ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pixel_mul_by_own_alpha>:
  endbr64
  lea    0x10(%rdi),%rax
  cmp    %rax,%rsi
  setae  %al
  cmp    %rdi,%rsi
  setbe  %dl
  or     %dl,%al
  je     L9
  lea    0x4(%rdi),%rax
  cmp    %rax,%rsi
  je     L9
  movss  0xc(%rdi),%xmm1
  movq   (%rdi),%xmm0
  shufps $0xe0,%xmm1,%xmm1
  mulps  %xmm1,%xmm0
  movlps %xmm0,(%rsi)
  movss  0x8(%rdi),%xmm0
  mulss  0xc(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  movss  0xc(%rdi),%xmm0
  movss  %xmm0,0xc(%rsi)
  ret
  xchg   %ax,%ax
L9:
  movss  (%rdi),%xmm0
  mulss  0xc(%rdi),%xmm0
  movss  %xmm0,(%rsi)
  movss  0x4(%rdi),%xmm0
  mulss  0xc(%rdi),%xmm0
  movss  %xmm0,0x4(%rsi)
  movss  0x8(%rdi),%xmm0
  mulss  0xc(%rdi),%xmm0
  movss  %xmm0,0x8(%rsi)
  movss  0xc(%rdi),%xmm0
  movss  %xmm0,0xc(%rsi)
  ret
```

assistant: ```c
void pixel_mul_by_own_alpha(float *p0, float *p1) {
  int ic;
  for (ic = 0; ic < 3; ic++)
    p1[ic] = p0[ic] * p0[3];
  p1[3] = p0[3];
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movss  D5(%rip),%xmm0
  movss  %xmm0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L15
L11:
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <InvSqrt@plt>
  movq   %xmm0,%rbx
  mov    -0x18(%rbp),%eax
  movd   %eax,%xmm0
  call   <sqrt@plt>
  movss  D5(%rip),%xmm1
  divss  %xmm0,%xmm1
  movd   %xmm1,%eax
  movq   %rbx,%xmm1
  movd   %eax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movss  -0x18(%rbp),%xmm1
  movss  D9(%rip),%xmm0
  mulss  %xmm1,%xmm0
  movss  %xmm0,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x13,-0x14(%rbp)
  jle    L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: byte[4]
name: read_data
arguments: tag: D7
datatype: string
name: read_data
arguments: tag: D9
datatype: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

tool: D7: %.10f	%.10f


tool: {"D9": [0x00,0x00,0x20,0x41]}

assistant: ```c
int main(void) {
  float x = 1.0f;
  int i;
  for (i = 0; i < 20; ++i) {
    printf("%.10f\t%.10f\n", 1.0f / sqrt(x), InvSqrt(x));
    x *= 10.0f;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x14,%r12d
  mov    D11(%rip),%ebx
  lea    D5(%rip),%r13
L4:
  movd   %ebx,%xmm0
  call   <InvSqrt@plt>
  movq   %xmm0,%rbp
  movd   %ebx,%xmm0
  call   <sqrt@plt>
  movaps %xmm0,%xmm1
  movss  D11(%rip),%xmm0
  divss  %xmm1,%xmm0
  movq   %rbp,%xmm1
  mov    %r13,%rdi
  call   <printf@plt>
  movd   %ebx,%xmm2
  mulss  D27(%rip),%xmm2
  movd   %xmm2,%ebx
  sub    $0x1,%r12d
  jne    L4
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: tag: D11
type_guessed: byte[4]
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D27
type_guessed: byte[4]

tool: {"D11": [0x00,0x00,0x80,0x3f]}

tool: D5: %.10f	%.10f


tool: {"D27": [0x00,0x00,0x20,0x41]}

assistant: ```c
int main(void) {
  float x = 1.0f;
  int i;
  for (i = 0; i < 20; ++i) {
    printf("%.10f\t%.10f\n", 1.0f / sqrt(x), InvSqrt(x));
    x *= 10.0f;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x18,%rsp
  movss  D6(%rip),%xmm2
  xchg   %ax,%ax
L4:
  movaps %xmm2,%xmm0
  movss  %xmm2,0x4(%rsp)
  call   <InvSqrt@plt>
  movss  0x4(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %rbp,%rdi
  movaps %xmm0,%xmm3
  movss  D6(%rip),%xmm0
  divss  %xmm3,%xmm0
  call   <printf@plt>
  movss  0x4(%rsp),%xmm2
  mulss  D21(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L4
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D6
type: byte[4]
name: unpack_data
arguments: tag: D21
type: byte[4]

tool: D2: %.10f	%.10f


tool: {"D6": [0x00,0x00,0x80,0x3f]}

tool: {"D21": [0x00,0x00,0x20,0x41]}

assistant: ```c
int main(void) {
  float x = 1.0f;
  int i;
  for (i = 0; i < 20; ++i) {
    printf("%.10f\t%.10f\n", 1.0f / sqrt(x), InvSqrt(x));
    x *= 10.0f;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D36(%rip),%rbp
  push   %rbx
  mov    $0x14,%ebx
  sub    $0x18,%rsp
  movss  D15(%rip),%xmm2
  xchg   %ax,%ax
L8:
  movaps %xmm2,%xmm0
  movss  %xmm2,0x4(%rsp)
  call   <InvSqrt@plt>
  movss  0x4(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movaps %xmm2,%xmm0
  call   <sqrt@plt>
  movsd  0x8(%rsp),%xmm1
  mov    %rbp,%rdi
  movaps %xmm0,%xmm3
  movss  D15(%rip),%xmm0
  divss  %xmm3,%xmm0
  call   <printf@plt>
  movss  0x4(%rsp),%xmm2
  mulss  D9(%rip),%xmm2
  sub    $0x1,%ebx
  jne    L8
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D36
type: string
name: read_data
arguments: data_label: D15
type: byte[4]
name: read_data
arguments: data_label: D9
type: byte[4]

tool: D36: %.10f	%.10f


tool: {"D15": [0x00,0x00,0x80,0x3f]}

tool: {"D9": [0x00,0x00,0x20,0x41]}

assistant: ```c
int main(void) {
  float x = 1.0f;
  int i;
  for (i = 0; i < 20; ++i) {
    printf("%.10f\t%.10f\n", 1.0f / sqrt(x), InvSqrt(x));
    x *= 10.0f;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sct_mouseinputy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L6
  movl   $0x0,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int8_t sct_mouseinputy(int8_t y) {
  int ry = y - 1;
  if (ry < 0)
    ry = 0;
  return ry;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sct_mouseinputy>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %eax,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int8_t sct_mouseinputy(int8_t y) {
  int ry = y - 1;
  if (ry < 0)
    ry = 0;
  return ry;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sct_mouseinputy>:
  endbr64
  lea    -0x1(%rdi),%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int8_t sct_mouseinputy(int8_t y) {
  int ry = y - 1;
  if (ry < 0)
    ry = 0;
  return ry;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sct_mouseinputy>:
  endbr64
  lea    -0x1(%rdi),%eax
  xor    %edx,%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  ret
```

