ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<scan_hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %rsi,%rsi
  je     L79
  cmp    $0x3b,%al
  je     L98
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  lea    0x4(%rsp),%r14
  mov    %rsp,%r15
  lea    D16(%rip),%r13
  jmp    L14
  nopl   0x0(%rax,%rax,1)
L82:
  mov    0x4(%rsp),%eax
  mov    %rbx,%rdi
  add    $0x1,%r12d
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movslq (%rsp),%rax
  add    %rax,(%rbx)
  xor    %eax,%eax
  call   <eat_whitespace@plt>
  mov    (%rbx),%rdi
  cmpb   $0x3b,(%rdi)
  je     L88
L14:
  xor    %eax,%eax
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  movl   $0x0,(%rsp)
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L82
L88:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L79:
  xor    %r12d,%r12d
  mov    %rsp,%r15
  lea    0x4(%rsp),%r14
  lea    D16(%rip),%r13
  cmp    $0x3b,%al
  jne    L12
  jmp    L88
  nopl   0x0(%rax,%rax,1)
L108:
  movslq (%rsp),%rax
  add    %rax,(%rbx)
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <eat_whitespace@plt>
  mov    (%rbx),%rdi
  cmpb   $0x3b,(%rdi)
  je     L88
L12:
  xor    %eax,%eax
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  movl   $0x0,(%rsp)
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L108
  jmp    L88
L98:
  xor    %r12d,%r12d
  jmp    L88
L76:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D16
type_guessed: string

tool: D16: %x%n

assistant: ```c
int scan_hex(const char **s, char *intarray) {
  int n, c;
  unsigned int i;
  c = 0;
  if (intarray) {
    while (**s != ';') {
      n = 0;
      if (!sscanf(*s, "%x%n", &i, &n))
        break;
      intarray[c] = i;
      *s += n;
      c++;
      eat_whitespace(s);
    }
  } else {
    while (**s != ';') {
      n = 0;
      if (!sscanf(*s, "%x%n", &i, &n))
        break;
      *s += n;
      c++;
      eat_whitespace(s);
    }
  }
  return c;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scan_hex>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    (%rdi),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movzbl (%rdi),%eax
  test   %rsi,%rsi
  je     L80
  cmp    $0x3b,%al
  je     L10
  mov    %rsi,%rbp
  xor    %r12d,%r12d
  lea    0x4(%rsp),%r14
  mov    %rsp,%r15
  lea    D6(%rip),%r13
  jmp    L54
  nopl   0x0(%rax,%rax,1)
L64:
  mov    0x4(%rsp),%eax
  mov    %rbx,%rdi
  add    $0x1,%r12d
  add    $0x1,%rbp
  mov    %al,-0x1(%rbp)
  movslq (%rsp),%rax
  add    %rax,(%rbx)
  xor    %eax,%eax
  call   <eat_whitespace@plt>
  mov    (%rbx),%rdi
  cmpb   $0x3b,(%rdi)
  je     L67
L54:
  xor    %eax,%eax
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  movl   $0x0,(%rsp)
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L64
L67:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L80:
  xor    %r12d,%r12d
  mov    %rsp,%r15
  lea    0x4(%rsp),%r14
  lea    D6(%rip),%r13
  cmp    $0x3b,%al
  jne    L83
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L36:
  movslq (%rsp),%rax
  add    %rax,(%rbx)
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x1,%r12d
  call   <eat_whitespace@plt>
  mov    (%rbx),%rdi
  cmpb   $0x3b,(%rdi)
  je     L67
L83:
  xor    %eax,%eax
  mov    %r15,%rcx
  mov    %r14,%rdx
  mov    %r13,%rsi
  movl   $0x0,(%rsp)
  call   <sscanf@plt>
  test   %eax,%eax
  jne    L36
  jmp    L67
L10:
  xor    %r12d,%r12d
  jmp    L67
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
data_type: string

tool: D6: %x%n

assistant: ```c
int scan_hex(const char **s, char *intarray) {
  int n, c;
  unsigned int i;
  c = 0;
  if (intarray) {
    while (**s != ';') {
      n = 0;
      if (!sscanf(*s, "%x%n", &i, &n))
        break;
      intarray[c] = i;
      *s += n;
      c++;
      eat_whitespace(s);
    }
  } else {
