ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  mov    $0x96,%edi
  call   <gcd@plt>
  lea    D6(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x195,%esi
  mov    $0x402,%edi
  call   <gcd@plt>
  lea    D15(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xf0,%esi
  mov    $0x53,%edi
  call   <gcd@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D15
datatype: string
name: parse_data
arguments: label: D8
datatype: string

tool: D6: The gcd of 150 and 35 is %i


tool: D15: The gcd of 1026 and 405 is %i


tool: D8: The gcd of 83 and 240 is %i


assistant: ```c
int main(void) {
  int result;
  result = gcd(150, 35);
  printf("The gcd of 150 and 35 is %i\n", result);
  result = gcd(1026, 405);
  printf("The gcd of 1026 and 405 is %i\n", result);
  printf("The gcd of 83 and 240 is %i\n", gcd(83, 240));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  mov    $0x96,%edi
  call   <gcd@plt>
  lea    D19(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0x195,%esi
  mov    $0x402,%edi
  call   <gcd@plt>
  lea    D11(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    $0xf0,%esi
  mov    $0x53,%edi
  call   <gcd@plt>
  lea    D7(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D11
datatype: string
name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D19: The gcd of 150 and 35 is %i


tool: D11: The gcd of 1026 and 405 is %i


tool: D7: The gcd of 83 and 240 is %i


assistant: ```c
int main(void) {
  int result;
  result = gcd(150, 35);
  printf("The gcd of 150 and 35 is %i\n", result);
  result = gcd(1026, 405);
  printf("The gcd of 1026 and 405 is %i\n", result);
  printf("The gcd of 83 and 240 is %i\n", gcd(83, 240));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cal_block>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0xc(%rbp)
  mov    D20(%rip),%rax
  mov    (%rax),%edx
  mov    -0x14(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  lea    0xfff(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0xc,%eax
  mov    %eax,-0x4(%rbp)
  mov    D24(%rip),%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <lseek@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cal_block(int fd) {
  int pos, end_pos, nr_blocks;
  pos = lseek(fd, 0, SEEK_CUR);
  end_pos = lseek(fd, 0, SEEK_END);
  nr_blocks = (end_pos - pos) / 4096;
  pos = lseek(fd, pos, SEEK_SET);
  return nr_blocks;
}
```
user: What is the c source code of the assembly code below:

```asm
<cal_block>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  call   <lseek@plt>
  mov    %eax,%r12d
  mov    D18(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <lseek@plt>
  mov    %eax,%ebx
  mov    D16(%rip),%rax
  mov    (%rax),%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <lseek@plt>
  mov    %ebx,%eax
  sub    %r12d,%eax
  lea    0xfff(%rax),%edx
  cmovs  %edx,%eax
  sar    $0xc,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int cal_block(int fd) {
  int pos, end_pos, nr_blocks;
  pos = lseek(fd, 0, SEEK_CUR);
  end_pos = lseek(fd, 0, SEEK_END);
  nr_blocks = (end_pos - pos) / 4096;
  pos = lseek(fd, pos, SEEK_SET);
  return nr_blocks;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cal_block>:
  endbr64
  mov    D4(%rip),%rax
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%edx
  call   <lseek@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r12d,%eax
  pop    %r12
  lea    0xfff(%rax),%edx
  cmovs  %edx,%eax
  sar    $0xc,%eax
  ret
```

assistant: ```c
int cal_block(int fd) {
  int pos, end_pos, nr_blocks;
  pos = lseek(fd, 0, SEEK_CUR);
  end_pos = lseek(fd, 0, SEEK_END);
  nr_blocks = (end_pos - pos) / 4096;
  pos = lseek(fd, pos, SEEK_SET);
  return nr_blocks;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<cal_block>:
  endbr64
  mov    D25(%rip),%rax
  push   %r12
  xor    %esi,%esi
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    (%rax),%edx
  call   <lseek@plt>
  xor    %esi,%esi
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ebx
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  call   <lseek@plt>
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r12d,%eax
  pop    %r12
  lea    0xfff(%rax),%edx
  cmovs  %edx,%eax
  sar    $0xc,%eax
  ret
```

