ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<DoPointerTest>:
  endbr64
  push   %r14
  pxor   %xmm0,%xmm0
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rdx,%rbp
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  movaps %xmm0,(%rsp)
  mov    %rbx,%rdi
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  movaps %xmm0,0x80(%rsp)
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xc0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  call   <_countof@plt>
  mov    %r13,%rdx
  mov    %r14,%rcx
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <sprintf_s@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  lea    0x1(%rax),%rdx
  call   <memcmp@plt>
  test   %rax,%rax
  jne    L9
L20:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x110,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  mov    %rbx,%r8
  mov    %r12,%rcx
  mov    %r13,%rdx
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <Fail@plt>
  jmp    L20
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D7: ERROR: failed to insert %s into "%s"
Expected "%s" got "%s".


assistant: ```c
void DoPointerTest(const char *formatstr, void *param, char *paramstr, const char *checkstr1) {
  char buf[256] = {0};
  sprintf_s(buf, _countof(buf), formatstr, param);
  if (memcmp(buf, checkstr1, strlen(checkstr1) + 1) != 0) {
    Fail("ERROR: failed to insert %s into \"%s\"\n"
         "Expected \"%s\" got \"%s\".\n",
         paramstr, formatstr, checkstr1, buf);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<permute>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jne    L18
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L0
L18:
  mov    -0x1c(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L17
L3:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    -0x20(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <permute>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <swap@plt>
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jle    L3
L0:
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D9
type: string

tool: D9: %s


assistant: ```c
void permute(char *a, int l, int r) {
  int i;
  if (l == r) {
    printf("%s\n", a);
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(a, l + 1, r);
      swap((a + l), (a + i));
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r14
  cmp    %edx,%esi
  je     L25
  mov    %esi,%r13d
  mov    %edx,%r12d
  jg     L19
  movslq %esi,%rbp
  add    %rdi,%rbp
  mov    %rbp,%rbx
  lea    0x1(%rsi),%r15d
L30:
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  mov    %r12d,%edx
  mov    %r15d,%esi
  mov    %r14,%rdi
  call   <permute>
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <swap@plt>
  add    $0x1,%rbx
  mov    %r13d,%eax
  sub    %ebp,%eax
  add    %ebx,%eax
  cmp    %eax,%r12d
  jge    L30
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  jmp    L19
```

tool_calls: name: read_data
arguments: data_tag: D2
type: string

tool: D2: %s


assistant: ```c
void permute(char *a, int l, int r) {
  int i;
  if (l == r) {
    printf("%s\n", a);
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(a, l + 1, r);
      swap((a + l), (a + i));
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<permute>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %edx,%esi
  je     L19
  jg     L21
  movslq %esi,%r12
  lea    0x1(%rsi),%r14d
  mov    %edx,%ebp
  add    %rdi,%r12
  sub    %r12d,%esi
  mov    %r12,%rbx
  mov    %esi,%r15d
L27:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <swap@plt>
  mov    %ebp,%edx
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <permute>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  lea    (%r15,%rbx,1),%eax
  cmp    %eax,%ebp
  jge    L27
L21:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  xchg   %ax,%ax
L19:
  add    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D2
datatype: string

tool: D2: %s


assistant: ```c
void permute(char *a, int l, int r) {
  int i;
  if (l == r) {
    printf("%s\n", a);
  } else {
    for (i = l; i <= r; i++) {
      swap((a + l), (a + i));
      permute(a, l + 1, r);
      swap((a + l), (a + i));
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test();
  test();
  test();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  call   <test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test();
  test();
  test();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  call   <test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  test();
  test();
  test();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x44(%rbp)
  movl   $0x0,-0x40(%rbp)
  movl   $0x9,-0x3c(%rbp)
  movl   $0x7,-0x38(%rbp)
  movl   $0x2,-0x34(%rbp)
  movl   $0x3,-0x30(%rbp)
  movl   $0x6,-0x2c(%rbp)
  movl   $0x8,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x4,-0x20(%rbp)
  movl   $0x5,-0x1c(%rbp)
  mov    $0xb,%edi
  call   <log@plt>
  mov    %eax,%ebx
  mov    $0x2,%edi
  call   <log@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,%edx
