ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<simple_distance>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L88
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    $0x0,%esi
  mov    $0x0,%r11d
  mov    $0x0,%ebx
  mov    $0x1,%r8d
  movabs $0x8000000000006001,%r9
  jmp    L23
L84:
  cmp    %al,%bpl
  setne  %al
  movzbl %al,%eax
  add    %eax,%ebx
  add    $0x1,%r11d
L56:
  add    $0x1,%rsi
  movzbl (%rdi,%rsi,1),%eax
  test   %al,%al
  je     L15
L23:
  lea    -0x20(%rax),%ecx
  mov    %r8d,%edx
  cmp    $0x3f,%cl
  ja     L81
  mov    %r9,%rdx
  shr    %cl,%rdx
  xor    $0x1,%rdx
  and    $0x1,%edx
L81:
  cmp    $0x7e,%al
  je     L56
  test   %dl,%dl
  je     L56
  movzbl (%r10,%rsi,1),%ebp
  lea    -0x20(%rbp),%ecx
  mov    %r8d,%edx
  cmp    $0x3f,%cl
  ja     L105
  mov    %r9,%rdx
  shr    %cl,%rdx
  xor    $0x1,%rdx
  and    $0x1,%edx
L105:
  cmp    $0x7e,%bpl
  je     L56
  test   %dl,%dl
  jne    L84
  jmp    L56
L15:
  pxor   %xmm0,%xmm0
  test   %r11d,%r11d
  jle    L58
  pxor   %xmm0,%xmm0
  cvtsi2ss %ebx,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %r11d,%xmm1
  divss  %xmm1,%xmm0
L58:
  pop    %rbx
  pop    %rbp
  ret
L88:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float simple_distance(char *s1, char *s2) {
  int diff = 0;
  int valid = 0;
  for (; *s1 != '\0'; s1++, s2++) {
    if (((*s1) == ' ' || (*s1) == '.' || (*s1) == '_' || (*s1) == '-' || (*s1) == '~') || ((*s2) == ' ' || (*s2) == '.' || (*s2) == '_' || (*s2) == '-' || (*s2) == '~'))
      continue;
    if (*s1 != *s2)
      diff++;
    valid++;
  }
  return (valid > 0 ? ((float)diff / (float)valid) : 0.0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<simple_distance>:
  endbr64
  mov    %rsi,%r10
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L61
  push   %rbp
  mov    %rdi,%r8
  xor    %r11d,%r11d
  xor    %edi,%edi
  movabs $0x8000000000006001,%r9
  push   %rbx
  xor    %ebx,%ebx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L65:
  add    $0x1,%rdi
  movzbl (%r8,%rdi,1),%esi
  test   %sil,%sil
  je     L58
L8:
  lea    -0x20(%rsi),%ecx
  mov    %r9,%rax
  xor    %edx,%edx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x40,%cl
  cmovae %edx,%eax
  cmp    $0x7e,%sil
  sete   %dl
  or     %al,%dl
  jne    L65
  movzbl (%r10,%rdi,1),%ebp
  mov    %r9,%rax
  lea    -0x20(%rbp),%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x40,%cl
  cmovb  %eax,%edx
  cmp    $0x7e,%bpl
  je     L65
  test   %dl,%dl
  jne    L65
  xor    %eax,%eax
  cmp    %sil,%bpl
  setne  %al
  add    $0x1,%rdi
  add    $0x1,%r11d
  movzbl (%r8,%rdi,1),%esi
  add    %eax,%ebx
  test   %sil,%sil
  jne    L8
  nopw   0x0(%rax,%rax,1)
L58:
  pxor   %xmm0,%xmm0
  test   %r11d,%r11d
  je     L36
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm0
  cvtsi2ss %r11d,%xmm1
  divss  %xmm1,%xmm0
L36:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L61:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float simple_distance(char *s1, char *s2) {
  int diff = 0;
  int valid = 0;
  for (; *s1 != '\0'; s1++, s2++) {
    if (((*s1) == ' ' || (*s1) == '.' || (*s1) == '_' || (*s1) == '-' || (*s1) == '~') || ((*s2) == ' ' || (*s2) == '.' || (*s2) == '_' || (*s2) == '-' || (*s2) == '~'))
      continue;
    if (*s1 != *s2)
      diff++;
    valid++;
  }
  return (valid > 0 ? ((float)diff / (float)valid) : 0.0);
}
```
user: What is the c source code of the assembly code below?

