ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stretching>:
  endbr64
  sub    $0x18,%rsp
  movsd  D6(%rip),%xmm1
  movapd %xmm0,%xmm2
  mov    $0x3,%edi
  addsd  %xmm0,%xmm2
  mulsd  %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  addsd  %xmm2,%xmm1
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  addsd  %xmm0,%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x08,0xc0]}

assistant: ```c
double stretching(double x) {
  double alpha = 2.0;
  double beta = 2.0;
  return alpha * x + (3 - 2 * alpha - beta) * x * x + (alpha - 2 + beta) * pow(x, 3.);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<smack_set_label_for_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <smack_label_length@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L9
  mov    $0xfffffffe,%eax
  jmp    L12
L9:
  mov    -0x4(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%r8d
  mov    %eax,%edi
  call   <fsetxattr@plt>
L12:
  leave
  ret
```

assistant: ```c
int smack_set_label_for_file(int fd, const char *xattr, const char *label) {
  int len;
  len = (int)smack_label_length(label);
  if (len < 0)
    return -2;
  return fsetxattr(fd, xattr, label, len, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<smack_set_label_for_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rdx,%rdi
  call   <smack_label_length@plt>
  test   %eax,%eax
  js     L11
  mov    %eax,%ecx
  mov    $0x0,%r8d
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <fsetxattr@plt>
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    $0xfffffffe,%eax
  jmp    L13
```

assistant: ```c
int smack_set_label_for_file(int fd, const char *xattr, const char *label) {
  int len;
  len = (int)smack_label_length(label);
  if (len < 0)
    return -2;
  return fsetxattr(fd, xattr, label, len, 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<smack_set_label_for_file>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  call   <smack_label_length@plt>
  test   %eax,%eax
  js     L4
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %eax,%ecx
  pop    %rbp
  xor    %r8d,%r8d
  pop    %r12
  pop    %r13
  jmp    1060 <fsetxattr@plt>
  nopl   0x0(%rax)
L4:
  pop    %rbp
  mov    $0xfffffffe,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int smack_set_label_for_file(int fd, const char *xattr, const char *label) {
  int len;
  len = (int)smack_label_length(label);
  if (len < 0)
    return -2;
  return fsetxattr(fd, xattr, label, len, 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<smack_set_label_for_file>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  call   <smack_label_length@plt>
  test   %eax,%eax
  js     L9
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %ebp,%edi
  mov    %eax,%ecx
  pop    %rbp
  xor    %r8d,%r8d
  pop    %r12
  pop    %r13
  jmp    1060 <fsetxattr@plt>
  nopl   0x0(%rax)
L9:
  pop    %rbp
  mov    $0xfffffffe,%eax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int smack_set_label_for_file(int fd, const char *xattr, const char *label) {
  int len;
  len = (int)smack_label_length(label);
  if (len < 0)
    return -2;
  return fsetxattr(fd, xattr, label, len, 0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nmea_checksum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L62
  mov    $0x1,%eax
  jmp    L20
L62:
  cmpq   $0x0,-0x20(%rbp)
  jne    L98
  mov    $0x1,%eax
  jmp    L20
L98:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <find_nmea_start@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L72
  mov    $0x1,%eax
  jmp    L20
L72:
  addq   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L99
L111:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  xor    %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x8(%rbp)
L99:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L55
