ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<mallocMem>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  call   <malloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
L5:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L16:
  mov    $0x33,%edx
  lea    D9(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L5
```

tool_calls: name: read_data
arguments: label: D9
type_infered: string
name: read_data
arguments: label: D12
type_infered: string

tool: D9: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Sunfe/sas/refs/heads/master/source/sas_common.c

tool: D12: 
%s,%d:malloc not successful!

assistant: ```c
char *mallocMem(int bufferLen) {
  char *buffer = (char *)malloc(bufferLen);
  if (NULL == buffer) {
    printf("\n%s,%d:malloc not successful!", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Sunfe/sas/refs/heads/master/source/sas_common.c", 51);
    return NULL;
  }
  memset(buffer, 0, bufferLen);
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mallocMem>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L7
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L7:
  mov    $0x33,%edx
  lea    D7(%rip),%rsi
  lea    D14(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: parse_data
arguments: label: D7
data_type: string
name: parse_data
arguments: label: D14
data_type: string

tool: D7: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Sunfe/sas/refs/heads/master/source/sas_common.c

tool: D14: 
%s,%d:malloc not successful!

assistant: ```c
char *mallocMem(int bufferLen) {
  char *buffer = (char *)malloc(bufferLen);
  if (NULL == buffer) {
    printf("\n%s,%d:malloc not successful!", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Sunfe/sas/refs/heads/master/source/sas_common.c", 51);
    return NULL;
  }
  memset(buffer, 0, bufferLen);
  return buffer;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mallocMem>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  push   %r12
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L5
  mov    %r13d,%edx
  xor    %esi,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L5:
  mov    $0x33,%edx
  lea    D3(%rip),%rsi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
datatype: string
name: extract_symbolic_data
arguments: tag: D12
datatype: string

tool: D3: /scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Sunfe/sas/refs/heads/master/source/sas_common.c

tool: D12: 
%s,%d:malloc not successful!

assistant: ```c
char *mallocMem(int bufferLen) {
  char *buffer = (char *)malloc(bufferLen);
  if (NULL == buffer) {
    printf("\n%s,%d:malloc not successful!", "/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/Sunfe/sas/refs/heads/master/source/sas_common.c", 51);
    return NULL;
  }
  memset(buffer, 0, bufferLen);
  return buffer;
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L75
L57:
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L41
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  jne    L41
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L104
L41:
  cmpl   $0x0,-0x4(%rbp)
  js     L104
  cmpl   $0x1,-0x8(%rbp)
  jne    L126
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  movl   $0x0,-0x8(%rbp)
  jmp    L104
L126:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  jne    L127
  addl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L104
L127:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x22,%al
  je     L73
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
  jmp    L104
L73:
  mov    -0xc(%rbp),%eax
  sub    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  jmp    L34
