ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<transform44f3f>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm3
  movss  0x8(%rsi),%xmm2
  movaps %xmm0,%xmm1
  mulss  (%rdi),%xmm1
  movaps %xmm3,%xmm4
  mulss  0x4(%rdi),%xmm4
  addss  %xmm4,%xmm1
  movaps %xmm2,%xmm4
  mulss  0x8(%rdi),%xmm4
  addss  %xmm4,%xmm1
  addss  0xc(%rdi),%xmm1
  movss  %xmm1,(%rdx)
  movaps %xmm0,%xmm1
  mulss  0x10(%rdi),%xmm1
  movaps %xmm3,%xmm4
  mulss  0x14(%rdi),%xmm4
  addss  %xmm4,%xmm1
  movaps %xmm2,%xmm4
  mulss  0x18(%rdi),%xmm4
  addss  %xmm4,%xmm1
  addss  0x1c(%rdi),%xmm1
  movss  %xmm1,0x4(%rdx)
  mulss  0x20(%rdi),%xmm0
  mulss  0x24(%rdi),%xmm3
  addss  %xmm3,%xmm0
  mulss  0x28(%rdi),%xmm2
  addss  %xmm2,%xmm0
  addss  0x2c(%rdi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void transform44f3f(float *m1, float *m2, float *m3) {
  register float m2r0 = m2[0];
  register float m2r1 = m2[1];
  register float m2r2 = m2[2];
  m3[0] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2 + m1[3];
  m3[1] = m1[4] * m2r0 + m1[5] * m2r1 + m1[6] * m2r2 + m1[7];
  m3[2] = m1[8] * m2r0 + m1[9] * m2r1 + m1[10] * m2r2 + m1[11];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<transform44f3f>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm3
  movss  (%rdi),%xmm1
  movss  0x4(%rdi),%xmm4
  movss  0x8(%rsi),%xmm2
  mulss  %xmm3,%xmm4
  mulss  %xmm0,%xmm1
  addss  %xmm4,%xmm1
  movss  0x8(%rdi),%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm4,%xmm1
  addss  0xc(%rdi),%xmm1
  movss  %xmm1,(%rdx)
  movss  0x10(%rdi),%xmm1
  movss  0x14(%rdi),%xmm4
  mulss  %xmm0,%xmm1
  mulss  %xmm3,%xmm4
  addss  %xmm4,%xmm1
  movss  0x18(%rdi),%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm4,%xmm1
  addss  0x1c(%rdi),%xmm1
  movss  %xmm1,0x4(%rdx)
  mulss  0x20(%rdi),%xmm0
  mulss  0x24(%rdi),%xmm3
  mulss  0x28(%rdi),%xmm2
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  addss  0x2c(%rdi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void transform44f3f(float *m1, float *m2, float *m3) {
  register float m2r0 = m2[0];
  register float m2r1 = m2[1];
  register float m2r2 = m2[2];
  m3[0] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2 + m1[3];
  m3[1] = m1[4] * m2r0 + m1[5] * m2r1 + m1[6] * m2r2 + m1[7];
  m3[2] = m1[8] * m2r0 + m1[9] * m2r1 + m1[10] * m2r2 + m1[11];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<transform44f3f>:
  endbr64
  movss  (%rsi),%xmm0
  movss  0x4(%rsi),%xmm3
  movss  (%rdi),%xmm1
  movss  0x4(%rdi),%xmm4
  movss  0x8(%rsi),%xmm2
  mulss  %xmm3,%xmm4
  mulss  %xmm0,%xmm1
  addss  %xmm4,%xmm1
  movss  0x8(%rdi),%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm4,%xmm1
  addss  0xc(%rdi),%xmm1
  movss  %xmm1,(%rdx)
  movss  0x10(%rdi),%xmm1
  movss  0x14(%rdi),%xmm4
  mulss  %xmm0,%xmm1
  mulss  %xmm3,%xmm4
  addss  %xmm4,%xmm1
  movss  0x18(%rdi),%xmm4
  mulss  %xmm2,%xmm4
  addss  %xmm4,%xmm1
  addss  0x1c(%rdi),%xmm1
  movss  %xmm1,0x4(%rdx)
  mulss  0x20(%rdi),%xmm0
  mulss  0x24(%rdi),%xmm3
  mulss  0x28(%rdi),%xmm2
  addss  %xmm3,%xmm0
  addss  %xmm2,%xmm0
  addss  0x2c(%rdi),%xmm0
  movss  %xmm0,0x8(%rdx)
  ret
```

assistant: ```c
void transform44f3f(float *m1, float *m2, float *m3) {
  register float m2r0 = m2[0];
  register float m2r1 = m2[1];
  register float m2r2 = m2[2];
  m3[0] = m1[0] * m2r0 + m1[1] * m2r1 + m1[2] * m2r2 + m1[3];
  m3[1] = m1[4] * m2r0 + m1[5] * m2r1 + m1[6] * m2r2 + m1[7];
  m3[2] = m1[8] * m2r0 + m1[9] * m2r1 + m1[10] * m2r2 + m1[11];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<soru_4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L39
L47:
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L9:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L35
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
L35:
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L9
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void soru_4(int dizi[], int N) {
  int i, j;
  for (j = 1; j < N; j++) {
    for (i = 0; i < N - 1; i++) {
      if (dizi[i] > dizi[i + 1]) {
        dizi[i] ^= dizi[i + 1];
        dizi[i + 1] ^= dizi[i];
        dizi[i] ^= dizi[i + 1];
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<soru_4>:
  endbr64
  cmp    $0x1,%esi
  jle    L54
  lea    -0x2(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  mov    $0x1,%r9d
  jmp    L51
L65:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L20
L64:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L65
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L65
L20:
  add    $0x1,%r9d
  cmp    %r9d,%esi
  je     L54
L51:
  mov    %rdi,%rax
  jmp    L64
L54:
  ret
```

