ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  divsd  D5(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D5
datatype: f64

tool: D5: 1000000

assistant: ```c
double now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + tv.tv_usec / 1000000.;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  divsd  D1(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D1
datatype: f64

tool: D1: 1000000

assistant: ```c
double now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + tv.tv_usec / 1000000.;
}
```
user: What is the c source code of the assembly code below:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sdl 0x8(%rsp),%xmm0
  divsd  D4(%rip),%xmm0
  addsd  (%rsp),%xmm0
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D4
type_infered: f64

tool: D4: 1000000

assistant: ```c
double now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  return tv.tv_sec + tv.tv_usec / 1000000.;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<icvTransposeMatrix_64d>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    %rcx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L13
L2:
  movl   $0x0,-0x4(%rbp)
  jmp    L19
L15:
  mov    -0x4(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rcx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jl     L15
  addl   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void icvTransposeMatrix_64d(const double *src, int w, int h, double *dst) {
  int i, j;
  for (i = 0; i < w; i++)
    for (j = 0; j < h; j++)
      *dst++ = src[j * w + i];
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<icvTransposeMatrix_64d>:
  endbr64
  mov    %esi,%r10d
  test   %esi,%esi
  jle    L9
  movslq %esi,%r8
  shl    $0x3,%r8
  lea    -0x1(%rdx),%eax
  lea    0x8(,%rax,8),%r11
  mov    $0x0,%r9d
  jmp    L21
L19:
  add    $0x8,%rcx
  movsd  (%rax),%xmm0
  movsd  %xmm0,-0x8(%rcx)
  add    %r8,%rax
  cmp    %rsi,%rcx
  jne    L19
  mov    %rsi,%rcx
L7:
  add    $0x1,%r9d
  add    $0x8,%rdi
  cmp    %r9d,%r10d
  je     L9
L21:
  lea    (%rcx,%r11,1),%rsi
  mov    %rdi,%rax
  test   %edx,%edx
  jg     L19
  jmp    L7
L9:
  ret
```

assistant: ```c
void icvTransposeMatrix_64d(const double *src, int w, int h, double *dst) {
  int i, j;
  for (i = 0; i < w; i++)
    for (j = 0; j < h; j++)
      *dst++ = src[j * w + i];
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<icvTransposeMatrix_64d>:
  endbr64
  mov    %esi,%r10d
  test   %esi,%esi
  jle    L13
  movslq %esi,%r8
  lea    -0x1(%rdx),%eax
  xor    %r9d,%r9d
  shl    $0x3,%r8
  lea    0x8(,%rax,8),%r11
L22:
  lea    (%rcx,%r11,1),%rsi
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L27
  nopl   0x0(%rax,%rax,1)
L9:
  movsd  (%rax),%xmm0
  add    $0x8,%rcx
  add    %r8,%rax
  movsd  %xmm0,-0x8(%rcx)
  cmp    %rsi,%rcx
  jne    L9
L27:
  add    $0x1,%r9d
  add    $0x8,%rdi
  cmp    %r9d,%r10d
  jne    L22
L13:
  ret
```

assistant: ```c
void icvTransposeMatrix_64d(const double *src, int w, int h, double *dst) {
  int i, j;
  for (i = 0; i < w; i++)
    for (j = 0; j < h; j++)
      *dst++ = src[j * w + i];
  ;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<icvTransposeMatrix_64d>:
  endbr64
  mov    %esi,%r11d
  test   %esi,%esi
  jle    L43
  test   %edx,%edx
  jle    L43
  movslq %edx,%rdx
  movslq %esi,%rsi
  xor    %r8d,%r8d
  lea    0x0(,%rdx,8),%r10
  shl    $0x3,%rsi
  lea    (%rcx,%r10,1),%r9
  mov    %r9,%rdx
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %rdi,%rax
  nopl   0x0(%rax,%rax,1)
L16:
  movsd  (%rax),%xmm0
  add    $0x8,%rcx
  add    %rsi,%rax
  movsd  %xmm0,-0x8(%rcx)
  cmp    %rdx,%rcx
  jne    L16
  add    $0x1,%r8d
  mov    %r9,%rcx
  add    %r10,%rdx
  add    $0x8,%rdi
  cmp    %r8d,%r11d
  je     L43
  add    %r10,%r9
  jmp    L13
  nopl   (%rax)
L43:
  ret
```

