ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3c(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x24,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  movl   $0x0,-0x38(%rbp)
  jmp    L47
L19:
  movl   $0x0,-0x34(%rbp)
  jmp    L9
L0:
  mov    -0x34(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x30(%rbp,%rax,4),%eax
  cmp    $0x10,%eax
  je     L46
  addl   $0x1,-0x3c(%rbp)
L46:
  addl   $0x1,-0x34(%rbp)
L9:
  cmpl   $0x1,-0x34(%rbp)
  jle    L0
  addl   $0x1,-0x38(%rbp)
L47:
  cmpl   $0x1,-0x38(%rbp)
  jle    L19
  cmpl   $0x4,-0x3c(%rbp)
  je     L39
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
L39:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L69
  call   <__stack_chk_fail@plt>
L69:
  leave
  ret
```

assistant: ```c
int main(void) {
  int l = 0;
  int b[3][3];
  int i, j;
  memset(b, '\0', sizeof(b));
#pragma acc parallel copy(b [0:3] [0:3]) copy(l)
  {
#pragma acc loop collapse(2) reduction(+ : l)
    for (i = 0; i < 2; i++)
      for (j = 0; j < 2; j++)
        if (b[i][j] != 16)
          l += 1;
  }
  if (l != 2 * 2)
    __builtin_abort();
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x24,%edx
  mov    $0x0,%esi
  call   <memset@plt>
  cmpl   $0x10,(%rsp)
  setne  %al
  movzbl %al,%eax
  cmpl   $0x10,0x4(%rsp)
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%eax
  cmpl   $0x10,0xc(%rsp)
  setne  %dl
  movzbl %dl,%edx
  add    %edx,%eax
  cmpl   $0x10,0x10(%rsp)
  je     L24
  cmp    $0x3,%eax
  jne    L24
L1:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L24:
  mov    $0x0,%eax
  call   <__builtin_abort@plt>
  jmp    L1
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int l = 0;
  int b[3][3];
  int i, j;
  memset(b, '\0', sizeof(b));
#pragma acc parallel copy(b [0:3] [0:3]) copy(l)
  {
#pragma acc loop collapse(2) reduction(+ : l)
    for (i = 0; i < 2; i++)
      for (j = 0; j < 2; j++)
        if (b[i][j] != 16)
          l += 1;
  }
  if (l != 2 * 2)
    __builtin_abort();
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x24,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  xor    %eax,%eax
  cmpl   $0x10,(%rsp)
  setne  %al
  xor    %edx,%edx
  cmpl   $0x10,0x4(%rsp)
  setne  %dl
  add    %edx,%eax
  cmpl   $0x10,0xc(%rsp)
  mov    0x10(%rsp),%edx
  je     L22
  cmp    $0x10,%edx
  je     L22
  cmp    $0x2,%eax
  jne    L22
L12:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L22:
  xor    %eax,%eax
  call   <__builtin_abort@plt>
  jmp    L12
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int l = 0;
  int b[3][3];
  int i, j;
  memset(b, '\0', sizeof(b));
#pragma acc parallel copy(b [0:3] [0:3]) copy(l)
  {
#pragma acc loop collapse(2) reduction(+ : l)
    for (i = 0; i < 2; i++)
      for (j = 0; j < 2; j++)
        if (b[i][j] != 16)
          l += 1;
  }
  if (l != 2 * 2)
    __builtin_abort();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x24,%edx
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <memset@plt>
  xor    %eax,%eax
  cmpl   $0x10,(%rsp)
  setne  %al
  xor    %edx,%edx
  cmpl   $0x10,0x4(%rsp)
  setne  %dl
  add    %edx,%eax
  cmpl   $0x10,0xc(%rsp)
  mov    0x10(%rsp),%edx
  je     L48
  cmp    $0x10,%edx
