ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<number>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  mov    $0x1,%ebp
  lea    D28(%rip),%r13
  lea    D23(%rip),%r12
  jmp    L120
L18:
  neg    %ebp
L120:
  mov    %r13,%rdi
  call   <match@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <match@plt>
  test   %rax,%rax
  jne    L18
  test   %rbx,%rbx
  jne    L120
  mov    $0x0,%eax
  call   <ch@plt>
  mov    %eax,%ebx
  movsbl %al,%edi
  call   <numeric@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jne    L112
L113:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L112:
  lea    D15(%rip),%rdi
  call   <match@plt>
  test   %rax,%rax
  je     L26
L127:
  mov    $0x0,%r13d
  jmp    L30
L26:
  lea    D31(%rip),%rdi
  call   <match@plt>
  test   %rax,%rax
  jne    L127
  cmp    $0x30,%bl
  setne  %bl
  movzbl %bl,%ebx
  lea    0x8(%rbx,%rbx,1),%ebx
  mov    $0x0,%r13d
  jmp    L114
L27:
  mov    $0x0,%eax
  call   <inbyte@plt>
  shl    $0x4,%r13d
  mov    %r15d,%edi
  call   <numeric@plt>
  sub    $0x30,%r15d
  and    $0x7,%ebx
  lea    0x9(%rbx),%r12d
  test   %rax,%rax
  cmovne %r15d,%r12d
  add    %r12d,%r13d
L30:
  mov    $0x0,%eax
  call   <ch@plt>
  mov    %eax,%ebx
  movsbl %al,%r15d
  mov    %r15d,%edi
  call   <numeric@plt>
  test   %rax,%rax
  jne    L27
  mov    %ebx,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x5,%al
  jbe    L27
L115:
  mov    %r13d,%eax
  neg    %eax
  test   %ebp,%ebp
  cmovs  %eax,%r13d
  mov    %r13d,(%r14)
  mov    %r13d,%eax
  shr    $0x1f,%eax
  add    $0x8,%eax
  jmp    L113
L38:
  mov    $0x0,%eax
  call   <inbyte@plt>
  mov    %r13d,%r12d
  imul   %ebx,%r12d
  movsbl %al,%edx
  lea    -0x30(%r12,%rdx,1),%r13d
L114:
  mov    $0x0,%eax
  call   <ch@plt>
  movsbl %al,%edi
  call   <numeric@plt>
  test   %rax,%rax
  jne    L38
  jmp    L115
```

tool_calls: name: read_data
arguments: label: D28
type: string
name: read_data
arguments: label: D23
type: string
name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D31
type: string

tool: D28: +

tool: D23: -

tool: D15: 0x

tool: D31: 0X

assistant: ```c
int number(int val[]) {
  int k, minus, base;
  char c;
  k = minus = 1;
  while (k) {
    k = 0;
    if (match("+"))
      k = 1;
    if (match("-")) {
      minus = (-minus);
      k = 1;
    }
  }
  if (!numeric(c = ch()))
    return (0);
  if (match("0x") || match("0X"))
    while (numeric(c = ch()) || (c >= 'a' && c <= 'f') || (c >= 'A' && c <= 'F')) {
      inbyte();
      k = k * 16 + (numeric(c) ? (c - '0') : ((c & 07) + 9));
    }
  else {
    base = (c == '0') ? 8 : 10;
    while (numeric(ch())) {
      c = inbyte();
      k = k * base + (c - '0');
    }
  }
  if (minus < 0)
    k = (-k);
  val[0] = k;
  if (k < 0) {
    return (((2 << 2) + 1));
  } else {
    return ((2 << 2));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<number>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  sub    $0x8,%rsp
  jmp    L61
  nopw   0x0(%rax,%rax,1)
L79:
  neg    %ebp
L61:
  mov    %r13,%rdi
  call   <match@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <match@plt>
  test   %rax,%rax
  jne    L79
  test   %rbx,%rbx
  jne    L61
  xor    %eax,%eax
  call   <ch@plt>
  movsbl %al,%edi
  mov    %edi,%ebx
  call   <numeric@plt>
  mov    %rax,%r8
  xor    %eax,%eax
  test   %r8,%r8
  jne    L53
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L53:
  lea    D39(%rip),%rdi
  call   <match@plt>
  test   %rax,%rax
  je     L26
L54:
  xor    %r13d,%r13d
  jmp    L10
  nop
L42:
  xor    %eax,%eax
  and    $0x7,%ebx
  shl    $0x4,%r13d
  call   <inbyte@plt>
  mov    %r15d,%edi
  lea    0x9(%rbx),%r12d
  sub    $0x30,%r15d
  call   <numeric@plt>
  test   %rax,%rax
  cmovne %r15d,%r12d
  add    %r12d,%r13d
L10:
  xor    %eax,%eax
  call   <ch@plt>
  movsbl %al,%r15d
  mov    %r15d,%edi
  mov    %r15d,%ebx
  call   <numeric@plt>
  test   %rax,%rax
  jne    L42
  mov    %r15d,%eax
  and    $0xffffffdf,%eax
  sub    $0x41,%eax
  cmp    $0x5,%al
  jbe    L42
L4:
  mov    %r13d,%eax
  neg    %eax
  cmp    $0xffffffff,%ebp
  cmove  %eax,%r13d
  mov    %r13d,%eax
  mov    %r13d,(%r14)
  add    $0x8,%rsp
  shr    $0x1f,%eax
  pop    %rbx
  pop    %rbp
  add    $0x8,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L26:
  lea    D33(%rip),%rdi
  call   <match@plt>
  test   %rax,%rax
  jne    L54
  cmp    $0x30,%bl
  setne  %bl
  xor    %r13d,%r13d
  movzbl %bl,%ebx
  lea    0x8(%rbx,%rbx,1),%ebx
  jmp    L66
L15:
  mov    %r13d,%r12d
  xor    %eax,%eax
  call   <inbyte@plt>
  imul   %ebx,%r12d
  movsbl %al,%edx
  lea    -0x30(%r12,%rdx,1),%r13d
L66:
  xor    %eax,%eax
  call   <ch@plt>
  movsbl %al,%edi
  call   <numeric@plt>
  test   %rax,%rax
  jne    L15
  jmp    L4
```

