ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<mergeKLists0>:
  endbr64
  mov    $0x0,%eax
  test   %esi,%esi
  je     L99
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r13d
  lea    0x0(,%rsi,8),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%r12
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L17
  lea    -0x1(%r13),%edi
  mov    %r13d,%r13d
  lea    0x0(%rbp,%r13,8),%rsi
  mov    %rbp,%rax
  mov    %rbx,%rcx
  sub    %rbp,%rcx
L109:
  mov    (%rcx,%rax,1),%rdx
  mov    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %rax,%rsi
  jne    L109
  mov    %edi,%ebx
  test   %edi,%edi
  jle    L24
  mov    $0xffffffff,%ebp
  jmp    L21
L8:
  movslq %ebx,%rax
  sub    $0x2,%ebx
  add    $0x1,%ebp
  movslq %ebp,%rdx
  lea    (%r14,%rdx,8),%r13
  mov    (%r12,%rax,8),%rsi
  mov    -0x8(%r12,%rax,8),%rdi
  call   <merge@plt>
  mov    %rax,0x0(%r13)
  test   %ebx,%ebx
  js     L100
L21:
  test   %ebx,%ebx
  jg     L8
  movslq %ebx,%rax
  lea    0x1(%rbp),%ebx
  mov    (%r12,%rax,8),%rdx
  movslq %ebx,%rax
  mov    %rdx,(%r14,%rax,8)
L11:
  test   %ebx,%ebx
  jle    L88
  mov    %r12,%rax
  mov    %r14,%r12
  mov    %rax,%r14
  mov    $0xffffffff,%ebp
  jmp    L21
L100:
  mov    %ebp,%ebx
  jmp    L11
L88:
  mov    %r14,%r12
  jmp    L24
L17:
  mov    $0xffffffff,%ebx
L24:
  movslq %ebx,%rbx
  mov    (%r12,%rbx,8),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L99:
  ret
```

assistant: ```c
struct ListNode *mergeKLists0(struct ListNode **lists, int listsSize) {
  if (listsSize == 0)
    return NULL;
  struct ListNode **stack0 = (struct ListNode **)malloc(sizeof(struct ListNode *) * listsSize);
  struct ListNode **stack1 = (struct ListNode **)malloc(sizeof(struct ListNode *) * listsSize);
  int top0 = -1, top1 = -1;
  for (int i = 0; i < listsSize; i++)
    stack0[++top0] = lists[i];
  while (top0 > 0) {
    while (top0 > -1) {
      if (top0 > 0)
        stack1[++top1] = merge(stack0[top0--], stack0[top0--]);
      else
        stack1[++top1] = stack0[top0--];
    }
    top0 = top1;
    top1 = -1;
    struct ListNode **tmp = stack0;
    stack0 = stack1;
    stack1 = tmp;
  }
  return stack0[top0];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mergeKLists0>:
  endbr64
  push   %r15
  xor    %r8d,%r8d
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  test   %ebp,%ebp
  je     L23
  lea    0x0(,%rbp,8),%r12d
  mov    %rdi,%r14
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %r12d,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r13
  test   %ebp,%ebp
  jle    L28
  mov    %r14,%rdx
  lea    -0x1(%rbp),%r12d
  lea    (%rbx,%rbp,8),%rcx
  mov    %rbx,%rax
  sub    %rbx,%rdx
  nopl   0x0(%rax)
L63:
  mov    (%rdx,%rax,1),%r8
  add    $0x8,%rax
  mov    %r8,-0x8(%rax)
  cmp    %rcx,%rax
  jne    L63
  test   %r12d,%r12d
  jne    L35
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %rax,%rbx
L35:
  movslq %r12d,%rbp
  mov    %r13,%r14
  mov    $0xffffffff,%r12d
L22:
  add    $0x1,%r12d
  mov    %r14,%r15
  test   %ebp,%ebp
  jne    L93
  mov    (%rbx),%rax
  mov    %rax,(%r14)
L91:
  mov    %r13,%rax
  mov    %rbx,%r13
  test   %r12d,%r12d
  jne    L10
  mov    (%r15),%r8
L23:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L93:
  mov    (%rbx,%rbp,8),%rsi
  mov    -0x8(%rbx,%rbp,8),%rdi
  sub    $0x2,%rbp
  add    $0x8,%r14
  call   <merge@plt>
