ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x48,%rsp
  lea    D3(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%r8d
  test   %r8d,%r8d
  jle    L19
  mov    %r8d,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L37:
  mov    %eax,%ecx
  add    $0x1,%eax
  sar    %edx
  jne    L37
  mov    %r8d,%esi
  movslq %ecx,%rdx
  and    $0x1,%esi
  mov    %esi,0x10(%rsp,%rdx,4)
  mov    %r8d,%edx
  sar    %edx
  test   %ecx,%ecx
  je     L16
  lea    -0x1(%rcx),%esi
  and    $0x1,%edx
  movslq %esi,%rdi
  mov    %edx,0x10(%rsp,%rdi,4)
  mov    %r8d,%edx
  sar    $0x2,%edx
  test   %esi,%esi
  je     L16
  lea    -0x2(%rcx),%esi
  and    $0x1,%edx
  movslq %esi,%rdi
  mov    %edx,0x10(%rsp,%rdi,4)
  mov    %r8d,%edx
  sar    $0x3,%edx
  test   %esi,%esi
  je     L16
  lea    -0x3(%rcx),%esi
  and    $0x1,%edx
  movslq %esi,%rdi
  mov    %edx,0x10(%rsp,%rdi,4)
  mov    %r8d,%edx
  sar    $0x4,%edx
  test   %esi,%esi
  je     L16
  lea    -0x4(%rcx),%esi
  and    $0x1,%edx
  movslq %esi,%rdi
  mov    %edx,0x10(%rsp,%rdi,4)
  mov    %r8d,%edx
  sar    $0x5,%edx
  test   %esi,%esi
  je     L16
  lea    -0x5(%rcx),%esi
  and    $0x1,%edx
  movslq %esi,%rdi
  mov    %edx,0x10(%rsp,%rdi,4)
  mov    %r8d,%edx
  sar    $0x6,%edx
  test   %esi,%esi
  je     L16
  sub    $0x6,%ecx
  and    $0x1,%edx
  movslq %ecx,%rcx
  mov    %edx,0x10(%rsp,%rcx,4)
  mov    %r8d,%edx
  sar    $0x7,%edx
L16:
  mov    %edx,0xc(%rsp)
L61:
  sub    0x8(%rsp),%eax
  lea    D6(%rip),%rdi
  sub    $0x1,%eax
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  xor    %eax,%eax
  add    $0x48,%rsp
  ret
L19:
  xor    %eax,%eax
  jmp    L61
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
type: string
name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D3: %d %d

