ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fread_Data_d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  movb   $0x0,-0x27(%rbp)
  movb   $0x0,-0x26(%rbp)
  movb   $0x0,-0x25(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L41
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L41:
  movsbl -0x25(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D46(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L44
  mov    $0x0,%edi
  call   <exit@plt>
L44:
  movsbl -0x25(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L15
L70:
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x18(%rbp),%rax
  lea    D46(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  addl   $0x1,-0x24(%rbp)
L15:
  movsbl -0x25(%rbp),%eax
  cmp    %eax,-0x24(%rbp)
  jl     L70
  movl   $0x0,-0x1c(%rbp)
  jmp    L71
L27:
  movsbl -0x26(%rbp),%edx
  mov    -0x18(%rbp),%rax
  lea    D46(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  movl   $0x0,-0x20(%rbp)
  jmp    L0
L74:
  movsbl -0x26(%rbp),%ebx
  mov    -0x20(%rbp),%eax
  mov    %eax,%edi
  call   <pow_2@plt>
  movsbl %al,%esi
  mov    %ebx,%eax
  cltd
  idiv   %esi
  mov    %eax,%edx
  mov    %edx,%eax
  sar    $0x1f,%eax
  shr    $0x1f,%eax
  mov    %eax,%ecx
  lea    (%rdx,%rcx,1),%eax
  and    $0x1,%eax
  sub    %ecx,%eax
  mov    %al,-0x27(%rbp)
  addl   $0x1,-0x20(%rbp)
L0:
  cmpl   $0x7,-0x20(%rbp)
  jle    L74
L71:
  movsbl -0x25(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L27
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D30
type_guessed: string
name: read_data
arguments: tag: D13
type_guessed: string
name: read_data
arguments: tag: D6
type_guessed: string
name: read_data
arguments: tag: D46
type_guessed: string

tool: D30: r

tool: D13: in.txt

tool: D6: error


tool: D46: %c

assistant: ```c
void fread_Data_d(char *elements, char **codes) {
  char tmp = 0;
  char code = 0;
  char number_elements = 0;
  FILE *file_in = fopen("in.txt", "r");
  if (!file_in) {
    printf("error\n");
    exit(1);
  }
  if (fscanf(file_in, "%c", number_elements) != 1) {
    exit(0);
  }
  elements = malloc(sizeof(char) * number_elements);
  for (int i = 0; i < number_elements; i++) {
    fscanf(file_in, "%c", elements[i]);
  }
  int i = 0;
  while (i < number_elements) {
    fscanf(file_in, "%c", code);
    for (int j = 0; j < 8; j++) {
      if ((tmp = (code / pow_2(j) % 2)) == 1) {
      } else {
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fread_Data_d>:
  endbr64
  push   %rbx
  lea    D25(%rip),%rsi
  lea    D24(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L0
L35:
  mov    $0x0,%edx
  lea    D9(%rip),%rsi
  mov    %rbx,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L13
L31:
  mov    $0x0,%edi
  call   <malloc@plt>
  pop    %rbx
  ret
L0:
  lea    D38(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L35
L13:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L31
```

tool_calls: name: read_data
arguments: data_tag: D25
datatype: string
name: read_data
arguments: data_tag: D24
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string
name: read_data
arguments: data_tag: D38
datatype: string

tool: D25: r

tool: D24: in.txt

tool: D9: %c

tool: D38: error


assistant: ```c
void fread_Data_d(char *elements, char **codes) {
  char tmp = 0;
  char code = 0;
  char number_elements = 0;
  FILE *file_in = fopen("in.txt", "r");
  if (!file_in) {
    printf("error\n");
    exit(1);
  }
  if (fscanf(file_in, "%c", number_elements) != 1) {
    exit(0);
  }
  elements = malloc(sizeof(char) * number_elements);
  for (int i = 0; i < number_elements; i++) {
    fscanf(file_in, "%c", elements[i]);
  }
  int i = 0;
  while (i < number_elements) {
    fscanf(file_in, "%c", code);
    for (int j = 0; j < 8; j++) {
      if ((tmp = (code / pow_2(j) % 2)) == 1) {
      } else {
      }
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fread_Data_d>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rsi
  lea    D25(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L15
L16:
  xor    %edx,%edx
  lea    D24(%rip),%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L21
  xor    %edi,%edi
  call   <exit@plt>
L21:
  xor    %edi,%edi
  pop    %rbp
  jmp    10b0 <malloc@plt>
  nopl   (%rax)
L15:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L16
```

