ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<t>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x2,%edx
  xor    %edi,%edi
  push   $0xf
  mov    $0x5,%r9d
  mov    $0x4,%r8d
  mov    $0x1,%esi
  push   $0xe
  push   $0xd
  push   $0xc
  push   $0xb
  push   $0xa
  push   $0x9
  push   $0x8
  push   $0x7
  push   $0x6
  call   <di16@plt>
  add    $0x50,%rsp
  mov    $0x3,%ecx
  xor    %edi,%edi
  push   $0xf
  mov    $0x5,%r9d
  mov    $0x4,%r8d
  mov    $0x2,%edx
  push   $0xe
  mov    $0x1,%esi
  push   $0xd
  push   $0xc
  push   $0xb
  push   $0xa
  push   $0x9
  push   $0x8
  push   $0x7
  push   $0x6
  call   <fi16@plt>
  add    $0x58,%rsp
  ret
```

assistant: ```c
void t() {
  di16(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15);
  fi16(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<t>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x3,%ecx
  mov    $0x2,%edx
  xor    %edi,%edi
  push   $0xf
  mov    $0x5,%r9d
  mov    $0x4,%r8d
  mov    $0x1,%esi
  push   $0xe
  push   $0xd
  push   $0xc
  push   $0xb
  push   $0xa
  push   $0x9
  push   $0x8
  push   $0x7
  push   $0x6
  call   <di16@plt>
  add    $0x50,%rsp
  mov    $0x3,%ecx
  xor    %edi,%edi
  push   $0xf
  mov    $0x5,%r9d
  mov    $0x4,%r8d
  mov    $0x2,%edx
  push   $0xe
  mov    $0x1,%esi
  push   $0xd
  push   $0xc
  push   $0xb
  push   $0xa
  push   $0x9
  push   $0x8
  push   $0x7
  push   $0x6
  call   <fi16@plt>
  add    $0x58,%rsp
  ret
```

assistant: ```c
void t() {
  di16(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15);
  fi16(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15);
}
```
user: What is the c source code of the assembly code below:

```asm
<arm_ws>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x240,%rsp
  mov    %esi,%eax
  mov    %rdx,-0x230(%rbp)
  mov    %rcx,-0x238(%rbp)
  mov    %edi,%edx
  mov    %dx,-0x224(%rbp)
  mov    %ax,-0x228(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rdi
  call   <init_send_buffer@plt>
  movswl -0x224(%rbp),%eax
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stuff2byteuint@plt>
  movswl -0x228(%rbp),%eax
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <stuff2byteuint@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x210(%rbp),%rcx
  mov    -0x230(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <stuff4byteuint@plt>
  movzwl -0x21c(%rbp),%eax
  movzwl %ax,%eax
  lea    -0x210(%rbp),%rdx
  mov    %rdx,%rcx
  mov    $0x29,%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <stuff_send_buffer_header@plt>
  lea    -0x110(%rbp),%rdx
  lea    -0x210(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <special_request@plt>
  lea    -0x21c(%rbp),%rax
  mov    %rax,%rdi
  call   <init_receive_buffer@plt>
  lea    -0x110(%rbp),%rcx
  lea    -0x21d(%rbp),%rdx
  lea    -0x21e(%rbp),%rsi
  lea    -0x21a(%rbp),%rax
  mov    %rax,%rdi
  call   <extract_receive_buffer_header@plt>
  lea    -0x21c(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,-0x218(%rbp)
  cmpq   $0x0,-0x238(%rbp)
  je     L10
  lea    -0x21c(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <extract4byteuint@plt>
  mov    -0x238(%rbp),%rdx
  mov    %rax,(%rdx)
L10:
  mov    -0x218(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

assistant: ```c
long arm_ws(short l, short g, long timeout, long *time_remain) {
  long result;
  unsigned short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff2byteuint(l, user_send_buffer, &b_index);
  stuff2byteuint(g, user_send_buffer, &b_index);
  stuff4byteuint(timeout, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 41, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  if (time_remain)
    *time_remain = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<arm_ws>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x228,%rsp
