ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<get_max>:
  endbr64
  test   %esi,%esi
  jle    L1
  lea    -0x1(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x4(%rdi,%rax,4),%rcx
  nopl   0x0(%rax,%rax,1)
L2:
  mov    (%rdi),%eax
  cmp    %eax,%edx
  cmovle %edx,%eax
  add    $0x4,%rdi
  add    %eax,%r8d
  cmp    %rcx,%rdi
  jne    L2
  mov    %r8d,%eax
  ret
  nop
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_max(int fruit[], int len, int X) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += fruit[i] < X ? fruit[i] : X;
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_max>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L52
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L15
  shr    $0x2,%esi
  movd   %edx,%xmm5
  pxor   %xmm1,%xmm1
  mov    %rdi,%rax
  sub    $0x1,%esi
  pshufd $0x0,%xmm5,%xmm2
  shl    $0x4,%rsi
  lea    0x10(%rdi,%rsi,1),%rsi
  nopl   0x0(%rax)
L66:
  movdqu (%rax),%xmm0
  movdqu (%rax),%xmm4
  movdqa %xmm2,%xmm3
  add    $0x10,%rax
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm3
  pandn  %xmm4,%xmm0
  por    %xmm3,%xmm0
  paddd  %xmm0,%xmm1
  cmp    %rsi,%rax
  jne    L66
  movdqa %xmm1,%xmm0
  mov    %ecx,%esi
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%esi
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%eax
  test   $0x3,%cl
  je     L32
L35:
  movslq %esi,%r8
  lea    0x0(,%r8,4),%r9
  mov    (%rdi,%r8,4),%r8d
  cmp    %r8d,%edx
  cmovle %edx,%r8d
  add    %r8d,%eax
  lea    0x1(%rsi),%r8d
  cmp    %r8d,%ecx
  jle    L26
  mov    0x4(%rdi,%r9,1),%r8d
  cmp    %r8d,%edx
  cmovle %edx,%r8d
  add    $0x2,%esi
  add    %r8d,%eax
  cmp    %esi,%ecx
  jle    L26
  mov    0x8(%rdi,%r9,1),%ecx
  cmp    %ecx,%edx
  cmovg  %ecx,%edx
  add    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L52:
  xor    %eax,%eax
L26:
  ret
  nopl   0x0(%rax,%rax,1)
L32:
  ret
L15:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L35
```

assistant: ```c
int get_max(int fruit[], int len, int X) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += fruit[i] < X ? fruit[i] : X;
  }
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1dc(%rbp)
  lea    -0x1e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1d8(%rbp)
  jmp    L50
L9:
  lea    -0x1d0(%rbp),%rdx
  mov    -0x1d8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1d8(%rbp)
L50:
  mov    -0x1e0(%rbp),%eax
  cmp    %eax,-0x1d8(%rbp)
  jl     L9
  movl   $0x0,-0x1d8(%rbp)
  jmp    L75
L39:
  mov    -0x1d8(%rbp),%eax
  mov    %eax,-0x1d4(%rbp)
  jmp    L56
L37:
  mov    -0x1d8(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%edx
  mov    -0x1d4(%rbp),%eax
  cltq
  mov    -0x1d0(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x1dc(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x1dc(%rbp)
  addl   $0x1,-0x1d4(%rbp)
L56:
  mov    -0x1e0(%rbp),%eax
  cmp    %eax,-0x1d4(%rbp)
  jl     L37
  addl   $0x1,-0x1d8(%rbp)
L75:
  mov    -0x1e0(%rbp),%eax
  cmp    %eax,-0x1d8(%rbp)
  jl     L39
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x1d8(%rbp)
  jmp    L48
L51:
  mov    -0x1d8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1d8(%rbp)
L48:
  mov    -0x1d8(%rbp),%eax
  cmp    -0x1dc(%rbp),%eax
  jl     L51
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D18
datatype: string
name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D14
datatype: string

tool: D18: %d

tool: D36: Output:

tool: D14: 
%d


assistant: ```c
int main() {
  int a[10];
  int temp[100];
  int k = 0;
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      temp[k] = a[i] + a[j];
      k++;
    }
  }
  printf("Output:");
  for (i = 0; i < k; i++) {
    printf("\n%d\n", temp[i]);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L84
  lea    0x10(%rsp),%rbp
  mov    %rbp,%r12
  mov    $0x0,%ebx
  lea    D39(%rip),%r13
L66:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%r10d
  add    $0x4,%r12
  cmp    %ebx,%r10d
  jg     L66
  test   %r10d,%r10d
  jle    L84
  mov    $0x0,%r9d
  mov    $0x0,%ebx
  lea    -0x1(%r10),%r13d
  lea    0x40(%rsp),%r12
  jmp    L40
L48:
  mov    %rbp,%r8
  mov    0x0(%rbp),%edi
  mov    %r9d,%r11d
  mov    %r13d,%eax
  sub    %r9d,%eax
  lea    0x4(,%rax,4),%rsi
  movslq %ebx,%rax
  lea    (%r12,%rax,4),%rcx
  mov    $0x0,%eax
L11:
  mov    %edi,%edx
  add    (%r8,%rax,1),%edx
  mov    %edx,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L11
  add    %r10d,%ebx
  sub    %r11d,%ebx
L74:
  add    $0x1,%r9d
  add    $0x4,%rbp
  cmp    %r9d,%r10d
  je     L4
L40:
  cmp    %r9d,%r10d
  jg     L48
  jmp    L74
L4:
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebx,%ebx
  jle    L104
  lea    0x40(%rsp),%rbp
  lea    -0x1(%rbx),%eax
  lea    0x44(%rsp,%rax,4),%r12
  lea    D14(%rip),%rbx
L92:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L92
L104:
  mov    0x1d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L95
  mov    $0x0,%eax
  add    $0x1e8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L84:
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L104
L95:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D39
type: string
name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D14
type: string

tool: D39: %d

tool: D36: Output:

tool: D14: 
%d


assistant: ```c
int main() {
  int a[10];
  int temp[100];
  int k = 0;
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      temp[k] = a[i] + a[j];
      k++;
    }
  }
  printf("Output:");
  for (i = 0; i < k; i++) {
    printf("\n%d\n", temp[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  lea    D36(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x1e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1d8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L8
  lea    0x10(%rsp),%rbx
  xor    %ebp,%ebp
  mov    %rbx,%r12
L21:
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebp
  add    $0x4,%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%ecx
  cmp    %ebp,%ecx
  jg     L21
  test   %ecx,%ecx
  jle    L8
  lea    -0x1(%rcx),%r11d
  movslq %ecx,%r14
  xor    %r10d,%r10d
  xor    %r8d,%r8d
  xor    %r9d,%r9d
  lea    0x40(%rsp),%rbp
  xor    %r13d,%r13d
  nopw   0x0(%rax,%rax,1)
L92:
  movslq %r9d,%rax
  mov    (%rbx,%r8,4),%edi
  mov    %r8d,%r12d
  lea    (%r10,%rax,4),%rsi
  mov    %r8,%rax
  add    %rbp,%rsi
  mov    %edi,%edx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L35:
  mov    (%rbx,%rax,4),%edx
L16:
  add    %edi,%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %eax,%ecx
  jg     L35
  cmp    %r12d,%ecx
  mov    %r13d,%eax
  cmovg  %r11d,%eax
  add    $0x1,%r8
  sub    $0x1,%r11d
  sub    $0x4,%r10
  lea    0x1(%r9,%rax,1),%edx
  lea    (%r9,%rax,1),%r12d
  cmp    %r14,%r8
  je     L93
  mov    %edx,%r9d
  jmp    L92
  nopl   0x0(%rax)
L93:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  lea    D30(%rip),%rbx
  call   <printf@plt>
  movslq %r12d,%r9
  lea    0x44(%rsp,%r9,4),%r12
  nopl   (%rax)
L31:
  mov    0x0(%rbp),%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%rbp
  call   <printf@plt>
  cmp    %r12,%rbp
  jne    L31
L9:
  mov    0x1d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L98
  add    $0x1e0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L9
L98:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D36
type_infered: string
name: read_data
arguments: tag: D10
type_infered: string
name: read_data
arguments: tag: D30
type_infered: string

tool: D36: %d

tool: D10: Output:

tool: D30: 
%d


assistant: ```c
int main() {
  int a[10];
  int temp[100];
  int k = 0;
  int i, j, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &a[i]);
  }
  for (i = 0; i < n; i++) {
    for (j = i; j < n; j++) {
      temp[k] = a[i] + a[j];
      k++;
    }
  }
  printf("Output:");
  for (i = 0; i < k; i++) {
    printf("\n%d\n", temp[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_suf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  leave
  ret
```

