ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <_pick_next_task_rt@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L6
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dequeue_pushable_task@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pick_next_task_rt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L5
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<checktick>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xcc(%rbp)
  jmp    L5
L59:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movq   %xmm0,%rax
  mov    %rax,-0xc0(%rbp)
  nop
L22:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movq   %xmm0,%rax
  mov    %rax,-0xb8(%rbp)
  movsd  -0xb8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0xc0(%rbp),%xmm1
  movsd  D4(%rip),%xmm0
  comisd %xmm1,%xmm0
  ja     L22
  movsd  -0xb8(%rbp),%xmm0
  movsd  %xmm0,-0xc0(%rbp)
  mov    -0xcc(%rbp),%eax
  cltq
  movsd  -0xc0(%rbp),%xmm0
  movsd  %xmm0,-0xb0(%rbp,%rax,8)
  addl   $0x1,-0xcc(%rbp)
L5:
  cmpl   $0x13,-0xcc(%rbp)
  jle    L59
  movl   $0xf4240,-0xc8(%rbp)
  movl   $0x1,-0xcc(%rbp)
  jmp    L12
L0:
  mov    -0xcc(%rbp),%eax
  cltq
  movsd  -0xb0(%rbp,%rax,8),%xmm0
  mov    -0xcc(%rbp),%eax
  sub    $0x1,%eax
  cltq
  movsd  -0xb0(%rbp,%rax,8),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D9(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0xc4(%rbp)
  mov    -0xc4(%rbp),%eax
  mov    $0x0,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  mov    -0xc8(%rbp),%edx
  cmp    %eax,%edx
  cmovle %edx,%eax
  mov    %eax,-0xc8(%rbp)
  addl   $0x1,-0xcc(%rbp)
L12:
  cmpl   $0x13,-0xcc(%rbp)
  jle    L0
  mov    -0xc8(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D4
type_guessed: byte[8]
name: retrieve_data
arguments: data_label: D9
type_guessed: f64

tool: {"D4": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D9: 1000000

assistant: ```c
int checktick() {
  int i, minDelta, Delta;
  double t1, t2, timesfound[20];
  for (i = 0; i < 20; i++) {
    t1 = mysecond();
    while (((t2 = mysecond()) - t1) < 1.0E-6)
      ;
    timesfound[i] = t1 = t2;
  }
  minDelta = 1000000;
  for (i = 1; i < 20; i++) {
    Delta = (int)(1.0E6 * (timesfound[i] - timesfound[i - 1]));
    minDelta = ((minDelta) < (((Delta) > (0) ? (Delta) : (0))) ? (minDelta) : (((Delta) > (0) ? (Delta) : (0))));
  }
  return (minDelta);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<checktick>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xb0(%rsp),%r12
  mov    %rbx,%rbp
L12:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movsd  %xmm0,0x8(%rsp)
L36:
  mov    $0x0,%eax
  call   <mysecond@plt>
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  movsd  D13(%rip),%xmm3
  comisd %xmm1,%xmm3
  ja     L36
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L12
  lea    0x98(%rbx),%rsi
  mov    $0xf4240,%edx
  movsd  D4(%rip),%xmm1
L33:
  movsd  0x8(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  mov    $0x0,%ecx
  cmovs  %ecx,%eax
  cmp    %eax,%edx
  cmovg  %eax,%edx
  add    $0x8,%rbx
  cmp    %rsi,%rbx
  jne    L33
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    %edx,%eax
  add    $0xc0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D13
datatype: byte[8]
name: parse_data
arguments: data_tag: D4
datatype: f64