    while (**s != ';') {
      n = 0;
      if (!sscanf(*s, "%x%n", &i, &n))
        break;
      *s += n;
      c++;
      eat_whitespace(s);
    }
  }
  return c;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x1c(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L7:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
void *memdup(const void *s, int n) {
  void *d = malloc(n);
  if (d)
    memcpy(d, s, n);
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memdup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L2
  mov    %ebp,%edx
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *memdup(const void *s, int n) {
  void *d = malloc(n);
  if (d)
    memcpy(d, s, n);
  return d;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L4:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(const void *s, int n) {
  void *d = malloc(n);
  if (d)
    memcpy(d, s, n);
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memdup>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L8
  mov    %r13d,%edx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
L8:
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *memdup(const void *s, int n) {
  void *d = malloc(n);
  if (d)
    memcpy(d, s, n);
  return d;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<init_mat2D_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movss  %xmm0,-0x24(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L28:
  movl   $0x0,-0x4(%rbp)
  jmp    L39
L27:
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  shl    $0x2,%rax
  add    %rdx,%rax
  movss  -0x24(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L39:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L27
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x1c(%rbp),%eax
  cmp    %eax,-0x8(%rbp)
  jb     L28
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void init_mat2D_float(float **mat2D_float, int x, int y, float val) {
  unsigned int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      mat2D_float[i][j] = val;
}
```
user: What is the c source code of the assembly code below?

```asm
<init_mat2D_float>:
  endbr64
  test   %esi,%esi
  je     L37
  mov    %rdi,%r8
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rdi
  lea    -0x1(%rdx),%eax
  lea    0x4(,%rax,4),%rsi
  jmp    L48
L12:
  mov    (%r8),%rcx
  movss  %xmm0,(%rcx,%rax,1)
  add    $0x4,%rax
  cmp    %rsi,%rax
  jne    L12
L45:
  add    $0x8,%r8
  cmp    %rdi,%r8
  je     L37
L48:
  mov    $0x0,%eax
  test   %edx,%edx
  jne    L12
  jmp    L45
L37:
  ret
```

assistant: ```c
void init_mat2D_float(float **mat2D_float, int x, int y, float val) {
  unsigned int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      mat2D_float[i][j] = val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<init_mat2D_float>:
  endbr64
  test   %esi,%esi
  je     L12
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rsi
  lea    -0x1(%rdx),%eax
  lea    0x4(,%rax,4),%r8
  nopl   0x0(%rax,%rax,1)
L5:
  test   %edx,%edx
  je     L14
  mov    (%rdi),%rax
  lea    (%r8,%rax,1),%rcx
  nopl   0x0(%rax,%rax,1)
L11:
  movss  %xmm0,(%rax)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L11
L14:
  add    $0x8,%rdi
  cmp    %rsi,%rdi
  jne    L5
L12:
  ret
```

assistant: ```c
void init_mat2D_float(float **mat2D_float, int x, int y, float val) {
  unsigned int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      mat2D_float[i][j] = val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_mat2D_float>:
  endbr64
  mov    %edx,%r8d
  test   %esi,%esi
  je     L23
  test   %edx,%edx
  je     L23
  lea    -0x1(%rsi),%eax
  movaps %xmm0,%xmm1
  lea    -0x1(%rdx),%r10d
  mov    %edx,%esi
  lea    0x8(%rdi,%rax,8),%r11
  mov    %edx,%eax
  and    $0xfffffffc,%esi
  shufps $0x0,%xmm1,%xmm1
  shr    $0x2,%eax
