ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<decrypt9p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %edx,-0xb4(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpl   $0x7,-0xb4(%rbp)
  jg     L25
  mov    $0x0,%eax
  jmp    L44
L25:
  lea    -0x90(%rbp),%rdx
  mov    -0xa8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <key_setup@plt>
  mov    -0xb0(%rbp),%rax
  mov    %rax,-0x98(%rbp)
  subl   $0x1,-0xb4(%rbp)
  mov    -0xb4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %edx,%ecx
  sub    %esi,%ecx
  mov    %ecx,%edx
  shl    $0x3,%edx
  sub    %ecx,%edx
  sub    %edx,%eax
  mov    %eax,-0x9c(%rbp)
  mov    -0xb4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0xffffffff92492493,%rdx,%rdx
  shr    $0x20,%rdx
  add    %eax,%edx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0xb4(%rbp)
  mov    -0xb4(%rbp),%edx
  mov    %edx,%eax
  shl    $0x3,%eax
  sub    %edx,%eax
  cltq
  add    %rax,-0x98(%rbp)
  cmpl   $0x0,-0x9c(%rbp)
  je     L28
  mov    -0x9c(%rbp),%eax
  cltq
  lea    -0x7(%rax),%rdx
  mov    -0x98(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0x90(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <block_cipher@plt>
L28:
  movl   $0x0,-0xa0(%rbp)
  jmp    L11
L57:
  subq   $0x7,-0x98(%rbp)
  mov    -0x98(%rbp),%rcx
  lea    -0x90(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <block_cipher@plt>
  addl   $0x1,-0xa0(%rbp)
L11:
  mov    -0xa0(%rbp),%eax
  cmp    -0xb4(%rbp),%eax
  jl     L57
  mov    $0x1,%eax
L44:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L49
  call   <__stack_chk_fail@plt>
L49:
  leave
  ret
```

assistant: ```c
int decrypt9p(void *key, void *vbuf, int n) {
  char ekey[128], *buf;
  int i, r;
  if (n < 8)
    return 0;
  key_setup(key, ekey);
  buf = vbuf;
  n--;
  r = n % 7;
  n /= 7;
  buf += n * 7;
  if (r)
    block_cipher(ekey, buf - 7 + r, 1);
  for (i = 0; i < n; i++) {
    buf -= 7;
    block_cipher(ekey, buf, 1);
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<decrypt9p>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edx
  jg     L30
L43:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L54
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L30:
  mov    %rsi,%r12
  mov    %edx,%ebx
  mov    %rsp,%rsi
  call   <key_setup@plt>
  lea    -0x1(%rbx),%eax
  movslq %eax,%rbp
  imul   $0xffffffff92492493,%rbp,%rbp
  shr    $0x20,%rbp
  add    %eax,%ebp
  sar    $0x2,%ebp
  mov    %eax,%esi
  sar    $0x1f,%esi
  mov    %ebp,%ecx
  sub    %esi,%ecx
  lea    0x0(,%rcx,8),%edx
  sub    %ecx,%edx
  mov    %ecx,%ebp
  movslq %edx,%rbx
  add    %r12,%rbx
  sub    %edx,%eax
  jne    L52
L25:
  mov    %ebp,%ebp
  lea    0x0(,%rbp,8),%rax
  sub    %rax,%rbp
  add    %rbx,%rbp
  mov    %rsp,%r12
L36:
  sub    $0x7,%rbx
  mov    $0x1,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <block_cipher@plt>
  cmp    %rbx,%rbp
  jne    L36
  mov    $0x1,%eax
  jmp    L43
L52:
  movslq %eax,%rcx
  lea    -0x7(%rbx,%rcx,1),%rsi
  mov    %rsp,%rdi
  mov    $0x1,%edx
  call   <block_cipher@plt>
  jmp    L25
L54:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decrypt9p(void *key, void *vbuf, int n) {
  char ekey[128], *buf;
  int i, r;
  if (n < 8)
    return 0;
  key_setup(key, ekey);
  buf = vbuf;
  n--;
  r = n % 7;
  n /= 7;
  buf += n * 7;
  if (r)
    block_cipher(ekey, buf - 7 + r, 1);
