ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<cmd_check>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <check_limits@plt>
  mov    %rbp,%rdi
  sar    $0x3f,%rax
  mov    %rax,%r12
  call   <check_draw@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovs  %eax,%r12d
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int cmd_check(struct command_opts *opts) {
  int ret = 0;
  if (check_limits(opts) < 0)
    ret = -1;
  if (check_draw(opts) < 0)
    ret = -1;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<cmd_check>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <check_limits@plt>
  mov    %rbp,%rdi
  sar    $0x3f,%rax
  mov    %rax,%r12
  call   <check_draw@plt>
  test   %rax,%rax
  mov    $0xffffffff,%eax
  cmovs  %eax,%r12d
  add    $0x8,%rsp
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  ret
```

assistant: ```c
int cmd_check(struct command_opts *opts) {
  int ret = 0;
  if (check_limits(opts) < 0)
    ret = -1;
  if (check_draw(opts) < 0)
    ret = -1;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L12
L8:
  mov    -0x8(%rbp),%edx
  mov    -0x1c(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <circle_rotate@plt>
  addl   $0x1,-0x8(%rbp)
L12:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L8
  nop
  nop
  leave
  ret
```

assistant: ```c
void rotate(int **array, int dimension) {
  int half = dimension / 2;
  for (int round = 0; round < half; round++) {
    circle_rotate(array, dimension, round);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rotate>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r12d
  shr    $0x1f,%r12d
  add    %esi,%r12d
  sar    %r12d
  cmp    $0x1,%esi
  jle    L2
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    $0x0,%ebx
L5:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <circle_rotate@plt>
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jg     L5
L2:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rotate(int **array, int dimension) {
  int half = dimension / 2;
  for (int round = 0; round < half; round++) {
    circle_rotate(array, dimension, round);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<rotate>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  push   %rbx
  add    %esi,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L10
  mov    %rdi,%r13
  mov    %esi,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <circle_rotate@plt>
  cmp    %ebx,%r12d
  jg     L13
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rotate(int **array, int dimension) {
  int half = dimension / 2;
  for (int round = 0; round < half; round++) {
    circle_rotate(array, dimension, round);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotate>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  shr    $0x1f,%r12d
  push   %rbx
  add    %esi,%r12d
  sar    %r12d
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L14
  mov    %rdi,%r13
  mov    %esi,%ebp
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  add    $0x1,%ebx
  call   <circle_rotate@plt>
  cmp    %ebx,%r12d
  jg     L0
L14:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void rotate(int **array, int dimension) {
  int half = dimension / 2;
  for (int round = 0; round < half; round++) {
    circle_rotate(array, dimension, round);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<make_cyclic>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L47
L23:
  movl   $0x0,-0x10(%rbp)
  jmp    L48
L2:
  mov    -0xc(%rbp),%eax
  imul   -0x24(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x24(%rbp),%eax
  add    $0x1,%eax
  imul   -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x10(%rbp)
L48:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L2
  addl   $0x1,-0xc(%rbp)
L47:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L23
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L12:
  mov    -0x24(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0xc(%rbp),%eax
