ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<load_personal_config>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rdi
  sub    $0x320,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x318(%rsp)
  xor    %eax,%eax
  call   <getenv@plt>
  mov    %rax,%rcx
  test   %rax,%rax
  je     L10
L0:
  lea    0x190(%rsp),%rbp
  lea    D15(%rip),%rdx
  mov    $0x180,%esi
  mov    %rbp,%rdi
  call   <snprintf@plt>
  mov    %rbp,%rdi
  call   <load_config_file@plt>
L1:
  mov    0x318(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x320,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  xor    %eax,%eax
  call   <getuid@plt>
  lea    0x10(%rsp),%rdx
  mov    %rsp,%rsi
  lea    0x8(%rsp),%r8
  mov    %eax,%edi
  mov    $0x180,%ecx
  call   <getpwuid_r@plt>
  test   %rax,%rax
  jne    L1
  mov    0x8(%rsp),%rax
  mov    (%rax),%rcx
  jmp    L0
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
data_type: string
name: retrieve_data
arguments: label: D15
data_type: string

tool: D8: HOME

tool: D15: %s/.unfit

assistant: ```c
void load_personal_config(void) {
  struct passwd passwd;
  struct passwd *pw;
  const char *p;
  char s[384];
  char cfg_file[384];
  p = getenv("HOME");
  if (p == NULL) {
    if (getpwuid_r(getuid(), &passwd, s, sizeof(s), &pw) != 0)
      return;
    p = pw->pw_dir;
  }
  snprintf(cfg_file, sizeof(cfg_file), "%s/.unfit", p);
  load_config_file(cfg_file);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x64(%rbp)
  lea    -0x68(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x64(%rbp)
  jmp    L45
L2:
  lea    -0x60(%rbp),%rdx
  mov    -0x64(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x64(%rbp)
L45:
  mov    -0x68(%rbp),%eax
  cmp    %eax,-0x64(%rbp)
  jl     L2
  mov    -0x68(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x68(%rbp)
  jmp    L11
L36:
  mov    -0x68(%rbp),%eax
  cltq
  mov    -0x60(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x68(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x68(%rbp)
L11:
  mov    -0x68(%rbp),%eax
  test   %eax,%eax
  jns    L36
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D23
data_type: string
name: unpack_data
arguments: data_label: D18
data_type: string

tool: D23: %d

tool: D18: %d


assistant: ```c
int main() {
  signed int zdr[20], i = 0, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &zdr[i]);
  n--;
  while (n >= 0) {
    printf("%d\n", zdr[n]);
    n--;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D6(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L16
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D6(%rip),%r12
L3:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%eax
  add    $0x4,%rbp
  cmp    %ebx,%eax
  jg     L3
L16:
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  js     L19
  lea    D15(%rip),%rbx
L28:
  cltq
  mov    0x10(%rsp,%rax,4),%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  jns    L28
L19:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
datatype: string
name: disassemble_data
arguments: tag: D15
datatype: string

tool: D6: %d

tool: D15: %d


assistant: ```c
int main() {
  signed int zdr[20], i = 0, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &zdr[i]);
  n--;
  while (n >= 0) {
    printf("%d\n", zdr[n]);
    n--;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L5
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L13:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L13
L5:
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  js     L21
  lea    D1(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L10:
  cltq
  mov    %rbx,%rdi
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  jns    L10
L21:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
type: string
name: extract_symbolic_data
arguments: label: D1
type: string

tool: D16: %d

tool: D1: %d


assistant: ```c
int main() {
  signed int zdr[20], i = 0, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &zdr[i]);
  n--;
  while (n >= 0) {
    printf("%d\n", zdr[n]);
    n--;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  test   %eax,%eax
  jle    L17
  lea    0x10(%rsp),%rbp
  xor    %ebx,%ebx
  nop
L25:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x1,%ebx
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  cmp    %ebx,%eax
  jg     L25
L17:
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  js     L36
  lea    D7(%rip),%rbx
  nopw   0x0(%rax,%rax,1)
L8:
  cltq
  mov    %rbx,%rdi
  mov    0x10(%rsp,%rax,4),%esi
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  mov    %eax,0xc(%rsp)
  jns    L8
L36:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D7
type: string

