ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<str_rindex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x30(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L91
  mov    -0x8(%rbp),%rax
  jmp    L13
L91:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jae    L117
  mov    $0xffffffffffffffff,%rax
  jmp    L13
L117:
  mov    -0x8(%rbp),%rax
  sub    -0x10(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L86
L70:
  movq   $0x0,-0x18(%rbp)
  jmp    L0
L88:
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x30(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L114
  addq   $0x1,-0x18(%rbp)
L0:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L88
  jmp    L100
L114:
  nop
L100:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jne    L2
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  jmp    L13
L2:
  subq   $0x1,-0x20(%rbp)
L86:
  mov    -0x20(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jae    L70
  mov    $0xffffffffffffffff,%rax
L13:
  leave
  ret
```

assistant: ```c
__attribute__((__pure__)) size_t str_rindex(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_n = strlen(needle);
  size_t haystack_n = strlen(haystack);
  if (needle_n == 0)
    return haystack_n;
  if (haystack_n < needle_n)
    return -1;
  for (const char *p = haystack + haystack_n - needle_n; p >= haystack; p--) {
    size_t i;
    for (i = 0; i < needle_n; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_n)
      return p - haystack;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_rindex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %rbp,%rbp
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  test   %rbx,%rbx
  je     L83
  mov    $0xffffffffffffffff,%rdx
  cmp    %rax,%rbx
  ja     L83
  sub    %rbx,%rax
  add    %r12,%rax
  mov    %rax,%rdx
  jae    L22
  mov    $0xffffffffffffffff,%rdx
  jmp    L83
L72:
  cmp    %rax,%rbx
  je     L57
  sub    $0x1,%rdx
  cmp    %rdx,%r12
  ja     L65
L22:
  mov    $0x0,%eax
L25:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%rdx,%rax,1)
  jne    L72
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L25
L57:
  sub    %r12,%rdx
L83:
  mov    %rdx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L65:
  mov    $0xffffffffffffffff,%rdx
  jmp    L83
```

