ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<trimmer>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  cmpb   $0x30,(%rdi)
  movslq %ecx,%rbx
  je     L112
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    $0x2,%eax
  jle    L79
  lea    -0x2(%rax),%esi
  cmp    $0x3,%eax
  je     L45
  movq   D8(%rip),%xmm0
  mov    %esi,%ecx
  xor    %edx,%edx
  shr    %ecx
  nopl   (%rax)
L113:
  movdqa %xmm0,%xmm1
  add    $0x1,%edx
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %ecx,%edx
  jne    L113
  movd   %xmm0,%edx
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%ecx
  imul   %ecx,%edx
  and    $0x1,%esi
  je     L109
L74:
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
L109:
  sub    $0x1,%eax
  mov    %rbp,%rcx
  xor    %esi,%esi
  mov    $0xcccccccd,%r8d
  lea    0x1(%rbp,%rax,1),%rdi
  xchg   %ax,%ax
L84:
  movzbl (%rcx),%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L87
  movsbl %al,%eax
  imul   %edx,%eax
  mov    %edx,%edx
  imul   %r8,%rdx
  add    %eax,%esi
  shr    $0x23,%rdx
L87:
  add    $0x1,%rcx
  cmp    %rcx,%rdi
  jne    L84
  mov    %esi,(%r12,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L112:
  mov    %rbp,%rax
  add    $0x1,%rbp
  cmpb   $0x30,0x1(%rax)
  jne    L25
  mov    %rbp,%rax
  add    $0x1,%rbp
  cmpb   $0x30,0x1(%rax)
  je     L112
  jmp    L25
  nopl   0x0(%rax)
L79:
  test   %eax,%eax
  jg     L127
  xor    %esi,%esi
  mov    %esi,(%r12,%rbx,4)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L45:
  mov    $0x1,%edx
  jmp    L74
L127:
  mov    $0x1,%edx
  jmp    L109
```

tool_calls: name: parse_data
arguments: data_label: D8
type_guessed: byte[8]

tool: {"D8": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void trimmer(char *number, int dimensions_array[], int size, int position) {
  int i, count = 0, mul = 1;
  do
    if (number[0] == '0')
      number++;
  while (number[0] == '0');
  for (i = 2; i < (int)strlen(number); i++)
    mul *= 10;
  for (i = 0; i < (int)strlen(number); i++)
    if (number[i] >= '0' && number[i] <= '9') {
      count += (mul * (number[i] - 48));
      mul /= 10;
    }
  dimensions_array[position] = count;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<verify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L8
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L11
L8:
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L11:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D11
type_infered: string
name: read_data
arguments: tag: D16
type_infered: string

tool: D11:  PASS


tool: D16:  FAIL!


assistant: ```c
void verify(bool condition) {
  if (condition) {
    printf(" PASS\n");
  } else {
    printf(" FAIL!\n");
    exit(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<verify>:
  endbr64
  sub    $0x8,%rsp
  test   %edi,%edi
  je     L19
  lea    D12(%rip),%rdi
  call   <printf@plt>
L5:
  add    $0x8,%rsp
  ret
L19:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_label: D12
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D12:  PASS


tool: D15:  FAIL!


assistant: ```c
void verify(bool condition) {
  if (condition) {
    printf(" PASS\n");
  } else {
    printf(" FAIL!\n");
    exit(1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<verify>:
  endbr64
  test   %edi,%edi
  je     L1
  lea    D12(%rip),%rdi
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L1:
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D12
type_guessed: string
name: disassemble_data
arguments: tag: D9
type_guessed: string

tool: D12:  PASS


tool: D9:  FAIL!


assistant: ```c
void verify(bool condition) {
  if (condition) {
    printf(" PASS\n");
  } else {
    printf(" FAIL!\n");
    exit(1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<verify>:
  endbr64
  test   %edi,%edi
  je     L9
  lea    D18(%rip),%rdi
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L9:
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type_infered: string
name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D18:  PASS


tool: D3:  FAIL!


