ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<__os_dir_create_rec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    D6(%rip),%r12
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
L74:
  movslq (%r12),%rax
  mov    %rsp,%rcx
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L89
L20:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L20
L89:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L38
L24:
  test   %r13,%r13
  je     L91
  test   %rbx,%rbx
  je     L57
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %rsp,%rdi
  sub    %r13,%rdx
  add    $0x1,%edx
  call   <os_strlcpy@plt>
  cmpb   $0x0,(%rsp)
  je     L55
  mov    %rsp,%rdi
  call   <os_dir_create@plt>
  test   %eax,%eax
  jne    L43
L55:
  lea    0x1(%rbx),%rdi
  mov    $0x2f,%esi
  call   <strchr@plt>
  mov    %rax,%rbx
  jmp    L74
  cs nopw 0x0(%rax,%rax,1)
L91:
  mov    D14(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
L43:
  mov    -0x28(%rbp),%rdx
  sub    %fs:0x28,%rdx
  jne    L101
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L38:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L24
L57:
  mov    %r13,%rdi
  call   <os_dir_create@plt>
  jmp    L43
L101:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int __os_dir_create_rec(const char *path, const char *sep) {
  char subdir[PATH_MAX];
  const char *next_sep;
  int err;
  if (path == NULL)
    return -EINVAL;
  if (sep == NULL)
    return os_dir_create(path);
  os_strlcpy((subdir), (path), (sep - path + 1));
  if (subdir[0] != '\0') {
    err = os_dir_create(subdir);
    if (err != 0)
      return err;
  }
  next_sep = strchr(sep + 1, *"/");
  return __os_dir_create_rec(path, next_sep);
}
```
user: What is the c source code of the assembly code below:

```asm
<cdft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    %r8,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  shl    $0x2,%eax
  cmp    %eax,-0x4(%rbp)
  jle    L50
  mov    -0x4(%rbp),%eax
  sar    $0x2,%eax
  mov    %eax,%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  call   <makewt@plt>
L50:
  cmpl   $0x4,-0x4(%rbp)
  jle    L4
  cmpl   $0x0,-0x8(%rbp)
  js     L29
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bitrv2@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <cftfsub@plt>
  jmp    L15
L29:
  mov    -0x18(%rbp),%rax
  lea    0x8(%rax),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <bitrv2conj@plt>
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <cftbsub@plt>
  jmp    L15
L4:
  cmpl   $0x4,-0x4(%rbp)
  jne    L15
  mov    -0x20(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x4(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <cftfsub@plt>
L15:
  nop
  leave
  ret
```

assistant: ```c
void cdft(int n, int isgn, double *a, int *ip, double *w) {
  void makewt(int nw, int *ip, double *w);
  void bitrv2(int n, int *ip, double *a);
  void bitrv2conj(int n, int *ip, double *a);
  void cftfsub(int n, double *a, double *w);
  void cftbsub(int n, double *a, double *w);
  if (n > (ip[0] << 2)) {
    makewt(n >> 2, ip, w);
  }
  if (n > 4) {
    if (isgn >= 0) {
      bitrv2(n, ip + 2, a);
      cftfsub(n, a, w);
    } else {
      bitrv2conj(n, ip + 2, a);
      cftbsub(n, a, w);
    }
  } else if (n == 4) {
    cftfsub(n, a, w);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cdft>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r14d
  mov    %rdx,%r12
  mov    %rcx,%rbp
  mov    %r8,%r13
  mov    (%rcx),%eax
  shl    $0x2,%eax
  cmp    %edi,%eax
  jl     L46
L68:
  cmp    $0x4,%ebx
  jle    L26
  test   %r14d,%r14d
  js     L52
  lea    0x8(%rbp),%rsi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <bitrv2@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <cftfsub@plt>
  jmp    L54
L46:
  sar    $0x2,%edi
  mov    %r8,%rdx
  mov    %rcx,%rsi
  call   <makewt@plt>
  jmp    L68
L52:
  lea    0x8(%rbp),%rsi
  mov    %r12,%rdx
  mov    %ebx,%edi
  call   <bitrv2conj@plt>
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <cftbsub@plt>
  jmp    L54
L26:
  je     L37
L54:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L37:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    $0x4,%edi
  call   <cftfsub@plt>
  jmp    L54
```

