ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movl   $0x0,-0x10(%rbp)
  jmp    L16
L8:
  movl   $0x0,-0xc(%rbp)
  jmp    L34
L21:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L34:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0xc(%rbp)
  jl     L21
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x10(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    %eax,-0x10(%rbp)
  jl     L8
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D25
type_infered: string
name: parse_data
arguments: label: D28
type_infered: string
name: parse_data
arguments: label: D24
type_infered: string
name: parse_data
arguments: label: D16
type_infered: string

tool: D25: Inserisci le dimensioni del lato del quadrato: 

tool: D28: %d

tool: D24: *

tool: D16: 


assistant: ```c
int main() {
  int x;
  int i, h;
  printf("Inserisci le dimensioni del lato del quadrato: ");
  scanf("%d", &x);
  for (i = 0; i < x; i++) {
    for (h = 0; h < x; h++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D31(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%r12d
  lea    D0(%rip),%rbp
  lea    D21(%rip),%r13
  cmpl   $0x0,0x4(%rsp)
  jg     L32
L51:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,0x4(%rsp)
  jg     L8
L11:
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%r12d
  cmp    %r12d,0x4(%rsp)
  jle    L51
L32:
  mov    $0x0,%ebx
  cmpl   $0x0,0x4(%rsp)
  jg     L8
  jmp    L11
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D31
datatype: string
name: disassemble_data
arguments: tag: D4
datatype: string
name: disassemble_data
arguments: tag: D0
datatype: string
name: disassemble_data
arguments: tag: D21
datatype: string

tool: D31: Inserisci le dimensioni del lato del quadrato: 

tool: D4: %d

tool: D0: *

tool: D21: 


assistant: ```c
int main() {
  int x;
  int i, h;
  printf("Inserisci le dimensioni del lato del quadrato: ");
  scanf("%d", &x);
  for (i = 0; i < x; i++) {
    for (h = 0; h < x; h++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %r13
  lea    D24(%rip),%rdi
  lea    D9(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D10(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L30
  nopl   0x0(%rax)
L0:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L18:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L18
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L0
L30:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D24
type_guessed: string
name: parse_data
arguments: data_tag: D9
type_guessed: string
name: parse_data
arguments: data_tag: D10
type_guessed: string
name: parse_data
arguments: data_tag: D5
type_guessed: string

tool: D24: Inserisci le dimensioni del lato del quadrato: 

tool: D9: 


tool: D10: *

tool: D5: %d

assistant: ```c
int main() {
  int x;
  int i, h;
  printf("Inserisci le dimensioni del lato del quadrato: ");
  scanf("%d", &x);
  for (i = 0; i < x; i++) {
    for (h = 0; h < x; h++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D29(%rip),%rdi
  lea    D19(%rip),%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D24(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L39
  nopl   0x0(%rax)
L14:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L6:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L6
  mov    %r13,%rdi
  add    $0x1,%r12d
  call   <printf@plt>
  cmp    %r12d,0x4(%rsp)
  jg     L14
L39:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D29
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D26
type: string
name: retrieve_data
arguments: data_tag: D24
type: string

tool: D29: Inserisci le dimensioni del lato del quadrato: 

tool: D19: 


tool: D26: *

tool: D24: %d

assistant: ```c
int main() {
  int x;
  int i, h;
  printf("Inserisci le dimensioni del lato del quadrato: ");
  scanf("%d", &x);
  for (i = 0; i < x; i++) {
    for (h = 0; h < x; h++) {
      printf("*");
    }
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<imatrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    -0x20(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
  shl    $0x3,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L38
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L38:
  mov    -0x18(%rbp),%rax
  shl    $0x3,%rax
  neg    %rax
  add    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L1
L4:
  mov    -0x30(%rbp),%rax
  sub    -0x28(%rbp),%rax
  add    $0x1,%rax
  shl    $0x2,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    -0x10(%rbp),%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L32
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <nrerror@plt>
L32:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x28(%rbp),%rax
  shl    $0x2,%rax
  neg    %rax
  mov    %rax,%rcx
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rsi
  mov    -0x8(%rbp),%rax
  add    %rsi,%rax
  add    %rcx,%rdx
  mov    %rdx,(%rax)
  addq   $0x1,-0x10(%rbp)
L1:
  mov    -0x10(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jle    L4
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
datatype: string
name: unpack_data
arguments: data_tag: D15
datatype: string

tool: D9: allocation failure 1 in imatrix()

tool: D15: allocation failure 2 in imatrix()

assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i;
  int **m;
  m = (int **)malloc((nrh - nrl + 1) * sizeof(int *));
  if (!m)
    nrerror("allocation failure 1 in imatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (int *)malloc((nch - ncl + 1) * sizeof(int));
    if (!m[i])
      nrerror("allocation failure 2 in imatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<imatrix>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%r14
  mov    %rdx,%r13
  mov    %rcx,%r12
  mov    %rsi,%rax
  sub    %rdi,%rax
  lea    0x8(,%rax,8),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  test   %rax,%rax
  je     L37
L26:
  lea    0x0(,%rbx,8),%rax
  sub    %rax,%rbp
  cmp    %rbx,%r14
  jl     L38
  sub    %r13,%r12
  lea    0x4(,%r12,4),%r15
  shl    $0x2,%r13
  neg    %r13
  jmp    L45
L37:
  lea    D2(%rip),%rdi
  call   <nrerror@plt>
  jmp    L26
L20:
  add    %r13,0x0(%rbp,%r12,8)
  add    $0x1,%rbx
  cmp    %rbx,%r14
  jl     L38
L45:
  mov    %r15,%rdi
  call   <malloc@plt>
  mov    %rbx,%r12
  mov    %rax,0x0(%rbp,%rbx,8)
  test   %rax,%rax
  jne    L20
  lea    D18(%rip),%rdi
  call   <nrerror@plt>
  jmp    L20
L38:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
type: string
name: retrieve_data
arguments: data_label: D18
type: string

tool: D2: allocation failure 1 in imatrix()

tool: D18: allocation failure 2 in imatrix()

assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i;
  int **m;
  m = (int **)malloc((nrh - nrl + 1) * sizeof(int *));
  if (!m)
    nrerror("allocation failure 1 in imatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (int *)malloc((nch - ncl + 1) * sizeof(int));
    if (!m[i])
      nrerror("allocation failure 2 in imatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<imatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  push   %r14
  sub    %rdi,%rax
  mov    %rdi,%r14
  push   %r13
  lea    0x8(,%rax,8),%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L35
L30:
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r14,%rbp
  jl     L21
  sub    %rbx,%r12
  shl    $0x2,%rbx
  lea    D18(%rip),%r13
  lea    0x4(,%r12,4),%r12
  neg    %rbx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L8:
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14,%rbp
  jl     L21
L10:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  jne    L8
  mov    %r13,%rdi
  call   <nrerror@plt>
  mov    (%r15,%r14,8),%rax
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14,%rbp
  jge    L10
L21:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nop
L35:
  lea    D14(%rip),%rdi
  call   <nrerror@plt>
  jmp    L30
```

tool_calls: name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D14
type_guessed: string

tool: D18: allocation failure 2 in imatrix()

tool: D14: allocation failure 1 in imatrix()

assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i;
  int **m;
  m = (int **)malloc((nrh - nrl + 1) * sizeof(int *));
  if (!m)
    nrerror("allocation failure 1 in imatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (int *)malloc((nch - ncl + 1) * sizeof(int));
    if (!m[i])
      nrerror("allocation failure 2 in imatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<imatrix>:
  endbr64
  push   %r15
  mov    %rsi,%rax
  push   %r14
  sub    %rdi,%rax
  mov    %rdi,%r14
  push   %r13
  lea    0x8(,%rax,8),%rdi
  push   %r12
  mov    %rcx,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r15
  test   %rax,%rax
  je     L67
L69:
  lea    0x0(,%r14,8),%rax
  sub    %rax,%r15
  cmp    %r14,%rbp
  jl     L28
  sub    %rbx,%r12
  shl    $0x2,%rbx
  lea    D4(%rip),%r13
  lea    0x4(,%r12,4),%r12
  neg    %rbx
  cs nopw 0x0(%rax,%rax,1)
L58:
  mov    %r12,%rdi
  call   <malloc@plt>
  mov    %rax,(%r15,%r14,8)
  test   %rax,%rax
  je     L31
  add    %rbx,%rax
  mov    %rax,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14,%rbp
  jge    L58
L28:
  add    $0x8,%rsp
  mov    %r15,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  mov    %r13,%rdi
  call   <nrerror@plt>
  add    %rbx,(%r15,%r14,8)
  add    $0x1,%r14
  cmp    %r14,%rbp
  jge    L58
  jmp    L28
  nop
L67:
  lea    D13(%rip),%rdi
  call   <nrerror@plt>
  jmp    L69
```

tool_calls: name: retrieve_data
arguments: data_label: D4
datatype: string
name: retrieve_data
arguments: data_label: D13
datatype: string

tool: D4: allocation failure 2 in imatrix()

tool: D13: allocation failure 1 in imatrix()

