ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pfdc4_save_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <psi_set_uint16_be@plt>
  lea    -0xc(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <psi_set_uint16_be@plt>
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x50464443,%esi
  mov    %rax,%rdi
  call   <pfdc4_save_chunk@plt>
  test   %rax,%rax
  je     L0
  mov    $0x1,%eax
  jmp    L1
L0:
  mov    $0x0,%eax
L1:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

assistant: ```c
int pfdc4_save_header(FILE *fp) {
  unsigned char buf[4];
  psi_set_uint16_be(buf, 0, 4);
  psi_set_uint16_be(buf, 2, 0);
  if (pfdc4_save_chunk(fp, 0x50464443, 4, buf)) {
    return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pfdc4_save_header>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <psi_set_uint16_be@plt>
  mov    $0x0,%edx
  mov    $0x2,%esi
  mov    %rbp,%rdi
  call   <psi_set_uint16_be@plt>
  mov    %rbp,%rcx
  mov    $0x4,%edx
  mov    $0x50464443,%esi
  mov    %rbx,%rdi
  call   <pfdc4_save_chunk@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  movzbl %al,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pfdc4_save_header(FILE *fp) {
  unsigned char buf[4];
  psi_set_uint16_be(buf, 0, 4);
  psi_set_uint16_be(buf, 2, 0);
  if (pfdc4_save_chunk(fp, 0x50464443, 4, buf)) {
    return (1);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pfdc4_save_header>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <psi_set_uint16_be@plt>
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    %r12,%rdi
  call   <psi_set_uint16_be@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rdi
  mov    $0x50464443,%esi
  call   <pfdc4_save_chunk@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pfdc4_save_header(FILE *fp) {
  unsigned char buf[4];
  psi_set_uint16_be(buf, 0, 4);
  psi_set_uint16_be(buf, 2, 0);
  if (pfdc4_save_chunk(fp, 0x50464443, 4, buf)) {
    return (1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pfdc4_save_header>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rdi
  call   <psi_set_uint16_be@plt>
  xor    %edx,%edx
  mov    $0x2,%esi
  mov    %r12,%rdi
  call   <psi_set_uint16_be@plt>
  mov    %r12,%rcx
  mov    $0x4,%edx
  mov    %rbp,%rdi
  mov    $0x50464443,%esi
  call   <pfdc4_save_chunk@plt>
  test   %rax,%rax
  setne  %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pfdc4_save_header(FILE *fp) {
  unsigned char buf[4];
  psi_set_uint16_be(buf, 0, 4);
  psi_set_uint16_be(buf, 2, 0);
  if (pfdc4_save_chunk(fp, 0x50464443, 4, buf)) {
    return (1);
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<mj_shuffle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L41
  cmpl   $0x2,-0x2c(%rbp)
  jle    L41
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x4,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x32,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  lea    0x3e8(%rdx),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L7
L56:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x2c(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  je     L59
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L59:
  addl   $0x1,-0x14(%rbp)
L7:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L56
  jmp    L27
L41:
  nop
L27:
  leave
  ret
```

assistant: ```c
void mj_shuffle(int *pais, int len) {
  int i, n;
  int a, b, temp;
  if (!pais || len <= 2)
    return;
  n = 1000 + rand() % 50;
  for (i = 0; i < n; ++i) {
    a = rand() % len;
    b = rand() % len;
    if (a != b) {
      temp = *(pais + a);
      *(pais + a) = *(pais + b);
      *(pais + b) = temp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mj_shuffle>:
  endbr64
  test   %rdi,%rdi
  je     L58
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%ebx
  cmp    $0x2,%esi
  jle    L10
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%r14d
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x24,%rdx
  sar    $0x1f,%eax
  sub    %eax,%edx
  imul   $0x32,%edx,%edx
  sub    %edx,%r14d
  add    $0x3e8,%r14d
  mov    $0x0,%r12d
  jmp    L16
L28:
  movslq %ebp,%rbp
  lea    0x0(%r13,%rbp,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
L29:
  add    $0x1,%r12d
  cmp    %r14d,%r12d
  je     L10
L16:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  mov    %edx,%ebp
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %edx,%ebp
  jne    L28
  jmp    L29
L10:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L58:
  ret
```

