ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1a8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1ac(%rbp)
  mov    -0x1a8(%rbp),%rdx
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  add    %rcx,%rax
  and    $0xf,%eax
  sub    %rcx,%rax
  mov    %rax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  lea    0xf(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x4,%rax
  mov    %eax,-0x1b4(%rbp)
  movl   $0x1,-0x1b0(%rbp)
  jmp    L31
L46:
  mov    -0x1a8(%rbp),%rax
  cqto
  shr    $0x3c,%rdx
  add    %rdx,%rax
  and    $0xf,%eax
  sub    %rdx,%rax
  mov    %eax,%edx
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  mov    -0x1a8(%rbp),%rdx
  mov    -0x1a8(%rbp),%rax
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  add    %rcx,%rax
  and    $0xf,%eax
  sub    %rcx,%rax
  mov    %rax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  lea    0xf(%rax),%rdx
  test   %rax,%rax
  cmovs  %rdx,%rax
  sar    $0x4,%rax
  mov    %eax,-0x1b4(%rbp)
  mov    -0x1b4(%rbp),%eax
  cltq
  mov    %rax,-0x1a8(%rbp)
  addl   $0x1,-0x1ac(%rbp)
  addl   $0x1,-0x1b0(%rbp)
L31:
  cmpl   $0x64,-0x1b0(%rbp)
  jg     L59
  cmpl   $0x0,-0x1b4(%rbp)
  jg     L46
L59:
  movl   $0x1,-0x1b0(%rbp)
  jmp    L5
L28:
  mov    -0x1b0(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x1b0(%rbp)
L5:
  mov    -0x1b0(%rbp),%eax
  cmp    -0x1ac(%rbp),%eax
  jle    L28
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D15
data_type: string
name: parse_data
arguments: data_label: D16
data_type: string

tool: D15: %ld

tool: D16: %d


assistant: ```c
main() {
  long int inp;
  scanf("%ld", &inp);
  int q, hst[100], i, c = 0;
  q = ((inp - (inp % 16)) / 16);
  for (i = 1; i <= 100 && q > 0; ++i) {
    hst[i] = inp % 16;
    q = ((inp - (inp % 16)) / 16);
    inp = q;
    c = c + 1;
  }
  for (i = 1; i <= c; ++i)
    printf("%d\n", hst[i]);
  getch();
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rax,%rcx,1),%rdx
  and    $0xf,%edx
  sub    %rcx,%rdx
  mov    %rax,%rcx
  sub    %rdx,%rcx
  lea    0xf(%rcx),%rdx
  cmovns %rcx,%rdx
  sar    $0x4,%rdx
  test   %edx,%edx
  jle    L28
  mov    $0x2,%esi
  mov    $0x0,%edi
L36:
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rax,%rcx,1),%rdx
  and    $0xf,%edx
  sub    %rcx,%rdx
  mov    %edx,0xc(%rsp,%rsi,4)
  sub    %rdx,%rax
  lea    0xf(%rax),%rdx
  cmovns %rax,%rdx
  sar    $0x4,%rdx
  movslq %edx,%rax
  mov    %edi,%ebp
  add    $0x1,%edi
  cmp    $0x64,%esi
  setle  %cl
  test   %edx,%edx
  setg   %dl
  add    $0x1,%rsi
  test   %dl,%cl
  jne    L36
  mov    %rax,0x8(%rsp)
  test   %edi,%edi
  jle    L28
  mov    $0x0,%ebx
  lea    D1(%rip),%r12
L17:
  mov    0x14(%rsp,%rbx,4),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %ebx,%ebp
  jge    L17
L28:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  mov    $0x0,%eax
  add    $0x1b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: string
name: unpack_data
arguments: data_label: D1
type: string

tool: D9: %ld

tool: D1: %d


assistant: ```c
main() {
  long int inp;
  scanf("%ld", &inp);
  int q, hst[100], i, c = 0;
  q = ((inp - (inp % 16)) / 16);
  for (i = 1; i <= 100 && q > 0; ++i) {
    hst[i] = inp % 16;
    q = ((inp - (inp % 16)) / 16);
    inp = q;
    c = c + 1;
  }
  for (i = 1; i <= c; ++i)
    printf("%d\n", hst[i]);
  getch();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D8(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x10(%rsp),%rdi
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rax,%rcx,1),%rdx
  and    $0xf,%edx
  sub    %rcx,%rdx
  mov    %rax,%rcx
  sub    %rdx,%rcx
  lea    0xf(%rcx),%rdx
  cmovns %rcx,%rdx
  xor    %esi,%esi
  sar    $0x4,%rdx
  test   %edx,%edx
  jle    L39
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rax,%rcx,1),%rdx
  and    $0xf,%edx
  sub    %rcx,%rdx
  mov    %rsi,%rcx
  sub    %rdx,%rax
  mov    %edx,0x4(%rdi,%rsi,4)
  lea    0xf(%rax),%rdx
  cmovns %rax,%rdx
  add    $0x1,%rsi
  sar    $0x4,%rdx
  movslq %edx,%rax
  test   %edx,%edx
  jg     L10
  mov    %rax,0x8(%rsp)
  lea    0x14(%rsp),%rbx
  lea    0x18(%rsp,%rcx,4),%r12
  lea    D3(%rip),%rbp
  nopl   0x0(%rax)
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
L39:
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string
name: unpack_data
arguments: data_label: D3
datatype: string

