ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<c_timegm>:
  endbr64
  movslq 0x4(%rdi),%rax
  mov    (%rdi),%edx
  mov    %rdi,%rsi
  mov    %rax,%r9
  imul   $0x2aaaaaab,%rax,%rax
  mov    %r9d,%ecx
  sar    $0x1f,%ecx
  sar    $0x21,%rax
  sub    %ecx,%eax
  lea    0x76c(%rdx,%rax,1),%r10d
  lea    (%rax,%rax,2),%eax
  movslq %r10d,%r8
  shl    $0x2,%eax
  sub    %eax,%r9d
  lea    -0x7b2(%r8),%rax
  lea    -0x7ad(%r8),%r11
  lea    (%rax,%rax,8),%rdx
  movslq %r9d,%rcx
  lea    -0x76c(%r8),%rdi
  lea    (%rax,%rdx,8),%rax
  lea    D9(%rip),%rdx
  movslq (%rdx,%rcx,4),%rdx
  lea    (%rax,%rax,4),%rax
  movabs $0xa3d70a3d70a3d70b,%rcx
  add    %rdx,%rax
  mov    %r8,%rdx
  sub    $0x7b0,%rdx
  cmovns %rdx,%r11
  sar    $0x2,%r11
  add    %rax,%r11
  mov    %rdi,%rax
  imul   %rcx
  add    %rdi,%rdx
  sar    $0x3f,%rdi
  sar    $0x6,%rdx
  sub    %rdx,%rdi
  add    %r11,%rdi
  lea    -0x640(%r8),%r11
  mov    %r11,%rax
  imul   %rcx
  add    %r11,%rdx
  sar    $0x3f,%r11
  sar    $0x8,%rdx
  sub    %r11,%rdx
  and    $0x3,%r10d
  lea    (%rdx,%rdi,1),%rax
  jne    L7
  movabs $0x8f5c28f5c28f5c29,%rdx
  movabs $0x28f5c28f5c28f5c,%rcx
  imul   %rdx,%r8
  movabs $0x51eb851eb851eb8,%rdx
  add    %r8,%rdx
  ror    $0x2,%rdx
  cmp    %rcx,%rdx
  jbe    L41
  xor    %edx,%edx
  cmp    $0x2,%r9d
  setl   %dl
  sub    %rdx,%rax
L7:
  mov    0x8(%rsi),%ecx
  lea    -0x1(%rcx),%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  lea    (%rax,%rax,2),%rdx
  mov    0x20(%rsi),%rax
  lea    (%rax,%rdx,8),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    0x18(%rsi),%rdx
  lea    (%rdx,%rax,4),%rdx
  mov    %rdx,%rax
  shl    $0x4,%rax
  sub    %rdx,%rax
  mov    0x10(%rsi),%rdx
  cmpl   $0x1,0xc(%rsi)
  lea    (%rdx,%rax,4),%rax
  je     L5
  ret
  nopl   0x0(%rax)
L5:
  sub    $0xe10,%rax
  ret
  nop
L41:
  movabs $0x51eb851eb851eb0,%rdx
  add    %rdx,%r8
  movabs $0xa3d70a3d70a3d6,%rdx
  ror    $0x4,%r8
  cmp    %rdx,%r8
  ja     L7
  xor    %edx,%edx
  cmp    $0x2,%r9d
  setl   %dl
  sub    %rdx,%rax
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: label: D9
type_guessed: string

tool: 

