ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<yyerror>:
  endbr64
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: Exiting with -1 status

assistant: ```c
void yyerror(s) char *s;
{
  printf("%s\n", s);
  printf("Exiting with -1 status\n");
  exit(-1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0xc(%rbp)
L17:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L16
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
  jmp    L17
L16:
  nop
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
type_infered: string
name: read_data
arguments: tag: D1
type_infered: string

tool: D0: %d


tool: D1: Case %d: %d


assistant: ```c
int main() {
  int x, i;
  for (i = 1;; i++) {
    scanf("%d\n", &x);
    if (x == 0)
      break;
    printf("Case %d: %d\n", i, x);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebx
  lea    0x4(%rsp),%r12
  lea    D18(%rip),%rbp
  lea    D13(%rip),%r13
  jmp    L5
L11:
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
L5:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L11
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D18
data_type: string
name: unpack_data
arguments: label: D13
data_type: string

tool: D18: %d


tool: D13: Case %d: %d


assistant: ```c
int main() {
  int x, i;
  for (i = 1;; i++) {
    scanf("%d\n", &x);
    if (x == 0)
      break;
    printf("Case %d: %d\n", i, x);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  push   %rbp
  lea    D16(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L12:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
L27:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L12
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D0
type_guessed: string
name: read_data
arguments: tag: D16
type_guessed: string

tool: D0: Case %d: %d


tool: D16: %d


assistant: ```c
int main() {
  int x, i;
  for (i = 1;; i++) {
    scanf("%d\n", &x);
    if (x == 0)
      break;
    printf("Case %d: %d\n", i, x);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D10(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  jmp    L3
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
L3:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jne    L28
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D10
type_guessed: string
name: read_data
arguments: tag: D12
type_guessed: string

tool: D10: Case %d: %d


tool: D12: %d


assistant: ```c
int main() {
  int x, i;
  for (i = 1;; i++) {
    scanf("%d\n", &x);
    if (x == 0)
      break;
    printf("Case %d: %d\n", i, x);
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mergeSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  mov    %r8,-0x30(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L6
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x30(%rbp),%rdi
  mov    -0x28(%rbp),%rcx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <mergeSort>
  mov    -0x28(%rbp),%rdi
  mov    -0x20(%rbp),%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    -0x30(%rbp),%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   *%r9
  nop
L6:
  nop
  leave
  ret
```

assistant: ```c
void mergeSort(void *arr, int left, int right, int (*comp)(void *, void *), void (*merge)(void *, int, int, int, int (*)(void *, void *))) {
  if (left < right) {
    int mid = (left + right) / 2;
    mergeSort(arr, left, mid, comp, merge);
    mergeSort(arr, mid + 1, right, comp, merge);
    merge(arr, left, mid, right, comp);
  }
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
L0:
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %rcx,%r14
  mov    %r8,%r15
  lea    (%rsi,%rdx,1),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %r12d,%edx
  call   <mergeSort>
  lea    0x1(%r12),%esi
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %ebp,%edx
  mov    %r13,%rdi
  call   <mergeSort>
  mov    %r14,%r8
  mov    %ebp,%ecx
  mov    %r12d,%edx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   *%r15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void mergeSort(void *arr, int left, int right, int (*comp)(void *, void *), void (*merge)(void *, int, int, int, int (*)(void *, void *))) {
  if (left < right) {
    int mid = (left + right) / 2;
    mergeSort(arr, left, mid, comp, merge);
    mergeSort(arr, mid + 1, right, comp, merge);
    merge(arr, left, mid, right, comp);
  }
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<mergeSort>:
  endbr64
  cmp    %edx,%esi
  jl     L6
  ret
  nopl   0x0(%rax)
L6:
  lea    (%rsi,%rdx,1),%eax
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %eax,%r14d
  push   %r13
  shr    $0x1f,%r14d
  mov    %r8,%r13
  push   %r12
  add    %eax,%r14d
  mov    %edx,%r12d
  push   %rbp
  sar    %r14d
  mov    %esi,%ebp
  push   %rbx
  mov    %r14d,%edx
  mov    %rcx,%rbx
  sub    $0x8,%rsp
  call   <mergeSort>
  lea    0x1(%r14),%esi
  mov    %r13,%r8
  mov    %rbx,%rcx
  mov    %r12d,%edx
  mov    %r15,%rdi
  call   <mergeSort>
  add    $0x8,%rsp
  mov    %rbx,%r8
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    *%rax
```

