ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<decrypt_str>:
  endbr64
  push   %r15
  mov    %rcx,%rax
  mov    %rcx,%r15
  push   %r14
  imul   %rsi,%rax
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rax,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x58,%rsp
  mov    %rsi,(%rsp)
  mov    $0x8,%esi
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x20(%rsp)
  mov    %r9,0x28(%rsp)
  mov    %rax,0x48(%rsp)
  call   <calloc@plt>
  mov    %rax,0x40(%rsp)
  lea    -0x1(%rbx,%rbx,1),%rax
  mov    %rax,0x10(%rsp)
  test   %r15,%r15
  je     L8
  mov    (%rsp),%rax
  xor    %r15d,%r15d
  mov    %r14,%r13
  movq   $0x0,0x8(%rsp)
  lea    -0x1(%rax),%rdi
  mov    %rdi,0x38(%rsp)
  mov    0x40(%rsp),%rdi
  lea    (%rdi,%rax,8),%rax
  mov    %rax,0x30(%rsp)
  nopl   0x0(%rax)
L70:
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%rax
  xor    %edx,%edx
  imul   (%rcx,%r15,8),%rax
  divq   0x28(%rsp)
  cmpq   $0x0,(%rsp)
  mov    %rdx,%rbp
  je     L24
  mov    0x30(%rsp),%rax
  mov    0x8(%rsp),%rcx
  mov    0x38(%rsp),%r14
  lea    -0x8(%rax,%rcx,8),%r12
  xor    %eax,%eax
  jmp    L29
  nopl   0x0(%rax,%rax,1)
L59:
  sub    $0x1,%r14
  sub    $0x8,%r12
  cmp    $0xffffffffffffffff,%r14
  je     L24
L29:
  mov    0x0(%r13,%r14,8),%rsi
  lea    (%rsi,%rax,1),%rbx
  cmp    %rbp,%rbx
  ja     L59
  mov    %r14,%rcx
  mov    %r15,%rdx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  movq   $0x1,(%r12)
  cmp    %rbp,%rbx
  je     L24
  sub    $0x1,%r14
  mov    %rbx,%rax
  sub    $0x8,%r12
  cmp    $0xffffffffffffffff,%r14
  jne    L29
L24:
  mov    (%rsp),%rdx
  add    $0x1,%r15
  add    %rdx,0x8(%rsp)
  cmp    %r15,0x20(%rsp)
  jne    L70
L8:
  mov    0x90(%rsp),%rax
  mov    0x40(%rsp),%rdi
  mov    %rdi,(%rax)
  mov    0x98(%rsp),%rax
  mov    0x48(%rsp),%rdi
  mov    %rdi,(%rax)
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: tmp: %d; i: %d; j: %d


assistant: ```c
void decrypt_str(const size_t *private_key, const size_t private_key_size, const size_t *str, const size_t str_size, const size_t n, const size_t m, size_t **decrypted_str, size_t *decrypted_str_size) {
  size_t size = str_size * private_key_size;
  size_t *p = (size_t *)calloc(size, (sizeof *decrypted_str));
  size_t x = (2 * n) - 1;
  size_t i;
  size_t j;
  size_t sum;
  size_t res;
  size_t tmp;
  for (i = 0; i < str_size; i++) {
    sum = (str[i] * x) % m;
    res = 0;
    j = private_key_size;
    for (; j-- != 0;) {
      tmp = private_key[j];
      if (res + tmp <= sum) {
        res += tmp;
        printf("tmp: %d; i: %d; j: %d\n", tmp, i, j);
        p[(i * private_key_size) + j] = 1;
        if (res == sum) {
          break;
        }
      }
    }
  }
  *decrypted_str = (size_t *)p;
  *decrypted_str_size = size;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<decrypt_str>:
  endbr64
  push   %r15
  mov    %rcx,%rax
  mov    %rcx,%r15
  push   %r14
  imul   %rsi,%rax
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rax,%rdi
  push   %rbx
  mov    %r8,%rbx
  sub    $0x58,%rsp
  mov    %rsi,0x8(%rsp)
  mov    $0x8,%esi
  mov    %rdx,0x18(%rsp)
  mov    %rcx,0x20(%rsp)
  mov    %r9,0x28(%rsp)
  mov    %rax,0x48(%rsp)
  call   <calloc@plt>
  mov    %rax,0x40(%rsp)
  lea    -0x1(%rbx,%rbx,1),%rax
  mov    %rax,0x10(%rsp)
  test   %r15,%r15
  je     L63
  mov    0x8(%rsp),%rax
  lea    -0x1(%rax),%rdi
  mov    %rdi,0x30(%rsp)
  test   %rax,%rax
  je     L63
  mov    0x40(%rsp),%rdi
  movq   $0x0,(%rsp)
  xor    %r15d,%r15d
  mov    %r14,%r13
  mov    %r15,%r12
  lea    -0x8(%rdi,%rax,8),%rax
  mov    %rax,0x38(%rsp)
  nopw   0x0(%rax,%rax,1)
L21:
  mov    0x18(%rsp),%rcx
  mov    0x10(%rsp),%rax
  xor    %edx,%edx
  mov    0x30(%rsp),%r14
  imul   (%rcx,%r12,8),%rax
  divq   0x28(%rsp)
  mov    0x38(%rsp),%rax
  mov    %rdx,%rbp
  mov    (%rsp),%rdx
  lea    (%rax,%rdx,8),%r15
