ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xa,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  addl   $0x1,-0x1c(%rbp)
  imul   -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x1c(%rbp)
  movl   $0x1,-0x10(%rbp)
  movl   $0x2,-0xc(%rbp)
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  mov    %eax,-0x10(%rbp,%rdx,4)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D42(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x18(%rbp)
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%edx
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  lea    D55(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x14(%rbp)
  movl   $0xa,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x14,-0x14(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D42
type_guessed: string
name: unpack_data
arguments: tag: D47
type_guessed: string
name: unpack_data
arguments: tag: D55
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string
name: unpack_data
arguments: tag: D14
type_guessed: string

tool: D42: %d


tool: D47: j=%d


tool: D55: j=%d j=%d


tool: D8: k=%d


tool: D14: k=%d k=%d


assistant: ```c
int main(void) {
  int i = 10;
  printf("%d\n", i++ * ++i);
  i = ++i;
  int array[] = {1, 2};
  array[i] = i++;
  printf("%d\n", array[0]);
  int j = 0;
  printf("j=%d\n", j += 1);
  printf("j=%d j=%d\n", j, j += 1);
  int k = 0;
  printf("k=%d\n", k = 10);
  printf("k=%d k=%d\n", k, k = 20);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x78,%esi
  lea    D2(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  lea    D7(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D45(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x14,%edx
  mov    $0x14,%esi
  lea    D24(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
type_infered: string
name: disassemble_data
arguments: data_tag: D46
type_infered: string
name: disassemble_data
arguments: data_tag: D7
type_infered: string
name: disassemble_data
arguments: data_tag: D45
type_infered: string
name: disassemble_data
arguments: data_tag: D24
type_infered: string

tool: D2: %d


tool: D46: j=%d


tool: D7: j=%d j=%d


tool: D45: k=%d


tool: D24: k=%d k=%d


assistant: ```c
int main(void) {
  int i = 10;
  printf("%d\n", i++ * ++i);
  i = ++i;
  int array[] = {1, 2};
  array[i] = i++;
  printf("%d\n", array[0]);
  int j = 0;
  printf("j=%d\n", j += 1);
  printf("j=%d j=%d\n", j, j += 1);
  int k = 0;
  printf("k=%d\n", k = 10);
  printf("k=%d k=%d\n", k, k = 20);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D23(%rip),%rbp
  mov    $0x78,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x14,%edx
  mov    $0x14,%esi
  xor    %eax,%eax
  lea    D32(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D23
datatype: string
name: disassemble_data
arguments: data_tag: D33
datatype: string
name: disassemble_data
arguments: data_tag: D17
datatype: string
name: disassemble_data
arguments: data_tag: D26
datatype: string
name: disassemble_data
arguments: data_tag: D32
datatype: string

tool: D23: %d


tool: D33: j=%d


tool: D17: j=%d j=%d


tool: D26: k=%d


tool: D32: k=%d k=%d


assistant: ```c
int main(void) {
  int i = 10;
  printf("%d\n", i++ * ++i);
  i = ++i;
  int array[] = {1, 2};
  array[i] = i++;
  printf("%d\n", array[0]);
  int j = 0;
  printf("j=%d\n", j += 1);
  printf("j=%d j=%d\n", j, j += 1);
  int k = 0;
  printf("k=%d\n", k = 10);
  printf("k=%d k=%d\n", k, k = 20);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D15(%rip),%rbp
  mov    $0x78,%esi
  xor    %eax,%eax
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x2,%edx
  mov    $0x2,%esi
  xor    %eax,%eax
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    $0xa,%esi
  lea    D13(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x14,%edx
  mov    $0x14,%esi
  xor    %eax,%eax
  lea    D2(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D15
type: string
name: unpack_data
arguments: data_label: D27
type: string
name: unpack_data
arguments: data_label: D21
type: string
name: unpack_data
arguments: data_label: D13
type: string
name: unpack_data
arguments: data_label: D2
type: string

