ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  lea    D20(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   0x0(%rax)
L12:
  mov    $0x2,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <timeSeed@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L12
  mov    $0xa,%edi
  mov    $0x64,%ebx
  lea    D34(%rip),%rbp
  call   <putchar@plt>
  lea    D33(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L10:
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <getRand@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L10
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_infered: string
name: retrieve_data
arguments: label: D20
type_infered: string
name: retrieve_data
arguments: label: D34
type_infered: string
name: retrieve_data
arguments: label: D33
type_infered: string

tool: D11: Seed test:

tool: D20: %zx 

tool: D34: %zd 

tool: D33: Random 100 to 1000 test

assistant: ```c
int main(int argc, char **argv) {
  int count;
  printf("Seed test:");
  for (count = 0; count < 10; count++) {
    sleep(2);
    printf("%zx ", timeSeed());
  }
  printf("\n");
  printf("Random 100 to 1000 test\n");
  for (count = 0; count < 100; count++) {
    printf("%zd ", getRand(100, 1000));
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  lea    D3(%rip),%rbp
  push   %rbx
  mov    $0xa,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  nopl   0x0(%rax)
L8:
  mov    $0x2,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  call   <timeSeed@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L8
  mov    $0xa,%edi
  mov    $0x64,%ebx
  lea    D25(%rip),%rbp
  call   <putchar@plt>
  lea    D9(%rip),%rdi
  call   <puts@plt>
  nopl   0x0(%rax)
L3:
  mov    $0x3e8,%esi
  mov    $0x64,%edi
  call   <getRand@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L3
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string

tool: D15: Seed test:

tool: D3: %zx 

tool: D25: %zd 

tool: D9: Random 100 to 1000 test

assistant: ```c
int main(int argc, char **argv) {
  int count;
  printf("Seed test:");
  for (count = 0; count < 10; count++) {
    sleep(2);
    printf("%zx ", timeSeed());
  }
  printf("\n");
  printf("Random 100 to 1000 test\n");
  for (count = 0; count < 100; count++) {
    printf("%zd ", getRand(100, 1000));
  }
  printf("\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L7
L11:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L32
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L30
L32:
  nop
L30:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x64,-0x4(%rbp)
  jle    L11
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_infered: string

tool: D5: %d


assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    if (!is_prime(i))
      continue;
    printf("%d\n", i);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D3(%rip),%rbp
  jmp    L8
L23:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  je     L4
L8:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L23
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L23
L4:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D3: %d


assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    if (!is_prime(i))
      continue;
    printf("%d\n", i);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L6
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L6:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L5
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D2
data_type: string

tool: D2: %d


assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    if (!is_prime(i))
      continue;
    printf("%d\n", i);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edi
  call   <is_prime@plt>
  test   %eax,%eax
  je     L5
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
L5:
  add    $0x1,%ebx
  cmp    $0x65,%ebx
  jne    L18
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D0
data_type: string

