ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<xrop3_25_1_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  and    %esi,%eax
  or     %esi,%edi
  not    %eax
  movzbl %al,%eax
  or     %edi,%eax
  movzbl %dil,%edi
  not    %eax
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_25_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T & S;
  stk3 = ~stk3;
  stk2 = D & stk3;
  stk1 = S ^ stk2;
  stk1 = ~stk1;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rop3_19_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x20(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  or     -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  notb   -0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  and    -0x1c(%rbp),%al
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  not    %eax
  mov    %eax,%edx
  movzbl -0x1(%rbp),%eax
  and    %edx,%eax
  or     %eax,%ecx
  mov    %ecx,%edx
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %eax,%ecx
  movzbl -0x20(%rbp),%eax
  and    %eax,%ecx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    %ecx,%eax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_19_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: What is the c source code of the assembly code below:

```asm
<rop3_19_0_1>:
  endbr64
  mov    %edx,%eax
  and    (%rdi),%al
  or     %esi,%eax
  or     %edx,%eax
  not    %eax
  not    %esi
  and    %edx,%esi
  and    (%rdi),%sil
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_19_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_19_0_1>:
  endbr64
  movzbl (%rdi),%eax
  and    %edx,%eax
  or     %esi,%eax
  not    %esi
  or     %edx,%eax
  and    %edx,%esi
  and    (%rdi),%sil
  not    %eax
  or     %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_19_0_1(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = *D & T;
  stk1 = S | stk2;
  stk1 = ~stk1;
  *D = (stk1 & S) | (stk1 & (~T)) | (T & (~S) & *D);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sort_by_freeqence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L1
L35:
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L45:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    0x4(%rax),%eax
  cmp    %eax,%edx
  jge    L24
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    0x4(%rax),%eax
  mov    %eax,0x4(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,0x4(%rdx)
L24:
  addl   $0x1,-0xc(%rbp)
L23:
  cmpl   $0x18,-0xc(%rbp)
  jle    L45
  addl   $0x1,-0x10(%rbp)
L1:
  cmpl   $0x19,-0x10(%rbp)
  jle    L35
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sort_by_freeqence(int diagram[26][2]) {
  int counter;
  for (counter = 0; counter < 26; counter++) {
    int i;
    for (i = 0; i < 26 - 1; i++) {
      if (diagram[i][1] < diagram[i + 1][1]) {
        int distribution;
        int ascii;
        ascii = diagram[i][0];
        distribution = diagram[i][1];
        diagram[i][0] = diagram[i + 1][0];
        diagram[i][1] = diagram[i + 1][1];
        diagram[i + 1][0] = ascii;
        diagram[i + 1][1] = distribution;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sort_by_freeqence>:
  endbr64
  mov    %rdi,%r10
  mov    $0x1a,%r9d
  lea    0xc8(%rdi),%rsi
  jmp    L9
L35:
  add    $0x8,%rax
  cmp    %rsi,%rax
  je     L26
L16:
  mov    0x4(%rax),%edx
  mov    0xc(%rax),%ecx
  cmp    %ecx,%edx
  jge    L35
  mov    (%rax),%edi
  mov    0x8(%rax),%r8d
  mov    %r8d,(%rax)
  mov    %ecx,0x4(%rax)
  mov    %edi,0x8(%rax)
  mov    %edx,0xc(%rax)
  jmp    L35
L26:
  sub    $0x1,%r9d
  je     L24
L9:
  mov    %r10,%rax
