ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ComputeFibonacci>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  cmp    $0x1,%eax
  jne    L42
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <Fibonacci@plt>
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L9
L42:
  mov    -0x10(%rbp),%eax
  cmp    $0x2,%eax
  jne    L9
  lea    D77(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L59
L39:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <Fibonacci@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L59:
  mov    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jle    L39
L9:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D13
type_infered: string
name: parse_data
arguments: label: D19
type_infered: string
name: parse_data
arguments: label: D77
type_infered: string
name: parse_data
arguments: label: D64
type_infered: string
name: parse_data
arguments: label: D52
type_infered: string

tool: D13: 1- Compute nth term
2- Compute Fibonacci till nth term


 Enter Choice
>>

tool: D19: %d

tool: D77: Enter Number

>>

tool: D64: The %dth term Fibonacci is %dof 

>>

tool: D52: Fibonacci till %dth term\n
>>

assistant: ```c
void ComputeFibonacci() {
  int input, i, output;
  printf("1- Compute nth term\n2- Compute Fibonacci till nth term\n\n\n Enter Choice\n>>");
  scanf("%d", &input);
  if (input == 1) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("The %dth term Fibonacci is %dof \n\n>>", input, Fibonacci(input));
  } else if (input == 2) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("Fibonacci till %dth term\\n\n>>", input);
    for (i = 0; i <= input; i++) {
      printf("%d", Fibonacci(i));
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ComputeFibonacci>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D63(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L67
  cmp    $0x2,%eax
  je     L1
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L67:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <Fibonacci@plt>
  mov    %eax,%edx
  mov    0x4(%rsp),%esi
  lea    D54(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L39
L1:
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D65(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D31(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  js     L39
  mov    $0x0,%ebx
  lea    D65(%rip),%rbp
L52:
  mov    %ebx,%edi
  call   <Fibonacci@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jge    L52
  jmp    L39
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D63
type_infered: string
name: parse_data
arguments: label: D65
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D54
type_infered: string
name: parse_data
arguments: label: D31
type_infered: string

tool: D63: 1- Compute nth term
2- Compute Fibonacci till nth term


 Enter Choice
>>

tool: D65: %d

tool: D23: Enter Number

>>

tool: D54: The %dth term Fibonacci is %dof 

>>

tool: D31: Fibonacci till %dth term\n
>>

assistant: ```c
void ComputeFibonacci() {
  int input, i, output;
  printf("1- Compute nth term\n2- Compute Fibonacci till nth term\n\n\n Enter Choice\n>>");
  scanf("%d", &input);
  if (input == 1) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("The %dth term Fibonacci is %dof \n\n>>", input, Fibonacci(input));
  } else if (input == 2) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("Fibonacci till %dth term\\n\n>>", input);
    for (i = 0; i <= input; i++) {
      printf("%d", Fibonacci(i));
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ComputeFibonacci>:
  endbr64
  push   %r12
  lea    D42(%rip),%rdi
  push   %rbp
  lea    D34(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L61
  cmp    $0x2,%eax
  je     L10
L62:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L44
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L61:
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <Fibonacci@plt>
  mov    0x4(%rsp),%esi
  lea    D14(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L62
  nopl   0x0(%rax,%rax,1)
L10:
  lea    D58(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D59(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L62
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L35:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <Fibonacci@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L35
  jmp    L62
L44:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D42
datatype: string
name: unpack_data
arguments: data_label: D34
datatype: string
name: unpack_data
arguments: data_label: D58
datatype: string
name: unpack_data
arguments: data_label: D14
datatype: string
name: unpack_data
arguments: data_label: D59
datatype: string

tool: D42: 1- Compute nth term
2- Compute Fibonacci till nth term


 Enter Choice
>>

tool: D34: %d

tool: D58: Enter Number

>>

tool: D14: The %dth term Fibonacci is %dof 

>>

tool: D59: Fibonacci till %dth term\n
>>

assistant: ```c
void ComputeFibonacci() {
  int input, i, output;
  printf("1- Compute nth term\n2- Compute Fibonacci till nth term\n\n\n Enter Choice\n>>");
  scanf("%d", &input);
  if (input == 1) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("The %dth term Fibonacci is %dof \n\n>>", input, Fibonacci(input));
  } else if (input == 2) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("Fibonacci till %dth term\\n\n>>", input);
    for (i = 0; i <= input; i++) {
      printf("%d", Fibonacci(i));
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ComputeFibonacci>:
  endbr64
  push   %r12
  lea    D41(%rip),%rdi
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  cmp    $0x1,%eax
  je     L52
  cmp    $0x2,%eax
  je     L33
L27:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <Fibonacci@plt>
  mov    0x4(%rsp),%esi
  lea    D55(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L33:
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D22(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  js     L27
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L7:
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <Fibonacci@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jge    L7
  jmp    L27
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D41
type_guessed: string
name: read_data
arguments: data_tag: D2
type_guessed: string
name: read_data
arguments: data_tag: D29
type_guessed: string
name: read_data
arguments: data_tag: D55
type_guessed: string
name: read_data
arguments: data_tag: D22
type_guessed: string

