ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<isHansa>:
  endbr64
  xor    %eax,%eax
  comisd D4(%rip),%xmm1
  ja     L30
  movsd  D11(%rip),%xmm3
  comisd %xmm2,%xmm3
  ja     L30
  comisd D23(%rip),%xmm2
  ja     L30
  movsd  D38(%rip),%xmm2
  subsd  %xmm1,%xmm2
  movsd  D30(%rip),%xmm1
  divsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  jbe    L30
  comisd D40(%rip),%xmm0
  seta   %al
L30:
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
type_infered: byte[16]
name: read_data
arguments: data_label: D11
type_infered: byte[8]
name: read_data
arguments: data_label: D23
type_infered: f64[2]
name: read_data
arguments: data_label: D38
type_infered: f64
name: read_data
arguments: data_label: D30
type_infered: f64
name: read_data
arguments: data_label: D40
type_infered: f64

tool: {"D4": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D11": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D23": [23.5,1.0]}

tool: D38: 1

tool: D30: 2.72

tool: D40: 2.55

assistant: ```c
_Bool isHansa(double q, double e, double i) {
  if (e > .25 || i < 20 || i > 23.5)
    return 0;
  double a = q / (1 - e);
  return a < 2.72 && a > 2.55;
}
```
user: Translate the below assembly code into C programming language:

```asm
<isHansa>:
  endbr64
  xor    %eax,%eax
  comisd D21(%rip),%xmm1
  ja     L23
  movsd  D44(%rip),%xmm3
  comisd %xmm2,%xmm3
  ja     L23
  comisd D41(%rip),%xmm2
  ja     L23
  movsd  D25(%rip),%xmm2
  subsd  %xmm1,%xmm2
  movsd  D2(%rip),%xmm1
  divsd  %xmm2,%xmm0
  comisd %xmm0,%xmm1
  jbe    L23
  comisd D13(%rip),%xmm0
  seta   %al
L23:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_guessed: byte[16]
name: retrieve_data
arguments: tag: D44
type_guessed: byte[8]
name: retrieve_data
arguments: tag: D41
type_guessed: f64[2]
name: retrieve_data
arguments: tag: D25
type_guessed: f64
name: retrieve_data
arguments: tag: D2
type_guessed: f64
name: retrieve_data
arguments: tag: D13
type_guessed: f64

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0xd0,0x3f,0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D44": [0x00,0x00,0x00,0x00,0x00,0x00,0x34,0x40]}