tool: D6: %d

assistant: ```c
int main() {
  int a, b, i, j = 0, c, m[7];
  scanf("%d %d", &a, &b);
  c = b;
  for (j = 0; c > 0; j++)
    c = c / 2;
  for (i = j; i > 0; i--) {
    m[i - 1] = b % 2;
    b = b / 2;
  }
  i = j - a - 1;
  printf("%d", m[i]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mulhi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mul    %edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int mulhi(int a, int b) {
  asm("mul %%edx   # %%1 was %1" : "+d"(a), "+a"(b));
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mulhi>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  mul    %edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int mulhi(int a, int b) {
  asm("mul %%edx   # %%1 was %1" : "+d"(a), "+a"(b));
  return a;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mulhi>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  mul    %edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int mulhi(int a, int b) {
  asm("mul %%edx   # %%1 was %1" : "+d"(a), "+a"(b));
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mulhi>:
  endbr64
  mov    %edi,%edx
  mov    %esi,%eax
  mul    %edx
  mov    %edx,%eax
  ret
```

assistant: ```c
int mulhi(int a, int b) {
  asm("mul %%edx   # %%1 was %1" : "+d"(a), "+a"(b));
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<validate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  jmp    L27
L2:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x1c(%rbp)
  jae    L27
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jbe    L27
  mov    -0xc(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jae    L17
  mov    -0xc(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <validate>
L17:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %ecx,%eax
  cmp    %eax,%edx
  jbe    L52
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    -0x10(%rbp),%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x10(%rbp),%eax
  add    %eax,%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <validate>
  jmp    L50
L27:
  lea    -0x10(%rbp),%rdx
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <rangeitem@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  lea    D4(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <error@plt>
  jmp    L50
L52:
  nop
L50:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: Cannot map onto IDs that are not delegated to you

assistant: ```c
void validate(char *range, unsigned first, unsigned count) {
  unsigned length, start;
  while ((range = rangeitem(range, &start, &length)))
    if (first < start + length && start < first + count) {
      if (first < start)
        validate(range, first, start - first);
      if (first + count > start + length)
        validate(range, start + length, first + count - start - length);
      return;
    }
  error(1, 0, "Cannot map onto IDs that are not delegated to you");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<validate>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r14d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
L42:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <rangeitem@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L51
  mov    0x4(%rsp),%edx
  mov    %edx,%eax
  add    (%rsp),%eax
  cmp    %ebp,%eax
  jbe    L42
  lea    0x0(%rbp,%r14,1),%r13d
  cmp    %r13d,%edx
  jae    L42
  cmp    %ebp,%edx
  ja     L39
L37:
  mov    (%rsp),%esi
  add    0x4(%rsp),%esi
  cmp    %esi,%r13d
  jbe    L67
  mov    %r13d,%edx
  sub    %esi,%edx
  mov    %rbx,%rdi
  call   <validate>
  jmp    L67
L39:
  sub    %ebp,%edx
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <validate>
  jmp    L37
L51:
  lea    D6(%rip),%rdx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <error@plt>
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D6
data_type: string

tool: D6: Cannot map onto IDs that are not delegated to you

assistant: ```c
void validate(char *range, unsigned first, unsigned count) {
  unsigned length, start;
  while ((range = rangeitem(range, &start, &length)))
    if (first < start + length && start < first + count) {
      if (first < start)
        validate(range, first, start - first);
      if (first + count > start + length)
        validate(range, start + length, first + count - start - length);
      return;
    }
  error(1, 0, "Cannot map onto IDs that are not delegated to you");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<validate>:
  endbr64
  push   %r13
  lea    (%rsi,%rdx,1),%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rbx
  xchg   %ax,%ax
L79:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <rangeitem@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L38
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  add    %edx,%esi
  cmp    %ebp,%esi
  jbe    L79
  cmp    %r13d,%edx
  jae    L79
  cmp    %ebp,%edx
  ja     L45
L13:
  cmp    %esi,%r13d
  jbe    L73
  mov    %r13d,%edx
  sub    %esi,%edx
  call   <validate>
  jmp    L73
  nopl   0x0(%rax,%rax,1)
L38:
  lea    D7(%rip),%rdx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <error@plt>
L73:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L45:
  mov    %ebp,%esi
  sub    %ebp,%edx
  mov    %rdi,0x8(%rsp)
  call   <validate>
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%rdi
  add    0x14(%rsp),%esi
  jmp    L13
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: Cannot map onto IDs that are not delegated to you

assistant: ```c
void validate(char *range, unsigned first, unsigned count) {
  unsigned length, start;
  while ((range = rangeitem(range, &start, &length)))
    if (first < start + length && start < first + count) {
      if (first < start)
        validate(range, first, start - first);
      if (first + count > start + length)
        validate(range, start + length, first + count - start - length);
      return;
    }
  error(1, 0, "Cannot map onto IDs that are not delegated to you");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<validate>:
  endbr64
  push   %r13
  lea    (%rsi,%rdx,1),%r13d
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x14(%rsp),%rbx
  xchg   %ax,%ax
L47:
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <rangeitem@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L2
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  add    %edx,%esi
  cmp    %ebp,%esi
  jbe    L47
  cmp    %r13d,%edx
  jae    L47
  cmp    %ebp,%edx
  ja     L10
L44:
  cmp    %esi,%r13d
  jbe    L62
  mov    %r13d,%edx
  sub    %esi,%edx
  call   <validate>
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L2:
  lea    D2(%rip),%rdx
  xor    %esi,%esi
  mov    $0x1,%edi
  call   <error@plt>
L62:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  mov    %ebp,%esi
  sub    %ebp,%edx
  mov    %rdi,0x8(%rsp)
  call   <validate>
  mov    0x10(%rsp),%esi
  mov    0x8(%rsp),%rdi
  add    0x14(%rsp),%esi
  jmp    L44
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
datatype: string

tool: D2: Cannot map onto IDs that are not delegated to you

assistant: ```c
void validate(char *range, unsigned first, unsigned count) {
  unsigned length, start;
  while ((range = rangeitem(range, &start, &length)))
    if (first < start + length && start < first + count) {
      if (first < start)
        validate(range, first, start - first);
      if (first + count > start + length)
        validate(range, start + length, first + count - start - length);
      return;
    }
  error(1, 0, "Cannot map onto IDs that are not delegated to you");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floyd_parallel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L56:
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L17:
  movl   $0x0,-0x8(%rbp)
  jmp    L1
L10:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  add    %eax,%ecx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rsi
  mov    %rsi,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  lea    0x0(,%rax,4),%rsi
  add    %rsi,%rax
  shl    $0x4,%rax
  mov    %rax,%rsi
  mov    -0x18(%rbp),%rax
  add    %rax,%rsi
  cmp    %edx,%ecx
  cmovle %ecx,%edx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %edx,(%rsi,%rax,4)
  addl   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L17
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L56
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void floyd_parallel(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++) {
#pragma omp parallel for shared(arr)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = ((arr[i][j] < arr[i][k] + arr[k][j]) ? (arr[i][j]) : (arr[i][k] + arr[k][j]));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<floyd_parallel>:
  endbr64
  test   %esi,%esi
  jle    L26
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    -0x1(%rsi),%eax
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  shl    $0x4,%rax
  lea    0x190(%rdi,%rax,1),%r11
  mov    %esi,%r9d
  mov    %r9,%r12
  neg    %r12
  shl    $0x2,%r12
  mov    %rdi,%rbp
  mov    $0x0,%r10d
L22:
  mov    %rbp,%r8
  mov    %rbx,%rdi
  sub    %r10,%rdi
L32:
  lea    (%rdi,%r10,1),%rsi
  mov    $0x0,%edx
L38:
  mov    (%r8,%rdx,4),%eax
  add    (%rdi),%eax
  mov    (%rsi,%rdx,4),%ecx
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    %r9,%rdx
  jne    L38
  add    $0x190,%rdi
  cmp    %r11,%rdi
  jne    L32
  add    $0x4,%r11
  add    $0x190,%rbp
  sub    $0x4,%r10
  cmp    %r12,%r10
  jne    L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  ret
```

