ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <header@plt>
  xor    %eax,%eax
  call   <main_float@plt>
  xor    %eax,%eax
  call   <main_double@plt>
  xor    %eax,%eax
  call   <flipped_double@plt>
  mov    D3(%rip),%rbx
  mov    (%rbx),%edi
  call   <ferror@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L2
  pop    %rbx
  ret
L2:
  mov    (%rbx),%edi
  call   <fclose@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  header();
  main_float();
  main_double();
  flipped_double();
  if (ferror(stdout) || fclose(stdout))
    return 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <header@plt>
  xor    %eax,%eax
  call   <main_float@plt>
  xor    %eax,%eax
  call   <main_double@plt>
  xor    %eax,%eax
  call   <flipped_double@plt>
  mov    D1(%rip),%rbx
  mov    (%rbx),%edi
  call   <ferror@plt>
  mov    %rax,%r8
  mov    $0x1,%eax
  test   %r8,%r8
  je     L6
  pop    %rbx
  ret
L6:
  mov    (%rbx),%edi
  call   <fclose@plt>
  pop    %rbx
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int main() {
  header();
  main_float();
  main_double();
  flipped_double();
  if (ferror(stdout) || fclose(stdout))
    return 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L1:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L1
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *save = s1;
  while ((*s1++ = *s2++) != '\0')
    ;
  return (save);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L8:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L8
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *save = s1;
  while ((*s1++ = *s2++) != '\0')
    ;
  return (save);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L7:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L7
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *save = s1;
  while ((*s1++ = *s2++) != '\0')
    ;
  return (save);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L1:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L1
  ret
```

assistant: ```c
char *strcpy(char *s1, const char *s2) {
  char *save = s1;
  while ((*s1++ = *s2++) != '\0')
    ;
  return (save);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  sub    $0x1,%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5b,%al
  jne    L16
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    D19(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L12
  mov    -0x20(%rbp),%rax
  lea    D1(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <error@plt>
L12:
  subl   $0x1,-0x14(%rbp)
L16:
  mov    -0x20(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x14(%rbp),%eax
  sub    $0x1,%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <test@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  jne    L22
  mov    -0x20(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <error@plt>
L22:
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
data_type: string
name: retrieve_data
arguments: data_tag: D1
data_type: string
name: retrieve_data
arguments: data_tag: D25
data_type: string

tool: D19: ]

tool: D1: Missing ']'

tool: D25: syntax error

assistant: ```c
int main(int argc, char *argv[]) {
  int arg0len;
  arg0len = strlen(argv[0]);
  if (argv[0][arg0len - 1] == '[') {
    if (strcmp(argv[argc - 1], "]") != 0)
      error(argv, "Missing ']'");
    argc--;
  }
  if ((argc = test(argc - 1, argv + 1)) == 2)
    error(argv, "syntax error");
  return argc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%rbp
  mov    (%rsi),%rdi
  call   <strlen@plt>
  cltq
  mov    0x0(%rbp),%rdx
  cmpb   $0x5b,-0x1(%rdx,%rax,1)
  je     L55
L29:
  lea    -0x1(%rbx),%edi
  lea    0x8(%rbp),%rsi
  call   <test@plt>
  mov    %eax,%ebx
  cmp    $0x2,%eax
  je     L7
L20:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L55:
  movslq %ebx,%rax
  mov    -0x8(%rbp,%rax,8),%rdi
  lea    D23(%rip),%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L57
L28:
  sub    $0x1,%ebx
  jmp    L29
L57:
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <error@plt>
  jmp    L28
L7:
  lea    D15(%rip),%rsi
  mov    %rbp,%rdi
  call   <error@plt>
  jmp    L20
```

tool_calls: name: parse_data
arguments: label: D23
type: string
name: parse_data
arguments: label: D22
type: string
name: parse_data
arguments: label: D15
type: string

tool: D23: ]

tool: D22: Missing ']'

