ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<file_parse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x2b0,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x2a8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rsi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rsi
  mov    %r12,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  mov    %rsp,%rbx
  test   %rax,%rax
  je     L14
L58:
  mov    %rbp,%rdx
  mov    $0x2a8,%esi
  mov    %rbx,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L54
  mov    %rbx,%rdi
  call   <check_upper_case@plt>
  test   %eax,%eax
  jne    L4
  mov    %rbx,%rdi
  call   <convert_to_int@plt>
  jmp    L58
L4:
  mov    %rsp,%rsi
  lea    D13(%rip),%rdi
  call   <printf@plt>
L54:
  mov    %rbp,%rdi
  call   <fclose@plt>
L5:
  mov    0x2a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x2b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %r12,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L5
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D38
type: string
name: unpack_data
arguments: tag: D37
type: string
name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D9
type: string

tool: D38: config file is: %s


tool: D37: r

tool: D13: Error!!!there is a upper case 'X' in config file 
Line: %s


tool: D9: can not open file in:%s

assistant: ```c
int file_parse(char *path) {
  FILE *filed;
  char tmp[680];
  int test = 0;
  int ret = 0;
  printf("config file is: %s\n", path);
  filed = fopen(path, "r");
  if (filed != NULL) {
    while (fgets(tmp, 680, filed) != NULL) {
      ret = check_upper_case(tmp);
      if (ret != 0) {
        printf("Error!!!there is a upper case 'X' in config file \nLine: %s\n", tmp);
        break;
      } else
        convert_to_int(tmp);
    }
    fclose(filed);
    return 0;
  } else {
    printf("can not open file in:%s", path);
    return 0;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<file_parse>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  mov    %rdi,%r13
  lea    D27(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x2b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  lea    D18(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L8
  jmp    L67
  nopl   0x0(%rax)
L46:
  mov    %rbp,%rdi
  call   <check_upper_case@plt>
  test   %eax,%eax
  jne    L63
  mov    %rbp,%rdi
  call   <convert_to_int@plt>
L8:
  mov    %r12,%rdx
  mov    $0x2a8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L46
L44:
  mov    %r12,%rdi
  call   <fclose@plt>
L41:
  mov    0x2a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x2b0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L63:
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L44
  nopl   0x0(%rax)
L67:
  mov    %r13,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L41
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D27: config file is: %s


tool: D18: r

tool: D3: Error!!!there is a upper case 'X' in config file 
Line: %s


tool: D7: can not open file in:%s

assistant: ```c
int file_parse(char *path) {
  FILE *filed;
  char tmp[680];
  int test = 0;
  int ret = 0;
  printf("config file is: %s\n", path);
  filed = fopen(path, "r");
  if (filed != NULL) {
    while (fgets(tmp, 680, filed) != NULL) {
      ret = check_upper_case(tmp);
      if (ret != 0) {
        printf("Error!!!there is a upper case 'X' in config file \nLine: %s\n", tmp);
        break;
      } else
        convert_to_int(tmp);
    }
    fclose(filed);
    return 0;
  } else {
    printf("can not open file in:%s", path);
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<file_parse>:
  endbr64
  push   %r13
  mov    %rdi,%rsi
  mov    %rdi,%r13
  lea    D17(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x2b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x2a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  lea    D36(%rip),%rsi
  mov    %r13,%rdi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %rax,%rax
  jne    L0
  jmp    L26
  nopl   0x0(%rax)
L60:
  mov    %rbp,%rdi
  call   <check_upper_case@plt>
  test   %eax,%eax
  jne    L9
  mov    %rbp,%rdi
  call   <convert_to_int@plt>
L0:
  mov    %r12,%rdx
  mov    $0x2a8,%esi
  mov    %rbp,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  jne    L60
L49:
  mov    %r12,%rdi
  call   <fclose@plt>
L57:
  mov    0x2a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L45
  add    $0x2b0,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %rbp,%rsi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L49
  nopl   0x0(%rax)
L26:
  mov    %r13,%rsi
  lea    D38(%rip),%rdi
  call   <printf@plt>
  jmp    L57
L45:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D17
data_type: string
name: read_data
arguments: data_label: D36
data_type: string
name: read_data
arguments: data_label: D34
data_type: string
name: read_data
arguments: data_label: D38
data_type: string

