ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<socketListen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <listen@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L1
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L1:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: listen()

assistant: ```c
uint32_t *socketListen(uint32_t context_len, uint32_t *tuple) {
  int sd;
  int n;
  int status;
  sd = (int)unboxUnsigned(unboxTuple(tuple, 0));
  n = (int)unboxUnsigned(unboxTuple(tuple, 1));
  status = listen(sd, n);
  if (-1 == status) {
    perror("listen()");
    exit(1);
  }
  return (uint32_t *)NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<socketListen>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    %rax,%rbx
  mov    $0x1,%esi
  mov    %rbp,%rdi
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L16
L8:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  lea    D9(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D9
datatype: string

tool: D9: listen()

assistant: ```c
uint32_t *socketListen(uint32_t context_len, uint32_t *tuple) {
  int sd;
  int n;
  int status;
  sd = (int)unboxUnsigned(unboxTuple(tuple, 0));
  n = (int)unboxUnsigned(unboxTuple(tuple, 1));
  status = listen(sd, n);
  if (-1 == status) {
    perror("listen()");
    exit(1);
  }
  return (uint32_t *)NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<socketListen>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    %ebx,%edi
  mov    %eax,%esi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L0
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L0:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
data_type: string

tool: D7: listen()

assistant: ```c
uint32_t *socketListen(uint32_t context_len, uint32_t *tuple) {
  int sd;
  int n;
  int status;
  sd = (int)unboxUnsigned(unboxTuple(tuple, 0));
  n = (int)unboxUnsigned(unboxTuple(tuple, 1));
  status = listen(sd, n);
  if (-1 == status) {
    perror("listen()");
    exit(1);
  }
  return (uint32_t *)NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<socketListen>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x8,%rsp
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    $0x1,%esi
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <unboxTuple@plt>
  mov    %eax,%edi
  call   <unboxUnsigned@plt>
  mov    %ebx,%edi
  mov    %eax,%esi
  call   <listen@plt>
  cmp    $0xffffffff,%eax
  je     L3
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L3:
  lea    D7(%rip),%rdi
  call   <perror@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D7
type: string

tool: D7: listen()

assistant: ```c
uint32_t *socketListen(uint32_t context_len, uint32_t *tuple) {
  int sd;
  int n;
  int status;
  sd = (int)unboxUnsigned(unboxTuple(tuple, 0));
  n = (int)unboxUnsigned(unboxTuple(tuple, 1));
  status = listen(sd, n);
  if (-1 == status) {
    perror("listen()");
    exit(1);
  }
  return (uint32_t *)NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x9,-0xc(%rbp)
  movl   $0xa,-0x8(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
data_type: string

tool: D2: 
soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  num1 = 9;
  num2 = 10;
  soma = num1 + num2;
  printf("\nsoma = %d\n", soma);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
datatype: string

tool: D9: 
soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  num1 = 9;
  num2 = 10;
  soma = num1 + num2;
  printf("\nsoma = %d\n", soma);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%esi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D9
type_infered: string

tool: D9: 
soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  num1 = 9;
  num2 = 10;
  soma = num1 + num2;
  printf("\nsoma = %d\n", soma);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x13,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type_guessed: string

tool: D5: 
soma = %d


assistant: ```c
int main() {
  int num1, num2;
  int soma;
  num1 = 9;
  num2 = 10;
  soma = num1 + num2;
  printf("\nsoma = %d\n", soma);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_8_2_t32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L19:
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <print_one_line_t32@plt>
  addl   $0x1,-0x4(%rbp)
L11:
  cmpl   $0x1,-0x4(%rbp)
  jle    L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void print_8_2_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_8_2_t32>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    $0x1,%edx
  mov    $0x0,%esi
  call   <print_one_line_t32@plt>
  mov    $0x1,%edx
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <print_one_line_t32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void print_8_2_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_8_2_t32>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  mov    %edi,%ebp
  xor    %esi,%esi
  call   <print_one_line_t32@plt>
  mov    %ebp,%edi
  mov    $0x1,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <print_one_line_t32@plt>
```

assistant: ```c
void print_8_2_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_8_2_t32>:
  endbr64
  push   %rbp
  mov    $0x1,%edx
  mov    %edi,%ebp
  xor    %esi,%esi
  call   <print_one_line_t32@plt>
  mov    %ebp,%edi
  mov    $0x1,%edx
  xor    %esi,%esi
  pop    %rbp
  jmp    1050 <print_one_line_t32@plt>
```

assistant: ```c
void print_8_2_t32(int k) {
  for (int loop = 0; loop < 2; ++loop) {
    print_one_line_t32(k, 0, 1);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_dobldobl_target_solutions_to_container>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0xff,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_dobldobl_target_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(255, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_dobldobl_target_solutions_to_container>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0xff,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_dobldobl_target_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(255, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<copy_dobldobl_target_solutions_to_container>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xff,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_dobldobl_target_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(255, a, b, c, 0);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copy_dobldobl_target_solutions_to_container>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0xff,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int copy_dobldobl_target_solutions_to_container(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(255, a, b, c, 0);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<printf_std_bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x44,%esi
  mov    $0x3d,%edi
  call   <fill_with_chars@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_guessed: string

