ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<ping>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    $0x5dd,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L17
  test   %r12,%r12
  je     L17
  mov    %rax,%rdi
  mov    %r12,%rcx
  mov    $0x5dc,%esi
  lea    D2(%rip),%rdx
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <irc_send@plt>
L27:
  mov    %rbp,%rdi
  call   <free@plt>
L14:
  test   %r12,%r12
  je     L9
  mov    %r12,%rdi
  call   <free@plt>
L9:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  test   %rbp,%rbp
  je     L14
  jmp    L27
```

tool_calls: name: unpack_data
arguments: data_label: D2
data_type: string
name: unpack_data
arguments: data_label: D12
data_type: string

tool: D2: PONG %s


tool: D12: Error with variables in ping thread.  PONG not sent.


assistant: ```c
void *ping(void *code) {
  char *packet = malloc(1501);
  if (packet && code) {
    snprintf(packet, 1500, "PONG %s\r\n", (char *)code);
    irc_send(packet);
  } else {
    printf("Error with variables in ping thread.  PONG not sent.\n");
  }
  if (packet)
    free(packet);
  if (code)
    free(code);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<val_mand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <xtr_name@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <val_ext@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <val_type@plt>
  nop
  leave
  ret
```

assistant: ```c
val_mand(nm, ex, tt, cc) int *nm, *ex, *tt, cc;
{
  xtr_name(nm, cc);
  val_ext(ex, cc);
  val_type(tt, cc);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<val_mand>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %ecx,%ebx
  mov    %ecx,%esi
  mov    $0x0,%eax
  call   <xtr_name@plt>
  mov    %ebx,%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <val_ext@plt>
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <val_type@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
val_mand(nm, ex, tt, cc) int *nm, *ex, *tt, cc;
{
  xtr_name(nm, cc);
  val_ext(ex, cc);
  val_type(tt, cc);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<val_mand>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  mov    %ecx,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  call   <xtr_name@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <val_ext@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    1090 <val_type@plt>
```

assistant: ```c
val_mand(nm, ex, tt, cc) int *nm, *ex, *tt, cc;
{
  xtr_name(nm, cc);
  val_ext(ex, cc);
  val_type(tt, cc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<val_mand>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  mov    %ecx,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %ecx,%ebp
  call   <xtr_name@plt>
  mov    %ebp,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <val_ext@plt>
  mov    %ebp,%esi
  mov    %r12,%rdi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    1090 <val_type@plt>
```

assistant: ```c
val_mand(nm, ex, tt, cc) int *nm, *ex, *tt, cc;
{
  xtr_name(nm, cc);
  val_ext(ex, cc);
  val_type(tt, cc);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BcdToStr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <BcdToStr0@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  movb   $0x20,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *BcdToStr(bcdc)
char bcdc;
{
  char *r;
  r = BcdToStr0(bcdc);
  if (*r == '0')
    *r = ' ';
  return (r);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<BcdToStr>:
  endbr64
  sub    $0x8,%rsp
  movsbl %dil,%edi
  mov    $0x0,%eax
  call   <BcdToStr0@plt>
  cltq
  cmpb   $0x30,(%rax)
  je     L4
L0:
  add    $0x8,%rsp
  ret
L4:
  movb   $0x20,(%rax)
  jmp    L0
```

assistant: ```c
char *BcdToStr(bcdc)
char bcdc;
{
  char *r;
  r = BcdToStr0(bcdc);
  if (*r == '0')
    *r = ' ';
  return (r);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BcdToStr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  movsbl %dil,%edi
  call   <BcdToStr0@plt>
  cltq
  cmpb   $0x30,(%rax)
  jne    L2
  movb   $0x20,(%rax)
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *BcdToStr(bcdc)
char bcdc;
{
  char *r;
  r = BcdToStr0(bcdc);
  if (*r == '0')
    *r = ' ';
  return (r);
}
```
user: What is the c source code of the assembly code below:

```asm
<BcdToStr>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  movsbl %dil,%edi
  call   <BcdToStr0@plt>
  cltq
  cmpb   $0x30,(%rax)
  jne    L0
  movb   $0x20,(%rax)
L0:
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *BcdToStr(bcdc)
char bcdc;
{
  char *r;
  r = BcdToStr0(bcdc);
  if (*r == '0')
    *r = ' ';
  return (r);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L20
  mov    $0x1,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L20:
  movl   $0x0,-0x14(%rbp)
  jmp    L64
L46:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0xa(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L64:
  cmpl   $0x0,-0x14(%rbp)
  jle    L46
  lea    -0x9(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0x38,%al
  jne    L32
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L32:
  movl   $0x0,-0x10(%rbp)
  jmp    L39
L22:
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L39:
  cmpl   $0x0,-0x10(%rbp)
  jle    L22
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D25
datatype: string
name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D2
datatype: string

tool: D25: Call this program with %i arguments


tool: D11: You win!

