ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<problem_003>:
  endbr64
  push   %rbx
  movabs $0x8be589eac7,%rbx
  mov    %rbx,%rdi
  call   <sqrt@plt>
  mov    $0x1,%r9d
  mov    $0x3,%esi
  mov    %eax,%edi
  cmp    $0x2,%eax
  jg     L77
  jmp    L55
  nopl   0x0(%rax,%rax,1)
L76:
  add    $0x1,%rsi
L77:
  mov    %esi,%r8d
  cmp    $0x1,%rbx
  jle    L55
  cmp    %esi,%edi
  jle    L55
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L76
  cqto
  mov    %rax,%rbx
  idiv   %rsi
  test   %rdx,%rdx
  jne    L20
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  cqto
  mov    %rax,%rbx
  idiv   %rsi
  test   %rdx,%rdx
  je     L1
  mov    %r8d,%r9d
  jmp    L76
  nopw   0x0(%rax,%rax,1)
L55:
  mov    %r9d,%esi
  lea    D8(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
L20:
  mov    %esi,%r9d
  jmp    L76
```

tool_calls: name: retrieve_data
arguments: tag: D8
type: string

tool: D8: %i

assistant: ```c
void problem_003(void) {
  long long n = 600851475143;
  int factor = 2;
  int largest_prime_factor = 1;
  int largest_possible_factor = sqrt(n);
  while (n > 1 && factor < largest_possible_factor) {
    if (n % factor == 0) {
      largest_prime_factor = factor;
      n = n / factor;
      while (n % factor == 0) {
        n = n / factor;
      }
    }
    factor++;
  }
  printf("%i", largest_prime_factor);
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<problem_003>:
  endbr64
  push   %rbx
  movabs $0x8be589eac7,%rbx
  mov    %rbx,%rdi
  call   <sqrt@plt>
  cmp    $0x2,%eax
  jle    L2
  mov    %eax,%r8d
  cmp    $0x3,%eax
  jle    L2
  mov    $0x3,%esi
  mov    $0x1,%r10d
  jmp    L43
  nopl   0x0(%rax)
L38:
  add    $0x1,%edi
  add    $0x1,%rsi
  cmp    %edi,%r8d
  jle    L40
L5:
  cmp    $0x1,%rbx
  jle    L40
L43:
  mov    %rbx,%rax
  mov    %esi,%edi
  mov    %esi,%r9d
  cqto
  idiv   %rsi
  test   %rdx,%rdx
  jne    L38
  cqto
  mov    %rax,%rbx
  idiv   %rsi
  test   %rdx,%rdx
  jne    L39
  nopl   0x0(%rax)
L84:
  mov    %rbx,%rax
  cqto
  idiv   %rsi
  cqto
  mov    %rax,%rbx
  idiv   %rsi
  test   %rdx,%rdx
  je     L84
  add    $0x1,%edi
  mov    %r9d,%r10d
  add    $0x1,%rsi
  cmp    %edi,%r8d
  jg     L5
L40:
  mov    %r10d,%esi
  lea    D18(%rip),%rdi
  pop    %rbx
  jmp    1060 <printf@plt>
  nopl   0x0(%rax)
L39:
  mov    %esi,%r10d
  jmp    L38
  nopl   (%rax)
L2:
  mov    $0x1,%r10d
  lea    D18(%rip),%rdi
  pop    %rbx
  mov    %r10d,%esi
  jmp    1060 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: label: D18
data_type: string

tool: D18: %i

assistant: ```c
void problem_003(void) {
  long long n = 600851475143;
  int factor = 2;
  int largest_prime_factor = 1;
  int largest_possible_factor = sqrt(n);
  while (n > 1 && factor < largest_possible_factor) {
    if (n % factor == 0) {
      largest_prime_factor = factor;
      n = n / factor;
      while (n % factor == 0) {
        n = n / factor;
      }
    }
    factor++;
  }
  printf("%i", largest_prime_factor);
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
type: string
name: unpack_data
arguments: data_tag: D23
type: string
name: unpack_data
arguments: data_tag: D13
type: string

tool: D6: USAGE: %s <dirs> [ -o <db_file> ]


tool: D23:        %s -h|--help prints this usage message.


