ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<rlemap_unpack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x16(%rbp)
  mov    -0x28(%rbp),%rax
  add    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L37
L66:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x17(%rbp)
  movzbl -0x17(%rbp),%eax
  and    $0x7f,%eax
  add    $0x1,%eax
  mov    %ax,-0x12(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  or     %edx,%eax
  mov    %ax,-0x14(%rbp)
  addq   $0x2,-0x10(%rbp)
  movzbl -0x17(%rbp),%eax
  test   %al,%al
  jns    L61
  jmp    L49
L6:
  movzwl -0x14(%rbp),%edx
  lea    0x1(%rdx),%eax
  mov    %ax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    %dx,(%rax)
L49:
  movzwl -0x12(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x12(%rbp)
  test   %ax,%ax
  jne    L6
  jmp    L37
L31:
  mov    -0x8(%rbp),%rax
  lea    0x2(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzwl -0x14(%rbp),%edx
  mov    %dx,(%rax)
L61:
  movzwl -0x12(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x12(%rbp)
  test   %ax,%ax
  jne    L31
L37:
  movzwl -0x16(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %dx,-0x16(%rbp)
  test   %ax,%ax
  jne    L66
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rlemap_unpack(unsigned char *src, unsigned char *dest) {
  unsigned char *s;
  unsigned short *d;
  unsigned short blocnum;
  blocnum = *((unsigned short *)src);
  s = src + 2;
  d = (unsigned short *)dest;
  while (blocnum--) {
    unsigned short data;
    const unsigned char v8 = *s++;
    unsigned short len = (v8 & 0x7F) + 1;
    data = (s[0] << 8) | (s[1] << 0);
    s += 2;
    if (v8 & 0x80) {
      while (len--)
        *d++ = data++;
    } else {
      while (len--)
        *d++ = data;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rlemap_unpack>:
  endbr64
  mov    %rsi,%r8
  movzwl (%rdi),%edx
  lea    0x2(%rdi),%rsi
  lea    -0x1(%rdx),%eax
  test   %dx,%dx
  je     L5
  movzwl %ax,%eax
  lea    0x5(%rax,%rax,2),%rax
  lea    (%rdi,%rax,1),%r9
  jmp    L38
L41:
  add    $0x1,%eax
  movzbl %al,%eax
  lea    (%r8,%rax,2),%r10
  mov    %r8,%rax
L55:
  mov    %edx,%ecx
  add    $0x1,%edx
  add    $0x2,%rax
  mov    %cx,-0x2(%rax)
  cmp    %rax,%r10
  jne    L55
  movzbl %dil,%edi
  lea    (%r8,%rdi,2),%r8
L54:
  cmp    %rsi,%r9
  je     L5
L38:
  movzbl (%rsi),%r10d
  mov    %r10d,%eax
  and    $0x7f,%eax
  lea    0x1(%rax),%edi
  movzbl 0x1(%rsi),%ecx
  shl    $0x8,%ecx
  movzbl 0x2(%rsi),%edx
  or     %ecx,%edx
  add    $0x3,%rsi
  test   %r10b,%r10b
  js     L41
  movzbl %dil,%eax
  lea    (%r8,%rax,2),%rcx
  mov    %r8,%rax
L21:
  add    $0x2,%rax
  mov    %dx,-0x2(%rax)
  cmp    %rcx,%rax
  jne    L21
  movzbl %dil,%edi
  lea    (%r8,%rdi,2),%r8
  jmp    L54
L5:
  ret
```

assistant: ```c
void rlemap_unpack(unsigned char *src, unsigned char *dest) {
  unsigned char *s;
  unsigned short *d;
  unsigned short blocnum;
  blocnum = *((unsigned short *)src);
  s = src + 2;
  d = (unsigned short *)dest;
  while (blocnum--) {
    unsigned short data;
    const unsigned char v8 = *s++;
    unsigned short len = (v8 & 0x7F) + 1;
    data = (s[0] << 8) | (s[1] << 0);
    s += 2;
    if (v8 & 0x80) {
      while (len--)
        *d++ = data++;
    } else {
      while (len--)
        *d++ = data;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rlemap_unpack>:
  endbr64
  movzwl (%rdi),%edx
  mov    %rsi,%r9
  lea    0x2(%rdi),%r8
  lea    -0x1(%rdx),%eax
  test   %dx,%dx
  je     L42
  movzwl %ax,%eax
  lea    0x5(%rax,%rax,2),%rax
  lea    (%rdi,%rax,1),%r10
  nopw   0x0(%rax,%rax,1)
L2:
  movzbl (%r8),%eax
  movzwl 0x1(%r8),%edx
  add    $0x3,%r8
  mov    %eax,%ecx
  rol    $0x8,%dx
  and    $0x7f,%ecx
  add    $0x1,%ecx
  movzbl %cl,%ecx
  test   %al,%al
  js     L39
  lea    (%r9,%rcx,2),%rsi
  mov    %r9,%rax
  nop
L44:
  add    $0x2,%rax
  mov    %dx,-0x2(%rax)
  cmp    %rax,%rsi
  jne    L44
  lea    (%r9,%rcx,2),%r9
  cmp    %r10,%r8
  jne    L2
L42:
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  lea    (%r9,%rcx,2),%rdi
  mov    %r9,%rax
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %edx,%esi
  add    $0x2,%rax
  add    $0x1,%edx
  mov    %si,-0x2(%rax)
  cmp    %rax,%rdi
  jne    L63
  lea    (%r9,%rcx,2),%r9
  cmp    %r10,%r8
  jne    L2
  jmp    L42
```

