ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GetCode_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  cmpl   $0x0,-0x20(%rbp)
  je     L6
  movl   $0x0,D191(%rip)
  movl   $0x0,D177(%rip)
  movl   $0x0,D220(%rip)
  mov    $0x0,%eax
  jmp    L33
L6:
  mov    D191(%rip),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    D177(%rip),%eax
  cmp    %eax,%edx
  jl     L47
  mov    D220(%rip),%eax
  test   %eax,%eax
  je     L40
  mov    $0xffffffff,%eax
  jmp    L33
L40:
  mov    D77(%rip),%eax
  sub    $0x2,%eax
  cltq
  lea    D167(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,D151(%rip)
  mov    D77(%rip),%eax
  sub    $0x1,%eax
  cltq
  lea    D151(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  mov    %al,D151(%rip)
  mov    -0x18(%rbp),%rax
  lea    D46(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <GetDataBlock@plt>
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xd(%rbp)
  jne    L12
  movl   $0x1,D220(%rip)
L12:
  movzbl -0xd(%rbp),%eax
  add    $0x2,%eax
  mov    %eax,D142(%rip)
  mov    D191(%rip),%eax
  mov    D177(%rip),%edx
  sub    %edx,%eax
  add    $0x10,%eax
  mov    %eax,D142(%rip)
  movzbl -0xd(%rbp),%eax
  add    $0x2,%eax
  shl    $0x3,%eax
  mov    %eax,D142(%rip)
L47:
  movl   $0x0,-0x4(%rbp)
  mov    D142(%rip),%eax
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L38
L50:
  mov    -0xc(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  cltq
  lea    D151(%rip),%rdx
  movzbl (%rax,%rdx,1),%eax
  movzbl %al,%edx
  mov    -0xc(%rbp),%eax
  and    $0x7,%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  setne  %al
  movzbl %al,%edx
  mov    -0x8(%rbp),%eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0x4(%rbp)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x8(%rbp)
L38:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L50
  mov    D142(%rip),%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  mov    %eax,D142(%rip)
  mov    -0x4(%rbp),%eax
L33:
  leave
  ret
```

assistant: ```c
int GetCode_(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<GetCode_>:
  endbr64
  test   %edx,%edx
  jne    L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %esi,%eax
  add    D100(%rip),%eax
  cmp    D123(%rip),%eax
  jl     L48
  cmpl   $0x0,D35(%rip)
  jne    L26
  mov    D45(%rip),%eax
  lea    D65(%rip),%rcx
  lea    -0x2(%rax),%edx
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,D161(%rip)
  sub    $0x1,%eax
  cltq
  movzbl (%rcx,%rax,1),%eax
  mov    %al,D161(%rip)
  lea    0x2(%rcx),%rsi
  call   <GetDataBlock@plt>
  test   %al,%al
  jne    L59
  movl   $0x1,D35(%rip)
L59:
  movzbl %al,%eax
  add    $0x2,%eax
  mov    %eax,D176(%rip)
  mov    D100(%rip),%edx
  sub    D123(%rip),%edx
  add    $0x10,%edx
  mov    %edx,D176(%rip)
  shl    $0x3,%eax
  mov    %eax,D176(%rip)
L48:
  mov    D176(%rip),%esi
  test   %ebp,%ebp
  jle    L71
  mov    %ebx,%edx
  lea    D161(%rip),%rdi
L79:
  lea    (%rbx,%rsi,1),%ecx
  lea    0x7(%rcx),%eax
  test   %ecx,%ecx
  cmovns %ecx,%eax
  sar    $0x3,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  and    $0x7,%ecx
  sar    %cl,%eax
  and    $0x1,%eax
  mov    %ebx,%ecx
  shl    %cl,%eax
  or     %eax,%edx
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L79
L12:
  add    %esi,%ebp
  mov    %ebp,D176(%rip)
L21:
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  movl   $0x0,D176(%rip)
  movl   $0x0,D176(%rip)
  movl   $0x0,D35(%rip)
  mov    $0x0,%edx
  mov    %edx,%eax
  ret
L71:
  mov    %ebx,%edx
  jmp    L12
L26:
  mov    $0xffffffff,%edx
  jmp    L21
```

assistant: ```c
int GetCode_(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<GetCode_>:
  endbr64
  test   %edx,%edx
  jne    L25
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D4(%rip),%esi
  lea    (%rsi,%rbx,1),%r8d
