ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<freeFileArgs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L10
L11:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addq   $0x8,-0x8(%rbp)
L10:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L11
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void freeFileArgs(char **args) {
  char **a;
  for (a = args; *a; a++)
    free(*a);
  free((char *)args);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<freeFileArgs>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L12
  mov    %rbp,%rbx
L4:
  call   <free@plt>
  add    $0x8,%rbx
  mov    (%rbx),%rdi
  test   %rdi,%rdi
  jne    L4
L12:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void freeFileArgs(char **args) {
  char **a;
  for (a = args; *a; a++)
    free(*a);
  free((char *)args);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<freeFileArgs>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L15
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L2:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L2
L15:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void freeFileArgs(char **args) {
  char **a;
  for (a = args; *a; a++)
    free(*a);
  free((char *)args);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<freeFileArgs>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L18
  mov    %rbp,%rbx
  nopl   0x0(%rax,%rax,1)
L17:
  call   <free@plt>
  mov    0x8(%rbx),%rdi
  add    $0x8,%rbx
  test   %rdi,%rdi
  jne    L17
L18:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <free@plt>
```

assistant: ```c
void freeFileArgs(char **args) {
  char **a;
  for (a = args; *a; a++)
    free(*a);
  free((char *)args);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<process_format_caps>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,0x4(%rsp)
  mov    %rcx,%rdi
  mov    %rcx,0x8(%rsp)
  mov    %r8,%r14
  mov    %r9,%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0xff,%esi
  call   <bzero@plt>
  mov    $0x3fc,%esi
  mov    %r14,%rdi
  call   <bzero@plt>
  mov    $0x3fc,%esi
  mov    %r15,%rdi
  call   <bzero@plt>
  lea    0x10(%r12),%rbx
  lea    -0x4(%r13),%ebp
  cmpl   $0x0,0x4(%rsp)
  jne    L4
L49:
  test   %ebp,%ebp
  jle    L13
  sub    $0x5,%r13d
  shr    $0x3,%r13d
  mov    %r13d,%r13d
  shl    $0x5,%r13
  lea    0x30(%r12,%r13,1),%rax
  mov    %rax,0x10(%rsp)
  lea    0x24(%rsp),%rax
  mov    %rax,0x18(%rsp)
L14:
  mov    0x8(%rbx),%ebp
  shl    $0x8,%ebp
  mov    0x4(%rbx),%eax
  shl    $0x10,%eax
  or     %eax,%ebp
  or     0xc(%rbx),%ebp
  mov    (%rbx),%eax
  shl    $0x18,%eax
  or     %eax,%ebp
  mov    0x10(%rbx),%ecx
  mov    %ecx,%r13d
  sar    $0x2,%r13d
  mov    0x18(%rbx),%r12d
  shl    $0x8,%r12d
  mov    0x14(%rbx),%eax
  shl    $0x10,%eax
  or     %eax,%r12d
  or     0x1c(%rbx),%r12d
  and    $0x3,%ecx
  mov    0x18(%rsp),%r9
  mov    0x4(%rsp),%r8d
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <print_format@plt>
  movslq %r13d,%r13
  mov    0x8(%rsp),%rax
  movl   $0x1,(%rax,%r13,4)
  mov    %ebp,(%r14,%r13,4)
  mov    %r12d,(%r15,%r13,4)
  add    $0x20,%rbx
  cmp    %rbx,0x10(%rsp)
  jne    L14
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L49
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D4: 	Current/max capacity followed by additional capacity,reported length of %d bytes (8/entry)


assistant: ```c
void process_format_caps(uint8_t *buf, int list_length, int verbose, uint8_t *allow, uint32_t *blks, uint32_t *params) {
  uint32_t num_blks, param;
  uint8_t *fcd;
  int dscr_type, format_tp;
  int supported;
  bzero(allow, 255);
  bzero(blks, 255 * 4);
  bzero(params, 255 * 4);
  fcd = buf + 4;
  list_length -= 4;
  if (verbose)
    printf("\tCurrent/max capacity followed by additional capacity,"
           "reported length of %d bytes (8/entry)\n",
           list_length);
  while (list_length > 0) {
    num_blks = fcd[3] | (fcd[2] << 8) | (fcd[1] << 16) | (fcd[0] << 24);
    dscr_type = fcd[4] & 3;
    format_tp = fcd[4] >> 2;
    param = fcd[7] | (fcd[6] << 8) | (fcd[5] << 16);
    print_format(format_tp, num_blks, param, dscr_type, verbose, &supported);
    allow[format_tp] = 1;
    blks[format_tp] = num_blks;
    params[format_tp] = param;
    fcd += 8;
    list_length -= 8;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<jelopt_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdi
  lea    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <jelopt@plt>
  test   %rax,%rax
  je     L12
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x30(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L7
L12:
  mov    $0x0,%eax
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int jelopt_int(char **argv, int opt_short, char *opt_long, int *value, int *err) {
  char *cvalue;
  if (jelopt(argv, opt_short, opt_long, &cvalue, err)) {
    *value = atoi(cvalue);
    free(cvalue);
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<jelopt_int>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rcx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <jelopt@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L4
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  mov    (%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,(%rbx)
  mov    (%rsp),%rdi
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L13
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int jelopt_int(char **argv, int opt_short, char *opt_long, int *value, int *err) {
  char *cvalue;
  if (jelopt(argv, opt_short, opt_long, &cvalue, err)) {
    *value = atoi(cvalue);
    free(cvalue);
    return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<jelopt_int>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <jelopt@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L5
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L5:
  mov    (%rsp),%rdi
  call   <atoi@plt>
  mov    (%rsp),%rdi
  mov    %eax,(%rbx)
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L1
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int jelopt_int(char **argv, int opt_short, char *opt_long, int *value, int *err) {
  char *cvalue;
  if (jelopt(argv, opt_short, opt_long, &cvalue, err)) {
    *value = atoi(cvalue);
    free(cvalue);
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<jelopt_int>:
  endbr64
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rcx
  call   <jelopt@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L19
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x10,%rsp
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  mov    (%rsp),%rdi
  call   <atoi@plt>
  mov    (%rsp),%rdi
  mov    %eax,(%rbx)
  call   <free@plt>
  mov    $0x1,%eax
  jmp    L1
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int jelopt_int(char **argv, int opt_short, char *opt_long, int *value, int *err) {
  char *cvalue;
  if (jelopt(argv, opt_short, opt_long, &cvalue, err)) {
    *value = atoi(cvalue);
    free(cvalue);
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<Prec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  cmp    $0x5e,%eax
  je     L91
  cmp    $0x5e,%eax
  jg     L103
  cmp    $0x2f,%eax
  je     L29
  cmp    $0x2f,%eax
  jg     L103
  cmp    $0x2d,%eax
  je     L76
  cmp    $0x2d,%eax
  jg     L103
  cmp    $0x2a,%eax
  je     L29
  cmp    $0x2b,%eax
  jne    L103
L76:
  mov    $0x1,%eax
  jmp    L60
L29:
  mov    $0x2,%eax
  jmp    L60
L91:
  mov    $0x3,%eax
  jmp    L60
L103:
  mov    $0xffffffff,%eax
L60:
  pop    %rbp
  ret
```

assistant: ```c
int Prec(char ch) {
  switch (ch) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  default:
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Prec>:
  endbr64
  cmp    $0x2f,%dil
  je     L12
  jg     L20
  lea    -0x2b(%rdi),%edx
  mov    $0x1,%eax
  test   $0xfd,%dl
  je     L24
  cmp    $0x2a,%dil
  sete   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,2),%eax
  ret
L20:
  cmp    $0x5e,%dil
  sete   %al
  movzbl %al,%eax
  lea    -0x1(,%rax,4),%eax
  ret
L12:
  mov    $0x2,%eax
L24:
  ret
```

assistant: ```c
int Prec(char ch) {
  switch (ch) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  default:
    return -1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Prec>:
  endbr64
  cmp    $0x2f,%dil
  je     L20
  jg     L17
  lea    -0x2b(%rdi),%edx
  mov    $0x1,%eax
  and    $0xfd,%edx
  je     L6
  xor    %eax,%eax
  cmp    $0x2a,%dil
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  cmp    $0x5e,%dil
  sete   %al
  lea    -0x1(,%rax,4),%eax
  ret
  nopl   0x0(%rax)
L20:
  mov    $0x2,%eax
L6:
  ret
```

assistant: ```c
int Prec(char ch) {
  switch (ch) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  default:
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Prec>:
  endbr64
  cmp    $0x2f,%dil
  je     L17
  jg     L5
  lea    -0x2b(%rdi),%edx
  mov    $0x1,%eax