  imul   %edx,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%ecx
  mov    -0x24(%rbp),%eax
  add    %ecx,%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movsd  (%rdx),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jl     L12
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void make_cyclic(double *array1, double *array2, int nlon, int nlat) {
  int i, j;
  int ij1, ij2;
  for (j = 0; j < nlat; ++j) {
    for (i = 0; i < nlon; ++i) {
      ij1 = j * nlon + i;
      ij2 = j * (nlon + 1) + i;
      array2[ij2] = array1[ij1];
    }
  }
  for (j = 0; j < nlat; ++j) {
    ij2 = j * (nlon + 1);
    array2[ij2 + nlon] = array2[ij2];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_cyclic>:
  endbr64
  test   %ecx,%ecx
  jle    L66
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%r8
  mov    %edx,%r9d
  mov    %ecx,%ebp
  lea    0x1(%rdx),%r12d
  mov    $0x0,%ecx
  mov    $0x0,%r11d
  mov    $0x0,%r10d
  mov    %edx,%edi
  jmp    L9
L61:
  movslq %r11d,%rax
  lea    (%rbx,%rax,8),%rsi
  movslq %ecx,%rax
  lea    (%r8,%rax,8),%rdx
  mov    $0x0,%eax
L36:
  movsd  (%rsi,%rax,8),%xmm0
  movsd  %xmm0,(%rdx,%rax,8)
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L36
L62:
  lea    0x1(%r10),%eax
  add    %r9d,%r11d
  add    %r12d,%ecx
  cmp    %eax,%ebp
  je     L15
  mov    %eax,%r10d
L9:
  test   %r9d,%r9d
  jg     L61
  jmp    L62
L15:
  movslq %r9d,%r9
  lea    0x8(,%r9,8),%rsi
  mov    %r8,%rax
  mov    $0x0,%edx
L11:
  movsd  (%rax),%xmm0
  movsd  %xmm0,(%rax,%r9,8)
  mov    %edx,%ecx
  add    $0x1,%edx
  add    %rsi,%rax
  cmp    %ecx,%r10d
  jne    L11
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L66:
  ret
```

assistant: ```c
void make_cyclic(double *array1, double *array2, int nlon, int nlat) {
  int i, j;
  int ij1, ij2;
  for (j = 0; j < nlat; ++j) {
    for (i = 0; i < nlon; ++i) {
      ij1 = j * nlon + i;
      ij2 = j * (nlon + 1) + i;
      array2[ij2] = array1[ij1];
    }
  }
  for (j = 0; j < nlat; ++j) {
    ij2 = j * (nlon + 1);
    array2[ij2 + nlon] = array2[ij2];
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<make_cyclic>:
  endbr64
  test   %ecx,%ecx
  jle    L50
  movslq %edx,%r9
  push   %r13
  mov    %rsi,%r8
  mov    %ecx,%r13d
  push   %r12
  xor    %r11d,%r11d
  lea    0x1(%r9),%r12d
  xor    %r10d,%r10d
  push   %rbp
  mov    %rdi,%rbp
  lea    -0x1(%r9),%edi
  push   %rbx
  xor    %ebx,%ebx
  xchg   %ax,%ax
L47:
  test   %r9d,%r9d
  jle    L24
  movslq %r11d,%rax
  lea    0x0(%rbp,%rax,8),%rsi
  movslq %ebx,%rax
  lea    (%r8,%rax,8),%rcx
  xor    %eax,%eax
  cs nopw 0x0(%rax,%rax,1)
L9:
  movsd  (%rsi,%rax,8),%xmm0
  mov    %rax,%rdx
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %rdx,%rdi
  jne    L9
L24:
  lea    0x1(%r10),%eax
  add    %r9d,%r11d
  add    %r12d,%ebx
  cmp    %eax,%r13d
  je     L15
  mov    %eax,%r10d
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L15:
  movslq %r12d,%rcx
  mov    %r8,%rax
  xor    %edx,%edx
  shl    $0x3,%rcx
  nopl   0x0(%rax)
L43:
  movsd  (%rax),%xmm0
  mov    %edx,%esi
  add    $0x1,%edx
  movsd  %xmm0,(%rax,%r9,8)
  add    %rcx,%rax
  cmp    %esi,%r10d
  jne    L43
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L50:
  ret
```

assistant: ```c
void make_cyclic(double *array1, double *array2, int nlon, int nlat) {
  int i, j;
  int ij1, ij2;
  for (j = 0; j < nlat; ++j) {
    for (i = 0; i < nlon; ++i) {
      ij1 = j * nlon + i;
      ij2 = j * (nlon + 1) + i;
      array2[ij2] = array1[ij1];
    }
  }
  for (j = 0; j < nlat; ++j) {
    ij2 = j * (nlon + 1);
    array2[ij2 + nlon] = array2[ij2];
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<make_cyclic>:
  endbr64
  test   %ecx,%ecx
  jle    L56
  push   %r15
  movslq %edx,%r15
  push   %r14
  push   %r13
  mov    %ecx,%r13d
  push   %r12
  lea    0x1(%rdx),%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  test   %edx,%edx
  jle    L91
  movslq %edx,%r15