  for (i = 0; i < n; i++) {
    buf -= 7;
    block_cipher(ekey, buf, 1);
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decrypt9p>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edx
  jg     L3
L34:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L3:
  mov    %rsp,%r12
  mov    %edx,%ebx
  mov    %rsi,%r13
  mov    %r12,%rsi
  call   <key_setup@plt>
  lea    -0x1(%rbx),%eax
  mov    %rax,%rdx
  imul   $0x24924925,%rax,%rax
  mov    %edx,%ebp
  shr    $0x20,%rax
  sub    %eax,%ebp
  shr    %ebp
  add    %eax,%ebp
  mov    %ebp,%ecx
  shr    $0x2,%ecx
  lea    0x0(,%rcx,8),%eax
  movslq %ecx,%rbp
  sub    %ecx,%eax
  mov    %edx,%ecx
  movslq %eax,%rbx
  add    %r13,%rbx
  sub    %eax,%ecx
  jne    L10
L56:
  lea    0x0(,%rbp,8),%rax
  sub    %rax,%rbp
  add    %rbx,%rbp
  nopl   0x0(%rax)
L25:
  sub    $0x7,%rbx
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <block_cipher@plt>
  cmp    %rbp,%rbx
  jne    L25
  mov    $0x1,%eax
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L10:
  movslq %ecx,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  lea    -0x7(%rbx,%rcx,1),%rsi
  call   <block_cipher@plt>
  jmp    L56
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decrypt9p(void *key, void *vbuf, int n) {
  char ekey[128], *buf;
  int i, r;
  if (n < 8)
    return 0;
  key_setup(key, ekey);
  buf = vbuf;
  n--;
  r = n % 7;
  n /= 7;
  buf += n * 7;
  if (r)
    block_cipher(ekey, buf - 7 + r, 1);
  for (i = 0; i < n; i++) {
    buf -= 7;
    block_cipher(ekey, buf, 1);
  }
  return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<decrypt9p>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  cmp    $0x7,%edx
  jg     L57
L34:
  mov    0x88(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L37
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L57:
  mov    %rsp,%r12
  mov    %edx,%ebx
  mov    %rsi,%r13
  mov    %r12,%rsi
  call   <key_setup@plt>
  lea    -0x1(%rbx),%eax
  mov    %rax,%rdx
  imul   $0x24924925,%rax,%rax
  mov    %edx,%ebp
  shr    $0x20,%rax
  sub    %eax,%ebp
  shr    %ebp
  add    %eax,%ebp
  mov    %ebp,%ecx
  shr    $0x2,%ecx
  lea    0x0(,%rcx,8),%eax
  movslq %ecx,%rbp
  sub    %ecx,%eax
  mov    %edx,%ecx
  movslq %eax,%rbx
  add    %r13,%rbx
  sub    %eax,%ecx
  jne    L7
L20:
  lea    0x0(,%rbp,8),%rax
  sub    %rax,%rbp
  add    %rbx,%rbp
  nopl   0x0(%rax)
L1:
  sub    $0x7,%rbx
  mov    $0x1,%edx
  mov    %r12,%rdi
  mov    %rbx,%rsi
  call   <block_cipher@plt>
  cmp    %rbp,%rbx
  jne    L1
  mov    $0x1,%eax
  jmp    L34
  nopl   0x0(%rax,%rax,1)
L7:
  movslq %ecx,%rcx
  mov    $0x1,%edx
  mov    %r12,%rdi
  lea    -0x7(%rbx,%rcx,1),%rsi
  call   <block_cipher@plt>
  jmp    L20
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int decrypt9p(void *key, void *vbuf, int n) {
  char ekey[128], *buf;
  int i, r;
  if (n < 8)
    return 0;
  key_setup(key, ekey);
  buf = vbuf;
  n--;
  r = n % 7;
  n /= 7;
  buf += n * 7;
  if (r)
    block_cipher(ekey, buf - 7 + r, 1);
  for (i = 0; i < n; i++) {
    buf -= 7;
    block_cipher(ekey, buf, 1);
  }
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_reset_errno_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  js     L11
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    D5(%rip),%rax
  mov    %edx,(%rax)
  jmp    L7
L11:
  nop
L7:
  pop    %rbp
  ret
```

