ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<UI_dup_input_boolean>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L40
  mov    %rsi,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L99
L40:
  test   %r13,%r13
  je     L33
  mov    %r13,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L66
L33:
  test   %r15,%r15
  je     L75
  mov    %r15,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L27
L75:
  test   %rbp,%rbp
  je     L105
  mov    %rbp,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
L105:
  mov    D50(%rip),%rax
  mov    %rbp,%r8
  mov    %r15,%rcx
  mov    %r13,%rdx
  sub    $0x8,%rsp
  mov    $0x1,%r9d
  mov    %r12,%rsi
  mov    %r14,%rdi
  push   0x48(%rsp)
  push   %rbx
  mov    (%rax),%eax
  push   %rax
  call   <general_allocate_boolean@plt>
  add    $0x20,%rsp
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L27:
  mov    D6(%rip),%rax
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
L89:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L43
L66:
  mov    D6(%rip),%rax
  xor    %r15d,%r15d
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  jmp    L89
L99:
  mov    D6(%rip),%rax
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  mov    (%rax),%esi
  mov    D19(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  jmp    L89
```

assistant: ```c
int UI_dup_input_boolean(UI *ui, const char *prompt, const char *action_desc, const char *ok_chars, const char *cancel_chars, int flags, char *result_buf) {
  char *prompt_copy = NULL;
  char *action_desc_copy = NULL;
  char *ok_chars_copy = NULL;
  char *cancel_chars_copy = NULL;
  if (prompt) {
    prompt_copy = BUF_strdup(prompt);
    if (prompt_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  if (action_desc) {
    action_desc_copy = BUF_strdup(action_desc);
    if (action_desc_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  if (ok_chars) {
    ok_chars_copy = BUF_strdup(ok_chars);
    if (ok_chars_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  if (cancel_chars) {
    cancel_chars_copy = BUF_strdup(cancel_chars);
    if (cancel_chars_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  return general_allocate_boolean(ui, prompt_copy, action_desc_copy, ok_chars_copy, cancel_chars_copy, 1, UIT_BOOLEAN, flags, result_buf);
err:
  free(prompt_copy);
  free(action_desc_copy);
  free(ok_chars_copy);
  free(cancel_chars_copy);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<UI_dup_input_boolean>:
  endbr64
  push   %r15
  mov    %rcx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9d,%ebx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L14
  mov    %rsi,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L70
L14:
  test   %r13,%r13
  je     L20
  mov    %r13,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L31
L20:
  test   %r15,%r15
  je     L56
  mov    %r15,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L34
L56:
  test   %rbp,%rbp
  je     L61
  mov    %rbp,%rdi
  call   <BUF_strdup@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L34
L61:
  mov    D20(%rip),%rax
  mov    %rbp,%r8
  mov    %r15,%rcx
  mov    %r13,%rdx
  sub    $0x8,%rsp
  mov    $0x1,%r9d
  mov    %r12,%rsi
  mov    %r14,%rdi
  push   0x48(%rsp)
  push   %rbx
  mov    (%rax),%eax
  push   %rax
  call   <general_allocate_boolean@plt>
  add    $0x20,%rsp
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L34:
  mov    D68(%rip),%rax
  mov    (%rax),%esi
  mov    D23(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
L40:
  mov    %r12,%rdi
  call   <free@plt>
  mov    %r13,%rdi
  call   <free@plt>
  mov    %r15,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L31:
