ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<putLines>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmpb   $0x0,(%rsi)
  je     L6
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %edx,%r13d
  xor    %r12d,%r12d
  nop
L11:
  mov    %r13d,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <putLine@plt>
  movslq %eax,%rdx
  add    %eax,%r12d
  add    %rdx,%rbx
  cmpb   $0x0,(%rbx)
  jne    L11
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int putLines(char **buffer, char *t, int addCRLF) {
  int n, n1 = 0;
  while (*t) {
    n = putLine(buffer, t, addCRLF);
    t += n;
    n1 += n;
  }
  return n1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<allMarked>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L32
L13:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L20
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L20:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L13
L7:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int allMarked(int *selected, int n) {
  int i, flag = 1;
  for (i = 0; i < n; i++) {
    if (selected[i] == 0) {
      flag = 0;
      break;
    }
  }
  return flag;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<allMarked>:
  endbr64
  test   %esi,%esi
  jle    L36
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%rcx
L31:
  mov    (%rax),%edx
  test   %edx,%edx
  je     L10
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L31
  mov    $0x1,%edx
L10:
  mov    %edx,%eax
  ret
L36:
  mov    $0x1,%edx
  jmp    L10
```

assistant: ```c
int allMarked(int *selected, int n) {
  int i, flag = 1;
  for (i = 0; i < n; i++) {
    if (selected[i] == 0) {
      flag = 0;
      break;
    }
  }
  return flag;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<allMarked>:
  endbr64
  test   %esi,%esi
  jle    L25
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L25
L4:
  mov    (%rdi),%eax
  test   %eax,%eax
  jne    L19
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int allMarked(int *selected, int n) {
  int i, flag = 1;
  for (i = 0; i < n; i++) {
    if (selected[i] == 0) {
      flag = 0;
      break;
    }
  }
  return flag;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<allMarked>:
  endbr64
  test   %esi,%esi
  jle    L2
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%rdx
  jmp    L30
  nopw   0x0(%rax,%rax,1)
L7:
  add    $0x4,%rdi
  cmp    %rdx,%rdi
  je     L2
L30:
  mov    (%rdi),%eax
  test   %eax,%eax
  jne    L7
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int allMarked(int *selected, int n) {
  int i, flag = 1;
  for (i = 0; i < n; i++) {
    if (selected[i] == 0) {
      flag = 0;
      break;
    }
  }
  return flag;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpl   $0x3,-0x24(%rbp)
  jg     L13
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0xffffffff,%eax
  jmp    L50
L13:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    D16(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L4
  movl   $0x1,-0x14(%rbp)
  jmp    L112
L4:
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L58
  movl   $0x0,-0x14(%rbp)
  jmp    L112
L58:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0xffffffff,%eax
  jmp    L50
L112:
  mov    -0x30(%rbp),%rax
  add    $0x18,%rax
  mov    (%rax),%rax
  mov    $0x10,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtol@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  js     L53
  cmpq   $0xffff,-0x8(%rbp)
  jle    L68
L53:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L50
L68:
  cmpl   $0x0,-0x14(%rbp)
  je     L67
  mov    -0x30(%rbp),%rax
  lea    0x20(%rax),%rcx
  mov    -0x24(%rbp),%eax
  lea    -0x4(%rax),%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <set_rid@plt>
  jmp    L50
