ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<print_linear_hist>:
  endbr64
  test   %esi,%esi
  jle    L23
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %esi,%edi
  mov    $0x0,%eax
  mov    $0x0,%ebx
  mov    $0xffffffff,%r12d
L34:
  mov    0x0(%r13,%rax,4),%ecx
  test   %ecx,%ecx
  cmovne %eax,%r12d
  cmp    %ecx,%ebx
  cmovb  %ecx,%ebx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L34
  test   %r12d,%r12d
  js     L1
  mov    %rdx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebp
  lea    D7(%rip),%r15
L26:
  mov    0x0(%r13,%rbp,4),%r14d
  mov    %r14d,%edx
  mov    %ebp,%esi
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x28,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <print_stars@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  add    $0x1,%rbp
  cmp    %ebp,%r12d
  jge    L26
L1:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D17
datatype: string

tool: D11:      %-13s : count     distribution


tool: D7:         %-10d : %-8d |

tool: D17: |

assistant: ```c
void print_linear_hist(unsigned int *vals, int vals_size, const char *val_type) {
  int i, stars_max = 40, idx_max = -1;
  unsigned int val, val_max = 0;
  for (i = 0; i < vals_size; i++) {
    val = vals[i];
    if (val > 0)
      idx_max = i;
    if (val > val_max)
      val_max = val;
  }
  if (idx_max < 0)
    return;
  printf("     %-13s : count     distribution\n", val_type);
  for (i = 0; i <= idx_max; i++) {
    val = vals[i];
    printf("        %-10d : %-8d |", i, val);
    print_stars(val, val_max, stars_max);
    printf("|\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_linear_hist>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  movslq %esi,%rdi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %edi,%edi
  jle    L10
  mov    %rdx,%rsi
  xor    %eax,%eax
  xor    %ebx,%ebx
  mov    $0xffffffff,%r12d
  nopl   (%rax)
L38:
  mov    0x0(%r13,%rax,4),%ecx
  test   %ecx,%ecx
  cmovne %eax,%r12d
  cmp    %ecx,%ebx
  cmovb  %ecx,%ebx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L38
  cmp    $0xffffffff,%r12d
  je     L10
  lea    D19(%rip),%rdi
  xor    %eax,%eax
  xor    %ebp,%ebp
  call   <printf@plt>
  lea    D0(%rip),%r15
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    0x0(%r13,%rbp,4),%r14d
  mov    %ebp,%esi
  mov    %r15,%rdi
  xor    %eax,%eax
  add    $0x1,%rbp
  mov    %r14d,%edx
  call   <printf@plt>
  mov    $0x28,%edx
  mov    %ebx,%esi
  mov    %r14d,%edi
  call   <print_stars@plt>
  lea    D18(%rip),%rdi
  call   <puts@plt>
  cmp    %ebp,%r12d
  jge    L25
L10:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: data_label: D19
data_type: string
name: parse_data
arguments: data_label: D0
data_type: string
name: parse_data
arguments: data_label: D18
data_type: string

tool: D19:      %-13s : count     distribution


tool: D0:         %-10d : %-8d |

tool: D18: |

assistant: ```c
void print_linear_hist(unsigned int *vals, int vals_size, const char *val_type) {
  int i, stars_max = 40, idx_max = -1;
  unsigned int val, val_max = 0;
  for (i = 0; i < vals_size; i++) {
    val = vals[i];
    if (val > 0)
      idx_max = i;
    if (val > val_max)
      val_max = val;
  }
  if (idx_max < 0)
    return;
  printf("     %-13s : count     distribution\n", val_type);
  for (i = 0; i <= idx_max; i++) {
    val = vals[i];
    printf("        %-10d : %-8d |", i, val);
    print_stars(val, val_max, stars_max);
    printf("|\n");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<timenewest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L16
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
L16:
  mov    $0x0,%eax
  call   <dbtgetnewest@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  lea    D17(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L4
L8:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <timeparse@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdx
  lea    D11(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <error@plt>
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D17
datatype: string
name: unpack_data
arguments: data_tag: D11
datatype: string

tool: D17: no time found in db

tool: D11: unkown time: '%s'

