ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<addBinary>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%ebx
  call   <strlen@plt>
  mov    $0x1,%esi
  cmp    %eax,%ebx
  mov    %eax,%edi
  mov    %eax,%ebp
  cmovge %ebx,%edi
  lea    0x1(%rdi),%r14d
  add    $0x2,%edi
  call   <calloc@plt>
  movslq %r14d,%rcx
  add    %rax,%rcx
  mov    %rax,%r8
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L14
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L34
  sub    $0x1,%ebx
  movslq %ebx,%rax
  movsbl 0x0(%r13,%rax,1),%eax
  sub    $0x30,%eax
L34:
  mov    %ebx,%esi
  test   %ebp,%ebp
  je     L47
  sub    $0x1,%ebp
  movslq %ebp,%rdx
  or     %ebp,%esi
  movsbl (%r12,%rdx,1),%edx
  lea    -0x30(%rax,%rdx,1),%eax
L47:
  add    -0x1(%rcx),%al
  sub    $0x1,%rcx
  mov    %eax,%edx
  shr    $0x7,%dl
  add    %eax,%edx
  sar    %dl
  mov    %dl,-0x1(%rcx)
  mov    %eax,%edx
  shr    $0x7,%dl
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  add    $0x30,%eax
  mov    %al,(%rcx)
  test   %esi,%esi
  jne    L1
L14:
  cmpb   $0x0,(%r8)
  je     L30
  movb   $0x31,(%r8)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L30:
  add    $0x1,%r8
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *addBinary(char *a, char *b) {
  int lengthA = strlen(a);
  int lengthB = strlen(b);
  int lengthSum = lengthA;
  if (lengthA < lengthB)
    lengthSum = lengthB;
  ++lengthSum;
  char *sum = calloc(lengthSum + 1, sizeof(char));
  while (lengthA || lengthB) {
    --lengthSum;
    sum[lengthSum] += (lengthA ? a[--lengthA] - '0' : 0) + (lengthB ? b[--lengthB] - '0' : 0);
    sum[lengthSum - 1] = sum[lengthSum] / 2;
    sum[lengthSum] %= 2;
    sum[lengthSum] += '0';
  }
  if (!sum[0])
    return sum + 1;
  sum[0] = '1';
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<addBinary>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r13,%rdi
  movslq %eax,%rbx
  call   <strlen@plt>
  mov    $0x1,%esi
  cmp    %eax,%ebx
  movslq %eax,%r15
  mov    %eax,%ebp
  cmovge %rbx,%r15
  lea    0x2(%r15),%edi
  call   <calloc@plt>
  mov    %rax,%r8
  mov    %ebx,%eax
  or     %ebp,%eax
  je     L23
  lea    0x1(%r15),%r14d
  movzbl (%r8,%r15,1),%edx
  movslq %r14d,%rcx
  add    %r8,%rcx
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L33
  sub    $0x1,%ebx
  movslq %ebx,%rax
  movsbl (%r12,%rax,1),%eax
  sub    $0x30,%eax
L33:
  mov    %ebx,%esi
  test   %ebp,%ebp
  je     L47
  sub    $0x1,%ebp
  movslq %ebp,%rsi
  movsbl 0x0(%r13,%rsi,1),%esi
  lea    -0x30(%rax,%rsi,1),%eax
  mov    %ebx,%esi
  or     %ebp,%esi
L47:
  add    %edx,%eax
  sub    $0x1,%rcx
  mov    %eax,%edx
  mov    %eax,%edi
  shr    $0x7,%dil
  shr    $0x7,%dl
  add    %eax,%edx
  add    %edi,%eax
  and    $0x1,%eax
  sar    %dl
  sub    %edi,%eax
  mov    %dl,-0x1(%rcx)
  add    $0x30,%eax
  mov    %al,(%rcx)
  test   %esi,%esi
  jne    L3
L23:
  cmpb   $0x0,(%r8)
  je     L35
  movb   $0x31,(%r8)
L12:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r8
  jmp    L12
```

assistant: ```c
char *addBinary(char *a, char *b) {
  int lengthA = strlen(a);
  int lengthB = strlen(b);
  int lengthSum = lengthA;
  if (lengthA < lengthB)
    lengthSum = lengthB;
  ++lengthSum;
  char *sum = calloc(lengthSum + 1, sizeof(char));
  while (lengthA || lengthB) {
    --lengthSum;
    sum[lengthSum] += (lengthA ? a[--lengthA] - '0' : 0) + (lengthB ? b[--lengthB] - '0' : 0);
    sum[lengthSum - 1] = sum[lengthSum] / 2;
    sum[lengthSum] %= 2;
    sum[lengthSum] += '0';
  }
  if (!sum[0])
    return sum + 1;
  sum[0] = '1';
  return sum;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ave>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
  mov    -0x8(%rbp),%eax
  cltd
  idivl  -0x1c(%rbp)
  pop    %rbp
  ret
```

