ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<FruTypeString>:
  endbr64
  sub    $0x7,%edi
  cmp    $0x39,%dil
  ja     L6
  movzbl %dil,%edi
  lea    D29(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D12(%rip),%rax
  ret
  test   %sil,%sil
  lea    D15(%rip),%rax
  lea    D32(%rip),%rdx
  cmovne %rdx,%rax
  ret
  lea    D99(%rip),%rax
  ret
  lea    D69(%rip),%rax
  ret
  lea    D0(%rip),%rax
  ret
  lea    D21(%rip),%rax
  ret
L6:
  lea    D26(%rip),%rax
  ret
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
datatype: string
name: disassemble_data
arguments: data_tag: D15
datatype: string
name: disassemble_data
arguments: data_tag: D32
datatype: string
name: disassemble_data
arguments: data_tag: D99
datatype: string
name: disassemble_data
arguments: data_tag: D69
datatype: string
name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D21
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D4
datatype: string

tool: D12: PowerCage

tool: D15: Baseboard

tool: D32: Board    

tool: D99: DIMM     

tool: D69: HotSwapCt

tool: D0: ME       

tool: D21: SysInfo  

tool: D26: Component

tool: D4: PowerSply

assistant: ```c
char *FruTypeString(unsigned char frutype, unsigned char dev) {
  char *pstr;
  switch (frutype) {
  case 0x07:
  case 0x0c:
    if (dev == 0)
      pstr = "Baseboard";
    else
      pstr = "Board    ";
    break;
  case 0x0a:
    pstr = "PowerSply";
    break;
  case 0x15:
    pstr = "PowerCage";
    break;
  case 0x20:
    pstr = "DIMM     ";
    break;
  case 0x0f:
    pstr = "HotSwapCt";
    break;
  case 0x2e:
    pstr = "ME       ";
    break;
  case 0x40:
    pstr = "SysInfo  ";
    break;
  default:
    pstr = "Component";
    break;
  }
  return (pstr);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<FruTypeString>:
  endbr64
  sub    $0x7,%edi
  cmp    $0x39,%dil
  ja     L6
  lea    D92(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L6:
  lea    D21(%rip),%rax
  ret
  test   %sil,%sil
  lea    D18(%rip),%rdx
  lea    D74(%rip),%rax
  cmovne %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
  lea    D87(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D23(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D81(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D56(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D36(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D39(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D21
datatype: string
name: unpack_data
arguments: data_tag: D18
datatype: string
name: unpack_data
arguments: data_tag: D74
datatype: string
name: unpack_data
arguments: data_tag: D87
datatype: string
name: unpack_data
arguments: data_tag: D23
datatype: string
name: unpack_data
arguments: data_tag: D81
datatype: string
name: unpack_data
arguments: data_tag: D56
datatype: string
name: unpack_data
arguments: data_tag: D36
datatype: string
name: unpack_data
arguments: data_tag: D39
datatype: string

tool: D21: Component

tool: D18: Board    

tool: D74: Baseboard

tool: D87: HotSwapCt

tool: D23: ME       

tool: D81: SysInfo  

tool: D56: DIMM     

tool: D36: PowerSply

tool: D39: PowerCage

assistant: ```c
char *FruTypeString(unsigned char frutype, unsigned char dev) {
  char *pstr;
  switch (frutype) {
  case 0x07:
  case 0x0c:
    if (dev == 0)
      pstr = "Baseboard";
    else
      pstr = "Board    ";
    break;
  case 0x0a:
    pstr = "PowerSply";
    break;
  case 0x15:
    pstr = "PowerCage";
    break;
  case 0x20:
    pstr = "DIMM     ";
    break;
  case 0x0f:
    pstr = "HotSwapCt";
    break;
  case 0x2e:
    pstr = "ME       ";
    break;
  case 0x40:
    pstr = "SysInfo  ";
    break;
  default:
    pstr = "Component";
    break;
  }
  return (pstr);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<FruTypeString>:
  endbr64
  sub    $0x7,%edi
  cmp    $0x39,%dil
  ja     L1
  lea    D47(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
L1:
  lea    D36(%rip),%rax
  ret
  test   %sil,%sil
  lea    D48(%rip),%rdx
  lea    D20(%rip),%rax
  cmovne %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
  lea    D19(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D13(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D64(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D5(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D74(%rip),%rax
  ret
  nopl   0x0(%rax,%rax,1)
  lea    D4(%rip),%rax
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D36
type_infered: string
name: retrieve_data
arguments: tag: D48
type_infered: string
name: retrieve_data
arguments: tag: D20
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D64
type_infered: string
name: retrieve_data
arguments: tag: D5
type_infered: string
name: retrieve_data
arguments: tag: D74
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D36: Component

