ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <GetInt@plt>
  cmp    $0x7,%eax
  jg     L27
  cmp    $0x3,%eax
  jg     L59
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L53
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L54
L27:
  sub    $0x8,%eax
  cmp    $0x2,%eax
  ja     L53
  lea    D30(%rip),%rdi
  call   <printf@plt>
L53:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L54:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L59:
  lea    D15(%rip),%rdi
  call   <printf@plt>
  jmp    L54
```

tool_calls: name: read_data
arguments: data_label: D5
data_type: string
name: read_data
arguments: data_label: D20
data_type: string
name: read_data
arguments: data_label: D30
data_type: string
name: read_data
arguments: data_label: D12
data_type: string
name: read_data
arguments: data_label: D15
data_type: string

tool: D5: Give me an int between 1 and 10: 

tool: D20: You picked a small int!


tool: D30: You picked a large int!


tool: D12: You picked an invalid int!


tool: D15: You picked a medium int!


assistant: ```c
int main(void) {
  printf("Give me an int between 1 and 10: ");
  int n = GetInt();
  switch (n) {
  case 1:
  case 2:
  case 3:
    printf("You picked a small int!\n");
    break;
  case 4:
  case 5:
  case 6:
  case 7:
    printf("You picked a medium int!\n");
    break;
  case 8:
  case 9:
  case 10:
    printf("You picked a large int!\n");
  default:
    printf("You picked an invalid int!\n");
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInt@plt>
  cmp    $0x7,%eax
  jg     L57
  cmp    $0x3,%eax
  jg     L41
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L33
  lea    D2(%rip),%rdi
  call   <printf@plt>
L16:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L57:
  sub    $0x8,%eax
  cmp    $0x2,%eax
  ja     L33
  lea    D41(%rip),%rdi
  call   <printf@plt>
L33:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L16
L41:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L16
```

tool_calls: name: unpack_data
arguments: data_tag: D23
type: string
name: unpack_data
arguments: data_tag: D2
type: string
name: unpack_data
arguments: data_tag: D41
type: string
name: unpack_data
arguments: data_tag: D0
type: string
name: unpack_data
arguments: data_tag: D44
type: string

tool: D23: Give me an int between 1 and 10: 

tool: D2: You picked a small int!


tool: D41: You picked a large int!


tool: D0: You picked an invalid int!


tool: D44: You picked a medium int!


assistant: ```c
int main(void) {
  printf("Give me an int between 1 and 10: ");
  int n = GetInt();
  switch (n) {
  case 1:
  case 2:
  case 3:
    printf("You picked a small int!\n");
    break;
  case 4:
  case 5:
  case 6:
  case 7:
    printf("You picked a medium int!\n");
    break;
  case 8:
  case 9:
  case 10:
    printf("You picked a large int!\n");
  default:
    printf("You picked an invalid int!\n");
    break;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <GetInt@plt>
  cmp    $0x7,%eax
  jg     L24
  cmp    $0x3,%eax
  jg     L58
  sub    $0x1,%eax
  cmp    $0x2,%eax
  ja     L38
  lea    D33(%rip),%rdi
  call   <printf@plt>
L8:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L24:
  sub    $0x8,%eax
  cmp    $0x2,%eax
  ja     L38
  lea    D40(%rip),%rdi
  call   <printf@plt>
L38:
  lea    D18(%rip),%rdi
  call   <printf@plt>
  jmp    L8
L58:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  jmp    L8
```

tool_calls: name: unpack_data
arguments: tag: D36
datatype: string
name: unpack_data
arguments: tag: D33
datatype: string
name: unpack_data
arguments: tag: D40
datatype: string
name: unpack_data
arguments: tag: D18
datatype: string
name: unpack_data
arguments: tag: D16
datatype: string

tool: D36: Give me an int between 1 and 10: 

tool: D33: You picked a small int!


tool: D40: You picked a large int!


tool: D18: You picked an invalid int!


tool: D16: You picked a medium int!


assistant: ```c
int main(void) {
  printf("Give me an int between 1 and 10: ");
  int n = GetInt();
  switch (n) {
  case 1:
  case 2:
  case 3:
    printf("You picked a small int!\n");
    break;
  case 4:
  case 5:
  case 6:
  case 7:
    printf("You picked a medium int!\n");
    break;
  case 8:
  case 9:
  case 10:
    printf("You picked a large int!\n");
  default:
    printf("You picked an invalid int!\n");
    break;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sumNumbersFrom1ToX>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L10:
  mov    -0x14(%rbp),%eax
  add    %eax,-0x4(%rbp)
L9:
  cmpl   $0x0,-0x14(%rbp)
  jg     L10
  subl   $0x1,-0x14(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
sumNumbersFrom1ToX(int x) {
  int s = 0;
  while (x > 0)
    s += x;
  x--;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sumNumbersFrom1ToX>:
  endbr64
L7:
  test   %edi,%edi
  jg     L7
  ret
```

