ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<i_crdy>:
  endbr64
  mov    $0x1,%r8d
  test   %esi,%esi
  je     L30
  jle    L7
  add    $0x10004,%edi
  xor    %eax,%eax
  shl    $0x4,%edi
  movslq %edi,%rdi
  testq  $0x1e00,(%rdi)
  jne    L30
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L31
L7:
  xor    %r8d,%r8d
L30:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int i_crdy(int channel, int tries) {
  int i;
  if (tries) {
    for (i = 0; i < tries; i++)
      if (*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e00)
        return (1);
    return (0);
  } else {
    while ((!*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e00))
      ;
    return (1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<i_crdy>:
  endbr64
  mov    $0x1,%eax
  test   %esi,%esi
  je     L17
  jle    L0
  add    $0x10004,%edi
  xor    %eax,%eax
  shl    $0x4,%edi
  movslq %edi,%rdi
  testq  $0x1e00,(%rdi)
  setne  %al
  ret
L0:
  xor    %eax,%eax
L17:
  ret
```

assistant: ```c
int i_crdy(int channel, int tries) {
  int i;
  if (tries) {
    for (i = 0; i < tries; i++)
      if (*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e00)
        return (1);
    return (0);
  } else {
    while ((!*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e00))
      ;
    return (1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x14(%rbp),%xmm1
  movss  -0x10(%rbp),%xmm0
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0xc(%rbp),%xmm2
  movq   %xmm2,%rax
  movq   %rax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D46
type_infered: string
name: unpack_data
arguments: tag: D49
type_infered: string
name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D1
type_infered: string
name: unpack_data
arguments: tag: D44
type_infered: string

tool: D46: This program will allow you to sum two numbers.

tool: D49: Please input your first number.

tool: D15: %f

tool: D1: Please input your second number.

tool: D44: The result of addition is %f

assistant: ```c
main() {
  float num1;
  float num2;
  float result;
  printf("This program will allow you to sum two numbers.\n");
  printf("Please input your first number.\n");
  scanf("%f", &num1);
  printf("Please input your second number.\n");
  scanf("%f", &num2);
  result = num1 + num2;
  printf("The result of addition is %f", result);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D29(%rip),%rbx
  mov    %rbx,%rdi
  call   <scanf@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  cvtss2sd %xmm0,%xmm0
  lea    D13(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
datatype: string
name: disassemble_data
arguments: data_label: D37
datatype: string
name: disassemble_data
arguments: data_label: D29
datatype: string
name: disassemble_data
arguments: data_label: D23
datatype: string
name: disassemble_data
arguments: data_label: D13
datatype: string

tool: D17: This program will allow you to sum two numbers.

tool: D37: Please input your first number.

tool: D29: %f

tool: D23: Please input your second number.

tool: D13: The result of addition is %f

assistant: ```c
main() {
  float num1;
  float num2;
  float result;
  printf("This program will allow you to sum two numbers.\n");
  printf("Please input your first number.\n");
  scanf("%f", &num1);
  printf("Please input your second number.\n");
  scanf("%f", &num2);
  result = num1 + num2;
  printf("The result of addition is %f", result);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D40(%rip),%rdi
  lea    D47(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D0(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D39(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D40
type_guessed: string
name: read_data
arguments: label: D47
type_guessed: string
name: read_data
arguments: label: D14
type_guessed: string
name: read_data
arguments: label: D0
type_guessed: string
name: read_data
arguments: label: D39
type_guessed: string

tool: D40: This program will allow you to sum two numbers.

tool: D47: %f

tool: D14: Please input your first number.

tool: D0: Please input your second number.

tool: D39: The result of addition is %f

assistant: ```c
main() {
  float num1;
  float num2;
  float result;
  printf("This program will allow you to sum two numbers.\n");
  printf("Please input your first number.\n");
  scanf("%f", &num1);
  printf("Please input your second number.\n");
  scanf("%f", &num2);
  result = num1 + num2;
  printf("The result of addition is %f", result);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  lea    D35(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  movss  (%rsp),%xmm0
  addss  0x4(%rsp),%xmm0
  lea    D38(%rip),%rdi
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D35
type_guessed: string
name: retrieve_data
arguments: data_tag: D29
type_guessed: string
name: retrieve_data
arguments: data_tag: D45
type_guessed: string
name: retrieve_data
arguments: data_tag: D38
type_guessed: string

tool: D13: This program will allow you to sum two numbers.

tool: D35: %f

tool: D29: Please input your first number.

tool: D45: Please input your second number.

