ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<string_escape>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L7
  call   <strlen@plt>
  lea    0x2(%rax,%rax,1),%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L108
  mov    %rax,%rcx
  jmp    L112
L48:
  cmp    $0x5c,%dl
  jne    L106
  movb   $0x5c,(%rcx)
  movb   $0x5c,0x1(%rcx)
  lea    0x2(%rcx),%rcx
L12:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L111
L112:
  cmp    $0x27,%dl
  je     L83
  ja     L48
  cmp    $0xa,%dl
  je     L97
  cmp    $0x22,%dl
  jne    L106
L83:
  movb   $0x5c,(%rcx)
  movzbl (%rbx),%edx
  mov    %dl,0x1(%rcx)
  lea    0x2(%rcx),%rcx
  jmp    L12
L97:
  movb   $0x5c,(%rcx)
  movb   $0x6e,0x1(%rcx)
  lea    0x2(%rcx),%rcx
  jmp    L12
L106:
  mov    %dl,(%rcx)
  lea    0x1(%rcx),%rcx
  jmp    L12
L108:
  mov    %rax,%rcx
L111:
  movb   $0x0,(%rcx)
L114:
  pop    %rbx
  ret
L7:
  mov    %rdi,%rax
  jmp    L114
```

assistant: ```c
unsigned char *string_escape(unsigned char *in) {
  unsigned char *c;
  unsigned char *out;
  if (!in)
    return NULL;
  out = malloc(strlen(in) * 2 + 2);
  for (c = out; *in; in++) {
    switch (*in) {
    case '\\':
      *c++ = '\\';
      *c++ = '\\';
      break;
    case '\n':
      *c++ = '\\';
      *c++ = 'n';
      break;
    case '\"':
    case '\'':
      *c++ = '\\';
      *c++ = *in;
      break;
    default:
      *c++ = *in;
    }
  }
  *c++ = '\0';
  return out;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<string_escape>:
  endbr64
  test   %rdi,%rdi
  je     L19
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x2(%rax,%rax,1),%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  jne    L7
  jmp    L85
  nopl   0x0(%rax,%rax,1)
L69:
  mov    $0x6e5c,%edx
  add    $0x2,%rcx
  mov    %dx,-0x2(%rcx)
L67:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  je     L85
L7:
  cmp    $0x27,%dl
  je     L111
  ja     L8
  cmp    $0xa,%dl
  je     L69
  cmp    $0x22,%dl
  jne    L105
L111:
  movb   $0x5c,(%rcx)
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  add    $0x2,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L7
L85:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  cmp    $0x5c,%dl
  jne    L105
  mov    $0x5c5c,%esi
  add    $0x2,%rcx
  mov    %si,-0x2(%rcx)
  jmp    L67
  nopl   0x0(%rax)
L105:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  jmp    L67
L19:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *string_escape(unsigned char *in) {
  unsigned char *c;
  unsigned char *out;
  if (!in)
    return NULL;
  out = malloc(strlen(in) * 2 + 2);
  for (c = out; *in; in++) {
    switch (*in) {
    case '\\':
      *c++ = '\\';
      *c++ = '\\';
      break;
    case '\n':
      *c++ = '\\';
      *c++ = 'n';
      break;
    case '\"':
    case '\'':
      *c++ = '\\';
      *c++ = *in;
      break;
    default:
      *c++ = *in;
    }
  }
  *c++ = '\0';
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<string_escape>:
  endbr64
  test   %rdi,%rdi
  je     L119
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x2(%rax,%rax,1),%edi
  call   <malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%rcx
  test   %dl,%dl
  jne    L4
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L48:
  mov    $0x6e5c,%edx
  add    $0x2,%rcx
  mov    %dx,-0x2(%rcx)
L103:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  test   %dl,%dl
  je     L60
L4:
  cmp    $0x27,%dl
  je     L71
  ja     L31
  cmp    $0xa,%dl
  je     L48
  cmp    $0x22,%dl
  jne    L109
L71:
  movb   $0x5c,(%rcx)
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  add    $0x2,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L4
L60:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  cmp    $0x5c,%dl
  jne    L109
  mov    $0x5c5c,%esi
  add    $0x2,%rcx
  mov    %si,-0x2(%rcx)
  jmp    L103
  nopl   0x0(%rax)
L109:
  mov    %dl,(%rcx)
  add    $0x1,%rcx
  jmp    L103
L119:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned char *string_escape(unsigned char *in) {
  unsigned char *c;
  unsigned char *out;
  if (!in)
    return NULL;
  out = malloc(strlen(in) * 2 + 2);
  for (c = out; *in; in++) {
    switch (*in) {
    case '\\':
      *c++ = '\\';
      *c++ = '\\';
      break;
    case '\n':
      *c++ = '\\';
      *c++ = 'n';
      break;
    case '\"':
    case '\'':
      *c++ = '\\';
      *c++ = *in;
      break;
    default:
      *c++ = *in;
    }
  }
  *c++ = '\0';
  return out;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L11:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x9,-0x14(%rbp)
  jg     L11
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int num_length(int num) {
  int len = 0;
  while (num / 10 > 0)
    ++len;
  return ++len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<num_length>:
  endbr64
  cmp    $0x9,%edi
  jle    L10
L7:
  jmp    L7
L10:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int num_length(int num) {
  int len = 0;
  while (num / 10 > 0)
    ++len;
  return ++len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<num_length>:
  endbr64
  cmp    $0x9,%edi
  jle    L19
L16:
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int num_length(int num) {
  int len = 0;
  while (num / 10 > 0)
    ++len;
  return ++len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<num_length>:
  endbr64
  cmp    $0x9,%edi
  jle    L14
L3:
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L14:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int num_length(int num) {
  int len = 0;
  while (num / 10 > 0)
    ++len;
  return ++len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ft_bin_to_dec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L23
L10:
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  subl   $0x1,-0x4(%rbp)
  jmp    L37
L7:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x31,%al
  jne    L29
  mov    -0x8(%rbp),%eax
  add    %eax,-0xc(%rbp)
L29:
  shll   -0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L37:
  cmpl   $0x0,-0x4(%rbp)
  jns    L7
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int ft_bin_to_dec(char *bin) {
  int res;
  int two;
  int i;
  i = 0;
  two = 1;
  res = 0;
  while (bin[i])
    i++;
  i--;
  while (i >= 0) {
    if (bin[i] == '1')
      res = res + two;
    two = two * 2;
    i--;
  }
  return (res);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_bin_to_dec>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x0,%eax
L54:
  mov    %eax,%edx
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L54
  test   %edx,%edx
  js     L22
  movslq %edx,%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    -0x1(%rdi,%rdx,1),%rdi
  mov    %ecx,%ecx
  sub    %rcx,%rdi
  mov    $0x1,%ecx
  mov    $0x0,%edx
L20:
  lea    (%rdx,%rcx,1),%esi
  cmpb   $0x31,(%rax)
  cmove  %esi,%edx
  add    %ecx,%ecx
  sub    $0x1,%rax
  cmp    %rdi,%rax
  jne    L20
L14:
  mov    %edx,%eax
  ret
L9:
  mov    $0x0,%edx
  jmp    L14
L22:
  mov    $0x0,%edx
  jmp    L14
```

