ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_len_word>:
  endbr64
  movzbl (%rdi),%eax
  test   $0xdf,%al
  je     L6
  cmp    $0x9,%al
  je     L6
  mov    $0x1,%eax
  jmp    L2
  cs nopw 0x0(%rax,%rax,1)
L27:
  cmp    $0x9,%dl
  je     L20
L2:
  movzbl (%rdi,%rax,1),%edx
  mov    %eax,%r8d
  add    $0x1,%rax
  test   $0xdf,%dl
  jne    L27
L20:
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int ft_len_word(char *str) {
  int i;
  i = 0;
  while (str[i] && str[i] != ' ' && str[i] != '\t')
    i++;
  return (i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  %xmm1,-0x30(%rbp)
  movsd  %xmm2,-0x38(%rbp)
  movsd  %xmm3,-0x40(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    $0x2,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double distance(double x1, double x2, double y1, double y2) {
  double dist = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
  return dist;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<distance>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  movq   %xmm2,%r14
  movq   %xmm3,%rbp
  subsd  %xmm0,%xmm1
  mov    $0x2,%edi
  movapd %xmm1,%xmm0
  call   <pow@plt>
  mov    %rax,%rbx
  movq   %rbp,%xmm0
  movq   %r14,%xmm4
  subsd  %xmm4,%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  lea    (%rbx,%rax,1),%rdi
  call   <sqrt@plt>
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

assistant: ```c
double distance(double x1, double x2, double y1, double y2) {
  double dist = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
  return dist;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<distance>:
  endbr64
  push   %rbx
  subsd  %xmm0,%xmm1
  mov    $0x2,%edi
  sub    $0x10,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm2,(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm3
  subsd  (%rsp),%xmm3
  mov    $0x2,%edi
  mov    %rax,%rbx
  movapd %xmm3,%xmm0
  call   <pow@plt>
  add    $0x10,%rsp
  lea    (%rbx,%rax,1),%rdi
  pop    %rbx
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double distance(double x1, double x2, double y1, double y2) {
  double dist = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
  return dist;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<distance>:
  endbr64
  push   %rbx
  subsd  %xmm0,%xmm1
  mov    $0x2,%edi
  sub    $0x10,%rsp
  movapd %xmm1,%xmm0
  movsd  %xmm2,(%rsp)
  movsd  %xmm3,0x8(%rsp)
  call   <pow@plt>
  movsd  0x8(%rsp),%xmm3
  subsd  (%rsp),%xmm3
  mov    $0x2,%edi
  mov    %rax,%rbx
  movapd %xmm3,%xmm0
  call   <pow@plt>
  add    $0x10,%rsp
  lea    (%rbx,%rax,1),%rdi
  pop    %rbx
  jmp    1060 <sqrt@plt>
```

assistant: ```c
double distance(double x1, double x2, double y1, double y2) {
  double dist = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
  return dist;
}
```
user: Translate the below assembly code into C programming language:

```asm
<revstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L19:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0xd(%rbp)
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0xd(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L8:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void revstr(char *str) {
  int end, mid;
  int i;
  char tmp;
  end = strlen(str);
  mid = end / 2;
  end = end - 1;
  for (i = 0; i < mid; i++) {
    tmp = str[i];
    str[i] = str[end - i];
    str[end - i] = tmp;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<revstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L2
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  add    %rbx,%rdx
  mov    $0x0,%eax
L6:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rdx),%esi
  mov    %sil,(%rbx,%rax,1)
  mov    %cl,(%rdx)
  add    $0x1,%rax
  sub    $0x1,%rdx
  cmp    %eax,%edi
  jg     L6
L2:
  pop    %rbx
  ret
```

