ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<printf_d>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  js     L9
L49:
  mov    %rsp,%r12
  mov    $0xcccccccd,%ecx
  mov    %r12,%rbp
  nopl   (%rax)
L25:
  mov    %ebx,%eax
  add    $0x1,%rbp
  imul   %rcx,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%edx
  add    %edx,%edx
  sub    %edx,%ebx
  add    $0x30,%ebx
  mov    %bl,-0x1(%rbp)
  mov    %eax,%ebx
  cmp    %r12,%rbp
  je     L25
  test   %eax,%eax
  jne    L25
  cs nopw 0x0(%rax,%rax,1)
L48:
  movsbl -0x1(%rbp),%edi
  sub    $0x1,%rbp
  call   <printf_c@plt>
  cmp    %r12,%rbp
  jne    L48
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L51
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x2d,%edi
  neg    %ebx
  call   <printf_c@plt>
  jmp    L49
L51:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void printf_d(int i) {
  char buf[16];
  char *p = buf;
  if (i < 0) {
    printf_c('-');
    i *= -1;
  }
  while (i > 0 || p == buf) {
    *(p++) = (char)('0' + (i % 10));
    i /= 10;
  }
  while (p != buf) {
    printf_c(*(--p));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L10
L5:
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <fastModularExpo@plt>
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
L10:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jne    L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L22
  call   <__stack_chk_fail@plt>
L22:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D13
type_guessed: string
name: parse_data
arguments: data_tag: D21
type_guessed: string
name: parse_data
arguments: data_tag: D18
type_guessed: string

tool: D13: %d

tool: D21: %d %d %d

tool: D18: %d


assistant: ```c
int main(void) {
  int T, base, exponent, modulo;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d %d", &base, &exponent, &modulo);
    printf("%d\n", fastModularExpo(base, exponent, modulo));
    T--;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  je     L19
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  lea    D13(%rip),%rbp
  lea    D12(%rip),%rbx
L14:
  lea    0xc(%rsp),%rsi
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <fastModularExpo@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x8(%rsp)
  jne    L14
L19:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D17
type: string
name: read_data
arguments: tag: D13
type: string
name: read_data
arguments: tag: D12
type: string

tool: D17: %d

tool: D13: %d %d %d

tool: D12: %d


assistant: ```c
int main(void) {
  int T, base, exponent, modulo;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d %d", &base, &exponent, &modulo);
    printf("%d\n", fastModularExpo(base, exponent, modulo));
    T--;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D7(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L28
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D17(%rip),%rbp
  lea    D2(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <fastModularExpo@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  subl   $0x1,0x8(%rsp)
  jne    L12
L28:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string
name: read_data
arguments: data_label: D17
datatype: string
name: read_data
arguments: data_label: D2
datatype: string

tool: D7: %d

tool: D17: %d %d %d

tool: D2: %d


assistant: ```c
int main(void) {
  int T, base, exponent, modulo;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d %d", &base, &exponent, &modulo);
    printf("%d\n", fastModularExpo(base, exponent, modulo));
    T--;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r14
  lea    D11(%rip),%rdi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  je     L4
  lea    0x14(%rsp),%r14
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    D16(%rip),%rbp
  lea    D10(%rip),%rbx
  cs nopw 0x0(%rax,%rax,1)
L27:
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <fastModularExpo@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  subl   $0x1,0x8(%rsp)
  jne    L27
L4:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D10
type_guessed: string