  cmp    D3(%rip),%r8d
  jge    L48
L32:
  test   %ebx,%ebx
  jle    L60
  xor    %edx,%edx
  lea    D88(%rip),%rdi
  cs nopw 0x0(%rax,%rax,1)
L77:
  lea    (%rdx,%rsi,1),%ecx
  test   %ecx,%ecx
  lea    0x7(%rcx),%eax
  cmovns %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  and    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%ebp
  cmp    %edx,%ebx
  jne    L77
L60:
  mov    %r8d,D143(%rip)
  mov    %ebp,%eax
L49:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    D143(%rip),%eax
  test   %eax,%eax
  jne    L23
  mov    D28(%rip),%eax
  mov    %rdi,%r9
  lea    D88(%rip),%rdi
  lea    0x2(%rdi),%rsi
  lea    -0x2(%rax),%edx
  sub    $0x1,%eax
  movslq %edx,%rdx
  cltq
  movzbl (%rdi,%rdx,1),%edx
  mov    %dl,D84(%rip)
  movzbl (%rdi,%rax,1),%eax
  mov    %r9,%rdi
  mov    %al,D84(%rip)
  call   <GetDataBlock@plt>
  test   %al,%al
  jne    L2
  movl   $0x1,D143(%rip)
L2:
  movzbl %al,%eax
  mov    D143(%rip),%esi
  sub    D3(%rip),%esi
  add    $0x2,%eax
  add    $0x10,%esi
  mov    %eax,D10(%rip)
  shl    $0x3,%eax
  lea    (%rsi,%rbx,1),%r8d
  mov    %eax,D10(%rip)
  jmp    L32
  nopl   0x0(%rax)
L25:
  movl   $0x0,D143(%rip)
  xor    %eax,%eax
  movl   $0x0,D10(%rip)
  movl   $0x0,D143(%rip)
  ret
L23:
  mov    $0xffffffff,%eax
  jmp    L49
```

assistant: ```c
int GetCode_(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<GetCode_>:
  endbr64
  test   %edx,%edx
  jne    L64
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  mov    D151(%rip),%esi
  lea    (%rsi,%rbx,1),%r8d
  cmp    D48(%rip),%r8d
  jge    L48
L24:
  test   %ebx,%ebx
  jle    L22
  xor    %edx,%edx
  lea    D110(%rip),%rdi
  cs nopw 0x0(%rax,%rax,1)
L70:
  lea    (%rsi,%rdx,1),%ecx
  test   %ecx,%ecx
  lea    0x7(%rcx),%eax
  cmovns %ecx,%eax
  and    $0x7,%ecx
  sar    $0x3,%eax
  cltq
  movzbl (%rdi,%rax,1),%eax
  sar    %cl,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  and    $0x1,%eax
  shl    %cl,%eax
  or     %eax,%ebp
  cmp    %edx,%ebx
  jne    L70
L22:
  mov    %r8d,D99(%rip)
  mov    %ebp,%eax
L59:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L48:
  mov    D99(%rip),%eax
  test   %eax,%eax
  jne    L33
  mov    D41(%rip),%eax
  mov    %rdi,%r9
  lea    D110(%rip),%rdi
  lea    0x2(%rdi),%rsi
  lea    -0x2(%rax),%edx
  sub    $0x1,%eax
  movslq %edx,%rdx
  cltq
  movzbl (%rdi,%rdx,1),%edx
  mov    %dl,D82(%rip)
  movzbl (%rdi,%rax,1),%eax
  mov    %r9,%rdi
  mov    %al,D82(%rip)
  call   <GetDataBlock@plt>
  test   %al,%al
  jne    L12
  movl   $0x1,D99(%rip)
L12:
  movzbl %al,%eax
  mov    D99(%rip),%esi
  sub    D48(%rip),%esi
  add    $0x2,%eax
  add    $0x10,%esi
  mov    %eax,D130(%rip)
  shl    $0x3,%eax
  lea    (%rsi,%rbx,1),%r8d
  mov    %eax,D130(%rip)
  jmp    L24
  nopl   0x0(%rax)
L64:
  movl   $0x0,D99(%rip)
  xor    %eax,%eax
  movl   $0x0,D130(%rip)
  movl   $0x0,D99(%rip)
  ret
L33:
  mov    $0xffffffff,%eax
  jmp    L59
```

assistant: ```c
int GetCode_(FILE *fd, int code_size, int flag) {
  static unsigned char buf[280];
  static int curbit, lastbit, done, last_byte;
  int i, j, ret;
  unsigned char count;
  if (flag) {
    curbit = 0;
    lastbit = 0;
    done = 0;
    return 0;
  }
  if ((curbit + code_size) >= lastbit) {
    if (done) {
      if (curbit >= lastbit) {
      }
      return -1;
    }
    buf[0] = buf[last_byte - 2];
    buf[1] = buf[last_byte - 1];
    if ((count = GetDataBlock(fd, &buf[2])) == 0)
      done = 1;
    last_byte = 2 + count;
    curbit = (curbit - lastbit) + 16;
    lastbit = (2 + count) * 8;
  }
  ret = 0;
  for (i = curbit, j = 0; j < code_size; ++i, ++j)
    ret |= ((buf[i / 8] & (1 << (i % 8))) != 0) << j;
  curbit += code_size;
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintNumber>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  cmpl   $0x3e7,-0x24(%rbp)