  lea    -0x1(%rbp),%r14d
  mov    %rdi,%r10
  mov    %rsi,%rcx
  lea    0x0(,%r15,8),%rax
  xor    %r9d,%r9d
  xor    %r8d,%r8d
  xor    %ebx,%ebx
  mov    %rax,-0x28(%rsp)
  add    $0x8,%rax
  mov    %rax,-0x18(%rsp)
  mov    %edx,%eax
  and    $0xfffffffe,%edx
  shr    %eax
  mov    %r15,-0x10(%rsp)
  mov    -0x18(%rsp),%r15
  lea    -0x1(%rax),%r11d
  mov    %r14d,-0x1c(%rsp)
  mov    %ebp,%r14d
  add    $0x1,%r11
  shl    $0x4,%r11
  nopw   0x0(%rax,%rax,1)
L35:
  lea    0x8(%rdi),%rax
  cmp    %rax,%rcx
  je     L67
  xor    %eax,%eax
  cmpl   $0x2,-0x1c(%rsp)
  jbe    L67
  nopw   0x0(%rax,%rax,1)
L90:
  movupd (%rdi,%rax,1),%xmm1
  movups %xmm1,(%rcx,%rax,1)
  add    $0x10,%rax
  cmp    %r11,%rax
  jne    L90
  cmp    %ebp,%edx
  je     L92
  lea    (%r8,%rdx,1),%eax
  cltq
  movsd  (%r10,%rax,8),%xmm0
  lea    (%r9,%rdx,1),%eax
  cltq
  movsd  %xmm0,(%rsi,%rax,8)
L92:
  add    $0x1,%ebx
  add    -0x28(%rsp),%rdi
  add    %r15,%rcx
  add    %ebp,%r8d
  add    %r12d,%r9d
  cmp    %ebx,%r13d
  jne    L35
  mov    -0x10(%rsp),%r15
L91:
  movslq %r12d,%rdx
  xor    %eax,%eax
  shl    $0x3,%rdx
  nopl   0x0(%rax)
L27:
  movsd  (%rsi),%xmm0
  add    $0x1,%eax
  movsd  %xmm0,(%rsi,%r15,8)
  add    %rdx,%rsi
  cmp    %eax,%r13d
  jne    L27
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L67:
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L9:
  movsd  (%rdi,%rax,8),%xmm0
  movsd  %xmm0,(%rcx,%rax,8)
  add    $0x1,%rax
  cmp    %r14,%rax
  jne    L9
  jmp    L92
L56:
  ret
```

assistant: ```c
void make_cyclic(double *array1, double *array2, int nlon, int nlat) {
  int i, j;
  int ij1, ij2;
  for (j = 0; j < nlat; ++j) {
    for (i = 0; i < nlon; ++i) {
      ij1 = j * nlon + i;
      ij2 = j * (nlon + 1) + i;
      array2[ij2] = array1[ij1];
    }
  }
  for (j = 0; j < nlat; ++j) {
    ij2 = j * (nlon + 1);
    array2[ij2 + nlon] = array2[ij2];
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movq   $0x2a,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L17
L9:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  imul   -0x1c(%rbp),%eax
  cltq
  add    %rax,-0x18(%rbp)
L17:
  mov    -0x1c(%rbp),%ebx
  lea    0x1(%rbx),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,%ebx
  jl     L9
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
long hash(char *word) {
  long result = 42;
  int counter = 0;
  while (counter++ < strlen(word)) {
    result += word[counter - 1] * (counter);
  }
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<hash>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    $0x0,%ebx
  mov    $0x2a,%r12d
  jmp    L15
L0:
  movsbl 0x0(%rbp,%rbx,1),%eax
  imul   %r13d,%eax
  cltq
  add    %rax,%r12
  add    $0x1,%rbx
L15:
  lea    0x1(%rbx),%r13d
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L0
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long hash(char *word) {
  long result = 42;
  int counter = 0;
  while (counter++ < strlen(word)) {
    result += word[counter - 1] * (counter);
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hash>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L16:
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  imul   %r13d,%eax
  cltq
  add    %rax,%r12
L8:
  mov    %rbp,%rdi
  lea    0x1(%rbx),%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L16
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long hash(char *word) {
  long result = 42;
  int counter = 0;
  while (counter++ < strlen(word)) {
    result += word[counter - 1] * (counter);
  }
  return result;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<hash>:
  endbr64
  push   %r13
  push   %r12
  mov    $0x2a,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L4
  nopl   0x0(%rax,%rax,1)
L19:
  movsbl 0x0(%rbp,%rbx,1),%eax
  add    $0x1,%rbx
  imul   %r13d,%eax
  cltq
  add    %rax,%r12
L4:
  mov    %rbp,%rdi
  lea    0x1(%rbx),%r13d
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L19