assistant: ```c
sumNumbersFrom1ToX(int x) {
  int s = 0;
  while (x > 0)
    s += x;
  x--;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sumNumbersFrom1ToX>:
  endbr64
  nopl   0x0(%rax)
L2:
  test   %edi,%edi
  jg     L2
  ret
```

assistant: ```c
sumNumbersFrom1ToX(int x) {
  int s = 0;
  while (x > 0)
    s += x;
  x--;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sumNumbersFrom1ToX>:
  endbr64
  test   %edi,%edi
  jle    L10
L12:
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
sumNumbersFrom1ToX(int x) {
  int s = 0;
  while (x > 0)
    s += x;
  x--;
}
```
user: What is the c source code of the assembly code below?

```asm
<ta_talloc_vasprintf_append>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  lea    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <ta_vasprintf_append@plt>
  mov    %eax,%edi
  call   <ta_oom_b@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *ta_talloc_vasprintf_append(char *s, const char *fmt, va_list ap) {
  ta_oom_b(ta_vasprintf_append(&s, fmt, ap));
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ta_talloc_vasprintf_append>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <ta_vasprintf_append@plt>
  mov    %eax,%edi
  call   <ta_oom_b@plt>
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  ret
```

assistant: ```c
char *ta_talloc_vasprintf_append(char *s, const char *fmt, va_list ap) {
  ta_oom_b(ta_vasprintf_append(&s, fmt, ap));
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<ta_talloc_vasprintf_append>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <ta_vasprintf_append@plt>
  mov    %eax,%edi
  call   <ta_oom_b@plt>
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  ret
```

assistant: ```c
char *ta_talloc_vasprintf_append(char *s, const char *fmt, va_list ap) {
  ta_oom_b(ta_vasprintf_append(&s, fmt, ap));
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ta_talloc_vasprintf_append>:
  endbr64
  sub    $0x18,%rsp
  mov    %rdi,0x8(%rsp)
  lea    0x8(%rsp),%rdi
  call   <ta_vasprintf_append@plt>
  mov    %eax,%edi
  call   <ta_oom_b@plt>
  mov    0x8(%rsp),%rax
  add    $0x18,%rsp
  ret
```

