul   %rcx,%rdx
  add    %rsi,%rdx
  movl   $0xffffffff,(%rax,%rdx,4)
  mov    -0x40(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <foo@plt>
  mov    %r12,%rcx
  shr    $0x2,%rcx
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x58(%rbp),%rax
  lea    -0x1(%rax),%rsi
  mov    -0x40(%rbp),%rax
  imul   %rcx,%rdx
  add    %rsi,%rdx
  mov    (%rax,%rdx,4),%eax
  cmp    $0x2,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    %r15,%rsp
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  long N = 2;
  int v[N][N];
  v[N - 1][N - 1] = -1;
  foo(N, v);
  assert(v[N - 1][N - 1] == 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0xffffffff,0xc(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edi
  call   <foo@plt>
  cmpl   $0x2,0xc(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long N = 2;
  int v[N][N];
  v[N - 1][N - 1] = -1;
  foo(N, v);
  assert(v[N - 1][N - 1] == 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x2,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0xffffffff,0xc(%rsp)
  call   <foo@plt>
  xor    %edi,%edi
  cmpl   $0x2,0xc(%rsp)
  sete   %dil
  call   <assert@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  long N = 2;
  int v[N][N];
  v[N - 1][N - 1] = -1;
  foo(N, v);
  assert(v[N - 1][N - 1] == 2);
}
```