  jg     L46
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
L46:
  movq   $0x1,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x18(%rbp)
  jmp    L21
L13:
  mov    -0x18(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  imul   $0x3e8,%rax,%rax
  mov    %rax,-0x10(%rbp)
L21:
  cmpq   $0x3e7,-0x18(%rbp)
  jg     L13
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  imul   -0x10(%rbp),%rax
  mov    %rax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L5:
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  imul   -0x10(%rbp),%rax
  sub    %rax,-0x18(%rbp)
  mov    -0x10(%rbp),%rcx
  movabs $0x20c49ba5e353f7cf,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x7,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x10(%rbp)
L2:
  cmpq   $0x1,-0x10(%rbp)
  jg     L5
  mov    -0x18(%rbp),%rax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string
name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D28
datatype: string

tool: D3: %d

tool: D1: %d,

tool: D20: %03d,

tool: D28: %03d

assistant: ```c
void PrintNumber(int number) {
  long long num, denom, quot;
  if (number < 1000) {
    printf("%d", (int)number);
    return;
  }
  denom = 1;
  num = number;
  while (num >= 1000) {
    num /= 1000;
    denom *= 1000;
  }
  printf("%d,", (int)num);
  num = (number - num * denom);
  denom /= 1000;
  while (denom > 1) {
    quot = (num / denom);
    printf("%03d,", (int)quot);
    num -= (quot * denom);
    denom /= 1000;
  }
  printf("%03d", (int)num);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintNumber>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%esi
  cmp    $0x3e7,%edi
  jle    L48
  movslq %edi,%rbp
  mov    %rbp,%r12
  mov    $0x1,%r13d
  movabs $0x20c49ba5e353f7cf,%rsi
L19:
  mov    %r12,%rcx
  mov    %r12,%rax
  imul   %rsi
  sar    $0x7,%rdx
  mov    %r12,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%r12
  mov    %r13,%rbx
  imul   $0x3e8,%r13,%r13
  cmp    $0xf423f,%rcx
  jg     L19
  mov    %edx,%esi
  lea    D23(%rip),%rdi
  call   <printf@plt>
  imul   %r13,%r12
  mov    %rbp,%rsi
  sub    %r12,%rsi
  cmp    $0x1,%rbx
  jle    L39
  lea    D29(%rip),%r12
  movabs $0x20c49ba5e353f7cf,%rbp
L5:
  mov    %rsi,%rax
  cqto
  idiv   %rbx
  mov    %rdx,%r13
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbx,%rcx
  mov    %rbx,%rax
  imul   %rbp
  sar    $0x7,%rdx
  mov    %rbx,%rax
  sar    $0x3f,%rax
  mov    %rdx,%rbx
  sub    %rax,%rbx
  cmp    $0x7cf,%rcx
  jg     L5
L39:
  lea    D14(%rip),%rdi
  call   <printf@plt>
L25:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L25
```

tool_calls: name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D29
type_guessed: string
name: read_data
arguments: tag: D14
type_guessed: string
name: read_data
arguments: tag: D34
type_guessed: string

tool: D23: %d,

tool: D29: %03d,

tool: D14: %03d

tool: D34: %d

assistant: ```c
void PrintNumber(int number) {
  long long num, denom, quot;
  if (number < 1000) {
    printf("%d", (int)number);
    return;
  }
  denom = 1;
  num = number;
  while (num >= 1000) {
    num /= 1000;
    denom *= 1000;
  }
  printf("%d,", (int)num);
  num = (number - num * denom);
  denom /= 1000;
  while (denom > 1) {
    quot = (num / denom);
    printf("%03d,", (int)quot);
    num -= (quot * denom);
    denom /= 1000;
  }
  printf("%03d", (int)num);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PrintNumber>:
  endbr64
  cmp    $0x3e7,%edi
  jle    L20
  movabs $0x20c49ba5e353f7cf,%rsi
  push   %r13
  movslq %edi,%r13
  push   %r12
  mov    %r13,%rdx
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
L29:
  mov    %rdx,%rbp
  mov    %rdx,%rcx
  mov    %r12,%rbx
  shr    $0x3,%rbp
  imul   $0x3e8,%r12,%r12
  mov    %rbp,%rax
