ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Add>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%r12
  mov    (%rsi),%ebp
  mov    (%rdi),%eax
  cmp    %eax,%ebp
  cmovl  %eax,%ebp
  lea    0x4(,%rbp,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r14d,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %ebp,(%rbx)
  test   %ebp,%ebp
  jle    L16
  lea    0x4(%rbx),%rcx
  lea    -0x1(%rbp),%eax
  lea    0x8(%rbx,%rax,4),%r9
  mov    %r13,%r8
  sub    %rbx,%r8
  mov    %r12,%rdi
  sub    %rbx,%rdi
L14:
  mov    %rcx,%rsi
  mov    (%rdi,%rcx,1),%eax
  add    (%r8,%rcx,1),%eax
  add    (%rcx),%eax
  add    $0x4,%rcx
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%edx
  add    %edx,(%rcx)
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  sar    $0x22,%rdx
  mov    %eax,%r10d
  sar    $0x1f,%r10d
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rsi)
  cmp    %r9,%rcx
  jne    L14
L16:
  mov    (%rbx),%eax
  movslq %eax,%rdx
  cmpl   $0x0,0x4(%rbx,%rdx,4)
  jle    L2
  add    $0x1,%eax
  mov    %eax,(%rbx)
L2:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *Add(int *n1, int *n2) {
  int *re;
  int i, len;
  len = n1[0] > n2[0] ? n1[0] : n2[0];
  re = (int *)malloc((len + 1) * sizeof(int));
  memset(re, 0, (len + 1) * sizeof(int));
  re[0] = len;
  for (i = 1; i <= len; i++) {
    re[i] += n1[i] + n2[i];
    re[i + 1] += re[i] / 10;
    re[i] = re[i] % 10;
  }
  if (re[re[0] + 1] > 0)
    re[0]++;
  return re;
}
```
user: What is the c source code of the assembly code below:

```asm
<Add>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%ebx
  mov    (%rdi),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  lea    0x4(,%rbx,4),%r13d
  mov    %r13d,%edi
  call   <malloc@plt>
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %ebx,(%r12)
  test   %ebx,%ebx
  jle    L24
  lea    -0x1(%rbx),%eax
  sub    %r12,%r14
  lea    0x4(%r12),%rcx
  mov    %rbp,%rdi
  lea    0x8(%r12,%rax,4),%r9
  mov    %r14,%r8
  sub    %r12,%rdi
  nopl   0x0(%rax)
L10:
  mov    (%rdi,%rcx,1),%eax
  add    (%r8,%rcx,1),%eax
  mov    %rcx,%rsi
  add    $0x4,%rcx
  add    -0x4(%rcx),%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  add    %edx,(%rcx)
  movslq %eax,%rdx
  mov    %eax,%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  sub    %edx,%eax
  mov    %eax,(%rsi)
  cmp    %rcx,%r9
  jne    L10
  mov    (%r12),%ebx
L24:
  movslq %ebx,%rax
  mov    0x4(%r12,%rax,4),%eax
  test   %eax,%eax
  jle    L4
  add    $0x1,%ebx
  mov    %ebx,(%r12)
L4:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *Add(int *n1, int *n2) {
  int *re;
  int i, len;
  len = n1[0] > n2[0] ? n1[0] : n2[0];
  re = (int *)malloc((len + 1) * sizeof(int));
  memset(re, 0, (len + 1) * sizeof(int));
  re[0] = len;
  for (i = 1; i <= len; i++) {
    re[i] += n1[i] + n2[i];
    re[i + 1] += re[i] / 10;
    re[i] = re[i] % 10;
  }
  if (re[re[0] + 1] > 0)
    re[0]++;
  return re;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<Add>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    (%rsi),%ebx
  mov    (%rdi),%eax
  cmp    %eax,%ebx
  cmovl  %eax,%ebx
  lea    0x4(,%rbx,4),%r14d
  mov    %r14d,%edi
  call   <malloc@plt>
  mov    %r14d,%edx
