ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<intro>:
  endbr64
  sub    $0x8,%rsp
  lea    D9(%rip),%rdi
  call   <printf@plt>
  lea    D33(%rip),%rdi
  call   <printf@plt>
  lea    D27(%rip),%rdi
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <printf@plt>
  lea    D40(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D9
type: string
name: unpack_data
arguments: data_tag: D33
type: string
name: unpack_data
arguments: data_tag: D27
type: string
name: unpack_data
arguments: data_tag: D14
type: string
name: unpack_data
arguments: data_tag: D40
type: string

tool: D9: Passgen 2.0


tool: D33: Written by Zach Young


tool: D27: Copyright 2004, 2005, 2006 Zach Young


tool: D14: This is free software; see the source for copying conditions.  There is NO


tool: D40: warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.



assistant: ```c
void intro() {
  printf("Passgen 2.0\n");
  printf("Written by Zach Young\n");
  printf("Copyright 2004, 2005, 2006 Zach Young\n");
  printf("This is free software; see the source for copying conditions.  There is NO\n");
  printf("warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.\n\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<intro>:
  endbr64
  sub    $0x8,%rsp
  lea    D3(%rip),%rdi
  call   <printf@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  lea    D5(%rip),%rdi
  call   <printf@plt>
  lea    D38(%rip),%rdi
  call   <printf@plt>
  lea    D41(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string
name: extract_symbolic_data
arguments: data_label: D16
type_infered: string
name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D38
type_infered: string
name: extract_symbolic_data
arguments: data_label: D41
type_infered: string

tool: D3: Passgen 2.0


tool: D16: Written by Zach Young


tool: D5: Copyright 2004, 2005, 2006 Zach Young


tool: D38: This is free software; see the source for copying conditions.  There is NO


tool: D41: warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.



assistant: ```c
void intro() {
  printf("Passgen 2.0\n");
  printf("Written by Zach Young\n");
  printf("Copyright 2004, 2005, 2006 Zach Young\n");
  printf("This is free software; see the source for copying conditions.  There is NO\n");
  printf("warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.\n\n");
  return;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<intro>:
  endbr64
  sub    $0x8,%rsp
  lea    D12(%rip),%rdi
  call   <printf@plt>
  lea    D19(%rip),%rdi
  call   <printf@plt>
  lea    D18(%rip),%rdi
  call   <printf@plt>
  lea    D32(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rdi
  add    $0x8,%rsp
  jmp    1050 <printf@plt>
```

tool_calls: name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string
name: parse_data
arguments: tag: D18
type_infered: string
name: parse_data
arguments: tag: D32
type_infered: string
name: parse_data
arguments: tag: D37
type_infered: string

tool: D12: Passgen 2.0


tool: D19: Written by Zach Young


tool: D18: Copyright 2004, 2005, 2006 Zach Young


tool: D32: This is free software; see the source for copying conditions.  There is NO


tool: D37: warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.



assistant: ```c
void intro() {
  printf("Passgen 2.0\n");
  printf("Written by Zach Young\n");
  printf("Copyright 2004, 2005, 2006 Zach Young\n");
  printf("This is free software; see the source for copying conditions.  There is NO\n");
  printf("warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.\n\n");
  return;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<addrcmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L17
L35:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x4(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L32
  mov    $0x0,%eax
  jmp    L18
L32:
  addl   $0x1,-0x4(%rbp)
L17:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L35
  mov    $0x1,%eax
L18:
  pop    %rbp
  ret
```

