ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(int argc, const char *argv[]) {
  long long k, p = 0;
  for (k = 0; k < 10000000000LL; k++)
    p++;
  if (p != k)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isAmPmString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x18(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x14(%rbp)
  movb   $0x0,-0x9(%rbp)
  cmpl   $0x4,-0x14(%rbp)
  jle    L17
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  lea    -0xe(%rbp),%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  movl   $0x0,-0x18(%rbp)
  jmp    L5
L33:
  mov    -0x18(%rbp),%eax
  cltq
  movzbl -0xe(%rbp,%rax,1),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <tolower@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0xe(%rbp,%rdx,1)
  addl   $0x1,-0x18(%rbp)
L5:
  cmpl   $0x4,-0x18(%rbp)
  jle    L33
  lea    -0xe(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L30
L17:
  mov    $0x0,%eax
L30:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
datatype: string

tool: D0: am/pm

assistant: ```c
int isAmPmString(char *format) {
  int i = 0, len = strlen(format);
  char buffer[6];
  buffer[5] = 0;
  if (len > 4) {
    memcpy(buffer, &format[i], 5);
    for (i = 0; i < 5; i++)
      buffer[i] = tolower(buffer[i]);
    return !strcmp(buffer, "am/pm");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<isAmPmString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%edx
  movb   $0x0,0x7(%rsp)
  mov    $0x0,%eax
  cmp    $0x4,%edx
  jg     L1
L28:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  lea    0x2(%rsp),%rbx
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  lea    0x7(%rsp),%rbp
L25:
  movsbl (%rbx),%edi
  call   <tolower@plt>
  mov    %al,(%rbx)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L25
  lea    0x2(%rsp),%rdi
  lea    D5(%rip),%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L28
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_infered: string

tool: D5: am/pm

assistant: ```c
int isAmPmString(char *format) {
  int i = 0, len = strlen(format);
  char buffer[6];
  buffer[5] = 0;
  if (len > 4) {
    memcpy(buffer, &format[i], 5);
    for (i = 0; i < 5; i++)
      buffer[i] = tolower(buffer[i]);
    return !strcmp(buffer, "am/pm");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<isAmPmString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movb   $0x0,0x7(%rsp)
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x4,%r8d
  jg     L28
L38:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L31
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L28:
  lea    0x2(%rsp),%r12
  mov    %rbp,%rsi
  mov    $0x5,%edx
  mov    %r12,%rdi
  mov    %r12,%rbx
  lea    0x7(%rsp),%rbp
  call   <memcpy@plt>
L1:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L1
  lea    D0(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L38
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D0
type_guessed: string

tool: D0: am/pm

assistant: ```c
int isAmPmString(char *format) {
  int i = 0, len = strlen(format);
  char buffer[6];
  buffer[5] = 0;
  if (len > 4) {
    memcpy(buffer, &format[i], 5);
    for (i = 0; i < 5; i++)
      buffer[i] = tolower(buffer[i]);
    return !strcmp(buffer, "am/pm");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<isAmPmString>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  movb   $0x0,0x7(%rsp)
  mov    %eax,%r8d
  xor    %eax,%eax
  cmp    $0x4,%r8d
  jg     L0
L25:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   (%rax)
L0:
  lea    0x2(%rsp),%r12
  mov    %rbp,%rsi
  mov    $0x5,%edx
  mov    %r12,%rdi
  mov    %r12,%rbx
  lea    0x7(%rsp),%rbp
  call   <memcpy@plt>
L39:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <tolower@plt>
  mov    %al,-0x1(%rbx)
  cmp    %rbp,%rbx
  jne    L39
  lea    D3(%rip),%rsi
  mov    %r12,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
  jmp    L25
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D3
type: string

tool: D3: am/pm

assistant: ```c
int isAmPmString(char *format) {
  int i = 0, len = strlen(format);
  char buffer[6];
  buffer[5] = 0;
  if (len > 4) {
    memcpy(buffer, &format[i], 5);
    for (i = 0; i < 5; i++)
      buffer[i] = tolower(buffer[i]);
    return !strcmp(buffer, "am/pm");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  call   <fork@plt>
  mov    %eax,-0x10(%rbp)
  cmpl   $0x0,-0x10(%rbp)
  jne    L69
  movl   $0x0,-0x18(%rbp)
  jmp    L10
L45:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0xa,-0x14(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  addl   $0x1,-0x18(%rbp)
L10:
  cmpl   $0x4,-0x18(%rbp)
  jle    L45
  jmp    L49
L69:
  call   <fork@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L0
  movl   $0x0,-0x18(%rbp)
  jmp    L65
L17:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x14,-0x14(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  addl   $0x1,-0x18(%rbp)
L65:
  cmpl   $0x4,-0x18(%rbp)
  jle    L17
  jmp    L49
L0:
  movl   $0x0,-0x18(%rbp)
  jmp    L14
L19:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x5,-0x14(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  addl   $0x1,-0x18(%rbp)
L14:
  cmpl   $0x4,-0x18(%rbp)
  jle    L19
  lea    -0x1c(%rbp),%rcx
  mov    -0x10(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
  lea    -0x1c(%rbp),%rcx
  mov    -0xc(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <waitpid@plt>
L49:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L88
  call   <__stack_chk_fail@plt>
L88:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D33
type_infered: string
name: extract_symbolic_data
arguments: data_label: D28
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string

