user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r14
  lea    D3(%rip),%rdi
  lea    D32(%rip),%r14
  push   %r13
  lea    D12(%rip),%r13
  push   %r12
  lea    D65(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D64(%rip),%rdi
  call   <scanf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L59
  nopl   0x0(%rax,%rax,1)
L139:
  mov    $0x1,%ebx
  jmp    L149
  nopw   0x0(%rax,%rax,1)
L32:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%edx
  cmp    %ebx,%edx
  jle    L23
L149:
  mov    %eax,%edx
  sub    %ebp,%edx
  add    $0x1,%edx
  cmp    %ebx,%edx
  je     L124
  lea    -0x1(%rax,%rbp,1),%eax
  cmp    %ebx,%eax
  jne    L32
L124:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%edx
  cmp    %ebx,%edx
  jg     L149
L23:
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  cmp    %ebp,%eax
  jge    L139
L59:
  lea    0x1(%rax),%ebp
  lea    (%rax,%rax,1),%edx
  lea    D12(%rip),%r13
  lea    D65(%rip),%r12
  lea    D32(%rip),%r14
  cmp    %edx,%ebp
  jge    L77
  nopl   0x0(%rax)
L154:
  lea    (%rax,%rax,1),%edx
  mov    $0x1,%ebx
  cmp    $0x1,%edx
  jg     L17
  jmp    L152
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %r14,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%edx
  cmp    %ebx,%edx
  jle    L152
L17:
  mov    %ebp,%edx
  sub    %eax,%edx
  add    $0x1,%edx
  cmp    %ebx,%edx
  je     L89
  lea    (%rax,%rax,2),%eax
  sub    %ebp,%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  jne    L18
L89:
  mov    %r12,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%edx
  cmp    %ebx,%edx
  jg     L17
L152:
  mov    %r13,%rdi
  add    $0x1,%ebp
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  lea    (%rax,%rax,1),%edx
  cmp    %ebp,%edx
  jg     L154
L77:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L123
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L123:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type: string
name: unpack_data
arguments: data_tag: D32
type: string
name: unpack_data
arguments: data_tag: D12
type: string
name: unpack_data
arguments: data_tag: D65
type: string
name: unpack_data
arguments: data_tag: D64
type: string
name: unpack_data
arguments: data_tag: D7
type: string

tool: D3: Please input an integer:

tool: D32:  

tool: D12: 


tool: D65: *

tool: D64: %d

tool: D7: The result is:


assistant: ```c
int main() {
  int n, i, j;
  printf("Please input an integer:");
  scanf("%d", &n);
  printf("The result is:\n");
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= 2 * n - 1; j++)
      if (j == n - i + 1 || j == n + i - 1)
        printf("*");
      else
        printf(" ");
    printf("\n");
  }
  for (i = n + 1; i <= 2 * n - 1; i++) {
    for (j = 1; j <= 2 * n - 1; j++)
      if (j == i - n + 1 || j == 3 * n - i - 1)
        printf("*");
      else
        printf(" ");
    printf("\n");
  }
  return 0;
}
```