ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<pr_exit>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <WIFEXITED@plt>
  test   %rax,%rax
  je     L15
  mov    %ebx,%edi
  call   <WEXITSTATUS@plt>
  mov    %eax,%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  pop    %rbx
  ret
L15:
  mov    %ebx,%edi
  call   <WIFSIGNALED@plt>
  test   %rax,%rax
  je     L42
  mov    %ebx,%edi
  call   <WTERMSIG@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rdx
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L42:
  mov    %ebx,%edi
  call   <WIFSTOPPEN@plt>
  test   %rax,%rax
  je     L24
  mov    %ebx,%edi
  call   <WSTOPSIG@plt>
  mov    %eax,%esi
  lea    D28(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D33
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D28
type_guessed: string

tool: D33: normal termination, exit status = %d


tool: 

tool: D23: abnormal termination, signal number = %d%s


tool: D28: child stopped, signal number = %d


assistant: ```c
void pr_exit(int status) {
  if (WIFEXITED(status))
    printf("normal termination, exit status = %d\n", WEXITSTATUS(status));
  else if (WIFSIGNALED(status))
    printf("abnormal termination, signal number = %d%s\n", WTERMSIG(status), "");
  else if (WIFSTOPPEN(status))
    printf("child stopped, signal number = %d\n", WSTOPSIG(status));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pr_exit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <WIFEXITED@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L3
  call   <WEXITSTATUS@plt>
  lea    D39(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L3:
  call   <WIFSIGNALED@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L12
  call   <WTERMSIG@plt>
  lea    D18(%rip),%rdx
  lea    D36(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L12:
  call   <WIFSTOPPEN@plt>
  test   %rax,%rax
  jne    L25
  pop    %rbp
  ret
  nopl   0x0(%rax)
L25:
  mov    %ebp,%edi
  call   <WSTOPSIG@plt>
  lea    D2(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D39
datatype: string
name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D36
datatype: string
name: parse_data
arguments: data_tag: D2
datatype: string

tool: D39: normal termination, exit status = %d


tool: 

tool: D36: abnormal termination, signal number = %d%s


tool: D2: child stopped, signal number = %d


assistant: ```c
void pr_exit(int status) {
  if (WIFEXITED(status))
    printf("normal termination, exit status = %d\n", WEXITSTATUS(status));
  else if (WIFSIGNALED(status))
    printf("abnormal termination, signal number = %d%s\n", WTERMSIG(status), "");
  else if (WIFSTOPPEN(status))
    printf("child stopped, signal number = %d\n", WSTOPSIG(status));
}
```
user: Translate the below assembly code into C programming language:

```asm
<pr_exit>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <WIFEXITED@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L0
  call   <WEXITSTATUS@plt>
  lea    D1(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L0:
  call   <WIFSIGNALED@plt>
  mov    %ebp,%edi
  test   %rax,%rax
  je     L29
  call   <WTERMSIG@plt>
  lea    D21(%rip),%rdx
  lea    D11(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
  nopl   0x0(%rax)
L29:
  call   <WIFSTOPPEN@plt>
  test   %rax,%rax
  jne    L26
  pop    %rbp
  ret
  nopl   0x0(%rax)
L26:
  mov    %ebp,%edi
  call   <WSTOPSIG@plt>
  lea    D31(%rip),%rdi
  pop    %rbp
  mov    %eax,%esi
  xor    %eax,%eax
  jmp    10b0 <printf@plt>
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D21
datatype: string
name: parse_data
arguments: label: D11
datatype: string
name: parse_data
arguments: label: D31
datatype: string

tool: D1: normal termination, exit status = %d


tool: 

