ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x1c(%rbp)
  movl   $0x2,-0x24(%rbp)
  movl   $0x1,-0x20(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x2,-0x1c(%rbp)
  jne    L15
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L27
L15:
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L27:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D25
data_type: string
name: disassemble_data
arguments: data_tag: D24
data_type: string
name: disassemble_data
arguments: data_tag: D33
data_type: string
name: disassemble_data
arguments: data_tag: D35
data_type: string

tool: D25: Show the adress of p
 %p 
 Show the number:%d


tool: D24: Show the adress of q
 %p 
 Show the number:%d


tool: D33: First cut down then compare

tool: D35: First compare then cut down

assistant: ```c
int main(int argc, char **argv) {
  int i = 3;
  int *p, m = 2;
  int *q, n = 1;
  p = &m;
  q = &n;
  printf("Show the adress of p\n %p \n Show the number:%d\n", p, *p);
  printf("Show the adress of q\n %p \n Show the number:%d\n", q, *q);
  if ((--i) == 2)
    printf("First cut down then compare\n");
  else
    printf("First compare then cut down\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  mov    %rsp,%rsi
  mov    $0x2,%edx
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    0x4(%rsp),%edx
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D25(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
type: string
name: unpack_data
arguments: label: D20
type: string
name: unpack_data
arguments: label: D25
type: string

tool: D29: Show the adress of p
 %p 
 Show the number:%d


tool: D20: Show the adress of q
 %p 
 Show the number:%d


tool: D25: First cut down then compare

assistant: ```c
int main(int argc, char **argv) {
  int i = 3;
  int *p, m = 2;
  int *q, n = 1;
  p = &m;
  q = &n;
  printf("Show the adress of p\n %p \n Show the number:%d\n", p, *p);
  printf("Show the adress of q\n %p \n Show the number:%d\n", q, *q);
  if ((--i) == 2)
    printf("First cut down then compare\n");
  else
    printf("First compare then cut down\n");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%edx
  lea    D13(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type: string
name: extract_symbolic_data
arguments: tag: D4
type: string
name: extract_symbolic_data
arguments: tag: D14
type: string

tool: D13: Show the adress of p
 %p 
 Show the number:%d


tool: D4: Show the adress of q
 %p 
 Show the number:%d


tool: D14: First cut down then compare

assistant: ```c
int main(int argc, char **argv) {
  int i = 3;
  int *p, m = 2;
  int *q, n = 1;
  p = &m;
  q = &n;
  printf("Show the adress of p\n %p \n Show the number:%d\n", p, *p);
  printf("Show the adress of q\n %p \n Show the number:%d\n", q, *q);
  if ((--i) == 2)
    printf("First cut down then compare\n");
  else
    printf("First compare then cut down\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%edx
  lea    D9(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D9
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string
name: read_data
arguments: data_label: D11
type_guessed: string

