ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x24000,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    D19(%rip),%rbp
  jmp    L2
L12:
  mov    D1(%rip),%rax
  mov    (%rax),%ecx
  mov    $0x24000,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fwrite@plt>
L2:
  mov    0x0(%rbp),%ecx
  mov    $0x24000,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jle    L11
  mov    %rbx,%rdx
  mov    $0x0,%ecx
L37:
  shll   (%rdx)
  addl   $0x78,0x4(%rdx)
  mov    0x8(%rdx),%esi
  add    $0xc,%rdx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  add    %esi,%eax
  mov    %eax,-0x4(%rdx)
  add    $0x1,%ecx
  cmp    $0xc000,%ecx
  jne    L37
  jmp    L12
L11:
  mov    D23(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int width = 256, heigh = 192, pixelsPerFrame = width * heigh, RGBframeBufferSize = pixelsPerFrame * 3;
  uint8_t *pixels = malloc(RGBframeBufferSize), *pix;
  while (1) {
    if (fread(pixels, 1, RGBframeBufferSize, stdin) <= 0) {
      break;
    }
    pix = pixels;
    for (int q = 0; q < pixelsPerFrame; q++) {
      *pix++ = *pix * 2;
      *pix++ = *pix + 120;
      *pix++ = *pix + q / 10;
    }
    fwrite(pixels, 1, RGBframeBufferSize, stdout);
  }
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x24000,%edi
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    D26(%rip),%rbx
  mov    %rax,%r12
  nopl   0x0(%rax)
L25:
  mov    (%rbx),%ecx
  mov    $0x24000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jle    L10
  mov    %r12,%rax
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %ecx,%edx
  mov    0x8(%rax),%esi
  addl   $0x78,0x4(%rax)
  add    $0x1,%ecx
  imul   %rbp,%rdx
  shll   (%rax)
  add    $0xc,%rax
  shr    $0x23,%rdx
  add    %esi,%edx
  mov    %edx,-0x4(%rax)
  cmp    $0xc000,%ecx
  jne    L2
  mov    D15(%rip),%rax
  mov    $0x24000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    (%rax),%ecx
  call   <fwrite@plt>
  jmp    L25
L10:
  mov    D24(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  int width = 256, heigh = 192, pixelsPerFrame = width * heigh, RGBframeBufferSize = pixelsPerFrame * 3;
  uint8_t *pixels = malloc(RGBframeBufferSize), *pix;
  while (1) {
    if (fread(pixels, 1, RGBframeBufferSize, stdin) <= 0) {
      break;
    }
    pix = pixels;
    for (int q = 0; q < pixelsPerFrame; q++) {
      *pix++ = *pix * 2;
      *pix++ = *pix + 120;
      *pix++ = *pix + q / 10;
    }
    fwrite(pixels, 1, RGBframeBufferSize, stdout);
  }
  return EXIT_SUCCESS;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x24000,%edi
  push   %rbp
  mov    $0xcccccccd,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    D2(%rip),%rbx
  mov    %rax,%r12
  nopl   0x0(%rax)
L22:
  mov    (%rbx),%ecx
  mov    $0x24000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  call   <fread@plt>
  test   %rax,%rax
  jle    L2
  mov    %r12,%rdx
  xor    %ecx,%ecx
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    (%rdx),%eax
  mov    0x8(%rdx),%esi
  add    $0xc,%rdx
  add    %eax,%eax
  movd   %eax,%xmm0
  mov    -0x8(%rdx),%eax
  add    $0x78,%eax
  movd   %eax,%xmm1
  mov    %ecx,%eax
  add    $0x1,%ecx
  imul   %rbp,%rax
  punpckldq %xmm1,%xmm0
  movq   %xmm0,-0xc(%rdx)
  shr    $0x23,%rax
  add    %esi,%eax
  mov    %eax,-0x4(%rdx)
  cmp    $0xc000,%ecx
  jne    L28
  mov    D21(%rip),%rax
  mov    $0x24000,%edx
  mov    $0x1,%esi
  mov    %r12,%rdi
  mov    (%rax),%ecx
  call   <fwrite@plt>
  jmp    L22
L2:
  mov    D16(%rip),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  mov    (%rax),%eax
  ret
```

assistant: ```c
int main() {
  int width = 256, heigh = 192, pixelsPerFrame = width * heigh, RGBframeBufferSize = pixelsPerFrame * 3;
  uint8_t *pixels = malloc(RGBframeBufferSize), *pix;
  while (1) {
    if (fread(pixels, 1, RGBframeBufferSize, stdin) <= 0) {
      break;
    }
    pix = pixels;
    for (int q = 0; q < pixelsPerFrame; q++) {
      *pix++ = *pix * 2;
      *pix++ = *pix + 120;
      *pix++ = *pix + q / 10;
    }
    fwrite(pixels, 1, RGBframeBufferSize, stdout);
  }
