user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x158,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x160(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x15c(%rbp)
  jmp    L58
L65:
  lea    -0x148(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x158(%rbp)
  movq   $0x0,-0x140(%rbp)
  mov    -0x148(%rbp),%rax
  cmp    $0x1,%rax
  jne    L38
  mov    $0xfffffffe,%eax
  mov    %rax,-0x130(%rbp)
  mov    -0x130(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L38:
  mov    -0x148(%rbp),%rax
  test   %rax,%rax
  jne    L104
  mov    $0xffffffff,%eax
  mov    %rax,-0x128(%rbp)
  mov    -0x128(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L104:
  mov    -0x148(%rbp),%rax
  cmp    $0x1,%rax
  je     L5
  mov    -0x148(%rbp),%rax
  test   %rax,%rax
  je     L5
  jmp    L110
L96:
  mov    -0x148(%rbp),%rax
  mov    $0x1f,%edx
  sub    -0x158(%rbp),%edx
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3f,%rcx
  add    %rcx,%rax
  and    $0x1,%eax
  sub    %rcx,%rax
  mov    %rax,%rcx
  movslq %edx,%rax
  mov    %rcx,-0x120(%rbp,%rax,8)
  mov    -0x148(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x140(%rbp)
  mov    -0x148(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x148(%rbp)
  addl   $0x1,-0x158(%rbp)
L110:
  cmpq   $0x1,-0x140(%rbp)
  jne    L96
  mov    $0x1f,%eax
  sub    -0x158(%rbp),%eax
  cltq
  movq   $0x1,-0x120(%rbp,%rax,8)
  movl   $0x0,-0x154(%rbp)
  jmp    L114
L89:
  mov    -0x154(%rbp),%eax
  cltq
  movq   $0x0,-0x120(%rbp,%rax,8)
  addl   $0x1,-0x154(%rbp)
L114:
  mov    $0x1e,%eax
  sub    -0x158(%rbp),%eax
  cmp    %eax,-0x154(%rbp)
  jle    L89
  movl   $0x0,-0x150(%rbp)
  jmp    L76
L91:
  mov    -0x150(%rbp),%eax
  cltq
  mov    -0x120(%rbp,%rax,8),%rax
  test   %rax,%rax
  jne    L66
  mov    -0x150(%rbp),%eax
  cltq
  movq   $0x1,-0x120(%rbp,%rax,8)
  jmp    L146
L66:
  mov    -0x150(%rbp),%eax
  cltq
  mov    -0x120(%rbp,%rax,8),%rax
  cmp    $0x1,%rax
  jne    L146
  mov    -0x150(%rbp),%eax
  cltq
  movq   $0x0,-0x120(%rbp,%rax,8)
L146:
  addl   $0x1,-0x150(%rbp)
L76:
  cmpl   $0x1f,-0x150(%rbp)
  jle    L91
  movq   $0x0,-0x138(%rbp)
  movl   $0x0,-0x14c(%rbp)
  jmp    L61
L1:
  mov    -0x14c(%rbp),%eax
  cltq
  mov    -0x120(%rbp,%rax,8),%rbx
  mov    $0x1f,%eax
  sub    -0x14c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <pow@plt>
  imul   %rbx,%rax
  add    %rax,-0x138(%rbp)
  addl   $0x1,-0x14c(%rbp)
L61:
  cmpl   $0x1f,-0x14c(%rbp)
  jle    L1
  mov    -0x138(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L5:
  addl   $0x1,-0x15c(%rbp)
L58:
  mov    -0x160(%rbp),%eax
  cmp    %eax,-0x15c(%rbp)
  jl     L65
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D23
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D15
type_guessed: string

tool: D23: %d

tool: D2: %ld

tool: D15: %ld


assistant: ```c
int main() {
  int test, i;
  scanf("%d", &test);
  for (i = 0; i < test; i++) {
    long int n;
    scanf("%ld", &n);
    int j = 0;
    long int c = 0;
    long int arr[32];
    if (n == 1) {
      long int s = 4294967294;
      printf("%ld\n", s);
    }
    if (n == 0) {
      long int g = 4294967295;
      printf("%ld\n", g);
    }
    if (n != 1 && n != 0) {
      while (c != 1) {
        arr[31 - j] = n % 2;
        c = n / 2;
        n = n / 2;
        j = j + 1;
      }
      arr[31 - j] = 1;
      int k;
      for (k = 0; k <= 31 - j - 1; k++) {
        arr[k] = 0;
      }
      int u;
      for (u = 0; u < 32; u++) {
        if (arr[u] == 0) {
          arr[u] = 1;
        } else if (arr[u] == 1) {
          arr[u] = 0;
        }
      }
      int h;
      long int count = 0;
      for (h = 0; h < 32; h++)
        count = count + arr[h] * (pow(2, 31 - h));
      printf("%ld\n", count);
    }
  }
  return 0;
}
```