ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_settings>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D31(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strcpy@plt>
  xor    %eax,%eax
  lea    D37(%rip),%rsi
  lea    D20(%rip),%rdi
  mov    %ax,(%r12)
  call   <fopen@plt>
  test   %rax,%rax
  je     L35
  mov    %rax,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <fgets@plt>
  test   %rax,%rax
  je     L35
  mov    %rbx,%rdi
  lea    0xe(%rsp),%r13
  call   <strlen@plt>
  mov    %rbp,%rdx
  mov    $0xa,%esi
  mov    %r13,%rdi
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  call   <fgets@plt>
  test   %rax,%rax
  je     L35
  lea    D17(%rip),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %r14,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %ax,(%r12)
  call   <fclose@plt>
L35:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D31
datatype: string
name: read_data
arguments: data_label: D37
datatype: string
name: read_data
arguments: data_label: D20
datatype: string
name: read_data
arguments: data_label: D17
datatype: string

tool: D31: logfile.log

tool: D37: r

tool: D20: settings

tool: D17: true

assistant: ```c
void get_settings(char LogFilename[], short *uselog) {
  FILE *settings_file = NULL;
  char uselogfile[10];
  strcpy(LogFilename, "logfile.log");
  *uselog = 0;
  if ((settings_file = fopen("settings", "r")) == NULL) {
    return;
  }
  if (fgets(LogFilename, 256, settings_file) == NULL) {
    return;
  }
  LogFilename[strlen(LogFilename) - 1] = '\0';
  if (fgets(uselogfile, sizeof(uselogfile), settings_file) == NULL) {
    return;
  }
  if (strncmp(uselogfile, "true", strlen("true")) == 0) {
    *uselog = 1;
  } else {
    *uselog = 0;
  }
  fclose(settings_file);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_settings>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  lea    D28(%rip),%rsi
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strcpy@plt>
  xor    %eax,%eax
  lea    D6(%rip),%rsi
  lea    D27(%rip),%rdi
  mov    %ax,(%r12)
  call   <fopen@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rdx
  mov    $0x100,%esi
  mov    %rbx,%rdi
  mov    %rax,%rbp
  call   <fgets@plt>
  test   %rax,%rax
  je     L17
  mov    %rbx,%rdi
  lea    0xe(%rsp),%r13
  call   <strlen@plt>
  mov    %rbp,%rdx
  mov    $0xa,%esi
  mov    %r13,%rdi
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  call   <fgets@plt>
  test   %rax,%rax
  je     L17
  lea    D38(%rip),%r14
  mov    %r14,%rdi
  call   <strlen@plt>
  mov    %r13,%rdi
  mov    %r14,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  mov    %rbp,%rdi
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %ax,(%r12)
  call   <fclose@plt>
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L16
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D28
type: string
name: read_data
arguments: tag: D6
type: string
name: read_data
arguments: tag: D27
type: string
name: read_data
arguments: tag: D38
type: string

tool: D28: logfile.log

tool: D6: r

tool: D27: settings

tool: D38: true

assistant: ```c
void get_settings(char LogFilename[], short *uselog) {
  FILE *settings_file = NULL;
  char uselogfile[10];
  strcpy(LogFilename, "logfile.log");
  *uselog = 0;
  if ((settings_file = fopen("settings", "r")) == NULL) {
    return;
  }
  if (fgets(LogFilename, 256, settings_file) == NULL) {
    return;
  }
  LogFilename[strlen(LogFilename) - 1] = '\0';
  if (fgets(uselogfile, sizeof(uselogfile), settings_file) == NULL) {
    return;
  }
  if (strncmp(uselogfile, "true", strlen("true")) == 0) {
    *uselog = 1;
  } else {
    *uselog = 0;
  }
  fclose(settings_file);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  nop
  pop    %rbp
  ret
```

assistant: ```c
void test3() {
  switch (0) {
  case 4:
    if (0) {
    case 6:;
    }
  default:;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3() {
  switch (0) {
  case 4:
    if (0) {
    case 6:;
    }
  default:;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3() {
  switch (0) {
  case 4:
    if (0) {
    case 6:;
    }
  default:;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<test3>:
  endbr64
  ret
```

