ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Calc_CheckSum>:
  endbr64
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%rcx
  test   %rsi,%rsi
  je     L82
  cmp    $0xe,%rcx
  jbe    L149
  mov    %rdi,%rax
  pxor   %xmm1,%xmm1
  pxor   %xmm2,%xmm2
  mov    %rsi,%rdi
  and    $0xfffffffffffffff0,%rdi
  add    %rdx,%rdi
  nopl   0x0(%rax,%rax,1)
L142:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm3
  punpckhbw %xmm2,%xmm0
  punpcklbw %xmm2,%xmm3
  paddw  %xmm3,%xmm0
  paddw  %xmm0,%xmm1
  cmp    %rdi,%rax
  jne    L142
  movdqa %xmm1,%xmm0
  mov    %rsi,%rdi
  psrldq $0x8,%xmm0
  and    $0xfffffffffffffff0,%rdi
  paddw  %xmm0,%xmm1
  add    %rdi,%rdx
  sub    %rdi,%rcx
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddw  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x2,%xmm0
  paddw  %xmm0,%xmm1
  pextrw $0x0,%xmm1,%eax
  cmp    %rdi,%rsi
  je     L156
L150:
  movzbl (%rdx),%esi
  add    %esi,%eax
  test   %rcx,%rcx
  je     L18
  movzbl 0x1(%rdx),%esi
  add    %esi,%eax
  cmp    $0x1,%rcx
  je     L18
  movzbl 0x2(%rdx),%esi
  add    %esi,%eax
  cmp    $0x2,%rcx
  je     L18
  movzbl 0x3(%rdx),%esi
  add    %esi,%eax
  cmp    $0x3,%rcx
  je     L18
  movzbl 0x4(%rdx),%esi
  add    %esi,%eax
  cmp    $0x4,%rcx
  je     L18
  movzbl 0x5(%rdx),%esi
  add    %esi,%eax
  cmp    $0x5,%rcx
  je     L18
  movzbl 0x6(%rdx),%esi
  add    %esi,%eax
  cmp    $0x6,%rcx
  je     L18
  movzbl 0x7(%rdx),%esi
  add    %esi,%eax
  cmp    $0x7,%rcx
  je     L18
  movzbl 0x8(%rdx),%esi
  add    %esi,%eax
  cmp    $0x8,%rcx
  je     L18
  movzbl 0x9(%rdx),%esi
  add    %esi,%eax
  cmp    $0x9,%rcx
  je     L18
  movzbl 0xa(%rdx),%esi
  add    %esi,%eax
  cmp    $0xa,%rcx
  je     L18
  movzbl 0xb(%rdx),%esi
  add    %esi,%eax
  cmp    $0xb,%rcx
  je     L18
  movzbl 0xc(%rdx),%esi
  add    %esi,%eax
  cmp    $0xc,%rcx
  je     L18
  movzbl 0xd(%rdx),%esi
  add    %esi,%eax
  cmp    $0xd,%rcx
  je     L18
  movzbl 0xe(%rdx),%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L82:
  xor    %eax,%eax
L18:
  ret
L149:
  xor    %eax,%eax
  jmp    L150
L156:
  ret
```

assistant: ```c
unsigned short Calc_CheckSum(unsigned char *mem, unsigned long size) {
  unsigned short u = 0;
  while (size--)
    u += *mem++;
  return (unsigned short)(u & 0xffff);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<errx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%ecx
  mov    -0xd0(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    $0x1,%r8d
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <err_common@plt>
  nop
  leave
  ret
```

assistant: ```c
void errx(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_common(eval, 0, fmt, ap, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<errx>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    $0x1,%r8d
  mov    %r12d,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <err_common@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void errx(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_common(eval, 0, fmt, ap, 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<errx>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    $0x1,%r8d
  xor    %esi,%esi
  call   <err_common@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void errx(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_common(eval, 0, fmt, ap, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<errx>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %ebp,%edi
  mov    $0x1,%r8d
  xor    %esi,%esi
  call   <err_common@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void errx(int eval, const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  err_common(eval, 0, fmt, ap, 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type: string

tool: D1: This is a "pre/bin" target.


assistant: ```c
int main(int argc, char *argv[]) {
  printf("This is a \"pre/bin\" target.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: This is a "pre/bin" target.


