ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<pcg_unique_64_xsh_rr_32_boundedrand_r>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %esi,%eax
  neg    %eax
  cltd
  idiv   %esi
  mov    %edx,%ebp
L2:
  mov    %rbx,%rdi
  call   <pcg_unique_64_xsh_rr_32_random_r@plt>
  cmp    %eax,%ebp
  jg     L2
  cltd
  idiv   %r12d
  mov    %edx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
uint32_t pcg_unique_64_xsh_rr_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_unique_64_xsh_rr_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pcg_unique_64_xsh_rr_32_boundedrand_r>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r12d
  neg    %eax
  push   %rbp
  cltd
  push   %rbx
  mov    %rdi,%rbx
  idiv   %esi
  mov    %edx,%ebp
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rbx,%rdi
  call   <pcg_unique_64_xsh_rr_32_random_r@plt>
  cmp    %eax,%ebp
  jg     L7
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t pcg_unique_64_xsh_rr_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_unique_64_xsh_rr_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pcg_unique_64_xsh_rr_32_boundedrand_r>:
  endbr64
  mov    %esi,%eax
  push   %r12
  mov    %esi,%r12d
  neg    %eax
  push   %rbp
  cltd
  push   %rbx
  mov    %rdi,%rbx
  idiv   %esi
  mov    %edx,%ebp
  nopw   0x0(%rax,%rax,1)
L3:
  mov    %rbx,%rdi
  call   <pcg_unique_64_xsh_rr_32_random_r@plt>
  cmp    %eax,%ebp
  jg     L3
  cltd
  pop    %rbx
  pop    %rbp
  idiv   %r12d
  pop    %r12
  mov    %edx,%eax
  ret
```

assistant: ```c
uint32_t pcg_unique_64_xsh_rr_32_boundedrand_r(struct pcg_state_64 *rng, uint32_t bound) {
  uint32_t threshold = -bound % bound;
  for (;;) {
    uint32_t r = pcg_unique_64_xsh_rr_32_random_r(rng);
    if (r >= threshold)
      return r % bound;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <maxi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <maxi@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    -0xc(%rbp),%esi
  mov    %esi,%r8d
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D1
data_type: string
name: extract_symbolic_data
arguments: tag: D18
data_type: string
name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D1: Please input three numbers:

tool: D18: %d%d%d

tool: D2: the maximum number of %d, %d, %d is %d


assistant: ```c
int main() {
  int a, b, c;
  int max;
  printf("Please input three numbers:");
  scanf("%d%d%d", &a, &b, &c);
  max = maxi(a, b);
  max = maxi(max, c);
  printf("the maximum number of %d, %d, %d is %d\n", a, b, c, max);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D25(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <maxi@plt>
  mov    %eax,%edi
  mov    0x14(%rsp),%esi
  call   <maxi@plt>
  mov    %eax,%r8d
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  mov    0xc(%rsp),%esi
  lea    D29(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D12
datatype: string
name: extract_symbolic_data
arguments: data_tag: D25
datatype: string
name: extract_symbolic_data
arguments: data_tag: D29
datatype: string

tool: D12: Please input three numbers:

tool: D25: %d%d%d

tool: D29: the maximum number of %d, %d, %d is %d


assistant: ```c
int main() {
  int a, b, c;
  int max;
  printf("Please input three numbers:");
  scanf("%d%d%d", &a, &b, &c);
  max = maxi(a, b);
  max = maxi(max, c);
  printf("the maximum number of %d, %d, %d is %d\n", a, b, c, max);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D7(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <maxi@plt>
  mov    0x14(%rsp),%esi
