ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<heap_delete>:
  endbr64
  push   %r15
  movslq %esi,%rax
  movslq %edx,%r15
  push   %r14
  mov    %rax,%r14
  push   %r13
  lea    (%rdi,%rax,4),%r13
  push   %r12
  mov    %r13,%rsi
  push   %rbp
  mov    %rdi,%rbp
  lea    (%rdi,%r15,4),%rdi
  push   %rbx
  sub    $0x18,%rsp
  mov    %edx,0xc(%rsp)
  call   <swap@plt>
  mov    0xc(%rsp),%edx
  lea    (%rdx,%rdx,1),%r12d
  lea    0x1(%r12),%ebx
  movslq %r12d,%rcx
  nopw   0x0(%rax,%rax,1)
L76:
  lea    0x0(%rbp,%r15,4),%rdi
  lea    0x0(%rbp,%rcx,4),%rsi
  mov    (%rdi),%edx
  mov    (%rsi),%eax
  cmp    %eax,%edx
  jl     L52
  movslq %ebx,%r8
  cmp    0x0(%rbp,%r8,4),%edx
  jge    L64
L52:
  cmp    %ebx,%r12d
  mov    %ebx,%edx
  cmovge %r12d,%edx
  cmp    %edx,%r14d
  jle    L64
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%r8
  cmp    %eax,(%r8)
  jge    L27
  cmp    %r14d,%r12d
  jge    L76
  call   <swap@plt>
  lea    (%r12,%r12,1),%eax
  movslq %r12d,%r15
  movslq %eax,%rcx
  lea    0x1(%rax),%ebx
  mov    %rcx,%r12
  jmp    L76
  nopl   0x0(%rax,%rax,1)
L27:
  jle    L76
  cmp    %r14d,%ebx
  jge    L76
  lea    (%rbx,%rbx,1),%r12d
  mov    %r8,%rsi
  movslq %ebx,%r15
  call   <swap@plt>
  lea    0x1(%r12),%ebx
  movslq %r12d,%rcx
  jmp    L76
L64:
  mov    0x0(%r13),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int heap_delete(int *heap, int max_index, int start_index) {
  swap(&heap[start_index], &heap[max_index]);
  int child1 = 2 * start_index, child2 = child1 + 1;
  while (((heap[start_index] < heap[child1]) || (heap[start_index] < heap[child2])) && (child1 < max_index) && (child2 < max_index)) {
    if ((heap[child2] < heap[child1]) && (child1 < max_index)) {
      swap(&heap[start_index], &heap[child1]);
      start_index = child1;
      child1 = 2 * start_index;
      child2 = child1 + 1;
    } else if ((heap[child1] < heap[child2]) && (child2 < max_index)) {
      swap(&heap[start_index], &heap[child2]);
      start_index = child2;
      child2 = 2 * start_index + 1;
      child1 = child2 - 1;
    }
  }
  return heap[max_index];
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %rsi,-0x70(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x5554535251504f4e,%rax
  movabs $0x4342415a59585756,%rdx
  mov    %rax,-0x50(%rbp)
  mov    %rdx,-0x48(%rbp)
  movabs $0x4b4a494847464544,%rax
  mov    %rax,-0x40(%rbp)
  movw   $0x4d4c,-0x38(%rbp)
  movb   $0x0,-0x36(%rbp)
  movabs $0x7574737271706f6e,%rax
  movabs $0x6362617a79787776,%rdx
  mov    %rax,-0x30(%rbp)
  mov    %rdx,-0x28(%rbp)
  movabs $0x6b6a696867666564,%rax
  mov    %rax,-0x20(%rbp)
  movw   $0x6d6c,-0x18(%rbp)
  movb   $0x0,-0x16(%rbp)
  movb   $0x3f,-0x55(%rbp)
  movw   $0xa78,-0x53(%rbp)
  movb   $0x0,-0x51(%rbp)
  movb   $0x21,-0x54(%rbp)
  cmpl   $0x1,-0x64(%rbp)
  jle    L34
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L34
  mov    -0x70(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  movzbl (%rax),%eax
  mov    %al,-0x54(%rbp)
L34:
  cmpb   $0x1f,-0x54(%rbp)
  jbe    L48
  cmpb   $0x40,-0x54(%rbp)
  ja     L48
  movzbl -0x54(%rbp),%eax
  mov    %al,-0x55(%rbp)
  jmp    L82
L48:
  cmpb   $0x40,-0x54(%rbp)
  jbe    L19
  cmpb   $0x60,-0x54(%rbp)
  ja     L19
  movzbl -0x54(%rbp),%eax
  sub    $0x41,%eax
  cltq
  movzbl -0x50(%rbp,%rax,1),%eax
  mov    %al,-0x55(%rbp)
  jmp    L82
L19:
  movzbl -0x54(%rbp),%eax
  sub    $0x61,%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  mov    %al,-0x55(%rbp)
L82:
  movzbl -0x55(%rbp),%eax
  mov    %al,-0x53(%rbp)
  lea    -0x53(%rbp),%rax
  mov    $0x2,%edx
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <write@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L37
  call   <__stack_chk_fail@plt>
L37:
  leave
  ret
```

assistant: ```c
int main(int argc, char **argv) {
  char rot_table_ucase[] = "NOPQRSTUVWXYZABCDEFGHIJKLM";
  char rot_table_lcase[] = "nopqrstuvwxyzabcdefghijklm";
