ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  cmpq   $0x0,-0x28(%rbp)
  je     L44
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L44
L6:
  cmpq   $0x0,-0x28(%rbp)
  je     L49
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L5
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L5:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L49:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L44:
  nop
  leave
  ret
```

assistant: ```c
void get_entry(char *buf, int buf_size, const char **pp) {
  const char *p, *r;
  int len;
  r = *pp;
  p = strchr(r, '-');
  if (!p) {
    if (buf)
      buf[0] = '\0';
  } else {
    if (buf) {
      len = p - r;
      if (len >= buf_size)
        len = buf_size - 1;
      memcpy(buf, r, len);
      buf[len] = '\0';
    }
    *pp = p + 1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_entry>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    %rdx,%r12
  mov    (%rdx),%r14
  mov    $0x2d,%esi
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L6
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L16
  sub    %r14,%rax
  lea    -0x1(%r13),%edx
  cmp    %eax,%r13d
  cmovg  %eax,%edx
  mov    %edx,%r13d
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %r13d,%r13
  movb   $0x0,0x0(%rbp,%r13,1)
L16:
  add    $0x1,%rbx
  mov    %rbx,(%r12)
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L6:
  test   %rbp,%rbp
  je     L29
  movb   $0x0,0x0(%rbp)
  jmp    L29
```

assistant: ```c
void get_entry(char *buf, int buf_size, const char **pp) {
  const char *p, *r;
  int len;
  r = *pp;
  p = strchr(r, '-');
  if (!p) {
    if (buf)
      buf[0] = '\0';
  } else {
    if (buf) {
      len = p - r;
      if (len >= buf_size)
        len = buf_size - 1;
      memcpy(buf, r, len);
      buf[len] = '\0';
    }
    *pp = p + 1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_entry>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  mov    $0x2d,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdx),%r14
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L11
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L24
  sub    %r14,%rax
  lea    -0x1(%r13),%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  cmp    %eax,%r13d
  cmovg  %eax,%edx
  movslq %edx,%r13
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r13,1)
L24:
  add    $0x1,%rbx
  mov    %rbx,(%r12)
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L11:
  test   %rbp,%rbp
  je     L16
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void get_entry(char *buf, int buf_size, const char **pp) {
  const char *p, *r;
  int len;
  r = *pp;
  p = strchr(r, '-');
  if (!p) {
    if (buf)
      buf[0] = '\0';
  } else {
    if (buf) {
      len = p - r;
      if (len >= buf_size)
        len = buf_size - 1;
      memcpy(buf, r, len);
      buf[len] = '\0';
    }
    *pp = p + 1;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_entry>:
  endbr64
  push   %r14
  push   %r13
  mov    %esi,%r13d
  mov    $0x2d,%esi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    (%rdx),%r14
  mov    %r14,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L9
  mov    %rax,%rbx
  test   %rbp,%rbp
  je     L3
  sub    %r14,%rax
  lea    -0x1(%r13),%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  cmp    %eax,%r13d
  cmovg  %eax,%edx
  movslq %edx,%r13
  call   <memcpy@plt>
  movb   $0x0,0x0(%rbp,%r13,1)
L3:
  add    $0x1,%rbx
  mov    %rbx,(%r12)
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L9:
  test   %rbp,%rbp
  je     L1
  pop    %rbx
  movb   $0x0,0x0(%rbp)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void get_entry(char *buf, int buf_size, const char **pp) {
  const char *p, *r;
  int len;
  r = *pp;
  p = strchr(r, '-');
  if (!p) {
    if (buf)
      buf[0] = '\0';
  } else {
    if (buf) {
      len = p - r;
      if (len >= buf_size)
        len = buf_size - 1;
      memcpy(buf, r, len);
      buf[len] = '\0';
    }
    *pp = p + 1;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L18:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L18
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x9c58(%rbp)
  jmp    L50
L36:
  movl   $0x0,-0x9c54(%rbp)
  jmp    L23
L27:
  mov    -0x9c58(%rbp),%eax
  imul   -0x9c54(%rbp),%eax
  mov    %eax,%edx
  mov    -0x9c54(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x9c58(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rcx,%rax
  lea    0x0(,%rax,4),%rcx
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    %edx,-0x9c50(%rbp,%rax,4)
  addl   $0x1,-0x9c54(%rbp)
L23:
  cmpl   $0x63,-0x9c54(%rbp)
  jle    L27
  addl   $0x1,-0x9c58(%rbp)
L50:
  cmpl   $0x63,-0x9c58(%rbp)
  jle    L36
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
void f(void) {
  int a[100][100];
#pragma hlt block
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      a[i][j] = i * j;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  mov    $0x64,%edx
L1:
  mov    $0x64,%eax
L7:
  sub    $0x1,%eax
  jne    L7
  sub    $0x1,%edx
  jne    L1
  ret
```

assistant: ```c
void f(void) {
  int a[100][100];
#pragma hlt block
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      a[i][j] = i * j;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int a[100][100];
#pragma hlt block
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      a[i][j] = i * j;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f>:
  endbr64
  ret
```

