ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<X>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0xd,%edi
  call   <eat@plt>
  mov    $0x11,%edi
  call   <eat@plt>
  xor    %eax,%eax
  call   <C@plt>
  mov    $0x12,%edi
  call   <eat@plt>
  mov    $0x13,%edi
  call   <eat@plt>
  xor    %eax,%eax
  call   <S@plt>
  mov    $0x14,%edi
  add    $0x8,%rsp
  jmp    1080 <eat@plt>
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: X -> while(C){S}


assistant: ```c
void X() {
  printf("X -> while(C){S}\n");
  eat(13);
  eat(17);
  C();
  eat(18);
  eat(19);
  S();
  eat(20);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<X>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0xd,%edi
  call   <eat@plt>
  mov    $0x11,%edi
  call   <eat@plt>
  xor    %eax,%eax
  call   <C@plt>
  mov    $0x12,%edi
  call   <eat@plt>
  mov    $0x13,%edi
  call   <eat@plt>
  xor    %eax,%eax
  call   <S@plt>
  mov    $0x14,%edi
  add    $0x8,%rsp
  jmp    1080 <eat@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: X -> while(C){S}


assistant: ```c
void X() {
  printf("X -> while(C){S}\n");
  eat(13);
  eat(17);
  C();
  eat(18);
  eat(19);
  S();
  eat(20);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fib>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L0
  mov    -0x14(%rbp),%eax
  cltq
  jmp    L9
L0:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,%edi
  call   <fib>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
L9:
  leave
  ret
```

assistant: ```c
long fib(int n) {
  long x, y;
  if (n < 2)
    return n;
#pragma omp task untied shared(x) firstprivate(n)
  x = fib(n - 1);
#pragma omp task untied shared(y) firstprivate(n)
  y = fib(n - 2);
#pragma omp taskwait
  return x + y;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fib>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  movslq %edi,%rax
  cmp    $0x1,%edi
  jle    L7
  lea    -0x1(%rdi),%edi
  call   <fib>
  mov    %rax,%rbp
  lea    -0x2(%rbx),%edi
  call   <fib>
  add    %rbp,%rax
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
long fib(int n) {
  long x, y;
  if (n < 2)
    return n;
#pragma omp task untied shared(x) firstprivate(n)
  x = fib(n - 1);
#pragma omp task untied shared(y) firstprivate(n)
  y = fib(n - 2);
#pragma omp taskwait
  return x + y;
}
```
user: What is the c source code of the assembly code below?

```asm
<__statvfs64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int __statvfs64(const char *file, struct statvfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__statvfs64>:
  endbr64
  sub    $0x8,%rsp
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __statvfs64(const char *file, struct statvfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__statvfs64>:
  endbr64
  sub    $0x8,%rsp
  mov    D1(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __statvfs64(const char *file, struct statvfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<__statvfs64>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int __statvfs64(const char *file, struct statvfs64 *buf) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x6c6c6568,-0xe(%rbp)
  movw   $0x6f,-0xa(%rbp)
  lea    -0xe(%rbp),%rax
  mov    %rax,%rdi
  call   <longestPalindrome@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: string

tool: D0: result: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char test[6] = "hello";
  char *result = longestPalindrome(test);
  printf("result: %s\n", result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x6c6c6568,0x2(%rsp)
  movw   $0x6f,0x6(%rsp)
  lea    0x2(%rsp),%rdi
  call   <longestPalindrome@plt>
  mov    %rax,%rsi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: D3: result: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char test[6] = "hello";
  char *result = longestPalindrome(test);
  printf("result: %s\n", result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rdi
  mov    $0x6f,%eax
  movl   $0x6c6c6568,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <longestPalindrome@plt>
  lea    D0(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: string

tool: D0: result: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char test[6] = "hello";
  char *result = longestPalindrome(test);
  printf("result: %s\n", result);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rdi
  mov    $0x6f,%eax
  movl   $0x6c6c6568,0x2(%rsp)
  mov    %ax,0x6(%rsp)
  call   <longestPalindrome@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D5
data_type: string

tool: D5: result: %s


assistant: ```c
int main(int argc, char const *argv[]) {
  char test[6] = "hello";
  char *result = longestPalindrome(test);
  printf("result: %s\n", result);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<select_random_points>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <srandom@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L12
L9:
  mov    $0x0,%eax
  call   <random@plt>
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L12:
  cmpl   $0x4,-0x10(%rbp)
  jle    L9
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
int *select_random_points(int Nv) {
  int i, j;
  int *rverts;
  rverts = (int *)malloc(5 * sizeof(int));
  srandom(Nv);
  for (i = 0; i < 5; i++) {
    j = random() % Nv;
    rverts[i] = j;
  }
  return rverts;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<select_random_points>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x14,%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebp,%edi
  call   <srandom@plt>
  mov    %r13,%rbx
  lea    0x14(%r13),%r12
L0:
  mov    $0x0,%eax
  call   <random@plt>
  cltd
  idiv   %ebp
  mov    %edx,(%rbx)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L0
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *select_random_points(int Nv) {
  int i, j;
  int *rverts;