tool: D48: Board    

tool: D20: Baseboard

tool: D19: HotSwapCt

tool: D13: ME       

tool: D64: SysInfo  

tool: D5: DIMM     

tool: D74: PowerSply

tool: D4: PowerCage

assistant: ```c
char *FruTypeString(unsigned char frutype, unsigned char dev) {
  char *pstr;
  switch (frutype) {
  case 0x07:
  case 0x0c:
    if (dev == 0)
      pstr = "Baseboard";
    else
      pstr = "Board    ";
    break;
  case 0x0a:
    pstr = "PowerSply";
    break;
  case 0x15:
    pstr = "PowerCage";
    break;
  case 0x20:
    pstr = "DIMM     ";
    break;
  case 0x0f:
    pstr = "HotSwapCt";
    break;
  case 0x2e:
    pstr = "ME       ";
    break;
  case 0x40:
    pstr = "SysInfo  ";
    break;
  default:
    pstr = "Component";
    break;
  }
  return (pstr);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <fn_b@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_infered: string

tool: D9: main() called


assistant: ```c
int main() {
  printf("main() called\n");
  fn_b();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <fn_b@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: main() called


assistant: ```c
int main() {
  printf("main() called\n");
  fn_b();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <fn_b@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
datatype: string

tool: D9: main() called


assistant: ```c
int main() {
  printf("main() called\n");
  fn_b();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <fn_b@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: string

tool: D2: main() called


assistant: ```c
int main() {
  printf("main() called\n");
  fn_b();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  cmpb   $0x0,-0x9(%rbp)
  jne    L48
  mov    $0x30,%eax
  jmp    L70
L48:
  cmpb   $0x28,-0x9(%rbp)
  jne    L46
  addl   $0x1,-0x8(%rbp)
L46:
  cmpb   $0x29,-0x9(%rbp)
  jne    L69
  subl   $0x1,-0x8(%rbp)
L69:
  movsbl -0x9(%rbp),%eax
  mov    %eax,%edi
  call   <bc@plt>
  cmp    $0x1,%eax
  jne    L56
  cmpl   $0x1,-0x8(%rbp)
  jne    L56
  movzbl -0x9(%rbp),%eax
  jmp    L70
L56:
  addl   $0x1,-0x4(%rbp)
  jmp    L9
L70:
  leave
  ret
```

assistant: ```c
char bin(char *g) {
  int brackets = 0, i = 0;
  while (1) {
    char c = g[i];
    if (c == '\0') {
      return '0';
    }
    if (c == '(') {
      brackets += 1;
    }
    if (c == ')') {
      brackets -= 1;
    }
    if (bc(c) == 1 && brackets == 1) {
      return c;
    }
    i++;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%ebx
  test   %bl,%bl
  je     L56
  lea    0x1(%rdi),%rbp
  mov    $0x0,%r12d
  jmp    L44
L39:
  add    $0x1,%r12d
  jmp    L31
L28:
  add    $0x1,%rbp
  movzbl -0x1(%rbp),%ebx
  test   %bl,%bl
  je     L37
L44:
  cmp    $0x28,%bl
  je     L39
  cmp    $0x29,%bl
  sete   %al
  movzbl %al,%eax
  sub    %eax,%r12d
L31:
  movsbl %bl,%edi
  call   <bc@plt>
  cmp    $0x1,%r12d
  jne    L28
  cmp    $0x1,%eax
  jne    L28
  jmp    L18
L37:
  mov    $0x30,%ebx
L18:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L56:
  mov    $0x30,%ebx
  jmp    L18
```

