ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<imgcelliter>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    %rdi,%rsi
  push   %r14
  movslq %ecx,%r14
  push   %r13
  mov    %r14d,%ecx
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %r15,%rdi
  mov    %edx,0x8(%rsp)
  mov    %r14d,0xc(%rsp)
  call   <imgcopy@plt>
  test   %ebx,%ebx
  jle    L36
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L42:
  mov    0xc(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jg     L89
  jmp    L77
  nopw   0x0(%rax,%rax,1)
L26:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L77
L89:
  mov    (%r15),%rax
  mov    (%rax,%rbx,4),%ecx
  test   %ecx,%ecx
  jle    L26
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r13d,%r8d
  mov    %r13d,%edi
  mov    (%rsp),%rdx
  mov    %eax,%esi
  movslq %r13d,%rax
  sar    $0x1f,%r8d
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %r8d,%eax
  mov    %esi,%r8d
  lea    (%rax,%rax,2),%eax
  sar    $0x1f,%r8d
  sub    %eax,%edi
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  lea    -0x1(%rbp,%rdi,1),%edi
  movslq %edi,%rdi
  shr    $0x20,%rax
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%esi
  lea    -0x1(%rsi,%rbx,1),%eax
  mov    (%rdx,%rdi,8),%rsi
  cltq
  lea    (%rsi,%rax,4),%rax
  mov    (%rax),%edx
  test   %edx,%edx
  je     L72
  add    $0x1,%rbx
  add    $0x1,%r12d
  cmp    %r14,%rbx
  jne    L89
  nopw   0x0(%rax,%rax,1)
L77:
  add    $0x1,%ebp
  add    $0x8,%r15
  cmp    %ebp,0x8(%rsp)
  jne    L42
L36:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  movl   $0xff,(%rax)
  add    $0x2,%r12d
  jmp    L26
```

assistant: ```c
int imgcelliter(int **img, int **buffer, int x, int y) {
  int i, j, rx, ry, ctr = 0;
  imgcopy(buffer, img, x, y);
  for (i = 0; i < x; i++)
    for (j = 0; j < y; j++)
      if (buffer[i][j] > 0) {
        ctr++;
        rx = (rand() % 3 - 1);
        ry = (rand() % 3 - 1);
        if (img[i + rx][j + ry] == 0) {
          img[i + rx][j + ry] = 255;
          ctr++;
        }
      }
  return ctr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imgcelliter>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  mov    %rdi,%rsi
  push   %r14
  movslq %ecx,%r14
  push   %r13
  mov    %r14d,%ecx
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rdi,(%rsp)
  mov    %r15,%rdi
  mov    %edx,0x8(%rsp)
  mov    %r14d,0xc(%rsp)
  call   <imgcopy@plt>
  test   %ebx,%ebx
  jle    L75
  xor    %ebp,%ebp
  nopw   0x0(%rax,%rax,1)
L26:
  mov    0xc(%rsp),%eax
  xor    %ebx,%ebx
  test   %eax,%eax
  jg     L77
  jmp    L88
  nopw   0x0(%rax,%rax,1)
L58:
  add    $0x1,%rbx
  cmp    %rbx,%r14
  je     L88
L77:
  mov    (%r15),%rax
  mov    (%rax,%rbx,4),%ecx
  test   %ecx,%ecx
  jle    L58
  xor    %eax,%eax
  call   <rand@plt>
  mov    %eax,%r13d
  xor    %eax,%eax
  call   <rand@plt>
  mov    %r13d,%r8d
  mov    %r13d,%edi
  mov    (%rsp),%rdx
  mov    %eax,%esi
  movslq %r13d,%rax
  sar    $0x1f,%r8d
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %r8d,%eax
  mov    %esi,%r8d
  lea    (%rax,%rax,2),%eax
  sar    $0x1f,%r8d
  sub    %eax,%edi
  movslq %esi,%rax
  imul   $0x55555556,%rax,%rax
  lea    -0x1(%rbp,%rdi,1),%edi
  movslq %edi,%rdi
  shr    $0x20,%rax
  sub    %r8d,%eax
  lea    (%rax,%rax,2),%eax
  sub    %eax,%esi
  lea    -0x1(%rsi,%rbx,1),%eax
  mov    (%rdx,%rdi,8),%rsi
  cltq
  lea    (%rsi,%rax,4),%rax
  mov    (%rax),%edx
  test   %edx,%edx
  je     L73
  add    $0x1,%rbx
  add    $0x1,%r12d
  cmp    %rbx,%r14
  jne    L77
  nopw   0x0(%rax,%rax,1)
L88:
  add    $0x1,%ebp
  add    $0x8,%r15
  cmp    %ebp,0x8(%rsp)
  jne    L26
L75:
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  movl   $0xff,(%rax)
  add    $0x2,%r12d
  jmp    L58
```

assistant: ```c
int imgcelliter(int **img, int **buffer, int x, int y) {
  int i, j, rx, ry, ctr = 0;
  imgcopy(buffer, img, x, y);
