ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<vrand>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x20,%rsp
  movss  %xmm0,0xc(%rsp)
  movss  D27(%rip),%xmm0
  call   <drand@plt>
  movss  %xmm0,0x10(%rsp)
  movss  D7(%rip),%xmm0
  call   <drand@plt>
  movss  0x10(%rsp),%xmm3
  movaps %xmm0,%xmm2
  movss  D0(%rip),%xmm0
  subss  %xmm0,%xmm2
  movaps %xmm2,%xmm1
  mulss  %xmm2,%xmm1
  subss  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  ucomiss %xmm0,%xmm1
  ja     L1
  movaps %xmm0,%xmm1
  sqrtss %xmm1,%xmm1
L11:
  lea    0x1c(%rsp),%rdi
  lea    0x18(%rsp),%rsi
  movaps %xmm3,%xmm0
  movss  %xmm1,0x14(%rsp)
  movss  %xmm2,0x10(%rsp)
  call   <sincosf@plt>
  movss  0xc(%rsp),%xmm4
  movss  0x14(%rsp),%xmm1
  movss  0x10(%rsp),%xmm2
  mulss  %xmm4,%xmm1
  mulss  %xmm4,%xmm2
  movaps %xmm1,%xmm0
  mulss  0x18(%rsp),%xmm1
  mulss  0x1c(%rsp),%xmm0
  movss  %xmm1,(%r12)
  movss  %xmm0,0x0(%rbp)
  movss  %xmm2,(%rbx)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  movss  %xmm2,0x14(%rsp)
  movss  %xmm3,0x10(%rsp)
  call   <sqrtf@plt>
  movss  0x14(%rsp),%xmm2
  movss  0x10(%rsp),%xmm3
  movaps %xmm0,%xmm1
  jmp    L11
```

tool_calls: name: retrieve_data
arguments: tag: D27
data_type: byte[4]
name: retrieve_data
arguments: tag: D7
data_type: byte[4]
name: retrieve_data
arguments: tag: D0
data_type: byte[4]

tool: {"D27": [0xdb,0x0f,0xc9,0x40]}

tool: {"D7": [0x00,0x00,0x00,0x40]}

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void vrand(float a, float *x, float *y, float *z) {
  float v = drand(2.0f * 3.141592654f);
  float u = drand(2.0f) - 1.0f;
  float r = sqrtf(1.0f - u * u);
  *x = a * r * cosf(v);
  *y = a * r * sinf(v);
  *z = a * u;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_scrambler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void ft_scrambler(int ***a, int *b, int *******c, int ****d) {
  int i_a;
  int i_b;
  int i_c;
  int i_d;
  i_a = ***a;
  i_b = *b;
  i_c = *******c;
  i_d = ****d;
  ***a = i_b;
  *b = i_d;
  *******c = i_a;
  ****d = i_c;
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_scrambler>:
  endbr64
  mov    %rcx,%rax
  mov    (%rdi),%rcx
  mov    (%rcx),%rcx
  mov    (%rcx),%r8d
  mov    (%rsi),%r10d
  mov    (%rdx),%rdi
  mov    (%rdi),%rdi
  mov    (%rdi),%rdi
  mov    (%rdi),%rdi
  mov    (%rdi),%rdi
  mov    (%rdi),%rdi
  mov    (%rdi),%edi
  mov    (%rax),%r9
  mov    (%r9),%r9
  mov    (%r9),%r9
  mov    (%r9),%r9d
  mov    %r10d,(%rcx)
  mov    %r9d,(%rsi)
  mov    (%rdx),%rdx
  mov    (%rdx),%rdx
  mov    (%rdx),%rdx
  mov    (%rdx),%rdx
  mov    (%rdx),%rdx
  mov    (%rdx),%rdx
  mov    %r8d,(%rdx)
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    (%rax),%rax
  mov    %edi,(%rax)
  ret
```

assistant: ```c
void ft_scrambler(int ***a, int *b, int *******c, int ****d) {
  int i_a;
  int i_b;
  int i_c;
  int i_d;
  i_a = ***a;
  i_b = *b;
  i_c = *******c;
  i_d = ****d;
  ***a = i_b;
  *b = i_d;
  *******c = i_a;
  ****d = i_c;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_scrambler>:
  endbr64
  mov    (%rdx),%rdx
  mov    %rcx,%r9
  mov    (%rdi),%rcx
  mov    %rsi,%rax
  mov    (%rax),%r10d
  mov    (%rdx),%rdx
  mov    (%rcx),%rsi
  mov    (%rdx),%rdx
  mov    (%rsi),%r8d
  mov    (%rdx),%rdx
  mov    (%rdx),%rdx
  mov    (%rdx),%rcx
  mov    (%r9),%rdx
  mov    (%rdx),%rdx
  mov    (%rcx),%edi
  mov    (%rdx),%rdx
  mov    (%rdx),%r9d
  mov    %r10d,(%rsi)
  mov    %r9d,(%rax)
  mov    %r8d,(%rcx)
  mov    %edi,(%rdx)
  ret
```

assistant: ```c
void ft_scrambler(int ***a, int *b, int *******c, int ****d) {
  int i_a;
  int i_b;
  int i_c;
  int i_d;
  i_a = ***a;
  i_b = *b;
  i_c = *******c;
  i_d = ****d;
  ***a = i_b;
  *b = i_d;
  *******c = i_a;
  ****d = i_c;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<write_coordinates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L17
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4:  %d

assistant: ```c
void write_coordinates(int n, int p[n]) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", p[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_coordinates>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  test   %edi,%edi
