ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<loop>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L4:
  mov    %ebx,0x0(%rbp)
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <swapcontext@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void loop(ucontext_t *loop_context, ucontext_t *other_context, int *i_from_iterator) {
  int i;
  for (i = 0; i < 10; ++i) {
    *i_from_iterator = i;
    swapcontext(loop_context, other_context);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<loop>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L9:
  mov    %ebx,0x0(%rbp)
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <swapcontext@plt>
  cmp    $0xa,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void loop(ucontext_t *loop_context, ucontext_t *other_context, int *i_from_iterator) {
  int i;
  for (i = 0; i < 10; ++i) {
    *i_from_iterator = i;
    swapcontext(loop_context, other_context);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<loop>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  mov    %ebx,0x0(%rbp)
  mov    %r12,%rsi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <swapcontext@plt>
  cmp    $0xa,%ebx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void loop(ucontext_t *loop_context, ucontext_t *other_context, int *i_from_iterator) {
  int i;
  for (i = 0; i < 10; ++i) {
    *i_from_iterator = i;
    swapcontext(loop_context, other_context);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<movsx_reg32_16preg64pimm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0xbf,%edi
  call   <put8@plt>
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  or     -0x8(%rbp),%eax
  or     $0x80,%al
  mov    %eax,%edi
  call   <put8@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void movsx_reg32_16preg64pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x0F);
  put8(0xBF);
  put8((reg1 << 3) | reg2 | 0x80);
  put32(imm32);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<movsx_reg32_16preg64pimm32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%ebp
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0xbf,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  mov    %ebp,%edi
  call   <put32@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void movsx_reg32_16preg64pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x0F);
  put8(0xBF);
  put8((reg1 << 3) | reg2 | 0x80);
  put32(imm32);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<movsx_reg32_16preg64pimm32>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %edi,%ebx
  mov    $0xf,%edi
  call   <put8@plt>
  mov    $0xbf,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %r12d,%edi
  or     $0x80,%dil
  call   <put8@plt>
  pop    %rbx
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <put32@plt>
```

assistant: ```c
void movsx_reg32_16preg64pimm32(int reg1, int reg2, unsigned int imm32) {
  put8(0x0F);
  put8(0xBF);
  put8((reg1 << 3) | reg2 | 0x80);
  put32(imm32);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L8
L11:
  mov    -0x10(%rbp),%rax
  cmp    $0x4,%rax
  jne    L53
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L2
L53:
  mov    -0x10(%rbp),%rax
  cmp    $0x1,%rax
  jne    L69
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L69:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sumsq@plt>
  mov    %rax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L8:
  mov    -0x10(%rbp),%rax
  cmp    $0x1,%rax
  jne    L11
  mov    -0x10(%rbp),%rax
  cmp    $0x4,%rax
  jne    L11
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L59
  call   <__stack_chk_fail@plt>
L59:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D12
type_guessed: string

tool: D10: %llu

tool: D0: -1

tool: D12: %d

assistant: ```c
int main() {
  int c = 0;
  unsigned long long int n;
  scanf("%llu", &n);
  while (n != 1 || n != 4) {
    if (n == 4) {
      printf("-1\n");
      break;
    }
    if (n == 1) {
      printf("%d", c);
      break;
    }
    n = sumsq(n);
    c++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  mov    $0x0,%ebx
  cmp    $0x4,%rdi
  je     L40
L6:
  cmp    $0x1,%rdi
  je     L5
  call   <sumsq@plt>
  mov    %rax,%rdi
  mov    %rax,(%rsp)
  add    $0x1,%ebx
  cmp    $0x4,%rax
  jne    L6
L40:
  lea    D23(%rip),%rdi
