ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<CL_DemoFilename>:
  endbr64
  mov    %edi,%eax
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cmp    $0x270f,%eax
  ja     L5
  movslq %eax,%rcx
  cltd
  imul   $0x10624dd3,%rcx,%rcx
  sar    $0x26,%rcx
  sub    %edx,%ecx
  imul   $0xfffffc18,%ecx,%edx
  add    %edx,%eax
  movslq %eax,%r8
  cltd
  imul   $0x51eb851f,%r8,%r8
  sar    $0x25,%r8
  sub    %edx,%r8d
  imul   $0xffffff9c,%r8d,%edx
  add    %eax,%edx
  movslq %edx,%r9
  mov    %edx,%eax
  imul   $0x66666667,%r9,%r9
  sar    $0x1f,%eax
  sar    $0x22,%r9
  sub    %eax,%r9d
  imul   $0xfffffff6,%r9d,%eax
  add    %edx,%eax
L1:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdx
  mov    $0x100,%esi
  push   %rax
  call   <Com_sprintf@plt>
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L5:
  mov    $0x9,%eax
  mov    $0x9,%r9d
  mov    $0x9,%r8d
  mov    $0x9,%ecx
  jmp    L1
```

tool_calls: name: parse_data
arguments: tag: D7
type_infered: string

tool: D7: demo%i%i%i%i

assistant: ```c
void CL_DemoFilename(int number, char *fileName) {
  int a, b, c, d;
  if (number < 0 || number > 9999)
    number = 9999;
  a = number / 1000;
  number -= a * 1000;
  b = number / 100;
  number -= b * 100;
  c = number / 10;
  number -= c * 10;
  d = number;
  Com_sprintf(fileName, 256, "demo%i%i%i%i", a, b, c, d);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<CL_DemoFilename>:
  endbr64
  mov    %edi,%eax
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cmp    $0x270f,%eax
  ja     L1
  movslq %eax,%rcx
  cltd
  imul   $0x10624dd3,%rcx,%rcx
  sar    $0x26,%rcx
  sub    %edx,%ecx
  imul   $0xfffffc18,%ecx,%edx
  add    %edx,%eax
  movslq %eax,%r8
  cltd
  imul   $0x51eb851f,%r8,%r8
  sar    $0x25,%r8
  sub    %edx,%r8d
  imul   $0xffffff9c,%r8d,%edx
  add    %eax,%edx
  movslq %edx,%r9
  mov    %edx,%eax
  imul   $0x66666667,%r9,%r9
  sar    $0x1f,%eax
  sar    $0x22,%r9
  sub    %eax,%r9d
  imul   $0xfffffff6,%r9d,%eax
  add    %edx,%eax
L18:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdx
  mov    $0x100,%esi
  push   %rax
  call   <Com_sprintf@plt>
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L1:
  mov    $0x9,%eax
  mov    $0x9,%r9d
  mov    $0x9,%r8d
  mov    $0x9,%ecx
  jmp    L18
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_guessed: string

tool: D7: demo%i%i%i%i

assistant: ```c
void CL_DemoFilename(int number, char *fileName) {
  int a, b, c, d;
  if (number < 0 || number > 9999)
    number = 9999;
  a = number / 1000;
  number -= a * 1000;
  b = number / 100;
  number -= b * 100;
  c = number / 10;
  number -= c * 10;
  d = number;
  Com_sprintf(fileName, 256, "demo%i%i%i%i", a, b, c, d);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<current_time_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,-0x18(%rbp)
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L27
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L20
L27:
  mov    -0x10(%rbp),%rcx
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strftime@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L49
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    D15(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L20
L49:
  mov    -0x14(%rbp),%eax
L20:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
int current_time_str(char *str, size_t len, const char *fmt) {
  time_t t;
  struct tm *t_local;
  int ret;
  t = time(NULL);
  t_local = localtime(&t);
  if (!t_local) {
    errno = ETIME;
    return -1;
  }
  ret = strftime(str, len, fmt, t_local);
  if (ret == 0) {
    errno = ETIME;
    return -1;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<current_time_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  test   %rax,%rax
  je     L19
  mov    %rax,%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strftime@plt>
  test   %eax,%eax
  je     L49
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L1
L49:
  mov    D1(%rip),%rax
  mov    (%rax),%edx
  mov    D8(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L1
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int current_time_str(char *str, size_t len, const char *fmt) {
  time_t t;
  struct tm *t_local;
  int ret;
  t = time(NULL);
  t_local = localtime(&t);
  if (!t_local) {
    errno = ETIME;
    return -1;
  }
  ret = strftime(str, len, fmt, t_local);
  if (ret == 0) {
    errno = ETIME;
    return -1;
  }
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<current_time_str>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  test   %rax,%rax
