ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_bigendian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_bigendian() {
  union {
    long l;
    char c[sizeof(long)];
  } u;
  u.l = 1;
  return (u.c[sizeof(long) - 1] == 1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_bigendian>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int is_bigendian() {
  union {
    long l;
    char c[sizeof(long)];
  } u;
  u.l = 1;
  return (u.c[sizeof(long) - 1] == 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<read_tiff_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
read_tiff_header(file_name, image_header) char file_name[];
struct tiff_header_struct *image_header;
{
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_tiff_header>:
  endbr64
  ret
```

assistant: ```c
read_tiff_header(file_name, image_header) char file_name[];
struct tiff_header_struct *image_header;
{
}
```
user: What is the c source code of the assembly code below:

```asm
<read_tiff_header>:
  endbr64
  ret
```

assistant: ```c
read_tiff_header(file_name, image_header) char file_name[];
struct tiff_header_struct *image_header;
{
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<read_tiff_header>:
  endbr64
  ret
```

assistant: ```c
read_tiff_header(file_name, image_header) char file_name[];
struct tiff_header_struct *image_header;
{
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<writeline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L24
L26:
  mov    -0x8(%rbp),%eax
  cltq
  mov    -0xc(%rbp),%edx
  movslq %edx,%rdx
  sub    %rdx,%rax
  mov    %rax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0xc(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L35
  mov    $0xffffffff,%eax
  jmp    L22
L35:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0xc(%rbp)
L24:
  cmpl   $0x0,-0xc(%rbp)
  jne    L26
  mov    $0x0,%eax
L22:
  leave
  ret
```

assistant: ```c
int writeline(int s, char *buff) {
  int r;
  int clen;
  int size;
  clen = strlen(buff);
  size = clen;
  while (size) {
    r = write(s, buff + clen - size, size);
    if (r == -1) {
      return (-1);
    }
    size -= r;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<writeline>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rsi,%rdi
  call   <strlen@plt>
  test   %eax,%eax
  je     L15
  mov    %eax,%ebx
  movslq %eax,%rbp
L22:
  movslq %ebx,%rax
  mov    %rbp,%rsi
  sub    %rax,%rsi
  add    %r12,%rsi
  mov    %ebx,%edx
  mov    %r13d,%edi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  je     L15
  sub    %eax,%ebx
  jne    L22
  mov    %ebx,%eax
L15:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int writeline(int s, char *buff) {
  int r;
  int clen;
  int size;
  clen = strlen(buff);
  size = clen;
  while (size) {
    r = write(s, buff + clen - size, size);
    if (r == -1) {
      return (-1);
    }
    size -= r;
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<writeline>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebx
  cltq
  mov    %rax,%r13
  test   %ebx,%ebx
  jne    L18
  jmp    L25
  nopl   0x0(%rax)
L34:
  sub    %eax,%ebx
  je     L25
  movslq %ebx,%rax
L18:
  mov    %r13,%rsi
  mov    %ebx,%edx
  mov    %r12d,%edi
  sub    %rax,%rsi
  add    %rbp,%rsi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L34
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int writeline(int s, char *buff) {
  int r;
  int clen;
  int size;
  clen = strlen(buff);
  size = clen;
  while (size) {
    r = write(s, buff + clen - size, size);
    if (r == -1) {
      return (-1);
    }
    size -= r;
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<writeline>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%ebx
  cltq
  mov    %rax,%r13
  test   %ebx,%ebx
  jne    L5
  jmp    L11
  nopl   0x0(%rax)
L24:
  sub    %eax,%ebx
  je     L11
  movslq %ebx,%rax
L5:
  mov    %r13,%rsi
  mov    %ebx,%edx
  mov    %r12d,%edi
  sub    %rax,%rsi
  add    %rbp,%rsi
  call   <write@plt>
  cmp    $0xffffffff,%eax
  jne    L24
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int writeline(int s, char *buff) {
  int r;
  int clen;
  int size;
  clen = strlen(buff);
  size = clen;
  while (size) {
    r = write(s, buff + clen - size, size);
    if (r == -1) {
      return (-1);
    }
    size -= r;
  }
  return (0);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<terminate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0xf,%edi
  call   <clear_pin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_guessed: string

tool: D0: Shutting down...

assistant: ```c
void terminate(int signo) {
  puts("Shutting down...");
  clear_pin((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<terminate>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    $0xf,%edi
  call   <clear_pin@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D3: Shutting down...

