ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<chop_newline>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  call   <strchr@plt>
  cmpb   $0xa,-0x1(%rax)
  jne    L2
  lea    -0x1(%rax),%rdx
  nopl   0x0(%rax)
L6:
  sub    $0x1,%rdx
  movb   $0x0,0x1(%rdx)
  cmpb   $0xa,(%rdx)
  je     L6
L2:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void chop_newline(char *s) {
  char *p;
  p = strchr(s, '\0') - 1;
  while (*p == '\n')
    *p-- = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<screen_monitor_string_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L6
L11:
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <screen_monitor_put_char@plt>
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  nop
  nop
  leave
  ret
```

assistant: ```c
void screen_monitor_string_write(char *c) {
  int i;
  i = 0;
  while (c[i]) {
    screen_monitor_put_char(c[i++]);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<screen_monitor_string_write>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  push   %rbx
  lea    0x1(%rdi),%rbx
L3:
  movsbl %al,%edi
  call   <screen_monitor_put_char@plt>
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L3
  pop    %rbx
  ret
L1:
  ret
```

assistant: ```c
void screen_monitor_string_write(char *c) {
  int i;
  i = 0;
  while (c[i]) {
    screen_monitor_put_char(c[i++]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<screen_monitor_string_write>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L13
  push   %rbx
  lea    0x1(%rdi),%rbx
L15:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <screen_monitor_put_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L15
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void screen_monitor_string_write(char *c) {
  int i;
  i = 0;
  while (c[i]) {
    screen_monitor_put_char(c[i++]);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<screen_monitor_string_write>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L0
  push   %rbx
  lea    0x1(%rdi),%rbx
L5:
  movsbl %al,%edi
  add    $0x1,%rbx
  call   <screen_monitor_put_char@plt>
  movzbl -0x1(%rbx),%eax
  test   %al,%al
  jne    L5
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  ret
```

assistant: ```c
void screen_monitor_string_write(char *c) {
  int i;
  i = 0;
  while (c[i]) {
    screen_monitor_put_char(c[i++]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<polares_cartesianas>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  mov    %rdi,-0x10(%rbp)
  mov    %rsi,-0x18(%rbp)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <cos@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%eax
  movd   %eax,%xmm0
  call   <sin@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm0
  mulss  -0x4(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  movss  %xmm0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void polares_cartesianas(float r, float theta, float *x, float *y) {
  *x = r * cos(theta);
  *y = r * sin(theta);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<polares_cartesianas>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  movss  %xmm1,0xc(%rsp)
  movaps %xmm1,%xmm0
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,0x0(%rbp)
  movss  0xc(%rsp),%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void polares_cartesianas(float r, float theta, float *x, float *y) {
  *x = r * cos(theta);
  *y = r * sin(theta);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<polares_cartesianas>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,0x0(%rbp)
  movaps %xmm1,%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void polares_cartesianas(float r, float theta, float *x, float *y) {
  *x = r * cos(theta);
  *y = r * sin(theta);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<polares_cartesianas>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movaps %xmm1,%xmm0
  movss  %xmm1,0xc(%rsp)
  call   <cos@plt>
  mulss  0x8(%rsp),%xmm0
  movss  0xc(%rsp),%xmm1
  movss  %xmm0,0x0(%rbp)
  movaps %xmm1,%xmm0
  call   <sin@plt>
  mulss  0x8(%rsp),%xmm0
  movss  %xmm0,(%rbx)
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void polares_cartesianas(float r, float theta, float *x, float *y) {
  *x = r * cos(theta);
  *y = r * sin(theta);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<store16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rcx,%rdx
  mov    %rdx,(%rax)
  sarl   $0x8,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %rcx,%rdx
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void store16(void *dst, uint16_t w) {
  uint8_t *p = (uint8_t *)dst;
  *p++ = (uint8_t)w;
  w >>= 8;
  *p++ = (uint8_t)w;
}
```
user: Translate the below assembly code into C programming language:

```asm
<store16>:
  endbr64
  movslq %esi,%rax
  mov    %rax,(%rdi)
  sar    $0x8,%esi
  movslq %esi,%rsi
  mov    %rsi,0x8(%rdi)
  ret
```

