ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<argv_create>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %rsi,%r14
  call   <_sizeargv@plt>
  mov    %eax,%r13d
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L52
  mov    %rax,%rbp
  test   %r13d,%r13d
  jle    L57
  mov    $0x0,%r12d
  lea    0x18(%rsp),%r15
L59:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <_nextargv@plt>
  mov    %rax,%rbx
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L12
  add    $0x1,%r12d
  add    $0x8,%rbp
  cmp    %r12d,%r13d
  jne    L59
L46:
  movslq %r13d,%r13
  mov    0x10(%rsp),%rax
  movq   $0x0,(%rax,%r13,8)
L68:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  mov    0x10(%rsp),%rdi
  call   <argv_destroy@plt>
  mov    %rbx,0x8(%rsp)
  jmp    L68
L57:
  mov    $0x0,%r13d
  jmp    L46
L52:
  movq   $0x0,0x8(%rsp)
  jmp    L68
```

assistant: ```c
char **argv_create(char *cmdline, char *ignore) {
  int argc = _sizeargv(cmdline, ignore);
  char **argv = (char **)malloc(sizeof(char *) * (argc + 1));
  int i;
  if (!argv)
    return (NULL);
  for (i = 0; i < argc; i++) {
    if (!(argv[i] = _nextargv(&cmdline, ignore))) {
      argv_destroy(argv);
      return (NULL);
    }
  }
  argv[i] = NULL;
  return argv;
}
```
user: What is the c source code of the assembly code below?

```asm
<argv_create>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <_sizeargv@plt>
  movslq %eax,%rbx
  lea    0x8(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L22
  test   %ebx,%ebx
  jle    L55
  mov    %rax,%r14
  xor    %r15d,%r15d
  lea    0x8(%rsp),%r12
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L18:
  add    $0x1,%r15d
  add    $0x8,%r14
  cmp    %r15d,%ebx
  je     L35
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_nextargv@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L18
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <argv_destroy@plt>
L22:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L35:
  lea    0x0(%r13,%rbx,8),%rax
L55:
  movq   $0x0,(%rax)
  jmp    L22
```

assistant: ```c
char **argv_create(char *cmdline, char *ignore) {
  int argc = _sizeargv(cmdline, ignore);
  char **argv = (char **)malloc(sizeof(char *) * (argc + 1));
  int i;
  if (!argv)
    return (NULL);
  for (i = 0; i < argc; i++) {
    if (!(argv[i] = _nextargv(&cmdline, ignore))) {
      argv_destroy(argv);
      return (NULL);
    }
  }
  argv[i] = NULL;
  return argv;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<argv_create>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  call   <_sizeargv@plt>
  movslq %eax,%rbx
  lea    0x8(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L39
  test   %ebx,%ebx
  jle    L1
  mov    %rax,%r14
  xor    %r15d,%r15d
  lea    0x8(%rsp),%r12
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%r15d
  add    $0x8,%r14
  cmp    %r15d,%ebx
  je     L20
L32:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <_nextargv@plt>
  mov    %rax,(%r14)
  test   %rax,%rax
  jne    L3
  mov    %r13,%rdi
  xor    %r13d,%r13d
  call   <argv_destroy@plt>
L39:
  add    $0x18,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L20:
  lea    0x0(%r13,%rbx,8),%rax
L1:
  movq   $0x0,(%rax)
  jmp    L39
```

assistant: ```c
char **argv_create(char *cmdline, char *ignore) {
  int argc = _sizeargv(cmdline, ignore);
  char **argv = (char **)malloc(sizeof(char *) * (argc + 1));
  int i;
  if (!argv)
    return (NULL);
  for (i = 0; i < argc; i++) {
    if (!(argv[i] = _nextargv(&cmdline, ignore))) {
      argv_destroy(argv);
      return (NULL);
    }
  }
  argv[i] = NULL;
  return argv;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <testComparison@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x0,%eax
  call   <testAddition@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x0,%eax
  call   <testSubtraction@plt>
  test   %rax,%rax
