ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r15
  lea    D8(%rip),%rdi
  lea    D4(%rip),%r15
  push   %r14
  lea    D53(%rip),%r14
  push   %r13
  push   %r12
  lea    D68(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  call   <printf@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1f(%rsp),%rax
  mov    %rax,0x8(%rsp)
L20:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L18
  movslq %eax,%rbx
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L7:
  movsbl 0x0(%rbp,%r13,1),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L7
L18:
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x1f(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x59,%al
  je     L20
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D53
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D68
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D43
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D52
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D26
type_guessed: string

tool: D8: Welcome to the String Scanner!

tool: D4: 

Please enter a string:

tool: D53: %s

tool: D68: 
The character at byte %d is: %c

tool: D43: 
Here you will be entering a string, and we will tell you the location of each character in the array!

tool: D52: 

That was fun! Type 'y' to do it again!

tool: D26:  %c

assistant: ```c
int main() {
  char userString[25];
  char userInput;
  int stringLength;
  printf("Welcome to the String Scanner!");
  printf("\nHere you will be entering a string, and we will tell you the location of each character in the array!");
  do {
    printf("\n\nPlease enter a string:");
    scanf("%s", userString);
    stringLength = strlen(userString);
    for (int counter = 0; counter < stringLength; counter++) {
      printf("\nThe character at byte %d is: %c", counter, userString[counter]);
    }
    printf("\n\nThat was fun! Type 'y' to do it again!");
    scanf(" %c", &userInput);
  } while (userInput == 'y' || userInput == 'Y');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r15
  lea    D1(%rip),%rdi
  lea    D11(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  push   %r12
  lea    D40(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%rbp
  call   <printf@plt>
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1f(%rsp),%rax
  mov    %rax,0x8(%rsp)
L22:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r14,%rdi
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  movslq %eax,%rbx
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L11:
  movsbl 0x0(%rbp,%r13,1),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r13
  call   <printf@plt>
  cmp    %rbx,%r13
  jne    L11
L9:
  lea    D38(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  movzbl 0x1f(%rsp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x59,%al
  je     L22
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
data_type: string
name: extract_symbolic_data
arguments: label: D11
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D40
data_type: string
name: extract_symbolic_data
arguments: label: D28
data_type: string
name: extract_symbolic_data
arguments: label: D38
data_type: string
name: extract_symbolic_data
arguments: label: D43
data_type: string

tool: D1: Welcome to the String Scanner!

tool: D11: 

Please enter a string:

tool: D15: %s

tool: D40: 
The character at byte %d is: %c

tool: D28: 
Here you will be entering a string, and we will tell you the location of each character in the array!

tool: D38: 

That was fun! Type 'y' to do it again!

