ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<findIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0xffffffff,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L4:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x28(%rbp),%xmm0
  jb     L47
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L2
L47:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L4
L2:
  cmpl   $0xffffffff,-0x8(%rbp)
  jne    L54
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  jmp    L39
L54:
  mov    -0x8(%rbp),%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
int findIndex(double *CDF, int lengthCDF, double value) {
  int index = -1;
  int x;
  for (x = 0; x < lengthCDF; x++) {
    if (CDF[x] >= value) {
      index = x;
      break;
    }
  }
  if (index == -1) {
    return lengthCDF - 1;
  }
  return index;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<findIndex>:
  endbr64
  test   %esi,%esi
  jle    L3
  mov    %esi,%ecx
  mov    $0x0,%eax
L21:
  mov    %eax,%edx
  movsd  (%rdi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  jae    L11
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L21
L3:
  lea    -0x1(%rsi),%edx
  jmp    L40
L11:
  cmp    $0xffffffff,%eax
  je     L3
L40:
  mov    %edx,%eax
  ret
```

assistant: ```c
int findIndex(double *CDF, int lengthCDF, double value) {
  int index = -1;
  int x;
  for (x = 0; x < lengthCDF; x++) {
    if (CDF[x] >= value) {
      index = x;
      break;
    }
  }
  if (index == -1) {
    return lengthCDF - 1;
  }
  return index;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<findIndex>:
  endbr64
  test   %esi,%esi
  jle    L30
  movslq %esi,%rdx
  xor    %eax,%eax
  jmp    L21
  nop
L0:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L30
L21:
  movsd  (%rdi,%rax,8),%xmm1
  mov    %eax,%r8d
  comisd %xmm0,%xmm1
  jb     L0
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L30:
  lea    -0x1(%rsi),%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int findIndex(double *CDF, int lengthCDF, double value) {
  int index = -1;
  int x;
  for (x = 0; x < lengthCDF; x++) {
    if (CDF[x] >= value) {
      index = x;
      break;
    }
  }
  if (index == -1) {
    return lengthCDF - 1;
  }
  return index;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<findIndex>:
  endbr64
  test   %esi,%esi
  jle    L35
  movslq %esi,%rdx
  xor    %eax,%eax
  jmp    L20
  nop
L9:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L35
L20:
  movsd  (%rdi,%rax,8),%xmm1
  mov    %eax,%r8d
  comisd %xmm0,%xmm1
  jb     L9
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L35:
  lea    -0x1(%rsi),%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int findIndex(double *CDF, int lengthCDF, double value) {
  int index = -1;
  int x;
  for (x = 0; x < lengthCDF; x++) {
    if (CDF[x] >= value) {
      index = x;
      break;
    }
  }
  if (index == -1) {
    return lengthCDF - 1;
  }
  return index;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wes_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: usage: wes <filename> <args>
Arguments can be:
 --help		Print this help and exit
 --verbose	Run with much more verbosity


assistant: ```c
void wes_help() {
  printf("usage: wes <filename> <args>\n"
         "Arguments can be:\n"
         " --help\t\tPrint this help and exit\n"
         " --verbose\tRun with much more verbosity\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wes_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: label: D8
type_infered: string

tool: D8: usage: wes <filename> <args>
Arguments can be:
 --help		Print this help and exit
 --verbose	Run with much more verbosity


assistant: ```c
void wes_help() {
  printf("usage: wes <filename> <args>\n"
         "Arguments can be:\n"
         " --help\t\tPrint this help and exit\n"
         " --verbose\tRun with much more verbosity\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wes_help>:
  endbr64
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type: string

tool: D2: usage: wes <filename> <args>
Arguments can be:
 --help		Print this help and exit
 --verbose	Run with much more verbosity


assistant: ```c
void wes_help() {
  printf("usage: wes <filename> <args>\n"
         "Arguments can be:\n"
         " --help\t\tPrint this help and exit\n"
         " --verbose\tRun with much more verbosity\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<wes_help>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
type: string

tool: D5: usage: wes <filename> <args>
Arguments can be:
 --help		Print this help and exit
 --verbose	Run with much more verbosity


assistant: ```c
void wes_help() {