assistant: ```c
int cal_block(int fd) {
  int pos, end_pos, nr_blocks;
  pos = lseek(fd, 0, SEEK_CUR);
  end_pos = lseek(fd, 0, SEEK_END);
  nr_blocks = (end_pos - pos) / 4096;
  pos = lseek(fd, pos, SEEK_SET);
  return nr_blocks;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mz_os_make_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x1ed,%esi
  mov    %rax,%rdi
  call   <mkdir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L1
  mov    D2(%rip),%rax
  mov    (%rax),%rdx
  mov    D14(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L1
  mov    $0xffffffffffffff98,%rax
  jmp    L5
L1:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
int32_t mz_os_make_dir(const char *path) {
  int32_t err = 0;
  err = mkdir(path, 0755);
  if (err != 0 && errno != EEXIST)
    return (-104);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mz_os_make_dir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1ed,%esi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L6
  mov    D4(%rip),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  mov    $0x0,%eax
  mov    $0xffffffffffffff98,%rdx
  cmovne %rdx,%rax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t mz_os_make_dir(const char *path) {
  int32_t err = 0;
  err = mkdir(path, 0755);
  if (err != 0 && errno != EEXIST)
    return (-104);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mz_os_make_dir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1ed,%esi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L5
  mov    D8(%rip),%rdx
  mov    D3(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  mov    $0x0,%eax
  mov    $0xffffffffffffff98,%rdx
  cmovne %rdx,%rax
L5:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t mz_os_make_dir(const char *path) {
  int32_t err = 0;
  err = mkdir(path, 0755);
  if (err != 0 && errno != EEXIST)
    return (-104);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mz_os_make_dir>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1ed,%esi
  call   <mkdir@plt>
  test   %rax,%rax
  je     L6
  mov    D4(%rip),%rdx
  mov    D19(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,(%rdx)
  mov    $0x0,%eax
  mov    $0xffffffffffffff98,%rdx
  cmovne %rdx,%rax
L6:
  add    $0x8,%rsp
  ret
```

assistant: ```c
int32_t mz_os_make_dir(const char *path) {
  int32_t err = 0;
  err = mkdir(path, 0755);
  if (err != 0 && errno != EEXIST)
    return (-104);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D18
data_type: string
name: retrieve_data
arguments: label: D47
data_type: string
name: retrieve_data
arguments: label: D45
data_type: string
name: retrieve_data
arguments: label: D49
data_type: string
name: retrieve_data
arguments: label: D4
data_type: string

tool: D18: Char: %i


tool: D47: Float: %i


tool: D45: Double: %i


tool: D49: Long long: %i


tool: D4: Int: %i


assistant: ```c
int main(void) {
  char c;
  float f;
  double d;
  long long l;
  int i;
  printf("Char: %i\n", sizeof(c));
  printf("Float: %i\n", sizeof(f));
  printf("Double: %i\n", sizeof(d));
  printf("Long long: %i\n", sizeof(l));
  printf("Int: %i\n", sizeof(i));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D42(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D49(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D46(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D42
type_infered: string
name: read_data
arguments: data_label: D49
type_infered: string
name: read_data
arguments: data_label: D2
type_infered: string
name: read_data
arguments: data_label: D46
type_infered: string
name: read_data
arguments: data_label: D13
type_infered: string

tool: D42: Char: %i


tool: D49: Float: %i


tool: D2: Double: %i


tool: D46: Long long: %i


tool: D13: Int: %i


assistant: ```c
int main(void) {
  char c;
  float f;
  double d;
  long long l;
  int i;
  printf("Char: %i\n", sizeof(c));
  printf("Float: %i\n", sizeof(f));
  printf("Double: %i\n", sizeof(d));
  printf("Long long: %i\n", sizeof(l));
  printf("Int: %i\n", sizeof(i));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string
name: disassemble_data
arguments: data_label: D8
type_guessed: string
name: disassemble_data
arguments: data_label: D3
type_guessed: string
name: disassemble_data
arguments: data_label: D12
type_guessed: string

tool: D16: Char: %i


tool: D22: Float: %i


tool: D8: Double: %i


tool: D3: Long long: %i


tool: D12: Int: %i


assistant: ```c
int main(void) {
  char c;
  float f;
  double d;
  long long l;
  int i;
  printf("Char: %i\n", sizeof(c));
  printf("Float: %i\n", sizeof(f));
  printf("Double: %i\n", sizeof(d));
  printf("Long long: %i\n", sizeof(l));
  printf("Int: %i\n", sizeof(i));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x8,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D48
data_type: string
name: extract_symbolic_data
arguments: tag: D10
data_type: string
name: extract_symbolic_data
arguments: tag: D8
data_type: string
name: extract_symbolic_data
arguments: tag: D32
data_type: string
name: extract_symbolic_data
arguments: tag: D29
data_type: string

tool: D48: Char: %i


tool: D10: Float: %i


tool: D8: Double: %i


tool: D32: Long long: %i


tool: D29: Int: %i


assistant: ```c
int main(void) {
  char c;
  float f;
  double d;
  long long l;
  int i;
  printf("Char: %i\n", sizeof(c));
  printf("Float: %i\n", sizeof(f));
  printf("Double: %i\n", sizeof(d));
  printf("Long long: %i\n", sizeof(l));
  printf("Int: %i\n", sizeof(i));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_basic_auth_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,-0x30(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x2,%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  shl    $0x2,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <kmalloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x40(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x2c(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <kmalloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <base64_encode@plt>