```asm
<simple_distance>:
  endbr64
  mov    %rsi,%r10
  movzbl (%rdi),%esi
  test   %sil,%sil
  je     L77
  push   %rbp
  mov    %rdi,%r8
  xor    %r11d,%r11d
  xor    %edi,%edi
  movabs $0x8000000000006001,%r9
  push   %rbx
  xor    %ebx,%ebx
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L4:
  add    $0x1,%rdi
  movzbl (%r8,%rdi,1),%esi
  test   %sil,%sil
  je     L58
L43:
  lea    -0x20(%rsi),%ecx
  mov    %r9,%rax
  xor    %edx,%edx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x40,%cl
  cmovae %edx,%eax
  cmp    $0x7e,%sil
  sete   %dl
  or     %al,%dl
  jne    L4
  movzbl (%r10,%rdi,1),%ebp
  mov    %r9,%rax
  lea    -0x20(%rbp),%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  cmp    $0x40,%cl
  cmovb  %eax,%edx
  cmp    $0x7e,%bpl
  je     L4
  test   %dl,%dl
  jne    L4
  xor    %eax,%eax
  cmp    %sil,%bpl
  setne  %al
  add    $0x1,%rdi
  add    $0x1,%r11d
  movzbl (%r8,%rdi,1),%esi
  add    %eax,%ebx
  test   %sil,%sil
  jne    L43
  nopw   0x0(%rax,%rax,1)
L58:
  pxor   %xmm0,%xmm0
  test   %r11d,%r11d
  je     L41
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2ss %ebx,%xmm0
  cvtsi2ss %r11d,%xmm1
  divss  %xmm1,%xmm0
L41:
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L77:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
float simple_distance(char *s1, char *s2) {
  int diff = 0;
  int valid = 0;
  for (; *s1 != '\0'; s1++, s2++) {
    if (((*s1) == ' ' || (*s1) == '.' || (*s1) == '_' || (*s1) == '-' || (*s1) == '~') || ((*s2) == ' ' || (*s2) == '.' || (*s2) == '_' || (*s2) == '-' || (*s2) == '~'))
      continue;
    if (*s1 != *s2)
      diff++;
    valid++;
  }
  return (valid > 0 ? ((float)diff / (float)valid) : 0.0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<update_position>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  cmp    $0x9,%eax
  je     L2
  cmp    $0xa,%eax
  jne    L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L3
L2:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x8(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L1:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  nop
L3:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void update_position(int *line, int *column, char c) {
  switch (c) {
  case '\n':
    ++*line;
    *column = 1;
    break;
  case '\t':
    *column += 8;
  default:
    ++*column;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<update_position>:
  endbr64
  cmp    $0x9,%dl
  je     L5
  cmp    $0xa,%dl
  jne    L11
  addl   $0x1,(%rdi)
  mov    $0x1,%eax
  jmp    L4
L5:
  addl   $0x8,(%rsi)
L11:
  mov    (%rsi),%eax
  add    $0x1,%eax
L4:
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void update_position(int *line, int *column, char c) {
  switch (c) {
  case '\n':
    ++*line;
    *column = 1;
    break;
  case '\t':
    *column += 8;
  default:
    ++*column;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<update_position>:
  endbr64
  cmp    $0x9,%dl
  je     L4
  cmp    $0xa,%dl
  je     L16
  mov    (%rsi),%eax
L27:
  add    $0x1,%eax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    (%rsi),%eax
  add    $0x8,%eax
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  addl   $0x1,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void update_position(int *line, int *column, char c) {
  switch (c) {
  case '\n':
    ++*line;
    *column = 1;
    break;
  case '\t':
    *column += 8;
  default:
    ++*column;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<update_position>:
  endbr64
  cmp    $0x9,%dl
  je     L21
  cmp    $0xa,%dl
  je     L9
  mov    (%rsi),%eax
L15:
  add    $0x1,%eax
  mov    %eax,(%rsi)
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    (%rsi),%eax
  add    $0x8,%eax
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%eax
  addl   $0x1,(%rdi)
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void update_position(int *line, int *column, char c) {
  switch (c) {
  case '\n':
    ++*line;
    *column = 1;
    break;
  case '\t':
    *column += 8;
  default:
    ++*column;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<transpose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L12:
  movl   $0x0,-0x4(%rbp)
  jmp    L35
L39:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  movsd  (%rcx,%rax,8),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x4(%rbp)
L35:
  cmpl   $0x2,-0x4(%rbp)
  jle    L39
  addl   $0x1,-0x8(%rbp)
L33:
  cmpl   $0x2,-0x8(%rbp)
  jle    L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transpose(mat, trans_mat) double mat[3][3];
double trans_mat[3][3];
{
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      trans_mat[i][j] = mat[j][i];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<transpose>:
  endbr64
  mov    %rdi,%rax
  add    $0x18,%rdi
L6:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x18(%rax),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x30(%rax),%xmm0
  movsd  %xmm0,0x10(%rsi)
  add    $0x8,%rax
  add    $0x18,%rsi
  cmp    %rdi,%rax
  jne    L6
  ret
```

assistant: ```c
void transpose(mat, trans_mat) double mat[3][3];
double trans_mat[3][3];
{
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      trans_mat[i][j] = mat[j][i];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<transpose>:
  endbr64
  lea    0x18(%rdi),%rax
L8:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  add    $0x18,%rsi
  movsd  %xmm0,-0x18(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,-0x10(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,-0x8(%rsi)
  cmp    %rax,%rdi
  jne    L8
  ret
```