assistant: ```c
void mergeSort(void *arr, int left, int right, int (*comp)(void *, void *), void (*merge)(void *, int, int, int, int (*)(void *, void *))) {
  if (left < right) {
    int mid = (left + right) / 2;
    mergeSort(arr, left, mid, comp, merge);
    mergeSort(arr, mid + 1, right, comp, merge);
    merge(arr, left, mid, right, comp);
  }
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substringx>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %ecx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x32,%ecx
  jg     L4
L57:
  mov    (%r14),%rdi
  mov    %rdi,0x10(%rsp)
  call   <strlen@plt>
  mov    %eax,%r15d
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,0x8(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    %rbp,%rsi
  mov    0x10(%rsp),%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  mov    $0x0,%eax
  test   %rbx,%rbx
  je     L27
  add    0x8(%rsp),%r15d
  lea    0x1(%r12,%r15,1),%r15d
  mov    $0x1,%esi
  mov    %r15d,%edi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L22:
  mov    0x10(%rsp),%rsi
  mov    %rbx,%r15
  sub    %rsi,%r15
  mov    %r15d,%edx
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %r15d,%r15
  lea    (%r12,%r15,1),%rdi
  mov    %r13,%rsi
  call   <strcpy@plt>
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,0x8(%rsp)
  mov    %rbp,%rdi
  call   <strlen@plt>
  cltq
  lea    (%rbx,%rax,1),%rsi
  movslq 0x8(%rsp),%rdi
  add    %r15,%rdi
  add    %r12,%rdi
  call   <strcpy@plt>
  lea    0x10(%rsp),%rdi
  call   <freestring@plt>
  mov    %r12,%rdi
  call   <strdup@plt>
  mov    %rax,(%r14)
  mov    %r12,%rdi
  call   <free@plt>
  mov    0xc(%rsp),%ecx
  add    $0x1,%ecx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <substringx>
  add    $0x1,%eax
L27:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L39
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    (%rdi),%rsi
  lea    D18(%rip),%rdi
  mov    $0x0,%eax
  call   <fatalx@plt>
  jmp    L57
L15:
  mov    %r15d,%esi
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <fatalx@plt>
  jmp    L22
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D18: bad string replacement
 %s


tool: D9: Unable to allocate %d unit(s) for item 


assistant: ```c
int substringx(char **ap, char *inx, char *outx, int niter) {
  char *a, *pt;
  char *str;
  int len, off, x;
  if (niter > 50)
    fatalx("bad string replacement\n %s\n", *ap);
  a = *ap;
  len = strlen(a) + strlen(inx) + strlen(outx) + 1;
  pt = strstr(a, inx);
  if (pt == NULL) {
    return 0;
  }
  if ((str = (char *)calloc((len), sizeof(char))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  off = pt - a;
  strncpy(str, a, off);
  strcpy(str + off, outx);
  x = strlen(outx);
  pt += strlen(inx);
  strcpy(str + off + x, pt);
  freestring(&a);
  *ap = strdup(str);
  free(str);
  return (1 + substringx(ap, inx, outx, niter + 1));
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<substringx>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x32,%ecx
  jg     L42
L49:
  mov    (%r14),%rdi
  mov    %rdi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %eax,%r15d
  call   <strstr@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  je     L32
  mov    0x8(%rsp),%eax
  mov    $0x1,%esi
  add    %r13d,%eax
  lea    0x1(%r15,%rax,1),%r15d
  mov    %r15d,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L40
L7:
  mov    0x10(%rsp),%rsi
  mov    %rbx,%r15
  mov    %r13,%rdi
  sub    %rsi,%r15
  mov    %r15d,%edx
  movslq %r15d,%r15
  call   <strncpy@plt>
  mov    %r12,%rsi
  lea    0x0(%r13,%r15,1),%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <strlen@plt>
  movslq 0x8(%rsp),%rdi
  cltq
  add    %r15,%rdi
  lea    (%rbx,%rax,1),%rsi
  add    %r13,%rdi
  call   <strcpy@plt>
  lea    0x10(%rsp),%rdi
  call   <freestring@plt>
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    %rax,(%r14)
  call   <free@plt>
  mov    0xc(%rsp),%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%ecx
  call   <substringx>
  add    $0x1,%eax
L32:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %r15d,%esi
  lea    D18(%rip),%rdi
  xor    %eax,%eax
  call   <fatalx@plt>
  jmp    L7
  xchg   %ax,%ax
L42:
  mov    (%rdi),%rsi
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <fatalx@plt>
  jmp    L49
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D18
data_type: string
name: disassemble_data
arguments: tag: D1
data_type: string