tool_calls: name: parse_data
arguments: tag: D22
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string
name: parse_data
arguments: tag: D39
type_guessed: string
name: parse_data
arguments: tag: D33
type_guessed: string

tool: D22: +

tool: D1: -

tool: D39: 0x

tool: D33: 0X

assistant: ```c
int number(int val[]) {
  int k, minus, base;
  char c;
  k = minus = 1;
  while (k) {
    k = 0;
    if (match("+"))
      k = 1;
    if (match("-")) {
      minus = (-minus);
      k = 1;
    }
  }
  if (!numeric(c = ch()))
    return (0);
  if (match("0x") || match("0X"))
    while (numeric(c = ch()) || (c >= 'a' && c <= 'f') || (c >= 'A' && c <= 'F')) {
      inbyte();
      k = k * 16 + (numeric(c) ? (c - '0') : ((c & 07) + 9));
    }
  else {
    base = (c == '0') ? 8 : 10;
    while (numeric(ch())) {
      c = inbyte();
      k = k * base + (c - '0');
    }
  }
  if (minus < 0)
    k = (-k);
  val[0] = k;
  if (k < 0) {
    return (((2 << 2) + 1));
  } else {
    return ((2 << 2));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<scim_bridge_perrorln>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L1
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L1:
  mov    -0xd8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0xc0(%rbp)
  mov    -0xc0(%rbp),%rax
  add    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0xb8(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0xb8(%rbp),%rdx
  mov    -0xc0(%rbp),%rax
  add    %rdx,%rax
  movb   $0xa,(%rax)
  mov    -0xc0(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0xd8(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  mov    -0xc4(%rbp),%edx
  mov    -0xb8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

assistant: ```c
void scim_bridge_perrorln(const char *string, ...) {
  va_list ap;
  const size_t str_length = strlen(string);
  char *format = malloc(sizeof(char) * (str_length + 2));
  strcpy(format, string);
  format[str_length] = '\n';
  format[str_length + 1] = '\0';
  va_start(ap, string);
  vfprintf(stderr, format, ap);
  va_end(ap);
  free(format);
}
```
user: Translate the below assembly code into C programming language:

```asm
<scim_bridge_perrorln>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  lea    0x2(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  movb   $0xa,(%rbx,%r12,1)
  movb   $0x0,0x1(%rbx,%r12,1)
  mov    %rbp,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void scim_bridge_perrorln(const char *string, ...) {
  va_list ap;
  const size_t str_length = strlen(string);
  char *format = malloc(sizeof(char) * (str_length + 2));
  strcpy(format, string);
  format[str_length] = '\n';
  format[str_length + 1] = '\0';
  va_start(ap, string);
  vfprintf(stderr, format, ap);
  va_end(ap);
  free(format);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<scim_bridge_perrorln>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  movb   $0xa,0x0(%rbp,%rbx,1)
  mov    %r12,%rsi
  xor    %r12d,%r12d
  movb   $0x0,0x1(%rbp,%rbx,1)
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void scim_bridge_perrorln(const char *string, ...) {
  va_list ap;
  const size_t str_length = strlen(string);
  char *format = malloc(sizeof(char) * (str_length + 2));
  strcpy(format, string);
  format[str_length] = '\n';
  format[str_length + 1] = '\0';
  va_start(ap, string);
  vfprintf(stderr, format, ap);
  va_end(ap);
  free(format);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scim_bridge_perrorln>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  lea    0x2(%rax),%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  movb   $0xa,0x0(%rbp,%rbx,1)
  mov    %r12,%rsi
  xor    %r12d,%r12d
  movb   $0x0,0x1(%rbp,%rbx,1)
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void scim_bridge_perrorln(const char *string, ...) {
  va_list ap;
  const size_t str_length = strlen(string);
  char *format = malloc(sizeof(char) * (str_length + 2));
  strcpy(format, string);
  format[str_length] = '\n';
  format[str_length + 1] = '\0';
  va_start(ap, string);
  vfprintf(stderr, format, ap);
  va_end(ap);
  free(format);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<copro_i80186_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Cleari80186Ram@plt>
  mov    $0x0,%eax
  call   <RomCopy@plt>
  mov    $0x0,%eax
  call   <reset@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void copro_i80186_reset() {
  Cleari80186Ram();
  RomCopy();
  reset();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<copro_i80186_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Cleari80186Ram@plt>
  mov    $0x0,%eax
  call   <RomCopy@plt>
  mov    $0x0,%eax
  call   <reset@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void copro_i80186_reset() {
  Cleari80186Ram();
  RomCopy();
  reset();
}
```
user: What is the c source code of the assembly code below:

```asm
<copro_i80186_reset>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cleari80186Ram@plt>
  xor    %eax,%eax
  call   <RomCopy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <reset@plt>
```

assistant: ```c
void copro_i80186_reset() {
  Cleari80186Ram();
  RomCopy();
  reset();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<copro_i80186_reset>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Cleari80186Ram@plt>
  xor    %eax,%eax
  call   <RomCopy@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1080 <reset@plt>
```

assistant: ```c
void copro_i80186_reset() {
  Cleari80186Ram();
  RomCopy();
  reset();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    D23(%rip),%rdx
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L0:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jae    L2
  mov    $0x2c,%edi
  call   <putchar@plt>
L2:
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L0
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D4
data_type: string
name: read_data
arguments: tag: D26
data_type: string
name: read_data
arguments: tag: D8
data_type: string

tool: D23: print_array

tool: D4: %s - %s [

tool: D26: %d

tool: D8: ]

