ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ffsl>:
  endbr64
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L11
  mov    $0x1,%eax
  test   $0x1,%dil
  jne    L11
  cs nopw 0x0(%rax,%rax,1)
L20:
  shr    %rdi
  add    $0x1,%eax
  test   $0x1,%dil
  je     L20
  ret
  nopl   (%rax)
L11:
  ret
```

assistant: ```c
int ffsl(unsigned long i) {
  int j = 0;
  if (i) {
    for (j = 1; (i & 1) == 0; j++)
      i >>= 1;
  }
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L15
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sum(int *a, int n) {
  int i = 0;
  int S = 0;
  for (i = 0; i < n; i++) {
    S += *(a + i);
  }
  return S;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L17
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
  mov    $0x0,%edx
L18:
  add    (%rax),%edx
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L18
L11:
  mov    %edx,%eax
  ret
L17:
  mov    $0x0,%edx
  jmp    L11
```

assistant: ```c
int sum(int *a, int n) {
  int i = 0;
  int S = 0;
  for (i = 0; i < n; i++) {
    S += *(a + i);
  }
  return S;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sum>:
  endbr64
  test   %esi,%esi
  jle    L17
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L8:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L8
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sum(int *a, int n) {
  int i = 0;
  int S = 0;
  for (i = 0; i < n; i++) {
    S += *(a + i);
  }
  return S;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sum>:
  endbr64
  mov    %rdi,%rdx
  test   %esi,%esi
  jle    L39
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L68
  mov    %esi,%ecx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%ecx
  sub    $0x1,%ecx
  shl    $0x4,%rcx
  lea    0x10(%rdi,%rcx,1),%rcx
  nopl   0x0(%rax,%rax,1)
L62:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rcx,%rax
  jne    L62
  movdqa %xmm0,%xmm1
  mov    %esi,%ecx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%ecx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%sil
  je     L59
L2:
  movslq %ecx,%rdi
  lea    0x0(,%rdi,4),%r8
  add    (%rdx,%rdi,4),%eax
  lea    0x1(%rcx),%edi
  cmp    %edi,%esi
  jle    L27
  add    $0x2,%ecx
  add    0x4(%rdx,%r8,1),%eax
  cmp    %ecx,%esi
  jle    L27
  add    0x8(%rdx,%r8,1),%eax
  ret
  nopl   0x0(%rax)
L39:
  xor    %eax,%eax
L27:
  ret
  nopl   0x0(%rax,%rax,1)
L59:
  ret
L68:
  xor    %eax,%eax
  xor    %ecx,%ecx
  jmp    L2
```

assistant: ```c
int sum(int *a, int n) {
  int i = 0;
  int S = 0;
  for (i = 0; i < n; i++) {
    S += *(a + i);
  }
  return S;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zsize_data_unescape>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
L44:
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  cmp    %eax,-0x2c(%rbp)
  je     L34
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  jmp    L31
L34:
  mov    $0xffffffff,%eax
L31:
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  jne    L11
  mov    $0xffffffff,%eax
  jmp    L65
L11:
  mov    -0xc(%rbp),%eax
  and    $0x7f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x80,%eax
  test   %eax,%eax
  jne    L69
  addl   $0x7,-0x10(%rbp)
  jmp    L44
L69:
  nop
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x2c(%rbp)
  jge    L56
  mov    $0xffffffff,%eax
  jmp    L65
L56:
  mov    -0x38(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
L65:
  pop    %rbp
  ret
```

assistant: ```c
int zsize_data_unescape(const void *src_data, int src_size, void **result_data, int *result_len) {
  int i = 0;
  unsigned char *buf = (unsigned char *)src_data;
  int ch, len = 0, shift = 0;
  while (1) {
    ch = ((i++ == src_size) ? -1 : *buf++);
    if (ch == -1) {
      return -1;
    }
    len |= ((ch & 0177) << shift);
    if (ch & 0200) {
      break;
    }
    shift += 7;
  }
  if (i + len > src_size) {
    return -1;
  }
  *result_data = buf;
  *result_len = len;
