ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<getlines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x420,%rsp
  mov    %rdi,-0x408(%rbp)
  mov    %esi,-0x40c(%rbp)
  mov    %rdx,-0x418(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x3fc(%rbp)
  jmp    L22
L23:
  lea    -0x3f0(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  add    $0x1,%rax
  mov    %rax,%rdi
  call   <malloc@plt>
  mov    %rax,-0x3f8(%rbp)
  lea    -0x3f0(%rbp),%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    -0x3fc(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x3fc(%rbp)
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x408(%rbp),%rax
  add    %rax,%rdx
  mov    -0x3f8(%rbp),%rax
  mov    %rax,(%rdx)
L22:
  mov    -0x418(%rbp),%rdx
  lea    -0x3f0(%rbp),%rax
  mov    $0x3e8,%esi
  mov    %rax,%rdi
  call   <fgets@plt>
  test   %rax,%rax
  je     L17
  mov    -0x3fc(%rbp),%eax
  cmp    -0x40c(%rbp),%eax
  jl     L23
L17:
  mov    -0x3fc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L35
  call   <__stack_chk_fail@plt>
L35:
  leave
  ret
```

assistant: ```c
int getlines(char *lines[], int nline, FILE *stream) {
  int i = 0;
  char s[1000];
  char *p;
  while (fgets(s, 1000, stream) && i < nline) {
    p = malloc(strlen(s) + 1);
    strcpy(p, s);
    lines[i++] = p;
  }
  return i;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getlines>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x3f8,%rsp
  mov    %rdi,%r15
  mov    %esi,%r14d
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
  mov    %rsp,%r12
L33:
  mov    %ebx,%ebp
  mov    %r13,%rdx
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  call   <fgets@plt>
  cmp    %ebx,%r14d
  jle    L34
  test   %rax,%rax
  je     L34
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,(%r15,%rbx,8)
  add    $0x1,%rbx
  jmp    L33
L34:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L31
  mov    %ebp,%eax
  add    $0x3f8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L31:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getlines(char *lines[], int nline, FILE *stream) {
  int i = 0;
  char s[1000];
  char *p;
  while (fgets(s, 1000, stream) && i < nline) {
    p = malloc(strlen(s) + 1);
    strcpy(p, s);
    lines[i++] = p;
  }
  return i;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<getlines>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L8
  nopl   0x0(%rax,%rax,1)
L15:
  test   %rax,%rax
  je     L5
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,(%r15,%rbx,8)
  add    $0x1,%rbx
L8:
  mov    %r13,%rdx
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %ebx,%ebp
  call   <fgets@plt>
  cmp    %ebx,%r14d
  jg     L15
L5:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x3f8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L24:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getlines(char *lines[], int nline, FILE *stream) {
  int i = 0;
  char s[1000];
  char *p;
  while (fgets(s, 1000, stream) && i < nline) {
    p = malloc(strlen(s) + 1);
    strcpy(p, s);
    lines[i++] = p;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getlines>:
  endbr64
  push   %r15
  mov    %rdi,%r15
  push   %r14
  mov    %esi,%r14d
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x3f8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x3e8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  jmp    L18
  nopl   0x0(%rax,%rax,1)
L11:
  test   %rax,%rax
  je     L10
  mov    %r12,%rdi
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %r12,%rsi
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <strcpy@plt>
  mov    %rbp,(%r15,%rbx,8)
  add    $0x1,%rbx
L18:
  mov    %r13,%rdx
  mov    $0x3e8,%esi
  mov    %r12,%rdi
  mov    %ebx,%ebp
  call   <fgets@plt>
  cmp    %ebx,%r14d
  jg     L11
L10:
  mov    0x3e8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x3f8,%rsp
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int getlines(char *lines[], int nline, FILE *stream) {
  int i = 0;
  char s[1000];
  char *p;
  while (fgets(s, 1000, stream) && i < nline) {
    p = malloc(strlen(s) + 1);
    strcpy(p, s);
    lines[i++] = p;
  }
  return i;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<fst3_64>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L16:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  movss  %xmm0,-0x4(%rbp)
  mov    $0x3f,%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  movss  (%rdx),%xmm0
  movss  %xmm0,(%rax)
  mov    $0x3f,%eax
  sub    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  -0x4(%rbp),%xmm0
  movss  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L34:
  cmpl   $0x1f,-0x8(%rbp)
  jle    L16
