ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash_find_prime>:
  endbr64
  mov    $0x9,%edx
  xor    %ecx,%ecx
  lea    D3(%rip),%r8
  jmp    L5
  nopl   0x0(%rax)
L35:
  lea    (%rdx,%rcx,1),%eax
  sar    %eax
  movslq %eax,%rsi
  cmp    %edi,(%r8,%rsi,4)
  jl     L22
  mov    %eax,%edx
L5:
  cmp    %ecx,%edx
  jg     L35
  movslq %ecx,%rcx
  mov    (%r8,%rcx,4),%eax
  ret
  nopl   0x0(%rax)
L22:
  lea    0x1(%rax),%ecx
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: tag: D3
type: string

tool: D3: 

assistant: ```c
int hash_find_prime(int cap) {
  static const int table[] = {
      7, 23, 107, 317, 719, 1777, 5107, 7879, 10007,
  };
  int l = 0, m, r = (sizeof(table) / sizeof(table[0]));
  while (l < r) {
    m = (l + r) / 2;
    if (table[m] < cap)
      l = m + 1;
    else
      r = m;
  }
  return table[l];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_region_name_BO>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x9,-0x4(%rbp)
  ja     L9
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D19(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D19(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D95(%rip),%rax
  jmp    L35
  lea    D80(%rip),%rax
  jmp    L35
  lea    D56(%rip),%rax
  jmp    L35
  lea    D104(%rip),%rax
  jmp    L35
  lea    D103(%rip),%rax
  jmp    L35
  lea    D107(%rip),%rax
  jmp    L35
  lea    D57(%rip),%rax
  jmp    L35
  lea    D93(%rip),%rax
  jmp    L35
  lea    D100(%rip),%rax
  jmp    L35
L9:
  mov    $0x0,%eax
L35:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D95
type: string
name: retrieve_data
arguments: tag: D80
type: string
name: retrieve_data
arguments: tag: D56
type: string
name: retrieve_data
arguments: tag: D104
type: string
name: retrieve_data
arguments: tag: D103
type: string
name: retrieve_data
arguments: tag: D107
type: string
name: retrieve_data
arguments: tag: D57
type: string
name: retrieve_data
arguments: tag: D93
type: string
name: retrieve_data
arguments: tag: D100
type: string

tool: D95: Chuquisaca

tool: D80: Cochabamba

tool: D56: El Beni

tool: D104: La Paz

tool: D103: Oruro

tool: D107: Pando

tool: D57: Potosi

tool: D93: Santa Cruz

tool: D100: Tarija

assistant: ```c
const char *get_region_name_BO(int region_code) {
  switch (region_code) {
  case 1:
    return "Chuquisaca";
  case 2:
    return "Cochabamba";
  case 3:
    return "El Beni";
  case 4:
    return "La Paz";
  case 5:
    return "Oruro";
  case 6:
    return "Pando";
  case 7:
    return "Potosi";
  case 8:
    return "Santa Cruz";
  case 9:
    return "Tarija";
  default:
    return NULL;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_region_name_BO>:
  endbr64
  cmp    $0x9,%edi
  ja     L6
  mov    %edi,%edi
  lea    D51(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D72(%rip),%rax
  ret
  lea    D38(%rip),%rax
  ret
  lea    D35(%rip),%rax
  ret
  lea    D0(%rip),%rax
  ret
  lea    D77(%rip),%rax
  ret
  lea    D3(%rip),%rax
  ret
  lea    D19(%rip),%rax
  ret
  lea    D48(%rip),%rax
  ret
L6:
  mov    $0x0,%eax
  ret
  lea    D79(%rip),%rax
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D72
datatype: string
name: parse_data
arguments: data_tag: D38
datatype: string
name: parse_data
arguments: data_tag: D35
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D77
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string
name: parse_data
arguments: data_tag: D19
datatype: string
name: parse_data
arguments: data_tag: D48
datatype: string
name: parse_data
arguments: data_tag: D79
datatype: string

tool: D72: Cochabamba

tool: D38: El Beni

tool: D35: La Paz

tool: D0: Oruro

tool: D77: Pando

tool: D3: Potosi

tool: D19: Santa Cruz

tool: D48: Tarija

tool: D79: Chuquisaca

assistant: ```c
const char *get_region_name_BO(int region_code) {
  switch (region_code) {
  case 1:
    return "Chuquisaca";
  case 2:
    return "Cochabamba";
  case 3:
    return "El Beni";
  case 4:
    return "La Paz";
  case 5:
    return "Oruro";
  case 6:
    return "Pando";
  case 7:
    return "Potosi";
  case 8:
    return "Santa Cruz";
  case 9:
    return "Tarija";
  default:
    return NULL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_region_name_BO>:
  endbr64
  cmp    $0x9,%edi
  ja     L7
  lea    D65(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D1(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D42(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D32(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D90(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D81(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D46(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D40(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D62(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D97(%rip),%rax
  ret
L7:
  xor    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string
name: disassemble_data
arguments: label: D42
type: string
name: disassemble_data
arguments: label: D32
type: string
name: disassemble_data
arguments: label: D90
type: string
name: disassemble_data
arguments: label: D81
type: string
name: disassemble_data
arguments: label: D46
type: string
name: disassemble_data
arguments: label: D40
type: string
name: disassemble_data
arguments: label: D62
type: string
name: disassemble_data
arguments: label: D97
type: string

