ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<bb_serial_read>:
  endbr64
  push   %r14
  xor    %r8d,%r8d
  mov    %rdx,%r14
  mov    %esi,%edx
  push   %r13
  mov    $0x2b,%esi
  mov    %rcx,%r13
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <pigpio_command@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L1
  mov    %eax,%ecx
  mov    %r13,%rdx
  mov    %r14,%rsi
  mov    %ebp,%edi
  call   <recvMax@plt>
  mov    %eax,%r12d
L1:
  mov    %ebp,%edi
  call   <_pmu@plt>
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int bb_serial_read(int pi, unsigned user_gpio, void *buf, size_t bufSize) {
  int bytes;
  bytes = pigpio_command(pi, 43, user_gpio, bufSize, 0);
  if (bytes > 0) {
    bytes = recvMax(pi, buf, bufSize, bytes);
  }
  _pmu(pi);
  return bytes;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func_eval>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <install_variable_buffer@plt>
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <eval_buffer@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <restore_variable_buffer@plt>
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
char *func_eval(char *o, char **argv, const char *funcname __attribute__((unused))) {
  char *buf;
  unsigned int len;
  install_variable_buffer(&buf, &len);
  eval_buffer(argv[0]);
  restore_variable_buffer(buf, len);
  return o;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<func_eval>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <install_variable_buffer@plt>
  mov    (%rbx),%rdi
  call   <eval_buffer@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <restore_variable_buffer@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    %rbp,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *func_eval(char *o, char **argv, const char *funcname __attribute__((unused))) {
  char *buf;
  unsigned int len;
  install_variable_buffer(&buf, &len);
  eval_buffer(argv[0]);
  restore_variable_buffer(buf, len);
  return o;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func_eval>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  call   <install_variable_buffer@plt>
  mov    (%rbx),%rdi
  call   <eval_buffer@plt>
  mov    0xc(%rsp),%esi
  mov    0x10(%rsp),%rdi
  call   <restore_variable_buffer@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *func_eval(char *o, char **argv, const char *funcname __attribute__((unused))) {
  char *buf;
  unsigned int len;
  install_variable_buffer(&buf, &len);
  eval_buffer(argv[0]);
  restore_variable_buffer(buf, len);
  return o;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getSize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
L2:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    $0xffffffff,%eax
  jne    L10
  mov    -0x4(%rbp),%eax
  jmp    L7
L10:
  addl   $0x1,-0x4(%rbp)
  jmp    L2
L7:
  pop    %rbp
  ret
```

assistant: ```c
int getSize(int *array) {
  int i = 0;
  while (1) {
    if (array[i] == -1)
      return i;
    else
      i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<getSize>:
  endbr64
  mov    $0x1,%eax
  mov    $0x0,%edx
  cmpl   $0xffffffff,(%rdi)
  je     L12
L0:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpl   $0xffffffff,-0x4(%rdi,%rax,4)
  jne    L0
L12:
  mov    %edx,%eax
  ret
```

assistant: ```c
int getSize(int *array) {
  int i = 0;
  while (1) {
    if (array[i] == -1)
      return i;
    else
      i++;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getSize>:
  endbr64
  xor    %r8d,%r8d
  cmpl   $0xffffffff,(%rdi)
  mov    $0x1,%eax
  je     L7
  nopl   0x0(%rax)
L3:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpl   $0xffffffff,-0x4(%rdi,%rax,4)
  jne    L3
L7:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getSize(int *array) {
  int i = 0;
  while (1) {
    if (array[i] == -1)
      return i;
    else
