ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strcasecmp>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  movsbl (%rdi),%edi
  test   %dil,%dil
  jne    L14
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L15:
  movsbl 0x1(%rbp),%edi
  add    $0x1,%rbp
  add    $0x1,%r12
  test   %dil,%dil
  je     L45
L14:
  call   <toupper@plt>
  movsbl (%r12),%edi
  mov    %eax,%ebx
  call   <toupper@plt>
  cmp    %eax,%ebx
  je     L15
L46:
  movsbl (%r12),%edi
  call   <toupper@plt>
  mov    %eax,%r8d
  mov    %ebx,%eax
  pop    %rbx
  pop    %rbp
  sub    %r8d,%eax
  pop    %r12
  ret
  nopl   (%rax)
L45:
  xor    %edi,%edi
  call   <toupper@plt>
  mov    %eax,%ebx
  jmp    L46
```

assistant: ```c
int strcasecmp(const char *s1, const char *s2) {
  const char *p, *q;
  p = s1;
  q = s2;
  while (*p && toupper((int)*p) == toupper((int)*q)) {
    p++, q++;
  }
  return (toupper((int)*p) - toupper((int)*q));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<v4l2_capture>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <open_camera@plt>
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <init_camera@plt>
  lea    D76(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <start_capturing@plt>
  lea    D51(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <init_photo@plt>
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <get_and_save_photo@plt>
  lea    D54(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <stop_capturing@plt>
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <uninit_camera@plt>
  lea    D38(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <close_camera@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D36
type: string
name: parse_data
arguments: data_tag: D76
type: string
name: parse_data
arguments: data_tag: D51
type: string
name: parse_data
arguments: data_tag: D18
type: string
name: parse_data
arguments: data_tag: D54
type: string
name: parse_data
arguments: data_tag: D39
type: string
name: parse_data
arguments: data_tag: D38
type: string
name: parse_data
arguments: data_tag: D7
type: string

tool: D36: open_camera 


tool: D76: init_camera 


tool: D51: start_capturing 


tool: D18: init_photo 


tool: D54: get_and_save_photo 


tool: D39: stop_capturing 


tool: D38: uninit_camera 


tool: D7: close_camera 


assistant: ```c
void v4l2_capture(struct camera *cam) {
  open_camera(cam);
  printf("open_camera \n");
  init_camera(cam);
  printf("init_camera \n");
  start_capturing(cam);
  printf("start_capturing \n");
  init_photo();
  printf("init_photo \n");
  get_and_save_photo(cam);
  printf("get_and_save_photo \n");
  stop_capturing(cam);
  printf("stop_capturing \n");
  uninit_camera(cam);
  printf("uninit_camera \n");
  close_camera(cam);
  printf("close_camera \n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<v4l2_capture>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <open_camera@plt>
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <init_camera@plt>
  lea    D77(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <start_capturing@plt>
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  call   <init_photo@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <get_and_save_photo@plt>
  lea    D11(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <stop_capturing@plt>
  lea    D47(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <uninit_camera@plt>
  lea    D31(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <close_camera@plt>
  lea    D59(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D23
type_guessed: string
name: disassemble_data
arguments: data_label: D77
type_guessed: string
name: disassemble_data
arguments: data_label: D24
type_guessed: string
name: disassemble_data
arguments: data_label: D18
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string
name: disassemble_data
arguments: data_label: D47
type_guessed: string
name: disassemble_data
arguments: data_label: D31
type_guessed: string
name: disassemble_data
arguments: data_label: D59
type_guessed: string

tool: D23: open_camera 


tool: D77: init_camera 


tool: D24: start_capturing 


tool: D18: init_photo 


tool: D11: get_and_save_photo 


tool: D47: stop_capturing 


tool: D31: uninit_camera 


tool: D59: close_camera 


assistant: ```c
void v4l2_capture(struct camera *cam) {
  open_camera(cam);
  printf("open_camera \n");
  init_camera(cam);
  printf("init_camera \n");
  start_capturing(cam);
  printf("start_capturing \n");
  init_photo();
  printf("init_photo \n");
  get_and_save_photo(cam);
  printf("get_and_save_photo \n");
  stop_capturing(cam);
  printf("stop_capturing \n");
  uninit_camera(cam);
  printf("uninit_camera \n");
  close_camera(cam);
  printf("close_camera \n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<v4l2_capture>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <open_camera@plt>
  lea    D56(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <init_camera@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <start_capturing@plt>
