ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<v_dot_p6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L13:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L17:
  cmpl   $0x5,-0xc(%rbp)
  jle    L13
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double v_dot_p6(const double x[6], const double y[6]) {
  double res = 0.0;
  int i;
  for (i = 0; i < 6; i++)
    res += x[i] * y[i];
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<v_dot_p6>:
  endbr64
  mov    $0x0,%eax
  pxor   %xmm1,%xmm1
L0:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  addsd  %xmm0,%xmm1
  add    $0x8,%rax
  cmp    $0x30,%rax
  jne    L0
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double v_dot_p6(const double x[6], const double y[6]) {
  double res = 0.0;
  int i;
  for (i = 0; i < 6; i++)
    res += x[i] * y[i];
  return res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<v_dot_p6>:
  endbr64
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  nopw   0x0(%rax,%rax,1)
L1:
  movsd  (%rdi,%rax,1),%xmm0
  mulsd  (%rsi,%rax,1),%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  cmp    $0x30,%rax
  jne    L1
  movapd %xmm1,%xmm0
  ret
```

assistant: ```c
double v_dot_p6(const double x[6], const double y[6]) {
  double res = 0.0;
  int i;
  for (i = 0; i < 6; i++)
    res += x[i] * y[i];
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<v_dot_p6>:
  endbr64
  movupd (%rdi),%xmm0
  movupd (%rsi),%xmm3
  pxor   %xmm1,%xmm1
  movupd 0x10(%rsi),%xmm4
  movupd 0x20(%rdi),%xmm2
  mulpd  %xmm3,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movupd 0x10(%rdi),%xmm0
  mulpd  %xmm4,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movupd 0x20(%rsi),%xmm0
  mulpd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double v_dot_p6(const double x[6], const double y[6]) {
  double res = 0.0;
  int i;
  for (i = 0; i < 6; i++)
    res += x[i] * y[i];
  return res;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<INTASCII>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x11c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movswl -0x11c(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D7(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x110(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %d

assistant: ```c
char *INTASCII(char *Result, short Num) {
  char St[256];
  sprintf(St, "%d", Num);
  return strcpy(Result, St);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<INTASCII>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movswl %si,%edx
  mov    %rsp,%rbp
  lea    D1(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D1
type_guessed: string

tool: D1: %d

assistant: ```c
char *INTASCII(char *Result, short Num) {
  char St[256];
  sprintf(St, "%d", Num);
  return strcpy(Result, St);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<INTASCII>:
  endbr64
  push   %r12
  movswl %si,%edx
  lea    D1(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D1
datatype: string

tool: D1: %d

assistant: ```c
char *INTASCII(char *Result, short Num) {
  char St[256];
  sprintf(St, "%d", Num);
  return strcpy(Result, St);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<INTASCII>:
  endbr64
  push   %r12
  movswl %si,%edx
  lea    D6(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x118,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: %d

assistant: ```c
char *INTASCII(char *Result, short Num) {
  char St[256];
  sprintf(St, "%d", Num);
  return strcpy(Result, St);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<adv_font_load_data_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L11:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0x7,%eax
  shr    $0x3,%eax
  imul   -0x18(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jb     L11
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int adv_font_load_data_size(unsigned count, unsigned *width, unsigned height) {
  unsigned size = 0;
  unsigned i;
  for (i = 0; i < count; ++i)
    size += ((width[i] + 7) / 8) * height;
  return size;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<adv_font_load_data_size>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L1
  mov    %rsi,%r8
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rsi
  mov    $0x0,%eax
L10:
  mov    (%r8),%edi
  lea    0x7(%rdi),%ecx
  shr    $0x3,%ecx
  imul   %edx,%ecx
  add    %ecx,%eax
  add    $0x4,%r8
  cmp    %rsi,%r8
  jne    L10
L1:
  ret
```

assistant: ```c
int adv_font_load_data_size(unsigned count, unsigned *width, unsigned height) {