assistant: ```c
time_t c_timegm(struct tm *t) {
  long year;
  time_t result;
  static const int cdays[12] = {0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334};
  year = 1900 + t->tm_year + t->tm_mon / 12;
  result = (year - 1970) * 365 + cdays[t->tm_mon % 12];
  result += (year - 1968) / 4;
  result -= (year - 1900) / 100;
  result += (year - 1600) / 400;
  if ((year % 4) == 0 && ((year % 100) != 0 || (year % 400) == 0) && (t->tm_mon % 12) < 2) {
    result--;
  }
  result += t->tm_mday - 1;
  result *= 24;
  result += t->tm_hour;
  result *= 60;
  result += t->tm_min;
  result *= 60;
  result += t->tm_sec;
  if (t->tm_isdst == 1)
    result -= 3600;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_num_bits_set_in_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L22:
  mov    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  test   %eax,%eax
  je     L8
  addl   $0x1,-0x4(%rbp)
L8:
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    $0x1f,%eax
  jbe    L22
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_num_bits_set_in_num(unsigned int num) {
  int i;
  int count = 0;
  for (i = 0; i < sizeof(num) * 8; ++i) {
    if (num & (1 << i)) {
      ++count;
    }
  }
  return (count);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<find_num_bits_set_in_num>:
  endbr64
  mov    $0x0,%edx
  mov    $0x0,%ecx
  mov    $0x1,%esi
L9:
  mov    %esi,%eax
  shl    %cl,%eax
  and    %edi,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%edx
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L9
  mov    %edx,%eax
  ret
```

assistant: ```c
int find_num_bits_set_in_num(unsigned int num) {
  int i;
  int count = 0;
  for (i = 0; i < sizeof(num) * 8; ++i) {
    if (num & (1 << i)) {
      ++count;
    }
  }
  return (count);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<find_num_bits_set_in_num>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  xchg   %ax,%ax
L5:
  mov    %edx,%eax
  shl    %cl,%eax
  and    %edi,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r8d
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L5
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_num_bits_set_in_num(unsigned int num) {
  int i;
  int count = 0;
  for (i = 0; i < sizeof(num) * 8; ++i) {
    if (num & (1 << i)) {
      ++count;
    }
  }
  return (count);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<find_num_bits_set_in_num>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  mov    $0x1,%edx
  xchg   %ax,%ax
L0:
  mov    %edx,%eax
  shl    %cl,%eax
  and    %edi,%eax
  cmp    $0x1,%eax
  sbb    $0xffffffff,%r8d
  add    $0x1,%ecx
  cmp    $0x20,%ecx
  jne    L0
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_num_bits_set_in_num(unsigned int num) {
  int i;
  int count = 0;
  for (i = 0; i < sizeof(num) * 8; ++i) {
    if (num & (1 << i)) {
      ++count;
    }
  }
  return (count);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  mov    $0x1f40,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xe,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffe0,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
datatype: string

tool: D16: %d


assistant: ```c
int main() {
  int foo = 2;
  printf("%d\n", 1000 + 7000);
  printf("%d\n", 1 + 2 + 7 + 4);
  printf("%d\n", foo - 66 + 33 - foo - 7 + 8);
  printf("%d\n", 4 + 1 + 7 - 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1f40,%esi
  lea    D4(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xe,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xffffffe0,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0xb,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_infered: string

tool: D4: %d


assistant: ```c
int main() {
  int foo = 2;
  printf("%d\n", 1000 + 7000);
  printf("%d\n", 1 + 2 + 7 + 4);
  printf("%d\n", foo - 66 + 33 - foo - 7 + 8);
  printf("%d\n", 4 + 1 + 7 - 1);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    $0x1f40,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xe,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffe0,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  int foo = 2;
  printf("%d\n", 1000 + 7000);
  printf("%d\n", 1 + 2 + 7 + 4);
  printf("%d\n", foo - 66 + 33 - foo - 7 + 8);
  printf("%d\n", 4 + 1 + 7 - 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  mov    $0x1f40,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xe,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xffffffe0,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xb,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: %d


assistant: ```c
int main() {
  int foo = 2;
  printf("%d\n", 1000 + 7000);
  printf("%d\n", 1 + 2 + 7 + 4);
  printf("%d\n", foo - 66 + 33 - foo - 7 + 8);
  printf("%d\n", 4 + 1 + 7 - 1);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cache_lfu_policy_destroy_item>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void cache_lfu_policy_destroy_item(struct cache_policy_item_ *item) {
  (void)0;
  assert(item != NULL);
  free(item);
  (void)0;
}
```
user: What is the c source code of the assembly code below:

```asm
<cache_lfu_policy_destroy_item>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void cache_lfu_policy_destroy_item(struct cache_policy_item_ *item) {
  (void)0;
  assert(item != NULL);
  free(item);
  (void)0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cache_lfu_policy_destroy_item>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void cache_lfu_policy_destroy_item(struct cache_policy_item_ *item) {
  (void)0;
  assert(item != NULL);
  free(item);
  (void)0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cache_lfu_policy_destroy_item>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void cache_lfu_policy_destroy_item(struct cache_policy_item_ *item) {
  (void)0;
  assert(item != NULL);
  free(item);
  (void)0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<atan2f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x14(%rbp),%xmm2
  movss  %xmm2,-0x1c(%rbp)
  flds   -0x1c(%rbp)
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  flds   -0x1c(%rbp)
  fpatan
  fstps  -0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

assistant: ```c
float atan2f(float y, float x) {
  float res = 0.0F;
  asm volatile("fpatan" : "=t"(res) : "u"(y), "0"(x) : "st(1)");
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<atan2f>:
  endbr64
  movss  %xmm1,-0x4(%rsp)
  flds   -0x4(%rsp)
  movss  %xmm0,-0x4(%rsp)
  flds   -0x4(%rsp)
  fxch   %st(1)
  fpatan
  fstps  -0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ret
```

