ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<prob>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  fldz
  fstpt  -0x20(%rbp)
  fld1
  fstpt  -0x10(%rbp)
  mov    -0x38(%rbp),%eax
  mov    %eax,-0x24(%rbp)
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x38(%rbp)
  jne    L97
  fld1
  jmp    L17
L97:
  mov    -0x34(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x38(%rbp)
  jge    L89
  mov    -0x38(%rbp),%eax
  sub    -0x34(%rbp),%eax
  mov    %eax,-0x34(%rbp)
L89:
  movl   $0x0,-0x28(%rbp)
  jmp    L86
L74:
  fldt   -0x20(%rbp)
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x20(%rbp)
  mov    -0x38(%rbp),%eax
  sub    -0x28(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  fildl  -0x3c(%rbp)
  fldt   -0x10(%rbp)
  fmulp  %st,%st(1)
  mov    -0x28(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x3c(%rbp)
  fildl  -0x3c(%rbp)
  fdivrp %st,%st(1)
  fstpt  -0x10(%rbp)
  jmp    L95
L33:
  subl   $0x1,-0x24(%rbp)
  fldt   -0x20(%rbp)
  fldt   0xe80(%rip)        # 2000 <_fini+0xe2c>
  fmulp  %st,%st(1)
  fstpt  -0x20(%rbp)
  fldt   -0x10(%rbp)
  fldt   0xe72(%rip)        # 2000 <_fini+0xe2c>
  fmulp  %st,%st(1)
  fstpt  -0x10(%rbp)
L95:
  cmpl   $0x0,-0x24(%rbp)
  jle    L82
  fld1
  fldt   -0x10(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  ja     L33
L82:
  addl   $0x1,-0x28(%rbp)
L86:
  mov    -0x28(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jle    L74
  jmp    L91
L54:
  subl   $0x1,-0x24(%rbp)
  fldt   -0x20(%rbp)
  fldt   0xe41(%rip)        # 2000 <_fini+0xe2c>
  fmulp  %st,%st(1)
  fstpt  -0x20(%rbp)
L91:
  cmpl   $0x0,-0x24(%rbp)
  jg     L54
  fldt   -0x20(%rbp)
  fadd   %st(0),%st
L17:
  pop    %rbp
  ret
```

assistant: ```c
long double prob(int last, int total) {
  long double sum = 0.;
  long double tmp = 1.;
  int i;
  int j = total;
  if (2 * last == total)
    return 1.;
  if (2 * last > total)
    last = total - last;
  for (i = 0; i <= last; i++) {
    sum += tmp;
    tmp = tmp * (total - i) / (1 + i);
    while (j > 0 && tmp > 1)
      j--, sum *= 0.5, tmp *= 0.5;
  }
  while (j > 0)
    j--, sum *= 0.5;
  return 2. * sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<prob>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  cmp    %esi,%eax
  je     L65
  mov    %esi,%edx
  sub    %edi,%edx
  cmp    %esi,%eax
  cmovg  %edx,%edi
  test   %edi,%edi
  js     L68
  lea    0x1(%rdi),%ecx
  mov    %esi,%eax
  mov    $0x0,%edx
  fld1
  fldz
  fld    %st(1)
  flds   0xed5(%rip)        # 2000 <_fini+0xe6c>
  fxch   %st(2)
  jmp    L34
L84:
  fxch   %st(3)
L44:
  cmp    %ecx,%edx
  je     L49
  fxch   %st(3)
L34:
  fadd   %st(3),%st
  mov    %esi,%edi
  sub    %edx,%edi
  mov    %edi,-0xc(%rsp)
  fildl  -0xc(%rsp)
  fmulp  %st,%st(4)
  add    $0x1,%edx
  mov    %edx,-0xc(%rsp)
  fildl  -0xc(%rsp)
  fdivrp %st,%st(4)
  test   %eax,%eax
  jle    L84
  fxch   %st(3)
L42:
  fcomi  %st(1),%st
  jbe    L44
  fxch   %st(3)
  fmul   %st(2),%st
  fxch   %st(3)
  fmul   %st(2),%st
  sub    $0x1,%eax
  jne    L42
  jmp    L44
L68:
  mov    %esi,%eax
  fldz
  jmp    L101
L49:
  fstp   %st(0)
  fstp   %st(0)
  fstp   %st(0)
L101:
  test   %eax,%eax
  jle    L67
  flds   0xe7d(%rip)        # 2000 <_fini+0xe6c>
L57:
  fmul   %st,%st(1)
  sub    $0x1,%eax
  jne    L57
  fstp   %st(0)
L67:
  fadd   %st(0),%st
  ret
L65:
  fld1
  ret
```

assistant: ```c
long double prob(int last, int total) {
  long double sum = 0.;
  long double tmp = 1.;
  int i;
  int j = total;
  if (2 * last == total)
    return 1.;
  if (2 * last > total)
