ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D14(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L115
  lea    0x10(%rsp),%rbx
  lea    D13(%rip),%r12
  lea    D29(%rip),%rbp
  lea    D37(%rip),%r13
  nopl   0x0(%rax,%rax,1)
L16:
  mov    %r12,%rdi
  xor    %eax,%eax
  mov    %rbx,%rsi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  js     L95
  cltq
  mov    %rbx,%rdx
  xor    %esi,%esi
  lea    0x11(%rsp,%rax,1),%rcx
  nopl   0x0(%rax)
L0:
  movzbl (%rdx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L12
  movzbl %al,%eax
  movslq 0x0(%r13,%rax,4),%rax
  add    %r13,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  add    $0x5,%esi
L12:
  add    $0x1,%rdx
  cmp    %rcx,%rdx
  jne    L0
L9:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  jg     L16
L115:
  mov    0x78(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x88,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
  add    $0x6,%esi
  jmp    L12
  nopl   (%rax)
  add    $0x7,%esi
  jmp    L12
  nopl   (%rax)
  add    $0x2,%esi
  jmp    L12
  nopl   (%rax)
  add    $0x3,%esi
  jmp    L12
  nopl   (%rax)
  add    $0x4,%esi
  jmp    L12
  nopl   (%rax)
L95:
  xor    %esi,%esi
  jmp    L9
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D13
type_infered: string
name: unpack_data
arguments: data_label: D29
type_infered: string

tool: D14:  %d

tool: D13:  %s

tool: D29: %d leds


assistant: ```c
int main() {
  char V[100];
  int i, N, tam, j, qtd_l = 0;
  scanf(" %d", &N);
  while (N > 0) {
    scanf(" %s", V);
    qtd_l = 0;
    tam = strlen(V);
    j = 0;
    while (j <= tam) {
      switch (V[j]) {
      case '0':
        qtd_l += 6;
        break;
      case '1':
        qtd_l += 2;
        break;
      case '2':
        qtd_l += 5;
        break;
      case '3':
        qtd_l += 5;
        break;
      case '4':
        qtd_l += 4;
        break;
      case '5':
        qtd_l += 5;
        break;
      case '6':
        qtd_l += 6;
        break;
      case '7':
        qtd_l += 3;
        break;
      case '8':
        qtd_l += 7;
        break;
      case '9':
        qtd_l += 6;
        break;
      }
      j++;
    }
    printf("%d leds\n", qtd_l);
    N--;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_conditional_literal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  jne    L19
  lea    D51(%rip),%rax
  jmp    L28
L19:
  lea    D3(%rip),%rax
L28:
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L21
  cmpl   $0x1,-0xc(%rbp)
  jne    L26
  lea    D51(%rip),%rax
  jmp    L6
L26:
  lea    D3(%rip),%rax
  jmp    L6
L21:
  lea    D52(%rip),%rax
L6:
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x0,-0xc(%rbp)
  jne    L92
  cmpl   $0x1,-0xc(%rbp)
  jne    L69
  mov    -0x8(%rbp),%rax
  jmp    L20
L69:
  lea    D3(%rip),%rax
  jmp    L20
L92:
  lea    D52(%rip),%rax
L20:
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D51
type: string
name: read_data
arguments: label: D3
type: string
name: read_data
arguments: label: D52
type: string

