ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<bsearch>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rcx,%rbx
  sub    $0x18,%rsp
  mov    %r8,0x8(%rsp)
  test   %rdx,%rdx
  je     L3
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r15,%r13
  mov    0x8(%rsp),%rax
  mov    %r14,%rdi
  shr    %r13
  mov    %r13,%r12
  imul   %rbx,%r12
  add    %rbp,%r12
  mov    %r12,%rsi
  call   *%rax
  test   %eax,%eax
  je     L23
  jle    L59
  sub    $0x1,%r15
  lea    (%r12,%rbx,1),%rbp
  shr    %r15
  jne    L4
L3:
  xor    %r12d,%r12d
L23:
  add    $0x18,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L59:
  test   %r13,%r13
  je     L3
  mov    %r13,%r15
  jmp    L4
```

assistant: ```c
void *bsearch(const void *key, const void *base0, size_t nmemb, size_t size, int (*compar)(const void *, const void *)) {
  const char *base = (const char *)base0;
  size_t lim;
  int cmp;
  const void *p;
  for (lim = nmemb; lim != 0; lim >>= 1) {
    p = base + (lim >> 1) * size;
    cmp = (*compar)(key, p);
    if (cmp == 0)
      return ((void *)p);
    if (cmp > 0) {
      base = (char *)p + size;
      lim--;
    }
  }
  return (NULL);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sub_pred>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L14:
  movl   $0x0,-0x8(%rbp)
  jmp    L41
L12:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x8(%rbp)
L41:
  cmpl   $0x7,-0x8(%rbp)
  jle    L12
  addq   $0x10,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L16
L22:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rdx),%edx
  movzbl %dl,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    (%rax,%rax,1),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    %dx,(%rax)
  addl   $0x1,-0x8(%rbp)
L16:
  cmpl   $0x7,-0x8(%rbp)
  jle    L22
  addq   $0x10,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L5:
  cmpl   $0x3,-0x4(%rbp)
  jle    L14
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sub_pred(unsigned char *pred, unsigned char *cur, signed int lx, signed short int *blk) {
  signed int i;
  signed int j = 0;
  while (j < 4) {
    i = 0;
    while (i < 8) {
      blk[(signed long int)i] = (signed short int)((signed int)cur[(signed long int)i] - (signed int)pred[(signed long int)i]);
      i = i + 1;
    }
    blk = blk + (signed long int)8;
    cur = cur + (signed long int)lx;
    pred = pred + (signed long int)lx;
    i = 0;
    while (i < 8) {
      blk[(signed long int)i] = (signed short int)((signed int)cur[(signed long int)i] - (signed int)pred[(signed long int)i]);
      i = i + 1;
    }
    blk = blk + (signed long int)8;
    cur = cur + (signed long int)lx;
    pred = pred + (signed long int)lx;
    j = j + 1;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sub_pred>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rcx,%r8
  lea    0x80(%rcx),%r11
  movslq %edx,%r9
  lea    (%r9,%r9,1),%r10
L18:
  mov    $0x0,%eax
L3:
  movzbl (%rsi,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  sub    %ecx,%edx
  mov    %dx,(%r8,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L3
  mov    %rsi,%rbp
  add    %r9,%rsi
  mov    %rdi,%rbx
  add    %r9,%rdi
  mov    $0x0,%eax
L19:
  movzbl (%rsi,%rax,1),%edx
  movzbl (%rdi,%rax,1),%ecx
  sub    %ecx,%edx
  mov    %dx,0x10(%r8,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L19
  add    $0x20,%r8
  lea    0x0(%rbp,%r10,1),%rsi
  lea    (%rbx,%r10,1),%rdi
  cmp    %r8,%r11
  jne    L18
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sub_pred(unsigned char *pred, unsigned char *cur, signed int lx, signed short int *blk) {
  signed int i;
  signed int j = 0;
  while (j < 4) {
    i = 0;
    while (i < 8) {
      blk[(signed long int)i] = (signed short int)((signed int)cur[(signed long int)i] - (signed int)pred[(signed long int)i]);
      i = i + 1;
    }
    blk = blk + (signed long int)8;
    cur = cur + (signed long int)lx;
    pred = pred + (signed long int)lx;
    i = 0;
    while (i < 8) {
      blk[(signed long int)i] = (signed short int)((signed int)cur[(signed long int)i] - (signed int)pred[(signed long int)i]);
