ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<countTrashSize>:
  endbr64
  mov    $0x0,%edx
  mov    $0x0,%r8d
  jmp    L16
L5:
  add    $0x1,%rdx
  cmp    $0x100,%rdx
  je     L31
L16:
  mov    (%rsi,%rdx,8),%rcx
  cmp    $0xffffffffffffffff,%rcx
  je     L5
  movslq (%rdi,%rdx,4),%rax
  imul   %rcx,%rax
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3d,%rcx
  add    %rcx,%rax
  and    $0x7,%eax
  sub    %rcx,%rax
  add    %rax,%r8
  jmp    L5
L31:
  mov    %r8,%rax
  sar    $0x3f,%rax
  shr    $0x3d,%rax
  add    %rax,%r8
  and    $0x7,%r8d
  sub    %r8,%rax
  lea    0x8(%rax),%eax
  ret
```

assistant: ```c
int countTrashSize(int bitsQuantity[], long long int frequency[]) {
  int i;
  long long int trashSize = 0;
  for (i = 0; i < 256; i++)
    if (frequency[i] != -1)
      trashSize += (bitsQuantity[i] * frequency[i]) % 8;
  trashSize = 8 - (trashSize % 8);
  return (trashSize);
}
```
user: Translate the below assembly code into C programming language:

```asm
<countTrashSize>:
  endbr64
  xor    %edx,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L7:
  mov    (%rsi,%rdx,8),%rcx
  cmp    $0xffffffffffffffff,%rcx
  je     L5
  movslq (%rdi,%rdx,4),%rax
  imul   %rcx,%rax
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3d,%rcx
  add    %rcx,%rax
  and    $0x7,%eax
  sub    %rcx,%rax
  add    %rax,%r8
L5:
  add    $0x1,%rdx
  cmp    $0x100,%rdx
  jne    L7
  mov    %r8,%rax
  sar    $0x3f,%rax
  shr    $0x3d,%rax
  add    %rax,%r8
  and    $0x7,%r8d
  sub    %r8,%rax
  add    $0x8,%eax
  ret
```

assistant: ```c
int countTrashSize(int bitsQuantity[], long long int frequency[]) {
  int i;
  long long int trashSize = 0;
  for (i = 0; i < 256; i++)
    if (frequency[i] != -1)
      trashSize += (bitsQuantity[i] * frequency[i]) % 8;
  trashSize = 8 - (trashSize % 8);
  return (trashSize);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<countTrashSize>:
  endbr64
  xor    %edx,%edx
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L4:
  mov    (%rsi,%rdx,8),%rcx
  cmp    $0xffffffffffffffff,%rcx
  je     L10
  movslq (%rdi,%rdx,4),%rax
  imul   %rcx,%rax
  mov    %rax,%rcx
  sar    $0x3f,%rcx
  shr    $0x3d,%rcx
  add    %rcx,%rax
  and    $0x7,%eax
  sub    %rcx,%rax
  add    %rax,%r8
L10:
  add    $0x1,%rdx
  cmp    $0x100,%rdx
  jne    L4
  mov    %r8,%rax
  sar    $0x3f,%rax
  shr    $0x3d,%rax
  add    %rax,%r8
  and    $0x7,%r8d
  sub    %r8,%rax
  add    $0x8,%eax
  ret
```

assistant: ```c
int countTrashSize(int bitsQuantity[], long long int frequency[]) {
  int i;
  long long int trashSize = 0;
  for (i = 0; i < 256; i++)
    if (frequency[i] != -1)
      trashSize += (bitsQuantity[i] * frequency[i]) % 8;
  trashSize = 8 - (trashSize % 8);
  return (trashSize);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<f>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  cmpl   $0x40,-0x14(%rbp)
  jle    L3
  mov    -0x1c(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x1c(%rbp),%eax
  shl    $0x2,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
L3:
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int f(int n, int c, int s) {
  int a, x1, x2, x3;
  x1 = x2 = x3 = c;
  if (n > 64) {
    a = 2 * s;
    x1 = c + a;
    a = 4 * s;
    x2 = c + a;
    a = 6 * s;
    x3 = c + a;
  }
  return x1 + x2 + x3;
}
```
user: What is the c source code of the assembly code below:

```asm
<f>:
  endbr64
  cmp    $0x40,%edi
  jle    L12
  add    %edx,%edx
  add    %edx,%esi
  lea    (%rdx,%rsi,1),%eax
  add    %eax,%edx
L4:
  add    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
L12:
  mov    %esi,%edx
  mov    %esi,%eax
  jmp    L4
```

assistant: ```c
int f(int n, int c, int s) {
  int a, x1, x2, x3;
  x1 = x2 = x3 = c;
