ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<lefttrim>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  mov    %rdi,%rcx
  xor    %r9d,%r9d
L9:
  movzbl (%rcx),%edx
  cmp    %sil,%dl
  jne    L7
  mov    %r9d,%r10d
  xor    %r9d,%r9d
  and    $0x1,%r10d
  test   %r10b,%r10b
  je     L0
L7:
  mov    %dl,(%r8)
  mov    $0x1,%r9d
  add    $0x1,%r8
L0:
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L9
  ret
```

assistant: ```c
char *lefttrim(char *string, char junk) {
  char *original = string;
  char *p = original;
  int trimmed = 0;
  do {
    if (*original != junk || trimmed) {
      trimmed = 1;
      *p++ = *original;
    }
  } while (*original++ != '\0');
  return string;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<lefttrim>:
  endbr64
  mov    %rdi,%rax
  mov    %rdi,%r8
  mov    %rdi,%rcx
  xor    %r10d,%r10d
  jmp    L9
  nopw   0x0(%rax,%rax,1)
L34:
  mov    %dl,(%r8)
  lea    0x1(%r8),%r9
  add    $0x1,%rcx
  test   %dl,%dl
  je     L46
  mov    $0x1,%r10d
L22:
  mov    %r9,%r8
L9:
  movzbl (%rcx),%edx
  cmp    %sil,%dl
  jne    L34
  test   %r10d,%r10d
  jne    L34
  add    $0x1,%rcx
  test   %dl,%dl
  je     L10
  mov    %r8,%r9
  xor    %r10d,%r10d
  jmp    L22
  nopl   (%rax)
L10:
  ret
  nopl   0x0(%rax)
L46:
  ret
```

assistant: ```c
char *lefttrim(char *string, char junk) {
  char *original = string;
  char *p = original;
  int trimmed = 0;
  do {
    if (*original != junk || trimmed) {
      trimmed = 1;
      *p++ = *original;
    }
  } while (*original++ != '\0');
  return string;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<test_memory_move_read_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x32100000,-0x30(%rbp)
  movl   $0xba987654,-0x2c(%rbp)
  mov    $0x3,%esi
  mov    $0x14,%edi
  call   <calculat_group_numbers@plt>
  mov    %eax,-0x38(%rbp)
  movl   $0x1,-0x34(%rbp)
  mov    -0x34(%rbp),%esi
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%edx
  lea    -0x30(%rbp),%rax
  mov    %esi,%r9d
  mov    %rcx,%r8
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x3,%esi
  mov    $0x14,%edi
  call   <memory_move_read@plt>
  mov    -0x20(%rbp),%eax
  cmp    $0x1,%eax
  jne    L9
  mov    $0x0,%eax
  jmp    L23
L9:
  mov    $0xffffffff,%eax
L23:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

