ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<optk_rename>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L26
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <access@plt>
  test   %rax,%rax
  js     L26
  mov    $0xffffffff,%eax
  jmp    L18
L26:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <rename@plt>
L18:
  leave
  ret
```

assistant: ```c
int optk_rename(const char *src_path, const char *dest_path, int clobber) {
  if (!clobber) {
    if (access(dest_path, 0) >= 0)
      return -1;
  }
  return rename(src_path, dest_path);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<optk_rename>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %edx,%edx
  jne    L1
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <access@plt>
  test   %rax,%rax
  jns    L17
L1:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <rename@plt>
L13:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0xffffffff,%eax
  jmp    L13
```

assistant: ```c
int optk_rename(const char *src_path, const char *dest_path, int clobber) {
  if (!clobber) {
    if (access(dest_path, 0) >= 0)
      return -1;
  }
  return rename(src_path, dest_path);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<optk_rename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L7
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  jns    L8
L7:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <rename@plt>
L8:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int optk_rename(const char *src_path, const char *dest_path, int clobber) {
  if (!clobber) {
    if (access(dest_path, 0) >= 0)
      return -1;
  }
  return rename(src_path, dest_path);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<optk_rename>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L16
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <access@plt>
  test   %rax,%rax
  jns    L19
L16:
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  pop    %r12
  jmp    1070 <rename@plt>
L19:
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int optk_rename(const char *src_path, const char *dest_path, int clobber) {
  if (!clobber) {
    if (access(dest_path, 0) >= 0)
      return -1;
  }
  return rename(src_path, dest_path);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<UARTIntEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%rdx
  add    $0x38,%rdx
  or     -0x10(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void UARTIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000038))) |= ulIntFlags;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<UARTIntEnable>:
  endbr64
  mov    0x38(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x38(%rdi)
  ret
```

assistant: ```c
void UARTIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000038))) |= ulIntFlags;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<UARTIntEnable>:
  endbr64
  mov    0x38(%rdi),%rax
  or     %rsi,%rax
  mov    %rax,0x38(%rdi)
  ret
```