assistant: ```c
struct dbt *timenewest(const char *stime) {
  struct dbt *dt;
  if (!stime || !stime[0]) {
    if (!(dt = dbtgetnewest()))
      error(1, "no time found in db");
  } else if (!(dt = timeparse(stime)))
    error(1, "unkown time: '%s'", stime);
  return dt;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<timenewest>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L10
  mov    %rdi,%rbx
  cmpb   $0x0,(%rdi)
  jne    L32
L10:
  mov    $0x0,%eax
  call   <dbtgetnewest@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L57
L38:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L57:
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L38
L32:
  call   <timeparse@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  jne    L38
  mov    %rbx,%rdx
  lea    D5(%rip),%rsi
  mov    $0x1,%edi
  mov    $0x0,%eax
  call   <error@plt>
  jmp    L38
```

tool_calls: name: disassemble_data
arguments: data_label: D1
datatype: string
name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D1: no time found in db

tool: D5: unkown time: '%s'

assistant: ```c
struct dbt *timenewest(const char *stime) {
  struct dbt *dt;
  if (!stime || !stime[0]) {
    if (!(dt = dbtgetnewest()))
      error(1, "no time found in db");
  } else if (!(dt = timeparse(stime)))
    error(1, "unkown time: '%s'", stime);
  return dt;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<timenewest>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L44
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  jne    L7
L44:
  xor    %eax,%eax
  call   <dbtgetnewest@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L1
L27:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L7:
  call   <timeparse@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L27
  mov    %r12,%rdx
  lea    D17(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L27
  nopl   (%rax)
L1:
  lea    D18(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L27
```

tool_calls: name: parse_data
arguments: tag: D17
type_guessed: string
name: parse_data
arguments: tag: D18
type_guessed: string

tool: D17: unkown time: '%s'

