ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<RandomFunc>:
  endbr64
  movabs $0xf8441195ebbd65eb,%rdx
  mov    (%rdi),%rax
  sub    $0x99f4bb,%rax
  imul   $0x42ae47dd,%rax,%rax
  add    %rdx,%rax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  char copy12;
  {
    state[0UL] = input[0UL] + 0xffffffffff660b45UL;
    local1 = 0UL;
    while (local1 < 0UL) {
      if (!(state[0UL] > local1)) {
        state[0UL] += state[0UL];
      }
      if (state[0UL] > local1) {
        state[local1] = state[0UL] - state[local1];
      } else {
        copy12 = *((char *)(&state[0UL]) + 1);
        *((char *)(&state[0UL]) + 1) = *((char *)(&state[0UL]) + 0);
        *((char *)(&state[0UL]) + 0) = copy12;
      }
      local1 += 2UL;
    }
    output[0UL] = (state[0UL] - 498160537UL) * 1118717917UL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<util_str_ends_with>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jbe    L37
  mov    $0x0,%eax
  jmp    L3
L4:
  mov    -0x10(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L41
  mov    $0x0,%eax
  jmp    L3
L41:
  subq   $0x1,-0x10(%rbp)
  subq   $0x1,-0x8(%rbp)
L37:
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    $0x1,%eax
L3:
  leave
  ret
```

assistant: ```c
int util_str_ends_with(const char *str, const char *end) {
  size_t i, j;
  i = strlen(str);
  j = strlen(end);
  if (j > i) {
    return 0;
  }
  while (j > 0) {
    if (str[i - 1] != end[j - 1]) {
      return 0;
    }
    i--;
    j--;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<util_str_ends_with>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    $0x0,%edx
  cmp    %rax,%r12
  jb     L24
  mov    %rax,%rdx
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rcx
L36:
  test   %rdx,%rdx
  je     L21
  movzbl -0x1(%rcx,%rdx,1),%eax
  sub    $0x1,%rdx
  cmp    0x0(%rbp,%rdx,1),%al
  je     L36
  mov    $0x0,%edx
  jmp    L24
L21:
  mov    $0x1,%edx
L24:
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int util_str_ends_with(const char *str, const char *end) {
  size_t i, j;
  i = strlen(str);
  j = strlen(end);
  if (j > i) {
    return 0;
  }
  while (j > 0) {
    if (str[i - 1] != end[j - 1]) {
      return 0;
    }
    i--;
    j--;
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<util_str_ends_with>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    %rdx,%r12
  jb     L7
  sub    %rdx,%r12
  lea    (%rbx,%r12,1),%rdi
  jmp    L2
  nopl   0x0(%rax)
L0:
  movzbl -0x1(%rdi,%rdx,1),%eax
  sub    $0x1,%rdx
  cmp    0x0(%rbp,%rdx,1),%al
  jne    L28
L2:
  test   %rdx,%rdx
  jne    L0
  mov    $0x1,%eax
L7:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int util_str_ends_with(const char *str, const char *end) {
  size_t i, j;
  i = strlen(str);
  j = strlen(end);
  if (j > i) {
    return 0;
  }
  while (j > 0) {
    if (str[i - 1] != end[j - 1]) {
      return 0;
    }
    i--;
    j--;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<util_str_ends_with>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  mov    %rax,%rdx
  xor    %eax,%eax
  cmp    %rdx,%r12
  jb     L25
  sub    %rdx,%r12
  lea    (%rbx,%r12,1),%rdi
  jmp    L31
  nopl   0x0(%rax)
L4:
  movzbl -0x1(%rdi,%rdx,1),%eax
  sub    $0x1,%rdx
  cmp    0x0(%rbp,%rdx,1),%al
  jne    L6
L31:
  test   %rdx,%rdx
  jne    L4
  mov    $0x1,%eax
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L6:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int util_str_ends_with(const char *str, const char *end) {
  size_t i, j;
  i = strlen(str);
  j = strlen(end);
  if (j > i) {
    return 0;
  }
  while (j > 0) {
    if (str[i - 1] != end[j - 1]) {
      return 0;
    }
    i--;
    j--;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<trim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L34
L12:
  addq   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L4
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L12
L4:
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L49:
  subq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jbe    L27
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L49
L27:
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x28(%rbp),%rax
  add    %rax,%rcx
  mov    -0x28(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  sub    %edx,%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void trim(line) char *line;
{
  int size, begin, end;
  char *p;
  size = strlen(line);
  p = line;
  while (*p != '\0' && isspace(*p))
    p++;
  begin = p - line;
  p = (line + size) - 1;
  while (p > line && isspace(*p))
    p--;
  end = size - (p - line) - 1;
  memmove(line, line + begin, size - (begin + end));
  line[size - (begin + end)] = '\0';
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trim>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%edi
  mov    %rbp,%r13
  test   %dil,%dil
