ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rdi
  lea    D70(%rip),%rbp
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D58(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D15(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D36(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D45(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D21(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D40
data_type: string
name: unpack_data
arguments: label: D70
data_type: string
name: unpack_data
arguments: label: D58
data_type: string
name: unpack_data
arguments: label: D38
data_type: string
name: unpack_data
arguments: label: D15
data_type: string
name: unpack_data
arguments: label: D36
data_type: string
name: unpack_data
arguments: label: D45
data_type: string
name: unpack_data
arguments: label: D21
data_type: string

tool: D40: USA

tool: D70: %d


tool: D58: leetcode

tool: D38: Google

tool: D15: U

tool: D36: l

tool: D45: GooglE

tool: D21: GoogLe

assistant: ```c
int main(void) {
  printf("%d\n", detectCapitalUse("USA"));
  printf("%d\n", detectCapitalUse("leetcode"));
  printf("%d\n", detectCapitalUse("Google"));
  printf("%d\n", detectCapitalUse("U"));
  printf("%d\n", detectCapitalUse("l"));
  printf("%d\n", detectCapitalUse("GooglE"));
  printf("%d\n", detectCapitalUse("GoogLe"));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D63(%rip),%rdi
  lea    D58(%rip),%rbp
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D57(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D24(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D0(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  lea    D56(%rip),%rdi
  call   <detectCapitalUse@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D63
type_infered: string
name: retrieve_data
arguments: label: D58
type_infered: string
name: retrieve_data
arguments: label: D57
type_infered: string
name: retrieve_data
arguments: label: D70
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D0
type_infered: string
name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D56
type_infered: string

tool: D63: USA

tool: D58: %d


tool: D57: leetcode

tool: D70: Google

tool: D24: U

tool: D0: l

tool: D8: GooglE

tool: D56: GoogLe

assistant: ```c
int main(void) {
  printf("%d\n", detectCapitalUse("USA"));
  printf("%d\n", detectCapitalUse("leetcode"));
  printf("%d\n", detectCapitalUse("Google"));
  printf("%d\n", detectCapitalUse("U"));
  printf("%d\n", detectCapitalUse("l"));
  printf("%d\n", detectCapitalUse("GooglE"));
  printf("%d\n", detectCapitalUse("GoogLe"));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ofl_hex_to_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <open_memstream@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ofl_hex_print@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
char *ofl_hex_to_string(uint8_t *buf, size_t buf_size) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_hex_print(stream, buf, buf_size);
  fclose(stream);
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ofl_hex_to_string>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <open_memstream@plt>
  mov    %rax,%rbx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <ofl_hex_print@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ofl_hex_to_string(uint8_t *buf, size_t buf_size) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_hex_print(stream, buf, buf_size);
  fclose(stream);
  return str;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ofl_hex_to_string>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <open_memstream@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <ofl_hex_print@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ofl_hex_to_string(uint8_t *buf, size_t buf_size) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_hex_print(stream, buf, buf_size);
  fclose(stream);
  return str;
}
```
user: What is the c source code of the assembly code below:

```asm
<ofl_hex_to_string>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <open_memstream@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <ofl_hex_print@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ofl_hex_to_string(uint8_t *buf, size_t buf_size) {
  char *str;
  size_t str_size;
  FILE *stream = open_memstream(&str, &str_size);
  ofl_hex_print(stream, buf, buf_size);
  fclose(stream);
  return str;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<encbe32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0xc(%rax),%rdx
  mov    -0x14(%rbp),%eax
  movzbl %al,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  movzbl %cl,%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void encbe32(const uint32_t n, void *_b) {
  uint8_t *b = (uint8_t *)_b;
  b[3] = (n >> 0) & 0xff;
  b[2] = (n >> 8) & 0xff;
  b[1] = (n >> 16) & 0xff;
  b[0] = (n >> 24) & 0xff;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<encbe32>:
  endbr64
  mov    %edi,%eax
  movzbl %dil,%edx
  mov    %edx,0xc(%rsi)
  movzbl %ah,%edx
  mov    %edx,0x8(%rsi)
  mov    %edi,%edx
  sar    $0x10,%edx
  and    $0xff,%edx
  mov    %edx,0x4(%rsi)
  shr    $0x18,%eax
  mov    %eax,(%rsi)
  ret
```

assistant: ```c
void encbe32(const uint32_t n, void *_b) {
  uint8_t *b = (uint8_t *)_b;
  b[3] = (n >> 0) & 0xff;
  b[2] = (n >> 8) & 0xff;
  b[1] = (n >> 16) & 0xff;
  b[0] = (n >> 24) & 0xff;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<encbe32>:
  endbr64
  mov    %edi,%eax
  movzbl %dil,%edx
  mov    %edx,0xc(%rsi)
  movzbl %ah,%edx
  shr    $0x18,%eax
  mov    %edx,0x8(%rsi)
  mov    %edi,%edx
  sar    $0x10,%edx
  mov    %eax,(%rsi)
  and    $0xff,%edx
  mov    %edx,0x4(%rsi)
  ret
```