tool: D17: config file is: %s


tool: D36: r

tool: D34: Error!!!there is a upper case 'X' in config file 
Line: %s


tool: D38: can not open file in:%s

assistant: ```c
int file_parse(char *path) {
  FILE *filed;
  char tmp[680];
  int test = 0;
  int ret = 0;
  printf("config file is: %s\n", path);
  filed = fopen(path, "r");
  if (filed != NULL) {
    while (fgets(tmp, 680, filed) != NULL) {
      ret = check_upper_case(tmp);
      if (ret != 0) {
        printf("Error!!!there is a upper case 'X' in config file \nLine: %s\n", tmp);
        break;
      } else
        convert_to_int(tmp);
    }
    fclose(filed);
    return 0;
  } else {
    printf("can not open file in:%s", path);
    return 0;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmdshell_init_password>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x410,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x3f0(%rbp)
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%edx
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <input_line@plt>
  mov    %eax,-0x3f8(%rbp)
  cmpl   $0x0,-0x3f8(%rbp)
  jne    L47
  mov    -0x408(%rbp),%rax
  movb   $0x0,(%rax)
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x3fc(%rbp)
  jmp    L20
L47:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x3f4(%rbp)
  cmpl   $0x64,-0x3f4(%rbp)
  ja     L17
  lea    -0x3f0(%rbp),%rdx
  mov    -0x408(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x3f4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x1,-0x3fc(%rbp)
  jmp    L20
L17:
  mov    -0x3f4(%rbp),%eax
  mov    $0x64,%edx
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x3fc(%rbp)
L20:
  mov    -0x3fc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
type: string
name: retrieve_data
arguments: label: D13
type: string
name: retrieve_data
arguments: label: D2
type: string
name: retrieve_data
arguments: label: D36
type: string

tool: D17: Input password: 

tool: D13: Ok empty

tool: D2: Ok %u characters


tool: D36: Fail too long password %u, maximum may be %u characters


assistant: ```c
int cmdshell_init_password(char password[]) {
  char input[1000];
  int retval, retin;
  *input = '\0';
  retin = input_line("Input password: ", input, sizeof input);
  if (!retin) {
    *password = '\0';
    printf("Ok empty\n");
    retval = 1;
  } else {
    unsigned int len = strlen(input);
    if (len <= 100) {
      strcpy(password, input);
      printf("Ok %u characters\n", len);
      retval = 1;
    } else {
      printf("Fail too long password %u, "
             "maximum may be %u characters\n",
             len, 100);
      retval = 0;
    }
  }
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cmdshell_init_password>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsp)
  mov    %rsp,%rsi
  mov    $0x3e8,%edx
  lea    D2(%rip),%rdi
  call   <input_line@plt>
  test   %eax,%eax
  jne    L27
  movb   $0x0,0x0(%rbp)
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L32:
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L17
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L27:
  mov    %rsp,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  cmp    $0x64,%eax
  ja     L11
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %ebx,%esi
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L32
L11:
  mov    $0x64,%edx
  mov    %eax,%esi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L32
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: string
name: disassemble_data
arguments: tag: D34
datatype: string
name: disassemble_data
arguments: tag: D39
datatype: string

tool: D2: Input password: 

tool: D21: Ok empty

tool: D34: Ok %u characters


tool: D39: Fail too long password %u, maximum may be %u characters


assistant: ```c
int cmdshell_init_password(char password[]) {
  char input[1000];
  int retval, retin;
  *input = '\0';
  retin = input_line("Input password: ", input, sizeof input);
  if (!retin) {
    *password = '\0';
    printf("Ok empty\n");
    retval = 1;
  } else {
    unsigned int len = strlen(input);
    if (len <= 100) {
      strcpy(password, input);
      printf("Ok %u characters\n", len);
      retval = 1;
    } else {
      printf("Fail too long password %u, "
             "maximum may be %u characters\n",
             len, 100);
      retval = 0;
    }
  }
  return retval;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cmdshell_init_password>:
  endbr64
  push   %r13
  mov    $0x3e8,%edx
  mov    %rdi,%r13
  lea    D9(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movb   $0x0,(%rsp)
  mov    %rbp,%rsi
  call   <input_line@plt>
  test   %eax,%eax
  jne    L19
  movb   $0x0,0x0(%r13)
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L37:
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L27
  add    $0x3f0,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    $0x64,%eax
  ja     L5
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12d,%esi
  lea    D23(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L5:
  mov    %eax,%esi
  mov    $0x64,%edx
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L37
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D23
type_infered: string
name: read_data
arguments: data_label: D35
type_infered: string

tool: D9: Input password: 

