ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quickSort>:
  endbr64
  cmp    %ecx,%edx
  jl     L2
  ret
L2:
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%ebp
  mov    %ecx,%ebx
  call   <partition@plt>
  mov    %eax,%r14d
  lea    -0x1(%rax),%ecx
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <quickSort>
  lea    0x1(%r14),%edx
  mov    %ebx,%ecx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <quickSort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void quickSort(void **ar, int (*cmp)(const void *, const void *), int left, int right) {
  if (left < right) {
    int p = partition(ar, cmp, left, right);
    quickSort(ar, cmp, left, p - 1);
    quickSort(ar, cmp, p + 1, right);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<normalised_notation_split>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  mov    %rdi,-0x30(%rbp)
  movl   $0x0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L7
  movl   $0x1,-0x14(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movq   D11(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
L7:
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   D11(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    $0xa,%edi
  call   <pow@plt>
  movsd  -0x28(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L20
  movsd  -0x10(%rbp),%xmm0
  movq   D11(%rip),%xmm1
  xorpd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L20:
  cmpq   $0x0,-0x30(%rbp)
  je     L27
  mov    -0x30(%rbp),%rax
  movsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L27:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D11
datatype: f32[2]

tool: {"D11": [0.0,-0.0]}

assistant: ```c
double normalised_notation_split(double number, double *m) {
  int neg = 0;
  double vexp, vm;
  if (number < 0.) {
    neg = 1;
    number = -number;
  }
  vexp = floor(log10(number));
  vm = number * pow(10., -vexp);
  if (neg)
    vm = -vm;
  if (m)
    *m = vm;
  return vexp;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<normalised_notation_split>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movapd %xmm0,%xmm1
  movsd  %xmm0,0x8(%rsp)
  mov    %rdi,%rbp
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L20
  movsd  0x8(%rsp),%xmm0
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm3
  xorpd  D10(%rip),%xmm3
  movapd %xmm3,%xmm0
  mov    $0xa,%edi
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  jmp    L9
L20:
  xorpd  D10(%rip),%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  movq   %xmm0,%rbx
  movapd %xmm0,%xmm2
  xorpd  D10(%rip),%xmm2
  movapd %xmm2,%xmm0
  mov    $0xa,%edi
  call   <pow@plt>
  mulsd  0x8(%rsp),%xmm0
  xorpd  D10(%rip),%xmm0
L9:
  test   %rbp,%rbp
  je     L14
  movsd  %xmm0,0x0(%rbp)
L14:
  movq   %rbx,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D10
type: f32[4]