  jle    L15
  mov    %rsi,%rbx
  lea    -0x1(%rdi),%eax
  lea    0x4(%rsi,%rax,4),%r12
  lea    D5(%rip),%rbp
L16:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L16
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string

tool: D5:  %d

assistant: ```c
void write_coordinates(int n, int p[n]) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", p[i]);
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<write_coordinates>:
  endbr64
  test   %edi,%edi
  jle    L4
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  lea    D5(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L2
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D5:  %d

assistant: ```c
void write_coordinates(int n, int p[n]) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", p[i]);
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_coordinates>:
  endbr64
  test   %edi,%edi
  jle    L1
  lea    -0x1(%rdi),%eax
  push   %r12
  lea    0x4(%rsi,%rax,4),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    %rsi,%rbx
  xchg   %ax,%ax
L9:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L9
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax,%rax,1)
L1:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4:  %d

assistant: ```c
void write_coordinates(int n, int p[n]) {
  int i;
  for (i = 0; i < n; i++)
    printf(" %d", p[i]);
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getDimension>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
L31:
  mov    $0x3,%esi
  lea    D67(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    $0x3,%esi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D64(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  jg     L47
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jle    L47
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x3,%eax
  jg     L47
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jg     L15
L47:
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L31
L15:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D67
datatype: string
name: retrieve_data
arguments: data_label: D64
datatype: string
name: retrieve_data
arguments: data_label: D35
datatype: string
name: retrieve_data
arguments: data_label: D44
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string

tool: D67: Give the number of rows for the matrix, (n <= %d) :  


tool: D64: >> 

tool: D35:  %d

tool: D44: Give the number of columns for the matrix, (n <= %d) :  


tool: D19: Invalid Input! Please try again...


assistant: ```c
void getDimension(int *prow, int *pcol) {
  for (;;) {
    printf("Give the number of rows for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", prow);
    printf("Give the number of columns for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", pcol);
    if ((*prow <= 3 && *prow > 0) && (*pcol <= 3 && *pcol > 0))
      break;
    else
      puts("Invalid Input! Please try again...\n");
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<getDimension>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r13
  lea    D7(%rip),%r15
  lea    D32(%rip),%r12
  lea    D46(%rip),%rbp
  lea    D8(%rip),%r14
  jmp    L26
L4:
  lea    D39(%rip),%rdi
  call   <puts@plt>
L26:
  mov    $0x3,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x3,%esi
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L4
  mov    0x0(%r13),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L4
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D7
type: string
name: extract_symbolic_data
arguments: data_label: D32
type: string
name: extract_symbolic_data
arguments: data_label: D46
type: string
name: extract_symbolic_data
arguments: data_label: D8
type: string
name: extract_symbolic_data
arguments: data_label: D39
type: string

tool: D7: Give the number of rows for the matrix, (n <= %d) :  


tool: D32: >> 

tool: D46:  %d

tool: D8: Give the number of columns for the matrix, (n <= %d) :  


tool: D39: Invalid Input! Please try again...


