ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<calculate>:
  endbr64
  test   %edx,%edx
  jle    L2
  mov    %edx,%r8d
  mov    $0x0,%eax
  mov    $0x1,%ecx
L15:
  mov    %ecx,(%rsi,%rax,4)
  imul   (%rdi,%rax,4),%ecx
  add    $0x1,%rax
  cmp    %r8,%rax
  jne    L15
  sub    $0x1,%edx
  movslq %edx,%rax
  mov    $0x1,%edx
L20:
  mov    %edx,%ecx
  imul   (%rsi,%rax,4),%ecx
  mov    %ecx,(%rsi,%rax,4)
  imul   (%rdi,%rax,4),%edx
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L20
  ret
L2:
  ret
```

assistant: ```c
void calculate(int input[], int output[], int size) {
  int product = 1;
  for (int i = 0; i < size; i++) {
    output[i] = product;
    product *= input[i];
  }
  product = 1;
  for (int i = size - 1; i >= 0; i--) {
    output[i] *= product;
    product *= input[i];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<calculate>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L33
  movslq %edx,%rdx
  xor    %ecx,%ecx
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %r8d,(%rsi,%rcx,4)
  imul   (%rdi,%rcx,4),%r8d
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L3
L39:
  cltq
  mov    $0x1,%edx
  nopl   0x0(%rax)
L4:
  mov    (%rsi,%rax,4),%ecx
  imul   %edx,%ecx
  mov    %ecx,(%rsi,%rax,4)
  imul   (%rdi,%rax,4),%edx
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L4
  ret
  cs nopw 0x0(%rax,%rax,1)
L33:
  test   %eax,%eax
  jns    L39
  ret
```

assistant: ```c
void calculate(int input[], int output[], int size) {
  int product = 1;
  for (int i = 0; i < size; i++) {
    output[i] = product;
    product *= input[i];
  }
  product = 1;
  for (int i = size - 1; i >= 0; i--) {
    output[i] *= product;
    product *= input[i];
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<calculate>:
  endbr64
  lea    -0x1(%rdx),%eax
  test   %edx,%edx
  jle    L34
  movslq %edx,%rdx
  xor    %ecx,%ecx
  mov    $0x1,%r8d
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %r8d,(%rsi,%rcx,4)
  imul   (%rdi,%rcx,4),%r8d
  add    $0x1,%rcx
  cmp    %rcx,%rdx
  jne    L1
L16:
  cltq
  mov    $0x1,%edx
  nopl   0x0(%rax)
L9:
  mov    (%rsi,%rax,4),%ecx
  imul   %edx,%ecx
  mov    %ecx,(%rsi,%rax,4)
  imul   (%rdi,%rax,4),%edx
  sub    $0x1,%rax
  test   %eax,%eax
  jns    L9
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  test   %eax,%eax
  jns    L16
  ret
```

assistant: ```c
void calculate(int input[], int output[], int size) {
  int product = 1;
  for (int i = 0; i < size; i++) {
    output[i] = product;
    product *= input[i];
  }
  product = 1;
  for (int i = size - 1; i >= 0; i--) {
    output[i] *= product;
    product *= input[i];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_not>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jp     L5
  pxor   %xmm1,%xmm1
  ucomisd %xmm1,%xmm0
  jne    L5
  movsd  D2(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L16
L5:
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
L16:
  movsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
datatype: byte[8]

tool: {"D2": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double _not(const int numInputs, const double *inputs, const double *connectionWeights) {
  double out;
  if (inputs[0] == 0) {
    out = 1;
  } else {
    out = 0;
  }
  return out;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_not>:
  endbr64
  pxor   %xmm0,%xmm0
  ucomisd (%rsi),%xmm0
  jp     L12
  movsd  D5(%rip),%xmm0
  jne    L12
L3:
  ret
L12:
  pxor   %xmm0,%xmm0
  jmp    L3
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double _not(const int numInputs, const double *inputs, const double *connectionWeights) {
  double out;
  if (inputs[0] == 0) {
    out = 1;
  } else {
    out = 0;
  }
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<_not>:
  endbr64
  pxor   %xmm0,%xmm0
  ucomisd (%rsi),%xmm0
  jp     L15
  movsd  D4(%rip),%xmm1
  jne    L15
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L15:
  movapd %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_guessed: byte[8]

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double _not(const int numInputs, const double *inputs, const double *connectionWeights) {
  double out;
  if (inputs[0] == 0) {
    out = 1;
  } else {
    out = 0;
  }
  return out;
}
```
user: What is the c source code of the assembly code below?

```asm
<_not>:
  endbr64
  pxor   %xmm0,%xmm0
  ucomisd (%rsi),%xmm0
  jp     L4
  movsd  D5(%rip),%xmm1
  jne    L4
  movapd %xmm1,%xmm0
  ret
  nopl   (%rax)
L4:
  movapd %xmm0,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: byte[8]

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0xf0,0x3f]}

assistant: ```c
double _not(const int numInputs, const double *inputs, const double *connectionWeights) {
  double out;
  if (inputs[0] == 0) {
    out = 1;
  } else {
    out = 0;
  }
  return out;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cmp2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jp     L60
  movsd  -0x10(%rbp),%xmm0
  ucomisd -0x8(%rbp),%xmm0
  jne    L60
  mov    $0x0,%eax
  jmp    L15
L60:
  movsd  -0x10(%rbp),%xmm0
  comisd -0x8(%rbp),%xmm0
  jbe    L61
  mov    $0x1,%eax
  jmp    L15
L61:
  movsd  -0x8(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jbe    L52
  mov    $0xffffffff,%eax
  jmp    L15
L52:
  mov    $0x0,%eax
L15:
  pop    %rbp
  ret
```

