ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<longestPalindrome>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbx,%r13
  cmp    $0x1,%eax
  jle    L108
  mov    %eax,%r9d
  mov    $0x0,%esi
  mov    $0x0,%ebp
  mov    $0x0,%r12d
  lea    -0x1(%rax),%edi
  jmp    L134
L137:
  lea    0x1(%rcx),%r11d
  cmp    %ecx,%edi
  jle    L139
  test   %esi,%esi
  jle    L139
  lea    -0x1(%rsi),%eax
  cltq
  movslq %r11d,%rdx
L9:
  lea    -0x1(%rdx),%ecx
  lea    0x1(%rax),%esi
  movzbl (%rbx,%rax,1),%r8d
  cmp    %r8b,(%rbx,%rdx,1)
  jne    L139
  mov    %eax,%esi
  mov    %edx,%ecx
  cmp    %edx,%edi
  setg   %r10b
  test   %eax,%eax
  setg   %r8b
  sub    $0x1,%rax
  add    $0x1,%rdx
  test   %r8b,%r10b
  jne    L9
L139:
  sub    %esi,%ecx
  add    $0x1,%ecx
  cmp    %ebp,%ecx
  jle    L60
  mov    %ecx,%ebp
  mov    %esi,%r12d
L60:
  cmp    %r11d,%r9d
  jle    L80
  mov    %r9d,%edx
  sub    %r11d,%edx
  mov    %ebp,%eax
  shr    $0x1f,%eax
  add    %ebp,%eax
  sar    %eax
  cmp    %eax,%edx
  jle    L80
  mov    %r11d,%esi
L134:
  cmp    %esi,%edi
  jle    L17
  movslq %esi,%rax
  add    %rbx,%rax
  mov    %esi,%ecx
L21:
  movzbl (%rax),%edx
  cmp    %dl,0x1(%rax)
  jne    L137
  add    $0x1,%ecx
  add    $0x1,%rax
  cmp    %edi,%ecx
  jne    L21
  mov    %edi,%ecx
  jmp    L137
L80:
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  movslq %r12d,%r12
  lea    (%rbx,%r12,1),%rsi
  mov    %ebp,%edx
  mov    %rax,%rdi
  call   <memcpy@plt>
  movslq %ebp,%rbp
  movb   $0x0,0x0(%r13,%rbp,1)
L108:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L17:
  lea    0x1(%rsi),%r11d
  mov    %esi,%ecx
  jmp    L139
```

assistant: ```c
char *longestPalindrome(char *s) {
  int len = strlen(s);
  if (len < 2)
    return s;
  int start = 0, maxLen = 0;
  int l = 0, r = 0;
  for (int i = 0; i < len && len - i > maxLen / 2;) {
    l = r = i;
    while (r < len - 1 && s[r + 1] == s[r])
      r++;
    i = r + 1;
    while (l > 0 && r < len - 1 && s[r + 1] == s[l - 1])
      l--, r++;
    int len0 = r - l + 1;
    if (len0 > maxLen) {
      maxLen = len0;
      start = l;
    }
  }
  char *t = (char *)malloc(sizeof(char) * (maxLen + 1));
  memcpy(t, s + start, sizeof(char) * maxLen);
  t[maxLen] = '\0';
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<longestPalindrome>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%r13
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L4
  mov    %eax,%r10d
  lea    -0x1(%rax),%r8d
  xor    %ecx,%ecx
  xor    %ebp,%ebp
  xor    %r12d,%r12d
L149:
  cmp    %ecx,%r8d
  jle    L122
  movslq %ecx,%rdi
  mov    %ecx,%esi
  lea    (%rbx,%rdi,1),%rdx
  jmp    L59
  nopl   0x0(%rax)
L34:
  add    $0x1,%rdx
  cmp    %esi,%r8d
  je     L68
L59:
  mov    %esi,%eax
  movzbl (%rdx),%r11d
  lea    0x1(%rsi),%esi
  cmp    %r11b,0x1(%rdx)
  je     L34
  lea    0x1(%rax),%edx
  mov    %edx,%r11d
  test   %ecx,%ecx
  je     L17
L167:
  cmp    %r8d,%eax
  jge    L188
  movslq %edx,%rsi
  lea    -0x1(%rbx,%rdi,1),%rdi
  add    %rbx,%rsi
  jmp    L61
  nopl   0x0(%rax,%rax,1)
L43:
  sub    $0x1,%ecx
  je     L174
  add    $0x1,%rsi
  sub    $0x1,%rdi
  cmp    %edx,%r8d
  je     L111
  add    $0x1,%edx
L61:
  mov    %eax,%r9d
  movzbl (%rdi),%r13d
  mov    %edx,%eax
  cmp    %r13b,(%rsi)
  je     L43
  sub    %ecx,%r9d
  mov    %ecx,%eax
  mov    %r11d,%ecx
  add    $0x1,%r9d
L141:
  cmp    %r9d,%ebp
  jge    L81
  movslq %r9d,%rbp
  movslq %eax,%r12
L81:
  cmp    %r11d,%r10d
  jle    L172
  mov    %r10d,%edx
  mov    %ebp,%eax
  sub    %r11d,%edx
  sar    %eax
  cmp    %eax,%edx
