ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uint_to_char>:
  endbr64
  sub    $0x1,%edx
  mov    %edi,%ecx
  mov    $0xcccccccd,%r9d
  movslq %edx,%rdi
  jns    L29
  jmp    L47
  cs nopw 0x0(%rax,%rax,1)
L36:
  add    $0x30,%eax
  mov    %r8d,%ecx
  mov    %al,(%rsi,%rdi,1)
  sub    $0x1,%rdi
  test   %edi,%edi
  js     L47
L29:
  mov    %ecx,%eax
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%r8d
  mov    %ecx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cmp    %ecx,%eax
  jne    L36
  lea    0x30(%rcx),%eax
  xor    %ecx,%ecx
  mov    %al,(%rsi,%rdi,1)
  sub    $0x1,%rdi
  test   %edi,%edi
  jns    L29
L47:
  ret
```

assistant: ```c
void uint_to_char(unsigned int val, unsigned char *buf, unsigned int len) {
  int i;
  for (i = (int)(len - 1); i >= 0; i--) {
    if ((val % 10) != val) {
      buf[i] = (unsigned char)((val % 10) + '0');
      val /= 10;
    } else {
      buf[i] = (unsigned char)(val + '0');
      val = 0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<uint_to_char>:
  endbr64
  sub    $0x1,%edx
  mov    %edi,%ecx
  mov    $0xcccccccd,%r9d
  movslq %edx,%rdi
  js     L16
  nopl   0x0(%rax)
L38:
  mov    %ecx,%eax
  imul   %r9,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  mov    %eax,%r8d
  mov    %ecx,%eax
  add    %edx,%edx
  sub    %edx,%eax
  cmp    %eax,%ecx
  je     L27
  add    $0x30,%eax
  mov    %r8d,%ecx
  mov    %al,(%rsi,%rdi,1)
  sub    $0x1,%rdi
  test   %edi,%edi
  jns    L38
  ret
  nopl   0x0(%rax)
L27:
  add    $0x30,%ecx
  mov    %cl,(%rsi,%rdi,1)
  sub    $0x1,%rdi
  test   %edi,%edi
  js     L16
  xor    %ecx,%ecx
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void uint_to_char(unsigned int val, unsigned char *buf, unsigned int len) {
  int i;
  for (i = (int)(len - 1); i >= 0; i--) {
    if ((val % 10) != val) {
      buf[i] = (unsigned char)((val % 10) + '0');
      val /= 10;
    } else {
      buf[i] = (unsigned char)(val + '0');
      val = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Snack_DoDispense>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L21
  cmpl   $0x63,-0x8(%rbp)
  jle    L10
L21:
  mov    $0xffffffff,%eax
  jmp    L23
L10:
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int Snack_DoDispense(int unused__User __attribute__((__unused__)), int Item) {
  if (Item < 0 || Item > 99)
    return -1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Snack_DoDispense>:
  endbr64
  cmp    $0x63,%esi
  seta   %al
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int Snack_DoDispense(int unused__User __attribute__((__unused__)), int Item) {
  if (Item < 0 || Item > 99)
    return -1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Snack_DoDispense>:
  endbr64
  xor    %eax,%eax
  cmp    $0x63,%esi
  seta   %al
  neg    %eax
  ret
```