      i = i + 1;
    }
    blk = blk + (signed long int)8;
    cur = cur + (signed long int)lx;
    pred = pred + (signed long int)lx;
    j = j + 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<sub_pred>:
  endbr64
  movslq %edx,%r10
  push   %rbp
  mov    %rdi,%r8
  mov    %rsi,%rdi
  push   %rbx
  lea    (%r10,%r10,1),%r11
  lea    0x80(%rcx),%rbx
L21:
  xor    %eax,%eax
  nopl   0x0(%rax)
L24:
  movzbl (%rdi,%rax,1),%edx
  movzbl (%r8,%rax,1),%esi
  sub    %esi,%edx
  mov    %dx,(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L24
  lea    (%rdi,%r10,1),%rbp
  lea    (%r8,%r10,1),%r9
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L9:
  movzbl 0x0(%rbp,%rax,1),%edx
  movzbl (%r9,%rax,1),%esi
  sub    %esi,%edx
  mov    %dx,0x10(%rcx,%rax,2)
  add    $0x1,%rax
  cmp    $0x8,%rax
  jne    L9
  add    $0x20,%rcx
  add    %r11,%rdi
  add    %r11,%r8
  cmp    %rbx,%rcx
  jne    L21
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void sub_pred(unsigned char *pred, unsigned char *cur, signed int lx, signed short int *blk) {
  signed int i;
  signed int j = 0;
  while (j < 4) {
    i = 0;
    while (i < 8) {
      blk[(signed long int)i] = (signed short int)((signed int)cur[(signed long int)i] - (signed int)pred[(signed long int)i]);
      i = i + 1;
    }
    blk = blk + (signed long int)8;
    cur = cur + (signed long int)lx;
    pred = pred + (signed long int)lx;
    i = 0;
    while (i < 8) {
      blk[(signed long int)i] = (signed short int)((signed int)cur[(signed long int)i] - (signed int)pred[(signed long int)i]);
      i = i + 1;
    }
    blk = blk + (signed long int)8;
    cur = cur + (signed long int)lx;
    pred = pred + (signed long int)lx;
    j = j + 1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<adjustnominals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,%eax
  mov    %rcx,-0x48(%rbp)
  mov    %al,-0x40(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x3,-0x2c(%rbp)
  movabs $0x62656164676366,%rax
  mov    %rax,-0x18(%rbp)
  movabs $0x42454144474346,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x28(%rbp)
  movl   $0x0,-0x30(%rbp)
  movsbl -0x40(%rbp),%edx
  lea    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L24
  lea    -0x18(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x30(%rbp)
L24:
  movsbl -0x40(%rbp),%edx
  lea    -0x10(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <strchr@plt>
  mov    %rax,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L21
  lea    -0x10(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  sub    %edx,%eax
  mov    %eax,-0x30(%rbp)
L21:
  mov    -0x38(%rbp),%rax
  movsd  (%rax),%xmm1
  mov    -0x48(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  movsd  D12(%rip),%xmm0
  addsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x30(%rbp),%xmm0
  mulsd  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x3c(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  movsd  D11(%rip),%xmm2
  divsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x20(%rbp)
  mov    -0x38(%rbp),%rax
  movsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  mov    $0x1,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
datatype: f64
name: disassemble_data
arguments: data_tag: D11
datatype: f64

tool: D12: 1.955000865387433

tool: D11: 100

assistant: ```c
int adjustnominals(double *num, int den, char nominal, double temper[]) {
  int c;
  double n;
  char *x;
  const int m = 3;
  const char pylow[8] = "fcgdaeb";
  const char pyupp[8] = "FCGDAEB";
  x = NULL;
  c = 0;
  x = strchr(pylow, nominal);
  if (x != NULL)
    c = (x - pylow) - m;
  x = strchr(pyupp, nominal);
  if (x != NULL)
    c = (x - pyupp) - m;
  n = *num + ((temper[1] + (1.9550008653874328956590034067630767822266)) * c * (double)den / 100.0);
  *num = n;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adjustnominals>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rcx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movabs $0x62656164676366,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x42454144474346,%rax