assistant: ```c
int ft_bin_to_dec(char *bin) {
  int res;
  int two;
  int i;
  i = 0;
  two = 1;
  res = 0;
  while (bin[i])
    i++;
  i--;
  while (i >= 0) {
    if (bin[i] == '1')
      res = res + two;
    two = two * 2;
    i--;
  }
  return (res);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_bin_to_dec>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L29
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L17:
  movslq %eax,%rdx
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L17
  lea    -0x1(%rdi,%rdx,1),%rsi
  lea    (%rdi,%rdx,1),%rax
  xor    %r8d,%r8d
  mov    $0x1,%edx
  sub    %rcx,%rsi
  nopl   0x0(%rax)
L24:
  cmpb   $0x31,(%rax)
  lea    (%r8,%rdx,1),%ecx
  cmove  %ecx,%r8d
  sub    $0x1,%rax
  add    %edx,%edx
  cmp    %rsi,%rax
  jne    L24
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_bin_to_dec(char *bin) {
  int res;
  int two;
  int i;
  i = 0;
  two = 1;
  res = 0;
  while (bin[i])
    i++;
  i--;
  while (i >= 0) {
    if (bin[i] == '1')
      res = res + two;
    two = two * 2;
    i--;
  }
  return (res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_bin_to_dec>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L23
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L13:
  movslq %eax,%rdx
  mov    %rax,%rcx
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L13
  lea    -0x1(%rdi,%rdx,1),%rsi
  lea    (%rdi,%rdx,1),%rax
  xor    %r8d,%r8d
  mov    $0x1,%edx
  sub    %rcx,%rsi
  nopl   0x0(%rax)
L1:
  cmpb   $0x31,(%rax)
  lea    (%r8,%rdx,1),%ecx
  cmove  %ecx,%r8d
  sub    $0x1,%rax
  add    %edx,%edx
  cmp    %rsi,%rax
  jne    L1
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L23:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_bin_to_dec(char *bin) {
  int res;
  int two;
  int i;
  i = 0;
  two = 1;
  res = 0;
  while (bin[i])
    i++;
  i--;
  while (i >= 0) {
    if (bin[i] == '1')
      res = res + two;
    two = two * 2;
    i--;
  }
  return (res);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<or_m32_imm32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x81,%edi
  call   <put8@plt>
  mov    $0xd,%edi
  call   <put8@plt>
  mov    -0x8(%rbp),%rax
  mov    %eax,%edi
  call   <put32@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void or_m32_imm32(unsigned int *m32, unsigned int imm32) {
  put8(0x81);
  put8(0x0D);
  put32((unsigned int)(m32));
  put32(imm32);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<or_m32_imm32>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x81,%edi
  call   <put8@plt>
  mov    $0xd,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  mov    %ebp,%edi
  call   <put32@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void or_m32_imm32(unsigned int *m32, unsigned int imm32) {
  put8(0x81);
  put8(0x0D);
  put32((unsigned int)(m32));
  put32(imm32);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<or_m32_imm32>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x81,%edi
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0xd,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void or_m32_imm32(unsigned int *m32, unsigned int imm32) {
  put8(0x81);
  put8(0x0D);
  put32((unsigned int)(m32));
  put32(imm32);
}
```
user: What is the c source code of the assembly code below?

