ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<meow>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    %rsp,%rax
  mov    %rax,%rsi
  movl   $0xa,-0x1c(%rbp)
  jmp    L42
L6:
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  je     L9
  subl   $0x1,-0x1c(%rbp)
L42:
  cmpl   $0x0,-0x1c(%rbp)
  jg     L6
  jmp    L77
L9:
  nop
L77:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x18(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r10
  mov    $0x0,%r11d
  movslq %eax,%rdx
  mov    %rdx,%r8
  mov    $0x0,%r9d
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%edi
  mov    $0x0,%edx
  div    %rdi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L12:
  cmp    %rdx,%rsp
  je     L63
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L12
L63:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L66
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L66:
  mov    %rsp,%rax
  add    $0x3,%rax
  shr    $0x2,%rax
  shl    $0x2,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %rsi,%rsp
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L36
  call   <__stack_chk_fail@plt>
L36:
  leave
  ret
```

assistant: ```c
int meow() {
  int i = 10;
  while (i > 0) {
    if (i % 3 == 2)
      break;
    i = i - 1;
  }
  int x[i];
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<meow>:
  endbr64
  mov    $0x9,%edx
L14:
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,2),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  cmp    $0x2,%eax
  je     L8
  sub    $0x1,%edx
  jne    L14
L8:
  mov    %edx,%eax
  ret
```

assistant: ```c
int meow() {
  int i = 10;
  while (i > 0) {
    if (i % 3 == 2)
      break;
    i = i - 1;
  }
  int x[i];
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<meow>:
  endbr64
  mov    $0xa,%eax
L8:
  sub    $0x1,%eax
  je     L15
  imul   $0xaaaaaaab,%eax,%edx
  sub    $0x55555556,%edx
  cmp    $0x55555554,%edx
  ja     L8
L15:
  ret
```

assistant: ```c
int meow() {
  int i = 10;
  while (i > 0) {
    if (i % 3 == 2)
      break;
    i = i - 1;
  }
  int x[i];
  return i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<meow>:
  endbr64
  mov    $0x8,%eax
  ret
```

assistant: ```c
int meow() {
  int i = 10;
  while (i > 0) {
    if (i % 3 == 2)
      break;
    i = i - 1;
  }
  int x[i];
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x2,-0x4(%rbp)
  movl   $0x3,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L35
  mov    $0x0,%eax
  jmp    L27
L35:
  movl   $0x4,-0x4(%rbp)
  movl   $0x5,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L24
  mov    $0x0,%eax
  jmp    L27
L24:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int i;
  int b = 1;
#pragma pomp inst init
#pragma pomp inst off
#pragma pomp inst begin(foo)
#pragma omp parallel
  i = 1;
#pragma pomp inst on
#pragma pomp noinstrument
#pragma omp parallel
  i = 2;
#pragma pomp instrument
#pragma omp parallel
  i = 3;
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma omp parallel
  {
#pragma pomp inst begin(phase1)
    i = 4;
#pragma omp barrier
    i = 5;
#pragma pomp inst end(phase1)
  }
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma pomp inst end(foo)
#pragma pomp inst finalize
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int b = 1;
#pragma pomp inst init
#pragma pomp inst off
#pragma pomp inst begin(foo)
#pragma omp parallel
  i = 1;
#pragma pomp inst on
#pragma pomp noinstrument
#pragma omp parallel
  i = 2;
#pragma pomp instrument
#pragma omp parallel
  i = 3;
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma omp parallel
  {
#pragma pomp inst begin(phase1)
    i = 4;
#pragma omp barrier
    i = 5;
#pragma pomp inst end(phase1)
  }
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma pomp inst end(foo)
#pragma pomp inst finalize
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int b = 1;
#pragma pomp inst init
#pragma pomp inst off
#pragma pomp inst begin(foo)
#pragma omp parallel
  i = 1;
#pragma pomp inst on
#pragma pomp noinstrument
#pragma omp parallel
  i = 2;
#pragma pomp instrument
#pragma omp parallel
  i = 3;
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma omp parallel
  {
#pragma pomp inst begin(phase1)
    i = 4;
#pragma omp barrier
    i = 5;
#pragma pomp inst end(phase1)
  }
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma pomp inst end(foo)
#pragma pomp inst finalize
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int i;
  int b = 1;
#pragma pomp inst init
#pragma pomp inst off
#pragma pomp inst begin(foo)
#pragma omp parallel
  i = 1;
#pragma pomp inst on
#pragma pomp noinstrument
#pragma omp parallel
  i = 2;
#pragma pomp instrument
#pragma omp parallel
  i = 3;
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma omp parallel
  {
#pragma pomp inst begin(phase1)
    i = 4;
#pragma omp barrier
    i = 5;
#pragma pomp inst end(phase1)
  }
  if (b) {
#pragma pomp inst altend(foo)
    return 0;
  }
#pragma pomp inst end(foo)
#pragma pomp inst finalize
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L29
L60:
  movl   $0x0,-0x4(%rbp)
  jmp    L0
L4:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  ucomisd D12(%rip),%xmm0
  jp     L15
  ucomisd D12(%rip),%xmm0
  jne    L15
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L34
L15:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L34:
  addl   $0x1,-0x4(%rbp)
L0:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L4
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L29:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L60
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D12
data_type: byte[8]
name: read_data
arguments: data_tag: D28
data_type: string
name: read_data
arguments: data_tag: D7
data_type: string