tool: D15: syntax error

assistant: ```c
int main(int argc, char *argv[]) {
  int arg0len;
  arg0len = strlen(argv[0]);
  if (argv[0][arg0len - 1] == '[') {
    if (strcmp(argv[argc - 1], "]") != 0)
      error(argv, "Missing ']'");
    argc--;
  }
  if ((argc = test(argc - 1, argv + 1)) == 2)
    error(argv, "syntax error");
  return argc;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    (%rsi),%rdi
  call   <strlen@plt>
  mov    0x0(%rbp),%rdx
  cltq
  cmpb   $0x5b,-0x1(%rdx,%rax,1)
  je     L19
L58:
  lea    -0x1(%rbx),%edi
  lea    0x8(%rbp),%rsi
  call   <test@plt>
  mov    %eax,%r12d
  cmp    $0x2,%eax
  je     L14
L23:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  movslq %ebx,%rax
  lea    D21(%rip),%rsi
  mov    -0x8(%rbp,%rax,8),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L18
L52:
  sub    $0x1,%ebx
  jmp    L58
L14:
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <error@plt>
  jmp    L23
L18:
  lea    D17(%rip),%rsi
  mov    %rbp,%rdi
  call   <error@plt>
  jmp    L52
```

tool_calls: name: retrieve_data
arguments: data_label: D21
data_type: string
name: retrieve_data
arguments: data_label: D18
data_type: string
name: retrieve_data
arguments: data_label: D17
data_type: string

tool: D21: ]

tool: D18: syntax error

tool: D17: Missing ']'

assistant: ```c
int main(int argc, char *argv[]) {
  int arg0len;
  arg0len = strlen(argv[0]);
  if (argv[0][arg0len - 1] == '[') {
    if (strcmp(argv[argc - 1], "]") != 0)
      error(argv, "Missing ']'");
    argc--;
  }
  if ((argc = test(argc - 1, argv + 1)) == 2)
    error(argv, "syntax error");
  return argc;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %edi,%ebx
  mov    (%rsi),%rdi
  call   <strlen@plt>
  mov    0x0(%rbp),%rdx
  cltq
  cmpb   $0x5b,-0x1(%rdx,%rax,1)
  je     L6
L39:
  lea    -0x1(%rbx),%edi
  lea    0x8(%rbp),%rsi
  call   <test@plt>
  mov    %eax,%r12d
  cmp    $0x2,%eax
  je     L8
L14:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  movslq %ebx,%rax
  lea    D10(%rip),%rsi
  mov    -0x8(%rbp,%rax,8),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L24
L55:
  sub    $0x1,%ebx
  jmp    L39
L8:
  lea    D16(%rip),%rsi
  mov    %rbp,%rdi
  call   <error@plt>
  jmp    L14
L24:
  lea    D14(%rip),%rsi
  mov    %rbp,%rdi
  call   <error@plt>
  jmp    L55
```

tool_calls: name: retrieve_data
arguments: tag: D10
datatype: string
name: retrieve_data
arguments: tag: D16
datatype: string
name: retrieve_data
arguments: tag: D14
datatype: string

tool: D10: ]

tool: D16: syntax error

tool: D14: Missing ']'

assistant: ```c
int main(int argc, char *argv[]) {
  int arg0len;
  arg0len = strlen(argv[0]);
  if (argv[0][arg0len - 1] == '[') {
    if (strcmp(argv[argc - 1], "]") != 0)
      error(argv, "Missing ']'");
    argc--;
  }
  if ((argc = test(argc - 1, argv + 1)) == 2)
    error(argv, "syntax error");
  return argc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<switch_led>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0xe0028000,%eax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  and    %rdx,%rax
  test   %rax,%rax
  jne    L30
  jmp    L8
L10:
  addl   $0x1,-0x4(%rbp)
L8:
  mov    $0xe0028000,%eax
  mov    (%rax),%rdx
  mov    -0x18(%rbp),%eax
  cltq
  and    %rdx,%rax
  test   %rax,%rax
  je     L10
  cmpl   $0x3e7,-0x4(%rbp)
  jle    L30
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  test   %eax,%eax
  jne    L40
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <led_on@plt>
  mov    -0x20(%rbp),%rax
  movl   $0x1,(%rax)
  jmp    L17
L40:
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <led_off@plt>
  mov    -0x20(%rbp),%rax
  movl   $0x0,(%rax)
L17:
  movl   $0x0,-0x4(%rbp)
L30:
  nop
  leave
  ret
```

assistant: ```c
void switch_led(int led, int button, int *marker) {
  int counter = 0;
  if (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0) {
    while (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0)
      counter++;
    if (counter >= 1000) {
      if (*marker == 0) {
        led_on(led);
        (*marker) = 1;
      } else {
        led_off(led);
        (*marker) = 0;
      }
      counter = 0;
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<switch_led>:
  endbr64
  movabs 0xe0028000,%rax
  movslq %esi,%rsi
  test   %rsi,%rax
  jne    L26
  push   %rbx
  mov    %rdx,%rbx
  movabs 0xe0028000,%rax
  test   %rax,%rsi
  jne    L2
  mov    $0x0,%eax
  mov    $0xe0028000,%ecx
L21:
  add    $0x1,%eax
  mov    (%rcx),%rdx
  test   %rdx,%rsi
  je     L21
  cmp    $0x3e7,%eax
  jle    L2
  cmpl   $0x0,(%rbx)
  jne    L56
  call   <led_on@plt>
  movl   $0x1,(%rbx)
L2:
  pop    %rbx
  ret
L56:
  call   <led_off@plt>
  movl   $0x0,(%rbx)
  jmp    L2
L26:
  ret
```