  je     L48
  cmp    $0x2,%eax
  jne    L48
L41:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  xor    %eax,%eax
  add    $0x38,%rsp
  ret
L48:
  xor    %eax,%eax
  call   <__builtin_abort@plt>
  jmp    L41
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int l = 0;
  int b[3][3];
  int i, j;
  memset(b, '\0', sizeof(b));
#pragma acc parallel copy(b [0:3] [0:3]) copy(l)
  {
#pragma acc loop collapse(2) reduction(+ : l)
    for (i = 0; i < 2; i++)
      for (j = 0; j < 2; j++)
        if (b[i][j] != 16)
          l += 1;
  }
  if (l != 2 * 2)
    __builtin_abort();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osip_hash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movq   $0x1505,-0x8(%rbp)
  jmp    L3
L5:
  mov    -0x8(%rbp),%rax
  shl    $0x5,%rax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
L3:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  jne    L5
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned long osip_hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<osip_hash>:
  endbr64
  lea    0x1(%rdi),%rcx
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L15
  mov    $0x1505,%eax
L11:
  mov    %rax,%rsi
  shl    $0x5,%rsi
  add    %rsi,%rax
  movsbq %dl,%rdx
  add    %rdx,%rax
  add    $0x1,%rcx
  movzbl -0x1(%rcx),%edx
  test   %dl,%dl
  jne    L11
  ret
L15:
  mov    $0x1505,%eax
  ret
```

assistant: ```c
unsigned long osip_hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<osip_hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L10
  nopl   (%rax)
L13:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L13
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  ret
```

assistant: ```c
unsigned long osip_hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<osip_hash>:
  endbr64
  movsbq (%rdi),%rdx
  lea    0x1(%rdi),%rcx
  mov    $0x1505,%eax
  test   %dl,%dl
  je     L1
  nopl   (%rax)
L18:
  mov    %rax,%rsi
  add    $0x1,%rcx
  shl    $0x5,%rsi
  add    %rsi,%rax
  add    %rdx,%rax
  movsbq -0x1(%rcx),%rdx
  test   %dl,%dl
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  ret
```

assistant: ```c
unsigned long osip_hash(const char *str) {
  unsigned long hash = 5381;
  int c;
  while (c = *str++)
    hash = ((hash << 5) + hash) + c;
  return hash;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<__puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L15
L8:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x4(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int __puts(const char *str) {
  int count = 0;
  while (*str) {
    putchar(*str);
    str++;
    count++;
  }
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<__puts>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L20
  mov    $0x0,%ebp
L16:
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  add    $0x1,%ebp
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L16
L13:
  mov    %ebp,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L20:
  mov    $0x0,%ebp
  jmp    L13
```

assistant: ```c
int __puts(const char *str) {
  int count = 0;
  while (*str) {
    putchar(*str);
    str++;
    count++;
  }
  return count;
}
```
user: What is the c source code of the assembly code below?