tool: {"D10": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double normalised_notation_split(double number, double *m) {
  int neg = 0;
  double vexp, vm;
  if (number < 0.) {
    neg = 1;
    number = -number;
  }
  vexp = floor(log10(number));
  vm = number * pow(10., -vexp);
  if (neg)
    vm = -vm;
  if (m)
    *m = vm;
  return vexp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<normalised_notation_split>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  comisd %xmm1,%xmm0
  ja     L0
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    $0xa,%edi
  movsd  %xmm0,(%rsp)
  xorpd  D36(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm1
L13:
  test   %rbx,%rbx
  je     L10
  movsd  %xmm1,(%rbx)
L10:
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  ret
  nopl   0x0(%rax)
L0:
  xorpd  D36(%rip),%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    $0xa,%edi
  movsd  %xmm0,(%rsp)
  xorpd  D36(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm1
  xorpd  D36(%rip),%xmm1
  jmp    L13
```

tool_calls: name: read_data
arguments: data_tag: D36
type_guessed: f32[4]

tool: {"D36": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double normalised_notation_split(double number, double *m) {
  int neg = 0;
  double vexp, vm;
  if (number < 0.) {
    neg = 1;
    number = -number;
  }
  vexp = floor(log10(number));
  vm = number * pow(10., -vexp);
  if (neg)
    vm = -vm;
  if (m)
    *m = vm;
  return vexp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<normalised_notation_split>:
  endbr64
  push   %rbx
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  mov    %rdi,%rbx
  sub    $0x10,%rsp
  comisd %xmm1,%xmm0
  ja     L19
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    $0xa,%edi
  movsd  %xmm0,(%rsp)
  xorpd  D23(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm1
L14:
  test   %rbx,%rbx
  je     L4
  movsd  %xmm1,(%rbx)
L4:
  add    $0x10,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  ret
  nopl   0x0(%rax)
L19:
  xorpd  D23(%rip),%xmm1
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x8(%rsp)
  call   <log10@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    $0xa,%edi
  movsd  %xmm0,(%rsp)
  xorpd  D23(%rip),%xmm0
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm1
  movsd  (%rsp),%xmm2
  mulsd  %xmm0,%xmm1
  xorpd  D23(%rip),%xmm1
  jmp    L14
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
type_infered: f32[4]

tool: {"D23": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double normalised_notation_split(double number, double *m) {
  int neg = 0;
  double vexp, vm;
  if (number < 0.) {
    neg = 1;
    number = -number;
  }
  vexp = floor(log10(number));
  vm = number * pow(10., -vexp);
  if (neg)
    vm = -vm;
  if (m)
    *m = vm;
  return vexp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_data>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L26
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L30
L26:
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  jne    L5
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L30
L5:
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L30:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D38
type: string
name: read_data
arguments: data_tag: D4
type: string
name: read_data
arguments: data_tag: D66
type: string
name: read_data
arguments: data_tag: D57
type: string
name: read_data
arguments: data_tag: D43
type: string
name: read_data
arguments: data_tag: D18
type: string

tool: D38: The year: 

tool: D4: %d

tool: D66: The year is not an number aborting

tool: D57: The day: 

tool: D43: The day is not an number aborting

tool: D18: 


assistant: ```c
int read_data(int *year, int *day) {
  printf("The year: ");
  if (scanf("%d", year) == 0) {
    printf("The year is not an number aborting");
    return 0;
  }
  printf("The day: ");
  if (scanf("%d", day) == 0) {
    printf("The day is not an number aborting");
    return 0;
  }
  printf("\n");
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_data>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D45(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L38
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D53(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L11
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  lea    D59(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
L11:
  lea    D35(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
```

tool_calls: name: parse_data
arguments: tag: D45
type_guessed: string
name: parse_data
arguments: tag: D53
type_guessed: string
name: parse_data
arguments: tag: D28
type_guessed: string
name: parse_data
arguments: tag: D64
type_guessed: string
name: parse_data
arguments: tag: D59
type_guessed: string
name: parse_data
arguments: tag: D35
type_guessed: string

tool: D45: The year: 

tool: D53: %d

tool: D28: The day: 

tool: D64: 


tool: D59: The year is not an number aborting

tool: D35: The day is not an number aborting

assistant: ```c
int read_data(int *year, int *day) {
  printf("The year: ");
  if (scanf("%d", year) == 0) {
    printf("The year is not an number aborting");
    return 0;
  }
  printf("The day: ");
  if (scanf("%d", day) == 0) {
    printf("The day is not an number aborting");
    return 0;
  }
  printf("\n");
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_data>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D53(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L10
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L7
  lea    D36(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  lea    D32(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D53
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D14
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D32
type_guessed: string
name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D53: The year: 

tool: D15: %d

tool: D14: The day: 

tool: D36: 


tool: D32: The day is not an number aborting

tool: D6: The year is not an number aborting

assistant: ```c
int read_data(int *year, int *day) {
  printf("The year: ");
  if (scanf("%d", year) == 0) {
    printf("The year is not an number aborting");
    return 0;
  }
  printf("The day: ");
  if (scanf("%d", day) == 0) {
    printf("The day is not an number aborting");
    return 0;
  }
  printf("\n");
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_data>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D43(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D36(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L7
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L0
  lea    D54(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L0:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L7:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D43
type_infered: string
name: read_data
arguments: data_tag: D36
type_infered: string
name: read_data
arguments: data_tag: D5
type_infered: string
name: read_data
arguments: data_tag: D54
type_infered: string
name: read_data
arguments: data_tag: D20
type_infered: string
name: read_data
arguments: data_tag: D50
type_infered: string