assistant: ```c
__attribute__((__pure__)) size_t str_rindex(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_n = strlen(needle);
  size_t haystack_n = strlen(haystack);
  if (needle_n == 0)
    return haystack_n;
  if (haystack_n < needle_n)
    return -1;
  for (const char *p = haystack + haystack_n - needle_n; p >= haystack; p--) {
    size_t i;
    for (i = 0; i < needle_n; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_n)
      return p - haystack;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_rindex>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  test   %rbx,%rbx
  je     L5
  mov    %rax,%rdx
  mov    $0xffffffffffffffff,%rax
  cmp    %rdx,%rbx
  ja     L5
  sub    %rbx,%rdx
  add    %r12,%rdx
  jb     L5
  nopl   0x0(%rax,%rax,1)
L29:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L32:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%rdx,%rax,1)
  jne    L13
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L32
L31:
  mov    %rdx,%rax
  sub    %r12,%rax
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  cmp    %rax,%rbx
  je     L31
  sub    $0x1,%rdx
  cmp    %rdx,%r12
  jbe    L29
  pop    %rbx
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__pure__)) size_t str_rindex(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_n = strlen(needle);
  size_t haystack_n = strlen(haystack);
  if (needle_n == 0)
    return haystack_n;
  if (haystack_n < needle_n)
    return -1;
  for (const char *p = haystack + haystack_n - needle_n; p >= haystack; p--) {
    size_t i;
    for (i = 0; i < needle_n; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_n)
      return p - haystack;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<str_rindex>:
  endbr64
  push   %r12
  test   %rdi,%rdi
  mov    %rdi,%r12
  push   %rbp
  setne  %dil
  mov    %rsi,%rbp
  push   %rbx
  movzbl %dil,%edi
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  test   %rbx,%rbx
  je     L51
  mov    %rax,%rdx
  mov    $0xffffffffffffffff,%rax
  cmp    %rdx,%rbx
  ja     L51
  sub    %rbx,%rdx
  add    %r12,%rdx
  jb     L51
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L65:
  movzbl 0x0(%rbp,%rax,1),%ecx
  cmp    %cl,(%rdx,%rax,1)
  jne    L1
  add    $0x1,%rax
  cmp    %rax,%rbx
  jne    L65
L49:
  mov    %rdx,%rax
  sub    %r12,%rax
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  cmp    %rax,%rbx
  je     L49
  sub    $0x1,%rdx
  cmp    %rdx,%r12
  jbe    L34
  pop    %rbx
  mov    $0xffffffffffffffff,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
__attribute__((__pure__)) size_t str_rindex(const char *haystack, const char *needle) {
  assert(haystack != NULL);
  assert(needle != NULL);
  size_t needle_n = strlen(needle);
  size_t haystack_n = strlen(haystack);
  if (needle_n == 0)
    return haystack_n;
  if (haystack_n < needle_n)
    return -1;
  for (const char *p = haystack + haystack_n - needle_n; p >= haystack; p--) {
    size_t i;
    for (i = 0; i < needle_n; i++) {
      if (p[i] != needle[i])
        break;
    }
    if (i == needle_n)
      return p - haystack;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<EMACTimestampPPSCommandModeSet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x400ec000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x8(%rbp),%eax
  and    $0x60,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  nop
L1:
  mov    -0x4(%rbp),%eax
  add    $0x72c,%eax
  cltq
  mov    (%rax),%eax
  and    $0xf,%eax
  test   %eax,%eax
  jne    L1
  mov    -0x4(%rbp),%eax
  add    $0x72c,%eax
  cltq
  mov    %rax,%rdx
  mov    -0x8(%rbp),%eax
  or     $0x10,%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void EMACTimestampPPSCommandModeSet(uint32_t ui32Base, uint32_t ui32Config) {
  ASSERT(ui32Base == 0x400EC000);
  ASSERT(!(ui32Config & (0x00000000 | 0x00000060 | 0x00000040)));
  while ((*((volatile uint32_t *)(ui32Base + 0x0000072C))) & 0x0000000F) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x0000072C))) = (0x00000010 | ui32Config);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<EMACTimestampPPSCommandModeSet>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  cmp    $0x400ec000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  test   $0x60,%bpl
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  lea    0x72c(%rbx),%edx
  movslq %edx,%rdx
L1:
  mov    (%rdx),%eax
  test   $0xf,%al
  jne    L1
  or     $0x10,%ebp
  mov    %ebp,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EMACTimestampPPSCommandModeSet(uint32_t ui32Base, uint32_t ui32Config) {
  ASSERT(ui32Base == 0x400EC000);
  ASSERT(!(ui32Config & (0x00000000 | 0x00000060 | 0x00000040)));
  while ((*((volatile uint32_t *)(ui32Base + 0x0000072C))) & 0x0000000F) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x0000072C))) = (0x00000010 | ui32Config);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<EMACTimestampPPSCommandModeSet>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400ec000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  test   $0x60,%bpl
  sete   %dil
  call   <ASSERT@plt>
  lea    0x72c(%rbx),%edx
  movslq %edx,%rdx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rdx),%eax
  test   $0xf,%al
  jne    L2
  or     $0x10,%ebp
  mov    %ebp,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EMACTimestampPPSCommandModeSet(uint32_t ui32Base, uint32_t ui32Config) {
  ASSERT(ui32Base == 0x400EC000);
  ASSERT(!(ui32Config & (0x00000000 | 0x00000060 | 0x00000040)));
  while ((*((volatile uint32_t *)(ui32Base + 0x0000072C))) & 0x0000000F) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x0000072C))) = (0x00000010 | ui32Config);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<EMACTimestampPPSCommandModeSet>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  cmp    $0x400ec000,%ebx
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  test   $0x60,%bpl
  sete   %dil
  call   <ASSERT@plt>
  lea    0x72c(%rbx),%edx
  movslq %edx,%rdx
  nopw   0x0(%rax,%rax,1)
L7:
  mov    (%rdx),%eax
  test   $0xf,%al
  jne    L7
  or     $0x10,%ebp
  mov    %ebp,(%rdx)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void EMACTimestampPPSCommandModeSet(uint32_t ui32Base, uint32_t ui32Config) {
  ASSERT(ui32Base == 0x400EC000);
  ASSERT(!(ui32Config & (0x00000000 | 0x00000060 | 0x00000040)));
  while ((*((volatile uint32_t *)(ui32Base + 0x0000072C))) & 0x0000000F) {
  }
  (*((volatile uint32_t *)(ui32Base + 0x0000072C))) = (0x00000010 | ui32Config);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<_RWSTD_NAMESPACE>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
_RWSTD_NAMESPACE(__rw) {
  union __rw_critical_section {
    long _C_pad;
    char _C_buf[24];
  };
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_RWSTD_NAMESPACE>:
  endbr64
  ret
```

assistant: ```c
_RWSTD_NAMESPACE(__rw) {
  union __rw_critical_section {
    long _C_pad;
    char _C_buf[24];
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_RWSTD_NAMESPACE>:
  endbr64
  ret
```