tool: {"D12": [0x00,0x00,0x00,0xfc,0x83,0xd7,0x97,0x41]}

tool: D28: e  

tool: D7: %f  

assistant: ```c
void print_matrix(double **a, int noc, int moc) {
  int i, j;
  for (i = 0; i < noc; i++) {
    for (j = 0; j < moc; j++) {
      if (a[i][j] == 99999999)
        printf("e  ");
      else
        printf("%f  ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %esi,%esi
  jle    L58
  mov    %edx,%r15d
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%r12
  lea    D23(%rip),%r14
  jmp    L82
L55:
  mov    %r14,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
L59:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L24
L54:
  mov    0x0(%rbp),%rax
  movsd  (%rax,%rbx,1),%xmm0
  ucomisd D5(%rip),%xmm0
  jp     L55
  jne    L55
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L59
L24:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rbp
  cmp    0x8(%rsp),%rbp
  je     L58
L82:
  mov    $0x0,%ebx
  lea    D13(%rip),%r13
  test   %r15d,%r15d
  jg     L54
  jmp    L24
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D5
data_type: byte[8]
name: unpack_data
arguments: label: D13
data_type: string

tool: D23: %f  

tool: {"D5": [0x00,0x00,0x00,0xfc,0x83,0xd7,0x97,0x41]}

tool: D13: e  

assistant: ```c
void print_matrix(double **a, int noc, int moc) {
  int i, j;
  for (i = 0; i < noc; i++) {
    for (j = 0; j < moc; j++) {
      if (a[i][j] == 99999999)
        printf("e  ");
      else
        printf("%f  ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L54
  push   %r15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r15
  push   %r14
  lea    0x8(%rdi,%rax,8),%rax
  mov    %edx,%r14d
  push   %r13
  lea    D9(%rip),%r13
  push   %r12
  lea    D22(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  cs nopw 0x0(%rax,%rax,1)
L59:
  xor    %ebx,%ebx
  test   %r14d,%r14d
  jg     L35
  jmp    L50
  nopl   0x0(%rax)
L23:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  je     L50
L35:
  mov    (%r15),%rax
  movsd  (%rax,%rbx,1),%xmm0
  ucomisd D15(%rip),%xmm0
  jp     L28
  je     L23
L28:
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L35
L50:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    0x8(%rsp),%r15
  jne    L59
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
L54:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type: string
name: read_data
arguments: tag: D22
type: string
name: read_data
arguments: tag: D15
type: byte[8]