  xor    %esi,%esi
  mov    %rax,%r12
  mov    %rax,%rdi
  call   <memset@plt>
  mov    %ebx,(%r12)
  test   %ebx,%ebx
  jle    L23
  lea    -0x1(%rbx),%eax
  mov    %r13,%r8
  mov    %rbp,%rdi
  mov    0x4(%r12),%r10d
  lea    0x4(%r12),%rcx
  lea    0x8(%r12,%rax,4),%r9
  sub    %r12,%r8
  sub    %r12,%rdi
  nopl   0x0(%rax)
L8:
  mov    (%rdi,%rcx,1),%eax
  add    (%r8,%rcx,1),%eax
  mov    %rcx,%rsi
  add    $0x4,%rcx
  add    %r10d,%eax
  movslq %eax,%rdx
  mov    %eax,%r10d
  imul   $0x66666667,%rdx,%rdx
  sar    $0x1f,%r10d
  sar    $0x22,%rdx
  sub    %r10d,%edx
  mov    (%rcx),%r10d
  add    %edx,%r10d
  lea    (%rdx,%rdx,4),%edx
  add    %edx,%edx
  mov    %r10d,(%rcx)
  sub    %edx,%eax
  mov    %eax,(%rsi)
  cmp    %rcx,%r9
  jne    L8
  mov    (%r12),%ebx
L23:
  movslq %ebx,%rax
  mov    0x4(%r12,%rax,4),%eax
  test   %eax,%eax
  jle    L16
  add    $0x1,%ebx
  mov    %ebx,(%r12)
L16:
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int *Add(int *n1, int *n2) {
  int *re;
  int i, len;
  len = n1[0] > n2[0] ? n1[0] : n2[0];
  re = (int *)malloc((len + 1) * sizeof(int));
  memset(re, 0, (len + 1) * sizeof(int));
  re[0] = len;
  for (i = 1; i <= len; i++) {
    re[i] += n1[i] + n2[i];
    re[i + 1] += re[i] / 10;
    re[i] = re[i] % 10;
  }
  if (re[re[0] + 1] > 0)
    re[0]++;
  return re;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<cephes_bdtr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  pxor   %xmm0,%xmm0
  comisd -0x20(%rbp),%xmm0
  ja     L34
  movsd  -0x20(%rbp),%xmm0
  movsd  D3(%rip),%xmm1
  comisd %xmm1,%xmm0
  ja     L34
  cmpl   $0x0,-0x14(%rbp)
  js     L105
  mov    -0x18(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jge    L106
  jmp    L105
L34:
  nop
  jmp    L0
L105:
  nop
L0:
  mov    $0x1,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
  jmp    L92
L106:
  mov    -0x14(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jne    L19
  movsd  D3(%rip),%xmm0
  jmp    L92
L19:
  mov    -0x18(%rbp),%eax
  sub    -0x14(%rbp),%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L7
  movsd  D3(%rip),%xmm0
  subsd  -0x20(%rbp),%xmm0
  movq   %xmm0,%rax
  movsd  -0x8(%rbp),%xmm0
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x2,%eax
  call   <cephes_pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  jmp    L37
L7:
  mov    -0x14(%rbp),%eax
  add    $0x1,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movsd  D3(%rip),%xmm0
  movapd %xmm0,%xmm1
  subsd  -0x20(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  mov    -0x8(%rbp),%rax
  movapd %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  mov    $0x3,%eax
  call   <cephes_incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x10(%rbp)
L37:
  movsd  -0x10(%rbp),%xmm0
L92:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D3
type: f64
name: parse_data
arguments: data_tag: D0
type: string

tool: D3: 1

tool: D0: bdtr

assistant: ```c
double cephes_bdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if ((k < 0) || (n < k)) {
  domerr:
    mtherr("bdtr", 1);
    return (0.0);
  }
  if (k == n)
    return (1.0);
  dn = n - k;
  if (k == 0) {
    dk = cephes_pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = cephes_incbet(dn, dk, 1.0 - p);
