ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<interp_cubic>:
  endbr64
  movaps %xmm0,%xmm6
  movaps %xmm0,%xmm5
  pxor   %xmm9,%xmm9
  movsd  D23(%rip),%xmm0
  cvtss2sd %xmm1,%xmm9
  movapd %xmm9,%xmm10
  pxor   %xmm8,%xmm8
  movaps %xmm4,%xmm7
  mulsd  %xmm0,%xmm10
  cvtss2sd %xmm2,%xmm8
  cvtss2sd %xmm3,%xmm3
  subss  %xmm6,%xmm2
  mulsd  %xmm8,%xmm0
  xorps  D28(%rip),%xmm5
  addss  %xmm1,%xmm1
  mulss  %xmm4,%xmm7
  cvtss2sd %xmm5,%xmm5
  mulss  %xmm4,%xmm2
  mulsd  D3(%rip),%xmm9
  mulsd  D16(%rip),%xmm8
  addsd  %xmm10,%xmm5
  subsd  %xmm0,%xmm5
  addsd  %xmm3,%xmm5
  cvtsd2ss %xmm5,%xmm5
  mulss  %xmm7,%xmm5
  movaps %xmm5,%xmm0
  pxor   %xmm5,%xmm5
  cvtss2sd %xmm6,%xmm5
  addsd  %xmm5,%xmm5
  mulss  %xmm4,%xmm0
  subsd  %xmm9,%xmm5
  addsd  %xmm8,%xmm5
  subsd  %xmm3,%xmm5
  pxor   %xmm3,%xmm3
  cvtsd2ss %xmm5,%xmm3
  mulss  %xmm7,%xmm3
  addss  %xmm3,%xmm0
  movaps %xmm0,%xmm5
  movss  D15(%rip),%xmm0
  addss  %xmm2,%xmm5
  addss  %xmm1,%xmm5
  mulss  %xmm5,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: tag: D23
type_infered: f64
name: unpack_data
arguments: tag: D28
type_infered: byte[16]
name: unpack_data
arguments: tag: D3
type_infered: f64
name: unpack_data
arguments: tag: D16
type_infered: f64
name: unpack_data
arguments: tag: D15
type_infered: f32

tool: D23: 3

tool: {"D28": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D3: 5

tool: D16: 4

tool: D15: 0.5

assistant: ```c
float interp_cubic(float a, float b, float c, float d, float t) {
  float x, y, z, w;
  float tsq = t * t;
  x = -a + 3.0 * b - 3.0 * c + d;
  y = 2.0 * a - 5.0 * b + 4.0 * c - d;
  z = c - a;
  w = 2.0 * b;
  return 0.5 * (x * tsq * t + y * tsq + z * t + w);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvt_bin24_31x5>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0xc,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  shl    $0x5,%eax
  sub    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  add    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t cvt_bin24_31x5(const uint8_t *gfv) {
  unsigned r = gfv[4];
  r = (r << 5) - r + gfv[3];
  r = (r << 5) - r + gfv[2];
  r = (r << 5) - r + gfv[1];
  return (r << 5) - r + gfv[0];
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cvt_bin24_31x5>:
  endbr64
  mov    0x10(%rdi),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  add    0xc(%rdi),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    0x8(%rdi),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  add    0x4(%rdi),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    (%rdi),%eax
  ret
```

assistant: ```c
uint32_t cvt_bin24_31x5(const uint8_t *gfv) {
  unsigned r = gfv[4];
  r = (r << 5) - r + gfv[3];
  r = (r << 5) - r + gfv[2];
  r = (r << 5) - r + gfv[1];
  return (r << 5) - r + gfv[0];
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cvt_bin24_31x5>:
  endbr64
  mov    0x10(%rdi),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  add    0xc(%rdi),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    0x8(%rdi),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  add    0x4(%rdi),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    (%rdi),%eax
  ret
```

