ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L51
  movzbl (%rsi),%r8d
  nop
L21:
  mov    %rsi,%rdx
  mov    %r8d,%eax
  test   %r8b,%r8b
  jne    L30
  jmp    L15
  nopl   (%rax)
L42:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L15
L30:
  cmp    %al,%cl
  jne    L42
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  cmovne %rdi,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  movzbl 0x1(%rdi),%ecx
  add    $0x1,%rdi
  test   %cl,%cl
  jne    L21
  xor    %eax,%eax
  cmpb   $0x0,(%rdx)
  cmovne %rdi,%rax
  ret
L51:
  xor    %eax,%eax
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  const char *c = NULL;
  if (!*s)
    return NULL;
  while (*s) {
    for (c = accept; *c; c++) {
      if (*s == *c)
        break;
    }
    if (*c)
      break;
    s++;
  }
  return (*c == 0) ? NULL : (char *)s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strpbrk>:
  endbr64
  movzbl (%rdi),%ecx
  mov    %rdi,%r8
  test   %cl,%cl
  je     L29
  movzbl (%rsi),%edi
  nopl   0x0(%rax)
L59:
  mov    %rsi,%rdx
  mov    %edi,%eax
  test   %dil,%dil
  jne    L43
  jmp    L15
  nopl   0x0(%rax)
L6:
  movzbl 0x1(%rdx),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L15
L43:
  cmp    %al,%cl
  jne    L6
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L15:
  movzbl 0x1(%r8),%ecx
  add    $0x1,%r8
  test   %cl,%cl
  jne    L59
L29:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
char *strpbrk(const char *s, const char *accept) {
  const char *c = NULL;
  if (!*s)
    return NULL;
  while (*s) {
    for (c = accept; *c; c++) {
      if (*s == *c)
        break;
    }
    if (*c)
      break;
    s++;
  }
  return (*c == 0) ? NULL : (char *)s;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x36,%edx
  mov    $0xc,%esi
  mov    $0x22,%edi
  call   <mod_pow@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x17,%edx
  mov    $0x37,%esi
  mov    $0x15,%edi
  call   <mod_pow@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type_guessed: string

tool: D4: result1 = %d, result2 = %d


assistant: ```c
int main() {
  int result1 = mod_pow(34, 12, 54);
  int result2 = mod_pow(21, 55, 23);
  printf("result1 = %d, result2 = %d\n", result1, result2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x36,%edx
  mov    $0xc,%esi
  mov    $0x22,%edi
  call   <mod_pow@plt>
  mov    %eax,%ebx
  mov    $0x17,%edx
  mov    $0x37,%esi
  mov    $0x15,%edi
  call   <mod_pow@plt>
  mov    %eax,%edx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
data_type: string

tool: D1: result1 = %d, result2 = %d


assistant: ```c
int main() {
  int result1 = mod_pow(34, 12, 54);
  int result2 = mod_pow(21, 55, 23);
  printf("result1 = %d, result2 = %d\n", result1, result2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x36,%edx
  mov    $0xc,%esi
  mov    $0x22,%edi
  call   <mod_pow@plt>
  mov    $0x17,%edx
  mov    $0x37,%esi
  mov    $0x15,%edi
  mov    %eax,%ebp
  call   <mod_pow@plt>
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
datatype: string

tool: D4: result1 = %d, result2 = %d


assistant: ```c
int main() {
  int result1 = mod_pow(34, 12, 54);
  int result2 = mod_pow(21, 55, 23);
  printf("result1 = %d, result2 = %d\n", result1, result2);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x36,%edx
  mov    $0xc,%esi
  mov    $0x22,%edi
  call   <mod_pow@plt>
  mov    $0x17,%edx
  mov    $0x37,%esi
  mov    $0x15,%edi
  mov    %eax,%ebp
  call   <mod_pow@plt>
  mov    %ebp,%esi
  lea    D0(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type: string

tool: D0: result1 = %d, result2 = %d


assistant: ```c
int main() {
  int result1 = mod_pow(34, 12, 54);
  int result2 = mod_pow(21, 55, 23);
  printf("result1 = %d, result2 = %d\n", result1, result2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L32:
  cmp    %rdx,%rsp
  je     L14
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L32
L14:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L28
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L28:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x58(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x40(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  nop
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: %s


assistant: ```c
void test1(const char *msg) {
  char a[strlen(msg) + 1];
  strcpy(a, msg);
  printf("%s\n", a);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L8:
  cmp    %rdx,%rsp
  je     L29
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L8
L29:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L2
  orq    $0x0,-0x8(%rsp,%rax,1)
L2:
  mov    %rbx,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  mov    -0x8(%rbp),%rbx
  leave
  ret
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: %s


assistant: ```c
void test1(const char *msg) {
  char a[strlen(msg) + 1];
  strcpy(a, msg);
  printf("%s\n", a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L3
L28:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L28
L3:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L25
L2:
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L2
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D9
type: string