assistant: ```c
void switch_led(int led, int button, int *marker) {
  int counter = 0;
  if (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0) {
    while (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0)
      counter++;
    if (counter >= 1000) {
      if (*marker == 0) {
        led_on(led);
        (*marker) = 1;
      } else {
        led_off(led);
        (*marker) = 0;
      }
      counter = 0;
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<switch_led>:
  endbr64
  mov    $0xe0028000,%r8d
  movslq %esi,%rsi
  mov    (%r8),%rax
  test   %rsi,%rax
  jne    L20
  mov    (%r8),%rax
  test   %rax,%rsi
  jne    L20
  push   %rbx
  xor    %eax,%eax
  mov    %rdx,%rbx
  nopl   0x0(%rax,%rax,1)
L45:
  mov    (%r8),%rcx
  add    $0x1,%eax
  test   %rcx,%rsi
  je     L45
  cmp    $0x3e7,%eax
  jle    L46
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L8
  call   <led_on@plt>
  movl   $0x1,(%rbx)
L46:
  pop    %rbx
  ret
  nopl   (%rax)
L20:
  ret
  nopl   0x0(%rax)
L8:
  call   <led_off@plt>
  movl   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void switch_led(int led, int button, int *marker) {
  int counter = 0;
  if (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0) {
    while (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0)
      counter++;
    if (counter >= 1000) {
      if (*marker == 0) {
        led_on(led);
        (*marker) = 1;
      } else {
        led_off(led);
        (*marker) = 0;
      }
      counter = 0;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<switch_led>:
  endbr64
  mov    $0xe0028000,%r8d
  movslq %esi,%rsi
  mov    (%r8),%rax
  test   %rsi,%rax
  jne    L3
  mov    (%r8),%rax
  test   %rax,%rsi
  jne    L3
  push   %rbx
  xor    %eax,%eax
  mov    %rdx,%rbx
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%r8),%rcx
  add    $0x1,%eax
  test   %rcx,%rsi
  je     L21
  cmp    $0x3e7,%eax
  jle    L33
  mov    (%rbx),%eax
  test   %eax,%eax
  jne    L9
  call   <led_on@plt>
  movl   $0x1,(%rbx)
L33:
  pop    %rbx
  ret
  nopl   (%rax)
L3:
  ret
  nopl   0x0(%rax)
L9:
  call   <led_off@plt>
  movl   $0x0,(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void switch_led(int led, int button, int *marker) {
  int counter = 0;
  if (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0) {
    while (((*(volatile unsigned long *)(0xE0028000 + 0x00)) & button) == 0)
      counter++;
    if (counter >= 1000) {
      if (*marker == 0) {
        led_on(led);
        (*marker) = 1;
      } else {
        led_off(led);
        (*marker) = 0;
      }
      counter = 0;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hexdump_helper>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  mov    -0x30(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L3
L20:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  movl   $0x0,-0x10(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L40
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1c,%edx
  add    %edx,%eax
  and    $0xf,%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L49
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  movl   $0x1,-0x10(%rbp)
  jmp    L40
L49:
  cmpl   $0x8,-0xc(%rbp)
  jne    L40
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
L40:
  addl   $0x1,-0x18(%rbp)
  addl   $0x1,-0x14(%rbp)
L3:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L20
  mov    -0x14(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D2
datatype: string
name: parse_data
arguments: data_label: D23
datatype: string
name: parse_data
arguments: data_label: D4
datatype: string

tool: D2: %02X 

tool: D23: 


tool: D4: - 

assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printk("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printk("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printk("- ");
      }
    }
  }
  return format_val;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<hexdump_helper>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edx,%ebx
  test   %esi,%esi
  jle    L37
  mov    %rdi,%rbp
  lea    (%rdx,%rsi,1),%r12d
  lea    D21(%rip),%r13
  lea    D27(%rip),%r15
  lea    D24(%rip),%r14
  jmp    L1
L39:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
L6:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  je     L37
L1:
  movzbl 0x0(%rbp),%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  test   %ebx,%ebx
  jle    L6
  test   $0xf,%bl
  je     L39
  mov    %ebx,%edx
  sar    $0x1f,%edx
  shr    $0x1c,%edx
  lea    (%rbx,%rdx,1),%eax
  and    $0xf,%eax
  sub    %edx,%eax
  cmp    $0x8,%eax
  jne    L6
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printk@plt>
  jmp    L6
L37:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: tag: D21
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D24
type_infered: string

