ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<put_str_proc>:
  endbr64
  push   %r12
  lea    D114(%rip),%r12
  lea    D67(%rip),%rdi
  xor    %eax,%eax
  push   %rbp
  mov    %r12,%rsi
  lea    D81(%rip),%rbp
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdx
  xor    %eax,%eax
  lea    D82(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D31(%rip),%rdx
  xor    %eax,%eax
  lea    D43(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D104(%rip),%rdx
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  xor    %eax,%eax
  pop    %rbp
  lea    D27(%rip),%rdi
  pop    %r12
  jmp    1070 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D114
type_infered: string
name: parse_data
arguments: data_label: D67
type_infered: string
name: parse_data
arguments: data_label: D81
type_infered: string
name: parse_data
arguments: data_label: D2
type_infered: string
name: parse_data
arguments: data_label: D82
type_infered: string
name: parse_data
arguments: data_label: D31
type_infered: string
name: parse_data
arguments: data_label: D43
type_infered: string
name: parse_data
arguments: data_label: D104
type_infered: string
name: parse_data
arguments: data_label: D0
type_infered: string
name: parse_data
arguments: data_label: D68
type_infered: string
name: parse_data
arguments: data_label: D11
type_infered: string
name: parse_data
arguments: data_label: D27
type_infered: string

tool: D114: put_str

tool: D67: %s PROC


tool: D81: BX

tool: D2: OFFSET Parameters

tool: D82: 	MOV	%s, %s


tool: D31: Parameter_Offset

tool: D43: 	ADD	%s, %s


tool: D104: 2

tool: D0: 	SUB	%s, %s


tool: D68: 	_PutStr	WORD PTR [BX]

tool: D11: 	RET

tool: D27: %s ENDP


assistant: ```c
void put_str_proc() {
  printf("%s PROC\n", "put_str");
  ;
  printf("\tMOV\t%s, %s\n", "BX", "OFFSET Parameters");
  ;
  printf("\tADD\t%s, %s\n", "BX", "Parameter_Offset");
  ;
  printf("\tSUB\t%s, %s\n", "BX", "2");
  ;
  printf("\t_PutStr\tWORD PTR [BX]\n");
  printf("\tRET\n");
  ;
  printf("%s ENDP\n", "put_str");
  ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<norm_3d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addq   $0x8,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double norm_3d(double *x) {
  double out;
  out = *x * *x;
  x++;
  out += *x * *x;
  x++;
  out += *x * *x;
  return sqrt(out);
}
```
user: Translate the below assembly code into C programming language:

```asm
<norm_3d>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L9
  sqrtsd %xmm0,%xmm0
  ret
L9:
  sub    $0x8,%rsp
  call   <sqrt@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double norm_3d(double *x) {
  double out;
  out = *x * *x;
  x++;
  out += *x * *x;
  x++;
  out += *x * *x;
  return sqrt(out);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<norm_3d>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L6
  sqrtsd %xmm0,%xmm0
  ret
L6:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm_3d(double *x) {
  double out;
  out = *x * *x;
  x++;
  out += *x * *x;
  x++;
  out += *x * *x;
  return sqrt(out);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<norm_3d>:
  endbr64
  movsd  (%rdi),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  0x8(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  0x10(%rdi),%xmm0
  mulsd  %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L7
  sqrtsd %xmm0,%xmm0
  ret
L7:
  jmp    1050 <sqrt@plt>
```

assistant: ```c
double norm_3d(double *x) {
  double out;
  out = *x * *x;
  x++;
  out += *x * *x;
  x++;
  out += *x * *x;
  return sqrt(out);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<intcelcon_set_type_of_mixture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x8(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2f1,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int intcelcon_set_type_of_mixture(int r, int *mix) {
  int fail, i;
  double *c;
  fail = _ada_use_c2phc4c(753, &r, mix, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<intcelcon_set_type_of_mixture>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %rsi,%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x2f1,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int intcelcon_set_type_of_mixture(int r, int *mix) {
  int fail, i;
  double *c;
  fail = _ada_use_c2phc4c(753, &r, mix, c, 0);
  return fail;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<intcelcon_set_type_of_mixture>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x2f1,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int intcelcon_set_type_of_mixture(int r, int *mix) {
  int fail, i;
  double *c;
  fail = _ada_use_c2phc4c(753, &r, mix, c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<intcelcon_set_type_of_mixture>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x2f1,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int intcelcon_set_type_of_mixture(int r, int *mix) {
  int fail, i;
  double *c;
  fail = _ada_use_c2phc4c(753, &r, mix, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putch@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void puts(const char *text) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putch(text[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  jmp    L0
L7:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <putch@plt>
  add    $0x1,%rbx
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void puts(const char *text) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putch(text[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   0x0(%rax)
L19:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putch@plt>
L7:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void puts(const char *text) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putch(text[i]);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax)
L6:
  movsbl 0x0(%rbp,%rbx,1),%edi
  add    $0x1,%rbx
  call   <putch@plt>
L0:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void puts(const char *text) {
  int i;
  for (i = 0; i < strlen(text); i++) {
    putch(text[i]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rsi
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,%ecx
  mov    -0x14(%rbp),%eax
  mov    -0xc(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %ecx,%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type: string
name: parse_data
arguments: tag: D0
type: string

tool: D18: %d%d%d%d

tool: D0: %d


assistant: ```c
int main() {
  int x1, y1, x2, y2;
  scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
  printf("%d\n", abs(x1 - x2) + abs(y1 - y2));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    0x10(%rsp),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    0xc(%rsp),%eax
  sub    0x14(%rsp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %eax,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
data_type: string
name: unpack_data
arguments: tag: D13
data_type: string

tool: D15: %d%d%d%d

tool: D13: %d


assistant: ```c
int main() {
  int x1, y1, x2, y2;
  scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
  printf("%d\n", abs(x1 - x2) + abs(y1 - y2));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D1(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    0x10(%rsp),%eax
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    0xc(%rsp),%eax
  sub    0x14(%rsp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D4
type_infered: string

tool: D1: %d%d%d%d

tool: D4: %d


assistant: ```c
int main() {
  int x1, y1, x2, y2;
  scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
  printf("%d\n", abs(x1 - x2) + abs(y1 - y2));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D8(%rip),%rdi
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  sub    0x10(%rsp),%eax
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    0xc(%rsp),%eax
  sub    0x14(%rsp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  add    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D8
datatype: string
name: read_data
arguments: label: D6
datatype: string

tool: D8: %d%d%d%d

tool: D6: %d


assistant: ```c
int main() {
  int x1, y1, x2, y2;
  scanf("%d%d%d%d", &x1, &y1, &x2, &y2);
  printf("%d\n", abs(x1 - x2) + abs(y1 - y2));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<wad_strcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L14
L19:
  addq   $0x1,-0x8(%rbp)
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <wad_strcpy@plt>
  leave
  ret
```

assistant: ```c
char *wad_strcat(char *t, const char *s) {
  while (*t)
    t++;
  return wad_strcpy(t, s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<wad_strcat>:
  endbr64
  sub    $0x8,%rsp
  cmpb   $0x0,(%rdi)
  je     L0
L11:
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L11
L0:
  call   <wad_strcpy@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *wad_strcat(char *t, const char *s) {
  while (*t)
    t++;
  return wad_strcpy(t, s);
}
```
user: What is the c source code of the assembly code below:

```asm
<wad_strcat>:
  endbr64
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L19:
  add    $0x1,%rdi
L2:
  cmpb   $0x0,(%rdi)
  jne    L19
  jmp    1050 <wad_strcpy@plt>
```

assistant: ```c
char *wad_strcat(char *t, const char *s) {
  while (*t)
    t++;
  return wad_strcpy(t, s);
}
```
user: What is the c source code of the assembly code below:

```asm
<wad_strcat>:
  endbr64
  jmp    L12
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%rdi
L12:
  cmpb   $0x0,(%rdi)
  jne    L0
  jmp    1050 <wad_strcpy@plt>
```

assistant: ```c
char *wad_strcat(char *t, const char *s) {
  while (*t)
    t++;
  return wad_strcpy(t, s);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_to_hex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L25
L23:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xb(%rbp)
  movb   $0x0,-0xa(%rbp)
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L20
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L15
L20:
  mov    $0x0,%eax
  jmp    L59
L15:
  lea    -0xc(%rbp),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x2,-0x14(%rbp)
L25:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L23
  mov    $0x1,%eax
L59:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!isxdigit(tmpBuf[0]) || !isxdigit(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)0, 16);
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<string_to_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L31
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  sub    $0x1,%edx
  shr    %edx
  mov    %edx,%edx
  lea    0x2(%rdi,%rdx,2),%r13
  lea    0x4(%rsp),%r12
L39:
  movzbl (%rbx),%edi
  mov    %dil,0x4(%rsp)
  movzbl 0x1(%rbx),%eax
  mov    %al,0x5(%rsp)
  movb   $0x0,0x6(%rsp)
  movsbl %dil,%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L26
  movsbl 0x5(%rsp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L26
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <strtol@plt>
  mov    %al,0x0(%rbp)
  add    $0x2,%rbx
  add    $0x1,%rbp
  cmp    %r13,%rbx
  jne    L39
  mov    $0x1,%eax
L26:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  mov    $0x1,%eax
  jmp    L26
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!isxdigit(tmpBuf[0]) || !isxdigit(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)0, 16);
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<string_to_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L45
  sub    $0x1,%edx
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r12
  mov    %rsi,%rbp
  shr    %edx
  lea    0x2(%rdi,%rdx,2),%r13
  jmp    L21
  nopl   (%rax)
L47:
  movsbl 0x5(%rsp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L57
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <strtol@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbx
  je     L45
L21:
  movsbl (%rbx),%edi
  movzbl 0x1(%rbx),%eax
  movb   $0x0,0x6(%rsp)
  mov    %dil,0x4(%rsp)
  mov    %al,0x5(%rsp)
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L47
L57:
  xor    %eax,%eax
L8:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  mov    $0x1,%eax
  jmp    L8
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!isxdigit(tmpBuf[0]) || !isxdigit(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)0, 16);
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<string_to_hex>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %edx,%edx
  jle    L1
  sub    $0x1,%edx
  mov    %rdi,%rbx
  lea    0x4(%rsp),%r12
  mov    %rsi,%rbp
  shr    %edx
  lea    0x2(%rdi,%rdx,2),%r13
  jmp    L42
  nopl   (%rax)
L35:
  movsbl 0x5(%rsp),%edi
  call   <isxdigit@plt>
  test   %eax,%eax
  je     L23
  mov    $0x10,%edx
  xor    %esi,%esi
  mov    %r12,%rdi
  add    $0x2,%rbx
  call   <strtol@plt>
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  cmp    %r13,%rbx
  je     L1
L42:
  movsbl (%rbx),%edi
  xor    %eax,%eax
  movb   $0x0,0x6(%rsp)
  mov    %dil,%al
  mov    0x1(%rbx),%ah
  mov    %ax,0x4(%rsp)
  call   <isxdigit@plt>
  test   %eax,%eax
  jne    L35
L23:
  xor    %eax,%eax
L44:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0x1,%eax
  jmp    L44
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int string_to_hex(char *string, unsigned char *key, int len) {
  char tmpBuf[4];
  int idx, ii = 0;
  for (idx = 0; idx < len; idx += 2) {
    tmpBuf[0] = string[idx];
    tmpBuf[1] = string[idx + 1];
    tmpBuf[2] = 0;
    if (!isxdigit(tmpBuf[0]) || !isxdigit(tmpBuf[1]))
      return 0;
    key[ii++] = (unsigned char)strtol(tmpBuf, (char **)0, 16);
  }
  return 1;
}
```