ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  lea    D21(%rip),%rdi
  push   %rbp
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x2(%rsp),%rbp
  lea    0xd(%rsp),%r12
  mov    %rbp,%rsi
  mov    %r12,%rdx
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <strlen@plt>
  lea    -0x1(%rax),%rsi
  movzbl 0x2(%rsp,%rsi,1),%ecx
  sub    $0x61,%ecx
  cmp    $0x17,%cl
  ja     L21
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x104111,%edx
  jne    L29
  cmp    $0x17,%cl
  je     L11
L21:
  mov    %r12,%rcx
  lea    D27(%rip),%rdx
  mov    %rbp,%rsi
  lea    D22(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L63
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L29:
  movb   $0x0,0x2(%rsp,%rsi,1)
  jmp    L21
L11:
  cmpb   $0x65,(%rsp,%rax,1)
  jne    L21
  movb   $0x0,(%rsp,%rax,1)
  jmp    L21
L63:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
datatype: string
name: retrieve_data
arguments: label: D27
datatype: string
name: retrieve_data
arguments: label: D22
datatype: string

tool: D21: %s %s

tool: D27: ex

tool: D22: %s%s%s


assistant: ```c
int main() {
  char first[11], second[11];
  scanf("%s %s", first, second);
  size_t f_len = strlen(first);
  switch (first[f_len - 1]) {
  case 'a':
  case 'e':
  case 'i':
  case 'o':
  case 'u':
    first[f_len - 1] = 0;
    break;
  case 'x':
    if (first[f_len - 2] == 'e')
      first[f_len - 2] = 0;
    break;
  }
  printf("%s%s%s\n", first, "ex", second);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<to_integer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,-0xc(%rbp)
  jmp    L14
L17:
  mov    -0xc(%rbp),%edx
  mov    -0x18(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <valueAt@plt>
  sub    $0x30,%eax
  imul   -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,-0x8(%rbp)
  subl   $0x1,-0xc(%rbp)
L14:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L17
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int to_integer(struct node *head, int begin, int end) {
  int i, p, s;
  for (s = 0, p = 1, i = end - 1; i >= begin; p *= 10, i--) {
    s += p * (valueAt(head, i) - '0');
  }
  return s;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<to_integer>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x1(%rdx),%ebp
  cmp    %esi,%ebp
  jl     L14
  mov    %rdi,%r14
  mov    %esi,%r13d
  mov    $0x0,%r12d
  mov    $0x1,%ebx
L28:
  mov    %ebp,%esi
  mov    %r14,%rdi
  call   <valueAt@plt>
  sub    $0x30,%eax
  imul   %ebx,%eax
  add    %eax,%r12d
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  sub    $0x1,%ebp
  cmp    %ebp,%r13d
  jle    L28
L24:
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    $0x0,%r12d
  jmp    L24
```

assistant: ```c
int to_integer(struct node *head, int begin, int end) {
  int i, p, s;
  for (s = 0, p = 1, i = end - 1; i >= begin; p *= 10, i--) {
    s += p * (valueAt(head, i) - '0');
  }
  return s;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<to_integer>:
  endbr64
  push   %r14
  lea    -0x1(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %esi,%r14d