L67:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_rid@plt>
L50:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D16
type_guessed: string
name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D2
type_guessed: string

tool: D16: set

tool: D7: get

tool: D2: 
Invalid rid 0x%lx


assistant: ```c
int main(int argc, char *argv[]) {
  char *dev;
  int set;
  long int rid;
  if (argc < 4) {
    usage();
    return -1;
  }
  dev = argv[1];
  if (strcmp(argv[2], "set") == 0)
    set = 1;
  else if (strcmp(argv[2], "get") == 0)
    set = 0;
  else {
    usage();
    return -1;
  }
  rid = strtol(argv[3], NULL, 16);
  if (rid < 0 || rid > 65535) {
    usage();
    printf("\nInvalid rid 0x%lx\n", rid);
    return -1;
  }
  if (set)
    return set_rid(dev, rid, argc - 4, &argv[4]);
  else
    return get_rid(dev, rid);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x3,%edi
  jle    L54
  mov    %edi,%r12d
  mov    %rsi,%rbx
  mov    0x8(%rsi),%r13
  mov    0x10(%rsi),%rdi
  lea    D24(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L86
  mov    0x10(%rbx),%rdi
  lea    D9(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L77
  mov    0x18(%rbx),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbp
  cmp    $0xffff,%rax
  ja     L62
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <get_rid@plt>
  jmp    L70
L54:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0xffffffff,%eax
  jmp    L70
L77:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    $0xffffffff,%eax
  jmp    L70
L62:
  mov    $0x0,%eax
  call   <usage@plt>
  mov    %rbp,%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L70
L86:
  mov    0x18(%rbx),%rdi
  mov    $0x10,%edx
  mov    $0x0,%esi
  call   <strtol@plt>
  mov    %rax,%rbp
  cmp    $0xffff,%rax
  ja     L62
  lea    0x20(%rbx),%rcx
  lea    -0x4(%r12),%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <set_rid@plt>
L70:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D24
type_guessed: string
name: parse_data
arguments: tag: D9
type_guessed: string
name: parse_data
arguments: tag: D14
type_guessed: string

tool: D24: set

tool: D9: get

tool: D14: 
Invalid rid 0x%lx


assistant: ```c
int main(int argc, char *argv[]) {
  char *dev;
  int set;
  long int rid;
  if (argc < 4) {
    usage();
    return -1;
  }
  dev = argv[1];
  if (strcmp(argv[2], "set") == 0)
    set = 1;
  else if (strcmp(argv[2], "get") == 0)
    set = 0;
  else {
    usage();
    return -1;
  }
  rid = strtol(argv[3], NULL, 16);
  if (rid < 0 || rid > 65535) {
    usage();
    printf("\nInvalid rid 0x%lx\n", rid);
    return -1;
  }
  if (set)
    return set_rid(dev, rid, argc - 4, &argv[4]);
  else
    return get_rid(dev, rid);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x3,%edi
  jle    L10
  mov    %edi,%ebp
  mov    0x10(%rsi),%rdi
  mov    0x8(%rsi),%r12
  mov    %rsi,%rbx
  lea    D26(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L31
  mov    0x10(%rbx),%rdi
  lea    D7(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L10
  mov    0x18(%rbx),%rdi
  xor    %esi,%esi
  mov    $0x10,%edx
  call   <strtol@plt>
  mov    %rax,%rsi
  cmp    $0xffff,%rax
  ja     L20
  add    $0x10,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10e0 <get_rid@plt>
L31:
  mov    0x18(%rbx),%rdi
  xor    %esi,%esi
  mov    $0x10,%edx
  call   <strtol@plt>
  mov    %rax,%rsi
  cmp    $0xffff,%rax
  ja     L20
  add    $0x10,%rsp
  lea    0x20(%rbx),%rcx
  lea    -0x4(%rbp),%edx
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <set_rid@plt>
L10:
  xor    %eax,%eax
  call   <usage@plt>
L46:
  add    $0x10,%rsp
  or     $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  call   <usage@plt>
  mov    0x8(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <printf@plt>
  jmp    L46
```