```asm
<or_m32_imm32>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x81,%edi
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0xd,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  add    $0x8,%rsp
  mov    %ebp,%edi
  pop    %rbx
  pop    %rbp
  jmp    1070 <put32@plt>
```

assistant: ```c
void or_m32_imm32(unsigned int *m32, unsigned int imm32) {
  put8(0x81);
  put8(0x0D);
  put32((unsigned int)(m32));
  put32(imm32);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L8:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isPowerOfThree@plt>
  cmp    $0x1,%eax
  jne    L19
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L19:
  addl   $0x1,-0x4(%rbp)
L0:
  cmpl   $0x63,-0x4(%rbp)
  jle    L8
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: %d is power of three


assistant: ```c
int main(void) {
  for (int i = 0; i < 100; i++) {
    if (isPowerOfThree(i) == true) {
      printf("%d is power of three\n", i);
    }
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebx
  lea    D4(%rip),%rbp
  jmp    L0
L31:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L3
L0:
  mov    %ebx,%edi
  call   <isPowerOfThree@plt>
  cmp    $0x1,%eax
  jne    L31
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L31
L3:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string

tool: D4: %d is power of three


assistant: ```c
int main(void) {
  for (int i = 0; i < 100; i++) {
    if (isPowerOfThree(i) == true) {
      printf("%d is power of three\n", i);
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L7
  nopl   (%rax)
L11:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L4
L7:
  mov    %ebx,%edi
  call   <isPowerOfThree@plt>
  cmp    $0x1,%eax
  jne    L11
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x64,%ebx
  jne    L7
L4:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
datatype: string

tool: D7: %d is power of three


assistant: ```c
int main(void) {
  for (int i = 0; i < 100; i++) {
    if (isPowerOfThree(i) == true) {
      printf("%d is power of three\n", i);
    }
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L3
  nopl   (%rax)
L4:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L17
L3:
  mov    %ebx,%edi
  call   <isPowerOfThree@plt>
  cmp    $0x1,%eax
  jne    L4
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x64,%ebx
  jne    L3
L17:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string

tool: D0: %d is power of three


assistant: ```c
int main(void) {
  for (int i = 0; i < 100; i++) {
    if (isPowerOfThree(i) == true) {
      printf("%d is power of three\n", i);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<op_cumulative_sum_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    -0x2(%rax),%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpq   $0x0,-0x40(%rbp)
  jne    L8
  lea    D37(%rip),%rax
  mov    %rax,-0x40(%rbp)
L8:
  cmpl   $0x0,-0x14(%rbp)
  jle    L29
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D28(%rip),%r9
  mov    %esi,%r8d
  lea    D29(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L9
L29:
  mov    -0x28(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L9:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D37
type: string
name: disassemble_data
arguments: data_tag: D28
type: string
name: disassemble_data
arguments: data_tag: D29
type: string
name: disassemble_data
arguments: data_tag: D3
type: string
name: disassemble_data
arguments: data_tag: D9
type: string

tool: 

tool: D28:  

tool: D29: %s%s:%*s

tool: D3: %s%s: 

tool: D9: compute the cumulative sum of the current set of interval values


assistant: ```c
void op_cumulative_sum_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "compute the cumulative sum of the current set of interval values\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<op_cumulative_sum_short>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %rcx,%rbp
  call   <strlen@plt>
  mov    %eax,%edx
  lea    -0x2(%rbx),%eax
  sub    %edx,%eax
  test   %rbp,%rbp
  lea    D39(%rip),%rdx
  cmove  %rdx,%rbp
  test   %eax,%eax
  jle    L2
  lea    D42(%rip),%r9
  lea    0x1(%rax),%r8d
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D36(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
L13:
  mov    %r12,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  lea    D20(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  mov    %r13,%rcx
  mov    %rbp,%rdx
  lea    D11(%rip),%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L13
```