tool: D41: 1- Compute nth term
2- Compute Fibonacci till nth term


 Enter Choice
>>

tool: D2: %d

tool: D29: Enter Number

>>

tool: D55: The %dth term Fibonacci is %dof 

>>

tool: D22: Fibonacci till %dth term\n
>>

assistant: ```c
void ComputeFibonacci() {
  int input, i, output;
  printf("1- Compute nth term\n2- Compute Fibonacci till nth term\n\n\n Enter Choice\n>>");
  scanf("%d", &input);
  if (input == 1) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("The %dth term Fibonacci is %dof \n\n>>", input, Fibonacci(input));
  } else if (input == 2) {
    printf("Enter Number\n\n>>");
    scanf("%d", &input);
    printf("Fibonacci till %dth term\\n\n>>", input);
    for (i = 0; i <= input; i++) {
      printf("%d", Fibonacci(i));
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L3:
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  test   %rax,%rax
  je     L2
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  movzbl %al,%ecx
  mov    -0x10(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    (%rax),%eax
  movzbl %al,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L3
L2:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  int ret = 0;
  const uint8_t *b1 = s1, *b2 = s2;
  while (n-- && !(ret = (unsigned char)*(b2++) - (unsigned char)*b1++))
    ;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memcmp>:
  endbr64
  mov    $0x0,%ecx
L10:
  cmp    %rcx,%rdx
  je     L2
  movzbl (%rsi,%rcx,4),%eax
  movzbl (%rdi,%rcx,4),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  je     L10
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  int ret = 0;
  const uint8_t *b1 = s1, *b2 = s2;
  while (n-- && !(ret = (unsigned char)*(b2++) - (unsigned char)*b1++))
    ;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<memcmp>:
  endbr64
  xor    %ecx,%ecx
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L17:
  movzbl (%rsi,%rcx,4),%eax
  movzbl (%rdi,%rcx,4),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  jne    L11
L14:
  cmp    %rcx,%rdx
  jne    L17
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  int ret = 0;
  const uint8_t *b1 = s1, *b2 = s2;
  while (n-- && !(ret = (unsigned char)*(b2++) - (unsigned char)*b1++))
    ;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memcmp>:
  endbr64
  xor    %ecx,%ecx
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L17:
  movzbl (%rsi,%rcx,4),%eax
  movzbl (%rdi,%rcx,4),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  jne    L3
L25:
  cmp    %rcx,%rdx
  jne    L17
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  ret
```

assistant: ```c
int memcmp(const void *s1, const void *s2, size_t n) {
  int ret = 0;
  const uint8_t *b1 = s1, *b2 = s2;
  while (n-- && !(ret = (unsigned char)*(b2++) - (unsigned char)*b1++))
    ;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CmdDrop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <Drop@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int CmdDrop(void) {
  Drop();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<CmdDrop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <Drop@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CmdDrop(void) {
  Drop();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CmdDrop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Drop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CmdDrop(void) {
  Drop();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<CmdDrop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <Drop@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int CmdDrop(void) {
  Drop();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rdtsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  rdtsc
  mov    %eax,-0x8(%rbp)
  mov    %edx,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x20,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  or     %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned int low, high;
  __asm__ __volatile__("rdtsc" : "=a"(low), "=d"(high));
  return ((unsigned long long int)high << 32) | low;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rdtsc>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned int low, high;
  __asm__ __volatile__("rdtsc" : "=a"(low), "=d"(high));
  return ((unsigned long long int)high << 32) | low;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rdtsc>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned int low, high;
  __asm__ __volatile__("rdtsc" : "=a"(low), "=d"(high));
  return ((unsigned long long int)high << 32) | low;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rdtsc>:
  endbr64
  rdtsc
  shl    $0x20,%rdx
  mov    %eax,%eax
  or     %rdx,%rax
  ret
```

assistant: ```c
unsigned long long int rdtsc(void) {
  unsigned int low, high;
  __asm__ __volatile__("rdtsc" : "=a"(low), "=d"(high));
  return ((unsigned long long int)high << 32) | low;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  push   $0xa
  push   $0xa
  push   $0x5
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x1e,%edx
  mov    $0x1d,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    D17(%rip),%rax
  movq   %rax,%xmm0
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D45
data_type: string
name: retrieve_data
arguments: label: D63
data_type: string
name: retrieve_data
arguments: label: D61
data_type: string
name: retrieve_data
arguments: label: D20
data_type: string
name: retrieve_data
arguments: label: D17
data_type: f64
name: retrieve_data
arguments: label: D36
data_type: string
name: retrieve_data
arguments: label: D27
data_type: string

