ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的:

```asm
<homo_print>:
  endbr64
  sub    $0x8,%rsp
  push   0x58(%rdi)
  push   0x50(%rdi)
  push   0x48(%rdi)
  push   0x40(%rdi)
  movsd  0x38(%rdi),%xmm7
  movsd  0x30(%rdi),%xmm6
  movsd  0x28(%rdi),%xmm5
  movsd  0x20(%rdi),%xmm4
  movsd  0x18(%rdi),%xmm3
  movsd  0x10(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm1
  movsd  (%rdi),%xmm0
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D5
datatype: string

tool: D5:    % 3.3f % 3.3f % 3.3f % 3.3f
   % 3.3f % 3.3f % 3.3f % 3.3f
   % 3.3f % 3.3f % 3.3f % 3.3f


assistant: ```c
void homo_print(double H[3][4]) {
  printf("   % 3.3f % 3.3f % 3.3f % 3.3f\n"
         "   % 3.3f % 3.3f % 3.3f % 3.3f\n"
         "   % 3.3f % 3.3f % 3.3f % 3.3f\n",
         H[0][0], H[0][1], H[0][2], H[0][3], H[1][0], H[1][1], H[1][2], H[1][3], H[2][0], H[2][1], H[2][2], H[2][3]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<homo_print>:
  endbr64
  sub    $0x8,%rsp
  push   0x58(%rdi)
  push   0x50(%rdi)
  push   0x48(%rdi)
  push   0x40(%rdi)
  movsd  0x38(%rdi),%xmm7
  movsd  0x30(%rdi),%xmm6
  movsd  0x28(%rdi),%xmm5
  movsd  0x20(%rdi),%xmm4
  movsd  0x18(%rdi),%xmm3
  movsd  0x10(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm1
  movsd  (%rdi),%xmm0
  lea    D2(%rip),%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type_guessed: string

tool: D2:    % 3.3f % 3.3f % 3.3f % 3.3f
   % 3.3f % 3.3f % 3.3f % 3.3f
   % 3.3f % 3.3f % 3.3f % 3.3f


assistant: ```c
void homo_print(double H[3][4]) {
  printf("   % 3.3f % 3.3f % 3.3f % 3.3f\n"
         "   % 3.3f % 3.3f % 3.3f % 3.3f\n"
         "   % 3.3f % 3.3f % 3.3f % 3.3f\n",
         H[0][0], H[0][1], H[0][2], H[0][3], H[1][0], H[1][1], H[1][2], H[1][3], H[2][0], H[2][1], H[2][2], H[2][3]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<homo_print>:
  endbr64
  sub    $0x8,%rsp
  push   0x58(%rdi)
  push   0x50(%rdi)
  push   0x48(%rdi)
  push   0x40(%rdi)
  movsd  0x38(%rdi),%xmm7
  movsd  0x30(%rdi),%xmm6
  movsd  0x28(%rdi),%xmm5
  movsd  0x20(%rdi),%xmm4
  movsd  0x18(%rdi),%xmm3
  movsd  0x10(%rdi),%xmm2
  movsd  0x8(%rdi),%xmm1
  movsd  (%rdi),%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x28,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
datatype: string

tool: D8:    % 3.3f % 3.3f % 3.3f % 3.3f
   % 3.3f % 3.3f % 3.3f % 3.3f
   % 3.3f % 3.3f % 3.3f % 3.3f


assistant: ```c
void homo_print(double H[3][4]) {
  printf("   % 3.3f % 3.3f % 3.3f % 3.3f\n"
         "   % 3.3f % 3.3f % 3.3f % 3.3f\n"
         "   % 3.3f % 3.3f % 3.3f % 3.3f\n",
         H[0][0], H[0][1], H[0][2], H[0][3], H[1][0], H[1][1], H[1][2], H[1][3], H[2][0], H[2][1], H[2][2], H[2][3]);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<die>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D5
data_type: string

tool: D5: die: %s


assistant: ```c
void die(const char *name) {
  printf("die: %s\n", name);
  exit(1);
}
```
user: Translate the below assembly code into C programming language:

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: die: %s


assistant: ```c
void die(const char *name) {
  printf("die: %s\n", name);
  exit(1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: read_data
arguments: data_tag: D8
type: string

tool: D8: die: %s


assistant: ```c
void die(const char *name) {
  printf("die: %s\n", name);
  exit(1);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<die>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: die: %s


assistant: ```c
void die(const char *name) {
  printf("die: %s\n", name);
  exit(1);
}
```
user: What is the c source code of the assembly code below:

```asm
<get_buf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D33(%rip),%eax
  lea    0x1(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x66666667,%rax,%rax
  shr    $0x20,%rax
  sar    $0x2,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,D23(%rip)
  mov    D23(%rip),%eax
  cltq
  shl    $0xa,%rax
  mov    %rax,%rdx
  lea    D23(%rip),%rax
  add    %rdx,%rax
  pop    %rbp
  ret
```

assistant: ```c
char *get_buf() {
  static int num = 0;
  static char buf[10][1024];
  return buf[num = (num + 1) % 10];
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<get_buf>:
  endbr64
  mov    D26(%rip),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,D21(%rip)
  cltq
  shl    $0xa,%rax
  lea    D21(%rip),%rdx
  add    %rdx,%rax
  ret
```

assistant: ```c
char *get_buf() {
  static int num = 0;
  static char buf[10][1024];
  return buf[num = (num + 1) % 10];
}
```
user: What is the c source code of the assembly code below:

```asm
<get_buf>:
  endbr64
  mov    D11(%rip),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  lea    D7(%rip),%rdx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,D23(%rip)
  cltq
  shl    $0xa,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
char *get_buf() {
  static int num = 0;
  static char buf[10][1024];
  return buf[num = (num + 1) % 10];
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_buf>:
  endbr64
  mov    D24(%rip),%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  mov    %edx,%ecx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%ecx
  sar    $0x22,%rax
  sub    %ecx,%eax
  lea    (%rax,%rax,4),%ecx
  mov    %edx,%eax
  lea    D22(%rip),%rdx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %eax,D4(%rip)
  cltq
  shl    $0xa,%rax
  add    %rdx,%rax
  ret
```

assistant: ```c
char *get_buf() {
  static int num = 0;
  static char buf[10][1024];
  return buf[num = (num + 1) % 10];
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<i_printf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xd0,%rsp
  mov    %edi,-0xc4(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L12
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L12:
  movl   $0x0,-0xb8(%rbp)
  cmpl   $0x0,-0xc4(%rbp)
  je     L1
  mov    -0xd0(%rbp),%rdx
  mov    -0xb4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    -0xb4(%rbp),%edx
  mov    -0xd0(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <vfprintf@plt>
  mov    %eax,-0xb8(%rbp)
  mov    -0xb4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
L1:
  mov    -0xb8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int i_printf(int interactive, char *format_str, ...) {
  va_list ap;
  int ret = 0;
  if (interactive) {
    va_start(ap, format_str);
    ret = vfprintf(stdout, format_str, ap);
    va_end(ap);
  }
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<i_printf>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  test   %edi,%edi
  jne    L14
L6:
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  mov    %rsi,%rbp
  mov    $0x0,%r12d
  mov    %r12d,%edi
  call   <va_start@plt>
  mov    %r12d,%edx
  mov    %rbp,%rsi
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %eax,%ebx
  mov    %r12d,%edi
  call   <va_end@plt>
  jmp    L6
```