  return i + len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<zsize_data_unescape>:
  endbr64
  test   %esi,%esi
  je     L25
  push   %rbp
  push   %rbx
  mov    %esi,%r11d
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  mov    %esi,%r10d
  add    %rdi,%r10
  mov    %rdi,%rdx
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  mov    $0x1,%r9d
  sub    %edi,%r9d
L33:
  lea    (%r9,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%edi
  mov    %edi,%esi
  and    $0x7f,%esi
  shl    %cl,%esi
  or     %esi,%r8d
  test   %dil,%dil
  js     L7
  add    $0x7,%ecx
  cmp    %r10,%rdx
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L1
L7:
  add    %r8d,%eax
  cmp    %r11d,%eax
  jg     L40
  mov    %rdx,0x0(%rbp)
  mov    %r8d,(%rbx)
L1:
  pop    %rbx
  pop    %rbp
  ret
L25:
  mov    $0xffffffff,%eax
  ret
L40:
  mov    $0xffffffff,%eax
  jmp    L1
```

assistant: ```c
int zsize_data_unescape(const void *src_data, int src_size, void **result_data, int *result_len) {
  int i = 0;
  unsigned char *buf = (unsigned char *)src_data;
  int ch, len = 0, shift = 0;
  while (1) {
    ch = ((i++ == src_size) ? -1 : *buf++);
    if (ch == -1) {
      return -1;
    }
    len |= ((ch & 0177) << shift);
    if (ch & 0200) {
      break;
    }
    shift += 7;
  }
  if (i + len > src_size) {
    return -1;
  }
  *result_data = buf;
  *result_len = len;
  return i + len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<zsize_data_unescape>:
  endbr64
  test   %esi,%esi
  je     L23
  push   %rbp
  mov    $0x1,%r9d
  mov    %esi,%ebp
  mov    %rcx,%r11
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rbx
  add    %rdi,%rbp
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  sub    %edi,%r9d
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L42:
  add    $0x7,%ecx
  cmp    %rbp,%rdi
  je     L34
L26:
  lea    (%r9,%rdi,1),%eax
  movzbl (%rdi),%esi
  add    $0x1,%rdi
  mov    %esi,%edx
  and    $0x7f,%edx
  shl    %cl,%edx
  or     %edx,%r8d
  test   %sil,%sil
  jns    L42
  add    %r8d,%eax
  cmp    %r10d,%eax
  jg     L34
  mov    %rdi,(%rbx)
  mov    %r8d,(%r11)
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
L23:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int zsize_data_unescape(const void *src_data, int src_size, void **result_data, int *result_len) {
  int i = 0;
  unsigned char *buf = (unsigned char *)src_data;
  int ch, len = 0, shift = 0;
  while (1) {
    ch = ((i++ == src_size) ? -1 : *buf++);
    if (ch == -1) {
      return -1;
    }
    len |= ((ch & 0177) << shift);
    if (ch & 0200) {
      break;
    }
    shift += 7;
  }
  if (i + len > src_size) {
    return -1;
  }
  *result_data = buf;
  *result_len = len;
  return i + len;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<zsize_data_unescape>:
  endbr64
  test   %esi,%esi
  je     L4
  push   %rbp
  mov    $0x1,%r9d
  mov    %esi,%ebp
  mov    %rcx,%r11
  push   %rbx
  mov    %esi,%r10d
  mov    %rdx,%rbx
  add    %rdi,%rbp
  xor    %ecx,%ecx
  xor    %r8d,%r8d
  sub    %edi,%r9d
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L39:
  add    $0x7,%ecx
  cmp    %rbp,%rdi
  je     L10
L3:
  lea    (%r9,%rdi,1),%eax
  movzbl (%rdi),%esi
  add    $0x1,%rdi
  mov    %esi,%edx
  and    $0x7f,%edx
  shl    %cl,%edx
  or     %edx,%r8d
  test   %sil,%sil
  jns    L39
  add    %r8d,%eax
  cmp    %r10d,%eax
  jg     L10
  mov    %rdi,(%rbx)
  mov    %r8d,(%r11)
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int zsize_data_unescape(const void *src_data, int src_size, void **result_data, int *result_len) {
  int i = 0;
  unsigned char *buf = (unsigned char *)src_data;
  int ch, len = 0, shift = 0;
  while (1) {
    ch = ((i++ == src_size) ? -1 : *buf++);
    if (ch == -1) {
      return -1;
    }
    len |= ((ch & 0177) << shift);
    if (ch & 0200) {
      break;
    }
    shift += 7;
  }
  if (i + len > src_size) {