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <fct3_64@plt>
  movl   $0x1,-0x8(%rbp)
  jmp    L4
L25:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movss  D1(%rip),%xmm1
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  addl   $0x2,-0x8(%rbp)
L4:
  cmpl   $0x3f,-0x8(%rbp)
  jle    L25
  nop
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
data_type: byte[4]

tool: {"D1": [0x00,0x00,0x00,0x80]}

assistant: ```c
void fst3_64(float *a) {
  int k;
  float xp;
  ;
  ;
  for (k = 0; k < 32; k++) {
    ;
    xp = a[k];
    a[k] = a[63 - k];
    a[63 - k] = xp;
  };
  fct3_64(a);
  ;
  for (k = 1; k < 64; k += 2) {
    ;
    ;
    a[k] = -a[k];
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fst3_64>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  lea    0xfc(%rdi),%rax
  lea    0x7c(%rdi),%rcx
  mov    %rdi,%rdx
L17:
  movss  (%rdx),%xmm0
  movss  (%rax),%xmm1
  movss  %xmm1,(%rdx)
  movss  %xmm0,(%rax)
  add    $0x4,%rdx
  sub    $0x4,%rax
  cmp    %rcx,%rax
  jne    L17
  mov    %rbx,%rdi
  call   <fct3_64@plt>
  lea    0x4(%rbx),%rax
  lea    0x104(%rbx),%rdx
  movss  D9(%rip),%xmm1
L10:
  movss  (%rax),%xmm0
  xorps  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  add    $0x8,%rax
  cmp    %rdx,%rax
  jne    L10
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: byte[4]

tool: {"D9": [0x00,0x00,0x00,0x80]}

assistant: ```c
void fst3_64(float *a) {
  int k;
  float xp;
  ;
  ;
  for (k = 0; k < 32; k++) {
    ;
    xp = a[k];
    a[k] = a[63 - k];
    a[63 - k] = xp;
  };
  fct3_64(a);
  ;
  for (k = 1; k < 64; k += 2) {
    ;
    ;
    a[k] = -a[k];
  };
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fst3_64>:
  endbr64
  push   %rbx
  lea    0xfc(%rdi),%rax
  mov    %rdi,%rbx
  lea    0x7c(%rdi),%rcx
  mov    %rdi,%rdx
  cs nopw 0x0(%rax,%rax,1)
L11:
  movss  (%rdx),%xmm0
  movss  (%rax),%xmm1
  sub    $0x4,%rax
  add    $0x4,%rdx
  movss  %xmm1,-0x4(%rdx)
  movss  %xmm0,0x4(%rax)
  cmp    %rcx,%rax
  jne    L11
  mov    %rbx,%rdi
  call   <fct3_64@plt>
  lea    0x4(%rbx),%rax
  lea    0x104(%rbx),%rdx
  movss  D2(%rip),%xmm1
  nopw   0x0(%rax,%rax,1)
L18:
  movss  (%rax),%xmm0
  add    $0x8,%rax
  xorps  %xmm1,%xmm0
  movss  %xmm0,-0x8(%rax)
  cmp    %rax,%rdx
  jne    L18
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: byte[4]

tool: {"D2": [0x00,0x00,0x00,0x80]}

assistant: ```c
void fst3_64(float *a) {
  int k;
  float xp;
  ;
  ;
  for (k = 0; k < 32; k++) {
    ;
    xp = a[k];
    a[k] = a[63 - k];
    a[63 - k] = xp;
  };
  fct3_64(a);
  ;
  for (k = 1; k < 64; k += 2) {
    ;
    ;
    a[k] = -a[k];
  };
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lio_listio>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x8(%rbp)
  mov    %rcx,-0x18(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  leave
  ret
```

assistant: ```c
int lio_listio(int mode, struct aiocb *const list[], int nent, struct sigevent *sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lio_listio>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lio_listio(int mode, struct aiocb *const list[], int nent, struct sigevent *sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lio_listio>:
  endbr64
  sub    $0x8,%rsp
  mov    D8(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lio_listio(int mode, struct aiocb *const list[], int nent, struct sigevent *sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lio_listio>:
  endbr64
  sub    $0x8,%rsp
  mov    D4(%rip),%rax
  mov    (%rax),%edi
  call   <__set_errno@plt>
  mov    $0xffffffff,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int lio_listio(int mode, struct aiocb *const list[], int nent, struct sigevent *sig) {
  __set_errno(ENOSYS);
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<_free>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L8
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x8(%rbp),%rax
  movq   $0x0,(%rax)
L8:
  nop
  leave
  ret
```

assistant: ```c
void _free(void **p) {
  if (*p != NULL) {
    free(*p);
    *p = NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L8
  call   <free@plt>
  movq   $0x0,(%rbx)
L8:
  pop    %rbx
  ret
```

assistant: ```c
void _free(void **p) {
  if (*p != NULL) {
    free(*p);
    *p = NULL;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  call   <free@plt>
  movq   $0x0,(%rbx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void _free(void **p) {
  if (*p != NULL) {
    free(*p);
    *p = NULL;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_free>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L6
  call   <free@plt>
  movq   $0x0,(%rbx)
L6:
  pop    %rbx
  ret
```

assistant: ```c
