ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<runAutostart>:
  endbr64
  sub    $0x8,%rsp
  lea    D15(%rip),%rdi
  call   <system@plt>
  lea    D7(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <system@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string

tool: D15: cd ~/.dwm; ./autostart_blocking.sh

tool: D7: cd ~/.dwm; ./autostart.sh &

assistant: ```c
void runAutostart(void) {
  system("cd ~/.dwm; ./autostart_blocking.sh");
  system("cd ~/.dwm; ./autostart.sh &");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rx_thread_write_frame>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %ecx,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%ecx
  mov    -0x8(%rbp),%edx
  mov    -0x10(%rbp),%rsi
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <write_frame@plt>
  mov    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
int rx_thread_write_frame(int channel, const unsigned char *input, int length, unsigned char type) {
  write_frame(channel, input, length, type);
  return length;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rx_thread_write_frame>:
  endbr64
  push   %rbx
  mov    %edx,%ebx
  movzbl %cl,%ecx
  call   <write_frame@plt>
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int rx_thread_write_frame(int channel, const unsigned char *input, int length, unsigned char type) {
  write_frame(channel, input, length, type);
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<rx_thread_write_frame>:
  endbr64
  push   %r12
  movzbl %cl,%ecx
  mov    %edx,%r12d
  call   <write_frame@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int rx_thread_write_frame(int channel, const unsigned char *input, int length, unsigned char type) {
  write_frame(channel, input, length, type);
  return length;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rx_thread_write_frame>:
  endbr64
  push   %r12
  movzbl %cl,%ecx
  mov    %edx,%r12d
  call   <write_frame@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int rx_thread_write_frame(int channel, const unsigned char *input, int length, unsigned char type) {
  write_frame(channel, input, length, type);
  return length;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<findPrime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x3,-0x14(%rbp)
  jg     L4
  mov    $0x3,%eax
  jmp    L70
L4:
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L57
  addl   $0x1,-0x14(%rbp)
L57:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  movq   %xmm1,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  movl   $0x3,-0x8(%rbp)
  jmp    L58
L68:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x8(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L31
  addl   $0x1,-0x8(%rbp)
L58:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L68
  jmp    L60
L31:
  nop
L60:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L86
  mov    -0x14(%rbp),%eax
  jmp    L70
L86:
  addl   $0x2,-0x14(%rbp)
  jmp    L57
L70:
  leave
  ret
```

assistant: ```c
int findPrime(int value) {
  if (value <= 3)
    return 3;
  if ((value & 1) == 0)
    value++;
  for (;;) {
    int root = (int)floor(sqrt((double)value)) + 1;
    int divisor;
    for (divisor = 3; divisor <= root; divisor++) {
      if ((value % divisor) == 0)
        break;
    }
    if (divisor > root)
      return value;
    value += 2;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<findPrime>:
  endbr64
  push   %rbx
  mov    $0x3,%ebx
  cmp    $0x3,%edi
  jle    L29
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%edi
  mov    %edi,%ebx
  jmp    L7
L35:
  add    $0x2,%ebx
L7:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L29
  movslq %ebx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  lea    (%rax,%rax,2),%eax
  cmp    %eax,%ebx
  je     L35
  mov    $0x3,%ecx
L43:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cmp    %eax,%esi
  jl     L29
  mov    %ebx,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  jne    L43
  jmp    L35
L29:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

assistant: ```c
int findPrime(int value) {
  if (value <= 3)
    return 3;
  if ((value & 1) == 0)
    value++;
  for (;;) {
    int root = (int)floor(sqrt((double)value)) + 1;
    int divisor;
    for (divisor = 3; divisor <= root; divisor++) {
      if ((value % divisor) == 0)
        break;
    }
    if (divisor > root)
      return value;
    value += 2;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<findPrime>:
  endbr64
  push   %r12
  mov    $0x3,%r12d
  cmp    $0x3,%edi
  jle    L36
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%edi
  mov    %edi,%r12d
  nop
L45:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L36
  imul   $0xaaaaaaab,%r12d,%eax
  cmp    $0x55555555,%eax
  jbe    L54
  mov    $0x3,%ecx
  jmp    L27
  nopl   0x0(%rax)
L11:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L54
L27:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cmp    %eax,%esi
  jge    L11
L36:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L54:
  add    $0x2,%r12d
  jmp    L45
```