tool: D51: yes

tool: D3: no

tool: D52: dont know

assistant: ```c
void check_conditional_literal(const char *s, int i) {
  printf(i == 1 ? "yes" : "no");
  printf(i == 0 ? (i == 1 ? "yes" : "no") : "dont know");
  printf(i == 0 ? (i == 1 ? s : "no") : "dont know");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<check_conditional_literal>:
  endbr64
  push   %rbx
  cmp    $0x1,%esi
  je     L21
  mov    %esi,%ebx
  lea    D33(%rip),%rdi
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L4
  lea    D33(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
L25:
  call   <printf@plt>
  pop    %rbx
  ret
L21:
  lea    D25(%rip),%rdi
  call   <printf@plt>
L4:
  lea    D6(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  jmp    L25
```

tool_calls: name: retrieve_data
arguments: data_label: D33
datatype: string
name: retrieve_data
arguments: data_label: D25
datatype: string
name: retrieve_data
arguments: data_label: D6
datatype: string

tool: D33: no

tool: D25: yes

tool: D6: dont know

assistant: ```c
void check_conditional_literal(const char *s, int i) {
  printf(i == 1 ? "yes" : "no");
  printf(i == 0 ? (i == 1 ? "yes" : "no") : "dont know");
  printf(i == 0 ? (i == 1 ? s : "no") : "dont know");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<check_conditional_literal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L13
  lea    D23(%rip),%rbx
  mov    %esi,%ebp
  mov    %rbx,%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jne    L29
L3:
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbx,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  lea    D14(%rip),%rdi
  call   <printf@plt>
L29:
  lea    D24(%rip),%rbx
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: label: D23
type_infered: string
name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D24
type_infered: string

tool: D23: no

tool: D14: yes

tool: D24: dont know

assistant: ```c
void check_conditional_literal(const char *s, int i) {
  printf(i == 1 ? "yes" : "no");
  printf(i == 0 ? (i == 1 ? "yes" : "no") : "dont know");
  printf(i == 0 ? (i == 1 ? s : "no") : "dont know");
}
```
user: Translate the below assembly code into C programming language:

```asm
<check_conditional_literal>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  je     L23
  lea    D24(%rip),%rbx
  mov    %esi,%ebp
  mov    %rbx,%rdi
  call   <printf@plt>
  test   %ebp,%ebp
  jne    L24
L21:
  mov    %rbx,%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbx,%rdi
  pop    %rbx
  pop    %rbp
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L23:
  lea    D10(%rip),%rdi
  call   <printf@plt>
L24:
  lea    D14(%rip),%rbx
  jmp    L21
```

tool_calls: name: read_data
arguments: label: D24
datatype: string
name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D14
datatype: string

tool: D24: no

tool: D10: yes

tool: D14: dont know

assistant: ```c
void check_conditional_literal(const char *s, int i) {
  printf(i == 1 ? "yes" : "no");
  printf(i == 0 ? (i == 1 ? "yes" : "no") : "dont know");
  printf(i == 0 ? (i == 1 ? s : "no") : "dont know");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0xc(%rbp)
  jmp    L12
L140:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L154
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L154:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L17
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L17:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L72
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L72
  lea    D50(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L72:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L30
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jle    L30
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L64
L30:
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L64
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jns    L64
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L64:
  addl   $0x1,-0xc(%rbp)
L12:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L140
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L56
  call   <__stack_chk_fail@plt>
L56:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D32
type: string
name: parse_data
arguments: data_tag: D10
type: string
name: parse_data
arguments: data_tag: D46
type: string
name: parse_data
arguments: data_tag: D50
type: string
name: parse_data
arguments: data_tag: D8
type: string
name: parse_data
arguments: data_tag: D53
type: string

tool: D32: %d

tool: D10: NULL


tool: D46: EVEN POSITIVE


tool: D50: EVEN NEGATIVE


tool: D8: ODD POSITIVE


tool: D53: ODD NEGATIVE


assistant: ```c
int main(void) {
  int valor, i, n;
  scanf("%d", &valor);
  for (i = 1; i <= valor; i++) {
    scanf("%d", &n);
    if (n == 0) {
      printf("NULL\n");
    } else if (n % 2 == 0 && n > 0) {
      printf("EVEN POSITIVE\n");
    } else if (n % 2 == 0 && n < 0) {
      printf("EVEN NEGATIVE\n");
    } else if (n % 2 != 0 && n > 0) {
      printf("ODD POSITIVE\n");
    } else if (n % 2 != 0 && n < 0) {
      printf("ODD NEGATIVE\n");
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L17
  mov    $0x1,%ebx
  lea    D34(%rip),%rbp
  lea    D13(%rip),%r14
  lea    D62(%rip),%r12
  lea    D64(%rip),%r13
  jmp    L82
L44:
  lea    D38(%rip),%rdi
  call   <printf@plt>
L50:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L17
L82:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L44
  setg   %cl
  mov    %eax,%edx
  and    $0x1,%edx
  sete   %sil
  test   %cl,%cl
  je     L142
  test   %sil,%sil
  jne    L87
L142:
  shr    $0x1f,%eax
  test   %sil,%sil
  je     L98
  test   %al,%al
  jne    L156
L98:
  test   %cl,%cl
  je     L158
  test   %dl,%dl
  jne    L160
L158:
  test   %al,%al
  je     L50
  test   %dl,%dl
  je     L50
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L50
L87:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L50
L156:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L50
L160:
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L50
L17:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L75
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L75:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D34
type_guessed: string
name: read_data
arguments: label: D13
type_guessed: string
name: read_data
arguments: label: D62
type_guessed: string
name: read_data
arguments: label: D64
type_guessed: string
name: read_data
arguments: label: D38
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string