assistant: ```c
int cmp2(void *a, void *b) {
  double a_, b_;
  a_ = *(double *)a;
  b_ = *(double *)b;
  if (a_ == b_)
    return 0;
  if (a_ > b_)
    return 1;
  if (a_ < b_)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<cmp2>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L9
  mov    $0x0,%eax
  je     L7
L9:
  mov    $0x1,%eax
  comisd %xmm1,%xmm0
  ja     L7
  comisd %xmm0,%xmm1
  seta   %al
  movzbl %al,%eax
  neg    %eax
L7:
  ret
```

assistant: ```c
int cmp2(void *a, void *b) {
  double a_, b_;
  a_ = *(double *)a;
  b_ = *(double *)b;
  if (a_ == b_)
    return 0;
  if (a_ > b_)
    return 1;
  if (a_ < b_)
    return -1;
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmp2>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L10
  mov    $0x0,%eax
  je     L20
L10:
  comisd %xmm1,%xmm0
  mov    $0x1,%eax
  ja     L20
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  neg    %eax
L20:
  ret
```

assistant: ```c
int cmp2(void *a, void *b) {
  double a_, b_;
  a_ = *(double *)a;
  b_ = *(double *)b;
  if (a_ == b_)
    return 0;
  if (a_ > b_)
    return 1;
  if (a_ < b_)
    return -1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cmp2>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  (%rsi),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L23
  mov    $0x0,%eax
  je     L15
L23:
  comisd %xmm1,%xmm0
  mov    $0x1,%eax
  ja     L15
  xor    %eax,%eax
  comisd %xmm0,%xmm1
  seta   %al
  neg    %eax
L15:
  ret
```

assistant: ```c
int cmp2(void *a, void *b) {
  double a_, b_;
  a_ = *(double *)a;
  b_ = *(double *)b;
  if (a_ == b_)
    return 0;
  if (a_ > b_)
    return 1;
  if (a_ < b_)
    return -1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x34(%rbp)
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x28(%rbp)
  cltq
  mov    %rax,%rcx
  mov    $0x0,%ebx
  mov    $0x0,%edi
  call   <s@plt>
L3:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x30(%rbp)
  cltq
  mov    %rax,%r12
  mov    $0x0,%r13d
  mov    $0x0,%edi
  call   <s@plt>
  jmp    L3
```