assistant: ```c
void icvTransposeMatrix_64d(const double *src, int w, int h, double *dst) {
  int i, j;
  for (i = 0; i < w; i++)
    for (j = 0; j < h; j++)
      *dst++ = src[j * w + i];
  ;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_index_aux>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  mov    %edi,-0x24(%rbp)
  movsd  %xmm2,-0x30(%rbp)
  movsd  -0x30(%rbp),%xmm0
  subsd  -0x18(%rbp),%xmm0
  mulsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <lfloor@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L2
  mov    -0x24(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  cmovbe %edx,%eax
  jmp    L5
L2:
  mov    $0x0,%eax
L5:
  leave
  ret
```

assistant: ```c
unsigned int hash_index_aux(double low, double fac, unsigned int n, double x) {
  const signed int i = lfloor((x - low) * fac);
  return i < 0 ? 0 : (n - 1 < (unsigned int)i ? n - 1 : (unsigned int)i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hash_index_aux>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  subsd  %xmm0,%xmm2
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  call   <lfloor@plt>
  lea    -0x1(%rbx),%edi
  cmp    %eax,%edi
  cmova  %eax,%edi
  test   %eax,%eax
  mov    $0x0,%eax
  cmovns %edi,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int hash_index_aux(double low, double fac, unsigned int n, double x) {
  const signed int i = lfloor((x - low) * fac);
  return i < 0 ? 0 : (n - 1 < (unsigned int)i ? n - 1 : (unsigned int)i);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hash_index_aux>:
  endbr64
  subsd  %xmm0,%xmm2
  push   %rbx
  mov    %edi,%ebx
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  call   <lfloor@plt>
  lea    -0x1(%rbx),%edi
  pop    %rbx
  cmp    %eax,%edi
  cmova  %eax,%edi
  test   %eax,%eax
  mov    $0x0,%eax
  cmovns %edi,%eax
  ret
```

assistant: ```c
unsigned int hash_index_aux(double low, double fac, unsigned int n, double x) {
  const signed int i = lfloor((x - low) * fac);
  return i < 0 ? 0 : (n - 1 < (unsigned int)i ? n - 1 : (unsigned int)i);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash_index_aux>:
  endbr64
  subsd  %xmm0,%xmm2
  push   %rbx
  mov    %edi,%ebx
  mulsd  %xmm1,%xmm2
  movapd %xmm2,%xmm0
  call   <lfloor@plt>
  lea    -0x1(%rbx),%edi
  pop    %rbx
  cmp    %eax,%edi
  cmova  %eax,%edi
  test   %eax,%eax
  mov    $0x0,%eax
  cmovns %edi,%eax
  ret
```

assistant: ```c
unsigned int hash_index_aux(double low, double fac, unsigned int n, double x) {
  const signed int i = lfloor((x - low) * fac);
  return i < 0 ? 0 : (n - 1 < (unsigned int)i ? n - 1 : (unsigned int)i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<b>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D13(%rip),%rax
  movl   $0x0,(%rax)
  mov    D1(%rip),%rax
  movl   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void b() {
  extern int ff;
  ff = 0;
  extern int gg;
  gg = 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<b>:
  endbr64
  mov    D6(%rip),%rax
  movl   $0x0,(%rax)
  mov    D18(%rip),%rax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void b() {
  extern int ff;
  ff = 0;
  extern int gg;
  gg = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<b>:
  endbr64
  mov    D18(%rip),%rax
  movl   $0x0,(%rax)
  mov    D12(%rip),%rax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void b() {
  extern int ff;
  ff = 0;
  extern int gg;
  gg = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<b>:
  endbr64
  mov    D8(%rip),%rax
  movl   $0x0,(%rax)
  mov    D17(%rip),%rax
  movl   $0x0,(%rax)
  ret
```

