ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cdeque_dump_str_cb>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L5
  mov    %rsi,%rdi
  mov    %rsi,%r12
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %r12,%r8
  mov    %r12,%rdx
  mov    %eax,%ecx
  mov    %rbp,%rdi
  lea    D15(%rip),%rsi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1070 <fprintf@plt>
  xchg   %ax,%ax
L5:
  add    $0x8,%rsp
  xor    %edx,%edx
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1070 <fprintf@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string

tool: D15: %p = [len: %d] "%s"


tool: D1: %p = NULL


assistant: ```c
int cdeque_dump_str_cb(FILE *o, void *data) {
  if (data != (void *)NULL) {
    return fprintf(o, "%p = [len: %d] \"%s\"\n", data, (int)strlen((char *)data), (char *)data);
  } else {
    return fprintf(o, "%p = NULL\n", data);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<left_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    0x10(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm3
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm2
  mulsd  %xmm3,%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  mov    0x18(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm3
  mov    -0x40(%rbp),%rax
  movsd  (%rax),%xmm1
  mulsd  %xmm3,%xmm1
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm4
  mov    -0x28(%rbp),%rax
  movsd  (%rax),%xmm3
  mulsd  %xmm4,%xmm3
  subsd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  mov    0x20(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm3
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm3,%xmm0
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm4
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm3
  mulsd  %xmm4,%xmm3
  subsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  setae  %al
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int left_(double *x1, double *y11, double *z1, double *x2, double *y2, double *z2, double *x0, double *y00, double *z0) {
  int ret_val;
  ret_val = *x0 * (*y11 * *z2 - *y2 * *z1) - *y00 * (*x1 * *z2 - *x2 * *z1) + *z0 * (*x1 * *y2 - *x2 * *y11) >= 0.;
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<left_>:
  endbr64
  movsd  (%rsi),%xmm3
  movsd  (%r9),%xmm2
  movsd  (%r8),%xmm1
  movsd  (%rdx),%xmm4
  movsd  (%rdi),%xmm6
  movsd  (%rcx),%xmm5
  movapd %xmm3,%xmm0
  mulsd  %xmm2,%xmm0
  movapd %xmm1,%xmm7
  mulsd  %xmm4,%xmm7
  subsd  %xmm7,%xmm0
  mov    0x8(%rsp),%rax
  mulsd  (%rax),%xmm0
  mulsd  %xmm6,%xmm2
  mulsd  %xmm5,%xmm4
  subsd  %xmm4,%xmm2
  mov    0x10(%rsp),%rax
  mulsd  (%rax),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm3,%xmm1
  mov    0x18(%rsp),%rax
  mulsd  (%rax),%xmm1
  addsd  %xmm1,%xmm0
  comisd D3(%rip),%xmm0
  setae  %al
  movzbl %al,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: f64

tool: D3: 0

assistant: ```c
int left_(double *x1, double *y11, double *z1, double *x2, double *y2, double *z2, double *x0, double *y00, double *z0) {
  int ret_val;
  ret_val = *x0 * (*y11 * *z2 - *y2 * *z1) - *y00 * (*x1 * *z2 - *x2 * *z1) + *z0 * (*x1 * *y2 - *x2 * *y11) >= 0.;
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<left_>:
  endbr64
  movsd  (%rsi),%xmm3
  movsd  (%r8),%xmm1
  movsd  (%r9),%xmm2
  movsd  (%rdx),%xmm4
  movapd %xmm3,%xmm0
  movapd %xmm1,%xmm7
  movsd  (%rdi),%xmm6
  movsd  (%rcx),%xmm5
  mulsd  %xmm4,%xmm7
  mov    0x8(%rsp),%rax
  mulsd  %xmm2,%xmm0
  mulsd  %xmm5,%xmm4
  mulsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm7,%xmm0
  mulsd  (%rax),%xmm0
  mov    0x10(%rsp),%rax
  subsd  %xmm4,%xmm2
  mulsd  (%rax),%xmm2
  mov    0x18(%rsp),%rax
  subsd  %xmm3,%xmm1
  mulsd  (%rax),%xmm1
  xor    %eax,%eax
  subsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  comisd D6(%rip),%xmm0
  setae  %al
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type_guessed: f64