assistant: ```c
int ave(int nums[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += nums[i];
  }
  return sum / len;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ave>:
  endbr64
  test   %esi,%esi
  jle    L7
  mov    %rdi,%rdx
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rcx
  mov    $0x0,%eax
L23:
  add    (%rdx),%eax
  add    $0x4,%rdx
  cmp    %rcx,%rdx
  jne    L23
L28:
  cltd
  idiv   %esi
  ret
L7:
  mov    $0x0,%eax
  jmp    L28
```

assistant: ```c
int ave(int nums[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += nums[i];
  }
  return sum / len;
}
```
user: What is the c source code of the assembly code below:

```asm
<ave>:
  endbr64
  test   %esi,%esi
  jle    L8
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L3:
  add    (%rdi),%eax
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  jne    L3
  cltd
  idiv   %esi
  ret
  nopw   0x0(%rax,%rax,1)
L8:
  xor    %eax,%eax
  ret
```

assistant: ```c
int ave(int nums[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += nums[i];
  }
  return sum / len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ave>:
  endbr64
  mov    %esi,%ecx
  test   %esi,%esi
  jle    L12
  lea    -0x1(%rsi),%eax
  cmp    $0x2,%eax
  jbe    L46
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopw   0x0(%rax,%rax,1)
L22:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  paddd  %xmm2,%xmm0
  cmp    %rdx,%rax
  jne    L22
  movdqa %xmm0,%xmm1
  mov    %ecx,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%edx
  paddd  %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%eax
  test   $0x3,%cl
  je     L0
L24:
  movslq %edx,%rsi
  lea    0x0(,%rsi,4),%r8
  add    (%rdi,%rsi,4),%eax
  lea    0x1(%rdx),%esi
  cmp    %esi,%ecx
  jle    L0
  add    $0x2,%edx
  add    0x4(%rdi,%r8,1),%eax
  cmp    %edx,%ecx
  jle    L0
  add    0x8(%rdi,%r8,1),%eax
L0:
  cltd
  idiv   %ecx
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  ret
L46:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L24
```

assistant: ```c
int ave(int nums[], int len) {
  int sum = 0;
  for (int i = 0; i < len; i++) {
    sum += nums[i];
  }
  return sum / len;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<numsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <atoi@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jge    L0
  mov    $0xffffffff,%eax
  jmp    L38
L0:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L23
  mov    $0x1,%eax
  jmp    L38
L23:
  mov    $0x0,%eax
L38:
  leave
  ret
```

