ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<atofs>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <strlen@plt>
  mov    %eax,%ebp
  cltq
  lea    -0x1(%r12,%rax,1),%rbx
  cmp    $0x1,%ebp
  jg     L19
  jmp    L5
  nopl   0x0(%rax)
L50:
  sub    $0x1,%ebp
  sub    $0x1,%rbx
  cmp    $0x1,%ebp
  je     L99
L19:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L50
L5:
  movzbl (%rbx),%ebp
  movb   $0x0,(%rbx)
  lea    -0x47(%rbp),%ecx
  cmp    $0x26,%cl
  ja     L29
  movabs $0x100000001,%rdx
  mov    $0x1,%eax
  shl    %cl,%rax
  test   %rdx,%rax
  jne    L106
  movabs $0x1000000010,%rdx
  test   %rdx,%rax
  jne    L23
  movabs $0x4000000040,%rdx
  test   %rdx,%rax
  jne    L0
L29:
  mov    %bpl,(%rbx)
  add    $0x10,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <atof@plt>
  nopw   0x0(%rax,%rax,1)
L99:
  mov    %r12,%rbx
  jmp    L5
L0:
  movsd  D11(%rip),%xmm2
  movsd  %xmm2,0x8(%rsp)
L18:
  mov    %r12,%rdi
  call   <atof@plt>
  mov    %bpl,(%rbx)
  mulsd  0x8(%rsp),%xmm0
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  movsd  D25(%rip),%xmm4
  movsd  %xmm4,0x8(%rsp)
  jmp    L18
L106:
  movsd  D15(%rip),%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L18
```

tool_calls: name: extract_symbolic_data
arguments: label: D11
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D25
datatype: f64
name: extract_symbolic_data
arguments: label: D15
datatype: byte[8]

tool: {"D11": [0x00,0x00,0x00,0x00,0x80,0x84,0x2e,0x41]}

tool: D25: 1000

tool: {"D15": [0x00,0x00,0x00,0x00,0x65,0xcd,0xcd,0x41]}

assistant: ```c
double atofs(char *s) {
  char last;
  int len;
  double suff = 1.0;
  len = strlen(s);
  while (len > 1 && isspace(s[len - 1]))
    --len;
  last = s[len - 1];
  s[len - 1] = '\0';
  switch (last) {
  case 'g':
  case 'G':
    suff *= 1e3;
  case 'm':
  case 'M':
    suff *= 1e3;
  case 'k':
  case 'K':
    suff *= 1e3;
    suff *= atof(s);
    s[len - 1] = last;
    return suff;
  }
  s[len - 1] = last;
  return atof(s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <fun@plt>
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string

tool: D2: %d

tool: D11: %.4lf


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%.4lf\n", fun(n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fun@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
datatype: string
name: parse_data
arguments: tag: D4
datatype: string

tool: D19: %d

tool: D4: %.4lf


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%.4lf\n", fun(n));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fun@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D4
type: string

tool: D7: %d

tool: D4: %.4lf


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%.4lf\n", fun(n));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <fun@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
datatype: string
name: disassemble_data
arguments: data_tag: D8
datatype: string

tool: D18: %d

tool: D8: %.4lf


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%.4lf\n", fun(n));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<inet_ntoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D12(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
char *inet_ntoa(void *in) {
  errno = ENXIO;
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<inet_ntoa>:
  endbr64
  mov    D14(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  ret
```

assistant: ```c
char *inet_ntoa(void *in) {
  errno = ENXIO;
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<inet_ntoa>:
  endbr64
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *inet_ntoa(void *in) {
  errno = ENXIO;
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inet_ntoa>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  xor    %eax,%eax
  ret
```

assistant: ```c
char *inet_ntoa(void *in) {
  errno = ENXIO;
  return NULL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<M4U_WriteReg32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%eax
  mov    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <iowrite32@plt>
  mov    $0x0,%eax
  call   <mb@plt>
  nop
  leave
  ret
```

assistant: ```c
void M4U_WriteReg32(unsigned int M4uBase, unsigned int Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: What is the c source code of the assembly code below:

```asm
<M4U_WriteReg32>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%eax
  mov    %edx,%edi
  lea    (%rax,%rsi,1),%esi
  call   <iowrite32@plt>