  lea    -0x1(%rax),%r9d
  add    $0x1,%r9
  shl    $0x4,%r9
  nopl   0x0(%rax)
L8:
  mov    (%rdi),%rcx
  mov    %rcx,%rax
  lea    (%r9,%rcx,1),%rdx
  cmp    $0x2,%r10d
  jbe    L43
L5:
  movups %xmm1,(%rax)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L5
  mov    %esi,%eax
  cmp    %esi,%r8d
  je     L32
L86:
  mov    %eax,%edx
  movss  %xmm0,(%rcx,%rdx,4)
  lea    0x1(%rax),%edx
  cmp    %edx,%r8d
  jbe    L32
  add    $0x2,%eax
  movss  %xmm0,(%rcx,%rdx,4)
  cmp    %eax,%r8d
  jbe    L32
  movss  %xmm0,(%rcx,%rax,4)
L32:
  add    $0x8,%rdi
  cmp    %r11,%rdi
  jne    L8
L23:
  ret
L43:
  xor    %eax,%eax
  jmp    L86
```

assistant: ```c
void init_mat2D_float(float **mat2D_float, int x, int y, float val) {
  unsigned int i, j;
  for (i = 0; i < x; ++i)
    for (j = 0; j < y; ++j)
      mat2D_float[i][j] = val;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<do_server_initialization>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %rdx,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <htonl@plt>
  mov    %al,-0x21(%rbp)
  mov    -0x38(%rbp),%eax
  mov    $0xc,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <do_write@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0xc,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <do_read@plt>
  test   %rax,%rax
  je     L2
  mov    $0x1,%eax
  jmp    L25
L2:
  lea    -0x21(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <do_write@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <do_read@plt>
  test   %rax,%rax
  je     L9
  mov    $0x1,%eax
  jmp    L25
L9:
  lea    -0x20(%rbp),%rax
  mov    $0x18,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  mov    -0x40(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <encode_FramebufferFormat@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x38(%rbp),%eax
  mov    $0x18,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  mov    $0x0,%eax
  call   <do_write@plt>
  mov    $0x0,%eax
L25:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_guessed: string

tool: D1: RFB 003.003


assistant: ```c
int do_server_initialization(int clientr, int clientw, struct FramebufferFormat *fbf) {
  unsigned char packet[24];
  uint32_t noauth = htonl(1);
  do_write(clientw, "RFB 003.003\n", 12);
  if (do_read(clientr, packet, 12))
    return 1;
  do_write(clientw, &noauth, 4);
  if (do_read(clientr, packet, 1))
    return 1;
  bzero(packet, 24);
  encode_FramebufferFormat(packet, fbf);
  do_write(clientw, packet, 24);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<do_server_initialization>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x1,%edi
  call   <htonl@plt>
  mov    %al,0xf(%rsp)
  mov    $0xc,%edx
  lea    D1(%rip),%rsi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <do_write@plt>
  lea    0x10(%rsp),%rsi
  mov    $0xc,%edx
  mov    %ebp,%edi
  call   <do_read@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  je     L38
L20:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L38:
  lea    0xf(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <do_write@plt>
  lea    0x10(%rsp),%rsi
  mov    $0x1,%edx
  mov    %ebp,%edi
  call   <do_read@plt>
  mov    %rax,%rdx
  mov    $0x1,%eax
  test   %rdx,%rdx
  jne    L20
  lea    0x10(%rsp),%rbp
  mov    $0x18,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <encode_FramebufferFormat@plt>
  mov    $0x18,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  mov    $0x0,%eax
  call   <do_write@plt>
  mov    $0x0,%eax
  jmp    L20
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_infered: string

tool: D1: RFB 003.003


assistant: ```c
int do_server_initialization(int clientr, int clientw, struct FramebufferFormat *fbf) {
  unsigned char packet[24];
  uint32_t noauth = htonl(1);
  do_write(clientw, "RFB 003.003\n", 12);
