ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L23
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L57
L23:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jne    L7
  mov    $0x31,%edi
  call   <putchar@plt>
  jmp    L109
L81:
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
L109:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  jne    L81
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  jmp    L57
L7:
  mov    -0x14(%rbp),%eax
  mov    -0x10(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L83
L80:
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
L83:
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x10(%rbp)
  test   %eax,%eax
  jne    L80
  jmp    L5
L79:
  mov    $0x30,%edi
  call   <putchar@plt>
L5:
  mov    -0xc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0xc(%rbp)
  test   %eax,%eax
  jne    L79
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
L57:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type_infered: string
name: parse_data
arguments: tag: D13
type_infered: string

tool: D1: %d%d

tool: D13: NO


assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  if (m > (n + 1)) {
    printf("NO\n");
    return 0;
  }
  if (m == (n + 1)) {
    putchar('1');
    while (--m) {
      putchar('0');
      putchar('1');
    }
    putchar('\n');
    return 0;
  }
  int nz = n - m;
  while (m--) {
    putchar('0');
    putchar('1');
  }
  while (nz--) {
    putchar('0');
  }
  putchar('\n');
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  lea    0x1(%rbx),%edx
  mov    0x4(%rsp),%eax
  cmp    %eax,%edx
  jl     L22
  je     L106
  sub    %eax,%ebx
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L18
L59:
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L59
L18:
  test   %ebx,%ebx
  je     L85
L23:
  mov    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L23
L85:
  mov    $0xa,%edi
  call   <putchar@plt>
L19:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L22:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L19
L106:
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  je     L0
L95:
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0x4(%rsp)
  jne    L95
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  jmp    L19
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
data_type: string
name: read_data
arguments: label: D5
data_type: string

tool: D4: %d%d

tool: D5: NO


assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  if (m > (n + 1)) {
    printf("NO\n");
    return 0;
  }
  if (m == (n + 1)) {
    putchar('1');
    while (--m) {
      putchar('0');
      putchar('1');
    }
    putchar('\n');
    return 0;
  }
  int nz = n - m;
  while (m--) {
    putchar('0');
    putchar('1');
  }
  while (nz--) {
    putchar('0');
  }
  putchar('\n');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D17(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%eax
  lea    0x1(%rbx),%edx
  cmp    %eax,%edx
  jl     L9
  je     L14
  lea    -0x1(%rax),%edx
  sub    %eax,%ebx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L34
  nopw   0x0(%rax,%rax,1)
L76:
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L76
L34:
  test   %ebx,%ebx
  je     L15
  nop
L27:
  mov    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L27
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
L63:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L24:
  mov    $0x30,%edi
  call   <putchar@plt>
L14:
  mov    $0x31,%edi
  call   <putchar@plt>
  subl   $0x1,0x4(%rsp)
  jne    L24
  jmp    L15
L9:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L63
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D17
type_guessed: string
name: unpack_data
arguments: tag: D3
type_guessed: string

tool: D17: %d%d

tool: D3: NO


assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  if (m > (n + 1)) {
    printf("NO\n");
    return 0;
  }
  if (m == (n + 1)) {
    putchar('1');
    while (--m) {
      putchar('0');
      putchar('1');
    }
    putchar('\n');
    return 0;
  }
  int nz = n - m;
  while (m--) {
    putchar('0');
    putchar('1');
  }
  while (nz--) {
    putchar('0');
  }
  putchar('\n');
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  lea    D7(%rip),%rdi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  call   <scanf@plt>
  mov    (%rsp),%ebx
  mov    0x4(%rsp),%eax
  lea    0x1(%rbx),%edx
  cmp    %eax,%edx
  jl     L77
  je     L93
  lea    -0x1(%rax),%edx
  sub    %eax,%ebx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  je     L3
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x31,%edi
  call   <putchar@plt>
  mov    0x4(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x4(%rsp)
  test   %eax,%eax
  jne    L5
L3:
  test   %ebx,%ebx
  je     L31
  nop
L57:
  mov    $0x30,%edi
  call   <putchar@plt>
  sub    $0x1,%ebx
  jne    L57
L31:
  mov    $0xa,%edi
  call   <putchar@plt>
L58:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L74
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L50:
  mov    $0x30,%edi
  call   <putchar@plt>
L93:
  mov    $0x31,%edi
  call   <putchar@plt>
  subl   $0x1,0x4(%rsp)
  jne    L50
  jmp    L31
L77:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L58
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type: string
name: retrieve_data
arguments: label: D2
type: string