assistant: ```c
int8_t sct_mouseinputy(int8_t y) {
  int ry = y - 1;
  if (ry < 0)
    ry = 0;
  return ry;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  xor    $0x29be1cdb,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  and    $0x10,%eax
  test   %rax,%rax
  je     L9
  mov    -0x10(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  shr    $0x3,%rax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L2
L9:
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  lea    -0x10(%rbp),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    -0x18(%rbp),%edx
  mov    %edx,(%rax)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  mov    %eax,-0x14(%rbp)
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rdx),%edx
  mov    %edx,(%rax)
  lea    -0x10(%rbp),%rax
  mov    -0x14(%rbp),%edx
  mov    %edx,(%rax)
L2:
  mov    -0x10(%rbp),%rax
  and    $0x240be0dd,%eax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned int copy12;
  unsigned int copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
    } else {
      copy12 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy12;
      copy13 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy13;
    }
    output[0UL] = state[0UL] & 604758237UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rax
  mov    %rax,%rdx
  xor    $0x29be1cdb,%rdx
  test   $0x10,%al
  jne    L12
  mov    %rdx,%rcx
  shr    $0x3,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  mov    %rdx,%rax
  shl    %cl,%rax
L0:
  and    $0x240be0dd,%eax
  mov    %rax,(%rsi)
  ret
L12:
  mov    %rdx,%rax
  shr    $0x20,%rax
  mov    %edx,%edx
  shl    $0x20,%rax
  or     %rdx,%rax
  jmp    L0
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned int copy12;
  unsigned int copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
    } else {
      copy12 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy12;
      copy13 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy13;
    }
    output[0UL] = state[0UL] & 604758237UL;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  xor    $0x29be1cdb,%rdx
  mov    %rdx,%rax
  and    $0x10,%edx
  je     L2
  mov    %rax,%rcx
  shr    $0x3,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L2:
  and    $0x240be0dd,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned int copy12;
  unsigned int copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
    } else {
      copy12 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy12;
      copy13 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy13;
    }
    output[0UL] = state[0UL] & 604758237UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rdx,%rax
  xor    $0x29be1cdb,%rax
  and    $0x10,%edx
  jne    L5
  mov    %rax,%rcx
  shr    $0x3,%rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
L5:
  and    $0x240be0dd,%eax
  mov    %rax,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned int copy12;
  unsigned int copy13;
  {
    state[0UL] = input[0UL] ^ 700325083UL;
    if ((state[0UL] >> 4UL) & 1UL) {
      state[0UL] <<= ((state[0UL] >> 3UL) & 7UL) | 1UL;
    } else {
      copy12 = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = copy12;
      copy13 = *((unsigned int *)(&state[0UL]) + 1);
      *((unsigned int *)(&state[0UL]) + 1) = *((unsigned int *)(&state[0UL]) + 0);
      *((unsigned int *)(&state[0UL]) + 0) = copy13;
    }
    output[0UL] = state[0UL] & 604758237UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xd4(%rbp)
  jmp    L32
L36:
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd4(%rbp),%edx
  mov    %edx,-0x90(%rbp,%rax,4)
  mov    -0xd4(%rbp),%eax
  lea    0x2(%rax),%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
  addl   $0x1,-0xd4(%rbp)
L32:
  cmpl   $0xe,-0xd4(%rbp)
  jle    L36
  movl   $0x0,-0xd4(%rbp)
  jmp    L0
L22:
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%edx
  mov    $0xe,%eax
  sub    -0xd4(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    %edx,-0xd0(%rbp,%rax,4)
  mov    $0xe,%eax
  sub    -0xd4(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%ecx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0x90(%rbp,%rax,4),%edx
  mov    -0xd4(%rbp),%eax
  cltq
  mov    -0xd0(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xd4(%rbp)
L0:
  cmpl   $0xe,-0xd4(%rbp)
  jle    L22
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D8
type_guessed: string

