ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  lea    0xc(%rsp),%rbp
  lea    0x8(%rsp),%rbx
  lea    0x14(%rsp),%r8
  mov    %r12,%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  lea    D3(%rip),%rdi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  mov    0x8(%rsp),%esi
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D3: %d  %d  %d  %d

tool: D11: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n;
  scanf("%d  %d  %d  %d", &a, &b, &c, &n);
  rotr(&a, &b, &c, n);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    0x14(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D4(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D18
data_type: string
name: parse_data
arguments: tag: D4
data_type: string

tool: D18: %d  %d  %d  %d

tool: D4: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n;
  scanf("%d  %d  %d  %d", &a, &b, &c, &n);
  rotr(&a, &b, &c, n);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D3(%rip),%rdi
  push   %r12
  push   %rbp
  sub    $0x20,%rsp
  lea    0x10(%rsp),%r13
  lea    0xc(%rsp),%r12
  lea    0x8(%rsp),%rbp
  lea    0x14(%rsp),%r8
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%ecx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <rotr@plt>
  mov    0x10(%rsp),%ecx
  mov    0xc(%rsp),%edx
  lea    D0(%rip),%rdi
  mov    0x8(%rsp),%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
datatype: string
name: disassemble_data
arguments: label: D0
datatype: string

tool: D3: %d  %d  %d  %d

tool: D0: %d %d %d

assistant: ```c
int main() {
  int a, b, c, n;
  scanf("%d  %d  %d  %d", &a, &b, &c, &n);
  rotr(&a, &b, &c, n);
  printf("%d %d %d", a, b, c);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<arrToInt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L3
L36:
  movl   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L39:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L39
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  sub    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  imul   -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x10(%rbp)
L3:
  mov    -0x10(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L36
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int arrToInt(int *arr, int len) {
  int i, j, tens;
  int result = 0;
  for (i = 0; i < len; i++) {
    tens = 1;
    for (j = 0; j < i; j++) {
      tens *= 10;
    }
    result += arr[len - 1 - i] * tens;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<arrToInt>:
  endbr64
  test   %esi,%esi
  jle    L43
  movslq %esi,%rax
  lea    (%rdi,%rax,4),%r9
  mov    $0x0,%r10d
  mov    $0x0,%edi
  mov    $0x1,%eax
  mov    $0x1,%r11d
  jmp    L54
L18:
  mov    %r11d,%eax
  mov    $0x0,%edx
L57:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  cmp    %ecx,%edi
  jne    L57
L0:
  sub    $0x4,%r9
  mov    %r8d,%edi
L54:
  imul   -0x4(%r9),%eax
  add    %eax,%r10d
  lea    0x1(%rdi),%r8d
  cmp    %r8d,%esi
  je     L19
  test   %r8d,%r8d
  jg     L18
  mov    %r11d,%eax
  jmp    L0
L43:
  mov    $0x0,%r10d
L19:
  mov    %r10d,%eax
  ret
```

assistant: ```c
int arrToInt(int *arr, int len) {
  int i, j, tens;
  int result = 0;
  for (i = 0; i < len; i++) {
    tens = 1;
    for (j = 0; j < i; j++) {
      tens *= 10;
    }
    result += arr[len - 1 - i] * tens;
  }
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<arrToInt>:
  endbr64
  test   %esi,%esi
  jle    L10
  lea    -0x1(%rsi),%eax
  xor    %r10d,%r10d
  cltq
  lea    (%rdi,%rax,4),%r9
  mov    $0x1,%eax
  xor    %edi,%edi
  imul   (%r9),%eax
  lea    0x1(%rdi),%r8d
  add    %eax,%r10d
  cmp    %r8d,%esi
  je     L21
  nopl   0x0(%rax,%rax,1)
L39:
  mov    $0x1,%eax
  xor    %edx,%edx
  nopw   0x0(%rax,%rax,1)
L38:
  lea    (%rax,%rax,4),%eax
  mov    %edx,%ecx
  add    $0x1,%edx
  add    %eax,%eax
  cmp    %ecx,%edi
  jne    L38
  imul   -0x4(%r9),%eax
  mov    %r8d,%edi
  sub    $0x4,%r9
  lea    0x1(%rdi),%r8d
  add    %eax,%r10d
  cmp    %r8d,%esi
  jne    L39
L21:
  mov    %r10d,%eax
  ret
L10:
  xor    %r10d,%r10d
  mov    %r10d,%eax
  ret
```

