user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<merge>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,0x8(%rsp)
  mov    %rsi,%rbp
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x40(%rsp)
  mov    %r8,%rbx
  mov    %r9,0x20(%rsp)
  lea    (%rsi,%rcx,1),%rax
  imul   %r8,%rax
  mov    %rax,0x48(%rsp)
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,0x38(%rsp)
  test   %rax,%rax
  je     L94
L114:
  imul   %rbx,%rbp
  mov    %rbp,0x10(%rsp)
  test   %rbp,%rbp
  je     L80
  mov    0x40(%rsp),%rax
  imul   %rbx,%rax
  mov    %rax,0x30(%rsp)
  test   %rax,%rax
  je     L134
  mov    0x38(%rsp),%rcx
  mov    %rcx,%rbp
  mov    $0x0,%r13d
  mov    $0x0,%r12d
  mov    %rbx,%rax
  sub    %rcx,%rax
  mov    %rax,0x28(%rsp)
  jmp    L85
L94:
  call   <abort@plt>
  jmp    L114
L130:
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    %rbx,%r12
L106:
  mov    0x28(%rsp),%rax
  lea    (%rax,%rbp,1),%r14
  cmp    0x10(%rsp),%r12
  jae    L6
  add    %rbx,%rbp
  cmp    0x30(%rsp),%r13
  jae    L73
L85:
  mov    0x18(%rsp),%rax
  lea    (%rax,%r13,1),%r14
  mov    0x8(%rsp),%rax
  lea    (%rax,%r12,1),%r15
  mov    %r14,%rsi
  mov    %r15,%rdi
  mov    0x20(%rsp),%rax
  call   *%rax
  test   %eax,%eax
  js     L130
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  add    %rbx,%r13
  jmp    L106
L122:
  mov    0x38(%rsp),%rdi
  call   <free@plt>
  jmp    L24
L134:
  mov    0x30(%rsp),%r12
  mov    %r12,%r13
  mov    %r12,%r14
L73:
  mov    %r14,%rbp
  mov    0x8(%rsp),%rax
  lea    (%rax,%r12,1),%r15
  sub    %r14,%r15
  mov    %r13,0x28(%rsp)
  mov    0x38(%rsp),%r13
  mov    %r14,0x20(%rsp)
  mov    0x10(%rsp),%r14
L0:
  lea    (%r15,%rbp,1),%rsi
  lea    0x0(%r13,%rbp,1),%rdi
  mov    %rbx,%rdx
  call   <memcpy@plt>
  add    %rbx,%rbp
  mov    %r12,%rax
  sub    0x20(%rsp),%rax
  add    %rbp,%rax
  cmp    %r14,%rax
  jb     L0
  mov    0x28(%rsp),%r13
L69:
  mov    0x40(%rsp),%r14
  imul   %rbx,%r14
  cmp    %r13,%r14
  jbe    L72
  mov    %r13,%r12
  add    0x38(%rsp),%rbp
  sub    %r13,%rbp
  mov    0x18(%rsp),%r13
L30:
  lea    0x0(%r13,%r12,1),%rsi
  lea    0x0(%rbp,%r12,1),%rdi
  mov    %rbx,%rdx
  call   <memcpy@plt>
  add    %rbx,%r12
  cmp    %r14,%r12
  jb     L30
L72:
  mov    0x48(%rsp),%rdx
  mov    0x38(%rsp),%rbx
  mov    %rbx,%rsi
  mov    0x8(%rsp),%rdi
  call   <memcpy@plt>
  test   %rbx,%rbx
  jne    L122
L24:
  mov    $0x1,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L80:
  mov    0x10(%rsp),%r14
  mov    %r14,%r13
L6:
  mov    %r14,%rbp
  jmp    L69
```

assistant: ```c
int merge(void *const part1, const size_t p1Len, const void *const part2, const size_t p2Len, const size_t size, int (*const cmp)(const void *const, const void *const)) {
  char *tmp = NULL;
  char *p1 = NULL, *p2 = NULL;
  size_t index = 0, index2 = 0, index3 = 0;
  p1 = (char *)part1;
  p2 = (char *)part2;
  if (!(tmp = (char *)malloc((p1Len + p2Len) * size))) {
    abort();
  }
  index = index2 = index3 = 0;
  while ((index < p1Len * size) && (index2 < p2Len * size)) {
    if (cmp(&p1[index], &p2[index2]) < 0) {
      memcpy(&tmp[index3], &p1[index], size);
      index += size;
    } else {
      memcpy(&tmp[index3], &p2[index2], size);
      index2 += size;
    }
    index3 += size;
  }
  while (index < p1Len * size) {
    memcpy(&tmp[index3], &p1[index], size);
    index += size;
    index3 += size;
  }
  while (index2 < p2Len * size) {
    memcpy(&tmp[index3], &p2[index2], size);
    index2 += size;
    index3 += size;
  }
  memcpy(p1, tmp, (p1Len + p2Len) * size);
  if (tmp) {
    free(tmp);
    tmp = NULL;
  }
  return 1;
}
```