ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<screentext_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L10
L20:
  mov    $0x0,%eax
  call   <update_cursor@plt>
  pop    %rbx
  ret
L18:
  mov    $0x0,%eax
  call   <screentext_newline@plt>
L24:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L20
L10:
  cmp    $0xa,%dil
  je     L18
  movsbl %dil,%edi
  call   <screentext_writecharnc@plt>
  jmp    L24
```

assistant: ```c
void screentext_print(char *c) {
  for (; *c; c++) {
    if (*c == '\n')
      screentext_newline();
    else
      screentext_writecharnc(*c);
  }
  update_cursor();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<screentext_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L21
  jmp    L45
  nopw   0x0(%rax,%rax,1)
L38:
  call   <screentext_writecharnc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L45
L21:
  cmp    $0xa,%dil
  jne    L38
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <screentext_newline@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L21
L45:
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <update_cursor@plt>
```

assistant: ```c
void screentext_print(char *c) {
  for (; *c; c++) {
    if (*c == '\n')
      screentext_newline();
    else
      screentext_writecharnc(*c);
  }
  update_cursor();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<screentext_print>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L28
L36:
  cmp    $0xa,%dil
  je     L12
  call   <screentext_writecharnc@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L36
L28:
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <update_cursor@plt>
L12:
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <screentext_newline@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L36
  xor    %eax,%eax
  pop    %rbx
  jmp    1070 <update_cursor@plt>
```

assistant: ```c
void screentext_print(char *c) {
  for (; *c; c++) {
    if (*c == '\n')
      screentext_newline();
    else
      screentext_writecharnc(*c);
  }
  update_cursor();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %rsi,-0x60(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x40(%rbp)
  movl   $0xcaa,-0x3c(%rbp)
  movl   $0x15,-0x38(%rbp)
  movl   $0x37,-0x34(%rbp)
  movl   $0x28d,-0x30(%rbp)
  movl   $0x13,-0x2c(%rbp)
  movl   $0x8b,-0x28(%rbp)
  movl   $0x1cb,-0x24(%rbp)
  movl   $0x8a,-0x20(%rbp)
  movl   $0xb125,-0x1c(%rbp)
  movl   $0x13,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0xd,-0x48(%rbp)
  mov    -0x48(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_sequence@plt>
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <insertion_sort@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <print_sequence@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x48(%rbp),%edx
  lea    -0x40(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <test_insertion_sort@plt>
  mov    %eax,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  je     L12
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L29
L12:
  lea    D27(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L29:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L24
  call   <__stack_chk_fail@plt>
L24:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type_guessed: string
name: parse_data
arguments: data_tag: D39
type_guessed: string
name: parse_data
arguments: data_tag: D36
type_guessed: string
name: parse_data
arguments: data_tag: D47
type_guessed: string
name: parse_data
arguments: data_tag: D27
type_guessed: string

tool: D0: Sorting %d values in sequence 

tool: D39: Done sorting. Result 

tool: D36: Testing if result sort is valid....

tool: D47: Yes!

tool: D27: No!

assistant: ```c
int main(int argc, char *argv[]) {
  int sequence[] = {3, 3242, 21, 55, 653, 19, 139, 459, 138, 45349, 19, 2, 1};
  int sequence_length = sizeof(sequence) / sizeof(sequence[0]);
  printf("Sorting %d values in sequence ", sequence_length);
  print_sequence(sequence, sequence_length);
  insertion_sort(sequence, sequence_length);
  printf("Done sorting. Result ");
  print_sequence(sequence, sequence_length);
  printf("Testing if result sort is valid....");
  int pass = test_insertion_sort(sequence, sequence_length);
  if (pass)
    printf("Yes!\n");
  else
    printf("No!\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movl   $0x3,(%rsp)
  movl   $0xcaa,0x4(%rsp)
  movl   $0x15,0x8(%rsp)