assistant: ```c
int is_suf(const char *str, const char *suf) {
  int str_len = strlen(str);
  int str_suf = strlen(suf);
  return strcmp(str + str_len - str_suf, suf) == 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_suf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  movslq %ebx,%rbx
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    %r12,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int is_suf(const char *str, const char *suf) {
  int str_len = strlen(str);
  int str_suf = strlen(suf);
  return strcmp(str + str_len - str_suf, suf) == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_suf>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_suf(const char *str, const char *suf) {
  int str_len = strlen(str);
  int str_suf = strlen(suf);
  return strcmp(str + str_len - str_suf, suf) == 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_suf>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    %r12,%rsi
  cltq
  sub    %rax,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  call   <strcmp@plt>
  pop    %rbx
  pop    %rbp
  test   %rax,%rax
  pop    %r12
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int is_suf(const char *str, const char *suf) {
  int str_len = strlen(str);
  int str_suf = strlen(suf);
  return strcmp(str + str_len - str_suf, suf) == 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printPascal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r14d
  mov    %edi,0xc(%rsp)
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  test   %r14d,%r14d
  jle    L70
  mov    %rax,%rbx
  lea    0x0(,%r14,4),%r13d
  mov    %rax,%r12
  mov    %r14d,%eax
  lea    (%rbx,%rax,8),%rbp
L92:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L92
  mov    $0x0,%r13d
  mov    $0xffffffff,%r14d
  lea    D7(%rip),%r15
  jmp    L93
L55:
  mov    (%r12),%rax
  movl   $0x1,(%rax,%rbx,1)
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L13:
  lea    0x1(%rbp),%eax
  add    $0x4,%rbx
  cmp    %ebp,%r13d
  je     L81
  mov    %eax,%ebp
L94:
  test   %ebp,%ebp
  je     L55
  cmp    %ebp,%r14d
  je     L55
  mov    -0x8(%r12),%rdx
  mov    (%r12),%rcx
  mov    (%rdx,%rbx,1),%eax
  add    -0x4(%rdx,%rbx,1),%eax
  mov    %eax,(%rcx,%rbx,1)
  mov    (%r12),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L13
L81:
  mov    0x8(%rsp),%r13d
L93:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    0x1(%r13),%eax
  mov    %eax,0x8(%rsp)
  add    $0x8,%r12
  add    $0x1,%r14d
  cmp    %eax,0xc(%rsp)
  je     L70
  test   %eax,%eax
  jle    L81
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  jmp    L94
L70:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string

