ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<_ucRcAT1608_VerifyPasswordEx>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  movzbl %bpl,%ecx
  mov    $0x2526,%edx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    %eax,%ebp
  mov    %eax,%edi
  add    %rbx,%rdi
  mov    $0x8,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
  lea    0x8(%rbp),%eax
  movw   $0x29,(%rbx,%rax,1)
  lea    0x9(%rbp),%esi
  mov    $0x2,%edx
  mov    %rbx,%rdi
  call   <iDoRemoteFunc@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  test   %ebp,%ebp
  jne    L16
  mov    $0x0,%edi
  call   <iGetParaInt@plt>
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L16:
  mov    %ebp,%esi
  lea    D9(%rip),%rdi
  call   <vWriteLogTxt@plt>
  mov    $0x1,%eax
  jmp    L19
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string
name: disassemble_data
arguments: data_tag: D9
type_guessed: string

tool: D7: %u(%u,b008

tool: D9: _AT1608_VerifyPasswordEx iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_VerifyPasswordEx(unsigned char Index, unsigned char *Password) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(%u,b008", 9510, Index);
  memcpy(psFunCall + uiDataLen, Password, 8);
  uiDataLen += 8;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 2);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_VerifyPasswordEx iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ucRcAT1608_VerifyPasswordEx>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x32,%edi
  call   <malloc@plt>
  movzbl %bl,%ecx
  mov    $0x2526,%edx
  lea    D13(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    $0x8,%edx
  mov    %eax,%edi
  mov    %rdi,%rbx
  add    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x8(%rbx),%eax
  mov    $0x29,%edx
  mov    %rbp,%rdi
  mov    %dx,0x0(%rbp,%rax,1)
  lea    0x9(%rbx),%esi
  mov    $0x2,%edx
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  test   %r12d,%r12d
  jne    L3
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <iGetParaInt@plt>
L3:
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <vWriteLogTxt@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string

tool: D13: %u(%u,b008

tool: D1: _AT1608_VerifyPasswordEx iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_VerifyPasswordEx(unsigned char Index, unsigned char *Password) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(%u,b008", 9510, Index);
  memcpy(psFunCall + uiDataLen, Password, 8);
  uiDataLen += 8;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 2);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_VerifyPasswordEx iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_ucRcAT1608_VerifyPasswordEx>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    $0x32,%edi
  call   <malloc@plt>
  movzbl %bl,%ecx
  mov    $0x2526,%edx
  lea    D0(%rip),%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    $0x8,%edx
  mov    %eax,%edi
  mov    %rdi,%rbx
  add    %rbp,%rdi
  call   <memcpy@plt>
  lea    0x8(%rbx),%eax
  mov    $0x29,%edx
  mov    %rbp,%rdi
  mov    %dx,0x0(%rbp,%rax,1)
  lea    0x9(%rbx),%esi
  mov    $0x2,%edx
  call   <iDoRemoteFunc@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  test   %r12d,%r12d
  jne    L5
  pop    %rbx
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    10c0 <iGetParaInt@plt>
L5:
  mov    %r12d,%esi
  lea    D8(%rip),%rdi
  call   <vWriteLogTxt@plt>
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type: string
name: parse_data
arguments: data_label: D8
type: string