  jl     L8
  mov    %rdi,%r13
  mov    %esi,%ebp
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  mov    %r14d,%esi
  mov    %r13,%rdi
  sub    $0x1,%r14d
  call   <valueAt@plt>
  sub    $0x30,%eax
  imul   %ebx,%eax
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  add    %eax,%r12d
  cmp    %r14d,%ebp
  jle    L0
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int to_integer(struct node *head, int begin, int end) {
  int i, p, s;
  for (s = 0, p = 1, i = end - 1; i >= begin; p *= 10, i--) {
    s += p * (valueAt(head, i) - '0');
  }
  return s;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<to_integer>:
  endbr64
  push   %r14
  lea    -0x1(%rdx),%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    %esi,%r14d
  jl     L19
  mov    %rdi,%r13
  mov    %esi,%ebp
  xor    %r12d,%r12d
  mov    $0x1,%ebx
  nopw   0x0(%rax,%rax,1)
L2:
  mov    %r14d,%esi
  mov    %r13,%rdi
  sub    $0x1,%r14d
  call   <valueAt@plt>
  sub    $0x30,%eax
  imul   %ebx,%eax
  lea    (%rbx,%rbx,4),%ebx
  add    %ebx,%ebx
  add    %eax,%r12d
  cmp    %r14d,%ebp
  jle    L2
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L19:
  xor    %r12d,%r12d
  pop    %rbx
  pop    %rbp
  mov    %r12d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int to_integer(struct node *head, int begin, int end) {
  int i, p, s;
  for (s = 0, p = 1, i = end - 1; i >= begin; p *= 10, i--) {
    s += p * (valueAt(head, i) - '0');
  }
  return s;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pdu_7to8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  jne    L43
  mov    -0x28(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <s_len@plt>
  mov    %rax,-0x30(%rbp)
L43:
  mov    -0x30(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  addq   $0x1,-0x30(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L96
L49:
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    $0x40,%rax
  jne    L1
  mov    -0x20(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L1:
  addq   $0x1,-0x20(%rbp)
L96:
  mov    -0x20(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L49
  movq   $0x0,-0x18(%rbp)
  jmp    L61
L25:
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    $0x5f,%rax
  jne    L21
  mov    -0x18(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movq   $0x11,(%rax)
L21:
  addq   $0x1,-0x18(%rbp)
L61:
  mov    -0x18(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jb     L25
  cmpq   $0x0,-0x30(%rbp)
  je     L48
  movq   $0x0,-0x10(%rbp)
  jmp    L112
L67:
  mov    -0x30(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L90
L77:
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  shl    $0x7,%rax
  movzbl %al,%edx
  mov    -0x8(%rbp),%rax
  shl    $0x3,%rax
  lea    -0x8(%rax),%rsi
  mov    -0x28(%rbp),%rax
  add    %rsi,%rax
  or     %rcx,%rdx
  mov    %rdx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rcx
  mov    -0x28(%rbp),%rax
  add    %rcx,%rax
  shr    %rdx
  mov    %rdx,(%rax)
  subq   $0x1,-0x8(%rbp)
L90:
  mov    -0x8(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  ja     L77