  xor    %eax,%eax
  jmp    L16
  nop
L77:
  sub    $0x1,%r14
  sub    $0x8,%r15
  cmp    $0xffffffffffffffff,%r14
  je     L53
L16:
  mov    0x0(%r13,%r14,8),%rsi
  lea    (%rsi,%rax,1),%rbx
  cmp    %rbp,%rbx
  ja     L77
  mov    %r14,%rcx
  mov    %r12,%rdx
  lea    D7(%rip),%rdi
  call   <printf@plt>
  movq   $0x1,(%r15)
  cmp    %rbp,%rbx
  je     L53
  sub    $0x1,%r14
  mov    %rbx,%rax
  sub    $0x8,%r15
  cmp    $0xffffffffffffffff,%r14
  jne    L16
L53:
  mov    0x8(%rsp),%rcx
  add    $0x1,%r12
  add    %rcx,(%rsp)
  cmp    %r12,0x20(%rsp)
  jne    L21
L63:
  mov    0x90(%rsp),%rax
  mov    0x40(%rsp),%rdi
  mov    %rdi,(%rax)
  mov    0x98(%rsp),%rax
  mov    0x48(%rsp),%rdi
  mov    %rdi,(%rax)
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
datatype: string

tool: D7: tmp: %d; i: %d; j: %d


assistant: ```c
void decrypt_str(const size_t *private_key, const size_t private_key_size, const size_t *str, const size_t str_size, const size_t n, const size_t m, size_t **decrypted_str, size_t *decrypted_str_size) {
  size_t size = str_size * private_key_size;
  size_t *p = (size_t *)calloc(size, (sizeof *decrypted_str));
  size_t x = (2 * n) - 1;
  size_t i;
  size_t j;
  size_t sum;
  size_t res;
  size_t tmp;
  for (i = 0; i < str_size; i++) {
    sum = (str[i] * x) % m;
    res = 0;
    j = private_key_size;
    for (; j-- != 0;) {
      tmp = private_key[j];
      if (res + tmp <= sum) {
        res += tmp;
        printf("tmp: %d; i: %d; j: %d\n", tmp, i, j);
        p[(i * private_key_size) + j] = 1;
        if (res == sum) {
          break;
        }
      }
    }
  }
  *decrypted_str = (size_t *)p;
  *decrypted_str_size = size;
}
```
user: Translate the below assembly code into C programming language:

```asm
<yyproto_list_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <yyproto_list_head@plt>
  mov    %rax,-0x10(%rbp)
  jmp    L5
L8:
  addq   $0x1,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <yyproto_list_next@plt>
  mov    %rax,-0x10(%rbp)
L5:
  cmpq   $0x0,-0x10(%rbp)
  jne    L8
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
size_t yyproto_list_length(const struct yyproto_list *list) {
  struct yyproto_value *v;
  size_t len = 0;
  for (v = yyproto_list_head(list); v != NULL; v = yyproto_list_next(list, v)) {
    len++;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<yyproto_list_length>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <yyproto_list_head@plt>
  test   %rax,%rax
  je     L29
  mov    %rax,%rsi
  mov    $0x0,%ebx
L13:
  add    $0x1,%rbx
  mov    %rbp,%rdi
  call   <yyproto_list_next@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L13
L23:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L29:
  mov    $0x0,%ebx
  jmp    L23
```

assistant: ```c
size_t yyproto_list_length(const struct yyproto_list *list) {
  struct yyproto_value *v;
  size_t len = 0;
  for (v = yyproto_list_head(list); v != NULL; v = yyproto_list_next(list, v)) {
    len++;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<yyproto_list_length>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <yyproto_list_head@plt>
  test   %rax,%rax
  je     L14
  mov    %rax,%rsi
  xor    %r12d,%r12d
  xchg   %ax,%ax
L9:
  mov    %rbx,%rdi
  add    $0x1,%r12
  call   <yyproto_list_next@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L9
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L14:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
size_t yyproto_list_length(const struct yyproto_list *list) {
  struct yyproto_value *v;
  size_t len = 0;
  for (v = yyproto_list_head(list); v != NULL; v = yyproto_list_next(list, v)) {
    len++;
  }
  return len;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yyproto_list_length>:
  endbr64
  push   %r12
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <yyproto_list_head@plt>
  test   %rax,%rax