tool: D18: no time found in db

assistant: ```c
struct dbt *timenewest(const char *stime) {
  struct dbt *dt;
  if (!stime || !stime[0]) {
    if (!(dt = dbtgetnewest()))
      error(1, "no time found in db");
  } else if (!(dt = timeparse(stime)))
    error(1, "unkown time: '%s'", stime);
  return dt;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<timenewest>:
  endbr64
  push   %r13
  push   %r12
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L54
  cmpb   $0x0,(%rdi)
  mov    %rdi,%r12
  jne    L15
L54:
  xor    %eax,%eax
  call   <dbtgetnewest@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L30
L33:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  call   <timeparse@plt>
  mov    %rax,%r13
  test   %rax,%rax
  jne    L33
  mov    %r12,%rdx
  lea    D18(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L33
  nopl   (%rax)
L30:
  lea    D15(%rip),%rsi
  mov    $0x1,%edi
  xor    %eax,%eax
  call   <error@plt>
  jmp    L33
```

tool_calls: name: parse_data
arguments: data_tag: D18
datatype: string
name: parse_data
arguments: data_tag: D15
datatype: string

tool: D18: unkown time: '%s'

tool: D15: no time found in db

assistant: ```c
struct dbt *timenewest(const char *stime) {
  struct dbt *dt;
  if (!stime || !stime[0]) {
    if (!(dt = dbtgetnewest()))
      error(1, "no time found in db");
  } else if (!(dt = timeparse(stime)))
    error(1, "unkown time: '%s'", stime);
  return dt;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x38(%rbp)
  jmp    L40
L30:
  mov    -0x38(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L40:
  mov    -0x38(%rbp),%eax
  cmp    -0x44(%rbp),%eax
  jl     L30
  lea    D42(%rip),%rax
  mov    %rax,-0x30(%rbp)
  lea    D49(%rip),%rax
  mov    %rax,-0x28(%rbp)
  lea    D57(%rip),%rax
  mov    %rax,-0x20(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x4,-0x34(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L32
L16:
  mov    -0x38(%rbp),%eax
  cltq
  mov    -0x30(%rbp,%rax,8),%rdx
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x38(%rbp)
L32:
  mov    -0x38(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L16
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D30
type: string
name: parse_data
arguments: tag: D42
type: string
name: parse_data
arguments: tag: D49
type: string
name: parse_data
arguments: tag: D57
type: string
name: parse_data
arguments: tag: D11
type: string
name: parse_data
arguments: tag: D47
type: string

tool: D30: arg %d: %s


tool: D42: California

tool: D49: Washington

tool: D57: Texas

tool: D11: Arizona

tool: D47: state %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("arg %d: %s\n", i, argv[i]);
    i++;
  }
  char *states[] = {"California", "Washington", "Texas", "Arizona"};
  int num_states = 4;
  i = 0;
  while (i < num_states) {
    printf("state %d: %s\n", i, states[i]);
    i++;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L6
  mov    %rsi,%r12
  mov    %edi,%ebp
  mov    $0x0,%ebx
  lea    D53(%rip),%r13
L24:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L24
L6:
  lea    D45(%rip),%rax
  mov    %rax,(%rsp)
  lea    D0(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    D17(%rip),%rax
  mov    %rax,0x10(%rsp)
  lea    D10(%rip),%rax
  mov    %rax,0x18(%rsp)
  mov    $0x0,%ebx
  lea    D54(%rip),%rbp
L36:
  mov    (%rsp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L36
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  mov    $0x0,%eax
  add    $0x38,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D53
type: string
name: retrieve_data
arguments: data_tag: D45
type: string
name: retrieve_data
arguments: data_tag: D0
type: string
name: retrieve_data
arguments: data_tag: D17
type: string
name: retrieve_data
arguments: data_tag: D10
type: string
name: retrieve_data
arguments: data_tag: D54
type: string

tool: D53: arg %d: %s


tool: D45: California

tool: D0: Washington

tool: D17: Texas

tool: D10: Arizona

tool: D54: state %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("arg %d: %s\n", i, argv[i]);
    i++;
  }
  char *states[] = {"California", "Washington", "Texas", "Arizona"};
  int num_states = 4;
  i = 0;
  while (i < num_states) {
    printf("state %d: %s\n", i, states[i]);
    i++;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L35
  mov    %rsi,%rbp
  movslq %edi,%r13
  lea    D10(%rip),%r12
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L26:
  mov    0x0(%rbp,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %r13,%rbx
  jne    L26
L35:
  lea    D4(%rip),%rax
  xor    %ebx,%ebx
  lea    D26(%rip),%rdx
