ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<show_help>:
  endbr64
  sub    $0x8,%rsp
  lea    D44(%rip),%rdi
  call   <printf@plt>
  lea    D2(%rip),%rdi
  call   <printf@plt>
  lea    D70(%rip),%rdi
  call   <printf@plt>
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  lea    D108(%rip),%rdi
  call   <printf@plt>
  lea    D82(%rip),%rdi
  call   <printf@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  lea    D100(%rip),%rdi
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <printf@plt>
  lea    D66(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D44
datatype: string
name: disassemble_data
arguments: data_label: D2
datatype: string
name: disassemble_data
arguments: data_label: D70
datatype: string
name: disassemble_data
arguments: data_label: D22
datatype: string
name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D108
datatype: string
name: disassemble_data
arguments: data_label: D82
datatype: string
name: disassemble_data
arguments: data_label: D59
datatype: string
name: disassemble_data
arguments: data_label: D100
datatype: string
name: disassemble_data
arguments: data_label: D68
datatype: string
name: disassemble_data
arguments: data_label: D66
datatype: string

tool: D44: Usage: a10-set-tpr3 new_tpr3


tool: D2: Where tpr3 is a hexadecimal number in the following format:


tool: D70:   bits [22:20] - MFWDLY of the command lane


tool: D22:   bits [18:16] - MFBDLY of the command lane


tool: D1:   bits [15:12] - SDPHASE of the byte lane 3


tool: D108:   bits  [11:8] - SDPHASE of the byte lane 2


tool: D82:   bits   [7:4] - SDPHASE of the byte lane 1


tool: D59:   bits   [3:0] - SDPHASE of the byte lane 0


tool: D100: 
See the RK30XX manual for more details. They are using


tool: D68: the same dram controller as Allwinner A10/A13/A20.


tool: D66: Though maybe a different revision of it.


