ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<cksum16>:
  endbr64
  cmp    $0x1,%esi
  jle    L20
  lea    -0x2(%rsi),%ecx
  shr    %ecx
  lea    0x1(%rcx),%edx
  add    %rdi,%rdx
  mov    $0x0,%eax
L66:
  add    $0x1,%rdi
  add    -0x1(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L66
  neg    %ecx
  lea    -0x2(%rsi,%rcx,2),%ecx
  test   %ecx,%ecx
  jle    L4
L53:
  add    (%rdx),%eax
L4:
  mov    %eax,%edx
  sar    $0x10,%edx
  je     L13
L25:
  movzwl %ax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  sar    $0x10,%edx
  jne    L25
L13:
  not    %eax
  ret
L20:
  mov    %rdi,%rdx
  mov    $0x0,%eax
  je     L53
  jmp    L13
```

assistant: ```c
uint16_t cksum16(void *addr, uint32_t length) {
  uint32_t sum = 0;
  while (length > 1) {
    sum = sum + *((uint16_t *)addr++);
    length = length - 2;
  }
  if (length > 0)
    sum = sum + *((uint8_t *)addr);
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return (uint16_t)(~sum);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cksum16>:
  endbr64
  cmp    $0x1,%esi
  jle    L0
  sub    $0x2,%esi
  xor    %eax,%eax
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%edx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L20:
  add    $0x1,%rdi
  add    -0x1(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L20
  neg    %ecx
  lea    (%rsi,%rcx,2),%ecx
  cmp    $0x1,%ecx
  jne    L4
  jmp    L28
  nopl   0x0(%rax,%rax,1)
L55:
  movzwl %ax,%eax
  add    %edx,%eax
L4:
  mov    %eax,%edx
  sar    $0x10,%edx
  jne    L55
  not    %eax
  ret
L8:
  mov    %rdi,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L28:
  add    (%rdx),%eax
  jmp    L4
  nopl   0x0(%rax)
L0:
  je     L8
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint16_t cksum16(void *addr, uint32_t length) {
  uint32_t sum = 0;
  while (length > 1) {
    sum = sum + *((uint16_t *)addr++);
    length = length - 2;
  }
  if (length > 0)
    sum = sum + *((uint8_t *)addr);
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return (uint16_t)(~sum);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cksum16>:
  endbr64
  cmp    $0x1,%esi
  jle    L53
  sub    $0x2,%esi
  xor    %eax,%eax
  mov    %esi,%ecx
  shr    %ecx
  lea    0x1(%rcx),%edx
  add    %rdi,%rdx
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x1,%rdi
  add    -0x1(%rdi),%eax
  cmp    %rdx,%rdi
  jne    L0
  neg    %ecx
  lea    (%rsi,%rcx,2),%ecx
  cmp    $0x1,%ecx
  jne    L59
  jmp    L58
  nopl   0x0(%rax,%rax,1)
L47:
  movzwl %ax,%eax
  add    %edx,%eax
L59:
  mov    %eax,%edx
  sar    $0x10,%edx
  jne    L47
  not    %eax
  ret
L27:
  mov    %rdi,%rdx
  xor    %eax,%eax
  nopl   0x0(%rax)
L58:
  add    (%rdx),%eax
  jmp    L59
  nopl   0x0(%rax)
L53:
  je     L27
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
uint16_t cksum16(void *addr, uint32_t length) {
  uint32_t sum = 0;
  while (length > 1) {
    sum = sum + *((uint16_t *)addr++);
    length = length - 2;
  }
  if (length > 0)
    sum = sum + *((uint8_t *)addr);
  while (sum >> 16)
    sum = (sum & 0xFFFF) + (sum >> 16);
  return (uint16_t)(~sum);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<matrixTransposition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L30
L18:
  mov    -0x1c(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L0:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rcx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  addl   $0x1,-0x10(%rbp)
L30:
  mov    -0x10(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L18
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
double **matrixTransposition(double **matrix, int row, int column) {
  double **result = (double **)malloc(column * sizeof(double *));
  for (int i = 0; i < column; i++) {
    result[i] = (double *)malloc(row * sizeof(double));
    for (int j = 0; j < row; j++) {
      result[i][j] = matrix[j][i];
    }
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<matrixTransposition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r14d
  mov    %edx,%ebx
  lea    0x0(,%rdx,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %ebx,%ebx
  jle    L12
  lea    0x0(,%r14,8),%r15d
  mov    %ebx,%ebx
  lea    0x0(,%rbx,8),%r13
  lea    -0x1(%r14),%eax
  lea    0x8(,%rax,8),%r12
  mov    $0x0,%ebx
L11:
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    0x8(%rsp),%rsi
  lea    (%rsi,%rbx,1),%rcx
  mov    %rax,(%rcx)
  test   %r14d,%r14d
  jle    L19
  mov    $0x0,%eax
L38:
  mov    0x0(%rbp,%rax,1),%rdx
  movsd  (%rdx,%rbx,1),%xmm0
  mov    (%rcx),%rdx
  movsd  %xmm0,(%rdx,%rax,1)
  add    $0x8,%rax
  cmp    %r12,%rax
  jne    L38
L19:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L11
L12:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **matrixTransposition(double **matrix, int row, int column) {
  double **result = (double **)malloc(column * sizeof(double *));
  for (int i = 0; i < column; i++) {
    result[i] = (double *)malloc(row * sizeof(double));
    for (int j = 0; j < row; j++) {
      result[i][j] = matrix[j][i];
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<matrixTransposition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x0(,%r13,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L28
  lea    -0x1(%rbx),%ebp
  lea    0x0(,%rbx,8),%r15d
  shl    $0x3,%r13
  xor    %r14d,%r14d
  add    $0x1,%rbp
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,(%r12,%r14,1)
  test   %ebx,%ebx
  jle    L29
  mov    0x8(%rsp),%rsi
  lea    (%rax,%rbp,8),%rdi
  sub    %rax,%rsi
  nopl   0x0(%rax)
L33:
  mov    (%rsi,%rax,1),%rdx
  add    $0x8,%rax
  movsd  (%rdx,%r14,1),%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rdi,%rax
  jne    L33
L29:
  add    $0x8,%r14
  cmp    %r13,%r14
  jne    L39
L28:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **matrixTransposition(double **matrix, int row, int column) {
  double **result = (double **)malloc(column * sizeof(double *));
  for (int i = 0; i < column; i++) {
    result[i] = (double *)malloc(row * sizeof(double));
    for (int j = 0; j < row; j++) {
      result[i][j] = matrix[j][i];
    }
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<matrixTransposition>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  movslq %edx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x0(,%r13,8),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %r13d,%r13d
  jle    L20