tool: D13:           -n|--no-rc means the rc file will not be written

assistant: ```c
void usage(char *filename) {
  printf("USAGE: %s <dirs> [ -o <db_file> ]\n", filename);
  printf("       %s -h|--help prints this usage message.\n", filename);
  printf("          -n|--no-rc means the rc file will not be written\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<usage>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rsi
  lea    D23(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: data_label: D1
datatype: string
name: read_data
arguments: data_label: D23
datatype: string
name: read_data
arguments: data_label: D26
datatype: string

tool: D1: USAGE: %s <dirs> [ -o <db_file> ]


tool: D23:        %s -h|--help prints this usage message.


tool: D26:           -n|--no-rc means the rc file will not be written

assistant: ```c
void usage(char *filename) {
  printf("USAGE: %s <dirs> [ -o <db_file> ]\n", filename);
  printf("       %s -h|--help prints this usage message.\n", filename);
  printf("          -n|--no-rc means the rc file will not be written\n");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D9(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D7(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string
name: extract_symbolic_data
arguments: data_label: D9
type_infered: string
name: extract_symbolic_data
arguments: data_label: D7
type_infered: string

tool: D2: USAGE: %s <dirs> [ -o <db_file> ]


tool: D9:        %s -h|--help prints this usage message.


tool: D7:           -n|--no-rc means the rc file will not be written

assistant: ```c
void usage(char *filename) {
  printf("USAGE: %s <dirs> [ -o <db_file> ]\n", filename);
  printf("       %s -h|--help prints this usage message.\n", filename);
  printf("          -n|--no-rc means the rc file will not be written\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<usage>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  xor    %eax,%eax
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D17(%rip),%rdi
  pop    %rbp
  jmp    1060 <puts@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type_infered: string
name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D17
type_infered: string

tool: D15: USAGE: %s <dirs> [ -o <db_file> ]


tool: D0:        %s -h|--help prints this usage message.


tool: D17:           -n|--no-rc means the rc file will not be written

assistant: ```c
void usage(char *filename) {
  printf("USAGE: %s <dirs> [ -o <db_file> ]\n", filename);
  printf("       %s -h|--help prints this usage message.\n", filename);
  printf("          -n|--no-rc means the rc file will not be written\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<fls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x20,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L14
  mov    $0x0,%eax
  jmp    L42
L14:
  mov    -0x14(%rbp),%eax
  mov    $0x0,%ax
  test   %eax,%eax
  jne    L16
  shll   $0x10,-0x14(%rbp)
  subl   $0x10,-0x4(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  and    $0xff000000,%eax
  test   %eax,%eax
  jne    L40
  shll   $0x8,-0x14(%rbp)
  subl   $0x8,-0x4(%rbp)
L40:
  mov    -0x14(%rbp),%eax
  and    $0xf0000000,%eax
  test   %eax,%eax
  jne    L65
  shll   $0x4,-0x14(%rbp)
  subl   $0x4,-0x4(%rbp)
L65:
  mov    -0x14(%rbp),%eax
  and    $0xc0000000,%eax
  test   %eax,%eax
  jne    L62
  shll   $0x2,-0x14(%rbp)
  subl   $0x2,-0x4(%rbp)
L62:
  cmpl   $0x0,-0x14(%rbp)
  js     L25
  shll   -0x14(%rbp)
  subl   $0x1,-0x4(%rbp)
L25:
  mov    -0x4(%rbp),%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