  addq   $0x1,-0x10(%rbp)
L112:
  mov    -0x30(%rbp),%rax
  sub    $0x2,%rax
  cmp    %rax,-0x10(%rbp)
  jb     L67
L48:
  subq   $0x1,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  shr    $0x3,%rax
  mov    %rax,%rdx
  mov    -0x30(%rbp),%rax
  sub    %rdx,%rax
  leave
  ret
```

assistant: ```c
uint8_t pdu_7to8(uint8_t *a, uint8_t len) {
  if (len == 0)
    len = s_len(a, 0);
  a[len] = 0;
  len++;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '@')
      a[j] = 0x00;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '_')
      a[j] = 0x11;
  if (len > 0) {
    for (uint8_t i1 = 0; i1 < (len - 2); i1++) {
      for (uint8_t i2 = (len - 1); i2 > i1; i2--) {
        a[i2 - 1] = a[i2 - 1] | ((a[i2] & 1) ? 0x80 : 0);
        a[i2] >>= 1;
      }
    }
  }
  len--;
  return len - (len >> 3);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pdu_7to8>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rax
  test   %rsi,%rsi
  je     L20
L12:
  lea    0x0(,%rax,8),%rdx
  lea    (%rbx,%rdx,1),%r9
  movq   $0x0,(%r9)
  cmp    $0xffffffffffffffff,%rax
  je     L62
  mov    %rbx,%rdi
  lea    0x8(%rbx,%rdx,1),%rcx
  mov    %rbx,%rdx
  jmp    L18
L20:
  mov    $0x0,%esi
  call   <s_len@plt>
  jmp    L12
L53:
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  je     L152
L18:
  cmpq   $0x40,(%rdx)
  jne    L53
  movq   $0x0,(%rdx)
  jmp    L53
L152:
  mov    %rbx,%rdx
  jmp    L163
L96:
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  je     L111
L163:
  cmpq   $0x5f,(%rdx)
  jne    L96
  movq   $0x11,(%rdx)
  jmp    L96
L110:
  mov    (%rdx),%rcx
  mov    %rcx,%rsi
  shl    $0x7,%rsi
  movzbl %sil,%esi
  or     %rsi,-0x8(%rdx)
  shr    %rcx
  mov    %rcx,(%rdx)
  sub    $0x8,%rdx
  cmp    %rdx,%rdi
  jne    L110
L76:
  add    $0x1,%r8
  add    $0x8,%rdi
  cmp    %r10,%r8
  je     L62
L107:
  mov    %r9,%rdx
  cmp    %r8,%rax
  ja     L110
  jmp    L76
L111:
  mov    %rax,%r10
  sub    $0x1,%r10
  je     L62
  mov    $0x0,%r8d
  jmp    L107
L62:
  mov    %rax,%rdx
  shr    $0x3,%rdx
  sub    %rdx,%rax
  pop    %rbx
  ret
```

assistant: ```c
uint8_t pdu_7to8(uint8_t *a, uint8_t len) {
  if (len == 0)
    len = s_len(a, 0);
  a[len] = 0;
  len++;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '@')
      a[j] = 0x00;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '_')
      a[j] = 0x11;
  if (len > 0) {
    for (uint8_t i1 = 0; i1 < (len - 2); i1++) {
      for (uint8_t i2 = (len - 1); i2 > i1; i2--) {
        a[i2 - 1] = a[i2 - 1] | ((a[i2] & 1) ? 0x80 : 0);
        a[i2] >>= 1;
      }
    }
  }
  len--;
  return len - (len >> 3);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pdu_7to8>:
  endbr64
  push   %rbx
  mov    %rsi,%rax
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L76
L21:
  lea    0x0(,%rax,8),%rdx
  lea    (%rbx,%rdx,1),%r9
  movq   $0x0,(%r9)
  cmp    $0xffffffffffffffff,%rax
  je     L83
  lea    0x8(%rbx,%rdx,1),%rcx
  mov    %rbx,%r8
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L12:
  cmpq   $0x40,(%rdx)
  jne    L25
  movq   $0x0,(%rdx)
L25:
  add    $0x8,%rdx
  cmp    %rcx,%rdx
  jne    L12
  mov    %rbx,%rdi
  nopl   0x0(%rax)
L99:
  cmpq   $0x5f,(%rdi)
  jne    L3
  movq   $0x11,(%rdi)
L3:
  add    $0x8,%rdi
  cmp    %rcx,%rdi
  jne    L99
  mov    %rax,%r10
  sub    $0x1,%r10
  je     L83
  xor    %edi,%edi
  nopl   0x0(%rax)
L95:
  mov    %r9,%rdx
  cmp    %rdi,%rax
  jbe    L88
L71:
  mov    (%rdx),%rcx
  mov    %rcx,%rsi
  shr    %rcx
  shl    $0x7,%rsi
  mov    %rcx,(%rdx)
  movzbl %sil,%esi
  or     %rsi,-0x8(%rdx)
  sub    $0x8,%rdx
  cmp    %r8,%rdx
  jne    L71
L88:
  add    $0x1,%rdi
  add    $0x8,%r8
  cmp    %r10,%rdi
  jne    L95
L83:
  mov    %rax,%rdx
  pop    %rbx
  shr    $0x3,%rdx
  sub    %rdx,%rax
  ret
L76:
  xor    %esi,%esi
  call   <s_len@plt>
  jmp    L21
```

assistant: ```c
uint8_t pdu_7to8(uint8_t *a, uint8_t len) {
  if (len == 0)
    len = s_len(a, 0);
  a[len] = 0;
  len++;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '@')
      a[j] = 0x00;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '_')
      a[j] = 0x11;
  if (len > 0) {
    for (uint8_t i1 = 0; i1 < (len - 2); i1++) {
      for (uint8_t i2 = (len - 1); i2 > i1; i2--) {
        a[i2 - 1] = a[i2 - 1] | ((a[i2] & 1) ? 0x80 : 0);
        a[i2] >>= 1;
      }
    }
  }
  len--;
  return len - (len >> 3);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pdu_7to8>:
  endbr64
  push   %rbp
  mov    %rsi,%rax
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  test   %rsi,%rsi
  je     L59
L71:
  lea    0x0(,%rax,8),%rdx
  lea    (%rbx,%rdx,1),%r9
  movq   $0x0,(%r9)
  cmp    $0xffffffffffffffff,%rax
  je     L2
  lea    0x8(%rbx,%rdx,1),%rsi
  mov    %rbx,%rcx
  mov    %rbx,%rdx
  nopl   0x0(%rax)
L32:
  cmpq   $0x40,(%rdx)
  jne    L140
  movq   $0x0,(%rdx)
L140:
  add    $0x8,%rdx
  cmp    %rsi,%rdx
  jne    L32
  xchg   %ax,%ax
L19:
  cmpq   $0x5f,(%rcx)
  jne    L87
  movq   $0x11,(%rcx)
L87:
  add    $0x8,%rcx
  cmp    %rsi,%rcx
  jne    L19
  mov    %rax,%r10
  sub    $0x1,%r10
  je     L2
  test   %rax,%rax
  je     L2
  cmp    %r10,%rax
  mov    %r10,%r11
  mov    $0x1,%r8d
  cmovbe %rax,%r11
  xor    %edi,%edi
  xchg   %ax,%ax
L14:
  cmp    %r8,%r10
  jbe    L83
  cmp    %r10,%rdi
  ja     L83
  mov    (%r9),%rcx
  mov    %r9,%rbp
  mov    %rax,%rdx
L80:
  mov    %rcx,%rsi
  shr    %rcx
  sub    $0x10,%rbp
  shl    $0x7,%rsi
  mov    %rcx,0x10(%rbp)
  movzbl %sil,%esi
  or     0x8(%rbp),%rsi
  mov    %rsi,%rcx
  shr    %rsi
  mov    %rsi,0x8(%rbp)
  shl    $0x7,%rcx
  mov    %rdx,%rsi
  sub    $0x2,%rdx
  movzbl %cl,%ecx
  sub    $0x3,%rsi
  or     0x0(%rbp),%rcx
  mov    %rcx,0x0(%rbp)
  cmp    %r8,%rsi
  ja     L80
  xchg   %ax,%ax
L49:
  mov    (%rbx,%rdx,8),%rcx
  mov    %rcx,%rsi
  shr    %rcx
  shl    $0x7,%rsi
  mov    %rcx,(%rbx,%rdx,8)
  movzbl %sil,%esi
  or     %rsi,-0x8(%rbx,%rdx,8)
  sub    $0x1,%rdx
  cmp    %rdx,%rdi
  jb     L49
  add    $0x1,%rdi
  add    $0x1,%r8
  cmp    %r11,%rdi
  jb     L14
L2:
  mov    %rax,%rdx
  add    $0x8,%rsp
  shr    $0x3,%rdx
  pop    %rbx
  pop    %rbp
  sub    %rdx,%rax
  ret
  cs nopw 0x0(%rax,%rax,1)
