ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  lea    D18(%rip),%rbp
  push   %rbx
  mov    $0x3e8,%ebx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rdi
  call   <gettimeofday@plt>
  nopw   0x0(%rax,%rax,1)
L7:
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  jne    L7
  lea    0x10(%rsp),%rdi
  xor    %esi,%esi
  mov    $0x3e8,%ebx
  call   <gettimeofday@plt>
  lea    0x18(%rsp),%rdi
  xor    %esi,%esi
  call   <gettimeofday@plt>
  nopl   0x0(%rax)
L1:
  mov    $0x6,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  sub    $0x1,%ebx
  jne    L1
  xor    %esi,%esi
  lea    0x20(%rsp),%rdi
  call   <gettimeofday@plt>
  imul   $0xf4240,0x20(%rsp),%edx
  add    0x24(%rsp),%edx
  lea    D2(%rip),%rdi
  imul   $0xf4240,0x18(%rsp),%eax
  add    0x1c(%rsp),%eax
  movslq %edx,%rdx
  cltq
  imul   $0xf4240,0x10(%rsp),%esi
  add    0x14(%rsp),%esi
  sub    %rax,%rdx
  imul   $0xf4240,0x8(%rsp),%eax
  add    0xc(%rsp),%eax
  movslq %esi,%rsi
  cltq
  sub    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D18
type: string
name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D18: hello

tool: D2: %ld
%ld


assistant: ```c
int main() {
  int i = 0;
  long int t1, t2, t3, t4;
  struct timeval time1;
  gettimeofday(&time1, NULL);
  for (i = 0; i < 1000; i++)
    printf("hello");
  struct timeval time2;
  gettimeofday(&time2, NULL);
  struct timeval time3;
  gettimeofday(&time3, NULL);
  for (i = 0; i < 1000; i++)
    write(1, "hello", 6);
  struct timeval time4;
  gettimeofday(&time4, NULL);
  t1 = time1.tv_sec * 1000000 + time1.tv_usec;
  t2 = time2.tv_sec * 1000000 + time2.tv_usec;
  t3 = time3.tv_sec * 1000000 + time3.tv_usec;
  t4 = time4.tv_sec * 1000000 + time4.tv_usec;
  printf("%ld\n%ld\n", t2 - t1, t4 - t3);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<tou_socket_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <tou_socket_write@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int tou_socket_puts(BIO *bp, const char *str) {
  int n, ret;
  n = strlen(str);
  ret = tou_socket_write(bp, str, n);
  return (ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<tou_socket_puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <tou_socket_write@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int tou_socket_puts(BIO *bp, const char *str) {
  int n, ret;
  n = strlen(str);
  ret = tou_socket_write(bp, str, n);
  return (ret);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<tou_socket_puts>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <tou_socket_write@plt>
```

assistant: ```c
int tou_socket_puts(BIO *bp, const char *str) {
  int n, ret;
  n = strlen(str);
  ret = tou_socket_write(bp, str, n);
  return (ret);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<tou_socket_puts>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  mov    %rbp,%rsi
  mov    %r12,%rdi
  pop    %rbp
  mov    %eax,%edx
  pop    %r12
  jmp    1060 <tou_socket_write@plt>
```

assistant: ```c
int tou_socket_puts(BIO *bp, const char *str) {
  int n, ret;
  n = strlen(str);
  ret = tou_socket_write(bp, str, n);
  return (ret);
}
```
user: Translate the below assembly code into C programming language:

```asm
<getIPbyname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <gethostbyname@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L38
  mov    D3(%rip),%rax
  movl   $0x1,(%rax)
  mov    $0x0,%eax
  jmp    L59
L38:
  movl   $0x0,-0x30(%rbp)
L27:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  addl   $0x1,-0x30(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L27
  mov    -0x30(%rbp),%eax
  mov    $0x4,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L18
  mov    D3(%rip),%rax
  movl   $0x2,(%rax)
  mov    $0x0,%eax
  jmp    L59
L18:
  subl   $0x1,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L19
L34:
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x2c(%rbp),%eax
  cltq
  shl    $0x3,%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    (%rax),%eax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %eax,%edi
  call   <ntohl@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x2c(%rbp)
L19:
  mov    -0x2c(%rbp),%eax
  cmp    -0x30(%rbp),%eax
  jl     L34
  mov    -0x18(%rbp),%rax
L59:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
unsigned long *getIPbyname(char *hostname) {
  unsigned long *IPs;
  struct hostent *hostinfo = gethostbyname(hostname);
  struct in_addr *address;
  int addrno, i;
  if (hostinfo == NULL) {
    errno = 1;
    return NULL;
  }
  addrno = 0;
  do {
    address = (struct in_addr *)hostinfo->h_addr_list[addrno];
    addrno++;
  } while (address != NULL);
  IPs = calloc(addrno, sizeof(unsigned int));
  if (IPs == NULL) {
    errno = 2;
    return NULL;
  }
  addrno--;
  for (i = 0; i < addrno; i++) {
    address = (struct in_addr *)hostinfo->h_addr_list[i];
    IPs[i] = ntohl(((struct in_addr *)hostinfo->h_addr_list[i])->s_addr);
  }
  return IPs;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<getIPbyname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <gethostbyname@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L2
  mov    (%rax),%rax
  mov    $0x0,%edi
L68:
  mov    (%rax),%rdx
  mov    %edi,%r12d
  add    $0x1,%edi
  add    $0x8,%rax
  test   %rdx,%rdx
  jne    L68
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L44
  mov    %r12d,%r14d
  shl    $0x3,%r14
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jle    L63
L20:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%rax
  mov    (%rax),%edi
  call   <ntohl@plt>
  mov    %rax,0x0(%r13,%rbx,1)
  add    $0x8,%rbx
  cmp    %r14,%rbx
  jne    L20
L63:
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L2:
  mov    D3(%rip),%rax
  movl   $0x1,(%rax)
  mov    %rbp,%r13
  jmp    L63
L44:
  mov    D3(%rip),%rax
  movl   $0x2,(%rax)
  jmp    L63
```

assistant: ```c
unsigned long *getIPbyname(char *hostname) {
  unsigned long *IPs;
  struct hostent *hostinfo = gethostbyname(hostname);
  struct in_addr *address;
  int addrno, i;
  if (hostinfo == NULL) {
    errno = 1;
    return NULL;
  }
  addrno = 0;
  do {
    address = (struct in_addr *)hostinfo->h_addr_list[addrno];
    addrno++;
  } while (address != NULL);
  IPs = calloc(addrno, sizeof(unsigned int));
  if (IPs == NULL) {
    errno = 2;
    return NULL;
  }
  addrno--;
  for (i = 0; i < addrno; i++) {
    address = (struct in_addr *)hostinfo->h_addr_list[i];
    IPs[i] = ntohl(((struct in_addr *)hostinfo->h_addr_list[i])->s_addr);
  }
  return IPs;
}
```
user: What is the c source code of the assembly code below?

```asm
<getIPbyname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L65
  mov    %rax,%r13
  mov    (%rax),%rax
  xor    %edi,%edi
  xchg   %ax,%ax
L63:
  mov    (%rax),%rdx
  mov    %edi,%r14d
  add    $0x8,%rax
  add    $0x1,%edi
  test   %rdx,%rdx
  jne    L63
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  movslq %r14d,%rbp
  xor    %ebx,%ebx
  shl    $0x3,%rbp
  test   %r14d,%r14d
  je     L56
  nopw   0x0(%rax,%rax,1)
L36:
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rax
  mov    (%rax),%edi
  call   <ntohl@plt>
  mov    %rax,(%r12,%rbx,1)
  add    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L36
L56:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L65:
  mov    D19(%rip),%rax
  xor    %r12d,%r12d
  movl   $0x1,(%rax)
  jmp    L56
L1:
  mov    D19(%rip),%rax
  movl   $0x2,(%rax)
  jmp    L56
```

