ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wildmatch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%r13
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L27
  mov    %rdi,%r12
  mov    %edx,%r14d
  lea    0x1(%rsi),%rbx
  jmp    L3
L31:
  lea    0x1(%r12),%rdi
  mov    %r14d,%edx
  call   <wildmatch>
  test   %eax,%eax
  jne    L6
  mov    %rbx,%r13
  cmpb   $0x0,-0x1(%rbx)
  je     L82
L101:
  movzbl (%r12),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L27
L3:
  lea    -0x1(%rbx),%rsi
  cmp    $0x2a,%bpl
  je     L31
  cmp    $0x3f,%bpl
  jne    L37
  mov    %rbx,%r13
  cmpb   $0x0,-0x1(%rbx)
  je     L86
  add    $0x1,%r12
  jmp    L101
L37:
  mov    %rbx,%r13
  movzbl -0x1(%rbx),%edi
  test   %dil,%dil
  je     L52
  test   %r14d,%r14d
  jne    L112
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %eax,%r15d
  add    $0x1,%r12
  movsbl %bpl,%edi
  call   <tolower@plt>
  cmp    %eax,%r15d
  je     L101
  mov    %r14d,%eax
  jmp    L82
L112:
  add    $0x1,%r12
  cmp    %bpl,%dil
  je     L101
  mov    $0x0,%eax
  jmp    L82
L27:
  cmpb   $0x0,0x0(%r13)
  sete   %al
  movzbl %al,%eax
L82:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L86:
  mov    $0x0,%eax
  jmp    L82
L6:
  mov    $0x1,%eax
  jmp    L82
L52:
  mov    $0x0,%eax
  jmp    L82
```

assistant: ```c
bool wildmatch(const char *wildcard, const char *str, bool casesensitive) {
  while (*wildcard != '\0') {
    switch (*wildcard) {
    case '?':
      if (*str++ == '\0')
        return false;
      wildcard += 1;
      break;
    case '*':
      if (wildmatch(&wildcard[1], str, casesensitive))
        return true;
      if (*str++ == '\0')
        return false;
      break;
    default:
      if (*str == '\0')
        return false;
      if (!casesensitive) {
        if (tolower(*str++) != tolower(*wildcard++))
          return false;
      } else {
        if (*str++ != *wildcard++)
          return false;
      }
      break;
    }
  }
  return *str == '\0';
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<wildmatch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rdi),%ebp
  test   %bpl,%bpl
  je     L50
  mov    %rdi,%r12
  mov    %edx,%r15d
  lea    0x1(%rsi),%rbx
  jmp    L137
  nopl   (%rax)
L39:
  cmpb   $0x0,-0x1(%rbx)
  je     L113
  add    $0x1,%r12
L24:
  movzbl (%r12),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  je     L50
L137:
  lea    -0x1(%rbx),%rsi
  cmp    $0x2a,%bpl
  je     L14
  mov    %rbx,%r13
  cmp    $0x3f,%bpl
  je     L39
  movsbl -0x1(%rbx),%edi
  test   %dil,%dil
  je     L113
  add    $0x1,%r12
  test   %r15d,%r15d
  jne    L11
  call   <tolower@plt>
  movsbl %bpl,%edi
  mov    %eax,%r14d
  call   <tolower@plt>
  cmp    %eax,%r14d
  je     L24
  nopl   0x0(%rax,%rax,1)
L113:
  xor    %eax,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L11:
  cmp    %bpl,%dil
  jne    L113
  movzbl (%r12),%ebp
  add    $0x1,%rbx
  test   %bpl,%bpl
  jne    L137
L50:
  xor    %eax,%eax
  cmpb   $0x0,0x0(%r13)
  sete   %al
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L14:
  lea    0x1(%r12),%rdi
  mov    %r15d,%edx
  call   <wildmatch>
  test   %eax,%eax
  jne    L6
  cmpb   $0x0,-0x1(%rbx)
  mov    %rbx,%r13
  jne    L24
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  mov    $0x1,%eax
  jmp    L15
```