tool: D18: Unable to allocate %d unit(s) for item 


tool: D1: bad string replacement
 %s


assistant: ```c
int substringx(char **ap, char *inx, char *outx, int niter) {
  char *a, *pt;
  char *str;
  int len, off, x;
  if (niter > 50)
    fatalx("bad string replacement\n %s\n", *ap);
  a = *ap;
  len = strlen(a) + strlen(inx) + strlen(outx) + 1;
  pt = strstr(a, inx);
  if (pt == NULL) {
    return 0;
  }
  if ((str = (char *)calloc((len), sizeof(char))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  off = pt - a;
  strncpy(str, a, off);
  strcpy(str + off, outx);
  x = strlen(outx);
  pt += strlen(inx);
  strcpy(str + off + x, pt);
  freestring(&a);
  *ap = strdup(str);
  free(str);
  return (1 + substringx(ap, inx, outx, niter + 1));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<substringx>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %ecx,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  cmp    $0x32,%ecx
  jg     L28
L36:
  mov    (%r14),%rdi
  mov    %rdi,0x10(%rsp)
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  mov    0x10(%rsp),%rdi
  mov    %rbp,%rsi
  mov    %eax,%r15d
  call   <strstr@plt>
  mov    %rax,%rbx
  xor    %eax,%eax
  test   %rbx,%rbx
  je     L30
  mov    0x8(%rsp),%eax
  mov    $0x1,%esi
  add    %r13d,%eax
  lea    0x1(%r15,%rax,1),%r15d
  mov    %r15d,%edi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L26
L56:
  mov    0x10(%rsp),%rsi
  mov    %rbx,%r15
  mov    %r13,%rdi
  sub    %rsi,%r15
  mov    %r15d,%edx
  movslq %r15d,%r15
  call   <strncpy@plt>
  mov    %r12,%rsi
  lea    0x0(%r13,%r15,1),%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %eax,0x8(%rsp)
  call   <strlen@plt>
  movslq 0x8(%rsp),%rdi
  cltq
  add    %r15,%rdi
  lea    (%rbx,%rax,1),%rsi
  add    %r13,%rdi
  call   <strcpy@plt>
  lea    0x10(%rsp),%rdi
  call   <freestring@plt>
  mov    %r13,%rdi
  call   <strdup@plt>
  mov    %r13,%rdi
  mov    %rax,(%r14)
  call   <free@plt>
  mov    0xc(%rsp),%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  add    $0x1,%ecx
  call   <substringx>
  add    $0x1,%eax
L30:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L46
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L26:
  mov    %r15d,%esi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <fatalx@plt>
  jmp    L56
  xchg   %ax,%ax
L28:
  mov    (%rdi),%rsi
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <fatalx@plt>
  jmp    L36
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D6
data_type: string
name: disassemble_data
arguments: label: D10
data_type: string

tool: D6: Unable to allocate %d unit(s) for item 


tool: D10: bad string replacement
 %s


assistant: ```c
int substringx(char **ap, char *inx, char *outx, int niter) {
  char *a, *pt;
  char *str;
  int len, off, x;
  if (niter > 50)
    fatalx("bad string replacement\n %s\n", *ap);
  a = *ap;
  len = strlen(a) + strlen(inx) + strlen(outx) + 1;
  pt = strstr(a, inx);
  if (pt == NULL) {
    return 0;
  }
  if ((str = (char *)calloc((len), sizeof(char))) == NULL)
    fatalx("Unable to allocate %d unit(s) for item \n", len);
  off = pt - a;
  strncpy(str, a, off);
  strcpy(str + off, outx);
  x = strlen(outx);
  pt += strlen(inx);
  strcpy(str + off + x, pt);
  freestring(&a);
  *ap = strdup(str);
  free(str);
  return (1 + substringx(ap, inx, outx, niter + 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D55(%rip),%rdi
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x10(%rsp),%xmm3
  comiss %xmm3,%xmm1
  jb     L79
  movss  0x14(%rsp),%xmm4
  comiss %xmm4,%xmm1
  jb     L32
  comiss %xmm4,%xmm3
  jb     L114
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm4,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm3,%xmm1
  lea    D66(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L123
L114:
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm3,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm4,%xmm1
  lea    D66(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L123
L79:
  movss  0x14(%rsp),%xmm4
  comiss %xmm4,%xmm3
  jb     L63
L54:
  comiss %xmm4,%xmm1
  jb     L73
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm4,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D66(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
L123:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L73:
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm3,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm4,%xmm1
  lea    D66(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L123
L63:
  comiss %xmm3,%xmm1
  jae    L84
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm4,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm3,%xmm1
  lea    D66(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L123
L32:
  comiss %xmm4,%xmm3
  jae    L54
L84:
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm4,%xmm0
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm3,%xmm2
  cvtss2sd %xmm1,%xmm1
  lea    D66(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L123
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D55
type: string
name: unpack_data
arguments: tag: D19
type: string
name: unpack_data
arguments: tag: D66
type: string