assistant: ```c
void getDimension(int *prow, int *pcol) {
  for (;;) {
    printf("Give the number of rows for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", prow);
    printf("Give the number of columns for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", pcol);
    if ((*prow <= 3 && *prow > 0) && (*pcol <= 3 && *pcol > 0))
      break;
    else
      puts("Invalid Input! Please try again...\n");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getDimension>:
  endbr64
  push   %r15
  lea    D9(%rip),%r15
  push   %r14
  lea    D22(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D4(%rip),%r12
  push   %rbp
  lea    D37(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    D12(%rip),%rdi
  call   <puts@plt>
L5:
  mov    $0x3,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x3,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L20
  mov    0x0(%r13),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D9
type_guessed: string
name: unpack_data
arguments: data_label: D22
type_guessed: string
name: unpack_data
arguments: data_label: D4
type_guessed: string
name: unpack_data
arguments: data_label: D37
type_guessed: string
name: unpack_data
arguments: data_label: D12
type_guessed: string

tool: D9: Give the number of rows for the matrix, (n <= %d) :  


tool: D22: Give the number of columns for the matrix, (n <= %d) :  


tool: D4: >> 

tool: D37:  %d

tool: D12: Invalid Input! Please try again...


assistant: ```c
void getDimension(int *prow, int *pcol) {
  for (;;) {
    printf("Give the number of rows for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", prow);
    printf("Give the number of columns for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", pcol);
    if ((*prow <= 3 && *prow > 0) && (*pcol <= 3 && *pcol > 0))
      break;
    else
      puts("Invalid Input! Please try again...\n");
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getDimension>:
  endbr64
  push   %r15
  lea    D23(%rip),%r15
  push   %r14
  lea    D3(%rip),%r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  lea    D18(%rip),%r12
  push   %rbp
  lea    D41(%rip),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L3
  cs nopw 0x0(%rax,%rax,1)
L20:
  lea    D5(%rip),%rdi
  call   <puts@plt>
L3:
  mov    $0x3,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    $0x3,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    (%rbx),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L20
  mov    0x0(%r13),%eax
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L20
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: tag: D3
type_guessed: string
name: extract_symbolic_data
arguments: tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: tag: D41
type_guessed: string
name: extract_symbolic_data
arguments: tag: D5
type_guessed: string

tool: D23: Give the number of rows for the matrix, (n <= %d) :  


tool: D3: Give the number of columns for the matrix, (n <= %d) :  


tool: D18: >> 

tool: D41:  %d

tool: D5: Invalid Input! Please try again...


assistant: ```c
void getDimension(int *prow, int *pcol) {
  for (;;) {
    printf("Give the number of rows for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", prow);
    printf("Give the number of columns for the matrix, (n <= %d) :  \n", 3);
    printf(">> ");
    scanf(" %d", pcol);
    if ((*prow <= 3 && *prow > 0) && (*pcol <= 3 && *pcol > 0))
      break;
    else
      puts("Invalid Input! Please try again...\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<idamax>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x28(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jg     L40
  mov    $0xffffffff,%eax
  jmp    L16
L40:
  cmpl   $0x1,-0x24(%rbp)
  jne    L48
  mov    $0x0,%eax
  jmp    L16
L48:
  cmpl   $0x1,-0x28(%rbp)
  je     L65
  movl   $0x1,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D42(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  add    %eax,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L46
L56:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D42(%rip),%xmm1
  andpd  %xmm1,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L54
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D42(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L54:
  mov    -0x28(%rbp),%eax
  add    %eax,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
L46:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L56
  jmp    L9
L65:
  movl   $0x0,-0xc(%rbp)
  mov    -0x30(%rbp),%rax