L83:
  mov    %rax,%rdx
  jmp    L49
L59:
  xor    %esi,%esi
  call   <s_len@plt>
  jmp    L71
```

assistant: ```c
uint8_t pdu_7to8(uint8_t *a, uint8_t len) {
  if (len == 0)
    len = s_len(a, 0);
  a[len] = 0;
  len++;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '@')
      a[j] = 0x00;
  for (uint8_t j = 0; j < len; j++)
    if (a[j] == '_')
      a[j] = 0x11;
  if (len > 0) {
    for (uint8_t i1 = 0; i1 < (len - 2); i1++) {
      for (uint8_t i2 = (len - 1); i2 > i1; i2--) {
        a[i2 - 1] = a[i2 - 1] | ((a[i2] & 1) ? 0x80 : 0);
        a[i2] >>= 1;
      }
    }
  }
  len--;
  return len - (len >> 3);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rand_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L8
  mov    $0x0,%eax
  jmp    L6
L8:
  mov    D11(%rip),%rax
  mov    (%rax),%ecx
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
L29:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L29
  mov    -0x4(%rbp),%eax
  cltd
  idivl  -0x14(%rbp)
  mov    %edx,%eax
L6:
  leave
  ret
```

assistant: ```c
int rand_int(int n) {
  if (n <= 0)
    return 0;
  int limit = RAND_MAX - RAND_MAX % n;
  int rnd;
  do {
    rnd = rand();
  } while (rnd >= limit);
  return rnd % n;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rand_int>:
  endbr64
  mov    $0x0,%edx
  test   %edi,%edi
  jle    L18
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    D0(%rip),%rax
  mov    (%rax),%ebx
  mov    %ebx,%eax
  cltd
  idiv   %edi
  sub    %edx,%ebx
L3:
  mov    $0x0,%eax
  call   <rand@plt>
  cmp    %eax,%ebx
  jle    L3
  cltd
  idiv   %ebp
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L18:
  mov    %edx,%eax
  ret
```

assistant: ```c
int rand_int(int n) {
  if (n <= 0)
    return 0;
  int limit = RAND_MAX - RAND_MAX % n;
  int rnd;
  do {
    rnd = rand();
  } while (rnd >= limit);
  return rnd % n;
}
```
user: What is the c source code of the assembly code below:

```asm
<rand_int>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%ebx
  mov    %ebx,%eax
  cltd
  idiv   %edi
  sub    %edx,%ebx
L0:
  xor    %eax,%eax
  call   <rand@plt>
  cmp    %eax,%ebx
  jle    L0
  cltd
  add    $0x8,%rsp
  idiv   %ebp
  pop    %rbx
  pop    %rbp
  mov    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rand_int(int n) {
  if (n <= 0)
    return 0;
  int limit = RAND_MAX - RAND_MAX % n;
  int rnd;
  do {
    rnd = rand();
  } while (rnd >= limit);
  return rnd % n;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rand_int>:
  endbr64
  test   %edi,%edi
  jle    L11
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x8,%rsp
  mov    D9(%rip),%rax
  mov    (%rax),%ebx
  mov    %ebx,%eax
  cltd
  idiv   %edi
  sub    %edx,%ebx
L12:
  xor    %eax,%eax
  call   <rand@plt>
  cmp    %eax,%ebx
  jle    L12
  cltd
  add    $0x8,%rsp
  idiv   %ebp
  pop    %rbx
  pop    %rbp
  mov    %edx,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int rand_int(int n) {
  if (n <= 0)
    return 0;
  int limit = RAND_MAX - RAND_MAX % n;
  int rnd;
  do {
    rnd = rand();
  } while (rnd >= limit);