assistant: ```c
void b() {
  extern int ff;
  ff = 0;
  extern int gg;
  gg = 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<elevation_from_hour_angle>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  %xmm2,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <radians@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x28(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <cos@plt>
  mulsd  -0x30(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <radians@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  movsd  %xmm0,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  movq   %rax,%xmm0
  call   <sin@plt>
  mulsd  -0x30(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <asin@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double elevation_from_hour_angle(double latitude, double declination, double hour_angle) {
  double rc = cos(radians(latitude));
  rc *= cos(hour_angle) * cos(declination);
  rc += sin(radians(latitude)) * sin(declination);
  return asin(rc);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<elevation_from_hour_angle>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  movq   %xmm0,%rbp
  movapd %xmm1,%xmm0
  movq   %xmm2,%r13
  lea    0x18(%rsp),%rdi
  lea    0x10(%rsp),%rsi
  call   <sincos@plt>
  mov    0x10(%rsp),%r12
  mov    0x18(%rsp),%rbx
  movq   %rbp,%xmm0
  call   <radians@plt>
  call   <cos@plt>
  movq   %xmm0,%r14
  movq   %r13,%xmm0
  call   <cos@plt>
  movq   %r12,%xmm3
  mulsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  movq   %r14,%xmm6
  mulsd  %xmm6,%xmm0
  movsd  %xmm0,0x8(%rsp)
  movq   %rbp,%xmm0
  call   <radians@plt>
  call   <sin@plt>
  movq   %rbx,%xmm5
  mulsd  %xmm0,%xmm5
  movapd %xmm5,%xmm0
  addsd  0x8(%rsp),%xmm0
  call   <asin@plt>
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
double elevation_from_hour_angle(double latitude, double declination, double hour_angle) {
  double rc = cos(radians(latitude));
  rc *= cos(hour_angle) * cos(declination);
  rc += sin(radians(latitude)) * sin(declination);
  return asin(rc);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<elevation_from_hour_angle>:
  endbr64
  sub    $0x48,%rsp
  lea    0x38(%rsp),%rdi
  lea    0x30(%rsp),%rsi
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x28(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm5
  movsd  0x38(%rsp),%xmm6
  movapd %xmm3,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  call   <radians@plt>
  call   <cos@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <cos@plt>
  mulsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  mulsd  %xmm0,%xmm4
  movapd %xmm3,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <radians@plt>
  call   <sin@plt>
  mulsd  0x18(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x48,%rsp
  jmp    10d0 <asin@plt>
```

assistant: ```c
double elevation_from_hour_angle(double latitude, double declination, double hour_angle) {
  double rc = cos(radians(latitude));
  rc *= cos(hour_angle) * cos(declination);
  rc += sin(radians(latitude)) * sin(declination);
  return asin(rc);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<elevation_from_hour_angle>:
  endbr64
  sub    $0x48,%rsp
  lea    0x38(%rsp),%rdi
  lea    0x30(%rsp),%rsi
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm1,%xmm0
  movsd  %xmm2,0x28(%rsp)
  call   <sincos@plt>
  movsd  0x8(%rsp),%xmm3
  movsd  0x30(%rsp),%xmm5
  movsd  0x38(%rsp),%xmm6
  movapd %xmm3,%xmm0
  movsd  %xmm5,0x10(%rsp)
  movsd  %xmm6,0x18(%rsp)
  movsd  %xmm3,0x20(%rsp)
  call   <radians@plt>
  call   <cos@plt>
  movsd  0x28(%rsp),%xmm2
  movsd  %xmm0,0x8(%rsp)
  movapd %xmm2,%xmm0
  call   <cos@plt>
  mulsd  0x10(%rsp),%xmm0
  movsd  0x8(%rsp),%xmm4
  movsd  0x20(%rsp),%xmm3
  mulsd  %xmm0,%xmm4
  movapd %xmm3,%xmm0
  movsd  %xmm4,0x8(%rsp)
  call   <radians@plt>
  call   <sin@plt>
  mulsd  0x18(%rsp),%xmm0
  addsd  0x8(%rsp),%xmm0
  add    $0x48,%rsp
  jmp    10d0 <asin@plt>
```

