ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L55
  mov    -0x20(%rbp),%rax
  jmp    L49
L55:
  cmpq   $0x0,-0x20(%rbp)
  jne    L41
  mov    -0x18(%rbp),%rax
  jmp    L49
L41:
  movq   $0x0,-0x10(%rbp)
  jmp    L40
L79:
  shrq   -0x18(%rbp)
  shrq   -0x20(%rbp)
  addq   $0x1,-0x10(%rbp)
L40:
  mov    -0x18(%rbp),%rax
  or     -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L79
  jmp    L101
L91:
  shrq   -0x18(%rbp)
L101:
  mov    -0x18(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L91
  jmp    L64
L66:
  shrq   -0x20(%rbp)
L64:
  mov    -0x20(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L66
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jbe    L82
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
L82:
  mov    -0x18(%rbp),%rax
  sub    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L64
  mov    -0x10(%rbp),%rax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%ecx
  shl    %cl,%rax
L49:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long gcd(unsigned long u, unsigned long v) {
  long shift;
  if (u == 0) {
    return v;
  }
  if (v == 0) {
    return u;
  }
  for (shift = 0; ((u | v) & 1) == 0; ++shift) {
    u >>= 1;
    v >>= 1;
  }
  while ((u & 1) == 0) {
    u >>= 1;
  }
  do {
    while ((v & 1) == 0) {
      v >>= 1;
    }
    if (u > v) {
      unsigned long t = v;
      v = u;
      u = t;
    }
    v = v - u;
  } while (v != 0);
  return u << shift;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<gcd>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L109
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L109
  or     %rsi,%rax
  test   $0x1,%al
  jne    L10
  mov    $0x0,%ecx
L16:
  shr    %rdi
  shr    %rsi
  add    $0x1,%rcx
  mov    %rdi,%rax
  or     %rsi,%rax
  test   $0x1,%al
  je     L16
L54:
  test   $0x1,%dil
  jne    L35
L6:
  shr    %rdi
  test   $0x1,%dil
  je     L6
  jmp    L35
L10:
  mov    $0x0,%ecx
  jmp    L54
L26:
  shr    %rsi
L35:
  test   $0x1,%sil
  je     L26
  cmp    %rsi,%rdi
  jbe    L52
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
L52:
  sub    %rdi,%rsi
  jne    L35
  mov    %rdi,%rax
  shl    %cl,%rax
L109:
  ret
```

assistant: ```c
unsigned long gcd(unsigned long u, unsigned long v) {
  long shift;
  if (u == 0) {
    return v;
  }
  if (v == 0) {
    return u;
  }
  for (shift = 0; ((u | v) & 1) == 0; ++shift) {
    u >>= 1;
    v >>= 1;
  }
  while ((u & 1) == 0) {
    u >>= 1;
  }
  do {
    while ((v & 1) == 0) {
      v >>= 1;
    }
    if (u > v) {
      unsigned long t = v;
      v = u;
      u = t;
    }
    v = v - u;
  } while (v != 0);
  return u << shift;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<gcd>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L81
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L81
  or     %rsi,%rax
  test   $0x1,%al
  jne    L71
  xor    %ecx,%ecx
  nopl   (%rax)
L64:
  shr    %rdi
  shr    %rsi
  add    $0x1,%rcx
  mov    %rdi,%rax
  or     %rsi,%rax
  test   $0x1,%al
  je     L64
L107:
  test   $0x1,%dil
  jne    L9
  nopw   0x0(%rax,%rax,1)
L87:
  shr    %rdi
  test   $0x1,%dil
  je     L87
  nopl   0x0(%rax)
L9:
  test   $0x1,%sil
  je     L94
  cmp    %rsi,%rdi
  jbe    L18
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
L18:
  sub    %rdi,%rsi
  jne    L9
  mov    %rdi,%rax
  shl    %cl,%rax
L81:
  ret
L94:
  shr    %rsi
  jmp    L9
L71:
  xor    %ecx,%ecx
  jmp    L107
```