  jne    L37
  mov    $0x0,%eax
  call   <testNegation@plt>
  test   %rax,%rax
  je     L26
L37:
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  jmp    L49
L26:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
L49:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  if (testComparison() || testAddition() || testSubtraction() || testNegation())
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <testComparison@plt>
  test   %rax,%rax
  je     L49
L20:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
L39:
  add    $0x8,%rsp
  ret
L49:
  call   <testAddition@plt>
  test   %rax,%rax
  jne    L20
  call   <testSubtraction@plt>
  test   %rax,%rax
  jne    L20
  call   <testNegation@plt>
  test   %rax,%rax
  jne    L20
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  jmp    L39
```

assistant: ```c
int main(int argc, char **argv) {
  if (testComparison() || testAddition() || testSubtraction() || testNegation())
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testComparison@plt>
  test   %rax,%rax
  je     L48
L45:
  mov    D18(%rip),%rax
  mov    (%rax),%eax
L9:
  add    $0x8,%rsp
  ret
L48:
  xor    %eax,%eax
  call   <testAddition@plt>
  test   %rax,%rax
  jne    L45
  call   <testSubtraction@plt>
  test   %rax,%rax
  jne    L45
  call   <testNegation@plt>
  test   %rax,%rax
  jne    L45
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  jmp    L9
```

assistant: ```c
int main(int argc, char **argv) {
  if (testComparison() || testAddition() || testSubtraction() || testNegation())
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <testComparison@plt>
  test   %rax,%rax
  je     L6
L10:
  mov    D1(%rip),%rax
  mov    (%rax),%eax
L49:
  add    $0x8,%rsp
  ret
L6:
  xor    %eax,%eax
  call   <testAddition@plt>
  test   %rax,%rax
  jne    L10
  call   <testSubtraction@plt>
  test   %rax,%rax
  jne    L10
  call   <testNegation@plt>
  test   %rax,%rax
  jne    L10
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  jmp    L49
```

assistant: ```c
int main(int argc, char **argv) {
  if (testComparison() || testAddition() || testSubtraction() || testNegation())
    return EXIT_FAILURE;
  return EXIT_SUCCESS;
}
```
user: What is the c source code of the assembly code below?

```asm
<findPart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x14(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L86
L27:
  mov    -0x14(%rbp),%eax
  cltq
  cmp    %rax,-0x30(%rbp)
  ja     L61
  mov    $0x1,%eax
  jmp    L33
L61:
  movzbl -0xa(%rbp),%edx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L71
  movl   $0x0,-0x14(%rbp)
  jmp    L74
L71:
  addl   $0x1,-0x14(%rbp)
L74:
  mov    -0x10(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  cmp    $0x7d0,%eax
  jle    L86
  mov    $0x0,%eax
  jmp    L33
L86:
  lea    -0xa(%rbp),%rax
  mov    %rax,%rdi
  call   <getByte@plt>
  test   %rax,%rax
  jg     L27
  mov    $0x0,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L80
  call   <__stack_chk_fail@plt>
L80:
  leave
  ret
```

assistant: ```c
int findPart(unsigned char *buffer, size_t len) {
  unsigned char charBuffer[2];
  int idx = 0;
  int total = 0;
  while (getByte(charBuffer) > 0) {
    if (idx >= len)
      return 1;
    if (*charBuffer != buffer[idx])
      idx = 0;
    else
      idx++;
    if (total++ > 2000)
      return 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findPart>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x7d2,%ebx
  mov    $0x0,%ebp
  lea    0x6(%rsp),%r14
  jmp    L59
L87:
  sub    $0x1,%ebx
  je     L47
L59:
  mov    %r14,%rdi
  call   <getByte@plt>
  test   %rax,%rax
  jle    L66
  movslq %ebp,%rax
  cmp    %r12,%rax
  jae    L29
  movzbl 0x0(%r13,%rax,1),%eax
  add    $0x1,%ebp
  cmp    %al,0x6(%rsp)
  je     L87
  mov    $0x0,%ebp
  jmp    L87
L66:
  mov    $0x0,%eax
L56:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  mov    $0x1,%eax