  mov    %rax,-0x8(%r14)
  cmp    $0xffffffff,%ebp
  jne    L22
  jmp    L91
L28:
  mov    -0x8(%rbx),%r8
  jmp    L23
```

assistant: ```c
struct ListNode *mergeKLists0(struct ListNode **lists, int listsSize) {
  if (listsSize == 0)
    return NULL;
  struct ListNode **stack0 = (struct ListNode **)malloc(sizeof(struct ListNode *) * listsSize);
  struct ListNode **stack1 = (struct ListNode **)malloc(sizeof(struct ListNode *) * listsSize);
  int top0 = -1, top1 = -1;
  for (int i = 0; i < listsSize; i++)
    stack0[++top0] = lists[i];
  while (top0 > 0) {
    while (top0 > -1) {
      if (top0 > 0)
        stack1[++top1] = merge(stack0[top0--], stack0[top0--]);
      else
        stack1[++top1] = stack0[top0--];
    }
    top0 = top1;
    top1 = -1;
    struct ListNode **tmp = stack0;
    stack0 = stack1;
    stack1 = tmp;
  }
  return stack0[top0];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<mergeKLists0>:
  endbr64
  push   %r14
  xor    %eax,%eax
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  test   %r13d,%r13d
  je     L112
  lea    0x0(,%r13,8),%r12d
  mov    %rdi,%rbp
  mov    %r12d,%edi
  call   <malloc@plt>
  mov    %r12d,%edi
  mov    %rax,%rbx
  call   <malloc@plt>
  mov    %rax,%r14
  test   %r13d,%r13d
  jle    L40
  lea    0x8(%rbp),%rax
  lea    -0x1(%r13),%r12d
  cmp    %rax,%rbx
  je     L8
  cmp    $0x2,%r12d
  jbe    L8
  mov    %r13d,%edx
  mov    %rbp,%rcx
  mov    %rbx,%rax
  shr    %edx
  sub    %rbx,%rcx
  shl    $0x4,%rdx
  add    %rbx,%rdx
  nopl   0x0(%rax)
L73:
  movdqu (%rax,%rcx,1),%xmm0
  add    $0x10,%rax
  movups %xmm0,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L73
  mov    %r13d,%edx
  movhlps %xmm0,%xmm1
  and    $0xfffffffe,%edx
  and    $0x1,%r13d
  movq   %xmm1,%rax
  je     L97
  movslq %edx,%rdx
  mov    0x0(%rbp,%rdx,8),%rax
  mov    %rax,(%rbx,%rdx,8)
L97:
  test   %r12d,%r12d
  jne    L133
  jmp    L112
  nopl   0x0(%rax)
L3:
  mov    %rdx,%rbx
L133:
  movslq %r12d,%rbp
  mov    %r14,%r13
  mov    $0xffffffff,%r12d
L30:
  add    $0x1,%r12d
  test   %ebp,%ebp
  jne    L77
  mov    (%rbx),%rax
  mov    %rax,0x0(%r13)
L45:
  mov    %r14,%rdx
  mov    %rbx,%r14
  test   %r12d,%r12d
  jne    L3
L112:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L77:
  mov    (%rbx,%rbp,8),%rsi
  mov    -0x8(%rbx,%rbp,8),%rdi
  sub    $0x2,%rbp
  add    $0x8,%r13
  call   <merge@plt>
  mov    %rax,-0x8(%r13)
  cmp    $0xffffffff,%ebp
  jne    L30
  jmp    L45
L8:
  lea    (%rbx,%r13,8),%rcx
  mov    %rbx,%rdx
  sub    %rbx,%rbp
  nopl   0x0(%rax,%rax,1)
L98:
  mov    0x0(%rbp,%rdx,1),%rax
  add    $0x8,%rdx
  mov    %rax,-0x8(%rdx)
  cmp    %rdx,%rcx
  jne    L98
  jmp    L97
L40:
  mov    -0x8(%rbx),%rax
  jmp    L112
```

assistant: ```c
struct ListNode *mergeKLists0(struct ListNode **lists, int listsSize) {
  if (listsSize == 0)
    return NULL;
  struct ListNode **stack0 = (struct ListNode **)malloc(sizeof(struct ListNode *) * listsSize);
  struct ListNode **stack1 = (struct ListNode **)malloc(sizeof(struct ListNode *) * listsSize);
  int top0 = -1, top1 = -1;
  for (int i = 0; i < listsSize; i++)
    stack0[++top0] = lists[i];
  while (top0 > 0) {
    while (top0 > -1) {
      if (top0 > 0)
        stack1[++top1] = merge(stack0[top0--], stack0[top0--]);
      else
        stack1[++top1] = stack0[top0--];
    }
    top0 = top1;
    top1 = -1;