tool: D1: Cochabamba

tool: D42: Chuquisaca

tool: D32: Tarija

tool: D90: Potosi

tool: D81: Santa Cruz

tool: D46: El Beni

tool: D40: La Paz

tool: D62: Oruro

tool: D97: Pando

assistant: ```c
const char *get_region_name_BO(int region_code) {
  switch (region_code) {
  case 1:
    return "Chuquisaca";
  case 2:
    return "Cochabamba";
  case 3:
    return "El Beni";
  case 4:
    return "La Paz";
  case 5:
    return "Oruro";
  case 6:
    return "Pando";
  case 7:
    return "Potosi";
  case 8:
    return "Santa Cruz";
  case 9:
    return "Tarija";
  default:
    return NULL;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_region_name_BO>:
  endbr64
  cmp    $0x9,%edi
  ja     L7
  lea    D46(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D96(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D10(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D88(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D45(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D79(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D61(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D67(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D42(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D89(%rip),%rax
  ret
L7:
  xor    %eax,%eax
  ret
```

tool_calls: name: parse_data
arguments: label: D96
type_infered: string
name: parse_data
arguments: label: D10
type_infered: string
name: parse_data
arguments: label: D88
type_infered: string
name: parse_data
arguments: label: D45
type_infered: string
name: parse_data
arguments: label: D79
type_infered: string
name: parse_data
arguments: label: D61
type_infered: string
name: parse_data
arguments: label: D67
type_infered: string
name: parse_data
arguments: label: D42
type_infered: string
name: parse_data
arguments: label: D89
type_infered: string

tool: D96: Cochabamba

tool: D10: Chuquisaca

tool: D88: Tarija

tool: D45: Potosi

tool: D79: Santa Cruz

tool: D61: El Beni

tool: D67: La Paz

tool: D42: Oruro

tool: D89: Pando

assistant: ```c
const char *get_region_name_BO(int region_code) {
  switch (region_code) {
  case 1:
    return "Chuquisaca";
  case 2:
    return "Cochabamba";
  case 3:
    return "El Beni";
  case 4:
    return "La Paz";
  case 5:
    return "Oruro";
  case 6:
    return "Pando";
  case 7:
    return "Potosi";
  case 8:
    return "Santa Cruz";
  case 9:
    return "Tarija";
  default:
    return NULL;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<tpi_sldcs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  or     $0x80,%al
  mov    %eax,%edi
  call   <tpi_write@plt>
  mov    $0x0,%eax
  call   <tpi_read@plt>
  leave
  ret
```

assistant: ```c
uint8_t tpi_sldcs(uint8_t address) {
  tpi_write((0x80) | ((address) & (0x0F)));
  return tpi_read();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tpi_sldcs>:
  endbr64
  sub    $0x8,%rsp
  and    $0xf,%edi
  or     $0x80,%dil
  call   <tpi_write@plt>
  mov    $0x0,%eax
  call   <tpi_read@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
uint8_t tpi_sldcs(uint8_t address) {
  tpi_write((0x80) | ((address) & (0x0F)));
  return tpi_read();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tpi_sldcs>:
  endbr64
  and    $0xf,%edi
  sub    $0x8,%rsp
  or     $0x80,%dil
  call   <tpi_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <tpi_read@plt>
```

assistant: ```c
uint8_t tpi_sldcs(uint8_t address) {
  tpi_write((0x80) | ((address) & (0x0F)));
  return tpi_read();
}
```
user: What is the c source code of the assembly code below:

```asm
<tpi_sldcs>:
  endbr64
  and    $0xf,%edi
  sub    $0x8,%rsp
  or     $0x80,%dil
  call   <tpi_write@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <tpi_read@plt>
```

assistant: ```c
uint8_t tpi_sldcs(uint8_t address) {
  tpi_write((0x80) | ((address) & (0x0F)));
  return tpi_read();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<raw_tanh_bulk_apply_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  movss  D20(%rip),%xmm0
  mulss  %xmm1,%xmm0
  cvttss2si %xmm0,%eax
  mov    %eax,%edi
  call   <exp@plt>
  movsd  D10(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D18(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  D10(%rip),%xmm1
  subsd  %xmm1,%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L7
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D20
type_infered: byte[4]
name: parse_data
arguments: tag: D10
type_infered: f64
name: parse_data
arguments: tag: D18
type_infered: f64