assistant: ```c
unsigned long gcd(unsigned long u, unsigned long v) {
  long shift;
  if (u == 0) {
    return v;
  }
  if (v == 0) {
    return u;
  }
  for (shift = 0; ((u | v) & 1) == 0; ++shift) {
    u >>= 1;
    v >>= 1;
  }
  while ((u & 1) == 0) {
    u >>= 1;
  }
  do {
    while ((v & 1) == 0) {
      v >>= 1;
    }
    if (u > v) {
      unsigned long t = v;
      v = u;
      u = t;
    }
    v = v - u;
  } while (v != 0);
  return u << shift;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gcd>:
  endbr64
  mov    %rsi,%rax
  test   %rdi,%rdi
  je     L18
  mov    %rdi,%rax
  test   %rsi,%rsi
  je     L18
  or     %rsi,%rax
  test   $0x1,%al
  jne    L16
  xor    %ecx,%ecx
  nopl   (%rax)
L47:
  shr    %rdi
  shr    %rsi
  add    $0x1,%rcx
  mov    %rdi,%rax
  or     %rsi,%rax
  test   $0x1,%al
  je     L47
L70:
  test   $0x1,%dil
  jne    L78
  nopw   0x0(%rax,%rax,1)
L53:
  shr    %rdi
  test   $0x1,%dil
  je     L53
  nopl   0x0(%rax)
L78:
  test   $0x1,%sil
  je     L44
  cmp    %rsi,%rdi
  jbe    L39
  mov    %rdi,%rax
  mov    %rsi,%rdi
  mov    %rax,%rsi
L39:
  sub    %rdi,%rsi
  jne    L78
  mov    %rdi,%rax
  shl    %cl,%rax
L18:
  ret
L44:
  shr    %rsi
  jmp    L78
L16:
  xor    %ecx,%ecx
  jmp    L70
```

assistant: ```c
unsigned long gcd(unsigned long u, unsigned long v) {
  long shift;
  if (u == 0) {
    return v;
  }
  if (v == 0) {
    return u;
  }
  for (shift = 0; ((u | v) & 1) == 0; ++shift) {
    u >>= 1;
    v >>= 1;
  }
  while ((u & 1) == 0) {
    u >>= 1;
  }
  do {
    while ((v & 1) == 0) {
      v >>= 1;
    }
    if (u > v) {
      unsigned long t = v;
      v = u;
      u = t;
    }
    v = v - u;
  } while (v != 0);
  return u << shift;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Sign>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  pxor   %xmm1,%xmm1
  comisd %xmm1,%xmm0
  jbe    L23
  mov    $0x1,%eax
  jmp    L4
L23:
  pxor   %xmm0,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L29
  mov    $0xffffffff,%eax
  jmp    L4
L29:
  mov    $0x0,%eax
L4:
  pop    %rbp
  ret
```

assistant: ```c
int Sign(double arg) {
  if (arg > 0)
    return 1;
  else if (arg < 0)
    return -1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Sign>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  neg    %eax
L1:
  ret
```

assistant: ```c
int Sign(double arg) {
  if (arg > 0)
    return 1;
  else if (arg < 0)
    return -1;
  else
    return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<Sign>:
  endbr64
  pxor   %xmm1,%xmm1
  mov    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L1
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  neg    %eax
L1:
  ret
```

assistant: ```c
int Sign(double arg) {
  if (arg > 0)
    return 1;
  else if (arg < 0)
    return -1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
L7:
  mov    %rax,0x30(%rsp,%rax,8)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L7
  lea    0x30(%rsp),%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print_longs@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <shuffle@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print_longs@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
L4:
  mov    0x30(%rsp,%rax,8),%rdx
  mov    %edx,(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L4
  mov    %rsp,%rbx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print_ints@plt>
  lea    D29(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quicksort_ints@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print_ints@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D29
datatype: string
name: unpack_data
arguments: data_tag: D27
datatype: string
name: unpack_data
arguments: data_tag: D48
datatype: string
name: unpack_data
arguments: data_tag: D8
datatype: string

tool: D29: 


tool: D27: 



tool: D48: ints:


tool: D8: DONE


assistant: ```c
int main() {
  int n = 10;
  long A[10];
  for (int i = 0; i < n; i++)
    A[i] = i;
  print_longs(A, n);
  printf("\n");
  shuffle(A, n);
  print_longs(A, n);
  printf("\n\n");
  printf("ints:\n");
  int B[n];
  for (int i = 0; i < n; i++)
    B[i] = A[i];
  print_ints(B, n);
  printf("\n");
  quicksort_ints(B, 0, 9);
  print_ints(B, n);
  printf("\n");
  printf("DONE\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  lea    0x30(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L20:
  mov    %rax,(%rbx,%rax,8)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L20
  mov    $0xa,%esi
  mov    %rbx,%rdi
  lea    D1(%rip),%r12
  mov    %rsp,%rbp
  call   <print_longs@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <shuffle@plt>
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <print_longs@plt>
  lea    D36(%rip),%rdi
  call   <printf@plt>
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  nopl   0x0(%rax)
L21:
  mov    (%rbx,%rax,8),%rdx
  mov    %edx,0x0(%rbp,%rax,4)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L21
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <print_ints@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x9,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <quicksort_ints@plt>
  mov    $0xa,%esi
  mov    %rbp,%rdi
  call   <print_ints@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <printf@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D1
datatype: string
name: parse_data
arguments: tag: D36
datatype: string
name: parse_data
arguments: tag: D39
datatype: string
name: parse_data
arguments: tag: D29
datatype: string

tool: D1: 


tool: D36: 



tool: D39: ints:


tool: D29: DONE


assistant: ```c
int main() {
  int n = 10;
  long A[10];
  for (int i = 0; i < n; i++)
    A[i] = i;
  print_longs(A, n);
  printf("\n");
  shuffle(A, n);
  print_longs(A, n);
  printf("\n\n");
  printf("ints:\n");
  int B[n];
  for (int i = 0; i < n; i++)
    B[i] = A[i];
  print_ints(B, n);
  printf("\n");
  quicksort_ints(B, 0, 9);
  print_ints(B, n);
  printf("\n");
  printf("DONE\n");
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ap_base64decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ap_base64decode_binary@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ap_base64decode(char *bufplain, const char *bufcoded) {
  int len;
  len = ap_base64decode_binary((unsigned char *)bufplain, bufcoded);
  bufplain[len] = '\0';
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ap_base64decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ap_base64decode_binary@plt>
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int ap_base64decode(char *bufplain, const char *bufcoded) {
  int len;
  len = ap_base64decode_binary((unsigned char *)bufplain, bufcoded);
  bufplain[len] = '\0';
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ap_base64decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ap_base64decode_binary@plt>
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int ap_base64decode(char *bufplain, const char *bufcoded) {
  int len;
  len = ap_base64decode_binary((unsigned char *)bufplain, bufcoded);
  bufplain[len] = '\0';
  return len;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ap_base64decode>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ap_base64decode_binary@plt>
  movslq %eax,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  pop    %rbx
  ret
```

assistant: ```c
int ap_base64decode(char *bufplain, const char *bufcoded) {
  int len;
  len = ap_base64decode_binary((unsigned char *)bufplain, bufcoded);
  bufplain[len] = '\0';
  return len;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lengthLongestIncreasingSubsequence>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L2
L6:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  movl   $0x0,-0x10(%rbp)
  jmp    L35
L41:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L42
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jl     L42
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  add    $0x1,%edx
  mov    %edx,(%rax)
L42:
  addl   $0x1,-0x10(%rbp)
L35:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L41
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L6
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <maximumElementInArray@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int lengthLongestIncreasingSubsequence(int A[], int n) {
  int *L = (int *)malloc(n * sizeof(int));
  int i, j;
  for (i = 0; i < n; i++) {
    L[i] = 1;
    for (j = 0; j < i; j++) {
      if (A[i] > A[j] && 1 + L[j] > L[i]) {
        L[i] = 1 + L[j];
      }
    }
  }
  int maximumLength = maximumElementInArray(L, n);
  free(L);
  return maximumLength;
}
```
user: What is the c source code of the assembly code below:

```asm
<lengthLongestIncreasingSubsequence>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %ebp,%ebp
  jle    L69
  movl   $0x1,(%rax)
  lea    0x4(%rax),%rcx
  lea    0x4(%r12),%rsi
  mov    $0x0,%r9d
  mov    %r12,%rdi
  sub    %rax,%rdi
  jmp    L20
L2:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L89
L18:
  mov    (%rdi,%rax,1),%edx
  cmp    %edx,(%rsi)
  jle    L2
  mov    (%rax),%edx
  cmp    (%r8),%edx
  jl     L2
  add    $0x1,%edx
  mov    %edx,(%r8)
  jmp    L2
L89:
  add    $0x4,%rcx
  add    $0x4,%rsi
L20:
  add    $0x1,%r9d
  cmp    %r9d,%ebp
  je     L69
  mov    %rcx,%r8
  movl   $0x1,(%rcx)
  test   %r9d,%r9d
  jle    L89
  mov    %rbx,%rax
  jmp    L18
L69:
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <maximumElementInArray@plt>
  mov    %eax,%ebp
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int lengthLongestIncreasingSubsequence(int A[], int n) {