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L55
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x21,%al
  je     L55
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x24,%al
  jne    L111
L55:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  je     L103
  mov    $0x1,%eax
  jmp    L20
L103:
  mov    $0x0,%eax
L20:
  leave
  ret
```

assistant: ```c
unsigned int nmea_checksum(char *buffer, unsigned char *checksum) {
  char *p;
  if (!buffer)
    return 1;
  if (!checksum)
    return 1;
  p = find_nmea_start(buffer);
  if (p == NULL)
    return 1;
  p++;
  *checksum = 0;
  while ((*p != 0) && (*p != '*') && !((*p == '!') || (*p == '$'))) {
    *checksum ^= *p;
    p++;
  }
  if (*p != '*')
    return 1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nmea_checksum>:
  endbr64
  test   %rsi,%rsi
  je     L21
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%eax
  test   %rdi,%rdi
  je     L45
  call   <find_nmea_start@plt>
  test   %rax,%rax
  je     L5
  lea    0x1(%rax),%rdx
  movb   $0x0,(%rbx)
  movzbl 0x1(%rax),%eax
  test   %al,%al
  je     L40
  cmp    $0x2a,%al
  je     L40
L41:
  cmp    $0x21,%al
  je     L40
  cmp    $0x24,%al
  je     L40
  xor    %al,(%rbx)
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L40
  cmp    $0x2a,%al
  jne    L41
L40:
  cmp    $0x2a,%al
  setne  %al
  movzbl %al,%eax
L45:
  pop    %rbx
  ret
L5:
  mov    $0x1,%eax
  jmp    L45
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int nmea_checksum(char *buffer, unsigned char *checksum) {
  char *p;
  if (!buffer)
    return 1;
  if (!checksum)
    return 1;
  p = find_nmea_start(buffer);
  if (p == NULL)
    return 1;
  p++;
  *checksum = 0;
  while ((*p != 0) && (*p != '*') && !((*p == '!') || (*p == '$'))) {
    *checksum ^= *p;
    p++;
  }
  if (*p != '*')
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nmea_checksum>:
  endbr64
  test   %rsi,%rsi
  je     L64
  test   %rdi,%rdi
  je     L64
  push   %rbx
  mov    %rsi,%rbx
  call   <find_nmea_start@plt>
  test   %rax,%rax
  je     L75
  movb   $0x0,(%rbx)
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rcx
  cmp    $0x2a,%dl
  setne  %sil
  test   %dl,%dl
  setne  %al
  and    %sil,%al
  jne    L76
  jmp    L74
  xchg   %ax,%ax
L79:
  cmp    $0x24,%dl
  je     L15
  add    $0x1,%rcx
  xor    %dl,(%rbx)
  movzbl (%rcx),%edx
  cmp    $0x2a,%dl
  setne  %sil
  test   %dl,%dl
  je     L74
  test   %sil,%sil
  je     L74
L76:
  cmp    $0x21,%dl
  jne    L79
L15:
  movzbl %al,%eax
L85:
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L74:
  mov    %esi,%eax
  movzbl %al,%eax
  jmp    L85
  nopw   0x0(%rax,%rax,1)
L64:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int nmea_checksum(char *buffer, unsigned char *checksum) {
  char *p;
  if (!buffer)
    return 1;
  if (!checksum)
    return 1;
  p = find_nmea_start(buffer);
  if (p == NULL)
    return 1;
  p++;
  *checksum = 0;
  while ((*p != 0) && (*p != '*') && !((*p == '!') || (*p == '$'))) {
    *checksum ^= *p;
    p++;
  }
  if (*p != '*')
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<nmea_checksum>:
  endbr64
  test   %rsi,%rsi
  je     L89
  test   %rdi,%rdi
  je     L89
  push   %rbx
  mov    %rsi,%rbx
  call   <find_nmea_start@plt>
  test   %rax,%rax
  je     L23
  movb   $0x0,(%rbx)
  movzbl 0x1(%rax),%edx
  lea    0x1(%rax),%rdi
  cmp    $0x2a,%dl
  setne  %sil
  test   %dl,%dl
  setne  %al
  xor    %ecx,%ecx
  and    %sil,%al
  jne    L8
  jmp    L20
L61:
  cmp    $0x24,%dl
  je     L94
  xor    %edx,%ecx
  add    $0x1,%rdi
  mov    %cl,(%rbx)
  movzbl (%rdi),%edx
  cmp    $0x2a,%dl
  setne  %sil
  test   %dl,%dl
  je     L20
  test   %sil,%sil
  je     L20
L8:
  cmp    $0x21,%dl
  jne    L61
L94:
  movzbl %al,%eax
L48:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %esi,%eax
