ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tanh>:
  endbr64
  ucomisd %xmm0,%xmm0
  jp     L0
  movq   D12(%rip),%xmm4
  movapd %xmm0,%xmm1
  movapd %xmm0,%xmm2
  movsd  D136(%rip),%xmm5
  movq   D18(%rip),%xmm3
  andpd  %xmm4,%xmm1
  comisd %xmm1,%xmm5
  andpd  %xmm3,%xmm2
  orpd   D70(%rip),%xmm2
  jbe    L32
  sub    $0x18,%rsp
  comisd D70(%rip),%xmm1
  ja     L59
  comisd D52(%rip),%xmm1
  ja     L27
L46:
  andpd  %xmm2,%xmm3
  andpd  %xmm4,%xmm0
  add    $0x18,%rsp
  orpd   %xmm3,%xmm0
  ret
  nopl   0x0(%rax)
L32:
  movsd  D30(%rip),%xmm0
  ucomisd %xmm1,%xmm0
  jb     L58
  addsd  D107(%rip),%xmm2
L58:
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  movapd %xmm0,%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax)
L27:
  addsd  %xmm1,%xmm1
  movsd  %xmm2,0x8(%rsp)
  xorpd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  call   <expm1@plt>
  movsd  D89(%rip),%xmm1
  movq   D18(%rip),%xmm3
  movsd  0x8(%rsp),%xmm2
  addsd  %xmm0,%xmm1
  divsd  %xmm1,%xmm0
L47:
  movq   D12(%rip),%xmm4
  jmp    L46
  nopw   0x0(%rax,%rax,1)
L59:
  addsd  %xmm1,%xmm1
  movsd  %xmm2,0x8(%rsp)
  movapd %xmm1,%xmm0
  call   <expm1@plt>
  movsd  D89(%rip),%xmm1
  movsd  0x8(%rsp),%xmm2
  movq   D18(%rip),%xmm3
  addsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm1
  movsd  D70(%rip),%xmm0
  subsd  %xmm1,%xmm0
  jmp    L47
```

tool_calls: name: read_data
arguments: label: D12
type_infered: byte[8]
name: read_data
arguments: label: D136
type_infered: f64
name: read_data
arguments: label: D18
type_infered: byte[8]
name: read_data
arguments: label: D70
type_infered: f64[2]
name: read_data
arguments: label: D52
type_infered: byte[16]
name: read_data
arguments: label: D30
type_infered: byte[8]
name: read_data
arguments: label: D107
type_infered: byte[8]
name: read_data
arguments: label: D89
type_infered: f64

tool: {"D12": [0xff,0xff,0xff,0xff,0xff,0xff,0xff,0x7f]}

tool: D136: 22

tool: {"D18": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

tool: {"D70": [1.0,0.0]}

tool: {"D52": [0xbb,0xbd,0xd7,0xd9,0xdf,0x7c,0xdb,0x3d,0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: {"D30": [0xff,0xff,0xff,0xff,0xff,0xff,0xef,0x7f]}

tool: {"D107": [0x8f,0x8b,0x8a,0x42,0x9d,0x03,0x41,0x38]}

tool: D89: 2

assistant: ```c
double tanh(x)
double x;
{
  static double one = 1.0, two = 2.0, small = 1.0e-10, big = 1.0e10;
  double expm1(), t, copysign(), sign;
  int finite(), isnan();
  if (x != x)
    return (x);
  sign = copysign(one, x);
  x = copysign(x, one);
  if (x < 22.0)
    if (x > one)
      return (copysign(one - two / (expm1(x + x) + two), sign));
    else if (x > small) {
      t = -expm1(-(x + x));
      return (copysign(t / (two - t), sign));
    } else {
      t = big + x;
      return (copysign(x, sign));
    }
  else if (finite(x))
    return (sign + 1.0E-37);
  else
    return (sign);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Swaps>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  movzwl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dx,(%rax)
  mov    -0x20(%rbp),%rax
  movzwl -0x2(%rbp),%edx
  mov    %dx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void Swaps(short *a, short *b) {
  short t = *a;
  *a = *b;
  *b = t;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Swaps>:
  endbr64
  movzwl (%rdi),%eax
  movzwl (%rsi),%edx
  mov    %dx,(%rdi)
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void Swaps(short *a, short *b) {
  short t = *a;
  *a = *b;
  *b = t;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<Swaps>:
  endbr64
  movzwl (%rdi),%eax
  movzwl (%rsi),%edx
  mov    %dx,(%rdi)
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void Swaps(short *a, short *b) {
  short t = *a;
  *a = *b;
  *b = t;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Swaps>:
  endbr64
  movzwl (%rdi),%eax
  movzwl (%rsi),%edx
  mov    %dx,(%rdi)
  mov    %ax,(%rsi)
  ret
```