  call   <puts@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L3
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D26
type_infered: string
name: read_data
arguments: data_tag: D23
type_infered: string
name: read_data
arguments: data_tag: D25
type_infered: string

tool: D26: %llu

tool: D23: -1

tool: D25: %d

assistant: ```c
int main() {
  int c = 0;
  unsigned long long int n;
  scanf("%llu", &n);
  while (n != 1 || n != 4) {
    if (n == 4) {
      printf("-1\n");
      break;
    }
    if (n == 1) {
      printf("%d", c);
      break;
    }
    n = sumsq(n);
    c++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rdi
  xor    %ebp,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  cmp    $0x4,%rdi
  jne    L55
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L41:
  call   <sumsq@plt>
  add    $0x1,%ebp
  mov    %rax,(%rsp)
  mov    %rax,%rdi
  cmp    $0x4,%rax
  je     L49
L55:
  cmp    $0x1,%rdi
  jne    L41
  mov    %ebp,%esi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L49:
  lea    D17(%rip),%rdi
  call   <puts@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D23
type_infered: string
name: read_data
arguments: label: D2
type_infered: string
name: read_data
arguments: label: D17
type_infered: string

tool: D23: %llu

tool: D2: %d

tool: D17: -1

assistant: ```c
int main() {
  int c = 0;
  unsigned long long int n;
  scanf("%llu", &n);
  while (n != 1 || n != 4) {
    if (n == 4) {
      printf("-1\n");
      break;
    }
    if (n == 1) {
      printf("%d", c);
      break;
    }
    n = sumsq(n);
    c++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  xor    %ebp,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  cmp    $0x4,%rdi
  jne    L49
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L1:
  call   <sumsq@plt>
  add    $0x1,%ebp
  mov    %rax,(%rsp)
  mov    %rax,%rdi
  cmp    $0x4,%rax
  je     L39
L49:
  cmp    $0x1,%rdi
  jne    L1
  mov    %ebp,%esi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L47
L39:
  lea    D21(%rip),%rdi
  call   <puts@plt>
L47:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L50:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D20
type: string
name: read_data
arguments: label: D21
type: string

tool: D3: %llu

tool: D20: %d

tool: D21: -1

assistant: ```c
int main() {
  int c = 0;
  unsigned long long int n;
  scanf("%llu", &n);
  while (n != 1 || n != 4) {
    if (n == 4) {
      printf("-1\n");
      break;
    }
    if (n == 1) {
      printf("%d", c);
      break;
    }
    n = sumsq(n);
    c++;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D6
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string

tool: D6: Usage: dataserver [ARGS]



tool: D18:   --tables DIR     Specify the tables folder. Default: working directory


assistant: ```c
void usage(int retval) {
  printf("Usage: dataserver [ARGS]\n\n");
  printf("  --tables DIR     Specify the tables folder. Default: working directory\n");
  exit(retval);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D11(%rip),%rdi
  call   <printf@plt>
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <exit@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D11
data_type: string
name: parse_data
arguments: data_tag: D4
data_type: string

tool: D11: Usage: dataserver [ARGS]



tool: D4:   --tables DIR     Specify the tables folder. Default: working directory


assistant: ```c
void usage(int retval) {
  printf("Usage: dataserver [ARGS]\n\n");
  printf("  --tables DIR     Specify the tables folder. Default: working directory\n");
  exit(retval);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D1
data_type: string

tool: D5: Usage: dataserver [ARGS]



tool: D1:   --tables DIR     Specify the tables folder. Default: working directory


assistant: ```c
void usage(int retval) {
  printf("Usage: dataserver [ARGS]\n\n");
  printf("  --tables DIR     Specify the tables folder. Default: working directory\n");
  exit(retval);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D18
type: string

tool: D7: Usage: dataserver [ARGS]



tool: D18:   --tables DIR     Specify the tables folder. Default: working directory


assistant: ```c
void usage(int retval) {
  printf("Usage: dataserver [ARGS]\n\n");
