ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<isProduct>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L6
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L59
L28:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  imul   %edx,%eax
  cmp    %eax,-0x20(%rbp)
  jne    L39
  mov    $0x1,%eax
  jmp    L53
L39:
  addl   $0x1,-0x4(%rbp)
L59:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L28
  addl   $0x1,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  mov    $0x0,%eax
L53:
  pop    %rbp
  ret
```

assistant: ```c
int isProduct(int arr[], int n, int x) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (x == arr[i] * arr[j]) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<isProduct>:
  endbr64
  test   %esi,%esi
  jle    L32
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r8
  mov    %rdi,%r9
L6:
  mov    (%r9),%esi
  mov    %rdi,%rax
L24:
  mov    %esi,%ecx
  imul   (%rax),%ecx
  cmp    %edx,%ecx
  je     L37
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L24
  add    $0x4,%r9
  cmp    %r8,%r9
  jne    L6
  mov    $0x0,%eax
  ret
L32:
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int isProduct(int arr[], int n, int x) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (x == arr[i] * arr[j]) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isProduct>:
  endbr64
  test   %esi,%esi
  jle    L42
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r9
  lea    0x4(%rdi,%rax,4),%r8
L20:
  mov    (%r9),%esi
  mov    %rdi,%rax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L9
L12:
  mov    (%rax),%ecx
  imul   %esi,%ecx
  cmp    %edx,%ecx
  jne    L2
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x4,%r9
  cmp    %rax,%r9
  jne    L20
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isProduct(int arr[], int n, int x) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (x == arr[i] * arr[j]) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<isProduct>:
  endbr64
  test   %esi,%esi
  jle    L49
  lea    -0x1(%rsi),%eax
  mov    %rdi,%r9
  lea    0x4(%rdi,%rax,4),%r8
L44:
  mov    (%r9),%esi
  mov    %rdi,%rax
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L11:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L45
L8:
  mov    (%rax),%ecx
  imul   %esi,%ecx
  cmp    %edx,%ecx
  jne    L11
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x4,%r9
  cmp    %rax,%r9
  jne    L44
L49:
  xor    %eax,%eax
  ret
```

assistant: ```c
int isProduct(int arr[], int n, int x) {
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < n; j++) {
      if (x == arr[i] * arr[j]) {
        return 1;
      }
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<invert_rotation_only44d44d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x20(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x10(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x40(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x20(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x8(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x28(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x28(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x30(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x48(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x40(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x10(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x48(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x30(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x50(%rax),%rdx
  mov    -0x8(%rbp),%rax
  movsd  0x50(%rax),%xmm0
  movsd  %xmm0,(%rdx)
  mov    -0x10(%rbp),%rax
  add    $0x18,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x38,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x58,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x60,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x68,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x70,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x78,%rax
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: f64

tool: D1: 1

assistant: ```c
void invert_rotation_only44d44d(double *orig, double *inv) {
  inv[0] = orig[0];
  inv[1] = orig[4];
  inv[2] = orig[8];
  inv[4] = orig[1];
  inv[5] = orig[5];
  inv[6] = orig[9];
  inv[8] = orig[2];
  inv[9] = orig[6];
  inv[10] = orig[10];
  inv[3] = 0.0;
  inv[7] = 0.0;
  inv[11] = 0.0;
  inv[12] = 0.0;
  inv[13] = 0.0;
  inv[14] = 0.0;
  inv[15] = 1.0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<invert_rotation_only44d44d>:
  endbr64
  movsd  (%rdi),%xmm0
  movsd  %xmm0,(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x48(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x48(%rsi)
  movsd  0x50(%rdi),%xmm0
  movsd  %xmm0,0x50(%rsi)
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x38(%rsi)
  movq   $0x0,0x58(%rsi)
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  mov    D3(%rip),%rax
  mov    %rax,0x78(%rsi)
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D3
data_type: f64