assistant: ```c
void cdft(int n, int isgn, double *a, int *ip, double *w) {
  void makewt(int nw, int *ip, double *w);
  void bitrv2(int n, int *ip, double *a);
  void bitrv2conj(int n, int *ip, double *a);
  void cftfsub(int n, double *a, double *w);
  void cftbsub(int n, double *a, double *w);
  if (n > (ip[0] << 2)) {
    makewt(n >> 2, ip, w);
  }
  if (n > 4) {
    if (isgn >= 0) {
      bitrv2(n, ip + 2, a);
      cftfsub(n, a, w);
    } else {
      bitrv2conj(n, ip + 2, a);
      cftbsub(n, a, w);
    }
  } else if (n == 4) {
    cftfsub(n, a, w);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cdft>:
  endbr64
  mov    (%rcx),%eax
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r8,%r13
  shl    $0x2,%eax
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  cmp    %edi,%eax
  jl     L31
L44:
  cmp    $0x4,%ebp
  jle    L3
  lea    0x8(%rbx),%rsi
  mov    %r12,%rdx
  mov    %ebp,%edi
  test   %r14d,%r14d
  js     L4
  call   <bitrv2@plt>
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <cftfsub@plt>
L3:
  je     L17
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  call   <bitrv2conj@plt>
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <cftbsub@plt>
  nopw   0x0(%rax,%rax,1)
L31:
  sar    $0x2,%edi
  mov    %r8,%rdx
  mov    %rcx,%rsi
  call   <makewt@plt>
  jmp    L44
L17:
  pop    %rbx
  mov    %r13,%rdx
  pop    %rbp
  mov    %r12,%rsi
  mov    $0x4,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <cftfsub@plt>
```

assistant: ```c
void cdft(int n, int isgn, double *a, int *ip, double *w) {
  void makewt(int nw, int *ip, double *w);
  void bitrv2(int n, int *ip, double *a);
  void bitrv2conj(int n, int *ip, double *a);
  void cftfsub(int n, double *a, double *w);
  void cftbsub(int n, double *a, double *w);
  if (n > (ip[0] << 2)) {
    makewt(n >> 2, ip, w);
  }
  if (n > 4) {
    if (isgn >= 0) {
      bitrv2(n, ip + 2, a);
      cftfsub(n, a, w);
    } else {
      bitrv2conj(n, ip + 2, a);
      cftbsub(n, a, w);
    }
  } else if (n == 4) {
    cftfsub(n, a, w);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cdft>:
  endbr64
  mov    (%rcx),%eax
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %r8,%r13
  shl    $0x2,%eax
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  cmp    %edi,%eax
  jl     L13
L37:
  cmp    $0x4,%ebp
  jle    L3
  lea    0x8(%rbx),%rsi
  mov    %r12,%rdx
  mov    %ebp,%edi
  test   %r14d,%r14d
  js     L43
  call   <bitrv2@plt>
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <cftfsub@plt>
L3:
  je     L45
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  call   <bitrv2conj@plt>
  pop    %rbx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %ebp,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <cftbsub@plt>
  nopw   0x0(%rax,%rax,1)
L13:
  sar    $0x2,%edi
  mov    %r8,%rdx
  mov    %rcx,%rsi
  call   <makewt@plt>
  jmp    L37
L45:
  pop    %rbx
  mov    %r13,%rdx
  pop    %rbp
  mov    %r12,%rsi
  mov    $0x4,%edi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10c0 <cftfsub@plt>
```

assistant: ```c
void cdft(int n, int isgn, double *a, int *ip, double *w) {
  void makewt(int nw, int *ip, double *w);
  void bitrv2(int n, int *ip, double *a);
  void bitrv2conj(int n, int *ip, double *a);
  void cftfsub(int n, double *a, double *w);
  void cftbsub(int n, double *a, double *w);
  if (n > (ip[0] << 2)) {
    makewt(n >> 2, ip, w);
  }
  if (n > 4) {
    if (isgn >= 0) {
      bitrv2(n, ip + 2, a);
      cftfsub(n, a, w);
    } else {
      bitrv2conj(n, ip + 2, a);
      cftbsub(n, a, w);
    }
  } else if (n == 4) {
    cftfsub(n, a, w);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x3b9aca00,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L6
L3:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x61,(%rax)
  addl   $0x1000,-0xc(%rbp)
L6:
  cmpl   $0x3b9ac9ff,-0xc(%rbp)
  jle    L3
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char *a = (char *)malloc(1000000000);
  int i;
  for (i = 0; i < 1000000000; i += 0x1000) {
    a[i] = 'a';
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b9aca00,%edi
  call   <malloc@plt>
  lea    0x3b9ad000(%rax),%rdx
L0:
  movb   $0x61,(%rax)
  add    $0x1000,%rax
  cmp    %rdx,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char *a = (char *)malloc(1000000000);
  int i;
  for (i = 0; i < 1000000000; i += 0x1000) {
    a[i] = 'a';
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b9aca00,%edi
  call   <malloc@plt>
  lea    0x3b9ad000(%rax),%rdx
  nopl   0x0(%rax)
L6:
  movb   $0x61,(%rax)
  add    $0x1000,%rax
  cmp    %rdx,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char *a = (char *)malloc(1000000000);
  int i;
  for (i = 0; i < 1000000000; i += 0x1000) {
    a[i] = 'a';
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3b9aca00,%edi
  call   <malloc@plt>
  lea    0x3b9ad000(%rax),%rdx
  nopl   0x0(%rax)
L4:
  movb   $0x61,(%rax)
  add    $0x1000,%rax
  cmp    %rdx,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  char *a = (char *)malloc(1000000000);
  int i;
  for (i = 0; i < 1000000000; i += 0x1000) {
    a[i] = 'a';
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getpgrp@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_infered: string

