ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rsi
  mov    $0x3e,%ecx
  sub    $0x270,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x268(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbp
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    (%rsi),%eax
  mov    $0x5,%esi
  mov    %eax,(%rdi)
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <select_movie@plt>
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rsi
  lea    0x200(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D37(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D29(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <bollywood_game@plt>
  mov    0x268(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x270,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D10
type: string
name: parse_data
arguments: tag: D12
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D37
type: string
name: parse_data
arguments: tag: D29
type: string

tool: D10: DON

tool: D12: 


			BOLLYWOOD


tool: D11: *****************************************************************************

tool: D37: 

		Rules : 

	1. You need to guess the movie by entering the letter and filling the missing letters.

	2. You have only 9 chances.

tool: D29: 

*****************************************************************************


assistant: ```c
int main() {
  int n, num;
  char movie_list[][100] = {"DON", "Om Shanti Om", "3 Idiots", "Mera Naam Joker", "Ready"};
  char text[100];
  n = 5;
  num = select_movie(movie_list, n);
  strcpy(text, movie_list[num]);
  printf("\n\n\n\t\t\tBOLLYWOOD\n\n");
  printf("*****************************************************************************");
  printf("\n\n\t\tRules : \n\n\t1. You need to guess the movie by entering the letter and filling the missing letters."
         "\n\n\t2. You have only 9 chances.");
  printf("\n\n*****************************************************************************\n\n");
  bollywood_game(text);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D30(%rip),%rsi
  mov    $0x3e,%ecx
  sub    $0x270,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x268(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rsp,%rbp
  rep movsq %ds:(%rsi),%es:(%rdi)
  mov    (%rsi),%eax
  mov    $0x5,%esi
  mov    %eax,(%rdi)
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <select_movie@plt>
  cltq
  lea    (%rax,%rax,4),%rax
  lea    (%rax,%rax,4),%rax
  lea    0x0(%rbp,%rax,4),%rsi
  lea    0x200(%rsp),%rbp
  mov    %rbp,%rdi
  call   <strcpy@plt>
  lea    D36(%rip),%rdi
  call   <puts@plt>
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    D26(%rip),%rdi
  call   <puts@plt>
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <bollywood_game@plt>
  mov    0x268(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x270,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D30
data_type: string
name: retrieve_data
arguments: label: D36
data_type: string
name: retrieve_data
arguments: label: D39
data_type: string
name: retrieve_data
arguments: label: D1
data_type: string
name: retrieve_data
arguments: label: D26
data_type: string

tool: D30: DON

tool: D36: 


			BOLLYWOOD


tool: D39: *****************************************************************************

tool: D1: 

		Rules : 

	1. You need to guess the movie by entering the letter and filling the missing letters.

	2. You have only 9 chances.

tool: D26: 

*****************************************************************************


assistant: ```c
int main() {
  int n, num;
  char movie_list[][100] = {"DON", "Om Shanti Om", "3 Idiots", "Mera Naam Joker", "Ready"};
  char text[100];
  n = 5;
  num = select_movie(movie_list, n);
  strcpy(text, movie_list[num]);
  printf("\n\n\n\t\t\tBOLLYWOOD\n\n");
  printf("*****************************************************************************");
  printf("\n\n\t\tRules : \n\n\t1. You need to guess the movie by entering the letter and filling the missing letters."
         "\n\n\t2. You have only 9 chances.");
  printf("\n\n*****************************************************************************\n\n");
  bollywood_game(text);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fungus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <niceprint@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type_guessed: string

tool: D0: The adventurers stumble upon a cavern filled with fungi and mushrooms of all sizes and types.



assistant: ```c
void fungus(void) {
  niceprint("The adventurers stumble upon a cavern filled with fungi and mushrooms "
            "of all sizes and types.\n\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fungus>:
  endbr64
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <niceprint@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D7
type_infered: string

tool: D7: The adventurers stumble upon a cavern filled with fungi and mushrooms of all sizes and types.



