ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x0,-0x18(%rbp)
  jmp    L56
L81:
  cmpq   $0x0,-0x18(%rbp)
  je     L48
  mov    $0xa,%edi
  call   <putchar@plt>
L48:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D44(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  jns    L110
  mov    -0x30(%rbp),%rax
  neg    %rax
  mov    %rax,-0x30(%rbp)
L110:
  mov    -0x30(%rbp),%rax
  test   %rax,%rax
  jne    L75
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  jmp    L76
L75:
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <sqrt@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    $0x1,%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  mov    %rax,-0x10(%rbp)
  jmp    L86
L50:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,-0x10(%rbp)
L86:
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jl     L50
  mov    -0x30(%rbp),%rax
  cmp    %rax,-0x10(%rbp)
  jne    L9
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L76
L83:
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  add    %rax,-0x10(%rbp)
L9:
  mov    -0x30(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  sub    %rdx,%rax
  and    $0x1,%eax
  test   %rax,%rax
  jne    L83
  mov    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L76:
  addq   $0x1,-0x18(%rbp)
L56:
  mov    -0x28(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jl     L81
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L63
  call   <__stack_chk_fail@plt>
L63:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D44
type_infered: string
name: retrieve_data
arguments: data_tag: D29
type_infered: string
name: retrieve_data
arguments: data_tag: D18
type_infered: string

tool: D44: %lld

tool: D29: 3

tool: D18: %lld


assistant: ```c
main() {
  long long k, n, i, j, sum, m;
  scanf("%lld", &m);
  for (i = 0; i < m; i++) {
    if (i)
      putchar('\n');
    scanf("%lld", &k);
    if (k < 0)
      k = -k;
    if (k == 0) {
      printf("3\n");
      continue;
    }
    n = (long long)sqrt(k);
    sum = (n + 1) * n / 2;
    while (k > sum) {
      n++;
      sum += n;
    }
    if (sum == k)
      printf("%lld\n", n);
    else {
      while ((sum - k) % 2 != 0) {
        n++;
        sum += n;
      }
      printf("%lld\n", n);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    D34(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    0x8(%rsp),%r12
  lea    D34(%rip),%rbp
  lea    D27(%rip),%r14
  lea    D37(%rip),%r13
  cmpq   $0x0,0x10(%rsp)
  jg     L128
L30:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L122
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L73:
  mov    $0xa,%edi
  call   <putchar@plt>
L128:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  js     L72
  jne    L96
  mov    %r13,%rdi
  call   <puts@plt>
L127:
  add    $0x1,%rbx
  cmp    %rbx,0x10(%rsp)
  jle    L30
  test   %rbx,%rbx
  je     L128
  jmp    L73
L72:
  neg    %rdi
  mov    %rdi,0x8(%rsp)
L96:
  call   <sqrt@plt>
  mov    %rax,%rsi
  lea    0x1(%rax),%rax
  imul   %rsi,%rax
  mov    %rax,%rcx
  shr    $0x3f,%rcx
  add    %rax,%rcx
  sar    %rcx
  mov    %rcx,%rax
  mov    0x8(%rsp),%rdx
  cmp    %rdx,%rcx
  jge    L4
L84:
  add    $0x1,%rsi
  add    %rsi,%rax
  cmp    %rdx,%rax
  jl     L84
L4:
  cmp    %rax,%rdx
  je     L121
  mov    %rax,%rcx
  sub    %rdx,%rcx
  test   $0x1,%cl
  je     L86
L23:
  add    $0x1,%rsi
  add    %rsi,%rax
  mov    %rax,%rcx
  sub    %rdx,%rcx
  test   $0x1,%cl
  jne    L23
L86:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L127
L121:
  mov    %r14,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L127
L122:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D34
type_infered: string
name: unpack_data
arguments: tag: D27
type_infered: string
name: unpack_data
arguments: tag: D37
type_infered: string

