ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_example_main_no_args>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D14(%rip),%rax
  mov    %rax,(%rsp)
  mov    %rsp,%rsi
  mov    $0x1,%edi
  call   <example_main@plt>
  mov    %eax,%edi
  mov    $0x1b0,%ecx
  lea    D12(%rip),%rdx
  mov    $0x0,%esi
  call   <_assert_int_equal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
type_guessed: string
name: unpack_data
arguments: tag: D12
type_guessed: string

tool: D14: example

tool: D12: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_example_main_no_args(void **state) {
  const char *args[] = {
      "example",
  };
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(example_main((sizeof(args) / sizeof((args)[0])), (char **)args)))), ((unsigned long long)((unsigned)(size_t)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 432);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_example_main_no_args>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  lea    D10(%rip),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <example_main@plt>
  xor    %esi,%esi
  mov    $0x1b0,%ecx
  lea    D11(%rip),%rdx
  mov    %eax,%edi
  call   <_assert_int_equal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D10
type_guessed: string
name: unpack_data
arguments: data_label: D11
type_guessed: string

tool: D10: example

tool: D11: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_example_main_no_args(void **state) {
  const char *args[] = {
      "example",
  };
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(example_main((sizeof(args) / sizeof((args)[0])), (char **)args)))), ((unsigned long long)((unsigned)(size_t)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 432);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_example_main_no_args>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  lea    D0(%rip),%rax
  mov    %rsp,%rsi
  mov    %rax,(%rsp)
  call   <example_main@plt>
  xor    %esi,%esi
  mov    $0x1b0,%ecx
  lea    D5(%rip),%rdx
  mov    %eax,%edi
  call   <_assert_int_equal@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string
name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D0: example

tool: D5: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c

assistant: ```c
void test_example_main_no_args(void **state) {
  const char *args[] = {
      "example",
  };
  (void)state;
  _assert_int_equal(((unsigned long long)((unsigned)(size_t)(example_main((sizeof(args) / sizeof((args)[0])), (char **)args)))), ((unsigned long long)((unsigned)(size_t)(0))), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/akikoskinen/cmocka/refs/heads/master/src/example/calculator_test.c", 432);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdx
  lea    D29(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D29
datatype: string
name: read_data
arguments: data_label: D16
datatype: string

tool: D7: todos

tool: D29: Hola a

tool: D16: %s %s


assistant: ```c
int main() {
  printf("%s %s\n", "Hola a", "todos");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D19(%rip),%rdx
  lea    D20(%rip),%rsi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D19
type_infered: string
name: read_data
arguments: label: D20
type_infered: string
name: read_data
arguments: label: D29
type_infered: string

tool: D19: todos

tool: D20: Hola a

tool: D29: %s %s


assistant: ```c
int main() {
  printf("%s %s\n", "Hola a", "todos");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdx
  lea    D27(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D27
type: string
name: parse_data
arguments: data_label: D26
type: string

tool: D17: todos

tool: D27: Hola a

tool: D26: %s %s


assistant: ```c
int main() {
  printf("%s %s\n", "Hola a", "todos");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdx
  lea    D8(%rip),%rsi
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string
name: retrieve_data
arguments: data_tag: D26
datatype: string