L104:
  addl   $0x1,-0xc(%rbp)
L75:
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0xc(%rbp)
  jge    L34
  mov    -0xc(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L57
L34:
  cmpl   $0x0,-0x4(%rbp)
  js     L36
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  jmp    L2
L36:
  mov    $0xffffffff,%eax
L2:
  leave
  ret
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        off++;
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: What is the c source code of the assembly code below:

```asm
<extract_string>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r14
  mov    %rsi,0x8(%rsp)
  mov    %edx,%r13d
  mov    $0x0,%ebx
  mov    $0xffffffff,%r12d
  mov    $0x0,%r15d
  jmp    L85
L143:
  cmpb   $0x22,(%r14,%rbx,1)
  je     L148
L80:
  add    $0x1,%rbx
L85:
  mov    %ebx,0x4(%rsp)
  mov    %ebx,%ebp
  mov    %r14,%rdi
  call   <strlen@plt>
  cmp    %r13d,%eax
  cmovg  %r13d,%eax
  cmp    %ebx,%eax
  jle    L121
  cmp    $0xffffffff,%r12d
  je     L143
  test   %r12d,%r12d
  js     L80
  cmp    $0x1,%r15d
  je     L56
  movzbl (%r14,%rbx,1),%eax
  cmp    $0x5c,%al
  je     L6
  cmp    $0x22,%al
  je     L29
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  mov    0x8(%rsp),%rcx
  mov    %al,(%rcx,%rbp,1)
  jmp    L80
L148:
  mov    0x4(%rsp),%r12d
  add    $0x1,%r12d
  jmp    L80
L56:
  movzbl (%r14,%rbx,1),%eax
  sub    %r12d,%ebp
  movslq %ebp,%rbp
  mov    0x8(%rsp),%rdx
  mov    %al,(%rdx,%rbp,1)
  mov    $0x0,%r15d
  jmp    L80
L6:
  add    $0x1,%r12d
  mov    $0x1,%r15d
  jmp    L80
L29:
  sub    %r12d,%ebp
  movslq %ebp,%rax
  mov    0x8(%rsp),%rsi
  movb   $0x0,(%rsi,%rax,1)
  jmp    L105
L121:
  test   %r12d,%r12d
  js     L115
L105:
  mov    0x8(%rsp),%rdi
  call   <strlen@plt>
L96:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L115:
  mov    $0xffffffff,%eax
  jmp    L96
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        off++;
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<extract_string>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L62
  nopl   (%rax)
L46:
  cmpl   $0x1,0x4(%rsp)
  je     L75
  cmp    $0x5c,%al
  je     L101
  sub    %r14d,%ebx
  movslq %ebx,%rbx
  add    0x8(%rsp),%rbx
  cmp    $0x22,%al
  je     L105
  mov    %al,(%rbx)
L48:
  add    $0x1,%r15
  add    $0x1,%r12d
L62:
  mov    %r13,%rdi
  mov    %r15d,%ebx
  call   <strlen@plt>
  cmp    %ebp,%eax
  cmovg  %ebp,%eax
  cmp    %r15d,%eax
  jle    L35
  movzbl 0x0(%r13,%r15,1),%eax
  cmp    $0xffffffff,%r14d
  jne    L46
  cmp    $0x22,%al
  cmove  %r12d,%r14d
  jmp    L48
  nopl   (%rax)
L75:
  mov    0x8(%rsp),%rdx
  sub    %r14d,%ebx
  movl   $0x0,0x4(%rsp)
  movslq %ebx,%rbx
  mov    %al,(%rdx,%rbx,1)
  jmp    L48
L101:
  movl   $0x1,0x4(%rsp)
  add    $0x1,%r14d
  jmp    L48
  xchg   %ax,%ax
L35:
  cmp    $0xffffffff,%r14d
  je     L30
L56:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <strlen@plt>
L105:
  movb   $0x0,(%rbx)
  jmp    L56
L30:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        off++;
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<extract_string>:
  endbr64
  push   %r15
  xor    %r15d,%r15d
  push   %r14
  mov    $0xffffffff,%r14d
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,0x8(%rsp)
  movl   $0x0,0x4(%rsp)
  jmp    L86
  nopl   (%rax)
L70:
  cmpl   $0x1,0x4(%rsp)
  je     L85
  cmp    $0x5c,%al
  je     L59
  sub    %r14d,%ebx
  movslq %ebx,%rbx
  add    0x8(%rsp),%rbx
  cmp    $0x22,%al
  je     L101
  mov    %al,(%rbx)
L49:
  add    $0x1,%r15
  add    $0x1,%r12d
L86:
  mov    %r13,%rdi
  mov    %r15d,%ebx