  for (i = 0; i < x; i++)
    for (j = 0; j < y; j++)
      if (buffer[i][j] > 0) {
        ctr++;
        rx = (rand() % 3 - 1);
        ry = (rand() % 3 - 1);
        if (img[i + rx][j + ry] == 0) {
          img[i + rx][j + ry] = 255;
          ctr++;
        }
      }
  return ctr;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x8(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  float a = 0;
  int i = 0;
  a = i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  float a = 0;
  int i = 0;
  a = i++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  float a = 0;
  int i = 0;
  a = i++;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  float a = 0;
  int i = 0;
  a = i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<convert_swap_sign16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L4:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  xor    $0x80,%ah
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  addl   $0x2,-0xc(%rbp)
  addq   $0x4,-0x8(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int convert_swap_sign16(struct xmms_convert_buffers *buf, void **data, int length) {
  int16_t *ptr = *data;
  int i;
  for (i = 0; i < length; i += 2, ptr++)
    *ptr ^= 1 << 15;
  return i;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<convert_swap_sign16>:
  endbr64
  mov    (%rsi),%rax
  test   %edx,%edx
  jle    L17
  sub    $0x1,%edx
  shr    %edx
  lea    0x1(%rdx),%ecx
  lea    (%rax,%rcx,4),%rcx
L13:
  xorl   $0x8000,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L13
  lea    0x2(%rdx,%rdx,1),%eax
  ret
L17:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int convert_swap_sign16(struct xmms_convert_buffers *buf, void **data, int length) {
  int16_t *ptr = *data;
  int i;
  for (i = 0; i < length; i += 2, ptr++)
    *ptr ^= 1 << 15;
  return i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<convert_swap_sign16>:
  endbr64
  mov    (%rsi),%rcx
  test   %edx,%edx
  jle    L19
  sub    $0x1,%edx
  shr    %edx
  add    $0x1,%edx
  mov    %rdx,%rax
  lea    (%rcx,%rdx,4),%rdx
  nopw   0x0(%rax,%rax,1)
L0:
  xorl   $0x8000,(%rcx)
  add    $0x4,%rcx
  cmp    %rdx,%rcx
  jne    L0
  add    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
int convert_swap_sign16(struct xmms_convert_buffers *buf, void **data, int length) {
  int16_t *ptr = *data;
  int i;
  for (i = 0; i < length; i += 2, ptr++)
    *ptr ^= 1 << 15;
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<convert_swap_sign16>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%esi
  mov    (%r8),%rcx
  test   %edx,%edx
  jle    L5
  lea    -0x1(%rdx),%edx
  mov    %edx,%eax
  shr    %eax
  add    $0x1,%eax
  cmp    $0x5,%edx
  jbe    L49
  mov    %eax,%edi
  movdqa D0(%rip),%xmm1
  mov    %rcx,%rdx
  shr    $0x2,%edi
  sub    $0x1,%edi
  shl    $0x4,%rdi
  lea    0x10(%rcx,%rdi,1),%rdi
  nop
L51:
  movdqu (%rdx),%xmm0
  add    $0x10,%rdx
  pxor   %xmm1,%xmm0
  movups %xmm0,-0x10(%rdx)
  cmp    %rdx,%rdi
  jne    L51
  mov    %eax,%edi
  and    $0xfffffffc,%edi
  mov    %edi,%edx
  lea    (%rcx,%rdx,4),%rcx
  lea    (%rdi,%rdi,1),%edx
  cmp    %edi,%eax
  je     L17
L47:
  lea    0x2(%rdx),%edi
  xorl   $0x8000,(%rcx)
  cmp    %edi,%esi
  jle    L17
  add    $0x4,%edx
  xorl   $0x8000,0x4(%rcx)
  cmp    %edx,%esi
  jle    L17
  xorl   $0x8000,0x8(%rcx)
L17:
  add    %eax,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
L49:
  xor    %edx,%edx
  jmp    L47
```

tool_calls: name: retrieve_data
arguments: data_label: D0
datatype: byte[16]

tool: {"D0": [0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x80,0x00,0x00]}

assistant: ```c
int convert_swap_sign16(struct xmms_convert_buffers *buf, void **data, int length) {
  int16_t *ptr = *data;
  int i;
  for (i = 0; i < length; i += 2, ptr++)
    *ptr ^= 1 << 15;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc0(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  movq   $0x0,-0x88(%rbp)
