ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<HibernateDataSet>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  xor    %edi,%edi
  cmp    $0x40,%esi
  push   %rbx
  setle  %dil
  mov    %esi,%ebx
  call   <ASSERT@plt>
  xor    %edi,%edi
  test   %rbp,%rbp
  setne  %dil
  call   <ASSERT@plt>
  test   %ebx,%ebx
  jle    L18
  lea    0x1003f00c(%rbx),%r12d
  mov    $0x400fc030,%ebx
  shl    $0x2,%r12
  nopl   (%rax)
L7:
  mov    -0x400fc030(%rbp,%rbx,1),%eax
  add    $0x4,%rbx
  mov    %eax,-0x4(%rbx)
  xor    %eax,%eax
  call   <_HibernateWriteComplete@plt>
  cmp    %rbx,%r12
  jne    L7
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void HibernateDataSet(uint32_t *pui32Data, uint32_t ui32Count) {
  uint32_t ui32Idx;
  ASSERT(ui32Count <= 64);
  ASSERT(pui32Data != 0);
  for (ui32Idx = 0; ui32Idx < ui32Count; ui32Idx++) {
    (*((volatile uint32_t *)(0x400FC030 + (ui32Idx * 4)))) = pui32Data[ui32Idx];
    _HibernateWriteComplete();
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<relax_graddesc>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r13d
  mov    %edx,%r15d
  mov    %r8,%rbp
  mov    %r9,%rbx
  mov    0x40(%rsp),%r12
  mov    %r12,%r9
  mov    %rbx,%r8
  call   <relax_ab@plt>
  mov    %r15d,%r8d
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <relax_dot@plt>
  movq   %xmm0,%r14
  mov    %r15d,%r8d
  mov    $0x1,%ecx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <relax_dot@plt>
  movq   %r14,%xmm2
  divsd  %xmm0,%xmm2
  movapd %xmm2,%xmm0
  mulsd  (%rbx),%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movapd %xmm2,%xmm1
  mulsd  (%r12),%xmm1
  movsd  (%rbx),%xmm0
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  andpd  D17(%rip),%xmm0
  cmp    $0x1,%r13d
  jle    L11
  mov    %r13d,%r13d
  mov    $0x1,%eax
  movq   D17(%rip),%xmm4
L0:
  movapd %xmm2,%xmm1
  mulsd  (%rbx,%rax,8),%xmm1
  addsd  0x0(%rbp,%rax,8),%xmm1
  movsd  %xmm1,0x0(%rbp,%rax,8)
  movapd %xmm2,%xmm3
  mulsd  (%r12,%rax,8),%xmm3
  movsd  (%rbx,%rax,8),%xmm1
  subsd  %xmm3,%xmm1
  movsd  %xmm1,(%rbx,%rax,8)
  andpd  %xmm4,%xmm1
  maxsd  %xmm1,%xmm0
  add    $0x1,%rax
  cmp    %r13,%rax
  jne    L0
L11:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
type_infered: qword[2]