assistant: ```c
void Swaps(short *a, short *b) {
  short t = *a;
  *a = *b;
  *b = t;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<OisEna_lc898122>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%edi
  call   <GyrCon_lc898122@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void OisEna_lc898122(void) {
  SrvCon_lc898122(0x00, 0x01);
  SrvCon_lc898122(0x01, 0x01);
  GyrCon_lc898122(0x01);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<OisEna_lc898122>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%edi
  call   <GyrCon_lc898122@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void OisEna_lc898122(void) {
  SrvCon_lc898122(0x00, 0x01);
  SrvCon_lc898122(0x01, 0x01);
  GyrCon_lc898122(0x01);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<OisEna_lc898122>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%edi
  mov    $0x1,%esi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <GyrCon_lc898122@plt>
```

assistant: ```c
void OisEna_lc898122(void) {
  SrvCon_lc898122(0x00, 0x01);
  SrvCon_lc898122(0x01, 0x01);
  GyrCon_lc898122(0x01);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<OisEna_lc898122>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%esi
  xor    %edi,%edi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%edi
  mov    $0x1,%esi
  call   <SrvCon_lc898122@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <GyrCon_lc898122@plt>
```

assistant: ```c
void OisEna_lc898122(void) {
  SrvCon_lc898122(0x00, 0x01);
  SrvCon_lc898122(0x01, 0x01);
  GyrCon_lc898122(0x01);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_x509_cert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <PEM_read_bio_X509@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L0
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <X509_print_fp@plt>
  mov    $0x1,%eax
  jmp    L9
L0:
  mov    $0x0,%eax
L9:
  leave
  ret
```

assistant: ```c
int print_x509_cert(const unsigned char *data, unsigned length) {
  BIO *bio;
  X509 *certificate = NULL;
  bio = BIO_new(BIO_s_mem());
  BIO_write(bio, (const void *)data, length);
  certificate = PEM_read_bio_X509(bio, NULL, 0, NULL);
  if (certificate != NULL) {
    X509_print_fp(stdout, certificate);
    return 1;
  } else {
    return 0;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_x509_cert>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    $0x0,%eax
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rbx
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <BIO_write@plt>
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <PEM_read_bio_X509@plt>
  mov    %rax,%rsi
  mov    $0x0,%eax
  test   %rsi,%rsi
  je     L7
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <X509_print_fp@plt>
  mov    $0x1,%eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int print_x509_cert(const unsigned char *data, unsigned length) {
  BIO *bio;
  X509 *certificate = NULL;
  bio = BIO_new(BIO_s_mem());
  BIO_write(bio, (const void *)data, length);
  certificate = PEM_read_bio_X509(bio, NULL, 0, NULL);
  if (certificate != NULL) {
    X509_print_fp(stdout, certificate);
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<print_x509_cert>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <BIO_write@plt>
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%rdi