assistant: ```c
void terminate(int signo) {
  puts("Shutting down...");
  clear_pin((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  exit(0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<terminate>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xf,%edi
  call   <clear_pin@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <exit@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string

tool: D6: Shutting down...

assistant: ```c
void terminate(int signo) {
  puts("Shutting down...");
  clear_pin((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  exit(0);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<terminate>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <puts@plt>
  mov    $0xf,%edi
  call   <clear_pin@plt>
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1080 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D6
type_guessed: string

tool: D6: Shutting down...

assistant: ```c
void terminate(int signo) {
  puts("Shutting down...");
  clear_pin((1 << 0) | (1 << 1) | (1 << 2) | (1 << 3));
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_var_test_bit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x14(%rbp),%edx
  bt     %edx,(%rax)
  sbb    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int sync_var_test_bit(int nr, const volatile unsigned long *addr) {
  int oldbit;
  __asm__ __volatile__("btl %2,%1\n\tsbbl %0,%0" : "=r"(oldbit) : "m"((*(volatile long *)addr)), "Ir"(nr));
  return oldbit;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<sync_var_test_bit>:
  endbr64
  bt     %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
int sync_var_test_bit(int nr, const volatile unsigned long *addr) {
  int oldbit;
  __asm__ __volatile__("btl %2,%1\n\tsbbl %0,%0" : "=r"(oldbit) : "m"((*(volatile long *)addr)), "Ir"(nr));
  return oldbit;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_var_test_bit>:
  endbr64
  bt     %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
int sync_var_test_bit(int nr, const volatile unsigned long *addr) {
  int oldbit;
  __asm__ __volatile__("btl %2,%1\n\tsbbl %0,%0" : "=r"(oldbit) : "m"((*(volatile long *)addr)), "Ir"(nr));
  return oldbit;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sync_var_test_bit>:
  endbr64
  bt     %edi,(%rsi)
  sbb    %eax,%eax
  ret
```

assistant: ```c
int sync_var_test_bit(int nr, const volatile unsigned long *addr) {
  int oldbit;
  __asm__ __volatile__("btl %2,%1\n\tsbbl %0,%0" : "=r"(oldbit) : "m"((*(volatile long *)addr)), "Ir"(nr));
  return oldbit;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<thread_fn2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
L0:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <sleep@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L0
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type: string

tool: D6: thread_fn2

assistant: ```c
void thread_fn2(void *data) {
  while (1) {
    sleep(1);
    printf("%s\n", __func__);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<thread_fn2>:
  endbr64
  push   %rbx
  lea    D5(%rip),%rbx
L6:
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L6
```

tool_calls: name: parse_data
arguments: label: D5
datatype: string

tool: D5: thread_fn2

assistant: ```c
void thread_fn2(void *data) {
  while (1) {
    sleep(1);
    printf("%s\n", __func__);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<thread_fn2>:
  endbr64
  push   %rbx
  lea    D6(%rip),%rbx
  nopl   0x0(%rax)
L9:
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L9
```

tool_calls: name: read_data
arguments: label: D6
type_guessed: string

tool: D6: thread_fn2

assistant: ```c
void thread_fn2(void *data) {
  while (1) {
    sleep(1);
    printf("%s\n", __func__);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<thread_fn2>:
  endbr64
  push   %rbx
  lea    D1(%rip),%rbx
  nopl   0x0(%rax)
L6:
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <sleep@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  jmp    L6
```