tool: D43:  %c

assistant: ```c
int main() {
  char userString[25];
  char userInput;
  int stringLength;
  printf("Welcome to the String Scanner!");
  printf("\nHere you will be entering a string, and we will tell you the location of each character in the array!");
  do {
    printf("\n\nPlease enter a string:");
    scanf("%s", userString);
    stringLength = strlen(userString);
    for (int counter = 0; counter < stringLength; counter++) {
      printf("\nThe character at byte %d is: %c", counter, userString[counter]);
    }
    printf("\n\nThat was fun! Type 'y' to do it again!");
    scanf(" %c", &userInput);
  } while (userInput == 'y' || userInput == 'Y');
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  je     L13
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <__print_sw_title@plt>
  mov    $0xffffffff,%eax
  jmp    L11
L13:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <__print_str@plt>
  mov    $0x0,%eax
L11:
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    __print_sw_title(argv[0]);
    return -1;
  } else {
    __print_str(argv);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %rsi,%rdi
  cmp    $0x2,%eax
  jne    L2
  call   <__print_str@plt>
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  ret
L2:
  mov    (%rsi),%rdi
  call   <__print_sw_title@plt>
  mov    $0xffffffff,%eax
  jmp    L4
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    __print_sw_title(argv[0]);
    return -1;
  } else {
    __print_str(argv);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cmp    $0x2,%r8d
  jne    L13
  call   <__print_str@plt>
  xor    %eax,%eax
L9:
  add    $0x8,%rsp
  ret
L13:
  mov    (%rsi),%rdi
  call   <__print_sw_title@plt>
  or     $0xffffffff,%eax
  jmp    L9
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    __print_sw_title(argv[0]);
    return -1;
  } else {
    __print_str(argv);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cmp    $0x2,%r8d
  jne    L11
  call   <__print_str@plt>
  xor    %eax,%eax
L3:
  add    $0x8,%rsp
  ret
L11:
  mov    (%rsi),%rdi
  call   <__print_sw_title@plt>
  or     $0xffffffff,%eax
  jmp    L3
```

assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    __print_sw_title(argv[0]);
    return -1;
  } else {
    __print_str(argv);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lu_backsub>:
  endbr64
  test   %esi,%esi
  jle    L52
  push   %rbx
  mov    %rdi,%r8
  mov    %rdx,%r11
  mov    %rcx,%rdx
  mov    %esi,%ebx
  mov    $0x0,%ecx
  mov    $0xffffffff,%r10d
  pxor   %xmm3,%xmm3
  movapd %xmm3,%xmm2
  jmp    L39
L8:
  cmp    %ecx,%r10d
  jge    L139
  mov    (%r8,%rcx,8),%r9
  movslq %r10d,%rax
L42:
  movsd  (%r9,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  subsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L42
  jmp    L139
L14:
  mov    %edi,%r10d
L139:
  movsd  %xmm1,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rbx,%rcx
  je     L3
L39:
  mov    %ecx,%edi
  movslq (%r11,%rcx,4),%rax
  lea    (%rdx,%rax,8),%rax
  movsd  (%rax),%xmm1
  movsd  (%rdx,%rcx,8),%xmm0
  movsd  %xmm0,(%rax)
  test   %r10d,%r10d
  jns    L8
  ucomisd %xmm3,%xmm1
  jp     L14
  ucomisd %xmm2,%xmm1
  je     L139
  jmp    L14
L30:
  mov    %eax,%r9d
L74:
  movsd  (%rdx,%rdi,1),%xmm1
  cmp    %r9d,%esi
  jle    L95
  mov    (%r8,%rdi,1),%rcx
  movslq %r9d,%rax
L98:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  subsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %eax,%esi
  jg     L98
L95:
  mov    (%r8,%rdi,1),%rax
  divsd  (%rax,%rdi,1),%xmm1
  movsd  %xmm1,(%rdx,%rdi,1)
  lea    -0x1(%r9),%eax
  sub    $0x8,%rdi
  sub    $0x2,%r9d
  jns    L30
  pop    %rbx
  ret
L3:
  mov    %esi,%r9d
  lea    -0x1(%rsi),%edi
  movslq %edi,%rdi
  shl    $0x3,%rdi
  jmp    L74
L52:
  ret
```