tool: {"D41": [23.5,1.0]}

tool: D25: 1

tool: D2: 2.72

tool: D13: 2.55

assistant: ```c
_Bool isHansa(double q, double e, double i) {
  if (e > .25 || i < 20 || i > 23.5)
    return 0;
  double a = q / (1 - e);
  return a < 2.72 && a > 2.55;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cec_msg_get_cec_version>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0x2,(%rax)
  mov    -0x8(%rbp),%rax
  mov    0x8(%rax),%rax
  lea    0x4(%rax),%rdx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  cmpl   $0x0,-0xc(%rbp)
  je     L7
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  jmp    L5
L7:
  mov    $0x0,%eax
L5:
  mov    -0x8(%rbp),%rdx
  mov    %eax,0x4(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void cec_msg_get_cec_version(struct cec_msg *msg, int reply) {
  msg->len = 2;
  msg->msg[1] = CEC_MSG_GET_CEC_VERSION;
  msg->reply = reply ? CEC_MSG_CEC_VERSION : 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<cec_msg_get_cec_version>:
  endbr64
  movl   $0x2,(%rdi)
  mov    0x8(%rdi),%rax
  mov    D11(%rip),%rdx
  mov    (%rdx),%edx
  mov    %edx,0x4(%rax)
  test   %esi,%esi
  je     L0
  mov    D18(%rip),%rax
  mov    (%rax),%esi
L0:
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void cec_msg_get_cec_version(struct cec_msg *msg, int reply) {
  msg->len = 2;
  msg->msg[1] = CEC_MSG_GET_CEC_VERSION;
  msg->reply = reply ? CEC_MSG_CEC_VERSION : 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<cec_msg_get_cec_version>:
  endbr64
  mov    D12(%rip),%rdx
  mov    0x8(%rdi),%rax
  movl   $0x2,(%rdi)
  mov    (%rdx),%edx
  mov    %edx,0x4(%rax)
  test   %esi,%esi
  je     L6
  mov    D6(%rip),%rax
  mov    (%rax),%esi
L6:
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void cec_msg_get_cec_version(struct cec_msg *msg, int reply) {
  msg->len = 2;
  msg->msg[1] = CEC_MSG_GET_CEC_VERSION;
  msg->reply = reply ? CEC_MSG_CEC_VERSION : 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<cec_msg_get_cec_version>:
  endbr64
  mov    D0(%rip),%rdx
  mov    0x8(%rdi),%rax
  movl   $0x2,(%rdi)
  mov    (%rdx),%edx
  mov    %edx,0x4(%rax)
  test   %esi,%esi
  je     L5
  mov    D2(%rip),%rax
  mov    (%rax),%esi
L5:
  mov    %esi,0x4(%rdi)
  ret
```

assistant: ```c
void cec_msg_get_cec_version(struct cec_msg *msg, int reply) {
  msg->len = 2;
  msg->msg[1] = CEC_MSG_GET_CEC_VERSION;
  msg->reply = reply ? CEC_MSG_CEC_VERSION : 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L17
L7:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L7
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D11
data_type: string
name: extract_symbolic_data
arguments: tag: D12
data_type: string

tool: D11: 	%.2f


tool: D12: %lf

assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%lf", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D13(%rip),%rbx
  mov    %rsp,%r12
  lea    D6(%rip),%rbp
  lea    D1(%rip),%r13
  jmp    L20
L26:
  movq   %rbx,%xmm1
  addsd  (%rsp),%xmm1
  movq   %xmm1,%rbx
  movapd %xmm1,%xmm0
  mov    %r13,%rdi
  call   <printf@plt>
L20:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L26
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
data_type: byte[8]
name: extract_symbolic_data
arguments: data_label: D6
data_type: string
name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: {"D13": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D6: %lf

tool: D1: 	%.2f


assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%lf", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm2,%xmm2
  push   %r12
  movq   %xmm2,%r14
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D8(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L22:
  movq   %r14,%xmm1
  addsd  (%rsp),%xmm1
  mov    %r12,%rdi
  movapd %xmm1,%xmm0
  movq   %xmm1,%r14
  call   <printf@plt>
L10:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L22
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
type: string
name: unpack_data
arguments: data_label: D8
type: string

tool: D3: 	%.2f


tool: D8: %lf

assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%lf", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r14
  pxor   %xmm2,%xmm2
  push   %r12
  movq   %xmm2,%r14
  lea    D16(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D18(%rip),%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  jmp    L5
  nopw   0x0(%rax,%rax,1)
L20:
  movq   %r14,%xmm1
  addsd  (%rsp),%xmm1
  mov    %r12,%rdi
  movapd %xmm1,%xmm0
  movq   %xmm1,%r14
  call   <printf@plt>
L5:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L20
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r14
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
datatype: string
name: disassemble_data
arguments: data_tag: D18
datatype: string

tool: D16: 	%.2f


tool: D18: %lf

assistant: ```c
main() {
  double sum, v;
  sum = 0;
  while (scanf("%lf", &v) == 1)
    printf("\t%.2f\n", sum += v);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<test_leftmost_one>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x80000000,-0x4(%rbp)
  jmp    L38
L5:
  mov    -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  test   %eax,%eax
  je     L7
  mov    -0x4(%rbp),%eax
  jmp    L32
L7:
  shrl   -0x4(%rbp)
L38:
  cmpl   $0x0,-0x4(%rbp)
  jne    L5
  mov    $0x0,%eax
L32:
  pop    %rbp
  ret
```