tool_calls: name: unpack_data
arguments: data_tag: D26
type: string
name: unpack_data
arguments: data_tag: D7
type: string
name: unpack_data
arguments: data_tag: D27
type: string

tool: D26: set

tool: D7: get

tool: D27: 
Invalid rid 0x%lx


assistant: ```c
int main(int argc, char *argv[]) {
  char *dev;
  int set;
  long int rid;
  if (argc < 4) {
    usage();
    return -1;
  }
  dev = argv[1];
  if (strcmp(argv[2], "set") == 0)
    set = 1;
  else if (strcmp(argv[2], "get") == 0)
    set = 0;
  else {
    usage();
    return -1;
  }
  rid = strtol(argv[3], NULL, 16);
  if (rid < 0 || rid > 65535) {
    usage();
    printf("\nInvalid rid 0x%lx\n", rid);
    return -1;
  }
  if (set)
    return set_rid(dev, rid, argc - 4, &argv[4]);
  else
    return get_rid(dev, rid);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  cmp    $0x3,%edi
  jle    L8
  mov    %edi,%ebp
  mov    0x10(%rsi),%rdi
  mov    0x8(%rsi),%r12
  mov    %rsi,%rbx
  lea    D22(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L57
  mov    0x10(%rbx),%rdi
  lea    D28(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L8
  mov    0x18(%rbx),%rdi
  xor    %esi,%esi
  mov    $0x10,%edx
  call   <strtol@plt>
  mov    %rax,%rsi
  cmp    $0xffff,%rax
  ja     L46
  add    $0x10,%rsp
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10e0 <get_rid@plt>
L57:
  mov    0x18(%rbx),%rdi
  xor    %esi,%esi
  mov    $0x10,%edx
  call   <strtol@plt>
  mov    %rax,%rsi
  cmp    $0xffff,%rax
  ja     L46
  add    $0x10,%rsp
  lea    0x20(%rbx),%rcx
  lea    -0x4(%rbp),%edx
  mov    %r12,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    10f0 <set_rid@plt>
L8:
  xor    %eax,%eax
  call   <usage@plt>
L14:
  add    $0x10,%rsp
  or     $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L46:
  xor    %eax,%eax
  mov    %rsi,0x8(%rsp)
  call   <usage@plt>
  mov    0x8(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: data_label: D22
data_type: string
name: retrieve_data
arguments: data_label: D28
data_type: string
name: retrieve_data
arguments: data_label: D21
data_type: string

tool: D22: set

tool: D28: get

tool: D21: 
Invalid rid 0x%lx


assistant: ```c
int main(int argc, char *argv[]) {
  char *dev;
  int set;
  long int rid;
  if (argc < 4) {
    usage();
    return -1;
  }
  dev = argv[1];
  if (strcmp(argv[2], "set") == 0)
    set = 1;
  else if (strcmp(argv[2], "get") == 0)
    set = 0;
  else {
    usage();
    return -1;
  }
  rid = strtol(argv[3], NULL, 16);
  if (rid < 0 || rid > 65535) {
    usage();
    printf("\nInvalid rid 0x%lx\n", rid);
    return -1;
  }
  if (set)
    return set_rid(dev, rid, argc - 4, &argv[4]);
  else
    return get_rid(dev, rid);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x9,-0x14(%rbp)
  mov    $0x7fc,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <fibonacci@plt>
  mov    %eax,(%rbx)
L2:
  jmp    L2
```

assistant: ```c
int main() {
  int n = 9;
  *(int *)0x07FC = fibonacci(n);
  while (1) {
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <fibonacci@plt>
  mov    %eax,0x7fc
L4:
  jmp    L4
```

assistant: ```c
int main() {
  int n = 9;
  *(int *)0x07FC = fibonacci(n);
  while (1) {
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <fibonacci@plt>
  mov    %eax,0x7fc
L0:
  jmp    L0
```

assistant: ```c
int main() {
  int n = 9;
  *(int *)0x07FC = fibonacci(n);
  while (1) {
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x9,%edi
  call   <fibonacci@plt>
  mov    %eax,0x7fc
L4:
  jmp    L4
```

