ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<argv_find>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <argv_count@plt>
  xor    %edi,%edi
  test   %r12,%r12
  setne  %dil
  movslq %eax,%rbp
  call   <assert@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  test   %ebp,%ebp
  jle    L0
  mov    %eax,%r13d
  xor    %ebx,%ebx
  jmp    L16
  nopl   0x0(%rax)
L2:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L0
L16:
  mov    (%r15,%rbx,8),%rdi
  mov    %r13d,%edx
  mov    %r12,%rsi
  mov    %ebx,%r14d
  call   <strncasecmp@plt>
  test   %rax,%rax
  jne    L2
L6:
  add    $0x8,%rsp
  mov    %r14d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  mov    $0xffffffff,%r14d
  jmp    L6
```

assistant: ```c
int argv_find(char **argv, const char *what) {
  int cnt = argv_count(argv), len, i;
  assert(what != NULL);
  for (i = 0, len = strlen(what); i < cnt; i++)
    if (strncasecmp(argv[i], what, len) == 0)
      return i;
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<CSystem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <system@plt>
  test   %rax,%rax
  je     L7
  mov    $0x0,%edi
  call   <exit@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
int CSystem(char *Command) {
  if (system(Command) != 0)
    exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CSystem>:
  endbr64
  sub    $0x8,%rsp
  call   <system@plt>
  test   %rax,%rax
  jne    L1
L9:
  add    $0x8,%rsp
  ret
L1:
  mov    $0x0,%edi
  call   <exit@plt>
  jmp    L9
```

assistant: ```c
int CSystem(char *Command) {
  if (system(Command) != 0)
    exit(0);
}
```
user: Translate the below assembly code into C programming language:

```asm
<CSystem>:
  endbr64
  sub    $0x8,%rsp
  call   <system@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
int CSystem(char *Command) {
  if (system(Command) != 0)
    exit(0);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CSystem>:
  endbr64
  sub    $0x8,%rsp
  call   <system@plt>
  test   %rax,%rax
  jne    L1
  add    $0x8,%rsp
  ret
  nopw   0x0(%rax,%rax,1)
L1:
  xor    %edi,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

assistant: ```c
int CSystem(char *Command) {
  if (system(Command) != 0)
    exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<pintar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <clear_Tablero@plt>
  mov    $0x0,%eax
  call   <pintaRaqueta@plt>
  mov    $0x0,%eax
  call   <pintaPelota@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void pintar(void) {
  clear_Tablero();
  pintaRaqueta();
  pintaPelota();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pintar>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <clear_Tablero@plt>
  mov    $0x0,%eax
  call   <pintaRaqueta@plt>
  mov    $0x0,%eax
  call   <pintaPelota@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pintar(void) {
  clear_Tablero();
  pintaRaqueta();
  pintaPelota();
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<pintar>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_Tablero@plt>
  xor    %eax,%eax
  call   <pintaRaqueta@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <pintaPelota@plt>
```

assistant: ```c
void pintar(void) {
  clear_Tablero();
  pintaRaqueta();
  pintaPelota();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pintar>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <clear_Tablero@plt>
  xor    %eax,%eax
  call   <pintaRaqueta@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1090 <pintaPelota@plt>
```

assistant: ```c
void pintar(void) {
  clear_Tablero();
  pintaRaqueta();
  pintaPelota();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L16
  mov    $0x0,%eax
  jmp    L4
L16:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
L4:
  leave
  ret
```

assistant: ```c
size_t str_len(char *str) {
  if (str == NULL)
    return (0);
  return (strlen(str));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_len>:
  endbr64
  test   %rdi,%rdi
  je     L5
  sub    $0x8,%rsp
  call   <strlen@plt>
  add    $0x8,%rsp
  ret
L5:
  mov    $0x0,%eax
  ret
```