  printf("usage: wes <filename> <args>\n"
         "Arguments can be:\n"
         " --help\t\tPrint this help and exit\n"
         " --verbose\tRun with much more verbosity\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_38_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  and    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_38_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T & S;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_38_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  and    %esi,%eax
  or     $0xff,%al
  xor    %edi,%eax
  mov    %esi,%edx
  not    %edx
  or     %edi,%edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_38_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T & S;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_38_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  and    %esi,%eax
  mov    %esi,%edx
  or     $0xff,%al
  not    %edx
  xor    %edi,%eax
  or     %edi,%edx
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_38_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T & S;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xrop3_38_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %edi,%eax
  and    %esi,%eax
  mov    %esi,%edx
  or     $0xff,%al
  not    %edx
  xor    %edi,%eax
  or     %edi,%edx
  not    %edi
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_38_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = T & S;
  stk2 = D | stk3;
  stk1 = S ^ stk2;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: What is the c source code of the assembly code below?

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L71:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L35
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L71
  jmp    L56
L35:
  nop
L56:
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L89:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L27:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L89
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L98
L28:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L37
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L65
L37:
  subl   $0x1,-0x10(%rbp)
L98:
  cmpl   $0x0,-0x10(%rbp)
  jns    L28
L65:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *s) {
  int len, len2, i, count = 0;
  len = strlen(s);
  for (i = 0; i < len; i++)
    if (isspace(s[i]))
      count++;
    else
      break;
  for (i = 0; s[i] != '\0'; i++)
    s[i] = s[count + i];
  len2 = strlen(s);
  for (i = len2 - 1; i >= 0; i--)
    if (!isspace(s[i])) {
      s[i + 1] = '\0';
      break;
    }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L70
  mov    %eax,%r13d
  mov    %rbp,%r12
  mov    $0x0,%ebx
L88:
  movsbl (%r12),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L41
  add    $0x1,%ebx
  add    $0x1,%r12
  cmp    %ebx,%r13d
  jne    L88
  mov    %r13d,%ebx
L41:
  cmpb   $0x0,0x0(%rbp)
  je     L17
  mov    %rbp,%rax
  movslq %ebx,%rbx
L15:
  movzbl (%rax,%rbx,1),%edx
  mov    %dl,(%rax)
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L15
L17:
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L19
  movslq %eax,%rbx
L4:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L49
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L4
  jmp    L19
L70:
  mov    $0x0,%ebx
  jmp    L41
L49:
  movb   $0x0,0x1(%rbp,%rbx,1)
L19:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *trim(char *s) {
  int len, len2, i, count = 0;
  len = strlen(s);
  for (i = 0; i < len; i++)
    if (isspace(s[i]))
      count++;
    else
      break;
  for (i = 0; s[i] != '\0'; i++)
    s[i] = s[count + i];
  len2 = strlen(s);
  for (i = len2 - 1; i >= 0; i--)
    if (!isspace(s[i])) {
      s[i + 1] = '\0';
      break;
    }
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L67
  mov    %eax,%r13d
  mov    %r12,%rbp
  xor    %ebx,%ebx
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L3:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r13d
  je     L14
L13:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L3
L14:
  cmpb   $0x0,(%r12)
  mov    %r12,%rax
  movslq %ebx,%rbx
  je     L54
  nopw   0x0(%rax,%rax,1)
L33:
  movzbl (%rax,%rbx,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmpb   $0x0,(%rax)
  jne    L33
L54:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L22
  movslq %eax,%rbx
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L17:
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  je     L22
L23:
  movsbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
  movb   $0x0,0x1(%r12,%rbx,1)
L22:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L67:
  xor    %ebx,%ebx
  jmp    L14
```