tool: D0: %u(%u,b008

tool: D8: _AT1608_VerifyPasswordEx iDoRemoteFunc ret = %d

assistant: ```c
unsigned char _ucRcAT1608_VerifyPasswordEx(unsigned char Index, unsigned char *Password) {
  unsigned int uiDataLen, uiRet;
  char *psFunCall = malloc(50);
  uiDataLen = sprintf(psFunCall, "%u(%u,b008", 9510, Index);
  memcpy(psFunCall + uiDataLen, Password, 8);
  uiDataLen += 8;
  uiDataLen += sprintf(psFunCall + uiDataLen, ")");
  uiRet = iDoRemoteFunc((unsigned char *)psFunCall, uiDataLen, 2);
  free(psFunCall);
  if (uiRet) {
    vWriteLogTxt("_AT1608_VerifyPasswordEx iDoRemoteFunc ret = %d", uiRet);
    return 1;
  }
  return iGetParaInt(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<two_two_five>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x6,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x40490fd0,0x10(%rsp)
  movl   $0x402df84d,0x14(%rsp)
  mov    $0x9,%edx
  mov    $0x6,%esi
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%r13
  lea    0x8(%rsp),%r12
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D22(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <generic_swap@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <generic_swap@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x10(%rsp),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd 0x14(%rsp),%xmm1
  mov    %rbx,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D22
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string

tool: D29: %d %d


tool: D22: 


tool: D6: %f %f


assistant: ```c
int two_two_five() {
  int a = 6;
  int b = 9;
  float c = 3.14159;
  float d = 2.71828;
  void *ptrA = &a;
  void *ptrB = &b;
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  swap(ptrA, ptrB);
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  printf("\n\n");
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  generic_swap(ptrA, ptrB, sizeof(int));
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  printf("\n\n");
  ptrA = &c;
  ptrB = &d;
  printf("%f %f\n", *(float *)ptrA, *(float *)ptrB);
  generic_swap(ptrA, ptrB, sizeof(float));
  printf("%f %f\n", *(float *)ptrA, *(float *)ptrB);
  printf("\n\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<two_two_five>:
  endbr64
  push   %r14
  mov    $0x9,%edx
  mov    $0x6,%esi
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  lea    D18(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%r13
  movl   $0x6,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x40490fd0,0x10(%rsp)
  movl   $0x402df84d,0x14(%rsp)
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <generic_swap@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D24(%rip),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <generic_swap@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type: string
name: retrieve_data
arguments: data_label: D18
type: string
name: retrieve_data
arguments: data_label: D24
type: string

tool: D3: 


tool: D18: %d %d


tool: D24: %f %f


assistant: ```c
int two_two_five() {
  int a = 6;
  int b = 9;
  float c = 3.14159;
  float d = 2.71828;
  void *ptrA = &a;
  void *ptrB = &b;
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  swap(ptrA, ptrB);
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  printf("\n\n");
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  generic_swap(ptrA, ptrB, sizeof(int));
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  printf("\n\n");
  ptrA = &c;
  ptrB = &d;
  printf("%f %f\n", *(float *)ptrA, *(float *)ptrB);
  generic_swap(ptrA, ptrB, sizeof(float));
  printf("%f %f\n", *(float *)ptrA, *(float *)ptrB);
  printf("\n\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<two_two_five>:
  endbr64
  push   %r14
  mov    $0x9,%edx
  mov    $0x6,%esi
  push   %r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D17(%rip),%rbp
  mov    %rbp,%rdi
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%r14
  lea    0x8(%rsp),%r13
  movl   $0x6,0x8(%rsp)
  movl   $0x9,0xc(%rsp)
  movl   $0x40490fd0,0x10(%rsp)
  movl   $0x402df84d,0x14(%rsp)
  call   <printf@plt>
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <generic_swap@plt>
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  lea    D20(%rip),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <generic_swap@plt>
  mov    %rbp,%rdi
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x2,%eax
  cvtss2sd 0x10(%rsp),%xmm0
  cvtss2sd 0x14(%rsp),%xmm1
  call   <printf@plt>
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D28
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D20
datatype: string

tool: D28: 