assistant: ```c
void revstr(char *str) {
  int end, mid;
  int i;
  char tmp;
  end = strlen(str);
  mid = end / 2;
  end = end - 1;
  for (i = 0; i < mid; i++) {
    tmp = str[i];
    str[i] = str[end - i];
    str[end - i] = tmp;
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<revstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L5
  lea    -0x1(%rax),%edx
  xor    %eax,%eax
  movslq %edx,%rdx
  add    %rbx,%rdx
  cs nopw 0x0(%rax,%rax,1)
L12:
  movzbl (%rdx),%esi
  movzbl (%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rbx,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%edi
  jg     L12
L5:
  pop    %rbx
  ret
```

assistant: ```c
void revstr(char *str) {
  int end, mid;
  int i;
  char tmp;
  end = strlen(str);
  mid = end / 2;
  end = end - 1;
  for (i = 0; i < mid; i++) {
    tmp = str[i];
    str[i] = str[end - i];
    str[end - i] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<revstr>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  cmp    $0x1,%eax
  jle    L11
  lea    -0x1(%rax),%edx
  xor    %eax,%eax
  movslq %edx,%rdx
  add    %rbx,%rdx
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl (%rdx),%esi
  movzbl (%rbx,%rax,1),%ecx
  sub    $0x1,%rdx
  mov    %sil,(%rbx,%rax,1)
  add    $0x1,%rax
  mov    %cl,0x1(%rdx)
  cmp    %eax,%edi
  jg     L19
L11:
  pop    %rbx
  ret
```

assistant: ```c
void revstr(char *str) {
  int end, mid;
  int i;
  char tmp;
  end = strlen(str);
  mid = end / 2;
  end = end - 1;
  for (i = 0; i < mid; i++) {
    tmp = str[i];
    str[i] = str[end - i];
    str[end - i] = tmp;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L0
  mov    -0x8(%rbp),%rax
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <xxswap4@plt>
L0:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  movd   %edx,%xmm0
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
type_guessed: string

tool: D0: %f

assistant: ```c
void print_float(char *buf, unsigned char *c, int bigendian) {
  float *f;
  f = (float *)c;
  if (bigendian)
    xxswap4(f, 1, 1);
  sprintf(buf, "%f", *f);
}
```
user: What is the c source code of the assembly code below?