assistant: ```c
unsigned test_leftmost_one(unsigned x) {
  unsigned mask;
  for (mask = 1u << 31; mask; mask >>= 1)
    if (x & mask)
      return mask;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<test_leftmost_one>:
  endbr64
  test   %edi,%edi
  js     L3
  mov    $0x40000000,%eax
L17:
  test   %eax,%edi
  jne    L6
  shr    %eax
  jne    L17
  ret
L3:
  mov    $0x80000000,%eax
L6:
  ret
```

assistant: ```c
unsigned test_leftmost_one(unsigned x) {
  unsigned mask;
  for (mask = 1u << 31; mask; mask >>= 1)
    if (x & mask)
      return mask;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<test_leftmost_one>:
  endbr64
  mov    $0x20,%edx
  mov    $0x80000000,%eax
  jmp    L28
L5:
  shr    %eax
  sub    $0x1,%edx
  je     L4
L28:
  test   %eax,%edi
  je     L5
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned test_leftmost_one(unsigned x) {
  unsigned mask;
  for (mask = 1u << 31; mask; mask >>= 1)
    if (x & mask)
      return mask;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_leftmost_one>:
  endbr64
  mov    $0x20,%edx
  mov    $0x80000000,%eax
  jmp    L29
L26:
  shr    %eax
  sub    $0x1,%edx
  je     L23
L29:
  test   %eax,%edi
  je     L26
  ret
  nopl   0x0(%rax)
L23:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned test_leftmost_one(unsigned x) {
  unsigned mask;
  for (mask = 1u << 31; mask; mask >>= 1)
    if (x & mask)
      return mask;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stpcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L36
  cmpq   $0x0,-0x10(%rbp)
  je     L36
  mov    $0x1,%eax
  jmp    L12
L36:
  mov    $0x0,%eax
L12:
  mov    %eax,%edi
  call   <assert@plt>
  nop
L32:
  mov    -0x10(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x8(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    -0x8(%rbp),%rax
  sub    $0x1,%rax
  leave
  ret
```

assistant: ```c
char *stpcpy(char *dst, const char *src) {
  assert(dst != NULL && src != NULL);
  while ((*dst++ = *src++) != 0)
    ;
  return (dst - 1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<stpcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x1,%edi
  call   <assert@plt>
L6:
  add    $0x1,%rbp
  mov    %rbx,%rdx
  add    $0x1,%rbx
  movzbl -0x1(%rbp),%eax
  mov    %al,-0x1(%rbx)
  test   %al,%al
  jne    L6
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *stpcpy(char *dst, const char *src) {
  assert(dst != NULL && src != NULL);
  while ((*dst++ = *src++) != 0)
    ;
  return (dst - 1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<stpcpy>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  nopw   0x0(%rax,%rax,1)
L5:
  movzbl 0x0(%rbp),%eax
  mov    %rbx,%r8
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  test   %al,%al
  jne    L5
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *stpcpy(char *dst, const char *src) {
  assert(dst != NULL && src != NULL);
  while ((*dst++ = *src++) != 0)
    ;
  return (dst - 1);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<stpcpy>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1,%edi
  sub    $0x8,%rsp
  call   <assert@plt>
  nopw   0x0(%rax,%rax,1)
L8:
  movzbl 0x0(%rbp),%eax
  mov    %rbx,%r8
  add    $0x1,%rbp
  add    $0x1,%rbx
  mov    %al,-0x1(%rbx)
  test   %al,%al
  jne    L8
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *stpcpy(char *dst, const char *src) {
  assert(dst != NULL && src != NULL);
  while ((*dst++ = *src++) != 0)
    ;
  return (dst - 1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_quaddobl_start_Laurent_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x2ff,%edi
  call   <_ada_use_c2phc@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int read_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(767, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_quaddobl_start_Laurent_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x2ff,%edi
  call   <_ada_use_c2phc@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int read_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(767, a, b, c, 0);
  return fail;
}
```
user: Translate the below assembly code into C programming language:

```asm
<read_quaddobl_start_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2ff,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int read_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(767, a, b, c, 0);
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<read_quaddobl_start_Laurent_system>:
  endbr64
  xor    %r8d,%r8d
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  mov    $0x2ff,%edi
  jmp    1050 <_ada_use_c2phc@plt>
```

assistant: ```c
int read_quaddobl_start_Laurent_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc(767, a, b, c, 0);
  return fail;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<threeSumClosestPartition>:
  endbr64
  mov    %rdi,%r9
  mov    %esi,%eax
  cmp    %edx,%esi
  jge    L35
  push   %rbx
  jmp    L99
L35:
  ret
L113:
  cmp    %eax,%edx
  jle    L115
L39:
  add    %esi,%r8d
  mov    %r8d,(%r10)
  sub    (%r11),%r8d
  mov    %r8d,(%r11)
  sub    %r8d,(%r10)
L99:
  movslq %eax,%rcx
  shl    $0x2,%rcx
  lea    (%r9,%rcx,1),%r10
  mov    (%r10),%esi
  movslq %edx,%rbx
  lea    (%r9,%rbx,4),%r11
  mov    (%r11),%edi
  cmp    %edx,%eax
  jge    L34
  lea    0x4(%r9,%rcx,1),%rcx
  cmp    %edi,%esi
  jg     L34
L47:
  add    $0x1,%eax
  mov    %rcx,%r10
  mov    (%rcx),%esi
  add    $0x4,%rcx
  cmp    %edi,%esi
  jg     L34
  cmp    %edx,%eax
  jl     L47
L34:
  cmp    %edx,%eax
  jge    L115
  add    %esi,%edi
  mov    %edi,(%r10)
  sub    (%r11),%edi
  mov    %edi,(%r11)
  mov    (%r10),%r8d
  sub    %edi,%r8d
  mov    %r8d,(%r10)
  mov    (%r11),%esi
  cmp    %esi,%r8d
  jge    L39
  lea    -0x4(%r9,%rbx,4),%rcx
L28:
  sub    $0x1,%edx
  mov    %rcx,%r11
  mov    (%rcx),%esi
  sub    $0x4,%rcx
  cmp    %eax,%edx
  jle    L113
  cmp    %esi,%r8d
  jl     L28
  jmp    L113
L115:
  pop    %rbx
  ret
```