assistant: ```c
size_t str_len(char *str) {
  if (str == NULL)
    return (0);
  return (strlen(str));
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_len>:
  endbr64
  test   %rdi,%rdi
  je     L1
  jmp    1050 <strlen@plt>
  xchg   %ax,%ax
L1:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t str_len(char *str) {
  if (str == NULL)
    return (0);
  return (strlen(str));
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<str_len>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <strlen@plt>
  xchg   %ax,%ax
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
size_t str_len(char *str) {
  if (str == NULL)
    return (0);
  return (strlen(str));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max_imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x30(%rbp),%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  jmp    L9
L44:
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  jmp    L32
L10:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jge    L23
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
L23:
  addl   $0x1,-0x8(%rbp)
L32:
  mov    -0x8(%rbp),%eax
  cltq
  cmp    %rax,-0x38(%rbp)
  jge    L10
  addl   $0x1,-0xc(%rbp)
L9:
  mov    -0xc(%rbp),%eax
  cltq
  cmp    %rax,-0x28(%rbp)
  jge    L44
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int max_imatrix(int **m, long nrl, long nrh, long ncl, long nch) {
  int i, j;
  int maximum = m[nrl][ncl];
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      if (m[i][j] > maximum)
        maximum = m[i][j];
    }
  }
  return maximum;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<max_imatrix>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi,%rsi,8),%rdi
  mov    (%rdi,%rcx,4),%edi
  movslq %esi,%r9
  cmp    %r9,%rdx
  jl     L11
  push   %rbx
  lea    (%rax,%r9,8),%rsi
  lea    0x8(%rax,%rdx,8),%r11
  movslq %ecx,%r10
  shl    $0x2,%r10
  movslq %ecx,%r9
  lea    0x4(,%r8,4),%rbx
L24:
  cmp    %r9,%r8
  jl     L17
  mov    (%rsi),%rcx
  lea    (%rcx,%r10,1),%rax
  add    %rbx,%rcx
L35:
  mov    (%rax),%edx
  cmp    %edx,%edi
  cmovl  %edx,%edi
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L35
L17:
  add    $0x8,%rsi
  cmp    %r11,%rsi
  jne    L24
  mov    %edi,%eax
  pop    %rbx
  ret
L11:
  mov    %edi,%eax
  ret
```

assistant: ```c
int max_imatrix(int **m, long nrl, long nrh, long ncl, long nch) {
  int i, j;
  int maximum = m[nrl][ncl];
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      if (m[i][j] > maximum)
        maximum = m[i][j];
    }
  }
  return maximum;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<max_imatrix>:
  endbr64
  mov    %rdi,%rax
  mov    (%rdi,%rsi,8),%rdi
  movslq %esi,%rsi
  mov    (%rdi,%rcx,4),%r9d
  cmp    %rsi,%rdx
  jl     L13
  movslq %ecx,%rdi
  push   %rbx
  lea    (%rax,%rsi,8),%rsi
  lea    0x8(%rax,%rdx,8),%r10
  lea    0x0(,%rdi,4),%rbx
  lea    0x4(,%r8,4),%r11
  nopl   0x0(%rax)
L20:
  cmp    %rdi,%r8
  jl     L10
  mov    (%rsi),%rcx
  lea    (%rcx,%rbx,1),%rax
  add    %r11,%rcx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%rax),%edx
  cmp    %edx,%r9d
  cmovl  %edx,%r9d
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L2
L10:
  add    $0x8,%rsi
  cmp    %r10,%rsi
  jne    L20
  mov    %r9d,%eax
  pop    %rbx
  ret
L13:
  mov    %r9d,%eax
  ret
```

