ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<get_rtc_year>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7e005040,%eax
  mov    (%rax),%eax
  mov    $0x7e005040,%edx
  or     $0x8,%eax
  mov    %eax,(%rdx)
  mov    $0x7e005040,%eax
  movl   $0x1,(%rax)
  mov    $0x7e005088,%eax
  mov    (%rax),%eax
  mov    %al,-0x5(%rbp)
  movzbl -0x5(%rbp),%eax
  sar    $0x4,%al
  movsbl %al,%eax
  and    $0xf,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  movsbl -0x5(%rbp),%eax
  and    $0xf,%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x7e005040,%eax
  movl   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_rtc_year(void) {
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  char value = (*(volatile unsigned int *)(0x7E005088));
  int year = ((value >> 4) & 0xF) * 10 + (value & 0xF);
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return year;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<get_rtc_year>:
  endbr64
  mov    0x7e005040,%eax
  or     $0x8,%eax
  mov    %eax,0x7e005040
  movl   $0x1,0x7e005040
  mov    0x7e005088,%eax
  movl   $0x0,0x7e005040
  mov    %eax,%edx
  shr    $0x4,%dl
  movsbl %dl,%edx
  lea    (%rdx,%rdx,4),%edx
  and    $0xf,%eax
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int get_rtc_year(void) {
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  char value = (*(volatile unsigned int *)(0x7E005088));
  int year = ((value >> 4) & 0xF) * 10 + (value & 0xF);
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return year;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<get_rtc_year>:
  endbr64
  mov    0x7e005040,%eax
  or     $0x8,%eax
  mov    %eax,0x7e005040
  movl   $0x1,0x7e005040
  mov    0x7e005088,%eax
  movl   $0x0,0x7e005040
  mov    %eax,%edx
  and    $0xf,%eax
  shr    $0x4,%dl
  movzbl %dl,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int get_rtc_year(void) {
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  char value = (*(volatile unsigned int *)(0x7E005088));
  int year = ((value >> 4) & 0xF) * 10 + (value & 0xF);
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return year;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_rtc_year>:
  endbr64
  mov    0x7e005040,%eax
  or     $0x8,%eax
  mov    %eax,0x7e005040
  movl   $0x1,0x7e005040
  mov    0x7e005088,%eax
  movl   $0x0,0x7e005040
  mov    %eax,%edx
  and    $0xf,%eax
  shr    $0x4,%dl
  movzbl %dl,%edx
  lea    (%rdx,%rdx,4),%edx
  lea    (%rax,%rdx,2),%eax
  ret
```

assistant: ```c
int get_rtc_year(void) {
  (*(volatile unsigned int *)(0x7E005040)) |= (1 << 3);
  (*(volatile unsigned int *)(0x7E005040)) = 1;
  char value = (*(volatile unsigned int *)(0x7E005088));
  int year = ((value >> 4) & 0xF) * 10 + (value & 0xF);
  (*(volatile unsigned int *)(0x7E005040)) = 0;
  return year;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<roll_n_dice>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x1,-0x18(%rbp)
  jg     L35
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%eax
  jmp    L47
L35:
  cmpl   $0x0,-0x14(%rbp)
  jg     L6
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L47
L6:
  movl   $0x0,-0x8(%rbp)
  jmp    L33
L59:
  mov    -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <rollem@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L59
  mov    -0x4(%rbp),%eax
L47:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D11
type_guessed: string
name: disassemble_data
arguments: tag: D19
type_guessed: string

tool: D11: Need at least 2 sides.


tool: D19: Need at least 1 die.


assistant: ```c
int roll_n_dice(int dice, int sides) {
  int d;
  int total = 0;
  if (sides < 2) {
    printf("Need at least 2 sides.\n");
    return -2;
  }
  if (dice < 1) {
    printf("Need at least 1 die.\n");
    return -1;
  }
  for (d = 0; d < dice; d++)
    total += rollem(sides);
  return total;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<roll_n_dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L39
  mov    %edi,%r12d
  mov    %esi,%r13d
  test   %edi,%edi
  jle    L49
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L24:
  mov    %r13d,%edi
  call   <rollem@plt>
  add    %eax,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r12d
  jne    L24
L43:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L39:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0xfffffffe,%ebp
  jmp    L43
L49:
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%ebp
  jmp    L43
```

tool_calls: name: disassemble_data
arguments: data_label: D0
type_infered: string
name: disassemble_data
arguments: data_label: D10
type_infered: string

tool: D0: Need at least 2 sides.


tool: D10: Need at least 1 die.


assistant: ```c
int roll_n_dice(int dice, int sides) {
  int d;
  int total = 0;
  if (sides < 2) {
    printf("Need at least 2 sides.\n");
    return -2;
  }
  if (dice < 1) {
    printf("Need at least 1 die.\n");
    return -1;
  }
  for (d = 0; d < dice; d++)
    total += rollem(sides);
  return total;
}
```
user: What is the c source code of the assembly code below?

