ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  je     L13
  lea    0x10(%rsp),%r12
  lea    D15(%rip),%rbp
  lea    D14(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L10:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  mov    $0x2,%esi
  call   <joseph@plt>
  mov    %rbx,%rdi
  lea    0x1(%rax),%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  jne    L10
L13:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D5
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D14
type_guessed: string

tool: D5: %d

tool: D15: %ld

tool: D14: %ld


assistant: ```c
int main() {
  long long t;
  scanf("%d", &t);
  while (t--) {
    long long n, k = 2;
    scanf("%ld", &n);
    printf("%ld\n", joseph(n, k) + 1);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  lea    D6(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  je     L20
  lea    0x10(%rsp),%r12
  lea    D0(%rip),%rbp
  lea    D7(%rip),%rbx
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%rdi
  mov    $0x2,%esi
  call   <joseph@plt>
  mov    %rbx,%rdi
  lea    0x1(%rax),%rsi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,0x8(%rsp)
  test   %rax,%rax
  jne    L18
L20:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D0
type_guessed: string
name: extract_symbolic_data
arguments: label: D7
type_guessed: string

tool: D6: %d

tool: D0: %ld

tool: D7: %ld


assistant: ```c
int main() {
  long long t;
  scanf("%d", &t);
  while (t--) {
    long long n, k = 2;
    scanf("%ld", &n);
    printf("%ld\n", joseph(n, k) + 1);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rewrite_url>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movw   $0x0,-0x1a(%rbp)
  jmp    L23
L14:
  movswq -0x1a(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movswq -0x1a(%rbp),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
L23:
  movswl -0x1a(%rbp),%ebx
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jge    L10
  movswq -0x1a(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3f,%al
  jne    L14
L10:
  movswl -0x1a(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *rewrite_url(char *url) {
  char *newURL = malloc(50);
  short i = 0;
  while (i < (signed)strlen(url) && url[i] != '?')
    newURL[i] = url[i];
  newURL = realloc(newURL, i);
  return newURL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rewrite_url>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    $0x32,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L24
L6:
  mov    %al,0x0(%rbp)
L24:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jle    L26
  movzbl (%rbx),%eax
  cmp    $0x3f,%al
  jne    L6
L26:
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *rewrite_url(char *url) {
  char *newURL = malloc(50);
  short i = 0;
  while (i < (signed)strlen(url) && url[i] != '?')
    newURL[i] = url[i];
  newURL = realloc(newURL, i);
  return newURL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<rewrite_url>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x32,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L21
  nopl   0x0(%rax)
L8:
  movzbl (%rbx),%eax
  cmp    $0x3f,%al
  je     L28
  mov    %al,0x0(%rbp)
L21:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L8
L28:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  jmp    1090 <realloc@plt>
```

assistant: ```c
char *rewrite_url(char *url) {
  char *newURL = malloc(50);
  short i = 0;
  while (i < (signed)strlen(url) && url[i] != '?')
    newURL[i] = url[i];
  newURL = realloc(newURL, i);
  return newURL;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rewrite_url>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x32,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L27
  nopl   0x0(%rax)
L24:
  movzbl (%rbx),%eax
  cmp    $0x3f,%al
  je     L11
  mov    %al,0x0(%rbp)
L27:
  mov    %rbx,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  jg     L24
L11:
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %esi,%esi
  pop    %rbx
  pop    %rbp
  jmp    1090 <realloc@plt>
```