assistant: ```c
int threeSumClosestPartition(int *nums, int start, int end) {
  while (start < end) {
    while (nums[start] <= nums[end] && start < end) {
      start++;
    }
    if (start < end) {
      nums[start] = nums[start] + nums[end];
      nums[end] = nums[start] - nums[end];
      nums[start] = nums[start] - nums[end];
    }
    while (nums[end] > nums[start] && start < end) {
      end--;
    }
    if (start < end) {
      nums[start] = nums[start] + nums[end];
      nums[end] = nums[start] - nums[end];
      nums[start] = nums[start] - nums[end];
    }
  }
  return start;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<threeSumClosestPartition>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r8d
  movslq %edx,%r11
  cmp    %edx,%esi
  jge    L105
  nopl   (%rax)
L48:
  movslq %r8d,%rcx
  lea    (%r10,%r11,4),%r9
  shl    $0x2,%rcx
  mov    (%r9),%eax
  lea    (%r10,%rcx,1),%rdi
  mov    (%rdi),%esi
  cmp    %eax,%esi
  jg     L6
  lea    0x4(%r10,%rcx,1),%rcx
  cmp    %edx,%r8d
  jl     L52
  jmp    L101
  nopl   0x0(%rax)
L31:
  add    $0x4,%rcx
  cmp    %edx,%r8d
  je     L101
L52:
  mov    (%rcx),%esi
  add    $0x1,%r8d
  mov    %rcx,%rdi
  cmp    %eax,%esi
  jle    L31
L6:
  cmp    %edx,%r8d
  jge    L26
  add    %esi,%eax
  mov    %eax,(%rdi)
  sub    (%r9),%eax
  mov    %eax,(%r9)
  mov    (%rdi),%esi
  sub    %eax,%esi
  mov    %esi,(%rdi)
  mov    (%r9),%eax
  cmp    %eax,%esi
  jge    L59
  lea    -0x4(%r10,%r11,4),%rcx
  jmp    L20
  nopl   0x0(%rax)
L104:
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jle    L105
L20:
  mov    (%rcx),%eax
  sub    $0x1,%edx
  mov    %rcx,%r9
  cmp    %eax,%esi
  jl     L104
L129:
  cmp    %r8d,%edx
  jle    L105
  movslq %edx,%r11
L59:
  add    %esi,%eax
  mov    %eax,(%rdi)
  sub    (%r9),%eax
  mov    %eax,(%r9)
  sub    %eax,(%rdi)
  jmp    L48
L26:
  mov    (%rdi),%esi
L101:
  cmp    %esi,%eax
  jle    L129
L105:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int threeSumClosestPartition(int *nums, int start, int end) {
  while (start < end) {
    while (nums[start] <= nums[end] && start < end) {
      start++;
    }
    if (start < end) {
      nums[start] = nums[start] + nums[end];
      nums[end] = nums[start] - nums[end];
      nums[start] = nums[start] - nums[end];
    }
    while (nums[end] > nums[start] && start < end) {
      end--;
    }
    if (start < end) {
      nums[start] = nums[start] + nums[end];
      nums[end] = nums[start] - nums[end];
      nums[start] = nums[start] - nums[end];
    }
  }
  return start;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<threeSumClosestPartition>:
  endbr64
  mov    %rdi,%r10
  mov    %esi,%r8d
  movslq %edx,%r11
  cmp    %edx,%esi
  jge    L0
  nopl   (%rax)
L134:
  movslq %r8d,%rcx
  lea    (%r10,%r11,4),%r9
  shl    $0x2,%rcx
  mov    (%r9),%eax
  lea    (%r10,%rcx,1),%rdi
  mov    (%rdi),%esi
  cmp    %eax,%esi
  jg     L122
  lea    0x4(%r10,%rcx,1),%rcx
  cmp    %edx,%r8d
  jl     L99
  jmp    L1
  nopl   0x0(%rax)
L82:
  add    $0x4,%rcx
  cmp    %edx,%r8d
  je     L1
L99:
  mov    (%rcx),%esi
  add    $0x1,%r8d
  mov    %rcx,%rdi
  cmp    %eax,%esi
  jle    L82
L122:
  cmp    %edx,%r8d
  jge    L0
  add    %esi,%eax
  mov    %eax,(%rdi)
  sub    (%r9),%eax
  mov    %eax,(%r9)
