ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<baud_from_num>:
  endbr64
  cmp    $0x70800,%edi
  je     L89
  jg     L105
  cmp    $0xe100,%edi
  je     L121
  jg     L96
  cmp    $0x4b00,%edi
  je     L63
  cmp    $0x9600,%edi
  jne    L51
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  ret
  xchg   %ax,%ax
L105:
  cmp    $0xe1000,%edi
  je     L52
  jle    L102
  cmp    $0xf4240,%edi
  je     L11
  cmp    $0x119400,%edi
  jne    L101
  mov    D59(%rip),%rax
  mov    (%rax),%eax
  ret
L51:
  cmp    $0x2580,%edi
  jne    L101
  mov    D114(%rip),%rax
  mov    (%rax),%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L96:
  cmp    $0x1c200,%edi
  je     L134
  cmp    $0x38400,%edi
  jne    L101
  mov    D97(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L102:
  cmp    $0x7a120,%edi
  je     L118
  cmp    $0x8ca00,%edi
  jne    L101
  mov    D84(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L89:
  mov    D19(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L121:
  mov    D49(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L63:
  mov    D80(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L52:
  mov    D55(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  mov    D102(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L134:
  mov    D56(%rip),%rax
  mov    (%rax),%eax
  ret
  nopw   0x0(%rax,%rax,1)
L118:
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  ret
L101:
  or     $0xffffffff,%eax
  ret
```

assistant: ```c
int baud_from_num(int baud_num) {
  switch (baud_num) {
  case 9600:
    return B9600;
  case 19200:
    return B19200;
  case 38400:
    return B38400;
  case 57600:
    return B57600;
  case 115200:
    return B115200;
  case 230400:
    return B230400;
  case 460800:
    return B460800;
  case 500000:
    return B500000;
  case 576000:
    return B576000;
  case 921600:
    return B921600;
  case 1000000:
    return B1000000;
  case 1152000:
    return B1152000;
  }
  return -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<llz_clip_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L24
  mov    -0x8(%rbp),%eax
  jmp    L13
L24:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L12
  mov    -0xc(%rbp),%eax
  jmp    L13
L12:
  mov    -0x4(%rbp),%eax
L13:
  pop    %rbp
  ret
```

assistant: ```c
int llz_clip_int(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<llz_clip_int>:
  endbr64
  cmp    %edx,%edi
  cmovle %edi,%edx
  cmp    %esi,%edi
  mov    %esi,%eax
  cmovge %edx,%eax
  ret
```

assistant: ```c
int llz_clip_int(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<llz_clip_int>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int llz_clip_int(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<llz_clip_int>:
  endbr64
  cmp    %edx,%edi
  mov    %esi,%eax
  cmovle %edi,%edx
  cmp    %esi,%edi
  cmovge %edx,%eax
  ret
```

assistant: ```c
int llz_clip_int(int a, int amin, int amax) {
  if (a < amin)
    return amin;
  else if (a > amax)
    return amax;
  else
    return a;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<float_to_uchar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  pxor   %xmm1,%xmm1
  cvtss2sd %xmm0,%xmm1
  movsd  D4(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0xc(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x8(%rbp),%rax
  add    %rcx,%rax
  mov    %dl,(%rax)
  addl   $0x1,-0xc(%rbp)
L19:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x20(%rbp)
  ja     L10
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D4
datatype: f64

tool: D4: 255

assistant: ```c
unsigned char *float_to_uchar(float *canal, size_t pixeles) {
  int i;
  unsigned char *output = (unsigned char *)malloc(sizeof(unsigned char) * pixeles);
  for (i = 0; i < pixeles; i++) {
    output[i] = (int)(canal[i] * 255.0);
  }
  return output;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<float_to_uchar>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %esi,%edi
  call   <malloc@plt>
  test   %rbx,%rbx
  je     L17
  mov    %rax,%rdx
  lea    (%rbx,%rax,1),%rsi
  mov    %rax,%rcx
  neg    %rcx
  lea    0x0(%rbp,%rcx,4),%rdi
  movsd  D7(%rip),%xmm1
L14:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi,%rdx,4),%xmm0
  mulsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%ecx
  mov    %cl,(%rdx)
  add    $0x1,%rdx
  cmp    %rsi,%rdx
  jne    L14
L17:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D7
data_type: f64

