ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<dirname>:
  endbr64
  push   %r13
  mov    $0x2f,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L37
  sub    %rbp,%rax
  mov    %eax,%r13d
  lea    0x1(%rax),%edi
  movslq %eax,%rbx
L18:
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L22
L21:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  lea    D8(%rip),%rsi
  xor    %edi,%edi
  call   <fatal@plt>
  jmp    L21
L37:
  mov    $0x1,%ebx
  mov    $0x2,%edi
  lea    D1(%rip),%rbp
  mov    $0x1,%r13d
  jmp    L18
```

tool_calls: name: read_data
arguments: tag: D8
data_type: string
name: read_data
arguments: tag: D1
data_type: string

tool: D8: dirname(): malloc() failed

tool: D1: ./

assistant: ```c
extern char *dirname(const char *s) {
  char *p = strrchr(s, '/');
  if (!p)
    s = "./";
  int len = (p ? p - s : 1);
  char *t = (char *)malloc(len + 1);
  if (!t)
    fatal(0, "dirname(): malloc() failed");
  memcpy(t, s, len);
  *(t + len) = 0;
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<dirname>:
  endbr64
  push   %r13
  mov    $0x2f,%esi
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strrchr@plt>
  test   %rax,%rax
  je     L10
  sub    %rbp,%rax
  mov    %eax,%r13d
  lea    0x1(%rax),%edi
  movslq %eax,%rbx
L24:
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L34
L30:
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  lea    D5(%rip),%rsi
  xor    %edi,%edi
  call   <fatal@plt>
  jmp    L30
L10:
  mov    $0x1,%ebx
  mov    $0x2,%edi
  lea    D14(%rip),%rbp
  mov    $0x1,%r13d
  jmp    L24
```

tool_calls: name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D14
type: string

tool: D5: dirname(): malloc() failed

tool: D14: ./

assistant: ```c
extern char *dirname(const char *s) {
  char *p = strrchr(s, '/');
  if (!p)
    s = "./";
  int len = (p ? p - s : 1);
  char *t = (char *)malloc(len + 1);
  if (!t)
    fatal(0, "dirname(): malloc() failed");
  memcpy(t, s, len);
  *(t + len) = 0;
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_strequ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L24
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    $0x1,%eax
  jmp    L29
L10:
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L24:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L16
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  while ((int)*s1 == (int)*s2) {
    if (*s1 == '\0')
      return (1);
    s1++;
    s2++;
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_strequ>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L7
  mov    $0x1,%eax
L8:
  test   %dl,%dl
  je     L14
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  je     L8
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  while ((int)*s1 == (int)*s2) {
    if (*s1 == '\0')
      return (1);
    s1++;
    s2++;
  }
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ft_strequ>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L9
  mov    $0x1,%eax
  jmp    L11
  nopw   0x0(%rax,%rax,1)
L39:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  jne    L9
L11:
  test   %dl,%dl
  jne    L39
  mov    $0x1,%eax
  ret
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  while ((int)*s1 == (int)*s2) {
    if (*s1 == '\0')
      return (1);
    s1++;
    s2++;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_strequ>:
  endbr64
  movzbl (%rdi),%edx
  cmp    (%rsi),%dl
  jne    L27
  mov    $0x1,%eax
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L29:
  movzbl (%rdi,%rax,1),%edx
  add    $0x1,%rax
  cmp    -0x1(%rsi,%rax,1),%dl
  jne    L27
L12:
  test   %dl,%dl
  jne    L29
  mov    $0x1,%eax
  ret
L27:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ft_strequ(char const *s1, char const *s2) {
  while ((int)*s1 == (int)*s2) {
    if (*s1 == '\0')
      return (1);
    s1++;
    s2++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<duracion_borrado_clasico>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  mov    %ecx,-0x34(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L15
L14:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <get_time@plt>
  mov    -0x28(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    $0x0,%eax
  call   <get_time@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  addl   $0x1,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L14
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double duracion_borrado_clasico(int iter, char *str, int first, int last) {
  int i;
  double time = 0;
  int tam_str = strlen(str);
  for (i = 0; i < iter; i++) {
    char *temp = (char *)malloc(tam_str * sizeof(char));
    get_time();
    strncpy(temp, str, first);
    strcpy(temp + first, str + last);
    time += get_time();
    free(temp);
  }
  return time;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<duracion_borrado_clasico>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r15d
  mov    %rsi,%r14
  mov    %edx,%r12d
  mov    %ecx,%r13d
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,0xc(%rsp)
  test   %r15d,%r15d
  jle    L26
  pxor   %xmm2,%xmm2
  movsd  %xmm2,(%rsp)
  mov    $0x0,%ebp
  movslq %r13d,%r13
  add    %r14,%r13
L4:
  mov    0xc(%rsp),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  call   <get_time@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  movslq %r12d,%rdi
  add    %rbx,%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  mov    $0x0,%eax
  call   <get_time@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  (%rsp),%xmm0
  movsd  %xmm0,(%rsp)
  mov    %rbx,%rdi
  call   <free@plt>
  add    $0x1,%ebp
  cmp    %ebp,%r15d
  jne    L4
L6:
  movsd  (%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,(%rsp)
  jmp    L6
```

assistant: ```c
double duracion_borrado_clasico(int iter, char *str, int first, int last) {
  int i;
  double time = 0;
  int tam_str = strlen(str);
  for (i = 0; i < iter; i++) {
    char *temp = (char *)malloc(tam_str * sizeof(char));
    get_time();
    strncpy(temp, str, first);
    strcpy(temp + first, str + last);
    time += get_time();
    free(temp);
  }
  return time;
}
```
user: Translate the below assembly code into C programming language:

```asm
<duracion_borrado_clasico>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x28,%rsp
  mov    %edi,0x14(%rsp)
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %r15d,%r15d
  jle    L23
  mov    %eax,%r14d
  movslq %r13d,%rax
  pxor   %xmm2,%xmm2
  add    %r12,%rbx
  mov    %rax,0x18(%rsp)
  xor    %r15d,%r15d
  movsd  %xmm2,0x8(%rsp)
  xchg   %ax,%ax
L27:
  mov    %r14d,%edi
  add    $0x1,%r15d
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <get_time@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    0x18(%rsp),%rax
  mov    %rbx,%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <strcpy@plt>
  xor    %eax,%eax
  call   <get_time@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  cmp    %r15d,0x14(%rsp)
  jne    L27
L25:
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L25
```