tool: {"D17": [0x7fffffffffffffff,0x0000000000000000]}

assistant: ```c
double relax_graddesc(double *A, int m, int n, int stride, double *x0, double *res, double *ares) {
  double a, restmp, maxres;
  int i;
  relax_ab(A, m, n, stride, res, ares);
  a = relax_dot(res, 1, res, 1, n) / relax_dot(res, 1, ares, 1, n);
  x0[0] = x0[0] + a * res[0];
  res[0] = res[0] - a * ares[0];
  maxres = fabs(res[0]);
  for (i = 1; i < m; i++) {
    x0[i] = x0[i] + a * res[i];
    res[i] = res[i] - a * ares[i];
    restmp = fabs(res[i]);
    maxres = maxres > restmp ? maxres : restmp;
  }
  return maxres;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<relax_graddesc>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %r13d,%esi
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9,%rbx
  mov    %rbx,%r8
  sub    $0x10,%rsp
  mov    0x40(%rsp),%r12
  mov    %r12,%r9
  call   <relax_ab@plt>
  mov    %r14d,%r8d
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <relax_dot@plt>
  mov    %r14d,%r8d
  mov    $0x1,%ecx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <relax_dot@plt>
  movsd  0x8(%rsp),%xmm2
  movq   D1(%rip),%xmm4
  divsd  %xmm0,%xmm2
  movsd  (%rbx),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  (%r12),%xmm1
  movsd  (%rbx),%xmm0
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  andpd  %xmm4,%xmm0
  cmp    $0x1,%r13d
  jle    L13
  mov    $0x1,%eax
  xchg   %ax,%ax
L7:
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  0x0(%rbp,%rax,8),%xmm1
  movsd  %xmm1,0x0(%rbp,%rax,8)
  movsd  (%r12,%rax,8),%xmm3
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  %xmm2,%xmm3
  subsd  %xmm3,%xmm1
  movsd  %xmm1,(%rbx,%rax,8)
  andpd  %xmm4,%xmm1
  add    $0x1,%rax
  maxsd  %xmm1,%xmm0
  cmp    %rax,%r13
  jne    L7
L13:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type_guessed: qword

tool: D1: 9223372036854775807

assistant: ```c
double relax_graddesc(double *A, int m, int n, int stride, double *x0, double *res, double *ares) {
  double a, restmp, maxres;
  int i;
  relax_ab(A, m, n, stride, res, ares);
  a = relax_dot(res, 1, res, 1, n) / relax_dot(res, 1, ares, 1, n);
  x0[0] = x0[0] + a * res[0];
  res[0] = res[0] - a * ares[0];
  maxres = fabs(res[0]);
  for (i = 1; i < m; i++) {
    x0[i] = x0[i] + a * res[i];
    res[i] = res[i] - a * ares[i];
    restmp = fabs(res[i]);
    maxres = maxres > restmp ? maxres : restmp;
  }
  return maxres;
}
```
user: Translate the below assembly code into C programming language:

```asm
<relax_graddesc>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  movslq %esi,%r13
  push   %r12
  mov    %r13d,%esi
  push   %rbp
  mov    %r8,%rbp
  push   %rbx
  mov    %r9,%rbx
  mov    %rbx,%r8
  sub    $0x10,%rsp
  mov    0x40(%rsp),%r12
  mov    %r12,%r9
  call   <relax_ab@plt>
  mov    %r14d,%r8d
  mov    $0x1,%ecx
  mov    %rbx,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <relax_dot@plt>
  mov    %r14d,%r8d
  mov    $0x1,%ecx
  mov    %r12,%rdx
  mov    $0x1,%esi
  mov    %rbx,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <relax_dot@plt>
  movsd  0x8(%rsp),%xmm2
  movq   D4(%rip),%xmm4
  divsd  %xmm0,%xmm2
  movsd  (%rbx),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  movsd  (%r12),%xmm1
  movsd  (%rbx),%xmm0
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movsd  %xmm0,(%rbx)
  andpd  %xmm4,%xmm0
  cmp    $0x1,%r13d
  jle    L19
  mov    $0x1,%eax
  xchg   %ax,%ax
L15:
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  %xmm2,%xmm1
  addsd  0x0(%rbp,%rax,8),%xmm1
  movsd  %xmm1,0x0(%rbp,%rax,8)
  movsd  (%r12,%rax,8),%xmm3
  movsd  (%rbx,%rax,8),%xmm1
  mulsd  %xmm2,%xmm3
  subsd  %xmm3,%xmm1
  movsd  %xmm1,(%rbx,%rax,8)
  andpd  %xmm4,%xmm1
  add    $0x1,%rax
  maxsd  %xmm1,%xmm0
  cmp    %rax,%r13
  jne    L15
L19:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: qword

