ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: Salut!


assistant: ```c
int main() {
  printf("Salut!\n");
  getchar();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wordcmp>:
  endbr64
  mov    %rsi,%r8
  test   $0x3,%dl
  je     L0
  lea    0x3(%rdx),%esi
  test   %edx,%edx
  cmovns %edx,%esi
  sar    $0x2,%esi
  movslq %esi,%r9
  lea    (%rdi,%r9,1),%r10
  sub    $0x1,%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  add    %eax,%edx
  and    $0x3,%edx
  sub    %edx,%eax
  lea    0x6(%rax,%rax,1),%ecx
  movzbl (%r10),%eax
  sar    %cl,%eax
  shl    %cl,%eax
  mov    %al,(%r10)
  lea    (%r8,%r9,1),%rax
  movzbl (%rax),%edx
  sar    %cl,%edx
  shl    %cl,%edx
  mov    %dl,(%rax)
  add    $0x1,%esi
L41:
  test   %esi,%esi
  jle    L25
  mov    %esi,%esi
  mov    $0x0,%eax
L3:
  movzbl (%rdi,%rax,1),%ecx
  movzbl (%r8,%rax,1),%edx
  cmp    %dl,%cl
  jb     L40
  ja     L21
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L3
  mov    $0x0,%eax
  ret
L0:
  lea    0x3(%rdx),%esi
  test   %edx,%edx
  cmovns %edx,%esi
  sar    $0x2,%esi
  jmp    L41
L25:
  mov    $0x0,%eax
  ret
L40:
  mov    $0xffffffff,%eax
  ret
L21:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wordcmp(unsigned char *w1, unsigned char *w2, int n) {
  int i = 0, limit;
  if (n % 4 != 0) {
    w1[n / 4] = w1[n / 4] >> (2 * (3 - ((n - 1) % 4)));
    w1[n / 4] = w1[n / 4] << (2 * (3 - ((n - 1) % 4)));
    w2[n / 4] = w2[n / 4] >> (2 * (3 - ((n - 1) % 4)));
    w2[n / 4] = w2[n / 4] << (2 * (3 - ((n - 1) % 4)));
    limit = (n / 4) + 1;
  } else {
    limit = n / 4;
  }
  for (i = 0; i < limit; i++) {
    if (w1[i] < w2[i])
      return -1;
    if (w1[i] > w2[i])
      return +1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<wordcmp>:
  endbr64
  mov    %edx,%ecx
  lea    0x3(%rdx),%edx
  test   %ecx,%ecx
  cmovns %ecx,%edx
  mov    %edx,%eax
  sar    $0x2,%eax
  test   $0x3,%cl
  je     L22
  sub    $0x1,%ecx
  movslq %eax,%r8
  add    $0x1,%eax
  mov    %ecx,%edx
  lea    (%rdi,%r8,1),%r9
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  add    %edx,%ecx
  and    $0x3,%ecx
  sub    %ecx,%edx
  lea    0x6(%rdx,%rdx,1),%ecx
  movzbl (%r9),%edx
  sar    %cl,%edx
  shl    %cl,%edx
  mov    %dl,(%r9)
  lea    (%rsi,%r8,1),%rdx
  movzbl (%rdx),%r8d
  sar    %cl,%r8d
  shl    %cl,%r8d
  mov    %r8b,(%rdx)
L22:
  test   %eax,%eax
  jle    L24
  movslq %eax,%rdx
  xor    %eax,%eax
  jmp    L15
  nop
L55:
  ja     L53
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L24
L15:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jae    L55
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L24:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L53:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wordcmp(unsigned char *w1, unsigned char *w2, int n) {