  lea    D45(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <init_photo@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <get_and_save_photo@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stop_capturing@plt>
  lea    D72(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <uninit_camera@plt>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <close_camera@plt>
  lea    D59(%rip),%rdi
  pop    %rbp
  jmp    1100 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D56
type_infered: string
name: disassemble_data
arguments: tag: D48
type_infered: string
name: disassemble_data
arguments: tag: D45
type_infered: string
name: disassemble_data
arguments: tag: D58
type_infered: string
name: disassemble_data
arguments: tag: D1
type_infered: string
name: disassemble_data
arguments: tag: D72
type_infered: string
name: disassemble_data
arguments: tag: D10
type_infered: string
name: disassemble_data
arguments: tag: D59
type_infered: string

tool: D56: open_camera 


tool: D48: init_camera 


tool: D45: start_capturing 


tool: D58: init_photo 


tool: D1: get_and_save_photo 


tool: D72: stop_capturing 


tool: D10: uninit_camera 


tool: D59: close_camera 


assistant: ```c
void v4l2_capture(struct camera *cam) {
  open_camera(cam);
  printf("open_camera \n");
  init_camera(cam);
  printf("init_camera \n");
  start_capturing(cam);
  printf("start_capturing \n");
  init_photo();
  printf("init_photo \n");
  get_and_save_photo(cam);
  printf("get_and_save_photo \n");
  stop_capturing(cam);
  printf("stop_capturing \n");
  uninit_camera(cam);
  printf("uninit_camera \n");
  close_camera(cam);
  printf("close_camera \n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<v4l2_capture>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  call   <open_camera@plt>
  lea    D61(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <init_camera@plt>
  lea    D58(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <start_capturing@plt>
  lea    D21(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <init_photo@plt>
  lea    D15(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <get_and_save_photo@plt>
  lea    D13(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <stop_capturing@plt>
  lea    D37(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <uninit_camera@plt>
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <close_camera@plt>
  lea    D54(%rip),%rdi
  pop    %rbp
  jmp    1100 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D61
type_infered: string
name: read_data
arguments: data_tag: D58
type_infered: string
name: read_data
arguments: data_tag: D21
type_infered: string
name: read_data
arguments: data_tag: D15
type_infered: string
name: read_data
arguments: data_tag: D13
type_infered: string
name: read_data
arguments: data_tag: D37
type_infered: string
name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D54
type_infered: string

tool: D61: open_camera 


tool: D58: init_camera 


tool: D21: start_capturing 


tool: D15: init_photo 


tool: D13: get_and_save_photo 


tool: D37: stop_capturing 


tool: D1: uninit_camera 


tool: D54: close_camera 


assistant: ```c
void v4l2_capture(struct camera *cam) {
  open_camera(cam);
  printf("open_camera \n");
  init_camera(cam);
  printf("init_camera \n");
  start_capturing(cam);
  printf("start_capturing \n");
  init_photo();
  printf("init_photo \n");
  get_and_save_photo(cam);
  printf("get_and_save_photo \n");
  stop_capturing(cam);
  printf("stop_capturing \n");
  uninit_camera(cam);
  printf("uninit_camera \n");
  close_camera(cam);
  printf("close_camera \n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xa0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x90(%rbp)
  movl   $0x1,-0x8c(%rbp)
  movl   $0x1,-0x88(%rbp)
  movl   $0x1,-0x84(%rbp)
  movl   $0x1,-0x80(%rbp)
  movl   $0x1,-0x7c(%rbp)
  movl   $0x1,-0x78(%rbp)
  movl   $0x0,-0x74(%rbp)
  movl   $0x1,-0x70(%rbp)
  movl   $0x1,-0x6c(%rbp)
  movl   $0x1,-0x68(%rbp)
  movl   $0x1,-0x64(%rbp)
  movl   $0x1,-0x60(%rbp)
  movl   $0x1,-0x5c(%rbp)
  movl   $0x1,-0x58(%rbp)
  movl   $0x1,-0x50(%rbp)
  movl   $0x1,-0x4c(%rbp)
  movl   $0x0,-0x48(%rbp)
  movl   $0x1,-0x44(%rbp)
  movl   $0x1,-0x40(%rbp)
  movl   $0x0,-0x3c(%rbp)
  movl   $0x0,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  movl   $0x0,-0x30(%rbp)
  movl   $0x0,-0x2c(%rbp)
  movl   $0x1,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x1,-0x18(%rbp)
  lea    -0x90(%rbp),%rax
  mov    $0x5,%edx
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <mark@plt>
  movl   $0x0,-0x94(%rbp)
  jmp    L24
L26:
  lea    -0x50(%rbp),%rcx
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rax,%rcx
  lea    -0x90(%rbp),%rsi
  mov    -0x94(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  shl    $0x2,%rax
  add    %rsi,%rax
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <assert@plt>
  addl   $0x1,-0x94(%rbp)
L24:
  cmpl   $0x2,-0x94(%rbp)
  jle    L26
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L14
  call   <__stack_chk_fail@plt>
L14:
  leave
  ret
```