tool: D8: Ok empty

tool: D23: Ok %u characters


tool: D35: Fail too long password %u, maximum may be %u characters


assistant: ```c
int cmdshell_init_password(char password[]) {
  char input[1000];
  int retval, retin;
  *input = '\0';
  retin = input_line("Input password: ", input, sizeof input);
  if (!retin) {
    *password = '\0';
    printf("Ok empty\n");
    retval = 1;
  } else {
    unsigned int len = strlen(input);
    if (len <= 100) {
      strcpy(password, input);
      printf("Ok %u characters\n", len);
      retval = 1;
    } else {
      printf("Fail too long password %u, "
             "maximum may be %u characters\n",
             len, 100);
      retval = 0;
    }
  }
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmdshell_init_password>:
  endbr64
  push   %r13
  mov    $0x3e8,%edx
  mov    %rdi,%r13
  lea    D2(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x3f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movb   $0x0,(%rsp)
  mov    %rbp,%rsi
  call   <input_line@plt>
  test   %eax,%eax
  jne    L40
  movb   $0x0,0x0(%r13)
  lea    D31(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L46:
  mov    0x3e8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x3f0,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    $0x64,%eax
  ja     L39
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12d,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L46
  nopl   0x0(%rax,%rax,1)
L39:
  mov    %eax,%esi
  mov    $0x64,%edx
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  jmp    L46
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_infered: string
name: parse_data
arguments: tag: D31
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string

tool: D2: Input password: 

tool: D31: Ok empty

tool: D11: Ok %u characters


tool: D26: Fail too long password %u, maximum may be %u characters


assistant: ```c
int cmdshell_init_password(char password[]) {
  char input[1000];
  int retval, retin;
  *input = '\0';
  retin = input_line("Input password: ", input, sizeof input);
  if (!retin) {
    *password = '\0';
    printf("Ok empty\n");
    retval = 1;
  } else {
    unsigned int len = strlen(input);
    if (len <= 100) {
      strcpy(password, input);
      printf("Ok %u characters\n", len);
      retval = 1;
    } else {
      printf("Fail too long password %u, "
             "maximum may be %u characters\n",
             len, 100);
      retval = 0;
    }
  }
  return retval;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getNameVal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0xa,%eax
  jne    L70
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x4d,%al
  jne    L70
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x55,%al
  jne    L70
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x53,%al
  jne    L70
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L70
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L70
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L70
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L70
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L70
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L70
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    $0x64,%edx
  imul   %edx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  movzbl (%rax),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  jmp    L84
L70:
  mov    $0x0,%eax
L84:
  leave
  ret
```

assistant: ```c
char getNameVal(char name[]) {
  if (strlen(name) == 10 && name[0] == 'M' && name[1] == 'U' && name[2] == 'S' && name[3] >= '0' && name[3] <= '9' && name[4] >= '0' && name[4] <= '9' && name[5] >= '0' && name[5] <= '9') {
    return ((name[3] - 48) * 100) + ((name[4] - 48) * 10) + (name[5] - 48);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getNameVal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x0,%eax
  cmp    $0xa,%edx
  je     L11
L13:
  pop    %rbx
  ret
L11:
  cmpb   $0x4d,(%rbx)
  jne    L13
  cmpb   $0x55,0x1(%rbx)
  jne    L13
  cmpb   $0x53,0x2(%rbx)
  jne    L13
  movzbl 0x3(%rbx),%edx
  lea    -0x30(%rdx),%ecx
  cmp    $0x9,%cl
  ja     L13
  movzbl 0x4(%rbx),%ecx
  lea    -0x30(%rcx),%esi
  cmp    $0x9,%sil
  ja     L13
  movzbl 0x5(%rbx),%esi
  sub    $0x30,%esi
  cmp    $0x9,%sil
  ja     L13
  sub    $0x30,%edx
  mov    $0x64,%edi
  mov    %edx,%eax
  imul   %edi,%eax
  mov    %eax,%edx
  add    %esi,%edx
  lea    -0x30(%rcx),%eax
  mov    $0xa,%ecx
  imul   %ecx,%eax
  add    %edx,%eax
  jmp    L13
```

