ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<fDetectHiLoTransition>:
  endbr64
  push   %rbx
  mov    $0x1e8481,%ebx
  jmp    L33
  nopl   0x0(%rax)
L57:
  call   <SCLKHigh@plt>
  sub    $0x1,%rbx
  je     L14
L33:
  xor    %eax,%eax
  call   <SCLKLow@plt>
  xor    %eax,%eax
  call   <fSDATACheck@plt>
  test   %rax,%rax
  je     L57
  mov    $0x1e8481,%ebx
  jmp    L1
  nopl   (%rax)
L25:
  call   <SCLKHigh@plt>
  sub    $0x1,%rbx
  je     L14
L1:
  xor    %eax,%eax
  call   <SCLKLow@plt>
  xor    %eax,%eax
  call   <fSDATACheck@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  jne    L25
  pop    %rbx
  ret
  nopl   (%rax)
L14:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
signed char fDetectHiLoTransition(void) {
  unsigned long int iTimer = 0;
  iTimer = 2000000;
  while (1) {
    SCLKLow();
    if (fSDATACheck())
      break;
    SCLKHigh();
    if (iTimer-- == 0) {
      return (-1);
    }
  }
  iTimer = 2000000;
  while (1) {
    SCLKLow();
    if (!fSDATACheck()) {
      break;
    }
    SCLKHigh();
    if (iTimer-- == 0) {
      return (-1);
    }
  }
  return (0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fDetectHiLoTransition>:
  endbr64
  push   %rbx
  mov    $0x1e8481,%ebx
  jmp    L6
  nopl   0x0(%rax)
L37:
  call   <SCLKHigh@plt>
  sub    $0x1,%rbx
  je     L21
L6:
  xor    %eax,%eax
  call   <SCLKLow@plt>
  xor    %eax,%eax
  call   <fSDATACheck@plt>
  test   %rax,%rax
  je     L37
  mov    $0x1e8481,%ebx
  jmp    L55
  nopl   (%rax)
L7:
  call   <SCLKHigh@plt>
  sub    $0x1,%rbx
  je     L21
L55:
  xor    %eax,%eax
  call   <SCLKLow@plt>
  xor    %eax,%eax
  call   <fSDATACheck@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  jne    L7
  pop    %rbx
  ret
  nopl   (%rax)
L21:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
signed char fDetectHiLoTransition(void) {
  unsigned long int iTimer = 0;
  iTimer = 2000000;
  while (1) {
    SCLKLow();
    if (fSDATACheck())
      break;
    SCLKHigh();
    if (iTimer-- == 0) {
      return (-1);
    }
  }
  iTimer = 2000000;
  while (1) {
    SCLKLow();
    if (!fSDATACheck()) {
      break;
    }
    SCLKHigh();
    if (iTimer-- == 0) {
      return (-1);
    }
  }
  return (0);
}
```
user: What is the c source code of the assembly code below?

