ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<islandPerimeter>:
  endbr64
  test   %esi,%esi
  jle    L66
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %edx,%r13d
  mov    %esi,%r14d
  mov    $0x0,%edi
  mov    $0x0,%r8d
  mov    %edx,%r9d
  lea    -0x1(%rdx),%r12d
  lea    -0x1(%rsi),%ebp
  jmp    L62
L54:
  lea    0x3(%r8),%edx
  jmp    L156
L36:
  cmp    %ebx,%ebp
  jle    L0
  mov    0x8(%r11,%rdi,8),%r8
  cmpl   $0x1,(%r8,%rsi,1)
  sete   %sil
  movzbl %sil,%esi
  sub    %esi,%edx
L0:
  mov    %edx,%r8d
  test   %r10d,%r10d
  jle    L131
  cmpl   $0x1,-0x4(%rcx,%rax,4)
  je     L118
L131:
  add    $0x1,%rax
  cmp    %r9,%rax
  je     L84
L109:
  lea    0x0(,%rax,4),%rsi
  cmpl   $0x1,(%rcx,%rax,4)
  jne    L131
  lea    0x4(%r8),%edx
  test   %edi,%edi
  jle    L156
  mov    -0x8(%r11,%rdi,8),%r10
  cmpl   $0x1,(%r10,%rsi,1)
  je     L54
L156:
  mov    %eax,%r10d
  cmp    %eax,%r12d
  jle    L36
  cmpl   $0x1,0x4(%rcx,%rax,4)
  jne    L36
  sub    $0x1,%edx
  jmp    L36
L118:
  lea    -0x1(%rdx),%r8d
  jmp    L131
L84:
  add    $0x1,%rdi
  cmp    %r14,%rdi
  je     L39
L62:
  test   %r13d,%r13d
  jle    L84
  mov    (%r11,%rdi,8),%rcx
  mov    $0x0,%eax
  mov    %edi,%ebx
  jmp    L109
L66:
  mov    $0x0,%r8d
  mov    %r8d,%eax
  ret
L39:
  mov    %r8d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int islandPerimeter(int **grid, int gridRowSize, int gridColSize) {
  int sum = 0;
  int i, j;
  for (i = 0; i < gridRowSize; i++) {
    for (j = 0; j < gridColSize; j++) {
      if (grid[i][j] == 1) {
        sum += 4;
        if (i > 0 && (grid[i - 1][j] == 1)) {
          sum -= 1;
        }
        if ((j < gridColSize - 1) && (grid[i][j + 1] == 1)) {
          sum -= 1;
        }
        if ((i < gridRowSize - 1) && (grid[i + 1][j] == 1)) {
          sum -= 1;
        }
        if (j > 0 && (grid[i][j - 1]) == 1) {
          sum -= 1;
        }
      }
    }
  }
  return sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<islandPerimeter>:
  endbr64
  test   %esi,%esi
  jle    L63
  push   %r14
  mov    %rdi,%r10
  xor    %r8d,%r8d
  xor    %edi,%edi
  push   %r13
  movslq %edx,%r9
  movslq %esi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  lea    -0x1(%rdx),%ebp
  push   %rbx
  lea    -0x1(%rsi),%ebx
  nopl   0x0(%rax,%rax,1)
L34:
  test   %r12d,%r12d
  jle    L89
  mov    (%r10,%rdi,8),%rdx
  xor    %eax,%eax
  mov    %edi,%r11d
  jmp    L55
  nopl   0x0(%rax)
L65:
  add    $0x1,%rax
  cmp    %rax,%r9
  je     L89
L55:
  cmpl   $0x1,(%rdx,%rax,4)
  lea    0x0(,%rax,4),%rcx
  jne    L65
  lea    0x4(%r8),%esi
  test   %rdi,%rdi
  je     L102
  mov    -0x8(%r10,%rdi,8),%r14
  add    $0x3,%r8d
  cmpl   $0x1,(%r14,%rcx,1)
  je     L121
L102:
  mov    %esi,%r8d
L121:
  cmp    %eax,%ebp
  jle    L57
  cmpl   $0x1,0x4(%rdx,%rax,4)
  jne    L57
  sub    $0x1,%r8d
  nopw   0x0(%rax,%rax,1)
L57:
  cmp    %r11d,%ebx
  jle    L103
  mov    0x8(%r10,%rdi,8),%rsi
  cmpl   $0x1,(%rsi,%rcx,1)
  sete   %cl
  movzbl %cl,%ecx
  sub    %ecx,%r8d
L103:
  test   %rax,%rax
  je     L65
  cmpl   $0x1,-0x4(%rdx,%rax,4)
  jne    L65
  add    $0x1,%rax
  sub    $0x1,%r8d
  cmp    %rax,%r9
  jne    L55
L89:
  add    $0x1,%rdi
  cmp    %r13,%rdi
  jne    L34
  pop    %rbx
  mov    %r8d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L63:
  xor    %eax,%eax
  ret
```

assistant: ```c
int islandPerimeter(int **grid, int gridRowSize, int gridColSize) {
  int sum = 0;
  int i, j;
  for (i = 0; i < gridRowSize; i++) {
    for (j = 0; j < gridColSize; j++) {
      if (grid[i][j] == 1) {
        sum += 4;
        if (i > 0 && (grid[i - 1][j] == 1)) {
          sum -= 1;
        }
        if ((j < gridColSize - 1) && (grid[i][j + 1] == 1)) {
          sum -= 1;
        }
        if ((i < gridRowSize - 1) && (grid[i + 1][j] == 1)) {
          sum -= 1;
        }
        if (j > 0 && (grid[i][j - 1]) == 1) {
          sum -= 1;
        }
      }
    }
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<zwavecmd_configuration_bulk_set_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x114(%rbp)
  mov    %esi,-0x118(%rbp)
  mov    %rdx,-0x120(%rbp)
  mov    %ecx,-0x124(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x118(%rbp),%eax
  shr    $0x8,%eax
  mov    %al,-0x110(%rbp)
  mov    -0x118(%rbp),%eax
  mov    %al,-0x10f(%rbp)
  mov    -0x124(%rbp),%eax
  and    $0x3,%eax
  test   %eax,%eax
  jne    L11
  mov    -0x124(%rbp),%eax
  lea    0x3(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x2,%eax
  mov    %al,-0x10e(%rbp)
  movb   $0x4,-0x10d(%rbp)
  jmp    L22
L11:
  mov    -0x124(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L12
  mov    -0x124(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %al,-0x10e(%rbp)
  movb   $0x2,-0x10d(%rbp)
  jmp    L22
L12:
  mov    -0x124(%rbp),%eax
  mov    %al,-0x10e(%rbp)
  movb   $0x1,-0x10d(%rbp)
L22:
  lea    -0x110(%rbp),%rax
  add    $0x4,%rax
  mov    -0x124(%rbp),%edx
  mov    -0x120(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x124(%rbp),%eax
  lea    0x4(%rax),%ecx
  lea    -0x110(%rbp),%rdx
  mov    -0x114(%rbp),%eax
  mov    %ecx,%r8d
  mov    %rdx,%rcx
  mov    $0x7,%edx
  mov    $0x70,%esi
  mov    %eax,%edi
  call   <zwave_sendClassCommand@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L32
  call   <__stack_chk_fail@plt>
L32:
  leave
  ret
```

assistant: ```c
void zwavecmd_configuration_bulk_set_buf(unsigned int id, unsigned int offset, unsigned char *data, int len) {
  unsigned char buf[255];
  buf[0] = offset / 256;
  buf[1] = offset % 256;
  if ((len % 4) == 0) {
    buf[2] = len / 4;
    buf[3] = 4;
  } else if ((len % 2) == 0) {
    buf[2] = len / 2;
    buf[3] = 2;
  } else {
    buf[2] = len;
    buf[3] = 1;
  }
  memcpy(buf + 4, data, len);
  zwave_sendClassCommand(id, 0x70, 0x07, buf, len + 4);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<zwavecmd_configuration_bulk_set_buf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %edi,%ebp
  mov    %rdx,%rdi
  mov    %ecx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %esi,%ecx
  shr    $0x8,%ecx
  test   $0x3,%bl
  jne    L49
  lea    0x3(%rbx),%eax
  test   %ebx,%ebx
  cmovns %ebx,%eax
  sar    $0x2,%eax
  mov    $0x4,%edx
L26:
  mov    %cl,(%rsp)
  mov    %sil,0x1(%rsp)
  mov    %al,0x2(%rsp)
  mov    %dl,0x3(%rsp)
  mov    %rsp,%r12
  lea    0x4(%rsp),%rax
  mov    %ebx,%edx
  mov    %rdi,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    0x4(%rbx),%r8d
  mov    %r12,%rcx
  mov    $0x7,%edx
  mov    $0x70,%esi
  mov    %ebp,%edi
  call   <zwave_sendClassCommand@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L49:
  test   $0x1,%bl
  jne    L38
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    $0x2,%edx
  jmp    L26
L38:
  mov    %ebx,%eax
  mov    $0x1,%edx
  jmp    L26
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zwavecmd_configuration_bulk_set_buf(unsigned int id, unsigned int offset, unsigned char *data, int len) {
  unsigned char buf[255];
  buf[0] = offset / 256;
  buf[1] = offset % 256;
  if ((len % 4) == 0) {
    buf[2] = len / 4;
    buf[3] = 4;
  } else if ((len % 2) == 0) {
    buf[2] = len / 2;
    buf[3] = 2;
  } else {
    buf[2] = len;
    buf[3] = 1;
  }
  memcpy(buf + 4, data, len);
  zwave_sendClassCommand(id, 0x70, 0x07, buf, len + 4);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<zwavecmd_configuration_bulk_set_buf>:
  endbr64
  push   %r12
  mov    %rdx,%r8
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  and    $0x3,%ecx
  jne    L2
  test   %ebx,%ebx
  lea    0x3(%rbx),%eax
  mov    $0x4,%edx
  cmovns %ebx,%eax
  sar    $0x2,%eax
L42:
  rol    $0x8,%si
  mov    %dl,0x3(%rsp)
  lea    0x4(%rsp),%rdi
  mov    %ebx,%edx
  mov    %si,(%rsp)
  mov    %rsp,%r12
  mov    %r8,%rsi
  mov    %al,0x2(%rsp)
  call   <memcpy@plt>
  lea    0x4(%rbx),%r8d
  mov    %r12,%rcx
  mov    %ebp,%edi
  mov    $0x7,%edx
  mov    $0x70,%esi
  call   <zwave_sendClassCommand@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  test   $0x1,%bl
  jne    L25
  mov    %ebx,%eax
  mov    $0x2,%edx
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  jmp    L42
  nopl   (%rax)
L25:
  mov    %ebx,%eax
  mov    $0x1,%edx
  jmp    L42
L29:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zwavecmd_configuration_bulk_set_buf(unsigned int id, unsigned int offset, unsigned char *data, int len) {
  unsigned char buf[255];
  buf[0] = offset / 256;
  buf[1] = offset % 256;
  if ((len % 4) == 0) {
    buf[2] = len / 4;
    buf[3] = 4;
  } else if ((len % 2) == 0) {
    buf[2] = len / 2;
    buf[3] = 2;
  } else {
    buf[2] = len;
    buf[3] = 1;
  }
  memcpy(buf + 4, data, len);
  zwave_sendClassCommand(id, 0x70, 0x07, buf, len + 4);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<zwavecmd_configuration_bulk_set_buf>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  mov    %rdx,%rsi
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  mov    %edi,%eax
  and    $0x3,%ecx
  movzbl %ah,%eax
  mov    %eax,%r8d
  jne    L44
  test   %ebx,%ebx
  lea    0x3(%rbx),%eax
  mov    $0x4,%ecx
  cmovns %ebx,%eax
  sar    $0x2,%eax
  mov    %eax,%r9d
L8:
  xor    %edx,%edx
  mov    %edi,%eax
  shl    $0x18,%ecx
  lea    0x4(%rsp),%rdi
  mov    %r8b,%dl
  mov    %rsp,%r12
  mov    %al,%dh
  movzbl %r9b,%eax
  shl    $0x10,%eax
  movzwl %dx,%edx
  or     %eax,%edx
  or     %ecx,%edx
  mov    %edx,(%rsp)
  mov    %ebx,%edx
  call   <memcpy@plt>
  lea    0x4(%rbx),%r8d
  mov    %r12,%rcx
  mov    %ebp,%edi
  mov    $0x7,%edx
  mov    $0x70,%esi
  call   <zwave_sendClassCommand@plt>
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L44:
  test   $0x1,%bl
  jne    L25
  mov    %ebx,%eax
  mov    $0x2,%ecx
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  mov    %eax,%r9d
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L25:
  mov    %ebx,%r9d
  mov    $0x1,%ecx
  jmp    L8