  if (n > 64) {
    a = 2 * s;
    x1 = c + a;
    a = 4 * s;
    x2 = c + a;
    a = 6 * s;
    x3 = c + a;
  }
  return x1 + x2 + x3;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<f>:
  endbr64
  cmp    $0x40,%edi
  jle    L1
  add    %edx,%edx
  add    %edx,%esi
  lea    (%rdx,%rsi,1),%eax
  add    %eax,%edx
  add    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %esi,%eax
  mov    %esi,%edx
  add    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
int f(int n, int c, int s) {
  int a, x1, x2, x3;
  x1 = x2 = x3 = c;
  if (n > 64) {
    a = 2 * s;
    x1 = c + a;
    a = 4 * s;
    x2 = c + a;
    a = 6 * s;
    x3 = c + a;
  }
  return x1 + x2 + x3;
}
```
user: Translate the below assembly code into C programming language:

```asm
<f>:
  endbr64
  cmp    $0x40,%edi
  jle    L8
  add    %edx,%edx
  add    %edx,%esi
  lea    (%rdx,%rsi,1),%eax
  add    %eax,%edx
  add    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %esi,%eax
  mov    %esi,%edx
  add    %eax,%esi
  lea    (%rsi,%rdx,1),%eax
  ret
```

assistant: ```c
int f(int n, int c, int s) {
  int a, x1, x2, x3;
  x1 = x2 = x3 = c;
  if (n > 64) {
    a = 2 * s;
    x1 = c + a;
    a = 4 * s;
    x2 = c + a;
    a = 6 * s;
    x3 = c + a;
  }
  return x1 + x2 + x3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %edx,-0x20(%rbp)
  mov    %al,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x1c(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L9
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void memset(void *dst, char value, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *((char *)dst + i) = value;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L4
  mov    %rdi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x1(%rdi,%rdx,1),%rdx
L1:
  mov    %sil,(%rax)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L1
L4:
  ret
```

assistant: ```c
void memset(void *dst, char value, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *((char *)dst + i) = value;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L4
  movslq %edx,%rdx
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L4:
  ret
```

assistant: ```c
void memset(void *dst, char value, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *((char *)dst + i) = value;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<memset>:
  endbr64
  test   %edx,%edx
  jle    L5
  movslq %edx,%rdx
  movsbl %sil,%esi
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void memset(void *dst, char value, int len) {
  int i;
  for (i = 0; i < len; i++) {
    *((char *)dst + i) = value;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<keyboard>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  cmp    $0x77,%eax
  jg     L45
  cmp    $0x61,%eax
  jge    L112
  cmp    $0x1b,%eax
  je     L64
  cmp    $0x20,%eax
  je     L1
  jmp    L45
L112:
  sub    $0x61,%eax
  cmp    $0x16,%eax
  ja     L45
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D18(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D18(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L64:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L45
L1:
  mov    $0x7,%edi
  call   <menu@plt>
  jmp    L45
  mov    $0x5,%edi
  call   <menu@plt>
  jmp    L45
  mov    $0x2,%edi
  call   <menu@plt>
  jmp    L45
  mov    $0x1,%edi
  call   <menu@plt>
  jmp    L45
  mov    $0x3,%edi
  call   <menu@plt>
  jmp    L45
  mov    $0x4,%edi
  call   <menu@plt>
  nop
L45:
  nop
  leave
  ret
```

assistant: ```c
void keyboard(unsigned char c, int x, int y) {
  switch (c) {
  case 27:
    exit(0);
    break;
  case ' ':
    menu(7);
    break;
  case 'a':
    menu(5);
    break;
  case 'w':
    menu(2);
    break;
  case 'f':
    menu(1);