assistant: ```c
char *rewrite_url(char *url) {
  char *newURL = malloc(50);
  short i = 0;
  while (i < (signed)strlen(url) && url[i] != '?')
    newURL[i] = url[i];
  newURL = realloc(newURL, i);
  return newURL;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x7dc,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x1,-0x10(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x46,-0xc(%rbp)
  cmpl   $0x41,-0xc(%rbp)
  jle    L42
  cmpl   $0x5a,-0xc(%rbp)
  jg     L42
  mov    $0x1,%eax
  jmp    L29
L42:
  mov    $0x0,%eax
L29:
  mov    %eax,-0x8(%rbp)
  cmpl   $0x1,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movb   $0x53,-0x15(%rbp)
  cmpb   $0x40,-0x15(%rbp)
  jle    L52
  cmpb   $0x5a,-0x15(%rbp)
  jg     L52
  mov    $0x1,%eax
  jmp    L15
L52:
  mov    $0x0,%eax
L15:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movb   $0x73,-0x15(%rbp)
  cmpb   $0x40,-0x15(%rbp)
  jle    L83
  cmpb   $0x5a,-0x15(%rbp)
  jg     L83
  mov    $0x1,%eax
  jmp    L60
L83:
  mov    $0x0,%eax
L60:
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int n = 2012;
  int leap = ((n % 4) == 0);
  assert(leap == 1);
  int number = 70;
  int ascii = number > 65 && number < 91;
  assert(ascii == 1);
  char ch = 'S';
  int uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 1);
  ch = 's';
  uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 0);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int n = 2012;
  int leap = ((n % 4) == 0);
  assert(leap == 1);
  int number = 70;
  int ascii = number > 65 && number < 91;
  assert(ascii == 1);
  char ch = 'S';
  int uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 1);
  ch = 's';
  uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 0);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int n = 2012;
  int leap = ((n % 4) == 0);
  assert(leap == 1);
  int number = 70;
  int ascii = number > 65 && number < 91;
  assert(ascii == 1);
  char ch = 'S';
  int uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 1);
  ch = 's';
  uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 0);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int n = 2012;
  int leap = ((n % 4) == 0);
  assert(leap == 1);
  int number = 70;
  int ascii = number > 65 && number < 91;
  assert(ascii == 1);
  char ch = 'S';
  int uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 1);
  ch = 's';
  uppercase = ch >= 65 && ch <= 90;
  assert(uppercase == 0);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<func_native>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movss  %xmm1,-0x1c(%rbp)
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x2c(%rbp)
  fldl   -0x18(%rbp)
  fldt   0x10(%rbp)
  faddp  %st,%st(1)
  flds   -0x1c(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  fildll -0x38(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
  cmpb   $0x0,-0x2c(%rbp)
  jle    L0
  movzbl -0x2c(%rbp),%eax
  neg    %eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%esi
  mov    -0x28(%rbp),%rcx
  movss  -0x1c(%rbp),%xmm0
  mov    -0x18(%rbp),%rax
  push   0x18(%rbp)
  push   0x10(%rbp)
  mov    %rcx,%rdi
  movaps %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <func_native>
  add    $0x10,%rsp
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
L0:
  fldt   -0x10(%rbp)
  leave
  ret
```

assistant: ```c
long double __attribute__((sysv_abi)) func_native(long double a, double b, float c, long d, int e, char f) {
  long double ret;
  ret = a + (long double)b + (long double)c;
  ret *= (long double)(d + (long)e);
  if (f > 0)
    ret += func_native(a, b, c, d, e, -f);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<func_native>:
  endbr64
  sub    $0x28,%rsp
  fldt   0x30(%rsp)
  movsd  %xmm0,0x10(%rsp)
  movss  %xmm1,0x1c(%rsp)
  fld    %st(0)
  faddl  0x10(%rsp)
  fadds  0x1c(%rsp)
  movslq %esi,%rax
  add    %rdi,%rax
  mov    %rax,(%rsp)
  fildll (%rsp)
  fmulp  %st,%st(1)
  fstpt  (%rsp)
  test   %dl,%dl
  jg     L1
  fstp   %st(0)
L14:
  fldt   (%rsp)
  add    $0x28,%rsp
  ret
L1:
  neg    %edx
  movsbl %dl,%edx
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <func_native>
  add    $0x10,%rsp
  fldt   (%rsp)
  faddp  %st,%st(1)
  fstpt  (%rsp)
  jmp    L14
```

assistant: ```c
long double __attribute__((sysv_abi)) func_native(long double a, double b, float c, long d, int e, char f) {
  long double ret;
  ret = a + (long double)b + (long double)c;
  ret *= (long double)(d + (long)e);
  if (f > 0)
    ret += func_native(a, b, c, d, e, -f);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func_native>:
  endbr64
  movsd  %xmm0,-0x18(%rsp)
  fldt   0x8(%rsp)
  faddl  -0x18(%rsp)
  movslq %esi,%rsi
  movss  %xmm1,-0xc(%rsp)
  add    %rdi,%rsi
  mov    %rsi,-0x18(%rsp)
  fadds  -0xc(%rsp)
  fildll -0x18(%rsp)
  fmulp  %st,%st(1)
  test   %dl,%dl
  jg     L2
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  fadd   %st(0),%st
  ret
```

assistant: ```c
long double __attribute__((sysv_abi)) func_native(long double a, double b, float c, long d, int e, char f) {
  long double ret;
  ret = a + (long double)b + (long double)c;
  ret *= (long double)(d + (long)e);
  if (f > 0)
    ret += func_native(a, b, c, d, e, -f);
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<func_native>:
  endbr64
  movsd  %xmm0,-0x18(%rsp)
  fldt   0x8(%rsp)
  faddl  -0x18(%rsp)
  movslq %esi,%rsi
  movss  %xmm1,-0xc(%rsp)
  add    %rdi,%rsi
  mov    %rsi,-0x18(%rsp)
  fadds  -0xc(%rsp)
  fildll -0x18(%rsp)
  fmulp  %st,%st(1)
  test   %dl,%dl
  jg     L7
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  fadd   %st(0),%st
  ret
```