assistant: ```c
int arrToInt(int *arr, int len) {
  int i, j, tens;
  int result = 0;
  for (i = 0; i < len; i++) {
    tens = 1;
    for (j = 0; j < i; j++) {
      tens *= 10;
    }
    result += arr[len - 1 - i] * tens;
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<arrToInt>:
  endbr64
  mov    %esi,%r9d
  test   %esi,%esi
  jle    L42
  lea    -0x1(%rsi),%eax
  cltq
  mov    (%rdi,%rax,4),%r8d
  cmp    $0x1,%esi
  je     L31
  lea    -0x4(%rdi,%rax,4),%rsi
  mov    D6(%rip),%rdi
  mov    $0x1,%ecx
  xchg   %ax,%ax
L13:
  cmp    $0x1,%ecx
  je     L8
  mov    %ecx,%edx
  xor    %eax,%eax
  movq   %rdi,%xmm0
  shr    %edx
L17:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L17
  movd   %xmm0,%eax
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%edx
  imul   %edx,%eax
  test   $0x1,%cl
  je     L53
L49:
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
L53:
  imul   (%rsi),%eax
  add    $0x1,%ecx
  sub    $0x4,%rsi
  add    %eax,%r8d
  cmp    %ecx,%r9d
  jne    L13
L31:
  mov    %r8d,%eax
  ret
L8:
  mov    $0x1,%eax
  jmp    L49
L42:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: byte[8]

tool: {"D6": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int arrToInt(int *arr, int len) {
  int i, j, tens;
  int result = 0;
  for (i = 0; i < len; i++) {
    tens = 1;
    for (j = 0; j < i; j++) {
      tens *= 10;
    }
    result += arr[len - 1 - i] * tens;
  }
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  int a;
  a = a++;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
main() {
  int a;
  a = a++;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
main() {
  int a;
  a = a++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<towlower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x8(%rbp)
  jne    L36
  mov    D6(%rip),%rax
  mov    (%rax),%rax
  jmp    L35
L36:
  cmpq   $0xff,-0x8(%rbp)
  jg     L9
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <tolower@plt>
  jmp    L35
L9:
  mov    -0x8(%rbp),%rax
L35:
  leave
  ret
```

assistant: ```c
wint_t towlower(wint_t wc) {
  if (wc == WEOF)
    return WEOF;
  return (wc < (wint_t)0x100 ? tolower(wc) : wc);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<towlower>:
  endbr64
  mov    %rdi,%rax
  mov    D0(%rip),%rdx
  cmp    %rdi,(%rdx)
  je     L13
  cmp    $0xff,%rdi
  jle    L12
L13:
  ret
L12:
  sub    $0x8,%rsp
  call   <tolower@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
wint_t towlower(wint_t wc) {
  if (wc == WEOF)
    return WEOF;
  return (wc < (wint_t)0x100 ? tolower(wc) : wc);
}
```
user: What is the c source code of the assembly code below:

```asm
<towlower>:
  endbr64
  mov    D4(%rip),%rdx
  mov    %rdi,%rax
  cmp    %rdi,(%rdx)
  je     L4
  cmp    $0xff,%rdi
  jle    L6
L4:
  ret
  nopl   (%rax)
L6:
  jmp    1050 <tolower@plt>
```