  call   <PEM_read_bio_X509@plt>
  mov    %rax,%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L7
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <X509_print_fp@plt>
  mov    $0x1,%eax
L7:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int print_x509_cert(const unsigned char *data, unsigned length) {
  BIO *bio;
  X509 *certificate = NULL;
  bio = BIO_new(BIO_s_mem());
  BIO_write(bio, (const void *)data, length);
  certificate = PEM_read_bio_X509(bio, NULL, 0, NULL);
  if (certificate != NULL) {
    X509_print_fp(stdout, certificate);
    return 1;
  } else {
    return 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_x509_cert>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  call   <BIO_s_mem@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <BIO_write@plt>
  xor    %esi,%esi
  xor    %ecx,%ecx
  xor    %edx,%edx
  mov    %rbp,%rdi
  call   <PEM_read_bio_X509@plt>
  mov    %rax,%rsi
  xor    %eax,%eax
  test   %rsi,%rsi
  je     L3
  mov    D5(%rip),%rax
  mov    (%rax),%edi
  call   <X509_print_fp@plt>
  mov    $0x1,%eax
L3:
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int print_x509_cert(const unsigned char *data, unsigned length) {
  BIO *bio;
  X509 *certificate = NULL;
  bio = BIO_new(BIO_s_mem());
  BIO_write(bio, (const void *)data, length);
  certificate = PEM_read_bio_X509(bio, NULL, 0, NULL);
  if (certificate != NULL) {
    X509_print_fp(stdout, certificate);
    return 1;
  } else {
    return 0;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<get_reversed_bits_uint64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L2
L10:
  mov    -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    -0x18(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L25
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
  jmp    L28
L25:
  mov    -0x18(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  neg    %eax
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
L28:
  addl   $0x1,-0x8(%rbp)
L2:
  mov    -0x18(%rbp),%eax
  sub    -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jle    L10
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t get_reversed_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint32_t val = 0;
  for (int i = 0; i <= bit0 - bit1; i++) {
    int shift_right = bit0 - 2 * i;
    if (shift_right >= 0)
      val |= (data & ((uint64_t)1 << (bit0 - i))) >> shift_right;
    else
      val |= (data & ((uint64_t)1 << (bit0 - i))) << (-shift_right);
  }
  return val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_reversed_bits_uint64>:
  endbr64
  mov    %edi,%r8d
  mov    %esi,%ecx
  sub    %edx,%ecx
  js     L23
  mov    %esi,%eax
  lea    -0x1(%rsi),%r9d
  sub    %ecx,%r9d
  mov    $0x0,%edi
  mov    $0x1,%r10d
  jmp    L24
L26:
  mov    %r10d,%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  and    %r8d,%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  or     %edx,%edi
L22:
  sub    $0x2,%eax
  sub    $0x1,%esi
  cmp    %r9d,%esi
  je     L25
L24:
  test   %eax,%eax
  jns    L26
  mov    %r10d,%edx
  mov    %esi,%ecx
  shl    %cl,%edx
  and    %r8d,%edx
  mov    %eax,%ecx
  neg    %ecx
  shl    %cl,%edx
  or     %edx,%edi
  jmp    L22
L23:
  mov    $0x0,%edi
L25:
  mov    %edi,%eax
  ret
```