    struct ListNode **tmp = stack0;
    stack0 = stack1;
    stack1 = tmp;
  }
  return stack0[top0];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sum_even>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x0,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L21:
  mov    -0xc(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L57
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jge    L50
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L25:
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  jmp    L10
L57:
  nop
  jmp    L10
L50:
  nop
L10:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D3
type_guessed: string

tool: D3: looping %d times


assistant: ```c
int sum_even(int limit) {
  int loop_count = 0;
  int f1 = 1;
  int f2 = 2;
  int sum = 0;
  while (f2 < limit) {
    sum += f2;
    loop_count++;
    int t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
  }
  printf("looping %d times\n", loop_count);
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sum_even>:
  endbr64
  push   %rbx
  cmp    $0x2,%edi
  jle    L69
  cmp    $0x5,%edi
  jle    L15
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    $0x2,%ebx
L38:
  lea    (%rdx,%rcx,1),%eax
  cmp    %eax,%edi
  jle    L51
  add    %eax,%ebx
  add    $0x1,%esi
  lea    (%rax,%rcx,1),%edx
  cmp    %edx,%edi
  jle    L51
  lea    (%rdx,%rax,1),%ecx
  cmp    %ecx,%edi
  jg     L38
L51:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L69:
  mov    $0x0,%ebx
  mov    $0x0,%esi
  jmp    L51
L15:
  mov    $0x2,%ebx
  mov    $0x1,%esi
  jmp    L51
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: string

tool: D5: looping %d times


assistant: ```c
int sum_even(int limit) {
  int loop_count = 0;
  int f1 = 1;
  int f2 = 2;
  int sum = 0;
  while (f2 < limit) {
    sum += f2;
    loop_count++;
    int t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
  }
  printf("looping %d times\n", loop_count);
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sum_even>:
  endbr64
  push   %r12
  cmp    $0x2,%edi
  jle    L41
  cmp    $0x5,%edi
  jle    L2
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    $0x2,%r12d
  jmp    L38
  nopw   0x0(%rax,%rax,1)
L53:
  lea    (%rax,%rcx,1),%edx
  add    %eax,%r12d
  add    $0x1,%esi
  cmp    %edx,%edi
  jle    L60
  lea    (%rdx,%rax,1),%ecx
  cmp    %ecx,%edi
  jle    L60
L38:
  lea    (%rdx,%rcx,1),%eax
  cmp    %eax,%edi
  jg     L53
L60:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L41:
  xor    %r12d,%r12d
  xor    %esi,%esi
  jmp    L60
L2:
  mov    $0x2,%r12d
  mov    $0x1,%esi
  jmp    L60
```

tool_calls: name: read_data
arguments: tag: D0
type: string

tool: D0: looping %d times


assistant: ```c
int sum_even(int limit) {
  int loop_count = 0;
  int f1 = 1;
  int f2 = 2;
  int sum = 0;
  while (f2 < limit) {
    sum += f2;
    loop_count++;
    int t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
  }
  printf("looping %d times\n", loop_count);
  return sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sum_even>:
  endbr64
  push   %r12
  cmp    $0x2,%edi
  jle    L0
  cmp    $0x5,%edi
  jle    L58
  mov    $0x5,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    $0x2,%r12d
  jmp    L63
  nopw   0x0(%rax,%rax,1)
L13:
  lea    (%rax,%rcx,1),%edx
  add    %eax,%r12d
  add    $0x1,%esi
  cmp    %edx,%edi
  jle    L75
  lea    (%rdx,%rax,1),%ecx