assistant: ```c
uint32_t cvt_bin24_31x5(const uint8_t *gfv) {
  unsigned r = gfv[4];
  r = (r << 5) - r + gfv[3];
  r = (r << 5) - r + gfv[2];
  r = (r << 5) - r + gfv[1];
  return (r << 5) - r + gfv[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cvt_bin24_31x5>:
  endbr64
  mov    0x10(%rdi),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  add    0xc(%rdi),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    0x8(%rdi),%eax
  mov    %eax,%edx
  shl    $0x5,%edx
  sub    %eax,%edx
  add    0x4(%rdi),%edx
  mov    %edx,%eax
  shl    $0x5,%eax
  sub    %edx,%eax
  add    (%rdi),%eax
  ret
```

assistant: ```c
uint32_t cvt_bin24_31x5(const uint8_t *gfv) {
  unsigned r = gfv[4];
  r = (r << 5) - r + gfv[3];
  r = (r << 5) - r + gfv[2];
  r = (r << 5) - r + gfv[1];
  return (r << 5) - r + gfv[0];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<evtag_marshal_kill>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    $0x0,%eax
  call   <evbuffer_new@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x28(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <kill_marshal@plt>
  mov    -0x8(%rbp),%rdx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <evtag_marshal_buffer@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <evbuffer_free@plt>
  nop
  leave
  ret
```

assistant: ```c
void evtag_marshal_kill(struct evbuffer *evbuf, ev_uint32_t tag, const struct kill *msg) {
  struct evbuffer *_buf = evbuffer_new();
  assert(_buf != NULL);
  kill_marshal(_buf, msg);
  evtag_marshal_buffer(evbuf, tag, _buf);
  evbuffer_free(_buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<evtag_marshal_kill>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  mov    %rdx,%r13
  mov    $0x0,%eax
  call   <evbuffer_new@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <kill_marshal@plt>
  mov    %rbx,%rdx
  mov    %r12d,%esi
  mov    %rbp,%rdi
  call   <evtag_marshal_buffer@plt>
  mov    %rbx,%rdi
  call   <evbuffer_free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void evtag_marshal_kill(struct evbuffer *evbuf, ev_uint32_t tag, const struct kill *msg) {
  struct evbuffer *_buf = evbuffer_new();
  assert(_buf != NULL);
  kill_marshal(_buf, msg);
  evtag_marshal_buffer(evbuf, tag, _buf);
  evbuffer_free(_buf);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<evtag_marshal_kill>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <evbuffer_new@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <kill_marshal@plt>
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r13d,%esi
  call   <evtag_marshal_buffer@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <evbuffer_free@plt>
```

assistant: ```c
void evtag_marshal_kill(struct evbuffer *evbuf, ev_uint32_t tag, const struct kill *msg) {
  struct evbuffer *_buf = evbuffer_new();
  assert(_buf != NULL);
  kill_marshal(_buf, msg);
  evtag_marshal_buffer(evbuf, tag, _buf);
  evbuffer_free(_buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<evtag_marshal_kill>:
  endbr64
  push   %r14
  xor    %eax,%eax
  mov    %rdx,%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <evbuffer_new@plt>
  xor    %edi,%edi
  test   %rax,%rax
  mov    %rax,%rbp
  setne  %dil
  call   <assert@plt>
  mov    %r14,%rsi
  mov    %rbp,%rdi
  call   <kill_marshal@plt>
  mov    %r12,%rdi
  mov    %rbp,%rdx
  mov    %r13d,%esi
  call   <evtag_marshal_buffer@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    10b0 <evbuffer_free@plt>
```