      i++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<getSize>:
  endbr64
  xor    %r8d,%r8d
  cmpl   $0xffffffff,(%rdi)
  mov    $0x1,%eax
  je     L19
  nopl   0x0(%rax)
L11:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpl   $0xffffffff,-0x4(%rdi,%rax,4)
  jne    L11
L19:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int getSize(int *array) {
  int i = 0;
  while (1) {
    if (array[i] == -1)
      return i;
    else
      i++;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PintegerValue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xffffffff,-0x4(%rbp)
  mov    $0x0,%eax
  call   <PintegerToken@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <PvalueNameRef@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pfloor@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pceiling@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pfix@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pmod@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <PxCoord@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <PyCoord@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pabs@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pmax@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pmin@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pnegate@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Pproduct@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Psubtract@plt>
  test   %rax,%rax
  jne    L76
  mov    $0x0,%eax
  call   <Psum@plt>
  test   %rax,%rax
  je     L105
L76:
  mov    $0x1,%eax
  jmp    L107
L105:
  mov    $0x0,%eax
L107:
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
PintegerValue() {
  int b = -1;
  ;
  b = PintegerToken() || PvalueNameRef() || Pfloor() || Pceiling() || Pfix() || Pmod() || PxCoord() || PyCoord() || Pabs() || Pmax() || Pmin() || Pnegate() || Pproduct() || Psubtract() || Psum();
  return (b);
}
```
user: Translate the below assembly code into C programming language:

```asm
<PintegerValue>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <PintegerToken@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L8
L45:
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <PvalueNameRef@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pfloor@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pceiling@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pfix@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pmod@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <PxCoord@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <PyCoord@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pabs@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pmax@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pmin@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pnegate@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Pproduct@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Psubtract@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L45
  mov    $0x0,%eax
  call   <Psum@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L45
```

assistant: ```c
PintegerValue() {
  int b = -1;
  ;
  b = PintegerToken() || PvalueNameRef() || Pfloor() || Pceiling() || Pfix() || Pmod() || PxCoord() || PyCoord() || Pabs() || Pmax() || Pmin() || Pnegate() || Pproduct() || Psubtract() || Psum();
  return (b);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<PintegerValue>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PintegerToken@plt>
  test   %rax,%rax
  je     L75
L72:
  mov    $0x1,%eax
L22:
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L75:
  xor    %eax,%eax
  call   <PvalueNameRef@plt>
  test   %rax,%rax
  jne    L72
  call   <Pfloor@plt>
  test   %rax,%rax
  jne    L72
  call   <Pceiling@plt>
  test   %rax,%rax
  jne    L72
  call   <Pfix@plt>
  test   %rax,%rax
  jne    L72
  call   <Pmod@plt>