assistant: ```c
void encbe32(const uint32_t n, void *_b) {
  uint8_t *b = (uint8_t *)_b;
  b[3] = (n >> 0) & 0xff;
  b[2] = (n >> 8) & 0xff;
  b[1] = (n >> 16) & 0xff;
  b[0] = (n >> 24) & 0xff;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<encbe32>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%edx
  mov    %edi,%eax
  shr    $0x18,%ecx
  sar    $0x10,%edx
  movd   %ecx,%xmm0
  movzbl %dl,%edx
  movzbl %ah,%ecx
  movzbl %dil,%eax
  movd   %ecx,%xmm1
  movd   %eax,%xmm2
  movd   %edx,%xmm3
  punpckldq %xmm2,%xmm1
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rsi)
  ret
```

assistant: ```c
void encbe32(const uint32_t n, void *_b) {
  uint8_t *b = (uint8_t *)_b;
  b[3] = (n >> 0) & 0xff;
  b[2] = (n >> 8) & 0xff;
  b[1] = (n >> 16) & 0xff;
  b[0] = (n >> 24) & 0xff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<normalise_vector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L33:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L33
  movl   $0x0,-0xc(%rbp)
  jmp    L32
L18:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L32:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void normalise_vector(double *vector, int length) {
  double z = 0;
  for (int i = 0; i < length; i++)
    z += vector[i];
  for (int i = 0; i < length; i++)
    vector[i] = vector[i] / z;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<normalise_vector>:
  endbr64
  test   %esi,%esi
  jle    L9
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
  pxor   %xmm1,%xmm1
L20:
  addsd  (%rdi),%xmm1
  add    $0x8,%rdi
  cmp    %rdx,%rdi
  jne    L20
L13:
  movsd  (%rax),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L13
L9:
  ret
```

assistant: ```c
void normalise_vector(double *vector, int length) {
  double z = 0;
  for (int i = 0; i < length; i++)
    z += vector[i];
  for (int i = 0; i < length; i++)
    vector[i] = vector[i] / z;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<normalise_vector>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  pxor   %xmm1,%xmm1
  lea    0x8(%rdi,%rax,8),%rdx
  mov    %rdi,%rax
  nopw   0x0(%rax,%rax,1)
L15:
  addsd  (%rax),%xmm1
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L15
  nopl   (%rax)
L3:
  movsd  (%rdi),%xmm0
  add    $0x8,%rdi
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rdi)
  cmp    %rdx,%rdi
  jne    L3
L9:
  ret
```

assistant: ```c
void normalise_vector(double *vector, int length) {
  double z = 0;
  for (int i = 0; i < length; i++)
    z += vector[i];
  for (int i = 0; i < length; i++)
    vector[i] = vector[i] / z;
}
```
user: Translate the below assembly code into C programming language:

```asm
<normalise_vector>:
  endbr64
  mov    %rdi,%rdx
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L45
  cmp    $0x1,%esi
  je     L51
  shr    %esi
  mov    %rdi,%rax
  lea    0x10(%rdi),%rdi
  sub    $0x1,%esi
  pxor   %xmm0,%xmm0
  shl    $0x4,%rsi
  add    %rdi,%rsi
  nopl   0x0(%rax)
L13:
  movsd  (%rax),%xmm1
  add    $0x10,%rax
  addsd  %xmm1,%xmm0
  movsd  -0x8(%rax),%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rsi,%rax
  jne    L13
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%cl
  je     L8
L30:
  cltq
  addsd  (%rdx,%rax,8),%xmm0
  cmp    $0x1,%ecx
  je     L41
  lea    0x10(%rdx),%rdi
L8:
  mov    %ecx,%esi
  movapd %xmm0,%xmm2
  mov    %rdx,%rax
  shr    %esi
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%esi
  shl    $0x4,%rsi
  add    %rdi,%rsi
  nopl   (%rax)
L79:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  divpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rax,%rsi
  jne    L79
  mov    %ecx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%ecx
  je     L69
L44:
  cltq
  lea    (%rdx,%rax,8),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
L45:
  ret
  nopw   0x0(%rax,%rax,1)
L41:
  xor    %eax,%eax
  jmp    L44
  nopl   0x0(%rax)
L69:
  ret
L51:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L30
```

assistant: ```c
void normalise_vector(double *vector, int length) {
  double z = 0;
  for (int i = 0; i < length; i++)
    z += vector[i];
  for (int i = 0; i < length; i++)
    vector[i] = vector[i] / z;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L28
L7:
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x10(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%edx
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %esi,%edx
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  test   %eax,%eax
  jg     L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
type: string
name: disassemble_data
arguments: tag: D17
type: string
name: disassemble_data
arguments: tag: D23
type: string