tool: D34: %lld

tool: D27: %lld


tool: D37: 3

assistant: ```c
main() {
  long long k, n, i, j, sum, m;
  scanf("%lld", &m);
  for (i = 0; i < m; i++) {
    if (i)
      putchar('\n');
    scanf("%lld", &k);
    if (k < 0)
      k = -k;
    if (k == 0) {
      printf("3\n");
      continue;
    }
    n = (long long)sqrt(k);
    sum = (n + 1) * n / 2;
    while (k > sum) {
      n++;
      sum += n;
    }
    if (sum == k)
      printf("%lld\n", n);
    else {
      while ((sum - k) % 2 != 0) {
        n++;
        sum += n;
      }
      printf("%lld\n", n);
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r14
  lea    D12(%rip),%r14
  push   %r13
  lea    D22(%rip),%r13
  push   %r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
  cmpq   $0x0,0x10(%rsp)
  jg     L10
  jmp    L89
  cs nopw 0x0(%rax,%rax,1)
L115:
  jne    L9
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbx,0x10(%rsp)
  jle    L89
L121:
  mov    $0xa,%edi
  call   <putchar@plt>
L10:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  jns    L115
  neg    %rdi
  mov    %rdi,0x8(%rsp)
L9:
  call   <sqrt@plt>
  lea    0x1(%rax),%rcx
  mov    %rax,%rsi
  mov    %rcx,%rax
  imul   %rsi,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rax,%rdx
  mov    0x8(%rsp),%rax
  sar    %rdx
  cmp    %rax,%rdx
  jl     L7
  jmp    L36
  nopl   0x0(%rax)
L86:
  add    $0x1,%rcx
L7:
  add    %rcx,%rdx
  mov    %rcx,%rsi
  cmp    %rax,%rdx
  jl     L86
L36:
  cmp    %rdx,%rax
  jne    L28
  jmp    L54
  cs nopw 0x0(%rax,%rax,1)
L124:
  add    $0x1,%rsi
  add    %rsi,%rdx
L28:
  mov    %rdx,%rcx
  sub    %rax,%rcx
  and    $0x1,%ecx
  jne    L124
L54:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,0x10(%rsp)
  jg     L121
L89:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L107
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L107:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D12
type: string
name: read_data
arguments: data_label: D22
type: string
name: read_data
arguments: data_label: D18
type: string

tool: D12: %lld


tool: D22: 3

tool: D18: %lld

assistant: ```c
main() {
  long long k, n, i, j, sum, m;
  scanf("%lld", &m);
  for (i = 0; i < m; i++) {
    if (i)
      putchar('\n');
    scanf("%lld", &k);
    if (k < 0)
      k = -k;
    if (k == 0) {
      printf("3\n");
      continue;
    }
    n = (long long)sqrt(k);
    sum = (n + 1) * n / 2;
    while (k > sum) {
      n++;
      sum += n;
    }
    if (sum == k)
      printf("%lld\n", n);
    else {
      while ((sum - k) % 2 != 0) {
        n++;
        sum += n;
      }
      printf("%lld\n", n);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r14
  lea    D23(%rip),%r14
  push   %r13
  lea    D29(%rip),%r13
  push   %r12
  push   %rbp
  lea    D12(%rip),%rbp
  push   %rbx
  mov    %rbp,%rdi
  xor    %ebx,%ebx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rsi
  lea    0x8(%rsp),%r12
  call   <scanf@plt>
  cmpq   $0x0,0x10(%rsp)
  jg     L111
  jmp    L129
  cs nopw 0x0(%rax,%rax,1)
L128:
  jne    L69
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <puts@plt>
  cmp    %rbx,0x10(%rsp)
  jle    L129
L21:
  mov    $0xa,%edi
  call   <putchar@plt>
L111:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <scanf@plt>
  mov    0x8(%rsp),%rdi
  test   %rdi,%rdi
  jns    L128
  neg    %rdi
  mov    %rdi,0x8(%rsp)
L69:
  call   <sqrt@plt>
  lea    0x1(%rax),%rcx
  mov    %rax,%rsi
  mov    %rcx,%rax
  imul   %rsi,%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rax,%rdx
  mov    0x8(%rsp),%rax
  sar    %rdx
  cmp    %rax,%rdx
  jl     L7
  jmp    L101
  nopl   0x0(%rax)
L58:
  add    $0x1,%rcx
L7:
  add    %rcx,%rdx
  mov    %rcx,%rsi
  cmp    %rax,%rdx
  jl     L58
L101:
  cmp    %rdx,%rax
  jne    L122
  jmp    L54
  cs nopw 0x0(%rax,%rax,1)
L90:
  add    $0x1,%rsi
  add    %rsi,%rdx
L122:
  mov    %rdx,%rcx
  sub    %rax,%rcx
  and    $0x1,%ecx
  jne    L90
L54:
  mov    %r14,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,0x10(%rsp)
  jg     L21
L129:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L104
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L104:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D23
type: string
name: read_data
arguments: tag: D29
type: string
name: read_data
arguments: tag: D12
type: string