  int i = 0, limit;
  if (n % 4 != 0) {
    w1[n / 4] = w1[n / 4] >> (2 * (3 - ((n - 1) % 4)));
    w1[n / 4] = w1[n / 4] << (2 * (3 - ((n - 1) % 4)));
    w2[n / 4] = w2[n / 4] >> (2 * (3 - ((n - 1) % 4)));
    w2[n / 4] = w2[n / 4] << (2 * (3 - ((n - 1) % 4)));
    limit = (n / 4) + 1;
  } else {
    limit = n / 4;
  }
  for (i = 0; i < limit; i++) {
    if (w1[i] < w2[i])
      return -1;
    if (w1[i] > w2[i])
      return +1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<wordcmp>:
  endbr64
  mov    %edx,%ecx
  lea    0x3(%rdx),%edx
  test   %ecx,%ecx
  cmovns %ecx,%edx
  mov    %edx,%eax
  sar    $0x2,%eax
  test   $0x3,%cl
  je     L0
  sub    $0x1,%ecx
  movslq %eax,%r8
  add    $0x1,%eax
  mov    %ecx,%edx
  lea    (%rdi,%r8,1),%r9
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  add    %edx,%ecx
  and    $0x3,%ecx
  sub    %ecx,%edx
  lea    0x6(%rdx,%rdx,1),%ecx
  movzbl (%r9),%edx
  sar    %cl,%edx
  shl    %cl,%edx
  mov    %dl,(%r9)
  lea    (%rsi,%r8,1),%rdx
  movzbl (%rdx),%r8d
  sar    %cl,%r8d
  shl    %cl,%r8d
  mov    %r8b,(%rdx)
L0:
  test   %eax,%eax
  jle    L7
  movslq %eax,%rdx
  xor    %eax,%eax
  jmp    L22
  nop
L5:
  ja     L48
  add    $0x1,%rax
  cmp    %rax,%rdx
  je     L7
L22:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jae    L5
  mov    $0xffffffff,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int wordcmp(unsigned char *w1, unsigned char *w2, int n) {
  int i = 0, limit;
  if (n % 4 != 0) {
    w1[n / 4] = w1[n / 4] >> (2 * (3 - ((n - 1) % 4)));
    w1[n / 4] = w1[n / 4] << (2 * (3 - ((n - 1) % 4)));
    w2[n / 4] = w2[n / 4] >> (2 * (3 - ((n - 1) % 4)));
    w2[n / 4] = w2[n / 4] << (2 * (3 - ((n - 1) % 4)));
    limit = (n / 4) + 1;
  } else {
    limit = n / 4;
  }
  for (i = 0; i < limit; i++) {
    if (w1[i] < w2[i])
      return -1;
    if (w1[i] > w2[i])
      return +1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L38
L54:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%rax
  cmp    $0x1,%rax
  jne    L56
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L38
L56:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  xor    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  cmp    %rax,%rdx
  jne    L12
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L12:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L38:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L54
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
datatype: string
name: retrieve_data
arguments: data_tag: D29
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D49
datatype: string
name: retrieve_data
arguments: data_tag: D13
datatype: string