tool: D11: %d

tool: D16: %d %d %d

tool: D10: %d


assistant: ```c
int main(void) {
  int T, base, exponent, modulo;
  scanf("%d", &T);
  while (T) {
    scanf("%d %d %d", &base, &exponent, &modulo);
    printf("%d\n", fastModularExpo(base, exponent, modulo));
    T--;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_62_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x4(%rbp),%al
  mov    %al,-0x3(%rbp)
  movzbl -0x20(%rbp),%eax
  or     -0x3(%rbp),%al
  mov    %al,-0x2(%rbp)
  movzbl -0x1c(%rbp),%eax
  xor    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_62_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = stk1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rop3_62_0_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    (%rdi),%al
  or     %edx,%eax
  xor    %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_62_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_62_0_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    (%rdi),%al
  or     %edx,%eax
  xor    %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_62_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = stk1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rop3_62_0_0>:
  endbr64
  mov    %esi,%eax
  not    %eax
  and    (%rdi),%al
  or     %edx,%eax
  xor    %esi,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void rop3_62_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  unsigned char stk3;
  unsigned char stk4;
  stk4 = ~S;
  stk3 = *D & stk4;
  stk2 = T | stk3;
  stk1 = S ^ stk2;
  *D = stk1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f7d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f7d(int *p) {
  p = (void *)(0);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f7d>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f7d(int *p) {
  p = (void *)(0);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<f7d>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f7d(int *p) {
  p = (void *)(0);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<f7d>:
  endbr64
  mov    $0x1,%eax
  ret
```

assistant: ```c
int f7d(int *p) {
  p = (void *)(0);
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ht_string_hash_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x7,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L16
L0:
  mov    -0xc(%rbp),%eax
  imul   $0xf4243,%eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %ecx,%eax
  mov    %eax,-0xc(%rbp)
L16:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L0
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  xor    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned ht_string_hash_(const char *s) {
  unsigned h;
  const unsigned char *cp = (const unsigned char *)s;
  h = *cp << 7;
  while (*cp) {
    h = (1000003 * h) ^ *cp++;
  }
  h ^= (unsigned)(cp - (const unsigned char *)s);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ht_string_hash_>:
  endbr64
  movzbl (%rdi),%edx
  movzbl %dl,%eax
  shl    $0x7,%eax
  test   %dl,%dl
  je     L3
  mov    %rdi,%rcx
L5:
  imul   $0xf4243,%eax,%eax
  add    $0x1,%rcx
  movzbl %dl,%edx
  xor    %edx,%eax
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L5
L0:
  sub    %rdi,%rcx
  xor    %ecx,%eax
  ret
L3:
  mov    %rdi,%rcx
  jmp    L0
```

assistant: ```c
unsigned ht_string_hash_(const char *s) {
  unsigned h;
  const unsigned char *cp = (const unsigned char *)s;
  h = *cp << 7;
  while (*cp) {
    h = (1000003 * h) ^ *cp++;
  }
  h ^= (unsigned)(cp - (const unsigned char *)s);
  return h;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ht_string_hash_>:
  endbr64
  movzbl (%rdi),%esi
  mov    %esi,%eax
  shl    $0x7,%eax
  test   %sil,%sil
  je     L20
  mov    %rdi,%rdx
  jmp    L24
  cs nopw 0x0(%rax,%rax,1)
L6:
  movzbl %cl,%esi
L24:
  imul   $0xf4243,%eax,%eax
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  xor    %esi,%eax
  test   %cl,%cl
  jne    L6
  sub    %rdi,%rdx
  xor    %edx,%eax
L20:
  ret
```

assistant: ```c
unsigned ht_string_hash_(const char *s) {
  unsigned h;
  const unsigned char *cp = (const unsigned char *)s;
  h = *cp << 7;
  while (*cp) {
    h = (1000003 * h) ^ *cp++;
  }
  h ^= (unsigned)(cp - (const unsigned char *)s);
  return h;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ht_string_hash_>:
  endbr64
  movzbl (%rdi),%esi
  mov    %esi,%eax
  shl    $0x7,%eax
  test   %sil,%sil
  je     L25
  mov    %rdi,%rdx
  jmp    L6
  cs nopw 0x0(%rax,%rax,1)
L17:
  movzbl %cl,%esi
L6:
  imul   $0xf4243,%eax,%eax
  movzbl 0x1(%rdx),%ecx
  add    $0x1,%rdx
  xor    %esi,%eax
  test   %cl,%cl
  jne    L17
  sub    %rdi,%rdx
  xor    %edx,%eax
L25:
  ret
```

assistant: ```c
unsigned ht_string_hash_(const char *s) {
  unsigned h;
  const unsigned char *cp = (const unsigned char *)s;
  h = *cp << 7;
  while (*cp) {
    h = (1000003 * h) ^ *cp++;
  }
  h ^= (unsigned)(cp - (const unsigned char *)s);
  return h;
}
```
user: Translate the below assembly code into C programming language:

```asm
<MinHeapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  add    $0x1,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L35
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L35
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L0
L35:
  mov    -0x20(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L59
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L59
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L59:
  mov    -0xc(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L29
  mov    -0x20(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <Swap@plt>
  mov    -0xc(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <MinHeapify>
L29:
  nop
  leave
  ret
```

assistant: ```c
void MinHeapify(uint32_t *array, uint32_t heapSize, uint32_t currentNode) {
  uint32_t leftChild = 0, rightChild = 0, minimum = 0;
  leftChild = 2 * currentNode + 1;
  rightChild = 2 * currentNode + 2;
  if (leftChild < heapSize && array[leftChild] < array[currentNode])
    minimum = leftChild;
  else
    minimum = currentNode;
  if (rightChild < heapSize && array[rightChild] < array[minimum])
    minimum = rightChild;
  if (minimum != currentNode) {
    Swap(array, minimum, currentNode);
    MinHeapify(array, heapSize, minimum);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<MinHeapify>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
  cmp    %esi,%eax
  jge    L38
  movslq %eax,%rcx
  movslq %edx,%rsi
  mov    (%rdi,%rsi,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  jge    L38
  cmp    %r12d,%ebx
  jge    L73
  movslq %ebx,%rsi
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rsi,4)
  cmovge %eax,%ebx
  jmp    L14
L73:
  mov    %eax,%ebx
  jmp    L14
L38:
  cmp    %r12d,%ebx
  jge    L70
  movslq %ebx,%rax
  movslq %edx,%rcx
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jge    L70
L14:
  cmp    %edx,%ebx
  je     L70
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Swap@plt>
  mov    %ebx,%edx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <MinHeapify>
L70:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void MinHeapify(uint32_t *array, uint32_t heapSize, uint32_t currentNode) {
  uint32_t leftChild = 0, rightChild = 0, minimum = 0;
  leftChild = 2 * currentNode + 1;
  rightChild = 2 * currentNode + 2;
  if (leftChild < heapSize && array[leftChild] < array[currentNode])
    minimum = leftChild;
  else
    minimum = currentNode;
  if (rightChild < heapSize && array[rightChild] < array[minimum])
    minimum = rightChild;
  if (minimum != currentNode) {
    Swap(array, minimum, currentNode);
    MinHeapify(array, heapSize, minimum);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<MinHeapify>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L29
L57:
  movslq %edx,%rsi
  movslq %eax,%rcx
  mov    0x0(%rbp,%rsi,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  jge    L13
  cmp    %r12d,%ebx
  jl     L40
  mov    %eax,%ebx
L2:
  cmp    %edx,%ebx
  je     L79
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Swap@plt>
  mov    %ebx,%edx
L29:
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
  cmp    %r12d,%eax
  jl     L57
L13:
  cmp    %r12d,%ebx
  jge    L79
  movslq %edx,%rcx
  movslq %ebx,%rax
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jl     L2
L79:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L40:
  movslq %ebx,%rsi
  mov    0x0(%rbp,%rcx,4),%edi
  cmp    %edi,0x0(%rbp,%rsi,4)
  cmovge %eax,%ebx
  jmp    L2
```

