ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x8(%rsp)
  movl   $0x3,(%rsp)
  movl   $0x2,0x4(%rsp)
  mov    $0x0,%ebx
  lea    D8(%rip),%rbp
L17:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L17
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D8
type_infered: string

tool: D8: count[%d]=%d


assistant: ```c
int main(void) {
  int count[4] =
      {
          3,
          2,
      },
      i;
  for (i = 0; i < 4; i++)
    printf("count[%d]=%d\n", i, count[i]);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x3,%edx
  lea    D3(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,0x4(%rsp)
  movq   $0x0,0x8(%rsp)
L29:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L7
  mov    (%rsp,%rbx,4),%edx
  jmp    L29
  nopw   0x0(%rax,%rax,1)
L7:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D3
datatype: string

tool: D3: count[%d]=%d


assistant: ```c
int main(void) {
  int count[4] =
      {
          3,
          2,
      },
      i;
  for (i = 0; i < 4; i++)
    printf("count[%d]=%d\n", i, count[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D6(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D16(%rip),%rax
  mov    %rsp,%r12
  movq   $0x0,0x8(%rsp)
  mov    %rax,(%rsp)
L12:
  mov    (%r12,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L12
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
type_guessed: string
name: retrieve_data
arguments: data_tag: D16
type_guessed: byte[8]

tool: D6: count[%d]=%d


tool: {"D16": [0x03,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

assistant: ```c
int main(void) {
  int count[4] =
      {
          3,
          2,
      },
      i;
  for (i = 0; i < 4; i++)
    printf("count[%d]=%d\n", i, count[i]);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1234,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  movzbl %al,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  sar    $0x4,%eax
  and    $0xf00,%eax
  or     %eax,%edx
  mov    -0x4(%rbp),%eax
  shl    $0x4,%eax
  and    $0xf000,%eax
  or     %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D2
type_infered: string

tool: D2: %x

assistant: ```c
int main() {
  int a = 0x1234;
  a = (a & 0xf) << 4 | (a & 0xf0) >> 4 | (a & 0xf000) >> 4 | (a & 0x0f00) << 4;
  printf("%x", a);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2143,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D2: %x

assistant: ```c
int main() {
  int a = 0x1234;
  a = (a & 0xf) << 4 | (a & 0xf0) >> 4 | (a & 0xf000) >> 4 | (a & 0x0f00) << 4;
  printf("%x", a);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2143,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D3
datatype: string

tool: D3: %x

assistant: ```c
int main() {
  int a = 0x1234;
  a = (a & 0xf) << 4 | (a & 0xf0) >> 4 | (a & 0xf000) >> 4 | (a & 0x0f00) << 4;
  printf("%x", a);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2143,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_infered: string