  jg     L149
L172:
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  lea    (%rbx,%r12,1),%rsi
  mov    %ebp,%edx
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L4:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L68:
  mov    %r8d,%eax
  lea    0x1(%rax),%edx
  mov    %edx,%r11d
  test   %ecx,%ecx
  jne    L167
L17:
  mov    %edx,%r9d
  xor    %eax,%eax
  mov    %edx,%ecx
  jmp    L141
  nopw   0x0(%rax,%rax,1)
L174:
  add    $0x2,%r9d
  xor    %eax,%eax
  mov    %r11d,%ecx
  jmp    L141
  xchg   %ax,%ax
L111:
  mov    %r8d,%r9d
  mov    %ecx,%eax
  sub    %ecx,%r9d
  mov    %r11d,%ecx
  add    $0x1,%r9d
  jmp    L141
L122:
  lea    0x1(%rcx),%r11d
  mov    %ecx,%eax
L188:
  sub    %ecx,%eax
  mov    %eax,%r9d
  mov    %ecx,%eax
  mov    %r11d,%ecx
  add    $0x1,%r9d
  jmp    L141
```

assistant: ```c
char *longestPalindrome(char *s) {
  int len = strlen(s);
  if (len < 2)
    return s;
  int start = 0, maxLen = 0;
  int l = 0, r = 0;
  for (int i = 0; i < len && len - i > maxLen / 2;) {
    l = r = i;
    while (r < len - 1 && s[r + 1] == s[r])
      r++;
    i = r + 1;
    while (l > 0 && r < len - 1 && s[r + 1] == s[l - 1])
      l--, r++;
    int len0 = r - l + 1;
    if (len0 > maxLen) {
      maxLen = len0;
      start = l;
    }
  }
  char *t = (char *)malloc(sizeof(char) * (maxLen + 1));
  memcpy(t, s + start, sizeof(char) * maxLen);
  t[maxLen] = '\0';
  return t;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<longestPalindrome>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbx,%r13
  sub    $0x8,%rsp
  call   <strlen@plt>
  cmp    $0x1,%eax
  jle    L78
  mov    %eax,%r10d
  lea    -0x1(%rax),%r8d
  xor    %ecx,%ecx
  xor    %ebp,%ebp
  xor    %r12d,%r12d
L177:
  cmp    %ecx,%r8d
  jle    L81
  movslq %ecx,%r11
  mov    %ecx,%esi
  movzbl (%rbx,%r11,1),%edx
  lea    0x1(%rbx,%r11,1),%rdi
  jmp    L90
  nopw   0x0(%rax,%rax,1)
L110:
  add    $0x1,%rdi
  cmp    %esi,%r8d
  je     L50
L90:
  mov    %edx,%r9d
  movzbl (%rdi),%edx
  mov    %esi,%eax
  lea    0x1(%rsi),%esi
  cmp    %r9b,%dl
  je     L110
  lea    0x1(%rax),%edx
  mov    %edx,%r13d
  test   %ecx,%ecx
  je     L151
L71:
  cmp    %r8d,%eax
  jge    L140
  movslq %edx,%rsi
  lea    -0x1(%rbx,%r11,1),%rdi
  add    %rbx,%rsi
  jmp    L189
  nopl   0x0(%rax)
L2:
  sub    $0x1,%ecx
  je     L73
  add    $0x1,%rsi
  sub    $0x1,%rdi
  cmp    %edx,%r8d
  je     L4
  add    $0x1,%edx
L189:
  mov    %eax,%r9d
  movzbl (%rdi),%r11d
  mov    %edx,%eax
  cmp    %r11b,(%rsi)
  je     L2
  sub    %ecx,%r9d
  mov    %ecx,%eax
  mov    %r13d,%ecx
  add    $0x1,%r9d
L15:
  cmp    %r9d,%ebp
  jge    L18
  movslq %r9d,%rbp
  movslq %eax,%r12
L18:
  cmp    %r10d,%r13d
  jge    L120
  mov    %r10d,%edx
  mov    %ebp,%eax
  sub    %r13d,%edx
  sar    %eax
  cmp    %eax,%edx
  jg     L177
L120:
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  lea    (%rbx,%r12,1),%rsi
  mov    %ebp,%edx
  mov    %rax,%r13
  mov    %rax,%rdi
  call   <memcpy@plt>
  movb   $0x0,0x0(%r13,%rbp,1)
L78:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  xchg   %ax,%ax
L50:
  mov    %r8d,%eax
  lea    0x1(%rax),%edx
  mov    %edx,%r13d
  test   %ecx,%ecx
  jne    L71
L151:
  mov    %edx,%r9d
  xor    %eax,%eax
  mov    %edx,%ecx
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L73:
  add    $0x2,%r9d
  xor    %eax,%eax
  mov    %r13d,%ecx
  jmp    L15
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r8d,%r9d
  mov    %ecx,%eax
  sub    %ecx,%r9d
  mov    %r13d,%ecx
  add    $0x1,%r9d
  jmp    L15
L81:
  lea    0x1(%rcx),%r13d
