ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L5
  lea    D9(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L5:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xd208,%si
  je     L32
L7:
  xor    %eax,%eax
  lea    D27(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L32:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L7
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D27
type: string
name: unpack_data
arguments: data_tag: D3
type: string

tool: D9: Call this program with %i arguments


tool: D27: %u


tool: D3: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 53768) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <megaInit@plt>
  cmp    $0x2,%ebp
  je     L9
  lea    D3(%rip),%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  or     $0xffffffff,%edi
  call   <exit@plt>
L9:
  mov    0x8(%rbx),%rdi
  mov    $0xa,%edx
  xor    %esi,%esi
  call   <strtoul@plt>
  lea    0x6(%rsp),%rsi
  lea    0x4(%rsp),%rdi
  mov    %ax,0x4(%rsp)
  call   <RandomFunc@plt>
  movzwl 0x6(%rsp),%esi
  cmp    $0xd208,%si
  je     L1
L21:
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L15
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  movzwl 0x6(%rsp),%esi
  jmp    L21
L15:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D14
type_guessed: string
name: retrieve_data
arguments: data_tag: D4
type_guessed: string

tool: D3: Call this program with %i arguments


tool: D14: %u


tool: D4: You win!

assistant: ```c
int main(int argc, char *argv[]) {
  unsigned short input[1];
  unsigned short output[1];
  int randomFuns_i5;
  unsigned short randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned short)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 53768) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L8
L3:
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L8:
  cmpl   $0x3e8,-0x4(%rbp)
  jle    L3
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x7a314,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D1: Sum is %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
#pragma offload target(mic)
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= 1000; i++) {
    sum += i;
  }
  printf("Sum is %d\n", sum);
  assert(sum == (1000 * (1000 + 1)) / 2);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3e8,%eax
L4:
  sub    $0x1,%eax
  jne    L4
  mov    $0x7a314,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: Sum is %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
#pragma offload target(mic)
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= 1000; i++) {
    sum += i;
  }
  printf("Sum is %d\n", sum);
  assert(sum == (1000 * (1000 + 1)) / 2);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7a314,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D2
type: string

tool: D2: Sum is %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
#pragma offload target(mic)
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= 1000; i++) {
    sum += i;
  }
  printf("Sum is %d\n", sum);
  assert(sum == (1000 * (1000 + 1)) / 2);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7a314,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
data_type: string

tool: D7: Sum is %d


assistant: ```c
int main(void) {
  int sum = 0;
  int i;
#pragma offload target(mic)
#pragma omp parallel for reduction(+ : sum)
  for (i = 1; i <= 1000; i++) {
    sum += i;
  }
  printf("Sum is %d\n", sum);
  assert(sum == (1000 * (1000 + 1)) / 2);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m_strdup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <m_xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  leave
  ret
```

assistant: ```c
char *m_strdup(const char *text) {
  char *p = m_xmalloc(strlen(text) + 1);
  return strcpy(p, text);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<m_strdup>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <m_xmalloc@plt>
  mov    %rax,%rdi
  mov    %rbx,%rsi
  call   <strcpy@plt>
  pop    %rbx
  ret
```

assistant: ```c
char *m_strdup(const char *text) {
  char *p = m_xmalloc(strlen(text) + 1);
  return strcpy(p, text);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<m_strdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <m_xmalloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *m_strdup(const char *text) {
  char *p = m_xmalloc(strlen(text) + 1);
  return strcpy(p, text);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<m_strdup>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <m_xmalloc@plt>
  mov    %rbp,%rsi
  pop    %rbp
  mov    %rax,%rdi
  jmp    1070 <strcpy@plt>
```

assistant: ```c
char *m_strdup(const char *text) {
  char *p = m_xmalloc(strlen(text) + 1);
  return strcpy(p, text);
}
```
user: What is the c source code of the assembly code below:

```asm
<f2u0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movsd  -0x18(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
unsigned int f2u0(double x) {
  union {
    double f;
    unsigned int u[2];
  } cvt;
  cvt.f = x;
  return cvt.u[0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f2u0>:
  endbr64
  movq   %xmm0,%rax
  ret
```

assistant: ```c
unsigned int f2u0(double x) {
  union {
    double f;
    unsigned int u[2];
  } cvt;
  cvt.f = x;
  return cvt.u[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<f2u0>:
  endbr64
  movq   %xmm0,%rax
  ret
```

assistant: ```c
unsigned int f2u0(double x) {
  union {
    double f;
    unsigned int u[2];
  } cvt;
  cvt.f = x;
  return cvt.u[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<f2u0>:
  endbr64
  movq   %xmm0,%rax
  ret
```