assistant: ```c
int i_printf(int interactive, char *format_str, ...) {
  va_list ap;
  int ret = 0;
  if (interactive) {
    va_start(ap, format_str);
    ret = vfprintf(stdout, format_str, ap);
    va_end(ap);
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i_printf>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  test   %edi,%edi
  jne    L0
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  xor    %ebp,%ebp
  mov    %rsi,%r13
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int i_printf(int interactive, char *format_str, ...) {
  va_list ap;
  int ret = 0;
  if (interactive) {
    va_start(ap, format_str);
    ret = vfprintf(stdout, format_str, ap);
    va_end(ap);
  }
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<i_printf>:
  endbr64
  push   %r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  test   %edi,%edi
  jne    L4
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L4:
  xor    %ebp,%ebp
  mov    %rsi,%r13
  mov    %ebp,%edi
  call   <va_start@plt>
  mov    D5(%rip),%rax
  mov    %ebp,%edx
  mov    %r13,%rsi
  mov    (%rax),%edi
  call   <vfprintf@plt>
  mov    %ebp,%edi
  mov    %eax,%r12d
  call   <va_end@plt>
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
int i_printf(int interactive, char *format_str, ...) {
  va_list ap;
  int ret = 0;
  if (interactive) {
    va_start(ap, format_str);
    ret = vfprintf(stdout, format_str, ap);
    va_end(ap);
  }
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<generate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L103
  mov    $0x0,%eax
  jmp    L58
L103:
  cmpl   $0x0,-0x24(%rbp)
  jne    L87
  mov    $0x0,%eax
  jmp    L58
L87:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L75
L0:
  mov    -0x24(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    -0x18(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x10(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0x18(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  movl   $0x0,-0x14(%rbp)
  jmp    L69
L98:
  cmpl   $0x0,-0x14(%rbp)
  je     L107
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L65
L107:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  movl   $0x1,(%rax)
  jmp    L42
L65:
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x18(%rbp),%eax
  cltq
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  sub    $0x4,%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rsi
  mov    -0x10(%rbp),%rax
  add    %rsi,%rax
  mov    (%rax),%rsi
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rsi,%rax
  add    %ecx,%edx
  mov    %edx,(%rax)
L42:
  addl   $0x1,-0x14(%rbp)
L69:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L98
  addl   $0x1,-0x18(%rbp)
L75:
  mov    -0x18(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L0
  mov    -0x30(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
L58:
  leave
  ret
```

assistant: ```c
int **generate(int numRows, int **columnSizes) {
  if (!columnSizes) {
    return 0;
  }
  if (numRows == 0) {
    return 0;
  }
  int **res = (int **)malloc(sizeof(int *) * numRows);
  int *columns = (int *)malloc(sizeof(int) * numRows);
  for (int i = 0; i < numRows; i++) {
    res[i] = (int *)malloc(sizeof(int) * numRows);
    columns[i] = i + 1;
    for (int j = 0; j <= i; j++) {
      if (j == 0 || j == i) {
        res[i][j] = 1;
      } else {
        res[i][j] = res[i - 1][j] + res[i - 1][j - 1];
      }
    }
  }
  *columnSizes = columns;
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x10(%rsp)
  test   %edi,%edi
  je     L90
  mov    %edi,%r14d
  test   %rsi,%rsi
  je     L90
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rax,0x8(%rsp)
  lea    0x0(,%r14,4),%r15d
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  test   %r14d,%r14d
  jle    L112
  mov    %rax,%r13
  sub    $0x8,%rbx
  mov    $0x0,%r12d
  mov    $0x0,%ebp
  jmp    L109
L70:
  mov    (%rdi),%rcx
  movl   $0x1,(%rcx,%rdx,1)
L60:
  lea    0x1(%rax),%ecx
  add    $0x4,%rdx
  cmp    %eax,%esi
  je     L38
  mov    %ecx,%eax
L20:
  test   %eax,%eax
  je     L70
  cmp    %r8d,%eax
  je     L70
  mov    (%r9),%r11
  mov    (%rdi),%r10
  mov    (%r11,%rdx,1),%ecx
  add    -0x4(%r11,%rdx,1),%ecx
  mov    %ecx,(%r10,%rdx,1)
  jmp    L60
L38:
  add    $0x1,%r12d
  add    $0x4,%r13
  cmp    %r14d,%ebp
  je     L112
L109:
  mov    %r15d,%edi
  call   <malloc@plt>
  mov    %rbx,%r9
  add    $0x8,%rbx
  mov    %rbx,%rdi
  mov    %rax,(%rbx)
  mov    %ebp,%esi
  add    $0x1,%ebp
  mov    %ebp,0x0(%r13)
  mov    %r12d,%r8d
  test   %r12d,%r12d
  js     L38
  mov    $0x0,%edx
  mov    $0x0,%eax
  jmp    L20
L112:
  mov    0x10(%rsp),%rax
  mov    0x18(%rsp),%rbx
  mov    %rbx,(%rax)
L28:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L90:
  movq   $0x0,0x8(%rsp)
  jmp    L28
```