tool: D7: 255

assistant: ```c
unsigned char *float_to_uchar(float *canal, size_t pixeles) {
  int i;
  unsigned char *output = (unsigned char *)malloc(sizeof(unsigned char) * pixeles);
  for (i = 0; i < pixeles; i++) {
    output[i] = (int)(canal[i] * 255.0);
  }
  return output;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<float_to_uchar>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  mov    %esi,%edi
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  test   %rbx,%rbx
  je     L14
  mov    %rax,%rcx
  movsd  D3(%rip),%xmm1
  mov    %rax,%rdx
  lea    (%rbx,%rax,1),%rsi
  neg    %rcx
  lea    0x0(%rbp,%rcx,4),%rdi
  cs nopw 0x0(%rax,%rax,1)
L16:
  pxor   %xmm0,%xmm0
  cvtss2sd (%rdi,%rdx,4),%xmm0
  mulsd  %xmm1,%xmm0
  add    $0x1,%rdx
  cvttsd2si %xmm0,%ecx
  mov    %cl,-0x1(%rdx)
  cmp    %rdx,%rsi
  jne    L16
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D3
type_infered: f64

tool: D3: 255

assistant: ```c
unsigned char *float_to_uchar(float *canal, size_t pixeles) {
  int i;
  unsigned char *output = (unsigned char *)malloc(sizeof(unsigned char) * pixeles);
  for (i = 0; i < pixeles; i++) {
    output[i] = (int)(canal[i] * 255.0);
  }
  return output;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<prefix6zero>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%esi
  mov    -0x1c(%rbp),%eax
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%eax
  and    $0x7,%eax
  sub    %ecx,%eax
  mov    %eax,%ecx
  mov    $0x8,%eax
  sub    %ecx,%eax
  mov    $0x1,%edi
  mov    %eax,%ecx
  shl    %cl,%edi
  mov    %edi,%eax
  neg    %eax
  movzbl %al,%ecx
  movslq %edx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  and    %ecx,%esi
  mov    %esi,%edx
  mov    %edx,(%rax)
  mov    -0x1c(%rbp),%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L4
L15:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movl   $0x0,(%rax)
  addl   $0x1,-0x4(%rbp)
L4:
  cmpl   $0xf,-0x4(%rbp)
  jle    L15
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void prefix6zero(uint8_t *a, uint8_t prefix) {
  uint8_t i;
  a[prefix / 8] &= 0xff & ~((1 << (8 - (prefix % 8))) - 1);
  for (i = (prefix / 8) + 1; i < 16; i++)
    a[i] = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<prefix6zero>:
  endbr64
  mov    %rdi,%rdx
  lea    0x7(%rsi),%eax
  test   %esi,%esi
  cmovns %esi,%eax
  sar    $0x3,%eax
  movslq %eax,%rcx
  lea    (%rdi,%rcx,4),%rdi
  mov    %esi,%ecx
  sar    $0x1f,%ecx
  shr    $0x1d,%ecx
  add    %ecx,%esi
  and    $0x7,%esi
  sub    %esi,%ecx
  lea    0x8(%rcx),%ecx
  mov    $0xffffffff,%esi
  shl    %cl,%esi
  and    (%rdi),%esi
  and    $0xff,%esi
  mov    %esi,(%rdi)
  add    $0x1,%eax
  cmp    $0xf,%eax
  jg     L19
  cltq
L9:
  movl   $0x0,(%rdx,%rax,4)
  add    $0x1,%rax
  cmp    $0xf,%eax
  jle    L9
L19:
  ret
```

assistant: ```c
void prefix6zero(uint8_t *a, uint8_t prefix) {
  uint8_t i;
  a[prefix / 8] &= 0xff & ~((1 << (8 - (prefix % 8))) - 1);
  for (i = (prefix / 8) + 1; i < 16; i++)
    a[i] = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<prefix6zero>:
  endbr64
  mov    %esi,%eax
  lea    0x7(%rsi),%esi
  mov    %rdi,%r8
  test   %eax,%eax
  cmovns %eax,%esi
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ecx
  sar    $0x3,%esi
  and    $0x7,%ecx
  movslq %esi,%rdi
  sub    %ecx,%edx
  shl    $0x2,%rdi
  lea    (%r8,%rdi,1),%r9
  lea    0x8(%rdx),%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  and    (%r9),%edx
  and    $0xff,%edx
  mov    %edx,(%r9)
  cmp    $0x77,%eax
  jg     L9
  mov    $0xe,%eax
  lea    0x4(%r8,%rdi,1),%rdi
  sub    %esi,%eax
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void prefix6zero(uint8_t *a, uint8_t prefix) {
  uint8_t i;
  a[prefix / 8] &= 0xff & ~((1 << (8 - (prefix % 8))) - 1);
  for (i = (prefix / 8) + 1; i < 16; i++)
    a[i] = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<prefix6zero>:
  endbr64
  mov    %esi,%eax
  lea    0x7(%rsi),%esi
  mov    %rdi,%r8
  test   %eax,%eax
  cmovns %eax,%esi
  cltd
  shr    $0x1d,%edx
  lea    (%rax,%rdx,1),%ecx
  sar    $0x3,%esi
  and    $0x7,%ecx
  movslq %esi,%rdi
  sub    %ecx,%edx
  shl    $0x2,%rdi
  lea    (%r8,%rdi,1),%r9
  lea    0x8(%rdx),%ecx
  mov    $0xffffffff,%edx
  shl    %cl,%edx
  and    (%r9),%edx
  and    $0xff,%edx
  mov    %edx,(%r9)
  cmp    $0x77,%eax
  jg     L1
  mov    $0xe,%eax
  lea    0x4(%r8,%rdi,1),%rdi
  sub    %esi,%eax
  xor    %esi,%esi
  lea    0x4(,%rax,4),%rdx
  jmp    1050 <memset@plt>
  nopl   0x0(%rax)
L1:
  ret
```

