ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0x14(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  call   <pow@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  sub    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2ss %eax,%xmm1
  mulss  0x14(%rsp),%xmm1
  movss  D31(%rip),%xmm0
  subss  0x10(%rsp),%xmm0
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D21(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
datatype: string
name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D31
datatype: byte[4]
name: disassemble_data
arguments: label: D21
datatype: string

tool: D1: Enter the first term of the GP then Common Ratio then number of terms.

tool: D27: %f%f%f

tool: {"D31": [0x00,0x00,0x80,0x3f]}

tool: D21: The sum of first %.0f terms is %f


assistant: ```c
void main() {
  float n, r, a, sum;
  printf("Enter the first term of the GP then Common Ratio then number of terms.\n");
  scanf("%f%f%f", &a, &r, &n);
  sum = (a * (1 - pow(r, n))) / (1 - r);
  printf("The sum of first %.0f terms is %f\n", n, sum);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D17(%rip),%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  movss  D7(%rip),%xmm0
  subss  0x10(%rsp),%xmm0
  mov    %eax,%r8d
  mov    $0x1,%eax
  lea    D30(%rip),%rdi
  sub    %r8d,%eax
  cvtsi2ss %eax,%xmm1
  mulss  0x14(%rsp),%xmm1
  mov    $0x2,%eax
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_infered: string
name: read_data
arguments: data_tag: D17
type_infered: string
name: read_data
arguments: data_tag: D7
type_infered: byte[4]
name: read_data
arguments: data_tag: D30
type_infered: string

tool: D6: Enter the first term of the GP then Common Ratio then number of terms.

tool: D17: %f%f%f

tool: {"D7": [0x00,0x00,0x80,0x3f]}

tool: D30: The sum of first %.0f terms is %f


assistant: ```c
void main() {
  float n, r, a, sum;
  printf("Enter the first term of the GP then Common Ratio then number of terms.\n");
  scanf("%f%f%f", &a, &r, &n);
  sum = (a * (1 - pow(r, n))) / (1 - r);
  printf("The sum of first %.0f terms is %f\n", n, sum);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D38(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0xc(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    D33(%rip),%rdi
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm0
  call   <pow@plt>
  pxor   %xmm1,%xmm1
  movss  D26(%rip),%xmm0
  subss  0x10(%rsp),%xmm0
  mov    %eax,%r8d
  mov    $0x1,%eax
  lea    D6(%rip),%rdi
  sub    %r8d,%eax
  cvtsi2ss %eax,%xmm1
  mulss  0x14(%rsp),%xmm1
  mov    $0x2,%eax
  divss  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  cvtss2sd 0xc(%rsp),%xmm0
  cvtss2sd %xmm1,%xmm1
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D38
type_infered: string
name: parse_data
arguments: data_tag: D33
type_infered: string
name: parse_data
arguments: data_tag: D26
type_infered: byte[4]
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D38: Enter the first term of the GP then Common Ratio then number of terms.

tool: D33: %f%f%f

tool: {"D26": [0x00,0x00,0x80,0x3f]}

tool: D6: The sum of first %.0f terms is %f


assistant: ```c
void main() {
  float n, r, a, sum;
  printf("Enter the first term of the GP then Common Ratio then number of terms.\n");
  scanf("%f%f%f", &a, &r, &n);
  sum = (a * (1 - pow(r, n))) / (1 - r);
  printf("The sum of first %.0f terms is %f\n", n, sum);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<align64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  neg    %eax
  mov    %eax,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  and    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long align64(unsigned long offset, unsigned int alignment) {
  unsigned long mask = ~(alignment - 1);
  return (offset + (alignment - 1)) & mask;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<align64>:
  endbr64
  lea    -0x1(%rsi),%eax
  add    %rdi,%rax
  neg    %esi
  and    %rsi,%rax
  ret
```

assistant: ```c
unsigned long align64(unsigned long offset, unsigned int alignment) {
  unsigned long mask = ~(alignment - 1);
  return (offset + (alignment - 1)) & mask;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<align64>:
  endbr64
  lea    -0x1(%rsi),%eax
  neg    %esi
  add    %rdi,%rax
  and    %rsi,%rax
  ret
```