assistant: ```c
char *ta_talloc_vasprintf_append(char *s, const char *fmt, va_list ap) {
  ta_oom_b(ta_vasprintf_append(&s, fmt, ap));
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L6
  mov    $0x0,%eax
  call   <abort@plt>
L6:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  if (foo(1) != 1)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x1,%eax
  jne    L3
L16:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
```

assistant: ```c
int main() {
  if (foo(1) != 1)
    abort();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L8
  xor    %eax,%eax
  call   <abort@plt>
L8:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(1) != 1)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <foo@plt>
  cmp    $0x1,%eax
  je     L5
  xor    %eax,%eax
  call   <abort@plt>
L5:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  if (foo(1) != 1)
    abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<GaussSeidelSeqLoopErr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,0x10(%rsp)
  movsd  %xmm0,0x18(%rsp)
  movapd %xmm0,%xmm2
  mulsd  D12(%rip),%xmm2
  comisd %xmm0,%xmm2
  jb     L64
  mov    %esi,%r14d
  mov    %edx,%ebp
  mov    %ecx,%r15d
  mov    %r9,%r13
  mov    %edx,%eax
  imul   %esi,%eax
  mov    %eax,0xc(%rsp)
  lea    -0x3(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%r12
  lea    -0x3(%rdx),%eax
  lea    0x10(,%rax,8),%rbx
  jmp    L16
L91:
  mov    0x8(%rcx),%rdx
  mov    (%rcx),%rdi
  mov    0x10(%rcx),%rsi
  movsd  (%rdi,%rax,1),%xmm0
  addsd  (%rsi,%rax,1),%xmm0
  addsd  -0x8(%rdx,%rax,1),%xmm0
  mov    %rax,%rsi
  add    $0x8,%rax
  addsd  (%rdx,%rax,1),%xmm0
  mulsd  D16(%rip),%xmm0
  add    %rsi,%rdx
  movapd %xmm0,%xmm1
  subsd  (%rdx),%xmm1
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  movsd  %xmm0,(%rdx)
  cmp    %rbx,%rax
  jne    L91
L1:
  add    $0x8,%rcx
  cmp    %r12,%rcx
  je     L42
L98:
  mov    $0x8,%eax
  cmp    $0x2,%ebp
  jg     L91
  jmp    L1
L42:
  addl   $0x1,0x0(%r13)
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  cltd
  idivl  0xc(%rsp)
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  comisd 0x18(%rsp),%xmm2
  jb     L64
L16:
  cmp    %r15d,0x0(%r13)
  jge    L64
  mov    0x10(%rsp),%rcx
  cmp    $0x2,%r14d
  jg     L98
  jmp    L42
L64:
  movapd %xmm2,%xmm0
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: label: D12
datatype: f64
name: read_data
arguments: label: D16
datatype: f64

tool: D12: 10

tool: D16: 0.25

assistant: ```c
double GaussSeidelSeqLoopErr(double **u, int m, int n, double eps, int maxit, int iterations_print, int *iterations) {
  int i, j;
  double v;
  double error = 10.0 * eps;
  while (error >= eps && (*iterations) < maxit) {
    for (i = 1; i < m - 1; i++) {
      for (j = 1; j < n - 1; j++) {
        v = 0.25 * (u[i - 1][j] + u[i + 1][j] + u[i][j - 1] + u[i][j + 1]);
        error += (v - u[i][j]) * (v - u[i][j]);
        u[i][j] = v;
      }
    }
    (*iterations)++;
    error = sqrt(error) / (m * n);
  }
  return error;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<GaussSeidelSeqLoopErr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  D22(%rip),%xmm2
  movsd  %xmm0,(%rsp)
  mulsd  %xmm0,%xmm2
  comisd %xmm0,%xmm2
  jb     L31
  mov    %edx,%eax
  movsd  D13(%rip),%xmm3
  mov    %rdi,%r12
  mov    %esi,%ebp
  imul   %esi,%eax
  mov    %ecx,%r13d
  mov    %r9,%r14
  mov    %eax,0x8(%rsp)
  lea    -0x3(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rbx
  lea    -0x3(%rdx),%eax
  mov    %eax,0xc(%rsp)
  mov    %rbx,%r15
  mov    %edx,%ebx
  nopl   (%rax)
L62:
  mov    (%r14),%r11d
  cmp    %r13d,%r11d
  jge    L31
  mov    0xc(%rsp),%edi
  mov    %r12,%r10
  add    $0x2,%rdi
  cmp    $0x2,%ebp
  jle    L24
  nopl   0x0(%rax)
L5:
  cmp    $0x2,%ebx
  jle    L29
  mov    (%r10),%rsi
  mov    0x10(%r10),%rcx
  mov    $0x1,%eax
  mov    0x8(%r10),%rdx
  nopl   (%rax)
L9:
  movsd  (%rsi,%rax,8),%xmm0
  addsd  (%rcx,%rax,8),%xmm0
  addsd  -0x8(%rdx,%rax,8),%xmm0
  addsd  0x8(%rdx,%rax,8),%xmm0
  mulsd  %xmm3,%xmm0
  movapd %xmm0,%xmm1
  subsd  (%rdx,%rax,8),%xmm1
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  mulsd  %xmm1,%xmm1
  addsd  %xmm1,%xmm2
  cmp    %rax,%rdi
  jne    L9
L29:
  add    $0x8,%r10
  cmp    %r10,%r15
  jne    L5
L24:
  add    $0x1,%r11d
  movapd %xmm2,%xmm0
  mov    %r11d,(%r14)
  call   <sqrt@plt>
  pxor   %xmm2,%xmm2
  cltd
  idivl  0x8(%rsp)
  cvtsi2sd %eax,%xmm2
  comisd (%rsp),%xmm2
  mov    D13(%rip),%rax
  movq   %rax,%xmm3
  jae    L62
L31:
  add    $0x18,%rsp
  movapd %xmm2,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: label: D22
type_guessed: f64
name: parse_data
arguments: label: D13
type_guessed: f64

tool: D22: 10

tool: D13: 0.25

assistant: ```c
double GaussSeidelSeqLoopErr(double **u, int m, int n, double eps, int maxit, int iterations_print, int *iterations) {
  int i, j;
  double v;
  double error = 10.0 * eps;
  while (error >= eps && (*iterations) < maxit) {
    for (i = 1; i < m - 1; i++) {
      for (j = 1; j < n - 1; j++) {
        v = 0.25 * (u[i - 1][j] + u[i + 1][j] + u[i][j - 1] + u[i][j + 1]);
        error += (v - u[i][j]) * (v - u[i][j]);
        u[i][j] = v;
      }
    }
    (*iterations)++;
    error = sqrt(error) / (m * n);
  }
  return error;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <f1@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
main() {
  int x = 0;
  x = f1(1, 2);
  printf(x);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <f1@plt>
  movslq %eax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int x = 0;
  x = f1(1, 2);
  printf(x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <f1@plt>
  movslq %eax,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int x = 0;
  x = f1(1, 2);
  printf(x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%esi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <f1@plt>
  movslq %eax,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  int x = 0;
  x = f1(1, 2);
  printf(x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<m48chrSetClock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <m48clock@plt>
  nop
  leave
  ret
```