assistant: ```c
void prefix6zero(uint8_t *a, uint8_t prefix) {
  uint8_t i;
  a[prefix / 8] &= 0xff & ~((1 << (8 - (prefix % 8))) - 1);
  for (i = (prefix / 8) + 1; i < 16; i++)
    a[i] = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hdr_quadratic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <commentln@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <codeln@plt>
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <codeln@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <codeln@plt>
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  call   <codeln@plt>
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <codeln@plt>
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  call   <codeln@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D39
datatype: string
name: unpack_data
arguments: data_tag: D7
datatype: string
name: unpack_data
arguments: data_tag: D30
datatype: string
name: unpack_data
arguments: data_tag: D12
datatype: string
name: unpack_data
arguments: data_tag: D62
datatype: string
name: unpack_data
arguments: data_tag: D49
datatype: string
name: unpack_data
arguments: data_tag: D63
datatype: string

tool: D39: Constants for the quadratic transfer function

tool: D7: static float q_Ts  = 0.0;

tool: D30: static float q_Tsi = 0.0;

tool: D12: static float q_Ta  = 0.0;

tool: D62: static float q_Tn  = 0.0;

tool: D49: static float q_Tni = 0.0;

tool: D63: static float q_Th  = 1.0;

assistant: ```c
void hdr_quadratic() {
  commentln("Constants for the quadratic transfer function");
  codeln("static float q_Ts  = 0.0;");
  codeln("static float q_Tsi = 0.0;");
  codeln("static float q_Ta  = 0.0;");
  codeln("static float q_Tn  = 0.0;");
  codeln("static float q_Tni = 0.0;");
  codeln("static float q_Th  = 1.0;");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<hdr_quadratic>:
  endbr64
  sub    $0x8,%rsp
  lea    D53(%rip),%rdi
  call   <commentln@plt>
  lea    D7(%rip),%rdi
  call   <codeln@plt>
  lea    D59(%rip),%rdi
  call   <codeln@plt>
  lea    D33(%rip),%rdi
  call   <codeln@plt>
  lea    D5(%rip),%rdi
  call   <codeln@plt>
  lea    D22(%rip),%rdi
  call   <codeln@plt>
  lea    D68(%rip),%rdi
  call   <codeln@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D53
type: string
name: extract_symbolic_data
arguments: tag: D7
type: string
name: extract_symbolic_data
arguments: tag: D59
type: string
name: extract_symbolic_data
arguments: tag: D33
type: string
name: extract_symbolic_data
arguments: tag: D5
type: string
name: extract_symbolic_data
arguments: tag: D22
type: string
name: extract_symbolic_data
arguments: tag: D68
type: string

tool: D53: Constants for the quadratic transfer function

tool: D7: static float q_Ts  = 0.0;

tool: D59: static float q_Tsi = 0.0;

tool: D33: static float q_Ta  = 0.0;

tool: D5: static float q_Tn  = 0.0;

tool: D22: static float q_Tni = 0.0;

tool: D68: static float q_Th  = 1.0;