  jmp    L56
L47:
  mov    $0x0,%eax
  jmp    L56
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findPart(unsigned char *buffer, size_t len) {
  unsigned char charBuffer[2];
  int idx = 0;
  int total = 0;
  while (getByte(charBuffer) > 0) {
    if (idx >= len)
      return 1;
    if (*charBuffer != buffer[idx])
      idx = 0;
    else
      idx++;
    if (total++ > 2000)
      return 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findPart>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x7d2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r14
  jmp    L0
  nopl   0x0(%rax)
L41:
  movslq %ebp,%rax
  cmp    %r12,%rax
  jae    L47
  movzbl 0x0(%r13,%rax,1),%eax
  add    $0x1,%ebp
  cmp    %al,0x6(%rsp)
  je     L44
  xor    %ebp,%ebp
L44:
  sub    $0x1,%ebx
  je     L68
L0:
  mov    %r14,%rdi
  call   <getByte@plt>
  test   %rax,%rax
  jg     L41
L68:
  xor    %eax,%eax
L58:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L47:
  mov    $0x1,%eax
  jmp    L58
L57:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findPart(unsigned char *buffer, size_t len) {
  unsigned char charBuffer[2];
  int idx = 0;
  int total = 0;
  while (getByte(charBuffer) > 0) {
    if (idx >= len)
      return 1;
    if (*charBuffer != buffer[idx])
      idx = 0;
    else
      idx++;
    if (total++ > 2000)
      return 0;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<findPart>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x7d2,%ebx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x6(%rsp),%r14
  jmp    L14
  nopl   0x0(%rax)
L15:
  movslq %ebp,%rax
  cmp    %r12,%rax
  jae    L4
  movzbl 0x0(%r13,%rax,1),%eax
  add    $0x1,%ebp
  cmp    %al,0x6(%rsp)
  je     L18
  xor    %ebp,%ebp
L18:
  sub    $0x1,%ebx
  je     L47
L14:
  mov    %r14,%rdi
  call   <getByte@plt>
  test   %rax,%rax
  jg     L15
L47:
  xor    %eax,%eax
L16:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L69
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    $0x1,%eax
  jmp    L16
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int findPart(unsigned char *buffer, size_t len) {
  unsigned char charBuffer[2];
  int idx = 0;
  int total = 0;
  while (getByte(charBuffer) > 0) {
    if (idx >= len)
      return 1;
    if (*charBuffer != buffer[idx])
      idx = 0;
    else
      idx++;
    if (total++ > 2000)
      return 0;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getsystemtotalmem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D22(%rip),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <popen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L17
  lea    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  lea    D32(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  jne    L17
  cmpl   $0x0,-0x24(%rbp)
  je     L24
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  lea    D43(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
L24:
  mov    -0x18(%rbp),%rax
  shl    $0xa,%rax
  mov    %rax,-0x18(%rbp)
  jmp    L41
L17:
  movq   $0x0,-0x18(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L41
  mov    $0xc,%ecx
  lea    D11(%rip),%rax
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
L41:
  cmpq   $0x0,-0x10(%rbp)
  je     L32
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <pclose@plt>
L32:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D22
type_guessed: string
name: extract_symbolic_data
arguments: label: D16
type_guessed: string
name: extract_symbolic_data
arguments: label: D32
type_guessed: string
name: extract_symbolic_data
arguments: label: D43
type_guessed: string
name: extract_symbolic_data
arguments: label: D11
type_guessed: string

tool: D22: r

tool: D16: grep MemTotal /proc/meminfo

tool: D32: MemTotal: %lld kB

tool: D43: %lld KB total memory according to /proc/meminfo

