ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__utac__exception__cf_handler_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    -0x88(%rbp),%rax
  mov    %rax,-0x78(%rbp)
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x70(%rbp)
  mov    -0x70(%rbp),%rax
  add    $0x18,%rax
  mov    %rax,-0x68(%rbp)
  mov    -0x68(%rbp),%rax
  mov    %rax,-0x60(%rbp)
  mov    -0x60(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x80(%rbp)
L13:
  movq   $0x0,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,-0x50(%rbp)
  mov    -0x80(%rbp),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  cmp    -0x50(%rbp),%rax
  je     L4
  mov    -0x80(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x80(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x80(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  jmp    L13
L4:
  nop
  mov    -0x78(%rbp),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x40(%rbp),%rax
  add    $0x18,%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void __utac__exception__cf_handler_free(void *exception) {
  struct __UTAC__EXCEPTION *excep;
  struct __UTAC__CFLOW_FUNC *cf;
  struct __UTAC__CFLOW_FUNC *tmp;
  unsigned long __cil_tmp5;
  unsigned long __cil_tmp6;
  struct __UTAC__CFLOW_FUNC *__cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  unsigned long __cil_tmp10;
  unsigned long __cil_tmp11;
  void *__cil_tmp12;
  unsigned long __cil_tmp13;
  unsigned long __cil_tmp14;
  struct __UTAC__CFLOW_FUNC **mem_15;
  struct __UTAC__CFLOW_FUNC **mem_16;
  struct __UTAC__CFLOW_FUNC **mem_17;
  {
    excep = (struct __UTAC__EXCEPTION *)exception;
    __cil_tmp5 = (unsigned long)excep;
    __cil_tmp6 = __cil_tmp5 + 24;
    mem_15 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp6;
    cf = *mem_15;
    {
      while (1) {
      while_1_continue:;
        {
          __cil_tmp7 = (struct __UTAC__CFLOW_FUNC *)0;
          __cil_tmp8 = (unsigned long)__cil_tmp7;
          __cil_tmp9 = (unsigned long)cf;
          if (__cil_tmp9 != __cil_tmp8) {
          } else {
            goto while_1_break;
          }
        }
        {
          tmp = cf;
          __cil_tmp10 = (unsigned long)cf;
          __cil_tmp11 = __cil_tmp10 + 16;
          mem_16 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp11;
          cf = *mem_16;
          __cil_tmp12 = (void *)tmp;
          free(__cil_tmp12);
        }
      }
    while_1_break:;
    }
    __cil_tmp13 = (unsigned long)excep;
    __cil_tmp14 = __cil_tmp13 + 24;
    mem_17 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp14;
    *mem_17 = (struct __UTAC__CFLOW_FUNC *)0;
    return;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__utac__exception__cf_handler_free>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    0x18(%rdi),%rbx
  mov    %rbx,%rax
  test   %rbx,%rbx
  je     L17
L6:
  mov    %rbx,%rdi
  mov    0x10(%rax),%rbx
  call   <free@plt>
  mov    %rbx,%rax
  test   %rbx,%rbx
  jne    L6
L17:
  movq   $0x0,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void __utac__exception__cf_handler_free(void *exception) {
  struct __UTAC__EXCEPTION *excep;
  struct __UTAC__CFLOW_FUNC *cf;
  struct __UTAC__CFLOW_FUNC *tmp;
  unsigned long __cil_tmp5;
  unsigned long __cil_tmp6;
  struct __UTAC__CFLOW_FUNC *__cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  unsigned long __cil_tmp10;
  unsigned long __cil_tmp11;
  void *__cil_tmp12;
  unsigned long __cil_tmp13;
  unsigned long __cil_tmp14;
  struct __UTAC__CFLOW_FUNC **mem_15;
  struct __UTAC__CFLOW_FUNC **mem_16;
  struct __UTAC__CFLOW_FUNC **mem_17;
  {
    excep = (struct __UTAC__EXCEPTION *)exception;
    __cil_tmp5 = (unsigned long)excep;
    __cil_tmp6 = __cil_tmp5 + 24;
    mem_15 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp6;
    cf = *mem_15;
    {
      while (1) {
      while_1_continue:;
        {
          __cil_tmp7 = (struct __UTAC__CFLOW_FUNC *)0;
          __cil_tmp8 = (unsigned long)__cil_tmp7;
          __cil_tmp9 = (unsigned long)cf;
