ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%eax
  sub    $0x99f4bb,%eax
  mov    %eax,0x4(%rsp)
  mov    0x4(%rdi),%esi
  test   %esi,%esi
  je     L51
  mov    $0x0,%eax
  lea    0x4(%rsp),%r8
L19:
  mov    0x4(%rsp),%edx
  cmp    %eax,%edx
  jbe    L8
  mov    %eax,%edi
  imul   %edx,%edx
  mov    %edx,0x4(%rsp,%rdi,4)
L66:
  mov    0x4(%rsp),%edx
  cmp    %eax,%edx
  jbe    L1
  add    %edx,%edx
  mov    %edx,0x4(%rsp)
L62:
  add    $0x2,%eax
  cmp    %eax,%esi
  ja     L19
L51:
  mov    0x4(%rsp),%eax
  add    $0x17c2d8f4,%eax
  mov    %eax,(%rcx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x18,%rsp
  ret
L8:
  mov    %eax,%edi
  add    %edx,%edx
  mov    %edx,%r10d
  shr    $0x10,%r10d
  lea    (%r8,%rdi,4),%rdi
  mov    %dx,0x2(%rdi)
  mov    %r10w,(%rdi)
  jmp    L66
L1:
  mov    %eax,%edi
  add    %edx,%edx
  mov    %edx,%r11d
  shr    $0x18,%r11d
  mov    %edx,0x4(%rsp,%rdi,4)
  lea    (%r8,%rdi,4),%rdi
  mov    %r11b,0x1(%rdi)
  movzbl %dh,%edx
  mov    %dl,0x3(%rdi)
  jmp    L62
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy13;
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 398645492UL;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%eax
  mov    0x4(%rdi),%edi
  sub    $0x99f4bb,%eax
  mov    %eax,0x4(%rsp)
  test   %edi,%edi
  je     L20
  xor    %edx,%edx
  lea    0x4(%rsp),%r10
L11:
  mov    %edx,%r9d
  lea    (%r10,%r9,4),%rcx
  cmp    %edx,%eax
  jbe    L45
  imul   %eax,%eax
  mov    %eax,%r8d
L63:
  lea    (%r8,%r8,1),%eax
  cmp    %r8d,%edx
  jae    L58
  mov    %eax,0x4(%rsp)
L43:
  add    $0x2,%edx
  cmp    %edi,%edx
  jb     L11
L20:
  add    $0x17c2d8f4,%eax
  mov    %eax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L64
  add    $0x18,%rsp
  ret
L58:
  mov    %eax,0x4(%rsp,%r9,4)
  movzbl 0x1(%rcx),%eax
  movzbl 0x3(%rcx),%r8d
  mov    %al,0x3(%rcx)
  mov    %r8b,0x1(%rcx)
  mov    0x4(%rsp),%eax
  jmp    L43
  nopl   0x0(%rax,%rax,1)
L45:
  movzwl (%rcx),%r11d
  lea    (%rax,%rax,1),%r8d
  movzwl 0x2(%rcx),%eax
  mov    %r11w,0x2(%rcx)
  mov    %ax,(%rcx)
  jmp    L63
L64:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned int input[1], unsigned int output[1]) {
  unsigned int state[1];
  unsigned int local1;
  unsigned short copy12;
  unsigned short copy13;
  char copy14;
  {
    state[0UL] = input[0UL] + 4284877637U;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] * state[0UL];
      } else {
        state[local1] += state[0UL];
        copy12 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy12;
      }
      if (state[0UL] > local1) {
        copy13 = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = copy13;
        copy13 = *((unsigned short *)(&state[local1]) + 0);
        *((unsigned short *)(&state[local1]) + 0) = *((unsigned short *)(&state[local1]) + 1);
        *((unsigned short *)(&state[local1]) + 1) = copy13;
        state[0UL] += state[0UL];
      } else {
        state[local1] += state[local1];
        copy14 = *((char *)(&state[local1]) + 1);
        *((char *)(&state[local1]) + 1) = *((char *)(&state[local1]) + 3);
        *((char *)(&state[local1]) + 3) = copy14;
      }
      local1 += 2UL;
    }
    output[0UL] = state[0UL] + 398645492UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<tc1_>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x12(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rcx
  lea    -0x12(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <cnfExprt@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: Test C1

assistant: ```c
void tc1_(char *const c, int c_length) {

  char string[10];
  strcpy(string, "Test C1");
  cnfExprt(string, c, c_length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<tc1_>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r12
  lea    D5(%rip),%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <cnfExprt@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D5: Test C1