assistant: ```c
int test_memory_move_read_1(void) {
  int buf_test1[4];
  int buf_test2[4];
  int group_read_from;
  int group_read_to;
  int group_write_from;
  int group_write_to;
  buf_test1[0] = 0x32100000;
  buf_test1[1] = 0xba987654;
  group_read_from = calculat_group_numbers(20, 3);
  group_read_to = (((3) + 31) / 32);
  memory_move_read(20, 3, buf_test1, group_read_from, buf_test2, group_read_to);
  if (buf_test2[0] == 1) {
    return 0;
  } else {
    return -1;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_memory_move_read_1>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x32100000,(%rsp)
  movl   $0xba987654,0x4(%rsp)
  mov    $0x3,%esi
  mov    $0x14,%edi
  call   <calculat_group_numbers@plt>
  mov    %eax,%ecx
  mov    %rsp,%rdx
  mov    $0x1,%r9d
  lea    0x10(%rsp),%r8
  mov    $0x3,%esi
  mov    $0x14,%edi
  call   <memory_move_read@plt>
  cmpl   $0x1,0x10(%rsp)
  setne  %al
  movzbl %al,%eax
  neg    %eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x38,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_memory_move_read_1(void) {
  int buf_test1[4];
  int buf_test2[4];
  int group_read_from;
  int group_read_to;
  int group_write_from;
  int group_write_to;
  buf_test1[0] = 0x32100000;
  buf_test1[1] = 0xba987654;
  group_read_from = calculat_group_numbers(20, 3);
  group_read_to = (((3) + 31) / 32);
  memory_move_read(20, 3, buf_test1, group_read_from, buf_test2, group_read_to);
  if (buf_test2[0] == 1) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<test_memory_move_read_1>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x3,%esi
  mov    $0x14,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0xba98765432100000,%rax
  mov    %rax,(%rsp)
  call   <calculat_group_numbers@plt>
  mov    %rsp,%rdx
  mov    $0x1,%r9d
  lea    0x10(%rsp),%r8
  mov    %eax,%ecx
  mov    $0x3,%esi
  mov    $0x14,%edi
  call   <memory_move_read@plt>
  xor    %eax,%eax
  cmpl   $0x1,0x10(%rsp)
  setne  %al
  neg    %eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int test_memory_move_read_1(void) {
  int buf_test1[4];
  int buf_test2[4];
  int group_read_from;
  int group_read_to;
  int group_write_from;
  int group_write_to;
  buf_test1[0] = 0x32100000;
  buf_test1[1] = 0xba987654;
  group_read_from = calculat_group_numbers(20, 3);
  group_read_to = (((3) + 31) / 32);
  memory_move_read(20, 3, buf_test1, group_read_from, buf_test2, group_read_to);
  if (buf_test2[0] == 1) {
    return 0;
  } else {
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_memory_move_read_1>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x3,%esi
  mov    $0x14,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D6(%rip),%rax
  mov    %rax,(%rsp)
  call   <calculat_group_numbers@plt>
  mov    %rsp,%rdx
  mov    $0x1,%r9d
  lea    0x10(%rsp),%r8
  mov    %eax,%ecx
  mov    $0x3,%esi
  mov    $0x14,%edi
  call   <memory_move_read@plt>
  xor    %eax,%eax
  cmpl   $0x1,0x10(%rsp)
  setne  %al
  neg    %eax
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: byte[8]

tool: {"D6": [0x00,0x00,0x10,0x32,0x54,0x76,0x98,0xba]}

assistant: ```c
int test_memory_move_read_1(void) {
  int buf_test1[4];
  int buf_test2[4];
  int group_read_from;
  int group_read_to;
  int group_write_from;
  int group_write_to;
  buf_test1[0] = 0x32100000;
  buf_test1[1] = 0xba987654;
  group_read_from = calculat_group_numbers(20, 3);
  group_read_to = (((3) + 31) / 32);
  memory_move_read(20, 3, buf_test1, group_read_from, buf_test2, group_read_to);
  if (buf_test2[0] == 1) {
    return 0;
  } else {
    return -1;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rbx
  movl   $0x0,-0x5c(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x60(%rbp),%eax
  add    $0x1,%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L10:
  cmp    %rdx,%rsp
  je     L48
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L10
L48:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L78
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L78:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x0,-0x58(%rbp)
  jmp    L38
L8:
  mov    -0x58(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x58(%rbp)
L38:
  mov    -0x60(%rbp),%eax
  cmp    %eax,-0x58(%rbp)
  jle    L8
  mov    -0x60(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  sub    $0x1,%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x60(%rbp),%edx
  mov    -0x40(%rbp),%rax
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4c(%rbp)
  mov    -0x50(%rbp),%eax
  mov    %eax,-0x54(%rbp)
  jmp    L73
L47:
  mov    -0x40(%rbp),%rax
  mov    -0x54(%rbp),%edx
  movslq %edx,%rdx
  mov    (%rax,%rdx,4),%eax
  add    %eax,-0x5c(%rbp)
  addl   $0x1,-0x54(%rbp)
L73:
  mov    -0x54(%rbp),%eax
  cmp    -0x4c(%rbp),%eax
  jl     L47
  mov    -0x5c(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  mov    $0x0,%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D17
datatype: string