assistant: ```c
int Snack_DoDispense(int unused__User __attribute__((__unused__)), int Item) {
  if (Item < 0 || Item > 99)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<Snack_DoDispense>:
  endbr64
  xor    %eax,%eax
  cmp    $0x63,%esi
  seta   %al
  neg    %eax
  ret
```

assistant: ```c
int Snack_DoDispense(int unused__User __attribute__((__unused__)), int Item) {
  if (Item < 0 || Item > 99)
    return -1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<aes_encrypt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <EVP_EncryptInit_ex@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edi
  mov    -0x30(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  mov    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <EVP_EncryptUpdate@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <EVP_EncryptFinal_ex@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned char *aes_encrypt(EVP_CIPHER_CTX *e, unsigned char *plaintext, int *len, int *retlen) {
  int rc = 0;
  int c_len = *len + AES_BLOCK_SIZE, f_len = 0;
  unsigned char *ciphertext = malloc(c_len);
  rc = EVP_EncryptInit_ex(e, NULL, NULL, NULL, NULL);
  assert(rc == 1);
  rc = EVP_EncryptUpdate(e, ciphertext, &c_len, plaintext, *len);
  assert(rc == 1);
  rc = EVP_EncryptFinal_ex(e, ciphertext + c_len, &f_len);
  assert(rc == 1);
  *len = c_len + f_len;
  return ciphertext;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<aes_encrypt>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  add    (%rdx),%edi
  mov    %edi,(%rsp)
  movl   $0x0,0x4(%rsp)
  call   <malloc@plt>
  mov    %rax,%r12
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <EVP_EncryptInit_ex@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rsp,%rdx
  mov    (%rbx),%r8d
  mov    %r13,%rcx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_EncryptUpdate@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  lea    0x4(%rsp),%rdx
  movslq (%rsp),%rsi
  add    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_EncryptFinal_ex@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    %r12,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *aes_encrypt(EVP_CIPHER_CTX *e, unsigned char *plaintext, int *len, int *retlen) {
  int rc = 0;
  int c_len = *len + AES_BLOCK_SIZE, f_len = 0;
  unsigned char *ciphertext = malloc(c_len);
  rc = EVP_EncryptInit_ex(e, NULL, NULL, NULL, NULL);
  assert(rc == 1);
  rc = EVP_EncryptUpdate(e, ciphertext, &c_len, plaintext, *len);
  assert(rc == 1);
  rc = EVP_EncryptFinal_ex(e, ciphertext + c_len, &f_len);
  assert(rc == 1);
  *len = c_len + f_len;
  return ciphertext;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<aes_encrypt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D3(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%edi
  add    (%rdx),%edi
  mov    %edi,(%rsp)
  call   <malloc@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_EncryptInit_ex@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%r8d
  mov    %r13,%rcx
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_EncryptUpdate@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  movslq (%rsp),%rsi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %r12,%rsi
  call   <EVP_EncryptFinal_ex@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *aes_encrypt(EVP_CIPHER_CTX *e, unsigned char *plaintext, int *len, int *retlen) {
  int rc = 0;
  int c_len = *len + AES_BLOCK_SIZE, f_len = 0;
  unsigned char *ciphertext = malloc(c_len);
  rc = EVP_EncryptInit_ex(e, NULL, NULL, NULL, NULL);
  assert(rc == 1);
  rc = EVP_EncryptUpdate(e, ciphertext, &c_len, plaintext, *len);
  assert(rc == 1);
  rc = EVP_EncryptFinal_ex(e, ciphertext + c_len, &f_len);
  assert(rc == 1);
  *len = c_len + f_len;
  return ciphertext;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<aes_encrypt>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    D6(%rip),%rax
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%edi
  add    (%rdx),%edi
  mov    %edi,(%rsp)
  call   <malloc@plt>
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <EVP_EncryptInit_ex@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    (%rbx),%r8d
  mov    %r13,%rcx
  mov    %rsp,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <EVP_EncryptUpdate@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  movslq (%rsp),%rsi
  lea    0x4(%rsp),%rdx
  mov    %rbp,%rdi
  add    %r12,%rsi
  call   <EVP_EncryptFinal_ex@plt>
  xor    %edi,%edi
  cmp    $0x1,%eax
  sete   %dil
  call   <assert@plt>
  mov    0x4(%rsp),%eax
  add    (%rsp),%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned char *aes_encrypt(EVP_CIPHER_CTX *e, unsigned char *plaintext, int *len, int *retlen) {
  int rc = 0;
  int c_len = *len + AES_BLOCK_SIZE, f_len = 0;
  unsigned char *ciphertext = malloc(c_len);
  rc = EVP_EncryptInit_ex(e, NULL, NULL, NULL, NULL);
  assert(rc == 1);
  rc = EVP_EncryptUpdate(e, ciphertext, &c_len, plaintext, *len);
  assert(rc == 1);
  rc = EVP_EncryptFinal_ex(e, ciphertext + c_len, &f_len);
  assert(rc == 1);
  *len = c_len + f_len;
  return ciphertext;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prm_next_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  or     $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L1
L8:
  addl   $0x2,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <prm_is_prime@plt>
  test   %eax,%eax
  je     L8
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned long prm_next_prime(unsigned int start) {
  unsigned int next;
  for (next = start | 1; !prm_is_prime(next); next += 2)
    ;
  return next;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prm_next_prime>:
  endbr64
  push   %rbx
  or     $0x1,%edi
  mov    %edi,%ebx
  jmp    L8
L2:
  add    $0x2,%ebx
L8:
  mov    %ebx,%edi
  call   <prm_is_prime@plt>
  test   %eax,%eax
  je     L2
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long prm_next_prime(unsigned int start) {
  unsigned int next;
  for (next = start | 1; !prm_is_prime(next); next += 2)
    ;
  return next;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prm_next_prime>:
  endbr64
  or     $0x1,%edi
  push   %rbx
  mov    %edi,%ebx
  jmp    L2
  nopl   0x0(%rax)
L18:
  add    $0x2,%ebx
L2:
  mov    %ebx,%edi
  call   <prm_is_prime@plt>
  test   %eax,%eax
  je     L18
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long prm_next_prime(unsigned int start) {
  unsigned int next;
  for (next = start | 1; !prm_is_prime(next); next += 2)
    ;
  return next;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prm_next_prime>:
  endbr64
  or     $0x1,%edi
  push   %rbx
  mov    %edi,%ebx
  jmp    L3
  nopl   0x0(%rax)
L16:
  add    $0x2,%ebx
L3:
  mov    %ebx,%edi
  call   <prm_is_prime@plt>
  test   %eax,%eax
  je     L16
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned long prm_next_prime(unsigned int start) {
  unsigned int next;
  for (next = start | 1; !prm_is_prime(next); next += 2)
    ;
  return next;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<matrix_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L23:
  movl   $0x0,-0x4(%rbp)
  jmp    L30
L17:
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <S@plt>
  addl   $0x1,-0x4(%rbp)
L30:
  mov    -0x30(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jg     L17
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x2c(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jg     L23
  nop
  nop
  leave
  ret
```