  je     L30
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strftime@plt>
  test   %eax,%eax
  je     L30
L35:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L30:
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    D19(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L35
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int current_time_str(char *str, size_t len, const char *fmt) {
  time_t t;
  struct tm *t_local;
  int ret;
  t = time(NULL);
  t_local = localtime(&t);
  if (!t_local) {
    errno = ETIME;
    return -1;
  }
  ret = strftime(str, len, fmt, t_local);
  if (ret == 0) {
    errno = ETIME;
    return -1;
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<current_time_str>:
  endbr64
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <time@plt>
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  test   %rax,%rax
  je     L10
  mov    %rax,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strftime@plt>
  test   %eax,%eax
  je     L10
L13:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L10:
  mov    D12(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L13
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int current_time_str(char *str, size_t len, const char *fmt) {
  time_t t;
  struct tm *t_local;
  int ret;
  t = time(NULL);
  t_local = localtime(&t);
  if (!t_local) {
    errno = ETIME;
    return -1;
  }
  ret = strftime(str, len, fmt, t_local);
  if (ret == 0) {
    errno = ETIME;
    return -1;
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L27
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
L27:
  cmpq   $0x0,-0x30(%rbp)
  je     L26
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
L26:
  cmpq   $0x0,-0x38(%rbp)
  je     L19
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
L19:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
void get_time(int *hour, int *min, int *sec) {
  struct timeval tv;
  struct tm *localTime = NULL;
  time_t actualTime;
  gettimeofday(&tv, 0);
  actualTime = tv.tv_sec;
  localTime = localtime(&actualTime);
  if (hour)
    *hour = localTime->tm_hour;
  if (min)
    *min = localTime->tm_min;
  if (sec)
    *sec = localTime->tm_sec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_time>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rsp),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdi
  call   <localtime@plt>
  test   %r12,%r12
  je     L28
  mov    (%rax),%edx
  mov    %edx,(%r12)
L28:
  test   %rbp,%rbp
  je     L35
  mov    0x4(%rax),%edx
  mov    %edx,0x0(%rbp)
L35:
  test   %rbx,%rbx
  je     L16
  mov    0x8(%rax),%eax
  mov    %eax,(%rbx)
L16:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_time(int *hour, int *min, int *sec) {
  struct timeval tv;
  struct tm *localTime = NULL;
  time_t actualTime;
  gettimeofday(&tv, 0);
  actualTime = tv.tv_sec;
  localTime = localtime(&actualTime);
  if (hour)
    *hour = localTime->tm_hour;
  if (min)
    *min = localTime->tm_min;
  if (sec)
    *sec = localTime->tm_sec;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_time>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%eax
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  test   %r12,%r12
  je     L19
  mov    (%rax),%edx
  mov    %edx,(%r12)
L19:
  test   %rbp,%rbp
  je     L5
  mov    0x4(%rax),%edx
  mov    %edx,0x0(%rbp)
L5:
  test   %rbx,%rbx
  je     L29
  mov    0x8(%rax),%eax
  mov    %eax,(%rbx)
L29:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_time(int *hour, int *min, int *sec) {
  struct timeval tv;
  struct tm *localTime = NULL;
  time_t actualTime;
  gettimeofday(&tv, 0);
  actualTime = tv.tv_sec;
  localTime = localtime(&actualTime);
  if (hour)
    *hour = localTime->tm_hour;
  if (min)
    *min = localTime->tm_min;
  if (sec)
    *sec = localTime->tm_sec;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_time>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  xor    %esi,%esi
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  mov    (%rsp),%eax
  lea    0x4(%rsp),%rdi
  mov    %eax,0x4(%rsp)
  call   <localtime@plt>
  test   %r12,%r12
  je     L29
  mov    (%rax),%edx
  mov    %edx,(%r12)
L29:
  test   %rbp,%rbp
  je     L30
  mov    0x4(%rax),%edx
  mov    %edx,0x0(%rbp)
L30:
  test   %rbx,%rbx
  je     L22
  mov    0x8(%rax),%eax
  mov    %eax,(%rbx)
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_time(int *hour, int *min, int *sec) {
  struct timeval tv;
  struct tm *localTime = NULL;
  time_t actualTime;