    return -1;
  }
  *result_data = buf;
  *result_len = len;
  return i + len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L42
L8:
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  js     L18
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L42:
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L8
  jmp    L28
L18:
  nop
L28:
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0x10(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0xc(%rbp),%xmm1
  divss  %xmm1,%xmm0
  movd   %xmm0,%edx
  mov    -0x10(%rbp),%eax
  movd   %edx,%xmm0
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
data_type: string
name: unpack_data
arguments: data_label: D2
data_type: string

tool: D8: %d

tool: D2: %d
%.1f


assistant: ```c
int main() {
  int num, soma = 0, count = 0;
  while (scanf("%d", &num)) {
    if (num < 0)
      break;
    soma += num;
    count++;
  }
  printf("%d\n%.1f\n", soma, ((float)soma / count));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    $0x0,%ebx
  lea    D16(%rip),%r12
  jmp    L14
L32:
  add    %eax,%ebx
  add    $0x1,%ebp
L14:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L27
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jns    L32
L27:
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebp,%xmm1
  divss  %xmm1,%xmm0
  mov    %ebx,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D16
type_infered: string
name: unpack_data
arguments: tag: D9
type_infered: string

tool: D16: %d

tool: D9: %d
%.1f


assistant: ```c
int main() {
  int num, soma = 0, count = 0;
  while (scanf("%d", &num)) {
    if (num < 0)
      break;
    soma += num;
    count++;
  }
  printf("%d\n%.1f\n", soma, ((float)soma / count));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  jmp    L39
L31:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L0
  add    %eax,%ebp
  add    $0x1,%ebx
L39:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L31
L0:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %ebp,%esi
  cvtsi2ss %ebp,%xmm0
  lea    D6(%rip),%rdi
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D6
type_infered: string

tool: D14: %d

tool: D6: %d
%.1f


assistant: ```c
int main() {
  int num, soma = 0, count = 0;
  while (scanf("%d", &num)) {
    if (num < 0)
      break;
    soma += num;
    count++;
  }
  printf("%d\n%.1f\n", soma, ((float)soma / count));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  jmp    L18
L0:
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L6
  add    %eax,%ebp
  add    $0x1,%ebx
L18:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L0
L6:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    %ebp,%esi
  cvtsi2ss %ebp,%xmm0
  lea    D15(%rip),%rdi
  cvtsi2ss %ebx,%xmm1
  divss  %xmm1,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: string
name: parse_data
arguments: tag: D15
datatype: string

tool: D3: %d

tool: D15: %d
%.1f


assistant: ```c
int main() {
  int num, soma = 0, count = 0;
  while (scanf("%d", &num)) {
    if (num < 0)
      break;
    soma += num;
    count++;
  }
  printf("%d\n%.1f\n", soma, ((float)soma / count));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_ZSt3maxImERKT_S2_S2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x38(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L20
  nop
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  jmp    L6
L20:
  nop
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  nop
L6:
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

assistant: ```c
unsigned long long *_ZSt3maxImERKT_S2_S2_(unsigned long long *llvm_cbe___a, unsigned long long *llvm_cbe___b) {
  unsigned long long *llvm_cbe_retval;
  unsigned long long *llvm_cbe___a_2e_addr;
  unsigned long long *llvm_cbe___b_2e_addr;
  unsigned long long *llvm_cbe_tmp;
  unsigned long long llvm_cbe_tmp1;
  unsigned long long *llvm_cbe_tmp2;
  unsigned long long llvm_cbe_tmp3;