__attribute__((always_)) int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fls>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L16
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L43
  shl    $0x10,%edi
  mov    $0x10,%eax
L43:
  test   $0xff000000,%edi
  jne    L14
  shl    $0x8,%edi
  sub    $0x8,%eax
L14:
  test   $0xf0000000,%edi
  jne    L48
  shl    $0x4,%edi
  sub    $0x4,%eax
L48:
  test   $0xc0000000,%edi
  jne    L32
  shl    $0x2,%edi
  sub    $0x2,%eax
L32:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L16:
  ret
```

assistant: ```c
__attribute__((always_)) int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L16
  mov    $0x20,%eax
  test   $0xffff0000,%edi
  jne    L39
  shl    $0x10,%edi
  mov    $0x10,%eax
L39:
  test   $0xff000000,%edi
  jne    L11
  shl    $0x8,%edi
  sub    $0x8,%eax
L11:
  test   $0xf0000000,%edi
  jne    L37
  shl    $0x4,%edi
  sub    $0x4,%eax
L37:
  test   $0xc0000000,%edi
  jne    L41
  shl    $0x2,%edi
  sub    $0x2,%eax
L41:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L16:
  ret
```

assistant: ```c
__attribute__((always_)) int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fls>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L10
  test   $0xffff0000,%edi
  je     L40
  mov    $0x18,%edx
  mov    $0x20,%eax
L38:
  test   $0xff000000,%edi
  jne    L55
  shl    $0x8,%edi
  mov    %edx,%eax
L55:
  test   $0xf0000000,%edi
  jne    L32
  shl    $0x4,%edi
  sub    $0x4,%eax
L32:
  test   $0xc0000000,%edi
  jne    L49
  shl    $0x2,%edi
  sub    $0x2,%eax
L49:
  cmp    $0x80000000,%edi
  sbb    $0x0,%eax
L10:
  ret
  nop
L40:
  shl    $0x10,%edi
  mov    $0x8,%edx
  mov    $0x10,%eax
  jmp    L38
```

assistant: ```c
__attribute__((always_)) int fls(int x) {
  int r = 32;
  if (!x)
    return 0;
  if (!(x & 0xffff0000u)) {
    x <<= 16;
    r -= 16;
  }
  if (!(x & 0xff000000u)) {
    x <<= 8;
    r -= 8;
  }
  if (!(x & 0xf0000000u)) {
    x <<= 4;
    r -= 4;
  }
  if (!(x & 0xc0000000u)) {
    x <<= 2;
    r -= 2;
  }
  if (!(x & 0x80000000u)) {
    x <<= 1;
    r -= 1;
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<tbinsearch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x18(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  comisd -0x28(%rbp),%xmm0
  jbe    L6
  mov    $0x0,%eax
  jmp    L28
L6:
  jmp    L42
L22:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm1
  movsd  -0x28(%rbp),%xmm0
  comisd %xmm1,%xmm0
  jbe    L19
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L42
L19:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
L42:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jg     L22
  mov    -0x8(%rbp),%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
int tbinsearch(size_t n, double *ordered, double val) {
  int b = 0;
  int t = n - 1;
  if (val < ordered[0])
    return 0;
  while (t > b + 1) {
    int c = (b + t) / 2;
    if (val > ordered[c])
      b = c;
    else
      t = c;
  }
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tbinsearch>:
  endbr64
  movsd  (%rsi),%xmm1
  mov    $0x0,%edx
  comisd %xmm0,%xmm1
  ja     L4
  lea    -0x1(%rdi),%edx
  mov    $0x0,%ecx
  jmp    L22
L14:
  lea    (%rcx,%rdx,1),%edi
  mov    %edi,%eax
  shr    $0x1f,%eax
  add    %edi,%eax
  sar    %eax
  movslq %eax,%rdi
  comisd (%rsi,%rdi,8),%xmm0
  cmovbe %eax,%edx
  cmova  %eax,%ecx
L22:
  lea    0x1(%rcx),%eax
  cmp    %edx,%eax
  jl     L14
L4:
  mov    %edx,%eax
  ret
```

assistant: ```c
int tbinsearch(size_t n, double *ordered, double val) {
  int b = 0;
  int t = n - 1;
  if (val < ordered[0])
    return 0;
  while (t > b + 1) {