assistant: ```c
void show_help(void) {
  printf("Usage: a10-set-tpr3 new_tpr3\n");
  printf("Where tpr3 is a hexadecimal number in the following format:\n");
  printf("  bits [22:20] - MFWDLY of the command lane\n");
  printf("  bits [18:16] - MFBDLY of the command lane\n");
  printf("  bits [15:12] - SDPHASE of the byte lane 3\n");
  printf("  bits  [11:8] - SDPHASE of the byte lane 2\n");
  printf("  bits   [7:4] - SDPHASE of the byte lane 1\n");
  printf("  bits   [3:0] - SDPHASE of the byte lane 0\n");
  printf("\nSee the RK30XX manual for more details. They are using\n");
  printf("the same dram controller as Allwinner A10/A13/A20.\n");
  printf("Though maybe a different revision of it.\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x18(%rbp),%rax
  jmp    L39
L31:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L68
  addl   $0x1,-0x4(%rbp)
  jmp    L35
L68:
  movl   $0x0,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L64
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  jmp    L39
L64:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
  mov    $0x0,%eax
L39:
  pop    %rbp
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  int begin;
  int current;
  begin = 0;
  current = 0;
  if (!*s2)
    return ((char *)s1);
  while (s1[begin]) {
    if (s1[begin + current] == s2[current])
      current++;
    else {
      current = 0;
      begin++;
    }
    if (!s2[current])
      return ((char *)s1 + begin);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_strstr>:
  endbr64
  mov    %rdi,%rax
  cmpb   $0x0,(%rsi)
  je     L49
  mov    $0x0,%ecx
  mov    $0x0,%r8d
  jmp    L53
L58:
  add    $0x1,%ecx
  movslq %ecx,%rdx
  cmpb   $0x0,(%rsi,%rdx,1)
  je     L10
L53:
  movslq %r8d,%rax
  add    %rdi,%rax
  cmpb   $0x0,(%rax)
  je     L57
  lea    (%r8,%rcx,1),%edx
  movslq %edx,%rdx
  movslq %ecx,%r9
  movzbl (%rsi,%r9,1),%r10d
  cmp    %r10b,(%rdi,%rdx,1)
  je     L58
  add    $0x1,%r8d
  mov    $0x0,%ecx
  jmp    L53
L10:
  ret
L57:
  mov    $0x0,%eax
L49:
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  int begin;
  int current;
  begin = 0;
  current = 0;
  if (!*s2)
    return ((char *)s1);
  while (s1[begin]) {
    if (s1[begin + current] == s2[current])
      current++;
    else {
      current = 0;
      begin++;
    }
    if (!s2[current])
      return ((char *)s1 + begin);
  }
  return (0);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_strstr>:
  endbr64
  cmpb   $0x0,(%rsi)
  mov    %rdi,%r8
  je     L21
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r10d,%r10d
L44:
  lea    (%rdi,%r10,1),%r8
  cmpb   $0x0,(%r8)
  je     L8
L14:
  lea    (%rcx,%rdx,1),%eax
  movslq %edx,%r9
  cltq
  movzbl (%rsi,%r9,1),%r11d
  cmp    %r11b,(%rdi,%rax,1)
  je     L39
  add    $0x1,%ecx
  xor    %edx,%edx
  movslq %ecx,%r10
  lea    (%rdi,%r10,1),%r8
  cmpb   $0x0,(%r8)
  jne    L14
L8:
  xor    %r8d,%r8d
L21:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L39:
  add    $0x1,%edx
  movslq %edx,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L44
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  int begin;
  int current;
  begin = 0;
  current = 0;
  if (!*s2)
    return ((char *)s1);
  while (s1[begin]) {
    if (s1[begin + current] == s2[current])
      current++;
    else {
      current = 0;
      begin++;
    }
    if (!s2[current])
      return ((char *)s1 + begin);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ft_strstr>:
  endbr64
  cmpb   $0x0,(%rsi)
  mov    %rdi,%r8
  je     L29
  xor    %edx,%edx
  xor    %ecx,%ecx
  xor    %r10d,%r10d
L43:
  lea    (%rdi,%r10,1),%r8
  cmpb   $0x0,(%r8)
  je     L49
L48:
  lea    (%rcx,%rdx,1),%eax
  movslq %edx,%r9
  cltq
  movzbl (%rsi,%r9,1),%r11d
  cmp    %r11b,(%rdi,%rax,1)
  je     L6
  add    $0x1,%ecx
  xor    %edx,%edx
  movslq %ecx,%r10
  lea    (%rdi,%r10,1),%r8
  cmpb   $0x0,(%r8)
  jne    L48
L49:
  xor    %r8d,%r8d
L29:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax)
L6:
  add    $0x1,%edx
  movslq %edx,%rax
  cmpb   $0x0,(%rsi,%rax,1)
  jne    L43
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  int begin;
  int current;
  begin = 0;
  current = 0;
  if (!*s2)
    return ((char *)s1);
  while (s1[begin]) {
    if (s1[begin + current] == s2[current])
      current++;
    else {
      current = 0;
      begin++;
    }
    if (!s2[current])
      return ((char *)s1 + begin);
  }
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<yesno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x2,-0xc(%rbp)
  jmp    L78
L27:
  cmpl   $0x0,-0x1c(%rbp)
  je     L71
  mov    $0x59,%edx
  jmp    L48
L71:
  mov    $0x4e,%edx
L48:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getLine@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L82
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L66
L82:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    $0x59,%al
  jne    L46
  movl   $0x1,-0xc(%rbp)
  jmp    L66
L46:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  cmp    $0x4e,%al
  jne    L66
  movl   $0x0,-0xc(%rbp)
L66:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L78:
  cmpl   $0x1,-0xc(%rbp)
  jg     L27
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
data_type: string

tool: D2: %s (yes or no) [%c]:  

assistant: ```c
int yesno(char *query, int def) {
  char *yn;
  int ans = 2;
  while (ans > 1) {
    printf("%s (yes or no) [%c]:  ", query, def ? 'Y' : 'N');
    yn = getLine();
    if (!*yn)
      ans = def;
    else if (toupper(*yn) == 'Y')
      ans = 1;
    else if (toupper(*yn) == 'N')
      ans = 0;
    free(yn);
  }
  return ans;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<yesno>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x2,%r12d
  lea    D6(%rip),%r14
  jmp    L16
L26:
  movsbl (%rbx),%edi
  call   <toupper@plt>
  cmp    $0x4e,%al
  je     L58
L83:
  mov    %rbx,%rdi
  call   <free@plt>
  cmp    $0x1,%r12d
  jle    L66
L16:
  test   %ebp,%ebp
  je     L90
  mov    $0x59,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getLine@plt>
  mov    %rax,%rbx
  movzbl (%rax),%edi
  test   %dil,%dil
  jne    L60
  mov    %ebp,%r12d
  jmp    L83
L58:
  mov    $0x0,%r12d
  jmp    L8
L4:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %ebp,%r12d
  jmp    L66
L90:
  mov    $0x4e,%edx
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getLine@plt>
  mov    %rax,%rbx
  movzbl (%rax),%edi
  test   %dil,%dil
  je     L4
L60:
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    $0x59,%al
  jne    L26
  mov    $0x1,%r12d
L8:
  mov    %rbx,%rdi
  call   <free@plt>
L66:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type_guessed: string

