ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<ConvertLine>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x2(%rdi),%rdi
  lea    D16(%rip),%rsi
  call   <strstr@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L27
  movb   $0x0,(%rdx)
  mov    %rsp,%rdx
  lea    0x4(%rsp),%rcx
  lea    0x3c(%rsp),%rax
  push   %rax
  lea    0x40(%rsp),%rax
  push   %rax
  lea    0x44(%rsp),%rax
  push   %rax
  lea    0x48(%rsp),%rax
  push   %rax
  lea    0x4c(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%rax
  push   %rax
  lea    0x54(%rsp),%rax
  push   %rax
  lea    0x58(%rsp),%rax
  push   %rax
  lea    0x5c(%rsp),%rax
  push   %rax
  lea    0x60(%rsp),%rax
  push   %rax
  lea    0x64(%rsp),%rax
  push   %rax
  lea    0x68(%rsp),%rax
  push   %rax
  lea    0x6c(%rsp),%r9
  lea    0x68(%rsp),%r8
  lea    D3(%rip),%rsi
  mov    %rbp,%rdi
  call   <sscanf@plt>
  add    $0x60,%rsp
  test   %eax,%eax
  jle    L7
  mov    %eax,%esi
  mov    $0x0,%edx
L14:
  mov    (%rsp,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L14
L7:
  cltq
L27:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D16
data_type: string
name: read_data
arguments: label: D3
data_type: string

tool: D16:   

tool: D3: %*s %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x

assistant: ```c
size_t ConvertLine(char *InputLine, unsigned char *OutputData) {
  char *End;
  int BytesConverted;
  int Converted[16];
  int i;
  End = strstr(InputLine + 2, "  ");
  if (!End) {
    return (0);
  }
  *End = 0;
  BytesConverted = sscanf(InputLine, "%*s %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x", &Converted[0], &Converted[1], &Converted[2], &Converted[3], &Converted[4], &Converted[5], &Converted[6], &Converted[7], &Converted[8], &Converted[9], &Converted[10], &Converted[11], &Converted[12], &Converted[13], &Converted[14], &Converted[15]);
  for (i = 0; i < BytesConverted; i++) {
    OutputData[i] = (unsigned char)Converted[i];
  }
  return ((size_t)BytesConverted);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ConvertLine>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  add    $0x2,%rdi
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  lea    D11(%rip),%rsi
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  call   <strstr@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  test   %rdx,%rdx
  je     L5
  lea    0x3c(%rsp),%rax
  movb   $0x0,(%rdx)
  mov    %rsp,%rbp
  lea    0x4(%rsp),%rcx
  push   %rax
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %r12,%rdi
  lea    0x40(%rsp),%rax
  push   %rax
  lea    0x44(%rsp),%rax
  push   %rax
  lea    0x48(%rsp),%rax
  push   %rax
  lea    0x4c(%rsp),%rax
  push   %rax
  lea    0x50(%rsp),%rax
  push   %rax
  lea    0x54(%rsp),%rax
  push   %rax
  lea    0x58(%rsp),%rax
  push   %rax
  lea    0x5c(%rsp),%rax
  push   %rax
  lea    0x60(%rsp),%rax
  push   %rax
  lea    0x64(%rsp),%rax
  push   %rax
  lea    0x68(%rsp),%rax
  push   %rax
  lea    0x6c(%rsp),%r9
  lea    0x68(%rsp),%r8
  call   <sscanf@plt>
  mov    %rbp,%rsp
  test   %eax,%eax
  cltq
  jle    L5
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    0x0(%rbp,%rdx,4),%ecx
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  cmp    %rax,%rdx
  jne    L18
L5:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L33
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D11
type_guessed: string
name: read_data
arguments: data_label: D10
type_guessed: string

tool: D11:   