    int c = (b + t) / 2;
    if (val > ordered[c])
      b = c;
    else
      t = c;
  }
  return t;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<tbinsearch>:
  endbr64
  movsd  (%rsi),%xmm1
  xor    %r8d,%r8d
  comisd %xmm0,%xmm1
  ja     L10
  lea    -0x1(%rdi),%r8d
  xor    %edx,%edx
  mov    $0x1,%ecx
  jmp    L47
  xchg   %ax,%ax
L20:
  lea    (%rdx,%r8,1),%eax
  sar    %eax
  movslq %eax,%rdi
  comisd (%rsi,%rdi,8),%xmm0
  jbe    L18
  mov    %eax,%edx
  lea    0x1(%rax),%ecx
L47:
  cmp    %r8d,%ecx
  jl     L20
L10:
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L18:
  mov    %eax,%r8d
  jmp    L47
```

assistant: ```c
int tbinsearch(size_t n, double *ordered, double val) {
  int b = 0;
  int t = n - 1;
  if (val < ordered[0])
    return 0;
  while (t > b + 1) {
    int c = (b + t) / 2;
    if (val > ordered[c])
      b = c;
    else
      t = c;
  }
  return t;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<tbinsearch>:
  endbr64
  movsd  (%rsi),%xmm1
  xor    %r8d,%r8d
  comisd %xmm0,%xmm1
  ja     L12
  lea    -0x1(%rdi),%r8d
  xor    %edx,%edx
  mov    $0x1,%ecx
  jmp    L16
  xchg   %ax,%ax
L17:
  lea    (%rdx,%r8,1),%eax
  sar    %eax
  movslq %eax,%rdi
  comisd (%rsi,%rdi,8),%xmm0
  jbe    L2
  mov    %eax,%edx
  lea    0x1(%rax),%ecx
L16:
  cmp    %r8d,%ecx
  jl     L17
L12:
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L2:
  mov    %eax,%r8d
  jmp    L16
```

assistant: ```c
int tbinsearch(size_t n, double *ordered, double val) {
  int b = 0;
  int t = n - 1;
  if (val < ordered[0])
    return 0;
  while (t > b + 1) {
    int c = (b + t) / 2;
    if (val > ordered[c])
      b = c;
    else
      t = c;
  }
  return t;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x5,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: %d

assistant: ```c
int main(void) {
  int i = 5, j = 0;
  int k = i / j;
  printf("%d", k);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%eax
  mov    $0x0,%ecx
  cltd
  idiv   %ecx
  mov    %eax,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
datatype: string

tool: D8: %d

assistant: ```c
int main(void) {
  int i = 5, j = 0;
  int k = i / j;
  printf("%d", k);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  ud2
```

assistant: ```c
int main(void) {
  int i = 5, j = 0;
  int k = i / j;
  printf("%d", k);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  ud2
```

assistant: ```c
int main(void) {
  int i = 5, j = 0;
  int k = i / j;
  printf("%d", k);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kinetic_energy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  movsd  %xmm0,-0x50(%rbp)
  movsd  %xmm1,-0x58(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  movl   $0x0,-0x2c(%rbp)
  jmp    L12
L22:
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x18(%rbp)
  movsd  -0x20(%rbp),%xmm1
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  -0x58(%rbp),%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm1
  movsd  -0x58(%rbp),%xmm0
  movq   D18(%rip),%xmm2
  xorpd  %xmm0,%xmm2
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  cltq
  add    $0x2,%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  -0x50(%rbp),%xmm1
  movsd  D16(%rip),%xmm0
  mulsd  %xmm0,%xmm1
  movsd  -0x20(%rbp),%xmm2
  movsd  -0x20(%rbp),%xmm0
  mulsd  %xmm0,%xmm2
  movsd  -0x18(%rbp),%xmm3
  movsd  -0x18(%rbp),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm0,%xmm2
  movsd  -0x10(%rbp),%xmm3
  movsd  -0x10(%rbp),%xmm0
  mulsd  %xmm3,%xmm0
  addsd  %xmm2,%xmm0
  mulsd  %xmm1,%xmm0
  movsd  -0x28(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x28(%rbp)