assistant: ```c
void MinHeapify(uint32_t *array, uint32_t heapSize, uint32_t currentNode) {
  uint32_t leftChild = 0, rightChild = 0, minimum = 0;
  leftChild = 2 * currentNode + 1;
  rightChild = 2 * currentNode + 2;
  if (leftChild < heapSize && array[leftChild] < array[currentNode])
    minimum = leftChild;
  else
    minimum = currentNode;
  if (rightChild < heapSize && array[rightChild] < array[minimum])
    minimum = rightChild;
  if (minimum != currentNode) {
    Swap(array, minimum, currentNode);
    MinHeapify(array, heapSize, minimum);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<MinHeapify>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  jmp    L33
L53:
  movslq %edx,%rsi
  movslq %eax,%rcx
  mov    0x0(%rbp,%rsi,4),%edi
  cmp    %edi,0x0(%rbp,%rcx,4)
  jge    L20
  cmp    %r12d,%ebx
  jl     L75
  mov    %eax,%ebx
L2:
  cmp    %edx,%ebx
  je     L38
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <Swap@plt>
  mov    %ebx,%edx
L33:
  lea    (%rdx,%rdx,1),%ebx
  lea    0x1(%rbx),%eax
  add    $0x2,%ebx
  cmp    %r12d,%eax
  jl     L53
L20:
  cmp    %r12d,%ebx
  jge    L38
  movslq %ebx,%rcx
  movslq %edx,%rax
  mov    0x0(%rbp,%rcx,4),%ecx
  cmp    %ecx,0x0(%rbp,%rax,4)
  jg     L2
L38:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L75:
  movslq %ebx,%rsi
  mov    0x0(%rbp,%rcx,4),%edi
  cmp    %edi,0x0(%rbp,%rsi,4)
  cmovge %eax,%ebx
  jmp    L2
```

assistant: ```c
void MinHeapify(uint32_t *array, uint32_t heapSize, uint32_t currentNode) {
  uint32_t leftChild = 0, rightChild = 0, minimum = 0;
  leftChild = 2 * currentNode + 1;
  rightChild = 2 * currentNode + 2;
  if (leftChild < heapSize && array[leftChild] < array[currentNode])
    minimum = leftChild;
  else
    minimum = currentNode;
  if (rightChild < heapSize && array[rightChild] < array[minimum])
    minimum = rightChild;
  if (minimum != currentNode) {
    Swap(array, minimum, currentNode);
    MinHeapify(array, heapSize, minimum);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<gdt_compare_ulonglong>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L30
  mov    $0xffffffff,%eax
  jmp    L23
L30:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L14
  mov    $0x1,%eax
  jmp    L23
L14:
  mov    $0x0,%eax
L23:
  pop    %rbp
  ret
```

assistant: ```c
int gdt_compare_ulonglong(const void *p1, const void *p2) {
  unsigned long long n1 = *((unsigned long long *)p1);
  unsigned long long n2 = *((unsigned long long *)p2);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<gdt_compare_ulonglong>:
  endbr64
  mov    (%rdi),%rcx
  mov    (%rsi),%rdx
  mov    $0xffffffff,%eax
  cmp    %rdx,%rcx
  jb     L0
  seta   %al
  movzbl %al,%eax
L0:
  ret
```

assistant: ```c
int gdt_compare_ulonglong(const void *p1, const void *p2) {
  unsigned long long n1 = *((unsigned long long *)p1);
  unsigned long long n2 = *((unsigned long long *)p2);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<gdt_compare_ulonglong>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int gdt_compare_ulonglong(const void *p1, const void *p2) {
  unsigned long long n1 = *((unsigned long long *)p1);
  unsigned long long n2 = *((unsigned long long *)p2);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<gdt_compare_ulonglong>:
  endbr64
  mov    (%rsi),%rax
  cmp    %rax,(%rdi)
  mov    $0xffffffff,%edx
  seta   %al
  movzbl %al,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int gdt_compare_ulonglong(const void *p1, const void *p2) {
  unsigned long long n1 = *((unsigned long long *)p1);
  unsigned long long n2 = *((unsigned long long *)p2);
  if (n1 < n2) {
    return -1;
  } else if (n1 > n2) {
    return 1;
  } else {
    return 0;
  }
}
```