ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<my_strcldup>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <my_strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L18
  cmpq   $0x0,-0x18(%rbp)
  jne    L38
L18:
  mov    $0x0,%eax
  jmp    L31
L30:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x10(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x10(%rbp)
L38:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jl     L30
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L31:
  leave
  ret
```

assistant: ```c
char *my_strcldup(char *src) {
  int len;
  int lp;
  char *dest;
  len = my_strlen(src);
  lp = 0;
  dest = malloc(sizeof(unsigned char) * len + 1);
  if (dest == NULL || src == NULL)
    return (NULL);
  while (lp < len) {
    dest[lp] = src[lp];
    ++lp;
  }
  dest[lp] = '\0';
  return (dest);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strcldup>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <my_strlen@plt>
  mov    %eax,%ebp
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L22
  test   %rbx,%rbx
  je     L22
  test   %ebp,%ebp
  jle    L35
  mov    %ebp,%esi
  mov    $0x0,%edx
L46:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L46
L16:
  movslq %ebp,%rbp
  movb   $0x0,(%rax,%rbp,1)
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  mov    $0x0,%ebp
  jmp    L16
L22:
  mov    $0x0,%eax
  jmp    L26
```

assistant: ```c
char *my_strcldup(char *src) {
  int len;
  int lp;
  char *dest;
  len = my_strlen(src);
  lp = 0;
  dest = malloc(sizeof(unsigned char) * len + 1);
  if (dest == NULL || src == NULL)
    return (NULL);
  while (lp < len) {
    dest[lp] = src[lp];
    ++lp;
  }
  dest[lp] = '\0';
  return (dest);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_strcldup>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  call   <my_strlen@plt>
  movslq %eax,%rbp
  lea    0x1(%rbp),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L35
  test   %rbx,%rbx
  je     L35
  test   %ebp,%ebp
  jle    L28
  lea    -0x1(%rbp),%esi
  xor    %edx,%edx
L29:
  movzbl (%rbx,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  mov    %rdx,%rcx
  add    $0x1,%rdx
  cmp    %rcx,%rsi
  jne    L29
  add    %rax,%rbp
L17:
  movb   $0x0,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L35:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L28:
  mov    %rax,%rbp
  jmp    L17
```

assistant: ```c
char *my_strcldup(char *src) {
  int len;
  int lp;
  char *dest;
  len = my_strlen(src);
  lp = 0;
  dest = malloc(sizeof(unsigned char) * len + 1);
  if (dest == NULL || src == NULL)
    return (NULL);
  while (lp < len) {
    dest[lp] = src[lp];
    ++lp;
  }
  dest[lp] = '\0';
  return (dest);
}
```
user: What is the c source code of the assembly code below:

```asm
<my_strcldup>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <my_strlen@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%edi
  call   <malloc@plt>
  test   %rax,%rax
  je     L16
  test   %rbp,%rbp
  je     L16
  mov    %rax,%r8
  test   %ebx,%ebx
  jle    L48
  lea    0x1(%rbp),%rcx
  mov    %r8,%rdx
  lea    -0x1(%rbx),%eax
  sub    %rcx,%rdx
  cmp    $0xe,%rdx
  jbe    L196
  cmp    $0x6,%eax
  jbe    L196
  cmp    $0xe,%eax
  jbe    L153
  mov    %ebx,%edx
  xor    %eax,%eax
  shr    $0x4,%edx
  shl    $0x4,%rdx
  nopl   0x0(%rax)
L109:
  movdqu 0x0(%rbp,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rax,%rdx
  jne    L109
  mov    %ebx,%edx
  and    $0xfffffff0,%edx
  mov    %edx,%eax
  cmp    %edx,%ebx
  je     L157
  mov    %ebx,%r12d
  sub    %edx,%r12d
  lea    -0x1(%r12),%ecx
  cmp    $0x6,%ecx
  jbe    L12
L194:
  mov    0x0(%rbp,%rdx,1),%rcx
  mov    %rcx,(%r8,%rdx,1)
  mov    %r12d,%edx
  and    $0xfffffff8,%edx
  add    %edx,%eax
  cmp    %edx,%r12d
  je     L157
L12:
  movslq %eax,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x1(%rax),%edx
  cmp    %edx,%ebx
  jle    L157
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x2(%rax),%edx
  cmp    %edx,%ebx
  jle    L157
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x3(%rax),%edx
  cmp    %edx,%ebx
  jle    L157
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x4(%rax),%edx
  cmp    %edx,%ebx
  jle    L157
  movslq %edx,%rdx
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  lea    0x5(%rax),%edx
  cmp    %edx,%ebx
  jle    L157
  movslq %edx,%rdx
  add    $0x6,%eax
  movzbl 0x0(%rbp,%rdx,1),%ecx
  mov    %cl,(%r8,%rdx,1)
  cmp    %eax,%ebx
  jle    L157
  cltq
  movzbl 0x0(%rbp,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L157:
  add    %r8,%rbx
L82:
  movb   $0x0,(%rbx)
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L16:
  xor    %r8d,%r8d
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L196:
  mov    %eax,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L171:
  movzbl 0x0(%rbp,%rax,1),%ecx
  mov    %cl,(%r8,%rax,1)
  mov    %rax,%rcx
  add    $0x1,%rax
  cmp    %rdx,%rcx
  jne    L171
  jmp    L157
  nopw   0x0(%rax,%rax,1)
L48:
  mov    %rax,%rbx
  jmp    L82
L153:
  mov    %ebx,%r12d
  xor    %edx,%edx
  xor    %eax,%eax
  jmp    L194
```