          if (__cil_tmp9 != __cil_tmp8) {
          } else {
            goto while_1_break;
          }
        }
        {
          tmp = cf;
          __cil_tmp10 = (unsigned long)cf;
          __cil_tmp11 = __cil_tmp10 + 16;
          mem_16 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp11;
          cf = *mem_16;
          __cil_tmp12 = (void *)tmp;
          free(__cil_tmp12);
        }
      }
    while_1_break:;
    }
    __cil_tmp13 = (unsigned long)excep;
    __cil_tmp14 = __cil_tmp13 + 24;
    mem_17 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp14;
    *mem_17 = (struct __UTAC__CFLOW_FUNC *)0;
    return;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__utac__exception__cf_handler_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rbx
  test   %rbx,%rbx
  je     L12
  cs nopw 0x0(%rax,%rax,1)
L8:
  mov    %rbx,%rdi
  mov    0x10(%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L8
L12:
  movq   $0x0,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void __utac__exception__cf_handler_free(void *exception) {
  struct __UTAC__EXCEPTION *excep;
  struct __UTAC__CFLOW_FUNC *cf;
  struct __UTAC__CFLOW_FUNC *tmp;
  unsigned long __cil_tmp5;
  unsigned long __cil_tmp6;
  struct __UTAC__CFLOW_FUNC *__cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  unsigned long __cil_tmp10;
  unsigned long __cil_tmp11;
  void *__cil_tmp12;
  unsigned long __cil_tmp13;
  unsigned long __cil_tmp14;
  struct __UTAC__CFLOW_FUNC **mem_15;
  struct __UTAC__CFLOW_FUNC **mem_16;
  struct __UTAC__CFLOW_FUNC **mem_17;
  {
    excep = (struct __UTAC__EXCEPTION *)exception;
    __cil_tmp5 = (unsigned long)excep;
    __cil_tmp6 = __cil_tmp5 + 24;
    mem_15 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp6;
    cf = *mem_15;
    {
      while (1) {
      while_1_continue:;
        {
          __cil_tmp7 = (struct __UTAC__CFLOW_FUNC *)0;
          __cil_tmp8 = (unsigned long)__cil_tmp7;
          __cil_tmp9 = (unsigned long)cf;
          if (__cil_tmp9 != __cil_tmp8) {
          } else {
            goto while_1_break;
          }
        }
        {
          tmp = cf;
          __cil_tmp10 = (unsigned long)cf;
          __cil_tmp11 = __cil_tmp10 + 16;
          mem_16 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp11;
          cf = *mem_16;
          __cil_tmp12 = (void *)tmp;
          free(__cil_tmp12);
        }
      }
    while_1_break:;
    }
    __cil_tmp13 = (unsigned long)excep;
    __cil_tmp14 = __cil_tmp13 + 24;
    mem_17 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp14;
    *mem_17 = (struct __UTAC__CFLOW_FUNC *)0;
    return;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__utac__exception__cf_handler_free>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    0x18(%rdi),%rbx
  test   %rbx,%rbx
  je     L2
  cs nopw 0x0(%rax,%rax,1)
L12:
  mov    %rbx,%rdi
  mov    0x10(%rbx),%rbx
  call   <free@plt>
  test   %rbx,%rbx
  jne    L12
L2:
  movq   $0x0,0x18(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void __utac__exception__cf_handler_free(void *exception) {
  struct __UTAC__EXCEPTION *excep;
  struct __UTAC__CFLOW_FUNC *cf;
  struct __UTAC__CFLOW_FUNC *tmp;
  unsigned long __cil_tmp5;
  unsigned long __cil_tmp6;
  struct __UTAC__CFLOW_FUNC *__cil_tmp7;
  unsigned long __cil_tmp8;
  unsigned long __cil_tmp9;
  unsigned long __cil_tmp10;
  unsigned long __cil_tmp11;
  void *__cil_tmp12;
  unsigned long __cil_tmp13;
  unsigned long __cil_tmp14;
  struct __UTAC__CFLOW_FUNC **mem_15;
  struct __UTAC__CFLOW_FUNC **mem_16;
  struct __UTAC__CFLOW_FUNC **mem_17;
  {
    excep = (struct __UTAC__EXCEPTION *)exception;
    __cil_tmp5 = (unsigned long)excep;
    __cil_tmp6 = __cil_tmp5 + 24;
    mem_15 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp6;
    cf = *mem_15;
    {
      while (1) {
      while_1_continue:;
        {
          __cil_tmp7 = (struct __UTAC__CFLOW_FUNC *)0;
          __cil_tmp8 = (unsigned long)__cil_tmp7;
          __cil_tmp9 = (unsigned long)cf;