assistant: ```c
char *trim(char *s) {
  int len, len2, i, count = 0;
  len = strlen(s);
  for (i = 0; i < len; i++)
    if (isspace(s[i]))
      count++;
    else
      break;
  for (i = 0; s[i] != '\0'; i++)
    s[i] = s[count + i];
  len2 = strlen(s);
  for (i = len2 - 1; i >= 0; i--)
    if (!isspace(s[i])) {
      s[i + 1] = '\0';
      break;
    }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L101
  mov    %eax,%r13d
  mov    %r12,%rbp
  xor    %ebx,%ebx
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L17:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %ebx,%r13d
  je     L89
L56:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
L89:
  cmpb   $0x0,(%r12)
  mov    %r12,%rax
  movslq %ebx,%rbx
  je     L21
  nopw   0x0(%rax,%rax,1)
L28:
  movzbl (%rax,%rbx,1),%edx
  add    $0x1,%rax
  mov    %dl,-0x1(%rax)
  cmpb   $0x0,(%rax)
  jne    L28
L21:
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L50
  movslq %eax,%rbx
  jmp    L99
  nopw   0x0(%rax,%rax,1)
L5:
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  je     L50
L99:
  movsbl (%r12,%rbx,1),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L5
  movb   $0x0,0x1(%r12,%rbx,1)
L50:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L101:
  xor    %ebx,%ebx
  jmp    L89
```

assistant: ```c
char *trim(char *s) {
  int len, len2, i, count = 0;
  len = strlen(s);
  for (i = 0; i < len; i++)
    if (isspace(s[i]))
      count++;
    else
      break;
  for (i = 0; s[i] != '\0'; i++)
    s[i] = s[count + i];
  len2 = strlen(s);
  for (i = len2 - 1; i >= 0; i--)
    if (!isspace(s[i])) {
      s[i + 1] = '\0';
      break;
    }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<protect_msg>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L17:
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <protect@plt>
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  mov    -0x28(%rbp),%rdx
  shr    $0x3,%rdx
  cmp    %rdx,%rax
  jb     L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void protect_msg(unsigned int *key, char *buf, size_t buf_len) {
  unsigned int i;
  for (i = 0; i < buf_len / 8; ++i)
    protect(key, (unsigned int *)&buf[i * 8]);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<protect_msg>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%r13
  shr    $0x3,%r13
  cmp    $0x7,%rdx
  jbe    L16
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    $0x0,%ebx
L17:
  lea    0x0(,%rbx,8),%esi
  mov    %esi,%esi
  add    %r12,%rsi
  mov    %rbp,%rdi
  call   <protect@plt>
  add    $0x1,%ebx
  mov    %ebx,%eax
  cmp    %r13,%rax
  jb     L17
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void protect_msg(unsigned int *key, char *buf, size_t buf_len) {
  unsigned int i;
  for (i = 0; i < buf_len / 8; ++i)
    protect(key, (unsigned int *)&buf[i * 8]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<protect_msg>:
  endbr64
  shr    $0x3,%rdx
  je     L5
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
L16:
  lea    0x0(,%r13,8),%esi
  mov    %rbp,%rdi
  add    %r12,%rsi
  call   <protect@plt>
  lea    0x1(%r13),%eax
  mov    %rax,%r13
  cmp    %rbx,%rax
  jb     L16
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
void protect_msg(unsigned int *key, char *buf, size_t buf_len) {
  unsigned int i;
  for (i = 0; i < buf_len / 8; ++i)
    protect(key, (unsigned int *)&buf[i * 8]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<protect_msg>:
  endbr64
  shr    $0x3,%rdx
  je     L15
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
L2:
  lea    0x0(,%r13,8),%esi
  mov    %rbp,%rdi
  add    %r12,%rsi
  call   <protect@plt>
  lea    0x1(%r13),%eax
  mov    %rax,%r13
  cmp    %rbx,%rax
  jb     L2
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void protect_msg(unsigned int *key, char *buf, size_t buf_len) {
  unsigned int i;
  for (i = 0; i < buf_len / 8; ++i)
    protect(key, (unsigned int *)&buf[i * 8]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ule>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D34
type_infered: string
name: read_data
arguments: tag: D59
type_infered: string
name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D24
type_infered: string
name: read_data
arguments: tag: D51
type_infered: string
name: read_data
arguments: tag: D31
type_infered: string

tool: D34: cmpl

tool: D59: %eax, %edx

tool: D8: setbe

tool: D24: %al

tool: D51: movzbl

tool: D31: %al, %eax

assistant: ```c
ule() {
  ot("cmpl");
  ot("%eax, %edx");
  nl();
  ot("setbe");
  ot("%al");
  nl();
  ot("movzbl");
  ot("%al, %eax");
  nl();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ule>:
  endbr64
  sub    $0x8,%rsp
  lea    D37(%rip),%rdi
  call   <ot@plt>
  lea    D11(%rip),%rdi
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  lea    D54(%rip),%rdi
  call   <ot@plt>
  lea    D4(%rip),%rdi
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  lea    D41(%rip),%rdi
  call   <ot@plt>
  lea    D25(%rip),%rdi
  call   <ot@plt>
  mov    $0x0,%eax
  call   <nl@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D37
datatype: string
name: disassemble_data
arguments: data_label: D11
datatype: string
name: disassemble_data
arguments: data_label: D54
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string
name: disassemble_data
arguments: data_label: D41
datatype: string
name: disassemble_data
arguments: data_label: D25
datatype: string

tool: D37: cmpl

tool: D11: %eax, %edx

tool: D54: setbe

tool: D4: %al

tool: D41: movzbl

tool: D25: %al, %eax

assistant: ```c
ule() {
  ot("cmpl");
  ot("%eax, %edx");
  nl();
  ot("setbe");
  ot("%al");
  nl();
  ot("movzbl");
  ot("%al, %eax");
  nl();
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ule>:
  endbr64
  sub    $0x8,%rsp
  lea    D14(%rip),%rdi
  call   <ot@plt>
  lea    D46(%rip),%rdi
  call   <ot@plt>
  xor    %eax,%eax
  call   <nl@plt>
  lea    D10(%rip),%rdi
  call   <ot@plt>
  lea    D33(%rip),%rdi
  call   <ot@plt>
  xor    %eax,%eax
  call   <nl@plt>
  lea    D38(%rip),%rdi
  call   <ot@plt>
  lea    D8(%rip),%rdi
  call   <ot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <nl@plt>
```

