ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<GetPhaseVal>:
  endbr64
  cvttsd2si %xmm0,%eax
  pxor   %xmm1,%xmm1
  movsd  D27(%rip),%xmm4
  cvtsi2sd %eax,%xmm1
  cltq
  movsd  0x8(%rdi,%rax,8),%xmm2
  subsd  %xmm1,%xmm0
  movsd  (%rdi,%rax,8),%xmm1
  movapd %xmm1,%xmm3
  subsd  %xmm2,%xmm3
  comisd %xmm4,%xmm3
  jbe    L1
  addsd  D7(%rip),%xmm2
  subsd  %xmm1,%xmm2
  movapd %xmm2,%xmm3
L6:
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  ret
L1:
  movapd %xmm2,%xmm3
  subsd  %xmm1,%xmm3
  comisd %xmm4,%xmm3
  jbe    L6
  addsd  D7(%rip),%xmm1
  subsd  %xmm1,%xmm2
  movapd %xmm2,%xmm3
  mulsd  %xmm3,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

tool_calls: name: parse_data
arguments: data_label: D27
type: byte[8]
name: parse_data
arguments: data_label: D7
type: f64

tool: {"D27": [0xd2,0x21,0x33,0x7f,0x7c,0xd9,0x12,0x40]}

tool: D7: 6.283185307179586

assistant: ```c
double GetPhaseVal(double *pPhaseSpectrum, double fPeakLoc) {
  int bin = (int)fPeakLoc;
  double fFraction = fPeakLoc - bin, fLeftPha = pPhaseSpectrum[bin], fRightPha = pPhaseSpectrum[bin + 1];
  if (fLeftPha - fRightPha > 1.5 * 3.141592653589793238462643)
    fRightPha += 6.28318530717958647692;
  else if (fRightPha - fLeftPha > 1.5 * 3.141592653589793238462643)
    fLeftPha += 6.28318530717958647692;
  return fLeftPha + fFraction * (fRightPha - fLeftPha);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  lea    D34(%rip),%rdi
  call   <printf@plt>
L88:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L21
  mov    %ebx,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L88
  mov    %ebx,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  jmp    L88
L21:
  lea    D14(%rip),%rdi
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  cmp    $0xa,%eax
  je     L90
  mov    %ebx,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L20
  mov    %ebx,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cltq
  subl   $0x1,(%rsp,%rax,4)
  jmp    L20
L90:
  mov    %rsp,%rax
  lea    0x68(%rsp),%rcx
  lea    0x64(%rsp),%rdx
  jmp    L74
L81:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L17
L93:
  add    $0x4,%rax
  cmp    %rcx,%rax
  je     L17
L74:
  cmpl   $0x0,(%rax)
  jne    L81
  cmp    %rdx,%rax
  jne    L93
  lea    D13(%rip),%rdi
  call   <printf@plt>
L17:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L106
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L106:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D34
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string
name: unpack_data
arguments: data_tag: D4
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D34: Enter the first word: 

tool: D14: Enter the second word: 

tool: D4: The words are not anagrams


tool: D13: The words are anagrams


assistant: ```c
int main(void) {
  int alphabet[26] = {0};
  int letter;
  int i;
  printf("Enter the first word: ");
  while ((letter = getchar()) != '\n') {
    if (isalpha(letter)) {
      letter = toupper(letter);
      alphabet[letter - 65] += 1;
    } else {
      continue;
    }
  }
  printf("Enter the second word: ");
  while ((letter = getchar()) != '\n') {
    if (isalpha(letter)) {
      letter = toupper(letter);
      alphabet[letter - 65] -= 1;
    } else {
      continue;
    }
  }
  i = 0;
  while (i < 26) {
    if (alphabet[i] != 0) {
      printf("The words are not anagrams\n");
      break;
    }
    if (i == 25 && alphabet[i] == 0) {
      printf("The words are anagrams\n");
    }
    i += 1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xd,%ecx
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D25(%rip),%rdi
  call   <printf@plt>
L61:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  je     L67
L111:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L61
  mov    %ebp,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  jne    L111
L67:
  lea    D22(%rip),%rdi
  call   <printf@plt>
L119:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  je     L26
L103:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L119
  mov    %ebp,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cltq
  subl   $0x1,(%rsp,%rax,4)
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  jne    L103
L26:
  mov    %rbx,%rdi
  lea    0x68(%rsp),%rdx
  lea    0x64(%rsp),%rax
  jmp    L84
  nop
L82:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L97
L84:
  mov    (%rdi),%ecx
  test   %ecx,%ecx
  jne    L110
  cmp    %rdi,%rax
  jne    L82
  lea    D39(%rip),%rdi
  call   <printf@plt>
L97:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L62
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L110:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L97
L62:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D25
type_infered: string
name: retrieve_data
arguments: label: D22
type_infered: string
name: retrieve_data
arguments: label: D39
type_infered: string
name: retrieve_data
arguments: label: D15
type_infered: string