assistant: ```c
int findPrime(int value) {
  if (value <= 3)
    return 3;
  if ((value & 1) == 0)
    value++;
  for (;;) {
    int root = (int)floor(sqrt((double)value)) + 1;
    int divisor;
    for (divisor = 3; divisor <= root; divisor++) {
      if ((value % divisor) == 0)
        break;
    }
    if (divisor > root)
      return value;
    value += 2;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<findPrime>:
  endbr64
  push   %r12
  mov    $0x3,%r12d
  cmp    $0x3,%edi
  jle    L12
  mov    %edi,%eax
  and    $0x1,%eax
  cmp    $0x1,%eax
  adc    $0x0,%edi
  mov    %edi,%r12d
  nop
L65:
  pxor   %xmm0,%xmm0
  cvtsi2sd %r12d,%xmm0
  call   <sqrt@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,%esi
  cmp    $0x1,%eax
  jle    L12
  imul   $0xaaaaaaab,%r12d,%eax
  cmp    $0x55555555,%eax
  jbe    L20
  mov    $0x3,%ecx
  jmp    L15
  nopl   0x0(%rax)
L42:
  mov    %r12d,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L20
L15:
  mov    %ecx,%eax
  add    $0x1,%ecx
  cmp    %eax,%esi
  jge    L42
L12:
  mov    %r12d,%eax
  pop    %r12
  ret
  nopl   0x0(%rax)
L20:
  add    $0x2,%r12d
  jmp    L65
```

assistant: ```c
int findPrime(int value) {
  if (value <= 3)
    return 3;
  if ((value & 1) == 0)
    value++;
  for (;;) {
    int root = (int)floor(sqrt((double)value)) + 1;
    int divisor;
    for (divisor = 3; divisor <= root; divisor++) {
      if ((value % divisor) == 0)
        break;
    }
    if (divisor > root)
      return value;
    value += 2;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<twoSum>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %rcx,-0x38(%rbp)
  mov    -0x38(%rbp),%rax
  movl   $0x2,(%rax)
  movl   $0x0,-0x1c(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L108
L84:
  mov    -0x18(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x30(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L13
L68:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x2c(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L71
L57:
  mov    -0x1c(%rbp),%eax
  sub    -0x20(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jne    L73
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    -0xc(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  jmp    L94
L73:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jge    L76
  mov    -0xc(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0x1c(%rbp)
  jmp    L71
L76:
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  cmp    %eax,-0x10(%rbp)
  jle    L71
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x20(%rbp)
L71:
  mov    -0x20(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L57
  addl   $0x1,-0x14(%rbp)
L13:
  mov    -0x14(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L68
  addl   $0x1,-0x18(%rbp)
L108:
  mov    -0x18(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jl     L84
  mov    -0x8(%rbp),%rax
L94:
  leave
  ret
```