tool: D9: %f  

tool: D22: e  

tool: {"D15": [0x00,0x00,0x00,0xfc,0x83,0xd7,0x97,0x41]}

assistant: ```c
void print_matrix(double **a, int noc, int moc) {
  int i, j;
  for (i = 0; i < noc; i++) {
    for (j = 0; j < moc; j++) {
      if (a[i][j] == 99999999)
        printf("e  ");
      else
        printf("%f  ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<print_matrix>:
  endbr64
  test   %esi,%esi
  jle    L14
  push   %r15
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r15
  push   %r14
  lea    0x8(%rdi,%rax,8),%rax
  mov    %edx,%r14d
  push   %r13
  lea    D15(%rip),%r13
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%rbp
  cs nopw 0x0(%rax,%rax,1)
L75:
  xor    %ebx,%ebx
  test   %r14d,%r14d
  jg     L51
  jmp    L32
  nopl   0x0(%rax)
L42:
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  je     L32
L51:
  mov    (%r15),%rax
  movsd  (%rax,%rbx,1),%xmm0
  ucomisd D29(%rip),%xmm0
  jp     L54
  je     L42
L54:
  mov    %r13,%rdi
  mov    $0x1,%eax
  add    $0x8,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L51
L32:
  mov    $0xa,%edi
  add    $0x8,%r15
  call   <putchar@plt>
  cmp    0x8(%rsp),%r15
  jne    L75
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <putchar@plt>
L14:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: parse_data
arguments: tag: D15
type_infered: string
name: parse_data
arguments: tag: D23
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: byte[8]