assistant: ```c
void floyd_parallel(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++) {
#pragma omp parallel for shared(arr)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = ((arr[i][j] < arr[i][k] + arr[k][j]) ? (arr[i][j]) : (arr[i][k] + arr[k][j]));
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<floyd_parallel>:
  endbr64
  mov    %esi,%r9d
  test   %r9d,%r9d
  jle    L18
  lea    -0x1(%r9),%eax
  push   %rbp
  mov    %r9,%rbp
  mov    %rdi,%r8
  lea    (%rax,%rax,4),%rax
  neg    %rbp
  push   %rbx
  xor    %r10d,%r10d
  lea    (%rax,%rax,4),%rax
  mov    %rdi,%rbx
  shl    $0x2,%rbp
  shl    $0x4,%rax
  lea    0x190(%rdi,%rax,1),%r11
  nopl   (%rax)
L7:
  mov    %rbx,%rdi
  sub    %r10,%rdi
  cs nopw 0x0(%rax,%rax,1)
L32:
  lea    (%rdi,%r10,1),%rsi
  xor    %edx,%edx
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    (%rsi,%rdx,4),%ecx
  mov    (%r8,%rdx,4),%eax
  add    (%rdi),%eax
  cmp    %ecx,%eax
  cmovg  %ecx,%eax
  mov    %eax,(%rsi,%rdx,4)
  add    $0x1,%rdx
  cmp    %r9,%rdx
  jne    L26
  add    $0x190,%rdi
  cmp    %rdi,%r11
  jne    L32
  sub    $0x4,%r10
  add    $0x4,%r11
  add    $0x190,%r8
  cmp    %rbp,%r10
  jne    L7
  pop    %rbx
  pop    %rbp
  ret
L18:
  ret
```

assistant: ```c
void floyd_parallel(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++) {
#pragma omp parallel for shared(arr)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = ((arr[i][j] < arr[i][k] + arr[k][j]) ? (arr[i][j]) : (arr[i][k] + arr[k][j]));
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<floyd_parallel>:
  endbr64
  test   %esi,%esi
  jle    L92
  push   %r15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r9
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  mov    %eax,-0x28(%rsp)
  lea    (%r12,%r12,4),%rax
  movq   $0x0,-0x10(%rsp)
  lea    (%rax,%rax,4),%rax
  movq   $0x0,-0x18(%rsp)
  shl    $0x4,%rax
  mov    %rax,-0x38(%rsp)
  movslq %esi,%rax
  shl    $0x2,%rax
  mov    %rax,-0x30(%rsp)
  mov    %esi,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%r11d
  mov    %esi,%eax
  and    $0xfffffffc,%eax
  add    $0x1,%r11
  lea    0x1(%rax),%esi
  lea    0x2(%rax),%ecx
  mov    %eax,-0x24(%rsp)
  shl    $0x4,%r11
  mov    %esi,-0x20(%rsp)
  movslq %eax,%rbp
  movslq %esi,%r13
  movslq %ecx,%r14
  mov    %ecx,-0x1c(%rsp)
  nopl   (%rax)
L53:
  mov    -0x18(%rsp),%rax
  xor    %r8d,%r8d
  lea    0x0(,%rax,4),%rsi
  mov    -0x10(%rsp),%rax
  lea    -0x4(%rax),%r15
  nopl   0x0(%rax)
L49:
  lea    (%r15,%rsi,1),%rdx
  lea    (%r9,%r8,1),%rax
  cmp    $0x8,%rdx
  seta   %cl
  cmpl   $0x2,-0x28(%rsp)
  seta   %dl
  test   %dl,%cl
  je     L18
  mov    -0x30(%rsp),%rcx
  lea    (%r8,%rcx,1),%rdx
  cmp    %rdx,%rsi
  lea    0x4(%rsi),%rdx
  setge  %cl
  cmp    %r8,%rdx
  setle  %dl
  or     %cl,%dl
  je     L18
  movd   (%r9,%rsi,1),%xmm5
  xor    %edx,%edx
  pshufd $0x0,%xmm5,%xmm3
  nopl   (%rax)
L84:
  movdqu (%rdi,%rdx,1),%xmm2
  movdqu (%rax,%rdx,1),%xmm4
  paddd  %xmm3,%xmm2
  movdqa %xmm4,%xmm1
  movdqa %xmm2,%xmm0
  pcmpgtd %xmm4,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r11,%rdx
  jne    L84
  cmp    %ebx,-0x24(%rsp)
  je     L25
  mov    (%rax,%rbp,4),%ecx
  mov    (%rdi,%rbp,4),%edx
  add    (%r9,%rsi,1),%edx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  mov    %edx,(%rax,%rbp,4)
  cmp    -0x20(%rsp),%ebx
  jle    L25
  mov    (%rax,%r13,4),%ecx
  mov    (%rdi,%r13,4),%edx
  add    (%r9,%rsi,1),%edx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x1c(%rsp),%ebx
  jle    L25
  mov    (%rax,%r14,4),%ecx
  mov    (%rdi,%r14,4),%edx
  add    (%r9,%rsi,1),%edx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  mov    %edx,(%rax,%r14,4)
L25:
  add    $0x190,%r8
  add    $0x190,%rsi
  cmp    -0x38(%rsp),%r8
  jne    L49
  addq   $0x1,-0x18(%rsp)
  mov    -0x18(%rsp),%rax
  add    $0x190,%rdi
  subq   $0x194,-0x10(%rsp)
  cmp    %r12,%rax
  jne    L53
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L18:
  xor    %ecx,%ecx
  nopw   0x0(%rax,%rax,1)
L60:
  mov    (%rax,%rcx,4),%r10d
  mov    (%rdi,%rcx,4),%edx
  add    (%r9,%rsi,1),%edx
  cmp    %r10d,%edx
  cmovg  %r10d,%edx
  mov    %edx,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %r12,%rcx
  jne    L60
  jmp    L25
L92:
  ret
```

