ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<_gmm_vec_divide_by_scalar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movsd  %xmm0,-0x20(%rbp)
  mov    %esi,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L5
L17:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  divsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x4(%rbp)
L5:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L17
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _gmm_vec_divide_by_scalar(double *x, double a, int D) {
  for (int i = 0; i < D; i++)
    x[i] = x[i] / a;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_gmm_vec_divide_by_scalar>:
  endbr64
  test   %esi,%esi
  jle    L18
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x8(%rdi,%rdx,8),%rdx
L4:
  movsd  (%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L4
L18:
  ret
```

assistant: ```c
void _gmm_vec_divide_by_scalar(double *x, double a, int D) {
  for (int i = 0; i < D; i++)
    x[i] = x[i] / a;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_gmm_vec_divide_by_scalar>:
  endbr64
  test   %esi,%esi
  jle    L9
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
L6:
  movsd  (%rdi),%xmm1
  add    $0x8,%rdi
  divsd  %xmm0,%xmm1
  movsd  %xmm1,-0x8(%rdi)
  cmp    %rax,%rdi
  jne    L6
L9:
  ret
```

assistant: ```c
void _gmm_vec_divide_by_scalar(double *x, double a, int D) {
  for (int i = 0; i < D; i++)
    x[i] = x[i] / a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_gmm_vec_divide_by_scalar>:
  endbr64
  test   %esi,%esi
  jle    L22
  cmp    $0x1,%esi
  je     L11
  mov    %esi,%edx
  movapd %xmm0,%xmm2
  mov    %rdi,%rax
  shr    %edx
  unpcklpd %xmm2,%xmm2
  sub    $0x1,%edx
  shl    $0x4,%rdx
  lea    0x10(%rdi,%rdx,1),%rdx
  nopl   0x0(%rax,%rax,1)
L49:
  movupd (%rax),%xmm1
  add    $0x10,%rax
  divpd  %xmm2,%xmm1
  movups %xmm1,-0x10(%rax)
  cmp    %rdx,%rax
  jne    L49
  mov    %esi,%eax
  and    $0xfffffffe,%eax
  and    $0x1,%esi
  je     L2
L13:
  cltq
  lea    (%rdi,%rax,8),%rax
  movsd  (%rax),%xmm1
  divsd  %xmm0,%xmm1
  movsd  %xmm1,(%rax)
L22:
  ret
  nopw   0x0(%rax,%rax,1)
L2:
  ret
L11:
  xor    %eax,%eax
  jmp    L13
```

assistant: ```c
void _gmm_vec_divide_by_scalar(double *x, double a, int D) {
  for (int i = 0; i < D; i++)
    x[i] = x[i] / a;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_argc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    %edx,-0xc(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  cmp    -0x8(%rbp),%eax
  jge    L1
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L0
L1:
  mov    -0x4(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L39
  mov    $0x0,%eax
  call   <print_too_many_args@plt>
  mov    $0xffffffff,%eax
  jmp    L0
L39:
  mov    $0x0,%eax
L0:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
data_type: string
name: unpack_data
arguments: tag: D17
data_type: string

tool: D4: *** argument missing:

tool: D17: usage: %s


assistant: ```c
int check_argc(int argc, int lower, int upper, char *usage) {
  if (argc < lower) {
    printf("*** argument missing:\n");
    printf("usage: %s\n", usage);
    return -1;
  }
  if (argc > upper) {
    print_too_many_args();
    return -1;
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<check_argc>:
  endbr64
  push   %rbx
  cmp    %esi,%edi
  jl     L33
  cmp    %edx,%edi
  jg     L7
  mov    $0x0,%eax
L20:
  pop    %rbx
  ret
L33:
  mov    %rcx,%rbx
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    %rbx,%rsi
  lea    D11(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L20
L7:
  mov    $0x0,%eax
  call   <print_too_many_args@plt>
  mov    $0xffffffff,%eax
  jmp    L20
```

tool_calls: name: read_data
arguments: label: D14
data_type: string
name: read_data
arguments: label: D11
data_type: string

tool: D14: *** argument missing:

tool: D11: usage: %s


assistant: ```c
int check_argc(int argc, int lower, int upper, char *usage) {
  if (argc < lower) {
    printf("*** argument missing:\n");
    printf("usage: %s\n", usage);
    return -1;
  }
  if (argc > upper) {
    print_too_many_args();
    return -1;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<check_argc>:
  endbr64
  sub    $0x18,%rsp
  cmp    %esi,%edi
  jl     L24
  cmp    %edx,%edi
  jg     L28
  xor    %eax,%eax
L0:
  add    $0x18,%rsp
  ret
L24:
  lea    D4(%rip),%rdi
  mov    %rcx,0x8(%rsp)
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L0
L28:
  xor    %eax,%eax
  call   <print_too_many_args@plt>
  mov    $0xffffffff,%eax
  jmp    L0
```

tool_calls: name: disassemble_data
arguments: data_tag: D4
type_infered: string
name: disassemble_data
arguments: data_tag: D6
type_infered: string

tool: D4: *** argument missing:

tool: D6: usage: %s


assistant: ```c
int check_argc(int argc, int lower, int upper, char *usage) {
  if (argc < lower) {
    printf("*** argument missing:\n");
    printf("usage: %s\n", usage);
    return -1;
  }
  if (argc > upper) {
    print_too_many_args();
    return -1;
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<check_argc>:
  endbr64
  sub    $0x18,%rsp
  cmp    %esi,%edi
  jl     L23
  cmp    %edx,%edi
  jg     L12
  xor    %eax,%eax
L5:
  add    $0x18,%rsp
  ret
L23:
  lea    D9(%rip),%rdi
  mov    %rcx,0x8(%rsp)
  call   <puts@plt>
  mov    0x8(%rsp),%rsi
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0xffffffff,%eax
  jmp    L5
L12:
  xor    %eax,%eax
  call   <print_too_many_args@plt>
  mov    $0xffffffff,%eax
  jmp    L5
```

tool_calls: name: unpack_data
arguments: tag: D9
type: string
name: unpack_data
arguments: tag: D16
type: string

tool: D9: *** argument missing:

tool: D16: usage: %s


assistant: ```c
int check_argc(int argc, int lower, int upper, char *usage) {
  if (argc < lower) {
    printf("*** argument missing:\n");
    printf("usage: %s\n", usage);
    return -1;
  }
  if (argc > upper) {
    print_too_many_args();
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x65,-0x50(%rbp)
  movl   $0x6,-0x4c(%rbp)
  movl   $0x4,-0x48(%rbp)
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x38(%rbp)
  movl   $0x1,-0x44(%rbp)
  movl   $0xffffffff,-0x40(%rbp)
  lea    -0x50(%rbp),%rax
  mov    %rax,%rdi
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  jne    L20
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x1,-0x54(%rbp)
  jmp    L9
L20:
  lea    -0x50(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rdx,%rcx
  lea    D21(%rip),%rdx
  mov    $0x14,%esi
  mov    %rax,%rdi
  call   <strftime@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  lea    -0x20(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    %eax,-0x54(%rbp)
L9:
  mov    -0x54(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D21
data_type: string
name: retrieve_data
arguments: label: D25
data_type: string

tool: D14: -unknown-

tool: D21: %A

tool: D25: Wednesday

assistant: ```c
int main(void) {
  struct tm time_str;
  char daybuf[20];
  int result;
  time_str.tm_year = 2001 - 1900;
  time_str.tm_mon = 7 - 1;
  time_str.tm_mday = 4;
  time_str.tm_hour = 0;
  time_str.tm_min = 0;
  time_str.tm_sec = 1;
  time_str.tm_isdst = -1;
  if (mktime(&time_str) == -1) {
    (void)puts("-unknown-");
    result = 1;
  } else {
    (void)strftime(daybuf, sizeof(daybuf), "%A", &time_str);
    (void)puts(daybuf);
    result = strcmp(daybuf, "Wednesday") != 0;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  movl   $0x65,(%rsp)
  movl   $0x6,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x18(%rsp)
  movl   $0x1,0xc(%rsp)
  movl   $0xffffffff,0x10(%rsp)
  mov    %rsp,%rdi
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  je     L2
  mov    %rsp,%rcx
  lea    0x30(%rsp),%rbx
  lea    D3(%rip),%rdx
  mov    $0x14,%esi
  mov    %rbx,%rdi
  call   <strftime@plt>
  mov    %rbx,%rdi
  call   <puts@plt>
  lea    D0(%rip),%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L20:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x50,%rsp
  pop    %rbx
  ret
L2:
  lea    D14(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L20
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D3
type: string
name: disassemble_data
arguments: label: D0
type: string
name: disassemble_data
arguments: label: D14
type: string

tool: D3: %A

tool: D0: Wednesday

tool: D14: -unknown-

assistant: ```c
int main(void) {
  struct tm time_str;
  char daybuf[20];
  int result;
  time_str.tm_year = 2001 - 1900;
  time_str.tm_mon = 7 - 1;
  time_str.tm_mday = 4;
  time_str.tm_hour = 0;
  time_str.tm_min = 0;
  time_str.tm_sec = 1;
  time_str.tm_isdst = -1;
  if (mktime(&time_str) == -1) {
    (void)puts("-unknown-");
    result = 1;
  } else {
    (void)strftime(daybuf, sizeof(daybuf), "%A", &time_str);
    (void)puts(daybuf);
    result = strcmp(daybuf, "Wednesday") != 0;
  }
  return result;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movl   $0xffffffff,0x10(%rsp)
  movabs $0x600000065,%rax
  mov    %rax,(%rsp)
  mov    %r12,%rdi
  movabs $0x100000004,%rax
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x18(%rsp)
  mov    %rax,0x8(%rsp)
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  je     L13
  lea    0x30(%rsp),%rbp
  mov    %r12,%rcx
  mov    $0x14,%esi
  lea    D23(%rip),%rdx
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D18(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L16:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
L13:
  lea    D21(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L16
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D23
data_type: string
name: read_data
arguments: tag: D18
data_type: string
name: read_data
arguments: tag: D21
data_type: string