tool: D8: %x

assistant: ```c
int main() {
  int a = 0x1234;
  a = (a & 0xf) << 4 | (a & 0xf0) >> 4 | (a & 0xf000) >> 4 | (a & 0x0f00) << 4;
  printf("%x", a);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trailingZeroes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L0:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    %edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
L15:
  cmpl   $0x0,-0x14(%rbp)
  jne    L0
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  int return_val = 0;
  while (n) {
    return_val += n / 5;
    n /= 5;
  }
  return return_val;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<trailingZeroes>:
  endbr64
  test   %edi,%edi
  je     L25
  mov    $0x0,%edx
L6:
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x21,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  add    %eax,%edx
  test   %eax,%eax
  jne    L6
L4:
  mov    %edx,%eax
  ret
L25:
  mov    %edi,%edx
  jmp    L4
```

assistant: ```c
int trailingZeroes(int n) {
  int return_val = 0;
  while (n) {
    return_val += n / 5;
    n /= 5;
  }
  return return_val;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<trailingZeroes>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L2
  nopl   0x0(%rax,%rax,1)
L11:
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  add    %eax,%r8d
  test   %eax,%eax
  jne    L11
L2:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  int return_val = 0;
  while (n) {
    return_val += n / 5;
    n /= 5;
  }
  return return_val;
}
```
user: Translate the below assembly code into C programming language:

```asm
<trailingZeroes>:
  endbr64
  xor    %r8d,%r8d
  test   %edi,%edi
  je     L18
  nopl   0x0(%rax,%rax,1)
L14:
  movslq %edi,%rax
  mov    %edi,%edx
  imul   $0x66666667,%rax,%rax
  sar    $0x1f,%edx
  sar    $0x21,%rax
  sub    %edx,%eax
  mov    %eax,%edi
  add    %eax,%r8d
  test   %eax,%eax
  jne    L14
L18:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int trailingZeroes(int n) {
  int return_val = 0;
  while (n) {
    return_val += n / 5;
    n /= 5;
  }
  return return_val;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<BMI_sockio_connect_sock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  lea    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BMI_sockio_init_sock@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L2
  mov    -0xc(%rbp),%eax
  jmp    L3
L2:
  nop
L57:
  lea    -0x10(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <connect@plt>
  test   %rax,%rax
  jns    L33
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L32
  jmp    L57
L32:
  mov    D3(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  mov    %eax,%edi
  call   <bmi_errno_to_pvfs@plt>
  jmp    L3
L33:
  mov    -0x14(%rbp),%eax
L3:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L18
  call   <__stack_chk_fail@plt>
L18:
  leave
  ret
```

assistant: ```c
int BMI_sockio_connect_sock(int sockd, const char *name, int service) {
  struct sockaddr saddr;
  int ret;
  if ((ret = BMI_sockio_init_sock(&saddr, name, service)) != 0)
    return (ret);
connect_sock_restart:
  if (connect(sockd, (struct sockaddr *)&saddr, sizeof(saddr)) < 0) {
    if (errno == EINTR)
      goto connect_sock_restart;
    return (bmi_errno_to_pvfs(-errno));
  }
  return (sockd);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<BMI_sockio_connect_sock>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdi
  call   <BMI_sockio_init_sock@plt>
  test   %eax,%eax
  jne    L40
  lea    0x4(%rsp),%rbp
L2:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <connect@plt>
  test   %rax,%rax
  jns    L35
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  mov    D13(%rip),%rax
  cmp    (%rax),%edi
  je     L2
  neg    %edi
  call   <bmi_errno_to_pvfs@plt>
  jmp    L40
L35:
  mov    %ebx,%eax
L40:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L30
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L30:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int BMI_sockio_connect_sock(int sockd, const char *name, int service) {
  struct sockaddr saddr;
  int ret;
  if ((ret = BMI_sockio_init_sock(&saddr, name, service)) != 0)
    return (ret);
connect_sock_restart:
  if (connect(sockd, (struct sockaddr *)&saddr, sizeof(saddr)) < 0) {
    if (errno == EINTR)
      goto connect_sock_restart;
    return (bmi_errno_to_pvfs(-errno));
  }
  return (sockd);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<BMI_sockio_connect_sock>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <BMI_sockio_init_sock@plt>
  test   %eax,%eax
  je     L40
  jmp    L5
  nop
L1:
  mov    D18(%rip),%rax
  mov    (%rax),%edi
  mov    D4(%rip),%rax
  cmp    (%rax),%edi
  jne    L46
L40:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <connect@plt>
  test   %rax,%rax
  js     L1
  mov    %ebx,%eax
L5:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L47
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L46:
  neg    %edi
  call   <bmi_errno_to_pvfs@plt>
  jmp    L5
L47:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int BMI_sockio_connect_sock(int sockd, const char *name, int service) {
  struct sockaddr saddr;
  int ret;
  if ((ret = BMI_sockio_init_sock(&saddr, name, service)) != 0)
    return (ret);
connect_sock_restart:
  if (connect(sockd, (struct sockaddr *)&saddr, sizeof(saddr)) < 0) {
    if (errno == EINTR)
      goto connect_sock_restart;
    return (bmi_errno_to_pvfs(-errno));
  }
  return (sockd);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<BMI_sockio_connect_sock>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  mov    %rbp,%rdi
  call   <BMI_sockio_init_sock@plt>
  test   %eax,%eax
  je     L41
  jmp    L42
  nop
L5:
  mov    D15(%rip),%rax
  mov    (%rax),%edi
  mov    D0(%rip),%rax
  cmp    (%rax),%edi
  jne    L29
L41:
  mov    $0x4,%edx
  mov    %rbp,%rsi
  mov    %ebx,%edi
  call   <connect@plt>
  test   %rax,%rax
  js     L5
  mov    %ebx,%eax
L42:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L29:
  neg    %edi
  call   <bmi_errno_to_pvfs@plt>
  jmp    L42
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int BMI_sockio_connect_sock(int sockd, const char *name, int service) {
  struct sockaddr saddr;
  int ret;
  if ((ret = BMI_sockio_init_sock(&saddr, name, service)) != 0)
    return (ret);
connect_sock_restart:
  if (connect(sockd, (struct sockaddr *)&saddr, sizeof(saddr)) < 0) {
    if (errno == EINTR)
      goto connect_sock_restart;
    return (bmi_errno_to_pvfs(-errno));
  }
  return (sockd);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bcf_gt2alleles>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L12
L14:
  addl   $0x1,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L14
  mov    -0x4(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  sub    -0x8(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  add    %eax,%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void bcf_gt2alleles(int igt, int *a, int *b) {
  int k = 0, dk = 1;
  while (k < igt) {
    dk++;
    k += dk;
  }
  *b = dk - 1;
  *a = igt - k + *b;
}
```
user: What is the c source code of the assembly code below:

```asm
<bcf_gt2alleles>:
  endbr64
  test   %edi,%edi
  jle    L28
  mov    $0x1,%eax
  mov    $0x0,%ecx
L21:
  add    $0x1,%eax
  add    %eax,%ecx
  cmp    %ecx,%edi
  jg     L21
L22:
  sub    $0x1,%eax
  mov    %eax,(%rdx)
  sub    %ecx,%edi
  add    %eax,%edi
  mov    %edi,(%rsi)
  ret
L28:
  mov    $0x1,%eax
  mov    $0x0,%ecx
  jmp    L22
```

assistant: ```c
void bcf_gt2alleles(int igt, int *a, int *b) {
  int k = 0, dk = 1;
  while (k < igt) {
    dk++;
    k += dk;
  }
  *b = dk - 1;
  *a = igt - k + *b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<bcf_gt2alleles>:
  endbr64
  test   %edi,%edi
  jle    L0
  mov    $0x1,%ecx
  xor    %eax,%eax
  nop
L14:
  mov    %ecx,%r8d
  lea    0x1(%rcx),%ecx
  add    %ecx,%eax
  cmp    %eax,%edi
  jg     L14
  sub    %eax,%edi
  mov    %r8d,(%rdx)
  add    %r8d,%edi
  mov    %edi,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L0:
  xor    %r8d,%r8d
  mov    %r8d,(%rdx)
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void bcf_gt2alleles(int igt, int *a, int *b) {
  int k = 0, dk = 1;
  while (k < igt) {
    dk++;
    k += dk;
  }
  *b = dk - 1;
  *a = igt - k + *b;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bcf_gt2alleles>:
  endbr64
  test   %edi,%edi
  jle    L16
  mov    $0x1,%ecx
  xor    %eax,%eax
  nop
L7:
  mov    %ecx,%r8d
  lea    0x1(%rcx),%ecx
  add    %ecx,%eax
  cmp    %eax,%edi
  jg     L7
  sub    %eax,%edi
  mov    %r8d,(%rdx)
  add    %r8d,%edi
  mov    %edi,(%rsi)
  ret
  nopw   0x0(%rax,%rax,1)
L16:
  xor    %r8d,%r8d
  mov    %r8d,(%rdx)
  mov    %edi,(%rsi)
  ret
```