tool: D25: Enter the first word: 

tool: D22: Enter the second word: 

tool: D39: The words are anagrams


tool: D15: The words are not anagrams


assistant: ```c
int main(void) {
  int alphabet[26] = {0};
  int letter;
  int i;
  printf("Enter the first word: ");
  while ((letter = getchar()) != '\n') {
    if (isalpha(letter)) {
      letter = toupper(letter);
      alphabet[letter - 65] += 1;
    } else {
      continue;
    }
  }
  printf("Enter the second word: ");
  while ((letter = getchar()) != '\n') {
    if (isalpha(letter)) {
      letter = toupper(letter);
      alphabet[letter - 65] -= 1;
    } else {
      continue;
    }
  }
  i = 0;
  while (i < 26) {
    if (alphabet[i] != 0) {
      printf("The words are not anagrams\n");
      break;
    }
    if (i == 25 && alphabet[i] == 0) {
      printf("The words are anagrams\n");
    }
    i += 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xd,%ecx
  push   %rbx
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    D0(%rip),%rdi
  call   <printf@plt>
L105:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  je     L100
L40:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L105
  mov    %ebp,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  jne    L40
L100:
  lea    D11(%rip),%rdi
  call   <printf@plt>
L114:
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  je     L3
L25:
  mov    %ebp,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L114
  mov    %ebp,%edi
  call   <toupper@plt>
  sub    $0x41,%eax
  cltq
  subl   $0x1,(%rsp,%rax,4)
  xor    %eax,%eax
  call   <getchar@plt>
  mov    %eax,%ebp
  cmp    $0xa,%eax
  jne    L25
L3:
  mov    %rbx,%rdi
  lea    0x68(%rsp),%rdx
  lea    0x64(%rsp),%rax
  jmp    L90
  nop
L35:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L2
L90:
  mov    (%rdi),%ecx
  test   %ecx,%ecx
  jne    L97
  cmp    %rdi,%rax
  jne    L35
  lea    D1(%rip),%rdi
  call   <printf@plt>
L2:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x78,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L97:
  lea    D30(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string
name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D1
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string

tool: D0: Enter the first word: 

tool: D11: Enter the second word: 

tool: D1: The words are anagrams


tool: D30: The words are not anagrams


assistant: ```c
int main(void) {
  int alphabet[26] = {0};
  int letter;
  int i;
  printf("Enter the first word: ");
  while ((letter = getchar()) != '\n') {
    if (isalpha(letter)) {
      letter = toupper(letter);
      alphabet[letter - 65] += 1;
    } else {
      continue;
    }
  }
  printf("Enter the second word: ");
  while ((letter = getchar()) != '\n') {
    if (isalpha(letter)) {
      letter = toupper(letter);
      alphabet[letter - 65] -= 1;
    } else {
      continue;
    }
  }
  i = 0;
  while (i < 26) {
    if (alphabet[i] != 0) {
      printf("The words are not anagrams\n");
      break;
    }
    if (i == 25 && alphabet[i] == 0) {
      printf("The words are anagrams\n");
    }
    i += 1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<M406_f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D19
type_infered: string
name: unpack_data
arguments: label: D7
type_infered: string

tool: D19: M406_f(const char *s) is not yet implemented!


tool: D7: %s


assistant: ```c
int M406_f(char *s) {
  debug("M406_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<M406_f>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string
name: disassemble_data
arguments: label: D3
datatype: string

tool: D4: M406_f(const char *s) is not yet implemented!