  }
  return (dk);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<cephes_bdtr>:
  endbr64
  sub    $0x8,%rsp
  movapd %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  comisd %xmm1,%xmm0
  ja     L37
  comisd D21(%rip),%xmm1
  ja     L37
  test   %edi,%edi
  js     L37
  cmp    %esi,%edi
  jg     L37
  je     L31
  sub    %edi,%esi
  pxor   %xmm0,%xmm0
  cvtsi2sd %esi,%xmm0
  test   %edi,%edi
  jne    L49
  movsd  D21(%rip),%xmm2
  subsd  %xmm1,%xmm2
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  mov    $0x2,%eax
  call   <cephes_pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L6
L37:
  mov    $0x1,%esi
  lea    D36(%rip),%rdi
  mov    $0x0,%eax
  call   <mtherr@plt>
  pxor   %xmm0,%xmm0
L6:
  add    $0x8,%rsp
  ret
L49:
  add    $0x1,%edi
  movsd  D21(%rip),%xmm2
  subsd  %xmm1,%xmm2
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mov    $0x3,%eax
  call   <cephes_incbet@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L6
L31:
  movsd  D21(%rip),%xmm0
  jmp    L6
```

tool_calls: name: unpack_data
arguments: data_label: D21
type_guessed: f64
name: unpack_data
arguments: data_label: D36
type_guessed: string

tool: D21: 1

tool: D36: bdtr

assistant: ```c
double cephes_bdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if ((k < 0) || (n < k)) {
  domerr:
    mtherr("bdtr", 1);
    return (0.0);
  }
  if (k == n)
    return (1.0);
  dn = n - k;
  if (k == 0) {
    dk = cephes_pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = cephes_incbet(dn, dk, 1.0 - p);
  }
  return (dk);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<cephes_bdtr>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  comisd %xmm0,%xmm3
  ja     L50
  comisd D1(%rip),%xmm0
  movapd %xmm0,%xmm1
  ja     L50
  test   %edi,%edi
  js     L50
  cmp    %esi,%edi
  jg     L50
  mov    D1(%rip),%rax
  movq   %rax,%xmm2
  je     L20
  sub    %edi,%esi
  pxor   %xmm0,%xmm0
  subsd  %xmm1,%xmm2
  cvtsi2sd %esi,%xmm0
  test   %edi,%edi
  jne    L29
  movapd %xmm0,%xmm1
  mov    $0x2,%eax
  movapd %xmm2,%xmm0
  call   <cephes_pow@plt>
  pxor   %xmm2,%xmm2
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L50:
  mov    $0x1,%esi
  lea    D4(%rip),%rdi
  xor    %eax,%eax
  call   <mtherr@plt>
  pxor   %xmm2,%xmm2
L20:
  movapd %xmm2,%xmm0
  add    $0x8,%rsp
  ret
L29:
  add    $0x1,%edi
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtsi2sd %edi,%xmm1
  call   <cephes_incbet@plt>
  pxor   %xmm2,%xmm2
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D1
type: f64
name: unpack_data
arguments: data_label: D4
type: string

tool: D1: 1

tool: D4: bdtr

assistant: ```c
double cephes_bdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if ((k < 0) || (n < k)) {
  domerr:
    mtherr("bdtr", 1);
    return (0.0);
  }
  if (k == n)
    return (1.0);
  dn = n - k;
  if (k == 0) {
    dk = cephes_pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = cephes_incbet(dn, dk, 1.0 - p);
  }
  return (dk);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cephes_bdtr>:
  endbr64
  pxor   %xmm3,%xmm3
  sub    $0x8,%rsp
  comisd %xmm0,%xmm3
  ja     L6
  comisd D7(%rip),%xmm0
  movapd %xmm0,%xmm1
  ja     L6
  test   %edi,%edi