assistant: ```c
bool wildmatch(const char *wildcard, const char *str, bool casesensitive) {
  while (*wildcard != '\0') {
    switch (*wildcard) {
    case '?':
      if (*str++ == '\0')
        return false;
      wildcard += 1;
      break;
    case '*':
      if (wildmatch(&wildcard[1], str, casesensitive))
        return true;
      if (*str++ == '\0')
        return false;
      break;
    default:
      if (*str == '\0')
        return false;
      if (!casesensitive) {
        if (tolower(*str++) != tolower(*wildcard++))
          return false;
      } else {
        if (*str++ != *wildcard++)
          return false;
      }
      break;
    }
  }
  return *str == '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wildmatch>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L49
  mov    %rdi,%rbp
  mov    %edx,%r14d
  lea    0x1(%rsi),%r12
  test   %edx,%edx
  je     L214
  lea    -0x1(%r12),%rsi
  cmp    $0x2a,%bl
  jne    L43
  nopw   0x0(%rax,%rax,1)
L36:
  lea    0x1(%rbp),%rdi
  mov    %r14d,%edx
  call   <wildmatch>
  test   %eax,%eax
  jne    L185
  cmpb   $0x0,-0x1(%r12)
  mov    %r12,%r13
  je     L37
  movzbl 0x0(%rbp),%ebx
  add    $0x1,%r12
  test   %bl,%bl
  jne    L80
L49:
  xor    %eax,%eax
  cmpb   $0x0,0x0(%r13)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L65:
  movzbl -0x1(%r12),%eax
  test   %al,%al
  je     L129
  add    $0x1,%rbp
  cmp    %al,%bl
  jne    L129
L174:
  movzbl 0x0(%rbp),%ebx
  add    $0x1,%r12
  test   %bl,%bl
  je     L49
L80:
  lea    -0x1(%r12),%rsi
  cmp    $0x2a,%bl
  je     L36
L43:
  mov    %r12,%r13
  cmp    $0x3f,%bl
  jne    L65
  cmpb   $0x0,-0x1(%r12)
  je     L129
  add    $0x1,%rbp
  jmp    L174
  cs nopw 0x0(%rax,%rax,1)
L204:
  cmpb   $0x0,-0x1(%r12)
  je     L129
  add    $0x1,%rbp
L175:
  movzbl 0x0(%rbp),%ebx
  add    $0x1,%r12
  test   %bl,%bl
  je     L49
L214:
  lea    -0x1(%r12),%rsi
  cmp    $0x2a,%bl
  je     L178
  mov    %r12,%r13
  cmp    $0x3f,%bl
  je     L204
  movsbl -0x1(%r12),%edi
  test   %dil,%dil
  je     L129
  call   <tolower@plt>
  movsbl %bl,%edi
  add    $0x1,%rbp
  mov    %eax,%r14d
  call   <tolower@plt>
  cmp    %eax,%r14d
  je     L175
  nopw   0x0(%rax,%rax,1)
L129:
  xor    %eax,%eax
L37:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L178:
  xor    %edx,%edx
  lea    0x1(%rbp),%rdi
  call   <wildmatch>
  test   %eax,%eax
  jne    L185
  cmpb   $0x0,-0x1(%r12)
  mov    %r12,%r13
  jne    L175
  jmp    L37
L185:
  mov    $0x1,%eax
  jmp    L37
```

assistant: ```c
bool wildmatch(const char *wildcard, const char *str, bool casesensitive) {
  while (*wildcard != '\0') {
    switch (*wildcard) {
    case '?':
      if (*str++ == '\0')
        return false;
      wildcard += 1;
      break;
    case '*':
      if (wildmatch(&wildcard[1], str, casesensitive))
        return true;
      if (*str++ == '\0')
        return false;
      break;
    default:
      if (*str == '\0')
        return false;
      if (!casesensitive) {
        if (tolower(*str++) != tolower(*wildcard++))
          return false;
      } else {
        if (*str++ != *wildcard++)
          return false;
      }
      break;
    }
  }
  return *str == '\0';
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_utoa_base>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  cmpl   $0x1,-0x2c(%rbp)
  jle    L46
  cmpl   $0x23,-0x2c(%rbp)
  jle    L38
L46:
  mov    $0x0,%eax
  jmp    L20
L15:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
L38:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <ft_power@plt>
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,%rdx
  mov    -0x10(%rbp),%eax
  cltq
  cmp    %rax,%rdx
  jae    L15
  mov    -0xc(%rbp),%eax
  add    $0x2,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movswl -0x30(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  lea    -0x10(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ft_utoa_base_p2@plt>
