user: 这段汇编代码用C语言表示是什么样的：

```asm
<combine>:
  endbr64
  push   %r15
  mov    %rdx,%r11
  push   %r14
  mov    %rcx,%r14
  lea    -0x1(%rsi,%rsi,1),%ecx
  push   %r13
  mov    %r8,%r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  mov    $0xffffffff,%esi
  push   %rbx
  add    %edi,%ebp
  add    %ebp,%ebp
  lea    -0x1(%rbp),%r15d
  sub    $0x28,%rsp
  lea    0x0(,%r15,4),%r12d
  mov    %r9,(%rsp)
  mov    %r12d,%edx
  lea    (%rdi,%rdi,1),%r9d
  mov    %edi,0xc(%rsp)
  mov    %r11,%rdi
  lea    -0x1(%r9),%ebx
  mov    %r9d,0x14(%rsp)
  mov    %ecx,0x10(%rsp)
  mov    %r11,0x18(%rsp)
  call   <memset@plt>
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %r14,%rdi
  call   <memset@plt>
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    %r13,%rdi
  call   <memset@plt>
  mov    (%rsp),%rdi
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  call   <memset@plt>
  mov    0x60(%rsp),%rdi
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  call   <memset@plt>
  test   %r15d,%r15d
  movslq 0xc(%rsp),%r10
  mov    0x10(%rsp),%ecx
  movslq 0x14(%rsp),%r9
  jle    L6
  mov    0x18(%rsp),%r11
  lea    -0x2(%rbp),%esi
  xor    %eax,%eax
  jmp    L118
  nopl   0x0(%rax)
L128:
  mov    %rdx,%rax
L118:
  cmp    %eax,%ebx
  jle    L1
  mov    %eax,(%r11,%rax,4)
L1:
  lea    0x1(%rax),%rdx
  cmp    %rsi,%rax
  jne    L128
L6:
  cmp    %r15d,%r10d
  jge    L44
  mov    %ebp,%eax
  sub    %r10d,%eax
  shl    $0x2,%r10
  lea    -0x2(%rax),%edx
  add    %r10,%r14
  xor    %eax,%eax
  jmp    L66
  nopl   0x0(%rax)
L37:
  mov    %rsi,%rax
L66:
  cmp    %eax,%ecx
  jle    L4
  mov    %eax,(%r14,%rax,4)
L4:
  lea    0x1(%rax),%rsi
  cmp    %rdx,%rax
  jne    L37
  add    %r10,%r13
  xor    %eax,%eax
  jmp    L96
  nopl   0x0(%rax,%rax,1)
L161:
  mov    %rsi,%rax
L96:
  cmp    %eax,%ebx
  jle    L20
  mov    %eax,0x0(%r13,%rax,4)
L20:
  lea    0x1(%rax),%rsi
  cmp    %rdx,%rax
  jne    L161
  mov    (%rsp),%r12
  xor    %eax,%eax
  add    %r10,%r12
  jmp    L36
  nopl   0x0(%rax,%rax,1)
L148:
  mov    %rsi,%rax
L36:
  cmp    %eax,%ebx
  jle    L24
  mov    %eax,(%r12,%rax,4)
L24:
  lea    0x1(%rax),%rsi
  cmp    %rdx,%rax
  jne    L148
L44:
  cmp    %r15d,%r9d
  jge    L76
  mov    0x60(%rsp),%rax
  sub    %r9d,%ebp
  sub    $0x2,%ebp
  lea    (%rax,%r9,4),%rsi
  xor    %eax,%eax
  jmp    L86
  nopl   0x0(%rax)
L106:
  mov    %rdx,%rax
L86:
  cmp    %eax,%ecx
  jle    L102
  mov    %eax,(%rsi,%rax,4)
L102:
  lea    0x1(%rax),%rdx
  cmp    %rax,%rbp
  jne    L106
L76:
  add    $0x28,%rsp
  mov    %r15d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int combine(int ml, int mh, unsigned int *p1, unsigned int *p2, unsigned int *p3, unsigned int *p4, unsigned int *p5) {
  int m;
  int mlp, mhp, mp;
  int i, j;
  int total_xor = 0, xori;
  ;
  m = ml + mh;
  if (ml == mh) {
  } else {
  }
  mlp = 2 * ml - 1;
  mhp = 2 * mh - 1;
  mp = 2 * m - 1;
  memset(p1, 0xFFFFFFFF, mp * sizeof(unsigned int));
  memset(p2, 0xFFFFFFFF, mp * sizeof(unsigned int));
  memset(p3, 0xFFFFFFFF, mp * sizeof(unsigned int));
  memset(p4, 0xFFFFFFFF, mp * sizeof(unsigned int));
  memset(p5, 0xFFFFFFFF, mp * sizeof(unsigned int));
  for (i = 0; i < mp; ++i) {
    if (i < mlp) {
      p1[i] = i;
    }
  }
  for (i = ml, j = 0; i < mp; ++i, j++) {
    if (j < mhp) {
      p2[i] = j;
    }
  }
  for (i = ml, j = 0; i < mp; ++i, j++) {
    if (j < mlp) {
      p3[i] = j;
    }
  }
  for (i = ml, j = 0; i < mp; ++i, j++) {
    if (j < mlp) {
      p4[i] = j;
    }
  }
  for (i = 2 * ml, j = 0; i < mp; ++i, ++j) {
    if (j < mhp) {
      p5[i] = j;
    }
  }
  return mp;
}
```