  lea    -0x40(%rbp),%rax
  mov    $0xa,%esi
  mov    %rax,%rdi
  call   <shellSort@plt>
  movl   $0x0,-0x44(%rbp)
  jmp    L4
L0:
  mov    -0x44(%rbp),%eax
  cltq
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x44(%rbp)
L4:
  cmpl   $0x9,-0x44(%rbp)
  jle    L0
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: %d 

assistant: ```c
int main() {
  int i = 0;
  int array[] = {0, 9, 7, 2, 3, 6, 8, 1, 4, 5};
  shellSort(array, 10, (int)log(10 + 1) / log(2));
  for (i = 0; i < 10; i++)
    printf("%d ", array[i]);
  printf("\n");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x0,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x7,0x8(%rsp)
  movl   $0x2,0xc(%rsp)
  movl   $0x3,0x10(%rsp)
  movl   $0x6,0x14(%rsp)
  movl   $0x8,0x18(%rsp)
  movl   $0x1,0x1c(%rsp)
  movl   $0x4,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  mov    $0xb,%edi
  call   <log@plt>
  mov    %eax,%ebx
  mov    $0x2,%edi
  call   <log@plt>
  mov    %eax,%ecx
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %rsp,%rbx
  mov    %eax,%edx
  mov    $0xa,%esi
  mov    %rbx,%rdi
  call   <shellSort@plt>
  lea    0x28(%rsp),%r12
  lea    D6(%rip),%rbp
L17:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r12,%rbx
  jne    L17
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D6
datatype: string

tool: D6: %d 

assistant: ```c
int main() {
  int i = 0;
  int array[] = {0, 9, 7, 2, 3, 6, 8, 1, 4, 5};
  shellSort(array, 10, (int)log(10 + 1) / log(2));
  for (i = 0; i < 10; i++)
    printf("%d ", array[i]);
  printf("\n");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edi
  push   %rbp
  lea    D0(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000000,%rax
  lea    0x28(%rsp),%r12
  mov    %rax,(%rsp)
  movabs $0x200000007,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x600000003,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x100000008,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x500000004,%rax
  mov    %rax,0x20(%rsp)
  call   <log@plt>
  mov    $0x2,%edi
  mov    %eax,%ebx
  call   <log@plt>
  mov    $0xa,%esi
  mov    %eax,%r8d
  mov    %ebx,%eax
  mov    %rsp,%rbx
  cltd
  mov    %rbx,%rdi
  idiv   %r8d
  mov    %eax,%edx
  call   <shellSort@plt>
  nopl   0x0(%rax)
L19:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %r12,%rbx
  jne    L19
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D0: %d 

assistant: ```c
int main() {
  int i = 0;
  int array[] = {0, 9, 7, 2, 3, 6, 8, 1, 4, 5};
  shellSort(array, 10, (int)log(10 + 1) / log(2));
  for (i = 0; i < 10; i++)
    printf("%d ", array[i]);
  printf("\n");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xb,%edi
  push   %rbp
  lea    D21(%rip),%rbp
  push   %rbx
  sub    $0x30,%rsp
  movdqa D3(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D24(%rip),%rax
  lea    0x28(%rsp),%r12
  movaps %xmm0,(%rsp)
  movdqa D12(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <log@plt>
  mov    $0x2,%edi
  mov    %eax,%ebx
  call   <log@plt>
  mov    $0xa,%esi
  mov    %eax,%r8d
  mov    %ebx,%eax
  mov    %rsp,%rbx
  cltd
  mov    %rbx,%rdi
  idiv   %r8d
  mov    %eax,%edx
  call   <shellSort@plt>
  xchg   %ax,%ax
L2:
  mov    (%rbx),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L2
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D21
data_type: string
name: read_data
arguments: tag: D3
data_type: byte[16]
name: read_data
arguments: tag: D24
data_type: byte[8]
name: read_data
arguments: tag: D12
data_type: byte[16]

tool: D21: %d 

tool: {"D3": [0x00,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: {"D24": [0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D12": [0x03,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x08,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int i = 0;
  int array[] = {0, 9, 7, 2, 3, 6, 8, 1, 4, 5};
  shellSort(array, 10, (int)log(10 + 1) / log(2));
  for (i = 0; i < 10; i++)
    printf("%d ", array[i]);
  printf("\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<src_int4_read>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x4,%edx
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
  movzbl -0xc(%rbp),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0xa(%rbp),%eax
  movzbl %al,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

assistant: ```c
void src_int4_read(FILE *fd, int *val) {
  unsigned char b[4];
  fread((char *)&b[0], (size_t)1, (size_t)4, fd);
  *val = 0;
  *val = (int)(((((b[0] << 8) + b[1]) << 8) + b[2]) << 8) + b[3];
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<src_int4_read>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  mov    $0x4,%edx
  mov    $0x1,%esi
  call   <fread@plt>
  movzbl 0x4(%rsp),%eax
  shl    $0x8,%eax
  movzbl 0x5(%rsp),%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x6(%rsp),%edx
  add    %edx,%eax
  shl    $0x8,%eax
  movzbl 0x7(%rsp),%edx
  add    %edx,%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x10,%rsp
  pop    %rbx