assistant: ```c
char bin(char *g) {
  int brackets = 0, i = 0;
  while (1) {
    char c = g[i];
    if (c == '\0') {
      return '0';
    }
    if (c == '(') {
      brackets += 1;
    }
    if (c == ')') {
      brackets -= 1;
    }
    if (bc(c) == 1 && brackets == 1) {
      return c;
    }
    i++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%r12d
  test   %r12b,%r12b
  je     L33
  lea    0x1(%rdi),%rbx
  xor    %ebp,%ebp
  jmp    L41
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
  cmp    $0x29,%r12b
  sete   %al
  sub    %eax,%ebp
L49:
  movsbl %r12b,%edi
  call   <bc@plt>
  cmp    $0x1,%eax
  jne    L56
  cmp    $0x1,%ebp
  je     L15
L56:
  movzbl (%rbx),%r12d
  add    $0x1,%rbx
  test   %r12b,%r12b
  je     L33
L41:
  cmp    $0x28,%r12b
  jne    L40
  add    $0x1,%ebp
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L33:
  mov    $0x30,%r12d
L15:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char bin(char *g) {
  int brackets = 0, i = 0;
  while (1) {
    char c = g[i];
    if (c == '\0') {
      return '0';
    }
    if (c == '(') {
      brackets += 1;
    }
    if (c == ')') {
      brackets -= 1;
    }
    if (bc(c) == 1 && brackets == 1) {
      return c;
    }
    i++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<bin>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rdi),%r12d
  test   %r12b,%r12b
  je     L5
  lea    0x1(%rdi),%rbx
  xor    %ebp,%ebp
  jmp    L2
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  cmp    $0x29,%r12b
  sete   %al
  sub    %eax,%ebp
L39:
  movsbl %r12b,%edi
  call   <bc@plt>
  cmp    $0x1,%eax
  jne    L45
  cmp    $0x1,%ebp
  je     L23
L45:
  movzbl (%rbx),%r12d
  add    $0x1,%rbx
  test   %r12b,%r12b
  je     L5
L2:
  cmp    $0x28,%r12b
  jne    L15
  add    $0x1,%ebp
  jmp    L39
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x30,%r12d
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char bin(char *g) {
  int brackets = 0, i = 0;
  while (1) {
    char c = g[i];
    if (c == '\0') {
      return '0';
    }
    if (c == '(') {
      brackets += 1;
    }
    if (c == ')') {
      brackets -= 1;
    }
    if (bc(c) == 1 && brackets == 1) {
      return c;
    }
    i++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test_intlist2str@plt>
  mov    $0x0,%eax
  call   <test_dbllist2str@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_intlist2str();
  test_dbllist2str();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_intlist2str@plt>
  mov    $0x0,%eax
  call   <test_dbllist2str@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_intlist2str();
  test_dbllist2str();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_intlist2str@plt>
  xor    %eax,%eax
  call   <test_dbllist2str@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_intlist2str();
  test_dbllist2str();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_intlist2str@plt>
  xor    %eax,%eax
  call   <test_dbllist2str@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test_intlist2str();
  test_dbllist2str();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x7f0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x7e8(%rbp)
  jmp    L7
L16:
  mov    -0x7e4(%rbp),%eax
  cmp    -0x7e8(%rbp),%eax
  jle    L7
  mov    -0x7e4(%rbp),%eax
  mov    %eax,-0x7e8(%rbp)
  lea    -0x7e0(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
L7:
  lea    -0x7e0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <getlin@plt>
  mov    %eax,-0x7e4(%rbp)
  cmpl   $0x0,-0x7e4(%rbp)
  jg     L16
  cmpl   $0x0,-0x7e8(%rbp)
  jle    L20
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L20:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D8
type_infered: string

tool: D8: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlin(line, 1000)) > 0)
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x7e0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebp
  mov    %rsp,%r12
L31:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlin@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jle    L20
  cmp    %ebx,%ebp
  jge    L31
  lea    0x3f0(%rsp),%rdi
  mov    %r12,%rsi
  call   <copy@plt>
  mov    %ebx,%ebp
  jmp    L31
L20:
  test   %ebp,%ebp
  jg     L34
L2:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x7e0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L34:
  lea    0x3f0(%rsp),%rsi
  lea    D9(%rip),%rdi
  call   <printf@plt>
  jmp    L2
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D9
data_type: string

tool: D9: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlin(line, 1000)) > 0)
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r13
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L9:
  cmp    %ebx,%ebp
  jl     L37
L8:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlin@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L9
  test   %ebp,%ebp
  jne    L3
L54:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L37:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <copy@plt>
  jmp    L8
L3:
  lea    0x3f0(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string