    break;
  case 't':
    menu(3);
    break;
  case 'n':
    menu(4);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<keyboard>:
  endbr64
  cmp    $0x77,%dil
  ja     L40
  sub    $0x8,%rsp
  cmp    $0x60,%dil
  jbe    L43
  sub    $0x61,%edi
  cmp    $0x16,%dil
  ja     L65
  movzbl %dil,%edi
  lea    D8(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
L43:
  cmp    $0x1b,%dil
  je     L10
  cmp    $0x20,%dil
  jne    L65
  mov    $0x7,%edi
  call   <menu@plt>
  jmp    L65
L10:
  mov    $0x0,%edi
  call   <exit@plt>
L65:
  add    $0x8,%rsp
  ret
  mov    $0x5,%edi
  call   <menu@plt>
  jmp    L65
  mov    $0x2,%edi
  call   <menu@plt>
  jmp    L65
  mov    $0x1,%edi
  call   <menu@plt>
  jmp    L65
  mov    $0x3,%edi
  call   <menu@plt>
  jmp    L65
  mov    $0x4,%edi
  call   <menu@plt>
  jmp    L65
L40:
  ret
```

assistant: ```c
void keyboard(unsigned char c, int x, int y) {
  switch (c) {
  case 27:
    exit(0);
    break;
  case ' ':
    menu(7);
    break;
  case 'a':
    menu(5);
    break;
  case 'w':
    menu(2);
    break;
  case 'f':
    menu(1);
    break;
  case 't':
    menu(3);
    break;
  case 'n':
    menu(4);
    break;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<keyboard>:
  endbr64
  cmp    $0x77,%dil
  ja     L23
  cmp    $0x60,%dil
  jbe    L39
  sub    $0x61,%edi
  cmp    $0x16,%dil
  ja     L23
  lea    D4(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
L39:
  cmp    $0x1b,%dil
  je     L2
  cmp    $0x20,%dil
  jne    L3
  mov    $0x7,%edi
  jmp    1060 <menu@plt>
  cs nopw 0x0(%rax,%rax,1)
L23:
  ret
  nopl   0x0(%rax)
  mov    $0x5,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
L2:
  xor    %edi,%edi
  jmp    1070 <exit@plt>
L3:
  ret
```

assistant: ```c
void keyboard(unsigned char c, int x, int y) {
  switch (c) {
  case 27:
    exit(0);
    break;
  case ' ':
    menu(7);
    break;
  case 'a':
    menu(5);
    break;
  case 'w':
    menu(2);
    break;
  case 'f':
    menu(1);
    break;
  case 't':
    menu(3);
    break;
  case 'n':
    menu(4);
    break;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<keyboard>:
  endbr64
  cmp    $0x77,%dil
  ja     L41
  cmp    $0x60,%dil
  jbe    L46
  sub    $0x61,%edi
  cmp    $0x16,%dil
  ja     L41
  lea    D1(%rip),%rdx
  movzbl %dil,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  xchg   %ax,%ax
L46:
  cmp    $0x1b,%dil
  je     L22
  cmp    $0x20,%dil
  jne    L8
  mov    $0x7,%edi
  jmp    1060 <menu@plt>
  cs nopw 0x0(%rax,%rax,1)
L41:
  ret
  nopl   0x0(%rax)
  mov    $0x5,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x1,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%edi
  jmp    1060 <menu@plt>
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %edi,%edi
  jmp    1070 <exit@plt>
L8:
  ret
```

assistant: ```c
void keyboard(unsigned char c, int x, int y) {
  switch (c) {
  case 27:
    exit(0);
    break;
  case ' ':
    menu(7);
    break;
  case 'a':
    menu(5);
    break;
  case 'w':
    menu(2);
    break;
  case 'f':
    menu(1);
    break;
  case 't':
    menu(3);
    break;
  case 'n':
    menu(4);
    break;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Operand_uimm6_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  and    $0x3f,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  add    $0x4,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int Operand_uimm6_decode(unsigned int *valp) {
  unsigned uimm6_0, imm6_0;
  imm6_0 = *valp & 0x3f;
  uimm6_0 = 0x4 + ((((0)) << 6) | imm6_0);
  *valp = uimm6_0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Operand_uimm6_decode>:
  endbr64
  mov    (%rdi),%eax
  and    $0x3f,%eax
  add    $0x4,%eax
  mov    %eax,(%rdi)
  mov    $0x0,%eax
  ret
