ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<calcbucket>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
  mov    $0x0,%eax
L20:
  add    $0x1,%rdi
  movsbl %dl,%edx
  add    %edx,%eax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L20
L1:
  movzbl %al,%eax
  ret
L2:
  mov    $0x0,%eax
  jmp    L1
```

assistant: ```c
int calcbucket(char *p) {
  int bucket = 0;
  while (*p)
    bucket += *p++;
  return bucket & (256 - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcbucket>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L9
  nopl   (%rax)
L12:
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L12
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
int calcbucket(char *p) {
  int bucket = 0;
  while (*p)
    bucket += *p++;
  return bucket & (256 - 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<calcbucket>:
  endbr64
  movsbl (%rdi),%edx
  xor    %eax,%eax
  test   %dl,%dl
  je     L5
  nopl   (%rax)
L14:
  add    $0x1,%rdi
  add    %edx,%eax
  movsbl (%rdi),%edx
  test   %dl,%dl
  jne    L14
  movzbl %al,%eax
  ret
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
int calcbucket(char *p) {
  int bucket = 0;
  while (*p)
    bucket += *p++;
  return bucket & (256 - 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<shellSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <tty_puts@plt>
  movl   $0x7,-0x4(%rbp)
  jmp    L1
L11:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <shellSortPhase@plt>
  subl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x0,-0x4(%rbp)
  jns    L11
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D12
datatype: string
name: parse_data
arguments: tag: D10
datatype: string

tool: D12: Shell Sort


tool: D10: 

assistant: ```c
void shellSort(unsigned int *base, unsigned int n) {
  static const int gaps[] = {1, 4, 10, 23, 57, 132, 301, 701};
  int sizeIndex;
  tty_puts("Shell Sort\n");
  for (sizeIndex = sizeof(gaps) / sizeof(gaps[0]) - 1; sizeIndex >= 0; --sizeIndex)
    shellSortPhase(base, n, gaps[sizeIndex]);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<shellSort>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  lea    D15(%rip),%rdi
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  lea    D7(%rip),%rbx
  lea    -0x1c(%rbx),%r13
  sub    $0x8,%rsp
  call   <tty_puts@plt>
  mov    $0x2bd,%edx
  jmp    L15
  nopl   0x0(%rax)
L5:
  mov    (%rbx),%edx
  sub    $0x4,%rbx
L15:
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <shellSortPhase@plt>
  cmp    %r13,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D15
datatype: string
name: extract_symbolic_data
arguments: data_label: D7
datatype: string

tool: D15: Shell Sort


tool: D7: -

assistant: ```c
void shellSort(unsigned int *base, unsigned int n) {
  static const int gaps[] = {1, 4, 10, 23, 57, 132, 301, 701};
  int sizeIndex;
  tty_puts("Shell Sort\n");
  for (sizeIndex = sizeof(gaps) / sizeof(gaps[0]) - 1; sizeIndex >= 0; --sizeIndex)
    shellSortPhase(base, n, gaps[sizeIndex]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitReverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  shr    %eax
  and    $0x55555555,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%eax
  and    $0xcccccccc,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf0f0f0f,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x8,%eax
  and    $0xff00ff00,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  roll   $0x10,-0x4(%rbp)
  mov    $0x20,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int bitReverse(unsigned int x, unsigned int length) {
  x = (((x & 0xaaaaaaaa) >> 1) | ((x & 0x55555555) << 1));
  x = (((x & 0xcccccccc) >> 2) | ((x & 0x33333333) << 2));
  x = (((x & 0xf0f0f0f0) >> 4) | ((x & 0x0f0f0f0f) << 4));
  x = (((x & 0xff00ff00) >> 8) | ((x & 0x00ff00ff) << 8));
  x = (x >> 16) | (x << 16);
  return (x >> (32 - length));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<bitReverse>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  and    $0x55555555,%edi
  add    %eax,%eax
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%eax
  shr    $0x2,%eax
  and    $0x33333333,%eax
  shl    $0x2,%edi
  and    $0xcccccccc,%edi
  or     %edi,%eax
  mov    %eax,%edx
  shr    $0x4,%edx
  and    $0xf0f0f0f,%edx
  shl    $0x4,%eax
  and    $0xf0f0f0f0,%eax
  or     %eax,%edx
  mov    %edx,%eax
  shr    $0x8,%eax
  and    $0xff00ff,%eax
  shl    $0x8,%edx
  and    $0xff00ff00,%edx
  or     %edx,%eax
  rol    $0x10,%eax
  mov    $0x20,%ecx
  sub    %esi,%ecx
  shr    %cl,%eax
  ret
```

