ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  jne    L17
L35:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  mov    $0x0,%esi
  call   <strtoul@plt>
  mov    %rax,0x8(%rsp)
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  call   <RandomFunc@plt>
  movabs $0xffffffff0ae7c66c,%rax
  cmp    %rax,0x10(%rsp)
  je     L23
L4:
  mov    0x10(%rsp),%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L17:
  mov    $0x1,%esi
  lea    D8(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L35
L23:
  lea    D23(%rip),%rdi
  call   <puts@plt>
  jmp    L4
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D27
data_type: string
name: unpack_data
arguments: tag: D8
data_type: string
name: unpack_data
arguments: tag: D23
data_type: string

tool: D27: %lu


tool: D8: Call this program with %i arguments


tool: D23: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744069597546092UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L5
  lea    D24(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0xffffffff0ae7c66c,%rax
  cmp    %rax,%rsi
  je     L9
L12:
  xor    %eax,%eax
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L9:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L12
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D24
type: string
name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D3
type: string

tool: D24: Call this program with %i arguments


tool: D1: %lu


tool: D3: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744069597546092UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L32
  lea    D10(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L32:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%rdi
  mov    %rax,0x8(%rsp)
  call   <RandomFunc@plt>
  mov    0x10(%rsp),%rsi
  movabs $0xffffffff0ae7c66c,%rax
  cmp    %rax,%rsi
  je     L7
L39:
  xor    %eax,%eax
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L7:
  lea    D29(%rip),%rdi
  call   <puts@plt>
  mov    0x10(%rsp),%rsi
  jmp    L39
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
type_guessed: string
name: unpack_data
arguments: label: D28
type_guessed: string
name: unpack_data
arguments: label: D29
type_guessed: string

