ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<diff>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  call   <calloc@plt>
  test   %r12d,%r12d
  jle    L5
  lea    -0x2(%rbp),%edx
  mov    %rbx,%rdi
  lea    0x8(%rbx,%rdx,8),%rcx
  mov    %rax,%rdx
  sub    %rbx,%rdx
  nopl   0x0(%rax)
L7:
  movsd  0x8(%rdi),%xmm0
  subsd  (%rdi),%xmm0
  movsd  %xmm0,(%rdx,%rdi,1)
  add    $0x8,%rdi
  cmp    %rcx,%rdi
  jne    L7
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *diff(double *vec, int n) {
  int i;
  double *vec_out;
  vec_out = (double *)calloc((n - 1), sizeof(double));
  for (i = 0; i < (n - 1); i++) {
    vec_out[i] = vec[i + 1] - vec[i];
  }
  return vec_out;
}
```
user: Translate the below assembly code into C programming language:

```asm
<diff>:
  endbr64
  push   %r12
  lea    -0x1(%rsi),%r12d
  push   %rbp
  mov    %esi,%ebp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  call   <calloc@plt>
  mov    %rax,%r8
  test   %r12d,%r12d
  jle    L9
  lea    0x8(%rbx),%rdx
  mov    %r8,%rcx
  sub    $0x2,%ebp
  sub    %rdx,%rcx
  mov    %rdx,%rax
  cmp    $0x8,%rcx
  jbe    L57
  cmp    $0x1,%ebp
  jbe    L57
  mov    %r12d,%edx
  mov    $0xfffffffffffffff8,%rcx
  shr    %edx
  sub    %rbx,%rcx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x18(%rbx,%rdx,1),%rsi
  nopl   0x0(%rax)
L44:
  movupd (%rax),%xmm0
  movupd -0x8(%rax),%xmm1
  lea    (%rax,%r8,1),%rdx
  add    $0x10,%rax
  subpd  %xmm1,%xmm0
  movups %xmm0,(%rdx,%rcx,1)
  cmp    %rsi,%rax
  jne    L44
  mov    %r12d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r12d
  je     L9
  cltq
  add    $0x1,%rax
  movsd  (%rbx,%rax,8),%xmm0
  subsd  -0x8(%rbx,%rax,8),%xmm0
  movsd  %xmm0,-0x8(%r8,%rax,8)
L9:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    %r8,%rax
  lea    (%rdx,%rbp,8),%rdx
  sub    %rbx,%rax
  nopw   0x0(%rax,%rax,1)
L8:
  movsd  0x8(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  movsd  %xmm0,(%rax,%rbx,1)
  add    $0x8,%rbx
  cmp    %rbx,%rdx
  jne    L8
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
double *diff(double *vec, int n) {
  int i;
  double *vec_out;
  vec_out = (double *)calloc((n - 1), sizeof(double));
  for (i = 0; i < (n - 1); i++) {
    vec_out[i] = vec[i + 1] - vec[i];
  }
  return vec_out;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<test_and_clear_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    -0x20(%rbp),%rdx
  btr    %eax,(%rcx)
  sbb    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile unsigned long *addr) {
  int oldbit;
  asm volatile(""
               "btrl %2,%1\n\t"
               "sbbl %0,%0"
               : "=r"(oldbit), "+m"((*(volatile long *)addr))
               : "Ir"(nr)
               : "memory");
  return oldbit;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_and_clear_bit>:
  endbr64
  btr    %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile unsigned long *addr) {
  int oldbit;
  asm volatile(""
               "btrl %2,%1\n\t"
               "sbbl %0,%0"
               : "=r"(oldbit), "+m"((*(volatile long *)addr))
               : "Ir"(nr)
               : "memory");
  return oldbit;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_and_clear_bit>:
  endbr64
  btr    %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile unsigned long *addr) {
  int oldbit;
  asm volatile(""
               "btrl %2,%1\n\t"
               "sbbl %0,%0"
               : "=r"(oldbit), "+m"((*(volatile long *)addr))
               : "Ir"(nr)
               : "memory");
  return oldbit;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test_and_clear_bit>:
  endbr64
  btr    %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
int test_and_clear_bit(int nr, volatile unsigned long *addr) {
  int oldbit;
  asm volatile(""
               "btrl %2,%1\n\t"
               "sbbl %0,%0"
               : "=r"(oldbit), "+m"((*(volatile long *)addr))
               : "Ir"(nr)
               : "memory");
  return oldbit;
}
```
user: Translate the below assembly code into C programming language:

```asm
<atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%rax
  mov    $0x0,%ebx
  mov    $0x0,%r12d
  jmp    L29
L1:
  add    $0x1,%rax
L29:
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  jg     L93
  movzbl (%rax),%edx
  test   %dl,%dl
  jg     L1
L93:
  movzbl (%rax),%edx
  cmp    $0x2d,%dl
  jne    L48
  mov    $0x1,%r12d
  add    $0x1,%rax
  jmp    L39
L48:
  movzbl (%rax),%edx
  cmp    $0x2b,%dl
  jne    L39
  add    $0x1,%rax
  jmp    L39
L58:
  mov    %ebx,%edx
  shl    $0x2,%edx
  add    %ebx,%edx
  add    %edx,%edx
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  movsbl %dl,%edx
  sub    $0x30,%edx
  lea    (%rcx,%rdx,1),%ebx
L39:
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  jle    L20
  movzbl (%rax),%edx
  cmp    $0x39,%dl
  jle    L58
L20:
  test   %r12d,%r12d
  je     L19
  mov    %ebx,%eax
  neg    %eax
  jmp    L25
L19:
  mov    %ebx,%eax
L25:
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int atoi(number)
register char *number;
{
  register int n = 0, neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<atoi>:
  endbr64
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  ja     L4
L42:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L42
L4:
  cmp    $0x2d,%al
  je     L10
  mov    $0x0,%esi
  cmp    $0x2b,%al
  je     L61
L18:
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  mov    $0x0,%edx
  cmp    $0x9,%cl
  ja     L33
L6:
  lea    (%rdx,%rdx,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    -0x30(%rax,%rdx,2),%edx
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%cl
  jbe    L6
L33:
  mov    %edx,%eax
  neg    %eax
  test   %esi,%esi
  cmovne %eax,%edx
  mov    %edx,%eax
  ret
L10:
  add    $0x1,%rdi
  mov    $0x1,%esi
  jmp    L18
L61:
  add    $0x1,%rdi
  jmp    L18
```

assistant: ```c
int atoi(number)
register char *number;
{
  register int n = 0, neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<atoi>:
  endbr64
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L50:
  add    $0x1,%rdi
L29:
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L50
  cmp    $0x2d,%al
  je     L17
  cmp    $0x2b,%al
  je     L48
  movzbl (%rdi),%eax
  xor    %ecx,%ecx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L85
L21:
  xor    %r8d,%r8d
  nopw   0x0(%rax,%rax,1)
L11:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L11
  mov    %r8d,%eax
  neg    %eax
  test   %ecx,%ecx
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L48:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L85
  mov    %rcx,%rdi
  xor    %ecx,%ecx
  jmp    L21
  nopw   0x0(%rax,%rax,1)
L17:
  movzbl 0x1(%rdi),%eax
  mov    $0x1,%ecx
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L21
L85:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(number)
register char *number;
{
  register int n = 0, neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<atoi>:
  endbr64
  jmp    L85
  cs nopw 0x0(%rax,%rax,1)
L34:
  add    $0x1,%rdi
L85:
  movzbl (%rdi),%eax
  lea    -0x1(%rax),%edx
  cmp    $0x1f,%dl
  jbe    L34
  cmp    $0x2d,%al
  je     L65
  cmp    $0x2b,%al
  je     L80
  lea    -0x30(%rax),%edx
  xor    %ecx,%ecx
  cmp    $0x9,%dl
  ja     L53
L69:
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L48:
  sub    $0x30,%eax
  lea    (%r8,%r8,4),%edx
  add    $0x1,%rdi
  movsbl %al,%eax
  lea    (%rax,%rdx,2),%r8d
  movzbl (%rdi),%eax
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L48
  mov    %r8d,%eax
  neg    %eax
  test   %ecx,%ecx
  cmovne %eax,%r8d
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L80:
  movzbl 0x1(%rdi),%eax
  lea    0x1(%rdi),%rcx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  ja     L53
  mov    %rcx,%rdi
  xor    %ecx,%ecx
  jmp    L69
  nop
L65:
  movzbl 0x1(%rdi),%eax
  mov    $0x1,%ecx
  add    $0x1,%rdi
  lea    -0x30(%rax),%edx
  cmp    $0x9,%dl
  jbe    L69
L53:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int atoi(number)
register char *number;
{
  register int n = 0, neg = 0;
  while (*number <= ' ' && *number > 0)
    ++number;
  if (*number == '-') {
    neg = 1;
    ++number;
  } else if (*number == '+')
    ++number;
  while (*number >= '0' && *number <= '9')
    n = (n * 10) + ((*number++) - '0');
  return (neg ? -n : n);
}
```
user: What is the c source code of the assembly code below?