  gettimeofday(&tv, 0);
  actualTime = tv.tv_sec;
  localTime = localtime(&actualTime);
  if (hour)
    *hour = localTime->tm_hour;
  if (min)
    *min = localTime->tm_min;
  if (sec)
    *sec = localTime->tm_sec;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<compare_int_keys>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  test   %r12,%r12
  je     L13
  test   %rbx,%rbx
  je     L13
  mov    $0x1,%eax
  jmp    L1
L13:
  mov    $0x0,%eax
L1:
  mov    %eax,%edi
  call   <assert@plt>
  mov    (%r12),%eax
  mov    (%rbx),%edx
  sub    %edx,%eax
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  assert(key1 != NULL && key2 != NULL);
  return *((int *)key1) - *((int *)key2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compare_int_keys>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %rdi,%rdi
  setne  %al
  test   %rsi,%rsi
  setne  %dil
  movzbl %dil,%edi
  and    %eax,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  sub    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  assert(key1 != NULL && key2 != NULL);
  return *((int *)key1) - *((int *)key2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compare_int_keys>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  sub    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  assert(key1 != NULL && key2 != NULL);
  return *((int *)key1) - *((int *)key2);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<compare_int_keys>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  setne  %al
  xor    %edi,%edi
  test   %rsi,%rsi
  setne  %dil
  and    %eax,%edi
  call   <assert@plt>
  mov    0x0(%rbp),%eax
  sub    (%rbx),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int compare_int_keys(register void *key1, register void *key2) {
  assert(key1 != NULL && key2 != NULL);
  return *((int *)key1) - *((int *)key2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<R_modeShapeTet>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  cmpl   $0x3,-0x24(%rbp)
  jle    L135
  cmpl   $0x0,-0x28(%rbp)
  js     L135
  mov    -0x24(%rbp),%eax
  lea    -0x2(%rax),%edx
  mov    -0x24(%rbp),%eax
  sub    $0x3,%eax
  imul   %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x28(%rbp)
  jl     L145
L135:
  pxor   %xmm0,%xmm0
  jmp    L156
L145:
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L164
L147:
  movl   $0x0,-0x10(%rbp)
  jmp    L98
L101:
  movl   $0x0,-0xc(%rbp)
  jmp    L198
L23:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  add    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x24(%rbp),%eax
  sub    $0x4,%eax
  cmp    %eax,%edx
  jne    L207
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jne    L99
  movl   $0x1,-0x4(%rbp)
  jmp    L207
L99:
  addl   $0x1,-0x8(%rbp)
L207:
  cmpl   $0x0,-0x4(%rbp)
  jne    L200
  addl   $0x1,-0xc(%rbp)
L198:
  mov    -0x24(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L23
  jmp    L125
L200:
  nop
L125:
  cmpl   $0x0,-0x4(%rbp)
  jne    L36
  addl   $0x1,-0x10(%rbp)
L98:
  mov    -0x24(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0x10(%rbp)
  jl     L101
  jmp    L4
L36:
  nop
L4:
  cmpl   $0x0,-0x4(%rbp)
  jne    L121
  addl   $0x1,-0x14(%rbp)
L164:
  mov    -0x24(%rbp),%eax
  sub    $0x3,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L147
  jmp    L86
L121:
  nop
L86:
  cmpl   $0x0,-0x4(%rbp)
  je     L61
  mov    -0x30(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rsi
  mov    -0xc(%rbp),%edx
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%eax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rsi,%xmm0
  mov    %ecx,%esi
  mov    %eax,%edi
  mov    $0x3,%eax
  call   <Bn@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L156
L61:
  pxor   %xmm0,%xmm0
L156:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double R_modeShapeTet(int p, int i, double *L) {
  int alpha, beta, gamma, count, found;
  if (p < 4 || i < 0 || i > (((p - 2) * (p - 3) / 2) - 1))
    return 0.0;
  count = 0;
  found = 0;
  for (alpha = 0; alpha <= p - 4; alpha++) {
    for (beta = 0; beta <= p - 4; beta++) {
      for (gamma = 0; gamma <= p - 4; gamma++) {
        if (alpha + beta + gamma == p - 4) {
          if (count == i)
            found = 1;
          else
            count++;
        }
        if (found)
          break;
      }
      if (found)
        break;
    }
    if (found)
      break;
  }
  if (found)
    return Bn(alpha, beta, gamma, L[0], L[1], L[2]);
  else
    return 0.0;
}
```
user: What is the c source code of the assembly code below?