  je     L0
L55:
  movsbl %dil,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L0
  add    $0x1,%r13
  movzbl 0x0(%r13),%edi
  test   %dil,%dil
  jne    L55
L0:
  sub    %rbp,%r13
  movslq %r12d,%rax
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jae    L14
L13:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L14
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  jne    L13
  mov    %rbp,%rbx
L14:
  lea    -0x1(%r12),%eax
  sub    %rbp,%rbx
  sub    %ebx,%eax
  add    %r13d,%eax
  sub    %eax,%r12d
  movslq %r12d,%r12
  movslq %r13d,%rsi
  add    %rbp,%rsi
  mov    %r12,%rdx
  mov    %rbp,%rdi
  call   <memmove@plt>
  movb   $0x0,0x0(%rbp,%r12,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void trim(line) char *line;
{
  int size, begin, end;
  char *p;
  size = strlen(line);
  p = line;
  while (*p != '\0' && isspace(*p))
    p++;
  begin = p - line;
  p = (line + size) - 1;
  while (p > line && isspace(*p))
    p--;
  end = size - (p - line) - 1;
  memmove(line, line + begin, size - (begin + end));
  line[size - (begin + end)] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<trim>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%r13
  call   <strlen@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L76
  mov    %rbp,%rbx
  jmp    L5
  nopl   0x0(%rax,%rax,1)
L50:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L55
L5:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L50
L55:
  sub    %rbp,%rbx
  mov    %ebx,%r14d
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%r13
L76:
  movslq %r12d,%rax
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jb     L33
  jmp    L44
  nopl   0x0(%rax,%rax,1)
L48:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L44
L33:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L48
L44:
  sub    %rbp,%rbx
  lea    -0x1(%r12),%eax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  sub    %ebx,%eax
  add    %r14d,%eax
  sub    %eax,%r12d
  movslq %r12d,%r12
  mov    %r12,%rdx
  call   <memmove@plt>
  pop    %rbx
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void trim(line) char *line;
{
  int size, begin, end;
  char *p;
  size = strlen(line);
  p = line;
  while (*p != '\0' && isspace(*p))
    p++;
  begin = p - line;
  p = (line + size) - 1;
  while (p > line && isspace(*p))
    p--;
  end = size - (p - line) - 1;
  memmove(line, line + begin, size - (begin + end));
  line[size - (begin + end)] = '\0';
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<trim>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%r13
  call   <strlen@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L17
  mov    %rbp,%rbx
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L2:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L60
L25:
  call   <isspace@plt>
  test   %eax,%eax
  jne    L2
L60:
  sub    %rbp,%rbx
  mov    %ebx,%r14d
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%r13
L17:
  movslq %r12d,%rax
  lea    -0x1(%rbp,%rax,1),%rbx
  cmp    %rbx,%rbp
  jb     L32
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L58:
  sub    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L36
L32:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L58
L36:
  sub    %rbp,%rbx
  lea    -0x1(%r12),%eax
  mov    %r13,%rsi
  mov    %rbp,%rdi
  sub    %ebx,%eax
  add    %r14d,%eax
  sub    %eax,%r12d
  movslq %r12d,%r12
  mov    %r12,%rdx
  call   <memmove@plt>
  pop    %rbx
  movb   $0x0,0x0(%rbp,%r12,1)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void trim(line) char *line;
{
  int size, begin, end;
  char *p;
  size = strlen(line);
  p = line;
  while (*p != '\0' && isspace(*p))
    p++;
  begin = p - line;
  p = (line + size) - 1;
  while (p > line && isspace(*p))
    p--;
  end = size - (p - line) - 1;
  memmove(line, line + begin, size - (begin + end));
  line[size - (begin + end)] = '\0';
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    $0x0,%eax
  call   <showFiles@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  showFiles();
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <showFiles@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  showFiles();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <showFiles@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  showFiles();
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <showFiles@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[], char *envp[]) {
  showFiles();
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<seno>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movss  %xmm0,-0x24(%rbp)
  movss  %xmm1,-0x28(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
L3:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  mov    D2(%rip),%eax
  movd   %eax,%xmm0
  call   <pow@plt>
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  lea    -0x1(%rax),%edx
  mov    -0x24(%rbp),%eax
