ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<o_crdy>:
  endbr64
  test   %esi,%esi
  je     L23
  jle    L10
  add    $0x10004,%edi
  shl    $0x4,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rdx
  and    $0x1e0,%edx
  mov    $0x0,%eax
L14:
  cmp    $0x1e0,%rdx
  jne    L13
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L14
  mov    $0x0,%eax
  ret
L23:
  add    $0x10004,%edi
  shl    $0x4,%edi
  movslq %edi,%rax
  mov    (%rax),%rax
  and    $0x1e0,%eax
L46:
  cmp    $0x1e0,%rax
  je     L46
  mov    $0x1,%eax
  ret
L10:
  mov    $0x0,%eax
  ret
L13:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int o_crdy(int channel, int tries) {
  int i;
  if (tries) {
    for (i = 0; i < tries; i++)
      if ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) != 0x1e0)
        return (1);
    return (0);
  } else {
    while ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) == 0x1e0)
      ;
    return (1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<o_crdy>:
  endbr64
  test   %esi,%esi
  je     L40
  jle    L3
  add    $0x10004,%edi
  xor    %eax,%eax
  shl    $0x4,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rdx
  and    $0x1e0,%edx
  cmp    $0x1e0,%rdx
  jne    L45
  nopw   0x0(%rax,%rax,1)
L21:
  add    $0x1,%eax
  cmp    %eax,%esi
  jne    L21
L3:
  xor    %eax,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  add    $0x10004,%edi
  shl    $0x4,%edi
  movslq %edi,%rax
  mov    (%rax),%rax
  and    $0x1e0,%eax
  cmp    $0x1e0,%rax
  je     L9
L45:
  mov    $0x1,%eax
  ret
L9:
  jmp    L9
```

assistant: ```c
int o_crdy(int channel, int tries) {
  int i;
  if (tries) {
    for (i = 0; i < tries; i++)
      if ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) != 0x1e0)
        return (1);
    return (0);
  } else {
    while ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) == 0x1e0)
      ;
    return (1);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<o_crdy>:
  endbr64
  test   %esi,%esi
  je     L31
  jle    L16
  add    $0x10004,%edi
  shl    $0x4,%edi
  movslq %edi,%rdi
  mov    (%rdi),%rax
  and    $0x1e0,%eax
  cmp    $0x1e0,%rax
  setne  %al
  movzbl %al,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x10004,%edi
  shl    $0x4,%edi
  movslq %edi,%rax
  mov    (%rax),%rax
  and    $0x1e0,%eax
  cmp    $0x1e0,%rax
  jne    L20
L4:
  jmp    L4
  xchg   %ax,%ax
L20:
  mov    $0x1,%eax
  ret
L16:
  xor    %eax,%eax
  ret
```

assistant: ```c
int o_crdy(int channel, int tries) {
  int i;
  if (tries) {
    for (i = 0; i < tries; i++)
      if ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) != 0x1e0)
        return (1);
    return (0);
  } else {
    while ((*(unsigned long *)(0x100040 + (channel * 0x10)) & 0x1e0) == 0x1e0)
      ;
    return (1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x2,-0x14(%rbp)
  je     L17
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  jmp    L4
L17:
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x122,%edi
  call   <syscall@plt>
  mov    $0x0,%eax
L4:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
data_type: string