  mov    %eax,%edi
  call   <maxi@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D8(%rip),%rdi
  mov    0xc(%rsp),%esi
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D7
data_type: string
name: disassemble_data
arguments: tag: D8
data_type: string

tool: D19: Please input three numbers:

tool: D7: %d%d%d

tool: D8: the maximum number of %d, %d, %d is %d


assistant: ```c
int main() {
  int a, b, c;
  int max;
  printf("Please input three numbers:");
  scanf("%d%d%d", &a, &b, &c);
  max = maxi(a, b);
  max = maxi(max, c);
  printf("the maximum number of %d, %d, %d is %d\n", a, b, c, max);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D2(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%esi
  mov    0xc(%rsp),%edi
  call   <maxi@plt>
  mov    0x14(%rsp),%esi
  mov    %eax,%edi
  call   <maxi@plt>
  mov    0x14(%rsp),%ecx
  mov    0x10(%rsp),%edx
  lea    D14(%rip),%rdi
  mov    0xc(%rsp),%esi
  mov    %eax,%r8d
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D2
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D14
type: string

tool: D2: Please input three numbers:

tool: D15: %d%d%d

tool: D14: the maximum number of %d, %d, %d is %d


assistant: ```c
int main() {
  int a, b, c;
  int max;
  printf("Please input three numbers:");
  scanf("%d%d%d", &a, &b, &c);
  max = maxi(a, b);
  max = maxi(max, c);
  printf("the maximum number of %d, %d, %d is %d\n", a, b, c, max);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<WatchdogResetEnable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x8,%eax
  cltq
  mov    (%rax),%eax
  mov    -0x4(%rbp),%edx
  add    $0x8,%edx
  movslq %edx,%rdx
  or     $0x2,%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<WatchdogResetEnable>:
  endbr64
  add    $0x8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x2,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: What is the c source code of the assembly code below?

```asm
<WatchdogResetEnable>:
  endbr64
  add    $0x8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x2,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<WatchdogResetEnable>:
  endbr64
  add    $0x8,%edi
  movslq %edi,%rdi
  mov    (%rdi),%eax
  or     $0x2,%eax
  mov    %eax,(%rdi)
  ret
```

assistant: ```c
void WatchdogResetEnable(uint32_t ui32Base) {
  ;
  (*((volatile uint32_t *)(ui32Base + 0x00000008))) |= 0x00000002;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<stack_impl_ops_is_full>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: stack_impl::is_full()


assistant: ```c
int stack_impl_ops_is_full(struct stack_impl *stack_impl) {
  printf("stack_impl::is_full()\n");
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stack_impl_ops_is_full>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_infered: string

tool: D6: stack_impl::is_full()


assistant: ```c
int stack_impl_ops_is_full(struct stack_impl *stack_impl) {
  printf("stack_impl::is_full()\n");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stack_impl_ops_is_full>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D6
data_type: string

tool: D6: stack_impl::is_full()


assistant: ```c
int stack_impl_ops_is_full(struct stack_impl *stack_impl) {
  printf("stack_impl::is_full()\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stack_impl_ops_is_full>:
  endbr64
  sub    $0x8,%rsp
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D1
datatype: string

tool: D1: stack_impl::is_full()


assistant: ```c
int stack_impl_ops_is_full(struct stack_impl *stack_impl) {