  mov    %ecx,%eax
L140:
  sub    %ecx,%eax
  mov    %eax,%r9d
  mov    %ecx,%eax
  mov    %r13d,%ecx
  add    $0x1,%r9d
  jmp    L15
```

assistant: ```c
char *longestPalindrome(char *s) {
  int len = strlen(s);
  if (len < 2)
    return s;
  int start = 0, maxLen = 0;
  int l = 0, r = 0;
  for (int i = 0; i < len && len - i > maxLen / 2;) {
    l = r = i;
    while (r < len - 1 && s[r + 1] == s[r])
      r++;
    i = r + 1;
    while (l > 0 && r < len - 1 && s[r + 1] == s[l - 1])
      l--, r++;
    int len0 = r - l + 1;
    if (len0 > maxLen) {
      maxLen = len0;
      start = l;
    }
  }
  char *t = (char *)malloc(sizeof(char) * (maxLen + 1));
  memcpy(t, s + start, sizeof(char) * maxLen);
  t[maxLen] = '\0';
  return t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_n>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L9:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x28(%rbp),%rdx
  sub    %rcx,%rdx
  shl    $0x2,%rdx
  lea    -0x4(%rdx),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  ja     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void swap_n(void *in, void *out, size_t size) {
  int i;
  for (i = 0; i < size; i++)
    ((uint8_t *)out)[size - i - 1] = ((uint8_t *)in)[i];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<swap_n>:
  endbr64
  test   %rdx,%rdx
  je     L3
  lea    -0x4(%rsi,%rdx,4),%rax
L4:
  mov    (%rdi),%edx
  mov    %edx,(%rax)
  add    $0x4,%rdi
  mov    %rax,%rdx
  sub    $0x4,%rax
  cmp    %rsi,%rdx
  jne    L4
L3:
  ret
```

assistant: ```c
void swap_n(void *in, void *out, size_t size) {
  int i;
  for (i = 0; i < size; i++)
    ((uint8_t *)out)[size - i - 1] = ((uint8_t *)in)[i];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<swap_n>:
  endbr64
  test   %rdx,%rdx
  je     L12
  lea    -0x4(%rsi,%rdx,4),%rax
  xchg   %ax,%ax
L1:
  mov    (%rdi),%edx
  add    $0x4,%rdi
  mov    %edx,(%rax)
  mov    %rax,%rdx
  sub    $0x4,%rax
  cmp    %rsi,%rdx
  jne    L1
L12:
  ret
```

assistant: ```c
void swap_n(void *in, void *out, size_t size) {
  int i;
  for (i = 0; i < size; i++)
    ((uint8_t *)out)[size - i - 1] = ((uint8_t *)in)[i];
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<swap_n>:
  endbr64
  mov    %rdi,%rcx
  mov    %rsi,%rdi
  mov    %rdx,%rsi
  test   %rdx,%rdx
  je     L20
  lea    0x0(,%rdx,4),%rdx
  lea    (%rdi,%rdx,1),%rax
  lea    (%rcx,%rdx,1),%r8
  cmp    %rax,%rcx
  setae  %al
  cmp    %r8,%rdi
  setae  %r8b
  or     %r8b,%al
  je     L41
  lea    -0x1(%rsi),%rax
  cmp    $0x2,%rax
  jbe    L41
  mov    %rsi,%r8
  mov    %rcx,%rax
  lea    -0x10(%rdi,%rdx,1),%rdx
  shr    $0x2,%r8
  shl    $0x4,%r8
  add    %rcx,%r8
L56:
  movdqu (%rax),%xmm1
  add    $0x10,%rax
  sub    $0x10,%rdx
  pshufd $0x1b,%xmm1,%xmm0
  movups %xmm0,0x10(%rdx)
  cmp    %r8,%rax
  jne    L56
  mov    %rsi,%rax
  and    $0xfffffffffffffffc,%rax
  test   $0x3,%sil
  je     L20
  mov    (%rcx,%rax,4),%r8d
  mov    %rsi,%rdx
  sub    %rax,%rdx
  mov    %r8d,-0x4(%rdi,%rdx,4)
  lea    0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    %rdx,%rsi
  jbe    L20
  mov    (%rcx,%rdx,4),%r9d
  mov    %rsi,%r8
  add    $0x2,%eax
  lea    0x0(,%rdx,4),%r10
  sub    %rdx,%r8
  cltq
  mov    %r9d,-0x4(%rdi,%r8,4)
  cmp    %rax,%rsi
  jbe    L20
  mov    0x4(%rcx,%r10,1),%edx
  sub    %rax,%rsi
  mov    %edx,-0x4(%rdi,%rsi,4)
  ret
  nop
L41:
  lea    -0x4(%rdi,%rdx,1),%rax
  nopl   (%rax)
L58:
  mov    (%rcx),%edx
  add    $0x4,%rcx
  mov    %edx,(%rax)
  mov    %rax,%rdx
  sub    $0x4,%rax
  cmp    %rdi,%rdx
  jne    L58
L20:
  ret