  and    $0xfd,%edx
  je     L3
  xor    %eax,%eax
  cmp    $0x2a,%dil
  sete   %al
  lea    -0x1(%rax,%rax,2),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %eax,%eax
  cmp    $0x5e,%dil
  sete   %al
  lea    -0x1(,%rax,4),%eax
  ret
  nopl   0x0(%rax)
L17:
  mov    $0x2,%eax
L3:
  ret
```

assistant: ```c
int Prec(char ch) {
  switch (ch) {
  case '+':
  case '-':
    return 1;
  case '*':
  case '/':
    return 2;
  case '^':
    return 3;
  default:
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exit_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    $0x0,%eax
  call   <cleanup@plt>
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type_infered: string

tool: D6: Exiting on signal %d


assistant: ```c
void exit_handler(int sig) {
  cleanup();
  if (sig)
    printf("Exiting on signal %d\n", sig);
  exit(0);
}
```
user: What is the c source code of the assembly code below?

```asm
<exit_handler>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <cleanup@plt>
  test   %ebx,%ebx
  jne    L12
L2:
  mov    $0x0,%edi
  call   <exit@plt>
  pop    %rbx
  ret
L12:
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string

tool: D8: Exiting on signal %d


assistant: ```c
void exit_handler(int sig) {
  cleanup();
  if (sig)
    printf("Exiting on signal %d\n", sig);
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<exit_handler>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <cleanup@plt>
  test   %ebp,%ebp
  jne    L4
  xor    %edi,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string

tool: D0: Exiting on signal %d


assistant: ```c
void exit_handler(int sig) {
  cleanup();
  if (sig)
    printf("Exiting on signal %d\n", sig);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<exit_handler>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %edi,%ebp
  call   <cleanup@plt>
  test   %ebp,%ebp
  jne    L4
  xor    %edi,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %edi,%edi
  pop    %rbp
  jmp    1090 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: Exiting on signal %d


assistant: ```c
void exit_handler(int sig) {
  cleanup();
  if (sig)
    printf("Exiting on signal %d\n", sig);
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L9
L15:
  nop
  addq   $0x1,-0x10(%rbp)
L9:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  jmp    L42
L48:
  mov    -0x8(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x10(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L42:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L14
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L48
L14:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char *dscan;
  const char *sscan;
  int count;
  for (dscan = s1; *dscan != '\0'; dscan++)
    continue;
  sscan = s2;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return s1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strncat>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%rcx
  cmpb   $0x0,(%rdi)
  jne    L22
L8:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L59
  test   %edx,%edx
  jle    L59
  lea    -0x1(%rdx),%edx
  lea    0x1(%rcx,%rdx,1),%rdx
L20:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L59
  cmp    %rcx,%rdx
  jne    L20
  mov    %rdx,%rcx
L59:
  movb   $0x0,(%rcx)
  ret
L22:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L8
  jmp    L22
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char *dscan;
  const char *sscan;
  int count;
  for (dscan = s1; *dscan != '\0'; dscan++)
    continue;
  sscan = s2;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return s1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  jne    L16
L62:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L30
  test   %edx,%edx
  jle    L30
  sub    $0x1,%edx
  lea    0x1(%rcx,%rdx,1),%rdx
  jmp    L86
  cs nopw 0x0(%rax,%rax,1)
L67:
  cmp    %rcx,%rdx
  je     L30
L86:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L67
L30:
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L16:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L62
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L62
  jmp    L16
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char *dscan;
  const char *sscan;
  int count;
  for (dscan = s1; *dscan != '\0'; dscan++)
    continue;
  sscan = s2;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return s1;
}
```
user: What is the c source code of the assembly code below?

