ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L4
  cmp    $0x2,%edi
  je     L16
  mov    $0x1,%eax
  ret
L16:
  push   %rax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  pop    %rdx
  mov    %eax,%edi
  jmp    1060 <startServer@plt>
L4:
  mov    $0xfa0,%edi
  jmp    1060 <startServer@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port;
  if (argc < 2)
    port = 4000;
  else if (argc == 2)
    port = atoi(argv[1]);
  else
    return 1;
  return startServer(port);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  cmp    $0x1,%edi
  jle    L14
  cmp    $0x2,%edi
  je     L5
  mov    $0x1,%eax
  ret
L5:
  push   %rax
  mov    0x8(%rsi),%rdi
  call   <atoi@plt>
  pop    %rdx
  mov    %eax,%edi
  jmp    1060 <startServer@plt>
L14:
  mov    $0xfa0,%edi
  jmp    1060 <startServer@plt>
```

assistant: ```c
int main(int argc, char *argv[]) {
  int port;
  if (argc < 2)
    port = 4000;
  else if (argc == 2)
    port = atoi(argv[1]);
  else
    return 1;
  return startServer(port);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<timeval_clear>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <assert@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,0x8(%rax)
  nop
  leave
  ret
```

assistant: ```c
void timeval_clear(struct timeval *a) {
  assert(a);
  a->tv_sec = a->tv_usec = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timeval_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movq   $0x0,(%rbx)
  movq   $0x0,0x8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void timeval_clear(struct timeval *a) {
  assert(a);
  a->tv_sec = a->tv_usec = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<timeval_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  movq   $0x0,(%rbx)
  movq   $0x0,0x8(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void timeval_clear(struct timeval *a) {
  assert(a);
  a->tv_sec = a->tv_usec = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<timeval_clear>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <assert@plt>
  pxor   %xmm0,%xmm0
  movups %xmm0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void timeval_clear(struct timeval *a) {
  assert(a);
  a->tv_sec = a->tv_usec = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mouse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %ecx,-0x10(%rbp)
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L0
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glutGet@plt>
  mov    %eax,%ecx
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%esi
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <startMotion@plt>
  jmp    L4
L0:
  mov    D32(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x8(%rbp)
  jne    L4
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <glutGet@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <stopMotion@plt>
L4:
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  nop
  leave
  ret
```

assistant: ```c
void mouse(int button, int state, int x, int y) {
  if (state == GLUT_DOWN)
    startMotion(x, y, button, glutGet(GLUT_ELAPSED_TIME));
  else if (state == GLUT_UP)
    stopMotion(button, glutGet(GLUT_ELAPSED_TIME));
  glutPostRedisplay();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mouse>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    D16(%rip),%rax
  cmp    %esi,(%rax)
  je     L12
  mov    D38(%rip),%rax
  cmp    %esi,(%rax)
  je     L0
L9:
  mov    $0x0,%eax
  call   <glutPostRedisplay@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L12:
  mov    %edx,%r12d
  mov    %ecx,%ebp
  mov    D24(%rip),%rax
  mov    (%rax),%edi
  call   <glutGet@plt>
  mov    %eax,%ecx
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <startMotion@plt>
  jmp    L9
L0:
  mov    D24(%rip),%rax
  mov    (%rax),%edi
  call   <glutGet@plt>
  mov    %eax,%esi
  mov    %ebx,%edi
  call   <stopMotion@plt>
  jmp    L9
```

assistant: ```c
void mouse(int button, int state, int x, int y) {
  if (state == GLUT_DOWN)
    startMotion(x, y, button, glutGet(GLUT_ELAPSED_TIME));
  else if (state == GLUT_UP)
    stopMotion(button, glutGet(GLUT_ELAPSED_TIME));
  glutPostRedisplay();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mouse>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  mov    D10(%rip),%rdx
  cmp    %esi,(%rdx)
  je     L18
  mov    D33(%rip),%rdx
  cmp    %esi,(%rdx)
  je     L12
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glutPostRedisplay@plt>
L18:
  mov    D14(%rip),%rax
  mov    %ecx,%r12d
  mov    (%rax),%edi
  call   <glutGet@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ecx
  call   <startMotion@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glutPostRedisplay@plt>
  nopl   0x0(%rax)
L12:
  mov    D14(%rip),%rax
  mov    (%rax),%edi
  call   <glutGet@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <stopMotion@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glutPostRedisplay@plt>
```

assistant: ```c
void mouse(int button, int state, int x, int y) {
  if (state == GLUT_DOWN)
    startMotion(x, y, button, glutGet(GLUT_ELAPSED_TIME));
  else if (state == GLUT_UP)
    stopMotion(button, glutGet(GLUT_ELAPSED_TIME));
  glutPostRedisplay();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<mouse>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  mov    D11(%rip),%rdx
  cmp    %esi,(%rdx)
  je     L1
  mov    D31(%rip),%rdx
  cmp    %esi,(%rdx)
  je     L10
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glutPostRedisplay@plt>
L1:
  mov    D10(%rip),%rax
  mov    %ecx,%r12d
  mov    (%rax),%edi
  call   <glutGet@plt>
  mov    %r13d,%edx
  mov    %r12d,%esi
  mov    %ebp,%edi
  mov    %eax,%ecx
  call   <startMotion@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glutPostRedisplay@plt>
  nopl   0x0(%rax)
L10:
  mov    D10(%rip),%rax
  mov    (%rax),%edi
  call   <glutGet@plt>
  mov    %r13d,%edi
  mov    %eax,%esi
  call   <stopMotion@plt>
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  pop    %r13
  jmp    10b0 <glutPostRedisplay@plt>
```