  printf("stack_impl::is_full()\n");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__gluMakeIdentityd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x10,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x20,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x14,%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x24,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x34,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x18,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x28,%rax
  movl   $0x1,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x38,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0xc,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x1c,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x2c,%rax
  movl   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x3c,%rax
  movl   $0x1,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void __gluMakeIdentityd(GLdouble m[16]) {
  m[0 + 4 * 0] = 1;
  m[0 + 4 * 1] = 0;
  m[0 + 4 * 2] = 0;
  m[0 + 4 * 3] = 0;
  m[1 + 4 * 0] = 0;
  m[1 + 4 * 1] = 1;
  m[1 + 4 * 2] = 0;
  m[1 + 4 * 3] = 0;
  m[2 + 4 * 0] = 0;
  m[2 + 4 * 1] = 0;
  m[2 + 4 * 2] = 1;
  m[2 + 4 * 3] = 0;
  m[3 + 4 * 0] = 0;
  m[3 + 4 * 1] = 0;
  m[3 + 4 * 2] = 0;
  m[3 + 4 * 3] = 1;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<__gluMakeIdentityd>:
  endbr64
  movl   $0x1,(%rdi)
  movl   $0x0,0x10(%rdi)
  movl   $0x0,0x20(%rdi)
  movl   $0x0,0x30(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x1,0x14(%rdi)
  movl   $0x0,0x24(%rdi)
  movl   $0x0,0x34(%rdi)
  movl   $0x0,0x8(%rdi)
  movl   $0x0,0x18(%rdi)
  movl   $0x1,0x28(%rdi)
  movl   $0x0,0x38(%rdi)
  movl   $0x0,0xc(%rdi)
  movl   $0x0,0x1c(%rdi)
  movl   $0x0,0x2c(%rdi)
  movl   $0x1,0x3c(%rdi)
  ret
```

assistant: ```c
void __gluMakeIdentityd(GLdouble m[16]) {
  m[0 + 4 * 0] = 1;
  m[0 + 4 * 1] = 0;
  m[0 + 4 * 2] = 0;
  m[0 + 4 * 3] = 0;
  m[1 + 4 * 0] = 0;
  m[1 + 4 * 1] = 1;
  m[1 + 4 * 2] = 0;
  m[1 + 4 * 3] = 0;
  m[2 + 4 * 0] = 0;
  m[2 + 4 * 1] = 0;
  m[2 + 4 * 2] = 1;
  m[2 + 4 * 3] = 0;
  m[3 + 4 * 0] = 0;
  m[3 + 4 * 1] = 0;
  m[3 + 4 * 2] = 0;
  m[3 + 4 * 3] = 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__gluMakeIdentityd>:
  endbr64
  movabs $0x100000000,%rax
  movq   $0x1,(%rdi)
  movq   $0x0,0x8(%rdi)
  mov    %rax,0x10(%rdi)
  movq   $0x0,0x18(%rdi)
  movq   $0x0,0x20(%rdi)
  movq   $0x1,0x28(%rdi)
  movq   $0x0,0x30(%rdi)
  mov    %rax,0x38(%rdi)
  ret
```

assistant: ```c
void __gluMakeIdentityd(GLdouble m[16]) {
  m[0 + 4 * 0] = 1;
  m[0 + 4 * 1] = 0;
  m[0 + 4 * 2] = 0;
  m[0 + 4 * 3] = 0;
  m[1 + 4 * 0] = 0;
  m[1 + 4 * 1] = 1;
  m[1 + 4 * 2] = 0;
  m[1 + 4 * 3] = 0;
  m[2 + 4 * 0] = 0;
  m[2 + 4 * 1] = 0;
  m[2 + 4 * 2] = 1;
  m[2 + 4 * 3] = 0;
  m[3 + 4 * 0] = 0;
  m[3 + 4 * 1] = 0;
  m[3 + 4 * 2] = 0;
  m[3 + 4 * 3] = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__gluMakeIdentityd>:
  endbr64
  movdqa D29(%rip),%xmm0
  movups %xmm0,(%rdi)
  movdqa D10(%rip),%xmm0
  movups %xmm0,0x10(%rdi)
  movdqa D8(%rip),%xmm0
  movups %xmm0,0x20(%rdi)
  movdqa D31(%rip),%xmm0
  movups %xmm0,0x30(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D29
type_infered: byte[16]
name: disassemble_data
arguments: tag: D10
type_infered: byte[16]
name: disassemble_data
arguments: tag: D8
type_infered: byte[16]
name: disassemble_data
arguments: tag: D31
type_infered: byte[16]

tool: {"D29": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D10": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D31": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void __gluMakeIdentityd(GLdouble m[16]) {