assistant: ```c
uint32_t get_reversed_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint32_t val = 0;
  for (int i = 0; i <= bit0 - bit1; i++) {
    int shift_right = bit0 - 2 * i;
    if (shift_right >= 0)
      val |= (data & ((uint64_t)1 << (bit0 - i))) >> shift_right;
    else
      val |= (data & ((uint64_t)1 << (bit0 - i))) << (-shift_right);
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_reversed_bits_uint64>:
  endbr64
  mov    %esi,%eax
  sub    %edx,%eax
  js     L12
  lea    -0x1(%rsi),%r9d
  mov    %esi,%edx
  xor    %r8d,%r8d
  mov    $0x1,%r10d
  sub    %eax,%r9d
  jmp    L19
  xchg   %ax,%ax
L40:
  mov    %edx,%ecx
  sub    $0x1,%esi
  sub    $0x2,%edx
  sar    %cl,%eax
  or     %eax,%r8d
  cmp    %r9d,%esi
  je     L39
L19:
  mov    %r10d,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  and    %edi,%eax
  test   %edx,%edx
  jns    L40
  mov    %edx,%ecx
  sub    $0x1,%esi
  sub    $0x2,%edx
  neg    %ecx
  shl    %cl,%eax
  or     %eax,%r8d
  cmp    %r9d,%esi
  jne    L19
L39:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L12:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t get_reversed_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint32_t val = 0;
  for (int i = 0; i <= bit0 - bit1; i++) {
    int shift_right = bit0 - 2 * i;
    if (shift_right >= 0)
      val |= (data & ((uint64_t)1 << (bit0 - i))) >> shift_right;
    else
      val |= (data & ((uint64_t)1 << (bit0 - i))) << (-shift_right);
  }
  return val;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_reversed_bits_uint64>:
  endbr64
  mov    %esi,%eax
  sub    %edx,%eax
  js     L10
  lea    -0x1(%rsi),%r9d
  mov    %esi,%edx
  xor    %r8d,%r8d
  mov    $0x1,%r10d
  sub    %eax,%r9d
  jmp    L20
  xchg   %ax,%ax
L39:
  mov    %edx,%ecx
  sub    $0x1,%esi
  sub    $0x2,%edx
  sar    %cl,%eax
  or     %eax,%r8d
  cmp    %esi,%r9d
  je     L46
L20:
  mov    %r10d,%eax
  mov    %esi,%ecx
  shl    %cl,%eax
  and    %edi,%eax
  test   %edx,%edx
  jns    L39
  mov    %edx,%ecx
  sub    $0x1,%esi
  sub    $0x2,%edx
  neg    %ecx
  shl    %cl,%eax
  or     %eax,%r8d
  cmp    %esi,%r9d
  jne    L20
L46:
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint32_t get_reversed_bits_uint64(uint64_t data, int bit0, int bit1) {
  uint32_t val = 0;
  for (int i = 0; i <= bit0 - bit1; i++) {
    int shift_right = bit0 - 2 * i;
    if (shift_right >= 0)
      val |= (data & ((uint64_t)1 << (bit0 - i))) >> shift_right;
    else
      val |= (data & ((uint64_t)1 << (bit0 - i))) << (-shift_right);
  }
  return val;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <displayBits@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D8
type: string

tool: D16: Enter an unsigned integer: 

tool: D8: %u

assistant: ```c
int main(void) {
  unsigned x;
  printf("Enter an unsigned integer: ");
  scanf("%u", &x);
  displayBits(x);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D11(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <displayBits@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string

tool: D0: Enter an unsigned integer: 

tool: D11: %u

assistant: ```c
int main(void) {
  unsigned x;
  printf("Enter an unsigned integer: ");
  scanf("%u", &x);
  displayBits(x);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D1(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D13(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <displayBits@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D13
datatype: string

tool: D1: Enter an unsigned integer: 

tool: D13: %u

assistant: ```c
int main(void) {
  unsigned x;
  printf("Enter an unsigned integer: ");
  scanf("%u", &x);
  displayBits(x);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D16(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D5(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%edi
  call   <displayBits@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D16
datatype: string
name: retrieve_data
arguments: label: D5
datatype: string

tool: D16: Enter an unsigned integer: 