tool: D3: 1

assistant: ```c
void invert_rotation_only44d44d(double *orig, double *inv) {
  inv[0] = orig[0];
  inv[1] = orig[4];
  inv[2] = orig[8];
  inv[4] = orig[1];
  inv[5] = orig[5];
  inv[6] = orig[9];
  inv[8] = orig[2];
  inv[9] = orig[6];
  inv[10] = orig[10];
  inv[3] = 0.0;
  inv[7] = 0.0;
  inv[11] = 0.0;
  inv[12] = 0.0;
  inv[13] = 0.0;
  inv[14] = 0.0;
  inv[15] = 1.0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<invert_rotation_only44d44d>:
  endbr64
  movsd  (%rdi),%xmm0
  mov    D1(%rip),%rax
  movsd  %xmm0,(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x48(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x48(%rsi)
  movsd  0x50(%rdi),%xmm0
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x38(%rsi)
  movq   $0x0,0x58(%rsi)
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  mov    %rax,0x78(%rsi)
  movsd  %xmm0,0x50(%rsi)
  ret
```

tool_calls: name: parse_data
arguments: label: D1
type: f64

tool: D1: 1

assistant: ```c
void invert_rotation_only44d44d(double *orig, double *inv) {
  inv[0] = orig[0];
  inv[1] = orig[4];
  inv[2] = orig[8];
  inv[4] = orig[1];
  inv[5] = orig[5];
  inv[6] = orig[9];
  inv[8] = orig[2];
  inv[9] = orig[6];
  inv[10] = orig[10];
  inv[3] = 0.0;
  inv[7] = 0.0;
  inv[11] = 0.0;
  inv[12] = 0.0;
  inv[13] = 0.0;
  inv[14] = 0.0;
  inv[15] = 1.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<invert_rotation_only44d44d>:
  endbr64
  movsd  (%rdi),%xmm0
  mov    D5(%rip),%rax
  movsd  %xmm0,(%rsi)
  movsd  0x20(%rdi),%xmm0
  movsd  %xmm0,0x8(%rsi)
  movsd  0x40(%rdi),%xmm0
  movsd  %xmm0,0x10(%rsi)
  movsd  0x8(%rdi),%xmm0
  movsd  %xmm0,0x20(%rsi)
  movsd  0x28(%rdi),%xmm0
  movsd  %xmm0,0x28(%rsi)
  movsd  0x48(%rdi),%xmm0
  movsd  %xmm0,0x30(%rsi)
  movsd  0x10(%rdi),%xmm0
  movsd  %xmm0,0x40(%rsi)
  movsd  0x30(%rdi),%xmm0
  movsd  %xmm0,0x48(%rsi)
  movsd  0x50(%rdi),%xmm0
  movq   $0x0,0x18(%rsi)
  movq   $0x0,0x38(%rsi)
  movq   $0x0,0x58(%rsi)
  movq   $0x0,0x60(%rsi)
  movq   $0x0,0x68(%rsi)
  movq   $0x0,0x70(%rsi)
  mov    %rax,0x78(%rsi)
  movsd  %xmm0,0x50(%rsi)
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D5
type_guessed: f64

tool: D5: 1

assistant: ```c
void invert_rotation_only44d44d(double *orig, double *inv) {
  inv[0] = orig[0];
  inv[1] = orig[4];
  inv[2] = orig[8];
  inv[4] = orig[1];
  inv[5] = orig[5];
  inv[6] = orig[9];
  inv[8] = orig[2];
  inv[9] = orig[6];
  inv[10] = orig[10];
  inv[3] = 0.0;
  inv[7] = 0.0;
  inv[11] = 0.0;
  inv[12] = 0.0;
  inv[13] = 0.0;
  inv[14] = 0.0;
  inv[15] = 1.0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x18(%rbp)
  lea    -0x28(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    -0x30(%rbp),%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L37
L30:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addq   $0x1,-0x20(%rbp)
L37:
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x20(%rbp)
  jl     L30
  mov    -0x30(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <mergeSort@plt>
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x20(%rbp)
  jmp    L47
L89:
  cmpq   $0x0,-0x20(%rbp)
  je     L48
