ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<sprintf>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  mov    %r13d,%edi
  push   %rbp
  mov    %rsi,%rbp
  call   <va_start@plt>
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <vsprintf@plt>
  mov    %r13d,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int sprintf(char *buf, const char *fmt, ...) {
  va_list args;
  int i;
  va_start(args, fmt);
  i = vsprintf(buf, fmt, args);
  va_end(args);
  return i;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<sanitize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L87
L55:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    $0x5c,%eax
  jg     L9
  cmp    $0x22,%eax
  jl     L45
  sub    $0x22,%eax
  cmp    $0x3a,%eax
  ja     L45
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D2(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D2(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L9:
  cmp    $0x7c,%eax
  je     L98
  jmp    L45
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5b,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5d,(%rax)
  jmp    L95
L98:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x5f,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x3b,(%rax)
  jmp    L95
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2d,(%rax)
  jmp    L95
L45:
  nop
L95:
  addl   $0x1,-0x4(%rbp)
L87:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jl     L55
  nop
  nop
  leave
  ret
```

assistant: ```c
void sanitize(char *string) {
  int i;
  for (i = 0; i < strlen(string); i++) {
    switch (string[i]) {
    case '<':
      string[i] = '[';
      break;
    case '>':
      string[i] = ']';
      break;
    case '|':
      string[i] = '_';
      break;
    case '/':
      string[i] = '-';
      break;
    case '\\':
      string[i] = '-';
      break;
    case '*':
      string[i] = '_';
      break;
    case '?':
      string[i] = '_';
      break;
    case ':':
      string[i] = ';';
      break;
    case '"':
      string[i] = '-';
      break;
    default:
      break;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sanitize>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    %rdi,%rbx
  lea    D5(%rip),%r12
  jmp    L38
L41:
  cmp    $0x7c,%al
  jne    L10
  movb   $0x5f,(%rbx)
  jmp    L10
  movb   $0x5b,(%rbx)
L10:
  add    $0x1,%rbx
L38:
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %ebx,%eax
  sub    %ebp,%eax
  cmp    %eax,%edx
  jle    L69
  movzbl (%rbx),%eax
  cmp    $0x5c,%al
  jg     L41
  cmp    $0x21,%al
  jle    L10
  sub    $0x22,%eax
  cmp    $0x3a,%al
  ja     L10
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  movb   $0x5d,(%rbx)
  jmp    L10
  movb   $0x2d,(%rbx)
  jmp    L10
  movb   $0x2d,(%rbx)
  jmp    L10
  movb   $0x5f,(%rbx)
  jmp    L10
  movb   $0x5f,(%rbx)
  jmp    L10
  movb   $0x3b,(%rbx)
  jmp    L10
  movb   $0x2d,(%rbx)
  jmp    L10
L69:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sanitize(char *string) {
  int i;
  for (i = 0; i < strlen(string); i++) {
    switch (string[i]) {
    case '<':
      string[i] = '[';
      break;
    case '>':
      string[i] = ']';
      break;
    case '|':
      string[i] = '_';
      break;
    case '/':
      string[i] = '-';
      break;
    case '\\':
      string[i] = '-';
      break;
    case '*':
      string[i] = '_';
      break;
    case '?':
      string[i] = '_';
      break;
    case ':':
      string[i] = ';';
      break;
    case '"':
      string[i] = '-';
      break;
    default:
      break;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sanitize>:
  endbr64
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L76
L98:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x5c,%al
  jg     L3
  cmp    $0x21,%al
  jle    L26
  sub    $0x22,%eax
  cmp    $0x3a,%al
  ja     L26
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L3:
  cmp    $0x7c,%al
  je     L87
L26:
  add    $0x1,%rbx
L101:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L98
L76:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
  movb   $0x2d,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L101
  nopl   0x0(%rax,%rax,1)
L87:
  movb   $0x5f,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L101
  nopl   0x0(%rax,%rax,1)
  movb   $0x5d,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L101