tool: D6: 0

assistant: ```c
int left_(double *x1, double *y11, double *z1, double *x2, double *y2, double *z2, double *x0, double *y00, double *z0) {
  int ret_val;
  ret_val = *x0 * (*y11 * *z2 - *y2 * *z1) - *y00 * (*x1 * *z2 - *x2 * *z1) + *z0 * (*x1 * *y2 - *x2 * *y11) >= 0.;
  return ret_val;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<left_>:
  endbr64
  movsd  (%rsi),%xmm3
  movsd  (%r8),%xmm1
  movsd  (%r9),%xmm2
  movsd  (%rdx),%xmm4
  movapd %xmm3,%xmm0
  movapd %xmm1,%xmm7
  movsd  (%rdi),%xmm6
  movsd  (%rcx),%xmm5
  mulsd  %xmm4,%xmm7
  mov    0x8(%rsp),%rax
  mulsd  %xmm2,%xmm0
  mulsd  %xmm5,%xmm4
  mulsd  %xmm6,%xmm2
  mulsd  %xmm6,%xmm1
  mulsd  %xmm5,%xmm3
  subsd  %xmm7,%xmm0
  mulsd  (%rax),%xmm0
  mov    0x10(%rsp),%rax
  subsd  %xmm4,%xmm2
  mulsd  (%rax),%xmm2
  mov    0x18(%rsp),%rax
  subsd  %xmm3,%xmm1
  mulsd  (%rax),%xmm1
  xor    %eax,%eax
  subsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  comisd D6(%rip),%xmm0
  setae  %al
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
datatype: f64

tool: D6: 0

assistant: ```c
int left_(double *x1, double *y11, double *z1, double *x2, double *y2, double *z2, double *x0, double *y00, double *z0) {
  int ret_val;
  ret_val = *x0 * (*y11 * *z2 - *y2 * *z1) - *y00 * (*x1 * *z2 - *x2 * *z1) + *z0 * (*x1 * *y2 - *x2 * *y11) >= 0.;
  return ret_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bn_div_words>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  divq   -0x28(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long bn_div_words(unsigned long h, unsigned long l, unsigned long d) {
  unsigned long ret, waste;
  asm("divq	%4" : "=a"(ret), "=d"(waste) : "a"(l), "d"(h), "g"(d) : "cc");
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bn_div_words>:
  endbr64
  mov    %rdx,%rcx
  mov    %rsi,%rax
  mov    %rdi,%rdx
  div    %rcx
  ret
```

assistant: ```c
unsigned long bn_div_words(unsigned long h, unsigned long l, unsigned long d) {
  unsigned long ret, waste;
  asm("divq	%4" : "=a"(ret), "=d"(waste) : "a"(l), "d"(h), "g"(d) : "cc");
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bn_div_words>:
  endbr64
  mov    %rdx,%r8
  mov    %rsi,%rax
  mov    %rdi,%rdx
  div    %r8
  ret
```