assistant: ```c
char *my_strcldup(char *src) {
  int len;
  int lp;
  char *dest;
  len = my_strlen(src);
  lp = 0;
  dest = malloc(sizeof(unsigned char) * len + 1);
  if (dest == NULL || src == NULL)
    return (NULL);
  while (lp < len) {
    dest[lp] = src[lp];
    ++lp;
  }
  dest[lp] = '\0';
  return (dest);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<str2num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L31
L67:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x11(%rbp)
  cmpb   $0x2f,-0x11(%rbp)
  jle    L62
  cmpb   $0x39,-0x11(%rbp)
  jg     L62
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  movsbl -0x11(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L20
L62:
  movsbl -0x11(%rbp),%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x11(%rbp)
  cmpl   $0xa,-0x2c(%rbp)
  jle    L25
  cmpb   $0x40,-0x11(%rbp)
  jle    L25
  movsbl -0x11(%rbp),%eax
  mov    -0x2c(%rbp),%edx
  add    $0x36,%edx
  cmp    %edx,%eax
  jg     L25
  mov    -0x10(%rbp),%eax
  imul   -0x2c(%rbp),%eax
  mov    %eax,%edx
  movsbl -0x11(%rbp),%eax
  sub    $0x37,%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
L20:
  addl   $0x1,-0xc(%rbp)
L31:
  cmpl   $0x2,-0xc(%rbp)
  jle    L67
L25:
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int str2num(char **pp, int rad) {
  char *p;
  int num;
  int i;
  p = *pp;
  num = 0;
  for (i = 0; i < 3; i++) {
    char c = p[i];
    if ('0' <= c && c <= '9') {
      num = num * rad + c;
    } else {
      c = toupper(c);
      if (rad > 10 && ('A' <= c && c <= ('A' + rad - 11))) {
        num = num * rad + (c - 'A' + 10);
      } else {
        break;
      }
    }
  }
  *pp = p;
  return num;
}
```
user: What is the c source code of the assembly code below?