assistant: ```c
void evtag_marshal_kill(struct evbuffer *evbuf, ev_uint32_t tag, const struct kill *msg) {
  struct evbuffer *_buf = evbuffer_new();
  assert(_buf != NULL);
  kill_marshal(_buf, msg);
  evtag_marshal_buffer(evbuf, tag, _buf);
  evbuffer_free(_buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<file_name>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  setne  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x18(%rbp),%rax
  mov    $0x2f,%esi
  mov    %rax,%rdi
  call   <strrchr@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L14
  mov    -0x18(%rbp),%rax
  jmp    L0
L14:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
L0:
  leave
  ret
```

assistant: ```c
char *file_name(const char *path) {
  char *name;
  assert(path != NULL);
  if ((name = strrchr(path, '/')) == NULL) {
    return (char *)path;
  }
  return (name + 1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<file_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  test   %rdi,%rdi
  setne  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    $0x2f,%esi
  mov    %rbx,%rdi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  cmovne %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
char *file_name(const char *path) {
  char *name;
  assert(path != NULL);
  if ((name = strrchr(path, '/')) == NULL) {
    return (char *)path;
  }
  return (name + 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<file_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *file_name(const char *path) {
  char *name;
  assert(path != NULL);
  if ((name = strrchr(path, '/')) == NULL) {
    return (char *)path;
  }
  return (name + 1);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<file_name>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  xor    %edi,%edi
  test   %rbx,%rbx
  setne  %dil
  call   <assert@plt>
  mov    %rbx,%rdi
  mov    $0x2f,%esi
  call   <strrchr@plt>
  lea    0x1(%rax),%rdx
  test   %rax,%rax
  mov    %rbx,%rax
  pop    %rbx
  cmovne %rdx,%rax
  ret
```

assistant: ```c
char *file_name(const char *path) {
  char *name;
  assert(path != NULL);
  if ((name = strrchr(path, '/')) == NULL) {
    return (char *)path;
  }
  return (name + 1);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<multiply281>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %rcx,-0x58(%rbp)
  mov    %r8,-0x60(%rbp)
  mov    -0x44(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x38(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  mov    -0x44(%rbp),%edx
  movslq %edx,%rcx
  sub    $0x1,%rcx
  mov    %rcx,-0x30(%rbp)
  movslq %edx,%rcx
  mov    %rcx,%r12
  mov    $0x0,%r13d
  mov    -0x44(%rbp),%ecx
  movslq %ecx,%rsi
  sub    $0x1,%rsi
  mov    %rsi,-0x28(%rbp)
  movslq %ecx,%rsi
  mov    %rsi,%r10
  mov    $0x0,%r11d
  movl   $0x0,-0x40(%rbp)
  jmp    L24
L5:
  movl   $0x0,-0x3c(%rbp)
  jmp    L0
L32:
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %eax,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x50(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%esi
  imul   -0x48(%rbp),%esi
  mov    %esi,%r9d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %edx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x58(%rbp),%rsi
  add    %rsi,%rdi
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    (%rdi,%rsi,4),%r8d
  mov    -0x40(%rbp),%esi
  movslq %esi,%rdi
  movslq %ecx,%rsi
  imul   %rdi,%rsi
  lea    0x0(,%rsi,4),%rdi
  mov    -0x60(%rbp),%rsi
  add    %rsi,%rdi
  add    %r9d,%r8d
  mov    -0x3c(%rbp),%esi
  movslq %esi,%rsi
  mov    %r8d,(%rdi,%rsi,4)
  addl   $0x1,-0x3c(%rbp)
L0:
  mov    -0x3c(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L32
  addl   $0x1,-0x40(%rbp)
L24:
  mov    -0x40(%rbp),%esi
  cmp    -0x44(%rbp),%esi
  jl     L5
  nop
  nop
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void multiply281(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<multiply281>:
  endbr64
  test   %edi,%edi
  jle    L21
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  mov    %esi,%r10d
  movslq %edi,%r12
  shl    $0x2,%r12
  mov    %rdx,%rbp
  mov    $0x0,%r13d
  mov    %edi,%r11d
L8:
  mov    %rbp,%r9
  mov    %rcx,%rdi
  mov    %r8,%rsi
  mov    $0x0,%eax
L14:
  mov    %r10d,%edx
  imul   (%r9,%rax,4),%edx
  add    (%rdi,%rax,4),%edx
  mov    %edx,(%rsi,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r11
  jne    L14
  add    $0x1,%r13d
  add    %r12,%rbp
  add    %r12,%rcx
  add    %r12,%r8
  cmp    %r13d,%ebx
  jne    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  ret
```

assistant: ```c
void multiply281(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<multiply281>:
  endbr64
  test   %edi,%edi
  jle    L28
  movslq %edi,%r10
  push   %rbx
  mov    %esi,%r9d
  xor    %r11d,%r11d
  lea    0x0(,%r10,4),%rbx
  nopw   0x0(%rax,%rax,1)
L22:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L26:
  mov    (%rdx,%rax,4),%esi
  imul   %r9d,%esi
  add    (%rcx,%rax,4),%esi
  mov    %esi,(%r8,%rax,4)
  add    $0x1,%rax
  cmp    %r10,%rax
  jne    L26
  add    $0x1,%r11d
  add    %rbx,%rdx
  add    %rbx,%rcx
  add    %rbx,%r8
  cmp    %r11d,%edi
  jne    L22
  pop    %rbx
  ret
L28:
  ret
```

