ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D26(%rip),%rax
  mov    $0xa,%edi
  movq   %rax,%xmm0
  call   <foo@plt>
  mov    %eax,%edx
  mov    D37(%rip),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <__builtin_copysignf@plt>
  movq   %xmm0,%rax
  movsd  D16(%rip),%xmm0
  movq   %rax,%xmm1
  ucomisd %xmm0,%xmm1
  jp     L15
  movsd  D16(%rip),%xmm0
  movq   %rax,%xmm2
  ucomisd %xmm0,%xmm2
  je     L4
L15:
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D26
datatype: f32[2]
name: disassemble_data
arguments: data_tag: D37
datatype: f64
name: disassemble_data
arguments: data_tag: D16
datatype: f32[2]

tool: {"D26": [0.0,-0.0]}

tool: D37: 1

tool: {"D16": [0.0,-1.875]}

assistant: ```c
int main() {
  if (__builtin_copysignf(1.0, foo(0.0 / -5.0, 10)) != -1.0)
    abort();
  exit(0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%edi
  movsd  D18(%rip),%xmm0
  call   <foo@plt>
  mov    %eax,%edi
  movsd  D29(%rip),%xmm0
  call   <__builtin_copysignf@plt>
  ucomisd D25(%rip),%xmm0
  jp     L21
  jne    L21
L2:
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L21:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L2
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D18
type: f32[2]
name: extract_symbolic_data
arguments: data_label: D29
type: f64
name: extract_symbolic_data
arguments: data_label: D25
type: f32[2]

tool: {"D18": [0.0,-0.0]}

tool: D29: 1

tool: {"D25": [0.0,-1.875]}

assistant: ```c
int main() {
  if (__builtin_copysignf(1.0, foo(0.0 / -5.0, 10)) != -1.0)
    abort();
  exit(0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D14(%rip),%xmm0
  mov    $0xa,%edi
  call   <foo@plt>
  movsd  D7(%rip),%xmm0
  mov    %eax,%edi
  call   <__builtin_copysignf@plt>
  ucomisd D27(%rip),%xmm0
  jp     L23
  jne    L23
L22:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L23:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L22
```

tool_calls: name: disassemble_data
arguments: data_tag: D14
data_type: f32[2]
name: disassemble_data
arguments: data_tag: D7
data_type: f64
name: disassemble_data
arguments: data_tag: D27
data_type: f32[2]

tool: {"D14": [0.0,-0.0]}

tool: D7: 1

tool: {"D27": [0.0,-1.875]}

assistant: ```c
int main() {
  if (__builtin_copysignf(1.0, foo(0.0 / -5.0, 10)) != -1.0)
    abort();
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm0
  mov    $0xa,%edi
  call   <foo@plt>
  movsd  D20(%rip),%xmm0
  mov    %eax,%edi
  call   <__builtin_copysignf@plt>
  ucomisd D23(%rip),%xmm0
  jp     L14
  jne    L14
L9:
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L14:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: tag: D9
type: f32[2]
name: unpack_data
arguments: tag: D20
type: f64
name: unpack_data
arguments: tag: D23
type: f32[2]

tool: {"D9": [0.0,-0.0]}

tool: D20: 1

tool: {"D23": [0.0,-1.875]}

assistant: ```c
int main() {
  if (__builtin_copysignf(1.0, foo(0.0 / -5.0, 10)) != -1.0)
    abort();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test6>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <my_malloc2@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_free1@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <my_free1@plt>
  nop
  leave
  ret
```

assistant: ```c
void test6() {
  int *data = (int *)my_malloc2(1, 4);
  my_free1((int *)data);
  my_free1((int *)data);
}
```
user: What is the c source code of the assembly code below:

