ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<allocate_matrix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %edx,%r13d
  lea    0x0(,%rsi,8),%edi
  call   <malloc@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L52
  test   %r12d,%r12d
  jle    L67
  shl    $0x3,%r13d
  mov    %r12d,%r12d
  shl    $0x3,%r12
  mov    $0x0,%ebx
L38:
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdx
  mov    %rax,(%rdx,%rbx,1)
  mov    0x0(%rbp),%rax
  cmpq   $0x0,(%rax,%rbx,1)
  je     L17
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L38
  mov    $0x0,%eax
  jmp    L43
L52:
  mov    $0x1,%eax
  jmp    L43
L67:
  mov    $0x0,%eax
  jmp    L43
L17:
  mov    $0x1,%eax
L43:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int allocate_matrix(int ***M, int nx, int ny) {
  int i;
  (*M) = (int **)malloc(sizeof(double *) * nx);
  if (*M == NULL)
    return 1;
  for (i = 0; i < nx; i++) {
    (*M)[i] = (int *)malloc(sizeof(double) * ny);
    if ((*M)[i] == NULL)
      return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<allocate_matrix>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %edx,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L28
  mov    %r12,%r14
  shl    $0x3,%ebp
  xor    %ebx,%ebx
  shl    $0x3,%r12
  test   %r14d,%r14d
  jg     L44
  jmp    L43
  nopl   (%rax)
L21:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L43
L44:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    0x0(%r13),%rdx
  mov    %rax,(%rdx,%rbx,1)
  test   %rax,%rax
  jne    L21
L28:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int allocate_matrix(int ***M, int nx, int ny) {
  int i;
  (*M) = (int **)malloc(sizeof(double *) * nx);
  if (*M == NULL)
    return 1;
  for (i = 0; i < nx; i++) {
    (*M)[i] = (int *)malloc(sizeof(double) * ny);
    if ((*M)[i] == NULL)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<allocate_matrix>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  movslq %esi,%r12
  push   %rbp
  lea    0x0(,%r12,8),%edi
  mov    %edx,%ebp
  push   %rbx
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L23
  mov    %r12,%r14
  shl    $0x3,%ebp
  xor    %ebx,%ebx
  shl    $0x3,%r12
  test   %r14d,%r14d
  jg     L34
  jmp    L7
  nopl   (%rax)
L15:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L7
L34:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    0x0(%r13),%rdx
  mov    %rax,(%rdx,%rbx,1)
  test   %rax,%rax
  jne    L15
L23:
  pop    %rbx
  mov    $0x1,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int allocate_matrix(int ***M, int nx, int ny) {
  int i;
  (*M) = (int **)malloc(sizeof(double *) * nx);
  if (*M == NULL)
    return 1;
  for (i = 0; i < nx; i++) {
    (*M)[i] = (int *)malloc(sizeof(double) * ny);
    if ((*M)[i] == NULL)
      return 1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xorncpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,%rax
  mov    -0x18(%rbp),%rbx
  mov    -0x20(%rbp),%r12
L2:
  mov    %r12,%rdx
  lea    0x1(%rdx),%r12
  movzbl (%rdx),%esi
  mov    %rbx,%rdx
  lea    0x1(%rdx),%rbx
  movzbl (%rdx),%ecx
  xor    %esi,%ecx
  mov    %cl,(%rdx)
  sub    $0x1,%rax
  test   %rax,%rax
  jne    L2
  mov    -0x18(%rbp),%rax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
char *xorncpy(char *destination, const char *source, register size_t n) {
  register char *d = destination;
  register const char *s = source;
  do {
    *d++ ^= *s++;
  } while (--n != 0);
  return (destination);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xorncpy>:
  endbr64
  mov    %rdi,%rax
  add    %rdi,%rdx
  mov    %rdi,%rcx
L7:
  add    $0x1,%rsi
  add    $0x1,%rcx
  movzbl -0x1(%rsi),%r8d
  xor    %r8b,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L7
  ret
```

assistant: ```c
char *xorncpy(char *destination, const char *source, register size_t n) {
  register char *d = destination;
  register const char *s = source;
  do {
    *d++ ^= *s++;
  } while (--n != 0);
  return (destination);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<xorncpy>:
  endbr64
  mov    %rdi,%rax
  add    %rdi,%rdx
  mov    %rdi,%rcx
  nopl   (%rax)
L4:
  add    $0x1,%rcx
  add    $0x1,%rsi
  movzbl -0x1(%rsi),%r8d
  xor    %r8b,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L4
  ret
```

