user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movq   $0xd700,0x10(%rsp)
  movq   $0xd810,0x18(%rsp)
  movq   $0xfdc0,0x20(%rsp)
  movq   $0xfdf0,0x28(%rsp)
  movq   $0xfff0,0x30(%rsp)
  movq   $0xfff0,0x38(%rsp)
  mov    $0x30,%ebp
  lea    D45(%rip),%r13
  lea    D23(%rip),%r12
L13:
  lea    -0x10(%rbp),%rbx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L10:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x10,%rbp
  cmp    $0x90,%rbp
  jne    L13
  lea    0x10(%rsp),%rax
  mov    %rax,0x8(%rsp)
  movq   $0x0,(%rsp)
  lea    D45(%rip),%r15
  lea    D22(%rip),%r12
L22:
  mov    0x8(%rsp),%rax
  mov    0x8(%rax),%r14
  mov    (%rax),%r13
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    (%rsp),%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r13,%r14
  jb     L5
  lea    0x10(%r13),%rbp
L68:
  mov    %r13,%rsi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13d,%ebx
L27:
  mov    %ebx,%ecx
  and    $0x3f,%ecx
  sub    $0xffffff80,%ecx
  mov    %ebx,%edx
  sar    $0x6,%edx
  and    $0x3f,%edx
  sub    $0xffffff80,%edx
  mov    %ebx,%esi
  sar    $0xc,%esi
  and    $0xf,%esi
  add    $0xe0,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebp,%ebx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x10,%r13
  add    $0x10,%rbp
  cmp    %r13,%r14
  jae    L68
L5:
  addq   $0x1,(%rsp)
  mov    (%rsp),%rax
  addq   $0x10,0x8(%rsp)
  cmp    $0x3,%rax
  jne    L22
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D45
datatype: string
name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D22
datatype: string
name: disassemble_data
arguments: tag: D3
datatype: string

tool: D45: %04x:

tool: D23:  %c

tool: D22:  %c%c%c

tool: D3: Block[%d]: %x -- %x


assistant: ```c
int main(int argc, char **argv) {
  struct _x {
    unsigned long l, u;
  };
  struct _x x[] = {{0xd700, 0xd810}, {0xfdc0, 0xfdf0}, {0xfff0, 0xfff0}};
  unsigned long k, j, i;
  for (k = 0x20; k < 0x80; k += 0x10) {
    printf("%04x:", k);
    for (j = 0; j < 0x10; j++)
      printf(" %c", k + j);
    printf("\n");
  }
  for (i = 0; i < ((sizeof(x)) / (sizeof(x[0]))); i++) {
    printf("Block[%d]: %x -- %x\n", i, x[i].l, x[i].u);
    for (k = x[i].l; k <= x[i].u; k += 0x10) {
      printf("%04x:", k);
      for (j = 0; j < 0x10; j++) {
        int sum = k + j;
        int b0 = 0x80 + ((sum & 0x003f));
        int b1 = 0x80 + ((sum & 0x0fc0) >> 6);
        int b2 = 0xe0 + ((sum & 0xf000) >> 12);
        printf(" %c%c%c", b2, b1, b0);
      }
      printf("\n");
    }
  }
}
```