  js     L6
  cmp    %esi,%edi
  jg     L6
  mov    D7(%rip),%rax
  movq   %rax,%xmm2
  je     L14
  sub    %edi,%esi
  pxor   %xmm0,%xmm0
  subsd  %xmm1,%xmm2
  cvtsi2sd %esi,%xmm0
  test   %edi,%edi
  jne    L28
  movapd %xmm0,%xmm1
  mov    $0x2,%eax
  movapd %xmm2,%xmm0
  call   <cephes_pow@plt>
  pxor   %xmm2,%xmm2
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm2
  movapd %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  xor    %eax,%eax
  call   <mtherr@plt>
  pxor   %xmm2,%xmm2
L14:
  movapd %xmm2,%xmm0
  add    $0x8,%rsp
  ret
L28:
  add    $0x1,%edi
  pxor   %xmm1,%xmm1
  mov    $0x3,%eax
  cvtsi2sd %edi,%xmm1
  call   <cephes_incbet@plt>
  pxor   %xmm2,%xmm2
  add    $0x8,%rsp
  cvtsi2sd %eax,%xmm2
  movapd %xmm2,%xmm0
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D7
data_type: f64
name: unpack_data
arguments: data_tag: D26
data_type: string

tool: D7: 1

tool: D26: bdtr

assistant: ```c
double cephes_bdtr(k, n, p)
int k, n;
double p;
{
  double dk, dn;
  if ((p < 0.0) || (p > 1.0))
    goto domerr;
  if ((k < 0) || (n < k)) {
  domerr:
    mtherr("bdtr", 1);
    return (0.0);
  }
  if (k == n)
    return (1.0);
  dn = n - k;
  if (k == 0) {
    dk = cephes_pow(1.0 - p, dn);
  } else {
    dk = k + 1;
    dk = cephes_incbet(dn, dk, 1.0 - p);
  }
  return (dk);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<finn_vec3_forward>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  pxor   %xmm0,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  D6(%rip),%xmm0
  movss  %xmm0,(%rax)
  nop
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: tag: D6
type_guessed: byte[4]

tool: {"D6": [0x00,0x00,0x80,0x3f]}

assistant: ```c
void finn_vec3_forward(float *vec) {
  vec[0] = 0;
  vec[1] = 0;
  vec[2] = 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<finn_vec3_forward>:
  endbr64
  movl   $0x0,(%rdi)
  movl   $0x0,0x4(%rdi)
  movl   $0x3f800000,0x8(%rdi)
  ret
```

assistant: ```c
void finn_vec3_forward(float *vec) {
  vec[0] = 0;
  vec[1] = 0;
  vec[2] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<finn_vec3_forward>:
  endbr64
  movq   $0x0,(%rdi)
  movl   $0x3f800000,0x8(%rdi)
  ret
```

assistant: ```c
void finn_vec3_forward(float *vec) {
  vec[0] = 0;
  vec[1] = 0;
  vec[2] = 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<finn_vec3_forward>:
  endbr64
  movq   $0x0,(%rdi)
  movl   $0x3f800000,0x8(%rdi)
  ret
```

assistant: ```c
void finn_vec3_forward(float *vec) {
  vec[0] = 0;
  vec[1] = 0;
  vec[2] = 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<factorial>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L28
  mov    $0x1,%eax
  jmp    L25
L28:
  movl   $0x1,-0x8(%rbp)
  jmp    L39
L8:
  mov    -0x4(%rbp),%eax
  imul   -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L39:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L8
  mov    -0x4(%rbp),%eax
L25:
  pop    %rbp
  ret
```

assistant: ```c
int factorial(int num) {
  int i = 0, fact = num;
  if (num == 0)
    return 1;
  for (i = 1; i < num; i++)
    fact = fact * i;
  return fact;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<factorial>:
  endbr64
  mov    $0x1,%edx
  test   %edi,%edi
  je     L33
  cmp    $0x1,%edi