  je     L15
  mov    %rax,%rsi
  xor    %r12d,%r12d
  xchg   %ax,%ax
L8:
  mov    %rbx,%rdi
  add    $0x1,%r12
  call   <yyproto_list_next@plt>
  mov    %rax,%rsi
  test   %rax,%rax
  jne    L8
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nop
L15:
  xor    %r12d,%r12d
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
size_t yyproto_list_length(const struct yyproto_list *list) {
  struct yyproto_value *v;
  size_t len = 0;
  for (v = yyproto_list_head(list); v != NULL; v = yyproto_list_next(list, v)) {
    len++;
  }
  return len;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<basSqlGetText>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <wrapsqlcoltext@plt>
  mov    %eax,%edi
  call   <pushStringCopy@plt>
  nop
  leave
  ret
```

assistant: ```c
void basSqlGetText() {
  int n, col;
  col = popNumber();
  n = popNumber();
  pushStringCopy(wrapsqlcoltext(n, col));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<basSqlGetText>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <popNumber@plt>
  mov    %eax,%edi
  mov    %ebx,%esi
  call   <wrapsqlcoltext@plt>
  mov    %eax,%edi
  call   <pushStringCopy@plt>
  pop    %rbx
  ret
```

assistant: ```c
void basSqlGetText() {
  int n, col;
  col = popNumber();
  n = popNumber();
  pushStringCopy(wrapsqlcoltext(n, col));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<basSqlGetText>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <wrapsqlcoltext@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <pushStringCopy@plt>
```

assistant: ```c
void basSqlGetText() {
  int n, col;
  col = popNumber();
  n = popNumber();
  pushStringCopy(wrapsqlcoltext(n, col));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<basSqlGetText>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %eax,%ebp
  xor    %eax,%eax
  call   <popNumber@plt>
  mov    %ebp,%esi
  mov    %eax,%edi
  call   <wrapsqlcoltext@plt>
  pop    %rbp
  mov    %eax,%edi
  jmp    1070 <pushStringCopy@plt>
```

assistant: ```c
void basSqlGetText() {
  int n, col;
  col = popNumber();
  n = popNumber();
  pushStringCopy(wrapsqlcoltext(n, col));
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<susp_cmd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <term_cmd_mode_set@plt>
  mov    $0x0,%eax
  call   <term_state_save@plt>
  mov    $0x0,%edi
  call   <term_conn_mode_set@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int susp_cmd(void) {
  term_cmd_mode_set();
  term_state_save();
  term_conn_mode_set(0);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<susp_cmd>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <term_cmd_mode_set@plt>
  mov    $0x0,%eax
  call   <term_state_save@plt>
  mov    $0x0,%edi
  call   <term_conn_mode_set@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int susp_cmd(void) {
  term_cmd_mode_set();
  term_state_save();
  term_conn_mode_set(0);
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<susp_cmd>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <term_cmd_mode_set@plt>
  xor    %eax,%eax
  call   <term_state_save@plt>
  xor    %edi,%edi
  call   <term_conn_mode_set@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int susp_cmd(void) {
  term_cmd_mode_set();
  term_state_save();
  term_conn_mode_set(0);
  return 1;
}
```
user: What is the c source code of the assembly code below:

```asm
<susp_cmd>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <term_cmd_mode_set@plt>
  xor    %eax,%eax
  call   <term_state_save@plt>
  xor    %edi,%edi
  call   <term_conn_mode_set@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int susp_cmd(void) {
  term_cmd_mode_set();
  term_state_save();
  term_conn_mode_set(0);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_escaped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L20:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L23