assistant: ```c
void f(void) {
  int a[100][100];
#pragma hlt block
  for (int i = 0; i < 100; i++) {
    for (int j = 0; j < 100; j++) {
      a[i][j] = i * j;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L27
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L7
L27:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L7:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string
name: disassemble_data
arguments: tag: D26
type_guessed: string
name: disassemble_data
arguments: tag: D12
type_guessed: string

tool: D6: %d

tool: D26: Leap Year

tool: D12: Not Leap Year

assistant: ```c
int main() {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0) {
    printf("Leap Year");
  } else {
    printf("Not Leap Year");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  testb  $0x3,0x4(%rsp)
  jne    L26
  lea    D2(%rip),%rdi
  call   <printf@plt>
L18:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L26:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  jmp    L18
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
datatype: string
name: extract_symbolic_data
arguments: label: D2
datatype: string
name: extract_symbolic_data
arguments: label: D3
datatype: string

tool: D8: %d

tool: D2: Leap Year

tool: D3: Not Leap Year

assistant: ```c
int main() {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0) {
    printf("Leap Year");
  } else {
    printf("Not Leap Year");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  testb  $0x3,0x4(%rsp)
  jne    L19
  lea    D16(%rip),%rdi
  call   <printf@plt>
L24:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L19:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L24
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D14
type: string
name: extract_symbolic_data
arguments: data_label: D16
type: string
name: extract_symbolic_data
arguments: data_label: D20
type: string

tool: D14: %d

tool: D16: Leap Year

tool: D20: Not Leap Year

assistant: ```c
int main() {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0) {
    printf("Leap Year");
  } else {
    printf("Not Leap Year");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  testb  $0x3,0x4(%rsp)
  jne    L23
  lea    D17(%rip),%rdi
  call   <printf@plt>
L7:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D29(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string
name: retrieve_data
arguments: tag: D29
datatype: string

tool: D5: %d

tool: D17: Leap Year

tool: D29: Not Leap Year

assistant: ```c
int main() {
  int year;
  scanf("%d", &year);
  if (year % 4 == 0) {
    printf("Leap Year");
  } else {
    printf("Not Leap Year");
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<command_check4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char command_check4(int number) {
  int response;
  response = 0x30 + number;
  return response;
}
```
user: Translate the below assembly code into C programming language:

```asm
<command_check4>:
  endbr64
  lea    0x30(%rdi),%eax
  ret
```

assistant: ```c
unsigned char command_check4(int number) {
  int response;
  response = 0x30 + number;
  return response;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<command_check4>:
  endbr64
  lea    0x30(%rdi),%eax
  ret
```