assistant: ```c
int **imatrix(long nrl, long nrh, long ncl, long nch) {
  long i;
  int **m;
  m = (int **)malloc((nrh - nrl + 1) * sizeof(int *));
  if (!m)
    nrerror("allocation failure 1 in imatrix()");
  m -= nrl;
  for (i = nrl; i <= nrh; i++) {
    m[i] = (int *)malloc((nch - ncl + 1) * sizeof(int));
    if (!m[i])
      nrerror("allocation failure 2 in imatrix()");
    m[i] -= ncl;
  }
  return m;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<pem_base64_decode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <pem_base64_estimate_decoded_data_len@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_new_mem_buf@plt>
  mov    %rax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <BIO_read@plt>
  mov    -0x40(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  setae  %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <BIO_free_all@plt>
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L12
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x38(%rbp),%rax
  movq   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L5
L12:
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  je     L27
  mov    -0x40(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x38(%rbp),%rax
  mov    (%rax),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,%rdx
  mov    -0x38(%rbp),%rax
  mov    %rdx,(%rax)
L27:
  mov    $0x1,%eax
L5:
  leave
  ret
```

assistant: ```c
int pem_base64_decode(const unsigned char *b64msg, size_t b64msg_len, unsigned char **binbuf, size_t *binbuf_len) {
  BIO *bio;
  BIO *b64;
  size_t allocated_len = pem_base64_estimate_decoded_data_len(b64msg, b64msg_len);
  *binbuf = (unsigned char *)malloc(allocated_len);
  bio = BIO_new_mem_buf((void *)b64msg, b64msg_len);
  b64 = BIO_new(BIO_f_base64());
  bio = BIO_push(b64, bio);
  *binbuf_len = BIO_read(bio, *binbuf, b64msg_len);
  assert(*binbuf_len <= allocated_len);
  BIO_free_all(bio);
  if (*binbuf_len <= 0) {
    free(*binbuf);
    *binbuf = NULL;
    *binbuf_len = 0;
    return 0;
  } else if (allocated_len != *binbuf_len) {
    *binbuf = (unsigned char *)realloc(*binbuf, *binbuf_len);
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<pem_base64_decode>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r14
  mov    %rsi,%rbp
  mov    %rdx,%rbx
  mov    %rcx,%r13
  call   <pem_base64_estimate_decoded_data_len@plt>
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <BIO_new_mem_buf@plt>
  mov    %rax,%r14
  mov    $0x0,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %rax,%rdi
  mov    %r14,%rsi
  call   <BIO_push@plt>
  mov    %rax,%r14
  mov    %rbp,%rdx
  mov    (%rbx),%rsi
  mov    %rax,%rdi
  call   <BIO_read@plt>
  mov    %rax,0x0(%r13)
  cmp    %r12,%rax
  setbe  %dil
  movzbl %dil,%edi
  call   <assert@plt>
  mov    %r14,%rdi
  call   <BIO_free_all@plt>
  mov    0x0(%r13),%rsi
  test   %rsi,%rsi
  je     L12
  mov    $0x1,%eax
  cmp    %r12,%rsi
  jne    L7
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  mov    (%rbx),%rdi
  call   <free@plt>
  movq   $0x0,(%rbx)
  movq   $0x0,0x0(%r13)
  mov    $0x0,%eax
  jmp    L16
L7:
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  mov    $0x1,%eax
  jmp    L16
```

