ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below:

```asm
<kth_smallest_uint8>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  mov    %rdi,-0x38(%rbp)
  mov    %esi,-0x3c(%rbp)
  mov    %edx,-0x40(%rbp)
  mov    $0x0,%r14d
  mov    -0x3c(%rbp),%eax
  lea    -0x1(%rax),%r13d
  jmp    L23
L83:
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x22(%rbp)
  mov    %r14d,%r12d
  mov    %r13d,%ebx
  jmp    L69
L43:
  add    $0x1,%r12d
L69:
  movslq %r12d,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x22(%rbp)
  ja     L43
  jmp    L60
L75:
  sub    $0x1,%ebx
L60:
  movslq %ebx,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x22(%rbp)
  jb     L75
  cmp    %ebx,%r12d
  jg     L3
  movslq %r12d,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x21(%rbp)
  movslq %ebx,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movslq %r12d,%rcx
  mov    -0x38(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movslq %ebx,%rdx
  mov    -0x38(%rbp),%rax
  add    %rax,%rdx
  movzbl -0x21(%rbp),%eax
  mov    %al,(%rdx)
  add    $0x1,%r12d
  sub    $0x1,%ebx
L3:
  cmp    %ebx,%r12d
  jle    L69
  cmp    -0x40(%rbp),%ebx
  jge    L72
  mov    %r12d,%r14d
L72:
  cmp    %r12d,-0x40(%rbp)
  jge    L23
  mov    %ebx,%r13d
L23:
  cmp    %r13d,%r14d
  jl     L83
  mov    -0x40(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x38(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %rbp
  ret
```