```asm
<R_modeShapeTet>:
  endbr64
  cmp    $0x3,%edi
  jle    L94
  push   %rbx
  mov    %esi,%r9d
  mov    %rdx,%rbx
  test   %esi,%esi
  js     L96
  lea    -0x3(%rdi),%esi
  lea    -0x2(%rdi),%edx
  imul   %esi,%edx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  pxor   %xmm0,%xmm0
  cmp    %r9d,%eax
  jle    L5
  mov    $0x0,%r8d
  mov    $0x0,%r11d
  sub    $0x4,%edi
  jmp    L62
L117:
  add    $0x1,%edx
  cmp    %edx,%esi
  jle    L64
L115:
  lea    (%rdx,%rcx,1),%eax
  cmp    %eax,%edi
  jne    L117
  cmp    %r8d,%r9d
  je     L32
  add    $0x1,%r8d
  jmp    L117
L96:
  pxor   %xmm0,%xmm0
  jmp    L5
L18:
  add    $0x1,%r11d
  cmp    %r11d,%esi
  jle    L114
L62:
  mov    %r11d,%ecx
  mov    $0x0,%r10d
  jmp    L20
L114:
  pxor   %xmm0,%xmm0
  jmp    L5
L32:
  movsd  0x10(%rbx),%xmm2
  movsd  0x8(%rbx),%xmm1
  movsd  (%rbx),%xmm0
  mov    %r10d,%esi
  mov    %r11d,%edi
  mov    $0x3,%eax
  call   <Bn@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L5:
  pop    %rbx
  ret
L64:
  add    $0x1,%r10d
  add    $0x1,%ecx
  cmp    %r10d,%esi
  jle    L18
L20:
  mov    $0x0,%edx
  jmp    L115
L94:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double R_modeShapeTet(int p, int i, double *L) {
  int alpha, beta, gamma, count, found;
  if (p < 4 || i < 0 || i > (((p - 2) * (p - 3) / 2) - 1))
    return 0.0;
  count = 0;
  found = 0;
  for (alpha = 0; alpha <= p - 4; alpha++) {
    for (beta = 0; beta <= p - 4; beta++) {
      for (gamma = 0; gamma <= p - 4; gamma++) {
        if (alpha + beta + gamma == p - 4) {
          if (count == i)
            found = 1;
          else
            count++;
        }
        if (found)
          break;
      }
      if (found)
        break;
    }
    if (found)
      break;
  }
  if (found)
    return Bn(alpha, beta, gamma, L[0], L[1], L[2]);
  else
    return 0.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<R_modeShapeTet>:
  endbr64
  cmp    $0x3,%edi
  jle    L45
  mov    %esi,%r9d
  test   %esi,%esi
  js     L45
  lea    -0x3(%rdi),%esi
  lea    -0x2(%rdi),%eax
  pxor   %xmm0,%xmm0
  imul   %esi,%eax
  sar    %eax
  cmp    %r9d,%eax
  jle    L44
  push   %rbx
  sub    $0x4,%edi
  mov    %rdx,%rbx
  xor    %r8d,%r8d
  xor    %r11d,%r11d
L70:
  mov    %r11d,%ecx
  xor    %r10d,%r10d
  nop
L22:
  xor    %edx,%edx
  jmp    L33
  nopl   0x0(%rax)
L53:
  add    $0x1,%edx
  cmp    %edx,%esi
  jle    L20
L33:
  lea    (%rdx,%rcx,1),%eax
  cmp    %edi,%eax
  jne    L53
  cmp    %r8d,%r9d
  je     L86
  add    $0x1,%edx
  add    $0x1,%r8d
  cmp    %edx,%esi
  jg     L33
L20:
  add    $0x1,%r10d
  add    $0x1,%ecx
  cmp    %r10d,%esi
  jg     L22
  add    $0x1,%r11d
  cmp    %r11d,%esi
  jg     L70
  pxor   %xmm0,%xmm0
  pop    %rbx
  ret
L44:
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  movsd  (%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mov    %r10d,%esi