tool_calls: name: parse_data
arguments: data_tag: D39
datatype: string
name: parse_data
arguments: data_tag: D42
datatype: string
name: parse_data
arguments: data_tag: D36
datatype: string
name: parse_data
arguments: data_tag: D20
datatype: string
name: parse_data
arguments: data_tag: D11
datatype: string

tool: 

tool: D42:  

tool: D36: %s%s:%*s

tool: D20: compute the cumulative sum of the current set of interval values


tool: D11: %s%s: 

assistant: ```c
void op_cumulative_sum_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "compute the cumulative sum of the current set of interval values\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<op_cumulative_sum_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D48(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L15
  lea    0x1(%rax),%r8d
  lea    D33(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D40(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L17:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D0(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L15:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D35(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: tag: D48
data_type: string
name: extract_symbolic_data
arguments: tag: D33
data_type: string
name: extract_symbolic_data
arguments: tag: D40
data_type: string
name: extract_symbolic_data
arguments: tag: D0
data_type: string
name: extract_symbolic_data
arguments: tag: D35
data_type: string

tool: 

tool: D33:  

tool: D40: %s%s:%*s

tool: D0: compute the cumulative sum of the current set of interval values


tool: D35: %s%s: 

assistant: ```c
void op_cumulative_sum_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "compute the cumulative sum of the current set of interval values\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<op_cumulative_sum_short>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    D15(%rip),%rdx
  mov    %eax,%r8d
  lea    -0x2(%rbx),%eax
  sub    %r8d,%eax
  test   %r12,%r12
  cmove  %rdx,%r12
  test   %eax,%eax
  jle    L13
  lea    0x1(%rax),%r8d
  lea    D26(%rip),%r9
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D11(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
L17:
  add    $0x8,%rsp
  mov    %r13,%rcx
  mov    $0x41,%edx
  mov    $0x1,%esi
  pop    %rbx
  lea    D22(%rip),%rdi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <fwrite@plt>
L13:
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D4(%rip),%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <fprintf@plt>
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string
name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D4
type_guessed: string

tool: 

tool: D26:  

tool: D11: %s%s:%*s

tool: D22: compute the cumulative sum of the current set of interval values


tool: D4: %s%s: 

assistant: ```c
void op_cumulative_sum_short(char *name, int nameWidth, FILE *f, char *indent) {
  int nameFill = nameWidth - 2 - strlen(name);
  if (indent == NULL)
    indent = "";
  if (nameFill > 0)
    fprintf(f, "%s%s:%*s", indent, name, nameFill + 1, " ");
  else
    fprintf(f, "%s%s: ", indent, name);
  fprintf(f, "compute the cumulative sum of the current set of interval values\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<bwa2i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,%eax
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %al,-0x14(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L27
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jg     L10
  mov    -0x10(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x14(%rbp)
L27:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <bwa2d@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L30
  jmp    L38
L10:
  nop
L38:
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  movzbl -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
char bwa2i(char ch, const char **src, int base, int *nump) {
  int num, digit;
  const char *p;
  p = *src;
  num = 0;
  while ((digit = bwa2d(ch)) >= 0) {
    if (digit > base)
      break;
    num = num * base + digit;
    ch = *p++;
  }
  *src = p;
  *nump = num;
  return ch;
}
```