  jle    L19
  mov    %edi,%edx
  mov    $0x1,%eax
L14:
  imul   %eax,%edx
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L14
L33:
  mov    %edx,%eax
  ret
L19:
  mov    %edi,%edx
  jmp    L33
```

assistant: ```c
int factorial(int num) {
  int i = 0, fact = num;
  if (num == 0)
    return 1;
  for (i = 1; i < num; i++)
    fact = fact * i;
  return fact;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<factorial>:
  endbr64
  mov    $0x1,%r8d
  test   %edi,%edi
  je     L28
  mov    %edi,%r8d
  cmp    $0x1,%edi
  jle    L28
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L12:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L12
L28:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int factorial(int num) {
  int i = 0, fact = num;
  if (num == 0)
    return 1;
  for (i = 1; i < num; i++)
    fact = fact * i;
  return fact;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<factorial>:
  endbr64
  mov    $0x1,%r8d
  test   %edi,%edi
  je     L8
  mov    %edi,%r8d
  cmp    $0x1,%edi
  jle    L8
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L21:
  imul   %eax,%r8d
  add    $0x1,%eax
  cmp    %eax,%edi
  jne    L21
L8:
  mov    %r8d,%eax
  ret
```

assistant: ```c
int factorial(int num) {
  int i = 0, fact = num;
  if (num == 0)
    return 1;
  for (i = 1; i < num; i++)
    fact = fact * i;
  return fact;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<quickSort>:
  endbr64
  mov    %esi,%eax
  sub    %edi,%eax
  cmp    $0x1,%eax
  jle    L57
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r8d
  mov    %esi,%r12d
  mov    %rdx,%rbp
  cmp    %edi,%esi
  jle    L51
  movslq %edi,%rax
  lea    (%rdx,%rax,4),%rdi
  mov    %esi,%eax
  mov    %r8d,%ebx
  jmp    L90
L39:
  cmp    %ebx,%eax
  je     L24
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%rcx
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,4),%rsi
  mov    (%rcx),%edx
  xor    (%rsi),%edx
  mov    %edx,(%rcx)
  xor    (%rsi),%edx
  mov    %edx,(%rsi)
  xor    %edx,(%rcx)
  cmp    %ebx,%eax
  jle    L24
L90:
  movslq %ebx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
L22:
  cmp    %eax,%ebx
  jge    L39
  add    $0x1,%ebx
  mov    0x4(%rdx),%esi
  mov    (%rdi),%ecx
  add    $0x4,%rdx
  cmp    %ecx,%esi
  jl     L22
  movslq %eax,%rdx
  lea    0x0(%rbp,%rdx,4),%rdx
L14:
  cmp    %ebx,%eax
  jle    L39
  sub    $0x1,%eax
  mov    -0x4(%rdx),%esi
  sub    $0x4,%rdx
  cmp    %esi,%ecx
  jl     L14
  jmp    L39
L51:
  mov    %edi,%ebx
L24:
  lea    -0x1(%rbx),%esi
  cmp    %r8d,%esi
  je     L84
  movslq %ebx,%rax
  lea    -0x4(%rbp,%rax,4),%rdx
  movslq %r8d,%rax
  lea    0x0(%rbp,%rax,4),%rcx
  mov    (%rdx),%eax
  xor    (%rcx),%eax
  mov    %eax,(%rdx)
  xor    (%rcx),%eax
  mov    %eax,(%rcx)
  xor    %eax,(%rdx)
L84:
  mov    %rbp,%rdx
  mov    %r8d,%edi
  call   <quickSort>
  mov    %rbp,%rdx
  mov    %r12d,%esi
  mov    %ebx,%edi
  call   <quickSort>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L57:
  ret
```

assistant: ```c
void quickSort(int left, int right, int *nums) {
  if (right - left <= 1) {
    return;
  }
  int piviot = left, end = right;
  while (left < right) {
    while (left < right && nums[++left] < nums[piviot])