tool: D3: %s


assistant: ```c
int M406_f(char *s) {
  debug("M406_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<M406_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D0(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
type_guessed: string
name: disassemble_data
arguments: label: D10
type_guessed: string

tool: D0: M406_f(const char *s) is not yet implemented!


tool: D10: %s


assistant: ```c
int M406_f(char *s) {
  debug("M406_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<M406_f>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %rdi,%rbp
  lea    D19(%rip),%rdi
  call   <debug@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  call   <debug@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D19
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string

tool: D19: M406_f(const char *s) is not yet implemented!


tool: D2: %s


assistant: ```c
int M406_f(char *s) {
  debug("M406_f(const char *s) is not yet implemented!\n");
  debug("%s\n", s);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x64,-0xc(%rbp)
  movl   $0x64,-0x8(%rbp)
  movl   $0x64,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D12
data_type: string
name: disassemble_data
arguments: tag: D0
data_type: string
name: disassemble_data
arguments: tag: D16
data_type: string
name: disassemble_data
arguments: tag: D33
data_type: string
name: disassemble_data
arguments: tag: D22
data_type: string

tool: D12: dec = %d, dec = %d, dec= %d


tool: D0: octal = %o, octal = %o, octal= %o


tool: D16: octal = %#o, octal = %#o, octal= %#o


tool: D33: hex = %x, hex = %x, hex= %x


tool: D22: hex = %#x, hex = %#x, hex= %#x


assistant: ```c
int main(void) {
  int x = 100;
  int y = 0144;
  int z = 0x64;
  printf("dec = %d, dec = %d, dec= %d\n", x, y, z);
  printf("octal = %o, octal = %o, octal= %o\n", x, y, z);
  printf("octal = %#o, octal = %#o, octal= %#o\n", x, y, z);
  printf("hex = %x, hex = %x, hex= %x\n", x, y, z);
  printf("hex = %#x, hex = %#x, hex= %#x\n", x, y, z);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D14
data_type: string
name: extract_symbolic_data
arguments: tag: D42
data_type: string
name: extract_symbolic_data
arguments: tag: D19
data_type: string
name: extract_symbolic_data
arguments: tag: D39
data_type: string
name: extract_symbolic_data
arguments: tag: D13
data_type: string

tool: D14: dec = %d, dec = %d, dec= %d


tool: D42: octal = %o, octal = %o, octal= %o


tool: D19: octal = %#o, octal = %#o, octal= %#o


tool: D39: hex = %x, hex = %x, hex= %x


tool: D13: hex = %#x, hex = %#x, hex= %#x


assistant: ```c
int main(void) {
  int x = 100;
  int y = 0144;
  int z = 0x64;
  printf("dec = %d, dec = %d, dec= %d\n", x, y, z);
  printf("octal = %o, octal = %o, octal= %o\n", x, y, z);
  printf("octal = %#o, octal = %#o, octal= %#o\n", x, y, z);
  printf("hex = %x, hex = %x, hex= %x\n", x, y, z);
  printf("hex = %#x, hex = %#x, hex= %#x\n", x, y, z);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D30(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D12
type_infered: string
name: parse_data
arguments: data_tag: D3
type_infered: string
name: parse_data
arguments: data_tag: D30
type_infered: string
name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D39
type_infered: string

tool: D12: dec = %d, dec = %d, dec= %d


tool: D3: octal = %o, octal = %o, octal= %o


tool: D30: octal = %#o, octal = %#o, octal= %#o


tool: D15: hex = %x, hex = %x, hex= %x


tool: D39: hex = %#x, hex = %#x, hex= %#x


assistant: ```c
int main(void) {
  int x = 100;
  int y = 0144;
  int z = 0x64;
  printf("dec = %d, dec = %d, dec= %d\n", x, y, z);
  printf("octal = %o, octal = %o, octal= %o\n", x, y, z);
  printf("octal = %#o, octal = %#o, octal= %#o\n", x, y, z);
  printf("hex = %x, hex = %x, hex= %x\n", x, y, z);
  printf("hex = %#x, hex = %#x, hex= %#x\n", x, y, z);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D33(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    $0x64,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D24
data_type: string
name: extract_symbolic_data
arguments: data_label: D33
data_type: string
name: extract_symbolic_data
arguments: data_label: D39
data_type: string
name: extract_symbolic_data
arguments: data_label: D5
data_type: string