assistant: ```c
void matrix_add(double **x, double **a, double **b, int m, int n) {
  int i, j;
  for (i = 0; i <= m - 1; i++)
    for (j = 0; j <= n - 1; j++)
      S(i, j);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matrix_add>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %ecx,%r13d
  mov    %r8d,%r12d
  mov    $0x0,%ebp
  test   %ecx,%ecx
  jg     L48
L29:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L42:
  mov    %ebx,%esi
  mov    %ebp,%edi
  call   <S@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L42
L36:
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  je     L29
L48:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jg     L42
  jmp    L36
```

assistant: ```c
void matrix_add(double **x, double **a, double **b, int m, int n) {
  int i, j;
  for (i = 0; i <= m - 1; i++)
    for (j = 0; j <= n - 1; j++)
      S(i, j);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<matrix_add>:
  endbr64
  test   %ecx,%ecx
  jle    L1
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %ebx,%ebx
  test   %r12d,%r12d
  jle    L24
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <S@plt>
  cmp    %ebx,%r12d
  jne    L12
L24:
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L22
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  ret
```

assistant: ```c
void matrix_add(double **x, double **a, double **b, int m, int n) {
  int i, j;
  for (i = 0; i <= m - 1; i++)
    for (j = 0; j <= n - 1; j++)
      S(i, j);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<matrix_add>:
  endbr64
  test   %ecx,%ecx
  jle    L36
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  mov    %r8d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %r8d,%r8d
  jle    L16
  nop
L14:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%ebx
  call   <S@plt>
  cmp    %ebx,%r12d
  jne    L12
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L14
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L36:
  ret
```

assistant: ```c
void matrix_add(double **x, double **a, double **b, int m, int n) {
  int i, j;
  for (i = 0; i <= m - 1; i++)
    for (j = 0; j <= n - 1; j++)
      S(i, j);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<toCode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  sub    $0xa,%eax
  cmp    $0x5,%eax
  ja     L0
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D3(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D3(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x41,%eax
  jmp    L4
  mov    $0x42,%eax
  jmp    L4
  mov    $0x43,%eax
  jmp    L4
  mov    $0x44,%eax
  jmp    L4
  mov    $0x45,%eax
  jmp    L4
  mov    $0x46,%eax
  jmp    L4
L0:
  movzbl -0x4(%rbp),%eax
  add    $0x30,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
unsigned char toCode(unsigned char c) {
  switch (c) {
  case 10:
    return 'A';
  case 11:
    return 'B';
  case 12:
    return 'C';
  case 13:
    return 'D';
  case 14:
    return 'E';
  case 15:
    return 'F';
  default:
    return c + 48;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<toCode>:
  endbr64
  lea    -0xa(%rdi),%eax
  cmp    $0x5,%al
  ja     L5
  movzbl %al,%eax
  lea    D2(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x42,%eax
  ret
  mov    $0x43,%eax
  ret
  mov    $0x44,%eax
  ret
  mov    $0x45,%eax
  ret
  mov    $0x46,%eax
  ret
L5:
  lea    0x30(%rdi),%eax
  ret
  mov    $0x41,%eax
  ret
```