tool_calls: name: retrieve_data
arguments: data_tag: D23
type: string
name: retrieve_data
arguments: data_tag: D25
type: string
name: retrieve_data
arguments: data_tag: D24
type: string
name: retrieve_data
arguments: data_tag: D11
type: string

tool: D23: r

tool: D25: in.txt

tool: D24: %c

tool: D11: error


assistant: ```c
void fread_Data_d(char *elements, char **codes) {
  char tmp = 0;
  char code = 0;
  char number_elements = 0;
  FILE *file_in = fopen("in.txt", "r");
  if (!file_in) {
    printf("error\n");
    exit(1);
  }
  if (fscanf(file_in, "%c", number_elements) != 1) {
    exit(0);
  }
  elements = malloc(sizeof(char) * number_elements);
  for (int i = 0; i < number_elements; i++) {
    fscanf(file_in, "%c", elements[i]);
  }
  int i = 0;
  while (i < number_elements) {
    fscanf(file_in, "%c", code);
    for (int j = 0; j < 8; j++) {
      if ((tmp = (code / pow_2(j) % 2)) == 1) {
      } else {
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fread_Data_d>:
  endbr64
  push   %rbp
  lea    D32(%rip),%rsi
  lea    D16(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L8
L25:
  xor    %edx,%edx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L23
  xor    %edi,%edi
  call   <exit@plt>
L23:
  xor    %edi,%edi
  pop    %rbp
  jmp    10b0 <malloc@plt>
  nopl   (%rax)
L8:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L25
```

tool_calls: name: parse_data
arguments: data_tag: D32
type_infered: string
name: parse_data
arguments: data_tag: D16
type_infered: string
name: parse_data
arguments: data_tag: D27
type_infered: string
name: parse_data
arguments: data_tag: D6
type_infered: string

tool: D32: r

tool: D16: in.txt

tool: D27: %c

tool: D6: error


assistant: ```c
void fread_Data_d(char *elements, char **codes) {
  char tmp = 0;
  char code = 0;
  char number_elements = 0;
  FILE *file_in = fopen("in.txt", "r");
  if (!file_in) {
    printf("error\n");
    exit(1);
  }
  if (fscanf(file_in, "%c", number_elements) != 1) {
    exit(0);
  }
  elements = malloc(sizeof(char) * number_elements);
  for (int i = 0; i < number_elements; i++) {
    fscanf(file_in, "%c", elements[i]);
  }
  int i = 0;
  while (i < number_elements) {
    fscanf(file_in, "%c", code);
    for (int j = 0; j < 8; j++) {
      if ((tmp = (code / pow_2(j) % 2)) == 1) {
      } else {
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L14
L8:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_string(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L4
L17:
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <putchar@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
L4:
  pop    %rbx
  ret
```

assistant: ```c
void print_string(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L1:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L1
L5:
  pop    %rbx
  ret
```

assistant: ```c
void print_string(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_string>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L7
L13:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L13
L7:
  pop    %rbx
  ret
```

assistant: ```c
void print_string(const char *s) {
  while (*s)
    putchar(*s++);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_ZSt4copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x68(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %rdx,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x58(%rbp)
  mov    -0x70(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x50(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <_ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
unsigned int **_ZSt4copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_call2;
  unsigned int **llvm_cbe_tmp3;
  unsigned int **llvm_cbe_call4;
  unsigned int **llvm_cbe_tmp__41;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_call = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_call2 = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp1);
  llvm_cbe_tmp3 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call4 = _ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_(llvm_cbe_call, llvm_cbe_call2, llvm_cbe_tmp3);
  *(&llvm_cbe_retval) = llvm_cbe_call4;
  llvm_cbe_tmp__41 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__41;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_ZSt4copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  mov    %rdx,%rbp
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %rax,%rsi
  mov    %rbp,%rdx
  mov    %rbx,%rdi
  call   <_ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned int **_ZSt4copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_call2;
  unsigned int **llvm_cbe_tmp3;
  unsigned int **llvm_cbe_call4;
  unsigned int **llvm_cbe_tmp__41;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_call = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_call2 = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp1);
  llvm_cbe_tmp3 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call4 = _ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_(llvm_cbe_call, llvm_cbe_call2, llvm_cbe_tmp3);
  *(&llvm_cbe_retval) = llvm_cbe_call4;
  llvm_cbe_tmp__41 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__41;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<_ZSt4copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  pop    %r12
  pop    %r13
  jmp    1060 <_ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_@plt>
```

assistant: ```c
unsigned int **_ZSt4copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_call2;
  unsigned int **llvm_cbe_tmp3;
  unsigned int **llvm_cbe_call4;
  unsigned int **llvm_cbe_tmp__41;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_call = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_call2 = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp1);
  llvm_cbe_tmp3 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call4 = _ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_(llvm_cbe_call, llvm_cbe_call2, llvm_cbe_tmp3);
  *(&llvm_cbe_retval) = llvm_cbe_call4;
  llvm_cbe_tmp__41 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__41;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_ZSt4copyIPPiS1_ET0_T_S3_S2_>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <_ZNSt12__miter_baseIPPiLb0EE3__bES1_@plt>
  mov    %r12,%rdx
  mov    %rbp,%rdi
  pop    %rbp
  mov    %rax,%rsi
  pop    %r12
  pop    %r13
  jmp    1060 <_ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_@plt>
```

