ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    D51(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x18(%rsp),%r8
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    0x20(%rsp),%rsi
  lea    D10(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  comisd (%rsp),%xmm0
  jae    L87
  comisd 0x8(%rsp),%xmm0
  jae    L19
  comisd 0x10(%rsp),%xmm0
  jae    L63
  comisd 0x18(%rsp),%xmm0
  jb     L52
  lea    D71(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L87:
  lea    D64(%rip),%rdi
  call   <printf@plt>
L65:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L19:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L63:
  lea    D83(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L52:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L65
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D51
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D5
type: string
name: unpack_data
arguments: tag: D10
type: string
name: unpack_data
arguments: tag: D71
type: string
name: unpack_data
arguments: tag: D64
type: string
name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D83
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D51: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D19: %lf %lf %lf %lf

tool: D5: Thank you. Now enter student score (percent) >

tool: D10: %lf

tool: D71: Student has an D grade


tool: D64: Student has an A grade


tool: D28: Student has an B grade


tool: D83: Student has an C grade


tool: D16: Student has failed the course


assistant: ```c
int main() {
  double a, b, c, d;
  double score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf %lf %lf %lf", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &score);
  if (score >= a)
    printf("Student has an A grade\n");
  else if (score >= b)
    printf("Student has an B grade\n");
  else if (score >= c)
    printf("Student has an C grade\n");
  else if (score >= d)
    printf("Student has an D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D47(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x18(%rsp),%r8
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    D39(%rip),%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  comisd (%rsp),%xmm0
  jae    L25
  comisd 0x8(%rsp),%xmm0
  jae    L41
  comisd 0x10(%rsp),%xmm0
  jae    L7
  comisd 0x18(%rsp),%xmm0
  jb     L9
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L41:
  lea    D69(%rip),%rdi
  call   <printf@plt>
L36:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L25:
  lea    D50(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L9:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L7:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L36
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D47
type: string
name: extract_symbolic_data
arguments: data_label: D4
type: string
name: extract_symbolic_data
arguments: data_label: D40
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string
name: extract_symbolic_data
arguments: data_label: D28
type: string
name: extract_symbolic_data
arguments: data_label: D69
type: string
name: extract_symbolic_data
arguments: data_label: D50
type: string
name: extract_symbolic_data
arguments: data_label: D17
type: string
name: extract_symbolic_data
arguments: data_label: D3
type: string

tool: D47: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D4: %lf %lf %lf %lf

tool: D40: Thank you. Now enter student score (percent) >

tool: D39: %lf

tool: D28: Student has an D grade


tool: D69: Student has an B grade


tool: D50: Student has an A grade


tool: D17: Student has failed the course


tool: D3: Student has an C grade


assistant: ```c
int main() {
  double a, b, c, d;
  double score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf %lf %lf %lf", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &score);
  if (score >= a)
    printf("Student has an A grade\n");
  else if (score >= b)
    printf("Student has an B grade\n");
  else if (score >= c)
    printf("Student has an C grade\n");
  else if (score >= d)
    printf("Student has an D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  lea    D17(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rcx
  mov    %rsp,%rsi
  xor    %eax,%eax
  lea    0x8(%rsp),%rdx
  lea    0x18(%rsp),%r8
  lea    D72(%rip),%rdi
  call   <scanf@plt>
  lea    D26(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x20(%rsp),%rsi
  lea    D78(%rip),%rdi
  call   <scanf@plt>
  movsd  0x20(%rsp),%xmm0
  comisd (%rsp),%xmm0
  jae    L3
  comisd 0x8(%rsp),%xmm0
  jae    L74
  comisd 0x10(%rsp),%xmm0
  jae    L69
  comisd 0x18(%rsp),%xmm0
  jb     L89
  lea    D24(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L74:
  lea    D89(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L3:
  lea    D58(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L89:
  lea    D39(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L69:
  lea    D71(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D72
type: string
name: disassemble_data
arguments: data_label: D26
type: string
name: disassemble_data
arguments: data_label: D78
type: string
name: disassemble_data
arguments: data_label: D24
type: string
name: disassemble_data
arguments: data_label: D89
type: string
name: disassemble_data
arguments: data_label: D58
type: string
name: disassemble_data
arguments: data_label: D39
type: string
name: disassemble_data
arguments: data_label: D71
type: string

tool: D17: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D72: %lf %lf %lf %lf