tool: D21: %02X 

tool: D27: - 

tool: D24: 


assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printk("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printk("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printk("- ");
      }
    }
  }
  return format_val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hexdump_helper>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x8,%rsp
  test   %esi,%esi
  jle    L66
  mov    %rdi,%rbp
  lea    (%rdx,%rsi,1),%r12d
  lea    D29(%rip),%r13
  lea    D18(%rip),%r15
  lea    D19(%rip),%r14
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L55:
  cmp    $0x8,%eax
  je     L37
L85:
  add    $0x1,%ebx
  add    $0x1,%rbp
  cmp    %r12d,%ebx
  je     L49
L4:
  movzbl 0x0(%rbp),%esi
  xor    %eax,%eax
  mov    %r13,%rdi
  call   <printk@plt>
  test   %ebx,%ebx
  jle    L85
  mov    %ebx,%eax
  and    $0xf,%eax
  jne    L55
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  add    $0x1,%rbp
  call   <printk@plt>
  cmp    %r12d,%ebx
  jne    L4
L49:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L37:
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printk@plt>
  jmp    L85
  nopl   0x0(%rax)
L66:
  mov    %edx,%r12d
  jmp    L49
```

tool_calls: name: disassemble_data
arguments: data_tag: D29
type_infered: string
name: disassemble_data
arguments: data_tag: D18
type_infered: string
name: disassemble_data
arguments: data_tag: D19
type_infered: string

tool: D29: %02X 

tool: D18: - 

tool: D19: 


assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printk("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printk("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printk("- ");
      }
    }
  }
  return format_val;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hexdump_helper>:
  endbr64
  test   %esi,%esi
  jle    L35
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  test   %edx,%edx
  jg     L66
  lea    (%rdx,%rsi,1),%eax
  mov    %edx,%r13d
  mov    $0x1,%r15d
  lea    -0x1(%rax),%r14d
  mov    %eax,0xc(%rsp)
  xor    %eax,%eax
  lea    D28(%rip),%rbp
  test   %r14d,%r14d
  cmovg  %eax,%r14d
  nopl   0x0(%rax)
L82:
  movzbl -0x1(%rbx,%r15,1),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%r13d
  call   <printk@plt>
  mov    %r15d,%ecx
  add    $0x1,%r15
  cmp    %r14d,%r13d
  jle    L82
  cmp    %ecx,%r12d
  jle    L6
L51:
  movslq %ecx,%r15
  lea    D14(%rip),%r14
  jmp    L2
  nopl   0x0(%rax)
L70:
  cmp    $0x8,%eax
  je     L86
L20:
  add    $0x1,%r15
  add    $0x1,%r13d
  cmp    %r15d,%r12d
  jle    L6
L2:
  movzbl (%rbx,%r15,1),%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printk@plt>
  mov    %r13d,%eax
  and    $0xf,%eax
  jne    L70
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%r15
  add    $0x1,%r13d
  call   <printk@plt>
  cmp    %r15d,%r12d
  jg     L2
L6:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L66:
  lea    (%rdx,%rsi,1),%eax
  mov    %edx,%r13d
  lea    D28(%rip),%rbp
  xor    %ecx,%ecx
  mov    %eax,0xc(%rsp)
  jmp    L51
  nopl   (%rax)
L86:
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  call   <printk@plt>
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L35:
  mov    %edx,%eax
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D28
type: string
name: extract_symbolic_data
arguments: data_tag: D14
type: string
name: extract_symbolic_data
arguments: data_tag: D19
type: string

tool: D28: %02X 

tool: D14: 


tool: D19: - 

assistant: ```c
int hexdump_helper(void *ptr, int len, int format_offset) {
  int i, newlined = 0, format_val;
  char *data = (char *)ptr;
  for (i = 0, format_val = format_offset; i < len; i++, format_val++) {
    printk("%02X ", (unsigned char)data[i]);
    newlined = 0;
    if (format_val > 0) {
      int mod = format_val % (16);
      if (mod == 0) {
        printk("\n");
        newlined = 1;
      } else if (mod == (16) / 2) {
        printk("- ");
      }
    }
  }
  return format_val;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L19
L1:
  lea    D28(%rip),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L19:
  cmpl   $0x2,-0xc(%rbp)
  jle    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D28
type: string
name: unpack_data
arguments: tag: D2
type: string
name: unpack_data
arguments: tag: D19
type: string

tool: D28: expit

tool: D2: # c::%s


tool: D19: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::%s\n", "expit");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```