assistant: ```c
void f(int n) {
  if (1)
    s((int(*)[n])0);
  else
    s((int(*)[n])0);
  while (1)
    s((int(*)[n])0);
  for (;;)
    s((int(*)[n])0);
  switch (0)
    s((int(*)[n])0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <s@plt>
L3:
  mov    $0x0,%edi
  call   <s@plt>
  jmp    L3
```

assistant: ```c
void f(int n) {
  if (1)
    s((int(*)[n])0);
  else
    s((int(*)[n])0);
  while (1)
    s((int(*)[n])0);
  for (;;)
    s((int(*)[n])0);
  switch (0)
    s((int(*)[n])0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %edi,%edi
  call   <s@plt>
  jmp    L1
```

assistant: ```c
void f(int n) {
  if (1)
    s((int(*)[n])0);
  else
    s((int(*)[n])0);
  while (1)
    s((int(*)[n])0);
  for (;;)
    s((int(*)[n])0);
  switch (0)
    s((int(*)[n])0);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<f>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %edi,%edi
  call   <s@plt>
  jmp    L1
```

assistant: ```c
void f(int n) {
  if (1)
    s((int(*)[n])0);
  else
    s((int(*)[n])0);
  while (1)
    s((int(*)[n])0);
  for (;;)
    s((int(*)[n])0);
  switch (0)
    s((int(*)[n])0);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  cmpq   $0x0,-0x38(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0xffffffff,%eax
  jmp    L55
L16:
  movl   $0x0,-0x18(%rbp)
  jmp    L47
L4:
  movl   $0x0,-0x14(%rbp)
  jmp    L58
L5:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x14(%rbp),%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rdx,%rdi
  call   *%rax
  test   %eax,%eax
  je     L25
  mov    -0x14(%rbp),%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x14(%rbp),%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  imul   -0x30(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x30(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
L25:
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x2c(%rbp),%eax
  sub    -0x18(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L5
  addl   $0x1,-0x18(%rbp)
L47:
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x18(%rbp)
  jl     L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L55:
  leave
  ret
```

assistant: ```c
int bubble_sort(void *data, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  assert(data != NULL);
  assert(compare != NULL);
  int i = 0;
  int j = 0;
  char *a = data;
  char *elem_temp = NULL;
  if ((elem_temp = (char *)malloc(esize)) == NULL) {
    return -1;
  }
  for (i = 0; i < size - 1; ++i) {
    for (j = 0; j < size - i - 1; ++j) {
      if (compare(&a[j * esize], &a[(j + 1) * esize])) {
        memcpy(elem_temp, &a[j * esize], esize);
        memcpy(&a[j * esize], &a[(j + 1) * esize], esize);
        memcpy(&a[(j + 1) * esize], elem_temp, esize);
      }
    }
  }
  free(elem_temp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x18(%rsp)
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %edx,0x10(%rsp)
  mov    %rcx,%r14
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  test   %r14,%r14
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %ebp,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L24
  mov    %rax,%r15
  lea    -0x1(%rbx),%eax
  test   %eax,%eax
  jle    L15
  mov    %eax,0x14(%rsp)
  movslq %ebp,%rax
  mov    %rax,0x8(%rsp)
  jmp    L88
L26:
  cmp    %r13d,%ebp
  je     L94
L68:
  add    $0x1,%ebp
  mov    %rbx,%r12
  add    0x8(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   *%r14
  test   %eax,%eax
  je     L26
  mov    0x10(%rsp),%edx
  mov    %r12,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    0x10(%rsp),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  mov    0x10(%rsp),%edx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  jmp    L26
L94:
  subl   $0x1,0x14(%rsp)
  je     L15
L88:
  mov    0x14(%rsp),%eax
  mov    %eax,%r13d
  mov    0x18(%rsp),%rbx
  mov    $0x0,%ebp
  test   %eax,%eax
  jg     L68
  jmp    L94
L15:
  mov    %r15,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L58:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  mov    $0xffffffff,%eax
  jmp    L58
```

assistant: ```c
int bubble_sort(void *data, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  assert(data != NULL);
  assert(compare != NULL);
  int i = 0;
  int j = 0;
  char *a = data;
  char *elem_temp = NULL;
  if ((elem_temp = (char *)malloc(esize)) == NULL) {
    return -1;
  }
  for (i = 0; i < size - 1; ++i) {
    for (j = 0; j < size - i - 1; ++j) {
      if (compare(&a[j * esize], &a[(j + 1) * esize])) {
        memcpy(elem_temp, &a[j * esize], esize);
        memcpy(&a[j * esize], &a[(j + 1) * esize], esize);
        memcpy(&a[(j + 1) * esize], elem_temp, esize);
      }
    }
  }
  free(elem_temp);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  mov    %rdi,0x18(%rsp)
  setne  %dil
  movzbl %dil,%edi
  mov    %rcx,0x8(%rsp)
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L70
  sub    $0x1,%ebp
  mov    %rax,%r15
  test   %ebp,%ebp
  jle    L16
  movslq %r12d,%rax
  mov    %rax,0x10(%rsp)
  nopl   (%rax)
L48:
  mov    0x18(%rsp),%r14
  xor    %ebx,%ebx
  jmp    L71
  nopl   0x0(%rax)
L17:
  cmp    %ebp,%ebx
  je     L68
L71:
  mov    %r14,%r13
  add    0x10(%rsp),%r14
  add    $0x1,%ebx
  mov    0x8(%rsp),%rax
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   *%rax
  test   %eax,%eax
  je     L17
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  cmp    %ebp,%ebx
  jne    L71
L68:
  sub    $0x1,%ebp
  jne    L48
L16:
  mov    %r15,%rdi
  call   <free@plt>
  xor    %eax,%eax
L12:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L70:
  mov    $0xffffffff,%eax
  jmp    L12
```