tool: D6: dec = %d, dec = %d, dec= %d


tool: D24: octal = %o, octal = %o, octal= %o


tool: D33: octal = %#o, octal = %#o, octal= %#o


tool: D39: hex = %x, hex = %x, hex= %x


tool: D5: hex = %#x, hex = %#x, hex= %#x


assistant: ```c
int main(void) {
  int x = 100;
  int y = 0144;
  int z = 0x64;
  printf("dec = %d, dec = %d, dec= %d\n", x, y, z);
  printf("octal = %o, octal = %o, octal= %o\n", x, y, z);
  printf("octal = %#o, octal = %#o, octal= %#o\n", x, y, z);
  printf("hex = %x, hex = %x, hex= %x\n", x, y, z);
  printf("hex = %#x, hex = %#x, hex= %#x\n", x, y, z);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<_getgrgid_r>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
L20:
  mov    -0x38(%rbp),%rdi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <getgrgid_r@plt>
  mov    %eax,-0x4(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  je     L3
  cmpl   $0x0,-0x4(%rbp)
  je     L35
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  jmp    L35
L3:
  nop
  jmp    L20
L35:
  nop
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int _getgrgid_r(gid_t gid, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrgid_r(gid, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_getgrgid_r>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %rsi,%r13
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8,%rbx
L5:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r13,%rsi
  mov    %r14d,%edi
  call   <getgrgid_r@plt>
  mov    D4(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L5
  test   %eax,%eax
  je     L19
  movq   $0x0,(%rbx)
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int _getgrgid_r(gid_t gid, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrgid_r(gid, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return rc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_getgrgid_r>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%r13
L11:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <getgrgid_r@plt>
  cmp    %eax,0x0(%r13)
  je     L11
  test   %eax,%eax
  je     L9
  movq   $0x0,(%rbx)
L9:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _getgrgid_r(gid_t gid, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrgid_r(gid, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return rc;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_getgrgid_r>:
  endbr64
  push   %r15
  mov    %edi,%r15d
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  push   %rbx
  mov    %r8,%rbx
  sub    $0x8,%rsp
  mov    D0(%rip),%r13
L2:
  mov    %rbx,%r8
  mov    %rbp,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %r15d,%edi
  call   <getgrgid_r@plt>
  cmp    %eax,0x0(%r13)
  je     L2
  test   %eax,%eax
  je     L8
  movq   $0x0,(%rbx)
L8:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int _getgrgid_r(gid_t gid, struct group *grp, char *buf, size_t bufsiz, struct group **result) {
  int rc;
  while (1) {
    rc = getgrgid_r(gid, grp, buf, bufsiz, result);
    if (rc == EINTR)
      continue;
    if (rc != 0)
      *result = NULL;
    break;
  }
  return rc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1f,-0x30(%rbp)
  movl   $0x1c,-0x2c(%rbp)
  movl   $0x1f,-0x28(%rbp)
  movl   $0x1e,-0x24(%rbp)
  movl   $0x1f,-0x20(%rbp)
  movl   $0x1e,-0x1c(%rbp)
  movl   $0x1f,-0x18(%rbp)
  movl   $0x1f,-0x14(%rbp)
  movl   $0x1e,-0x10(%rbp)
  movl   $0x1f,-0xc(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L8
L10:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    -0x34(%rbp),%edx
  lea    0x1(%rdx),%ecx
  mov    %eax,%edx
  mov    %ecx,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L8:
  mov    -0x34(%rbp),%eax
  cmp    $0x9,%eax
  jbe    L10
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
datatype: string

tool: D2: Month %2d has %d days.


assistant: ```c
int main(void) {
  const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31};
  int index;
  for (index = 0; index < sizeof days / sizeof days[0]; index++) {
    printf("Month %2d has %d days.\n", index + 1, days[index]);
  }
  return 0;
}
```