ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<gmt2local>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  je     L28
L17:
  lea    0x8(%rsp),%r12
  mov    %r12,%rdi
  call   <gmtime@plt>
  mov    %r12,%rdi
  mov    (%rax),%r14d
  mov    0x4(%rax),%r13d
  mov    0x8(%rax),%ebp
  mov    0xc(%rax),%ebx
  call   <localtime@plt>
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  sub    %r14d,%ecx
  sub    %r13d,%edx
  imul   $0x3c,%edx,%edx
  imul   $0xe10,%ecx,%ecx
  add    %edx,%ecx
  mov    0x8(%rax),%edx
  sub    %ebp,%edx
  jne    L6
  mov    0xc(%rax),%edx
  sub    %ebx,%edx
L6:
  imul   $0x15180,%edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  add    %ecx,%eax
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  xor    %edi,%edi
  call   <time@plt>
  mov    %rax,0x8(%rsp)
  jmp    L17
```

assistant: ```c
int32_t gmt2local(time_t t) {
  register int dt, dir;
  register struct tm *gmt, *loc;
  struct tm sgmt;
  if (t == 0)
    t = time(NULL);
  gmt = &sgmt;
  *gmt = *gmtime(&t);
  loc = localtime(&t);
  dt = (loc->tm_hour - gmt->tm_hour) * 60 * 60 + (loc->tm_min - gmt->tm_min) * 60;
  dir = loc->tm_year - gmt->tm_year;
  if (dir == 0)
    dir = loc->tm_yday - gmt->tm_yday;
  dt += dir * 24 * 60 * 60;
  return (dt);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<gmt2local>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,0x8(%rsp)
  test   %rdi,%rdi
  je     L11
L17:
  lea    0x8(%rsp),%r12
  mov    %r12,%rdi
  call   <gmtime@plt>
  mov    %r12,%rdi
  mov    (%rax),%r14d
  mov    0x4(%rax),%r13d
  mov    0x8(%rax),%ebp
  mov    0xc(%rax),%ebx
  call   <localtime@plt>
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  sub    %r14d,%ecx
  sub    %r13d,%edx
  imul   $0x3c,%edx,%edx
  imul   $0xe10,%ecx,%ecx
  add    %edx,%ecx
  mov    0x8(%rax),%edx
  sub    %ebp,%edx
  jne    L29
  mov    0xc(%rax),%edx
  sub    %ebx,%edx
L29:
  imul   $0x15180,%edx,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  add    %ecx,%eax
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  xor    %edi,%edi
  call   <time@plt>
  mov    %rax,0x8(%rsp)
  jmp    L17
```

assistant: ```c
int32_t gmt2local(time_t t) {
  register int dt, dir;
  register struct tm *gmt, *loc;
  struct tm sgmt;
  if (t == 0)
    t = time(NULL);
  gmt = &sgmt;
  *gmt = *gmtime(&t);
  loc = localtime(&t);
  dt = (loc->tm_hour - gmt->tm_hour) * 60 * 60 + (loc->tm_min - gmt->tm_min) * 60;
  dir = loc->tm_year - gmt->tm_year;
  if (dir == 0)
    dir = loc->tm_yday - gmt->tm_yday;
  dt += dir * 24 * 60 * 60;
  return (dt);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  movl   $0x0,0x10(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    D74(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D55(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0xb(%rsp),%rsi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0xc(%rsp),%r13d
  lea    D91(%rip),%rdi
  call   <printf@plt>
  lea    0xb(%rsp),%rbp
  lea    D24(%rip),%rbx
  lea    D96(%rip),%r12
  jmp    L10
L52:
  mov    %r12,%rdi
  call   <printf@plt>
L10:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movzbl 0xb(%rsp),%ecx
  cmp    $0x30,%cl
  je     L33
  cmp    $0x31,%cl
  jne    L52
  lea    0x1(%r13),%eax
  cltd
  idivl  0x14(%rsp)
  mov    %edx,%r13d
  jmp    L10
L33:
  cmp    %r13d,0x10(%rsp)
  je     L38
  lea    D22(%rip),%rdi
  call   <printf@plt>
L9:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  lea    D99(%rip),%rdi
  call   <printf@plt>
  jmp    L9
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D74
type: string
name: retrieve_data
arguments: tag: D29
type: string
name: retrieve_data
arguments: tag: D55
type: string
name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D24
type: string
name: retrieve_data
arguments: tag: D91
type: string
name: retrieve_data
arguments: tag: D96
type: string
name: retrieve_data
arguments: tag: D22
type: string
name: retrieve_data
arguments: tag: D99
type: string