assistant: ```c
int main() {
  int matrix[3][5] = {{1, 1, 1, 1, 1}, {1, 1, 0, 1, 1}, {1, 1, 1, 1, 1}};
  int expected[3][5] = {{1, 1, 0, 1, 1}, {0, 0, 0, 0, 0}, {1, 1, 0, 1, 1}};
  mark(matrix, 3, 5);
  for (int i = 0; i < 3; i++) {
    assert(memcmp(matrix[i], expected[i], 5) == 0);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  movl   $0x1,0x8(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0x1,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x1,0x18(%rsp)
  movl   $0x0,0x1c(%rsp)
  movl   $0x1,0x20(%rsp)
  movl   $0x1,0x24(%rsp)
  movl   $0x1,0x28(%rsp)
  movl   $0x1,0x2c(%rsp)
  movl   $0x1,0x30(%rsp)
  movl   $0x1,0x34(%rsp)
  movl   $0x1,0x38(%rsp)
  movl   $0x1,0x40(%rsp)
  movl   $0x1,0x44(%rsp)
  movl   $0x0,0x48(%rsp)
  movl   $0x1,0x4c(%rsp)
  movl   $0x1,0x50(%rsp)
  movl   $0x0,0x54(%rsp)
  movl   $0x0,0x58(%rsp)
  movl   $0x0,0x5c(%rsp)
  movl   $0x0,0x60(%rsp)
  movl   $0x0,0x64(%rsp)
  movl   $0x1,0x68(%rsp)
  movl   $0x1,0x6c(%rsp)
  movl   $0x0,0x70(%rsp)
  movl   $0x1,0x74(%rsp)
  movl   $0x1,0x78(%rsp)
  mov    %rsp,%rbx
  mov    $0x5,%edx
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <mark@plt>
  lea    0x40(%rsp),%rbp
  lea    0x3c(%rsp),%r12
L18:
  mov    $0x5,%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %rax,%rax
  sete   %dil
  movzbl %dil,%edi
  call   <assert@plt>
  add    $0x14,%rbx
  add    $0x14,%rbp
  cmp    %r12,%rbx
  jne    L18
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  mov    $0x0,%eax
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int matrix[3][5] = {{1, 1, 1, 1, 1}, {1, 1, 0, 1, 1}, {1, 1, 1, 1, 1}};
  int expected[3][5] = {{1, 1, 0, 1, 1}, {0, 0, 0, 0, 0}, {1, 1, 0, 1, 1}};
  mark(matrix, 3, 5);
  for (int i = 0; i < 3; i++) {
    assert(memcmp(matrix[i], expected[i], 5) == 0);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x3,%esi
  movabs $0x100000000,%rdx
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%rbx
  mov    %rdx,0x48(%rsp)
  lea    0x40(%rsp),%rbp
  mov    %rdx,0x70(%rsp)
  mov    %rbx,%rdi
  mov    $0x5,%edx
  lea    0x3c(%rsp),%r12
  movq   $0x1,0x18(%rsp)
  movl   $0x1,0x38(%rsp)
  movq   $0x1,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  mov    %rax,(%rsp)
  mov    %rax,0x8(%rsp)