assistant: ```c
wint_t towlower(wint_t wc) {
  if (wc == WEOF)
    return WEOF;
  return (wc < (wint_t)0x100 ? tolower(wc) : wc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<towlower>:
  endbr64
  mov    D4(%rip),%rdx
  mov    %rdi,%rax
  cmp    %rdi,(%rdx)
  je     L15
  cmp    $0xff,%rdi
  jle    L1
L15:
  ret
  nopl   (%rax)
L1:
  jmp    1050 <tolower@plt>
```

assistant: ```c
wint_t towlower(wint_t wc) {
  if (wc == WEOF)
    return WEOF;
  return (wc < (wint_t)0x100 ? tolower(wc) : wc);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ut_teardown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <context_clear@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
struct context *ut_teardown(struct context *cxt) {
  context_clear(cxt);
  return cxt;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ut_teardown>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <context_clear@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
struct context *ut_teardown(struct context *cxt) {
  context_clear(cxt);
  return cxt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ut_teardown>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <context_clear@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct context *ut_teardown(struct context *cxt) {
  context_clear(cxt);
  return cxt;
}
```
user: What is the c source code of the assembly code below?

```asm
<ut_teardown>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <context_clear@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
struct context *ut_teardown(struct context *cxt) {
  context_clear(cxt);
  return cxt;
}
```
user: What is the c source code of the assembly code below?

```asm
<read_move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
L100:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L100
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L198
  mov    $0xffffffff,%eax
  jmp    L20
L198:
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %eax,%eax
  jne    L29
  cmpl   $0x5b,-0x8(%rbp)
  jne    L164
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <clear_buf@plt>
  jmp    L194
L164:
  cmpl   $0x28,-0x8(%rbp)
  je     L137
  cmpl   $0x7b,-0x8(%rbp)
  jne    L194
L137:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  cmpl   $0x28,-0x8(%rbp)
  jne    L124
  movl   $0x29,-0x10(%rbp)
  jmp    L148
L124:
  movl   $0x7d,-0x10(%rbp)
  jmp    L148
L84:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jne    L45
  addl   $0x1,-0xc(%rbp)
  jmp    L148
L45:
  mov    -0x8(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jne    L148
  subl   $0x1,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jle    L203
L148:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x8(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L84
  jmp    L194
L203:
  nop
L194:
  mov    $0x0,%eax
  jmp    L20
L29:
  movl   $0x1,-0x14(%rbp)
  jmp    L56
L92:
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <fgetc@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L41
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x14(%rbp)
L56:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L92
  jmp    L154
L41:
  nop
L154:
  mov    -0x28(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x14(%rbp),%eax
L20:
  leave
  ret
```