assistant: ```c
void bcf_gt2alleles(int igt, int *a, int *b) {
  int k = 0, dk = 1;
  while (k < igt) {
    dk++;
    k += dk;
  }
  *b = dk - 1;
  *a = igt - k + *b;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseSource>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x7(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rdx,%rdi
  call   <copyGraphToEOL@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    $0x1,%eax
  jg     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <errmessage1@plt>
  mov    $0x0,%eax
  jmp    L4
L7:
  mov    $0x1,%eax
L4:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D2
type: string

tool: D2: Could not parse an SOURCE out of "%s"


assistant: ```c
int parseSource(const char *line, char *source) {
  copyGraphToEOL(line + 6 + 1, source);
  if (strlen(source) < 2) {
    errmessage1("Could not parse an SOURCE out of \"%s\"\n", line);
    return 0;
  }
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<parseSource>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  lea    0x7(%rdi),%rdi
  call   <copyGraphToEOL@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  cmp    $0x1,%edx
  jle    L3
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  mov    %rbp,%rsi
  lea    D7(%rip),%rdi
  call   <errmessage1@plt>
  mov    $0x0,%eax
  jmp    L18
```

tool_calls: name: read_data
arguments: data_label: D7
type: string

tool: D7: Could not parse an SOURCE out of "%s"


assistant: ```c
int parseSource(const char *line, char *source) {
  copyGraphToEOL(line + 6 + 1, source);
  if (strlen(source) < 2) {
    errmessage1("Could not parse an SOURCE out of \"%s\"\n", line);
    return 0;
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parseSource>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  add    $0x7,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <copyGraphToEOL@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  jle    L6
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    %r12,%rsi
  lea    D5(%rip),%rdi
  call   <errmessage1@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D5
type_guessed: string

tool: D5: Could not parse an SOURCE out of "%s"


assistant: ```c
int parseSource(const char *line, char *source) {
  copyGraphToEOL(line + 6 + 1, source);
  if (strlen(source) < 2) {
    errmessage1("Could not parse an SOURCE out of \"%s\"\n", line);
    return 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parseSource>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  add    $0x7,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <copyGraphToEOL@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r8d
  mov    $0x1,%eax
  cmp    $0x1,%r8d
  jle    L4
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  mov    %r12,%rsi
  lea    D2(%rip),%rdi
  call   <errmessage1@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_infered: string

tool: D2: Could not parse an SOURCE out of "%s"


assistant: ```c
int parseSource(const char *line, char *source) {
  copyGraphToEOL(line + 6 + 1, source);
  if (strlen(source) < 2) {
    errmessage1("Could not parse an SOURCE out of \"%s\"\n", line);
    return 0;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<desloca_baixo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x1d,-0x4(%rbp)
  jmp    L4
L2:
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  subl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jg     L2
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void desloca_baixo(int ind_apelido[30], int indice) {
  int i;
  for (i = 30 - 1; i > indice; i--) {
    ind_apelido[i] = ind_apelido[i - 1];
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<desloca_baixo>:
  endbr64
  cmp    $0x1c,%esi
  jg     L15
  lea    0x70(%rdi),%rax
  add    $0x6c,%rdi
  mov    $0x1c,%edx
  sub    %esi,%edx
  shl    $0x2,%rdx
  sub    %rdx,%rdi
L18:
  mov    (%rax),%edx
  mov    %edx,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rdi,%rax
  jne    L18
L15:
  ret
```