assistant: ```c
unsigned long *getIPbyname(char *hostname) {
  unsigned long *IPs;
  struct hostent *hostinfo = gethostbyname(hostname);
  struct in_addr *address;
  int addrno, i;
  if (hostinfo == NULL) {
    errno = 1;
    return NULL;
  }
  addrno = 0;
  do {
    address = (struct in_addr *)hostinfo->h_addr_list[addrno];
    addrno++;
  } while (address != NULL);
  IPs = calloc(addrno, sizeof(unsigned int));
  if (IPs == NULL) {
    errno = 2;
    return NULL;
  }
  addrno--;
  for (i = 0; i < addrno; i++) {
    address = (struct in_addr *)hostinfo->h_addr_list[i];
    IPs[i] = ntohl(((struct in_addr *)hostinfo->h_addr_list[i])->s_addr);
  }
  return IPs;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<getIPbyname>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  call   <gethostbyname@plt>
  test   %rax,%rax
  je     L7
  mov    %rax,%r13
  mov    (%rax),%rax
  xor    %edi,%edi
  xchg   %ax,%ax
L65:
  mov    (%rax),%rdx
  mov    %edi,%r14d
  add    $0x8,%rax
  add    $0x1,%edi
  test   %rdx,%rdx
  jne    L65
  mov    $0x4,%esi
  call   <calloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L62
  movslq %r14d,%rbp
  xor    %ebx,%ebx
  shl    $0x3,%rbp
  test   %r14d,%r14d
  je     L15
  nopw   0x0(%rax,%rax,1)
L24:
  mov    0x0(%r13),%rax
  mov    (%rax,%rbx,1),%rax
  mov    (%rax),%edi
  call   <ntohl@plt>
  mov    %rax,(%r12,%rbx,1)
  add    $0x8,%rbx
  cmp    %rbx,%rbp
  jne    L24
L15:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L7:
  mov    D0(%rip),%rax
  xor    %r12d,%r12d
  movl   $0x1,(%rax)
  jmp    L15
L62:
  mov    D0(%rip),%rax
  movl   $0x2,(%rax)
  jmp    L15
```

assistant: ```c
unsigned long *getIPbyname(char *hostname) {
  unsigned long *IPs;
  struct hostent *hostinfo = gethostbyname(hostname);
  struct in_addr *address;
  int addrno, i;
  if (hostinfo == NULL) {
    errno = 1;
    return NULL;
  }
  addrno = 0;
  do {
    address = (struct in_addr *)hostinfo->h_addr_list[addrno];
    addrno++;
  } while (address != NULL);
  IPs = calloc(addrno, sizeof(unsigned int));
  if (IPs == NULL) {
    errno = 2;
    return NULL;
  }
  addrno--;
  for (i = 0; i < addrno; i++) {
    address = (struct in_addr *)hostinfo->h_addr_list[i];
    IPs[i] = ntohl(((struct in_addr *)hostinfo->h_addr_list[i])->s_addr);
  }
  return IPs;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movsd  D1(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <roundInt@plt>
  cmp    $0xffffffff,%eax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: byte[8]

tool: {"D1": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0xbf]}

assistant: ```c
void main() {
  double a = -0.6;
  assert(roundInt(a) == -1);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D5(%rip),%xmm0
  call   <roundInt@plt>
  cmp    $0xffffffff,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D5
datatype: byte[8]

tool: {"D5": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0xbf]}

assistant: ```c
void main() {
  double a = -0.6;
  assert(roundInt(a) == -1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D7(%rip),%xmm0
  call   <roundInt@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
datatype: byte[8]

tool: {"D7": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0xbf]}

assistant: ```c
void main() {
  double a = -0.6;
  assert(roundInt(a) == -1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movsd  D9(%rip),%xmm0
  call   <roundInt@plt>
  xor    %edi,%edi
  cmp    $0xffffffff,%eax
  sete   %dil
  add    $0x8,%rsp
  jmp    1060 <assert@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
datatype: byte[8]

tool: {"D9": [0x33,0x33,0x33,0x33,0x33,0x33,0xe3,0xbf]}

assistant: ```c
void main() {
  double a = -0.6;
  assert(roundInt(a) == -1);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<transposeMatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  cmovge %edx,%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L26
L1:
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L2
L29:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  movsd  (%rdx,%rax,8),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  movsd  (%rcx,%rax,8),%xmm0
  mov    -0x14(%rbp),%eax
  cltq
  movsd  %xmm0,(%rdx,%rax,8)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  shl    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  cltq
  movsd  -0x8(%rbp),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L29
  addl   $0x1,-0x18(%rbp)
L26:
  mov    -0x18(%rbp),%eax
  cmp    -0x10(%rbp),%eax
  jl     L1
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x38(%rbp),%rax
  mov    -0xc(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transposeMatrix(double source[][3], int *prows, int *pcols) {
  double tempElem;
  int tempDim;
  int max = (*prows > *pcols) ? *prows : *pcols;
  int i, j;
  for (i = 0; i < max; ++i) {
    for (j = i + 1; j < max; ++j) {
      tempElem = source[i][j];
      source[i][j] = source[j][i];
      source[j][i] = tempElem;
    }
  }
  tempDim = *prows;
  *prows = *pcols;
  *pcols = tempDim;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<transposeMatrix>:
  endbr64
  mov    %rsi,%r10
  mov    (%rdx),%esi
  mov    (%r10),%eax
  cmp    %eax,%esi
  cmovl  %eax,%esi
  test   %esi,%esi
  jle    L45
  mov    %rdi,%r11
  mov    $0x1,%r9d
  jmp    L25
L3:
  movsd  (%r8,%rax,8),%xmm0
  movsd  0x18(%rcx),%xmm1
  movsd  %xmm1,(%r8,%rax,8)
  movsd  %xmm0,0x18(%rcx)
  add    $0x1,%rax
  add    $0x18,%rcx
  cmp    %eax,%esi
  jg     L3
  add    $0x1,%r9
  add    $0x20,%r11
  add    $0x18,%rdi
L25:
  cmp    %r9d,%esi
  jle    L45
  mov    %rdi,%r8
  mov    %r11,%rcx
  mov    %r9,%rax
  jmp    L3
L45:
  mov    (%r10),%eax
  mov    (%rdx),%ecx
  mov    %ecx,(%r10)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void transposeMatrix(double source[][3], int *prows, int *pcols) {
  double tempElem;
  int tempDim;
  int max = (*prows > *pcols) ? *prows : *pcols;
  int i, j;
  for (i = 0; i < max; ++i) {
    for (j = i + 1; j < max; ++j) {
      tempElem = source[i][j];
      source[i][j] = source[j][i];
      source[j][i] = tempElem;
    }
  }
  tempDim = *prows;
  *prows = *pcols;
  *pcols = tempDim;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<transposeMatrix>:
  endbr64
  mov    (%rsi),%r11d
  push   %rbx
  mov    (%rdx),%ebx
  mov    %r11d,%r9d
  cmp    %r11d,%ebx
  cmovge %ebx,%r9d
  test   %r9d,%r9d
  jle    L26
  mov    $0x1,%r10d
  mov    %rdi,%r8
  cmp    %r10d,%r9d
  jle    L26
L38:
  mov    %rdi,%rcx
  mov    %r10,%rax
L17:
  movsd  0x18(%rcx),%xmm1
  movsd  (%r8,%rax,8),%xmm0
  add    $0x18,%rcx
  movsd  %xmm1,(%r8,%rax,8)
  add    $0x1,%rax
  movsd  %xmm0,(%rcx)
  cmp    %eax,%r9d
  jg     L17
  add    $0x1,%r10
  add    $0x20,%rdi
  add    $0x18,%r8
  cmp    %r10d,%r9d
  jg     L38
L26:
  mov    %ebx,(%rsi)
  pop    %rbx
  mov    %r11d,(%rdx)
  ret
```