tool: D34: %d

tool: D13: ODD NEGATIVE


tool: D62: ODD POSITIVE


tool: D64: EVEN NEGATIVE


tool: D38: NULL


tool: D26: EVEN POSITIVE


assistant: ```c
int main(void) {
  int valor, i, n;
  scanf("%d", &valor);
  for (i = 1; i <= valor; i++) {
    scanf("%d", &n);
    if (n == 0) {
      printf("NULL\n");
    } else if (n % 2 == 0 && n > 0) {
      printf("EVEN POSITIVE\n");
    } else if (n % 2 == 0 && n < 0) {
      printf("EVEN NEGATIVE\n");
    } else if (n % 2 != 0 && n > 0) {
      printf("ODD POSITIVE\n");
    } else if (n % 2 != 0 && n < 0) {
      printf("ODD NEGATIVE\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L88
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r12
  lea    D22(%rip),%r14
  lea    D55(%rip),%r15
  lea    D19(%rip),%r13
  jmp    L48
L86:
  test   %eax,%eax
  jg     L25
  lea    D48(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L84:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L88
L48:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L64
  test   $0x1,%al
  jne    L86
  test   %eax,%eax
  jg     L11
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L84
  nopl   (%rax)
L64:
  lea    D0(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L48
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L111
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L11:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L25:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L84
L111:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string
name: read_data
arguments: data_tag: D55
type_guessed: string
name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D48
type_guessed: string
name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D7: %d

tool: D22: ODD POSITIVE


tool: D55: EVEN NEGATIVE


tool: D19: EVEN POSITIVE


tool: D48: ODD NEGATIVE


tool: D0: NULL


assistant: ```c
int main(void) {
  int valor, i, n;
  scanf("%d", &valor);
  for (i = 1; i <= valor; i++) {
    scanf("%d", &n);
    if (n == 0) {
      printf("NULL\n");
    } else if (n % 2 == 0 && n > 0) {
      printf("EVEN POSITIVE\n");
    } else if (n % 2 == 0 && n < 0) {
      printf("EVEN NEGATIVE\n");
    } else if (n % 2 != 0 && n > 0) {
      printf("ODD POSITIVE\n");
    } else if (n % 2 != 0 && n < 0) {
      printf("ODD NEGATIVE\n");
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D45(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L50
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r12
  lea    D6(%rip),%r14
  lea    D17(%rip),%r15
  lea    D7(%rip),%r13
  jmp    L103
L63:
  test   %eax,%eax
  jg     L27
  lea    D18(%rip),%rdi
  call   <printf@plt>
  nopl   0x0(%rax)
L6:
  add    $0x1,%ebx
  cmp    %ebx,(%rsp)
  jl     L50
L103:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  je     L73
  test   $0x1,%al
  jne    L63
  test   %eax,%eax
  jg     L56
  mov    %r15,%rdi
  call   <printf@plt>
  jmp    L6
  nopl   (%rax)
L73:
  lea    D21(%rip),%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,(%rsp)
  jge    L103
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L56:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L6
  nopw   0x0(%rax,%rax,1)
L27:
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L6
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D45
type: string
name: parse_data
arguments: data_label: D6
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D18
type: string
name: parse_data
arguments: data_label: D21
type: string