assistant: ```c
void test3() {
  switch (0) {
  case 4:
    if (0) {
    case 6:;
    }
  default:;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<charToHex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x2f,-0x4(%rbp)
  jle    L28
  cmpb   $0x39,-0x4(%rbp)
  jg     L28
  movsbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L21
L28:
  movsbl -0x4(%rbp),%eax
  sub    $0x57,%eax
L21:
  pop    %rbp
  ret
```

assistant: ```c
int charToHex(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else {
    return c - 'a' + 10;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<charToHex>:
  endbr64
  lea    -0x30(%rdi),%eax
  cmp    $0x9,%al
  ja     L6
  movsbl %dil,%edi
  lea    -0x30(%rdi),%eax
  ret
L6:
  movsbl %dil,%edi
  lea    -0x57(%rdi),%eax
  ret
```

assistant: ```c
int charToHex(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else {
    return c - 'a' + 10;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<charToHex>:
  endbr64
  lea    -0x30(%rdi),%edx
  movsbl %dil,%eax
  movsbl %dl,%ecx
  sub    $0x57,%eax
  cmp    $0x9,%dl
  cmovbe %ecx,%eax
  ret
```

assistant: ```c
int charToHex(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else {
    return c - 'a' + 10;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<charToHex>:
  endbr64
  lea    -0x30(%rdi),%edx
  movsbl %dil,%eax
  movsbl %dl,%ecx
  sub    $0x57,%eax
  cmp    $0x9,%dl
  cmovbe %ecx,%eax
  ret
```

assistant: ```c
int charToHex(char c) {
  if (c >= '0' && c <= '9') {
    return c - '0';
  } else {
    return c - 'a' + 10;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  jmp    L27
L22:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putc@plt>
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L0
  mov    $0xd,%edi
  call   <putc@plt>
L0:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L22
  nop
  nop
  leave
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s);
    if (*s == '\n')
      putc('\r');
    s++;
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  jne    L39
L22:
  pop    %rbx
  ret
L31:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L22
L39:
  movsbl %dil,%edi
  call   <putc@plt>
  cmpb   $0xa,(%rbx)
  jne    L31
  mov    $0xd,%edi
  call   <putc@plt>
  jmp    L31
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s);
    if (*s == '\n')
      putc('\r');
    s++;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L23
  jmp    L41
  nopw   0x0(%rax,%rax,1)
L8:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L41
L23:
  call   <putc@plt>
  cmpb   $0xa,(%rbx)
  jne    L8
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <putc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L23
L41:
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s);
    if (*s == '\n')
      putc('\r');
    s++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L5
L24:
  call   <putc@plt>
  cmpb   $0xa,(%rbx)
  je     L39
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L24
L5:
  pop    %rbx
  ret
  nopl   0x0(%rax)
L39:
  mov    $0xd,%edi
  add    $0x1,%rbx
  call   <putc@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L24
  pop    %rbx
  ret
```

assistant: ```c
void puts(const char *s) {
  while (*s) {
    putc(*s);
    if (*s == '\n')
      putc('\r');
    s++;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<gen_umod>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <gen_udiv@plt>
  mov    $0x0,%eax
  call   <gen_swap@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void gen_umod(void) {
  gen_udiv();
  gen_swap();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<gen_umod>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <gen_udiv@plt>
  mov    $0x0,%eax
  call   <gen_swap@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void gen_umod(void) {
  gen_udiv();
  gen_swap();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_umod>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gen_udiv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <gen_swap@plt>
```

assistant: ```c
void gen_umod(void) {
  gen_udiv();
  gen_swap();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<gen_umod>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <gen_udiv@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <gen_swap@plt>
```

assistant: ```c
void gen_umod(void) {
  gen_udiv();
  gen_swap();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<Move>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <push@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <merge@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <push@plt>
  nop
  leave
  ret
```