assistant: ```c
void _reset_errno_(int *saved_errno) {
  if (*saved_errno < 0)
    return;
  errno = *saved_errno;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_reset_errno_>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  js     L5
  mov    D9(%rip),%rdx
  mov    %eax,(%rdx)
L5:
  ret
```

assistant: ```c
void _reset_errno_(int *saved_errno) {
  if (*saved_errno < 0)
    return;
  errno = *saved_errno;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_reset_errno_>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  js     L8
  mov    D3(%rip),%rdx
  mov    %eax,(%rdx)
L8:
  ret
```

assistant: ```c
void _reset_errno_(int *saved_errno) {
  if (*saved_errno < 0)
    return;
  errno = *saved_errno;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<_reset_errno_>:
  endbr64
  mov    (%rdi),%eax
  test   %eax,%eax
  js     L6
  mov    D9(%rip),%rdx
  mov    %eax,(%rdx)
L6:
  ret
```

assistant: ```c
void _reset_errno_(int *saved_errno) {
  if (*saved_errno < 0)
    return;
  errno = *saved_errno;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<SOR_execute>:
  endbr64
  movapd %xmm0,%xmm3
  mulsd  D0(%rip),%xmm3
  movsd  D12(%rip),%xmm2
  subsd  %xmm0,%xmm2
  test   %ecx,%ecx
  jle    L60
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r11d
  mov    %esi,%r9d
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  lea    -0x3(%rdi),%eax
  lea    0x8(%rdx,%rax,8),%r10
  mov    $0x0,%ebx
  lea    -0x3(%rsi),%edi
  add    $0x2,%rdi
  jmp    L2
L37:
  mov    0x8(%r8),%rdx
  mov    (%r8),%rcx
  mov    0x10(%r8),%rsi
  cmp    $0x2,%r9d
  jle    L46
  mov    $0x1,%eax
L16:
  movsd  (%rcx,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movapd %xmm2,%xmm1
  mulsd  (%rdx,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rax,%rdi
  jne    L16
L46:
  add    $0x8,%r8
  cmp    %r10,%r8
  jne    L37
L52:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  je     L48
L2:
  mov    %rbp,%r8
  cmp    $0x2,%r11d
  jg     L37
  jmp    L52
L48:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L60:
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: f64
name: disassemble_data
arguments: data_tag: D12
type_guessed: f64

tool: D0: 0.25

tool: D12: 1

assistant: ```c
void SOR_execute(int M, int N, double omega, double **G, int num_iterations) {
  double omega_over_four = omega * 0.25;
  double one_minus_omega = 1.0 - omega;
  int Mm1 = M - 1;
  int Nm1 = N - 1;
  int p;
  int i;
  int j;
  double *Gi;
  double *Gim1;
  double *Gip1;
  for (p = 0; p < num_iterations; p++) {
    for (i = 1; i < Mm1; i++) {
      Gi = G[i];
      Gim1 = G[i - 1];
      Gip1 = G[i + 1];
      for (j = 1; j < Nm1; j++)
        Gi[j] = omega_over_four * (Gim1[j] + Gip1[j] + Gi[j - 1] + Gi[j + 1]) + one_minus_omega * Gi[j];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<SOR_execute>:
  endbr64
  movsd  D10(%rip),%xmm3
  movsd  D2(%rip),%xmm2
  mulsd  %xmm0,%xmm3
  subsd  %xmm0,%xmm2
  test   %ecx,%ecx
  jle    L33
  lea    -0x3(%rdi),%eax
  mov    %edi,%r11d
  lea    -0x3(%rsi),%edi
  push   %r12
  mov    %esi,%r9d
  push   %rbp
  mov    %ecx,%r12d
  mov    %rdx,%rbp
  push   %rbx
  lea    0x8(%rdx,%rax,8),%r10
  xor    %ebx,%ebx
  add    $0x2,%rdi
  nopl   (%rax)
L13:
  mov    %rbp,%r8
  cmp    $0x2,%r11d
  jle    L7
  nopl   0x0(%rax)
L3:
  mov    0x8(%r8),%rdx
  mov    (%r8),%rcx
  mov    0x10(%r8),%rsi
  cmp    $0x2,%r9d
  jle    L9
  mov    $0x1,%eax
  xchg   %ax,%ax
L37:
  movsd  (%rcx,%rax,8),%xmm0
  addsd  (%rsi,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  %xmm3,%xmm0
  mulsd  %xmm2,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L37
L9:
  add    $0x8,%r8
  cmp    %r8,%r10
  jne    L3
L7:
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L13
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D10
type_guessed: f64
name: retrieve_data
arguments: tag: D2
type_guessed: f64

tool: D10: 0.25

tool: D2: 1

assistant: ```c
void SOR_execute(int M, int N, double omega, double **G, int num_iterations) {
  double omega_over_four = omega * 0.25;
  double one_minus_omega = 1.0 - omega;
  int Mm1 = M - 1;