tool: {"D13": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D4: 1000000

assistant: ```c
int checktick() {
  int i, minDelta, Delta;
  double t1, t2, timesfound[20];
  for (i = 0; i < 20; i++) {
    t1 = mysecond();
    while (((t2 = mysecond()) - t1) < 1.0E-6)
      ;
    timesfound[i] = t1 = t2;
  }
  minDelta = 1000000;
  for (i = 1; i < 20; i++) {
    Delta = (int)(1.0E6 * (timesfound[i] - timesfound[i - 1]));
    minDelta = ((minDelta) < (((Delta) > (0) ? (Delta) : (0))) ? (minDelta) : (((Delta) > (0) ? (Delta) : (0))));
  }
  return (minDelta);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<checktick>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbx
  lea    0xb0(%rsp),%r12
  mov    %rbx,%rbp
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  call   <mysecond@plt>
  movsd  %xmm0,0x8(%rsp)
  nopl   (%rax)
L0:
  xor    %eax,%eax
  call   <mysecond@plt>
  movsd  D18(%rip),%xmm3
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm1
  comisd %xmm1,%xmm3
  ja     L0
  movsd  %xmm0,0x0(%rbp)
  add    $0x8,%rbp
  cmp    %r12,%rbp
  jne    L8
  movsd  D17(%rip),%xmm1
  lea    0x98(%rbx),%rcx
  mov    $0xf4240,%r8d
  nopw   0x0(%rax,%rax,1)
L21:
  movsd  0x8(%rbx),%xmm0
  subsd  (%rbx),%xmm0
  xor    %edx,%edx
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  test   %eax,%eax
  cmovs  %edx,%eax
  cmp    %eax,%r8d
  cmovg  %eax,%r8d
  add    $0x8,%rbx
  cmp    %rbx,%rcx
  jne    L21
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0xc0,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_infered: byte[8]
name: retrieve_data
arguments: data_label: D17
type_infered: f64

tool: {"D18": [0x8d,0xed,0xb5,0xa0,0xf7,0xc6,0xb0,0x3e]}

tool: D17: 1000000

assistant: ```c
int checktick() {
  int i, minDelta, Delta;
  double t1, t2, timesfound[20];
  for (i = 0; i < 20; i++) {
    t1 = mysecond();
    while (((t2 = mysecond()) - t1) < 1.0E-6)
      ;
    timesfound[i] = t1 = t2;
  }
  minDelta = 1000000;
  for (i = 1; i < 20; i++) {
    Delta = (int)(1.0E6 * (timesfound[i] - timesfound[i - 1]));
    minDelta = ((minDelta) < (((Delta) > (0) ? (Delta) : (0))) ? (minDelta) : (((Delta) > (0) ? (Delta) : (0))));
  }
  return (minDelta);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xd0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x18,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  movl   $0x0,-0xdc(%rbp)
  movl   $0x0,-0xd8(%rbp)
  movl   $0x1,-0xd4(%rbp)
  mov    -0xd4(%rbp),%eax
  mov    %eax,-0xd0(%rbp)
  movl   $0x1,-0xe0(%rbp)
  jmp    L21
L85:
  movl   $0x0,-0xd8(%rbp)
  mov    -0xe0(%rbp),%eax
  mov    %eax,-0xdc(%rbp)
  jmp    L37
L66:
  addl   $0x1,-0xd4(%rbp)
  mov    -0xd8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xdc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  lea    (%rax,%rcx,1),%rdx
  mov    -0xd4(%rbp),%eax
  mov    %eax,-0xd0(%rbp,%rdx,4)
  addl   $0x1,-0xd8(%rbp)
  subl   $0x1,-0xdc(%rbp)
L37:
  cmpl   $0x0,-0xdc(%rbp)
  jns    L66
  addl   $0x1,-0xe0(%rbp)
L21:
  cmpl   $0x6,-0xe0(%rbp)
  jle    L85
  movl   $0x0,-0xdc(%rbp)
  jmp    L80
L108:
  movl   $0x0,-0xd8(%rbp)
  jmp    L14
L63:
  mov    -0xd8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xdc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  add    %rcx,%rax
  mov    -0xd0(%rbp,%rax,4),%eax
  test   %eax,%eax
  jle    L32
  mov    -0xd8(%rbp),%eax
  movslq %eax,%rcx
  mov    -0xdc(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x3,%rax
  sub    %rdx,%rax
  add    %rcx,%rax
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L25
L32:
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L25:
  addl   $0x1,-0xd8(%rbp)
L14:
  cmpl   $0x6,-0xd8(%rbp)
  jle    L63
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0xdc(%rbp)
L80:
  cmpl   $0x6,-0xdc(%rbp)
  jle    L108
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type: string
name: disassemble_data
arguments: data_tag: D8
type: string