assistant: ```c
int bubble_sort(void *data, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  assert(data != NULL);
  assert(compare != NULL);
  int i = 0;
  int j = 0;
  char *a = data;
  char *elem_temp = NULL;
  if ((elem_temp = (char *)malloc(esize)) == NULL) {
    return -1;
  }
  for (i = 0; i < size - 1; ++i) {
    for (j = 0; j < size - i - 1; ++j) {
      if (compare(&a[j * esize], &a[(j + 1) * esize])) {
        memcpy(elem_temp, &a[j * esize], esize);
        memcpy(&a[j * esize], &a[(j + 1) * esize], esize);
        memcpy(&a[(j + 1) * esize], elem_temp, esize);
      }
    }
  }
  free(elem_temp);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bubble_sort>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x28,%rsp
  test   %rdi,%rdi
  mov    %rdi,0x18(%rsp)
  setne  %dil
  movzbl %dil,%edi
  mov    %rcx,0x8(%rsp)
  call   <assert@plt>
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %r12d,%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L43
  sub    $0x1,%ebp
  mov    %rax,%r15
  test   %ebp,%ebp
  jle    L30
  movslq %r12d,%rax
  mov    %rax,0x10(%rsp)
  nopl   (%rax)
L3:
  mov    0x18(%rsp),%r14
  xor    %ebx,%ebx
  jmp    L76
  nopl   0x0(%rax)
L14:
  cmp    %ebp,%ebx
  je     L8
L76:
  mov    %r14,%r13
  add    0x10(%rsp),%r14
  add    $0x1,%ebx
  mov    0x8(%rsp),%rax
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   *%rax
  test   %eax,%eax
  je     L14
  mov    %r12d,%edx
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    %r12d,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  call   <memcpy@plt>
  cmp    %ebp,%ebx
  jne    L76
L8:
  sub    $0x1,%ebp
  jne    L3
L30:
  mov    %r15,%rdi
  call   <free@plt>
  xor    %eax,%eax
L72:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  mov    $0xffffffff,%eax
  jmp    L72
```

assistant: ```c
int bubble_sort(void *data, int size, int esize, int (*compare)(const void *key1, const void *key2)) {
  assert(data != NULL);
  assert(compare != NULL);
  int i = 0;
  int j = 0;
  char *a = data;
  char *elem_temp = NULL;
  if ((elem_temp = (char *)malloc(esize)) == NULL) {
    return -1;
  }
  for (i = 0; i < size - 1; ++i) {
    for (j = 0; j < size - i - 1; ++j) {
      if (compare(&a[j * esize], &a[(j + 1) * esize])) {
        memcpy(elem_temp, &a[j * esize], esize);
        memcpy(&a[j * esize], &a[(j + 1) * esize], esize);
        memcpy(&a[(j + 1) * esize], elem_temp, esize);
      }
    }
  }
  free(elem_temp);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BTSHASP_ParseToken>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %rdi,-0x118(%rbp)
  mov    %rsi,-0x120(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rdx
  mov    -0x118(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BTSHASP_ParseTokenBasic@plt>
  mov    %rax,-0x118(%rbp)
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <btshas_rstrdup@plt>
  mov    -0x120(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x118(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
char *BTSHASP_ParseToken(char *cs, char **rstr) {
  char tb[256];
  cs = BTSHASP_ParseTokenBasic(cs, tb);
  *rstr = btshas_rstrdup(tb);
