ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<do_query>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <mb_query_total@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L59
L27:
  mov    $0x0,%eax
  call   <mb_query_server@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L19
L48:
  mov    $0x0,%eax
  call   <mb_query@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  js     L20
L3:
  mov    %r12d,%edi
  call   <pages_to_megabytes@plt>
  mov    %r12d,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <pages_to_megabytes@plt>
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%edi
  call   <pages_to_megabytes@plt>
  mov    %ebx,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L59:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  mov    %eax,%esi
  lea    D59(%rip),%rdi
  call   <error@plt>
  jmp    L27
L19:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  mov    %eax,%esi
  lea    D38(%rip),%rdi
  call   <error@plt>
  jmp    L48
L20:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  mov    %eax,%esi
  lea    D20(%rip),%rdi
  call   <error@plt>
  jmp    L3
```

tool_calls: name: parse_data
arguments: data_label: D25
type_infered: string
name: parse_data
arguments: data_label: D22
type_infered: string
name: parse_data
arguments: data_label: D33
type_infered: string
name: parse_data
arguments: data_label: D59
type_infered: string
name: parse_data
arguments: data_label: D38
type_infered: string
name: parse_data
arguments: data_label: D20
type_infered: string

tool: D25: total   %9d p (%.1f M)


tool: D22: server  %9d p (%.1f M)


tool: D33: client  %9d p (%.1f M)


tool: D59: mb_query_total() said %s


tool: D38: mb_query_server() said %s


tool: D20: mb_query() said %s


assistant: ```c
void do_query(void) {
  int total;
  int server;
  int client;
  total = mb_query_total();
  if (total < 0) {
    error("mb_query_total() said %s\n", mb_error_to_string(total));
    ;
  }
  server = mb_query_server();
  if (server < 0) {
    error("mb_query_server() said %s\n", mb_error_to_string(server));
  }
  client = mb_query();
  if (client < 0) {
    error("mb_query() said %s\n", mb_error_to_string(client));
  }
  printf("total   %9d p (%.1f M)\n", total, pages_to_megabytes(total));
  printf("server  %9d p (%.1f M)\n", server, pages_to_megabytes(server));
  printf("client  %9d p (%.1f M)\n", client, pages_to_megabytes(client));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_query>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <mb_query_total@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  js     L9
  xor    %eax,%eax
  call   <mb_query_server@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L7
L43:
  xor    %eax,%eax
  call   <mb_query@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L38
L13:
  mov    %r13d,%edi
  call   <pages_to_megabytes@plt>
  mov    %r13d,%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <pages_to_megabytes@plt>
  mov    %r12d,%esi
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <pages_to_megabytes@plt>
  mov    %ebp,%esi
  lea    D18(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <printf@plt>
  xchg   %ax,%ax
L9:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  call   <error@plt>
  xor    %eax,%eax
  call   <mb_query_server@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L43
L7:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <error@plt>
  xor    %eax,%eax
  call   <mb_query@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jns    L13
L38:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  lea    D41(%rip),%rdi
  mov    %eax,%esi
  call   <error@plt>
  jmp    L13
```

tool_calls: name: read_data
arguments: data_label: D21
type_infered: string
name: read_data
arguments: data_label: D37
type_infered: string
name: read_data
arguments: data_label: D18
type_infered: string
name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D15
type_infered: string
name: read_data
arguments: data_label: D41
type_infered: string

tool: D21: total   %9d p (%.1f M)


tool: D37: server  %9d p (%.1f M)


tool: D18: client  %9d p (%.1f M)