  mov    $0x0,%eax
  call   <mb@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void M4U_WriteReg32(unsigned int M4uBase, unsigned int Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<M4U_WriteReg32>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    %edx,%edi
  add    %r8d,%esi
  mov    %esi,%esi
  call   <iowrite32@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <mb@plt>
```

assistant: ```c
void M4U_WriteReg32(unsigned int M4uBase, unsigned int Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<M4U_WriteReg32>:
  endbr64
  mov    %edi,%r8d
  sub    $0x8,%rsp
  mov    %edx,%edi
  add    %r8d,%esi
  mov    %esi,%esi
  call   <iowrite32@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <mb@plt>
```

assistant: ```c
void M4U_WriteReg32(unsigned int M4uBase, unsigned int Offset, unsigned int Val) {
  iowrite32(Val, (void *)(M4uBase + Offset));
  mb();
}
```
user: What is the c source code of the assembly code below:

```asm
<parsein>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <skip@plt>
  mov    -0x8(%rbp),%rax
  mov    $0xd,%esi
  mov    %rax,%rdi
  call   <skip@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <sout@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: D4: %s

assistant: ```c
void parsein(char *s) {
  skip(s, '\n');
  skip(s, '\r');
  sout("%s", s);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<parsein>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%esi
  call   <skip@plt>
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <skip@plt>
  mov    %rbx,%rsi
  lea    D4(%rip),%rdi
  call   <sout@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: D4: %s

assistant: ```c
void parsein(char *s) {
  skip(s, '\n');
  skip(s, '\r');
  sout("%s", s);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parsein>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <skip@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  call   <skip@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  pop    %rbp
  jmp    1060 <sout@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: %s

assistant: ```c
void parsein(char *s) {
  skip(s, '\n');
  skip(s, '\r');
  sout("%s", s);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parsein>:
  endbr64
  push   %rbp
  mov    $0xa,%esi
  mov    %rdi,%rbp
  call   <skip@plt>
  mov    %rbp,%rdi
  mov    $0xd,%esi
  call   <skip@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  pop    %rbp
  jmp    1060 <sout@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: %s

assistant: ```c
void parsein(char *s) {
  skip(s, '\n');
  skip(s, '\r');
  sout("%s", s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<splitline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8d,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x3d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  cmpq   $0x0,-0x8(%rbp)
  je     L39
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x28(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <cutspaces@plt>
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L39
  mov    -0x24(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jg     L29
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L29:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <cutspaces@plt>
  mov    $0x1,%eax
  jmp    L31
L39:
  mov    $0x0,%eax
L31:
  leave
  ret
```

assistant: ```c
int splitline(char *source, char *name, int size_name, char *value, int size_value) {
  char *equalchar;
  int n;
  equalchar = strchr(source, '=');
  value[0] = 0;
  name[0] = 0;
  if (equalchar) {
    strncpy(value, equalchar + 1, size_value);
    value[size_value - 1] = 0;
    cutspaces(value);
    n = equalchar - source;
    if (n > 0) {
      if (n > size_name - 1)
        n = size_name - 1;
      strncpy(name, source, n);
      name[n] = 0;
      cutspaces(name);
      return 1;
    }
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<splitline>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %rcx,%r15
  mov    %r8d,%ebp
  mov    $0x3d,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  movb   $0x0,(%r15)
  movb   $0x0,0x0(%r13)
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L27
  lea    0x1(%rbx),%rsi
  mov    %ebp,%edx
  mov    %r15,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rbp
  movb   $0x0,-0x1(%r15,%rbp,1)
  mov    %r15,%rdi
  call   <cutspaces@plt>
  sub    %r12,%rbx
  mov    %ebx,%ebp
  mov    $0x0,%eax
  test   %ebx,%ebx
  jg     L10