tool: D2: %3d

tool: D8:   

assistant: ```c
int main() {
  int arr[7][7] = {0};
  int k, i = 0, j = 0;
  int count = 1;
  arr[0][0] = count;
  for (k = 1; k < 7; k++) {
    j = 0;
    for (i = k; i >= 0; i--) {
      arr[i][j] = ++count;
      j++;
    }
  }
  for (i = 0; i < 7; i++) {
    for (j = 0; j < 7; j++) {
      if (arr[i][j] > 0) {
        printf("%3d", arr[i][j]);
      } else
        printf("  ");
    }
    printf("\n");
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x18,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movl   $0x1,(%rsp)
  lea    0x1c(%rsp),%r8
  mov    $0x1,%edi
  mov    $0x1,%esi
L92:
  test   %esi,%esi
  js     L59
  lea    0x1(%rsi,%rdi,1),%ecx
  mov    %r8,%rdx
  mov    %edi,%eax
L94:
  add    $0x1,%eax
  mov    %eax,(%rdx)
  sub    $0x18,%rdx
  cmp    %ecx,%eax
  jne    L94
  lea    0x1(%rsi,%rdi,1),%edi
L59:
  add    $0x1,%esi
  add    $0x1c,%r8
  cmp    $0x7,%esi
  jne    L92
  mov    %rsp,%rbp
  lea    0xc4(%rsp),%r14
  lea    D8(%rip),%r13
  lea    D4(%rip),%r12
  jmp    L54
L68:
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L62:
  add    $0x1,%rbx
  cmp    $0x7,%rbx
  je     L42
L99:
  mov    0x0(%rbp,%rbx,4),%esi
  test   %esi,%esi
  jle    L68
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L62
L42:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1c,%rbp
  cmp    %r14,%rbp
  je     L74
L54:
  mov    $0x0,%ebx
  jmp    L99
L74:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0xd0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D8
datatype: string
name: unpack_data
arguments: data_tag: D4
datatype: string

tool: D8:   

tool: D4: %3d

assistant: ```c
int main() {
  int arr[7][7] = {0};
  int k, i = 0, j = 0;
  int count = 1;
  arr[0][0] = count;
  for (k = 1; k < 7; k++) {
    j = 0;
    for (i = k; i >= 0; i--) {
      arr[i][j] = ++count;
      j++;
    }
  }
  for (i = 0; i < 7; i++) {
    for (j = 0; j < 7; j++) {
      if (arr[i][j] > 0) {
        printf("%3d", arr[i][j]);
      } else
        printf("  ");
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  mov    $0x18,%ecx
  mov    $0x1,%esi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x1,(%rsp)
  mov    $0x1,%eax
  movl   $0x0,(%rdi)
  lea    0x1c(%rsp),%rdi
L57:
  lea    0x1(%rax),%r8d
  mov    %rdi,%rdx
  lea    (%r8,%rsi,1),%ecx
  nopl   0x0(%rax,%rax,1)
L77:
  add    $0x1,%eax
  sub    $0x18,%rdx
  mov    %eax,0x18(%rdx)
  cmp    %ecx,%eax
  jne    L77
  lea    (%r8,%rsi,1),%eax
  add    $0x1,%esi
  add    $0x1c,%rdi
  cmp    $0x7,%esi
  jne    L57
  lea    0xc4(%rsp),%r14
  lea    D11(%rip),%r13
  lea    D1(%rip),%r12
  nopl   0x0(%rax)
L6:
  xor    %ebx,%ebx
  jmp    L65
  nopl   0x0(%rax)
L75:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  je     L60
L65:
  mov    0x0(%rbp,%rbx,4),%esi
  test   %esi,%esi
  jg     L75
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x7,%rbx
  jne    L65
L60:
  mov    $0xa,%edi
  add    $0x1c,%rbp
  call   <putchar@plt>
  cmp    %r14,%rbp
  jne    L6
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L72
  add    $0xd0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L72:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type_guessed: string
name: disassemble_data
arguments: label: D1
type_guessed: string

tool: D11:   