tool: D7: %d%d

tool: D2: NO


assistant: ```c
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  if (m > (n + 1)) {
    printf("NO\n");
    return 0;
  }
  if (m == (n + 1)) {
    putchar('1');
    while (--m) {
      putchar('0');
      putchar('1');
    }
    putchar('\n');
    return 0;
  }
  int nz = n - m;
  while (m--) {
    putchar('0');
    putchar('1');
  }
  while (nz--) {
    putchar('0');
  }
  putchar('\n');
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GetCode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L31
  movl   $0x0,D18(%rip)
  movl   $0x0,D33(%rip)
  movl   $0x0,D192(%rip)
  mov    $0x0,%eax
  jmp    L41
L31:
  mov    D18(%rip),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    D33(%rip),%eax
  cmp    %eax,%edx
  jl     L39
  mov    D192(%rip),%eax
  test   %eax,%eax
  je     L71
  mov    $0xffffffff,%eax
  jmp    L41
L71:
  mov    D97(%rip),%eax
  sub    $0x2,%eax
  cltq
  lea    D39(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,D11(%rip)
  mov    D97(%rip),%eax
  sub    $0x1,%eax
  cltq
  lea    D11(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,D11(%rip)
  mov    -0x18(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <GetDataBlock@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L0
  movl   $0x1,D192(%rip)
L0:
  movzbl -0xd(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,D101(%rip)
  mov    D18(%rip),%eax
  mov    D33(%rip),%edx
  sub    %edx,%eax
  add    $0x10,%eax
  mov    %eax,D101(%rip)
  movzbl -0xd(%rbp),%eax
  add    $0x2,%eax
  shl    $0x3,%eax
  mov    %eax,D101(%rip)
L39:
  movl   $0x0,-0x4(%rbp)
  mov    D101(%rip),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L26:
  mov    -0xc(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  lea    D11(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  mov    D101(%rip),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D101(%rip)
  mov    -0x4(%rbp),%eax
L41:
  leave
  ret
```

assistant: ```c
int GetCode(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetCode>:
  endbr64
  test   %edx,%edx
  jne    L17
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %esi,%eax
  add    D171(%rip),%eax
  cmp    D79(%rip),%eax
  jl     L55
  cmpl   $0x0,D125(%rip)
  jne    L54
  mov    D61(%rip),%eax
  lea    D34(%rip),%rcx
  lea    -0x2(%rax),%edx
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,D124(%rip)
  sub    $0x1,%eax
  cltq
  movzbl (%rcx,%rax,1),%eax
  mov    %al,D124(%rip)
  lea    0x2(%rcx),%rsi
  call   <GetDataBlock@plt>
  test   %al,%al
  jne    L62
  movl   $0x1,D125(%rip)
L62:
  movzbl %al,%eax
  add    $0x2,%eax
  mov    %eax,D183(%rip)
  mov    D171(%rip),%edx
  sub    D79(%rip),%edx
  add    $0x10,%edx
  mov    %edx,D183(%rip)
  shl    $0x3,%eax
  mov    %eax,D183(%rip)
L55:
  mov    D183(%rip),%esi
  test   %ebp,%ebp
  jle    L38
  mov    %ebx,%edx
  lea    D124(%rip),%rdi
L33:
  lea    (%rbx,%rsi,1),%ecx
  lea    0x7(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x3,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L33
L5:
  add    %esi,%ebp
  mov    %ebp,D183(%rip)
L68:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  movl   $0x0,D183(%rip)
  movl   $0x0,D183(%rip)
  movl   $0x0,D125(%rip)
  mov    $0x0,%edx
  mov    %edx,%eax
  ret
L38:
  mov    %ebx,%edx
  jmp    L5
L54:
  mov    $0xffffffff,%edx
  jmp    L68
```