assistant: ```c
char *xorncpy(char *destination, const char *source, register size_t n) {
  register char *d = destination;
  register const char *s = source;
  do {
    *d++ ^= *s++;
  } while (--n != 0);
  return (destination);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<xorncpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rdi
  lea    -0x1(%rdx),%rax
  mov    %rdx,%rsi
  mov    %r8,%rcx
  lea    0x1(%rdi),%rdx
  sub    %rdx,%rcx
  cmp    $0xe,%rcx
  jbe    L131
  cmp    $0x6,%rax
  jbe    L131
  cmp    $0xe,%rax
  jbe    L79
  lea    -0x10(%rsi),%rcx
  xor    %eax,%eax
  xor    %edx,%edx
  shr    $0x4,%rcx
  add    $0x1,%rcx
  nopl   0x0(%rax)
L16:
  movdqu (%rdi,%rax,1),%xmm0
  movdqu (%r8,%rax,1),%xmm2
  add    $0x1,%rdx
  pxor   %xmm2,%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rcx
  ja     L16
  shl    $0x4,%rcx
  mov    %rsi,%rdx
  lea    (%r8,%rcx,1),%r10
  sub    %rcx,%rdx
  lea    (%rdi,%rcx,1),%r9
  mov    %r10,%rax
  cmp    %rcx,%rsi
  je     L58
  lea    -0x1(%rdx),%r11
  mov    %rdx,%rsi
  cmp    $0x6,%r11
  jbe    L8
L69:
  movq   (%rdi,%rcx,1),%xmm0
  movq   (%r10),%xmm1
  mov    %rsi,%rcx
  and    $0xfffffffffffffff8,%rcx
  pxor   %xmm1,%xmm0
  sub    %rcx,%rdx
  add    %rcx,%rax
  add    %rcx,%r9
  movq   %xmm0,(%r10)
  cmp    %rcx,%rsi
  je     L58
  lea    -0x1(%rdx),%r11
L8:
  movzbl (%r9),%ecx
  xor    %cl,(%rax)
  test   %r11,%r11
  je     L58
  movzbl 0x1(%r9),%ecx
  xor    %cl,0x1(%rax)
  cmp    $0x2,%rdx
  je     L58
  movzbl 0x2(%r9),%ecx
  xor    %cl,0x2(%rax)
  cmp    $0x3,%rdx
  je     L58
  movzbl 0x3(%r9),%ecx
  xor    %cl,0x3(%rax)
  cmp    $0x4,%rdx
  je     L58
  movzbl 0x4(%r9),%ecx
  xor    %cl,0x4(%rax)
  cmp    $0x5,%rdx
  je     L58
  movzbl 0x5(%r9),%ecx
  xor    %cl,0x5(%rax)
  cmp    $0x6,%rdx
  je     L58
  movzbl 0x6(%r9),%edx
  xor    %dl,0x6(%rax)
L58:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L131:
  add    %r8,%rsi
  mov    %r8,%rax
  jmp    L81
L12:
  add    $0x1,%rdx
L81:
  add    $0x1,%rax
  movzbl -0x1(%rdx),%ecx
  xor    %cl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L12
  mov    %r8,%rax
  ret
L79:
  mov    %rdi,%r9
  mov    %r8,%rax
  mov    %rsi,%rdx
  xor    %ecx,%ecx
  mov    %r8,%r10
  jmp    L69
```

assistant: ```c
char *xorncpy(char *destination, const char *source, register size_t n) {
  register char *d = destination;
  register const char *s = source;
  do {
    *d++ ^= *s++;
  } while (--n != 0);
  return (destination);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<alloc_rdata_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%eax
  mov    %eax,%edi
  call   <xalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    -0x20(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
uint16_t *alloc_rdata_init(const void *data, size_t size) {
  uint16_t *result = xalloc(sizeof(uint16_t) + size);
  *result = size;
  memcpy(result + 1, data, size);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_rdata_init>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  lea    0x8(%rsi),%edi
  call   <xalloc@plt>
  mov    %rax,%rbx
  mov    %rbp,(%rax)
  lea    0x8(%rax),%rdi
  mov    %rbp,%rdx
  mov    %r12,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint16_t *alloc_rdata_init(const void *data, size_t size) {
  uint16_t *result = xalloc(sizeof(uint16_t) + size);
  *result = size;
  memcpy(result + 1, data, size);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<alloc_rdata_init>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x8(%rsi),%edi
  call   <xalloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r13,(%rax)
  mov    %rax,%r12
  lea    0x8(%rax),%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint16_t *alloc_rdata_init(const void *data, size_t size) {
  uint16_t *result = xalloc(sizeof(uint16_t) + size);
  *result = size;
  memcpy(result + 1, data, size);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<alloc_rdata_init>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  lea    0x8(%rsi),%edi
  call   <xalloc@plt>
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r13,(%rax)
  mov    %rax,%r12
  lea    0x8(%rax),%rdi
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
uint16_t *alloc_rdata_init(const void *data, size_t size) {
  uint16_t *result = xalloc(sizeof(uint16_t) + size);
  *result = size;