tool: D4: 9223372036854775807

assistant: ```c
double relax_graddesc(double *A, int m, int n, int stride, double *x0, double *res, double *ares) {
  double a, restmp, maxres;
  int i;
  relax_ab(A, m, n, stride, res, ares);
  a = relax_dot(res, 1, res, 1, n) / relax_dot(res, 1, ares, 1, n);
  x0[0] = x0[0] + a * res[0];
  res[0] = res[0] - a * ares[0];
  maxres = fabs(res[0]);
  for (i = 1; i < m; i++) {
    x0[i] = x0[i] + a * res[i];
    res[i] = res[i] - a * ares[i];
    restmp = fabs(res[i]);
    maxres = maxres > restmp ? maxres : restmp;
  }
  return maxres;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x23,%esi
  mov    $0x1b2,%edi
  call   <mdc@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string

tool: D2: o mdc entr 434 e 35 eh: %d

assistant: ```c
int main() {
  printf("o mdc entr 434 e 35 eh: %d", mdc(434, 35));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  mov    $0x1b2,%edi
  call   <mdc@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
datatype: string

tool: D0: o mdc entr 434 e 35 eh: %d

assistant: ```c
int main() {
  printf("o mdc entr 434 e 35 eh: %d", mdc(434, 35));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  mov    $0x1b2,%edi
  call   <mdc@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type_infered: string

tool: D4: o mdc entr 434 e 35 eh: %d

assistant: ```c
int main() {
  printf("o mdc entr 434 e 35 eh: %d", mdc(434, 35));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x23,%esi
  mov    $0x1b2,%edi
  call   <mdc@plt>
  lea    D9(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: o mdc entr 434 e 35 eh: %d

assistant: ```c
int main() {
  printf("o mdc entr 434 e 35 eh: %d", mdc(434, 35));
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<initializeCero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L6:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0x3fffff,-0x4(%rbp)
  jle    L6
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void initializeCero(double *array) {
  int i;
  for (i = 0; i < 2048 * 2048; i++)
    array[i] = 0.0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<initializeCero>:
  endbr64
  lea    0x2000000(%rdi),%rax
L8:
  movq   $0x0,(%rdi)
  add    $0x8,%rdi
  cmp    %rax,%rdi
  jne    L8
  ret
```

assistant: ```c
void initializeCero(double *array) {
  int i;
  for (i = 0; i < 2048 * 2048; i++)
    array[i] = 0.0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<initializeCero>:
  endbr64
  mov    $0x2000000,%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void initializeCero(double *array) {
  int i;
  for (i = 0; i < 2048 * 2048; i++)
    array[i] = 0.0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<initializeCero>:
  endbr64
  mov    $0x2000000,%edx
  xor    %esi,%esi
  jmp    1050 <memset@plt>
```