assistant: ```c
int GetCode(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetCode>:
  endbr64
  test   %edx,%edx
  jne    L44
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D105(%rip),%esi
  lea    (%rsi,%rbx,1),%r8d
  cmp    D107(%rip),%r8d
  jge    L48
L47:
  test   %ebx,%ebx
  jle    L41
  xor    %edx,%edx
  lea    D165(%rip),%rdi
  cs nopw 0x0(%rax,%rax,1)
L21:
  lea    (%rdx,%rsi,1),%ecx
  test   %ecx,%ecx
  lea    0x7(%rcx),%eax
  cmovns %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  and    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%ebp
  cmp    %edx,%ebx
  jne    L21
L41:
  mov    %r8d,D130(%rip)
  mov    %ebp,%eax
L38:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    D130(%rip),%eax
  test   %eax,%eax
  jne    L72
  mov    D20(%rip),%eax
  mov    %rdi,%r9
  lea    D165(%rip),%rdi
  lea    0x2(%rdi),%rsi
  lea    -0x2(%rax),%edx
  sub    $0x1,%eax
  movslq %edx,%rdx
  cltq
  movzbl (%rdi,%rdx,1),%edx
  mov    %dl,D7(%rip)
  movzbl (%rdi,%rax,1),%eax
  mov    %r9,%rdi
  mov    %al,D7(%rip)
  call   <GetDataBlock@plt>
  test   %al,%al
  jne    L16
  movl   $0x1,D130(%rip)
L16:
  movzbl %al,%eax
  mov    D130(%rip),%esi
  sub    D107(%rip),%esi
  add    $0x2,%eax
  add    $0x10,%esi
  mov    %eax,D122(%rip)
  shl    $0x3,%eax
  lea    (%rsi,%rbx,1),%r8d
  mov    %eax,D122(%rip)
  jmp    L47
  nopl   0x0(%rax)
L44:
  movl   $0x0,D130(%rip)
  xor    %eax,%eax
  movl   $0x0,D122(%rip)
  movl   $0x0,D130(%rip)
  ret
L72:
  mov    $0xffffffff,%eax
  jmp    L38
```

assistant: ```c
int GetCode(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<GetCode>:
  endbr64
  test   %edx,%edx
  jne    L35
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D130(%rip),%esi
  lea    (%rsi,%rbx,1),%r8d
  cmp    D107(%rip),%r8d
  jge    L72
L59:
  test   %ebx,%ebx
  jle    L15
  xor    %edx,%edx
  lea    D86(%rip),%rdi
  cs nopw 0x0(%rax,%rax,1)
L34:
  lea    (%rsi,%rdx,1),%ecx
  test   %ecx,%ecx
  lea    0x7(%rcx),%eax
  cmovns %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  and    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%ebp
  cmp    %edx,%ebx
  jne    L34
L15:
  mov    %r8d,D152(%rip)
  mov    %ebp,%eax
L6:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L72:
  mov    D152(%rip),%eax
  test   %eax,%eax
  jne    L53
  mov    D17(%rip),%eax
  mov    %rdi,%r9
  lea    D86(%rip),%rdi
  lea    0x2(%rdi),%rsi
  lea    -0x2(%rax),%edx
  sub    $0x1,%eax
  movslq %edx,%rdx
  cltq
  movzbl (%rdi,%rdx,1),%edx
  mov    %dl,D73(%rip)
  movzbl (%rdi,%rax,1),%eax
  mov    %r9,%rdi
  mov    %al,D73(%rip)
  call   <GetDataBlock@plt>
  test   %al,%al
  jne    L7
  movl   $0x1,D152(%rip)
L7:
  movzbl %al,%eax
  mov    D152(%rip),%esi
  sub    D107(%rip),%esi
  add    $0x2,%eax
  add    $0x10,%esi
  mov    %eax,D40(%rip)
  shl    $0x3,%eax
  lea    (%rsi,%rbx,1),%r8d
  mov    %eax,D40(%rip)
  jmp    L59
  nopl   0x0(%rax)
L35:
  movl   $0x0,D152(%rip)
  xor    %eax,%eax
  movl   $0x0,D40(%rip)
  movl   $0x0,D152(%rip)
  ret
L53:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int GetCode(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<discardnewline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L24:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L9
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L9:
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void discardnewline(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '\n')
      s[i] = '\0';
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<discardnewline>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L6
L23:
  ret
L33:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L23
L6:
  cmp    $0xa,%al
  jne    L33
  movb   $0x0,(%rdi)
  jmp    L33
```

assistant: ```c
void discardnewline(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '\n')
      s[i] = '\0';
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<discardnewline>:
  endbr64
  jmp    L29
  cs nopw 0x0(%rax,%rax,1)
L7:
  cmp    $0xa,%al
  jne    L28
  movb   $0x0,(%rdi)
L28:
  add    $0x1,%rdi
L29:
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L7
  ret
```

assistant: ```c
void discardnewline(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '\n')
      s[i] = '\0';
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<discardnewline>:
  endbr64
  jmp    L30
  cs nopw 0x0(%rax,%rax,1)
L9:
  add    $0x1,%rdi
L30:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
L35:
  cmp    $0xa,%al
  jne    L9
  movb   $0x0,(%rdi)
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L35
  ret
  nop
L4:
  ret
```

assistant: ```c
void discardnewline(char s[]) {
  int i;
  for (i = 0; s[i] != '\0'; i++) {
    if (s[i] == '\n')
      s[i] = '\0';
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rcx
  lea    -0x10(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L139
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jg     L131
L139:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L80
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jle    L80
L131:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L80:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L35
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jg     L136
L35:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  cmp    %eax,%edx
  jge    L109
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L109
L136:
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L109:
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L57
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jg     L27
L57:
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L2
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jle    L2
L27:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L38
  call   <__stack_chk_fail@plt>
L38:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_guessed: string
name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D5
type_guessed: string

tool: D0: Please enter 3 numbers separated by spaces > 

tool: D6: %d %d %d

tool: D5: %d is the median


assistant: ```c
int main(void) {
  int int1, int2, int3;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d %d %d", &int1, &int2, &int3);
  if (((int1 < int2) && (int1 > int3)) || ((int1 < int2) && (int1 > int3)))
    printf("%d is the median\n", int1);
  else if ((((int2 < int1)) && (int2 > int3)) || ((int2 < int3) && (int2 > int1)))
    printf("%d is the median\n", int2);
  else if (((int3 < int1) && (int3 > int2)) || ((int3 < int2) && (int3 > int1)))
    printf("%d is the median\n", int3);
  return 0;
}
```