  mov    D68(%rip),%rax
  xor    %r15d,%r15d
  mov    (%rax),%esi
  mov    D23(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  jmp    L40
L70:
  mov    D68(%rip),%rax
  xor    %r15d,%r15d
  xor    %r13d,%r13d
  mov    (%rax),%esi
  mov    D23(%rip),%rax
  mov    (%rax),%edi
  call   <UIerr@plt>
  jmp    L40
```

assistant: ```c
int UI_dup_input_boolean(UI *ui, const char *prompt, const char *action_desc, const char *ok_chars, const char *cancel_chars, int flags, char *result_buf) {
  char *prompt_copy = NULL;
  char *action_desc_copy = NULL;
  char *ok_chars_copy = NULL;
  char *cancel_chars_copy = NULL;
  if (prompt) {
    prompt_copy = BUF_strdup(prompt);
    if (prompt_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  if (action_desc) {
    action_desc_copy = BUF_strdup(action_desc);
    if (action_desc_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  if (ok_chars) {
    ok_chars_copy = BUF_strdup(ok_chars);
    if (ok_chars_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  if (cancel_chars) {
    cancel_chars_copy = BUF_strdup(cancel_chars);
    if (cancel_chars_copy == NULL) {
      UIerr(UI_F_UI_DUP_INPUT_BOOLEAN, ERR_R_MALLOC_FAILURE);
      goto err;
    }
  }
  return general_allocate_boolean(ui, prompt_copy, action_desc_copy, ok_chars_copy, cancel_chars_copy, 1, UIT_BOOLEAN, flags, result_buf);
err:
  free(prompt_copy);
  free(action_desc_copy);
  free(ok_chars_copy);
  free(cancel_chars_copy);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ReadWordIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %rdi,-0x78(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x78(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ReadWord@plt>
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <feof@plt>
  test   %rax,%rax
  je     L18
  mov    $0xffffffff,%eax
  jmp    L7
L18:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rdi
  call   <SearchVocab@plt>
L7:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

assistant: ```c
int ReadWordIndex(FILE *fin) {
  char word[100];
  ReadWord(word, fin);
  if (feof(fin))
    return -1;
  return SearchVocab(word);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ReadWordIndex>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rbx,%rsi
  call   <ReadWord@plt>
  mov    %rbx,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L18
  mov    %rsp,%rdi
  call   <SearchVocab@plt>
L3:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x70,%rsp
  pop    %rbx
  ret
L18:
  mov    $0xffffffff,%eax
  jmp    L3
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadWordIndex(FILE *fin) {
  char word[100];
  ReadWord(word, fin);
  if (feof(fin))
    return -1;
  return SearchVocab(word);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ReadWordIndex>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <ReadWord@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L6
  mov    %r12,%rdi
  call   <SearchVocab@plt>
L25:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L19
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L6:
  mov    $0xffffffff,%eax
  jmp    L25
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadWordIndex(FILE *fin) {
  char word[100];
  ReadWord(word, fin);
  if (feof(fin))
    return -1;
  return SearchVocab(word);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReadWordIndex>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <ReadWord@plt>
  mov    %rbp,%rdi
  call   <feof@plt>
  test   %rax,%rax
  jne    L17
  mov    %r12,%rdi
  call   <SearchVocab@plt>
L3:
  mov    0x68(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x78,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L17:
  mov    $0xffffffff,%eax