assistant: ```c
double duracion_borrado_clasico(int iter, char *str, int first, int last) {
  int i;
  double time = 0;
  int tam_str = strlen(str);
  for (i = 0; i < iter; i++) {
    char *temp = (char *)malloc(tam_str * sizeof(char));
    get_time();
    strncpy(temp, str, first);
    strcpy(temp + first, str + last);
    time += get_time();
    free(temp);
  }
  return time;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<duracion_borrado_clasico>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  movslq %ecx,%rbx
  sub    $0x28,%rsp
  mov    %edi,0x14(%rsp)
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %r15d,%r15d
  jle    L13
  mov    %eax,%r14d
  movslq %r13d,%rax
  pxor   %xmm2,%xmm2
  add    %r12,%rbx
  mov    %rax,0x18(%rsp)
  xor    %r15d,%r15d
  movsd  %xmm2,0x8(%rsp)
  xchg   %ax,%ax
L26:
  mov    %r14d,%edi
  add    $0x1,%r15d
  call   <malloc@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <get_time@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncpy@plt>
  mov    0x18(%rsp),%rax
  mov    %rbx,%rsi
  lea    0x0(%rbp,%rax,1),%rdi
  call   <strcpy@plt>
  xor    %eax,%eax
  call   <get_time@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rdi
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  call   <free@plt>
  cmp    %r15d,0x14(%rsp)
  jne    L26
L22:
  movsd  0x8(%rsp),%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  pxor   %xmm3,%xmm3
  movsd  %xmm3,0x8(%rsp)
  jmp    L22
```

assistant: ```c
double duracion_borrado_clasico(int iter, char *str, int first, int last) {
  int i;
  double time = 0;
  int tam_str = strlen(str);
  for (i = 0; i < iter; i++) {
    char *temp = (char *)malloc(tam_str * sizeof(char));
    get_time();
    strncpy(temp, str, first);
    strcpy(temp + first, str + last);
    time += get_time();
    free(temp);
  }
  return time;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <init_matrices@plt>
  mov    $0x0,%eax
  call   <sanity_check@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int rank, nproc;
  int idx_start, idx_end;
  init_matrices();
  sanity_check();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init_matrices@plt>
  mov    $0x0,%eax
  call   <sanity_check@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int rank, nproc;
  int idx_start, idx_end;
  init_matrices();
  sanity_check();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_matrices@plt>
  xor    %eax,%eax
  call   <sanity_check@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int rank, nproc;
  int idx_start, idx_end;
  init_matrices();
  sanity_check();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <init_matrices@plt>
  xor    %eax,%eax
  call   <sanity_check@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  int rank, nproc;
  int idx_start, idx_end;
  init_matrices();
  sanity_check();
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bitLength>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L17:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
L19:
  cmpl   $0x0,-0x14(%rbp)
  jg     L17
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int bitLength(ulong v) {
  int result = 0;
  while (v > 0) {
    v >>= 1;
    result++;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitLength>:
  endbr64
  test   %edi,%edi
  jle    L17
  mov    $0x0,%eax
L19:
  sar    %edi
  add    $0x1,%eax
  test   %edi,%edi
  jg     L19
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int bitLength(ulong v) {
  int result = 0;
  while (v > 0) {
    v >>= 1;
    result++;
  }
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitLength>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L5
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%eax
  sar    %edi
  jne    L3
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  ret
```