  m[0 + 4 * 0] = 1;
  m[0 + 4 * 1] = 0;
  m[0 + 4 * 2] = 0;
  m[0 + 4 * 3] = 0;
  m[1 + 4 * 0] = 0;
  m[1 + 4 * 1] = 1;
  m[1 + 4 * 2] = 0;
  m[1 + 4 * 3] = 0;
  m[2 + 4 * 0] = 0;
  m[2 + 4 * 1] = 0;
  m[2 + 4 * 2] = 1;
  m[2 + 4 * 3] = 0;
  m[3 + 4 * 0] = 0;
  m[3 + 4 * 1] = 0;
  m[3 + 4 * 2] = 0;
  m[3 + 4 * 3] = 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
  movl   $0xa,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  je     L18
  mov    $0x2,%eax
  jmp    L19
L18:
  mov    $0x0,%eax
L19:
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int a = 0;
  if (0) {
    return 1;
  } else {
    a = 10;
  }
  if (a != 10)
    return 2;
  else {
    if (0)
      if (1)
        return 4;
      else
        return 5;
    return 0;
  }
  return 6;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  if (0) {
    return 1;
  } else {
    a = 10;
  }
  if (a != 10)
    return 2;
  else {
    if (0)
      if (1)
        return 4;
      else
        return 5;
    return 0;
  }
  return 6;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  if (0) {
    return 1;
  } else {
    a = 10;
  }
  if (a != 10)
    return 2;
  else {
    if (0)
      if (1)
        return 4;
      else
        return 5;
    return 0;
  }
  return 6;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main() {
  int a = 0;
  if (0) {
    return 1;
  } else {
    a = 10;
  }
  if (a != 10)
    return 2;
  else {
    if (0)
      if (1)
        return 4;
      else
        return 5;
    return 0;
  }
  return 6;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ft_strsplit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,%eax
  mov    %al,-0x2c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_cnt_parts@plt>
  mov    %eax,-0x20(%rbp)
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_cnt_parts@plt>
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L12
  mov    $0x0,%eax
  jmp    L68
L26:
  addq   $0x1,-0x28(%rbp)
L32:
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x2c(%rbp)
  jne    L13
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L26
L13:
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_wlen@plt>
  mov    %eax,%edx
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <ft_strsub@plt>
  mov    %rax,(%rbx)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L40
  mov    $0x0,%eax
  jmp    L68
L40:
  movsbl -0x2c(%rbp),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <ft_wlen@plt>
  cltq
  add    %rax,-0x28(%rbp)
  addl   $0x1,-0x1c(%rbp)
L12:
  mov    -0x20(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  test   %eax,%eax
  jne    L32
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
L68:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **ft_strsplit(char const *s, char c) {
  char **t;
  int nb_word;
  int index;
  index = 0;
  nb_word = ft_cnt_parts((const char *)s, c);
  t = (char **)malloc(sizeof(*t) * (ft_cnt_parts((const char *)s, c) + 1));
  if (t == NULL)
    return (NULL);
  while (nb_word--) {
    while (*s == c && *s != '\0')
      s++;
    t[index] = ft_strsub((const char *)s, 0, ft_wlen((const char *)s, c));
    if (t[index] == NULL)
      return (NULL);
    s = s + ft_wlen(s, c);
    index++;
  }
  t[index] = NULL;
  return (t);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strsplit>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  movsbl %sil,%r13d
  mov    %r13d,%esi
  call   <ft_cnt_parts@plt>
  mov    %eax,%r14d