```asm
<suEzo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %al,-0x1(%rbp)
  cmpb   $0x64,-0x1(%rbp)
  jne    L15
  mov    $0x0,%eax
  call   <downRows@plt>
  jmp    L5
L15:
  cmpb   $0x75,-0x1(%rbp)
  jne    L5
  mov    $0x0,%eax
  call   <upRows@plt>
L5:
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char suEzo(void) {
  char d = getch();
  if (d == 'd') {
    downRows();
  } else if (d == 'u') {
    upRows();
  }
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<suEzo>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getch@plt>
  mov    %eax,%ebx
  cmp    $0x64,%al
  je     L0
  cmp    $0x75,%al
  je     L33
L13:
  mov    %ebx,%eax
  pop    %rbx
  ret
L0:
  mov    $0x0,%eax
  call   <downRows@plt>
  jmp    L13
L33:
  mov    $0x0,%eax
  call   <upRows@plt>
  jmp    L13
```

assistant: ```c
char suEzo(void) {
  char d = getch();
  if (d == 'd') {
    downRows();
  } else if (d == 'u') {
    upRows();
  }
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<suEzo>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  cmp    $0x64,%al
  je     L16
  cmp    $0x75,%al
  je     L11
  mov    %r12d,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L16:
  xor    %eax,%eax
  call   <downRows@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L11:
  xor    %eax,%eax
  call   <upRows@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char suEzo(void) {
  char d = getch();
  if (d == 'd') {
    downRows();
  } else if (d == 'u') {
    upRows();
  }
  return d;
}
```
user: Translate the below assembly code into C programming language:

```asm
<suEzo>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getch@plt>
  mov    %eax,%r12d
  cmp    $0x64,%al
  je     L15
  cmp    $0x75,%al
  je     L10
  mov    %r12d,%eax
  pop    %r12
  ret
  xchg   %ax,%ax
L15:
  xor    %eax,%eax
  call   <downRows@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L10:
  xor    %eax,%eax
  call   <upRows@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char suEzo(void) {
  char d = getch();
  if (d == 'd') {
    downRows();
  } else if (d == 'u') {
    upRows();
  }
  return d;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<nread>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L22
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L82
L22:
  mov    D34(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jbe    L26
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D9(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L82
L26:
  movq   $0x0,-0x8(%rbp)
  jmp    L51
L75:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L35
  mov    -0xc(%rbp),%eax
  jmp    L82
L35:
  cmpl   $0x0,-0xc(%rbp)
  jne    L27
  mov    -0x8(%rbp),%rax
  jmp    L82
L27:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L51:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jb     L75
  mov    -0x28(%rbp),%rax
L82:
  leave
  ret
```