tool: D15: %d


tool: D27: j=%d


tool: D21: j=%d j=%d


tool: D13: k=%d


tool: D2: k=%d k=%d


assistant: ```c
int main(void) {
  int i = 10;
  printf("%d\n", i++ * ++i);
  i = ++i;
  int array[] = {1, 2};
  array[i] = i++;
  printf("%d\n", array[0]);
  int j = 0;
  printf("j=%d\n", j += 1);
  printf("j=%d j=%d\n", j, j += 1);
  int k = 0;
  printf("k=%d\n", k = 10);
  printf("k=%d k=%d\n", k, k = 20);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<safe_pwrite>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x18(%rbp)
  jmp    L26
L20:
  mov    -0x18(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <pwrite@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L3
  mov    D22(%rip),%rax
  mov    (%rax),%edx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jne    L54
  jmp    L26
L54:
  mov    D22(%rip),%rax
  mov    (%rax),%eax
  neg    %eax
  jmp    L42
L3:
  mov    -0x4(%rbp),%eax
  cltq
  sub    %rax,-0x28(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  add    %rax,-0x20(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0x18(%rbp)
L26:
  cmpq   $0x0,-0x28(%rbp)
  jne    L20
  mov    $0x0,%eax
L42:
  leave
  ret
```

assistant: ```c
ssize_t safe_pwrite(int fd, const void *buf, size_t count, off_t offset) {
  int r;
  while (count > 0) {
    r = pwrite(fd, buf, count, offset);
    if (r < 0) {
      if (errno == EINTR)
        continue;
      return -errno;
    }
    count -= r;
    buf = (char *)buf + r;
    offset += r;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<safe_pwrite>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r13d
  mov    %rsi,%r12
  mov    %rdx,%rbx
  mov    %ecx,%ebp
  test   %rdx,%rdx
  jne    L14
  mov    $0x0,%eax
  jmp    L30
L5:
  movslq %eax,%rdx
  sub    %rdx,%rbx
  add    %rdx,%r12
  add    %eax,%ebp
L53:
  test   %rbx,%rbx
  je     L49
L14:
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r12,%rsi
  mov    %r13d,%edi
  call   <pwrite@plt>
  test   %eax,%eax
  jns    L5
  mov    D11(%rip),%rax
  mov    (%rax),%eax
  mov    D4(%rip),%rdx
  cmp    (%rdx),%eax
  je     L53
  neg    %eax
L30:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  mov    $0x0,%eax
  jmp    L30
```

assistant: ```c
ssize_t safe_pwrite(int fd, const void *buf, size_t count, off_t offset) {
  int r;
  while (count > 0) {
    r = pwrite(fd, buf, count, offset);
    if (r < 0) {
      if (errno == EINTR)
        continue;
      return -errno;
    }
    count -= r;
    buf = (char *)buf + r;
    offset += r;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<safe_pwrite>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L16
L3:
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <pwrite@plt>
  test   %eax,%eax
  js     L10
  movslq %eax,%rdx
  add    %eax,%ebp
  add    %rdx,%r13
  sub    %rdx,%rbx
  jne    L3
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L10:
  mov    D6(%rip),%rax
  mov    D15(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  je     L3
  add    $0x8,%rsp
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t safe_pwrite(int fd, const void *buf, size_t count, off_t offset) {
  int r;
  while (count > 0) {
    r = pwrite(fd, buf, count, offset);
    if (r < 0) {
      if (errno == EINTR)
        continue;
      return -errno;
    }
    count -= r;
    buf = (char *)buf + r;
    offset += r;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<safe_pwrite>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %ecx,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  je     L16
L23:
  mov    %ebp,%ecx
  mov    %rbx,%rdx
  mov    %r13,%rsi
  mov    %r12d,%edi
  call   <pwrite@plt>
  test   %eax,%eax
  js     L33
  movslq %eax,%rdx
  add    %eax,%ebp
  add    %rdx,%r13
  sub    %rdx,%rbx
  jne    L23
L16:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L33:
  mov    D11(%rip),%rax
  mov    D3(%rip),%rdx
  mov    (%rax),%eax
  cmp    (%rdx),%eax
  je     L23
  add    $0x8,%rsp
  neg    %eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
ssize_t safe_pwrite(int fd, const void *buf, size_t count, off_t offset) {
  int r;
  while (count > 0) {
    r = pwrite(fd, buf, count, offset);
    if (r < 0) {
      if (errno == EINTR)
        continue;
      return -errno;
    }
    count -= r;
    buf = (char *)buf + r;
    offset += r;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x2,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x5,-0x14(%rbp)
  movl   $0x4,-0x10(%rbp)
  lea    -0x20(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <test@plt>
  movl   $0x0,-0x24(%rbp)
  jmp    L1
L11:
  mov    -0x24(%rbp),%eax
  cltq
  mov    -0x20(%rbp,%rax,4),%edx
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x24(%rbp)
L1:
  cmpl   $0x4,-0x24(%rbp)
  jle    L11
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type_infered: string

tool: D4:  < Vet[%d] = %d

assistant: ```c
int main() {
  int vet[] = {2, 1, 3, 5, 4};
  test(vet, 0, 5);
  for (int i = 0; i < 5; i++)
    printf(" < Vet[%d] = %d", i, vet[i]);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movl   $0x2,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x3,0x8(%rsp)
  movl   $0x5,0xc(%rsp)
  movl   $0x4,0x10(%rsp)
  mov    %rsp,%rdi
  mov    $0x5,%edx
  mov    $0x0,%esi
  call   <test@plt>
  mov    $0x0,%ebx
  lea    D1(%rip),%rbp
L3:
  mov    (%rsp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x5,%rbx
  jne    L3
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D1
data_type: string

tool: D1:  < Vet[%d] = %d

assistant: ```c
int main() {
  int vet[] = {2, 1, 3, 5, 4};
  test(vet, 0, 5);
  for (int i = 0; i < 5; i++)
    printf(" < Vet[%d] = %d", i, vet[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  xor    %esi,%esi
  lea    D5(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x100000002,%rax
  mov    %rsp,%rbp
  movl   $0x4,0x10(%rsp)
  mov    %rbp,%rdi
  mov    %rax,(%rsp)
  movabs $0x500000003,%rax
  mov    %rax,0x8(%rsp)
  call   <test@plt>
L4:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L4
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D5
type_guessed: string