  mov    -0x18(%rbp),%rax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
char *ft_utoa_base(unsigned long nb, int base, short min) {
  int vals[2];
  char *str;
  vals[0] = base;
  vals[1] = 0;
  if (base < 2 || base > 35)
    return ((void *)0);
  while (nb / ft_power(vals[0], vals[1]) >= (unsigned long)vals[0])
    vals[1]++;
  str = (char *)malloc(vals[1] + 2);
  ft_utoa_base_p2(str, &vals[0], nb, min);
  return (str);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ft_utoa_base>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %esi,(%rsp)
  movl   $0x0,0x4(%rsp)
  sub    $0x2,%esi
  cmp    $0x21,%esi
  jbe    L13
  mov    $0x0,%r12d
  jmp    L23
L39:
  addl   $0x1,0x4(%rsp)
L13:
  mov    0x4(%rsp),%esi
  mov    (%rsp),%edi
  mov    $0x0,%eax
  call   <ft_power@plt>
  movslq %eax,%rcx
  mov    %rbx,%rax
  mov    $0x0,%edx
  div    %rcx
  movslq (%rsp),%rdx
  cmp    %rdx,%rax
  jae    L39
  mov    0x4(%rsp),%eax
  lea    0x2(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  movswl %bp,%ecx
  mov    %rsp,%rsi
  mov    %rbx,%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <ft_utoa_base_p2@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ft_utoa_base(unsigned long nb, int base, short min) {
  int vals[2];
  char *str;
  vals[0] = base;
  vals[1] = 0;
  if (base < 2 || base > 35)
    return ((void *)0);
  while (nb / ft_power(vals[0], vals[1]) >= (unsigned long)vals[0])
    vals[1]++;
  str = (char *)malloc(vals[1] + 2);
  ft_utoa_base_p2(str, &vals[0], nb, min);
  return (str);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_utoa_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rsi),%eax
  mov    %esi,(%rsp)
  movl   $0x0,0x4(%rsp)
  cmp    $0x21,%eax
  ja     L32
  mov    %rdi,%r12
  mov    %edx,%ebx
  mov    %esi,%edi
  xor    %esi,%esi
  jmp    L39
  nop
L20:
  lea    0x1(%rax),%esi
  mov    %esi,0x4(%rsp)
L39:
  xor    %eax,%eax
  call   <ft_power@plt>
  xor    %edx,%edx
  mov    (%rsp),%edi
  movslq %eax,%rcx
  mov    %r12,%rax
  div    %rcx
  movslq %edi,%rdx
  cmp    %rdx,%rax
  mov    0x4(%rsp),%eax
  jae    L20
  lea    0x2(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  movswl %bx,%ecx
  mov    %rsp,%rsi
  mov    %r12,%rdx
  mov    %rax,%r13
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <ft_utoa_base_p2@plt>
L23:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L32:
  xor    %r13d,%r13d
  jmp    L23
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ft_utoa_base(unsigned long nb, int base, short min) {
  int vals[2];
  char *str;
  vals[0] = base;
  vals[1] = 0;
  if (base < 2 || base > 35)
    return ((void *)0);
  while (nb / ft_power(vals[0], vals[1]) >= (unsigned long)vals[0])
    vals[1]++;
  str = (char *)malloc(vals[1] + 2);
  ft_utoa_base_p2(str, &vals[0], nb, min);
  return (str);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_utoa_base>:
  endbr64
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    -0x2(%rsi),%eax
  mov    %esi,(%rsp)
  movl   $0x0,0x4(%rsp)
  cmp    $0x21,%eax
  ja     L35
  mov    %rdi,%r12
  mov    %edx,%ebx
  mov    %esi,%edi
  xor    %esi,%esi
  jmp    L8
  nop
L20:
  lea    0x1(%rax),%esi
  mov    %esi,0x4(%rsp)
L8:
  xor    %eax,%eax
  call   <ft_power@plt>
  xor    %edx,%edx
  mov    (%rsp),%edi
  movslq %eax,%rcx
  mov    %r12,%rax
  div    %rcx
  movslq %edi,%rdx
  cmp    %rdx,%rax
  mov    0x4(%rsp),%eax
  jae    L20
  lea    0x2(%rax),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  movswl %bx,%ecx
  mov    %rsp,%rsi
  mov    %r12,%rdx
  mov    %rax,%r13
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <ft_utoa_base_p2@plt>
L49:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x10,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L35:
  xor    %r13d,%r13d
  jmp    L49
L28:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *ft_utoa_base(unsigned long nb, int base, short min) {
  int vals[2];
  char *str;
  vals[0] = base;
  vals[1] = 0;