assistant: ```c
ssize_t nread(int fd, void *b, size_t s) {
  size_t i;
  ssize_t t;
  if (b == NULL) {
    errno = EINVAL;
    return (-1);
  }
  if (s > SSIZE_MAX) {
    errno = ERANGE;
    return (-1);
  }
  for (i = 0; i < s; i += t)
    if ((t = read(fd, (char *)b + i, s - i)) < 0)
      return (t);
    else if (t == 0)
      return (i);
  return (s);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nread>:
  endbr64
  test   %rsi,%rsi
  je     L32
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    D18(%rip),%rax
  cmp    %rdx,(%rax)
  jb     L52
  mov    $0x0,%ebx
  test   %rdx,%rdx
  je     L55
L26:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    (%r12,%rbx,1),%rsi
  mov    %r13d,%edi
  call   <read@plt>
  test   %eax,%eax
  js     L58
  je     L5
  cltq
  add    %rax,%rbx
  cmp    %rbx,%rbp
  ja     L26
L55:
  mov    %ebp,%eax
L58:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  mov    D46(%rip),%rax
  mov    (%rax),%edx
  mov    D35(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
L52:
  mov    D9(%rip),%rax
  mov    (%rax),%edx
  mov    D35(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L58
L5:
  mov    %ebx,%eax
  jmp    L58
```

assistant: ```c
ssize_t nread(int fd, void *b, size_t s) {
  size_t i;
  ssize_t t;
  if (b == NULL) {
    errno = EINVAL;
    return (-1);
  }
  if (s > SSIZE_MAX) {
    errno = ERANGE;
    return (-1);
  }
  for (i = 0; i < s; i += t)
    if ((t = read(fd, (char *)b + i, s - i)) < 0)
      return (t);
    else if (t == 0)
      return (i);
  return (s);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<nread>:
  endbr64
  test   %rsi,%rsi
  je     L4
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    D14(%rip),%rax
  cmp    %rdx,(%rax)
  jb     L16
  mov    %edi,%r12d
  mov    %rsi,%rbp
  xor    %r13d,%r13d
  test   %rdx,%rdx
  jne    L45
  jmp    L55
  cs nopw 0x0(%rax,%rax,1)
L1:
  je     L34
  cltq
  add    %rax,%r13
  cmp    %r13,%rbx
  jbe    L55
L45:
  mov    %rbx,%rdx
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %r12d,%edi
  sub    %r13,%rdx
  call   <read@plt>
  test   %eax,%eax
  jns    L1
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L55:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L34:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  mov    D41(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L38
L4:
  mov    D42(%rip),%rax
  mov    (%rax),%edx
  mov    D21(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t nread(int fd, void *b, size_t s) {
  size_t i;
  ssize_t t;
  if (b == NULL) {
    errno = EINVAL;
    return (-1);
  }
  if (s > SSIZE_MAX) {
    errno = ERANGE;
    return (-1);
  }
  for (i = 0; i < s; i += t)
    if ((t = read(fd, (char *)b + i, s - i)) < 0)
      return (t);
    else if (t == 0)
      return (i);
  return (s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<nread>:
  endbr64
  test   %rsi,%rsi
  je     L32
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  mov    D36(%rip),%rax
  cmp    %rdx,(%rax)
  jb     L7
  mov    %edi,%r12d
  mov    %rsi,%rbp
  xor    %r13d,%r13d
  test   %rdx,%rdx
  jne    L67
  jmp    L10
  cs nopw 0x0(%rax,%rax,1)
L0:
  je     L72
  cltq
  add    %rax,%r13
  cmp    %r13,%rbx
  jbe    L10
L67:
  mov    %rbx,%rdx
  lea    0x0(%rbp,%r13,1),%rsi
  mov    %r12d,%edi
  sub    %r13,%rdx
  call   <read@plt>
  test   %eax,%eax
  jns    L0
L79:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L10:
  add    $0x8,%rsp
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L72:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L79
L32:
  mov    D7(%rip),%rax
  mov    (%rax),%edx
  mov    D23(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
ssize_t nread(int fd, void *b, size_t s) {
  size_t i;
  ssize_t t;
  if (b == NULL) {
    errno = EINVAL;
    return (-1);
  }
  if (s > SSIZE_MAX) {
    errno = ERANGE;
    return (-1);
  }
  for (i = 0; i < s; i += t)
    if ((t = read(fd, (char *)b + i, s - i)) < 0)
      return (t);
    else if (t == 0)
      return (i);
  return (s);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<m_ident>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  D16(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movss  D16(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x24,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movss  D16(%rip),%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2c,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3c,%rax
  movss  D16(%rip),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
data_type: byte[4]

tool: {"D16": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void m_ident(float *M) {
  M[0] = 1.f;
  M[4] = 0.f;
  M[8] = 0.f;
  M[12] = 0.f;
  M[1] = 0.f;
  M[5] = 1.f;
  M[9] = 0.f;
  M[13] = 0.f;
  M[2] = 0.f;
  M[6] = 0.f;
  M[10] = 1.f;
  M[14] = 0.f;
  M[3] = 0.f;
  M[7] = 0.f;
  M[11] = 0.f;
  M[15] = 1.f;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<m_ident>:
  endbr64
  movss  D8(%rip),%xmm0
  movss  %xmm0,(%rdi)
  movl   $0x0,0x10(%rdi)
  movl   $0x0,0x20(%rdi)
  movl   $0x0,0x30(%rdi)
  movl   $0x0,0x4(%rdi)
  movss  %xmm0,0x14(%rdi)
  movl   $0x0,0x24(%rdi)
  movl   $0x0,0x34(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0x18(%rdi)
  movss  %xmm0,0x28(%rdi)
  movl   $0x0,0x38(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0x0,0x1c(%rdi)
  movl   $0x0,0x2c(%rdi)
  movss  %xmm0,0x3c(%rdi)
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: byte[4]

tool: {"D8": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void m_ident(float *M) {
  M[0] = 1.f;
  M[4] = 0.f;
  M[8] = 0.f;
  M[12] = 0.f;
  M[1] = 0.f;
  M[5] = 1.f;
  M[9] = 0.f;
  M[13] = 0.f;
  M[2] = 0.f;
  M[6] = 0.f;
  M[10] = 1.f;
  M[14] = 0.f;
  M[3] = 0.f;
  M[7] = 0.f;
  M[11] = 0.f;
  M[15] = 1.f;
}
```
user: Translate the below assembly code into C programming language:

```asm
<m_ident>:
  endbr64
  movabs $0x3f80000000000000,%rax
  movq   $0x3f800000,(%rdi)
  movq   $0x0,0x8(%rdi)
  mov    %rax,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x20(%rdi)
  movq   $0x3f800000,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  mov    %rax,0x38(%rdi)
  ret
```