  char out_char = '?';
  char out_msg[] = "x\n";
  unsigned char in_char = '!';
  if (argc > 1 && argv[1][0])
    in_char = argv[1][0];
  if (in_char >= ' ' && in_char < 'A') {
    out_char = in_char;
  } else if (in_char >= 'A' && in_char < 'a') {
    out_char = rot_table_ucase[in_char - 'A'];
  } else {
    out_char = rot_table_lcase[in_char - 'a'];
  }
  out_msg[0] = out_char;
  write(1, out_msg, sizeof(out_msg) - 1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x5554535251504f4e,%rax
  movabs $0x4342415a59585756,%rdx
  mov    %rax,0x10(%rsp)
  mov    %rdx,0x18(%rsp)
  movabs $0x4b4a494847464544,%rax
  mov    %rax,0x20(%rsp)
  movw   $0x4d4c,0x28(%rsp)
  movb   $0x0,0x2a(%rsp)
  movabs $0x7574737271706f6e,%rax
  movabs $0x6362617a79787776,%rdx
  mov    %rax,0x30(%rsp)
  mov    %rdx,0x38(%rsp)
  movabs $0x6b6a696867666564,%rax
  mov    %rax,0x40(%rsp)
  movw   $0x6d6c,0x48(%rsp)
  movb   $0x0,0x4a(%rsp)
  movw   $0xa78,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  cmp    $0x1,%edi
  jle    L45
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L60
  mov    %eax,%edx
  lea    -0x20(%rax),%ecx
  cmp    $0x20,%cl
  jbe    L71
  lea    -0x41(%rax),%edx
  cmp    $0x1f,%dl
  ja     L9
  movzbl %al,%eax
  sub    $0x41,%eax
  cltq
  movzbl 0x10(%rsp,%rax,1),%eax
  jmp    L69
L45:
  mov    $0x21,%edx
L71:
  mov    %edx,%eax
L69:
  mov    %al,0xd(%rsp)
  lea    0xd(%rsp),%rsi
  mov    $0x2,%edx
  mov    $0x1,%edi
  call   <write@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L60:
  mov    $0x21,%edx
  jmp    L71
L9:
  movzbl %al,%eax
  sub    $0x61,%eax
  cltq
  movzbl 0x30(%rsp,%rax,1),%eax
  jmp    L69
L63:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(int argc, char **argv) {
  char rot_table_ucase[] = "NOPQRSTUVWXYZABCDEFGHIJKLM";
  char rot_table_lcase[] = "nopqrstuvwxyzabcdefghijklm";
  char out_char = '?';
  char out_msg[] = "x\n";
  unsigned char in_char = '!';
  if (argc > 1 && argv[1][0])
    in_char = argv[1][0];
  if (in_char >= ' ' && in_char < 'A') {
    out_char = in_char;
  } else if (in_char >= 'A' && in_char < 'a') {
    out_char = rot_table_ucase[in_char - 'A'];
  } else {
    out_char = rot_table_lcase[in_char - 'a'];
  }
  out_msg[0] = out_char;
  write(1, out_msg, sizeof(out_msg) - 1);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0x6d6c,%edx
  mov    $0xa78,%ecx
  movdqa D10(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x2a(%rsp)
  movabs $0x4b4a494847464544,%rax
  mov    %rax,0x20(%rsp)
  mov    $0x4d4c,%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D11(%rip),%xmm0
  mov    %ax,0x28(%rsp)
  movabs $0x6b6a696867666564,%rax
  mov    %rax,0x40(%rsp)
  mov    %dx,0x48(%rsp)
  movb   $0x0,0x4a(%rsp)
  mov    %cx,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  movaps %xmm0,0x30(%rsp)
  cmp    $0x1,%edi
  jle    L65
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L65
  lea    -0x20(%rax),%ecx
  mov    %eax,%edx
  cmp    $0x20,%cl
  jbe    L20
  movzbl %al,%edx
  sub    $0x41,%eax
  cmp    $0x1f,%al
  ja     L50
  sub    $0x41,%edx
  movslq %edx,%rdx
  movzbl 0x10(%rsp,%rdx,1),%eax
  jmp    L62
  xchg   %ax,%ax
L65:
  mov    $0x21,%edx
L20:
  mov    %edx,%eax
L62:
  lea    0xd(%rsp),%rsi
  mov    $0x2,%edx
  mov    $0x1,%edi
  mov    %al,0xd(%rsp)
  call   <write@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L50:
  sub    $0x61,%edx
  movslq %edx,%rdx
  movzbl 0x30(%rsp,%rdx,1),%eax
  jmp    L62
L35:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
type_infered: byte[16]
name: read_data
arguments: label: D11
type_infered: byte[16]

tool: {"D10": [0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x41,0x42,0x43]}

tool: {"D11": [0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x61,0x62,0x63]}

assistant: ```c
int main(int argc, char **argv) {
  char rot_table_ucase[] = "NOPQRSTUVWXYZABCDEFGHIJKLM";
  char rot_table_lcase[] = "nopqrstuvwxyzabcdefghijklm";