tool: D0: %d


assistant: ```c
int main(void) {
  int i;
  for (i = 1; i <= 100; i++) {
    if (!is_prime(i))
      continue;
    printf("%d\n", i);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L45:
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L28:
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    -0x28(%rbp),%rcx
  mov    %edx,%esi
  mov    %eax,%edi
  call   *%rcx
  test   %eax,%eax
  je     L20
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
L20:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L28
  addl   $0x1,-0x8(%rbp)
L41:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L45
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubble_sort(int arr[], int size, int (*compare)(int, int)) {
  int i, j;
  for (i = 0; i < size; i++)
    for (j = 0; j < size - 1; j++)
      if ((*compare)(arr[i], arr[j + 1]))
        swap(&arr[i], &arr[i + 1]);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %esi,0x14(%rsp)
  test   %esi,%esi
  jle    L52
  mov    %rdx,%r12
  mov    %rdi,%r14
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rax
  mov    %rax,0x18(%rsp)
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%r13
  jmp    L71
L26:
  add    $0x4,%rbx
  cmp    %r13,%rbx
  je     L3
L61:
  mov    (%rbx),%esi
  mov    0x0(%rbp),%edi
  call   *%r12
  test   %eax,%eax
  je     L26
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L26
L3:
  add    $0x4,%r14
  cmp    0x18(%rsp),%r14
  je     L52
L71:
  mov    %r14,%rbp
  lea    0x4(%r14),%r15
  mov    0x8(%rsp),%rax
  lea    0x4(%rax),%rbx
  cmpl   $0x1,0x14(%rsp)
  jg     L61
  jmp    L3
L52:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void bubble_sort(int arr[], int size, int (*compare)(int, int)) {
  int i, j;
  for (i = 0; i < size; i++)
    for (j = 0; j < size - 1; j++)
      if ((*compare)(arr[i], arr[j + 1]))
        swap(&arr[i], &arr[i + 1]);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  test   %esi,%esi
  jle    L42
  push   %r15
  lea    0x4(%rdi),%rcx
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    (%rcx,%rax,4),%rax
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %rcx,0x8(%rsp)
  mov    %rax,(%rsp)
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%r12
  nop
L48:
  mov    0x8(%rsp),%r15
  lea    0x4(%rbx),%r13
  cmp    $0x1,%r14d
  jne    L31
  jmp    L44
  nopl   0x0(%rax)
L53:
  add    $0x4,%r15
  cmp    %r12,%r15
  je     L44
L31:
  mov    (%r15),%esi
  mov    (%rbx),%edi
  call   *%rbp
  test   %eax,%eax
  je     L53
  mov    %r13,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <swap@plt>
  cmp    %r12,%r15
  jne    L31
L44:
  mov    %r13,%rbx
  cmp    (%rsp),%r13
  jne    L48
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L42:
  ret
```

assistant: ```c
void bubble_sort(int arr[], int size, int (*compare)(int, int)) {
  int i, j;
  for (i = 0; i < size; i++)
    for (j = 0; j < size - 1; j++)
      if ((*compare)(arr[i], arr[j + 1]))
        swap(&arr[i], &arr[i + 1]);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bubble_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L47
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  lea    0x4(%rdi),%r14
  push   %r13
  lea    (%r14,%rax,4),%rax
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x2(%rsi),%eax
  lea    0x8(%rdi,%rax,4),%r12
  nopl   (%rax)
L15:
  mov    %r13,%rbx
  mov    %r14,%r15
  add    $0x4,%r13
  jmp    L56
  nopl   0x0(%rax)
L6:
  add    $0x4,%r15
  cmp    %r15,%r12
  je     L1
L56:
  mov    (%r15),%esi
  mov    (%rbx),%edi
  call   *%rbp
  test   %eax,%eax
  je     L6
  mov    %r13,%rsi
  mov    %rbx,%rdi
  add    $0x4,%r15
  call   <swap@plt>
  cmp    %r15,%r12
  jne    L56
L1:
  cmp    %r13,0x8(%rsp)
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L47:
  ret
```

assistant: ```c
void bubble_sort(int arr[], int size, int (*compare)(int, int)) {
  int i, j;
  for (i = 0; i < size; i++)
    for (j = 0; j < size - 1; j++)
      if ((*compare)(arr[i], arr[j + 1]))
        swap(&arr[i], &arr[i + 1]);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    D120(%rip),%rdi
  call   <printf@plt>
  lea    D34(%rip),%rsi
  lea    D39(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L14
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    D120(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  lea    D8(%rip),%r12
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  lea    D52(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rbp
  mov    0xc(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
L14:
  mov    %rbx,%rdi
  call   <fclose@plt>
  movl   $0x2a,0xc(%rsp)
  lea    D96(%rip),%rsi
  lea    D39(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  lea    D63(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  mov    %rbx,%rdi
  call   <fclose@plt>
  lea    D87(%rip),%rdi
  call   <printf@plt>
  lea    D120(%rip),%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    $0x0,%eax
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D23
type_guessed: string
name: read_data
arguments: label: D120
type_guessed: string
name: read_data
arguments: label: D34
type_guessed: string
name: read_data
arguments: label: D39
type_guessed: string
name: read_data
arguments: label: D6
type_guessed: string
name: read_data
arguments: label: D8
type_guessed: string
name: read_data
arguments: label: D52
type_guessed: string
name: read_data
arguments: label: D96
type_guessed: string
name: read_data
arguments: label: D63
type_guessed: string
name: read_data
arguments: label: D87
type_guessed: string