assistant: ```c
void lu_backsub(double **a, int n, int *pivx, double *b) {
  int i, j;
  int nvi;
  for (nvi = -1, i = 0; i < n; i++) {
    int px;
    double sum;
    px = pivx[i];
    sum = b[px];
    b[px] = b[i];
    if (nvi >= 0) {
      for (j = nvi; j < i; j++)
        sum -= a[i][j] * b[j];
    } else {
      if (sum != 0.0)
        nvi = i;
    }
    b[i] = sum;
  }
  for (i = (n - 1); i >= 0; i--) {
    double sum;
    sum = b[i];
    for (j = i + 1; j < n; j++)
      sum -= a[i][j] * b[j];
    b[i] = sum / a[i][i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lu_backsub>:
  endbr64
  push   %rbp
  mov    %rdi,%r8
  lea    -0x1(%rsi),%edi
  push   %rbx
  mov    %rdx,%rbx
  mov    %rcx,%rdx
  test   %esi,%esi
  jle    L36
  movslq %esi,%rbp
  xor    %ecx,%ecx
  pxor   %xmm2,%xmm2
  mov    $0xffffffff,%r11d
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L39:
  ucomisd %xmm2,%xmm1
  jp     L119
  je     L107
L119:
  mov    %r9d,%r11d
L107:
  movsd  %xmm1,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  je     L45
L67:
  movslq (%rbx,%rcx,4),%rax
  movsd  (%rdx,%rcx,8),%xmm0
  mov    %ecx,%r9d
  lea    (%rdx,%rax,8),%rax
  movsd  (%rax),%xmm1
  movsd  %xmm0,(%rax)
  cmp    $0xffffffff,%r11d
  je     L39
  cmp    %ecx,%r11d
  jge    L107
  mov    (%r8,%rcx,8),%r10
  movslq %r11d,%rax
  nopl   0x0(%rax,%rax,1)
L66:
  movsd  (%r10,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  cmp    %eax,%r9d
  jg     L66
  movsd  %xmm1,(%rdx,%rcx,8)
  add    $0x1,%rcx
  cmp    %rcx,%rbp
  jne    L67
L45:
  movslq %edi,%rdi
  mov    %esi,%r9d
  shl    $0x3,%rdi
  nopl   0x0(%rax,%rax,1)
L34:
  movsd  (%rdx,%rdi,1),%xmm1
  mov    (%r8,%rdi,1),%rcx
  cmp    %r9d,%esi
  jle    L134
  movslq %r9d,%rax
  nopl   0x0(%rax)
L86:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  add    $0x1,%rax
  subsd  %xmm0,%xmm1
  cmp    %eax,%esi
  jg     L86
L134:
  divsd  (%rcx,%rdi,1),%xmm1
  lea    -0x1(%r9),%eax
  movsd  %xmm1,(%rdx,%rdi,1)
  sub    $0x8,%rdi
  sub    $0x2,%r9d
  js     L89
  mov    %eax,%r9d
  jmp    L34
L36:
  test   %edi,%edi
  jns    L45
L89:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lu_backsub(double **a, int n, int *pivx, double *b) {
  int i, j;
  int nvi;
  for (nvi = -1, i = 0; i < n; i++) {
    int px;
    double sum;
    px = pivx[i];
    sum = b[px];
    b[px] = b[i];
    if (nvi >= 0) {
      for (j = nvi; j < i; j++)
        sum -= a[i][j] * b[j];
    } else {
      if (sum != 0.0)
        nvi = i;
    }
    b[i] = sum;
  }
  for (i = (n - 1); i >= 0; i--) {
    double sum;
    sum = b[i];
    for (j = i + 1; j < n; j++)
      sum -= a[i][j] * b[j];
    b[i] = sum / a[i][i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xmpp_trim_ws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L14
L49:
  addq   $0x1,-0x18(%rbp)
L14:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L57
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L49
L57:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L7:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  subq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L7
L1:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *xmpp_trim_ws(char *src) {
  char *end;
  for (; *src && isspace(*src); src++) {
  }
  end = src + strlen(src);
  for (; *end && isspace(*end); end--)
    *end = 0;
  return src;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<xmpp_trim_ws>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L14
L17:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L14
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  jne    L17
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %rbp,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L51
L52:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L51
  movb   $0x0,(%rbx)
  sub    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L52
L51:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *xmpp_trim_ws(char *src) {
  char *end;
  for (; *src && isspace(*src); src++) {
  }
  end = src + strlen(src);
  for (; *end && isspace(*end); end--)
    *end = 0;
  return src;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xmpp_trim_ws>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L35
  jmp    L77
  nopl   0x0(%rax,%rax,1)
L24:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L77
L35:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L24
L77:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L21
  jmp    L28
  nopl   0x0(%rax)
L64:
  movb   $0x0,(%rbx)
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  test   %dil,%dil
  je     L28
L21:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L64
L28:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *xmpp_trim_ws(char *src) {
  char *end;
  for (; *src && isspace(*src); src++) {
  }
  end = src + strlen(src);
  for (; *end && isspace(*end); end--)
    *end = 0;
  return src;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xmpp_trim_ws>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L16
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L52:
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  test   %dil,%dil
  je     L23
L16:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L52
L23:
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %eax,%rbx
  add    %r12,%rbx
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L55
  jmp    L75
  nopl   0x0(%rax)
L36:
  movb   $0x0,(%rbx)
  movsbl -0x1(%rbx),%edi
  sub    $0x1,%rbx
  test   %dil,%dil
  je     L75
L55:
  call   <isspace@plt>
  test   %rax,%rax
  jne    L36
L75:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *xmpp_trim_ws(char *src) {
  char *end;
  for (; *src && isspace(*src); src++) {
  }
  end = src + strlen(src);
  for (; *end && isspace(*end); end--)
    *end = 0;
  return src;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<necro_sinc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  comisd D24(%rip),%xmm0
  jbe    L0
  movsd  D22(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L0
  movsd  D25(%rip),%xmm0
  jmp    L23
L0:
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  divsd  -0x8(%rbp),%xmm0
L23:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D24
type_guessed: byte[16]
name: parse_data
arguments: data_tag: D22
type_guessed: byte[8]
name: parse_data
arguments: data_tag: D25
type_guessed: f64