tool: D17: %d

assistant: ```c
int main() {
  int n, x, y, c = 0;
  scanf("%d", &n);
  int a[n + 1];
  for (int i = 0; i < n + 1; ++i)
    scanf("%d", &a[i]);
  x = a[n - 1] - 1;
  y = a[n] - 1;
  for (int i = x; i < y; ++i)
    c += a[i];
  printf("%d", c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    -0x2c(%rbp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    -0x2c(%rbp),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rdx
  mov    %rsp,%rcx
  sub    %rdx,%rcx
L86:
  cmp    %rcx,%rsp
  je     L17
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L86
L17:
  mov    %rsi,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L4
  orq    $0x0,-0x8(%rsp,%rdx,1)
L4:
  mov    %rsp,%r13
  test   %eax,%eax
  js     L88
  mov    %r13,%r12
  mov    $0x0,%ebx
  lea    D12(%rip),%r14
L68:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    -0x2c(%rbp),%eax
  add    $0x4,%r12
  cmp    %ebx,%eax
  jge    L68
L88:
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,4),%ecx
  cltq
  mov    0x0(%r13,%rax,4),%edx
  cmp    %edx,%ecx
  jge    L8
  movslq %ecx,%rsi
  lea    -0x4(%r13,%rsi,4),%rax
  sub    $0x1,%edx
  sub    %ecx,%edx
  add    %rsi,%rdx
  lea    0x0(%r13,%rdx,4),%rdx
  mov    $0x0,%esi
L37:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L37
L52:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L78
  mov    $0x0,%eax
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L8:
  mov    $0x0,%esi
  jmp    L52
L78:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
data_type: string

tool: D12: %d

assistant: ```c
int main() {
  int n, x, y, c = 0;
  scanf("%d", &n);
  int a[n + 1];
  for (int i = 0; i < n + 1; ++i)
    scanf("%d", &a[i]);
  x = a[n - 1] - 1;
  y = a[n] - 1;
  for (int i = x; i < y; ++i)
    c += a[i];
  printf("%d", c);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D1(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L58
L77:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L77
L58:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L95
L53:
  mov    %rsp,%r13
  test   %eax,%eax
  js     L69
  mov    %r13,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L73:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  cmp    %ebx,%eax
  jge    L73
L69:
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  mov    0x0(%r13,%rdx,4),%ecx
  mov    0x0(%r13,%rax,4),%edx
  cmp    %edx,%ecx
  jge    L89
  sub    $0x1,%edx
  movslq %ecx,%rsi
  sub    %ecx,%edx
  lea    -0x4(%r13,%rsi,4),%rax
  add    %rsi,%rdx
  xor    %esi,%esi
  lea    0x0(%r13,%rdx,4),%rdx
  nopl   (%rax)
L66:
  add    (%rax),%esi
  add    $0x4,%rax
  cmp    %rdx,%rax
  jne    L66
L97:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L95:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L53
L89:
  xor    %esi,%esi
  jmp    L97
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type: string