assistant: ```c
void initializeCero(double *array) {
  int i;
  for (i = 0; i < 2048 * 2048; i++)
    array[i] = 0.0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scanexp>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %edx,%ebx
  call   <shgetc@plt>
  lea    -0x2b(%rax),%edx
  mov    $0x0,%r14d
  test   $0xfffffffd,%edx
  je     L109
L85:
  lea    -0x30(%rax),%edx
  mov    $0x0,%ebx
  cmp    $0x9,%edx
  ja     L22
  mov    D0(%rip),%r13
L105:
  mov    0x0(%r13),%ecx
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  cmp    %ebx,%edx
  jle    L114
  lea    (%rbx,%rbx,4),%edx
  lea    -0x30(%rax,%rdx,2),%ebx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <shgetc@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L105
  movslq %ebx,%rbx
  jmp    L122
L109:
  cmp    $0x2d,%eax
  sete   %r14b
  movzbl %r14b,%r14d
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <shgetc@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L85
  test   %ebx,%ebx
  je     L85
  mov    %rbp,%rdi
  call   <shunget@plt>
L22:
  mov    %rbp,%rdi
  call   <shunget@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%rbx
  jmp    L20
L114:
  movslq %ebx,%rbx
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  ja     L122
  mov    D11(%rip),%r13
L26:
  mov    0x0(%r13),%ecx
  movslq %ecx,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  cmp    %rbx,%rdx
  jle    L51
  lea    (%rbx,%rbx,4),%rdx
  cltq
  lea    -0x30(%rax,%rdx,2),%rbx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <shgetc@plt>
  lea    -0x30(%rax),%edx
  cmp    $0x9,%edx
  jbe    L26
  jmp    L122
L51:
  sub    $0x30,%eax
  cmp    $0x9,%eax
  ja     L122
L23:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <shgetc@plt>
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L23
L122:
  mov    %rbp,%rdi
  call   <shunget@plt>
  mov    %rbx,%rax
  neg    %rax
  test   %r14d,%r14d
  cmovne %rax,%rbx
L20:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long long scanexp(char *input, int *index, int pok) {
  int c;
  int x;
  long long y;
  int neg = 0;
  c = shgetc(input, index);
  if (c == '+' || c == '-') {
    neg = (c == '-');
    c = shgetc(input, index);
    if ((unsigned)(c - '0') >= 10U && pok)
      shunget(index);
  }
  if ((unsigned)(c - '0') >= 10U) {
    shunget(index);
    return LLONG_MIN;
  }
  for (x = 0; (unsigned)(c - '0') < 10U && x < INT_MAX / 10; c = shgetc(input, index))
    x = 10 * x + c - '0';
  for (y = x; (unsigned)(c - '0') < 10U && y < LLONG_MAX / 100; c = shgetc(input, index))
    y = 10 * y + c - '0';
  for (; (unsigned)(c - '0') < 10U; c = shgetc(input, index))
    ;
  shunget(index);
  return neg ? -y : y;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<scanexp>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <shgetc@plt>
  lea    -0x2b(%rax),%edx
  and    $0xfffffffd,%edx
  je     L13
  lea    -0x30(%rax),%ecx
  xor    %ebp,%ebp
L23:
  cmp    $0x9,%ecx
  ja     L25
L70:
  mov    D27(%rip),%r14
  xor    %r12d,%r12d
  jmp    L120
L49:
  lea    (%r12,%r12,4),%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  lea    -0x30(%rax,%rdx,2),%r12d
  call   <shgetc@plt>
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  ja     L99
L120:
  movslq (%r14),%rdx
  mov    %rdx,%rsi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  cmp    %r12d,%edx
  jg     L49
  movslq %r12d,%r12
  cmp    $0x9,%ecx
  ja     L21
  mov    D24(%rip),%r14
  jmp    L61
  nopl   0x0(%rax)
L14:
  lea    (%r12,%r12,4),%rdx
  cltq
  mov    %r13,%rsi
  mov    %rbx,%rdi
  lea    -0x30(%rax,%rdx,2),%r12
  call   <shgetc@plt>
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  ja     L21
L61:
  movslq (%r14),%rdx