    last = total - last;
  for (i = 0; i <= last; i++) {
    sum += tmp;
    tmp = tmp * (total - i) / (1 + i);
    while (j > 0 && tmp > 1)
      j--, sum *= 0.5, tmp *= 0.5;
  }
  while (j > 0)
    j--, sum *= 0.5;
  return 2. * sum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<prob>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  cmp    %esi,%eax
  je     L35
  mov    %esi,%edx
  sub    %edi,%edx
  cmp    %esi,%eax
  cmovg  %edx,%edi
  test   %edi,%edi
  js     L115
  fld1
  lea    0x1(%rdi),%ecx
  mov    %esi,%eax
  xor    %edx,%edx
  fldz
  fld    %st(1)
  flds   0xecd(%rip)        # 2000 <_fini+0xe48>
  fxch   %st(2)
  jmp    L57
  nopw   0x0(%rax,%rax,1)
L79:
  fxch   %st(3)
L57:
  mov    %esi,%edi
  fadd   %st(3),%st
  sub    %edx,%edi
  add    $0x1,%edx
  mov    %edi,-0xc(%rsp)
  fildl  -0xc(%rsp)
  mov    %edx,-0xc(%rsp)
  fmulp  %st,%st(4)
  fildl  -0xc(%rsp)
  fdivrp %st,%st(4)
  test   %eax,%eax
  jg     L116
  fxch   %st(3)
  jmp    L3
  nopw   0x0(%rax,%rax,1)
L14:
  fxch   %st(3)
  fmul   %st(2),%st
  fxch   %st(3)
  fmul   %st(2),%st
  sub    $0x1,%eax
  je     L3
  jmp    L101
  nop
L116:
  fxch   %st(3)
  nopw   0x0(%rax,%rax,1)
L101:
  fcomi  %st(1),%st
  ja     L14
L3:
  cmp    %ecx,%edx
  jne    L79
  fstp   %st(0)
  fstp   %st(0)
  fstp   %st(0)
L52:
  test   %eax,%eax
  jle    L12
  flds   0xe60(%rip)        # 2000 <_fini+0xe48>
L5:
  fmul   %st,%st(1)
  sub    $0x1,%eax
  jne    L5
  fstp   %st(0)
L12:
  fadd   %st(0),%st
  ret
L35:
  fld1
  ret
L115:
  mov    %esi,%eax
  fldz
  jmp    L52
```

assistant: ```c
long double prob(int last, int total) {
  long double sum = 0.;
  long double tmp = 1.;
  int i;
  int j = total;
  if (2 * last == total)
    return 1.;
  if (2 * last > total)
    last = total - last;
  for (i = 0; i <= last; i++) {
    sum += tmp;
    tmp = tmp * (total - i) / (1 + i);
    while (j > 0 && tmp > 1)
      j--, sum *= 0.5, tmp *= 0.5;
  }
  while (j > 0)
    j--, sum *= 0.5;
  return 2. * sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<prob>:
  endbr64
  lea    (%rdi,%rdi,1),%eax
  cmp    %esi,%eax
  je     L122
  mov    %esi,%edx
  sub    %edi,%edx
  cmp    %esi,%eax
  mov    %esi,%eax
  cmovg  %edx,%edi
  test   %edi,%edi
  js     L60
  fld1
  xor    %edx,%edx
  fldz
  fld    %st(1)
  flds   0xed0(%rip)        # 2000 <_fini+0xe18>
  fxch   %st(2)
  jmp    L73
  nopl   0x0(%rax)
L142:
  fxch   %st(3)
L73:
  mov    %esi,%ecx
  fadd   %st(3),%st
  sub    %edx,%ecx
  add    $0x1,%edx
  mov    %ecx,-0xc(%rsp)
  fildl  -0xc(%rsp)
  mov    %edx,-0xc(%rsp)
  fmulp  %st,%st(4)
  fildl  -0xc(%rsp)
  fdivrp %st,%st(4)
  test   %eax,%eax
  jg     L145
  fstp   %st(2)
  fstp   %st(0)
  jmp    L77
  nopl   0x0(%rax)
L18:
  fxch   %st(3)
  fmul   %st(2),%st
  fxch   %st(3)
  fmul   %st(2),%st
  sub    $0x1,%eax
  je     L80
  jmp    L124
  nopw   0x0(%rax,%rax,1)
L145:
  fxch   %st(3)
  nopw   0x0(%rax,%rax,1)
L124:
  fcomi  %st(1),%st
  ja     L18
L80:
  cmp    %edi,%edx
  jle    L142
  fstp   %st(0)
  fstp   %st(0)
  fstp   %st(0)
L57:
  test   %eax,%eax
  jle    L42
  flds   0xe60(%rip)        # 2000 <_fini+0xe18>
L49:
  fmul   %st,%st(1)
  sub    $0x1,%eax
  jne    L49
  fstp   %st(0)
  jmp    L42
L120:
  fstp   %st(1)
L42:
  fadd   %st(0),%st
  ret
L77:
  cmp    %edi,%edx
  jg     L120
  nopl   0x0(%rax)
L63:
  mov    %esi,%eax
  fadd   %st(1),%st
  sub    %edx,%eax
  add    $0x1,%edx
  mov    %eax,-0xc(%rsp)
  fildl  -0xc(%rsp)
  mov    %edx,-0xc(%rsp)
  fmulp  %st,%st(2)
  fildl  -0xc(%rsp)
  fdivrp %st,%st(2)
