ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ne_test_plbpc>:
  endbr64
  sub    $0x158,%rsp
  movdqa D133(%rip),%xmm6
  movdqa D121(%rip),%xmm5
  mov    %fs:0x28,%rax
  mov    %rax,0x148(%rsp)
  xor    %eax,%eax
  mov    D133(%rip),%rax
  movdqa D68(%rip),%xmm4
  lea    0x60(%rsp),%rcx
  movdqa D90(%rip),%xmm3
  movaps %xmm6,(%rsp)
  mov    %rsp,%rsi
  movdqa D12(%rip),%xmm2
  mov    %rax,0x20(%rsp)
  mov    D121(%rip),%rax
  lea    0x30(%rsp),%rdx
  movdqa D67(%rip),%xmm1
  movdqa D103(%rip),%xmm0
  movaps %xmm5,0x30(%rsp)
  mov    %rax,0x50(%rsp)
  mov    D68(%rip),%rax
  movaps %xmm4,0x60(%rsp)
  mov    %rax,0x80(%rsp)
  mov    D90(%rip),%rax
  movaps %xmm3,0x90(%rsp)
  movaps %xmm2,0xc0(%rsp)
  movaps %xmm1,0xf0(%rsp)
  movaps %xmm0,0x120(%rsp)
  movaps %xmm6,0x10(%rsp)
  movaps %xmm5,0x40(%rsp)
  movaps %xmm4,0x70(%rsp)
  movaps %xmm3,0xa0(%rsp)
  movaps %xmm2,0xd0(%rsp)
  movaps %xmm1,0x100(%rsp)
  movaps %xmm0,0x130(%rsp)
  mov    %rax,0xb0(%rsp)
  mov    D12(%rip),%rax
  mov    %rax,0xe0(%rsp)
  mov    D67(%rip),%rax
  mov    %rax,0x110(%rsp)
  mov    D103(%rip),%rax
  mov    %rax,0x140(%rsp)
  lea    0x120(%rsp),%rax
  push   %rax
  lea    0xf8(%rsp),%rax
  push   %rax
  lea    0xd0(%rsp),%r9
  lea    0xa0(%rsp),%r8
  call   <ne_put_loadbal_param_cc@plt>
  pop    %rdx
  pop    %rcx
  mov    0x148(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x158,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D133
datatype: byte[16]
name: read_data
arguments: label: D121
datatype: byte[16]
name: read_data
arguments: label: D68
datatype: byte[16]
name: read_data
arguments: label: D90
datatype: byte[16]
name: read_data
arguments: label: D12
datatype: byte[16]
name: read_data
arguments: label: D67
datatype: byte[16]
name: read_data
arguments: label: D103
datatype: byte[16]

tool: {"D133": [0xc8,0x00,0x00,0x00,0xc8,0x00,0x00,0x00,0xc8,0x00,0x00,0x00,0xc8,0x00,0x00,0x00]}

tool: {"D121": [0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0a,0x00,0x00,0x00]}

tool: {"D68": [0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D90": [0x64,0x00,0x00,0x00,0x64,0x00,0x00,0x00,0x64,0x00,0x00,0x00,0x64,0x00,0x00,0x00]}

tool: {"D12": [0x14,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x14,0x00,0x00,0x00,0x14,0x00,0x00,0x00]}

tool: {"D67": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D103": [0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int ne_test_plbpc(int fileid) {
  int iproc;
  int num_int_nodes[10], num_bor_nodes[10], num_ext_nodes[10];
  int num_int_elems[10], num_bor_elems[10];
  int num_node_cmaps[10], num_elem_cmaps[10];
  for (iproc = 0; iproc < 10; iproc++) {
    num_int_nodes[iproc] = 200;
    num_bor_nodes[iproc] = 10;
    num_ext_nodes[iproc] = 5;
    num_int_elems[iproc] = 100;
    num_bor_elems[iproc] = 20;
    num_node_cmaps[iproc] = 4;
    num_elem_cmaps[iproc] = 2;
  }
  return (ne_put_loadbal_param_cc(fileid, num_int_nodes, num_bor_nodes, num_ext_nodes, num_int_elems, num_bor_elems, num_node_cmaps, num_elem_cmaps));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<radiNesto>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L8
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  add    %ecx,%edx
  mov    %edx,(%rax)
  addl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void radiNesto(int n, int a[]) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] += i;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<radiNesto>:
  endbr64
  test   %edi,%edi
  jle    L7
  mov    %edi,%edi
  mov    $0x0,%eax
L18:
  add    %eax,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L18
L7:
  ret
```

assistant: ```c
void radiNesto(int n, int a[]) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] += i;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<radiNesto>:
  endbr64
  test   %edi,%edi
  jle    L4
  movslq %edi,%rdi
  xor    %eax,%eax
  nopl   (%rax)
L0:
  add    %eax,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L0
L4:
  ret
```