tool: D5:  < Vet[%d] = %d

assistant: ```c
int main() {
  int vet[] = {2, 1, 3, 5, 4};
  test(vet, 0, 5);
  for (int i = 0; i < 5; i++)
    printf(" < Vet[%d] = %d", i, vet[i]);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  xor    %esi,%esi
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  movdqa D12(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movl   $0x4,0x10(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,(%rsp)
  call   <test@plt>
L13:
  mov    0x0(%rbp,%rbx,4),%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x5,%rbx
  jne    L13
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D3
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: byte[16]

tool: D3:  < Vet[%d] = %d

tool: {"D12": [0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int vet[] = {2, 1, 3, 5, 4};
  test(vet, 0, 5);
  for (int i = 0; i < 5; i++)
    printf(" < Vet[%d] = %d", i, vet[i]);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  jmp    L29
L3:
  mov    -0x18(%rbp),%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%eax
  sub    $0x1,%eax
  mov    %eax,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L14
L5:
  addl   $0x1,-0x1c(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0xc(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%edi
  call   <print_results@plt>
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L14:
  cmpl   $0x2,-0x14(%rbp)
  jle    L5
  addl   $0x1,-0x18(%rbp)
L29:
  cmpl   $0x6,-0x18(%rbp)
  jle    L3
  mov    -0x1c(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D9
type_guessed: string
name: unpack_data
arguments: tag: D18
type_guessed: string
name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D9: dcuminabs

tool: D18: # c::%s:len=%d


tool: D8: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dcuminabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x3,%r12d
  mov    $0x1,%r14d
  lea    D25(%rip),%r15
  jmp    L30
L34:
  add    $0x1,%r14d
  add    $0x3,%r12d
  cmp    $0x15,%r12d
  je     L19
L30:
  lea    -0x3(%r12),%ebx
  mov    %r14d,%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ebp
  lea    -0x1(%r14),%esi
  mov    $0xa,%edi
  call   <pow@plt>
  mov    %eax,%ecx
  mov    $0xf4240,%eax
  cltd
  idiv   %ecx
  mov    %eax,%r13d
L14:
  add    $0x1,%ebx
  mov    %ebp,%edx
  mov    %r15,%rsi
  lea    D19(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebp,%esi
  mov    %r13d,%edi
  call   <benchmark@plt>
  mov    %r13d,%edi
  call   <print_results@plt>
  mov    %ebx,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    %r12d,%ebx
  jne    L14
  jmp    L34
L19:
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: parse_data
arguments: tag: D25
datatype: string
name: parse_data
arguments: tag: D19
datatype: string
name: parse_data
arguments: tag: D3
datatype: string

tool: D25: dcuminabs

tool: D19: # c::%s:len=%d


tool: D3: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dcuminabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %r15
  xor    %edi,%edi
  lea    D7(%rip),%r15
  push   %r14
  lea    D20(%rip),%r14
  push   %r13
  lea    D17(%rip),%r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
  movl   $0x3,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  nopl   0x0(%rax)
L1:
  mov    0xc(%rsp),%ebp
  mov    0x8(%rsp),%eax
  mov    $0xa,%edi
  mov    %ebp,%esi
  lea    -0x3(%rax),%r12d
  call   <pow@plt>
  lea    -0x1(%rbp),%esi
  mov    $0xa,%edi
  mov    %eax,%ebx
  call   <pow@plt>
  mov    %eax,%r8d
  mov    $0xf4240,%eax
  cltd
  idiv   %r8d
  mov    %eax,%ebp
L18:
  mov    %ebx,%edx
  mov    %r15,%rsi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%esi
  mov    %ebp,%edi
  add    $0x1,%r12d
  call   <benchmark@plt>
  mov    %ebp,%edi
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %r12d,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  cmp    0x8(%rsp),%r12d
  jne    L18
  lea    0x3(%r12),%eax
  addl   $0x1,0xc(%rsp)
  mov    %eax,0x8(%rsp)
  cmp    $0x12,%r12d
  jne    L1
  mov    $0x12,%esi
  mov    $0x12,%edi
  call   <print_summary@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type: string
name: read_data
arguments: data_tag: D20
type: string
name: read_data
arguments: data_tag: D17
type: string

tool: D7: dcuminabs

tool: D20: # c::%s:len=%d


tool: D17: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int count;
  int iter;
  int len;
  int i;
  int j;
  srand(time(NULL));
  print_version();
  count = 0;
  for (i = 1; i <= 6; i++) {
    len = pow(10, i);
    iter = 1000000 / pow(10, i - 1);
    for (j = 0; j < 3; j++) {
      count += 1;
      printf("# c::%s:len=%d\n", "dcuminabs", len);
      elapsed = benchmark(iter, len);
      print_results(iter, elapsed);
      printf("ok %d benchmark finished\n", count);
    }
  }
  print_summary(count, count);
}
```