tool: D74: 
Enter the number of states.


tool: D29: %d

tool: D55: 
Enter the start state.


tool: D17: 
Enter the accept state.


tool: D24: %c

tool: D91: 
Please enter a number of 1s, followed by a 0.


tool: D96: Illegal character.


tool: D22: 
Reject.


tool: D99: 
Accept.


assistant: ```c
int main() {
  char temp;
  int currentState = 0, startState = 0, acceptState = 0, numStates = 0;
  printf("\nEnter the number of states.\n");
  scanf("%d", &numStates);
  printf("\nEnter the start state.\n");
  scanf("%d", &startState);
  printf("\nEnter the accept state.\n");
  scanf("%d", &acceptState);
  scanf("%c", &temp);
  currentState = startState;
  printf("\nPlease enter a number of 1s, followed by a 0.\n");
  while (1) {
    scanf("%c", &temp);
    if (temp == '0') {
      break;
    } else if (temp == '1') {
      currentState++;
      currentState = currentState % numStates;
    } else {
      printf("Illegal character.\n");
    }
  }
  if (currentState == acceptState) {
    printf("\nAccept.\n");
  } else {
    printf("\nReject.\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<cmd_bind>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpl   $0x2,-0x4(%rbp)
  jg     L19
  mov    $0xffffffff,%eax
  jmp    L4
L19:
  mov    -0x10(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rc_bindkey@plt>
L4:
  leave
  ret
```

assistant: ```c
int cmd_bind(int argc, char **argv) {
  if (argc < 3)
    return -1;
  return rc_bindkey(argv[1], argv[2]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmd_bind>:
  endbr64
  cmp    $0x2,%edi
  jle    L3
  sub    $0x8,%rsp
  mov    0x10(%rsi),%rax
  mov    0x8(%rsi),%rdi
  mov    %rax,%rsi
  call   <rc_bindkey@plt>
  add    $0x8,%rsp
  ret
L3:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cmd_bind(int argc, char **argv) {
  if (argc < 3)
    return -1;
  return rc_bindkey(argv[1], argv[2]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cmd_bind>:
  endbr64
  cmp    $0x2,%edi
  jle    L1
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  jmp    1050 <rc_bindkey@plt>
  nopl   0x0(%rax)
L1:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cmd_bind(int argc, char **argv) {
  if (argc < 3)
    return -1;
  return rc_bindkey(argv[1], argv[2]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmd_bind>:
  endbr64
  cmp    $0x2,%edi
  jle    L6
  mov    0x10(%rsi),%r8
  mov    0x8(%rsi),%rdi
  mov    %r8,%rsi
  jmp    1050 <rc_bindkey@plt>
  nopl   0x0(%rax)
L6:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int cmd_bind(int argc, char **argv) {
  if (argc < 3)
    return -1;
  return rc_bindkey(argv[1], argv[2]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_guessed: string
name: unpack_data
arguments: data_label: D25
type_guessed: string

tool: D16: %d

tool: D25:  e 

assistant: ```c
int main() {
  int x;
  int *endx;
  x = 0;
  printf("%d", x);
  printf(" e ");
  endx = &x;
  *endx = 1;
  printf("%d", x);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D10
data_type: string

tool: D15: %d

tool: D10:  e 

assistant: ```c
int main() {
  int x;
  int *endx;
  x = 0;
  printf("%d", x);
  printf(" e ");
  endx = &x;
  *endx = 1;
  printf("%d", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D8
type_guessed: string

tool: D16: %d

tool: D8:  e 

assistant: ```c
int main() {
  int x;
  int *endx;
  x = 0;
  printf("%d", x);
  printf(" e ");
  endx = &x;
  *endx = 1;
  printf("%d", x);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rbp
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string

tool: D13: %d

tool: D17:  e 

assistant: ```c
int main() {
  int x;
  int *endx;
  x = 0;
  printf("%d", x);
  printf(" e ");
  endx = &x;
  *endx = 1;
  printf("%d", x);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  lea    D119(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D114(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  D55(%rip),%xmm0