  return rnd % n;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movq   $0x0,-0x10(%rbp)
  movq   $0x2000000,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  movl   $0x1,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%edx
  mov    -0x10(%rbp),%rax
  mov    %edx,(%rax)
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  *(localArr) = 1;
  *(remoteArr1) = *(localArr);
  *(localArr) += 1;
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  movl   $0x1,0x2000000
  movl   $0x2,0x0
  mov    $0x0,%eax
  ret
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  *(localArr) = 1;
  *(remoteArr1) = *(localArr);
  *(localArr) += 1;
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  movl   $0x1,0x2000000
  movl   $0x0,0x0
  ud2
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  *(localArr) = 1;
  *(remoteArr1) = *(localArr);
  *(localArr) += 1;
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  movl   $0x1,0x2000000
  movl   $0x0,0x0
  ud2
```

assistant: ```c
int main() {
  int *localArr = (int *)0x00000000;
  int *remoteArr1 = (int *)0x02000000;
  *(localArr) = 1;
  *(remoteArr1) = *(localArr);
  *(localArr) += 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ambe_resample_mag>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  pxor   %xmm6,%xmm6
  cvtsi2ss %esi,%xmm6
  movss  %xmm6,0xc(%rsp)
  pxor   %xmm0,%xmm0
  cvtsi2ss %ecx,%xmm0
  movaps %xmm0,%xmm5
  divss  %xmm6,%xmm5
  movss  %xmm5,0x8(%rsp)
  test   %esi,%esi
  jle    L46
  mov    %rdi,%rbx
  mov    %rdx,%r13
  mov    %ecx,%r14d
  movslq %ecx,%rax
  lea    -0x4(%rdx,%rax,4),%r15
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi,%rax,4),%r12
  movss  %xmm5,(%rsp)
  pxor   %xmm7,%xmm7
  movss  %xmm7,0x4(%rsp)
  jmp    L24
L28:
  cmp    %eax,%r14d
  jg     L34
  movss  (%r15),%xmm0
  movss  %xmm0,(%rbx)
L37:
  movss  0x4(%rsp),%xmm2
  addss  (%rbx),%xmm2
  movss  %xmm2,0x4(%rsp)
  movss  (%rsp),%xmm3
  addss  0x8(%rsp),%xmm3
  movss  %xmm3,(%rsp)
  add    $0x4,%rbx
  cmp    %r12,%rbx
  je     L25
L24:
  movss  (%rsp),%xmm0
  call   <floorf@plt>
  test   %eax,%eax
  jne    L28
  movss  0x0(%r13),%xmm0
  movss  %xmm0,(%rbx)
  jmp    L37
L34:
  pxor   %xmm0,%xmm0
  cvtsi2ss %eax,%xmm0
  movss  (%rsp),%xmm1
  subss  %xmm0,%xmm1
  cltq
  movss  D0(%rip),%xmm0
  subss  %xmm1,%xmm0
  mulss  -0x4(%r13,%rax,4),%xmm0
  mulss  0x0(%r13,%rax,4),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,(%rbx)
  jmp    L37
L25:
  movss  0x4(%rsp),%xmm1
  divss  0xc(%rsp),%xmm1
L23:
  movss  0x0(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movss  %xmm0,0x0(%rbp)
  add    $0x4,%rbp
  cmp    %r12,%rbp
  jne    L23
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D0
type_guessed: byte[4]

tool: {"D0": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void ambe_resample_mag(float *mag_dst, int L_dst, float *mag_src, int L_src) {
  float avg, step, pos;
  int i;
  avg = 0.0f;
  step = (float)L_src / (float)L_dst;
  pos = step;
  for (i = 0; i < L_dst; i++) {
    int posi = (int)floorf(pos);
    if (posi == 0) {