  addl   $0x1,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L23:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jl     L20
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int count_escaped(char *buf, int len) {
  int cnt = 0;
  int i = 0;
  while (i < len - 1) {
    if (buf[i] == '\\') {
      cnt++;
      i++;
    }
    i++;
  }
  return cnt;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<count_escaped>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L24
  mov    $0x0,%eax
  mov    $0x0,%ecx
  jmp    L35
L38:
  add    $0x1,%eax
  cmp    %esi,%eax
  jge    L6
L35:
  movslq %eax,%rdx
  cmpb   $0x5c,(%rdi,%rdx,1)
  jne    L38
  add    $0x1,%ecx
  add    $0x1,%eax
  jmp    L38
L24:
  mov    $0x0,%ecx
L6:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int count_escaped(char *buf, int len) {
  int cnt = 0;
  int i = 0;
  while (i < len - 1) {
    if (buf[i] == '\\') {
      cnt++;
      i++;
    }
    i++;
  }
  return cnt;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<count_escaped>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L1
  xor    %eax,%eax
  xor    %r8d,%r8d
L6:
  movslq %eax,%rdx
  cmpb   $0x5c,(%rdi,%rdx,1)
  jne    L22
  add    $0x1,%eax
  add    $0x1,%r8d
L22:
  add    $0x1,%eax
  cmp    %esi,%eax
  jl     L6
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_escaped(char *buf, int len) {
  int cnt = 0;
  int i = 0;
  while (i < len - 1) {
    if (buf[i] == '\\') {
      cnt++;
      i++;
    }
    i++;
  }
  return cnt;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<count_escaped>:
  endbr64
  sub    $0x1,%esi
  test   %esi,%esi
  jle    L39
  xor    %eax,%eax
  xor    %r8d,%r8d
L21:
  movslq %eax,%rdx
  cmpb   $0x5c,(%rdi,%rdx,1)
  je     L24
  add    $0x1,%eax
  cmp    %eax,%esi
  jg     L21
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L24:
  add    $0x2,%eax
  add    $0x1,%r8d
  cmp    %eax,%esi
  jg     L21
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L39:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int count_escaped(char *buf, int len) {
  int cnt = 0;
  int i = 0;
  while (i < len - 1) {
    if (buf[i] == '\\') {
      cnt++;
      i++;
    }
    i++;
  }
  return cnt;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x8c0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28c0(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x28c0(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x28bc(%rbp)
  lea    -0x2720(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x2720(%rbp),%rax
  lea    D15(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    %rax,-0x28b8(%rbp)
  mov    -0x28b8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x28bc(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x28b0(%rbp,%rdx,4)
  jmp    L12
L55:
  lea    D15(%rip),%rax
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  mov    %rax,-0x28b8(%rbp)
  cmpq   $0x0,-0x28b8(%rbp)
  je     L12
  subl   $0x1,-0x28bc(%rbp)
  mov    -0x28b8(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    -0x28bc(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x28b0(%rbp,%rdx,4)
L12:
  cmpq   $0x0,-0x28b8(%rbp)
  jne    L55
  movl   $0x0,-0x28bc(%rbp)
  jmp    L5
L59:
  mov    -0x28bc(%rbp),%eax
  cltq
  mov    -0x28b0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x28c0(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x28bc(%rbp)
  je     L14
  mov    $0x20,%edi
  call   <putchar@plt>
L14:
  addl   $0x1,-0x28bc(%rbp)
L5:
  mov    -0x28c0(%rbp),%eax
  cmp    %eax,-0x28bc(%rbp)
  jl     L59
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D14
type: string
name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D10
type: string

tool: D14: %d


tool: D15:  

tool: D10: %d

assistant: ```c
int main() {
  int n, i;
  int nums[100];
  char str[10000];
  char *p;
  scanf("%d\n", &n);
  i = n - 1;
  gets(str);
  p = strtok(str, " ");
