ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<pcap_ether_aton>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x6,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  mov    %r12,%r13
  test   %al,%al
  jne    L11
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rbx
  mov    %ebp,0x0(%r13)
  lea    0x4(%r13),%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L36
L7:
  mov    %rdx,%r13
L11:
  cmp    $0x3a,%al
  sete   %al
  movzbl %al,%eax
  add    %rax,%rbx
  movsbl (%rbx),%edi
  call   <xdtoi@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%ebp
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L40
  movsbl 0x1(%rbx),%edi
  shl    $0x4,%ebp
  lea    0x2(%rbx),%r14
  mov    %r14,%rbx
  call   <xdtoi@plt>
  lea    0x4(%r13),%rdx
  or     %eax,%ebp
  mov    %ebp,0x0(%r13)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L7
L36:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
u_char *pcap_ether_aton(const char *s) {
  register u_char *ep, *e;
  register u_int d;
  e = ep = (u_char *)malloc(6);
  while (*s) {
    if (*s == ':')
      s += 1;
    d = xdtoi(*s++);
    if (isxdigit(*s)) {
      d <<= 4;
      d |= xdtoi(*s++);
    }
    *ep++ = d;
  }
  return (e);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pcap_ether_aton>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x6,%edi
  call   <malloc@plt>
  movsbl (%rbx),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L55
  mov    %rax,%rbp
  jmp    L45
  nopl   0x0(%rax)
L46:
  mov    %r13d,0x0(%rbp)
  movsbl 0x1(%rbx),%edi
  lea    0x1(%rbx),%r14
  lea    0x4(%rbp),%rdx
  test   %dil,%dil
  je     L55
L16:
  mov    %rdx,%rbp
  mov    %r14,%rbx
L45:
  cmp    $0x3a,%dil
  jne    L4
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
L4:
  call   <xdtoi@plt>
  movsbl 0x1(%rbx),%edi
  mov    %eax,%r13d
  call   <isxdigit@plt>
  test   %rax,%rax
  je     L46
  movsbl 0x1(%rbx),%edi
  shl    $0x4,%r13d
  lea    0x2(%rbx),%r14
  call   <xdtoi@plt>
  lea    0x4(%rbp),%rdx
  or     %eax,%r13d
  mov    %r13d,0x0(%rbp)
  movsbl 0x2(%rbx),%edi
  test   %dil,%dil
  jne    L16
L55:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
u_char *pcap_ether_aton(const char *s) {
  register u_char *ep, *e;
  register u_int d;
  e = ep = (u_char *)malloc(6);
  while (*s) {
    if (*s == ':')
      s += 1;
    d = xdtoi(*s++);
    if (isxdigit(*s)) {
      d <<= 4;
      d |= xdtoi(*s++);
    }
    *ep++ = d;
  }
  return (e);
}
```
user: What is the c source code of the assembly code below:

```asm
<find_first_lt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L22:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x20(%rbp),%xmm0
  comisd %xmm1,%xmm0
  ja     L19
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L22
  jmp    L14
L19:
  nop
L14:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int find_first_lt(double *x, double a, int n) {
  int i;
  for (i = 0; i < n; ++i)
    if (x[i] < a)
      break;
  return i;
}
```
user: What is the c source code of the assembly code below:

```asm
<find_first_lt>:
  endbr64
  test   %esi,%esi
  jle    L8
  mov    $0x0,%eax
L29:
  comisd (%rdi),%xmm0
  ja     L14
  add    $0x1,%eax
  add    $0x8,%rdi
  cmp    %eax,%esi
  jne    L29
  mov    %esi,%eax
  ret
L8:
  mov    $0x0,%eax
L14:
  ret
```

assistant: ```c
int find_first_lt(double *x, double a, int n) {
  int i;
  for (i = 0; i < n; ++i)
    if (x[i] < a)
      break;
  return i;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<find_first_lt>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jg     L25
  jmp    L38
  nopl   0x0(%rax)
L22:
  add    $0x1,%eax
  add    $0x8,%rdi
  cmp    %eax,%esi
  je     L3
L25:
  comisd (%rdi),%xmm0
  jbe    L22
L38:
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
int find_first_lt(double *x, double a, int n) {
  int i;
  for (i = 0; i < n; ++i)
    if (x[i] < a)
      break;
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<find_first_lt>:
  endbr64
  xor    %eax,%eax
  test   %esi,%esi
  jg     L21
  jmp    L39
  nopl   0x0(%rax)
L3:
  add    $0x1,%eax
  add    $0x8,%rdi
  cmp    %eax,%esi
  je     L31
L21:
  comisd (%rdi),%xmm0
  jbe    L3
L39:
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  ret
```