  jmp    L3
L31:
  movq   $0x0,-0xb8(%rbp)
  movq   $0x1,-0xb0(%rbp)
  movq   $0x1,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  mov    -0xb8(%rbp),%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x98(%rbp)
  mov    -0xa8(%rbp),%rdx
  mov    -0xa0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x90(%rbp)
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x78(%rbp)
  movq   $0x0,-0x80(%rbp)
  jmp    L29
L15:
  lea    -0x70(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x52,%al
  jne    L12
  mov    -0x98(%rbp),%rax
  mov    %rax,-0xb8(%rbp)
  mov    -0x90(%rbp),%rax
  mov    %rax,-0xa8(%rbp)
  jmp    L64
L12:
  lea    -0x70(%rbp),%rdx
  mov    -0x80(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x4c,%al
  jne    L64
  mov    -0x98(%rbp),%rax
  mov    %rax,-0xb0(%rbp)
  mov    -0x90(%rbp),%rax
  mov    %rax,-0xa0(%rbp)
L64:
  mov    -0xb8(%rbp),%rdx
  mov    -0xb0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x98(%rbp)
  mov    -0xa8(%rbp),%rdx
  mov    -0xa0(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x90(%rbp)
  addq   $0x1,-0x80(%rbp)
L29:
  mov    -0x80(%rbp),%rax
  cmp    -0x78(%rbp),%rax
  jl     L15
  mov    -0x90(%rbp),%rdx
  mov    -0x98(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addq   $0x1,-0x88(%rbp)
L3:
  mov    -0xc0(%rbp),%rax
  cmp    %rax,-0x88(%rbp)
  jl     L31
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string

tool: D13: %lld

tool: D4: %lld/%lld


assistant: ```c
int main() {
  char str[100];
  long long a, b, c, d, x, y, n, i, j, len;
  scanf("%lld", &n);
  getchar();
  for (i = 0; i < n; i++) {
    a = 0, b = 1, c = 1, d = 0;
    x = a + b;
    y = c + d;
    gets(str);
    len = strlen(str);
    for (j = 0; j < len; j++) {
      if (str[j] == 'R') {
        a = x;
        c = y;
      } else if (str[j] == 'L') {
        b = x;
        d = y;
      }
      x = a + b;
      y = c + d;
    }
    printf("%lld/%lld\n", x, y);
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D14(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L23
  mov    $0x0,%ebx
  lea    D19(%rip),%rbp
  jmp    L29
L67:
  cmp    $0x4c,%cl
  cmove  %r9,%rdi
  cmove  %r8,%rsi
L16:
  lea    (%r10,%rsi,1),%r8
  lea    (%r11,%rdi,1),%r9
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L30
L60:
  movzbl (%rdx),%ecx
  cmp    $0x52,%cl
  jne    L67
  mov    %r9,%r11
  mov    %r8,%r10
  jmp    L16
L52:
  mov    $0x1,%r9d
  mov    $0x1,%r8d
L30:
  mov    %r9,%rdx
  mov    %r8,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbx,0x8(%rsp)
  jle    L23
L29:
  lea    0x10(%rsp),%r12
  mov    %r12,%rdi
  call   <gets@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  jle    L52
  mov    %r12,%rdx
  add    %r12,%rax
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  mov    $0x0,%edi
  mov    $0x1,%r11d
  mov    $0x1,%esi
  mov    $0x0,%r10d
  jmp    L60
L23:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L87
  mov    $0x0,%eax
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L87:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D14
datatype: string
name: extract_symbolic_data
arguments: data_tag: D19
datatype: string

tool: D14: %lld

tool: D19: %lld/%lld


assistant: ```c
int main() {
  char str[100];
  long long a, b, c, d, x, y, n, i, j, len;
  scanf("%lld", &n);
  getchar();
  for (i = 0; i < n; i++) {
    a = 0, b = 1, c = 1, d = 0;
    x = a + b;
    y = c + d;
    gets(str);
    len = strlen(str);
    for (j = 0; j < len; j++) {
      if (str[j] == 'R') {
        a = x;
        c = y;
      } else if (str[j] == 'L') {
        b = x;
        d = y;
      }
      x = a + b;
      y = c + d;
    }
    printf("%lld/%lld\n", x, y);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%rdi
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L67