  call   <strlen@plt>
  cmp    %ebp,%eax
  cmovg  %ebp,%eax
  cmp    %r15d,%eax
  jle    L68
  movzbl 0x0(%r13,%r15,1),%eax
  cmp    $0xffffffff,%r14d
  jne    L70
  cmp    $0x22,%al
  cmove  %r12d,%r14d
  jmp    L49
  nopl   (%rax)
L85:
  mov    0x8(%rsp),%rdx
  sub    %r14d,%ebx
  movl   $0x0,0x4(%rsp)
  movslq %ebx,%rbx
  mov    %al,(%rdx,%rbx,1)
  jmp    L49
L59:
  movl   $0x1,0x4(%rsp)
  add    $0x1,%r14d
  jmp    L49
  xchg   %ax,%ax
L68:
  cmp    $0xffffffff,%r14d
  je     L75
L38:
  mov    0x8(%rsp),%rdi
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1050 <strlen@plt>
L101:
  movb   $0x0,(%rbx)
  jmp    L38
L75:
  add    $0x18,%rsp
  mov    $0xffffffff,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
int extract_string(const char *src, char *dest, int len) {
  int pos = 0;
  int esc = 0;
  int off = -1;
  for (pos = 0; (pos < strlen(src)) && (pos < len); pos++) {
    if ((off == -1) && (src[pos] == '"')) {
      off = pos + 1;
    } else if (off >= 0) {
      if (esc == 1) {
        dest[pos - off] = src[pos];
        esc = 0;
      } else if (src[pos] == '\\') {
        off++;
        esc = 1;
      } else if (src[pos] != '"') {
        dest[pos - off] = src[pos];
      } else {
        dest[pos - off] = '\0';
        break;
      }
    }
  }
  return (off > -1) ? strlen(dest) : -1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <GIEOn@plt>
  mov    $0x0,%eax
  call   <hint@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
main() {
  GIEOn();
  hint();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <GIEOn@plt>
  mov    $0x0,%eax
  call   <hint@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  GIEOn();
  hint();
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <GIEOn@plt>
  xor    %eax,%eax
  call   <hint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  GIEOn();
  hint();
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <GIEOn@plt>
  xor    %eax,%eax
  call   <hint@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
main() {
  GIEOn();
  hint();
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <sub@plt>
  mov    %eax,-0x4(%rbp)
  nop
  leave
  ret
```

assistant: ```c
void main(void) {
  int x;
  int y;
  y = sub(x);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <sub@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void main(void) {
  int x;
  int y;
  y = sub(x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <sub@plt>
```

assistant: ```c
void main(void) {
  int x;
  int y;
  y = sub(x);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  xor    %edi,%edi
  jmp    1050 <sub@plt>
```

assistant: ```c
void main(void) {
  int x;
  int y;
  y = sub(x);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<idfPoisson>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  %xmm1,-0x20(%rbp)
  movsd  -0x18(%rbp),%xmm0
  cvttsd2si %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <cdfPoisson@plt>
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jb     L79
  jmp    L33
L75:
  addq   $0x1,-0x8(%rbp)
L33:
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <cdfPoisson@plt>
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jae    L75
  jmp    L4
L79:
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edi
  movq   %rax,%xmm0
  call   <cdfPoisson@plt>
  movsd  -0x20(%rbp),%xmm1
  comisd %xmm0,%xmm1
  jb     L28
  jmp    L18
L6:
  subq   $0x1,-0x8(%rbp)
L18:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rdi
  movq   %rax,%xmm0
  call   <cdfPoisson@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm2
  comisd -0x20(%rbp),%xmm2
  ja     L6