tool: D10: %*s %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x

assistant: ```c
size_t ConvertLine(char *InputLine, unsigned char *OutputData) {
  char *End;
  int BytesConverted;
  int Converted[16];
  int i;
  End = strstr(InputLine + 2, "  ");
  if (!End) {
    return (0);
  }
  *End = 0;
  BytesConverted = sscanf(InputLine, "%*s %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x %x", &Converted[0], &Converted[1], &Converted[2], &Converted[3], &Converted[4], &Converted[5], &Converted[6], &Converted[7], &Converted[8], &Converted[9], &Converted[10], &Converted[11], &Converted[12], &Converted[13], &Converted[14], &Converted[15]);
  for (i = 0; i < BytesConverted; i++) {
    OutputData[i] = (unsigned char)Converted[i];
  }
  return ((size_t)BytesConverted);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<read_symbol_table>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L13
  mov    D51(%rip),%rax
  mov    (%rax),%eax
  jmp    L58
L13:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    D53(%rip),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%ecx
  mov    -0x4(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  test   %rax,%rax
  jns    L8
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L58
L8:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jg     L43
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    D51(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    D21(%rip),%rax
  mov    (%rax),%eax
  jmp    L58
L43:
  mov    $0x0,%eax
L58:
  leave
  ret
```

assistant: ```c
int read_symbol_table(int d, Elf64_Shdr const *section, Elf64_Sym **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Sym *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_symbol_table>:
  endbr64
  test   %rsi,%rsi
  je     L28
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    (%rsi),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  mov    0x4(%rbx),%esi
  mov    D41(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%edi
  call   <lseek@plt>
  test   %rax,%rax
  js     L19
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jle    L32
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
L19:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D43(%rip),%rax
  mov    (%rax),%eax
  jmp    L22
L32:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    D43(%rip),%rdx
  mov    %eax,(%rdx)
  jmp    L22
```

assistant: ```c
int read_symbol_table(int d, Elf64_Shdr const *section, Elf64_Sym **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Sym *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_symbol_table>:
  endbr64
  test   %rsi,%rsi
  je     L34
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rsi),%edi
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    0x4(%rbx),%esi
  mov    %r12d,%edi
  mov    %rax,0x0(%rbp)
  mov    D23(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  test   %rax,%rax
  js     L26
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jle    L6
L24:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  mov    D26(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D26(%rip),%rax
  mov    D0(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L24
  nopl   (%rax)
L26:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D0(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int read_symbol_table(int d, Elf64_Shdr const *section, Elf64_Sym **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Sym *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_symbol_table>:
  endbr64
  test   %rsi,%rsi
  je     L14
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    (%rsi),%edi
  mov    %rsi,%rbx
  call   <malloc@plt>
  mov    0x4(%rbx),%esi
  mov    %r12d,%edi
  mov    %rax,0x0(%rbp)
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  test   %rax,%rax
  js     L11
  mov    (%rbx),%edx
  mov    0x0(%rbp),%rsi
  mov    %r12d,%edi
  call   <read@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jle    L32
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    D42(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L32:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D42(%rip),%rax
  mov    D8(%rip),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  jmp    L31
  nopl   (%rax)
L11:
  mov    0x0(%rbp),%rdi
  call   <free@plt>
  mov    D8(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int read_symbol_table(int d, Elf64_Shdr const *section, Elf64_Sym **table) {
  if (NULL == section)
    return EINVAL;
  *table = (Elf64_Sym *)malloc(section->sh_size);
  if (lseek(d, section->sh_offset, SEEK_SET) < 0) {
    free(*table);
    return errno;
  }
  if (read(d, *table, section->sh_size) <= 0) {
    free(*table);
    return errno = EINVAL;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<compileTerm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <compileFactor@plt>
  mov    $0x0,%eax
  call   <compileTerm2@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void compileTerm(void) {
  compileFactor();
  compileTerm2();
}
```
user: Translate the below assembly code into C programming language:

```asm
<compileTerm>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <compileFactor@plt>
  mov    $0x0,%eax
  call   <compileTerm2@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void compileTerm(void) {
  compileFactor();
  compileTerm2();
}
```
user: Translate the below assembly code into C programming language:

```asm
<compileTerm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <compileFactor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <compileTerm2@plt>
```

assistant: ```c
void compileTerm(void) {
  compileFactor();
  compileTerm2();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<compileTerm>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <compileFactor@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <compileTerm2@plt>
```

assistant: ```c
void compileTerm(void) {
  compileFactor();
  compileTerm2();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <puts@plt>
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%r9d
  movslq %r9d,%r8
  imul   $0x68db8bad,%r8,%rsi
  sar    $0x2c,%rsi
  mov    %r9d,%edx
  sar    $0x1f,%edx
  sub    %edx,%esi
  imul   $0x10624dd3,%r8,%rax
  sar    $0x26,%rax
  sub    %edx,%eax
  imul   $0x51eb851f,%r8,%rcx
  sar    $0x25,%rcx
  sub    %edx,%ecx
  imul   $0x66666667,%r8,%r8
  sar    $0x22,%r8
  sub    %edx,%r8d
  lea    (%r8,%r8,4),%r10d
  add    %r10d,%r10d
  movslq %r8d,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %r8d,%edi
  sar    $0x1f,%edi
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edi
  add    %edi,%edi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %esi,%r11d
  sar    $0x1f,%r11d
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  sub    %r10d,%r9d
  sub    %edi,%r8d
  mov    %eax,%edx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string
name: disassemble_data
arguments: label: D20
type_guessed: string
name: disassemble_data
arguments: label: D39
type_guessed: string
name: disassemble_data
arguments: label: D9
type_guessed: string

tool: D5: Bu program girdiginiz sayinin ilk 5 basamagini soyler.

tool: D20: Bir sayi giriniz: 

tool: D39: %d

tool: D9: Onbinler basamagi:%d
Binler basamagi:%d
Yuzler basamagi:%d
Onlar basamagi:%d
Birler basamagi:%d

assistant: ```c
int main() {
  int sayi1, birler, onlar, yuzler, binler, onbinler;
  printf("Bu program girdiginiz sayinin ilk 5 basamagini soyler.\n");
  printf("Bir sayi giriniz: ");
  scanf("%d", &sayi1);
  onbinler = sayi1 / 10000;
  onbinler = onbinler % 10;
  binler = sayi1 / 1000;
  binler = binler % 10;
  yuzler = sayi1 / 100;
  yuzler = yuzler % 10;
  onlar = sayi1 / 10;
  onlar = onlar % 10;
  birler = sayi1 % 10;
  printf("Onbinler basamagi:%d\nBinler basamagi:%d\nYuzler basamagi:%d\nOnlar basamagi:%d\nBirler basamagi:%d", onbinler, binler, yuzler, onlar, birler);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D32(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%r8
  imul   $0x68db8bad,%r8,%rsi
  mov    %r8,%r9
  mov    %r8d,%edx
  imul   $0x10624dd3,%r8,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%r8,%rcx
  imul   $0x66666667,%r8,%r8
  sar    $0x2c,%rsi
  sar    $0x26,%rax
  sub    %edx,%esi
  sar    $0x25,%rcx
  sub    %edx,%eax
  sar    $0x22,%r8
  sub    %edx,%ecx
  sub    %edx,%r8d
  mov    %ecx,%r11d
  movslq %r8d,%rdx
  mov    %r8d,%edi
  sar    $0x1f,%r11d
  lea    (%r8,%r8,4),%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%edi
  add    %r10d,%r10d
  sar    $0x22,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  add    %edi,%edi
  sar    $0x22,%rdx
  sub    %r11d,%edx
  mov    %eax,%r11d
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%r11d
  sub    %edi,%r8d
  sub    %r10d,%r9d
  sub    %r11d,%edx
  mov    %esi,%r11d
  lea    D4(%rip),%rdi
  lea    (%rdx,%rdx,4),%edx
  sar    $0x1f,%r11d
  add    %edx,%edx
  sub    %edx,%eax
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D32
type_guessed: string
name: read_data
arguments: data_label: D21
type_guessed: string
name: read_data
arguments: data_label: D15
type_guessed: string
name: read_data
arguments: data_label: D4
type_guessed: string

tool: D32: Bu program girdiginiz sayinin ilk 5 basamagini soyler.