```asm
<str2num>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%r12d
  mov    (%rdi),%r14
  mov    %r14,%rbp
  lea    0x3(%r14),%r15
  mov    $0x0,%ebx
  lea    0x36(%rsi),%eax
  mov    %eax,0xc(%rsp)
  jmp    L27
L58:
  movsbl %dil,%edi
  call   <toupper@plt>
  cmp    $0xa,%r12d
  jle    L67
  cmp    $0x40,%al
  jle    L67
  movsbl %al,%eax
  cmp    0xc(%rsp),%eax
  jg     L67
  imul   %r12d,%ebx
  lea    -0x37(%rax,%rbx,1),%ebx
L53:
  add    $0x1,%rbp
  cmp    %r15,%rbp
  je     L67
L27:
  movzbl 0x0(%rbp),%edi
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  ja     L58
  imul   %r12d,%ebx
  movsbl %dil,%edi
  add    %edi,%ebx
  jmp    L53
L67:
  mov    %r14,0x0(%r13)
  mov    %ebx,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int str2num(char **pp, int rad) {
  char *p;
  int num;
  int i;
  p = *pp;
  num = 0;
  for (i = 0; i < 3; i++) {
    char c = p[i];
    if ('0' <= c && c <= '9') {
      num = num * rad + c;
    } else {
      c = toupper(c);
      if (rad > 10 && ('A' <= c && c <= ('A' + rad - 11))) {
        num = num * rad + (c - 'A' + 10);
      } else {
        break;
      }
    }
  }
  *pp = p;
  return num;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<str2num>:
  endbr64
  push   %r15
  lea    0x36(%rsi),%eax
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    (%rdi),%r15
  mov    %eax,0xc(%rsp)
  mov    %r15,%rbp
  lea    0x3(%r15),%rbx
L25:
  movsbl 0x0(%rbp),%edi
  mov    %edi,%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L2
  imul   %r13d,%r12d
  add    %edi,%r12d
L15:
  add    $0x1,%rbp
  cmp    %rbx,%rbp
  jne    L25
L0:
  mov    %r15,(%r14)
  add    $0x18,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L2:
  call   <toupper@plt>
  cmp    $0xa,%r13d
  jle    L0
  cmp    $0x40,%al
  jle    L0
  movsbl %al,%eax
  cmp    0xc(%rsp),%eax
  jg     L0
  imul   %r13d,%r12d
  lea    -0x37(%rax,%r12,1),%r12d
  jmp    L15
```

assistant: ```c
int str2num(char **pp, int rad) {
  char *p;
  int num;
  int i;
  p = *pp;
  num = 0;
  for (i = 0; i < 3; i++) {
    char c = p[i];
    if ('0' <= c && c <= '9') {
      num = num * rad + c;
    } else {
      c = toupper(c);
      if (rad > 10 && ('A' <= c && c <= ('A' + rad - 11))) {
        num = num * rad + (c - 'A' + 10);
      } else {
        break;
      }
    }
  }
  *pp = p;
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<str2num>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  mov    (%rdi),%rbp
  movsbl 0x0(%rbp),%r12d
  mov    %r12d,%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L65
  movsbl 0x1(%rbp),%edi
  mov    %edi,%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L99
L110:
  imul   %r13d,%r12d
  add    %edi,%r12d
  movsbl 0x2(%rbp),%edi
  mov    %edi,%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  ja     L159
L137:
  imul   %r13d,%r12d
  add    %edi,%r12d
L38:
  mov    %rbp,(%rbx)
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L65:
  mov    %r12d,%edi
  call   <toupper@plt>
  cmp    $0xa,%r13d
  jle    L135
  cmp    $0x40,%al
  jle    L135
  movsbl %al,%eax
  lea    0x36(%r13),%edx
  cmp    %edx,%eax
  jg     L135
  movsbl 0x1(%rbp),%edi
  lea    -0x37(%rax),%r12d
  mov    %edi,%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L110
L99:
  call   <toupper@plt>
  cmp    $0xa,%r13d
  jle    L38
  cmp    $0x40,%al
  jle    L38
  movsbl %al,%eax
  lea    0x36(%r13),%edx
  cmp    %edx,%eax
  jg     L38
  imul   %r13d,%r12d
  movsbl 0x2(%rbp),%edi
  lea    -0x37(%rax,%r12,1),%r12d
  mov    %edi,%eax
  sub    $0x30,%eax
  cmp    $0x9,%al
  jbe    L137
L159:
  call   <toupper@plt>
  cmp    $0xa,%r13d
  jle    L38
  cmp    $0x40,%al
  jle    L38
  movsbl %al,%eax
  lea    0x36(%r13),%edx
  cmp    %edx,%eax
  jg     L38
  imul   %r13d,%r12d
  lea    -0x37(%rax,%r12,1),%r12d
  jmp    L38
L135:
  xor    %r12d,%r12d
  jmp    L38
```

