ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<readn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  jmp    L21
L11:
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <read@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L30
  mov    $0xffffffff,%eax
  jmp    L2
L30:
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x18(%rbp)
L21:
  cmpl   $0x0,-0x18(%rbp)
  jg     L11
  mov    $0x0,%eax
L2:
  leave
  ret
```

assistant: ```c
int readn(int fd, void *data, int n) {
  int m;
  while (n > 0) {
    m = read(fd, data, n);
    if (m <= 0)
      return -1;
    data += m;
    n -= m;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<readn>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%rbp
  mov    %edx,%ebx
  test   %edx,%edx
  jle    L8
L17:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jle    L48
  movslq %eax,%rdx
  add    %rdx,%rbp
  sub    %eax,%ebx
  test   %ebx,%ebx
  jg     L17
  mov    $0x0,%eax
  jmp    L26
L8:
  mov    $0x0,%eax
  jmp    L26
L48:
  mov    $0xffffffff,%eax
L26:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int readn(int fd, void *data, int n) {
  int m;
  while (n > 0) {
    m = read(fd, data, n);
    if (m <= 0)
      return -1;
    data += m;
    n -= m;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<readn>:
  endbr64
  test   %edx,%edx
  jle    L20
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L8
  cs nopw 0x0(%rax,%rax,1)
L16:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L1
L8:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L16
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L20:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readn(int fd, void *data, int n) {
  int m;
  while (n > 0) {
    m = read(fd, data, n);
    if (m <= 0)
      return -1;
    data += m;
    n -= m;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<readn>:
  endbr64
  test   %edx,%edx
  jle    L32
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edx,%ebx
  jmp    L33
  cs nopw 0x0(%rax,%rax,1)
L28:
  movslq %eax,%rdx
  sub    %eax,%ebx
  add    %rdx,%rbp
  test   %ebx,%ebx
  jle    L4
L33:
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <read@plt>
  test   %eax,%eax
  jg     L28
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
int readn(int fd, void *data, int n) {
  int m;
  while (n > 0) {
    m = read(fd, data, n);
    if (m <= 0)
      return -1;
    data += m;
    n -= m;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x44(%rbp)
  movl   $0x0,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  jmp    L26
L45:
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  cmp    $0x20,%al
  je     L41
  mov    -0x4c(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%edx
  mov    -0x48(%rbp),%eax
  cltq
  mov    %dl,-0x20(%rbp,%rax,1)
  jmp    L15
L41:
  mov    -0x48(%rbp),%eax
  cltq
  movb   $0x25,-0x20(%rbp,%rax,1)
  mov    -0x48(%rbp),%eax
  add    $0x1,%eax
  cltq
  movb   $0x32,-0x20(%rbp,%rax,1)
  mov    -0x48(%rbp),%eax
  add    $0x2,%eax
  cltq
  movb   $0x30,-0x20(%rbp,%rax,1)
  addl   $0x2,-0x48(%rbp)
L15:
  addl   $0x1,-0x48(%rbp)
  addl   $0x1,-0x4c(%rbp)
L26:
  mov    -0x44(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x48(%rbp)
  jl     L45
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L48
  call   <__stack_chk_fail@plt>
L48:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D1
type: string

tool: D1: %s


assistant: ```c
int main() {
  char a[20], r[20];
  int l, i, j;
  gets(a);
  l = strlen(a);
  for (i = 0, j = 0; j < l - 1; i++) {
    if (a[i] != ' ')
      r[j] = a[i];
    else {
      r[j] = '%';
      r[j + 1] = '2';
      r[j + 2] = '0';
      j += 2;
    }
    j++;
  }
  printf("%s\n", r);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L18
  mov    %rsp,%rcx
  mov    $0x0,%edx
  jmp    L12
L49:
  movslq %edx,%rsi
  movb   $0x25,0x20(%rsp,%rsi,1)
  lea    0x1(%rdx),%esi
  movslq %esi,%rsi
  movb   $0x32,0x20(%rsp,%rsi,1)
  add    $0x2,%edx
  movslq %edx,%rsi
  movb   $0x30,0x20(%rsp,%rsi,1)
L48:
  add    $0x1,%edx
  add    $0x1,%rcx
  cmp    %eax,%edx
  jge    L18
L12:
  movzbl (%rcx),%esi
  cmp    $0x20,%sil
  je     L49
  movslq %edx,%rdi
  mov    %sil,0x20(%rsp,%rdi,1)
  jmp    L48
L18:
  lea    0x20(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  mov    $0x0,%eax
  add    $0x40,%rsp
  pop    %rbx
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D0
datatype: string

tool: D0: %s