assistant: ```c
void verify(bool condition) {
  if (condition) {
    printf(" PASS\n");
  } else {
    printf(" FAIL!\n");
    exit(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<test_1_get_description>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D6(%rip),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D6
type: string

tool: D6: Create a directory named test_1_test_dir_pid, where pid is the process id.  Within that directory, create a big file (approx. half the file system in size), open it, and unlink it. Create many smaller files until the file system is full. Check the big file is ok. Delete all the smaller files. Check the big file again. Finally delete the big file and directory.

assistant: ```c
const char *test_1_get_description(void) {
  return "Create a directory named test_1_test_dir_pid, where "
         "pid is the process id.  Within that directory, "
         "create a big file (approx. half the file system in size), "
         "open it, and unlink it. "
         "Create many smaller files until the file system is full. "
         "Check the big file is ok. "
         "Delete all the smaller files. "
         "Check the big file again. "
         "Finally delete the big file and directory.";
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_1_get_description>:
  endbr64
  lea    D0(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D0: Create a directory named test_1_test_dir_pid, where pid is the process id.  Within that directory, create a big file (approx. half the file system in size), open it, and unlink it. Create many smaller files until the file system is full. Check the big file is ok. Delete all the smaller files. Check the big file again. Finally delete the big file and directory.

assistant: ```c
const char *test_1_get_description(void) {
  return "Create a directory named test_1_test_dir_pid, where "
         "pid is the process id.  Within that directory, "
         "create a big file (approx. half the file system in size), "
         "open it, and unlink it. "
         "Create many smaller files until the file system is full. "
         "Check the big file is ok. "
         "Delete all the smaller files. "
         "Check the big file again. "
         "Finally delete the big file and directory.";
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_1_get_description>:
  endbr64
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string

tool: D4: Create a directory named test_1_test_dir_pid, where pid is the process id.  Within that directory, create a big file (approx. half the file system in size), open it, and unlink it. Create many smaller files until the file system is full. Check the big file is ok. Delete all the smaller files. Check the big file again. Finally delete the big file and directory.

assistant: ```c
const char *test_1_get_description(void) {
  return "Create a directory named test_1_test_dir_pid, where "
         "pid is the process id.  Within that directory, "
         "create a big file (approx. half the file system in size), "
         "open it, and unlink it. "
         "Create many smaller files until the file system is full. "
         "Check the big file is ok. "
         "Delete all the smaller files. "
         "Check the big file again. "
         "Finally delete the big file and directory.";
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_1_get_description>:
  endbr64
  lea    D2(%rip),%rax
  ret
```

tool_calls: name: read_data
arguments: tag: D2
datatype: string

tool: D2: Create a directory named test_1_test_dir_pid, where pid is the process id.  Within that directory, create a big file (approx. half the file system in size), open it, and unlink it. Create many smaller files until the file system is full. Check the big file is ok. Delete all the smaller files. Check the big file again. Finally delete the big file and directory.