assistant: ```c
double elevation_from_hour_angle(double latitude, double declination, double hour_angle) {
  double rc = cos(radians(latitude));
  rc *= cos(hour_angle) * cos(declination);
  rc += sin(radians(latitude)) * sin(declination);
  return asin(rc);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  mov    %eax,-0x10(%rbp)
  movl   $0x6,-0x8(%rbp)
  movl   $0x6,-0xc(%rbp)
  movl   $0x8,-0x4(%rbp)
  cmpl   $0x6,-0x10(%rbp)
  jne    L37
  movl   $0x7,-0x10(%rbp)
  jmp    L31
L37:
  movl   $0x4,-0xc(%rbp)
L31:
  cmpl   $0x63,-0x10(%rbp)
  jne    L51
  mov    $0x21,%eax
  jmp    L8
L51:
  cmpl   $0x6,-0x10(%rbp)
  jne    L28
  cmpl   $0x6,-0x8(%rbp)
  jne    L28
  cmpl   $0x6,-0xc(%rbp)
  jne    L28
  cmpl   $0x6,-0x4(%rbp)
  je     L74
L28:
  movl   $0x21,-0x10(%rbp)
  mov    $0x1,%eax
  jmp    L8
L74:
  nop
L47:
  jmp    L47
L8:
  leave
  ret
```

assistant: ```c
int main() {
  int a = random();
  int b = 6;
  int c = 6;
  int d = 8;
  if (a == 6) {
    a = 7;
  } else {
    c = 4;
  }
  if (c == 5) {
  }
  if (a == 99) {
    return 33;
  }
  if (!(a == 6 && b == 6 && c == 6 && d == 6)) {
    a = 33;
  } else {
  ERROR:
    goto ERROR;
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <random@plt>
  cmp    $0x63,%eax
  mov    $0x21,%eax
  mov    $0x1,%edx
  cmovne %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = random();
  int b = 6;
  int c = 6;
  int d = 8;
  if (a == 6) {
    a = 7;
  } else {
    c = 4;
  }
  if (c == 5) {
  }
  if (a == 99) {
    return 33;
  }
  if (!(a == 6 && b == 6 && c == 6 && d == 6)) {
    a = 33;
  } else {
  ERROR:
    goto ERROR;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <random@plt>
  mov    $0x21,%edx
  cmp    $0x63,%eax
  mov    $0x1,%eax
  cmove  %edx,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int a = random();
  int b = 6;
  int c = 6;
  int d = 8;
  if (a == 6) {
    a = 7;
  } else {
    c = 4;
  }
  if (c == 5) {
  }
  if (a == 99) {
    return 33;
  }
  if (!(a == 6 && b == 6 && c == 6 && d == 6)) {
    a = 33;
  } else {
  ERROR:
    goto ERROR;
  }
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<acquire_memory>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L6
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <plotz@plt>
L6:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
type_infered: string

tool: D5: acquire_memory malloc

assistant: ```c
char *acquire_memory(int bytes) {
  char *p = malloc(bytes);
  if (p == NULL)
    plotz("acquire_memory malloc");
  return p;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<acquire_memory>:
  endbr64
  push   %rbx
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L19
L12:
  mov    %rbx,%rax
  pop    %rbx
  ret
L19:
  lea    D9(%rip),%rdi
  call   <plotz@plt>
  jmp    L12
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D9: acquire_memory malloc

assistant: ```c
char *acquire_memory(int bytes) {
  char *p = malloc(bytes);
  if (p == NULL)
    plotz("acquire_memory malloc");
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<acquire_memory>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L9
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  lea    D5(%rip),%rdi
  call   <plotz@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D5: acquire_memory malloc

assistant: ```c
char *acquire_memory(int bytes) {
  char *p = malloc(bytes);
  if (p == NULL)
    plotz("acquire_memory malloc");
  return p;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<acquire_memory>:
  endbr64
  push   %r12
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L2
  mov    %r12,%rax
  pop    %r12
  ret
  nopl   0x0(%rax)
L2:
  lea    D3(%rip),%rdi
  call   <plotz@plt>
  mov    %r12,%rax
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: acquire_memory malloc

assistant: ```c
char *acquire_memory(int bytes) {
  char *p = malloc(bytes);
  if (p == NULL)
    plotz("acquire_memory malloc");
  return p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<diversifiedInitializeUpdate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    %rcx,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  lea    D11(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x20(%rbp),%rax
  lea    D12(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x20(%rbp),%rax
  lea    D28(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D11
datatype: string
name: extract_symbolic_data
arguments: data_label: D12
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string

tool: 

tool: D12: d050

tool: D28: 1018

assistant: ```c
void diversifiedInitializeUpdate(char *keysetId, char *hostChallenge, char *masterKeyDiversifier, char *d_init_up_apdu) {
  strcpy(d_init_up_apdu, "");
  strcat(d_init_up_apdu, "d050");
  strcat(d_init_up_apdu, keysetId);
  strcat(d_init_up_apdu, "1018");
  strcat(d_init_up_apdu, hostChallenge);
  strcat(d_init_up_apdu, masterKeyDiversifier);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<diversifiedInitializeUpdate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    %rdx,%rbp
  mov    %rcx,%rbx
  lea    D24(%rip),%rsi
  mov    %rcx,%rdi
  call   <strcpy@plt>
  lea    D6(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  lea    D26(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D24
data_type: string
name: read_data
arguments: tag: D6
data_type: string
name: read_data
arguments: tag: D26
data_type: string

tool: 

tool: D6: d050

tool: D26: 1018

assistant: ```c
void diversifiedInitializeUpdate(char *keysetId, char *hostChallenge, char *masterKeyDiversifier, char *d_init_up_apdu) {
  strcpy(d_init_up_apdu, "");
  strcat(d_init_up_apdu, "d050");
  strcat(d_init_up_apdu, keysetId);
  strcat(d_init_up_apdu, "1018");
  strcat(d_init_up_apdu, hostChallenge);
  strcat(d_init_up_apdu, masterKeyDiversifier);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<diversifiedInitializeUpdate>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rcx,%rdi
  push   %r13
  mov    %rsi,%r13
  lea    D9(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D8(%rip),%rsi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  lea    D17(%rip),%rsi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strcat@plt>
```