assistant: ```c
void rlemap_unpack(unsigned char *src, unsigned char *dest) {
  unsigned char *s;
  unsigned short *d;
  unsigned short blocnum;
  blocnum = *((unsigned short *)src);
  s = src + 2;
  d = (unsigned short *)dest;
  while (blocnum--) {
    unsigned short data;
    const unsigned char v8 = *s++;
    unsigned short len = (v8 & 0x7F) + 1;
    data = (s[0] << 8) | (s[1] << 0);
    s += 2;
    if (v8 & 0x80) {
      while (len--)
        *d++ = data++;
    } else {
      while (len--)
        *d++ = data;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<SeleccionPadres>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x98(%rbp)
  mov    %rsi,-0xa0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x88(%rbp)
  jmp    L36
L17:
  mov    $0x0,%eax
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  mov    -0x88(%rbp),%eax
  cltq
  movss  %xmm0,-0x80(%rbp,%rax,4)
  addl   $0x1,-0x88(%rbp)
L36:
  cmpl   $0x1d,-0x88(%rbp)
  jle    L17
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x84(%rbp)
  jmp    L0
L38:
  movl   $0x1e,-0x88(%rbp)
L27:
  subl   $0x1,-0x88(%rbp)
  mov    -0x88(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0xa0(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm1
  mov    -0x84(%rbp),%eax
  cltq
  movss  -0x80(%rbp,%rax,4),%xmm0
  comiss %xmm1,%xmm0
  jae    L27
  mov    -0x84(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x98(%rbp),%rax
  add    %rax,%rdx
  mov    $0x1e,%eax
  sub    -0x88(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x84(%rbp)
L0:
  cmpl   $0x1d,-0x84(%rbp)
  jle    L38
  mov    -0x98(%rbp),%rax
  mov    0x78(%rax),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D13: Aleatorios generados: 

tool: D10: 


assistant: ```c
int SeleccionPadres(int padres[30], float acum[30]) {
  int i, x;
  float lista_aleatorios[30];
  printf("Aleatorios generados: ");
  for (i = 0; i < 30; i++) {
    lista_aleatorios[i] = drand48() * 1;
  }
  printf("\n");
  for (x = 0; x < 30; x++) {
    i = 30;
    do {
      i--;
    } while (acum[i] <= lista_aleatorios[x]);
    padres[x] = (30 - i);
  }
  return padres[30];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SeleccionPadres>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x88,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%r12
  lea    0x78(%rsp),%r13
L28:
  mov    $0x0,%eax
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,(%r12)
  add    $0x4,%r12
  cmp    %r13,%r12
  jne    L28
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ecx
  mov    $0x1e,%esi
L18:
  movss  (%rsp,%rcx,1),%xmm0
  mov    $0x1d,%eax
L37:
  mov    %eax,%edx
  sub    $0x1,%rax
  comiss 0x4(%rbx,%rax,4),%xmm0
  jae    L37
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x78,%rcx
  jne    L18
  mov    0x78(%rbp),%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x88,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
type: string
name: retrieve_data
arguments: label: D5
type: string