assistant: ```c
int bitLength(ulong v) {
  int result = 0;
  while (v > 0) {
    v >>= 1;
    result++;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bitLength>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  jle    L16
  nopw   0x0(%rax,%rax,1)
L4:
  add    $0x1,%eax
  sar    %edi
  jne    L4
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
int bitLength(ulong v) {
  int result = 0;
  while (v > 0) {
    v >>= 1;
    result++;
  }
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sigmaRecalc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x24(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm2
  mov    -0x24(%rbp),%eax
  cltq
  imul   $0x1f40,%rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  %xmm2,%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sigmaRecalc(double A[1000][1000], double sigma[1000], int index, int n, int m) {
  int i, j;
  for (j = 0; j < m; j++)
    sigma[j] -= (A[index][j] * A[index][j]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sigmaRecalc>:
  endbr64
  test   %r8d,%r8d
  jle    L17
  movslq %edx,%rdx
  imul   $0x1f40,%rdx,%rdx
  add    %rdx,%rdi
  mov    %r8d,%r8d
  mov    $0x0,%eax
L1:
  movsd  (%rdi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L1
L17:
  ret
```

assistant: ```c
void sigmaRecalc(double A[1000][1000], double sigma[1000], int index, int n, int m) {
  int i, j;
  for (j = 0; j < m; j++)
    sigma[j] -= (A[index][j] * A[index][j]);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sigmaRecalc>:
  endbr64
  test   %r8d,%r8d
  jle    L2
  movslq %edx,%rdx
  movslq %r8d,%r8
  xor    %eax,%eax
  imul   $0x1f40,%rdx,%rdx
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L10:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  (%rsi,%rax,8),%xmm1
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%r8
  jne    L10
L2:
  ret
```