tool: D26: Thank you. Now enter student score (percent) >

tool: D78: %lf

tool: D24: Student has an D grade


tool: D89: Student has an B grade


tool: D58: Student has an A grade


tool: D39: Student has failed the course


tool: D71: Student has an C grade


assistant: ```c
int main() {
  double a, b, c, d;
  double score;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%lf %lf %lf %lf", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%lf", &score);
  if (score >= a)
    printf("Student has an A grade\n");
  else if (score >= b)
    printf("Student has an B grade\n");
  else if (score >= c)
    printf("Student has an C grade\n");
  else if (score >= d)
    printf("Student has an D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ViewPerspective>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ViewPerspective(void) {
  glMatrixMode(GL_PROJECTION);
  glPopMatrix();
  glMatrixMode(GL_MODELVIEW);
  glPopMatrix();
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ViewPerspective>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  mov    $0x0,%eax
  call   <glPopMatrix@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void ViewPerspective(void) {
  glMatrixMode(GL_PROJECTION);
  glPopMatrix();
  glMatrixMode(GL_MODELVIEW);
  glPopMatrix();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ViewPerspective>:
  endbr64
  sub    $0x8,%rsp
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glPopMatrix@plt>
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <glPopMatrix@plt>
```

assistant: ```c
void ViewPerspective(void) {
  glMatrixMode(GL_PROJECTION);
  glPopMatrix();
  glMatrixMode(GL_MODELVIEW);
  glPopMatrix();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ViewPerspective>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  call   <glPopMatrix@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <glMatrixMode@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <glPopMatrix@plt>
```

assistant: ```c
void ViewPerspective(void) {
  glMatrixMode(GL_PROJECTION);
  glPopMatrix();
  glMatrixMode(GL_MODELVIEW);
  glPopMatrix();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<printString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L1:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  movl   $0x0,-0x8(%rbp)
  jmp    L39
L32:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L32
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

assistant: ```c
void printString(char a[]) {
  int i = 0;
  int len = 0;
  for (i = 0; a[i] != 0; i++) {
    len++;
  }
  for (i = 0; i < len; i++) {
    printf("%c", a[i]);
  }
  printf("\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printString>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  cmpb   $0x0,(%rdi)
  je     L0
  mov    %rdi,%r12
  lea    0x1(%rdi),%rdx
  mov    $0x0,%eax
L37:
  mov    %eax,%ebp
  add    $0x1,%eax
  add    $0x1,%rdx
  cmpb   $0x0,-0x1(%rdx)
  jne    L37
  test   %eax,%eax
  jle    L0
  mov    %r12,%rbx
L38:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  mov    %ebx,%eax
  sub    %r12d,%eax
  sub    $0x1,%eax
  cmp    %ebp,%eax
  jl     L38
L0:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void printString(char a[]) {
  int i = 0;
  int len = 0;
  for (i = 0; a[i] != 0; i++) {
    len++;
  }
  for (i = 0; i < len; i++) {
    printf("%c", a[i]);
  }
  printf("\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<printString>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L22
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L19:
  mov    %rax,%rbp
  add    $0x1,%rax
  cmpb   $0x0,(%rbx,%rax,1)
  jne    L19
  add    $0x1,%rbx
  add    %rbx,%rbp
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L18:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
L39:
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L18
L22:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
```

assistant: ```c
void printString(char a[]) {
  int i = 0;
  int len = 0;
  for (i = 0; a[i] != 0; i++) {
    len++;
  }
  for (i = 0; i < len; i++) {
    printf("%c", a[i]);
  }
  printf("\n");
  return;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<printString>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L11
  push   %rbp
  xor    %eax,%eax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L21:
  mov    %rax,%rdx
  add    $0x1,%rax
  cmpb   $0x0,(%rbx,%rax,1)
  jne    L21
  lea    0x1(%rdx,%rbx,1),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbx,%rbp
  jne    L1
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1050 <putchar@plt>
  nopl   0x0(%rax)
L11:
  mov    $0xa,%edi
  jmp    1050 <putchar@plt>
```