assistant: ```c
int *twoSum(int *numbers, int numbersSize, int target, int *returnSize) {
  *returnSize = 2;
  int k, l, m, r = 0;
  int *returnA = (int *)malloc(sizeof(int) * 2);
  for (int i = 0; i < numbersSize; i++) {
    k = target - numbers[i];
    for (int j = i + 1; j < numbersSize; j++) {
      l = j, r = numbersSize - 1;
      while (l < r) {
        m = l + (r - l) / 2;
        if (k == numbers[m]) {
          returnA[0] = i + 1;
          returnA[1] = m + 1;
          return returnA;
        } else if (k < numbers[m]) {
          r = m - 1;
        } else if (k > numbers[m]) {
          l = m + 1;
        }
      }
    }
  }
  return returnA;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<twoSum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%ebp
  mov    %edx,%r12d
  movl   $0x2,(%rcx)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L11
  mov    %ebp,%r13d
  mov    $0x1,%r9d
  lea    -0x1(%rbp),%r10d
L82:
  mov    %r12d,%esi
  sub    -0x4(%rbx,%r9,4),%esi
  mov    %r9d,%r11d
  cmp    %r13,%r9
  je     L11
  mov    %r9d,%edi
L51:
  mov    %r10d,%ecx
  cmp    %edi,%r10d
  jle    L50
  mov    %edi,%edx
  jmp    L53
L52:
  mov    %r11d,(%r8)
  add    $0x1,%eax
  mov    %eax,0x4(%r8)
L11:
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  add    $0x1,%eax
  cmp    %esi,%r14d
  cmovl  %eax,%edx
L5:
  cmp    %ecx,%edx
  jge    L50
L53:
  mov    %ecx,%r14d
  sub    %edx,%r14d
  mov    %r14d,%eax
  shr    $0x1f,%eax
  add    %r14d,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r14
  mov    (%rbx,%r14,4),%r14d
  cmp    %esi,%r14d
  je     L52
  jle    L21
  lea    -0x1(%rax),%ecx
  jmp    L5
L50:
  add    $0x1,%edi
  cmp    %edi,%ebp
  jne    L51
  add    $0x1,%r9
  jmp    L82
```

assistant: ```c
int *twoSum(int *numbers, int numbersSize, int target, int *returnSize) {
  *returnSize = 2;
  int k, l, m, r = 0;
  int *returnA = (int *)malloc(sizeof(int) * 2);
  for (int i = 0; i < numbersSize; i++) {
    k = target - numbers[i];
    for (int j = i + 1; j < numbersSize; j++) {
      l = j, r = numbersSize - 1;
      while (l < r) {
        m = l + (r - l) / 2;
        if (k == numbers[m]) {
          returnA[0] = i + 1;
          returnA[1] = m + 1;
          return returnA;
        } else if (k < numbers[m]) {
          r = m - 1;
        } else if (k > numbers[m]) {
          l = m + 1;
        }
      }
    }
  }
  return returnA;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<twoSum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  movl   $0x2,(%rcx)
  call   <malloc@plt>
  mov    %rax,%r8
  test   %ebp,%ebp
  jle    L105
  movslq %ebp,%r13
  mov    $0x1,%r9d
  lea    -0x1(%rbp),%r10d
L39:
  mov    %r12d,%esi
  mov    %r9d,%r11d
  sub    -0x4(%rbx,%r9,4),%esi
  cmp    %r9,%r13
  je     L105
  mov    %r9d,%edi
L15:
  cmp    %r10d,%edi
  jge    L86
  mov    %r10d,%ecx
  mov    %edi,%edx
  jmp    L54
  nopw   0x0(%rax,%rax,1)
L30:
  lea    -0x1(%rax),%ecx
L14:
  cmp    %ecx,%edx
  jge    L86
L54:
  mov    %ecx,%eax
  sub    %edx,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r14
  cmp    %esi,(%rbx,%r14,4)
  je     L3
  jg     L30
  jge    L14
  lea    0x1(%rax),%edx
  cmp    %ecx,%edx
  jl     L54
L86:
  add    $0x1,%edi
  cmp    %edi,%ebp
  jne    L15
  add    $0x1,%r9
  jmp    L39
L3:
  add    $0x1,%eax
  mov    %r11d,(%r8)
  mov    %eax,0x4(%r8)
L105:
  pop    %rbx
  mov    %r8,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *twoSum(int *numbers, int numbersSize, int target, int *returnSize) {
  *returnSize = 2;
  int k, l, m, r = 0;