L27:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L10:
  lea    -0x1(%r14),%eax
  cmp    %ebx,%r14d
  cmovle %eax,%ebp
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
  mov    %r13,%rdi
  call   <cutspaces@plt>
  mov    $0x1,%eax
  jmp    L27
```

assistant: ```c
int splitline(char *source, char *name, int size_name, char *value, int size_value) {
  char *equalchar;
  int n;
  equalchar = strchr(source, '=');
  value[0] = 0;
  name[0] = 0;
  if (equalchar) {
    strncpy(value, equalchar + 1, size_value);
    value[size_value - 1] = 0;
    cutspaces(value);
    n = equalchar - source;
    if (n > 0) {
      if (n > size_name - 1)
        n = size_name - 1;
      strncpy(name, source, n);
      name[n] = 0;
      cutspaces(name);
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<splitline>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  movslq %r8d,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x3d,%esi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  movb   $0x0,0x0(%rbp)
  movb   $0x0,(%r12)
  test   %rax,%rax
  je     L4
  mov    %rbp,%rdi
  lea    0x1(%rax),%rsi
  mov    %r14d,%edx
  mov    %rax,%rbx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rbp,%r14,1)
  mov    %rbp,%rdi
  sub    %r15,%rbx
  mov    %ebx,%ebp
  call   <cutspaces@plt>
  test   %ebx,%ebx
  jg     L16
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  cmp    %ebx,%r13d
  lea    -0x1(%r13),%eax
  mov    %r15,%rsi
  mov    %r12,%rdi
  cmovle %eax,%ebp
  mov    %ebp,%edx
  movslq %ebp,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rdi
  call   <cutspaces@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int splitline(char *source, char *name, int size_name, char *value, int size_value) {
  char *equalchar;
  int n;
  equalchar = strchr(source, '=');
  value[0] = 0;
  name[0] = 0;
  if (equalchar) {
    strncpy(value, equalchar + 1, size_value);
    value[size_value - 1] = 0;
    cutspaces(value);
    n = equalchar - source;
    if (n > 0) {
      if (n > size_name - 1)
        n = size_name - 1;
      strncpy(name, source, n);
      name[n] = 0;
      cutspaces(name);
      return 1;
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<splitline>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  movslq %r8d,%r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    $0x3d,%esi
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strchr@plt>
  movb   $0x0,0x0(%rbp)
  movb   $0x0,(%r12)
  test   %rax,%rax
  je     L10
  mov    %rbp,%rdi
  lea    0x1(%rax),%rsi
  mov    %r14d,%edx
  mov    %rax,%rbx
  call   <strncpy@plt>
  movb   $0x0,-0x1(%rbp,%r14,1)
  mov    %rbp,%rdi
  sub    %r15,%rbx
  mov    %ebx,%ebp
  call   <cutspaces@plt>
  test   %ebx,%ebx
  jg     L7
L10:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  cmp    %ebx,%r13d
  lea    -0x1(%r13),%eax
  mov    %r15,%rsi
  mov    %r12,%rdi
  cmovle %eax,%ebp
  mov    %ebp,%edx
  movslq %ebp,%rbp
  call   <strncpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rdi
  call   <cutspaces@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int splitline(char *source, char *name, int size_name, char *value, int size_value) {
  char *equalchar;
  int n;
  equalchar = strchr(source, '=');
  value[0] = 0;
  name[0] = 0;
  if (equalchar) {
    strncpy(value, equalchar + 1, size_value);
    value[size_value - 1] = 0;
    cutspaces(value);
    n = equalchar - source;
    if (n > 0) {
      if (n > size_name - 1)
        n = size_name - 1;
      strncpy(name, source, n);
      name[n] = 0;
      cutspaces(name);
      return 1;
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<checkenv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getenv@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L31
L6:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L6
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L48
  mov    $0x0,%eax
  jmp    L31
L48:
  mov    -0x8(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
char *checkenv(const char *env) {
  char *envstr;
  if ((envstr = getenv(env)) == NULL)
    return (NULL);
  while (*envstr == ' ')
    envstr++;
  if (*envstr == '\0')
    return (NULL);
  return (envstr);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<checkenv>:
  endbr64
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  je     L20
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jne    L27
L10:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L10
L27:
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %rdx,%rax
L20:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *checkenv(const char *env) {
  char *envstr;
  if ((envstr = getenv(env)) == NULL)
    return (NULL);
  while (*envstr == ' ')
    envstr++;
  if (*envstr == '\0')
    return (NULL);
  return (envstr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<checkenv>:
  endbr64
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  jne    L8
  jmp    L25
  nopl   0x0(%rax)
L16:
  add    $0x1,%rax
L8:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L16
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %rdx,%rax
L25:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *checkenv(const char *env) {
  char *envstr;
  if ((envstr = getenv(env)) == NULL)
    return (NULL);
  while (*envstr == ' ')
    envstr++;
  if (*envstr == '\0')
    return (NULL);
  return (envstr);
}
```
user: What is the c source code of the assembly code below:

```asm
<checkenv>:
  endbr64
  sub    $0x8,%rsp
  call   <getenv@plt>
  test   %rax,%rax
  jne    L24
  jmp    L23
  nopl   0x0(%rax)
L18:
  add    $0x1,%rax
L24:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L18
  test   %dl,%dl
  mov    $0x0,%edx
  cmove  %rdx,%rax
L23:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *checkenv(const char *env) {
  char *envstr;
  if ((envstr = getenv(env)) == NULL)
    return (NULL);
  while (*envstr == ' ')
    envstr++;
  if (*envstr == '\0')
    return (NULL);
  return (envstr);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<assert_lsbversion_valid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L66
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L66
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L66
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L66
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L66
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L66
  mov    $0x1,%eax
  jmp    L13
L66:
  mov    $0x0,%eax
L13:
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

assistant: ```c
void assert_lsbversion_valid(const char *lsbversion) {
  assert(lsbversion != NULL);
  assert((lsbversion[0] >= '0' && lsbversion[0] <= '9') && lsbversion[1] == '.' && (lsbversion[2] >= '0' && lsbversion[2] <= '9') && lsbversion[3] == '\0');
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<assert_lsbversion_valid>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  sub    $0x30,%eax
  mov    $0x0,%edi
  cmp    $0x9,%al
  ja     L31
  cmpb   $0x2e,0x1(%rbx)
  je     L32
L31:
  call   <assert@plt>
  pop    %rbx
  ret
L32:
  movzbl 0x2(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L31
  cmpb   $0x0,0x3(%rbx)
  sete   %dil
  movzbl %dil,%edi
  jmp    L31
```

assistant: ```c
void assert_lsbversion_valid(const char *lsbversion) {
  assert(lsbversion != NULL);
  assert((lsbversion[0] >= '0' && lsbversion[0] <= '9') && lsbversion[1] == '.' && (lsbversion[2] >= '0' && lsbversion[2] <= '9') && lsbversion[3] == '\0');
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<assert_lsbversion_valid>:
  endbr64
  test   %rdi,%rdi
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  xor    %edi,%edi
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L15
  cmpb   $0x2e,0x1(%rbx)
  je     L19
L15:
  pop    %rbx
  jmp    1050 <assert@plt>
L19:
  movzbl 0x2(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L15
  xor    %edi,%edi
  cmpb   $0x0,0x3(%rbx)
  sete   %dil
  jmp    L15
```

assistant: ```c
void assert_lsbversion_valid(const char *lsbversion) {
  assert(lsbversion != NULL);
  assert((lsbversion[0] >= '0' && lsbversion[0] <= '9') && lsbversion[1] == '.' && (lsbversion[2] >= '0' && lsbversion[2] <= '9') && lsbversion[3] == '\0');
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<assert_lsbversion_valid>:
  endbr64
  test   %rdi,%rdi
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  movzbl (%rbx),%eax
  xor    %edi,%edi
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L3
  cmpb   $0x2e,0x1(%rbx)
  je     L26
L3:
  pop    %rbx
  jmp    1050 <assert@plt>
L26:
  movzbl 0x2(%rbx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L3
  xor    %edi,%edi
  cmpb   $0x0,0x3(%rbx)
  sete   %dil
  jmp    L3
```

assistant: ```c
void assert_lsbversion_valid(const char *lsbversion) {
  assert(lsbversion != NULL);
  assert((lsbversion[0] >= '0' && lsbversion[0] <= '9') && lsbversion[1] == '.' && (lsbversion[2] >= '0' && lsbversion[2] <= '9') && lsbversion[3] == '\0');
}
```