      mag_dst[i] = mag_src[0];
    } else if (posi >= L_src) {
      mag_dst[i] = mag_src[L_src - 1];
    } else {
      float alpha = pos - posi;
      mag_dst[i] = mag_src[posi - 1] * (1.0f - alpha) + mag_src[posi] * alpha;
    }
    avg += mag_dst[i];
    pos += step;
  }
  avg /= L_dst;
  for (i = 0; i < L_dst; i++)
    mag_dst[i] -= avg;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ambe_resample_mag>:
  endbr64
  pxor   %xmm0,%xmm0
  pxor   %xmm5,%xmm5
  push   %r15
  cvtsi2ss %ecx,%xmm0
  push   %r14
  cvtsi2ss %esi,%xmm5
  push   %r13
  push   %r12
  push   %rbp
  movaps %xmm0,%xmm1
  push   %rbx
  divss  %xmm5,%xmm1
  sub    $0x18,%rsp
  movss  %xmm5,0xc(%rsp)
  movss  %xmm1,0x8(%rsp)
  test   %esi,%esi
  jle    L3
  movslq %ecx,%rax
  mov    %rdx,%rbp
  mov    %ecx,%r12d
  mov    %rdi,%rbx
  lea    -0x4(%rdx,%rax,4),%r13
  lea    -0x1(%rsi),%eax
  pxor   %xmm2,%xmm2
  mov    %rdi,%r15
  lea    0x4(%rdi,%rax,4),%r14
  jmp    L53
  nop
L50:
  movss  0x0(%rbp),%xmm0
L14:
  movss  %xmm0,(%r15)
  add    $0x4,%r15
  addss  %xmm0,%xmm2
  addss  0x8(%rsp),%xmm1
  cmp    %r15,%r14
  je     L11
L53:
  movaps %xmm1,%xmm0
  movss  %xmm2,0x4(%rsp)
  movss  %xmm1,(%rsp)
  call   <floorf@plt>
  movss  (%rsp),%xmm1
  movss  0x4(%rsp),%xmm2
  test   %eax,%eax
  je     L50
  cmp    %eax,%r12d
  jg     L9
  movss  0x0(%r13),%xmm0
  jmp    L14
  nopl   0x0(%rax)
L9:
  pxor   %xmm0,%xmm0
  movaps %xmm1,%xmm3
  cvtsi2ss %eax,%xmm0
  cltq
  subss  %xmm0,%xmm3
  movss  D5(%rip),%xmm0
  subss  %xmm3,%xmm0
  mulss  0x0(%rbp,%rax,4),%xmm3
  mulss  -0x4(%rbp,%rax,4),%xmm0
  addss  %xmm3,%xmm0
  jmp    L14
  nop
L11:
  divss  0xc(%rsp),%xmm2
  cs nopw 0x0(%rax,%rax,1)
L7:
  movss  (%rbx),%xmm0
  add    $0x4,%rbx
  subss  %xmm2,%xmm0
  movss  %xmm0,-0x4(%rbx)
  cmp    %rbx,%r14
  jne    L7
L3:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_guessed: byte[4]

tool: {"D5": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void ambe_resample_mag(float *mag_dst, int L_dst, float *mag_src, int L_src) {
  float avg, step, pos;
  int i;
  avg = 0.0f;
  step = (float)L_src / (float)L_dst;
  pos = step;
  for (i = 0; i < L_dst; i++) {
    int posi = (int)floorf(pos);
    if (posi == 0) {
      mag_dst[i] = mag_src[0];
    } else if (posi >= L_src) {
      mag_dst[i] = mag_src[L_src - 1];
    } else {
      float alpha = pos - posi;
      mag_dst[i] = mag_src[posi - 1] * (1.0f - alpha) + mag_src[posi] * alpha;
    }
    avg += mag_dst[i];
    pos += step;
  }
  avg /= L_dst;
  for (i = 0; i < L_dst; i++)
    mag_dst[i] -= avg;
}
```
user: What is the c source code of the assembly code below?

```asm
<wy2u01>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movsd  D8(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  sar    $0xb,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  mulsd  -0x8(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D8
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xb0,0x3c]}

assistant: ```c
double wy2u01(uint64_t r) {
  const double _wynorm = 1.0 / (1ull << 52);
  return (r >> 11) * _wynorm;
}
```