assistant: ```c
void UARTIntEnable(unsigned long ulBase, unsigned long ulIntFlags) {
  ;
  (*((volatile unsigned long *)(ulBase + 0x00000038))) |= ulIntFlags;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<allocated_variable_expand_for_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%eax
  call   <save_variable_output@plt>
  cltq
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <variable_expand_for_file@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <savestring@plt>
  cltq
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <restore_variable_output@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *allocated_variable_expand_for_file(line, file)
char *line;
struct file *file;
{
  char *save;
  char *value;
  save = save_variable_output();
  value = variable_expand_for_file(line, file);
  value = savestring(value, strlen(value));
  restore_variable_output(save);
  return value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<allocated_variable_expand_for_file>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    $0x0,%eax
  call   <save_variable_output@plt>
  mov    %eax,%ebp
  mov    %r12,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <variable_expand_for_file@plt>
  movslq %eax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <savestring@plt>
  mov    %eax,%ebx
  movslq %ebp,%rdi
  mov    $0x0,%eax
  call   <restore_variable_output@plt>
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *allocated_variable_expand_for_file(line, file)
char *line;
struct file *file;
{
  char *save;
  char *value;
  save = save_variable_output();
  value = variable_expand_for_file(line, file);
  value = savestring(value, strlen(value));
  restore_variable_output(save);
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<allocated_variable_expand_for_file>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <save_variable_output@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <variable_expand_for_file@plt>
  movslq %eax,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <savestring@plt>
  movslq %ebp,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <restore_variable_output@plt>
  add    $0x8,%rsp
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *allocated_variable_expand_for_file(line, file)
char *line;
struct file *file;
{
  char *save;
  char *value;
  save = save_variable_output();
  value = variable_expand_for_file(line, file);
  value = savestring(value, strlen(value));
  restore_variable_output(save);
  return value;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<allocated_variable_expand_for_file>:
  endbr64
  push   %r13
  xor    %eax,%eax
  mov    %rsi,%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <save_variable_output@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <variable_expand_for_file@plt>
  movslq %eax,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <savestring@plt>
  movslq %ebp,%rdi
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <restore_variable_output@plt>
  add    $0x8,%rsp
  movslq %ebx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *allocated_variable_expand_for_file(line, file)
char *line;
struct file *file;
{
  char *save;
  char *value;
  save = save_variable_output();
  value = variable_expand_for_file(line, file);
  value = savestring(value, strlen(value));
  restore_variable_output(save);
  return value;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__acpi_acquire_global_lock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0xfffffffc,%eax
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  shr    %eax
  and    $0x1,%eax
  or     %edx,%eax
  add    $0x2,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    $0x4,%ecx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <__cmpxchg@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  setne  %al
  movzbl %al,%eax
  test   %rax,%rax
  jne    L15
  cmpl   $0x2,-0x8(%rbp)
  ja     L6
  mov    $0xffffffff,%eax
  jmp    L3
L6:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int __acpi_acquire_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = (((old & ~0x3) + 2) + ((old >> 1) & 0x1));
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect((val != old), 0));
  return (new < 3) ? -1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__acpi_acquire_global_lock>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
L4:
  mov    (%r12),%ebp
  mov    %ebp,%ebx
  shr    %ebx
  and    $0x1,%ebx
  mov    %ebp,%eax
  and    $0xfffffffc,%eax
  or     %eax,%ebx
  add    $0x2,%ebx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    $0x4,%ecx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <__cmpxchg@plt>
  cmp    %eax,%ebp
  jne    L4
  cmp    $0x3,%ebx
  sbb    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int __acpi_acquire_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = (((old & ~0x3) + 2) + ((old >> 1) & 0x1));
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect((val != old), 0));
  return (new < 3) ? -1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__acpi_acquire_global_lock>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
L8:
  mov    (%r12),%esi
  mov    $0x4,%ecx
  mov    %r12,%rdi
  mov    %esi,%ebx
  mov    %esi,%eax
  mov    %rsi,%rbp
  shr    %ebx
  and    $0xfffffffc,%eax
  and    $0x1,%ebx
  or     %eax,%ebx
  xor    %eax,%eax
  lea    0x2(%rbx),%edx
  mov    %rdx,%rbx
  call   <__cmpxchg@plt>
  cmp    %eax,%ebp
  jne    L8
  cmp    $0x3,%ebx
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int __acpi_acquire_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = (((old & ~0x3) + 2) + ((old >> 1) & 0x1));
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect((val != old), 0));
  return (new < 3) ? -1 : 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__acpi_acquire_global_lock>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
L7:
  mov    (%r12),%esi
  mov    $0x4,%ecx
  mov    %r12,%rdi
  mov    %esi,%ebx
  mov    %esi,%eax
  mov    %rsi,%rbp
  shr    %ebx
  and    $0xfffffffc,%eax
  and    $0x1,%ebx
  or     %eax,%ebx
  xor    %eax,%eax
  lea    0x2(%rbx),%edx
  mov    %rdx,%rbx
  call   <__cmpxchg@plt>
  cmp    %eax,%ebp
  jne    L7
  cmp    $0x3,%ebx
  pop    %rbx
  pop    %rbp
  sbb    %eax,%eax
  pop    %r12
  ret
```

assistant: ```c
int __acpi_acquire_global_lock(unsigned int *lock) {
  unsigned int old, new, val;
  do {
    old = *lock;
    new = (((old & ~0x3) + 2) + ((old >> 1) & 0x1));
    val = ((__typeof__(*(lock)))__cmpxchg((lock), (unsigned long)(old), (unsigned long)(new), sizeof(*(lock))));
  } while (__builtin_expect((val != old), 0));
  return (new < 3) ? -1 : 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x811c9dc5,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L8:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  xor    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  imul   $0x1000193,%eax,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x10(%rbp),%eax
  cqto
  idivq  -0x28(%rbp)
  mov    %rdx,%rax
  leave
  ret
```

assistant: ```c
unsigned int hash(void *f1, int size, long long max) {
  char *f = *(char **)f1;
  unsigned int hash = 2166136261;
  size = strlen(f);
  for (int i = 0; i < size; i++) {
    hash = hash ^ *(f + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdx,%rbx
  mov    (%rdi),%rbp
  mov    %rbp,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L17
  mov    %rbp,%rdx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%rsi
  mov    $0x811c9dc5,%eax
L0:
  movsbl (%rdx),%ecx
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L0
L2:
  mov    %eax,%eax
  cqto
  idiv   %rbx
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x811c9dc5,%eax
  jmp    L2
```

assistant: ```c
unsigned int hash(void *f1, int size, long long max) {
  char *f = *(char **)f1;
  unsigned int hash = 2166136261;
  size = strlen(f);
  for (int i = 0; i < size; i++) {
    hash = hash ^ *(f + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    $0x811c9dc5,%eax
  test   %ecx,%ecx
  jle    L19
  lea    -0x1(%rcx),%eax
  mov    %rbx,%rdx
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x811c9dc5,%eax
  nopl   0x0(%rax,%rax,1)
L3:
  movsbl (%rdx),%ecx
  add    $0x1,%rdx
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  cmp    %rdx,%rsi
  jne    L3
L19:
  cqto
  add    $0x8,%rsp
  idiv   %rbp
  pop    %rbx
  pop    %rbp
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash(void *f1, int size, long long max) {
  char *f = *(char **)f1;
  unsigned int hash = 2166136261;
  size = strlen(f);
  for (int i = 0; i < size; i++) {
    hash = hash ^ *(f + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    $0x811c9dc5,%eax
  test   %ecx,%ecx
  jle    L0
  lea    -0x1(%rcx),%eax
  mov    %rbx,%rdx
  lea    0x1(%rbx,%rax,1),%rsi
  mov    $0x811c9dc5,%eax
  nopl   0x0(%rax,%rax,1)
L10:
  movsbl (%rdx),%ecx
  add    $0x1,%rdx
  xor    %ecx,%eax
  imul   $0x1000193,%eax,%eax
  cmp    %rdx,%rsi
  jne    L10
L0:
  cqto
  add    $0x8,%rsp
  idiv   %rbp
  pop    %rbx
  pop    %rbp
  mov    %edx,%eax
  ret
```