  movss  0xc(%rsp),%xmm1
  comiss D38(%rip),%xmm1
  jbe    L68
L21:
  pxor   %xmm1,%xmm1
  ucomiss 0x10(%rsp),%xmm1
  jp     L58
  jne    L58
  movss  0x14(%rsp),%xmm1
  movss  D126(%rip),%xmm2
  comiss %xmm1,%xmm2
  jbe    L54
  addss  %xmm0,%xmm0
L54:
  comiss D126(%rip),%xmm1
  jbe    L69
  mulss  D69(%rip),%xmm0
L69:
  cvtss2sd %xmm0,%xmm0
  lea    D80(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L68:
  movss  D71(%rip),%xmm0
  jmp    L21
L58:
  movss  D126(%rip),%xmm1
  comiss 0x14(%rsp),%xmm1
  jbe    L69
  mulss  D69(%rip),%xmm0
  jmp    L69
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D119
type_guessed: string
name: unpack_data
arguments: tag: D48
type_guessed: string
name: unpack_data
arguments: tag: D114
type_guessed: string
name: unpack_data
arguments: tag: D55
type_guessed: byte[4]
name: unpack_data
arguments: tag: D38
type_guessed: byte[4]
name: unpack_data
arguments: tag: D126
type_guessed: byte[4]
name: unpack_data
arguments: tag: D69
type_guessed: f32
name: unpack_data
arguments: tag: D80
type_guessed: string
name: unpack_data
arguments: tag: D71
type_guessed: f32

tool: D2: is the customer married (1=married, 0=unmarried)? 

tool: D119: %f

tool: D48: is the customer male or female (1=female, 0=male? 

tool: D114: What is the customer's age? 

tool: {"D55": [0x00,0x00,0xb4,0x42]}

tool: {"D38": [0x00,0x00,0x00,0x00]}

tool: {"D126": [0x00,0x00,0xc8,0x41]}

tool: D69: 1.5

tool: D80: The daily rate for the customer is:$%.2f

tool: D71: 100

assistant: ```c
int main() {
  float relation, gender, age, rate;
  rate = 100.00;
  printf("is the customer married (1=married, 0=unmarried)? \n");
  scanf("%f", &relation);
  printf("is the customer male or female (1=female, 0=male? \n");
  scanf("%f", &gender);
  printf("What is the customer's age? \n");
  scanf("%f", &age);
  if (relation > 0) {
    rate -= 10;
  }
  if (gender == 0) {
    if (age < 25)
      rate *= 2;
    if (age > 25)
      rate *= 1.5;
  } else {
    if (age < 25)
      rate *= 1.5;
  }
  printf("The daily rate for the customer is:$%.2f", rate);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  lea    D66(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D86(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movss  D79(%rip),%xmm0
  comiss %xmm1,%xmm2
  ja     L78
  movss  D40(%rip),%xmm0
L78:
  ucomiss 0x10(%rsp),%xmm1
  movss  0x14(%rsp),%xmm2
  movss  D44(%rip),%xmm1
  jp     L75
  jne    L75
  comiss %xmm2,%xmm1
  jbe    L16
  addss  %xmm0,%xmm0
L16:
  comiss D44(%rip),%xmm2
  ja     L57
L17:
  lea    D56(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L75:
  comiss %xmm2,%xmm1
  jbe    L17
L57:
  mulss  D29(%rip),%xmm0
  jmp    L17
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D38
type_guessed: string
name: disassemble_data
arguments: data_label: D66
type_guessed: string
name: disassemble_data
arguments: data_label: D86
type_guessed: string
name: disassemble_data
arguments: data_label: D21
type_guessed: string
name: disassemble_data
arguments: data_label: D79
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D40
type_guessed: f32
name: disassemble_data
arguments: data_label: D44
type_guessed: byte[4]
name: disassemble_data
arguments: data_label: D56
type_guessed: string
name: disassemble_data
arguments: data_label: D29
type_guessed: f32

tool: D38: is the customer married (1=married, 0=unmarried)? 

tool: D66: %f

tool: D86: is the customer male or female (1=female, 0=male? 

tool: D21: What is the customer's age? 

tool: {"D79": [0x00,0x00,0xb4,0x42]}

tool: D40: 100

tool: {"D44": [0x00,0x00,0xc8,0x41]}

tool: D56: The daily rate for the customer is:$%.2f

tool: D29: 1.5

assistant: ```c
int main() {
  float relation, gender, age, rate;
  rate = 100.00;
  printf("is the customer married (1=married, 0=unmarried)? \n");
  scanf("%f", &relation);
  printf("is the customer male or female (1=female, 0=male? \n");