assistant: ```c
int pem_base64_decode(const unsigned char *b64msg, size_t b64msg_len, unsigned char **binbuf, size_t *binbuf_len) {
  BIO *bio;
  BIO *b64;
  size_t allocated_len = pem_base64_estimate_decoded_data_len(b64msg, b64msg_len);
  *binbuf = (unsigned char *)malloc(allocated_len);
  bio = BIO_new_mem_buf((void *)b64msg, b64msg_len);
  b64 = BIO_new(BIO_f_base64());
  bio = BIO_push(b64, bio);
  *binbuf_len = BIO_read(bio, *binbuf, b64msg_len);
  assert(*binbuf_len <= allocated_len);
  BIO_free_all(bio);
  if (*binbuf_len <= 0) {
    free(*binbuf);
    *binbuf = NULL;
    *binbuf_len = 0;
    return 0;
  } else if (allocated_len != *binbuf_len) {
    *binbuf = (unsigned char *)realloc(*binbuf, *binbuf_len);
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<pem_base64_decode>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <pem_base64_estimate_decoded_data_len@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %rax,(%rbx)
  call   <BIO_new_mem_buf@plt>
  mov    %rax,%r14
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    (%rbx),%rsi
  mov    %r12,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <BIO_read@plt>
  xor    %edi,%edi
  mov    %rax,0x0(%r13)
  cmp    %rbp,%rax
  setbe  %dil
  call   <assert@plt>
  mov    %r14,%rdi
  call   <BIO_free_all@plt>
  mov    0x0(%r13),%rsi
  test   %rsi,%rsi
  je     L4
  mov    $0x1,%r12d
  cmp    %rbp,%rsi
  jne    L16
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L16:
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    (%rbx),%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  movq   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  movq   $0x0,0x0(%r13)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int pem_base64_decode(const unsigned char *b64msg, size_t b64msg_len, unsigned char **binbuf, size_t *binbuf_len) {
  BIO *bio;
  BIO *b64;
  size_t allocated_len = pem_base64_estimate_decoded_data_len(b64msg, b64msg_len);
  *binbuf = (unsigned char *)malloc(allocated_len);
  bio = BIO_new_mem_buf((void *)b64msg, b64msg_len);
  b64 = BIO_new(BIO_f_base64());
  bio = BIO_push(b64, bio);
  *binbuf_len = BIO_read(bio, *binbuf, b64msg_len);
  assert(*binbuf_len <= allocated_len);
  BIO_free_all(bio);
  if (*binbuf_len <= 0) {
    free(*binbuf);
    *binbuf = NULL;
    *binbuf_len = 0;
    return 0;
  } else if (allocated_len != *binbuf_len) {
    *binbuf = (unsigned char *)realloc(*binbuf, *binbuf_len);
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pem_base64_decode>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  mov    %rcx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <pem_base64_estimate_decoded_data_len@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %r14,%rdi
  mov    %rax,(%rbx)
  call   <BIO_new_mem_buf@plt>
  mov    %rax,%r14
  xor    %eax,%eax
  call   <BIO_f_base64@plt>
  mov    %eax,%edi
  call   <BIO_new@plt>
  mov    %r14,%rsi
  mov    %rax,%rdi
  call   <BIO_push@plt>
  mov    (%rbx),%rsi
  mov    %r12,%rdx
  mov    %rax,%rdi
  mov    %rax,%r14
  call   <BIO_read@plt>
  xor    %edi,%edi
  mov    %rax,0x0(%r13)
  cmp    %rbp,%rax
  setbe  %dil
  call   <assert@plt>
  mov    %r14,%rdi
  call   <BIO_free_all@plt>
  mov    0x0(%r13),%rsi
  test   %rsi,%rsi
  je     L15
  mov    $0x1,%r12d
  cmp    %rbp,%rsi
  jne    L1
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   (%rax)
L1:
  mov    (%rbx),%rdi
  call   <realloc@plt>
  mov    %rax,(%rbx)
  pop    %rbx
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L15:
  mov    (%rbx),%rdi
  xor    %r12d,%r12d
  call   <free@plt>
  movq   $0x0,(%rbx)
  mov    %r12d,%eax
  pop    %rbx
  movq   $0x0,0x0(%r13)
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int pem_base64_decode(const unsigned char *b64msg, size_t b64msg_len, unsigned char **binbuf, size_t *binbuf_len) {
  BIO *bio;
  BIO *b64;
  size_t allocated_len = pem_base64_estimate_decoded_data_len(b64msg, b64msg_len);
  *binbuf = (unsigned char *)malloc(allocated_len);
  bio = BIO_new_mem_buf((void *)b64msg, b64msg_len);
  b64 = BIO_new(BIO_f_base64());
  bio = BIO_push(b64, bio);
  *binbuf_len = BIO_read(bio, *binbuf, b64msg_len);
  assert(*binbuf_len <= allocated_len);
  BIO_free_all(bio);
  if (*binbuf_len <= 0) {
    free(*binbuf);
    *binbuf = NULL;
    *binbuf_len = 0;
    return 0;
  } else if (allocated_len != *binbuf_len) {
    *binbuf = (unsigned char *)realloc(*binbuf, *binbuf_len);
  }
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<poly1305aes_aix_authenticate>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  mov    %r8d,-0x44(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x38(%rbp),%rdx
  mov    -0x30(%rbp),%rcx
  lea    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <aes_aix@plt>
  mov    -0x30(%rbp),%rax
  lea    0x10(%rax),%rsi
  mov    -0x44(%rbp),%edi
  mov    -0x40(%rbp),%rcx
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <poly1305_aix@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void poly1305aes_aix_authenticate(unsigned char out[16], const unsigned char kr[32], const unsigned char n[16], const unsigned char m[], unsigned int l) {
  unsigned char aeskn[16];
  aes_aix(aeskn, (kr + 0), n);
  poly1305_aix(out, (kr + 16), aeskn, m, l);
}
```