  nopl   0x0(%rax,%rax,1)
  movb   $0x5b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L101
  nopl   0x0(%rax,%rax,1)
  movb   $0x3b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L101
```

assistant: ```c
void sanitize(char *string) {
  int i;
  for (i = 0; i < strlen(string); i++) {
    switch (string[i]) {
    case '<':
      string[i] = '[';
      break;
    case '>':
      string[i] = ']';
      break;
    case '|':
      string[i] = '_';
      break;
    case '/':
      string[i] = '-';
      break;
    case '\\':
      string[i] = '-';
      break;
    case '*':
      string[i] = '_';
      break;
    case '?':
      string[i] = '_';
      break;
    case ':':
      string[i] = ';';
      break;
    case '"':
      string[i] = '-';
      break;
    default:
      break;
    }
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sanitize>:
  endbr64
  push   %r12
  lea    D6(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L47
L44:
  movzbl 0x0(%rbp,%rbx,1),%eax
  cmp    $0x5c,%al
  jg     L28
  cmp    $0x21,%al
  jle    L109
  sub    $0x22,%eax
  cmp    $0x3a,%al
  ja     L109
  movzbl %al,%eax
  movslq (%r12,%rax,4),%rax
  add    %r12,%rax
  notrack jmp *%rax
  nopl   0x0(%rax)
L28:
  cmp    $0x7c,%al
  je     L96
L109:
  add    $0x1,%rbx
L74:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L44
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
  movb   $0x2d,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
L96:
  movb   $0x5f,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
  movb   $0x5d,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
  movb   $0x5b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L74
  nopl   0x0(%rax,%rax,1)
  movb   $0x3b,0x0(%rbp,%rbx,1)
  add    $0x1,%rbx
  jmp    L74
```

assistant: ```c
void sanitize(char *string) {
  int i;
  for (i = 0; i < strlen(string); i++) {
    switch (string[i]) {
    case '<':
      string[i] = '[';
      break;
    case '>':
      string[i] = ']';
      break;
    case '|':
      string[i] = '_';
      break;
    case '/':
      string[i] = '-';
      break;
    case '\\':
      string[i] = '-';
      break;
    case '*':
      string[i] = '_';
      break;
    case '?':
      string[i] = '_';
      break;
    case ':':
      string[i] = ';';
      break;
    case '"':
      string[i] = '-';
      break;
    default:
      break;
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  lea    D1(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D5(%rip),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string
name: disassemble_data
arguments: data_tag: D5
datatype: string
name: disassemble_data
arguments: data_tag: D27
datatype: string

tool: D1: kammo DJ

tool: D5: roomies!!

tool: D27: 
%s

assistant: ```c
main() {
  char *a = "kammo DJ";
  const char *b = "roomies!!";
  char *c;
  a = (char *)malloc(strlen(a) + strlen(b));
  c = (char *)malloc(strlen(a) + strlen(b));
  c = strcat(a, b);
  printf("\n%s", a);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x11,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <strlen@plt>
  lea    0x9(%rax),%rdi
  call   <malloc@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    %rbx,%rax
  movabs $0x217365696d6f6f72,%rdx
  mov    %rdx,(%rax)
  movw   $0x21,0x8(%rax)
  mov    %rbx,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: label: D5
data_type: string

tool: D5: 
%s

assistant: ```c
main() {
  char *a = "kammo DJ";
  const char *b = "roomies!!";
  char *c;
  a = (char *)malloc(strlen(a) + strlen(b));
  c = (char *)malloc(strlen(a) + strlen(b));
  c = strcat(a, b);
  printf("\n%s", a);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x11,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x9(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D4(%rip),%rdi
  movabs $0x217365696d6f6f72,%rdx
  add    %rbp,%rax
  mov    %rdx,(%rax)
  mov    $0x21,%edx
  mov    %dx,0x8(%rax)
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string

tool: D4: 
%s

assistant: ```c
main() {
  char *a = "kammo DJ";
  const char *b = "roomies!!";
  char *c;
  a = (char *)malloc(strlen(a) + strlen(b));
  c = (char *)malloc(strlen(a) + strlen(b));
  c = strcat(a, b);
  printf("\n%s", a);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x11,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  lea    0x9(%rax),%rdi