assistant: ```c
unsigned char kth_smallest_uint8(unsigned char a[], int n, int k) {
  register int i, j, l, m;
  unsigned char x;
  l = 0;
  m = n - 1;
  while (l < m) {
    x = a[k];
    i = l;
    j = m;
    do {
      while (a[i] < x)
        i++;
      while (x < a[j])
        j--;
      if (i <= j) {
        {
          unsigned char temp = (a[i]);
          (a[i]) = (a[j]);
          (a[j]) = temp;
        };
        i++;
        j--;
      }
    } while (i <= j);
    if (j < k)
      l = i;
    if (k < i)
      m = j;
  }
  return a[k];
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<kth_smallest_uint8>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %edx,-0xc(%rsp)
  lea    -0x1(%rsi),%r15d
  test   %r15d,%r15d
  jle    L115
  mov    $0x0,%r14d
  movslq %edx,%rax
  mov    %rax,-0x8(%rsp)
  jmp    L81
L57:
  mov    %sil,(%r12)
  mov    %bl,(%r8)
  mov    %r11d,%ebp
  sub    $0x1,%edx
  cmp    %edx,%r11d
  jg     L78
L107:
  add    $0x1,%r9
  add    $0x1,%r11d
  add    $0x1,%r10d
L11:
  mov    %r10d,%ebp
  mov    %r9,%r12
  movzbl (%r9),%ebx
  cmp    %dil,%bl
  jb     L107
  movslq %edx,%rax
  lea    0x0(%r13,%rax,1),%r8
  movzbl (%r8),%esi
  cmp    %sil,%dil
  jae    L65
  lea    -0x1(%r13,%rax,1),%rsi
  mov    %rsi,%rax
  lea    -0x1(%rdx),%ecx
  sub    %esi,%ecx
L110:
  lea    (%rcx,%rax,1),%edx
  mov    %rax,%r8
  sub    $0x1,%rax
  movzbl 0x1(%rax),%esi
  cmp    %dil,%sil
  ja     L110
L65:
  cmp    %edx,%ebp
  jle    L57
L78:
  mov    -0xc(%rsp),%eax
  cmp    %edx,%eax
  jg     L42
  cmp    %ebp,%eax
  cmovl  %edx,%r15d
L24:
  cmp    %r14d,%r15d
  jle    L115
L81:
  mov    -0x8(%rsp),%rax
  movzbl 0x0(%r13,%rax,1),%edi
  movslq %r14d,%r9
  add    %r13,%r9
  mov    %r14d,%r10d
  lea    0x1(%r14),%r11d
  mov    %r15d,%edx
  jmp    L11
L42:
  cmp    %ebp,-0xc(%rsp)
  jl     L115
  mov    %ebp,%r14d
  jmp    L24
L115:
  movslq -0xc(%rsp),%rax
  movzbl 0x0(%r13,%rax,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
unsigned char kth_smallest_uint8(unsigned char a[], int n, int k) {
  register int i, j, l, m;
  unsigned char x;
  l = 0;
  m = n - 1;
  while (l < m) {
    x = a[k];
    i = l;
    j = m;
    do {
      while (a[i] < x)
        i++;
      while (x < a[j])
        j--;
      if (i <= j) {
        {
          unsigned char temp = (a[i]);
          (a[i]) = (a[j]);
          (a[j]) = temp;
        };
        i++;
        j--;
      }
    } while (i <= j);
    if (j < k)
      l = i;
    if (k < i)
      m = j;
  }
  return a[k];
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<kth_smallest_uint8>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rax,%r15
  lea    -0x1(%rsi),%r14d
  add    %rdi,%rax
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rax,-0x8(%rsp)
  test   %r14d,%r14d
  jle    L5
  mov    %rdi,%r12
  xor    %r13d,%r13d
  nopl   0x0(%rax,%rax,1)
L72:
  mov    -0x8(%rsp),%rax
  movslq %r13d,%r9
  mov    %r13d,%r10d
  lea    0x1(%r13),%ebx
  add    %r12,%r9
  mov    %r14d,%ecx
  movzbl (%rax),%edi
  movslq %r14d,%rax
  nopl   0x0(%rax,%rax,1)
L8:
  movzbl (%r9),%r8d
  lea    (%r12,%rax,1),%rsi
  mov    %r10d,%ebp
  movzbl (%rsi),%edx
  cmp    %dil,%r8b
  jb     L31
  cmp    %dl,%dil
  jae    L13
  lea    -0x1(%r12,%rax,1),%rax
  lea    -0x1(%rcx),%r11d
  sub    %eax,%r11d
  nopl   0x0(%rax)
L78:
  lea    (%r11,%rax,1),%ecx
  mov    %rax,%rsi
  movzbl (%rax),%edx
  sub    $0x1,%rax
  cmp    %dil,%dl
  ja     L78
L13:
  cmp    %ecx,%r10d
  jle    L75
L20:
  cmp    %ecx,%r15d
  cmovg  %ebp,%r13d
  cmp    %ebp,%r15d
  cmovl  %ecx,%r14d
  cmp    %r13d,%r14d
  jg     L72
L5:
  mov    -0x8(%rsp),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  movzbl (%rax),%eax
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  cs nopw 0x0(%rax,%rax,1)
L75:
  sub    $0x1,%ecx
  mov    %dl,(%r9)
  mov    %ebx,%ebp
  mov    %r8b,(%rsi)
  cmp    %ecx,%ebx
  jg     L20
  movslq %ecx,%rax
L31:
  add    $0x1,%r9
  add    $0x1,%ebx
  add    $0x1,%r10d
  jmp    L8
```

assistant: ```c
unsigned char kth_smallest_uint8(unsigned char a[], int n, int k) {
  register int i, j, l, m;
  unsigned char x;
  l = 0;
  m = n - 1;
  while (l < m) {
    x = a[k];
    i = l;
    j = m;
    do {
      while (a[i] < x)
        i++;
      while (x < a[j])
        j--;
      if (i <= j) {
        {
          unsigned char temp = (a[i]);
          (a[i]) = (a[j]);
          (a[j]) = temp;
        };
        i++;
        j--;
      }
    } while (i <= j);
    if (j < k)
      l = i;
    if (k < i)
      m = j;
  }
  return a[k];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<kth_smallest_uint8>:
  endbr64
  push   %r15
  movslq %edx,%rax
  push   %r14
  mov    %rax,%r15
  lea    -0x1(%rsi),%r14d
  add    %rdi,%rax
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  mov    %rax,-0x8(%rsp)
  test   %r14d,%r14d
  jle    L45
  nopl   0x0(%rax,%rax,1)
L59:
  mov    -0x8(%rsp),%rax
  movslq %r13d,%r8
  mov    %r13d,%r9d
  lea    0x1(%r13),%r11d
  add    %r12,%r8
  mov    %r14d,%ecx
  movzbl (%rax),%edi
  movslq %r14d,%rax
  nopl   0x0(%rax,%rax,1)
L40:
  movzbl (%r8),%r10d
  lea    (%r12,%rax,1),%rsi
  mov    %r9d,%ebx
  movzbl (%rsi),%edx
  cmp    %dil,%r10b
  jb     L97
  cmp    %dl,%dil
  jae    L27
  lea    -0x1(%r12,%rax,1),%rax
  lea    -0x1(%rcx),%ebp
  sub    %eax,%ebp
  nopw   0x0(%rax,%rax,1)
L73:
  lea    0x0(%rbp,%rax,1),%ecx
  mov    %rax,%rsi
  movzbl (%rax),%edx
  sub    $0x1,%rax
  cmp    %dil,%dl
  ja     L73
L27:
  cmp    %ecx,%r9d
  jle    L29
L78:
  cmp    %ecx,%r15d
  cmovg  %ebx,%r13d
  cmp    %ebx,%r15d
  jl     L35
  cmp    %r14d,%r13d
  jl     L59
L45:
  mov    -0x8(%rsp),%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  movzbl (%rax),%eax
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L29:
  sub    $0x1,%ecx
  mov    %dl,(%r8)
  mov    %r11d,%ebx
  mov    %r10b,(%rsi)
  cmp    %ecx,%r11d
  jg     L78
  movslq %ecx,%rax
L97:
  add    $0x1,%r8
  add    $0x1,%r11d
  add    $0x1,%r9d
  jmp    L40
L35:
  cmp    %ecx,%r13d
  jge    L45
  mov    %ecx,%r14d
  jmp    L59
```