  mov    %edi,%r13d
  mov    %esi,%r12d
  mov    %rdx,%r15
  mov    %rcx,%r14
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rdi
  call   <init_send_buffer@plt>
  lea    0x10(%rsp),%rbp
  movswl %r13w,%edi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <stuff2byteuint@plt>
  movswl %r12w,%edi
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  call   <stuff2byteuint@plt>
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <stuff4byteuint@plt>
  movzwl 0xc(%rsp),%edi
  mov    %rbp,%rcx
  mov    $0x29,%edx
  mov    $0x0,%esi
  call   <stuff_send_buffer_header@plt>
  lea    0x110(%rsp),%r12
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <special_request@plt>
  mov    %rbx,%rdi
  call   <init_receive_buffer@plt>
  lea    0xb(%rsp),%rdx
  lea    0xa(%rsp),%rsi
  lea    0xe(%rsp),%rdi
  mov    %r12,%rcx
  call   <extract_receive_buffer_header@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,%rbx
  test   %r14,%r14
  je     L0
  lea    0xc(%rsp),%rsi
  mov    %r12,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,(%r14)
L0:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  mov    %rbx,%rax
  add    $0x228,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long arm_ws(short l, short g, long timeout, long *time_remain) {
  long result;
  unsigned short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff2byteuint(l, user_send_buffer, &b_index);
  stuff2byteuint(g, user_send_buffer, &b_index);
  stuff4byteuint(timeout, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 41, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  if (time_remain)
    *time_remain = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<arm_ws>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdi
  call   <init_send_buffer@plt>
  movswl %r13w,%edi
  mov    %r12,%rsi
  mov    %rbp,%rdx
  call   <stuff2byteuint@plt>
  mov    %r12,%rsi
  movswl %bx,%edi
  mov    %rbp,%rdx
  call   <stuff2byteuint@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    %r15,%rdi
  call   <stuff4byteuint@plt>
  movzwl 0xc(%rsp),%edi
  mov    %r12,%rcx
  xor    %esi,%esi
  mov    $0x29,%edx
  lea    0x110(%rsp),%r13
  call   <stuff_send_buffer_header@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <special_request@plt>
  mov    %rbp,%rdi
  call   <init_receive_buffer@plt>
  lea    0xb(%rsp),%rdx
  lea    0xa(%rsp),%rsi
  mov    %r13,%rcx
  lea    0xe(%rsp),%rdi
  call   <extract_receive_buffer_header@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,%r12
  test   %r14,%r14
  je     L10
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,(%r14)
L10:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x228,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long arm_ws(short l, short g, long timeout, long *time_remain) {
  long result;
  unsigned short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff2byteuint(l, user_send_buffer, &b_index);
  stuff2byteuint(g, user_send_buffer, &b_index);
  stuff4byteuint(timeout, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 41, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  if (time_remain)
    *time_remain = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<arm_ws>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x228,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x218(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  lea    0x10(%rsp),%r12
  mov    %rbp,%rdi
  call   <init_send_buffer@plt>
  movswl %r13w,%edi
  mov    %r12,%rsi
  mov    %rbp,%rdx
  call   <stuff2byteuint@plt>
  mov    %r12,%rsi
  movswl %bx,%edi
  mov    %rbp,%rdx
  call   <stuff2byteuint@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdx
  mov    %r15,%rdi
  call   <stuff4byteuint@plt>
  movzwl 0xc(%rsp),%edi
  mov    %r12,%rcx
  xor    %esi,%esi
  mov    $0x29,%edx