assistant: ```c
void store16(void *dst, uint16_t w) {
  uint8_t *p = (uint8_t *)dst;
  *p++ = (uint8_t)w;
  w >>= 8;
  *p++ = (uint8_t)w;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<store16>:
  endbr64
  movslq %esi,%rax
  sar    $0x8,%esi
  movslq %esi,%rsi
  mov    %rax,(%rdi)
  mov    %rsi,0x8(%rdi)
  ret
```

assistant: ```c
void store16(void *dst, uint16_t w) {
  uint8_t *p = (uint8_t *)dst;
  *p++ = (uint8_t)w;
  w >>= 8;
  *p++ = (uint8_t)w;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<store16>:
  endbr64
  movslq %esi,%rax
  sar    $0x8,%esi
  movslq %esi,%rsi
  movq   %rax,%xmm0
  movq   %rsi,%xmm1
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  ret
```

assistant: ```c
void store16(void *dst, uint16_t w) {
  uint8_t *p = (uint8_t *)dst;
  *p++ = (uint8_t)w;
  w >>= 8;
  *p++ = (uint8_t)w;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ft_iterative_factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L29
  mov    $0x0,%eax
  jmp    L12
L29:
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L15:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  mov    -0x4(%rbp),%edx
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L9:
  cmpl   $0x1,-0x14(%rbp)
  jg     L15
  mov    -0x4(%rbp),%eax
L12:
  pop    %rbp
  ret
```

assistant: ```c
int ft_iterative_factorial(int nb) {
  int res;
  if (nb < 0)
    return (0);
  res = 1;
  while (nb > 1)
    res *= (nb--);
  return (res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_iterative_factorial>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L9
  cmp    $0x1,%edi
  jle    L26
  mov    $0x1,%eax
L15:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L15
  ret
L26:
  mov    $0x1,%eax
L9:
  ret
```

assistant: ```c
int ft_iterative_factorial(int nb) {
  int res;
  if (nb < 0)
    return (0);
  res = 1;
  while (nb > 1)
    res *= (nb--);
  return (res);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_iterative_factorial>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L18
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L18
  nopl   0x0(%rax)
L2:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L2
  ret
  cs nopw 0x0(%rax,%rax,1)
L18:
  ret
```

assistant: ```c
int ft_iterative_factorial(int nb) {
  int res;
  if (nb < 0)
    return (0);
  res = 1;
  while (nb > 1)
    res *= (nb--);
  return (res);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_iterative_factorial>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L29
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L29
  nopl   0x0(%rax)
L5:
  mov    %edi,%edx
  sub    $0x1,%edi
  imul   %edx,%eax
  cmp    $0x1,%edi
  jne    L5
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  ret
```

assistant: ```c
int ft_iterative_factorial(int nb) {
  int res;
  if (nb < 0)
    return (0);
  res = 1;
  while (nb > 1)
    res *= (nb--);
  return (res);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexdump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  jmp    L0
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  lea    D2(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  subq   $0x1,-0x20(%rbp)
L0:
  cmpq   $0x0,-0x20(%rbp)
  jne    L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
datatype: string

tool: D2:  0x%02x

assistant: ```c
void hexdump(FILE *f, const char *title, const unsigned char *s, size_t len) {
  fprintf(f, "%s", title);
  for (; len != 0; len--)
    fprintf(f, " 0x%02x", *(s++));
  fprintf(f, "\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hexdump>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    %rcx,%rbp
  mov    %r12,%rsi
  call   <fputs@plt>
  test   %rbp,%rbp
  je     L16
  add    %rbx,%rbp
  lea    D4(%rip),%r13
L3:
  add    $0x1,%rbx
  movzbl -0x1(%rbx),%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  cmp    %rbx,%rbp
  jne    L3
L16:
  mov    %r12,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4:  0x%02x