  unsigned long long *llvm_cbe_tmp4;
  unsigned long long *llvm_cbe_tmp5;
  unsigned long long *llvm_cbe_tmp__53;
  *(&llvm_cbe___a_2e_addr) = llvm_cbe___a;
  *(&llvm_cbe___b_2e_addr) = llvm_cbe___b;
  llvm_cbe_tmp = *(&llvm_cbe___a_2e_addr);
  llvm_cbe_tmp1 = *llvm_cbe_tmp;
  llvm_cbe_tmp2 = *(&llvm_cbe___b_2e_addr);
  llvm_cbe_tmp3 = *llvm_cbe_tmp2;
  if ((((unsigned long long)llvm_cbe_tmp1) < ((unsigned long long)llvm_cbe_tmp3))) {
    goto llvm_cbe_if_2e_then;
  } else {
    goto llvm_cbe_if_2e_end;
  }
llvm_cbe_if_2e_then:
  llvm_cbe_tmp4 = *(&llvm_cbe___b_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp4;
  goto llvm_cbe_return;
llvm_cbe_if_2e_end:
  llvm_cbe_tmp5 = *(&llvm_cbe___a_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp5;
  goto llvm_cbe_return;
llvm_cbe_return:
  llvm_cbe_tmp__53 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__53;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_ZSt3maxImERKT_S2_S2_>:
  endbr64
  mov    %rsi,%rax
  mov    (%rsi),%rdx
  cmp    %rdx,(%rdi)
  cmovae %rdi,%rax
  ret
```

assistant: ```c
unsigned long long *_ZSt3maxImERKT_S2_S2_(unsigned long long *llvm_cbe___a, unsigned long long *llvm_cbe___b) {
  unsigned long long *llvm_cbe_retval;
  unsigned long long *llvm_cbe___a_2e_addr;
  unsigned long long *llvm_cbe___b_2e_addr;
  unsigned long long *llvm_cbe_tmp;
  unsigned long long llvm_cbe_tmp1;
  unsigned long long *llvm_cbe_tmp2;
  unsigned long long llvm_cbe_tmp3;
  unsigned long long *llvm_cbe_tmp4;
  unsigned long long *llvm_cbe_tmp5;
  unsigned long long *llvm_cbe_tmp__53;
  *(&llvm_cbe___a_2e_addr) = llvm_cbe___a;
  *(&llvm_cbe___b_2e_addr) = llvm_cbe___b;
  llvm_cbe_tmp = *(&llvm_cbe___a_2e_addr);
  llvm_cbe_tmp1 = *llvm_cbe_tmp;
  llvm_cbe_tmp2 = *(&llvm_cbe___b_2e_addr);
  llvm_cbe_tmp3 = *llvm_cbe_tmp2;
  if ((((unsigned long long)llvm_cbe_tmp1) < ((unsigned long long)llvm_cbe_tmp3))) {
    goto llvm_cbe_if_2e_then;
  } else {
    goto llvm_cbe_if_2e_end;
  }
llvm_cbe_if_2e_then:
  llvm_cbe_tmp4 = *(&llvm_cbe___b_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp4;
  goto llvm_cbe_return;
llvm_cbe_if_2e_end:
  llvm_cbe_tmp5 = *(&llvm_cbe___a_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp5;
  goto llvm_cbe_return;
llvm_cbe_return:
  llvm_cbe_tmp__53 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__53;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_ZSt3maxImERKT_S2_S2_>:
  endbr64
  mov    (%rsi),%rdx
  mov    %rsi,%rax
  cmp    %rdx,(%rdi)
  cmovae %rdi,%rax
  ret
```

assistant: ```c
unsigned long long *_ZSt3maxImERKT_S2_S2_(unsigned long long *llvm_cbe___a, unsigned long long *llvm_cbe___b) {
  unsigned long long *llvm_cbe_retval;
  unsigned long long *llvm_cbe___a_2e_addr;
  unsigned long long *llvm_cbe___b_2e_addr;
  unsigned long long *llvm_cbe_tmp;
  unsigned long long llvm_cbe_tmp1;
  unsigned long long *llvm_cbe_tmp2;
  unsigned long long llvm_cbe_tmp3;
  unsigned long long *llvm_cbe_tmp4;
  unsigned long long *llvm_cbe_tmp5;
  unsigned long long *llvm_cbe_tmp__53;
  *(&llvm_cbe___a_2e_addr) = llvm_cbe___a;
  *(&llvm_cbe___b_2e_addr) = llvm_cbe___b;
  llvm_cbe_tmp = *(&llvm_cbe___a_2e_addr);
  llvm_cbe_tmp1 = *llvm_cbe_tmp;
  llvm_cbe_tmp2 = *(&llvm_cbe___b_2e_addr);
  llvm_cbe_tmp3 = *llvm_cbe_tmp2;
  if ((((unsigned long long)llvm_cbe_tmp1) < ((unsigned long long)llvm_cbe_tmp3))) {
    goto llvm_cbe_if_2e_then;
  } else {
    goto llvm_cbe_if_2e_end;
  }
llvm_cbe_if_2e_then:
  llvm_cbe_tmp4 = *(&llvm_cbe___b_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp4;
  goto llvm_cbe_return;
llvm_cbe_if_2e_end:
  llvm_cbe_tmp5 = *(&llvm_cbe___a_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp5;
  goto llvm_cbe_return;
llvm_cbe_return:
  llvm_cbe_tmp__53 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__53;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_ZSt3maxImERKT_S2_S2_>:
  endbr64
  mov    (%rsi),%rdx