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rdx
  shl    $0x3,%rdx
  lea    -0x8(%rdx),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rdx),%rcx
  sub    %rcx,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  cmp    %rax,%rdx
  jg     L70
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x20(%rbp)
  jmp    L76
L48:
  nop
  jmp    L76
L70:
  nop
L76:
  subq   $0x1,-0x20(%rbp)
L47:
  cmpq   $0x0,-0x20(%rbp)
  jns    L89
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D23
datatype: string
name: retrieve_data
arguments: label: D25
datatype: string
name: retrieve_data
arguments: label: D17
datatype: string

tool: D23: %lld%lld

tool: D25: %lld

tool: D17: %lld


assistant: ```c
int main() {
  long long int n, k, i, *a, count = 0;
  scanf("%lld%lld", &n, &k);
  a = (long long int *)malloc(n * sizeof(long long int));
  for (i = 0; i < n; ++i)
    scanf("%lld", &a[i]);
  mergeSort(a, 0, n - 1);
  for (i = n - 1; i >= 0; --i) {
    if (i == 0)
      continue;
    else if ((a[i] - a[i - 1]) > k)
      continue;
    else {
      count += 1;
      i -= 1;
    }
  }
  printf("%lld\n", count);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D20(%rip),%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x0(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x8(%rsp),%rdx
  test   %rdx,%rdx
  jle    L20
  mov    %rax,%rbp
  mov    $0x0,%ebx
  lea    D22(%rip),%r13
L40:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%rbx
  mov    0x8(%rsp),%rdx
  add    $0x8,%rbp
  cmp    %rbx,%rdx
  jg     L40
L20:
  sub    $0x1,%rdx
  mov    $0x0,%esi
  mov    %r12,%rdi
  call   <mergeSort@plt>
  mov    0x8(%rsp),%rax
  sub    $0x1,%rax
  js     L59
  mov    0x10(%rsp),%rcx
  mov    $0x0,%esi
  jmp    L84
L86:
  sub    $0x1,%rax
  js     L14
L84:
  test   %rax,%rax
  je     L14
  mov    (%r12,%rax,8),%rdx
  sub    -0x8(%r12,%rax,8),%rdx
  cmp    %rcx,%rdx
  jg     L86
  add    $0x1,%rsi
  sub    $0x1,%rax
  jmp    L86
L59:
  mov    $0x0,%esi
L14:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D20
data_type: string
name: parse_data
arguments: data_tag: D22
data_type: string
name: parse_data
arguments: data_tag: D21
data_type: string

tool: D20: %lld%lld

tool: D22: %lld

tool: D21: %lld


assistant: ```c
int main() {
  long long int n, k, i, *a, count = 0;
  scanf("%lld%lld", &n, &k);
  a = (long long int *)malloc(n * sizeof(long long int));
  for (i = 0; i < n; ++i)
    scanf("%lld", &a[i]);
  mergeSort(a, 0, n - 1);
  for (i = n - 1; i >= 0; --i) {
    if (i == 0)
      continue;
    else if ((a[i] - a[i - 1]) > k)
      continue;
    else {
      count += 1;
      i -= 1;
    }
  }
  printf("%lld\n", count);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r13
  lea    D22(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x0(,%rax,8),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdx
  mov    %rax,%r12
  test   %rdx,%rdx
  jle    L42
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D25(%rip),%r13
  nop
L4:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0x8(%rsp),%rdx
  add    $0x8,%rbp
  cmp    %rbx,%rdx
  jg     L4
L42:
  sub    $0x1,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <mergeSort@plt>
  mov    0x8(%rsp),%rax
  sub    $0x1,%rax
  js     L76
  mov    0x10(%rsp),%rcx
  xor    %esi,%esi
  jmp    L32
  nopl   0x0(%rax)
L23:
  mov    (%r12,%rax,8),%rdx
  sub    -0x8(%r12,%rax,8),%rdx
  cmp    %rcx,%rdx
  jg     L5
  sub    $0x1,%rax
  add    $0x1,%rsi
L5:
  sub    $0x1,%rax
  jb     L0
L32:
  test   %rax,%rax
  jne    L23
L0:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L49
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L76:
  xor    %esi,%esi
  jmp    L0
L49:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D22
datatype: string
name: retrieve_data
arguments: tag: D25
datatype: string
name: retrieve_data
arguments: tag: D8
datatype: string

tool: D22: %lld%lld

tool: D25: %lld

tool: D8: %lld


assistant: ```c
int main() {
  long long int n, k, i, *a, count = 0;
  scanf("%lld%lld", &n, &k);
  a = (long long int *)malloc(n * sizeof(long long int));
  for (i = 0; i < n; ++i)
    scanf("%lld", &a[i]);
  mergeSort(a, 0, n - 1);
  for (i = n - 1; i >= 0; --i) {
    if (i == 0)
      continue;
    else if ((a[i] - a[i - 1]) > k)
      continue;
    else {
      count += 1;
      i -= 1;
    }
  }
  printf("%lld\n", count);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  lea    D25(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rax
  lea    0x0(,%rax,8),%rdi
  call   <malloc@plt>
  mov    0x8(%rsp),%rdx
  mov    %rax,%r12
  test   %rdx,%rdx
  jle    L17
  mov    %rax,%rbp
  xor    %ebx,%ebx
  lea    D22(%rip),%r13
  nop
L32:
  mov    %rbp,%rsi
  mov    %r13,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <scanf@plt>
  mov    0x8(%rsp),%rdx
  add    $0x8,%rbp
  cmp    %rbx,%rdx
  jg     L32
L17:
  sub    $0x1,%rdx
  xor    %esi,%esi
  mov    %r12,%rdi
  call   <mergeSort@plt>
  mov    0x8(%rsp),%rax
  sub    $0x1,%rax
  js     L77
  mov    0x10(%rsp),%rcx
  xor    %esi,%esi
  nop
L64:
  test   %rax,%rax
  je     L82
  mov    (%r12,%rax,8),%rdx
  sub    -0x8(%r12,%rax,8),%rdx
  cmp    %rcx,%rdx
  jg     L20
  sub    $0x2,%rax
  add    $0x1,%rsi
  cmp    $0xffffffffffffffff,%rax
  jne    L64
  nopl   0x0(%rax)
L82:
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L20:
  sub    $0x1,%rax
  jmp    L64
L77:
  xor    %esi,%esi
  jmp    L82
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D25
type_guessed: string
name: retrieve_data
arguments: tag: D22
type_guessed: string
name: retrieve_data
arguments: tag: D2
type_guessed: string

tool: D25: %lld%lld

tool: D22: %lld

tool: D2: %lld


assistant: ```c
int main() {
  long long int n, k, i, *a, count = 0;
  scanf("%lld%lld", &n, &k);
  a = (long long int *)malloc(n * sizeof(long long int));
  for (i = 0; i < n; ++i)
    scanf("%lld", &a[i]);
  mergeSort(a, 0, n - 1);
  for (i = n - 1; i >= 0; --i) {
    if (i == 0)
      continue;
    else if ((a[i] - a[i - 1]) > k)
      continue;
    else {
      count += 1;
      i -= 1;
    }
  }
  printf("%lld\n", count);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<increase>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <worker@plt>
  nop
  leave
  ret
```