tool: D15: %d

tool: D29: %ld

tool: D5: 2

tool: D49: %ld


tool: D13: -1

assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    long int n;
    scanf("%ld", &n);
    if (n == 1)
      printf("2\n");
    else {
      long int m;
      m = n / 2;
      if ((m ^ (m + 1)) == n)
        printf("%ld\n", m);
      else
        printf("-1\n");
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L39
  lea    D47(%rip),%rbx
  lea    D38(%rip),%rbp
  lea    D2(%rip),%r12
  lea    D31(%rip),%r13
  jmp    L50
L17:
  mov    %r13,%rdi
  call   <puts@plt>
  jmp    L57
L52:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L57:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L39
L50:
  lea    0x10(%rsp),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  cmp    $0x1,%rax
  je     L17
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  lea    0x1(%rsi),%rdx
  xor    %rsi,%rdx
  cmp    %rdx,%rax
  je     L52
  mov    %rbp,%rdi
  call   <puts@plt>
  jmp    L57
L39:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string
name: retrieve_data
arguments: data_label: D47
type_infered: string
name: retrieve_data
arguments: data_label: D38
type_infered: string
name: retrieve_data
arguments: data_label: D2
type_infered: string
name: retrieve_data
arguments: data_label: D31
type_infered: string

tool: D3: %d

tool: D47: %ld

tool: D38: -1

tool: D2: %ld


tool: D31: 2

assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    long int n;
    scanf("%ld", &n);
    if (n == 1)
      printf("2\n");
    else {
      long int m;
      m = n / 2;
      if ((m ^ (m + 1)) == n)
        printf("%ld\n", m);
      else
        printf("-1\n");
    }
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D45(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L11
  lea    0x10(%rsp),%rbp
  lea    D12(%rip),%rbx
  lea    D21(%rip),%r12
  lea    D40(%rip),%r13
  lea    D20(%rip),%r14
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L47:
  mov    %r12,%rdi
  call   <puts@plt>
L29:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L11
L25:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  cmp    $0x1,%rax
  je     L26
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  lea    0x1(%rsi),%rdx
  xor    %rsi,%rdx
  cmp    %rdx,%rax
  jne    L47
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L25
L11:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L29
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D45
type_infered: string
name: retrieve_data
arguments: data_label: D12
type_infered: string
name: retrieve_data
arguments: data_label: D21
type_infered: string
name: retrieve_data
arguments: data_label: D40
type_infered: string
name: retrieve_data
arguments: data_label: D20
type_infered: string

tool: D45: %d

tool: D12: %ld

tool: D21: -1

tool: D40: %ld


tool: D20: 2

assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    long int n;
    scanf("%ld", &n);
    if (n == 1)
      printf("2\n");
    else {
      long int m;
      m = n / 2;
      if ((m ^ (m + 1)) == n)
        printf("%ld\n", m);
      else
        printf("-1\n");
    }
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L69
  lea    0x10(%rsp),%rbp
  lea    D42(%rip),%rbx
  lea    D48(%rip),%r12
  lea    D39(%rip),%r13
  lea    D49(%rip),%r14
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r12,%rdi
  call   <puts@plt>
L50:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L69
L38:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x10(%rsp),%rax
  cmp    $0x1,%rax
  je     L18
  mov    %rax,%rsi
  shr    $0x3f,%rsi
  add    %rax,%rsi
  sar    %rsi
  lea    0x1(%rsi),%rdx
  xor    %rsi,%rdx
  cmp    %rdx,%rax
  jne    L39
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jne    L38
L69:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L18:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L50
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
datatype: string
name: extract_symbolic_data
arguments: data_tag: D42
datatype: string
name: extract_symbolic_data
arguments: data_tag: D48
datatype: string
name: extract_symbolic_data
arguments: data_tag: D39
datatype: string
name: extract_symbolic_data
arguments: data_tag: D49
datatype: string