  mov    %rax,0x20(%rsp)
  movsbl %dl,%r14d
  lea    0x18(%rsp),%rdi
  mov    %r14d,%esi
  call   <strchr@plt>
  lea    0x30(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  mov    %eax,%edx
  sub    0x8(%rsp),%edx
  lea    0x15(%rdx),%ebx
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %eax,%ebx
  lea    0x20(%rsp),%rdi
  mov    %r14d,%esi
  call   <strchr@plt>
  lea    0x30(%rsp),%rcx
  mov    %rcx,0x8(%rsp)
  mov    %eax,%edx
  sub    0x8(%rsp),%edx
  lea    0xd(%rdx),%edx
  test   %rax,%rax
  cmovne %edx,%ebx
  movsd  D19(%rip),%xmm0
  addsd  0x8(%r13),%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %ebx,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r12d,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  D17(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x1,%eax
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D19
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: f64

tool: D19: 1.955000865387433

tool: D17: 100

assistant: ```c
int adjustnominals(double *num, int den, char nominal, double temper[]) {
  int c;
  double n;
  char *x;
  const int m = 3;
  const char pylow[8] = "fcgdaeb";
  const char pyupp[8] = "FCGDAEB";
  x = NULL;
  c = 0;
  x = strchr(pylow, nominal);
  if (x != NULL)
    c = (x - pylow) - m;
  x = strchr(pyupp, nominal);
  if (x != NULL)
    c = (x - pyupp) - m;
  n = *num + ((temper[1] + (1.9550008653874328956590034067630767822266)) * c * (double)den / 100.0);
  *num = n;
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<adjustnominals>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movsbl %dl,%r12d
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x62656164676366,%rax
  lea    0x8(%rsp),%r15
  mov    %r15,%rdi
  mov    %rax,0x8(%rsp)
  movabs $0x42454144474346,%rax
  mov    %rax,0x10(%rsp)
  call   <strchr@plt>
  mov    %r12d,%esi
  mov    %rax,%rbx
  sub    %r15,%rbx
  lea    0x10(%rsp),%r15
  sub    $0x3,%ebx
  mov    %r15,%rdi
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %eax,%ebx
  call   <strchr@plt>
  pxor   %xmm1,%xmm1
  movsd  D4(%rip),%xmm0
  addsd  0x8(%r14),%xmm0
  mov    %rax,%rdx
  sub    %r15,%rdx
  sub    $0x3,%edx
  test   %rax,%rax
  cmovne %edx,%ebx
  cvtsi2sd %ebx,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  D11(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D4
type: f64
name: unpack_data
arguments: label: D11
type: f64

tool: D4: 1.955000865387433

tool: D11: 100

assistant: ```c
int adjustnominals(double *num, int den, char nominal, double temper[]) {
  int c;
  double n;
  char *x;
  const int m = 3;
  const char pylow[8] = "fcgdaeb";
  const char pyupp[8] = "FCGDAEB";
  x = NULL;
  c = 0;
  x = strchr(pylow, nominal);
  if (x != NULL)
    c = (x - pylow) - m;
  x = strchr(pyupp, nominal);
  if (x != NULL)
    c = (x - pyupp) - m;
  n = *num + ((temper[1] + (1.9550008653874328956590034067630767822266)) * c * (double)den / 100.0);
  *num = n;
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<adjustnominals>:
  endbr64
  push   %r15
  push   %r14
  mov    %rcx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movsbl %dl,%r12d
  push   %rbp
  mov    %r12d,%esi
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x62656164676366,%rax
  lea    0x8(%rsp),%r15
  mov    %r15,%rdi
  mov    %rax,0x8(%rsp)
  movabs $0x42454144474346,%rax
  mov    %rax,0x10(%rsp)
  call   <strchr@plt>
  mov    %r12d,%esi
  mov    %rax,%rbx
  sub    %r15,%rbx
  lea    0x10(%rsp),%r15
  sub    $0x3,%ebx
  mov    %r15,%rdi
  test   %rax,%rax
  mov    $0x0,%eax
  cmove  %eax,%ebx
  call   <strchr@plt>
  pxor   %xmm1,%xmm1
  movsd  D16(%rip),%xmm0
  addsd  0x8(%r14),%xmm0
  mov    %rax,%rdx
  sub    %r15,%rdx
  sub    $0x3,%edx
  test   %rax,%rax
  cmovne %edx,%ebx
  cvtsi2sd %ebx,%xmm1
  mulsd  %xmm1,%xmm0
  pxor   %xmm1,%xmm1
  cvtsi2sd %r13d,%xmm1
  mulsd  %xmm1,%xmm0
  divsd  D11(%rip),%xmm0
  addsd  0x0(%rbp),%xmm0
  movsd  %xmm0,0x0(%rbp)
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x28,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D16
