ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x58,%rsp
  movdqa D27(%rip),%xmm0
  mov    $0x62,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    $0x6262,%eax
  lea    0x6(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  movaps %xmm0,0x10(%rsp)
  movdqa D31(%rip),%xmm0
  mov    %ax,0x40(%rsp)
  movabs $0x6262622a2a61622a,%rax
  movaps %xmm0,0x20(%rsp)
  movdqa D30(%rip),%xmm0
  mov    %rax,0x6(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x42(%rsp)
  mov    %dx,0xe(%rsp)
  movaps %xmm0,0x30(%rsp)
  call   <isMatch@plt>
  lea    D14(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x58,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D27
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D31
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D30
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_tag: D14
type_infered: string

tool: {"D27": [0x62,0x61,0x62,0x61,0x61,0x62,0x62,0x62,0x62,0x62,0x61,0x61,0x61,0x61,0x61,0x62]}

tool: {"D31": [0x62,0x61,0x61,0x62,0x61,0x62,0x62,0x61,0x61,0x61,0x61,0x61,0x61,0x61,0x62,0x62]}

tool: {"D30": [0x61,0x61,0x62,0x61,0x61,0x62,0x62,0x62,0x61,0x62,0x62,0x61,0x61,0x62,0x62,0x62]}

tool: D14: %d


assistant: ```c
int main(int argc, char *argv[]) {
  char s[] = {"babaabbbbbaaaaabbaababbaaaaaaabbaabaabbbabbaabbbbb"};
  char p[] = {"*ba**bbbb"};
  printf("%d\n", isMatch(s, p));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<call7j>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,%eax
  mov    %r8,-0x18(%rbp)
  mov    %r9d,%edi
  movsd  %xmm1,-0x28(%rbp)
  mov    0x10(%rbp),%edx
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %ax,-0x10(%rbp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x20(%rbp)
  mov    %edi,%eax
  mov    %al,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x2c(%rbp)
  movzwl -0x2c(%rbp),%r9d
  movzbl -0x1c(%rbp),%r10d
  pxor   %xmm2,%xmm2
  cvtss2sd -0x20(%rbp),%xmm2
  movq   %xmm2,%rdi
  movswl -0x10(%rbp),%edx
  movsbl -0x8(%rbp),%eax
  movsd  -0x28(%rbp),%xmm0
  mov    -0x18(%rbp),%rcx
  mov    -0xc(%rbp),%esi
  mov    -0x4(%rbp),%r8d
  push   %r8
  push   0x18(%rbp)
  movapd %xmm0,%xmm1
  mov    %r10d,%r8d
  movq   %rdi,%xmm0
  mov    %eax,%edi
  mov    $0x2,%eax
  call   <call7k@plt>
  add    $0x10,%rsp
  nop
  leave
  ret
```

assistant: ```c
call7j(ui, c, i, s, l, f, uc, d, us, ul) unsigned int ui;
char c;
int i;
short s;
long l;
float f;
unsigned char uc;
double d;
unsigned short us;
unsigned long ul;
{ call7k(c, i, s, l, f, uc, d, us, ul, ui); }
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<call7j>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,%r11d
  mov    %edx,%eax
  mov    %r8,%r10
  mov    %r9d,%r8d
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  movswl %cx,%edx
  movsbl %sil,%edi
  push   %r11
  push   0x20(%rsp)
  movzwl 0x20(%rsp),%r9d
  movzbl %r8b,%r8d
  mov    %r10,%rcx
  mov    %eax,%esi
  mov    $0x2,%eax
  call   <call7k@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
call7j(ui, c, i, s, l, f, uc, d, us, ul) unsigned int ui;
char c;
int i;
short s;
long l;
float f;
unsigned char uc;
double d;
unsigned short us;
unsigned long ul;
{ call7k(c, i, s, l, f, uc, d, us, ul, ui); }
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<call7j>:
  endbr64
  push   %rbp
  mov    0x18(%rsp),%rax
  mov    %edi,%ebp
  mov    %edx,%r10d
  mov    %r8,%r11
  mov    %r9d,%r8d
  movzwl 0x10(%rsp),%r9d
  movswl %cx,%edx
  movsbl %sil,%edi
  movzbl %r8b,%r8d
  mov    %r11,%rcx
  mov    %r10d,%esi
  mov    %rax,0x10(%rsp)
  mov    $0x2,%eax
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %ebp,0x18(%rsp)
  pop    %rbp
  jmp    1050 <call7k@plt>
```