tool: D8: pgrp %d


assistant: ```c
int main() {
  __pid_t pgrp = getpgrp();
  printf("pgrp %d\n", pgrp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <getpgrp@plt>
  mov    %eax,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D5
type: string

tool: D5: pgrp %d


assistant: ```c
int main() {
  __pid_t pgrp = getpgrp();
  printf("pgrp %d\n", pgrp);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpgrp@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: pgrp %d


assistant: ```c
int main() {
  __pid_t pgrp = getpgrp();
  printf("pgrp %d\n", pgrp);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <getpgrp@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_guessed: string

tool: D8: pgrp %d


assistant: ```c
int main() {
  __pid_t pgrp = getpgrp();
  printf("pgrp %d\n", pgrp);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bulk_talk>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %ecx,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x14,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    D4(%rip),%rax
  mov    (%rax),%ecx
  lea    -0x20(%rbp),%rdx
  mov    -0x34(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    %eax,-0x24(%rbp)
  mov    -0x24(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int bulk_talk(int fd, int endpoint, char *buffer, int length) {
  const int kTimeoutMs = 20;
  struct usbdevfs_bulktransfer ctrl = {0};
  ctrl.ep = endpoint;
  ctrl.len = length;
  ctrl.data = buffer;
  ctrl.timeout = kTimeoutMs;
  int ret = ioctl(fd, USBDEVFS_BULK, &ctrl);
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bulk_talk>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x14(%rsp)
  mov    %esi,(%rsp)
  mov    %ecx,0x4(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x14,0x10(%rsp)
  mov    %rsp,%rdx
  mov    D4(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bulk_talk(int fd, int endpoint, char *buffer, int length) {
  const int kTimeoutMs = 20;
  struct usbdevfs_bulktransfer ctrl = {0};
  ctrl.ep = endpoint;
  ctrl.len = length;
  ctrl.data = buffer;
  ctrl.timeout = kTimeoutMs;
  int ret = ioctl(fd, USBDEVFS_BULK, &ctrl);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bulk_talk>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %esi,(%rsp)
  mov    %rdx,0x8(%rsp)
  mov    %rsp,%rdx
  mov    (%rax),%esi
  mov    %ecx,0x4(%rsp)
  movq   $0x14,0x10(%rsp)
  call   <ioctl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bulk_talk(int fd, int endpoint, char *buffer, int length) {
  const int kTimeoutMs = 20;
  struct usbdevfs_bulktransfer ctrl = {0};
  ctrl.ep = endpoint;
  ctrl.len = length;
  ctrl.data = buffer;
  ctrl.timeout = kTimeoutMs;
  int ret = ioctl(fd, USBDEVFS_BULK, &ctrl);
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bulk_talk>:
  endbr64
  sub    $0x28,%rsp
  movd   %esi,%xmm0
  movd   %ecx,%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D4(%rip),%rax
  mov    %rdx,0x8(%rsp)
  punpckldq %xmm1,%xmm0
  mov    %rsp,%rdx
  movq   %xmm0,(%rsp)
  movq   $0x14,0x10(%rsp)
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int bulk_talk(int fd, int endpoint, char *buffer, int length) {
  const int kTimeoutMs = 20;
  struct usbdevfs_bulktransfer ctrl = {0};
  ctrl.ep = endpoint;
  ctrl.len = length;
  ctrl.data = buffer;
  ctrl.timeout = kTimeoutMs;
  int ret = ioctl(fd, USBDEVFS_BULK, &ctrl);
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<support_avx512>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  mov    $0x0,%eax
  call   <support_avx@plt>
  test   %eax,%eax
  jne    L38
  mov    $0x0,%eax
  jmp    L45
L38:
  lea    -0x10(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  mov    $0x7,%edi
  call   <cpuid@plt>
  mov    -0x18(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  jne    L3
  movl   $0x0,-0xc(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  test   %eax,%eax
  jns    L31
  lea    -0x10(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <xgetbv@plt>
  mov    -0x1c(%rbp),%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  jne    L31
  movl   $0x1,-0xc(%rbp)
L31:
  mov    -0xc(%rbp),%eax
L45:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L34
  call   <__stack_chk_fail@plt>
L34:
  leave
  ret
```

assistant: ```c
int support_avx512() {
  int eax, ebx, ecx, edx;
  int ret = 0;
  if (!support_avx())
    return 0;
  cpuid(7, &eax, &ebx, &ecx, &edx);
  if ((ebx & (1 << 5)) == 0) {
    ret = 0;
  }
  if ((ebx & (1 << 31)) != 0) {
    xgetbv(0, &eax, &edx);
    if ((eax & 0xe0) == 0xe0)
