ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<basCircle>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%edi
  mov    %ebp,%edx
  mov    %ebx,%esi
  call   <circle@plt>
  mov    %eax,%edi
  call   <pushNumber@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void basCircle() {
  int x, y, r;
  r = popNumber();
  y = popNumber();
  x = popNumber();
  pushNumber(circle(x, y, r));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<basCircle>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <popNumber@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <circle@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    1070 <pushNumber@plt>
```

assistant: ```c
void basCircle() {
  int x, y, r;
  r = popNumber();
  y = popNumber();
  x = popNumber();
  pushNumber(circle(x, y, r));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basCircle>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  sub    $0x8,%rsp
  call   <popNumber@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <circle@plt>
  add    $0x8,%rsp
  pop    %rbp
  mov    %eax,%edi
  pop    %r12
  jmp    1070 <pushNumber@plt>
```

assistant: ```c
void basCircle() {
  int x, y, r;
  r = popNumber();
  y = popNumber();
  x = popNumber();
  pushNumber(circle(x, y, r));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clear_4d_facets>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x249,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int clear_4d_facets(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(585, a, b, c);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<clear_4d_facets>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x249,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int clear_4d_facets(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(585, a, b, c);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<clear_4d_facets>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x249,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int clear_4d_facets(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(585, a, b, c);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<clear_4d_facets>:
  endbr64
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x249,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int clear_4d_facets(void) {
  int fail, *a, *b;
  double *c;
  fail = _ada_use_c2phc(585, a, b, c);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4,%edi
  call   <f1@plt>
  mov    $0x3,%edi
  call   <f1@plt>
  mov    $0x5,%edi
  call   <f1@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  f1(4);
  f1(3);
  f1(5);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <f1@plt>
  mov    $0x3,%edi
  call   <f1@plt>
  mov    $0x5,%edi
  call   <f1@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f1(4);
  f1(3);
  f1(5);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <f1@plt>
  mov    $0x3,%edi
  call   <f1@plt>
  mov    $0x5,%edi
  call   <f1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f1(4);
  f1(3);
  f1(5);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%edi
  call   <f1@plt>
  mov    $0x3,%edi
  call   <f1@plt>
  mov    $0x5,%edi
  call   <f1@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  f1(4);
  f1(3);
  f1(5);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<oid_part_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L4
L19:
  sarl   $0x7,-0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0x7f,-0x14(%rbp)
  jg     L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int oid_part_length(int part) {
  int len = 1;
  while (part > 127) {
    part >>= 7;
    len++;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<oid_part_length>:
  endbr64
  cmp    $0x7f,%edi
  jle    L5
  mov    $0x1,%eax
L18:
  sar    $0x7,%edi
  add    $0x1,%eax
  cmp    $0x7f,%edi
  jg     L18
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int oid_part_length(int part) {
  int len = 1;
  while (part > 127) {
    part >>= 7;
    len++;
  }
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<oid_part_length>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L6
  xchg   %ax,%ax
L16:
  sar    $0x7,%edi
  add    $0x1,%eax
  cmp    $0x7f,%edi
  jg     L16
  ret
  nopl   0x0(%rax)
L6:
  ret
```

assistant: ```c
int oid_part_length(int part) {
  int len = 1;
  while (part > 127) {
    part >>= 7;
    len++;
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<oid_part_length>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x7f,%edi
  jle    L1
  xchg   %ax,%ax
L15:
  sar    $0x7,%edi
  add    $0x1,%eax
  cmp    $0x7f,%edi
  jg     L15
  ret
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
int oid_part_length(int part) {
  int len = 1;
  while (part > 127) {
    part >>= 7;
    len++;
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<glmMultVectorByScalar4f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movss  %xmm0,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mulss  -0xc(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  mulss  -0xc(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void glmMultVectorByScalar4f(float v[4], float a) {
  v[0] *= a;
  v[1] *= a;
  v[2] *= a;
  v[3] *= a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<glmMultVectorByScalar4f>:
  endbr64
  movaps %xmm0,%xmm1
  mulss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x4(%rdi),%xmm1
  movss  %xmm1,0x4(%rdi)
  movaps %xmm0,%xmm1
  mulss  0x8(%rdi),%xmm1
  movss  %xmm1,0x8(%rdi)
  mulss  0xc(%rdi),%xmm0
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void glmMultVectorByScalar4f(float v[4], float a) {
  v[0] *= a;
  v[1] *= a;
  v[2] *= a;
  v[3] *= a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<glmMultVectorByScalar4f>:
  endbr64
  movss  (%rdi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,(%rdi)
  movss  0x4(%rdi),%xmm1
  mulss  %xmm0,%xmm1
  movss  %xmm1,0x4(%rdi)
  movss  0x8(%rdi),%xmm1
  mulss  %xmm0,%xmm1
  mulss  0xc(%rdi),%xmm0
  movss  %xmm1,0x8(%rdi)
  movss  %xmm0,0xc(%rdi)
  ret
```

assistant: ```c
void glmMultVectorByScalar4f(float v[4], float a) {
  v[0] *= a;
  v[1] *= a;
  v[2] *= a;
  v[3] *= a;
}
```
user: What is the c source code of the assembly code below:

```asm
<glmMultVectorByScalar4f>:
  endbr64
  movups (%rdi),%xmm1
  shufps $0x0,%xmm0,%xmm0
  mulps  %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void glmMultVectorByScalar4f(float v[4], float a) {
  v[0] *= a;
  v[1] *= a;
  v[2] *= a;
  v[3] *= a;
}
```
user: What is the c source code of the assembly code below?

```asm
<mulmvv>:
  endbr64
  movsd  (%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x28(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x30(%rdi)
  movq   $0x0,0x38(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x40(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x48(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x50(%rdi)
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movq   $0x0,0x70(%rdi)
  mov    D2(%rip),%rcx
  mov    %rcx,0x78(%rdi)
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void mulmvv(double *dest, const double *s1, const double *s2) {
  dest[(0 + (0 << 2))] = s1[0] * s2[0];
  dest[(1 + (0 << 2))] = s1[1] * s2[0];
  dest[(2 + (0 << 2))] = s1[2] * s2[0];
  dest[(3 + (0 << 2))] = 0;
  dest[(0 + (1 << 2))] = s1[0] * s2[1];
  dest[(1 + (1 << 2))] = s1[1] * s2[1];
  dest[(2 + (1 << 2))] = s1[2] * s2[1];
  dest[(3 + (1 << 2))] = 0;
  dest[(0 + (2 << 2))] = s1[0] * s2[2];
  dest[(1 + (2 << 2))] = s1[1] * s2[2];
  dest[(2 + (2 << 2))] = s1[2] * s2[2];
  dest[(3 + (2 << 2))] = 0;
  dest[(0 + (3 << 2))] = 0;
  dest[(1 + (3 << 2))] = 0;
  dest[(2 + (3 << 2))] = 0;
  dest[(3 + (3 << 2))] = 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mulmvv>:
  endbr64
  movsd  (%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movq   $0x0,0x18(%rdi)
  movsd  %xmm0,0x10(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x28(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movq   $0x0,0x38(%rdi)
  movsd  %xmm0,0x30(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x40(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x48(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movsd  %xmm0,0x50(%rdi)
  movq   $0x0,0x70(%rdi)
  mov    D3(%rip),%rcx
  mov    %rcx,0x78(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type_guessed: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void mulmvv(double *dest, const double *s1, const double *s2) {
  dest[(0 + (0 << 2))] = s1[0] * s2[0];
  dest[(1 + (0 << 2))] = s1[1] * s2[0];
  dest[(2 + (0 << 2))] = s1[2] * s2[0];
  dest[(3 + (0 << 2))] = 0;
  dest[(0 + (1 << 2))] = s1[0] * s2[1];
  dest[(1 + (1 << 2))] = s1[1] * s2[1];
  dest[(2 + (1 << 2))] = s1[2] * s2[1];
  dest[(3 + (1 << 2))] = 0;
  dest[(0 + (2 << 2))] = s1[0] * s2[2];
  dest[(1 + (2 << 2))] = s1[1] * s2[2];
  dest[(2 + (2 << 2))] = s1[2] * s2[2];
  dest[(3 + (2 << 2))] = 0;
  dest[(0 + (3 << 2))] = 0;
  dest[(1 + (3 << 2))] = 0;
  dest[(2 + (3 << 2))] = 0;
  dest[(3 + (3 << 2))] = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mulmvv>:
  endbr64
  movsd  (%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movsd  %xmm0,0x8(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  (%rdx),%xmm0
  movq   $0x0,0x18(%rdi)
  movsd  %xmm0,0x10(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x20(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movsd  %xmm0,0x28(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  0x8(%rdx),%xmm0
  movq   $0x0,0x38(%rdi)
  movsd  %xmm0,0x30(%rdi)
  movsd  (%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x40(%rdi)
  movsd  0x8(%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movsd  %xmm0,0x48(%rdi)
  movsd  0x10(%rsi),%xmm0
  mulsd  0x10(%rdx),%xmm0
  movq   $0x0,0x58(%rdi)
  movq   $0x0,0x60(%rdi)
  movq   $0x0,0x68(%rdi)
  movsd  %xmm0,0x50(%rdi)
  movq   $0x0,0x70(%rdi)
  mov    D0(%rip),%rcx
  mov    %rcx,0x78(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_infered: byte[8]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
void mulmvv(double *dest, const double *s1, const double *s2) {
  dest[(0 + (0 << 2))] = s1[0] * s2[0];
  dest[(1 + (0 << 2))] = s1[1] * s2[0];
  dest[(2 + (0 << 2))] = s1[2] * s2[0];
  dest[(3 + (0 << 2))] = 0;
  dest[(0 + (1 << 2))] = s1[0] * s2[1];
  dest[(1 + (1 << 2))] = s1[1] * s2[1];
  dest[(2 + (1 << 2))] = s1[2] * s2[1];
  dest[(3 + (1 << 2))] = 0;
  dest[(0 + (2 << 2))] = s1[0] * s2[2];
  dest[(1 + (2 << 2))] = s1[1] * s2[2];
  dest[(2 + (2 << 2))] = s1[2] * s2[2];
  dest[(3 + (2 << 2))] = 0;
  dest[(0 + (3 << 2))] = 0;
  dest[(1 + (3 << 2))] = 0;
  dest[(2 + (3 << 2))] = 0;
  dest[(3 + (3 << 2))] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<replace_ltgt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  shl    $0x2,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L21
L14:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3c,%al
  jne    L56
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x26,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x6c,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x74,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3b,(%rax)
  addl   $0x3,-0xc(%rbp)
  jmp    L50
L56:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3e,%al
  jne    L24
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x26,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x67,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x74,(%rax)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x3(%rax),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3b,(%rax)
  addl   $0x3,-0xc(%rbp)
  jmp    L50
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L50:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L21:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x10(%rbp)