assistant: ```c
void desloca_baixo(int ind_apelido[30], int indice) {
  int i;
  for (i = 30 - 1; i > indice; i--) {
    ind_apelido[i] = ind_apelido[i - 1];
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<desloca_baixo>:
  endbr64
  cmp    $0x1c,%esi
  jg     L5
  mov    $0x1c,%edx
  sub    %esi,%edx
  mov    %rdx,%rax
  lea    0x4(,%rdx,4),%rdx
  neg    %rax
  shl    $0x2,%rax
  lea    0x70(%rdi,%rax,1),%rsi
  lea    0x74(%rdi,%rax,1),%rdi
  jmp    1050 <memmove@plt>
  nopl   0x0(%rax)
L5:
  ret
```

assistant: ```c
void desloca_baixo(int ind_apelido[30], int indice) {
  int i;
  for (i = 30 - 1; i > indice; i--) {
    ind_apelido[i] = ind_apelido[i - 1];
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<desloca_baixo>:
  endbr64
  cmp    $0x1c,%esi
  jg     L0
  mov    $0x1c,%edx
  sub    %esi,%edx
  mov    %rdx,%rax
  lea    0x4(,%rdx,4),%rdx
  neg    %rax
  shl    $0x2,%rax
  lea    0x70(%rdi,%rax,1),%rsi
  lea    0x74(%rdi,%rax,1),%rdi
  jmp    1050 <memmove@plt>
  nopl   0x0(%rax)
L0:
  ret
```

assistant: ```c
void desloca_baixo(int ind_apelido[30], int indice) {
  int i;
  for (i = 30 - 1; i > indice; i--) {
    ind_apelido[i] = ind_apelido[i - 1];
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<partition>:
  endbr64
  mov    %rdi,%rcx
  mov    %esi,%eax
  mov    %edx,%edi
  lea    (%rsi,%rdx,1),%esi
  mov    %esi,%edx
  shr    $0x1f,%edx
  add    %esi,%edx
  sar    %edx
  movslq %edx,%rdx
  lea    (%rcx,%rdx,4),%rdx
  mov    (%rdx),%esi
  movslq %edi,%r8
  lea    (%rcx,%r8,4),%r8
  mov    (%r8),%r9d
  mov    %r9d,(%rdx)
  mov    %esi,(%r8)
  movslq %eax,%rdx
  cmp    (%rcx,%rdx,4),%esi
  jle    L68
  add    $0x1,%eax
  cltq
L22:
  mov    %eax,%edx
  add    $0x1,%rax
  cmp    %esi,-0x4(%rcx,%rax,4)
  jl     L22
L4:
  lea    0x1(%rdx),%eax
  cmp    %eax,%edi
  jle    L59
  cltq
  jmp    L75
L68:
  mov    %eax,%edx
  jmp    L4
L66:
  add    $0x1,%rax
  cmp    %eax,%edi
  jle    L59
L75:
  mov    (%rcx,%rax,4),%esi
  cmp    (%r8),%esi
  jg     L66
  movslq %edx,%r9
  lea    (%rcx,%r9,4),%r9
  mov    (%r9),%r10d
  mov    %r10d,(%rcx,%rax,4)
  mov    %esi,(%r9)
  add    $0x1,%edx
  jmp    L66
L59:
  movslq %edx,%rax
  lea    (%rcx,%rax,4),%rax
  mov    (%rax),%ecx
  mov    (%r8),%esi
  mov    %esi,(%rax)
  mov    %ecx,(%r8)
  mov    %edx,%eax
  ret
```

assistant: ```c
int partition(int array[], int start, int end) {
  int average = (start + end) / 2;
  int marker;
  int buffer = array[average];
  array[average] = array[end];
  array[end] = buffer;
  for (marker = start; array[marker] < array[end]; marker++)
    ;
  for (int i = marker + 1; i < end; i++) {
    if (array[i] <= array[end]) {
      buffer = array[i];
      array[i] = array[marker];
      array[marker] = buffer;
      marker += 1;
    }
  }
  buffer = array[marker];
  array[marker] = array[end];
  array[end] = buffer;
  return marker;
}
```