ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<linkstate2str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x6,-0x14(%rbp)
  ja     L39
  mov    -0x14(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  lea    D83(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D83(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D98(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
  lea    D94(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
  lea    D25(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
  lea    D81(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
  lea    D45(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
  lea    D96(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
  lea    D97(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L49
L39:
  lea    D64(%rip),%rax
  mov    %rax,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D98
data_type: string
name: unpack_data
arguments: data_label: D94
data_type: string
name: unpack_data
arguments: data_label: D25
data_type: string
name: unpack_data
arguments: data_label: D81
data_type: string
name: unpack_data
arguments: data_label: D45
data_type: string
name: unpack_data
arguments: data_label: D96
data_type: string
name: unpack_data
arguments: data_label: D97
data_type: string
name: unpack_data
arguments: data_label: D64
data_type: string

tool: D98: IDLE

tool: D94: NOTALIGNED

tool: D25: ALIGNED

tool: D81: PROVING

tool: D45: ALIGNEDREADY

tool: D96: INSERVICE

tool: D97: ALARM

tool: D64: UNKNOWN

assistant: ```c
char *linkstate2str(int linkstate) {
  char *statestr = NULL;
  switch (linkstate) {
  case 0:
    statestr = "IDLE";
    break;
  case 1:
    statestr = "NOTALIGNED";
    break;
  case 2:
    statestr = "ALIGNED";
    break;
  case 3:
    statestr = "PROVING";
    break;
  case 4:
    statestr = "ALIGNEDREADY";
    break;
  case 5:
    statestr = "INSERVICE";
    break;
  case 6:
    statestr = "ALARM";
    break;
  default:
    statestr = "UNKNOWN";
  }
  return statestr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<linkstate2str>:
  endbr64
  cmp    $0x6,%edi
  ja     L1
  mov    %edi,%edi
  lea    D1(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D37(%rip),%rax
  ret
  lea    D5(%rip),%rax
  ret
  lea    D66(%rip),%rax
  ret
  lea    D69(%rip),%rax
  ret
  lea    D82(%rip),%rax
  ret
  lea    D79(%rip),%rax
  ret
L1:
  lea    D7(%rip),%rax
  ret
  lea    D88(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: tag: D37
datatype: string
name: unpack_data
arguments: tag: D5
datatype: string
name: unpack_data
arguments: tag: D66
datatype: string
name: unpack_data
arguments: tag: D69
datatype: string
name: unpack_data
arguments: tag: D82
datatype: string
name: unpack_data
arguments: tag: D79
datatype: string
name: unpack_data
arguments: tag: D7
datatype: string
name: unpack_data
arguments: tag: D88
datatype: string

tool: D37: NOTALIGNED

tool: D5: ALIGNED

tool: D66: PROVING

tool: D69: ALIGNEDREADY

tool: D82: INSERVICE

tool: D79: ALARM

tool: D7: UNKNOWN

tool: D88: IDLE

assistant: ```c
char *linkstate2str(int linkstate) {
  char *statestr = NULL;
  switch (linkstate) {
  case 0:
    statestr = "IDLE";
    break;
  case 1:
    statestr = "NOTALIGNED";
    break;
  case 2:
    statestr = "ALIGNED";
    break;
  case 3:
    statestr = "PROVING";
    break;
  case 4:
    statestr = "ALIGNEDREADY";
    break;
  case 5:
    statestr = "INSERVICE";
    break;
  case 6:
    statestr = "ALARM";
    break;
  default:
    statestr = "UNKNOWN";
  }
  return statestr;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L9
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <ft_putstr@plt>
  mov    $0x0,%eax
  jmp    L2
L9:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <ft_extract_tetrimino@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_fillit@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_print_array@plt>
  mov    $0x0,%eax
L2:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_infered: string