```asm
<__puts>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L6
  nopl   0x0(%rax)
L17:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%r12d
  test   %dil,%dil
  jne    L17
L6:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int __puts(const char *str) {
  int count = 0;
  while (*str) {
    putchar(*str);
    str++;
    count++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<__puts>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L19
  nopl   0x0(%rax)
L11:
  call   <putchar@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  add    $0x1,%r12d
  test   %dil,%dil
  jne    L11
L19:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
int __puts(const char *str) {
  int count = 0;
  while (*str) {
    putchar(*str);
    str++;
    count++;
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x1,%edx
  lea    D36(%rip),%rsi
  lea    D96(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x2,%edx
  lea    D64(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%edx
  lea    D65(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D17(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D73(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D63(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D75(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x4,%edx
  lea    D58(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x8,%edx
  lea    D13(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x10,%edx
  lea    D22(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x20,%edx
  lea    D10(%rip),%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: read_data
arguments: tag: D36
datatype: string
name: read_data
arguments: tag: D96
datatype: string
name: read_data
arguments: tag: D64
datatype: string
name: read_data
arguments: tag: D65
datatype: string
name: read_data
arguments: tag: D17
datatype: string
name: read_data
arguments: tag: D73
datatype: string
name: read_data
arguments: tag: D63
datatype: string
name: read_data
arguments: tag: D75
datatype: string
name: read_data
arguments: tag: D58
datatype: string
name: read_data
arguments: tag: D13
datatype: string
name: read_data
arguments: tag: D22
datatype: string
name: read_data
arguments: tag: D10
datatype: string

tool: D36: char

tool: D96: sizeof(%s) = %d


tool: D64: short

tool: D65: int

tool: D17: long

tool: D73: long long

tool: D63: void *

tool: D75: size_t

tool: D58: float

tool: D13: double

tool: D22: long double

tool: D10: long double[2]

assistant: ```c
main() {
  long double ld[2];
  printf("sizeof(%s) = %d\n", "char", (int)sizeof(char));
  printf("sizeof(%s) = %d\n", "short", (int)sizeof(short));
  printf("sizeof(%s) = %d\n", "int", (int)sizeof(int));
  printf("sizeof(%s) = %d\n", "long", (int)sizeof(long));
  printf("sizeof(%s) = %d\n", "long long", (int)sizeof(long long));
  printf("sizeof(%s) = %d\n", "void *", (int)sizeof(void *));
  printf("sizeof(%s) = %d\n", "size_t", (int)sizeof(size_t));
  printf("sizeof(%s) = %d\n", "float", (int)sizeof(float));
  printf("sizeof(%s) = %d\n", "double", (int)sizeof(double));
  printf("sizeof(%s) = %d\n", "long double", (int)sizeof(long double));
  printf("sizeof(%s) = %d\n", "long double[2]", (int)sizeof(ld));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D110(%rip),%rbp
  mov    $0x1,%edx
  lea    D100(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  lea    D102(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  lea    D14(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D51(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D98(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D19(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D46(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  lea    D30(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D7(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x10,%edx
  lea    D64(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x20,%edx
  lea    D22(%rip),%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D110
datatype: string
name: retrieve_data
arguments: tag: D100
datatype: string
name: retrieve_data
arguments: tag: D102
datatype: string