assistant: ```c
unsigned long bn_div_words(unsigned long h, unsigned long l, unsigned long d) {
  unsigned long ret, waste;
  asm("divq	%4" : "=a"(ret), "=d"(waste) : "a"(l), "d"(h), "g"(d) : "cc");
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bn_div_words>:
  endbr64
  mov    %rdx,%r8
  mov    %rsi,%rax
  mov    %rdi,%rdx
  div    %r8
  ret
```

assistant: ```c
unsigned long bn_div_words(unsigned long h, unsigned long l, unsigned long d) {
  unsigned long ret, waste;
  asm("divq	%4" : "=a"(ret), "=d"(waste) : "a"(l), "d"(h), "g"(d) : "cc");
  return ret;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x20,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  jne    L12
  movl   $0x5,-0x8(%rbp)
  jmp    L6
L12:
  movl   $0x7,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i = 32;
  int j;
  if (i == 32) {
    j = 5;
  } else {
    j = 7;
  }
  return j;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int i = 32;
  int j;
  if (i == 32) {
    j = 5;
  } else {
    j = 7;
  }
  return j;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int i = 32;
  int j;
  if (i == 32) {
    j = 5;
  } else {
    j = 7;
  }
  return j;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<Sfile_leafname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <Sfile_count_components@plt>
  mov    %eax,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jne    L36
  mov    $0x0,%eax
  jmp    L20
L36:
  mov    -0x18(%rbp),%eax
  lea    -0x1(%rax),%edx
  lea    -0x10(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    $0x0,%ecx
  mov    %rax,%rdi
  call   <Sfile_component_pointer@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L4
  mov    -0x14(%rbp),%eax
  jmp    L20
L4:
  mov    -0x10(%rbp),%rcx
  mov    -0x30(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <Sfile_str@plt>
  test   %rax,%rax
  jg     L32
  mov    $0x0,%eax
  jmp    L20
L32:
  mov    -0x30(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  test   %rax,%rax
  je     L13
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
L13:
  mov    $0x1,%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

assistant: ```c
int Sfile_leafname(char *path, char leafname[4096], int flag) {
  int count, ret;
  char *lpt;
  leafname[0] = 0;
  count = Sfile_count_components(path, 0);
  if (count == 0)
    return (0);
  ret = Sfile_component_pointer(path, &lpt, count - 1, 0);
  if (ret <= 0)
    return (ret);
  if (Sfile_str(leafname, lpt, 0) <= 0)
    return (0);
  lpt = strchr(leafname, '/');
  if (lpt != NULL)
    *lpt = 0;
  return (1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Sfile_leafname>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsi)
  mov    $0x0,%esi
  call   <Sfile_count_components@plt>
  test   %eax,%eax
  jne    L43
L53:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L34
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  lea    -0x1(%rax),%edx
  mov    %rsp,%rsi
  mov    $0x0,%ecx
  mov    %rbx,%rdi
  call   <Sfile_component_pointer@plt>
  test   %eax,%eax
  jle    L53
  mov    $0x0,%edx
  mov    (%rsp),%rsi
  mov    %rbp,%rdi
  call   <Sfile_str@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jle    L53
  mov    $0x2f,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L53
  movb   $0x0,(%rdx)
  jmp    L53
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Sfile_leafname(char *path, char leafname[4096], int flag) {
  int count, ret;
  char *lpt;
  leafname[0] = 0;
  count = Sfile_count_components(path, 0);
  if (count == 0)
    return (0);
  ret = Sfile_component_pointer(path, &lpt, count - 1, 0);
  if (ret <= 0)
    return (ret);
  if (Sfile_str(leafname, lpt, 0) <= 0)
    return (0);
  lpt = strchr(leafname, '/');
  if (lpt != NULL)
    *lpt = 0;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Sfile_leafname>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsi)
  xor    %esi,%esi
  call   <Sfile_count_components@plt>
  test   %eax,%eax
  jne    L23
L33:
  xor    %eax,%eax
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L59
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L23:
  xor    %ecx,%ecx
  lea    -0x1(%rax),%edx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <Sfile_component_pointer@plt>
  test   %eax,%eax
  jle    L13
  mov    (%rsp),%rsi
  xor    %edx,%edx
  mov    %r12,%rdi
  call   <Sfile_str@plt>
  test   %rax,%rax
  jle    L33
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L13
  movb   $0x0,(%rdx)
  jmp    L13
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Sfile_leafname(char *path, char leafname[4096], int flag) {
  int count, ret;
  char *lpt;
  leafname[0] = 0;
  count = Sfile_count_components(path, 0);
  if (count == 0)
    return (0);
  ret = Sfile_component_pointer(path, &lpt, count - 1, 0);
  if (ret <= 0)
    return (ret);
  if (Sfile_str(leafname, lpt, 0) <= 0)
    return (0);
  lpt = strchr(leafname, '/');
  if (lpt != NULL)
    *lpt = 0;
  return (1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<Sfile_leafname>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rsi)
  xor    %esi,%esi
  call   <Sfile_count_components@plt>
  test   %eax,%eax
  jne    L46
L23:
  xor    %eax,%eax
L17:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L40
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L46:
  xor    %ecx,%ecx
  lea    -0x1(%rax),%edx
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <Sfile_component_pointer@plt>
  test   %eax,%eax
  jle    L17
  mov    (%rsp),%rsi
  xor    %edx,%edx
  mov    %r12,%rdi
  call   <Sfile_str@plt>
  test   %rax,%rax
  jle    L23
  mov    $0x2f,%esi
  mov    %r12,%rdi
  call   <strchr@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L17
  movb   $0x0,(%rdx)
  jmp    L17
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Sfile_leafname(char *path, char leafname[4096], int flag) {
  int count, ret;
  char *lpt;
  leafname[0] = 0;
  count = Sfile_count_components(path, 0);
  if (count == 0)
    return (0);
  ret = Sfile_component_pointer(path, &lpt, count - 1, 0);
  if (ret <= 0)
    return (ret);
  if (Sfile_str(leafname, lpt, 0) <= 0)
    return (0);
  lpt = strchr(leafname, '/');
  if (lpt != NULL)
    *lpt = 0;
  return (1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Z>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  jmp    L3
L7:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  add    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
L3:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L7
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int Z(int N) {
  int i = 0, j;
  for (j = 5; j <= N; j *= 5) {
    i += N / j;
  }
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Z>:
  endbr64
  cmp    $0x4,%edi
  jle    L22
  mov    $0x5,%ecx
  mov    $0x0,%esi
L28:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  add    %eax,%esi
  lea    (%rcx,%rcx,4),%eax
  mov    %eax,%ecx
  cmp    %eax,%edi
  jge    L28
L26:
  mov    %esi,%eax
  ret
L22:
  mov    $0x0,%esi
  jmp    L26
```