      ;
    while (left < right && nums[--right] > nums[piviot])
      ;
    if (left != right) {
      {
        nums[left] = nums[left] ^ nums[right];
        nums[right] = nums[left] ^ nums[right];
        nums[left] = nums[left] ^ nums[right];
      };
    }
  }
  if (left - 1 != piviot) {
    {
      nums[left - 1] = nums[left - 1] ^ nums[piviot];
      nums[piviot] = nums[left - 1] ^ nums[piviot];
      nums[left - 1] = nums[left - 1] ^ nums[piviot];
    };
  }
  quickSort(piviot, left - 1, nums);
  quickSort(left, end, nums);
}
```
user: Translate the below assembly code into C programming language:

```asm
<quickSort>:
  endbr64
  mov    %esi,%eax
  sub    %edi,%eax
  cmp    $0x1,%eax
  jle    L49
  push   %r13
  mov    %edi,%r8d
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    %r8d,%r13d
  jle    L68
L71:
  movslq %r8d,%rax
  mov    %r8d,%ebx
  mov    %rbp,%r11
  lea    (%r12,%rax,4),%r10
  mov    %r13d,%eax
L9:
  movslq %ebx,%rdx
  mov    (%r10),%esi
  lea    0x4(%r12,%rdx,4),%rdx
  jmp    L22
  nopl   (%rax)
L27:
  cmp    %esi,%ecx
  jge    L58
L22:
  mov    %ebx,%r9d
  add    $0x1,%ebx
  mov    (%rdx),%ecx
  mov    %rdx,%rdi
  add    $0x4,%rdx
  cmp    %eax,%ebx
  jl     L27
L58:
  lea    (%r12,%r11,4),%rdx
  jmp    L99
  nopl   (%rax)
L13:
  sub    $0x4,%rdx
  sub    $0x1,%eax
  cmp    (%rdx),%esi
  jge    L5
L99:
  cmp    %ebx,%eax
  jg     L13
L5:
  cmp    %ebx,%eax
  je     L124
  movslq %eax,%r11
  lea    (%r12,%r11,4),%rdx
  xor    (%rdx),%ecx
  mov    %ecx,(%rdi)
  xor    (%rdx),%ecx
  mov    %ecx,(%rdx)
  xor    %ecx,(%rdi)
  cmp    %ebx,%eax
  jg     L9
  nopl   0x0(%rax,%rax,1)
L124:
  cmp    %r9d,%r8d
  je     L75
  movslq %ebx,%rax
  lea    -0x4(%r12,%rax,4),%rdx
  movslq %r8d,%rax
  lea    (%r12,%rax,4),%rcx
  mov    (%rdx),%eax
  xor    (%rcx),%eax
  mov    %eax,(%rdx)
  xor    (%rcx),%eax
  mov    %eax,(%rcx)
  xor    %eax,(%rdx)
L75:
  mov    %r12,%rdx
  mov    %r9d,%esi
  mov    %r8d,%edi
  call   <quickSort>
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jle    L33
  mov    %ebx,%r8d
  cmp    %r8d,%r13d
  jg     L71
L68:
  lea    -0x1(%r8),%r9d
  mov    %r8d,%ebx
  jmp    L124
L33:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L49:
  ret
```

assistant: ```c
void quickSort(int left, int right, int *nums) {
  if (right - left <= 1) {
    return;
  }
  int piviot = left, end = right;
  while (left < right) {
    while (left < right && nums[++left] < nums[piviot])
      ;
    while (left < right && nums[--right] > nums[piviot])
      ;
    if (left != right) {
      {
        nums[left] = nums[left] ^ nums[right];
        nums[right] = nums[left] ^ nums[right];
        nums[left] = nums[left] ^ nums[right];
      };
    }
  }
  if (left - 1 != piviot) {
    {
      nums[left - 1] = nums[left - 1] ^ nums[piviot];
      nums[piviot] = nums[left - 1] ^ nums[piviot];
      nums[left - 1] = nums[left - 1] ^ nums[piviot];
    };
  }
  quickSort(piviot, left - 1, nums);
  quickSort(left, end, nums);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<quickSort>:
  endbr64
  mov    %esi,%eax
  sub    %edi,%eax
  cmp    $0x1,%eax
  jle    L77
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  cmp    %r14d,%r13d