tool: D1: %d

tool: D7: %d


assistant: ```c
int main() {
  signed int zdr[20], i = 0, n;
  scanf("%d", &n);
  for (i = 0; i < n; i++)
    scanf("%d", &zdr[i]);
  n--;
  while (n >= 0) {
    printf("%d\n", zdr[n]);
    n--;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<tree_range_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_find@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L14
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_rank@plt>
  mov    %eax,%ebx
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_rank@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  add    $0x1,%eax
  jmp    L5
L14:
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_rank@plt>
  mov    %eax,%ebx
  mov    -0x48(%rbp),%rcx
  mov    -0x40(%rbp),%rdx
  mov    -0x30(%rbp),%rsi
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <tree_rank@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
L5:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int tree_range_size(struct tree *tree, void *lo, void *hi, int (*compare)(const void *a, const void *b, void *context), void *context) {
  struct tree *node;
  node = tree_find(tree, hi, compare, context);
  if (node != NULL) {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context) + 1;
  } else {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<tree_range_size>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    %rcx,%r12
  mov    %r8,%r13
  mov    %r8,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  call   <tree_find@plt>
  test   %rax,%rax
  je     L9
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <tree_rank@plt>
  mov    %eax,%ebx
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <tree_rank@plt>
  sub    %eax,%ebx
  lea    0x1(%rbx),%eax
L4:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L9:
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <tree_rank@plt>
  mov    %eax,%ebx
  mov    %r13,%rcx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <tree_rank@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %edx,%eax
  jmp    L4
```

assistant: ```c
int tree_range_size(struct tree *tree, void *lo, void *hi, int (*compare)(const void *a, const void *b, void *context), void *context) {
  struct tree *node;
  node = tree_find(tree, hi, compare, context);
  if (node != NULL) {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context) + 1;
  } else {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tree_range_size>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  mov    %r8,%rcx
  push   %r12
  mov    %r13,%rdx
  mov    %rsi,%r12
  mov    %r15,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <tree_find@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L3
  call   <tree_rank@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <tree_rank@plt>
  add    $0x8,%rsp
  sub    %eax,%ebx
  lea    0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L3:
  call   <tree_rank@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <tree_rank@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int tree_range_size(struct tree *tree, void *lo, void *hi, int (*compare)(const void *a, const void *b, void *context), void *context) {
  struct tree *node;
  node = tree_find(tree, hi, compare, context);
  if (node != NULL) {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context) + 1;
  } else {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tree_range_size>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %r8,%r14
  push   %r13
  mov    %rcx,%r13
  mov    %r8,%rcx
  push   %r12
  mov    %r13,%rdx
  mov    %rsi,%r12
  mov    %r15,%rsi
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <tree_find@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  test   %rax,%rax
  je     L1
  call   <tree_rank@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <tree_rank@plt>
  add    $0x8,%rsp
  sub    %eax,%ebx
  lea    0x1(%rbx),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L1:
  call   <tree_rank@plt>
  mov    %r14,%rcx
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <tree_rank@plt>
  add    $0x8,%rsp
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int tree_range_size(struct tree *tree, void *lo, void *hi, int (*compare)(const void *a, const void *b, void *context), void *context) {
  struct tree *node;
  node = tree_find(tree, hi, compare, context);
  if (node != NULL) {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context) + 1;
  } else {
    return tree_rank(tree, hi, compare, context) - tree_rank(tree, lo, compare, context);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rstrip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L13
L9:
  subl   $0x1,-0x4(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  je     L9
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void rstrip(char str[], const char del) {
  int index = strlen(str) - 1;
  while (str[index] == del)
    index--;
  str[index + 1] = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rstrip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%ebp
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    (%rbx,%rdx,1),%r12b
  jne    L12
  sub    $0x2,%eax
  cltq
L14:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmp    %bpl,0x1(%rbx,%rax,1)
  je     L14
L12:
  movb   $0x0,0x1(%rbx,%rdx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rstrip(char str[], const char del) {
  int index = strlen(str) - 1;
  while (str[index] == del)
    index--;
  str[index + 1] = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rstrip>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    (%rbx,%rdx,1),%r12b
  jne    L14
  sub    $0x2,%eax
  cltq
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmp    %bpl,0x1(%rbx,%rax,1)
  je     L7
L14:
  movb   $0x0,0x1(%rbx,%rdx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rstrip(char str[], const char del) {
  int index = strlen(str) - 1;
  while (str[index] == del)
    index--;
  str[index + 1] = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rstrip>:
  endbr64
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  cmp    (%rbx,%rdx,1),%r12b
  jne    L10
  sub    $0x2,%eax
  cltq
  cs nopw 0x0(%rax,%rax,1)
L16:
  mov    %rax,%rdx
  sub    $0x1,%rax
  cmp    %bpl,0x1(%rbx,%rax,1)
  je     L16
L10:
  movb   $0x0,0x1(%rbx,%rdx,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void rstrip(char str[], const char del) {
  int index = strlen(str) - 1;
  while (str[index] == del)
    index--;
  str[index + 1] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L4
L10:
  lea    D18(%rip),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L4:
  cmpl   $0x2,-0xc(%rbp)
  jle    L10
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string

tool: D18: hypotf

tool: D6: # c::%s


tool: D29: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "hypotf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D4(%rip),%r13
  lea    D16(%rip),%r12
  lea    D6(%rip),%rbp
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: label: D4
type: string
name: read_data
arguments: label: D16
type: string
name: read_data
arguments: label: D6
type: string

tool: D4: hypotf

tool: D16: # c::%s


tool: D6: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "hypotf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D20(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L9:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L9
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
datatype: string
name: read_data
arguments: data_tag: D8
datatype: string
name: read_data
arguments: data_tag: D4
datatype: string

tool: D20: hypotf

tool: D8: # c::%s


tool: D4: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "hypotf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D19(%rip),%r13
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  lea    D22(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L2:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D19
data_type: string
name: parse_data
arguments: label: D12
data_type: string
name: parse_data
arguments: label: D22
data_type: string

tool: D19: hypotf

tool: D12: # c::%s


tool: D22: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "hypotf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<getTIssue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movl   $0x1e,-0x14(%rbp)
  mov    $0x0,%eax
  call   <klock_getT2@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L2
L8:
  mov    $0x0,%eax
  call   <klock_getT2@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    (%rax),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L2:
  cmpl   $0x14,-0x14(%rbp)
  jg     L8
  mov    -0x14(%rbp),%eax
  leave
  ret
```