tool: D0: Aleatorios generados: 

tool: D5: 


assistant: ```c
int SeleccionPadres(int padres[30], float acum[30]) {
  int i, x;
  float lista_aleatorios[30];
  printf("Aleatorios generados: ");
  for (i = 0; i < 30; i++) {
    lista_aleatorios[i] = drand48() * 1;
  }
  printf("\n");
  for (x = 0; x < 30; x++) {
    i = 30;
    do {
      i--;
    } while (acum[i] <= lista_aleatorios[x]);
    padres[x] = (30 - i);
  }
  return padres[30];
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<SeleccionPadres>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D16(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x78(%rsp),%r14
  call   <printf@plt>
  mov    %r12,%r13
  nopl   (%rax)
L10:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%r13)
  cmp    %r14,%r13
  jne    L10
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %ecx,%ecx
  mov    $0x1e,%esi
  nopl   0x0(%rax)
L5:
  movss  (%r12,%rcx,1),%xmm0
  mov    $0x1d,%eax
  nopl   0x0(%rax,%rax,1)
L9:
  mov    %eax,%edx
  sub    $0x1,%rax
  comiss 0x4(%rbx,%rax,4),%xmm0
  jae    L9
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x78,%rcx
  jne    L5
  mov    0x78(%rbp),%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L32
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D16
type_guessed: string
name: retrieve_data
arguments: data_label: D4
type_guessed: string

tool: D16: Aleatorios generados: 

tool: D4: 


assistant: ```c
int SeleccionPadres(int padres[30], float acum[30]) {
  int i, x;
  float lista_aleatorios[30];
  printf("Aleatorios generados: ");
  for (i = 0; i < 30; i++) {
    lista_aleatorios[i] = drand48() * 1;
  }
  printf("\n");
  for (x = 0; x < 30; x++) {
    i = 30;
    do {
      i--;
    } while (acum[i] <= lista_aleatorios[x]);
    padres[x] = (30 - i);
  }
  return padres[30];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<SeleccionPadres>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D3(%rip),%rdi
  push   %rbx
  mov    %rsi,%rbx
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x78(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x78(%rsp),%r14
  call   <printf@plt>
  mov    %r12,%r13
  nopl   (%rax)
L35:
  xor    %eax,%eax
  add    $0x4,%r13
  call   <drand48@plt>
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  %xmm0,-0x4(%r13)
  cmp    %r14,%r13
  jne    L35
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %ecx,%ecx
  mov    $0x1e,%esi
  nopl   0x0(%rax)
L27:
  movss  (%r12,%rcx,1),%xmm0
  mov    $0x1d,%eax
  nopl   0x0(%rax,%rax,1)
L29:
  mov    %eax,%edx
  sub    $0x1,%rax
  comiss 0x4(%rbx,%rax,4),%xmm0
  jae    L29
  mov    %esi,%eax
  sub    %edx,%eax
  mov    %eax,0x0(%rbp,%rcx,1)
  add    $0x4,%rcx
  cmp    $0x78,%rcx
  jne    L27
  mov    0x78(%rbp),%eax
  mov    0x78(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  sub    $0xffffffffffffff80,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D3
type_guessed: string
name: parse_data
arguments: data_label: D2
type_guessed: string

tool: D3: Aleatorios generados: 

tool: D2: 


