ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<vp8_variance8x16_c>:
  endbr64
  push   %rbx
  mov    $0x10,%r9d
  mov    %r8,%rbx
  mov    $0x8,%r8d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rax
  push   %rax
  lea    0x8(%rsp),%rax
  push   %rax
  call   <vp8_variance@plt>
  mov    0x14(%rsp),%edx
  mov    0x10(%rsp),%eax
  imul   %edx,%edx
  mov    %eax,(%rbx)
  sar    $0x7,%edx
  sub    %edx,%eax
  pop    %rdx
  pop    %rcx
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
unsigned int vp8_variance8x16_c(unsigned char *src_ptr, int source_stride, unsigned char *ref_ptr, int recon_stride, unsigned int *sse) {
  unsigned int var;
  int avg;
  vp8_variance(src_ptr, source_stride, ref_ptr, recon_stride, 8, 16, &var, &avg);
  *sse = var;
  return (var - ((avg * avg) >> 7));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L49
  mov    $0x1,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L49:
  movl   $0x0,-0x14(%rbp)
  jmp    L11
L42:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %ax,-0x16(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzwl -0x16(%rbp),%edx
  mov    %dx,-0xc(%rbp,%rax,2)
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0x0,-0x14(%rbp)
  jle    L42
  lea    -0xa(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzwl -0xa(%rbp),%eax
  cmp    $0xbfcf,%ax
  jne    L53
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L53:
  movl   $0x0,-0x10(%rbp)
  jmp    L0
L19:
  mov    -0x10(%rbp),%eax
  cltq
  movzwl -0xa(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L0:
  cmpl   $0x0,-0x10(%rbp)
  jle    L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D10
type: string

tool: D18: Call this program with %i arguments


tool: D19: You win!

tool: D10: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 49103) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L30
L21:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %ax,0x4(%rsp)
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  call   <RandomFunc@plt>
  cmpw   $0xbfcf,0x6(%rsp)
  je     L26
L45:
  movzwl 0x6(%rsp),%esi
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  mov    $0x1,%esi
  lea    D22(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L21
L26:
  lea    D25(%rip),%rdi
  call   <puts@plt>
  jmp    L45
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
type_guessed: string
name: disassemble_data
arguments: data_label: D22
type_guessed: string
name: disassemble_data
arguments: data_label: D25
type_guessed: string

tool: D13: %u


tool: D22: Call this program with %i arguments


tool: D25: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 49103) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L1
  lea    D19(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L1:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xbfcf,%si
  je     L22
L26:
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  lea    D24(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L26
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D19
type_guessed: string
name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D24
type_guessed: string

tool: D19: Call this program with %i arguments


tool: D4: %u


tool: D24: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 49103) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L19
  lea    D8(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L19:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xbfcf,%si
  je     L24
L21:
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L21
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string
name: read_data
arguments: data_label: D22
type_infered: string
name: read_data
arguments: data_label: D21
type_infered: string

tool: D8: Call this program with %i arguments


tool: D22: %u


tool: D21: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 49103) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L33
L56:
  addq   $0x1,-0x10(%rbp)
L33:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L56
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L68
L59:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addq   $0x1,-0x10(%rbp)
  addq   $0x1,-0x8(%rbp)
L68:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L59
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  jmp    L19
L58:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L19:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jbe    L29
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L58
L29:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *trim(char *s) {
  char *cp1, *cp2;
  for (cp1 = s; isspace(*cp1); cp1++)
    ;
  for (cp2 = s; *cp1; cp1++, cp2++)
    *cp2 = *cp1;
  *cp2-- = 0;
  while (cp2 > s && isspace(*cp2))
    *cp2-- = 0;
  return s;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<trim>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  jmp    L6
L59:
  add    $0x1,%rbx
L6:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L59
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L77
  mov    %rbp,%rax
L64:
  mov    %dl,(%rax)
  add    $0x1,%rbx
  add    $0x1,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L64
L13:
  lea    -0x1(%rax),%rbx
  movb   $0x0,(%rax)
  cmp    %rbx,%rbp
  jae    L71
L11:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L71
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
  cmp    %rbx,%rbp
  jne    L11
L71:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L77:
  mov    %rbp,%rax
  jmp    L13
```

assistant: ```c
char *trim(char *s) {
  char *cp1, *cp2;
  for (cp1 = s; isspace(*cp1); cp1++)
    ;
  for (cp2 = s; *cp1; cp1++, cp2++)
    *cp2 = *cp1;
  *cp2-- = 0;
  while (cp2 > s && isspace(*cp2))
    *cp2-- = 0;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L81
L82:
  add    $0x1,%rbx
L81:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L82
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L40
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L71:
  add    $0x1,%rbx
  mov    %dl,(%rax)
  mov    %rax,%rbp
  add    $0x1,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L71
L37:
  movb   $0x0,(%rax)
  cmp    %r12,%rbp
  ja     L44
  jmp    L14
  xchg   %ax,%ax
L17:
  sub    $0x1,%rbp
  movb   $0x0,0x1(%rbp)
  cmp    %rbp,%r12
  je     L14
L44:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L17
L14:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  lea    -0x1(%r12),%rbp
  mov    %r12,%rax
  jmp    L37
```

