user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x7a1000(%rsp),%r11
L49:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L49
  sub    $0x238,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7a1228(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r13
  mov    %r13,%rsi
  mov    $0x3e8,%ecx
L3:
  lea    -0x3e8(%rcx),%eax
  mov    %rsi,%rdx
L59:
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,(%rdx)
  add    $0x1,%eax
  add    $0x8,%rdx
  cmp    %ecx,%eax
  jne    L59
  add    $0x1f40,%rsi
  add    $0xa,%ecx
  cmp    $0x2af8,%ecx
  jne    L3
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  lea    0x79f2c0(%r13),%r15
  mov    %r13,%r14
  jmp    L19
L114:
  add    $0x8,%rbp
  cmp    %r12,%rbp
  je     L61
L88:
  mov    $0x64,%ebx
L63:
  movsd  D2(%rip),%xmm0
  mulsd  0x1f48(%rbp),%xmm0
  call   <sin@plt>
  movsd  %xmm0,0x0(%rbp)
  sub    $0x1,%ebx
  jne    L63
  jmp    L114
L61:
  add    $0x1f40,%r14
  cmp    %r15,%r14
  je     L4
L19:
  mov    %r14,%rbp
  lea    0x1f38(%r14),%r12
  jmp    L88
L4:
  lea    0x10(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    0x10(%rsp),%rax
  sub    (%rsp),%rax
  imul   $0x3e8,%rax,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    0x18(%rsp),%rax
  sub    0x8(%rsp),%rax
  pxor   %xmm1,%xmm1
  cvtsi2sd %rax,%xmm1
  divsd  D8(%rip),%xmm1
  addsd  %xmm1,%xmm0
  lea    D46(%rip),%rdi
  call   <printf@plt>
  lea    D31(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  lea    0x1f40(%r13),%r12
  add    $0x7a3140,%r13
  lea    D40(%rip),%r14
L53:
  lea    -0x1f40(%r12),%rbx
L69:
  movsd  (%rbx),%xmm0
  mov    %r14,%rsi
  mov    %rbp,%rdi
  mov    $0x1,%eax
  call   <fprintf@plt>
  add    $0x8,%rbx
  cmp    %rbx,%r12
  jne    L69
  mov    %rbp,%rsi
  mov    $0xa,%edi
  call   <fputc@plt>
  add    $0x1f40,%r12
  cmp    %r12,%r13
  jne    L53
  mov    %rbp,%rdi
  call   <fclose@plt>
  mov    0x7a1228(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x7a1238,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: f64
name: parse_data
arguments: data_tag: D8
datatype: f64
name: parse_data
arguments: data_tag: D46
datatype: string
name: parse_data
arguments: data_tag: D31
datatype: string
name: parse_data
arguments: data_tag: D13
datatype: string
name: parse_data
arguments: data_tag: D40
datatype: string

tool: D2: 1e-05

tool: D8: 1000

tool: D46: %.6lf


tool: D31: w

tool: D13: 6.out

tool: D40: %f 

assistant: ```c
int main(int argc, char **argv) {
  double a[1000][1000];
  int i, j;
  FILE *ff;
  for (i = 0; i < 1000; ++i) {
    for (j = 0; j < 1000; ++j) {
      a[i][j] = 10 * i + j;
    }
  }
  double timeElapsed = 0.0;
  do {
    struct timeval timeElapsed_start, timeElapsed_end;
    long timeElapsed_seconds, timeElapsed_useconds;
    gettimeofday(&timeElapsed_start, NULL);
    {
      for (int i = 0; i < 1000 - 1; ++i) {
        for (int j = 0; j < 1000 - 1; ++j) {
          for (int k = 0; k < 100; k++)
            a[i][j] = sin(0.00001 * a[i + 1][j + 1]);
        }
      }
    }
    gettimeofday(&timeElapsed_end, NULL);
    timeElapsed_seconds = timeElapsed_end.tv_sec - timeElapsed_start.tv_sec;
    timeElapsed_useconds = timeElapsed_end.tv_usec - timeElapsed_start.tv_usec;
    timeElapsed = (timeElapsed_seconds * 1000 + timeElapsed_useconds / 1000.0);
  } while (0);
  printf("%.6lf\n", timeElapsed);
  ff = fopen("6.out", "w");
  for (i = 0; i < 1000; ++i) {
    for (j = 0; j < 1000; ++j) {
      fprintf(ff, "%f ", a[i][j]);
    }
    fprintf(ff, "\n");
  }
  fclose(ff);
  return 0;
}
```