assistant: ```c
call7j(ui, c, i, s, l, f, uc, d, us, ul) unsigned int ui;
char c;
int i;
short s;
long l;
float f;
unsigned char uc;
double d;
unsigned short us;
unsigned long ul;
{ call7k(c, i, s, l, f, uc, d, us, ul, ui); }
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<call7j>:
  endbr64
  push   %rbp
  mov    0x18(%rsp),%rax
  mov    %edi,%ebp
  mov    %edx,%r10d
  mov    %r8,%r11
  mov    %r9d,%r8d
  movzwl 0x10(%rsp),%r9d
  movswl %cx,%edx
  movsbl %sil,%edi
  movzbl %r8b,%r8d
  mov    %r11,%rcx
  mov    %r10d,%esi
  mov    %rax,0x10(%rsp)
  mov    $0x2,%eax
  cvtsd2ss %xmm0,%xmm0
  cvtss2sd %xmm0,%xmm0
  mov    %ebp,0x18(%rsp)
  pop    %rbp
  jmp    1050 <call7k@plt>
```

assistant: ```c
call7j(ui, c, i, s, l, f, uc, d, us, ul) unsigned int ui;
char c;
int i;
short s;
long l;
float f;
unsigned char uc;
double d;
unsigned short us;
unsigned long ul;
{ call7k(c, i, s, l, f, uc, d, us, ul, ui); }
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xbc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xbc(%rbp),%edx
  lea    -0xb0(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <input@plt>
  lea    -0xb8(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xb8(%rbp),%edx
  lea    -0x60(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <input@plt>
  mov    -0xb8(%rbp),%ecx
  mov    -0xbc(%rbp),%edx
  lea    -0x60(%rbp),%rsi
  lea    -0xb0(%rbp),%rax
  mov    %rax,%rdi
  call   <check@plt>
  mov    %eax,-0xb4(%rbp)
  cmpl   $0x1,-0xb4(%rbp)
  jne    L37
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L28
L37:
  cmpl   $0xffffffff,-0xb4(%rbp)
  jne    L28
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L28:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D15
type: string
name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D2
type: string

tool: D15: %d

tool: D18: YES


tool: D2: NO


assistant: ```c
int main() {
  int N1, A1[20], N2, A2[20], b;
  scanf("%d", &N1);
  input(A1, N1);
  scanf("%d", &N2);
  input(A2, N2);
  b = check(A1, A2, N1, N2);
  if (b == 1)
    printf("YES\n");
  else if (b == -1)
    printf("NO\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D11(%rip),%rbp
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rbx
  mov    0x8(%rsp),%esi
  mov    %rbx,%rdi
  call   <input@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  lea    0x60(%rsp),%rbp
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  call   <input@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L5
  cmp    $0xffffffff,%eax
  je     L41
L43:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  mov    $0x0,%eax
  add    $0xc8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L41:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L43
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D11
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D26
data_type: string

tool: D11: %d

tool: D18: YES


tool: D26: NO


assistant: ```c
int main() {
  int N1, A1[20], N2, A2[20], b;
  scanf("%d", &N1);
  input(A1, N1);
  scanf("%d", &N2);
  input(A2, N2);
  b = check(A1, A2, N1, N2);
  if (b == 1)
    printf("YES\n");
  else if (b == -1)
    printf("NO\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D14(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <input@plt>
  mov    %r12,%rdi
  lea    0xc(%rsp),%rsi
  lea    0x60(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <input@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L23
  cmp    $0xffffffff,%eax
  je     L42
L10:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L23:
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L42:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
type_infered: string
name: extract_symbolic_data
arguments: label: D27
type_infered: string
name: extract_symbolic_data
arguments: label: D8
type_infered: string

tool: D14: %d

tool: D27: YES


tool: D8: NO


assistant: ```c
int main() {
  int N1, A1[20], N2, A2[20], b;
  scanf("%d", &N1);
  input(A1, N1);
  scanf("%d", &N2);
  input(A2, N2);
  b = check(A1, A2, N1, N2);
  if (b == 1)
    printf("YES\n");
  else if (b == -1)
    printf("NO\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0xc8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xb8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%esi
  mov    %rbp,%rdi
  call   <input@plt>
  mov    %r12,%rdi
  lea    0xc(%rsp),%rsi
  lea    0x60(%rsp),%r12
  call   <scanf@plt>
  mov    0xc(%rsp),%esi
  mov    %r12,%rdi
  call   <input@plt>
  mov    0xc(%rsp),%ecx
  mov    0x8(%rsp),%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <check@plt>
  cmp    $0x1,%eax
  je     L3
  cmp    $0xffffffff,%eax
  je     L28
L40:
  mov    0xb8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0xc8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L28:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L40
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D19
data_type: string
name: parse_data
arguments: tag: D6
data_type: string
name: parse_data
arguments: tag: D18
data_type: string

tool: D19: %d

tool: D6: YES


tool: D18: NO


assistant: ```c
int main() {
  int N1, A1[20], N2, A2[20], b;
  scanf("%d", &N1);
  input(A1, N1);
  scanf("%d", &N2);
  input(A2, N2);
  b = check(A1, A2, N1, N2);
  if (b == 1)
    printf("YES\n");
  else if (b == -1)
    printf("NO\n");
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_recv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L15
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listening@plt>
L15:
  cmpl   $0x0,-0x4(%rbp)
  jne    L8
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listening@plt>
  nop
L8:
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D5
type_infered: string
name: read_data
arguments: data_label: D8
type_infered: string

tool: D5: Receive error!


tool: D8: No data received!


assistant: ```c
void check_recv(int recv_res) {
  if (recv_res == -1) {
    printf("Receive error!\n");
    listening();
  }
  if (recv_res == 0) {
    printf("No data received!\n");
    listening();
  }
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<check_recv>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  je     L26
  test   %edi,%edi
  je     L0
L24:
  add    $0x8,%rsp
  ret
L26:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listening@plt>
  jmp    L24
L0:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <listening@plt>
  jmp    L24
```