```

assistant: ```c
void swap_n(void *in, void *out, size_t size) {
  int i;
  for (i = 0; i < size; i++)
    ((uint8_t *)out)[size - i - 1] = ((uint8_t *)in)[i];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cmd_bkgd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L7
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <bkgd@plt>
  mov    %eax,%edi
  call   <report_return@plt>
  jmp    L15
L7:
  nop
L15:
  leave
  ret
```

assistant: ```c
void cmd_bkgd(int nargs, char **args) {
  chtype *ch;
  if (check_arg_count(nargs, 1) == 1)
    return;
  ch = (chtype *)args[0];
  report_count(1);
  report_return(bkgd(ch[0]));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<cmd_bkgd>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L3
  mov    (%rbx),%rbx
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%edi
  call   <bkgd@plt>
  mov    %eax,%edi
  call   <report_return@plt>
L3:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_bkgd(int nargs, char **args) {
  chtype *ch;
  if (check_arg_count(nargs, 1) == 1)
    return;
  ch = (chtype *)args[0];
  report_count(1);
  report_return(bkgd(ch[0]));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cmd_bkgd>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L6
  mov    (%rbx),%rbx
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%edi
  call   <bkgd@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
  nopl   0x0(%rax,%rax,1)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_bkgd(int nargs, char **args) {
  chtype *ch;
  if (check_arg_count(nargs, 1) == 1)
    return;
  ch = (chtype *)args[0];
  report_count(1);
  report_return(bkgd(ch[0]));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmd_bkgd>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  mov    $0x1,%esi
  call   <check_arg_count@plt>
  cmp    $0x1,%eax
  je     L0
  mov    (%rbx),%rbx
  mov    $0x1,%edi
  call   <report_count@plt>
  mov    (%rbx),%edi
  call   <bkgd@plt>
  pop    %rbx
  mov    %eax,%edi
  jmp    1090 <report_return@plt>
  nopl   0x0(%rax,%rax,1)
L0:
  pop    %rbx
  ret
```

assistant: ```c
void cmd_bkgd(int nargs, char **args) {
  chtype *ch;
  if (check_arg_count(nargs, 1) == 1)
    return;
  ch = (chtype *)args[0];
  report_count(1);
  report_return(bkgd(ch[0]));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<resetbus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x0,%eax
  call   <setpin0@plt>
  mov    $0xed0,%edi
  call   <BusyWait@plt>
  mov    $0x0,%eax
  call   <setpinhiz@plt>
  mov    $0x229,%edi
  call   <BusyWait@plt>
  mov    $0x0,%eax
  call   <getpin@plt>
  test   %rax,%rax
  jne    L1
  movl   $0x1,-0x4(%rbp)
L1:
  mov    $0xca7,%edi
  call   <BusyWait@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
uint32_t resetbus(void) {
  uint32_t devicepresent = 0;
  setpin0();
  BusyWait(((uint32_t)(((((double)480 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  setpinhiz();
  BusyWait(((uint32_t)(((((double)70 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  if (getpin() == 0)
    devicepresent = 1;
  BusyWait(((uint32_t)(((((double)410 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  return devicepresent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<resetbus>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <setpin0@plt>
  mov    $0xed0,%edi
  call   <BusyWait@plt>
  mov    $0x0,%eax
  call   <setpinhiz@plt>
  mov    $0x229,%edi
  call   <BusyWait@plt>
  mov    $0x0,%eax
  call   <getpin@plt>
  mov    %rax,%rbx
  mov    $0xca7,%edi
  call   <BusyWait@plt>
  test   %rbx,%rbx