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  lea    D13(%rip),%r12
  xchg   %ax,%ax
L2:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L47
  mov    %rbx,%rdx
  add    %rbx,%rax
  mov    $0x1,%r9d
  xor    %edi,%edi
  mov    $0x1,%r8d
  mov    $0x1,%r11d
  mov    $0x1,%esi
  xor    %r10d,%r10d
  jmp    L78
  nopl   0x0(%rax)
L13:
  cmp    $0x4c,%cl
  cmove  %r9,%rdi
  cmove  %r8,%rsi
L51:
  lea    (%r10,%rsi,1),%r8
  add    $0x1,%rdx
  lea    (%r11,%rdi,1),%r9
  cmp    %rdx,%rax
  je     L21
L78:
  movzbl (%rdx),%ecx
  cmp    $0x52,%cl
  jne    L13
  mov    %r9,%r11
  mov    %r8,%r10
  jmp    L51
  nopl   0x0(%rax)
L47:
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L21:
  mov    %r9,%rdx
  mov    %r8,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %rbp,0x8(%rsp)
  jg     L2
L67:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L79
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D13
data_type: string

tool: D14: %lld

tool: D13: %lld/%lld


assistant: ```c
int main() {
  char str[100];
  long long a, b, c, d, x, y, n, i, j, len;
  scanf("%lld", &n);
  getchar();
  for (i = 0; i < n; i++) {
    a = 0, b = 1, c = 1, d = 0;
    x = a + b;
    y = c + d;
    gets(str);
    len = strlen(str);
    for (j = 0; j < len; j++) {
      if (str[j] == 'R') {
        a = x;
        c = y;
      } else if (str[j] == 'L') {
        b = x;
        d = y;
      }
      x = a + b;
      y = c + d;
    }
    printf("%lld/%lld\n", x, y);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D17(%rip),%rdi
  push   %rbp
  push   %rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  cmpq   $0x0,0x8(%rsp)
  jle    L2
  xor    %ebp,%ebp
  lea    0x10(%rsp),%rbx
  lea    D3(%rip),%r12
  xchg   %ax,%ax
L0:
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L34
  mov    %rbx,%rdx
  add    %rbx,%rax
  mov    $0x1,%r9d
  xor    %edi,%edi
  mov    $0x1,%r8d
  mov    $0x1,%r11d
  mov    $0x1,%esi
  xor    %r10d,%r10d
  jmp    L1
  nopl   0x0(%rax)
L76:
  cmp    $0x4c,%cl
  cmove  %r9,%rdi
  cmove  %r8,%rsi
L21:
  lea    (%rsi,%r10,1),%r8
  add    $0x1,%rdx
  lea    (%r11,%rdi,1),%r9
  cmp    %rdx,%rax
  je     L54
L1:
  movzbl (%rdx),%ecx
  cmp    $0x52,%cl
  jne    L76
  mov    %r9,%r11
  mov    %r8,%r10
  jmp    L21
  nopl   0x0(%rax)
L34:
  mov    $0x1,%r9d
  mov    $0x1,%r8d
  nopl   0x0(%rax)
L54:
  mov    %r9,%rdx
  mov    %r8,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbp
  call   <printf@plt>
  cmp    %rbp,0x8(%rsp)
  jg     L0
L2:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  sub    $0xffffffffffffff80,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D17
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D17: %lld

tool: D3: %lld/%lld


assistant: ```c
int main() {
  char str[100];
  long long a, b, c, d, x, y, n, i, j, len;
  scanf("%lld", &n);
  getchar();
  for (i = 0; i < n; i++) {
    a = 0, b = 1, c = 1, d = 0;
    x = a + b;
    y = c + d;
    gets(str);
    len = strlen(str);
    for (j = 0; j < len; j++) {
      if (str[j] == 'R') {
        a = x;
        c = y;
      } else if (str[j] == 'L') {
        b = x;
        d = y;
      }
      x = a + b;
      y = c + d;
    }
    printf("%lld/%lld\n", x, y);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<parse_usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    %r8,-0x28(%rbp)
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rsi,%r8
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D18(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D18
type: string

tool: D19: %s: %s %s


tool: D18: %s


assistant: ```c
void parse_usage(FILE *fd, const char *progname, const char *s1, const char *s2, const char *description) {
  fprintf(fd, "%s: %s %s\n", progname, s1, s2);
  fprintf(fd, "%s\n", description);
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<parse_usage>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %r8,%rbp
