user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movabs $0x303130312e3031,%rax
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <atof@plt>
  lea    D85(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  movabs $0x30303330332e3032,%rax
  movabs $0x7369207369685420,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x7473657420,%rax
  mov    %rax,0x20(%rsp)
  movl   $0x0,0x28(%rsp)
  movw   $0x0,0x2c(%rsp)
  mov    %rsp,%rsi
  lea    0x10(%rsp),%rdi
  call   <strtod@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <puts@plt>
  lea    D2(%rip),%rdi
  call   <atof@plt>
  lea    D24(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D68(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D75(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D87(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D65(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D94(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D78(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D35(%rip),%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  lea    D26(%rip),%rbp
  mov    %rbp,%rdi
  call   <atof@plt>
  mov    %rbx,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <atoll@plt>
  lea    D117(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x48,%rsp
  pop    %rbx
  pop    %rbp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D85
type: string
name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D24
type: string
name: retrieve_data
arguments: data_label: D68
type: string
name: retrieve_data
arguments: data_label: D75
type: string
name: retrieve_data
arguments: data_label: D87
type: string
name: retrieve_data
arguments: data_label: D65
type: string
name: retrieve_data
arguments: data_label: D94
type: string
name: retrieve_data
arguments: data_label: D78
type: string
name: retrieve_data
arguments: data_label: D35
type: string
name: retrieve_data
arguments: data_label: D26
type: string
name: retrieve_data
arguments: data_label: D117
type: string

tool: D85: %lf


tool: D2:   -0.0000000123junk

tool: D24: %g


tool: D68: 0.012

tool: D75: 15e16

tool: D87: -0x1afp-2

tool: D65: inF

tool: D94: Nan

tool: D78: 1.0e+309

tool: D35: 0.0

tool: D26: junk

tool: D117: %lld


assistant: ```c
int main() {
  char str[] = "10.1010";
  double d = atof(str);
  printf("%lf\n", d);
  char str2[30] = "20.30300 This is test";
  char *ptr;
  double ret;
  ret = strtod(str2, &ptr);
  printf("%lf\n", ret);
  printf("%s\n", ptr);
  printf("%g\n", atof("  -0.0000000123junk"));
  printf("%g\n", atof("0.012"));
  printf("%g\n", atof("15e16"));
  printf("%g\n", atof("-0x1afp-2"));
  printf("%g\n", atof("inF"));
  printf("%g\n", atof("Nan"));
  printf("%g\n", atof("1.0e+309"));
  printf("%g\n", atof("0.0"));
  printf("%g\n", atof("junk"));
  printf("%lld\n", atoll("junk"));
  return 0;
}
```