user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x150,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1148(%rsp)
  xor    %eax,%eax
  lea    D67(%rip),%rdi
  call   <printf@plt>
  lea    0x8(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  lea    D69(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L66
  lea    0x1a0(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D24(%rip),%r12
L60:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L60
L66:
  lea    D75(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  lea    D53(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmpl   $0x0,0xc(%rsp)
  jle    L107
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D24(%rip),%r12
L123:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0xc(%rsp)
  jg     L123
L107:
  lea    D4(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%ebp
  lea    D31(%rip),%r14
  lea    D81(%rip),%r13
  lea    D110(%rip),%r12
  cmpl   $0x0,0xc(%rsp)
  jg     L62
L5:
  mov    0x1148(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L85
  mov    $0x0,%eax
  add    $0x1150,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L139:
  test   %ebx,%ebx
  je     L4
  lea    -0x1(%rdx),%eax
  cmp    %ebx,%eax
  je     L94
  lea    0x1(%rbx),%eax
  cltq
  mov    0x1a0(%rsp,%rax,4),%edx
  lea    -0x1(%rbx),%eax
  cltq
  mov    0x1a0(%rsp,%rax,4),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L74:
  cmp    %ebx,0x8(%rsp)
  je     L122
L125:
  add    $0x1,%rbp
  cmp    %ebp,0xc(%rsp)
  jle    L5
L62:
  mov    0x8(%rsp),%edx
  mov    $0x0,%ebx
  test   %edx,%edx
  jle    L74
  mov    0x10(%rsp,%rbp,4),%ecx
  lea    0x1a0(%rsp),%rax
  mov    $0x0,%ebx
L1:
  cmp    (%rax),%ecx
  je     L139
  add    $0x1,%ebx
  add    $0x4,%rax
  cmp    %edx,%ebx
  jne    L1
L122:
  mov    %r14,%rdi
  call   <puts@plt>
  jmp    L125
L4:
  mov    0x1a4(%rsp),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L74
L94:
  lea    -0x2(%rdx),%eax
  cltq
  mov    0x1a0(%rsp,%rax,4),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L74
L85:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D67
type_infered: string
name: read_data
arguments: label: D24
type_infered: string
name: read_data
arguments: label: D69
type_infered: string
name: read_data
arguments: label: D75
type_infered: string
name: read_data
arguments: label: D53
type_infered: string
name: read_data
arguments: label: D4
type_infered: string
name: read_data
arguments: label: D31
type_infered: string
name: read_data
arguments: label: D81
type_infered: string
name: read_data
arguments: label: D110
type_infered: string

tool: D67: Please input the number of integers:

tool: D24: %d

tool: D69: Please input the integers:

tool: D75: Please input the times of query:

tool: D53: Please input the integers you want to query:

tool: D4: The result is:

tool: D31: NULL

tool: D81: %d %d


tool: D110: %d


assistant: ```c
int main() {
  int n, m, num[1000], query[100], i, j;
  printf("Please input the number of integers:");
  scanf("%d", &n);
  printf("Please input the integers:");
  for (i = 0; i < n; i++)
    scanf("%d", &num[i]);
  printf("Please input the times of query:");
  scanf("%d", &m);
  printf("Please input the integers you want to query:");
  for (i = 0; i < m; i++)
    scanf("%d", &query[i]);
  printf("The result is:\n");
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++)
      if (query[i] == num[j]) {
        if (j == 0)
          printf("%d\n", num[1]);
        else if (j == n - 1)
          printf("%d\n", num[n - 2]);
        else
          printf("%d %d\n", num[j - 1], num[j + 1]);
        break;
      }
    if (j == n)
      printf("NULL\n");
  }
  return 0;
}
```