tool: D5: mb_query_total() said %s


tool: D15: mb_query_server() said %s


tool: D41: mb_query() said %s


assistant: ```c
void do_query(void) {
  int total;
  int server;
  int client;
  total = mb_query_total();
  if (total < 0) {
    error("mb_query_total() said %s\n", mb_error_to_string(total));
    ;
  }
  server = mb_query_server();
  if (server < 0) {
    error("mb_query_server() said %s\n", mb_error_to_string(server));
  }
  client = mb_query();
  if (client < 0) {
    error("mb_query() said %s\n", mb_error_to_string(client));
  }
  printf("total   %9d p (%.1f M)\n", total, pages_to_megabytes(total));
  printf("server  %9d p (%.1f M)\n", server, pages_to_megabytes(server));
  printf("client  %9d p (%.1f M)\n", client, pages_to_megabytes(client));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_query>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  push   %rbp
  call   <mb_query_total@plt>
  mov    %eax,%r13d
  test   %eax,%eax
  js     L34
  xor    %eax,%eax
  call   <mb_query_server@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  js     L15
L32:
  xor    %eax,%eax
  call   <mb_query@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  js     L33
L27:
  mov    %r13d,%edi
  call   <pages_to_megabytes@plt>
  mov    %r13d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%edi
  call   <pages_to_megabytes@plt>
  mov    %r12d,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  call   <pages_to_megabytes@plt>
  mov    %ebp,%esi
  lea    D59(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10b0 <printf@plt>
  xchg   %ax,%ax
L34:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  lea    D22(%rip),%rdi
  mov    %eax,%esi
  call   <error@plt>
  xor    %eax,%eax
  call   <mb_query_server@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jns    L32
L15:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  lea    D16(%rip),%rdi
  mov    %eax,%esi
  call   <error@plt>
  xor    %eax,%eax
  call   <mb_query@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  jns    L27
L33:
  mov    %eax,%edi
  call   <mb_error_to_string@plt>
  lea    D48(%rip),%rdi
  mov    %eax,%esi
  call   <error@plt>
  jmp    L27
```

tool_calls: name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D7
data_type: string
name: retrieve_data
arguments: tag: D59
data_type: string
name: retrieve_data
arguments: tag: D22
data_type: string
name: retrieve_data
arguments: tag: D16
data_type: string
name: retrieve_data
arguments: tag: D48
data_type: string

tool: D1: total   %9d p (%.1f M)


tool: D7: server  %9d p (%.1f M)


tool: D59: client  %9d p (%.1f M)


tool: D22: mb_query_total() said %s


tool: D16: mb_query_server() said %s


tool: D48: mb_query() said %s


assistant: ```c
void do_query(void) {
  int total;
  int server;
  int client;
  total = mb_query_total();
  if (total < 0) {
    error("mb_query_total() said %s\n", mb_error_to_string(total));
    ;
  }
  server = mb_query_server();
  if (server < 0) {
    error("mb_query_server() said %s\n", mb_error_to_string(server));
  }
  client = mb_query();
  if (client < 0) {
    error("mb_query() said %s\n", mb_error_to_string(client));
  }
  printf("total   %9d p (%.1f M)\n", total, pages_to_megabytes(total));
  printf("server  %9d p (%.1f M)\n", server, pages_to_megabytes(server));
  printf("client  %9d p (%.1f M)\n", client, pages_to_megabytes(client));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ClrGyr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,%edx
  mov    %ax,-0x14(%rbp)
  mov    %edx,%eax
  mov    %al,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x0,-0x9(%rbp)
  movzwl -0x14(%rbp),%eax
  shr    $0x8,%ax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x18f,%edi
  call   <RegWriteA@plt>
  movzwl -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  mov    $0x18e,%edi
  call   <RegWriteA@plt>
  movzbl -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0x102,%edi