tool: D43: The year: 

tool: D36: %d

tool: D5: The day: 

tool: D54: 


tool: D20: The day is not an number aborting

tool: D50: The year is not an number aborting

assistant: ```c
int read_data(int *year, int *day) {
  printf("The year: ");
  if (scanf("%d", year) == 0) {
    printf("The year is not an number aborting");
    return 0;
  }
  printf("The day: ");
  if (scanf("%d", day) == 0) {
    printf("The day is not an number aborting");
    return 0;
  }
  printf("\n");
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int y = n << 3;
  return ((x & (255 << y)) >> y) & 255;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getByte>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  mov    $0xff,%edx
  shl    %cl,%edx
  and    %edi,%edx
  sar    %cl,%edx
  movzbl %dl,%eax
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int y = n << 3;
  return ((x & (255 << y)) >> y) & 255;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getByte>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  mov    $0xff,%edx
  shl    %cl,%edx
  and    %edi,%edx
  sar    %cl,%edx
  movzbl %dl,%eax
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int y = n << 3;
  return ((x & (255 << y)) >> y) & 255;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getByte>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  mov    $0xff,%edx
  shl    %cl,%edx
  and    %edi,%edx
  sar    %cl,%edx
  movzbl %dl,%eax
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int y = n << 3;
  return ((x & (255 << y)) >> y) & 255;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<plainstring_new_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <plainstring_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    -0x8(%rbp),%rax
  jmp    L8
L16:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <plainstring_set_int@plt>
  mov    -0x8(%rbp),%rax
L8:
  leave
  ret
```

assistant: ```c
struct plainstring *plainstring_new_int(int i) {
  struct plainstring *str = plainstring_new();
  if (!str)
    return str;
  plainstring_set_int(str, i);
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<plainstring_new_int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%eax
  call   <plainstring_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L9
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <plainstring_set_int@plt>
L9:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct plainstring *plainstring_new_int(int i) {
  struct plainstring *str = plainstring_new();
  if (!str)
    return str;
  plainstring_set_int(str, i);
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<plainstring_new_int>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <plainstring_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <plainstring_set_int@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct plainstring *plainstring_new_int(int i) {
  struct plainstring *str = plainstring_new();
  if (!str)
    return str;
  plainstring_set_int(str, i);
  return str;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<plainstring_new_int>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <plainstring_new@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %ebp,%esi
  mov    %rax,%rdi
  call   <plainstring_set_int@plt>
L9:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct plainstring *plainstring_new_int(int i) {
  struct plainstring *str = plainstring_new();
  if (!str)
    return str;
  plainstring_set_int(str, i);
  return str;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strcaseeq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L93
L16:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L7
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L68
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    -0x20(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,%edx
  je     L91
L68:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L0
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    0x20(%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,%edx
  je     L87
L0:
  mov    $0x0,%eax
  jmp    L74
L7:
  nop
  jmp    L32
L91:
  nop
  jmp    L32
L87:
  nop
L32:
  addl   $0x1,-0x4(%rbp)
L93:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
L74:
  leave
  ret
```