assistant: ```c
void soru_4(int dizi[], int N) {
  int i, j;
  for (j = 1; j < N; j++) {
    for (i = 0; i < N - 1; i++) {
      if (dizi[i] > dizi[i + 1]) {
        dizi[i] ^= dizi[i + 1];
        dizi[i + 1] ^= dizi[i];
        dizi[i] ^= dizi[i + 1];
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<soru_4>:
  endbr64
  cmp    $0x1,%esi
  jle    L24
  lea    -0x2(%rsi),%eax
  mov    $0x1,%r9d
  lea    0x4(%rdi,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L38:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L26
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L26:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L38
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jne    L20
L24:
  ret
```

assistant: ```c
void soru_4(int dizi[], int N) {
  int i, j;
  for (j = 1; j < N; j++) {
    for (i = 0; i < N - 1; i++) {
      if (dizi[i] > dizi[i + 1]) {
        dizi[i] ^= dizi[i + 1];
        dizi[i + 1] ^= dizi[i];
        dizi[i] ^= dizi[i + 1];
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<soru_4>:
  endbr64
  cmp    $0x1,%esi
  jle    L29
  lea    -0x2(%rsi),%eax
  mov    $0x1,%r9d
  lea    0x4(%rdi,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L5:
  mov    (%rax),%ecx
  mov    0x4(%rax),%edx
  cmp    %edx,%ecx
  jle    L37
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L37:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L5
  add    $0x1,%r9d
  cmp    %r9d,%esi
  jne    L26
L29:
  ret
```

assistant: ```c
void soru_4(int dizi[], int N) {
  int i, j;
  for (j = 1; j < N; j++) {
    for (i = 0; i < N - 1; i++) {
      if (dizi[i] > dizi[i + 1]) {
        dizi[i] ^= dizi[i + 1];
        dizi[i + 1] ^= dizi[i];
        dizi[i] ^= dizi[i + 1];
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prod_merge_two_strings>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  cltq
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rsi
  mov    -0x38(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rsi,%r8
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %s%s%s

assistant: ```c
char *prod_merge_two_strings(const char *str1, const char *str2, const char *separator) {
  char *new_str = NULL;
  size_t new_str_len;
  new_str_len = strlen(str1) + strlen(str2) + strlen(separator) + 1;
  new_str = malloc(new_str_len);
  sprintf(new_str, "%s%s%s", str1, separator, str2);
  new_str[new_str_len] = '\0';
  return new_str;
}
```
user: What is the c source code of the assembly code below?

```asm
<prod_merge_two_strings>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r13
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %eax,%ebx
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%r14d
  movslq %r14d,%r14
  mov    %r14,%rdi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r13,%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movb   $0x0,(%rbx,%r14,1)
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D0
data_type: string

tool: D0: %s%s%s

assistant: ```c
char *prod_merge_two_strings(const char *str1, const char *str2, const char *separator) {
  char *new_str = NULL;
  size_t new_str_len;
  new_str_len = strlen(str1) + strlen(str2) + strlen(separator) + 1;
  new_str = malloc(new_str_len);
  sprintf(new_str, "%s%s%s", str1, separator, str2);
  new_str[new_str_len] = '\0';
  return new_str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prod_merge_two_strings>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r14,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rbp,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rax,%r12
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D1
type_guessed: string