  if (do_read(clientr, packet, 12))
    return 1;
  do_write(clientw, &noauth, 4);
  if (do_read(clientr, packet, 1))
    return 1;
  bzero(packet, 24);
  encode_FramebufferFormat(packet, fbf);
  do_write(clientw, packet, 24);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<do_server_initialization>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  mov    $0x1,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <htonl@plt>
  mov    $0xc,%edx
  lea    D6(%rip),%rsi
  mov    %ebp,%edi
  mov    %al,0xf(%rsp)
  xor    %eax,%eax
  call   <do_write@plt>
  mov    $0xc,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <do_read@plt>
  test   %rax,%rax
  je     L6
L11:
  mov    $0x1,%eax
L27:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L6:
  lea    0xf(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <do_write@plt>
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <do_read@plt>
  test   %rax,%rax
  jne    L11
  mov    $0x18,%esi
  mov    %r14,%rdi
  call   <bzero@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <encode_FramebufferFormat@plt>
  mov    $0x18,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <do_write@plt>
  xor    %eax,%eax
  jmp    L27
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D6
type_infered: string

tool: D6: RFB 003.003


assistant: ```c
int do_server_initialization(int clientr, int clientw, struct FramebufferFormat *fbf) {
  unsigned char packet[24];
  uint32_t noauth = htonl(1);
  do_write(clientw, "RFB 003.003\n", 12);
  if (do_read(clientr, packet, 12))
    return 1;
  do_write(clientw, &noauth, 4);
  if (do_read(clientr, packet, 1))
    return 1;
  bzero(packet, 24);
  encode_FramebufferFormat(packet, fbf);
  do_write(clientw, packet, 24);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<do_server_initialization>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %edi,%r12d
  mov    $0x1,%edi
  push   %rbp
  mov    %esi,%ebp
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r14
  call   <htonl@plt>
  mov    $0xc,%edx
  lea    D6(%rip),%rsi
  mov    %ebp,%edi
  mov    %al,0xf(%rsp)
  xor    %eax,%eax
  call   <do_write@plt>
  mov    $0xc,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <do_read@plt>
  test   %rax,%rax
  je     L11
L19:
  mov    $0x1,%eax
L32:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L36
  add    $0x38,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L11:
  lea    0xf(%rsp),%rsi
  mov    $0x4,%edx
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <do_write@plt>
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r12d,%edi
  call   <do_read@plt>
  test   %rax,%rax
  jne    L19
  mov    $0x18,%esi
  mov    %r14,%rdi
  call   <bzero@plt>
  mov    %r13,%rsi
  mov    %r14,%rdi
  call   <encode_FramebufferFormat@plt>
  mov    $0x18,%edx
  mov    %r14,%rsi
  mov    %ebp,%edi
  xor    %eax,%eax
  call   <do_write@plt>
  xor    %eax,%eax
  jmp    L32
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: RFB 003.003


assistant: ```c
int do_server_initialization(int clientr, int clientw, struct FramebufferFormat *fbf) {
  unsigned char packet[24];
  uint32_t noauth = htonl(1);
  do_write(clientw, "RFB 003.003\n", 12);
  if (do_read(clientr, packet, 12))
    return 1;
  do_write(clientw, &noauth, 4);
  if (do_read(clientr, packet, 1))
    return 1;
  bzero(packet, 24);
  encode_FramebufferFormat(packet, fbf);
  do_write(clientw, packet, 24);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_atoi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %rdi,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x30(%rbp)
  movl   $0xa,-0x2c(%rbp)
  movl   $0x64,-0x28(%rbp)
  movl   $0x3e8,-0x24(%rbp)
  movl   $0x2710,-0x20(%rbp)
  movl   $0x186a0,-0x1c(%rbp)
  movl   $0xf4240,-0x18(%rbp)
  movl   $0x989680,-0x14(%rbp)