assistant: ```c
int read_move(char *word, int lim, FILE *fp) {
  int i;
  int c;
  do {
    c = fgetc(fp);
  } while (isspace(c));
  if (c == EOF)
    return -1;
  *word++ = (char)c;
  if (!isalpha(c)) {
    if (c == '[')
      clear_buf(fp);
    else if (c == '(' || c == '{') {
      int open_b = c;
      int close_b;
      int nb = 1;
      if (c == '(')
        close_b = ')';
      else
        close_b = '}';
      while ((c = fgetc(fp)) != EOF) {
        if (c == open_b)
          nb++;
        else if (c == close_b && --nb <= 0)
          break;
      }
    }
    return 0;
  }
  for (i = 1; i < lim - 1; i++) {
    c = fgetc(fp);
    if (isspace(c))
      break;
    *word++ = (char)c;
  }
  *word = '\0';
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<read_move>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r15d
  mov    %rdx,%r13
L27:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
  mov    D12(%rip),%rax
  cmp    %ebx,(%rax)
  je     L152
  mov    %bl,(%r12)
  mov    %ebx,%edi
  call   <isalpha@plt>
  mov    %eax,%ebp
  test   %eax,%eax
  je     L37
  add    $0x1,%r12
  lea    -0x1(%r15),%r14d
  mov    $0x1,%ebp
  cmp    $0x2,%r15d
  jle    L142
L48:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L142
  add    $0x1,%r12
  mov    %bl,-0x1(%r12)
  add    $0x1,%ebp
  cmp    %r14d,%ebp
  jne    L48
  mov    %r14d,%ebp
L142:
  movb   $0x0,(%r12)
L81:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  cmp    $0x5b,%ebx
  je     L22
  cmp    $0x28,%ebx
  je     L99
  cmp    $0x7b,%ebx
  jne    L81
L99:
  cmp    $0x28,%ebx
  mov    $0x29,%r14d
  mov    $0x7d,%eax
  cmovne %eax,%r14d
  mov    $0x1,%r12d
  jmp    L29
L22:
  mov    %r13,%rdi
  call   <clear_buf@plt>
  jmp    L81
L10:
  add    $0x1,%r12d
L29:
  mov    %r13,%rdi
  call   <fgetc@plt>
  mov    D12(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L81
  cmp    %eax,%ebx
  je     L10
  cmp    %r14d,%eax
  jne    L29
  sub    $0x1,%r12d
  test   %r12d,%r12d
  jg     L29
  jmp    L81
L152:
  mov    $0xffffffff,%ebp
  jmp    L81
```

assistant: ```c
int read_move(char *word, int lim, FILE *fp) {
  int i;
  int c;
  do {
    c = fgetc(fp);
  } while (isspace(c));
  if (c == EOF)
    return -1;
  *word++ = (char)c;
  if (!isalpha(c)) {
    if (c == '[')
      clear_buf(fp);
    else if (c == '(' || c == '{') {
      int open_b = c;
      int close_b;
      int nb = 1;
      if (c == '(')
        close_b = ')';
      else
        close_b = '}';
      while ((c = fgetc(fp)) != EOF) {
        if (c == open_b)
          nb++;
        else if (c == close_b && --nb <= 0)
          break;
      }
    }
    return 0;
  }
  for (i = 1; i < lim - 1; i++) {
    c = fgetc(fp);
    if (isspace(c))
      break;
    *word++ = (char)c;
  }
  *word = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_move>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L72:
  mov    %r12,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L72
  mov    D4(%rip),%r15
  cmp    %ebx,(%r15)
  je     L32
  mov    %bl,0x0(%rbp)
  mov    %ebx,%edi
  call   <isalpha@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L165
  sub    $0x1,%r13d
  add    $0x1,%rbp
  mov    $0x1,%r14d
  cmp    $0x1,%r13d
  jg     L66
  jmp    L57
  nopl   (%rax)
L51:
  add    $0x1,%r14d
  add    $0x1,%rbp
  mov    %bl,-0x1(%rbp)
  cmp    %r13d,%r14d
  je     L57
L66:
  mov    %r12,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  je     L51
L57:
  movb   $0x0,0x0(%rbp)
L53:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L165:
  cmp    $0x5b,%ebx
  je     L112
  cmp    $0x28,%ebx
  je     L81
  cmp    $0x7b,%ebx
  jne    L53
L81:
  cmp    $0x28,%ebx
  mov    $0x29,%r13d
  mov    $0x7d,%eax
  mov    $0x1,%ebp
  cmovne %eax,%r13d
  cs nopw 0x0(%rax,%rax,1)
L90:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r15)
  je     L53
  cmp    %eax,%ebx
  je     L161
  cmp    %r13d,%eax
  jne    L90
  sub    $0x1,%ebp
  jne    L90
  jmp    L53
  nopl   (%rax)
L161:
  add    $0x1,%ebp
  jmp    L90
L112:
  mov    %r12,%rdi
  call   <clear_buf@plt>
  jmp    L53
L32:
  mov    $0xffffffff,%r14d
  jmp    L53
```

