user: 请将以下的汇编代码转换成C语言代码:

```asm
<DIVIDER_32b_AUTOTEST>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  lea    D56(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x1c(%rbp)
  movl   $0x0,-0x20(%rbp)
  jmp    L5
L24:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  shr    $0x10,%edx
  add    %edx,%eax
  movzwl %ax,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_fudiv@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_fudiv@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_mod@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <instr_mod@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jne    L25
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  je     L45
L25:
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0xc(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D62(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x4(%rbp),%ecx
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D66(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L13
L45:
  addl   $0x1,-0x20(%rbp)
L5:
  cmpl   $0x9,-0x20(%rbp)
  jle    L24
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x1,%eax
L13:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D56
data_type: string
name: parse_data
arguments: label: D52
data_type: string
name: parse_data
arguments: label: D11
data_type: string
name: parse_data
arguments: label: D15
data_type: string
name: parse_data
arguments: label: D62
data_type: string
name: parse_data
arguments: label: D1
data_type: string
name: parse_data
arguments: label: D66
data_type: string
name: parse_data
arguments: label: D42
data_type: string

tool: D56: LAUNCHING THE (uDIV/MOD) RESOURCE TEST...

tool: D52: - TEST OF THE DIVIDER_32b RESOURCE => FAILED !

tool: D11:   + %d COMPUTATION BEFORE ERROR... !


tool: D15:   + INSTRUCTION RESULT (%d udiv %d) => %d


tool: D62:   + C CODE RESULT      (%d udiv %d) => %d


tool: D1:   + INSTRUCTION RESULT (%d umod %d) => %d


tool: D66:   + C CODE RESULT      (%d umod %d) => %d


tool: D42: - TEST OF THE DIVIDER_32b RESOURCE => OK

assistant: ```c
int DIVIDER_32b_AUTOTEST() {
  printf("LAUNCHING THE (uDIV/MOD) RESOURCE TEST...\n");
  int isOk1 = 1;
  int i, j;
  for (j = 0; j < 10; j++) {
    int op1 = rand() % 65536;
    int op2 = rand() % 65536;
    int res1 = instr_fudiv(op1, op2);
    int res2 = instr_fudiv(op1, op2);
    int res3 = instr_mod(op1, op2);
    int res4 = instr_mod(op1, op2);
    if ((res1 != res2) || (res3 != res4)) {
      printf("- TEST OF THE DIVIDER_32b RESOURCE => FAILED !\n");
      printf("  + %d COMPUTATION BEFORE ERROR... !\n", j);
      printf("  + INSTRUCTION RESULT (%d udiv %d) => %d\n", op1, op2, res1);
      printf("  + C CODE RESULT      (%d udiv %d) => %d\n", op1, op2, res2);
      printf("  + INSTRUCTION RESULT (%d umod %d) => %d\n", op1, op2, res3);
      printf("  + C CODE RESULT      (%d umod %d) => %d\n", op1, op2, res4);
      return 0;
    }
  }
  printf("- TEST OF THE DIVIDER_32b RESOURCE => OK\n");
  return 1;
}
```