ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L28
  mov    $0x1,%ecx
  mov    $0x0,%edi
L5:
  mov    %eax,%esi
  shr    $0x1f,%esi
  lea    (%rax,%rsi,1),%edx
  and    $0x1,%edx
  sub    %esi,%edx
  mov    %eax,%esi
  mov    %eax,%r8d
  shr    $0x1f,%r8d
  add    %r8d,%eax
  sar    %eax
  imul   %ecx,%edx
  add    %edx,%edi
  lea    (%rcx,%rcx,4),%ecx
  add    %ecx,%ecx
  cmp    $0x1,%esi
  jg     L5
  mov    %eax,0x4(%rsp)
L32:
  mov    %edi,%esi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L28:
  mov    $0x0,%edi
  jmp    L32
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
type_infered: string
name: retrieve_data
arguments: label: D14
type_infered: string
name: retrieve_data
arguments: label: D11
type_infered: string

tool: D12: entre com um numero inteiro: 

tool: D14: %d

tool: D11: %d


assistant: ```c
int main() {
  int num, bin = 0, pot10 = 1, rest;
  printf("entre com um numero inteiro: ");
  scanf("%d", &num);
  while (num > 0) {
    rest = num % 2;
    num = num / 2;
    bin = bin + rest * pot10;
    pot10 = pot10 * 10;
  }
  printf("%d\n", bin);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L23
  mov    $0x1,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L31:
  mov    %edx,%ecx
  and    $0x1,%ecx
  imul   %eax,%ecx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %ecx,%esi
  sar    %edx
  jne    L31
  movl   $0x0,0x4(%rsp)
L25:
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  xor    %esi,%esi
  jmp    L25
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string
name: read_data
arguments: data_tag: D27
datatype: string

tool: D19: entre com um numero inteiro: 

tool: D5: %d

tool: D27: %d


assistant: ```c
int main() {
  int num, bin = 0, pot10 = 1, rest;
  printf("entre com um numero inteiro: ");
  scanf("%d", &num);
  while (num > 0) {
    rest = num % 2;
    num = num / 2;
    bin = bin + rest * pot10;
    pot10 = pot10 * 10;
  }
  printf("%d\n", bin);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L30
  mov    $0x1,%eax
  xor    %esi,%esi
  nopl   0x0(%rax)
L1:
  mov    %edx,%ecx
  and    $0x1,%ecx
  imul   %eax,%ecx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  add    %ecx,%esi
  sar    %edx
  jne    L1
  movl   $0x0,0x4(%rsp)
L26:
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L30:
  xor    %esi,%esi
  jmp    L26
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D13
type_guessed: string
name: disassemble_data
arguments: label: D4
type_guessed: string
name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D13: entre com um numero inteiro: 