tool: D38: The result of addition is %f

assistant: ```c
main() {
  float num1;
  float num2;
  float result;
  printf("This program will allow you to sum two numbers.\n");
  printf("Please input your first number.\n");
  scanf("%f", &num1);
  printf("Please input your second number.\n");
  scanf("%f", &num2);
  result = num1 + num2;
  printf("The result of addition is %f", result);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  mov    $0x13,%edx
  lea    D68(%rip),%rsi
  call   <open_i2c_dev@plt>
  test   %rax,%rax
  jne    L51
  lea    0xc(%rsp),%rdx
  mov    $0x20,%esi
  mov    0x8(%rsp),%edi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  jne    L87
  mov    0xc(%rsp),%esi
  lea    D66(%rip),%rdi
  call   <printf@plt>
L27:
  lea    0x10(%rsp),%rdx
  mov    $0x22,%esi
  mov    0x8(%rsp),%edi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L29
L98:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  mov    $0x1310,%edx
  mov    $0x50,%esi
  mov    0x8(%rsp),%edi
  call   <write_i2c_reg@plt>
  test   %rax,%rax
  je     L84
L109:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  lea    0x14(%rsp),%rdx
  mov    $0x50,%esi
  mov    0x8(%rsp),%edi
  call   <read_i2c_reg@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L2
L13:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x28,%rsp
  ret
L51:
  lea    D55(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L13
L87:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L29:
  mov    0x10(%rsp),%esi
  lea    D66(%rip),%rdi
  call   <printf@plt>
  jmp    L98
L84:
  mov    $0x1310,%esi
  lea    D54(%rip),%rdi
  call   <printf@plt>
  jmp    L109
L2:
  mov    0x14(%rsp),%esi
  lea    D44(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D68
type_guessed: string
name: parse_data
arguments: tag: D66
type_guessed: string
name: parse_data
arguments: tag: D55
type_guessed: string
name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D54
type_guessed: string
name: parse_data
arguments: tag: D44
type_guessed: string

tool: D68: /dev/i2c-1

tool: D66: Read VCC as %d mV. 


tool: D55: Failed to setup i2c

tool: D24: Failed to read VCC 

tool: D54: Set vbat_conv to %i. 


tool: D44: Read vbat_conv as %i. 


assistant: ```c
int main(void) {
  int file_i2c;
  char *filename = (char *)"/dev/i2c-1";
  uint16_t vcc;
  uint16_t vbat;
  if (open_i2c_dev(&file_i2c, filename, 0x13) != 0) {
    printf("Failed to setup i2c");
    return -1;
  }
  if (read_i2c_reg(file_i2c, 0x20, &vcc) == 0) {
    printf("Read VCC as %d mV. \n", vcc);
  } else {
    printf("Failed to read VCC \n");
  }
  if (read_i2c_reg(file_i2c, 0x22, &vbat) == 0) {
    printf("Read VCC as %d mV. \n", vbat);
  }
  usleep(1000);
  uint16_t vbat_conv_set = 4880, vbat_conv_read;
  if (write_i2c_reg(file_i2c, 0x50, vbat_conv_set) == 0) {
    printf("Set vbat_conv to %i. \n", vbat_conv_set);
  }
  usleep(1000);
  if (read_i2c_reg(file_i2c, 0x50, &vbat_conv_read) == 0) {
    printf("Read vbat_conv as %i. \n", vbat_conv_read);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x13,%edx
  lea    D9(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <open_i2c_dev@plt>
  test   %rax,%rax
  jne    L22
  mov    0x8(%rsp),%edi
  lea    0xc(%rsp),%rdx
  mov    $0x20,%esi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L20
  lea    D25(%rip),%rdi
  call   <puts@plt>
L4:
  mov    0x8(%rsp),%edi
  lea    0x10(%rsp),%rdx
  mov    $0x22,%esi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L63
L68:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  mov    0x8(%rsp),%edi
  mov    $0x1310,%edx
  mov    $0x50,%esi
  call   <write_i2c_reg@plt>
  test   %rax,%rax
  je     L27
L67:
  mov    $0x3e8,%edi
  xor    %r12d,%r12d
  call   <usleep@plt>
  mov    0x8(%rsp),%edi
  lea    0x14(%rsp),%rdx
  mov    $0x50,%esi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L7
L31:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L20:
  mov    0xc(%rsp),%esi
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L4
L7:
  mov    0x14(%rsp),%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L27:
  mov    $0x1310,%esi
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L67
L63:
  mov    0x10(%rsp),%esi
  lea    D56(%rip),%rdi
  call   <printf@plt>
  jmp    L68
L22:
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L31
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D56
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D50
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D42
type_infered: string

tool: D9: /dev/i2c-1

tool: D25: Failed to read VCC 

tool: D56: Read VCC as %d mV. 