  return EXIT_SUCCESS;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print_str_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x5b,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L19:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L19
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D11
type_infered: string

tool: D19: %s, 

tool: D11: ]

assistant: ```c
void print_str_array(char **cs, int size) {
  printf("[");
  for (int i = 0; i < size; i++)
    printf("%s, ", cs[i]);
  printf("]\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print_str_array>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L5
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r12
  lea    D14(%rip),%rbp
L9:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L9
L5:
  lea    D13(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D14
type: string
name: retrieve_data
arguments: data_tag: D13
type: string

tool: D14: %s, 

tool: D13: ]

assistant: ```c
void print_str_array(char **cs, int size) {
  printf("[");
  for (int i = 0; i < size; i++)
    printf("%s, ", cs[i]);
  printf("]\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_str_array>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L1
  lea    -0x1(%rbp),%eax
  lea    D15(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L12:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L12
L1:
  pop    %rbx
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <puts@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D15
type_infered: string
name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D15: %s, 

tool: D5: ]

assistant: ```c
void print_str_array(char **cs, int size) {
  printf("[");
  for (int i = 0; i < size; i++)
    printf("%s, ", cs[i]);
  printf("]\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_str_array>:
  endbr64
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x5b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  jle    L19
  lea    -0x1(%rbp),%eax
  lea    D4(%rip),%rbp
  lea    0x8(%rbx,%rax,8),%r12
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rbx),%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
L19:
  pop    %rbx
  lea    D11(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1080 <puts@plt>
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D11
data_type: string

tool: D4: %s, 

tool: D11: ]

assistant: ```c
void print_str_array(char **cs, int size) {
  printf("[");
  for (int i = 0; i < size; i++)
    printf("%s, ", cs[i]);
  printf("]\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initMat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L43
L48:
  mov    $0x1,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  addl   $0x1,-0x10(%rbp)
L43:
  cmpl   $0x9,-0x10(%rbp)
  jle    L48
  movl   $0x0,-0x10(%rbp)
  jmp    L50
L41:
  movl   $0x0,-0xc(%rbp)
  jmp    L38
L11:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x7e,(%rax)
  addl   $0x1,-0xc(%rbp)
L38:
  cmpl   $0x9,-0xc(%rbp)
  jle    L11
  addl   $0x1,-0x10(%rbp)
L50:
  cmpl   $0x9,-0x10(%rbp)
  jle    L41
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **initMat() {
  int i, j;
  char **mat = (char **)calloc(10, sizeof(char *));
  for (i = 0; i < 10; i++)
    mat[i] = (char *)calloc(10, sizeof(char));
  for (i = 0; i < 10; i++)
    for (j = 0; j < 10; j++) {
      mat[i][j] = '~';
    }
  return mat;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<initMat>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x8,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  mov    %rax,%rbx
  lea    0x50(%rax),%rbp
  mov    %rax,%r13
L11:
  mov    $0x1,%esi
  mov    $0xa,%edi
  call   <calloc@plt>
  mov    %rax,0x0(%r13)
  add    $0x8,%r13
  cmp    %rbp,%r13
  jne    L11
L27:
  mov    %rbx,%rcx
  mov    $0x0,%eax
L18:
  mov    (%rcx),%rdx
  movb   $0x7e,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L18
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L27
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **initMat() {
  int i, j;
  char **mat = (char **)calloc(10, sizeof(char *));
  for (i = 0; i < 10; i++)
    mat[i] = (char *)calloc(10, sizeof(char));
  for (i = 0; i < 10; i++)
    for (j = 0; j < 10; j++) {
      mat[i][j] = '~';
    }
  return mat;
}
```
user: What is the c source code of the assembly code below?