assistant: ```c
void sigmaRecalc(double A[1000][1000], double sigma[1000], int index, int n, int m) {
  int i, j;
  for (j = 0; j < m; j++)
    sigma[j] -= (A[index][j] * A[index][j]);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sigmaRecalc>:
  endbr64
  mov    %rsi,%rcx
  test   %r8d,%r8d
  jle    L31
  movslq %edx,%rdx
  imul   $0x1f40,%rdx,%rax
  lea    (%rdi,%rax,1),%rsi
  lea    0x8(%rdi,%rax,1),%rax
  cmp    %rax,%rcx
  je     L33
  cmp    $0x1,%r8d
  je     L33
  mov    %r8d,%edx
  xor    %eax,%eax
  shr    %edx
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L14:
  movupd (%rsi,%rax,1),%xmm0
  movupd (%rcx,%rax,1),%xmm1
  mulpd  %xmm0,%xmm0
  subpd  %xmm0,%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L14
  mov    %r8d,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%r8d
  je     L31
  mov    %eax,%edx
  cltq
  movsd  (%rsi,%rax,8),%xmm0
  lea    (%rcx,%rdx,8),%rdx
  movsd  (%rdx),%xmm1
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rdx)
  ret
  nopl   0x0(%rax)
L33:
  movslq %r8d,%r8
  xor    %eax,%eax
  nopl   (%rax)
L7:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  (%rcx,%rax,8),%xmm1
  mulsd  %xmm0,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L7
L31:
  ret
```

assistant: ```c
void sigmaRecalc(double A[1000][1000], double sigma[1000], int index, int n, int m) {
  int i, j;
  for (j = 0; j < m; j++)
    sigma[j] -= (A[index][j] * A[index][j]);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
L35:
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%rax
  test   %rax,%rax
  jne    L6
  mov    -0x18(%rbp),%rax
  test   %rax,%rax
  je     L32
L6:
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lcm@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    $0x0,%edx
  div    %rsi
  imul   %rcx,%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L32:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D12
type: string
name: unpack_data
arguments: data_label: D16
type: string

tool: D12: %llu%llu

tool: D16: %llu


assistant: ```c
int main() {
  unsigned long long int w, h;
  unsigned long long int num;
  while (1) {
    scanf("%llu%llu", &w, &h);
    if (w == 0 && h == 0)
      break;
    num = lcm(w, h);
    printf("%llu\n", ((num / h) * (num / w)));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    D16(%rip),%rbx
  lea    D15(%rip),%r13
  jmp    L18
L15:
  call   <lcm@plt>
  mov    %rax,%rcx
  mov    $0x0,%edx
  divq   0x10(%rsp)
  mov    %rax,%rsi
  mov    %rcx,%rax
  mov    $0x0,%edx
  divq   0x8(%rsp)
  imul   %rax,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
L18:
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  mov    0x10(%rsp),%rsi
  mov    %rdi,%rax
  or     %rsi,%rax
  jne    L15
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D16
data_type: string
name: extract_symbolic_data
arguments: tag: D15
data_type: string

tool: D16: %llu%llu

tool: D15: %llu


assistant: ```c
int main() {
  unsigned long long int w, h;
  unsigned long long int num;
  while (1) {
    scanf("%llu%llu", &w, &h);
    if (w == 0 && h == 0)
      break;
    num = lcm(w, h);
    printf("%llu\n", ((num / h) * (num / w)));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D11(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L1:
  call   <lcm@plt>
  xor    %edx,%edx
  mov    %r13,%rdi
  mov    %rax,%rcx
  divq   0x10(%rsp)
  xor    %edx,%edx
  mov    %rax,%rsi
  mov    %rcx,%rax
  divq   0x8(%rsp)
  imul   %rax,%rsi
  call   <printf@plt>
L4:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r12,%rdx
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  mov    0x10(%rsp),%rsi
  mov    %rdi,%rax
  or     %rsi,%rax
  jne    L1
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D17
type: string
name: retrieve_data
arguments: tag: D11
type: string

tool: D17: %llu


tool: D11: %llu%llu

assistant: ```c
int main() {
  unsigned long long int w, h;
  unsigned long long int num;
  while (1) {
    scanf("%llu%llu", &w, &h);
    if (w == 0 && h == 0)
      break;
    num = lcm(w, h);
    printf("%llu\n", ((num / h) * (num / w)));
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0x8(%rsp),%rbp
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L16:
  call   <lcm@plt>
  xor    %edx,%edx
  mov    %r13,%rdi
  mov    %rax,%rcx
  divq   0x10(%rsp)
  xor    %edx,%edx
  mov    %rax,%rsi
  mov    %rcx,%rax
  divq   0x8(%rsp)
  imul   %rax,%rsi
  call   <printf@plt>
L20:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    %r12,%rdx
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  mov    0x10(%rsp),%rsi
  mov    %rdi,%rax
  or     %rsi,%rax
  jne    L16
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D10
type_infered: string
name: retrieve_data
arguments: data_label: D8
type_infered: string

tool: D10: %llu


tool: D8: %llu%llu

assistant: ```c
int main() {
  unsigned long long int w, h;
  unsigned long long int num;
  while (1) {
    scanf("%llu%llu", &w, &h);
    if (w == 0 && h == 0)
      break;
    num = lcm(w, h);
    printf("%llu\n", ((num / h) * (num / w)));
  }
  return 0;
}
```