  cmp    %edx,%edi
  jge    L63
  fstp   %st(1)
  fadd   %st(0),%st
  ret
L122:
  fld1
  ret
L60:
  fldz
  jmp    L57
```

assistant: ```c
long double prob(int last, int total) {
  long double sum = 0.;
  long double tmp = 1.;
  int i;
  int j = total;
  if (2 * last == total)
    return 1.;
  if (2 * last > total)
    last = total - last;
  for (i = 0; i <= last; i++) {
    sum += tmp;
    tmp = tmp * (total - i) / (1 + i);
    while (j > 0 && tmp > 1)
      j--, sum *= 0.5, tmp *= 0.5;
  }
  while (j > 0)
    j--, sum *= 0.5;
  return 2. * sum;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<get_x_init_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %rcx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  movl   $0x10,-0x28(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L74
L91:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x24(%rbp)
  mov    -0x28(%rbp),%edx
  sub    $0x1,%edx
  cmp    %edx,%eax
  jl     L9
  shll   -0x28(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_realloc@plt>
  mov    %rax,-0x20(%rbp)
L9:
  mov    -0x48(%rbp),%rax
  movzbl (%rax),%edx
  movzbl -0x29(%rbp),%eax
  cmp    %al,%dl
  jne    L53
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L74
L53:
  mov    -0x48(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%edx
  movzbl -0x29(%rbp),%eax
  cmp    %al,%dl
  jne    L76
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
L74:
  lea    -0x29(%rbp),%rcx
  mov    -0x34(%rbp),%eax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  test   %rax,%rax
  jne    L91
  jmp    L10
L76:
  nop
L10:
  movzbl -0x29(%rbp),%eax
  cmp    $0xa,%al
  jne    L70
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  jmp    L67
L70:
  mov    $0xffffffff,%edx
L67:
  mov    -0x40(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%eax
  add    $0x1,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x50(%rbp),%rax
  lea    0x8(%rax),%rbx
  mov    %edx,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    -0x50(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rax,(%rdx)
  nop
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void get_x_init_matrix(int fd, int *x, char *auf, int **matrix) {
  int *first_line;
  char buff;
  int size;
  int i;
  first_line = malloc(sizeof(int) * (16));
  first_line[0] = 0;
  size = (16);
  i = 0;
  while (read(fd, &buff, 1)) {
    if (i++ >= size - 1)
      first_line = ft_realloc(first_line, (size *= 2));
    if (buff == auf[0])
      first_line[i] = 1;
    else if (buff == auf[1])
      first_line[i] = 0;
    else
      break;
  }
  *x = (buff == '\n') ? i - 1 : -1;
  matrix[1] = malloc(sizeof(int) * (*x + 1));
  matrix[1] = first_line;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<get_x_init_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,0x4(%rsp)
  mov    %rsi,0x10(%rsp)
  mov    %rdx,%r15
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    $0x40,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  movl   $0x0,(%rax)
  mov    $0x4,%ebp
  mov    $0x0,%ebx
  mov    $0x10,%r13d
  lea    0x27(%rsp),%rax
  mov    %rax,0x8(%rsp)
  jmp    L14
L1:
  add    %r13d,%r13d
  mov    %r13d,%esi
  mov    %r12,%rdi
  call   <ft_realloc@plt>
  mov    %rax,%r12
  jmp    L29
L43:
  movl   $0x1,(%r12,%rbp,1)
L82:
  add    $0x4,%rbp
  mov    %r14d,%ebx
L14:
  mov    $0x1,%edx
  mov    0x8(%rsp),%rsi
  mov    0x4(%rsp),%edi
  call   <read@plt>
  test   %rax,%rax
  je     L93
  lea    0x1(%rbx),%r14d
  lea    -0x1(%r13),%eax
  cmp    %ebx,%eax
  jle    L1
L29:
  movzbl 0x27(%rsp),%eax
  cmp    %al,(%r15)