  mov    %edx,%edi
  movd   %eax,%xmm0
  call   <pow@plt>
  movapd %xmm0,%xmm2
  mulsd  -0x30(%rbp),%xmm2
  movsd  %xmm2,-0x30(%rbp)
  mov    -0x14(%rbp),%eax
  add    %eax,%eax
  sub    $0x1,%eax
  mov    %eax,%edi
  call   <factorial@plt>
  movapd %xmm0,%xmm1
  movsd  -0x30(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x10(%rbp),%xmm0
  addsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <fabs@plt>
  movd   %xmm0,%eax
  movd   %eax,%xmm4
  comiss -0x28(%rbp),%xmm4
  jae    L3
  movsd  -0x10(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: byte[4]

tool: {"D2": [0x00,0x00,0x80,0xbf]}

assistant: ```c
double seno(float x, float tol) {
  double term, result = 0;
  int i = 1;
  do {
    term = pow(-1, i - 1) * pow(x, 2 * i - 1) / factorial(2 * i - 1);
    result += term;
    i++;
  } while (fabs(term) >= tol);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<seno>:
  endbr64
  push   %r14
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  %xmm0,0x8(%rsp)
  movss  %xmm1,0xc(%rsp)
  mov    $0x1,%ebx
  mov    $0x0,%ebp
  mov    D12(%rip),%r12
L4:
  mov    %ebp,%edi
  movss  D2(%rip),%xmm0
  call   <pow@plt>
  movq   %xmm0,%r14
  mov    %ebx,%edi
  movss  0x8(%rsp),%xmm0
  call   <pow@plt>
  movq   %r14,%xmm3
  mulsd  %xmm3,%xmm0
  movsd  %xmm0,(%rsp)
  mov    %ebx,%edi
  call   <factorial@plt>
  movapd %xmm0,%xmm1
  movsd  (%rsp),%xmm0
  divsd  %xmm1,%xmm0
  movq   %r12,%xmm2
  addsd  %xmm0,%xmm2
  movq   %xmm2,%r12
  call   <fabs@plt>
  add    $0x1,%ebp
  add    $0x2,%ebx
  comiss 0xc(%rsp),%xmm0
  jae    L4
  movq   %r12,%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_label: D12
datatype: f64
name: read_data
arguments: data_label: D2
datatype: byte[4]

tool: D12: 0

tool: {"D2": [0x00,0x00,0x80,0xbf]}

assistant: ```c
double seno(float x, float tol) {
  double term, result = 0;
  int i = 1;
  do {
    term = pow(-1, i - 1) * pow(x, 2 * i - 1) / factorial(2 * i - 1);
    result += term;
    i++;
  } while (fabs(term) >= tol);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<seno>:
  endbr64
  push   %r15
  pxor   %xmm5,%xmm5
  movd   %xmm0,%r15d
  push   %r14
  movq   %xmm5,%r14
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  nopl   0x0(%rax)
L6:
  movss  D4(%rip),%xmm0
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %ebx,%edi
  movsd  %xmm0,(%rsp)
  movd   %r15d,%xmm0
  call   <pow@plt>
  movsd  (%rsp),%xmm1
  mov    %ebx,%edi
  add    $0x2,%ebx
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  call   <factorial@plt>
  movsd  (%rsp),%xmm1
  movq   %r14,%xmm3
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm3
  movapd %xmm1,%xmm0
  movq   %xmm3,%r14
  call   <fabs@plt>
  comiss 0xc(%rsp),%xmm0
  jae    L6
  add    $0x18,%rsp
  movq   %r14,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D4
type_guessed: byte[4]

tool: {"D4": [0x00,0x00,0x80,0xbf]}

assistant: ```c
double seno(float x, float tol) {
  double term, result = 0;
  int i = 1;
  do {
    term = pow(-1, i - 1) * pow(x, 2 * i - 1) / factorial(2 * i - 1);
    result += term;
    i++;
  } while (fabs(term) >= tol);
  return result;
}
```
user: What is the c source code of the assembly code below?

```asm
<seno>:
  endbr64
  push   %r15
  pxor   %xmm5,%xmm5
  movd   %xmm0,%r15d
  push   %r14
  movq   %xmm5,%r14
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  nopl   0x0(%rax)
L9:
  movss  D8(%rip),%xmm0
  mov    %ebp,%edi
  add    $0x1,%ebp
  call   <pow@plt>
  mov    %ebx,%edi
  movsd  %xmm0,(%rsp)
  movd   %r15d,%xmm0
  call   <pow@plt>
  movsd  (%rsp),%xmm1
  mov    %ebx,%edi
  add    $0x2,%ebx
  mulsd  %xmm0,%xmm1
  movsd  %xmm1,(%rsp)
  call   <factorial@plt>
  movsd  (%rsp),%xmm1
  movq   %r14,%xmm3
  divsd  %xmm0,%xmm1
  addsd  %xmm1,%xmm3
  movapd %xmm1,%xmm0
  movq   %xmm3,%r14
  call   <fabs@plt>
  comiss 0xc(%rsp),%xmm0
  jae    L9
  add    $0x18,%rsp
  movq   %r14,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D8
data_type: byte[4]

tool: {"D8": [0x00,0x00,0x80,0xbf]}

assistant: ```c
double seno(float x, float tol) {
  double term, result = 0;
  int i = 1;
  do {
    term = pow(-1, i - 1) * pow(x, 2 * i - 1) / factorial(2 * i - 1);
    result += term;
    i++;
  } while (fabs(term) >= tol);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imap_undefer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <isany_deferred@plt>
  test   %rax,%rax
  je     L5
  mov    $0x0,%eax
  call   <pop_deferred@plt>
L5:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void imap_undefer(void) {
  if (isany_deferred())
    pop_deferred();
}
```
user: What is the c source code of the assembly code below?

```asm
<imap_undefer>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <isany_deferred@plt>
  test   %rax,%rax
  jne    L8
L17:
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <pop_deferred@plt>
  jmp    L17
```

