ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<l2Norm>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  subsd  %xmm1,%xmm0
  movq   D4(%rip),%xmm1
  andpd  %xmm0,%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm2
  subsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  cltd
  idivl  -0x24(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D4
data_type: qword

tool: D4: 9223372036854775807

assistant: ```c
double l2Norm(double *v1, double *v2, int size) {
  double myl2 = 0.;
#pragma omp parallel for reduction(+ : myl2)
  for (int ii = 0; ii < size; ++ii) {
    myl2 += fabs(v1[ii] - v2[ii]) * (v1[ii] - v2[ii]);
  }
  return sqrt(myl2) / size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<l2Norm>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  jle    L10
  mov    %edx,%edx
  mov    $0x0,%eax
  pxor   %xmm2,%xmm2
  movq   D0(%rip),%xmm3
L6:
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  movapd %xmm0,%xmm1
  andpd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L6
L11:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  cltd
  idiv   %ebx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  pop    %rbx
  ret
L10:
  pxor   %xmm2,%xmm2
  jmp    L11
```

tool_calls: name: read_data
arguments: data_label: D0
type: qword

tool: D0: 9223372036854775807

assistant: ```c
double l2Norm(double *v1, double *v2, int size) {
  double myl2 = 0.;
#pragma omp parallel for reduction(+ : myl2)
  for (int ii = 0; ii < size; ++ii) {
    myl2 += fabs(v1[ii] - v2[ii]) * (v1[ii] - v2[ii]);
  }
  return sqrt(myl2) / size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<l2Norm>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  jle    L19
  movq   D8(%rip),%xmm3
  movslq %edx,%rcx
  xor    %eax,%eax
  pxor   %xmm2,%xmm2
  nopl   0x0(%rax)
L5:
  movsd  (%rdi,%rax,8),%xmm0
  subsd  (%rsi,%rax,8),%xmm0
  add    $0x1,%rax
  movapd %xmm0,%xmm1
  andpd  %xmm3,%xmm1
  mulsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm2
  cmp    %rax,%rcx
  jne    L5
L29:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
  nopl   0x0(%rax)
L19:
  pxor   %xmm2,%xmm2
  jmp    L29
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: qword

tool: D8: 9223372036854775807

assistant: ```c
double l2Norm(double *v1, double *v2, int size) {
  double myl2 = 0.;
#pragma omp parallel for reduction(+ : myl2)
  for (int ii = 0; ii < size; ++ii) {
    myl2 += fabs(v1[ii] - v2[ii]) * (v1[ii] - v2[ii]);
  }
  return sqrt(myl2) / size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<l2Norm>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  test   %edx,%edx
  jle    L1
  cmp    $0x1,%edx
  je     L19
  shr    %edx
  movapd D13(%rip),%xmm3
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L15:
  movupd (%rdi,%rax,1),%xmm2
  movupd (%rsi,%rax,1),%xmm4
  add    $0x10,%rax
  subpd  %xmm4,%xmm2
  movapd %xmm2,%xmm1
  andpd  %xmm3,%xmm1
  mulpd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  unpckhpd %xmm1,%xmm1
  addsd  %xmm1,%xmm0
  cmp    %rax,%rdx
  jne    L15
  mov    %ebx,%eax
  and    $0xfffffffe,%eax
  test   $0x1,%bl
  je     L36
L45:
  cltq
  movsd  (%rdi,%rax,8),%xmm1
  subsd  (%rsi,%rax,8),%xmm1
  movapd %xmm1,%xmm2
  andpd  D19(%rip),%xmm2
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
L36:
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  pxor   %xmm0,%xmm0
  call   <sqrt@plt>
  pxor   %xmm0,%xmm0
  cltd
  idiv   %ebx
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
L19:
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  jmp    L45
```

tool_calls: name: unpack_data
arguments: tag: D13
type_guessed: qword[2]
name: unpack_data
arguments: tag: D19
type_guessed: qword[2]

tool: {"D13": [0x7fffffffffffffff,0x7fffffffffffffff]}

tool: {"D19": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double l2Norm(double *v1, double *v2, int size) {
  double myl2 = 0.;
#pragma omp parallel for reduction(+ : myl2)
  for (int ii = 0; ii < size; ++ii) {
    myl2 += fabs(v1[ii] - v2[ii]) * (v1[ii] - v2[ii]);
  }
  return sqrt(myl2) / size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<showarray_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L13:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0x6,-0x4(%rbp)
  jle    L13
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type: string
name: disassemble_data
arguments: tag: D14
type: string