datatype: f64
name: retrieve_data
arguments: tag: D11
datatype: f64

tool: D16: 1.955000865387433

tool: D11: 100

assistant: ```c
int adjustnominals(double *num, int den, char nominal, double temper[]) {
  int c;
  double n;
  char *x;
  const int m = 3;
  const char pylow[8] = "fcgdaeb";
  const char pyupp[8] = "FCGDAEB";
  x = NULL;
  c = 0;
  x = strchr(pylow, nominal);
  if (x != NULL)
    c = (x - pylow) - m;
  x = strchr(pyupp, nominal);
  if (x != NULL)
    c = (x - pyupp) - m;
  n = *num + ((temper[1] + (1.9550008653874328956590034067630767822266)) * c * (double)den / 100.0);
  *num = n;
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x3,-0x14(%rbp)
  jmp    L11
L33:
  movl   $0x1,-0xc(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x2,-0x10(%rbp)
  jmp    L8
L38:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  addl   $0x1,-0x10(%rbp)
L8:
  mov    -0x10(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L38
  mov    -0x4(%rbp),%edx
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L11:
  cmpl   $0xa,-0x14(%rbp)
  jle    L33
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D12
type_infered: string
name: disassemble_data
arguments: data_label: D8
type_infered: string
name: disassemble_data
arguments: data_label: D40
type_infered: string
name: disassemble_data
arguments: data_label: D16
type_infered: string
name: disassemble_data
arguments: data_label: D25
type_infered: string

tool: D12: Uma serie muito famosa na matematica e a serie de FIBONACCI

Aqui vamos te mostrar o n-esimo termo da serie de FIBONACCI
Veja abaixo:


tool: D8: 

Serie de Fibonacci:


tool: D40: Termo 0: 1

tool: D16: Termo 1: 1

tool: D25: Termo %d: %d


assistant: ```c
int main() {
  int termo, base, serie, a, b, c, n;
  printf("Uma serie muito famosa na matematica e a serie de FIBONACCI\n\nAqui vamos te mostrar o n-esimo termo da serie de FIBONACCI\nVeja abaixo:\n\n");
  printf("\n\nSerie de Fibonacci:\n\n");
  printf("Termo 0: 1\n");
  printf("Termo 1: 1\n");
  for (termo = 3; termo <= 10; termo++) {
    a = 1;
    b = 1;
    for (base = 2; base < termo; base++) {
      c = a + b;
      a = b;
      b = c;
    }
    printf("Termo %d: %d\n", base, c);
  }
  getch();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D14(%rip),%rdi
  call   <puts@plt>
  lea    D44(%rip),%rdi
  call   <puts@plt>
  lea    D43(%rip),%rdi
  call   <puts@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x3,%ebp
  mov    $0x1,%r12d
  mov    $0x2,%r14d
  lea    D46(%rip),%r13
  jmp    L15
L46:
  mov    %ebx,%edx
L39:
  lea    (%rcx,%rdx,1),%ebx
  add    $0x1,%eax
  mov    %edx,%ecx
  cmp    %ebp,%eax
  jne    L46
  mov    %ebp,%esi
L44:
  mov    %ebx,%edx
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%ebp
  cmp    $0xb,%ebp
  je     L43
L15:
  mov    %r12d,%edx
  mov    %r12d,%ecx
  mov    $0x2,%eax
  mov    %r14d,%esi
  cmp    $0x2,%ebp
  jg     L39
  jmp    L44
L43:
  mov    $0x0,%eax
  call   <getch@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D14
type_infered: string
name: unpack_data
arguments: data_label: D44
type_infered: string
name: unpack_data
arguments: data_label: D43
type_infered: string
name: unpack_data
arguments: data_label: D8
type_infered: string
name: unpack_data
arguments: data_label: D46
type_infered: string

tool: D14: Uma serie muito famosa na matematica e a serie de FIBONACCI

Aqui vamos te mostrar o n-esimo termo da serie de FIBONACCI
Veja abaixo:


tool: D44: 

Serie de Fibonacci:


tool: D43: Termo 0: 1

tool: D8: Termo 1: 1

tool: D46: Termo %d: %d


assistant: ```c
int main() {
  int termo, base, serie, a, b, c, n;
  printf("Uma serie muito famosa na matematica e a serie de FIBONACCI\n\nAqui vamos te mostrar o n-esimo termo da serie de FIBONACCI\nVeja abaixo:\n\n");
  printf("\n\nSerie de Fibonacci:\n\n");
  printf("Termo 0: 1\n");
  printf("Termo 1: 1\n");
  for (termo = 3; termo <= 10; termo++) {
    a = 1;
    b = 1;
    for (base = 2; base < termo; base++) {
      c = a + b;
      a = b;