tool_calls: name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D5
type: string

tool: D16: Receive error!


tool: D5: No data received!


assistant: ```c
void check_recv(int recv_res) {
  if (recv_res == -1) {
    printf("Receive error!\n");
    listening();
  }
  if (recv_res == 0) {
    printf("No data received!\n");
    listening();
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check_recv>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  je     L11
  test   %edi,%edi
  je     L4
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <listening@plt>
  nopw   0x0(%rax,%rax,1)
L11:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <listening@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D6: No data received!


tool: D4: Receive error!


assistant: ```c
void check_recv(int recv_res) {
  if (recv_res == -1) {
    printf("Receive error!\n");
    listening();
  }
  if (recv_res == 0) {
    printf("No data received!\n");
    listening();
  }
  return;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_recv>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0xffffffff,%edi
  je     L4
  test   %edi,%edi
  je     L14
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L14:
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <listening@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  lea    D14(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <listening@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D14
data_type: string

tool: D9: No data received!


tool: D14: Receive error!


assistant: ```c
void check_recv(int recv_res) {
  if (recv_res == -1) {
    printf("Receive error!\n");
    listening();
  }
  if (recv_res == 0) {
    printf("No data received!\n");
    listening();
  }
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  jmp    L13
L8:
  cmpl   $0x3,-0x4(%rbp)
  jle    L30
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x4,-0x4(%rbp)
  jmp    L13
L30:
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x0,-0x4(%rbp)
  jg     L8
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D13
type_guessed: string

tool: D6: (tab)

tool: D13: (spc)

assistant: ```c
void printSpaces(int n) {
  while (n > 0) {
    if (n >= 4) {
      printf("(tab)");
      n -= 4;
    } else {
      printf("(spc)");
      n--;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printSpaces>:
  endbr64
  test   %edi,%edi
  jle    L2
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  lea    D7(%rip),%r12
  lea    D12(%rip),%rbp
  jmp    L20
L21:
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
L11:
  test   %ebx,%ebx
  jle    L35
L20:
  cmp    $0x3,%ebx
  jle    L21
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x4,%ebx
  jmp    L11
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L2:
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_infered: string
name: read_data
arguments: data_tag: D12
type_infered: string