tool: D21: Bir sayi giriniz: 

tool: D15: %d

tool: D4: Onbinler basamagi:%d
Binler basamagi:%d
Yuzler basamagi:%d
Onlar basamagi:%d
Birler basamagi:%d

assistant: ```c
int main() {
  int sayi1, birler, onlar, yuzler, binler, onbinler;
  printf("Bu program girdiginiz sayinin ilk 5 basamagini soyler.\n");
  printf("Bir sayi giriniz: ");
  scanf("%d", &sayi1);
  onbinler = sayi1 / 10000;
  onbinler = onbinler % 10;
  binler = sayi1 / 1000;
  binler = binler % 10;
  yuzler = sayi1 / 100;
  yuzler = yuzler % 10;
  onlar = sayi1 / 10;
  onlar = onlar % 10;
  birler = sayi1 % 10;
  printf("Onbinler basamagi:%d\nBinler basamagi:%d\nYuzler basamagi:%d\nOnlar basamagi:%d\nBirler basamagi:%d", onbinler, binler, yuzler, onlar, birler);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D6(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D22(%rip),%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%r8
  imul   $0x68db8bad,%r8,%rsi
  mov    %r8,%r9
  mov    %r8d,%edx
  imul   $0x10624dd3,%r8,%rax
  sar    $0x1f,%edx
  imul   $0x51eb851f,%r8,%rcx
  imul   $0x66666667,%r8,%r8
  sar    $0x2c,%rsi
  sar    $0x26,%rax
  sub    %edx,%esi
  sar    $0x25,%rcx
  sub    %edx,%eax
  sar    $0x22,%r8
  sub    %edx,%ecx
  sub    %edx,%r8d
  mov    %ecx,%r11d
  movslq %r8d,%rdx
  mov    %r8d,%edi
  sar    $0x1f,%r11d
  lea    (%r8,%r8,4),%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%edi
  add    %r10d,%r10d
  sar    $0x22,%rdx
  sub    %edi,%edx
  lea    (%rdx,%rdx,4),%edi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  add    %edi,%edi
  sar    $0x22,%rdx
  sub    %r11d,%edx
  mov    %eax,%r11d
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%ecx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%r11d
  sub    %edi,%r8d
  sub    %r10d,%r9d
  sub    %r11d,%edx
  mov    %esi,%r11d
  lea    D37(%rip),%rdi
  lea    (%rdx,%rdx,4),%edx
  sar    $0x1f,%r11d
  add    %edx,%edx
  sub    %edx,%eax
  movslq %esi,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sub    %r11d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%esi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string
name: read_data
arguments: data_tag: D11
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string
name: read_data
arguments: data_tag: D37
type_guessed: string

tool: D6: Bu program girdiginiz sayinin ilk 5 basamagini soyler.

tool: D11: Bir sayi giriniz: 

tool: D22: %d

tool: D37: Onbinler basamagi:%d
Binler basamagi:%d
Yuzler basamagi:%d
Onlar basamagi:%d
Birler basamagi:%d