tool: D2: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L49
L47:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %al,0x6(%rsp)
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpb   $0x38,0x7(%rsp)
  je     L37
L5:
  movzbl 0x7(%rsp),%esi
  lea    D15(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L49:
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L47
L37:
  lea    D0(%rip),%rdi
  call   <puts@plt>
  jmp    L5
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
data_type: string
name: unpack_data
arguments: data_label: D20
data_type: string
name: unpack_data
arguments: data_label: D0
data_type: string

tool: D15: %u


tool: D20: Call this program with %i arguments


tool: D0: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L38
  lea    D5(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L38:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x38,%sil
  je     L28
L19:
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L28:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L19
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string
name: parse_data
arguments: tag: D8
type_guessed: string

tool: D5: Call this program with %i arguments


tool: D10: %u


tool: D8: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L9
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L9:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x7(%rsp),%rsi
  lea    0x6(%rsp),%rdi
  mov    %al,0x6(%rsp)
  call   <RandomFunc@plt>
  movzbl 0x7(%rsp),%esi
  cmp    $0x38,%sil
  je     L33
L28:
  xor    %eax,%eax
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L33:
  lea    D15(%rip),%rdi
  call   <puts@plt>
  movzbl 0x7(%rsp),%esi
  jmp    L28
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D8
type_infered: string
name: disassemble_data
arguments: tag: D15
type_infered: string

tool: D24: Call this program with %i arguments


tool: D8: %u


tool: D15: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 56) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<gmul>:
  endbr64
  mov    %edi,%edx
  cmp    $0xe,%sil
  ja     L5
  movzbl %sil,%esi
  lea    D9(%rip),%rdi
  movslq (%rdi,%rsi,4),%rcx
  add    %rdi,%rcx
  notrack jmp *%rcx
  lea    (%rdx,%rdx,1),%eax
  ret
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  ret
  lea    0x0(,%rdx,8),%eax
  xor    %edx,%eax
  ret
  lea    0x0(,%rdx,4),%eax
  xor    %edx,%eax
  add    %eax,%eax
  xor    %edx,%eax
  ret
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  shl    $0x2,%eax
  xor    %edx,%eax
  ret
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  add    %eax,%eax
  xor    %edx,%eax
  add    %eax,%eax
L5:
  ret
```

assistant: ```c
unsigned char gmul(unsigned char x, unsigned char y) {
  unsigned char z;
  if (y == 2) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
  } else if (y == 3) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 9) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 11) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 13) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 14) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
  }
  return (unsigned char)z;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gmul>:
  endbr64
  mov    %edi,%edx
  cmp    $0xe,%sil
  ja     L2
  lea    D7(%rip),%rdi
  movzbl %sil,%esi
  movslq (%rdi,%rsi,4),%rcx
  add    %rdi,%rcx
  notrack jmp *%rcx
  nopl   0x0(%rax)
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  add    %eax,%eax
  xor    %edx,%eax
  add    %eax,%eax
L2:
  ret
  nopl   0x0(%rax)
  lea    (%rdx,%rdx,1),%eax
  ret
  nopl   0x0(%rax)
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  lea    0x0(,%rdx,8),%eax
  xor    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  lea    0x0(,%rdx,4),%eax
  xor    %edx,%eax
  add    %eax,%eax
  xor    %edx,%eax
  ret
  xchg   %ax,%ax
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  shl    $0x2,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned char gmul(unsigned char x, unsigned char y) {