  mov    %rax,0x8(%rsp)
  lea    D58(%rip),%rax
  lea    D21(%rip),%rbp
  mov    %rax,0x10(%rsp)
  lea    D38(%rip),%rax
  mov    %rax,0x18(%rsp)
L34:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  je     L25
  mov    (%rsp,%rbx,8),%rdx
  jmp    L34
  xchg   %ax,%ax
L25:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D10
datatype: string
name: extract_symbolic_data
arguments: data_tag: D4
datatype: string
name: extract_symbolic_data
arguments: data_tag: D26
datatype: string
name: extract_symbolic_data
arguments: data_tag: D58
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string
name: extract_symbolic_data
arguments: data_tag: D38
datatype: string

tool: D10: arg %d: %s


tool: D4: Washington

tool: D26: California

tool: D58: Texas

tool: D21: state %d: %s


tool: D38: Arizona

assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("arg %d: %s\n", i, argv[i]);
    i++;
  }
  char *states[] = {"California", "Washington", "Texas", "Arizona"};
  int num_states = 4;
  i = 0;
  while (i < num_states) {
    printf("state %d: %s\n", i, states[i]);
    i++;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  test   %edi,%edi
  jle    L22
  mov    %rsi,%r12
  movslq %edi,%rbp
  lea    D34(%rip),%r13
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L27:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L27
L22:
  lea    D2(%rip),%rax
  lea    D53(%rip),%rcx
  xor    %ebx,%ebx
  mov    %rsp,%r12
  movq   %rcx,%xmm0
  movq   %rax,%xmm1
  lea    D48(%rip),%rcx
  punpcklqdq %xmm1,%xmm0
  lea    D35(%rip),%rax
  lea    D42(%rip),%rbp
  movaps %xmm0,(%rsp)
  movq   %rax,%xmm2
  movq   %rcx,%xmm0
  punpcklqdq %xmm2,%xmm0
  movaps %xmm0,0x10(%rsp)
L33:
  mov    (%r12,%rbx,8),%rdx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x4,%rbx
  jne    L33
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x38,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D34
type_infered: string
name: disassemble_data
arguments: data_label: D2
type_infered: string
name: disassemble_data
arguments: data_label: D53
type_infered: string
name: disassemble_data
arguments: data_label: D48
type_infered: string
name: disassemble_data
arguments: data_label: D35
type_infered: string
name: disassemble_data
arguments: data_label: D42
type_infered: string

tool: D34: arg %d: %s


tool: D2: Washington

tool: D53: California

tool: D48: Texas

tool: D35: Arizona

tool: D42: state %d: %s


assistant: ```c
int main(int argc, char *argv[]) {
  int i = 0;
  while (i < argc) {
    printf("arg %d: %s\n", i, argv[i]);
    i++;
  }
  char *states[] = {"California", "Washington", "Texas", "Arizona"};
  int num_states = 4;
  i = 0;
  while (i < num_states) {
    printf("state %d: %s\n", i, states[i]);
    i++;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<kaczmarz>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %esi,%ebx
  mov    %edx,%ebp
  mov    %ecx,0x4(%rsp)
  mov    %r8,%r14
  mov    %r9,0x8(%rsp)
  cmp    %edx,%esi
  je     L6
  jle    L21
  mov    %edx,%edi
  imul   %edx,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebp,%r9d
  mov    %r12,%r8
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <relax_ata@plt>
  mov    %r13,%r9
  mov    %r14,%r8
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <relax_atb@plt>
  mov    0x8(%rsp),%r9
  mov    %r13,%r8
  mov    %ebp,%ecx
  mov    %ebp,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <iterate_kacz@plt>
  mov    %eax,%r14d
L18:
  test   %r12,%r12
  je     L69
  mov    %r12,%rdi
  call   <free@plt>
L69:
  test   %r13,%r13
  je     L41
  mov    %r13,%rdi
  call   <free@plt>
L41:
  mov    %r14d,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L6:
  lea    0x0(,%rsi,8),%edx
  mov    %r8,%rsi
  mov    %r9,%r13
  mov    %r9,%rdi
  call   <memcpy@plt>
  mov    %r13,%r9
  mov    %r14,%r8
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <iterate_kacz@plt>
  mov    %eax,%r14d
  jmp    L41
L21:
  mov    %esi,%edi
  imul   %esi,%edi
  shl    $0x3,%edi
  call   <malloc@plt>
  mov    %rax,%r12
  lea    0x0(,%rbx,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    %ebx,%r9d
  mov    %r12,%r8
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <relax_aat@plt>
  mov    %r13,%r9
  mov    %r14,%r8
  mov    %ebx,%ecx
  mov    %ebx,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <iterate_kacz@plt>
  mov    %eax,%r14d
  cmp    $0xffffffff,%eax
  je     L18
  mov    0x8(%rsp),%r9
  mov    %r13,%r8
  mov    0x4(%rsp),%ecx
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r15,%rdi
  call   <relax_atb@plt>
  jmp    L18
```