assistant: ```c
int Z(int N) {
  int i = 0, j;
  for (j = 5; j <= N; j *= 5) {
    i += N / j;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Z>:
  endbr64
  cmp    $0x4,%edi
  jle    L6
  mov    $0x5,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L12:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %eax,%r8d
  cmp    %ecx,%edi
  jge    L12
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Z(int N) {
  int i = 0, j;
  for (j = 5; j <= N; j *= 5) {
    i += N / j;
  }
  return i;
}
```
user: What is the c source code of the assembly code below?

```asm
<Z>:
  endbr64
  cmp    $0x4,%edi
  jle    L6
  mov    $0x5,%ecx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  lea    (%rcx,%rcx,4),%ecx
  add    %eax,%r8d
  cmp    %ecx,%edi
  jge    L4
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Z(int N) {
  int i = 0, j;
  for (j = 5; j <= N; j *= 5) {
    i += N / j;
  }
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sys$readef>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    -0x14(%rbp),%eax
  mov    %rax,%rdi
  mov    $0x19,%rax
  int    $0x81
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int sys$readef(unsigned int efn, unsigned int *state) {
  return ({
    unsigned long resultvar;
    register long int _a2 asm("rsi") = (long)(state);
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(25), "r"(_a1), "r"(_a2)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What is the c source code of the assembly code below?

```asm
<sys$readef>:
  endbr64
  mov    %edi,%edi
  mov    $0x19,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$readef(unsigned int efn, unsigned int *state) {
  return ({
    unsigned long resultvar;
    register long int _a2 asm("rsi") = (long)(state);
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(25), "r"(_a1), "r"(_a2)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sys$readef>:
  endbr64
  mov    %edi,%edi
  mov    $0x19,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$readef(unsigned int efn, unsigned int *state) {
  return ({
    unsigned long resultvar;
    register long int _a2 asm("rsi") = (long)(state);
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(25), "r"(_a1), "r"(_a2)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sys$readef>:
  endbr64
  mov    %edi,%edi
  mov    $0x19,%rax
  int    $0x81
  ret
```