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <ft_cnt_parts@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L0
  mov    %rax,%rcx
  test   %r14d,%r14d
  je     L58
  mov    %rax,%r12
  lea    -0x1(%r14),%eax
  lea    0x8(%rcx,%rax,8),%r15
  mov    $0x0,%r14d
  jmp    L57
L50:
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <ft_wlen@plt>
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <ft_strsub@plt>
  mov    %rax,(%r12)
  test   %rax,%rax
  je     L12
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <ft_wlen@plt>
  cltq
  add    %rax,%rbx
  add    $0x1,%r14d
  add    $0x8,%r12
  cmp    %r15,%r12
  je     L58
L57:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L50
  cmp    %al,%bpl
  jne    L50
L68:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L50
  cmp    %bpl,%al
  je     L68
  jmp    L50
L58:
  movslq %r14d,%r14
  mov    0x8(%rsp),%rax
  movq   $0x0,(%rax,%r14,8)
L12:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  mov    $0x0,%eax
  jmp    L12
```

assistant: ```c
char **ft_strsplit(char const *s, char c) {
  char **t;
  int nb_word;
  int index;
  index = 0;
  nb_word = ft_cnt_parts((const char *)s, c);
  t = (char **)malloc(sizeof(*t) * (ft_cnt_parts((const char *)s, c) + 1));
  if (t == NULL)
    return (NULL);
  while (nb_word--) {
    while (*s == c && *s != '\0')
      s++;
    t[index] = ft_strsub((const char *)s, 0, ft_wlen((const char *)s, c));
    if (t[index] == NULL)
      return (NULL);
    s = s + ft_wlen(s, c);
    index++;
  }
  t[index] = NULL;
  return (t);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ft_strsplit>:
  endbr64
  push   %r15
  mov    %esi,%r15d
  push   %r14
  push   %r13
  push   %r12
  movsbl %sil,%r12d
  push   %rbp
  mov    %r12d,%esi
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  call   <ft_cnt_parts@plt>
  mov    %r12d,%esi
  mov    %rbx,%rdi
  mov    %eax,%r13d
  call   <ft_cnt_parts@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,0x8(%rsp)
  test   %rax,%rax
  je     L53
  mov    0x8(%rsp),%rax
  test   %r13d,%r13d
  je     L91
  mov    0x8(%rsp),%rcx
  lea    -0x1(%r13),%eax
  xor    %r13d,%r13d
  mov    %rcx,%rbp
  lea    0x8(%rcx,%rax,8),%r14
  xchg   %ax,%ax
L2:
  movzbl (%rbx),%eax
  test   %al,%al
  je     L63
  cmp    %al,%r15b
  je     L58
  jmp    L63
  xchg   %ax,%ax
L90:
  cmp    %r15b,%al
  jne    L63
L58:
  movzbl 0x1(%rbx),%eax
  add    $0x1,%rbx
  test   %al,%al
  jne    L90
L63:
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <ft_wlen@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  mov    %eax,%edx
  call   <ft_strsub@plt>
  mov    %rax,0x0(%rbp)
  test   %rax,%rax
  je     L53
  mov    %rbx,%rdi
  mov    %r12d,%esi
  add    $0x8,%rbp
  add    $0x1,%r13d
  call   <ft_wlen@plt>
  cltq
  add    %rax,%rbx
  cmp    %rbp,%r14
  jne    L2
  mov    0x8(%rsp),%rax
  movslq %r13d,%r13
  lea    (%rax,%r13,8),%rax
L91:
  movq   $0x0,(%rax)
  jmp    L61
L53:
  movq   $0x0,0x8(%rsp)
L61:
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
char **ft_strsplit(char const *s, char c) {
  char **t;
  int nb_word;
  int index;
  index = 0;
  nb_word = ft_cnt_parts((const char *)s, c);
  t = (char **)malloc(sizeof(*t) * (ft_cnt_parts((const char *)s, c) + 1));
  if (t == NULL)
    return (NULL);
  while (nb_word--) {
    while (*s == c && *s != '\0')
      s++;
    t[index] = ft_strsub((const char *)s, 0, ft_wlen((const char *)s, c));
    if (t[index] == NULL)
      return (NULL);
    s = s + ft_wlen(s, c);
    index++;
  }
  t[index] = NULL;
  return (t);
}
```