```

assistant: ```c
int Operand_uimm6_decode(unsigned int *valp) {
  unsigned uimm6_0, imm6_0;
  imm6_0 = *valp & 0x3f;
  uimm6_0 = 0x4 + ((((0)) << 6) | imm6_0);
  *valp = uimm6_0;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Operand_uimm6_decode>:
  endbr64
  mov    (%rdi),%eax
  and    $0x3f,%eax
  add    $0x4,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_uimm6_decode(unsigned int *valp) {
  unsigned uimm6_0, imm6_0;
  imm6_0 = *valp & 0x3f;
  uimm6_0 = 0x4 + ((((0)) << 6) | imm6_0);
  *valp = uimm6_0;
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Operand_uimm6_decode>:
  endbr64
  mov    (%rdi),%eax
  and    $0x3f,%eax
  add    $0x4,%eax
  mov    %eax,(%rdi)
  xor    %eax,%eax
  ret
```

assistant: ```c
int Operand_uimm6_decode(unsigned int *valp) {
  unsigned uimm6_0, imm6_0;
  imm6_0 = *valp & 0x3f;
  uimm6_0 = 0x4 + ((((0)) << 6) | imm6_0);
  *valp = uimm6_0;
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error_output>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void error_output(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error_output>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void error_output(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<error_output>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D0(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error_output(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<error_output>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    D3(%rip),%rax
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void error_output(const char *fmt, ...) {
  va_list ap;
  va_start(ap, fmt);
  vfprintf(stderr, fmt, ap);
  va_end(ap);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<startGame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x43,-0xc(%rbp)
  movb   $0xf8,-0xb(%rbp)
  movb   $0xe8,-0xa(%rbp)
  movb   $0xb0,-0x9(%rbp)
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <newwin@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wrefresh@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <box@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wrefresh@plt>
  mov    $0x0,%eax
  call   <has_colors@plt>
  test   %rax,%rax
  je     L6
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    D58(%rip),%rax
  mov    (%rax),%edx
  mov    D16(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <init_pair@plt>
  mov    D58(%rip),%rax
  mov    (%rax),%edx
  mov    D37(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <init_pair@plt>
  mov    D58(%rip),%rax
  mov    (%rax),%edx
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x3,%edi
  call   <init_pair@plt>
  mov    D58(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  mov    $0x4,%edi
  call   <init_pair@plt>
L6:
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <wattrset@plt>
  movsbl -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <mvwaddch@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <wgetch@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <delwin@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

assistant: ```c
void startGame() {
  chtype pacman = 'C';
  chtype food = 248;
  chtype monster = 232;
  chtype wall = 176;
  WINDOW *win = newwin(0, 0, 0, 0);
  wrefresh(win);
  box(win, 0, 0);
  wrefresh(win);
  if (has_colors()) {
    start_color();
    init_pair(1, COLOR_YELLOW, COLOR_BLACK);
    init_pair(2, COLOR_GREEN, COLOR_BLACK);
    init_pair(3, COLOR_CYAN, COLOR_BLACK);
    init_pair(4, COLOR_WHITE, COLOR_BLACK);
  }
  wattrset(win, COLOR_PAIR(1));
  mvwaddch(win, 2, 2, pacman);
  wgetch(win);
  delwin(win);
  endwin();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<startGame>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <newwin@plt>