  je     L43
  cmp    0x1(%r15),%al
  jne    L69
  movl   $0x0,(%r12,%rbp,1)
  jmp    L82
L69:
  mov    %r14d,%ebx
L93:
  mov    $0xffffffff,%eax
  cmpb   $0xa,0x27(%rsp)
  je     L51
L7:
  mov    0x10(%rsp),%rcx
  mov    %eax,(%rcx)
  lea    0x4(,%rax,4),%edi
  call   <malloc@plt>
  mov    0x18(%rsp),%rax
  mov    %r12,0x8(%rax)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L51:
  lea    -0x1(%rbx),%eax
  jmp    L7
L36:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_x_init_matrix(int fd, int *x, char *auf, int **matrix) {
  int *first_line;
  char buff;
  int size;
  int i;
  first_line = malloc(sizeof(int) * (16));
  first_line[0] = 0;
  size = (16);
  i = 0;
  while (read(fd, &buff, 1)) {
    if (i++ >= size - 1)
      first_line = ft_realloc(first_line, (size *= 2));
    if (buff == auf[0])
      first_line[i] = 1;
    else if (buff == auf[1])
      first_line[i] = 0;
    else
      break;
  }
  *x = (buff == '\n') ? i - 1 : -1;
  matrix[1] = malloc(sizeof(int) * (*x + 1));
  matrix[1] = first_line;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_x_init_matrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    $0x40,%edi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x10,%r12d
  push   %rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  lea    0x27(%rsp),%r15
  mov    %rdx,(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    %rax,%rbp
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L31:
  mov    (%rsp),%rsi
  cmp    0x1(%rsi),%al
  jne    L88
  movl   $0x0,0x0(%rbp,%rbx,1)
L69:
  add    $0x4,%rbx
  mov    %edx,%r13d
L19:
  mov    $0x1,%edx
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L78
  lea    -0x1(%r12),%eax
  lea    0x1(%r13),%edx
  cmp    %r13d,%eax
  jle    L62
L23:
  mov    (%rsp),%rcx
  movzbl 0x27(%rsp),%eax
  cmp    %al,(%rcx)
  jne    L31
  movl   $0x1,0x0(%rbp,%rbx,1)
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L62:
  add    %r12d,%r12d
  mov    %rbp,%rdi
  mov    %edx,0xc(%rsp)
  mov    %r12d,%esi
  call   <ft_realloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rax,%rbp
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L78:
  movzbl 0x27(%rsp),%eax
  mov    %r13d,%edx
L88:
  xor    %edi,%edi
  mov    $0xffffffff,%ecx
  cmp    $0xa,%al
  jne    L68
  lea    -0x1(%rdx),%ecx
  lea    0x0(,%rdx,4),%edi
L68:
  mov    0x10(%rsp),%rax
  mov    %ecx,(%rax)
  call   <malloc@plt>
  mov    0x18(%rsp),%rax
  mov    %rbp,0x8(%rax)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_x_init_matrix(int fd, int *x, char *auf, int **matrix) {
  int *first_line;
  char buff;
  int size;
  int i;
  first_line = malloc(sizeof(int) * (16));
  first_line[0] = 0;
  size = (16);
  i = 0;
  while (read(fd, &buff, 1)) {
    if (i++ >= size - 1)
      first_line = ft_realloc(first_line, (size *= 2));
    if (buff == auf[0])
      first_line[i] = 1;
    else if (buff == auf[1])
      first_line[i] = 0;
    else
      break;
  }
  *x = (buff == '\n') ? i - 1 : -1;
  matrix[1] = malloc(sizeof(int) * (*x + 1));
  matrix[1] = first_line;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_x_init_matrix>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  mov    $0x40,%edi
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0x10,%r12d
  push   %rbp
  push   %rbx
  mov    $0x4,%ebx
  sub    $0x38,%rsp
  mov    %rsi,0x10(%rsp)
  lea    0x27(%rsp),%r15
  mov    %rdx,(%rsp)
  mov    %rcx,0x18(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <malloc@plt>
  movl   $0x0,(%rax)
  mov    %rax,%rbp