assistant: ```c
int numsort(const struct dirent **d1, const struct dirent **d2) {
  const int n1 = atoi((*d1)->d_name);
  const int n2 = atoi((*d2)->d_name);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numsort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    (%rdi),%rax
  mov    (%rax),%edi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%rax
  mov    (%rax),%edi
  call   <atoi@plt>
  mov    $0xffffffff,%edx
  cmp    %eax,%ebx
  jl     L4
  setg   %dl
  movzbl %dl,%edx
L4:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int numsort(const struct dirent **d1, const struct dirent **d2) {
  const int n1 = atoi((*d1)->d_name);
  const int n2 = atoi((*d2)->d_name);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<numsort>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  mov    (%rax),%edi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%rax
  mov    (%rax),%edi
  call   <atoi@plt>
  mov    $0xffffffff,%edx
  cmp    %eax,%ebx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int numsort(const struct dirent **d1, const struct dirent **d2) {
  const int n1 = atoi((*d1)->d_name);
  const int n2 = atoi((*d2)->d_name);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<numsort>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rax
  mov    (%rax),%edi
  call   <atoi@plt>
  mov    %eax,%ebx
  mov    0x0(%rbp),%rax
  mov    (%rax),%edi
  call   <atoi@plt>
  mov    $0xffffffff,%edx
  cmp    %eax,%ebx
  setg   %al
  movzbl %al,%eax
  cmovl  %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int numsort(const struct dirent **d1, const struct dirent **d2) {
  const int n1 = atoi((*d1)->d_name);
  const int n2 = atoi((*d2)->d_name);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<my_qsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L45
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L6
L0:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L7
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L7:
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L0
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <my_qsort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <my_qsort>
  jmp    L46
L45:
  nop
L46:
  leave
  ret
```

assistant: ```c
void my_qsort(char *v[], int left, int right) {
  int i, last;
  void swap(char *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  my_qsort(v, left, last - 1);
  my_qsort(v, last + 1, right);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<my_qsort>:
  endbr64
  cmp    %edx,%esi
  jl     L24
  ret
L24:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %edx,%r12d
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r13),%ebx
  cmp    %ebx,%r12d
  jl     L44
  movslq %r13d,%rax
  lea    0x0(%rbp,%rax,8),%r15
  movslq %ebx,%rbx
  mov    %r13d,%r14d
  jmp    L31
L59:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L32
L31:
  mov    %ebx,0xc(%rsp)
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    (%r15),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L59
  add    $0x1,%r14d
  mov    0xc(%rsp),%edx
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L59
L44:
  mov    %r13d,%r14d
L32:
  mov    %r14d,%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  lea    -0x1(%r14),%edx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <my_qsort>
  lea    0x1(%r14),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  call   <my_qsort>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void my_qsort(char *v[], int left, int right) {
  int i, last;
  void swap(char *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  my_qsort(v, left, last - 1);
  my_qsort(v, last + 1, right);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<my_qsort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L15:
  cmp    %r14d,%ebp
  jle    L53
L58:
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,%ebp
  jl     L2
  movslq %r14d,%rax
  movslq %ecx,%r15
  mov    %r14d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L3
  nopl   0x0(%rax)
L20:
  add    $0x1,%r15
  cmp    %r15d,%ebp
  jl     L66
L3:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r15,8),%rdi
  mov    (%rax),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L20
  add    $0x1,%r13d
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r15
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %r15d,%ebp
  jge    L3
L66:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  call   <my_qsort>
  lea    0x1(%r13),%r14d
  cmp    %ebp,%r14d
  jl     L58
L53:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%ebp
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L15
```

assistant: ```c
void my_qsort(char *v[], int left, int right) {
  int i, last;
  void swap(char *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  my_qsort(v, left, last - 1);
  my_qsort(v, last + 1, right);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<my_qsort>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
L55:
  cmp    %r14d,%ebp
  jle    L47
L57:
  lea    0x0(%rbp,%r14,1),%eax
  mov    %r14d,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %eax,%edx
  sar    %edx
  call   <swap@plt>
  lea    0x1(%r14),%ecx
  cmp    %ecx,%ebp
  jl     L4
  movslq %r14d,%rax
  movslq %ecx,%r15
  mov    %r14d,%r13d
  lea    (%rbx,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  jmp    L51
  nopl   0x0(%rax)
L17:
  add    $0x1,%r15
  cmp    %r15d,%ebp
  jl     L28
L51:
  mov    0x8(%rsp),%rax
  mov    (%rbx,%r15,8),%rdi
  mov    (%rax),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jns    L17
  add    $0x1,%r13d
  mov    %r15d,%edx
  mov    %rbx,%rdi
  add    $0x1,%r15
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %r15d,%ebp
  jge    L51
L28:
  mov    %r14d,%esi
  mov    %r13d,%edx
  mov    %rbx,%rdi
  call   <swap@plt>
  mov    %r14d,%esi
  lea    -0x1(%r13),%edx
  mov    %rbx,%rdi
  call   <my_qsort>
  lea    0x1(%r13),%r14d
  cmp    %ebp,%r14d
  jl     L57
L47:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r14d,%edx
  mov    %r14d,%esi
  lea    -0x1(%r14),%ebp
  mov    %rbx,%rdi
  call   <swap@plt>
  jmp    L55
```

assistant: ```c
void my_qsort(char *v[], int left, int right) {
  int i, last;
  void swap(char *v[], int i, int j);
  if (left >= right)
    return;
  swap(v, left, (left + right) / 2);
  last = left;
  for (i = left + 1; i <= right; i++)
    if (strcmp(v[i], v[left]) < 0)
      swap(v, ++last, i);
  swap(v, left, last);
  my_qsort(v, left, last - 1);
  my_qsort(v, last + 1, right);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serverWrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x4,%edx
  lea    D13(%rip),%rsi
  mov    %eax,%edi
  call   <send@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D13
type: string

tool: D3: serverWrite on FD %d


tool: D13: 123

assistant: ```c
void serverWrite(int fd, void *data) {
  printf("serverWrite on FD %d\n");
  send(fd, "123", 4, 0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<serverWrite>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ecx
  mov    $0x4,%edx
  lea    D2(%rip),%rsi
  mov    %ebx,%edi
  call   <send@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D4: serverWrite on FD %d


tool: D2: 123

assistant: ```c
void serverWrite(int fd, void *data) {
  printf("serverWrite on FD %d\n");
  send(fd, "123", 4, 0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<serverWrite>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0x4,%edx
  lea    D6(%rip),%rsi
  pop    %rbp
  jmp    1060 <send@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
data_type: string
name: retrieve_data
arguments: data_label: D6
data_type: string

tool: D16: serverWrite on FD %d


tool: D6: 123

assistant: ```c
void serverWrite(int fd, void *data) {
  printf("serverWrite on FD %d\n");
  send(fd, "123", 4, 0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<serverWrite>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0x4,%edx
  lea    D11(%rip),%rsi
  pop    %rbp
  jmp    1060 <send@plt>
```