tool_calls: name: unpack_data
arguments: label: D1
datatype: string

tool: D1: thread_fn2

assistant: ```c
void thread_fn2(void *data) {
  while (1) {
    sleep(1);
    printf("%s\n", __func__);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf80,%rsp
  mov    %edi,-0x1f74(%rbp)
  mov    %rsi,-0x1f80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x1f64(%rbp),%rdx
  lea    -0x1f68(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movl   $0x0,-0x1f60(%rbp)
  jmp    L67
L1:
  lea    -0x1f50(%rbp),%rdx
  mov    -0x1f60(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1f60(%rbp)
L67:
  mov    -0x1f68(%rbp),%eax
  cmp    %eax,-0x1f60(%rbp)
  jl     L1
  movl   $0x0,-0x1f60(%rbp)
  jmp    L32
L60:
  lea    -0xfb0(%rbp),%rdx
  mov    -0x1f60(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  addl   $0x1,-0x1f60(%rbp)
L32:
  mov    -0x1f64(%rbp),%eax
  cmp    %eax,-0x1f60(%rbp)
  jl     L60
  mov    -0x1f50(%rbp),%eax
  mov    -0xfb0(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x1f58(%rbp)
  movl   $0x0,-0x1f60(%rbp)
  jmp    L6
L29:
  movl   $0x0,-0x1f5c(%rbp)
  jmp    L74
L68:
  mov    -0x1f60(%rbp),%eax
  cltq
  mov    -0x1f50(%rbp,%rax,4),%edx
  mov    -0x1f5c(%rbp),%eax
  cltq
  mov    -0xfb0(%rbp,%rax,4),%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x1f54(%rbp)
  mov    -0x1f54(%rbp),%eax
  cmp    -0x1f58(%rbp),%eax
  jge    L49
  mov    -0x1f54(%rbp),%eax
  mov    %eax,-0x1f58(%rbp)
L49:
  addl   $0x1,-0x1f5c(%rbp)
L74:
  mov    -0x1f64(%rbp),%eax
  cmp    %eax,-0x1f5c(%rbp)
  jl     L68
  addl   $0x1,-0x1f60(%rbp)
L6:
  mov    -0x1f68(%rbp),%eax
  cmp    %eax,-0x1f60(%rbp)
  jl     L29
  mov    -0x1f58(%rbp),%eax
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
datatype: string
name: extract_symbolic_data
arguments: data_label: D19
datatype: string
name: extract_symbolic_data
arguments: data_label: D0
datatype: string

tool: D17: %d%d

tool: D19: %d

tool: D0: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, j, m, n, f[1000], g[1000], tmp, min;
  scanf("%d%d", &m, &n);
  for (i = 0; i < m; i++)
    scanf("%d", &f[i]);
  for (i = 0; i < n; i++)
    scanf("%d", &g[i]);
  min = abs(f[0] - g[0]);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      tmp = abs(f[i] - g[j]);
      if (tmp < min)
        min = tmp;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    D28(%rip),%rdi
  call   <scanf@plt>
  cmpl   $0x0,0x8(%rsp)
  jle    L45
  lea    0x10(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L106:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L106
  mov    0xc(%rsp),%r10d
  test   %r10d,%r10d
  jle    L78
L49:
  lea    0xfb0(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D0(%rip),%r12
L111:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0xc(%rsp),%r10d
  add    $0x4,%rbp
  cmp    %ebx,%r10d
  jg     L111
L78:
  mov    0x10(%rsp),%eax
  sub    0xfb0(%rsp),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L63
  lea    0x10(%rsp),%r9
  lea    -0x1(%rax),%eax
  lea    0x14(%rsp,%rax,4),%r11
  lea    0xfb0(%rsp),%rbx
  lea    -0x1(%r10),%eax
  lea    0xfb4(%rsp,%rax,4),%r8
  jmp    L66
L31:
  mov    (%r9),%edi
  mov    %rbx,%rdx
L61:
  mov    %edi,%ecx
  sub    (%rdx),%ecx
  mov    %ecx,%eax
  neg    %eax
  cmovs  %ecx,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L61
L83:
  add    $0x4,%r9
  cmp    %r11,%r9
  je     L63
L66:
  test   %r10d,%r10d
  jg     L31
  jmp    L83
L45:
  cmpl   $0x0,0xc(%rsp)
  jg     L49
  mov    0x10(%rsp),%eax
  sub    0xfb0(%rsp),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
L63:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x1f60,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D28
datatype: string
name: retrieve_data
arguments: data_tag: D0
datatype: string
name: retrieve_data
arguments: data_tag: D8
datatype: string

