ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <function@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <function@plt>
  sub    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L2
  negl   -0xc(%rbp)
L2:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L10
  call   <__stack_chk_fail@plt>
L10:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D20
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string
name: unpack_data
arguments: tag: D38
type_guessed: string

tool: D20: %d

tool: D16: %d%d

tool: D38: %d


assistant: ```c
int main() {
  int year, month, day;
  scanf("%d", &year);
  scanf("%d%d", &month, &day);
  int dayInYear = function(year, month, day);
  scanf("%d%d", &month, &day);
  dayInYear -= function(year, month, day);
  if (dayInYear < 0) {
    dayInYear = -dayInYear;
  }
  printf("%d\n", dayInYear);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  mov    %r13,%rdx
  mov    %r12,%rsi
  lea    D20(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <function@plt>
  mov    %eax,%ebx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <function@plt>
  mov    %eax,%edx
  sub    %ebx,%edx
  sub    %eax,%ebx
  mov    %ebx,%esi
  cmovs  %edx,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D27
type_infered: string
name: parse_data
arguments: data_label: D20
type_infered: string
name: parse_data
arguments: data_label: D23
type_infered: string

tool: D27: %d

tool: D20: %d%d

tool: D23: %d


assistant: ```c
int main() {
  int year, month, day;
  scanf("%d", &year);
  scanf("%d%d", &month, &day);
  int dayInYear = function(year, month, day);
  scanf("%d%d", &month, &day);
  dayInYear -= function(year, month, day);
  if (dayInYear < 0) {
    dayInYear = -dayInYear;
  }
  printf("%d\n", dayInYear);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <function@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <function@plt>
  lea    D13(%rip),%rdi
  mov    %eax,%edx
  sub    %ebx,%edx
  sub    %eax,%ebx
  mov    %ebx,%esi
  cmovs  %edx,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D3
type_guessed: string
name: parse_data
arguments: label: D1
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D3: %d

tool: D1: %d%d

tool: D13: %d


assistant: ```c
int main() {
  int year, month, day;
  scanf("%d", &year);
  scanf("%d%d", &month, &day);
  int dayInYear = function(year, month, day);
  scanf("%d%d", &month, &day);
  dayInYear -= function(year, month, day);
  if (dayInYear < 0) {
    dayInYear = -dayInYear;
  }
  printf("%d\n", dayInYear);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  lea    D27(%rip),%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x14(%rsp),%r13
  lea    0x10(%rsp),%r12
  call   <scanf@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <function@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <function@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  sub    %ebx,%edx
  sub    %eax,%ebx
  mov    %ebx,%esi
  cmovs  %edx,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string
name: read_data
arguments: label: D27
type_guessed: string
name: read_data
arguments: label: D4
type_guessed: string

tool: D3: %d

tool: D27: %d%d

tool: D4: %d


assistant: ```c
int main() {
  int year, month, day;
  scanf("%d", &year);
  scanf("%d%d", &month, &day);
  int dayInYear = function(year, month, day);
  scanf("%d%d", &month, &day);
  dayInYear -= function(year, month, day);
  if (dayInYear < 0) {
    dayInYear = -dayInYear;
  }
  printf("%d\n", dayInYear);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<minipmi_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L6
L19:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  add    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  sub    %rax,-0x28(%rbp)
L6:
  cmpq   $0x0,-0x28(%rbp)
  jg     L19
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int minipmi_read(int fd, void *buf, long long count) {
  long long i;
  while (count > 0) {
    i = read(fd, buf, count);
    buf = (void *)(((char *)buf) + count);
    count = count - i;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<minipmi_read>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdx,%rdx
  jle    L2
L17:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  add    %rbx,%rbp
  sub    %rax,%rbx
  test   %rbx,%rbx
  jg     L17
L2:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int minipmi_read(int fd, void *buf, long long count) {
  long long i;
  while (count > 0) {
    i = read(fd, buf, count);
    buf = (void *)(((char *)buf) + count);
    count = count - i;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<minipmi_read>:
  endbr64
  test   %rdx,%rdx
  jle    L17
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  add    %rbx,%rbp
  call   <read@plt>
  sub    %rax,%rbx
  test   %rbx,%rbx
  jg     L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int minipmi_read(int fd, void *buf, long long count) {
  long long i;
  while (count > 0) {
    i = read(fd, buf, count);
    buf = (void *)(((char *)buf) + count);
    count = count - i;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<minipmi_read>:
  endbr64
  test   %rdx,%rdx
  jle    L1
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  add    %rbx,%rbp
  call   <read@plt>
  sub    %rax,%rbx
  test   %rbx,%rbx
  jg     L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
int minipmi_read(int fd, void *buf, long long count) {
  long long i;
  while (count > 0) {
    i = read(fd, buf, count);
    buf = (void *)(((char *)buf) + count);
    count = count - i;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1d(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x1d(%rbp),%eax
  movsbl %al,%edx
  lea    -0x12(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ultima@plt>
  mov    %eax,-0x1c(%rbp)
  movzbl -0x1d(%rbp),%eax
  movsbl %al,%edx
  lea    -0x12(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <primeira@plt>
  mov    %eax,-0x18(%rbp)
  movzbl -0x1d(%rbp),%eax
  movsbl %al,%ecx
  movzbl -0x1d(%rbp),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%esi
  mov    -0x1c(%rbp),%edx
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D38
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D10
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D20
type_infered: string