          if (__cil_tmp9 != __cil_tmp8) {
          } else {
            goto while_1_break;
          }
        }
        {
          tmp = cf;
          __cil_tmp10 = (unsigned long)cf;
          __cil_tmp11 = __cil_tmp10 + 16;
          mem_16 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp11;
          cf = *mem_16;
          __cil_tmp12 = (void *)tmp;
          free(__cil_tmp12);
        }
      }
    while_1_break:;
    }
    __cil_tmp13 = (unsigned long)excep;
    __cil_tmp14 = __cil_tmp13 + 24;
    mem_17 = (struct __UTAC__CFLOW_FUNC **)__cil_tmp14;
    *mem_17 = (struct __UTAC__CFLOW_FUNC *)0;
    return;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<qtime_parse_gmtstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strptime@plt>
  test   %rax,%rax
  jne    L40
  mov    $0x0,%eax
  jmp    L33
L40:
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rdi
  call   <timegm@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L70
  mov    $0xffffffffffffffff,%rax
  jmp    L33
L70:
  mov    -0x28(%rbp),%rax
  mov    $0x2b,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L58
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  sub    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L85
  mov    $0xffffffffffffffff,%rax
  jmp    L33
L58:
  mov    -0x28(%rbp),%rax
  mov    $0x2d,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L85
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  add    %rax,-0x18(%rbp)
L85:
  mov    -0x18(%rbp),%rax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D1
data_type: string

tool: D1: %a, %d %b %Y %H:%M:%S

assistant: ```c
time_t qtime_parse_gmtstr(const char *gmtstr) {
  struct tm gmtm;
  if (strptime(gmtstr, "%a, %d %b %Y %H:%M:%S", &gmtm) == NULL)
    return 0;
  time_t utc = timegm(&gmtm);
  if (utc < 0)
    return -1;
  char *p;
  if ((p = strstr(gmtstr, "+")) != NULL) {
    utc -= ((atoi(p + 1) / 100) * 60 * 60);
    if (utc < 0)
      return -1;
  } else if ((p = strstr(gmtstr, "-")) != NULL) {
    utc += ((atoi(p + 1) / 100) * 60 * 60);
  }
  return utc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<qtime_parse_gmtstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  lea    D6(%rip),%rsi
  call   <strptime@plt>
  mov    $0x0,%ebx
  test   %rax,%rax
  je     L2
  lea    0x4(%rsp),%rdi
  call   <timegm@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  js     L12
  mov    $0x2b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L5
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  cltq
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  sub    %rax,%rbx
  mov    $0xffffffffffffffff,%rax
  cmovs  %rax,%rbx
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L46
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  mov    $0x2d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  cltq
  imul   $0x51eb851f,%rax,%rax
  sar    $0x25,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  add    %rax,%rbx
  jmp    L2
L12:
  mov    $0xffffffffffffffff,%rbx
  jmp    L2
L46:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_guessed: string

tool: D6: %a, %d %b %Y %H:%M:%S

assistant: ```c
time_t qtime_parse_gmtstr(const char *gmtstr) {
  struct tm gmtm;
  if (strptime(gmtstr, "%a, %d %b %Y %H:%M:%S", &gmtm) == NULL)
    return 0;
  time_t utc = timegm(&gmtm);
  if (utc < 0)
    return -1;
  char *p;
  if ((p = strstr(gmtstr, "+")) != NULL) {
    utc -= ((atoi(p + 1) / 100) * 60 * 60);
    if (utc < 0)
      return -1;
  } else if ((p = strstr(gmtstr, "-")) != NULL) {
    utc += ((atoi(p + 1) / 100) * 60 * 60);
  }
  return utc;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<qtime_parse_gmtstr>:
  endbr64
  push   %r13
  lea    D0(%rip),%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  call   <strptime@plt>
  test   %rax,%rax
  je     L53
  mov    %r13,%rdi
  call   <timegm@plt>
  mov    %rax,%r12
  test   %rax,%rax
  js     L47
  mov    $0x2b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L57