assistant: ```c
void floyd_parallel(int arr[100][100], int N) {
  int i, j, k;
  for (k = 0; k < N; k++) {
#pragma omp parallel for shared(arr)
    for (i = 0; i < N; i++)
      for (j = 0; j < N; j++)
        arr[i][j] = ((arr[i][j] < arr[i][k] + arr[k][j]) ? (arr[i][j]) : (arr[i][k] + arr[k][j]));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L4
L28:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L4:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L5
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L28
L5:
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
type_guessed: string

tool: D9: 


assistant: ```c
void chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && strchr("\r\n", *p))
    *(p--) = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chomp>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  lea    D3(%rip),%r12
  cmp    %rbx,%rbp
  ja     L14
L29:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L14
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  jbe    L29
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: 


assistant: ```c
void chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && strchr("\r\n", *p))
    *(p--) = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<chomp>:
  endbr64
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jbe    L17
  jmp    L1
  nopl   (%rax)
L38:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  ja     L1
L17:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L38
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string

tool: D3: 


assistant: ```c
void chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && strchr("\r\n", *p))
    *(p--) = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<chomp>:
  endbr64
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jbe    L7
  jmp    L3
  nopl   (%rax)
L37:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  ja     L3
L7:
  movsbl (%rbx),%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  jne    L37
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
datatype: string

tool: D4: 


assistant: ```c
void chomp(char *str) {
  char *p;
  p = str + strlen(str) - 1;
  while (p >= str && strchr("\r\n", *p))
    *(p--) = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_timeout>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
struct timespec get_timeout() {
  struct timespec t;
  clock_gettime(CLOCK_REALTIME, &t);
  t.tv_sec++;
  return t;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_timeout>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec get_timeout() {
  struct timespec t;
  clock_gettime(CLOCK_REALTIME, &t);
  t.tv_sec++;
  return t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_timeout>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  addl   $0x1,0x4(%rsp)
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
struct timespec get_timeout() {
  struct timespec t;
  clock_gettime(CLOCK_REALTIME, &t);
  t.tv_sec++;
  return t;
}
```