  mul    %rsi
  shr    $0x4,%rdx
  cmp    $0xf423f,%rcx
  jg     L29
  mov    %edx,%esi
  lea    D34(%rip),%rdi
  mov    %rdx,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  imul   %r12,%rdx
  sub    %rdx,%rsi
  cmp    $0x1,%rbx
  je     L16
  lea    D25(%rip),%r12
  movabs $0x20c49ba5e353f7cf,%rbp
L31:
  mov    %rsi,%rax
  mov    %r12,%rdi
  cqto
  idiv   %rbx
  mov    %rax,%rsi
  mov    %rdx,%r13
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rcx
  mov    %r13,%rsi
  shr    $0x3,%rdx
  mov    %rdx,%rax
  mul    %rbp
  mov    %rdx,%rbx
  shr    $0x4,%rbx
  cmp    $0x7cf,%rcx
  jg     L31
L16:
  add    $0x18,%rsp
  lea    D4(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
  nop
L20:
  mov    %edi,%esi
  lea    D1(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D34
datatype: string
name: read_data
arguments: tag: D25
datatype: string
name: read_data
arguments: tag: D4
datatype: string
name: read_data
arguments: tag: D1
datatype: string

tool: D34: %d,

tool: D25: %03d,

tool: D4: %03d

tool: D1: %d

assistant: ```c
void PrintNumber(int number) {
  long long num, denom, quot;
  if (number < 1000) {
    printf("%d", (int)number);
    return;
  }
  denom = 1;
  num = number;
  while (num >= 1000) {
    num /= 1000;
    denom *= 1000;
  }
  printf("%d,", (int)num);
  num = (number - num * denom);
  denom /= 1000;
  while (denom > 1) {
    quot = (num / denom);
    printf("%03d,", (int)quot);
    num -= (quot * denom);
    denom /= 1000;
  }
  printf("%03d", (int)num);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PrintNumber>:
  endbr64
  cmp    $0x3e7,%edi
  jle    L9
  movabs $0x20c49ba5e353f7cf,%rsi
  push   %r13
  movslq %edi,%r13
  push   %r12
  mov    %r13,%rdx
  mov    $0x1,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
L28:
  mov    %rdx,%rbp
  mov    %rdx,%rcx
  mov    %r12,%rbx
  shr    $0x3,%rbp
  imul   $0x3e8,%r12,%r12
  mov    %rbp,%rax
  mul    %rsi
  shr    $0x4,%rdx
  cmp    $0xf423f,%rcx
  jg     L28
  mov    %edx,%esi
  lea    D0(%rip),%rdi
  mov    %rdx,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rdx
  mov    %r13,%rsi
  imul   %r12,%rdx
  sub    %rdx,%rsi
  cmp    $0x1,%rbx
  je     L36
  lea    D24(%rip),%r12
  movabs $0x20c49ba5e353f7cf,%rbp
L4:
  mov    %rsi,%rax
  mov    %r12,%rdi
  cqto
  idiv   %rbx
  mov    %rax,%rsi
  mov    %rdx,%r13
  call   <printf@plt>
  mov    %rbx,%rdx
  mov    %rbx,%rcx
  mov    %r13,%rsi
  shr    $0x3,%rdx
  mov    %rdx,%rax
  mul    %rbp
  mov    %rdx,%rbx
  shr    $0x4,%rbx
  cmp    $0x7cf,%rcx
  jg     L4
L36:
  add    $0x18,%rsp
  lea    D39(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <printf@plt>
  nop
L9:
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D0
type: string
name: parse_data
arguments: tag: D24
type: string
name: parse_data
arguments: tag: D39
type: string
name: parse_data
arguments: tag: D2
type: string

tool: D0: %d,

tool: D24: %03d,

tool: D39: %03d

tool: D2: %d

assistant: ```c
void PrintNumber(int number) {
  long long num, denom, quot;
  if (number < 1000) {
    printf("%d", (int)number);
    return;
  }
  denom = 1;
  num = number;
  while (num >= 1000) {
    num /= 1000;
    denom *= 1000;
  }
  printf("%d,", (int)num);
  num = (number - num * denom);
  denom /= 1000;
  while (denom > 1) {
    quot = (num / denom);
    printf("%03d,", (int)quot);
    num -= (quot * denom);
    denom /= 1000;
  }
  printf("%03d", (int)num);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<assign_dobldobl_coefficient_of_slice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  mov    -0x20(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x279,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int assign_dobldobl_coefficient_of_slice(int i, int j, double *r) {
  int fail;