tool: {"D20": [0x00,0x00,0x00,0xc0]}

tool: D10: 1

tool: D18: 2

assistant: ```c
void raw_tanh_bulk_apply_function(int n, float *ptr) {
  int i;
  for (i = 0; i < n; i++) {
    ptr[i] = (2.0 / (1.0 + exp(-2 * ptr[i]))) - 1.0;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<raw_tanh_bulk_apply_function>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rbp
L6:
  movss  D14(%rip),%xmm0
  mulss  (%rbx),%xmm0
  cvttss2si %xmm0,%edi
  call   <exp@plt>
  movsd  D12(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D39(%rip),%xmm0
  divsd  %xmm1,%xmm0
  subsd  D12(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L11:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D12
datatype: f64
name: extract_symbolic_data
arguments: label: D39
datatype: f64

tool: {"D14": [0x00,0x00,0x00,0xc0]}

tool: D12: 1

tool: D39: 2

assistant: ```c
void raw_tanh_bulk_apply_function(int n, float *ptr) {
  int i;
  for (i = 0; i < n; i++) {
    ptr[i] = (2.0 / (1.0 + exp(-2 * ptr[i]))) - 1.0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<raw_tanh_bulk_apply_function>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L17:
  movss  D15(%rip),%xmm0
  mulss  (%rbx),%xmm0
  add    $0x4,%rbx
  cvttss2si %xmm0,%edi
  call   <exp@plt>
  movsd  D28(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D19(%rip),%xmm0
  divsd  %xmm1,%xmm0
  subsd  D28(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L7:
  ret
```

tool_calls: name: read_data
arguments: tag: D15
datatype: byte[4]
name: read_data
arguments: tag: D28
datatype: f64
name: read_data
arguments: tag: D19
datatype: f64

tool: {"D15": [0x00,0x00,0x00,0xc0]}

tool: D28: 1

tool: D19: 2

assistant: ```c
void raw_tanh_bulk_apply_function(int n, float *ptr) {
  int i;
  for (i = 0; i < n; i++) {
    ptr[i] = (2.0 / (1.0 + exp(-2 * ptr[i]))) - 1.0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<raw_tanh_bulk_apply_function>:
  endbr64
  test   %edi,%edi
  jle    L7
  push   %rbp
  lea    -0x1(%rdi),%eax
  push   %rbx
  lea    0x4(%rsi,%rax,4),%rbp
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L16:
  movss  D38(%rip),%xmm0
  mulss  (%rbx),%xmm0
  add    $0x4,%rbx
  cvttss2si %xmm0,%edi
  call   <exp@plt>
  movsd  D23(%rip),%xmm1
  addsd  %xmm0,%xmm1
  movsd  D5(%rip),%xmm0
  divsd  %xmm1,%xmm0
  subsd  D23(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbx)
  cmp    %rbp,%rbx
  jne    L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  xchg   %ax,%ax
L7:
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D38
datatype: byte[4]
name: disassemble_data
arguments: data_label: D23
datatype: f64
name: disassemble_data
arguments: data_label: D5
datatype: f64

tool: {"D38": [0x00,0x00,0x00,0xc0]}

tool: D23: 1

tool: D5: 2

assistant: ```c
void raw_tanh_bulk_apply_function(int n, float *ptr) {
  int i;
  for (i = 0; i < n; i++) {
    ptr[i] = (2.0 / (1.0 + exp(-2 * ptr[i]))) - 1.0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_fatptr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <f@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: f64

tool: D2: 10

assistant: ```c
void test_fatptr() {
  double x = 10;
  f(&x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_fatptr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D9(%rip),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rdi
  call   <f@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: f64

tool: D9: 10

assistant: ```c
void test_fatptr() {
  double x = 10;
  f(&x);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_fatptr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <f@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D4
type_infered: f64

tool: D4: 10

assistant: ```c
void test_fatptr() {
  double x = 10;
  f(&x);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_fatptr>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <f@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D5
type: f64

tool: D5: 10

assistant: ```c
void test_fatptr() {
  double x = 10;
  f(&x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<remove_last_slack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xab,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int remove_last_slack(int k) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(171, &k, b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<remove_last_slack>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0xab,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int remove_last_slack(int k) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(171, &k, b, c);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<remove_last_slack>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0xab,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int remove_last_slack(int k) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(171, &k, b, c);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<remove_last_slack>:
  endbr64
  sub    $0x18,%rsp
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0xab,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int remove_last_slack(int k) {
  int *b, fail;
  double *c;
  fail = _ada_use_c2phc(171, &k, b, c);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<voltea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    D19(%rip),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L16
L17:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    D19(%rip),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    D8(%rip),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x0,-0x4(%rbp)
  jns    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void voltea(void) {
  int i = 0;
  extern char linea[], linea_max[];
  int length = strlen(linea) - 1;
  while (length >= 0) {
    *(linea_max + i) = *(linea + length);
    i++, length--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<voltea>:
  endbr64
  sub    $0x8,%rsp
  mov    D23(%rip),%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  sub    $0x1,%ecx
  js     L4
  movslq %ecx,%rcx
  add    D23(%rip),%rcx
  mov    D22(%rip),%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rdx,%rax,1),%rsi
L12:
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  sub    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L12
L4:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void voltea(void) {
  int i = 0;
  extern char linea[], linea_max[];
  int length = strlen(linea) - 1;
  while (length >= 0) {
    *(linea_max + i) = *(linea + length);
    i++, length--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<voltea>:
  endbr64
  sub    $0x8,%rsp
  mov    D5(%rip),%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L29
  mov    D4(%rip),%rsi
  movslq %eax,%rcx
  mov    %eax,%eax
  add    D5(%rip),%rcx
  lea    0x1(%rsi),%rdx
  add    %rdx,%rax
  jmp    L15
  nopl   (%rax)
L24:
  add    $0x1,%rdx
L15:
  movzbl (%rcx),%edi
  sub    $0x1,%rcx
  mov    %dil,(%rsi)
  mov    %rdx,%rsi
  cmp    %rax,%rdx
  jne    L24
L29:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void voltea(void) {
  int i = 0;
  extern char linea[], linea_max[];
  int length = strlen(linea) - 1;
  while (length >= 0) {
    *(linea_max + i) = *(linea + length);
    i++, length--;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<voltea>:
  endbr64
  sub    $0x8,%rsp
  mov    D12(%rip),%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L2
  mov    D24(%rip),%rsi
  movslq %eax,%rcx
  mov    %eax,%eax
  add    D12(%rip),%rcx
  lea    0x1(%rsi),%rdx
  add    %rdx,%rax
  jmp    L0
  nopl   (%rax)
L29:
  add    $0x1,%rdx
L0:
  movzbl (%rcx),%edi
  sub    $0x1,%rcx
  mov    %dil,(%rsi)
  mov    %rdx,%rsi
  cmp    %rax,%rdx
  jne    L29
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void voltea(void) {
  int i = 0;
  extern char linea[], linea_max[];
  int length = strlen(linea) - 1;
  while (length >= 0) {
    *(linea_max + i) = *(linea + length);
    i++, length--;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sg_put_unaligned_le64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    $0x20,%ecx
  mov    -0x4(%rbp),%eax
  sar    %cl,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sg_put_unaligned_le32@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <sg_put_unaligned_le32@plt>
  nop
  leave
  ret
```