  call   <malloc@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %rbp,%rsi
  lea    D2(%rip),%rdi
  movabs $0x217365696d6f6f72,%rdx
  add    %rbp,%rax
  mov    %rdx,(%rax)
  mov    $0x21,%edx
  mov    %dx,0x8(%rax)
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D2
data_type: string

tool: D2: 
%s

assistant: ```c
main() {
  char *a = "kammo DJ";
  const char *b = "roomies!!";
  char *c;
  a = (char *)malloc(strlen(a) + strlen(b));
  c = (char *)malloc(strlen(a) + strlen(b));
  c = strcat(a, b);
  printf("\n%s", a);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<mem_put_le16_as_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x1c(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mem_put_le16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 0) & 0xff);
  mem[1] = (unsigned char)((val >> 8) & 0xff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_put_le16_as_int>:
  endbr64
  mov    %esi,%eax
  mov    %sil,(%rdi)
  movzbl %ah,%eax
  mov    %al,0x1(%rdi)
  ret
```

assistant: ```c
void mem_put_le16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 0) & 0xff);
  mem[1] = (unsigned char)((val >> 8) & 0xff);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mem_put_le16_as_int>:
  endbr64
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void mem_put_le16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 0) & 0xff);
  mem[1] = (unsigned char)((val >> 8) & 0xff);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mem_put_le16_as_int>:
  endbr64
  mov    %si,(%rdi)
  ret
```

assistant: ```c
void mem_put_le16_as_int(void *vmem, int val) {
  unsigned char *mem = (unsigned char *)vmem;
  mem[0] = (unsigned char)((val >> 0) & 0xff);
  mem[1] = (unsigned char)((val >> 8) & 0xff);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <debug_puts@plt>
  mov    $0x4,%edi
  call   <sim_exit@plt>
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <debug_puts@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
data_type: string
name: read_data
arguments: data_label: D17
data_type: string

tool: D4: 
This program tests the simulator magic exit port.
There should be no more messages after this one.


tool: D17: ERROR - Simulation did not exit?


assistant: ```c
int main() {
  debug_puts("\n"
             "This program tests the simulator magic exit port.\n"
             "There should be no more messages after this one.\n");
  sim_exit(4);
  debug_puts("ERROR - Simulation did not exit?\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <debug_puts@plt>
  mov    $0x4,%edi
  call   <sim_exit@plt>
  lea    D11(%rip),%rdi
  call   <debug_puts@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string
name: extract_symbolic_data
arguments: data_label: D11
data_type: string

tool: D1: 
This program tests the simulator magic exit port.
There should be no more messages after this one.


tool: D11: ERROR - Simulation did not exit?


assistant: ```c
int main() {
  debug_puts("\n"
             "This program tests the simulator magic exit port.\n"
             "There should be no more messages after this one.\n");
  sim_exit(4);
  debug_puts("ERROR - Simulation did not exit?\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <debug_puts@plt>
  mov    $0x4,%edi
  call   <sim_exit@plt>
  lea    D17(%rip),%rdi
  call   <debug_puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type_guessed: string
name: read_data
arguments: data_label: D17
type_guessed: string

tool: D8: 
This program tests the simulator magic exit port.
There should be no more messages after this one.


tool: D17: ERROR - Simulation did not exit?


assistant: ```c
int main() {
  debug_puts("\n"
             "This program tests the simulator magic exit port.\n"
             "There should be no more messages after this one.\n");
  sim_exit(4);
  debug_puts("ERROR - Simulation did not exit?\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <debug_puts@plt>
  mov    $0x4,%edi
  call   <sim_exit@plt>
  lea    D14(%rip),%rdi
  call   <debug_puts@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
type_guessed: string
name: retrieve_data
arguments: tag: D14
type_guessed: string

tool: D3: 
This program tests the simulator magic exit port.
There should be no more messages after this one.


tool: D14: ERROR - Simulation did not exit?


