user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r12
  lea    D95(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  lea    D17(%rip),%rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    D176(%rip),%rdi
  call   <puts@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D110(%rip),%rdi
  call   <puts@plt>
  lea    D93(%rip),%rdi
  call   <puts@plt>
  lea    D161(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x6,0x14(%rsp)
  je     L38
  lea    D120(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D113(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  sub    $0x1,%eax
  cmp    $0x4,%eax
  ja     L42
  lea    D50(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D118(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  mov    $0x1,%eax
  cvtsi2ss %edx,%xmm0
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
L42:
  mov    %r12,%rdi
  call   <puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L38:
  lea    D83(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D40(%rip),%rdi
  cltd
  idivl  0x10(%rsp)
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L42
  mov    0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  add    0xc(%rsp),%eax
  lea    D146(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L42
  mov    0xc(%rsp),%eax
  pxor   %xmm0,%xmm0
  sub    0x10(%rsp),%eax
  lea    D26(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L42
  mov    0xc(%rsp),%eax
  imul   0x10(%rsp),%eax
  pxor   %xmm0,%xmm0
  lea    D108(%rip),%rdi
  cvtsi2ss %eax,%xmm0
  mov    $0x1,%eax
  cvtss2sd %xmm0,%xmm0
  call   <printf@plt>
  jmp    L42
L59:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D95
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D176
type: string
name: retrieve_data
arguments: data_tag: D48
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D39
type: string
name: retrieve_data
arguments: data_tag: D110
type: string
name: retrieve_data
arguments: data_tag: D93
type: string
name: retrieve_data
arguments: data_tag: D161
type: string
name: retrieve_data
arguments: data_tag: D120
type: string
name: retrieve_data
arguments: data_tag: D113
type: string
name: retrieve_data
arguments: data_tag: D118
type: string
name: retrieve_data
arguments: data_tag: D83
type: string
name: retrieve_data
arguments: data_tag: D40
type: string
name: retrieve_data
arguments: data_tag: D146
type: string
name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D108
type: string

tool: D95: 
---------------------------------

tool: D17: %d

tool: D176: Please, choose an option of operation: 

tool: D48: * 1 = Addition 

tool: D21: * 2 = Subtraction 

tool: D39: * 3 = Multiplication 

tool: D110: * 4 = Division 

tool: D93: * 5 = MOD 

tool: D161: * 6 = Exit 

tool: D120: Please, insert the number primary: 

tool: D113: 
Please, insert the number secondary: 

tool: D118: Result the mod is: %.2f 


tool: D83: -----BYE----- 

tool: D40: Result division is: %.2f 


tool: D146: Result addition is: %.2f 


tool: D26: Result subtraction is: %.2f 


tool: D108: Result multiplication is: %.2f 


assistant: ```c
int main() {
  int numberPrimary;
  int numberSecondary;
  int option;
  float result;
  printf("\n---------------------------------\n");
  printf("Please, choose an option of operation: \n");
  printf("* 1 = Addition \n");
  printf("* 2 = Subtraction \n");
  printf("* 3 = Multiplication \n");
  printf("* 4 = Division \n");
  printf("* 5 = MOD \n");
  printf("* 6 = Exit \n");
  scanf("%d", &option);
  if (option == 6) {
    printf("-----BYE----- \n");
    exit(0);
  }
  printf("Please, insert the number primary: ");
  scanf("%d", &numberPrimary);
  printf("\nPlease, insert the number secondary: ");
  scanf("%d", &numberSecondary);
  switch (option) {
  case 1:
    result = ((numberPrimary) + (numberSecondary));
    printf("Result addition is: %.2f \n", result);
    break;
  case 2:
    result = ((numberPrimary) - (numberSecondary));
    printf("Result subtraction is: %.2f \n", result);
    break;
  case 3:
    result = ((numberPrimary) * (numberSecondary));
    printf("Result multiplication is: %.2f \n", result);
    break;
  case 4:
    result = ((numberPrimary) / (numberSecondary));
    printf("Result division is: %.2f \n", result);
    break;
  case 5:
    result = (numberPrimary % numberSecondary);
    printf("Result the mod is: %.2f \n", result);
    break;
  }
  printf("\n---------------------------------\n");
}
```