tool: D15: %f  

tool: D23: e  

tool: {"D29": [0x00,0x00,0x00,0xfc,0x83,0xd7,0x97,0x41]}

assistant: ```c
void print_matrix(double **a, int noc, int moc) {
  int i, j;
  for (i = 0; i < noc; i++) {
    for (j = 0; j < moc; j++) {
      if (a[i][j] == 99999999)
        printf("e  ");
      else
        printf("%f  ", a[i][j]);
    }
    printf("\n");
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below?

```asm
<reg_print_val>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  movsd  %xmm0,-0x88(%rbp)
  mov    %rdi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x78(%rbp)
  mov    -0x88(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x60(%rbp),%rax
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strpbrk@plt>
  mov    %rax,-0x70(%rbp)
  cmpq   $0x0,-0x70(%rbp)
  je     L102
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x78(%rbp)
  jmp    L12
L102:
  lea    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  cltq
  mov    %rax,-0x78(%rbp)
L12:
  lea    -0x60(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x68(%rbp)
  cmpq   $0x0,-0x68(%rbp)
  je     L66
  lea    -0x60(%rbp),%rdx
  mov    -0x68(%rbp),%rax
  sub    %rdx,%rax
  cmp    %rax,-0x78(%rbp)
  jle    L66
  jmp    L61
L91:
  mov    -0x78(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x78(%rbp)
  movb   $0x0,-0x60(%rbp,%rax,1)
L61:
  cmpq   $0x0,-0x78(%rbp)
  jle    L54
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x30,%al
  je     L91
L54:
  cmpq   $0x0,-0x78(%rbp)
  jle    L66
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L66
  lea    -0x60(%rbp),%rdx
  mov    -0x78(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L66:
  lea    -0x60(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  cmpq   $0x0,-0x70(%rbp)
  je     L103
  lea    -0x60(%rbp),%rdx
  mov    -0x70(%rbp),%rax
  sub    %rdx,%rax
  cmp    %rax,-0x78(%rbp)
  jge    L103
  mov    -0x70(%rbp),%rdx
  mov    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
L103:
  mov    -0x90(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
data_type: string
name: parse_data
arguments: data_label: D9
data_type: string

tool: D2: %g

tool: D9: eE

assistant: ```c
char *reg_print_val(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<reg_print_val>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %rdi,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <sprintf@plt>
  lea    D5(%rip),%rsi
  mov    %rbx,%rdi
  call   <strpbrk@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L107
  mov    %rsp,%rdi
  mov    %rax,%rbx
  sub    %rdi,%rbx
  mov    $0x2e,%esi
  call   <strchr@plt>
  test   %rax,%rax
  je     L170
  cmp    %rax,%rbp
  ja     L109
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L28:
  mov    %rsp,%rdx
  mov    %rbp,%rax
  sub    %rdx,%rax
  cmp    %rbx,%rax
  jle    L102
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L102
L107:
  mov    %rsp,%r13
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    $0x2e,%esi
  mov    %r13,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L179
  sub    $0x1,%ebx
  movslq %ebx,%rbx
  sub    %r13,%rax
  cmp    %rax,%rbx
  jle    L89
L109:
  mov    %rsp,%rax
  lea    0x1(%rsp),%rdx
  test   %rbx,%rbx
  jle    L75
L88:
  cmpb   $0x30,(%rbx,%rax,1)
  jne    L175
  sub    $0x1,%rbx
  movb   $0x0,(%rdx,%rbx,1)
  jne    L88
L75:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %rbp,%rbp
  je     L102
  jmp    L28
L175:
  test   %rbx,%rbx
  jle    L75
  cmpb   $0x2e,(%rsp,%rbx,1)
  jne    L75
  movb   $0x0,(%rsp,%rbx,1)
  jmp    L75
L170:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L102:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L113
  mov    %r12,%rax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L179:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L102
L89:
  mov    %rsp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L102
L113:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string
name: disassemble_data
arguments: data_tag: D5
type_guessed: string

tool: D0: %g

tool: D5: eE

assistant: ```c
char *reg_print_val(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<reg_print_val>:
  endbr64
  push   %r13
  lea    D18(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D13(%rip),%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L21
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L33
  mov    %r13,%rbx
  sub    %rbp,%rbx
  cmp    %rax,%r13
  jbe    L33
  test   %rbx,%rbx
  jle    L141
L49:
  lea    0x1(%rsp),%rdx
  jmp    L53
  nop
L47:
  sub    $0x1,%rbx
  movb   $0x0,(%rdx,%rbx,1)
  je     L46
L53:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x30,%al
  je     L47
  cmp    $0x2e,%al
  je     L138
L46:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %r13,%r13
  je     L2
L78:
  mov    %r13,%rax
  sub    %rbp,%rax
  cmp    %rbx,%rax
  jle    L2
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L2
  nopl   0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L33
  sub    $0x1,%ebx
  sub    %rbp,%rax
  movslq %ebx,%rbx
  cmp    %rax,%rbx
  jle    L33
  test   %rbx,%rbx
  jg     L49
  nopw   0x0(%rax,%rax,1)
L33:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L2:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x68,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L138:
  movb   $0x0,(%rsp,%rbx,1)
  jmp    L46
L141:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L78
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D18
data_type: string
name: unpack_data
arguments: data_tag: D13
data_type: string

tool: D18: %g

tool: D13: eE

assistant: ```c
char *reg_print_val(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<reg_print_val>:
  endbr64
  push   %r13
  lea    D19(%rip),%rsi
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <strpbrk@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L25
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  call   <strchr@plt>
  test   %rax,%rax
  je     L63
  mov    %r13,%rbx
  sub    %rbp,%rbx
  cmp    %rax,%r13
  jbe    L63
  test   %rbx,%rbx
  jle    L26
L108:
  lea    0x1(%rsp),%rdx
  jmp    L69
  nop
L79:
  sub    $0x1,%rbx
  movb   $0x0,(%rdx,%rbx,1)
  je     L147
L69:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x30,%al
  je     L79
  cmp    $0x2e,%al
  je     L163
L147:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  test   %r13,%r13
  je     L157
L86:
  mov    %r13,%rax
  sub    %rbp,%rax
  cmp    %rbx,%rax
  jle    L157
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strcat@plt>
  jmp    L157
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x2e,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  test   %rax,%rax
  je     L63
  sub    $0x1,%ebx
  sub    %rbp,%rax
  movslq %ebx,%rbx
  cmp    %rax,%rbx
  jle    L63
  test   %rbx,%rbx
  jg     L108
  nopw   0x0(%rax,%rax,1)
L63:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
L157:
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  add    $0x68,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L163:
  movb   $0x0,(%rsp,%rbx,1)
  jmp    L147
L26:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  jmp    L86
L81:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D19
datatype: string
name: extract_symbolic_data
arguments: tag: D15
datatype: string

tool: D19: %g

tool: D15: eE

assistant: ```c
char *reg_print_val(double x, char *buf) {
  char tmp[80];
  char *ptr;
  char *decimal;
  long j = 0;
  sprintf(tmp, "%g", x);
  ptr = strpbrk(tmp, "eE");
  if (ptr)
    j = ptr - tmp;
  else
    j = strlen(tmp) - 1;
  decimal = strchr(tmp, '.');
  if (decimal && j > decimal - tmp) {
    while (j > 0 && tmp[j] == '0')
      tmp[j--] = '\0';
    if (j > 0 && tmp[j] == '.')
      tmp[j] = '\0';
  }
  strcpy(buf, tmp);
  if (ptr && j < ptr - tmp)
    strcat(buf, ptr);
  return buf;
}
```