  printf("  --tables DIR     Specify the tables folder. Default: working directory\n");
  exit(retval);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dspd_tmperr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L6
  negl   -0x4(%rbp)
L6:
  mov    D34(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  cmp    %eax,-0x4(%rbp)
  je     L64
  mov    D31(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  cmp    %eax,-0x4(%rbp)
  je     L64
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  cmp    %eax,-0x4(%rbp)
  je     L64
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  cmp    %eax,-0x4(%rbp)
  je     L64
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  cmp    %eax,-0x4(%rbp)
  jne    L22
L64:
  mov    $0x1,%eax
  jmp    L18
L22:
  mov    $0x0,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
bool dspd_tmperr(int err) {
  if (err > 0)
    err *= -1;
  return err == -EAGAIN || err == -EWOULDBLOCK || err == -EINTR || err == -EBUSY || err == -EINVAL;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<dspd_tmperr>:
  endbr64
  mov    %edi,%eax
  neg    %eax
  cmovs  %edi,%eax
  neg    %eax
  mov    $0x1,%edx
  mov    D30(%rip),%rcx
  mov    %eax,%esi
  add    (%rcx),%esi
  je     L29
  mov    D46(%rip),%rcx
  mov    %eax,%esi
  add    (%rcx),%esi
  je     L29
  mov    D27(%rip),%rcx
  mov    %eax,%esi
  add    (%rcx),%esi
  je     L29
  mov    D37(%rip),%rcx
  mov    %eax,%edi
  add    (%rcx),%edi
  je     L29
  mov    D26(%rip),%rdx
  add    (%rdx),%eax
  sete   %dl
  movzbl %dl,%edx
L29:
  mov    %edx,%eax
  ret
```

assistant: ```c
bool dspd_tmperr(int err) {
  if (err > 0)
    err *= -1;
  return err == -EAGAIN || err == -EWOULDBLOCK || err == -EINTR || err == -EBUSY || err == -EINVAL;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dspd_tmperr>:
  endbr64
  mov    %edi,%eax
  mov    D46(%rip),%rdx
  mov    $0x1,%r8d
  neg    %eax
  cmovs  %edi,%eax
  neg    %eax
  mov    %eax,%ecx
  add    (%rdx),%ecx
  je     L12
  mov    D18(%rip),%rdx
  mov    %eax,%esi
  add    (%rdx),%esi
  je     L12
  mov    D47(%rip),%rdx
  mov    %eax,%esi
  add    (%rdx),%esi
  je     L12
  mov    D42(%rip),%rdx
  mov    %eax,%ecx
  add    (%rdx),%ecx
  je     L12
  mov    D16(%rip),%rdx
  xor    %r8d,%r8d
  add    (%rdx),%eax
  sete   %r8b
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool dspd_tmperr(int err) {
  if (err > 0)
    err *= -1;
  return err == -EAGAIN || err == -EWOULDBLOCK || err == -EINTR || err == -EBUSY || err == -EINVAL;
}
```
user: What is the c source code of the assembly code below:

```asm
<dspd_tmperr>:
  endbr64
  mov    %edi,%eax
  mov    D5(%rip),%rdx
  mov    $0x1,%r8d
  neg    %eax
  cmovs  %edi,%eax
  neg    %eax
  mov    %eax,%ecx
  add    (%rdx),%ecx
  je     L33
  mov    D37(%rip),%rdx
  mov    %eax,%esi
  add    (%rdx),%esi
  je     L33
  mov    D49(%rip),%rdx
  mov    %eax,%esi
  add    (%rdx),%esi
  je     L33
  mov    D17(%rip),%rdx
  mov    %eax,%ecx
  add    (%rdx),%ecx
  je     L33
  mov    D42(%rip),%rdx
  xor    %r8d,%r8d
  add    (%rdx),%eax
  sete   %r8b
L33:
  mov    %r8d,%eax
  ret
```

assistant: ```c
bool dspd_tmperr(int err) {
  if (err > 0)
    err *= -1;
  return err == -EAGAIN || err == -EWOULDBLOCK || err == -EINTR || err == -EBUSY || err == -EINVAL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<dobulk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %rcx,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  movl   $0x3e8,-0x2c(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0x60(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <doioctl@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  js     L27
  mov    -0x34(%rbp),%eax
  jmp    L6
L27:
  mov    $0xffffffff,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%rax
  mov    %rcx,%rdx
  mov    %fs:0x28,%rcx
  mov    %rcx,0x28(%rsp)
  xor    %ecx,%ecx
  movq   $0x0,0x18(%rsp)
  mov    %edi,(%rsp)
  movl   $0x3e8,0x4(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <doioctl@plt>
  test   %eax,%eax
  mov    $0xffffffff,%edx
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x38,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dobulk>:
  endbr64
  sub    $0x38,%rsp
  mov    %rdx,%r8