  jmp    L3
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadWordIndex(FILE *fin) {
  char word[100];
  ReadWord(word, fin);
  if (feof(fin))
    return -1;
  return SearchVocab(word);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<merge_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L9
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <merge_sort>
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <merge_without_sentinel@plt>
L9:
  nop
  leave
  ret
```

assistant: ```c
void merge_sort(int *input_array, int start, int end) {
  int mid;
  if (start < end) {
    mid = (start + end) / 2;
    merge_sort(input_array, start, mid);
    merge_sort(input_array, mid + 1, end);
    merge_without_sentinel(input_array, start, mid, end);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<merge_sort>:
  endbr64
  cmp    %edx,%esi
  jl     L7
  ret
L7:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r13d
  shr    $0x1f,%r13d
  add    %eax,%r13d
  sar    %r13d
  mov    %r13d,%edx
  call   <merge_sort>
  lea    0x1(%r13),%esi
  mov    %ebp,%edx
  mov    %r12,%rdi
  call   <merge_sort>
  mov    %ebp,%ecx
  mov    %r13d,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <merge_without_sentinel@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void merge_sort(int *input_array, int start, int end) {
  int mid;
  if (start < end) {
    mid = (start + end) / 2;
    merge_sort(input_array, start, mid);
    merge_sort(input_array, mid + 1, end);
    merge_without_sentinel(input_array, start, mid, end);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    $0x4,%esi
  mov    $0x4c4b400,%edi
  call   <calloc@plt>
  mov    %rax,-0x10(%rbp)
  movl   $0x2,-0x34(%rbp)
  jmp    L17
L25:
  mov    -0x34(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L12
  mov    -0x34(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  jmp    L71
L16:
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x34(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x34(%rbp),%eax
  add    %eax,-0x30(%rbp)
L71:
  cmpl   $0x4c4b3ff,-0x30(%rbp)
  jle    L16
L12:
  addl   $0x1,-0x34(%rbp)
L17:
  cmpl   $0x4c4b3ff,-0x34(%rbp)
  jle    L25
  movq   $0x1,-0x20(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x2,-0x34(%rbp)
  jmp    L89
L26:
  mov    -0x34(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  jmp    L65
L114:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x2c(%rbp)
  jne    L40
  addl   $0x1,-0x28(%rbp)
  jmp    L109
L40:
  mov    -0x28(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x24(%rbp)
  movl   $0x1,-0x28(%rbp)
L109:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x2c(%rbp)
L65:
  cmpq   $0x1,-0x18(%rbp)
  jne    L114
  cmpl   $0x1f4,-0x24(%rbp)
  jle    L13
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L61
L13:
  addl   $0x1,-0x34(%rbp)
L89:
  cmpl   $0x4c4b3ff,-0x34(%rbp)
  jle    L26
L61:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: %lld


assistant: ```c
int main(void) {
  int *seive = (int *)calloc(80000000, sizeof(int));
  int i, j;
  for (i = 2; i < 80000000; i++) {
    if (seive[i] == 0) {
      for (j = i; j < 80000000; j += i)
        seive[j] = i;
    }
  }
  long long int sum = 1;
  long long int factors = 1;
  for (i = 2; i < 80000000; i++) {
    sum += i;
    long long int x = sum;
    int prev = seive[x], count = 1;
    int val = 1;
    while (x != 1) {
      x /= seive[x];
      if (seive[x] == prev)
        count++;
      else {
        val *= count + 1;
        count = 1;
      }
      prev = seive[x];
    }
    if (val > 500) {
      printf("%lld\n", sum);
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x4,%esi
  mov    $0x4c4b400,%edi