tool: D10: Call this program with %i arguments


tool: D28: %lu


tool: D29: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned long input[1];
  unsigned long output[1];
  int randomFuns_i5;
  unsigned long randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 18446744069597546092UL) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%lu\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  jmp    L77
L56:
  mov    $0x0,%eax
  call   <nondet_bool@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0xe(%rbp)
  mov    $0x0,%eax
  call   <nondet_bool@plt>
  test   %eax,%eax
  setne  %al
  mov    %al,-0xd(%rbp)
  cmpb   $0x0,-0xe(%rbp)
  je     L17
  subl   $0x1,-0xc(%rbp)
  jmp    L77
L17:
  cmpb   $0x0,-0xd(%rbp)
  je     L79
  subl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L77
L79:
  subl   $0x1,-0x4(%rbp)
  mov    $0x0,%eax
  call   <nondet_int@plt>
  mov    %eax,-0xc(%rbp)
L77:
  cmpl   $0x0,-0xc(%rbp)
  jle    L50
  cmpl   $0x0,-0x8(%rbp)
  jle    L50
  cmpl   $0x0,-0x4(%rbp)
  jg     L56
L50:
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int x, y, z;
  while (x > 0 && y > 0 && z > 0) {
    _Bool c1 = nondet_bool();
    _Bool c2 = nondet_bool();
    if (c1) {
      x = x - 1;
    } else if (c2) {
      y = y - 1;
      z = nondet_int();
    } else {
      z = z - 1;
      x = nondet_int();
    }
  }
  assert(0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  mov    $0x0,%eax
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int x, y, z;
  while (x > 0 && y > 0 && z > 0) {
    _Bool c1 = nondet_bool();
    _Bool c2 = nondet_bool();
    if (c1) {
      x = x - 1;
    } else if (c2) {
      y = y - 1;
      z = nondet_int();
    } else {
      z = z - 1;
      x = nondet_int();
    }
  }
  assert(0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int x, y, z;
  while (x > 0 && y > 0 && z > 0) {
    _Bool c1 = nondet_bool();
    _Bool c2 = nondet_bool();
    if (c1) {
      x = x - 1;
    } else if (c2) {
      y = y - 1;
      z = nondet_int();
    } else {
      z = z - 1;
      x = nondet_int();
    }
  }
  assert(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  xor    %eax,%eax
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int x, y, z;
  while (x > 0 && y > 0 && z > 0) {
    _Bool c1 = nondet_bool();
    _Bool c2 = nondet_bool();
    if (c1) {
      x = x - 1;
    } else if (c2) {
      y = y - 1;
      z = nondet_int();
    } else {
      z = z - 1;
      x = nondet_int();
    }
  }
  assert(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<try_numeric_match>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L25
L23:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2f,-0x4(%rbp)
  jle    L71
  cmpl   $0x39,-0x4(%rbp)
  jg     L71
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x8(%rbp)
  ja     L128
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    %eax,-0x8(%rbp)
  jne    L42
  mov    D13(%rip),%rax
  mov    (%rax),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  lea    0x2f(%rdx),%eax
  cmp    %eax,-0x4(%rbp)
  jle    L42
L128:
  mov    $0xffffffff,%eax
  jmp    L57
L42:
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L25
L71:
  mov    $0xffffffff,%eax
  jmp    L57
L25:
  mov    -0x18(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L23
  mov    -0x8(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L108
  mov    -0x8(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jbe    L89
L108:
  mov    $0xffffffff,%eax
  jmp    L57
L89:
  mov    -0x8(%rbp),%eax
L57:
  pop    %rbp
  ret
```

assistant: ```c
int try_numeric_match(const char *buf, const char *limit, unsigned low, unsigned high) {
  unsigned n = 0;
  while (buf < limit) {
    int ch = (unsigned char)*buf++;
    if (ch >= '0' && ch <= '9') {
      if (n > INT_MAX / 10 || (n == INT_MAX / 10 && ch >= INT_MAX % 10 + '0'))
        return -1;
      n = 10 * n + ch - '0';
    } else
      return -1;
  }
  if (n < low || n > high)
    return -1;
  return (int)n;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<try_numeric_match>:
  endbr64
  mov    %rsi,%r9
  mov    %edx,%r10d
  mov    %ecx,%r11d
  cmp    %rsi,%rdi
  jae    L0
  mov    D3(%rip),%rax
  mov    (%rax),%r8d
  movslq %r8d,%rsi
  imul   $0x66666667,%rsi,%rsi
  sar    $0x22,%rsi
  mov    %r8d,%eax
  sar    $0x1f,%eax
  sub    %eax,%esi
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%r8d
  add    $0x2f,%r8d
  mov    $0x0,%eax
  jmp    L63
L17:
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  cmp    %rdi,%r9
  je     L43
L63:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%ecx
  movzbl %cl,%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L34
  cmp    %eax,%esi
  jb     L30
  jne    L17
  movzbl %cl,%ecx
  cmp    %ecx,%r8d
  jge    L17
  mov    $0xffffffff,%eax
  ret
L0:
  mov    $0x0,%eax
L43:
  cmp    %eax,%r10d
  ja     L59
  cmp    %eax,%r11d
  jb     L59
  ret
L34:
  mov    $0xffffffff,%eax
  ret
L30:
  mov    $0xffffffff,%eax
  ret
L59:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int try_numeric_match(const char *buf, const char *limit, unsigned low, unsigned high) {
  unsigned n = 0;
  while (buf < limit) {
    int ch = (unsigned char)*buf++;
    if (ch >= '0' && ch <= '9') {
      if (n > INT_MAX / 10 || (n == INT_MAX / 10 && ch >= INT_MAX % 10 + '0'))
        return -1;
      n = 10 * n + ch - '0';
    } else
      return -1;
  }
  if (n < low || n > high)
    return -1;
  return (int)n;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<try_numeric_match>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%r10d
  mov    %ecx,%r11d
  cmp    %rsi,%rdi
  jae    L38
  mov    D8(%rip),%rax
  movslq (%rax),%rsi
  mov    %rsi,%r9
  imul   $0x66666667,%rsi,%rsi
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  sub    %eax,%esi
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  xor    %eax,%eax
  add    $0x2f,%r9d
  jmp    L35
  nopw   0x0(%rax,%rax,1)
L25:
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  cmp    %rdi,%r8
  je     L0
L35:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  ja     L5
  cmp    %eax,%esi
  jb     L5
  jne    L25
  cmp    %ecx,%r9d
  jge    L25
L5:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  cmp    %eax,%r11d
  setb   %dl
L98:
  cmp    %eax,%r10d
  ja     L5
  test   %dl,%dl
  jne    L5
  ret
L38:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L98
```