assistant: ```c
int main(int argc, char *argv[]) {
  printf("This is a \"pre/bin\" target.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: This is a "pre/bin" target.


assistant: ```c
int main(int argc, char *argv[]) {
  printf("This is a \"pre/bin\" target.\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type: string

tool: D7: This is a "pre/bin" target.


assistant: ```c
int main(int argc, char *argv[]) {
  printf("This is a \"pre/bin\" target.\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<updateOwnerSingle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movswl -0x30(%rbp),%eax
  shl    $0x3,%eax
  cltq
  add    $0x4,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <copyArrays@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sort4_sorting_network_simple_swap@plt>
  movzwl -0x10(%rbp),%edx
  movzwl -0xe(%rbp),%eax
  cmp    %ax,%dx
  jne    L48
  movswl -0x30(%rbp),%eax
  shl    $0x3,%eax
  cltq
  add    $0x3,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movw   $0xffff,(%rax)
  jmp    L3
L48:
  movl   $0x0,-0x14(%rbp)
  jmp    L18
L25:
  movzwl -0x10(%rbp),%edx
  movswl -0x30(%rbp),%eax
  shl    $0x3,%eax
  lea    0x4(%rax),%ecx
  mov    -0x14(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzwl (%rax),%eax
  cmp    %ax,%dx
  jne    L13
  movswl -0x30(%rbp),%eax
  shl    $0x3,%eax
  cltq
  add    $0x3,%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  mov    %dx,(%rax)
L13:
  addl   $0x1,-0x14(%rbp)
L18:
  cmpl   $0x3,-0x14(%rbp)
  jle    L25
L3:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
void updateOwnerSingle(short *world, int myId, short zone) {
  short temp[4];
  copyArrays(&world[zone * 8 + 4], temp, 4);
  sort4_sorting_network_simple_swap(temp);
  if (temp[0] == temp[1]) {
    world[zone * 8 + 3] = -1;
  } else {
    for (int i = 0; i < 4; i++) {
      if (temp[0] == world[zone * 8 + 4 + i])
        world[zone * 8 + 3] = i;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<updateOwnerSingle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movswl %dx,%ebx
  shl    $0x3,%ebx
  movslq %ebx,%rbx
  lea    0x8(%rbx,%rbx,1),%r12
  mov    %rsp,%r13
  lea    (%rdi,%r12,1),%rdi
  mov    $0x4,%edx
  mov    %r13,%rsi
  call   <copyArrays@plt>
  mov    %r13,%rdi
  call   <sort4_sorting_network_simple_swap@plt>
  movzwl (%rsp),%edx
  cmp    0x2(%rsp),%dx
  je     L14
  lea    -0x2(%rbp,%r12,1),%rsi
  lea    0x0(%rbp,%rbx,2),%rcx
  mov    $0x0,%eax
  jmp    L2
L14:
  movw   $0xffff,-0x2(%rbp,%r12,1)
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L53:
  add    $0x1,%rax
  cmp    $0x4,%rax
  je     L30
L2:
  cmp    0x8(%rcx,%rax,2),%dx
  jne    L53
  mov    %ax,(%rsi)
  jmp    L53
L46:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void updateOwnerSingle(short *world, int myId, short zone) {
  short temp[4];
  copyArrays(&world[zone * 8 + 4], temp, 4);
  sort4_sorting_network_simple_swap(temp);
  if (temp[0] == temp[1]) {
    world[zone * 8 + 3] = -1;
  } else {
    for (int i = 0; i < 4; i++) {
      if (temp[0] == world[zone * 8 + 4 + i])
        world[zone * 8 + 3] = i;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<updateOwnerSingle>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movswl %dx,%ebx
  mov    $0x4,%edx
  shl    $0x3,%ebx
  movslq %ebx,%rbx
  sub    $0x18,%rsp
  lea    0x8(%rbx,%rbx,1),%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  add    %r12,%rdi
  mov    %r13,%rsi
  call   <copyArrays@plt>
  mov    %r13,%rdi
  call   <sort4_sorting_network_simple_swap@plt>
  movzwl (%rsp),%edx
  lea    -0x2(%rbp,%r12,1),%rsi
  cmp    0x2(%rsp),%dx
  je     L41
  lea    0x0(%rbp,%rbx,2),%rcx
  xor    %eax,%eax
L39:
  cmp    0x8(%rcx,%rax,2),%dx
  jne    L6
  mov    %ax,(%rsi)
L6:
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L39
L0:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L41:
  mov    $0xffffffff,%eax
  mov    %ax,(%rsi)
  jmp    L0
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void updateOwnerSingle(short *world, int myId, short zone) {
  short temp[4];
  copyArrays(&world[zone * 8 + 4], temp, 4);
  sort4_sorting_network_simple_swap(temp);
  if (temp[0] == temp[1]) {
    world[zone * 8 + 3] = -1;
  } else {
    for (int i = 0; i < 4; i++) {
      if (temp[0] == world[zone * 8 + 4 + i])
        world[zone * 8 + 3] = i;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<updateOwnerSingle>:
  endbr64
  push   %r13