  call   <calloc@plt>
  mov    %rax,%r8
  lea    0x8(%rax),%rdi
  mov    $0x2,%esi
  jmp    L33
L138:
  add    $0x1,%rsi
  add    $0x4,%rdi
  cmp    $0x4c4b400,%rsi
  je     L35
L33:
  mov    %esi,%ecx
  cmpl   $0x0,(%rdi)
  jne    L138
  cmp    $0x4c4b3ff,%esi
  jg     L138
  lea    0x0(,%rsi,4),%r9
  mov    %rdi,%rdx
  mov    %esi,%eax
L112:
  mov    %ecx,(%rdx)
  add    %ecx,%eax
  add    %r9,%rdx
  cmp    $0x4c4b3ff,%eax
  jle    L112
  jmp    L138
L35:
  mov    $0x2,%r11d
  mov    $0x1,%r10d
  jmp    L62
L124:
  add    $0x1,%ecx
L22:
  cmp    $0x1,%rax
  je     L44
L119:
  movslq (%r8,%rdx,4),%rdi
  mov    %rdx,%rax
  cqto
  idiv   %rdi
  mov    %rax,%rdx
  mov    %esi,%edi
  mov    (%r8,%rax,4),%esi
  cmp    %edi,%esi
  je     L124
  add    $0x1,%ecx
  imul   %ecx,%r9d
  mov    $0x1,%ecx
  jmp    L22
L44:
  cmp    $0x1f4,%r9d
  jg     L31
L0:
  add    $0x1,%r11
  cmp    $0x4c4b400,%r11
  je     L26
L62:
  add    %r11,%r10
  mov    (%r8,%r10,4),%esi
  cmp    $0x1,%r10
  je     L0
  mov    %r10,%rdx
  mov    $0x1,%r9d
  mov    $0x1,%ecx
  jmp    L119
L31:
  mov    %r10,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
L26:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_infered: string

tool: D7: %lld


assistant: ```c
int main(void) {
  int *seive = (int *)calloc(80000000, sizeof(int));
  int i, j;
  for (i = 2; i < 80000000; i++) {
    if (seive[i] == 0) {
      for (j = i; j < 80000000; j += i)
        seive[j] = i;
    }
  }
  long long int sum = 1;
  long long int factors = 1;
  for (i = 2; i < 80000000; i++) {
    sum += i;
    long long int x = sum;
    int prev = seive[x], count = 1;
    int val = 1;
    while (x != 1) {
      x /= seive[x];
      if (seive[x] == prev)
        count++;
      else {
        val *= count + 1;
        count = 1;
      }
      prev = seive[x];
    }
    if (val > 500) {
      printf("%lld\n", sum);
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  mov    $0x4,%esi
  mov    $0x4c4b400,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    $0x2,%edi
  mov    %rax,%r9
  lea    0x8(%rax),%rsi
  lea    0x1312d000(%rax),%r10
  jmp    L68
  nopl   0x0(%rax)
L71:
  add    $0x4,%rsi
  add    $0x1,%rdi
  cmp    %rsi,%r10
  je     L6
L68:
  mov    (%rsi),%eax
  mov    %edi,%ecx
  test   %eax,%eax
  jne    L71
  lea    0x0(,%rdi,4),%r8
  mov    %rsi,%rdx
  mov    %edi,%eax
  nopw   0x0(%rax,%rax,1)
L62:
  add    %ecx,%eax
  mov    %ecx,(%rdx)
  add    %r8,%rdx
  cmp    $0x4c4b3ff,%eax
  jle    L62
  add    $0x4,%rsi
  add    $0x1,%rdi
  cmp    %rsi,%r10
  jne    L68
L6:
  mov    $0x2,%r11d
  mov    $0x1,%r10d
  nop
L4:
  add    %r11,%r10
  mov    $0x1,%r8d
  mov    $0x1,%edi
  mov    (%r9,%r10,4),%ecx
  mov    %r10,%rax
  nopl   (%rax)
L23:
  movslq %ecx,%rsi
  cqto
  add    $0x1,%edi
  idiv   %rsi
  mov    %ecx,%edx
  mov    (%r9,%rax,4),%ecx
  mov    %rax,%rsi
  cmp    %edx,%ecx
  je     L52
  imul   %edi,%r8d
  mov    $0x1,%edi
L52:
  cmp    $0x1,%rsi
  jne    L23
  cmp    $0x1f4,%r8d
  jg     L26
  add    $0x1,%r11
  cmp    $0x4c4b400,%r11
  jne    L4
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L26:
  mov    %r10,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: %lld


assistant: ```c
int main(void) {
  int *seive = (int *)calloc(80000000, sizeof(int));
  int i, j;
  for (i = 2; i < 80000000; i++) {
    if (seive[i] == 0) {
      for (j = i; j < 80000000; j += i)
        seive[j] = i;
    }
  }
  long long int sum = 1;
  long long int factors = 1;
  for (i = 2; i < 80000000; i++) {
    sum += i;
    long long int x = sum;
    int prev = seive[x], count = 1;
    int val = 1;
    while (x != 1) {
      x /= seive[x];
