user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x4e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x4e0(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  jmp    L26
L52:
  lea    -0x4c0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    -0x330(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x32,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0x4cc(%rbp)
  lea    -0x4d0(%rbp),%rsi
  lea    -0x4d4(%rbp),%rcx
  lea    -0x4d8(%rbp),%rdx
  lea    -0x4dc(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x63,-0x4c8(%rbp)
  jmp    L117
L57:
  mov    -0x4d4(%rbp),%eax
  mov    -0x4d8(%rbp),%esi
  mov    -0x4c8(%rbp),%ecx
  lea    -0x1(%rcx),%edx
  mov    %edx,-0x4c8(%rbp)
  cltd
  idiv   %esi
  movslq %ecx,%rax
  mov    %edx,-0x4c0(%rbp,%rax,4)
  mov    -0x4d4(%rbp),%eax
  mov    -0x4d8(%rbp),%edi
  cltd
  idiv   %edi
  mov    %eax,-0x4d4(%rbp)
L117:
  mov    -0x4d4(%rbp),%eax
  test   %eax,%eax
  jne    L57
  movl   $0x63,-0x4c8(%rbp)
  jmp    L110
L93:
  mov    -0x4d0(%rbp),%eax
  mov    -0x4d8(%rbp),%esi
  mov    -0x4c8(%rbp),%ecx
  lea    -0x1(%rcx),%edx
  mov    %edx,-0x4c8(%rbp)
  cltd
  idiv   %esi
  movslq %ecx,%rax
  mov    %edx,-0x330(%rbp,%rax,4)
  mov    -0x4d0(%rbp),%eax
  mov    -0x4d8(%rbp),%esi
  cltd
  idiv   %esi
  mov    %eax,-0x4d0(%rbp)
L110:
  mov    -0x4d0(%rbp),%eax
  test   %eax,%eax
  jne    L93
  movl   $0x0,-0x4c8(%rbp)
  jmp    L4
L100:
  mov    -0x4c8(%rbp),%eax
  cltq
  mov    -0x4c0(%rbp,%rax,4),%edx
  mov    -0x4c8(%rbp),%eax
  cltq
  mov    -0x330(%rbp,%rax,4),%eax
  add    %edx,%eax
  mov    -0x4d8(%rbp),%ecx
  cltd
  idiv   %ecx
  mov    -0x4c8(%rbp),%eax
  cltq
  mov    %edx,-0x1a0(%rbp,%rax,4)
  addl   $0x1,-0x4c8(%rbp)
L4:
  cmpl   $0x63,-0x4c8(%rbp)
  jle    L100
  movl   $0x0,-0x4c8(%rbp)
  movl   $0x63,-0x4c4(%rbp)
  jmp    L119
L49:
  mov    -0x4c4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L88
  mov    -0x4d8(%rbp),%eax
  mov    -0x4c8(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    -0x4c4(%rbp),%edx
  movslq %edx,%rdx
  mov    -0x1a0(%rbp,%rdx,4),%edx
  imul   %edx,%eax
  add    %eax,-0x4cc(%rbp)
L88:
  addl   $0x1,-0x4c8(%rbp)
  subl   $0x1,-0x4c4(%rbp)
L119:
  cmpl   $0x0,-0x4c4(%rbp)
  jne    L49
  mov    -0x4dc(%rbp),%eax
  mov    -0x4cc(%rbp),%edx
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L26:
  mov    -0x4e0(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x4e0(%rbp)
  test   %eax,%eax
  jne    L52
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string

tool: D3: %d

tool: D16: %d%d%d%d

tool: D10: %d %d


assistant: ```c
int main() {
  int t, n, b, x, y;
  scanf("%d", &t);
  while (t--) {
    int num1[100] = {0}, num2[100] = {0};
    int sum[100], ans;
    ans = 0;
    scanf("%d%d%d%d", &n, &b, &x, &y);
    int i = 99;
    while (x) {
      num1[i--] = x % b;
      x /= b;
    }
    i = 99;
    while (y) {
      num2[i--] = y % b;
      y /= b;
    }
    for (i = 0; i < 100; i++)
      sum[i] = (num1[i] + num2[i]) % b;
    i = 0;
    int j = 99;
    while (j) {
      if (sum[j] != 0)
        ans += (pow(b, i) * sum[j]);
      i++;
      j--;
    }
    printf("%d %d\n", n, ans);
  }
  return 0;
}
```