tool: D45: %d

tool: D6: ODD POSITIVE


tool: D17: EVEN NEGATIVE


tool: D7: EVEN POSITIVE


tool: D18: ODD NEGATIVE


tool: D21: NULL


assistant: ```c
int main(void) {
  int valor, i, n;
  scanf("%d", &valor);
  for (i = 1; i <= valor; i++) {
    scanf("%d", &n);
    if (n == 0) {
      printf("NULL\n");
    } else if (n % 2 == 0 && n > 0) {
      printf("EVEN POSITIVE\n");
    } else if (n % 2 == 0 && n < 0) {
      printf("EVEN NEGATIVE\n");
    } else if (n % 2 != 0 && n > 0) {
      printf("ODD POSITIVE\n");
    } else if (n % 2 != 0 && n < 0) {
      printf("ODD NEGATIVE\n");
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<digit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L70
  cmpl   $0x39,-0x4(%rbp)
  jg     L70
  subl   $0x30,-0x4(%rbp)
  jmp    L25
L70:
  cmpl   $0x60,-0x4(%rbp)
  jle    L61
  cmpl   $0x66,-0x4(%rbp)
  jg     L61
  subl   $0x57,-0x4(%rbp)
  jmp    L25
L61:
  cmpl   $0x40,-0x4(%rbp)
  jle    L29
  cmpl   $0x46,-0x4(%rbp)
  jg     L29
  subl   $0x37,-0x4(%rbp)
  jmp    L25
L29:
  movl   $0xffffffff,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int digit(int i) {
  if ('0' <= i && i <= '9')
    i -= '0';
  else if ('a' <= i && i <= 'f')
    i -= 'a' - 10;
  else if ('A' <= i && i <= 'F')
    i -= 'A' - 10;
  else
    i = -1;
  return i;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L12
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%eax
  ja     L4
  lea    -0x57(%rdi),%eax
  ret
L4:
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%eax
  ja     L22
  lea    -0x37(%rdi),%eax
  ret
L22:
  mov    $0xffffffff,%eax
L12:
  ret
```

assistant: ```c
int digit(int i) {
  if ('0' <= i && i <= '9')
    i -= '0';
  else if ('a' <= i && i <= 'f')
    i -= 'a' - 10;
  else if ('A' <= i && i <= 'F')
    i -= 'A' - 10;
  else
    i = -1;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L25
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%eax
  jbe    L20
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%eax
  ja     L2
  lea    -0x37(%rdi),%eax
  ret
L2:
  mov    $0xffffffff,%eax
L25:
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int digit(int i) {
  if ('0' <= i && i <= '9')
    i -= '0';
  else if ('a' <= i && i <= 'f')
    i -= 'a' - 10;
  else if ('A' <= i && i <= 'F')
    i -= 'A' - 10;
  else
    i = -1;
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<digit>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%eax
  jbe    L27
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%eax
  jbe    L5
  lea    -0x41(%rdi),%eax
  cmp    $0x5,%eax
  ja     L1
  lea    -0x37(%rdi),%eax
  ret
L1:
  mov    $0xffffffff,%eax
L27:
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int digit(int i) {
  if ('0' <= i && i <= '9')
    i -= '0';
  else if ('a' <= i && i <= 'f')
    i -= 'a' - 10;
  else if ('A' <= i && i <= 'F')
    i -= 'A' - 10;
  else
    i = -1;
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0x20(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L20
L53:
  mov    -0x8(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L34
  mov    -0x24(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <F@plt>
  mov    -0x10(%rbp),%edx
  add    %edx,%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  jmp    L31
L34:
  mov    -0x24(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <F@plt>
  mov    -0x10(%rbp),%edx
  add    %edx,%eax
  cltd
  idivl  -0x1c(%rbp)
  mov    %edx,%eax
L31:
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jbe    L53
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L7
  mov    -0x18(%rbp),%eax
  imul   -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  jmp    L40
L7:
  mov    -0x18(%rbp),%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
L40:
  leave
  ret
```

assistant: ```c
uint64_t do_shuffle(unsigned r, uint64_t a, uint64_t b, uint64_t m, uint64_t seed) {
  uint64_t tmp;
  uint64_t L = m % a;
  uint64_t R = m / a;
  for (unsigned j = 1; j <= r; j++) {
    tmp = (j & 1) ? (L + F(j, R, seed)) % a : (L + F(j, R, seed)) % b;
    L = R;
    R = tmp;
  }
  return (r & 1) ? a * L + R : a * R + L;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<do_shuffle>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%r12d
  mov    %edx,%r14d
  mov    %ecx,%eax
  cltd
  idiv   %esi
  mov    %edx,0xc(%rsp)
  test   %edi,%edi
  je     L8
  mov    %edi,%r13d
  mov    %r8d,%r15d
  mov    %eax,%ebp
  mov    $0x1,%ebx
  jmp    L4
L17:
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <F@plt>
  add    0xc(%rsp),%eax
  cltd
  idiv   %r14d
L61:
  add    $0x1,%ebx
  mov    %ebp,0xc(%rsp)
  cmp    %ebx,%r13d
  jb     L59
  mov    %edx,%ebp
L4:
  test   $0x1,%bl
  je     L17
  mov    %r15d,%edx
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <F@plt>
  add    0xc(%rsp),%eax
  cltd
  idiv   %r12d
  jmp    L61
L59:
  test   $0x1,%r13b
  je     L44
  imul   %ebp,%r12d
  lea    (%r12,%rdx,1),%eax
L26:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    %ecx,%ebp
L44:
  imul   %edx,%r12d
  lea    (%r12,%rbp,1),%eax
  jmp    L26
```

assistant: ```c
uint64_t do_shuffle(unsigned r, uint64_t a, uint64_t b, uint64_t m, uint64_t seed) {
  uint64_t tmp;
  uint64_t L = m % a;
  uint64_t R = m / a;
  for (unsigned j = 1; j <= r; j++) {
    tmp = (j & 1) ? (L + F(j, R, seed)) % a : (L + F(j, R, seed)) % b;
    L = R;
    R = tmp;
  }
  return (r & 1) ? a * L + R : a * R + L;
}
```