assistant: ```c
char *trim(char *s) {
  char *cp1, *cp2;
  for (cp1 = s; isspace(*cp1); cp1++)
    ;
  for (cp2 = s; *cp1; cp1++, cp2++)
    *cp2 = *cp1;
  *cp2-- = 0;
  while (cp2 > s && isspace(*cp2))
    *cp2-- = 0;
  return s;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trim>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L69
L57:
  add    $0x1,%rbx
L69:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L57
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L33
  mov    %r12,%rax
  nopl   0x0(%rax,%rax,1)
L77:
  add    $0x1,%rbx
  mov    %dl,(%rax)
  mov    %rax,%rbp
  add    $0x1,%rax
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L77
L72:
  movb   $0x0,(%rax)
  cmp    %r12,%rbp
  ja     L86
  jmp    L31
  xchg   %ax,%ax
L20:
  sub    $0x1,%rbp
  movb   $0x0,0x1(%rbp)
  cmp    %rbp,%r12
  je     L31
L86:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L20
L31:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L33:
  lea    -0x1(%r12),%rbp
  mov    %r12,%rax
  jmp    L72
```

assistant: ```c
char *trim(char *s) {
  char *cp1, *cp2;
  for (cp1 = s; isspace(*cp1); cp1++)
    ;
  for (cp2 = s; *cp1; cp1++, cp2++)
    *cp2 = *cp1;
  *cp2-- = 0;
  while (cp2 > s && isspace(*cp2))
    *cp2-- = 0;
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<build>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L11
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <build>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rsi
  mov    -0x20(%rbp),%rax
  add    %rax,%rsi
  mov    -0x14(%rbp),%eax
  sub    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <build>
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  jmp    L12
L11:
  nop
L12:
  leave
  ret
```

