ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_matrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  sub    $0x18,%rsp
  shr    $0x2,%ebp
  mov    %rdi,(%rsp)
  mov    %esi,0xc(%rsp)
  je     L28
  xor    %r14d,%r14d
  lea    D11(%rip),%r15
L68:
  movl   $0x0,0x8(%rsp)
L46:
  mov    0x8(%rsp),%r12d
  xor    %r13d,%r13d
  shl    $0x2,%r12
  nopl   0x0(%rax,%rax,1)
L36:
  xor    %ebx,%ebx
L0:
  mov    %ebp,%edx
  mov    %r13d,%esi
  mov    %r14d,%edi
  call   <get_index@plt>
  mov    %ebx,%edx
  pxor   %xmm0,%xmm0
  mov    %r15,%rdi
  add    %r12,%rdx
  shl    $0x6,%rax
  add    (%rsp),%rax
  add    $0x1,%ebx
  cvtss2sd (%rax,%rdx,4),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    $0x4,%ebx
  jne    L0
  add    $0x1,%r13d
  cmp    %ebp,%r13d
  jne    L36
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,0x8(%rsp)
  mov    0x8(%rsp),%eax
  cmp    $0x4,%eax
  jne    L46
  add    $0x1,%r14d
  cmp    %ebp,%r14d
  jne    L68
L28:
  lea    D15(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0xc(%rsp),%eax
  imul   %eax,%eax
  test   %eax,%eax
  je     L40
  mov    (%rsp),%r13
  sub    $0x1,%eax
  lea    D3(%rip),%rbx
  lea    0x4(%r13,%rax,4),%rbp
L62:
  pxor   %xmm0,%xmm0
  mov    %rbx,%rdi
  mov    $0x1,%eax
  add    $0x4,%r13
  cvtss2sd -0x4(%r13),%xmm0
  call   <printf@plt>
  cmp    %rbp,%r13
  jne    L62
L40:
  add    $0x18,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: label: D11
type_guessed: string
name: disassemble_data
arguments: label: D15
type_guessed: string
name: disassemble_data
arguments: label: D3
type_guessed: string

tool: D11: % 1.4f 

tool: D15: memory layout, linear: 

tool: D3: % 1.3f 

assistant: ```c
void print_matrix(float (*A)[4][4], const unsigned int N) {
  unsigned int i_block, j_block;
  unsigned int i, j;
  float *A_linear;
  for (i = 0; i < N / 4; i++) {
    for (i_block = 0; i_block < 4; i_block++) {
      for (j = 0; j < N / 4; j++) {
        for (j_block = 0; j_block < 4; j_block++) {
          printf("% 1.4f ", A[get_index(i, j, N / 4)][i_block][j_block]);
        }
      }
      printf("\n");
    }
  }
  printf("memory layout, linear: ");
  A_linear = &(A[0][0][0]);
  for (i = 0; i < N * N; ++i) {
    printf("% 1.3f ", A_linear[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<fistp_m32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    $0x1d,%edi
  call   <put8@plt>
  mov    -0x8(%rbp),%rax
  mov    %eax,%edi
  call   <put32@plt>
  nop
  leave
  ret
```

assistant: ```c
void fistp_m32(unsigned int *m32) {
  put8(0xDB);
  put8(0x1D);
  put32((unsigned int)(m32));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fistp_m32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    $0x1d,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  call   <put32@plt>
  pop    %rbx
  ret
```

assistant: ```c
void fistp_m32(unsigned int *m32) {
  put8(0xDB);
  put8(0x1D);
  put32((unsigned int)(m32));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fistp_m32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    $0x1d,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1070 <put32@plt>
```

assistant: ```c
void fistp_m32(unsigned int *m32) {
  put8(0xDB);
  put8(0x1D);
  put32((unsigned int)(m32));
}
```
user: What is the c source code of the assembly code below:

```asm
<fistp_m32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xdb,%edi
  call   <put8@plt>
  mov    $0x1d,%edi
  call   <put8@plt>
  mov    %ebx,%edi
  pop    %rbx
  jmp    1070 <put32@plt>
```

assistant: ```c
void fistp_m32(unsigned int *m32) {
  put8(0xDB);
  put8(0x1D);
  put32((unsigned int)(m32));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  lea    D6(%rip),%rax
  mov    %rax,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L37