assistant: ```c
void mouse(int button, int state, int x, int y) {
  if (state == GLUT_DOWN)
    startMotion(x, y, button, glutGet(GLUT_ELAPSED_TIME));
  else if (state == GLUT_UP)
    stopMotion(button, glutGet(GLUT_ELAPSED_TIME));
  glutPostRedisplay();
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ssock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    D0(%rip),%rcx
  mov    %rax,%rsi
  mov    $0x0,%edi
  call   <get_socket@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  je     L1
  mov    -0x4(%rbp),%eax
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <listen@plt>
  test   %rax,%rax
  jns    L1
  movl   $0xffffffff,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int ssock(int fam, char *port) {
  int s = get_socket(NULL, port, fam, &bind);
  if (s != -1 && listen(s, 3) < 0) {
    s = -1;
  }
  return s;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ssock>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  mov    D4(%rip),%rcx
  mov    $0x0,%edi
  call   <get_socket@plt>
  mov    %eax,%ebx
  cmp    $0xffffffff,%eax
  jne    L13
L9:
  mov    %ebx,%eax
  pop    %rbx
  ret
L13:
  mov    $0x3,%esi
  mov    %eax,%edi
  call   <listen@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovs  %eax,%ebx
  jmp    L9
```

assistant: ```c
int ssock(int fam, char *port) {
  int s = get_socket(NULL, port, fam, &bind);
  if (s != -1 && listen(s, 3) < 0) {
    s = -1;
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ssock>:
  endbr64
  push   %r12
  mov    D6(%rip),%rcx
  mov    %edi,%edx
  xor    %edi,%edi
  call   <get_socket@plt>
  cmp    $0xffffffff,%eax
  je     L12
  mov    $0x3,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <listen@plt>
  test   %rax,%rax
  js     L12
L27:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L12:
  mov    $0xffffffff,%r12d
  jmp    L27
```

assistant: ```c
int ssock(int fam, char *port) {
  int s = get_socket(NULL, port, fam, &bind);
  if (s != -1 && listen(s, 3) < 0) {
    s = -1;
  }
  return s;
}
```
user: What is the c source code of the assembly code below?

```asm
<ssock>:
  endbr64
  push   %r12
  mov    D1(%rip),%rcx
  mov    %edi,%edx
  xor    %edi,%edi
  call   <get_socket@plt>
  cmp    $0xffffffff,%eax
  je     L11
  mov    $0x3,%esi
  mov    %eax,%edi
  mov    %eax,%r12d
  call   <listen@plt>
  test   %rax,%rax
  js     L11
L0:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L11:
  mov    $0xffffffff,%r12d
  jmp    L0
```

assistant: ```c
int ssock(int fam, char *port) {
  int s = get_socket(NULL, port, fam, &bind);
  if (s != -1 && listen(s, 3) < 0) {
    s = -1;
  }
  return s;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<cdft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %rdx,-0x10(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  js     L14
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cftfsub@plt>
  jmp    L19
L14:
  mov    -0x10(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <cftbsub@plt>
L19:
  nop
  leave
  ret
```