tool: D9: %s


assistant: ```c
void test1(const char *msg) {
  char a[strlen(msg) + 1];
  strcpy(a, msg);
  printf("%s\n", a);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  mov    %rdi,%r12
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %rsp,%rcx
  add    $0x1,%eax
  cltq
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L39
L22:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L22
L39:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L1
L24:
  mov    %r12,%rsi
  mov    %rsp,%rdi
  call   <strcpy@plt>
  mov    %rsp,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    -0x8(%rbp),%r12
  leave
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L24
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type: string

tool: D6: %s


assistant: ```c
void test1(const char *msg) {
  char a[strlen(msg) + 1];
  strcpy(a, msg);
  printf("%s\n", a);
}
```
user: What is the c source code of the assembly code below?

```asm
<pack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L19
L10:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L5
  cmpl   $0x1,-0x4(%rbp)
  jg     L71
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L42
L71:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L89
L5:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L12
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L19:
  subl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L10
  jmp    L89
L42:
  nop
  jmp    L89
L12:
  nop
L89:
  nop
  leave
  ret
```

assistant: ```c
void pack(unsigned char *s) {
  int pos = strlen((char *)s);
  for (; --pos >= 0;) {
    if (s[pos] == '/') {
      if (pos < 2 && s[0] == '/')
        break;
      s[pos] = 0;
      break;
    }
    if (s[pos] == ' ')
      s[pos] = 0;
    else
      break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<pack>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L39
  movslq %eax,%rdx
  add    %rbx,%rdx
L13:
  mov    %rdx,%rsi
  movzbl (%rdx),%ecx
  cmp    $0x2f,%cl
  je     L11
  cmp    $0x20,%cl
  jne    L39
  movb   $0x0,(%rdx)
  sub    $0x1,%eax
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  jne    L13
L39:
  pop    %rbx
  ret
L11:
  cmp    $0x1,%eax
  jle    L21
L26:
  movb   $0x0,(%rsi)
  jmp    L39
L21:
  cmpb   $0x2f,(%rbx)
  jne    L26
  jmp    L39
```

assistant: ```c
void pack(unsigned char *s) {
  int pos = strlen((char *)s);
  for (; --pos >= 0;) {
    if (s[pos] == '/') {
      if (pos < 2 && s[0] == '/')
        break;
      s[pos] = 0;
      break;
    }
    if (s[pos] == ' ')
      s[pos] = 0;
    else
      break;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pack>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L76
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L56:
  cmp    $0x20,%cl
  jne    L76
  sub    $0x1,%eax
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L76
L78:
  movzbl (%rdx),%ecx
  cmp    $0x2f,%cl
  jne    L56
  cmp    $0x1,%eax
  jle    L55
L53:
  movb   $0x0,(%rdx)
L76:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L55:
  cmpb   $0x2f,(%rbx)
  jne    L53
  jmp    L76
```

assistant: ```c
void pack(unsigned char *s) {
  int pos = strlen((char *)s);
  for (; --pos >= 0;) {
    if (s[pos] == '/') {
      if (pos < 2 && s[0] == '/')
        break;
      s[pos] = 0;
      break;
    }
    if (s[pos] == ' ')
      s[pos] = 0;
    else
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pack>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L45
  movslq %eax,%rdx
  add    %rbx,%rdx
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L3:
  cmp    $0x20,%cl
  jne    L45
  sub    $0x1,%eax
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  cmp    $0xffffffff,%eax
  je     L45
L46:
  movzbl (%rdx),%ecx
  cmp    $0x2f,%cl
  jne    L3
  cmp    $0x1,%eax
  jle    L21
L70:
  movb   $0x0,(%rdx)
L45:
  pop    %rbx
  ret
  cs nopw 0x0(%rax,%rax,1)
L21:
  cmpb   $0x2f,(%rbx)
  jne    L70
  jmp    L45
```

