ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <high_freq@plt>
  xor    %eax,%eax
  call   <continue_dynamically@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  int i, j, k;
  unsigned long long sum = 0;
  high_freq();
  for (i = 0; i < 10000000; i++) {
    sum += i;
  }
  continue_dynamically();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%edx
  mov    -0x20(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x4(%rbp)
  mov    D3(%rip),%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  ioctl(fd, CDROMEJECT);
  close(fd);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  mov    0x8(%rsi),%rdi
  mov    D12(%rip),%rax
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebx
  mov    D16(%rip),%rax
  mov    (%rax),%esi
  mov    %ebx,%edi
  call   <ioctl@plt>
  mov    %ebx,%edi
  call   <close@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  ioctl(fd, CDROMEJECT);
  close(fd);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  mov    D15(%rip),%rax
  push   %rbp
  mov    0x8(%rsi),%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  mov    D6(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  ioctl(fd, CDROMEJECT);
  close(fd);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  mov    D2(%rip),%rax
  push   %rbp
  mov    0x8(%rsi),%rdi
  mov    (%rax),%esi
  call   <open@plt>
  mov    %eax,%ebp
  mov    D4(%rip),%rax
  mov    %ebp,%edi
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    %ebp,%edi
  call   <close@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  int fd = open(argv[1], O_RDONLY);
  ioctl(fd, CDROMEJECT);
  close(fd);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<writeall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L6
L11:
  mov    -0x28(%rbp),%rax
  sub    -0x8(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x20(%rbp),%rax
  add    %rax,%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <write@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jns    L16
  mov    $0xffffffff,%eax
  jmp    L34
L16:
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,-0x8(%rbp)
L6:
  mov    -0x8(%rbp),%rax
  cmp    -0x28(%rbp),%rax
  jl     L11
  mov    -0x8(%rbp),%rax
L34:
  leave
  ret
```

assistant: ```c
int32_t writeall(int sock, uint8_t *buff, uint32_t leng) {
  uint32_t bsent;
  int res;
  bsent = 0;
  while (bsent < leng) {
    res = write(sock, buff + bsent, leng - bsent);
    if (res < 0) {
      return -1;
    }
    bsent += res;
  }
  return bsent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<writeall>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdx,%rdx
  jle    L39
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %rdx,%rbp
  mov    $0x0,%ebx
L13:
  mov    %rbp,%rdx
  sub    %rbx,%rdx
  lea    0x0(%r13,%rbx,4),%rsi
  mov    %r12d,%edi
  call   <write@plt>
  test   %eax,%eax
  js     L48
  cltq
  add    %rax,%rbx
  cmp    %rbx,%rbp
  jg     L13
L40:
  mov    %ebx,%eax
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  mov    $0x0,%ebx
  jmp    L40
L48:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int32_t writeall(int sock, uint8_t *buff, uint32_t leng) {
  uint32_t bsent;
  int res;
  bsent = 0;
  while (bsent < leng) {
    res = write(sock, buff + bsent, leng - bsent);
    if (res < 0) {
      return -1;
    }
    bsent += res;
  }
  return bsent;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<writeall>:
  endbr64
  test   %rdx,%rdx
  jle    L31
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L20
L6:
  cltq
  add    %rax,%r13
  cmp    %r13,%rbx
  jle    L32
L20:
  mov    %rbx,%rdx
  lea    (%r12,%r13,4),%rsi
  mov    %ebp,%edi
  sub    %r13,%rdx
  call   <write@plt>
  test   %eax,%eax
  jns    L6
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L32:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L31:
  xor    %eax,%eax
  ret
```