tool: D2: todos

tool: D8: Hola a

tool: D26: %s %s


assistant: ```c
int main() {
  printf("%s %s\n", "Hola a", "todos");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lbs_str_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lbs_str_vprintf@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *lbs_str_printf(const char *format, ...) {
  va_list ap;
  char *newstr;
  va_start(ap, format);
  newstr = lbs_str_vprintf(format, ap);
  va_end(ap);
  return newstr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lbs_str_printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <lbs_str_vprintf@plt>
  mov    %rax,%rbx
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *lbs_str_printf(const char *format, ...) {
  va_list ap;
  char *newstr;
  va_start(ap, format);
  newstr = lbs_str_vprintf(format, ap);
  va_end(ap);
  return newstr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lbs_str_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <lbs_str_vprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *lbs_str_printf(const char *format, ...) {
  va_list ap;
  char *newstr;
  va_start(ap, format);
  newstr = lbs_str_vprintf(format, ap);
  va_end(ap);
  return newstr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<lbs_str_printf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  mov    %rdi,%rsi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <lbs_str_vprintf@plt>
  mov    %r13d,%edi
  mov    %rax,%r12
  call   <va_end@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *lbs_str_printf(const char *format, ...) {
  va_list ap;
  char *newstr;
  va_start(ap, format);
  newstr = lbs_str_vprintf(format, ap);
  va_end(ap);
  return newstr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<doubleCapacity>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L16:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    (%rcx),%rax
  mov    %rax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L16
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void doubleCapacity(char ***array, int *count, int *capacity) {
  int i;
  char **arrayCopy = *array;
  *capacity = 2 * (*capacity);
  *array = (char **)malloc(*capacity * sizeof(char *));
  for (i = 0; i < *count; i++) {
    (*array)[i] = arrayCopy[i];
  }
  free(arrayCopy);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<doubleCapacity>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rdi),%r12
  mov    (%rdx),%eax
  lea    (%rax,%rax,1),%edi
  mov    %edi,(%rdx)
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  cmpl   $0x0,0x0(%rbp)
  jle    L14
  mov    $0x0,%eax
L19:
  mov    (%r12,%rax,8),%rcx
  mov    (%rbx),%rdx
  mov    %rcx,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,0x0(%rbp)
  jg     L19
L14:
  mov    %r12,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void doubleCapacity(char ***array, int *count, int *capacity) {
  int i;
  char **arrayCopy = *array;
  *capacity = 2 * (*capacity);
  *array = (char **)malloc(*capacity * sizeof(char *));
  for (i = 0; i < *count; i++) {
    (*array)[i] = arrayCopy[i];
  }
  free(arrayCopy);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<doubleCapacity>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  mov    (%rdx),%edi
  lea    (%rdi,%rdi,1),%eax
  shl    $0x4,%edi
  mov    %eax,(%rdx)
  call   <malloc@plt>
  mov    (%r12),%edx
  mov    %rax,(%rbx)
  test   %edx,%edx
  jle    L1
  mov    %rbp,%rcx
  lea    (%rax,%rdx,8),%rsi
  sub    %rax,%rcx
  nopl   (%rax)
L4:
  mov    (%rcx,%rax,1),%rdx
  add    $0x8,%rax
  mov    %rdx,-0x8(%rax)
  cmp    %rsi,%rax
  jne    L4
L1:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
```

assistant: ```c
void doubleCapacity(char ***array, int *count, int *capacity) {
  int i;
  char **arrayCopy = *array;
  *capacity = 2 * (*capacity);
  *array = (char **)malloc(*capacity * sizeof(char *));
  for (i = 0; i < *count; i++) {
    (*array)[i] = arrayCopy[i];
  }
  free(arrayCopy);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<doubleCapacity>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rbp
  mov    (%rdx),%edi
  lea    (%rdi,%rdi,1),%eax
  shl    $0x4,%edi
  mov    %eax,(%rdx)
  call   <malloc@plt>
  mov    (%r12),%esi
  mov    %rax,(%rbx)
  test   %esi,%esi
  jle    L42
  mov    %rax,%rdx
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L44
  lea    0x8(%rbp),%rax
  cmp    %rax,%rdx
  je     L44
  mov    %esi,%ecx
  mov    %rbp,%rdi
  mov    %rdx,%rax
  shr    %ecx
  sub    %rdx,%rdi
  shl    $0x4,%rcx
  add    %rdx,%rcx
  nopl   0x0(%rax,%rax,1)
L35:
  movdqu (%rax,%rdi,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rcx,%rax
  jne    L35
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L42
  mov    0x0(%rbp,%rax,8),%rcx
  mov    %rcx,(%rdx,%rax,8)
L42:
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
  nopl   0x0(%rax)
L44:
  mov    %rbp,%rcx
  lea    (%rdx,%rsi,8),%rsi
  sub    %rdx,%rcx
  nopw   0x0(%rax,%rax,1)
L51:
  mov    (%rcx,%rdx,1),%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rdx,%rsi
  jne    L51
  pop    %rbx
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <free@plt>
```