  char out_char = '?';
  char out_msg[] = "x\n";
  unsigned char in_char = '!';
  if (argc > 1 && argv[1][0])
    in_char = argv[1][0];
  if (in_char >= ' ' && in_char < 'A') {
    out_char = in_char;
  } else if (in_char >= 'A' && in_char < 'a') {
    out_char = rot_table_ucase[in_char - 'A'];
  } else {
    out_char = rot_table_lcase[in_char - 'a'];
  }
  out_msg[0] = out_char;
  write(1, out_msg, sizeof(out_msg) - 1);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0x6d6c,%edx
  mov    $0xa78,%ecx
  movdqa D17(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movb   $0x0,0x2a(%rsp)
  movabs $0x4b4a494847464544,%rax
  mov    %rax,0x20(%rsp)
  mov    $0x4d4c,%eax
  movaps %xmm0,0x10(%rsp)
  movdqa D12(%rip),%xmm0
  mov    %ax,0x28(%rsp)
  movabs $0x6b6a696867666564,%rax
  mov    %rax,0x40(%rsp)
  mov    %dx,0x48(%rsp)
  movb   $0x0,0x4a(%rsp)
  mov    %cx,0xd(%rsp)
  movb   $0x0,0xf(%rsp)
  movaps %xmm0,0x30(%rsp)
  cmp    $0x1,%edi
  jle    L50
  mov    0x8(%rsi),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L50
  lea    -0x20(%rax),%ecx
  mov    %eax,%edx
  cmp    $0x20,%cl
  jbe    L6
  movzbl %al,%edx
  sub    $0x41,%eax
  cmp    $0x1f,%al
  ja     L44
  sub    $0x41,%edx
  movslq %edx,%rdx
  movzbl 0x10(%rsp,%rdx,1),%eax
  jmp    L45
  xchg   %ax,%ax
L50:
  mov    $0x21,%edx
L6:
  mov    %edx,%eax
L45:
  lea    0xd(%rsp),%rsi
  mov    $0x2,%edx
  mov    $0x1,%edi
  mov    %al,0xd(%rsp)
  call   <write@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L44:
  sub    $0x61,%edx
  movslq %edx,%rdx
  movzbl 0x30(%rsp,%rdx,1),%eax
  jmp    L45
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D17
type: byte[16]
name: extract_symbolic_data
arguments: data_tag: D12
type: byte[16]

tool: {"D17": [0x4e,0x4f,0x50,0x51,0x52,0x53,0x54,0x55,0x56,0x57,0x58,0x59,0x5a,0x41,0x42,0x43]}

tool: {"D12": [0x6e,0x6f,0x70,0x71,0x72,0x73,0x74,0x75,0x76,0x77,0x78,0x79,0x7a,0x61,0x62,0x63]}

assistant: ```c
int main(int argc, char **argv) {
  char rot_table_ucase[] = "NOPQRSTUVWXYZABCDEFGHIJKLM";
  char rot_table_lcase[] = "nopqrstuvwxyzabcdefghijklm";
  char out_char = '?';
  char out_msg[] = "x\n";
  unsigned char in_char = '!';
  if (argc > 1 && argv[1][0])
    in_char = argv[1][0];
  if (in_char >= ' ' && in_char < 'A') {
    out_char = in_char;
  } else if (in_char >= 'A' && in_char < 'a') {
    out_char = rot_table_ucase[in_char - 'A'];
  } else {
    out_char = rot_table_lcase[in_char - 'a'];
  }
  out_msg[0] = out_char;
  write(1, out_msg, sizeof(out_msg) - 1);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<pwd_gene>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %rdi,-0x48(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %rdx,-0x58(%rbp)
  mov    %ecx,-0x5c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    %ebx,%eax
  lea    0x1(%rax),%edx
  mov    -0x38(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,-0x30(%rbp)
  mov    -0x38(%rbp),%rdx
  mov    -0x50(%rbp),%rcx
  mov    -0x48(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <seed_gene@plt>
  mov    -0x30(%rbp),%rcx
  mov    -0x38(%rbp),%rax
  mov    $0x3,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <random_num_gene@plt>
  mov    -0x5c(%rbp),%edx
  mov    -0x30(%rbp),%rcx
  lea    -0x24(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <box_num_gene@plt>
  mov    -0x5c(%rbp),%ecx
  lea    -0x24(%rbp),%rdx
  mov    -0x58(%rbp),%rsi
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <pword_gene@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <adj_order@plt>
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int pwd_gene(unsigned char *app, unsigned char *username, unsigned char *password, int pwd_len) {
  do {
  } while (0);
  int box_num[3];
  unsigned char *seed = (unsigned char *)malloc((strlen(app) + strlen(username) + 1) * sizeof(unsigned char));
  memset(seed, '\0', strlen(app) + strlen(username) + 1);