assistant: ```c
unsigned char kth_smallest_uint8(unsigned char a[], int n, int k) {
  register int i, j, l, m;
  unsigned char x;
  l = 0;
  m = n - 1;
  while (l < m) {
    x = a[k];
    i = l;
    j = m;
    do {
      while (a[i] < x)
        i++;
      while (x < a[j])
        j--;
      if (i <= j) {
        {
          unsigned char temp = (a[i]);
          (a[i]) = (a[j]);
          (a[j]) = temp;
        };
        i++;
        j--;
      }
    } while (i <= j);
    if (j < k)
      l = i;
    if (k < i)
      m = j;
  }
  return a[k];
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<sub_help_filter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %rdx,-0x18(%rbp)
  cmpl   $0x2000004,-0x4(%rbp)
  jne    L8
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <strdup@plt>
  jmp    L15
L8:
  mov    -0x10(%rbp),%rax
L15:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
datatype: string

tool: D5: This is some extra text from the sub parser (note that it is preceded by a blank line).

assistant: ```c
char *sub_help_filter(int key, const char *text, void *input __attribute__((unused))) {
  if (key == 0x2000004)
    return strdup("This is some extra text from the sub parser (note that it is preceded by a blank line).");
  else
    return (char *)text;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sub_help_filter>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x2000004,%edi
  je     L3
  ret
L3:
  sub    $0x8,%rsp
  lea    D7(%rip),%rdi
  call   <strdup@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D7
datatype: string

tool: D7: This is some extra text from the sub parser (note that it is preceded by a blank line).

assistant: ```c
char *sub_help_filter(int key, const char *text, void *input __attribute__((unused))) {
  if (key == 0x2000004)
    return strdup("This is some extra text from the sub parser (note that it is preceded by a blank line).");
  else
    return (char *)text;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<sub_help_filter>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x2000004,%edi
  je     L0
  ret
L0:
  lea    D8(%rip),%rdi
  jmp    1050 <strdup@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type: string

tool: D8: This is some extra text from the sub parser (note that it is preceded by a blank line).

assistant: ```c
char *sub_help_filter(int key, const char *text, void *input __attribute__((unused))) {
  if (key == 0x2000004)
    return strdup("This is some extra text from the sub parser (note that it is preceded by a blank line).");
  else
    return (char *)text;
}
```
user: Translate the below assembly code into C programming language:

```asm
<sub_help_filter>:
  endbr64
  mov    %rsi,%rax
  cmp    $0x2000004,%edi
  je     L4
  ret
L4:
  lea    D5(%rip),%rdi
  jmp    1050 <strdup@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D5
datatype: string

tool: D5: This is some extra text from the sub parser (note that it is preceded by a blank line).