assistant: ```c
void radiNesto(int n, int a[]) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] += i;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<radiNesto>:
  endbr64
  test   %edi,%edi
  jle    L33
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L16
  mov    %edi,%edx
  movdqa D7(%rip),%xmm1
  movdqa D9(%rip),%xmm2
  mov    %rsi,%rax
  shr    $0x2,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rsi,%rdx,1),%rdx
  nopl   0x0(%rax)
L54:
  movdqu (%rax),%xmm3
  movdqa %xmm1,%xmm0
  add    $0x10,%rax
  paddd  %xmm2,%xmm1
  paddd  %xmm3,%xmm0
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L54
  mov    %edi,%edx
  and    $0xfffffffc,%edx
  test   $0x3,%dil
  je     L21
L27:
  movslq %edx,%rax
  lea    0x1(%rdx),%ecx
  shl    $0x2,%rax
  add    %edx,(%rsi,%rax,1)
  cmp    %ecx,%edi
  jle    L33
  add    $0x2,%edx
  add    %ecx,0x4(%rsi,%rax,1)
  cmp    %edx,%edi
  jle    L33
  add    %edx,0x8(%rsi,%rax,1)
L33:
  ret
  nopl   0x0(%rax)
L21:
  ret
L16:
  xor    %edx,%edx
  jmp    L27
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: byte[16]
name: extract_symbolic_data
arguments: data_tag: D9
data_type: byte[16]

tool: {"D7": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D9": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