      ret = 1;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<support_avx512>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <support_avx@plt>
  test   %eax,%eax
  jne    L32
L21:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
L32:
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  mov    $0x7,%edi
  call   <cpuid@plt>
  mov    $0x0,%eax
  cmpl   $0x0,0xc(%rsp)
  jns    L21
  lea    0x14(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  mov    $0x0,%edi
  call   <xgetbv@plt>
  mov    0x8(%rsp),%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L21
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int support_avx512() {
  int eax, ebx, ecx, edx;
  int ret = 0;
  if (!support_avx())
    return 0;
  cpuid(7, &eax, &ebx, &ecx, &edx);
  if ((ebx & (1 << 5)) == 0) {
    ret = 0;
  }
  if ((ebx & (1 << 31)) != 0) {
    xgetbv(0, &eax, &edx);
    if ((eax & 0xe0) == 0xe0)
      ret = 1;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<support_avx512>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <support_avx@plt>
  test   %eax,%eax
  jne    L3
L2:
  xor    %eax,%eax
L16:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L3:
  lea    0x14(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    $0x7,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %r12,%r8
  mov    %rbp,%rsi
  call   <cpuid@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L2
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <xgetbv@plt>
  mov    0x8(%rsp),%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L16
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int support_avx512() {
  int eax, ebx, ecx, edx;
  int ret = 0;
  if (!support_avx())
    return 0;
  cpuid(7, &eax, &ebx, &ecx, &edx);
  if ((ebx & (1 << 5)) == 0) {
    ret = 0;
  }
  if ((ebx & (1 << 31)) != 0) {
    xgetbv(0, &eax, &edx);
    if ((eax & 0xe0) == 0xe0)
      ret = 1;
  }
  return ret;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<support_avx512>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <support_avx@plt>
  test   %eax,%eax
  jne    L32
L9:
  xor    %eax,%eax
L8:
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
  xchg   %ax,%ax
L32:
  lea    0x14(%rsp),%r12
  lea    0x8(%rsp),%rbp
  mov    $0x7,%edi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %r12,%r8
  mov    %rbp,%rsi
  call   <cpuid@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jns    L9
  xor    %edi,%edi
  mov    %r12,%rdx
  mov    %rbp,%rsi
  call   <xgetbv@plt>
  mov    0x8(%rsp),%eax
  and    $0xe0,%eax
  cmp    $0xe0,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L8
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int support_avx512() {
  int eax, ebx, ecx, edx;
  int ret = 0;
  if (!support_avx())
    return 0;
  cpuid(7, &eax, &ebx, &ecx, &edx);
  if ((ebx & (1 << 5)) == 0) {
    ret = 0;
  }
  if ((ebx & (1 << 31)) != 0) {
    xgetbv(0, &eax, &edx);
    if ((eax & 0xe0) == 0xe0)
      ret = 1;
  }
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mkdir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x210,%rsp
  mov    %rdi,-0x208(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x200(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x208(%rbp),%rdx
  lea    -0x200(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  lea    -0x200(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D1
data_type: string

tool: D1: mkdir -p 

assistant: ```c
void mkdir(char *c_file) {
  char c_aux[500];
  strcpy(c_aux, "mkdir -p ");
  strcat(c_aux, c_file);
  system(c_aux);
}
```
user: What is the c source code of the assembly code below:

```asm
<mkdir>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x208,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D7(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x208,%rsp
  pop    %rbx
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D7
type_infered: string

tool: D7: mkdir -p 

assistant: ```c
void mkdir(char *c_file) {
  char c_aux[500];
  strcpy(c_aux, "mkdir -p ");
  strcat(c_aux, c_file);
  system(c_aux);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mkdir>:
  endbr64
  push   %r12
  lea    D2(%rip),%rsi
  mov    %rdi,%r12
  push   %rbp
  sub    $0x208,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strcat@plt>
  mov    %rbp,%rdi
  call   <system@plt>
  mov    0x1f8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x208,%rsp
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: mkdir -p 

assistant: ```c
void mkdir(char *c_file) {
  char c_aux[500];
  strcpy(c_aux, "mkdir -p ");
  strcat(c_aux, c_file);
  system(c_aux);
}
```