tool: D7: %d

assistant: ```c
void printPascal(int n) {
  int line = n;
  int i = 0;
  int **arr = (int **)malloc(sizeof(int *) * n);
  for (int j = 0; j < n; j++) {
    arr[j] = malloc(sizeof(int) * n);
  }
  for (line = 0; line < n; line++) {
    for (i = 0; i < line; i++) {
      if (i == 0 || i == line - 1) {
        arr[line][i] = 1;
        printf("%d", arr[line][i]);
      } else {
        arr[line][i] = arr[line - 1][i - 1] + arr[line - 1][i];
        printf("%d", arr[line][i]);
      }
    }
    printf("\n");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<printPascal>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  lea    0x0(,%rbp,8),%edi
  sub    $0x18,%rsp
  call   <malloc@plt>
  test   %ebp,%ebp
  jle    L78
  mov    %rax,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x0(,%rbp,4),%r12d
  mov    %eax,0xc(%rsp)
  lea    (%rbx,%rbp,8),%r13
  mov    %rbx,%rbp
  nopl   0x0(%rax)
L6:
  mov    %r12d,%edi
  add    $0x8,%rbp
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r13,%rbp
  jne    L6
  mov    $0xffffffff,%r14d
  lea    D9(%rip),%r13
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r14d,%ebp
  add    $0x1,%r14d
  xor    %r15d,%r15d
  mov    %rbp,%r12
  test   %r14d,%r14d
  jg     L56
  jmp    L43
  nopl   0x0(%rax)
L26:
  mov    -0x8(%rbx),%rdi
  mov    (%rdi,%rax,1),%esi
  add    -0x4(%rdi,%rax,1),%esi
  mov    %r13,%rdi
  mov    %esi,(%rcx,%rax,1)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r15),%rax
  cmp    %r15,%rbp
  je     L43
L37:
  mov    %rax,%r15
L56:
  mov    (%rbx),%rcx
  lea    0x0(,%r15,4),%rax
  test   %r15,%r15
  je     L77
  cmp    %r15d,%r12d
  jne    L26
L77:
  movl   $0x1,(%rcx,%rax,1)
  mov    $0x1,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%r15),%rax
  cmp    %r15,%rbp
  jne    L37
L43:
  mov    $0xa,%edi
  add    $0x8,%rbx
  call   <putchar@plt>
  cmp    0xc(%rsp),%r14d
  jne    L27
L78:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string