tool: D9: Show the adress of p
 %p 
 Show the number:%d


tool: D17: Show the adress of q
 %p 
 Show the number:%d


tool: D11: First cut down then compare

assistant: ```c
int main(int argc, char **argv) {
  int i = 3;
  int *p, m = 2;
  int *q, n = 1;
  p = &m;
  q = &n;
  printf("Show the adress of p\n %p \n Show the number:%d\n", p, *p);
  printf("Show the adress of q\n %p \n Show the number:%d\n", q, *q);
  if ((--i) == 2)
    printf("First cut down then compare\n");
  else
    printf("First compare then cut down\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<isFibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L31
L14:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jne    L25
  mov    $0x1,%eax
  jmp    L0
L25:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L31:
  mov    -0x10(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L14
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int isFibonacci(unsigned long long n) {
  unsigned long long x = 0, y = 1;
  unsigned long long next = x + y;
  while (next <= n) {
    if (next == n) {
      return 1;
    }
    x = y;
    y = next;
    next = x + y;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isFibonacci>:
  endbr64
  test   %rdi,%rdi
  je     L19
  cmp    $0x1,%rdi
  je     L17
  mov    $0x1,%ecx
  mov    $0x2,%eax
  jmp    L16
L45:
  mov    %rdx,%rax
L16:
  cmp    %rax,%rdi
  je     L47
  lea    (%rax,%rcx,1),%rdx
  mov    %rax,%rcx
  cmp    %rdx,%rdi
  jae    L45
  mov    $0x0,%eax
  ret
L19:
  mov    $0x0,%eax
  ret
L17:
  mov    $0x1,%eax
  ret
L47:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isFibonacci(unsigned long long n) {
  unsigned long long x = 0, y = 1;
  unsigned long long next = x + y;
  while (next <= n) {
    if (next == n) {
      return 1;
    }
    x = y;
    y = next;
    next = x + y;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<isFibonacci>:
  endbr64
  test   %rdi,%rdi
  je     L18
  cmp    $0x1,%rdi
  je     L14
  mov    $0x1,%ecx
  mov    $0x2,%eax
  jmp    L7
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdx,%rax
L7:
  cmp    %rax,%rdi
  je     L14
  lea    (%rax,%rcx,1),%rdx
  mov    %rax,%rcx
  cmp    %rdx,%rdi
  jae    L1
L18:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isFibonacci(unsigned long long n) {
  unsigned long long x = 0, y = 1;
  unsigned long long next = x + y;
  while (next <= n) {
    if (next == n) {
      return 1;
    }
    x = y;
    y = next;
    next = x + y;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isFibonacci>:
  endbr64
  test   %rdi,%rdi
  je     L39
  cmp    $0x1,%rdi
  je     L7
  mov    $0x1,%ecx
  mov    $0x2,%eax
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L30:
  mov    %rdx,%rax
L5:
  cmp    %rax,%rdi
  je     L7
  lea    (%rax,%rcx,1),%rdx
  mov    %rax,%rcx
  cmp    %rdx,%rdi
  jae    L30
L39:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isFibonacci(unsigned long long n) {
  unsigned long long x = 0, y = 1;
  unsigned long long next = x + y;
  while (next <= n) {
    if (next == n) {
      return 1;
    }
    x = y;
    y = next;
    next = x + y;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<__yell>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x100,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void __yell(void) {
  char buf[256];
  memset(buf, 0, sizeof(buf));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__yell>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x100,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x118,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __yell(void) {
  char buf[256];
  memset(buf, 0, sizeof(buf));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<__yell>:
  endbr64
  sub    $0x118,%rsp
  xor    %esi,%esi
  mov    $0x100,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x118,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __yell(void) {
  char buf[256];
  memset(buf, 0, sizeof(buf));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__yell>:
  endbr64
  sub    $0x118,%rsp
  xor    %esi,%esi
  mov    $0x100,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x118,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __yell(void) {
  char buf[256];
  memset(buf, 0, sizeof(buf));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sign_extend64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x18(%rbp),%eax
  mov    $0xffffffff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  xor    -0x8(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int64_t sign_extend64(uint64_t val, uint64_t bits) {
  int64_t r;
  int64_t const m = 1U << (bits - 1);