tool: D8: %ld

tool: D3: %d


assistant: ```c
main() {
  long int inp;
  scanf("%ld", &inp);
  int q, hst[100], i, c = 0;
  q = ((inp - (inp % 16)) / 16);
  for (i = 1; i <= 100 && q > 0; ++i) {
    hst[i] = inp % 16;
    q = ((inp - (inp % 16)) / 16);
    inp = q;
    c = c + 1;
  }
  for (i = 1; i <= c; ++i)
    printf("%d\n", hst[i]);
  getch();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x1b0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x10(%rsp),%rdi
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rax,%rcx,1),%rdx
  and    $0xf,%edx
  sub    %rcx,%rdx
  mov    %rax,%rcx
  sub    %rdx,%rcx
  lea    0xf(%rcx),%rdx
  cmovns %rcx,%rdx
  xor    %esi,%esi
  sar    $0x4,%rdx
  test   %edx,%edx
  jle    L37
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3c,%rcx
  lea    (%rax,%rcx,1),%rdx
  and    $0xf,%edx
  sub    %rcx,%rdx
  mov    %rsi,%rcx
  sub    %rdx,%rax
  mov    %edx,0x4(%rdi,%rsi,4)
  lea    0xf(%rax),%rdx
  cmovns %rax,%rdx
  add    $0x1,%rsi
  sar    $0x4,%rdx
  movslq %edx,%rax
  test   %edx,%edx
  jg     L34
  mov    %rax,0x8(%rsp)
  lea    0x14(%rsp),%rbx
  lea    0x18(%rsp,%rcx,4),%r12
  lea    D11(%rip),%rbp
  nopl   0x0(%rax)
L12:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L12
L37:
  xor    %eax,%eax
  call   <getch@plt>
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x1b0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D11
datatype: string

tool: D9: %ld

tool: D11: %d


assistant: ```c
main() {
  long int inp;
  scanf("%ld", &inp);
  int q, hst[100], i, c = 0;
  q = ((inp - (inp % 16)) / 16);
  for (i = 1; i <= 100 && q > 0; ++i) {
    hst[i] = inp % 16;
    q = ((inp - (inp % 16)) / 16);
    inp = q;
    c = c + 1;
  }
  for (i = 1; i <= c; ++i)
    printf("%d\n", hst[i]);
  getch();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  cmp    $0x1,%eax
  jne    L40
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L78
L40:
  movl   $0x0,-0x14(%rbp)
  movl   $0xffffffff,-0x10(%rbp)
  jmp    L56
L27:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L74
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x10(%rbp)
L74:
  mov    -0x18(%rbp),%eax
  add    %eax,-0x14(%rbp)
L56:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L27
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L24
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  jmp    L46
L24:
  mov    -0x14(%rbp),%eax
L46:
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L78:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type: string
name: disassemble_data
arguments: data_tag: D36
type: string
name: disassemble_data
arguments: data_tag: D15
type: string

tool: D11: %d

tool: D36: %d


tool: D15: %llu


assistant: ```c
int main() {
  int32_t n;
  scanf("%d", &n);
  if (n == 1) {
    scanf("%d", &n);
    printf("%d\n", n);
  } else {
    uint64_t total = 0;
    int32_t max = -1;
    while (n--) {
      int next;
      scanf("%d", &next);
      if (next > max)
        max = next;
      total += next;
    }
    uint64_t rest = total - max;
    printf("%llu\n", rest < max ? max << 1 : total);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  cmp    $0x1,%ebp
  je     L6
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  test   %ebp,%ebp
  je     L27
  mov    $0xffffffff,%ebx
  mov    $0x0,%ebp
  lea    D43(%rip),%r12
L33:
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  add    %eax,%ebp
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L33
  mov    %ebp,%edx
  sub    %ebx,%edx
  lea    (%rbx,%rbx,1),%eax
  cmp    %ebx,%edx
  cmovl  %eax,%ebp
L27:
  mov    %ebp,%esi
  lea    D35(%rip),%rdi
  call   <printf@plt>
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    %rsp,%rsi
  lea    D43(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  jmp    L11
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D43
type_infered: string
name: extract_symbolic_data
arguments: label: D35
type_infered: string
name: extract_symbolic_data
arguments: label: D32
type_infered: string

