ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bytes_to_hex_uc>:
  endbr64
  mov    %rdi,%rcx
  test   %rsi,%rsi
  je     L3
  lea    (%rdi,%rsi,1),%r9
  lea    D4(%rip),%r8
  mov    %rdx,%rdi
  nopw   0x0(%rax,%rax,1)
L9:
  movzbl (%rcx),%eax
  add    $0x2,%rdi
  add    $0x1,%rcx
  shr    $0x4,%al
  and    $0xf,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,-0x2(%rdi)
  movzbl -0x1(%rcx),%eax
  and    $0xf,%eax
  movzbl (%r8,%rax,1),%eax
  mov    %al,-0x1(%rdi)
  cmp    %rcx,%r9
  jne    L9
  lea    (%rdx,%rsi,2),%rdx
L3:
  movb   $0x0,(%rdx)
  lea    0x1(%rsi,%rsi,1),%rax
  ret
```

tool_calls: name: disassemble_data
arguments: label: D4
type: string

tool: D4: 0123456789ABCDEF

assistant: ```c
size_t bytes_to_hex_uc(const void *input, size_t size, unsigned char *output) {
  size_t i;
  const unsigned char *p;
  for (i = 0, p = (const unsigned char *)input; i < size; ++i, ++p) {
    *output++ = "0123456789ABCDEF"[(*p) >> 4];
    *output++ = "0123456789ABCDEF"[(*p) & 15];
  }
  *output = '\0';
  return 2 * size + 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0xc(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D3
datatype: string
name: read_data
arguments: data_tag: D19
datatype: string

tool: D3: %d

tool: D19: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%d\n", (n = ((1 << n) + 1)) * n);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    D12(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%esi
  shl    %cl,%esi
  add    $0x1,%esi
  mov    %esi,0x4(%rsp)
  imul   %esi,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D12
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D12: %d

tool: D2: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%d\n", (n = ((1 << n) + 1)) * n);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D12(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%esi
  lea    D0(%rip),%rdi
  shl    %cl,%esi
  add    $0x1,%esi
  mov    %esi,0x4(%rsp)
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_guessed: string
name: disassemble_data
arguments: label: D0
type_guessed: string

tool: D12: %d

tool: D0: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%d\n", (n = ((1 << n) + 1)) * n);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D5(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  mov    0x4(%rsp),%ecx
  mov    $0x1,%esi
  lea    D18(%rip),%rdi
  shl    %cl,%esi
  add    $0x1,%esi
  mov    %esi,0x4(%rsp)
  imul   %esi,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D5
data_type: string
name: parse_data
arguments: tag: D18
data_type: string

tool: D5: %d

tool: D18: %d


assistant: ```c
int main() {
  int n;
  scanf("%d", &n);
  printf("%d\n", (n = ((1 << n) + 1)) * n);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_num>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L8
L15:
  mov    -0x8(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  add    %rax,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L8:
  cmpl   $0x9,-0xc(%rbp)
  jle    L15
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long get_num(char *a) {
  int i;
  unsigned long long sum = 0;
  for (i = 0; i < 10; i++) {
    sum *= 10;
    sum += a[i];
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_num>:
  endbr64
  lea    0xa(%rdi),%rcx
  mov    $0x0,%eax
L5:
  lea    (%rax,%rax,4),%rdx
  movsbq (%rdi),%rax
  lea    (%rax,%rdx,2),%rax
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L5
  ret
```

assistant: ```c
unsigned long long get_num(char *a) {
  int i;
  unsigned long long sum = 0;
  for (i = 0; i < 10; i++) {
    sum *= 10;
    sum += a[i];
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_num>:
  endbr64
  lea    0xa(%rdi),%rcx
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L2:
  lea    (%rax,%rax,4),%rdx
  movsbq (%rdi),%rax
  add    $0x1,%rdi
  lea    (%rax,%rdx,2),%rax
  cmp    %rcx,%rdi
  jne    L2
  ret
```

assistant: ```c
unsigned long long get_num(char *a) {
  int i;
  unsigned long long sum = 0;
  for (i = 0; i < 10; i++) {
    sum *= 10;
    sum += a[i];
  }
  return sum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_num>:
  endbr64
  movsbq (%rdi),%rdx
  movsbq 0x9(%rdi),%rax
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x1(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x2(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x3(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x4(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x5(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x6(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x7(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rcx
