ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<panicf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <_Exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void panicf(char const *const format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  _Exit(EXIT_FAILURE);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<panicf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    D16(%rip),%rax
  mov    (%rax),%edi
  call   <_Exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void panicf(char const *const format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  _Exit(EXIT_FAILURE);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<panicf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D9(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%edi
  call   <_Exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void panicf(char const *const format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  _Exit(EXIT_FAILURE);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<panicf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%edi
  call   <_Exit@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void panicf(char const *const format, ...) {
  va_list args;
  va_start(args, format);
  vfprintf(stderr, format, args);
  _Exit(EXIT_FAILURE);
}
```
user: Translate the below assembly code into C programming language:

```asm
<st_xor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movb   $0x0,-0x5(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L11
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  xor    %al,-0x5(%rbp)
  addl   $0x1,-0x4(%rbp)
L11:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L3
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x5(%rbp),%eax
  mov    %al,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void st_xor(unsigned char *out, int len) {
  int i;
  unsigned char res = 0;
  for (i = 0; i < len; i++)
    res ^= out[i];
  out[len] = res;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<st_xor>:
  endbr64
  test   %esi,%esi
  jle    L21
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rcx
  mov    $0x0,%edx
L24:
  xor    (%rax),%dl
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L24
L0:
  movslq %esi,%rsi
  mov    %dl,(%rdi,%rsi,1)
  ret
L21:
  mov    $0x0,%edx
  jmp    L0
```

assistant: ```c
void st_xor(unsigned char *out, int len) {
  int i;
  unsigned char res = 0;
  for (i = 0; i < len; i++)
    res ^= out[i];
  out[len] = res;
}
```
user: What is the c source code of the assembly code below:

```asm
<st_xor>:
  endbr64
  test   %esi,%esi
  jle    L5
  lea    -0x1(%rsi),%edx
  mov    %rdi,%rax
  lea    0x1(%rdi,%rdx,1),%rcx
  xor    %edx,%edx
  nopl   (%rax)
L12:
  xor    (%rax),%dl
  add    $0x1,%rax
  cmp    %rcx,%rax
  jne    L12
  movslq %esi,%rsi
  mov    %dl,(%rdi,%rsi,1)
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  xor    %edx,%edx
  movslq %esi,%rsi
  mov    %dl,(%rdi,%rsi,1)
  ret
```

assistant: ```c
void st_xor(unsigned char *out, int len) {
  int i;
  unsigned char res = 0;
  for (i = 0; i < len; i++)
    res ^= out[i];
  out[len] = res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<st_xor>:
  endbr64
  test   %esi,%esi
  jle    L141
  lea    -0x1(%rsi),%eax
  cmp    $0xe,%eax
  jbe    L20
  mov    %esi,%edx
  mov    %rdi,%rax
  pxor   %xmm0,%xmm0
  shr    $0x4,%edx
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
L182:
  movdqu (%rax),%xmm2
  add    $0x10,%rax
  pxor   %xmm2,%xmm0
  cmp    %rax,%rdx
  jne    L182
  movdqa %xmm0,%xmm1
  mov    %esi,%edx
  psrldq $0x8,%xmm1
  and    $0xfffffff0,%edx
  pxor   %xmm1,%xmm0
  mov    %edx,%r8d
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x2,%xmm1
  pxor   %xmm1,%xmm0
  movdqa %xmm0,%xmm1
  psrldq $0x1,%xmm1
  pxor   %xmm1,%xmm0
  movd   %xmm0,%eax
  cmp    %edx,%esi
  je     L22
L196:
  mov    %esi,%r9d