tool: D23: %A

tool: D18: Wednesday

tool: D21: -unknown-

assistant: ```c
int main(void) {
  struct tm time_str;
  char daybuf[20];
  int result;
  time_str.tm_year = 2001 - 1900;
  time_str.tm_mon = 7 - 1;
  time_str.tm_mday = 4;
  time_str.tm_hour = 0;
  time_str.tm_min = 0;
  time_str.tm_sec = 1;
  time_str.tm_isdst = -1;
  if (mktime(&time_str) == -1) {
    (void)puts("-unknown-");
    result = 1;
  } else {
    (void)strftime(daybuf, sizeof(daybuf), "%A", &time_str);
    (void)puts(daybuf);
    result = strcmp(daybuf, "Wednesday") != 0;
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  pxor   %xmm0,%xmm0
  push   %rbp
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  movups %xmm0,0x18(%rsp)
  movdqa D26(%rip),%xmm0
  mov    %r12,%rdi
  movl   $0xffffffff,0x10(%rsp)
  movaps %xmm0,(%rsp)
  call   <mktime@plt>
  cmp    $0xffffffff,%eax
  je     L11
  lea    0x30(%rsp),%rbp
  mov    %r12,%rcx
  mov    $0x14,%esi
  lea    D27(%rip),%rdx
  mov    %rbp,%rdi
  call   <strftime@plt>
  mov    %rbp,%rdi
  call   <puts@plt>
  lea    D22(%rip),%rsi
  mov    %rbp,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
L22:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x58,%rsp
  pop    %rbp
  pop    %r12
  ret
L11:
  lea    D7(%rip),%rdi
  call   <puts@plt>
  mov    $0x1,%eax
  jmp    L22
L8:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D26
type_infered: byte[16]
name: disassemble_data
arguments: data_label: D27
type_infered: string
name: disassemble_data
arguments: data_label: D22
type_infered: string
name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: {"D26": [0x65,0x00,0x00,0x00,0x06,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D27: %A

tool: D22: Wednesday

tool: D7: -unknown-

assistant: ```c
int main(void) {
  struct tm time_str;
  char daybuf[20];
  int result;
  time_str.tm_year = 2001 - 1900;
  time_str.tm_mon = 7 - 1;
  time_str.tm_mday = 4;
  time_str.tm_hour = 0;
  time_str.tm_min = 0;
  time_str.tm_sec = 1;
  time_str.tm_isdst = -1;
  if (mktime(&time_str) == -1) {
    (void)puts("-unknown-");
    result = 1;
  } else {
    (void)strftime(daybuf, sizeof(daybuf), "%A", &time_str);
    (void)puts(daybuf);
    result = strcmp(daybuf, "Wednesday") != 0;
  }
  return result;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<strcpy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strcpy(char *restrict dst, const char *restrict src) {
  const size_t length = strlen(src);
  memcpy(dst, src, length + 1);
  return dst;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strcpy>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdx
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strcpy(char *restrict dst, const char *restrict src) {
  const size_t length = strlen(src);
  memcpy(dst, src, length + 1);
  return dst;
}
```
user: What is the c source code of the assembly code below:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *restrict dst, const char *restrict src) {
  const size_t length = strlen(src);
  memcpy(dst, src, length + 1);
  return dst;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strcpy>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  lea    0x1(%rax),%rdx
  call   <memcpy@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *strcpy(char *restrict dst, const char *restrict src) {
  const size_t length = strlen(src);
  memcpy(dst, src, length + 1);
  return dst;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<vasprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x8(%rbp),%edx
  mov    -0x20(%rbp),%rax
  mov    %edx,%ecx
  mov    %rax,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <smb_vsnprintf@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jg     L32
  mov    -0x4(%rbp),%eax
  jmp    L13
L32:
  mov    -0x4(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L29
  mov    $0xffffffff,%eax
  jmp    L13
L29:
  mov    -0x24(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <va_copy@plt>
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x8(%rbp),%ecx
  mov    -0x20(%rbp),%rdx
  mov    %rax,%rdi
  call   <smb_vsnprintf@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
L13:
  leave
  ret
```