```asm
<roll_n_dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L12
  mov    %edi,%ebp
  test   %edi,%edi
  jle    L10
  mov    %esi,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L33:
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <rollem@plt>
  add    %eax,%r12d
  cmp    %ebx,%ebp
  jne    L33
L15:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L12:
  lea    D4(%rip),%rdi
  mov    $0xfffffffe,%r12d
  call   <printf@plt>
  jmp    L15
L10:
  lea    D12(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L15
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type_guessed: string
name: retrieve_data
arguments: data_tag: D12
type_guessed: string

tool: D4: Need at least 2 sides.


tool: D12: Need at least 1 die.


assistant: ```c
int roll_n_dice(int dice, int sides) {
  int d;
  int total = 0;
  if (sides < 2) {
    printf("Need at least 2 sides.\n");
    return -2;
  }
  if (dice < 1) {
    printf("Need at least 1 die.\n");
    return -1;
  }
  for (d = 0; d < dice; d++)
    total += rollem(sides);
  return total;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<roll_n_dice>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x1,%esi
  jle    L28
  mov    %edi,%ebp
  test   %edi,%edi
  jle    L49
  mov    %esi,%r13d
  xor    %r12d,%r12d
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L44:
  mov    %r13d,%edi
  add    $0x1,%ebx
  call   <rollem@plt>
  add    %eax,%r12d
  cmp    %ebx,%ebp
  jne    L44
L33:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L28:
  lea    D2(%rip),%rdi
  mov    $0xfffffffe,%r12d
  call   <printf@plt>
  jmp    L33
L49:
  lea    D18(%rip),%rdi
  mov    $0xffffffff,%r12d
  call   <printf@plt>
  jmp    L33
```

tool_calls: name: retrieve_data
arguments: label: D2
data_type: string
name: retrieve_data
arguments: label: D18
data_type: string

tool: D2: Need at least 2 sides.


tool: D18: Need at least 1 die.


assistant: ```c
int roll_n_dice(int dice, int sides) {
  int d;
  int total = 0;
  if (sides < 2) {
    printf("Need at least 2 sides.\n");
    return -2;
  }
  if (dice < 1) {
    printf("Need at least 1 die.\n");
    return -1;
  }
  for (d = 0; d < dice; d++)
    total += rollem(sides);
  return total;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strmap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  je     L35
  cmpq   $0x0,-0x30(%rbp)
  jne    L0
L35:
  mov    $0x0,%eax
  jmp    L55
L0:
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,-0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L27
  mov    $0x0,%eax
  jmp    L55
L30:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  mov    %al,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L27:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L30
  mov    -0x18(%rbp),%rax
L55:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  int i;
  char *ret;
  if (!s || !f)
    return (0);
  i = 0;
  ret = ft_strnew(ft_strlen(s));
  if (!ret)
    return (0);
  while (s[i]) {
    ret[i] = f(s[i]);
    ++i;
  }
  return (ret);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ft_strmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L48
  mov    %rdi,%rbx
  mov    %rsi,%r12
  test   %rsi,%rsi
  je     L48
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L28
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L28
  mov    %rax,%rbp
  add    $0x1,%rbx
L3:
  movsbl %dil,%edi
  call   *%r12
  mov    %al,0x0(%rbp)
  movzbl (%rbx),%edi
  add    $0x1,%rbp
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L3
L28:
  mov    %r13,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L48:
  mov    $0x0,%r13d
  jmp    L28
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  int i;
  char *ret;
  if (!s || !f)
    return (0);
  i = 0;
  ret = ft_strnew(ft_strlen(s));
  if (!ret)
    return (0);
  while (s[i]) {
    ret[i] = f(s[i]);
    ++i;
  }
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_strmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L33
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L33
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L33
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L19
  mov    %rax,%r13
  add    $0x1,%rbx
  nopl   0x0(%rax)
L44:
  call   *%rbp
  add    $0x1,%r13
  add    $0x1,%rbx
  mov    %al,-0x1(%r13)
  movsbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L44
L19:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L33:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  int i;
  char *ret;
  if (!s || !f)
    return (0);
  i = 0;
  ret = ft_strnew(ft_strlen(s));
  if (!ret)
    return (0);
  while (s[i]) {
    ret[i] = f(s[i]);
    ++i;
  }
  return (ret);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strmap>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  test   %rdi,%rdi
  je     L1
  mov    %rsi,%rbp
  test   %rsi,%rsi
  je     L1
  mov    %rdi,%rbx
  call   <ft_strlen@plt>
  mov    %eax,%edi
  call   <ft_strnew@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L1
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L5
  mov    %rax,%r13
  add    $0x1,%rbx
  nopl   0x0(%rax)
L17:
  call   *%rbp
  add    $0x1,%r13
  add    $0x1,%rbx
  mov    %al,-0x1(%r13)
  movsbl -0x1(%rbx),%edi
  test   %dil,%dil
  jne    L17
L5:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L1:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *ft_strmap(const char *s, char (*f)(char)) {
  int i;
  char *ret;
  if (!s || !f)
    return (0);
  i = 0;
  ret = ft_strnew(ft_strlen(s));
  if (!ret)
    return (0);
  while (s[i]) {
    ret[i] = f(s[i]);
    ++i;
  }
  return (ret);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sort2@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sort2@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <sort2@plt>
  nop
  leave
  ret
```