assistant: ```c
int main() {
  char a[20], r[20];
  int l, i, j;
  gets(a);
  l = strlen(a);
  for (i = 0, j = 0; j < l - 1; i++) {
    if (a[i] != ' ')
      r[j] = a[i];
    else {
      r[j] = '%';
      r[j + 1] = '2';
      r[j + 2] = '0';
      j += 2;
    }
    j++;
  }
  printf("%s\n", r);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rcx
  xor    %edx,%edx
  sub    $0x1,%eax
  test   %eax,%eax
  jg     L50
  jmp    L40
  nopw   0x0(%rax,%rax,1)
L56:
  movslq %edx,%rdi
  add    $0x1,%edx
  add    $0x1,%rcx
  mov    %sil,0x20(%rsp,%rdi,1)
  cmp    %eax,%edx
  jge    L40
L50:
  movzbl (%rcx),%esi
  cmp    $0x20,%sil
  jne    L56
  movslq %edx,%rsi
  add    $0x1,%rcx
  movb   $0x25,0x20(%rsp,%rsi,1)
  lea    0x1(%rdx),%esi
  add    $0x2,%edx
  movslq %esi,%rsi
  movb   $0x32,0x20(%rsp,%rsi,1)
  movslq %edx,%rsi
  add    $0x1,%edx
  movb   $0x30,0x20(%rsp,%rsi,1)
  cmp    %eax,%edx
  jl     L50
L40:
  lea    0x20(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D1
type: string

tool: D1: %s


assistant: ```c
int main() {
  char a[20], r[20];
  int l, i, j;
  gets(a);
  l = strlen(a);
  for (i = 0, j = 0; j < l - 1; i++) {
    if (a[i] != ' ')
      r[j] = a[i];
    else {
      r[j] = '%';
      r[j + 1] = '2';
      r[j + 2] = '0';
      j += 2;
    }
    j++;
  }
  printf("%s\n", r);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <gets@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rbx,%rcx
  xor    %edx,%edx
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L49
  nopl   0x0(%rax,%rax,1)
L26:
  movzbl (%rcx),%esi
  cmp    $0x20,%sil
  je     L54
  movslq %edx,%rdi
  add    $0x1,%edx
  add    $0x1,%rcx
  mov    %sil,0x20(%rsp,%rdi,1)
  cmp    %eax,%edx
  jl     L26
L49:
  lea    0x20(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    0x38(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x40,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   (%rax)
L54:
  movslq %edx,%rsi
  add    $0x1,%rcx
  movb   $0x25,0x20(%rsp,%rsi,1)
  lea    0x1(%rdx),%esi
  movslq %esi,%rsi
  movb   $0x32,0x20(%rsp,%rsi,1)
  lea    0x2(%rdx),%esi
  add    $0x3,%edx
  movslq %esi,%rsi
  movb   $0x30,0x20(%rsp,%rsi,1)
  cmp    %eax,%edx
  jl     L26
  jmp    L49
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D0
datatype: string

tool: D0: %s


assistant: ```c
int main() {
  char a[20], r[20];
  int l, i, j;
  gets(a);
  l = strlen(a);
  for (i = 0, j = 0; j < l - 1; i++) {
    if (a[i] != ' ')
      r[j] = a[i];
    else {
      r[j] = '%';
      r[j + 1] = '2';
      r[j + 2] = '0';
      j += 2;
    }
    j++;
  }
  printf("%s\n", r);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<url_encode_whitespace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <am_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L12
L30:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L10
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movb   $0x25,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sar    $0x4,%al
  movsbl %al,%eax
  mov    %eax,%edi
  call   <to_hex@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edi
  call   <to_hex@plt>
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L24
L10:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L24:
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    -0x10(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *url_encode_whitespace(const char *str) {
  const char *pstr = str;
  char *buf = am_malloc(strlen(str) * 3 + 1);
  char *pbuf = buf;
  while (*pstr) {
    if (*pstr == ' ')
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex(*pstr & 15);
    else
      *pbuf++ = *pstr;
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<url_encode_whitespace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,2),%edi
  call   <am_malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L16
  mov    %r12,%rbp
  jmp    L9
L27:
  movb   $0x25,0x0(%rbp)
  movzbl (%rbx),%edi
  sar    $0x4,%dil
  movsbl %dil,%edi
  call   <to_hex@plt>
  mov    %al,0x1(%rbp)
  movzbl (%rbx),%edi
  and    $0xf,%edi
  call   <to_hex@plt>
  mov    %al,0x2(%rbp)
  lea    0x3(%rbp),%rbp
L7:
  add    $0x1,%rbx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L5
L9:
  cmp    $0x20,%al
  je     L27
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rbp
  jmp    L7
L16:
  mov    %r12,%rbp
L5:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *url_encode_whitespace(const char *str) {
