user: 这段汇编代码用C语言表示是什么样的：

```asm
<test_hls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %rdi,-0x88(%rbp)
  mov    %rsi,-0x90(%rbp)
  mov    %rdx,-0x98(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x30(%rbp),%r8
  lea    -0x50(%rbp),%rdi
  lea    -0x70(%rbp),%rcx
  mov    -0x98(%rbp),%rdx
  mov    -0x90(%rbp),%rsi
  mov    -0x88(%rbp),%rax
  mov    %r8,%r9
  mov    %rdi,%r8
  mov    %rax,%rdi
  call   <curve25519_donna@plt>
  lea    -0x70(%rbp),%rcx
  mov    -0x88(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x50(%rbp),%rcx
  mov    -0x90(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    -0x30(%rbp),%rcx
  mov    -0x98(%rbp),%rax
  mov    $0x20,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L68
L69:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x90(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x74(%rbp)
L68:
  cmpl   $0x1f,-0x74(%rbp)
  jle    L69
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L45
L0:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x98(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x74(%rbp)
L45:
  cmpl   $0x1f,-0x74(%rbp)
  jle    L0
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x74(%rbp)
  jmp    L62
L21:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x88(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%esi
  lea    D63(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x74(%rbp)
L62:
  cmpl   $0x1f,-0x74(%rbp)
  jle    L21
  lea    D74(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L39
  call   <__stack_chk_fail@plt>
L39:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D17
type: string
name: extract_symbolic_data
arguments: tag: D21
type: string
name: extract_symbolic_data
arguments: tag: D63
type: string
name: extract_symbolic_data
arguments: tag: D41
type: string
name: extract_symbolic_data
arguments: tag: D23
type: string
name: extract_symbolic_data
arguments: tag: D74
type: string

tool: D17: HLS results:

tool: D21: e: 0x

tool: D63: %02x

tool: D41: 
k: 0x

tool: D23: 
ek: 0x

tool: D74: 


assistant: ```c
void test_hls(unsigned char *ek, unsigned char *e, unsigned char *k) {
  int i;
  unsigned char ek_out[32];
  unsigned char e_out[32];
  unsigned char k_out[32];
  printf("HLS results:\n");
  curve25519_donna(ek, e, k, ek_out, e_out, k_out);
  memcpy(ek, ek_out, 32);
  memcpy(e, e_out, 32);
  memcpy(k, k_out, 32);
  printf("e: 0x");
  for (i = 0; i < 32; ++i) {
    printf("%02x", (unsigned int)e[i]);
  }
  printf("\nk: 0x");
  for (i = 0; i < 32; ++i) {
    printf("%02x", (unsigned int)k[i]);
  }
  printf("\nek: 0x");
  for (i = 0; i < 32; ++i) {
    printf("%02x", (unsigned int)ek[i]);
  }
  printf("\n\n");
}
```