  movzbl %al,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L89:
  mov    $0x1,%eax
  ret
```

assistant: ```c
unsigned int nmea_checksum(char *buffer, unsigned char *checksum) {
  char *p;
  if (!buffer)
    return 1;
  if (!checksum)
    return 1;
  p = find_nmea_start(buffer);
  if (p == NULL)
    return 1;
  p++;
  *checksum = 0;
  while ((*p != 0) && (*p != '*') && !((*p == '!') || (*p == '$'))) {
    *checksum ^= *p;
    p++;
  }
  if (*p != '*')
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<timespec_before>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jge    L49
  mov    $0x1,%eax
  jmp    L7
L49:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L45
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%rax
  cmp    %rax,%rdx
  jge    L45
  mov    $0x1,%eax
  jmp    L7
L45:
  mov    $0x0,%eax
L7:
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((always_)) timespec_before(const struct timespec *__restrict t1, const struct timespec *__restrict t2) {
  if (t1->tv_sec < t2->tv_sec)
    return 1;
  if (t1->tv_sec == t2->tv_sec && t1->tv_nsec < t2->tv_nsec)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timespec_before>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,%rcx
  jl     L7
  mov    $0x0,%eax
  je     L24
L7:
  ret
L24:
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  setl   %al
  movzbl %al,%eax
  jmp    L7
```

assistant: ```c
int __attribute__((always_)) timespec_before(const struct timespec *__restrict t1, const struct timespec *__restrict t2) {
  if (t1->tv_sec < t2->tv_sec)
    return 1;
  if (t1->tv_sec == t2->tv_sec && t1->tv_nsec < t2->tv_nsec)
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timespec_before>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jl     L9
  mov    $0x0,%eax
  je     L7
L9:
  ret
  nopl   0x0(%rax)
L7:
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int __attribute__((always_)) timespec_before(const struct timespec *__restrict t1, const struct timespec *__restrict t2) {
  if (t1->tv_sec < t2->tv_sec)
    return 1;
  if (t1->tv_sec == t2->tv_sec && t1->tv_nsec < t2->tv_nsec)
    return 1;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<timespec_before>:
  endbr64
  mov    (%rsi),%rdx
  mov    $0x1,%eax
  cmp    %rdx,(%rdi)
  jl     L8
  mov    $0x0,%eax
  je     L16
L8:
  ret
  nopl   0x0(%rax)
L16:
  mov    0x8(%rsi),%rax
  cmp    %rax,0x8(%rdi)
  setl   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int __attribute__((always_)) timespec_before(const struct timespec *__restrict t1, const struct timespec *__restrict t2) {
  if (t1->tv_sec < t2->tv_sec)
    return 1;
  if (t1->tv_sec == t2->tv_sec && t1->tv_nsec < t2->tv_nsec)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<genrand_res53_mix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gen_rand32@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <gen_rand32@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <to_res53_mix@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double genrand_res53_mix(struct sfmt_state_t *s) {
  uint32_t x, y;
  x = gen_rand32(s);
  y = gen_rand32(s);
  return to_res53_mix(x, y);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<genrand_res53_mix>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <gen_rand32@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <gen_rand32@plt>
  mov    %eax,%esi
  mov    %ebp,%edi
  call   <to_res53_mix@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
double genrand_res53_mix(struct sfmt_state_t *s) {
  uint32_t x, y;
  x = gen_rand32(s);
  y = gen_rand32(s);
  return to_res53_mix(x, y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<genrand_res53_mix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <gen_rand32@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <gen_rand32@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1070 <to_res53_mix@plt>