  unsigned char z;
  if (y == 2) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
  } else if (y == 3) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 9) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 11) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 13) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 14) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
  }
  return (unsigned char)z;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<gmul>:
  endbr64
  mov    %edi,%edx
  cmp    $0xe,%sil
  ja     L8
  lea    D7(%rip),%rdi
  movzbl %sil,%esi
  movslq (%rdi,%rsi,4),%rcx
  add    %rdi,%rcx
  notrack jmp *%rcx
  nopl   0x0(%rax)
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  add    %eax,%eax
  xor    %edx,%eax
  add    %eax,%eax
L8:
  ret
  nopl   0x0(%rax)
  lea    (%rdx,%rdx,1),%eax
  ret
  nopl   0x0(%rax)
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
  lea    0x0(,%rdx,8),%eax
  xor    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
  lea    0x0(,%rdx,4),%eax
  xor    %edx,%eax
  add    %eax,%eax
  xor    %edx,%eax
  ret
  xchg   %ax,%ax
  lea    (%rdx,%rdx,1),%eax
  xor    %edx,%eax
  shl    $0x2,%eax
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned char gmul(unsigned char x, unsigned char y) {
  unsigned char z;
  if (y == 2) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
  } else if (y == 3) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 9) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 11) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 13) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
  } else if (y == 14) {
    z = x << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
    z ^= x;
    z = z << 1;
    if ((z >> 8) > 0) {
      z ^= 0x11B;
    }
  }
  return (unsigned char)z;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  add    $0x696a,%ax
  xor    $0xb,%eax
  movzwl 0x2(%rdi),%ecx
  test   %cx,%cx
  je     L54
  mov    $0x0,%edx
  jmp    L64
L27:
  jae    L44
  imul   %eax,%eax
L4:
  add    $0x1,%edx
  cmp    %cx,%dx
  je     L54
L64:
  cmp    %dx,%ax
  jbe    L27
  add    %eax,%eax
  jmp    L4
L44:
  lea    0x0(,%rax,4),%edi
  and    $0x1c,%edi
  or     %edi,%eax
  jmp    L4
L54:
  ror    $0x7,%ax
  sub    $0x2021,%ax
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else if (state[0UL] < local1) {
        state[local1] *= state[local1];
      } else {
        state[local1] |= (state[local1] & (unsigned short)7) << 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) + (unsigned short)57311;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movzwl (%rdi),%eax
  movzwl 0x2(%rdi),%ecx
  add    $0x696a,%ax
  xor    $0xb,%eax
  test   %cx,%cx
  je     L14
  xor    %edx,%edx
  jmp    L31
  nopl   0x0(%rax,%rax,1)
L4:
  add    %eax,%eax
L11:
  add    $0x1,%edx
  cmp    %cx,%dx
  je     L14
L31:
  cmp    %dx,%ax
  ja     L4
  jae    L67
  add    $0x1,%edx
  imul   %eax,%eax
  cmp    %cx,%dx
  jne    L31
L14:
  ror    $0x7,%ax
  sub    $0x2021,%ax
  mov    %ax,(%rsi)
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  lea    0x0(,%rax,4),%edi
  and    $0x1c,%edi
  or     %edi,%eax
  jmp    L11
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  char copy11;
  {
    state[0UL] = (input[0UL] + 914778474UL) ^ (unsigned short)11;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        if (state[0UL] == local1) {
          state[0UL] = state[local1] - state[0UL];
          copy11 = *((char *)(&state[local1]) + 1);
          *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 0);
          *((char *)(&state[local1]) + 0) = copy11;
        } else {
          state[0UL] = state[local1] + state[0UL];
        }
      } else if (state[0UL] < local1) {
        state[local1] *= state[local1];
      } else {
        state[local1] |= (state[local1] & (unsigned short)7) << 2UL;
      }
      local1++;
    }
    output[0UL] = ((state[0UL] << (unsigned short)9) | (state[0UL] >> (unsigned short)7)) + (unsigned short)57311;
  }
}
```