  sub    %edx,%r9d
  lea    -0x1(%r9),%ecx
  cmp    $0x6,%ecx
  jbe    L135
  mov    (%rdi,%rdx,1),%rcx
  push   %rbx
  mov    %ecx,%edx
  movzbl %ch,%ebx
  xor    %ebx,%edx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x10,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x18,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x20,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x28,%rdx
  xor    %edx,%eax
  mov    %rcx,%rdx
  shr    $0x38,%rcx
  shr    $0x30,%rdx
  xor    %edx,%eax
  mov    %r9d,%edx
  and    $0xfffffff8,%edx
  xor    %ecx,%eax
  add    %edx,%r8d
  cmp    %edx,%r9d
  je     L74
  movslq %r8d,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x1(%r8),%edx
  cmp    %edx,%esi
  jle    L74
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x2(%r8),%edx
  cmp    %esi,%edx
  jge    L74
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x3(%r8),%edx
  cmp    %edx,%esi
  jle    L74
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x4(%r8),%edx
  cmp    %edx,%esi
  jle    L74
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x5(%r8),%edx
  cmp    %edx,%esi
  jle    L74
  movslq %edx,%rdx
  add    $0x6,%r8d
  xor    (%rdi,%rdx,1),%al
  cmp    %r8d,%esi
  jle    L74
  movslq %r8d,%r8
  xor    (%rdi,%r8,1),%al
L74:
  movslq %esi,%rsi
  pop    %rbx
  mov    %al,(%rdi,%rsi,1)
  ret
  nop
L141:
  xor    %eax,%eax
L22:
  movslq %esi,%rsi
  mov    %al,(%rdi,%rsi,1)
  ret
L20:
  xor    %edx,%edx
  xor    %eax,%eax
  xor    %r8d,%r8d
  jmp    L196
L135:
  movslq %r8d,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x1(%r8),%edx
  cmp    %edx,%esi
  jle    L22
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x2(%r8),%edx
  cmp    %esi,%edx
  jge    L22
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x3(%r8),%edx
  cmp    %edx,%esi
  jle    L22
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x4(%r8),%edx
  cmp    %edx,%esi
  jle    L22
  movslq %edx,%rdx
  xor    (%rdi,%rdx,1),%al
  lea    0x5(%r8),%edx
  cmp    %edx,%esi
  jle    L22
  movslq %edx,%rdx
  add    $0x6,%r8d
  xor    (%rdi,%rdx,1),%al
  cmp    %r8d,%esi
  jle    L22
  movslq %r8d,%r8
  xor    (%rdi,%r8,1),%al
  jmp    L22
```

assistant: ```c
void st_xor(unsigned char *out, int len) {
  int i;
  unsigned char res = 0;
  for (i = 0; i < len; i++)
    res ^= out[i];
  out[len] = res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<le_short>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  and    $0xff,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x8,%eax
  and    $0xff00,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x18,%eax
  or     %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t le_short(uint32_t x) {
  uint32_t val;
  uint8_t *p = (uint8_t *)(&x);
  val = (*p++ & 0xff) << 0;
  val |= (*p++ & 0xff) << 8;
  val |= (*p++ & 0xff) << 16;
  val |= (*p & 0xff) << 24;
  return val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<le_short>:
  endbr64
  mov    0x8(%rsp),%edx
  shl    $0x18,%edx
  movzbl %dil,%eax
  or     %eax,%edx
  shl    $0x8,%edi
  movzwl %di,%edi
  or     %edi,%edx
  mov    0x4(%rsp),%eax
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t le_short(uint32_t x) {
  uint32_t val;
  uint8_t *p = (uint8_t *)(&x);
  val = (*p++ & 0xff) << 0;
  val |= (*p++ & 0xff) << 8;
  val |= (*p++ & 0xff) << 16;
  val |= (*p & 0xff) << 24;
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<le_short>:
  endbr64
  mov    0x8(%rsp),%edx
  movzbl %dil,%eax
  shl    $0x8,%edi
  movzwl %di,%edi
  shl    $0x18,%edx
  or     %eax,%edx
  mov    0x4(%rsp),%eax
  or     %edi,%edx
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t le_short(uint32_t x) {
  uint32_t val;
  uint8_t *p = (uint8_t *)(&x);
  val = (*p++ & 0xff) << 0;
  val |= (*p++ & 0xff) << 8;
  val |= (*p++ & 0xff) << 16;
  val |= (*p & 0xff) << 24;