tool: D5: %u

assistant: ```c
int main(void) {
  unsigned x;
  printf("Enter an unsigned integer: ");
  scanf("%u", &x);
  displayBits(x);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<nextStringLine>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L19
L10:
  addq   $0x1,-0x10(%rbp)
L19:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L32
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
L32:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L63
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <eMalloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L63:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L20
  addq   $0x1,-0x10(%rbp)
  jmp    L18
L20:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L18
  addq   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L18
  addq   $0x1,-0x10(%rbp)
L18:
  mov    -0x28(%rbp),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *nextStringLine(const char **const next) {
  char *result = NULL;
  size_t length;
  const char *end;
  ;
  for (end = *next; *end != '\n' && *end != '\0'; ++end)
    ;
  length = end - *next;
  if (length > 0) {
    result = (char *)eMalloc((size_t)(length + 1) * sizeof(char));
    strncpy(result, *next, length);
    result[length] = '\0';
  }
  if (*end == '\n')
    ++end;
  else if (*end == '\r') {
    ++end;
    if (*end == '\n')
      ++end;
  }
  *next = end;
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<nextStringLine>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  cmp    $0xa,%al
  je     L97
  test   %al,%al
  je     L97
  mov    %rdx,%rbx
L33:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L48
  test   %al,%al
  jne    L33
L48:
  mov    $0x0,%r12d
  mov    %rbx,%r13
  sub    %rdx,%r13
  je     L102
  lea    0x1(%r13),%rdi
  call   <eMalloc@plt>
  mov    %rax,%r12
  mov    %r13,%rdx
  mov    0x0(%rbp),%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r12,%r13,1)
L102:
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  je     L100
  cmp    $0xd,%al
  je     L99
L78:
  mov    %rbx,0x0(%rbp)
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L97:
  mov    %rdx,%rbx
  mov    $0x0,%r12d
  jmp    L102
L100:
  add    $0x1,%rbx
  jmp    L78
L99:
  cmpb   $0xa,0x1(%rbx)
  je     L61
  add    $0x1,%rbx
  jmp    L78
L61:
  add    $0x2,%rbx
  jmp    L78
```

assistant: ```c
char *nextStringLine(const char **const next) {
  char *result = NULL;
  size_t length;
  const char *end;
  ;
  for (end = *next; *end != '\n' && *end != '\0'; ++end)
    ;
  length = end - *next;
  if (length > 0) {
    result = (char *)eMalloc((size_t)(length + 1) * sizeof(char));
    strncpy(result, *next, length);
    result[length] = '\0';
  }
  if (*end == '\n')
    ++end;
  else if (*end == '\r') {
    ++end;
    if (*end == '\n')
      ++end;
  }
  *next = end;
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<nextStringLine>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    (%rdi),%rdx
  movzbl (%rdx),%eax
  mov    %rdx,%rbx
  cmp    $0xa,%al
  je     L9
  test   %al,%al
  je     L9
  nopl   0x0(%rax,%rax,1)
L59:
  mov    %rbx,%rbp
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  cmp    $0xa,%al
  je     L50
  test   %al,%al
  jne    L59
L50:
  mov    %rbx,%r14
  xor    %r13d,%r13d
  sub    %rdx,%r14
  je     L16
  lea    0x1(%r14),%rdi
  call   <eMalloc@plt>
  mov    (%r12),%rsi
  mov    %r14,%rdx
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <strncpy@plt>
  movb   $0x0,0x0(%r13,%r14,1)
  movzbl 0x1(%rbp),%eax
L16:
  cmp    $0xa,%al
  je     L76
  cmp    $0xd,%al
  je     L68
L91:
  mov    %rbx,(%r12)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  cmpb   $0xa,0x1(%rbx)
  je     L57
L76:
  add    $0x1,%rbx
  mov    %r13,%rax
  mov    %rbx,(%r12)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L57:
  add    $0x2,%rbx
  jmp    L91
L9:
  xor    %r13d,%r13d
  jmp    L16
```

assistant: ```c
char *nextStringLine(const char **const next) {
  char *result = NULL;
  size_t length;
  const char *end;
  ;
  for (end = *next; *end != '\n' && *end != '\0'; ++end)
    ;
  length = end - *next;
  if (length > 0) {
    result = (char *)eMalloc((size_t)(length + 1) * sizeof(char));
    strncpy(result, *next, length);
    result[length] = '\0';
  }
  if (*end == '\n')
    ++end;
  else if (*end == '\r') {
    ++end;
    if (*end == '\n')
      ++end;
  }
  *next = end;
  return result;
}
```