tool: D1: %s%s%s

assistant: ```c
char *prod_merge_two_strings(const char *str1, const char *str2, const char *separator) {
  char *new_str = NULL;
  size_t new_str_len;
  new_str_len = strlen(str1) + strlen(str2) + strlen(separator) + 1;
  new_str = malloc(new_str_len);
  sprintf(new_str, "%s%s%s", str1, separator, str2);
  new_str[new_str_len] = '\0';
  return new_str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<prod_merge_two_strings>:
  endbr64
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  mov    %r14,%rdi
  add    %eax,%r12d
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%ebx
  movslq %ebx,%rbx
  mov    %rbx,%rdi
  call   <malloc@plt>
  mov    %rbp,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %rax,%r12
  lea    D4(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type_infered: string

tool: D4: %s%s%s

assistant: ```c
char *prod_merge_two_strings(const char *str1, const char *str2, const char *separator) {
  char *new_str = NULL;
  size_t new_str_len;
  new_str_len = strlen(str1) + strlen(str2) + strlen(separator) + 1;
  new_str = malloc(new_str_len);
  sprintf(new_str, "%s%s%s", str1, separator, str2);
  new_str[new_str_len] = '\0';
  return new_str;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cxl_sysfs_adapter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <cxl_adapter_dev_name@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <asprintf@plt>
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type: string

tool: D1: /sys/class/cxl/%s

assistant: ```c
int cxl_sysfs_adapter(char **bufp, struct cxl_adapter_h *adapter) {
  return asprintf(bufp,
                  "/sys/class/cxl"
                  "/%s",
                  cxl_adapter_dev_name(adapter));
}
```
user: Translate the below assembly code into C programming language:

```asm
<cxl_sysfs_adapter>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  call   <cxl_adapter_dev_name@plt>
  mov    %eax,%edx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <asprintf@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D6
datatype: string

tool: D6: /sys/class/cxl/%s

assistant: ```c
int cxl_sysfs_adapter(char **bufp, struct cxl_adapter_h *adapter) {
  return asprintf(bufp,
                  "/sys/class/cxl"
                  "/%s",
                  cxl_adapter_dev_name(adapter));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cxl_sysfs_adapter>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <cxl_adapter_dev_name@plt>
  mov    %rbp,%rdi
  lea    D9(%rip),%rsi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <asprintf@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D9
datatype: string

tool: D9: /sys/class/cxl/%s

assistant: ```c
int cxl_sysfs_adapter(char **bufp, struct cxl_adapter_h *adapter) {
  return asprintf(bufp,
                  "/sys/class/cxl"
                  "/%s",
                  cxl_adapter_dev_name(adapter));
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cxl_sysfs_adapter>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %rsi,%rdi
  call   <cxl_adapter_dev_name@plt>
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  pop    %rbp
  mov    %eax,%edx
  jmp    1060 <asprintf@plt>
```

tool_calls: name: parse_data
arguments: label: D1
type_guessed: string

tool: D1: /sys/class/cxl/%s

assistant: ```c
int cxl_sysfs_adapter(char **bufp, struct cxl_adapter_h *adapter) {
  return asprintf(bufp,
                  "/sys/class/cxl"
                  "/%s",
                  cxl_adapter_dev_name(adapter));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<recv_new>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    D0(%rip),%rcx
  movzbl (%rax,%rcx,1),%eax
  cmp    %al,%dl
  jne    L15
  addl   $0x1,-0xc(%rbp)
  cmpl   $0x2,-0xc(%rbp)
  jne    L34
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L13
L15:
  movl   $0x0,-0xc(%rbp)
L34:
  addq   $0x1,-0x8(%rbp)
L30:
  mov    -0x8(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %eax,%edi
  call   <recv@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x0,%eax
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type_guessed: string

tool: D0: 


assistant: ```c
int recv_new(int fd, char *buffer) {
  char *p = buffer;
  int eol_matched = 0;
  while (recv(fd, p, 1, 0) != 0) {
    if (*p == "\r\n"[eol_matched]) {
      ++eol_matched;
      if (eol_matched == 2) {
        *(p + 1 - 2) = '\0';
        return (strlen(buffer));
      }
    } else {
      eol_matched = 0;
    }
    p++;
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<recv_new>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r14
  mov    %rsi,%rbx
  mov    $0x0,%ebp
  lea    D6(%rip),%r13
  jmp    L49
L37:
  add    $0x1,%ebp
  cmp    $0x2,%ebp
  je     L26
L16:
  add    $0x1,%rbx
L49:
  mov    $0x0,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %rax,%rax
  je     L19
  movslq %ebp,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  cmp    %al,(%rbx)
  je     L37
  mov    $0x0,%ebp
  jmp    L16
L26:
  movb   $0x0,-0x1(%rbx)
  mov    %r14,%rdi
  call   <strlen@plt>
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: label: D6
type_infered: string

tool: D6: 


assistant: ```c
int recv_new(int fd, char *buffer) {
  char *p = buffer;
  int eol_matched = 0;
  while (recv(fd, p, 1, 0) != 0) {
    if (*p == "\r\n"[eol_matched]) {
      ++eol_matched;
      if (eol_matched == 2) {
        *(p + 1 - 2) = '\0';
        return (strlen(buffer));
      }
    } else {
      eol_matched = 0;
    }
    p++;
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<recv_new>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L24
L31:
  xor    %ebp,%ebp
L41:
  add    $0x1,%rbx
L24:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %rax,%rax
  je     L4
  movslq %ebp,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  cmp    %al,(%rbx)
  jne    L31
  cmp    $0x1,%ebp
  je     L3
  mov    $0x1,%ebp
  jmp    L41
  cs nopw 0x0(%rax,%rax,1)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  movb   $0x0,-0x1(%rbx)
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strlen@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: 


assistant: ```c
int recv_new(int fd, char *buffer) {
  char *p = buffer;
  int eol_matched = 0;
  while (recv(fd, p, 1, 0) != 0) {
    if (*p == "\r\n"[eol_matched]) {
      ++eol_matched;
      if (eol_matched == 2) {
        *(p + 1 - 2) = '\0';
        return (strlen(buffer));
      }
    } else {
      eol_matched = 0;
    }
    p++;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<recv_new>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  lea    D8(%rip),%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rsi,%rbx
  jmp    L2
L24:
  xor    %ebp,%ebp
L48:
  add    $0x1,%rbx
L2:
  xor    %ecx,%ecx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12d,%edi
  call   <recv@plt>
  test   %rax,%rax
  je     L36
  movslq %ebp,%rax
  movzbl 0x0(%r13,%rax,1),%eax
  cmp    %al,(%rbx)
  jne    L24
  cmp    $0x1,%ebp
  je     L10
  mov    $0x1,%ebp
  jmp    L48
  cs nopw 0x0(%rax,%rax,1)
L36:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L10:
  movb   $0x0,-0x1(%rbx)
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strlen@plt>
```