assistant: ```c
int max_imatrix(int **m, long nrl, long nrh, long ncl, long nch) {
  int i, j;
  int maximum = m[nrl][ncl];
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      if (m[i][j] > maximum)
        maximum = m[i][j];
    }
  }
  return maximum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<max_imatrix>:
  endbr64
  mov    (%rdi,%rsi,8),%rax
  mov    %rcx,%r11
  mov    (%rax,%rcx,4),%eax
  movslq %esi,%rcx
  cmp    %rcx,%rdx
  jl     L37
  push   %r15
  movslq %r11d,%rsi
  lea    (%rdi,%rcx,8),%rcx
  push   %r14
  push   %r13
  lea    0x0(,%rsi,4),%r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    0x8(%rdi,%rdx,8),%rbx
  mov    %r8,%rdi
  sub    %rsi,%rdi
  lea    0x1(%rdi),%r9
  mov    %r9,%r10
  mov    %r9,%rbp
  shr    $0x2,%r10
  and    $0xfffffffffffffffc,%rbp
  lea    0x0(%rbp,%r11,1),%edx
  shl    $0x4,%r10
  cmp    $0x2,%rdi
  cmovbe %r11d,%edx
  movslq %edx,%r12
  lea    0x1(%rdx),%r11d
  add    $0x2,%edx
  movslq %edx,%rdx
  movslq %r11d,%r11
  shl    $0x2,%r12
  mov    %rdx,-0x18(%rsp)
  shl    $0x2,%rdx
  lea    0x0(,%r11,4),%r14
  mov    %rdx,-0x10(%rsp)
  nopl   0x0(%rax,%rax,1)
L41:
  cmp    %rsi,%r8
  jl     L28
  mov    (%rcx),%rdx
  cmp    $0x2,%rdi
  jbe    L75
  movd   %eax,%xmm3
  lea    (%rdx,%r13,1),%rax
  pshufd $0x0,%xmm3,%xmm2
  lea    (%rax,%r10,1),%r15
  nopl   0x0(%rax,%rax,1)
L78:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  movdqa %xmm0,%xmm1
  pcmpgtd %xmm2,%xmm1
  pand   %xmm1,%xmm0
  pandn  %xmm2,%xmm1
  movdqa %xmm1,%xmm2
  por    %xmm0,%xmm2
  cmp    %r15,%rax
  jne    L78
  movdqa %xmm2,%xmm1
  psrldq $0x8,%xmm1
  movdqa %xmm1,%xmm0
  pcmpgtd %xmm2,%xmm0
  pand   %xmm0,%xmm1
  pandn  %xmm2,%xmm0
  por    %xmm1,%xmm0
  movdqa %xmm0,%xmm2
  psrldq $0x4,%xmm2
  movdqa %xmm2,%xmm1
  pcmpgtd %xmm0,%xmm1
  pand   %xmm1,%xmm2
  pandn  %xmm0,%xmm1
  por    %xmm2,%xmm1
  movd   %xmm1,%eax
  cmp    %rbp,%r9
  je     L28
L75:
  mov    (%rdx,%r12,1),%r15d
  cmp    %r15d,%eax
  cmovl  %r15d,%eax
  cmp    %r8,%r11
  jg     L28
  mov    (%rdx,%r14,1),%r15d
  cmp    %r15d,%eax
  cmovl  %r15d,%eax
  cmp    -0x18(%rsp),%r8
  jl     L28
  mov    -0x10(%rsp),%r15
  mov    (%rdx,%r15,1),%edx
  cmp    %edx,%eax
  cmovl  %edx,%eax
L28:
  add    $0x8,%rcx
  cmp    %rbx,%rcx
  jne    L41
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  ret
```

assistant: ```c
int max_imatrix(int **m, long nrl, long nrh, long ncl, long nch) {
  int i, j;
  int maximum = m[nrl][ncl];
  for (i = nrl; i <= nrh; i++) {
    for (j = ncl; j <= nch; j++) {
      if (m[i][j] > maximum)
        maximum = m[i][j];
    }
  }
  return maximum;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<USBDMAChannelStatus>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  cmpl   $0x40050000,-0x4(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  cmpl   $0x7,-0x8(%rbp)
  setle  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <ASSERT@plt>
  mov    -0x4(%rbp),%eax
  lea    0x204(%rax),%edx
  mov    -0x8(%rbp),%eax
  shl    $0x4,%eax
  add    %edx,%eax
  cltq
  mov    (%rax),%eax
  and    $0x100,%eax
  leave
  ret
```