assistant: ```c
int addrcmp(char *snd_addr, char *rcv_addr, int size) {
  if (0) {
    trace_flow("ENTERING: addrcmp");
  }
  int i = 0;
  for (i = 0; i < size; i++) {
    if (snd_addr[i] != rcv_addr[i]) {
      return 0;
    }
  }
  if (0) {
    trace_flow("Leaving: addrcmp");
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<addrcmp>:
  endbr64
  test   %edx,%edx
  jle    L17
  mov    %edx,%edx
  mov    $0x0,%eax
L11:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  jne    L20
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L11
  mov    $0x1,%eax
  ret
L17:
  mov    $0x1,%eax
  ret
L20:
  mov    $0x0,%eax
  ret
```

assistant: ```c
int addrcmp(char *snd_addr, char *rcv_addr, int size) {
  if (0) {
    trace_flow("ENTERING: addrcmp");
  }
  int i = 0;
  for (i = 0; i < size; i++) {
    if (snd_addr[i] != rcv_addr[i]) {
      return 0;
    }
  }
  if (0) {
    trace_flow("Leaving: addrcmp");
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<addrcmp>:
  endbr64
  test   %edx,%edx
  jle    L28
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L26
  nop
L39:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L28
L26:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L39
  xor    %eax,%eax
  ret
  nopl   (%rax)
L28:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int addrcmp(char *snd_addr, char *rcv_addr, int size) {
  if (0) {
    trace_flow("ENTERING: addrcmp");
  }
  int i = 0;
  for (i = 0; i < size; i++) {
    if (snd_addr[i] != rcv_addr[i]) {
      return 0;
    }
  }
  if (0) {
    trace_flow("Leaving: addrcmp");
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<addrcmp>:
  endbr64
  test   %edx,%edx
  jle    L11
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L33
  nop
L7:
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L11
L33:
  movzbl (%rsi,%rax,1),%ecx
  cmp    %cl,(%rdi,%rax,1)
  je     L7
  xor    %eax,%eax
  ret
  nopl   (%rax)
L11:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int addrcmp(char *snd_addr, char *rcv_addr, int size) {
  if (0) {
    trace_flow("ENTERING: addrcmp");
  }
  int i = 0;
  for (i = 0; i < size; i++) {
    if (snd_addr[i] != rcv_addr[i]) {
      return 0;
    }
  }
  if (0) {
    trace_flow("Leaving: addrcmp");
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<memcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %edx,-0x34(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L1
L3:
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    -0x14(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x14(%rbp)
L1:
  mov    -0x14(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L3
  mov    -0x28(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
unsigned char *memcpy(unsigned char *dest, const unsigned char *src, int count) {
  char *csrc = (char *)src;
  char *cdest = (char *)dest;
  for (int i = 0; i < count; i++) {
    cdest[i] = csrc[i];
  }
  return dest;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L2
  mov    %edx,%edx
  mov    $0x0,%ecx
L12:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L12
L2:
  ret
```

assistant: ```c
unsigned char *memcpy(unsigned char *dest, const unsigned char *src, int count) {
  char *csrc = (char *)src;
  char *cdest = (char *)dest;
  for (int i = 0; i < count; i++) {
    cdest[i] = csrc[i];
  }
  return dest;
}
```
user: Translate the below assembly code into C programming language:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%rax
  test   %edx,%edx
  jle    L2
  movslq %edx,%rdx
  xor    %ecx,%ecx
L10:
  movzbl (%rsi,%rcx,1),%r8d
  mov    %r8b,(%rax,%rcx,1)
  add    $0x1,%rcx
  cmp    %rdx,%rcx
  jne    L10
L2:
  ret
```