L5:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%eax
  add    $0x30,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  jmp    L9
L37:
  mov    -0x14(%rbp),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %edx,%ecx
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    $0x30,%eax
  sub    %edx,%eax
  subq   $0x1,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L37
  subq   $0x1,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movb   $0x2d,(%rax)
  mov    -0x8(%rbp),%rax
L9:
  pop    %rbp
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[3 + 2];
  char *p = buf + 3 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  mov    %edi,%ecx
  lea    D1(%rip),%rdi
  mov    $0x30,%r8d
  test   %ecx,%ecx
  jns    L12
L5:
  mov    %rdi,%rax
  sub    $0x1,%rdi
  movslq %ecx,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%esi
  lea    (%r8,%rsi,2),%esi
  sub    %ecx,%esi
  mov    %sil,(%rdi)
  mov    %edx,%ecx
  test   %edx,%edx
  jne    L5
  lea    -0x2(%rax),%rdx
  movb   $0x2d,-0x1(%rdi)
L28:
  mov    %rdx,%rax
  ret
L12:
  mov    %rdi,%rdx
L38:
  sub    $0x1,%rdx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  lea    (%rax,%rax,4),%esi
  add    %esi,%esi
  sub    %esi,%ecx
  add    $0x30,%ecx
  mov    %cl,(%rdx)
  mov    %eax,%ecx
  test   %eax,%eax
  jne    L38
  jmp    L28
```

assistant: ```c
char *itoa(int i) {
  static char buf[3 + 2];
  char *p = buf + 3 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  mov    $0x30,%r9d
  lea    D0(%rip),%rdi
  test   %edx,%edx
  jns    L7
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %edx,%rcx
  mov    %edx,%eax
  mov    %rdi,%r8
  sub    $0x1,%rdi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%r9,%rsi,2),%esi
  sub    %edx,%esi
  mov    %ecx,%edx
  mov    %sil,(%rdi)
  test   %ecx,%ecx
  jne    L6
  sub    $0x2,%r8
  movb   $0x2d,-0x1(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L7:
  mov    %rdi,%r8
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %edx,%eax
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L3
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[3 + 2];
  char *p = buf + 3 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<itoa>:
  endbr64
  mov    %edi,%edx
  mov    $0x30,%r9d
  lea    D9(%rip),%rdi
  test   %edx,%edx
  jns    L29
  nopw   0x0(%rax,%rax,1)
L14:
  movslq %edx,%rcx
  mov    %edx,%eax
  mov    %rdi,%r8
  sub    $0x1,%rdi
  imul   $0x66666667,%rcx,%rcx
  sar    $0x1f,%eax
  sar    $0x22,%rcx
  sub    %eax,%ecx
  lea    (%rcx,%rcx,4),%esi
  lea    (%r9,%rsi,2),%esi
  sub    %edx,%esi
  mov    %ecx,%edx
  mov    %sil,(%rdi)
  test   %ecx,%ecx
  jne    L14
  sub    $0x2,%r8
  movb   $0x2d,-0x1(%rdi)
  mov    %r8,%rax
  ret
  nopw   0x0(%rax,%rax,1)
L29:
  mov    %rdi,%r8
  mov    $0xcccccccd,%esi
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %edx,%eax
  sub    $0x1,%r8
  imul   %rsi,%rax
  shr    $0x23,%rax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%edx
  add    $0x30,%edx
  mov    %dl,(%r8)
  mov    %eax,%edx
  test   %eax,%eax
  jne    L11
  mov    %r8,%rax
  ret
```

assistant: ```c
char *itoa(int i) {
  static char buf[3 + 2];
  char *p = buf + 3 + 1;
  if (i >= 0) {
    do {
      *--p = '0' + (i % 10);
      i /= 10;
    } while (i != 0);
    return p;
  } else {
    do {
      *--p = '0' - (i % 10);
      i /= 10;
    } while (i != 0);
    *--p = '-';
  }
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sc_flops_papi>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x20(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x18(%rbp),%rax
  movq   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void sc_flops_papi(float *rtime, float *ptime, long long *flpops, float *mflops) {