assistant: ```c
void printString(char a[]) {
  int i = 0;
  int len = 0;
  for (i = 0; a[i] != 0; i++) {
    len++;
  }
  for (i = 0; i < len; i++) {
    printf("%c", a[i]);
  }
  printf("\n");
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex2bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  shr    %rax
  mov    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cltq
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  movl   $0x0,-0x14(%rbp)
  jmp    L17
L1:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <hex2dec@plt>
  shl    $0x4,%eax
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <hex2dec@plt>
  lea    (%rbx,%rax,1),%ecx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  shr    $0x1f,%esi
  add    %esi,%eax
  sar    %eax
  cltq
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x2,-0x14(%rbp)
L17:
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L1
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void hex2bin(char *hx, char **bin, int *len) {
  int i;
  *len = strlen(hx) / 2;
  *bin = malloc(*len + 1);
  for (i = 0; i < (*len) * 2; i += 2) {
    (*bin)[i / 2] = hex2dec(hx[i]) * 16 + hex2dec(hx[i + 1]);
  }
  bin[*len] = '\0';
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hex2bin>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  call   <strlen@plt>
  shr    %rax
  mov    %eax,(%r14)
  add    $0x1,%eax
  movslq %eax,%rdi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  mov    (%r14),%eax
  test   %eax,%eax
  jle    L12
  mov    $0x0,%ebp
L6:
  movsbl (%r12,%rbp,1),%edi
  mov    $0x0,%eax
  call   <hex2dec@plt>
  mov    %eax,%ebx
  movsbl 0x1(%r12,%rbp,1),%edi
  mov    $0x0,%eax
  call   <hex2dec@plt>
  mov    %eax,%ecx
  mov    %ebp,%eax
  shr    $0x1f,%eax
  add    %ebp,%eax
  sar    %eax
  cltq
  mov    0x0(%r13),%rdx
  shl    $0x4,%ebx
  add    %ecx,%ebx
  mov    %bl,(%rdx,%rax,1)
  mov    (%r14),%eax
  add    $0x2,%rbp
  lea    (%rax,%rax,1),%edx
  cmp    %ebp,%edx
  jg     L6
L12:
  cltq
  movq   $0x0,0x0(%r13,%rax,8)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void hex2bin(char *hx, char **bin, int *len) {
  int i;
  *len = strlen(hx) / 2;
  *bin = malloc(*len + 1);
  for (i = 0; i < (*len) * 2; i += 2) {
    (*bin)[i / 2] = hex2dec(hx[i]) * 16 + hex2dec(hx[i + 1]);
  }
  bin[*len] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<hex2bin>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  shr    %rax
  mov    %eax,0x0(%r13)
  add    $0x1,%eax
  movslq %eax,%rdi
  call   <malloc@plt>
  mov    %rax,(%r14)
  movslq 0x0(%r13),%rax
  test   %eax,%eax
  jle    L9
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L7:
  movsbl (%r12,%rbp,1),%edi
  xor    %eax,%eax
  call   <hex2dec@plt>
  movsbl 0x1(%r12,%rbp,1),%edi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <hex2dec@plt>
  shl    $0x4,%ebx
  mov    (%r14),%rdx
  mov    %eax,%r8d
  mov    %ebp,%eax
  add    $0x2,%rbp
  sar    %eax
  add    %r8d,%ebx
  cltq
  mov    %bl,(%rdx,%rax,1)
  movslq 0x0(%r13),%rax
  lea    (%rax,%rax,1),%edx
  cmp    %ebp,%edx
  jg     L7
L9:
  pop    %rbx
  pop    %rbp
  movq   $0x0,(%r14,%rax,8)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void hex2bin(char *hx, char **bin, int *len) {
  int i;
  *len = strlen(hx) / 2;
  *bin = malloc(*len + 1);
  for (i = 0; i < (*len) * 2; i += 2) {
    (*bin)[i / 2] = hex2dec(hx[i]) * 16 + hex2dec(hx[i + 1]);
  }
  bin[*len] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hex2bin>:
  endbr64
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  call   <strlen@plt>
  shr    %rax
  mov    %eax,0x0(%r13)
  add    $0x1,%eax
  movslq %eax,%rdi
  call   <malloc@plt>
  mov    %rax,(%r14)
  movslq 0x0(%r13),%rax
  test   %eax,%eax
  jle    L10
  xor    %ebp,%ebp
  nopl   0x0(%rax)
L1:
  movsbl (%r12,%rbp,1),%edi
  xor    %eax,%eax
  call   <hex2dec@plt>
  movsbl 0x1(%r12,%rbp,1),%edi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <hex2dec@plt>
  shl    $0x4,%ebx
  mov    (%r14),%rdx
  mov    %eax,%r8d
  mov    %ebp,%eax
  add    $0x2,%rbp
  sar    %eax
  add    %r8d,%ebx
  cltq
  mov    %bl,(%rdx,%rax,1)
  movslq 0x0(%r13),%rax
  lea    (%rax,%rax,1),%edx
  cmp    %ebp,%edx
  jg     L1
L10:
  pop    %rbx
  pop    %rbp
  movq   $0x0,(%r14,%rax,8)
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void hex2bin(char *hx, char **bin, int *len) {
  int i;
  *len = strlen(hx) / 2;
  *bin = malloc(*len + 1);
  for (i = 0; i < (*len) * 2; i += 2) {
    (*bin)[i / 2] = hex2dec(hx[i]) * 16 + hex2dec(hx[i + 1]);
  }
  bin[*len] = '\0';
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hex_to_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L1
  cmpb   $0x39,-0x4(%rbp)
  jg     L1
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L77
L1:
  cmpb   $0x60,-0x4(%rbp)
  jle    L75
  cmpb   $0x66,-0x4(%rbp)
  jg     L75
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L77
L75:
  cmpb   $0x40,-0x4(%rbp)
  jle    L86
  cmpb   $0x46,-0x4(%rbp)
  jg     L86
  movsbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L77
L86:
  mov    $0x0,%eax
L77:
  pop    %rbp
  ret
```

assistant: ```c
int hex_to_int(char ch) {
  if (ch >= '0' && ch <= '9')
    return (int)ch - '0';
  else if (ch >= 'a' && ch <= 'f')
    return (int)ch - 'a' + 10;
  else if (ch >= 'A' && ch <= 'F')
    return (int)ch - 'A' + 10;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hex_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L8
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L6
  lea    -0x41(%rdi),%edx
  movsbl %dil,%eax
  sub    $0x37,%eax
  cmp    $0x6,%dl
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
L8:
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L6:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int hex_to_int(char ch) {
  if (ch >= '0' && ch <= '9')
    return (int)ch - '0';
  else if (ch >= 'a' && ch <= 'f')
    return (int)ch - 'a' + 10;
  else if (ch >= 'A' && ch <= 'F')
    return (int)ch - 'A' + 10;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hex_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L4
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L6
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex_to_int(char ch) {
  if (ch >= '0' && ch <= '9')
    return (int)ch - '0';
  else if (ch >= 'a' && ch <= 'f')
    return (int)ch - 'a' + 10;
  else if (ch >= 'A' && ch <= 'F')
    return (int)ch - 'A' + 10;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<hex_to_int>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  jbe    L4
  lea    -0x61(%rdi),%eax
  cmp    $0x5,%al
  jbe    L16
  lea    -0x41(%rdi),%edx
  lea    -0x37(%rdi),%eax
  cmp    $0x6,%dl
  movsbl %al,%eax
  mov    $0x0,%edx
  cmovae %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  sub    $0x57,%edi
  movsbl %dil,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  movsbl %al,%eax
  ret
```

