ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<multiply36>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L1
L15:
  movl   $0x0,-0x3c(%rbp)
  jmp    L10
L6:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L10:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L6
  addl   $0x1,-0x40(%rbp)
L1:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L15
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply36(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply36>:
  endbr64
  test   %edi,%edi
  jle    L22
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L26:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L2:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L2
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L26
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  ret
```

assistant: ```c
void multiply36(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply36>:
  endbr64
  test   %edi,%edi
  jle    L7
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L24:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L24
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L2
  pop    %rbx
  ret
L7:
  ret
```

assistant: ```c
void multiply36(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiply36>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L5
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L78:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L48
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L48
  nopl   0x0(%rax)
L79:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L79
  cmp    -0x24(%rsp),%r11d
  je     L84
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L84
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L84
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L84:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L78
L5:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L48:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L55:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L55
  mov    -0x18(%rsp),%r8
  jmp    L84
```

assistant: ```c
void multiply36(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<wrsz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %ax,-0x2(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movzwl -0x2(%rbp),%edx
  mov    %dl,(%rax)
  movzwl -0x2(%rbp),%eax
  sar    $0x8,%ax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void wrsz(int i, char *a) {
  short s;
  s = i;
  *a++ = s & 0xff;
  *a = (s >> 8) & 0xff;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<wrsz>:
  endbr64
  mov    %edi,%eax
  mov    %dil,(%rsi)
  movzbl %ah,%eax
  mov    %al,0x1(%rsi)
  ret
```

assistant: ```c
void wrsz(int i, char *a) {
  short s;
  s = i;
  *a++ = s & 0xff;
  *a = (s >> 8) & 0xff;
}
```
user: What is the c source code of the assembly code below?

```asm
<wrsz>:
  endbr64
  mov    %di,(%rsi)
  ret
```

assistant: ```c
void wrsz(int i, char *a) {
  short s;
  s = i;
  *a++ = s & 0xff;
  *a = (s >> 8) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<wrsz>:
  endbr64
  mov    %di,(%rsi)
  ret
```