tool: D20: Read vbat_conv as %i. 


tool: D50: Set vbat_conv to %i. 


tool: D42: Failed to setup i2c

assistant: ```c
int main(void) {
  int file_i2c;
  char *filename = (char *)"/dev/i2c-1";
  uint16_t vcc;
  uint16_t vbat;
  if (open_i2c_dev(&file_i2c, filename, 0x13) != 0) {
    printf("Failed to setup i2c");
    return -1;
  }
  if (read_i2c_reg(file_i2c, 0x20, &vcc) == 0) {
    printf("Read VCC as %d mV. \n", vcc);
  } else {
    printf("Failed to read VCC \n");
  }
  if (read_i2c_reg(file_i2c, 0x22, &vbat) == 0) {
    printf("Read VCC as %d mV. \n", vbat);
  }
  usleep(1000);
  uint16_t vbat_conv_set = 4880, vbat_conv_read;
  if (write_i2c_reg(file_i2c, 0x50, vbat_conv_set) == 0) {
    printf("Set vbat_conv to %i. \n", vbat_conv_set);
  }
  usleep(1000);
  if (read_i2c_reg(file_i2c, 0x50, &vbat_conv_read) == 0) {
    printf("Read vbat_conv as %i. \n", vbat_conv_read);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x13,%edx
  lea    D46(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <open_i2c_dev@plt>
  test   %rax,%rax
  jne    L0
  mov    0x8(%rsp),%edi
  lea    0xc(%rsp),%rdx
  mov    $0x20,%esi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L106
  lea    D21(%rip),%rdi
  call   <puts@plt>
L88:
  mov    0x8(%rsp),%edi
  lea    0x10(%rsp),%rdx
  mov    $0x22,%esi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L29
L101:
  mov    $0x3e8,%edi
  call   <usleep@plt>
  mov    0x8(%rsp),%edi
  mov    $0x1310,%edx
  mov    $0x50,%esi
  call   <write_i2c_reg@plt>
  test   %rax,%rax
  je     L16
L31:
  mov    $0x3e8,%edi
  xor    %r12d,%r12d
  call   <usleep@plt>
  mov    0x8(%rsp),%edi
  lea    0x14(%rsp),%rdx
  mov    $0x50,%esi
  call   <read_i2c_reg@plt>
  test   %rax,%rax
  je     L105
L60:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x20,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L106:
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L88
L105:
  mov    0x14(%rsp),%esi
  lea    D69(%rip),%rdi
  call   <printf@plt>
  jmp    L60
L16:
  mov    $0x1310,%esi
  lea    D67(%rip),%rdi
  call   <printf@plt>
  jmp    L31
L29:
  mov    0x10(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L101
L0:
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  or     $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L60
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D46
type_guessed: string
name: retrieve_data
arguments: data_label: D21
type_guessed: string
name: retrieve_data
arguments: data_label: D8
type_guessed: string
name: retrieve_data
arguments: data_label: D69
type_guessed: string
name: retrieve_data
arguments: data_label: D67
type_guessed: string
name: retrieve_data
arguments: data_label: D28
type_guessed: string

tool: D46: /dev/i2c-1

tool: D21: Failed to read VCC 

tool: D8: Read VCC as %d mV. 


tool: D69: Read vbat_conv as %i. 


tool: D67: Set vbat_conv to %i. 


tool: D28: Failed to setup i2c

assistant: ```c
int main(void) {
  int file_i2c;
  char *filename = (char *)"/dev/i2c-1";
  uint16_t vcc;
  uint16_t vbat;
  if (open_i2c_dev(&file_i2c, filename, 0x13) != 0) {
    printf("Failed to setup i2c");
    return -1;
  }
  if (read_i2c_reg(file_i2c, 0x20, &vcc) == 0) {
    printf("Read VCC as %d mV. \n", vcc);
  } else {
    printf("Failed to read VCC \n");
  }
  if (read_i2c_reg(file_i2c, 0x22, &vbat) == 0) {
    printf("Read VCC as %d mV. \n", vbat);
  }
  usleep(1000);
  uint16_t vbat_conv_set = 4880, vbat_conv_read;
  if (write_i2c_reg(file_i2c, 0x50, vbat_conv_set) == 0) {
    printf("Set vbat_conv to %i. \n", vbat_conv_set);
  }
  usleep(1000);
  if (read_i2c_reg(file_i2c, 0x50, &vbat_conv_read) == 0) {
    printf("Read vbat_conv as %i. \n", vbat_conv_read);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L13
  mov    $0x0,%eax
  jmp    L6
L13:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %edx,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edi
  call   <count>
  mov    -0x8(%rbp),%edx
  add    %edx,%eax
L6:
  leave
  ret
```

assistant: ```c
int count(int dig) {
  int cnt = 0, num;
  if (dig == 0)
    return 0;
  num = dig % 10;
  cnt++;
  return cnt + count(dig / 10);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<count>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  jne    L3
  ret
L3:
  sub    $0x8,%rsp
  movslq %edi,%rdi
  imul   $0x66666667,%rdi,%rdi
  sar    $0x22,%rdi
  sar    $0x1f,%eax
  sub    %eax,%edi
  call   <count>
  add    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int count(int dig) {
  int cnt = 0, num;
  if (dig == 0)
    return 0;
  num = dig % 10;
  cnt++;
  return cnt + count(dig / 10);
}
```
user: What is the c source code of the assembly code below?