assistant: ```c
uint32_t USBDMAChannelStatus(uint32_t ui32Base, uint32_t ui32Channel) {
  ASSERT(ui32Base == 0x40050000);
  ASSERT(ui32Channel < 8);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000204 + (0x10 * ui32Channel)))) & 0x00000100);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<USBDMAChannelStatus>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %esi,%ebx
  cmp    $0x40050000,%edi
  sete   %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  cmp    $0x7,%ebx
  setle  %dil
  movzbl %dil,%edi
  call   <ASSERT@plt>
  shl    $0x4,%ebx
  lea    0x204(%rbp,%rbx,1),%eax
  cltq
  mov    (%rax),%eax
  and    $0x100,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
uint32_t USBDMAChannelStatus(uint32_t ui32Base, uint32_t ui32Channel) {
  ASSERT(ui32Base == 0x40050000);
  ASSERT(ui32Channel < 8);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000204 + (0x10 * ui32Channel)))) & 0x00000100);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<USBDMAChannelStatus>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x40050000,%ebp
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebx
  setle  %dil
  shl    $0x4,%ebx
  call   <ASSERT@plt>
  lea    0x204(%rbp,%rbx,1),%eax
  cltq
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  and    $0x100,%eax
  ret
```

assistant: ```c
uint32_t USBDMAChannelStatus(uint32_t ui32Base, uint32_t ui32Channel) {
  ASSERT(ui32Base == 0x40050000);
  ASSERT(ui32Channel < 8);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000204 + (0x10 * ui32Channel)))) & 0x00000100);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<USBDMAChannelStatus>:
  endbr64
  push   %rbp
  mov    %edi,%ebp
  xor    %edi,%edi
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  cmp    $0x40050000,%ebp
  sete   %dil
  call   <ASSERT@plt>
  xor    %edi,%edi
  cmp    $0x7,%ebx
  setle  %dil
  shl    $0x4,%ebx
  call   <ASSERT@plt>
  lea    0x204(%rbp,%rbx,1),%eax
  cltq
  mov    (%rax),%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  and    $0x100,%eax
  ret
```

assistant: ```c
uint32_t USBDMAChannelStatus(uint32_t ui32Base, uint32_t ui32Channel) {
  ASSERT(ui32Base == 0x40050000);
  ASSERT(ui32Channel < 8);
  return ((*((volatile uint32_t *)(ui32Base + 0x00000204 + (0x10 * ui32Channel)))) & 0x00000100);
}
```
user: What is the c source code of the assembly code below:

```asm
<stringduplicate_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  movb   $0x0,-0x19(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L41
  cmpq   $0x0,-0x30(%rbp)
  jne    L60
L41:
  mov    $0x0,%eax
  jmp    L102
L60:
  mov    -0x30(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L103
  mov    $0x0,%eax
  jmp    L102
L103:
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  jmp    L87
L10:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L18
  cmpb   $0x0,-0x19(%rbp)
  jne    L39
  movb   $0x1,-0x19(%rbp)
  jmp    L36
L18:
  movb   $0x0,-0x19(%rbp)
L36:
  mov    -0x28(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  jmp    L98
L39:
  nop
L98:
  addq   $0x1,-0x18(%rbp)
L87:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L10
  mov    -0x8(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
L102:
  leave
  ret
```

assistant: ```c
char *stringduplicate_length(const char *string, size_t len) {
  char *ret;
  size_t i, j;
  char space = 0;
  if (!(string && len))
    return NULL;
  if (!(ret = malloc(len + 1)))
    return NULL;
  for (i = 0, j = 0; j < len; i++) {
    if (isspace(string[i])) {
      if (space)
        continue;
      space = 1;
    } else
      space = 0;
    ret[j++] = string[i];
  }
  ret[len] = 0;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<stringduplicate_length>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L36
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L36
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L88
  mov    $0x0,%r15d
  mov    $0x0,%ebp
  jmp    L50
L21:
  mov    $0x0,%r15d
L19:
  movzbl 0x0(%r13),%eax
  mov    %al,(%r14,%rbp,1)
  lea    0x1(%rbp),%rbp
L77:
  add    $0x1,%rbx
  cmp    %r12,%rbp
  jae    L23
L50:
  mov    %rbx,%r13
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  je     L21
  test   %r15b,%r15b
  jne    L77
  mov    $0x1,%r15d
  jmp    L19
L23:
  movb   $0x0,(%r14,%r12,1)
L88:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L36:
  mov    $0x0,%r14d
  jmp    L88
```