  movsd  (%rax),%xmm0
  movq   D42(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L24
L21:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D42(%rip),%xmm1
  andpd  %xmm1,%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L96
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movq   D42(%rip),%xmm1
  andpd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L96:
  addl   $0x1,-0x14(%rbp)
L24:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
L9:
  mov    -0xc(%rbp),%eax
L16:
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D42
type_guessed: qword

tool: D42: 9223372036854775807

assistant: ```c
int idamax(int n, double dx[], int incx) {
  double dmax;
  int i, ix, itemp;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 1;
    dmax = fabs((double)dx[0]);
    ix = ix + incx;
    for (i = 1; i < n; i++) {
      if (fabs((double)dx[ix]) > dmax) {
        itemp = i;
        dmax = fabs((double)dx[ix]);
      }
      ix = ix + incx;
    }
  } else {
    itemp = 0;
    dmax = fabs((double)dx[0]);
    for (i = 1; i < n; i++) {
      if (fabs((double)dx[i]) > dmax) {
        itemp = i;
        dmax = fabs((double)dx[i]);
      }
    }
  }
  return (itemp);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<idamax>:
  endbr64
  test   %edi,%edi
  jle    L22
  mov    $0x0,%ecx
  cmp    $0x1,%edi
  je     L17
  cmp    $0x1,%edx
  je     L12
  movsd  (%rsi),%xmm1
  andpd  D11(%rip),%xmm1
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%r8
  lea    0x8(%rsi,%r8,1),%rdx
  mov    $0x1,%eax
  movq   D11(%rip),%xmm2
L7:
  movsd  (%rdx),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  cmova  %eax,%ecx
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  add    $0x1,%eax
  add    %r8,%rdx
  cmp    %eax,%edi
  jg     L7
L17:
  mov    %ecx,%eax
  ret
L12:
  movsd  (%rsi),%xmm1
  andpd  D11(%rip),%xmm1
  mov    $0x1,%eax
  mov    $0x0,%ecx
  movq   D11(%rip),%xmm2
L54:
  movsd  (%rsi,%rax,8),%xmm0
  andpd  %xmm2,%xmm0
  comisd %xmm1,%xmm0
  cmova  %eax,%ecx
  maxsd  %xmm1,%xmm0
  movapd %xmm0,%xmm1
  add    $0x1,%rax
  cmp    %eax,%edi
  jg     L54
  jmp    L17
L22:
  mov    $0xffffffff,%ecx
  jmp    L17
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D11
type_infered: qword[2]

tool: {"D11": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
int idamax(int n, double dx[], int incx) {
  double dmax;
  int i, ix, itemp;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 1;
    dmax = fabs((double)dx[0]);
    ix = ix + incx;
    for (i = 1; i < n; i++) {
      if (fabs((double)dx[ix]) > dmax) {
        itemp = i;
        dmax = fabs((double)dx[ix]);
      }
      ix = ix + incx;
    }
  } else {
    itemp = 0;
    dmax = fabs((double)dx[0]);
    for (i = 1; i < n; i++) {
      if (fabs((double)dx[i]) > dmax) {
        itemp = i;
        dmax = fabs((double)dx[i]);
      }
    }
  }
  return (itemp);
}
```
user: What is the c source code of the assembly code below?

```asm
<idamax>:
  endbr64
  test   %edi,%edi
  jle    L3
  xor    %r8d,%r8d
  cmp    $0x1,%edi
  je     L50
  movsd  (%rsi),%xmm0
  movq   D1(%rip),%xmm2
  andpd  %xmm2,%xmm0
  cmp    $0x1,%edx
  je     L33
  movslq %edx,%rdx
  mov    $0x1,%eax
  lea    0x0(,%rdx,8),%rcx
  lea    0x8(%rsi,%rcx,1),%rdx
  xchg   %ax,%ax
L10:
  movsd  (%rdx),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%eax
  movapd %xmm1,%xmm0
  add    %rcx,%rdx
  cmp    %eax,%edi
  jg     L10
L50:
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    $0x1,%eax
  nopl   (%rax)
L17:
  movsd  (%rsi,%rax,8),%xmm1
  andpd  %xmm2,%xmm1
  comisd %xmm0,%xmm1
  maxsd  %xmm0,%xmm1
  cmova  %eax,%r8d
  add    $0x1,%rax
  movapd %xmm1,%xmm0
  cmp    %eax,%edi
  jg     L17
  mov    %r8d,%eax
  ret
L3:
  mov    $0xffffffff,%r8d
  jmp    L50
```

tool_calls: name: parse_data
arguments: label: D1
type_infered: qword

tool: D1: 9223372036854775807

assistant: ```c
int idamax(int n, double dx[], int incx) {
  double dmax;
  int i, ix, itemp;
  if (n < 1)
    return (-1);
  if (n == 1)
    return (0);
  if (incx != 1) {
    ix = 1;
    dmax = fabs((double)dx[0]);
    ix = ix + incx;
    for (i = 1; i < n; i++) {
      if (fabs((double)dx[ix]) > dmax) {
        itemp = i;
        dmax = fabs((double)dx[ix]);
      }
      ix = ix + incx;
    }
  } else {
    itemp = 0;
    dmax = fabs((double)dx[0]);
    for (i = 1; i < n; i++) {
      if (fabs((double)dx[i]) > dmax) {
        itemp = i;
        dmax = fabs((double)dx[i]);
      }
    }
  }
  return (itemp);
}
```