  jmp    L4
L28:
  movq   $0x0,-0x8(%rbp)
L4:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long idfPoisson(double m, double u) {
  long x = (long)m;
  if (cdfPoisson(m, x) <= u)
    while (cdfPoisson(m, x) <= u)
      x++;
  else if (cdfPoisson(m, 0) <= u)
    while (cdfPoisson(m, x - 1) > u)
      x--;
  else
    x = 0;
  return (x);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<idfPoisson>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,0x8(%rsp)
  movsd  %xmm1,(%rsp)
  cvttsd2si %xmm0,%rbx
  mov    %rbx,%rdi
  call   <cdfPoisson@plt>
  movsd  (%rsp),%xmm3
  comisd %xmm0,%xmm3
  jae    L47
  mov    $0x0,%edi
  movsd  0x8(%rsp),%xmm0
  call   <cdfPoisson@plt>
  movsd  (%rsp),%xmm5
  comisd %xmm0,%xmm5
  jb     L40
L2:
  mov    %rbx,%rbp
  sub    $0x1,%rbx
  mov    %rbx,%rdi
  movsd  0x8(%rsp),%xmm0
  call   <cdfPoisson@plt>
  comisd (%rsp),%xmm0
  ja     L2
  mov    %rbp,%rbx
  jmp    L15
L27:
  add    $0x1,%rbx
L47:
  mov    %rbx,%rdi
  movsd  0x8(%rsp),%xmm0
  call   <cdfPoisson@plt>
  movsd  (%rsp),%xmm2
  comisd %xmm0,%xmm2
  jae    L27
L15:
  mov    %rbx,%rax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L40:
  mov    $0x0,%ebx
  jmp    L15
```

assistant: ```c
long idfPoisson(double m, double u) {
  long x = (long)m;
  if (cdfPoisson(m, x) <= u)
    while (cdfPoisson(m, x) <= u)
      x++;
  else if (cdfPoisson(m, 0) <= u)
    while (cdfPoisson(m, x - 1) > u)
      x--;
  else
    x = 0;
  return (x);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<idfPoisson>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  cvttsd2si %xmm0,%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <cdfPoisson@plt>
  movsd  0x8(%rsp),%xmm3
  comisd %xmm0,%xmm3
  jae    L4
  jmp    L20
  nopl   0x0(%rax,%rax,1)
L9:
  add    $0x1,%r12
L4:
  mov    %r12,%rdi
  movq   %r14,%xmm0
  call   <cdfPoisson@plt>
  movsd  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm2
  jae    L9
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L20:
  xor    %edi,%edi
  movq   %r14,%xmm0
  call   <cdfPoisson@plt>
  movsd  0x8(%rsp),%xmm5
  comisd %xmm0,%xmm5
  jb     L19
L12:
  mov    %r12,%rbx
  sub    $0x1,%r12
  movq   %r14,%xmm0
  mov    %r12,%rdi
  call   <cdfPoisson@plt>
  comisd 0x8(%rsp),%xmm0
  ja     L12
  mov    %rbx,%r12
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax)
L19:
  add    $0x10,%rsp
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
long idfPoisson(double m, double u) {
  long x = (long)m;
  if (cdfPoisson(m, x) <= u)
    while (cdfPoisson(m, x) <= u)
      x++;
  else if (cdfPoisson(m, 0) <= u)
    while (cdfPoisson(m, x - 1) > u)
      x--;
  else
    x = 0;
  return (x);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<idfPoisson>:
  endbr64
  push   %r14
  movq   %xmm0,%r14
  push   %r12
  cvttsd2si %xmm0,%r12
  push   %rbx
  mov    %r12,%rdi
  sub    $0x10,%rsp
  movsd  %xmm1,0x8(%rsp)
  call   <cdfPoisson@plt>
  movsd  0x8(%rsp),%xmm3
  comisd %xmm0,%xmm3
  jae    L14
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L31:
  add    $0x1,%r12
L14:
  mov    %r12,%rdi
  movq   %r14,%xmm0
  call   <cdfPoisson@plt>
  movsd  0x8(%rsp),%xmm2
  comisd %xmm0,%xmm2
  jae    L31
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  xor    %edi,%edi
  movq   %r14,%xmm0
  call   <cdfPoisson@plt>
  movsd  0x8(%rsp),%xmm5
  comisd %xmm0,%xmm5
  jb     L24
L0:
  mov    %r12,%rbx
  sub    $0x1,%r12
  movq   %r14,%xmm0
  mov    %r12,%rdi
  call   <cdfPoisson@plt>
  comisd 0x8(%rsp),%xmm0
  ja     L0
  mov    %rbx,%r12
  add    $0x10,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