assistant: ```c
int **generate(int numRows, int **columnSizes) {
  if (!columnSizes) {
    return 0;
  }
  if (numRows == 0) {
    return 0;
  }
  int **res = (int **)malloc(sizeof(int *) * numRows);
  int *columns = (int *)malloc(sizeof(int) * numRows);
  for (int i = 0; i < numRows; i++) {
    res[i] = (int *)malloc(sizeof(int) * numRows);
    columns[i] = i + 1;
    for (int j = 0; j <= i; j++) {
      if (j == 0 || j == i) {
        res[i][j] = 1;
      } else {
        res[i][j] = res[i - 1][j] + res[i - 1][j - 1];
      }
    }
  }
  *columnSizes = columns;
  return res;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<generate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  test   %edi,%edi
  je     L67
  test   %rsi,%rsi
  je     L67
  mov    %edi,%ebx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  lea    0x0(,%rbx,4),%ebp
  mov    %ebp,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %ebx,%ebx
  jle    L30
  mov    0x8(%rsp),%rax
  mov    0x10(%rsp),%r13
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  lea    -0x8(%rax),%r12
  nopw   0x0(%rax,%rax,1)
L83:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %r12,%r9
  mov    %r15d,%r8d
  add    $0x1,%r15d
  mov    %rax,0x8(%r12)
  mov    %rax,%rdi
  add    $0x8,%r12
  xor    %edx,%edx
  mov    %r15d,0x0(%r13)
  xor    %eax,%eax
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L69:
  mov    (%r9),%r10
  mov    (%r10,%rdx,1),%ecx
  add    -0x4(%r10,%rdx,1),%ecx
  add    $0x4,%rdx
  mov    %ecx,(%rsi)
  lea    0x1(%rax),%ecx
  cmp    %eax,%r8d
  je     L56
L68:
  mov    %ecx,%eax
L72:
  lea    (%rdi,%rdx,1),%rsi
  test   %eax,%eax
  je     L4
  cmp    %r14d,%eax
  jne    L69
L4:
  mov    $0x1,%ecx
  add    $0x4,%rdx
  mov    %ecx,(%rsi)
  lea    0x1(%rax),%ecx
  cmp    %eax,%r8d
  jne    L68
L56:
  add    $0x1,%r14
  add    $0x4,%r13
  cmp    %ebx,%r15d
  jne    L83
L30:
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%rbx
  mov    %rbx,(%rax)
L73:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L67:
  movq   $0x0,0x8(%rsp)
  jmp    L73
```

assistant: ```c
int **generate(int numRows, int **columnSizes) {
  if (!columnSizes) {
    return 0;
  }
  if (numRows == 0) {
    return 0;
  }
  int **res = (int **)malloc(sizeof(int *) * numRows);
  int *columns = (int *)malloc(sizeof(int) * numRows);
  for (int i = 0; i < numRows; i++) {
    res[i] = (int *)malloc(sizeof(int) * numRows);
    columns[i] = i + 1;
    for (int j = 0; j <= i; j++) {
      if (j == 0 || j == i) {
        res[i][j] = 1;
      } else {
        res[i][j] = res[i - 1][j] + res[i - 1][j - 1];
      }
    }
  }
  *columnSizes = columns;
  return res;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<generate>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rsi,0x18(%rsp)
  test   %edi,%edi
  je     L52
  test   %rsi,%rsi
  je     L52
  mov    %edi,%ebx
  lea    0x0(,%rdi,8),%edi
  call   <malloc@plt>
  lea    0x0(,%rbx,4),%ebp
  mov    %ebp,%edi
  mov    %rax,0x8(%rsp)
  call   <malloc@plt>
  mov    %rax,0x10(%rsp)
  test   %ebx,%ebx
  jle    L33
  mov    %rax,%r13
  mov    0x8(%rsp),%rax
  xor    %r14d,%r14d
  xor    %r15d,%r15d
  lea    -0x8(%rax),%r12
  nopl   0x0(%rax,%rax,1)
L93:
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %r12,%r9
  mov    %r15d,%r8d
  xor    %edx,%edx
  mov    %rax,%rdi
  mov    %rax,0x8(%r12)
  add    $0x1,%r15d
  xor    %eax,%eax
  add    $0x8,%r12
  mov    %r15d,0x0(%r13)
  lea    (%rdi,%rdx,1),%rcx
  test   %eax,%eax
  je     L50
  nopl   (%rax)
L81:
  cmp    %r14d,%eax
  je     L50
  mov    (%r9),%r10
  mov    (%r10,%rdx,1),%esi
  add    -0x4(%r10,%rdx,1),%esi
  add    $0x4,%rdx
  mov    %esi,(%rcx)
  lea    0x1(%rax),%ecx
  cmp    %eax,%r8d
  je     L12
L85:
  mov    %ecx,%eax
  lea    (%rdi,%rdx,1),%rcx
  test   %eax,%eax
  jne    L81
L50:
  movl   $0x1,(%rcx)
  add    $0x4,%rdx
  lea    0x1(%rax),%ecx
  cmp    %eax,%r8d
  jne    L85
L12:
  add    $0x1,%r14
  add    $0x4,%r13
  cmp    %ebx,%r15d
  jne    L93
L33:
  mov    0x18(%rsp),%rax
  mov    0x10(%rsp),%rbx
  mov    %rbx,(%rax)
L27:
  mov    0x8(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L52:
  movq   $0x0,0x8(%rsp)
  jmp    L27
```