tool: D4: %d

tool: D2: %d


assistant: ```c
int main() {
  int num, bin = 0, pot10 = 1, rest;
  printf("entre com um numero inteiro: ");
  scanf("%d", &num);
  while (num > 0) {
    rest = num % 2;
    num = num / 2;
    bin = bin + rest * pot10;
    pot10 = pot10 * 10;
  }
  printf("%d\n", bin);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<gameOfLife>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,-0x4(%rsp)
  mov    %edx,%r15d
  lea    -0x1(%rsi),%ebx
  mov    %rbx,-0x18(%rsp)
  mov    %esi,%ebx
  mov    %rbx,-0x10(%rsp)
  mov    $0x0,%r14d
  lea    0x2(%rdx),%ebx
  mov    %ebx,-0x8(%rsp)
  test   %esi,%esi
  jg     L100
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    $0x0,%ecx
  jmp    L165
L89:
  or     $0x2,%eax
  mov    %eax,(%rdx)
L88:
  add    $0x4,%r12
  add    $0x1,%ebp
  cmp    -0x8(%rsp),%ebp
  je     L122
L93:
  lea    -0x2(%rbp),%r8d
  mov    -0x24(%rsp),%edi
  cmp    %edi,-0x28(%rsp)
  jg     L6
  test   %r8d,%r8d
  mov    $0x1,%eax
  cmovle %eax,%r8d
  cmp    %r15d,%ebp
  mov    %r15d,%r11d
  cmovle %ebp,%r11d
  lea    -0x1(%r8),%r10d
  movslq %r10d,%r10
  shl    $0x2,%r10
  mov    %r11d,%r9d
  sub    %r8d,%r9d
  movslq %r8d,%rax
  add    %rax,%r9
  shl    $0x2,%r9
  mov    -0x20(%rsp),%rdi
  mov    $0x0,%ecx
L126:
  cmp    %r11d,%r8d
  jg     L112
  mov    (%rdi),%rsi
  lea    (%rsi,%r10,1),%rax
  add    %r9,%rsi
L137:
  mov    (%rax),%edx
  and    $0x1,%edx
  add    %edx,%ecx
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L137
L112:
  add    $0x8,%rdi
  cmp    %rbx,%rdi
  jne    L126
L165:
  mov    %r12,%rdx
  add    0x0(%r13,%r14,8),%rdx
  mov    (%rdx),%eax
  sub    %eax,%ecx
  cmp    $0x3,%ecx
  je     L89
  cmp    $0x2,%ecx
  jne    L88
  test   %eax,%eax
  je     L88
  jmp    L89
L122:
  add    $0x1,%r14
  cmp    -0x10(%rsp),%r14
  je     L41
L100:
  test   %r15d,%r15d
  jle    L122
  test   %r14d,%r14d
  mov    $0x1,%eax
  mov    %eax,%ebx
  cmovg  %r14d,%ebx
  mov    %ebx,-0x28(%rsp)
  lea    0x2(%r14),%eax
  mov    -0x4(%rsp),%edi
  cmp    %edi,%eax
  cmovg  %edi,%eax
  mov    %eax,%edi
  mov    %eax,-0x24(%rsp)
  lea    -0x1(%rbx),%eax
  cltq
  lea    0x0(%r13,%rax,8),%rax
  mov    %rax,-0x20(%rsp)
  mov    %edi,%eax
  sub    %ebx,%eax
  movslq %ebx,%rdx
  add    %rdx,%rax
  lea    0x0(%r13,%rax,8),%rbx
  mov    $0x2,%ebp
  mov    $0x0,%r12d
  jmp    L93
L41:
  mov    %r13,%rcx
  mov    -0x18(%rsp),%rax
  lea    0x8(%r13,%rax,8),%rdi
  lea    -0x1(%r15),%eax
  lea    0x4(,%rax,4),%rsi
  jmp    L149
L64:
  mov    %rax,%rdx
  add    (%rcx),%rdx
  sarl   (%rdx)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L64
L98:
  add    $0x8,%rcx
  cmp    %rcx,%rdi
  je     L47
L149:
  mov    $0x0,%eax
  test   %r15d,%r15d
  jg     L64
  jmp    L98
```

assistant: ```c
void gameOfLife(int **board, int rSize, int cSize) {
  for (int i = 0; i < rSize; i++)
    for (int j = 0; j < cSize; j++) {
      int count = 0;
      for (int rr = ((i - 1) > (0) ? (i - 1) : (0)); rr < ((i + 2) < (rSize) ? (i + 2) : (rSize)); rr++)
        for (int cc = ((j - 1) > (0) ? (j - 1) : (0)); cc < ((j + 2) < (cSize) ? (j + 2) : (cSize)); cc++)
          count += board[rr][cc] & 1;
      count -= board[i][j];
      if (count == 3 || (board[i][j] && count == 2))
        board[i][j] |= 2;
    }
  for (int i = 0; i < rSize; i++)
    for (int j = 0; j < cSize; j++)
      board[i][j] >>= 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gameOfLife>:
  endbr64
  push   %r15
  mov    %edx,%r15d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  mov    %rbx,-0x18(%rsp)
  mov    %esi,%ebx
  mov    %rbx,-0x10(%rsp)
  movslq %edx,%rbx
  mov    %rdi,-0x20(%rsp)
  mov    %esi,-0x4(%rsp)
  movq   $0x0,-0x28(%rsp)
  mov    %rbx,-0x38(%rsp)
  test   %esi,%esi
  jle    L105
L137:
  test   %r15d,%r15d
  jle    L101
  mov    -0x28(%rsp),%rbx
  mov    -0x20(%rsp),%rdi
  mov    $0x1,%eax
  test   %ebx,%ebx
  lea    0x2(%rbx),%r13d
  mov    (%rdi,%rbx,8),%r12
  cmovg  %ebx,%eax
  mov    -0x4(%rsp),%ebx
  cmp    %ebx,%r13d
  lea    -0x1(%rax),%r14d
  cmovg  %ebx,%r13d
  movslq %r14d,%rdx
  xor    %ebp,%ebp
  lea    (%rdi,%rdx,8),%rbx
  mov    %r13d,%edx
  mov    %rbx,-0x30(%rsp)
  sub    %eax,%edx
  cltq
  add    %rdx,%rax
  lea    (%rdi,%rax,8),%rbx
  nopw   0x0(%rax,%rax,1)
L3:
  cmp    %r13d,%r14d
  jge    L92
  test   %ebp,%ebp
  lea    0x2(%rbp),%r8d
  mov    $0x1,%eax
  mov    -0x30(%rsp),%rdi
  cmovg  %ebp,%eax
  cmp    %r15d,%r8d
  cmovg  %r15d,%r8d
  xor    %ecx,%ecx
  lea    -0x1(%rax),%r10d
  mov    %r8d,%r9d
  movslq %r10d,%r11
  sub    %eax,%r9d
  cltq
  shl    $0x2,%r11
  add    %rax,%r9
  shl    $0x2,%r9
  nopw   0x0(%rax,%rax,1)
L50:
  cmp    %r8d,%r10d
  jge    L49
  mov    (%rdi),%rsi
  lea    (%rsi,%r11,1),%rax
  add    %r9,%rsi
  nop
L12:
  mov    (%rax),%edx
  add    $0x4,%rax
  and    $0x1,%edx
  add    %edx,%ecx
  cmp    %rsi,%rax
  jne    L12
L49:
  add    $0x8,%rdi
  cmp    %rbx,%rdi
  jne    L50
L46:
  mov    (%r12,%rbp,4),%eax
  sub    %eax,%ecx
  cmp    $0x3,%ecx
  je     L86
  cmp    $0x2,%ecx
  jne    L106
  test   %eax,%eax
  jne    L86
L106:
  add    $0x1,%rbp
  cmp    -0x38(%rsp),%rbp
  jne    L3
L101:
  addq   $0x1,-0x28(%rsp)
  mov    -0x28(%rsp),%rax
  cmp    -0x10(%rsp),%rax
  jne    L137
  mov    -0x18(%rsp),%rax
  mov    -0x20(%rsp),%rcx
  lea    0x8(%rcx,%rax,8),%rdi
  lea    -0x1(%r15),%eax
  lea    0x4(,%rax,4),%rsi
L20:
  test   %r15d,%r15d
  jle    L24
  mov    (%rcx),%rax
  lea    (%rsi,%rax,1),%rdx
  nopl   0x0(%rax)
L94:
  sarl   (%rax)
  add    $0x4,%rax
  cmp    %rax,%rdx
  jne    L94
L24:
  add    $0x8,%rcx
  cmp    %rdi,%rcx
  jne    L20
L105:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L86:
  or     $0x2,%eax
  mov    %eax,(%r12,%rbp,4)
  jmp    L106
L92:
  xor    %ecx,%ecx
  jmp    L46
```