  movswl %dx,%edx
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  lea    0x4(,%rdx,8),%ebx
  mov    $0x4,%edx
  movslq %ebx,%rbx
  add    %rbx,%rbx
  sub    $0x18,%rsp
  lea    (%rdi,%rbx,1),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r13,%rdi
  mov    %r12,%rsi
  call   <copyArrays@plt>
  mov    %r12,%rdi
  call   <sort4_sorting_network_simple_swap@plt>
  movzwl (%rsp),%eax
  lea    -0x2(%rbp,%rbx,1),%rdx
  cmp    0x2(%rsp),%ax
  je     L34
  cmp    0x0(%r13),%ax
  je     L0
  cmp    0x2(%rbp,%rbx,1),%ax
  je     L47
L92:
  cmp    0x4(%rbp,%rbx,1),%ax
  je     L58
L28:
  cmp    0x6(%rbp,%rbx,1),%ax
  je     L88
L118:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L96
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L88:
  mov    $0x3,%eax
  mov    %ax,(%rdx)
  jmp    L118
  nopw   0x0(%rax,%rax,1)
L58:
  mov    $0x2,%ecx
  mov    %cx,(%rdx)
  cmp    0x6(%rbp,%rbx,1),%ax
  jne    L118
  jmp    L88
  nopl   0x0(%rax)
L47:
  mov    $0x1,%esi
  mov    %si,(%rdx)
  cmp    0x4(%rbp,%rbx,1),%ax
  jne    L28
  jmp    L58
  nopl   0x0(%rax)
L0:
  xor    %edi,%edi
  mov    %di,(%rdx)
  cmp    0x2(%rbp,%rbx,1),%ax
  jne    L92
  jmp    L47
  xchg   %ax,%ax
L34:
  mov    $0xffffffff,%r8d
  mov    %r8w,(%rdx)
  jmp    L118
L96:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void updateOwnerSingle(short *world, int myId, short zone) {
  short temp[4];
  copyArrays(&world[zone * 8 + 4], temp, 4);
  sort4_sorting_network_simple_swap(temp);
  if (temp[0] == temp[1]) {
    world[zone * 8 + 3] = -1;
  } else {
    for (int i = 0; i < 4; i++) {
      if (temp[0] == world[zone * 8 + 4 + i])
        world[zone * 8 + 3] = i;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<tokenize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L76
L27:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L70:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  je     L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  mov    %eax,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  jmp    L33
L63:
  addq   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L76
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L63
L76:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jae    L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L70
L4:
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int tokenize(char *res[], unsigned int reslen, char *str, char delim) {
  char *s;
  unsigned int i;
  i = 0;
  s = str;
  while (i < reslen && *s) {
    while (*s == delim)
      *(s++) = '\0';
    if (*s)
      res[i++] = s;
    while (*s && *s != delim)
      s++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tokenize>:
  endbr64
  mov    %rdi,%r8
  mov    $0x0,%edi
  test   %esi,%esi
  jne    L37
  mov    %esi,%edi
L41:
  mov    %edi,%eax
  ret
L64:
  mov    %edi,%eax
  mov    %rdx,(%r8,%rax,8)
  lea    0x1(%rdi),%edi
  jmp    L77
L8:
  cmp    %edi,%esi
  jbe    L41
L37:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L41
  cmp    %cl,%al
  jne    L64
L48:
  add    $0x1,%rdx
  movb   $0x0,-0x1(%rdx)
  movzbl (%rdx),%eax
  cmp    %cl,%al
  je     L48
  test   %al,%al
  jne    L64
L77:
  movzbl (%rdx),%eax
  cmp    %al,%cl
  je     L8
  test   %al,%al
  je     L8
L9:
  add    $0x1,%rdx
  movzbl (%rdx),%eax
  test   %al,%al
  je     L8
  cmp    %cl,%al
  jne    L9
  jmp    L8
```

assistant: ```c
unsigned int tokenize(char *res[], unsigned int reslen, char *str, char delim) {
  char *s;
  unsigned int i;
  i = 0;
  s = str;
  while (i < reslen && *s) {
    while (*s == delim)
      *(s++) = '\0';
    if (*s)
      res[i++] = s;
    while (*s && *s != delim)
      s++;
  }
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tokenize>:
  endbr64
  mov    %rdi,%r9
  xor    %r8d,%r8d
  test   %esi,%esi
  je     L40
  xchg   %ax,%ax
L21:
  movzbl (%rdx),%eax
  test   %al,%al
  je     L40
  cmp    %cl,%al
  jne    L36
  nopl   0x0(%rax,%rax,1)
L85:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  movb   $0x0,-0x1(%rdx)
  cmp    %cl,%al
  je     L85
  test   %al,%al
  jne    L36
L41:
  cmp    %r8d,%esi
  ja     L21
L40:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L36:
  mov    %rdx,(%r9,%r8,8)
  movzbl (%rdx),%eax
  lea    0x1(%r8),%edi
  test   %al,%al
  je     L54
  nop
L35:
  cmp    %cl,%al
  je     L54
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L35
L54:
  mov    %edi,%r8d
  jmp    L41
```