assistant: ```c
_RWSTD_NAMESPACE(__rw) {
  union __rw_critical_section {
    long _C_pad;
    char _C_buf[24];
  };
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_RWSTD_NAMESPACE>:
  endbr64
  ret
```

assistant: ```c
_RWSTD_NAMESPACE(__rw) {
  union __rw_critical_section {
    long _C_pad;
    char _C_buf[24];
  };
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<lireCaractere>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x0,-0x1(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp)
  movsbl -0x1(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x1(%rbp)
  nop
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
  movzbl -0x1(%rbp),%eax
  leave
  ret
```

assistant: ```c
char lireCaractere() {
  char caractere = 0;
  caractere = getchar();
  caractere = toupper(caractere);
  while (getchar() != '\n')
    ;
  return caractere;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<lireCaractere>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
L0:
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L0
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
char lireCaractere() {
  char caractere = 0;
  caractere = getchar();
  caractere = toupper(caractere);
  while (getchar() != '\n')
    ;
  return caractere;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lireCaractere>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <toupper@plt>
  mov    %eax,%r12d
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L4
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char lireCaractere() {
  char caractere = 0;
  caractere = getchar();
  caractere = toupper(caractere);
  while (getchar() != '\n')
    ;
  return caractere;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lireCaractere>:
  endbr64
  push   %r12
  xor    %eax,%eax
  call   <getchar@plt>
  movsbl %al,%edi
  call   <toupper@plt>
  mov    %eax,%r12d
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%al
  jne    L4
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
char lireCaractere() {
  char caractere = 0;
  caractere = getchar();
  caractere = toupper(caractere);
  while (getchar() != '\n')
    ;
  return caractere;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rtime_check_working>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  je     L18
  mov    $0x0,%eax
  jmp    L8
L18:
  mov    $0x1,%eax
L8:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

assistant: ```c
int rtime_check_working(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) != 0)
    return 0;
  else
    return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rtime_check_working>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rtime_check_working(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) != 0)
    return 0;
  else
    return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<rtime_check_working>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rtime_check_working(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) != 0)
    return 0;
  else
    return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rtime_check_working>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x4(%rsp),%rsi
  mov    (%rax),%edi
  call   <clock_gettime@plt>
  test   %rax,%rax
  sete   %al
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  movzbl %al,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int rtime_check_working(void) {
  struct timespec ts;
  if (clock_gettime(CLOCK_MONOTONIC, &ts) != 0)
    return 0;
  else
    return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<cdrom_exit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <HsPrintk@plt>
  mov    $0x0,%eax
  call   <cdrom_sysctl_unregister@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D2
datatype: string

tool: D2: <6>Uniform CD-ROM driver unloaded


assistant: ```c
void cdrom_exit(void) {
  HsPrintk("<6>Uniform CD-ROM driver unloaded\n");
  cdrom_sysctl_unregister();
  return;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cdrom_exit>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <HsPrintk@plt>
  mov    $0x0,%eax
  call   <cdrom_sysctl_unregister@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
datatype: string

tool: D0: <6>Uniform CD-ROM driver unloaded


assistant: ```c
void cdrom_exit(void) {
  HsPrintk("<6>Uniform CD-ROM driver unloaded\n");
  cdrom_sysctl_unregister();
  return;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cdrom_exit>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <HsPrintk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <cdrom_sysctl_unregister@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type: string

tool: D7: <6>Uniform CD-ROM driver unloaded


assistant: ```c
void cdrom_exit(void) {
  HsPrintk("<6>Uniform CD-ROM driver unloaded\n");
  cdrom_sysctl_unregister();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<cdrom_exit>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <HsPrintk@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <cdrom_sysctl_unregister@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D2
type_guessed: string