assistant: ```c
void transposeMatrix(double source[][3], int *prows, int *pcols) {
  double tempElem;
  int tempDim;
  int max = (*prows > *pcols) ? *prows : *pcols;
  int i, j;
  for (i = 0; i < max; ++i) {
    for (j = i + 1; j < max; ++j) {
      tempElem = source[i][j];
      source[i][j] = source[j][i];
      source[j][i] = tempElem;
    }
  }
  tempDim = *prows;
  *prows = *pcols;
  *pcols = tempDim;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<transposeMatrix>:
  endbr64
  push   %r13
  mov    %rdi,%r9
  mov    %rsi,%r8
  mov    %rdx,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  mov    (%rdx),%ebp
  mov    (%rsi),%ebx
  cmp    %ebx,%ebp
  mov    %ebx,%ecx
  cmovge %ebp,%ecx
  cmp    $0x1,%ecx
  jle    L10
  lea    0x18(%r9),%rax
  mov    %r9,%rsi
  mov    $0x4,%r11d
  mov    $0x1,%edx
L46:
  movsd  -0x10(%rax),%xmm0
  movsd  (%rax),%xmm1
  lea    0x1(%rdx),%r10d
  lea    -0x1(%rdx),%r12d
  movsd  %xmm1,-0x10(%rax)
  movsd  %xmm0,(%rax)
  cmp    %ecx,%r10d
  jge    L42
  movsd  -0x8(%rax),%xmm0
  movsd  0x18(%rax),%xmm1
  add    $0x2,%edx
  movsd  %xmm1,-0x8(%rax)
  movsd  %xmm0,0x18(%rax)
  cmp    %edx,%ecx
  jle    L18
  movslq %edx,%rdx
  movslq %r12d,%r12
  lea    (%rdx,%rdx,2),%r13
  movsd  (%rsi,%rdx,8),%xmm0
  lea    (%r9,%r13,8),%r13
  movsd  0x0(%r13,%r12,8),%xmm1
  movsd  %xmm1,(%rsi,%rdx,8)
  movsd  %xmm0,0x0(%r13,%r12,8)
  cmp    %r11d,%ecx
  jle    L18
  movslq %r11d,%rdx
  mov    %rax,%r12
L61:
  movsd  0x48(%r12),%xmm1
  movsd  (%rsi,%rdx,8),%xmm0
  add    $0x18,%r12
  movsd  %xmm1,(%rsi,%rdx,8)
  add    $0x1,%rdx
  movsd  %xmm0,0x30(%r12)
  cmp    %edx,%ecx
  jg     L61
L18:
  add    $0x1,%r11d
  add    $0x20,%rax
  add    $0x18,%rsi
L6:
  mov    %r10d,%edx
  jmp    L46
L42:
  add    $0x1,%r11d
  add    $0x20,%rax
  add    $0x18,%rsi
  cmp    %ecx,%r10d
  jne    L6
L10:
  mov    %ebp,(%r8)
  mov    %ebx,(%rdi)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void transposeMatrix(double source[][3], int *prows, int *pcols) {
  double tempElem;
  int tempDim;
  int max = (*prows > *pcols) ? *prows : *pcols;
  int i, j;
  for (i = 0; i < max; ++i) {
    for (j = i + 1; j < max; ++j) {
      tempElem = source[i][j];
      source[i][j] = source[j][i];
      source[j][i] = tempElem;
    }
  }
  tempDim = *prows;
  *prows = *pcols;
  *pcols = tempDim;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x20432078756e694c,%rax
  movabs $0x617720796d207369,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movw   $0x746e,-0x10(%rbp)
  movb   $0x0,-0xe(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x7a,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <bzero@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D22
datatype: string

