ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jne    L4
L28:
  mov    %rsp,%rsi
  mov    %r8d,%edi
  call   <getNumberAsBin@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r8d
  jmp    L28
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *args[]) {
  int n;
  if (argc)
    n = atoi(args[1]);
  char *binBuff;
  getNumberAsBin(n, &binBuff);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jne    L27
L28:
  mov    %rsp,%rsi
  mov    %r8d,%edi
  call   <getNumberAsBin@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L27:
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  mov    %eax,%r8d
  jmp    L28
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char *args[]) {
  int n;
  if (argc)
    n = atoi(args[1]);
  char *binBuff;
  getNumberAsBin(n, &binBuff);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<draw_box>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edx
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,%edi
  call   <attrset@plt>
  movl   $0xfffffffb,-0x8(%rbp)
  jmp    L18
L28:
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x2b,%edx
  mov    %eax,%esi
  mov    $0x9,%edi
  call   <mvaddch@plt>
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x2b,%edx
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <mvaddch@plt>
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x2b,%edx
  mov    %eax,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x2b,%edx
  mov    %eax,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x2b,%edx
  mov    %eax,%esi
  mov    $0xd,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x8(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  add    $0x4,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L28
  movl   $0xfffffffd,-0x8(%rbp)
  jmp    L14
L26:
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x20,%edx
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <mvaddch@plt>
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x20,%edx
  mov    %eax,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x28,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    $0x20,%edx
  mov    %eax,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  addl   $0x1,-0x8(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  add    $0x2,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L26
  nop
  nop
  leave
  ret
```

assistant: ```c
void draw_box(int width) {
  int x;
  int half = width / 2;
  attrset(COLOR_PAIR(COLOR_WHITE) | A_BOLD);
  for (x = -5; x < width + 5; x++) {
    mvaddch(23 / 2 - 2, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 2, (80 / 2) - half + x, '+');
  }
  for (x = -3; x < width + 3; x++) {
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, ' ');
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<draw_box>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %edi,%r13d
  shr    $0x1f,%r13d
  add    %edi,%r13d
  sar    %r13d
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <COLOR_PAIR@plt>
  mov    D16(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edi
  call   <attrset@plt>
  lea    0x4(%r12),%r15d
  cmp    $0xfffffffb,%r15d
  jl     L17
  mov    $0xfffffffb,%ebp
  mov    $0x28,%r14d
  sub    %r13d,%r14d
L5:
  lea    (%r14,%rbp,1),%ebx
  mov    $0x2b,%edx
  mov    %ebx,%esi
  mov    $0x9,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebx,%esi
  mov    $0xa,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebx,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebx,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebx,%esi
  mov    $0xd,%edi
  call   <mvaddch@plt>
  add    $0x1,%ebp
  cmp    %r15d,%ebp
  jle    L5
L17:
  add    $0x2,%r12d
  cmp    $0xfffffffd,%r12d
  jl     L20
  mov    $0xfffffffd,%ebx
  mov    $0x28,%r14d
  sub    %r13d,%r14d
L30:
  lea    (%r14,%rbx,1),%ebp
  mov    $0x20,%edx
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <mvaddch@plt>
  mov    $0x20,%edx
  mov    %ebp,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x20,%edx
  mov    %ebp,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jle    L30
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void draw_box(int width) {
  int x;
  int half = width / 2;
  attrset(COLOR_PAIR(COLOR_WHITE) | A_BOLD);
  for (x = -5; x < width + 5; x++) {
    mvaddch(23 / 2 - 2, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 2, (80 / 2) - half + x, '+');
  }
  for (x = -3; x < width + 3; x++) {
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, ' ');
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<draw_box>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x28,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  shr    $0x1f,%r13d
  mov    %edi,%r12d