assistant: ```c
void sort3(int *x, int *y, int *z) {
  sort2(x, z);
  sort2(x, y);
  sort2(y, z);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<sort3>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%rbx
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <sort2@plt>
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <sort2@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <sort2@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void sort3(int *x, int *y, int *z) {
  sort2(x, z);
  sort2(x, y);
  sort2(y, z);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sort3>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  call   <sort2@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <sort2@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <sort2@plt>
```

assistant: ```c
void sort3(int *x, int *y, int *z) {
  sort2(x, z);
  sort2(x, y);
  sort2(y, z);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sort3>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rsi,%rbp
  mov    %rdx,%rsi
  call   <sort2@plt>
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <sort2@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1050 <sort2@plt>
```

assistant: ```c
void sort3(int *x, int *y, int *z) {
  sort2(x, z);
  sort2(x, y);
  sort2(y, z);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<formated_system_datetime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xb0,%rsp
  mov    %rdi,-0xa8(%rbp)
  mov    %rsi,-0xb0(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <local_time@plt>
  mov    %rax,-0x98(%rbp)
  mov    -0x98(%rbp),%rcx
  mov    -0xb0(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    $0x80,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x90(%rbp),%rdx
  mov    -0xa8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
extern void formated_system_datetime(char *ret, const char *format) {
  struct tm *t_st;
  char buf[128];
  t_st = local_time();
  strftime(buf, sizeof(buf), format, t_st);
  strcpy(ret, buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<formated_system_datetime>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x90,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  call   <local_time@plt>
  mov    %rax,%rcx
  mov    %rsp,%r12
  mov    %rbp,%rdx
  mov    $0x80,%esi
  mov    %r12,%rdi
  call   <strftime@plt>
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <strcpy@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x90,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void formated_system_datetime(char *ret, const char *format) {
  struct tm *t_st;
  char buf[128];
  t_st = local_time();
  strftime(buf, sizeof(buf), format, t_st);
  strcpy(ret, buf);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<formated_system_datetime>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <local_time@plt>
  mov    $0x80,%esi
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x90,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void formated_system_datetime(char *ret, const char *format) {
  struct tm *t_st;
  char buf[128];
  t_st = local_time();
  strftime(buf, sizeof(buf), format, t_st);
  strcpy(ret, buf);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<formated_system_datetime>:
  endbr64
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x90,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x88(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  call   <local_time@plt>
  mov    $0x80,%esi
  mov    %r13,%rdi
  mov    %r12,%rdx
  mov    %rax,%rcx
  call   <strftime@plt>
  mov    %r13,%rsi
  mov    %rbp,%rdi
  call   <strcpy@plt>
  mov    0x88(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x90,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
extern void formated_system_datetime(char *ret, const char *format) {
  struct tm *t_st;
  char buf[128];
  t_st = local_time();
  strftime(buf, sizeof(buf), format, t_st);
  strcpy(ret, buf);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<mystrstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  jmp    L42
L40:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  jmp    L70
L23:
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L70:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L33