assistant: ```c
void transpose(mat, trans_mat) double mat[3][3];
double trans_mat[3][3];
{
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      trans_mat[i][j] = mat[j][i];
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<transpose>:
  endbr64
  lea    0x47(%rdi),%rax
  sub    %rsi,%rax
  cmp    $0x8e,%rax
  jbe    L2
  movupd (%rdi),%xmm1
  movupd 0x18(%rdi),%xmm0
  movupd 0x30(%rdi),%xmm2
  movapd %xmm1,%xmm3
  movapd %xmm1,%xmm4
  unpcklpd %xmm0,%xmm3
  movsd  %xmm2,%xmm4
  shufpd $0x1,%xmm1,%xmm0
  movsd  %xmm0,%xmm2
  movups %xmm3,(%rsi)
  movups %xmm4,0x10(%rsi)
  movups %xmm2,0x20(%rsi)
L19:
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x38(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  ret
  nopl   0x0(%rax)
L2:
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x18(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x38(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  jmp    L19
```

assistant: ```c
void transpose(mat, trans_mat) double mat[3][3];
double trans_mat[3][3];
{
  int i, j;
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 3; j++) {
      trans_mat[i][j] = mat[j][i];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<UtfCount>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L69
  cmpl   $0x7f,-0x4(%rbp)
  jg     L69
  mov    $0x1,%eax
  jmp    L48
L69:
  cmpl   $0x7ff,-0x4(%rbp)
  jg     L56
  mov    $0x2,%eax
  jmp    L48
L56:
  cmpl   $0xffff,-0x4(%rbp)
  jg     L3
  mov    $0x3,%eax
  jmp    L48
L3:
  mov    $0x3,%eax
L48:
  pop    %rbp
  ret
```

assistant: ```c
int UtfCount(ch)
int ch;
{
  if ((ch > 0) && (ch < 0x80)) {
    return 1;
  }
  if (ch <= 0x7FF) {
    return 2;
  }
  if (ch <= 0xFFFF) {
    return 3;
  }
  return 3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<UtfCount>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x7e,%edx
  jbe    L6
  cmp    $0x7ff,%edi
  setg   %al
  movzbl %al,%eax
  add    $0x2,%eax
L6:
  ret
```

assistant: ```c
int UtfCount(ch)
int ch;
{
  if ((ch > 0) && (ch < 0x80)) {
    return 1;
  }
  if (ch <= 0x7FF) {
    return 2;
  }
  if (ch <= 0xFFFF) {
    return 3;
  }
  return 3;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UtfCount>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x7e,%edx
  jbe    L0
  xor    %eax,%eax
  cmp    $0x7ff,%edi
  setg   %al
  add    $0x2,%eax
L0:
  ret
```