  mov    %rdx,%rsi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x25,%rdx
  sub    %esi,%edx
  movslq %edx,%rdx
  cmp    %r12,%rdx
  jg     L14
  cmp    $0x9,%ecx
  ja     L21
  nopl   0x0(%rax)
L9:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <shgetc@plt>
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L9
L21:
  mov    %r13,%rdi
  call   <shunget@plt>
  mov    %r12,%rax
  pop    %rbx
  neg    %rax
  test   %ebp,%ebp
  pop    %rbp
  cmovne %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L13:
  xor    %ebp,%ebp
  mov    %r13,%rsi
  cmp    $0x2d,%eax
  mov    %rbx,%rdi
  sete   %bpl
  call   <shgetc@plt>
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  jbe    L70
  test   %r12d,%r12d
  je     L23
  mov    %r13,%rdi
  call   <shunget@plt>
L25:
  mov    %r13,%rdi
  call   <shunget@plt>
  mov    D21(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L99:
  movslq %r12d,%r12
  jmp    L21
```

assistant: ```c
long long scanexp(char *input, int *index, int pok) {
  int c;
  int x;
  long long y;
  int neg = 0;
  c = shgetc(input, index);
  if (c == '+' || c == '-') {
    neg = (c == '-');
    c = shgetc(input, index);
    if ((unsigned)(c - '0') >= 10U && pok)
      shunget(index);
  }
  if ((unsigned)(c - '0') >= 10U) {
    shunget(index);
    return LLONG_MIN;
  }
  for (x = 0; (unsigned)(c - '0') < 10U && x < INT_MAX / 10; c = shgetc(input, index))
    x = 10 * x + c - '0';
  for (y = x; (unsigned)(c - '0') < 10U && y < LLONG_MAX / 100; c = shgetc(input, index))
    y = 10 * y + c - '0';
  for (; (unsigned)(c - '0') < 10U; c = shgetc(input, index))
    ;
  shunget(index);
  return neg ? -y : y;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<scanexp>:
  endbr64
  push   %r14
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <shgetc@plt>
  lea    -0x2b(%rax),%edx
  and    $0xfffffffd,%edx
  je     L8
  lea    -0x30(%rax),%ecx
  xor    %ebp,%ebp
L90:
  cmp    $0x9,%ecx
  ja     L132
L80:
  mov    D24(%rip),%r14
  xor    %r12d,%r12d
  jmp    L13
L19:
  lea    (%r12,%r12,4),%edx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  lea    -0x30(%rax,%rdx,2),%r12d
  call   <shgetc@plt>
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  ja     L134
L13:
  movslq (%r14),%rdx
  mov    %rdx,%rsi
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x22,%rdx
  sub    %esi,%edx
  cmp    %r12d,%edx
  jg     L19
  movslq %r12d,%r12
  cmp    $0x9,%ecx
  ja     L124
  mov    D16(%rip),%r14
  jmp    L84
  nopl   0x0(%rax)
L18:
  lea    (%r12,%r12,4),%rdx
  cltq
  mov    %r13,%rsi
  mov    %rbx,%rdi
  lea    -0x30(%rax,%rdx,2),%r12
  call   <shgetc@plt>
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  ja     L124
L84:
  movslq (%r14),%rdx
  mov    %rdx,%rsi
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%esi
  sar    $0x25,%rdx
  sub    %esi,%edx
  movslq %edx,%rdx
  cmp    %r12,%rdx
  jg     L18
  cmp    $0x9,%ecx
  ja     L124
  nopl   0x0(%rax)
L103:
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <shgetc@plt>
  sub    $0x30,%eax
  cmp    $0x9,%eax
  jbe    L103
L124:
  mov    %r13,%rdi
  call   <shunget@plt>
  mov    %r12,%rax
  pop    %rbx
  neg    %rax
  test   %ebp,%ebp
  pop    %rbp
  cmovne %rax,%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  xor    %ebp,%ebp
  mov    %r13,%rsi
  cmp    $0x2d,%eax
  mov    %rbx,%rdi
  sete   %bpl
  call   <shgetc@plt>
  lea    -0x30(%rax),%ecx
  cmp    $0x9,%ecx
  jbe    L80
  test   %r12d,%r12d
  je     L90
  mov    %r13,%rdi
  call   <shunget@plt>
L132:
  mov    %r13,%rdi
  call   <shunget@plt>
  mov    D2(%rip),%rax
  pop    %rbx
  pop    %rbp
  mov    (%rax),%r12
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L134:
  movslq %r12d,%r12
  jmp    L124
```