tool_calls: name: disassemble_data
arguments: label: D14
data_type: string
name: disassemble_data
arguments: label: D46
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string
name: disassemble_data
arguments: label: D33
data_type: string
name: disassemble_data
arguments: label: D38
data_type: string
name: disassemble_data
arguments: label: D8
data_type: string

tool: D14: cmpl

tool: D46: %eax, %edx

tool: D10: setbe

tool: D33: %al

tool: D38: movzbl

tool: D8: %al, %eax

assistant: ```c
ule() {
  ot("cmpl");
  ot("%eax, %edx");
  nl();
  ot("setbe");
  ot("%al");
  nl();
  ot("movzbl");
  ot("%al, %eax");
  nl();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ule>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <ot@plt>
  lea    D7(%rip),%rdi
  call   <ot@plt>
  xor    %eax,%eax
  call   <nl@plt>
  lea    D51(%rip),%rdi
  call   <ot@plt>
  lea    D31(%rip),%rdi
  call   <ot@plt>
  xor    %eax,%eax
  call   <nl@plt>
  lea    D50(%rip),%rdi
  call   <ot@plt>
  lea    D6(%rip),%rdi
  call   <ot@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <nl@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_infered: string
name: unpack_data
arguments: data_label: D7
type_infered: string
name: unpack_data
arguments: data_label: D51
type_infered: string
name: unpack_data
arguments: data_label: D31
type_infered: string
name: unpack_data
arguments: data_label: D50
type_infered: string
name: unpack_data
arguments: data_label: D6
type_infered: string

tool: D2: cmpl

tool: D7: %eax, %edx

tool: D51: setbe

tool: D31: %al

tool: D50: movzbl

tool: D6: %al, %eax

assistant: ```c
ule() {
  ot("cmpl");
  ot("%eax, %edx");
  nl();
  ot("setbe");
  ot("%al");
  nl();
  ot("movzbl");
  ot("%al, %eax");
  nl();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <__ctype_toupper_loc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0xffffff80,-0xc(%rbp)
  jmp    L1
L14:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0xff,-0xc(%rbp)
  jle    L14
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type_guessed: string

tool: D8: %d->0x%x


assistant: ```c
int main(int argc, char *argv[]) {
  const int **upper_loc = __ctype_toupper_loc();
  for (int i = -128; i < 256; i++) {
    printf("%d->0x%x\n", i, (*upper_loc)[i]);
  }
  return 0;
}
```