tool: D23: %lld


tool: D29: 3

tool: D12: %lld

assistant: ```c
main() {
  long long k, n, i, j, sum, m;
  scanf("%lld", &m);
  for (i = 0; i < m; i++) {
    if (i)
      putchar('\n');
    scanf("%lld", &k);
    if (k < 0)
      k = -k;
    if (k == 0) {
      printf("3\n");
      continue;
    }
    n = (long long)sqrt(k);
    sum = (n + 1) * n / 2;
    while (k > sum) {
      n++;
      sum += n;
    }
    if (sum == k)
      printf("%lld\n", n);
    else {
      while ((sum - k) % 2 != 0) {
        n++;
        sum += n;
      }
      printf("%lld\n", n);
    }
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D23(%rip),%rdi
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D16(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    D30(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rsi
  lea    D35(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  ja     L122
  comiss %xmm0,%xmm1
  jb     L127
  comiss 0x8(%rsp),%xmm0
  jae    L125
L127:
  movss  0x8(%rsp),%xmm1
  comiss %xmm0,%xmm1
  jb     L19
  comiss 0xc(%rsp),%xmm0
  jae    L34
L19:
  movss  0xc(%rsp),%xmm1
  comiss %xmm0,%xmm1
  jb     L94
  comiss 0x10(%rsp),%xmm0
  jae    L123
L94:
  movss  0x10(%rsp),%xmm1
  comiss %xmm0,%xmm1
  jbe    L116
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L122:
  lea    D12(%rip),%rdi
  call   <printf@plt>
L116:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L125:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L34:
  lea    D60(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L123:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L116
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D23
type_infered: string
name: retrieve_data
arguments: tag: D16
type_infered: string
name: retrieve_data
arguments: tag: D30
type_infered: string
name: retrieve_data
arguments: tag: D35
type_infered: string
name: retrieve_data
arguments: tag: D4
type_infered: string
name: retrieve_data
arguments: tag: D12
type_infered: string
name: retrieve_data
arguments: tag: D45
type_infered: string
name: retrieve_data
arguments: tag: D60
type_infered: string
name: retrieve_data
arguments: tag: D11
type_infered: string