assistant: ```c
void pack(unsigned char *s) {
  int pos = strlen((char *)s);
  for (; --pos >= 0;) {
    if (s[pos] == '/') {
      if (pos < 2 && s[0] == '/')
        break;
      s[pos] = 0;
      break;
    }
    if (s[pos] == ' ')
      s[pos] = 0;
    else
      break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getrank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <MPI_Comm_rank@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int getrank() {
  int errorcode, rank;
  errorcode = MPI_Comm_rank((1), &rank);
  return rank;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getrank>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x1,%edi
  call   <MPI_Comm_rank@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getrank() {
  int errorcode, rank;
  errorcode = MPI_Comm_rank((1), &rank);
  return rank;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<getrank>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <MPI_Comm_rank@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getrank() {
  int errorcode, rank;
  errorcode = MPI_Comm_rank((1), &rank);
  return rank;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getrank>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <MPI_Comm_rank@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getrank() {
  int errorcode, rank;
  errorcode = MPI_Comm_rank((1), &rank);
  return rank;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wcslcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x8(%rbp)
  je     L22
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L22
L0:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  je     L77
  subq   $0x1,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  jmp    L22
L77:
  nop
L22:
  cmpq   $0x0,-0x8(%rbp)
  jne    L70
  cmpq   $0x0,-0x38(%rbp)
  je     L51
  mov    -0x18(%rbp),%rax
  movb   $0x0,(%rax)
L51:
  nop
L39:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
L70:
  mov    -0x10(%rbp),%rax
  sub    -0x30(%rbp),%rax
  sub    $0x1,%rax
  leave
  ret
```

assistant: ```c
size_t wcslcpy(wchar_t *dst, const wchar_t *src, size_t siz) {
  wchar_t *d = dst;
  const wchar_t *s = src;
  size_t n = siz;
  assert(dst != NULL);
  assert(src != NULL);
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wcslcpy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbx,%rbx
  je     L89
  sub    $0x1,%rbx
  mov    %rbx,%rdx
  je     L82
  mov    %rbp,%rax
L32:
  add    $0x1,%rax
  add    $0x1,%r12
  movzbl -0x1(%rax),%ecx
  mov    %cl,-0x1(%r12)
  test   %cl,%cl
  je     L62
  sub    $0x1,%rdx
  jne    L32
  jmp    L42
L89:
  mov    %rbp,%rax
L78:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L78
L81:
  sub    %rbp,%rax
  sub    $0x1,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L82:
  mov    %rbp,%rax
L42:
  movb   $0x0,(%r12)
  jmp    L78
L62:
  test   %rdx,%rdx
  jne    L81
  jmp    L42
```

assistant: ```c
size_t wcslcpy(wchar_t *dst, const wchar_t *src, size_t siz) {
  wchar_t *d = dst;
  const wchar_t *s = src;
  size_t n = siz;
  assert(dst != NULL);
  assert(src != NULL);
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<wcslcpy>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rax
  test   %r12,%r12
  je     L56
  cmp    $0x1,%r12
  je     L48
  mov    %rbx,%rcx
  jmp    L70
  nopw   0x0(%rax,%rax,1)
L12:
  mov    %r12,%rdx
  sub    %rcx,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  test   %rdx,%rdx
  je     L25
L70:
  movzbl (%rax),%esi
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  test   %sil,%sil
  jne    L12
L75:
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  sub    $0x1,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rcx,%rbx
L48:
  movb   $0x0,(%rbx)
  cs nopw 0x0(%rax,%rax,1)
L56:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L75
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L56
  jmp    L75
```

assistant: ```c
size_t wcslcpy(wchar_t *dst, const wchar_t *src, size_t siz) {
  wchar_t *d = dst;
  const wchar_t *s = src;
  size_t n = siz;
  assert(dst != NULL);
  assert(src != NULL);
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<wcslcpy>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rax
  test   %r12,%r12
  je     L53
  cmp    $0x1,%r12
  je     L48
  mov    %rbx,%rcx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L28:
  mov    %r12,%rdx
  sub    %rcx,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  test   %rdx,%rdx
  je     L43
L18:
  movzbl (%rax),%esi
  add    $0x1,%rax
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  test   %sil,%sil
  jne    L28
L55:
  sub    %rbp,%rax
  pop    %rbx
  pop    %rbp
  sub    $0x1,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  mov    %rcx,%rbx
L48:
  movb   $0x0,(%rbx)
  cs nopw 0x0(%rax,%rax,1)
L53:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  je     L55
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L53
  jmp    L55
```

assistant: ```c
size_t wcslcpy(wchar_t *dst, const wchar_t *src, size_t siz) {
  wchar_t *d = dst;
  const wchar_t *s = src;
  size_t n = siz;
  assert(dst != NULL);
  assert(src != NULL);
  if (n != 0 && --n != 0) {
    do {
      if ((*d++ = *s++) == 0)
        break;
    } while (--n != 0);
  }
  if (n == 0) {
    if (siz != 0)
      *d = '\0';
    while (*s++)
      ;
  }
  return (s - src - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x2c(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  mov    -0x30(%rbp),%edx
  sub    %edx,%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x28(%rbp),%edx
  sub    %edx,%eax
  mov    $0x2,%esi
  mov    %eax,%edi
  call   <pow@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm0
  addsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D31
type_infered: string
name: extract_symbolic_data
arguments: data_label: D44
type_infered: string

tool: D31: %i

tool: D44: A DISTANCIA ENTRE A e B = %0.2f


assistant: ```c
int main() {
  int x1, x2, y1, y2;
  scanf("%i", &x1);
  scanf("%i", &y1);
  scanf("%i", &x2);
  scanf("%i", &y2);
  double e1 = pow(x2 - x1, 2);
  double e2 = pow(y2 - y1, 2);
  double d = sqrt(e1 + e2);
  printf("A DISTANCIA ENTRE A e B = %0.2f\n", d);
  return 0;
}
```