assistant: ```c
unsigned long align64(unsigned long offset, unsigned int alignment) {
  unsigned long mask = ~(alignment - 1);
  return (offset + (alignment - 1)) & mask;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<align64>:
  endbr64
  lea    -0x1(%rsi),%eax
  neg    %esi
  add    %rdi,%rax
  and    %rsi,%rax
  ret
```

assistant: ```c
unsigned long align64(unsigned long offset, unsigned int alignment) {
  unsigned long mask = ~(alignment - 1);
  return (offset + (alignment - 1)) & mask;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x10(%rbp)
L18:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jg     L48
  mov    -0x18(%rbp),%eax
  cmp    $0x270f,%eax
  jg     L18
L48:
  movl   $0x0,-0x14(%rbp)
  jmp    L62
L61:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ssl -0xc(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L62:
  mov    -0x18(%rbp),%eax
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L61
  pxor   %xmm1,%xmm1
  cvtsi2ssl -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  D19(%rip),%xmm0
  comiss -0x10(%rbp),%xmm0
  jbe    L11
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L8
L11:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L8:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D32
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: byte[4]
name: extract_symbolic_data
arguments: data_tag: D21
type: string
name: extract_symbolic_data
arguments: data_tag: D7
type: string

tool: D32: %d

tool: {"D19": [0x00,0x00,0xe0,0x40]}

tool: D21: light


tool: D7: heavy


assistant: ```c
int main() {
  int n, i, new1;
  float avg = 0;
  do {
    scanf("%d", &n);
  } while (n < 1 && n > 9999);
  for (i = 0; n / 10 != 0; i++) {
    new1 = n % 10;
    avg += new1;
    n /= 10;
  }
  avg = avg / i;
  if (avg < 7)
    printf("light\n");
  else
    printf("heavy\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D29(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  lea    0x9(%rdx),%eax
  cmp    $0x12,%eax
  jbe    L3
  pxor   %xmm0,%xmm0
  mov    $0x0,%esi
L54:
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  pxor   %xmm1,%xmm1
  cvtsi2ss %edx,%xmm1
  addss  %xmm1,%xmm0
  mov    %eax,%edx
  add    $0x1,%esi
  add    $0x9,%eax
  cmp    $0x12,%eax
  ja     L54
  mov    %edx,0x4(%rsp)
L17:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D36(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L33
  lea    D14(%rip),%rdi
  call   <printf@plt>
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  pxor   %xmm0,%xmm0
  mov    $0x0,%esi
  jmp    L17
L33:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
type: string
name: unpack_data
arguments: label: D36
type: byte[4]
name: unpack_data
arguments: label: D14
type: string
name: unpack_data
arguments: label: D31
type: string

tool: D29: %d

tool: {"D36": [0x00,0x00,0xe0,0x40]}

tool: D14: light


tool: D31: heavy


assistant: ```c
int main() {
  int n, i, new1;
  float avg = 0;
  do {
    scanf("%d", &n);
  } while (n < 1 && n > 9999);
  for (i = 0; n / 10 != 0; i++) {
    new1 = n % 10;
    avg += new1;
    n /= 10;
  }
  avg = avg / i;
  if (avg < 7)
    printf("light\n");
  else
    printf("heavy\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D11(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  lea    0x9(%rdx),%eax
  cmp    $0x12,%eax
  jbe    L36
  nopl   0x0(%rax,%rax,1)
L15:
  movslq %edx,%rax
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm1
  mov    %eax,%edx
  lea    0x9(%rax),%eax
  addss  %xmm1,%xmm0
  cmp    $0x12,%eax
  ja     L15
  mov    %edx,0x4(%rsp)
L36:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D13(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L37
  lea    D0(%rip),%rdi
  call   <printf@plt>
L40:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L37:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D11
data_type: string
name: read_data
arguments: tag: D13
data_type: byte[4]
name: read_data
arguments: tag: D0
data_type: string
name: read_data
arguments: tag: D28
data_type: string

tool: D11: %d

tool: {"D13": [0x00,0x00,0xe0,0x40]}

tool: D0: light


tool: D28: heavy


assistant: ```c
int main() {
  int n, i, new1;
  float avg = 0;
  do {
    scanf("%d", &n);
  } while (n < 1 && n > 9999);
  for (i = 0; n / 10 != 0; i++) {
    new1 = n % 10;
    avg += new1;
    n /= 10;
  }
  avg = avg / i;
  if (avg < 7)
    printf("light\n");
  else
    printf("heavy\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D37(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  pxor   %xmm0,%xmm0
  xor    %esi,%esi
  lea    0x9(%rdx),%eax
  cmp    $0x12,%eax
  jbe    L10
  nopl   0x0(%rax,%rax,1)
L26:
  movslq %edx,%rax
  mov    %edx,%ecx
  pxor   %xmm1,%xmm1
  add    $0x1,%esi
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  cvtsi2ss %edx,%xmm1
  mov    %eax,%edx
  lea    0x9(%rax),%eax
  addss  %xmm1,%xmm0
  cmp    $0x12,%eax
  ja     L26
  mov    %edx,0x4(%rsp)
L10:
  pxor   %xmm1,%xmm1
  cvtsi2ss %esi,%xmm1
  divss  %xmm1,%xmm0
  movss  D6(%rip),%xmm1
  comiss %xmm0,%xmm1
  jbe    L22