  int Nm1 = N - 1;
  int p;
  int i;
  int j;
  double *Gi;
  double *Gim1;
  double *Gip1;
  for (p = 0; p < num_iterations; p++) {
    for (i = 1; i < Mm1; i++) {
      Gi = G[i];
      Gim1 = G[i - 1];
      Gip1 = G[i + 1];
      for (j = 1; j < Nm1; j++)
        Gi[j] = omega_over_four * (Gim1[j] + Gip1[j] + Gi[j - 1] + Gi[j + 1]) + one_minus_omega * Gi[j];
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<SOR_execute>:
  endbr64
  movsd  D5(%rip),%xmm4
  movsd  D17(%rip),%xmm3
  mulsd  %xmm0,%xmm4
  subsd  %xmm0,%xmm3
  test   %ecx,%ecx
  jle    L80
  mov    %edi,%eax
  cmp    $0x2,%edi
  jle    L80
  lea    -0x1(%rsi),%edi
  cmp    $0x1,%edi
  jle    L80
  sub    $0x3,%eax
  push   %r13
  mov    %esi,%r9d
  lea    0x8(%rdx,%rax,8),%r10
  lea    -0x5(%rsi),%eax
  push   %r12
  mov    %ecx,%r12d
  shr    %eax
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  lea    0x5(%rax,%rax,1),%r11
  xor    %ebx,%ebx
  xchg   %ax,%ax
L63:
  mov    %rbp,%r8
  nopl   0x0(%rax,%rax,1)
L23:
  mov    0x8(%r8),%rdx
  mov    (%r8),%rcx
  mov    0x10(%r8),%rsi
  cmp    $0x4,%r9d
  jle    L11
  movsd  0x8(%rdx),%xmm5
  movsd  (%rdx),%xmm0
  mov    $0x3,%eax
L71:
  movsd  -0x10(%rcx,%rax,8),%xmm2
  addsd  -0x10(%rsi,%rax,8),%xmm2
  mulsd  %xmm3,%xmm5
  mov    %eax,%r13d
  movsd  -0x8(%rdx,%rax,8),%xmm6
  addsd  %xmm0,%xmm2
  addsd  %xmm6,%xmm2
  mulsd  %xmm3,%xmm6
  mulsd  %xmm4,%xmm2
  addsd  %xmm5,%xmm2
  movsd  (%rdx,%rax,8),%xmm5
  movsd  %xmm2,-0x10(%rdx,%rax,8)
  movsd  -0x8(%rsi,%rax,8),%xmm1
  addsd  -0x8(%rcx,%rax,8),%xmm1
  movapd %xmm1,%xmm0
  addsd  %xmm2,%xmm0
  addsd  %xmm5,%xmm0
  mulsd  %xmm4,%xmm0
  addsd  %xmm6,%xmm0
  movsd  %xmm0,-0x8(%rdx,%rax,8)
  add    $0x2,%rax
  cmp    %r11,%rax
  jne    L71
L55:
  movslq %r13d,%rax
  nopl   (%rax)
L61:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  movsd  (%rdx,%rax,8),%xmm1
  mulsd  %xmm4,%xmm0
  mulsd  %xmm3,%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L61
  add    $0x8,%r8
  cmp    %r10,%r8
  jne    L23
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L63
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  mov    $0x1,%r13d
  jmp    L55
L80:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: f64
name: extract_symbolic_data
arguments: data_label: D17
datatype: f64

tool: D5: 0.25

tool: D17: 1

assistant: ```c
void SOR_execute(int M, int N, double omega, double **G, int num_iterations) {
  double omega_over_four = omega * 0.25;
  double one_minus_omega = 1.0 - omega;
  int Mm1 = M - 1;
  int Nm1 = N - 1;
  int p;
  int i;
  int j;
  double *Gi;
  double *Gim1;
  double *Gip1;
  for (p = 0; p < num_iterations; p++) {
    for (i = 1; i < Mm1; i++) {
      Gi = G[i];
      Gim1 = G[i - 1];
      Gip1 = G[i + 1];
      for (j = 1; j < Nm1; j++)
        Gi[j] = omega_over_four * (Gim1[j] + Gip1[j] + Gi[j - 1] + Gi[j + 1]) + one_minus_omega * Gi[j];
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_243_1_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  or     -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  not    %eax
  and    %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0x10(%rbp),%eax
  or     %eax,%edx
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_243_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_243_1_1>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%esi
  mov    %edi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  mov    %esi,%edx
  shl    $0x8,%edx
  or     %esi,%edx
  or     %edx,%eax
  not    %eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_243_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xrop3_243_1_1>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  shl    $0x8,%edi
  or     %esi,%eax
  or     %edi,%eax
  not    %eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_243_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<xrop3_243_1_1>:
  endbr64
  movzbl %sil,%esi
  movzbl %dil,%edi
  mov    %esi,%eax
  shl    $0x8,%eax
  or     %edi,%eax
  shl    $0x8,%edi
  or     %esi,%eax
  or     %edi,%eax
  not    %eax
  or     $0xff,%al
  ret
```

