ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<parse_assem1>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <atoi@plt>
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L0
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  shl    $0x10,%eax
  add    %r8d,%eax
  movslq %eax,%r8
L0:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long parse_assem1(char *str) {
  int highval, lowval;
  highval = atoi(str);
  str = strchr(str, ',');
  if (str)
    lowval = atoi(str + 1);
  else {
    return 0;
  }
  return (unsigned long long)((highval << 16) + lowval);
}
```
user: Translate the below assembly code into C programming language:

```asm
<parse_assem1>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <atoi@plt>
  mov    $0x2c,%esi
  mov    %rbp,%rdi
  mov    %eax,%ebx
  call   <strchr@plt>
  xor    %r8d,%r8d
  test   %rax,%rax
  je     L2
  lea    0x1(%rax),%rdi
  call   <atoi@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  shl    $0x10,%eax
  add    %r8d,%eax
  movslq %eax,%r8
L2:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
unsigned long long parse_assem1(char *str) {
  int highval, lowval;
  highval = atoi(str);
  str = strchr(str, ',');
  if (str)
    lowval = atoi(str + 1);
  else {
    return 0;
  }
  return (unsigned long long)((highval << 16) + lowval);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<rotr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap;
  swap = *b;
  *b = *a;
  *a = *c;
  *c = swap;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rotr>:
  endbr64
  mov    (%rsi),%eax
  mov    (%rdi),%ecx
  mov    %ecx,(%rsi)
  mov    (%rdx),%ecx
  mov    %ecx,(%rdi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap;
  swap = *b;
  *b = *a;
  *a = *c;
  *c = swap;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<rotr>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    (%rdx),%ecx
  mov    %ecx,(%rdi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap;
  swap = *b;
  *b = *a;
  *a = *c;
  *c = swap;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rotr>:
  endbr64
  mov    (%rdi),%ecx
  mov    (%rsi),%eax
  mov    %ecx,(%rsi)
  mov    (%rdx),%ecx
  mov    %ecx,(%rdi)
  mov    %eax,(%rdx)
  ret
```

assistant: ```c
void rotr(int *a, int *b, int *c) {
  int swap;
  swap = *b;
  *b = *a;
  *a = *c;
  *c = swap;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<dll_create_generic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x10(%rbp)
  lea    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rdx
  lea    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rdx
  jmp    L25
L21:
  lea    -0x10(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   *%rdx
L25:
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L21
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void *dll_create_generic(void (*insert_fnc)()) {
  void *dll = NULL;
  insert_fnc(&dll);
  insert_fnc(&dll);
  while (___sl_get_nondet_int())
    insert_fnc(&dll);
  return dll;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<dll_create_generic>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rdi
  call   *%rbx
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   *%rbx
  jmp    L4
L18:
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   *%rbx
L4:
  mov    $0x0,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L18
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L21:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *dll_create_generic(void (*insert_fnc)()) {
  void *dll = NULL;
  insert_fnc(&dll);
  insert_fnc(&dll);
  while (___sl_get_nondet_int())
    insert_fnc(&dll);
  return dll;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<dll_create_generic>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   *%rbx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   *%rbx
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L20:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   *%rbx
L25:
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L20
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *dll_create_generic(void (*insert_fnc)()) {
  void *dll = NULL;
  insert_fnc(&dll);
  insert_fnc(&dll);
  while (___sl_get_nondet_int())
    insert_fnc(&dll);
  return dll;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<dll_create_generic>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x0,(%rsp)
  mov    %rbp,%rdi
  call   *%rbx
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   *%rbx
  jmp    L28
  cs nopw 0x0(%rax,%rax,1)
L17:
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   *%rbx
L28:
  xor    %eax,%eax
  call   <___sl_get_nondet_int@plt>
  test   %rax,%rax
  jne    L17
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void *dll_create_generic(void (*insert_fnc)()) {
  void *dll = NULL;
  insert_fnc(&dll);
  insert_fnc(&dll);
  while (___sl_get_nondet_int())
    insert_fnc(&dll);
  return dll;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_latency_stats>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void print_latency_stats(FILE *log_fp, int thd_id) {
  (void)log_fp;
  (void)thd_id;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_latency_stats>:
  endbr64
  ret
```

assistant: ```c
void print_latency_stats(FILE *log_fp, int thd_id) {
  (void)log_fp;
  (void)thd_id;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_latency_stats>:
  endbr64
  ret
```

assistant: ```c
void print_latency_stats(FILE *log_fp, int thd_id) {
  (void)log_fp;
  (void)thd_id;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_latency_stats>:
  endbr64
  ret
```