assistant: ```c
void hdr_quadratic() {
  commentln("Constants for the quadratic transfer function");
  codeln("static float q_Ts  = 0.0;");
  codeln("static float q_Tsi = 0.0;");
  codeln("static float q_Ta  = 0.0;");
  codeln("static float q_Tn  = 0.0;");
  codeln("static float q_Tni = 0.0;");
  codeln("static float q_Th  = 1.0;");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hdr_quadratic>:
  endbr64
  sub    $0x8,%rsp
  lea    D23(%rip),%rdi
  call   <commentln@plt>
  lea    D43(%rip),%rdi
  call   <codeln@plt>
  lea    D17(%rip),%rdi
  call   <codeln@plt>
  lea    D50(%rip),%rdi
  call   <codeln@plt>
  lea    D8(%rip),%rdi
  call   <codeln@plt>
  lea    D11(%rip),%rdi
  call   <codeln@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <codeln@plt>
```

tool_calls: name: parse_data
arguments: label: D23
type: string
name: parse_data
arguments: label: D43
type: string
name: parse_data
arguments: label: D17
type: string
name: parse_data
arguments: label: D50
type: string
name: parse_data
arguments: label: D8
type: string
name: parse_data
arguments: label: D11
type: string
name: parse_data
arguments: label: D14
type: string

tool: D23: Constants for the quadratic transfer function

tool: D43: static float q_Ts  = 0.0;

tool: D17: static float q_Tsi = 0.0;

tool: D50: static float q_Ta  = 0.0;

tool: D8: static float q_Tn  = 0.0;

tool: D11: static float q_Tni = 0.0;

tool: D14: static float q_Th  = 1.0;

assistant: ```c
void hdr_quadratic() {
  commentln("Constants for the quadratic transfer function");
  codeln("static float q_Ts  = 0.0;");
  codeln("static float q_Tsi = 0.0;");
  codeln("static float q_Ta  = 0.0;");
  codeln("static float q_Tn  = 0.0;");
  codeln("static float q_Tni = 0.0;");
  codeln("static float q_Th  = 1.0;");
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hdr_quadratic>:
  endbr64
  sub    $0x8,%rsp
  lea    D36(%rip),%rdi
  call   <commentln@plt>
  lea    D44(%rip),%rdi
  call   <codeln@plt>
  lea    D25(%rip),%rdi
  call   <codeln@plt>
  lea    D23(%rip),%rdi
  call   <codeln@plt>
  lea    D3(%rip),%rdi
  call   <codeln@plt>
  lea    D34(%rip),%rdi
  call   <codeln@plt>
  lea    D14(%rip),%rdi
  add    $0x8,%rsp
  jmp    1060 <codeln@plt>
```

tool_calls: name: read_data
arguments: label: D36
datatype: string
name: read_data
arguments: label: D44
datatype: string
name: read_data
arguments: label: D25
datatype: string
name: read_data
arguments: label: D23
datatype: string
name: read_data
arguments: label: D3
datatype: string
name: read_data
arguments: label: D34
datatype: string
name: read_data
arguments: label: D14
datatype: string

tool: D36: Constants for the quadratic transfer function

tool: D44: static float q_Ts  = 0.0;

tool: D25: static float q_Tsi = 0.0;

tool: D23: static float q_Ta  = 0.0;

tool: D3: static float q_Tn  = 0.0;

tool: D34: static float q_Tni = 0.0;

tool: D14: static float q_Th  = 1.0;

assistant: ```c
void hdr_quadratic() {
  commentln("Constants for the quadratic transfer function");
  codeln("static float q_Ts  = 0.0;");
  codeln("static float q_Tsi = 0.0;");
  codeln("static float q_Ta  = 0.0;");
  codeln("static float q_Tn  = 0.0;");
  codeln("static float q_Tni = 0.0;");
  codeln("static float q_Th  = 1.0;");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movq   $0x2,-0x10(%rbp)
  movq   $0x1,-0x8(%rbp)
  movl   $0x2,-0x14(%rbp)
  jmp    L15
L17:
  mov    -0x8(%rbp),%rax
  add    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  add    %rax,-0x8(%rbp)
  addl   $0x2,-0x14(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L15:
  cmpl   $0x64,-0x14(%rbp)
  jle    L17
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D2
type: string
name: parse_data
arguments: label: D21
type: string

tool: D25: 2

tool: D2: 1

tool: D21: %llu


assistant: ```c
int main() {
  printf("2\n");
  printf("1\n");
  unsigned long long int a, b;
  int i;
  a = 2;
  b = 1;
  i = 2;
  while (i <= 100) {
    a = a + b;
    b = b + a;
    i = i + 2;
    printf("%llu\n", a);
    printf("%llu\n", b);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  call   <puts@plt>
  lea    D13(%rip),%rdi
  call   <puts@plt>
  mov    $0x32,%r12d
  mov    $0x1,%ebp
  mov    $0x2,%ebx
  lea    D19(%rip),%r13
L1:
  add    %rbp,%rbx
  add    %rbx,%rbp
  mov    %rbx,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L1
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
data_type: string
name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D19
data_type: string

