user: 请从给定的汇编指令推导出C源代码：

```asm
<questions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <randomize@plt>
  jmp    L119
L10:
  mov    $0x14,%esi
  mov    $0x1,%edi
  call   <randomInteger@plt>
  mov    %eax,-0x20(%rbp)
  mov    $0x14,%esi
  mov    $0x1,%edi
  call   <randomInteger@plt>
  mov    %eax,-0x1c(%rbp)
  mov    D12(%rip),%rax
  movq   %rax,%xmm0
  call   <randomChance@plt>
  mov    %eax,-0x18(%rbp)
  movl   $0x1,-0x28(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  je     L173
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  jmp    L18
L173:
  mov    -0x20(%rbp),%eax
  sub    -0x1c(%rbp),%eax
L18:
  mov    %eax,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L119
  cmpl   $0x13,-0x14(%rbp)
  jg     L119
  cmpl   $0x0,-0x18(%rbp)
  je     L64
  lea    D78(%rip),%rax
  jmp    L113
L64:
  lea    D47(%rip),%rax
L113:
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%esi
  mov    %edx,%ecx
  mov    %rax,%rdx
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L135
L151:
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    %eax,-0x10(%rbp)
  nop
L169:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xa,-0xc(%rbp)
  jne    L169
  cmpl   $0x2,-0x24(%rbp)
  jne    L2
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  subl   $0x1,-0x34(%rbp)
  jmp    L119
L2:
  cmpl   $0x0,-0x10(%rbp)
  je     L153
  mov    -0x2c(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  jne    L141
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <sayCorrect@plt>
  movl   $0x0,-0x28(%rbp)
  subl   $0x1,-0x34(%rbp)
  jmp    L135
L141:
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
  jmp    L135
L153:
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L135:
  cmpl   $0x0,-0x28(%rbp)
  jne    L151
L119:
  cmpl   $0x0,-0x34(%rbp)
  jne    L10
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L58
  call   <__stack_chk_fail@plt>
L58:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_infered: f64
name: extract_symbolic_data
arguments: tag: D78
type_infered: string
name: extract_symbolic_data
arguments: tag: D47
type_infered: string
name: extract_symbolic_data
arguments: tag: D1
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D62
type_infered: string
name: extract_symbolic_data
arguments: tag: D65
type_infered: string

tool: D12: 0.5

tool: D78: +

tool: D47: -

tool: D1: What is %d %s %d? 

tool: D4: %d

tool: D62: No, the answer is %d.


tool: D65: That's incorrect. Try a different answer: 

assistant: ```c
void questions(int times) {
  randomize();
  int x, y, sum, answer, correct, loop;
  int op;
  int ref, c;
  while (times) {
    x = randomInteger(1, 20);
    y = randomInteger(1, 20);
    op = randomChance(0.5);
    correct = 1;
    sum = (op) ? x + y : x - y;
    loop = 0;
    if (sum > 0 && sum < 20) {
      printf("What is %d %s %d? ", x, (op) ? "+" : "-", y);
      while (correct) {
        ref = scanf("%d", &answer);
        while ((c = getchar()) != '\n')
          ;
        if (loop == 2) {
          printf("No, the answer is %d.\n", sum);
          times--;
          break;
        }
        if (ref != 0) {
          if (answer == sum) {
            sayCorrect(sum);
            correct = 0;
            times--;
          } else {
            printf("That's incorrect. Try a different answer: ");
            loop++;
          }
        } else {
          printf("That's incorrect. Try a different answer: ");
          loop++;
        }
      }
    }
  }
}
```