assistant: ```c
int find_first_lt(double *x, double a, int n) {
  int i;
  for (i = 0; i < n; ++i)
    if (x[i] < a)
      break;
  return i;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x4d,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L36
L51:
  movb   $0x0,-0xb(%rbp)
  jmp    L16
L13:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  movzbl -0xb(%rbp),%ecx
  movzbl -0xa(%rbp),%edx
  add    %ecx,%edx
  cmp    %edx,%eax
  jge    L43
  movzbl -0xb(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0x9(%rbp),%ecx
  movzbl -0xb(%rbp),%eax
  sub    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  jmp    L11
L43:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
L11:
  movzbl -0xb(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xb(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xb(%rbp)
  jb     L13
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L51
  movzbl -0x9(%rbp),%eax
  lea    0x1a(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] -= state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 304314215UL) - (unsigned char)127;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x4d,%eax
  movzbl 0x1(%rdi),%r10d
  test   %r10b,%r10b
  je     L4
  movzbl %r10b,%edi
  mov    $0x0,%r9d
  mov    $0x0,%r8d
L29:
  mov    %r9d,%edx
L25:
  movzbl %al,%ecx
  add    %eax,%eax
  cmp    %edx,%ecx
  cmovl  %r8d,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L25
  add    $0x1,%r9d
  add    $0x1,%edi
  cmp    %r9b,%r10b
  ja     L29
L4:
  add    $0x1a,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] -= state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 304314215UL) - (unsigned char)127;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%r10d
  sub    $0x4d,%eax
  test   %r10b,%r10b
  je     L10
  movzbl %r10b,%edi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xchg   %ax,%ax
L1:
  mov    %r9d,%edx
  nopl   0x0(%rax,%rax,1)
L18:
  movzbl %al,%ecx
  add    %eax,%eax
  cmp    %edx,%ecx
  cmovl  %r8d,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L18
  add    $0x1,%r9d
  add    $0x1,%edi
  cmp    %r9b,%r10b
  ja     L1
L10:
  add    $0x1a,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] -= state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 304314215UL) - (unsigned char)127;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%r10d
  sub    $0x4d,%eax
  test   %r10b,%r10b
  je     L22
  movzbl %r10b,%edi
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xchg   %ax,%ax
L8:
  mov    %r9d,%edx
  nopl   0x0(%rax,%rax,1)
L12:
  movzbl %al,%ecx
  add    %eax,%eax
  cmp    %ecx,%edx
  cmovg  %r8d,%eax
  add    $0x1,%edx
  cmp    %edx,%edi
  jne    L12
  add    $0x1,%r9d
  add    $0x1,%edi
  cmp    %r9b,%r10b
  ja     L8
L22:
  add    $0x1a,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local2;
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      local2 = 0UL;
      while (local2 < input[1UL]) {
        if (state[0UL] < local2 + local1) {
          state[local2] -= state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
        local2++;
      }
      local1++;
    }
    output[0UL] = (state[0UL] - 304314215UL) - (unsigned char)127;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<long_abs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jns    L19
  mov    -0x8(%rbp),%rax
  neg    %rax
  jmp    L14
L19:
  mov    -0x8(%rbp),%rax
L14:
  pop    %rbp
  ret
```

assistant: ```c
long int long_abs(value)
long int value;
{
  if (value < 0L)
    return (-(value));
  else
    return (value);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<long_abs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long int long_abs(value)
long int value;
{
  if (value < 0L)
    return (-(value));
  else
    return (value);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<long_abs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long int long_abs(value)
long int value;
{
  if (value < 0L)
    return (-(value));
  else
    return (value);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<long_abs>:
  endbr64
  mov    %rdi,%rax
  neg    %rax
  cmovs  %rdi,%rax
  ret
```