name: retrieve_data
arguments: tag: D14
datatype: string
name: retrieve_data
arguments: tag: D51
datatype: string
name: retrieve_data
arguments: tag: D98
datatype: string
name: retrieve_data
arguments: tag: D19
datatype: string
name: retrieve_data
arguments: tag: D46
datatype: string
name: retrieve_data
arguments: tag: D30
datatype: string
name: retrieve_data
arguments: tag: D7
datatype: string
name: retrieve_data
arguments: tag: D64
datatype: string
name: retrieve_data
arguments: tag: D22
datatype: string

tool: D110: sizeof(%s) = %d


tool: D100: char

tool: D102: short

tool: D14: int

tool: D51: long

tool: D98: long long

tool: D19: void *

tool: D46: size_t

tool: D30: float

tool: D7: double

tool: D64: long double

tool: D22: long double[2]

assistant: ```c
main() {
  long double ld[2];
  printf("sizeof(%s) = %d\n", "char", (int)sizeof(char));
  printf("sizeof(%s) = %d\n", "short", (int)sizeof(short));
  printf("sizeof(%s) = %d\n", "int", (int)sizeof(int));
  printf("sizeof(%s) = %d\n", "long", (int)sizeof(long));
  printf("sizeof(%s) = %d\n", "long long", (int)sizeof(long long));
  printf("sizeof(%s) = %d\n", "void *", (int)sizeof(void *));
  printf("sizeof(%s) = %d\n", "size_t", (int)sizeof(size_t));
  printf("sizeof(%s) = %d\n", "float", (int)sizeof(float));
  printf("sizeof(%s) = %d\n", "double", (int)sizeof(double));
  printf("sizeof(%s) = %d\n", "long double", (int)sizeof(long double));
  printf("sizeof(%s) = %d\n", "long double[2]", (int)sizeof(ld));
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  lea    D63(%rip),%rbp
  mov    $0x1,%edx
  lea    D87(%rip),%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x2,%edx
  lea    D59(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  lea    D35(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D1(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D95(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D96(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D24(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x4,%edx
  lea    D42(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x8,%edx
  lea    D104(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x10,%edx
  lea    D107(%rip),%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x20,%edx
  lea    D38(%rip),%rsi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D63
data_type: string
name: retrieve_data
arguments: tag: D87
data_type: string
name: retrieve_data
arguments: tag: D59
data_type: string
name: retrieve_data
arguments: tag: D35
data_type: string
name: retrieve_data
arguments: tag: D1
data_type: string
name: retrieve_data
arguments: tag: D95
data_type: string
name: retrieve_data
arguments: tag: D96
data_type: string
name: retrieve_data
arguments: tag: D24
data_type: string
name: retrieve_data
arguments: tag: D42
data_type: string
name: retrieve_data
arguments: tag: D104
data_type: string
name: retrieve_data
arguments: tag: D107
data_type: string
name: retrieve_data
arguments: tag: D38
data_type: string

tool: D63: sizeof(%s) = %d


tool: D87: char

tool: D59: short

tool: D35: int

tool: D1: long

tool: D95: long long

tool: D96: void *

tool: D24: size_t

tool: D42: float

tool: D104: double

tool: D107: long double

tool: D38: long double[2]

assistant: ```c
main() {
  long double ld[2];
  printf("sizeof(%s) = %d\n", "char", (int)sizeof(char));
  printf("sizeof(%s) = %d\n", "short", (int)sizeof(short));
  printf("sizeof(%s) = %d\n", "int", (int)sizeof(int));
  printf("sizeof(%s) = %d\n", "long", (int)sizeof(long));
  printf("sizeof(%s) = %d\n", "long long", (int)sizeof(long long));
  printf("sizeof(%s) = %d\n", "void *", (int)sizeof(void *));
  printf("sizeof(%s) = %d\n", "size_t", (int)sizeof(size_t));
  printf("sizeof(%s) = %d\n", "float", (int)sizeof(float));
  printf("sizeof(%s) = %d\n", "double", (int)sizeof(double));
  printf("sizeof(%s) = %d\n", "long double", (int)sizeof(long double));
  printf("sizeof(%s) = %d\n", "long double[2]", (int)sizeof(ld));
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hypre_BigSwapb2i>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x2c(%rbp)