assistant: ```c
unsigned int hash(void *f1, int size, long long max) {
  char *f = *(char **)f1;
  unsigned int hash = 2166136261;
  size = strlen(f);
  for (int i = 0; i < size; i++) {
    hash = hash ^ *(f + i);
    hash = hash * 16777619;
  }
  return hash % max;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_108_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x14(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x10(%rbp),%eax
  xor    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_108_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xrop3_108_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_108_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_108_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_108_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xrop3_108_0_0>:
  endbr64
  movzbl %dil,%edi
  movzbl %sil,%eax
  mov    %edi,%edx
  shl    $0x8,%edx
  or     %edi,%edx
  xor    %edx,%eax
  ret
```

assistant: ```c
unsigned xrop3_108_0_0(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  stk2 = D & T;
  stk1 = S ^ stk2;
  return stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<TtlUnmarshal_uint16_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  lea    0x8(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void TtlUnmarshal_uint16_t(uint8_t **cursor, uint16_t *x) {
  uint8_t *buffer = *cursor;
  *x = ((buffer[0] << 8) | (buffer[1] << 0));
  *cursor += 2;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<TtlUnmarshal_uint16_t>:
  endbr64
  mov    (%rdi),%rdx
  mov    (%rdx),%eax
  shl    $0x8,%eax
  or     0x4(%rdx),%eax
  mov    %eax,(%rsi)
  addq   $0x8,(%rdi)
  ret
```

assistant: ```c
void TtlUnmarshal_uint16_t(uint8_t **cursor, uint16_t *x) {
  uint8_t *buffer = *cursor;
  *x = ((buffer[0] << 8) | (buffer[1] << 0));
  *cursor += 2;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TtlUnmarshal_uint16_t>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%edx
  add    $0x8,%rax
  shl    $0x8,%edx
  or     -0x4(%rax),%edx
  mov    %edx,(%rsi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void TtlUnmarshal_uint16_t(uint8_t **cursor, uint16_t *x) {
  uint8_t *buffer = *cursor;
  *x = ((buffer[0] << 8) | (buffer[1] << 0));
  *cursor += 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<TtlUnmarshal_uint16_t>:
  endbr64
  mov    (%rdi),%rax
  mov    (%rax),%edx
  add    $0x8,%rax
  shl    $0x8,%edx
  or     -0x4(%rax),%edx
  mov    %edx,(%rsi)
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void TtlUnmarshal_uint16_t(uint8_t **cursor, uint16_t *x) {
  uint8_t *buffer = *cursor;
  *x = ((buffer[0] << 8) | (buffer[1] << 0));
  *cursor += 2;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uninitvar_wprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    -0x1c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  nop
  leave
  ret
```

assistant: ```c
void uninitvar_wprintf(wchar_t *Format, int Argument) {
  const wchar_t *format1, *format2, *format3;
  int argument1, argument2;
  (void)wprintf(format1, argument1);
  (void)wprintf(format2);
  (void)wprintf(Format, argument2);
  (void)wprintf(format3, Argument);
  (void)wprintf(Format, Argument);
  (void)wprintf(Format);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<uninitvar_wprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    $0x0,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    $0x0,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    %ebp,%esi
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <wprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void uninitvar_wprintf(wchar_t *Format, int Argument) {
  const wchar_t *format1, *format2, *format3;
  int argument1, argument2;
  (void)wprintf(format1, argument1);
  (void)wprintf(format2);
  (void)wprintf(Format, argument2);
  (void)wprintf(format3, Argument);
  (void)wprintf(Format, Argument);
  (void)wprintf(Format);
}
```
user: What is the c source code of the assembly code below:

```asm
<uninitvar_wprintf>:
  endbr64
  push   %r12
  xor    %eax,%eax
  mov    %esi,%r12d
  xor    %esi,%esi
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <wprintf@plt>
  xor    %edi,%edi
  xor    %eax,%eax
  call   <wprintf@plt>
  mov    %rbp,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <wprintf@plt>
  mov    %r12d,%esi
  xor    %edi,%edi
  xor    %eax,%eax
  call   <wprintf@plt>
  mov    %rbp,%rdi
  mov    %r12d,%esi
  xor    %eax,%eax
  call   <wprintf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  jmp    1050 <wprintf@plt>
```

assistant: ```c
void uninitvar_wprintf(wchar_t *Format, int Argument) {
  const wchar_t *format1, *format2, *format3;
  int argument1, argument2;
  (void)wprintf(format1, argument1);
  (void)wprintf(format2);
  (void)wprintf(Format, argument2);
  (void)wprintf(format3, Argument);
  (void)wprintf(Format, Argument);
  (void)wprintf(Format);
}
```