assistant: ```c
void mj_shuffle(int *pais, int len) {
  int i, n;
  int a, b, temp;
  if (!pais || len <= 2)
    return;
  n = 1000 + rand() % 50;
  for (i = 0; i < n; ++i) {
    a = rand() % len;
    b = rand() % len;
    if (a != b) {
      temp = *(pais + a);
      *(pais + a) = *(pais + b);
      *(pais + b) = temp;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mj_shuffle>:
  endbr64
  test   %rdi,%rdi
  je     L31
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x2,%esi
  jle    L17
  xor    %eax,%eax
  mov    %rdi,%rbp
  xor    %r14d,%r14d
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %rdx,%r12
  imul   $0x51eb851f,%rdx,%rdx
  mov    %r12d,%eax
  sar    $0x1f,%eax
  sar    $0x24,%rdx
  sub    %eax,%edx
  imul   $0x32,%edx,%edx
  sub    %edx,%r12d
  add    $0x3e8,%r12d
  nop
L14:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%r13
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %edx,%r13d
  je     L0
  movslq %edx,%rdx
  lea    0x0(%rbp,%r13,4),%rcx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
L0:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  jne    L14
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  ret
```

assistant: ```c
void mj_shuffle(int *pais, int len) {
  int i, n;
  int a, b, temp;
  if (!pais || len <= 2)
    return;
  n = 1000 + rand() % 50;
  for (i = 0; i < n; ++i) {
    a = rand() % len;
    b = rand() % len;
    if (a != b) {
      temp = *(pais + a);
      *(pais + a) = *(pais + b);
      *(pais + b) = temp;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mj_shuffle>:
  endbr64
  test   %rdi,%rdi
  je     L39
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  cmp    $0x2,%esi
  jle    L29
  xor    %eax,%eax
  mov    %rdi,%rbp
  xor    %r14d,%r14d
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %rdx,%r12
  imul   $0x51eb851f,%rdx,%rdx
  mov    %r12d,%eax
  sar    $0x1f,%eax
  sar    $0x24,%rdx
  sub    %eax,%edx
  imul   $0x32,%edx,%edx
  sub    %edx,%r12d
  add    $0x3e8,%r12d
  nop
L13:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  xor    %eax,%eax
  movslq %edx,%r13
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %edx,%r13d
  je     L23
  movslq %edx,%rdx
  lea    0x0(%rbp,%r13,4),%rcx
  lea    0x0(%rbp,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
L23:
  add    $0x1,%r14d
  cmp    %r14d,%r12d
  jne    L13
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  ret
```

assistant: ```c
void mj_shuffle(int *pais, int len) {
  int i, n;
  int a, b, temp;
  if (!pais || len <= 2)
    return;
  n = 1000 + rand() % 50;
  for (i = 0; i < n; ++i) {
    a = rand() % len;
    b = rand() % len;
    if (a != b) {
      temp = *(pais + a);
      *(pais + a) = *(pais + b);
      *(pais + b) = temp;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1bc(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  jmp    L111
L139:
  movl   $0x0,-0x1b4(%rbp)
  movl   $0x0,-0x1a4(%rbp)
  lea    -0x1b8(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x1ac(%rbp)
  jmp    L81
L16:
  lea    -0x1a0(%rbp),%rdx
  mov    -0x1ac(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1ac(%rbp)
L81:
  mov    -0x1b8(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L16
  movl   $0x0,-0x1ac(%rbp)
  jmp    L37
L69:
  movl   $0x0,-0x1b0(%rbp)
  movl   $0x0,-0x1a8(%rbp)
  jmp    L109
L14:
  mov    -0x1a8(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jne    L63
  addl   $0x1,-0x1b0(%rbp)
L63:
  addl   $0x1,-0x1a8(%rbp)
L109:
  mov    -0x1b8(%rbp),%eax
  cmp    %eax,-0x1a8(%rbp)
  jl     L14
  mov    -0x1b0(%rbp),%eax
  cmp    -0x1b4(%rbp),%eax
  jle    L130
  mov    -0x1b0(%rbp),%eax
  mov    %eax,-0x1b4(%rbp)
  mov    -0x1ac(%rbp),%eax
  mov    %eax,-0x1a4(%rbp)
  jmp    L102
L130:
  mov    -0x1b4(%rbp),%eax
  cmp    -0x1b0(%rbp),%eax
  jne    L102
  mov    -0x1ac(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%edx
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  cmp    %eax,%edx
  jge    L102
  mov    -0x1ac(%rbp),%eax
  mov    %eax,-0x1a4(%rbp)
L102:
  addl   $0x1,-0x1ac(%rbp)
L37:
  mov    -0x1b8(%rbp),%eax
  cmp    %eax,-0x1ac(%rbp)
  jl     L69
  mov    -0x1a4(%rbp),%eax
  cltq
  mov    -0x1a0(%rbp,%rax,4),%eax
  mov    -0x1b4(%rbp),%edx
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L111:
  mov    -0x1bc(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1bc(%rbp)
  test   %eax,%eax
  jne    L139
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L65
  call   <__stack_chk_fail@plt>
L65:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D20
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string