  movsbq 0x8(%rdi),%rdx
  lea    (%rdx,%rcx,2),%rdx
  lea    (%rdx,%rdx,4),%rdx
  lea    (%rax,%rdx,2),%rax
  ret
```

assistant: ```c
unsigned long long get_num(char *a) {
  int i;
  unsigned long long sum = 0;
  for (i = 0; i < 10; i++) {
    sum *= 10;
    sum += a[i];
  }
  return sum;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<ev_emit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %edx,-0x2c(%rbp)
  mov    %ecx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x20(%rbp),%rax
  add    $0xc,%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  lea    -0x20(%rbp),%rcx
  mov    -0x24(%rbp),%eax
  mov    $0x10,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int ev_emit(int fd, int type, int code, int value) {
  struct input_event ev = {.type = type, .code = code, .value = value};
  gettimeofday(&ev.time, 0);
  return write(fd, &ev, sizeof(ev));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ev_emit>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x0,0xc(%rsp)
  mov    %esi,(%rsp)
  mov    %edx,0x4(%rsp)
  mov    %ecx,0x8(%rsp)
  mov    %rsp,%rbp
  lea    0xc(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    $0x10,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L4
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ev_emit(int fd, int type, int code, int value) {
  struct input_event ev = {.type = type, .code = code, .value = value};
  gettimeofday(&ev.time, 0);
  return write(fd, &ev, sizeof(ev));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ev_emit>:
  endbr64
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    %esi,(%rsp)
  mov    %rsp,%r12
  xor    %esi,%esi
  mov    %edx,0x4(%rsp)
  movl   $0x0,0xc(%rsp)
  mov    %ecx,0x8(%rsp)
  call   <gettimeofday@plt>
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ev_emit(int fd, int type, int code, int value) {
  struct input_event ev = {.type = type, .code = code, .value = value};
  gettimeofday(&ev.time, 0);
  return write(fd, &ev, sizeof(ev));
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ev_emit>:
  endbr64
  push   %r12
  movd   %edx,%xmm1
  movd   %esi,%xmm0
  xor    %esi,%esi
  push   %rbp
  punpckldq %xmm1,%xmm0
  mov    %edi,%ebp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdi
  mov    %rsp,%r12
  mov    %ecx,0x8(%rsp)
  movl   $0x0,0xc(%rsp)
  movq   %xmm0,(%rsp)
  call   <gettimeofday@plt>
  mov    $0x10,%edx
  mov    %r12,%rsi
  mov    %ebp,%edi
  call   <write@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ev_emit(int fd, int type, int code, int value) {
  struct input_event ev = {.type = type, .code = code, .value = value};
  gettimeofday(&ev.time, 0);
  return write(fd, &ev, sizeof(ev));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<noisy_div>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movsd  %xmm0,-0x8(%rbp)
  movsd  %xmm1,-0x10(%rbp)
  movsd  %xmm2,-0x18(%rbp)
  movsd  -0x18(%rbp),%xmm0
  comisd -0x10(%rbp),%xmm0
  jb     L13
  pxor   %xmm0,%xmm0
  jmp    L6
L13:
  movsd  -0x8(%rbp),%xmm0
  divsd  -0x10(%rbp),%xmm0
L6:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

assistant: ```c
double noisy_div(double x, double y, double t) {
  if (y <= t)
    return 0;
  return x / y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<noisy_div>:
  endbr64
  comisd %xmm1,%xmm2
  jae    L4
  divsd  %xmm1,%xmm0
  ret
L4:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double noisy_div(double x, double y, double t) {
  if (y <= t)
    return 0;
  return x / y;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<noisy_div>:
  endbr64
  comisd %xmm1,%xmm2
  jae    L3
  divsd  %xmm1,%xmm0
  ret
  nop
L3:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double noisy_div(double x, double y, double t) {
  if (y <= t)
    return 0;
  return x / y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<noisy_div>:
  endbr64
  comisd %xmm1,%xmm2
  jae    L5
  divsd  %xmm1,%xmm0
  ret
  nop
L5:
  pxor   %xmm0,%xmm0
  ret
```

assistant: ```c
double noisy_div(double x, double y, double t) {
  if (y <= t)
    return 0;
  return x / y;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trigger>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <mill_msleep_@plt>
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ecx
  mov    $0x1,%edx
  lea    D14(%rip),%rsi
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x1,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D7