assistant: ```c
void tc1_(char *const c, int c_length) {

  char string[10];
  strcpy(string, "Test C1");
  cnfExprt(string, c, c_length);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<tc1_>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D6(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <cnfExprt@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: Test C1

assistant: ```c
void tc1_(char *const c, int c_length) {

  char string[10];
  strcpy(string, "Test C1");
  cnfExprt(string, c, c_length);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tc1_>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D1(%rip),%rsi
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xe(%rsp),%r13
  mov    %r13,%rdi
  call   <strcpy@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <cnfExprt@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x20,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string

tool: D1: Test C1

assistant: ```c
void tc1_(char *const c, int c_length) {

  char string[10];
  strcpy(string, "Test C1");
  cnfExprt(string, c, c_length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ft_init_grid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_atoi@plt>
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_atoi@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L30
L9:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L10
L1:
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0xc(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  movl   $0x0,(%rax)
L10:
  cmpl   $0x0,-0x8(%rbp)
  jns    L1
  subl   $0x1,-0xc(%rbp)
L30:
  cmpl   $0x0,-0xc(%rbp)
  jns    L9
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_init_grid(int ***tab, char **av) {
  int line;
  int column;
  int tmp;
  line = ft_atoi(av[1]) - 1;
  column = ft_atoi(av[2]) - 1;
  while (line >= 0) {
    tmp = column;
    while (tmp >= 0)
      (*tab)[line][tmp--] = 0;
    line--;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_init_grid>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    0x8(%rsi),%rdi
  call   <ft_atoi@plt>
  mov    %eax,%r13d
  lea    -0x1(%rax),%r12d
  mov    0x10(%rbp),%rdi
  call   <ft_atoi@plt>
  test   %r12d,%r12d
  js     L39
  mov    %eax,%r9d
  movslq %r12d,%rcx
  shl    $0x3,%rcx
  movslq %r13d,%rax
  lea    -0x1(%r13),%edx
  sub    %rdx,%rax
  lea    -0x10(,%rax,8),%r8
  lea    -0x1(%r9),%edx
  movslq %edx,%rdi
  shl    $0x2,%rdi
  movslq %r9d,%rax
  mov    %edx,%edx
  sub    %rdx,%rax
  lea    -0x8(,%rax,4),%rsi
  jmp    L1
L9:
  mov    (%rbx),%rdx
  mov    (%rdx,%rcx,1),%rdx
  movl   $0x0,(%rdx,%rax,1)
  sub    $0x4,%rax
  cmp    %rsi,%rax
  jne    L9
L8:
  sub    $0x8,%rcx
  cmp    %r8,%rcx
  je     L39
L1:
  mov    %rdi,%rax
  test   %r9d,%r9d
  jg     L9
  jmp    L8
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void ft_init_grid(int ***tab, char **av) {
  int line;
  int column;
  int tmp;
  line = ft_atoi(av[1]) - 1;
  column = ft_atoi(av[2]) - 1;
  while (line >= 0) {
    tmp = column;
    while (tmp >= 0)
      (*tab)[line][tmp--] = 0;
    line--;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ft_init_grid>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  mov    0x8(%rsi),%rdi
  call   <ft_atoi@plt>
  mov    0x10(%rbx),%rdi
  movslq %eax,%r12
  lea    -0x1(%r12),%r14d
  call   <ft_atoi@plt>
  test   %r14d,%r14d
  js     L7
  movslq %r14d,%rbx
  mov    %r14d,%r14d
  lea    -0x1(%rax),%ebp
  sub    %r14,%r12
  mov    %ebp,%eax
  shl    $0x3,%rbx
  lea    -0x10(,%r12,8),%r14
  movslq %ebp,%r12
  lea    0x4(,%rax,4),%r15
  sub    %rax,%r12
  shl    $0x2,%r12
  nopl   0x0(%rax,%rax,1)
L20:
  test   %ebp,%ebp
  js     L24
  mov    0x0(%r13),%rax
  mov    %r15,%rdx
  xor    %esi,%esi
  mov    (%rax,%rbx,1),%rdi
  add    %r12,%rdi
  call   <memset@plt>
L24:
  sub    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L20
L7:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void ft_init_grid(int ***tab, char **av) {
  int line;
  int column;
  int tmp;
  line = ft_atoi(av[1]) - 1;
  column = ft_atoi(av[2]) - 1;
  while (line >= 0) {
    tmp = column;
    while (tmp >= 0)
      (*tab)[line][tmp--] = 0;
    line--;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ft_init_grid>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    %rsi,%rbx
  call   <ft_atoi@plt>
  mov    0x10(%rbx),%rdi
  movslq %eax,%rbp
  call   <ft_atoi@plt>
  lea    -0x1(%rbp),%r13d
  sub    $0x1,%eax
  test   %r13d,%r13d
  js     L8
  test   %eax,%eax
  js     L8
  mov    %eax,%edx
  movslq %r13d,%rbx
  cltq
  mov    %r13d,%r13d
  sub    %r13,%rbp
  sub    %rdx,%rax
  shl    $0x3,%rbx
  lea    0x4(,%rdx,4),%r13
  lea    -0x10(,%rbp,8),%r14
  lea    0x0(,%rax,4),%rbp
  nopl   0x0(%rax,%rax,1)
L22:
  mov    (%r12),%rax
  mov    %r13,%rdx
  xor    %esi,%esi
  mov    (%rax,%rbx,1),%rdi
  sub    $0x8,%rbx
  add    %rbp,%rdi
  call   <memset@plt>
  cmp    %r14,%rbx
  jne    L22
L8:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void ft_init_grid(int ***tab, char **av) {
  int line;
  int column;
  int tmp;
  line = ft_atoi(av[1]) - 1;
  column = ft_atoi(av[2]) - 1;
  while (line >= 0) {
    tmp = column;
    while (tmp >= 0)
      (*tab)[line][tmp--] = 0;
    line--;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_procs_of_exe>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <pids_of_exe@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <countlist@plt>
  mov    %eax,-0xc(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L3
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L3:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