  movl   $0x37,0xc(%rsp)
  movl   $0x28d,0x10(%rsp)
  movl   $0x13,0x14(%rsp)
  movl   $0x8b,0x18(%rsp)
  movl   $0x1cb,0x1c(%rsp)
  movl   $0x8a,0x20(%rsp)
  movl   $0xb125,0x24(%rsp)
  movl   $0x13,0x28(%rsp)
  movl   $0x2,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  mov    $0xd,%esi
  lea    D32(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <print_sequence@plt>
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <insertion_sort@plt>
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <print_sequence@plt>
  lea    D13(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbx,%rdi
  call   <test_insertion_sort@plt>
  test   %eax,%eax
  je     L26
  lea    D30(%rip),%rdi
  call   <puts@plt>
L23:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L26:
  lea    D39(%rip),%rdi
  call   <puts@plt>
  jmp    L23
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D32
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string
name: retrieve_data
arguments: data_tag: D13
type_guessed: string
name: retrieve_data
arguments: data_tag: D30
type_guessed: string
name: retrieve_data
arguments: data_tag: D39
type_guessed: string

tool: D32: Sorting %d values in sequence 

tool: D9: Done sorting. Result 

tool: D13: Testing if result sort is valid....

tool: D30: Yes!

tool: D39: No!

assistant: ```c
int main(int argc, char *argv[]) {
  int sequence[] = {3, 3242, 21, 55, 653, 19, 139, 459, 138, 45349, 19, 2, 1};
  int sequence_length = sizeof(sequence) / sizeof(sequence[0]);
  printf("Sorting %d values in sequence ", sequence_length);
  print_sequence(sequence, sequence_length);
  insertion_sort(sequence, sequence_length);
  printf("Done sorting. Result ");
  print_sequence(sequence, sequence_length);
  printf("Testing if result sort is valid....");
  int pass = test_insertion_sort(sequence, sequence_length);
  if (pass)
    printf("Yes!\n");
  else
    printf("No!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xd,%esi
  lea    D47(%rip),%rdi
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  movabs $0xcaa00000003,%rax
  mov    %rsp,%rbp
  movl   $0x1,0x30(%rsp)
  mov    %rax,(%rsp)
  movabs $0x3700000015,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x130000028d,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x1cb0000008b,%rax
  mov    %rax,0x18(%rsp)
  movabs $0xb1250000008a,%rax
  mov    %rax,0x20(%rsp)
  movabs $0x200000013,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <print_sequence@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <insertion_sort@plt>
  lea    D43(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <print_sequence@plt>
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <test_insertion_sort@plt>
  test   %eax,%eax
  je     L11
  lea    D45(%rip),%rdi
  call   <puts@plt>
L7:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L11:
  lea    D44(%rip),%rdi
  call   <puts@plt>
  jmp    L7
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D47
data_type: string
name: read_data
arguments: tag: D43
data_type: string
name: read_data
arguments: tag: D33
data_type: string
name: read_data
arguments: tag: D45
data_type: string
name: read_data
arguments: tag: D44
data_type: string

tool: D47: Sorting %d values in sequence 

tool: D43: Done sorting. Result 

tool: D33: Testing if result sort is valid....

tool: D45: Yes!

tool: D44: No!

assistant: ```c
int main(int argc, char *argv[]) {
  int sequence[] = {3, 3242, 21, 55, 653, 19, 139, 459, 138, 45349, 19, 2, 1};
  int sequence_length = sizeof(sequence) / sizeof(sequence[0]);
  printf("Sorting %d values in sequence ", sequence_length);
  print_sequence(sequence, sequence_length);
  insertion_sort(sequence, sequence_length);
  printf("Done sorting. Result ");
  print_sequence(sequence, sequence_length);
  printf("Testing if result sort is valid....");
  int pass = test_insertion_sort(sequence, sequence_length);
  if (pass)
    printf("Yes!\n");
  else
    printf("No!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0xd,%esi
  lea    D39(%rip),%rdi
  sub    $0x40,%rsp
  movdqa D79(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x1,0x30(%rsp)
  movaps %xmm0,(%rsp)
  movdqa D41(%rip),%xmm0
  movaps %xmm0,0x10(%rsp)
  movdqa D52(%rip),%xmm0
  movaps %xmm0,0x20(%rsp)
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <print_sequence@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <insertion_sort@plt>