tool: D3: Before forking, the value of x is %d


tool: D33: 			 At first child: x= %d


tool: D28: 						 At second child: x= %d


tool: D38: At parent: x= %d


assistant: ```c
main() {
  int i;
  int x = 10;
  int pid1, pid2, status;
  printf("Before forking, the value of x is %d\n", x);
  if ((pid1 = fork()) == 0) {
    for (i = 0; i < 5; i++) {
      printf("\t\t\t At first child: x= %d\n", x);
      x = x + 10;
      sleep(1);
    }
  } else {
    if ((pid2 = fork()) == 0) {
      for (i = 0; i < 5; i++) {
        printf("\t\t\t\t\t\t At second child: x= %d\n", x);
        x = x + 20;
        sleep(1);
      }
    } else {
      for (i = 0; i < 5; i++) {
        printf("At parent: x= %d\n", x);
        x = x + 5;
        sleep(1);
      }
      waitpid(pid1, &status, 0);
      waitpid(pid2, &status, 0);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0xa,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  call   <fork@plt>
  test   %eax,%eax
  jne    L58
  mov    $0xa,%ebx
  lea    D35(%rip),%rbp
L59:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0xa,%ebx
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x3c,%ebx
  jne    L59
L78:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L58:
  mov    %eax,%ebx
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L27
  mov    $0xa,%ebx
  lea    D6(%rip),%rbp
L70:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x14,%ebx
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x6e,%ebx
  jne    L70
  jmp    L78
L27:
  mov    $0xa,%ebp
  lea    D4(%rip),%r13
L43:
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x5,%ebp
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x23,%ebp
  jne    L43
  lea    0x4(%rsp),%rbp
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <waitpid@plt>
  mov    $0x0,%edx
  mov    %rbp,%rsi
  mov    %r12d,%edi
  call   <waitpid@plt>
  jmp    L78
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D1
datatype: string
name: parse_data
arguments: label: D35
datatype: string
name: parse_data
arguments: label: D6
datatype: string
name: parse_data
arguments: label: D4
datatype: string

tool: D1: Before forking, the value of x is %d


tool: D35: 			 At first child: x= %d


tool: D6: 						 At second child: x= %d


tool: D4: At parent: x= %d


assistant: ```c
main() {
  int i;
  int x = 10;
  int pid1, pid2, status;
  printf("Before forking, the value of x is %d\n", x);
  if ((pid1 = fork()) == 0) {
    for (i = 0; i < 5; i++) {
      printf("\t\t\t At first child: x= %d\n", x);
      x = x + 10;
      sleep(1);
    }
  } else {
    if ((pid2 = fork()) == 0) {
      for (i = 0; i < 5; i++) {
        printf("\t\t\t\t\t\t At second child: x= %d\n", x);
        x = x + 20;
        sleep(1);
      }
    } else {
      for (i = 0; i < 5; i++) {
        printf("At parent: x= %d\n", x);
        x = x + 5;
        sleep(1);
      }
      waitpid(pid1, &status, 0);
      waitpid(pid2, &status, 0);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D14(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  call   <fork@plt>
  test   %eax,%eax
  jne    L48
  mov    $0xa,%ebx
  lea    D8(%rip),%rbp
L77:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0xa,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x3c,%ebx
  jne    L77
L25:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  mov    %eax,%ebp
  mov    $0xa,%ebx
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L16
  lea    D34(%rip),%rbp
L57:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x6e,%ebx
  jne    L57
  jmp    L25
L16:
  lea    D1(%rip),%r13
L34:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x5,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x23,%ebx
  jne    L34
  lea    0x4(%rsp),%r13
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %r13,%rsi
  call   <waitpid@plt>
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <waitpid@plt>
  jmp    L25
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D14
type_infered: string
name: parse_data
arguments: data_tag: D8
type_infered: string
name: parse_data
arguments: data_tag: D34
type_infered: string
name: parse_data
arguments: data_tag: D1
type_infered: string

