ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<preOrder>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movslq %esi,%rbx
  sub    $0x18,%rsp
  cmp    %edx,%ebx
  jl     L128
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L128:
  lea    (%rbx,%rbx,1),%r13d
  mov    %rdi,%rbp
  mov    %edx,%r12d
  lea    D3(%rip),%r14
  cmp    %edx,%r13d
  jl     L105
  add    $0x1,%r13d
  cmp    %r12d,%r13d
  jl     L124
L23:
  mov    0x0(%rbp,%rbx,4),%esi
  add    $0x18,%rsp
  mov    %r14,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L105:
  lea    0x0(,%rbx,4),%r15d
  cmp    %r15d,%edx
  jg     L114
L11:
  add    $0x1,%r15d
  cmp    %r15d,%r12d
  jg     L60
L85:
  movslq %r13d,%rax
  mov    %r14,%rdi
  add    $0x1,%r13d
  mov    0x0(%rbp,%rax,4),%esi
  call   <printf@plt>
  cmp    %r12d,%r13d
  jge    L23
L124:
  lea    0x0(%r13,%r13,1),%r15d
  cmp    %r15d,%r12d
  jg     L111
L29:
  add    $0x1,%r15d
  cmp    %r15d,%r12d
  jg     L6
L92:
  movslq %r13d,%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,4),%esi
  call   <printf@plt>
  jmp    L23
  nopw   0x0(%rax,%rax,1)
L114:
  lea    0x0(,%rbx,8),%esi
  mov    %esi,0xc(%rsp)
  call   <preOrder>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  mov    %r12d,%edx
  add    $0x1,%esi
  call   <preOrder>
  movslq %r15d,%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,4),%esi
  call   <printf@plt>
  jmp    L11
  cs nopw 0x0(%rax,%rax,1)
L6:
  lea    (%r15,%r15,1),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  movslq %r15d,%r15
  mov    %esi,0xc(%rsp)
  call   <preOrder>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  mov    %r12d,%edx
  add    $0x1,%esi
  call   <preOrder>
  mov    0x0(%rbp,%r15,4),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L92
  nopw   0x0(%rax,%rax,1)
L111:
  lea    0x0(,%r13,4),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  mov    %esi,0xc(%rsp)
  call   <preOrder>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  mov    %r12d,%edx
  add    $0x1,%esi
  call   <preOrder>
  movslq %r15d,%rax
  mov    %r14,%rdi
  mov    0x0(%rbp,%rax,4),%esi
  call   <printf@plt>
  jmp    L29
  nopl   (%rax)
L60:
  lea    (%r15,%r15,1),%esi
  mov    %r12d,%edx
  mov    %rbp,%rdi
  movslq %r15d,%r15
  mov    %esi,0xc(%rsp)
  call   <preOrder>
  mov    0xc(%rsp),%esi
  mov    %rbp,%rdi
  mov    %r12d,%edx
  add    $0x1,%esi
  call   <preOrder>
  mov    0x0(%rbp,%r15,4),%esi
  mov    %r14,%rdi
  call   <printf@plt>
  jmp    L85
```

tool_calls: name: read_data
arguments: label: D3
data_type: string

tool: D3: %d, 

assistant: ```c
void preOrder(int *a, int i, int n) {
  if (i < n) {
    preOrder(a, 2 * i, n);
    preOrder(a, 2 * i + 1, n);
    printf("%d, ", a[i]);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0xa,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  mov    -0x28(%rbp),%edx
  mov    -0x24(%rbp),%ecx
  lea    -0x20(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <coin_change_problem@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D1
type_infered: string

tool: D1: %d


assistant: ```c
int main() {
  int coin[] = {2, 5, 3, 6};
  int n = 10, m = sizeof(coin) / sizeof(coin[0]);
  printf("%d\n", coin_change_problem(coin, m, n));
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x5,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x6,0xc(%rsp)
  mov    %rsp,%rdi
  mov    $0xa,%edx
  mov    $0x4,%esi
  call   <coin_change_problem@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D7
datatype: string

tool: D7: %d


assistant: ```c
int main() {
  int coin[] = {2, 5, 3, 6};
  int n = 10, m = sizeof(coin) / sizeof(coin[0]);
  printf("%d\n", coin_change_problem(coin, m, n));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%esi