```asm
<count>:
  endbr64
  mov    $0x1,%edx
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L12
L7:
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edx,%r8d
  add    $0x1,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edi
  jne    L7
L12:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count(int dig) {
  int cnt = 0, num;
  if (dig == 0)
    return 0;
  num = dig % 10;
  cnt++;
  return cnt + count(dig / 10);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<count>:
  endbr64
  mov    $0x1,%edx
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L13
L14:
  movslq %edi,%rax
  mov    %edi,%ecx
  mov    %edx,%r8d
  add    $0x1,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  mov    %eax,%edi
  jne    L14
L13:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count(int dig) {
  int cnt = 0, num;
  if (dig == 0)
    return 0;
  num = dig % 10;
  cnt++;
  return cnt + count(dig / 10);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Generate_Pattern>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L24
L6:
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L39:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    (%rax,%rax,1),%ecx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  sub    $0x1,%ecx
  mov    -0x8(%rbp),%eax
  cltq
  mov    %ecx,(%rdx,%rax,4)
  addl   $0x1,-0x8(%rbp)
L29:
  cmpl   $0x63,-0x8(%rbp)
  jle    L39
  addl   $0x1,-0x4(%rbp)
L24:
  cmpl   $0x4,-0x4(%rbp)
  jle    L6
  nop
  nop
  leave
  ret
```

assistant: ```c
void Generate_Pattern(int pattern[][100]) {
  int i, p;
  for (p = 0; p < 5; p++) {
    for (i = 0; i < 100; i++) {
      pattern[p][i] = 2 * (rand() % 2) - 1;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Generate_Pattern>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  lea    0x190(%rdi),%rbp
  add    $0x960,%r12
L9:
  lea    -0x190(%rbp),%rbx
L15:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,(%rbx)
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L15
  add    $0x190,%rbp
  cmp    %r12,%rbp
  jne    L9
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Generate_Pattern(int pattern[][100]) {
  int i, p;
  for (p = 0; p < 5; p++) {
    for (i = 0; i < 100; i++) {
      pattern[p][i] = 2 * (rand() % 2) - 1;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Generate_Pattern>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    $0x960,%rbp
  lea    0x190(%rdi),%rbx
L2:
  lea    -0x190(%rbx),%r12
L7:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L7
  lea    0x190(%r12),%rbx
  cmp    %rbp,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Generate_Pattern(int pattern[][100]) {
  int i, p;
  for (p = 0; p < 5; p++) {
    for (i = 0; i < 100; i++) {
      pattern[p][i] = 2 * (rand() % 2) - 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Generate_Pattern>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  add    $0x960,%rbp
  lea    0x190(%rdi),%rbx
L6:
  lea    -0x190(%rbx),%r12
L1:
  xor    %eax,%eax
  add    $0x4,%r12
  call   <rand@plt>
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  lea    -0x1(%rax,%rax,1),%eax
  mov    %eax,-0x4(%r12)
  cmp    %rbx,%r12
  jne    L1
  lea    0x190(%r12),%rbx
  cmp    %rbp,%rbx
  jne    L6
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void Generate_Pattern(int pattern[][100]) {
  int i, p;
  for (p = 0; p < 5; p++) {
    for (i = 0; i < 100; i++) {
      pattern[p][i] = 2 * (rand() % 2) - 1;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strcatchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L10
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L10:
  cmpq   $0x0,-0x18(%rbp)
  je     L1
  mov    -0x18(%rbp),%rax
  jmp    L7
L1:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
char *strcatchar(char *String, char Ch) {
  size_t Len;
  if (String != NULL) {
    Len = strlen(String);
    String[Len] = Ch;
    String[Len + 1] = '\0';
  }
  if (String != NULL)
    return (String);
  else
    return (NULL);
}
```