tool: D11: abnormal termination, signal number = %d%s


tool: D31: child stopped, signal number = %d


assistant: ```c
void pr_exit(int status) {
  if (WIFEXITED(status))
    printf("normal termination, exit status = %d\n", WEXITSTATUS(status));
  else if (WIFSIGNALED(status))
    printf("abnormal termination, signal number = %d%s\n", WTERMSIG(status), "");
  else if (WIFSTOPPEN(status))
    printf("child stopped, signal number = %d\n", WSTOPSIG(status));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<BASM_Parse_IsWhiteOnly>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L32
L25:
  addq   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L25
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L158
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L158
  mov    $0x0,%eax
  jmp    L127
L158:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L123
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L123
  mov    $0x0,%eax
  jmp    L127
L123:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2a,%al
  jne    L114
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jne    L114
  mov    $0x0,%eax
  jmp    L127
L114:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jle    L108
  mov    $0x1,%eax
  jmp    L127
L108:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L96
  mov    $0x1,%eax
  jmp    L127
L96:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  jne    L164
  mov    $0x1,%eax
  jmp    L127
L164:
  mov    $0x0,%eax
L127:
  pop    %rbp
  ret
```

assistant: ```c
int BASM_Parse_IsWhiteOnly(char *s) {
  while ((*s == ' ') || (*s == '\t'))
    s++;
  if ((s[0] == '/') && (s[1] == '/'))
    return (0);
  if ((s[0] == '/') && (s[1] == '*'))
    return (0);
  if ((s[0] == '*') && (s[1] == '/'))
    return (0);
  if (*s > ' ')
    return (1);
  if (*s == ' ')
    return (1);
  if (*s == '\t')
    return (1);
  return (0);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BASM_Parse_IsWhiteOnly>:
  endbr64
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L39
  cmp    $0x9,%dl
  jne    L81
L39:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L39
  cmp    $0x9,%dl
  je     L39
L81:
  cmp    $0x2f,%dl
  je     L67
  cmp    $0x2a,%dl
  je     L34
L36:
  cmp    $0x9,%dl
  sete   %al
  cmp    $0x1f,%dl
  setg   %dl
  or     %edx,%eax
  movzbl %al,%eax
L87:
  ret
L67:
  movzbl 0x1(%rdi),%ecx
  mov    $0x0,%eax
  cmp    $0x2f,%cl
  je     L87
  cmp    $0x2a,%cl
  jne    L36
  ret
L34:
  mov    $0x0,%eax
  cmpb   $0x2f,0x1(%rdi)
  jne    L36
  jmp    L87
```

assistant: ```c
int BASM_Parse_IsWhiteOnly(char *s) {
  while ((*s == ' ') || (*s == '\t'))
    s++;
  if ((s[0] == '/') && (s[1] == '/'))
    return (0);
  if ((s[0] == '/') && (s[1] == '*'))
    return (0);
  if ((s[0] == '*') && (s[1] == '/'))
    return (0);
  if (*s > ' ')
    return (1);
  if (*s == ' ')
    return (1);
  if (*s == '\t')
    return (1);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<BASM_Parse_IsWhiteOnly>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L44
  cmp    $0x20,%al
  jne    L72
  nop
L44:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  je     L44
  cmp    $0x9,%al
  je     L44
L72:
  cmp    $0x2f,%al
  je     L86
  cmp    $0x2a,%al
  je     L74
L66:
  xor    %r8d,%r8d
  cmp    $0x20,%al
  setg   %r8b
L5:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L74:
  xor    %r8d,%r8d
  cmpb   $0x2f,0x1(%rdi)
  setne  %r8b
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L86:
  movzbl 0x1(%rdi),%edx
  xor    %r8d,%r8d
  cmp    $0x2f,%dl
  je     L5
  cmp    $0x2a,%dl
  jne    L66
  jmp    L5
```

assistant: ```c
int BASM_Parse_IsWhiteOnly(char *s) {
  while ((*s == ' ') || (*s == '\t'))
    s++;
  if ((s[0] == '/') && (s[1] == '/'))
    return (0);
  if ((s[0] == '/') && (s[1] == '*'))
    return (0);
  if ((s[0] == '*') && (s[1] == '/'))
    return (0);
  if (*s > ' ')
    return (1);
  if (*s == ' ')
    return (1);
  if (*s == '\t')
    return (1);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BASM_Parse_IsWhiteOnly>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0x9,%al
  je     L32
  cmp    $0x20,%al
  jne    L75
  nop
L32:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0x20,%al
  je     L32
  cmp    $0x9,%al
  je     L32
L75:
  cmp    $0x2f,%al
  je     L19
  cmp    $0x2a,%al
  je     L53
L71:
  xor    %r8d,%r8d
  cmp    $0x20,%al
  setg   %r8b
L36:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L53:
  xor    %r8d,%r8d
  cmpb   $0x2f,0x1(%rdi)
  setne  %r8b
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  movzbl 0x1(%rdi),%edx
  xor    %r8d,%r8d
  cmp    $0x2f,%dl
  je     L36
  cmp    $0x2a,%dl
  jne    L71
  jmp    L36
```