tool: D4: Pass Process ID as command line argument


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Pass Process ID as command line argument\n");
    return 0;
  }
  long pid = atol(argv[1]);
  syscall(290, pid);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L0
  lea    D4(%rip),%rdi
  call   <printf@plt>
L11:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L0:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    %rax,%rsi
  mov    $0x122,%edi
  call   <syscall@plt>
  jmp    L11
```

tool_calls: name: parse_data
arguments: tag: D4
type_infered: string

tool: D4: Pass Process ID as command line argument


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Pass Process ID as command line argument\n");
    return 0;
  }
  long pid = atol(argv[1]);
  syscall(290, pid);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L14
  lea    D9(%rip),%rdi
  call   <printf@plt>
L12:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L14:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    $0x122,%edi
  mov    %rax,%rsi
  call   <syscall@plt>
  jmp    L12
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string

tool: D9: Pass Process ID as command line argument


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Pass Process ID as command line argument\n");
    return 0;
  }
  long pid = atol(argv[1]);
  syscall(290, pid);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x2,%edi
  je     L3
  lea    D6(%rip),%rdi
  call   <printf@plt>
L18:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L3:
  mov    0x8(%rsi),%rdi
  call   <atol@plt>
  mov    $0x122,%edi
  mov    %rax,%rsi
  call   <syscall@plt>
  jmp    L18
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: Pass Process ID as command line argument


assistant: ```c
int main(int argc, char *argv[]) {
  if (argc != 2) {
    printf("Pass Process ID as command line argument\n");
    return 0;
  }
  long pid = atol(argv[1]);
  syscall(290, pid);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<snappend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xc8(%rbp)
  mov    %rsi,-0xd0(%rbp)
  mov    %rdx,-0xd8(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L2
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L2:
  mov    -0xc8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc0(%rbp)
  mov    -0xc0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc8(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0xb8(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xbc(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc0(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xd0(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,%rsi
  mov    -0xbc(%rbp),%ecx
  mov    -0xd8(%rbp),%rdx
  mov    -0xb8(%rbp),%rax
  mov    %rax,%rdi
  call   <vsnprintf@plt>
  mov    -0xbc(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  nop
  leave
  ret
```

assistant: ```c
void snappend(char *str, size_t size, const char *fmt, ...) {
  va_list args;
  int len = strlen(str);
  char *cp = &str[len];
  va_start(args, fmt);
  vsnprintf(cp, size - len, fmt, args);
  va_end(args);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<snappend>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <strlen@plt>
  movslq %eax,%r13
  add    %r13,%rbx
  mov    %r12,%rsi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <va_start@plt>
  mov    %rbp,%rsi
  sub    %r13,%rsi
  mov    %r14d,%ecx
  mov    %r12,%rdx
  mov    %rbx,%rdi
  call   <vsnprintf@plt>
  mov    %r14d,%edi
  call   <va_end@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void snappend(char *str, size_t size, const char *fmt, ...) {
  va_list args;
  int len = strlen(str);
  char *cp = &str[len];
  va_start(args, fmt);
  vsnprintf(cp, size - len, fmt, args);
  va_end(args);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<snappend>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r15d,%edi
  movslq %eax,%r14
  call   <va_start@plt>
  add    %r14,%rbp
  mov    %r12,%rsi
  mov    %r15d,%ecx
  sub    %r14,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r15d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void snappend(char *str, size_t size, const char *fmt, ...) {
  va_list args;
  int len = strlen(str);
  char *cp = &str[len];
  va_start(args, fmt);
  vsnprintf(cp, size - len, fmt, args);
  va_end(args);
}
```
user: What is the c source code of the assembly code below:

```asm
<snappend>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <strlen@plt>
  mov    %r13,%rsi
  mov    %r15d,%edi
  movslq %eax,%r14
  call   <va_start@plt>
  add    %r14,%rbp
  mov    %r12,%rsi
  mov    %r15d,%ecx
  sub    %r14,%rsi
  mov    %r13,%rdx
  mov    %rbp,%rdi
  call   <vsnprintf@plt>
  mov    %r15d,%edi
  call   <va_end@plt>
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void snappend(char *str, size_t size, const char *fmt, ...) {
  va_list args;
  int len = strlen(str);
  char *cp = &str[len];
  va_start(args, fmt);
  vsnprintf(cp, size - len, fmt, args);
  va_end(args);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<jr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,%rsi
  mov    $0x4,%edi
  call   <searchcond@plt>
  shl    $0x3,%eax
  add    $0x20,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x10(%rbp),%rcx
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rsi
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <relbranch@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
int jr(int code, char *label, char *mnemo, char *oper) {
  char *operand2;
  code = 0x20 + (searchcond(4, oper, &operand2) << 3);
  return relbranch(code, label, mnemo, operand2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<jr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rcx,%rsi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  mov    $0x4,%edi
  call   <searchcond@plt>
  lea    0x20(,%rax,8),%edi
  mov    (%rsp),%rcx
  mov    %rbp,%rdx
  mov    %rbx,%rsi
  call   <relbranch@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int jr(int code, char *label, char *mnemo, char *oper) {
  char *operand2;
  code = 0x20 + (searchcond(4, oper, &operand2) << 3);
  return relbranch(code, label, mnemo, operand2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<jr>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rcx,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <searchcond@plt>
  mov    (%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    0x20(,%rax,8),%edi
  call   <relbranch@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int jr(int code, char *label, char *mnemo, char *oper) {
  char *operand2;
  code = 0x20 + (searchcond(4, oper, &operand2) << 3);
  return relbranch(code, label, mnemo, operand2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<jr>:
  endbr64
  push   %r12
  mov    $0x4,%edi
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rcx,%rsi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdx
  call   <searchcond@plt>
  mov    (%rsp),%rcx
  mov    %r12,%rdx
  mov    %rbp,%rsi
  lea    0x20(,%rax,8),%edi
  call   <relbranch@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int jr(int code, char *label, char *mnemo, char *oper) {
  char *operand2;
  code = 0x20 + (searchcond(4, oper, &operand2) << 3);
  return relbranch(code, label, mnemo, operand2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<memory_study_next_id>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D11(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D17(%rip)
  mov    D17(%rip),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long memory_study_next_id() {
  ;
  static unsigned long long id = 0;
  id++;
  return id;
}
```
user: What is the c source code of the assembly code below:

```asm
<memory_study_next_id>:
  endbr64
  mov    D8(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D9(%rip)
  ret
```

assistant: ```c
unsigned long memory_study_next_id() {
  ;
  static unsigned long long id = 0;
  id++;
  return id;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memory_study_next_id>:
  endbr64
  mov    D16(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D9(%rip)
  ret
```

assistant: ```c
unsigned long memory_study_next_id() {
  ;
  static unsigned long long id = 0;
  id++;
  return id;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<memory_study_next_id>:
  endbr64
  mov    D4(%rip),%rax
  add    $0x1,%rax
  mov    %rax,D15(%rip)
  ret
```

assistant: ```c
unsigned long memory_study_next_id() {
  ;
  static unsigned long long id = 0;
  id++;
  return id;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CompressAnimationTypes>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  movzwl -0x4(%rbp),%eax
  sub    $0x29,%eax
  cmp    $0x4b,%eax
  ja     L85
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D13(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D13(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x2e,%eax
  jmp    L109
  mov    $0x2e,%eax
  jmp    L109
  mov    $0x2e,%eax
  jmp    L109
  mov    $0x59,%eax
  jmp    L109
  mov    $0x59,%eax
  jmp    L109
  mov    $0x6b,%eax
  jmp    L109
  mov    $0x6b,%eax
  jmp    L109
  mov    $0x6b,%eax
  jmp    L109
  mov    $0x73,%eax
  jmp    L109
  mov    $0x73,%eax
  jmp    L109
L85:
  movzwl -0x4(%rbp),%eax
L109:
  pop    %rbp
  ret
```

