ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<ad_getnew>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D0(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D6(%rip)
  pop    %rbp
  ret
```

assistant: ```c
int ad_getnew() {
  static int cur = 10;
  return cur++;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ad_getnew>:
  endbr64
  mov    D15(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D18(%rip)
  ret
```

assistant: ```c
int ad_getnew() {
  static int cur = 10;
  return cur++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ad_getnew>:
  endbr64
  mov    D12(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D11(%rip)
  ret
```

assistant: ```c
int ad_getnew() {
  static int cur = 10;
  return cur++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ad_getnew>:
  endbr64
  mov    D10(%rip),%eax
  lea    0x1(%rax),%edx
  mov    %edx,D12(%rip)
  ret
```

assistant: ```c
int ad_getnew() {
  static int cur = 10;
  return cur++;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<saday_sort_2_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x48(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x50(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    0x10(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  jne    L28
  cmpl   $0x2,-0xc(%rbp)
  jne    L28
  mov    -0x18(%rbp),%eax
  imul   -0x14(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rsi
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rax
  movq   %rsi,%xmm0
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <copy@plt>
  jmp    L101
L28:
  cmpl   $0x0,-0x18(%rbp)
  jle    L14
  cmpl   $0x0,-0x14(%rbp)
  jg     L105
L14:
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L101
L105:
  mov    -0x18(%rbp),%eax
  cltq
  and    $0x7,%eax
  test   %rax,%rax
  jne    L1
  mov    -0x14(%rbp),%eax
  cltq
  and    $0x7,%eax
  test   %rax,%rax
  jne    L1
  mov    -0x28(%rbp),%rax
  and    $0x3f,%eax
  test   %rax,%rax
  jne    L1
  mov    -0x30(%rbp),%rax
  and    $0x3f,%eax
  test   %rax,%rax
  jne    L1
  mov    -0x8(%rbp),%rdi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <transpose_aligned@plt>
  jmp    L101
L1:
  mov    -0x8(%rbp),%rdi
  mov    -0x14(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  movq   %rdi,%xmm0
  mov    %rax,%rdi
  call   <transpose_misaligned@plt>
L101:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
datatype: string

tool: D2: Dimensions must be larger than zero! 


assistant: ```c
void saday_sort_2_(double *unsorted, double *sorted, int *a_in, int *b_in, int *i_in, int *j_in, double *factor_in) {
  int a = *a_in;
  int b = *b_in;
  int i = *i_in;
  int j = *j_in;
  double factor = *factor_in;
  if (i == 1 && j == 2) {
    copy(unsorted, sorted, a * b, factor);
    return;
  }
  if (a <= 0 || b <= 0) {
    printf("Dimensions must be larger than zero! \n");
  } else if (a % (64 / sizeof(double)) == 0 && b % (64 / sizeof(double)) == 0 && (long)unsorted % 64 == 0 && (long)sorted % 64 == 0) {
    transpose_aligned(unsorted, sorted, a, b, factor);
  } else {
    transpose_misaligned(unsorted, sorted, a, b, factor);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<saday_sort_2_>:
  endbr64
  sub    $0x8,%rsp
  mov    (%rdx),%edx
  mov    (%rcx),%ecx
  mov    0x10(%rsp),%rax
  movsd  (%rax),%xmm0
  cmpl   $0x1,(%r8)
  jne    L85
  cmpl   $0x2,(%r9)
  je     L26
L85:
  test   %edx,%edx
  jle    L37
  test   %ecx,%ecx
  jle    L37
  mov    %edx,%eax
  or     %ecx,%eax
  test   $0x7,%al
  je     L32
L52:
  call   <transpose_misaligned@plt>
L82:
  add    $0x8,%rsp
  ret
L26:
  imul   %ecx,%edx
  call   <copy@plt>
  jmp    L82
L37:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L32:
  mov    %rdi,%rax
  or     %rsi,%rax
  test   $0x3f,%al
  jne    L52
  call   <transpose_aligned@plt>
  jmp    L82
```

tool_calls: name: read_data
arguments: tag: D8
type: string

tool: D8: Dimensions must be larger than zero! 