  lea    0x110(%rsp),%r13
  call   <stuff_send_buffer_header@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <special_request@plt>
  mov    %rbp,%rdi
  call   <init_receive_buffer@plt>
  lea    0xb(%rsp),%rdx
  lea    0xa(%rsp),%rsi
  mov    %r13,%rcx
  lea    0xe(%rsp),%rdi
  call   <extract_receive_buffer_header@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,%r12
  test   %r14,%r14
  je     L5
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <extract4byteuint@plt>
  mov    %rax,(%r14)
L5:
  mov    0x218(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x228,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long arm_ws(short l, short g, long timeout, long *time_remain) {
  long result;
  unsigned short b_index, b_length;
  unsigned char serial_number;
  unsigned char packet_type;
  unsigned char user_send_buffer[256];
  unsigned char user_receive_buffer[256];
  init_send_buffer(&b_index);
  stuff2byteuint(l, user_send_buffer, &b_index);
  stuff2byteuint(g, user_send_buffer, &b_index);
  stuff4byteuint(timeout, user_send_buffer, &b_index);
  stuff_send_buffer_header(b_index, 0, 41, user_send_buffer);
  special_request(user_send_buffer, user_receive_buffer);
  init_receive_buffer(&b_index);
  extract_receive_buffer_header(&b_length, &serial_number, &packet_type, user_receive_buffer);
  result = extract4byteuint(user_receive_buffer, &b_index);
  if (time_remain)
    *time_remain = extract4byteuint(user_receive_buffer, &b_index);
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<debug_fmt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L7
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L7:
  movq   $0x1ff,-0xb8(%rbp)
  mov    -0xc8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xbc(%rbp),%ecx
  mov    -0xc8(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  lea    D4(%rip),%rdx
  mov    -0xb8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  lea    D4(%rip),%rax
  leave
  ret
```

assistant: ```c
char *debug_fmt(const char *format, ...) {
  va_list argp;
  static char str[512];
  size_t maxlen = sizeof(str) - 1;
  va_start(argp, format);
  vsnprintf(str, maxlen, format, argp);
  va_end(argp);
  str[maxlen] = '\0';
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<debug_fmt>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    $0x1ff,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  movb   $0x0,D18(%rip)
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *debug_fmt(const char *format, ...) {
  va_list argp;
  static char str[512];
  size_t maxlen = sizeof(str) - 1;
  va_start(argp, format);
  vsnprintf(str, maxlen, format, argp);
  va_end(argp);
  str[maxlen] = '\0';
  return (str);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<debug_fmt>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    $0x1ff,%esi
  lea    D19(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  movb   $0x0,D14(%rip)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *debug_fmt(const char *format, ...) {
  va_list argp;
  static char str[512];
  size_t maxlen = sizeof(str) - 1;
  va_start(argp, format);
  vsnprintf(str, maxlen, format, argp);
  va_end(argp);
  str[maxlen] = '\0';
  return (str);
}
```
user: What is the c source code of the assembly code below?

```asm
<debug_fmt>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12,%rdx
  mov    %ebp,%ecx
  mov    $0x1ff,%esi
  lea    D11(%rip),%r12
  mov    %r12,%rdi
  call   <vsnprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  movb   $0x0,D19(%rip)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *debug_fmt(const char *format, ...) {
  va_list argp;
  static char str[512];
  size_t maxlen = sizeof(str) - 1;
  va_start(argp, format);
  vsnprintf(str, maxlen, format, argp);
  va_end(argp);
  str[maxlen] = '\0';
  return (str);
}