assistant: ```c
void imap_undefer(void) {
  if (isany_deferred())
    pop_deferred();
}
```
user: Translate the below assembly code into C programming language:

```asm
<imap_undefer>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <isany_deferred@plt>
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L8:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <pop_deferred@plt>
```

assistant: ```c
void imap_undefer(void) {
  if (isany_deferred())
    pop_deferred();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imap_undefer>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <isany_deferred@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L1:
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <pop_deferred@plt>
```

assistant: ```c
void imap_undefer(void) {
  if (isany_deferred())
    pop_deferred();
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<GuardaMap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x90,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x78(%rbp)
  mov    -0x90(%rbp),%rdx
  lea    -0x70(%rbp),%rax
  lea    D16(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    -0x70(%rbp),%rax
  lea    D2(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x78(%rbp)
  movl   $0x0,-0x7c(%rbp)
  jmp    L22
L33:
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  mov    $0x4,%edx
  lea    D25(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L13
  mov    -0x7c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rax,%rdx
  mov    -0x78(%rbp),%rax
  lea    D35(%rip),%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  mov    -0x7c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x7c(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  shl    $0x2,%rax
  add    %rax,%rcx
  mov    -0x88(%rbp),%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L13:
  addl   $0x1,-0x7c(%rbp)
L22:
  cmpl   $0x13,-0x7c(%rbp)
  jle    L33
  mov    -0x78(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D16
datatype: string
name: read_data
arguments: label: D2
datatype: string
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D35
datatype: string

tool: D16: %s_MapTipos

tool: D2: w

tool: D25: 0000

tool: D35: %s -> %d


assistant: ```c
void GuardaMap(char map[20][5], char *origen) {
  FILE *fmap = NULL;
  char archivo[100];
  sprintf(archivo, "%s_MapTipos", origen);
  fmap = fopen(archivo, "w");
  int i;
  for (i = 0; i < 20; i++) {
    if (strncmp(map[i], "0000", 4) != 0) {
      fprintf(fmap, "%s -> %d\n", map[i], (i + 1));
      printf("%s -> %d\n", map[i], (i + 1));
    }
  }
  fclose(fmap);
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GuardaMap>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    D9(%rip),%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
  lea    D28(%rip),%rsi
  mov    %rbp,%rdi
  call   <fopen@plt>
  mov    %rax,%r13
  mov    $0x1,%ebp
  lea    D0(%rip),%r12
  lea    D39(%rip),%r14
  jmp    L4
L27:
  add    $0x1,%ebp
  add    $0x5,%rbx
  cmp    $0x15,%ebp
  je     L42
L4:
  mov    $0x4,%edx
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L27
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <fprintf@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L27
L42:
  mov    %r13,%rdi
  call   <fclose@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D28
type_guessed: string
name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: string

tool: D9: %s_MapTipos

tool: D28: w

tool: D0: 0000

tool: D39: %s -> %d


assistant: ```c
void GuardaMap(char map[20][5], char *origen) {
  FILE *fmap = NULL;
  char archivo[100];
  sprintf(archivo, "%s_MapTipos", origen);
  fmap = fopen(archivo, "w");
  int i;
  for (i = 0; i < 20; i++) {
    if (strncmp(map[i], "0000", 4) != 0) {
      fprintf(fmap, "%s -> %d\n", map[i], (i + 1));
      printf("%s -> %d\n", map[i], (i + 1));
    }
  }
  fclose(fmap);
  return;
}
```