assistant: ```c
void Move(int d) {
  push(d);
  merge(d);
  push(d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Move>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  call   <push@plt>
  mov    %ebx,%edi
  call   <merge@plt>
  mov    %ebx,%edi
  call   <push@plt>
  pop    %rbx
  ret
```

assistant: ```c
void Move(int d) {
  push(d);
  merge(d);
  push(d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Move>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <push@plt>
  mov    %ebp,%edi
  call   <merge@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <push@plt>
```

assistant: ```c
void Move(int d) {
  push(d);
  merge(d);
  push(d);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<Move>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  call   <push@plt>
  mov    %ebp,%edi
  call   <merge@plt>
  mov    %ebp,%edi
  pop    %rbp
  jmp    1070 <push@plt>
```

assistant: ```c
void Move(int d) {
  push(d);
  merge(d);
  push(d);
}
```
user: Translate the below assembly code into C programming language:

```asm
<numReales>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  D21(%rip),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  lea    D60(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D21
type_infered: f32
name: disassemble_data
arguments: data_tag: D43
type_infered: string
name: disassemble_data
arguments: data_tag: D17
type_infered: string
name: disassemble_data
arguments: data_tag: D59
type_infered: string
name: disassemble_data
arguments: data_tag: D37
type_infered: string
name: disassemble_data
arguments: data_tag: D66
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D60
type_infered: string

tool: D21: 12.56

tool: D43: El valor de x es: %f


tool: D17:  pero lo podemos escribir con 2 decimales: %5.2f


tool: D59:  o solo con uno %5.1f


tool: D37:  o con 7 cifras %7.1f


tool: D66:  o alineado a la izquierda %-7.1f


tool: D7:  o sin decimales %2.0f


tool: D60:  o solo con una cifra %1.0f


assistant: ```c
void numReales(void) {
  float x = 12.56;
  printf("El valor de x es: %f\n", x);
  printf(" pero lo podemos escribir con 2 decimales: %5.2f\n", x);
  printf(" o solo con uno %5.1f\n", x);
  printf(" o con 7 cifras %7.1f\n", x);
  printf(" o alineado a la izquierda %-7.1f\n", x);
  printf(" o sin decimales %2.0f\n", x);
  printf(" o solo con una cifra %1.0f\n", x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<numReales>:
  endbr64
  sub    $0x8,%rsp
  movss  D106(%rip),%xmm0
  lea    D99(%rip),%rdi
  call   <printf@plt>
  movss  D106(%rip),%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  movss  D106(%rip),%xmm0
  lea    D133(%rip),%rdi
  call   <printf@plt>
  movss  D106(%rip),%xmm0
  lea    D104(%rip),%rdi
  call   <printf@plt>
  movss  D106(%rip),%xmm0
  lea    D27(%rip),%rdi
  call   <printf@plt>
  movss  D106(%rip),%xmm0
  lea    D91(%rip),%rdi
  call   <printf@plt>
  movss  D106(%rip),%xmm0
  lea    D88(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D106
datatype: f32
name: retrieve_data
arguments: data_tag: D99
datatype: string
name: retrieve_data
arguments: data_tag: D5
datatype: string
name: retrieve_data
arguments: data_tag: D133
datatype: string
name: retrieve_data
arguments: data_tag: D104
datatype: string
name: retrieve_data
arguments: data_tag: D27
datatype: string
name: retrieve_data
arguments: data_tag: D91
datatype: string