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void zwavecmd_configuration_bulk_set_buf(unsigned int id, unsigned int offset, unsigned char *data, int len) {
  unsigned char buf[255];
  buf[0] = offset / 256;
  buf[1] = offset % 256;
  if ((len % 4) == 0) {
    buf[2] = len / 4;
    buf[3] = 4;
  } else if ((len % 2) == 0) {
    buf[2] = len / 2;
    buf[3] = 2;
  } else {
    buf[2] = len;
    buf[3] = 1;
  }
  memcpy(buf + 4, data, len);
  zwave_sendClassCommand(id, 0x70, 0x07, buf, len + 4);
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_valeurs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x30(%rbp)
  mov    %al,-0x2c(%rbp)
  mov    -0x30(%rbp),%eax
  mov    $0x8,%esi
  mov    %eax,%edi
  call   <sdb_calloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L107
L73:
  mov    $0x8,%esi
  mov    $0x64,%edi
  call   <sdb_calloc@plt>
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L104
L31:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L106
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  je     L106
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L106
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
  jmp    L104
L106:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L75
  addl   $0x1,-0xc(%rbp)
  jmp    L104
L75:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L115
  addl   $0x1,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L104
L115:
  movl   $0x0,-0x18(%rbp)
L104:
  cmpl   $0x1,-0x18(%rbp)
  je     L31
  addl   $0x1,-0x14(%rbp)
L107:
  mov    -0x14(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L73
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char **get_valeurs(char *buffer, char sep, int nbre) {
  int test;
  int i, jr, jb;
  char **result;
  result = (char **)sdb_calloc(nbre, sizeof(char *));
  jb = 0;
  for (i = 0; i < nbre; i++) {
    result[i] = (char *)sdb_calloc(100, sizeof(char *));
    jr = 0;
    test = 1;
    while (test == 1) {
      if (buffer[jb] != ' ' && buffer[jb] != sep && buffer[jb] != '\0') {
        result[i][jr] = buffer[jb];
        jb++;
        jr++;
      } else if (buffer[jb] == ' ') {
        jb++;
      } else if (buffer[jb] == sep) {
        jb++;
        test = 0;
      } else {
        test = 0;
      }
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<get_valeurs>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %edx,%r12d
  mov    %esi,%ebp
  mov    $0x8,%esi
  mov    %edx,%edi
  call   <sdb_calloc@plt>
  mov    %rax,%r14
  test   %r12d,%r12d
  jle    L45
  mov    %rax,%rbx
  mov    %r12d,%r12d
  lea    (%rax,%r12,8),%r12
  mov    $0x0,%r15d
  jmp    L58
L6:
  movslq %edi,%rsi
  mov    (%r9),%r8
  mov    %al,(%r8,%rsi,1)
  add    $0x1,%edi
L20:
  add    $0x1,%rcx
  add    $0x1,%edx
L40:
  lea    -0x1(%rdx),%esi
  movzbl (%rcx),%eax
  test   $0xdf,%al
  je     L69
  cmp    %bpl,%al
  jne    L6
L69:
  cmp    $0x20,%al
  je     L20
  cmp    %bpl,%al
  cmove  %edx,%esi
  mov    %esi,%r15d
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L45
L58:
  mov    $0x8,%esi
  mov    $0x64,%edi
  call   <sdb_calloc@plt>
  mov    %rbx,%r9
  mov    %rax,(%rbx)
  movslq %r15d,%rcx
  add    %r13,%rcx
  lea    0x1(%r15),%edx
  mov    $0x0,%edi
  jmp    L40
L45:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **get_valeurs(char *buffer, char sep, int nbre) {
  int test;
  int i, jr, jb;
  char **result;