```

assistant: ```c
double genrand_res53_mix(struct sfmt_state_t *s) {
  uint32_t x, y;
  x = gen_rand32(s);
  y = gen_rand32(s);
  return to_res53_mix(x, y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<genrand_res53_mix>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <gen_rand32@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <gen_rand32@plt>
  add    $0x8,%rsp
  mov    %r12d,%edi
  pop    %rbp
  mov    %eax,%esi
  pop    %r12
  jmp    1070 <to_res53_mix@plt>
```

assistant: ```c
double genrand_res53_mix(struct sfmt_state_t *s) {
  uint32_t x, y;
  x = gen_rand32(s);
  y = gen_rand32(s);
  return to_res53_mix(x, y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  addl   $0x1,-0x34(%rbp)
  subl   $0x2,-0x2c(%rbp)
  subl   $0x1,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L4
L23:
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%esi
  mov    -0x14(%rbp),%eax
  cltd
  idiv   %esi
  mov    %eax,%ecx
  movslq %ecx,%rax
  mov    -0x10(%rbp,%rax,4),%eax
  lea    0x1(%rax),%edx
  movslq %ecx,%rax
  mov    %edx,-0x10(%rbp,%rax,4)
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movb   $0x3,(%rdx,%rax,1)
  addl   $0x1,-0x14(%rbp)
L4:
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L23
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  movb   $0x0,(%rdx,%rax,1)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
void print_1(char m[][66], int h, int k, int n) {
  int b[2], y;
  n = n + 1;
  h = h - 2;
  k = k - 1;
  b[0] = h;
  b[1] = k + 1;
  for (y = 0; y < 2 * n - 1; y++) {
    b[y / (n - 1)]++;
    m[b[0]][b[1]] = 3;
  }
  m[b[0]][b[1]] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_1>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  sub    $0x2,%esi
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  lea    0x2(%rcx,%rcx,1),%esi
  cmp    $0x1,%esi
  jle    L11
  mov    %ecx,%edi
  sub    $0x1,%esi
  mov    $0x0,%ecx
L20:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  cltq
  addl   $0x1,(%rsp,%rax,4)
  movslq (%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    (%r8,%rax,2),%rdx
  movslq 0x4(%rsp),%rax
  movb   $0x3,(%rdx,%rax,1)
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jne    L20
L11:
  movslq (%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    (%r8,%rax,2),%rdx
  movslq 0x4(%rsp),%rax
  movb   $0x0,(%rdx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x18,%rsp
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_1(char m[][66], int h, int k, int n) {
  int b[2], y;
  n = n + 1;
  h = h - 2;
  k = k - 1;
  b[0] = h;
  b[1] = k + 1;
  for (y = 0; y < 2 * n - 1; y++) {
    b[y / (n - 1)]++;
    m[b[0]][b[1]] = 3;
  }
  m[b[0]][b[1]] = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_1>:
  endbr64
  sub    $0x18,%rsp
  sub    $0x2,%esi
  lea    0x1(%rcx,%rcx,1),%r9d
  mov    %rdi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  test   %r9d,%r9d
  jle    L18
  mov    %ecx,%edi
  xor    %ecx,%ecx
  jmp    L2
  nopl   (%rax)
L21:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  cltq
  mov    (%rsp,%rax,4),%esi
L2:
  mov    %ecx,%eax
  add    $0x1,%esi
  add    $0x1,%ecx
  cltd
  idiv   %edi
  cltq
  mov    %esi,(%rsp,%rax,4)
  movslq (%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    (%r8,%rax,2),%rsi
  movslq 0x4(%rsp),%rax
  movb   $0x3,(%rsi,%rax,1)
  cmp    %r9d,%ecx
  jne    L21
L46:
  movb   $0x0,(%rsi,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  movslq %esi,%rsi
  mov    %rsi,%rax
  shl    $0x5,%rax
  add    %rsi,%rax
  lea    (%rdi,%rax,2),%rsi
  movslq %edx,%rax
  jmp    L46
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_1(char m[][66], int h, int k, int n) {
  int b[2], y;
  n = n + 1;
  h = h - 2;
  k = k - 1;
  b[0] = h;
  b[1] = k + 1;