tool: D11: assuming compiled in memory size of %d GB

assistant: ```c
int64_t getsystemtotalmem(int explain) {
  long long res;
  FILE *p = popen("grep MemTotal /proc/meminfo", "r");
  if (p && fscanf(p, "MemTotal: %lld kB", &res) == 1) {
    if (explain)
      msg(-1, 0, "%lld KB total memory according to /proc/meminfo", res);
    res <<= 10;
  } else {
    res = 12 << 30;
    ;
    if (explain)
      msg(-1, 0, "assuming compiled in memory size of %d GB", 12);
  }
  if (p)
    pclose(p);
  return (int64_t)res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getsystemtotalmem>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D15(%rip),%rsi
  lea    D39(%rip),%rdi
  call   <popen@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbx
  mov    %rsp,%rdx
  lea    D30(%rip),%rsi
  mov    %rax,%rdi
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L8
  movq   $0x0,(%rsp)
  test   %ebp,%ebp
  jne    L33
L10:
  mov    %rbx,%rdi
  call   <pclose@plt>
L82:
  mov    (%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L97
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  test   %ebp,%ebp
  jne    L38
L98:
  shlq   $0xa,(%rsp)
  jmp    L10
L38:
  mov    (%rsp),%ecx
  lea    D38(%rip),%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L98
L17:
  movq   $0x0,(%rsp)
  test   %ebp,%ebp
  je     L82
  mov    $0xc,%ecx
  lea    D28(%rip),%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L82
L33:
  mov    $0xc,%ecx
  lea    D28(%rip),%rdx
  mov    $0x0,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L10
L97:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D15
type_infered: string
name: unpack_data
arguments: tag: D39
type_infered: string
name: unpack_data
arguments: tag: D30
type_infered: string
name: unpack_data
arguments: tag: D38
type_infered: string
name: unpack_data
arguments: tag: D28
type_infered: string

tool: D15: r

tool: D39: grep MemTotal /proc/meminfo

tool: D30: MemTotal: %lld kB

tool: D38: %lld KB total memory according to /proc/meminfo

tool: D28: assuming compiled in memory size of %d GB

assistant: ```c
int64_t getsystemtotalmem(int explain) {
  long long res;
  FILE *p = popen("grep MemTotal /proc/meminfo", "r");
  if (p && fscanf(p, "MemTotal: %lld kB", &res) == 1) {
    if (explain)
      msg(-1, 0, "%lld KB total memory according to /proc/meminfo", res);
    res <<= 10;
  } else {
    res = 12 << 30;
    ;
    if (explain)
      msg(-1, 0, "assuming compiled in memory size of %d GB", 12);
  }
  if (p)
    pclose(p);
  return (int64_t)res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getsystemtotalmem>:
  endbr64
  push   %rbp
  lea    D45(%rip),%rsi
  push   %rbx
  mov    %edi,%ebx
  lea    D4(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <popen@plt>
  test   %rax,%rax
  je     L1
  mov    %rsp,%rdx
  lea    D49(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L47
  movq   $0x0,(%rsp)
  test   %ebx,%ebx
  jne    L19
L78:
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    (%rsp),%eax
L99:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  movq   $0x0,(%rsp)
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L99
  mov    $0xc,%ecx
  lea    D2(%rip),%rdx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  mov    (%rsp),%eax
  jmp    L99
  nopl   0x0(%rax,%rax,1)
L47:
  test   %ebx,%ebx
  jne    L52
L73:
  shlq   $0xa,(%rsp)
  jmp    L78
  nopl   0x0(%rax,%rax,1)
L19:
  mov    $0xc,%ecx
  lea    D2(%rip),%rdx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L78
  nopw   0x0(%rax,%rax,1)
L52:
  mov    (%rsp),%ecx
  lea    D41(%rip),%rdx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L73
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D45
type_infered: string
name: unpack_data
arguments: label: D4
type_infered: string
name: unpack_data
arguments: label: D49
type_infered: string
name: unpack_data
arguments: label: D2
type_infered: string