  scanf("%f", &gender);
  printf("What is the customer's age? \n");
  scanf("%f", &age);
  if (relation > 0) {
    rate -= 10;
  }
  if (gender == 0) {
    if (age < 25)
      rate *= 2;
    if (age > 25)
      rate *= 1.5;
  } else {
    if (age < 25)
      rate *= 1.5;
  }
  printf("The daily rate for the customer is:$%.2f", rate);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D83(%rip),%rdi
  lea    D22(%rip),%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D58(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm2
  pxor   %xmm1,%xmm1
  movss  D62(%rip),%xmm0
  comiss %xmm1,%xmm2
  ja     L49
  movss  D70(%rip),%xmm0
L49:
  ucomiss 0x10(%rsp),%xmm1
  movss  0x14(%rsp),%xmm2
  movss  D13(%rip),%xmm1
  jp     L15
  jne    L15
  comiss %xmm2,%xmm1
  jbe    L4
  addss  %xmm0,%xmm0
L4:
  comiss D13(%rip),%xmm2
  ja     L30
L68:
  lea    D79(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L15:
  comiss %xmm2,%xmm1
  jbe    L68
L30:
  mulss  D14(%rip),%xmm0
  jmp    L68
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D83
datatype: string
name: parse_data
arguments: label: D22
datatype: string
name: parse_data
arguments: label: D45
datatype: string
name: parse_data
arguments: label: D58
datatype: string
name: parse_data
arguments: label: D62
datatype: byte[4]
name: parse_data
arguments: label: D70
datatype: f32
name: parse_data
arguments: label: D13
datatype: byte[4]
name: parse_data
arguments: label: D79
datatype: string
name: parse_data
arguments: label: D14
datatype: f32

tool: D83: is the customer married (1=married, 0=unmarried)? 

tool: D22: %f

tool: D45: is the customer male or female (1=female, 0=male? 

tool: D58: What is the customer's age? 

tool: {"D62": [0x00,0x00,0xb4,0x42]}

tool: D70: 100

tool: {"D13": [0x00,0x00,0xc8,0x41]}

tool: D79: The daily rate for the customer is:$%.2f

tool: D14: 1.5

assistant: ```c
int main() {
  float relation, gender, age, rate;
  rate = 100.00;
  printf("is the customer married (1=married, 0=unmarried)? \n");
  scanf("%f", &relation);
  printf("is the customer male or female (1=female, 0=male? \n");
  scanf("%f", &gender);
  printf("What is the customer's age? \n");
  scanf("%f", &age);
  if (relation > 0) {
    rate -= 10;
  }
  if (gender == 0) {
    if (age < 25)
      rate *= 2;
    if (age > 25)
      rate *= 1.5;
  } else {
    if (age < 25)
      rate *= 1.5;
  }
  printf("The daily rate for the customer is:$%.2f", rate);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<update_CRCDAB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L8
L24:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  and    $0x80,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  cmpl   $0x0,-0x4(%rbp)
  sete   %dl
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  sete   %al
  xor    %edx,%eax
  test   %al,%al
  je     L8
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  xor    $0x1d,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
L8:
  shrl   -0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L24
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  movzbl %al,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_CRCDAB(unsigned int data, unsigned int length, unsigned int *crc) {
  unsigned int masking, carry;
  masking = 1 << length;
  while ((masking >>= 1)) {
    carry = *crc & 0x80;
    *crc <<= 1;
    if (!carry ^ !(data & masking))
      *crc ^= 0x1D;
  }
  *crc &= 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<update_CRCDAB>:
  endbr64
  mov    $0x1,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  mov    %eax,%ecx
  shr    %ecx
  je     L18
  mov    (%rdx),%eax
L9:
  mov    %eax,%esi
  and    $0x80,%esi
  add    %eax,%eax
  test   %esi,%esi
  sete   %r9b
  test   %ecx,%edi
  sete   %r8b
  mov    %eax,%esi
  xor    $0x1d,%esi
  cmp    %r8b,%r9b
  cmovne %esi,%eax
  shr    %ecx
  jne    L9
  mov    %eax,(%rdx)
L18:
  andl   $0xff,(%rdx)
  ret
```