  unsigned size = 0;
  unsigned i;
  for (i = 0; i < count; ++i)
    size += ((width[i] + 7) / 8) * height;
  return size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<adv_font_load_data_size>:
  endbr64
  test   %edi,%edi
  je     L0
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%rdi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rsi),%ecx
  add    $0x4,%rsi
  add    $0x7,%ecx
  shr    $0x3,%ecx
  imul   %edx,%ecx
  add    %ecx,%eax
  cmp    %rsi,%rdi
  jne    L15
  ret
  nop
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int adv_font_load_data_size(unsigned count, unsigned *width, unsigned height) {
  unsigned size = 0;
  unsigned i;
  for (i = 0; i < count; ++i)
    size += ((width[i] + 7) / 8) * height;
  return size;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<adv_font_load_data_size>:
  endbr64
  mov    %edi,%ecx
  mov    %edx,%edi
  test   %ecx,%ecx
  je     L41
  lea    -0x1(%rcx),%eax
  cmp    $0x2,%eax
  jbe    L11
  movd   %edx,%xmm6
  mov    %ecx,%edx
  pxor   %xmm2,%xmm2
  mov    %rsi,%rax
  shr    $0x2,%edx
  pshufd $0x0,%xmm6,%xmm3
  movdqa D6(%rip),%xmm5
  sub    $0x1,%edx
  movdqa %xmm3,%xmm4
  shl    $0x4,%rdx
  psrlq  $0x20,%xmm4
  lea    0x10(%rsi,%rdx,1),%rdx
  xchg   %ax,%ax
L7:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  paddd  %xmm5,%xmm0
  psrld  $0x3,%xmm0
  movdqa %xmm0,%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm3,%xmm1
  pmuludq %xmm4,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  paddd  %xmm1,%xmm2
  cmp    %rdx,%rax
  jne    L7
  movdqa %xmm2,%xmm0
  mov    %ecx,%edx
  psrldq $0x8,%xmm0
  and    $0xfffffffc,%edx
  paddd  %xmm0,%xmm2
  movdqa %xmm2,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm2
  movd   %xmm2,%eax
  test   $0x3,%cl
  je     L38
L40:
  mov    %edx,%r8d
  mov    (%rsi,%r8,4),%r8d
  add    $0x7,%r8d
  shr    $0x3,%r8d
  imul   %edi,%r8d
  add    %r8d,%eax
  lea    0x1(%rdx),%r8d
  cmp    %r8d,%ecx
  jbe    L44
  mov    (%rsi,%r8,4),%r8d
  add    $0x2,%edx
  add    $0x7,%r8d
  shr    $0x3,%r8d
  imul   %edi,%r8d
  add    %r8d,%eax
  cmp    %edx,%ecx
  jbe    L44
  mov    (%rsi,%rdx,4),%edx
  add    $0x7,%edx
  shr    $0x3,%edx
  imul   %edi,%edx
  add    %edx,%eax
  ret
  nopl   0x0(%rax)
L41:
  xor    %eax,%eax
L44:
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  ret
L11:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L40
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: byte[16]

tool: {"D6": [0x07,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

assistant: ```c
int adv_font_load_data_size(unsigned count, unsigned *width, unsigned height) {
  unsigned size = 0;
  unsigned i;
  for (i = 0; i < count; ++i)
    size += ((width[i] + 7) / 8) * height;
  return size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_case_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L6
L24:
  mov    -0x20(%rbp),%rax
  shl    $0x4,%rax
  mov    %rax,%rbx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  add    %rbx,%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  and    $0xf0000000,%eax
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L30
  mov    -0x18(%rbp),%rax
  shr    $0x18,%rax
  xor    -0x20(%rbp),%rax
  xor    -0x18(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L30:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L24
  mov    -0x20(%rbp),%rax
L6:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long string_case_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + toupper(*x++);
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<string_case_hash>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L28
  mov    $0x0,%eax
  movabs $0xffffffff0fffffff,%r12
  jmp    L17
L18:
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L44
L17:
  shl    $0x4,%rax
  mov    %rax,%rbx
  add    $0x1,%rbp
  movzbl %dil,%edi
  call   <toupper@plt>
  add    %rbx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L18
  and    %r12,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
  jmp    L18
L39:
  mov    $0x0,%eax
  ret
L28:
  mov    $0x0,%eax
L44:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
unsigned long string_case_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + toupper(*x++);
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<string_case_hash>:
  endbr64
  test   %rdi,%rdi
  je     L23
  push   %r12
  mov    %rdi,%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L35
  movabs $0xffffffff0fffffff,%rbp
  nopl   0x0(%rax)
L3:
  shl    $0x4,%rax
  add    $0x1,%r12
  mov    %rax,%rbx
  call   <toupper@plt>
  add    %rbx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L30
  and    %rbp,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
L30:
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L3
L35:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long string_case_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + toupper(*x++);
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<string_case_hash>:
  endbr64
  test   %rdi,%rdi
  je     L0
  push   %r12
  mov    %rdi,%r12
  xor    %eax,%eax
  push   %rbp
  push   %rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L31
  movabs $0xffffffff0fffffff,%rbp
  nopl   0x0(%rax)
L34:
  shl    $0x4,%rax
  add    $0x1,%r12
  mov    %rax,%rbx
  call   <toupper@plt>
  add    %rbx,%rax
  mov    %rax,%rdx
  and    $0xf0000000,%edx
  je     L27
  and    %rbp,%rax
  shr    $0x18,%rdx
  xor    %rdx,%rax
L27:
  movzbl (%r12),%edi
  test   %dil,%dil
  jne    L34
L31:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nop
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long string_case_hash(const unsigned char *x) {
  unsigned long g, h = 0;
  if (!x)
    return 0;
  while (*x != 0) {
    h = (h << 4) + toupper(*x++);
    if ((g = h & 0xf0000000) != 0)
      h = (h ^ (g >> 24)) ^ g;
  }
  return h;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<heapify>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  sar    %eax
  mov    %eax,-0x10(%rbp)
  jmp    L72
L66:
  mov    -0x2c(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jg     L57
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L30
  mov    -0x8(%rbp),%eax
  jmp    L4
L30:
  mov    -0xc(%rbp),%eax
L4:
  mov    %eax,-0x14(%rbp)
  jmp    L67
L57:
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x14(%rbp)
L67:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L43
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x2c(%rbp)
L72:
  mov    -0x2c(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L66
  jmp    L42
L43:
  nop
L42:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void heapify(int *heap, int start, int end) {
  int last = ((end + 1) >> 1);
  int lson, rson, largest, tmp;
  while (start < last) {
    lson = (start << 1) + 1;
    rson = lson + 1;
    if (rson <= end) {
      largest = (heap[lson] < heap[rson]) ? rson : lson;
    } else {
      largest = lson;
    }
    if (heap[largest] > heap[start]) {
      tmp = heap[start];
      heap[start] = heap[largest];
      heap[largest] = tmp;
      start = largest;
    } else {
      break;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<heapify>:
  endbr64
  lea    0x1(%rdx),%r10d
  sar    %r10d
  cmp    %esi,%r10d
  jg     L44
  ret
L39:
  movslq %ecx,%rax
  lea    (%rdi,%rax,4),%rax
  mov    (%rax),%r9d
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%r8
  mov    (%r8),%esi
  cmp    %esi,%r9d
  jle    L36
  mov    %r9d,(%r8)
  mov    %esi,(%rax)
  cmp    %r10d,%ecx
  jge    L36
  mov    %ecx,%esi
L44:
  lea    (%rsi,%rsi,1),%eax
  lea    0x1(%rax),%ecx
  add    $0x2,%eax
  cmp    %eax,%edx
  jl     L39
  movslq %ecx,%r8
  mov    0x4(%rdi,%r8,4),%r11d
  cmp    %r11d,(%rdi,%r8,4)
  cmovl  %eax,%ecx
  jmp    L39
L36:
  ret
```

assistant: ```c
void heapify(int *heap, int start, int end) {
  int last = ((end + 1) >> 1);
  int lson, rson, largest, tmp;
  while (start < last) {
    lson = (start << 1) + 1;
    rson = lson + 1;
    if (rson <= end) {
      largest = (heap[lson] < heap[rson]) ? rson : lson;
    } else {
      largest = lson;
    }
    if (heap[largest] > heap[start]) {
      tmp = heap[start];
      heap[start] = heap[largest];
      heap[largest] = tmp;
      start = largest;
    } else {
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<heapify>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x1(%rdx),%ebx
  sar    %ebx
  cmp    %esi,%ebx
  jle    L44
  movslq %esi,%r9
  mov    %rdi,%r8
  mov    %edx,%r11d
  mov    (%rdi,%r9,4),%r10d
  jmp    L19
  xchg   %ax,%ax
L22:
  mov    %ecx,(%rax)
  mov    %r10d,(%rdi)
  cmp    %ebx,%esi
  jge    L44
  movslq %esi,%r9
L19:
  lea    (%rsi,%rsi,1),%eax
  lea    0x1(%rax),%esi
  add    $0x2,%eax
  movslq %esi,%rdx
  shl    $0x2,%rdx
  lea    (%r8,%rdx,1),%rdi
  mov    (%rdi),%ecx
  cmp    %eax,%r11d
  jl     L25
  lea    0x4(%r8,%rdx,1),%rdx
  mov    (%rdx),%ebp
  cmp    %ecx,%ebp
  jle    L25
  mov    %ebp,%ecx
  mov    %rdx,%rdi
  mov    %eax,%esi
L25:
  lea    (%r8,%r9,4),%rax