assistant: ```c
unsigned short CompressAnimationTypes(unsigned short animationType_id) {
  switch (animationType_id) {
  case 41:
    return 46;
  case 48:
    return 46;
  case 49:
    return 46;
  case 88:
    return 89;
  case 90:
    return 89;
  case 103:
    return 107;
  case 109:
    return 107;
  case 110:
    return 107;
  case 114:
    return 115;
  case 116:
    return 115;
  default:
    return animationType_id;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<CompressAnimationTypes>:
  endbr64
  lea    -0x29(%rdi),%eax
  cmp    $0x4b,%ax
  ja     L5
  movzwl %ax,%eax
  lea    D8(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x59,%eax
  ret
  mov    $0x6b,%eax
  ret
  mov    $0x6b,%eax
  ret
  mov    $0x6b,%eax
  ret
  mov    $0x73,%eax
  ret
  mov    $0x73,%eax
  ret
L5:
  mov    %edi,%eax
  ret
  mov    $0x2e,%eax
  ret
```

assistant: ```c
unsigned short CompressAnimationTypes(unsigned short animationType_id) {
  switch (animationType_id) {
  case 41:
    return 46;
  case 48:
    return 46;
  case 49:
    return 46;
  case 88:
    return 89;
  case 90:
    return 89;
  case 103:
    return 107;
  case 109:
    return 107;
  case 110:
    return 107;
  case 114:
    return 115;
  case 116:
    return 115;
  default:
    return animationType_id;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<CompressAnimationTypes>:
  endbr64
  mov    %edi,%eax
  cmp    $0x74,%di
  ja     L25
  cmp    $0x57,%di
  jbe    L4
  lea    -0x58(%rdi),%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x608000,%edx
  jne    L28
  test   $0x5,%dl
  jne    L6
  test   $0x14000000,%edx
  mov    $0x73,%edx
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L6:
  mov    $0x59,%eax
L25:
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  cmp    $0x29,%di
  je     L13
  sub    $0x30,%edi
  mov    $0x2e,%edx
  cmp    $0x1,%di
  cmovbe %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    $0x2e,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L28:
  mov    $0x6b,%eax
  ret
```

assistant: ```c
unsigned short CompressAnimationTypes(unsigned short animationType_id) {
  switch (animationType_id) {
  case 41:
    return 46;
  case 48:
    return 46;
  case 49:
    return 46;
  case 88:
    return 89;
  case 90:
    return 89;
  case 103:
    return 107;
  case 109:
    return 107;
  case 110:
    return 107;
  case 114:
    return 115;
  case 116:
    return 115;
  default:
    return animationType_id;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<CompressAnimationTypes>:
  endbr64
  mov    %edi,%eax
  cmp    $0x74,%di
  ja     L37
  cmp    $0x57,%di
  jbe    L8
  lea    -0x58(%rdi),%ecx
  mov    $0x1,%edx
  shl    %cl,%rdx
  test   $0x608000,%edx
  jne    L25
  test   $0x5,%dl
  jne    L13
  test   $0x14000000,%edx
  mov    $0x73,%edx
  cmovne %edx,%eax
  ret
  nopl   0x0(%rax)
L13:
  mov    $0x59,%eax
L37:
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  cmp    $0x29,%di
  je     L5
  sub    $0x30,%edi
  mov    $0x2e,%edx
  cmp    $0x1,%di
  cmovbe %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x2e,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  mov    $0x6b,%eax
  ret
```

assistant: ```c
unsigned short CompressAnimationTypes(unsigned short animationType_id) {
  switch (animationType_id) {
  case 41:
    return 46;
  case 48:
    return 46;
  case 49:
    return 46;
  case 88:
    return 89;
  case 90:
    return 89;
  case 103:
    return 107;
  case 109:
    return 107;
  case 110:
    return 107;
  case 114:
    return 115;
  case 116:
    return 115;
  default:
    return animationType_id;
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,-0x18(%rbp)
  cmpl   $0x2,-0x24(%rbp)
  je     L15
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
  jmp    L6
L15:
  mov    -0x30(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <createOutFilename_orDie@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <compress_orDie@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%eax
L6:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
type: string
name: disassemble_data
arguments: data_tag: D12
type: string
name: disassemble_data
arguments: data_tag: D6
type: string

tool: D24: wrong arguments

tool: D12: usage:

tool: D6: %s FILE


assistant: ```c
int main(int argc, const char **argv) {
  const char *const exeName = argv[0];
  if (argc != 2) {
    printf("wrong arguments\n");
    printf("usage:\n");
    printf("%s FILE\n", exeName);
    return 1;
  }
  const char *const inFilename = argv[1];
  char *const outFilename = createOutFilename_orDie(inFilename);
  compress_orDie(inFilename, outFilename);
  free(outFilename);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%rbx
  cmp    $0x2,%edi
  je     L19
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D22(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D26(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L5:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L19:
  mov    0x8(%rsi),%rbp
  mov    %rbp,%rdi
  call   <createOutFilename_orDie@plt>
  mov    %rax,%rbx
  mov    %rax,%rsi
  mov    %rbp,%rdi
  call   <compress_orDie@plt>
  mov    %rbx,%rdi
  call   <free@plt>
  mov    $0x0,%eax
  jmp    L5
```