tool: D45: Grade report for : Ziad

tool: D63: Assignment 01	Test 01 Quiz 01 Worksheet 01

tool: D61: %d/%d	%d/%d	%d/%d	%d/%d


tool: D20: Total points:	%d/%d


tool: D17: 96.67

tool: D36: Average:	%.2f


tool: D27: Letter grade:	%c

assistant: ```c
int main() {
  printf("Grade report for : Ziad\n");
  printf("Assignment 01\tTest 01 Quiz 01 Worksheet 01\n");
  printf("%d/%d\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("Total points:\t%d/%d\n", 29, 30);
  printf("Average:\t%.2f\n", 96.67);
  printf("Letter grade:\t%c", 'A');
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <puts@plt>
  lea    D37(%rip),%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  push   $0xa
  push   $0xa
  push   $0x5
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0xa,%ecx
  mov    $0x5,%edx
  mov    $0x5,%esi
  lea    D59(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x1e,%edx
  mov    $0x1d,%esi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movsd  D64(%rip),%xmm0
  lea    D52(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D20(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
type_guessed: string
name: extract_symbolic_data
arguments: label: D37
type_guessed: string
name: extract_symbolic_data
arguments: label: D59
type_guessed: string
name: extract_symbolic_data
arguments: label: D23
type_guessed: string
name: extract_symbolic_data
arguments: label: D64
type_guessed: f64
name: extract_symbolic_data
arguments: label: D52
type_guessed: string
name: extract_symbolic_data
arguments: label: D20
type_guessed: string

tool: D7: Grade report for : Ziad

tool: D37: Assignment 01	Test 01 Quiz 01 Worksheet 01

tool: D59: %d/%d	%d/%d	%d/%d	%d/%d


tool: D23: Total points:	%d/%d


tool: D64: 96.67

tool: D52: Average:	%.2f


tool: D20: Letter grade:	%c

assistant: ```c
int main() {
  printf("Grade report for : Ziad\n");
  printf("Assignment 01\tTest 01 Quiz 01 Worksheet 01\n");
  printf("%d/%d\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("Total points:\t%d/%d\n", 29, 30);
  printf("Average:\t%.2f\n", 96.67);
  printf("Letter grade:\t%c", 'A');
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  mov    $0xa,%ecx
  xor    %eax,%eax
  push   $0xa
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0x5,%edx
  push   $0xa
  mov    $0x5,%esi
  lea    D39(%rip),%rdi
  push   $0x5
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x1e,%edx
  xor    %eax,%eax
  mov    $0x1d,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  movsd  D38(%rip),%xmm0
  mov    $0x1,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
data_type: string
name: parse_data
arguments: tag: D22
data_type: string
name: parse_data
arguments: tag: D39
data_type: string
name: parse_data
arguments: tag: D0
data_type: string
name: parse_data
arguments: tag: D38
data_type: f64
name: parse_data
arguments: tag: D6
data_type: string
name: parse_data
arguments: tag: D11
data_type: string

tool: D12: Grade report for : Ziad

tool: D22: Assignment 01	Test 01 Quiz 01 Worksheet 01

tool: D39: %d/%d	%d/%d	%d/%d	%d/%d


tool: D0: Total points:	%d/%d


tool: D38: 96.67

tool: D6: Average:	%.2f


tool: D11: Letter grade:	%c

assistant: ```c
int main() {
  printf("Grade report for : Ziad\n");
  printf("Assignment 01\tTest 01 Quiz 01 Worksheet 01\n");
  printf("%d/%d\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("Total points:\t%d/%d\n", 29, 30);
  printf("Average:\t%.2f\n", 96.67);
  printf("Letter grade:\t%c", 'A');
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D42(%rip),%rdi
  call   <puts@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  sub    $0x8,%rsp
  mov    $0xa,%ecx
  xor    %eax,%eax
  push   $0xa
  mov    $0x4,%r9d
  mov    $0xa,%r8d
  mov    $0x5,%edx
  push   $0xa
  mov    $0x5,%esi
  lea    D69(%rip),%rdi
  push   $0x5
  call   <printf@plt>
  add    $0x20,%rsp
  mov    $0x1e,%edx
  xor    %eax,%eax
  mov    $0x1d,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  movsd  D2(%rip),%xmm0
  mov    $0x1,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x41,%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D42
type: string
name: unpack_data
arguments: data_label: D36
type: string
name: unpack_data
arguments: data_label: D69
type: string
name: unpack_data
arguments: data_label: D10
type: string
name: unpack_data
arguments: data_label: D2
type: f64
name: unpack_data
arguments: data_label: D1
type: string
name: unpack_data
arguments: data_label: D30
type: string

tool: D42: Grade report for : Ziad

tool: D36: Assignment 01	Test 01 Quiz 01 Worksheet 01

tool: D69: %d/%d	%d/%d	%d/%d	%d/%d


tool: D10: Total points:	%d/%d


tool: D2: 96.67

tool: D1: Average:	%.2f


tool: D30: Letter grade:	%c

assistant: ```c
int main() {
  printf("Grade report for : Ziad\n");
  printf("Assignment 01\tTest 01 Quiz 01 Worksheet 01\n");
  printf("%d/%d\t%d/%d\t%d/%d\t%d/%d\n", 5, 5, 10, 10, 4, 5, 10, 10);
  printf("Total points:\t%d/%d\n", 29, 30);
  printf("Average:\t%.2f\n", 96.67);
  printf("Letter grade:\t%c", 'A');
  return 0;
}
```