tool: D25: Entre com um string: 

tool: D38: Entre com um letra: 

tool: D10:  %c

tool: D20: Ultima ocorrencia da letra %c: %d
Primeira ocorrencia da letra %c: %d

assistant: ```c
int main() {
  char string[10], letra;
  int ult, pri;
  printf("Entre com um string: ");
  gets(string);
  printf("Entre com um letra: ");
  scanf(" %c", &letra);
  ult = ultima(&string[0], letra);
  pri = primeira(&string[0], letra);
  printf("Ultima ocorrencia da letra %c: %d\nPrimeira ocorrencia da letra %c: %d", letra, ult, letra, pri);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0xe(%rsp),%rbp
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  call   <ultima@plt>
  mov    %eax,%ebx
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  call   <primeira@plt>
  mov    %eax,%r8d
  movsbl 0xd(%rsp),%esi
  mov    %esi,%ecx
  mov    %ebx,%edx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D4
type: string
name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D2
type: string

tool: D4: Entre com um string: 

tool: D8: Entre com um letra: 

tool: D33:  %c

tool: D2: Ultima ocorrencia da letra %c: %d
Primeira ocorrencia da letra %c: %d

assistant: ```c
int main() {
  char string[10], letra;
  int ult, pri;
  printf("Entre com um string: ");
  gets(string);
  printf("Entre com um letra: ");
  scanf(" %c", &letra);
  ult = ultima(&string[0], letra);
  pri = primeira(&string[0], letra);
  printf("Ultima ocorrencia da letra %c: %d\nPrimeira ocorrencia da letra %c: %d", letra, ult, letra, pri);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D19(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D28(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rsi
  lea    D35(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  call   <ultima@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <primeira@plt>
  movsbl 0xd(%rsp),%esi
  mov    %r12d,%edx
  lea    D3(%rip),%rdi
  mov    %eax,%r8d
  xor    %eax,%eax
  mov    %esi,%ecx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D19
data_type: string
name: unpack_data
arguments: data_label: D28
data_type: string
name: unpack_data
arguments: data_label: D35
data_type: string
name: unpack_data
arguments: data_label: D3
data_type: string

tool: D19: Entre com um string: 

tool: D28: Entre com um letra: 

tool: D35:  %c

tool: D3: Ultima ocorrencia da letra %c: %d
Primeira ocorrencia da letra %c: %d

assistant: ```c
int main() {
  char string[10], letra;
  int ult, pri;
  printf("Entre com um string: ");
  gets(string);
  printf("Entre com um letra: ");
  scanf(" %c", &letra);
  ult = ultima(&string[0], letra);
  pri = primeira(&string[0], letra);
  printf("Ultima ocorrencia da letra %c: %d\nPrimeira ocorrencia da letra %c: %d", letra, ult, letra, pri);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D7(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%rbp
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <gets@plt>
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xd(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  call   <ultima@plt>
  movsbl 0xd(%rsp),%esi
  mov    %rbp,%rdi
  mov    %eax,%r12d
  call   <primeira@plt>
  movsbl 0xd(%rsp),%esi
  mov    %r12d,%edx
  lea    D34(%rip),%rdi
  mov    %eax,%r8d
  xor    %eax,%eax
  mov    %esi,%ecx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
data_type: string
name: disassemble_data
arguments: label: D4
data_type: string
name: disassemble_data
arguments: label: D37
data_type: string
name: disassemble_data
arguments: label: D34
data_type: string

tool: D7: Entre com um string: 

tool: D4: Entre com um letra: 