tool: D1: %3d

assistant: ```c
int main() {
  int arr[7][7] = {0};
  int k, i = 0, j = 0;
  int count = 1;
  arr[0][0] = count;
  for (k = 1; k < 7; k++) {
    j = 0;
    for (i = k; i >= 0; i--) {
      arr[i][j] = ++count;
      j++;
    }
  }
  for (i = 0; i < 7; i++) {
    for (j = 0; j < 7; j++) {
      if (arr[i][j] > 0) {
        printf("%3d", arr[i][j]);
      } else
        printf("  ");
    }
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_Memrel>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void _Memrel(void *p) {
  assert(p != NULL);
  free(p);
}
```
user: What is the c source code of the assembly code below:

```asm
<_Memrel>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  ret
```

assistant: ```c
void _Memrel(void *p) {
  assert(p != NULL);
  free(p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_Memrel>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void _Memrel(void *p) {
  assert(p != NULL);
  free(p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_Memrel>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1060 <free@plt>
```

assistant: ```c
void _Memrel(void *p) {
  assert(p != NULL);
  free(p);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<slaDcc2s>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x34(%rbp)
  jmp    L23
L4:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x34(%rbp),%eax
  cltq
  movsd  %xmm0,-0x20(%rbp,%rax,8)
  addl   $0x1,-0x34(%rbp)
L23:
  cmpl   $0x2,-0x34(%rbp)
  jle    L4
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sla_dcc2s_@plt>
  movsd  -0x30(%rbp),%xmm0
  mov    -0x50(%rbp),%rax
  movsd  %xmm0,(%rax)
  movsd  -0x28(%rbp),%xmm0
  mov    -0x58(%rbp),%rax
  movsd  %xmm0,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
void slaDcc2s(double v[3], double *a, double *b) {
  double V[3];
  double A;
  double B;
  int i;
  for (i = 0; i < 3; i++)
    V[i] = v[i];
  sla_dcc2s_((double *)V, &A, &B);
  *a = A;
  *b = B;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<slaDcc2s>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movsd  (%rdi),%xmm0
  movsd  %xmm0,0x10(%rsp)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsp)
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x10(%rsp),%rdi
  call   <sla_dcc2s_@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaDcc2s(double v[3], double *a, double *b) {
  double V[3];
  double A;
  double B;
  int i;
  for (i = 0; i < 3; i++)
    V[i] = v[i];
  sla_dcc2s_((double *)V, &A, &B);
  *a = A;
  *b = B;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<slaDcc2s>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  movsd  (%rdi),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  movsd  %xmm0,0x10(%rsp)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x18(%rsp)
  movsd  0x10(%rdi),%xmm0
  lea    0x10(%rsp),%rdi
  movsd  %xmm0,0x20(%rsp)
  call   <sla_dcc2s_@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaDcc2s(double v[3], double *a, double *b) {
  double V[3];
  double A;
  double B;
  int i;
  for (i = 0; i < 3; i++)
    V[i] = v[i];
  sla_dcc2s_((double *)V, &A, &B);
  *a = A;
  *b = B;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<slaDcc2s>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x38,%rsp
  movsd  0x10(%rdi),%xmm0
  movupd (%rdi),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x10(%rsp),%rdi
  movsd  %xmm0,0x20(%rsp)
  movaps %xmm1,0x10(%rsp)
  call   <sla_dcc2s_@plt>
  movsd  (%rsp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  0x8(%rsp),%xmm0
  movsd  %xmm0,(%rbx)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void slaDcc2s(double v[3], double *a, double *b) {
  double V[3];
  double A;
  double B;
  int i;
  for (i = 0; i < 3; i++)
    V[i] = v[i];
  sla_dcc2s_((double *)V, &A, &B);
  *a = A;
  *b = B;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x8(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L62
L35:
  movl   $0x2,-0xc(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L72
L7:
  mov    -0x10(%rbp),%eax
  cltd
  idivl  -0xc(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L44
  movl   $0x0,-0x4(%rbp)