assistant: ```c
int getTIssue(int x) {
  int *a, *b;
  int c = 30;
  b = (int *)klock_getT2();
  while (c > 20) {
    a = (int *)klock_getT2();
    c = *a - *b;
    b = a;
  }
  return c;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getTIssue>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <klock_getT2@plt>
  mov    %rax,%rbx
L1:
  mov    $0x0,%eax
  call   <klock_getT2@plt>
  mov    %rbx,%rdx
  mov    %rax,%rbx
  mov    (%rax),%eax
  sub    (%rdx),%eax
  cmp    $0x14,%eax
  jg     L1
  pop    %rbx
  ret
```

assistant: ```c
int getTIssue(int x) {
  int *a, *b;
  int c = 30;
  b = (int *)klock_getT2();
  while (c > 20) {
    a = (int *)klock_getT2();
    c = *a - *b;
    b = a;
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getTIssue>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <klock_getT2@plt>
  mov    %rax,%rbx
  nop
L5:
  xor    %eax,%eax
  call   <klock_getT2@plt>
  mov    %rbx,%rdx
  mov    %rax,%rbx
  mov    (%rax),%eax
  sub    (%rdx),%eax
  cmp    $0x14,%eax
  jg     L5
  pop    %rbx
  ret
```

assistant: ```c
int getTIssue(int x) {
  int *a, *b;
  int c = 30;
  b = (int *)klock_getT2();
  while (c > 20) {
    a = (int *)klock_getT2();
    c = *a - *b;
    b = a;
  }
  return c;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getTIssue>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <klock_getT2@plt>
  mov    %rax,%rbx
  nop
L3:
  xor    %eax,%eax
  call   <klock_getT2@plt>
  mov    %rbx,%rdx
  mov    %rax,%rbx
  mov    (%rax),%eax
  sub    (%rdx),%eax
  cmp    $0x14,%eax
  jg     L3
  pop    %rbx
  ret
```

assistant: ```c
int getTIssue(int x) {
  int *a, *b;
  int c = 30;
  b = (int *)klock_getT2();
  while (c > 20) {
    a = (int *)klock_getT2();
    c = *a - *b;
    b = a;
  }
  return c;
}
```