assistant: ```c
unsigned int bitReverse(unsigned int x, unsigned int length) {
  x = (((x & 0xaaaaaaaa) >> 1) | ((x & 0x55555555) << 1));
  x = (((x & 0xcccccccc) >> 2) | ((x & 0x33333333) << 2));
  x = (((x & 0xf0f0f0f0) >> 4) | ((x & 0x0f0f0f0f) << 4));
  x = (((x & 0xff00ff00) >> 8) | ((x & 0x00ff00ff) << 8));
  x = (x >> 16) | (x << 16);
  return (x >> (32 - length));
}
```
user: What is the c source code of the assembly code below:

```asm
<bitReverse>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  mov    $0x20,%ecx
  add    %eax,%eax
  and    $0x55555555,%edi
  sub    %esi,%ecx
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  shl    $0x2,%edi
  shr    $0x2,%edx
  and    $0xcccccccc,%edi
  and    $0x33333333,%edx
  or     %edi,%edx
  mov    %edx,%eax
  shl    $0x4,%edx
  shr    $0x4,%eax
  and    $0xf0f0f0f0,%edx
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  bswap  %eax
  shr    %cl,%eax
  ret
```

assistant: ```c
unsigned int bitReverse(unsigned int x, unsigned int length) {
  x = (((x & 0xaaaaaaaa) >> 1) | ((x & 0x55555555) << 1));
  x = (((x & 0xcccccccc) >> 2) | ((x & 0x33333333) << 2));
  x = (((x & 0xf0f0f0f0) >> 4) | ((x & 0x0f0f0f0f) << 4));
  x = (((x & 0xff00ff00) >> 8) | ((x & 0x00ff00ff) << 8));
  x = (x >> 16) | (x << 16);
  return (x >> (32 - length));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bitReverse>:
  endbr64
  mov    %edi,%eax
  shr    %edi
  mov    $0x20,%ecx
  add    %eax,%eax
  and    $0x55555555,%edi
  sub    %esi,%ecx
  and    $0xaaaaaaaa,%eax
  or     %eax,%edi
  mov    %edi,%edx
  shl    $0x2,%edi
  shr    $0x2,%edx
  and    $0xcccccccc,%edi
  and    $0x33333333,%edx
  or     %edi,%edx
  mov    %edx,%eax
  shl    $0x4,%edx
  shr    $0x4,%eax
  and    $0xf0f0f0f0,%edx
  and    $0xf0f0f0f,%eax
  or     %edx,%eax
  bswap  %eax
  shr    %cl,%eax
  ret
```