assistant: ```c
unsigned int tokenize(char *res[], unsigned int reslen, char *str, char delim) {
  char *s;
  unsigned int i;
  i = 0;
  s = str;
  while (i < reslen && *s) {
    while (*s == delim)
      *(s++) = '\0';
    if (*s)
      res[i++] = s;
    while (*s && *s != delim)
      s++;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tokenize>:
  endbr64
  test   %esi,%esi
  je     L23
  movzbl (%rdx),%eax
  xor    %r8d,%r8d
  xchg   %ax,%ax
L96:
  test   %al,%al
  je     L67
  cmp    %al,%cl
  jne    L105
  nopl   0x0(%rax,%rax,1)
L117:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  movb   $0x0,-0x1(%rdx)
  cmp    %cl,%al
  je     L117
  test   %al,%al
  jne    L105
L67:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L105:
  mov    %rdx,(%rdi,%r8,8)
  movzbl (%rdx),%eax
  lea    0x1(%r8),%r9d
  test   %al,%al
  je     L93
  cmp    %al,%cl
  jne    L32
  jmp    L93
  nopl   (%rax)
L59:
  cmp    %cl,%al
  je     L93
L32:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  jne    L59
L93:
  cmp    %r9d,%esi
  jbe    L57
  mov    %r9d,%r8d
  jmp    L96
L57:
  mov    %r9d,%r8d
  mov    %r8d,%eax
  ret
L23:
  xor    %r8d,%r8d
  jmp    L67
```

assistant: ```c
unsigned int tokenize(char *res[], unsigned int reslen, char *str, char delim) {
  char *s;
  unsigned int i;
  i = 0;
  s = str;
  while (i < reslen && *s) {
    while (*s == delim)
      *(s++) = '\0';
    if (*s)
      res[i++] = s;
    while (*s && *s != delim)
      s++;
  }
  return i;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<whisperPrintInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %ecx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0xa,-0x50(%rbp)
  jne    L79
  mov    -0x4c(%rbp),%edx
  mov    -0x48(%rbp),%ecx
  mov    -0x44(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <whisperPrintDecimal@plt>
  jmp    L20
L79:
  movl   $0x0,-0x38(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x8,-0x50(%rbp)
  jne    L94
L3:
  mov    -0x34(%rbp),%eax
  and    $0x7,%eax
  add    $0x30,%eax
  mov    %al,-0x39(%rbp)
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  cltq
  movzbl -0x39(%rbp),%edx
  mov    %dl,-0x20(%rbp,%rax,1)
  shrl   $0x3,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L3
  jmp    L139
L94:
  cmpl   $0x10,-0x50(%rbp)
  jne    L17
L59:
  mov    -0x34(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,-0x2c(%rbp)
  cmpl   $0x9,-0x2c(%rbp)
  jg     L136
  mov    -0x2c(%rbp),%eax
  add    $0x30,%eax
  jmp    L42
L136:
  mov    -0x2c(%rbp),%eax
  add    $0x57,%eax
L42:
  mov    %al,-0x3a(%rbp)
  mov    -0x38(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x38(%rbp)
  cltq
  movzbl -0x3a(%rbp),%edx
  mov    %dl,-0x20(%rbp,%rax,1)
  shrl   $0x4,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  jne    L59
  jmp    L139
L17:
  mov    $0xffffffff,%eax
  jmp    L20
L139:
  mov    -0x38(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  lea    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x30(%rbp)
  jmp    L124
L15:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <whisperPutc@plt>
  addl   $0x1,-0x30(%rbp)
L124:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x30(%rbp)
  jb     L15
  mov    -0x38(%rbp),%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L103
  call   <__stack_chk_fail@plt>
L103:
  leave
  ret
```