assistant: ```c
unsigned int **_ZSt4copyIPPiS1_ET0_T_S3_S2_(unsigned int **llvm_cbe___first, unsigned int **llvm_cbe___last, unsigned int **llvm_cbe___result) {
  unsigned int **llvm_cbe_retval;
  unsigned int **llvm_cbe___first_2e_addr;
  unsigned int **llvm_cbe___last_2e_addr;
  unsigned int **llvm_cbe___result_2e_addr;
  unsigned int **llvm_cbe_tmp;
  unsigned int **llvm_cbe_call;
  unsigned int **llvm_cbe_tmp1;
  unsigned int **llvm_cbe_call2;
  unsigned int **llvm_cbe_tmp3;
  unsigned int **llvm_cbe_call4;
  unsigned int **llvm_cbe_tmp__41;
  *(&llvm_cbe___first_2e_addr) = llvm_cbe___first;
  *(&llvm_cbe___last_2e_addr) = llvm_cbe___last;
  *(&llvm_cbe___result_2e_addr) = llvm_cbe___result;
  llvm_cbe_tmp = *(&llvm_cbe___first_2e_addr);
  llvm_cbe_call = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp);
  llvm_cbe_tmp1 = *(&llvm_cbe___last_2e_addr);
  llvm_cbe_call2 = _ZNSt12__miter_baseIPPiLb0EE3__bES1_(llvm_cbe_tmp1);
  llvm_cbe_tmp3 = *(&llvm_cbe___result_2e_addr);
  llvm_cbe_call4 = _ZSt14__copy_move_a2ILb0EPPiS1_ET1_T0_S3_S2_(llvm_cbe_call, llvm_cbe_call2, llvm_cbe_tmp3);
  *(&llvm_cbe_retval) = llvm_cbe_call4;
  llvm_cbe_tmp__41 = *(&llvm_cbe_retval);
  return llvm_cbe_tmp__41;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L42
L33:
  addl   $0x1,-0x4c(%rbp)
L42:
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L33
  movl   $0x0,-0x48(%rbp)
  mov    -0x4c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x44(%rbp)
  jmp    L59
L46:
  mov    -0x48(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%edx
  mov    -0x44(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    %al,%dl
  je     L63
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
L63:
  addl   $0x1,-0x48(%rbp)
  subl   $0x1,-0x44(%rbp)
L59:
  mov    -0x4c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x48(%rbp)
  jl     L46
L69:
  mov    -0x4c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x48(%rbp)
  jne    L35
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L35:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type_infered: string
name: unpack_data
arguments: data_tag: D16
type_infered: string
name: unpack_data
arguments: data_tag: D22
type_infered: string