tool: D8: The first 7 primes numbers are: 

tool: D14: %d, 

assistant: ```c
void showarray_1(int array[]) {
  int x;
  printf("The first 7 primes numbers are: ");
  for (x = 0; x < 7; x++)
    printf("%d, ", array[x]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<showarray_1>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rbx
  add    $0x1c,%rbp
  lea    D5(%rip),%r12
L5:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L5
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D7
datatype: string
name: parse_data
arguments: label: D5
datatype: string

tool: D7: The first 7 primes numbers are: 

tool: D5: %d, 

assistant: ```c
void showarray_1(int array[]) {
  int x;
  printf("The first 7 primes numbers are: ");
  for (x = 0; x < 7; x++)
    printf("%d, ", array[x]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<showarray_1>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D0(%rip),%rdi
  lea    0x1c(%rbx),%r12
  call   <printf@plt>
  nopl   0x0(%rax)
L8:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type_infered: string
name: retrieve_data
arguments: tag: D0
type_infered: string

tool: D6: %d, 

tool: D0: The first 7 primes numbers are: 

assistant: ```c
void showarray_1(int array[]) {
  int x;
  printf("The first 7 primes numbers are: ");
  for (x = 0; x < 7; x++)
    printf("%d, ", array[x]);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<showarray_1>:
  endbr64
  push   %r12
  xor    %eax,%eax
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  lea    D15(%rip),%rdi
  lea    0x1c(%rbx),%r12
  call   <printf@plt>
  nopl   0x0(%rax)
L0:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D15
type_infered: string

tool: D16: %d, 

tool: D15: The first 7 primes numbers are: 

assistant: ```c
void showarray_1(int array[]) {
  int x;
  printf("The first 7 primes numbers are: ");
  for (x = 0; x < 7; x++)
    printf("%d, ", array[x]);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%esi
  lea    D70(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D31(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D19(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D31
type_guessed: string
name: unpack_data
arguments: data_tag: D19
type_guessed: string
name: unpack_data
arguments: data_tag: D70
type_guessed: string
name: unpack_data
arguments: data_tag: D2
type_guessed: string
name: unpack_data
arguments: data_tag: D29
type_guessed: string

tool: D31: abcd

tool: D19: abc

tool: D70: abc - abcd %d


tool: D2: abcd -abcd %d


tool: D29: abcd - abc %d


assistant: ```c
int main() {
  printf("abc - abcd %d\n", my_strcmp("abc", "abcd"));
  printf("abcd -abcd %d\n", my_strcmp("abcd", "abcd"));
  printf("abcd - abc %d\n", my_strcmp("abcd", "abc"));
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D18(%rip),%rbx
  mov    %rbx,%rsi
  lea    D42(%rip),%rbp
  mov    %rbp,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbx,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%esi
  lea    D34(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <my_strcmp@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D18
type_infered: string
name: read_data
arguments: data_tag: D42
type_infered: string
name: read_data
arguments: data_tag: D8
type_infered: string
name: read_data
arguments: data_tag: D34
type_infered: string
name: read_data
arguments: data_tag: D2
type_infered: string

tool: D18: abcd

tool: D42: abc

tool: D8: abc - abcd %d


tool: D34: abcd -abcd %d


tool: D2: abcd - abc %d


assistant: ```c
int main() {
  printf("abc - abcd %d\n", my_strcmp("abc", "abcd"));
  printf("abcd -abcd %d\n", my_strcmp("abcd", "abcd"));
  printf("abcd - abc %d\n", my_strcmp("abcd", "abc"));
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D0(%rip),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <my_strcmp@plt>
  lea    D49(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <my_strcmp@plt>
  lea    D32(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <my_strcmp@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: read_data
arguments: data_tag: D28
datatype: string
name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D49
datatype: string
name: read_data
arguments: data_tag: D32
datatype: string
name: read_data
arguments: data_tag: D9
datatype: string