assistant: ```c
long double __attribute__((sysv_abi)) func_native(long double a, double b, float c, long d, int e, char f) {
  long double ret;
  ret = a + (long double)b + (long double)c;
  ret *= (long double)(d + (long)e);
  if (f > 0)
    ret += func_native(a, b, c, d, e, -f);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Hanoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  jle    L4
  mov    $0x6,%eax
  sub    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <Hanoi>
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <DISPLAY_INT@plt>
  mov    $0xa,%edi
  call   <outchar@plt>
  cmpl   $0x1,-0x4(%rbp)
  jle    L3
  mov    $0x6,%eax
  sub    -0x8(%rbp),%eax
  sub    -0xc(%rbp),%eax
  mov    -0x4(%rbp),%edx
  lea    -0x1(%rdx),%ecx
  mov    -0xc(%rbp),%edx
  mov    %eax,%esi
  mov    %ecx,%edi
  call   <Hanoi>
  nop
L3:
  nop
  leave
  ret
```

assistant: ```c
void Hanoi(int n, int x, int y) {
  if (n >= 2)
    Hanoi(n - 1, x, 6 - x - y);
  DISPLAY_INT(n);
  outchar(' ');
  DISPLAY_INT(x);
  outchar(' ');
  DISPLAY_INT(y);
  outchar('\n');
  if (n >= 2)
    Hanoi(n - 1, 6 - x - y, y);
  return;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Hanoi>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%ebp
  cmp    $0x1,%edi
  jg     L11
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %r12d,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %ebp,%edi
  call   <DISPLAY_INT@plt>
  mov    $0xa,%edi
  call   <outchar@plt>
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L11:
  mov    $0x6,%r13d
  sub    %esi,%r13d
  sub    %edx,%r13d
  lea    -0x1(%rdi),%r14d
  mov    %r13d,%edx
  mov    %r14d,%edi
  call   <Hanoi>
  mov    %ebx,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %r12d,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %ebp,%edi
  call   <DISPLAY_INT@plt>
  mov    $0xa,%edi
  call   <outchar@plt>
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <Hanoi>
  jmp    L7
```

assistant: ```c
void Hanoi(int n, int x, int y) {
  if (n >= 2)
    Hanoi(n - 1, x, 6 - x - y);
  DISPLAY_INT(n);
  outchar(' ');
  DISPLAY_INT(x);
  outchar(' ');
  DISPLAY_INT(y);
  outchar('\n');
  if (n >= 2)
    Hanoi(n - 1, 6 - x - y, y);
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Hanoi>:
  endbr64
  push   %r15
  push   %r14
  mov    %edx,%r14d
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%edi
  jle    L7
  mov    $0x6,%ebx
L5:
  mov    %r12d,%r13d
  mov    %ebx,%r12d
  mov    %ebp,%r15d
  sub    $0x1,%ebp
  sub    %r13d,%r12d
  mov    %r13d,%esi
  mov    %ebp,%edi
  sub    %r14d,%r12d
  mov    %r12d,%edx
  call   <Hanoi>
  mov    %r15d,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %r13d,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %r14d,%edi
  call   <DISPLAY_INT@plt>
  mov    $0xa,%edi
  call   <outchar@plt>
  cmp    $0x1,%ebp
  jne    L5
L7:
  mov    %ebp,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %r12d,%edi
  call   <DISPLAY_INT@plt>
  mov    $0x20,%edi
  call   <outchar@plt>
  mov    %r14d,%edi
  call   <DISPLAY_INT@plt>
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <outchar@plt>
```

assistant: ```c
void Hanoi(int n, int x, int y) {
  if (n >= 2)
    Hanoi(n - 1, x, 6 - x - y);
  DISPLAY_INT(n);
  outchar(' ');
  DISPLAY_INT(x);
  outchar(' ');
  DISPLAY_INT(y);
  outchar('\n');
  if (n >= 2)
    Hanoi(n - 1, 6 - x - y, y);
  return;
}
```
user: What is the c source code of the assembly code below?

```asm
<opr_erfc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <erfc@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double opr_erfc(struct lifo *stack) {
  double op = pop(stack);
  return erfc(op);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<opr_erfc>:
  endbr64
  sub    $0x8,%rsp
  call   <pop@plt>
  call   <erfc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double opr_erfc(struct lifo *stack) {
  double op = pop(stack);
  return erfc(op);
}
```
user: Translate the below assembly code into C programming language:

```asm
<opr_erfc>:
  endbr64
  sub    $0x8,%rsp
  call   <pop@plt>
  add    $0x8,%rsp
  jmp    1070 <erfc@plt>
```