assistant: ```c
int UtfCount(ch)
int ch;
{
  if ((ch > 0) && (ch < 0x80)) {
    return 1;
  }
  if (ch <= 0x7FF) {
    return 2;
  }
  if (ch <= 0xFFFF) {
    return 3;
  }
  return 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<UtfCount>:
  endbr64
  lea    -0x1(%rdi),%edx
  mov    $0x1,%eax
  cmp    $0x7e,%edx
  jbe    L7
  xor    %eax,%eax
  cmp    $0x7ff,%edi
  setg   %al
  add    $0x2,%eax
L7:
  ret
```

assistant: ```c
int UtfCount(ch)
int ch;
{
  if ((ch > 0) && (ch < 0x80)) {
    return 1;
  }
  if (ch <= 0x7FF) {
    return 2;
  }
  if (ch <= 0xFFFF) {
    return 3;
  }
  return 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x24(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int g(long long a, long long b, int c) {
  int d = a != b;
  return d + c;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<g>:
  endbr64
  cmp    %rsi,%rdi
  setne  %al
  movzbl %al,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
int g(long long a, long long b, int c) {
  int d = a != b;
  return d + c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<g>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  setne  %al
  add    %edx,%eax
  ret
```

assistant: ```c
int g(long long a, long long b, int c) {
  int d = a != b;
  return d + c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<g>:
  endbr64
  xor    %eax,%eax
  cmp    %rsi,%rdi
  setne  %al
  add    %edx,%eax
  ret
```

assistant: ```c
int g(long long a, long long b, int c) {
  int d = a != b;
  return d + c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_filetype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L44
  mov    -0x10(%rbp),%rax
  lea    D59(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L53
L44:
  mov    -0x8(%rbp),%rax
  lea    D14(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L36
  mov    -0x10(%rbp),%rax
  lea    D47(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  jmp    L53
L36:
  mov    -0x8(%rbp),%rax
  lea    D73(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L16
  mov    -0x10(%rbp),%rax
  lea    D44(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L65
L16:
  mov    -0x8(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L56
  mov    -0x10(%rbp),%rax
  lea    D84(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L65
L56:
  mov    -0x10(%rbp),%rax
  lea    D20(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L53:
  mov    $0x0,%eax
L65:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string
name: parse_data
arguments: tag: D59
data_type: string
name: parse_data
arguments: tag: D14
data_type: string
name: parse_data
arguments: tag: D47
data_type: string
name: parse_data
arguments: tag: D73
data_type: string
name: parse_data
arguments: tag: D44
data_type: string
name: parse_data
arguments: tag: D9
data_type: string
name: parse_data
arguments: tag: D84
data_type: string
name: parse_data
arguments: tag: D20
data_type: string

tool: D7: .html

tool: D59: text/html


tool: D14: .gif

tool: D47: image/gif

tool: D73: .jpg

tool: D44: image/jpeg


tool: D9: .png

tool: D84: image/png


tool: 

assistant: ```c
int get_filetype(char *filename, char *filetype) {
  if (strstr(filename, ".html"))
    strcpy(filetype, "text/html\r\n");
  else if (strstr(filename, ".gif"))
    strcpy(filetype, "image/gif");
  else if (strstr(filename, ".jpg")) {
    strcpy(filetype, "image/jpeg\r\n");
    return 1;
  } else if (strstr(filename, ".png")) {
    strcpy(filetype, "image/png\r\n");
    return 1;
  } else
    strcpy(filetype, "");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_filetype>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D28(%rip),%rsi
  call   <strstr@plt>
  test   %rax,%rax
  je     L44
  lea    D20(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L44:
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L40
  lea    D52(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  jmp    L2
L40:
  lea    D59(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L47
  lea    D39(%rip),%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L61
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  jmp    L2
L47:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L2
L61:
  lea    D46(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L2
```

tool_calls: name: unpack_data
arguments: label: D28
type_infered: string
name: unpack_data
arguments: label: D20
type_infered: string
name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D52
type_infered: string
name: unpack_data
arguments: label: D59
type_infered: string
name: unpack_data
arguments: label: D39
type_infered: string
name: unpack_data
arguments: label: D27
type_infered: string
name: unpack_data
arguments: label: D17
type_infered: string
name: unpack_data
arguments: label: D46
type_infered: string