  memcpy(result + 1, data, size);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printfConsole>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x2e0,%rsp
  mov    %rdi,-0x2d8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L23
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L23:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x2d8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L68
L18:
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x2c8(%rbp)
  cmpq   $0x0,-0x2c8(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L68
L24:
  movb   $0x0,-0xc1(%rbp)
  mov    -0x2d8(%rbp),%rdx
  mov    -0x2d0(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x2d0(%rbp),%ecx
  mov    -0x2d8(%rbp),%rdx
  lea    -0x2c0(%rbp),%rax
  mov    $0x200,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    %eax,-0x2cc(%rbp)
  mov    -0x2d0(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  movzbl -0xc1(%rbp),%eax
  test   %al,%al
  je     L13
  mov    -0x2c8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x22,%edx
  mov    $0x1,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
L13:
  movb   $0x0,-0xc1(%rbp)
  mov    -0x2c8(%rbp),%rdx
  lea    -0x2c0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fputs@plt>
  mov    -0x2c8(%rbp),%rax
  mov    %rax,%rdi
  call   <fflush@plt>
  mov    -0x2c8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  mov    -0x2cc(%rbp),%eax
L68:
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D22
type: string
name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D8: w

tool: D22: /dev/console

tool: D6: NOTE: printfConsole() overflow!!!


assistant: ```c
int printfConsole(const char *sFmt, ...) {
  va_list vlVars;
  char sBuf[512];
  int iRet;
  FILE *fnOut;
  if (sFmt == 0)
    return 0;
  fnOut = fopen("/dev/console", "w");
  if (fnOut == 0)
    return 0;
  sBuf[sizeof(sBuf) - 1] = '\0';
  va_start(vlVars, sFmt);
  iRet = vsnprintf(sBuf, sizeof(sBuf), sFmt, vlVars);
  va_end(vlVars);
  if (sBuf[sizeof(sBuf) - 1] != '\0') {
    fprintf(fnOut, "NOTE: printfConsole() overflow!!!\n");
  }
  sBuf[sizeof(sBuf) - 1] = '\0';
  fprintf(fnOut, "%s", sBuf);
  fflush(fnOut);
  fclose(fnOut);
  return iRet;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<printfConsole>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  mov    $0x0,%r12d
  test   %rdi,%rdi
  je     L35
  mov    %rdi,%rbx
  lea    D29(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L35
  movb   $0x0,0x1ff(%rsp)
  mov    %rbx,%rsi
  mov    $0x0,%r13d
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r13d,%ecx
  mov    %rbx,%rdx
  mov    $0x200,%esi
  call   <vsnprintf@plt>
  mov    %eax,%r12d
  mov    %r13d,%edi
  call   <va_end@plt>
  cmpb   $0x0,0x1ff(%rsp)
  jne    L5
L6:
  movb   $0x0,0x1ff(%rsp)
  mov    %rsp,%rdi
  mov    %rbp,%rsi
  call   <fputs@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
L35:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    %r12d,%eax
  add    $0x218,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  mov    %rbp,%rcx
  mov    $0x22,%edx
  mov    $0x1,%esi
  lea    D28(%rip),%rdi
  call   <fwrite@plt>
  jmp    L6
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D29
data_type: string
name: read_data
arguments: tag: D13
data_type: string
name: read_data
arguments: tag: D28
data_type: string

tool: D29: w

tool: D13: /dev/console

tool: D28: NOTE: printfConsole() overflow!!!


assistant: ```c
int printfConsole(const char *sFmt, ...) {
  va_list vlVars;
  char sBuf[512];
  int iRet;
  FILE *fnOut;
  if (sFmt == 0)
    return 0;
  fnOut = fopen("/dev/console", "w");
  if (fnOut == 0)
    return 0;
  sBuf[sizeof(sBuf) - 1] = '\0';
  va_start(vlVars, sFmt);
  iRet = vsnprintf(sBuf, sizeof(sBuf), sFmt, vlVars);
  va_end(vlVars);
  if (sBuf[sizeof(sBuf) - 1] != '\0') {
    fprintf(fnOut, "NOTE: printfConsole() overflow!!!\n");
  }
  sBuf[sizeof(sBuf) - 1] = '\0';
  fprintf(fnOut, "%s", sBuf);
  fflush(fnOut);
  fclose(fnOut);
  return iRet;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<printfConsole>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L36
  mov    %rdi,%r12
  lea    D8(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L36
  xor    %r13d,%r13d
  mov    %r12,%rsi
  mov    %rsp,%r14
  movb   $0x0,0x1ff(%rsp)
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %r13d,%ecx
  mov    $0x200,%esi
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  cmpb   $0x0,0x1ff(%rsp)
  jne    L13