assistant: ```c
void hexdump(FILE *f, const char *title, const unsigned char *s, size_t len) {
  fprintf(f, "%s", title);
  for (; len != 0; len--)
    fprintf(f, " 0x%02x", *(s++));
  fprintf(f, "\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<hexdump>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %r12,%rsi
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <fputs@plt>
  test   %rbp,%rbp
  je     L10
  add    %rbx,%rbp
  lea    D9(%rip),%r13
  nopl   0x0(%rax)
L2:
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  cmp    %rbp,%rbx
  jne    L2
L10:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <fputc@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9:  0x%02x

assistant: ```c
void hexdump(FILE *f, const char *title, const unsigned char *s, size_t len) {
  fprintf(f, "%s", title);
  for (; len != 0; len--)
    fprintf(f, " 0x%02x", *(s++));
  fprintf(f, "\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hexdump>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %r12,%rsi
  mov    %rcx,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <fputs@plt>
  test   %rbp,%rbp
  je     L11
  add    %rbx,%rbp
  lea    D3(%rip),%r13
  nopl   0x0(%rax)
L8:
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  xor    %eax,%eax
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  cmp    %rbp,%rbx
  jne    L8
L11:
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1080 <fputc@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type_infered: string

tool: D3:  0x%02x

assistant: ```c
void hexdump(FILE *f, const char *title, const unsigned char *s, size_t len) {
  fprintf(f, "%s", title);
  for (; len != 0; len--)
    fprintf(f, " 0x%02x", *(s++));
  fprintf(f, "\n");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <build_max_heap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L16
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  subl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <max_heapify@plt>
  subl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x0,-0x8(%rbp)
  jg     L13
  nop
  nop
  leave
  ret
```

assistant: ```c
void heap_sort(int *a, int heapsize) {
  int i, tmp;
  build_max_heap(a, heapsize);
  for (i = heapsize; i > 0; i--) {
    tmp = a[i];
    a[i] = a[0];
    a[0] = tmp;
    heapsize--;
    max_heapify(a, 0, heapsize);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heap_sort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  call   <build_max_heap@plt>
  test   %ebx,%ebx
  jle    L16
  movslq %ebx,%rbx
L4:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    0x0(%rbp),%edx
  mov    %edx,0x0(%rbp,%rbx,4)
  mov    %eax,0x0(%rbp)
  lea    -0x1(%rbx),%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <max_heapify@plt>
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jg     L4
L16:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heap_sort(int *a, int heapsize) {
  int i, tmp;
  build_max_heap(a, heapsize);
  for (i = heapsize; i > 0; i--) {
    tmp = a[i];
    a[i] = a[0];
    a[0] = tmp;
    heapsize--;
    max_heapify(a, 0, heapsize);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <build_max_heap@plt>
  test   %ebx,%ebx
  jle    L13
  nopl   0x0(%rax,%rax,1)
L2:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    0x0(%rbp),%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp,%rbx,4)
  lea    -0x1(%rbx),%edx
  sub    $0x1,%rbx
  mov    %eax,0x0(%rbp)
  call   <max_heapify@plt>
  test   %ebx,%ebx
  jg     L2
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heap_sort(int *a, int heapsize) {
  int i, tmp;
  build_max_heap(a, heapsize);
  for (i = heapsize; i > 0; i--) {
    tmp = a[i];
    a[i] = a[0];
    a[0] = tmp;
    heapsize--;
    max_heapify(a, 0, heapsize);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<heap_sort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  mov    %ebx,%esi
  sub    $0x8,%rsp
  call   <build_max_heap@plt>
  test   %ebx,%ebx
  jle    L0
  nopl   0x0(%rax,%rax,1)
L10:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    0x0(%rbp),%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    %edx,0x0(%rbp,%rbx,4)
  lea    -0x1(%rbx),%edx
  sub    $0x1,%rbx
  mov    %eax,0x0(%rbp)
  call   <max_heapify@plt>
  test   %ebx,%ebx
  jg     L10
L0:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heap_sort(int *a, int heapsize) {
  int i, tmp;
  build_max_heap(a, heapsize);
  for (i = heapsize; i > 0; i--) {
    tmp = a[i];
    a[i] = a[0];
    a[0] = tmp;
    heapsize--;
    max_heapify(a, 0, heapsize);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<sleep>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    -0x24(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L12:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    -0x18(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jle    L29
  jmp    L12
L29:
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
sleep(unsigned int seconds) {
  long tnow, tthen;
  time(&tnow);
  tthen = tnow + seconds;
  while (1) {
    time(&tnow);
    if (tnow >= tthen)
      return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sleep>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <time@plt>
  mov    %ebx,%ebx
  add    (%rsp),%rbx
  mov    %rsp,%rbp
L1:
  mov    %rbp,%rdi
  call   <time@plt>
  cmp    %rbx,(%rsp)
  jl     L1
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sleep(unsigned int seconds) {
  long tnow, tthen;
  time(&tnow);
  tthen = tnow + seconds;
  while (1) {
    time(&tnow);
    if (tnow >= tthen)
      return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sleep>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  add    (%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rbp,%rdi
  call   <time@plt>
  cmp    %rbx,(%rsp)
  jl     L14
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sleep(unsigned int seconds) {
  long tnow, tthen;
  time(&tnow);
  tthen = tnow + seconds;
  while (1) {
    time(&tnow);
    if (tnow >= tthen)
      return;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<sleep>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <time@plt>
  add    (%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L0:
  mov    %rbp,%rdi
  call   <time@plt>
  cmp    %rbx,(%rsp)
  jl     L0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
sleep(unsigned int seconds) {
  long tnow, tthen;
  time(&tnow);
  tthen = tnow + seconds;
  while (1) {
    time(&tnow);
    if (tnow >= tthen)
      return;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ispalindrome>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edi
  mov    -0x8(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  lea    (%rdi,%rcx,1),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
bool ispalindrome(int number) {
  int i = number;
  int result = 0;
  do {
    result = result * 10 + (i % 10);
  } while (i /= 10);
  return result == number;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ispalindrome>:
  endbr64
  mov    %edi,%edx
  mov    $0x0,%ecx
L7:
  lea    (%rcx,%rcx,4),%esi
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L7
  cmp    %ecx,%edi
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
bool ispalindrome(int number) {
  int i = number;
  int result = 0;
  do {
    result = result * 10 + (i % 10);
  } while (i /= 10);
  return result == number;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ispalindrome>:
  endbr64
  mov    %edi,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L5:
  movslq %edx,%rax
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L5
  xor    %eax,%eax
  cmp    %ecx,%edi
  sete   %al
  ret
```