assistant: ```c
unsigned int bitReverse(unsigned int x, unsigned int length) {
  x = (((x & 0xaaaaaaaa) >> 1) | ((x & 0x55555555) << 1));
  x = (((x & 0xcccccccc) >> 2) | ((x & 0x33333333) << 2));
  x = (((x & 0xf0f0f0f0) >> 4) | ((x & 0x0f0f0f0f) << 4));
  x = (((x & 0xff00ff00) >> 8) | ((x & 0x00ff00ff) << 8));
  x = (x >> 16) | (x << 16);
  return (x >> (32 - length));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<index2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L31
L23:
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  cmp    $0xb,%eax
  jg     L38
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  add    $0x30,%eax
  jmp    L51
L38:
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  cmp    $0x25,%eax
  jg     L18
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  add    $0x35,%eax
  jmp    L51
L18:
  mov    -0x1c(%rbp),%eax
  and    $0x3f,%eax
  add    $0x3b,%eax
L51:
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    %al,(%rdx)
  sarl   $0x6,-0x1c(%rbp)
  addl   $0x1,-0x4(%rbp)
L31:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L23
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *index2str(char *buffer, int index, int charsPerPixel) {
  int i;
  for (i = 0; i < charsPerPixel; i++) {
    buffer[i] = ((index & 63) < 12 ? (index & 63) + '0' : ((index & 63) < 38 ? (index & 63) + 'A' - 12 : (index & 63) + 'a' - 38));
    index >>= 6;
  }
  buffer[i] = 0;
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<index2str>:
  endbr64
  mov    %rdi,%r8
  test   %edx,%edx
  jle    L38
  mov    %rdi,%rax
  lea    -0x1(%rdx),%ecx
  lea    0x1(%rdi,%rcx,1),%rdi
  jmp    L30
L6:
  cmp    $0x25,%ecx
  jg     L33
  mov    %esi,%ecx
  and    $0x3f,%ecx
  add    $0x35,%ecx
L21:
  mov    %cl,(%rax)
  sar    $0x6,%esi
  add    $0x1,%rax
  cmp    %rdi,%rax
  je     L46
L30:
  mov    %esi,%ecx
  and    $0x3f,%ecx
  cmp    $0xb,%ecx
  jg     L6
  mov    %esi,%ecx
  and    $0x3f,%ecx
  add    $0x30,%ecx
  jmp    L21
L33:
  mov    %esi,%ecx
  and    $0x3f,%ecx
  add    $0x3b,%ecx
  jmp    L21
L38:
  mov    $0x0,%edx
L46:
  movslq %edx,%rdx
  movb   $0x0,(%r8,%rdx,1)
  mov    %r8,%rax
  ret
```

assistant: ```c
char *index2str(char *buffer, int index, int charsPerPixel) {
  int i;
  for (i = 0; i < charsPerPixel; i++) {
    buffer[i] = ((index & 63) < 12 ? (index & 63) + '0' : ((index & 63) < 38 ? (index & 63) + 'A' - 12 : (index & 63) + 'a' - 38));
    index >>= 6;
  }
  buffer[i] = 0;
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<index2str>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  jle    L40
  lea    -0x1(%rdx),%ecx
  mov    %rdi,%rax
  lea    0x1(%rdi,%rcx,1),%r8
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L44:
  add    $0x30,%ecx
  add    $0x1,%rax
  sar    $0x6,%esi
  mov    %cl,-0x1(%rax)
  cmp    %rax,%r8
  je     L3
L36:
  mov    %esi,%ecx
  and    $0x3f,%ecx
  cmp    $0xb,%ecx
  jle    L44
  lea    0x35(%rcx),%r9d
  cmp    $0x25,%ecx
  lea    0x3b(%rcx),%edi
  mov    %r9d,%ecx
  cmovg  %edi,%ecx
  add    $0x1,%rax
  sar    $0x6,%esi
  mov    %cl,-0x1(%rax)
  cmp    %rax,%r8
  jne    L36
L3:
  movslq %edx,%rdx
  mov    %r10,%rax
  add    %r10,%rdx
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L40:
  mov    %rdi,%rdx
  mov    %r10,%rax
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *index2str(char *buffer, int index, int charsPerPixel) {
  int i;
  for (i = 0; i < charsPerPixel; i++) {
    buffer[i] = ((index & 63) < 12 ? (index & 63) + '0' : ((index & 63) < 38 ? (index & 63) + 'A' - 12 : (index & 63) + 'a' - 38));
    index >>= 6;
  }
  buffer[i] = 0;
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<index2str>:
  endbr64
  mov    %rdi,%r10
  test   %edx,%edx
  jle    L25
  lea    -0x1(%rdx),%ecx
  mov    %rdi,%rax
  lea    0x1(%rdi,%rcx,1),%r8
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x30,%ecx
  add    $0x1,%rax
  sar    $0x6,%esi
  mov    %cl,-0x1(%rax)
  cmp    %rax,%r8
  je     L40
L0:
  mov    %esi,%ecx
  and    $0x3f,%ecx
  cmp    $0xb,%ecx
  jle    L2
  lea    0x35(%rcx),%r9d
  cmp    $0x25,%ecx
  lea    0x3b(%rcx),%edi
  mov    %r9d,%ecx
  cmovg  %edi,%ecx
  add    $0x1,%rax
  sar    $0x6,%esi
  mov    %cl,-0x1(%rax)
  cmp    %rax,%r8
  jne    L0
L40:
  movslq %edx,%rdx
  mov    %r10,%rax
  add    %r10,%rdx
  movb   $0x0,(%rdx)
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %rdi,%rdx
  mov    %r10,%rax
  movb   $0x0,(%rdx)
  ret
```