L39:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  movb   $0x0,0x1ff(%rsp)
  call   <fputs@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L36:
  xor    %r12d,%r12d
L46:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x218,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L13:
  mov    %rbp,%rcx
  mov    $0x22,%edx
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  call   <fwrite@plt>
  jmp    L39
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string
name: retrieve_data
arguments: data_tag: D0
type_infered: string
name: retrieve_data
arguments: data_tag: D4
type_infered: string

tool: D8: w

tool: D0: /dev/console

tool: D4: NOTE: printfConsole() overflow!!!


assistant: ```c
int printfConsole(const char *sFmt, ...) {
  va_list vlVars;
  char sBuf[512];
  int iRet;
  FILE *fnOut;
  if (sFmt == 0)
    return 0;
  fnOut = fopen("/dev/console", "w");
  if (fnOut == 0)
    return 0;
  sBuf[sizeof(sBuf) - 1] = '\0';
  va_start(vlVars, sFmt);
  iRet = vsnprintf(sBuf, sizeof(sBuf), sFmt, vlVars);
  va_end(vlVars);
  if (sBuf[sizeof(sBuf) - 1] != '\0') {
    fprintf(fnOut, "NOTE: printfConsole() overflow!!!\n");
  }
  sBuf[sizeof(sBuf) - 1] = '\0';
  fprintf(fnOut, "%s", sBuf);
  fflush(fnOut);
  fclose(fnOut);
  return iRet;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<printfConsole>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L27
  mov    %rdi,%r12
  lea    D0(%rip),%rsi
  lea    D13(%rip),%rdi
  call   <fopen@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L27
  xor    %r13d,%r13d
  mov    %r12,%rsi
  mov    %rsp,%r14
  movb   $0x0,0x1ff(%rsp)
  mov    %r13d,%edi
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %r13d,%ecx
  mov    $0x200,%esi
  mov    %r14,%rdi
  call   <vsnprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  cmpb   $0x0,0x1ff(%rsp)
  jne    L42
L22:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  movb   $0x0,0x1ff(%rsp)
  call   <fputs@plt>
  mov    %rbp,%rdi
  call   <fflush@plt>
  mov    %rbp,%rdi
  call   <fclose@plt>
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L27:
  xor    %r12d,%r12d
L10:
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x218,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  mov    %rbp,%rcx
  mov    $0x22,%edx
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  call   <fwrite@plt>
  jmp    L22
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string
name: extract_symbolic_data
arguments: tag: D13
type_infered: string
name: extract_symbolic_data
arguments: tag: D26
type_infered: string

tool: D0: w

tool: D13: /dev/console

tool: D26: NOTE: printfConsole() overflow!!!


assistant: ```c
int printfConsole(const char *sFmt, ...) {
  va_list vlVars;
  char sBuf[512];
  int iRet;
  FILE *fnOut;
  if (sFmt == 0)
    return 0;
  fnOut = fopen("/dev/console", "w");
  if (fnOut == 0)
    return 0;
  sBuf[sizeof(sBuf) - 1] = '\0';
  va_start(vlVars, sFmt);
  iRet = vsnprintf(sBuf, sizeof(sBuf), sFmt, vlVars);
  va_end(vlVars);
  if (sBuf[sizeof(sBuf) - 1] != '\0') {
    fprintf(fnOut, "NOTE: printfConsole() overflow!!!\n");
  }
  sBuf[sizeof(sBuf) - 1] = '\0';
  fprintf(fnOut, "%s", sBuf);
  fflush(fnOut);
  fclose(fnOut);
  return iRet;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<self_strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L11
L3:
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L3
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t self_strlen(char s[]) {
  size_t len = 0;
  while (s[len] != '\0')
    len++;
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<self_strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L8
  mov    $0x0,%eax
L17:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L17
  ret
L8:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t self_strlen(char s[]) {
  size_t len = 0;
  while (s[len] != '\0')
    len++;
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<self_strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L19
  nopl   0x0(%rax,%rax,1)
L12:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
size_t self_strlen(char s[]) {
  size_t len = 0;
  while (s[len] != '\0')
    len++;
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<self_strlen>:
  endbr64
  xor    %eax,%eax
  cmpb   $0x0,(%rdi)
  je     L11
  nopl   0x0(%rax,%rax,1)
L15:
  add    $0x1,%rax
  cmpb   $0x0,(%rdi,%rax,1)
  jne    L15
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  ret
```