assistant: ```c
void m_ident(float *M) {
  M[0] = 1.f;
  M[4] = 0.f;
  M[8] = 0.f;
  M[12] = 0.f;
  M[1] = 0.f;
  M[5] = 1.f;
  M[9] = 0.f;
  M[13] = 0.f;
  M[2] = 0.f;
  M[6] = 0.f;
  M[10] = 1.f;
  M[14] = 0.f;
  M[3] = 0.f;
  M[7] = 0.f;
  M[11] = 0.f;
  M[15] = 1.f;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m_ident>:
  endbr64
  movss  D23(%rip),%xmm0
  movups %xmm0,(%rdi)
  movaps D37(%rip),%xmm0
  movups %xmm0,0x10(%rdi)
  movaps D14(%rip),%xmm0
  movups %xmm0,0x20(%rdi)
  movaps D26(%rip),%xmm0
  movups %xmm0,0x30(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_infered: byte[4]
name: retrieve_data
arguments: tag: D37
type_infered: byte[16]
name: retrieve_data
arguments: tag: D14
type_infered: byte[16]
name: retrieve_data
arguments: tag: D26
type_infered: byte[16]

tool: {"D23": [0x00,0x00,0x80,0x3f]}

tool: {"D37": [0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f,0x00,0x00,0x00,0x00]}

tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x3f]}

assistant: ```c
void m_ident(float *M) {
  M[0] = 1.f;
  M[4] = 0.f;
  M[8] = 0.f;
  M[12] = 0.f;
  M[1] = 0.f;
  M[5] = 1.f;
  M[9] = 0.f;
  M[13] = 0.f;
  M[2] = 0.f;
  M[6] = 0.f;
  M[10] = 1.f;
  M[14] = 0.f;
  M[3] = 0.f;
  M[7] = 0.f;
  M[11] = 0.f;
  M[15] = 1.f;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L6
L13:
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  test   %eax,%eax
  jne    L35
  mov    $0x0,%eax
  jmp    L36
L35:
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cmp    %eax,-0x14(%rbp)
  ja     L13
  mov    $0x1,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
int prime(unsigned int n) {
  int i = 2;
  for (i; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime>:
  endbr64
  cmp    $0x2,%edi
  jbe    L11
  test   $0x1,%dil
  je     L31
  mov    $0x2,%ecx
L29:
  add    $0x1,%ecx
  mov    %ecx,%esi
  cmp    %ecx,%edi
  je     L8
  mov    %edi,%eax
  mov    $0x0,%edx
  div    %esi
  test   %edx,%edx
  jne    L29
  mov    $0x0,%eax
  ret
L8:
  mov    $0x1,%eax
  ret
L11:
  mov    $0x1,%eax
  ret
L31:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int prime(unsigned int n) {
  int i = 2;
  for (i; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime>:
  endbr64
  cmp    $0x2,%edi
  jbe    L14
  test   $0x1,%dil
  je     L45
  mov    $0x2,%ecx
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L45
L33:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L25
L14:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L45:
  xor    %eax,%eax
  ret
```

assistant: ```c
int prime(unsigned int n) {
  int i = 2;
  for (i; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<prime>:
  endbr64
  cmp    $0x2,%edi
  jbe    L44
  test   $0x1,%dil
  je     L25
  mov    $0x2,%ecx
  jmp    L9
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %edi,%eax
  xor    %edx,%edx
  div    %ecx
  test   %edx,%edx
  je     L25
L9:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  jne    L18
L44:
  mov    $0x1,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  ret
```

assistant: ```c
int prime(unsigned int n) {
  int i = 2;
  for (i; i < n; i++) {
    if (n % i == 0)
      return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<affecter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x440,%rsp
  mov    %rdi,-0x438(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3f0(%rbp),%rcx
  lea    -0x430(%rbp),%rdx
  mov    -0x438(%rbp),%rax
  lea    D9(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  jne    L8
  mov    $0x1,%eax
  jmp    L14
L8:
  mov    $0x0,%eax
L14:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D9
type: string