assistant: ```c
char *index2str(char *buffer, int index, int charsPerPixel) {
  int i;
  for (i = 0; i < charsPerPixel; i++) {
    buffer[i] = ((index & 63) < 12 ? (index & 63) + '0' : ((index & 63) < 38 ? (index & 63) + 'A' - 12 : (index & 63) + 'a' - 38));
    index >>= 6;
  }
  buffer[i] = 0;
  return buffer;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<psBurnStack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x20,%esi
  mov    %rax,%rdi
  call   <psZeromem@plt>
  cmpq   $0x20,-0x38(%rbp)
  jbe    L18
  mov    -0x38(%rbp),%rax
  sub    $0x20,%rax
  mov    %rax,%rdi
  call   <psBurnStack>
L18:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void psBurnStack(unsigned long len) {
  unsigned char buf[32];
  psZeromem(buf, sizeof(buf));
  if (len > (unsigned long)sizeof(buf)) {
    psBurnStack(len - sizeof(buf));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<psBurnStack>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x20,%esi
  call   <psZeromem@plt>
  cmp    $0x20,%rbx
  ja     L6
L21:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x30,%rsp
  pop    %rbx
  ret
L6:
  lea    -0x20(%rbx),%rdi
  call   <psBurnStack>
  jmp    L21
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void psBurnStack(unsigned long len) {
  unsigned char buf[32];
  psZeromem(buf, sizeof(buf));
  if (len > (unsigned long)sizeof(buf)) {
    psBurnStack(len - sizeof(buf));
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<psBurnStack>:
  endbr64
  push   %rbx
  mov    $0x20,%esi
  mov    %rdi,%rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <psZeromem@plt>
  cmp    $0x20,%rbx
  ja     L29
L23:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x70,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L29:
  lea    0x20(%rsp),%rdi
  mov    $0x20,%esi
  call   <psZeromem@plt>
  lea    -0x20(%rbx),%rax
  cmp    $0x20,%rax
  jbe    L23
  lea    0x40(%rsp),%rdi
  mov    $0x20,%esi
  call   <psZeromem@plt>
  lea    -0x40(%rbx),%rax
  cmp    $0x20,%rax
  jbe    L23
  lea    -0x60(%rbx),%rdi
  call   <psBurnStack>
  jmp    L23
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void psBurnStack(unsigned long len) {
  unsigned char buf[32];
  psZeromem(buf, sizeof(buf));
  if (len > (unsigned long)sizeof(buf)) {
    psBurnStack(len - sizeof(buf));
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<psBurnStack>:
  endbr64
  push   %rbx
  mov    $0x20,%esi
  mov    %rdi,%rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <psZeromem@plt>
  cmp    $0x20,%rbx
  ja     L15
L27:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x70,%rsp
  pop    %rbx
  ret
  nopl   (%rax)
L15:
  lea    0x20(%rsp),%rdi
  mov    $0x20,%esi
  call   <psZeromem@plt>
  lea    -0x20(%rbx),%rax
  cmp    $0x20,%rax
  jbe    L27
  lea    0x40(%rsp),%rdi
  mov    $0x20,%esi
  call   <psZeromem@plt>
  lea    -0x40(%rbx),%rax
  cmp    $0x20,%rax
  jbe    L27
  lea    -0x60(%rbx),%rdi
  call   <psBurnStack>
  jmp    L27
L22:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void psBurnStack(unsigned long len) {
  unsigned char buf[32];
  psZeromem(buf, sizeof(buf));
  if (len > (unsigned long)sizeof(buf)) {
    psBurnStack(len - sizeof(buf));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,-0x18(%rbp)
  test   %rbx,%rbx
  jne    L2
  lea    D13(%rip),%rbx
L2:
  cmpq   $0x0,-0x18(%rbp)
  jne    L20
  lea    D13(%rip),%rax
  mov    %rax,-0x18(%rbp)
L20:
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  mov    -0x18(%rbp),%rdi
  call   <strlen@plt>
  add    %r12d,%eax
  add    $0x1,%eax
  mov    %eax,%eax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    D23(%rip),%rax
  mov    %rax,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  mov    -0x18(%rbp),%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  je     L1
  mov    $0x0,%eax
  call   <cndfree@plt>
L1:
  mov    %r12,%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D13
type: string
name: unpack_data
arguments: tag: D23
type: string