  *rtime = *ptime = *mflops = 0.;
  *flpops = 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<sc_flops_papi>:
  endbr64
  movl   $0x0,(%rcx)
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdi)
  movq   $0x0,(%rdx)
  ret
```

assistant: ```c
void sc_flops_papi(float *rtime, float *ptime, long long *flpops, float *mflops) {
  *rtime = *ptime = *mflops = 0.;
  *flpops = 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<sc_flops_papi>:
  endbr64
  movl   $0x0,(%rcx)
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdi)
  movq   $0x0,(%rdx)
  ret
```

assistant: ```c
void sc_flops_papi(float *rtime, float *ptime, long long *flpops, float *mflops) {
  *rtime = *ptime = *mflops = 0.;
  *flpops = 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sc_flops_papi>:
  endbr64
  movl   $0x0,(%rcx)
  movl   $0x0,(%rsi)
  movl   $0x0,(%rdi)
  movq   $0x0,(%rdx)
  ret
```

assistant: ```c
void sc_flops_papi(float *rtime, float *ptime, long long *flpops, float *mflops) {
  *rtime = *ptime = *mflops = 0.;
  *flpops = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <parse@plt>
  mov    %rax,-0x10(%rbp)
  call   <fork@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L25
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <execvp@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L34
L25:
  cmpl   $0x0,-0x14(%rbp)
  jns    L34
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L29
L34:
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <wait@plt>
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <WIFEXITED@plt>
  test   %rax,%rax
  je     L59
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <WEXITSTATUS@plt>
  jmp    L29
L59:
  mov    $0xffffffff,%eax
L29:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

assistant: ```c
int _system(char *command) {
  int pid, st;
  char **vect;
  vect = parse(command);
  if ((pid = fork()) == 0) {
    execvp(vect[0], vect);
    exit(-1);
  } else if (pid < 0) {
    free(vect);
    return -1;
  }
  free(vect);
  wait(&st);
  if (WIFEXITED(st))
    return WEXITSTATUS(st);
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<_system>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <parse@plt>
  mov    %rax,%rbx
  call   <fork@plt>
  test   %eax,%eax
  je     L29
  js     L32
L56:
  mov    %rbx,%rdi
  call   <free@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  test   %rax,%rax
  je     L13
  mov    0x4(%rsp),%edi
  call   <WEXITSTATUS@plt>
L64:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L41
  add    $0x10,%rsp
  pop    %rbx
  ret
L29:
  mov    %rbx,%rsi
  mov    (%rbx),%rdi
  call   <execvp@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L56
L32:
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L64
L13:
  mov    $0xffffffff,%eax
  jmp    L64
L41:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _system(char *command) {
  int pid, st;
  char **vect;
  vect = parse(command);
  if ((pid = fork()) == 0) {
    execvp(vect[0], vect);
    exit(-1);
  } else if (pid < 0) {
    free(vect);
    return -1;
  }
  free(vect);
  wait(&st);
  if (WIFEXITED(st))
    return WEXITSTATUS(st);
  else
    return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<_system>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <parse@plt>
  mov    %rax,%rbp
  call   <fork@plt>
  test   %eax,%eax
  je     L42
  js     L40
L24:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  test   %rax,%rax
  je     L7
  mov    0x4(%rsp),%edi
  call   <WEXITSTATUS@plt>
L31:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L66
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L42:
  mov    0x0(%rbp),%rdi
  mov    %rbp,%rsi
  call   <execvp@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L24
  nopl   0x0(%rax,%rax,1)