```asm
<print_float>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  test   %edx,%edx
  jne    L1
L3:
  movss  (%rbx),%xmm0
  lea    D8(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <xxswap4@plt>
  jmp    L3
```

tool_calls: name: disassemble_data
arguments: label: D8
datatype: string

tool: D8: %f

assistant: ```c
void print_float(char *buf, unsigned char *c, int bigendian) {
  float *f;
  f = (float *)c;
  if (bigendian)
    xxswap4(f, 1, 1);
  sprintf(buf, "%f", *f);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_float>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L9
L5:
  movss  (%rbx),%xmm0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D3(%rip),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1070 <sprintf@plt>
  nopl   (%rax)
L9:
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <xxswap4@plt>
  jmp    L5
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: %f

assistant: ```c
void print_float(char *buf, unsigned char *c, int bigendian) {
  float *f;
  f = (float *)c;
  if (bigendian)
    xxswap4(f, 1, 1);
  sprintf(buf, "%f", *f);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_float>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  test   %edx,%edx
  jne    L18
L13:
  movss  (%rbx),%xmm0
  add    $0x8,%rsp
  mov    %rbp,%rdi
  lea    D1(%rip),%rsi
  pop    %rbx
  pop    %rbp
  jmp    1070 <sprintf@plt>
  nopl   (%rax)
L18:
  mov    $0x1,%edx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <xxswap4@plt>
  jmp    L13
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_infered: string

tool: D1: %f

assistant: ```c
void print_float(char *buf, unsigned char *c, int bigendian) {
  float *f;
  f = (float *)c;
  if (bigendian)
    xxswap4(f, 1, 1);
  sprintf(buf, "%f", *f);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convert_in6arpa>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x28,%edi
  call   <malloc@plt>
  mov    %eax,%edi
  mov    $0x540,%edx
  lea    D19(%rip),%rsi
  call   <do_nofail@plt>
  mov    %rax,%rbx
  lea    D5(%rip),%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  je     L122
  cmp    %rax,%rbp
  je     L122
  sub    $0x1,%rax
  mov    $0x1,%edi
  mov    $0x0,%edx
  jmp    L30
L122:
  movb   $0x0,(%rbx)
L121:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L145:
  movslq %edx,%rdx
  movb   $0x0,(%rbx,%rdx,1)
  jmp    L121
L62:
  cmpb   $0x2e,-0x1(%rax)
  jne    L29
  add    $0x1,%edi
  lea    -0x1(%rax),%rdx
  cmp    %rdx,%rbp
  je     L9
  sub    $0x2,%rax
  mov    %ecx,%edx
L30:
  movzbl (%rax),%esi
  lea    -0x30(%rsi),%ecx
  cmp    $0x9,%cl
  jbe    L1
  mov    %esi,%ecx
  and    $0xffffffdf,%ecx
  sub    $0x41,%ecx
  cmp    $0x5,%cl
  ja     L145
L1:
  lea    0x1(%rdx),%ecx
  movslq %edx,%r8
  mov    %sil,(%rbx,%r8,1)
  cmp    $0x26,%edx
  je     L75
  cmp    %rbp,%rax
  je     L75
  test   $0x3,%dil
  jne    L62
  movslq %ecx,%rcx
  movb   $0x3a,(%rbx,%rcx,1)
  lea    0x2(%rdx),%ecx
  jmp    L62
L29:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  jmp    L121
L9:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  jmp    L121
L75:
  movslq %ecx,%rcx
  movb   $0x0,(%rbx,%rcx,1)
  jmp    L121
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D5
type_infered: string

tool: D19: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mrash/psad/refs/heads/master/deps/whois/whois.c

tool: D5: .ip6.arpa

assistant: ```c
char *convert_in6arpa(const char *s) {
  char *ip, *p;
  int character = 0;
  int digits = 1;
  ip = do_nofail((malloc(40)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mrash/psad/refs/heads/master/deps/whois/whois.c", 1344);
  p = strstr(s, ".ip6.arpa");
  if (!p || p == s) {
    ip[character] = '\0';
    return ip;
  }
  p--;
  while (1) {
    if (!((*p >= '0' && *p <= '9') || (*p >= 'a' && *p <= 'f') || (*p >= 'A' && *p <= 'F'))) {
      ip[character] = '\0';
      return ip;
    }
    ip[character++] = *p;
    if (p == s)
      break;
    if (character == 39)
      break;
    if ((digits++ % 4) == 0)
      ip[character++] = ':';
    p--;
