user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  pcmpeqd %xmm0,%xmm0
  xor    %edi,%edi
  push   %rbp
  lea    D44(%rip),%rbp
  push   %rbx
  mov    $0xffffffff,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D24(%rip),%rax
  movaps %xmm0,(%rsp)
  mov    %rax,0x10(%rsp)
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D31(%rip),%rdi
  call   <puts@plt>
  xor    %esi,%esi
  nopl   0x0(%rax,%rax,1)
L95:
  mov    %rbp,%rdi
  call   <printf@plt>
L0:
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x2aaaaaab,%rdx,%rdx
  sar    $0x1f,%ecx
  shr    $0x20,%rdx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,2),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  cmp    %ebx,%eax
  je     L0
  cmp    $0xffffffff,%ebx
  je     L34
  mov    0x4(%rsp),%eax
  cmp    %eax,%edx
  je     L0
  cmp    $0xffffffff,%eax
  je     L25
  mov    0x8(%rsp),%eax
  cmp    %eax,%edx
  je     L0
  cmp    $0xffffffff,%eax
  je     L104
  mov    0xc(%rsp),%eax
  cmp    %eax,%edx
  je     L0
  cmp    $0xffffffff,%eax
  je     L149
  mov    0x10(%rsp),%eax
  cmp    %eax,%edx
  je     L0
  cmp    $0xffffffff,%eax
  jne    L26
  mov    $0x5,%esi
  mov    $0x4,%eax
  jmp    L148
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    $0x1,%esi
  xor    %eax,%eax
L148:
  mov    %edx,(%rsp,%rax,4)
  mov    (%rsp),%ebx
  jmp    L95
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x2,%esi
  mov    $0x1,%eax
  jmp    L148
  nopl   0x0(%rax)
L104:
  mov    $0x3,%esi
  mov    $0x2,%eax
  jmp    L148
  nopl   0x0(%rax)
L149:
  mov    $0x4,%esi
  mov    $0x3,%eax
  jmp    L148
L26:
  mov    0x14(%rsp),%eax
  cmp    %eax,%edx
  je     L0
  add    $0x1,%eax
  jne    L99
  mov    %edx,0x14(%rsp)
L99:
  mov    $0x24,%esi
  lea    D35(%rip),%rdi
  mov    %rsp,%rbx
  call   <printf@plt>
  lea    0x18(%rsp),%r12
  lea    D47(%rip),%rbp
  nopl   0x0(%rax)
L56:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L56
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D44
type: string
name: unpack_data
arguments: tag: D24
type: byte[8]
name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D35
type: string
name: unpack_data
arguments: tag: D47
type: string

tool: D44: %d


tool: {"D24": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0xff]}

tool: D31: THE AMAZING LOTTERY

tool: D35: Today's numbers are : %c

tool: D47: %d, 

assistant: ```c
int main() {
  int x, y, z, numbers[6];
  for (x = 0; x < 6; x++)
    numbers[x] = -1;
  srand((unsigned)time(NULL));
  puts("THE AMAZING LOTTERY");
  for (y = 0; y < 6; y++) {
    printf("%d\n", y);
  label:
    z = rand() % 6;
    for (y = 0; y < 6; y++) {
      if (z == numbers[y])
        goto label;
      else if (numbers[y] != -1)
        continue;
      else {
        numbers[y] = z;
        break;
      }
    }
  }
  printf("Today's numbers are : %c", 36);
  for (x = 0; x < 6; x++)
    printf("%d, ", numbers[x]);
  return 0;
}
```