  mov    $0xa,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x500000002,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x8(%rsp)
  call   <coin_change_problem@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D1
type: string

tool: D1: %d


assistant: ```c
int main() {
  int coin[] = {2, 5, 3, 6};
  int n = 10, m = sizeof(coin) / sizeof(coin[0]);
  printf("%d\n", coin_change_problem(coin, m, n));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    $0x4,%esi
  mov    $0xa,%edx
  movdqa D16(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movaps %xmm0,(%rsp)
  call   <coin_change_problem@plt>
  lea    D18(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
data_type: byte[16]
name: extract_symbolic_data
arguments: data_tag: D18
data_type: string

tool: {"D16": [0x02,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00]}

tool: D18: %d


assistant: ```c
int main() {
  int coin[] = {2, 5, 3, 6};
  int n = 10, m = sizeof(coin) / sizeof(coin[0]);
  printf("%d\n", coin_change_problem(coin, m, n));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x5,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: string

tool: D8: %ld 

assistant: ```c
int main(void) {
  printf("%ld ", factorial(5));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <factorial@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
data_type: string

tool: D4: %ld 

assistant: ```c
int main(void) {
  printf("%ld ", factorial(5));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <factorial@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: %ld 

assistant: ```c
int main(void) {
  printf("%ld ", factorial(5));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x5,%edi
  call   <factorial@plt>
  lea    D1(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D1
data_type: string

tool: D1: %ld 

assistant: ```c
int main(void) {
  printf("%ld ", factorial(5));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_seed_old>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x24(%rbp),%rax
  mov    %rax,%rdi
  call   <time@plt>
  mov    %eax,-0x28(%rbp)
  lea    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <localtime@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  cmpl   $0xc,-0x20(%rbp)
  jle    L7
  subl   $0xc,-0x20(%rbp)
L7:
  subl   $0x1,-0x20(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x4(%rax),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x10(%rbp),%rax
  mov    0x8(%rax),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x20(%rbp),%eax
  imul   $0x3c,%eax,%edx
  mov    -0x18(%rbp),%eax
  add    %edx,%eax
  imul   $0x3c,%eax,%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x1c(%rbp)
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x1c(%rbp),%xmm0
  movsd  D10(%rip),%xmm2
  movapd %xmm0,%xmm1
  divsd  %xmm2,%xmm1
  movsd  D26(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%eax
  mov    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x1c(%rbp)
  jg     L22
  movl   $0x1,-0x1c(%rbp)
L22:
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <tprintf@plt>
  mov    -0x1c(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D10
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D26
type_infered: byte[8]
name: disassemble_data
arguments: data_tag: D25
type_infered: string

tool: {"D10": [0x00,0x00,0x00,0x00,0x00,0x18,0xe5,0x40]}

tool: {"D26": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

tool: D25: Seed: %d


assistant: ```c
int get_seed_old() {
  time_t clock;
  struct tm *lt;
  time_t tloc;
  int ihour, imin, isec, seed;
  clock = time(&tloc);
  lt = localtime(&clock);
  ihour = lt->tm_hour;
  if (ihour > 12)
    ihour -= 12;
  ihour--;
  imin = lt->tm_min;
  isec = lt->tm_sec;