assistant: ```c
int str2num(char **pp, int rad) {
  char *p;
  int num;
  int i;
  p = *pp;
  num = 0;
  for (i = 0; i < 3; i++) {
    char c = p[i];
    if ('0' <= c && c <= '9') {
      num = num * rad + c;
    } else {
      c = toupper(c);
      if (rad > 10 && ('A' <= c && c <= ('A' + rad - 11))) {
        num = num * rad + (c - 'A' + 10);
      } else {
        break;
      }
    }
  }
  *pp = p;
  return num;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Q_UTF8Width>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L30
  mov    $0x0,%eax
  jmp    L34
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  js     L126
  movl   $0x0,-0xc(%rbp)
  jmp    L40
L126:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xc1,%al
  jbe    L37
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xdf,%al
  ja     L37
  movl   $0x1,-0xc(%rbp)
  jmp    L148
L37:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xdf,%al
  jbe    L75
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xef,%al
  ja     L75
  movl   $0x2,-0xc(%rbp)
  jmp    L148
L75:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xef,%al
  jbe    L84
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xf4,%al
  ja     L84
  movl   $0x3,-0xc(%rbp)
  jmp    L148
L84:
  movl   $0x0,-0xc(%rbp)
L148:
  jmp    L40
L42:
  addq   $0x1,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L40:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L78
  cmpl   $0x0,-0xc(%rbp)
  jg     L42
L78:
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%eax
L34:
  pop    %rbp
  ret
```

assistant: ```c
int Q_UTF8Width(const char *str) {
  int ewidth;
  const unsigned char *s = (const unsigned char *)str;
  if (!str)
    return 0;
  if (0x00 <= *s && *s <= 0x7F)
    ewidth = 0;
  else if (0xC2 <= *s && *s <= 0xDF)
    ewidth = 1;
  else if (0xE0 <= *s && *s <= 0xEF)
    ewidth = 2;
  else if (0xF0 <= *s && *s <= 0xF4)
    ewidth = 3;
  else
    ewidth = 0;
  for (; *s && ewidth > 0; s++, ewidth--)
    ;
  return s - (const unsigned char *)str + 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Q_UTF8Width>:
  endbr64
  test   %rdi,%rdi
  je     L4
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  js     L38
L10:
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
L38:
  cmp    $0xef,%dl
  ja     L11
  cmp    $0xdf,%dl
  ja     L97
  add    $0x3e,%edx
  mov    $0x1,%ecx
  cmp    $0x1d,%dl
  ja     L10
L70:
  mov    %rdi,%rax
L16:
  add    $0x1,%rax
  mov    %edi,%edx
  sub    %eax,%edx
  add    %ecx,%edx
  cmpb   $0x0,(%rax)
  je     L10
  test   %edx,%edx
  jg     L16
  jmp    L10
L11:
  add    $0x10,%edx
  mov    $0x3,%ecx
  cmp    $0x4,%dl
  jbe    L70
  jmp    L10
L4:
  mov    $0x0,%eax
  ret
L97:
  mov    $0x2,%ecx
  jmp    L70
```