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  cltq
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x25,%rax
  sub    %edx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  sub    %rax,%r12
  mov    $0xffffffffffffffff,%rax
  cmovs  %rax,%r12
L53:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L57:
  mov    $0x2d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L53
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  cltq
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x25,%rax
  sub    %edx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  add    %rax,%r12
  jmp    L53
L47:
  mov    $0xffffffffffffffff,%r12
  jmp    L53
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: %a, %d %b %Y %H:%M:%S

assistant: ```c
time_t qtime_parse_gmtstr(const char *gmtstr) {
  struct tm gmtm;
  if (strptime(gmtstr, "%a, %d %b %Y %H:%M:%S", &gmtm) == NULL)
    return 0;
  time_t utc = timegm(&gmtm);
  if (utc < 0)
    return -1;
  char *p;
  if ((p = strstr(gmtstr, "+")) != NULL) {
    utc -= ((atoi(p + 1) / 100) * 60 * 60);
    if (utc < 0)
      return -1;
  } else if ((p = strstr(gmtstr, "-")) != NULL) {
    utc += ((atoi(p + 1) / 100) * 60 * 60);
  }
  return utc;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<qtime_parse_gmtstr>:
  endbr64
  push   %r13
  lea    D2(%rip),%rsi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  call   <strptime@plt>
  test   %rax,%rax
  je     L48
  mov    %r13,%rdi
  call   <timegm@plt>
  mov    %rax,%r12
  test   %rax,%rax
  js     L65
  mov    $0x2b,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L58
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  cltq
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x25,%rax
  sub    %edx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  sub    %rax,%r12
  mov    $0xffffffffffffffff,%rax
  cmovs  %rax,%r12
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L58:
  mov    $0x2d,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L48
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  cltq
  imul   $0x51eb851f,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x25,%rax
  sub    %edx,%eax
  imul   $0xe10,%eax,%eax
  cltq
  add    %rax,%r12
  jmp    L48
L65:
  mov    $0xffffffffffffffff,%r12
  jmp    L48
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D2
data_type: string

tool: D2: %a, %d %b %Y %H:%M:%S

assistant: ```c
time_t qtime_parse_gmtstr(const char *gmtstr) {
  struct tm gmtm;
  if (strptime(gmtstr, "%a, %d %b %Y %H:%M:%S", &gmtm) == NULL)
    return 0;
  time_t utc = timegm(&gmtm);
  if (utc < 0)
    return -1;
  char *p;
  if ((p = strstr(gmtstr, "+")) != NULL) {
    utc -= ((atoi(p + 1) / 100) * 60 * 60);
    if (utc < 0)
      return -1;
  } else if ((p = strstr(gmtstr, "-")) != NULL) {
    utc += ((atoi(p + 1) / 100) * 60 * 60);
  }
  return utc;
}
```
user: Translate the below assembly code into C programming language:

```asm
<squares>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x14(%rbp)
  jle    L19
  addl   $0x1,-0x8(%rbp)
  jmp    L9
L19:
  nop
  movl   $0x1,-0x4(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L11
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L39
L11:
  nop
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int squares(int n1, int n2) {
  int i = 1;
  while (1) {
    if (i * i >= n1) {
      break;
    }
    i++;
  }
  int c = 1;
  while (1) {
    if (i * i > n2) {
      break;
    }
    i++;
    c++;
  }
  return c - 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<squares>:
  endbr64
  mov    $0x1,%edx
  cmp    $0x1,%edi
  jle    L3
L46:
  add    $0x1,%edx
  mov    %edx,%eax
  imul   %edx,%eax
  cmp    %edi,%eax
  jl     L46
L3:
  mov    %edx,%eax
  imul   %edx,%eax
  cmp    %eax,%esi
  jl     L29
  mov    $0x1,%eax
L37:
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%eax
  imul   %ecx,%ecx
  cmp    %esi,%ecx
  jle    L37
L33:
  sub    $0x1,%eax
  ret
L29:
  mov    $0x1,%eax
  jmp    L33
```

assistant: ```c
int squares(int n1, int n2) {
  int i = 1;