assistant: ```c
void cdft(int n, int isgn, float *a) {
  void cftfsub(int n, float *a);
  void cftbsub(int n, float *a);
  if (isgn >= 0) {
    cftfsub(n, a);
  } else {
    cftbsub(n, a);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<cdft>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  mov    %rdx,%rsi
  test   %eax,%eax
  js     L3
  call   <cftfsub@plt>
L4:
  add    $0x8,%rsp
  ret
L3:
  call   <cftbsub@plt>
  jmp    L4
```

assistant: ```c
void cdft(int n, int isgn, float *a) {
  void cftfsub(int n, float *a);
  void cftbsub(int n, float *a);
  if (isgn >= 0) {
    cftfsub(n, a);
  } else {
    cftbsub(n, a);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cdft>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rsi
  test   %r8d,%r8d
  js     L5
  jmp    1070 <cftfsub@plt>
  nopl   0x0(%rax)
L5:
  jmp    1060 <cftbsub@plt>
```

assistant: ```c
void cdft(int n, int isgn, float *a) {
  void cftfsub(int n, float *a);
  void cftbsub(int n, float *a);
  if (isgn >= 0) {
    cftfsub(n, a);
  } else {
    cftbsub(n, a);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<cdft>:
  endbr64
  mov    %esi,%r8d
  mov    %rdx,%rsi
  test   %r8d,%r8d
  js     L9
  jmp    1070 <cftfsub@plt>
  nopl   0x0(%rax)
L9:
  jmp    1060 <cftbsub@plt>
```

assistant: ```c
void cdft(int n, int isgn, float *a) {
  void cftfsub(int n, float *a);
  void cftbsub(int n, float *a);
  if (isgn >= 0) {
    cftfsub(n, a);
  } else {
    cftbsub(n, a);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<private_get_line_from_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  movl   $0x0,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L105
L79:
  mov    -0x10(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  jl     L62
  addl   $0x50,-0x10(%rbp)
  mov    -0x10(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <xrealloc@plt>
  mov    %rax,-0x8(%rbp)
L62:
  mov    -0x14(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x14(%rbp)
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  cmpl   $0x0,-0xc(%rbp)
  jne    L19
  mov    -0x8(%rbp),%rax
  jmp    L94
L19:
  cmpl   $0x1,-0x2c(%rbp)
  jg     L105
  cmpl   $0xa,-0xc(%rbp)
  jne    L105
  cmpl   $0x0,-0x2c(%rbp)
  je     L67
  subl   $0x1,-0x14(%rbp)
  jmp    L67
L105:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0xc(%rbp)
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0xc(%rbp)
  jne    L79
  jmp    L34
L67:
  nop
L34:
  cmpq   $0x0,-0x8(%rbp)
  je     L125
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  je     L32
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L94
L32:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L125:
  mov    -0x8(%rbp),%rax
L94:
  leave
  ret
```

assistant: ```c
char *private_get_line_from_file(FILE *file, int c) {
  int ch;
  int idx = 0;
  char *linebuf = NULL;
  int linebufsz = 0;
  while ((ch = getc(file)) != EOF) {
    if (idx > linebufsz - 2) {
      linebuf = xrealloc(linebuf, linebufsz += (80));
    }
    linebuf[idx++] = (char)ch;
    if (!ch)
      return linebuf;
    if (c < 2 && ch == '\n') {
      if (c) {
        --idx;
      }
      break;
    }
  }
  if (linebuf) {
    if (ferror(file)) {
      free(linebuf);
      return NULL;
    }
    linebuf[idx] = 0;
  }
  return linebuf;
}
```
user: Translate the below assembly code into C programming language:

```asm
<private_get_line_from_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,0xc(%rsp)
  mov    $0x0,%ebp
  mov    $0x0,%r14d
  mov    $0x0,%r13d
L18:
  mov    %ebp,%r12d
  mov    %ebp,0x8(%rsp)
  mov    %r15,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D9(%rip),%rax
  cmp    %ebx,(%rax)
  je     L24
  lea    -0x1(%r14),%eax
  cmp    %ebp,%eax
  jle    L43
L34:
  add    $0x1,%r12d
  mov    %bl,0x0(%r13,%rbp,1)
  test   %ebx,%ebx
  je     L59
  add    $0x1,%rbp
  cmpl   $0x1,0xc(%rsp)
  jg     L18
  cmp    $0xa,%ebx
  jne    L18
  cmpl   $0x0,0xc(%rsp)
  cmovne 0x8(%rsp),%r12d
  mov    %r12d,0x8(%rsp)
L24:
  test   %r13,%r13
  je     L59
  mov    %r15,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L32
  movslq 0x8(%rsp),%rax
  movb   $0x0,0x0(%r13,%rax,1)
L59:
  mov    %r13,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  add    $0x50,%r14d
  mov    %r14d,%esi
  mov    %r13,%rdi
  call   <xrealloc@plt>
  mov    %rax,%r13
  jmp    L34
L32:
  mov    %r13,%rdi
  call   <free@plt>
  mov    $0x0,%r13d
  jmp    L59
```

assistant: ```c
char *private_get_line_from_file(FILE *file, int c) {
  int ch;
  int idx = 0;
  char *linebuf = NULL;
  int linebufsz = 0;
  while ((ch = getc(file)) != EOF) {
    if (idx > linebufsz - 2) {
      linebuf = xrealloc(linebuf, linebufsz += (80));
    }
    linebuf[idx++] = (char)ch;
    if (!ch)
      return linebuf;
    if (c < 2 && ch == '\n') {
      if (c) {
        --idx;
      }
      break;
    }
  }
  if (linebuf) {
    if (ferror(file)) {
      free(linebuf);
      return NULL;
    }
    linebuf[idx] = 0;
  }
  return linebuf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<private_get_line_from_file>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  nopl   0x0(%rax)
L22:
  mov    %r12,%rdi
  mov    %r13d,%ebx
  mov    %r13d,%r14d
  call   <getc@plt>
  mov    %eax,%edx
  mov    D1(%rip),%rax
  cmp    %edx,(%rax)
  je     L88
  lea    -0x1(%rbp),%eax
  cmp    %r13d,%eax
  jle    L73
L72:
  mov    %dl,(%r15,%r13,1)
  add    $0x1,%ebx
  test   %edx,%edx
  je     L14
  add    $0x1,%r13
  cmpl   $0x1,0x8(%rsp)
  jg     L22
  cmp    $0xa,%edx
  jne    L22
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  cmove  %ebx,%r14d
L88:
  test   %r15,%r15
  je     L14
  mov    %r12,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L12
  movslq %r14d,%r14
  movb   $0x0,(%r15,%r14,1)
L14:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L73:
  add    $0x50,%ebp
  mov    %r15,%rdi
  mov    %edx,0xc(%rsp)
  mov    %ebp,%esi
  call   <xrealloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rax,%r15
  jmp    L72
L12:
  mov    %r15,%rdi
  xor    %r15d,%r15d
  call   <free@plt>
  jmp    L14
```

assistant: ```c
char *private_get_line_from_file(FILE *file, int c) {
  int ch;
  int idx = 0;
  char *linebuf = NULL;
  int linebufsz = 0;
  while ((ch = getc(file)) != EOF) {
    if (idx > linebufsz - 2) {
      linebuf = xrealloc(linebuf, linebufsz += (80));
    }
    linebuf[idx++] = (char)ch;
    if (!ch)
      return linebuf;
    if (c < 2 && ch == '\n') {
      if (c) {
        --idx;
      }
      break;
    }
  }
  if (linebuf) {
    if (ferror(file)) {
      free(linebuf);
      return NULL;
    }
    linebuf[idx] = 0;
  }
  return linebuf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<private_get_line_from_file>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,0x8(%rsp)
  nopl   0x0(%rax)
L83:
  mov    %r12,%rdi
  mov    %r13d,%ebx
  mov    %r13d,%r14d
  call   <getc@plt>
  mov    %eax,%edx
  mov    D7(%rip),%rax
  cmp    %edx,(%rax)
  je     L37
  lea    -0x1(%rbp),%eax
  cmp    %r13d,%eax
  jle    L4
L8:
  mov    %dl,(%r15,%r13,1)
  add    $0x1,%ebx
  test   %edx,%edx
  je     L19
  add    $0x1,%r13
  cmpl   $0x1,0x8(%rsp)
  jg     L83
  cmp    $0xa,%edx
  jne    L83
  mov    0x8(%rsp),%eax
  test   %eax,%eax
  cmove  %ebx,%r14d
L37:
  test   %r15,%r15
  je     L19
  mov    %r12,%rdi
  call   <ferror@plt>
  test   %rax,%rax
  jne    L77
  movslq %r14d,%r14
  movb   $0x0,(%r15,%r14,1)
L19:
  add    $0x18,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L4:
  add    $0x50,%ebp
  mov    %r15,%rdi
  mov    %edx,0xc(%rsp)
  mov    %ebp,%esi
  call   <xrealloc@plt>
  mov    0xc(%rsp),%edx
  mov    %rax,%r15
  jmp    L8
L77:
  mov    %r15,%rdi
  xor    %r15d,%r15d
  call   <free@plt>
  jmp    L19
```

assistant: ```c
char *private_get_line_from_file(FILE *file, int c) {
  int ch;
  int idx = 0;
  char *linebuf = NULL;
  int linebufsz = 0;
  while ((ch = getc(file)) != EOF) {
    if (idx > linebufsz - 2) {
      linebuf = xrealloc(linebuf, linebufsz += (80));
    }
    linebuf[idx++] = (char)ch;
    if (!ch)
      return linebuf;
    if (c < 2 && ch == '\n') {
      if (c) {
        --idx;
      }
      break;
    }
  }
  if (linebuf) {
    if (ferror(file)) {
      free(linebuf);
      return NULL;
    }
    linebuf[idx] = 0;
  }
  return linebuf;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L13
L34:
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L47:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L31
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L31:
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x14(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jl     L47
  addl   $0x1,-0xc(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0xc(%rbp)
  jl     L34
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bubble_sort(int n, int *v) {
  int aux = 0;
  for (int i = 0; i < n - 1; i++) {
    for (int j = 0; j < n - i - 1; j++) {
      if (v[j] > v[j + 1]) {
        aux = v[j];
        v[j] = v[j + 1];
        v[j + 1] = aux;
      }
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rdi),%r8d
  test   %r8d,%r8d
  jle    L59
  lea    0x4(%rsi),%r9
  jmp    L36
L76:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L26
L56:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L76
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
  jmp    L76
L26:
  sub    $0x1,%r8d
  je     L59
L36:
  test   %r8d,%r8d
  jle    L26
  mov    %rsi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rdi
  jmp    L56
L59:
  ret
```