tool_calls: name: unpack_data
arguments: label: D6
type_infered: string
name: unpack_data
arguments: label: D11
type_infered: string

tool: D6: serverWrite on FD %d


tool: D11: 123

assistant: ```c
void serverWrite(int fd, void *data) {
  printf("serverWrite on FD %d\n");
  send(fd, "123", 4, 0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<test_void_pointers>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D36(%rip),%rdi
  call   <puts@plt>
  movl   $0x2a,0x4(%rsp)
  lea    0x4(%rsp),%rsi
  lea    D50(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x2a,0x4(%rsp)
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <puts@plt>
  cmpl   $0x2a,0x4(%rsp)
  sete   %dil
  movzbl %dil,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    0x4(%rsp),%esi
  lea    D66(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D64(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  lea    D25(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D36
type: string
name: read_data
arguments: label: D50
type: string
name: read_data
arguments: label: D20
type: string
name: read_data
arguments: label: D35
type: string
name: read_data
arguments: label: D66
type: string
name: read_data
arguments: label: D64
type: string
name: read_data
arguments: label: D25
type: string

tool: D36: 
===== test_void_pointers

tool: D50: Set void pointer to the address of an int: `void *p = &i`. Address: %p


tool: D20: Casting a void pointer to assumed type and dereferencing: `*(int*)p`. Returns %d


tool: D35: Set int pointer equal to void pointer: `int *int_p = p`

tool: D66: Dereferencing int pointer: `*int_p`. Returns %d


tool: D64: But would not stop you setting float pointer equal to void pointer that points to int: `float *float_p = p`

tool: D25: Dereferencing the float pointer doesn't blow up (since float and int both 4 bytes), but value is wrong: %f


assistant: ```c
void test_void_pointers() {
  printf("\n===== test_void_pointers\n");
  int i = 42;
  void *p = &i;
  printf("Set void pointer to the address of an int: `void *p = &i`. Address: %p\n", p);
  assert(*(int *)p == 42);
  printf("Casting a void pointer to assumed type and dereferencing: `*(int*)p`. Returns %d\n", *(int *)p);
  int *int_p = p;
  printf("Set int pointer equal to void pointer: `int *int_p = p`\n");
  assert(*int_p == 42);
  printf("Dereferencing int pointer: `*int_p`. Returns %d\n", *int_p);
  float *float_p = p;
  printf("But would not stop you setting float pointer equal to void pointer that points to int: `float *float_p = p`\n");
  printf("Dereferencing the float pointer doesn't blow up (since float and int both 4 bytes), but value is wrong: %f\n", *float_p);
}
```