tool: D1: %d

assistant: ```c
int main() {
  int n, x, y, c = 0;
  scanf("%d", &n);
  int a[n + 1];
  for (int i = 0; i < n + 1; ++i)
    scanf("%d", &a[i]);
  x = a[n - 1] - 1;
  y = a[n] - 1;
  for (int i = x; i < y; ++i)
    c += a[i];
  printf("%d", c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  lea    D8(%rip),%r14
  push   %r13
  lea    -0x2c(%rbp),%rsi
  mov    %r14,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  mov    %rsp,%rsi
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0xf(,%rdx,4),%rdx
  mov    %rdx,%rcx
  and    $0xfffffffffffff000,%rdx
  sub    %rdx,%rsi
  and    $0xfffffffffffffff0,%rcx
  cmp    %rsi,%rsp
  je     L57
L8:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rsi,%rsp
  jne    L8
L57:
  and    $0xfff,%ecx
  sub    %rcx,%rsp
  test   %rcx,%rcx
  jne    L75
L69:
  mov    %rsp,%r13
  test   %eax,%eax
  js     L7
  mov    %r13,%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L102:
  mov    %r12,%rsi
  mov    %r14,%rdi
  add    $0x1,%ebx
  add    $0x4,%r12
  call   <scanf@plt>
  movslq -0x2c(%rbp),%rax
  cmp    %ebx,%eax
  jge    L102
L7:
  lea    -0x1(%rax),%edx
  mov    0x0(%r13,%rax,4),%edi
  movslq %edx,%rdx
  movslq 0x0(%r13,%rdx,4),%rdx
  lea    -0x1(%rdi),%r9d
  lea    -0x1(%rdx),%r8d
  cmp    %edi,%edx
  jge    L37
  sub    %edx,%edi
  lea    -0x1(%rdi),%eax
  cmp    $0x2,%eax
  jbe    L156
  mov    %edi,%eax
  lea    -0x4(%r13,%rdx,4),%rdx
  pxor   %xmm0,%xmm0
  shr    $0x2,%eax
  lea    -0x1(%rax),%ecx
  lea    0x10(%rdx),%rax
  shl    $0x4,%rcx
  add    %rax,%rcx
  jmp    L15
  xchg   %ax,%ax
L150:
  add    $0x10,%rax
L15:
  movdqu (%rdx),%xmm1
  mov    %rax,%rdx
  paddd  %xmm1,%xmm0
  cmp    %rcx,%rax
  jne    L150
  movdqa %xmm0,%xmm1
  mov    %edi,%eax
  psrldq $0x8,%xmm1
  and    $0xfffffffc,%eax
  paddd  %xmm1,%xmm0
  add    %eax,%r8d
  movdqa %xmm0,%xmm1
  psrldq $0x4,%xmm1
  paddd  %xmm1,%xmm0
  movd   %xmm0,%esi
  cmp    %eax,%edi
  je     L153
L63:
  movslq %r8d,%rax
  lea    0x1(%r8),%edx
  lea    0x0(%r13,%rax,4),%rax
  add    (%rax),%esi
  cmp    %edx,%r9d
  jle    L153
  add    $0x2,%r8d
  add    0x4(%rax),%esi
  cmp    %r8d,%r9d
  jle    L153
  add    0x8(%rax),%esi
L153:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L120
  lea    -0x20(%rbp),%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
L75:
  orq    $0x0,-0x8(%rsp,%rcx,1)
  jmp    L69
L37:
  xor    %esi,%esi
  jmp    L153
L156:
  xor    %esi,%esi
  jmp    L63
L120:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type_infered: string

tool: D8: %d

assistant: ```c
int main() {
  int n, x, y, c = 0;
  scanf("%d", &n);
  int a[n + 1];
  for (int i = 0; i < n + 1; ++i)
    scanf("%d", &a[i]);
  x = a[n - 1] - 1;
  y = a[n] - 1;
  for (int i = x; i < y; ++i)
    c += a[i];
  printf("%d", c);
}
```
user: What is the c source code of the assembly code below?