tool_calls: name: retrieve_data
arguments: data_tag: D17
datatype: string
name: retrieve_data
arguments: data_tag: D22
datatype: string
name: retrieve_data
arguments: data_tag: D26
datatype: string

tool: D17: wrong arguments

tool: D22: usage:

tool: D26: %s FILE


assistant: ```c
int main(int argc, const char **argv) {
  const char *const exeName = argv[0];
  if (argc != 2) {
    printf("wrong arguments\n");
    printf("usage:\n");
    printf("%s FILE\n", exeName);
    return 1;
  }
  const char *const inFilename = argv[1];
  char *const outFilename = createOutFilename_orDie(inFilename);
  compress_orDie(inFilename, outFilename);
  free(outFilename);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  cmp    $0x2,%edi
  je     L17
  lea    D17(%rip),%rdi
  call   <puts@plt>
  lea    D3(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L15:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L17:
  mov    0x8(%rsi),%r12
  mov    %r12,%rdi
  call   <createOutFilename_orDie@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <compress_orDie@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  jmp    L15
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D17
data_type: string
name: extract_symbolic_data
arguments: data_label: D3
data_type: string
name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D17: wrong arguments

tool: D3: usage:

tool: D8: %s FILE


assistant: ```c
int main(int argc, const char **argv) {
  const char *const exeName = argv[0];
  if (argc != 2) {
    printf("wrong arguments\n");
    printf("usage:\n");
    printf("%s FILE\n", exeName);
    return 1;
  }
  const char *const inFilename = argv[1];
  char *const outFilename = createOutFilename_orDie(inFilename);
  compress_orDie(inFilename, outFilename);
  free(outFilename);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x8,%rsp
  mov    (%rsi),%rbp
  cmp    $0x2,%edi
  je     L9
  lea    D21(%rip),%rdi
  call   <puts@plt>
  lea    D16(%rip),%rdi
  call   <puts@plt>
  mov    %rbp,%rsi
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x1,%eax
L14:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L9:
  mov    0x8(%rsi),%r12
  mov    %r12,%rdi
  call   <createOutFilename_orDie@plt>
  mov    %r12,%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <compress_orDie@plt>
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %eax,%eax
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D21
type_guessed: string
name: retrieve_data
arguments: tag: D16
type_guessed: string
name: retrieve_data
arguments: tag: D5
type_guessed: string

tool: D21: wrong arguments

tool: D16: usage:

tool: D5: %s FILE


assistant: ```c
int main(int argc, const char **argv) {
  const char *const exeName = argv[0];
  if (argc != 2) {
    printf("wrong arguments\n");
    printf("usage:\n");
    printf("%s FILE\n", exeName);
    return 1;
  }
  const char *const inFilename = argv[1];
  char *const outFilename = createOutFilename_orDie(inFilename);
  compress_orDie(inFilename, outFilename);
  free(outFilename);
  return 0;
}
```