tool: D2: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlin(line, 1000)) > 0)
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x7e8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x7d8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x3f0(%rsp),%r13
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L21:
  cmp    %ebx,%ebp
  jl     L8
L13:
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <getlin@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L21
  test   %ebp,%ebp
  jne    L65
L7:
  mov    0x7d8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x7e8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %r12,%rsi
  mov    %r13,%rdi
  mov    %ebx,%ebp
  call   <copy@plt>
  jmp    L13
L65:
  lea    0x3f0(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L7
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
data_type: string

tool: D4: %s

assistant: ```c
int main() {
  int len;
  int max;
  char line[1000];
  char longest[1000];
  max = 0;
  while ((len = getlin(line, 1000)) > 0)
    if (len > max) {
      max = len;
      copy(longest, line);
    }
  if (max > 0)
    printf("%s", longest);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<n_caseft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <skip@plt>
  mov    $0x1,%edi
  call   <setfont@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void n_caseft(void) {
  skip();
  setfont(1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<n_caseft>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <skip@plt>
  mov    $0x1,%edi
  call   <setfont@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void n_caseft(void) {
  skip();
  setfont(1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<n_caseft>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <skip@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <setfont@plt>
```

assistant: ```c
void n_caseft(void) {
  skip();
  setfont(1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<n_caseft>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <skip@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1060 <setfont@plt>
```

assistant: ```c
void n_caseft(void) {
  skip();
  setfont(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_ses_fru_identify_state>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x6f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L33
L7:
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x6f,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L20
  mov    $0xffffffff,%eax
  jmp    L33
L20:
  mov    -0x8(%rbp),%rax
  mov    $0x2,%edx
  lea    D8(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L33:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: on

assistant: ```c
int get_ses_fru_identify_state(const char *buf) {
  char *fault;
  char *ident;
  fault = strchr(buf, 'o');
  if (!fault)
    return -1;
  fault++;
  ident = strchr(fault, 'o');
  if (!ident)
    return -1;
  return !strncmp(ident, "on", 2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_ses_fru_identify_state>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%esi
  call   <strchr@plt>
  mov    $0xffffffff,%edx
  test   %rax,%rax
  je     L0
  lea    0x1(%rax),%rdi
  mov    $0x6f,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  mov    $0xffffffff,%edx
  test   %rax,%rax
  je     L0
  mov    $0x2,%edx
  lea    D9(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %dl
  movzbl %dl,%edx
L0:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
datatype: string

tool: D9: on

assistant: ```c
int get_ses_fru_identify_state(const char *buf) {
  char *fault;
  char *ident;
  fault = strchr(buf, 'o');
  if (!fault)
    return -1;
  fault++;
  ident = strchr(fault, 'o');
  if (!ident)
    return -1;
  return !strncmp(ident, "on", 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_ses_fru_identify_state>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L16
  lea    0x1(%rax),%rdi
  mov    $0x6f,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L16
  mov    $0x2,%edx
  lea    D0(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D0
type_infered: string

tool: D0: on

assistant: ```c
int get_ses_fru_identify_state(const char *buf) {
  char *fault;
  char *ident;
  fault = strchr(buf, 'o');
  if (!fault)
    return -1;
  fault++;
  ident = strchr(fault, 'o');
  if (!ident)
    return -1;
  return !strncmp(ident, "on", 2);
}
```
user: What is the c source code of the assembly code below?

```asm
<get_ses_fru_identify_state>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x6f,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L11
  lea    0x1(%rax),%rdi
  mov    $0x6f,%esi
  call   <strchr@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L11
  mov    $0x2,%edx
  lea    D0(%rip),%rsi
  call   <strncmp@plt>
  test   %eax,%eax
  sete   %al
  add    $0x8,%rsp
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L11:
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: string

tool: D0: on

assistant: ```c
int get_ses_fru_identify_state(const char *buf) {
  char *fault;
  char *ident;
  fault = strchr(buf, 'o');
  if (!fault)
    return -1;
  fault++;
  ident = strchr(fault, 'o');
  if (!ident)
    return -1;
  return !strncmp(ident, "on", 2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrdp_painter_delete>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L19
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <g_free@plt>
  jmp    L10
L19:
  nop
L10:
  leave
  ret
```

assistant: ```c
void xrdp_painter_delete(struct xrdp_painter *self) {
  if (self == 0) {
    return;
  }
  g_free(self);
}
```