tool: D8: %d = %d + %d


assistant: ```c
void main() {
  int c[15], a[15], b[15], i;
  for (i = 0; i < 15; i++) {
    a[i] = i;
    b[i] = i + 2;
  }
  for (i = 0; i < 15; i++) {
    c[i] = a[i] + b[14 - i];
    printf("%d = %d + %d\n", c[i], a[i], b[14 - i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
L20:
  mov    %eax,(%rsp,%rax,4)
  lea    0x2(%rax),%edx
  mov    %edx,0x40(%rsp,%rax,4)
  add    $0x1,%rax
  cmp    $0xf,%rax
  jne    L20
  mov    %rsp,%rbp
  lea    0x40(%rsp),%r13
  lea    0x78(%rsp),%rbx
  lea    D5(%rip),%r12
L5:
  mov    0x0(%rbp),%edx
  mov    (%rbx),%ecx
  lea    (%rdx,%rcx,1),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbp
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %r13,%rax
  jne    L5
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D5
type: string

tool: D5: %d = %d + %d


assistant: ```c
void main() {
  int c[15], a[15], b[15], i;
  for (i = 0; i < 15; i++) {
    a[i] = i;
    b[i] = i + 2;
  }
  for (i = 0; i < 15; i++) {
    c[i] = a[i] + b[14 - i];
    printf("%d = %d + %d\n", c[i], a[i], b[14 - i]);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%r12
  nopl   0x0(%rax)
L18:
  lea    0x2(%rax),%edx
  mov    %eax,(%rbx,%rax,4)
  mov    %edx,(%r12,%rax,4)
  add    $0x1,%rax
  cmp    $0xf,%rax
  jne    L18
  lea    0x78(%rsp),%rbp
  lea    D2(%rip),%r13
L4:
  mov    (%rbx),%edx
  mov    0x0(%rbp),%ecx
  mov    %r13,%rdi
  add    $0x4,%rbx
  lea    (%rdx,%rcx,1),%esi
  call   <printf@plt>
  mov    %rbp,%rax
  sub    $0x4,%rbp
  cmp    %r12,%rax
  jne    L4
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D2
type_guessed: string