assistant: ```c
void sg_put_unaligned_le64(uint64_t val, void *p) {
  sg_put_unaligned_le32(val >> 32, (uint8_t *)p + 4);
  sg_put_unaligned_le32(val, p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<sg_put_unaligned_le64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    0x4(%rsi),%rsi
  mov    $0x20,%ecx
  sar    %cl,%edi
  call   <sg_put_unaligned_le32@plt>
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <sg_put_unaligned_le32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sg_put_unaligned_le64(uint64_t val, void *p) {
  sg_put_unaligned_le32(val >> 32, (uint8_t *)p + 4);
  sg_put_unaligned_le32(val, p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sg_put_unaligned_le64>:
  endbr64
  push   %r12
  mov    $0x20,%ecx
  mov    %rsi,%r12
  lea    0x4(%rsi),%rsi
  push   %rbp
  mov    %edi,%ebp
  sar    %cl,%edi
  sub    $0x8,%rsp
  call   <sg_put_unaligned_le32@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <sg_put_unaligned_le32@plt>
```

assistant: ```c
void sg_put_unaligned_le64(uint64_t val, void *p) {
  sg_put_unaligned_le32(val >> 32, (uint8_t *)p + 4);
  sg_put_unaligned_le32(val, p);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sg_put_unaligned_le64>:
  endbr64
  push   %r12
  mov    $0x20,%ecx
  mov    %rsi,%r12
  lea    0x4(%rsi),%rsi
  push   %rbp
  mov    %edi,%ebp
  sar    %cl,%edi
  sub    $0x8,%rsp
  call   <sg_put_unaligned_le32@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1050 <sg_put_unaligned_le32@plt>
```

assistant: ```c
void sg_put_unaligned_le64(uint64_t val, void *p) {
  sg_put_unaligned_le32(val >> 32, (uint8_t *)p + 4);
  sg_put_unaligned_le32(val, p);
}
```