tool: D17: %d %d


tool: D20: %f %f


assistant: ```c
int two_two_five() {
  int a = 6;
  int b = 9;
  float c = 3.14159;
  float d = 2.71828;
  void *ptrA = &a;
  void *ptrB = &b;
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  swap(ptrA, ptrB);
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  printf("\n\n");
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  generic_swap(ptrA, ptrB, sizeof(int));
  printf("%d %d\n", *(int *)ptrA, *(int *)ptrB);
  printf("\n\n");
  ptrA = &c;
  ptrB = &d;
  printf("%f %f\n", *(float *)ptrA, *(float *)ptrB);
  generic_swap(ptrA, ptrB, sizeof(float));
  printf("%f %f\n", *(float *)ptrA, *(float *)ptrB);
  printf("\n\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<even>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x2,%esi
  mov    $0xd,%edi
  call   <__CrestCall@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xc,%edi
  call   <__CrestStore@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0xe,%edi
  call   <__CrestLoad@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xf,%edi
  call   <__CrestLoad@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <_divides@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  mov    %rax,%rsi
  mov    $0x11,%edi
  call   <__CrestHandleReturn@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x10,%edi
  call   <__CrestStore@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x12,%edi
  call   <__CrestLoad@plt>
  mov    $0x13,%edi
  call   <__CrestReturn@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int even(int n) {
  int tmp;
  {
    __CrestCall(13, 2);
    __CrestStore(12, (unsigned long)(&n));
    __CrestLoad(14, (unsigned long)0, (long long)2);
    __CrestLoad(15, (unsigned long)(&n), (long long)n);
    tmp = _divides(2, n);
    __CrestHandleReturn(17, (long long)tmp);
    __CrestStore(16, (unsigned long)(&tmp));
    {
      __CrestLoad(18, (unsigned long)(&tmp), (long long)tmp);
      __CrestReturn(19);
      return (tmp);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<even>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x2,%esi
  mov    $0xd,%edi
  call   <__CrestCall@plt>
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0xc,%edi
  call   <__CrestStore@plt>
  mov    $0x2,%edx
  mov    $0x0,%esi
  mov    $0xe,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbx,%rsi
  mov    $0xf,%edi
  call   <__CrestLoad@plt>
  mov    0xc(%rsp),%esi
  mov    $0x2,%edi
  call   <_divides@plt>
  mov    %eax,0x14(%rsp)
  movslq %eax,%rsi
  mov    $0x11,%edi
  call   <__CrestHandleReturn@plt>
  lea    0x14(%rsp),%rbx
  mov    %rbx,%rsi
  mov    $0x10,%edi
  call   <__CrestStore@plt>
  movslq 0x14(%rsp),%rdx
  mov    %rbx,%rsi
  mov    $0x12,%edi
  call   <__CrestLoad@plt>
  mov    $0x13,%edi
  call   <__CrestReturn@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int even(int n) {
  int tmp;
  {
    __CrestCall(13, 2);
    __CrestStore(12, (unsigned long)(&n));
    __CrestLoad(14, (unsigned long)0, (long long)2);
    __CrestLoad(15, (unsigned long)(&n), (long long)n);
    tmp = _divides(2, n);
    __CrestHandleReturn(17, (long long)tmp);
    __CrestStore(16, (unsigned long)(&tmp));
    {
      __CrestLoad(18, (unsigned long)(&tmp), (long long)tmp);
      __CrestReturn(19);
      return (tmp);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<even>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  mov    $0xd,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <__CrestCall@plt>
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <__CrestStore@plt>
  mov    $0x2,%edx
  xor    %esi,%esi
  mov    $0xe,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0xf,%edi
  lea    0x14(%rsp),%rbp
  call   <__CrestLoad@plt>
  mov    0xc(%rsp),%esi
  mov    $0x2,%edi
  call   <_divides@plt>
  mov    $0x11,%edi
  movslq %eax,%rsi
  mov    %eax,0x14(%rsp)
  call   <__CrestHandleReturn@plt>
  mov    %rbp,%rsi
  mov    $0x10,%edi
  call   <__CrestStore@plt>
  movslq 0x14(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x12,%edi
