user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1a8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x198(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x190(%rsp),%rbx
  mov    %r12,%rax
L3:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L3
  lea    D34(%rip),%rbp
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D23(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    %r12,%r13
  mov    $0x0,%ebp
L36:
  mov    %ebp,%r14d
  add    $0x1,%ebp
  mov    0x4(%r13),%r15d
  mov    -0x4(%r13),%ecx
  lea    -0x1(%r14),%edx
  push   %r15
  push   %rbp
  mov    0x0(%r13),%r9d
  mov    %r14d,%r8d
  mov    %r14d,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x0(%rbp,%rbp,4),%ecx
  add    %ecx,%ecx
  mov    %ecx,0x0(%r13)
  mov    0x8(%r13),%eax
  push   %rax
  lea    0x2(%r14),%eax
  push   %rax
  mov    %r15d,%r9d
  mov    %ebp,%r8d
  mov    %r14d,%edx
  mov    %ebp,%esi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r13
  add    $0x20,%rsp
  cmp    $0x8,%ebp
  jne    L36
  mov    %r12,%rax
L48:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rbx,%rax
  jne    L48
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D15(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    $0x0,%ebx
  lea    D3(%rip),%r15
  lea    D17(%rip),%r14
L28:
  mov    %ebx,%ebp
  add    $0x1,%ebx
  mov    (%r12),%r13d
  mov    -0x4(%r12),%ecx
  lea    -0x1(%rbp),%edx
  mov    0x4(%r12),%eax
  push   %rax
  push   %rbx
  mov    %r13d,%r9d
  mov    %ebp,%r8d
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    (%rbx,%rbx,4),%r9d
  add    %r9d,%r9d
  mov    %r9d,0x4(%r12)
  mov    0x8(%r12),%eax
  push   %rax
  lea    0x2(%rbp),%eax
  push   %rax
  mov    %ebx,%r8d
  mov    %r13d,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%r12
  add    $0x20,%rsp
  cmp    $0x8,%ebx
  jne    L28
  lea    D34(%rip),%rbx
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x198(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x1a8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D34
datatype: string
name: disassemble_data
arguments: label: D23
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D17
datatype: string
name: disassemble_data
arguments: label: D15
datatype: string

tool: D34: ============================================================================

tool: D23: ================================= i ++ =====================================

tool: D3: before check i = %2d; val [ i - 1 = %2d ] = %3d; val [ i = %2d ] = %3d; val [ i + 1 = %2d ] = %3d 


tool: D17: after  check i = %2d; val [ i - 1 = %2d ] = %3d; val [ i = %2d ] = %3d; val [ i + 1 = %2d ] = %3d 



tool: D15: ================================= ++ i =====================================

assistant: ```c
void main() {
  int i = 0;
  int val[100];
  for (i = 0; i < 100; ++i) {
    val[i] = 0;
  };
  printf("============================================================================\n");
  printf("================================= i ++ =====================================\n");
  printf("============================================================================\n");
  for (i = 0; i < 8;) {
    printf("before check i = %2d; val [ i - 1 = %2d ] = %3d; val [ i = %2d ] = %3d; val [ i + 1 = %2d ] = %3d \n", i, i - 1, val[i - 1], i, val[i], i + 1, val[i + 1]);
    val[i++] = i * 10;
    printf("after  check i = %2d; val [ i - 1 = %2d ] = %3d; val [ i = %2d ] = %3d; val [ i + 1 = %2d ] = %3d \n\n", i, i - 1, val[i - 1], i, val[i], i + 1, val[i + 1]);
  }
  for (i = 0; i < 100; ++i) {
    val[i] = 0;
  };
  printf("============================================================================\n");
  printf("================================= ++ i =====================================\n");
  printf("============================================================================\n");
  for (i = 0; i < 8;) {
    printf("before check i = %2d; val [ i - 1 = %2d ] = %3d; val [ i = %2d ] = %3d; val [ i + 1 = %2d ] = %3d \n", i, i - 1, val[i - 1], i, val[i], i + 1, val[i + 1]);
    val[++i] = i * 10;
    printf("after  check i = %2d; val [ i - 1 = %2d ] = %3d; val [ i = %2d ] = %3d; val [ i + 1 = %2d ] = %3d \n\n", i, i - 1, val[i - 1], i, val[i], i + 1, val[i + 1]);
  }
  printf("============================================================================\n");
  printf("============================================================================\n");
}
```