assistant: ```c
void doubleCapacity(char ***array, int *count, int *capacity) {
  int i;
  char **arrayCopy = *array;
  *capacity = 2 * (*capacity);
  *array = (char **)malloc(*capacity * sizeof(char *));
  for (i = 0; i < *count; i++) {
    (*array)[i] = arrayCopy[i];
  }
  free(arrayCopy);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <approx_pi@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string

tool: D4: %d

tool: D9: %.6f

assistant: ```c
int main() {
  int z;
  scanf("%d", &z);
  printf("%.6f", approx_pi(z));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D13(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <approx_pi@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_infered: string
name: parse_data
arguments: data_tag: D11
type_infered: string

tool: D13: %d

tool: D11: %.6f

assistant: ```c
int main() {
  int z;
  scanf("%d", &z);
  printf("%.6f", approx_pi(z));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <approx_pi@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D17
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D17: %d

tool: D1: %.6f

assistant: ```c
int main() {
  int z;
  scanf("%d", &z);
  printf("%.6f", approx_pi(z));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D0(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <approx_pi@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string

tool: D0: %d

tool: D9: %.6f

assistant: ```c
int main() {
  int z;
  scanf("%d", &z);
  printf("%.6f", approx_pi(z));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<floats_mat_ABt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x20(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    0x18(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x2c(%rbp),%eax
  cmp    0x20(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L0:
  movl   $0x0,-0xc(%rbp)
  jmp    L16
L35:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L36
L15:
  mov    -0x10(%rbp),%eax
  imul   -0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  imul   -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L36:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L15
  mov    -0x10(%rbp),%eax
  imul   0x20(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movss  -0x8(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L16:
  mov    -0xc(%rbp),%eax
  cmp    0x20(%rbp),%eax
  jl     L35
  addl   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%eax
  cmp    0x18(%rbp),%eax
  jl     L0
  nop
  nop
  leave
  ret
```

assistant: ```c
void floats_mat_ABt(const float *A, int Arows, int Acols, const float *B, int Brows, int Bcols, float *R, int Rrows, int Rcols) {
  assert(Acols == Bcols);
  assert(Rrows == Arows);
  assert(Brows == Rcols);
  for (int Rrow = 0; Rrow < Rrows; Rrow++) {
    for (int Rcol = 0; Rcol < Rcols; Rcol++) {
      float acc = 0;
      for (int i = 0; i < Acols; i++)
        acc += A[Rrow * Acols + i] * B[Rcol * Bcols + i];
      R[Rrow * Rcols + Rcol] = acc;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<floats_mat_ABt>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %esi,%r15d
  mov    %edx,%ebx
  mov    %rcx,%r12
  mov    %r8d,%r14d
  mov    %r9d,%ebp
  mov    0x60(%rsp),%r13d
  cmp    %r9d,%edx
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r15d,0x58(%rsp)
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmp    %r13d,%r14d
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  cmpl   $0x0,0x58(%rsp)
  jle    L31
  mov    $0x0,%r14d
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  lea    -0x1(%r13),%eax
