ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<convertPixelYUV444toARGB32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edx,%eax
  mov    %rcx,-0x38(%rbp)
  mov    %edi,%edx
  mov    %dl,-0x24(%rbp)
  mov    %esi,%edx
  mov    %dl,-0x28(%rbp)
  mov    %al,-0x2c(%rbp)
  movzbl -0x24(%rbp),%eax
  sub    $0x10,%eax
  imul   $0x12a,%eax,%eax
  sub    $0xffffff80,%eax
  mov    %eax,-0x1c(%rbp)
  movzbl -0x28(%rbp),%eax
  add    $0xffffff80,%eax
  mov    %eax,-0x18(%rbp)
  movzbl -0x2c(%rbp),%eax
  add    $0xffffff80,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x18(%rbp),%eax
  imul   $0x204,%eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    %eax,%edi
  call   <clipPixel@plt>
  mov    -0x38(%rbp),%rdx
  mov    %al,(%rdx)
  mov    -0x18(%rbp),%eax
  imul   $0xffffff9c,%eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  imul   $0xffffff30,%eax,%eax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    -0x38(%rbp),%rdx
  lea    0x1(%rdx),%rbx
  mov    %eax,%edi
  call   <clipPixel@plt>
  mov    %al,(%rbx)
  mov    -0x14(%rbp),%eax
  imul   $0x199,%eax,%edx
  mov    -0x1c(%rbp),%eax
  add    %edx,%eax
  sar    $0x8,%eax
  mov    -0x38(%rbp),%rdx
  lea    0x2(%rdx),%rbx
  mov    %eax,%edi
  call   <clipPixel@plt>
  mov    %al,(%rbx)
  mov    -0x38(%rbp),%rax
  add    $0x3,%rax
  movb   $0xff,(%rax)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void convertPixelYUV444toARGB32(const unsigned char y, const unsigned char u, const unsigned char v, unsigned char *dest) {
  const int C = (y - 16) * 298 + 128;
  const int D = u - 128;
  const int E = v - 128;
  dest[0] = clipPixel((C + 516 * D) >> 8);
  dest[1] = clipPixel((C - 100 * D - 208 * E) >> 8);
  dest[2] = clipPixel((C + 409 * E) >> 8);
  dest[3] = 255;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<convertPixelYUV444toARGB32>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rcx,%r13
  movzbl %dil,%r12d
  sub    $0x10,%r12d
  imul   $0x12a,%r12d,%r12d
  sub    $0xffffff80,%r12d
  movzbl %sil,%esi
  lea    -0x80(%rsi),%ebx
  movzbl %dl,%edx
  lea    -0x80(%rdx),%ebp
  imul   $0x204,%ebx,%edi
  add    %r12d,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  mov    %al,0x0(%r13)
  imul   $0xffffff9c,%ebx,%edi
  add    %r12d,%edi
  imul   $0xffffff30,%ebp,%eax
  add    %eax,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  mov    %al,0x1(%r13)
  imul   $0x199,%ebp,%edi
  add    %r12d,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  mov    %al,0x2(%r13)
  movb   $0xff,0x3(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void convertPixelYUV444toARGB32(const unsigned char y, const unsigned char u, const unsigned char v, unsigned char *dest) {
  const int C = (y - 16) * 298 + 128;
  const int D = u - 128;
  const int E = v - 128;
  dest[0] = clipPixel((C + 516 * D) >> 8);
  dest[1] = clipPixel((C - 100 * D - 208 * E) >> 8);
  dest[2] = clipPixel((C + 409 * E) >> 8);
  dest[3] = 255;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<convertPixelYUV444toARGB32>:
  endbr64
  push   %r13
  movzbl %sil,%esi
  movzbl %dl,%edx
  push   %r12
  lea    -0x80(%rdx),%r13d
  mov    %rcx,%r12
  push   %rbp
  movzbl %dil,%ebp
  sub    $0x10,%ebp
  push   %rbx
  lea    -0x80(%rsi),%ebx
  imul   $0x12a,%ebp,%ebp
  imul   $0x204,%ebx,%edi
  sub    $0x8,%rsp
  sub    $0xffffff80,%ebp
  add    %ebp,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  imul   $0xffffff9c,%ebx,%edi
  mov    %al,(%r12)
  imul   $0xffffff30,%r13d,%eax
  add    %ebp,%edi
  add    %eax,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  imul   $0x199,%r13d,%edi
  mov    %al,0x1(%r12)
  add    %ebp,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  movb   $0xff,0x3(%r12)
  mov    %al,0x2(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void convertPixelYUV444toARGB32(const unsigned char y, const unsigned char u, const unsigned char v, unsigned char *dest) {
  const int C = (y - 16) * 298 + 128;
  const int D = u - 128;
  const int E = v - 128;
  dest[0] = clipPixel((C + 516 * D) >> 8);
  dest[1] = clipPixel((C - 100 * D - 208 * E) >> 8);
  dest[2] = clipPixel((C + 409 * E) >> 8);
  dest[3] = 255;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<convertPixelYUV444toARGB32>:
  endbr64
  push   %r13
  movzbl %sil,%esi
  movzbl %dl,%edx
  push   %r12
  lea    -0x80(%rdx),%r13d
  mov    %rcx,%r12
  push   %rbp
  movzbl %dil,%ebp
  sub    $0x10,%ebp
  push   %rbx
  lea    -0x80(%rsi),%ebx
  imul   $0x12a,%ebp,%ebp
  imul   $0x204,%ebx,%edi
  sub    $0x8,%rsp
  sub    $0xffffff80,%ebp
  add    %ebp,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  imul   $0xffffff9c,%ebx,%edi
  mov    %al,(%r12)
  imul   $0xffffff30,%r13d,%eax
  add    %ebp,%edi
  add    %eax,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  imul   $0x199,%r13d,%edi
  mov    %al,0x1(%r12)
  add    %ebp,%edi
  sar    $0x8,%edi
  call   <clipPixel@plt>
  movb   $0xff,0x3(%r12)
  mov    %al,0x2(%r12)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void convertPixelYUV444toARGB32(const unsigned char y, const unsigned char u, const unsigned char v, unsigned char *dest) {
  const int C = (y - 16) * 298 + 128;
  const int D = u - 128;
  const int E = v - 128;
  dest[0] = clipPixel((C + 516 * D) >> 8);
  dest[1] = clipPixel((C - 100 * D - 208 * E) >> 8);
  dest[2] = clipPixel((C + 409 * E) >> 8);
  dest[3] = 255;
}
```
user: What is the c source code of the assembly code below:

```asm
<buttons_check>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
L6:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L6
```

assistant: ```c
void buttons_check() {
  while (1) {
    sleep(1);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<buttons_check>:
  endbr64
  sub    $0x8,%rsp
L9:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L9
```

assistant: ```c
void buttons_check() {
  while (1) {
    sleep(1);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<buttons_check>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L6
```

assistant: ```c
void buttons_check() {
  while (1) {
    sleep(1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<buttons_check>:
  endbr64
  sub    $0x8,%rsp
  nopl   0x0(%rax,%rax,1)
L9:
  mov    $0x1,%edi
  call   <sleep@plt>
  jmp    L9
```

assistant: ```c
void buttons_check() {
  while (1) {
    sleep(1);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<print_enable>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L18
L6:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L6
  mov    $0xa,%edi
  call   <putchar@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
data_type: string

tool: D7: Enable: 

assistant: ```c
void print_enable(char *result_chars, int result_count) {
  printf("Enable: ");
  for (int i = 0; i < result_count; i++) {
    printf("%c", result_chars[i]);
  }
  printf("\n");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print_enable>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %esi,%ebp
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L15
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x1(%r12,%rax,1),%rbp
L14:
  movsbl (%rbx),%edi
  call   <putchar@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L14
L15:
  mov    $0xa,%edi
  call   <putchar@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
type_guessed: string

tool: D4: Enable: 

assistant: ```c
void print_enable(char *result_chars, int result_count) {
  printf("Enable: ");
  for (int i = 0; i < result_count; i++) {
    printf("%c", result_chars[i]);
  }
  printf("\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_enable>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D6(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L3
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopl   0x0(%rax)
L16:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L16
L3:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D6
data_type: string

tool: D6: Enable: 

assistant: ```c
void print_enable(char *result_chars, int result_count) {
  printf("Enable: ");
  for (int i = 0; i < result_count; i++) {
    printf("%c", result_chars[i]);
  }
  printf("\n");
}
```
user: What is the c source code of the assembly code below:

```asm
<print_enable>:
  endbr64
  push   %rbp
  xor    %eax,%eax
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  lea    D5(%rip),%rdi
  sub    $0x8,%rsp
  call   <printf@plt>
  test   %ebp,%ebp
  jle    L18
  lea    -0x1(%rbp),%eax
  lea    0x1(%rbx,%rax,1),%rbp
  nopl   0x0(%rax)
L19:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <putchar@plt>
  cmp    %rbp,%rbx
  jne    L19
L18:
  add    $0x8,%rsp
  mov    $0xa,%edi
  pop    %rbx
  pop    %rbp
  jmp    1060 <putchar@plt>
```

tool_calls: name: read_data
arguments: tag: D5
data_type: string

tool: D5: Enable: 

assistant: ```c
void print_enable(char *result_chars, int result_count) {
  printf("Enable: ");
  for (int i = 0; i < result_count; i++) {
    printf("%c", result_chars[i]);
  }
  printf("\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_max>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x20(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x30(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x18(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L14
L10:
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%ebx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x18(%rbp),%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %ebx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x1c(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x30(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x20(%rbp),%edx
  mov    -0x1c(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,-0x20(%rbp)
  addl   $0x1,-0x14(%rbp)
L14:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L10
  mov    -0x18(%rbp),%edx
  mov    -0x20(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D4
type: string

tool: D4: %d %d


assistant: ```c
void print_max(int n, int *ar) {
  int max_contiguos = ar[0];
  int cur_sum = ar[0];
  int max_non_contiguos = ar[0];
  for (int i = 1; i < n; i++) {
    max_non_contiguos = max(max(max_non_contiguos, max_non_contiguos + ar[i]), ar[i]);
    cur_sum = max(ar[i], cur_sum + ar[i]);
    max_contiguos = max(cur_sum, max_contiguos);
  }
  printf("%d %d\n", max_contiguos, max_non_contiguos);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_max>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%r13d
  cmp    $0x1,%edi
  jle    L28
  lea    0x4(%rsi),%r12
  lea    -0x2(%rdi),%eax
  lea    0x8(%rsi,%rax,4),%r15
  mov    %r13d,%ebp
  mov    %r13d,%ebx
L7:
  mov    (%r12),%r14d
  lea    (%r14,%rbp,1),%esi
  mov    %ebp,%edi
  call   <max@plt>
  mov    %eax,%edi
  mov    %r14d,%esi
  call   <max@plt>
  mov    %eax,%ebp
  mov    (%r12),%edi
  lea    (%rdi,%rbx,1),%esi
  call   <max@plt>
  mov    %eax,%ebx
  mov    %r13d,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    %eax,%r13d
  add    $0x4,%r12
  cmp    %r15,%r12
  jne    L7
L23:
  mov    %ebp,%edx
  mov    %r13d,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L28:
  mov    %r13d,%ebp
  jmp    L23
```

tool_calls: name: read_data
arguments: data_tag: D8
data_type: string

tool: D8: %d %d


assistant: ```c
void print_max(int n, int *ar) {
  int max_contiguos = ar[0];
  int cur_sum = ar[0];
  int max_non_contiguos = ar[0];
  for (int i = 1; i < n; i++) {
    max_non_contiguos = max(max(max_non_contiguos, max_non_contiguos + ar[i]), ar[i]);
    cur_sum = max(ar[i], cur_sum + ar[i]);
    max_contiguos = max(cur_sum, max_contiguos);
  }
  printf("%d %d\n", max_contiguos, max_non_contiguos);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<print_max>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%ebp
  cmp    $0x1,%edi
  jle    L10
  lea    -0x2(%rdi),%eax
  lea    0x4(%rsi),%r12
  mov    %ebp,%ebx
  mov    %ebp,%r13d
  lea    0x8(%rsi,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L2:
  mov    (%r12),%r15d
  mov    %ebp,%edi
  add    $0x4,%r12
  lea    (%r15,%rbp,1),%esi
  call   <max@plt>
  mov    %r15d,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    -0x4(%r12),%edi
  mov    %eax,%ebp
  lea    (%rdi,%rbx,1),%esi
  call   <max@plt>
  mov    %r13d,%esi
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <max@plt>
  mov    %eax,%r13d
  cmp    %r14,%r12
  jne    L2
L19:
  add    $0x8,%rsp
  mov    %ebp,%edx
  lea    D0(%rip),%rdi
  mov    %r13d,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
  nop
L10:
  mov    %ebp,%r13d
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
data_type: string