  val = val & ((1U << bits) - 1);
  r = (val ^ m) - m;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sign_extend64>:
  endbr64
  mov    %edi,%eax
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edi
  shl    %cl,%edi
  mov    $0xffffffff,%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  not    %edx
  and    %edx,%eax
  xor    %edi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int64_t sign_extend64(uint64_t val, uint64_t bits) {
  int64_t r;
  int64_t const m = 1U << (bits - 1);
  val = val & ((1U << bits) - 1);
  r = (val ^ m) - m;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sign_extend64>:
  endbr64
  mov    %edi,%r8d
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edi
  mov    $0xffffffff,%edx
  shl    %cl,%edi
  mov    %esi,%ecx
  shl    %cl,%edx
  not    %edx
  mov    %edx,%eax
  and    %r8d,%eax
  xor    %edi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int64_t sign_extend64(uint64_t val, uint64_t bits) {
  int64_t r;
  int64_t const m = 1U << (bits - 1);
  val = val & ((1U << bits) - 1);
  r = (val ^ m) - m;
  return r;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sign_extend64>:
  endbr64
  mov    %edi,%r8d
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%edi
  mov    $0xffffffff,%edx
  shl    %cl,%edi
  mov    %esi,%ecx
  shl    %cl,%edx
  not    %edx
  mov    %edx,%eax
  and    %r8d,%eax
  xor    %edi,%eax
  sub    %edi,%eax
  ret
```

assistant: ```c
int64_t sign_extend64(uint64_t val, uint64_t bits) {
  int64_t r;
  int64_t const m = 1U << (bits - 1);
  val = val & ((1U << bits) - 1);
  r = (val ^ m) - m;
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sleep_millis>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  mov    %eax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <nanosleep@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
void sleep_millis(int millis) {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = millis * 1000 * 1000;
  nanosleep(&ts, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep_millis>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  imul   $0xf4240,%edi,%edi
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_millis(int millis) {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = millis * 1000 * 1000;
  nanosleep(&ts, NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sleep_millis>:
  endbr64
  imul   $0xf4240,%edi,%edi
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_millis(int millis) {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = millis * 1000 * 1000;
  nanosleep(&ts, NULL);
}
```
user: What is the c source code of the assembly code below?

```asm
<sleep_millis>:
  endbr64
  imul   $0xf4240,%edi,%edi
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  mov    %edi,(%rsp)
  mov    %rsp,%rdi
  call   <nanosleep@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void sleep_millis(int millis) {
  struct timespec ts;
  ts.tv_sec = 0;
  ts.tv_nsec = millis * 1000 * 1000;
  nanosleep(&ts, NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<smooth_mv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L21
L7:
  mov    -0x8(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L39
L25:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D6(%rip),%xmm0
  comisd %xmm1,%xmm0
  jbe    L20
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  lea    (%rdx,%rax,1),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x2c(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %eax,%ecx
  mov    -0x4(%rbp),%eax
  sub    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %ecx,%eax
  movslq %eax,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
L20:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
L39:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L25
  addl   $0x1,-0x8(%rbp)
L21:
  mov    -0x30(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: f64

tool: D6: 0.95

assistant: ```c
void smooth_mv(char *in, char *out, float *conf, int w, int h) {
  int i, j, c;
  for (j = 1; j < h - 1; j++) {
    c = j * w + 1;
    for (i = 1; i < w - 1; i++) {
      if (conf[c] < 0.95) {
        out[c] = (2 * in[c] + in[c - 1] + in[c + 1] + in[c + w] + in[c - w]) / 6;
      }
      c++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<smooth_mv>:
  endbr64
  cmp    $0x2,%r8d
  jle    L20
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r10
  mov    %rdx,%rsi
  mov    %ecx,%r9d
  movslq %ecx,%r12
  lea    -0x3(%rcx),%eax
  lea    0x3(%r12,%rax,1),%rcx
  lea    0x1(%r9),%ebx
  lea    -0x1(%r8),%ebp
  mov    $0x1,%r11d
  movsd  D9(%rip),%xmm1
  lea    -0x1(%r9),%r8d
  jmp    L43