assistant: ```c
double opr_erfc(struct lifo *stack) {
  double op = pop(stack);
  return erfc(op);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<opr_erfc>:
  endbr64
  sub    $0x8,%rsp
  call   <pop@plt>
  add    $0x8,%rsp
  jmp    1070 <erfc@plt>
```

assistant: ```c
double opr_erfc(struct lifo *stack) {
  double op = pop(stack);
  return erfc(op);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sliprxone>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <infromdev@plt>
  mov    %eax,%ebx
  cmp    $0xc0,%bl
  jne    L7
  mov    $0xffffffff,%eax
  jmp    L15
L7:
  cmp    $0xdb,%bl
  jne    L72
  mov    $0x0,%eax
  call   <infromdev@plt>
  mov    %eax,%ebx
  cmp    $0xdc,%bl
  jne    L34
  mov    $0xc0,%eax
  jmp    L15
L34:
  cmp    $0xdd,%bl
  jne    L73
  mov    $0xdb,%eax
  jmp    L15
L73:
  mov    $0xffffffff,%eax
  jmp    L15
L72:
  movzbl %bl,%eax
L15:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int sliprxone(void) {
  register unsigned char c;
  register unsigned char d;
  c = infromdev();
  if (c == 0xC0)
    return -1;
  if (c == 0xDB) {
    d = infromdev();
    if (d == 0xDC)
      return (0xC0);
    if (d == 0xDD)
      return (0xDB);
    return (-1);
  }
  return (c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sliprxone>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <infromdev@plt>
  cmp    $0xc0,%al
  je     L22
  movzbl %al,%edx
  cmp    $0xdb,%al
  je     L38
L47:
  mov    %edx,%eax
  add    $0x8,%rsp
  ret
L38:
  mov    $0x0,%eax
  call   <infromdev@plt>
  cmp    $0xdc,%al
  je     L3
  cmp    $0xdd,%al
  mov    $0xdb,%edx
  mov    $0xffffffff,%eax
  cmovne %eax,%edx
  jmp    L47
L22:
  mov    $0xffffffff,%edx
  jmp    L47
L3:
  mov    $0xc0,%edx
  jmp    L47
```

assistant: ```c
int sliprxone(void) {
  register unsigned char c;
  register unsigned char d;
  c = infromdev();
  if (c == 0xC0)
    return -1;
  if (c == 0xDB) {
    d = infromdev();
    if (d == 0xDC)
      return (0xC0);
    if (d == 0xDD)
      return (0xDB);
    return (-1);
  }
  return (c);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sliprxone>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <infromdev@plt>
  cmp    $0xc0,%al
  je     L19
  movzbl %al,%r8d
  cmp    $0xdb,%al
  je     L12
L22:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  call   <infromdev@plt>
  cmp    $0xdc,%al
  je     L16
  mov    $0xdb,%r8d
  cmp    $0xdd,%al
  je     L22
L19:
  mov    $0xffffffff,%r8d
  jmp    L22
  nopl   (%rax)
L16:
  mov    $0xc0,%r8d
  jmp    L22
```

assistant: ```c
int sliprxone(void) {
  register unsigned char c;
  register unsigned char d;
  c = infromdev();
  if (c == 0xC0)
    return -1;
  if (c == 0xDB) {
    d = infromdev();
    if (d == 0xDC)
      return (0xC0);
    if (d == 0xDD)
      return (0xDB);
    return (-1);
  }
  return (c);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<sliprxone>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <infromdev@plt>
  cmp    $0xc0,%al
  je     L8
  movzbl %al,%r8d
  cmp    $0xdb,%al
  je     L17
L4:
  mov    %r8d,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  call   <infromdev@plt>
  cmp    $0xdc,%al
  je     L32
  mov    $0xdb,%r8d
  cmp    $0xdd,%al
  je     L4
L8:
  mov    $0xffffffff,%r8d
  jmp    L4
  nopl   (%rax)
L32:
  mov    $0xc0,%r8d
  jmp    L4
```

assistant: ```c
int sliprxone(void) {
  register unsigned char c;
  register unsigned char d;
  c = infromdev();
  if (c == 0xC0)
    return -1;
  if (c == 0xDB) {
    d = infromdev();
    if (d == 0xDC)
      return (0xC0);
    if (d == 0xDD)
      return (0xDB);
    return (-1);
  }
  return (c);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getNewDecimal>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x2,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %rcx,%r8
  mov    %rdx,%rcx
  lea    D4(%rip),%rdx
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type: string

tool: D4: %s.%s

assistant: ```c
char *getNewDecimal(char *left, char *right) {
  int size = strlen(left) + strlen(right) + 2;
  char *result = (char *)malloc(size);
  snprintf(result, size, "%s.%s", left, right);
  free(left);
  free(right);
  return result;
}
```