assistant: ```c
size_t self_strlen(char s[]) {
  size_t len = 0;
  while (s[len] != '\0')
    len++;
  return len;
}
```
user: What is the c source code of the assembly code below:

```asm
<printMenu>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D68(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D53(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D61(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D68
type: string
name: parse_data
arguments: tag: D53
type: string
name: parse_data
arguments: tag: D61
type: string
name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D52
type: string
name: parse_data
arguments: tag: D59
type: string
name: parse_data
arguments: tag: D18
type: string

tool: D68: 
	<a>. Enqueue Integer


tool: D53: 	<b>. Dequeue Integer


tool: D61: 	<c>. Queue Size


tool: D5: 	<d>. Queue Front


tool: D52: 	<e>. Print Queue



tool: D59: 	<q>. Exit


tool: D18: 	Opt: 

assistant: ```c
void printMenu() {
  printf("\n\t<a>. Enqueue Integer\n");
  printf("\t<b>. Dequeue Integer\n");
  printf("\t<c>. Queue Size\n");
  printf("\t<d>. Queue Front\n");
  printf("\t<e>. Print Queue\n\n");
  printf("\t<q>. Exit\n");
  printf("\tOpt: ");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<printMenu>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D7(%rip),%rdi
  call   <printf@plt>
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    D54(%rip),%rdi
  call   <printf@plt>
  lea    D43(%rip),%rdi
  call   <printf@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
data_type: string
name: disassemble_data
arguments: tag: D44
data_type: string
name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D67
data_type: string
name: disassemble_data
arguments: tag: D54
data_type: string
name: disassemble_data
arguments: tag: D43
data_type: string
name: disassemble_data
arguments: tag: D10
data_type: string

tool: D4: 
	<a>. Enqueue Integer


tool: D44: 	<b>. Dequeue Integer


tool: D7: 	<c>. Queue Size


tool: D67: 	<d>. Queue Front


tool: D54: 	<e>. Print Queue



tool: D43: 	<q>. Exit


tool: D10: 	Opt: 

assistant: ```c
void printMenu() {
  printf("\n\t<a>. Enqueue Integer\n");
  printf("\t<b>. Dequeue Integer\n");
  printf("\t<c>. Queue Size\n");
  printf("\t<d>. Queue Front\n");
  printf("\t<e>. Print Queue\n\n");
  printf("\t<q>. Exit\n");
  printf("\tOpt: ");
}
```