  push   %rbp
  add    %edi,%r13d
  lea    0x4(%r12),%r15d
  push   %rbx
  sar    %r13d
  mov    $0xfffffffb,%ebx
  sub    %r13d,%r14d
  sub    $0x8,%rsp
  mov    D12(%rip),%rax
  mov    (%rax),%edi
  call   <COLOR_PAIR@plt>
  mov    D15(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edi
  call   <attrset@plt>
  cmp    $0xfffffffb,%r15d
  jl     L8
  nopl   0x0(%rax)
L38:
  lea    (%r14,%rbx,1),%ebp
  mov    $0x2b,%edx
  mov    $0x9,%edi
  add    $0x1,%ebx
  mov    %ebp,%esi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xd,%edi
  call   <mvaddch@plt>
  cmp    %r15d,%ebx
  jle    L38
L8:
  mov    $0x28,%ebx
  lea    0x2(%r12),%r14d
  mov    $0xfffffffd,%ebp
  sub    %r13d,%ebx
  cmp    $0xfffffffd,%r14d
  jl     L30
  nopl   0x0(%rax)
L32:
  lea    0x0(%rbp,%rbx,1),%r12d
  mov    $0x20,%edx
  mov    $0xa,%edi
  add    $0x1,%ebp
  mov    %r12d,%esi
  call   <mvaddch@plt>
  mov    $0x20,%edx
  mov    %r12d,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x20,%edx
  mov    %r12d,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  cmp    %r14d,%ebp
  jle    L32
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void draw_box(int width) {
  int x;
  int half = width / 2;
  attrset(COLOR_PAIR(COLOR_WHITE) | A_BOLD);
  for (x = -5; x < width + 5; x++) {
    mvaddch(23 / 2 - 2, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 2, (80 / 2) - half + x, '+');
  }
  for (x = -3; x < width + 3; x++) {
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, ' ');
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<draw_box>:
  endbr64
  push   %r15
  push   %r14
  mov    $0x28,%r14d
  push   %r13
  mov    %edi,%r13d
  push   %r12
  shr    $0x1f,%r13d
  mov    %edi,%r12d
  push   %rbp
  add    %edi,%r13d
  lea    0x4(%r12),%r15d
  push   %rbx
  sar    %r13d
  mov    $0xfffffffb,%ebx
  sub    %r13d,%r14d
  sub    $0x8,%rsp
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  call   <COLOR_PAIR@plt>
  mov    D2(%rip),%rdx
  or     (%rdx),%eax
  mov    %eax,%edi
  call   <attrset@plt>
  cmp    $0xfffffffb,%r15d
  jl     L23
  nopl   0x0(%rax)
L4:
  lea    (%r14,%rbx,1),%ebp
  mov    $0x2b,%edx
  mov    $0x9,%edi
  add    $0x1,%ebx
  mov    %ebp,%esi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  mov    $0x2b,%edx
  mov    %ebp,%esi
  mov    $0xd,%edi
  call   <mvaddch@plt>
  cmp    %r15d,%ebx
  jle    L4
L23:
  mov    $0x28,%ebx
  lea    0x2(%r12),%r14d
  mov    $0xfffffffd,%ebp
  sub    %r13d,%ebx
  cmp    $0xfffffffd,%r14d
  jl     L14
  nopl   0x0(%rax)
L34:
  lea    0x0(%rbp,%rbx,1),%r12d
  mov    $0x20,%edx
  mov    $0xa,%edi
  add    $0x1,%ebp
  mov    %r12d,%esi
  call   <mvaddch@plt>
  mov    $0x20,%edx
  mov    %r12d,%esi
  mov    $0xb,%edi
  call   <mvaddch@plt>
  mov    $0x20,%edx
  mov    %r12d,%esi
  mov    $0xc,%edi
  call   <mvaddch@plt>
  cmp    %r14d,%ebp
  jle    L34
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void draw_box(int width) {
  int x;
  int half = width / 2;
  attrset(COLOR_PAIR(COLOR_WHITE) | A_BOLD);
  for (x = -5; x < width + 5; x++) {
    mvaddch(23 / 2 - 2, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, '+');
    mvaddch(23 / 2 + 2, (80 / 2) - half + x, '+');
  }
  for (x = -3; x < width + 3; x++) {
    mvaddch(23 / 2 - 1, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 0, (80 / 2) - half + x, ' ');
    mvaddch(23 / 2 + 1, (80 / 2) - half + x, ' ');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<simd_alignment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  mov    %eax,-0x20(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  and    $0x10000000,%eax
  test   %eax,%eax
  je     L3
  mov    $0x20,%eax
  jmp    L19
L3:
  mov    -0x14(%rbp),%eax
  and    $0x2000000,%eax
  test   %eax,%eax
  je     L46
  mov    $0x10,%eax
  jmp    L19
L46:
  mov    $0x4,%eax
L19:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int simd_alignment(void) {
  int cpuinfo[4];
  cpuinfo[0] = 1;
  __asm__ __volatile__("mov %%ebx, %%edi;"
                       "cpuid;"
                       "mov %%ebx, %%esi;"
                       "mov %%edi, %%ebx;"
                       : "+a"(cpuinfo[0]), "=S"(cpuinfo[1]), "=c"(cpuinfo[2]), "=d"(cpuinfo[3])
                       :
                       : "edi");
  if (cpuinfo[2] & (1 << 28))
    return 32;
  else if (cpuinfo[3] & (1 << 25))
    return 16;
  else
    return 4;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<simd_alignment>:
  endbr64
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  mov    $0x20,%eax
  test   $0x10000000,%ecx
  jne    L1
  and    $0x2000000,%edx
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff4,%eax
  add    $0x10,%eax
L1:
  ret
```