tool_calls: name: read_data
arguments: tag: D9
type_infered: string
name: read_data
arguments: tag: D8
type_infered: string
name: read_data
arguments: tag: D17
type_infered: string

tool: 

tool: D8: d050

tool: D17: 1018

assistant: ```c
void diversifiedInitializeUpdate(char *keysetId, char *hostChallenge, char *masterKeyDiversifier, char *d_init_up_apdu) {
  strcpy(d_init_up_apdu, "");
  strcat(d_init_up_apdu, "d050");
  strcat(d_init_up_apdu, keysetId);
  strcat(d_init_up_apdu, "1018");
  strcat(d_init_up_apdu, hostChallenge);
  strcat(d_init_up_apdu, masterKeyDiversifier);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<diversifiedInitializeUpdate>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  mov    %rcx,%rdi
  push   %r13
  mov    %rsi,%r13
  lea    D23(%rip),%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rcx,%rbp
  sub    $0x8,%rsp
  call   <strcpy@plt>
  mov    %rbp,%rdi
  lea    D5(%rip),%rsi
  call   <strcat@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  mov    %rbp,%rdi
  lea    D0(%rip),%rsi
  call   <strcat@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcat@plt>
  add    $0x8,%rsp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1070 <strcat@plt>
```

tool_calls: name: parse_data
arguments: tag: D23
type_guessed: string
name: parse_data
arguments: tag: D5
type_guessed: string
name: parse_data
arguments: tag: D0
type_guessed: string

tool: 

tool: D5: d050

tool: D0: 1018

assistant: ```c
void diversifiedInitializeUpdate(char *keysetId, char *hostChallenge, char *masterKeyDiversifier, char *d_init_up_apdu) {
  strcpy(d_init_up_apdu, "");
  strcat(d_init_up_apdu, "d050");
  strcat(d_init_up_apdu, keysetId);
  strcat(d_init_up_apdu, "1018");
  strcat(d_init_up_apdu, hostChallenge);
  strcat(d_init_up_apdu, masterKeyDiversifier);
}
```