assistant: ```c
long int long_abs(value)
long int value;
{
  if (value < 0L)
    return (-(value));
  else
    return (value);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncatb>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L63
  jmp    L49
L19:
  addq   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  jmp    L4
L39:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L4:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L38
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L39
L38:
  cmpq   $0x0,-0x28(%rbp)
  je     L63
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L63:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strncatb(char *dest, const char *src, size_t n) {
  char *cptr = dest;
  if (n) {
    while (*cptr) {
      cptr++;
    }
    while ((*src) && (n--)) {
      *cptr++ = *src++;
    }
    if (n) {
      *cptr = *src;
    }
  }
  return dest;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strncatb>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L3
  cmpb   $0x0,(%rdi)
  je     L28
  mov    %rdi,%rcx
L26:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L26
L76:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L68
  sub    $0x1,%rdx
L50:
  add    $0x1,%rsi
  add    $0x1,%rcx
  mov    %r8b,-0x1(%rcx)
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L4
  sub    $0x1,%rdx
  cmp    $0xffffffffffffffff,%rdx
  jne    L50
L68:
  mov    %r8b,(%rcx)
L3:
  ret
L28:
  mov    %rdi,%rcx
  jmp    L76
L4:
  test   %rdx,%rdx
  je     L3
  jmp    L68
```

assistant: ```c
char *strncatb(char *dest, const char *src, size_t n) {
  char *cptr = dest;
  if (n) {
    while (*cptr) {
      cptr++;
    }
    while ((*src) && (n--)) {
      *cptr++ = *src++;
    }
    if (n) {
      *cptr = *src;
    }
  }
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strncatb>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L62
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rcx
  je     L58
  nopl   0x0(%rax)
L52:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L52
L58:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L31
  sub    $0x1,%rdx
  jmp    L43
L68:
  sub    $0x1,%rdx
  jb     L31
L43:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L68
  test   %rdx,%rdx
  jne    L31
L62:
  ret
L31:
  mov    %r8b,(%rcx)
  ret
```

assistant: ```c
char *strncatb(char *dest, const char *src, size_t n) {
  char *cptr = dest;
  if (n) {
    while (*cptr) {
      cptr++;
    }
    while ((*src) && (n--)) {
      *cptr++ = *src++;
    }
    if (n) {
      *cptr = *src;
    }
  }
  return dest;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strncatb>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L10
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rcx
  je     L46
  nopl   0x0(%rax)
L70:
  add    $0x1,%rcx
  cmpb   $0x0,(%rcx)
  jne    L70
L46:
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  je     L7
  sub    $0x1,%rdx
  jmp    L12
L78:
  sub    $0x1,%rdx
  jb     L7
L12:
  add    $0x1,%rsi
  mov    %r8b,(%rcx)
  add    $0x1,%rcx
  movzbl (%rsi),%r8d
  test   %r8b,%r8b
  jne    L78
  test   %rdx,%rdx
  jne    L7
L10:
  ret
L7:
  mov    %r8b,(%rcx)
  ret
```

assistant: ```c
char *strncatb(char *dest, const char *src, size_t n) {
  char *cptr = dest;
  if (n) {
    while (*cptr) {
      cptr++;
    }
    while ((*src) && (n--)) {
      *cptr++ = *src++;
    }
    if (n) {
      *cptr = *src;
    }
  }
  return dest;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<__i64tostr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L2
  negq   -0x18(%rbp)
  mov    -0x20(%rbp),%rax
  movb   $0x2d,(%rax)
  addq   $0x1,-0x20(%rbp)
  movl   $0x1,-0x4(%rbp)
L2:
  mov    -0x18(%rbp),%rax
  mov    %eax,%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <__u64tostr@plt>
  mov    -0x4(%rbp),%edx
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int __i64tostr(int64_t value, char *nptr, int base) {
  int n = 0;
  if (value < 0) {
    value = -value;
    nptr[0] = '-';
    nptr++;
    n = 1;
  }
  return (n + __u64tostr((uint64_t)value, nptr, base));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__i64tostr>:
  endbr64
  push   %rbx
  mov    $0x0,%ebx
  test   %rdi,%rdi
  js     L13
L14:
  call   <__u64tostr@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
L13:
  neg    %rdi
  movb   $0x2d,(%rsi)
  add    $0x1,%rsi
  mov    $0x1,%ebx
  jmp    L14
```

assistant: ```c
int __i64tostr(int64_t value, char *nptr, int base) {
  int n = 0;
  if (value < 0) {
    value = -value;
    nptr[0] = '-';
    nptr++;
    n = 1;
  }
  return (n + __u64tostr((uint64_t)value, nptr, base));
}
```
user: What is the c source code of the assembly code below?