  jmp    L16
L24:
  ret
```

assistant: ```c
void sort_by_freeqence(int diagram[26][2]) {
  int counter;
  for (counter = 0; counter < 26; counter++) {
    int i;
    for (i = 0; i < 26 - 1; i++) {
      if (diagram[i][1] < diagram[i + 1][1]) {
        int distribution;
        int ascii;
        ascii = diagram[i][0];
        distribution = diagram[i][1];
        diagram[i][0] = diagram[i + 1][0];
        diagram[i][1] = diagram[i + 1][1];
        diagram[i + 1][0] = ascii;
        diagram[i + 1][1] = distribution;
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sort_by_freeqence>:
  endbr64
  mov    %rdi,%r10
  mov    $0x1a,%r9d
  lea    0xc8(%rdi),%rsi
  nopl   0x0(%rax)
L20:
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L0:
  mov    0x4(%rax),%edx
  mov    0xc(%rax),%ecx
  cmp    %ecx,%edx
  jge    L5
  mov    (%rax),%edi
  mov    0x8(%rax),%r8d
  mov    %ecx,0x4(%rax)
  mov    %edx,0xc(%rax)
  mov    %r8d,(%rax)
  mov    %edi,0x8(%rax)
L5:
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L0
  sub    $0x1,%r9d
  jne    L20
  ret
```

assistant: ```c
void sort_by_freeqence(int diagram[26][2]) {
  int counter;
  for (counter = 0; counter < 26; counter++) {
    int i;
    for (i = 0; i < 26 - 1; i++) {
      if (diagram[i][1] < diagram[i + 1][1]) {
        int distribution;
        int ascii;
        ascii = diagram[i][0];
        distribution = diagram[i][1];
        diagram[i][0] = diagram[i + 1][0];
        diagram[i][1] = diagram[i + 1][1];
        diagram[i + 1][0] = ascii;
        diagram[i + 1][1] = distribution;
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sort_by_freeqence>:
  endbr64
  mov    %rdi,%r10
  mov    $0x1a,%r9d
  lea    0xc8(%rdi),%rsi
  nopl   0x0(%rax)
L23:
  mov    %r10,%rax
  nopl   0x0(%rax,%rax,1)
L9:
  mov    0x4(%rax),%edx
  mov    0xc(%rax),%ecx
  cmp    %ecx,%edx
  jge    L2
  mov    (%rax),%edi
  mov    0x8(%rax),%r8d
  mov    %ecx,0x4(%rax)
  mov    %edx,0xc(%rax)
  mov    %r8d,(%rax)
  mov    %edi,0x8(%rax)
L2:
  add    $0x8,%rax
  cmp    %rsi,%rax
  jne    L9
  sub    $0x1,%r9d
  jne    L23
  ret
```

assistant: ```c
void sort_by_freeqence(int diagram[26][2]) {
  int counter;
  for (counter = 0; counter < 26; counter++) {
    int i;
    for (i = 0; i < 26 - 1; i++) {
      if (diagram[i][1] < diagram[i + 1][1]) {
        int distribution;
        int ascii;
        ascii = diagram[i][0];
        distribution = diagram[i][1];
        diagram[i][0] = diagram[i + 1][0];
        diagram[i][1] = diagram[i + 1][1];
        diagram[i + 1][0] = ascii;
        diagram[i + 1][1] = distribution;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_dobldobl_target_Laurent_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2fd,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_dobldobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(765, a, b, c, 0);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_dobldobl_target_Laurent_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x2fd,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_dobldobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(765, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_dobldobl_target_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2fd,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int read_dobldobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(765, a, b, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<read_dobldobl_target_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2fd,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int read_dobldobl_target_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(765, a, b, c, 0);