tool: D9: %d

assistant: ```c
void printPascal(int n) {
  int line = n;
  int i = 0;
  int **arr = (int **)malloc(sizeof(int *) * n);
  for (int j = 0; j < n; j++) {
    arr[j] = malloc(sizeof(int) * n);
  }
  for (line = 0; line < n; line++) {
    for (i = 0; i < line; i++) {
      if (i == 0 || i == line - 1) {
        arr[line][i] = 1;
        printf("%d", arr[line][i]);
      } else {
        arr[line][i] = arr[line - 1][i - 1] + arr[line - 1][i];
        printf("%d", arr[line][i]);
      }
    }
    printf("\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printPascal>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  shl    $0x3,%edi
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %r15d,%r15d
  jle    L37
  mov    %rax,%rbp
  mov    %rax,%rbx
  mov    %r15d,%eax
  lea    0x0(,%r15,4),%r13d
  lea    0x0(%rbp,%rax,8),%r12
  nopl   0x0(%rax)
L33:
  mov    %r13d,%edi
  add    $0x8,%rbx
  call   <malloc@plt>
  mov    %rax,-0x8(%rbx)
  cmp    %r12,%rbx
  jne    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  cmp    $0x1,%r15d
  je     L37
  add    $0x8,%rbp
  xor    %r13d,%r13d
  mov    $0x1,%r12d
  lea    D6(%rip),%r14
  nopl   (%rax)
L1:
  xor    %ebx,%ebx
  jmp    L28
  nopl   0x0(%rax)
L50:
  mov    -0x8(%rbp),%rcx
  mov    %r14,%rdi
  add    $0x1,%rbx
  mov    (%rcx,%rax,1),%esi
  add    -0x4(%rcx,%rax,1),%esi
  mov    %esi,(%rdx,%rax,1)
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%r12d
  jle    L48
L28:
  mov    0x0(%rbp),%rdx
  lea    0x0(,%rbx,4),%rax
  test   %rbx,%rbx
  je     L46
  cmp    %r13d,%ebx
  jne    L50
L46:
  movl   $0x1,(%rdx,%rax,1)
  mov    $0x1,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %ebx,%r12d
  jg     L28
L48:
  mov    $0xa,%edi
  add    $0x1,%r12d
  add    $0x8,%rbp
  add    $0x1,%r13d
  call   <putchar@plt>
  cmp    %r12d,%r15d
  jne    L1
L37:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: %d

assistant: ```c
void printPascal(int n) {
  int line = n;
  int i = 0;
  int **arr = (int **)malloc(sizeof(int *) * n);
  for (int j = 0; j < n; j++) {
    arr[j] = malloc(sizeof(int) * n);
  }
  for (line = 0; line < n; line++) {
    for (i = 0; i < line; i++) {
      if (i == 0 || i == line - 1) {
        arr[line][i] = 1;
        printf("%d", arr[line][i]);
      } else {
        arr[line][i] = arr[line - 1][i - 1] + arr[line - 1][i];
        printf("%d", arr[line][i]);
      }
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x54(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L67:
  cmp    %rdx,%rsp
  je     L23
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L67
L23:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L39
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L39:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x50(%rbp)
  jmp    L71
L76:
  mov    -0x50(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x50(%rbp)
L71:
  mov    -0x54(%rbp),%eax
  cmp    %eax,-0x50(%rbp)
  jl     L76
  mov    -0x54(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  jmp    L31
L37:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4c(%rbp)
L31:
  cmpl   $0x0,-0x4c(%rbp)
  jns    L37
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D18
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: string

tool: D18: %d

tool: D23: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int mas[n];
  for (int i = 0; i < n; i++)
    scanf("%d", &mas[i]);
  for (int i = n - 1; i >= 0; i--)
    printf("%d\n", mas[i]);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x3c(%rbp),%rsi
  lea    D23(%rip),%rdi
  call   <scanf@plt>
  mov    -0x3c(%rbp),%ebx
  movslq %ebx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L58:
  cmp    %rdx,%rsp
  je     L54
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L58
L54:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L11
  orq    $0x0,-0x8(%rsp,%rax,1)
L11:
  mov    %rsp,%r13
  test   %ebx,%ebx
  jle    L63
  mov    %r13,%r14
  mov    $0x0,%r12d
  lea    D23(%rip),%r15
L36:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <scanf@plt>
  add    $0x1,%r12d
  mov    -0x3c(%rbp),%ebx
  add    $0x4,%r14
  cmp    %r12d,%ebx
  jg     L36
L63:
  sub    $0x1,%ebx
  js     L3
  movslq %ebx,%rbx
  lea    D28(%rip),%r12
L48:
  mov    0x0(%r13,%rbx,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L48
L3:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D28
type_guessed: string

tool: D23: %d

tool: D28: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  int mas[n];
  for (int i = 0; i < n; i++)
    scanf("%d", &mas[i]);
  for (int i = n - 1; i >= 0; i--)
    printf("%d\n", mas[i]);
  return 0;
}
```