tool: D6: %s (yes or no) [%c]:  

assistant: ```c
int yesno(char *query, int def) {
  char *yn;
  int ans = 2;
  while (ans > 1) {
    printf("%s (yes or no) [%c]:  ", query, def ? 'Y' : 'N');
    yn = getLine();
    if (!*yn)
      ans = def;
    else if (toupper(*yn) == 'Y')
      ans = 1;
    else if (toupper(*yn) == 'N')
      ans = 0;
    free(yn);
  }
  return ans;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yesno>:
  endbr64
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L42:
  test   %ebx,%ebx
  je     L58
  mov    %r13,%rdi
  mov    $0x59,%edx
  mov    %r12,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getLine@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L23
  mov    %rax,%rdi
  call   <free@plt>
  cmp    $0x1,%ebx
  jg     L42
  mov    %ebx,%eax
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L58:
  mov    %r13,%rdi
  mov    $0x4e,%edx
  mov    %r12,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getLine@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  je     L43
L23:
  call   <toupper@plt>
  cmp    $0x59,%al
  jne    L7
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  mov    %rbp,%rdi
  cmp    $0x4e,%al
  je     L70
  call   <free@plt>
  jmp    L42
L43:
  mov    %rbp,%rdi
L70:
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D0
data_type: string

tool: D0: %s (yes or no) [%c]:  

assistant: ```c
int yesno(char *query, int def) {
  char *yn;
  int ans = 2;
  while (ans > 1) {
    printf("%s (yes or no) [%c]:  ", query, def ? 'Y' : 'N');
    yn = getLine();
    if (!*yn)
      ans = def;
    else if (toupper(*yn) == 'Y')
      ans = 1;
    else if (toupper(*yn) == 'N')
      ans = 0;
    free(yn);
  }
  return ans;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<yesno>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  lea    D11(%rip),%r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %esi,%esi
  jne    L47
  lea    D11(%rip),%r12
  nopw   0x0(%rax,%rax,1)
L77:
  mov    %r12,%rdi
  mov    $0x4e,%edx
  mov    %rbx,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getLine@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  je     L98
  call   <toupper@plt>
  cmp    $0x59,%al
  je     L25
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  cmp    $0x4e,%al
  je     L98
  mov    %rbp,%rdi
  call   <free@plt>
  jmp    L77
L61:
  call   <toupper@plt>
  cmp    $0x59,%al
  je     L25
  movsbl 0x0(%rbp),%edi
  call   <toupper@plt>
  cmp    $0x4e,%al
  je     L98
  mov    %rbp,%rdi
  call   <free@plt>
  nopl   0x0(%rax,%rax,1)
L47:
  mov    %r12,%rdi
  mov    $0x59,%edx
  mov    %rbx,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getLine@plt>
  movsbl (%rax),%edi
  mov    %rax,%rbp
  test   %dil,%dil
  jne    L61
  mov    %rax,%rdi
  call   <free@plt>
  cmp    $0x1,%r13d
  jg     L47
  mov    %r13d,%eax
  jmp    L80
  nopl   (%rax)
L25:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x1,%eax
L80:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L98:
  mov    %rbp,%rdi
  call   <free@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
data_type: string

tool: D11: %s (yes or no) [%c]:  