assistant: ```c
void print_array(const int *array, const int size, const char *tag) {
  printf("%s - %s [", tag, __func__);
  for (unsigned int i = 0; i < size; ++i) {
    printf("%d", array[i]);
    if (i < size - 1)
      printf(",");
  }
  printf("]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_array>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %rdx,%rsi
  lea    D18(%rip),%rdx
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  je     L49
  lea    -0x1(%rbp),%r14d
  mov    $0x0,%ebx
  lea    D32(%rip),%r13
  jmp    L25
L27:
  lea    0x1(%rbx),%rax
  cmp    %r14,%rbx
  je     L49
  mov    %rax,%rbx
L25:
  mov    (%r12,%rbx,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x1(%rbp),%eax
  cmp    %ebx,%eax
  jbe    L27
  mov    $0x2c,%edi
  call   <putchar@plt>
  jmp    L27
L49:
  lea    D36(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: tag: D18
type_guessed: string
name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D32
type_guessed: string
name: parse_data
arguments: tag: D36
type_guessed: string

tool: D18: print_array

tool: D2: %s - %s [

tool: D32: %d

tool: D36: ]

assistant: ```c
void print_array(const int *array, const int size, const char *tag) {
  printf("%s - %s [", tag, __func__);
  for (unsigned int i = 0; i < size; ++i) {
    printf("%d", array[i]);
    if (i < size - 1)
      printf(",");
  }
  printf("]\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_array>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  push   %r13
  mov    %esi,%r13d
  mov    %rdx,%rsi
  lea    D27(%rip),%rdx
  push   %r12
  lea    -0x1(%r13),%r14d
  lea    D30(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D9(%rip),%rdi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r13d,%r13d
  jne    L6
  jmp    L26
  nopl   0x0(%rax)
L47:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L26
L6:
  mov    0x0(%rbp,%rbx,4),%esi
  xor    %eax,%eax
  mov    %r12,%rdi
  call   <printf@plt>
  cmp    %ebx,%r14d
  jbe    L47
  mov    $0x2c,%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %r13,%rbx
  jne    L6
L26:
  add    $0x8,%rsp
  lea    D39(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D27
datatype: string
name: disassemble_data
arguments: data_tag: D30
datatype: string
name: disassemble_data
arguments: data_tag: D9
datatype: string
name: disassemble_data
arguments: data_tag: D39
datatype: string

tool: D27: print_array

tool: D30: %d

tool: D9: %s - %s [

tool: D39: ]

assistant: ```c
void print_array(const int *array, const int size, const char *tag) {
  printf("%s - %s [", tag, __func__);
  for (unsigned int i = 0; i < size; ++i) {
    printf("%d", array[i]);
    if (i < size - 1)
      printf(",");
  }
  printf("]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_array>:
  endbr64
  push   %r15
  xor    %eax,%eax
  push   %r14
  mov    %rdi,%r14
  lea    D23(%rip),%rdi
  push   %r13
  mov    %esi,%r13d
  mov    %rdx,%rsi
  lea    D26(%rip),%rdx
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r13d,%r13d
  je     L2
  mov    %r13d,%ebx
  sub    $0x1,%ebx
  jne    L17
  lea    D31(%rip),%r12
  nopl   0x0(%rax)
L30:
  mov    %ebx,%eax
  mov    %r12,%rdi
  add    $0x1,%ebx
  mov    (%r14,%rax,4),%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,%r13d
  ja     L30
L2:
  add    $0x8,%rsp
  lea    D47(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopw   0x0(%rax,%rax,1)
L17:
  cmp    %ebx,%r13d
  mov    %r14,%rbp
  lea    D31(%rip),%r12
  cmovbe %r13d,%ebx
  mov    %ebx,%r15d
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L29:
  mov    0x0(%rbp),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <printf@plt>
  mov    $0x2c,%edi
  call   <putchar@plt>
  cmp    %r15d,%ebx
  jb     L29
  cmp    %r13d,%ebx
  jb     L30
  jmp    L2
```

tool_calls: name: read_data
arguments: data_label: D23
type_infered: string
name: read_data
arguments: data_label: D26
type_infered: string
name: read_data
arguments: data_label: D31
type_infered: string
name: read_data
arguments: data_label: D47
type_infered: string

tool: D23: %s - %s [

tool: D26: print_array

tool: D31: %d

tool: D47: ]

assistant: ```c
void print_array(const int *array, const int size, const char *tag) {
  printf("%s - %s [", tag, __func__);
  for (unsigned int i = 0; i < size; ++i) {
    printf("%d", array[i]);
    if (i < size - 1)
      printf(",");
  }
  printf("]\n");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<QINIT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xb8(%rbp)
  mov    %rsi,-0xc0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L0
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L0:
  mov    -0xb8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <mpq_init@plt>
  nop
  leave
  ret
```