assistant: ```c
float atan2f(float y, float x) {
  float res = 0.0F;
  asm volatile("fpatan" : "=t"(res) : "u"(y), "0"(x) : "st(1)");
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<atan2f>:
  endbr64
  movss  %xmm1,-0x4(%rsp)
  flds   -0x4(%rsp)
  movss  %xmm0,-0x4(%rsp)
  flds   -0x4(%rsp)
  fxch   %st(1)
  fpatan
  fstps  -0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ret
```

assistant: ```c
float atan2f(float y, float x) {
  float res = 0.0F;
  asm volatile("fpatan" : "=t"(res) : "u"(y), "0"(x) : "st(1)");
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<atan2f>:
  endbr64
  movss  %xmm1,-0x4(%rsp)
  flds   -0x4(%rsp)
  movss  %xmm0,-0x4(%rsp)
  flds   -0x4(%rsp)
  fxch   %st(1)
  fpatan
  fstps  -0x4(%rsp)
  movss  -0x4(%rsp),%xmm0
  ret
```

assistant: ```c
float atan2f(float y, float x) {
  float res = 0.0F;
  asm volatile("fpatan" : "=t"(res) : "u"(y), "0"(x) : "st(1)");
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
data_type: string

tool: D1: Usage: %s add x1 y1 x2 y2
       %s mul x  y  k


assistant: ```c
int usage(char *progname) {
  printf("Usage: %s add x1 y1 x2 y2\n"
         "       %s mul x  y  k\n",
         progname, progname);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string

tool: D3: Usage: %s add x1 y1 x2 y2
       %s mul x  y  k


assistant: ```c
int usage(char *progname) {
  printf("Usage: %s add x1 y1 x2 y2\n"
         "       %s mul x  y  k\n",
         progname, progname);
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: string

tool: D1: Usage: %s add x1 y1 x2 y2
       %s mul x  y  k


assistant: ```c
int usage(char *progname) {
  printf("Usage: %s add x1 y1 x2 y2\n"
         "       %s mul x  y  k\n",
         progname, progname);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<usage>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    %rdi,%rdx
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
type_infered: string

tool: D8: Usage: %s add x1 y1 x2 y2
       %s mul x  y  k


assistant: ```c
int usage(char *progname) {
  printf("Usage: %s add x1 y1 x2 y2\n"
         "       %s mul x  y  k\n",
         progname, progname);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isupper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L8
  cmpl   $0x5a,-0x4(%rbp)
  jg     L8
  mov    $0x1,%eax
  jmp    L29
L8:
  mov    $0x0,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int isupper(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return 1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isupper>:
  endbr64
  sub    $0x41,%edi
  cmp    $0x19,%edi
  setbe  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int isupper(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<isupper>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int isupper(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<isupper>:
  endbr64
  sub    $0x41,%edi
  xor    %eax,%eax
  cmp    $0x19,%edi
  setbe  %al
  ret
```

assistant: ```c
int isupper(int c) {
  if ((c >= 'A') && (c <= 'Z'))
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<int_compare>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x30(%rbp)
  mov    %al,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  cmpb   $0x3d,-0x24(%rbp)
  jne    L31
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  jmp    L28
L31:
  cmpb   $0x3c,-0x24(%rbp)
  jne    L29
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setl   %al
  movzbl %al,%eax
  jmp    L28
L29:
  cmpb   $0x3e,-0x24(%rbp)
  jne    L50
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  setg   %al
  movzbl %al,%eax
  jmp    L28
L50:
  mov    $0x0,%eax
L28:
  leave
  ret
```