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
long hash(char *word) {
  long result = 42;
  int counter = 0;
  while (counter++ < strlen(word)) {
    result += word[counter - 1] * (counter);
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L4
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pick_next_task_rt>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <_pick_next_task_rt@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <dequeue_pushable_task@plt>
L1:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
struct task_struct *pick_next_task_rt(struct rq *rq) {
  struct task_struct *p = _pick_next_task_rt(rq);
  if (p)
    dequeue_pushable_task(rq, p);
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fibo3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x54(%rbp)
  mov    -0x64(%rbp),%eax
  cmp    -0x54(%rbp),%eax
  jle    L79
  mov    $0xffffffff,%eax
  jmp    L13
L79:
  movl   $0x1,-0x58(%rbp)
  jmp    L22
L73:
  cmpl   $0x1,-0x58(%rbp)
  jne    L83
  mov    -0x58(%rbp),%eax
  cltq
  movl   $0x1,-0x50(%rbp,%rax,4)
  jmp    L55
L83:
  cmpl   $0x2,-0x58(%rbp)
  jne    L64
  mov    -0x58(%rbp),%eax
  cltq
  movl   $0x1,-0x50(%rbp,%rax,4)
  jmp    L55
L64:
  mov    -0x58(%rbp),%eax
  sub    $0x1,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%edx
  mov    -0x58(%rbp),%eax
  sub    $0x2,%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
  add    %eax,%edx
  mov    -0x58(%rbp),%eax
  cltq
  mov    %edx,-0x50(%rbp,%rax,4)
L55:
  addl   $0x1,-0x58(%rbp)
L22:
  mov    -0x58(%rbp),%eax
  cmp    -0x64(%rbp),%eax
  jle    L73
  mov    -0x64(%rbp),%eax
  cltq
  mov    -0x50(%rbp,%rax,4),%eax
L13:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
int fibo3(int n) {
  const int MAX = 10;
  int ary[15];
  int i;
  if (n > MAX)
    return (-1);
  i = 1;
  while (i <= n) {
    if (i == 1)
      ary[i] = 1;
    else if (i == 2)
      ary[i] = 1;
    else
      ary[i] = ary[i - 1] + ary[i - 2];
    i = i + 1;
  }
  return (ary[n]);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fibo3>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0xa,%edi
  jg     L34
  test   %edi,%edi
  jle    L96
  mov    %rsp,%rdx
  lea    0x1(%rdi),%esi
  mov    $0x1,%eax
  jmp    L40
L8:
  movl   $0x1,0x4(%rsp)
  jmp    L94
L54:
  mov    -0x4(%rdx),%ecx
  add    (%rdx),%ecx
  mov    %ecx,0x4(%rdx)
L94:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %esi,%eax
  je     L96
L40:
  cmp    $0x1,%eax
  je     L8
  cmp    $0x2,%eax
  jne    L54
  movl   $0x1,0x8(%rsp)
  jmp    L94
L96:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
L73:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L99
  add    $0x58,%rsp
  ret
L34:
  mov    $0xffffffff,%eax
  jmp    L73
L99:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fibo3(int n) {
  const int MAX = 10;
  int ary[15];
  int i;
  if (n > MAX)
    return (-1);
  i = 1;
  while (i <= n) {
    if (i == 1)
      ary[i] = 1;
    else if (i == 2)
      ary[i] = 1;
    else
      ary[i] = ary[i - 1] + ary[i - 2];
    i = i + 1;
  }
  return (ary[n]);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fibo3>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0xa,%edi
  jg     L91
  test   %edi,%edi
  jle    L48
  mov    %rsp,%rdx
  lea    0x1(%rdi),%esi
  mov    $0x1,%eax
  jmp    L26
  xchg   %ax,%ax
L55:
  cmp    $0x2,%eax
  je     L14
  mov    -0x4(%rdx),%ecx
  add    (%rdx),%ecx
  mov    %ecx,0x4(%rdx)
L39:
  add    $0x1,%eax
  add    $0x4,%rdx
  cmp    %esi,%eax
  je     L48
L26:
  cmp    $0x1,%eax
  jne    L55
  add    $0x1,%eax
  movl   $0x1,0x4(%rsp)
  add    $0x4,%rdx
  cmp    %esi,%eax
  jne    L26
L48:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
L71:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x58,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movl   $0x1,0x8(%rsp)
  jmp    L39
L91:
  mov    $0xffffffff,%eax
  jmp    L71