assistant: ```c
int SeleccionPadres(int padres[30], float acum[30]) {
  int i, x;
  float lista_aleatorios[30];
  printf("Aleatorios generados: ");
  for (i = 0; i < 30; i++) {
    lista_aleatorios[i] = drand48() * 1;
  }
  printf("\n");
  for (x = 0; x < 30; x++) {
    i = 30;
    do {
      i--;
    } while (acum[i] <= lista_aleatorios[x]);
    padres[x] = (30 - i);
  }
  return padres[30];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x38(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x30(%rbp)
  jmp    L49
L47:
  movq   $0x1,-0x20(%rbp)
  movl   $0x0,-0x28(%rbp)
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L36
L61:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x34(%rbp)
  addl   $0x1,-0x24(%rbp)
L36:
  mov    -0x34(%rbp),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  test   %edx,%edx
  je     L61
  movl   $0x5,-0x2c(%rbp)
  jmp    L73
L59:
  mov    -0x34(%rbp),%eax
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L66
  addl   $0x1,-0x28(%rbp)
L66:
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  mov    %eax,-0x2c(%rbp)
L73:
  mov    -0x34(%rbp),%eax
  cmp    %eax,-0x2c(%rbp)
  jle    L59
  mov    -0x34(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <pow@plt>
  imul   %rax,%rbx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  imul   %rbx,%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x30(%rbp)
L49:
  mov    -0x38(%rbp),%eax
  cmp    %eax,-0x30(%rbp)
  jl     L47
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L51
  call   <__stack_chk_fail@plt>
L51:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D17
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string

tool: D17: %d

tool: D27: %lld


assistant: ```c
int main() {
  int i, j, c, n, len, num, temp, t, res;
  long long int ans;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    ans = 1;
    c = 0;
    scanf("%d", &num);
    temp = 0;
    while (num % 10 == 0) {
      num /= 10;
      temp++;
    }
    for (j = 5; j <= num; j = j * 5)
      if (num % j == 0)
        c++;
    printf("%lld\n", (long long int)num * (long long int)pow(4, (int)(c + 1) / 2) * (long long int)pow(10, temp));
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,(%rsp)
  jle    L39
  mov    $0x0,%r12d
  lea    0x4(%rsp),%r15
  lea    D1(%rip),%r14
  lea    D5(%rip),%r13
L57:
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ebx
  movslq %ebx,%rbp
  imul   $0x66666667,%rbp,%rbp
  sar    $0x22,%rbp
  mov    %ebx,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebp
  lea    0x0(%rbp,%rbp,4),%eax
  add    %eax,%eax
  mov    %ebx,%ebp
  sub    %eax,%ebp
  jne    L37
L69:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%ebx
  sub    %ebx,%eax
  mov    %eax,%ebx
  add    $0x1,%ebp
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  cmp    %edx,%eax
  je     L69
  mov    %eax,0x4(%rsp)
L49:
  cmp    $0x4,%ebx
  jle    L77
  mov    $0x0,%esi
  mov    $0x5,%ecx
L24:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cmp    $0x1,%edx
  adc    $0x0,%esi
  lea    (%rcx,%rcx,4),%eax
  mov    %eax,%ecx
  cmp    %ebx,%eax
  jle    L24
L41:
  add    $0x1,%esi
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %eax,%esi
  sar    %esi
  mov    $0x4,%edi
  call   <pow@plt>
  movslq %ebx,%rbx
  imul   %rax,%rbx
  mov    %ebp,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %rbx,%rsi
  imul   %rax,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,(%rsp)
  jg     L57
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  mov    $0x0,%ebp
  jmp    L49
L77:
  mov    $0x0,%esi
  jmp    L41
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type: string
name: disassemble_data
arguments: data_label: D5
type: string

tool: D1: %d

tool: D5: %lld


assistant: ```c
int main() {
  int i, j, c, n, len, num, temp, t, res;
  long long int ans;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    ans = 1;
    c = 0;
    scanf("%d", &num);
    temp = 0;
    while (num % 10 == 0) {
      num /= 10;
      temp++;
    }
    for (j = 5; j <= num; j = j * 5)
      if (num % j == 0)
        c++;
    printf("%lld\n", (long long int)num * (long long int)pow(4, (int)(c + 1) / 2) * (long long int)pow(10, temp));
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r14
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L73
  nopl   (%rax)
L84:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rbx
  imul   $0x66666667,%rbx,%r15
  mov    %ebx,%eax
  mov    %rbx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%r15
  sub    %eax,%r15d
  lea    (%r15,%r15,4),%eax
  mov    %ebx,%r15d
  add    %eax,%eax
  sub    %eax,%r15d
  je     L71
  jmp    L61
  nopl   0x0(%rax)
L20:
  movslq %ebx,%rbx
L71:
  imul   $0x66666667,%rbx,%rbx
  mov    %ecx,%eax
  add    $0x1,%r15d
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  imul   $0xcccccccd,%ebx,%eax
  mov    %ebx,%ecx
  add    $0x19999998,%eax
  ror    %eax
  cmp    $0x19999998,%eax
  jbe    L20
  mov    %ebx,0x4(%rsp)
  movslq %ebx,%rbx
L9:
  xor    %esi,%esi
  cmp    $0x4,%ecx
  jle    L24
  mov    $0x5,%edi
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  lea    (%rdi,%rdi,4),%edi
  cmp    $0x1,%edx
  adc    $0x0,%esi
  cmp    %ecx,%edi
  jle    L18
  add    $0x1,%esi
  sar    %esi
L24:
  mov    $0x4,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %r15d,%esi
  mov    $0xa,%edi
  imul   %rax,%rbx
  call   <pow@plt>
  mov    %r13,%rdi
  mov    %rbx,%rsi
  imul   %rax,%rsi
  call   <printf@plt>
  cmp    %ebp,(%rsp)
  jg     L84
L73:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L61:
  xor    %r15d,%r15d
  jmp    L9
L86:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
datatype: string
name: unpack_data
arguments: tag: D0
datatype: string