assistant: ```c
void wrsz(int i, char *a) {
  short s;
  s = i;
  *a++ = s & 0xff;
  *a = (s >> 8) & 0xff;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_filesize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fgetpos@plt>
  mov    D4(%rip),%rax
  mov    (%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <fseeko@plt>
  lea    -0x14(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fgetpos@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fsetpos@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
uint64_t get_filesize(FILE *fp) {
  uint64_t file_size;
  fpos_t pos, pos_curr;
  fgetpos(fp, &pos_curr);
  fseeko(fp, 0, SEEK_END);
  fgetpos(fp, &pos);
  file_size = *(uint64_t *)&pos;
  fsetpos(fp, &pos_curr);
  return file_size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_filesize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rsi
  call   <fgetpos@plt>
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <fseeko@plt>
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <fgetpos@plt>
  mov    (%rsp),%r12d
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <fsetpos@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    %r12d,%eax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_filesize(FILE *fp) {
  uint64_t file_size;
  fpos_t pos, pos_curr;
  fgetpos(fp, &pos_curr);
  fseeko(fp, 0, SEEK_END);
  fgetpos(fp, &pos);
  file_size = *(uint64_t *)&pos;
  fsetpos(fp, &pos_curr);
  return file_size;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<get_filesize>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <fgetpos@plt>
  mov    D6(%rip),%rax
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <fseeko@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <fgetpos@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    (%rsp),%r13d
  call   <fsetpos@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_filesize(FILE *fp) {
  uint64_t file_size;
  fpos_t pos, pos_curr;
  fgetpos(fp, &pos_curr);
  fseeko(fp, 0, SEEK_END);
  fgetpos(fp, &pos);
  file_size = *(uint64_t *)&pos;
  fsetpos(fp, &pos_curr);
  return file_size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_filesize>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  mov    %r12,%rsi
  call   <fgetpos@plt>
  mov    D4(%rip),%rax
  xor    %esi,%esi
  mov    %rbp,%rdi
  mov    (%rax),%edx
  call   <fseeko@plt>
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <fgetpos@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    (%rsp),%r13d
  call   <fsetpos@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  mov    %r13d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint64_t get_filesize(FILE *fp) {
  uint64_t file_size;
  fpos_t pos, pos_curr;
  fgetpos(fp, &pos_curr);
  fseeko(fp, 0, SEEK_END);
  fgetpos(fp, &pos);
  file_size = *(uint64_t *)&pos;
  fsetpos(fp, &pos_curr);
  return file_size;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mkfifoat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  or     -0x18(%rbp),%eax
  mov    %eax,%ecx
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  lea    -0xc(%rbp),%rdi
  mov    -0x20(%rbp),%rdx
  mov    -0x14(%rbp),%esi
  mov    %rdi,%r8
  mov    %eax,%edi
  call   <__xmknodat@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int mkfifoat(int fd, const char *file, mode_t mode) {
  dev_t dev = 0;
  return __xmknodat(_MKNOD_VER, fd, file, mode | S_IFIFO, &dev);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<mkfifoat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  mov    D18(%rip),%rax
  mov    %edx,%ecx
  or     (%rax),%ecx
  lea    0x4(%rsp),%r8
  mov    %rsi,%rdx
  mov    %edi,%esi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <__xmknodat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mkfifoat(int fd, const char *file, mode_t mode) {
  dev_t dev = 0;
  return __xmknodat(_MKNOD_VER, fd, file, mode | S_IFIFO, &dev);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mkfifoat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  lea    0x4(%rsp),%r8
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  or     %edx,%ecx
  mov    %rsi,%rdx
  mov    %edi,%esi
  mov    (%rax),%edi
  call   <__xmknodat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mkfifoat(int fd, const char *file, mode_t mode) {
  dev_t dev = 0;
  return __xmknodat(_MKNOD_VER, fd, file, mode | S_IFIFO, &dev);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mkfifoat>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D12(%rip),%rax
  lea    0x4(%rsp),%r8
  movl   $0x0,0x4(%rsp)
  mov    (%rax),%ecx
  mov    D18(%rip),%rax
  or     %edx,%ecx
  mov    %rsi,%rdx
  mov    %edi,%esi
  mov    (%rax),%edi
  call   <__xmknodat@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int mkfifoat(int fd, const char *file, mode_t mode) {
  dev_t dev = 0;
  return __xmknodat(_MKNOD_VER, fd, file, mode | S_IFIFO, &dev);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x1,-0x4(%rbp)
  movzbl -0x14(%rbp),%eax
  test   %eax,%eax
  setne  %al
  xor    $0x1,%eax
  movzbl %al,%eax
  mov    %al,-0x3(%rbp)
  andb   $0x1,-0x3(%rbp)
  movzbl -0x3(%rbp),%eax
  cmp    -0x4(%rbp),%al
  sete   %al
  mov    %al,-0x2(%rbp)
  movzbl -0x2(%rbp),%eax
  cmp    -0x14(%rbp),%al
  sete   %al
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int foo(_Bool x) {
  _Bool t = 1;
  _Bool xx = !x;
  _Bool y = xx == t;
  _Bool z = y == x;
  return z ? 1 : 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<foo>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int foo(_Bool x) {
  _Bool t = 1;
  _Bool xx = !x;
  _Bool y = xx == t;
  _Bool z = y == x;
  return z ? 1 : 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo(_Bool x) {
  _Bool t = 1;
  _Bool xx = !x;
  _Bool y = xx == t;
  _Bool z = y == x;
  return z ? 1 : 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<foo>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int foo(_Bool x) {
  _Bool t = 1;
  _Bool xx = !x;
  _Bool y = xx == t;
  _Bool z = y == x;
  return z ? 1 : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<exfiles_alloc_group_from_gr_entry>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,0x8(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  test   %rax,%rax
  je     L11
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L26
L11:
  mov    $0xffffffff,%eax
  jmp    L0
L26:
  mov    $0x0,%eax
L0:
  leave
  ret
```

assistant: ```c
int exfiles_alloc_group_from_gr_entry(struct group *grbuf, char **gr_entry) {
  grbuf->gr_name = malloc(sizeof(char) * (strlen(gr_entry[0]) + 1));
  grbuf->gr_passwd = malloc(sizeof(char) * (strlen(gr_entry[1]) + 1));
  if (grbuf->gr_name == NULL || grbuf->gr_passwd == NULL)
    return -1;
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<exfiles_alloc_group_from_gr_entry>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    (%rsi),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rbx)
  mov    0x8(%rbp),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    %rax,(%rbx)
  cmpq   $0x0,0x8(%rbx)
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  neg    %eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int exfiles_alloc_group_from_gr_entry(struct group *grbuf, char **gr_entry) {
  grbuf->gr_name = malloc(sizeof(char) * (strlen(gr_entry[0]) + 1));
  grbuf->gr_passwd = malloc(sizeof(char) * (strlen(gr_entry[1]) + 1));
  if (grbuf->gr_name == NULL || grbuf->gr_passwd == NULL)
    return -1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<exfiles_alloc_group_from_gr_entry>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    0x8(%rbp),%rdi
  mov    %rax,0x8(%rbx)
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  cmpq   $0x0,0x8(%rbx)
  mov    %rax,%rdx
  mov    %rax,(%rbx)
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int exfiles_alloc_group_from_gr_entry(struct group *grbuf, char **gr_entry) {
  grbuf->gr_name = malloc(sizeof(char) * (strlen(gr_entry[0]) + 1));
  grbuf->gr_passwd = malloc(sizeof(char) * (strlen(gr_entry[1]) + 1));
  if (grbuf->gr_name == NULL || grbuf->gr_passwd == NULL)
    return -1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<exfiles_alloc_group_from_gr_entry>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    0x8(%rbp),%rdi
  mov    %rax,0x8(%rbx)
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  cmpq   $0x0,0x8(%rbx)
  mov    %rax,%rdx
  mov    %rax,(%rbx)
  sete   %al
  test   %rdx,%rdx
  sete   %dl
  add    $0x8,%rsp
  or     %edx,%eax
  pop    %rbx
  pop    %rbp
  movzbl %al,%eax
  neg    %eax
  ret
```