  unsigned char *random_num = (unsigned char *)malloc(3 * sizeof(unsigned char));
  seed_gene(app, username, seed);
  random_num_gene(seed, random_num, 3);
  box_num_gene(box_num, random_num, pwd_len);
  pword_gene(seed, password, box_num, pwd_len);
  adj_order(password);
  free(seed);
  free(random_num);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<pwd_gene>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rdx,%r14
  mov    %ecx,%r15d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbx,%rax,1),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  mov    %r13,%rdi
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <seed_gene@plt>
  mov    $0x3,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <random_num_gene@plt>
  lea    0xc(%rsp),%r12
  mov    %r15d,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <box_num_gene@plt>
  mov    %r15d,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <pword_gene@plt>
  mov    %r14,%rdi
  call   <adj_order@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pwd_gene(unsigned char *app, unsigned char *username, unsigned char *password, int pwd_len) {
  do {
  } while (0);
  int box_num[3];
  unsigned char *seed = (unsigned char *)malloc((strlen(app) + strlen(username) + 1) * sizeof(unsigned char));
  memset(seed, '\0', strlen(app) + strlen(username) + 1);
  unsigned char *random_num = (unsigned char *)malloc(3 * sizeof(unsigned char));
  seed_gene(app, username, seed);
  random_num_gene(seed, random_num, 3);
  box_num_gene(box_num, random_num, pwd_len);
  pword_gene(seed, password, box_num, pwd_len);
  adj_order(password);
  free(seed);
  free(random_num);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pwd_gene>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    0x1(%r12,%rax,1),%edx
  call   <memset@plt>
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  lea    0xc(%rsp),%r13
  call   <seed_gene@plt>
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <random_num_gene@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <box_num_gene@plt>
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <pword_gene@plt>
  mov    %r15,%rdi
  call   <adj_order@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pwd_gene(unsigned char *app, unsigned char *username, unsigned char *password, int pwd_len) {
  do {
  } while (0);
  int box_num[3];
  unsigned char *seed = (unsigned char *)malloc((strlen(app) + strlen(username) + 1) * sizeof(unsigned char));
  memset(seed, '\0', strlen(app) + strlen(username) + 1);
  unsigned char *random_num = (unsigned char *)malloc(3 * sizeof(unsigned char));
  seed_gene(app, username, seed);
  random_num_gene(seed, random_num, 3);
  box_num_gene(box_num, random_num, pwd_len);
  pword_gene(seed, password, box_num, pwd_len);
  adj_order(password);
  free(seed);
  free(random_num);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<pwd_gene>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %ecx,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%ebp
  call   <strlen@plt>
  lea    0x1(%rbp,%rax,1),%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rax,%rbp
  call   <strlen@plt>
  mov    %r14,%rdi
  mov    %eax,%r12d
  call   <strlen@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  lea    0x1(%r12,%rax,1),%edx
  call   <memset@plt>
  mov    $0x3,%edi
  call   <malloc@plt>
  mov    %r13,%rdi
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rax,%r12
  lea    0xc(%rsp),%r13
  call   <seed_gene@plt>
  mov    $0x3,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <random_num_gene@plt>
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  call   <box_num_gene@plt>
  mov    %ebx,%ecx
  mov    %r13,%rdx
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <pword_gene@plt>
  mov    %r15,%rdi
  call   <adj_order@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int pwd_gene(unsigned char *app, unsigned char *username, unsigned char *password, int pwd_len) {