  jl     L14
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *replace_ltgt(char *str) {
  int i, j = 0;
  char *new = malloc(sizeof(char) * (strlen(str) * 4 + 1));
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == '<') {
      new[j] = '&';
      new[j + 1] = 'l';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else if (str[i] == '>') {
      new[j] = '&';
      new[j + 1] = 'g';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else
      new[j] = str[i];
    j++;
  }
  new[j] = '\0';
  return new;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<replace_ltgt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  call   <strlen@plt>
  lea    0x1(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  jmp    L58
L20:
  movslq %ebx,%rax
  movb   $0x26,(%r12,%rax,1)
  movb   $0x6c,0x1(%r12,%rax,1)
  movb   $0x74,0x2(%r12,%rax,1)
  movb   $0x3b,0x3(%r12,%rax,1)
  add    $0x3,%ebx
L7:
  add    $0x1,%ebx
  add    $0x1,%rbp
L58:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jle    L25
  movzbl 0x0(%r13,%rbp,1),%eax
  cmp    $0x3c,%al
  je     L20
  cmp    $0x3e,%al
  je     L18
  movslq %ebx,%rdx
  mov    %al,(%r12,%rdx,1)
  jmp    L7
L18:
  movslq %ebx,%rax
  movb   $0x26,(%r12,%rax,1)
  movb   $0x67,0x1(%r12,%rax,1)
  movb   $0x74,0x2(%r12,%rax,1)
  movb   $0x3b,0x3(%r12,%rax,1)
  add    $0x3,%ebx
  jmp    L7
L25:
  movslq %ebx,%rbx
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *replace_ltgt(char *str) {
  int i, j = 0;
  char *new = malloc(sizeof(char) * (strlen(str) * 4 + 1));
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == '<') {
      new[j] = '&';
      new[j + 1] = 'l';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else if (str[i] == '>') {
      new[j] = '&';
      new[j + 1] = 'g';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else
      new[j] = str[i];
    j++;
  }
  new[j] = '\0';
  return new;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<replace_ltgt>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L59:
  cmp    $0x3e,%dl
  je     L1
  mov    %dl,(%rcx)
L10:
  add    $0x1,%ebx
  add    $0x1,%rbp
L4:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  movslq %ebx,%rax
  lea    (%r12,%rax,1),%rcx
  cmp    %ebp,%r8d
  jle    L24
  movzbl 0x0(%r13,%rbp,1),%edx
  cmp    $0x3c,%dl
  jne    L59
  movb   $0x26,(%rcx)
  add    $0x3,%ebx
  movb   $0x6c,0x1(%r12,%rax,1)
  movb   $0x74,0x2(%r12,%rax,1)
  movb   $0x3b,0x3(%r12,%rax,1)
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L1:
  movb   $0x26,(%rcx)
  add    $0x3,%ebx
  movb   $0x67,0x1(%r12,%rax,1)
  movb   $0x74,0x2(%r12,%rax,1)
  movb   $0x3b,0x3(%r12,%rax,1)
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L24:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *replace_ltgt(char *str) {
  int i, j = 0;
  char *new = malloc(sizeof(char) * (strlen(str) * 4 + 1));
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == '<') {
      new[j] = '&';
      new[j + 1] = 'l';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else if (str[i] == '>') {
      new[j] = '&';
      new[j + 1] = 'g';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else
      new[j] = str[i];
    j++;
  }
  new[j] = '\0';
  return new;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<replace_ltgt>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L28:
  cmp    $0x3e,%dl
  je     L18
  mov    %dl,(%rcx)
L27:
  add    $0x1,%ebx
  add    $0x1,%rbp
L25:
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  movslq %ebx,%rax
  lea    (%r12,%rax,1),%rcx
  cmp    %ebp,%r8d
  jle    L36
  movzbl 0x0(%r13,%rbp,1),%edx
  cmp    $0x3c,%dl
  jne    L28
  movb   $0x26,(%rcx)
  add    $0x3,%ebx
  movb   $0x6c,0x1(%r12,%rax,1)
  movb   $0x74,0x2(%r12,%rax,1)
  movb   $0x3b,0x3(%r12,%rax,1)
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L18:
  movb   $0x26,(%rcx)
  add    $0x3,%ebx
  movb   $0x67,0x1(%r12,%rax,1)
  movb   $0x74,0x2(%r12,%rax,1)
  movb   $0x3b,0x3(%r12,%rax,1)
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L36:
  movb   $0x0,(%rcx)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *replace_ltgt(char *str) {
  int i, j = 0;
  char *new = malloc(sizeof(char) * (strlen(str) * 4 + 1));
  for (i = 0; i < strlen(str); i++) {
    if (str[i] == '<') {
      new[j] = '&';
      new[j + 1] = 'l';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else if (str[i] == '>') {
      new[j] = '&';
      new[j + 1] = 'g';
      new[j + 2] = 't';
      new[j + 3] = ';';
      j += 3;
    } else
      new[j] = str[i];
    j++;
  }
  new[j] = '\0';
  return new;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  lea    D7(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x3e8,%edx
  mov    $0x78,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <__builtin_memchr@plt>
  test   %rax,%rax
  je     L8
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L8:
  mov    -0x8(%rbp),%rax
  mov    $0x3e8,%edx
  mov    $0x78,%esi
  mov    %rax,%rdi
  call   <__builtin_memchr@plt>
  test   %rax,%rax
  je     L9
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L9:
  mov    $0xffffffff,%edx
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L16
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L16:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D8
type_guessed: string
name: unpack_data
arguments: data_label: D31
type_guessed: string
name: unpack_data
arguments: data_label: D25
type_guessed: string