assistant: ```c
int32_t writeall(int sock, uint8_t *buff, uint32_t leng) {
  uint32_t bsent;
  int res;
  bsent = 0;
  while (bsent < leng) {
    res = write(sock, buff + bsent, leng - bsent);
    if (res < 0) {
      return -1;
    }
    bsent += res;
  }
  return bsent;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<writeall>:
  endbr64
  test   %rdx,%rdx
  jle    L11
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x8,%rsp
  jmp    L36
L34:
  cltq
  add    %rax,%r13
  cmp    %r13,%rbx
  jle    L31
L36:
  mov    %rbx,%rdx
  lea    (%r12,%r13,4),%rsi
  mov    %ebp,%edi
  sub    %r13,%rdx
  call   <write@plt>
  test   %eax,%eax
  jns    L34
  add    $0x8,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L31:
  add    $0x8,%rsp
  mov    %r13d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  xor    %eax,%eax
  ret
```

assistant: ```c
int32_t writeall(int sock, uint8_t *buff, uint32_t leng) {
  uint32_t bsent;
  int res;
  bsent = 0;
  while (bsent < leng) {
    res = write(sock, buff + bsent, leng - bsent);
    if (res < 0) {
      return -1;
    }
    bsent += res;
  }
  return bsent;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
L9:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L9
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: %04x


assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  srand(time(NULL));
  for (;;) {
    r = rand();
    printf("%04x\r\n", r);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  lea    D8(%rip),%rbx
L4:
  mov    $0x0,%eax
  call   <rand@plt>
  mov    %eax,%esi
  mov    %rbx,%rdi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type: string

tool: D8: %04x


assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  srand(time(NULL));
  for (;;) {
    r = rand();
    printf("%04x\r\n", r);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  lea    D4(%rip),%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L6
```

tool_calls: name: read_data
arguments: label: D4
type: string

tool: D4: %04x


assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  srand(time(NULL));
  for (;;) {
    r = rand();
    printf("%04x\r\n", r);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  lea    D2(%rip),%rbx
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  nopw   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  call   <rand@plt>
  mov    %rbx,%rdi
  mov    %eax,%esi
  call   <printf@plt>
  jmp    L4
```

tool_calls: name: read_data
arguments: data_label: D2
type: string

tool: D2: %04x


assistant: ```c
int main(int argc, char *argv[]) {
  int r;
  srand(time(NULL));
  for (;;) {
    r = rand();
    printf("%04x\r\n", r);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  jne    L6
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <quit@plt>
L6:
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L17
  call   <__stack_chk_fail@plt>
L17:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D0
type_infered: string

tool: D0: fstat() failed

assistant: ```c
size_t file_size(int fd) {
  struct stat s;
  if (fstat(fd, &s) == -1)
    quit("fstat() failed");
  return s.st_size;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L7
L19:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L22
  add    $0x18,%rsp
  ret
L7:
  lea    D9(%rip),%rdi
  call   <quit@plt>
  jmp    L19
L22:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D9
data_type: string

tool: D9: fstat() failed

assistant: ```c
size_t file_size(int fd) {
  struct stat s;
  if (fstat(fd, &s) == -1)
    quit("fstat() failed");
  return s.st_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L17
L3:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L28
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L17:
  lea    D4(%rip),%rdi
  call   <quit@plt>
  jmp    L3
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D4
data_type: string

tool: D4: fstat() failed

assistant: ```c
size_t file_size(int fd) {
  struct stat s;
  if (fstat(fd, &s) == -1)
    quit("fstat() failed");
  return s.st_size;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  call   <fstat@plt>
  cmp    $0xffffffff,%eax
  je     L24
L20:
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x18,%rsp
  ret
  xchg   %ax,%ax
L24:
  lea    D0(%rip),%rdi
  call   <quit@plt>
  jmp    L20
L16:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string

tool: D0: fstat() failed

assistant: ```c
size_t file_size(int fd) {
  struct stat s;
  if (fstat(fd, &s) == -1)
    quit("fstat() failed");
  return s.st_size;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_header>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L56
L68:
  cmpl   $0x9,-0x4(%rbp)
  jle    L4
  cmpl   $0xfffffff7,-0x4(%rbp)
  jl     L61
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L46
L61:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L46:
  addl   $0x1,-0x4(%rbp)
L56:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L68
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L21
L15:
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L21:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L15
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D26
type: string
name: disassemble_data
arguments: label: D2
type: string
name: disassemble_data
arguments: label: D12
type: string
name: disassemble_data
arguments: label: D31
type: string
name: disassemble_data
arguments: label: D44
type: string

tool: D26: 
ROW/COL |

tool: D2:   %d   

tool: D12:   %d  

tool: D31: 
---------

tool: D44: ------

assistant: ```c
void print_header(int cols) {
  int i;
  printf("\nROW/COL |");
  for (i = 0; i < cols; ++i) {
    if (i < 10 || i > -10)
      printf("  %d   ", i);
    else
      printf("  %d  ", i);
  }
  printf("\n---------");
  for (i = 0; i < cols; ++i) {
    printf("------");
  }
  printf("\n");
  return;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<print_header>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r12d
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L35
  mov    $0x0,%ebx
  lea    D42(%rip),%r13
L37:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L37
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D45(%rip),%r12
L31:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L31
L11:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  lea    D37(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L11
```

