user: 请从给定的汇编指令推导出C源代码:

```asm
<count_numbers>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebx
  mov    %edi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  mov    $0x2,%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,-0x44(%rbp)
  mov    $0x3,%eax
  cmp    %eax,%ebx
  cmovle %ebx,%eax
  lea    -0x1(%rax),%esi
  mov    $0xa,%edi
  call   <power@plt>
  mov    %eax,%ebx
  lea    (%rax,%rax,4),%r15d
  add    %r15d,%r15d
  lea    -0x1(%r15),%eax
  mov    %eax,-0x5c(%rbp)
  movslq %r15d,%rax
  lea    0x0(,%rax,8),%rdi
  mov    %rdi,-0x58(%rbp)
  shl    $0x4,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L54:
  cmp    %rdx,%rsp
  je     L176
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L54
L176:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  je     L155
  orq    $0x0,-0x8(%rsp,%rdx,1)
L155:
  mov    %rsp,%r13
  mov    %r13,-0x68(%rbp)
  lea    0x0(,%r15,8),%r14d
  mov    %r14d,-0x6c(%rbp)
  mov    -0x58(%rbp),%r12
  mov    %r12,%rax
  shr    $0x3,%rax
  mov    %rax,-0x78(%rbp)
  mov    %r14d,%edx
  mov    $0x0,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    %r13,%rdi
  add    %r12,%rdi
  mov    %r14d,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  mov    -0x5c(%rbp),%r12d
  cmp    %r12d,%ebx
  jg     L103
  movslq %ebx,%rbx
  jmp    L188
L178:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L103
L188:
  mov    %ebx,%edi
  call   <digits_sum@plt>
  cmp    $0x9,%eax
  jg     L178
  movq   $0x1,0x0(%r13,%rbx,8)
  jmp    L178
L103:
  cmpl   $0x3,-0x60(%rbp)
  jle    L60
  movl   $0x4,-0x48(%rbp)
  movl   $0x1,-0x50(%rbp)
  movl   $0x0,-0x4c(%rbp)
L101:
  mov    -0x4c(%rbp),%eax
  movslq %eax,%rbx
  mov    -0x58(%rbp),%rdi
  imul   %rdi,%rbx
  mov    -0x68(%rbp),%rcx
  add    %rcx,%rbx
  mov    -0x50(%rbp),%esi
  movslq %esi,%r14
  imul   %rdi,%r14
  add    %rcx,%r14
  add    $0x1,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x4c(%rbp)
  lea    0x1(%rsi),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  and    $0x1,%eax
  sub    %edx,%eax
  mov    %eax,-0x50(%rbp)
  mov    -0x6c(%rbp),%edx
  mov    $0x0,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  cmpl   $0x0,-0x5c(%rbp)
  js     L14
  mov    $0x0,%r12d
L97:
  mov    %r12d,%eax
  cltd
  idivl  -0x44(%rbp)
  mov    %edx,%r13d
  mov    %edx,%edi
  call   <digits_sum@plt>
  mov    $0x9,%ecx
  sub    %eax,%ecx
  js     L100
  lea    0x0(%r13,%r13,4),%edx
  add    %edx,%edx
  movslq %edx,%rdx
  lea    (%r14,%rdx,8),%rax
  mov    %ecx,%ecx
  add    %rdx,%rcx
  lea    0x8(%r14,%rcx,8),%rcx
L69:
  mov    (%rbx),%rdx
  add    %rdx,(%rax)
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L69
L100:
  add    $0x1,%r12d
  add    $0x8,%rbx
  cmp    %r12d,%r15d
  jne    L97
L14:
  addl   $0x1,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  cmp    %eax,-0x60(%rbp)
  jge    L101
L115:
  cmpl   $0x0,-0x5c(%rbp)
  js     L48
  movslq -0x4c(%rbp),%rdx
  mov    -0x58(%rbp),%rax
  imul   %rdx,%rax
  mov    -0x68(%rbp),%rdi
  add    %rdi,%rax
  lea    -0x1(%r15),%ecx
  imul   -0x78(%rbp),%rdx
  add    %rcx,%rdx
  lea    0x8(%rdi,%rdx,8),%rcx
  mov    $0x0,%edx
L152:
  add    (%rax),%rdx
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L152
L179:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L123
  mov    %rdx,%rax
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L60:
  movl   $0x0,-0x4c(%rbp)
  jmp    L115
L48:
  mov    $0x0,%edx
  jmp    L179
L123:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long count_numbers(int digits) {
  int mod = power(10, 3 - 1);
  int min_seq = power(10, ((3) < (digits) ? (3) : (digits)) - 1);
  int max_seq = min_seq * 10 - 1;
  int current = 0;
  int new = 1;
  long counts[2][max_seq + 1];
  memset(counts[current], 0, (max_seq + 1) * sizeof(counts[0][0]));
  memset(counts[new], 0, (max_seq + 1) * sizeof(counts[0][0]));
  for (int i = min_seq; i <= max_seq; i++)
    if (digits_sum(i) <= 9)
      counts[current][i] = 1;
  for (int i = 3 + 1; i <= digits; i++) {
    long *c = counts[current];
    long *n = counts[new];
    current = (current + 1) % 2;
    new = (new + 1) % 2;
    memset(n, 0, (max_seq + 1) * sizeof(counts[0][0]));
    for (int seq = 0; seq <= max_seq; seq++) {
      int prefix = seq % mod;
      int prefix_sum = digits_sum(prefix);
      for (int new_digit = 0; new_digit <= 9 - prefix_sum; new_digit++) {
        int new_seq = prefix * 10 + new_digit;
        n[new_seq] += c[seq];
      }
    }
  }
  long count = 0;
  for (int seq = 0; seq <= max_seq; seq++)
    count += counts[current][seq];
  return count;
}
```