tool: D9: %s = %[^
]


assistant: ```c
int affecter(const char *affectation) {
  char nom[50];
  char valeur[1000];
  if (sscanf(affectation, "%s = %[^\n]\n", nom, valeur) == 2)
    return 1;
  else
    return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<affecter>:
  endbr64
  sub    $0x438,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rcx
  mov    %rsp,%rdx
  lea    D0(%rip),%rsi
  call   <sscanf@plt>
  cmp    $0x2,%eax
  sete   %al
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x438,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
data_type: string

tool: D0: %s = %[^
]


assistant: ```c
int affecter(const char *affectation) {
  char nom[50];
  char valeur[1000];
  if (sscanf(affectation, "%s = %[^\n]\n", nom, valeur) == 2)
    return 1;
  else
    return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<affecter>:
  endbr64
  sub    $0x438,%rsp
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rcx
  mov    %rsp,%rdx
  call   <sscanf@plt>
  cmp    $0x2,%eax
  sete   %al
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  movzbl %al,%eax
  add    $0x438,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type: string

tool: D8: %s = %[^
]


assistant: ```c
int affecter(const char *affectation) {
  char nom[50];
  char valeur[1000];
  if (sscanf(affectation, "%s = %[^\n]\n", nom, valeur) == 2)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<affecter>:
  endbr64
  sub    $0x438,%rsp
  lea    D8(%rip),%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x428(%rsp)
  xor    %eax,%eax
  lea    0x40(%rsp),%rcx
  mov    %rsp,%rdx
  call   <sscanf@plt>
  cmp    $0x2,%eax
  sete   %al
  mov    0x428(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x438,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_guessed: string

tool: D8: %s = %[^
]


assistant: ```c
int affecter(const char *affectation) {
  char nom[50];
  char valeur[1000];
  if (sscanf(affectation, "%s = %[^\n]\n", nom, valeur) == 2)
    return 1;
  else
    return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<insertion_asm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
L14:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L63
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L56
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L56
  jmp    L48
L56:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L44
L63:
  nop
L44:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L59
  jmp    L14
L59:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void insertion_asm(int nums[], int len) {
  int i = 1;
  int j;
  int temp1, temp2;
insertion_outer:
  temp1 = nums[i];
  temp2 = nums[i - 1];
  if (temp2 <= temp1)
    goto insertion_if;
  j = i;
insertion_inner:
  nums[j] = temp2;
  j--;
  temp2 = nums[j - 1];
  if (j > 0 && (temp2 > temp1))
    goto insertion_inner;
  nums[j] = temp1;
insertion_if:
  i++;
  if (i < len)
    goto insertion_outer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<insertion_asm>:
  endbr64
  mov    $0x1,%r10d
  jmp    L1
L23:
  add    $0x1,%r10
  cmp    %r10d,%esi
  jle    L9
L1:
  mov    (%rdi,%r10,4),%r9d
  mov    -0x4(%rdi,%r10,4),%edx
  cmp    %edx,%r9d
  jge    L23
  lea    -0x1(%r10),%rax
L41:
  mov    %edx,0x4(%rdi,%rax,4)
  lea    0x0(,%rax,4),%r11
  mov    -0x4(%rdi,%rax,4),%edx
  test   %eax,%eax
  setg   %r8b
  cmp    %edx,%r9d
  setl   %cl
  sub    $0x1,%rax
  test   %cl,%r8b
  jne    L41
  mov    %r9d,(%rdi,%r11,1)
  jmp    L23
L9:
  ret
```

assistant: ```c
void insertion_asm(int nums[], int len) {
  int i = 1;
  int j;
  int temp1, temp2;
insertion_outer:
  temp1 = nums[i];
  temp2 = nums[i - 1];
  if (temp2 <= temp1)
    goto insertion_if;
  j = i;
insertion_inner:
  nums[j] = temp2;
  j--;
  temp2 = nums[j - 1];
  if (j > 0 && (temp2 > temp1))
    goto insertion_inner;
  nums[j] = temp1;
insertion_if:
  i++;
  if (i < len)
    goto insertion_outer;
}
```