tool: D10: %[^
]s

tool: D16: 0

tool: D22: 1

assistant: ```c
int main() {
  char word[50];
  scanf("%[^\n]s", word);
  int l = 0, i, j;
  while (word[l] != '\0')
    l++;
  for (i = 0, j = l - 1; i < l / 2; i++, j--) {
    if (word[i] != word[j]) {
      printf("0");
      break;
    }
  }
  if (i == l / 2)
    printf("1");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L93
  lea    0x1(%rsp),%rcx
  mov    $0x0,%edx
L4:
  mov    %edx,%eax
  add    $0x1,%edx
  add    $0x1,%rcx
  cmpb   $0x0,-0x1(%rcx)
  jne    L4
  mov    %edx,%ebx
  shr    $0x1f,%ebx
  add    %edx,%ebx
  sar    %ebx
  cmp    $0x1,%edx
  jle    L52
  mov    %rsp,%rdx
  cltq
  add    %rdx,%rax
  mov    $0x0,%ebp
L17:
  movzbl (%rax),%esi
  cmp    %sil,(%rdx)
  jne    L63
  add    $0x1,%ebp
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %ebx,%ebp
  jl     L17
  jmp    L44
L63:
  lea    D23(%rip),%rdi
  call   <printf@plt>
L44:
  cmp    %ebp,%ebx
  je     L93
L76:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L52:
  mov    $0x0,%ebp
  jmp    L44
L93:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L76
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D23
datatype: string
name: retrieve_data
arguments: label: D29
datatype: string

tool: D25: %[^
]s

tool: D23: 0

tool: D29: 1

assistant: ```c
int main() {
  char word[50];
  scanf("%[^\n]s", word);
  int l = 0, i, j;
  while (word[l] != '\0')
    l++;
  for (i = 0, j = l - 1; i < l / 2; i++, j--) {
    if (word[i] != word[j]) {
      printf("0");
      break;
    }
  }
  if (i == l / 2)
    printf("1");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movzbl (%rsp),%esi
  test   %sil,%sil
  je     L34
  lea    0x1(%rsp),%rdx
  xor    %eax,%eax
  mov    %rdx,%rcx
  nop
L11:
  add    $0x1,%rcx
  movslq %eax,%rdi
  add    $0x1,%eax
  cmpb   $0x0,-0x1(%rcx)
  jne    L11
  sar    %eax
  mov    %eax,%ebx
  je     L34
  lea    0x0(%rbp,%rdi,1),%rax
  xor    %ebp,%ebp
  jmp    L65
  nop
L38:
  add    $0x1,%ebp
  sub    $0x1,%rax
  cmp    %ebp,%ebx
  je     L34
  movzbl (%rdx),%esi
  add    $0x1,%rdx
L65:
  cmp    %sil,(%rax)
  je     L38
  lea    D12(%rip),%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L34
L69:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L34:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  jmp    L69
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D19
type_guessed: string
name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D13
type_guessed: string

tool: D19: %[^
]s

tool: D12: 0

tool: D13: 1

assistant: ```c
int main() {
  char word[50];
  scanf("%[^\n]s", word);
  int l = 0, i, j;
  while (word[l] != '\0')
    l++;
  for (i = 0, j = l - 1; i < l / 2; i++, j--) {
    if (word[i] != word[j]) {
      printf("0");
      break;
    }
  }
  if (i == l / 2)
    printf("1");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D12(%rip),%rdi
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  cmpb   $0x0,(%rsp)
  je     L22
  lea    0x1(%rsp),%rcx
  xor    %edx,%edx
  nopl   0x0(%rax)
L60:
  add    $0x1,%rcx
  movslq %edx,%rax
  add    $0x1,%edx
  cmpb   $0x0,-0x1(%rcx)
  jne    L60
  mov    %edx,%ebx
  sar    %ebx
  je     L22
  mov    %rbp,%rdx
  add    %rbp,%rax
  xor    %ebp,%ebp
  jmp    L66
L39:
  add    $0x1,%ebp
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %ebp,%ebx
  je     L22
L66:
  movzbl (%rax),%esi
  cmp    %sil,(%rdx)
  je     L39
  lea    D6(%rip),%rdi
  call   <printf@plt>
  cmp    %ebp,%ebx
  je     L22
L43:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x48,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D12
datatype: string
name: unpack_data
arguments: data_label: D6
datatype: string
name: unpack_data
arguments: data_label: D8
datatype: string

tool: D12: %[^
]s

tool: D6: 0

tool: D8: 1

assistant: ```c
int main() {
  char word[50];
  scanf("%[^\n]s", word);
  int l = 0, i, j;
  while (word[l] != '\0')
    l++;
  for (i = 0, j = l - 1; i < l / 2; i++, j--) {
    if (word[i] != word[j]) {
      printf("0");
      break;
    }
  }
  if (i == l / 2)
    printf("1");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<berechne_kosten_pro_einheit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x20(%rbp),%xmm0
  divsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double berechne_kosten_pro_einheit(double gesamtmenge, double gesamtkosten) {
  double kosten_pro_einheit = gesamtkosten / gesamtmenge;
  return kosten_pro_einheit;
}
```