assistant: ```c
bool strcaseeq(const char *str1, const char *str2) {
  int i;
  for (i = 0; str1[i] != '\0'; i++) {
    if (str1[i] == str2[i])
      continue;
    else if (islower(str1[i]) && (str1[i] - 32) == str2[i])
      continue;
    else if (isupper(str1[i]) && (str1[i] + 32) == str2[i])
      continue;
    return false;
  }
  return str2[i] == '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcaseeq>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r12
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L59
  mov    $0x0,%ebx
  jmp    L38
L36:
  add    $0x1,%rbx
  movzbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  je     L96
L38:
  cmp    %dil,(%r12,%rbx,1)
  je     L36
  movsbl %dil,%edi
  call   <islower@plt>
  test   %rax,%rax
  je     L7
  movsbl 0x0(%rbp,%rbx,1),%eax
  sub    $0x20,%eax
  movsbl (%r12,%rbx,1),%edx
  cmp    %edx,%eax
  je     L36
L7:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L22
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x20,%eax
  movsbl (%r12,%rbx,1),%edx
  cmp    %edx,%eax
  je     L36
  mov    $0x0,%eax
L73:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  mov    $0x0,%ebx
L96:
  cmpb   $0x0,(%r12,%rbx,1)
  sete   %al
  movzbl %al,%eax
  jmp    L73
L22:
  mov    $0x0,%eax
  jmp    L73
```

assistant: ```c
bool strcaseeq(const char *str1, const char *str2) {
  int i;
  for (i = 0; str1[i] != '\0'; i++) {
    if (str1[i] == str2[i])
      continue;
    else if (islower(str1[i]) && (str1[i] - 32) == str2[i])
      continue;
    else if (isupper(str1[i]) && (str1[i] + 32) == str2[i])
      continue;
    return false;
  }
  return str2[i] == '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcaseeq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L75
  xor    %ebx,%ebx
L67:
  cmp    %dil,(%r12,%rbx,1)
  je     L18
  call   <islower@plt>
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %rax,%rax
  je     L40
  movsbl (%r12,%rbx,1),%eax
  lea    -0x20(%rdi),%edx
  cmp    %eax,%edx
  je     L18
L40:
  call   <isupper@plt>
  test   %rax,%rax
  je     L62
  movsbl 0x0(%rbp,%rbx,1),%eax
  movsbl (%r12,%rbx,1),%edx
  add    $0x20,%eax
  cmp    %edx,%eax
  je     L18
L62:
  xor    %eax,%eax
L45:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L67
  add    %rbx,%r12
L75:
  xor    %eax,%eax
  cmpb   $0x0,(%r12)
  sete   %al
  jmp    L45
```

assistant: ```c
bool strcaseeq(const char *str1, const char *str2) {
  int i;
  for (i = 0; str1[i] != '\0'; i++) {
    if (str1[i] == str2[i])
      continue;
    else if (islower(str1[i]) && (str1[i] - 32) == str2[i])
      continue;
    else if (isupper(str1[i]) && (str1[i] + 32) == str2[i])
      continue;
    return false;
  }
  return str2[i] == '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcaseeq>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L58
  xor    %ebx,%ebx
L74:
  cmp    %dil,(%r12,%rbx,1)
  je     L62
  call   <islower@plt>
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %rax,%rax
  je     L30
  movsbl (%r12,%rbx,1),%eax
  lea    -0x20(%rdi),%edx
  cmp    %eax,%edx
  je     L62
L30:
  call   <isupper@plt>
  test   %rax,%rax
  je     L71
  movsbl 0x0(%rbp,%rbx,1),%eax
  movsbl (%r12,%rbx,1),%edx
  add    $0x20,%eax
  cmp    %edx,%eax
  je     L62
L71:
  xor    %eax,%eax
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L62:
  add    $0x1,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L74
  add    %rbx,%r12
L58:
  xor    %eax,%eax
  cmpb   $0x0,(%r12)
  sete   %al
  jmp    L70
```

assistant: ```c
bool strcaseeq(const char *str1, const char *str2) {
  int i;
  for (i = 0; str1[i] != '\0'; i++) {
    if (str1[i] == str2[i])
      continue;
    else if (islower(str1[i]) && (str1[i] - 32) == str2[i])
      continue;
    else if (isupper(str1[i]) && (str1[i] + 32) == str2[i])
      continue;
    return false;
  }
  return str2[i] == '\0';
}
```