assistant: ```c
void saday_sort_2_(double *unsorted, double *sorted, int *a_in, int *b_in, int *i_in, int *j_in, double *factor_in) {
  int a = *a_in;
  int b = *b_in;
  int i = *i_in;
  int j = *j_in;
  double factor = *factor_in;
  if (i == 1 && j == 2) {
    copy(unsorted, sorted, a * b, factor);
    return;
  }
  if (a <= 0 || b <= 0) {
    printf("Dimensions must be larger than zero! \n");
  } else if (a % (64 / sizeof(double)) == 0 && b % (64 / sizeof(double)) == 0 && (long)unsorted % 64 == 0 && (long)sorted % 64 == 0) {
    transpose_aligned(unsorted, sorted, a, b, factor);
  } else {
    transpose_misaligned(unsorted, sorted, a, b, factor);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<saday_sort_2_>:
  endbr64
  mov    0x8(%rsp),%rax
  cmpl   $0x1,(%r8)
  mov    (%rdx),%edx
  mov    (%rcx),%ecx
  movsd  (%rax),%xmm0
  jne    L14
  cmpl   $0x2,(%r9)
  je     L4
L14:
  test   %edx,%edx
  jle    L20
  test   %ecx,%ecx
  jle    L20
  mov    %edx,%eax
  or     %ecx,%eax
  test   $0x7,%al
  je     L0
L50:
  jmp    10b0 <transpose_misaligned@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  imul   %ecx,%edx
  jmp    10a0 <copy@plt>
L20:
  lea    D5(%rip),%rdi
  jmp    1090 <printf@plt>
  nopl   0x0(%rax)
L0:
  mov    %rdi,%rax
  or     %rsi,%rax
  test   $0x3f,%al
  jne    L50
  jmp    1080 <transpose_aligned@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string

tool: D5: Dimensions must be larger than zero! 


assistant: ```c
void saday_sort_2_(double *unsorted, double *sorted, int *a_in, int *b_in, int *i_in, int *j_in, double *factor_in) {
  int a = *a_in;
  int b = *b_in;
  int i = *i_in;
  int j = *j_in;
  double factor = *factor_in;
  if (i == 1 && j == 2) {
    copy(unsorted, sorted, a * b, factor);
    return;
  }
  if (a <= 0 || b <= 0) {
    printf("Dimensions must be larger than zero! \n");
  } else if (a % (64 / sizeof(double)) == 0 && b % (64 / sizeof(double)) == 0 && (long)unsorted % 64 == 0 && (long)sorted % 64 == 0) {
    transpose_aligned(unsorted, sorted, a, b, factor);
  } else {
    transpose_misaligned(unsorted, sorted, a, b, factor);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<saday_sort_2_>:
  endbr64
  mov    0x8(%rsp),%rax
  cmpl   $0x1,(%r8)
  mov    (%rdx),%edx
  mov    (%rcx),%ecx
  movsd  (%rax),%xmm0
  jne    L10
  cmpl   $0x2,(%r9)
  je     L53
L10:
  test   %edx,%edx
  jle    L47
  test   %ecx,%ecx
  jle    L47
  mov    %edx,%eax
  or     %ecx,%eax
  test   $0x7,%al
  je     L1
L29:
  jmp    10b0 <transpose_misaligned@plt>
  nopw   0x0(%rax,%rax,1)
L53:
  imul   %ecx,%edx
  jmp    10a0 <copy@plt>
L47:
  lea    D6(%rip),%rdi
  jmp    1090 <printf@plt>
  nopl   0x0(%rax)
L1:
  mov    %rdi,%rax
  or     %rsi,%rax
  test   $0x3f,%al
  jne    L29
  jmp    1080 <transpose_aligned@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type: string

tool: D6: Dimensions must be larger than zero! 