  call   <RegWriteA@plt>
L20:
  lea    -0xa(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x102,%edi
  call   <RegReadA@plt>
  movzbl -0xa(%rbp),%eax
  and    -0x18(%rbp),%al
  mov    %al,-0xa(%rbp)
  movzbl -0x9(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %dl,-0x9(%rbp)
  cmp    $0x63,%al
  ja     L3
  movzbl -0xa(%rbp),%eax
  test   %al,%al
  jne    L20
  jmp    L12
L3:
  nop
L12:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void ClrGyr(unsigned short UsClrFil, unsigned char UcClrMod) {
  unsigned char UcRamClr;
  unsigned char count = 0;
  RegWriteA(0x018F, (unsigned char)(UsClrFil >> 8));
  RegWriteA(0x018E, (unsigned char)UsClrFil);
  RegWriteA(0x0102, UcClrMod);
  do {
    RegReadA(0x0102, &UcRamClr);
    UcRamClr &= UcClrMod;
    if (count++ >= 100) {
      break;
    }
  } while (UcRamClr != 0x00);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ClrGyr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %esi,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  movzbl %ah,%esi
  mov    $0x18f,%edi
  call   <RegWriteA@plt>
  movzbl %bpl,%esi
  mov    $0x18e,%edi
  call   <RegWriteA@plt>
  movzbl %bl,%esi
  mov    $0x102,%edi
  call   <RegWriteA@plt>
  mov    $0x0,%ebx
  lea    0x7(%rsp),%rbp
L8:
  mov    %rbp,%rsi
  mov    $0x102,%edi
  call   <RegReadA@plt>
  mov    %r12d,%eax
  and    0x7(%rsp),%al
  mov    %al,0x7(%rsp)
  setne  %dl
  cmp    $0x63,%bl
  setbe  %al
  add    $0x1,%ebx
  test   %al,%dl
  jne    L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ClrGyr(unsigned short UsClrFil, unsigned char UcClrMod) {
  unsigned char UcRamClr;
  unsigned char count = 0;
  RegWriteA(0x018F, (unsigned char)(UsClrFil >> 8));
  RegWriteA(0x018E, (unsigned char)UsClrFil);
  RegWriteA(0x0102, UcClrMod);
  do {
    RegReadA(0x0102, &UcRamClr);
    UcRamClr &= UcClrMod;
    if (count++ >= 100) {
      break;
    }
  } while (UcRamClr != 0x00);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ClrGyr>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    %edi,%eax
  mov    $0x18f,%edi
  movzbl %ah,%esi
  call   <RegWriteA@plt>
  movzbl %bpl,%esi
  mov    $0x18e,%edi
  lea    0x7(%rsp),%rbp
  call   <RegWriteA@plt>
  movzbl %bl,%esi
  mov    $0x102,%edi
  xor    %ebx,%ebx
  call   <RegWriteA@plt>
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rsi
  mov    $0x102,%edi
  call   <RegReadA@plt>
  and    %r12b,0x7(%rsp)
  setne  %dl
  cmp    $0x64,%bl
  setne  %al
  add    $0x1,%ebx
  test   %al,%dl
  jne    L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ClrGyr(unsigned short UsClrFil, unsigned char UcClrMod) {
  unsigned char UcRamClr;
  unsigned char count = 0;
  RegWriteA(0x018F, (unsigned char)(UsClrFil >> 8));
  RegWriteA(0x018E, (unsigned char)UsClrFil);
  RegWriteA(0x0102, UcClrMod);
  do {
    RegReadA(0x0102, &UcRamClr);
    UcRamClr &= UcClrMod;
    if (count++ >= 100) {
      break;
    }
  } while (UcRamClr != 0x00);
}
```
user: What is the c source code of the assembly code below?

```asm
<ClrGyr>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    %edi,%eax
  mov    $0x18f,%edi
  movzbl %ah,%esi
  call   <RegWriteA@plt>
  movzbl %bpl,%esi
  mov    $0x18e,%edi
  lea    0x7(%rsp),%rbp
  call   <RegWriteA@plt>
  movzbl %bl,%esi
  mov    $0x102,%edi
  xor    %ebx,%ebx
  call   <RegWriteA@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  mov    %rbp,%rsi
  mov    $0x102,%edi
  call   <RegReadA@plt>
  and    %r12b,0x7(%rsp)
  setne  %dl
  cmp    $0x64,%bl
  setne  %al
  add    $0x1,%ebx
  test   %al,%dl
  jne    L5
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void ClrGyr(unsigned short UsClrFil, unsigned char UcClrMod) {
  unsigned char UcRamClr;
  unsigned char count = 0;
  RegWriteA(0x018F, (unsigned char)(UsClrFil >> 8));
  RegWriteA(0x018E, (unsigned char)UsClrFil);
  RegWriteA(0x0102, UcClrMod);
  do {