assistant: ```c
void gameOfLife(int **board, int rSize, int cSize) {
  for (int i = 0; i < rSize; i++)
    for (int j = 0; j < cSize; j++) {
      int count = 0;
      for (int rr = ((i - 1) > (0) ? (i - 1) : (0)); rr < ((i + 2) < (rSize) ? (i + 2) : (rSize)); rr++)
        for (int cc = ((j - 1) > (0) ? (j - 1) : (0)); cc < ((j + 2) < (cSize) ? (j + 2) : (cSize)); cc++)
          count += board[rr][cc] & 1;
      count -= board[i][j];
      if (count == 3 || (board[i][j] && count == 2))
        board[i][j] |= 2;
    }
  for (int i = 0; i < rSize; i++)
    for (int j = 0; j < cSize; j++)
      board[i][j] >>= 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  lea    D20(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  lea    D21(%rip),%r15
  lea    0x30(%rsp),%r14
  lea    D15(%rip),%r13
L2:
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rbx
  lea    (%r14,%r12,1),%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%ebp
  add    $0x4,%r12
  cmp    $0x5,%ebp
  jne    L2
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D60(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  mov    $0x0,%edx
  pxor   %xmm1,%xmm1
  lea    0x30(%rsp),%rcx
  jmp    L9
L31:
  add    $0x1,%rax
  cmp    $0x5,%rax
  je     L76
L30:
  cmp    %edx,%eax
  je     L31
  movss  0x10(%rsp,%rax,4),%xmm4
  movaps %xmm0,%xmm3
  subss  %xmm4,%xmm3
  mulss  %xmm3,%xmm2
  movss  (%rbx),%xmm3
  subss  %xmm4,%xmm3
  divss  %xmm3,%xmm2
  jmp    L31
L76:
  mulss  (%rcx,%rdx,4),%xmm2
  addss  %xmm2,%xmm1
  add    $0x1,%rdx
  add    $0x4,%rbx
  cmp    $0x5,%rdx
  je     L12
L9:
  mov    $0x0,%eax
  movss  D16(%rip),%xmm2
  jmp    L30
L12:
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D64(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D20
type_guessed: string
name: disassemble_data
arguments: data_tag: D21
type_guessed: string
name: disassemble_data
arguments: data_tag: D15
type_guessed: string
name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D60
type_guessed: string
name: disassemble_data
arguments: data_tag: D16
type_guessed: f32
name: disassemble_data
arguments: data_tag: D64
type_guessed: string