```asm
<__i64tostr>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  test   %rdi,%rdi
  jns    L6
  movb   $0x2d,(%rsi)
  neg    %rdi
  add    $0x1,%rsi
  mov    $0x1,%ebx
L6:
  call   <__u64tostr@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int __i64tostr(int64_t value, char *nptr, int base) {
  int n = 0;
  if (value < 0) {
    value = -value;
    nptr[0] = '-';
    nptr++;
    n = 1;
  }
  return (n + __u64tostr((uint64_t)value, nptr, base));
}
```
user: Translate the below assembly code into C programming language:

```asm
<__i64tostr>:
  endbr64
  push   %rbx
  xor    %ebx,%ebx
  test   %rdi,%rdi
  jns    L8
  movb   $0x2d,(%rsi)
  neg    %rdi
  add    $0x1,%rsi
  mov    $0x1,%ebx
L8:
  call   <__u64tostr@plt>
  add    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int __i64tostr(int64_t value, char *nptr, int base) {
  int n = 0;
  if (value < 0) {
    value = -value;
    nptr[0] = '-';
    nptr++;
    n = 1;
  }
  return (n + __u64tostr((uint64_t)value, nptr, base));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_min_steps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jne    L53
  mov    $0x0,%eax
  jmp    L64
L53:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  je     L43
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  jmp    L64
L43:
  mov    -0x14(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L74
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L74
  mov    -0x14(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L74:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L66
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L66
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  mov    %edx,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
L66:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x4(%rbp),%eax
L64:
  leave
  ret
```

assistant: ```c
int get_min_steps(int n, int *memo) {
  int res;
  if (n == 1)
    return 0;
  if (memo[n] != -1)
    return memo[n];
  res = 1 + get_min_steps(n - 1, memo);
  if (n % 2 == 0) {
    if (res > (1 + get_min_steps(n / 2, memo)))
      res = 1 + get_min_steps(n / 2, memo);
  }
  if (n % 3 == 0) {
    if (res > (1 + get_min_steps(n / 3, memo)))
      res = 1 + get_min_steps(n / 3, memo);
  }
  memo[n] = res;
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_min_steps>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  cmp    $0x1,%edi
  je     L53
  mov    %edi,%ebx
  mov    %rsi,%r12
  movslq %edi,%rax
  lea    (%rsi,%rax,4),%r13
  mov    0x0(%r13),%ebp
  cmp    $0xffffffff,%ebp
  je     L8
L53:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L8:
  lea    -0x1(%rdi),%edi
  call   <get_min_steps>
  mov    %eax,%r14d
  lea    0x1(%rax),%ebp
  test   $0x1,%bl
  je     L45
L9:
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L35
L33:
  mov    %ebp,0x0(%r13)
  jmp    L53
L45:
  mov    %ebx,%r15d
  shr    $0x1f,%r15d
  add    %ebx,%r15d
  sar    %r15d
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <get_min_steps>
  cmp    %eax,%r14d
  jle    L9
  mov    %r12,%rsi
  mov    %r15d,%edi
  call   <get_min_steps>
  lea    0x1(%rax),%ebp
  jmp    L9
L35:
  movslq %ebx,%r14
  imul   $0x55555556,%r14,%r14
  shr    $0x20,%r14
  sub    %edx,%r14d
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <get_min_steps>
  add    $0x1,%eax
  cmp    %ebp,%eax
  jge    L33
  mov    %r12,%rsi
  mov    %r14d,%edi
  call   <get_min_steps>
  lea    0x1(%rax),%ebp
  jmp    L33
```

assistant: ```c
int get_min_steps(int n, int *memo) {
  int res;
  if (n == 1)
    return 0;
  if (memo[n] != -1)
    return memo[n];
  res = 1 + get_min_steps(n - 1, memo);
  if (n % 2 == 0) {
    if (res > (1 + get_min_steps(n / 2, memo)))
      res = 1 + get_min_steps(n / 2, memo);
  }
  if (n % 3 == 0) {
    if (res > (1 + get_min_steps(n / 3, memo)))
      res = 1 + get_min_steps(n / 3, memo);
  }
  memo[n] = res;
  return res;
}
```