  result = (char **)sdb_calloc(nbre, sizeof(char *));
  jb = 0;
  for (i = 0; i < nbre; i++) {
    result[i] = (char *)sdb_calloc(100, sizeof(char *));
    jr = 0;
    test = 1;
    while (test == 1) {
      if (buffer[jb] != ' ' && buffer[jb] != sep && buffer[jb] != '\0') {
        result[i][jr] = buffer[jb];
        jb++;
        jr++;
      } else if (buffer[jb] == ' ') {
        jb++;
      } else if (buffer[jb] == sep) {
        jb++;
        test = 0;
      } else {
        test = 0;
      }
    }
  }
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_valeurs>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  mov    $0x8,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <sdb_calloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L44
  lea    (%rax,%rbx,8),%r15
  mov    %rax,%r13
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L57:
  mov    $0x8,%esi
  mov    $0x64,%edi
  call   <sdb_calloc@plt>
  movslq %ebx,%rcx
  lea    0x1(%rbx),%edx
  xor    %edi,%edi
  add    %rbp,%rcx
  mov    %rax,0x0(%r13)
  lea    -0x1(%rdx),%esi
  movzbl (%rcx),%eax
  cmp    $0x20,%al
  je     L9
  cmp    %r14b,%al
  je     L55
L2:
  test   %al,%al
  je     L55
  mov    0x0(%r13),%r8
  movslq %edi,%rsi
  add    $0x1,%edi
  mov    %al,(%r8,%rsi,1)
L9:
  movzbl 0x1(%rcx),%eax
  add    $0x1,%edx
  add    $0x1,%rcx
  lea    -0x1(%rdx),%esi
  cmp    $0x20,%al
  je     L9
  cmp    %r14b,%al
  jne    L2
L55:
  cmp    %r14b,%al
  mov    %esi,%ebx
  cmove  %edx,%ebx
  add    $0x8,%r13
  cmp    %r15,%r13
  jne    L57
L44:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **get_valeurs(char *buffer, char sep, int nbre) {
  int test;
  int i, jr, jb;
  char **result;
  result = (char **)sdb_calloc(nbre, sizeof(char *));
  jb = 0;
  for (i = 0; i < nbre; i++) {
    result[i] = (char *)sdb_calloc(100, sizeof(char *));
    jr = 0;
    test = 1;
    while (test == 1) {
      if (buffer[jb] != ' ' && buffer[jb] != sep && buffer[jb] != '\0') {
        result[i][jr] = buffer[jb];
        jb++;
        jr++;
      } else if (buffer[jb] == ' ') {
        jb++;
      } else if (buffer[jb] == sep) {
        jb++;
        test = 0;
      } else {
        test = 0;
      }
    }
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_valeurs>:
  endbr64
  push   %r15
  push   %r14
  mov    %esi,%r14d
  mov    $0x8,%esi
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %edx,%ebx
  mov    %ebx,%edi
  sub    $0x8,%rsp
  call   <sdb_calloc@plt>
  mov    %rax,%r12
  test   %ebx,%ebx
  jle    L49
  lea    (%rax,%rbx,8),%r15
  mov    %rax,%r13
  xor    %ebx,%ebx
  cs nopw 0x0(%rax,%rax,1)
L53:
  mov    $0x8,%esi
  mov    $0x64,%edi
  call   <sdb_calloc@plt>
  movslq %ebx,%rcx
  lea    0x1(%rbx),%edx
  xor    %edi,%edi
  add    %rbp,%rcx
  mov    %rax,0x0(%r13)
  lea    -0x1(%rdx),%esi
  movzbl (%rcx),%eax
  cmp    $0x20,%al
  je     L56
  cmp    %r14b,%al
  je     L22
L25:
  test   %al,%al
  je     L22
  mov    0x0(%r13),%r8
  movslq %edi,%rsi
  add    $0x1,%edi
  mov    %al,(%r8,%rsi,1)
L56:
  movzbl 0x1(%rcx),%eax
  add    $0x1,%edx
  add    $0x1,%rcx
  lea    -0x1(%rdx),%esi
  cmp    $0x20,%al
  je     L56
  cmp    %r14b,%al
  jne    L25
L22:
  cmp    %r14b,%al
  mov    %esi,%ebx
  cmove  %edx,%ebx
  add    $0x8,%r13
  cmp    %r13,%r15
  jne    L53