assistant: ```c
void print_latency_stats(FILE *log_fp, int thd_id) {
  (void)log_fp;
  (void)thd_id;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<all_factors>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,%edi
  call   <sqrt@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L2
L49:
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L6
  mov    -0x14(%rbp),%eax
  imul   %eax,%eax
  cmp    %eax,-0x24(%rbp)
  jne    L32
  addl   $0x1,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L6
L32:
  addl   $0x2,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x18(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  sub    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x24(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %eax,(%rcx)
L6:
  addl   $0x1,-0x14(%rbp)
L2:
  mov    -0x14(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L49
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%esi
  mov    -0xc(%rbp),%eax
  add    %eax,%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,%ecx
  shr    $0x1f,%ecx
  add    %ecx,%eax
  sar    %eax
  movslq %eax,%rcx
  mov    %rdx,%rax
  sub    %rcx,%rax
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %esi,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x10(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    -0x30(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%eax
  leave
  ret
```

assistant: ```c
int all_factors(int n, int **ff) {
  int i, d, nf;
  int s = sqrt(n);
  int *f = malloc(2 * s * sizeof(int));
  i = nf = 0;
  for (d = 1; d <= s; d++) {
    if (n % d == 0) {
      if (d * d == n) {
        nf++;
        f[i++] = d;
      } else {
        nf += 2;
        f[i++] = d;
        f[2 * s - i] = n / d;
      }
    }
  }
  memcpy(f + i, f + 2 * s - (nf / 2), (nf / 2) * sizeof(int));
  *ff = realloc(f, nf * sizeof(int));
  return nf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<all_factors>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    %rsi,%r14
  call   <sqrt@plt>
  mov    %eax,%ebp
  lea    (%rax,%rax,1),%r13d
  movslq %r13d,%r15
  lea    0x0(,%r13,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  test   %ebp,%ebp
  jle    L20
  lea    0x1(%rbp),%edi
  mov    $0x0,%ebp
  mov    $0x1,%ecx
  mov    $0x0,%esi
  jmp    L42
L9:
  add    $0x1,%ebp
  movslq %esi,%rax
  mov    %ecx,(%r12,%rax,4)
  lea    0x1(%rsi),%esi
L22:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  je     L2
L42:
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L22
  mov    %ecx,%eax
  imul   %ecx,%eax
  cmp    %ebx,%eax
  je     L9
  add    $0x2,%ebp
  lea    0x1(%rsi),%r8d
  movslq %esi,%rsi
  mov    %ecx,(%r12,%rsi,4)
  mov    %r13d,%esi
  sub    %r8d,%esi
  movslq %esi,%rsi
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  mov    %eax,(%r12,%rsi,4)
  mov    %r8d,%esi
  jmp    L22
L20:
  mov    $0x0,%ebp
  mov    $0x0,%esi
L2:
  mov    %ebp,%edx
  shr    $0x1f,%edx
  add    %ebp,%edx
  sar    %edx
  movslq %edx,%rax
  shl    $0x2,%edx
  sub    %rax,%r15
  lea    (%r12,%r15,4),%rax
  movslq %esi,%rsi
  lea    (%r12,%rsi,4),%rdi
  mov    %rax,%rsi
  call   <memcpy@plt>
  lea    0x0(,%rbp,4),%esi
  mov    %r12,%rdi
  call   <realloc@plt>
  mov    %rax,(%r14)
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int all_factors(int n, int **ff) {
  int i, d, nf;
  int s = sqrt(n);
  int *f = malloc(2 * s * sizeof(int));
  i = nf = 0;
  for (d = 1; d <= s; d++) {
    if (n % d == 0) {
      if (d * d == n) {
        nf++;
        f[i++] = d;
      } else {
        nf += 2;
        f[i++] = d;
        f[2 * s - i] = n / d;
      }
    }
  }
  memcpy(f + i, f + 2 * s - (nf / 2), (nf / 2) * sizeof(int));
  *ff = realloc(f, nf * sizeof(int));
  return nf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<all_factors>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  lea    0x0(,%rax,8),%edi
  lea    (%rax,%rax,1),%r15d
  mov    %eax,%r13d
  call   <malloc@plt>
  movslq %r15d,%r14
  mov    %rax,%rbp
  test   %r13d,%r13d
  jle    L27
  lea    0x1(%r13),%edi
  mov    $0x1,%ecx
  xor    %r13d,%r13d
  xor    %esi,%esi
  jmp    L65
  nop
L37:
  mov    %r15d,%edx
  mov    %ecx,(%r8)
  add    $0x2,%r13d
  sub    %esi,%edx
  movslq %edx,%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
L36:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  je     L61
L65:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L36
  movslq %esi,%rdx
  add    $0x1,%esi
  lea    0x0(%rbp,%rdx,4),%r8
  mov    %ecx,%edx
  imul   %ecx,%edx
  cmp    %r12d,%edx
  jne    L37
  mov    %ecx,(%r8)
  add    $0x1,%ecx
  add    $0x1,%r13d
  cmp    %edi,%ecx
  jne    L65
  nopw   0x0(%rax,%rax,1)
L61:
  mov    %r13d,%eax
  movslq %esi,%rsi
  lea    0x0(,%r13,4),%r12d
  sar    %eax
  lea    0x0(%rbp,%rsi,4),%rdi
  lea    0x0(,%rax,4),%edx
  cltq
  sub    %rax,%r14
L17:
  lea    0x0(%rbp,%r14,4),%rsi
  call   <memcpy@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rax,%rdi
  xor    %r12d,%r12d
  xor    %edx,%edx
  xor    %r13d,%r13d
  jmp    L17
```