  lea    -0x1(%rbx),%ebp
  lea    0x0(,%rbx,8),%r15d
  shl    $0x3,%r13
  xor    %r14d,%r14d
  add    $0x1,%rbp
  nopw   0x0(%rax,%rax,1)
L39:
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,(%r12,%r14,1)
  test   %ebx,%ebx
  jle    L1
  mov    0x8(%rsp),%rsi
  lea    (%rax,%rbp,8),%rdi
  sub    %rax,%rsi
  nopl   0x0(%rax)
L0:
  mov    (%rsi,%rax,1),%rdx
  add    $0x8,%rax
  movsd  (%rdx,%r14,1),%xmm0
  movsd  %xmm0,-0x8(%rax)
  cmp    %rax,%rdi
  jne    L0
L1:
  add    $0x8,%r14
  cmp    %r13,%r14
  jne    L39
L20:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
double **matrixTransposition(double **matrix, int row, int column) {
  double **result = (double **)malloc(column * sizeof(double *));
  for (int i = 0; i < column; i++) {
    result[i] = (double *)malloc(row * sizeof(double));
    for (int j = 0; j < row; j++) {
      result[i][j] = matrix[j][i];
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0x4(%rbp)
  jmp    L2
L16:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <fbnc@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x14,-0x4(%rbp)
  jle    L16
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D2: %d  

assistant: ```c
int main(void) {
  for (int i = 1; i <= 20; i++) {
    printf("%d  ", fbnc(i));
  }
  printf("\n");
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D8(%rip),%rbp
L0:
  mov    %ebx,%edi
  call   <fbnc@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0x15,%ebx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D8
data_type: string

tool: D8: %d  

assistant: ```c
int main(void) {
  for (int i = 1; i <= 20; i++) {
    printf("%d  ", fbnc(i));
  }
  printf("\n");
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fbnc@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x15,%ebx
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: %d  

assistant: ```c
int main(void) {
  for (int i = 1; i <= 20; i++) {
    printf("%d  ", fbnc(i));
  }
  printf("\n");
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <fbnc@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    $0x15,%ebx
  jne    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %d  

assistant: ```c
int main(void) {
  for (int i = 1; i <= 20; i++) {
    printf("%d  ", fbnc(i));
  }
  printf("\n");
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<dotime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

assistant: ```c
dotime() {
  long curtime;
  time(&curtime);
  printf(ctime(&curtime));
}
```
user: Translate the below assembly code into C programming language:

```asm
<dotime>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <time@plt>
  mov    %rbx,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
dotime() {
  long curtime;
  time(&curtime);
  printf(ctime(&curtime));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<dotime>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
dotime() {
  long curtime;
  time(&curtime);
  printf(ctime(&curtime));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<dotime>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  mov    %rbp,%rdi
  call   <ctime@plt>
  mov    %rax,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
dotime() {
  long curtime;
  time(&curtime);
  printf(ctime(&curtime));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<aeron_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <aeron_hash_code@plt>
  mov    %eax,-0x4(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x20(%rbp)
  ja     L1
  mov    $0x20,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%ecx
  shr    %cl,%eax
  xor    %eax,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  and    -0x20(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t aeron_hash(uint64_t value, size_t mask) {
  uint64_t hash = aeron_hash_code(value);
  if (mask <= UINT32_MAX) {
    hash = (uint32_t)hash ^ (uint32_t)(hash >> 32u);
  }
  return (size_t)(hash & mask);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<aeron_hash>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <aeron_hash_code@plt>
  and    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t aeron_hash(uint64_t value, size_t mask) {
  uint64_t hash = aeron_hash_code(value);
  if (mask <= UINT32_MAX) {
    hash = (uint32_t)hash ^ (uint32_t)(hash >> 32u);
  }
  return (size_t)(hash & mask);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<aeron_hash>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <aeron_hash_code@plt>
  and    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t aeron_hash(uint64_t value, size_t mask) {
  uint64_t hash = aeron_hash_code(value);
  if (mask <= UINT32_MAX) {
    hash = (uint32_t)hash ^ (uint32_t)(hash >> 32u);
  }
  return (size_t)(hash & mask);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<aeron_hash>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <aeron_hash_code@plt>
  and    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
size_t aeron_hash(uint64_t value, size_t mask) {
  uint64_t hash = aeron_hash_code(value);
  if (mask <= UINT32_MAX) {
    hash = (uint32_t)hash ^ (uint32_t)(hash >> 32u);
  }
  return (size_t)(hash & mask);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<caf_shash_rs>:
  endbr64
  test   %rdi,%rdi
  je     L61
  test   %esi,%esi
  jle    L61
  cmp    $0x3,%esi
  jle    L39
  lea    0x3(%rsi),%ecx
  test   %esi,%esi
  cmovns %esi,%ecx
  sar    $0x2,%ecx
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    $0xf8c9,%r8d
L21:
  imul   %r8d,%eax
  add    (%rdi,%rdx,4),%eax
  imul   $0x5c6b7,%r8d,%r8d
  add    $0x1,%rdx
  cmp    %edx,%ecx
  jg     L21
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x1e,%edx
  lea    (%rsi,%rdx,1),%r9d
  and    $0x3,%r9d
  sub    %edx,%r9d
  test   %r9d,%r9d
  jle    L35
  shl    $0x2,%ecx
  movslq %ecx,%rcx
  add    %rdi,%rcx
  mov    %rcx,%rdx
  mov    %esi,%edi
  sub    %r9d,%edi
  cmp    %edi,%esi
  jle    L35
  sub    $0x1,%esi
  sub    %edi,%esi
  lea    0x1(%rcx,%rsi,1),%rsi
L4:
  imul   %r8d,%eax
  movsbl (%rdx),%ecx
  add    %ecx,%eax
  imul   $0x5c6b7,%r8d,%r8d
  add    $0x1,%rdx
  cmp    %rdx,%rsi
  jne    L4
  ret
L39:
  mov    $0x0,%edx
  mov    $0x0,%eax
  mov    $0xf8c9,%ecx
L41:
  imul   %ecx,%eax
  movsbl (%rdi,%rdx,1),%r8d
  add    %r8d,%eax
  imul   $0x5c6b7,%ecx,%ecx
  add    $0x1,%rdx
  cmp    %edx,%esi
  jg     L41
  ret
L61:
  mov    $0x0,%eax
L35:
  ret
```