  seed = isec + 60 * (imin + 60 * ihour);
  seed = (int)((double)(seed / (60.0 * 60.0 * 12.0)) * 2147483647);
  if (seed <= 0)
    seed = 1;
  tprintf("Seed: %d\n", seed);
  return seed;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<get_seed_old>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %eax,(%rsp)
  mov    %rsp,%rdi
  call   <localtime@plt>
  mov    (%rax),%edx
  lea    -0xc(%rdx),%ecx
  cmp    $0xc,%edx
  cmovg  %ecx,%edx
  sub    $0x1,%edx
  imul   $0x3c,%edx,%edx
  add    0x4(%rax),%edx
  imul   $0x3c,%edx,%edx
  add    0x8(%rax),%edx
  pxor   %xmm0,%xmm0
  cvtsi2sd %edx,%xmm0
  divsd  D0(%rip),%xmm0
  mulsd  D24(%rip),%xmm0
  cvttsd2si %xmm0,%ebx
  test   %ebx,%ebx
  mov    $0x1,%eax
  cmovle %eax,%ebx
  mov    %ebx,%esi
  lea    D13(%rip),%rdi
  call   <tprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    %ebx,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type: byte[8]
name: extract_symbolic_data
arguments: tag: D24
type: byte[8]
name: extract_symbolic_data
arguments: tag: D13
type: string

tool: {"D0": [0x00,0x00,0x00,0x00,0x00,0x18,0xe5,0x40]}

tool: {"D24": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

tool: D13: Seed: %d


assistant: ```c
int get_seed_old() {
  time_t clock;
  struct tm *lt;
  time_t tloc;
  int ihour, imin, isec, seed;
  clock = time(&tloc);
  lt = localtime(&clock);
  ihour = lt->tm_hour;
  if (ihour > 12)
    ihour -= 12;
  ihour--;
  imin = lt->tm_min;
  isec = lt->tm_sec;
  seed = isec + 60 * (imin + 60 * ihour);
  seed = (int)((double)(seed / (60.0 * 60.0 * 12.0)) * 2147483647);
  if (seed <= 0)
    seed = 1;
  tprintf("Seed: %d\n", seed);
  return seed;
}
```
user: What is the c source code of the assembly code below:

```asm
<get_seed_old>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  lea    D9(%rip),%rdi
  mov    (%rax),%edx
  cmp    $0xc,%edx
  lea    -0xc(%rdx),%ecx
  cmovg  %ecx,%edx
  sub    $0x1,%edx
  imul   $0x3c,%edx,%edx
  add    0x4(%rax),%edx
  imul   $0x3c,%edx,%edx
  add    0x8(%rax),%edx
  mov    $0x1,%eax
  cvtsi2sd %edx,%xmm0
  divsd  D26(%rip),%xmm0
  mulsd  D20(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  test   %r12d,%r12d
  cmovle %eax,%r12d
  mov    %r12d,%esi
  call   <tprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string
name: parse_data
arguments: data_tag: D26
data_type: byte[8]
name: parse_data
arguments: data_tag: D20
data_type: byte[8]

tool: D9: Seed: %d


tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x18,0xe5,0x40]}

tool: {"D20": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

assistant: ```c
int get_seed_old() {
  time_t clock;
  struct tm *lt;
  time_t tloc;
  int ihour, imin, isec, seed;
  clock = time(&tloc);
  lt = localtime(&clock);
  ihour = lt->tm_hour;
  if (ihour > 12)
    ihour -= 12;
  ihour--;
  imin = lt->tm_min;
  isec = lt->tm_sec;
  seed = isec + 60 * (imin + 60 * ihour);
  seed = (int)((double)(seed / (60.0 * 60.0 * 12.0)) * 2147483647);
  if (seed <= 0)
    seed = 1;
  tprintf("Seed: %d\n", seed);
  return seed;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_seed_old>:
  endbr64
  push   %r12
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <time@plt>
  mov    %rsp,%rdi
  mov    %eax,(%rsp)
  call   <localtime@plt>
  pxor   %xmm0,%xmm0
  lea    D16(%rip),%rdi
  mov    (%rax),%edx
  cmp    $0xc,%edx
  lea    -0xc(%rdx),%ecx
  cmovg  %ecx,%edx
  sub    $0x1,%edx
  imul   $0x3c,%edx,%edx
  add    0x4(%rax),%edx
  imul   $0x3c,%edx,%edx
  add    0x8(%rax),%edx
  mov    $0x1,%eax
  cvtsi2sd %edx,%xmm0
  divsd  D26(%rip),%xmm0
  mulsd  D19(%rip),%xmm0
  cvttsd2si %xmm0,%r12d
  test   %r12d,%r12d
  cmovle %eax,%r12d
  mov    %r12d,%esi
  call   <tprintf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x10,%rsp