tool: D23: starting

tool: D120: 


tool: D34: r

tool: D39: test.dat

tool: D6: Reading File

tool: D8: %d

tool: D52: data is read

tool: D96: w

tool: D63: Writing file

tool: D87: Ending

assistant: ```c
int main(int argc, char *argv[]) {
  printf("starting");
  printf("\n");
  int numItems;
  FILE *infile = fopen("test.dat", "r");
  if (infile != NULL) {
    printf("Reading File");
    printf("\n");
    fscanf(infile, "%d", &numItems);
    printf("data is read");
    char line[255];
    sprintf(line, "%d", numItems);
    puts(line);
  }
  fclose(infile);
  numItems = 42;
  FILE *outfile = fopen("test.dat", "w");
  printf("Writing file");
  fprintf(outfile, "%d", numItems);
  fclose(outfile);
  printf("Ending");
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r15
  lea    D64(%rip),%rdi
  push   %r14
  lea    D46(%rip),%r14
  push   %r13
  lea    D69(%rip),%r13
  push   %r12
  lea    D53(%rip),%r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D86(%rip),%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L1
  lea    D91(%rip),%rdi
  lea    0x10(%rsp),%r15
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    %r15,%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <puts@plt>
L1:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D11(%rip),%rsi
  mov    %r14,%rdi
  movl   $0x2a,0xc(%rsp)
  call   <fopen@plt>
  lea    D39(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D64
data_type: string
name: parse_data
arguments: data_tag: D46
data_type: string
name: parse_data
arguments: data_tag: D69
data_type: string
name: parse_data
arguments: data_tag: D53
data_type: string
name: parse_data
arguments: data_tag: D86
data_type: string
name: parse_data
arguments: data_tag: D91
data_type: string
name: parse_data
arguments: data_tag: D25
data_type: string
name: parse_data
arguments: data_tag: D11
data_type: string
name: parse_data
arguments: data_tag: D39
data_type: string
name: parse_data
arguments: data_tag: D57
data_type: string

tool: D64: starting

tool: D46: test.dat

tool: D69: %d

tool: D53: 


tool: D86: r

tool: D91: Reading File

tool: D25: data is read

tool: D11: w

tool: D39: Writing file

tool: D57: Ending

assistant: ```c
int main(int argc, char *argv[]) {
  printf("starting");
  printf("\n");
  int numItems;
  FILE *infile = fopen("test.dat", "r");
  if (infile != NULL) {
    printf("Reading File");
    printf("\n");
    fscanf(infile, "%d", &numItems);
    printf("data is read");
    char line[255];
    sprintf(line, "%d", numItems);
    puts(line);
  }
  fclose(infile);
  numItems = 42;
  FILE *outfile = fopen("test.dat", "w");
  printf("Writing file");
  fprintf(outfile, "%d", numItems);
  fclose(outfile);
  printf("Ending");
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D76(%rip),%rdi
  push   %r14
  lea    D33(%rip),%r14
  push   %r13
  lea    D67(%rip),%r13
  push   %r12
  lea    D62(%rip),%r12
  push   %rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D60(%rip),%rsi
  mov    %r14,%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L3
  lea    D44(%rip),%rdi
  lea    0x10(%rsp),%r15
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rdx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    %r15,%rdi
  mov    %r13,%rsi
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <puts@plt>
L3:
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D7(%rip),%rsi
  mov    %r14,%rdi
  movl   $0x2a,0xc(%rsp)
  call   <fopen@plt>
  lea    D27(%rip),%rdi
  mov    %rax,%rbp
  call   <printf@plt>
  mov    0xc(%rsp),%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <fprintf@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x120,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D76
datatype: string
name: extract_symbolic_data
arguments: data_label: D33
datatype: string
name: extract_symbolic_data
arguments: data_label: D67
datatype: string
name: extract_symbolic_data
arguments: data_label: D62
datatype: string
name: extract_symbolic_data
arguments: data_label: D60
datatype: string
name: extract_symbolic_data
arguments: data_label: D44
datatype: string
name: extract_symbolic_data
arguments: data_label: D46
datatype: string
name: extract_symbolic_data
arguments: data_label: D7
datatype: string
name: extract_symbolic_data
arguments: data_label: D27
datatype: string
name: extract_symbolic_data
arguments: data_label: D9
datatype: string

