user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L33
L30:
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L30
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L23:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  add    %rdx,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L23
  jmp    L39
L45:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    %rax,-0x20(%rbp)
L39:
  cmpl   $0x0,-0x14(%rbp)
  jg     L45
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
datatype: string
name: extract_symbolic_data
arguments: label: D65
datatype: string
name: extract_symbolic_data
arguments: label: D62
datatype: string
name: extract_symbolic_data
arguments: label: D61
datatype: string
name: extract_symbolic_data
arguments: label: D38
datatype: string
name: extract_symbolic_data
arguments: label: D66
datatype: string
name: extract_symbolic_data
arguments: label: D9
datatype: string
name: extract_symbolic_data
arguments: label: D28
datatype: string

tool: D15: i = %d; 

tool: D65: argv [ %d ] = %s;


tool: D62: * ( argv + %d ) = %s;


tool: D61: * ( ( argv + %d ) + %d ) = %c;


tool: D38: argc = %d;

tool: D66:  i = %d;

tool: D9:  * argv = %s;

tool: D28:  argv [ %d ] = %s;

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  int j = 2;
  while (i < argc) {
    printf("i = %d; ", i);
    printf("argv [ %d ] = %s;\n", i, argv[i]);
    i++;
  }
  i = 0;
  while (i < argc) {
    printf("* ( argv + %d ) = %s;\n", i, *(argv + i));
    printf("* ( ( argv + %d ) + %d ) = %c;\n", i, j, *((argv + i) + j));
    i++;
  }
  while (argc > 0) {
    printf("argc = %d;", argc);
    printf(" i = %d;", i);
    printf(" * argv = %s;", *argv);
    printf(" argv [ %d ] = %s;", i, argv[i]);
    printf("\n");
    i++;
    argc--;
    *argv++;
  }
  return 0;
}
```