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    -0x2c(%rbp),%edx
  add    %edx,%eax
  add    $0xb,%eax
  mov    %eax,%edi
  call   <kmalloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <kfree@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <kfree@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D5
type_guessed: string
name: parse_data
arguments: label: D10
type_guessed: string

tool: D5: %s:%s

tool: D10: %s: Basic %s


assistant: ```c
char *get_basic_auth_str(char *user, char *passwd, char *auth_header) {
  char *p1, *p2, *ret;
  int len = strlen(user) + strlen(passwd) + 1;
  int b64len = 4 * ((len + 2) / 3);
  p1 = kmalloc(len + 1);
  sprintf(p1, "%s:%s", user, passwd);
  p2 = kmalloc(b64len + 1);
  base64_encode(p1, p2, len);
  ret = kmalloc(strlen(auth_header) + b64len + 11);
  sprintf(ret, "%s: Basic %s\r\n", auth_header, p2);
  kfree(p1);
  kfree(p2);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_basic_auth_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%r12
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r14,%rdi
  call   <strlen@plt>
  add    %eax,%ebp
  lea    0x3(%rbp),%eax
  movslq %eax,%rbx
  imul   $0x55555556,%rbx,%rbx
  shr    $0x20,%rbx
  sar    $0x1f,%eax
  sub    %eax,%ebx
  shl    $0x2,%ebx
  lea    0x2(%rbp),%edi
  call   <kmalloc@plt>
  mov    %rax,%r15
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    0x1(%rbx),%edi
  call   <kmalloc@plt>
  mov    %rax,%r13
  lea    0x1(%rbp),%edx
  mov    %rax,%rsi
  mov    %r15,%rdi
  call   <base64_encode@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0xb(%rbx,%rax,1),%edi
  call   <kmalloc@plt>
  mov    %rax,%rbx
  mov    %r13,%rcx
  mov    %r12,%rdx
  lea    D3(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    %r15,%rdi
  call   <kfree@plt>
  mov    %r13,%rdi
  call   <kfree@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string

tool: D7: %s:%s

tool: D3: %s: Basic %s


assistant: ```c
char *get_basic_auth_str(char *user, char *passwd, char *auth_header) {
  char *p1, *p2, *ret;
  int len = strlen(user) + strlen(passwd) + 1;
  int b64len = 4 * ((len + 2) / 3);
  p1 = kmalloc(len + 1);
  sprintf(p1, "%s:%s", user, passwd);
  p2 = kmalloc(b64len + 1);
  base64_encode(p1, p2, len);
  ret = kmalloc(strlen(auth_header) + b64len + 11);
  sprintf(ret, "%s: Basic %s\r\n", auth_header, p2);
  kfree(p1);
  kfree(p2);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_basic_auth_str>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  add    %eax,%ebp
  lea    0x3(%rbp),%eax
  lea    0x2(%rbp),%edi
  movslq %eax,%rbx
  sar    $0x1f,%eax
  imul   $0x55555556,%rbx,%rbx
  shr    $0x20,%rbx
  sub    %eax,%ebx
  call   <kmalloc@plt>
  shl    $0x2,%ebx
  mov    %r15,%rcx
  mov    %r12,%rdx
  lea    D6(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  lea    0x1(%rbx),%edi
  call   <kmalloc@plt>
  lea    0x1(%rbp),%edx
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <base64_encode@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0xb(%rbx,%rax,1),%edi
  call   <kmalloc@plt>
  mov    %r12,%rcx
  mov    %r14,%rdx
  lea    D17(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <kfree@plt>
  mov    %r12,%rdi
  call   <kfree@plt>
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D6
type: string
name: retrieve_data
arguments: tag: D17
type: string

tool: D6: %s:%s

tool: D17: %s: Basic %s


assistant: ```c
char *get_basic_auth_str(char *user, char *passwd, char *auth_header) {
  char *p1, *p2, *ret;
  int len = strlen(user) + strlen(passwd) + 1;
  int b64len = 4 * ((len + 2) / 3);
  p1 = kmalloc(len + 1);
  sprintf(p1, "%s:%s", user, passwd);
  p2 = kmalloc(b64len + 1);
  base64_encode(p1, p2, len);
  ret = kmalloc(strlen(auth_header) + b64len + 11);
  sprintf(ret, "%s: Basic %s\r\n", auth_header, p2);
  kfree(p1);
  kfree(p2);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_basic_auth_str>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdx,%r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %r15,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  add    %eax,%ebp
  lea    0x3(%rbp),%eax
  lea    0x2(%rbp),%edi
  movslq %eax,%rbx
  sar    $0x1f,%eax
  imul   $0x55555556,%rbx,%rbx
  shr    $0x20,%rbx
  sub    %eax,%ebx
  call   <kmalloc@plt>
  shl    $0x2,%ebx
  mov    %r15,%rcx
  mov    %r12,%rdx
  lea    D0(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  call   <sprintf@plt>
  lea    0x1(%rbx),%edi
  call   <kmalloc@plt>
  lea    0x1(%rbp),%edx
  mov    %r13,%rdi
  mov    %rax,%rsi
  mov    %rax,%r12
  call   <base64_encode@plt>
  mov    %r14,%rdi
  call   <strlen@plt>
  lea    0xb(%rbx,%rax,1),%edi
  call   <kmalloc@plt>
  mov    %r12,%rcx
  mov    %r14,%rdx
  lea    D5(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r15
  call   <sprintf@plt>
  mov    %r13,%rdi
  call   <kfree@plt>
  mov    %r12,%rdi
  call   <kfree@plt>
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
datatype: string
name: unpack_data
arguments: data_label: D5
datatype: string

tool: D0: %s:%s

tool: D5: %s: Basic %s


assistant: ```c
char *get_basic_auth_str(char *user, char *passwd, char *auth_header) {
  char *p1, *p2, *ret;
  int len = strlen(user) + strlen(passwd) + 1;
  int b64len = 4 * ((len + 2) / 3);
  p1 = kmalloc(len + 1);
  sprintf(p1, "%s:%s", user, passwd);
  p2 = kmalloc(b64len + 1);
  base64_encode(p1, p2, len);
  ret = kmalloc(strlen(auth_header) + b64len + 11);
  sprintf(ret, "%s: Basic %s\r\n", auth_header, p2);
  kfree(p1);
  kfree(p2);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<single_o>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void single_o() {
  register int out0 = 0;
  register int index = 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<single_o>:
  endbr64
  ret
```