  return fail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtol>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L100
L154:
  addq   $0x1,-0x28(%rbp)
L100:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L154
  cmpl   $0x0,-0x34(%rbp)
  jne    L120
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L42
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x78,%al
  je     L214
  mov    -0x28(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  jne    L61
L214:
  movl   $0x10,-0x34(%rbp)
  jmp    L120
L61:
  movl   $0x8,-0x34(%rbp)
  jmp    L120
L42:
  movl   $0xa,-0x34(%rbp)
L120:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2b,%al
  jne    L192
  addq   $0x1,-0x28(%rbp)
  jmp    L118
L192:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L118
  movl   $0xffffffff,-0x14(%rbp)
  addq   $0x1,-0x28(%rbp)
  jmp    L118
L156:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    %al,-0x15(%rbp)
  movsbl -0x15(%rbp),%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L199
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  cltq
  mov    %rax,-0x8(%rbp)
  jmp    L97
L199:
  cmpb   $0x60,-0x15(%rbp)
  jg     L101
  cmpb   $0x66,-0x15(%rbp)
  jg     L97
L101:
  movsbl -0x15(%rbp),%eax
  sub    $0x57,%eax
  cltq
  mov    %rax,-0x8(%rbp)
L97:
  mov    -0x34(%rbp),%eax
  cltq
  cmp    %rax,-0x8(%rbp)
  jge    L163
  mov    -0x34(%rbp),%eax
  cltq
  imul   -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  addq   $0x1,-0x28(%rbp)
L118:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L156
  jmp    L79
L163:
  nop
L79:
  cmpq   $0x0,-0x30(%rbp)
  je     L32
  mov    -0x30(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rdx,(%rax)
L32:
  cmpl   $0x0,-0x14(%rbp)
  jg     L119
  mov    -0x10(%rbp),%rax
  neg    %rax
  jmp    L91
L119:
  mov    -0x10(%rbp),%rax
L91:
  leave
  ret
```

assistant: ```c
long strtol(const char *str, char **endp, int base) {
  long acc = 0;
  int sign = 1;
  while (isspace(*str))
    str++;
  if (base == 0) {
    if (str[0] == '0') {
      if (str[1] == 'x' || str[1] == 'X') {
        base = 16;
      } else {
        base = 8;
      }
    } else {
      base = 10;
    }
  }
  if (*str == '+') {
    str++;
  } else if (*str == '-') {
    sign = -1;
    str++;
  }
  while (*str) {
    long val;
    char c = tolower(*str);
    if (isdigit(c)) {
      val = *str - '0';
    } else if (c >= 'a' || c <= 'f') {
      val = 10 + c - 'a';
    }
    if (val >= base) {
      break;
    }
    acc = acc * base + val;
    str++;
  }
  if (endp) {
    *endp = (char *)str;
  }
  return sign > 0 ? acc : -acc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strtol>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %edx,%r12d
  jmp    L49
L130:
  add    $0x1,%rbp
L49:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L130
  test   %r12d,%r12d
  jne    L51
  mov    $0xa,%r12d
  cmpb   $0x30,0x0(%rbp)
  je     L29
L51:
  movzbl 0x0(%rbp),%eax
  cmp    $0x2b,%al
  je     L96
  mov    $0x1,%r14d
  cmp    $0x2d,%al
  jne    L105
  add    $0x1,%rbp
  mov    $0xffffffff,%r14d
  jmp    L105
L29:
  movzbl 0x1(%rbp),%eax
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %r12b
  movzbl %r12b,%r12d
  lea    0x8(,%r12,8),%r12d
  movzbl 0x0(%rbp),%edi
  mov    $0x1,%r14d
  jmp    L17
L96:
  add    $0x1,%rbp
  mov    $0x1,%r14d
L105:
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L113
L17:
  movslq %r12d,%r12
  jmp    L98
L12:
  lea    -0x57(%r15),%eax
  cltq