assistant: ```c
void m48chrSetClock(uint16_t addr, uint8_t val) {
  (void)val;
  m48clock(addr);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<m48chrSetClock>:
  endbr64
  sub    $0x8,%rsp
  call   <m48clock@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void m48chrSetClock(uint16_t addr, uint8_t val) {
  (void)val;
  m48clock(addr);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m48chrSetClock>:
  endbr64
  jmp    1050 <m48clock@plt>
```

assistant: ```c
void m48chrSetClock(uint16_t addr, uint8_t val) {
  (void)val;
  m48clock(addr);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<m48chrSetClock>:
  endbr64
  jmp    1050 <m48clock@plt>
```

assistant: ```c
void m48chrSetClock(uint16_t addr, uint8_t val) {
  (void)val;
  m48clock(addr);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<subCopyAnimToScreen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <GetStretchX@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <GetStretchY@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%esi
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <DDSpriteBuffer_BltImg@plt>
  nop
  leave
  ret
```

assistant: ```c
void subCopyAnimToScreen(int si, int graphic, int sync_frame) {
  int X, Y;
  X = GetStretchX(si);
  Y = GetStretchY(si);
  DDSpriteBuffer_BltImg(X, Y, graphic, sync_frame);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subCopyAnimToScreen>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %esi,%r12d
  mov    %edx,%r13d
  call   <GetStretchX@plt>
  mov    %eax,%ebp
  mov    %ebx,%edi
  call   <GetStretchY@plt>
  mov    %eax,%esi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    %ebp,%edi
  call   <DDSpriteBuffer_BltImg@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void subCopyAnimToScreen(int si, int graphic, int sync_frame) {
  int X, Y;
  X = GetStretchX(si);
  Y = GetStretchY(si);
  DDSpriteBuffer_BltImg(X, Y, graphic, sync_frame);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<subCopyAnimToScreen>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <GetStretchX@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <GetStretchY@plt>
  add    $0x8,%rsp
  mov    %r14d,%ecx
  mov    %r13d,%edx
  pop    %rbp
  mov    %r12d,%edi
  mov    %eax,%esi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <DDSpriteBuffer_BltImg@plt>
```