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L89:
  cmp    0x1(%rcx),%al
  jne    L21
  movl   $0x0,0x0(%rbp,%rbx,1)
L30:
  add    $0x4,%rbx
  mov    %edx,%r13d
L39:
  mov    $0x1,%edx
  mov    %r15,%rsi
  mov    %r14d,%edi
  call   <read@plt>
  test   %rax,%rax
  je     L45
  lea    -0x1(%r12),%eax
  lea    0x1(%r13),%edx
  cmp    %r13d,%eax
  jle    L18
L75:
  mov    (%rsp),%rcx
  movzbl 0x27(%rsp),%eax
  cmp    %al,(%rcx)
  jne    L89
  movl   $0x1,0x0(%rbp,%rbx,1)
  jmp    L30
  xchg   %ax,%ax
L18:
  add    %r12d,%r12d
  mov    %rbp,%rdi
  mov    %edx,0xc(%rsp)
  mov    %r12d,%esi
  call   <ft_realloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rax,%rbp
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L45:
  movzbl 0x27(%rsp),%eax
  mov    %r13d,%edx
L21:
  xor    %edi,%edi
  mov    $0xffffffff,%ecx
  cmp    $0xa,%al
  jne    L4
  lea    -0x1(%rdx),%ecx
  lea    0x0(,%rdx,4),%edi
L4:
  mov    0x10(%rsp),%rax
  mov    %ecx,(%rax)
  call   <malloc@plt>
  mov    0x18(%rsp),%rax
  mov    %rbp,0x8(%rax)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L59
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L59:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void get_x_init_matrix(int fd, int *x, char *auf, int **matrix) {
  int *first_line;
  char buff;
  int size;
  int i;
  first_line = malloc(sizeof(int) * (16));
  first_line[0] = 0;
  size = (16);
  i = 0;
  while (read(fd, &buff, 1)) {
    if (i++ >= size - 1)
      first_line = ft_realloc(first_line, (size *= 2));
    if (buff == auf[0])
      first_line[i] = 1;
    else if (buff == auf[1])
      first_line[i] = 0;
    else
      break;
  }
  *x = (buff == '\n') ? i - 1 : -1;
  matrix[1] = malloc(sizeof(int) * (*x + 1));
  matrix[1] = first_line;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ILibGetHashValueEx>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%esi
  jle    L14
  test   %edx,%edx
  jne    L21
  lea    0x4(%rsp),%r13
  mov    $0x4,%edx
  mov    %rdi,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    0x4(%rsp),%ebp
  movslq %ebx,%rax
  lea    -0x4(%r12,%rax,1),%rsi
  mov    $0x4,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  xor    0x4(%rsp),%ebp
  cmp    $0x9,%ebx
  jle    L79
  mov    %ebx,%esi
  shr    $0x1f,%esi
  add    %ebx,%esi
  sar    %esi
  movslq %esi,%rsi
  add    %r12,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
L25:
  xor    0x4(%rsp),%ebp
L79:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L76
  mov    %ebp,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L14:
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  test   %ebp,%ebp
  jne    L68
  lea    0x4(%rsp),%rdi
  mov    %ebx,%edx
  mov    %r12,%rsi
  call   <memcpy@plt>
L78:
  mov    0x4(%rsp),%ebp
  jmp    L79
L68:
  lea    0x4(%rsp),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <ILibToLower@plt>
  jmp    L78
L21:
  lea    0x4(%rsp),%r13
  mov    %r13,%rdx
  mov    $0x4,%esi
  call   <ILibToLower@plt>
  mov    0x4(%rsp),%ebp
  movslq %ebx,%rax
  lea    -0x4(%r12,%rax,1),%rdi
  mov    %r13,%rdx
  mov    $0x4,%esi
  call   <ILibToLower@plt>
  xor    0x4(%rsp),%ebp
  cmp    $0x9,%ebx
  jle    L79
  lea    0x4(%rsp),%rdx
  mov    %ebx,%eax
  shr    $0x1f,%eax
  add    %ebx,%eax
  sar    %eax
  cltq
  lea    (%r12,%rax,1),%rdi
  mov    $0x4,%esi
  call   <ILibToLower@plt>
  jmp    L25
L76:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ILibGetHashValueEx(char *key, int keylength, int caseInSensitiveText) {
  int HashValue = 0;
  char TempValue[4];
  if (keylength <= 4) {
    memset(TempValue, 0, 4);