L144:
  cmp    %rax,%r12
  jle    L113
  imul   %r12,%rbx
  add    %rax,%rbx
  add    $0x1,%rbp
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L113
L98:
  movsbl %dil,%edi
  call   <tolower@plt>
  movsbl %al,%r15d
  mov    %r15d,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L12
  movsbl 0x0(%rbp),%eax
  sub    $0x30,%eax
  cltq
  jmp    L144
L113:
  test   %r13,%r13
  je     L35
  mov    %rbp,0x0(%r13)
L35:
  mov    %rbx,%rax
  neg    %rax
  test   %r14d,%r14d
  cmovle %rax,%rbx
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
long strtol(const char *str, char **endp, int base) {
  long acc = 0;
  int sign = 1;
  while (isspace(*str))
    str++;
  if (base == 0) {
    if (str[0] == '0') {
      if (str[1] == 'x' || str[1] == 'X') {
        base = 16;
      } else {
        base = 8;
      }
    } else {
      base = 10;
    }
  }
  if (*str == '+') {
    str++;
  } else if (*str == '-') {
    sign = -1;
    str++;
  }
  while (*str) {
    long val;
    char c = tolower(*str);
    if (isdigit(c)) {
      val = *str - '0';
    } else if (c >= 'a' || c <= 'f') {
      val = 10 + c - 'a';
    }
    if (val >= base) {
      break;
    }
    acc = acc * base + val;
    str++;
  }
  if (endp) {
    *endp = (char *)str;
  }
  return sign > 0 ? acc : -acc;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strtol>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L116
  nopl   0x0(%rax)
L145:
  add    $0x1,%r15
L116:
  movsbl (%r15),%edi
  call   <isspace@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L145
  movsbl (%r15),%edi
  test   %ebp,%ebp
  jne    L130
  mov    $0xa,%ebp
  cmp    $0x30,%dil
  je     L141
L130:
  cmp    $0x2b,%dil
  je     L71
  mov    $0x1,%r13d
  cmp    $0x2d,%dil
  jne    L5
  movsbl 0x1(%r15),%edi
  mov    $0xffffffff,%r13d
  add    $0x1,%r15
L5:
  test   %dil,%dil
  je     L117
L80:
  movslq %ebp,%rbp
  jmp    L119
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl (%r15),%eax
  sub    $0x30,%eax
  cltq
  cmp    %rbp,%rax
  jge    L117
L32:
  imul   %rbp,%r14
  movsbl 0x1(%r15),%edi
  add    $0x1,%r15
  add    %rax,%r14
  test   %dil,%dil
  je     L117
L119:
  call   <tolower@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L4
  lea    -0x57(%rbx),%eax
  cltq
  cmp    %rbp,%rax
  jl     L32
L117:
  test   %r12,%r12
  je     L43
  mov    %r15,(%r12)
L43:
  mov    %r14,%rax
  neg    %rax
  cmp    $0x1,%r13d
  cmovne %rax,%r14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L71:
  movsbl 0x1(%r15),%edi
  mov    $0x1,%r13d
  add    $0x1,%r15
  jmp    L5
  nopl   0x0(%rax)
L141:
  movzbl 0x1(%r15),%eax
  xor    %ebp,%ebp
  mov    $0x1,%r13d
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %bpl
  lea    0x8(,%rbp,8),%ebp
  jmp    L80
```

assistant: ```c
long strtol(const char *str, char **endp, int base) {
  long acc = 0;
  int sign = 1;
  while (isspace(*str))
    str++;
  if (base == 0) {
    if (str[0] == '0') {
      if (str[1] == 'x' || str[1] == 'X') {
        base = 16;
      } else {
        base = 8;
      }
    } else {
      base = 10;
    }
  }
  if (*str == '+') {
    str++;
  } else if (*str == '-') {
    sign = -1;
    str++;
  }
  while (*str) {
    long val;
    char c = tolower(*str);
    if (isdigit(c)) {
      val = *str - '0';
    } else if (c >= 'a' || c <= 'f') {
      val = 10 + c - 'a';
    }
    if (val >= base) {
      break;
    }
    acc = acc * base + val;
    str++;
  }
  if (endp) {
    *endp = (char *)str;
  }
  return sign > 0 ? acc : -acc;
}
```
user: What is the c source code of the assembly code below?