```
user: Translate the below assembly code into C programming language:

```asm
<rebin>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x24(%rbp)
  mov    %edi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  movl   $0x0,-0x10(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  pxor   %xmm0,%xmm0
  movss  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L0
L14:
  addl   $0x1,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  -0xc(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
L28:
  movss  -0x24(%rbp),%xmm0
  comiss -0xc(%rbp),%xmm0
  ja     L14
  cmpl   $0x1,-0x10(%rbp)
  jle    L11
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x8(%rbp)
L11:
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  subss  -0x24(%rbp),%xmm0
  movss  %xmm0,-0xc(%rbp)
  movss  -0x4(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  mulss  -0xc(%rbp),%xmm0
  mov    -0x10(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm2
  movaps %xmm0,%xmm1
  divss  %xmm2,%xmm1
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L0:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L28
  movl   $0x1,-0x14(%rbp)
  jmp    L58
L54:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x40(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x14(%rbp)
L58:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L54
  mov    -0x28(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  movss  D4(%rip),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type_infered: f32

tool: D4: 1

assistant: ```c
void rebin(float rc, int nd, float r[], float xin[], float xi[]) {
  int i, k = 0;
  float dr = 0.0, xn = 0.0, xo = 0.0;
  for (i = 1; i < nd; i++) {
    while (rc > dr)
      dr += r[++k];
    if (k > 1)
      xo = xi[k - 1];
    xn = xi[k];
    dr -= rc;
    xin[i] = xn - (xn - xo) * dr / r[k];
  }
  for (i = 1; i < nd; i++)
    xi[i] = xin[i];
  xi[nd] = 1.0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<rebin>:
  endbr64
  mov    %edi,%r8d
  mov    %rdx,%r9
  mov    %rcx,%rdi
  cmp    $0x1,%r8d
  jle    L3
  lea    0x4(%rdx),%rcx
  lea    -0x2(%r8),%eax
  lea    0x8(%rdx,%rax,4),%r10
  pxor   %xmm4,%xmm4
  movaps %xmm4,%xmm1
  mov    $0x0,%edx
  jmp    L79
L31:
  movslq %edx,%rax
  movss  (%rdi,%rax,4),%xmm3
  subss  %xmm0,%xmm1
  movaps %xmm3,%xmm2
  subss  %xmm4,%xmm2
  mulss  %xmm1,%xmm2
  divss  (%rsi,%rax,4),%xmm2
  subss  %xmm2,%xmm3
  movss  %xmm3,(%rcx)
  add    $0x4,%rcx
  cmp    %r10,%rcx
  je     L40
L79:
  lea    0x1(%rdx),%eax
  cltq
  comiss %xmm1,%xmm0
  jbe    L11
L7:
  mov    %eax,%edx
  addss  (%rsi,%rax,4),%xmm1
  add    $0x1,%rax
  comiss %xmm1,%xmm0
  ja     L7
L11:
  cmp    $0x1,%edx
  jle    L31
  movslq %edx,%rax
  movss  -0x4(%rdi,%rax,4),%xmm4
  jmp    L31
L40:
  mov    %r8d,%edx
  mov    $0x1,%eax
L9:
  movss  (%r9,%rax,4),%xmm0
  movss  %xmm0,(%rdi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L9
L3:
  movslq %r8d,%r8
  movl   $0x3f800000,(%rdi,%r8,4)
  ret
```

assistant: ```c
void rebin(float rc, int nd, float r[], float xin[], float xi[]) {
  int i, k = 0;
  float dr = 0.0, xn = 0.0, xo = 0.0;
  for (i = 1; i < nd; i++) {
    while (rc > dr)
      dr += r[++k];
    if (k > 1)
      xo = xi[k - 1];
    xn = xi[k];
    dr -= rc;
    xin[i] = xn - (xn - xo) * dr / r[k];
  }
  for (i = 1; i < nd; i++)
    xi[i] = xin[i];
  xi[nd] = 1.0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<rebin>:
  endbr64
  movslq %edi,%r8
  mov    %rdx,%r10
  mov    %rcx,%r9
  cmp    $0x1,%r8d
  jle    L17
  lea    -0x2(%r8),%eax
  pxor   %xmm5,%xmm5
  lea    0x4(%rdx),%rdi
  lea    0x8(%rdx,%rax,4),%r11
  movaps %xmm5,%xmm1
  xor    %edx,%edx
  nopl   (%rax)
L65:
  comiss %xmm1,%xmm0
  lea    0x1(%rdx),%eax
  cltq
  jbe    L50
  xchg   %ax,%ax
L13:
  movss  (%rsi,%rax,4),%xmm2
  mov    %eax,%edx
  lea    0x0(,%rax,4),%rcx