name: unpack_data
arguments: label: D41
type_infered: string

tool: D45: r

tool: D4: grep MemTotal /proc/meminfo

tool: D49: MemTotal: %lld kB

tool: D2: assuming compiled in memory size of %d GB

tool: D41: %lld KB total memory according to /proc/meminfo

assistant: ```c
int64_t getsystemtotalmem(int explain) {
  long long res;
  FILE *p = popen("grep MemTotal /proc/meminfo", "r");
  if (p && fscanf(p, "MemTotal: %lld kB", &res) == 1) {
    if (explain)
      msg(-1, 0, "%lld KB total memory according to /proc/meminfo", res);
    res <<= 10;
  } else {
    res = 12 << 30;
    ;
    if (explain)
      msg(-1, 0, "assuming compiled in memory size of %d GB", 12);
  }
  if (p)
    pclose(p);
  return (int64_t)res;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getsystemtotalmem>:
  endbr64
  push   %rbp
  lea    D33(%rip),%rsi
  push   %rbx
  mov    %edi,%ebx
  lea    D37(%rip),%rdi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <popen@plt>
  test   %rax,%rax
  je     L91
  mov    %rsp,%rdx
  lea    D13(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <fscanf@plt>
  cmp    $0x1,%eax
  je     L62
  movq   $0x0,(%rsp)
  test   %ebx,%ebx
  jne    L33
L23:
  mov    %rbp,%rdi
  call   <pclose@plt>
  mov    (%rsp),%eax
L89:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L79
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L91:
  movq   $0x0,(%rsp)
  xor    %eax,%eax
  test   %ebx,%ebx
  je     L89
  mov    $0xc,%ecx
  lea    D57(%rip),%rdx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  mov    (%rsp),%eax
  jmp    L89
  nopl   0x0(%rax,%rax,1)
L62:
  test   %ebx,%ebx
  jne    L54
L74:
  shlq   $0xa,(%rsp)
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L33:
  mov    $0xc,%ecx
  lea    D57(%rip),%rdx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L54:
  mov    (%rsp),%ecx
  lea    D43(%rip),%rdx
  xor    %esi,%esi
  mov    $0xffffffff,%edi
  call   <msg@plt>
  jmp    L74
L79:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D33
type: string
name: extract_symbolic_data
arguments: data_tag: D37
type: string
name: extract_symbolic_data
arguments: data_tag: D13
type: string
name: extract_symbolic_data
arguments: data_tag: D57
type: string
name: extract_symbolic_data
arguments: data_tag: D43
type: string

tool: D33: r

tool: D37: grep MemTotal /proc/meminfo

tool: D13: MemTotal: %lld kB

tool: D57: assuming compiled in memory size of %d GB

tool: D43: %lld KB total memory according to /proc/meminfo

assistant: ```c
int64_t getsystemtotalmem(int explain) {
  long long res;
  FILE *p = popen("grep MemTotal /proc/meminfo", "r");
  if (p && fscanf(p, "MemTotal: %lld kB", &res) == 1) {
    if (explain)
      msg(-1, 0, "%lld KB total memory according to /proc/meminfo", res);
    res <<= 10;
  } else {
    res = 12 << 30;
    ;
    if (explain)
      msg(-1, 0, "assuming compiled in memory size of %d GB", 12);
  }
  if (p)
    pclose(p);
  return (int64_t)res;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <dollars@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: 113213212

assistant: ```c
int main(int argc, char *argv[]) {
  char dest[20];
  char *src = "113213212";
  dollars(dest, src);
  puts(dest);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <dollars@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D0
data_type: string

tool: D0: 113213212

assistant: ```c
int main(int argc, char *argv[]) {
  char dest[20];
  char *src = "113213212";
  dollars(dest, src);
  puts(dest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D5(%rip),%rsi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <dollars@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_infered: string

tool: D5: 113213212

assistant: ```c
int main(int argc, char *argv[]) {
  char dest[20];
  char *src = "113213212";
  dollars(dest, src);
  puts(dest);
  return 0;
}
```