assistant: ```c
void increase(long long int index, long long int change, long long int A[]) {
  A[index] += change;
  worker(A, index);
}
```
user: Translate the below assembly code into C programming language:

```asm
<increase>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rax
  mov    %rdx,%rdi
  add    %rsi,(%rdx,%rax,8)
  mov    %rax,%rsi
  call   <worker@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void increase(long long int index, long long int change, long long int A[]) {
  A[index] += change;
  worker(A, index);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<increase>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  add    %rsi,(%rdx,%r8,8)
  mov    %r8,%rsi
  jmp    1050 <worker@plt>
```

assistant: ```c
void increase(long long int index, long long int change, long long int A[]) {
  A[index] += change;
  worker(A, index);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<increase>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rdi
  add    %rsi,(%rdx,%r8,8)
  mov    %r8,%rsi
  jmp    1050 <worker@plt>
```

assistant: ```c
void increase(long long int index, long long int change, long long int A[]) {
  A[index] += change;
  worker(A, index);
}
```
user: Translate the below assembly code into C programming language:

```asm
<_cp_single_p>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x40(%rbp),%rax
  mov    0xc(%rax),%edx
  mov    -0x40(%rbp),%rax
  mov    0x10(%rax),%ecx
  mov    -0x38(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <lchown@plt>
  test   %rax,%rax
  je     L55
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <_cp_error@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    D17(%rip),%rax
  mov    (%rax),%ecx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  or     %ecx,%eax
  not    %eax
  and    %eax,%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lchmod@plt>
  test   %rax,%rax
  je     L26
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <_cp_error@plt>
  jmp    L26
L55:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <lchmod@plt>
  test   %rax,%rax
  je     L26
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <_cp_error@plt>
L26:
  mov    -0x40(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x28(%rbp)
  movq   $0x0,-0x30(%rbp)
  mov    -0x40(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  lea    -0x30(%rbp),%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <lutimes@plt>
  test   %rax,%rax
  je     L6
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <_cp_error@plt>
L6:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

assistant: ```c
int _cp_single_p(char const *dst, struct stat *st) {
  struct timeval tv[2];
  if (lchown(dst, st->st_uid, st->st_gid) != 0) {
    _cp_error(dst, 0);
    if (lchmod(dst, st->st_mode & ~(S_ISUID | S_ISGID)) != 0)
      _cp_error(dst, 0);
  } else if (lchmod(dst, st->st_mode) != 0)
    _cp_error(dst, 0);
  tv[0].tv_sec = st->st_atime;
  tv[0].tv_usec = 0;
  tv[1].tv_sec = st->st_mtime;
  tv[1].tv_usec = 0;
  if (lutimes(dst, tv) != 0)
    _cp_error(dst, 0);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_cp_single_p>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    0xc(%rsi),%edx
  mov    0x10(%rsi),%esi
  call   <lchown@plt>
  test   %rax,%rax
  je     L69
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <_cp_error@plt>
  mov    D3(%rip),%rax
  mov    (%rax),%esi
  mov    D2(%rip),%rax
  or     (%rax),%esi
  not    %esi
  and    (%rbx),%esi
  mov    %rbp,%rdi
  call   <lchmod@plt>
  test   %rax,%rax
  jne    L58
L7:
  mov    0x8(%rbx),%eax
  mov    %eax,0x8(%rsp)
  movq   $0x0,(%rsp)
  mov    0x4(%rbx),%eax
  mov    %eax,0x18(%rsp)
  movq   $0x0,0x10(%rsp)
  mov    %rsp,%rsi
  mov    %rbp,%rdi
  call   <lutimes@plt>
  test   %rax,%rax
  jne    L47
L62:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L50
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <_cp_error@plt>
  jmp    L7
L69:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  call   <lchmod@plt>
  test   %rax,%rax
  je     L7
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <_cp_error@plt>
  jmp    L7
L47:
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <_cp_error@plt>
  jmp    L62
L50:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _cp_single_p(char const *dst, struct stat *st) {
  struct timeval tv[2];
  if (lchown(dst, st->st_uid, st->st_gid) != 0) {
    _cp_error(dst, 0);
    if (lchmod(dst, st->st_mode & ~(S_ISUID | S_ISGID)) != 0)
      _cp_error(dst, 0);
  } else if (lchmod(dst, st->st_mode) != 0)
    _cp_error(dst, 0);
  tv[0].tv_sec = st->st_atime;
  tv[0].tv_usec = 0;
  tv[1].tv_sec = st->st_mtime;
  tv[1].tv_usec = 0;
  if (lutimes(dst, tv) != 0)
    _cp_error(dst, 0);
  return 0;
}
```