tool: D11: %d

tool: D42: %ld

tool: D48: -1

tool: D39: %ld


tool: D49: 2

assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    long int n;
    scanf("%ld", &n);
    if (n == 1)
      printf("2\n");
    else {
      long int m;
      m = n / 2;
      if ((m ^ (m + 1)) == n)
        printf("%ld\n", m);
      else
        printf("-1\n");
    }
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_kill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D7(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int _kill(int pid, int sig) {
  errno = EINVAL;
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_kill>:
  endbr64
  mov    D13(%rip),%rax
  mov    (%rax),%edx
  mov    D10(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _kill(int pid, int sig) {
  errno = EINVAL;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<_kill>:
  endbr64
  mov    D5(%rip),%rax
  mov    (%rax),%edx
  mov    D1(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _kill(int pid, int sig) {
  errno = EINVAL;
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_kill>:
  endbr64
  mov    D6(%rip),%rax
  mov    (%rax),%edx
  mov    D2(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int _kill(int pid, int sig) {
  errno = EINVAL;
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Pack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L15:
  movb   $0x0,-0x9(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L16
L35:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    $0x7,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  or     %edx,%eax
  mov    %al,-0x9(%rbp)
  addl   $0x1,-0x4(%rbp)
L16:
  cmpl   $0x7,-0x4(%rbp)
  jbe    L35
  mov    -0x8(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Pack(block, bit, blockLen) unsigned char *block;
unsigned char *bit;
unsigned int blockLen;
{
  unsigned int i, j;
  unsigned char t;
  for (i = 0; i < blockLen; i++) {
    t = 0;
    for (j = 0; j < 8; j++)
      t |= bit[8 * i + j] << (7 - j);
    block[i] = t;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Pack>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  je     L5
  mov    %edx,%r9d
  mov    $0x0,%r8d
  jmp    L42
L41:
  mov    %dl,(%r10,%r8,1)
  add    $0x1,%r8
  cmp    %r9,%r8
  je     L5
L42:
  mov    $0x7,%ecx
  mov    $0x0,%edx
  lea    0x7(,%r8,8),%edi
L47:
  mov    %edi,%eax
  sub    %ecx,%eax
  movzbl (%rsi,%rax,1),%eax
  shl    %cl,%eax
  or     %eax,%edx
  sub    $0x1,%ecx
  cmp    $0xffffffff,%ecx
  jne    L47
  jmp    L41
L5:
  ret
```

assistant: ```c
void Pack(block, bit, blockLen) unsigned char *block;
unsigned char *bit;
unsigned int blockLen;
{
  unsigned int i, j;
  unsigned char t;
  for (i = 0; i < blockLen; i++) {
    t = 0;
    for (j = 0; j < 8; j++)
      t |= bit[8 * i + j] << (7 - j);
    block[i] = t;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Pack>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  je     L17
  mov    %edx,%r9d
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L23:
  mov    $0x7,%ecx
  xor    %edx,%edx
  lea    0x7(,%r8,8),%edi
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %edi,%eax
  sub    %ecx,%eax
  movzbl (%rsi,%rax,1),%eax
  shl    %cl,%eax
  or     %eax,%edx
  sub    $0x1,%ecx
  jae    L19
  mov    %dl,(%r10,%r8,1)
  add    $0x1,%r8
  cmp    %r8,%r9
  jne    L23
L17:
  ret
```