tool: D28: .html

tool: D20: text/html


tool: D6: .gif

tool: D52: image/gif

tool: D59: .jpg

tool: D39: .png

tool: 

tool: D17: image/jpeg


tool: D46: image/png


assistant: ```c
int get_filetype(char *filename, char *filetype) {
  if (strstr(filename, ".html"))
    strcpy(filetype, "text/html\r\n");
  else if (strstr(filename, ".gif"))
    strcpy(filetype, "image/gif");
  else if (strstr(filename, ".jpg")) {
    strcpy(filetype, "image/jpeg\r\n");
    return 1;
  } else if (strstr(filename, ".png")) {
    strcpy(filetype, "image/png\r\n");
    return 1;
  } else
    strcpy(filetype, "");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_filetype>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D24(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L7
  lea    D41(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  xor    %eax,%eax
L12:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L2
  mov    %r12,%rdi
  lea    D62(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L2:
  lea    D47(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L41
  lea    D52(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L50
  mov    %r12,%rdi
  lea    D16(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L41:
  lea    D2(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L12
  nopl   0x0(%rax)
L50:
  lea    D35(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L12
```

tool_calls: name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D41
datatype: string
name: parse_data
arguments: label: D45
datatype: string
name: parse_data
arguments: label: D62
datatype: string
name: parse_data
arguments: label: D47
datatype: string
name: parse_data
arguments: label: D52
datatype: string
name: parse_data
arguments: label: D16
datatype: string
name: parse_data
arguments: label: D2
datatype: string
name: parse_data
arguments: label: D35
datatype: string

tool: D24: .html

tool: D41: text/html


tool: D45: .gif

tool: D62: image/gif

tool: D47: .jpg

tool: D52: .png

tool: 

tool: D2: image/jpeg


tool: D35: image/png


assistant: ```c
int get_filetype(char *filename, char *filetype) {
  if (strstr(filename, ".html"))
    strcpy(filetype, "text/html\r\n");
  else if (strstr(filename, ".gif"))
    strcpy(filetype, "image/gif");
  else if (strstr(filename, ".jpg")) {
    strcpy(filetype, "image/jpeg\r\n");
    return 1;
  } else if (strstr(filename, ".png")) {
    strcpy(filetype, "image/png\r\n");
    return 1;
  } else
    strcpy(filetype, "");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_filetype>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  lea    D50(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strstr@plt>
  test   %rax,%rax
  je     L43
  lea    D51(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  xor    %eax,%eax
L7:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  lea    D40(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L10
  mov    %r12,%rdi
  lea    D55(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L10:
  lea    D45(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L1
  lea    D67(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L30
  mov    %r12,%rdi
  lea    D8(%rip),%rsi
  call   <strcpy@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L1:
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L7
  nopl   0x0(%rax)
L30:
  lea    D62(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    $0x1,%eax
  jmp    L7
```

tool_calls: name: unpack_data
arguments: label: D50
datatype: string
name: unpack_data
arguments: label: D51
datatype: string
name: unpack_data
arguments: label: D40
datatype: string
name: unpack_data
arguments: label: D55
datatype: string
name: unpack_data
arguments: label: D45
datatype: string
name: unpack_data
arguments: label: D67
datatype: string
name: unpack_data
arguments: label: D8
datatype: string
name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D62
datatype: string

tool: D50: .html

tool: D51: text/html


tool: D40: .gif

tool: D55: image/gif

tool: D45: .jpg

tool: D67: .png

tool: 

tool: D3: image/jpeg


tool: D62: image/png


assistant: ```c
int get_filetype(char *filename, char *filetype) {
  if (strstr(filename, ".html"))
    strcpy(filetype, "text/html\r\n");
  else if (strstr(filename, ".gif"))
    strcpy(filetype, "image/gif");
  else if (strstr(filename, ".jpg")) {
    strcpy(filetype, "image/jpeg\r\n");
    return 1;
  } else if (strstr(filename, ".png")) {
    strcpy(filetype, "image/png\r\n");
    return 1;
  } else
    strcpy(filetype, "");
  return 0;
}
```