  mov    %rcx,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %edi,(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rsp,%rsi
  mov    (%rax),%edi
  movl   $0x3e8,0x4(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %r8,0x8(%rsp)
  call   <doioctl@plt>
  mov    $0xffffffff,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x38,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int dobulk(int EndPt, void *pvBuf, size_t cbBuf, const char *pszWho) {
  struct usbdevfs_bulktransfer BulkMsg = {0};
  BulkMsg.ep = EndPt;
  BulkMsg.timeout = 1000;
  BulkMsg.len = cbBuf;
  BulkMsg.data = pvBuf;
  int rc = doioctl(USBDEVFS_BULK, &BulkMsg, pszWho);
  if (rc >= 0)
    return rc;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<h5f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edi
  call   <hexc1@plt>
  mov    -0x18(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x1c(%rbp),%eax
  and    $0xff00,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x18,%eax
  or     %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0xf000f00,%eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  sar    $0xc,%eax
  and    $0xf000f,%eax
  or     %edx,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x6060606,%eax
  and    $0x10101010,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  lea    0x30303030(%rax),%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void h5f(char *to, int x) {
  to[0] = hexc1(x >> 16);
  x = (x & 0xff00) | ((x & 255) << 24);
  x = (x & 0xf000f00) | ((x >> 12) & 0xf000f);
  unsigned int ten = (x + 0x6060606) & 0x10101010;
  *(int *)(to + 1) = (int)(x + 0x30303030 + (ten >> 1) - (ten >> 4));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<h5f>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%edi
  sar    $0x10,%edi
  call   <hexc1@plt>
  mov    %al,0x0(%rbp)
  mov    %ebx,%esi
  and    $0xff00,%esi
  shl    $0x18,%ebx
  or     %ebx,%esi
  mov    %esi,%edx
  and    $0xf000f00,%edx
  sar    $0xc,%esi
  and    $0xf000f,%esi
  or     %esi,%edx
  lea    0x6060606(%rdx),%eax
  and    $0x10101010,%eax
  mov    %eax,%ecx
  shr    %ecx
  lea    0x30303030(%rdx,%rcx,1),%edx
  shr    $0x4,%eax
  sub    %eax,%edx
  mov    %edx,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void h5f(char *to, int x) {
  to[0] = hexc1(x >> 16);
  x = (x & 0xff00) | ((x & 255) << 24);
  x = (x & 0xf000f00) | ((x >> 12) & 0xf000f);
  unsigned int ten = (x + 0x6060606) & 0x10101010;
  *(int *)(to + 1) = (int)(x + 0x30303030 + (ten >> 1) - (ten >> 4));
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<h5f>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  sar    $0x10,%edi
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <hexc1@plt>
  mov    %ebx,%esi
  shl    $0x18,%ebx
  and    $0xff00,%esi
  mov    %al,0x0(%rbp)
  or     %ebx,%esi
  mov    %esi,%edx
  sar    $0xc,%esi
  and    $0xf000f00,%edx
  and    $0xf000f,%esi
  or     %esi,%edx
  lea    0x6060606(%rdx),%eax
  and    $0x10101010,%eax
  mov    %eax,%ecx
  shr    $0x4,%eax
  shr    %ecx
  lea    0x30303030(%rdx,%rcx,1),%edx
  sub    %eax,%edx
  mov    %edx,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void h5f(char *to, int x) {
  to[0] = hexc1(x >> 16);
  x = (x & 0xff00) | ((x & 255) << 24);
  x = (x & 0xf000f00) | ((x >> 12) & 0xf000f);
  unsigned int ten = (x + 0x6060606) & 0x10101010;
  *(int *)(to + 1) = (int)(x + 0x30303030 + (ten >> 1) - (ten >> 4));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<h5f>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  sar    $0x10,%edi
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <hexc1@plt>
  mov    %ebx,%esi
  shl    $0x18,%ebx
  and    $0xff00,%esi
  mov    %al,0x0(%rbp)
  or     %ebx,%esi
  mov    %esi,%edx
  sar    $0xc,%esi
  and    $0xf000f00,%edx
  and    $0xf000f,%esi
  or     %esi,%edx
  lea    0x6060606(%rdx),%eax
  and    $0x10101010,%eax
  mov    %eax,%ecx
  shr    $0x4,%eax
  shr    %ecx
  lea    0x30303030(%rdx,%rcx,1),%edx
  sub    %eax,%edx
  mov    %edx,0x1(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void h5f(char *to, int x) {
  to[0] = hexc1(x >> 16);
  x = (x & 0xff00) | ((x & 255) << 24);
  x = (x & 0xf000f00) | ((x >> 12) & 0xf000f);
  unsigned int ten = (x + 0x6060606) & 0x10101010;
  *(int *)(to + 1) = (int)(x + 0x30303030 + (ten >> 1) - (ten >> 4));
}
```