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void src_int4_read(FILE *fd, int *val) {
  unsigned char b[4];
  fread((char *)&b[0], (size_t)1, (size_t)4, fd);
  *val = 0;
  *val = (int)(((((b[0] << 8) + b[1]) << 8) + b[2]) << 8) + b[3];
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<src_int4_read>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    $0x4,%edx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  movzbl 0x4(%rsp),%eax
  movzbl 0x5(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x6(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x7(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void src_int4_read(FILE *fd, int *val) {
  unsigned char b[4];
  fread((char *)&b[0], (size_t)1, (size_t)4, fd);
  *val = 0;
  *val = (int)(((((b[0] << 8) + b[1]) << 8) + b[2]) << 8) + b[3];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<src_int4_read>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rbx
  mov    $0x4,%edx
  mov    $0x1,%esi
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <fread@plt>
  movzbl 0x4(%rsp),%eax
  movzbl 0x5(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x6(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  movzbl 0x7(%rsp),%edx
  shl    $0x8,%eax
  add    %edx,%eax
  mov    %eax,(%rbx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void src_int4_read(FILE *fd, int *val) {
  unsigned char b[4];
  fread((char *)&b[0], (size_t)1, (size_t)4, fd);
  *val = 0;
  *val = (int)(((((b[0] << 8) + b[1]) << 8) + b[2]) << 8) + b[3];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<setTimeIndex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %rdx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x18(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jne    L23
  movl   $0x4,-0x24(%rbp)
  jmp    L40
L23:
  subl   $0x1,-0x24(%rbp)
L40:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  imul   $0x3e8,%eax,%ecx
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  add    %eax,%ecx
  mov    -0x10(%rbp),%eax
  imul   $0x3e8,%eax,%esi
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%edi
  mov    %edx,%eax
  sub    %edi,%eax
  lea    (%rsi,%rax,1),%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cmp    $0x4,%eax
  jg     L34
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    %edx,(%rax)
  jmp    L20
L34:
  mov    -0x38(%rbp),%rax
  movl   $0x0,(%rax)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x48(%rbp),%rax
  add    %rdx,%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
L20:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

assistant: ```c
void setTimeIndex(int *index, struct timeval *position, double *result) {
  struct timeval tv2;
  gettimeofday(&tv2, NULL);
  int x = *index;
  if (x == 0) {
    x = 4;
  } else {
    x--;
  }
  struct timeval tv1 = position[x];
  double diff = (((tv2.tv_sec) * 1000 + (tv2.tv_usec) / 1000) - ((tv1.tv_sec) * 1000 + (tv1.tv_usec) / 1000));
  if (*index < 5) {
    position[*index] = tv2;
    result[*index] = diff;
    (*index)++;
  } else {
    (*index) = 0;
    position[*index] = tv2;
    result[*index] = diff;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<setTimeIndex>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    (%rbx),%eax
  test   %eax,%eax
  je     L8
  lea    -0x1(%rax),%edx
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,8),%r8
  imul   $0x3e8,(%rsp),%ecx
  mov    0x4(%rsp),%esi
  movslq %esi,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%esi
  sub    %esi,%edx
  add    %edx,%ecx
  imul   $0x3e8,(%r8),%edi
  mov    0x4(%r8),%esi
  movslq %esi,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdi,%rdx,1),%esi
  sub    %esi,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
  cmp    $0x4,%eax
  jle    L12
  movl   $0x0,(%rbx)
  mov    (%rsp),%rax
  mov    %rax,0x0(%rbp)
  movslq (%rbx),%rax
  movsd  %xmm0,(%r12,%rax,8)
  jmp    L4
L8:
  imul   $0x3e8,(%rsp),%ecx
  mov    0x4(%rsp),%esi
  movslq %esi,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%esi
  sub    %esi,%edx
  add    %edx,%ecx
  imul   $0x3e8,0x20(%rbp),%edi
  mov    0x24(%rbp),%esi
  movslq %esi,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdi,%rdx,1),%esi
  sub    %esi,%ecx
  pxor   %xmm0,%xmm0
  cvtsi2sd %ecx,%xmm0
L12:
  cltq
  mov    (%rsp),%rdx
  mov    %rdx,0x0(%rbp,%rax,8)
  movslq (%rbx),%rax
  movsd  %xmm0,(%r12,%rax,8)
  addl   $0x1,(%rbx)
L4:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void setTimeIndex(int *index, struct timeval *position, double *result) {
  struct timeval tv2;
  gettimeofday(&tv2, NULL);
  int x = *index;
  if (x == 0) {
    x = 4;
  } else {
    x--;
  }
  struct timeval tv1 = position[x];
  double diff = (((tv2.tv_sec) * 1000 + (tv2.tv_usec) / 1000) - ((tv1.tv_sec) * 1000 + (tv1.tv_usec) / 1000));
  if (*index < 5) {
    position[*index] = tv2;
    result[*index] = diff;
    (*index)++;
  } else {
    (*index) = 0;
    position[*index] = tv2;
    result[*index] = diff;
  }
}
```