  mov    %r11d,%edi
  movsd  0x8(%rbx),%xmm1
  mov    $0x3,%eax
  call   <Bn@plt>
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
L45:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double R_modeShapeTet(int p, int i, double *L) {
  int alpha, beta, gamma, count, found;
  if (p < 4 || i < 0 || i > (((p - 2) * (p - 3) / 2) - 1))
    return 0.0;
  count = 0;
  found = 0;
  for (alpha = 0; alpha <= p - 4; alpha++) {
    for (beta = 0; beta <= p - 4; beta++) {
      for (gamma = 0; gamma <= p - 4; gamma++) {
        if (alpha + beta + gamma == p - 4) {
          if (count == i)
            found = 1;
          else
            count++;
        }
        if (found)
          break;
      }
      if (found)
        break;
    }
    if (found)
      break;
  }
  if (found)
    return Bn(alpha, beta, gamma, L[0], L[1], L[2]);
  else
    return 0.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<R_modeShapeTet>:
  endbr64
  cmp    $0x3,%edi
  jle    L27
  mov    %esi,%r9d
  test   %esi,%esi
  js     L27
  lea    -0x3(%rdi),%esi
  lea    -0x2(%rdi),%eax
  pxor   %xmm0,%xmm0
  imul   %esi,%eax
  sar    %eax
  cmp    %r9d,%eax
  jle    L97
  push   %rbx
  sub    $0x4,%edi
  mov    %rdx,%rbx
  xor    %r8d,%r8d
  xor    %r11d,%r11d
L23:
  mov    %r11d,%ecx
  xor    %r10d,%r10d
  nop
L71:
  xor    %edx,%edx
  jmp    L35
  nopl   0x0(%rax)
L5:
  add    $0x1,%edx
  cmp    %edx,%esi
  jle    L58
L35:
  lea    (%rdx,%rcx,1),%eax
  cmp    %edi,%eax
  jne    L5
  cmp    %r8d,%r9d
  je     L10
  add    $0x1,%edx
  add    $0x1,%r8d
  cmp    %edx,%esi
  jg     L35
L58:
  add    $0x1,%r10d
  add    $0x1,%ecx
  cmp    %r10d,%esi
  jg     L71
  add    $0x1,%r11d
  cmp    %r11d,%esi
  jg     L23
  pxor   %xmm0,%xmm0
  pop    %rbx
  ret
L97:
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  movsd  (%rbx),%xmm0
  movsd  0x10(%rbx),%xmm2
  mov    %r10d,%esi
  mov    %r11d,%edi
  movsd  0x8(%rbx),%xmm1
  mov    $0x3,%eax
  call   <Bn@plt>
  pxor   %xmm0,%xmm0
  pop    %rbx
  cvtsi2sd %eax,%xmm0
  ret
L27:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double R_modeShapeTet(int p, int i, double *L) {
  int alpha, beta, gamma, count, found;
  if (p < 4 || i < 0 || i > (((p - 2) * (p - 3) / 2) - 1))
    return 0.0;
  count = 0;
  found = 0;
  for (alpha = 0; alpha <= p - 4; alpha++) {
    for (beta = 0; beta <= p - 4; beta++) {
      for (gamma = 0; gamma <= p - 4; gamma++) {
        if (alpha + beta + gamma == p - 4) {
          if (count == i)
            found = 1;
          else
            count++;
        }
        if (found)
          break;
      }
      if (found)
        break;
    }
    if (found)
      break;
  }
  if (found)
    return Bn(alpha, beta, gamma, L[0], L[1], L[2]);
  else
    return 0.0;
}
```