  jle    L70
L87:
  movslq %r14d,%rax
  mov    %r14d,%ebx
  mov    %rbp,%r10
  lea    (%r12,%rax,4),%r9
  mov    %r13d,%eax
  xchg   %ax,%ax
L42:
  movslq %ebx,%rdx
  mov    (%r9),%esi
  lea    0x4(%r12,%rdx,4),%rdx
  jmp    L134
  nopl   (%rax)
L120:
  cmp    %esi,%ecx
  jge    L2
L134:
  mov    %ebx,%r8d
  add    $0x1,%ebx
  mov    (%rdx),%ecx
  mov    %rdx,%rdi
  add    $0x4,%rdx
  cmp    %eax,%ebx
  jl     L120
L2:
  lea    (%r12,%r10,4),%rdx
  jmp    L16
  nopl   (%rax)
L57:
  sub    $0x4,%rdx
  sub    $0x1,%eax
  cmp    (%rdx),%esi
  jge    L50
L16:
  cmp    %ebx,%eax
  jg     L57
L50:
  cmp    %ebx,%eax
  je     L36
  movslq %eax,%r10
  lea    (%r12,%r10,4),%rdx
  xor    (%rdx),%ecx
  mov    %ecx,(%rdi)
  xor    (%rdx),%ecx
  mov    %ecx,(%rdx)
  xor    %ecx,(%rdi)
  cmp    %ebx,%eax
  jg     L42
  nopl   0x0(%rax,%rax,1)
L36:
  cmp    %r8d,%r14d
  je     L22
  movslq %ebx,%rax
  lea    -0x4(%r12,%rax,4),%rdx
  movslq %r14d,%rax
  lea    (%r12,%rax,4),%rcx
  mov    (%rdx),%eax
  xor    (%rcx),%eax
  mov    %eax,(%rdx)
  xor    (%rcx),%eax
  mov    %eax,(%rcx)
  xor    %eax,(%rdx)
L22:
  mov    %r12,%rdx
  mov    %r8d,%esi
  mov    %r14d,%edi
  call   <quickSort>
  mov    %r13d,%eax
  sub    %ebx,%eax
  cmp    $0x1,%eax
  jle    L59
  cmp    %r14d,%r13d
  jle    1040 <quickSort.cold>
  mov    %ebx,%r14d
  cmp    %r14d,%r13d
  jg     L87
L70:
  lea    -0x1(%r14),%r8d
  mov    %r14d,%ebx
  jmp    L36
L59:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L77:
  ret
```

assistant: ```c
void quickSort(int left, int right, int *nums) {
  if (right - left <= 1) {
    return;
  }
  int piviot = left, end = right;
  while (left < right) {
    while (left < right && nums[++left] < nums[piviot])
      ;
    while (left < right && nums[--right] > nums[piviot])
      ;
    if (left != right) {
      {
        nums[left] = nums[left] ^ nums[right];
        nums[right] = nums[left] ^ nums[right];
        nums[left] = nums[left] ^ nums[right];
      };
    }
  }
  if (left - 1 != piviot) {
    {
      nums[left - 1] = nums[left - 1] ^ nums[piviot];
      nums[piviot] = nums[left - 1] ^ nums[piviot];
      nums[left - 1] = nums[left - 1] ^ nums[piviot];
    };
  }
  quickSort(piviot, left - 1, nums);
  quickSort(left, end, nums);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<copy_quaddobl_container_to_start_system>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    -0x8(%rbp),%rcx
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rsi
  mov    $0x108,%edi
  call   <_ada_use_c2phc4c@plt>
  mov    %eax,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int copy_quaddobl_container_to_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(264, a, b, c, 0);
  return fail;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<copy_quaddobl_container_to_start_system>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%r8d
  mov    $0x0,%ecx
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    $0x108,%edi
  call   <_ada_use_c2phc4c@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int copy_quaddobl_container_to_start_system(void) {
  int *a, *b, fail;
  double *c;
  fail = _ada_use_c2phc4c(264, a, b, c, 0);
  return fail;
}
```