user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x828,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x818(%rsp)
  xor    %eax,%eax
  lea    0x3c(%rsp),%rax
  mov    %rax,0x20(%rsp)
  lea    0x38(%rsp),%rax
  mov    %rax,0x18(%rsp)
  lea    0x40(%rsp),%rax
  mov    %rax,0x28(%rsp)
  lea    0x44(%rsp),%rax
  mov    %rax,0x10(%rsp)
  nopw   0x0(%rax,%rax,1)
L187:
  mov    0x20(%rsp),%rdx
  mov    0x18(%rsp),%rsi
  lea    D23(%rip),%rdi
  movq   $0x0,0x808(%rsp)
  call   <scanf@plt>
  mov    0x38(%rsp),%r13d
  mov    0x3c(%rsp),%edx
  test   %r13d,%r13d
  jne    L172
  test   %edx,%edx
  je     L61
L172:
  lea    0x1(%rdx),%eax
  movl   $0x0,0x4(%rsp)
  xor    %r15d,%r15d
  cmp    %eax,%r13d
  je     L17
  xor    %ebp,%ebp
  jmp    L92
  nopl   0x0(%rax,%rax,1)
L62:
  lea    0x1(%r13),%eax
  cmp    %r13d,%edx
  je     L64
L19:
  mov    %eax,%r13d
L92:
  cmp    $0x1,%r13d
  jle    L62
  mov    $0x2,%ebx
  jmp    L82
  nopl   0x0(%rax)
L89:
  mov    %r13d,%eax
  cltd
  idiv   %ebx
  test   %edx,%edx
  je     L199
  add    $0x1,%ebx
L82:
  mov    %r13d,%edi
  call   <sqrt@plt>
  cmp    %eax,%ebx
  jle    L89
  mov    0x3c(%rsp),%edx
  lea    0x1(%rbp),%eax
  mov    %eax,0x80c(%rsp)
  lea    0x1(%r13),%eax
  mov    %r13d,0x40(%rsp,%rbp,4)
  movslq 0x80c(%rsp),%rbp
  cmp    %r13d,%edx
  jne    L19
  nopl   0x0(%rax)
L64:
  mov    %ebp,0x4(%rsp)
  mov    0x808(%rsp),%r15d
  cmp    $0x1,%ebp
  jle    L17
  lea    -0x2(%rbp),%r13d
  mov    0x28(%rsp),%r14
  mov    $0x1,%ebx
  lea    0x2(%r13),%rax
  mov    %rax,0x8(%rsp)
  mov    %r15d,%eax
  mov    %r14,%r15
  mov    %eax,%r14d
  nopl   (%rax)
L117:
  mov    0x4(%rsp),%eax
  cmp    %ebx,%eax
  jle    L194
  sub    $0x1,%eax
  mov    0x10(%rsp),%rcx
  mov    %r15,%rbp
  sub    %ebx,%eax
  lea    -0x1(%rbx,%rax,1),%rax
  lea    (%rcx,%rax,4),%r13
  jmp    L165
  nopl   0x0(%rax,%rax,1)
L96:
  add    $0x4,%rbp
  cmp    %r13,%rbp
  je     L194
L165:
  mov    0x4(%rbp),%edx
  mov    (%r15),%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    $0x2,%eax
  jg     L96
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%r14d
  add    $0x4,%rbp
  call   <printf@plt>
  mov    %r14d,0x808(%rsp)
  cmp    %r13,%rbp
  jne    L165
L194:
  add    $0x1,%rbx
  add    $0x4,%r15
  cmp    0x8(%rsp),%rbx
  jne    L117
  mov    %r14d,%r15d
L17:
  mov    %r15d,%esi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L187
  nop
L199:
  mov    0x3c(%rsp),%edx
  jmp    L62
L61:
  mov    0x818(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x828,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string

tool: D3: %d %d


tool: D23: %d,%d

tool: D29: %d


assistant: ```c
int main() {
  int n, m, i, j, flag, num[500];
  do {
    num[498] = 0;
    num[499] = 0;
    scanf("%d,%d", &n, &m);
    if (n == 0 && m == 0)
      break;
    for (i = n; i != m + 1; ++i) {
      if (i > 1) {
        flag = 1;
        for (j = 2; j <= (int)sqrt(i * 1.0); ++j)
          if (i % j == 0) {
            flag = 0;
            break;
          }
        if (flag == 1)
          num[num[499]++] = i;
      }
    }
    for (i = 0; i < num[499] - 1; ++i)
      for (j = i + 1; j < num[499]; ++j)
        if (num[j] - num[i] <= 2) {
          printf("%d %d\n", num[i], num[j]);
          ++num[498];
        }
    printf("%d\n", num[498]);
  } while (1);
  return 0;
}
```