assistant: ```c
unsigned char command_check4(int number) {
  int response;
  response = 0x30 + number;
  return response;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<command_check4>:
  endbr64
  lea    0x30(%rdi),%eax
  ret
```

assistant: ```c
unsigned char command_check4(int number) {
  int response;
  response = 0x30 + number;
  return response;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rte_calc_order>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  sar    $0xb,%eax
  mov    %eax,-0x14(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
L2:
  sarl   -0x14(%rbp)
  addl   $0x1,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L2
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int rte_calc_order(int size) {
  int order;
  size = (size - 1) >> (12U - 1);
  order = -1;
  do {
    size >>= 1;
    order++;
  } while (size);
  return order;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rte_calc_order>:
  endbr64
  sub    $0x1,%edi
  sar    $0xb,%edi
  mov    $0xffffffff,%eax
L8:
  add    $0x1,%eax
  sar    %edi
  jne    L8
  ret
```

assistant: ```c
int rte_calc_order(int size) {
  int order;
  size = (size - 1) >> (12U - 1);
  order = -1;
  do {
    size >>= 1;
    order++;
  } while (size);
  return order;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rte_calc_order>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  sar    $0xb,%edi
  nop
L8:
  add    $0x1,%eax
  sar    %edi
  jne    L8
  ret
```

assistant: ```c
int rte_calc_order(int size) {
  int order;
  size = (size - 1) >> (12U - 1);
  order = -1;
  do {
    size >>= 1;
    order++;
  } while (size);
  return order;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rte_calc_order>:
  endbr64
  sub    $0x1,%edi
  mov    $0xffffffff,%eax
  sar    $0xb,%edi
  nop
L9:
  add    $0x1,%eax
  sar    %edi
  jne    L9
  ret
```

assistant: ```c
int rte_calc_order(int size) {
  int order;
  size = (size - 1) >> (12U - 1);
  order = -1;
  do {
    size >>= 1;
    order++;
  } while (size);
  return order;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<parse_trace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x2b0,%rsp
  mov    %rdi,-0x2a8(%rbp)
  mov    %rsi,-0x2b0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x290(%rbp)
  jmp    L62
L70:
  mov    -0x290(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x2b0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x140(%rbp),%rdi
  lea    -0x294(%rbp),%rsi
  lea    -0x270(%rbp),%rcx
  lea    -0x298(%rbp),%rdx
  mov    %rdi,%r9
  mov    %rsi,%r8
  lea    D1(%rip),%rsi
  mov    %rax,%rdi
  call   <sscanf@plt>
  mov    -0x290(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x2b0(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x278(%rbp)
  movq   $0x0,-0x280(%rbp)
  movq   $0x0,-0x288(%rbp)
  jmp    L74
L34:
  lea    -0x140(%rbp),%rdx
  mov    -0x288(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L73
  addq   $0x1,-0x280(%rbp)
  addq   $0x1,-0x288(%rbp)
L74:
  mov    -0x288(%rbp),%rax
  cmp    -0x278(%rbp),%rax
  jb     L34
  jmp    L54
L73:
  nop
L54:
  cmpq   $0x0,-0x280(%rbp)
  je     L3
  movq   $0x0,-0x288(%rbp)
  jmp    L90
L44:
  mov    -0x288(%rbp),%rdx
  mov    -0x280(%rbp),%rax
  add    %rdx,%rax
  movzbl -0x140(%rbp,%rax,1),%eax
  lea    -0x140(%rbp),%rcx
  mov    -0x288(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  addq   $0x1,-0x288(%rbp)
L90:
  mov    -0x278(%rbp),%rax
  sub    -0x280(%rbp),%rax
  cmp    %rax,-0x288(%rbp)
  jb     L44
L3:
  mov    -0x294(%rbp),%edi
  mov    -0x298(%rbp),%edx
  mov    -0x278(%rbp),%rax
  lea    -0x1(%rax),%rsi
  mov    -0x290(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x2b0(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  lea    -0x140(%rbp),%rcx
  mov    %edi,%r9d
  mov    %rcx,%r8
  mov    %edx,%ecx
  lea    D19(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  addq   $0x1,-0x290(%rbp)
L62:
  mov    -0x290(%rbp),%rax
  cmp    -0x2a8(%rbp),%rax
  jb     L70
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L76
  call   <__stack_chk_fail@plt>
L76:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string

tool: D1: %d %s %x %s

tool: D19: %d <%s> [%x]