tool: D23: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D16: %f%f%f%f

tool: D30: Thank you. Now enter student score (percent) >

tool: D35: %f

tool: D4: Student has failed that course


tool: D12: Student has an A grade


tool: D45: Student has an B grade


tool: D60: Student has an C grade


tool: D11: Student has an D grade


assistant: ```c
int main(void) {
  float a, b, c, d;
  float percent;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &percent);
  if (percent > a)
    printf("Student has an A grade\n");
  else if (percent <= a && percent >= b)
    printf("Student has an B grade\n");
  else if (percent <= b && percent >= c)
    printf("Student has an C grade\n");
  else if (percent <= c && percent >= d)
    printf("Student has an D grade\n");
  else if (percent < d)
    printf("Student has failed that course\n");
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D89(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D73(%rip),%rdi
  call   <scanf@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D67(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  ja     L24
  comiss %xmm0,%xmm1
  movss  0x8(%rsp),%xmm2
  jb     L1
  comiss %xmm2,%xmm0
  jae    L101
L1:
  comiss %xmm0,%xmm2
  movss  0xc(%rsp),%xmm1
  jae    L6
L137:
  comiss %xmm0,%xmm1
  movss  0x10(%rsp),%xmm2
  jb     L13
  comiss %xmm2,%xmm0
  jae    L34
L13:
  comiss %xmm0,%xmm2
  ja     L43
L10:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L80
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L6:
  comiss %xmm1,%xmm0
  jb     L137
  lea    D61(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L24:
  lea    D20(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L101:
  lea    D79(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L34:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L43:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L10
L80:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D89
type: string
name: unpack_data
arguments: tag: D73
type: string
name: unpack_data
arguments: tag: D8
type: string
name: unpack_data
arguments: tag: D67
type: string
name: unpack_data
arguments: tag: D61
type: string
name: unpack_data
arguments: tag: D20
type: string
name: unpack_data
arguments: tag: D79
type: string
name: unpack_data
arguments: tag: D31
type: string
name: unpack_data
arguments: tag: D62
type: string

tool: D89: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D73: %f%f%f%f

tool: D8: Thank you. Now enter student score (percent) >

tool: D67: %f

tool: D61: Student has an C grade


tool: D20: Student has an A grade


tool: D79: Student has an B grade


tool: D31: Student has an D grade


tool: D62: Student has failed that course


assistant: ```c
int main(void) {
  float a, b, c, d;
  float percent;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &percent);
  if (percent > a)
    printf("Student has an A grade\n");
  else if (percent <= a && percent >= b)
    printf("Student has an B grade\n");
  else if (percent <= b && percent >= c)
    printf("Student has an C grade\n");
  else if (percent <= c && percent >= d)
    printf("Student has an D grade\n");
  else if (percent < d)
    printf("Student has failed that course\n");
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D40(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0xc(%rsp),%rcx
  lea    0x8(%rsp),%rdx
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  lea    0x10(%rsp),%r8
  lea    D16(%rip),%rdi
  call   <scanf@plt>
  lea    D57(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  movss  0x14(%rsp),%xmm0
  movss  0x4(%rsp),%xmm1
  comiss %xmm1,%xmm0
  ja     L48
  comiss %xmm0,%xmm1
  movss  0x8(%rsp),%xmm2
  jb     L125
  comiss %xmm2,%xmm0
  jae    L104
L125:
  comiss %xmm0,%xmm2
  movss  0xc(%rsp),%xmm1
  jae    L38
L22:
  comiss %xmm0,%xmm1
  movss  0x10(%rsp),%xmm2
  jb     L102
  comiss %xmm2,%xmm0
  jae    L35
L102:
  comiss %xmm0,%xmm2
  ja     L109
L138:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L38:
  comiss %xmm1,%xmm0
  jb     L22
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L138
L48:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L138
L104:
  lea    D26(%rip),%rdi
  call   <printf@plt>
  jmp    L138
L35:
  lea    D11(%rip),%rdi
  call   <printf@plt>
  jmp    L138
L109:
  lea    D44(%rip),%rdi
  call   <printf@plt>
  jmp    L138
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D40
type_infered: string
name: parse_data
arguments: tag: D16
type_infered: string
name: parse_data
arguments: tag: D57
type_infered: string
name: parse_data
arguments: tag: D10
type_infered: string
name: parse_data
arguments: tag: D0
type_infered: string
name: parse_data
arguments: tag: D19
type_infered: string
name: parse_data
arguments: tag: D26
type_infered: string
name: parse_data
arguments: tag: D11
type_infered: string
name: parse_data
arguments: tag: D44
type_infered: string

tool: D40: Enter thresholds for A, B, C, D
in that order, decreasing percentages > 