assistant: ```c
void build(int n, char *s1, char *s2, char *s3) {
  if (n <= 0) {
    return;
  }
  int p = strchr(s2, s1[0]) - s2;
  build(p, s1 + 1, s2, s3);
  build(n - p - 1, s1 + 1 + p, s2 + p + 1, s3 + p);
  s3[n - 1] = s1[0];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<build>:
  endbr64
  test   %edi,%edi
  jle    L5
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %rcx,%r13
  movsbl (%rsi),%esi
  mov    %rdx,%rdi
  call   <strchr@plt>
  sub    %rbx,%rax
  mov    %rax,%r14
  mov    %eax,%edi
  lea    0x1(%r12),%rsi
  mov    %r13,%rcx
  mov    %rbx,%rdx
  call   <build>
  movslq %r14d,%rcx
  lea    0x1(%rcx),%rsi
  add    %r13,%rcx
  lea    (%rbx,%rsi,1),%rdx
  add    %r12,%rsi
  mov    %ebp,%edi
  sub    %r14d,%edi
  sub    $0x1,%edi
  call   <build>
  movzbl (%r12),%eax
  movslq %ebp,%rbp
  mov    %al,-0x1(%r13,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L5:
  ret
```

assistant: ```c
void build(int n, char *s1, char *s2, char *s3) {
  if (n <= 0) {
    return;
  }
  int p = strchr(s2, s1[0]) - s2;
  build(p, s1 + 1, s2, s3);
  build(n - p - 1, s1 + 1 + p, s2 + p + 1, s3 + p);
  s3[n - 1] = s1[0];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<build>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L4
  mov    %rsi,%r12
  movsbl (%rsi),%esi
  mov    %rdx,%rdi
  mov    %rdx,%rbx
  mov    %rcx,%r13
  call   <strchr@plt>
  lea    0x1(%r12),%rsi
  mov    %r13,%rcx
  mov    %rbx,%rdx
  sub    %rbx,%rax
  mov    %rax,%r14
  mov    %eax,%edi
  call   <build>
  movslq %r14d,%rcx
  mov    %ebp,%edi
  lea    0x1(%rcx),%rsi
  sub    %r14d,%edi
  add    %r13,%rcx
  lea    (%rbx,%rsi,1),%rdx
  sub    $0x1,%edi
  add    %r12,%rsi
  call   <build>
  movzbl (%r12),%eax
  mov    %al,-0x1(%r13,%rbp,1)
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void build(int n, char *s1, char *s2, char *s3) {
  if (n <= 0) {
    return;
  }
  int p = strchr(s2, s1[0]) - s2;
  build(p, s1 + 1, s2, s3);
  build(n - p - 1, s1 + 1 + p, s2 + p + 1, s3 + p);
  s3[n - 1] = s1[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<baseFilename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strRSeparator@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L17
L4:
  addq   $0x1,-0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
extern const char *baseFilename(const char *const filePath) {
  const char *tail = strRSeparator(filePath);
  if (tail == NULL)
    tail = filePath;
  else
    ++tail;
  return tail;
}
```
user: What is the c source code of the assembly code below:

```asm
<baseFilename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strRSeparator@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
extern const char *baseFilename(const char *const filePath) {
  const char *tail = strRSeparator(filePath);
  if (tail == NULL)
    tail = filePath;
  else
    ++tail;
  return tail;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<baseFilename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strRSeparator@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
extern const char *baseFilename(const char *const filePath) {
  const char *tail = strRSeparator(filePath);
  if (tail == NULL)
    tail = filePath;
  else
    ++tail;
  return tail;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<baseFilename>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strRSeparator@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
extern const char *baseFilename(const char *const filePath) {
  const char *tail = strRSeparator(filePath);
  if (tail == NULL)
    tail = filePath;
  else
    ++tail;
  return tail;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<functions>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L6
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <functions>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  cltq
  leave
  ret
```

assistant: ```c
long int functions(int a) {
  if (a > 1) {
    a *= functions(a - 1);
  }
  return a;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<functions>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L8
L6:
  movslq %ebx,%rax
  pop    %rbx
  ret
L8:
  lea    -0x1(%rdi),%edi
  call   <functions>
  imul   %eax,%ebx
  jmp    L6
```

assistant: ```c
long int functions(int a) {
  if (a > 1) {
    a *= functions(a - 1);
  }
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<functions>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L14
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  lea    -0x1(%rdi),%ebp
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L24
L15:
  imul   %eax,%ebx
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L24:
  lea    -0x2(%rdi),%r12d
  cmp    $0x3,%edi
  je     L37
  lea    -0x3(%rdi),%edi
  call   <functions>
  imul   %r12d,%eax
L37:
  imul   %ebp,%eax
  jmp    L15
```

assistant: ```c
long int functions(int a) {
  if (a > 1) {
    a *= functions(a - 1);
  }
  return a;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<functions>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  cmp    $0x1,%edi
  jg     L35
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  lea    -0x1(%rdi),%ebp
  mov    $0x1,%eax
  cmp    $0x2,%edi
  jne    L37
L15:
  imul   %eax,%ebx
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L37:
  lea    -0x2(%rdi),%r12d
  cmp    $0x3,%edi
  je     L10
  lea    -0x3(%rdi),%edi
  call   <functions>
  imul   %r12d,%eax
L10:
  imul   %ebp,%eax
  jmp    L15
```

assistant: ```c
long int functions(int a) {
  if (a > 1) {
    a *= functions(a - 1);
  }
  return a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L17
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L35:
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  sub    -0x10(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L35
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L17:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L25
  call   <__stack_chk_fail@plt>
L25:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
datatype: string
name: extract_symbolic_data
arguments: tag: D0
datatype: string
name: extract_symbolic_data
arguments: tag: D30
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string

tool: D37: enter the size of pattern: 

tool: D0: %d

tool: D30: * 

tool: D15: 


assistant: ```c
int main() {
  int i, j, num;
  printf("enter the size of pattern: ");
  scanf("%d", &num);
  for (i = 0; i < num; i++) {
    for (j = 0; j < num - i; j++) {
      printf("* ");
    }
    printf("\n");
  }
  return 0;
}
```