assistant: ```c
int int_compare(const char *s1, const char *s2, char o, void *object) {
  int l1 = atoi(s1);
  int l2 = atoi(s2);
  if (o == '=')
    return (l1 == l2);
  if (o == '<')
    return (l1 < l2);
  if (o == '>')
    return (l1 > l2);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<int_compare>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <atoi@plt>
  mov    %eax,%r12d
  mov    %rbp,%rdi
  call   <atoi@plt>
  cmp    $0x3d,%bl
  je     L54
  cmp    $0x3c,%bl
  je     L44
  mov    $0x0,%edx
  cmp    $0x3e,%bl
  je     L38
L11:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L54:
  cmp    %eax,%r12d
  sete   %dl
  movzbl %dl,%edx
  jmp    L11
L44:
  cmp    %eax,%r12d
  setl   %dl
  movzbl %dl,%edx
  jmp    L11
L38:
  cmp    %eax,%r12d
  setg   %dl
  movzbl %dl,%edx
  jmp    L11
```

assistant: ```c
int int_compare(const char *s1, const char *s2, char o, void *object) {
  int l1 = atoi(s1);
  int l2 = atoi(s2);
  if (o == '=')
    return (l1 == l2);
  if (o == '<')
    return (l1 < l2);
  if (o == '>')
    return (l1 > l2);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<int_compare>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  cmp    $0x3d,%bl
  je     L17
  cmp    $0x3c,%bl
  je     L20
  xor    %r8d,%r8d
  cmp    $0x3e,%bl
  je     L27
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L17:
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  pop    %rbx
  pop    %rbp
  sete   %r8b
  pop    %r12
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  pop    %rbx
  pop    %rbp
  setg   %r8b
  pop    %r12
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  pop    %rbx
  pop    %rbp
  setl   %r8b
  pop    %r12
  mov    %r8d,%eax
  ret
```