    if (caseInSensitiveText == 0) {
      memcpy(TempValue, key, keylength);
    } else {
      ILibToLower(key, keylength, TempValue);
    }

    HashValue = *((int *)TempValue);
  } else {
    if (caseInSensitiveText == 0) {
      memcpy(TempValue, key, 4);
    } else {
      ILibToLower(key, 4, TempValue);
    }
    HashValue = *((int *)TempValue);
    if (caseInSensitiveText == 0) {
      memcpy(TempValue, (char *)key + (keylength - 4), 4);
    } else {
      ILibToLower((char *)key + (keylength - 4), 4, TempValue);
    }
    HashValue = HashValue ^ (*((int *)TempValue));
    if (keylength >= 10) {
      if (caseInSensitiveText == 0) {
        memcpy(TempValue, (char *)key + (keylength / 2), 4);
      } else {
        ILibToLower((char *)key + (keylength / 2), 4, TempValue);
      }
      HashValue = HashValue ^ (*((int *)TempValue));
    }
  }
  return (HashValue);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ILibGetHashValueEx>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmp    $0x4,%esi
  jle    L61
  movslq %esi,%rax
  lea    0x4(%rsp),%r13
  lea    -0x4(%rdi,%rax,1),%rbp
  test   %edx,%edx
  jne    L66
  mov    %rdi,%rsi
  mov    $0x4,%edx
  mov    %r13,%rdi
  call   <memcpy@plt>
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    0x4(%rsp),%r15d
  call   <memcpy@plt>
  xor    0x4(%rsp),%r15d
  cmp    $0x9,%r12d
  jle    L44
  sar    %r12d
  mov    $0x4,%edx
  mov    %r13,%rdi
  movslq %r12d,%rsi
  add    %r14,%rsi
  call   <memcpy@plt>
L73:
  xor    0x4(%rsp),%r15d
L44:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L69
  add    $0x18,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L66:
  mov    %r13,%rdx
  mov    $0x4,%esi
  call   <ILibToLower@plt>
  mov    %r13,%rdx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  mov    0x4(%rsp),%r15d
  call   <ILibToLower@plt>
  xor    0x4(%rsp),%r15d
  cmp    $0x9,%r12d
  jle    L44
  sar    %r12d
  mov    %r13,%rdx
  mov    $0x4,%esi
  movslq %r12d,%r12
  lea    (%r14,%r12,1),%rdi
  call   <ILibToLower@plt>
  jmp    L73
  xchg   %ax,%ax
L61:
  lea    0x4(%rsp),%r13
  xor    %esi,%esi
  mov    $0x4,%edx
  mov    %r13,%rdi
  call   <memset@plt>
  test   %ebx,%ebx
  je     L53
  mov    %r13,%rdx
  mov    %r12d,%esi
  mov    %r14,%rdi
  call   <ILibToLower@plt>
L26:
  mov    0x4(%rsp),%r15d
  jmp    L44
L53:
  mov    %r12d,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <memcpy@plt>
  jmp    L26
L69:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ILibGetHashValueEx(char *key, int keylength, int caseInSensitiveText) {
  int HashValue = 0;
  char TempValue[4];
  if (keylength <= 4) {
    memset(TempValue, 0, 4);
    if (caseInSensitiveText == 0) {
      memcpy(TempValue, key, keylength);
    } else {
      ILibToLower(key, keylength, TempValue);
    }

    HashValue = *((int *)TempValue);
  } else {
    if (caseInSensitiveText == 0) {
      memcpy(TempValue, key, 4);
    } else {
      ILibToLower(key, 4, TempValue);
    }
    HashValue = *((int *)TempValue);
    if (caseInSensitiveText == 0) {
      memcpy(TempValue, (char *)key + (keylength - 4), 4);
    } else {
      ILibToLower((char *)key + (keylength - 4), 4, TempValue);
    }
    HashValue = HashValue ^ (*((int *)TempValue));
    if (keylength >= 10) {
      if (caseInSensitiveText == 0) {
        memcpy(TempValue, (char *)key + (keylength / 2), 4);
      } else {
        ILibToLower((char *)key + (keylength / 2), 4, TempValue);
      }
      HashValue = HashValue ^ (*((int *)TempValue));
    }
  }
  return (HashValue);
}
```