assistant: ```c
long long scanexp(char *input, int *index, int pok) {
  int c;
  int x;
  long long y;
  int neg = 0;
  c = shgetc(input, index);
  if (c == '+' || c == '-') {
    neg = (c == '-');
    c = shgetc(input, index);
    if ((unsigned)(c - '0') >= 10U && pok)
      shunget(index);
  }
  if ((unsigned)(c - '0') >= 10U) {
    shunget(index);
    return LLONG_MIN;
  }
  for (x = 0; (unsigned)(c - '0') < 10U && x < INT_MAX / 10; c = shgetc(input, index))
    x = 10 * x + c - '0';
  for (y = x; (unsigned)(c - '0') < 10U && y < LLONG_MAX / 100; c = shgetc(input, index))
    y = 10 * y + c - '0';
  for (; (unsigned)(c - '0') < 10U; c = shgetc(input, index))
    ;
  shunget(index);
  return neg ? -y : y;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L3
L17:
  mov    $0x0,%eax
  call   <f2@plt>
  addl   $0x1,-0x4(%rbp)
L3:
  cmpl   $0x9,-0x4(%rbp)
  jle    L17
  nop
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++)
    f2();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
L3:
  mov    $0x0,%eax
  call   <f2@plt>
  sub    $0x1,%ebx
  jne    L3
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++)
    f2();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <f2@plt>
  sub    $0x1,%ebx
  jne    L4
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++)
    f2();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <f2@plt>
  sub    $0x1,%ebx
  jne    L0
  pop    %rbx
  ret
```

assistant: ```c
void main(void) {
  int i;
  for (i = 0; i < 10; i++)
    f2();
}
```
user: Translate the below assembly code into C programming language:

```asm
<hexdigitp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  sub    $0x30,%eax
  cmp    $0x36,%eax
  seta   %dl
  test   %dl,%dl
  jne    L18
  movabs $0x7e0000007e03ff,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L18
  movl   $0x1,-0x4(%rbp)
  nop
L18:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hexdigitp(int c) {
  int ret = 0;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case 'A':
  case 'B':
  case 'C':
  case 'D':
  case 'E':
  case 'F':
  case 'a':
  case 'b':
  case 'c':
  case 'd':
  case 'e':
  case 'f':
    ret = 1;
    break;
  }
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hexdigitp>:
  endbr64
  lea    -0x30(%rdi),%ecx
  cmp    $0x36,%ecx
  ja     L4
  movabs $0x7e0000007e03ff,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L4:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int hexdigitp(int c) {
  int ret = 0;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case 'A':
  case 'B':
  case 'C':
  case 'D':
  case 'E':
  case 'F':
  case 'a':
  case 'b':
  case 'c':
  case 'd':
  case 'e':
  case 'f':
    ret = 1;
    break;
  }
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<hexdigitp>:
  endbr64
  lea    -0x30(%rdi),%ecx
  cmp    $0x36,%ecx
  ja     L3
  movabs $0x7e0000007e03ff,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hexdigitp(int c) {
  int ret = 0;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case 'A':
  case 'B':
  case 'C':
  case 'D':
  case 'E':
  case 'F':
  case 'a':
  case 'b':
  case 'c':
  case 'd':
  case 'e':
  case 'f':
    ret = 1;
    break;
  }
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hexdigitp>:
  endbr64
  lea    -0x30(%rdi),%ecx
  cmp    $0x36,%ecx
  ja     L0
  movabs $0x7e0000007e03ff,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   (%rax)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hexdigitp(int c) {
  int ret = 0;
  switch (c) {
  case '0':
  case '1':
  case '2':
  case '3':
  case '4':
  case '5':
  case '6':
  case '7':
  case '8':
  case '9':
  case 'A':
  case 'B':
  case 'C':
  case 'D':
  case 'E':
  case 'F':
  case 'a':
  case 'b':
  case 'c':
  case 'd':
  case 'e':
  case 'f':
    ret = 1;
    break;
  }
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<panel_utils_scroll_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jge    L9
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%edx
  mov    %edx,(%rax)
  jmp    L19
L9:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
  add    %edx,%eax
  cmp    %eax,-0x8(%rbp)
  jle    L19
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%ecx
  mov    -0x8(%rbp),%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
L19:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void panel_utils_scroll_list(int numslots, int edit_pos, int *display_pos) {
  if (*display_pos > edit_pos) {
    *display_pos = edit_pos;
  } else if (edit_pos > (*display_pos + (numslots - 1))) {
    *display_pos = edit_pos - (numslots - 1);
  }
}
```