assistant: ```c
int int_compare(const char *s1, const char *s2, char o, void *object) {
  int l1 = atoi(s1);
  int l2 = atoi(s2);
  if (o == '=')
    return (l1 == l2);
  if (o == '<')
    return (l1 < l2);
  if (o == '>')
    return (l1 > l2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<int_compare>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <atoi@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <atoi@plt>
  cmp    $0x3d,%bl
  je     L15
  cmp    $0x3c,%bl
  je     L28
  xor    %r8d,%r8d
  cmp    $0x3e,%bl
  je     L3
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  pop    %rbx
  pop    %rbp
  sete   %r8b
  pop    %r12
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  pop    %rbx
  pop    %rbp
  setg   %r8b
  pop    %r12
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L28:
  xor    %r8d,%r8d
  cmp    %eax,%r12d
  pop    %rbx
  pop    %rbp
  setl   %r8b
  pop    %r12
  mov    %r8d,%eax
  ret
```

assistant: ```c
int int_compare(const char *s1, const char *s2, char o, void *object) {
  int l1 = atoi(s1);
  int l2 = atoi(s2);
  if (o == '=')
    return (l1 == l2);
  if (o == '<')
    return (l1 < l2);
  if (o == '>')
    return (l1 > l2);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<new_Int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *new_Int(const int value) {
  int *p = (int *)malloc(sizeof(int));
  assert(p);
  *p = value;
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<new_Int>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %ebp,(%rbx)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int *new_Int(const int value) {
  int *p = (int *)malloc(sizeof(int));
  assert(p);
  *p = value;
  return p;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<new_Int>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %ebx,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int *new_Int(const int value) {
  int *p = (int *)malloc(sizeof(int));
  assert(p);
  *p = value;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<new_Int>:
  endbr64
  push   %r12
  push   %rbx
  mov    %edi,%ebx
  mov    $0x4,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <assert@plt>
  mov    %ebx,(%r12)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int *new_Int(const int value) {
  int *p = (int *)malloc(sizeof(int));
  assert(p);
  *p = value;
  return p;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<socket_log2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,-0x10(%rbp)
  mov    $0x0,%ebx
  movabs $0xffffffff00000000,%rax
  and    -0x10(%rbp),%rax
  test   %rax,%rax
  je     L24
  shrq   $0x20,-0x10(%rbp)
  or     $0x20,%rbx
L24:
  mov    -0x10(%rbp),%rax
  and    $0xffff0000,%eax
  test   %rax,%rax
  je     L19
  shrq   $0x10,-0x10(%rbp)
  or     $0x10,%rbx
L19:
  mov    -0x10(%rbp),%rax
  and    $0xff00,%eax
  test   %rax,%rax
  je     L25
  shrq   $0x8,-0x10(%rbp)
  or     $0x8,%rbx
L25:
  mov    -0x10(%rbp),%rax
  and    $0xf0,%eax
  test   %rax,%rax
  je     L44
  shrq   $0x4,-0x10(%rbp)
  or     $0x4,%rbx
L44:
  mov    -0x10(%rbp),%rax
  and    $0xc,%eax
  test   %rax,%rax
  je     L13
  shrq   $0x2,-0x10(%rbp)
  or     $0x2,%rbx
L13:
  mov    -0x10(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L15
  shrq   -0x10(%rbp)
  or     $0x1,%rbx
L15:
  mov    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long socket_log2(unsigned long v) {
  register unsigned long c = 0;
  if (v & 0xFFFFFFFF00000000UL) {
    v >>= 0x20;
    c |= 0x20;
  }
  if (v & 0xFFFF0000UL) {
    v >>= 0x10;
    c |= 0x10;
  }
  if (v & 0x0000FF00UL) {
    v >>= 0x08;
    c |= 0x08;
  }
  if (v & 0x000000F0UL) {
    v >>= 0x04;
    c |= 0x04;
  }
  if (v & 0x0000000CUL) {
    v >>= 0x02;
    c |= 0x02;
  }
  if (v & 0x00000002UL) {
    v >>= 0x01;
    c |= 0x01;
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<socket_log2>:
  endbr64
  movabs $0xffffffff00000000,%rax
  and    %rdi,%rax
  je     L17
  shr    $0x20,%rdi
  mov    $0x20,%eax
L17:
  test   $0xffff0000,%edi
  je     L36
  shr    $0x10,%rdi
  or     $0x10,%rax
L36:
  test   $0xff00,%edi
  je     L11
  shr    $0x8,%rdi
  or     $0x8,%rax
L11:
  test   $0xf0,%dil
  je     L8
  shr    $0x4,%rdi
  or     $0x4,%rax
L8:
  test   $0xc,%dil
  je     L25
  shr    $0x2,%rdi
  or     $0x2,%rax
L25:
  mov    %rax,%rdx
  or     $0x1,%rdx
  test   $0x2,%dil
  cmovne %rdx,%rax
  ret
```

assistant: ```c
unsigned long socket_log2(unsigned long v) {
  register unsigned long c = 0;
  if (v & 0xFFFFFFFF00000000UL) {
    v >>= 0x20;
    c |= 0x20;
  }
  if (v & 0xFFFF0000UL) {
    v >>= 0x10;
    c |= 0x10;
  }
  if (v & 0x0000FF00UL) {
    v >>= 0x08;
    c |= 0x08;
  }
  if (v & 0x000000F0UL) {
    v >>= 0x04;
    c |= 0x04;
  }
  if (v & 0x0000000CUL) {
    v >>= 0x02;
    c |= 0x02;
  }
  if (v & 0x00000002UL) {
    v >>= 0x01;
    c |= 0x01;
  }
  return c;
}
```