    if (*p != '.') {
      ip[character] = '\0';
      return ip;
    }
    if (p == s) {
      ip[character] = '\0';
      return ip;
    }
    p--;
  }
  ip[character] = '\0';
  return ip;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<convert_in6arpa>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D0(%rip),%rsi
  mov    $0x540,%edx
  mov    %eax,%edi
  call   <do_nofail@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strstr@plt>
  test   %rax,%rax
  je     L83
  cmp    %rax,%rbx
  je     L83
  sub    $0x1,%rax
  mov    $0x1,%edi
  xor    %esi,%esi
  jmp    L96
  nopl   0x0(%rax)
L32:
  cmp    $0x27,%edx
  je     L4
  test   $0x3,%dil
  jne    L14
  movslq %edx,%rdx
  movb   $0x3a,(%r12,%rdx,1)
  lea    0x2(%rsi),%edx
L14:
  cmpb   $0x2e,-0x1(%rax)
  jne    L31
  lea    -0x1(%rax),%rcx
  add    $0x1,%edi
  cmp    %rcx,%rbx
  je     L31
  sub    $0x2,%rax
  movslq %edx,%rsi
L96:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L62
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  ja     L23
L62:
  movslq %esi,%r8
  lea    0x1(%rsi),%edx
  mov    %cl,(%r12,%r8,1)
  cmp    %rbx,%rax
  jne    L32
  movslq %edx,%rdx
L92:
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L83:
  movb   $0x0,(%r12)
L85:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L31:
  movslq %edx,%rdx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    $0x27,%edx
  jmp    L92
  nop
L23:
  movb   $0x0,(%r12,%rsi,1)
  jmp    L85
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string
name: parse_data
arguments: data_tag: D3
datatype: string

tool: D0: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mrash/psad/refs/heads/master/deps/whois/whois.c

tool: D3: .ip6.arpa

assistant: ```c
char *convert_in6arpa(const char *s) {
  char *ip, *p;
  int character = 0;
  int digits = 1;
  ip = do_nofail((malloc(40)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mrash/psad/refs/heads/master/deps/whois/whois.c", 1344);
  p = strstr(s, ".ip6.arpa");
  if (!p || p == s) {
    ip[character] = '\0';
    return ip;
  }
  p--;
  while (1) {
    if (!((*p >= '0' && *p <= '9') || (*p >= 'a' && *p <= 'f') || (*p >= 'A' && *p <= 'F'))) {
      ip[character] = '\0';
      return ip;
    }
    ip[character++] = *p;
    if (p == s)
      break;
    if (character == 39)
      break;
    if ((digits++ % 4) == 0)
      ip[character++] = ':';
    p--;
    if (*p != '.') {
      ip[character] = '\0';
      return ip;
    }
    if (p == s) {
      ip[character] = '\0';
      return ip;
    }
    p--;
  }
  ip[character] = '\0';
  return ip;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convert_in6arpa>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x28,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  lea    D7(%rip),%rsi
  mov    $0x540,%edx
  mov    %eax,%edi
  call   <do_nofail@plt>
  lea    D3(%rip),%rsi
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <strstr@plt>
  test   %rax,%rax
  je     L70
  cmp    %rax,%rbx
  je     L70
  sub    $0x1,%rax
  mov    $0x1,%edi
  xor    %esi,%esi
  jmp    L0
  nopl   0x0(%rax)
L23:
  cmp    $0x27,%edx
  je     L73
  test   $0x3,%dil
  jne    L95
  movslq %edx,%rdx
  movb   $0x3a,(%r12,%rdx,1)
  lea    0x2(%rsi),%edx
L95:
  cmpb   $0x2e,-0x1(%rax)
  jne    L37
  lea    -0x1(%rax),%rcx
  add    $0x1,%edi
  cmp    %rcx,%rbx
  je     L37
  sub    $0x2,%rax
  movslq %edx,%rsi
L0:
  movzbl (%rax),%ecx
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%dl
  jbe    L21
  mov    %ecx,%edx
  and    $0xffffffdf,%edx
  sub    $0x41,%edx
  cmp    $0x5,%dl
  ja     L87
L21:
  movslq %esi,%r8
  lea    0x1(%rsi),%edx
  mov    %cl,(%r12,%r8,1)
  cmp    %rbx,%rax
  jne    L23
  movslq %edx,%rdx
L47:
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopl   (%rax)
L70:
  movb   $0x0,(%r12)
L55:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
L37:
  movslq %edx,%rdx
  mov    %r12,%rax
  movb   $0x0,(%r12,%rdx,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L73:
  mov    $0x27,%edx
  jmp    L47
  nop
L87:
  movb   $0x0,(%r12,%rsi,1)
  jmp    L55
```