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <print_sequence@plt>
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xd,%esi
  mov    %rbp,%rdi
  call   <test_insertion_sort@plt>
  test   %eax,%eax
  je     L13
  lea    D74(%rip),%rdi
  call   <puts@plt>
L27:
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L25
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  lea    D8(%rip),%rdi
  call   <puts@plt>
  jmp    L27
L25:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D39
type: string
name: retrieve_data
arguments: label: D79
type: byte[16]
name: retrieve_data
arguments: label: D41
type: byte[16]
name: retrieve_data
arguments: label: D52
type: byte[16]
name: retrieve_data
arguments: label: D42
type: string
name: retrieve_data
arguments: label: D40
type: string
name: retrieve_data
arguments: label: D74
type: string
name: retrieve_data
arguments: label: D8
type: string

tool: D39: Sorting %d values in sequence 

tool: {"D79": [0x03,0x00,0x00,0x00,0xaa,0x0c,0x00,0x00,0x15,0x00,0x00,0x00,0x37,0x00,0x00,0x00]}

tool: {"D41": [0x8d,0x02,0x00,0x00,0x13,0x00,0x00,0x00,0x8b,0x00,0x00,0x00,0xcb,0x01,0x00,0x00]}

tool: {"D52": [0x8a,0x00,0x00,0x00,0x25,0xb1,0x00,0x00,0x13,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D42: Done sorting. Result 

tool: D40: Testing if result sort is valid....

tool: D74: Yes!

tool: D8: No!

assistant: ```c
int main(int argc, char *argv[]) {
  int sequence[] = {3, 3242, 21, 55, 653, 19, 139, 459, 138, 45349, 19, 2, 1};
  int sequence_length = sizeof(sequence) / sizeof(sequence[0]);
  printf("Sorting %d values in sequence ", sequence_length);
  print_sequence(sequence, sequence_length);
  insertion_sort(sequence, sequence_length);
  printf("Done sorting. Result ");
  print_sequence(sequence, sequence_length);
  printf("Testing if result sort is valid....");
  int pass = test_insertion_sort(sequence, sequence_length);
  if (pass)
    printf("Yes!\n");
  else
    printf("No!\n");
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L17:
  mov    -0x10(%rbp),%rdx
  lea    0x4(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  mov    (%rdx),%edx
  mov    %edx,(%rax)
L18:
  mov    -0x28(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  test   %rax,%rax
  jne    L17
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, size_t n) {
  uint8_t const *byte_src = (uint8_t const *)src;
  uint8_t *byte_dest = (uint8_t *)dest;
  while (n--)
    *byte_dest++ = *byte_src++;
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L2
  mov    $0x0,%ecx
L14:
  mov    (%rsi,%rcx,4),%r8d
  mov    %r8d,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L14
L2:
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, size_t n) {
  uint8_t const *byte_src = (uint8_t const *)src;
  uint8_t *byte_dest = (uint8_t *)dest;
  while (n--)
    *byte_dest++ = *byte_src++;
  return dest;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L18
  xor    %ecx,%ecx
  xchg   %ax,%ax
L5:
  mov    (%rsi,%rcx,4),%r8d
  mov    %r8d,(%rax,%rcx,4)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L5
L18:
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, size_t n) {
  uint8_t const *byte_src = (uint8_t const *)src;
  uint8_t *byte_dest = (uint8_t *)dest;
  while (n--)
    *byte_dest++ = *byte_src++;
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rdx,%rcx
  lea    -0x1(%rdx),%r9
  test   %rdx,%rdx
  je     L59
  lea    0x4(%rsi),%rdx
  mov    %rdi,%rax
  sub    %rdx,%rax
  cmp    $0x8,%rax
  jbe    L51
  cmp    $0x2,%r9
  jbe    L51
  mov    %rcx,%rdi
  xor    %eax,%eax
  xor    %edx,%edx
  shr    $0x2,%rdi
  nopl   0x0(%rax)
L48:
  movdqu (%rsi,%rax,1),%xmm0
  add    $0x1,%rdx
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rdi
  jne    L48
  mov    %rcx,%rdx
  and    $0xfffffffffffffffc,%rdx
  lea    0x0(,%rdx,4),%rax
  sub    %rdx,%r9
  add    %rax,%rsi
  add    %r8,%rax
  cmp    %rdx,%rcx
  je     L59
  mov    (%rsi),%edx
  mov    %edx,(%rax)
  test   %r9,%r9
  je     L59
  mov    0x4(%rsi),%edx
  mov    %edx,0x4(%rax)
  cmp    $0x1,%r9
  je     L59
  mov    0x8(%rsi),%edx
  mov    %edx,0x8(%rax)
L59:
  mov    %r8,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L57:
  mov    (%rsi,%rax,4),%edx
  mov    %edx,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rcx
  jne    L57
  mov    %r8,%rax
  ret
```