  cmp    %ecx,%edi
  jle    L75
L63:
  lea    (%rdx,%rcx,1),%eax
  cmp    %eax,%edi
  jg     L13
L75:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L0:
  xor    %r12d,%r12d
  xor    %esi,%esi
  jmp    L75
L58:
  mov    $0x2,%r12d
  mov    $0x1,%esi
  jmp    L75
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: looping %d times


assistant: ```c
int sum_even(int limit) {
  int loop_count = 0;
  int f1 = 1;
  int f2 = 2;
  int sum = 0;
  while (f2 < limit) {
    sum += f2;
    loop_count++;
    int t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
    if (f2 >= limit) {
      break;
    }
    t = f1;
    f1 = f2;
    f2 = f1 + t;
  }
  printf("looping %d times\n", loop_count);
  return sum;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pjpeg_idct_2D_double>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x618,%rsp
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
L10:
  movsd  (%rdi,%rax,1),%xmm0
  movsd  %xmm0,(%rsp,%rax,1)
  add    $0x8,%rax
  cmp    $0x200,%rax
  jne    L10
  mov    %rsp,%r13
  lea    0x400(%rsp),%rbx
  lea    0x200(%rsp),%r15
  mov    %rbx,%r14
L84:
  mov    $0x1,%ecx
  mov    %r14,%rdx
  mov    $0x1,%esi
  mov    %r13,%rdi
  call   <idct_1D_double@plt>
  add    $0x40,%r13
  add    $0x40,%r14
  cmp    %r15,%r13
  jne    L84
  lea    0x200(%rsp),%r13
  lea    0x40(%rbx),%r15
  mov    %r13,%r14
L87:
  mov    $0x8,%ecx
  mov    %r14,%rdx
  mov    $0x8,%esi
  mov    %rbx,%rdi
  call   <idct_1D_double@plt>
  add    $0x8,%rbx
  add    $0x8,%r14
  cmp    %r15,%rbx
  jne    L87
  lea    0x40(%r13),%rsi
  movslq %r12d,%rdi
  shl    $0x3,%rdi
  add    $0x240,%r13
  movsd  D6(%rip),%xmm7
  movsd  D14(%rip),%xmm6
  pxor   %xmm5,%xmm5
  movapd %xmm5,%xmm4
  movsd  D13(%rip),%xmm2
  movapd %xmm2,%xmm3
  jmp    L7
L54:
  movapd %xmm2,%xmm1
  cmpnltsd %xmm0,%xmm1
  andpd  %xmm1,%xmm0
  andnpd %xmm3,%xmm1
  orpd   %xmm1,%xmm0
  movsd  %xmm0,(%rcx)
  movsd  %xmm0,(%rdx)
  add    $0x8,%rax
  add    $0x8,%rdx
  cmp    %rsi,%rax
  je     L97
L6:
  mov    %rax,%rcx
  movapd %xmm7,%xmm1
  mulsd  (%rax),%xmm1
  addsd  %xmm6,%xmm1
  movsd  %xmm1,(%rax)
  movapd %xmm4,%xmm0
  comisd %xmm1,%xmm5
  ja     L54
  movapd %xmm1,%xmm0
  jmp    L54
L97:
  add    $0x40,%rsi
  add    %rdi,%rbp
  cmp    %r13,%rsi
  je     L93
L7:
  lea    -0x40(%rsi),%rax
  mov    %rbp,%rdx
  jmp    L6
L93:
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x618,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D14
type_guessed: byte[8]
name: extract_symbolic_data
arguments: data_label: D13
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D14": [0x00,0x00,0x00,0x00,0x00,0x00,0x60,0x40]}

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

assistant: ```c
void pjpeg_idct_2D_double(int32_t in[64], uint8_t *out, uint32_t outstride) {
  double din[64], dout[64];
  for (int i = 0; i < 64; i++)
    din[i] = in[i];
  double tmp[64];
  for (int y = 0; y < 8; y++)
    idct_1D_double(&din[8 * y], 1, &tmp[8 * y], 1);
  for (int x = 0; x < 8; x++)
    idct_1D_double(&tmp[x], 8, &dout[x], 8);
  for (int y = 0; y < 8; y++) {
    for (int x = 0; x < 8; x++) {
      int i = 8 * y + x;
      dout[i] = (dout[i] / 4) + 128;
      if (dout[i] < 0)
        dout[i] = 0;
      if (dout[i] > 255)
        dout[i] = 255;
      out[y * outstride + x] = dout[i];
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pjpeg_idct_2D_double>:
  endbr64
  push   %r15
  mov    %rdi,%r8
  mov    $0x40,%ecx
  push   %r14
  push   %r13
  mov    %edx,%r13d
  push   %r12
  mov    %rsi,%r12
  mov    %r8,%rsi
  push   %rbp
  push   %rbx
  sub    $0x618,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x608(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x400(%rsp),%rbp
  lea    0x200(%rsp),%r14
  mov    %rbx,%rdi
  mov    %rbp,%r15
  rep movsq %ds:(%rsi),%es:(%rdi)
  nopl   (%rax)
L15:
  mov    %r15,%rdx
  mov    %rbx,%rdi
  mov    $0x1,%ecx
  mov    $0x1,%esi
  call   <idct_1D_double@plt>
  add    $0x40,%rbx
  add    $0x40,%r15
  cmp    %r14,%rbx
  jne    L15
  lea    0x40(%rbp),%r15
  mov    %r14,%rbx
  nopl   0x0(%rax)
L63:
  mov    %rbx,%rdx
  mov    %rbp,%rdi
  mov    $0x8,%ecx
  mov    $0x8,%esi
  call   <idct_1D_double@plt>
  add    $0x8,%rbp
  add    $0x8,%rbx
  cmp    %r15,%rbp
  jne    L63
  movslq %r13d,%rsi
  lea    0x40(%r14),%rcx
  pxor   %xmm1,%xmm1
  movsd  D9(%rip),%xmm3
  movsd  D21(%rip),%xmm2
  movsd  D6(%rip),%xmm4
  shl    $0x3,%rsi
  add    $0x240,%r14
  nopl   0x0(%rax,%rax,1)
L4:
  lea    -0x40(%rcx),%rax
  mov    %r12,%rdx
  jmp    L38
  nopl   0x0(%rax)
L58:
  movapd %xmm4,%xmm5
  minsd  %xmm0,%xmm5
  movapd %xmm5,%xmm0
L23:
  movsd  %xmm0,(%rax)
  add    $0x8,%rax
  add    $0x8,%rdx
  movsd  %xmm0,-0x8(%rdx)
  cmp    %rax,%rcx
  je     L29
L38:
  movsd  (%rax),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  jbe    L58
  movapd %xmm1,%xmm0
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L29:
  add    $0x40,%rcx
  add    %rsi,%r12
  cmp    %r14,%rcx
  jne    L4
  mov    0x608(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x618,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L40:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
data_type: byte[8]
name: parse_data
arguments: label: D21
data_type: byte[8]
name: parse_data
arguments: label: D6
data_type: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f]}

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x60,0x40]}

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0xe0,0x6f,0x40]}

assistant: ```c
void pjpeg_idct_2D_double(int32_t in[64], uint8_t *out, uint32_t outstride) {
  double din[64], dout[64];
  for (int i = 0; i < 64; i++)
    din[i] = in[i];
  double tmp[64];
  for (int y = 0; y < 8; y++)
    idct_1D_double(&din[8 * y], 1, &tmp[8 * y], 1);
  for (int x = 0; x < 8; x++)
    idct_1D_double(&tmp[x], 8, &dout[x], 8);
  for (int y = 0; y < 8; y++) {
    for (int x = 0; x < 8; x++) {
      int i = 8 * y + x;
      dout[i] = (dout[i] / 4) + 128;
      if (dout[i] < 0)
        dout[i] = 0;
      if (dout[i] > 255)
        dout[i] = 255;
      out[y * outstride + x] = dout[i];
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<getseed>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    $0x0,%eax
  call   <srandomdev@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L10:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L10
  nop
  nop
  leave
  ret
```

assistant: ```c
void getseed(char *seed, int seedsize) {
  int i;
  srandomdev();
  for (i = 0; i < seedsize; i++) {
    seed[i] = random() & 0xff;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<getseed>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%eax
  call   <srandomdev@plt>
  test   %ebp,%ebp
  jle    L17
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%rbp