  mov    (%rdi),%esi
  sub    %eax,%esi
  mov    %esi,(%rdi)
  mov    (%r9),%eax
  cmp    %eax,%esi
  jge    L38
  lea    -0x4(%r10,%r11,4),%rcx
  jmp    L85
  nopl   0x0(%rax)
L73:
  sub    $0x4,%rcx
  cmp    %r8d,%edx
  jle    L0
L85:
  mov    (%rcx),%eax
  sub    $0x1,%edx
  mov    %rcx,%r9
  cmp    %eax,%esi
  jl     L73
L3:
  cmp    %r8d,%edx
  jle    L0
  movslq %edx,%r11
L38:
  add    %esi,%eax
  mov    %eax,(%rdi)
  sub    (%r9),%eax
  mov    %eax,(%r9)
  sub    %eax,(%rdi)
  jmp    L134
  xchg   %ax,%ax
L1:
  cmp    %eax,%esi
  jge    L3
L0:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int threeSumClosestPartition(int *nums, int start, int end) {
  while (start < end) {
    while (nums[start] <= nums[end] && start < end) {
      start++;
    }
    if (start < end) {
      nums[start] = nums[start] + nums[end];
      nums[end] = nums[start] - nums[end];
      nums[start] = nums[start] - nums[end];
    }
    while (nums[end] > nums[start] && start < end) {
      end--;
    }
    if (start < end) {
      nums[start] = nums[start] + nums[end];
      nums[end] = nums[start] - nums[end];
      nums[start] = nums[start] - nums[end];
    }
  }
  return start;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PrintErrorDestroyFile>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x160,%rsp
  mov    %rdi,-0x158(%rbp)
  mov    %rsi,-0x160(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L23
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L23:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x158(%rbp)
  je     L53
  mov    -0x158(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L53
  cmpq   $0x0,-0x160(%rbp)
  je     L53
  mov    -0x160(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L44
L53:
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L69
L44:
  mov    -0x160(%rbp),%rdx
  mov    -0x144(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0x144(%rbp),%ecx
  mov    -0x160(%rbp),%rdx
  lea    -0x140(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0x144(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  movb   $0x0,-0xc1(%rbp)
  lea    -0x140(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x158(%rbp),%rax
  mov    %rax,%rdi
  call   <unlink@plt>
  cmp    $0xffffffff,%eax
  jne    L69
  mov    -0x158(%rbp),%rdx
  lea    -0x140(%rbp),%rax
  mov    %rdx,%rcx
  lea    D18(%rip),%rdx
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  lea    -0x140(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L69:
  mov    -0xb8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string
name: disassemble_data
arguments: data_label: D18
type_infered: string

tool: D7: NULL arguments passed into [LogErrorDestroyFile]


tool: D18: [Error]: Could not remove file '%s'


assistant: ```c
void PrintErrorDestroyFile(const char *filename, const char *format, ...) {
  va_list argptr;
  char msg[128];
  if (!filename || !*filename || !format || !*format) {
    printf("NULL arguments passed into [LogErrorDestroyFile]\n");
    return;
  }
  va_start(argptr, format);
  vsnprintf(msg, sizeof(msg), format, argptr);
  va_end(argptr);
  msg[sizeof(msg) - 1] = '\0';
  printf(msg);
  if (unlink(filename) == -1) {
    snprintf(msg, sizeof(msg), "[Error]: Could not remove file '%s'\n", filename);
    printf(msg);
  }
}
```