  int *L = (int *)malloc(n * sizeof(int));
  int i, j;
  for (i = 0; i < n; i++) {
    L[i] = 1;
    for (j = 0; j < i; j++) {
      if (A[i] > A[j] && 1 + L[j] > L[i]) {
        L[i] = 1 + L[j];
      }
    }
  }
  int maximumLength = maximumElementInArray(L, n);
  free(L);
  return maximumLength;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<lengthLongestIncreasingSubsequence>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L2
  xor    %r9d,%r9d
  mov    %rbx,%rdi
  movl   $0x1,(%rax)
  lea    0x4(%rax),%rdx
  add    $0x1,%r9d
  lea    0x4(%rbx),%r8
  sub    %rax,%rdi
  cmp    %r9d,%r12d
  je     L2
  nopw   0x0(%rax,%rax,1)
L32:
  movl   $0x1,(%rdx)
  mov    %rbp,%rax
  nopl   0x0(%rax)
L7:
  mov    (%rdi,%rax,1),%ebx
  cmp    %ebx,(%r8)
  jle    L21
  mov    (%rax),%ecx
  cmp    (%rdx),%ecx
  jl     L21
  add    $0x1,%ecx
  mov    %ecx,(%rdx)
L21:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L7
  add    $0x1,%r9d
  add    $0x4,%rdx
  add    $0x4,%r8
  cmp    %r9d,%r12d
  jne    L32
L2:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <maximumElementInArray@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int lengthLongestIncreasingSubsequence(int A[], int n) {
  int *L = (int *)malloc(n * sizeof(int));
  int i, j;
  for (i = 0; i < n; i++) {
    L[i] = 1;
    for (j = 0; j < i; j++) {
      if (A[i] > A[j] && 1 + L[j] > L[i]) {
        L[i] = 1 + L[j];
      }
    }
  }
  int maximumLength = maximumElementInArray(L, n);
  free(L);
  return maximumLength;
}
```
user: What is the c source code of the assembly code below:

```asm
<lengthLongestIncreasingSubsequence>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    0x0(,%rsi,4),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %r12d,%r12d
  jle    L8
  mov    %rbx,%rdi
  movl   $0x1,(%rax)
  lea    0x4(%rax),%rdx
  lea    0x4(%rbx),%r8
  mov    $0x1,%r9d
  sub    %rax,%rdi
  cmp    $0x1,%r12d
  je     L8
  nopw   0x0(%rax,%rax,1)
L15:
  movl   $0x1,(%rdx)
  mov    %rbp,%rax
  nopl   0x0(%rax)
L4:
  mov    (%rdi,%rax,1),%ebx
  cmp    %ebx,(%r8)
  jle    L33
  mov    (%rax),%ecx
  cmp    (%rdx),%ecx
  jl     L33
  add    $0x1,%ecx
  mov    %ecx,(%rdx)
L33:
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L4
  add    $0x1,%r9d
  add    $0x4,%rdx
  add    $0x4,%r8
  cmp    %r9d,%r12d
  jne    L15
L8:
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <maximumElementInArray@plt>
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <free@plt>
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int lengthLongestIncreasingSubsequence(int A[], int n) {
  int *L = (int *)malloc(n * sizeof(int));
  int i, j;
  for (i = 0; i < n; i++) {
    L[i] = 1;
    for (j = 0; j < i; j++) {
      if (A[i] > A[j] && 1 + L[j] > L[i]) {
        L[i] = 1 + L[j];
      }
    }
  }
  int maximumLength = maximumElementInArray(L, n);
  free(L);
  return maximumLength;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sb_iir>:
  endbr64
  lea    D13(%rip),%rsi
  movslq %edi,%rax
  lea    (%rax,%rax,1),%rdx
  lea    (%rdx,%rax,1),%rcx
  movss  0x4(%rsi,%rcx,4),%xmm2
  movss  %xmm2,0x8(%rsi,%rcx,4)
  lea    D40(%rip),%rcx
  lea    (%rdx,%rax,1),%rdi
  movss  0x4(%rcx,%rdi,4),%xmm3
  movss  %xmm3,0x8(%rcx,%rdi,4)
  movss  (%rsi,%rdi,4),%xmm1
  movss  %xmm1,0x4(%rsi,%rdi,4)
  movss  (%rcx,%rdi,4),%xmm4
  movss  %xmm4,0x4(%rcx,%rdi,4)
  movss  %xmm0,(%rsi,%rdi,4)
  mulss  D43(%rip),%xmm1
  mulss  D3(%rip),%xmm4
  subss  %xmm4,%xmm1
  movss  D27(%rip),%xmm4
  mulss  %xmm4,%xmm0
  addss  %xmm1,%xmm0
  mulss  %xmm4,%xmm2
  mulss  D26(%rip),%xmm3
  subss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rcx,%rdi,4)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D43
datatype: f32
name: parse_data
arguments: data_tag: D3
datatype: byte[4]
name: parse_data
arguments: data_tag: D27
datatype: f32
name: parse_data
arguments: data_tag: D26
datatype: f32

tool: D43: 0.0671367410298401

tool: {"D3": [0x39,0xa1,0xb5,0xbf]}