tool: D7: 
 

assistant: ```c
void printf_std_bar() {
  printf("\n ");
  fill_with_chars('=', 68);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printf_std_bar>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x44,%esi
  mov    $0x3d,%edi
  call   <fill_with_chars@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_guessed: string

tool: D6: 
 

assistant: ```c
void printf_std_bar() {
  printf("\n ");
  fill_with_chars('=', 68);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<printf_std_bar>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x44,%esi
  mov    $0x3d,%edi
  add    $0x8,%rsp
  jmp    1070 <fill_with_chars@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
type_infered: string

tool: D9: 
 

assistant: ```c
void printf_std_bar() {
  printf("\n ");
  fill_with_chars('=', 68);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printf_std_bar>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x44,%esi
  mov    $0x3d,%edi
  add    $0x8,%rsp
  jmp    1070 <fill_with_chars@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type: string

tool: D5: 
 

assistant: ```c
void printf_std_bar() {
  printf("\n ");
  fill_with_chars('=', 68);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x5,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x1(%rbp)
  cmpb   $0xa,-0x1(%rbp)
  je     L5
  mov    $0x0,%eax
  call   <abort@plt>
L5:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  char c = 5;
  c <<= 1;
  if (c != 10)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  char c = 5;
  c <<= 1;
  if (c != 10)
    abort();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  char c = 5;
  c <<= 1;
  if (c != 10)
    abort();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  char c = 5;
  c <<= 1;
  if (c != 10)
    abort();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<flexram_wait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
L0:
  mov    $0x40020001,%eax
  mov    (%rax),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void flexram_wait(void) {
  while (!(*(volatile uint8_t *)0x40020001 & (uint8_t)0x01)) {
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<flexram_wait>:
  endbr64
L6:
  mov    0x40020001,%eax
  test   $0x1,%al
  je     L6
  ret
```

assistant: ```c
void flexram_wait(void) {
  while (!(*(volatile uint8_t *)0x40020001 & (uint8_t)0x01)) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flexram_wait>:
  endbr64
  nopl   0x0(%rax)
L5:
  mov    0x40020001,%eax
  test   $0x1,%al
  je     L5
  ret
```

assistant: ```c
void flexram_wait(void) {
  while (!(*(volatile uint8_t *)0x40020001 & (uint8_t)0x01)) {
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<flexram_wait>:
  endbr64
  nopl   0x0(%rax)
L1:
  mov    0x40020001,%eax
  test   $0x1,%al
  je     L1
  ret
```

assistant: ```c
void flexram_wait(void) {
  while (!(*(volatile uint8_t *)0x40020001 & (uint8_t)0x01)) {
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<send_response>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <send_status@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%esi
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rcx
  mov    %esi,%edx
  lea    D2(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  jns    L6
  mov    $0xffffffff,%edi
  call   <exit@plt>
L6:
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
datatype: string

tool: D2: Connection: close
Content-Length: %ld
Content-Type: text/plain

%s

assistant: ```c
void send_response(FILE *client, int code, const char *reason_phrase, const char *message_body) {
  send_status(client, code, reason_phrase);
  if (fprintf(client, "Connection: close\r\nContent-Length: %ld\r\nContent-Type: text/plain\r\n\r\n%s", strlen(message_body), message_body) < 0)
    exit(-1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_response>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rcx,%rbp
  call   <send_status@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rcx
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <fprintf@plt>
  test   %rax,%rax
  js     L6
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: retrieve_data
arguments: label: D6
data_type: string

tool: D6: Connection: close
Content-Length: %ld
Content-Type: text/plain

%s

assistant: ```c
void send_response(FILE *client, int code, const char *reason_phrase, const char *message_body) {
  send_status(client, code, reason_phrase);
  if (fprintf(client, "Connection: close\r\nContent-Length: %ld\r\nContent-Type: text/plain\r\n\r\n%s", strlen(message_body), message_body) < 0)
    exit(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<send_response>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <send_status@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rcx
  lea    D0(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <fprintf@plt>
  test   %rax,%rax
  js     L7
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L7:
  add    $0x8,%rsp
  mov    $0xffffffff,%edi
  pop    %rbp
  pop    %r12
  jmp    10b0 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D0
type: string

tool: D0: Connection: close
Content-Length: %ld
Content-Type: text/plain

%s

assistant: ```c
void send_response(FILE *client, int code, const char *reason_phrase, const char *message_body) {
  send_status(client, code, reason_phrase);
  if (fprintf(client, "Connection: close\r\nContent-Length: %ld\r\nContent-Type: text/plain\r\n\r\n%s", strlen(message_body), message_body) < 0)
    exit(-1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<send_response>:
  endbr64
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <send_status@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rcx
  lea    D2(%rip),%rsi
  mov    %rbp,%rdi
  mov    %eax,%edx
  call   <fprintf@plt>
  test   %rax,%rax
  js     L0
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nop
L0:
  add    $0x8,%rsp
  mov    $0xffffffff,%edi
  pop    %rbp
  pop    %r12
  jmp    10b0 <exit@plt>
```