```asm
<intostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L23
  cmpl   $0x0,-0x14(%rbp)
  jns    L49
  negl   -0x14(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x2d,(%rax)
  addl   $0x1,-0x8(%rbp)
  jmp    L49
L24:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  addl   $0x1,-0x8(%rbp)
L49:
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  sub    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x4(%rbp)
  jl     L14
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L58
L23:
  mov    -0x20(%rbp),%rax
  movb   $0x30,(%rax)
L58:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void intostr(int num, char *ret) {
  int dig = 0;
  char aux;
  if (num != 0) {
    if (num < 0) {
      num = -num;
      ret[0] = '-';
      dig++;
    }
    while (num != 0) {
      ret[dig] = (num % 10) + '0';
      num = num / 10;
      dig++;
    }
    for (int x = 0; x < dig / 2; x++) {
      aux = ret[x];
      ret[x] = ret[dig - x - 1];
      ret[dig - x - 1] = aux;
    }
    ret[dig] = 0;
  } else {
    ret[0] = '0';
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<intostr>:
  endbr64
  mov    %rsi,%rcx
  test   %edi,%edi
  je     L5
  mov    $0x0,%edx
  js     L50
L37:
  add    $0x1,%edx
  movslq %edx,%rdx
L14:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edi,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rcx,%rdx,1)
  mov    %eax,%edi
  mov    %edx,%r8d
  add    $0x1,%rdx
  test   %eax,%eax
  jne    L14
  mov    %r8d,%r9d
  shr    $0x1f,%r9d
  add    %r8d,%r9d
  sar    %r9d
  cmp    $0x1,%r8d
  jle    L11
  movslq %r8d,%rax
  lea    -0x1(%rcx,%rax,1),%rdx
  mov    $0x0,%eax
L51:
  movzbl (%rcx,%rax,1),%esi
  movzbl (%rdx),%edi
  mov    %dil,(%rcx,%rax,1)
  mov    %sil,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%r9d
  jg     L51
L11:
  movslq %r8d,%r8
  movb   $0x0,(%rcx,%r8,1)
  ret
L50:
  neg    %edi
  movb   $0x2d,(%rsi)
  mov    $0x1,%edx
  jmp    L37
L5:
  movb   $0x30,(%rsi)
  ret
```

assistant: ```c
void intostr(int num, char *ret) {
  int dig = 0;
  char aux;
  if (num != 0) {
    if (num < 0) {
      num = -num;
      ret[0] = '-';
      dig++;
    }
    while (num != 0) {
      ret[dig] = (num % 10) + '0';
      num = num / 10;
      dig++;
    }
    for (int x = 0; x < dig / 2; x++) {
      aux = ret[x];
      ret[x] = ret[dig - x - 1];
      ret[dig - x - 1] = aux;
    }
    ret[dig] = 0;
  } else {
    ret[0] = '0';
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<intostr>:
  endbr64
  test   %edi,%edi
  je     L8
  mov    $0x0,%edx
  js     L58
L67:
  add    $0x1,%edx
  mov    $0xcccccccd,%r8d
  movslq %edx,%rdx
  nopl   0x0(%rax,%rax,1)
L65:
  mov    %edi,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rsi,%rdx,1)
  mov    %eax,%edi
  mov    %edx,%eax
  add    $0x1,%rdx
  test   %edi,%edi
  jne    L65
  mov    %eax,%ecx
  sar    %ecx
  je     L30
  movslq %eax,%r8
  sub    $0x1,%ecx
  mov    %rsi,%rdx
  lea    -0x2(%rsi,%r8,1),%r9
  lea    -0x1(%rsi,%r8,1),%rax
  sub    %rcx,%r9
  nopl   0x0(%rax)
L44:
  movzbl (%rdx),%ecx
  movzbl (%rax),%edi
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %dil,-0x1(%rdx)
  mov    %cl,0x1(%rax)
  cmp    %rax,%r9
  jne    L44
L66:
  movb   $0x0,(%rsi,%r8,1)
  ret
L8:
  movb   $0x30,(%rsi)
  ret
  nopl   0x0(%rax)
L58:
  movb   $0x2d,(%rsi)
  neg    %edi
  mov    $0x1,%edx
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L30:
  movslq %eax,%r8
  jmp    L66
```

assistant: ```c
void intostr(int num, char *ret) {
  int dig = 0;
  char aux;
  if (num != 0) {
    if (num < 0) {
      num = -num;
      ret[0] = '-';
      dig++;
    }
    while (num != 0) {
      ret[dig] = (num % 10) + '0';
      num = num / 10;
      dig++;
    }
    for (int x = 0; x < dig / 2; x++) {