      if (seive[x] == prev)
        count++;
      else {
        val *= count + 1;
        count = 1;
      }
      prev = seive[x];
    }
    if (val > 500) {
      printf("%lld\n", sum);
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  mov    $0x4,%esi
  mov    $0x4c4b400,%edi
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    $0x2,%edi
  mov    %rax,%r9
  lea    0x8(%rax),%rsi
  lea    0x1312d000(%rax),%r10
  jmp    L61
  nopl   0x0(%rax)
L55:
  add    $0x4,%rsi
  add    $0x1,%rdi
  cmp    %r10,%rsi
  je     L83
L61:
  mov    (%rsi),%eax
  mov    %edi,%ecx
  test   %eax,%eax
  jne    L55
  lea    0x0(,%rdi,4),%r8
  mov    %rsi,%rdx
  mov    %edi,%eax
  nopw   0x0(%rax,%rax,1)
L5:
  add    %ecx,%eax
  mov    %ecx,(%rdx)
  add    %r8,%rdx
  cmp    $0x4c4b3ff,%eax
  jle    L5
  add    $0x4,%rsi
  add    $0x1,%rdi
  cmp    %r10,%rsi
  jne    L61
L83:
  mov    $0x2,%r11d
  mov    $0x1,%r10d
  nop
L84:
  add    %r11,%r10
  mov    $0x1,%r8d
  mov    $0x1,%edi
  mov    (%r9,%r10,4),%ecx
  mov    %r10,%rax
  nopl   (%rax)
L38:
  movslq %ecx,%rsi
  cqto
  add    $0x1,%edi
  idiv   %rsi
  mov    %ecx,%edx
  mov    (%r9,%rax,4),%ecx
  mov    %rax,%rsi
  cmp    %edx,%ecx
  je     L4
  imul   %edi,%r8d
  mov    $0x1,%edi
L4:
  cmp    $0x1,%rsi
  jne    L38
  cmp    $0x1f4,%r8d
  jg     L64
  add    $0x1,%r11
  cmp    $0x4c4b400,%r11
  jne    L84
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L64:
  mov    %r10,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_infered: string

tool: D0: %lld


assistant: ```c
int main(void) {
  int *seive = (int *)calloc(80000000, sizeof(int));
  int i, j;
  for (i = 2; i < 80000000; i++) {
    if (seive[i] == 0) {
      for (j = i; j < 80000000; j += i)
        seive[j] = i;
    }
  }
  long long int sum = 1;
  long long int factors = 1;
  for (i = 2; i < 80000000; i++) {
    sum += i;
    long long int x = sum;
    int prev = seive[x], count = 1;
    int val = 1;
    while (x != 1) {
      x /= seive[x];
      if (seive[x] == prev)
        count++;
      else {
        val *= count + 1;
        count = 1;
      }
      prev = seive[x];
    }
    if (val > 500) {
      printf("%lld\n", sum);
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x70(%rbp)
  jmp    L12
L44:
  addl   $0x1,-0x74(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    -0x74(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0x70(%rbp,%rdx,1)
L12:
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0xa,%al
  je     L55
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  je     L55
  mov    -0x74(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L44
L55:
  lea    -0x7c(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x7c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x4ec4ec4f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x3,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x1a,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x7c(%rbp)
  movl   $0x0,-0x78(%rbp)
  jmp    L24
L13:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  mov    %eax,%edx
  mov    -0x7c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x78(%rbp)
L24:
  mov    -0x78(%rbp),%eax
  cmp    -0x74(%rbp),%eax
  jl     L13
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: string
name: unpack_data
arguments: data_label: D1
datatype: string

tool: D7: %d

tool: D1: %c

assistant: ```c
int main() {
  char arr[100];
  int n, j, i = 0;
  arr[0] = getchar();
  while (arr[i] != '\n' && arr[i] != '\0' && arr[i] != ' ') {
    i++;
    arr[i] = getchar();
  }
  scanf("%d", &n);
  n = n % 26;
  for (j = 0; j < i; j++) {
    arr[j] = arr[j] + n;
    printf("%c", arr[j]);
  }
  return 0;
}
```