user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bdecode_value>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %eax,%r14d
  mov    %eax,0x10(%rsp)
  call   <strlen@plt>
  lea    0x1(%rax),%ecx
  mov    %eax,%ebx
  mov    %ecx,%edi
  mov    %ecx,0x14(%rsp)
  call   <malloc@plt>
  lea    0x23(%rsp),%rcx
  xor    %esi,%esi
  mov    $0x5,%edx
  mov    %rax,%r15
  mov    %rcx,%rdi
  mov    %rcx,0x18(%rsp)
  call   <memset@plt>
  xor    %esi,%esi
  mov    %ebx,%edx
  mov    %r15,%rdi
  call   <memset@plt>
  test   %r14d,%r14d
  jle    L74
  movslq 0x10(%rsp),%rax
  movslq %ebx,%r14
  xor    %r12d,%r12d
  add    %r15,%r14
  mov    %rax,0x8(%rsp)
  jmp    L117
  nopw   0x0(%rax,%rax,1)
L49:
  add    $0x1,%r12
  cmp    0x8(%rsp),%r12
  je     L74
L117:
  lea    0x0(%rbp,%r12,1),%rsi
  mov    %r15,%rdi
  mov    %ebx,%edx
  mov    %r12d,0x4(%rsp)
  call   <strncpy@plt>
  movb   $0x0,(%r14)
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L49
  mov    0x10(%rsp),%ecx
  mov    0x14(%rsp),%r12d
  add    0x4(%rsp),%r12d
  cmp    %r12d,%ecx
  jle    L118
  movslq %r12d,%rax
  movzbl 0x0(%rbp,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L118
  mov    %al,0x23(%rsp)
  lea    0x1(%r12),%eax
  cmp    %eax,%ecx
  jle    L118
  cltq
  movzbl 0x0(%rbp,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L118
  mov    %al,0x24(%rsp)
  lea    0x2(%r12),%eax
  cmp    %eax,%ecx
  jle    L118
  cltq
  movzbl 0x0(%rbp,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L118
  mov    %al,0x25(%rsp)
  lea    0x3(%r12),%eax
  cmp    %eax,%ecx
  jle    L118
  cltq
  movzbl 0x0(%rbp,%rax,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L118
  add    $0x4,%r12d
  mov    %al,0x26(%rsp)
  cmp    %r12d,%ecx
  jle    L118
  movslq %r12d,%r12
  movzbl 0x0(%rbp,%r12,1),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L118
  mov    %al,0x27(%rsp)
L118:
  mov    0x18(%rsp),%rdi
  call   <atoi@plt>
  mov    %eax,%r12d
  jmp    L65
  nopl   0x0(%rax,%rax,1)
L74:
  xor    %r12d,%r12d
L65:
  mov    %r15,%rdi
  call   <free@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x38,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bdecode_value(char *source, char *search) {
  int i, intlen = 0, value = 0;
  int source_len = strlen(source);
  int search_len = strlen(search);
  char *seek = (char *)malloc(search_len + 1);
  char tmp[5];
  memset(tmp, '\0', sizeof(tmp));
  memset(seek, '\0', search_len);
  for (i = 0; i < source_len; i++) {
    strncpy(seek, source + i, search_len);
    seek[search_len] = '\0';
    if (strcmp(seek, search) == 0) {
      i += search_len + 1;
      while (i < source_len && intlen < 5 && 47 < source[i] && source[i] < 58) {
        tmp[intlen] = source[i];
        intlen++;
        i++;
      }
      value = atoi(tmp);
      break;
    }
  }
  free(seek);
  return value;
}
```