tool: 

tool: D23: %s%s

assistant: ```c
char *add(this, that)
register char *this, *that;
{
  register char *r;
  if (!this)
    this = "";
  if (!that)
    that = "";
  r = malloc((unsigned)(strlen(this) + strlen(that) + 1));
  sprintf(r, "%s%s", that, this);
  if (*that)
    cndfree(that);
  return (r);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<add>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  lea    D1(%rip),%rax
  cmove  %rax,%rbx
  test   %rsi,%rsi
  je     L17
  mov    %rsi,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%r12,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rcx
  mov    %rbp,%rdx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  cmpb   $0x0,0x0(%rbp)
  jne    L39
L21:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L39:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <cndfree@plt>
  jmp    L21
L17:
  mov    %rbx,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    %rbx,%rcx
  lea    D1(%rip),%rdx
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <sprintf@plt>
  jmp    L21
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: string
name: parse_data
arguments: data_label: D10
datatype: string

tool: 

tool: D10: %s%s

assistant: ```c
char *add(this, that)
register char *this, *that;
{
  register char *r;
  if (!this)
    this = "";
  if (!that)
    that = "";
  r = malloc((unsigned)(strlen(this) + strlen(that) + 1));
  sprintf(r, "%s%s", that, this);
  if (*that)
    cndfree(that);
  return (r);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<add>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D27(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L21
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%r13d
L21:
  test   %rbp,%rbp
  je     L28
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%r13,%rax,1),%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D8(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <sprintf@plt>
  cmpb   $0x0,0x0(%rbp)
  jne    L25
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <cndfree@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L28:
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  lea    D27(%rip),%rdx
  lea    D8(%rip),%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: label: D27
datatype: string
name: disassemble_data
arguments: label: D8
datatype: string

tool: 

tool: D8: %s%s

assistant: ```c
char *add(this, that)
register char *this, *that;
{
  register char *r;
  if (!this)
    this = "";
  if (!that)
    that = "";
  r = malloc((unsigned)(strlen(this) + strlen(that) + 1));
  sprintf(r, "%s%s", that, this);
  if (*that)
    cndfree(that);
  return (r);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<add>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rsi,%rbp
  test   %rdi,%rdi
  je     L16
  mov    %rdi,%r12
  call   <strlen@plt>
  mov    %eax,%r13d
L16:
  test   %rbp,%rbp
  je     L5
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    0x1(%r13,%rax,1),%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  mov    %rbp,%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%rdi
  mov    %rax,%r13
  xor    %eax,%eax
  call   <sprintf@plt>
  cmpb   $0x0,0x0(%rbp)
  jne    L3
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  cs nopw 0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <cndfree@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L5:
  lea    0x1(%r13),%edi
  call   <malloc@plt>
  mov    %r12,%rcx
  lea    D8(%rip),%rdx
  lea    D19(%rip),%rsi
  mov    %rax,%r13
  mov    %rax,%rdi
  xor    %eax,%eax
  call   <sprintf@plt>
  mov    %r13,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string
name: disassemble_data
arguments: data_label: D19
data_type: string

tool: 

tool: D19: %s%s

assistant: ```c
char *add(this, that)
register char *this, *that;
{
  register char *r;
  if (!this)
    this = "";
  if (!that)
    that = "";
  r = malloc((unsigned)(strlen(this) + strlen(that) + 1));
  sprintf(r, "%s%s", that, this);
  if (*that)
    cndfree(that);
  return (r);
}
```