  return (cs);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<BTSHASP_ParseToken>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  mov    %r12,%rsi
  call   <BTSHASP_ParseTokenBasic@plt>
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <btshas_rstrdup@plt>
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  mov    %rbp,%rax
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *BTSHASP_ParseToken(char *cs, char **rstr) {
  char tb[256];
  cs = BTSHASP_ParseTokenBasic(cs, tb);
  *rstr = btshas_rstrdup(tb);
  return (cs);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<BTSHASP_ParseToken>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <BTSHASP_ParseTokenBasic@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <btshas_rstrdup@plt>
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *BTSHASP_ParseToken(char *cs, char **rstr) {
  char tb[256];
  cs = BTSHASP_ParseTokenBasic(cs, tb);
  *rstr = btshas_rstrdup(tb);
  return (cs);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<BTSHASP_ParseToken>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <BTSHASP_ParseTokenBasic@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <btshas_rstrdup@plt>
  mov    %rax,(%rbx)
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x110,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *BTSHASP_ParseToken(char *cs, char **rstr) {
  char tb[256];
  cs = BTSHASP_ParseTokenBasic(cs, tb);
  *rstr = btshas_rstrdup(tb);
  return (cs);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<makepow2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L1
  mov    $0x0,%eax
  jmp    L27
L7:
  addl   $0x1,-0x4(%rbp)
L1:
  sarl   -0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int makepow2(int val) {
  int power = 0;
  if (!val)
    return 0;
  while (val >>= 1)
    power++;
  return (1 << power);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<makepow2>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L2
  sar    %edi
  je     L16
  mov    $0x0,%ecx
L18:
  add    $0x1,%ecx
  sar    %edi
  jne    L18
L4:
  mov    $0x1,%eax
  shl    %cl,%eax
L2:
  ret
L16:
  mov    %edi,%ecx
  jmp    L4
```

assistant: ```c
int makepow2(int val) {
  int power = 0;
  if (!val)
    return 0;
  while (val >>= 1)
    power++;
  return (1 << power);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<makepow2>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L20
  sar    %edi
  je     L2
  xor    %ecx,%ecx
L12:
  add    $0x1,%ecx
  sar    %edi
  jne    L12
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
  nop
L2:
  mov    $0x1,%eax
L20:
  ret
```

assistant: ```c
int makepow2(int val) {
  int power = 0;
  if (!val)
    return 0;
  while (val >>= 1)
    power++;
  return (1 << power);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<makepow2>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L26
  sar    %edi
  je     L14
  xor    %ecx,%ecx
L12:
  add    $0x1,%ecx
  sar    %edi
  jne    L12
  mov    $0x1,%eax
  shl    %cl,%eax
  ret
  nop
L14:
  mov    $0x1,%eax
L26:
  ret
```

assistant: ```c
int makepow2(int val) {
  int power = 0;
  if (!val)
    return 0;
  while (val >>= 1)
    power++;
  return (1 << power);
}
```