      aux = ret[x];
      ret[x] = ret[dig - x - 1];
      ret[dig - x - 1] = aux;
    }
    ret[dig] = 0;
  } else {
    ret[0] = '0';
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intostr>:
  endbr64
  test   %edi,%edi
  je     L66
  mov    $0x0,%edx
  js     L61
L30:
  add    $0x1,%edx
  mov    $0xcccccccd,%r8d
  movslq %edx,%rdx
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %edi,%eax
  imul   %r8,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edi
  add    $0x30,%edi
  mov    %dil,-0x1(%rsi,%rdx,1)
  mov    %eax,%edi
  mov    %edx,%eax
  add    $0x1,%rdx
  test   %edi,%edi
  jne    L4
  mov    %eax,%ecx
  sar    %ecx
  je     L20
  movslq %eax,%r8
  sub    $0x1,%ecx
  mov    %rsi,%rdx
  lea    -0x2(%rsi,%r8,1),%r9
  lea    -0x1(%rsi,%r8,1),%rax
  sub    %rcx,%r9
  nopl   0x0(%rax)
L42:
  movzbl (%rdx),%ecx
  movzbl (%rax),%edi
  sub    $0x1,%rax
  add    $0x1,%rdx
  mov    %dil,-0x1(%rdx)
  mov    %cl,0x1(%rax)
  cmp    %rax,%r9
  jne    L42
L7:
  movb   $0x0,(%rsi,%r8,1)
  ret
L66:
  movb   $0x30,(%rsi)
  ret
  nopl   0x0(%rax)
L61:
  movb   $0x2d,(%rsi)
  neg    %edi
  mov    $0x1,%edx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L20:
  movslq %eax,%r8
  jmp    L7
```

assistant: ```c
void intostr(int num, char *ret) {
  int dig = 0;
  char aux;
  if (num != 0) {
    if (num < 0) {
      num = -num;
      ret[0] = '-';
      dig++;
    }
    while (num != 0) {
      ret[dig] = (num % 10) + '0';
      num = num / 10;
      dig++;
    }
    for (int x = 0; x < dig / 2; x++) {
      aux = ret[x];
      ret[x] = ret[dig - x - 1];
      ret[dig - x - 1] = aux;
    }
    ret[dig] = 0;
  } else {
    ret[0] = '0';
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<dup_two>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    D26(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L3
  mov    D7(%rip),%rax
  mov    (%rax),%rdx
  mov    D36(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L3
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L3:
  mov    D3(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x3,%edx
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  leave
  ret
```

assistant: ```c
int dup_two(int oldfd, int newfd) {
  int is_exist;
  if ((is_exist = fcntl(oldfd, F_GETFL)) == -1) {
    if (errno == EBADF) {
      close(oldfd);
    }
  }
  newfd = fcntl(oldfd, F_DUPFD, 3);
  return newfd;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dup_two>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    D0(%rip),%rax
  mov    (%rax),%esi
  mov    $0x0,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L10
L6:
  mov    $0x3,%edx
  mov    D9(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <fcntl@plt>
  pop    %rbx
  ret
L10:
  mov    D35(%rip),%rdx
  mov    D25(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L6
  mov    %ebx,%edi
  call   <close@plt>
  jmp    L6
```

assistant: ```c
int dup_two(int oldfd, int newfd) {
  int is_exist;
  if ((is_exist = fcntl(oldfd, F_GETFL)) == -1) {
    if (errno == EBADF) {
      close(oldfd);
    }
  }
  newfd = fcntl(oldfd, F_DUPFD, 3);
  return newfd;
}
```
user: Translate the below assembly code into C programming language:

```asm
<dup_two>:
  endbr64
  mov    D34(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L15
L11:
  mov    D7(%rip),%rax
  mov    %ebp,%edi
  mov    $0x3,%edx
  pop    %rbp
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1060 <fcntl@plt>
  nopl   0x0(%rax)
L15:
  mov    D1(%rip),%rax
  mov    D3(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L11
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L11
```

assistant: ```c
int dup_two(int oldfd, int newfd) {
  int is_exist;
  if ((is_exist = fcntl(oldfd, F_GETFL)) == -1) {