assistant: ```c
void radiNesto(int n, int a[]) {
  int i;
  for (i = 0; i < n; i++) {
    a[i] += i;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<transition>:
  endbr64
  mov    %rsi,%r9
  mov    %edx,%esi
  mov    %r8d,%eax
  cltd
  idiv   %esi
  pxor   %xmm2,%xmm2
  test   %eax,%eax
  jle    L28
  mov    %r8d,%r10d
  sub    %esi,%r10d
  movslq %r10d,%r10
  cmpl   $0x0,(%rdi,%r10,4)
  je     L28
  movsd  (%r9,%r10,8),%xmm2
L28:
  add    $0x1,%eax
  pxor   %xmm4,%xmm4
  cmp    %ecx,%eax
  jge    L35
  lea    (%r8,%rsi,1),%eax
  cltq
  cmpl   $0x0,(%rdi,%rax,4)
  je     L35
  movsd  (%r9,%rax,8),%xmm4
L35:
  pxor   %xmm1,%xmm1
  test   %edx,%edx
  jle    L20
  movslq %r8d,%rax
  cmpl   $0x0,-0x4(%rdi,%rax,4)
  je     L20
  movsd  -0x8(%r9,%rax,8),%xmm1
L20:
  add    $0x1,%edx
  pxor   %xmm3,%xmm3
  cmp    %esi,%edx
  jge    L39
  movslq %r8d,%rax
  lea    0x1(%rax),%rdx
  cmpl   $0x0,0x4(%rdi,%rax,4)
  je     L39
  movsd  (%r9,%rdx,8),%xmm3
L39:
  movslq %r8d,%r8
  testl  $0xfffffffd,(%rdi,%r8,4)
  je     L70
  movapd %xmm2,%xmm0
  addsd  %xmm4,%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm3,%xmm0
  pxor   %xmm5,%xmm5
  comisd %xmm5,%xmm2
  seta   %al
  movzbl %al,%eax
  comisd %xmm5,%xmm4
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  comisd %xmm5,%xmm1
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  comisd %xmm5,%xmm3
  seta   %dl
  movzbl %dl,%edx
  add    %edx,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  ret
L70:
  movsd  (%r9,%r8,8),%xmm0
  ret
```

assistant: ```c
double transition(int *B, double *T, int nx, int ny, int cell) {
  int row = 0, col = 0;
  row = cell / nx, col = cell % nx;
  double up = (row - 1 < 0 || B[cell - nx] == 0) ? 0 : T[cell - nx];
  double down = (row + 1 >= ny || B[cell + nx] == 0) ? 0 : T[cell + nx];
  double left = (col - 1 < 0 || B[cell - 1] == 0) ? 0 : T[cell - 1];
  double right = (col + 1 >= nx || B[cell + 1] == 0) ? 0 : T[cell + 1];
  double sum = ((up > 0) ? 1 : 0) + ((down > 0) ? 1 : 0) + ((left > 0) ? 1 : 0) + ((right > 0) ? 1 : 0);
  double Tij = (up + down + left + right) / sum;
  return (B[cell] == 0 || B[cell] == 2) ? T[cell] : Tij;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transition>:
  endbr64
  mov    %r8d,%eax
  mov    %rsi,%r9
  mov    %edx,%esi
  cltd
  idiv   %esi
  test   %eax,%eax
  jle    L86
  mov    %r8d,%r11d
  sub    %esi,%r11d
  movslq %r11d,%r11
  mov    (%rdi,%r11,4),%r10d
  test   %r10d,%r10d
  jne    L35
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
L34:
  add    $0x1,%eax
  movapd %xmm0,%xmm4
  cmp    %ecx,%eax
  jge    L76
  lea    (%r8,%rsi,1),%eax
  cltq
  mov    (%rdi,%rax,4),%r11d
  test   %r11d,%r11d
  je     L76
  movsd  (%r9,%rax,8),%xmm4
  xor    %eax,%eax
  comisd %xmm0,%xmm4
  seta   %al
  add    %eax,%r10d
L76:
  movslq %r8d,%r8
  movapd %xmm0,%xmm2
  lea    0x0(,%r8,4),%rax
  test   %edx,%edx
  jle    L15
  mov    -0x4(%rdi,%rax,1),%ecx
  test   %ecx,%ecx
  je     L15
  movsd  -0x8(%r9,%r8,8),%xmm2
  xor    %ecx,%ecx
  comisd %xmm0,%xmm2
  seta   %cl
  add    %ecx,%r10d
L15:
  add    $0x1,%edx
  movapd %xmm0,%xmm3
  cmp    %esi,%edx
  jge    L13
  mov    0x4(%rdi,%rax,1),%eax
  lea    0x1(%r8),%rdx
  test   %eax,%eax
  je     L13
  movsd  (%r9,%rdx,8),%xmm3
  xor    %eax,%eax
  comisd %xmm0,%xmm3
  seta   %al
  add    %eax,%r10d
L13:
  testl  $0xfffffffd,(%rdi,%r8,4)
  je     L102
  addsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r10d,%xmm1
  divsd  %xmm1,%xmm0
  ret
L35:
  movsd  (%r9,%r11,8),%xmm1
  pxor   %xmm0,%xmm0
  xor    %r10d,%r10d
  comisd %xmm0,%xmm1
  seta   %r10b
  jmp    L34
  nopw   0x0(%rax,%rax,1)
L102:
  movsd  (%r9,%r8,8),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  pxor   %xmm0,%xmm0
  xor    %r10d,%r10d
  movapd %xmm0,%xmm1
  jmp    L34
```