assistant: ```c
void multiply281(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<multiply281>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
  test   %ebp,%ebp
  jle    L47
  mov    %rbp,%r11
  mov    %esi,%ebx
  lea    0x4(%rdx),%r10
  mov    %r8,%rax
  mov    %r11d,%edx
  mov    %r11d,%esi
  lea    0x4(%rcx),%r9
  shl    $0x2,%rbp
  and    $0xfffffffc,%esi
  shr    $0x2,%edx
  movd   %ebx,%xmm4
  xor    %r12d,%r12d
  lea    0x1(%rsi),%ecx
  lea    0x2(%rsi),%edi
  mov    %esi,-0x24(%rsp)
  movslq %esi,%r13
  lea    -0x1(%rdx),%r8d
  mov    %r11d,%esi
  lea    -0x1(%r11),%edx
  mov    %ecx,-0x20(%rsp)
  pshufd $0x0,%xmm4,%xmm2
  mov    %edi,-0x1c(%rsp)
  add    $0x1,%r8
  movslq %ecx,%r14
  mov    %edx,-0x28(%rsp)
  movdqa %xmm2,%xmm3
  shl    $0x4,%r8
  movslq %edi,%r15
  mov    %rsi,-0x10(%rsp)
  psrlq  $0x20,%xmm3
  nopl   (%rax)
L70:
  mov    %rax,%rdx
  lea    -0x4(%r10),%rcx
  lea    -0x4(%r9),%rsi
  sub    %r10,%rdx
  cmp    $0x8,%rdx
  mov    %rax,%rdx
  seta   %dil
  sub    %r9,%rdx
  cmp    $0x8,%rdx
  seta   %dl
  test   %dl,%dil
  je     L28
  xor    %edx,%edx
  cmpl   $0x2,-0x28(%rsp)
  jbe    L28
  nopl   0x0(%rax)
L59:
  movdqu (%rcx,%rdx,1),%xmm0
  movdqu (%rcx,%rdx,1),%xmm1
  psrlq  $0x20,%xmm0
  pmuludq %xmm2,%xmm1
  pmuludq %xmm3,%xmm0
  pshufd $0x8,%xmm1,%xmm1
  pshufd $0x8,%xmm0,%xmm0
  punpckldq %xmm0,%xmm1
  movdqu (%rsi,%rdx,1),%xmm0
  paddd  %xmm1,%xmm0
  movups %xmm0,(%rax,%rdx,1)
  add    $0x10,%rdx
  cmp    %r8,%rdx
  jne    L59
  cmp    -0x24(%rsp),%r11d
  je     L68
  mov    (%rcx,%r13,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r13,4),%edx
  mov    %edx,(%rax,%r13,4)
  cmp    -0x20(%rsp),%r11d
  jle    L68
  mov    (%rcx,%r14,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r14,4),%edx
  mov    %edx,(%rax,%r14,4)
  cmp    -0x1c(%rsp),%r11d
  jle    L68
  mov    (%rcx,%r15,4),%edx
  imul   %ebx,%edx
  add    (%rsi,%r15,4),%edx
  mov    %edx,(%rax,%r15,4)
L68:
  add    $0x1,%r12d
  add    %rbp,%rax
  add    %rbp,%r10
  add    %rbp,%r9
  cmp    %r12d,%r11d
  jne    L70
L47:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    %r8,-0x18(%rsp)
  mov    -0x10(%rsp),%r8
  xor    %edx,%edx
  nopl   0x0(%rax)
L55:
  mov    (%rcx,%rdx,4),%edi
  imul   %ebx,%edi
  add    (%rsi,%rdx,4),%edi
  mov    %edi,(%rax,%rdx,4)
  add    $0x1,%rdx
  cmp    %rdx,%r8
  jne    L55
  mov    -0x18(%rsp),%r8
  jmp    L68
```

assistant: ```c
void multiply281(int n, int a, int tab1[n][n], int tab2[n][n], int tab3[n][n]) {
  int i, j, k;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      tab3[i][j] = a * tab1[i][j] + tab2[i][j];
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<drp_explain>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x6,%edi
  call   <drp_value@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x6,%esi
  mov    $0x0,%edi
  call   <drp_set@plt>
  mov    -0x8(%rbp),%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L68
  mov    $0x0,%eax
  jmp    L52
L68:
  mov    -0x8(%rbp),%rax
  and    $0x2,%eax
  test   %rax,%rax
  je     L12
  mov    $0x1,%eax
  jmp    L52
L12:
  mov    -0x8(%rbp),%rax
  and    $0x4,%eax
  test   %rax,%rax
  je     L73
  mov    $0x2,%eax
  jmp    L52
L73:
  mov    -0x8(%rbp),%rax
  and    $0x8,%eax
  test   %rax,%rax
  je     L61
  mov    $0x3,%eax
  jmp    L52
L61:
  mov    $0xffffffff,%eax
L52:
  leave
  ret
```