void _free(void **p) {
  if (*p != NULL) {
    free(*p);
    *p = NULL;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<write_score>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x1c(%rbp),%edx
  lea    -0xc(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%ecx
  lea    -0xc(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <write_line@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: %d

assistant: ```c
void write_score(int x, int y, int score) {
  char string[4];
  sprintf(string, "%d", score);
  write_line(string, x, y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_score>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %edi,%ebx
  mov    %esi,%ebp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r12
  lea    D8(%rip),%rsi
  mov    %r12,%rdi
  call   <sprintf@plt>
  mov    %ebp,%edx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <write_line@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
datatype: string

tool: D8: %d

assistant: ```c
void write_score(int x, int y, int score) {
  char string[4];
  sprintf(string, "%d", score);
  write_line(string, x, y);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_score>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D4(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <write_line@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type: string

tool: D4: %d

assistant: ```c
void write_score(int x, int y, int score) {
  char string[4];
  sprintf(string, "%d", score);
  write_line(string, x, y);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<write_score>:
  endbr64
  push   %r13
  push   %r12
  mov    %esi,%r12d
  lea    D1(%rip),%rsi
  push   %rbp
  mov    %edi,%ebp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
  mov    %r13,%rdi
  call   <sprintf@plt>
  mov    %r12d,%edx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <write_line@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x10,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
type_infered: string

tool: D1: %d

assistant: ```c
void write_score(int x, int y, int score) {
  char string[4];
  sprintf(string, "%d", score);
  write_line(string, x, y);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ResultArguments_toProgramCall>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ResultArguments_getFlagsFromSuffix@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <StringArray_getLength@plt>
  mov    %eax,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  add    $0x3,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <ResultArguments_getProgram@plt>
  mov    %eax,%edi
  call   <Tool_toString@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    -0x30(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <StringArray_getLength@plt>
  cltq
  shl    $0x3,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  lea    0x10(%rax),%rcx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   <memcpy@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
const char **ResultArguments_toProgramCall(const struct ResultArguments *this, const char *file) {
  const char **flags = ResultArguments_getFlagsFromSuffix(this, file);
  const int numberOfFlags = StringArray_getLength(flags);
  const int length = 2 + numberOfFlags + 1;
  const char **programCall = malloc(sizeof(*flags) * length);
  programCall[0] = Tool_toString(ResultArguments_getProgram(file));
  programCall[1] = file;
  memcpy(&programCall[2], flags, StringArray_getLength(flags) * sizeof(*programCall));
  return programCall;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ResultArguments_toProgramCall>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%r12
  call   <ResultArguments_getFlagsFromSuffix@plt>
  mov    %rax,%rbp
  mov    %rax,%rdi
  call   <StringArray_getLength@plt>
  lea    0x18(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbx
  mov    %r12,%rdi
  call   <ResultArguments_getProgram@plt>
  mov    %eax,%edi
  call   <Tool_toString@plt>
  mov    %rax,(%rbx)
  mov    %r12,0x8(%rbx)
  mov    %rbp,%rdi
  call   <StringArray_getLength@plt>
  lea    0x0(,%rax,8),%edx
  lea    0x10(%rbx),%rdi
  mov    %rbp,%rsi
  call   <memcpy@plt>
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char **ResultArguments_toProgramCall(const struct ResultArguments *this, const char *file) {
  const char **flags = ResultArguments_getFlagsFromSuffix(this, file);
  const int numberOfFlags = StringArray_getLength(flags);
  const int length = 2 + numberOfFlags + 1;
  const char **programCall = malloc(sizeof(*flags) * length);
  programCall[0] = Tool_toString(ResultArguments_getProgram(file));
  programCall[1] = file;