```asm
<test6>:
  endbr64
  push   %rbx
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <my_malloc2@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <my_free1@plt>
  mov    %rbx,%rdi
  call   <my_free1@plt>
  pop    %rbx
  ret
```

assistant: ```c
void test6() {
  int *data = (int *)my_malloc2(1, 4);
  my_free1((int *)data);
  my_free1((int *)data);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test6>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <my_malloc2@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <my_free1@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <my_free1@plt>
```

assistant: ```c
void test6() {
  int *data = (int *)my_malloc2(1, 4);
  my_free1((int *)data);
  my_free1((int *)data);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test6>:
  endbr64
  push   %rbp
  mov    $0x4,%esi
  mov    $0x1,%edi
  call   <my_malloc2@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <my_free1@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <my_free1@plt>
```

assistant: ```c
void test6() {
  int *data = (int *)my_malloc2(1, 4);
  my_free1((int *)data);
  my_free1((int *)data);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<msx_readproc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rcx
  mov    -0x34(%rbp),%edx
  lea    -0x30(%rbp),%rax
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <msx_read@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: /proc/%d/%s

assistant: ```c
int msx_readproc(int pid, char *item) {
  char fn[30];
  sprintf(fn, "/proc/%d/%s", pid, item);
  return (msx_read(fn));
}
```
user: What is the c source code of the assembly code below?

```asm
<msx_readproc>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%edx
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D8(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rdi
  call   <msx_read@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x30,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: /proc/%d/%s

assistant: ```c
int msx_readproc(int pid, char *item) {
  char fn[30];
  sprintf(fn, "/proc/%d/%s", pid, item);
  return (msx_read(fn));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<msx_readproc>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %rsi,%rcx
  lea    D2(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <msx_read@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x30,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: /proc/%d/%s

assistant: ```c
int msx_readproc(int pid, char *item) {
  char fn[30];
  sprintf(fn, "/proc/%d/%s", pid, item);
  return (msx_read(fn));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<msx_readproc>:
  endbr64
  push   %rbp
  mov    %edi,%edx
  mov    %rsi,%rcx
  lea    D5(%rip),%rsi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rdi
  call   <msx_read@plt>
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x30,%rsp
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: string

tool: D5: /proc/%d/%s

assistant: ```c
int msx_readproc(int pid, char *item) {
  char fn[30];
  sprintf(fn, "/proc/%d/%s", pid, item);
  return (msx_read(fn));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<be_uint24_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void be_uint24_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[2] = v & 0xFF;
  ptr8[1] = (v >> 8) & 0xFF;
  ptr8[0] = (v >> 16) & 0xFF;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<be_uint24_write>:
  endbr64
  mov    %esi,%eax
  mov    %sil,0x2(%rdi)
  movzbl %ah,%edx
  mov    %dl,0x1(%rdi)
  shr    $0x10,%eax
  mov    %al,(%rdi)
  ret
```

assistant: ```c
void be_uint24_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[2] = v & 0xFF;
  ptr8[1] = (v >> 8) & 0xFF;
  ptr8[0] = (v >> 16) & 0xFF;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<be_uint24_write>:
  endbr64
  mov    %esi,%eax
  shr    $0x10,%esi
  rol    $0x8,%ax
  mov    %sil,(%rdi)
  mov    %ax,0x1(%rdi)
  ret
```

assistant: ```c
void be_uint24_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[2] = v & 0xFF;
  ptr8[1] = (v >> 8) & 0xFF;
  ptr8[0] = (v >> 16) & 0xFF;
}
```
user: Translate the below assembly code into C programming language:

```asm
<be_uint24_write>:
  endbr64
  mov    %esi,%eax
  shr    $0x10,%esi
  rol    $0x8,%ax
  mov    %sil,(%rdi)
  mov    %ax,0x1(%rdi)
  ret
```

assistant: ```c
void be_uint24_write(void *ptr, unsigned v) {
  unsigned char *ptr8 = (unsigned char *)ptr;
  ptr8[2] = v & 0xFF;
  ptr8[1] = (v >> 8) & 0xFF;
  ptr8[0] = (v >> 16) & 0xFF;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x21,-0x4(%rbp)
  jmp    L18
L1:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x7e,-0x4(%rbp)
  jle    L1
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string
name: read_data
arguments: data_tag: D23
data_type: string
name: read_data
arguments: data_tag: D17
data_type: string