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rsi,%rdx
  lea    D17(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbp,%rdx
  lea    D16(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type_guessed: string
name: disassemble_data
arguments: data_label: D16
type_guessed: string

tool: D17: %s: %s %s


tool: D16: %s


assistant: ```c
void parse_usage(FILE *fd, const char *progname, const char *s1, const char *s2, const char *description) {
  fprintf(fd, "%s: %s %s\n", progname, s1, s2);
  fprintf(fd, "%s\n", description);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parse_usage>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %r8,%r12
  mov    %rcx,%r8
  push   %rbp
  mov    %rdx,%rcx
  mov    %rdi,%rbp
  mov    %rsi,%rdx
  lea    D12(%rip),%rsi
  sub    $0x8,%rsp
  call   <fprintf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  xor    %eax,%eax
  lea    D13(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D13
data_type: string

tool: D12: %s: %s %s


tool: D13: %s


assistant: ```c
void parse_usage(FILE *fd, const char *progname, const char *s1, const char *s2, const char *description) {
  fprintf(fd, "%s: %s %s\n", progname, s1, s2);
  fprintf(fd, "%s\n", description);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_usage>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %r8,%r12
  mov    %rcx,%r8
  push   %rbp
  mov    %rdx,%rcx
  mov    %rdi,%rbp
  mov    %rsi,%rdx
  lea    D18(%rip),%rsi
  sub    $0x8,%rsp
  call   <fprintf@plt>
  mov    %rbp,%rdi
  mov    %r12,%rdx
  xor    %eax,%eax
  lea    D11(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbp
  pop    %r12
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D11
data_type: string

tool: D18: %s: %s %s


tool: D11: %s


assistant: ```c
void parse_usage(FILE *fd, const char *progname, const char *s1, const char *s2, const char *description) {
  fprintf(fd, "%s: %s %s\n", progname, s1, s2);
  fprintf(fd, "%s\n", description);
  exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<input>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movb   $0x0,-0x3(%rbp)
  jmp    L47
L66:
  movb   $0x0,-0x2(%rbp)
  jmp    L39
L62:
  movsbl -0x3(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  add    %eax,%edx
  movsbl -0x2(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  lea    -0x30(%rax),%ecx
  movsbq -0x3(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  movsbl -0x2(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  mov    %cl,(%rax)
  movsbq -0x3(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movsbl -0x2(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  movb   $0x1,-0x1(%rbp)
  jmp    L14
L11:
  movsbq -0x3(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  movsbl -0x2(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1(%rbp)
  je     L26
  movsbq -0x3(%rbp),%rax
  imul   $0x5a,%rax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  movsbl -0x2(%rbp),%eax
  movsbl -0x1(%rbp),%edx
  movslq %edx,%rcx
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  add    %rsi,%rax
  add    %rcx,%rax
  movb   $0x0,(%rax)
L26:
  movzbl -0x1(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x1(%rbp)
L14:
  cmpb   $0x9,-0x1(%rbp)
  jle    L11
L65:
  movzbl -0x2(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x2(%rbp)
L39:
  cmpb   $0x8,-0x2(%rbp)
  jle    L62
  movzbl -0x3(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0x3(%rbp)
L47:
  cmpb   $0x8,-0x3(%rbp)
  jle    L66
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void input(char grid[9][9][10], char string[81]) {
  char i, j, k;
  for (i = 0; i < 9; ++i)
    for (j = 0; j < 9; ++j) {
      grid[i][j][0] = string[9 * i + j] - '0';
      if (grid[i][j][0])
        for (k = 1; k < 10; ++k)
          if (k != grid[i][j][0])
            grid[i][j][k] = 0;
    }
}
```