assistant: ```c
int num_procs_of_exe(const char *exe) {
  pid_t *pids = pids_of_exe(exe);
  int ret;
  ret = countlist((void **)pids);
  if (pids)
    free(pids);
  return ret;
}
```
user: What is the c source code of the assembly code below?

```asm
<num_procs_of_exe>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <pids_of_exe@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <countlist@plt>
  mov    %eax,%ebp
  test   %rbx,%rbx
  je     L8
  mov    %rbx,%rdi
  call   <free@plt>
L8:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int num_procs_of_exe(const char *exe) {
  pid_t *pids = pids_of_exe(exe);
  int ret;
  ret = countlist((void **)pids);
  if (pids)
    free(pids);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<num_procs_of_exe>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <pids_of_exe@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <countlist@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L9
  mov    %rbp,%rdi
  call   <free@plt>
L9:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int num_procs_of_exe(const char *exe) {
  pid_t *pids = pids_of_exe(exe);
  int ret;
  ret = countlist((void **)pids);
  if (pids)
    free(pids);
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<num_procs_of_exe>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  call   <pids_of_exe@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <countlist@plt>
  mov    %eax,%r12d
  test   %rbp,%rbp
  je     L1
  mov    %rbp,%rdi
  call   <free@plt>
L1:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int num_procs_of_exe(const char *exe) {
  pid_t *pids = pids_of_exe(exe);
  int ret;
  ret = countlist((void **)pids);
  if (pids)
    free(pids);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L37
L5:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  jne    L22
  addl   $0x1,-0x74(%rbp)
L22:
  addl   $0x1,-0x78(%rbp)
L37:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L5
  mov    -0x74(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_infered: string
name: read_data
arguments: data_tag: D4
type_infered: string
name: read_data
arguments: data_tag: D22
type_infered: string

tool: D8: Type a sentence

tool: D4: %[^
]s

tool: D22: Number of words in the sentence=%d


assistant: ```c
void main() {
  int i, count = 0;
  char ch[100];
  printf("Type a sentence\n");
  scanf("%[^\n]s", ch);
  for (i = 0; ch[i] != '\0'; i++) {
    if (ch[i] == ' ') {
      count++;
    }
  }
  printf("Number of words in the sentence=%d\n", count + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L15
  lea    0x1(%rsp),%rdx
  mov    $0x0,%esi
L17:
  cmp    $0x20,%al
  sete   %al
  movzbl %al,%eax
  add    %eax,%esi
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L17
L18:
  add    $0x1,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L36
  add    $0x78,%rsp
  ret
L15:
  mov    $0x0,%esi
  jmp    L18
L36:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
type: string
name: read_data
arguments: data_tag: D0
type: string
name: read_data
arguments: data_tag: D3
type: string