tool_calls: name: read_data
arguments: tag: D7
data_type: string
name: read_data
arguments: tag: D3
data_type: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mrash/psad/refs/heads/master/deps/whois/whois.c

tool: D3: .ip6.arpa

assistant: ```c
char *convert_in6arpa(const char *s) {
  char *ip, *p;
  int character = 0;
  int digits = 1;
  ip = do_nofail((malloc(40)), "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/mrash/psad/refs/heads/master/deps/whois/whois.c", 1344);
  p = strstr(s, ".ip6.arpa");
  if (!p || p == s) {
    ip[character] = '\0';
    return ip;
  }
  p--;
  while (1) {
    if (!((*p >= '0' && *p <= '9') || (*p >= 'a' && *p <= 'f') || (*p >= 'A' && *p <= 'F'))) {
      ip[character] = '\0';
      return ip;
    }
    ip[character++] = *p;
    if (p == s)
      break;
    if (character == 39)
      break;
    if ((digits++ % 4) == 0)
      ip[character++] = ':';
    p--;
    if (*p != '.') {
      ip[character] = '\0';
      return ip;
    }
    if (p == s) {
      ip[character] = '\0';
      return ip;
    }
    p--;
  }
  ip[character] = '\0';
  return ip;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<chmod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %ax,-0xc(%rbp)
  mov    $0x8c004004,%eax
  mov    (%rax),%eax
  cmp    $0xdeadbeef,%eax
  jne    L13
  movswl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x8,%edi
  call   <dcloadsyscall@plt>
  jmp    L11
L13:
  mov    $0xffffffff,%eax
L11:
  leave
  ret
```

assistant: ```c
int chmod(const char *path, short mode) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(8, path, mode);
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<chmod>:
  endbr64
  mov    $0x8c004004,%eax
  cmpl   $0xdeadbeef,(%rax)
  jne    L0
  sub    $0x8,%rsp
  movswl %si,%edx
  mov    %rdi,%rsi
  mov    $0x8,%edi
  call   <dcloadsyscall@plt>
  add    $0x8,%rsp
  ret
L0:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int chmod(const char *path, short mode) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(8, path, mode);
  else
    return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chmod>:
  endbr64
  mov    $0x8c004004,%eax
  cmpl   $0xdeadbeef,(%rax)
  jne    L9
  movswl %si,%edx
  mov    %rdi,%rsi
  mov    $0x8,%edi
  jmp    1050 <dcloadsyscall@plt>
  nopl   0x0(%rax)
L9:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int chmod(const char *path, short mode) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(8, path, mode);
  else
    return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chmod>:
  endbr64
  mov    $0x8c004004,%eax
  cmpl   $0xdeadbeef,(%rax)
  jne    L8
  movswl %si,%edx
  mov    %rdi,%rsi
  mov    $0x8,%edi
  jmp    1050 <dcloadsyscall@plt>
  nopl   0x0(%rax)
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int chmod(const char *path, short mode) {
  if (*(unsigned int *)0x8c004004 == 0xdeadbeef)
    return dcloadsyscall(8, path, mode);
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<minibuf_write>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L3
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L3:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <minibuf_vwrite@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void minibuf_write(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  minibuf_vwrite(fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<minibuf_write>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%esi
  mov    %rbx,%rdi
  call   <minibuf_vwrite@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void minibuf_write(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  minibuf_vwrite(fmt, ap);
  va_end(ap);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<minibuf_write>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <minibuf_vwrite@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void minibuf_write(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  minibuf_vwrite(fmt, ap);
  va_end(ap);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<minibuf_write>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <minibuf_vwrite@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void minibuf_write(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  minibuf_vwrite(fmt, ap);
  va_end(ap);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<cmd_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <check_limits@plt>
  test   %rax,%rax
  jns    L9
  movl   $0xffffffff,-0x4(%rbp)
L9:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <check_draw@plt>
  test   %rax,%rax
  jns    L1
  movl   $0xffffffff,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int cmd_check(struct command_opts *opts) {
  int ret = 0;
  if (check_limits(opts) < 0)
    ret = -1;
  if (check_draw(opts) < 0)
    ret = -1;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmd_check>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <check_limits@plt>
  sar    $0x3f,%rax
  mov    %rax,%rbx
  mov    %rbp,%rdi
  call   <check_draw@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovs  %eax,%ebx
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int cmd_check(struct command_opts *opts) {
  int ret = 0;
  if (check_limits(opts) < 0)
    ret = -1;
  if (check_draw(opts) < 0)
    ret = -1;
  return ret;
}
```