assistant: ```c
int try_numeric_match(const char *buf, const char *limit, unsigned low, unsigned high) {
  unsigned n = 0;
  while (buf < limit) {
    int ch = (unsigned char)*buf++;
    if (ch >= '0' && ch <= '9') {
      if (n > INT_MAX / 10 || (n == INT_MAX / 10 && ch >= INT_MAX % 10 + '0'))
        return -1;
      n = 10 * n + ch - '0';
    } else
      return -1;
  }
  if (n < low || n > high)
    return -1;
  return (int)n;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<try_numeric_match>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%r10d
  mov    %ecx,%r11d
  cmp    %rsi,%rdi
  jae    L45
  mov    D8(%rip),%rax
  movslq (%rax),%rsi
  mov    %rsi,%r9
  imul   $0x66666667,%rsi,%rsi
  mov    %r9d,%eax
  sar    $0x1f,%eax
  sar    $0x22,%rsi
  sub    %eax,%esi
  lea    (%rsi,%rsi,4),%eax
  add    %eax,%eax
  sub    %eax,%r9d
  xor    %eax,%eax
  add    $0x2f,%r9d
  jmp    L22
  nopw   0x0(%rax,%rax,1)
L94:
  lea    (%rax,%rax,4),%eax
  lea    (%rdx,%rax,2),%eax
  cmp    %rdi,%r8
  je     L98
L22:
  movzbl (%rdi),%ecx
  add    $0x1,%rdi
  lea    -0x30(%rcx),%edx
  cmp    $0x9,%edx
  ja     L25
  cmp    %eax,%esi
  jb     L25
  jne    L94
  cmp    %ecx,%r9d
  jge    L94
L25:
  mov    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L98:
  cmp    %eax,%r11d
  setb   %dl
L99:
  cmp    %eax,%r10d
  ja     L25
  test   %dl,%dl
  jne    L25
  ret
L45:
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L99
```

assistant: ```c
int try_numeric_match(const char *buf, const char *limit, unsigned low, unsigned high) {
  unsigned n = 0;
  while (buf < limit) {
    int ch = (unsigned char)*buf++;
    if (ch >= '0' && ch <= '9') {
      if (n > INT_MAX / 10 || (n == INT_MAX / 10 && ch >= INT_MAX % 10 + '0'))
        return -1;
      n = 10 * n + ch - '0';
    } else
      return -1;
  }
  if (n < low || n > high)
    return -1;
  return (int)n;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<config_ddr_phy_x>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x4c0000e4,%eax
  movq   $0x100007,(%rax)
  mov    $0x4c0000e8,%eax
  movq   $0x100007,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void config_ddr_phy_x(void) {
  *(uint32_t *)(0x4C0000E4) = (uint32_t)(0x00100007);
  *(uint32_t *)(0x4C0000E8) = (uint32_t)(0x00100007);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<config_ddr_phy_x>:
  endbr64
  movq   $0x100007,0x4c0000e4
  movq   $0x100007,0x4c0000e8
  ret
```

assistant: ```c
void config_ddr_phy_x(void) {
  *(uint32_t *)(0x4C0000E4) = (uint32_t)(0x00100007);
  *(uint32_t *)(0x4C0000E8) = (uint32_t)(0x00100007);
}
```
user: What is the c source code of the assembly code below?

```asm
<config_ddr_phy_x>:
  endbr64
  movq   $0x100007,0x4c0000e4
  movq   $0x100007,0x4c0000e8
  ret
```

assistant: ```c
void config_ddr_phy_x(void) {
  *(uint32_t *)(0x4C0000E4) = (uint32_t)(0x00100007);
  *(uint32_t *)(0x4C0000E8) = (uint32_t)(0x00100007);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<config_ddr_phy_x>:
  endbr64
  movq   $0x100007,0x4c0000e4
  movq   $0x100007,0x4c0000e8
  ret
```

assistant: ```c
void config_ddr_phy_x(void) {
  *(uint32_t *)(0x4C0000E4) = (uint32_t)(0x00100007);
  *(uint32_t *)(0x4C0000E8) = (uint32_t)(0x00100007);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<real_to_ieee>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x30(%rbp)
  mov    %esi,-0x24(%rbp)
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movss  -0x28(%rbp),%xmm0
  movss  %xmm0,-0x20(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  je     L18
  mov    -0x10(%rbp),%rax
  mov    $0xffffffff,%esi
  mov    %rsi,(%rax)
L18:
  movl   $0x0,-0x1c(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L23
L30:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x30(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L23:
  cmpl   $0x3,-0x1c(%rbp)
  jle    L30
  nop
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