tool: D55: 
Digite 3 valores:

tool: D19: %f%f%f

tool: D66: 
%.2f, %.2f, %.2f


assistant: ```c
int main() {
  float a, b, c;
  printf("\nDigite 3 valores:\n");
  scanf("%f%f%f", &a, &b, &c);
  if (a >= b && a >= c) {
    if (b >= c) {
      printf("\n%.2f, %.2f, %.2f\n", a, b, c);
    } else {
      printf("\n%.2f, %.2f, %.2f\n", a, c, b);
    }
  } else {
    if (b >= c) {
      if (a >= c) {
        printf("\n%.2f, %.2f, %.2f\n", b, a, c);
      } else {
        printf("\n%.2f, %.2f, %.2f\n", b, c, a);
      }
    } else {
      if (a >= b) {
        printf("\n%.2f, %.2f, %.2f\n", c, a, b);
      } else {
        printf("\n%.2f, %.2f, %.2f\n", c, b, a);
      }
    }
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D44(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  movss  0xc(%rsp),%xmm4
  movss  0x10(%rsp),%xmm3
  movss  0x14(%rsp),%xmm2
  comiss %xmm3,%xmm4
  jb     L85
  comiss %xmm2,%xmm4
  jb     L59
  comiss %xmm2,%xmm3
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm4,%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm2,%xmm1
  cvtss2sd %xmm3,%xmm4
  jb     L1
  movapd %xmm1,%xmm2
  lea    D45(%rip),%rdi
  movapd %xmm4,%xmm1
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L33
L85:
  comiss %xmm2,%xmm3
  jae    L15
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtss2sd %xmm2,%xmm0
  lea    D45(%rip),%rdi
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm3,%xmm1
  cvtss2sd %xmm4,%xmm2
  call   <printf@plt>
  nopl   0x0(%rax)
L33:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L59:
  comiss %xmm2,%xmm3
  jb     L70
L15:
  comiss %xmm2,%xmm4
  pxor   %xmm5,%xmm5
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm4,%xmm5
  cvtss2sd %xmm3,%xmm0
  cvtss2sd %xmm2,%xmm1
  jb     L110
  movapd %xmm1,%xmm2
  lea    D45(%rip),%rdi
  movapd %xmm5,%xmm1
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L33
L110:
  movapd %xmm5,%xmm2
  lea    D45(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L33
L70:
  pxor   %xmm0,%xmm0
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtss2sd %xmm2,%xmm0
  lea    D45(%rip),%rdi
  pxor   %xmm2,%xmm2
  cvtss2sd %xmm4,%xmm1
  cvtss2sd %xmm3,%xmm2
  call   <printf@plt>
  jmp    L33
L1:
  movapd %xmm4,%xmm2
  lea    D45(%rip),%rdi
  mov    $0x3,%eax
  call   <printf@plt>
  jmp    L33
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D44
datatype: string
name: retrieve_data
arguments: data_label: D2
datatype: string
name: retrieve_data
arguments: data_label: D45
datatype: string

tool: D44: 
Digite 3 valores:

tool: D2: %f%f%f

tool: D45: 
%.2f, %.2f, %.2f


assistant: ```c
int main() {
  float a, b, c;
  printf("\nDigite 3 valores:\n");
  scanf("%f%f%f", &a, &b, &c);
  if (a >= b && a >= c) {
    if (b >= c) {
      printf("\n%.2f, %.2f, %.2f\n", a, b, c);
    } else {
      printf("\n%.2f, %.2f, %.2f\n", a, c, b);
    }
  } else {
    if (b >= c) {
      if (a >= c) {
        printf("\n%.2f, %.2f, %.2f\n", b, a, c);
      } else {
        printf("\n%.2f, %.2f, %.2f\n", b, c, a);
      }
    } else {
      if (a >= b) {
        printf("\n%.2f, %.2f, %.2f\n", c, a, b);
      } else {
        printf("\n%.2f, %.2f, %.2f\n", c, b, a);
      }
    }
  }
  return 0;
}
```