assistant: ```c
unsigned int f2u0(double x) {
  union {
    double f;
    unsigned int u[2];
  } cvt;
  cvt.f = x;
  return cvt.u[0];
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<LnGamma>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x28(%rbp)
  movsd  -0x28(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D119(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L2
  movsd  D61(%rip),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D61(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  jmp    L17
L11:
  movsd  -0x10(%rbp),%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x10(%rbp)
L17:
  movsd  -0x8(%rbp),%xmm1
  movsd  D61(%rip),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  D119(%rip),%xmm0
  comisd -0x8(%rbp),%xmm0
  ja     L11
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   D16(%rip),%xmm0
  movq   %rax,%xmm3
  xorpd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L2:
  movsd  -0x18(%rbp),%xmm0
  movapd %xmm0,%xmm1
  mulsd  %xmm0,%xmm1
  movsd  D61(%rip),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x18(%rbp),%xmm0
  movsd  D111(%rip),%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  mulsd  -0x30(%rbp),%xmm0
  addsd  -0x10(%rbp),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x18(%rbp),%xmm1
  movsd  D11(%rip),%xmm0
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rbp),%xmm2
  movsd  D86(%rip),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  D98(%rip),%xmm0
  addsd  %xmm2,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movsd  D31(%rip),%xmm2
  subsd  %xmm2,%xmm0
  movapd %xmm0,%xmm2
  mulsd  -0x8(%rbp),%xmm2
  movsd  D99(%rip),%xmm0
  addsd  %xmm2,%xmm0
  divsd  -0x18(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D119
type_infered: f64
name: unpack_data
arguments: data_label: D61
type_infered: f64
name: unpack_data
arguments: data_label: D16
type_infered: f32[2]
name: unpack_data
arguments: data_label: D111
type_infered: f64
name: unpack_data
arguments: data_label: D11
type_infered: f64
name: unpack_data
arguments: data_label: D86
type_infered: byte[8]
name: unpack_data
arguments: data_label: D98
type_infered: f64
name: unpack_data
arguments: data_label: D31
type_infered: f64
name: unpack_data
arguments: data_label: D99
type_infered: f64