  test   %rax,%rax
  jne    L72
  call   <PxCoord@plt>
  test   %rax,%rax
  jne    L72
  call   <PyCoord@plt>
  test   %rax,%rax
  jne    L72
  call   <Pabs@plt>
  test   %rax,%rax
  jne    L72
  call   <Pmax@plt>
  test   %rax,%rax
  jne    L72
  call   <Pmin@plt>
  test   %rax,%rax
  jne    L72
  call   <Pnegate@plt>
  test   %rax,%rax
  jne    L72
  call   <Pproduct@plt>
  test   %rax,%rax
  jne    L72
  call   <Psubtract@plt>
  test   %rax,%rax
  jne    L72
  call   <Psum@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L22
```

assistant: ```c
PintegerValue() {
  int b = -1;
  ;
  b = PintegerToken() || PvalueNameRef() || Pfloor() || Pceiling() || Pfix() || Pmod() || PxCoord() || PyCoord() || Pabs() || Pmax() || Pmin() || Pnegate() || Pproduct() || Psubtract() || Psum();
  return (b);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<PintegerValue>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <PintegerToken@plt>
  test   %rax,%rax
  je     L34
L139:
  mov    $0x1,%eax
L69:
  add    $0x8,%rsp
  ret
  xchg   %ax,%ax
L34:
  xor    %eax,%eax
  call   <PvalueNameRef@plt>
  test   %rax,%rax
  jne    L139
  call   <Pfloor@plt>
  test   %rax,%rax
  jne    L139
  call   <Pceiling@plt>
  test   %rax,%rax
  jne    L139
  call   <Pfix@plt>
  test   %rax,%rax
  jne    L139
  call   <Pmod@plt>
  test   %rax,%rax
  jne    L139
  call   <PxCoord@plt>
  test   %rax,%rax
  jne    L139
  call   <PyCoord@plt>
  test   %rax,%rax
  jne    L139
  call   <Pabs@plt>
  test   %rax,%rax
  jne    L139
  call   <Pmax@plt>
  test   %rax,%rax
  jne    L139
  call   <Pmin@plt>
  test   %rax,%rax
  jne    L139
  call   <Pnegate@plt>
  test   %rax,%rax
  jne    L139
  call   <Pproduct@plt>
  test   %rax,%rax
  jne    L139
  call   <Psubtract@plt>
  test   %rax,%rax
  jne    L139
  call   <Psum@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  jmp    L69
```

assistant: ```c
PintegerValue() {
  int b = -1;
  ;
  b = PintegerToken() || PvalueNameRef() || Pfloor() || Pceiling() || Pfix() || Pmod() || PxCoord() || PyCoord() || Pabs() || Pmax() || Pmin() || Pnegate() || Pproduct() || Psubtract() || Psum();
  return (b);
}
```
user: What is the c source code of the assembly code below:

```asm
<maxProfit0>:
  endbr64
  mov    $0x0,%ecx
  cmp    $0x1,%edx
  jle    L28
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%r13d
  mov    %rsi,%rbx
  mov    %edx,%r12d
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  cmp    %edi,%eax
  jge    L6
  mov    %rsi,%rax
  lea    -0x2(%rdx),%edx
  lea    0x4(%rsi,%rdx,4),%r8
L5:
  mov    0x4(%rax),%edi
  mov    (%rax),%esi
  mov    %edi,%edx
  sub    %esi,%edx
  add    %ecx,%edx
  cmp    %esi,%edi
  cmovg  %edx,%ecx
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L5
  jmp    L63
L6:
  lea    0x8(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rsi
  mov    %rax,0x8(%rsp)
  test   %r13d,%r13d
  js     L38
  lea    0x0(,%r12,4),%r14d
  mov    %rax,%rbp
  lea    0x1(%r13),%eax
  lea    (%rsi,%rax,8),%r15
L71:
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,0x0(%rbp)
  mov    %r14d,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  jne    L71
L38:
  test   %r13d,%r13d
  jle    L0
  mov    0x8(%rsp),%rsi
  lea    0x8(%rsi),%r9
  lea    -0x1(%r13),%eax
  lea    0x10(%rsi,%rax,8),%r10
  mov    %r12d,%r8d
  shl    $0x2,%r8
L79:
  mov    (%rbx),%ecx
  neg    %ecx
  mov    %r9,%rdi
  lea    -0x8(%r9),%rsi
  mov    $0x4,%eax
L35:
  mov    (%rdi),%r11
  mov    %ecx,%edx
  add    (%rbx,%rax,1),%edx
  mov    -0x4(%r11,%rax,1),%ebp
  cmp    %ebp,%edx
  cmovl  %ebp,%edx
  mov    %edx,(%r11,%rax,1)
  mov    (%rsi),%rdx
  mov    -0x4(%rdx,%rax,1),%edx
  sub    (%rbx,%rax,1),%edx
  cmp    %edx,%ecx
  cmovl  %edx,%ecx
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L35
  add    $0x8,%r9
  cmp    %r10,%r9
  jne    L79
L0:
  movslq %r13d,%r13