assistant: ```c
char *sub_help_filter(int key, const char *text, void *input __attribute__((unused))) {
  if (key == 0x2000004)
    return strdup("This is some extra text from the sub parser (note that it is preceded by a blank line).");
  else
    return (char *)text;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sync_stq>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%eax
  mov    %al,-0xc(%rbp)
  mov    -0x8(%rbp),%rax
  movzbl 0x1(%rax),%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  movzbl -0xc(%rbp),%eax
  mov    %al,(%rdx)
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa0,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    $0xa1,%al
  jne    L19
  mov    $0x1,%eax
  jmp    L27
L19:
  mov    $0x0,%eax
L27:
  pop    %rbp
  ret
```

assistant: ```c
int sync_stq(unsigned char *buff, unsigned char data) {
  buff[0] = buff[1];
  buff[1] = data;
  return buff[0] == 0xA0 && buff[1] == 0xA1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<sync_stq>:
  endbr64
  movzbl 0x1(%rdi),%eax
  mov    %al,(%rdi)
  mov    %sil,0x1(%rdi)
  cmp    $0xa1,%sil
  sete   %dl
  cmp    $0xa0,%al
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int sync_stq(unsigned char *buff, unsigned char data) {
  buff[0] = buff[1];
  buff[1] = data;
  return buff[0] == 0xA0 && buff[1] == 0xA1;
}
```
user: What is the c source code of the assembly code below:

```asm
<sync_stq>:
  endbr64
  movzbl 0x1(%rdi),%eax
  cmp    $0xa1,%sil
  mov    %sil,0x1(%rdi)
  sete   %dl
  cmp    $0xa0,%al
  mov    %al,(%rdi)
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int sync_stq(unsigned char *buff, unsigned char data) {
  buff[0] = buff[1];
  buff[1] = data;
  return buff[0] == 0xA0 && buff[1] == 0xA1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<sync_stq>:
  endbr64
  movzbl 0x1(%rdi),%eax
  cmp    $0xa1,%sil
  mov    %sil,0x1(%rdi)
  sete   %dl
  cmp    $0xa0,%al
  mov    %al,(%rdi)
  sete   %al
  movzbl %al,%eax
  and    %edx,%eax
  ret
```

assistant: ```c
int sync_stq(unsigned char *buff, unsigned char data) {
  buff[0] = buff[1];
  buff[1] = data;
  return buff[0] == 0xA0 && buff[1] == 0xA1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_dobldobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x54(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x38(%rbp)
  xor    %eax,%eax
  lea    -0x50(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <solcon_length_dobldobl_solution_string@plt>
  mov    %eax,-0x4c(%rbp)
  mov    %rsp,%rax
  mov    %rax,%rbx
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  sub    $0x1,%rdx
  mov    %rdx,-0x48(%rbp)
  movslq %eax,%rdx
  mov    %rdx,%r14
  mov    $0x0,%r15d
  movslq %eax,%rdx
  mov    %rdx,%r12
  mov    $0x0,%r13d
  cltq
  mov    $0x10,%edx
  sub    $0x1,%rdx
  add    %rdx,%rax
  mov    $0x10,%esi
  mov    $0x0,%edx
  div    %rsi
  imul   $0x10,%rax,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffff000,%rcx
  mov    %rsp,%rdx
  sub    %rcx,%rdx
L21:
  cmp    %rdx,%rsp
  je     L10
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L21
L10:
  mov    %rax,%rdx
  and    $0xfff,%edx
  sub    %rdx,%rsp
  mov    %rax,%rdx
  and    $0xfff,%edx
  test   %rdx,%rdx
  je     L18
  and    $0xfff,%eax
  sub    $0x8,%rax
  add    %rsp,%rax
  orq    $0x0,(%rax)
L18:
  mov    %rsp,%rax
  add    $0x0,%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x50(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <solcon_write_dobldobl_solution_string@plt>
  mov    %eax,-0x4c(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x54(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    %rbx,%rsp
  mov    -0x4c(%rbp),%eax
  mov    -0x38(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  lea    -0x28(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D8
type_infered: string

tool: D8: 
solution %d :
%s


assistant: ```c
int write_dobldobl_solution(int index) {
  int fail, nb;
  fail = solcon_length_dobldobl_solution_string(index, &nb);
  {
    char solution[nb];
    fail = solcon_write_dobldobl_solution_string(index, nb, solution);
    printf("\nsolution %d :\n%s\n", index, solution);
  }
  return fail;
}
```
user: What is the c source code of the assembly code below:

```asm
<write_dobldobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r12
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x1c(%rbp),%rsi
  call   <solcon_length_dobldobl_solution_string@plt>
  mov    -0x1c(%rbp),%esi
  movslq %esi,%rax
  add    $0xf,%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L27:
  cmp    %rdx,%rsp
  je     L17
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L27
L17:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L24
  orq    $0x0,-0x8(%rsp,%rax,1)
L24:
  mov    %rsp,%rdx
  mov    %ebx,%edi
  call   <solcon_write_dobldobl_solution_string@plt>
  mov    %eax,%r12d
  mov    %rsp,%rdx
  mov    %ebx,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L39
  mov    %r12d,%eax
  lea    -0x10(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %rbp
  ret
L39:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: 
solution %d :
%s


assistant: ```c
int write_dobldobl_solution(int index) {
  int fail, nb;
  fail = solcon_length_dobldobl_solution_string(index, &nb);
  {
    char solution[nb];
    fail = solcon_write_dobldobl_solution_string(index, nb, solution);
    printf("\nsolution %d :\n%s\n", index, solution);
  }
  return fail;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_dobldobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    -0x1c(%rbp),%rsi
  mov    %edi,%r12d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <solcon_length_dobldobl_solution_string@plt>
  movslq -0x1c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L20
L4:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L4
L20:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L22
L19:
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <solcon_write_dobldobl_solution_string@plt>
  mov    %rsp,%rdx
  mov    %r12d,%esi
  lea    D9(%rip),%rdi
  mov    %eax,%r13d
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  lea    -0x10(%rbp),%rsp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L22:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L19
L31:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D9
data_type: string

tool: D9: 
solution %d :
%s


assistant: ```c
int write_dobldobl_solution(int index) {
  int fail, nb;
  fail = solcon_length_dobldobl_solution_string(index, &nb);
  {
    char solution[nb];
    fail = solcon_write_dobldobl_solution_string(index, nb, solution);
    printf("\nsolution %d :\n%s\n", index, solution);
  }
  return fail;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_dobldobl_solution>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  lea    -0x1c(%rbp),%rsi
  mov    %edi,%r12d
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  call   <solcon_length_dobldobl_solution_string@plt>
  movslq -0x1c(%rbp),%rax
  mov    %rsp,%rcx
  mov    %rax,%rsi
  add    $0xf,%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L29
L0:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L0
L29:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L27
L12:
  mov    %rsp,%rdx
  mov    %r12d,%edi
  call   <solcon_write_dobldobl_solution_string@plt>
  mov    %rsp,%rdx
  mov    %r12d,%esi
  lea    D2(%rip),%rdi
  mov    %eax,%r13d
  call   <printf@plt>
  mov    -0x18(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  lea    -0x10(%rbp),%rsp
  mov    %r13d,%eax
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
  nopl   (%rax)
L27:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L12
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D2
type_guessed: string

tool: D2: 
solution %d :
%s


assistant: ```c
int write_dobldobl_solution(int index) {
  int fail, nb;
  fail = solcon_length_dobldobl_solution_string(index, &nb);
  {
    char solution[nb];
    fail = solcon_write_dobldobl_solution_string(index, nb, solution);
    printf("\nsolution %d :\n%s\n", index, solution);
  }
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<yuva_to_yuvyuv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    %ecx,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  add    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  cltq
  add    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  imul   -0x18(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  nop
  leave
  ret
```

assistant: ```c
void yuva_to_yuvyuv(unsigned char *input, unsigned char *output, int width, int height) {
  memcpy(output, input, (width * height * 3) / 2);
  input += (width * height * 3) / 2;
  output += (width * height * 3) / 2;
  memcpy(output, input, width * height);
  output += width * height;
  memset(output, 0, (width * height) / 2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<yuva_to_yuvyuv>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%ebx
  imul   %ecx,%ebx
  lea    (%rbx,%rbx,2),%eax
  mov    %eax,%r12d
  shr    $0x1f,%r12d
  add    %eax,%r12d
  sar    %r12d
  mov    %r12d,%edx
  mov    %rdi,%rsi
  mov    %rbp,%rdi
  call   <memcpy@plt>
  movslq %r12d,%r12
  add    %r12,%rbp
  lea    0x0(%r13,%r12,1),%rsi
  mov    %ebx,%edx
  mov    %rbp,%rdi
  call   <memcpy@plt>
  mov    %ebx,%edx
  shr    $0x1f,%edx
  add    %ebx,%edx
  sar    %edx
  movslq %ebx,%rbx
  lea    0x0(%rbp,%rbx,1),%rdi
  mov    $0x0,%esi
  call   <memset@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void yuva_to_yuvyuv(unsigned char *input, unsigned char *output, int width, int height) {
  memcpy(output, input, (width * height * 3) / 2);
  input += (width * height * 3) / 2;
  output += (width * height * 3) / 2;
  memcpy(output, input, width * height);
  output += width * height;
  memset(output, 0, (width * height) / 2);
}
```