    RegReadA(0x0102, &UcRamClr);
    UcRamClr &= UcClrMod;
    if (count++ >= 100) {
      break;
    }
  } while (UcRamClr != 0x00);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_gpio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x70(%rbp),%rcx
  mov    -0x64(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D7(%rip),%rdx
  mov    $0x50,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x78(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <write_to_path@plt>
  test   %rax,%rax
  je     L21
  mov    $0x1,%eax
  jmp    L8
L21:
  mov    $0x0,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D7
type_infered: string

tool: D7: /sys/class/gpio/gpio%d/%s

assistant: ```c
int write_gpio(unsigned int gpio, char *filename, char *val) {
  char path[80];
  snprintf(path, 80, "/sys/class/gpio/gpio%d/%s", gpio, filename);
  if (write_to_path(path, val))
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_gpio>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %edi,%ecx
  mov    %rsi,%r8
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D6(%rip),%rdx
  mov    $0x50,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <write_to_path@plt>
  test   %rax,%rax
  setne  %al
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  movzbl %al,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: /sys/class/gpio/gpio%d/%s

assistant: ```c
int write_gpio(unsigned int gpio, char *filename, char *val) {
  char path[80];
  snprintf(path, 80, "/sys/class/gpio/gpio%d/%s", gpio, filename);
  if (write_to_path(path, val))
    return 1;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<write_gpio>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  mov    %rsi,%r8
  mov    $0x50,%esi
  push   %rbp
  mov    %rdx,%rbp
  lea    D9(%rip),%rdx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <write_to_path@plt>
  test   %rax,%rax
  setne  %al
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x68,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D9
data_type: string

tool: D9: /sys/class/gpio/gpio%d/%s

assistant: ```c
int write_gpio(unsigned int gpio, char *filename, char *val) {
  char path[80];
  snprintf(path, 80, "/sys/class/gpio/gpio%d/%s", gpio, filename);
  if (write_to_path(path, val))
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_gpio>:
  endbr64
  push   %r12
  mov    %edi,%ecx
  mov    %rsi,%r8
  mov    $0x50,%esi
  push   %rbp
  mov    %rdx,%rbp
  lea    D7(%rip),%rdx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <write_to_path@plt>
  test   %rax,%rax
  setne  %al
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x68,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: /sys/class/gpio/gpio%d/%s

assistant: ```c
int write_gpio(unsigned int gpio, char *filename, char *val) {
  char path[80];
  snprintf(path, 80, "/sys/class/gpio/gpio%d/%s", gpio, filename);
  if (write_to_path(path, val))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<efprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  movl   $0x0,-0xb8(%rbp)
  cmpq   $0x0,-0xc8(%rbp)
  je     L5
  mov    -0xd8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  mov    -0xd0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vfprintf@plt>
  mov    %eax,-0xb8(%rbp)
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
L5:
  mov    -0xb8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int efprintf(unsigned long int expr, FILE *s, const char *fmt, ...) {
  va_list ap;
  int x = 0;
  if (expr) {
    va_start(ap, fmt);
    x = vfprintf(s, fmt, ap);
    va_end(ap);
  }
  return (x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<efprintf>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%r12d
  test   %rdi,%rdi
  jne    L17
L11:
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rdx,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <vfprintf@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <va_end@plt>
  jmp    L11
```