tool: D0: %d %d


assistant: ```c
void print_max(int n, int *ar) {
  int max_contiguos = ar[0];
  int cur_sum = ar[0];
  int max_non_contiguos = ar[0];
  for (int i = 1; i < n; i++) {
    max_non_contiguos = max(max(max_non_contiguos, max_non_contiguos + ar[i]), ar[i]);
    cur_sum = max(ar[i], cur_sum + ar[i]);
    max_contiguos = max(cur_sum, max_contiguos);
  }
  printf("%d %d\n", max_contiguos, max_non_contiguos);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_max>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    (%rsi),%ebp
  cmp    $0x1,%edi
  jle    L15
  lea    -0x2(%rdi),%eax
  lea    0x4(%rsi),%r12
  mov    %ebp,%ebx
  mov    %ebp,%r13d
  lea    0x8(%rsi,%rax,4),%r14
  nopw   0x0(%rax,%rax,1)
L1:
  mov    (%r12),%r15d
  mov    %ebp,%edi
  add    $0x4,%r12
  lea    (%r15,%rbp,1),%esi
  call   <max@plt>
  mov    %r15d,%esi
  mov    %eax,%edi
  call   <max@plt>
  mov    -0x4(%r12),%edi
  mov    %eax,%ebp
  lea    (%rdi,%rbx,1),%esi
  call   <max@plt>
  mov    %r13d,%esi
  mov    %eax,%edi
  mov    %eax,%ebx
  call   <max@plt>
  mov    %eax,%r13d
  cmp    %r14,%r12
  jne    L1
L17:
  add    $0x8,%rsp
  mov    %ebp,%edx
  lea    D8(%rip),%rdi
  mov    %r13d,%esi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
  nop
L15:
  mov    %ebp,%r13d
  jmp    L17
```

tool_calls: name: unpack_data
arguments: data_label: D8
datatype: string

tool: D8: %d %d


assistant: ```c
void print_max(int n, int *ar) {
  int max_contiguos = ar[0];
  int cur_sum = ar[0];
  int max_non_contiguos = ar[0];
  for (int i = 1; i < n; i++) {
    max_non_contiguos = max(max(max_non_contiguos, max_non_contiguos + ar[i]), ar[i]);
    cur_sum = max(ar[i], cur_sum + ar[i]);
    max_contiguos = max(cur_sum, max_contiguos);
  }
  printf("%d %d\n", max_contiguos, max_non_contiguos);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x312b322d,-0x110(%rbp)
  movq   $0x0,-0x108(%rbp)
  movq   $0x0,-0x100(%rbp)
  movq   $0x0,-0xf8(%rbp)
  movq   $0x0,-0xf0(%rbp)
  movq   $0x0,-0xe8(%rbp)
  movq   $0x0,-0xe0(%rbp)
  movq   $0x0,-0xd8(%rbp)
  movabs $0x312b29322d3028,%rax
  mov    $0x0,%edx
  mov    %rax,-0xd0(%rbp)
  mov    %rdx,-0xc8(%rbp)
  movq   $0x0,-0xc0(%rbp)
  movq   $0x0,-0xb8(%rbp)
  movq   $0x0,-0xb0(%rbp)
  movq   $0x0,-0xa8(%rbp)
  movq   $0x0,-0xa0(%rbp)
  movq   $0x0,-0x98(%rbp)
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <replace_minus@plt>
  lea    -0xd0(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L9
  mov    $0xffffffff,%eax
  jmp    L33
L9:
  movq   $0x322d33,-0x90(%rbp)
  movq   $0x0,-0x88(%rbp)
  movq   $0x0,-0x80(%rbp)
  movq   $0x0,-0x78(%rbp)
  movq   $0x0,-0x70(%rbp)
  movq   $0x0,-0x68(%rbp)
  movq   $0x0,-0x60(%rbp)
  movq   $0x0,-0x58(%rbp)
  movq   $0x322d33,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  movq   $0x0,-0x38(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x90(%rbp),%rax
  mov    %rax,%rdi
  call   <replace_minus@plt>
  lea    -0x50(%rbp),%rdx
  lea    -0x90(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L23
  mov    $0xffffffff,%eax
  jmp    L33
L23:
  mov    $0x0,%eax
L33:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(void) {
  char before1[64] = "-2+1";
  char after1[64] = "(0-2)+1";
  replace_minus(before1);
  if (strcmp(before1, after1) != 0) {
    return (-1);
  }
  char before2[64] = "3-2";
  char after2[64] = "3-2";
  replace_minus(before2);
  if (strcmp(before2, after2) != 0) {
    return (-1);
  }
  return (0);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x312b322d,(%rsp)
  movq   $0x0,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movabs $0x312b29322d3028,%rax
  mov    $0x0,%edx
  mov    %rax,0x40(%rsp)
  mov    %rdx,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  movq   $0x0,0x58(%rsp)
  movq   $0x0,0x60(%rsp)
  movq   $0x0,0x68(%rsp)
  movq   $0x0,0x70(%rsp)