tool: D6: usage: fillit input_file


assistant: ```c
int main(int argc, char **argv) {
  char *tetrimino;
  char **solution;
  if (argc != 2) {
    ft_putstr("usage: fillit input_file\n");
    return (0);
  }
  tetrimino = ft_extract_tetrimino(argv[1]);
  solution = ft_fillit(tetrimino);
  ft_print_array(solution);
  return (0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L16
  lea    D4(%rip),%rdi
  call   <ft_putstr@plt>
L4:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L16:
  mov    0x8(%rsi),%rdi
  call   <ft_extract_tetrimino@plt>
  mov    %rax,%rdi
  call   <ft_fillit@plt>
  mov    %rax,%rdi
  call   <ft_print_array@plt>
  jmp    L4
```

tool_calls: name: parse_data
arguments: tag: D4
data_type: string

tool: D4: usage: fillit input_file


assistant: ```c
int main(int argc, char **argv) {
  char *tetrimino;
  char **solution;
  if (argc != 2) {
    ft_putstr("usage: fillit input_file\n");
    return (0);
  }
  tetrimino = ft_extract_tetrimino(argv[1]);
  solution = ft_fillit(tetrimino);
  ft_print_array(solution);
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L10
  lea    D2(%rip),%rdi
  call   <ft_putstr@plt>
L4:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L10:
  mov    0x8(%rsi),%rdi
  call   <ft_extract_tetrimino@plt>
  mov    %rax,%rdi
  call   <ft_fillit@plt>
  mov    %rax,%rdi
  call   <ft_print_array@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type: string

tool: D2: usage: fillit input_file


assistant: ```c
int main(int argc, char **argv) {
  char *tetrimino;
  char **solution;
  if (argc != 2) {
    ft_putstr("usage: fillit input_file\n");
    return (0);
  }
  tetrimino = ft_extract_tetrimino(argv[1]);
  solution = ft_fillit(tetrimino);
  ft_print_array(solution);
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L4
  lea    D6(%rip),%rdi
  call   <ft_putstr@plt>
L14:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L4:
  mov    0x8(%rsi),%rdi
  call   <ft_extract_tetrimino@plt>
  mov    %rax,%rdi
  call   <ft_fillit@plt>
  mov    %rax,%rdi
  call   <ft_print_array@plt>
  jmp    L14
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: usage: fillit input_file


assistant: ```c
int main(int argc, char **argv) {
  char *tetrimino;
  char **solution;
  if (argc != 2) {
    ft_putstr("usage: fillit input_file\n");
    return (0);
  }
  tetrimino = ft_extract_tetrimino(argv[1]);
  solution = ft_fillit(tetrimino);
  ft_print_array(solution);
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L7
L11:
  addl   $0x1,-0xc(%rbp)
  addq   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L11
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(char *str) {
  int counter = 0;
  char *pc = str;
  while (*pc != (void *)0) {
    counter++;
    pc++;
  }
  return counter;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L24
  mov    %rdi,%rax
  mov    $0x1,%edx
  sub    %edi,%edx
L21:
  lea    (%rdx,%rax,1),%ecx
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L21
L7:
  mov    %ecx,%eax
  ret
L24:
  mov    $0x0,%ecx
  jmp    L7
```