assistant: ```c
char *stringduplicate_length(const char *string, size_t len) {
  char *ret;
  size_t i, j;
  char space = 0;
  if (!(string && len))
    return NULL;
  if (!(ret = malloc(len + 1)))
    return NULL;
  for (i = 0, j = 0; j < len; i++) {
    if (isspace(string[i])) {
      if (space)
        continue;
      space = 1;
    } else
      space = 0;
    ret[j++] = string[i];
  }
  ret[len] = 0;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<stringduplicate_length>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L43
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L43
  mov    %rdi,%rbx
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L43
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L79
  nopl   0x0(%rax)
L68:
  test   %r14b,%r14b
  jne    L36
  mov    $0x1,%r14d
L62:
  movzbl (%rbx),%eax
  mov    %al,0x0(%r13,%rbp,1)
  add    $0x1,%rbp
L36:
  add    $0x1,%rbx
  cmp    %r12,%rbp
  jae    L53
L79:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L68
  xor    %r14d,%r14d
  jmp    L62
  nopw   0x0(%rax,%rax,1)
L53:
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L43:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *stringduplicate_length(const char *string, size_t len) {
  char *ret;
  size_t i, j;
  char space = 0;
  if (!(string && len))
    return NULL;
  if (!(ret = malloc(len + 1)))
    return NULL;
  for (i = 0, j = 0; j < len; i++) {
    if (isspace(string[i])) {
      if (space)
        continue;
      space = 1;
    } else
      space = 0;
    ret[j++] = string[i];
  }
  ret[len] = 0;
  return ret;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<stringduplicate_length>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  test   %rdi,%rdi
  je     L20
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L20
  mov    %rdi,%rbx
  lea    0x1(%rsi),%rdi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L20
  xor    %r14d,%r14d
  xor    %ebp,%ebp
  jmp    L44
  nopl   0x0(%rax)
L26:
  test   %r14b,%r14b
  jne    L39
  mov    $0x1,%r14d
L43:
  movzbl (%rbx),%eax
  mov    %al,0x0(%r13,%rbp,1)
  add    $0x1,%rbp
L39:
  add    $0x1,%rbx
  cmp    %r12,%rbp
  jae    L33
L44:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L26
  xor    %r14d,%r14d
  jmp    L43
  nopw   0x0(%rax,%rax,1)
L33:
  movb   $0x0,0x0(%r13,%r12,1)
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %r13d,%r13d
  pop    %rbx
  pop    %rbp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *stringduplicate_length(const char *string, size_t len) {
  char *ret;
  size_t i, j;
  char space = 0;
  if (!(string && len))
    return NULL;
  if (!(ret = malloc(len + 1)))
    return NULL;
  for (i = 0, j = 0; j < len; i++) {
    if (isspace(string[i])) {
      if (space)
        continue;
      space = 1;
    } else
      space = 0;
    ret[j++] = string[i];
  }
  ret[len] = 0;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x18(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rdi
  call   <atoi@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
type: string
name: retrieve_data
arguments: label: D1
type: string

tool: D14: %s

tool: D1: %s = %i 


assistant: ```c
int main() {
  char s[12] = "";
  int i = 0;
  scanf("%s", s);
  i = atoi(s);
  printf("%s = %i \n", s, i);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0xc(%rsp)
  movl   $0x0,0x14(%rsp)
  lea    0xc(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <atoi@plt>
  mov    %eax,%edx
  mov    %rbx,%rsi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D15
datatype: string
name: unpack_data
arguments: data_tag: D16
datatype: string

tool: D15: %s

tool: D16: %s = %i 


assistant: ```c
int main() {
  char s[12] = "";
  int i = 0;
  scanf("%s", s);
  i = atoi(s);
  printf("%s = %i \n", s, i);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D19(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbp
  movl   $0x0,0x14(%rsp)
  movq   $0x0,0xc(%rsp)
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <atoi@plt>
  mov    %rbp,%rsi
  lea    D6(%rip),%rdi
  mov    %eax,%edx
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D19
data_type: string
name: disassemble_data
arguments: tag: D6
data_type: string

tool: D19: %s

tool: D6: %s = %i 


assistant: ```c
int main() {
  char s[12] = "";
  int i = 0;
  scanf("%s", s);
  i = atoi(s);
  printf("%s = %i \n", s, i);
  return 0;
}
```