  movslq %r12d,%r12
  mov    0x8(%rsp),%rax
  mov    (%rax,%r13,8),%rax
  mov    -0x4(%rax,%r12,4),%ecx
L63:
  mov    %ecx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int maxProfit0(int k, int *prices, int size) {
  if (size < 2)
    return 0;
  if (k > size / 2) {
    int profit = 0;
    for (int i = 1; i < size; i++)
      if (prices[i] > prices[i - 1])
        profit += prices[i] - prices[i - 1];
    return profit;
  }
  int **t = (int **)malloc(sizeof(int *) * (k + 1));
  for (int i = 0; i <= k; i++) {
    t[i] = (int *)malloc(sizeof(int) * size);
    memset(t[i], 0, sizeof(int) * size);
  }
  int cur = 0;
  for (int i = 1; i <= k; i++) {
    cur = -prices[0];
    for (int j = 1; j < size; j++) {
      t[i][j] = (t[i][j - 1]) > (prices[j] + cur) ? (t[i][j - 1]) : (prices[j] + cur);
      cur = (cur) > (t[i - 1][j - 1] - prices[j]) ? (cur) : (t[i - 1][j - 1] - prices[j]);
    }
  }
  return t[k][size - 1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<maxProfit0>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  push   %r14
  push   %r13
  push   %r12
  movslq %edx,%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  cmp    $0x1,%r12d
  jle    L49
  mov    %r12d,%eax
  movslq %edi,%rbx
  mov    %rsi,%rbp
  sar    %eax
  cmp    %ebx,%eax
  jge    L40
  lea    -0x2(%r12),%eax
  mov    %rsi,%rcx
  lea    0x4(%rsi,%rax,4),%rdi
  nopw   0x0(%rax,%rax,1)
L25:
  mov    0x4(%rcx),%esi
  mov    (%rcx),%edx
  mov    %esi,%eax
  sub    %edx,%eax
  add    %r8d,%eax
  cmp    %edx,%esi
  cmovg  %eax,%r8d
  add    $0x4,%rcx
  cmp    %rcx,%rdi
  jne    L25
L49:
  add    $0x18,%rsp
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L40:
  lea    0x1(%rbx),%r15d
  lea    0x0(,%r15,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %ebx,%ebx
  js     L34
  movslq %r15d,%r15
  lea    0x0(,%r12,4),%r14d
  mov    %rax,%r13
  lea    (%rax,%r15,8),%r15
  nopl   0x0(%rax)
L72:
  mov    %r14d,%edi
  add    $0x8,%r13
  call   <malloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %rax,-0x8(%r13)
  mov    %rax,%rdi
  call   <memset@plt>
  cmp    %r13,%r15
  jne    L72
L34:
  test   %ebx,%ebx
  jle    L21
  mov    0x8(%rsp),%rcx
  lea    -0x1(%rbx),%eax
  lea    0x8(%rcx),%r10
  lea    0x10(%rcx,%rax,8),%r11
  nopw   0x0(%rax,%rax,1)
L67:
  mov    0x0(%rbp),%esi
  mov    (%r10),%r8
  mov    $0x1,%eax
  mov    -0x8(%r10),%r9
  neg    %esi
  nopl   0x0(%rax)
L0:
  mov    0x0(%rbp,%rax,4),%edx
  mov    -0x4(%r8,%rax,4),%edi
  add    %esi,%edx
  cmp    %edi,%edx
  cmovl  %edi,%edx
  mov    %edx,(%r8,%rax,4)
  mov    -0x4(%r9,%rax,4),%edx
  sub    0x0(%rbp,%rax,4),%edx
  cmp    %edx,%esi
  cmovl  %edx,%esi
  add    $0x1,%rax
  cmp    %rax,%r12
  jne    L0
  add    $0x8,%r10
  cmp    %r10,%r11
  jne    L67
L21:
  mov    0x8(%rsp),%rax
  mov    (%rax,%rbx,8),%rax
  mov    -0x4(%rax,%r12,4),%r8d
  jmp    L49
```

assistant: ```c
int maxProfit0(int k, int *prices, int size) {
  if (size < 2)
    return 0;
  if (k > size / 2) {
    int profit = 0;
    for (int i = 1; i < size; i++)
      if (prices[i] > prices[i - 1])
        profit += prices[i] - prices[i - 1];
    return profit;
  }
  int **t = (int **)malloc(sizeof(int *) * (k + 1));
  for (int i = 0; i <= k; i++) {
    t[i] = (int *)malloc(sizeof(int) * size);
    memset(t[i], 0, sizeof(int) * size);
  }
  int cur = 0;
  for (int i = 1; i <= k; i++) {
    cur = -prices[0];
    for (int j = 1; j < size; j++) {
      t[i][j] = (t[i][j - 1]) > (prices[j] + cur) ? (t[i][j - 1]) : (prices[j] + cur);
      cur = (cur) > (t[i - 1][j - 1] - prices[j]) ? (cur) : (t[i - 1][j - 1] - prices[j]);
    }
  }
  return t[k][size - 1];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<b1_put_byte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,%eax
  mov    %al,-0x8(%rbp)
  nop
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <b1_tx_empty@plt>