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  ret
```

assistant: ```c
uint32_t resetbus(void) {
  uint32_t devicepresent = 0;
  setpin0();
  BusyWait(((uint32_t)(((((double)480 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  setpinhiz();
  BusyWait(((uint32_t)(((((double)70 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  if (getpin() == 0)
    devicepresent = 1;
  BusyWait(((uint32_t)(((((double)410 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  return devicepresent;
}
```
user: Translate the below assembly code into C programming language:

```asm
<resetbus>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <setpin0@plt>
  mov    $0xed0,%edi
  call   <BusyWait@plt>
  xor    %eax,%eax
  call   <setpinhiz@plt>
  mov    $0x229,%edi
  call   <BusyWait@plt>
  xor    %eax,%eax
  call   <getpin@plt>
  mov    $0xca7,%edi
  mov    %rax,%rbx
  call   <BusyWait@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
uint32_t resetbus(void) {
  uint32_t devicepresent = 0;
  setpin0();
  BusyWait(((uint32_t)(((((double)480 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  setpinhiz();
  BusyWait(((uint32_t)(((((double)70 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  if (getpin() == 0)
    devicepresent = 1;
  BusyWait(((uint32_t)(((((double)410 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  return devicepresent;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<resetbus>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <setpin0@plt>
  mov    $0xed0,%edi
  call   <BusyWait@plt>
  xor    %eax,%eax
  call   <setpinhiz@plt>
  mov    $0x229,%edi
  call   <BusyWait@plt>
  xor    %eax,%eax
  call   <getpin@plt>
  mov    $0xca7,%edi
  mov    %rax,%rbx
  call   <BusyWait@plt>
  xor    %eax,%eax
  test   %rbx,%rbx
  pop    %rbx
  sete   %al
  ret
```

assistant: ```c
uint32_t resetbus(void) {
  uint32_t devicepresent = 0;
  setpin0();
  BusyWait(((uint32_t)(((((double)480 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  setpinhiz();
  BusyWait(((uint32_t)(((((double)70 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  if (getpin() == 0)
    devicepresent = 1;
  BusyWait(((uint32_t)(((((double)410 * (double)(5 * 11059200)) / ((double)(7) * 1000.0f * 1000.0f))) + 0.5f)));
  return devicepresent;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<logbl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <isnan@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  je     L57
  mov    0x10(%rbp),%rax
  mov    0x18(%rbp),%edx
  jmp    L56
L57:
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <isinf@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  je     L43
  mov    0x10(%rbp),%rax
  mov    0x18(%rbp),%edx
  jmp    L56
L43:
  fldt   0x10(%rbp)
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  jp     L1
  fldt   0x10(%rbp)
  fldz
  fucomip %st(1),%st
  fstp   %st(0)
  jne    L1
  mov    D19(%rip),%rax
  mov    (%rax),%edx
  mov    D11(%rip),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  mov    $0x0,%edx
  jmp    L56
L1:
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <__approx_log2l@plt>
  add    $0x10,%rsp
  fstpt  -0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%edx
L56:
  mov    %rax,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  fldt   -0x10(%rbp)
  leave
  ret
```

assistant: ```c
long double logbl(long double x) {
  if (isnan(x))
    return x;
  if (isinf(x))
    return x;
  if (!x) {
    errno = ERANGE;
    return 0;
  }
  return __approx_log2l(x);
}
```
user: What is the c source code of the assembly code below?