tool: D28: abc

tool: D0: abcd

tool: D49: abc - abcd %d


tool: D32: abcd -abcd %d


tool: D9: abcd - abc %d


assistant: ```c
int main() {
  printf("abc - abcd %d\n", my_strcmp("abc", "abcd"));
  printf("abcd -abcd %d\n", my_strcmp("abcd", "abcd"));
  printf("abcd - abc %d\n", my_strcmp("abcd", "abc"));
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D25(%rip),%r12
  push   %rbp
  lea    D31(%rip),%rbp
  mov    %r12,%rdi
  mov    %rbp,%rsi
  sub    $0x8,%rsp
  call   <my_strcmp@plt>
  lea    D44(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %rbp,%rdi
  call   <my_strcmp@plt>
  lea    D42(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <my_strcmp@plt>
  lea    D29(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
type: string
name: disassemble_data
arguments: label: D31
type: string
name: disassemble_data
arguments: label: D44
type: string
name: disassemble_data
arguments: label: D42
type: string
name: disassemble_data
arguments: label: D29
type: string

tool: D25: abc

tool: D31: abcd

tool: D44: abc - abcd %d


tool: D42: abcd -abcd %d


tool: D29: abcd - abc %d


assistant: ```c
int main() {
  printf("abc - abcd %d\n", my_strcmp("abc", "abcd"));
  printf("abcd -abcd %d\n", my_strcmp("abcd", "abcd"));
  printf("abcd - abc %d\n", my_strcmp("abcd", "abc"));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<C_Ret>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x100,%edx
  lea    D39(%rip),%rax
  mov    %rax,%rsi
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    D4(%rip),%rax
  mov    %rax,%rsi
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    D42(%rip),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D39
type_infered: string
name: extract_symbolic_data
arguments: tag: D31
type_infered: string
name: extract_symbolic_data
arguments: tag: D4
type_infered: string
name: extract_symbolic_data
arguments: tag: D32
type_infered: string
name: extract_symbolic_data
arguments: tag: D42
type_infered: string
name: extract_symbolic_data
arguments: tag: D10
type_infered: string

tool: D39: $%d,%%rsp

tool: D31: addq

tool: D4: %%rbx

tool: D32: popq

tool: 

tool: D10: ret

assistant: ```c
void C_Ret(void) {
  Inst_Printf("addq", "$%d,%%rsp", 32 * 8);
  Inst_Printf("popq", "%%rbx");
  Inst_Printf("ret", "");
}
```
user: What is the c source code of the assembly code below:

```asm
<C_Ret>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x100,%edx
  lea    D26(%rip),%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    D34(%rip),%rsi
  lea    D56(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  lea    D27(%rip),%rsi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <Inst_Printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D26
type_guessed: string
name: parse_data
arguments: label: D12
type_guessed: string
name: parse_data
arguments: label: D34
type_guessed: string
name: parse_data
arguments: label: D56
type_guessed: string
name: parse_data
arguments: label: D27
type_guessed: string
name: parse_data
arguments: label: D13
type_guessed: string

tool: D26: $%d,%%rsp

tool: D12: addq

tool: D34: %%rbx

tool: D56: popq

tool: 

tool: D13: ret

assistant: ```c
void C_Ret(void) {
  Inst_Printf("addq", "$%d,%%rsp", 32 * 8);
  Inst_Printf("popq", "%%rbx");
  Inst_Printf("ret", "");
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<C_Ret>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x100,%edx
  lea    D1(%rip),%rsi
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D8(%rip),%rsi
  lea    D52(%rip),%rdi
  xor    %eax,%eax
  call   <Inst_Printf@plt>
  lea    D38(%rip),%rsi
  xor    %eax,%eax
  add    $0x8,%rsp
  lea    D18(%rip),%rdi
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D1
datatype: string
name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D8
datatype: string
name: extract_symbolic_data
arguments: label: D52
datatype: string
name: extract_symbolic_data
arguments: label: D38
datatype: string
name: extract_symbolic_data
arguments: label: D18
datatype: string

tool: D1: $%d,%%rsp

tool: D21: addq

tool: D8: %%rbx

tool: D52: popq

tool: 