assistant: ```c
double transition(int *B, double *T, int nx, int ny, int cell) {
  int row = 0, col = 0;
  row = cell / nx, col = cell % nx;
  double up = (row - 1 < 0 || B[cell - nx] == 0) ? 0 : T[cell - nx];
  double down = (row + 1 >= ny || B[cell + nx] == 0) ? 0 : T[cell + nx];
  double left = (col - 1 < 0 || B[cell - 1] == 0) ? 0 : T[cell - 1];
  double right = (col + 1 >= nx || B[cell + 1] == 0) ? 0 : T[cell + 1];
  double sum = ((up > 0) ? 1 : 0) + ((down > 0) ? 1 : 0) + ((left > 0) ? 1 : 0) + ((right > 0) ? 1 : 0);
  double Tij = (up + down + left + right) / sum;
  return (B[cell] == 0 || B[cell] == 2) ? T[cell] : Tij;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<transition>:
  endbr64
  mov    %r8d,%eax
  mov    %rsi,%r9
  mov    %edx,%esi
  cltd
  idiv   %esi
  test   %eax,%eax
  jle    L64
  mov    %r8d,%r11d
  sub    %esi,%r11d
  movslq %r11d,%r11
  mov    (%rdi,%r11,4),%r10d
  test   %r10d,%r10d
  jne    L45
  pxor   %xmm0,%xmm0
  movapd %xmm0,%xmm1
L84:
  add    $0x1,%eax
  movapd %xmm0,%xmm4
  cmp    %ecx,%eax
  jge    L49
  lea    (%r8,%rsi,1),%eax
  cltq
  mov    (%rdi,%rax,4),%r11d
  test   %r11d,%r11d
  je     L49
  movsd  (%r9,%rax,8),%xmm4
  xor    %eax,%eax
  comisd %xmm0,%xmm4
  seta   %al
  add    %eax,%r10d
L49:
  movslq %r8d,%r8
  movapd %xmm0,%xmm2
  lea    0x0(,%r8,4),%rax
  test   %edx,%edx
  jle    L90
  mov    -0x4(%rdi,%rax,1),%ecx
  test   %ecx,%ecx
  je     L90
  movsd  -0x8(%r9,%r8,8),%xmm2
  xor    %ecx,%ecx
  comisd %xmm0,%xmm2
  seta   %cl
  add    %ecx,%r10d
L90:
  add    $0x1,%edx
  movapd %xmm0,%xmm3
  cmp    %esi,%edx
  jge    L75
  mov    0x4(%rdi,%rax,1),%eax
  lea    0x1(%r8),%rdx
  test   %eax,%eax
  je     L75
  movsd  (%r9,%rdx,8),%xmm3
  xor    %eax,%eax
  comisd %xmm0,%xmm3
  seta   %al
  add    %eax,%r10d
L75:
  testl  $0xfffffffd,(%rdi,%r8,4)
  je     L109
  addsd  %xmm4,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r10d,%xmm1
  divsd  %xmm1,%xmm0
  ret
L45:
  movsd  (%r9,%r11,8),%xmm1
  pxor   %xmm0,%xmm0
  xor    %r10d,%r10d
  comisd %xmm0,%xmm1
  seta   %r10b
  jmp    L84
  nopw   0x0(%rax,%rax,1)
L109:
  movsd  (%r9,%r8,8),%xmm0
  ret
  nopw   0x0(%rax,%rax,1)
L64:
  pxor   %xmm0,%xmm0
  xor    %r10d,%r10d
  movapd %xmm0,%xmm1
  jmp    L84
```

assistant: ```c
double transition(int *B, double *T, int nx, int ny, int cell) {
  int row = 0, col = 0;
  row = cell / nx, col = cell % nx;
  double up = (row - 1 < 0 || B[cell - nx] == 0) ? 0 : T[cell - nx];
  double down = (row + 1 >= ny || B[cell + nx] == 0) ? 0 : T[cell + nx];
  double left = (col - 1 < 0 || B[cell - 1] == 0) ? 0 : T[cell - 1];
  double right = (col + 1 >= nx || B[cell + 1] == 0) ? 0 : T[cell + 1];
  double sum = ((up > 0) ? 1 : 0) + ((down > 0) ? 1 : 0) + ((left > 0) ? 1 : 0) + ((right > 0) ? 1 : 0);
  double Tij = (up + down + left + right) / sum;
  return (B[cell] == 0 || B[cell] == 2) ? T[cell] : Tij;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  nop
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  nop
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <bla@plt>
  nop
  leave
  ret
```