tool: D37:  %c

tool: D34: Ultima ocorrencia da letra %c: %d
Primeira ocorrencia da letra %c: %d

assistant: ```c
int main() {
  char string[10], letra;
  int ult, pri;
  printf("Entre com um string: ");
  gets(string);
  printf("Entre com um letra: ");
  scanf(" %c", &letra);
  ult = ultima(&string[0], letra);
  pri = primeira(&string[0], letra);
  printf("Ultima ocorrencia da letra %c: %d\nPrimeira ocorrencia da letra %c: %d", letra, ult, letra, pri);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x22,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fibI@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fibR@plt>
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D3
datatype: string

tool: D3: fib: %d = %d


assistant: ```c
int main() {
  int N;
  N = 34;
  printf("fib: %d = %d\n", fibR(N), fibI(N));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x22,%edi
  call   <fibI@plt>
  mov    %eax,%ebx
  mov    $0x22,%edi
  call   <fibR@plt>
  mov    %eax,%esi
  mov    %ebx,%edx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_guessed: string

tool: D7: fib: %d = %d


assistant: ```c
int main() {
  int N;
  N = 34;
  printf("fib: %d = %d\n", fibR(N), fibI(N));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x22,%edi
  call   <fibI@plt>
  mov    $0x22,%edi
  mov    %eax,%r12d
  call   <fibR@plt>
  mov    %r12d,%edx
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type_infered: string

tool: D9: fib: %d = %d


assistant: ```c
int main() {
  int N;
  N = 34;
  printf("fib: %d = %d\n", fibR(N), fibI(N));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x22,%edi
  call   <fibI@plt>
  mov    $0x22,%edi
  mov    %eax,%r12d
  call   <fibR@plt>
  mov    %r12d,%edx
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
type_infered: string

tool: D7: fib: %d = %d


assistant: ```c
int main() {
  int N;
  N = 34;
  printf("fib: %d = %d\n", fibR(N), fibI(N));
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SE_intercept>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  movsd  %xmm0,-0x40(%rbp)
  movsd  %xmm1,-0x48(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x34(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <mean@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L0:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  subsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L11:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L0
  movsd  -0x48(%rbp),%xmm0
  mov    -0x40(%rbp),%rsi
  mov    -0x34(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <var@plt>
  movsd  %xmm0,-0x50(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm1
  divsd  -0x10(%rbp),%xmm1
  mov    $0x1,%eax
  cltd
  idivl  -0x34(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mulsd  -0x50(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double SE_intercept(double *x, double *y, int n, double slope, double intercept) {
  double sumXmeanX = 0;
  double meanX = mean(x, n);
  for (int j = 0; j < n; j++)
    sumXmeanX += pow(x[j] - meanX, 2);
  return var(x, y, n, slope, intercept) * sqrt((pow(meanX, 2) / sumXmeanX) + (1 / n));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<SE_intercept>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %edx,%r12d
  movsd  %xmm0,0x18(%rsp)
  movq   %xmm1,%r15
  mov    %edx,%esi
  call   <mean@plt>
  movsd  %xmm0,0x10(%rsp)
  test   %r12d,%r12d
  jle    L11
  mov    %r13,%rbx
  lea    -0x1(%r12),%eax
  lea    0x8(%r13,%rax,8),%rbp
  pxor   %xmm6,%xmm6
  movsd  %xmm6,0x8(%rsp)
L26:
  movsd  (%rbx),%xmm0
  subsd  0x10(%rsp),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L26
L32:
  movq   %r15,%xmm1
  movsd  0x18(%rsp),%xmm0
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <var@plt>
  movq   %xmm0,%rbx
  mov    $0x2,%edi
  movsd  0x10(%rsp),%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm1
  mov    $0x1,%eax
  cltd
  idiv   %r12d
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  divsd  0x8(%rsp),%xmm1
  addsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm0,%xmm1
  ja     L31
  sqrtsd %xmm0,%xmm0
L44:
  movq   %rbx,%xmm4
  mulsd  %xmm0,%xmm4
  movapd %xmm4,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  pxor   %xmm7,%xmm7
  movsd  %xmm7,0x8(%rsp)
  jmp    L32
L31:
  call   <sqrt@plt>
  jmp    L44
```

assistant: ```c
double SE_intercept(double *x, double *y, int n, double slope, double intercept) {
  double sumXmeanX = 0;
  double meanX = mean(x, n);
  for (int j = 0; j < n; j++)
    sumXmeanX += pow(x[j] - meanX, 2);
  return var(x, y, n, slope, intercept) * sqrt((pow(meanX, 2) / sumXmeanX) + (1 / n));
}
```