tool: D9: %d

tool: D17: %d %d

tool: D23: %d %d %d %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  while (n-- > 0) {
    int K, N;
    scanf("%d %d", &K, &N);
    int sq = N * N;
    printf("%d %d %d %d\n", K, (sq + N) >> 1, sq, sq + N);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L4
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D27(%rip),%rbp
  lea    D28(%rip),%rbx
L19:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%r8d
  mov    %r8d,%ecx
  imul   %r8d,%ecx
  add    %ecx,%r8d
  mov    %r8d,%edx
  sar    %edx
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L19
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D27
type: string
name: retrieve_data
arguments: label: D28
type: string

tool: D0: %d

tool: D27: %d %d

tool: D28: %d %d %d %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  while (n-- > 0) {
    int K, N;
    scanf("%d %d", &K, &N);
    int sq = N * N;
    printf("%d %d %d %d\n", K, (sq + N) >> 1, sq, sq + N);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L28
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D28(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L22:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  mov    %r8d,%ecx
  imul   %r8d,%ecx
  add    %ecx,%r8d
  mov    %r8d,%edx
  sar    %edx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L22
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D3
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D28
data_type: string

tool: D3: %d

tool: D18: %d %d

tool: D28: %d %d %d %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  while (n-- > 0) {
    int K, N;
    scanf("%d %d", &K, &N);
    int sq = N * N;
    printf("%d %d %d %d\n", K, (sq + N) >> 1, sq, sq + N);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D11(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jle    L15
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D6(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L14:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%r8d
  mov    0x10(%rsp),%esi
  mov    %rbx,%rdi
  mov    %r8d,%ecx
  imul   %r8d,%ecx
  add    %ecx,%r8d
  mov    %r8d,%edx
  sar    %edx
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  jg     L14
L15:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D11: %d

tool: D18: %d %d

tool: D6: %d %d %d %d


assistant: ```c
int main() {
  int n, i;
  scanf("%d", &n);
  while (n-- > 0) {
    int K, N;
    scanf("%d %d", &K, &N);
    int sq = N * N;
    printf("%d %d %d %d\n", K, (sq + N) >> 1, sq, sq + N);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<UnitVectorNV>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  movss  %xmm0,-0x1c(%rbp)
  movss  %xmm1,-0x20(%rbp)
  movss  %xmm2,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x1c(%rbp),%xmm0
  comisd D36(%rip),%xmm0
  ja     L17
  pxor   %xmm1,%xmm1
  cvtss2sd -0x1c(%rbp),%xmm1
  movsd  D9(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L4
L17:
  movss  -0x20(%rbp),%xmm0
  movss  D0(%rip),%xmm1
  xorps  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  jmp    L8
L4:
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  movss  -0x24(%rbp),%xmm0
  movss  D0(%rip),%xmm1
  xorps  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movss  -0x20(%rbp),%xmm0
  movss  %xmm0,(%rax)
  nop
L8:
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D36
type_infered: f64[2]
name: unpack_data
arguments: tag: D9
type_infered: byte[8]
name: unpack_data
arguments: tag: D0
type_infered: byte[4]

tool: {"D36": [0.1,-0.1]}

tool: {"D9": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

tool: {"D0": [0x00,0x00,0x00,0x80]}

assistant: ```c
void UnitVectorNV(float *wx, float *wy, float *wz, float ux, float uy, float uz) {
  if (ux > 0.1 || ux < -0.1) {
    *wx = -uy;
    *wy = ux;
    *wz = 0.0f;
  } else {
    *wx = 0.0f;
    *wy = -uz;
    *wz = uy;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<UnitVectorNV>:
  endbr64
  pxor   %xmm3,%xmm3
  cvtss2sd %xmm0,%xmm3
  comisd D35(%rip),%xmm3
  ja     L4
  movsd  D18(%rip),%xmm4
  comisd %xmm3,%xmm4
  jbe    L11
L4:
  movaps %xmm1,%xmm2
  xorps  D37(%rip),%xmm2
  pxor   %xmm1,%xmm1
L13:
  movss  %xmm2,(%rdi)
  movss  %xmm0,(%rsi)
  movss  %xmm1,(%rdx)
  ret
L11:
  movaps %xmm2,%xmm0
  xorps  D37(%rip),%xmm0
  pxor   %xmm2,%xmm2
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: data_label: D35
type_infered: f64[2]
name: retrieve_data
arguments: data_label: D18
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D37
type_infered: byte[16]

tool: {"D35": [0.1,-0.1]}

tool: {"D18": [0x9a,0x99,0x99,0x99,0x99,0x99,0xb9,0xbf]}

tool: {"D37": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
void UnitVectorNV(float *wx, float *wy, float *wz, float ux, float uy, float uz) {
  if (ux > 0.1 || ux < -0.1) {
    *wx = -uy;
    *wy = ux;
    *wz = 0.0f;
  } else {
    *wx = 0.0f;
    *wy = -uz;
    *wz = uy;
  }
}
```