tool: D2: 2

tool: D13: 1

tool: D19: %llu


assistant: ```c
int main() {
  printf("2\n");
  printf("1\n");
  unsigned long long int a, b;
  int i;
  a = 2;
  b = 1;
  i = 2;
  while (i <= 100) {
    a = a + b;
    b = b + a;
    i = i + 2;
    printf("%llu\n", a);
    printf("%llu\n", b);
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r13
  lea    D6(%rip),%rdi
  lea    D29(%rip),%r13
  push   %r12
  mov    $0x32,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L9:
  add    %rbp,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    %rbx,%rbp
  mov    %rbx,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L9
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D6
data_type: string
name: disassemble_data
arguments: data_tag: D29
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string

tool: D6: 2

tool: D29: %llu


tool: D17: 1

assistant: ```c
int main() {
  printf("2\n");
  printf("1\n");
  unsigned long long int a, b;
  int i;
  a = 2;
  b = 1;
  i = 2;
  while (i <= 100) {
    a = a + b;
    b = b + a;
    i = i + 2;
    printf("%llu\n", a);
    printf("%llu\n", b);
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r13
  lea    D17(%rip),%rdi
  lea    D23(%rip),%r13
  push   %r12
  mov    $0x32,%r12d
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  nopl   (%rax)
L2:
  add    %rbp,%rbx
  mov    %r13,%rdi
  xor    %eax,%eax
  add    %rbx,%rbp
  mov    %rbx,%rsi
  call   <printf@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <printf@plt>
  sub    $0x1,%r12d
  jne    L2
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D17
type_guessed: string
name: read_data
arguments: tag: D23
type_guessed: string
name: read_data
arguments: tag: D26
type_guessed: string

tool: D17: 2

tool: D23: %llu


tool: D26: 1

assistant: ```c
int main() {
  printf("2\n");
  printf("1\n");
  unsigned long long int a, b;
  int i;
  a = 2;
  b = 1;
  i = 2;
  while (i <= 100) {
    a = a + b;
    b = b + a;
    i = i + 2;
    printf("%llu\n", a);
    printf("%llu\n", b);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<maptype>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movsbl -0x14(%rbp),%eax
  cmp    $0x73,%eax
  je     L92
  cmp    $0x73,%eax
  jg     L35
  cmp    $0x70,%eax
  je     L19
  cmp    $0x70,%eax
  jg     L35
  cmp    $0x63,%eax
  je     L38
  cmp    $0x69,%eax
  je     L84
  jmp    L35
L92:
  lea    D5(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L84:
  lea    D21(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L19:
  lea    D0(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L38:
  lea    D9(%rip),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L83
L35:
  lea    D47(%rip),%rax
  mov    %rax,-0x8(%rbp)
  nop
L83:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D0
datatype: string
name: extract_symbolic_data
arguments: data_tag: D9
datatype: string
name: extract_symbolic_data
arguments: data_tag: D47
datatype: string

tool: D5: char *

tool: D21: int

tool: D0: int *

tool: D9: char

tool: 

assistant: ```c
char *maptype(char f) {
  char *mt;
  switch (f) {
  case 's':
    mt = "char *";
    break;
  case 'i':
    mt = "int";
    break;
  case 'p':
    mt = "int *";
    break;
  case 'c':
    mt = "char";
    break;
  default:
    mt = "";
    break;
  }
  return mt;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<maptype>:
  endbr64
  lea    D14(%rip),%rax
  cmp    $0x70,%dil
  je     L26
  jg     L10
  lea    D40(%rip),%rax
  cmp    $0x63,%dil
  je     L26
  cmp    $0x69,%dil
  lea    D33(%rip),%rax
  lea    D35(%rip),%rdx
  cmove  %rdx,%rax
  ret
L10:
  cmp    $0x73,%dil
  lea    D33(%rip),%rax
  lea    D50(%rip),%rdx
  cmove  %rdx,%rax
L26:
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D14
datatype: string
name: extract_symbolic_data
arguments: label: D40
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string
name: extract_symbolic_data
arguments: label: D35
datatype: string
name: extract_symbolic_data
arguments: label: D50
datatype: string

tool: D14: int *

tool: D40: char

tool: 

tool: D35: int

tool: D50: char *

assistant: ```c
char *maptype(char f) {
  char *mt;
  switch (f) {
  case 's':
    mt = "char *";
    break;
  case 'i':
    mt = "int";
    break;
  case 'p':
    mt = "int *";
    break;
  case 'c':
    mt = "char";
    break;
  default:
    mt = "";
    break;
  }
  return mt;
}
```