  rverts = (int *)malloc(5 * sizeof(int));
  srandom(Nv);
  for (i = 0; i < 5; i++) {
    j = random() % Nv;
    rverts[i] = j;
  }
  return rverts;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<select_random_points>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x14,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <srandom@plt>
  mov    %r13,%rbx
  lea    0x14(%r13),%r12
L9:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <random@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L9
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *select_random_points(int Nv) {
  int i, j;
  int *rverts;
  rverts = (int *)malloc(5 * sizeof(int));
  srandom(Nv);
  for (i = 0; i < 5; i++) {
    j = random() % Nv;
    rverts[i] = j;
  }
  return rverts;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<select_random_points>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    $0x14,%edi
  push   %rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %ebp,%edi
  mov    %rax,%r13
  call   <srandom@plt>
  mov    %r13,%rbx
  lea    0x14(%r13),%r12
L0:
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <random@plt>
  cltd
  idiv   %ebp
  mov    %edx,-0x4(%rbx)
  cmp    %r12,%rbx
  jne    L0
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int *select_random_points(int Nv) {
  int i, j;
  int *rverts;
  rverts = (int *)malloc(5 * sizeof(int));
  srandom(Nv);
  for (i = 0; i < 5; i++) {
    j = random() % Nv;
    rverts[i] = j;
  }
  return rverts;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movss  D53(%rip),%xmm0
  movss  %xmm0,-0x30(%rbp)
  movss  D72(%rip),%xmm0
  movss  %xmm0,-0x2c(%rbp)
  movss  D3(%rip),%xmm0
  movss  %xmm0,-0x28(%rbp)
  movss  D21(%rip),%xmm0
  movss  %xmm0,-0x24(%rbp)
  movss  D25(%rip),%xmm0
  movss  %xmm0,-0x20(%rbp)
  movss  D80(%rip),%xmm0
  movss  %xmm0,-0x1c(%rbp)
  movss  D41(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movss  D50(%rip),%xmm0
  movss  %xmm0,-0x14(%rbp)
  lea    -0x20(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sse@plt>
  movss  -0x24(%rbp),%xmm2
  movss  -0x28(%rbp),%xmm1
  movss  -0x2c(%rbp),%xmm0
  mov    -0x30(%rbp),%eax
  movaps %xmm2,%xmm3
  movaps %xmm1,%xmm2
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D53
data_type: byte[4]
name: read_data
arguments: label: D72
data_type: byte[4]
name: read_data
arguments: label: D3
data_type: byte[4]
name: read_data
arguments: label: D21
data_type: byte[4]
name: read_data
arguments: label: D25
data_type: byte[4]
name: read_data
arguments: label: D80
data_type: byte[4]
name: read_data
arguments: label: D41
data_type: byte[4]
name: read_data
arguments: label: D50
data_type: byte[4]
name: read_data
arguments: label: D54
data_type: string

tool: {"D53": [0x00,0x00,0x80,0x3f]}

tool: {"D72": [0x00,0x00,0x00,0x40]}

tool: {"D3": [0x00,0x00,0x40,0x40]}

tool: {"D21": [0x00,0x00,0x80,0x40]}

tool: {"D25": [0x00,0x00,0xa0,0x40]}

tool: {"D80": [0x00,0x00,0xc0,0x40]}

tool: {"D41": [0x00,0x00,0xe0,0x40]}

tool: {"D50": [0x00,0x00,0x00,0x41]}

tool: D54: %f %f %f %f


assistant: ```c
int main() {
  float x[4] = {1.0f, 2.0f, 3.0f, 4.0f};
  float y[4] = {5.0f, 6.0f, 7.0f, 8.0f};
  sse(x, y);
  printf("%f %f %f %f\n", x[0], x[1], x[2], x[3]);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x3f800000,(%rsp)
  movl   $0x40000000,0x4(%rsp)
  movl   $0x40400000,0x8(%rsp)
  movl   $0x40800000,0xc(%rsp)
  movl   $0x40a00000,0x10(%rsp)
  movl   $0x40c00000,0x14(%rsp)
  movl   $0x40e00000,0x18(%rsp)
  movl   $0x41000000,0x1c(%rsp)
  lea    0x10(%rsp),%rsi
  mov    %rsp,%rdi
  call   <sse@plt>
  movss  0xc(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
datatype: string

tool: D0: %f %f %f %f


assistant: ```c
int main() {
  float x[4] = {1.0f, 2.0f, 3.0f, 4.0f};
  float y[4] = {5.0f, 6.0f, 7.0f, 8.0f};
  sse(x, y);
  printf("%f %f %f %f\n", x[0], x[1], x[2], x[3]);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x400000003f800000,%rax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%rsi
  mov    %rax,(%rsp)
  movabs $0x4080000040400000,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x40c0000040a00000,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x4100000040e00000,%rax
  mov    %rax,0x18(%rsp)
  call   <sse@plt>
  movss  0xc(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  lea    D6(%rip),%rdi
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
data_type: string

tool: D6: %f %f %f %f


assistant: ```c
int main() {
  float x[4] = {1.0f, 2.0f, 3.0f, 4.0f};
  float y[4] = {5.0f, 6.0f, 7.0f, 8.0f};
  sse(x, y);
  printf("%f %f %f %f\n", x[0], x[1], x[2], x[3]);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  movaps D27(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  lea    0x10(%rsp),%rsi
  movaps %xmm0,(%rsp)
  movaps D15(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <sse@plt>
  movss  0xc(%rsp),%xmm3
  movss  0x8(%rsp),%xmm2
  lea    D4(%rip),%rdi
  movss  0x4(%rsp),%xmm1
  movss  (%rsp),%xmm0
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D27
data_type: byte[16]
name: retrieve_data
arguments: tag: D15
data_type: byte[16]
name: retrieve_data
arguments: tag: D4
data_type: string

tool: {"D27": [0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x40,0x00,0x00,0x40,0x40,0x00,0x00,0x80,0x40]}

tool: {"D15": [0x00,0x00,0xa0,0x40,0x00,0x00,0xc0,0x40,0x00,0x00,0xe0,0x40,0x00,0x00,0x00,0x41]}

tool: D4: %f %f %f %f


assistant: ```c
int main() {
  float x[4] = {1.0f, 2.0f, 3.0f, 4.0f};
  float y[4] = {5.0f, 6.0f, 7.0f, 8.0f};
  sse(x, y);
  printf("%f %f %f %f\n", x[0], x[1], x[2], x[3]);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_strndup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L10
  mov    $0x0,%eax
  jmp    L8
L10:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  jmp    L8
L6:
  mov    $0x0,%eax
L8:
  leave
  ret
```

