user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  lea    D37(%rip),%r13
  push   %r12
  lea    D39(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    0x20(%rsp),%r14
  lea    0xce(%rsp),%rbp
  mov    %r14,%rbx
  jmp    L117
  nopl   0x0(%rax,%rax,1)
L114:
  lea    0x8(%rbx),%rcx
  lea    0x4(%rbx),%rdx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  lea    0xc(%rbx),%r8
  xor    %eax,%eax
  add    $0x1,%r15
  add    $0x10,%rbx
  call   <scanf@plt>
L117:
  xor    %eax,%eax
  lea    0x0(%rbp,%r15,1),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  cmpb   $0x2a,0x0(%rbp,%r15,1)
  jne    L114
  xor    %ebx,%ebx
  lea    0x1c(%rsp),%r13
  lea    0x18(%rsp),%r12
  lea    D38(%rip),%rbp
  nopl   0x0(%rax,%rax,1)
L128:
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  movss  D2(%rip),%xmm1
  mulss  0x1c(%rsp),%xmm1
  movss  0x18(%rsp),%xmm0
  cvttss2si %xmm1,%rax
  cmp    $0x1869f,%rax
  jne    L48
  movss  D2(%rip),%xmm1
  mulss  %xmm0,%xmm1
  cvttss2si %xmm1,%rax
  cmp    $0x1869f,%rax
  je     L32
L48:
  add    $0x1,%rbx
  mov    %r14,%rcx
  xor    %eax,%eax
  xor    %edx,%edx
  test   %r15,%r15
  jne    L11
  jmp    L66
L95:
  movss  0x18(%rsp),%xmm0
L11:
  add    $0x1,%rdx
  comiss (%rcx),%xmm0
  jbe    L67
  movss  0x8(%rcx),%xmm1
  comiss %xmm0,%xmm1
  jbe    L67
  movss  0x1c(%rsp),%xmm0
  movss  0x4(%rcx),%xmm1
  comiss %xmm0,%xmm1
  jbe    L67
  comiss 0xc(%rcx),%xmm0
  ja     L101
  nop
L67:
  add    $0x10,%rcx
  cmp    %rdx,%r15
  jne    L95
  test   %rax,%rax
  jne    L128
L66:
  mov    %rbx,%rsi
  lea    D1(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L128
  nopl   0x0(%rax,%rax,1)
L101:
  mov    %rbx,%rsi
  lea    D40(%rip),%rdi
  xor    %eax,%eax
  mov    %rdx,(%rsp)
  mov    %rcx,0x8(%rsp)
  call   <printf@plt>
  mov    0x8(%rsp),%rcx
  mov    (%rsp),%rdx
  mov    $0x1,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L32:
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L65
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L65:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D37
type: string
name: read_data
arguments: label: D39
type: string
name: read_data
arguments: label: D38
type: string
name: read_data
arguments: label: D2
type: byte[4]
name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D40
type: string

tool: D37: %f %f %f %f

tool: D39:  %c

tool: D38: %f %f

tool: {"D2": [0x00,0x00,0x20,0x41]}

tool: D1: Point %ld is not contained in any figure


tool: D40: Point %ld is contained in figure %ld


assistant: ```c
int main(void) {
  long int i, k = 0, j, ture = 0, s, tmp, tmps;
  char t[10];
  float n[10][4], inx, iny;
  while (1) {
    scanf(" %c", &t[k]);
    if (t[k] == '*')
      break;
    scanf("%f %f %f %f", &n[k][0], &n[k][1], &n[k][2], &n[k][3]);
    k++;
  }
  j = 0;
  while (1) {
    scanf("%f %f", &inx, &iny);
    tmp = inx * 10;
    tmps = iny * 10;
    if (tmp == 99999 && tmps == 99999)
      break;
    ture = 0;
    for (i = 0; i < k; i++) {
      if (inx > n[i][0] && inx < n[i][2]) {
        if (iny < n[i][1] && iny > n[i][3]) {
          ture = 1;
          printf("Point %ld is contained in figure %ld\n", j + 1, i + 1);
        }
      }
    }
    if (ture == 0)
      printf("Point %ld is not contained in any figure\n", j + 1);
    j++;
  }
  return 0;
}
```