L7:
  mov    $0xffffffff,%eax
  jmp    L31
L40:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L31
L66:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _system(char *command) {
  int pid, st;
  char **vect;
  vect = parse(command);
  if ((pid = fork()) == 0) {
    execvp(vect[0], vect);
    exit(-1);
  } else if (pid < 0) {
    free(vect);
    return -1;
  }
  free(vect);
  wait(&st);
  if (WIFEXITED(st))
    return WEXITSTATUS(st);
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<_system>:
  endbr64
  push   %rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <parse@plt>
  mov    %rax,%rbp
  call   <fork@plt>
  test   %eax,%eax
  je     L38
  js     L56
L19:
  mov    %rbp,%rdi
  call   <free@plt>
  lea    0x4(%rsp),%rdi
  call   <wait@plt>
  mov    0x4(%rsp),%edi
  call   <WIFEXITED@plt>
  test   %rax,%rax
  je     L51
  mov    0x4(%rsp),%edi
  call   <WEXITSTATUS@plt>
L11:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L53
  add    $0x10,%rsp
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L38:
  mov    0x0(%rbp),%rdi
  mov    %rbp,%rsi
  call   <execvp@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L51:
  mov    $0xffffffff,%eax
  jmp    L11
L56:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0xffffffff,%eax
  jmp    L11
L53:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int _system(char *command) {
  int pid, st;
  char **vect;
  vect = parse(command);
  if ((pid = fork()) == 0) {
    execvp(vect[0], vect);
    exit(-1);
  } else if (pid < 0) {
    free(vect);
    return -1;
  }
  free(vect);
  wait(&st);
  if (WIFEXITED(st))
    return WEXITSTATUS(st);
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<fahrtocelsius>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movss  %xmm0,-0x14(%rbp)
  pxor   %xmm0,%xmm0
  cvtss2sd -0x14(%rbp),%xmm0
  movsd  D25(%rip),%xmm2
  movapd %xmm0,%xmm1
  subsd  %xmm2,%xmm1
  movsd  D17(%rip),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  D19(%rip),%xmm1
  divsd  %xmm1,%xmm0
  cvtsd2ss %xmm0,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D25
data_type: f64
name: disassemble_data
arguments: label: D17
data_type: f64
name: disassemble_data
arguments: label: D19
data_type: f64

tool: D25: 32

tool: D17: 5

tool: D19: 9

assistant: ```c
float fahrtocelsius(float fahr) {
  float x = (float)5.0 * (fahr - 32.0) / 9.0;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fahrtocelsius>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  subsd  D22(%rip),%xmm0
  mulsd  D16(%rip),%xmm0
  divsd  D2(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: label: D22
type_infered: f64
name: retrieve_data
arguments: label: D16
type_infered: f64
name: retrieve_data
arguments: label: D2
type_infered: f64

tool: D22: 32

tool: D16: 5

tool: D2: 9

assistant: ```c
float fahrtocelsius(float fahr) {
  float x = (float)5.0 * (fahr - 32.0) / 9.0;
  return x;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<fahrtocelsius>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  subsd  D21(%rip),%xmm0
  mulsd  D2(%rip),%xmm0
  divsd  D23(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D21
type: f64
name: retrieve_data
arguments: data_tag: D2
type: f64
name: retrieve_data
arguments: data_tag: D23
type: f64

tool: D21: 32

tool: D2: 5

tool: D23: 9

assistant: ```c
float fahrtocelsius(float fahr) {
  float x = (float)5.0 * (fahr - 32.0) / 9.0;
  return x;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fahrtocelsius>:
  endbr64
  cvtss2sd %xmm0,%xmm0
  subsd  D5(%rip),%xmm0
  mulsd  D14(%rip),%xmm0
  divsd  D25(%rip),%xmm0
  cvtsd2ss %xmm0,%xmm0
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type: f64
name: retrieve_data
arguments: tag: D14
type: f64
name: retrieve_data
arguments: tag: D25