assistant: ```c
unsigned char *memcpy(unsigned char *dest, const unsigned char *src, int count) {
  char *csrc = (char *)src;
  char *cdest = (char *)dest;
  for (int i = 0; i < count; i++) {
    cdest[i] = csrc[i];
  }
  return dest;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<memcpy>:
  endbr64
  mov    %rdi,%r8
  mov    %rsi,%rcx
  test   %edx,%edx
  jle    L92
  lea    0x1(%rsi),%r9
  mov    %r8,%rsi
  lea    -0x1(%rdx),%eax
  mov    %edx,%edi
  sub    %r9,%rsi
  cmp    $0xe,%rsi
  jbe    L133
  cmp    $0x6,%eax
  jbe    L133
  cmp    $0xe,%eax
  jbe    L157
  mov    %edx,%esi
  xor    %eax,%eax
  shr    $0x4,%esi
  shl    $0x4,%rsi
  nopl   0x0(%rax,%rax,1)
L84:
  movdqu (%rcx,%rax,1),%xmm0
  movups %xmm0,(%r8,%rax,1)
  add    $0x10,%rax
  cmp    %rsi,%rax
  jne    L84
  mov    %edx,%esi
  and    $0xfffffff0,%esi
  mov    %esi,%eax
  cmp    %esi,%edx
  je     L92
  mov    %edx,%edi
  sub    %esi,%edi
  lea    -0x1(%rdi),%r9d
  cmp    $0x6,%r9d
  jbe    L75
L55:
  mov    (%rcx,%rsi,1),%r9
  mov    %r9,(%r8,%rsi,1)
  mov    %edi,%esi
  and    $0xfffffff8,%esi
  add    %esi,%eax
  cmp    %esi,%edi
  je     L92
L75:
  movslq %eax,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x1(%rax),%esi
  cmp    %esi,%edx
  jle    L92
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x2(%rax),%esi
  cmp    %esi,%edx
  jle    L92
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x3(%rax),%esi
  cmp    %esi,%edx
  jle    L92
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x4(%rax),%esi
  cmp    %esi,%edx
  jle    L92
  movslq %esi,%rsi
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  lea    0x5(%rax),%esi
  cmp    %esi,%edx
  jle    L92
  movslq %esi,%rsi
  add    $0x6,%eax
  movzbl (%rcx,%rsi,1),%edi
  mov    %dil,(%r8,%rsi,1)
  cmp    %eax,%edx
  jle    L92
  cltq
  movzbl (%rcx,%rax,1),%edx
  mov    %dl,(%r8,%rax,1)
L92:
  mov    %r8,%rax
  ret
  nopl   (%rax)
L133:
  mov    %edx,%edx
  xor    %eax,%eax
  nopl   0x0(%rax)
L2:
  movzbl (%rcx,%rax,1),%esi
  mov    %sil,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L2
  mov    %r8,%rax
  ret
L157:
  xor    %esi,%esi
  xor    %eax,%eax
  jmp    L55
```

assistant: ```c
unsigned char *memcpy(unsigned char *dest, const unsigned char *src, int count) {
  char *csrc = (char *)src;
  char *cdest = (char *)dest;
  for (int i = 0; i < count; i++) {
    cdest[i] = csrc[i];
  }
  return dest;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movb   $0x41,-0x9(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L20
L30:
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L33:
  movzbl -0x9(%rbp),%eax
  mov    %eax,%edx
  add    $0x1,%edx
  mov    %dl,-0x9(%rbp)
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jle    L33
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L20:
  cmpl   $0x5,-0x8(%rbp)
  jle    L30
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  int i, j;
  char a = 'A';
  for (i = 0; i < 6; i++) {
    for (j = 0; j <= i; j++)
      printf("%c", a++);
    printf("\n");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x41,%ebp
  mov    $0x0,%r12d
  jmp    L37
L4:
  mov    %ebp,%edi
  add    $0x1,%ebp
  movsbl %dil,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %r12d,%ebx
  jle    L4
L7:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r12d
  cmp    $0x6,%r12d
  je     L18
L37:
  mov    $0x0,%ebx
  test   %r12d,%r12d
  jns    L4
  jmp    L7
L18:
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int main(void) {
  int i, j;
  char a = 'A';
  for (i = 0; i < 6; i++) {
    for (j = 0; j <= i; j++)
      printf("%c", a++);
    printf("\n");
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x41,%ebx
  nopl   0x0(%rax)
L0:
  mov    %r12d,%r14d
  mov    %ebx,%r13d
  lea    0x1(%rbx,%r12,1),%ebp
  nopl   0x0(%rax,%rax,1)
L1:
  movsbl %bl,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %bpl,%bl
  jne    L1
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x1(%r13,%r14,1),%ebx
  call   <putchar@plt>
  cmp    $0x6,%r12d
  jne    L0
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(void) {
  int i, j;
  char a = 'A';
  for (i = 0; i < 6; i++) {
    for (j = 0; j <= i; j++)
      printf("%c", a++);
    printf("\n");
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    $0x41,%ebx
  nopl   0x0(%rax)
L1:
  mov    %r12d,%r14d
  mov    %ebx,%r13d
  lea    0x1(%rbx,%r12,1),%ebp
  nopl   0x0(%rax,%rax,1)
L6:
  movsbl %bl,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %bpl,%bl
  jne    L6
  mov    $0xa,%edi
  add    $0x1,%r12d
  lea    0x1(%r13,%r14,1),%ebx
  call   <putchar@plt>
  cmp    $0x6,%r12d
  jne    L1
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int main(void) {
  int i, j;
  char a = 'A';
  for (i = 0; i < 6; i++) {
    for (j = 0; j <= i; j++)
      printf("%c", a++);
    printf("\n");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_user_time>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <getrusage@plt>
  mov    -0x20(%rbp),%eax
  imul   $0xf4240,%eax,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

assistant: ```c
long long get_user_time() {
  struct rusage rusage = {};
  getrusage(RUSAGE_SELF, &rusage);
  return rusage.ru_utime.tv_sec * 1000000 + rusage.ru_utime.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_user_time>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <getrusage@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x28,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_user_time() {
  struct rusage rusage = {};
  getrusage(RUSAGE_SELF, &rusage);
  return rusage.ru_utime.tv_sec * 1000000 + rusage.ru_utime.tv_usec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_user_time>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  mov    (%rax),%edi
  call   <getrusage@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_user_time() {
  struct rusage rusage = {};
  getrusage(RUSAGE_SELF, &rusage);
  return rusage.ru_utime.tv_sec * 1000000 + rusage.ru_utime.tv_usec;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_user_time>:
  endbr64
  sub    $0x28,%rsp
  pxor   %xmm0,%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    D3(%rip),%rax
  mov    %rsp,%rsi
  movaps %xmm0,(%rsp)
  mov    (%rax),%edi
  call   <getrusage@plt>
  imul   $0xf4240,(%rsp),%eax
  cltq
  add    0x8(%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x28,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_user_time() {
  struct rusage rusage = {};
  getrusage(RUSAGE_SELF, &rusage);
  return rusage.ru_utime.tv_sec * 1000000 + rusage.ru_utime.tv_usec;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<string_value>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  jne    L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *string_value(char *value) {
  char *tmp = (char *)malloc(strlen(value) + 1);
  strcpy(tmp, value);
  value = tmp;
  if (value[strlen(value) - 1] == '\n')
    value[strlen(value) - 1] = '\0';
  return value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<string_value>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %rbp,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%rbx,%rax,1)
  je     L16
L3:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    %rbx,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%rbx,%rax,1)
  jmp    L3
```