```asm
<strncat>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  mov    %rdi,%rcx
  jne    L77
L30:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L50
  test   %edx,%edx
  jle    L50
  sub    $0x1,%edx
  lea    0x1(%rcx,%rdx,1),%rdx
  jmp    L84
  cs nopw 0x0(%rax,%rax,1)
L70:
  cmp    %rcx,%rdx
  je     L50
L84:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L70
L50:
  movb   $0x0,(%rcx)
  ret
  nopl   (%rax)
L77:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L30
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  je     L30
  jmp    L77
```

assistant: ```c
char *strncat(char *s1, const char *s2, size_t n) {
  char *dscan;
  const char *sscan;
  int count;
  for (dscan = s1; *dscan != '\0'; dscan++)
    continue;
  sscan = s2;
  count = n;
  while (*sscan != '\0' && --count >= 0)
    *dscan++ = *sscan++;
  *dscan++ = '\0';
  return s1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<utf8len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L32
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L33:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xc0,%eax
  cmp    $0x80,%eax
  je     L10
  addl   $0x1,-0x8(%rbp)
L10:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
L32:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int utf8len(char *s) {
  int len = 0;
  if (s != NULL) {
    for (int i = 0; s[i]; ++i) {
      if ((s[i] & 0xc0) != 0x80)
        ++len;
    }
  }
  return len;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<utf8len>:
  endbr64
  mov    $0x0,%edx
  test   %rdi,%rdi
  je     L26
  movzbl (%rdi),%eax
  test   %al,%al
  je     L27
  add    $0x1,%rdi
L25:
  and    $0xc0,%eax
  cmp    $0x80,%eax
  setne  %al
  movzbl %al,%eax
  add    %eax,%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L25
L26:
  mov    %edx,%eax
  ret
L27:
  mov    $0x0,%edx
  jmp    L26
```

assistant: ```c
int utf8len(char *s) {
  int len = 0;
  if (s != NULL) {
    for (int i = 0; s[i]; ++i) {
      if ((s[i] & 0xc0) != 0x80)
        ++len;
    }
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<utf8len>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L2
  movzbl (%rdi),%eax
  test   %al,%al
  je     L2
  add    $0x1,%rdi
  nopw   0x0(%rax,%rax,1)
L14:
  and    $0xc0,%eax
  cmp    $0x80,%eax
  setne  %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L14
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int utf8len(char *s) {
  int len = 0;
  if (s != NULL) {
    for (int i = 0; s[i]; ++i) {
      if ((s[i] & 0xc0) != 0x80)
        ++len;
    }
  }
  return len;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<utf8len>:
  endbr64
  xor    %r8d,%r8d
  test   %rdi,%rdi
  je     L28
  movzbl (%rdi),%eax
  test   %al,%al
  je     L28
  add    $0x1,%rdi
  nopw   0x0(%rax,%rax,1)
L29:
  and    $0xc0,%eax
  cmp    $0x80,%eax
  setne  %al
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %eax,%r8d
  movzbl -0x1(%rdi),%eax
  test   %al,%al
  jne    L29
L28:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int utf8len(char *s) {
  int len = 0;
  if (s != NULL) {
    for (int i = 0; s[i]; ++i) {
      if ((s[i] & 0xc0) != 0x80)
        ++len;
    }
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strupr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  jmp    L8
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %eax,%ecx
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strupr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = toupper(c);
  }
  return (string);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strupr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %edi,%edi
  je     L16
L4:
  call   <toupper@plt>
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %edi,%edi
  jne    L4
L16:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *strupr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = toupper(c);
  }
  return (string);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strupr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %edi,%edi
  je     L9
L7:
  call   <toupper@plt>
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  test   %edi,%edi
  jne    L7
L9:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strupr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = toupper(c);
  }
  return (string);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strupr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  movsbl (%rdi),%edi
  test   %edi,%edi
  je     L12
L9:
  call   <toupper@plt>
  movsbl 0x1(%r12),%edi
  add    $0x1,%r12
  mov    %al,-0x1(%r12)
  test   %edi,%edi
  jne    L9
L12:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *strupr(char *string) {
  int c;
  while ((c = *string) != 0) {
    *string++ = toupper(c);
  }
  return (string);
}
```