tool: D43: %d

tool: D35: %llu


tool: D32: %d


assistant: ```c
int main() {
  int32_t n;
  scanf("%d", &n);
  if (n == 1) {
    scanf("%d", &n);
    printf("%d\n", n);
  } else {
    uint64_t total = 0;
    int32_t max = -1;
    while (n--) {
      int next;
      scanf("%d", &next);
      if (next > max)
        max = next;
      total += next;
    }
    uint64_t rest = total - max;
    printf("%llu\n", rest < max ? max << 1 : total);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  cmp    $0x1,%ebp
  je     L0
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  test   %ebp,%ebp
  je     L27
  mov    $0xffffffff,%ebx
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L34:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  add    %eax,%ebp
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L34
  mov    %ebp,%edx
  lea    (%rbx,%rbx,1),%eax
  sub    %ebx,%edx
  cmp    %ebx,%edx
  cmovl  %eax,%ebp
L27:
  mov    %ebp,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D22
data_type: string
name: disassemble_data
arguments: data_label: D5
data_type: string
name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D22: %d

tool: D5: %llu


tool: D8: %d


assistant: ```c
int main() {
  int32_t n;
  scanf("%d", &n);
  if (n == 1) {
    scanf("%d", &n);
    printf("%d\n", n);
  } else {
    uint64_t total = 0;
    int32_t max = -1;
    while (n--) {
      int next;
      scanf("%d", &next);
      if (next > max)
        max = next;
      total += next;
    }
    uint64_t rest = total - max;
    printf("%llu\n", rest < max ? max << 1 : total);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D23(%rip),%r13
  push   %r12
  mov    %r13,%rdi
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebp
  cmp    $0x1,%ebp
  je     L44
  lea    -0x1(%rbp),%eax
  mov    %eax,(%rsp)
  test   %ebp,%ebp
  je     L10
  mov    $0xffffffff,%ebx
  xor    %ebp,%ebp
  lea    0x4(%rsp),%r12
  nopl   0x0(%rax)
L5:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  add    %eax,%ebp
  mov    (%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,(%rsp)
  test   %eax,%eax
  jne    L5
  mov    %ebp,%edx
  lea    (%rbx,%rbx,1),%eax
  sub    %ebx,%edx
  cmp    %ebx,%edx
  cmovl  %eax,%ebp
L10:
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L44:
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <scanf@plt>
  mov    (%rsp),%esi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D23
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string

tool: D23: %d

tool: D0: %llu


tool: D21: %d


assistant: ```c
int main() {
  int32_t n;
  scanf("%d", &n);
  if (n == 1) {
    scanf("%d", &n);
    printf("%d\n", n);
  } else {
    uint64_t total = 0;
    int32_t max = -1;
    while (n--) {
      int next;
      scanf("%d", &next);
      if (next > max)
        max = next;
      total += next;
    }
    uint64_t rest = total - max;
    printf("%llu\n", rest < max ? max << 1 : total);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<fclose>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fileno@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <op_fclose@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  mov    -0x4(%rbp),%eax
  jmp    L6
L5:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <wsocks_ctx_map_remove_by_fd@plt>
  mov    -0x4(%rbp),%eax
L6:
  leave
  ret
```

assistant: ```c
int fclose(FILE *fh) {
  int retval, fd;
  assert(fh);
  do {
  } while (0);
  fd = fileno(fh);
  retval = op_fclose(fh);
  if (retval != 0) {
    return retval;
  }
  wsocks_ctx_map_remove_by_fd(fd);
  return retval;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fclose>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <fileno@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <op_fclose@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  je     L15
L3:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  mov    %ebp,%edi
  call   <wsocks_ctx_map_remove_by_fd@plt>
  jmp    L3
```

assistant: ```c
int fclose(FILE *fh) {
  int retval, fd;
  assert(fh);
  do {
  } while (0);
  fd = fileno(fh);
  retval = op_fclose(fh);
  if (retval != 0) {
    return retval;
  }
  wsocks_ctx_map_remove_by_fd(fd);
  return retval;
}
```
user: What is the c source code of the assembly code below:

```asm
<fclose>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <fileno@plt>
  mov    %rbp,%rdi
  mov    %eax,%r13d
  call   <op_fclose@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L5
  mov    %r13d,%edi
  call   <wsocks_ctx_map_remove_by_fd@plt>
L5:
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int fclose(FILE *fh) {
  int retval, fd;
  assert(fh);
  do {
  } while (0);
  fd = fileno(fh);
  retval = op_fclose(fh);
  if (retval != 0) {
    return retval;
  }
  wsocks_ctx_map_remove_by_fd(fd);
  return retval;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x29,-0x40(%rbp)
  movl   $0x1f,-0x3c(%rbp)
  movl   $0x15,-0x38(%rbp)
  movl   $0xb,-0x34(%rbp)
  movl   $0xffffff9c,-0x30(%rbp)
  movl   $0xffffff38,-0x2c(%rbp)
  movl   $0xfffffed4,-0x28(%rbp)
  movl   $0xfffffe70,-0x24(%rbp)
  movl   $0x3,-0x20(%rbp)
  movl   $0xfffffff7,-0x1c(%rbp)
  movl   $0x1b,-0x18(%rbp)
  movl   $0xffffffaf,-0x14(%rbp)
  mov    -0x40(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  movq   $0x0,-0x50(%rbp)
  jmp    L36
L23:
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movq   $0x0,-0x48(%rbp)
  jmp    L22
L44:
  mov    -0x50(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addq   $0x1,-0x48(%rbp)
L22:
  cmpq   $0x3,-0x48(%rbp)
  jbe    L44
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addq   $0x1,-0x50(%rbp)
L36:
  cmpq   $0x2,-0x50(%rbp)
  jbe    L23
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D28
type_infered: string
name: read_data
arguments: tag: D20
type_infered: string
name: read_data
arguments: tag: D3
type_infered: string
name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D4
type_infered: string

tool: D28: values[0][0] == %d


tool: D20: values[2][1] == %d


tool: D3: [ 

tool: D32: %5d 

tool: D4: ]

assistant: ```c
int main(int argc, char **argv) {
  size_t i, j;
  int values[][4] = {
      {41, 31, 21, 11},
      {-100, -200, -300, -400},
      {3, -9, 27, -81},
  };
  printf("values[0][0] == %d\n", values[0][0]);
  printf("values[2][1] == %d\n", values[2][1]);
  printf("\n");
  for (i = 0; i < 3; i++) {
    printf("[ ");
    for (j = 0; j < 4; j++)
      printf("%5d ", values[i][j]);
    printf("]\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x29,(%rsp)
  movl   $0x1f,0x4(%rsp)
  movl   $0x15,0x8(%rsp)
  movl   $0xb,0xc(%rsp)
  movl   $0xffffff9c,0x10(%rsp)
  movl   $0xffffff38,0x14(%rsp)
  movl   $0xfffffed4,0x18(%rsp)
  movl   $0xfffffe70,0x1c(%rsp)
  movl   $0x3,0x20(%rsp)
  movl   $0xfffffff7,0x24(%rsp)
  movl   $0x1b,0x28(%rsp)
  movl   $0xffffffaf,0x2c(%rsp)
  mov    $0x29,%esi
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffff7,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    %rsp,%rbp
  lea    0x30(%rsp),%r15
  lea    D10(%rip),%r14
  lea    D0(%rip),%r12
  lea    D2(%rip),%r13
L15:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
L29:
  mov    0x0(%rbp,%rbx,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L29
  mov    %r13,%rdi
  call   <puts@plt>
  add    $0x10,%rbp
  cmp    %r15,%rbp
  jne    L15
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D43
datatype: string
name: parse_data
arguments: label: D20
datatype: string
name: parse_data
arguments: label: D10
datatype: string
name: parse_data
arguments: label: D0
datatype: string
name: parse_data
arguments: label: D2
datatype: string

tool: D43: values[0][0] == %d


tool: D20: values[2][1] == %d


tool: D10: [ 

tool: D0: %5d 

tool: D2: ]

assistant: ```c
int main(int argc, char **argv) {
  size_t i, j;
  int values[][4] = {
      {41, 31, 21, 11},
      {-100, -200, -300, -400},
      {3, -9, 27, -81},
  };
  printf("values[0][0] == %d\n", values[0][0]);
  printf("values[2][1] == %d\n", values[2][1]);
  printf("\n");
  for (i = 0; i < 3; i++) {
    printf("[ ");
    for (j = 0; j < 4; j++)
      printf("%5d ", values[i][j]);
    printf("]\n");
  }
  return 0;
}
```