assistant: ```c
void foo(void) {
  int k;
  goto forward;
back:
  bla(k);
  return;
forward : {
  int i = bar();
  k = i;
  goto back;
}
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bar@plt>
  mov    %eax,%edi
  call   <bla@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void foo(void) {
  int k;
  goto forward;
back:
  bla(k);
  return;
forward : {
  int i = bar();
  k = i;
  goto back;
}
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <bla@plt>
```

assistant: ```c
void foo(void) {
  int k;
  goto forward;
back:
  bla(k);
  return;
forward : {
  int i = bar();
  k = i;
  goto back;
}
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bar@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <bla@plt>
```

assistant: ```c
void foo(void) {
  int k;
  goto forward;
back:
  bla(k);
  return;
forward : {
  int i = bar();
  k = i;
  goto back;
}
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<primepow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L54:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L54
  sub    $0xc70,%rsp
  mov    %edi,-0x9c64(%rbp)
  mov    %esi,-0x9c68(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x9c58(%rbp)
  movl   $0x0,-0x9c54(%rbp)
  jmp    L10
L14:
  addl   $0x1,-0x9c58(%rbp)
  mov    -0x9c58(%rbp),%edx
  mov    -0x9c68(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    -0x9c64(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  mov    -0x9c58(%rbp),%eax
  cltq
  mov    %edx,-0x9c50(%rbp,%rax,4)
  mov    -0x9c58(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  add    %eax,-0x9c54(%rbp)
  mov    -0x9c58(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L46
L10:
  cmpl   $0x0,-0x9c58(%rbp)
  jns    L14
  jmp    L28
L46:
  nop
L28:
  mov    -0x9c54(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int primepow(int n, int p) {
  int j, k[10000], s;
  j = 0;
  s = 0;
  while (j >= 0) {
    ++j;
    k[j] = n / (pow(p, j));
    s = s + k[j];
    if (k[j] == 0) {
      break;
    }
  }
  return s;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<primepow>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%r13d
  mov    $0x0,%r12d
  mov    $0x0,%ebx
L5:
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %r13d,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  cltd
  idiv   %ecx
  add    %eax,%r12d
  test   %eax,%eax
  jne    L5
  mov    %r12d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int primepow(int n, int p) {
  int j, k[10000], s;
  j = 0;
  s = 0;
  while (j >= 0) {
    ++j;
    k[j] = n / (pow(p, j));
    s = s + k[j];
    if (k[j] == 0) {
      break;
    }
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<primepow>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L5:
  add    $0x1,%ebx
  mov    %r13d,%edi
  mov    %ebx,%esi
  call   <pow@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  add    %eax,%r12d
  test   %eax,%eax
  jne    L5
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int primepow(int n, int p) {
  int j, k[10000], s;
  j = 0;
  s = 0;
  while (j >= 0) {
    ++j;
    k[j] = n / (pow(p, j));
    s = s + k[j];
    if (k[j] == 0) {
      break;
    }
  }
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<primepow>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  add    $0x1,%ebx
  mov    %r13d,%edi
  mov    %ebx,%esi
  call   <pow@plt>
  mov    %eax,%r8d
  mov    %ebp,%eax
  cltd
  idiv   %r8d
  add    %eax,%r12d
  test   %eax,%eax
  jne    L6
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int primepow(int n, int p) {
  int j, k[10000], s;
  j = 0;
  s = 0;
  while (j >= 0) {
    ++j;
    k[j] = n / (pow(p, j));
    s = s + k[j];
    if (k[j] == 0) {
      break;
    }
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<emit_pop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <emit_basic_rex@plt>
  mov    -0xc(%rbp),%eax
  and    $0x7,%eax
  or     $0x58,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <emit1@plt>
  nop
  leave
  ret
```

assistant: ```c
void emit_pop(struct jit_state *state, int r) {
  emit_basic_rex(state, 0, 0, r);
  emit1(state, 0x58 | (r & 7));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<emit_pop>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  mov    %esi,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  call   <emit_basic_rex@plt>
  and    $0x7,%ebx
  mov    %ebx,%esi
  or     $0x58,%esi
  mov    %rbp,%rdi
  call   <emit1@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void emit_pop(struct jit_state *state, int r) {
  emit_basic_rex(state, 0, 0, r);
  emit1(state, 0x58 | (r & 7));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<emit_pop>:
  endbr64
  push   %rbp
  mov    %esi,%ecx
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  and    $0x7,%ebx
  sub    $0x8,%rsp
  call   <emit_basic_rex@plt>
  mov    %ebx,%esi
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  or     $0x58,%esi
  pop    %rbp
  jmp    1060 <emit1@plt>
```