assistant: ```c
void fungus(void) {
  niceprint("The adventurers stumble upon a cavern filled with fungi and mushrooms "
            "of all sizes and types.\n\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fungus>:
  endbr64
  lea    D6(%rip),%rdi
  jmp    1050 <niceprint@plt>
```

tool_calls: name: parse_data
arguments: tag: D6
type_guessed: string

tool: D6: The adventurers stumble upon a cavern filled with fungi and mushrooms of all sizes and types.



assistant: ```c
void fungus(void) {
  niceprint("The adventurers stumble upon a cavern filled with fungi and mushrooms "
            "of all sizes and types.\n\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fungus>:
  endbr64
  lea    D5(%rip),%rdi
  jmp    1050 <niceprint@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
datatype: string

tool: D5: The adventurers stumble upon a cavern filled with fungi and mushrooms of all sizes and types.



assistant: ```c
void fungus(void) {
  niceprint("The adventurers stumble upon a cavern filled with fungi and mushrooms "
            "of all sizes and types.\n\n");
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L50
L48:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x12(%rbp),%rdx
  add    %rdx,%rax
  mov    $0x4,%edx
  lea    D20(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x4,-0x1c(%rbp)
L17:
  mov    -0x18(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    %eax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  shl    $0x2,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   %eax,%eax
  jne    L52
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x12(%rbp),%rdx
  add    %rdx,%rax
  mov    $0x4,%edx
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  addl   $0x4,-0x1c(%rbp)
L52:
  cmpl   $0x0,-0x1c(%rbp)
  jne    L26
  mov    -0x18(%rbp),%edx
  lea    -0x12(%rbp),%rax
  lea    D17(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  jmp    L31
L26:
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  cltq
  movb   $0xa,-0x12(%rbp,%rax,1)
  mov    -0x1c(%rbp),%eax
  cltq
  movb   $0x0,-0x12(%rbp,%rax,1)
L31:
  lea    -0x12(%rbp),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x1c(%rbp)
  addl   $0x1,-0x18(%rbp)
L50:
  cmpl   $0x64,-0x18(%rbp)
  jle    L48
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L13
  call   <__stack_chk_fail@plt>
L13:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
data_type: string
name: retrieve_data
arguments: data_tag: D13
data_type: string
name: retrieve_data
arguments: data_tag: D17
data_type: string

tool: D20: fizz

tool: D13: buzz

tool: D17: %d


assistant: ```c
int main(int argc, char **argv) {
  char s[10];
  int spos = 0;
  for (int i = 1; i < 101; i++) {
    if (i % 3 == 0) {
      memcpy(s + spos, "fizz", 4);
      spos += 4;
    }
    if (i % 5 == 0) {
      memcpy(s + spos, "buzz", 4);
      spos += 4;
    }
    if (spos == 0) {
      sprintf(s, "%d\n", i);
    } else {
      s[spos++] = '\n';
      s[spos] = 0;
    }
    printf(s);
    spos = 0;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x1,%ebp
  lea    0xe(%rsp),%r12
  lea    D21(%rip),%r15
  lea    D3(%rip),%r14
  lea    D5(%rip),%r13
  jmp    L74
L78:
  mov    $0x4,%edx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <memcpy@plt>
  movslq %ebp,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,4),%eax
  cmp    %eax,%ebp
  je     L12
  mov    $0x4,%ebx
L15:
  movslq %ebx,%rax
  movb   $0xa,0xe(%rsp,%rax,1)
  add    $0x1,%ebx
  movslq %ebx,%rbx
  movb   $0x0,0xe(%rsp,%rbx,1)
L36:
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0x65,%ebp
  je     L55
L74:
  movslq %ebp,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebp,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebp
  je     L78
  movslq %ebp,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x21,%rbx
  mov    %ebp,%eax
  sar    $0x1f,%eax
  sub    %eax,%ebx
  lea    (%rbx,%rbx,4),%eax
  mov    %ebp,%ebx
  sub    %eax,%ebx
  jne    L58
L38:
  movslq %ebx,%rdi
  add    %r12,%rdi
  mov    $0x4,%edx
  mov    %r14,%rsi
  call   <memcpy@plt>
  add    $0x4,%ebx
  jmp    L15
L12:
  mov    $0x4,%ebx
  jmp    L38
L55:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  mov    %ebp,%edx
  mov    %r15,%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  jmp    L36
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D21
datatype: string
name: retrieve_data
arguments: data_label: D3
datatype: string
name: retrieve_data
arguments: data_label: D5
datatype: string

tool: D21: %d


tool: D3: buzz

tool: D5: fizz

assistant: ```c
int main(int argc, char **argv) {
  char s[10];
  int spos = 0;
  for (int i = 1; i < 101; i++) {
    if (i % 3 == 0) {
      memcpy(s + spos, "fizz", 4);
      spos += 4;
    }
    if (i % 5 == 0) {
      memcpy(s + spos, "buzz", 4);
      spos += 4;
    }
    if (spos == 0) {
      sprintf(s, "%d\n", i);
    } else {
      s[spos++] = '\n';
      s[spos] = 0;
    }
    printf(s);
    spos = 0;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    D21(%rip),%r14
  push   %r13
  lea    D4(%rip),%r13
  push   %r12
  mov    $0xcccccccd,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1e(%rsp),%rbp
  jmp    L82
  nopl   0x0(%rax,%rax,1)
L10:
  test   %ebx,%ebx
  je     L25
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
L4:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x65,%r15d
  je     L43
L82:
  mov    %r15d,%ebx
  imul   %r12,%rbx
  shr    $0x22,%rbx
  lea    (%rbx,%rbx,4),%eax
  mov    %r15d,%ebx
  sub    %eax,%ebx
  imul   $0xaaaaaaab,%r15d,%eax
  cmp    $0x55555555,%eax
  ja     L10
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  je     L42
  mov    $0x5,%ebx
  mov    $0x4,%r8d
L26:
  movslq %r8d,%rax
  movb   $0xa,0x1e(%rsp,%rax,1)
  movslq %ebx,%rax
  movb   $0x0,0x1e(%rsp,%rax,1)
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L25:
  mov    $0x5,%ebx
  mov    $0x4,%r8d
  mov    %rbp,%rdi
L47:
  mov    $0x4,%edx
  lea    D1(%rip),%rsi
  mov    %r8d,0xc(%rsp)
  call   <memcpy@plt>
  mov    0xc(%rsp),%r8d
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L42:
  mov    $0x9,%ebx
  mov    $0x8,%r8d
  lea    0x22(%rsp),%rdi
  jmp    L47
L43:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L56
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D4
type_guessed: string
name: read_data
arguments: data_tag: D1
type_guessed: string

tool: D21: fizz

tool: D4: %d


tool: D1: buzz

assistant: ```c
int main(int argc, char **argv) {
  char s[10];
  int spos = 0;
  for (int i = 1; i < 101; i++) {
    if (i % 3 == 0) {
      memcpy(s + spos, "fizz", 4);
      spos += 4;
    }
    if (i % 5 == 0) {
      memcpy(s + spos, "buzz", 4);
      spos += 4;
    }
    if (spos == 0) {
      sprintf(s, "%d\n", i);
    } else {
      s[spos++] = '\n';
      s[spos] = 0;
    }
    printf(s);
    spos = 0;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %r15
  mov    $0x1,%r15d
  push   %r14
  lea    D16(%rip),%r14
  push   %r13
  lea    D25(%rip),%r13
  push   %r12
  mov    $0xcccccccd,%r12d
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0x1e(%rsp),%rbp
  jmp    L21
  nopl   0x0(%rax,%rax,1)
L81:
  test   %ebx,%ebx
  je     L86
  mov    %r15d,%edx
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <sprintf@plt>