tool: D76: starting

tool: D33: test.dat

tool: D67: %d

tool: D62: 


tool: D60: r

tool: D44: Reading File

tool: D46: data is read

tool: D7: w

tool: D27: Writing file

tool: D9: Ending

assistant: ```c
int main(int argc, char *argv[]) {
  printf("starting");
  printf("\n");
  int numItems;
  FILE *infile = fopen("test.dat", "r");
  if (infile != NULL) {
    printf("Reading File");
    printf("\n");
    fscanf(infile, "%d", &numItems);
    printf("data is read");
    char line[255];
    sprintf(line, "%d", numItems);
    puts(line);
  }
  fclose(infile);
  numItems = 42;
  FILE *outfile = fopen("test.dat", "w");
  printf("Writing file");
  fprintf(outfile, "%d", numItems);
  fclose(outfile);
  printf("Ending");
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prodmatAAtB>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movsd  (%rax),%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x1c(%rbp)
  jmp    L16
L20:
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <dot@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  jmp    L39
L30:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L59
L45:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L59:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L45
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L39:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L30
  addl   $0x1,-0x1c(%rbp)
L16:
  mov    -0x1c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jle    L20
  nop
  nop
  leave
  ret
```

assistant: ```c
void prodmatAAtB(double **a, double **b) {
  int j, k, i, lig, col;
  double s;
  lig = (int)a[0][0];
  col = (int)a[1][0];
  for (j = 1; j <= lig; j++) {
    dot(1, 10);
    for (k = j; k <= lig; k++) {
      s = 0;
      for (i = 1; i <= col; i++) {
        s = s + a[j][i] * a[k][i];
      }
      b[j][k] = s;
      b[k][j] = s;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prodmatAAtB>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  cvttsd2si (%rax),%r14d
  mov    0x8(%rdi),%rax
  cvttsd2si (%rax),%r13d
  test   %r14d,%r14d
  jle    L21
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    $0x1,%ebx
  lea    0x1(%r13),%r15d
  jmp    L22
L16:
  mov    (%r12,%rbx,8),%rcx
  mov    (%r12,%rdi,1),%rdx
  mov    $0x1,%eax
  pxor   %xmm1,%xmm1
L33:
  movsd  (%rcx,%rax,8),%xmm0
  mulsd  (%rdx,%rax,8),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L33
L89:
  mov    0x0(%rbp,%rbx,8),%rax
  movsd  %xmm1,(%rax,%rdi,1)
  mov    0x0(%rbp,%rdi,1),%rax
  movsd  %xmm1,(%rax,%r9,1)
  add    $0x8,%rdi
  cmp    %r8,%rdi
  je     L72
L73:
  pxor   %xmm1,%xmm1
  test   %r13d,%r13d
  jg     L16
  jmp    L89
L72:
  add    $0x1,%rbx
  cmp    %ebx,%r14d
  jl     L21
L22:
  mov    $0xa,%esi
  mov    $0x1,%edi
  call   <dot@plt>
  cmp    %ebx,%r14d
  jl     L72
  lea    0x0(,%rbx,8),%r9
  mov    %r14d,%eax
  sub    %ebx,%eax
  lea    0x1(%rbx,%rax,1),%r8
  shl    $0x3,%r8
  mov    %r9,%rdi
  mov    %r15d,%esi
  jmp    L73
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void prodmatAAtB(double **a, double **b) {
  int j, k, i, lig, col;
  double s;
  lig = (int)a[0][0];
  col = (int)a[1][0];
  for (j = 1; j <= lig; j++) {
    dot(1, 10);
    for (k = j; k <= lig; k++) {
      s = 0;
      for (i = 1; i <= col; i++) {
        s = s + a[j][i] * a[k][i];
      }
      b[j][k] = s;
      b[k][j] = s;
    }
  }
}
```