tool: D2: <6>Uniform CD-ROM driver unloaded


assistant: ```c
void cdrom_exit(void) {
  HsPrintk("<6>Uniform CD-ROM driver unloaded\n");
  cdrom_sysctl_unregister();
  return;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  nop
L2:
  mov    $0x11006014,%eax
  movzbl (%rax),%eax
  movzbl %al,%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L2
  mov    $0x11006000,%eax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void putc(int c) {
  while (!(*(volatile unsigned char *)(0x11006000 + 0x14) & 0x20))
    ;
  *(volatile unsigned char *)(0x11006000 + 0x0) = c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<putc>:
  endbr64
L7:
  movzbl 0x11006014,%eax
  test   $0x20,%al
  je     L7
  mov    %dil,0x11006000
  ret
```

assistant: ```c
void putc(int c) {
  while (!(*(volatile unsigned char *)(0x11006000 + 0x14) & 0x20))
    ;
  *(volatile unsigned char *)(0x11006000 + 0x0) = c;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<putc>:
  endbr64
  nopl   0x0(%rax)
L6:
  movzbl 0x11006014,%eax
  test   $0x20,%al
  je     L6
  mov    %dil,0x11006000
  ret
```

assistant: ```c
void putc(int c) {
  while (!(*(volatile unsigned char *)(0x11006000 + 0x14) & 0x20))
    ;
  *(volatile unsigned char *)(0x11006000 + 0x0) = c;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<putc>:
  endbr64
  nopl   0x0(%rax)
L7:
  movzbl 0x11006014,%eax
  test   $0x20,%al
  je     L7
  mov    %dil,0x11006000
  ret
```

assistant: ```c
void putc(int c) {
  while (!(*(volatile unsigned char *)(0x11006000 + 0x14) & 0x20))
    ;
  *(volatile unsigned char *)(0x11006000 + 0x0) = c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<quicksort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jle    L18
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L13
L47:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L24
  addl   $0x1,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L24:
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L47
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  mov    -0x1c(%rbp),%eax
  sub    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <quicksort>
  jmp    L39
L18:
  nop
L39:
  leave
  ret
```

assistant: ```c
void quicksort(int v[], int n) {
  int i, last;
  if (n <= 1)
    return;
  swap(v, 0, rand() % n);
  last = 0;
  for (i = 1; i < n; i++)
    if (v[i] < v[0])
      swap(v, ++last, i);
  swap(v, 0, last);
  quicksort(v, last);
  quicksort(v + last + 1, n - last - 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<quicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L49
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r13d
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %r13d
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r13d,%r14d
  mov    $0x1,%ebx
  mov    $0x0,%r12d
  jmp    L28
L33:
  add    $0x1,%rbx
  cmp    %r14,%rbx
  je     L13
L28:
  mov    %ebx,%edx
  mov    0x0(%rbp),%eax
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L33
  add    $0x1,%r12d
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L33
L13:
  mov    %r12d,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  sub    %r12d,%r13d
  lea    -0x1(%r13),%esi
  movslq %r12d,%r12
  lea    0x4(%rbp,%r12,4),%rdi
  call   <quicksort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L49:
  ret
```

assistant: ```c
void quicksort(int v[], int n) {
  int i, last;
  if (n <= 1)
    return;
  swap(v, 0, rand() % n);
  last = 0;
  for (i = 1; i < n; i++)
    if (v[i] < v[0])
      swap(v, ++last, i);
  swap(v, 0, last);
  quicksort(v, last);
  quicksort(v + last + 1, n - last - 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quicksort>:
  endbr64
  cmp    $0x1,%esi
  jle    L14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L15:
  xor    %eax,%eax
  mov    $0x1,%ebx
  xor    %r13d,%r13d
  call   <rand@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  cltd
  idiv   %r12d
  call   <swap@plt>
  jmp    L55
  nopl   0x0(%rax)
L48:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jle    L10
L55:
  mov    0x0(%rbp),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%rbx,4)
  jge    L48
  add    $0x1,%r13d
  mov    %rbp,%rdi
  add    $0x1,%rbx
  mov    %r13d,%esi
  call   <swap@plt>
  cmp    %ebx,%r12d
  jg     L55
L10:
  mov    %r13d,%edx
  mov    %rbp,%rdi
  xor    %esi,%esi
  sub    %r13d,%r12d
  call   <swap@plt>
  sub    $0x1,%r12d
  mov    %r13d,%esi
  mov    %rbp,%rdi
  call   <quicksort>
  movslq %r13d,%r13
  lea    0x4(%rbp,%r13,4),%rbp
  cmp    $0x1,%r12d
  jg     L15
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  ret
```

assistant: ```c
void quicksort(int v[], int n) {
  int i, last;
  if (n <= 1)
    return;
  swap(v, 0, rand() % n);
  last = 0;
  for (i = 1; i < n; i++)
    if (v[i] < v[0])
      swap(v, ++last, i);
  swap(v, 0, last);
  quicksort(v, last);
  quicksort(v + last + 1, n - last - 1);
}
```