tool: {"D24": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0xbe,0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: {"D22": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: D25: 1

assistant: ```c
double necro_sinc(const double x) {
  if (x > -1.0E-5 && x < 1.0E-5)
    return (1.0);
  return sin(x) / x;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<necro_sinc>:
  endbr64
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  comisd D17(%rip),%xmm0
  jbe    L2
  movapd %xmm0,%xmm2
  movsd  D1(%rip),%xmm0
  movsd  D27(%rip),%xmm1
  comisd %xmm2,%xmm1
  ja     L8
L2:
  movsd  0x8(%rsp),%xmm0
  call   <sin@plt>
  divsd  0x8(%rsp),%xmm0
L8:
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D17
type: byte[16]
name: disassemble_data
arguments: label: D1
type: f64
name: disassemble_data
arguments: label: D27
type: byte[8]

tool: {"D17": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0xbe,0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: D1: 1

tool: {"D27": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

assistant: ```c
double necro_sinc(const double x) {
  if (x > -1.0E-5 && x < 1.0E-5)
    return (1.0);
  return sin(x) / x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<necro_sinc>:
  endbr64
  comisd D14(%rip),%xmm0
  movapd %xmm0,%xmm1
  jbe    L17
  movsd  D22(%rip),%xmm2
  movsd  D5(%rip),%xmm0
  comisd %xmm1,%xmm2
  ja     L2
L17:
  sub    $0x18,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
```

tool_calls: name: parse_data
arguments: tag: D14
type: byte[16]
name: parse_data
arguments: tag: D22
type: byte[8]
name: parse_data
arguments: tag: D5
type: f64

tool: {"D14": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0xbe,0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: {"D22": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: D5: 1

assistant: ```c
double necro_sinc(const double x) {
  if (x > -1.0E-5 && x < 1.0E-5)
    return (1.0);
  return sin(x) / x;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<necro_sinc>:
  endbr64
  comisd D20(%rip),%xmm0
  movapd %xmm0,%xmm1
  jbe    L0
  movsd  D12(%rip),%xmm2
  movsd  D0(%rip),%xmm0
  comisd %xmm1,%xmm2
  ja     L11
L0:
  sub    $0x18,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <sin@plt>
  movsd  0x8(%rsp),%xmm1
  add    $0x18,%rsp
  divsd  %xmm1,%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D20
datatype: byte[16]
name: retrieve_data
arguments: label: D12
datatype: byte[8]
name: retrieve_data
arguments: label: D0
datatype: f64

tool: {"D20": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0xbe,0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: {"D12": [0xf1,0x68,0xe3,0x88,0xb5,0xf8,0xe4,0x3e]}

tool: D0: 1

assistant: ```c
double necro_sinc(const double x) {
  if (x > -1.0E-5 && x < 1.0E-5)
    return (1.0);
  return sin(x) / x;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<calc_s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L21
  movsd  D14(%rip),%xmm0
  jmp    L9
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jne    L12
  movsd  D3(%rip),%xmm0
  jmp    L9
L12:
  pxor   %xmm0,%xmm0
L9:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_infered: f64
name: extract_symbolic_data
arguments: label: D3
type_infered: f64

tool: D14: 1

tool: D3: 0.5

assistant: ```c
double calc_s(int rank_i, int rank_j) {
  if (rank_i < rank_j) {
    return 1.0;
  } else if (rank_i == rank_j) {
    return 0.5;
  } else {
    return 0.0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<calc_s>:
  endbr64
  movsd  D10(%rip),%xmm0
  cmp    %esi,%edi
  jl     L14
  movsd  D0(%rip),%xmm0
  je     L14
  pxor   %xmm0,%xmm0
L14:
  ret
```