  movl   $0x5f5e100,-0x10(%rbp)
  movl   $0x3b9aca00,-0xc(%rbp)
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L19
L56:
  addl   $0x1,-0x38(%rbp)
L19:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L56
  mov    -0x38(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  mov    -0x58(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L64
  addl   $0x1,-0x40(%rbp)
  subl   $0x1,-0x3c(%rbp)
  jmp    L64
L97:
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  sub    $0x30,%eax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x34(%rbp)
  js     L23
  cmpl   $0x9,-0x34(%rbp)
  jle    L87
L23:
  mov    -0x3c(%rbp),%eax
  add    $0x1,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%ecx
  mov    -0x44(%rbp),%eax
  cltd
  idiv   %ecx
  mov    %eax,-0x44(%rbp)
  jmp    L9
L87:
  mov    -0x3c(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  imul   -0x34(%rbp),%eax
  add    %eax,-0x44(%rbp)
  addl   $0x1,-0x40(%rbp)
  subl   $0x1,-0x3c(%rbp)
L64:
  mov    -0x40(%rbp),%eax
  cmp    -0x38(%rbp),%eax
  jl     L97
L9:
  mov    -0x58(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L44
  negl   -0x44(%rbp)
L44:
  mov    -0x44(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L77
  call   <__stack_chk_fail@plt>
L77:
  leave
  ret
```

assistant: ```c
int ft_atoi(const char *str) {
  int pos[10] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  int result = 0;
  int i = 0;
  int n = 0;
  int size = 0;
  int num = 0;
  while (str[size])
    size++;
  n = size - 1;
  if (str[0] == '-') {
    i++;
    n--;
  }
  while (i < size) {
    num = str[i] - 48;
    if (num < 0 || num > 9) {
      result = result / pos[n + 1];
      break;
    }
    result += num * pos[n];
    i++;
    n--;
  }
  if (str[0] == '-')
    result = result * -1;
  return (result);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_atoi>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0xa,0x4(%rsp)
  movl   $0x64,0x8(%rsp)
  movl   $0x3e8,0xc(%rsp)
  movl   $0x2710,0x10(%rsp)
  movl   $0x186a0,0x14(%rsp)
  movl   $0xf4240,0x18(%rsp)
  movl   $0x989680,0x1c(%rsp)
  movl   $0x5f5e100,0x20(%rsp)
  movl   $0x3b9aca00,0x24(%rsp)
  movzbl (%rdi),%r10d
  test   %r10b,%r10b
  je     L104
  lea    0x1(%rdi),%rax
  mov    $0x0,%r8d
L136:
  mov    %r8d,%ecx
  add    $0x1,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L136
  cmp    $0x2d,%r10b
  je     L80
  test   %r8d,%r8d
  jle    L3
  mov    $0x0,%esi
L78:
  movslq %esi,%rsi
  movslq %ecx,%rcx
  mov    $0x0,%eax
  mov    %rsp,%r11
L111:
  mov    %ecx,%r9d
  movsbl (%rdi,%rsi,1),%edx
  sub    $0x30,%edx
  cmp    $0x9,%edx
  ja     L89
  imul   (%r11,%rcx,4),%edx
  add    %edx,%eax
  add    $0x1,%rsi
  sub    $0x1,%rcx
  cmp    %esi,%r8d
  jg     L111
  jmp    L37
L80:
  sub    $0x1,%ecx
  cmp    $0x1,%r8d
  jle    L129
  mov    $0x1,%esi
  jmp    L78
L89:
  add    $0x1,%r9d
  movslq %r9d,%r9
  cltd
  idivl  (%rsp,%r9,4)
L37:
  cmp    $0x2d,%r10b
  je     L139
L95:
  mov    0x28(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L52
  add    $0x38,%rsp
  ret
L129:
  mov    $0x0,%eax
L139:
  neg    %eax
  jmp    L95
L104:
  mov    $0x0,%eax
  jmp    L95
L3:
  mov    $0x0,%eax
  jmp    L95
L52:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ft_atoi(const char *str) {
  int pos[10] = {1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000};
  int result = 0;
  int i = 0;
  int n = 0;
  int size = 0;
  int num = 0;
  while (str[size])
    size++;
  n = size - 1;
  if (str[0] == '-') {
    i++;
    n--;
  }
  while (i < size) {
    num = str[i] - 48;
    if (num < 0 || num > 9) {
      result = result / pos[n + 1];
      break;
    }
    result += num * pos[n];
    i++;
    n--;
  }
  if (str[0] == '-')
    result = result * -1;
  return (result);
}
```