assistant: ```c
int vasprintf(char **ptr, const char *format, va_list ap) {
  int ret;
  va_list ap2;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(NULL, 0, format, ap2);
  if (ret <= 0)
    return ret;
  (*ptr) = (char *)malloc(ret + 1);
  if (!*ptr)
    return -1;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(*ptr, ret + 1, format, ap2);
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<vasprintf>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %edx,%r12d
  mov    %edx,%esi
  mov    $0x0,%r14d
  mov    %r14d,%edi
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <smb_vsnprintf@plt>
  test   %eax,%eax
  jle    L22
  lea    0x1(%rax),%ebx
  mov    %ebx,%edi
  call   <malloc@plt>
  mov    %rax,0x0(%r13)
  test   %rax,%rax
  je     L14
  mov    %r12d,%esi
  mov    %r14d,%edi
  call   <va_copy@plt>
  mov    %r14d,%ecx
  mov    %rbp,%rdx
  mov    %ebx,%esi
  mov    0x0(%r13),%rdi
  call   <smb_vsnprintf@plt>
L22:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L14:
  mov    $0xffffffff,%eax
  jmp    L22
```

assistant: ```c
int vasprintf(char **ptr, const char *format, va_list ap) {
  int ret;
  va_list ap2;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(NULL, 0, format, ap2);
  if (ret <= 0)
    return ret;
  (*ptr) = (char *)malloc(ret + 1);
  if (!*ptr)
    return -1;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(*ptr, ret + 1, format, ap2);
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<vasprintf>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%esi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  call   <va_copy@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  call   <smb_vsnprintf@plt>
  test   %eax,%eax
  jle    L18
  lea    0x1(%rax),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L19
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <va_copy@plt>
  mov    (%rbx),%rdi
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r13,%rdx
  mov    %ebp,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <smb_vsnprintf@plt>
L19:
  mov    $0xffffffff,%eax
L18:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vasprintf(char **ptr, const char *format, va_list ap) {
  int ret;
  va_list ap2;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(NULL, 0, format, ap2);
  if (ret <= 0)
    return ret;
  (*ptr) = (char *)malloc(ret + 1);
  if (!*ptr)
    return -1;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(*ptr, ret + 1, format, ap2);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<vasprintf>:
  endbr64
  push   %r14
  mov    %edx,%r14d
  push   %r13
  mov    %rsi,%r13
  mov    %edx,%esi
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %r12d,%edi
  call   <va_copy@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %r12d,%ecx
  mov    %r13,%rdx
  call   <smb_vsnprintf@plt>
  test   %eax,%eax
  jle    L14
  lea    0x1(%rax),%ebp
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  je     L11
  mov    %r14d,%esi
  mov    %r12d,%edi
  call   <va_copy@plt>
  mov    (%rbx),%rdi
  mov    %r12d,%ecx
  pop    %rbx
  mov    %r13,%rdx
  mov    %ebp,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1090 <smb_vsnprintf@plt>
L11:
  mov    $0xffffffff,%eax
L14:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int vasprintf(char **ptr, const char *format, va_list ap) {
  int ret;
  va_list ap2;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(NULL, 0, format, ap2);
  if (ret <= 0)
    return ret;
  (*ptr) = (char *)malloc(ret + 1);
  if (!*ptr)
    return -1;
  va_copy(ap2, ap);
  ret = smb_vsnprintf(*ptr, ret + 1, format, ap2);
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<iter>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L10:
  mov    -0x4(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  add    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L10
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int iter(int N) {
  int sum = 0;
  for (int i = 0; i < N; i++)
    sum += 1 + 2 * (i);
  return sum;
}
```
user: What is the c source code of the assembly code below:

```asm
<iter>:
  endbr64
  test   %edi,%edi
  jle    L6
  lea    0x1(%rdi,%rdi,1),%ecx
  mov    $0x1,%eax
  mov    $0x0,%edx
L20:
  add    %eax,%edx
  add    $0x2,%eax
  cmp    %ecx,%eax
  jne    L20
L4:
  mov    %edx,%eax
  ret
L6:
  mov    $0x0,%edx
  jmp    L4
```

assistant: ```c
int iter(int N) {
  int sum = 0;
  for (int i = 0; i < N; i++)
    sum += 1 + 2 * (i);
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<iter>:
  endbr64
  test   %edi,%edi
  jle    L8
  lea    0x1(%rdi,%rdi,1),%edx
  mov    $0x1,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L0:
  add    %eax,%r8d
  add    $0x2,%eax
  cmp    %edx,%eax
  jne    L0
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L8:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int iter(int N) {
  int sum = 0;
  for (int i = 0; i < N; i++)
    sum += 1 + 2 * (i);
  return sum;
}
```