user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<score_exact>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  mov    %rdx,-0x30(%rbp)
  movl   $0x64,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x28(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
  cmpl   $0x0,-0x24(%rbp)
  jle    L134
  mov    -0x24(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L45
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  add    %eax,-0x1c(%rbp)
  jmp    L36
L45:
  cmpl   $0x1,-0x28(%rbp)
  jne    L66
  mov    $0x0,%eax
  jmp    L84
L66:
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L61
L39:
  subl   $0x1,-0x18(%rbp)
L61:
  cmpl   $0x0,-0x18(%rbp)
  js     L135
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L39
L135:
  mov    -0x4(%rbp),%eax
  sub    -0x28(%rbp),%eax
  sub    -0x18(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L36:
  movl   $0x0,-0x14(%rbp)
  mov    -0x24(%rbp),%eax
  sub    $0x2,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L53
L91:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L38
  addl   $0x1,-0x14(%rbp)
L38:
  subl   $0x1,-0x10(%rbp)
L53:
  cmpl   $0x0,-0x10(%rbp)
  jns    L91
  mov    -0x14(%rbp),%eax
  sub    %eax,-0x1c(%rbp)
L134:
  movl   $0x0,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  sub    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L77
L47:
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%eax
  add    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  movslq %eax,%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L24
  addl   $0x1,-0xc(%rbp)
L24:
  subl   $0x1,-0x8(%rbp)
L77:
  cmpl   $0x0,-0x8(%rbp)
  jns    L47
  mov    -0xc(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  neg    %eax
  add    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x1,%edi
  call   <max@plt>
L84:
  leave
  ret
```

assistant: ```c
int score_exact(int match_index, int match_len, const char *value) {
  int score = 100, value_len = strlen(value);
  score -= (value_len - match_len);
  if (match_index > 0) {
    if (value[match_index - 1] == '.') {
      score += (match_index - 1);
    } else if (match_len == 1) {
      return 0;
    } else {
      int i = match_index - 2;
      while (i >= 0 && value[i] != '.')
        --i;
      score -= (match_index - i) + (value_len - match_len - match_index);
    }
    int separators = 0, i = match_index - 2;
    while (i >= 0) {
      if (value[i] == '.') {
        separators += 1;
      }
      i--;
    }
    score -= separators;
  }
  int separators = 0;
  int i = value_len - match_len - match_index - 1;
  while (i >= 0) {
    if (value[match_index + match_len + i] == '.') {
      separators += 1;
    }
    i--;
  }
  score -= separators * 5;
  return max(1, score);
}
```