tool_calls: name: read_data
arguments: data_label: D27
type: string
name: read_data
arguments: data_label: D42
type: string
name: read_data
arguments: data_label: D37
type: string
name: read_data
arguments: data_label: D45
type: string

tool: D27: 
ROW/COL |

tool: D42:   %d   

tool: D37: 
---------

tool: D45: ------

assistant: ```c
void print_header(int cols) {
  int i;
  printf("\nROW/COL |");
  for (i = 0; i < cols; ++i) {
    if (i < 10 || i > -10)
      printf("  %d   ", i);
    else
      printf("  %d  ", i);
  }
  printf("\n---------");
  for (i = 0; i < cols; ++i) {
    printf("------");
  }
  printf("\n");
  return;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_header>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %edi,%r12d
  lea    D4(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L25
  xor    %ebx,%ebx
  lea    D49(%rip),%r13
  nopl   (%rax)
L0:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <printf@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r12d
  jne    L0
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  lea    D37(%rip),%r12
  nopl   (%rax)
L31:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L31
L14:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L25:
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L14
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string
name: retrieve_data
arguments: tag: D49
type: string
name: retrieve_data
arguments: tag: D26
type: string
name: retrieve_data
arguments: tag: D37
type: string

tool: D4: 
ROW/COL |

tool: D49:   %d   

tool: D26: 
---------

tool: D37: ------

assistant: ```c
void print_header(int cols) {
  int i;
  printf("\nROW/COL |");
  for (i = 0; i < cols; ++i) {
    if (i < 10 || i > -10)
      printf("  %d   ", i);
    else
      printf("  %d  ", i);
  }
  printf("\n---------");
  for (i = 0; i < cols; ++i) {
    printf("------");
  }
  printf("\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_header>:
  endbr64
  push   %r13
  xor    %eax,%eax
  push   %r12
  mov    %edi,%r12d
  lea    D26(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %r12d,%r12d
  jle    L31
  xor    %ebx,%ebx
  lea    D3(%rip),%r13
  nopl   (%rax)
L16:
  mov    %ebx,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  mov    %ebx,%ebp
  call   <printf@plt>
  lea    0x1(%rbx),%ebx
  cmp    %ebx,%r12d
  jne    L16
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  xor    %ebx,%ebx
  call   <printf@plt>
  lea    D4(%rip),%r12
  nopl   (%rax)
L32:
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %ebx,%eax
  add    $0x1,%ebx
  cmp    %eax,%ebp
  jne    L32
L0:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <putchar@plt>
  nopw   0x0(%rax,%rax,1)
L31:
  lea    D33(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: label: D26
type_infered: string
name: disassemble_data
arguments: label: D3
type_infered: string
name: disassemble_data
arguments: label: D33
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D26: 
ROW/COL |