assistant: ```c
int exfiles_alloc_group_from_gr_entry(struct group *grbuf, char **gr_entry) {
  grbuf->gr_name = malloc(sizeof(char) * (strlen(gr_entry[0]) + 1));
  grbuf->gr_passwd = malloc(sizeof(char) * (strlen(gr_entry[1]) + 1));
  if (grbuf->gr_name == NULL || grbuf->gr_passwd == NULL)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L0
L23:
  mov    $0x0,%eax
  call   <rand_float@plt>
  movss  D3(%rip),%xmm1
  mulss  %xmm1,%xmm0
  movss  D35(%rip),%xmm1
  subss  %xmm1,%xmm0
  movss  %xmm0,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movd   %eax,%xmm0
  call   <stdlib_base_is_infinitef@plt>
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  je     L9
  cmpl   $0x0,-0x1c(%rbp)
  je     L9
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L59
L9:
  addl   $0x1,-0x18(%rbp)
L0:
  cmpl   $0xf423f,-0x18(%rbp)
  jle    L23
L59:
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  subsd  -0x10(%rbp),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  je     L51
  cmpl   $0x0,-0x1c(%rbp)
  je     L51
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L51:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D3
datatype: byte[4]
name: read_data
arguments: label: D35
datatype: byte[4]
name: read_data
arguments: label: D2
datatype: string

tool: {"D3": [0x80,0x96,0x18,0x4b]}

tool: {"D35": [0x80,0x96,0x98,0x4a]}

tool: D2: should return either true or false


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  float x;
  bool b;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (rand_float() * 1.0e7f) - 5.0e6f;
    b = stdlib_base_is_infinitef(x);
    if (b != true && b != false) {
      printf("should return either true or false\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (b != true && b != false) {
    printf("should return either true or false\n");
  }
  return elapsed;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<benchmark>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %xmm0,%r12
  mov    $0xf4240,%ebx
L12:
  mov    $0x0,%eax
  call   <rand_float@plt>
  mulss  D23(%rip),%xmm0
  subss  D26(%rip),%xmm0
  call   <stdlib_base_is_infinitef@plt>
  cmp    $0x1,%eax
  ja     L24
  sub    $0x1,%ebx
  jne    L12
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm2
  subsd  %xmm2,%xmm0
  movq   %xmm0,%rbx
  jmp    L10
L24:
  lea    D13(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <tic@plt>
  movq   %r12,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  mov    %rbp,%rdi
  call   <printf@plt>
L10:
  movq   %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: tag: D23
data_type: byte[4]
name: parse_data
arguments: tag: D26
data_type: byte[4]
name: parse_data
arguments: tag: D13
data_type: string

tool: {"D23": [0x80,0x96,0x18,0x4b]}

tool: {"D26": [0x80,0x96,0x98,0x4a]}

tool: D13: should return either true or false


assistant: ```c
double benchmark() {
  double elapsed;
  double t;
  float x;
  bool b;
  int i;
  t = tic();
  for (i = 0; i < 1000000; i++) {
    x = (rand_float() * 1.0e7f) - 5.0e6f;
    b = stdlib_base_is_infinitef(x);
    if (b != true && b != false) {
      printf("should return either true or false\n");
      break;
    }
  }
  elapsed = tic() - t;
  if (b != true && b != false) {
    printf("should return either true or false\n");
  }
  return elapsed;
}
```