```asm
<logbl>:
  endbr64
  sub    $0x8,%rsp
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <isnan@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  je     L30
L55:
  fldt   0x10(%rsp)
  add    $0x8,%rsp
  ret
L30:
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <isinf@plt>
  add    $0x10,%rsp
  test   %rax,%rax
  jne    L55
  fldz
  fldt   0x10(%rsp)
  fucomip %st(1),%st
  jp     L68
  jne    L51
  mov    D0(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    %edx,(%rax)
  fstpt  0x10(%rsp)
  jmp    L55
L68:
  fstp   %st(0)
  jmp    L49
L51:
  fstp   %st(0)
L49:
  push   0x18(%rsp)
  push   0x18(%rsp)
  call   <__approx_log2l@plt>
  fstpt  0x20(%rsp)
  add    $0x10,%rsp
  jmp    L55
```

assistant: ```c
long double logbl(long double x) {
  if (isnan(x))
    return x;
  if (isinf(x))
    return x;
  if (!x) {
    errno = ERANGE;
    return 0;
  }
  return __approx_log2l(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logbl>:
  endbr64
  sub    $0x28,%rsp
  fldt   0x30(%rsp)
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x10(%rsp)
  call   <isnan@plt>
  pop    %rsi
  pop    %rdi
  fldt   (%rsp)
  test   %rax,%rax
  je     L39
L18:
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L39:
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <isinf@plt>
  pop    %rdx
  pop    %rcx
  fldt   (%rsp)
  test   %rax,%rax
  jne    L18
  fldz
  fld    %st(0)
  fxch   %st(2)
  fucomi %st(2),%st
  fstp   %st(2)
  jp     L33
  jne    L40
  fstp   %st(1)
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D4(%rip),%rax
  mov    %edx,(%rax)
  add    $0x18,%rsp
  ret
L33:
  fstp   %st(0)
  jmp    L49
  nopl   0x0(%rax)
L40:
  fstp   %st(0)
L49:
  fstpt  0x20(%rsp)
  add    $0x18,%rsp
  jmp    1080 <__approx_log2l@plt>
```

assistant: ```c
long double logbl(long double x) {
  if (isnan(x))
    return x;
  if (isinf(x))
    return x;
  if (!x) {
    errno = ERANGE;
    return 0;
  }
  return __approx_log2l(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logbl>:
  endbr64
  sub    $0x28,%rsp
  fldt   0x30(%rsp)
  fld    %st(0)
  fstpt  (%rsp)
  fstpt  0x10(%rsp)
  call   <isnan@plt>
  pop    %rsi
  pop    %rdi
  fldt   (%rsp)
  test   %rax,%rax
  je     L36
L20:
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L36:
  sub    $0x10,%rsp
  fstpt  (%rsp)
  call   <isinf@plt>
  pop    %rdx
  pop    %rcx
  fldt   (%rsp)
  test   %rax,%rax
  jne    L20
  fldz
  fld    %st(0)
  fxch   %st(2)
  fucomi %st(2),%st
  fstp   %st(2)
  jp     L40
  jne    L6
  fstp   %st(1)
  mov    D15(%rip),%rax
  mov    (%rax),%edx
  mov    D0(%rip),%rax
  mov    %edx,(%rax)
  add    $0x18,%rsp
  ret
L40:
  fstp   %st(0)
  jmp    L28
  nopl   0x0(%rax)
L6:
  fstp   %st(0)
L28:
  fstpt  0x20(%rsp)
  add    $0x18,%rsp
  jmp    1080 <__approx_log2l@plt>
```

assistant: ```c
long double logbl(long double x) {
  if (isnan(x))
    return x;
  if (isinf(x))
    return x;
  if (!x) {
    errno = ERANGE;
    return 0;
  }
  return __approx_log2l(x);
}
```
user: What is the c source code of the assembly code below:

```asm
<printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  call   <vFormatPrintString@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vFormatPrintString((void *)putchar, 0, fmt, ap);
  va_end(ap);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<printf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    D8(%rip),%rax
  mov    (%rax),%rdi
  call   <vFormatPrintString@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int printf(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vFormatPrintString((void *)putchar, 0, fmt, ap);
  va_end(ap);
  return 0;
}
```