```asm
<initMat>:
  endbr64
  push   %r13
  mov    $0x8,%esi
  mov    $0xa,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <calloc@plt>
  mov    %rax,%r13
  mov    %rax,%rbx
  lea    0x50(%rax),%r12
  mov    %rax,%rbp
  nopw   0x0(%rax,%rax,1)
L20:
  mov    $0x1,%esi
  mov    $0xa,%edi
  add    $0x8,%rbp
  call   <calloc@plt>
  mov    %rax,-0x8(%rbp)
  cmp    %r12,%rbp
  jne    L20
  nopl   0x0(%rax)
L25:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%rbx),%rdx
  movb   $0x7e,(%rdx,%rax,1)
  add    $0x1,%rax
  cmp    $0xa,%rax
  jne    L1
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L25
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char **initMat() {
  int i, j;
  char **mat = (char **)calloc(10, sizeof(char *));
  for (i = 0; i < 10; i++)
    mat[i] = (char *)calloc(10, sizeof(char));
  for (i = 0; i < 10; i++)
    for (j = 0; j < 10; j++) {
      mat[i][j] = '~';
    }
  return mat;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<clean_up>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D15
data_type: string
name: parse_data
arguments: tag: D13
data_type: string

tool: D15: dummy0

tool: D13: dummy1

assistant: ```c
void clean_up(void) {
  unlink("dummy0");
  unlink("dummy1");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<clean_up>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <unlink@plt>
  lea    D5(%rip),%rdi
  call   <unlink@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
datatype: string
name: extract_symbolic_data
arguments: data_tag: D5
datatype: string

tool: D17: dummy0

tool: D5: dummy1

assistant: ```c
void clean_up(void) {
  unlink("dummy0");
  unlink("dummy1");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<clean_up>:
  endbr64
  sub    $0x8,%rsp
  lea    D17(%rip),%rdi
  call   <unlink@plt>
  lea    D10(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <unlink@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D10
type_guessed: string

tool: D17: dummy0

tool: D10: dummy1

assistant: ```c
void clean_up(void) {
  unlink("dummy0");
  unlink("dummy1");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<clean_up>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <unlink@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <unlink@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D7
type_infered: string

tool: D12: dummy0

tool: D7: dummy1

assistant: ```c
void clean_up(void) {
  unlink("dummy0");
  unlink("dummy1");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<generate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x50(%rbp),%rcx
  mov    -0x44(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D3(%rip),%rdx
  mov    $0x32,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: gen_all %d %s

assistant: ```c
void generate(int n, char *suf) {
  char buf[50];
  snprintf(buf, 50, "gen_all %d %s", n, suf);
  system(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<generate>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %edi,%ecx
  mov    %rsi,%r8
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D6(%rip),%rdx
  mov    $0x32,%esi
  mov    %rbx,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x40,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D6
type: string

tool: D6: gen_all %d %s

assistant: ```c
void generate(int n, char *suf) {
  char buf[50];
  snprintf(buf, 50, "gen_all %d %s", n, suf);
  system(buf);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<generate>:
  endbr64
  push   %rbp
  mov    %edi,%ecx
  mov    %rsi,%r8
  lea    D5(%rip),%rdx
  mov    $0x32,%esi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x40,%rsp
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D5
type: string

tool: D5: gen_all %d %s

assistant: ```c
void generate(int n, char *suf) {
  char buf[50];
  snprintf(buf, 50, "gen_all %d %s", n, suf);
  system(buf);
}
```
user: What is the c source code of the assembly code below:

```asm
<generate>:
  endbr64
  push   %rbp
  mov    %edi,%ecx
  mov    %rsi,%r8
  lea    D6(%rip),%rdx
  mov    $0x32,%esi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x40,%rsp
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: gen_all %d %s

assistant: ```c
void generate(int n, char *suf) {
  char buf[50];
  snprintf(buf, 50, "gen_all %d %s", n, suf);
  system(buf);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  lea    -0x54(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x54(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L23:
  cmp    %rdx,%rsp
  je     L0
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L23
L0:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L26
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L26:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x4c(%rbp)
  jmp    L20
L37:
  mov    -0x4c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x4c(%rbp)
L20:
  mov    -0x54(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L37
  lea    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x4c(%rbp)
  jmp    L24
L87:
  mov    -0x40(%rbp),%rax
  mov    -0x4c(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%edx
  mov    -0x50(%rbp),%eax
  cmp    %eax,%edx
  jne    L22
  mov    -0x4c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L22:
  addl   $0x1,-0x4c(%rbp)
L24:
  mov    -0x54(%rbp),%eax
  cmp    %eax,-0x4c(%rbp)
  jl     L87
  mov    $0x0,%eax
  mov    %rbx,%rsp
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L84
  call   <__stack_chk_fail@plt>
L84:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D10
datatype: string
name: parse_data
arguments: data_tag: D37
datatype: string

tool: D10: %d

tool: D37: Key found at position %d 


assistant: ```c
int main() {
  int n, i, key;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &key);
  for (i = 0; i < n; i++)
    if (a[i] == key)
      printf("Key found at position %d \n", i + 1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%edx
  movslq %edx,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L39:
  cmp    %rcx,%rsp
  je     L18
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L39
L18:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L42
  orq    $0x0,-0x8(%rsp,%rax,1)
L42:
  mov    %rsp,%r13
  test   %edx,%edx
  jle    L41
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D26(%rip),%r14
L21:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%r12
  cmp    %ebx,-0x30(%rbp)
  jg     L21
L41:
  lea    -0x2c(%rbp),%rsi
  lea    D26(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,-0x30(%rbp)
  jle    L92
  mov    $0x0,%ebx
  lea    D20(%rip),%r12
  jmp    L44
L0:
  add    $0x1,%rbx
  cmp    %ebx,-0x30(%rbp)
  jle    L92
L44:
  mov    -0x2c(%rbp),%eax
  cmp    %eax,0x0(%r13,%rbx,4)
  jne    L0
  lea    0x1(%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L0
L92:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L69:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D26
data_type: string
name: parse_data
arguments: label: D20
data_type: string

tool: D26: %d

tool: D20: Key found at position %d 


assistant: ```c
int main() {
  int n, i, key;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &key);
  for (i = 0; i < n; i++)
    if (a[i] == key)
      printf("Key found at position %d \n", i + 1);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D2(%rip),%r14
  push   %r13
  lea    -0x30(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x30(%rbp),%rax
  mov    %rsp,%rsi
  mov    %rax,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rsi
  and    $0xfffffffffffffff0,%rdx
  cmp    %rsi,%rsp
  je     L75
L74:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L74
L75:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L65
L6:
  mov    %rsp,%r12
  xor    %ebx,%ebx
  mov    %r12,%r13
  test   %ecx,%ecx
  jle    L15
  nop
L51:
  mov    %r13,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r13
  call   <scanf@plt>
  cmp    %ebx,-0x30(%rbp)
  jg     L51
L15:
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  lea    D1(%rip),%r13
  xor    %ebx,%ebx
  call   <scanf@plt>
  mov    -0x30(%rbp),%eax
  test   %eax,%eax
  jg     L53
  jmp    L85
  nopl   (%rax)
L14:
  add    $0x4,%r12
  cmp    %ebx,-0x30(%rbp)
  jle    L85
L53:
  mov    -0x2c(%rbp),%eax
  add    $0x1,%ebx
  cmp    %eax,(%r12)
  jne    L14
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x4,%r12
  call   <printf@plt>
  cmp    %ebx,-0x30(%rbp)
  jg     L53
L85:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L65:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L6
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D2
type_guessed: string
name: parse_data
arguments: tag: D1
type_guessed: string

tool: D2: %d

tool: D1: Key found at position %d 


assistant: ```c
int main() {
  int n, i, key;
  scanf("%d", &n);
  int a[n];
  for (i = 0; i < n; i++)
    scanf("%d", &a[i]);
  scanf("%d", &key);
  for (i = 0; i < n; i++)
    if (a[i] == key)
      printf("Key found at position %d \n", i + 1);
  return 0;
}
```