  mov    %rsi,%rax
  cmp    %rdx,(%rdi)
  cmovae %rdi,%rax
  ret
```

assistant: ```c
unsigned long long *_ZSt3maxImERKT_S2_S2_(unsigned long long *llvm_cbe___a, unsigned long long *llvm_cbe___b) {
  unsigned long long *llvm_cbe_retval;
  unsigned long long *llvm_cbe___a_2e_addr;
  unsigned long long *llvm_cbe___b_2e_addr;
  unsigned long long *llvm_cbe_tmp;
  unsigned long long llvm_cbe_tmp1;
  unsigned long long *llvm_cbe_tmp2;
  unsigned long long llvm_cbe_tmp3;
  unsigned long long *llvm_cbe_tmp4;
  unsigned long long *llvm_cbe_tmp5;
  unsigned long long *llvm_cbe_tmp__53;
  *(&llvm_cbe___a_2e_addr) = llvm_cbe___a;
  *(&llvm_cbe___b_2e_addr) = llvm_cbe___b;
  llvm_cbe_tmp = *(&llvm_cbe___a_2e_addr);
  llvm_cbe_tmp1 = *llvm_cbe_tmp;
  llvm_cbe_tmp2 = *(&llvm_cbe___b_2e_addr);
  llvm_cbe_tmp3 = *llvm_cbe_tmp2;
  if ((((unsigned long long)llvm_cbe_tmp1) < ((unsigned long long)llvm_cbe_tmp3))) {
    goto llvm_cbe_if_2e_then;
  } else {
    goto llvm_cbe_if_2e_end;
  }
llvm_cbe_if_2e_then:
  llvm_cbe_tmp4 = *(&llvm_cbe___b_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp4;
  goto llvm_cbe_return;
llvm_cbe_if_2e_end:
  llvm_cbe_tmp5 = *(&llvm_cbe___a_2e_addr);
  *(&llvm_cbe_retval) = llvm_cbe_tmp5;
  goto llvm_cbe_return;
llvm_cbe_return:
  llvm_cbe_tmp__53 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__53;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xls_is_bigendian>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D1(%rip),%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int xls_is_bigendian() {
  static int n = 1;
  return (*(char *)&n == 0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xls_is_bigendian>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int xls_is_bigendian() {
  static int n = 1;
  return (*(char *)&n == 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<xls_is_bigendian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int xls_is_bigendian() {
  static int n = 1;
  return (*(char *)&n == 0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<xls_is_bigendian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int xls_is_bigendian() {
  static int n = 1;
  return (*(char *)&n == 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hash_tw1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xf,%eax
  not    %eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0xa,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x6,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xb,%eax
  not    %eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sar    $0x10,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t hash_tw1(uint32_t a) {
  a += ~(a << 15);
  a ^= (a >> 10);
  a += (a << 3);
  a ^= (a >> 6);
  a += ~(a << 11);
  a ^= (a >> 16);
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<hash_tw1>:
  endbr64
  mov    %edi,%eax
  shl    $0xf,%eax
  not    %eax
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0xa,%eax
  xor    %edi,%eax
  lea    (%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0x6,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shl    $0xb,%edx
  not    %edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash_tw1(uint32_t a) {
  a += ~(a << 15);
  a ^= (a >> 10);
  a += (a << 3);
  a ^= (a >> 6);
  a += ~(a << 11);
  a ^= (a >> 16);
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hash_tw1>:
  endbr64
  mov    %edi,%eax
  shl    $0xf,%eax
  not    %eax
  add    %eax,%edi
  mov    %edi,%eax
  sar    $0xa,%eax
  xor    %edi,%eax
  lea    (%rax,%rax,8),%edx
  mov    %edx,%eax
  sar    $0x6,%eax
  xor    %edx,%eax
  mov    %eax,%edx
  shl    $0xb,%edx
  not    %edx
  add    %eax,%edx
  mov    %edx,%eax
  sar    $0x10,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
uint32_t hash_tw1(uint32_t a) {
  a += ~(a << 15);
  a ^= (a >> 10);
  a += (a << 3);
  a ^= (a >> 6);
  a += ~(a << 11);
  a ^= (a >> 16);
  return a;
}
```