L12:
  mov    %rbp,%rdi
  add    $0x1,%r15d
  call   <printf@plt>
  cmp    $0x65,%r15d
  je     L36
L21:
  mov    %r15d,%ebx
  imul   %r12,%rbx
  shr    $0x22,%rbx
  lea    (%rbx,%rbx,4),%eax
  mov    %r15d,%ebx
  sub    %eax,%ebx
  imul   $0xaaaaaaab,%r15d,%eax
  cmp    $0x55555555,%eax
  ja     L81
  mov    $0x4,%edx
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  test   %ebx,%ebx
  je     L3
  mov    $0x5,%ebx
  mov    $0x4,%r8d
L75:
  movslq %r8d,%rax
  movb   $0xa,0x1e(%rsp,%rax,1)
  movslq %ebx,%rax
  movb   $0x0,0x1e(%rsp,%rax,1)
  jmp    L12
  nopw   0x0(%rax,%rax,1)
L86:
  mov    $0x5,%ebx
  mov    $0x4,%r8d
  mov    %rbp,%rdi
L64:
  mov    $0x4,%edx
  lea    D29(%rip),%rsi
  mov    %r8d,0xc(%rsp)
  call   <memcpy@plt>
  mov    0xc(%rsp),%r8d
  jmp    L75
  nopl   0x0(%rax,%rax,1)
L3:
  mov    $0x9,%ebx
  mov    $0x8,%r8d
  lea    0x22(%rsp),%rdi
  jmp    L64
L36:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L58
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L58:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D25
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D29
type_infered: string

tool: D16: fizz

tool: D25: %d


tool: D29: buzz

assistant: ```c
int main(int argc, char **argv) {
  char s[10];
  int spos = 0;
  for (int i = 1; i < 101; i++) {
    if (i % 3 == 0) {
      memcpy(s + spos, "fizz", 4);
      spos += 4;
    }
    if (i % 5 == 0) {
      memcpy(s + spos, "buzz", 4);
      spos += 4;
    }
    if (spos == 0) {
      sprintf(s, "%d\n", i);
    } else {
      s[spos++] = '\n';
      s[spos] = 0;
    }
    printf(s);
    spos = 0;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<emit_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D5
type: string

tool: D5: // File generated by ArduinoML (C/yacc/lex) for %s
long time = 0;
long debounce = 200;



assistant: ```c
void emit_header(char *appname) {
  printf("// File generated by ArduinoML (C/yacc/lex) for %s\n"
         "long time = 0;\n"
         "long debounce = 200;\n\n",
         appname);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<emit_header>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: // File generated by ArduinoML (C/yacc/lex) for %s
long time = 0;
long debounce = 200;



assistant: ```c
void emit_header(char *appname) {
  printf("// File generated by ArduinoML (C/yacc/lex) for %s\n"
         "long time = 0;\n"
         "long debounce = 200;\n\n",
         appname);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<emit_header>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: // File generated by ArduinoML (C/yacc/lex) for %s
long time = 0;
long debounce = 200;



assistant: ```c
void emit_header(char *appname) {
  printf("// File generated by ArduinoML (C/yacc/lex) for %s\n"
         "long time = 0;\n"
         "long debounce = 200;\n\n",
         appname);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<emit_header>:
  endbr64
  mov    %rdi,%rsi
  lea    D2(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D2
type: string

tool: D2: // File generated by ArduinoML (C/yacc/lex) for %s
long time = 0;
long debounce = 200;



assistant: ```c
void emit_header(char *appname) {
  printf("// File generated by ArduinoML (C/yacc/lex) for %s\n"
         "long time = 0;\n"
         "long debounce = 200;\n\n",
         appname);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<FP_strerror>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <sprintf@plt>
  lea    D1(%rip),%rax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
type_infered: string

tool: D17: %03d