tool: D28: %d%d

tool: D0: %d

tool: D8: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, j, m, n, f[1000], g[1000], tmp, min;
  scanf("%d%d", &m, &n);
  for (i = 0; i < m; i++)
    scanf("%d", &f[i]);
  for (i = 0; i < n; i++)
    scanf("%d", &g[i]);
  min = abs(f[0] - g[0]);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      tmp = abs(f[i] - g[j]);
      if (tmp < min)
        min = tmp;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  sub    $0xf60,%rsp
  lea    D2(%rip),%rdi
  lea    D7(%rip),%r12
  xor    %ebx,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x1f58(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  call   <scanf@plt>
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L105
  xchg   %ax,%ax
L73:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  add    $0x4,%rbp
  cmp    %ebx,0x8(%rsp)
  jg     L73
  mov    0xc(%rsp),%r10d
  test   %r10d,%r10d
  jle    L109
L47:
  lea    0xfb0(%rsp),%rbp
  xor    %ebx,%ebx
  xchg   %ax,%ax
L93:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <scanf@plt>
  mov    0xc(%rsp),%r10d
  add    $0x4,%rbp
  cmp    %ebx,%r10d
  jg     L93
L109:
  mov    0xfb0(%rsp),%r11d
  mov    0x10(%rsp),%eax
  sub    %r11d,%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  jle    L7
  sub    $0x1,%eax
  lea    0xfb4(%rsp),%rbp
  lea    0x10(%rsp),%r9
  lea    0x14(%rsp,%rax,4),%rbx
  lea    -0x1(%r10),%eax
  lea    0x0(%rbp,%rax,4),%r8
  nopw   0x0(%rax,%rax,1)
L63:
  test   %r10d,%r10d
  jle    L80
  mov    (%r9),%edi
  mov    %rbp,%rcx
  mov    %r11d,%eax
  jmp    L72
L92:
  mov    (%rcx),%eax
  add    $0x4,%rcx
L72:
  mov    %edi,%edx
  sub    %eax,%edx
  mov    %edx,%eax
  neg    %eax
  cmovs  %edx,%eax
  cmp    %eax,%esi
  cmovg  %eax,%esi
  cmp    %rcx,%r8
  jne    L92
L80:
  add    $0x4,%r9
  cmp    %rbx,%r9
  jne    L63
L7:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x1f58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L94
  add    $0x1f60,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L105:
  cmpl   $0x0,0xc(%rsp)
  jg     L47
  mov    0x10(%rsp),%eax
  sub    0xfb0(%rsp),%eax
  mov    %eax,%esi
  neg    %esi
  cmovs  %eax,%esi
  jmp    L7
L94:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D2
type_guessed: string
name: unpack_data
arguments: tag: D7
type_guessed: string
name: unpack_data
arguments: tag: D16
type_guessed: string

tool: D2: %d%d

tool: D7: %d

tool: D16: %d


assistant: ```c
int main(int argc, const char *argv[]) {
  int i, j, m, n, f[1000], g[1000], tmp, min;
  scanf("%d%d", &m, &n);
  for (i = 0; i < m; i++)
    scanf("%d", &f[i]);
  for (i = 0; i < n; i++)
    scanf("%d", &g[i]);
  min = abs(f[0] - g[0]);
  for (i = 0; i < m; i++) {
    for (j = 0; j < n; j++) {
      tmp = abs(f[i] - g[j]);
      if (tmp < min)
        min = tmp;
    }
  }
  printf("%d\n", min);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<LeftTurn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <orient2d@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double LeftTurn(const double a[2], const double b[2], const double c[2]) {
  extern double orient2d(double *, double *, double *);
  return orient2d((double *)a, (double *)b, (double *)c);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<LeftTurn>:
  endbr64
  sub    $0x8,%rsp
  call   <orient2d@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
double LeftTurn(const double a[2], const double b[2], const double c[2]) {
  extern double orient2d(double *, double *, double *);
  return orient2d((double *)a, (double *)b, (double *)c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<LeftTurn>:
  endbr64
  jmp    1050 <orient2d@plt>
```

assistant: ```c
double LeftTurn(const double a[2], const double b[2], const double c[2]) {
  extern double orient2d(double *, double *, double *);
  return orient2d((double *)a, (double *)b, (double *)c);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<LeftTurn>:
  endbr64
  jmp    1050 <orient2d@plt>
```

assistant: ```c
double LeftTurn(const double a[2], const double b[2], const double c[2]) {
  extern double orient2d(double *, double *, double *);
  return orient2d((double *)a, (double *)b, (double *)c);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<proxyLog>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L8
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L8:
  mov    -0xc8(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xb4(%rbp),%edx
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <internalProxyLog@plt>
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void proxyLog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  internalProxyLog(true, format, args);
  va_end(args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<proxyLog>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  mov    $0x0,%ebp
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    %ebp,%edx
  mov    %rbx,%rsi
  mov    $0x1,%edi
  call   <internalProxyLog@plt>
  mov    %ebp,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void proxyLog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  internalProxyLog(true, format, args);
  va_end(args);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<proxyLog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <internalProxyLog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void proxyLog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  internalProxyLog(true, format, args);
  va_end(args);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<proxyLog>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x8,%rsp
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    $0x1,%edi
  call   <internalProxyLog@plt>
  mov    %r12d,%edi
  call   <va_end@plt>
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void proxyLog(const char *format, ...) {
  va_list args;
  va_start(args, format);
  internalProxyLog(true, format, args);
  va_end(args);
}
```