  mov    %rax,0x10(%rsp)
  mov    %rax,0x20(%rsp)
  mov    %rax,0x28(%rsp)
  mov    %rax,0x30(%rsp)
  mov    %rax,0x40(%rsp)
  movq   $0x0,0x60(%rsp)
  mov    %rax,0x68(%rsp)
  movl   $0x1,0x78(%rsp)
  call   <mark@plt>
L0:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x5,%edx
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x14,%rbx
  add    $0x14,%rbp
  call   <assert@plt>
  cmp    %r12,%rbx
  jne    L0
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L13
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L13:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  int matrix[3][5] = {{1, 1, 1, 1, 1}, {1, 1, 0, 1, 1}, {1, 1, 1, 1, 1}};
  int expected[3][5] = {{1, 1, 0, 1, 1}, {0, 0, 0, 0, 0}, {1, 1, 0, 1, 1}};
  mark(matrix, 3, 5);
  for (int i = 0; i < 3; i++) {
    assert(memcmp(matrix[i], expected[i], 5) == 0);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r12
  mov    $0x5,%edx
  mov    $0x3,%esi
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  movdqa D50(%rip),%xmm0
  movdqa D68(%rip),%xmm1
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  lea    0x40(%rsp),%rbp
  lea    0x3c(%rsp),%r12
  movaps %xmm0,(%rsp)
  mov    D50(%rip),%rax
  mov    %rbx,%rdi
  movaps %xmm0,0x20(%rsp)
  movdqa D35(%rip),%xmm0
  mov    %rax,0x30(%rsp)
  mov    D57(%rip),%rax
  movaps %xmm0,0x40(%rsp)
  movdqa D6(%rip),%xmm0
  movl   $0x1,0x38(%rsp)
  movaps %xmm0,0x50(%rsp)
  movdqa D60(%rip),%xmm0
  mov    %rax,0x70(%rsp)
  movl   $0x1,0x78(%rsp)
  movaps %xmm1,0x10(%rsp)
  movaps %xmm0,0x60(%rsp)
  call   <mark@plt>
L1:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  mov    $0x5,%edx
  call   <memcmp@plt>
  xor    %edi,%edi
  test   %rax,%rax
  sete   %dil
  add    $0x14,%rbx
  add    $0x14,%rbp
  call   <assert@plt>
  cmp    %rbx,%r12
  jne    L1
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x90,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D50
data_type: byte[16]
name: parse_data
arguments: label: D68
data_type: byte[16]
name: parse_data
arguments: label: D35
data_type: byte[16]
name: parse_data
arguments: label: D57
data_type: byte[8]
name: parse_data
arguments: label: D6
data_type: byte[16]
name: parse_data
arguments: label: D60
data_type: byte[16]