```asm
<bitmap_set>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  lea    0x1f(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x5,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  mov    $0x20,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x2c(%rbp),%eax
  and    $0x1f,%eax
  mov    $0xffffffffffffffff,%rdx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L39
L28:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  or     -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%eax
  sub    %eax,-0x30(%rbp)
  movl   $0x20,-0x18(%rbp)
  movq   $0xffffffffffffffff,-0x8(%rbp)
  addq   $0x8,-0x10(%rbp)
L39:
  mov    -0x30(%rbp),%eax
  sub    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L28
  cmpl   $0x0,-0x30(%rbp)
  je     L30
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  test   %eax,%eax
  je     L4
  mov    -0x14(%rbp),%eax
  and    $0x1f,%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  sub    $0x1,%rax
  jmp    L25
L4:
  mov    $0xffffffffffffffff,%rax
L25:
  and    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  or     -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
L30:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bitmap_set(unsigned long *map, int start, int nr) {
  unsigned long *p = map + ((start) / 32);
  const int size = start + nr;
  int bits_to_set = 32 - (start % 32);
  unsigned long mask_to_set = (~0ul << ((start) % 32));
  while (nr - bits_to_set >= 0) {
    *p |= mask_to_set;
    nr -= bits_to_set;
    bits_to_set = 32;
    mask_to_set = ~0UL;
    p++;
  }
  if (nr) {
    mask_to_set &= (((size) % 32) ? (1ul << ((size) % 32)) - 1 : ~0ul);
    *p |= mask_to_set;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_set>:
  endbr64
  mov    %edx,%r9d
  lea    0x1f(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x5,%eax
  cltq
  lea    (%rdi,%rax,8),%rax
  mov    %esi,%ecx
  and    $0x1f,%ecx
  mov    $0xffffffffffffffff,%rdx
  shl    %cl,%rdx
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  shr    $0x1b,%ecx
  lea    (%rsi,%rcx,1),%edi
  and    $0x1f,%edi
  mov    %r9d,%r8d
  sub    %ecx,%r8d
  lea    -0x20(%r8,%rdi,1),%r8d
  test   %r8d,%r8d
  js     L25
  mov    %r8d,%r10d
  shr    $0x5,%r10d
  lea    0x1(%r10),%ecx
  mov    %ecx,%ecx
  lea    (%rax,%rcx,8),%rdi
  mov    $0xffffffffffffffff,%rcx
L12:
  or     %rdx,(%rax)
  add    $0x8,%rax
  mov    %rcx,%rdx
  cmp    %rdi,%rax
  jne    L12
  shl    $0x5,%r10d
  sub    %r10d,%r8d
  mov    $0xffffffffffffffff,%rdx
L32:
  test   %r8d,%r8d
  je     L39
  lea    (%rsi,%r9,1),%ecx
  mov    $0xffffffffffffffff,%rax
  test   $0x1f,%cl
  je     L14
  and    $0x1f,%ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  sub    $0x1,%rax
L14:
  and    %rdx,%rax
  or     %rax,(%rdi)
L39:
  ret
L25:
  mov    %rax,%rdi
  mov    %r9d,%r8d
  jmp    L32
```

assistant: ```c
void bitmap_set(unsigned long *map, int start, int nr) {
  unsigned long *p = map + ((start) / 32);
  const int size = start + nr;
  int bits_to_set = 32 - (start % 32);
  unsigned long mask_to_set = (~0ul << ((start) % 32));
  while (nr - bits_to_set >= 0) {
    *p |= mask_to_set;
    nr -= bits_to_set;
    bits_to_set = 32;
    mask_to_set = ~0UL;
    p++;
  }
  if (nr) {
    mask_to_set &= (((size) % 32) ? (1ul << ((size) % 32)) - 1 : ~0ul);
    *p |= mask_to_set;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bitmap_set>:
  endbr64
  test   %esi,%esi
  lea    0x1f(%rsi),%eax
  mov    %esi,%ecx
  mov    %edx,%r8d
  cmovns %esi,%eax
  mov    $0xffffffffffffffff,%rdx
  and    $0x1f,%ecx
  mov    %r8d,%r9d
  shl    %cl,%rdx
  mov    %esi,%ecx
  sar    $0x5,%eax
  sar    $0x1f,%ecx
  shr    $0x1b,%ecx
  cltq
  lea    (%rdi,%rax,8),%rax
  lea    (%rsi,%rcx,1),%edi
  sub    %ecx,%r9d
  and    $0x1f,%edi
  lea    -0x20(%r9,%rdi,1),%ecx
  test   %ecx,%ecx
  js     L19
  mov    %ecx,%r9d
  shr    $0x5,%r9d
  lea    0x1(%r9),%edi
  lea    (%rax,%rdi,8),%rdi
  nopl   0x0(%rax,%rax,1)
L3:
  or     %rdx,(%rax)
  add    $0x8,%rax
  mov    $0xffffffffffffffff,%rdx
  cmp    %rdi,%rax
  jne    L3
  shl    $0x5,%r9d
  sub    %r9d,%ecx
L41:
  test   %ecx,%ecx
  je     L10
  lea    (%rsi,%r8,1),%ecx
  and    $0x1f,%ecx
  je     L38
  mov    $0xffffffffffffffff,%rax
  shl    %cl,%rax
  not    %rax
  and    %rax,%rdx
L38:
  or     %rdx,(%rdi)
L10:
  ret
  nopl   0x0(%rax,%rax,1)
L19:
  mov    %rax,%rdi
  mov    %r8d,%ecx
  jmp    L41
```