assistant: ```c
const char *test_1_get_description(void) {
  return "Create a directory named test_1_test_dir_pid, where "
         "pid is the process id.  Within that directory, "
         "create a big file (approx. half the file system in size), "
         "open it, and unlink it. "
         "Create many smaller files until the file system is full. "
         "Check the big file is ok. "
         "Delete all the smaller files. "
         "Check the big file again. "
         "Finally delete the big file and directory.";
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L28
  mov    $0x0,%eax
  jmp    L37
L28:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L34:
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L34
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
L37:
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char *str) {
  if (!str) {
    return 0;
  }
  char *ptr = str;
  while (*str) {
    ++str;
  }
  return str - ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<strlen>:
  endbr64
  test   %rdi,%rdi
  je     L3
  cmpb   $0x0,(%rdi)
  je     L9
  mov    %rdi,%rax
L2:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L2
L32:
  sub    %edi,%eax
  ret
L9:
  mov    %rdi,%rax
  jmp    L32
L3:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int strlen(char *str) {
  if (!str) {
    return 0;
  }
  char *ptr = str;
  while (*str) {
    ++str;
  }
  return str - ptr;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  test   %rdi,%rdi
  je     L8
  cmpb   $0x0,(%rdi)
  je     L8
  mov    %rdi,%rax
  nopl   0x0(%rax)
L1:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L1
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strlen(char *str) {
  if (!str) {
    return 0;
  }
  char *ptr = str;
  while (*str) {
    ++str;
  }
  return str - ptr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  test   %rdi,%rdi
  je     L11
  cmpb   $0x0,(%rdi)
  je     L11
  mov    %rdi,%rax
  nopl   0x0(%rax)
L9:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L9
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strlen(char *str) {
  if (!str) {
    return 0;
  }
  char *ptr = str;
  while (*str) {
    ++str;
  }
  return str - ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<util_strlcat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L61
L9:
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x18(%rbp)
L61:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jae    L20
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L9
L20:
  mov    -0x18(%rbp),%rax
  cmp    -0x38(%rbp),%rax
  jne    L55
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rax
  jmp    L63
L19:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  cmp    %rax,-0x38(%rbp)
  jbe    L54
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl -0x19(%rbp),%edx
  mov    %dl,(%rax)
L54:
  addq   $0x1,-0x18(%rbp)
L55:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  cmpb   $0x0,-0x19(%rbp)
  jne    L19
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L63:
  leave
  ret
```

assistant: ```c
size_t util_strlcat(char *dst, const char *src, size_t size) {
  size_t bytes = 0;
  char *q = dst;
  const char *p = src;
  char ch;
  while (bytes < size && *q) {
    q++;
    bytes++;
  }
  if (bytes == size)
    return (bytes + strlen(src));
  while ((ch = *p++)) {
    if (bytes + 1 < size)
      *q++ = ch;
    bytes++;
  }
  *q = '\0';
  return bytes;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<util_strlcat>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  mov    %rdx,%rbx
  mov    $0x0,%edx
  test   %rbx,%rbx
  je     L39
L94:
  cmpb   $0x0,(%rcx)
  je     L76
  add    $0x1,%rcx
  add    $0x1,%rdx
  cmp    %rdx,%rbx
  jne    L94
L39:
  call   <strlen@plt>
  add    %rbx,%rax
  jmp    L80
L76:
  cmp    %rdx,%rbx
  je     L9
  movzbl (%rdi),%r8d
  mov    %rdx,%rax
  sub    %rdx,%rdi
  test   %r8b,%r8b
  jne    L5
L21:
  movb   $0x0,(%rcx)
L80:
  pop    %rbx
  ret
L9:
  mov    %rdx,%rbx
  jmp    L39
L83:
  movzbl (%rdi,%rax,1),%r8d
  test   %r8b,%r8b
  je     L21
L5:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jae    L83
  mov    %r8b,(%rcx)
  lea    0x1(%rcx),%rcx
  jmp    L83
```

assistant: ```c
size_t util_strlcat(char *dst, const char *src, size_t size) {
  size_t bytes = 0;
  char *q = dst;
  const char *p = src;
  char ch;
  while (bytes < size && *q) {
    q++;
    bytes++;
  }
  if (bytes == size)
    return (bytes + strlen(src));
  while ((ch = *p++)) {
    if (bytes + 1 < size)
      *q++ = ch;
    bytes++;
  }
  *q = '\0';
  return bytes;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<util_strlcat>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L35
  jmp    L64