assistant: ```c
void saday_sort_2_(double *unsorted, double *sorted, int *a_in, int *b_in, int *i_in, int *j_in, double *factor_in) {
  int a = *a_in;
  int b = *b_in;
  int i = *i_in;
  int j = *j_in;
  double factor = *factor_in;
  if (i == 1 && j == 2) {
    copy(unsorted, sorted, a * b, factor);
    return;
  }
  if (a <= 0 || b <= 0) {
    printf("Dimensions must be larger than zero! \n");
  } else if (a % (64 / sizeof(double)) == 0 && b % (64 / sizeof(double)) == 0 && (long)unsorted % 64 == 0 && (long)sorted % 64 == 0) {
    transpose_aligned(unsorted, sorted, a, b, factor);
  } else {
    transpose_misaligned(unsorted, sorted, a, b, factor);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sigwait>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sigtimedwait@plt>
  test   %rax,%rax
  jns    L7
  mov    $0xffffffff,%eax
  jmp    L6
L7:
  mov    -0xc(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
int sigwait(const sigset_t *restrict mask, int *restrict sig) {
  siginfo_t si;
  if (sigtimedwait(mask, &si, 0) < 0)
    return -1;
  *sig = si.si_signo;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sigwait>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  mov    $0x0,%edx
  call   <sigtimedwait@plt>
  test   %rax,%rax
  js     L6
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  mov    $0x0,%eax
L14:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L6:
  mov    $0xffffffff,%eax
  jmp    L14
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sigwait(const sigset_t *restrict mask, int *restrict sig) {
  siginfo_t si;
  if (sigtimedwait(mask, &si, 0) < 0)
    return -1;
  *sig = si.si_signo;
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sigwait>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <sigtimedwait@plt>
  test   %rax,%rax
  js     L16
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x10,%rsp
  pop    %rbx
  ret
L16:
  mov    $0xffffffff,%eax
  jmp    L5
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sigwait(const sigset_t *restrict mask, int *restrict sig) {
  siginfo_t si;
  if (sigtimedwait(mask, &si, 0) < 0)
    return -1;
  *sig = si.si_signo;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sigwait>:
  endbr64
  push   %rbx
  xor    %edx,%edx
  mov    %rsi,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <sigtimedwait@plt>
  test   %rax,%rax
  js     L26
  mov    0x4(%rsp),%eax
  mov    %eax,(%rbx)
  xor    %eax,%eax
L1:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L26:
  mov    $0xffffffff,%eax
  jmp    L1
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int sigwait(const sigset_t *restrict mask, int *restrict sig) {
  siginfo_t si;
  if (sigtimedwait(mask, &si, 0) < 0)
    return -1;
  *sig = si.si_signo;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cntleadzeros>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
L15:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L11
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  sub    $0x1,%rax
  jmp    L22
L11:
  subq   $0x1,-0x8(%rbp)
  jmp    L15
L22:
  pop    %rbp
  ret
```

assistant: ```c
uint64_t cntleadzeros(uint64_t size, uint64_t src) {
  int64_t i;
  for (i = (int64_t)size - 1; i >= 0; i--) {
    if (src & (1ull << i))
      return (uint64_t)(size - (i + 1));
  }
  return (uint64_t)size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cntleadzeros>:
  endbr64
  lea    -0x1(%rdi),%rax
  mov    %rax,%rdx
  bt     %rax,%rsi
  jb     L9
L18:
  sub    $0x1,%rdx
  bt     %rdx,%rsi
  jae    L18
L9:
  sub    %rdx,%rax
  ret
```

assistant: ```c
uint64_t cntleadzeros(uint64_t size, uint64_t src) {
  int64_t i;
  for (i = (int64_t)size - 1; i >= 0; i--) {
    if (src & (1ull << i))
      return (uint64_t)(size - (i + 1));
  }
  return (uint64_t)size;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cntleadzeros>:
  endbr64
  lea    -0x1(%rdi),%rdx
  bt     %rdx,%rsi
  jb     L17
  xchg   %ax,%ax
L1:
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  bt     %rdx,%rsi
  jae    L1
  mov    %rdi,%rax
  sub    %rcx,%rax
  ret
  nopl   0x0(%rax)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t cntleadzeros(uint64_t size, uint64_t src) {
  int64_t i;
  for (i = (int64_t)size - 1; i >= 0; i--) {
    if (src & (1ull << i))
      return (uint64_t)(size - (i + 1));
  }
  return (uint64_t)size;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cntleadzeros>:
  endbr64
  lea    -0x1(%rdi),%rdx
  bt     %rdx,%rsi
  jb     L10
  xchg   %ax,%ax
L18:
  mov    %rdx,%rcx
  sub    $0x1,%rdx
  bt     %rdx,%rsi
  jae    L18
  mov    %rdi,%rax
  sub    %rcx,%rax
  ret
  nopl   0x0(%rax)
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
uint64_t cntleadzeros(uint64_t size, uint64_t src) {
  int64_t i;
  for (i = (int64_t)size - 1; i >= 0; i--) {
    if (src & (1ull << i))
      return (uint64_t)(size - (i + 1));
  }
  return (uint64_t)size;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__put_user>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  je     L45
  cmpl   $0x4,-0x14(%rbp)
  jg     L74
  cmpl   $0x1,-0x14(%rbp)
  je     L43
  cmpl   $0x2,-0x14(%rbp)
  je     L3
  jmp    L74
L43:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dl,(%rax)
  jmp    L28
L3:
  mov    -0x8(%rbp),%rax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
  jmp    L28
L45:
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
  jmp    L28
L74:
  mov    $0x0,%eax
  call   <bad_user_access_length@plt>
  nop
L28:
  nop
  leave
  ret
```

assistant: ```c
void __put_user(unsigned long x, void *y, int size) {
  switch (size) {
  case 1:
    *(char *)y = x;
    break;
  case 2:
    *(short *)y = x;
    break;
  case 4:
    *(long *)y = x;
    break;
  default:
    bad_user_access_length();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<__put_user>:
  endbr64
  cmp    $0x2,%edx
  je     L27
  cmp    $0x4,%edx
  je     L1
  cmp    $0x1,%edx
  je     L26
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bad_user_access_length@plt>
  add    $0x8,%rsp
  ret
L26:
  mov    %dil,(%rsi)
  ret
L27:
  mov    %di,(%rsi)
  ret
L1:
  mov    %rdi,(%rsi)
  ret
```

assistant: ```c
void __put_user(unsigned long x, void *y, int size) {
  switch (size) {
  case 1:
    *(char *)y = x;
    break;
  case 2:
    *(short *)y = x;
    break;
  case 4:
    *(long *)y = x;
    break;
  default:
    bad_user_access_length();
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__put_user>:
  endbr64
  cmp    $0x2,%edx
  je     L9
  cmp    $0x4,%edx
  je     L13
  cmp    $0x1,%edx
  je     L24
  xor    %eax,%eax
  jmp    1050 <bad_user_access_length@plt>
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %di,(%rsi)
  ret
  nopl   0x0(%rax)
L24:
  mov    %dil,(%rsi)
  ret
  nopl   0x0(%rax)
L13:
  mov    %rdi,(%rsi)
  ret
```

assistant: ```c
void __put_user(unsigned long x, void *y, int size) {
  switch (size) {
  case 1:
    *(char *)y = x;
    break;
  case 2:
    *(short *)y = x;
    break;
  case 4:
    *(long *)y = x;
    break;
  default:
    bad_user_access_length();
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__put_user>:
  endbr64
  cmp    $0x2,%edx
  je     L3
  cmp    $0x4,%edx
  je     L18
  cmp    $0x1,%edx
  je     L26
  xor    %eax,%eax
  jmp    1050 <bad_user_access_length@plt>
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %di,(%rsi)
  ret
  nopl   0x0(%rax)
L26:
  mov    %dil,(%rsi)
  ret
  nopl   0x0(%rax)
L18:
  mov    %rdi,(%rsi)
  ret
```

assistant: ```c
void __put_user(unsigned long x, void *y, int size) {
  switch (size) {
  case 1:
    *(char *)y = x;
    break;
  case 2:
    *(short *)y = x;
    break;
  case 4:
    *(long *)y = x;
    break;
  default:
    bad_user_access_length();
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<i2c_read_leint16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %edx,-0x4c(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x4c(%rbp),%eax
  mov    %eax,-0x30(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x48(%rbp),%esi
  mov    -0x44(%rbp),%eax
  mov    $0x8,%r8d
  mov    $0x1,%ecx
  mov    %eax,%edi
  call   <i2c_transact@plt>
  mov    %eax,-0x34(%rbp)
  cmpl   $0x8,-0x34(%rbp)
  jne    L15
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <__rleu16@plt>
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  mov    %rdx,(%rax)
L15:
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

assistant: ```c
int i2c_read_leint16(int fd, int chip_addr, int reg, int16_t *value) {
  uint8_t data[sizeof(int16_t)];
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, sizeof(int16_t));
  if (err == sizeof(int16_t))
    *value = (int16_t)__rleu16(data);
  return err;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<i2c_read_leint16>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rcx,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %edx,(%rsp)
  mov    %rsp,%rdx
  mov    $0x8,%r8d
  mov    $0x1,%ecx
  call   <i2c_transact@plt>
  mov    %eax,%ebx
  cmp    $0x8,%eax
  je     L8