  const char *pstr = str;
  char *buf = am_malloc(strlen(str) * 3 + 1);
  char *pbuf = buf;
  while (*pstr) {
    if (*pstr == ' ')
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex(*pstr & 15);
    else
      *pbuf++ = *pstr;
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<url_encode_whitespace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,2),%edi
  call   <am_malloc@plt>
  movzbl (%rbx),%edx
  mov    %rax,%r12
  mov    %rax,%rbp
  test   %dl,%dl
  jne    L19
  jmp    L6
  nopl   0x0(%rax,%rax,1)
L45:
  add    $0x1,%rbx
  mov    %dl,0x0(%rbp)
  add    $0x1,%rbp
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L6
L19:
  cmp    $0x20,%dl
  jne    L45
  movb   $0x25,0x0(%rbp)
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  add    $0x3,%rbp
  sar    $0x4,%dil
  movsbl %dil,%edi
  call   <to_hex@plt>
  mov    %al,-0x2(%rbp)
  movzbl -0x1(%rbx),%edi
  and    $0xf,%edi
  call   <to_hex@plt>
  mov    %al,-0x1(%rbp)
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L19
L6:
  movb   $0x0,0x0(%rbp)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *url_encode_whitespace(const char *str) {
  const char *pstr = str;
  char *buf = am_malloc(strlen(str) * 3 + 1);
  char *pbuf = buf;
  while (*pstr) {
    if (*pstr == ' ')
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex(*pstr & 15);
    else
      *pbuf++ = *pstr;
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<url_encode_whitespace>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  lea    0x1(%rax,%rax,2),%edi
  call   <am_malloc@plt>
  mov    %rax,%r12
  movzbl (%rbx),%eax
  test   %al,%al
  je     L43
  mov    %r12,%rbp
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L40:
  add    $0x1,%rbx
  mov    %al,0x0(%rbp)
  lea    0x1(%rbp),%rdx
  movzbl (%rbx),%eax
  test   %al,%al
  je     L20
L4:
  mov    %rdx,%rbp
L11:
  cmp    $0x20,%al
  jne    L40
  movb   $0x25,0x0(%rbp)
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  sar    $0x4,%dil
  movsbl %dil,%edi
  call   <to_hex@plt>
  mov    %al,0x1(%rbp)
  movzbl -0x1(%rbx),%edi
  and    $0xf,%edi
  call   <to_hex@plt>
  lea    0x3(%rbp),%rdx
  mov    %al,0x2(%rbp)
  movzbl (%rbx),%eax
  test   %al,%al
  jne    L4
L20:
  movb   $0x0,(%rdx)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L43:
  mov    %r12,%rdx
  mov    %r12,%rax
  movb   $0x0,(%rdx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *url_encode_whitespace(const char *str) {
  const char *pstr = str;
  char *buf = am_malloc(strlen(str) * 3 + 1);
  char *pbuf = buf;
  while (*pstr) {
    if (*pstr == ' ')
      *pbuf++ = '%', *pbuf++ = to_hex(*pstr >> 4), *pbuf++ = to_hex(*pstr & 15);
    else
      *pbuf++ = *pstr;
    pstr++;
  }
  *pbuf = '\0';
  return buf;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<default_mix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L3:
  mov    -0x24(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0xc(%rbp),%esi
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <default_gen@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0xf,-0xc(%rbp)
  jle    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void default_mix(void *ud, float out[], int count) {
  struct defstate *data = ud;
  int i;
  for (i = 0; i < 16; i++) {
    default_gen(data, i, out, count);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<default_mix>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %edx,%ebp
  mov    $0x0,%ebx
L1:
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <default_gen@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void default_mix(void *ud, float out[], int count) {
  struct defstate *data = ud;
  int i;
  for (i = 0; i < 16; i++) {
    default_gen(data, i, out, count);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<default_mix>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%esi
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <default_gen@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void default_mix(void *ud, float out[], int count) {
  struct defstate *data = ud;
  int i;
  for (i = 0; i < 16; i++) {
    default_gen(data, i, out, count);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<default_mix>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%esi
  mov    %ebp,%ecx
  mov    %r12,%rdx
  mov    %r13,%rdi
  call   <default_gen@plt>
  add    $0x1,%ebx
  cmp    $0x10,%ebx
  jne    L8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void default_mix(void *ud, float out[], int count) {