tool: D7: (spc)

tool: D12: (tab)

assistant: ```c
void printSpaces(int n) {
  while (n > 0) {
    if (n >= 4) {
      printf("(tab)");
      n -= 4;
    } else {
      printf("(spc)");
      n--;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printSpaces>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  jmp    L29
  xchg   %ax,%ax
L7:
  mov    %rbp,%rdi
  sub    $0x4,%ebx
  call   <printf@plt>
  test   %ebx,%ebx
  je     L15
L29:
  cmp    $0x3,%ebx
  jg     L7
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <printf@plt>
  test   %ebx,%ebx
  jne    L29
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
data_type: string
name: retrieve_data
arguments: data_tag: D18
data_type: string

tool: D4: (spc)

tool: D18: (tab)

assistant: ```c
void printSpaces(int n) {
  while (n > 0) {
    if (n >= 4) {
      printf("(tab)");
      n -= 4;
    } else {
      printf("(spc)");
      n--;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printSpaces>:
  endbr64
  test   %edi,%edi
  jle    L21
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    %edi,%ebx
  nopl   0x0(%rax)
L5:
  cmp    $0x3,%ebx
  jle    L26
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x4,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L26:
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L21:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_guessed: string
name: extract_symbolic_data
arguments: tag: D16
type_guessed: string

tool: D4: (spc)

tool: D16: (tab)

assistant: ```c
void printSpaces(int n) {
  while (n > 0) {
    if (n >= 4) {
      printf("(tab)");
      n -= 4;
    } else {
      printf("(spc)");
      n--;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cal_bx>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %rdx,-0x68(%rbp)
  movsd  %xmm0,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x60(%rbp),%rdx
  lea    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <crstrns@plt>
  mov    -0x70(%rbp),%rcx
  lea    -0x50(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  movq   %rcx,%xmm0
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  jne    L28
  mov    $0xffffffff,%eax
  jmp    L22
L28:
  mov    -0x68(%rbp),%rdx
  lea    -0x30(%rbp),%rcx
  mov    -0x58(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <mm_mul@plt>
  mov    $0x0,%eax
L22:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

assistant: ```c
int cal_bx(double *bx, double *vx, double *ex, const double eps) {
  double t[4], s[4];
  crstrns(t, vx);
  if (inverse(s, t, eps) == -1)
    return (-1);
  mm_mul(bx, s, ex);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cal_bx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <crstrns@plt>
  lea    0x20(%rsp),%rdi
  movq   %rbx,%xmm0
  mov    %r13,%rsi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L5
  lea    0x20(%rsp),%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <mm_mul@plt>
  mov    $0x0,%eax
L5:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cal_bx(double *bx, double *vx, double *ex, const double eps) {
  double t[4], s[4];
  crstrns(t, vx);
  if (inverse(s, t, eps) == -1)
    return (-1);
  mm_mul(bx, s, ex);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cal_bx>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x68,%rsp
  lea    0x10(%rsp),%rbp
  movsd  %xmm0,0x8(%rsp)
  lea    0x30(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <crstrns@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L18
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <mm_mul@plt>
  xor    %eax,%eax
L18:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cal_bx(double *bx, double *vx, double *ex, const double eps) {
  double t[4], s[4];
  crstrns(t, vx);
  if (inverse(s, t, eps) == -1)
    return (-1);
  mm_mul(bx, s, ex);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cal_bx>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  sub    $0x68,%rsp
  lea    0x10(%rsp),%rbp
  movsd  %xmm0,0x8(%rsp)
  lea    0x30(%rsp),%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <crstrns@plt>
  movsd  0x8(%rsp),%xmm0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <inverse@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <mm_mul@plt>
  xor    %eax,%eax
L2:
  mov    0x58(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L14
  add    $0x68,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int cal_bx(double *bx, double *vx, double *ex, const double eps) {
  double t[4], s[4];
  crstrns(t, vx);
  if (inverse(s, t, eps) == -1)
    return (-1);
  mm_mul(bx, s, ex);
  return (0);
}
```