tool_calls: name: read_data
arguments: tag: D10
type: f64
name: read_data
arguments: tag: D0
type: f64

tool: D10: 1

tool: D0: 0.5

assistant: ```c
double calc_s(int rank_i, int rank_j) {
  if (rank_i < rank_j) {
    return 1.0;
  } else if (rank_i == rank_j) {
    return 0.5;
  } else {
    return 0.0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<calc_s>:
  endbr64
  movsd  D8(%rip),%xmm0
  cmp    %esi,%edi
  jl     L1
  movsd  D22(%rip),%xmm0
  movq   %xmm0,%rax
  cmovne D9(%rip),%rax
  movq   %rax,%xmm0
L1:
  ret
```

tool_calls: name: read_data
arguments: label: D8
datatype: f64
name: read_data
arguments: label: D22
datatype: f64
name: read_data
arguments: label: D9
datatype: f64

tool: D8: 1

tool: D22: 0.5

tool: D9: 0

assistant: ```c
double calc_s(int rank_i, int rank_j) {
  if (rank_i < rank_j) {
    return 1.0;
  } else if (rank_i == rank_j) {
    return 0.5;
  } else {
    return 0.0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<calc_s>:
  endbr64
  movsd  D2(%rip),%xmm0
  cmp    %esi,%edi
  jl     L8
  movsd  D15(%rip),%xmm0
  movq   %xmm0,%rax
  cmovne D8(%rip),%rax
  movq   %rax,%xmm0
L8:
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: f64
name: read_data
arguments: label: D15
type: f64
name: read_data
arguments: label: D8
type: f64

tool: D2: 1

tool: D15: 0.5

tool: D8: 0

assistant: ```c
double calc_s(int rank_i, int rank_j) {
  if (rank_i < rank_j) {
    return 1.0;
  } else if (rank_i == rank_j) {
    return 0.5;
  } else {
    return 0.0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chomp_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L29
L1:
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L29:
  cmpl   $0x0,-0x4(%rbp)
  js     L10
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L1
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L1
L10:
  nop
  leave
  ret
```

assistant: ```c
void chomp_string(char *str) {
  int last_index = (int)strlen(str) - 1;
  while (last_index >= 0 && (str[last_index] == '\n' || str[last_index] == '\r')) {
    str[last_index--] = '\0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<chomp_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  sub    $0x1,%edx
  js     L37
  movslq %edx,%rdx
  add    %rbx,%rdx
  movslq %eax,%rcx
  lea    -0x2(%rbx,%rcx,1),%rsi
  lea    -0x1(%rax),%eax
  sub    %rax,%rsi
  jmp    L14
L9:
  movb   $0x0,(%rcx)
  sub    $0x1,%rdx
  cmp    %rsi,%rdx
  je     L37
L14:
  mov    %rdx,%rcx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L9
  cmp    $0xd,%al
  je     L9
L37:
  pop    %rbx
  ret
```

assistant: ```c
void chomp_string(char *str) {
  int last_index = (int)strlen(str) - 1;
  while (last_index >= 0 && (str[last_index] == '\n' || str[last_index] == '\r')) {
    str[last_index--] = '\0';
  }
}
```