assistant: ```c
int yesno(char *query, int def) {
  char *yn;
  int ans = 2;
  while (ans > 1) {
    printf("%s (yes or no) [%c]:  ", query, def ? 'Y' : 'N');
    yn = getLine();
    if (!*yn)
      ans = def;
    else if (toupper(*yn) == 'Y')
      ans = 1;
    else if (toupper(*yn) == 'N')
      ans = 0;
    free(yn);
  }
  return ans;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fiat_p384_mulx_u32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x24(%rbp),%eax
  imul   -0x28(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    $0xffffffff,%edi
  call   <UINT32_C@plt>
  and    -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void fiat_p384_mulx_u32(uint32_t *out1, uint32_t *out2, uint32_t arg1, uint32_t arg2) {
  uint64_t x1;
  uint32_t x2;
  uint32_t x3;
  x1 = ((uint64_t)arg1 * arg2);
  x2 = (uint32_t)(x1 & UINT32_C(0xffffffff));
  x3 = (uint32_t)(x1 >> 32);
  *out1 = x2;
  *out2 = x3;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fiat_p384_mulx_u32>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  imul   %ecx,%edx
  mov    %edx,%ebx
  mov    $0xffffffff,%edi
  call   <UINT32_C@plt>
  and    %ebx,%eax
  mov    %eax,(%r12)
  mov    $0x20,%ecx
  sar    %cl,%ebx
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fiat_p384_mulx_u32(uint32_t *out1, uint32_t *out2, uint32_t arg1, uint32_t arg2) {
  uint64_t x1;
  uint32_t x2;
  uint32_t x3;
  x1 = ((uint64_t)arg1 * arg2);
  x2 = (uint32_t)(x1 & UINT32_C(0xffffffff));
  x3 = (uint32_t)(x1 >> 32);
  *out1 = x2;
  *out2 = x3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fiat_p384_mulx_u32>:
  endbr64
  push   %r12
  imul   %ecx,%edx
  mov    %rdi,%r12
  mov    $0xffffffff,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <UINT32_C@plt>
  mov    $0x20,%ecx
  and    %ebx,%eax
  sar    %cl,%ebx
  mov    %eax,(%r12)
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fiat_p384_mulx_u32(uint32_t *out1, uint32_t *out2, uint32_t arg1, uint32_t arg2) {
  uint64_t x1;
  uint32_t x2;
  uint32_t x3;
  x1 = ((uint64_t)arg1 * arg2);
  x2 = (uint32_t)(x1 & UINT32_C(0xffffffff));
  x3 = (uint32_t)(x1 >> 32);
  *out1 = x2;
  *out2 = x3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fiat_p384_mulx_u32>:
  endbr64
  push   %r12
  imul   %ecx,%edx
  mov    %rdi,%r12
  mov    $0xffffffff,%edi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  call   <UINT32_C@plt>
  mov    $0x20,%ecx
  and    %ebx,%eax
  sar    %cl,%ebx
  mov    %eax,(%r12)
  mov    %ebx,0x0(%rbp)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void fiat_p384_mulx_u32(uint32_t *out1, uint32_t *out2, uint32_t arg1, uint32_t arg2) {
  uint64_t x1;
  uint32_t x2;
  uint32_t x3;
  x1 = ((uint64_t)arg1 * arg2);
  x2 = (uint32_t)(x1 & UINT32_C(0xffffffff));
  x3 = (uint32_t)(x1 >> 32);
  *out1 = x2;
  *out2 = x3;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L5
  cmpl   $0x5a,-0x4(%rbp)
  jle    L29
L5:
  mov    -0x4(%rbp),%eax
  jmp    L18
L29:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <_tolower@plt>
L18:
  leave
  ret
```

assistant: ```c
int tolower(int c) {
  if (c < 'A' || c > 'Z')
    return c;
  return _tolower(c);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tolower>:
  endbr64
  mov    %edi,%eax
  lea    -0x41(%rdi),%edx
  cmp    $0x19,%edx
  jbe    L1
  ret
L1:
  sub    $0x8,%rsp
  call   <_tolower@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int tolower(int c) {
  if (c < 'A' || c > 'Z')
    return c;
  return _tolower(c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%edx
  cmp    $0x19,%edx
  jbe    L0
  mov    %edi,%eax
  ret
  nop
L0:
  jmp    1050 <_tolower@plt>
```