assistant: ```c
int Q_UTF8Width(const char *str) {
  int ewidth;
  const unsigned char *s = (const unsigned char *)str;
  if (!str)
    return 0;
  if (0x00 <= *s && *s <= 0x7F)
    ewidth = 0;
  else if (0xC2 <= *s && *s <= 0xDF)
    ewidth = 1;
  else if (0xE0 <= *s && *s <= 0xEF)
    ewidth = 2;
  else if (0xF0 <= *s && *s <= 0xF4)
    ewidth = 3;
  else
    ewidth = 0;
  for (; *s && ewidth > 0; s++, ewidth--)
    ;
  return s - (const unsigned char *)str + 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Q_UTF8Width>:
  endbr64
  test   %rdi,%rdi
  je     L65
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  js     L85
L78:
  ret
  cs nopw 0x0(%rax,%rax,1)
L85:
  cmp    $0xef,%dl
  ja     L29
  cmp    $0xdf,%dl
  ja     L3
  add    $0x3e,%edx
  mov    $0x1,%ecx
  cmp    $0x1d,%dl
  ja     L78
L94:
  mov    %rdi,%rax
  jmp    L40
  nopl   0x0(%rax)
L41:
  cmpb   $0x0,(%rax)
  je     L28
L40:
  add    $0x1,%rax
  mov    %edi,%edx
  sub    %eax,%edx
  add    %ecx,%edx
  jne    L41
L28:
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  add    $0x10,%edx
  mov    $0x3,%ecx
  cmp    $0x4,%dl
  jbe    L94
  ret
  xchg   %ax,%ax
L65:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x2,%ecx
  jmp    L94
```

assistant: ```c
int Q_UTF8Width(const char *str) {
  int ewidth;
  const unsigned char *s = (const unsigned char *)str;
  if (!str)
    return 0;
  if (0x00 <= *s && *s <= 0x7F)
    ewidth = 0;
  else if (0xC2 <= *s && *s <= 0xDF)
    ewidth = 1;
  else if (0xE0 <= *s && *s <= 0xEF)
    ewidth = 2;
  else if (0xF0 <= *s && *s <= 0xF4)
    ewidth = 3;
  else
    ewidth = 0;
  for (; *s && ewidth > 0; s++, ewidth--)
    ;
  return s - (const unsigned char *)str + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<Q_UTF8Width>:
  endbr64
  test   %rdi,%rdi
  je     L68
  movzbl (%rdi),%edx
  mov    $0x1,%eax
  test   %dl,%dl
  js     L34
L39:
  ret
  cs nopw 0x0(%rax,%rax,1)
L34:
  cmp    $0xef,%dl
  ja     L81
  cmp    $0xdf,%dl
  ja     L71
  add    $0x3e,%edx
  cmp    $0x1d,%dl
  ja     L85
  lea    0x1(%rdi),%rax
L75:
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   (%rax)
L81:
  add    $0x10,%edx
  cmp    $0x4,%dl
  ja     L39
  mov    $0x3,%edx
L13:
  cmpb   $0x0,0x1(%rdi)
  lea    0x1(%rdi),%rax
  je     L75
  cmpb   $0x0,0x2(%rdi)
  lea    0x2(%rdi),%rax
  je     L75
  cmp    $0x2,%edx
  lea    0x3(%rdi),%rdx
  setne  %cl
  test   %cl,%cl
  cmovne %rdx,%rax
  sub    %rdi,%rax
  add    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L68:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L85:
  ret
  nopl   0x0(%rax)
L71:
  mov    $0x2,%edx
  jmp    L13
```

assistant: ```c
int Q_UTF8Width(const char *str) {
  int ewidth;
  const unsigned char *s = (const unsigned char *)str;
  if (!str)
    return 0;
  if (0x00 <= *s && *s <= 0x7F)
    ewidth = 0;
  else if (0xC2 <= *s && *s <= 0xDF)
    ewidth = 1;
  else if (0xE0 <= *s && *s <= 0xEF)
    ewidth = 2;
  else if (0xF0 <= *s && *s <= 0xF4)
    ewidth = 3;
  else
    ewidth = 0;
  for (; *s && ewidth > 0; s++, ewidth--)
    ;
  return s - (const unsigned char *)str + 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L19
L17:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%ecx
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    %ecx,%eax
  mov    %eax,-0x8(%rbp)
  addq   $0x1,-0x18(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  mov    -0x8(%rbp),%eax
  mov    %eax,%edx
  imul   $0x446f8657,%rdx,%rdx
  mov    %rdx,%rcx
  shr    $0x20,%rcx
  mov    %eax,%edx
  sub    %ecx,%edx
  shr    %edx
  add    %ecx,%edx
  shr    $0x6,%edx
  imul   $0x65,%edx,%edx
  sub    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D0
type: string