  int *returnA = (int *)malloc(sizeof(int) * 2);
  for (int i = 0; i < numbersSize; i++) {
    k = target - numbers[i];
    for (int j = i + 1; j < numbersSize; j++) {
      l = j, r = numbersSize - 1;
      while (l < r) {
        m = l + (r - l) / 2;
        if (k == numbers[m]) {
          returnA[0] = i + 1;
          returnA[1] = m + 1;
          return returnA;
        } else if (k < numbers[m]) {
          r = m - 1;
        } else if (k > numbers[m]) {
          l = m + 1;
        }
      }
    }
  }
  return returnA;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<twoSum>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  movl   $0x2,(%rcx)
  call   <malloc@plt>
  mov    %rax,%r9
  test   %ebp,%ebp
  jle    L12
  movslq %ebp,%r13
  mov    $0x1,%r8d
  lea    -0x1(%rbp),%r10d
L11:
  mov    %r12d,%esi
  mov    %r8d,%r11d
  sub    -0x4(%rbx,%r8,4),%esi
  cmp    %r8,%r13
  je     L12
  mov    %r8d,%edi
L102:
  cmp    %r10d,%edi
  jge    L55
  mov    %r10d,%ecx
  mov    %edi,%edx
  jmp    L87
  nopw   0x0(%rax,%rax,1)
L25:
  lea    -0x1(%rax),%ecx
L61:
  cmp    %ecx,%edx
  jge    L55
L87:
  mov    %ecx,%eax
  sub    %edx,%eax
  sar    %eax
  add    %edx,%eax
  movslq %eax,%r14
  cmp    %esi,(%rbx,%r14,4)
  je     L79
  jg     L25
  jge    L61
  lea    0x1(%rax),%edx
  cmp    %ecx,%edx
  jl     L87
L55:
  add    $0x1,%edi
  cmp    %edi,%ebp
  jne    L102
  add    $0x1,%r8
  jmp    L11
L79:
  add    $0x1,%eax
  movd   %r11d,%xmm0
  movd   %eax,%xmm1
  punpckldq %xmm1,%xmm0
  movq   %xmm0,(%r9)
L12:
  pop    %rbx
  mov    %r9,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *twoSum(int *numbers, int numbersSize, int target, int *returnSize) {
  *returnSize = 2;
  int k, l, m, r = 0;
  int *returnA = (int *)malloc(sizeof(int) * 2);
  for (int i = 0; i < numbersSize; i++) {
    k = target - numbers[i];
    for (int j = i + 1; j < numbersSize; j++) {
      l = j, r = numbersSize - 1;
      while (l < r) {
        m = l + (r - l) / 2;
        if (k == numbers[m]) {
          returnA[0] = i + 1;
          returnA[1] = m + 1;
          return returnA;
        } else if (k < numbers[m]) {
          r = m - 1;
        } else if (k > numbers[m]) {
          l = m + 1;
        }
      }
    }
  }
  return returnA;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L15
L8:
  subl   $0x1,-0x8(%rbp)
  mov    -0x4(%rbp),%edx
  mov    $0x0,%eax
  sub    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
L15:
  mov    -0x8(%rbp),%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  test   %eax,%eax
  jg     L8
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x + y > 0) {
    x = x - 1;
    y = -2 * y;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <__VERIFIER_nondet_int@plt>
  lea    (%rbx,%rax,1),%edx
  test   %edx,%edx
  jle    L14
L5:
  sub    $0x1,%ebx
  neg    %eax
  lea    (%rax,%rax,1),%edx
  mov    %edx,%eax
  add    %ebx,%edx
  test   %edx,%edx
  jg     L5
L14:
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x + y > 0) {
    x = x - 1;
    y = -2 * y;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x + y > 0) {
    x = x - 1;
    y = -2 * y;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  call   <__VERIFIER_nondet_int@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  int x, y;
  x = __VERIFIER_nondet_int();
  y = __VERIFIER_nondet_int();
  while (x + y > 0) {
    x = x - 1;
    y = -2 * y;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<eventLoop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L0:
  mov    $0x0,%eax
  call   <eventLoopInterrupt@plt>
  jmp    L0
```

