user: 请从给定的汇编指令推导出C源代码：

```asm
<findTwoNonRepeatElements>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  test   %esi,%esi
  jle    L145
  lea    -0x1(%rsi),%ebp
  cmp    $0x2,%ebp
  jbe    L130
  mov    %esi,%eax
  mov    %rdi,%rdx
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  sub    $0x1,%eax
  shl    $0x4,%rax
  lea    0x10(%rdi,%rax,1),%rax
  nopl   0x0(%rax)
L127:
  movdqu (%rdx),%xmm2
  add    $0x10,%rdx
  pxor   %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L127
  movdqa %xmm0,%xmm1
  mov    %r12d,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%ebx
  test   $0x3,%r12b
  je     L15
L150:
  mov    0x8(%rsp),%rsi
  movslq %eax,%rdx
  lea    0x0(,%rdx,4),%rcx
  xor    (%rsi,%rdx,4),%ebx
  lea    0x1(%rax),%edx
  cmp    %edx,%r12d
  jle    L15
  add    $0x2,%eax
  xor    0x4(%rsi,%rcx,1),%ebx
  cmp    %eax,%r12d
  jle    L15
  xor    0x8(%rsi,%rcx,1),%ebx
L15:
  mov    %ebx,%esi
  lea    D76(%rip),%rdi
  mov    %ebx,%r13d
  call   <printf@plt>
  and    $0x1,%r13d
  jne    L8
L104:
  xor    %ebp,%ebp
  nopl   0x0(%rax,%rax,1)
L83:
  sar    %ebx
  add    $0x1,%ebp
  mov    %ebx,%r13d
  and    $0x1,%r13d
  je     L83
  mov    %ebp,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L117:
  add    %r13d,%r13d
  sub    $0x1,%ebp
  jne    L117
  mov    %r13d,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L108
  lea    -0x1(%r12),%ebp
L159:
  mov    0x8(%rsp),%rax
  lea    0x4(%rax,%rbp,4),%rcx
  jmp    L24
  nopl   (%rax)
L63:
  add    $0x4,%rax
  xor    %edx,(%r14)
  cmp    %rcx,%rax
  je     L108
L24:
  mov    (%rax),%edx
  test   %r13d,%edx
  jne    L63
  add    $0x4,%rax
  xor    %edx,(%r15)
  cmp    %rcx,%rax
  jne    L24
L108:
  mov    (%r14),%esi
  lea    D64(%rip),%rdi
  call   <printf@plt>
  mov    (%r15),%esi
  add    $0x18,%rsp
  lea    D53(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %esi,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L159
  nopl   0x0(%rax)
L145:
  xor    %esi,%esi
  lea    D76(%rip),%rdi
  xor    %ebx,%ebx
  call   <printf@plt>
  jmp    L104
L130:
  xor    %ebx,%ebx
  xor    %eax,%eax
  jmp    L150
```

tool_calls: name: retrieve_data
arguments: label: D76
datatype: string
name: retrieve_data
arguments: label: D10
datatype: string
name: retrieve_data
arguments: label: D20
datatype: string
name: retrieve_data
arguments: label: D64
datatype: string
name: retrieve_data
arguments: label: D53
datatype: string

tool: D76: Sum = %04X


tool: D10: First 1 from left (position from 0) = %d


tool: D20: Flag = %04X


tool: D64: X = %d


tool: D53: Y = %d


assistant: ```c
void findTwoNonRepeatElements(int *pdata, int size, int *pX, int *pY) {
  int i;
  int sum = 0;
  for (i = 0; i < size; i++) {
    sum ^= pdata[i];
  }
  printf("Sum = %04X\n", sum);
  i = 0;
  while ((sum & 1) == 0) {
    sum >>= 1;
    i++;
  }
  printf("First 1 from left (position from 0) = %d\n", i);
  int flag = 1;
  while (i > 0) {
    flag <<= 1;
    i--;
  }
  printf("Flag = %04X\n", flag);
  for (i = 0; i < size; i++) {
    if (pdata[i] & flag) {
      *pX ^= pdata[i];
    } else {
      *pY ^= pdata[i];
    }
  }
  printf("X = %d\n", *pX);
  printf("Y = %d\n", *pY);
}
```