tool_calls: name: read_data
arguments: label: D8
type: string

tool: D8: 


assistant: ```c
int recv_new(int fd, char *buffer) {
  char *p = buffer;
  int eol_matched = 0;
  while (recv(fd, p, 1, 0) != 0) {
    if (*p == "\r\n"[eol_matched]) {
      ++eol_matched;
      if (eol_matched == 2) {
        *(p + 1 - 2) = '\0';
        return (strlen(buffer));
      }
    } else {
      eol_matched = 0;
    }
    p++;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<getcwd_no_buf_no_check_bad>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <getcwd@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  movzbl -0x9(%rbp),%eax
  leave
  ret
```

assistant: ```c
char getcwd_no_buf_no_check_bad() {
  char *cwd = getcwd(NULL, 0);
  char result = cwd[0];
  free(cwd);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<getcwd_no_buf_no_check_bad>:
  endbr64
  push   %rbx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <getcwd@plt>
  mov    %rax,%rdi
  movzbl (%rax),%ebx
  call   <free@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char getcwd_no_buf_no_check_bad() {
  char *cwd = getcwd(NULL, 0);
  char result = cwd[0];
  free(cwd);
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getcwd_no_buf_no_check_bad>:
  endbr64
  push   %r12
  xor    %esi,%esi
  xor    %edi,%edi
  call   <getcwd@plt>
  movzbl (%rax),%r12d
  mov    %rax,%rdi
  call   <free@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char getcwd_no_buf_no_check_bad() {
  char *cwd = getcwd(NULL, 0);
  char result = cwd[0];
  free(cwd);
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__str_reverse__>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L0
L2:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x8(%rbp)
  subl   $0x1,-0x4(%rbp)
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __str_reverse__(char str[], ssize_t len) {
  for (int i = 0, j = len - 1; i < j; ++i, --j) {
    char tmp = str[i];
    str[i] = str[j];
    str[j] = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__str_reverse__>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L8
  movslq %esi,%rsi
  mov    $0x0,%eax
L18:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%rdi,%rsi,1),%ecx
  mov    %cl,(%rdi,%rax,1)
  mov    %dl,(%rdi,%rsi,1)
  add    $0x1,%rax
  sub    $0x1,%rsi
  cmp    %esi,%eax
  jl     L18
L8:
  ret
```

assistant: ```c
void __str_reverse__(char str[], ssize_t len) {
  for (int i = 0, j = len - 1; i < j; ++i, --j) {
    char tmp = str[i];
    str[i] = str[j];
    str[j] = tmp;
  }
}
```