  movq   $0x0,0x78(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <replace_minus@plt>
  lea    0x40(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L2
  movq   $0x322d33,0x80(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x0,0x90(%rsp)
  movq   $0x0,0x98(%rsp)
  movq   $0x0,0xa0(%rsp)
  movq   $0x0,0xa8(%rsp)
  movq   $0x0,0xb0(%rsp)
  movq   $0x0,0xb8(%rsp)
  movq   $0x322d33,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  movq   $0x0,0xd0(%rsp)
  movq   $0x0,0xd8(%rsp)
  movq   $0x0,0xe0(%rsp)
  movq   $0x0,0xe8(%rsp)
  movq   $0x0,0xf0(%rsp)
  movq   $0x0,0xf8(%rsp)
  lea    0x80(%rsp),%rbx
  mov    %rbx,%rdi
  call   <replace_minus@plt>
  lea    0xc0(%rsp),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
L20:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L24
  add    $0x110,%rsp
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L20
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char before1[64] = "-2+1";
  char after1[64] = "(0-2)+1";
  replace_minus(before1);
  if (strcmp(before1, after1) != 0) {
    return (-1);
  }
  char before2[64] = "3-2";
  char after2[64] = "3-2";
  replace_minus(before2);
  if (strcmp(before2, after2) != 0) {
    return (-1);
  }
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x312b322d,(%rsp)
  movabs $0x312b29322d3028,%rax
  mov    %rbp,%rdi
  mov    %rax,0x40(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rdx,0x48(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <replace_minus@plt>
  lea    0x40(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L20
  lea    0x80(%rsp),%rbp
  pxor   %xmm0,%xmm0
  movq   $0x322d33,0x80(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x322d33,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  call   <replace_minus@plt>
  lea    0xc0(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
L3:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x110,%rsp
  pop    %rbp
  ret
L20:
  or     $0xffffffff,%eax
  jmp    L3
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char before1[64] = "-2+1";
  char after1[64] = "(0-2)+1";
  replace_minus(before1);
  if (strcmp(before1, after1) != 0) {
    return (-1);
  }
  char before2[64] = "3-2";
  char after2[64] = "3-2";
  replace_minus(before2);
  if (strcmp(before2, after2) != 0) {
    return (-1);
  }
  return (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm0,%xmm0
  xor    %edx,%edx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  movq   $0x312b322d,(%rsp)
  movabs $0x312b29322d3028,%rax
  mov    %rbp,%rdi
  mov    %rax,0x40(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rdx,0x48(%rsp)
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x50(%rsp)
  movaps %xmm0,0x60(%rsp)
  movaps %xmm0,0x70(%rsp)
  call   <replace_minus@plt>
  lea    0x40(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L14
  lea    0x80(%rsp),%rbp
  pxor   %xmm0,%xmm0
  movq   $0x322d33,0x80(%rsp)
  mov    %rbp,%rdi
  movaps %xmm0,0x90(%rsp)
  movaps %xmm0,0xa0(%rsp)
  movaps %xmm0,0xb0(%rsp)
  movaps %xmm0,0xd0(%rsp)
  movaps %xmm0,0xe0(%rsp)
  movaps %xmm0,0xf0(%rsp)
  movq   $0x0,0x88(%rsp)
  movq   $0x322d33,0xc0(%rsp)
  movq   $0x0,0xc8(%rsp)
  call   <replace_minus@plt>
  lea    0xc0(%rsp),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  neg    %rax
  sbb    %eax,%eax
L6:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L18
  add    $0x110,%rsp
  pop    %rbp
  ret
L14:
  or     $0xffffffff,%eax
  jmp    L6
L18:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char before1[64] = "-2+1";
  char after1[64] = "(0-2)+1";
  replace_minus(before1);
  if (strcmp(before1, after1) != 0) {
    return (-1);
  }
  char before2[64] = "3-2";
  char after2[64] = "3-2";
  replace_minus(before2);
  if (strcmp(before2, after2) != 0) {
    return (-1);
  }
  return (0);
}
```