assistant: ```c
void parse_trace(size_t size, char **strings_in) {
  size_t i, len, k, junk;
  int a;
  unsigned int b;
  char string[(300)];
  char strings_out[(300)];
  for (i = 0; i < size; i++) {
    sscanf(strings_in[i], "%d %s %x %s", &a, string, &b, strings_out);
    len = strlen(strings_in[i]);
    junk = 0;
    for (k = 0; k < len; k++)
      if (strings_out[k] == '_')
        junk++;
      else
        break;
    if (junk != 0)
      for (k = 0; k < (len - junk); k++)
        strings_out[k] = strings_out[k + junk];
    snprintf(strings_in[i], (len - 1), "%d <%s> [%x]\n", a, strings_out, b);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<parse_trace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x288,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x278(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L52
  mov    %rdi,%r14
  mov    %rsi,%r13
  mov    $0x0,%ebp
  lea    0x140(%rsp),%rbx
  lea    0xc(%rsp),%r15
  jmp    L37
L89:
  test   %rdx,%rdx
  jne    L84
L17:
  lea    -0x1(%rax),%rsi
  mov    0xc(%rsp),%r9d
  mov    %rbx,%r8
  mov    0x8(%rsp),%ecx
  lea    D12(%rip),%rdx
  mov    %r12,%rdi
  call   <snprintf@plt>
  add    $0x1,%rbp
  cmp    %rbp,%r14
  je     L52
L37:
  lea    0x10(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  mov    0x0(%r13,%rbp,8),%rdi
  mov    %rbx,%r9
  mov    %r15,%r8
  lea    D19(%rip),%rsi
  call   <sscanf@plt>
  mov    0x0(%r13,%rbp,8),%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %rax,%rax
  je     L17
  mov    $0x0,%edx
L118:
  cmpb   $0x5f,(%rdx,%rbx,1)
  jne    L89
  add    $0x1,%rdx
  cmp    %rdx,%rax
  jne    L118
  jmp    L17
L84:
  mov    %rax,%rdi
  sub    %rdx,%rdi
  je     L17
  lea    0x140(%rsp),%rcx
  add    %rcx,%rdi
L74:
  movzbl (%rcx,%rdx,1),%esi
  mov    %sil,(%rcx)
  add    $0x1,%rcx
  cmp    %rdi,%rcx
  jne    L74
  jmp    L17
L52:
  mov    0x278(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x288,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D19
type_infered: string

tool: D12: %d <%s> [%x]


tool: D19: %d %s %x %s

assistant: ```c
void parse_trace(size_t size, char **strings_in) {
  size_t i, len, k, junk;
  int a;
  unsigned int b;
  char string[(300)];
  char strings_out[(300)];
  for (i = 0; i < size; i++) {
    sscanf(strings_in[i], "%d %s %x %s", &a, string, &b, strings_out);
    len = strlen(strings_in[i]);
    junk = 0;
    for (k = 0; k < len; k++)
      if (strings_out[k] == '_')
        junk++;
      else
        break;
    if (junk != 0)
      for (k = 0; k < (len - junk); k++)
        strings_out[k] = strings_out[k + junk];
    snprintf(strings_in[i], (len - 1), "%d <%s> [%x]\n", a, strings_out, b);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<parse_trace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x298,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x288(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L39
  mov    %rsi,%rbp
  lea    0x1c(%rsp),%r15
  lea    0x20(%rsp),%r14
  xor    %ebx,%ebx
  lea    0x150(%rsp),%r12
  lea    0x18(%rsp),%r13
  nopw   0x0(%rax,%rax,1)
L59:
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %r12,%r9
  mov    %r15,%r8
  mov    %r14,%rcx
  mov    %r13,%rdx
  lea    D2(%rip),%rsi
  call   <sscanf@plt>
  mov    0x0(%rbp,%rbx,8),%rdi
  mov    %rdi,(%rsp)
  call   <strlen@plt>
  mov    (%rsp),%rdi
  test   %rax,%rax
  je     L28
  xor    %edx,%edx
  jmp    L54
L89:
  add    $0x1,%rdx
  cmp    %rdx,%rax
  je     L28
L54:
  cmpb   $0x5f,(%r12,%rdx,1)
  je     L89
  test   %rdx,%rdx
  jne    L16
L28:
  mov    0x1c(%rsp),%r9d
  mov    0x18(%rsp),%ecx
  lea    -0x1(%rax),%rsi
  mov    %r12,%r8
  lea    D8(%rip),%rdx
  add    $0x1,%rbx
  call   <snprintf@plt>
  cmp    %rbx,0x8(%rsp)
  jne    L59
L39:
  mov    0x288(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  add    $0x298,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L16:
  mov    %rax,%r8
  sub    %rdx,%r8
  je     L28
  mov    %r12,%rcx
  add    %r12,%r8
  nop
L58:
  movzbl (%rcx,%rdx,1),%esi
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %r8,%rcx
  jne    L58
  jmp    L28
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D2: %d %s %x %s