  mov    %r12d,%eax
  pop    %r12
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D26
datatype: byte[8]
name: extract_symbolic_data
arguments: label: D19
datatype: byte[8]

tool: D16: Seed: %d


tool: {"D26": [0x00,0x00,0x00,0x00,0x00,0x18,0xe5,0x40]}

tool: {"D19": [0x00,0x00,0xc0,0xff,0xff,0xff,0xdf,0x41]}

assistant: ```c
int get_seed_old() {
  time_t clock;
  struct tm *lt;
  time_t tloc;
  int ihour, imin, isec, seed;
  clock = time(&tloc);
  lt = localtime(&clock);
  ihour = lt->tm_hour;
  if (ihour > 12)
    ihour -= 12;
  ihour--;
  imin = lt->tm_min;
  isec = lt->tm_sec;
  seed = isec + 60 * (imin + 60 * ihour);
  seed = (int)((double)(seed / (60.0 * 60.0 * 12.0)) * 2147483647);
  if (seed <= 0)
    seed = 1;
  tprintf("Seed: %d\n", seed);
  return seed;
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_binary>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x4,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L36
L11:
  movl   $0x7,-0x14(%rbp)
  jmp    L16
L5:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %eax,%esi
  mov    -0x14(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  and    %esi,%eax
  mov    %al,-0x19(%rbp)
  movzbl -0x19(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  mov    %al,-0x19(%rbp)
  movzbl -0x19(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  subl   $0x1,-0x14(%rbp)
L16:
  cmpl   $0x0,-0x14(%rbp)
  jns    L5
  subl   $0x1,-0x18(%rbp)
L36:
  cmpl   $0x0,-0x18(%rbp)
  jns    L11
  nop
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
datatype: string

tool: D3: %u

assistant: ```c
void print_binary(void const *const ptr) {
  unsigned char *b = (unsigned char *)ptr;
  unsigned char byte;
  size_t size = sizeof(uint64_t);
  int i, j;
  for (i = size - 1; i >= 0; i--) {
    for (j = 7; j >= 0; j--) {
      byte = b[i] & (1 << j);
      byte >>= j;
      printf("%u", byte);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_binary>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  lea    0x3(%rdi),%rbp
  lea    D5(%rip),%r12
L13:
  mov    $0x7,%ebx
L5:
  mov    $0x1,%esi
  mov    %ebx,%ecx
  shl    %cl,%esi
  and    0x0(%rbp),%sil
  movzbl %sil,%esi
  sar    %cl,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  sub    $0x1,%ebx
  cmp    $0xffffffff,%ebx
  jne    L5
  lea    -0x1(%rbp),%rax
  cmp    %r13,%rbp
  je     L20
  mov    %rax,%rbp
  jmp    L13
L20:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D5
type_guessed: string

tool: D5: %u

assistant: ```c
void print_binary(void const *const ptr) {
  unsigned char *b = (unsigned char *)ptr;
  unsigned char byte;
  size_t size = sizeof(uint64_t);
  int i, j;
  for (i = size - 1; i >= 0; i--) {
    for (j = 7; j >= 0; j--) {
      byte = b[i] & (1 << j);
      byte >>= j;
      printf("%u", byte);
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<print_binary>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  lea    0x3(%rdi),%rbx
L24:
  mov    $0x7,%r14d
  nopl   (%rax)
L16:
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %r12,%rdi
  shl    %cl,%esi
  and    (%rbx),%sil
  movzbl %sil,%esi
  sar    %cl,%esi
  call   <printf@plt>
  sub    $0x1,%r14d
  jae    L16
  lea    -0x1(%rbx),%rax
  cmp    %rbx,%r13
  je     L25
  mov    %rax,%rbx
  jmp    L24
  nopl   0x0(%rax)
L25:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
datatype: string

tool: D2: %u

assistant: ```c
void print_binary(void const *const ptr) {
  unsigned char *b = (unsigned char *)ptr;
  unsigned char byte;
  size_t size = sizeof(uint64_t);
  int i, j;
  for (i = size - 1; i >= 0; i--) {
    for (j = 7; j >= 0; j--) {
      byte = b[i] & (1 << j);
      byte >>= j;