assistant: ```c
bool ispalindrome(int number) {
  int i = number;
  int result = 0;
  do {
    result = result * 10 + (i % 10);
  } while (i /= 10);
  return result == number;
}
```
user: What is the c source code of the assembly code below?

```asm
<ispalindrome>:
  endbr64
  mov    %edi,%edx
  xor    %ecx,%ecx
  nopl   0x0(%rax,%rax,1)
L0:
  movslq %edx,%rax
  lea    (%rcx,%rcx,4),%esi
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rsi,2),%ecx
  mov    %eax,%edx
  test   %eax,%eax
  jne    L0
  xor    %eax,%eax
  cmp    %ecx,%edi
  sete   %al
  ret
```

assistant: ```c
bool ispalindrome(int number) {
  int i = number;
  int result = 0;
  do {
    result = result * 10 + (i % 10);
  } while (i /= 10);
  return result == number;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rie_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L3
  mov    -0x8(%rbp),%eax
  jmp    L4
L3:
  mov    -0x4(%rbp),%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int rie_max(int a, int b) {
  if (a < b) {
    return b;
  }
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rie_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int rie_max(int a, int b) {
  if (a < b) {
    return b;
  }
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rie_max>:
  endbr64
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edi,%eax
  ret
```

assistant: ```c
int rie_max(int a, int b) {
  if (a < b) {
    return b;
  }
  return a;
}
```