assistant: ```c
int all_factors(int n, int **ff) {
  int i, d, nf;
  int s = sqrt(n);
  int *f = malloc(2 * s * sizeof(int));
  i = nf = 0;
  for (d = 1; d <= s; d++) {
    if (n % d == 0) {
      if (d * d == n) {
        nf++;
        f[i++] = d;
      } else {
        nf += 2;
        f[i++] = d;
        f[2 * s - i] = n / d;
      }
    }
  }
  memcpy(f + i, f + 2 * s - (nf / 2), (nf / 2) * sizeof(int));
  *ff = realloc(f, nf * sizeof(int));
  return nf;
}
```
user: What is the c source code of the assembly code below:

```asm
<all_factors>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  sub    $0x8,%rsp
  call   <sqrt@plt>
  lea    0x0(,%rax,8),%edi
  lea    (%rax,%rax,1),%r15d
  mov    %eax,%r13d
  call   <malloc@plt>
  movslq %r15d,%r14
  mov    %rax,%rbp
  test   %r13d,%r13d
  jle    L27
  lea    0x1(%r13),%edi
  mov    $0x1,%ecx
  xor    %r13d,%r13d
  xor    %esi,%esi
  jmp    L17
  nop
L57:
  mov    %r15d,%edx
  mov    %ecx,(%r8)
  add    $0x2,%r13d
  sub    %esi,%edx
  movslq %edx,%rdx
  mov    %eax,0x0(%rbp,%rdx,4)
L12:
  add    $0x1,%ecx
  cmp    %edi,%ecx
  je     L6
L17:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L12
  movslq %esi,%rdx
  add    $0x1,%esi
  lea    0x0(%rbp,%rdx,4),%r8
  mov    %ecx,%edx
  imul   %ecx,%edx
  cmp    %r12d,%edx
  jne    L57
  mov    %ecx,(%r8)
  add    $0x1,%ecx
  add    $0x1,%r13d
  cmp    %edi,%ecx
  jne    L17
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %r13d,%eax
  movslq %esi,%rsi
  lea    0x0(,%r13,4),%r12d
  sar    %eax
  lea    0x0(%rbp,%rsi,4),%rdi
  lea    0x0(,%rax,4),%edx
  cltq
  sub    %rax,%r14
L11:
  lea    0x0(%rbp,%r14,4),%rsi
  call   <memcpy@plt>
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rax,%rdi
  xor    %r12d,%r12d
  xor    %edx,%edx
  xor    %r13d,%r13d
  jmp    L11
```

assistant: ```c
int all_factors(int n, int **ff) {
  int i, d, nf;
  int s = sqrt(n);
  int *f = malloc(2 * s * sizeof(int));
  i = nf = 0;
  for (d = 1; d <= s; d++) {
    if (n % d == 0) {
      if (d * d == n) {
        nf++;
        f[i++] = d;
      } else {
        nf += 2;
        f[i++] = d;
        f[2 * s - i] = n / d;
      }
    }
  }
  memcpy(f + i, f + 2 * s - (nf / 2), (nf / 2) * sizeof(int));
  *ff = realloc(f, nf * sizeof(int));
  return nf;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_url_encoded_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L35:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <is_valid_url_char@plt>
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rdi
  mov    %eax,%ecx
  lea    D6(%rip),%rax
  mov    %rax,%rdx
  call   <snprintf@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L4
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  sub    %rcx,%rsi
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rdx,%rcx
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <print_url_encoded_char@plt>
  mov    %eax,%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
L4:
  addq   $0x1,-0x8(%rbp)
L38:
  mov    -0x28(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  cmp    %rax,-0x8(%rbp)
  jb     L35
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D6
datatype: string

tool: D6: %1c

assistant: ```c
int print_url_encoded_str(char *out, size_t n, const unsigned char *orig, size_t olen) {
  int written = 0;
  for (const unsigned char *i = orig; i < orig + olen; i++) {
    if (is_valid_url_char(*i))
      written += snprintf(out + written, n - written, "%1c", (char)(*i));
    else
      written += print_url_encoded_char(out + written, n - written, *i);
  }
  return written;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_url_encoded_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  lea    (%rdx,%rcx,1),%r12
  cmp    %r12,%rdx
  jae    L41
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbx
  mov    $0x0,%ebp
  lea    D8(%rip),%r15
  jmp    L17
L45:
  movslq %ebp,%rdi
  movzbl (%rbx),%edx
  mov    %r14,%rsi
  sub    %rdi,%rsi
  add    %r13,%rdi
  call   <print_url_encoded_char@plt>
  add    %eax,%ebp
L16:
  add    $0x1,%rbx
  cmp    %r12,%rbx
  je     L24
L17:
  movzbl (%rbx),%edi
  call   <is_valid_url_char@plt>
  test   %rax,%rax
  je     L45
  movslq %ebp,%rdi
  movsbl (%rbx),%ecx
  mov    %r14,%rsi
  sub    %rdi,%rsi
  add    %r13,%rdi
  mov    %r15,%rdx
  call   <snprintf@plt>
  add    %eax,%ebp
  jmp    L16
L41:
  mov    $0x0,%ebp
L24:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %1c

assistant: ```c
int print_url_encoded_str(char *out, size_t n, const unsigned char *orig, size_t olen) {
  int written = 0;
  for (const unsigned char *i = orig; i < orig + olen; i++) {
    if (is_valid_url_char(*i))
      written += snprintf(out + written, n - written, "%1c", (char)(*i));
    else
      written += print_url_encoded_char(out + written, n - written, *i);
  }
  return written;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_url_encoded_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    (%rdx,%rcx,1),%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rbp,%rdx
  jae    L53
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  lea    D7(%rip),%r15
  jmp    L59
L23:
  movsbl (%rbx),%ecx
  mov    %r15,%rdx
  add    $0x1,%rbx
  call   <snprintf@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  je     L32
L59:
  movzbl (%rbx),%edi
  call   <is_valid_url_char@plt>
  movslq %r12d,%rdi
  mov    %r14,%rsi
  sub    %rdi,%rsi
  add    %r13,%rdi
  test   %rax,%rax
  jne    L23
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  call   <print_url_encoded_char@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L59
L32:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L53:
  xor    %r12d,%r12d
  jmp    L32
```