tool: D2: %d = %d + %d


assistant: ```c
void main() {
  int c[15], a[15], b[15], i;
  for (i = 0; i < 15; i++) {
    a[i] = i;
    b[i] = i + 2;
  }
  for (i = 0; i < 15; i++) {
    c[i] = a[i] + b[14 - i];
    printf("%d = %d + %d\n", c[i], a[i], b[14 - i]);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  lea    D50(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x98,%rsp
  movdqa D86(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x40(%rsp),%r13
  lea    0x78(%rsp),%rbx
  movaps %xmm0,(%rsp)
  movdqa D56(%rip),%xmm0
  mov    D57(%rip),%rax
  movl   $0xe,0x38(%rsp)
  movaps %xmm0,0x40(%rsp)
  movdqa D37(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  mov    D31(%rip),%rax
  movaps %xmm0,0x10(%rsp)
  movdqa D82(%rip),%xmm0
  mov    %rax,0x70(%rsp)
  movaps %xmm0,0x50(%rsp)
  movdqa D16(%rip),%xmm0
  movl   $0x10,0x78(%rsp)
  movaps %xmm0,0x20(%rsp)
  movdqa D58(%rip),%xmm0
  movaps %xmm0,0x60(%rsp)
  nopl   (%rax)
L13:
  mov    0x0(%rbp),%edx
  mov    (%rbx),%ecx
  mov    %r12,%rdi
  add    $0x4,%rbp
  lea    (%rdx,%rcx,1),%esi
  call   <printf@plt>
  mov    %rbx,%rax
  sub    $0x4,%rbx
  cmp    %r13,%rax
  jne    L13
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x98,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D50
type_infered: string
name: extract_symbolic_data
arguments: data_label: D86
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D56
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D57
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D37
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D31
type_infered: byte[8]
name: extract_symbolic_data
arguments: data_label: D82
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D16
type_infered: byte[16]
name: extract_symbolic_data
arguments: data_label: D58
type_infered: byte[16]

tool: D50: %d = %d + %d


tool: {"D86": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D56": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D57": [0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

tool: {"D37": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00]}

tool: {"D31": [0x0e,0x00,0x00,0x00,0x0f,0x00,0x00,0x00]}

tool: {"D82": [0x06,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00]}

tool: {"D16": [0x08,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00]}

tool: {"D58": [0x0a,0x00,0x00,0x00,0x0b,0x00,0x00,0x00,0x0c,0x00,0x00,0x00,0x0d,0x00,0x00,0x00]}

assistant: ```c
void main() {
  int c[15], a[15], b[15], i;
  for (i = 0; i < 15; i++) {
    a[i] = i;
    b[i] = i + 2;
  }
  for (i = 0; i < 15; i++) {
    c[i] = a[i] + b[14 - i];
    printf("%d = %d + %d\n", c[i], a[i], b[14 - i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x24(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jne    L22
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L13
L22:
  movl   $0x0,-0x4(%rbp)
  jmp    L10
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x24(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edi
  mov    -0x2c(%rbp),%ecx
  mov    -0x28(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %ecx,%r8d
  mov    %edx,%ecx
  mov    %edi,%edx
  mov    %rax,%rdi
  call   <print_string>
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L19
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D0
datatype: string

tool: D0: %s


assistant: ```c
void print_string(char str[], char new_str[], int curr_len, int n, int len) {
  if (curr_len == len) {
    printf("%s\n", new_str);
    return;
  } else {
    int i;
    for (i = 0; i < n; i++) {
      new_str[curr_len] = str[i];
      print_string(str, new_str, curr_len + 1, n, len);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<print_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbp
  mov    %r8d,0x4(%rsp)
  cmp    %r8d,%edx
  je     L18
  mov    %rdi,%r14
  mov    %edx,%r12d
  mov    %ecx,%r13d
  test   %ecx,%ecx
  jle    L38
  mov    %rdi,%rbx
  lea    -0x1(%rcx),%eax
  lea    0x1(%rdi,%rax,1),%rax
  mov    %rax,0x8(%rsp)
  movslq %edx,%r15
L1:
  movzbl (%rbx),%eax
  mov    %al,0x0(%rbp,%r15,1)
  lea    0x1(%r12),%edx
  mov    0x4(%rsp),%r8d
  mov    %r13d,%ecx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <print_string>
  add    $0x1,%rbx
  cmp    0x8(%rsp),%rbx
  jne    L1
L38:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L38
```

tool_calls: name: retrieve_data
arguments: data_label: D7
datatype: string

tool: D7: %s


assistant: ```c
void print_string(char str[], char new_str[], int curr_len, int n, int len) {
  if (curr_len == len) {
    printf("%s\n", new_str);
    return;
  } else {
    int i;
    for (i = 0; i < n; i++) {
      new_str[curr_len] = str[i];
      print_string(str, new_str, curr_len + 1, n, len);
    }
  }
}
```