assistant: ```c
u_int32_t caf_shash_rs(const char *str, const u_int len) {
  u_int32_t b = 378551;
  u_int32_t a = 63689;
  u_int32_t hash = 0;
  u_int32_t i = 0;
  u_int32_t i32b = 0;
  u_int32_t *i32p = (u_int32_t *)NULL;
  char *ptr = (char *)str;
  if (ptr != (const char *)NULL && len > 0) {
    i32b = len / 4;
    if (i32b > 0) {
      i32p = (u_int32_t *)ptr;
      for (i = 0; i < i32b; i32p++, i++) {
        hash = hash * a + (*i32p);
        a = a * b;
      }
      if ((len % 4) > 0) {
        i32b *= 4;
        ptr = (char *)((size_t)i32b + (size_t)ptr);
        for (i = (len - (len % 4)); i < len; ptr++, i++) {
          hash = hash * a + (*ptr);
          a = a * b;
        }
      }
    } else {
      for (i = 0; i < len; ptr++, i++) {
        hash = hash * a + (*ptr);
        a = a * b;
      }
    }
    return hash;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<caf_shash_rs>:
  endbr64
  test   %rdi,%rdi
  je     L59
  test   %esi,%esi
  jle    L59
  cmp    $0x3,%esi
  jle    L37
  mov    %esi,%ecx
  mov    %rdi,%rdx
  mov    $0xf8c9,%r9d
  sar    $0x2,%ecx
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%r8
  xor    %eax,%eax
  nopl   (%rax)
L52:
  imul   %r9d,%eax
  add    $0x4,%rdx
  add    -0x4(%rdx),%eax
  imul   $0x5c6b7,%r9d,%r9d
  cmp    %r8,%rdx
  jne    L52
  mov    %esi,%r8d
  and    $0x3,%r8d
  je     L2
  lea    0x0(,%rcx,4),%edx
  mov    %esi,%ecx
  movslq %edx,%rdx
  sub    %r8d,%ecx
  add    %rdi,%rdx
  cmp    %ecx,%esi
  jle    L2
  sub    $0x1,%esi
  sub    %ecx,%esi
  lea    0x1(%rdx,%rsi,1),%rsi
  nopl   0x0(%rax,%rax,1)
L54:
  imul   %r9d,%eax
  movsbl (%rdx),%ecx
  add    $0x1,%rdx
  imul   $0x5c6b7,%r9d,%r9d
  add    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L54
  ret
  nopw   0x0(%rax,%rax,1)
L59:
  xor    %eax,%eax
L2:
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  xor    %edx,%edx
  xor    %eax,%eax
  mov    $0xf8c9,%ecx
L23:
  imul   %ecx,%eax
  movsbl (%rdi,%rdx,1),%r8d
  add    $0x1,%rdx
  imul   $0x5c6b7,%ecx,%ecx
  add    %r8d,%eax
  cmp    %edx,%esi
  jg     L23
  ret
```

assistant: ```c
u_int32_t caf_shash_rs(const char *str, const u_int len) {
  u_int32_t b = 378551;
  u_int32_t a = 63689;
  u_int32_t hash = 0;
  u_int32_t i = 0;
  u_int32_t i32b = 0;
  u_int32_t *i32p = (u_int32_t *)NULL;
  char *ptr = (char *)str;
  if (ptr != (const char *)NULL && len > 0) {
    i32b = len / 4;
    if (i32b > 0) {
      i32p = (u_int32_t *)ptr;
      for (i = 0; i < i32b; i32p++, i++) {
        hash = hash * a + (*i32p);
        a = a * b;
      }
      if ((len % 4) > 0) {
        i32b *= 4;
        ptr = (char *)((size_t)i32b + (size_t)ptr);
        for (i = (len - (len % 4)); i < len; ptr++, i++) {
          hash = hash * a + (*ptr);
          a = a * b;
        }
      }
    } else {
      for (i = 0; i < len; ptr++, i++) {
        hash = hash * a + (*ptr);
        a = a * b;
      }
    }
    return hash;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<caf_shash_rs>:
  endbr64
  test   %rdi,%rdi
  je     L20
  test   %esi,%esi
  jle    L20
  cmp    $0x3,%esi
  jg     L29
  movsbl (%rdi),%eax
  cmp    $0x1,%esi
  je     L6
  imul   $0x9d0a4daf,%eax,%eax
  movsbl 0x1(%rdi),%edx
  add    %edx,%eax
  cmp    $0x3,%esi
  jne    L6
  imul   $0xbedde219,%eax,%eax
  movsbl 0x2(%rdi),%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  xor    %eax,%eax
L6:
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %esi,%ecx
  mov    %rdi,%rdx
  mov    $0xf8c9,%r9d
  sar    $0x2,%ecx
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%r8
  xor    %eax,%eax
  nop
L10:
  imul   %r9d,%eax
  add    $0x4,%rdx
  add    -0x4(%rdx),%eax
  imul   $0x5c6b7,%r9d,%r9d
  cmp    %rdx,%r8
  jne    L10
  mov    %esi,%r8d
  and    $0x3,%r8d
  je     L6
  lea    0x0(,%rcx,4),%edx
  mov    %esi,%ecx
  movslq %edx,%rdx
  sub    %r8d,%ecx
  add    %rdi,%rdx
  cmp    %ecx,%esi
  jle    L6
  sub    $0x1,%esi
  sub    %ecx,%esi
  lea    0x1(%rdx,%rsi,1),%rsi
L69:
  imul   %r9d,%eax
  movsbl (%rdx),%ecx
  add    $0x1,%rdx
  imul   $0x5c6b7,%r9d,%r9d
  add    %ecx,%eax
  cmp    %rdx,%rsi
  jne    L69
  ret
```