    if (errno == EBADF) {
      close(oldfd);
    }
  }
  newfd = fcntl(oldfd, F_DUPFD, 3);
  return newfd;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dup_two>:
  endbr64
  mov    D2(%rip),%rax
  push   %rbp
  mov    %edi,%ebp
  mov    (%rax),%esi
  xor    %eax,%eax
  call   <fcntl@plt>
  cmp    $0xffffffff,%eax
  je     L6
L18:
  mov    D24(%rip),%rax
  mov    %ebp,%edi
  mov    $0x3,%edx
  pop    %rbp
  mov    (%rax),%esi
  xor    %eax,%eax
  jmp    1060 <fcntl@plt>
  nopl   0x0(%rax)
L6:
  mov    D11(%rip),%rax
  mov    D21(%rip),%rdx
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  jne    L18
  mov    %ebp,%edi
  call   <close@plt>
  jmp    L18
```

assistant: ```c
int dup_two(int oldfd, int newfd) {
  int is_exist;
  if ((is_exist = fcntl(oldfd, F_GETFL)) == -1) {
    if (errno == EBADF) {
      close(oldfd);
    }
  }
  newfd = fcntl(oldfd, F_DUPFD, 3);
  return newfd;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<str_equaln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <str_len@plt>
  cmp    %rax,-0x20(%rbp)
  je     L2
  mov    $0x0,%eax
  jmp    L40
L2:
  movq   $0x0,-0x8(%rbp)
  jmp    L25
L23:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L9
  mov    $0x0,%eax
  jmp    L40
L9:
  addq   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jl     L23
  mov    $0x1,%eax
L40:
  leave
  ret
```

assistant: ```c
int str_equaln(const char *y, long long ylen, const char *x) {
  long long i;
  if (str_len(x) != ylen)
    return 0;
  for (i = 0; i < ylen; ++i)
    if (y[i] != x[i])
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_equaln>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rdx,%rdi
  call   <str_len@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  cmp    %rbx,%rdx
  jne    L13
  test   %rbx,%rbx
  jle    L44
  mov    $0x0,%eax
L20:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%r12,%rax,1)
  jne    L26
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L20
  mov    $0x1,%eax
  jmp    L13
L44:
  mov    $0x1,%eax
  jmp    L13
L26:
  mov    $0x0,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_equaln(const char *y, long long ylen, const char *x) {
  long long i;
  if (str_len(x) != ylen)
    return 0;
  for (i = 0; i < ylen; ++i)
    if (y[i] != x[i])
      return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_equaln>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <str_len@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %rbx,%r8
  jne    L14
  test   %rbx,%rbx
  jle    L40
  xor    %eax,%eax
  jmp    L43
  nopl   0x0(%rax)
L7:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L40
L43:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%r12,%rax,1)
  je     L7
  xor    %eax,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_equaln(const char *y, long long ylen, const char *x) {
  long long i;
  if (str_len(x) != ylen)
    return 0;
  for (i = 0; i < ylen; ++i)
    if (y[i] != x[i])
      return 0;
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_equaln>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rdx,%rdi
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <str_len@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  cmp    %rbx,%r8
  jne    L39
  test   %rbx,%rbx
  jle    L15
  xor    %eax,%eax
  jmp    L9
  nopl   0x0(%rax)
L0:
  add    $0x1,%rax
  cmp    %rax,%rbx
  je     L15
L9:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%r12,%rax,1)
  je     L0
  xor    %eax,%eax
L39:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int str_equaln(const char *y, long long ylen, const char *x) {
  long long i;
  if (str_len(x) != ylen)
    return 0;
  for (i = 0; i < ylen; ++i)
    if (y[i] != x[i])
      return 0;
  return 1;
}
```