assistant: ```c
int BASM_Parse_IsWhiteOnly(char *s) {
  while ((*s == ' ') || (*s == '\t'))
    s++;
  if ((s[0] == '/') && (s[1] == '/'))
    return (0);
  if ((s[0] == '/') && (s[1] == '*'))
    return (0);
  if ((s[0] == '*') && (s[1] == '/'))
    return (0);
  if (*s > ' ')
    return (1);
  if (*s == ' ')
    return (1);
  if (*s == '\t')
    return (1);
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cr250>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x67,-0x8(%rbp)
  movl   $0xfa,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L29
L4:
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0xc(%rbp),%esi
  mov    -0x4(%rbp),%eax
  add    %esi,%eax
  cltq
  lea    0x0(,%rax,4),%rsi
  mov    -0x18(%rbp),%rax
  add    %rsi,%rax
  xor    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  D4(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L29:
  cmpl   $0x63,-0xc(%rbp)
  jle    L4
  movl   $0x0,-0xc(%rbp)
  jmp    L18
L0:
  mov    -0xc(%rbp),%eax
  cltq
  add    $0x64,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L18:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L0
  nop
  nop
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: f64

tool: D4: 2147483648

assistant: ```c
void cr250(int *locSeed, double *locRandNums) {
  int i;
  int q = 103, p = 250;
  for (i = 0; i < 100; i++) {
    locSeed[i + p] = locSeed[i + p - q] ^ locSeed[i];
    locRandNums[i] = (double)(locSeed[i + p] / 2147483648.0);
  }
  for (i = 0; i < p; i++)
    locSeed[i] = locSeed[i + 100];
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<cr250>:
  endbr64
  mov    $0x0,%eax
  movsd  D2(%rip),%xmm1
L9:
  mov    0x24c(%rdi,%rax,4),%edx
  xor    (%rdi,%rax,4),%edx
  mov    %edx,0x3e8(%rdi,%rax,4)
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L9
  mov    %rdi,%rax
  add    $0x3e8,%rdi
L11:
  mov    0x190(%rax),%edx
  mov    %edx,(%rax)
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L11
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type_infered: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e]}

assistant: ```c
void cr250(int *locSeed, double *locRandNums) {
  int i;
  int q = 103, p = 250;
  for (i = 0; i < 100; i++) {
    locSeed[i + p] = locSeed[i + p - q] ^ locSeed[i];
    locRandNums[i] = (double)(locSeed[i + p] / 2147483648.0);
  }
  for (i = 0; i < p; i++)
    locSeed[i] = locSeed[i + 100];
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cr250>:
  endbr64
  movsd  D3(%rip),%xmm1
  xor    %eax,%eax
  xchg   %ax,%ax
L7:
  mov    0x24c(%rdi,%rax,4),%edx
  pxor   %xmm0,%xmm0
  xor    (%rdi,%rax,4),%edx
  cvtsi2sd %edx,%xmm0
  mov    %edx,0x3e8(%rdi,%rax,4)
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L7
  lea    0x190(%rdi),%rsi
  mov    $0x3e8,%edx
  jmp    1050 <memmove@plt>
```

tool_calls: name: parse_data
arguments: tag: D3
datatype: byte[8]

tool: {"D3": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e]}

assistant: ```c
void cr250(int *locSeed, double *locRandNums) {
  int i;
  int q = 103, p = 250;
  for (i = 0; i < 100; i++) {
    locSeed[i + p] = locSeed[i + p - q] ^ locSeed[i];
    locRandNums[i] = (double)(locSeed[i + p] / 2147483648.0);
  }
  for (i = 0; i < p; i++)
    locSeed[i] = locSeed[i + 100];
}
```
user: Translate the below assembly code into C programming language:

```asm
<cr250>:
  endbr64
  lea    0x3e8(%rdi),%rdx
  lea    0x320(%rsi),%rax
  cmp    %rax,%rdx
  jae    L45
  lea    0x578(%rdi),%rax
  cmp    %rax,%rsi
  jb     L33
L45:
  movapd D9(%rip),%xmm2
  xor    %eax,%eax
  nopl   (%rax)
L37:
  movdqu 0x24c(%rdi,%rax,1),%xmm0
  movdqu (%rdi,%rax,1),%xmm3
  pxor   %xmm3,%xmm0
  movups %xmm0,0x3e8(%rdi,%rax,1)
  cvtdq2pd %xmm0,%xmm1
  mulpd  %xmm2,%xmm1
  pshufd $0xee,%xmm0,%xmm0
  cvtdq2pd %xmm0,%xmm0
  mulpd  %xmm2,%xmm0
  movups %xmm1,(%rsi,%rax,2)
  movups %xmm0,0x10(%rsi,%rax,2)
  add    $0x10,%rax
  cmp    $0x190,%rax
  jne    L37
L21:
  lea    0x190(%rdi),%rsi
  mov    $0x3e8,%edx
  jmp    1050 <memmove@plt>
L33:
  movsd  D9(%rip),%xmm1
  xor    %eax,%eax
  nop
L46:
  mov    (%rdi,%rax,4),%edx
  pxor   %xmm0,%xmm0
  xor    0x24c(%rdi,%rax,4),%edx
  cvtsi2sd %edx,%xmm0
  mov    %edx,0x3e8(%rdi,%rax,4)
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rsi,%rax,8)
  add    $0x1,%rax
  cmp    $0x64,%rax
  jne    L46
  jmp    L21
```