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  mov    %ebx,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L8:
  mov    %rsp,%rdi
  call   <__rleu16@plt>
  cltq
  mov    %rax,0x0(%rbp)
  jmp    L21
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_leint16(int fd, int chip_addr, int reg, int16_t *value) {
  uint8_t data[sizeof(int16_t)];
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, sizeof(int16_t));
  if (err == sizeof(int16_t))
    *value = (int16_t)__rleu16(data);
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2c_read_leint16>:
  endbr64
  push   %r12
  mov    $0x8,%r8d
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  mov    $0x1,%ecx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %edx,(%rsp)
  mov    %rbp,%rdx
  call   <i2c_transact@plt>
  mov    %eax,%r12d
  cmp    $0x8,%eax
  je     L7
L11:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L7:
  mov    %rbp,%rdi
  call   <__rleu16@plt>
  cltq
  mov    %rax,(%rbx)
  jmp    L11
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_leint16(int fd, int chip_addr, int reg, int16_t *value) {
  uint8_t data[sizeof(int16_t)];
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, sizeof(int16_t));
  if (err == sizeof(int16_t))
    *value = (int16_t)__rleu16(data);
  return err;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<i2c_read_leint16>:
  endbr64
  push   %r12
  mov    $0x8,%r8d
  push   %rbp
  push   %rbx
  mov    %rcx,%rbx
  mov    $0x1,%ecx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %edx,(%rsp)
  mov    %rbp,%rdx
  call   <i2c_transact@plt>
  mov    %eax,%r12d
  cmp    $0x8,%eax
  je     L14
L13:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L14:
  mov    %rbp,%rdi
  call   <__rleu16@plt>
  cltq
  mov    %rax,(%rbx)
  jmp    L13
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int i2c_read_leint16(int fd, int chip_addr, int reg, int16_t *value) {
  uint8_t data[sizeof(int16_t)];
  data[0] = reg;
  int err = i2c_transact(fd, chip_addr, data, 1, sizeof(int16_t));
  if (err == sizeof(int16_t))
    *value = (int16_t)__rleu16(data);
  return err;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Q_PrintStrlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L98
  mov    $0x0,%eax
  jmp    L43
L98:
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L15:
  cmpq   $0x0,-0x8(%rbp)
  je     L91
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5e,%al
  jne    L91
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L91
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L91
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0x37,%al
  jg     L91
  addq   $0x2,-0x8(%rbp)
  jmp    L56
L91:
  addq   $0x1,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  mov    -0xc(%rbp),%eax
L43:
  pop    %rbp
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if (((p) && *(p) == '^' && *((p) + 1) && (*((p) + 1) >= '0' && *((p) + 1) <= '7'))) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Q_PrintStrlen>:
  endbr64
  test   %rdi,%rdi
  je     L65
  movzbl (%rdi),%eax
  test   %al,%al
  je     L57
  mov    $0x0,%edx
  jmp    L59
L5:
  add    $0x1,%rdi
  add    $0x1,%edx
L74:
  movzbl (%rdi),%eax
  test   %al,%al
  je     L79
L59:
  cmp    $0x5e,%al
  jne    L5
  test   %rdi,%rdi
  je     L5
  movzbl 0x1(%rdi),%eax
  sub    $0x30,%eax
  cmp    $0x7,%al
  ja     L5
  add    $0x2,%rdi
  jmp    L74
L65:
  mov    $0x0,%edx
L79:
  mov    %edx,%eax
  ret
L57:
  mov    $0x0,%edx
  jmp    L79
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if (((p) && *(p) == '^' && *((p) + 1) && (*((p) + 1) >= '0' && *((p) + 1) <= '7'))) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Q_PrintStrlen>:
  endbr64
  test   %rdi,%rdi
  je     L7
  movzbl (%rdi),%eax
  xor    %r8d,%r8d
  jmp    L26
  nopl   0x0(%rax)
L18:
  add    $0x1,%rdi
  add    $0x1,%r8d
  mov    %edx,%eax
L26:
  test   %al,%al
  je     L58
L30:
  movzbl 0x1(%rdi),%edx
  cmp    $0x5e,%al
  jne    L18
  lea    -0x30(%rdx),%eax
  cmp    $0x7,%al
  ja     L18
  movzbl 0x2(%rdi),%eax
  add    $0x2,%rdi
  test   %al,%al
  jne    L30
L58:
  mov    %r8d,%eax
  ret
  nopl   (%rax)
L7:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int Q_PrintStrlen(const char *string) {
  int len;
  const char *p;
  if (!string) {
    return 0;
  }
  len = 0;
  p = string;
  while (*p) {
    if (((p) && *(p) == '^' && *((p) + 1) && (*((p) + 1) >= '0' && *((p) + 1) <= '7'))) {
      p += 2;
      continue;
    }
    p++;
    len++;
  }
  return len;
}
```