  struct defstate *data = ud;
  int i;
  for (i = 0; i < 16; i++) {
    default_gen(data, i, out, count);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D32(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x10(%rbp),%rsi
  lea    -0x14(%rbp),%rcx
  lea    -0x18(%rbp),%rdx
  lea    -0x1c(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  movss  -0x1c(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jb     L59
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L88
L59:
  movss  -0xc(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jb     L80
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L88
L80:
  movss  -0xc(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jb     L69
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L88
L69:
  movss  -0xc(%rbp),%xmm0
  movss  -0x10(%rbp),%xmm1
  comiss %xmm1,%xmm0
  jb     L13
  lea    D65(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L88
L13:
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L88:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L64
  call   <__stack_chk_fail@plt>
L64:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D32
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D34
datatype: string
name: retrieve_data
arguments: data_tag: D18
datatype: string
name: retrieve_data
arguments: data_tag: D33
datatype: string
name: retrieve_data
arguments: data_tag: D7
datatype: string
name: retrieve_data
arguments: data_tag: D37
datatype: string
name: retrieve_data
arguments: data_tag: D65
datatype: string
name: retrieve_data
arguments: data_tag: D15
datatype: string

tool: D32: Enter thresholds for A, B, C, D
in that order, decreasing percentages >

tool: D5: %f%f%f%f

tool: D34: Thank you. Now enter student score (percent) >

tool: D18: %f

tool: D33: Student has an A grade


tool: D7: Student has an B grade


tool: D37: Student has an C grade


tool: D65: Student has an D grade


tool: D15: Student has failed the course


assistant: ```c
int main() {
  float a, b, c, d, e;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages >");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &e);
  if (e >= a)
    printf("Student has an A grade\n");
  else if (e >= b)
    printf("Student has an B grade\n");
  else if (e >= c)
    printf("Student has an C grade\n");
  else if (e >= d)
    printf("Student has an D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D73(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D67(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  comiss 0x4(%rsp),%xmm0
  jae    L37
  comiss 0x8(%rsp),%xmm0
  jae    L5
  comiss 0xc(%rsp),%xmm0
  jae    L75
  comiss 0x10(%rsp),%xmm0
  jb     L4
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L81
L37:
  lea    D44(%rip),%rdi
  call   <printf@plt>
L81:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L5:
  lea    D48(%rip),%rdi
  call   <printf@plt>
  jmp    L81
L75:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  jmp    L81
L4:
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L81
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D38
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D73
type_infered: string
name: unpack_data
arguments: data_label: D67
type_infered: string
name: unpack_data
arguments: data_label: D4
type_infered: string
name: unpack_data
arguments: data_label: D44
type_infered: string
name: unpack_data
arguments: data_label: D48
type_infered: string
name: unpack_data
arguments: data_label: D28
type_infered: string
name: unpack_data
arguments: data_label: D17
type_infered: string

tool: D38: Enter thresholds for A, B, C, D
in that order, decreasing percentages >

tool: D27: %f%f%f%f

tool: D73: Thank you. Now enter student score (percent) >

tool: D67: %f

tool: D4: Student has an D grade


tool: D44: Student has an A grade


tool: D48: Student has an B grade


tool: D28: Student has an C grade


tool: D17: Student has failed the course


assistant: ```c
int main() {
  float a, b, c, d, e;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages >");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &e);
  if (e >= a)
    printf("Student has an A grade\n");
  else if (e >= b)
    printf("Student has an B grade\n");
  else if (e >= c)
    printf("Student has an C grade\n");
  else if (e >= d)
    printf("Student has an D grade\n");
  else
    printf("Student has failed the course\n");
  return 0;
}
```