tool: D0: hash result: %d


assistant: ```c
unsigned hash(char *s) {
  unsigned hashval;
  unsigned result;
  for (hashval = 0; *s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  result = hashval % 101;
  printf("hash result: %d\n", result);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %rbx
  movzbl (%rdi),%eax
  test   %al,%al
  je     L18
  mov    $0x0,%ecx
L17:
  mov    %ecx,%edx
  shl    $0x5,%edx
  sub    %ecx,%edx
  movsbl %al,%eax
  lea    (%rax,%rdx,1),%ecx
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  test   %al,%al
  jne    L17
L7:
  mov    %ecx,%eax
  imul   $0x446f8657,%rax,%rax
  shr    $0x20,%rax
  mov    %ecx,%ebx
  sub    %eax,%ebx
  shr    %ebx
  add    %eax,%ebx
  shr    $0x6,%ebx
  imul   $0x65,%ebx,%eax
  mov    %ecx,%ebx
  sub    %eax,%ebx
  mov    %ebx,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
L18:
  mov    $0x0,%ecx
  jmp    L7
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
datatype: string

tool: D6: hash result: %d


assistant: ```c
unsigned hash(char *s) {
  unsigned hashval;
  unsigned result;
  for (hashval = 0; *s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  result = hashval % 101;
  printf("hash result: %d\n", result);
  return result;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hash>:
  endbr64
  push   %r12
  movsbl (%rdi),%eax
  test   %al,%al
  je     L21
  xor    %ecx,%ecx
  nop
L10:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L10
  mov    %ecx,%eax
  mov    %ecx,%r12d
  imul   $0x446f8657,%rax,%rax
  shr    $0x20,%rax
  sub    %eax,%r12d
  shr    %r12d
  add    %eax,%r12d
  shr    $0x6,%r12d
  imul   $0x65,%r12d,%eax
  sub    %eax,%ecx
  mov    %ecx,%r12d
L5:
  mov    %r12d,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L21:
  xor    %r12d,%r12d
  jmp    L5
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: hash result: %d


assistant: ```c
unsigned hash(char *s) {
  unsigned hashval;
  unsigned result;
  for (hashval = 0; *s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  result = hashval % 101;
  printf("hash result: %d\n", result);
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<hash>:
  endbr64
  push   %r12
  movsbl (%rdi),%eax
  test   %al,%al
  je     L25
  xor    %ecx,%ecx
  nop
L27:
  mov    %ecx,%edx
  add    $0x1,%rdi
  shl    $0x5,%edx
  sub    %ecx,%edx
  lea    (%rax,%rdx,1),%ecx
  movsbl (%rdi),%eax
  test   %al,%al
  jne    L27
  mov    %ecx,%eax
  mov    %ecx,%r12d
  imul   $0x446f8657,%rax,%rax
  shr    $0x20,%rax
  sub    %eax,%r12d
  shr    %r12d
  add    %eax,%r12d
  shr    $0x6,%r12d
  imul   $0x65,%r12d,%eax
  sub    %eax,%ecx
  mov    %ecx,%r12d
L0:
  mov    %r12d,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
L25:
  xor    %r12d,%r12d
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: string

tool: D5: hash result: %d


assistant: ```c
unsigned hash(char *s) {
  unsigned hashval;
  unsigned result;
  for (hashval = 0; *s != '\0'; s++) {
    hashval = *s + 31 * hashval;
  }
  result = hashval % 101;
  printf("hash result: %d\n", result);
  return result;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<command_help>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %ecx,-0x1c(%rbp)
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string

tool: D3: Graphdateline is a test client for the graph_dateline data type in libgraph.a

Below, X and Y stand for single-character variable names;
DBID stands for a 48-bit database ID, written as a number.
N stands for a 34-bit element count, written as a number.

Quickreference:
    help                 create X        add  X DBID N IID
    quit                 destroy X
    dump X               format X
    time [on / off]
    time now


assistant: ```c
void command_help(char const *progname, char const *const *argv, char const *filename, int line) {
  puts("Graphdateline is a test client for the graph_dateline data type in "
       "libgraph.a\n"
       "\n"
       "Below, X and Y stand for single-character variable names;\n"
       "DBID stands for a 48-bit database ID, written as a number.\n"
       "N stands for a 34-bit element count, written as a number.\n"
       "\n"
       "Quickreference:\n"
       "    help                 create X        add  X DBID N IID\n"
       "    quit                 destroy X\n"
       "    dump X               format X\n"
       "    time [on / off]\n"
       "    time now\n");
}
```