tool: D18: ret

assistant: ```c
void C_Ret(void) {
  Inst_Printf("addq", "$%d,%%rsp", 32 * 8);
  Inst_Printf("popq", "%%rbx");
  Inst_Printf("ret", "");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<C_Ret>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x100,%edx
  lea    D47(%rip),%rsi
  xor    %eax,%eax
  lea    D52(%rip),%rdi
  call   <Inst_Printf@plt>
  lea    D36(%rip),%rsi
  lea    D20(%rip),%rdi
  xor    %eax,%eax
  call   <Inst_Printf@plt>
  lea    D29(%rip),%rsi
  xor    %eax,%eax
  add    $0x8,%rsp
  lea    D44(%rip),%rdi
  jmp    1050 <Inst_Printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D47
data_type: string
name: parse_data
arguments: data_label: D52
data_type: string
name: parse_data
arguments: data_label: D36
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D29
data_type: string
name: parse_data
arguments: data_label: D44
data_type: string

tool: D47: $%d,%%rsp

tool: D52: addq

tool: D36: %%rbx

tool: D20: popq

tool: 

tool: D44: ret

assistant: ```c
void C_Ret(void) {
  Inst_Printf("addq", "$%d,%%rsp", 32 * 8);
  Inst_Printf("popq", "%%rbx");
  Inst_Printf("ret", "");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %rdi,%rax
  mov    %rax,%rbx
  nop
L2:
  mov    %rax,%rdx
  lea    0x1(%rdx),%rax
  movzbl (%rdx),%edx
  test   %dl,%dl
  jne    L2
  sub    $0x1,%rax
  sub    %rbx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int strlen(string)
register char *string;
{
  register char *ret = string;
  while (*string++)
    ;
  return string - 1 - ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
L8:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L8
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlen(string)
register char *string;
{
  register char *ret = string;
  while (*string++)
    ;
  return string - 1 - ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L9
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlen(string)
register char *string;
{
  register char *ret = string;
  while (*string++)
    ;
  return string - 1 - ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen>:
  endbr64
  mov    %rdi,%rdx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rdx,%rax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L6
  sub    %edi,%eax
  ret
```

assistant: ```c
int strlen(string)
register char *string;
{
  register char *ret = string;
  while (*string++)
    ;
  return string - 1 - ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  jmp    L22
L12:
  mov    -0x28(%rbp),%rax
  mov    %eax,%edi
  call   <factorial@plt>
  imul   -0x30(%rbp),%eax
  mov    %eax,%ebx
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edi
  call   <factorial@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cltq
  add    %rax,-0x20(%rbp)
  negl   -0x30(%rbp)
  addl   $0x1,-0x2c(%rbp)
L22:
  mov    -0x2c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jle    L12
  mov    -0x28(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D19
type_guessed: string
name: unpack_data
arguments: tag: D15
type_guessed: string
name: unpack_data
arguments: tag: D13
type_guessed: string

tool: D19: Enter a Natural number

tool: D15: %lli

tool: D13: Number of derangements possible for %lli are %lli


assistant: ```c
int main() {
  long long int n, sum = 0;
  printf("Enter a Natural number\n");
  scanf("%lli", &n);
  int sign = 1;
  for (int i = 2; i <= n; i++) {
    sum = sum + (sign * factorial(n) / factorial(i));
    sign = -sign;
  }
  printf("Number of derangements possible for %lli are %lli\n", n, sum);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D18(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  cmp    $0x1,%rdi
  jle    L13
  mov    $0x0,%ebp
  mov    $0x1,%r12d
  mov    $0x0,%r13d
L36:
  call   <factorial@plt>
  imul   %r12d,%eax
  mov    %eax,%ebx
  lea    0x2(%rbp),%edi
  call   <factorial@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  cltq
  add    %rax,%r13
  neg    %r12d
  mov    (%rsp),%rdi
  mov    %rbp,%rax
  add    $0x1,%rbp
  add    $0x3,%rax
  cmp    %rax,%rdi
  jge    L36
L15:
  mov    %r13,%rdx
  mov    %rdi,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L13:
  mov    $0x0,%r13d
  jmp    L15
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D18
data_type: string
name: extract_symbolic_data
arguments: label: D7
data_type: string
name: extract_symbolic_data
arguments: label: D26
data_type: string

tool: D18: Enter a Natural number

tool: D7: %lli

tool: D26: Number of derangements possible for %lli are %lli


assistant: ```c
int main() {
  long long int n, sum = 0;
  printf("Enter a Natural number\n");
  scanf("%lli", &n);
  int sign = 1;
  for (int i = 2; i <= n; i++) {
    sum = sum + (sign * factorial(n) / factorial(i));
    sign = -sign;
  }
  printf("Number of derangements possible for %lli are %lli\n", n, sum);
  return (0);
}
```