  memcpy(&programCall[2], flags, StringArray_getLength(flags) * sizeof(*programCall));
  return programCall;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ResultArguments_toProgramCall>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <ResultArguments_getFlagsFromSuffix@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <StringArray_getLength@plt>
  lea    0x18(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <ResultArguments_getProgram@plt>
  mov    %eax,%edi
  call   <Tool_toString@plt>
  mov    %rbx,0x8(%r12)
  mov    %rbp,%rdi
  mov    %rax,(%r12)
  call   <StringArray_getLength@plt>
  lea    0x10(%r12),%rdi
  mov    %rbp,%rsi
  lea    0x0(,%rax,8),%edx
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char **ResultArguments_toProgramCall(const struct ResultArguments *this, const char *file) {
  const char **flags = ResultArguments_getFlagsFromSuffix(this, file);
  const int numberOfFlags = StringArray_getLength(flags);
  const int length = 2 + numberOfFlags + 1;
  const char **programCall = malloc(sizeof(*flags) * length);
  programCall[0] = Tool_toString(ResultArguments_getProgram(file));
  programCall[1] = file;
  memcpy(&programCall[2], flags, StringArray_getLength(flags) * sizeof(*programCall));
  return programCall;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ResultArguments_toProgramCall>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  call   <ResultArguments_getFlagsFromSuffix@plt>
  mov    %rax,%rdi
  mov    %rax,%rbp
  call   <StringArray_getLength@plt>
  lea    0x18(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rbx,%rdi
  mov    %rax,%r12
  call   <ResultArguments_getProgram@plt>
  mov    %eax,%edi
  call   <Tool_toString@plt>
  movq   %rbx,%xmm1
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%r12)
  call   <StringArray_getLength@plt>
  lea    0x10(%r12),%rdi
  mov    %rbp,%rsi
  lea    0x0(,%rax,8),%edx
  call   <memcpy@plt>
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
const char **ResultArguments_toProgramCall(const struct ResultArguments *this, const char *file) {
  const char **flags = ResultArguments_getFlagsFromSuffix(this, file);
  const int numberOfFlags = StringArray_getLength(flags);
  const int length = 2 + numberOfFlags + 1;
  const char **programCall = malloc(sizeof(*flags) * length);
  programCall[0] = Tool_toString(ResultArguments_getProgram(file));
  programCall[1] = file;
  memcpy(&programCall[2], flags, StringArray_getLength(flags) * sizeof(*programCall));
  return programCall;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<fc8180_ppi_init>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dx,-0xc(%rbp)
  mov    %ax,-0x10(%rbp)
  mov    $0x0,%eax
  call   <OAL_CREATE_SEMAPHORE@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
signed int fc8180_ppi_init(void *handle, unsigned short param1, unsigned short param2) {
  OAL_CREATE_SEMAPHORE();
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<fc8180_ppi_init>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <OAL_CREATE_SEMAPHORE@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed int fc8180_ppi_init(void *handle, unsigned short param1, unsigned short param2) {
  OAL_CREATE_SEMAPHORE();
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fc8180_ppi_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <OAL_CREATE_SEMAPHORE@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed int fc8180_ppi_init(void *handle, unsigned short param1, unsigned short param2) {
  OAL_CREATE_SEMAPHORE();
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fc8180_ppi_init>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <OAL_CREATE_SEMAPHORE@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
signed int fc8180_ppi_init(void *handle, unsigned short param1, unsigned short param2) {
  OAL_CREATE_SEMAPHORE();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<edit_xscript_to_rflen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L2
L33:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x53,%al
  je     L4
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x3d,%al
  je     L4
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x58,%al
  je     L4
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x44,%al
  jne    L12
L4:
  addq   $0x1,-0x8(%rbp)
L12:
  addq   $0x1,-0x10(%rbp)
L2:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L33
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
size_t edit_xscript_to_rflen(const char *edit_xscript) {
  const char *cur = edit_xscript;
  size_t rflen = 0;
  while (*cur != '\0') {
    if (*cur == 'S' || *cur == '=' || *cur == 'X' || *cur == 'D') {
      rflen++;
    }
    cur++;
  }
  return rflen;
}
```