  nopl   0x0(%rax)
L24:
  add    $0x10,%rsp
  xor    %r12d,%r12d
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  pop    %r14
  ret
```

assistant: ```c
long idfPoisson(double m, double u) {
  long x = (long)m;
  if (cdfPoisson(m, x) <= u)
    while (cdfPoisson(m, x) <= u)
      x++;
  else if (cdfPoisson(m, 0) <= u)
    while (cdfPoisson(m, x - 1) > u)
      x--;
  else
    x = 0;
  return (x);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L17
L3:
  addl   $0x1,-0x8(%rbp)
  shll   -0x4(%rbp)
L17:
  cmpl   $0x5,-0x8(%rbp)
  jbe    L3
  cmpl   $0x6,-0x8(%rbp)
  sete   %al
  movzbl %al,%eax
  mov    %eax,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 1;
  while (x < 6) {
    x++;
    y *= 2;
  }
  __VERIFIER_assert(x == 6);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__VERIFIER_assert@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 1;
  while (x < 6) {
    x++;
    y *= 2;
  }
  __VERIFIER_assert(x == 6);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 1;
  while (x < 6) {
    x++;
    y *= 2;
  }
  __VERIFIER_assert(x == 6);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x1,%edi
  call   <__VERIFIER_assert@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  unsigned int x = 0;
  unsigned int y = 1;
  while (x < 6) {
    x++;
    y *= 2;
  }
  __VERIFIER_assert(x == 6);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<mcast_index>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  movl   $0xffffffff,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x6,-0x18(%rbp)
  jmp    L24
L12:
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  movl   $0x8,-0x14(%rbp)
  jmp    L15
L7:
  mov    -0x1c(%rbp),%eax
  shr    $0x1f,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%eax
  and    $0x1,%eax
  xor    %edx,%eax
  mov    %eax,-0xc(%rbp)
  shll   -0x1c(%rbp)
  sarl   -0x10(%rbp)
  cmpl   $0x0,-0xc(%rbp)
  je     L15
  mov    -0x1c(%rbp),%eax
  xor    $0x4c11db6,%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x1c(%rbp)
L15:
  subl   $0x1,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L7
L24:
  subl   $0x1,-0x18(%rbp)
  cmpl   $0x0,-0x18(%rbp)
  jns    L12
  mov    -0x1c(%rbp),%eax
  sar    $0x1a,%eax
  pop    %rbp
  ret
```

assistant: ```c
int mcast_index(const void *dst) {
  uint32_t crc = 0xffffffffL;
  int carry, i, j;
  uint8_t b;
  uint8_t *ep = (uint8_t *)dst;
  for (i = 6; --i >= 0;) {
    b = *ep++;
    for (j = 8; --j >= 0;) {
      carry = ((crc & 0x80000000L) ? 1 : 0) ^ (b & 0x01);
      crc <<= 1;
      b >>= 1;
      if (carry)
        crc = ((crc ^ 0x04c11db6) | carry);
    }
  }
  return (crc >> 26);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mcast_index>:
  endbr64
  lea    0x18(%rdi),%r9
  mov    $0xffffffff,%eax
  jmp    L32
L53:
  sub    $0x1,%ecx
  je     L14
L41:
  mov    %eax,%edx
  shr    $0x1f,%edx
  mov    %esi,%r8d
  and    $0x1,%r8d
  add    %eax,%eax
  sar    %esi
  cmp    %r8d,%edx
  je     L53
  xor    $0x4c11db6,%eax
  xor    %r8d,%edx
  or     %edx,%eax
  jmp    L53
L14:
  cmp    %rdi,%r9
  je     L27
L32:
  add    $0x4,%rdi
  mov    -0x4(%rdi),%esi
  mov    $0x8,%ecx
  jmp    L41
L27:
  sar    $0x1a,%eax
  ret
```

assistant: ```c
int mcast_index(const void *dst) {
  uint32_t crc = 0xffffffffL;
  int carry, i, j;
  uint8_t b;
  uint8_t *ep = (uint8_t *)dst;
  for (i = 6; --i >= 0;) {
    b = *ep++;
    for (j = 8; --j >= 0;) {
      carry = ((crc & 0x80000000L) ? 1 : 0) ^ (b & 0x01);
      crc <<= 1;
      b >>= 1;
      if (carry)
        crc = ((crc ^ 0x04c11db6) | carry);
    }
  }
  return (crc >> 26);
}
```