assistant: ```c
int main() {
  debug_puts("\n"
             "This program tests the simulator magic exit port.\n"
             "There should be no more messages after this one.\n");
  sim_exit(4);
  debug_puts("ERROR - Simulation did not exit?\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<deps_calc_target>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <base_name@plt>
  cltq
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x8,%rax
  lea    0x8(%rax),%rdx
  mov    $0x10,%eax
  sub    $0x1,%rax
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L55:
  cmp    %rdx,%rsp
  je     L38
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L55
L38:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L2
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L2:
  mov    %rsp,%rax
  add    $0xf,%rax
  shr    $0x4,%rax
  shl    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x2e,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L13
  mov    -0x10(%rbp),%rax
  movw   $0x6f2e,(%rax)
  movb   $0x0,0x2(%rax)
  jmp    L43
L13:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movw   $0x6f2e,(%rax)
  movb   $0x0,0x2(%rax)
L43:
  mov    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <deps_add_target@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void deps_calc_target(d, t) struct deps *d;
const char *t;
{
  char *o, *suffix;
  t = base_name(t);
  o = (char *)alloca(strlen(t) + 8);
  strcpy(o, t);
  suffix = strrchr(o, '.');
  if (suffix)
    strcpy(suffix, ".o");
  else
    strcat(o, ".o");
  deps_add_target(d, o);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<deps_calc_target>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rdi
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <base_name@plt>
  movslq %eax,%rbx
  mov    %rbx,%rdi
  call   <strlen@plt>
  add    $0x1f,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L41:
  cmp    %rdx,%rsp
  je     L9
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L41
L9:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L16
  orq    $0x0,-0x8(%rsp,%rax,1)
L16:
  lea    0xf(%rsp),%r13
  and    $0xfffffffffffffff0,%r13
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    $0x2e,%esi
  mov    %r13,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L24
  movw   $0x6f2e,(%rax)
  movb   $0x0,0x2(%rax)
L33:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <deps_add_target@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L24:
  mov    %r13,%rdi
  call   <strlen@plt>
  add    %r13,%rax
  movw   $0x6f2e,(%rax)
  movb   $0x0,0x2(%rax)
  jmp    L33
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void deps_calc_target(d, t) struct deps *d;
const char *t;
{
  char *o, *suffix;
  t = base_name(t);
  o = (char *)alloca(strlen(t) + 8);
  strcpy(o, t);
  suffix = strrchr(o, '.');
  if (suffix)
    strcpy(suffix, ".o");
  else
    strcat(o, ".o");
  deps_add_target(d, o);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<deps_calc_target>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    %rsi,%rdi
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  call   <base_name@plt>
  movslq %eax,%r12
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rsp,%rcx
  mov    %rax,%rbx
  lea    0x1f(%rax),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L17
L58:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L58
L17:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L32
L19:
  lea    0xf(%rsp),%r14
  mov    %r12,%rsi
  lea    0x1(%rbx),%rdx
  and    $0xfffffffffffffff0,%r14
  mov    %r14,%rdi
  call   <memcpy@plt>
  mov    $0x2e,%esi
  mov    %r14,%rdi
  call   <strrchr@plt>
  test   %rax,%rax
  je     L62
  mov    $0x6f2e,%edx
  movb   $0x0,0x2(%rax)
  mov    %dx,(%rax)
L38:
  xor    %eax,%eax
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <deps_add_target@plt>
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  lea    -0x20(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
  nopl   0x0(%rax)
L62:
  add    %r14,%rbx
  mov    $0x6f2e,%eax
  mov    %ax,(%rbx)
  movb   $0x0,0x2(%rbx)
  jmp    L38
  nopl   0x0(%rax)
L32:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L19
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void deps_calc_target(d, t) struct deps *d;
const char *t;
{
  char *o, *suffix;
  t = base_name(t);
  o = (char *)alloca(strlen(t) + 8);
  strcpy(o, t);
  suffix = strrchr(o, '.');
  if (suffix)
    strcpy(suffix, ".o");
  else
    strcat(o, ".o");
  deps_add_target(d, o);
}
```