assistant: ```c
void update_CRCDAB(unsigned int data, unsigned int length, unsigned int *crc) {
  unsigned int masking, carry;
  masking = 1 << length;
  while ((masking >>= 1)) {
    carry = *crc & 0x80;
    *crc <<= 1;
    if (!carry ^ !(data & masking))
      *crc ^= 0x1D;
  }
  *crc &= 0xff;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_CRCDAB>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%ecx
  mov    (%rdx),%eax
  shr    %ecx
  je     L9
  nopl   (%rax)
L19:
  mov    %eax,%esi
  add    %eax,%eax
  and    $0x80,%esi
  test   %esi,%esi
  mov    %eax,%esi
  sete   %r9b
  test   %ecx,%edi
  sete   %r8b
  xor    $0x1d,%esi
  cmp    %r8b,%r9b
  cmovne %esi,%eax
  shr    %ecx
  jne    L19
L9:
  and    $0xff,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void update_CRCDAB(unsigned int data, unsigned int length, unsigned int *crc) {
  unsigned int masking, carry;
  masking = 1 << length;
  while ((masking >>= 1)) {
    carry = *crc & 0x80;
    *crc <<= 1;
    if (!carry ^ !(data & masking))
      *crc ^= 0x1D;
  }
  *crc &= 0xff;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<update_CRCDAB>:
  endbr64
  mov    %esi,%ecx
  mov    $0x1,%eax
  shl    %cl,%eax
  mov    %eax,%ecx
  mov    (%rdx),%eax
  shr    %ecx
  je     L8
  nopl   (%rax)
L5:
  mov    %eax,%esi
  add    %eax,%eax
  and    $0x80,%esi
  test   %esi,%esi
  mov    %eax,%esi
  sete   %r9b
  test   %ecx,%edi
  sete   %r8b
  xor    $0x1d,%esi
  cmp    %r8b,%r9b
  cmovne %esi,%eax
  shr    %ecx
  jne    L5
L8:
  and    $0xff,%eax
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void update_CRCDAB(unsigned int data, unsigned int length, unsigned int *crc) {
  unsigned int masking, carry;
  masking = 1 << length;
  while ((masking >>= 1)) {
    carry = *crc & 0x80;
    *crc <<= 1;
    if (!carry ^ !(data & masking))
      *crc ^= 0x1D;
  }
  *crc &= 0xff;
}
```