assistant: ```c
int **generate(int numRows, int **columnSizes) {
  if (!columnSizes) {
    return 0;
  }
  if (numRows == 0) {
    return 0;
  }
  int **res = (int **)malloc(sizeof(int *) * numRows);
  int *columns = (int *)malloc(sizeof(int) * numRows);
  for (int i = 0; i < numRows; i++) {
    res[i] = (int *)malloc(sizeof(int) * numRows);
    columns[i] = i + 1;
    for (int j = 0; j <= i; j++) {
      if (j == 0 || j == i) {
        res[i][j] = 1;
      } else {
        res[i][j] = res[i - 1][j] + res[i - 1][j - 1];
      }
    }
  }
  *columnSizes = columns;
  return res;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_reverse>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L16:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x9(%rbp)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x9(%rbp),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
  subl   $0x1,-0x8(%rbp)
L13:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jl     L16
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *str_reverse(char *str) {
  int r = strlen(str) - 1;
  int l = 0;
  char c;
  while (l < r) {
    c = str[r];
    str[r] = str[l];
    str[l] = c;
    l++;
    r--;
  }
  return str;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<str_reverse>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L17
  cltq
  mov    $0x0,%edx
L19:
  movzbl (%rbx,%rax,1),%ecx
  movzbl (%rbx,%rdx,1),%esi
  mov    %sil,(%rbx,%rax,1)
  mov    %cl,(%rbx,%rdx,1)
  add    $0x1,%rdx
  sub    $0x1,%rax
  cmp    %eax,%edx
  jl     L19
L17:
  mov    %rbx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *str_reverse(char *str) {
  int r = strlen(str) - 1;
  int l = 0;
  char c;
  while (l < r) {
    c = str[r];
    str[r] = str[l];
    str[l] = c;
    l++;
    r--;
  }
  return str;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L9
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax)
L14:
  movzbl (%r12,%rax,1),%ecx
  movzbl (%r12,%rdx,1),%esi
  mov    %sil,(%r12,%rax,1)
  sub    $0x1,%rax
  mov    %cl,(%r12,%rdx,1)
  add    $0x1,%rdx
  cmp    %eax,%edx
  jl     L14
L9:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *str_reverse(char *str) {
  int r = strlen(str) - 1;
  int l = 0;
  char c;
  while (l < r) {
    c = str[r];
    str[r] = str[l];
    str[l] = c;
    l++;
    r--;
  }
  return str;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_reverse>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  test   %eax,%eax
  jle    L5
  cltq
  xor    %edx,%edx
  nopl   0x0(%rax)
L18:
  movzbl (%r12,%rax,1),%ecx
  movzbl (%r12,%rdx,1),%esi
  mov    %sil,(%r12,%rax,1)
  sub    $0x1,%rax
  mov    %cl,(%r12,%rdx,1)
  add    $0x1,%rdx
  cmp    %edx,%eax
  jg     L18
L5:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *str_reverse(char *str) {
  int r = strlen(str) - 1;
  int l = 0;
  char c;
  while (l < r) {
    c = str[r];
    str[r] = str[l];
    str[l] = c;
    l++;
    r--;
  }
  return str;
}
```