assistant: ```c
char *my_strndup(char *s, int n) {
  char *res;
  if (s) {
    if (!(res = malloc(sizeof(char) * (n + 1))))
      return (NULL);
    bzero(res, n + 1);
    return (strncpy(res, s, n));
  }
  return (NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strndup>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  test   %rdi,%rdi
  je     L11
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    0x1(%rsi),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L11
  mov    %r13d,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strncpy@plt>
  mov    %rax,%rbx
L11:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *my_strndup(char *s, int n) {
  char *res;
  if (s) {
    if (!(res = malloc(sizeof(char) * (n + 1))))
      return (NULL);
    bzero(res, n + 1);
    return (strncpy(res, s, n));
  }
  return (NULL);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<my_strndup>:
  endbr64
  test   %rdi,%rdi
  je     L17
  push   %r14
  lea    0x1(%rsi),%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L13
  mov    %r14d,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strncpy@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *my_strndup(char *s, int n) {
  char *res;
  if (s) {
    if (!(res = malloc(sizeof(char) * (n + 1))))
      return (NULL);
    bzero(res, n + 1);
    return (strncpy(res, s, n));
  }
  return (NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_strndup>:
  endbr64
  test   %rdi,%rdi
  je     L11
  push   %r14
  lea    0x1(%rsi),%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  mov    %r14d,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L19
  mov    %r14d,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  add    $0x8,%rsp
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strncpy@plt>
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *my_strndup(char *s, int n) {
  char *res;
  if (s) {
    if (!(res = malloc(sizeof(char) * (n + 1))))
      return (NULL);
    bzero(res, n + 1);
    return (strncpy(res, s, n));
  }
  return (NULL);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L37:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L37
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x9c58(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x9c54(%rbp)
  jmp    L31
L2:
  lea    -0x9c50(%rbp),%rdx
  mov    -0x9c54(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x9c54(%rbp)
L31:
  mov    -0x9c58(%rbp),%eax
  cmp    %eax,-0x9c54(%rbp)
  jl     L2
  mov    -0x9c58(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x9c54(%rbp)
  jmp    L29
L40:
  mov    -0x9c54(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x9c54(%rbp)
L29:
  cmpl   $0x0,-0x9c54(%rbp)
  jns    L40
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string
name: read_data
arguments: data_label: D15
type: string

tool: D7: %d

tool: D15: %d 

assistant: ```c
int main() {
  int storage[10000], n, i;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &storage[i]);
  }
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", storage[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x9000(%rsp),%r11
L6:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L6
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x9c58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L25
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D21(%rip),%r12
L4:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L4
L25:
  test   %eax,%eax
  jle    L3
  movslq %eax,%rdx
  shl    $0x2,%rdx
  lea    0x10(%rsp,%rdx,1),%rbx
  lea    0xc(%rsp,%rdx,1),%rbp
  lea    -0x1(%rax),%eax
  shl    $0x2,%rax
  sub    %rax,%rbp
  lea    D2(%rip),%r12
L28:
  mov    -0x4(%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L28
L3:
  mov    0x9c58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  mov    $0x0,%eax
  add    $0x9c60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D21
datatype: string
name: unpack_data
arguments: data_label: D2
datatype: string

tool: D21: %d

tool: D2: %d 

assistant: ```c
int main() {
  int storage[10000], n, i;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &storage[i]);
  }
  for (i = n - 1; i >= 0; i--) {
    printf("%d ", storage[i]);
  }
  return 0;
}
```