assistant: ```c
char getNameVal(char name[]) {
  if (strlen(name) == 10 && name[0] == 'M' && name[1] == 'U' && name[2] == 'S' && name[3] >= '0' && name[3] <= '9' && name[4] >= '0' && name[4] <= '9' && name[5] >= '0' && name[5] <= '9') {
    return ((name[3] - 48) * 100) + ((name[4] - 48) * 10) + (name[5] - 48);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getNameVal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xa,%r8d
  je     L47
L58:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  cmpb   $0x4d,(%rbx)
  jne    L58
  cmpb   $0x55,0x1(%rbx)
  jne    L58
  cmpb   $0x53,0x2(%rbx)
  jne    L58
  movzbl 0x3(%rbx),%esi
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  ja     L58
  movzbl 0x4(%rbx),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L58
  movzbl 0x5(%rbx),%esi
  sub    $0x30,%esi
  cmp    $0x9,%sil
  ja     L58
  mov    $0x64,%edi
  mov    %edx,%eax
  pop    %rbx
  imul   %edi,%eax
  mov    $0xa,%edi
  mov    %eax,%edx
  mov    %ecx,%eax
  imul   %edi,%eax
  add    %eax,%edx
  lea    (%rdx,%rsi,1),%eax
  ret
```

assistant: ```c
char getNameVal(char name[]) {
  if (strlen(name) == 10 && name[0] == 'M' && name[1] == 'U' && name[2] == 'S' && name[3] >= '0' && name[3] <= '9' && name[4] >= '0' && name[4] <= '9' && name[5] >= '0' && name[5] <= '9') {
    return ((name[3] - 48) * 100) + ((name[4] - 48) * 10) + (name[5] - 48);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getNameVal>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0xa,%r8d
  je     L33
L5:
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L33:
  cmpb   $0x4d,(%rbx)
  jne    L5
  cmpb   $0x55,0x1(%rbx)
  jne    L5
  cmpb   $0x53,0x2(%rbx)
  jne    L5
  movzbl 0x3(%rbx),%esi
  lea    -0x30(%rsi),%edx
  cmp    $0x9,%dl
  ja     L5
  movzbl 0x4(%rbx),%ecx
  sub    $0x30,%ecx
  cmp    $0x9,%cl
  ja     L5
  movzbl 0x5(%rbx),%esi
  sub    $0x30,%esi
  cmp    $0x9,%sil
  ja     L5
  mov    $0x64,%edi
  mov    %edx,%eax
  pop    %rbx
  imul   %edi,%eax
  mov    $0xa,%edi
  mov    %eax,%edx
  mov    %ecx,%eax
  imul   %edi,%eax
  add    %eax,%edx
  lea    (%rdx,%rsi,1),%eax
  ret
```

assistant: ```c
char getNameVal(char name[]) {
  if (strlen(name) == 10 && name[0] == 'M' && name[1] == 'U' && name[2] == 'S' && name[3] >= '0' && name[3] <= '9' && name[4] >= '0' && name[4] <= '9' && name[5] >= '0' && name[5] <= '9') {
    return ((name[3] - 48) * 100) + ((name[4] - 48) * 10) + (name[5] - 48);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L15
  movss  -0x14(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L15
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L20
L15:
  movss  -0x10(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L26
  movss  -0x10(%rbp),%xmm0
  movss  -0xc(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L26
  mov    -0x10(%rbp),%eax
  movd   %eax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L20
L26:
  movss  -0xc(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L20
  movss  -0xc(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L20
  mov    -0xc(%rbp),%eax
  movd   %eax,%xmm0
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L79
  call   <__stack_chk_fail@plt>
L79:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D35
data_type: string
name: read_data
arguments: tag: D10
data_type: string

tool: D35: %f %f %f

tool: D10: 
%.1f

assistant: ```c
int main() {
  float x, y, z;
  scanf("%f %f %f", &x, &y, &z);
  if (x > y && x > z) {
    printf("\n%.1f", x);
  } else if (y > x && y > z) {
    printf("\n%.1f", y);
  } else if (z > x && z > y) {
    printf("\n%.1f", z);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm1
  comiss %xmm1,%xmm0
  jbe    L6
  comiss 0x14(%rsp),%xmm0
  ja     L72
L6:
  comiss %xmm0,%xmm1
  jbe    L32
  comiss 0x14(%rsp),%xmm1
  ja     L48
L32:
  movss  0x14(%rsp),%xmm2
  comiss %xmm0,%xmm2
  jbe    L95
  comiss %xmm1,%xmm2
  ja     L80
L95:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L92
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L72:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L95
L48:
  movaps %xmm1,%xmm0
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L95
L80:
  movaps %xmm2,%xmm0
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L95
L92:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string
name: disassemble_data
arguments: data_tag: D27
type_guessed: string

tool: D3: %f %f %f

tool: D27: 
%.1f

assistant: ```c
int main() {
  float x, y, z;
  scanf("%f %f %f", &x, &y, &z);
  if (x > y && x > z) {
    printf("\n%.1f", x);
  } else if (y > x && y > z) {
    printf("\n%.1f", y);
  } else if (z > x && z > y) {
    printf("\n%.1f", z);
  }
}
```