  if (base < 2 || base > 35)
    return ((void *)0);
  while (nb / ft_power(vals[0], vals[1]) >= (unsigned long)vals[0])
    vals[1]++;
  str = (char *)malloc(vals[1] + 2);
  ft_utoa_base_p2(str, &vals[0], nb, min);
  return (str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<put64bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  shl    %cl,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  and    $0xff000000,%eax
  or     %eax,%edx
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  and    $0xff0000,%eax
  mov    %edx,%esi
  or     %eax,%esi
  mov    -0xc(%rbp),%eax
  mov    $0x28,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  and    $0xff00,%eax
  or     %eax,%esi
  mov    -0xc(%rbp),%eax
  mov    $0x38,%edx
  mov    %edx,%ecx
  sar    %cl,%eax
  movzbl %al,%eax
  or     %esi,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    -0xc(%rbp),%rcx
  mov    $0x8,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x20(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void put64bit(uint8_t **ptr, uint64_t val) {
  val = ((((val) << 56) & 0xFF00000000000000) | (((val) << 40) & 0xFF000000000000) | (((val) << 24) & 0xFF0000000000) | (((val) << 8) & 0xFF00000000) | (((val) >> 8) & 0xFF000000) | (((val) >> 24) & 0xFF0000) | (((val) >> 40) & 0xFF00) | (((val) >> 56) & 0xFF));
  memcpy(*ptr, &val, 8);
  (*ptr) += 8;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<put64bit>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %esi,%eax
  sar    $0x8,%eax
  and    $0xff000000,%eax
  mov    %esi,%edx
  sar    $0x18,%edx
  and    $0xff0000,%edx
  or     %edx,%eax
  mov    %esi,%edx
  mov    $0x28,%ecx
  sar    %cl,%edx
  and    $0xff00,%edx
  or     %edx,%eax
  mov    $0x38,%ecx
  sar    %cl,%esi
  movzbl %sil,%esi
  or     %esi,%eax
  mov    %eax,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  mov    $0x8,%edx
  mov    (%rdi),%rdi
  call   <memcpy@plt>
  addq   $0x20,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void put64bit(uint8_t **ptr, uint64_t val) {
  val = ((((val) << 56) & 0xFF00000000000000) | (((val) << 40) & 0xFF000000000000) | (((val) << 24) & 0xFF0000000000) | (((val) << 8) & 0xFF00000000) | (((val) >> 8) & 0xFF000000) | (((val) >> 24) & 0xFF0000) | (((val) >> 40) & 0xFF00) | (((val) >> 56) & 0xFF));
  memcpy(*ptr, &val, 8);
  (*ptr) += 8;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<put64bit>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  push   %rbx
  mov    $0x28,%ecx
  sar    $0x8,%eax
  sar    $0x18,%edx
  mov    %rdi,%rbx
  and    $0xff0000,%edx
  and    $0xff000000,%eax
  or     %edx,%eax
  mov    %esi,%edx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  sar    %cl,%edx
  mov    $0x38,%ecx
  and    $0xff00,%edx
  sar    %cl,%esi
  or     %edx,%eax
  movzbl %sil,%esi
  mov    $0x8,%edx
  or     %esi,%eax
  lea    0xc(%rsp),%rsi
  mov    %eax,0xc(%rsp)
  call   <memcpy@plt>
  addq   $0x20,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void put64bit(uint8_t **ptr, uint64_t val) {
  val = ((((val) << 56) & 0xFF00000000000000) | (((val) << 40) & 0xFF000000000000) | (((val) << 24) & 0xFF0000000000) | (((val) << 8) & 0xFF00000000) | (((val) >> 8) & 0xFF000000) | (((val) >> 24) & 0xFF0000) | (((val) >> 40) & 0xFF00) | (((val) >> 56) & 0xFF));
  memcpy(*ptr, &val, 8);
  (*ptr) += 8;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<put64bit>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  push   %rbx
  mov    $0x28,%ecx
  sar    $0x8,%eax
  sar    $0x18,%edx
  mov    %rdi,%rbx
  and    $0xff0000,%edx
  and    $0xff000000,%eax
  or     %edx,%eax
  mov    %esi,%edx
  sub    $0x10,%rsp
  mov    (%rdi),%rdi
  sar    %cl,%edx
  mov    $0x38,%ecx
  and    $0xff00,%edx
  sar    %cl,%esi
  or     %edx,%eax
  movzbl %sil,%esi
  mov    $0x8,%edx
  or     %esi,%eax
  lea    0xc(%rsp),%rsi
  mov    %eax,0xc(%rsp)
  call   <memcpy@plt>
  addq   $0x20,(%rbx)
  add    $0x10,%rsp
  pop    %rbx
  ret
```