assistant: ```c
void eventLoop() {
head:
  eventLoopInterrupt();
  goto head;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<eventLoop>:
  endbr64
  sub    $0x8,%rsp
L8:
  mov    $0x0,%eax
  call   <eventLoopInterrupt@plt>
  jmp    L8
```

assistant: ```c
void eventLoop() {
head:
  eventLoopInterrupt();
  goto head;
}
```
user: What is the c source code of the assembly code below?

```asm
<eventLoop>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L2:
  xor    %eax,%eax
  call   <eventLoopInterrupt@plt>
  jmp    L2
```

assistant: ```c
void eventLoop() {
head:
  eventLoopInterrupt();
  goto head;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<eventLoop>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  call   <eventLoopInterrupt@plt>
  jmp    L0
```

assistant: ```c
void eventLoop() {
head:
  eventLoopInterrupt();
  goto head;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<generic_hweight8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x55,%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  shr    %eax
  and    $0x55,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x33,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x2,%eax
  and    $0x33,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  shr    $0x4,%eax
  and    $0xf,%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int generic_hweight8(unsigned int w) {
  unsigned int res = (w & 0x55) + ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res & 0x0F) + ((res >> 4) & 0x0F);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<generic_hweight8>:
  endbr64
  mov    %edi,%eax
  shr    %eax
  and    $0x55,%eax
  and    $0x55,%edi
  add    %eax,%edi
  mov    %edi,%edx
  and    $0x33,%edx
  shr    $0x2,%edi
  and    $0x33,%edi
  add    %edi,%edx
  mov    %edx,%eax
  and    $0xf,%eax
  shr    $0x4,%edx
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int generic_hweight8(unsigned int w) {
  unsigned int res = (w & 0x55) + ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res & 0x0F) + ((res >> 4) & 0x0F);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<generic_hweight8>:
  endbr64
  mov    %edi,%eax
  and    $0x55,%edi
  shr    %eax
  and    $0x55,%eax
  add    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33,%edx
  and    $0x33,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%edx
  and    $0xf,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int generic_hweight8(unsigned int w) {
  unsigned int res = (w & 0x55) + ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res & 0x0F) + ((res >> 4) & 0x0F);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<generic_hweight8>:
  endbr64
  mov    %edi,%eax
  and    $0x55,%edi
  shr    %eax
  and    $0x55,%eax
  add    %eax,%edi
  mov    %edi,%edx
  shr    $0x2,%edi
  and    $0x33,%edx
  and    $0x33,%edi
  add    %edi,%edx
  mov    %edx,%eax
  shr    $0x4,%edx
  and    $0xf,%eax
  add    %edx,%eax
  ret
```

assistant: ```c
unsigned int generic_hweight8(unsigned int w) {
  unsigned int res = (w & 0x55) + ((w >> 1) & 0x55);
  res = (res & 0x33) + ((res >> 2) & 0x33);
  return (res & 0x0F) + ((res >> 4) & 0x0F);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<waitfor>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L67
L60:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x5(%rbp)
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <feof@plt>
  test   %rax,%rax
  je     L33
  mov    $0x0,%eax
  jmp    L1
L33:
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L37
  addl   $0x1,-0x4(%rbp)
  jmp    L67
L37:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x5(%rbp)
  jne    L62
  movl   $0x1,-0x4(%rbp)
  jmp    L67
L62:
  movl   $0x0,-0x4(%rbp)
L67:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x4(%rbp)
  jb     L60
  mov    $0x1,%eax
L1:
  leave
  ret
```

assistant: ```c
int waitfor(char *end) {
  unsigned int i = 0;
  char c;
  while (i < strlen(end)) {
    c = getchar();
    if (feof(stdin))
      return 0;
    else if (c == end[i])
      i++;
    else if (c == end[0])
      i = 1;
    else
      i = 0;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<waitfor>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x0,%ebp
L42:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebp,%eax
  jbe    L1
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <feof@plt>
  test   %rax,%rax
  jne    L10
  mov    %ebp,%eax
  add    $0x1,%ebp
  cmp    %bl,(%r12,%rax,1)
  je     L42
  cmp    %bl,(%r12)
  sete   %bpl
  movzbl %bpl,%ebp
  jmp    L42
L1:
  mov    $0x1,%eax
L3:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L10:
  mov    $0x0,%eax
  jmp    L3
```

assistant: ```c
int waitfor(char *end) {
  unsigned int i = 0;
  char c;
  while (i < strlen(end)) {
    c = getchar();
    if (feof(stdin))
      return 0;
    else if (c == end[i])
      i++;
    else if (c == end[0])
      i = 1;
    else
      i = 0;
  }
  return 1;
}
```