  call   <__CrestLoad@plt>
  mov    $0x13,%edi
  call   <__CrestReturn@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int even(int n) {
  int tmp;
  {
    __CrestCall(13, 2);
    __CrestStore(12, (unsigned long)(&n));
    __CrestLoad(14, (unsigned long)0, (long long)2);
    __CrestLoad(15, (unsigned long)(&n), (long long)n);
    tmp = _divides(2, n);
    __CrestHandleReturn(17, (long long)tmp);
    __CrestStore(16, (unsigned long)(&tmp));
    {
      __CrestLoad(18, (unsigned long)(&tmp), (long long)tmp);
      __CrestReturn(19);
      return (tmp);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<even>:
  endbr64
  push   %rbp
  mov    $0x2,%esi
  sub    $0x20,%rsp
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rbp
  mov    $0xd,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <__CrestCall@plt>
  mov    %rbp,%rsi
  mov    $0xc,%edi
  call   <__CrestStore@plt>
  mov    $0x2,%edx
  xor    %esi,%esi
  mov    $0xe,%edi
  call   <__CrestLoad@plt>
  movslq 0xc(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0xf,%edi
  lea    0x14(%rsp),%rbp
  call   <__CrestLoad@plt>
  mov    0xc(%rsp),%esi
  mov    $0x2,%edi
  call   <_divides@plt>
  mov    $0x11,%edi
  movslq %eax,%rsi
  mov    %eax,0x14(%rsp)
  call   <__CrestHandleReturn@plt>
  mov    %rbp,%rsi
  mov    $0x10,%edi
  call   <__CrestStore@plt>
  movslq 0x14(%rsp),%rdx
  mov    %rbp,%rsi
  mov    $0x12,%edi
  call   <__CrestLoad@plt>
  mov    $0x13,%edi
  call   <__CrestReturn@plt>
  mov    0x14(%rsp),%eax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x20,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int even(int n) {
  int tmp;
  {
    __CrestCall(13, 2);
    __CrestStore(12, (unsigned long)(&n));
    __CrestLoad(14, (unsigned long)0, (long long)2);
    __CrestLoad(15, (unsigned long)(&n), (long long)n);
    tmp = _divides(2, n);
    __CrestHandleReturn(17, (long long)tmp);
    __CrestStore(16, (unsigned long)(&tmp));
    {
      __CrestLoad(18, (unsigned long)(&tmp), (long long)tmp);
      __CrestReturn(19);
      return (tmp);
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<matmul>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    %r9d,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  je     L106
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L21
L106:
  movl   $0x0,-0x10(%rbp)
  jmp    L77
L86:
  movl   $0x0,-0xc(%rbp)
  jmp    L76
L100:
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L50
L53:
  mov    -0x10(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L50:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L53
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  ucomiss -0x8(%rbp),%xmm0
  jp     L27
  ucomiss -0x8(%rbp),%xmm0
  je     L38
L27:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x8(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    0x10(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  movq   %xmm2,%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L21
L38:
  addl   $0x1,-0xc(%rbp)
L76:
  mov    -0xc(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L100
  addl   $0x1,-0x10(%rbp)
L77:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L86
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L21:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D18
data_type: string
name: unpack_data
arguments: data_label: D11
data_type: string
name: unpack_data
arguments: data_label: D25
data_type: string

tool: D18: wrong width/height

tool: D11: diff result %f %f


tool: D25: ok!

assistant: ```c
void matmul(float *m1, int w1, int h1, float *m2, int w2, int h2, float *mo) {
  if (w1 != h2) {
    printf("wrong width/height\n");
    return;
  }
  for (int y = 0; y < h1; y++) {
    for (int x = 0; x < w2; x++) {
      float val = 0.0f;
      for (int idx = 0; idx < w1; idx++) {
        val += (*(m1 + y * w1 + idx)) * (*(m2 + idx * w2 + x));
      }
      if (*(mo + y * w2 + x) != val) {
        printf("diff result %f %f\n", *(mo + y * w2 + x), val);
        return;
      }
    }
  }
  printf("ok!\n");
}
```