assistant: ```c
int sys$readef(unsigned int efn, unsigned int *state) {
  return ({
    unsigned long resultvar;
    register long int _a2 asm("rsi") = (long)(state);
    register long int _a1 asm("rdi") = (long)(efn);
    asm volatile("movq %1, %%rax\n\t"
                 "int $0x81\n\t"
                 : "=a"(resultvar)
                 : "i"(25), "r"(_a1), "r"(_a2)
                 : "memory", "cc", "r11", "cx");
    (long)resultvar;
  });
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_path_substr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L73
L23:
  subq   $0x1,-0x8(%rbp)
L73:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L59
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L23
L59:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L51
  subq   $0x1,-0x8(%rbp)
  jmp    L51
L78:
  subq   $0x1,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L80
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L78
L80:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L32
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L32
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char *get_path_substr(const char *path) {
  const char *result;
  result = path + strlen(path) - 1;
  while (result > path && *result != '/')
    result--;
  if (result > path)
    result--;
  while (result >= path && *result != '/')
    result--;
  if (result > path && *result == '/')
    result++;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_path_substr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jae    L84
L25:
  cmpb   $0x2f,(%rax)
  je     L121
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jne    L25
  mov    %rbx,%rax
  jmp    L60
L121:
  cmp    %rax,%rbx
  jae    L15
  sub    $0x1,%rax
L84:
  cmp    %rax,%rbx
  ja     L4
L60:
  cmpb   $0x2f,(%rax)
  je     L21
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L60
L4:
  cmp    %rax,%rbx
  jae    L52
  cmpb   $0x2f,(%rax)
  je     L8
L52:
  pop    %rbx
  ret
L21:
  cmp    %rax,%rbx
  jae    L52
L8:
  add    $0x1,%rax
  jmp    L52
L15:
  jbe    L52
  jmp    L4
```

assistant: ```c
const char *get_path_substr(const char *path) {
  const char *result;
  result = path + strlen(path) - 1;
  while (result > path && *result != '/')
    result--;
  if (result > path)
    result--;
  while (result >= path && *result != '/')
    result--;
  if (result > path && *result == '/')
    result++;
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<get_path_substr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jb     L10
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L82:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L18
L10:
  cmpb   $0x2f,(%rax)
  jne    L82
  cmp    %rax,%rbx
  jb     L45
L34:
  ja     L80
  nopl   (%rax)
L18:
  cmpb   $0x2f,(%rax)
  je     L49
L45:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L18
  jmp    L80
  nopl   0x0(%rax,%rax,1)
L49:
  cmp    %rax,%rbx
  adc    $0x0,%rax
L80:
  pop    %rbx
  ret
```

assistant: ```c
const char *get_path_substr(const char *path) {
  const char *result;
  result = path + strlen(path) - 1;
  while (result > path && *result != '/')
    result--;
  if (result > path)
    result--;
  while (result >= path && *result != '/')
    result--;
  if (result > path && *result == '/')
    result++;
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_path_substr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  cltq
  lea    -0x1(%rbx,%rax,1),%rax
  cmp    %rax,%rbx
  jb     L6
  jmp    L32
  nopl   0x0(%rax,%rax,1)
L23:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  je     L51
L6:
  cmpb   $0x2f,(%rax)
  jne    L23
  cmp    %rax,%rbx
  jb     L17
L32:
  ja     L37
  nopl   (%rax)
L51:
  cmpb   $0x2f,(%rax)
  je     L26
L17:
  sub    $0x1,%rax
  cmp    %rax,%rbx
  jbe    L51
  jmp    L37
  nopl   0x0(%rax,%rax,1)
L26:
  cmp    %rax,%rbx
  adc    $0x0,%rax
L37:
  pop    %rbx
  ret
```

assistant: ```c
const char *get_path_substr(const char *path) {
  const char *result;
  result = path + strlen(path) - 1;
  while (result > path && *result != '/')
    result--;
  if (result > path)
    result--;
  while (result >= path && *result != '/')
    result--;
  if (result > path && *result == '/')
    result++;
  return result;
}
```