assistant: ```c
void put64bit(uint8_t **ptr, uint64_t val) {
  val = ((((val) << 56) & 0xFF00000000000000) | (((val) << 40) & 0xFF000000000000) | (((val) << 24) & 0xFF0000000000) | (((val) << 8) & 0xFF00000000) | (((val) >> 8) & 0xFF000000) | (((val) >> 24) & 0xFF0000) | (((val) >> 40) & 0xFF00) | (((val) >> 56) & 0xFF));
  memcpy(*ptr, &val, 8);
  (*ptr) += 8;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pack_int_double_plus_7>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L7:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  D4(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L7
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

assistant: ```c
void __attribute__((no, noclone)) pack_int_double_plus_7(uint32_t *d, double *s, int size) {
  for (int i = 0; i < size; i++)
    d[i] = s[i] + 7;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pack_int_double_plus_7>:
  endbr64
  test   %edx,%edx
  jle    L9
  mov    %edx,%edx
  mov    $0x0,%eax
  movsd  D7(%rip),%xmm1
L17:
  movapd %xmm1,%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L17
L9:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

assistant: ```c
void __attribute__((no, noclone)) pack_int_double_plus_7(uint32_t *d, double *s, int size) {
  for (int i = 0; i < size; i++)
    d[i] = s[i] + 7;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pack_int_double_plus_7>:
  endbr64
  test   %edx,%edx
  jle    L11
  movsd  D7(%rip),%xmm1
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L19:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L19
L11:
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: byte[8]

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

assistant: ```c
void __attribute__((no, noclone)) pack_int_double_plus_7(uint32_t *d, double *s, int size) {
  for (int i = 0; i < size; i++)
    d[i] = s[i] + 7;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pack_int_double_plus_7>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L24
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L26
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L26
  mov    %edx,%edi
  movapd D0(%rip),%xmm1
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  nopw   0x0(%rax,%rax,1)
L18:
  movupd (%rsi,%rax,1),%xmm0
  addpd  %xmm1,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L18
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L24
  movsd  D0(%rip),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  movsd  D0(%rip),%xmm1
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L20:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L20
L24:
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: byte[16]

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40,0x00,0x00,0x00,0x00,0x00,0x00,0x1c,0x40]}

assistant: ```c
void __attribute__((no, noclone)) pack_int_double_plus_7(uint32_t *d, double *s, int size) {
  for (int i = 0; i < size; i++)
    d[i] = s[i] + 7;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<emit_slti32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  je     L3
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <emit_zeroreg@plt>
L3:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <emit_cmpimm@plt>
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L10
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x0,%edi
  call   <emit_movimm@plt>
L10:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <emit_cmovl_imm@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_slti32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_cmovl_imm(1, rt);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<emit_slti32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %esi,%r12d
  mov    %edx,%ebx
  cmp    %edx,%edi
  jne    L18
  call   <emit_cmpimm@plt>
  mov    %ebx,%esi
  mov    $0x0,%edi
  call   <emit_movimm@plt>
  jmp    L10
L18:
  mov    %edx,%edi
  call   <emit_zeroreg@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <emit_cmpimm@plt>
L10:
  mov    %ebx,%esi
  mov    $0x1,%edi
  call   <emit_cmovl_imm@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void emit_slti32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_cmovl_imm(1, rt);
}
```
user: What is the c source code of the assembly code below?

```asm
<emit_slti32>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  cmp    %edx,%edi
  jne    L3
  mov    %edx,%edi
  call   <emit_cmpimm@plt>
  mov    %ebp,%esi
  xor    %edi,%edi
  call   <emit_movimm@plt>
L16:
  mov    %ebp,%esi
  mov    $0x1,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10a0 <emit_cmovl_imm@plt>
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edi,%r12d
  mov    %edx,%edi
  call   <emit_zeroreg@plt>
  mov    %r13d,%esi
  mov    %r12d,%edi
  call   <emit_cmpimm@plt>
  jmp    L16
```

assistant: ```c
void emit_slti32(int rs, int imm, int rt) {
  if (rs != rt)
    emit_zeroreg(rt);
  emit_cmpimm(rs, imm);
  if (rs == rt)
    emit_movimm(0, rt);
  emit_cmovl_imm(1, rt);
}
```