tool: D8: %d <%s> [%x]


assistant: ```c
void parse_trace(size_t size, char **strings_in) {
  size_t i, len, k, junk;
  int a;
  unsigned int b;
  char string[(300)];
  char strings_out[(300)];
  for (i = 0; i < size; i++) {
    sscanf(strings_in[i], "%d %s %x %s", &a, string, &b, strings_out);
    len = strlen(strings_in[i]);
    junk = 0;
    for (k = 0; k < len; k++)
      if (strings_out[k] == '_')
        junk++;
      else
        break;
    if (junk != 0)
      for (k = 0; k < (len - junk); k++)
        strings_out[k] = strings_out[k + junk];
    snprintf(strings_in[i], (len - 1), "%d <%s> [%x]\n", a, strings_out, b);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<extended_pci_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x24(%rbp)
  mov    -0x20(%rbp),%eax
  shl    $0x10,%eax
  and    $0xf000000,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,%edx
  mov    -0x18(%rbp),%eax
  shl    $0xb,%eax
  movzwl %ax,%eax
  or     %eax,%edx
  mov    -0x1c(%rbp),%eax
  shl    $0x8,%eax
  and    $0x700,%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%eax
  and    $0xfc,%eax
  or     %edx,%eax
  or     $0x80000000,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    $0xcf8,%esi
  mov    %eax,%edi
  call   <outl_p@plt>
  mov    -0x24(%rbp),%eax
  mov    $0xcfc,%esi
  mov    %eax,%edi
  call   <outl_p@plt>
  nop
  leave
  ret
```

assistant: ```c
void extended_pci_write(int bus, int device, int func, int offset, unsigned int value) {
  unsigned int tmp;
  tmp = 0x80000000 | ((offset & 0xf00) << 16) | ((bus & 0xff) << 16) | ((device & 0x1f) << 11) | ((func & 0x7) << 0x8) | (offset & 0xfc);
  outl_p(tmp, 0xcf8);
  outl_p(value, 0xcfc);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extended_pci_write>:
  endbr64
  push   %rbx
  mov    %r8d,%ebx
  mov    %ecx,%eax
  shl    $0x10,%eax
  and    $0xf000000,%eax
  shl    $0x8,%edx
  and    $0x700,%edx
  or     %edx,%eax
  shl    $0xb,%esi
  movzwl %si,%esi
  or     %esi,%eax
  shl    $0x10,%edi
  and    $0xff0000,%edi
  or     %edi,%eax
  and    $0xfc,%ecx
  or     %ecx,%eax
  mov    %eax,%edi
  or     $0x80000000,%edi
  mov    $0xcf8,%esi
  call   <outl_p@plt>
  mov    $0xcfc,%esi
  mov    %ebx,%edi
  call   <outl_p@plt>
  pop    %rbx
  ret
```

assistant: ```c
void extended_pci_write(int bus, int device, int func, int offset, unsigned int value) {
  unsigned int tmp;
  tmp = 0x80000000 | ((offset & 0xf00) << 16) | ((bus & 0xff) << 16) | ((device & 0x1f) << 11) | ((func & 0x7) << 0x8) | (offset & 0xfc);
  outl_p(tmp, 0xcf8);
  outl_p(value, 0xcfc);
}
```