      b = c;
    }
    printf("Termo %d: %d\n", base, c);
  }
  getch();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rdi
  lea    D37(%rip),%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <puts@plt>
  lea    D45(%rip),%rdi
  call   <puts@plt>
  lea    D27(%rip),%rdi
  call   <puts@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    $0x3,%ecx
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    $0x1,%eax
  mov    $0x1,%edx
  mov    $0x2,%ebx
  jmp    L17
  nopl   0x0(%rax)
L1:
  mov    %r8d,%eax
L17:
  add    $0x1,%ebx
  lea    (%rdx,%rax,1),%r8d
  mov    %eax,%edx
  cmp    %ecx,%ebx
  jne    L1
  mov    %r8d,%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x1(%rbx),%ecx
  cmp    $0xa,%ebx
  jne    L20
  xor    %eax,%eax
  call   <getch@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D15
type_infered: string
name: disassemble_data
arguments: label: D37
type_infered: string
name: disassemble_data
arguments: label: D45
type_infered: string
name: disassemble_data
arguments: label: D27
type_infered: string
name: disassemble_data
arguments: label: D48
type_infered: string

tool: D15: Uma serie muito famosa na matematica e a serie de FIBONACCI

Aqui vamos te mostrar o n-esimo termo da serie de FIBONACCI
Veja abaixo:


tool: D37: Termo %d: %d


tool: D45: 

Serie de Fibonacci:


tool: D27: Termo 0: 1

tool: D48: Termo 1: 1

assistant: ```c
int main() {
  int termo, base, serie, a, b, c, n;
  printf("Uma serie muito famosa na matematica e a serie de FIBONACCI\n\nAqui vamos te mostrar o n-esimo termo da serie de FIBONACCI\nVeja abaixo:\n\n");
  printf("\n\nSerie de Fibonacci:\n\n");
  printf("Termo 0: 1\n");
  printf("Termo 1: 1\n");
  for (termo = 3; termo <= 10; termo++) {
    a = 1;
    b = 1;
    for (base = 2; base < termo; base++) {
      c = a + b;
      a = b;
      b = c;
    }
    printf("Termo %d: %d\n", base, c);
  }
  getch();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D38(%rip),%rdi
  lea    D6(%rip),%rbp
  call   <puts@plt>
  lea    D39(%rip),%rdi
  call   <puts@plt>
  lea    D1(%rip),%rdi
  call   <puts@plt>
  lea    D48(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  xor    %eax,%eax
  mov    $0x3,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x3,%edx
  xor    %eax,%eax
  mov    $0x4,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x5,%edx
  xor    %eax,%eax
  mov    $0x5,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  xor    %eax,%eax
  mov    $0x6,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0xd,%edx
  xor    %eax,%eax
  mov    $0x7,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x15,%edx
  xor    %eax,%eax
  mov    $0x8,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x22,%edx
  xor    %eax,%eax
  mov    $0x9,%esi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x37,%edx
  xor    %eax,%eax
  mov    $0xa,%esi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getch@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D38
type_guessed: string
name: parse_data
arguments: data_label: D6
type_guessed: string
name: parse_data
arguments: data_label: D39
type_guessed: string
name: parse_data
arguments: data_label: D1
type_guessed: string
name: parse_data
arguments: data_label: D48
type_guessed: string

tool: D38: Uma serie muito famosa na matematica e a serie de FIBONACCI

Aqui vamos te mostrar o n-esimo termo da serie de FIBONACCI
Veja abaixo:


tool: D6: Termo %d: %d


tool: D39: 

Serie de Fibonacci:


tool: D1: Termo 0: 1

tool: D48: Termo 1: 1

assistant: ```c
int main() {
  int termo, base, serie, a, b, c, n;
  printf("Uma serie muito famosa na matematica e a serie de FIBONACCI\n\nAqui vamos te mostrar o n-esimo termo da serie de FIBONACCI\nVeja abaixo:\n\n");
  printf("\n\nSerie de Fibonacci:\n\n");
  printf("Termo 0: 1\n");
  printf("Termo 1: 1\n");
  for (termo = 3; termo <= 10; termo++) {
    a = 1;
    b = 1;
    for (base = 2; base < termo; base++) {
      c = a + b;
      a = b;
      b = c;
    }
    printf("Termo %d: %d\n", base, c);
  }
  getch();
  return 0;
}
```