```asm
<strtol>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L148
  nopl   0x0(%rax)
L100:
  add    $0x1,%r15
L148:
  movsbl (%r15),%edi
  call   <isspace@plt>
  mov    %rax,%r14
  test   %rax,%rax
  jne    L100
  movsbl (%r15),%edi
  test   %ebp,%ebp
  jne    L137
  mov    $0xa,%ebp
  cmp    $0x30,%dil
  je     L107
L137:
  cmp    $0x2b,%dil
  je     L75
  mov    $0x1,%r13d
  cmp    $0x2d,%dil
  jne    L78
  movsbl 0x1(%r15),%edi
  mov    $0xffffffff,%r13d
  add    $0x1,%r15
L78:
  test   %dil,%dil
  je     L126
L91:
  movslq %ebp,%rbp
  jmp    L122
  nopl   0x0(%rax,%rax,1)
L26:
  movsbl (%r15),%eax
  sub    $0x30,%eax
  cltq
  cmp    %rbp,%rax
  jge    L126
L149:
  imul   %rbp,%r14
  movsbl 0x1(%r15),%edi
  add    $0x1,%r15
  add    %rax,%r14
  test   %dil,%dil
  je     L126
L122:
  call   <tolower@plt>
  movsbl %al,%ebx
  mov    %ebx,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  jne    L26
  lea    -0x57(%rbx),%eax
  cltq
  cmp    %rbp,%rax
  jl     L149
L126:
  test   %r12,%r12
  je     L135
  mov    %r15,(%r12)
L135:
  mov    %r14,%rax
  neg    %rax
  cmp    $0x1,%r13d
  cmovne %rax,%r14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L75:
  movsbl 0x1(%r15),%edi
  mov    $0x1,%r13d
  add    $0x1,%r15
  jmp    L78
  nopl   0x0(%rax)
L107:
  movzbl 0x1(%r15),%eax
  xor    %ebp,%ebp
  mov    $0x1,%r13d
  and    $0xffffffdf,%eax
  cmp    $0x58,%al
  sete   %bpl
  lea    0x8(,%rbp,8),%ebp
  jmp    L91
```

assistant: ```c
long strtol(const char *str, char **endp, int base) {
  long acc = 0;
  int sign = 1;
  while (isspace(*str))
    str++;
  if (base == 0) {
    if (str[0] == '0') {
      if (str[1] == 'x' || str[1] == 'X') {
        base = 16;
      } else {
        base = 8;
      }
    } else {
      base = 10;
    }
  }
  if (*str == '+') {
    str++;
  } else if (*str == '-') {
    sign = -1;
    str++;
  }
  while (*str) {
    long val;
    char c = tolower(*str);
    if (isdigit(c)) {
      val = *str - '0';
    } else if (c >= 'a' || c <= 'f') {
      val = 10 + c - 'a';
    }
    if (val >= base) {
      break;
    }
    acc = acc * base + val;
    str++;
  }
  if (endp) {
    *endp = (char *)str;
  }
  return sign > 0 ? acc : -acc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<COM_GetExtension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L4
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L20
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L4
L20:
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  jmp    L17
L4:
  lea    D9(%rip),%rax
L17:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
data_type: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  const char *dot = strrchr(name, '.'), *slash;
  if (dot && (!(slash = strrchr(name, '/')) || slash < dot))
    return dot + 1;
  else
    return "";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<COM_GetExtension>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x2e,%esi
  call   <strrchr@plt>
  lea    D5(%rip),%rdx
  test   %rax,%rax
  je     L8
  mov    %rax,%rbx
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strrchr@plt>
  cmp    %rax,%rbx
  ja     L13
  lea    D5(%rip),%rdx
  test   %rax,%rax
  jne    L8
L13:
  lea    0x1(%rbx),%rdx
L8:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  const char *dot = strrchr(name, '.'), *slash;
  if (dot && (!(slash = strrchr(name, '/')) || slash < dot))
    return dot + 1;
  else
    return "";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<COM_GetExtension>:
  endbr64
  push   %rbp
  mov    $0x2e,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L29
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  cmp    %rax,%rbx
  ja     L19
  test   %rax,%rax
  jne    L29
L19:
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L29:
  add    $0x8,%rsp
  lea    D0(%rip),%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  const char *dot = strrchr(name, '.'), *slash;
  if (dot && (!(slash = strrchr(name, '/')) || slash < dot))
    return dot + 1;
  else
    return "";
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<COM_GetExtension>:
  endbr64
  push   %rbp
  mov    $0x2e,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L23
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strrchr@plt>
  cmp    %rax,%rbx
  ja     L11
  test   %rax,%rax
  jne    L23
L11:
  add    $0x8,%rsp
  lea    0x1(%rbx),%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L23:
  add    $0x8,%rsp
  lea    D1(%rip),%rax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
type_infered: string

tool: 

assistant: ```c
const char *COM_GetExtension(const char *name) {
  const char *dot = strrchr(name, '.'), *slash;
  if (dot && (!(slash = strrchr(name, '/')) || slash < dot))
    return dot + 1;
  else
    return "";
}
```