assistant: ```c
void *memcpy(void *dest, const void *src, size_t n) {
  uint8_t const *byte_src = (uint8_t const *)src;
  uint8_t *byte_dest = (uint8_t *)dest;
  while (n--)
    *byte_dest++ = *byte_src++;
  return dest;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  movl   $0x1,-0x30(%rbp)
  movl   $0x2,-0x2c(%rbp)
  movl   $0x3,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  movl   $0x5,-0x20(%rbp)
  movl   $0x0,-0x34(%rbp)
  jmp    L21
L43:
  mov    -0x34(%rbp),%eax
  cltq
  movl   $0x0,-0x30(%rbp,%rax,4)
  addl   $0x1,-0x34(%rbp)
L21:
  cmpl   $0x9,-0x34(%rbp)
  jle    L43
  movl   $0x0,-0x34(%rbp)
  jmp    L1
L5:
  mov    -0x34(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x34(%rbp)
L1:
  cmpl   $0x9,-0x34(%rbp)
  jle    L5
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D8
type: string

tool: D8: %d


assistant: ```c
int main(void) {
  int i, a[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  for (i = 0; i < 10; i++) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movl   $0x1,(%rsp)
  movl   $0x2,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x4,0xc(%rsp)
  movl   $0x5,0x10(%rsp)
  mov    %rsp,%rbx
  lea    0x28(%rsp),%rbp
  mov    %rbx,%rax
L23:
  movl   $0x0,(%rax)
  add    $0x4,%rax
  cmp    %rbp,%rax
  jne    L23
  lea    D8(%rip),%r12
L19:
  mov    (%rbx),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L19
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d


assistant: ```c
int main(void) {
  int i, a[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  for (i = 0; i < 10; i++) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  lea    0x28(%rsp),%r12
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L15:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L15
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type: string

tool: D8: %d


assistant: ```c
int main(void) {
  int i, a[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  for (i = 0; i < 10; i++) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  lea    0x28(%rsp),%r12
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  nopl   0x0(%rax)
L14:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L14
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: %d


assistant: ```c
int main(void) {
  int i, a[10] = {1, 2, 3, 4, 5};
  for (i = 0; i < 10; i++) {
    a[i] = 0;
  }
  for (i = 0; i < 10; i++) {
    printf("%d\n", a[i]);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<insertionSortArr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L21
L20:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L48
L44:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  add    $0x1,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x8(%rbp)
L48:
  cmpl   $0x0,-0x8(%rbp)
  js     L15
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jb     L44
L15:
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0xc(%rbp)
L21:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L20
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int *insertionSortArr(unsigned int arr[], int length) {
  unsigned int x;
  int i, j;
  for (i = 1; i < length; i++) {
    x = arr[i];
    j = i - 1;
    while ((j >= 0) && (arr[j] > x)) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = x;
  }
  return arr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<insertionSortArr>:
  endbr64
  cmp    $0x1,%esi
  jle    L38
  mov    %rdi,%r9
  lea    -0x1(%rsi),%r10d
  mov    $0x0,%r8d
  jmp    L0
L2:
  movslq %edx,%rdx
  mov    %esi,0x4(%rdi,%rdx,4)
  add    $0x1,%r8
  add    $0x4,%r9
  cmp    %r10,%r8
  je     L38
L0:
  mov    0x4(%r9),%esi
  mov    %r8d,%edx
  mov    %r9,%rax
  test   %r8d,%r8d
  js     L2
L16:
  mov    (%rax),%ecx
  cmp    %esi,%ecx
  jbe    L2
  mov    %ecx,0x4(%rax)
  sub    $0x1,%edx
  sub    $0x4,%rax
  cmp    $0xffffffff,%edx
  jne    L16
  jmp    L2
L38:
  mov    %rdi,%rax
  ret
```

assistant: ```c
unsigned int *insertionSortArr(unsigned int arr[], int length) {
  unsigned int x;
  int i, j;
  for (i = 1; i < length; i++) {
    x = arr[i];
    j = i - 1;
    while ((j >= 0) && (arr[j] > x)) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = x;
  }
  return arr;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<insertionSortArr>:
  endbr64
  mov    %rdi,%r8
  lea    -0x1(%rsi),%r9d
  xor    %edi,%edi
  cmp    $0x1,%esi
  jle    L3
  nopw   0x0(%rax,%rax,1)
L32:
  mov    0x4(%r8,%rdi,4),%esi
  mov    %rdi,%rax
L31:
  mov    (%r8,%rax,4),%edx
  mov    %eax,%ecx
  cmp    %esi,%edx
  jbe    L34
  mov    %edx,0x4(%r8,%rax,4)
  sub    $0x1,%rax
  cmp    $0xffffffff,%eax
  jne    L31
  mov    %r8,%rax
L5:
  add    $0x1,%rdi
  mov    %esi,(%rax)
  cmp    %rdi,%r9
  jne    L32
L3:
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L34:
  add    $0x1,%ecx
  movslq %ecx,%rcx
  lea    (%r8,%rcx,4),%rax
  jmp    L5
```

assistant: ```c
unsigned int *insertionSortArr(unsigned int arr[], int length) {
  unsigned int x;
  int i, j;
  for (i = 1; i < length; i++) {
    x = arr[i];
    j = i - 1;
    while ((j >= 0) && (arr[j] > x)) {
      arr[j + 1] = arr[j];
      j = j - 1;
    }
    arr[j + 1] = x;
  }
  return arr;
}
```