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fibo3(int n) {
  const int MAX = 10;
  int ary[15];
  int i;
  if (n > MAX)
    return (-1);
  i = 1;
  while (i <= n) {
    if (i == 1)
      ary[i] = 1;
    else if (i == 2)
      ary[i] = 1;
    else
      ary[i] = ary[i - 1] + ary[i - 2];
    i = i + 1;
  }
  return (ary[n]);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<fibo3>:
  endbr64
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  cmp    $0xa,%edi
  jg     L10
  test   %edi,%edi
  jle    L108
  movl   $0x1,0x4(%rsp)
  cmp    $0x1,%edi
  je     L108
  movl   $0x1,0x8(%rsp)
  cmp    $0x2,%edi
  je     L108
  movl   $0x2,0xc(%rsp)
  cmp    $0x3,%edi
  je     L108
  movl   $0x3,0x10(%rsp)
  cmp    $0x4,%edi
  je     L108
  movl   $0x5,0x14(%rsp)
  cmp    $0x5,%edi
  je     L108
  movl   $0x8,0x18(%rsp)
  cmp    $0x6,%edi
  je     L108
  movl   $0xd,0x1c(%rsp)
  cmp    $0x7,%edi
  je     L108
  movl   $0x15,0x20(%rsp)
  cmp    $0x8,%edi
  je     L108
  movl   $0x22,0x24(%rsp)
  cmp    $0xa,%edi
  jne    L108
  movl   $0x37,0x28(%rsp)
L108:
  movslq %edi,%rdi
  mov    (%rsp,%rdi,4),%eax
L122:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L26
  add    $0x58,%rsp
  ret
L10:
  mov    $0xffffffff,%eax
  jmp    L122
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int fibo3(int n) {
  const int MAX = 10;
  int ary[15];
  int i;
  if (n > MAX)
    return (-1);
  i = 1;
  while (i <= n) {
    if (i == 1)
      ary[i] = 1;
    else if (i == 2)
      ary[i] = 1;
    else
      ary[i] = ary[i - 1] + ary[i - 2];
    i = i + 1;
  }
  return (ary[n]);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<json_isspace>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    $0x20,%eax
  seta   %dl
  test   %dl,%dl
  jne    L1
  movabs $0x100002600,%rdx
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  setne  %al
  test   %al,%al
  je     L1
  mov    $0x1,%eax
  jmp    L0
L1:
  mov    $0x0,%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int json_isspace(int c) {
  switch (c) {
  case 0x09:
  case 0x0a:
  case 0x0d:
  case 0x20:
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<json_isspace>:
  endbr64
  cmp    $0x20,%edi
  ja     L2
  movabs $0x100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L2:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int json_isspace(int c) {
  switch (c) {
  case 0x09:
  case 0x0a:
  case 0x0d:
  case 0x20:
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<json_isspace>:
  endbr64
  cmp    $0x20,%edi
  ja     L4
  movabs $0x100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int json_isspace(int c) {
  switch (c) {
  case 0x09:
  case 0x0a:
  case 0x0d:
  case 0x20:
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<json_isspace>:
  endbr64
  cmp    $0x20,%edi
  ja     L6
  movabs $0x100002600,%rax
  mov    %edi,%ecx
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax)
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int json_isspace(int c) {
  switch (c) {
  case 0x09:
  case 0x0a:
  case 0x0d:
  case 0x20:
    return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <setbuf@plt>
L6:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L24
  mov    $0x0,%eax
  jmp    L23
L24:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <serial_interrupt@plt>
  jmp    L6
L23:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  setbuf(stdin, NULL);
  while (true) {
    int in = getchar();
    if (in == EOF)
      return 0;
    serial_interrupt(in);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    D6(%rip),%rax
  mov    (%rax),%edi
  call   <setbuf@plt>
  jmp    L9
L8:
  call   <serial_interrupt@plt>
L9:
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%edi
  mov    D5(%rip),%rax
  cmp    %edi,(%rax)
  jne    L8
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  setbuf(stdin, NULL);
  while (true) {
    int in = getchar();
    if (in == EOF)
      return 0;
    serial_interrupt(in);
  }
}
```