assistant: ```c
u_int32_t caf_shash_rs(const char *str, const u_int len) {
  u_int32_t b = 378551;
  u_int32_t a = 63689;
  u_int32_t hash = 0;
  u_int32_t i = 0;
  u_int32_t i32b = 0;
  u_int32_t *i32p = (u_int32_t *)NULL;
  char *ptr = (char *)str;
  if (ptr != (const char *)NULL && len > 0) {
    i32b = len / 4;
    if (i32b > 0) {
      i32p = (u_int32_t *)ptr;
      for (i = 0; i < i32b; i32p++, i++) {
        hash = hash * a + (*i32p);
        a = a * b;
      }
      if ((len % 4) > 0) {
        i32b *= 4;
        ptr = (char *)((size_t)i32b + (size_t)ptr);
        for (i = (len - (len % 4)); i < len; ptr++, i++) {
          hash = hash * a + (*ptr);
          a = a * b;
        }
      }
    } else {
      for (i = 0; i < len; ptr++, i++) {
        hash = hash * a + (*ptr);
        a = a * b;
      }
    }
    return hash;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<shape_line2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  movsd  D29(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x8(%rbp),%xmm1
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x8(%rbp),%xmm1
  movsd  D29(%rip),%xmm0
  addsd  %xmm0,%xmm1
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movsd  D13(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D29
type_guessed: f64
name: read_data
arguments: data_label: D13
type_guessed: f64