L9:
  mov    $0x0,%eax
  call   <random@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L9
L17:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void getseed(char *seed, int seedsize) {
  int i;
  srandomdev();
  for (i = 0; i < seedsize; i++) {
    seed[i] = random() & 0xff;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getseed>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <srandomdev@plt>
  test   %ebp,%ebp
  jle    L10
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <random@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L1
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void getseed(char *seed, int seedsize) {
  int i;
  srandomdev();
  for (i = 0; i < seedsize; i++) {
    seed[i] = random() & 0xff;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getseed>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <srandomdev@plt>
  test   %ebp,%ebp
  jle    L4
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <random@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L19
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void getseed(char *seed, int seedsize) {
  int i;
  srandomdev();
  for (i = 0; i < seedsize; i++) {
    seed[i] = random() & 0xff;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<ENGINE_register_complete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_ciphers@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_digests@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_RSA@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_DSA@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_DH@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_ECDH@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_ECDSA@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_EC@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_RAND@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ENGINE_register_pkey_meths@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int ENGINE_register_complete(ENGINE *e) {
  ENGINE_register_ciphers(e);
  ENGINE_register_digests(e);
  ENGINE_register_RSA(e);
  ENGINE_register_DSA(e);
  ENGINE_register_DH(e);
  ENGINE_register_ECDH(e);
  ENGINE_register_ECDSA(e);
  ENGINE_register_EC(e);
  ENGINE_register_RAND(e);
  ENGINE_register_pkey_meths(e);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ENGINE_register_complete>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <ENGINE_register_ciphers@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_digests@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_RSA@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_DSA@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_DH@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_ECDH@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_ECDSA@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_EC@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_RAND@plt>
  mov    %rbx,%rdi
  call   <ENGINE_register_pkey_meths@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int ENGINE_register_complete(ENGINE *e) {
  ENGINE_register_ciphers(e);
  ENGINE_register_digests(e);
  ENGINE_register_RSA(e);
  ENGINE_register_DSA(e);
  ENGINE_register_DH(e);
  ENGINE_register_ECDH(e);
  ENGINE_register_ECDSA(e);
  ENGINE_register_EC(e);
  ENGINE_register_RAND(e);
  ENGINE_register_pkey_meths(e);
  return 1;
}
```