  mov    %rax,0x8(%rsp)
  mov    0x50(%rsp),%rax
  lea    0x4(%rax),%r15
  mov    %ebx,%esi
  jmp    L56
L62:
  movslq %r8d,%rax
  lea    (%r12,%rax,4),%rdx
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L2:
  movss  (%rcx,%rax,4),%xmm0
  mulss  (%rdx,%rax,4),%xmm0
  addss  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L2
L39:
  movss  %xmm1,(%rdi)
  add    $0x4,%rdi
  add    %ebp,%r8d
  cmp    %r9,%rdi
  je     L60
L71:
  pxor   %xmm1,%xmm1
  test   %ebx,%ebx
  jg     L62
  jmp    L39
L60:
  add    $0x1,%r10d
  add    %r13d,%r11d
  add    %ebx,%r14d
  cmp    %r10d,0x58(%rsp)
  je     L31
L56:
  test   %r13d,%r13d
  jle    L60
  movslq %r11d,%rax
  mov    0x50(%rsp),%rdi
  lea    (%rdi,%rax,4),%rdi
  add    0x8(%rsp),%rax
  lea    (%r15,%rax,4),%r9
  movslq %r14d,%rax
  mov    (%rsp),%rdx
  lea    (%rdx,%rax,4),%rcx
  mov    $0x0,%r8d
  jmp    L71
L31:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void floats_mat_ABt(const float *A, int Arows, int Acols, const float *B, int Brows, int Bcols, float *R, int Rrows, int Rcols) {
  assert(Acols == Bcols);
  assert(Rrows == Arows);
  assert(Brows == Rcols);
  for (int Rrow = 0; Rrow < Rrows; Rrow++) {
    for (int Rcol = 0; Rcol < Rcols; Rcol++) {
      float acc = 0;
      for (int i = 0; i < Acols; i++)
        acc += A[Rrow * Acols + i] * B[Rcol * Bcols + i];
      R[Rrow * Rcols + Rcol] = acc;
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<floats_mat_ABt>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  mov    %r8d,%r14d
  push   %r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %r9d,%ebp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  xor    %edi,%edi
  cmp    %r9d,%edx
  mov    0x70(%rsp),%r13d
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r15d,0x68(%rsp)
  sete   %dil
  call   <assert@plt>
  xor    %edi,%edi
  cmp    %r13d,%r14d
  sete   %dil
  call   <assert@plt>
  mov    0x68(%rsp),%eax
  test   %eax,%eax
  jle    L36
  lea    -0x1(%r13),%eax
  xor    %r15d,%r15d
  xor    %r14d,%r14d
  xor    %r11d,%r11d
  mov    %rax,0x10(%rsp)
  mov    0x60(%rsp),%rax
  pxor   %xmm2,%xmm2
  lea    -0x1(%rbx),%edi
  add    $0x4,%rax
  mov    %rax,0x18(%rsp)
  nopl   0x0(%rax)
L33:
  test   %r13d,%r13d
  jle    L53
  mov    0x60(%rsp),%rcx
  movslq %r14d,%rax
  xor    %r9d,%r9d
  lea    (%rcx,%rax,4),%r8
  mov    0x18(%rsp),%rcx
  add    0x10(%rsp),%rax
  lea    (%rcx,%rax,4),%r10
  mov    0x8(%rsp),%rcx
  movslq %r15d,%rax
  lea    (%rcx,%rax,4),%rsi
  xchg   %ax,%ax
L25:
  movaps %xmm2,%xmm1
  test   %ebx,%ebx
  jle    L16
  movslq %r9d,%rax
  movaps %xmm2,%xmm1
  lea    (%r12,%rax,4),%rcx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L35:
  movss  (%rsi,%rax,4),%xmm0
  mulss  (%rcx,%rax,4),%xmm0
  mov    %rax,%rdx
  add    $0x1,%rax
  addss  %xmm0,%xmm1
  cmp    %rdi,%rdx
  jne    L35
L16:
  movss  %xmm1,(%r8)
  add    $0x4,%r8
  add    %ebp,%r9d
  cmp    %r10,%r8
  jne    L25
L53:
  add    $0x1,%r11d
  add    %r13d,%r14d
  add    %ebx,%r15d
  cmp    %r11d,0x68(%rsp)
  jne    L33
L36:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void floats_mat_ABt(const float *A, int Arows, int Acols, const float *B, int Brows, int Bcols, float *R, int Rrows, int Rcols) {
  assert(Acols == Bcols);
  assert(Rrows == Arows);
  assert(Brows == Rcols);
  for (int Rrow = 0; Rrow < Rrows; Rrow++) {
    for (int Rcol = 0; Rcol < Rcols; Rcol++) {
      float acc = 0;
      for (int i = 0; i < Acols; i++)
        acc += A[Rrow * Acols + i] * B[Rcol * Bcols + i];
      R[Rrow * Rcols + Rcol] = acc;
    }
  }
}
```