tool: D20: Enter the (x,y) values:

tool: D21: Enter (X%d,Y%d): 

tool: D15: %f %f

tool: D7: Enter the value to interpolate: 

tool: D60: %f

tool: D16: 1

tool: D64: Interpolated value corresponding %f = %f


assistant: ```c
int main() {
  int i, j;
  float X[5], Y[5], Xin = 0.0f, poly = 0, temp = 1;
  printf("Enter the (x,y) values:\n");
  for (i = 0; i < 5; ++i) {
    printf("Enter (X%d,Y%d): ", i, i);
    scanf("%f %f", &X[i], &Y[i]);
    putchar('\n');
  }
  printf("Enter the value to interpolate: ");
  scanf("%f", &Xin);
  for (i = 0; i < 5; ++i) {
    temp = 1;
    for (j = 0; j < 5; ++j) {
      if (i != j) {
        temp = temp * (Xin - X[j]);
        temp = temp / ((X[i] - X[j]));
      }
    }
    temp = temp * Y[i];
    poly = poly + temp;
  }
  printf("Interpolated value corresponding %f = %f\n", Xin, poly);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r15
  lea    D16(%rip),%rdi
  lea    D44(%rip),%r15
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x30(%rsp),%r12
  movl   $0x0,0xc(%rsp)
  call   <puts@plt>
L0:
  mov    %r14d,%edx
  mov    %r14d,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    (%r12,%r13,1),%rdx
  lea    0x0(%rbp,%r13,1),%rsi
  xor    %eax,%eax
  lea    D3(%rip),%rdi
  add    $0x1,%r14d
  mov    %rbp,%rbx
  add    $0x4,%r13
  call   <scanf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x5,%r14d
  jne    L0
  lea    D36(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  xor    %edx,%edx
  pxor   %xmm1,%xmm1
L13:
  movss  D49(%rip),%xmm2
  xor    %eax,%eax
L17:
  cmp    %eax,%edx
  je     L45
  movss  0x0(%rbp,%rax,4),%xmm4
  movaps %xmm0,%xmm3
  subss  %xmm4,%xmm3
  mulss  %xmm3,%xmm2
  movss  (%rbx),%xmm3
  subss  %xmm4,%xmm3
  divss  %xmm3,%xmm2
L45:
  add    $0x1,%rax
  cmp    $0x5,%rax
  jne    L17
  mulss  (%r12,%rdx,4),%xmm2
  add    $0x1,%rdx
  add    $0x4,%rbx
  addss  %xmm2,%xmm1
  cmp    $0x5,%rdx
  jne    L13
  lea    D25(%rip),%rdi
  mov    $0x2,%eax
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x58,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D16
type_guessed: string
name: parse_data
arguments: tag: D44
type_guessed: string
name: parse_data
arguments: tag: D3
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string
name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D49
type_guessed: f32
name: parse_data
arguments: tag: D25
type_guessed: string

tool: D16: Enter the (x,y) values:

tool: D44: Enter (X%d,Y%d): 

tool: D3: %f %f

tool: D36: Enter the value to interpolate: 