assistant: ```c
char *string_value(char *value) {
  char *tmp = (char *)malloc(strlen(value) + 1);
  strcpy(tmp, value);
  value = tmp;
  if (value[strlen(value) - 1] == '\n')
    value[strlen(value) - 1] = '\0';
  return value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<string_value>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%r12,%rax,1)
  je     L4
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *string_value(char *value) {
  char *tmp = (char *)malloc(strlen(value) + 1);
  strcpy(tmp, value);
  value = tmp;
  if (value[strlen(value) - 1] == '\n')
    value[strlen(value) - 1] = '\0';
  return value;
}
```
user: What is the c source code of the assembly code below:

```asm
<string_value>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  lea    0x1(%rax),%edi
  call   <malloc@plt>
  mov    %rbp,%rsi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  cmpb   $0xa,-0x1(%r12,%rax,1)
  je     L1
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    %r12,%rdi
  call   <strlen@plt>
  cltq
  movb   $0x0,-0x1(%r12,%rax,1)
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *string_value(char *value) {
  char *tmp = (char *)malloc(strlen(value) + 1);
  strcpy(tmp, value);
  value = tmp;
  if (value[strlen(value) - 1] == '\n')
    value[strlen(value) - 1] = '\0';
  return value;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L56
L42:
  addq   $0x1,-0x8(%rbp)
L56:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L42
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  je     L51
  mov    -0xc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memmove@plt>
L51:
  cmpl   $0x0,-0xc(%rbp)
  je     L24
  mov    -0xc(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L0
L46:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L0:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L46
  jmp    L19
L24:
  nop
L19:
  leave
  ret
```

assistant: ```c
void strip(char *str) {
  char *p = str;
  int l;
  while ((isspace(*p))) {
    p++;
  }
  l = strlen(p);
  if (p != str) {
    memmove(str, p, l + 1);
  }
  if (!l) {
    return;
  }
  p = str + l - 1;
  while ((isspace(*p))) {
    *p-- = 0;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<strip>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rdi,%rbx
  jmp    L53
L27:
  add    $0x1,%rbx
L53:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L27
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %eax,%ebp
  cmp    %r12,%rbx
  je     L7
  lea    0x1(%rax),%edx
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <memmove@plt>
L7:
  test   %ebp,%ebp
  je     L29
  movslq %ebp,%rbp
  lea    -0x1(%r12,%rbp,1),%rbx
  jmp    L4
L18:
  sub    $0x1,%rbx
  movb   $0x0,0x1(%rbx)
L4:
  movsbl (%rbx),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L18
L29:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void strip(char *str) {
  char *p = str;
  int l;
  while ((isspace(*p))) {
    p++;
  }
  l = strlen(p);
  if (p != str) {
    memmove(str, p, l + 1);
  }
  if (!l) {
    return;
  }
  p = str + l - 1;
  while ((isspace(*p))) {
    *p-- = 0;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<strip>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L36
L59:
  add    $0x1,%rbp
L36:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L59
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  cmp    %rbx,%rbp
  je     L30
  lea    0x1(%rax),%edx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memmove@plt>
L30:
  movslq %r12d,%rax
  lea    -0x1(%rbx,%rax,1),%rbp
  test   %r12d,%r12d
  jne    L27
  jmp    L0
  nop
L13:
  movb   $0x0,0x0(%rbp)
  sub    $0x1,%rbp
L27:
  movsbl 0x0(%rbp),%edi
  call   <isspace@plt>
  test   %rax,%rax
  jne    L13
L0:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void strip(char *str) {
  char *p = str;
  int l;
  while ((isspace(*p))) {
    p++;
  }
  l = strlen(p);
  if (p != str) {
    memmove(str, p, l + 1);
  }
  if (!l) {
    return;
  }
  p = str + l - 1;
  while ((isspace(*p))) {
    *p-- = 0;
  }
}
```