assistant: ```c
int simd_alignment(void) {
  int cpuinfo[4];
  cpuinfo[0] = 1;
  __asm__ __volatile__("mov %%ebx, %%edi;"
                       "cpuid;"
                       "mov %%ebx, %%esi;"
                       "mov %%edi, %%ebx;"
                       : "+a"(cpuinfo[0]), "=S"(cpuinfo[1]), "=c"(cpuinfo[2]), "=d"(cpuinfo[3])
                       :
                       : "edi");
  if (cpuinfo[2] & (1 << 28))
    return 32;
  else if (cpuinfo[3] & (1 << 25))
    return 16;
  else
    return 4;
}
```
user: What is the c source code of the assembly code below:

```asm
<simd_alignment>:
  endbr64
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  and    $0x10000000,%ecx
  mov    $0x20,%eax
  jne    L6
  and    $0x2000000,%edx
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff4,%eax
  add    $0x10,%eax
L6:
  ret
```

assistant: ```c
int simd_alignment(void) {
  int cpuinfo[4];
  cpuinfo[0] = 1;
  __asm__ __volatile__("mov %%ebx, %%edi;"
                       "cpuid;"
                       "mov %%ebx, %%esi;"
                       "mov %%edi, %%ebx;"
                       : "+a"(cpuinfo[0]), "=S"(cpuinfo[1]), "=c"(cpuinfo[2]), "=d"(cpuinfo[3])
                       :
                       : "edi");
  if (cpuinfo[2] & (1 << 28))
    return 32;
  else if (cpuinfo[3] & (1 << 25))
    return 16;
  else
    return 4;
}
```
user: Translate the below assembly code into C programming language:

```asm
<simd_alignment>:
  endbr64
  mov    $0x1,%eax
  mov    %ebx,%edi
  cpuid
  mov    %ebx,%esi
  mov    %edi,%ebx
  and    $0x10000000,%ecx
  mov    $0x20,%eax
  jne    L8
  and    $0x2000000,%edx
  cmp    $0x1,%edx
  sbb    %eax,%eax
  and    $0xfffffff4,%eax
  add    $0x10,%eax
L8:
  ret
```

assistant: ```c
int simd_alignment(void) {
  int cpuinfo[4];
  cpuinfo[0] = 1;
  __asm__ __volatile__("mov %%ebx, %%edi;"
                       "cpuid;"
                       "mov %%ebx, %%esi;"
                       "mov %%edi, %%ebx;"
                       : "+a"(cpuinfo[0]), "=S"(cpuinfo[1]), "=c"(cpuinfo[2]), "=d"(cpuinfo[3])
                       :
                       : "edi");
  if (cpuinfo[2] & (1 << 28))
    return 32;
  else if (cpuinfo[3] & (1 << 25))
    return 16;
  else
    return 4;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<depth_type>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  D36(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L13
  lea    D6(%rip),%rax
  jmp    L30
L13:
  movsd  -0x8(%rbp),%xmm0
  comisd D17(%rip),%xmm0
  jbe    L29
  lea    D24(%rip),%rax
  jmp    L30
L29:
  lea    D1(%rip),%rax
L30:
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D36
type_infered: f64
name: parse_data
arguments: data_tag: D6
type_infered: string
name: parse_data
arguments: data_tag: D17
type_infered: f64
name: parse_data
arguments: data_tag: D24
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D36: 0.3001

tool: D6: wide

tool: D17: 0.6999

tool: D24: long

tool: D1: medium

assistant: ```c
char *depth_type(double d) {
  if (d < 0.3001)
    return "wide";
  if (d > 0.6999)
    return "long";
  return "medium";
}
```
user: What is the c source code of the assembly code below:

```asm
<depth_type>:
  endbr64
  lea    D43(%rip),%rax
  movsd  D45(%rip),%xmm1
  comisd %xmm0,%xmm1
  ja     L3
  comisd D32(%rip),%xmm0
  lea    D1(%rip),%rax
  lea    D18(%rip),%rdx
  cmovbe %rdx,%rax
L3:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D43
data_type: string
name: retrieve_data
arguments: label: D45
data_type: f64
name: retrieve_data
arguments: label: D32
data_type: f64
name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D43: wide

tool: D45: 0.3001

tool: D32: 0.6999

tool: D1: long

tool: D18: medium

assistant: ```c
char *depth_type(double d) {
  if (d < 0.3001)
    return "wide";
  if (d > 0.6999)
    return "long";
  return "medium";
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<depth_type>:
  endbr64
  movsd  D3(%rip),%xmm1
  lea    D48(%rip),%rax
  comisd %xmm0,%xmm1
  ja     L4
  comisd D18(%rip),%xmm0
  lea    D24(%rip),%rax
  lea    D49(%rip),%rdx
  cmovbe %rdx,%rax
L4:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: f64
name: disassemble_data
arguments: tag: D48
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: f64
name: disassemble_data
arguments: tag: D24
type_infered: string
name: disassemble_data
arguments: tag: D49
type_infered: string

tool: D3: 0.3001

tool: D48: wide

tool: D18: 0.6999

tool: D24: long

tool: D49: medium

assistant: ```c
char *depth_type(double d) {
  if (d < 0.3001)
    return "wide";
  if (d > 0.6999)
    return "long";
  return "medium";
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<depth_type>:
  endbr64
  movsd  D9(%rip),%xmm1
  lea    D10(%rip),%rax
  comisd %xmm0,%xmm1
  ja     L4
  comisd D18(%rip),%xmm0
  lea    D15(%rip),%rax
  lea    D1(%rip),%rdx
  cmovbe %rdx,%rax
L4:
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type_guessed: f64
name: unpack_data
arguments: data_tag: D10
type_guessed: string
name: unpack_data
arguments: data_tag: D18
type_guessed: f64
name: unpack_data
arguments: data_tag: D15
type_guessed: string
name: unpack_data
arguments: data_tag: D1
type_guessed: string

tool: D9: 0.3001

tool: D10: wide

tool: D18: 0.6999

tool: D15: long

tool: D1: medium

assistant: ```c
char *depth_type(double d) {
  if (d < 0.3001)
    return "wide";
  if (d > 0.6999)
    return "long";
  return "medium";
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <abc@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
type_guessed: string

tool: D2: Enter a string: 

assistant: ```c
int main() {
  char s[50];
  printf("Enter a string: ");
  gets(s);
  abc(s);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <abc@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D5
type: string

tool: D5: Enter a string: 

assistant: ```c
int main() {
  char s[50];
  printf("Enter a string: ");
  gets(s);
  abc(s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <abc@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: Enter a string: 

assistant: ```c
int main() {
  char s[50];
  printf("Enter a string: ");
  gets(s);
  abc(s);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  mov    %rbp,%rdi
  call   <abc@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: Enter a string: 

assistant: ```c
int main() {
  char s[50];
  printf("Enter a string: ");
  gets(s);
  abc(s);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<g>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x2,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <h@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L27
  mov    $0x0,%eax
  call   <link_error@plt>
L27:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  je     L8
  mov    $0x0,%eax
  call   <link_error@plt>
L8:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <g1@plt>
  mov    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L29
  mov    $0x0,%eax
  call   <link_error@plt>
L29:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  je     L33
  mov    $0x0,%eax
  call   <link_error@plt>
L33:
  cmpl   $0x2,-0xc(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int g(void) {
  int t = 0, t1 = 2;
  int t2 = h(&t, &t1);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  g1(t2);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  return t2 == 2;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<g>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x2,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <h@plt>
  mov    %eax,%ebx
  cmpl   $0x0,(%rsp)
  jne    L72
L10:
  cmpl   $0x2,0x4(%rsp)
  jne    L83
L41:
  mov    %ebx,%edi
  call   <g1@plt>
  cmpl   $0x0,(%rsp)
  jne    L77
L39:
  cmpl   $0x2,0x4(%rsp)
  jne    L50
L23:
  cmp    $0x2,%ebx
  sete   %al
  movzbl %al,%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L86
  add    $0x10,%rsp
  pop    %rbx
  ret
L72:
  mov    $0x0,%eax
  call   <link_error@plt>
  jmp    L10
L83:
  mov    $0x0,%eax
  call   <link_error@plt>
  jmp    L41
L77:
  mov    $0x0,%eax
  call   <link_error@plt>
  jmp    L39
L50:
  mov    $0x0,%eax
  call   <link_error@plt>
  jmp    L23
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int g(void) {
  int t = 0, t1 = 2;
  int t2 = h(&t, &t1);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  g1(t2);
  if (t != 0)
    link_error();
  if (t1 != 2)
    link_error();
  return t2 == 2;
}
```