assistant: ```c
int hex_to_int(char ch) {
  if (ch >= '0' && ch <= '9')
    return (int)ch - '0';
  else if (ch >= 'a' && ch <= 'f')
    return (int)ch - 'a' + 10;
  else if (ch >= 'A' && ch <= 'F')
    return (int)ch - 'A' + 10;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__libc_pselect>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x48(%rbp)
  je     L18
  mov    -0x48(%rbp),%rdx
  lea    -0x14(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <TIMESPEC_TO_TIMEVAL@plt>
L18:
  cmpq   $0x0,-0x50(%rbp)
  je     L33
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x50(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
L33:
  cmpq   $0x0,-0x48(%rbp)
  je     L25
  lea    -0x14(%rbp),%rdi
  jmp    L32
L25:
  mov    $0x0,%edi
L32:
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x24(%rbp),%eax
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <select@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x50(%rbp)
  je     L26
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  lea    -0x10(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <sigprocmask@plt>
L26:
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int __libc_pselect(int nfds, fd_set *readfds, fd_set *writefds, fd_set *exceptfds, const struct timespec *timeout, const sigset_t *sigmask) {
  struct timeval tval;
  int retval;
  sigset_t savemask;
  if (timeout != NULL)
    TIMESPEC_TO_TIMEVAL(&tval, timeout);
  if (sigmask != NULL)
    sigprocmask(SIG_SETMASK, sigmask, &savemask);
  retval = select(nfds, readfds, writefds, exceptfds, timeout != NULL ? &tval : NULL);
  if (sigmask != NULL)
    sigprocmask(SIG_SETMASK, &savemask, NULL);
  return retval;
}
```