L49:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **get_valeurs(char *buffer, char sep, int nbre) {
  int test;
  int i, jr, jb;
  char **result;
  result = (char **)sdb_calloc(nbre, sizeof(char *));
  jb = 0;
  for (i = 0; i < nbre; i++) {
    result[i] = (char *)sdb_calloc(100, sizeof(char *));
    jr = 0;
    test = 1;
    while (test == 1) {
      if (buffer[jb] != ' ' && buffer[jb] != sep && buffer[jb] != '\0') {
        result[i][jr] = buffer[jb];
        jb++;
        jr++;
      } else if (buffer[jb] == ' ') {
        jb++;
      } else if (buffer[jb] == sep) {
        jb++;
        test = 0;
      } else {
        test = 0;
      }
    }
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<imprimirMatriz>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L45
L0:
  movl   $0x0,-0x4(%rbp)
  jmp    L29
L8:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x9,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  cmp    $0x63,%eax
  jle    L12
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x9,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L69
L12:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x9,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  cltq
  mov    (%rdx,%rax,4),%eax
  mov    %eax,%esi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L69:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L28
  mov    $0x20,%edi
  call   <putchar@plt>
L28:
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L45:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L0
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D13
type_infered: string
name: parse_data
arguments: tag: D5
type_infered: string

tool: D13: %d

tool: D5: % 3d

assistant: ```c
void imprimirMatriz(int matriz[][128], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (matriz[i][j] >= 100) {
        printf("%d", matriz[i][j]);
      } else {
        printf("% 3d", matriz[i][j]);
      }
      if (j < n - 1) {
        printf(" ");
      }
    }
    printf("\n");
  }
  printf("\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<imprimirMatriz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x4(%rsp)
  test   %esi,%esi
  jle    L41
  mov    %rdi,%r15
  lea    -0x1(%rsi),%eax
  shl    $0x9,%rax
  lea    0x200(%rdi,%rax,1),%rax
  mov    %rax,0x8(%rsp)
  lea    D18(%rip),%r14
  lea    -0x1(%rsi),%r13d
  jmp    L21
L29:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  cmp    %ebx,%r13d
  jg     L14
L44:
  add    $0x1,%rbx
  cmp    %rbx,%rbp
  je     L25
L38:
  mov    (%r12,%rbx,4),%esi
  cmp    $0x63,%esi
  jle    L29
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L15
L14:
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L44
L25:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x200,%r15
  cmp    0x8(%rsp),%r15
  je     L41
L21:
  mov    %r15,%r12
  mov    0x4(%rsp),%ebp
  mov    $0x0,%ebx
  jmp    L38
L41:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D0
type_guessed: string

tool: D18: % 3d

tool: D0: %d

assistant: ```c
void imprimirMatriz(int matriz[][128], int n) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      if (matriz[i][j] >= 100) {
        printf("%d", matriz[i][j]);
      } else {
        printf("% 3d", matriz[i][j]);
      }
      if (j < n - 1) {
        printf(" ");
      }
    }
    printf("\n");
  }
  printf("\n");
}
```