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<le_short>:
  endbr64
  mov    0x8(%rsp),%edx
  movzbl %dil,%eax
  shl    $0x8,%edi
  movzwl %di,%edi
  shl    $0x18,%edx
  or     %eax,%edx
  mov    0x4(%rsp),%eax
  or     %edi,%edx
  shl    $0x10,%eax
  and    $0xff0000,%eax
  or     %edx,%eax
  ret
```

assistant: ```c
uint32_t le_short(uint32_t x) {
  uint32_t val;
  uint8_t *p = (uint8_t *)(&x);
  val = (*p++ & 0xff) << 0;
  val |= (*p++ & 0xff) << 8;
  val |= (*p++ & 0xff) << 16;
  val |= (*p & 0xff) << 24;
  return val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_subset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L45
L54:
  movl   $0x0,-0x10(%rbp)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L17
L58:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L16
  movl   $0x1,-0x10(%rbp)
  jmp    L62
L16:
  addl   $0x1,-0xc(%rbp)
L17:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jl     L58
L62:
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L19
  cmpl   $0x0,-0x10(%rbp)
  jne    L54
L19:
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int is_subset(const char *super, const char *sub) {
  int found = 1;
  int i, j = 0, c = 0;
  for (; *(sub + j) != '\0' && found; ++j) {
    found = 0;
    c = *(sub + j);
    for (i = 0; i < strlen(super); ++i) {
      if (c == *(super + i)) {
        found = 1;
        break;
      }
    }
  }
  return found;
}
```
user: What is the c source code of the assembly code below:

```asm
<is_subset>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%r12d
  test   %r12b,%r12b
  je     L79
  mov    %rdi,%rbp
  lea    0x1(%rsi),%r13
  jmp    L65
L24:
  mov    $0x0,%eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  add    $0x1,%r13
  movzbl -0x1(%r13),%r12d
  test   %r12b,%r12b
  je     L50
L65:
  mov    $0x0,%ebx
L54:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L24
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  jne    L54
  jmp    L2
L79:
  mov    $0x1,%eax
  jmp    L30
L50:
  mov    $0x1,%eax
  jmp    L30
```

assistant: ```c
int is_subset(const char *super, const char *sub) {
  int found = 1;
  int i, j = 0, c = 0;
  for (; *(sub + j) != '\0' && found; ++j) {
    found = 0;
    c = *(sub + j);
    for (i = 0; i < strlen(super); ++i) {
      if (c == *(super + i)) {
        found = 1;
        break;
      }
    }
  }
  return found;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_subset>:
  endbr64
  push   %r13
  lea    0x1(%rsi),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%r12d
  test   %r12b,%r12b
  je     L36
  xchg   %ax,%ax
L47:
  xor    %ebx,%ebx
  jmp    L14
  nopl   0x0(%rax)
L29:
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L11
L14:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L29
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L11:
  movzbl 0x0(%r13),%r12d
  add    $0x1,%r13
  test   %r12b,%r12b
  jne    L47
L36:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is_subset(const char *super, const char *sub) {
  int found = 1;
  int i, j = 0, c = 0;
  for (; *(sub + j) != '\0' && found; ++j) {
    found = 0;
    c = *(sub + j);
    for (i = 0; i < strlen(super); ++i) {
      if (c == *(super + i)) {
        found = 1;
        break;
      }
    }
  }
  return found;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<is_subset>:
  endbr64
  push   %r13
  lea    0x1(%rsi),%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%r12d
  test   %r12b,%r12b
  je     L49
  xchg   %ax,%ax
L35:
  xor    %ebx,%ebx
  jmp    L28
  nopl   0x0(%rax)
L39:
  add    $0x1,%rbx
  cmp    %r12b,-0x1(%rbp,%rbx,1)
  je     L4
L28:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L39
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  movzbl 0x0(%r13),%r12d
  add    $0x1,%r13
  test   %r12b,%r12b
  jne    L35
L49:
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int is_subset(const char *super, const char *sub) {