assistant: ```c
int tolower(int c) {
  if (c < 'A' || c > 'Z')
    return c;
  return _tolower(c);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tolower>:
  endbr64
  lea    -0x41(%rdi),%edx
  cmp    $0x19,%edx
  jbe    L1
  mov    %edi,%eax
  ret
  nop
L1:
  jmp    1050 <_tolower@plt>
```

assistant: ```c
int tolower(int c) {
  if (c < 'A' || c > 'Z')
    return c;
  return _tolower(c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<reverse_recur>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %edx,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jge    L4
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x10(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <reverse_recur>
  jmp    L8
L4:
  nop
L8:
  leave
  ret
```

assistant: ```c
void reverse_recur(char s[], int start, int end) {
  if (start >= end) {
    return;
  }
  swap(s, start, end);
  reverse_recur(s, start + 1, end - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<reverse_recur>:
  endbr64
  cmp    %edx,%esi
  jl     L0
  ret
L0:
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  call   <swap@plt>
  lea    -0x1(%rbp),%edx
  lea    0x1(%rbx),%esi
  mov    %r12,%rdi
  call   <reverse_recur>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void reverse_recur(char s[], int start, int end) {
  if (start >= end) {
    return;
  }
  swap(s, start, end);
  reverse_recur(s, start + 1, end - 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<reverse_recur>:
  endbr64
  cmp    %edx,%esi
  jge    L1
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <swap@plt>
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jg     L14
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
void reverse_recur(char s[], int start, int end) {
  if (start >= end) {
    return;
  }
  swap(s, start, end);
  reverse_recur(s, start + 1, end - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<reverse_recur>:
  endbr64
  cmp    %edx,%esi
  jge    L13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %edx,%ebx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  sub    $0x1,%ebx
  call   <swap@plt>
  add    $0x1,%ebp
  cmp    %ebp,%ebx
  jg     L18
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  ret
```

assistant: ```c
void reverse_recur(char s[], int start, int end) {
  if (start >= end) {
    return;
  }
  swap(s, start, end);
  reverse_recur(s, start + 1, end - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bartlett>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  D18(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L3
L5:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L5
  jmp    L28
L18:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  -0x8(%rbp),%xmm1
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movsd  D18(%rip),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x18(%rbp)
L28:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L18
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D18
type_guessed: f64

tool: D18: 2

assistant: ```c
double *bartlett(double *w, const int leng) {
  int k, m;
  double *p, slope;
  m = leng / 2;
  slope = 2.0 / (double)(leng - 1);
  for (k = 0, p = w; k < m; k++)
    *p++ = slope * k;
  for (; k < leng; k++)
    *p++ = 2.0 - slope * k;
  return (w);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bartlett>:
  endbr64
  mov    %esi,%ecx
  mov    %esi,%eax
  shr    $0x1f,%eax
  add    %esi,%eax
  sar    %eax
  lea    -0x1(%rsi),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  movsd  D1(%rip),%xmm1
  divsd  %xmm0,%xmm1
  cmp    $0x1,%esi
  jle    L15
  mov    $0x0,%edx
L45:
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,(%rdi,%rdx,8)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L45
  lea    -0x1(%rax),%edx
  lea    0x8(,%rdx,8),%rdx
  cmp    $0x1,%ecx
  mov    $0x8,%esi
  cmovle %rsi,%rdx
  add    %rdi,%rdx
  test   %eax,%eax
  mov    $0x1,%esi
  cmovle %esi,%eax
L46:
  cmp    %eax,%ecx
  jle    L13
  movsd  D1(%rip),%xmm3
L28:
  add    $0x8,%rdx
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  %xmm1,%xmm0
  movapd %xmm3,%xmm2
  subsd  %xmm0,%xmm2
  movsd  %xmm2,-0x8(%rdx)
  add    $0x1,%eax
  cmp    %eax,%ecx
  jne    L28
L13:
  mov    %rdi,%rax
  ret
L15:
  mov    %rdi,%rdx
  mov    $0x0,%eax
  jmp    L46
```

tool_calls: name: disassemble_data
arguments: label: D1
type_guessed: f64

tool: D1: 2

assistant: ```c
double *bartlett(double *w, const int leng) {
  int k, m;
  double *p, slope;
  m = leng / 2;
  slope = 2.0 / (double)(leng - 1);
  for (k = 0, p = w; k < m; k++)
    *p++ = slope * k;
  for (; k < leng; k++)
    *p++ = 2.0 - slope * k;
  return (w);
}
```