  cmp    %ecx,%r10d
  jl     L22
L44:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapify(int *heap, int start, int end) {
  int last = ((end + 1) >> 1);
  int lson, rson, largest, tmp;
  while (start < last) {
    lson = (start << 1) + 1;
    rson = lson + 1;
    if (rson <= end) {
      largest = (heap[lson] < heap[rson]) ? rson : lson;
    } else {
      largest = lson;
    }
    if (heap[largest] > heap[start]) {
      tmp = heap[start];
      heap[start] = heap[largest];
      heap[largest] = tmp;
      start = largest;
    } else {
      break;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<heapify>:
  endbr64
  push   %rbp
  push   %rbx
  lea    0x1(%rdx),%ebx
  sar    %ebx
  cmp    %esi,%ebx
  jle    L58
  movslq %esi,%r9
  mov    %rdi,%r8
  mov    %edx,%r11d
  mov    (%rdi,%r9,4),%r10d
  jmp    L4
  xchg   %ax,%ax
L54:
  mov    %ecx,(%rax)
  mov    %r10d,(%rdi)
  cmp    %ebx,%esi
  jge    L58
  movslq %esi,%r9
L4:
  lea    (%rsi,%rsi,1),%eax
  lea    0x1(%rax),%esi
  add    $0x2,%eax
  movslq %esi,%rdx
  shl    $0x2,%rdx
  lea    (%r8,%rdx,1),%rdi
  mov    (%rdi),%ecx
  cmp    %eax,%r11d
  jl     L1
  lea    0x4(%r8,%rdx,1),%rdx
  mov    (%rdx),%ebp
  cmp    %ecx,%ebp
  jle    L1
  mov    %ebp,%ecx
  mov    %rdx,%rdi
  mov    %eax,%esi
L1:
  lea    (%r8,%r9,4),%rax
  cmp    %ecx,%r10d
  jl     L54
L58:
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void heapify(int *heap, int start, int end) {
  int last = ((end + 1) >> 1);
  int lson, rson, largest, tmp;
  while (start < last) {
    lson = (start << 1) + 1;
    rson = lson + 1;
    if (rson <= end) {
      largest = (heap[lson] < heap[rson]) ? rson : lson;
    } else {
      largest = lson;
    }
    if (heap[largest] > heap[start]) {
      tmp = heap[start];
      heap[start] = heap[largest];
      heap[largest] = tmp;
      start = largest;
    } else {
      break;
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ssqr_dvector>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L8:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L8
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ssqr_dvector(double *ret, double *s, int dim) {
  int i;
  for (i = 0; i < dim; i++)
    ret[i] = s[i] * s[i];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ssqr_dvector>:
  endbr64
  test   %edx,%edx
  jle    L1
  mov    %edx,%edx
  mov    $0x0,%eax
L2:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
L1:
  ret
```

assistant: ```c
void ssqr_dvector(double *ret, double *s, int dim) {
  int i;
  for (i = 0; i < dim; i++)
    ret[i] = s[i] * s[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssqr_dvector>:
  endbr64
  test   %edx,%edx
  jle    L14
  movslq %edx,%rdx
  xor    %eax,%eax
  nopl   (%rax)
L12:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rdi,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L12
L14:
  ret
```

assistant: ```c
void ssqr_dvector(double *ret, double *s, int dim) {
  int i;
  for (i = 0; i < dim; i++)
    ret[i] = s[i] * s[i];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ssqr_dvector>:
  endbr64
  mov    %rdi,%rcx
  test   %edx,%edx
  jle    L2
  lea    0x8(%rsi),%rax
  cmp    %rax,%rdi
  je     L3
  lea    -0x1(%rdx),%eax
  cmp    $0x1,%eax
  jbe    L3
  mov    %edx,%edi
  xor    %eax,%eax
  shr    %edi
  shl    $0x4,%rdi
  cs nopw 0x0(%rax,%rax,1)
L42:
  movupd (%rsi,%rax,1),%xmm0
  mulpd  %xmm0,%xmm0
  movups %xmm0,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %rdi,%rax
  jne    L42
  mov    %edx,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%edx
  je     L2
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  ret
  nop
L3:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L20:
  movsd  (%rsi,%rax,8),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L20
L2:
  ret
```

assistant: ```c
void ssqr_dvector(double *ret, double *s, int dim) {
  int i;
  for (i = 0; i < dim; i++)
    ret[i] = s[i] * s[i];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  add    $0xb45,%ax
  mov    %ax,-0xa(%rbp)
  movw   $0x0,-0xc(%rbp)
  jmp    L25
L11:
  addw   $0x2,-0xc(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  movzwl (%rax),%eax
  cmp    %ax,-0xc(%rbp)
  jb     L11
  movzwl -0xa(%rbp),%eax
  lea    0x319d(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned short input[1], unsigned short output[1]) {
  unsigned short state[1];
  unsigned short local1;
  {
    state[0UL] = input[0UL] + (unsigned short)2885;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 371143069UL;
  }
}
```