  while (1) {
    if (i * i >= n1) {
      break;
    }
    i++;
  }
  int c = 1;
  while (1) {
    if (i * i > n2) {
      break;
    }
    i++;
    c++;
  }
  return c - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<squares>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L6
  xchg   %ax,%ax
L35:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jl     L35
  cmp    %esi,%edx
  jg     L25
L40:
  mov    $0x1,%ecx
  nopl   (%rax)
L32:
  lea    (%rcx,%rax,1),%edx
  mov    %ecx,%r8d
  add    $0x1,%ecx
  imul   %edx,%edx
  cmp    %esi,%edx
  jle    L32
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x1,%edx
  cmp    %esi,%edx
  jle    L40
L25:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int squares(int n1, int n2) {
  int i = 1;
  while (1) {
    if (i * i >= n1) {
      break;
    }
    i++;
  }
  int c = 1;
  while (1) {
    if (i * i > n2) {
      break;
    }
    i++;
    c++;
  }
  return c - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<squares>:
  endbr64
  mov    $0x1,%eax
  cmp    $0x1,%edi
  jle    L24
  xchg   %ax,%ax
L32:
  add    $0x1,%eax
  mov    %eax,%edx
  imul   %eax,%edx
  cmp    %edi,%edx
  jl     L32
  cmp    %edx,%esi
  jl     L23
L11:
  mov    $0x1,%ecx
  nopl   (%rax)
L2:
  lea    (%rcx,%rax,1),%edx
  mov    %ecx,%r8d
  add    $0x1,%ecx
  imul   %edx,%edx
  cmp    %esi,%edx
  jle    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L24:
  mov    $0x1,%edx
  cmp    %edx,%esi
  jge    L11
L23:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int squares(int n1, int n2) {
  int i = 1;
  while (1) {
    if (i * i >= n1) {
      break;
    }
    i++;
  }
  int c = 1;
  while (1) {
    if (i * i > n2) {
      break;
    }
    i++;
    c++;
  }
  return c - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__sanitizer_cov_trace_const_cmp2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  test   %rax,%rax
  je     L14
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <__builtin_bswap16@plt>
  mov    %rax,-0x20(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <instrumentAddConstMem@plt>
  lea    -0x28(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x8,%esi
  mov    %rax,%rdi
  call   <instrumentAddConstMem@plt>
L14:
  mov    -0x28(%rbp),%rbx
  mov    $0x0,%edi
  call   <__builtin_return_address@plt>
  mov    %rax,%rcx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdx
  mov    %rbx,%rsi
  mov    %rcx,%rdi
  call   <hfuzz_trace_cmp2_internal@plt>
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void __sanitizer_cov_trace_const_cmp2(uint16_t Arg1, uint16_t Arg2) {
  if (Arg1) {
    uint16_t bswp = __builtin_bswap16(Arg1);
    instrumentAddConstMem(&bswp, sizeof(bswp), false);
    instrumentAddConstMem(&Arg1, sizeof(Arg1), false);
  }
  hfuzz_trace_cmp2_internal((uintptr_t)__builtin_return_address(0), Arg1, Arg2);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__sanitizer_cov_trace_const_cmp2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbx
  mov    %fs:0x28,%rdx
  mov    %rdx,0x18(%rsp)
  xor    %edx,%edx
  test   %rdi,%rdi
  jne    L18
L24:
  mov    0x8(%rsp),%rbp
  mov    $0x0,%edi
  call   <__builtin_return_address@plt>
  mov    %rax,%rdi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <hfuzz_trace_cmp2_internal@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  call   <__builtin_bswap16@plt>
  mov    %rax,0x10(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x0,%edx
  mov    $0x8,%esi
  call   <instrumentAddConstMem@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x0,%edx
  mov    $0x8,%esi
  call   <instrumentAddConstMem@plt>
  jmp    L24
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void __sanitizer_cov_trace_const_cmp2(uint16_t Arg1, uint16_t Arg2) {
  if (Arg1) {
    uint16_t bswp = __builtin_bswap16(Arg1);
    instrumentAddConstMem(&bswp, sizeof(bswp), false);
    instrumentAddConstMem(&Arg1, sizeof(Arg1), false);
  }
  hfuzz_trace_cmp2_internal((uintptr_t)__builtin_return_address(0), Arg1, Arg2);
}
```