type: f64

tool: D5: 32

tool: D14: 5

tool: D25: 9

assistant: ```c
float fahrtocelsius(float fahr) {
  float x = (float)5.0 * (fahr - 32.0) / 9.0;
  return x;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<flash_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  sub    $0x4,%eax
  cmp    $0x24,%eax
  ja     L80
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D30(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D30(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D97(%rip),%rax
  jmp    L16
  lea    D39(%rip),%rax
  jmp    L16
  lea    D50(%rip),%rax
  jmp    L16
  lea    D41(%rip),%rax
  jmp    L16
  lea    D51(%rip),%rax
  jmp    L16
  lea    D55(%rip),%rax
  jmp    L16
  lea    D77(%rip),%rax
  jmp    L16
  lea    D74(%rip),%rax
  jmp    L16
L80:
  lea    D63(%rip),%rax
L16:
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: label: D97
type_infered: string
name: read_data
arguments: label: D39
type_infered: string
name: read_data
arguments: label: D50
type_infered: string
name: read_data
arguments: label: D41
type_infered: string
name: read_data
arguments: label: D51
type_infered: string
name: read_data
arguments: label: D55
type_infered: string
name: read_data
arguments: label: D77
type_infered: string
name: read_data
arguments: label: D74
type_infered: string
name: read_data
arguments: label: D63
type_infered: string

tool: D97: MB90F497G

tool: D39: LPC_IAP

tool: D50: M32C87_1MB

tool: D41: LPC23xx_256k

tool: D51: USB_PRO_FD_Flash

tool: D55: USB_FD_Flash

tool: D77: LPC407X_8X

tool: D74: FLASH_ROUTER_FD

tool: D63: unkown

assistant: ```c
const char *flash_name(uint8_t flash_type) {
  switch (flash_type) {
  case 4:
    return "MB90F497G";
  case 12:
    return "LPC_IAP";
  case 14:
    return "M32C87_1MB";
  case 16:
    return "LPC23xx_256k";
  case 20:
    return "USB_PRO_FD_Flash";
  case 21:
    return "USB_FD_Flash";
  case 22:
    return "LPC407X_8X";
  case 40:
    return "FLASH_ROUTER_FD";
  default:
    return "unkown";
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<flash_name>:
  endbr64
  sub    $0x4,%edi
  cmp    $0x24,%edi
  ja     L8
  mov    %edi,%edi
  lea    D62(%rip),%rdx
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  lea    D15(%rip),%rax
  ret
  lea    D19(%rip),%rax
  ret
  lea    D89(%rip),%rax
  ret
  lea    D36(%rip),%rax
  ret
  lea    D45(%rip),%rax
  ret
  lea    D64(%rip),%rax
  ret
  lea    D26(%rip),%rax
  ret
L8:
  lea    D21(%rip),%rax
  ret
  lea    D91(%rip),%rax
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type_infered: string
name: unpack_data
arguments: data_label: D19
type_infered: string
name: unpack_data
arguments: data_label: D89
type_infered: string
name: unpack_data
arguments: data_label: D36
type_infered: string
name: unpack_data
arguments: data_label: D45
type_infered: string
name: unpack_data
arguments: data_label: D64
type_infered: string
name: unpack_data
arguments: data_label: D26
type_infered: string
name: unpack_data
arguments: data_label: D21
type_infered: string
name: unpack_data
arguments: data_label: D91
type_infered: string

tool: D15: LPC_IAP

tool: D19: M32C87_1MB

tool: D89: LPC23xx_256k

tool: D36: USB_PRO_FD_Flash

tool: D45: USB_FD_Flash

tool: D64: LPC407X_8X

tool: D26: FLASH_ROUTER_FD

tool: D21: unkown

tool: D91: MB90F497G

assistant: ```c
const char *flash_name(uint8_t flash_type) {
  switch (flash_type) {
  case 4:
    return "MB90F497G";
  case 12:
    return "LPC_IAP";
  case 14:
    return "M32C87_1MB";
  case 16:
    return "LPC23xx_256k";
  case 20:
    return "USB_PRO_FD_Flash";
  case 21:
    return "USB_FD_Flash";
  case 22:
    return "LPC407X_8X";
  case 40:
    return "FLASH_ROUTER_FD";
  default:
    return "unkown";
  }
}
```