tool: D27: 0.03356837051492005

tool: D26: 0.5532698896886828

assistant: ```c
float sb_iir(int i, float NewSample) {
  float ACoef[2 + 1] = {0.03356837051492005100, 0.06713674102984010200, 0.03356837051492005100};
  float BCoef[2 + 1] = {1.00000000000000000000, -1.41898265221812010000, 0.55326988968868285000};
  static float y[2][2 + 1];
  static float x[2][2 + 1];
  int n;
  for (n = 2; n > 0; n--) {
    x[i][n] = x[i][n - 1];
    y[i][n] = y[i][n - 1];
  }
  x[i][0] = NewSample;
  y[i][0] = ACoef[0] * x[i][0];
  for (n = 1; n <= 2; n++)
    y[i][0] += ACoef[n] * x[i][n] - BCoef[n] * y[i][n];
  return y[i][0];
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sb_iir>:
  endbr64
  movslq %edi,%rdi
  lea    D1(%rip),%rdx
  lea    D25(%rip),%rax
  lea    (%rdi,%rdi,2),%rcx
  shl    $0x2,%rcx
  add    %rcx,%rdx
  add    %rcx,%rax
  movss  (%rdx),%xmm1
  movss  (%rax),%xmm4
  movss  %xmm0,(%rdx)
  movss  0x4(%rdx),%xmm2
  movss  0x4(%rax),%xmm3
  movss  %xmm1,0x4(%rdx)
  mulss  D41(%rip),%xmm1
  movss  %xmm4,0x4(%rax)
  mulss  D24(%rip),%xmm4
  movss  %xmm2,0x8(%rdx)
  movss  %xmm3,0x8(%rax)
  mulss  D18(%rip),%xmm3
  subss  %xmm4,%xmm1
  movss  D23(%rip),%xmm4
  mulss  %xmm4,%xmm0
  mulss  %xmm4,%xmm2
  addss  %xmm1,%xmm0
  subss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  movss  %xmm0,(%rax)
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D41
type: f32
name: unpack_data
arguments: data_label: D24
type: byte[4]
name: unpack_data
arguments: data_label: D18
type: f32
name: unpack_data
arguments: data_label: D23
type: f32

tool: D41: 0.0671367410298401

tool: {"D24": [0x39,0xa1,0xb5,0xbf]}

tool: D18: 0.5532698896886828

tool: D23: 0.03356837051492005

assistant: ```c
float sb_iir(int i, float NewSample) {
  float ACoef[2 + 1] = {0.03356837051492005100, 0.06713674102984010200, 0.03356837051492005100};
  float BCoef[2 + 1] = {1.00000000000000000000, -1.41898265221812010000, 0.55326988968868285000};
  static float y[2][2 + 1];
  static float x[2][2 + 1];
  int n;
  for (n = 2; n > 0; n--) {
    x[i][n] = x[i][n - 1];
    y[i][n] = y[i][n - 1];
  }
  x[i][0] = NewSample;
  y[i][0] = ACoef[0] * x[i][0];
  for (n = 1; n <= 2; n++)
    y[i][0] += ACoef[n] * x[i][n] - BCoef[n] * y[i][n];
  return y[i][0];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sb_iir>:
  endbr64
  movslq %edi,%rdi
  lea    D10(%rip),%r8
  lea    D2(%rip),%rsi
  lea    (%rdi,%rdi,2),%rax
  movaps %xmm0,%xmm5
  shl    $0x2,%rax
  lea    (%r8,%rax,1),%rcx
  lea    (%rsi,%rax,1),%rdx
  movss  (%rcx),%xmm1
  movss  0x4(%rcx),%xmm2
  movss  0x4(%rdx),%xmm3
  movss  (%rdx),%xmm4
  unpcklps %xmm1,%xmm5
  movss  %xmm2,0x8(%rcx)
  movss  %xmm3,0x8(%rdx)
  mulss  D24(%rip),%xmm1
  movlps %xmm5,(%r8,%rax,1)
  movss  D30(%rip),%xmm5
  mulss  D40(%rip),%xmm3
  mulss  %xmm4,%xmm5
  subss  %xmm5,%xmm1
  movss  D41(%rip),%xmm5
  mulss  %xmm5,%xmm0
  mulss  %xmm5,%xmm2
  addss  %xmm1,%xmm0
  subss  %xmm3,%xmm2
  addss  %xmm2,%xmm0
  movaps %xmm0,%xmm1
  unpcklps %xmm4,%xmm1
  movlps %xmm1,(%rsi,%rax,1)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D24
datatype: f32
name: parse_data
arguments: data_tag: D30
datatype: byte[4]
name: parse_data
arguments: data_tag: D40
datatype: f32
name: parse_data
arguments: data_tag: D41
datatype: f32

tool: D24: 0.0671367410298401

tool: {"D30": [0x39,0xa1,0xb5,0xbf]}

tool: D40: 0.5532698896886828

tool: D41: 0.03356837051492005

assistant: ```c
float sb_iir(int i, float NewSample) {
  float ACoef[2 + 1] = {0.03356837051492005100, 0.06713674102984010200, 0.03356837051492005100};
  float BCoef[2 + 1] = {1.00000000000000000000, -1.41898265221812010000, 0.55326988968868285000};
  static float y[2][2 + 1];
  static float x[2][2 + 1];
  int n;
  for (n = 2; n > 0; n--) {
    x[i][n] = x[i][n - 1];
    y[i][n] = y[i][n - 1];
  }
  x[i][0] = NewSample;
  y[i][0] = ACoef[0] * x[i][0];
  for (n = 1; n <= 2; n++)
    y[i][0] += ACoef[n] * x[i][n] - BCoef[n] * y[i][n];
  return y[i][0];
}
```