assistant: ```c
int efprintf(unsigned long int expr, FILE *s, const char *fmt, ...) {
  va_list ap;
  int x = 0;
  if (expr) {
    va_start(ap, fmt);
    x = vfprintf(s, fmt, ap);
    va_end(ap);
  }
  return (x);
}
```
user: What is the c source code of the assembly code below:

```asm
<efprintf>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L2
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  xor    %r14d,%r14d
  mov    %rdx,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int efprintf(unsigned long int expr, FILE *s, const char *fmt, ...) {
  va_list ap;
  int x = 0;
  if (expr) {
    va_start(ap, fmt);
    x = vfprintf(s, fmt, ap);
    va_end(ap);
  }
  return (x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<efprintf>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  test   %rdi,%rdi
  jne    L6
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  xor    %r14d,%r14d
  mov    %rdx,%rbp
  mov    %rsi,%r12
  mov    %rdx,%rsi
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %r14d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vfprintf@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <va_end@plt>
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int efprintf(unsigned long int expr, FILE *s, const char *fmt, ...) {
  va_list ap;
  int x = 0;
  if (expr) {
    va_start(ap, fmt);
    x = vfprintf(s, fmt, ap);
    va_end(ap);
  }
  return (x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sgs_is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x4,-0x10(%rbp)
  movq   $0x5,-0x18(%rbp)
L18:
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  divq   -0x18(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jae    L38
  mov    $0x1,%eax
  jmp    L27
L38:
  mov    -0x8(%rbp),%rax
  imul   -0x18(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L4
  mov    $0x0,%eax
  jmp    L27
L4:
  xorq   $0x6,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x18(%rbp)
  jmp    L18
L27:
  pop    %rbp
  ret
```

assistant: ```c
int sgs_is_prime(size_t x) {
  size_t i, o = 4;
  for (i = 5; 1; i += o) {
    size_t q = x / i;
    if (q < i)
      return 1;
    if (x == q * i)
      return 0;
    o ^= 6;
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sgs_is_prime>:
  endbr64
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x2,%rdx
  cmp    $0x18,%rdi
  jbe    L36
  lea    (%rdx,%rdx,4),%rax
  cmp    %rax,%rdi
  je     L20
  mov    $0x4,%esi
  mov    $0x5,%ecx
L0:
  xor    $0x6,%rsi
  add    %rsi,%rcx
  mov    %rdi,%rax
  mov    $0x0,%edx
  div    %rcx
  cmp    %rcx,%rax
  jb     L3
  imul   %rcx,%rax
  cmp    %rdi,%rax
  jne    L0
  mov    $0x0,%eax
  ret
L3:
  mov    $0x1,%eax
  ret
L36:
  mov    $0x1,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int sgs_is_prime(size_t x) {
  size_t i, o = 4;
  for (i = 5; 1; i += o) {
    size_t q = x / i;
    if (q < i)
      return 1;
    if (x == q * i)
      return 0;
    o ^= 6;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sgs_is_prime>:
  endbr64
  movabs $0xcccccccccccccccd,%rdx
  mov    %rdi,%rax
  mul    %rdx
  shr    $0x2,%rdx
  cmp    $0x18,%rdi
  jbe    L13
  lea    (%rdx,%rdx,4),%rax
  cmp    %rax,%rdi
  je     L39
  mov    $0x4,%esi
  mov    $0x5,%ecx
  jmp    L41
  nopl   0x0(%rax,%rax,1)
L18:
  imul   %rcx,%rax
  cmp    %rdi,%rax
  je     L39
L41:
  xor    $0x6,%rsi
  mov    %rdi,%rax
  xor    %edx,%edx
  add    %rsi,%rcx
  div    %rcx
  cmp    %rcx,%rax
  jae    L18
L13:
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  xor    %eax,%eax
  ret
```

assistant: ```c
int sgs_is_prime(size_t x) {
  size_t i, o = 4;
  for (i = 5; 1; i += o) {
    size_t q = x / i;
    if (q < i)
      return 1;
    if (x == q * i)
      return 0;
    o ^= 6;
  }
  return 1;
}
```