tool: D20: %d

tool: D17: %d %d


assistant: ```c
int main() {
  int t, max, maxtemp, arr[100], n, i, j, pos;
  scanf("%d", &t);
  while (t--) {
    max = 0;
    pos = 0;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
      scanf("%d", &arr[i]);
    for (i = 0; i < n; i++) {
      maxtemp = 0;
      for (j = 0; j < n; j++) {
        if (arr[j] == arr[i])
          maxtemp++;
      }
      if (maxtemp > max) {
        max = maxtemp;
        pos = i;
      } else if (max == maxtemp) {
        if (arr[i] < arr[pos])
          pos = i;
      }
    }
    printf("%d %d\n", arr[pos], max);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1b8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1a8(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L129
  lea    D25(%rip),%rbp
  lea    0x10(%rsp),%rbx
  lea    0x14(%rsp),%r13
  lea    D28(%rip),%r12
  jmp    L62
L34:
  mov    %r8d,%r14d
  mov    %edx,%r11d
L44:
  add    $0x1,%r8d
  add    $0x4,%r10
  cmp    %r8d,%r9d
  je     L38
L78:
  mov    (%r10),%esi
  mov    %rbx,%rax
  mov    $0x0,%edx
L98:
  cmp    %esi,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L98
  cmp    %r11d,%edx
  jg     L34
  jne    L44
  movslq %r14d,%rax
  cmp    0x10(%rsp,%rax,4),%esi
  cmovl  %r8d,%r14d
  jmp    L44
L35:
  mov    $0x0,%r14d
  mov    $0x0,%r11d
L38:
  movslq %r14d,%r14
  mov    0x10(%rsp,%r14,4),%esi
  mov    %r11d,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x8(%rsp)
  test   %eax,%eax
  je     L129
L62:
  lea    0xc(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L35
  mov    %rbx,%r15
  mov    $0x0,%r14d
L85:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  add    $0x1,%r14d
  mov    0xc(%rsp),%r9d
  add    $0x4,%r15
  cmp    %r14d,%r9d
  jg     L85
  test   %r9d,%r9d
  jle    L118
  lea    -0x1(%r9),%eax
  lea    0x0(%r13,%rax,4),%rdi
  mov    %rbx,%r10
  mov    $0x0,%r14d
  mov    $0x0,%r8d
  mov    $0x0,%r11d
  jmp    L78
L118:
  mov    $0x0,%r14d
  mov    $0x0,%r11d
  jmp    L38
L129:
  mov    0x1a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  mov    $0x0,%eax
  add    $0x1b8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D25
type_infered: string
name: read_data
arguments: data_label: D28
type_infered: string

tool: D25: %d

tool: D28: %d %d


assistant: ```c
int main() {
  int t, max, maxtemp, arr[100], n, i, j, pos;
  scanf("%d", &t);
  while (t--) {
    max = 0;
    pos = 0;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
      scanf("%d", &arr[i]);
    for (i = 0; i < n; i++) {
      maxtemp = 0;
      for (j = 0; j < n; j++) {
        if (arr[j] == arr[i])
          maxtemp++;
      }
      if (maxtemp > max) {
        max = maxtemp;
        pos = i;
      } else if (max == maxtemp) {
        if (arr[i] < arr[pos])
          pos = i;
      }
    }
    printf("%d %d\n", arr[pos], max);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    D11(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x18(%rsp),%rsi
  call   <scanf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  je     L58
  lea    0x24(%rsp),%rax
  lea    0x1c(%rsp),%r13
  mov    %rax,0x8(%rsp)
  lea    D2(%rip),%r12
  lea    0x20(%rsp),%rbx
  nopw   0x0(%rax,%rax,1)
L42:
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  jle    L32
  mov    %rbx,%r14
  xor    %r15d,%r15d
  nopl   (%rax)
L45:
  mov    %r14,%rsi
  mov    %rbp,%rdi
  add    $0x1,%r15d
  add    $0x4,%r14
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  cmp    %r15d,%eax
  jg     L45
  test   %eax,%eax
  jle    L32
  mov    0x8(%rsp),%rdi
  mov    %eax,%r11d
  sub    $0x1,%eax
  xor    %r8d,%r8d
  xor    %r15d,%r15d
  xor    %r9d,%r9d
  lea    (%rdi,%rax,4),%rdi
  nopl   0x0(%rax)
L8:
  mov    (%rbx,%r8,4),%esi
  movslq %r8d,%r10
  mov    %rbx,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L83:
  xor    %ecx,%ecx
  cmp    %esi,(%rax)
  sete   %cl
  add    $0x4,%rax
  add    %ecx,%edx
  cmp    %rdi,%rax
  jne    L83
  cmp    %r9d,%edx
  jg     L72
  jne    L71
  movslq %r15d,%rax
  cmp    0x20(%rsp,%rax,4),%esi
  cmovl  %r10,%r15
  nopl   0x0(%rax)
L71:
  add    $0x1,%r8
  cmp    %r11,%r8
  jne    L8
L18:
  mov    0x20(%rsp,%r15,4),%esi
  mov    %r9d,%edx
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x18(%rsp)
  test   %eax,%eax
  jne    L42
L58:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L72:
  movslq %r10d,%r15
  mov    %edx,%r9d
  jmp    L71
L32:
  xor    %r15d,%r15d
  xor    %r9d,%r9d
  jmp    L18
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D11
data_type: string
name: parse_data
arguments: data_tag: D2
data_type: string