tool: D119: 7

tool: D61: 1

tool: {"D16": [0.0,-0.0]}

tool: D111: 0.5

tool: D11: 0.918938533204673

tool: {"D86": [0xa5,0x34,0x81,0x13,0x38,0x81,0x43,0xbf]}

tool: D98: 0.000793650793651

tool: D31: 0.002777777777778

tool: D99: 0.083333333333333

assistant: ```c
double LnGamma(double alpha) {
  double x = alpha, f = 0.0, z;
  if (x < 7) {
    f = 1.0;
    z = x - 1.0;
    while (++z < 7.0)
      f *= z;
    x = z;
    f = -log(f);
  }
  z = 1.0 / (x * x);
  return f + (x - 0.5) * log(x) - x + 0.918938533204673 + (((-0.000595238095238 * z + 0.000793650793651) * z - 0.002777777777778) * z + 0.083333333333333) / x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<LnGamma>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm3
  movsd  %xmm0,(%rsp)
  movsd  D51(%rip),%xmm0
  mov    D55(%rip),%rbx
  comisd %xmm3,%xmm0
  jbe    L12
  movsd  D119(%rip),%xmm0
  subsd  %xmm0,%xmm3
  movapd %xmm3,%xmm1
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm7
  movsd  %xmm1,(%rsp)
  movapd %xmm0,%xmm2
  movsd  D51(%rip),%xmm1
  comisd %xmm7,%xmm1
  jbe    L37
L4:
  movsd  (%rsp),%xmm4
  mulsd  %xmm4,%xmm0
  addsd  %xmm2,%xmm4
  movsd  %xmm4,(%rsp)
  comisd %xmm4,%xmm1
  ja     L4
L20:
  call   <log@plt>
  xorpd  D79(%rip),%xmm0
  movq   %xmm0,%rbx
L12:
  movsd  (%rsp),%xmm5
  movapd %xmm5,%xmm0
  mulsd  %xmm5,%xmm0
  movsd  D119(%rip),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,0x8(%rsp)
  movapd %xmm5,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm2
  movsd  0x8(%rsp),%xmm6
  movapd %xmm6,%xmm7
  mulsd  D19(%rip),%xmm7
  movapd %xmm7,%xmm0
  addsd  D60(%rip),%xmm0
  mulsd  %xmm6,%xmm0
  subsd  D43(%rip),%xmm0
  mulsd  %xmm6,%xmm0
  addsd  D52(%rip),%xmm0
  movsd  (%rsp),%xmm5
  divsd  %xmm5,%xmm0
  movapd %xmm5,%xmm1
  subsd  D72(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  movq   %rbx,%xmm7
  addsd  %xmm7,%xmm1
  subsd  %xmm5,%xmm1
  addsd  D83(%rip),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x10,%rsp
  pop    %rbx
  ret
L37:
  movsd  D119(%rip),%xmm0
  jmp    L20
```

tool_calls: name: extract_symbolic_data
arguments: label: D51
data_type: f64
name: extract_symbolic_data
arguments: label: D55
data_type: f64
name: extract_symbolic_data
arguments: label: D119
data_type: f64
name: extract_symbolic_data
arguments: label: D79
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D19
data_type: byte[8]
name: extract_symbolic_data
arguments: label: D60
data_type: f64
name: extract_symbolic_data
arguments: label: D43
data_type: f64
name: extract_symbolic_data
arguments: label: D52
data_type: f64
name: extract_symbolic_data
arguments: label: D72
data_type: f64
name: extract_symbolic_data
arguments: label: D83
data_type: f64

tool: D51: 7

tool: D55: 0

tool: D119: 1

tool: {"D79": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D19": [0xa5,0x34,0x81,0x13,0x38,0x81,0x43,0xbf]}

tool: D60: 0.000793650793651

tool: D43: 0.002777777777778

tool: D52: 0.083333333333333

tool: D72: 0.5

tool: D83: 0.918938533204673

assistant: ```c
double LnGamma(double alpha) {
  double x = alpha, f = 0.0, z;
  if (x < 7) {
    f = 1.0;
    z = x - 1.0;
    while (++z < 7.0)
      f *= z;
    x = z;
    f = -log(f);
  }
  z = 1.0 / (x * x);
  return f + (x - 0.5) * log(x) - x + 0.918938533204673 + (((-0.000595238095238 * z + 0.000793650793651) * z - 0.002777777777778) * z + 0.083333333333333) / x;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LnGamma>:
  endbr64
  sub    $0x28,%rsp
  movsd  D8(%rip),%xmm3
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm3
  jbe    L18
  movsd  D14(%rip),%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm2,%xmm0
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm3
  jbe    L31
  nopl   0x0(%rax,%rax,1)
L20:
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm3
  ja     L20
L31:
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <log@plt>
  xorpd  D21(%rip),%xmm0
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
L33:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  mulsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movsd  D37(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D27(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D18(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  subsd  D33(%rip),%xmm2
  addsd  D28(%rip),%xmm0
  mulsd  %xmm3,%xmm2
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm2
  subsd  %xmm1,%xmm2
  addsd  D79(%rip),%xmm2
  add    $0x28,%rsp
  addsd  %xmm2,%xmm0
  ret
  nopl   (%rax)
L18:
  pxor   %xmm5,%xmm5
  movsd  D14(%rip),%xmm2
  movsd  %xmm5,0x8(%rsp)
  jmp    L33
```

tool_calls: name: read_data
arguments: label: D8
type_infered: f64
name: read_data
arguments: label: D14
type_infered: f64
name: read_data
arguments: label: D21
type_infered: f32[4]
name: read_data
arguments: label: D37
type_infered: byte[8]
name: read_data
arguments: label: D27
type_infered: f64
name: read_data
arguments: label: D18
type_infered: f64
name: read_data
arguments: label: D33
type_infered: f64
name: read_data
arguments: label: D28
type_infered: f64
name: read_data
arguments: label: D79
type_infered: f64