  for (y = 0; y < 2 * n - 1; y++) {
    b[y / (n - 1)]++;
    m[b[0]][b[1]] = 3;
  }
  m[b[0]][b[1]] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_1>:
  endbr64
  sub    $0x18,%rsp
  movslq %edx,%rax
  lea    0x1(%rcx,%rcx,1),%r9d
  mov    %rdi,%r8
  mov    %fs:0x28,%rdx
  mov    %rdx,0x8(%rsp)
  xor    %edx,%edx
  lea    -0x2(%rsi),%edx
  movd   %eax,%xmm1
  movd   %edx,%xmm0
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%rsp)
  test   %r9d,%r9d
  jle    L11
  sub    $0x1,%esi
  mov    %ecx,%edi
  mov    $0x1,%ecx
  mov    %esi,(%rsp)
  movslq %esi,%rsi
  mov    %rsi,%rdx
  shl    $0x5,%rdx
  add    %rsi,%rdx
  lea    (%r8,%rdx,2),%rdx
  movb   $0x3,(%rdx,%rax,1)
  cmp    $0x1,%r9d
  je     L4
  nopl   0x0(%rax)
L17:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cltd
  idiv   %edi
  cltq
  addl   $0x1,(%rsp,%rax,4)
  movslq (%rsp),%rdx
  mov    %rdx,%rax
  shl    $0x5,%rax
  add    %rdx,%rax
  lea    (%r8,%rax,2),%rdx
  movslq 0x4(%rsp),%rax
  movb   $0x3,(%rdx,%rax,1)
  cmp    %r9d,%ecx
  jne    L17
L4:
  movb   $0x0,(%rdx,%rax,1)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x18,%rsp
  ret
  nop
L11:
  movslq %edx,%rdx
  mov    %rdx,%rcx
  shl    $0x5,%rcx
  add    %rcx,%rdx
  lea    (%rdi,%rdx,2),%rdx
  jmp    L4
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void print_1(char m[][66], int h, int k, int n) {
  int b[2], y;
  n = n + 1;
  h = h - 2;
  k = k - 1;
  b[0] = h;
  b[1] = k + 1;
  for (y = 0; y < 2 * n - 1; y++) {
    b[y / (n - 1)]++;
    m[b[0]][b[1]] = 3;
  }
  m[b[0]][b[1]] = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L4
L13:
  mov    -0x18(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  subq   $0x1,-0x18(%rbp)
L4:
  cmpq   $0x0,-0x18(%rbp)
  jne    L13
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *reverse_string(char *str) {
  size_t len = strlen(str);
  char *result = malloc(len + 1);
  size_t idx = 0;
  for (size_t i = len; i > 0; --i)
    result[idx++] = str[i - 1];
  result[idx] = '\0';
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L6
  mov    %rax,%rcx
  mov    %rbp,%rdx
L17:
  sub    $0x1,%rdx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  test   %rdx,%rdx
  jne    L17
L6:
  movb   $0x0,(%rax,%rbp,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverse_string(char *str) {
  size_t len = strlen(str);
  char *result = malloc(len + 1);
  size_t idx = 0;
  for (size_t i = len; i > 0; --i)
    result[idx++] = str[i - 1];
  result[idx] = '\0';
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L13
  mov    %rax,%rcx
  mov    %rbp,%rdx
  nopl   0x0(%rax)
L2:
  sub    $0x1,%rdx
  add    $0x1,%rcx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,-0x1(%rcx)
  test   %rdx,%rdx
  jne    L2
  add    %rax,%rbp
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rax,%rbp
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverse_string(char *str) {
  size_t len = strlen(str);
  char *result = malloc(len + 1);
  size_t idx = 0;
  for (size_t i = len; i > 0; --i)
    result[idx++] = str[i - 1];
  result[idx] = '\0';
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<reverse_string>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rax,%rbp
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  test   %rbp,%rbp
  je     L15
  mov    %rax,%rcx
  mov    %rbp,%rdx
  nopl   0x0(%rax)
L18:
  sub    $0x1,%rdx
  add    $0x1,%rcx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,-0x1(%rcx)
  test   %rdx,%rdx
  jne    L18
  add    %rax,%rbp
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %rax,%rbp
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *reverse_string(char *str) {
  size_t len = strlen(str);
  char *result = malloc(len + 1);
  size_t idx = 0;
  for (size_t i = len; i > 0; --i)
    result[idx++] = str[i - 1];
  result[idx] = '\0';
  return result;
}
```