assistant: ```c
int read_move(char *word, int lim, FILE *fp) {
  int i;
  int c;
  do {
    c = fgetc(fp);
  } while (isspace(c));
  if (c == EOF)
    return -1;
  *word++ = (char)c;
  if (!isalpha(c)) {
    if (c == '[')
      clear_buf(fp);
    else if (c == '(' || c == '{') {
      int open_b = c;
      int close_b;
      int nb = 1;
      if (c == '(')
        close_b = ')';
      else
        close_b = '}';
      while ((c = fgetc(fp)) != EOF) {
        if (c == open_b)
          nb++;
        else if (c == close_b && --nb <= 0)
          break;
      }
    }
    return 0;
  }
  for (i = 1; i < lim - 1; i++) {
    c = fgetc(fp);
    if (isspace(c))
      break;
    *word++ = (char)c;
  }
  *word = '\0';
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<read_move>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L151:
  mov    %r12,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  jne    L151
  mov    D3(%rip),%r15
  cmp    %ebx,(%r15)
  je     L92
  mov    %bl,0x0(%rbp)
  mov    %ebx,%edi
  call   <isalpha@plt>
  mov    %eax,%r14d
  test   %eax,%eax
  je     L176
  sub    $0x1,%r13d
  add    $0x1,%rbp
  mov    $0x1,%r14d
  cmp    $0x1,%r13d
  jg     L35
  jmp    L164
  nopl   (%rax)
L149:
  add    $0x1,%r14d
  add    $0x1,%rbp
  mov    %bl,-0x1(%rbp)
  cmp    %r13d,%r14d
  je     L164
L35:
  mov    %r12,%rdi
  call   <fgetc@plt>
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <isspace@plt>
  test   %rax,%rax
  je     L149
L164:
  movb   $0x0,0x0(%rbp)
L91:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L176:
  cmp    $0x5b,%ebx
  je     L162
  cmp    $0x28,%ebx
  je     L82
  cmp    $0x7b,%ebx
  jne    L91
L82:
  cmp    $0x28,%ebx
  mov    $0x29,%r13d
  mov    $0x7d,%eax
  mov    $0x1,%ebp
  cmovne %eax,%r13d
  cs nopw 0x0(%rax,%rax,1)
L69:
  mov    %r12,%rdi
  call   <fgetc@plt>
  cmp    %eax,(%r15)
  je     L91
  cmp    %eax,%ebx
  je     L123
  cmp    %r13d,%eax
  jne    L69
  sub    $0x1,%ebp
  jne    L69
  jmp    L91
  nopl   (%rax)
L123:
  add    $0x1,%ebp
  jmp    L69
L162:
  mov    %r12,%rdi
  call   <clear_buf@plt>
  jmp    L91
L92:
  mov    $0xffffffff,%r14d
  jmp    L91
```

assistant: ```c
int read_move(char *word, int lim, FILE *fp) {
  int i;
  int c;
  do {
    c = fgetc(fp);
  } while (isspace(c));
  if (c == EOF)
    return -1;
  *word++ = (char)c;
  if (!isalpha(c)) {
    if (c == '[')
      clear_buf(fp);
    else if (c == '(' || c == '{') {
      int open_b = c;
      int close_b;
      int nb = 1;
      if (c == '(')
        close_b = ')';
      else
        close_b = '}';
      while ((c = fgetc(fp)) != EOF) {
        if (c == open_b)
          nb++;
        else if (c == close_b && --nb <= 0)
          break;
      }
    }
    return 0;
  }
  for (i = 1; i < lim - 1; i++) {
    c = fgetc(fp);
    if (isspace(c))
      break;
    *word++ = (char)c;
  }
  *word = '\0';
  return i;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<quickSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L6
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <partition@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <quickSort>
L6:
  nop
  leave
  ret
```

assistant: ```c
void quickSort(int arr[], int low, int high) {
  if (low < high) {
    int pi = partition(arr, low, high);
    quickSort(arr, low, pi - 1);
    quickSort(arr, pi + 1, high);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<quickSort>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
L0:
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  call   <partition@plt>
  mov    %eax,%ebp
  lea    -0x1(%rax),%edx
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <quickSort>
  lea    0x1(%rbp),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <quickSort>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void quickSort(int arr[], int low, int high) {
  if (low < high) {
    int pi = partition(arr, low, high);
    quickSort(arr, low, pi - 1);
    quickSort(arr, pi + 1, high);
  }
}
```