      printf("%u", byte);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_binary>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  lea    D0(%rip),%r12
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  lea    0x3(%rdi),%rbx
L10:
  mov    $0x7,%r14d
  nopl   (%rax)
L14:
  mov    %r14d,%ecx
  mov    %ebp,%esi
  mov    %r12,%rdi
  shl    %cl,%esi
  and    (%rbx),%sil
  movzbl %sil,%esi
  sar    %cl,%esi
  call   <printf@plt>
  sub    $0x1,%r14d
  jae    L14
  lea    -0x1(%rbx),%rax
  cmp    %rbx,%r13
  je     L21
  mov    %rax,%rbx
  jmp    L10
  nopl   0x0(%rax)
L21:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
data_type: string

tool: D0: %u

assistant: ```c
void print_binary(void const *const ptr) {
  unsigned char *b = (unsigned char *)ptr;
  unsigned char byte;
  size_t size = sizeof(uint64_t);
  int i, j;
  for (i = size - 1; i >= 0; i--) {
    for (j = 7; j >= 0; j--) {
      byte = b[i] & (1 << j);
      byte >>= j;
      printf("%u", byte);
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L21
L37:
  mov    -0xc(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  cmpl   $0xff,-0xc(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L27:
  mov    -0x8(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  cmpl   $0xff,-0x8(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L8:
  mov    -0x4(%rbp),%eax
  not    %eax
  shr    $0x1f,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  cmpl   $0xff,-0x4(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__analyzer_eval@plt>
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0xff,-0x4(%rbp)
  jle    L8
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0xff,-0x8(%rbp)
  jle    L27
  addl   $0x1,-0xc(%rbp)
L21:
  cmpl   $0xff,-0xc(%rbp)
  jle    L37
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  nop
  leave
  ret
```

assistant: ```c
void test(void) {
  int i, j, k;
  __analyzer_dump_exploded_nodes(0);
  for (i = 0; i < 256; i++) {
    __analyzer_eval(i >= 0);
    __analyzer_eval(i < 256);
    for (j = 0; j < 256; j++) {
      __analyzer_eval(j >= 0);
      __analyzer_eval(j < 256);
      __analyzer_dump_exploded_nodes(0);
      for (k = 0; k < 256; k++) {
        __analyzer_eval(k >= 0);
        __analyzer_eval(k < 256);
        __analyzer_dump_exploded_nodes(0);
      }
    }
  }
  __analyzer_dump_exploded_nodes(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<test>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  mov    $0x0,%r12d
L14:
  mov    %r12d,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <__analyzer_eval@plt>
  mov    $0x1,%edi
  call   <__analyzer_eval@plt>
  mov    $0x0,%ebp
L13:
  mov    %ebp,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <__analyzer_eval@plt>
  mov    $0x1,%edi
  call   <__analyzer_eval@plt>
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  mov    $0x0,%ebx
L12:
  mov    %ebx,%edi
  not    %edi
  shr    $0x1f,%edi
  call   <__analyzer_eval@plt>
  mov    $0x1,%edi
  call   <__analyzer_eval@plt>
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  add    $0x1,%ebx
  cmp    $0x100,%ebx
  jne    L12
  add    $0x1,%ebp
  cmp    $0x100,%ebp
  jne    L13
  add    $0x1,%r12d
  cmp    $0x100,%r12d
  jne    L14
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void test(void) {
  int i, j, k;
  __analyzer_dump_exploded_nodes(0);
  for (i = 0; i < 256; i++) {
    __analyzer_eval(i >= 0);
    __analyzer_eval(i < 256);
    for (j = 0; j < 256; j++) {
      __analyzer_eval(j >= 0);
      __analyzer_eval(j < 256);
      __analyzer_dump_exploded_nodes(0);
      for (k = 0; k < 256; k++) {
        __analyzer_eval(k >= 0);
        __analyzer_eval(k < 256);
        __analyzer_dump_exploded_nodes(0);
      }
    }
  }
  __analyzer_dump_exploded_nodes(0);
}
```