assistant: ```c
void bitmap_set(unsigned long *map, int start, int nr) {
  unsigned long *p = map + ((start) / 32);
  const int size = start + nr;
  int bits_to_set = 32 - (start % 32);
  unsigned long mask_to_set = (~0ul << ((start) % 32));
  while (nr - bits_to_set >= 0) {
    *p |= mask_to_set;
    nr -= bits_to_set;
    bits_to_set = 32;
    mask_to_set = ~0UL;
    p++;
  }
  if (nr) {
    mask_to_set &= (((size) % 32) ? (1ul << ((size) % 32)) - 1 : ~0ul);
    *p |= mask_to_set;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bitmap_set>:
  endbr64
  test   %esi,%esi
  lea    0x1f(%rsi),%eax
  mov    %esi,%ecx
  mov    %edx,%r8d
  cmovns %esi,%eax
  mov    $0xffffffffffffffff,%rdx
  and    $0x1f,%ecx
  mov    %r8d,%r9d
  shl    %cl,%rdx
  mov    %esi,%ecx
  sar    $0x5,%eax
  sar    $0x1f,%ecx
  shr    $0x1b,%ecx
  cltq
  lea    (%rdi,%rax,8),%rax
  lea    (%rsi,%rcx,1),%edi
  sub    %ecx,%r9d
  and    $0x1f,%edi
  lea    -0x20(%r9,%rdi,1),%ecx
  test   %ecx,%ecx
  js     L3
  mov    %ecx,%r9d
  shr    $0x5,%r9d
  lea    0x1(%r9),%edi
  lea    (%rax,%rdi,8),%rdi
  nopl   0x0(%rax,%rax,1)
L28:
  or     %rdx,(%rax)
  add    $0x8,%rax
  mov    $0xffffffffffffffff,%rdx
  cmp    %rdi,%rax
  jne    L28
  shl    $0x5,%r9d
  sub    %r9d,%ecx
L49:
  test   %ecx,%ecx
  je     L17
  lea    (%rsi,%r8,1),%ecx
  and    $0x1f,%ecx
  je     L11
  mov    $0xffffffffffffffff,%rax
  shl    %cl,%rax
  not    %rax
  and    %rax,%rdx
L11:
  or     %rdx,(%rdi)
L17:
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rax,%rdi
  mov    %r8d,%ecx
  jmp    L49
```

assistant: ```c
void bitmap_set(unsigned long *map, int start, int nr) {
  unsigned long *p = map + ((start) / 32);
  const int size = start + nr;
  int bits_to_set = 32 - (start % 32);
  unsigned long mask_to_set = (~0ul << ((start) % 32));
  while (nr - bits_to_set >= 0) {
    *p |= mask_to_set;
    nr -= bits_to_set;
    bits_to_set = 32;
    mask_to_set = ~0UL;
    p++;
  }
  if (nr) {
    mask_to_set &= (((size) % 32) ? (1ul << ((size) % 32)) - 1 : ~0ul);
    *p |= mask_to_set;
  }
}
```