tool: D14: Before forking, the value of x is %d


tool: D8: 			 At first child: x= %d


tool: D34: 						 At second child: x= %d


tool: D1: At parent: x= %d


assistant: ```c
main() {
  int i;
  int x = 10;
  int pid1, pid2, status;
  printf("Before forking, the value of x is %d\n", x);
  if ((pid1 = fork()) == 0) {
    for (i = 0; i < 5; i++) {
      printf("\t\t\t At first child: x= %d\n", x);
      x = x + 10;
      sleep(1);
    }
  } else {
    if ((pid2 = fork()) == 0) {
      for (i = 0; i < 5; i++) {
        printf("\t\t\t\t\t\t At second child: x= %d\n", x);
        x = x + 20;
        sleep(1);
      }
    } else {
      for (i = 0; i < 5; i++) {
        printf("At parent: x= %d\n", x);
        x = x + 5;
        sleep(1);
      }
      waitpid(pid1, &status, 0);
      waitpid(pid2, &status, 0);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r13
  mov    $0xa,%esi
  lea    D21(%rip),%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  call   <fork@plt>
  test   %eax,%eax
  jne    L29
  mov    $0xa,%ebx
  lea    D32(%rip),%rbp
L66:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0xa,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x3c,%ebx
  jne    L66
L13:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  mov    %eax,%ebp
  mov    $0xa,%ebx
  call   <fork@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jne    L71
  lea    D23(%rip),%rbp
L47:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x14,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x6e,%ebx
  jne    L47
  jmp    L13
L71:
  lea    D13(%rip),%r13
L64:
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x5,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x23,%ebx
  jne    L64
  lea    0x4(%rsp),%r13
  xor    %edx,%edx
  mov    %ebp,%edi
  mov    %r13,%rsi
  call   <waitpid@plt>
  xor    %edx,%edx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <waitpid@plt>
  jmp    L13
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D21
datatype: string
name: extract_symbolic_data
arguments: label: D32
datatype: string
name: extract_symbolic_data
arguments: label: D23
datatype: string
name: extract_symbolic_data
arguments: label: D13
datatype: string

tool: D21: Before forking, the value of x is %d


tool: D32: 			 At first child: x= %d


tool: D23: 						 At second child: x= %d


tool: D13: At parent: x= %d


assistant: ```c
main() {
  int i;
  int x = 10;
  int pid1, pid2, status;
  printf("Before forking, the value of x is %d\n", x);
  if ((pid1 = fork()) == 0) {
    for (i = 0; i < 5; i++) {
      printf("\t\t\t At first child: x= %d\n", x);
      x = x + 10;
      sleep(1);
    }
  } else {
    if ((pid2 = fork()) == 0) {
      for (i = 0; i < 5; i++) {
        printf("\t\t\t\t\t\t At second child: x= %d\n", x);
        x = x + 20;
        sleep(1);
      }
    } else {
      for (i = 0; i < 5; i++) {
        printf("At parent: x= %d\n", x);
        x = x + 5;
        sleep(1);
      }
      waitpid(pid1, &status, 0);
      waitpid(pid2, &status, 0);
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wind_strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
L6:
  mov    -0x20(%rbp),%rdx
  lea    0x1(%rdx),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    %rcx,-0x18(%rbp)
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
  movzbl (%rax),%eax
  test   %al,%al
  jne    L6
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *wind_strcpy(char *dest, const char *src) {
  char *tmp = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return tmp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<wind_strcpy>:
  endbr64
  mov    %rdi,%rax
  mov    $0x0,%edx
L9:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L9
  ret
```

assistant: ```c
char *wind_strcpy(char *dest, const char *src) {
  char *tmp = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<wind_strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L3:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L3
  ret
```