tool: D3:   %d   

tool: D33: 
---------

tool: D4: ------

assistant: ```c
void print_header(int cols) {
  int i;
  printf("\nROW/COL |");
  for (i = 0; i < cols; ++i) {
    if (i < 10 || i > -10)
      printf("  %d   ", i);
    else
      printf("  %d  ", i);
  }
  printf("\n---------");
  for (i = 0; i < cols; ++i) {
    printf("------");
  }
  printf("\n");
  return;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<xoroshiro_jump>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L10
L13:
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L19:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  movslq %eax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,%ecx
  shr    %cl,%rdx
  mov    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  je     L36
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  xor    %eax,-0x10(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  xor    %eax,-0xc(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <xoroshiro_next@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  cmpl   $0x3f,-0x4(%rbp)
  jle    L19
  addl   $0x1,-0x8(%rbp)
L10:
  cmpl   $0x1,-0x8(%rbp)
  jle    L13
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    -0xc(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  leave
  ret
```

assistant: ```c
void xoroshiro_jump(uint64_t s[2]) {
  static const uint64_t JUMP[] = {0xbeac0467eba5facb, 0xd86b048b86aa9922};
  uint64_t s0 = 0;
  uint64_t s1 = 0;
  int i, b;
  for (i = 0; i < (int)(sizeof JUMP / sizeof *JUMP); i++)
    for (b = 0; b < 64; b++) {
      if (JUMP[i] & 1ULL << b) {
        s0 ^= s[0];
        s1 ^= s[1];
      }
      xoroshiro_next(s);
    }
  s[0] = s0;
  s[1] = s1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xoroshiro_jump>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  lea    D4(%rip),%r12
  lea    0x8(%r12),%r15
  mov    $0x0,%r13d
  mov    $0x0,%r14d
  jmp    L55
L25:
  mov    %rbp,%rdi
  call   <xoroshiro_next@plt>
  add    $0x1,%ebx
  cmp    $0x40,%ebx
  je     L6
L26:
  movslq (%r12),%rax
  bt     %rbx,%rax
  jae    L25
  xor    0x0(%rbp),%r14d
  xor    0x4(%rbp),%r13d
  jmp    L25
L6:
  add    $0x4,%r12
  cmp    %r12,%r15
  je     L13
L55:
  mov    $0x0,%ebx
  jmp    L26
L13:
  mov    %r14d,0x0(%rbp)
  mov    %r13d,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xoroshiro_jump(uint64_t s[2]) {
  static const uint64_t JUMP[] = {0xbeac0467eba5facb, 0xd86b048b86aa9922};
  uint64_t s0 = 0;
  uint64_t s1 = 0;
  int i, b;
  for (i = 0; i < (int)(sizeof JUMP / sizeof *JUMP); i++)
    for (b = 0; b < 64; b++) {
      if (JUMP[i] & 1ULL << b) {
        s0 ^= s[0];
        s1 ^= s[1];
      }
      xoroshiro_next(s);
    }
  s[0] = s0;
  s[1] = s1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xoroshiro_jump>:
  endbr64
  push   %r14
  mov    $0xffffffffeba5facb,%r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  mov    %rdi,%rbx
  xchg   %ax,%ax
L17:
  bt     %rbp,%r14
  jae    L15
  xor    (%rbx),%r13d
  xor    0x4(%rbx),%r12d
L15:
  mov    %rbx,%rdi
  add    $0x1,%ebp
  call   <xoroshiro_next@plt>
  cmp    $0x40,%ebp
  jne    L17
  xor    %ebp,%ebp
  mov    $0xffffffff86aa9922,%r14
  cs nopw 0x0(%rax,%rax,1)
L24:
  bt     %rbp,%r14
  jae    L21
  xor    (%rbx),%r13d
  xor    0x4(%rbx),%r12d
L21:
  mov    %rbx,%rdi
  add    $0x1,%ebp
  call   <xoroshiro_next@plt>
  cmp    $0x40,%ebp
  jne    L24
  mov    %r13d,(%rbx)
  mov    %r12d,0x4(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void xoroshiro_jump(uint64_t s[2]) {
  static const uint64_t JUMP[] = {0xbeac0467eba5facb, 0xd86b048b86aa9922};
  uint64_t s0 = 0;
  uint64_t s1 = 0;
  int i, b;
  for (i = 0; i < (int)(sizeof JUMP / sizeof *JUMP); i++)
    for (b = 0; b < 64; b++) {
      if (JUMP[i] & 1ULL << b) {
        s0 ^= s[0];
        s1 ^= s[1];
      }
      xoroshiro_next(s);
    }
  s[0] = s0;
  s[1] = s1;
}
```
user: What is the c source code of the assembly code below:

```asm
<xoroshiro_jump>:
  endbr64
  push   %r15
  mov    $0x2,%r15d
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    $0xffffffffeba5facb,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
L1:
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L21:
  bt     %rbx,%r12
  jae    L2
  xor    0x0(%rbp),%r14d
  xor    0x4(%rbp),%r13d
L2:
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <xoroshiro_next@plt>
  cmp    $0x40,%ebx
  jne    L21
  mov    $0xffffffff86aa9922,%r12
  cmp    $0x1,%r15d
  je     L20
  mov    $0x1,%r15d
  jmp    L1
L20:
  mov    %r14d,0x0(%rbp)
  mov    %r13d,0x4(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void xoroshiro_jump(uint64_t s[2]) {
  static const uint64_t JUMP[] = {0xbeac0467eba5facb, 0xd86b048b86aa9922};
  uint64_t s0 = 0;
  uint64_t s1 = 0;
  int i, b;
  for (i = 0; i < (int)(sizeof JUMP / sizeof *JUMP); i++)
    for (b = 0; b < 64; b++) {
      if (JUMP[i] & 1ULL << b) {
        s0 ^= s[0];
        s1 ^= s[1];
      }
      xoroshiro_next(s);
    }
  s[0] = s0;
  s[1] = s1;
}
```