  addl   $0x1,-0x2c(%rbp)
L12:
  mov    -0x2c(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L22
  movsd  -0x28(%rbp),%xmm0
  movq   %xmm0,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D18
data_type: f32[2]
name: retrieve_data
arguments: data_tag: D16
data_type: f64

tool: {"D18": [0.0,-0.0]}

tool: D16: 0.5

assistant: ```c
double kinetic_energy(int num_ptcls, const double *x, const double *v, double mass, double omega) {
  double energy = 0.0;
  int i;
  double vr[3];
  for (i = 0; i < num_ptcls; ++i) {
    vr[0] = v[3 * i + 0];
    vr[1] = v[3 * i + 1];
    vr[0] -= (-omega) * x[3 * i + 1];
    vr[1] += (-omega) * x[3 * i + 0];
    vr[2] = v[3 * i + 2];
    energy += 0.5 * mass * (vr[0] * vr[0] + vr[1] * vr[1] + vr[2] * vr[2]);
  }
  return energy;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kinetic_energy>:
  endbr64
  mov    %rsi,%rcx
  movapd %xmm0,%xmm5
  test   %edi,%edi
  jle    L8
  mulsd  D13(%rip),%xmm5
  mov    %edi,%edi
  lea    (%rdi,%rdi,2),%rsi
  shl    $0x3,%rsi
  mov    $0x0,%eax
  pxor   %xmm0,%xmm0
  movapd %xmm1,%xmm6
  xorpd  D8(%rip),%xmm6
L7:
  movapd %xmm1,%xmm2
  mulsd  0x8(%rcx,%rax,1),%xmm2
  addsd  (%rdx,%rax,1),%xmm2
  movapd %xmm6,%xmm3
  mulsd  (%rcx,%rax,1),%xmm3
  addsd  0x8(%rdx,%rax,1),%xmm3
  movsd  0x10(%rdx,%rax,1),%xmm4
  mulsd  %xmm2,%xmm2
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm2
  mulsd  %xmm4,%xmm4
  addsd  %xmm4,%xmm2
  mulsd  %xmm5,%xmm2
  addsd  %xmm2,%xmm0
  add    $0x18,%rax
  cmp    %rsi,%rax
  jne    L7
  ret
L8:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_guessed: f64
name: unpack_data
arguments: data_label: D8
type_guessed: f32[4]

tool: D13: 0.5

tool: {"D8": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double kinetic_energy(int num_ptcls, const double *x, const double *v, double mass, double omega) {
  double energy = 0.0;
  int i;
  double vr[3];
  for (i = 0; i < num_ptcls; ++i) {
    vr[0] = v[3 * i + 0];
    vr[1] = v[3 * i + 1];
    vr[0] -= (-omega) * x[3 * i + 1];
    vr[1] += (-omega) * x[3 * i + 0];
    vr[2] = v[3 * i + 2];
    energy += 0.5 * mass * (vr[0] * vr[0] + vr[1] * vr[1] + vr[2] * vr[2]);
  }
  return energy;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<kinetic_energy>:
  endbr64
  mov    %rsi,%rcx
  movapd %xmm0,%xmm5
  test   %edi,%edi
  jle    L18
  movslq %edi,%rdi
  movapd %xmm1,%xmm6
  pxor   %xmm0,%xmm0
  xor    %eax,%eax
  mulsd  D2(%rip),%xmm5
  lea    (%rdi,%rdi,2),%rsi
  xorpd  D16(%rip),%xmm6
  shl    $0x3,%rsi
  nopl   0x0(%rax)
L11:
  movsd  0x8(%rcx,%rax,1),%xmm2
  movsd  (%rcx,%rax,1),%xmm3
  movsd  0x10(%rdx,%rax,1),%xmm4
  mulsd  %xmm1,%xmm2
  mulsd  %xmm6,%xmm3
  addsd  (%rdx,%rax,1),%xmm2
  addsd  0x8(%rdx,%rax,1),%xmm3
  mulsd  %xmm4,%xmm4
  add    $0x18,%rax
  mulsd  %xmm2,%xmm2
  mulsd  %xmm3,%xmm3
  addsd  %xmm3,%xmm2
  addsd  %xmm4,%xmm2
  mulsd  %xmm5,%xmm2
  addsd  %xmm2,%xmm0
  cmp    %rax,%rsi
  jne    L11
  ret
  nopw   0x0(%rax,%rax,1)
L18:
  pxor   %xmm0,%xmm0
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_guessed: f64
name: read_data
arguments: label: D16
type_guessed: f32[4]

tool: D2: 0.5

tool: {"D16": [0.0,-0.0,0.0,0.0]}

assistant: ```c
double kinetic_energy(int num_ptcls, const double *x, const double *v, double mass, double omega) {
  double energy = 0.0;
  int i;
  double vr[3];
  for (i = 0; i < num_ptcls; ++i) {
    vr[0] = v[3 * i + 0];
    vr[1] = v[3 * i + 1];
    vr[0] -= (-omega) * x[3 * i + 1];
    vr[1] += (-omega) * x[3 * i + 0];
    vr[2] = v[3 * i + 2];
    energy += 0.5 * mass * (vr[0] * vr[0] + vr[1] * vr[1] + vr[2] * vr[2]);
  }
  return energy;
}
```