  add    $0x1,%rax
  addss  %xmm2,%xmm1
  comiss %xmm1,%xmm0
  ja     L13
L16:
  cmp    $0x1,%edx
  jle    L25
  movss  -0x4(%r9,%rcx,1),%xmm5
L25:
  movss  (%r9,%rcx,1),%xmm4
  subss  %xmm0,%xmm1
  add    $0x4,%rdi
  movaps %xmm4,%xmm3
  subss  %xmm5,%xmm3
  mulss  %xmm1,%xmm3
  divss  %xmm2,%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,-0x4(%rdi)
  cmp    %rdi,%r11
  jne    L65
  mov    %r8d,%edx
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L56:
  movss  (%r10,%rax,4),%xmm0
  movss  %xmm0,(%r9,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L56
L17:
  movl   $0x3f800000,(%r9,%r8,4)
  ret
  xchg   %ax,%ax
L50:
  movslq %edx,%rax
  movss  (%rsi,%rax,4),%xmm2
  lea    0x0(,%rax,4),%rcx
  jmp    L16
```

assistant: ```c
void rebin(float rc, int nd, float r[], float xin[], float xi[]) {
  int i, k = 0;
  float dr = 0.0, xn = 0.0, xo = 0.0;
  for (i = 1; i < nd; i++) {
    while (rc > dr)
      dr += r[++k];
    if (k > 1)
      xo = xi[k - 1];
    xn = xi[k];
    dr -= rc;
    xin[i] = xn - (xn - xo) * dr / r[k];
  }
  for (i = 1; i < nd; i++)
    xi[i] = xin[i];
  xi[nd] = 1.0;
}
```
user: What is the c source code of the assembly code below:

```asm
<rebin>:
  endbr64
  movslq %edi,%r10
  mov    %rcx,%r8
  cmp    $0x1,%r10d
  jle    L129
  push   %rbp
  lea    -0x2(%r10),%eax
  pxor   %xmm5,%xmm5
  mov    %rdx,%r9
  push   %rbx
  lea    0x8(%rdx),%rbx
  lea    0x4(%rdx),%rdi
  mov    %rax,%rbp
  lea    (%rbx,%rax,4),%r11
  movaps %xmm5,%xmm1
  xor    %edx,%edx
  nopl   (%rax)
L46:
  comiss %xmm1,%xmm0
  lea    0x1(%rdx),%eax
  cltq
  jbe    L38
  cs nopw 0x0(%rax,%rax,1)
L102:
  movss  (%rsi,%rax,4),%xmm2
  mov    %eax,%edx
  lea    0x0(,%rax,4),%rcx
  add    $0x1,%rax
  addss  %xmm2,%xmm1
  comiss %xmm1,%xmm0
  ja     L102
L4:
  cmp    $0x1,%edx
  jle    L74
  movss  -0x4(%r8,%rcx,1),%xmm5
L74:
  movss  (%r8,%rcx,1),%xmm4
  subss  %xmm0,%xmm1
  add    $0x4,%rdi
  movaps %xmm4,%xmm3
  subss  %xmm5,%xmm3
  mulss  %xmm1,%xmm3
  divss  %xmm2,%xmm3
  subss  %xmm3,%xmm4
  movss  %xmm4,-0x4(%rdi)
  cmp    %r11,%rdi
  jne    L46
  lea    0x4(%r8),%rax
  sub    %rbx,%rax
  cmp    $0x8,%rax
  jbe    L42
  cmp    $0x2,%ebp
  jbe    L42
  lea    -0x1(%r10),%ecx
  mov    %ecx,%eax
  shr    $0x2,%eax
  lea    -0x1(%rax),%edx
  mov    $0x4,%eax
  shl    $0x4,%rdx
  add    $0x14,%rdx
  cs nopw 0x0(%rax,%rax,1)
L101:
  movups (%r9,%rax,1),%xmm6
  movups %xmm6,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rdx,%rax
  jne    L101
  mov    %ecx,%eax
  and    $0xfffffffc,%eax
  lea    0x1(%rax),%edx
  cmp    %ecx,%eax
  je     L82
  movslq %edx,%rdx
  movss  (%r9,%rdx,4),%xmm0
  lea    0x0(,%rdx,4),%rcx
  movss  %xmm0,(%r8,%rdx,4)
  lea    0x2(%rax),%edx
  cmp    %edx,%r10d
  jle    L82
  movss  0x4(%r9,%rcx,1),%xmm0
  add    $0x3,%eax
  movss  %xmm0,0x4(%r8,%rcx,1)
  cmp    %eax,%r10d
  jle    L82
  movss  0x8(%r9,%rcx,1),%xmm0
  movss  %xmm0,0x8(%r8,%rcx,1)
L82:
  pop    %rbx
  pop    %rbp
  movl   $0x3f800000,(%r8,%r10,4)
  ret
  nopl   (%rax)
L38:
  movslq %edx,%rax
  movss  (%rsi,%rax,4),%xmm2
  lea    0x0(,%rax,4),%rcx
  jmp    L4
L42:
  mov    %r10d,%edx
  mov    $0x1,%eax
  nopl   (%rax)
L55:
  movss  (%r9,%rax,4),%xmm0
  movss  %xmm0,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%rdx
  jne    L55
  pop    %rbx
  pop    %rbp
  movl   $0x3f800000,(%r8,%r10,4)
  ret
L129:
  movl   $0x3f800000,(%rcx,%r10,4)
  ret
```

assistant: ```c
void rebin(float rc, int nd, float r[], float xin[], float xi[]) {
  int i, k = 0;
  float dr = 0.0, xn = 0.0, xo = 0.0;
  for (i = 1; i < nd; i++) {
    while (rc > dr)
      dr += r[++k];
    if (k > 1)
      xo = xi[k - 1];
    xn = xi[k];
    dr -= rc;
    xin[i] = xn - (xn - xo) * dr / r[k];
  }
  for (i = 1; i < nd; i++)
    xi[i] = xin[i];
  xi[nd] = 1.0;
}
```