tool_calls: name: read_data
arguments: label: D2
data_type: string

tool: D2: Connection: close
Content-Length: %ld
Content-Type: text/plain

%s

assistant: ```c
void send_response(FILE *client, int code, const char *reason_phrase, const char *message_body) {
  send_status(client, code, reason_phrase);
  if (fprintf(client, "Connection: close\r\nContent-Length: %ld\r\nContent-Type: text/plain\r\n\r\n%s", strlen(message_body), message_body) < 0)
    exit(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getCommandExecutableName>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jg     L17
  subq   $0x1,-0x10(%rbp)
  jmp    L8
L17:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L42
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L19
L42:
  addq   $0x1,-0x10(%rbp)
L19:
  jmp    L1
L8:
  mov    -0x10(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *getCommandExecutableName(char *commandline) {
  char *nameStart;
  char *nameEnd;
  char *name;
  int length;
  nameStart = commandline;
  nameEnd = commandline;
  for (;;) {
    if (nameEnd[0] <= 32) {
      nameEnd--;
      break;
    }
    if (nameEnd[0] == '/') {
      nameEnd = nameEnd + 1;
      nameStart = nameEnd;
      continue;
    }
    nameEnd = nameEnd + 1;
  }
  length = (nameEnd - nameStart) + 1;
  name = (char *)malloc((size_t)(length + 1));
  memcpy(name, nameStart, (size_t)length);
  name[length] = '\0';
  return name;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getCommandExecutableName>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edx
  mov    %rdi,%rcx
  cmp    $0x20,%dl
  jle    L3
  lea    0x1(%rdi),%rax
L2:
  cmp    $0x2f,%dl
  cmove  %rax,%rbx
  mov    %rax,%rcx
  movzbl (%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  jg     L2
L3:
  lea    -0x1(%rcx),%rbp
  sub    %rbx,%rbp
  lea    0x2(%rbp),%edi
  movslq %edi,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  add    $0x1,%ebp
  movslq %ebp,%rbp
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbp,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getCommandExecutableName(char *commandline) {
  char *nameStart;
  char *nameEnd;
  char *name;
  int length;
  nameStart = commandline;
  nameEnd = commandline;
  for (;;) {
    if (nameEnd[0] <= 32) {
      nameEnd--;
      break;
    }
    if (nameEnd[0] == '/') {
      nameEnd = nameEnd + 1;
      nameStart = nameEnd;
      continue;
    }
    nameEnd = nameEnd + 1;
  }
  length = (nameEnd - nameStart) + 1;
  name = (char *)malloc((size_t)(length + 1));
  memcpy(name, nameStart, (size_t)length);
  name[length] = '\0';
  return name;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getCommandExecutableName>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jle    L18
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  movzbl (%rdi),%eax
  cmove  %rdi,%rbp
  cmp    $0x20,%al
  jg     L7
L18:
  lea    -0x1(%rdi),%rbx
  sub    %rbp,%rbx
  lea    0x2(%rbx),%edi
  add    $0x1,%ebx
  movslq %edi,%rdi
  movslq %ebx,%rbx
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getCommandExecutableName(char *commandline) {
  char *nameStart;
  char *nameEnd;
  char *name;
  int length;
  nameStart = commandline;
  nameEnd = commandline;
  for (;;) {
    if (nameEnd[0] <= 32) {
      nameEnd--;
      break;
    }
    if (nameEnd[0] == '/') {
      nameEnd = nameEnd + 1;
      nameStart = nameEnd;
      continue;
    }
    nameEnd = nameEnd + 1;
  }
  length = (nameEnd - nameStart) + 1;
  name = (char *)malloc((size_t)(length + 1));
  memcpy(name, nameStart, (size_t)length);
  name[length] = '\0';
  return name;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<getCommandExecutableName>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movzbl (%rdi),%eax
  cmp    $0x20,%al
  jle    L4
  nopw   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rdi
  cmp    $0x2f,%al
  movzbl (%rdi),%eax
  cmove  %rdi,%rbp
  cmp    $0x20,%al
  jg     L12
L4:
  lea    -0x1(%rdi),%rbx
  sub    %rbp,%rbx
  lea    0x2(%rbx),%edi
  add    $0x1,%ebx
  movslq %edi,%rdi
  movslq %ebx,%rbx
  call   <malloc@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *getCommandExecutableName(char *commandline) {
  char *nameStart;
  char *nameEnd;
  char *name;
  int length;
  nameStart = commandline;
  nameEnd = commandline;
  for (;;) {
    if (nameEnd[0] <= 32) {
      nameEnd--;
      break;
    }
    if (nameEnd[0] == '/') {
      nameEnd = nameEnd + 1;
      nameStart = nameEnd;
      continue;
    }
    nameEnd = nameEnd + 1;
  }
  length = (nameEnd - nameStart) + 1;
  name = (char *)malloc((size_t)(length + 1));
  memcpy(name, nameStart, (size_t)length);
  name[length] = '\0';
  return name;
}
```