tool_calls: name: read_data
arguments: data_label: D7
datatype: string

tool: D7: %1c

assistant: ```c
int print_url_encoded_str(char *out, size_t n, const unsigned char *orig, size_t olen) {
  int written = 0;
  for (const unsigned char *i = orig; i < orig + olen; i++) {
    if (is_valid_url_char(*i))
      written += snprintf(out + written, n - written, "%1c", (char)(*i));
    else
      written += print_url_encoded_char(out + written, n - written, *i);
  }
  return written;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_url_encoded_str>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    (%rdx,%rcx,1),%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %rbp,%rdx
  jae    L29
  mov    %rdi,%r13
  mov    %rsi,%r14
  mov    %rdx,%rbx
  xor    %r12d,%r12d
  lea    D4(%rip),%r15
  jmp    L5
L13:
  movsbl (%rbx),%ecx
  mov    %r15,%rdx
  add    $0x1,%rbx
  call   <snprintf@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  je     L59
L5:
  movzbl (%rbx),%edi
  call   <is_valid_url_char@plt>
  movslq %r12d,%rdi
  mov    %r14,%rsi
  sub    %rdi,%rsi
  add    %r13,%rdi
  test   %rax,%rax
  jne    L13
  movzbl (%rbx),%edx
  add    $0x1,%rbx
  call   <print_url_encoded_char@plt>
  add    %eax,%r12d
  cmp    %rbp,%rbx
  jne    L5
L59:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L29:
  xor    %r12d,%r12d
  jmp    L59
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_guessed: string

tool: D4: %1c

assistant: ```c
int print_url_encoded_str(char *out, size_t n, const unsigned char *orig, size_t olen) {
  int written = 0;
  for (const unsigned char *i = orig; i < orig + olen; i++) {
    if (is_valid_url_char(*i))
      written += snprintf(out + written, n - written, "%1c", (char)(*i));
    else
      written += print_url_encoded_char(out + written, n - written, *i);
  }
  return written;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<func>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x3,-0x8(%rbp)
  movl   $0x5,-0x4(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  je     L0
  cmpl   $0x0,-0x4(%rbp)
L0:
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n &&m;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<func>:
  endbr64
  mov    $0x0,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n &&m;
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n &&m;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<func>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int func(void) {
  int n = 3;
  int m = 5;
  n &&m;
  return 0;
}
```