tool: D8: 7

tool: D14: 1

tool: {"D21": [0.0,-0.0,0.0,0.0]}

tool: {"D37": [0xa5,0x34,0x81,0x13,0x38,0x81,0x43,0xbf]}

tool: D27: 0.000793650793651

tool: D18: 0.002777777777778

tool: D33: 0.5

tool: D28: 0.083333333333333

tool: D79: 0.918938533204673

assistant: ```c
double LnGamma(double alpha) {
  double x = alpha, f = 0.0, z;
  if (x < 7) {
    f = 1.0;
    z = x - 1.0;
    while (++z < 7.0)
      f *= z;
    x = z;
    f = -log(f);
  }
  z = 1.0 / (x * x);
  return f + (x - 0.5) * log(x) - x + 0.918938533204673 + (((-0.000595238095238 * z + 0.000793650793651) * z - 0.002777777777778) * z + 0.083333333333333) / x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LnGamma>:
  endbr64
  sub    $0x28,%rsp
  movsd  D42(%rip),%xmm3
  movapd %xmm0,%xmm1
  comisd %xmm0,%xmm3
  jbe    L23
  movsd  D89(%rip),%xmm2
  subsd  %xmm2,%xmm1
  movapd %xmm2,%xmm0
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm3
  jbe    L32
  nopl   0x0(%rax,%rax,1)
L25:
  mulsd  %xmm1,%xmm0
  addsd  %xmm2,%xmm1
  comisd %xmm1,%xmm3
  ja     L25
L32:
  movsd  %xmm2,0x18(%rsp)
  movsd  %xmm1,0x10(%rsp)
  call   <log@plt>
  xorpd  D79(%rip),%xmm0
  movsd  0x10(%rsp),%xmm1
  movsd  0x18(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
L15:
  movapd %xmm1,%xmm0
  movsd  %xmm1,0x10(%rsp)
  mulsd  %xmm1,%xmm0
  divsd  %xmm0,%xmm2
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x18(%rsp)
  call   <log@plt>
  movsd  0x18(%rsp),%xmm2
  movsd  0x10(%rsp),%xmm1
  movapd %xmm0,%xmm3
  movsd  D35(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  D93(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  D81(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  movapd %xmm1,%xmm2
  subsd  D82(%rip),%xmm2
  addsd  D22(%rip),%xmm0
  mulsd  %xmm3,%xmm2
  divsd  %xmm1,%xmm0
  addsd  0x8(%rsp),%xmm2
  subsd  %xmm1,%xmm2
  addsd  D37(%rip),%xmm2
  add    $0x28,%rsp
  addsd  %xmm2,%xmm0
  ret
  nopl   (%rax)
L23:
  pxor   %xmm5,%xmm5
  movsd  D89(%rip),%xmm2
  movsd  %xmm5,0x8(%rsp)
  jmp    L15
```

tool_calls: name: parse_data
arguments: label: D42
type_guessed: f64
name: parse_data
arguments: label: D89
type_guessed: f64
name: parse_data
arguments: label: D79
type_guessed: f32[4]
name: parse_data
arguments: label: D35
type_guessed: byte[8]
name: parse_data
arguments: label: D93
type_guessed: f64
name: parse_data
arguments: label: D81
type_guessed: f64
name: parse_data
arguments: label: D82
type_guessed: f64
name: parse_data
arguments: label: D22
type_guessed: f64
name: parse_data
arguments: label: D37
type_guessed: f64

tool: D42: 7

tool: D89: 1

tool: {"D79": [0.0,-0.0,0.0,0.0]}

tool: {"D35": [0xa5,0x34,0x81,0x13,0x38,0x81,0x43,0xbf]}

tool: D93: 0.000793650793651

tool: D81: 0.002777777777778

tool: D82: 0.5

tool: D22: 0.083333333333333

tool: D37: 0.918938533204673

assistant: ```c
double LnGamma(double alpha) {
  double x = alpha, f = 0.0, z;
  if (x < 7) {
    f = 1.0;
    z = x - 1.0;
    while (++z < 7.0)
      f *= z;
    x = z;
    f = -log(f);
  }
  z = 1.0 / (x * x);
  return f + (x - 0.5) * log(x) - x + 0.918938533204673 + (((-0.000595238095238 * z + 0.000793650793651) * z - 0.002777777777778) * z + 0.083333333333333) / x;
}
```
user: What is the c source code of the assembly code below?

```asm
<main_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D39(%rip),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  cmp    %rax,-0x28(%rbp)
  jne    L28
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L20
L28:
  mov    $0x0,%eax
  call   <abort@plt>
L20:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    (%rax),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  lea    -0x20(%rbp),%rax
  add    $0x8,%rax
  cmp    %rax,-0x28(%rbp)
  jne    L2
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L48
L2:
  mov    $0x0,%eax
  call   <abort@plt>
L48:
  mov    $0xa,%edi
  call   <putchar@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rsi
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <__builtin_printf@plt>
  mov    $0xa,%edi
  call   <__builtin_putchar@plt>
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D39
data_type: string
name: parse_data
arguments: data_label: D20
data_type: string
name: parse_data
arguments: data_label: D27
data_type: string

tool: D39: hello world

tool: D20: hello

tool: D27: %s


assistant: ```c
void main_test(void) {
  const char *const s1 = "hello world";
  const char *const s2[] = {s1, 0}, *const * s3;
  printf("%s\n", "hello");
  printf("%s\n", *s2);
  s3 = s2;
  printf("%s\n", *s3++);
  if (s3 != s2 + 1 || *s3 != 0)
    abort();
  printf("%c", '\n');
  printf("%c", **s2);
  s3 = s2;
  printf("%c", **s3++);
  if (s3 != s2 + 1 || *s3 != 0)
    abort();
  printf("\n");
  printf("hello world\n");
  __builtin_printf("%s\n", "hello");
  __builtin_putchar('\n');
  __builtin_puts("hello");
}
```