tool: D29: 1

tool: D13: 0.5

assistant: ```c
int shape_line2(double L, double *N) {
  N[0] = 0.5 * (1.0 - L);
  N[1] = 0.5 * (1.0 + L);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<shape_line2>:
  endbr64
  movsd  D4(%rip),%xmm3
  movapd %xmm3,%xmm1
  subsd  %xmm0,%xmm1
  movsd  D3(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  movsd  %xmm1,(%rdi)
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  movsd  %xmm0,0x8(%rdi)
  mov    $0x0,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D3
type_guessed: f64

tool: D4: 1

tool: D3: 0.5

assistant: ```c
int shape_line2(double L, double *N) {
  N[0] = 0.5 * (1.0 - L);
  N[1] = 0.5 * (1.0 + L);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shape_line2>:
  endbr64
  movsd  D13(%rip),%xmm3
  movsd  D10(%rip),%xmm2
  xor    %eax,%eax
  movapd %xmm3,%xmm1
  subsd  %xmm0,%xmm1
  addsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm1
  mulsd  %xmm2,%xmm0
  movsd  %xmm1,(%rdi)
  movsd  %xmm0,0x8(%rdi)
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: f64
name: unpack_data
arguments: label: D10
type_infered: f64

tool: D13: 1

tool: D10: 0.5

assistant: ```c
int shape_line2(double L, double *N) {
  N[0] = 0.5 * (1.0 - L);
  N[1] = 0.5 * (1.0 + L);
  return 0;
}
```