tool: {"D50": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D68": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D35": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D57": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: {"D6": [0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D60": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int matrix[3][5] = {{1, 1, 1, 1, 1}, {1, 1, 0, 1, 1}, {1, 1, 1, 1, 1}};
  int expected[3][5] = {{1, 1, 0, 1, 1}, {0, 0, 0, 0, 0}, {1, 1, 0, 1, 1}};
  mark(matrix, 3, 5);
  for (int i = 0; i < 3; i++) {
    assert(memcmp(matrix[i], expected[i], 5) == 0);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x4(%rbp)
  jmp    L13
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L4
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  addl   $0x1,-0x4(%rbp)
L13:
  cmpl   $0x63,-0x4(%rbp)
  jle    L18
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type: string

tool: D3: %d 

assistant: ```c
main() {
  int n;
  for (n = 2; n < 100; ++n) {
    if (isprime(n)) {
      printf("%d ", n);
    }
  }
  printf("\n");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x2,%ebx
  lea    D5(%rip),%rbp
  jmp    L11
L26:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L17
L11:
  mov    %ebx,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L26
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L26
L17:
  mov    $0xa,%edi
  call   <putchar@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: %d 

assistant: ```c
main() {
  int n;
  for (n = 2; n < 100; ++n) {
    if (isprime(n)) {
      printf("%d ", n);
    }
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L36:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L14
L17:
  mov    %ebx,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L36
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x64,%ebx
  jne    L17
L14:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
datatype: string

tool: D8: %d 

assistant: ```c
main() {
  int n;
  for (n = 2; n < 100; ++n) {
    if (isprime(n)) {
      printf("%d ", n);
    }
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  push   %rbx
  mov    $0x2,%ebx
  sub    $0x8,%rsp
  jmp    L39
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%ebx
  cmp    $0x64,%ebx
  je     L26
L39:
  mov    %ebx,%edi
  call   <isprime@plt>
  test   %rax,%rax
  je     L8
  mov    %ebx,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0x64,%ebx
  jne    L39
L26:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D8
type_guessed: string

tool: D8: %d 

assistant: ```c
main() {
  int n;
  for (n = 2; n < 100; ++n) {
    if (isprime(n)) {
      printf("%d ", n);
    }
  }
  printf("\n");
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<num_to_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %esi,-0x48(%rbp)
  mov    %rdx,-0x50(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x21,%edx
  mov    $0x30,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movb   $0x0,-0x10(%rbp)
  movl   $0x1f,-0x34(%rbp)
L30:
  mov    -0x44(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x48(%rbp)
  mov    %edx,%eax
  mov    %al,-0x35(%rbp)
  cmpb   $0x9,-0x35(%rbp)
  jle    L17
  movzbl -0x35(%rbp),%eax
  add    $0x37,%eax
  mov    %al,-0x35(%rbp)
  jmp    L19
L17:
  movzbl -0x35(%rbp),%eax
  add    $0x30,%eax
  mov    %al,-0x35(%rbp)
L19:
  mov    -0x34(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x34(%rbp)
  mov    %eax,%edx
  movzbl -0x35(%rbp),%eax
  mov    %al,-0x30(%rbp,%rdx,1)
  mov    -0x44(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x48(%rbp)
  mov    %eax,-0x44(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jne    L30
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <remove_zeros@plt>
  lea    -0x30(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L29
  call   <__stack_chk_fail@plt>
L29:
  leave
  ret
```

assistant: ```c
void num_to_str(unsigned int n, unsigned int base, char *output) {
  char buf[33];
  memset(buf, '0', sizeof(buf));
  *(buf + 32) = '\0';
  unsigned int ind = 31;
  do {
    char c = n % base;
    if (c > 9) {
      c = c - 10 + 'A';
    } else {
      c = c + '0';
    }
    buf[ind--] = c;
    n = n / base;
  } while (n > 0);
  remove_zeros(buf);
  strcpy(output, buf);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<num_to_str>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x30,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x21,%edx
  mov    $0x30,%esi
  call   <memset@plt>
  movb   $0x0,0x20(%rsp)
  mov    $0x1f,%ecx
  jmp    L24
L16:
  mov    %esi,%ecx
  mov    %eax,%ebx
L24:
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %ebp
  lea    0x37(%rdx),%esi
  lea    0x30(%rdx),%eax
  cmp    $0xa,%dl
  cmovge %esi,%eax
  lea    -0x1(%rcx),%esi
  mov    %ecx,%ecx
  mov    %al,(%rsp,%rcx,1)
  mov    %ebx,%eax
  mov    $0x0,%edx
  div    %ebp
  cmp    %ebp,%ebx
  jae    L16
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <remove_zeros@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x30,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void num_to_str(unsigned int n, unsigned int base, char *output) {
  char buf[33];
  memset(buf, '0', sizeof(buf));
  *(buf + 32) = '\0';
  unsigned int ind = 31;
  do {
    char c = n % base;
    if (c > 9) {
      c = c - 10 + 'A';
    } else {
      c = c + '0';
    }
    buf[ind--] = c;
    n = n / base;
  } while (n > 0);
  remove_zeros(buf);
  strcpy(output, buf);
}
```