  do {
  } while (0);
  int box_num[3];
  unsigned char *seed = (unsigned char *)malloc((strlen(app) + strlen(username) + 1) * sizeof(unsigned char));
  memset(seed, '\0', strlen(app) + strlen(username) + 1);
  unsigned char *random_num = (unsigned char *)malloc(3 * sizeof(unsigned char));
  seed_gene(app, username, seed);
  random_num_gene(seed, random_num, 3);
  box_num_gene(box_num, random_num, pwd_len);
  pword_gene(seed, password, box_num, pwd_len);
  adj_order(password);
  free(seed);
  free(random_num);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<average>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L4:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x4,%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    0xc(%rax),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L11:
  cmpl   $0x2,-0x8(%rbp)
  jle    L4
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x55555556,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  pop    %rbp
  ret
```

assistant: ```c
int average(int a[3][4]) {
  int i;
  int j = 0;
  for (i = 0; i < 3; i++)
    j = j + a[i][3];
  return j / 3;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<average>:
  endbr64
  mov    0x1c(%rdi),%edx
  add    0xc(%rdi),%edx
  add    0x2c(%rdi),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sar    $0x1f,%edx
  sub    %edx,%eax
  ret
```

assistant: ```c
int average(int a[3][4]) {
  int i;
  int j = 0;
  for (i = 0; i < 3; i++)
    j = j + a[i][3];
  return j / 3;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<average>:
  endbr64
  mov    0x1c(%rdi),%edx
  add    0xc(%rdi),%edx
  add    0x2c(%rdi),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  ret
```

assistant: ```c
int average(int a[3][4]) {
  int i;
  int j = 0;
  for (i = 0; i < 3; i++)
    j = j + a[i][3];
  return j / 3;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<average>:
  endbr64
  mov    0x1c(%rdi),%edx
  add    0xc(%rdi),%edx
  add    0x2c(%rdi),%edx
  movslq %edx,%rax
  sar    $0x1f,%edx
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  sub    %edx,%eax
  ret
```

assistant: ```c
int average(int a[3][4]) {
  int i;
  int j = 0;
  for (i = 0; i < 3; i++)
    j = j + a[i][3];
  return j / 3;
}
```
user: What is the c source code of the assembly code below?

```asm
<treedir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x20(%rbp),%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x10,%rax
  movsd  (%rax),%xmm1
  addsd  %xmm2,%xmm1
  movsd  D16(%rip),%xmm2
  divsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jbe    L6
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm0
  mov    -0x18(%rbp),%rax
  add    $0x8,%rax
  movsd  (%rax),%xmm2
  mov    -0x18(%rbp),%rax
  add    $0x18,%rax
  movsd  (%rax),%xmm1
  addsd  %xmm2,%xmm1
  movsd  D16(%rip),%xmm2
  divsd  %xmm2,%xmm1
  comisd %xmm1,%xmm0
  jbe    L1
  addl   $0x2,-0x4(%rbp)
L1:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D16
type: f64

tool: D16: 2

assistant: ```c
int treedir(double *bb, double *x) {
  int d = 0;
  if (x[0] > (bb[0] + bb[2]) / 2.0)
    d += 1;
  if (x[1] > (bb[1] + bb[3]) / 2.0)
    d += 2;
  return d;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<treedir>:
  endbr64
  movsd  (%rdi),%xmm0
  addsd  0x10(%rdi),%xmm0
  movsd  D6(%rip),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  (%rsi),%xmm2
  comisd %xmm0,%xmm2
  seta   %al
  movzbl %al,%eax
  movsd  0x8(%rdi),%xmm0
  addsd  0x18(%rdi),%xmm0
  mulsd  %xmm1,%xmm0
  movsd  0x8(%rsi),%xmm1
  lea    0x2(%rax),%edx
  comisd %xmm0,%xmm1
  cmova  %edx,%eax
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D6
type_guessed: byte[8]

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
int treedir(double *bb, double *x) {
  int d = 0;
  if (x[0] > (bb[0] + bb[2]) / 2.0)
    d += 1;
  if (x[1] > (bb[1] + bb[3]) / 2.0)
    d += 2;
  return d;
}
```