assistant: ```c
int kaczmarz(double *A, int m, int n, int stride, double *b, double *x0) {
  double *C, *c;
  int err;
  err = 0;
  C = NULL;
  c = NULL;
  if (m == n) {
    memcpy(x0, b, m * sizeof b[0]);
    if ((err = iterate_kacz(A, m, n, stride, b, x0)) == -1) {
      err = -1;
      goto err_out;
    }
  } else if (m > n) {
    C = malloc(n * n * sizeof C[0]);
    c = malloc(m * sizeof c[0]);
    relax_ata(A, m, n, stride, C, n);
    relax_atb(A, m, n, stride, b, c);
    if ((err = iterate_kacz(C, n, n, n, c, x0)) == -1) {
      err = -1;
      goto err_out;
    }
  } else {
    C = malloc(m * m * sizeof C[0]);
    c = malloc(m * sizeof c[0]);
    relax_aat(A, m, n, stride, C, m);
    if ((err = iterate_kacz(C, m, m, m, b, c)) == -1) {
      err = -1;
      goto err_out;
    }
    relax_atb(A, m, n, stride, c, x0);
  }
err_out:
  if (C != NULL)
    free(C);
  if (c != NULL)
    free(c);
  return err;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<foo>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8,-0x48(%rbp)
  mov    %r9,-0x50(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L31:
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  add    %edx,%eax
  cmp    $0x3,%eax
  jle    L0
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L18
L0:
  mov    -0xc(%rbp),%eax
  imul   %eax,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%eax
  imul   %eax,%eax
  sub    %eax,%edx
  mov    0x10(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x18(%rbp)
  mov    -0xc(%rbp),%eax
  imul   -0x8(%rbp),%eax
  lea    (%rax,%rax,1),%edx
  mov    0x18(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
L18:
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    -0x18(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x48(%rbp),%rax
  add    %rax,%rdx
  mov    -0x14(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x1c(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rax,%rdx
  mov    -0x10(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L14:
  cmpl   $0x3ffff,-0x1c(%rbp)
  jbe    L31
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void foo(const int *__restrict__ zr_in, const int *__restrict__ zi_in, const int *__restrict__ zk_in, int *__restrict__ zr_out, int *__restrict__ zi_out, int *__restrict__ zk_out, int cr, int ci) {
  unsigned int pi;
  int tmp_r, tmp_i, tmp_k;
  for (pi = 0; pi < (512) * (512); pi++) {
    int zr = zr_in[pi];
    int zi = zi_in[pi];
    int zk = zk_in[pi];
    if (zr * zr + zi * zi >= 4) {
      tmp_r = zr;
      tmp_i = zi;
      tmp_k = zk;
    } else {
      tmp_r = (zr * zr - zi * zi + cr);
      tmp_i = (2 * zr * zi + ci);
      tmp_k = zk + 1;
    }
    zr_out[pi] = tmp_r;
    zi_out[pi] = tmp_i;
    zk_out[pi] = tmp_k;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<foo>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r11
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%r12
  mov    0x38(%rsp),%r14d
  mov    0x40(%rsp),%r13d
  mov    $0x0,%eax
  jmp    L2
L26:
  mov    %ecx,(%r12,%rax,1)
  mov    %edx,(%r8,%rax,1)
  mov    %edi,(%r9,%rax,1)
  add    $0x4,%rax
  cmp    $0x100000,%rax
  je     L34
L2:
  mov    (%r11,%rax,1),%ecx
  mov    (%rbx,%rax,1),%edx
  mov    0x0(%rbp,%rax,1),%edi
  mov    %ecx,%esi
  imul   %ecx,%esi
  mov    %edx,%r10d
  imul   %edx,%r10d
  lea    (%rsi,%r10,1),%r15d
  cmp    $0x3,%r15d
  jg     L26
  sub    %r10d,%esi
  imul   %ecx,%edx
  lea    0x0(%r13,%rdx,2),%edx
  add    $0x1,%edi
  lea    (%rsi,%r14,1),%ecx
  jmp    L26
L34:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void foo(const int *__restrict__ zr_in, const int *__restrict__ zi_in, const int *__restrict__ zk_in, int *__restrict__ zr_out, int *__restrict__ zi_out, int *__restrict__ zk_out, int cr, int ci) {
  unsigned int pi;
  int tmp_r, tmp_i, tmp_k;
  for (pi = 0; pi < (512) * (512); pi++) {
    int zr = zr_in[pi];
    int zi = zi_in[pi];
    int zk = zk_in[pi];
    if (zr * zr + zi * zi >= 4) {
      tmp_r = zr;
      tmp_i = zi;
      tmp_k = zk;
    } else {
      tmp_r = (zr * zr - zi * zi + cr);
      tmp_i = (2 * zr * zi + ci);
      tmp_k = zk + 1;
    }
    zr_out[pi] = tmp_r;
    zi_out[pi] = tmp_i;
    zk_out[pi] = tmp_k;
  }
}
```