tool: D17: %lld


tool: D0: %d

assistant: ```c
int main() {
  int i, j, c, n, len, num, temp, t, res;
  long long int ans;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    ans = 1;
    c = 0;
    scanf("%d", &num);
    temp = 0;
    while (num % 10 == 0) {
      num /= 10;
      temp++;
    }
    for (j = 5; j <= num; j = j * 5)
      if (num % j == 0)
        c++;
    printf("%lld\n", (long long int)num * (long long int)pow(4, (int)(c + 1) / 2) * (long long int)pow(10, temp));
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%r14
  call   <scanf@plt>
  mov    (%rsp),%eax
  test   %eax,%eax
  jle    L88
  nopl   (%rax)
L80:
  mov    %r14,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rbx
  imul   $0x66666667,%rbx,%r15
  mov    %ebx,%eax
  mov    %rbx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%r15
  sub    %eax,%r15d
  lea    (%r15,%r15,4),%eax
  mov    %ebx,%r15d
  add    %eax,%eax
  sub    %eax,%r15d
  je     L66
  jmp    L57
  nopl   0x0(%rax)
L30:
  movslq %ebx,%rbx
L66:
  imul   $0x66666667,%rbx,%rbx
  mov    %ecx,%eax
  add    $0x1,%r15d
  sar    $0x1f,%eax
  sar    $0x22,%rbx
  sub    %eax,%ebx
  imul   $0xcccccccd,%ebx,%eax
  mov    %ebx,%ecx
  add    $0x19999998,%eax
  ror    %eax
  cmp    $0x19999998,%eax
  jbe    L30
  mov    %ebx,0x4(%rsp)
  movslq %ebx,%rbx
L25:
  xor    %esi,%esi
  cmp    $0x4,%ecx
  jle    L51
  mov    $0x5,%edi
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %ecx,%eax
  cltd
  idiv   %edi
  lea    (%rdi,%rdi,4),%edi
  cmp    $0x1,%edx
  adc    $0x0,%esi
  cmp    %ecx,%edi
  jle    L33
  add    $0x1,%esi
  sar    %esi
L51:
  mov    $0x4,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %r15d,%esi
  mov    $0xa,%edi
  imul   %rax,%rbx
  call   <pow@plt>
  mov    %r13,%rdi
  mov    %rbx,%rsi
  imul   %rax,%rsi
  call   <printf@plt>
  cmp    %ebp,(%rsp)
  jg     L80
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L57:
  xor    %r15d,%r15d
  jmp    L25
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
datatype: string
name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D0: %lld


tool: D2: %d

assistant: ```c
int main() {
  int i, j, c, n, len, num, temp, t, res;
  long long int ans;
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    ans = 1;
    c = 0;
    scanf("%d", &num);
    temp = 0;
    while (num % 10 == 0) {
      num /= 10;
      temp++;
    }
    for (j = 5; j <= num; j = j * 5)
      if (num % j == 0)
        c++;
    printf("%lld\n", (long long int)num * (long long int)pow(4, (int)(c + 1) / 2) * (long long int)pow(10, temp));
  }
  return 0;
}
```