  int found = 1;
  int i, j = 0, c = 0;
  for (; *(sub + j) != '\0' && found; ++j) {
    found = 0;
    c = *(sub + j);
    for (i = 0; i < strlen(super); ++i) {
      if (c == *(super + i)) {
        found = 1;
        break;
      }
    }
  }
  return found;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uc2i_array>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  jmp    L15
L18:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    $0xffffff80,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    $0x18,%esi
  mov    %eax,%edi
  call   <arith_shift_left@plt>
  mov    %eax,(%rbx)
L15:
  subl   $0x1,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jns    L18
  nop
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void uc2i_array(unsigned char *src, int count, int *dest) {
  while (--count >= 0) {
    dest[count] = arith_shift_left(((int)src[count]) - 128, 24);
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uc2i_array>:
  endbr64
  sub    $0x1,%esi
  js     L14
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdx,%r12
  movslq %esi,%rbx
L12:
  movzbl 0x0(%rbp,%rbx,1),%edi
  add    $0xffffff80,%edi
  mov    $0x18,%esi
  call   <arith_shift_left@plt>
  mov    %eax,(%r12,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L12
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  ret
```

assistant: ```c
void uc2i_array(unsigned char *src, int count, int *dest) {
  while (--count >= 0) {
    dest[count] = arith_shift_left(((int)src[count]) - 128, 24);
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<uc2i_array>:
  endbr64
  sub    $0x1,%esi
  js     L19
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L11:
  movzbl 0x0(%rbp,%rbx,1),%edi
  mov    $0x18,%esi
  add    $0xffffff80,%edi
  call   <arith_shift_left@plt>
  mov    %eax,(%r12,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  ret
```

assistant: ```c
void uc2i_array(unsigned char *src, int count, int *dest) {
  while (--count >= 0) {
    dest[count] = arith_shift_left(((int)src[count]) - 128, 24);
  };
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<uc2i_array>:
  endbr64
  sub    $0x1,%esi
  js     L1
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movslq %esi,%rbx
  cs nopw 0x0(%rax,%rax,1)
L7:
  movzbl 0x0(%rbp,%rbx,1),%edi
  mov    $0x18,%esi
  add    $0xffffff80,%edi
  call   <arith_shift_left@plt>
  mov    %eax,(%r12,%rbx,4)
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void uc2i_array(unsigned char *src, int count, int *dest) {
  while (--count >= 0) {
    dest[count] = arith_shift_left(((int)src[count]) - 128, 24);
  };
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strtob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %rdx,-0x38(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L68
L32:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rcx
  mov    -0x28(%rbp),%rdx
  mov    %rcx,(%rdx)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x11(%rbp)
  cmpb   $0x0,-0x11(%rbp)
  je     L0
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L31
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    %al,-0x11(%rbp)
  je     L87
  addq   $0x1,-0x8(%rbp)
L31:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L20
  jmp    L7
L87:
  nop
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  mov    -0xc(%rbp),%eax
  or     %eax,-0x10(%rbp)
L14:
  sarl   -0xc(%rbp)
L68:
  cmpl   $0x0,-0xc(%rbp)
  jne    L32
  jmp    L62
L0:
  nop
L62:
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int strtob(char **ptr, int bits, char const *c0) {
  int retval = 0;
  for (int bit = 1 << (bits - 1); bit; bit >>= 1) {
    char c = toupper(*((*ptr)++));
    if (c) {
      char const *c1;
      for (c1 = c0; *c1; c1++)
        if (c == toupper(*c1))
          break;
      if (!*c1)
        retval |= bit;
    } else
      break;