name: retrieve_data
arguments: data_tag: D88
datatype: string

tool: D106: 12.56

tool: D99: El valor de x es: %f


tool: D5:  pero lo podemos escribir con 2 decimales: %5.2f


tool: D133:  o solo con uno %5.1f


tool: D104:  o con 7 cifras %7.1f


tool: D27:  o alineado a la izquierda %-7.1f


tool: D91:  o sin decimales %2.0f


tool: D88:  o solo con una cifra %1.0f


assistant: ```c
void numReales(void) {
  float x = 12.56;
  printf("El valor de x es: %f\n", x);
  printf(" pero lo podemos escribir con 2 decimales: %5.2f\n", x);
  printf(" o solo con uno %5.1f\n", x);
  printf(" o con 7 cifras %7.1f\n", x);
  printf(" o alineado a la izquierda %-7.1f\n", x);
  printf(" o sin decimales %2.0f\n", x);
  printf(" o solo con una cifra %1.0f\n", x);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<numReales>:
  endbr64
  sub    $0x8,%rsp
  movss  D97(%rip),%xmm0
  lea    D21(%rip),%rdi
  call   <printf@plt>
  movss  D97(%rip),%xmm0
  lea    D52(%rip),%rdi
  call   <printf@plt>
  movss  D97(%rip),%xmm0
  lea    D111(%rip),%rdi
  call   <printf@plt>
  movss  D97(%rip),%xmm0
  lea    D110(%rip),%rdi
  call   <printf@plt>
  movss  D97(%rip),%xmm0
  lea    D127(%rip),%rdi
  call   <printf@plt>
  movss  D97(%rip),%xmm0
  lea    D126(%rip),%rdi
  call   <printf@plt>
  movss  D97(%rip),%xmm0
  add    $0x8,%rsp
  lea    D50(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_label: D97
datatype: f32
name: parse_data
arguments: data_label: D21
datatype: string
name: parse_data
arguments: data_label: D52
datatype: string
name: parse_data
arguments: data_label: D111
datatype: string
name: parse_data
arguments: data_label: D110
datatype: string
name: parse_data
arguments: data_label: D127
datatype: string
name: parse_data
arguments: data_label: D126
datatype: string
name: parse_data
arguments: data_label: D50
datatype: string

tool: D97: 12.56

tool: D21: El valor de x es: %f


tool: D52:  pero lo podemos escribir con 2 decimales: %5.2f


tool: D111:  o solo con uno %5.1f


tool: D110:  o con 7 cifras %7.1f


tool: D127:  o alineado a la izquierda %-7.1f


tool: D126:  o sin decimales %2.0f


tool: D50:  o solo con una cifra %1.0f


assistant: ```c
void numReales(void) {
  float x = 12.56;
  printf("El valor de x es: %f\n", x);
  printf(" pero lo podemos escribir con 2 decimales: %5.2f\n", x);
  printf(" o solo con uno %5.1f\n", x);
  printf(" o con 7 cifras %7.1f\n", x);
  printf(" o alineado a la izquierda %-7.1f\n", x);
  printf(" o sin decimales %2.0f\n", x);
  printf(" o solo con una cifra %1.0f\n", x);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<numReales>:
  endbr64
  sub    $0x8,%rsp
  movss  D123(%rip),%xmm0
  lea    D49(%rip),%rdi
  call   <printf@plt>
  movss  D123(%rip),%xmm0
  lea    D108(%rip),%rdi
  call   <printf@plt>
  movss  D123(%rip),%xmm0
  lea    D33(%rip),%rdi
  call   <printf@plt>
  movss  D123(%rip),%xmm0
  lea    D97(%rip),%rdi
  call   <printf@plt>
  movss  D123(%rip),%xmm0
  lea    D21(%rip),%rdi
  call   <printf@plt>
  movss  D123(%rip),%xmm0
  lea    D88(%rip),%rdi
  call   <printf@plt>
  movss  D123(%rip),%xmm0
  add    $0x8,%rsp
  lea    D120(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D123
type_guessed: f32
name: retrieve_data
arguments: data_tag: D49
type_guessed: string
name: retrieve_data
arguments: data_tag: D108
type_guessed: string
name: retrieve_data