tool: D11: %d

tool: D2: %d %d


assistant: ```c
int main() {
  int t, max, maxtemp, arr[100], n, i, j, pos;
  scanf("%d", &t);
  while (t--) {
    max = 0;
    pos = 0;
    scanf("%d", &n);
    for (i = 0; i < n; i++)
      scanf("%d", &arr[i]);
    for (i = 0; i < n; i++) {
      maxtemp = 0;
      for (j = 0; j < n; j++) {
        if (arr[j] == arr[i])
          maxtemp++;
      }
      if (maxtemp > max) {
        max = maxtemp;
        pos = i;
      } else if (max == maxtemp) {
        if (arr[i] < arr[pos])
          pos = i;
      }
    }
    printf("%d %d\n", arr[pos], max);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max_sum_for_submatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_sum_for_submatrix(unsigned int size, int **matrix) {
  int ret = 0;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_sum_for_submatrix>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int max_sum_for_submatrix(unsigned int size, int **matrix) {
  int ret = 0;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<max_sum_for_submatrix>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int max_sum_for_submatrix(unsigned int size, int **matrix) {
  int ret = 0;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<max_sum_for_submatrix>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int max_sum_for_submatrix(unsigned int size, int **matrix) {
  int ret = 0;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<refresh_records>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <read_records_from_file@plt>
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D19
type_infered: string

tool: D4: read from records.z


tool: D19: records.z

assistant: ```c
int refresh_records(struct htable *ds, struct rbtree *rbt) {
  printf("read from records.z\n");
  return read_records_from_file("records.z", ds, rbt);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<refresh_records>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <read_records_from_file@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D10
data_type: string
name: extract_symbolic_data
arguments: label: D5
data_type: string

tool: D10: read from records.z


tool: D5: records.z

assistant: ```c
int refresh_records(struct htable *ds, struct rbtree *rbt) {
  printf("read from records.z\n");
  return read_records_from_file("records.z", ds, rbt);
}
```
user: Translate the below assembly code into C programming language:

```asm
<refresh_records>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D11(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <read_records_from_file@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D11
type_infered: string
name: disassemble_data
arguments: data_tag: D2
type_infered: string

tool: D11: read from records.z


tool: D2: records.z

assistant: ```c
int refresh_records(struct htable *ds, struct rbtree *rbt) {
  printf("read from records.z\n");
  return read_records_from_file("records.z", ds, rbt);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<refresh_records>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  lea    D13(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    D16(%rip),%rdi
  pop    %rbp
  pop    %r12
  jmp    1060 <read_records_from_file@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_infered: string
name: disassemble_data
arguments: data_label: D16
type_infered: string

tool: D13: read from records.z


tool: D16: records.z

assistant: ```c
int refresh_records(struct htable *ds, struct rbtree *rbt) {
  printf("read from records.z\n");
  return read_records_from_file("records.z", ds, rbt);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x2,-0x4(%rbp)
  jmp    L14
L10:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L27
  mov    $0x0,%eax
  jmp    L15
L27:
  nop
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jge    L10
  mov    $0x1,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
bool prime(int num) {
  int i;
  for (i = 2; i * i < (num + 1); i++) {
    if (num % i == 0)
      return false;
    else
      continue;
  }
  return true;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<prime>:
  endbr64
  cmp    $0x3,%edi
  jle    L37
  mov    $0x0,%eax
  mov    $0x2,%ecx
  test   $0x1,%dil
  jne    L18
L8:
  ret
L18:
  add    $0x1,%ecx
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %edi,%eax
  jg     L55
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  je     L8
  jmp    L18
L55:
  mov    $0x1,%eax
  ret
L37:
  mov    $0x1,%eax
  jmp    L8
```

assistant: ```c
bool prime(int num) {
  int i;
  for (i = 2; i * i < (num + 1); i++) {
    if (num % i == 0)
      return false;
    else
      continue;
  }
  return true;
}
```