assistant: ```c
void Pack(block, bit, blockLen) unsigned char *block;
unsigned char *bit;
unsigned int blockLen;
{
  unsigned int i, j;
  unsigned char t;
  for (i = 0; i < blockLen; i++) {
    t = 0;
    for (j = 0; j < 8; j++)
      t |= bit[8 * i + j] << (7 - j);
    block[i] = t;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<Pack>:
  endbr64
  mov    %rsi,%rcx
  test   %edx,%edx
  je     L18
  lea    -0x1(%rdx),%eax
  mov    %rdi,%rsi
  xor    %edx,%edx
  lea    0x1(%rdi,%rax,1),%r8
  nopl   0x0(%rax,%rax,1)
L14:
  lea    0x1(%rdx),%eax
  mov    %edx,%edi
  add    $0x1,%rsi
  movzbl (%rcx,%rax,1),%eax
  movzbl (%rcx,%rdi,1),%edi
  shl    $0x6,%eax
  shl    $0x7,%edi
  or     %edi,%eax
  lea    0x7(%rdx),%edi
  or     (%rcx,%rdi,1),%al
  lea    0x2(%rdx),%edi
  movzbl (%rcx,%rdi,1),%edi
  shl    $0x5,%edi
  or     %edi,%eax
  lea    0x3(%rdx),%edi
  movzbl (%rcx,%rdi,1),%edi
  shl    $0x4,%edi
  or     %edi,%eax
  lea    0x4(%rdx),%edi
  movzbl (%rcx,%rdi,1),%edi
  shl    $0x3,%edi
  or     %edi,%eax
  lea    0x5(%rdx),%edi
  movzbl (%rcx,%rdi,1),%edi
  shl    $0x2,%edi
  or     %edi,%eax
  lea    0x6(%rdx),%edi
  add    $0x8,%edx
  movzbl (%rcx,%rdi,1),%edi
  add    %edi,%edi
  or     %edi,%eax
  mov    %al,-0x1(%rsi)
  cmp    %rsi,%r8
  jne    L14
L18:
  ret
```

assistant: ```c
void Pack(block, bit, blockLen) unsigned char *block;
unsigned char *bit;
unsigned int blockLen;
{
  unsigned int i, j;
  unsigned char t;
  for (i = 0; i < blockLen; i++) {
    t = 0;
    for (j = 0; j < 8; j++)
      t |= bit[8 * i + j] << (7 - j);
    block[i] = t;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <enableGPIO1Clocks@plt>
  mov    $0x4804c134,%eax
  mov    (%rax),%eax
  mov    $0x4804c134,%edx
  and    $0xfe1fffff,%eax
  mov    %eax,(%rdx)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L18:
  mov    $0x4804c190,%eax
  movl   $0xffffff,(%rax)
  mov    -0x4(%rbp),%eax
  shl    $0x15,%eax
  mov    $0x4804c194,%edx
  mov    %eax,(%rdx)
  mov    $0x3fffff,%edi
  call   <delay@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0xf,-0x4(%rbp)
  jle    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  int x;
  enableGPIO1Clocks();
  (*((volatile unsigned int *)(0x4804C000 + 0x134))) &= ~(0xf << 21);
  for (x = 0; x < 16; x++) {
    (*((volatile unsigned int *)(0x4804C000 + 0x190))) = 0xffffff;
    (*((volatile unsigned int *)(0x4804C000 + 0x194))) = (x << 21);
    delay(0x3fffff);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <enableGPIO1Clocks@plt>
  mov    0x4804c134,%eax
  and    $0xfe1fffff,%eax
  mov    %eax,0x4804c134
  mov    $0x0,%ebx
L2:
  movl   $0xffffff,0x4804c190
  mov    %ebx,0x4804c194
  mov    $0x3fffff,%edi
  call   <delay@plt>
  add    $0x200000,%ebx
  cmp    $0x2000000,%ebx
  jne    L2
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  int x;
  enableGPIO1Clocks();
  (*((volatile unsigned int *)(0x4804C000 + 0x134))) &= ~(0xf << 21);
  for (x = 0; x < 16; x++) {
    (*((volatile unsigned int *)(0x4804C000 + 0x190))) = 0xffffff;
    (*((volatile unsigned int *)(0x4804C000 + 0x194))) = (x << 21);
    delay(0x3fffff);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <enableGPIO1Clocks@plt>
  mov    0x4804c134,%eax
  and    $0xfe1fffff,%eax
  mov    %eax,0x4804c134
  nopl   0x0(%rax)
L7:
  movl   $0xffffff,0x4804c190
  mov    $0x3fffff,%edi
  mov    %ebx,0x4804c194
  add    $0x200000,%ebx
  call   <delay@plt>
  cmp    $0x2000000,%ebx
  jne    L7
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  int x;
  enableGPIO1Clocks();
  (*((volatile unsigned int *)(0x4804C000 + 0x134))) &= ~(0xf << 21);
  for (x = 0; x < 16; x++) {
    (*((volatile unsigned int *)(0x4804C000 + 0x190))) = 0xffffff;
    (*((volatile unsigned int *)(0x4804C000 + 0x194))) = (x << 21);
    delay(0x3fffff);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <enableGPIO1Clocks@plt>
  mov    0x4804c134,%eax
  and    $0xfe1fffff,%eax
  mov    %eax,0x4804c134
  nopl   0x0(%rax)
L4:
  movl   $0xffffff,0x4804c190
  mov    $0x3fffff,%edi
  mov    %ebx,0x4804c194
  add    $0x200000,%ebx
  call   <delay@plt>
  cmp    $0x2000000,%ebx
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  int x;
  enableGPIO1Clocks();
  (*((volatile unsigned int *)(0x4804C000 + 0x134))) &= ~(0xf << 21);
  for (x = 0; x < 16; x++) {
    (*((volatile unsigned int *)(0x4804C000 + 0x190))) = 0xffffff;
    (*((volatile unsigned int *)(0x4804C000 + 0x194))) = (x << 21);
    delay(0x3fffff);
  }
}
```