assistant: ```c
unsigned xrop3_243_1_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = ~S;
  stk1 = T | stk2;
  return (stk1 & (~S) & (~T)) | (D & S) | (D & T);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<Print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L4:
  movl   $0x0,-0x4(%rbp)
  jmp    L26
L0:
  mov    -0x8(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L4
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type: string

tool: D3: %4.1f 

assistant: ```c
void Print_matrix(char *title, double A[], int m, int n) {
  int i, j;
  printf("%s\n", title);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%4.1f ", A[i * n + j]);
    printf("\n");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,%ebx
  mov    %edx,0x4(%rsp)
  mov    %ecx,%r13d
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L39
  mov    $0x0,%r15d
  mov    $0x0,%r14d
  lea    D3(%rip),%r12
  jmp    L1
L6:
  movslq %r15d,%rdx
  mov    0x8(%rsp),%rcx
  lea    (%rcx,%rdx,8),%rbx
  lea    -0x1(%r13),%eax
  add    %rdx,%rax
  lea    0x8(%rcx,%rax,8),%rbp
L10:
  movsd  (%rbx),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L10
L51:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  add    %r13d,%r15d
  cmp    %r14d,0x4(%rsp)
  je     L39
L1:
  test   %r13d,%r13d
  jg     L6
  jmp    L51
L39:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_infered: string

tool: D3: %4.1f 

assistant: ```c
void Print_matrix(char *title, double A[], int m, int n) {
  int i, j;
  printf("%s\n", title);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%4.1f ", A[i * n + j]);
    printf("\n");
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L32
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D6(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L6:
  test   %r12d,%r12d
  jle    L18
  mov    0x8(%rsp),%rdx
  movslq %r14d,%rcx
  lea    -0x1(%r12),%eax
  add    %rcx,%rax
  lea    (%rdx,%rcx,8),%r15
  lea    0x8(%rdx,%rax,8),%rbx
  xchg   %ax,%ax
L34:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %rbx,%r15
  jne    L34
L18:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    %r12d,%r14d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jne    L6
L32:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D6
type: string

tool: D6: %4.1f 

assistant: ```c
void Print_matrix(char *title, double A[], int m, int n) {
  int i, j;
  printf("%s\n", title);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%4.1f ", A[i * n + j]);
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  mov    %edx,0x4(%rsp)
  call   <puts@plt>
  test   %ebx,%ebx
  jle    L37
  xor    %r14d,%r14d
  xor    %r13d,%r13d
  lea    D6(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L26:
  test   %r12d,%r12d
  jle    L38
  mov    0x8(%rsp),%rdx
  movslq %r14d,%rcx
  lea    -0x1(%r12),%eax
  add    %rcx,%rax
  lea    (%rdx,%rcx,8),%r15
  lea    0x8(%rdx,%rax,8),%rbx
  xchg   %ax,%ax
L2:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x8,%r15
  call   <printf@plt>
  cmp    %r15,%rbx
  jne    L2
L38:
  mov    $0xa,%edi
  add    $0x1,%r13d
  add    %r12d,%r14d
  call   <putchar@plt>
  cmp    %r13d,0x4(%rsp)
  jne    L26
L37:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: string

tool: D6: %4.1f 

assistant: ```c
void Print_matrix(char *title, double A[], int m, int n) {
  int i, j;
  printf("%s\n", title);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      printf("%4.1f ", A[i * n + j]);
    printf("\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  movl   $0x5,(%rax)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main() {
  int a;
  int *pa;
  int **ppa;
  int ***pppa;
  pppa = &ppa;
  ppa = &pa;
  pa = &a;
  ***pppa = 5;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  mov    $0x5,%eax
  ret
```

assistant: ```c
int main() {
  int a;
  int *pa;
  int **ppa;
  int ***pppa;
  pppa = &ppa;
  ppa = &pa;
  pa = &a;
  ***pppa = 5;
  return a;
}
```