tool: D22: %s


assistant: ```c
int main() {
  char ch[] = "Linux C is my want";
  printf("%s\n", ch);
  memset(ch, 'z', 5);
  printf("%s\n", ch);
  bzero(ch, 5);
  printf("%s\n", ch);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x20432078756e694c,%rax
  movabs $0x617720796d207369,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movw   $0x746e,0x10(%rsp)
  movb   $0x0,0x12(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D6(%rip),%rbp
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x5,%edx
  mov    $0x7a,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbx,%rdi
  call   <bzero@plt>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type: string

tool: D6: %s


assistant: ```c
int main() {
  char ch[] = "Linux C is my want";
  printf("%s\n", ch);
  memset(ch, 'z', 5);
  printf("%s\n", ch);
  bzero(ch, 5);
  printf("%s\n", ch);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  lea    D12(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  sub    $0x28,%rsp
  movdqa D0(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x746e,%eax
  movb   $0x0,0x12(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  mov    %ax,0x10(%rsp)
  call   <printf@plt>
  mov    $0x5,%edx
  mov    $0x7a,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    $0x5,%esi
  mov    %rbp,%rdi
  call   <bzero@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_infered: string
name: extract_symbolic_data
arguments: tag: D0
type_infered: byte[16]

tool: D12: %s


tool: {"D0": [0x4c,0x69,0x6e,0x75,0x78,0x20,0x43,0x20,0x69,0x73,0x20,0x6d,0x79,0x20,0x77,0x61]}

assistant: ```c
int main() {
  char ch[] = "Linux C is my want";
  printf("%s\n", ch);
  memset(ch, 'z', 5);
  printf("%s\n", ch);
  bzero(ch, 5);
  printf("%s\n", ch);
  return 0;
}
```