assistant: ```c
int main() {
  int n = 9;
  *(int *)0x07FC = fibonacci(n);
  while (1) {
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strCpyReplace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L25
L39:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  je     L34
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  jmp    L9
L34:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x20,(%rax)
L9:
  addq   $0x1,-0x10(%rbp)
L25:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L39
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void strCpyReplace(char *dest, const char *src) {
  while (*src) {
    if (*src != '_')
      *dest++ = *src;
    else
      *dest++ = ' ';
    src++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strCpyReplace>:
  endbr64
  movzbl (%rsi),%eax
  test   %al,%al
  je     L8
  add    $0x1,%rdi
  mov    $0x20,%edx
L16:
  cmp    $0x5f,%al
  cmove  %edx,%eax
  mov    %al,-0x1(%rdi)
  add    $0x1,%rsi
  movzbl (%rsi),%eax
  add    $0x1,%rdi
  test   %al,%al
  jne    L16
L8:
  ret
```

assistant: ```c
void strCpyReplace(char *dest, const char *src) {
  while (*src) {
    if (*src != '_')
      *dest++ = *src;
    else
      *dest++ = ' ';
    src++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strCpyReplace>:
  endbr64
  movzbl (%rsi),%eax
  xor    %edx,%edx
  mov    $0x20,%ecx
  test   %al,%al
  je     L1
  nopw   0x0(%rax,%rax,1)
L17:
  cmp    $0x5f,%al
  cmove  %ecx,%eax
  mov    %al,(%rdi,%rdx,1)
  add    $0x1,%rdx
  movzbl (%rsi,%rdx,1),%eax
  test   %al,%al
  jne    L17
L1:
  ret
```

assistant: ```c
void strCpyReplace(char *dest, const char *src) {
  while (*src) {
    if (*src != '_')
      *dest++ = *src;
    else
      *dest++ = ' ';
    src++;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strCpyReplace>:
  endbr64
  movzbl (%rsi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L28
  nopl   (%rax)
L5:
  cmp    $0x5f,%dl
  je     L20
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L5
  ret
  nopl   (%rax)
L20:
  movb   $0x20,(%rdi,%rax,1)
  add    $0x1,%rax
  movzbl (%rsi,%rax,1),%edx
  test   %dl,%dl
  jne    L5
L28:
  ret
```

assistant: ```c
void strCpyReplace(char *dest, const char *src) {
  while (*src) {
    if (*src != '_')
      *dest++ = *src;
    else
      *dest++ = ' ';
    src++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sched_get_priority_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L12
  cmpl   $0x1,-0x4(%rbp)
  je     L12
  cmpl   $0x2,-0x4(%rbp)
  je     L12
  mov    D2(%rip),%rax
  movl   $0x1de7,(%rax)
  mov    $0xffffffff,%eax
  jmp    L15
L12:
  cmpl   $0x0,-0x4(%rbp)
  je     L22
  mov    $0x63,%eax
  jmp    L15
L22:
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
extern int sched_get_priority_max(int policy) {
  if (policy != 0 && policy != 1 && policy != 2) {
    (void)(errno = (7655));
    return -1;
  }
  return ((policy) != 0 ? 99 : 0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sched_get_priority_max>:
  endbr64
  cmp    $0x2,%edi
  ja     L8
  test   %edi,%edi
  mov    $0x63,%eax
  cmove  %edi,%eax
  ret
L8:
  mov    D6(%rip),%rax
  movl   $0x1de7,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
extern int sched_get_priority_max(int policy) {
  if (policy != 0 && policy != 1 && policy != 2) {
    (void)(errno = (7655));
    return -1;
  }
  return ((policy) != 0 ? 99 : 0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sched_get_priority_max>:
  endbr64
  cmp    $0x2,%edi
  ja     L4
  neg    %edi
  sbb    %eax,%eax
  and    $0x63,%eax
  ret
  nopl   0x0(%rax)
L4:
  mov    D0(%rip),%rax
  movl   $0x1de7,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
extern int sched_get_priority_max(int policy) {
  if (policy != 0 && policy != 1 && policy != 2) {
    (void)(errno = (7655));
    return -1;
  }
  return ((policy) != 0 ? 99 : 0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sched_get_priority_max>:
  endbr64
  cmp    $0x2,%edi
  ja     L7
  neg    %edi
  sbb    %eax,%eax
  and    $0x63,%eax
  ret
  nopl   0x0(%rax)
L7:
  mov    D6(%rip),%rax
  movl   $0x1de7,(%rax)
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
extern int sched_get_priority_max(int policy) {
  if (policy != 0 && policy != 1 && policy != 2) {
    (void)(errno = (7655));
    return -1;
  }
  return ((policy) != 0 ? 99 : 0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_string_blank>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L2
L14:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L2
  mov    $0x0,%eax
  jmp    L17
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    $0x1,%eax
L17:
  leave
  ret
```