  test   %eax,%eax
  je     L4
  movzbl -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <b1outp@plt>
  nop
  leave
  ret
```

assistant: ```c
void b1_put_byte(unsigned int base, unsigned char val) {
  while (!b1_tx_empty(base))
    ;
  b1outp(base, 0x01, val);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<b1_put_byte>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
L8:
  mov    %ebx,%edi
  call   <b1_tx_empty@plt>
  test   %eax,%eax
  je     L8
  movzbl %bpl,%edx
  mov    $0x1,%esi
  mov    %ebx,%edi
  call   <b1outp@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void b1_put_byte(unsigned int base, unsigned char val) {
  while (!b1_tx_empty(base))
    ;
  b1outp(base, 0x01, val);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<b1_put_byte>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L7:
  mov    %ebp,%edi
  call   <b1_tx_empty@plt>
  test   %eax,%eax
  je     L7
  add    $0x8,%rsp
  movzbl %bl,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <b1outp@plt>
```

assistant: ```c
void b1_put_byte(unsigned int base, unsigned char val) {
  while (!b1_tx_empty(base))
    ;
  b1outp(base, 0x01, val);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<b1_put_byte>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  xchg   %ax,%ax
L2:
  mov    %ebp,%edi
  call   <b1_tx_empty@plt>
  test   %eax,%eax
  je     L2
  add    $0x8,%rsp
  movzbl %bl,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  pop    %rbx
  pop    %rbp
  jmp    1060 <b1outp@plt>
```

assistant: ```c
void b1_put_byte(unsigned int base, unsigned char val) {
  while (!b1_tx_empty(base))
    ;
  b1outp(base, 0x01, val);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<leapyear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L15
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x64,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L8
L15:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L12
L8:
  mov    $0x1d,%eax
  jmp    L34
L12:
  mov    $0x1c,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int leapyear(int year) {
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
    return 29;
  }
  return 28;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<leapyear>:
  endbr64
  test   $0x3,%dil
  jne    L13
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x64,%eax,%eax
  mov    $0x1d,%edx
  cmp    %eax,%edi
  jne    L19
L13:
  movslq %edi,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edi,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0x190,%eax,%eax
  cmp    %eax,%edi
  sete   %dl
  movzbl %dl,%edx
  add    $0x1c,%edx
L19:
  mov    %edx,%eax
  ret
```

assistant: ```c
int leapyear(int year) {
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
    return 29;
  }
  return 28;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<leapyear>:
  endbr64
  test   $0x3,%dil
  jne    L6
  imul   $0xc28f5c29,%edi,%edx
  mov    $0x1d,%eax
  add    $0x51eb850,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L0
L6:
  imul   $0xc28f5c29,%edi,%edi
  xor    %eax,%eax
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70b,%edi
  setb   %al
  add    $0x1c,%eax
L0:
  ret
```

assistant: ```c
int leapyear(int year) {
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
    return 29;
  }
  return 28;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<leapyear>:
  endbr64
  test   $0x3,%dil
  jne    L5
  imul   $0xc28f5c29,%edi,%edx
  mov    $0x1d,%eax
  add    $0x51eb850,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L15
L5:
  imul   $0xc28f5c29,%edi,%edi
  xor    %eax,%eax
  add    $0x51eb850,%edi
  ror    $0x4,%edi
  cmp    $0xa3d70b,%edi
  setb   %al
  add    $0x1c,%eax
L15:
  ret
```

assistant: ```c
int leapyear(int year) {
  if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
    return 29;
  }
  return 28;
}
```