datatype: string
name: parse_data
arguments: tag: D14
datatype: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c:36

tool: D14: A

assistant: ```c
__attribute__((no)) void trigger(int fd, int64_t deadline) {
  mill_msleep_((deadline), ("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c"
                            ":"
                            "36"));
  ssize_t sz = send(fd, "A", 1, 0);
  assert(sz == 1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<trigger>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%edi
  lea    D2(%rip),%rsi
  call   <mill_msleep_@plt>
  mov    $0x0,%ecx
  mov    $0x1,%edx
  lea    D17(%rip),%rsi
  mov    %ebx,%edi
  call   <send@plt>
  cmp    $0x1,%eax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: tag: D2
type: string
name: parse_data
arguments: tag: D17
type: string

tool: D2: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c:36

tool: D17: A

assistant: ```c
__attribute__((no)) void trigger(int fd, int64_t deadline) {
  mill_msleep_((deadline), ("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c"
                            ":"
                            "36"));
  ssize_t sz = send(fd, "A", 1, 0);
  assert(sz == 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<trigger>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  lea    D7(%rip),%rsi
  call   <mill_msleep_@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0x1,%edx
  lea    D13(%rip),%rsi
  call   <send@plt>
  xor    %edi,%edi
  pop    %rbp
  cmp    $0x1,%eax
  sete   %dil
  jmp    1080 <assert@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D13
type_infered: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c:36

tool: D13: A

assistant: ```c
__attribute__((no)) void trigger(int fd, int64_t deadline) {
  mill_msleep_((deadline), ("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c"
                            ":"
                            "36"));
  ssize_t sz = send(fd, "A", 1, 0);
  assert(sz == 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<trigger>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  mov    %esi,%edi
  lea    D14(%rip),%rsi
  call   <mill_msleep_@plt>
  mov    %ebp,%edi
  xor    %ecx,%ecx
  mov    $0x1,%edx
  lea    D4(%rip),%rsi
  call   <send@plt>
  xor    %edi,%edi
  pop    %rbp
  cmp    $0x1,%eax
  sete   %dil
  jmp    1080 <assert@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D14
datatype: string
name: disassemble_data
arguments: data_label: D4
datatype: string

tool: D14: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c:36

tool: D4: A

assistant: ```c
__attribute__((no)) void trigger(int fd, int64_t deadline) {
  mill_msleep_((deadline), ("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/jimjag/mill/refs/heads/master/tests/fdwait.c"
                            ":"
                            "36"));
  ssize_t sz = send(fd, "A", 1, 0);
  assert(sz == 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<grid_search>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  mov    %rsi,-0x38(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L34
L15:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  comisd -0x30(%rbp),%xmm0
  jbe    L31
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L10
L31:
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x20(%rbp)
L10:
  mov    -0x18(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L34:
  cmpq   $0x1,-0x10(%rbp)
  jg     L15
  mov    -0x20(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
long grid_search(long n, double quarry, double *A) {
  long lowerLimit = 0;
  long upperLimit = n - 1;
  long examinationPoint;
  long length = upperLimit - lowerLimit;
  while (length > 1) {
    examinationPoint = lowerLimit + (length / 2);
    if (A[examinationPoint] > quarry)
      upperLimit = examinationPoint;
    else
      lowerLimit = examinationPoint;
    length = upperLimit - lowerLimit;
  }
  return lowerLimit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<grid_search>:
  endbr64
  sub    $0x1,%rdi
  cmp    $0x1,%rdi
  jle    L26
  mov    %rdi,%rcx
  mov    $0x0,%edx
L6:
  mov    %rcx,%rax
  shr    $0x3f,%rax
  add    %rcx,%rax
  sar    %rax
  add    %rdx,%rax
  movsd  (%rsi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  cmovbe %rax,%rdx
  cmova  %rax,%rdi
  mov    %rdi,%rcx
  sub    %rdx,%rcx
  cmp    $0x1,%rcx
  jg     L6
L15:
  mov    %rdx,%rax
  ret
L26:
  mov    $0x0,%edx
  jmp    L15
```

assistant: ```c