  mov    %r8d,-0x30(%rbp)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  mov    -0x2c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    -0x2c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x28(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x30(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x28(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void hypre_BigSwapb2i(int *v, int *w, int *z, int i, int j) {
  int big_temp;
  int temp;
  big_temp = v[i];
  v[i] = v[j];
  v[j] = big_temp;
  temp = w[i];
  w[i] = w[j];
  w[j] = temp;
  temp = z[i];
  z[i] = z[j];
  z[j] = temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<hypre_BigSwapb2i>:
  endbr64
  mov    %rdx,%rax
  movslq %ecx,%rcx
  shl    $0x2,%rcx
  lea    (%rdi,%rcx,1),%rdx
  mov    (%rdx),%r9d
  movslq %r8d,%r8
  shl    $0x2,%r8
  add    %r8,%rdi
  mov    (%rdi),%r10d
  mov    %r10d,(%rdx)
  mov    %r9d,(%rdi)
  lea    (%rsi,%rcx,1),%rdx
  mov    (%rdx),%edi
  add    %r8,%rsi
  mov    (%rsi),%r9d
  mov    %r9d,(%rdx)
  mov    %edi,(%rsi)
  add    %rax,%rcx
  mov    (%rcx),%edx
  add    %r8,%rax
  mov    (%rax),%esi
  mov    %esi,(%rcx)
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void hypre_BigSwapb2i(int *v, int *w, int *z, int i, int j) {
  int big_temp;
  int temp;
  big_temp = v[i];
  v[i] = v[j];
  v[j] = big_temp;
  temp = w[i];
  w[i] = w[j];
  w[j] = temp;
  temp = z[i];
  z[i] = z[j];
  z[j] = temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<hypre_BigSwapb2i>:
  endbr64
  movslq %ecx,%rcx
  movslq %r8d,%r8
  mov    %rdx,%rax
  shl    $0x2,%rcx
  shl    $0x2,%r8
  lea    (%rdi,%rcx,1),%rdx
  add    %r8,%rdi
  mov    (%rdi),%r10d
  mov    (%rdx),%r9d
  mov    %r10d,(%rdx)
  lea    (%rsi,%rcx,1),%rdx
  add    %r8,%rsi
  add    %rax,%rcx
  mov    %r9d,(%rdi)
  mov    (%rdx),%edi
  add    %r8,%rax
  mov    (%rsi),%r9d
  mov    %r9d,(%rdx)
  mov    %edi,(%rsi)
  mov    (%rcx),%edx
  mov    (%rax),%esi
  mov    %esi,(%rcx)
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void hypre_BigSwapb2i(int *v, int *w, int *z, int i, int j) {
  int big_temp;
  int temp;
  big_temp = v[i];
  v[i] = v[j];
  v[j] = big_temp;
  temp = w[i];
  w[i] = w[j];
  w[j] = temp;
  temp = z[i];
  z[i] = z[j];
  z[j] = temp;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hypre_BigSwapb2i>:
  endbr64
  movslq %ecx,%rcx
  movslq %r8d,%r8
  mov    %rdx,%rax
  shl    $0x2,%rcx
  shl    $0x2,%r8
  lea    (%rdi,%rcx,1),%rdx
  add    %r8,%rdi
  mov    (%rdi),%r10d
  mov    (%rdx),%r9d
  mov    %r10d,(%rdx)
  lea    (%rsi,%rcx,1),%rdx
  add    %r8,%rsi
  add    %rax,%rcx
  mov    %r9d,(%rdi)
  mov    (%rdx),%edi
  add    %r8,%rax
  mov    (%rsi),%r9d
  mov    %r9d,(%rdx)
  mov    %edi,(%rsi)
  mov    (%rcx),%edx
  mov    (%rax),%esi
  mov    %esi,(%rcx)
  mov    %edx,(%rax)
  ret
```

assistant: ```c
void hypre_BigSwapb2i(int *v, int *w, int *z, int i, int j) {
  int big_temp;
  int temp;
  big_temp = v[i];
  v[i] = v[j];
  v[j] = big_temp;
  temp = w[i];
  w[i] = w[j];
  w[j] = temp;
  temp = z[i];
  z[i] = z[j];
  z[j] = temp;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<pipe_close>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  je     L5
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <close@plt>
L5:
  nop
  leave
  ret
```

assistant: ```c
void pipe_close(int handle) {
  if (handle)
    close(handle);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pipe_close>:
  endbr64
  test   %edi,%edi
  jne    L9
  ret
L9:
  sub    $0x8,%rsp
  call   <close@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void pipe_close(int handle) {
  if (handle)
    close(handle);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<pipe_close>:
  endbr64
  test   %edi,%edi
  jne    L7
  ret
  nopl   0x0(%rax)
L7:
  jmp    1050 <close@plt>
```

assistant: ```c
void pipe_close(int handle) {
  if (handle)
    close(handle);
}
```
user: Translate the below assembly code into C programming language:

```asm
<pipe_close>:
  endbr64
  test   %edi,%edi
  jne    L2
  ret
  nopl   0x0(%rax)
L2:
  jmp    1050 <close@plt>
```

assistant: ```c
void pipe_close(int handle) {
  if (handle)
    close(handle);
}
```