assistant: ```c
void subCopyAnimToScreen(int si, int graphic, int sync_frame) {
  int X, Y;
  X = GetStretchX(si);
  Y = GetStretchY(si);
  DDSpriteBuffer_BltImg(X, Y, graphic, sync_frame);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<subCopyAnimToScreen>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  mov    %edi,%ebp
  sub    $0x8,%rsp
  call   <GetStretchX@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <GetStretchY@plt>
  add    $0x8,%rsp
  mov    %r14d,%ecx
  mov    %r13d,%edx
  pop    %rbp
  mov    %r12d,%edi
  mov    %eax,%esi
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <DDSpriteBuffer_BltImg@plt>
```

assistant: ```c
void subCopyAnimToScreen(int si, int graphic, int sync_frame) {
  int X, Y;
  X = GetStretchX(si);
  Y = GetStretchY(si);
  DDSpriteBuffer_BltImg(X, Y, graphic, sync_frame);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %esi,%r13d
  mov    %edx,%ebx
  mov    %rcx,%r14
  mov    %r8d,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    0xa(%rdx),%edx
  movslq %edx,%rax
  add    $0xf,%rax
  mov    %rax,%rsi
  and    $0xfffffffffffffff0,%rsi
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rcx
  sub    %rax,%rcx
L35:
  cmp    %rcx,%rsp
  je     L95
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L35
L95:
  mov    %rsi,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L99
  orq    $0x0,-0x8(%rsp,%rax,1)
L99:
  mov    %rsp,%r15
  mov    $0x2a,%esi
  mov    %rsp,%rdi
  call   <memset@plt>
  lea    0x9(%rbx),%eax
  cltq
  movb   $0x0,(%rsp,%rax,1)
  mov    -0x44(%rbp),%edx
  mov    %ebx,%esi
  mov    %rsp,%rdi
  call   <rlstr@plt>
  mov    %rsp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jl     L34
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%ecx
  mov    %ebx,%r8d
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    D14(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L53:
  mov    -0x38(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
L34:
  mov    %r14,%rsi
  mov    %r15,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L45
  movslq %ebx,%rbx
  cmpb   $0x2a,(%r15,%rbx,1)
  je     L52
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L53
L45:
  mov    %r14,%r8
  mov    %r15,%rcx
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    D39(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L53
L52:
  mov    %r15,%rcx
  mov    %r13d,%edx
  mov    %r12,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L53
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D27
type_infered: string
name: unpack_data
arguments: data_label: D39
type_infered: string
name: unpack_data
arguments: data_label: D0
type_infered: string

tool: D14: %s:%i: FAILED overflow 1 (%i over %i)


tool: D27: %s:%i: FAILED overflow 2


tool: D39: %s:%i: FAILED "%s" != "%s"


tool: D0: %s:%i: OK "%s"


assistant: ```c
void check(const char *file, int line, int len, const char *exp, int mask) {
  int buflen = len + 10;
  char buf[buflen];
  memset(buf, '*', buflen);
  buf[buflen - 1] = '\0';
  rlstr(buf, len, mask);
  if (strlen(buf) >= len)
    printf("%s:%i: FAILED overflow 1 (%i over %i)\n", file, line, (int)strlen(buf), len);
  else if (strcmp(buf, exp))
    printf("%s:%i: FAILED \"%s\" != \"%s\"\n", file, line, buf, exp);
  else if (buf[len] != '*')
    printf("%s:%i: FAILED overflow 2\n", file, line);
  else
    printf("%s:%i: OK \"%s\"\n", file, line, buf);
}
```