assistant: ```c
real_to_ieee(r, a, iflg) float r;
char *a;
int iflg;
{
  long *xx;
  char *cf;
  float xf;
  int i;
  xx = (long *)&xf;
  xf = r;
  if (iflg != 0)
    *xx = 0xFFFFFFFF;
  for (i = 0, cf = (char *)xx; i < 4; i++)
    a[i] = *cf++;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<real_to_ieee>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  jne    L29
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,0x4(%rsp)
L25:
  mov    $0x0,%eax
L24:
  movzbl 0x4(%rsp,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L24
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L29:
  mov    $0xffffffff,%eax
  mov    %rax,0x4(%rsp)
  jmp    L25
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
real_to_ieee(r, a, iflg) float r;
char *a;
int iflg;
{
  long *xx;
  char *cf;
  float xf;
  int i;
  xx = (long *)&xf;
  xf = r;
  if (iflg != 0)
    *xx = 0xFFFFFFFF;
  for (i = 0, cf = (char *)xx; i < 4; i++)
    a[i] = *cf++;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<real_to_ieee>:
  endbr64
  sub    $0x18,%rsp
  cvtsd2ss %xmm0,%xmm0
  movd   %xmm0,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movss  %xmm0,0x4(%rsp)
  test   %esi,%esi
  je     L2
  mov    $0xffffffff,%eax
  mov    $0xffffffff,%edx
  mov    %rax,0x4(%rsp)
L2:
  xor    %eax,%eax
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  je     L11
L12:
  movzbl 0x4(%rsp,%rax,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x4,%rax
  jne    L12
L11:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
real_to_ieee(r, a, iflg) float r;
char *a;
int iflg;
{
  long *xx;
  char *cf;
  float xf;
  int i;
  xx = (long *)&xf;
  xf = r;
  if (iflg != 0)
    *xx = 0xFFFFFFFF;
  for (i = 0, cf = (char *)xx; i < 4; i++)
    a[i] = *cf++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<real_to_ieee>:
  endbr64
  mov    $0xffffffff,%eax
  cvtsd2ss %xmm0,%xmm0
  test   %esi,%esi
  jne    L8
  movd   %xmm0,%eax
L8:
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
real_to_ieee(r, a, iflg) float r;
char *a;
int iflg;
{
  long *xx;
  char *cf;
  float xf;
  int i;
  xx = (long *)&xf;
  xf = r;
  if (iflg != 0)
    *xx = 0xFFFFFFFF;
  for (i = 0, cf = (char *)xx; i < 4; i++)
    a[i] = *cf++;
}
```
user: What is the c source code of the assembly code below:

```asm
<jenkins_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L2:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xa,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x6,%eax
  xor    %eax,-0x4(%rbp)
L5:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L2
  mov    -0x4(%rbp),%eax
  shl    $0x3,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0xb,%eax
  xor    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0xf,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int jenkins_hash(const unsigned char *key) {
  unsigned int hash = 0;
  while (*key) {
    hash += *(key++);
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<jenkins_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L4
  mov    $0x0,%edx
L2:
  add    $0x1,%rdi
  movzbl %al,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shl    $0xa,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L2
L3:
  lea    (%rdx,%rdx,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
L4:
  mov    $0x0,%edx
  jmp    L3
```

assistant: ```c
unsigned int jenkins_hash(const unsigned char *key) {
  unsigned int hash = 0;
  while (*key) {
    hash += *(key++);
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<jenkins_hash>:
  endbr64
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  xor    %edx,%edx
  nopl   (%rax)
L18:
  add    %edx,%eax
  add    $0x1,%rdi
  mov    %eax,%edx
  shl    $0xa,%edx
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x6,%edx
  xor    %eax,%edx
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L18
  lea    (%rdx,%rdx,8),%eax
  mov    %eax,%edx
  shr    $0xb,%edx
  xor    %eax,%edx
  mov    %edx,%eax
  shl    $0xf,%eax
  add    %edx,%eax
  ret
  nopl   (%rax)
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int jenkins_hash(const unsigned char *key) {
  unsigned int hash = 0;
  while (*key) {
    hash += *(key++);
    hash += (hash << 10);
    hash ^= (hash >> 6);
  }
  hash += (hash << 3);
  hash ^= (hash >> 11);
  hash += (hash << 15);
  return hash;
}
```