tool: D24: %f

tool: D49: 1

tool: D25: Interpolated value corresponding %f = %f


assistant: ```c
int main() {
  int i, j;
  float X[5], Y[5], Xin = 0.0f, poly = 0, temp = 1;
  printf("Enter the (x,y) values:\n");
  for (i = 0; i < 5; ++i) {
    printf("Enter (X%d,Y%d): ", i, i);
    scanf("%f %f", &X[i], &Y[i]);
    putchar('\n');
  }
  printf("Enter the value to interpolate: ");
  scanf("%f", &Xin);
  for (i = 0; i < 5; ++i) {
    temp = 1;
    for (j = 0; j < 5; ++j) {
      if (i != j) {
        temp = temp * (Xin - X[j]);
        temp = temp / ((X[i] - X[j]));
      }
    }
    temp = temp * Y[i];
    poly = poly + temp;
  }
  printf("Interpolated value corresponding %f = %f\n", Xin, poly);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tx_wcoloreol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getyx@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <getmaxyx@plt>
  mov    -0x18(%rbp),%eax
  sub    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x12(%rbp),%rax
  lea    D4(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <scrollok@plt>
  lea    -0x12(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <wprintw@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
datatype: string

tool: D4: %%%dc

assistant: ```c
void tx_wcoloreol(WINDOW *win) {
  int y, x;
  int cury, curx;
  char sp_buf[10];
  getyx(win, cury, curx);
  getmaxyx(win, y, x);
  sprintf(sp_buf, "%%%dc", x - curx - 1);
  scrollok(win, 0);
  wprintw(win, sp_buf, ' ');
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tx_wcoloreol>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    %ebp,%edx
  mov    $0x0,%esi
  call   <getyx@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <getmaxyx@plt>
  mov    %ebp,%edx
  not    %edx
  lea    0xe(%rsp),%rbp
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <scrollok@plt>
  mov    $0x20,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <wprintw@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
datatype: string

tool: D8: %%%dc

assistant: ```c
void tx_wcoloreol(WINDOW *win) {
  int y, x;
  int cury, curx;
  char sp_buf[10];
  getyx(win, cury, curx);
  getmaxyx(win, y, x);
  sprintf(sp_buf, "%%%dc", x - curx - 1);
  scrollok(win, 0);
  wprintw(win, sp_buf, ' ');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tx_wcoloreol>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,%edx
  not    %ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  call   <getyx@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <getmaxyx@plt>
  mov    %ebx,%edx
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <scrollok@plt>
  mov    $0x20,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wprintw@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type_guessed: string

tool: D5: %%%dc

assistant: ```c
void tx_wcoloreol(WINDOW *win) {
  int y, x;
  int cury, curx;
  char sp_buf[10];
  getyx(win, cury, curx);
  getmaxyx(win, y, x);
  sprintf(sp_buf, "%%%dc", x - curx - 1);
  scrollok(win, 0);
  wprintw(win, sp_buf, ' ');
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tx_wcoloreol>:
  endbr64
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  mov    %ebx,%edx
  not    %ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  call   <getyx@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <getmaxyx@plt>
  mov    %ebx,%edx
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <scrollok@plt>
  mov    $0x20,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <wprintw@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: %%%dc

assistant: ```c
void tx_wcoloreol(WINDOW *win) {
  int y, x;
  int cury, curx;
  char sp_buf[10];
  getyx(win, cury, curx);
  getmaxyx(win, y, x);
  sprintf(sp_buf, "%%%dc", x - curx - 1);
  scrollok(win, 0);
  wprintw(win, sp_buf, ' ');
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L37
L4:
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L26:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    $0x7c,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L37:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D17
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string

tool: D17: 
|

tool: D2: %12.2f

assistant: ```c
void print_array(double **m, int dim) {
  int row, col;
  for (row = 0; row < dim; row++) {
    printf("\n|");
    for (col = 0; col < dim; col++)
      printf("%12.2f", m[row][col]);
    printf("|");
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_array>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L4
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r15
  mov    %esi,%esi
  lea    0x0(,%rsi,8),%r12
  lea    D13(%rip),%r14
  lea    D0(%rip),%r13
L1:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
L15:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,1),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L15
  mov    $0x7c,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  jne    L1
L4:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D13
type_infered: string
name: read_data
arguments: label: D0
type_infered: string

tool: D13: 
|

tool: D0: %12.2f

assistant: ```c
void print_array(double **m, int dim) {
  int row, col;
  for (row = 0; row < dim; row++) {
    printf("\n|");
    for (col = 0; col < dim; col++)
      printf("%12.2f", m[row][col]);
    printf("|");
  }
  printf("\n");
}
```