assistant: ```c
int drp_explain() {
  unsigned long val = drp_value(6);
  drp_set(0x0, 6);
  if (val & 0x01) {
    return 0;
  } else if (val & 0x02) {
    return 1;
  } else if (val & 0x04) {
    return 2;
  } else if (val & 0x08) {
    return 3;
  } else {
    return -1;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<drp_explain>:
  endbr64
  push   %rbx
  mov    $0x6,%edi
  call   <drp_value@plt>
  mov    %rax,%rbx
  mov    $0x6,%esi
  mov    $0x0,%edi
  call   <drp_set@plt>
  mov    $0x0,%eax
  test   $0x1,%bl
  jne    L20
  mov    $0x1,%eax
  test   $0x2,%bl
  jne    L20
  mov    $0x2,%eax
  test   $0x4,%bl
  jne    L20
  and    $0x8,%ebx
  cmp    $0x1,%rbx
  sbb    %eax,%eax
  or     $0x3,%eax
L20:
  pop    %rbx
  ret
```

assistant: ```c
int drp_explain() {
  unsigned long val = drp_value(6);
  drp_set(0x0, 6);
  if (val & 0x01) {
    return 0;
  } else if (val & 0x02) {
    return 1;
  } else if (val & 0x04) {
    return 2;
  } else if (val & 0x08) {
    return 3;
  } else {
    return -1;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<drp_explain>:
  endbr64
  push   %rbx
  mov    $0x6,%edi
  call   <drp_value@plt>
  mov    $0x6,%esi
  xor    %edi,%edi
  mov    %rax,%rbx
  call   <drp_set@plt>
  xor    %eax,%eax
  test   $0x1,%bl
  jne    L9
  mov    $0x1,%eax
  test   $0x2,%bl
  jne    L9
  mov    $0x2,%eax
  test   $0x4,%bl
  jne    L9
  and    $0x8,%ebx
  cmp    $0x1,%rbx
  sbb    %eax,%eax
  or     $0x3,%eax
L9:
  pop    %rbx
  ret
```