assistant: ```c
char is_string_blank(char *s) {
  while (*s != '\0')
    if (!isspace(*s++))
      return 0;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<is_string_blank>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
L3:
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L23
  add    $0x1,%rbx
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L3
  mov    $0x0,%eax
  jmp    L4
L23:
  mov    $0x1,%eax
L4:
  pop    %rbx
  ret
```

assistant: ```c
char is_string_blank(char *s) {
  while (*s != '\0')
    if (!isspace(*s++))
      return 0;
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_string_blank>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L3:
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %eax,%eax
  je     L22
L18:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L3
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char is_string_blank(char *s) {
  while (*s != '\0')
    if (!isspace(*s++))
      return 0;
  return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_string_blank>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  jmp    L24
  nopw   0x0(%rax,%rax,1)
L1:
  add    $0x1,%rbx
  call   <isspace@plt>
  test   %eax,%eax
  je     L22
L24:
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L1
  mov    $0x1,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax)
L22:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
char is_string_blank(char *s) {
  while (*s != '\0')
    if (!isspace(*s++))
      return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x3,-0xc(%rbp)
  movl   $0x5,-0x8(%rbp)
  movl   $0x2,-0x4(%rbp)
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <record@plt>
  jmp    L40
L36:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L26
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <record@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L26:
  addl   $0x2,-0x8(%rbp)
  cmpl   $0xf423f,-0x4(%rbp)
  jg     L40
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  je     L49
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <record@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x1,-0x4(%rbp)
L49:
  addl   $0x4,-0x8(%rbp)
L40:
  cmpl   $0xf423f,-0x4(%rbp)
  jle    L36
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  mov    $0xf4240,%edi
  call   <printTransitions@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int last_prime = 3, n = 5, count = 2;
  init();
  record(2, 3);
  while (count < 1000000) {
    if (isPrime(n)) {
      record(last_prime, n);
      last_prime = n;
      count++;
    }
    n += 2;
    if (count < 1000000) {
      if (isPrime(n)) {
        record(last_prime, n);
        last_prime = n;
        count++;
      }
      n += 4;
    }
  }
  printTransitions(1000000, last_prime);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <init@plt>
  mov    $0x3,%esi
  mov    $0x2,%edi
  call   <record@plt>
  mov    $0x2,%ebp
  mov    $0x5,%ebx
  mov    $0x3,%r13d
  jmp    L44
L33:
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <record@plt>
  add    $0x1,%ebp
  mov    %ebx,%r13d
  cmp    $0xf423f,%ebp
  jle    L22
  mov    %r12d,%ebx
L44:
  cmp    $0xf423f,%ebp
  jg     L52
  mov    %ebx,%edi
  call   <isPrime@plt>
  lea    0x2(%rbx),%r12d
  test   %rax,%rax
  jne    L33
L22:
  mov    %r12d,%edi
  call   <isPrime@plt>
  test   %rax,%rax
  jne    L48
L19:
  add    $0x6,%ebx
  jmp    L44
L48:
  mov    %r12d,%esi
  mov    %r13d,%edi
  call   <record@plt>
  add    $0x1,%ebp
  mov    %r12d,%r13d
  jmp    L19
L52:
  mov    %r13d,%esi
  mov    $0xf4240,%edi
  call   <printTransitions@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int main() {
  int last_prime = 3, n = 5, count = 2;
  init();
  record(2, 3);
  while (count < 1000000) {
    if (isPrime(n)) {
      record(last_prime, n);
      last_prime = n;
      count++;
    }
    n += 2;
    if (count < 1000000) {
      if (isPrime(n)) {
        record(last_prime, n);
        last_prime = n;
        count++;
      }
      n += 4;
    }
  }
  printTransitions(1000000, last_prime);
  return 0;
}
```