tool: D16: %f%f%f%f

tool: D57: Thank you. Now enter student score (percent) >

tool: D10: %f

tool: D0: Student has an C grade


tool: D19: Student has an A grade


tool: D26: Student has an B grade


tool: D11: Student has an D grade


tool: D44: Student has failed that course


assistant: ```c
int main(void) {
  float a, b, c, d;
  float percent;
  printf("Enter thresholds for A, B, C, D\nin that order, decreasing percentages > ");
  scanf("%f%f%f%f", &a, &b, &c, &d);
  printf("Thank you. Now enter student score (percent) >");
  scanf("%f", &percent);
  if (percent > a)
    printf("Student has an A grade\n");
  else if (percent <= a && percent >= b)
    printf("Student has an B grade\n");
  else if (percent <= b && percent >= c)
    printf("Student has an C grade\n");
  else if (percent <= c && percent >= d)
    printf("Student has an D grade\n");
  else if (percent < d)
    printf("Student has failed that course\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<bar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movl   $0xfffffffe,(%rax)
  mov    -0x10(%rbp),%rax
  movl   $0xffffffff,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  pop    %rbp
  ret
```

assistant: ```c
int __attribute__((no)) bar(int *p, int *q) {
  *p = -2;
  *q = -1;
  return *p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<bar>:
  endbr64
  movl   $0xfffffffe,(%rdi)
  movl   $0xffffffff,(%rsi)
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int __attribute__((no)) bar(int *p, int *q) {
  *p = -2;
  *q = -1;
  return *p;
}
```
user: What is the c source code of the assembly code below?

```asm
<bar>:
  endbr64
  movl   $0xfffffffe,(%rdi)
  movl   $0xffffffff,(%rsi)
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int __attribute__((no)) bar(int *p, int *q) {
  *p = -2;
  *q = -1;
  return *p;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bar>:
  endbr64
  movl   $0xfffffffe,(%rdi)
  movl   $0xffffffff,(%rsi)
  mov    (%rdi),%eax
  ret
```

assistant: ```c
int __attribute__((no)) bar(int *p, int *q) {
  *p = -2;
  *q = -1;
  return *p;
}
```
user: What is the c source code of the assembly code below:

```asm
<_check_times>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  imul   %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  cmp    %rax,-0x8(%rbp)
  ja     L13
  cmpl   $0x10000000,-0xc(%rbp)
  jbe    L10
L13:
  mov    $0x103,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L10:
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/vc_cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/vc_cyc_include.h", 259));
  return word_ans;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<_check_times>:
  endbr64
  push   %rbx
  mov    %edi,%edi
  mov    %esi,%esi
  imul   %rsi,%rdi
  mov    %edi,%ebx
  mov    %edi,%eax
  cmp    %rax,%rdi
  ja     L3
  cmp    $0x10000000,%edi
  jbe    L13
L3:
  mov    $0x103,%esi
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <_throw_badalloc_fn@plt>
L13:
  mov    %ebx,%eax
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
type: string

tool: D4: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/vc_cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/vc_cyc_include.h", 259));
  return word_ans;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_check_times>:
  endbr64
  mov    %edi,%edi
  mov    %esi,%esi
  push   %r12
  imul   %rsi,%rdi
  mov    %edi,%eax
  mov    %edi,%r12d
  cmp    %rax,%rdi
  ja     L5
  cmp    $0x10000000,%edi
  ja     L5
  mov    %r12d,%eax
  pop    %r12
  ret
  cs nopw 0x0(%rax,%rax,1)
L5:
  mov    $0x103,%esi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <_throw_badalloc_fn@plt>
  mov    %r12d,%eax
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D3
type_infered: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/vc_cyc_include.h

assistant: ```c
unsigned int _check_times(unsigned x, unsigned y) {
  unsigned long long whole_ans = ((unsigned long long)x) * ((unsigned long long)y);
  unsigned word_ans = (unsigned)whole_ans;
  if (word_ans < whole_ans || word_ans > (1 << 28))
    (_throw_badalloc_fn("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/FauxFaux/cyclone/refs/heads/master/bin/cyc-lib/vc_cyc_include.h", 259));
  return word_ans;
}
```