L54:
  add    $0x1,%rax
  cmp    %rcx,%rax
  je     L3
L69:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rsi,%rax,4),%xmm0
  comisd %xmm0,%xmm1
  jbe    L54
  movsbl -0x1(%rdi,%rax,1),%r13d
  movsbl -0x2(%rdi,%rax,1),%edx
  lea    (%rdx,%r13,2),%r13d
  movsbl (%rdi,%rax,1),%edx
  add    %edx,%r13d
  lea    (%r8,%rax,1),%edx
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%edx
  add    %edx,%r13d
  mov    %eax,%edx
  sub    %r9d,%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%edx
  add    %edx,%r13d
  movslq %r13d,%rdx
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%r13d
  sub    %r13d,%edx
  mov    %dl,-0x1(%r10,%rax,1)
  jmp    L54
L3:
  add    $0x1,%r11d
  add    %r12,%rcx
  add    %r9d,%ebx
  cmp    %ebp,%r11d
  je     L46
L43:
  cmp    $0x2,%r9d
  jle    L3
  lea    0x1(%rbx),%eax
  cltq
  jmp    L69
L46:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L20:
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type: f64

tool: D9: 0.95

assistant: ```c
void smooth_mv(char *in, char *out, float *conf, int w, int h) {
  int i, j, c;
  for (j = 1; j < h - 1; j++) {
    c = j * w + 1;
    for (i = 1; i < w - 1; i++) {
      if (conf[c] < 0.95) {
        out[c] = (2 * in[c] + in[c - 1] + in[c + 1] + in[c + w] + in[c - w]) / 6;
      }
      c++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<smooth_mv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x1(%r8),%ebp
  push   %rbx
  cmp    $0x1,%ebp
  jle    L17
  mov    %ecx,%r9d
  movslq %ecx,%r12
  lea    -0x3(%rcx),%eax
  mov    %rsi,%r10
  movsd  D4(%rip),%xmm1
  mov    %rdx,%rsi
  lea    0x1(%r9),%ebx
  lea    0x3(%r12,%rax,1),%rcx
  mov    $0x1,%r11d
  lea    -0x1(%r9),%r8d
  nopl   0x0(%rax)
L7:
  lea    0x1(%rbx),%eax
  cltq
  cmp    $0x2,%r9d
  jle    L20
  nopl   0x0(%rax,%rax,1)
L26:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rsi,%rax,4),%xmm0
  comisd %xmm0,%xmm1
  jbe    L49
  movsbl -0x2(%rdi,%rax,1),%edx
  movsbl -0x1(%rdi,%rax,1),%r13d
  lea    (%rdx,%r13,2),%r13d
  movsbl (%rdi,%rax,1),%edx
  add    %edx,%r13d
  lea    (%r8,%rax,1),%edx
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%edx
  add    %edx,%r13d
  mov    %eax,%edx
  sub    %r9d,%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%edx
  add    %edx,%r13d
  movslq %r13d,%rdx
  sar    $0x1f,%r13d
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %r13d,%edx
  mov    %dl,-0x1(%r10,%rax,1)
L49:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L26
L20:
  add    $0x1,%r11d
  add    %r12,%rcx
  add    %r9d,%ebx
  cmp    %ebp,%r11d
  jne    L7
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: f64

tool: D4: 0.95

assistant: ```c
void smooth_mv(char *in, char *out, float *conf, int w, int h) {
  int i, j, c;
  for (j = 1; j < h - 1; j++) {
    c = j * w + 1;
    for (i = 1; i < w - 1; i++) {
      if (conf[c] < 0.95) {
        out[c] = (2 * in[c] + in[c - 1] + in[c + 1] + in[c + w] + in[c - w]) / 6;
      }
      c++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<smooth_mv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%r8),%ebx
  cmp    $0x1,%ebx
  jle    L48
  mov    %ecx,%r9d
  cmp    $0x2,%ecx
  jle    L48
  movslq %ecx,%rbp
  lea    -0x3(%rcx),%r12d
  mov    %rsi,%r10
  mov    $0x1,%r11d
  movsd  D2(%rip),%xmm1
  mov    %rdx,%rsi
  lea    0x3(%r12,%rbp,1),%rcx
  lea    -0x1(%r9),%r8d
  nopw   0x0(%rax,%rax,1)
L23:
  mov    %rcx,%rax
  sub    %r12,%rax
  sub    $0x1,%rax
  nopw   0x0(%rax,%rax,1)
L47:
  pxor   %xmm0,%xmm0
  cvtss2sd -0x4(%rsi,%rax,4),%xmm0
  comisd %xmm0,%xmm1
  jbe    L37
  movsbl -0x2(%rdi,%rax,1),%edx
  movsbl -0x1(%rdi,%rax,1),%r13d
  lea    (%rdx,%r13,2),%r13d
  movsbl (%rdi,%rax,1),%edx
  add    %edx,%r13d
  lea    (%r8,%rax,1),%edx
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%edx
  add    %edx,%r13d
  mov    %eax,%edx
  sub    %r9d,%edx
  sub    $0x1,%edx
  movslq %edx,%rdx
  movsbl (%rdi,%rdx,1),%edx
  add    %edx,%r13d
  movslq %r13d,%rdx
  sar    $0x1f,%r13d
  imul   $0x2aaaaaab,%rdx,%rdx
  shr    $0x20,%rdx
  sub    %r13d,%edx
  mov    %dl,-0x1(%r10,%rax,1)
L37:
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L47
  add    $0x1,%r11d
  add    %rbp,%rcx
  cmp    %ebx,%r11d
  jne    L23
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
data_type: f64

tool: D2: 0.95

assistant: ```c
void smooth_mv(char *in, char *out, float *conf, int w, int h) {
  int i, j, c;
  for (j = 1; j < h - 1; j++) {
    c = j * w + 1;
    for (i = 1; i < w - 1; i++) {
      if (conf[c] < 0.95) {
        out[c] = (2 * in[c] + in[c - 1] + in[c + 1] + in[c + w] + in[c - w]) / 6;
      }
      c++;
    }
  }
}
```