user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x7a1000(%rsp),%r11
L66:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L66
  sub    $0x230,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x7a1224(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x7a121c(%rbp)
  jmp    L76
L35:
  lea    -0x7a1220(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x7a1218(%rbp)
  jmp    L21
L114:
  lea    -0x7a1210(%rbp),%rdx
  mov    -0x7a1218(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    $0x4,%rax
  add    %rax,%rdx
  lea    -0x7a1210(%rbp),%rcx
  mov    -0x7a1218(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rcx,%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x7a1218(%rbp)
L21:
  mov    -0x7a1220(%rbp),%eax
  cmp    %eax,-0x7a1218(%rbp)
  jl     L114
  mov    -0x7a1220(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x7a1218(%rbp)
  jmp    L65
L2:
  mov    -0x7a1218(%rbp),%eax
  cltq
  mov    -0x7a1210(%rbp,%rax,8),%edx
  mov    -0x7a1218(%rbp),%eax
  cltq
  mov    -0x7a120c(%rbp,%rax,8),%eax
  add    %edx,%eax
  mov    %eax,-0x7a1214(%rbp)
  cmpl   $0x9,-0x7a1214(%rbp)
  jle    L120
  mov    -0x7a1214(%rbp),%eax
  lea    -0xa(%rax),%edx
  mov    -0x7a1218(%rbp),%eax
  cltq
  mov    %edx,-0x7a1210(%rbp,%rax,8)
  mov    -0x7a1218(%rbp),%eax
  sub    $0x1,%eax
  movslq %eax,%rdx
  mov    -0x7a1210(%rbp,%rdx,8),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0x7a1210(%rbp,%rax,8)
  jmp    L87
L120:
  mov    -0x7a1218(%rbp),%eax
  cltq
  mov    -0x7a1214(%rbp),%edx
  mov    %edx,-0x7a1210(%rbp,%rax,8)
L87:
  subl   $0x1,-0x7a1218(%rbp)
L65:
  cmpl   $0x0,-0x7a1218(%rbp)
  jns    L2
  movl   $0x0,-0x7a1218(%rbp)
  jmp    L98
L123:
  mov    -0x7a1218(%rbp),%eax
  cltq
  mov    -0x7a1210(%rbp,%rax,8),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x7a1218(%rbp)
L98:
  mov    -0x7a1220(%rbp),%eax
  cmp    %eax,-0x7a1218(%rbp)
  jl     L123
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x7a1224(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x7a121c(%rbp)
  jge    L17
  mov    $0xa,%edi
  call   <putchar@plt>
L17:
  addl   $0x1,-0x7a121c(%rbp)
L76:
  mov    -0x7a1224(%rbp),%eax
  cmp    %eax,-0x7a121c(%rbp)
  jl     L35
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D14: %d

tool: D10: %d %d

assistant: ```c
int main() {
  int i, j, n, m, sum, a[1000000][2];
  scanf("%d", &n);
  for (i = 0; i < n; i++) {
    scanf("%d", &m);
    for (j = 0; j < m; j++)
      scanf("%d %d", &a[j][0], &a[j][1]);
    for (j = m - 1; j >= 0; j--) {
      sum = a[j][0] + a[j][1];
      if (sum >= 10) {
        a[j][0] = sum - 10;
        a[j - 1][0]++;
      } else
        a[j][0] = sum;
    }
    for (j = 0; j < m; j++)
      printf("%d", a[j][0]);
    printf("\n");
    if (i < n - 1)
      printf("\n");
  }
  return 0;
}
```