  nums[i] = atoi(p);
  while (p != NULL) {
    p = strtok(NULL, " ");
    if (p != NULL) {
      i--;
      nums[i] = atoi(p);
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d", nums[i]);
    if (i != n - 1)
      printf(" ");
  }
  printf("\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x8c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%ebp
  lea    0x1a0(%rsp),%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  lea    D28(%rip),%rsi
  mov    %rbx,%rdi
  call   <strtok@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  lea    -0x1(%rbp),%eax
  cltq
  mov    %edx,0x10(%rsp,%rax,4)
  test   %rbx,%rbx
  je     L6
  movslq %ebp,%rbp
  lea    0x10(%rsp,%rbp,4),%rbx
  lea    D28(%rip),%rbp
L12:
  mov    %rbp,%rsi
  mov    $0x0,%edi
  call   <strtok@plt>
  sub    $0x4,%rbx
  test   %rax,%rax
  je     L6
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x4(%rbx)
  jmp    L12
L6:
  cmpl   $0x0,0xc(%rsp)
  jle    L58
  mov    $0x0,%ebx
  lea    D27(%rip),%rbp
  jmp    L52
L29:
  add    $0x1,%rbx
  cmp    %ebx,0xc(%rsp)
  jle    L58
L52:
  mov    0x10(%rsp,%rbx,4),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  sub    $0x1,%eax
  cmp    %ebx,%eax
  je     L29
  mov    $0x20,%edi
  call   <putchar@plt>
  jmp    L29
L58:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x28c8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D37
data_type: string
name: read_data
arguments: data_tag: D28
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D37: %d


tool: D28:  

tool: D27: %d

assistant: ```c
int main() {
  int n, i;
  int nums[100];
  char str[10000];
  char *p;
  scanf("%d\n", &n);
  i = n - 1;
  gets(str);
  p = strtok(str, " ");
  nums[i] = atoi(p);
  while (p != NULL) {
    p = strtok(NULL, " ");
    if (p != NULL) {
      i--;
      nums[i] = atoi(p);
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d", nums[i]);
    if (i != n - 1)
      printf(" ");
  }
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0x8c8,%rsp
  lea    D15(%rip),%rdi
  lea    D3(%rip),%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x28b8(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x1a0(%rsp),%r13
  call   <scanf@plt>
  mov    %r13,%rdi
  movslq 0xc(%rsp),%r12
  call   <gets@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <strtok@plt>
  mov    %rax,%rdi
  mov    %rax,%rbx
  call   <atoi@plt>
  mov    %eax,%r8d
  lea    -0x1(%r12),%eax
  cltq
  mov    %r8d,0x10(%rsp,%rax,4)
  test   %rbx,%rbx
  je     L49
  lea    0x10(%rsp,%r12,4),%rbx
  nopl   0x0(%rax,%rax,1)
L24:
  xor    %edi,%edi
  mov    %rbp,%rsi
  sub    $0x4,%rbx
  call   <strtok@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L49
  call   <atoi@plt>
  mov    %eax,-0x4(%rbx)
  jmp    L24
L49:
  mov    0xc(%rsp),%eax
  xor    %ebx,%ebx
  lea    0x10(%rsp),%r12
  lea    D14(%rip),%rbp
  test   %eax,%eax
  jle    L48
L63:
  mov    (%r12,%rbx,4),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  cmp    %ebx,%edx
  je     L52
  mov    $0x20,%edi
  call   <putchar@plt>
  mov    0xc(%rsp),%eax
L52:
  add    $0x1,%rbx
  cmp    %ebx,%eax
  jg     L63
L48:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L22
  add    $0x28c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_guessed: string
name: unpack_data
arguments: data_label: D3
type_guessed: string
name: unpack_data
arguments: data_label: D14
type_guessed: string

tool: D15: %d


tool: D3:  

tool: D14: %d

assistant: ```c
int main() {
  int n, i;
  int nums[100];
  char str[10000];
  char *p;
  scanf("%d\n", &n);
  i = n - 1;
  gets(str);
  p = strtok(str, " ");
  nums[i] = atoi(p);
  while (p != NULL) {
    p = strtok(NULL, " ");
    if (p != NULL) {
      i--;
      nums[i] = atoi(p);
    }
  }
  for (i = 0; i < n; i++) {
    printf("%d", nums[i]);
    if (i != n - 1)
      printf(" ");
  }
  printf("\n");
  return 0;
}
```