assistant: ```c
int strlen(char *str) {
  int counter = 0;
  char *pc = str;
  while (*pc != (void *)0) {
    counter++;
    pc++;
  }
  return counter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x1,%eax
  sub    %edi,%eax
L2:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L2
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char *str) {
  int counter = 0;
  char *pc = str;
  while (*pc != (void *)0) {
    counter++;
    pc++;
  }
  return counter;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L18
  mov    $0x1,%eax
  sub    %edi,%eax
L19:
  lea    (%rax,%rdi,1),%r8d
  add    $0x1,%rdi
  cmpb   $0x0,(%rdi)
  jne    L19
  mov    %r8d,%eax
  ret
  nopl   0x0(%rax)
L18:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen(char *str) {
  int counter = 0;
  char *pc = str;
  while (*pc != (void *)0) {
    counter++;
    pc++;
  }
  return counter;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yacalloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L2
  mov    $0x0,%eax
  jmp    L20
L2:
  mov    -0x18(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <yamalloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L25
  mov    $0x0,%eax
  jmp    L20
L25:
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    -0x8(%rbp),%rax
L20:
  leave
  ret
```

assistant: ```c
void *yacalloc(size_t nelem, size_t elsize) {
  if (nelem == 0)
    return NULL;
  size_t size = nelem * elsize;
  void *ptr = yamalloc(size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, size);
  return ptr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<yacalloc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ebp
  test   %rdi,%rdi
  je     L0
  mov    %rdi,%rbx
  imul   %rsi,%rbx
  mov    %rbx,%rdi
  call   <yamalloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L0
  mov    %rbx,%rdx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void *yacalloc(size_t nelem, size_t elsize) {
  if (nelem == 0)
    return NULL;
  size_t size = nelem * elsize;
  void *ptr = yamalloc(size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, size);
  return ptr;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<yacalloc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L0
  imul   %rsi,%rdi
  mov    %rdi,%r12
  call   <yamalloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L0
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L0:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *yacalloc(size_t nelem, size_t elsize) {
  if (nelem == 0)
    return NULL;
  size_t size = nelem * elsize;
  void *ptr = yamalloc(size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, size);
  return ptr;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<yacalloc>:
  endbr64
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  imul   %rsi,%rdi
  mov    %rdi,%r12
  call   <yamalloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L1
  mov    %r12,%rdx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L1:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void *yacalloc(size_t nelem, size_t elsize) {
  if (nelem == 0)
    return NULL;
  size_t size = nelem * elsize;
  void *ptr = yamalloc(size);
  if (!ptr)
    return NULL;
  memset(ptr, 0, size);
  return ptr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<bitmapUnset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x80,-0x30(%rbp)
  movl   $0x40,-0x2c(%rbp)
  movl   $0x20,-0x28(%rbp)
  movl   $0x10,-0x24(%rbp)
  movl   $0x8,-0x20(%rbp)
  movl   $0x4,-0x1c(%rbp)
  movl   $0x2,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  mov    -0x3c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%ecx
  mov    -0x3c(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cltq
  mov    -0x30(%rbp,%rax,4),%eax
  not    %eax
  mov    %eax,%esi
  mov    -0x3c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  and    %esi,%ecx
  mov    %ecx,%edx
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
void bitmapUnset(char *bitmap, int idx) {
  int bit_mask[8] = {128, 64, 32, 16, 8, 4, 2, 1};
  bitmap[idx / 8] = bitmap[idx / 8] & ~bit_mask[idx % 8];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bitmapUnset>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x80,(%rsp)
  movl   $0x40,0x4(%rsp)
  movl   $0x20,0x8(%rsp)
  movl   $0x10,0xc(%rsp)
  movl   $0x8,0x10(%rsp)
  movl   $0x4,0x14(%rsp)
  movl   $0x2,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  lea    0x7(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  cltq
  mov    %esi,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  add    %edx,%esi
  and    $0x7,%esi
  sub    %edx,%esi
  movslq %esi,%rsi
  mov    (%rsp,%rsi,4),%edx
  not    %edx
  and    %dl,(%rdi,%rax,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x38,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bitmapUnset(char *bitmap, int idx) {
  int bit_mask[8] = {128, 64, 32, 16, 8, 4, 2, 1};
  bitmap[idx / 8] = bitmap[idx / 8] & ~bit_mask[idx % 8];
}
```
user: Translate the below assembly code into C programming language:

```asm
<bitmapUnset>:
  endbr64
  sub    $0x38,%rsp
  mov    %esi,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x4000000080,%rax
  test   %esi,%esi
  mov    %rax,(%rsp)
  movabs $0x1000000020,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x400000008,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000002,%rax
  mov    %rax,0x18(%rsp)
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  add    %edx,%esi
  sar    $0x3,%eax
  and    $0x7,%esi
  cltq
  sub    %edx,%esi
  movslq %esi,%rsi
  mov    (%rsp,%rsi,4),%edx
  not    %edx
  and    %dl,(%rdi,%rax,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void bitmapUnset(char *bitmap, int idx) {
  int bit_mask[8] = {128, 64, 32, 16, 8, 4, 2, 1};
  bitmap[idx / 8] = bitmap[idx / 8] & ~bit_mask[idx % 8];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bitmapUnset>:
  endbr64
  sub    $0x38,%rsp
  mov    %esi,%edx
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %esi,%esi
  lea    0x7(%rsi),%eax
  cmovns %esi,%eax
  sar    $0x1f,%edx
  movaps %xmm0,(%rsp)
  movdqa D6(%rip),%xmm0
  shr    $0x1d,%edx
  add    %edx,%esi
  movaps %xmm0,0x10(%rsp)
  sar    $0x3,%eax
  and    $0x7,%esi
  cltq
  sub    %edx,%esi
  movslq %esi,%rsi
  mov    (%rsp,%rsi,4),%edx
  not    %edx
  and    %dl,(%rdi,%rax,1)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x38,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D10
data_type: byte[16]
name: retrieve_data
arguments: label: D6
data_type: byte[16]

tool: {"D10": [0x80,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x20,0x00,0x00,0x00,0x10,0x00,0x00,0x00]}

tool: {"D6": [0x08,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
void bitmapUnset(char *bitmap, int idx) {
  int bit_mask[8] = {128, 64, 32, 16, 8, 4, 2, 1};
  bitmap[idx / 8] = bitmap[idx / 8] & ~bit_mask[idx % 8];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x0,-0x4(%rbp)
L21:
  cmpl   $0xa,-0x4(%rbp)
  jle    L26
  mov    -0x4(%rbp),%eax
  jmp    L22
L26:
  addl   $0x1,-0x4(%rbp)
  jmp    L21
L22:
  pop    %rbp
  ret
```