assistant: ```c
int drp_explain() {
  unsigned long val = drp_value(6);
  drp_set(0x0, 6);
  if (val & 0x01) {
    return 0;
  } else if (val & 0x02) {
    return 1;
  } else if (val & 0x04) {
    return 2;
  } else if (val & 0x08) {
    return 3;
  } else {
    return -1;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<drp_explain>:
  endbr64
  push   %rbx
  mov    $0x6,%edi
  call   <drp_value@plt>
  mov    $0x6,%esi
  xor    %edi,%edi
  mov    %rax,%rbx
  call   <drp_set@plt>
  xor    %eax,%eax
  test   $0x1,%bl
  jne    L18
  mov    $0x1,%eax
  test   $0x2,%bl
  jne    L18
  mov    $0x2,%eax
  test   $0x4,%bl
  jne    L18
  and    $0x8,%ebx
  cmp    $0x1,%rbx
  sbb    %eax,%eax
  or     $0x3,%eax
L18:
  pop    %rbx
  ret
```

assistant: ```c
int drp_explain() {
  unsigned long val = drp_value(6);
  drp_set(0x0, 6);
  if (val & 0x01) {
    return 0;
  } else if (val & 0x02) {
    return 1;
  } else if (val & 0x04) {
    return 2;
  } else if (val & 0x08) {
    return 3;
  } else {
    return -1;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<uint32_to_bytes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L10
L0:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  shr    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ecx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %ecx,%edx
  mov    %dl,(%rax)
  addl   $0x1,-0x4(%rbp)
L10:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jb     L0
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void uint32_to_bytes(unsigned char *out, const u_int32_t *in, unsigned int n) {
  unsigned int x, y;
  for (x = y = 0; y < n; y++) {
    out[x++] = (in[y] >> 24) & 0xff;
    out[x++] = (in[y] >> 16) & 0xff;
    out[x++] = (in[y] >> 8) & 0xff;
    out[x++] = in[y] & 0xff;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<uint32_to_bytes>:
  endbr64
  test   %edx,%edx
  je     L9
  push   %rbx
  mov    %rdi,%rcx
  mov    %rsi,%rax
  lea    -0x1(%rdx),%edx
  lea    0x4(%rsi,%rdx,4),%r8
  mov    $0x0,%edx
L0:
  mov    %edx,%edi
  mov    (%rax),%esi
  shr    $0x18,%esi
  mov    %sil,(%rcx,%rdi,1)
  lea    0x1(%rdx),%edi
  mov    (%rax),%esi
  sar    $0x10,%esi
  mov    %sil,(%rcx,%rdi,1)
  lea    0x3(%rdx),%esi
  lea    0x2(%rdx),%edi
  mov    (%rax),%ebx
  movzbl %bh,%ebx
  mov    %bl,(%rcx,%rdi,1)
  add    $0x4,%edx
  mov    %esi,%esi
  mov    (%rax),%edi
  mov    %dil,(%rcx,%rsi,1)
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L0
  pop    %rbx
  ret
L9:
  ret
```

assistant: ```c
void uint32_to_bytes(unsigned char *out, const u_int32_t *in, unsigned int n) {
  unsigned int x, y;
  for (x = y = 0; y < n; y++) {
    out[x++] = (in[y] >> 24) & 0xff;
    out[x++] = (in[y] >> 16) & 0xff;
    out[x++] = (in[y] >> 8) & 0xff;
    out[x++] = in[y] & 0xff;
  }
}
```