tool_calls: name: retrieve_data
arguments: tag: D9
type: byte[16]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x3e]}

assistant: ```c
void cr250(int *locSeed, double *locRandNums) {
  int i;
  int q = 103, p = 250;
  for (i = 0; i < 100; i++) {
    locSeed[i + p] = locSeed[i + p - q] ^ locSeed[i];
    locRandNums[i] = (double)(locSeed[i + p] / 2147483648.0);
  }
  for (i = 0; i < p; i++)
    locSeed[i] = locSeed[i + 100];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<random_number>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    -0x18(%rbp),%edx
  sub    -0x14(%rbp),%edx
  lea    0x1(%rdx),%ecx
  cltd
  idiv   %ecx
  mov    %eax,-0x8(%rbp)
  mov    D18(%rip),%eax
  test   %eax,%eax
  jne    L15
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,D18(%rip)
L15:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jg     L15
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  leave
  ret
```

assistant: ```c
int random_number(int min, int max) {
  static int initialized = 0;
  int divisor = RAND_MAX / (max - min + 1);
  int retval;
  if (!initialized) {
    srand(time(NULL));
    initialized = 1;
  }
  do {
    retval = rand() / divisor;
  } while (retval > max - min);
  return retval + min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<random_number>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  sub    %edi,%esi
  mov    %esi,%ebp
  lea    0x1(%rsi),%ecx
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  cmpl   $0x0,D1(%rip)
  je     L1
L5:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %eax,%ebp
  jl     L5
  add    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,D1(%rip)
  jmp    L5
```

assistant: ```c
int random_number(int min, int max) {
  static int initialized = 0;
  int divisor = RAND_MAX / (max - min + 1);
  int retval;
  if (!initialized) {
    srand(time(NULL));
    initialized = 1;
  }
  do {
    retval = rand() / divisor;
  } while (retval > max - min);
  return retval + min;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<random_number>:
  endbr64
  mov    D25(%rip),%rax
  push   %r12
  sub    %edi,%esi
  mov    %edi,%r12d
  push   %rbp
  lea    0x1(%rsi),%ecx
  mov    %esi,%ebp
  push   %rbx
  mov    (%rax),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  mov    D20(%rip),%eax
  test   %eax,%eax
  je     L22
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %eax,%ebp
  jl     L16
  add    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L22:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,D20(%rip)
  jmp    L16
```

assistant: ```c
int random_number(int min, int max) {
  static int initialized = 0;
  int divisor = RAND_MAX / (max - min + 1);
  int retval;
  if (!initialized) {
    srand(time(NULL));
    initialized = 1;
  }
  do {
    retval = rand() / divisor;
  } while (retval > max - min);
  return retval + min;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<random_number>:
  endbr64
  mov    D25(%rip),%rax
  push   %r12
  sub    %edi,%esi
  mov    %edi,%r12d
  push   %rbp
  lea    0x1(%rsi),%ecx
  mov    %esi,%ebp
  push   %rbx
  mov    (%rax),%eax
  cltd
  idiv   %ecx
  mov    %eax,%ebx
  mov    D22(%rip),%eax
  test   %eax,%eax
  je     L24
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  cmp    %eax,%ebp
  jl     L25
  add    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L24:
  xor    %edi,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  movl   $0x1,D22(%rip)
  jmp    L25
```