assistant: ```c
extern void QINIT(mpq_t *q, char *format, ...) {
  mpq_init(*q);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<QINIT>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <mpq_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern void QINIT(mpq_t *q, char *format, ...) {
  mpq_init(*q);
  ;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<QINIT>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <mpq_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern void QINIT(mpq_t *q, char *format, ...) {
  mpq_init(*q);
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<QINIT>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdi),%edi
  call   <mpq_init@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
extern void QINIT(mpq_t *q, char *format, ...) {
  mpq_init(*q);
  ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<signalSafeEpollWait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %ecx,-0x24(%rbp)
L31:
  mov    -0x24(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <epoll_wait@plt>
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jns    L22
  mov    D3(%rip),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  jne    L22
  mov    $0x1,%eax
  jmp    L29
L22:
  mov    $0x0,%eax
L29:
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x24(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jne    L31
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int signalSafeEpollWait(int epfd, struct epoll_event *events, int maxevents, int timeout) {
  bool interrupted;
  int retVal;
  do {
    retVal = epoll_wait(epfd, events, maxevents, timeout);
    interrupted = ((retVal < 0) && (errno == EINTR));
    timeout = 0;
  } while (interrupted);
  return retVal;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<signalSafeEpollWait>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  mov    $0x0,%r13d
L13:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <epoll_wait@plt>
  test   %eax,%eax
  jns    L19
  mov    %r13d,%ecx
  mov    D8(%rip),%rsi
  mov    D7(%rip),%rdx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rsi)
  je     L13
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int signalSafeEpollWait(int epfd, struct epoll_event *events, int maxevents, int timeout) {
  bool interrupted;
  int retVal;
  do {
    retVal = epoll_wait(epfd, events, maxevents, timeout);
    interrupted = ((retVal < 0) && (errno == EINTR));
    timeout = 0;
  } while (interrupted);
  return retVal;
}
```
user: What is the c source code of the assembly code below:

```asm
<signalSafeEpollWait>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L2:
  mov    D0(%rip),%rdx
  mov    D5(%rip),%rsi
  xor    %ecx,%ecx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rsi)
  jne    L18
L19:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <epoll_wait@plt>
  test   %eax,%eax
  js     L2
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int signalSafeEpollWait(int epfd, struct epoll_event *events, int maxevents, int timeout) {
  bool interrupted;
  int retVal;
  do {
    retVal = epoll_wait(epfd, events, maxevents, timeout);
    interrupted = ((retVal < 0) && (errno == EINTR));
    timeout = 0;
  } while (interrupted);
  return retVal;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<signalSafeEpollWait>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L0
  nopw   0x0(%rax,%rax,1)
L5:
  mov    D19(%rip),%rdx
  mov    D11(%rip),%rsi
  xor    %ecx,%ecx
  mov    (%rdx),%rdi
  cmp    %rdi,(%rsi)
  jne    L4
L0:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <epoll_wait@plt>
  test   %eax,%eax
  js     L5
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int signalSafeEpollWait(int epfd, struct epoll_event *events, int maxevents, int timeout) {
  bool interrupted;
  int retVal;
  do {
    retVal = epoll_wait(epfd, events, maxevents, timeout);
    interrupted = ((retVal < 0) && (errno == EINTR));
    timeout = 0;
  } while (interrupted);
  return retVal;
}
```