tool: D0: s/&#%i

tool: D23: ;/

tool: D17: /g

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 33; i < 127; i++) {
    printf("s/&#%i", i);
    printf(";/");
    putchar(i);
    printf("/g\n");
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x21,%ebx
  lea    D11(%rip),%r13
  lea    D6(%rip),%r12
  lea    D10(%rip),%rbp
L9:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  add    $0x1,%ebx
  cmp    $0x7f,%ebx
  jne    L9
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string
name: unpack_data
arguments: label: D6
type_guessed: string
name: unpack_data
arguments: label: D10
type_guessed: string

tool: D11: s/&#%i

tool: D6: ;/

tool: D10: /g

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 33; i < 127; i++) {
    printf("s/&#%i", i);
    printf(";/");
    putchar(i);
    printf("/g\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  lea    D28(%rip),%r12
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x21,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  cmp    $0x7f,%ebx
  jne    L1
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D15
type_guessed: string
name: read_data
arguments: label: D28
type_guessed: string
name: read_data
arguments: label: D2
type_guessed: string

tool: D15: s/&#%i

tool: D28: ;/

tool: D2: /g

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 33; i < 127; i++) {
    printf("s/&#%i", i);
    printf(";/");
    putchar(i);
    printf("/g\n");
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  lea    D24(%rip),%r12
  push   %rbp
  lea    D9(%rip),%rbp
  push   %rbx
  mov    $0x21,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  cmp    $0x7f,%ebx
  jne    L8
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_guessed: string
name: extract_symbolic_data
arguments: label: D24
type_guessed: string
name: extract_symbolic_data
arguments: label: D9
type_guessed: string

tool: D4: s/&#%i

tool: D24: ;/

tool: D9: /g

assistant: ```c
int main(int argc, char *argv[]) {
  int i;
  for (i = 33; i < 127; i++) {
    printf("s/&#%i", i);
    printf(";/");
    putchar(i);
    printf("/g\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<registered_via_two_paths>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x190,%rsp
  mov    %edi,-0x184(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x120(%rbp),%rdx
  lea    -0x180(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <my_task@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void registered_via_two_paths(int x) {
  double p[12], q[34];
  if (x > 42) {
#pragma starpu register p
  } else {
#pragma starpu register p
  }
#pragma starpu register q
  my_task(p, q);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<registered_via_two_paths>:
  endbr64
  sub    $0x188,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rsi
  mov    %rsp,%rdi
  call   <my_task@plt>
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x188,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void registered_via_two_paths(int x) {
  double p[12], q[34];
  if (x > 42) {
#pragma starpu register p
  } else {
#pragma starpu register p
  }
#pragma starpu register q
  my_task(p, q);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<registered_via_two_paths>:
  endbr64
  sub    $0x188,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rsi
  mov    %rsp,%rdi
  call   <my_task@plt>
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x188,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void registered_via_two_paths(int x) {
  double p[12], q[34];
  if (x > 42) {
#pragma starpu register p
  } else {
#pragma starpu register p
  }
#pragma starpu register q
  my_task(p, q);
}
```
user: What is the c source code of the assembly code below:

```asm
<registered_via_two_paths>:
  endbr64
  sub    $0x188,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x178(%rsp)
  xor    %eax,%eax
  lea    0x60(%rsp),%rsi
  mov    %rsp,%rdi
  call   <my_task@plt>
  mov    0x178(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x188,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void registered_via_two_paths(int x) {
  double p[12], q[34];
  if (x > 42) {
#pragma starpu register p
  } else {
#pragma starpu register p
  }
#pragma starpu register q
  my_task(p, q);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x1,%edi
  call   <omp_set_nested@plt>
  mov    $0x0,%edi
  call   <omp_set_dynamic@plt>
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
data_type: string
name: unpack_data
arguments: data_label: D21
data_type: string
name: unpack_data
arguments: data_label: D23
data_type: string

tool: D9: Master : Thread %d of %d (%d Max)



tool: D21: Outer  : Thread %d of %d (%d Max)



tool: D23: Inner  : Thread %d of %d (%d Max)


assistant: ```c
int main(int argc, char **argv) {
  omp_set_nested(1);
  omp_set_dynamic(0);
  int num = 0;
  int threads = 0;
  int max = 0;
  num = omp_get_thread_num();
  threads = omp_get_num_threads();
  max = omp_get_max_threads();
  printf("Master : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(8)
  {
    num = omp_get_thread_num();
    threads = omp_get_num_threads();
    max = omp_get_max_threads();
    printf("Outer  : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(4)
    {
      num = omp_get_thread_num();
      threads = omp_get_num_threads();
      max = omp_get_max_threads();
      printf("Inner  : Thread %d of %d (%d Max)\n", num, threads, max);
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <omp_set_nested@plt>
  mov    $0x0,%edi
  call   <omp_set_dynamic@plt>
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D25(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%ebp
  mov    $0x0,%eax
  call   <omp_get_max_threads@plt>
  mov    %eax,%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D25
data_type: string
name: retrieve_data
arguments: data_label: D16
data_type: string

tool: D20: Master : Thread %d of %d (%d Max)



tool: D25: Outer  : Thread %d of %d (%d Max)



tool: D16: Inner  : Thread %d of %d (%d Max)


assistant: ```c
int main(int argc, char **argv) {
  omp_set_nested(1);
  omp_set_dynamic(0);
  int num = 0;
  int threads = 0;
  int max = 0;
  num = omp_get_thread_num();
  threads = omp_get_num_threads();
  max = omp_get_max_threads();
  printf("Master : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(8)
  {
    num = omp_get_thread_num();
    threads = omp_get_num_threads();
    max = omp_get_max_threads();
    printf("Outer  : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(4)
    {
      num = omp_get_thread_num();
      threads = omp_get_num_threads();
      max = omp_get_max_threads();
      printf("Inner  : Thread %d of %d (%d Max)\n", num, threads, max);
    }
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x1,%edi
  push   %rbp
  sub    $0x8,%rsp
  call   <omp_set_nested@plt>
  xor    %edi,%edi
  call   <omp_set_dynamic@plt>
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D22(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  xor    %eax,%eax
  call   <omp_get_thread_num@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <omp_get_num_threads@plt>
  mov    %eax,%r12d
  xor    %eax,%eax
  call   <omp_get_max_threads@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  mov    %eax,%ecx
  call   <printf@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: label: D22
type: string
name: disassemble_data
arguments: label: D19
type: string
name: disassemble_data
arguments: label: D4
type: string

tool: D22: Master : Thread %d of %d (%d Max)



tool: D19: Outer  : Thread %d of %d (%d Max)



tool: D4: Inner  : Thread %d of %d (%d Max)


assistant: ```c
int main(int argc, char **argv) {
  omp_set_nested(1);
  omp_set_dynamic(0);
  int num = 0;
  int threads = 0;
  int max = 0;
  num = omp_get_thread_num();
  threads = omp_get_num_threads();
  max = omp_get_max_threads();
  printf("Master : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(8)
  {
    num = omp_get_thread_num();
    threads = omp_get_num_threads();
    max = omp_get_max_threads();
    printf("Outer  : Thread %d of %d (%d Max)\n\n", num, threads, max);
#pragma omp parallel num_threads(4)
    {
      num = omp_get_thread_num();
      threads = omp_get_num_threads();
      max = omp_get_max_threads();
      printf("Inner  : Thread %d of %d (%d Max)\n", num, threads, max);
    }
  }
  return 0;
}
```