assistant: ```c
int random_number(int min, int max) {
  static int initialized = 0;
  int divisor = RAND_MAX / (max - min + 1);
  int retval;
  if (!initialized) {
    srand(time(NULL));
    initialized = 1;
  }
  do {
    retval = rand() / divisor;
  } while (retval > max - min);
  return retval + min;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  jmp    L89
L101:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L89
  cmpl   $0x0,-0x4(%rbp)
  jle    L64
  mov    $0x1,%eax
  jmp    L66
L64:
  mov    $0xffffffff,%eax
  jmp    L66
L89:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L24
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L101
L24:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L35
  mov    $0x1,%eax
  jmp    L66
L35:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L75
  mov    $0xffffffff,%eax
  jmp    L66
L75:
  mov    $0x0,%eax
L66:
  pop    %rbp
  ret
```

assistant: ```c
int mystrcmp(char *str1, char *str2) {
  int diff;
  while (*str1 && *str2) {
    diff = (*str1++) - (*str2++);
    if (diff != 0) {
      if (diff > 0)
        return 1;
      else
        return -1;
    }
  }
  if (*str1)
    return 1;
  if (*str2)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mystrcmp>:
  endbr64
L4:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L9
  movzbl (%rsi),%edx
  test   %dl,%dl
  je     L28
  add    $0x1,%rdi
  add    $0x1,%rsi
  movsbl %al,%eax
  movsbl %dl,%edx
  sub    %edx,%eax
  je     L4
  test   %eax,%eax
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
L28:
  mov    $0x1,%eax
  ret
L9:
  movzbl (%rsi),%eax
  neg    %al
  sbb    %eax,%eax
  ret
```

assistant: ```c
int mystrcmp(char *str1, char *str2) {
  int diff;
  while (*str1 && *str2) {
    diff = (*str1++) - (*str2++);
    if (diff != 0) {
      if (diff > 0)
        return 1;
      else
        return -1;
    }
  }
  if (*str1)
    return 1;
  if (*str2)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mystrcmp>:
  endbr64
  xor    %ecx,%ecx
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L17:
  test   %dl,%dl
  je     L2
  sub    %edx,%eax
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L30
L8:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edx
  test   %al,%al
  jne    L17
  neg    %dl
  sbb    %eax,%eax
  ret
  nop
L2:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L30:
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int mystrcmp(char *str1, char *str2) {
  int diff;
  while (*str1 && *str2) {
    diff = (*str1++) - (*str2++);
    if (diff != 0) {
      if (diff > 0)
        return 1;
      else
        return -1;
    }
  }
  if (*str1)
    return 1;
  if (*str2)
    return -1;
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<mystrcmp>:
  endbr64
  xor    %ecx,%ecx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L8:
  test   %dl,%dl
  je     L21
  sub    %edx,%eax
  add    $0x1,%rcx
  test   %eax,%eax
  jne    L15
L1:
  movsbl (%rdi,%rcx,1),%eax
  movsbl (%rsi,%rcx,1),%edx
  test   %al,%al
  jne    L8
  neg    %dl
  sbb    %eax,%eax
  ret
  nop
L21:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L15:
  setg   %al
  movzbl %al,%eax
  lea    -0x1(%rax,%rax,1),%eax
  ret
```

assistant: ```c
int mystrcmp(char *str1, char *str2) {
  int diff;
  while (*str1 && *str2) {
    diff = (*str1++) - (*str2++);
    if (diff != 0) {
      if (diff > 0)
        return 1;
      else
        return -1;
    }
  }
  if (*str1)
    return 1;
  if (*str2)
    return -1;
  return 0;
}
```