tool: D7: hello world

tool: 

tool: D31: b

tool: D25: a

assistant: ```c
int main(void) {
  const char *const foo1 = "hello world";
  if (__builtin_memchr("", 'x', 1000))
    __builtin_abort();
  if (__builtin_memchr(foo1, 'x', 1000))
    __builtin_abort();
  if (strncmp("a", "b", -1))
    __builtin_abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%edx
  mov    $0x78,%esi
  lea    D11(%rip),%rdi
  call   <__builtin_memchr@plt>
  test   %rax,%rax
  jne    L42
L21:
  mov    $0x3e8,%edx
  mov    $0x78,%esi
  lea    D26(%rip),%rdi
  call   <__builtin_memchr@plt>
  test   %rax,%rax
  jne    L12
L49:
  mov    $0xffffffff,%edx
  lea    D38(%rip),%rsi
  lea    D8(%rip),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L47
L39:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L42:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L21
L12:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L49
L47:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L39
```

tool_calls: name: retrieve_data
arguments: data_label: D11
type_guessed: string
name: retrieve_data
arguments: data_label: D26
type_guessed: string
name: retrieve_data
arguments: data_label: D38
type_guessed: string
name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: 

tool: D26: hello world

tool: D38: b

tool: D8: a

assistant: ```c
int main(void) {
  const char *const foo1 = "hello world";
  if (__builtin_memchr("", 'x', 1000))
    __builtin_abort();
  if (__builtin_memchr(foo1, 'x', 1000))
    __builtin_abort();
  if (strncmp("a", "b", -1))
    __builtin_abort();
  return 0;
}
```