  }
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtob>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    -0x1(%rsi),%ecx
  mov    $0x1,%r12d
  shl    %cl,%r12d
  test   %r12d,%r12d
  je     L70
  mov    %rdi,%r13
  mov    %rdx,%r14
  mov    $0x0,%r15d
  jmp    L67
L89:
  cmpb   $0x0,(%rbx)
  jne    L87
L3:
  or     %r12d,%r15d
L87:
  sar    %r12d
  je     L44
L67:
  mov    0x0(%r13),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,0x0(%r13)
  movsbl (%rax),%edi
  call   <toupper@plt>
  mov    %eax,%ebp
  test   %al,%al
  je     L44
  movzbl (%r14),%edi
  test   %dil,%dil
  je     L3
  mov    %r14,%rbx
L79:
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    %bpl,%al
  je     L89
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L79
  jmp    L3
L70:
  mov    %r12d,%r15d
L44:
  mov    %r15d,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int strtob(char **ptr, int bits, char const *c0) {
  int retval = 0;
  for (int bit = 1 << (bits - 1); bit; bit >>= 1) {
    char c = toupper(*((*ptr)++));
    if (c) {
      char const *c1;
      for (c1 = c0; *c1; c1++)
        if (c == toupper(*c1))
          break;
      if (!*c1)
        retval |= bit;
    } else
      break;
  }
  return retval;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<strtob>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%ecx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  shl    %cl,%ebp
  sub    $0x8,%rsp
  test   %ebp,%ebp
  je     L63
  mov    %rdi,%r12
  mov    %rdx,%r13
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L94:
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movsbl (%rax),%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  test   %al,%al
  je     L83
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L69
  mov    %r13,%r15
  jmp    L67
  nopl   0x0(%rax)
L53:
  movsbl 0x1(%r15),%edi
  add    $0x1,%r15
  test   %dil,%dil
  je     L69
L67:
  call   <toupper@plt>
  cmp    %bl,%al
  jne    L53
  cmpb   $0x0,(%r15)
  je     L69
L26:
  sar    %ebp
  jne    L94
L83:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L69:
  or     %ebp,%r14d
  jmp    L26
L63:
  xor    %r14d,%r14d
  jmp    L83
```

assistant: ```c
int strtob(char **ptr, int bits, char const *c0) {
  int retval = 0;
  for (int bit = 1 << (bits - 1); bit; bit >>= 1) {
    char c = toupper(*((*ptr)++));
    if (c) {
      char const *c1;
      for (c1 = c0; *c1; c1++)
        if (c == toupper(*c1))
          break;
      if (!*c1)
        retval |= bit;
    } else
      break;
  }
  return retval;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtob>:
  endbr64
  push   %r15
  lea    -0x1(%rsi),%ecx
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  shl    %cl,%ebp
  sub    $0x8,%rsp
  test   %ebp,%ebp
  je     L96
  mov    %rdi,%r12
  mov    %rdx,%r13
  xor    %r14d,%r14d
  nopl   0x0(%rax)
L3:
  mov    (%r12),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,(%r12)
  movsbl (%rax),%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  test   %al,%al
  je     L19
  movsbl 0x0(%r13),%edi
  test   %dil,%dil
  je     L25
  mov    %r13,%r15
  jmp    L56
  nopl   0x0(%rax)
L31:
  movsbl 0x1(%r15),%edi
  add    $0x1,%r15
  test   %dil,%dil
  je     L25
L56:
  call   <toupper@plt>
  cmp    %bl,%al
  jne    L31
  cmpb   $0x0,(%r15)
  je     L25
L89:
  sar    %ebp
  jne    L3
L19:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  or     %ebp,%r14d
  jmp    L89
L96:
  xor    %r14d,%r14d
  jmp    L19
```

assistant: ```c
int strtob(char **ptr, int bits, char const *c0) {
  int retval = 0;
  for (int bit = 1 << (bits - 1); bit; bit >>= 1) {
    char c = toupper(*((*ptr)++));
    if (c) {
      char const *c1;
      for (c1 = c0; *c1; c1++)
        if (c == toupper(*c1))
          break;
      if (!*c1)
        retval |= bit;
    } else
      break;
  }
  return retval;
}
```