long grid_search(long n, double quarry, double *A) {
  long lowerLimit = 0;
  long upperLimit = n - 1;
  long examinationPoint;
  long length = upperLimit - lowerLimit;
  while (length > 1) {
    examinationPoint = lowerLimit + (length / 2);
    if (A[examinationPoint] > quarry)
      upperLimit = examinationPoint;
    else
      lowerLimit = examinationPoint;
    length = upperLimit - lowerLimit;
  }
  return lowerLimit;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<grid_search>:
  endbr64
  sub    $0x1,%rdi
  cmp    $0x1,%rdi
  jle    L37
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  jmp    L22
  cs nopw 0x0(%rax,%rax,1)
L32:
  mov    %rdx,%rdi
  mov    %rax,%r8
  sub    %rax,%rdi
  cmp    $0x1,%rdi
  jle    L40
L22:
  sar    %rdi
  lea    (%rdi,%r8,1),%rax
  movsd  (%rsi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  jbe    L32
  mov    %rax,%rdx
  cmp    $0x1,%rdi
  jg     L22
L40:
  mov    %r8,%rax
  ret
  xchg   %ax,%ax
L37:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long grid_search(long n, double quarry, double *A) {
  long lowerLimit = 0;
  long upperLimit = n - 1;
  long examinationPoint;
  long length = upperLimit - lowerLimit;
  while (length > 1) {
    examinationPoint = lowerLimit + (length / 2);
    if (A[examinationPoint] > quarry)
      upperLimit = examinationPoint;
    else
      lowerLimit = examinationPoint;
    length = upperLimit - lowerLimit;
  }
  return lowerLimit;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<grid_search>:
  endbr64
  sub    $0x1,%rdi
  cmp    $0x1,%rdi
  jle    L47
  mov    %rdi,%rdx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L16:
  sar    %rdi
  lea    (%rdi,%r8,1),%rax
  movsd  (%rsi,%rax,8),%xmm1
  comisd %xmm0,%xmm1
  ja     L20
  mov    %rdx,%rdi
  mov    %rax,%r8
  sub    %rax,%rdi
  cmp    $0x1,%rdi
  jg     L16
L13:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L20:
  cmp    $0x1,%rdi
  je     L13
  mov    %rax,%rdx
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L47:
  xor    %r8d,%r8d
  mov    %r8,%rax
  ret
```

assistant: ```c
long grid_search(long n, double quarry, double *A) {
  long lowerLimit = 0;
  long upperLimit = n - 1;
  long examinationPoint;
  long length = upperLimit - lowerLimit;
  while (length > 1) {
    examinationPoint = lowerLimit + (length / 2);
    if (A[examinationPoint] > quarry)
      upperLimit = examinationPoint;
    else
      lowerLimit = examinationPoint;
    length = upperLimit - lowerLimit;
  }
  return lowerLimit;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <megaInit@plt>
  cmpl   $0x2,-0x24(%rbp)
  je     L6
  mov    $0x1,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
L6:
  movl   $0x0,-0x14(%rbp)
  jmp    L51
L24:
  mov    -0x14(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    $0xa,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <strtoul@plt>
  mov    %al,-0x15(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  movzbl -0x15(%rbp),%edx
  mov    %dl,-0xa(%rbp,%rax,1)
  addl   $0x1,-0x14(%rbp)
L51:
  cmpl   $0x0,-0x14(%rbp)
  jle    L24
  lea    -0x9(%rbp),%rdx
  lea    -0xa(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <RandomFunc@plt>
  movzbl -0x9(%rbp),%eax
  cmp    $0xa1,%al
  jne    L1
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L1:
  movl   $0x0,-0x10(%rbp)
  jmp    L15
L9:
  mov    -0x10(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L15:
  cmpl   $0x0,-0x10(%rbp)
  jle    L9
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D3
type: string
name: unpack_data
arguments: label: D19
type: string
name: unpack_data
arguments: label: D26
type: string

tool: D3: Call this program with %i arguments


tool: D19: You win!

tool: D26: %u


assistant: ```c
int main(int argc, char *argv[]) {
  unsigned char input[1];
  unsigned char output[1];
  int randomFuns_i5;
  unsigned char randomFuns_value6;
  int randomFuns_main_i7;
  {
    megaInit();
    if (argc != 2) {
      printf("Call this program with %i arguments\n", 1);
      exit(-1);
    } else {
    }
    randomFuns_i5 = 0;
    while (randomFuns_i5 < 1) {
      randomFuns_value6 = (unsigned char)strtoul(argv[randomFuns_i5 + 1], 0, 10);
      input[randomFuns_i5] = randomFuns_value6;
      randomFuns_i5++;
    }
    RandomFunc(input, output);
    if (output[0] == 161) {
      printf("You win!\n");
    } else {
    }
    randomFuns_main_i7 = 0;
    while (randomFuns_main_i7 < 1) {
      printf("%u\n", output[randomFuns_main_i7]);
      randomFuns_main_i7++;
    }
  }
}
```