assistant: ```c
char *wind_strcpy(char *dest, const char *src) {
  char *tmp = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return tmp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<wind_strcpy>:
  endbr64
  mov    %rdi,%rax
  xor    %edx,%edx
  nopl   0x0(%rax)
L6:
  movzbl (%rsi,%rdx,1),%ecx
  mov    %cl,(%rax,%rdx,1)
  add    $0x1,%rdx
  test   %cl,%cl
  jne    L6
  ret
```

assistant: ```c
char *wind_strcpy(char *dest, const char *src) {
  char *tmp = dest;
  while ((*dest++ = *src++) != '\0')
    ;
  return tmp;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r8
  mov    %esi,%r10d
  mov    %edx,%esi
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    %edx,%eax
  sub    %r10d,%eax
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L109:
  cmp    %rdx,%rsp
  je     L5
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L109
L5:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L37
  orq    $0x0,-0x8(%rsp,%rax,1)
L37:
  mov    %rsp,%r11
  lea    (%rsi,%r10,1),%eax
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  lea    0x1(%rdi),%edx
  cmp    %edi,%r10d
  jle    L44
  cmp    %edx,%esi
  jl     L12
L44:
  mov    %r11,%rcx
  mov    %r10d,%eax
  jmp    L93
L30:
  cmp    %edx,%esi
  jge    L111
  movslq %eax,%r9
  mov    (%r8,%r9,4),%r9d
  lea    0x1(%rax),%eax
  jmp    L13
L111:
  movslq %eax,%r9
  mov    (%r8,%r9,4),%ebx
  movslq %edx,%r9
  mov    (%r8,%r9,4),%r9d
  cmp    %r9d,%ebx
  jge    L45
  add    $0x1,%eax
  mov    %ebx,%r9d
L157:
  mov    %r9d,(%rcx)
L99:
  add    $0x4,%rcx
L93:
  cmp    %eax,%edi
  jge    L30
  movslq %edx,%r9
  mov    (%r8,%r9,4),%r9d
  lea    0x1(%rdx),%edx
L13:
  mov    %r9d,(%rcx)
  cmp    %edi,%eax
  jle    L99
  cmp    %esi,%edx
  jle    L99
L12:
  cmp    %r10d,%esi
  jl     L144
  sub    %r10d,%esi
  movslq %r10d,%r10
  lea    (%r8,%r10,4),%rcx
  mov    $0x0,%eax
L107:
  mov    (%r11,%rax,4),%edx
  mov    %edx,(%rcx,%rax,4)
  mov    %rax,%rdx
  add    $0x1,%rax
  cmp    %rsi,%rdx
  jne    L107
L144:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L83
  mov    -0x8(%rbp),%rbx
  leave
  ret
L45:
  add    $0x1,%edx
  jmp    L157
L83:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int *array, int left, int right) {
  int i, j, k;
  int tmp[(right - left) + 1];
  int mid = (left + right) / 2;
  for (k = 0, i = left, j = mid + 1; i <= mid || j <= right; k++) {
    if (i > mid)
      tmp[k] = array[j++];
    else if (j > right)
      tmp[k] = array[i++];
    else if (array[i] < array[j])
      tmp[k] = array[i++];
    else
      tmp[k] = array[j++];
  }
  for (i = left, k = 0; i <= right; i++, k++)
    array[i] = tmp[k];
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<merge>:
  endbr64
  push   %rbp
  mov    %edx,%r8d
  mov    %rdi,%r9
  mov    %esi,%r10d
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  mov    %edx,%eax
  mov    %rsp,%rcx
  sub    %esi,%eax
  add    $0x1,%eax
  cltq
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L159
L9:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L9
L159:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L19
L81:
  lea    (%r8,%r10,1),%eax
  mov    %rsp,%r11
  mov    %eax,%edi
  shr    $0x1f,%edi
  add    %eax,%edi
  sar    %edi
  lea    0x1(%rdi),%edx
  cmp    %edi,%r10d
  jle    L157
  cmp    %edx,%r8d
  jl     L118
L157:
  mov    %r11,%rcx
  mov    %r10d,%eax
  jmp    L119
  nopl   0x0(%rax,%rax,1)
L74:
  movslq %edx,%rsi
  add    $0x1,%edx
  mov    (%r9,%rsi,4),%esi
L161:
  mov    %esi,(%rcx)
  cmp    %edi,%eax
  jle    L71
  cmp    %r8d,%edx
  jg     L118
L71:
  add    $0x4,%rcx
L119:
  cmp    %eax,%edi
  jl     L74
  movslq %eax,%rsi
  mov    (%r9,%rsi,4),%esi
  cmp    %edx,%r8d
  jge    L141
  add    $0x1,%eax
  jmp    L161
  xchg   %ax,%ax
L141:
  movslq %edx,%rbx
  mov    (%r9,%rbx,4),%ebx
  cmp    %esi,%ebx
  jle    L142
  mov    %esi,%ebx
  add    $0x1,%eax
  mov    %ebx,(%rcx)
  jmp    L71
  nopl   0x0(%rax)
L142:
  mov    %ebx,(%rcx)
  add    $0x1,%edx
  jmp    L71
  nop
L118:
  cmp    %r10d,%r8d
  jl     L31
  movslq %r10d,%rax
  sub    %r10d,%r8d
  mov    %r11,%rsi
  lea    (%r9,%rax,4),%rdi
  lea    0x4(,%r8,4),%rdx
  call   <memcpy@plt>
L31:
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L166
  mov    -0x8(%rbp),%rbx
  leave
  ret
  nopl   0x0(%rax)
L19:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L81
L166:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void merge(int *array, int left, int right) {
  int i, j, k;
  int tmp[(right - left) + 1];
  int mid = (left + right) / 2;
  for (k = 0, i = left, j = mid + 1; i <= mid || j <= right; k++) {
    if (i > mid)
      tmp[k] = array[j++];
    else if (j > right)
      tmp[k] = array[i++];
    else if (array[i] < array[j])
      tmp[k] = array[i++];
    else
      tmp[k] = array[j++];
  }
  for (i = left, k = 0; i <= right; i++, k++)
    array[i] = tmp[k];
}
```