assistant: ```c
int whisperPrintInt(int value, int width, int pad, int base) {
  if (base == 10)
    return whisperPrintDecimal(value, width, pad);
  char buffer[20];
  int charCount = 0;
  unsigned uu = value;
  if (base == 8) {
    do {
      char c = '0' + (uu & 7);
      buffer[charCount++] = c;
      uu >>= 3;
    } while (uu);
  } else if (base == 16) {
    do {
      int digit = uu & 0xf;
      char c = digit < 10 ? '0' + digit : 'a' + digit - 10;
      buffer[charCount++] = c;
      uu >>= 4;
    } while (uu);
  } else
    return -1;
  char *p = buffer + charCount - 1;
  for (unsigned i = 0; i < charCount; ++i)
    whisperPutc(*p--);
  return charCount;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<whisperPrintInt>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0xa,%ecx
  je     L82
  cmp    $0x8,%ecx
  je     L52
  cmp    $0x10,%ecx
  jne    L48
  mov    $0x1,%eax
  lea    -0x1(%rsp),%r8
L3:
  mov    %edi,%ecx
  and    $0xf,%ecx
  lea    0x30(%rcx),%esi
  lea    0x57(%rcx),%edx
  cmp    $0x9,%ecx
  cmovle %esi,%edx
  mov    %eax,%ebp
  mov    %dl,(%r8,%rax,1)
  add    $0x1,%rax
  shr    $0x4,%edi
  jne    L3
L89:
  movslq %ebp,%rax
  lea    -0x1(%rsp,%rax,1),%rbx
  test   %ebp,%ebp
  je     L30
  lea    -0x1(%rbp),%r12d
  not    %r12
  add    %rbx,%r12
L29:
  sub    $0x1,%rbx
  movsbl 0x1(%rbx),%edi
  call   <whisperPutc@plt>
  cmp    %r12,%rbx
  jne    L29
L46:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    %ebp,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L82:
  call   <whisperPrintDecimal@plt>
  mov    %eax,%ebp
  jmp    L46
L52:
  mov    $0x1,%eax
  lea    -0x1(%rsp),%rcx
L47:
  mov    %eax,%ebp
  mov    %edi,%edx
  and    $0x7,%edx
  add    $0x30,%edx
  mov    %dl,(%rcx,%rax,1)
  add    $0x1,%rax
  shr    $0x3,%edi
  jne    L47
  jmp    L89
L48:
  mov    $0xffffffff,%ebp
  jmp    L46
L30:
  mov    $0x0,%ebp
  jmp    L46
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int whisperPrintInt(int value, int width, int pad, int base) {
  if (base == 10)
    return whisperPrintDecimal(value, width, pad);
  char buffer[20];
  int charCount = 0;
  unsigned uu = value;
  if (base == 8) {
    do {
      char c = '0' + (uu & 7);
      buffer[charCount++] = c;
      uu >>= 3;
    } while (uu);
  } else if (base == 16) {
    do {
      int digit = uu & 0xf;
      char c = digit < 10 ? '0' + digit : 'a' + digit - 10;
      buffer[charCount++] = c;
      uu >>= 4;
    } while (uu);
  } else
    return -1;
  char *p = buffer + charCount - 1;
  for (unsigned i = 0; i < charCount; ++i)
    whisperPutc(*p--);
  return charCount;
}
```