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L23
L33:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L77
  mov    -0x8(%rbp),%rax
  jmp    L34
L77:
  addq   $0x1,-0x20(%rbp)
L42:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L40
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
char *mystrstr(char *hay, char *needle) {
  char *h = hay;
  char *n = needle;
  char *h1 = (char *)malloc(sizeof(char *));
  char *n1 = (char *)malloc(sizeof(char *));
  while (*h != '\0') {
    h1 = h;
    n1 = n;
    while (*h1 != '\0' && *n1 != '\0' && *h == *n1) {
      h++;
      n1++;
    }
    if (!*n1) {
      return h1;
    } else {
      h++;
    }
  }
  return NULL;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mystrstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    $0x8,%edi
  call   <malloc@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L26
  movzbl 0x0(%rbp),%esi
  jmp    L3
L85:
  test   %dl,%dl
  je     L16
  lea    0x1(%rax),%rbx
  cmpb   $0x0,0x1(%rax)
  je     L72
L3:
  test   %sil,%sil
  je     L16
  mov    %rbp,%rcx
  mov    %rbx,%rax
  mov    %esi,%edx
L24:
  cmp    %dl,(%rax)
  jne    L85
  add    $0x1,%rax
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L24
L16:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L26:
  mov    $0x0,%ebx
  jmp    L16
L72:
  mov    $0x0,%ebx
  jmp    L16
```

assistant: ```c
char *mystrstr(char *hay, char *needle) {
  char *h = hay;
  char *n = needle;
  char *h1 = (char *)malloc(sizeof(char *));
  char *n1 = (char *)malloc(sizeof(char *));
  while (*h != '\0') {
    h1 = h;
    n1 = n;
    while (*h1 != '\0' && *n1 != '\0' && *h == *n1) {
      h++;
      n1++;
    }
    if (!*n1) {
      return h1;
    } else {
      h++;
    }
  }
  return NULL;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mystrstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L46
  movzbl 0x0(%rbp),%edi
  mov    %rbx,%r10
  test   %dil,%dil
  je     L29
  nopl   (%rax)
L55:
  mov    %rbp,%rcx
  mov    %r10,%rax
  mov    %edi,%edx
  jmp    L18
  nopw   0x0(%rax,%rax,1)
L52:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L29
L18:
  movzbl (%rax),%r8d
  mov    %rax,%r9
  add    $0x1,%rax
  cmp    %r8b,%dl
  je     L52
  cmpb   $0x0,0x1(%r9)
  je     L46
  mov    %rax,%r10
  test   %dil,%dil
  jne    L55
L29:
  add    $0x8,%rsp
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  ret
L46:
  add    $0x8,%rsp
  xor    %r10d,%r10d
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrstr(char *hay, char *needle) {
  char *h = hay;
  char *n = needle;
  char *h1 = (char *)malloc(sizeof(char *));
  char *n1 = (char *)malloc(sizeof(char *));
  while (*h != '\0') {
    h1 = h;
    n1 = n;
    while (*h1 != '\0' && *n1 != '\0' && *h == *n1) {
      h++;
      n1++;
    }
    if (!*n1) {
      return h1;
    } else {
      h++;
    }
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<mystrstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x8,%edi
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    $0x8,%edi
  call   <malloc@plt>
  cmpb   $0x0,(%rbx)
  je     L7
  movzbl 0x0(%rbp),%edi
  mov    %rbx,%r10
  test   %dil,%dil
  je     L34
  nopl   (%rax)
L31:
  mov    %rbp,%rcx
  mov    %r10,%rax
  mov    %edi,%edx
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L29:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  je     L34
L8:
  movzbl (%rax),%r8d
  mov    %rax,%r9
  add    $0x1,%rax
  cmp    %r8b,%dl
  je     L29
  cmpb   $0x0,0x1(%r9)
  je     L7
  mov    %rax,%r10
  test   %dil,%dil
  jne    L31
L34:
  add    $0x8,%rsp
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  ret
L7:
  add    $0x8,%rsp
  xor    %r10d,%r10d
  mov    %r10,%rax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *mystrstr(char *hay, char *needle) {
  char *h = hay;
  char *n = needle;
  char *h1 = (char *)malloc(sizeof(char *));
  char *n1 = (char *)malloc(sizeof(char *));
  while (*h != '\0') {
    h1 = h;
    n1 = n;
    while (*h1 != '\0' && *n1 != '\0' && *h == *n1) {
      h++;
      n1++;
    }
    if (!*n1) {
      return h1;
    } else {
      h++;
    }
  }
  return NULL;
}
```