user: Demonstrate the C code that generates the assembly output below:

```asm
<solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x3d000(%rsp),%r11
L2:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L2
  sub    $0x2c0,%rsp
  mov    %rdi,-0x3d2b8(%rbp)
  mov    %esi,-0x3d2bc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x3d2a0(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    $0x40,%ecx
  mov    %rax,%rdi
  mov    %rdx,%rsi
  rep movsq %ds:(%rsi),%es:(%rdi)
  movl   $0x0,-0x3d2a8(%rbp)
  movl   $0x0,-0x3d2a4(%rbp)
  lea    -0x3d0a0(%rbp),%rax
  mov    $0x3d091,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x3d2a8(%rbp)
  jmp    L56
L5:
  mov    -0x3d2a8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x3d2b8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  add    $0xf4240,%eax
  lea    0x7(%rax),%edx
  test   %eax,%eax
  cmovs  %edx,%eax
  sar    $0x3,%eax
  mov    %eax,%edx
  movslq %edx,%rax
  movzbl -0x3d0a0(%rbp,%rax,1),%eax
  mov    %eax,%edi
  mov    -0x3d2a8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x3d2b8(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  and    $0x7,%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    %esi,%eax
  or     %edi,%eax
  mov    %eax,%ecx
  movslq %edx,%rax
  mov    %cl,-0x3d0a0(%rbp,%rax,1)
  addl   $0x1,-0x3d2a8(%rbp)
L56:
  mov    -0x3d2a8(%rbp),%eax
  cmp    -0x3d2bc(%rbp),%eax
  jl     L5
  movl   $0x0,-0x3d2a8(%rbp)
  jmp    L29
L9:
  mov    -0x3d2a8(%rbp),%eax
  cltq
  movzbl -0x3d0a0(%rbp,%rax,1),%eax
  movzbl %al,%eax
  cltq
  movzwl -0x3d2a0(%rbp,%rax,2),%eax
  movzwl %ax,%eax
  add    %eax,-0x3d2a4(%rbp)
  addl   $0x1,-0x3d2a8(%rbp)
L29:
  cmpl   $0x3d090,-0x3d2a8(%rbp)
  jle    L9
  mov    -0x3d2a4(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L16
  call   <__stack_chk_fail@plt>
L16:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_guessed: string

tool: 

assistant: ```c
int solution(int A[], int N) {
  unsigned char appeared[2000001 / 8 + 1];
  unsigned short int onesInByte[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 4, 5, 5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8};
  int index = 0;
  int result = 0;
  memset(appeared, 0, 2000001 / 8 + 1);
  for (index = 0; index < N; ++index) {
    appeared[(A[index] + 1000000) / 8] |= (1 << (int)((A[index] + 1000000) % 8));
  }
  for (index = 0; index < 2000001 / 8 + 1; ++index) {
    result += onesInByte[appeared[index]];
  }
  return result;
}
```