assistant: ```c
int f() {
  int c = 0;
  while (1) {
    if (c > 10)
      return c;
    c++;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int f() {
  int c = 0;
  while (1) {
    if (c > 10)
      return c;
    c++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<f>:
  endbr64
  mov    $0xb,%eax
  ret
```

assistant: ```c
int f() {
  int c = 0;
  while (1) {
    if (c > 10)
      return c;
    c++;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L11
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %dl,(%rax)
  subq   $0x1,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L3
L11:
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
void *memset(void *buffer, int value, size_t size) {
  if (size) {
    char *d = buffer;
    do {
      *d++ = value;
    } while (--size);
  }
  return buffer;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<memset>:
  endbr64
  mov    %rdi,%rax
  test   %rdx,%rdx
  je     L12
  add    %rdi,%rdx
  mov    %rdi,%rcx
L10:
  add    $0x1,%rcx
  mov    %sil,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L10
L12:
  ret
```

assistant: ```c
void *memset(void *buffer, int value, size_t size) {
  if (size) {
    char *d = buffer;
    do {
      *d++ = value;
    } while (--size);
  }
  return buffer;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L7
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *buffer, int value, size_t size) {
  if (size) {
    char *d = buffer;
    do {
      *d++ = value;
    } while (--size);
  }
  return buffer;
}
```
user: What is the c source code of the assembly code below:

```asm
<memset>:
  endbr64
  test   %rdx,%rdx
  je     L6
  sub    $0x8,%rsp
  movsbl %sil,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %rdi,%rax
  ret
```

assistant: ```c
void *memset(void *buffer, int value, size_t size) {
  if (size) {
    char *d = buffer;
    do {
      *d++ = value;
    } while (--size);
  }
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  add    $0x136ff696,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  je     L5
  mov    -0x10(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L17
  mov    -0x10(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L30
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L55
L30:
  mov    -0x10(%rbp),%rax
  add    %rax,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L55
L17:
  lea    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rax),%eax
  mov    %al,-0x13(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x2,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x3,%rax
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzbl -0x13(%rbp),%edx
  mov    %dl,(%rax)
  jmp    L55
L5:
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0x10(%rbp),%rdx
  add    $0x4,%rdx
  lea    -0x10(%rbp),%rax
  add    $0x6,%rax
  movzwl (%rdx),%edx
  mov    %dx,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
  lea    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  mov    %ax,-0x12(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  lea    -0x10(%rbp),%rdx
  movzwl (%rax),%eax
  mov    %ax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x2,%rax
  movzwl -0x12(%rbp),%edx
  mov    %dx,(%rax)
L55:
  mov    -0x10(%rbp),%rax
  movabs $0xeee1729a46ef9ea2,%rdx
  imul   %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  char copy11;
  unsigned short copy12;
  {
    state[0UL] = (input[0UL] + 51238316UL) + 274866410UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      if ((state[0UL] >> 3UL) & 1UL) {
        if ((state[0UL] >> 2UL) & 1UL) {
          state[0UL] += state[0UL];
        } else {
          state[0UL] += state[0UL];
        }
      } else {
        copy11 = *((char *)(&state[0UL]) + 3);
        *((char *)(&state[0UL]) + 3) = *((char *)(&state[0UL]) + 2);
        *((char *)(&state[0UL]) + 2) = copy11;
      }
    } else {
      copy12 = *((unsigned short *)(&state[0UL]) + 3);
      *((unsigned short *)(&state[0UL]) + 3) = *((unsigned short *)(&state[0UL]) + 2);
      *((unsigned short *)(&state[0UL]) + 2) = copy12;
      copy12 = *((unsigned short *)(&state[0UL]) + 0);
      *((unsigned short *)(&state[0UL]) + 0) = *((unsigned short *)(&state[0UL]) + 1);
      *((unsigned short *)(&state[0UL]) + 1) = copy12;
    }
    output[0UL] = (state[0UL] * 943156777UL) * 495144311008221650UL;
  }
}
```