assistant: ```c
void bubble_sort(int n, int *v) {
  int aux = 0;
  for (int i = 0; i < n - 1; i++) {
    for (int j = 0; j < n - i - 1; j++) {
      if (v[j] > v[j + 1]) {
        aux = v[j];
        v[j] = v[j + 1];
        v[j + 1] = aux;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rdi),%edx
  test   %edx,%edx
  jle    L37
  lea    0x4(%rsi),%r9
  nop
L24:
  sub    $0x1,%edx
  mov    %rsi,%rax
  mov    %rdx,%r8
  lea    (%r9,%rdx,4),%rdi
  nopl   (%rax)
L21:
  mov    (%rax),%edx
  mov    0x4(%rax),%ecx
  cmp    %ecx,%edx
  jle    L33
  mov    %ecx,(%rax)
  mov    %edx,0x4(%rax)
L33:
  add    $0x4,%rax
  cmp    %rdi,%rax
  jne    L21
  mov    %r8d,%edx
  test   %r8d,%r8d
  jne    L24
L37:
  ret
```

assistant: ```c
void bubble_sort(int n, int *v) {
  int aux = 0;
  for (int i = 0; i < n - 1; i++) {
    for (int j = 0; j < n - i - 1; j++) {
      if (v[j] > v[j + 1]) {
        aux = v[j];
        v[j] = v[j + 1];
        v[j + 1] = aux;
      }
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubble_sort>:
  endbr64
  lea    -0x1(%rdi),%eax
  test   %eax,%eax
  jle    L14
  lea    0x4(%rsi),%r9
  nop
L4:
  sub    $0x1,%eax
  mov    %rsi,%rdx
  mov    %rax,%r8
  lea    (%r9,%rax,4),%rdi
  nopl   (%rax)
L9:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L16
  movq   %xmm1,(%rdx)
L16:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  jne    L9
  mov    %r8d,%eax
  test   %r8d,%r8d
  jne    L4
L14:
  ret
```

assistant: ```c
void bubble_sort(int n, int *v) {
  int aux = 0;
  for (int i = 0; i < n - 1; i++) {
    for (int j = 0; j < n - i - 1; j++) {
      if (v[j] > v[j + 1]) {
        aux = v[j];
        v[j] = v[j + 1];
        v[j + 1] = aux;
      }
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<grub_tolower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x40,-0x4(%rbp)
  jle    L12
  cmpl   $0x5a,-0x4(%rbp)
  jg     L12
  mov    -0x4(%rbp),%eax
  add    $0x20,%eax
  jmp    L1
L12:
  mov    -0x4(%rbp),%eax
L1:
  pop    %rbp
  ret
```

assistant: ```c
int grub_tolower(int c) {
  if (c >= 'A' && c <= 'Z') {
    return c - 'A' + 'a';
  }
  return c;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<grub_tolower>:
  endbr64
  mov    %edi,%eax
  lea    -0x41(%rdi),%ecx
  lea    0x20(%rdi),%edx
  cmp    $0x1a,%ecx
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int grub_tolower(int c) {
  if (c >= 'A' && c <= 'Z') {
    return c - 'A' + 'a';
  }
  return c;
}
```