arguments: data_tag: D33
type_guessed: string
name: retrieve_data
arguments: data_tag: D97
type_guessed: string
name: retrieve_data
arguments: data_tag: D21
type_guessed: string
name: retrieve_data
arguments: data_tag: D88
type_guessed: string
name: retrieve_data
arguments: data_tag: D120
type_guessed: string

tool: D123: 12.56

tool: D49: El valor de x es: %f


tool: D108:  pero lo podemos escribir con 2 decimales: %5.2f


tool: D33:  o solo con uno %5.1f


tool: D97:  o con 7 cifras %7.1f


tool: D21:  o alineado a la izquierda %-7.1f


tool: D88:  o sin decimales %2.0f


tool: D120:  o solo con una cifra %1.0f


assistant: ```c
void numReales(void) {
  float x = 12.56;
  printf("El valor de x es: %f\n", x);
  printf(" pero lo podemos escribir con 2 decimales: %5.2f\n", x);
  printf(" o solo con uno %5.1f\n", x);
  printf(" o con 7 cifras %7.1f\n", x);
  printf(" o alineado a la izquierda %-7.1f\n", x);
  printf(" o sin decimales %2.0f\n", x);
  printf(" o solo con una cifra %1.0f\n", x);
}
```
user: Translate the below assembly code into C programming language:

```asm
<replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r15
  mov    %rdx,%rbx
  mov    %rdx,0x8(%rsp)
  call   <strstr@plt>
  test   %rax,%rax
  jne    L2
L55:
  mov    %r13,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L2:
  mov    %rax,%rbp
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,0x14(%rsp)
  mov    %r15,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,0x18(%rsp)
  mov    %r13,%rdi
  call   <strlen@plt>
  sub    %r13d,%ebp
  sub    %ebx,%eax
  mov    %eax,0x1c(%rsp)
  js     L5
  mov    $0x0,%r14d
  mov    $0x0,%ebx
  jmp    L58
L69:
  sub    %r13d,%ebp
  cmp    %ebx,0x1c(%rsp)
  jl     L14
L58:
  mov    %ebp,%r12d
  sub    %ebx,%r12d
  movslq %ebx,%rsi
  add    %r13,%rsi
  movslq %r14d,%rdi
  lea    D15(%rip),%rbx
  add    %rbx,%rdi
  mov    %r12d,%edx
  call   <strncpy@plt>
  add    %r12d,%r14d
  movslq %r14d,%rdi
  add    %rbx,%rdi
  mov    0x8(%rsp),%rsi
  call   <strcpy@plt>
  add    0x14(%rsp),%r14d
  mov    0x18(%rsp),%eax
  lea    (%rax,%rbp,1),%ebx
  movslq %ebx,%rdi
  add    %r13,%rdi
  mov    %r15,%rsi
  call   <strstr@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L69
L14:
  movslq %ebx,%rsi
  add    %r13,%rsi
  movslq %r14d,%rdi
  lea    D15(%rip),%r13
  add    %r13,%rdi
  call   <strcpy@plt>
  jmp    L55
L5:
  mov    $0x0,%r14d
  mov    $0x0,%ebx
  jmp    L14
```

assistant: ```c
char *replace(char *string, char *oldpiece, char *newpiece) {
  int str_index, newstr_index, oldpiece_index, end, new_len, old_len, cpy_len;
  char *c;
  static char newstring[10000];
  if ((c = (char *)strstr(string, oldpiece)) == NULL)
    return string;
  new_len = strlen(newpiece);
  old_len = strlen(oldpiece);
  end = strlen(string) - old_len;
  oldpiece_index = c - string;
  newstr_index = 0;
  str_index = 0;
  while (str_index <= end && c != NULL) {
    cpy_len = oldpiece_index - str_index;
    strncpy(newstring + newstr_index, string + str_index, cpy_len);
    newstr_index += cpy_len;
    str_index += cpy_len;
    strcpy(newstring + newstr_index, newpiece);
    newstr_index += new_len;
    str_index += old_len;
    if ((c = (char *)strstr(string + str_index, oldpiece)) != NULL)
      oldpiece_index = c - string;
  }
  strcpy(newstring + newstr_index, string + str_index);
  return newstring;
}
```