assistant: ```c
char *FP_strerror(int errcode) {
  static char number[8];
  sprintf(number, "%03d", errcode);
  return number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FP_strerror>:
  endbr64
  push   %rbx
  mov    %edi,%edx
  lea    D11(%rip),%rsi
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  call   <sprintf@plt>
  mov    %rbx,%rax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D11
type_guessed: string

tool: D11: %03d

assistant: ```c
char *FP_strerror(int errcode) {
  static char number[8];
  sprintf(number, "%03d", errcode);
  return number;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<FP_strerror>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  mov    %edi,%edx
  lea    D14(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: label: D14
datatype: string

tool: D14: %03d

assistant: ```c
char *FP_strerror(int errcode) {
  static char number[8];
  sprintf(number, "%03d", errcode);
  return number;
}
```
user: Translate the below assembly code into C programming language:

```asm
<FP_strerror>:
  endbr64
  push   %r12
  lea    D1(%rip),%r12
  mov    %edi,%edx
  lea    D19(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string

tool: D19: %03d

assistant: ```c
char *FP_strerror(int errcode) {
  static char number[8];
  sprintf(number, "%03d", errcode);
  return number;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vec2_inverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm1
  movss  D14(%rip),%xmm0
  divss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  D14(%rip),%xmm0
  divss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: f32

tool: D14: 1

assistant: ```c
void vec2_inverse(float *dst) {
  dst[0] = 1.0 / dst[0];
  dst[1] = 1.0 / dst[1];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vec2_inverse>:
  endbr64
  movss  D1(%rip),%xmm0
  movaps %xmm0,%xmm1
  divss  (%rdi),%xmm1
  movss  %xmm1,(%rdi)
  divss  0x4(%rdi),%xmm0
  movss  %xmm0,0x4(%rdi)
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: f32

tool: D1: 1

assistant: ```c
void vec2_inverse(float *dst) {
  dst[0] = 1.0 / dst[0];
  dst[1] = 1.0 / dst[1];
}
```
user: Translate the below assembly code into C programming language:

```asm
<vec2_inverse>:
  endbr64
  movss  D0(%rip),%xmm0
  movaps %xmm0,%xmm1
  divss  0x4(%rdi),%xmm0
  divss  (%rdi),%xmm1
  movss  %xmm0,0x4(%rdi)
  movss  %xmm1,(%rdi)
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
type_guessed: f32

tool: D0: 1

assistant: ```c
void vec2_inverse(float *dst) {
  dst[0] = 1.0 / dst[0];
  dst[1] = 1.0 / dst[1];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<vec2_inverse>:
  endbr64
  movss  D2(%rip),%xmm0
  movaps %xmm0,%xmm1
  divss  0x4(%rdi),%xmm0
  divss  (%rdi),%xmm1
  unpcklps %xmm0,%xmm1
  movlps %xmm1,(%rdi)
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
type: f32

tool: D2: 1

assistant: ```c
void vec2_inverse(float *dst) {
  dst[0] = 1.0 / dst[0];
  dst[1] = 1.0 / dst[1];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x3,-0x1c(%rbp)
  movl   $0x5,-0x18(%rbp)
  movl   $0x6,-0x14(%rbp)
  movl   $0x9,-0x10(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0x0,-0x28(%rbp)
  movl   $0x4,-0x24(%rbp)
  mov    -0x2c(%rbp),%ecx
  mov    -0x24(%rbp),%edx
  mov    -0x28(%rbp),%esi
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <binarySearch@plt>
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
data_type: string

tool: D7: %d


assistant: ```c
int main() {
  int p[] = {1, 3, 5, 6, 9};
  int target = 9;
  int low = 0;
  int high = 4;
  printf("%d\n", binarySearch(p, low, high, target));
  return 0;
}
```