L44:
  addl   $0x1,-0xc(%rbp)
L72:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L7
  addl   $0x1,-0x10(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L62
  addl   $0x1,-0x8(%rbp)
L62:
  cmpl   $0x1387,-0x10(%rbp)
  jle    L35
  cmpl   $0x29d,-0x8(%rbp)
  je     L21
  mov    $0x1,%eax
  jmp    L77
L21:
  mov    $0x0,%eax
L77:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int n;
  int t;
  int c;
  int p;
  c = 0;
  n = 2;
  while (n < 5000) {
    t = 2;
    p = 1;
    while (t * t <= n) {
      if (n % t == 0)
        p = 0;
      t++;
    }
    n++;
    if (p)
      c++;
  }
  if (c != 669)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x3,%r9d
  mov    $0x2,%r8d
  mov    $0x0,%r10d
  jmp    L23
L18:
  add    $0x1,%r10d
L45:
  add    $0x1,%r8d
  add    $0x1,%r9d
  cmp    $0x1387,%eax
  jg     L57
L23:
  mov    %r8d,%esi
  mov    $0x1,%edi
  mov    $0x2,%ecx
  mov    %r9d,%eax
  cmp    $0x3,%r8d
  jle    L18
L56:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %edx,%edi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %esi,%eax
  jle    L56
  mov    %r9d,%eax
  test   %edi,%edi
  je     L45
  jmp    L18
L57:
  cmp    $0x29d,%r10d
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  int n;
  int t;
  int c;
  int p;
  c = 0;
  n = 2;
  while (n < 5000) {
    t = 2;
    p = 1;
    while (t * t <= n) {
      if (n % t == 0)
        p = 0;
      t++;
    }
    n++;
    if (p)
      c++;
  }
  if (c != 669)
    return 1;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  mov    $0x2,%esi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nop
L5:
  mov    $0x1,%edi
  mov    $0x2,%ecx
  cmp    $0x3,%esi
  jbe    L13
  nop
L27:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %r8d,%edi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %esi,%eax
  jle    L27
  test   %edi,%edi
  jne    L13
L23:
  add    $0x1,%esi
  cmp    $0x1388,%esi
  jne    L5
  xor    %eax,%eax
  cmp    $0x29d,%r9d
  setne  %al
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r9d
  jmp    L23
```

assistant: ```c
int main() {
  int n;
  int t;
  int c;
  int p;
  c = 0;
  n = 2;
  while (n < 5000) {
    t = 2;
    p = 1;
    while (t * t <= n) {
      if (n % t == 0)
        p = 0;
      t++;
    }
    n++;
    if (p)
      c++;
  }
  if (c != 669)
    return 1;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  mov    $0x2,%esi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  nop
L45:
  mov    $0x1,%edi
  mov    $0x2,%ecx
  cmp    $0x3,%esi
  jbe    L13
  nop
L18:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %r8d,%edi
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %eax,%esi
  jge    L18
  test   %edi,%edi
  jne    L13
L1:
  add    $0x1,%esi
  cmp    $0x1388,%esi
  jne    L45
  xor    %eax,%eax
  cmp    $0x29d,%r9d
  setne  %al
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r9d
  jmp    L1
```

assistant: ```c
int main() {
  int n;
  int t;
  int c;
  int p;
  c = 0;
  n = 2;
  while (n < 5000) {
    t = 2;
    p = 1;
    while (t * t <= n) {
      if (n % t == 0)
        p = 0;
      t++;
    }
    n++;
    if (p)
      c++;
  }
  if (c != 669)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <testcq@plt>
  mov    $0x0,%eax
  call   <testlnv@plt>
  mov    $0x0,%eax
  call   <testcqp2@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  testcq();
  testlnv();
  testcqp2();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testcq@plt>
  mov    $0x0,%eax
  call   <testlnv@plt>
  mov    $0x0,%eax
  call   <testcqp2@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testcq();
  testlnv();
  testcqp2();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testcq@plt>
  xor    %eax,%eax
  call   <testlnv@plt>
  xor    %eax,%eax
  call   <testcqp2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testcq();
  testlnv();
  testcqp2();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testcq@plt>
  xor    %eax,%eax
  call   <testlnv@plt>
  xor    %eax,%eax
  call   <testcqp2@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  testcq();
  testlnv();
  testcqp2();
  return 0;
}
```