tool: D19: Type a sentence

tool: D0: %[^
]s

tool: D3: Number of words in the sentence=%d


assistant: ```c
void main() {
  int i, count = 0;
  char ch[100];
  printf("Type a sentence\n");
  scanf("%[^\n]s", ch);
  for (i = 0; ch[i] != '\0'; i++) {
    if (ch[i] == ' ') {
      count++;
    }
  }
  printf("Number of words in the sentence=%d\n", count + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  lea    D27(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L38
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L20:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%esi
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L20
L6:
  add    $0x1,%esi
  xor    %eax,%eax
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x78,%rsp
  ret
L38:
  xor    %esi,%esi
  jmp    L6
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D27
datatype: string
name: retrieve_data
arguments: data_tag: D1
datatype: string
name: retrieve_data
arguments: data_tag: D19
datatype: string

tool: D27: Type a sentence

tool: D1: %[^
]s

tool: D19: Number of words in the sentence=%d


assistant: ```c
void main() {
  int i, count = 0;
  char ch[100];
  printf("Type a sentence\n");
  scanf("%[^\n]s", ch);
  for (i = 0; ch[i] != '\0'; i++) {
    if (ch[i] == ' ') {
      count++;
    }
  }
  printf("Number of words in the sentence=%d\n", count + 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x78,%rsp
  lea    D7(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  call   <puts@plt>
  mov    %rsp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  movzbl (%rsp),%eax
  test   %al,%al
  je     L32
  lea    0x1(%rsp),%rdx
  xor    %esi,%esi
  nopw   0x0(%rax,%rax,1)
L4:
  cmp    $0x20,%al
  sete   %al
  add    $0x1,%rdx
  movzbl %al,%eax
  add    %eax,%esi
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L4
L13:
  add    $0x1,%esi
  xor    %eax,%eax
  lea    D14(%rip),%rdi
  call   <printf@plt>
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  add    $0x78,%rsp
  ret
L32:
  xor    %esi,%esi
  jmp    L13
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_guessed: string
name: parse_data
arguments: data_tag: D8
type_guessed: string
name: parse_data
arguments: data_tag: D14
type_guessed: string

tool: D7: Type a sentence

tool: D8: %[^
]s

tool: D14: Number of words in the sentence=%d


assistant: ```c
void main() {
  int i, count = 0;
  char ch[100];
  printf("Type a sentence\n");
  scanf("%[^\n]s", ch);
  for (i = 0; ch[i] != '\0'; i++) {
    if (ch[i] == ' ') {
      count++;
    }
  }
  printf("Number of words in the sentence=%d\n", count + 1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xor_reg64_reg64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    $0x48,%edi
  call   <put8@plt>
  mov    $0x31,%edi
  call   <put8@plt>
  mov    -0x8(%rbp),%eax
  shl    $0x3,%eax
  or     -0x4(%rbp),%eax
  or     $0xc0,%al
  mov    %eax,%edi
  call   <put8@plt>
  nop
  leave
  ret
```

assistant: ```c
void xor_reg64_reg64(unsigned int reg1, unsigned int reg2) {
  put8(0x48);
  put8(0x31);
  put8(0xC0 | (reg2 << 3) | reg1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xor_reg64_reg64>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  mov    $0x48,%edi
  call   <put8@plt>
  mov    $0x31,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  or     %ebp,%edi
  or     $0xc0,%dil
  call   <put8@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void xor_reg64_reg64(unsigned int reg1, unsigned int reg2) {
  put8(0x48);
  put8(0x31);
  put8(0xC0 | (reg2 << 3) | reg1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<xor_reg64_reg64>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x48,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0x31,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <put8@plt>
```

assistant: ```c
void xor_reg64_reg64(unsigned int reg1, unsigned int reg2) {
  put8(0x48);
  put8(0x31);
  put8(0xC0 | (reg2 << 3) | reg1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xor_reg64_reg64>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    $0x48,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <put8@plt>
  mov    $0x31,%edi
  call   <put8@plt>
  lea    0x0(,%rbx,8),%edi
  add    $0x8,%rsp
  or     %ebp,%edi
  pop    %rbx
  pop    %rbp
  or     $0xc0,%dil
  jmp    1050 <put8@plt>
```

assistant: ```c
void xor_reg64_reg64(unsigned int reg1, unsigned int reg2) {
  put8(0x48);
  put8(0x31);
  put8(0xC0 | (reg2 << 3) | reg1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_imm_22>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D34(%rip),%eax
  add    $0x4,%eax
  and    $0x3fffff,%eax
  mov    %eax,D3(%rip)
  mov    D3(%rip),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D3
type_guessed: string

tool: D3: 0x%x

assistant: ```c
void print_imm_22(void) {
  static int val = 0;
  val = (val + 4) & 0x3fffff;
  printf("0x%x", val);
}
```