  lea    D27(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L22:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D37
datatype: string
name: extract_symbolic_data
arguments: label: D6
datatype: byte[4]
name: extract_symbolic_data
arguments: label: D27
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string

tool: D37: %d

tool: {"D6": [0x00,0x00,0xe0,0x40]}

tool: D27: light


tool: D18: heavy


assistant: ```c
int main() {
  int n, i, new1;
  float avg = 0;
  do {
    scanf("%d", &n);
  } while (n < 1 && n > 9999);
  for (i = 0; n / 10 != 0; i++) {
    new1 = n % 10;
    avg += new1;
    n /= 10;
  }
  avg = avg / i;
  if (avg < 7)
    printf("light\n");
  else
    printf("heavy\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L22
L36:
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L11
  mov    -0x14(%rbp),%eax
  add    %eax,-0x10(%rbp)
L11:
  addl   $0x1,-0xc(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L36
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D21
type: string
name: retrieve_data
arguments: data_label: D10
type: string
name: retrieve_data
arguments: data_label: D2
type: string

tool: D21: %d

tool: D10: %d %d

tool: D2: %d


assistant: ```c
int main() {
  int trayQtt;
  scanf("%d", &trayQtt);
  int canesPerTray, cupsPerTray;
  int brokenCups = 0;
  int i;
  for (i = 0; i < trayQtt; i++) {
    scanf("%d %d", &canesPerTray, &cupsPerTray);
    if (canesPerTray > cupsPerTray)
      brokenCups += cupsPerTray;
  }
  printf("%d\n", brokenCups);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L36
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  lea    D5(%rip),%r12
  jmp    L33
L32:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jle    L11
L33:
  lea    0x14(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x10(%rsp)
  jle    L32
  add    %eax,%ebp
  jmp    L32
L36:
  mov    $0x0,%ebp
L11:
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
datatype: string
name: parse_data
arguments: data_tag: D5
datatype: string
name: parse_data
arguments: data_tag: D0
datatype: string

tool: D14: %d

tool: D5: %d %d

tool: D0: %d


assistant: ```c
int main() {
  int trayQtt;
  scanf("%d", &trayQtt);
  int canesPerTray, cupsPerTray;
  int brokenCups = 0;
  int i;
  for (i = 0; i < trayQtt; i++) {
    scanf("%d %d", &canesPerTray, &cupsPerTray);
    if (canesPerTray > cupsPerTray)
      brokenCups += cupsPerTray;
  }
  printf("%d\n", brokenCups);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r14
  lea    D13(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L35
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  xor    %ebp,%ebp
  lea    D12(%rip),%r12
  xchg   %ax,%ax
L15:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x10(%rsp)
  jle    L36
  add    %eax,%ebp
L36:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L15
L38:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L35:
  xor    %ebp,%ebp
  jmp    L38
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string

tool: D13: %d

tool: D12: %d %d

tool: D5: %d


assistant: ```c
int main() {
  int trayQtt;
  scanf("%d", &trayQtt);
  int canesPerTray, cupsPerTray;
  int brokenCups = 0;
  int i;
  for (i = 0; i < trayQtt; i++) {
    scanf("%d %d", &canesPerTray, &cupsPerTray);
    if (canesPerTray > cupsPerTray)
      brokenCups += cupsPerTray;
  }
  printf("%d\n", brokenCups);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D28(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L3
  xor    %ebx,%ebx
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  xor    %ebp,%ebp
  lea    D14(%rip),%r12
  xchg   %ax,%ax
L46:
  mov    %r14,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  cmp    %eax,0x10(%rsp)
  jle    L49
  add    %eax,%ebp
L49:
  add    $0x1,%ebx
  cmp    %ebx,0xc(%rsp)
  jg     L46
L27:
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L3:
  xor    %ebp,%ebp
  jmp    L27
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D10
type_guessed: string

tool: D28: %d

tool: D14: %d %d

tool: D10: %d


assistant: ```c
int main() {
  int trayQtt;
  scanf("%d", &trayQtt);
  int canesPerTray, cupsPerTray;
  int brokenCups = 0;
  int i;
  for (i = 0; i < trayQtt; i++) {
    scanf("%d %d", &canesPerTray, &cupsPerTray);
    if (canesPerTray > cupsPerTray)
      brokenCups += cupsPerTray;
  }
  printf("%d\n", brokenCups);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L8
L34:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0xf4240,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L12
L1:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L12:
  cmpl   $0x2,-0x14(%rbp)
  jle    L1
  addl   $0x1,-0x18(%rbp)
L8:
  cmpl   $0x6,-0x18(%rbp)
  jle    L34
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D28
datatype: string
name: disassemble_data
arguments: data_label: D21
datatype: string
name: disassemble_data
arguments: data_label: D14
datatype: string

tool: D28: smaxsorted

tool: D21: # c::%s:len=%d


tool: D14: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000;
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "smaxsorted", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```