assistant: ```c
unsigned char toCode(unsigned char c) {
  switch (c) {
  case 10:
    return 'A';
  case 11:
    return 'B';
  case 12:
    return 'C';
  case 13:
    return 'D';
  case 14:
    return 'E';
  case 15:
    return 'F';
  default:
    return c + 48;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<toCode>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x37(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x5,%dl
  cmova  %edi,%eax
  ret
```

assistant: ```c
unsigned char toCode(unsigned char c) {
  switch (c) {
  case 10:
    return 'A';
  case 11:
    return 'B';
  case 12:
    return 'C';
  case 13:
    return 'D';
  case 14:
    return 'E';
  case 15:
    return 'F';
  default:
    return c + 48;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<toCode>:
  endbr64
  lea    -0xa(%rdi),%edx
  lea    0x37(%rdi),%eax
  add    $0x30,%edi
  cmp    $0x5,%dl
  cmova  %edi,%eax
  ret
```

assistant: ```c
unsigned char toCode(unsigned char c) {
  switch (c) {
  case 10:
    return 'A';
  case 11:
    return 'B';
  case 12:
    return 'C';
  case 13:
    return 'D';
  case 14:
    return 'E';
  case 15:
    return 'F';
  default:
    return c + 48;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<dummy_serve>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <mark_invoked@plt>
  mov    $0x4,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <has_flag@plt>
  test   %rax,%rax
  je     L9
  mov    $0xffffffff,%eax
  jmp    L16
L9:
  mov    $0x0,%eax
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type: string

tool: D3: rapp_serve

assistant: ```c
int dummy_serve(void *handle, void *http_request, void *response) {
  mark_invoked("rapp_serve");
  if (has_flag("rapp_serve", 0x04)) {
    return -1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<dummy_serve>:
  endbr64
  push   %rbx
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <mark_invoked@plt>
  mov    $0x4,%esi
  mov    %rbx,%rdi
  call   <has_flag@plt>
  neg    %rax
  sbb    %eax,%eax
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
data_type: string

tool: D4: rapp_serve

assistant: ```c
int dummy_serve(void *handle, void *http_request, void *response) {
  mark_invoked("rapp_serve");
  if (has_flag("rapp_serve", 0x04)) {
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<dummy_serve>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  mov    %rbp,%rdi
  call   <mark_invoked@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <has_flag@plt>
  pop    %rbp
  neg    %rax
  sbb    %eax,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: rapp_serve

assistant: ```c
int dummy_serve(void *handle, void *http_request, void *response) {
  mark_invoked("rapp_serve");
  if (has_flag("rapp_serve", 0x04)) {
    return -1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<dummy_serve>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rbp
  mov    %rbp,%rdi
  call   <mark_invoked@plt>
  mov    %rbp,%rdi
  mov    $0x4,%esi
  call   <has_flag@plt>
  pop    %rbp
  neg    %rax
  sbb    %eax,%eax
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5: rapp_serve

assistant: ```c
int dummy_serve(void *handle, void *http_request, void *response) {
  mark_invoked("rapp_serve");
  if (has_flag("rapp_serve", 0x04)) {
    return -1;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa8,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
L33:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  lea    0x30(%rax),%ecx
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  mov    %ecx,%edx
  cltq
  mov    %dl,-0x12(%rbp,%rax,1)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  je     L0
  jmp    L33
L0:
  nop
  subl   $0x1,-0x18(%rbp)
  jmp    L4
L21:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0x12(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x18(%rbp)
L4:
  cmpl   $0x0,-0x18(%rbp)
  jns    L21
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string
name: parse_data
arguments: data_label: D10
type_infered: string

tool: D8: %c

tool: 

assistant: ```c
int main(void) {
  int data = 168;
  char num[10];
  int i = 0;
  while (1) {
    num[i++] = data % 10 + '0';
    data /= 10;
    if (data == 0)
      break;
  }
  for (i -= 1; i >= 0; --i) {
    printf("%c", num[i]);
  }
  puts("");
  return 0;
}
```