assistant: ```c
void single_o() {
  register int out0 = 0;
  register int index = 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<single_o>:
  endbr64
  ret
```

assistant: ```c
void single_o() {
  register int out0 = 0;
  register int index = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<single_o>:
  endbr64
  ret
```

assistant: ```c
void single_o() {
  register int out0 = 0;
  register int index = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<consume_token>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
L36:
  cmpq   $0x0,-0x20(%rbp)
  je     L15
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
L15:
  addl   $0x1,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x20,-0x4(%rbp)
  je     L33
  cmpl   $0x9,-0x4(%rbp)
  je     L33
  cmpl   $0xa,-0x4(%rbp)
  je     L33
  cmpl   $0x3e,-0x4(%rbp)
  jne    L36
L33:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int consume_token(FILE *source_file, char *s) {
  int i = 0;
  int c = fgetc(source_file);
  do {
    if (NULL != s)
      s[i] = c;
    i = i + 1;
    c = fgetc(source_file);
  } while ((' ' != c) && ('\t' != c) && ('\n' != c) && '>' != c);
  return c;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<consume_token>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  call   <fgetc@plt>
  mov    %rbp,%rbx
  movabs $0x4000000100000600,%r13
  jmp    L8
L16:
  add    $0x1,%rbx
L8:
  test   %rbp,%rbp
  je     L21
  mov    %al,(%rbx)
L21:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    $0x3e,%eax
  ja     L16
  add    $0x1,%rbx
  bt     %rax,%r13
  jae    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int consume_token(FILE *source_file, char *s) {
  int i = 0;
  int c = fgetc(source_file);
  do {
    if (NULL != s)
      s[i] = c;
    i = i + 1;
    c = fgetc(source_file);
  } while ((' ' != c) && ('\t' != c) && ('\n' != c) && '>' != c);
  return c;
}
```