assistant: ```c
int main() {
  int sayi1, birler, onlar, yuzler, binler, onbinler;
  printf("Bu program girdiginiz sayinin ilk 5 basamagini soyler.\n");
  printf("Bir sayi giriniz: ");
  scanf("%d", &sayi1);
  onbinler = sayi1 / 10000;
  onbinler = onbinler % 10;
  binler = sayi1 / 1000;
  binler = binler % 10;
  yuzler = sayi1 / 100;
  yuzler = yuzler % 10;
  onlar = sayi1 / 10;
  onlar = onlar % 10;
  birler = sayi1 % 10;
  printf("Onbinler basamagi:%d\nBinler basamagi:%d\nYuzler basamagi:%d\nOnlar basamagi:%d\nBirler basamagi:%d", onbinler, binler, yuzler, onlar, birler);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<delay_ms>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x0,%eax
  call   <clk_get_cpu_rate@plt>
  movslq %eax,%rdx
  imul   $0x57619f1,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L32
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L33
L38:
  nop
  subl   $0x1,-0x8(%rbp)
L33:
  cmpl   $0x0,-0x8(%rbp)
  jg     L38
  subl   $0x1,-0x14(%rbp)
L32:
  cmpl   $0x0,-0x14(%rbp)
  jg     L19
  nop
  leave
  ret
```

assistant: ```c
void delay_ms(int j) {
  int k_max = clk_get_cpu_rate() / 1000 / 3;
  int k = k_max;
  for (; j > 0; j--) {
    for (k = k_max; k > 0; k--) {
      __asm__("nop");
    }
  }
  return;
}
```
user: What is the c source code of the assembly code below:

```asm
<delay_ms>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x0,%eax
  call   <clk_get_cpu_rate@plt>
  movslq %eax,%rcx
  imul   $0x57619f1,%rcx,%rcx
  sar    $0x26,%rcx
  cltd
  sub    %edx,%ecx
  test   %ebx,%ebx
  jg     L32
L47:
  pop    %rbx
  ret
L5:
  nop
  sub    $0x1,%edx
  test   %edx,%edx
  jg     L5
L37:
  sub    $0x1,%ebx
  je     L47
L32:
  mov    %ecx,%edx
  cmp    $0xbb7,%eax
  jg     L5
  jmp    L37
```

assistant: ```c
void delay_ms(int j) {
  int k_max = clk_get_cpu_rate() / 1000 / 3;
  int k = k_max;
  for (; j > 0; j--) {
    for (k = k_max; k > 0; k--) {
      __asm__("nop");
    }
  }
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<delay_ms>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <clk_get_cpu_rate@plt>
  movslq %eax,%rcx
  cltd
  imul   $0x57619f1,%rcx,%rcx
  sar    $0x26,%rcx
  sub    %edx,%ecx
  test   %ebx,%ebx
  jle    L10
  nopl   0x0(%rax,%rax,1)
L15:
  mov    %ecx,%edx
  cmp    $0xbb7,%eax
  jle    L21
  nopl   0x0(%rax)
L30:
  nop
  sub    $0x1,%edx
  jne    L30
L21:
  sub    $0x1,%ebx
  jne    L15
L10:
  pop    %rbx
  ret
```

assistant: ```c
void delay_ms(int j) {
  int k_max = clk_get_cpu_rate() / 1000 / 3;
  int k = k_max;
  for (; j > 0; j--) {
    for (k = k_max; k > 0; k--) {
      __asm__("nop");
    }
  }
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<delay_ms>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  mov    %edi,%ebx
  call   <clk_get_cpu_rate@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x57619f1,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  test   %ebx,%ebx
  jle    L8
  cmp    $0xbb7,%eax
  jle    L8
  xchg   %ax,%ax
L5:
  mov    %edx,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  nop
  sub    $0x1,%eax
  jne    L3
  sub    $0x1,%ebx
  jne    L5
L8:
  pop    %rbx
  ret
```

assistant: ```c
void delay_ms(int j) {
  int k_max = clk_get_cpu_rate() / 1000 / 3;
  int k = k_max;
  for (; j > 0; j--) {
    for (k = k_max; k > 0; k--) {
      __asm__("nop");
    }
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<genname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <gsym@plt>
  mov    %rax,%rdi
  call   <genraw@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <genraw@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D4: :


assistant: ```c
void genname(char *name) {
  genraw(gsym(name));
  genraw(":\n");
}
```