user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<processInput>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x0,0x4(%rsp)
  cmp    $0x6,%edi
  ja     L107
  lea    D17(%rip),%rdx
  mov    %edi,%edi
  movslq (%rdx,%rdi,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopl   0x0(%rax,%rax,1)
  xor    %eax,%eax
  call   <pop@plt>
  nopw   0x0(%rax,%rax,1)
L107:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L66
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
  lea    0x4(%rsp),%r12
  lea    D56(%rip),%rbp
L23:
  lea    D84(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L107
  mov    0x4(%rsp),%edi
  call   <findLast@plt>
  mov    0x4(%rsp),%esi
  lea    D48(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <wait@plt>
  jmp    L107
  nop
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L107
  mov    0x4(%rsp),%edi
  call   <push@plt>
  jmp    L107
  nopl   (%rax)
  xor    %eax,%eax
  call   <clear@plt>
  jmp    L107
  nopl   0x0(%rax)
  lea    D42(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L107
  mov    0x4(%rsp),%edi
  call   <seek@plt>
  mov    0x4(%rsp),%esi
  lea    D92(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <wait@plt>
  jmp    L107
  nopl   0x0(%rax,%rax,1)
  lea    D68(%rip),%rdi
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  call   <printf@plt>
  lea    D56(%rip),%rbp
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  test   %eax,%eax
  je     L23
  mov    0x4(%rsp),%edi
  call   <find@plt>
  mov    0x4(%rsp),%esi
  lea    D52(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  call   <wait@plt>
  jmp    L23
L66:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D56
type_infered: string
name: extract_symbolic_data
arguments: tag: D84
type_infered: string
name: extract_symbolic_data
arguments: tag: D48
type_infered: string
name: extract_symbolic_data
arguments: tag: D29
type_infered: string
name: extract_symbolic_data
arguments: tag: D42
type_infered: string
name: extract_symbolic_data
arguments: tag: D92
type_infered: string
name: extract_symbolic_data
arguments: tag: D68
type_infered: string
name: extract_symbolic_data
arguments: tag: D52
type_infered: string

tool: D56: %d

tool: D84: value to find: 

tool: D48: Position of last element with value %d is %i


tool: D29: Value to add: 

tool: D42: Position to seek: 

tool: D92: Value of element %d is %i


tool: D68: Value to find: 

tool: D52: Position of element with value %d is %i


assistant: ```c
void processInput(int res) {
  int arg = 0;
  switch (res) {
  case 1:
    printf("Value to add: ");
    if (scanf("%d", &arg))
      push(arg);
    break;
  case 2:
    pop();
    break;
  case 3:
    clear();
    break;
  case 4:
    printf("Position to seek: ");
    if (scanf("%d", &arg)) {
      int val = seek(arg);
      printf("Value of element %d is %i\n", arg, val);
      wait();
    }
    break;
  case 5:
    printf("Value to find: ");
    if (scanf("%d", &arg)) {
      int val = find(arg);
      printf("Position of element with value %d is %i\n", arg, val);
      wait();
    }
  case 6:
    printf("value to find: ");
    if (scanf("%d", &arg)) {
      int val = findLast(arg);
      printf("Position of last element with value %d is %i\n", arg, val);
      wait();
    }
  }
}
```