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x1,%rax
  add    $0x1,%rcx
  cmp    %rax,%rbx
  je     L64
L35:
  cmpb   $0x0,(%rcx)
  jne    L22
  movzbl (%rdi),%edx
  sub    %rax,%rdi
  test   %dl,%dl
  je     L69
  nopl   0x0(%rax)
L54:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jae    L1
  mov    %dl,(%rcx)
  add    $0x1,%rcx
L1:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L54
L69:
  movb   $0x0,(%rcx)
  pop    %rbx
  ret
  nopl   0x0(%rax)
L64:
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t util_strlcat(char *dst, const char *src, size_t size) {
  size_t bytes = 0;
  char *q = dst;
  const char *p = src;
  char ch;
  while (bytes < size && *q) {
    q++;
    bytes++;
  }
  if (bytes == size)
    return (bytes + strlen(src));
  while ((ch = *p++)) {
    if (bytes + 1 < size)
      *q++ = ch;
    bytes++;
  }
  *q = '\0';
  return bytes;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<util_strlcat>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rdx,%rbx
  mov    %rsi,%rdi
  xor    %eax,%eax
  test   %rdx,%rdx
  jne    L79
  jmp    L56
  nopw   0x0(%rax,%rax,1)
L32:
  add    $0x1,%rax
  add    $0x1,%rcx
  cmp    %rax,%rbx
  je     L56
L79:
  cmpb   $0x0,(%rcx)
  jne    L32
  movzbl (%rdi),%edx
  sub    %rax,%rdi
  test   %dl,%dl
  je     L34
  nopl   0x0(%rax)
L44:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jae    L24
  mov    %dl,(%rcx)
  movzbl (%rdi,%rax,1),%edx
  lea    0x1(%rcx),%rsi
  mov    %rsi,%rcx
  test   %dl,%dl
  jne    L44
L34:
  movb   $0x0,(%rcx)
L17:
  pop    %rbx
  ret
  nop
L24:
  movzbl (%rdi,%rax,1),%edx
  test   %dl,%dl
  jne    L44
  movb   $0x0,(%rcx)
  jmp    L17
  nopl   (%rax)
L56:
  call   <strlen@plt>
  add    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
size_t util_strlcat(char *dst, const char *src, size_t size) {
  size_t bytes = 0;
  char *q = dst;
  const char *p = src;
  char ch;
  while (bytes < size && *q) {
    q++;
    bytes++;
  }
  if (bytes == size)
    return (bytes + strlen(src));
  while ((ch = *p++)) {
    if (bytes + 1 < size)
      *q++ = ch;
    bytes++;
  }
  *q = '\0';
  return bytes;
}
```
user: What is the c source code of the assembly code below?

```asm
<multiply379>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L32
L31:
  movl   $0x0,-0x3c(%rbp)
  jmp    L16
L0:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L16:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L0
  addl   $0x1,-0x40(%rbp)
L32:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L31
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply379(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply379>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L22:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L9:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L9
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L22
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  ret
```

assistant: ```c
void multiply379(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<multiply379>:
  endbr64
  test   %edi,%edi
  jle    L11
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L29
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L12
  pop    %rbx
  ret
L11:
  ret
```

assistant: ```c
void multiply379(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply379>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L82
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L2:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L0
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L0
  nopl   0x0(%rax)
L81:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L81
  cmp    -0x24(%rsp),%r11d
  je     L34
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L34
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L34
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L34:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L2
L82:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L60:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L60
  mov    -0x18(%rsp),%r8
  jmp    L34
```

assistant: ```c
void multiply379(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  addl   $0x5,-0x4(%rbp)
  movl   $0x500,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L14:
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L6:
  cmpl   $0x7,-0x8(%rbp)
  jle    L14
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int res, res2 = 0;
#pragma acc parallel num_gangs(GANGS) copy(res2)
  {
#pragma acc atomic
    res2 += 5;
  }
  res = 256 * 5;
  assert(res == res2);
  res = res2 = 1;
#pragma acc parallel num_gangs(GANGS) copy(res2)
  {
#pragma acc atomic
    res2 *= 5;
  }
  for (int i = 0; i < 8; ++i)
    res *= 5;
  assert(res == res2);
  return 0;
}
```