assistant: ```c
void emit_pop(struct jit_state *state, int r) {
  emit_basic_rex(state, 0, 0, r);
  emit1(state, 0x58 | (r & 7));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<emit_pop>:
  endbr64
  push   %rbp
  mov    %esi,%ecx
  xor    %edx,%edx
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  xor    %esi,%esi
  and    $0x7,%ebx
  sub    $0x8,%rsp
  call   <emit_basic_rex@plt>
  mov    %ebx,%esi
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbx
  or     $0x58,%esi
  pop    %rbp
  jmp    1060 <emit1@plt>
```

assistant: ```c
void emit_pop(struct jit_state *state, int r) {
  emit_basic_rex(state, 0, 0, r);
  emit1(state, 0x58 | (r & 7));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<LVInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <initButtons@plt>
  mov    $0x0,%eax
  call   <initIME@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void LVInit() {
  initButtons();
  initIME();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<LVInit>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <initButtons@plt>
  mov    $0x0,%eax
  call   <initIME@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void LVInit() {
  initButtons();
  initIME();
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<LVInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initButtons@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <initIME@plt>
```

assistant: ```c
void LVInit() {
  initButtons();
  initIME();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<LVInit>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <initButtons@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <initIME@plt>
```

assistant: ```c
void LVInit() {
  initButtons();
  initIME();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<decode_spca561>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%esi
  mov    -0x24(%rbp),%eax
  lea    D8(%rip),%rcx
  mov    %eax,%edi
  call   <internal_spca561_decode@plt>
  test   %rax,%rax
  jne    L6
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0x24(%rbp),%eax
  add    $0x6,%eax
  imul   %edx,%eax
  cltq
  lea    0x3(%rax),%rdx
  lea    D8(%rip),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x4(%rbp),%eax
  imul   -0x24(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L15
L6:
  nop
  leave
  ret
```

assistant: ```c
void decode_spca561(unsigned char *inbuf, unsigned char *outbuf, int width, int height) {
  int i;
  static char tmpbuf[650 * 490];
  if (internal_spca561_decode(width, height, inbuf, (unsigned char *)tmpbuf) == 0) {
    for (i = 0; i < height; i++)
      memcpy(outbuf + i * width, tmpbuf + (i + 2) * (width + 6) + 3, width);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<decode_spca561>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %edx,%r13d
  mov    %ecx,%r14d
  lea    D8(%rip),%rcx
  mov    %rdi,%rdx
  mov    %r14d,%esi
  mov    %r13d,%edi
  call   <internal_spca561_decode@plt>
  test   %rax,%rax
  jne    L14
  test   %r14d,%r14d
  jle    L14
  movslq %r13d,%r15
  lea    0x6(%r15),%rax
  mov    %rax,0x8(%rsp)
  lea    0xc(%r13,%r13,1),%eax
  cltq
  lea    D8(%rip),%rdx
  lea    0x3(%rdx,%rax,1),%r12
  mov    $0x0,%ebp
L17:
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    $0x1,%ebp
  add    %r15,%rbx
  add    0x8(%rsp),%r12
  cmp    %ebp,%r14d
  jne    L17
L14:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void decode_spca561(unsigned char *inbuf, unsigned char *outbuf, int width, int height) {
  int i;
  static char tmpbuf[650 * 490];
  if (internal_spca561_decode(width, height, inbuf, (unsigned char *)tmpbuf) == 0) {
    for (i = 0; i < height; i++)
      memcpy(outbuf + i * width, tmpbuf + (i + 2) * (width + 6) + 3, width);
  }
}
```