  fail = _ada_use_c2phc(633, &i, &j, r);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<assign_dobldobl_coefficient_of_slice>:
  endbr64
  sub    $0x18,%rsp
  mov    %edi,0xc(%rsp)
  mov    %esi,0x8(%rsp)
  mov    %rdx,%rcx
  lea    0x8(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  mov    $0x279,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int assign_dobldobl_coefficient_of_slice(int i, int j, double *r) {
  int fail;
  fail = _ada_use_c2phc(633, &i, &j, r);
  return fail;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<assign_dobldobl_coefficient_of_slice>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdx,%rcx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x279,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int assign_dobldobl_coefficient_of_slice(int i, int j, double *r) {
  int fail;
  fail = _ada_use_c2phc(633, &i, &j, r);
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<assign_dobldobl_coefficient_of_slice>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdx,%rcx
  mov    %edi,0xc(%rsp)
  lea    0x8(%rsp),%rdx
  mov    $0x279,%edi
  mov    %esi,0x8(%rsp)
  lea    0xc(%rsp),%rsi
  call   <_ada_use_c2phc@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
int assign_dobldobl_coefficient_of_slice(int i, int j, double *r) {
  int fail;
  fail = _ada_use_c2phc(633, &i, &j, r);
  return fail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_three>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int print_three(char *s) {
  printf(s);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_three>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int print_three(char *s) {
  printf(s);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_three>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int print_three(char *s) {
  printf(s);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_three>:
  endbr64
  sub    $0x8,%rsp
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int print_three(char *s) {
  printf(s);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<trans>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r9d
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1e,%eax
  lea    (%rsi,%rax,1),%r8d
  and    $0x3,%r8d
  sub    %eax,%r8d
  mov    %esi,%edx
  sub    %r8d,%edx
  test   %edx,%edx
  jle    L38
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edi
  shr    $0x2,%edi
  mov    %edi,%edx
  lea    0x4(%r10,%rdx,4),%rsi
L24:
  movzbl (%rax),%edx
  movzbl 0x2(%rax),%ecx
  mov    %cl,(%rax)
  mov    %dl,0x2(%rax)
  movzbl 0x1(%rax),%edx
  movzbl 0x3(%rax),%ecx
  mov    %cl,0x1(%rax)
  mov    %dl,0x3(%rax)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L24
  lea    0x4(,%rdi,4),%eax
L21:
  test   $0x3,%r9b
  je     L57
  cmp    $0x2,%r8d
  je     L16
  cmp    $0x3,%r8d
  je     L52
  ret
L38:
  mov    $0x0,%eax
  jmp    L21
L16:
  cltq
  lea    (%r10,%rax,1),%rdx
  movzbl (%rdx),%ecx
  lea    0x1(%r10,%rax,1),%rax
  movzbl (%rax),%esi
  mov    %sil,(%rdx)
  mov    %cl,(%rax)
  ret
L52:
  cltq
  lea    (%r10,%rax,1),%rdx
  movzbl (%rdx),%ecx
  lea    0x2(%r10,%rax,1),%rax
  movzbl (%rax),%esi
  mov    %sil,(%rdx)
  mov    %cl,(%rax)
L57:
  ret
```

assistant: ```c
void trans(char *text, int textLength) {
  char temp;
  int i;
  int lastQuad = textLength % 4;
  for (i = 0; i < (textLength - lastQuad); i += 4) {
    temp = text[i];
    text[i] = text[i + 2];
    text[i + 2] = temp;
    temp = text[i + 1];
    text[i + 1] = text[i + 3];
    text[i + 3] = temp;
  }
  if (lastQuad != 0)
    switch (lastQuad) {
    case 1:
      break;
    case 2:
      temp = text[i];
      text[i] = text[i + 1];
      text[i + 1] = temp;
      break;
    case 3:
      temp = text[i];
      text[i] = text[i + 2];
      text[i + 2] = temp;
      break;
    }
}
```