  mov    %rax,%rbx
  mov    %rax,%rdi
  call   <wrefresh@plt>
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <box@plt>
  mov    %rbx,%rdi
  call   <wrefresh@plt>
  mov    $0x0,%eax
  call   <has_colors@plt>
  test   %rax,%rax
  jne    L19
L8:
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <wattrset@plt>
  mov    $0x43,%ecx
  mov    $0x2,%edx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <mvwaddch@plt>
  mov    %rbx,%rdi
  call   <wgetch@plt>
  mov    %rbx,%rdi
  call   <delwin@plt>
  mov    $0x0,%eax
  call   <endwin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    $0x0,%eax
  call   <start_color@plt>
  mov    D19(%rip),%rbp
  mov    0x0(%rbp),%edx
  mov    D25(%rip),%rax
  mov    (%rax),%esi
  mov    $0x1,%edi
  call   <init_pair@plt>
  mov    0x0(%rbp),%edx
  mov    D8(%rip),%rax
  mov    (%rax),%esi
  mov    $0x2,%edi
  call   <init_pair@plt>
  mov    0x0(%rbp),%edx
  mov    D22(%rip),%rax
  mov    (%rax),%esi
  mov    $0x3,%edi
  call   <init_pair@plt>
  mov    0x0(%rbp),%edx
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  mov    $0x4,%edi
  call   <init_pair@plt>
  jmp    L8
```

assistant: ```c
void startGame() {
  chtype pacman = 'C';
  chtype food = 248;
  chtype monster = 232;
  chtype wall = 176;
  WINDOW *win = newwin(0, 0, 0, 0);
  wrefresh(win);
  box(win, 0, 0);
  wrefresh(win);
  if (has_colors()) {
    start_color();
    init_pair(1, COLOR_YELLOW, COLOR_BLACK);
    init_pair(2, COLOR_GREEN, COLOR_BLACK);
    init_pair(3, COLOR_CYAN, COLOR_BLACK);
    init_pair(4, COLOR_WHITE, COLOR_BLACK);
  }
  wattrset(win, COLOR_PAIR(1));
  mvwaddch(win, 2, 2, pacman);
  wgetch(win);
  delwin(win);
  endwin();
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<startGame>:
  endbr64
  push   %rbp
  xor    %ecx,%ecx
  xor    %edx,%edx
  xor    %esi,%esi
  push   %rbx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <newwin@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <wrefresh@plt>
  xor    %edx,%edx
  xor    %esi,%esi
  mov    %rbp,%rdi
  call   <box@plt>
  mov    %rbp,%rdi
  call   <wrefresh@plt>
  xor    %eax,%eax
  call   <has_colors@plt>
  test   %rax,%rax
  jne    L5
L2:
  mov    $0x1,%edi
  call   <COLOR_PAIR@plt>
  mov    %rbp,%rdi
  mov    %eax,%esi
  call   <wattrset@plt>
  mov    $0x43,%ecx
  mov    $0x2,%edx
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <mvwaddch@plt>
  mov    %rbp,%rdi
  call   <wgetch@plt>
  mov    %rbp,%rdi
  call   <delwin@plt>
  xor    %eax,%eax
  call   <endwin@plt>
  add    $0x8,%rsp
  xor    %edi,%edi
  pop    %rbx
  pop    %rbp
  jmp    11d0 <exit@plt>
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  call   <start_color@plt>
  mov    D8(%rip),%rbx
  mov    $0x1,%edi
  mov    D9(%rip),%rax
  mov    (%rbx),%edx
  mov    (%rax),%esi
  call   <init_pair@plt>
  mov    D15(%rip),%rax
  mov    (%rbx),%edx
  mov    $0x2,%edi
  mov    (%rax),%esi
  call   <init_pair@plt>
  mov    D31(%rip),%rax
  mov    (%rbx),%edx
  mov    $0x3,%edi
  mov    (%rax),%esi
  call   <init_pair@plt>
  mov    D1(%rip),%rax
  mov    (%rbx),%edx
  mov    $0x4,%edi
  mov    (%rax),%esi
  call   <init_pair@plt>
  jmp    L2
```

assistant: ```c
void startGame() {
  chtype pacman = 'C';
  chtype food = 248;
  chtype monster = 232;
  chtype wall = 176;
  WINDOW *win = newwin(0, 0, 0, 0);
  wrefresh(win);
  box(win, 0, 0);
  wrefresh(win);
  if (has_colors()) {
    start_color();
    init_pair(1, COLOR_YELLOW, COLOR_BLACK);
    init_pair(2, COLOR_GREEN, COLOR_BLACK);
    init_pair(3, COLOR_CYAN, COLOR_BLACK);
    init_pair(4, COLOR_WHITE, COLOR_BLACK);
  }
  wattrset(win, COLOR_PAIR(1));
  mvwaddch(win, 2, 2, pacman);
  wgetch(win);
  delwin(win);
  endwin();
  exit(0);
}
```