ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sin_of_distance>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x130,%rsp
  mov    %edi,-0x124(%rbp)
  mov    %esi,-0x128(%rbp)
  movsd  %xmm0,-0x130(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x124(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x124(%rbp)
  mov    -0x128(%rbp),%eax
  mov    %eax,%edx
  neg    %edx
  cmovns %edx,%eax
  mov    %eax,-0x128(%rbp)
  movsd  -0x130(%rbp),%xmm0
  ucomisd D16(%rip),%xmm0
  jp     L16
  movsd  -0x130(%rbp),%xmm0
  ucomisd D16(%rip),%xmm0
  jne    L16
  cmpl   $0x1f4,-0x124(%rbp)
  jg     L16
  cmpl   $0x1f4,-0x128(%rbp)
  jg     L16
  mov    -0x128(%rbp),%edx
  mov    -0x124(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <fetch_sin_of_distance@plt>
  movq   %xmm0,%rax
  jmp    L47
L16:
  mov    -0x128(%rbp),%ecx
  mov    -0x124(%rbp),%edx
  lea    -0x110(%rbp),%rax
  lea    D10(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  test   %rax,%rax
  jle    L8
  lea    D25(%rip),%rax
  mov    %rax,-0x118(%rbp)
  lea    -0x118(%rbp),%rdx
  lea    -0x110(%rbp),%rax
  mov    $0x1,%ecx
  mov    %rax,%rsi
  mov    $0x2,%edi
  call   <log_message@plt>
L8:
  mov    -0x130(%rbp),%rcx
  mov    -0x128(%rbp),%edx
  mov    -0x124(%rbp),%eax
  movq   %rcx,%xmm0
  mov    %edx,%esi
  mov    %eax,%edi
  call   <evaluate_sin_of_distance@plt>
  movq   %xmm0,%rax
L47:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L61
  call   <__stack_chk_fail@plt>
L61:
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D16
type_infered: f64
name: unpack_data
arguments: data_label: D10
type_infered: string
name: unpack_data
arguments: data_label: D25
type_infered: string

tool: D16: 50

tool: D10: Failed to fetch (%d, %d) from the cache.

tool: D25: GEOMETRY_CACHE_MISS

assistant: ```c
double sin_of_distance(int x, int y, double wavelength) {
  x = abs(x);
  y = abs(y);
  if (wavelength == 50.0 && x <= 500 && y <= 500) {
    return fetch_sin_of_distance(x, y);
  } else {
    char message[256];
    if (sprintf(message, "Failed to fetch (%d, %d) from the cache.", x, y) > 0) {
      char *tags[] = {"GEOMETRY_CACHE_MISS"};
      log_message(2, message, tags, 1);
    }
    return evaluate_sin_of_distance(x, y, wavelength);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sin_of_distance>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x120,%rsp
  movq   %xmm0,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x118(%rsp)
  xor    %eax,%eax
  mov    %edi,%r12d
  neg    %r12d
  cmovs  %edi,%r12d
  mov    %esi,%ebp
  neg    %ebp
  cmovs  %esi,%ebp
  ucomisd D10(%rip),%xmm0
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  cmp    $0x1f4,%ebp
  setle  %dl
  test   %dl,%al
  je     L23
  cmp    $0x1f4,%r12d
  jle    L11
L23:
  lea    0x10(%rsp),%rdi
  mov    %ebp,%ecx
  mov    %r12d,%edx
  lea    D22(%rip),%rsi
  call   <sprintf@plt>
  test   %rax,%rax
  jg     L21
L55:
  movq   %rbx,%xmm0
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <evaluate_sin_of_distance@plt>
L43:
  mov    0x118(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0x120,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L11:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <fetch_sin_of_distance@plt>
  jmp    L43
L21:
  lea    D19(%rip),%rax
  mov    %rax,0x8(%rsp)
  lea    0x8(%rsp),%rdx
  lea    0x10(%rsp),%rsi
  mov    $0x1,%ecx
  mov    $0x2,%edi
  call   <log_message@plt>
  jmp    L55
L32:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D10
type: f64
name: unpack_data
arguments: data_tag: D22
type: string
name: unpack_data
arguments: data_tag: D19
type: string

tool: D10: 50

tool: D22: Failed to fetch (%d, %d) from the cache.

tool: D19: GEOMETRY_CACHE_MISS

assistant: ```c
double sin_of_distance(int x, int y, double wavelength) {
  x = abs(x);
  y = abs(y);
  if (wavelength == 50.0 && x <= 500 && y <= 500) {
    return fetch_sin_of_distance(x, y);
  } else {
    char message[256];
    if (sprintf(message, "Failed to fetch (%d, %d) from the cache.", x, y) > 0) {
      char *tags[] = {"GEOMETRY_CACHE_MISS"};
      log_message(2, message, tags, 1);
    }
    return evaluate_sin_of_distance(x, y, wavelength);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<sin_of_distance>:
  endbr64
  push   %r13
  mov    $0x0,%edx
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x130,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  neg    %r12d
  cmovs  %edi,%r12d
  neg    %ebp
  cmovs  %esi,%ebp
  ucomisd D26(%rip),%xmm0
  setnp  %al
  cmovne %edx,%eax
  cmp    $0x1f4,%ebp
  setle  %dl
  test   %dl,%al
  je     L28
  cmp    $0x1f4,%r12d
  jle    L41
L28:
  lea    0x20(%rsp),%r13
  mov    %ebp,%ecx
  mov    %r12d,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    D15(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jg     L20
L16:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <evaluate_sin_of_distance@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x130,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L20:
  lea    D19(%rip),%rax
  lea    0x18(%rsp),%rdx
  mov    $0x1,%ecx
  mov    %r13,%rsi
  mov    $0x2,%edi
  mov    %rax,0x18(%rsp)
  call   <log_message@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L16
  nopl   0x0(%rax,%rax,1)
L41:
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x130,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <fetch_sin_of_distance@plt>
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
type_guessed: f64
name: extract_symbolic_data
arguments: data_label: D15
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D19
type_guessed: string

tool: D26: 50

tool: D15: Failed to fetch (%d, %d) from the cache.

tool: D19: GEOMETRY_CACHE_MISS

assistant: ```c
double sin_of_distance(int x, int y, double wavelength) {
  x = abs(x);
  y = abs(y);
  if (wavelength == 50.0 && x <= 500 && y <= 500) {
    return fetch_sin_of_distance(x, y);
  } else {
    char message[256];
    if (sprintf(message, "Failed to fetch (%d, %d) from the cache.", x, y) > 0) {
      char *tags[] = {"GEOMETRY_CACHE_MISS"};
      log_message(2, message, tags, 1);
    }
    return evaluate_sin_of_distance(x, y, wavelength);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<sin_of_distance>:
  endbr64
  push   %r13
  mov    $0x0,%edx
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    %esi,%ebp
  sub    $0x130,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  neg    %r12d
  cmovs  %edi,%r12d
  neg    %ebp
  cmovs  %esi,%ebp
  ucomisd D8(%rip),%xmm0
  setnp  %al
  cmovne %edx,%eax
  cmp    $0x1f4,%ebp
  setle  %dl
  test   %dl,%al
  je     L38
  cmp    $0x1f4,%r12d
  jle    L29
L38:
  lea    0x20(%rsp),%r13
  mov    %ebp,%ecx
  mov    %r12d,%edx
  movsd  %xmm0,0x8(%rsp)
  lea    D4(%rip),%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  movsd  0x8(%rsp),%xmm0
  test   %rax,%rax
  jg     L27
L33:
  mov    %ebp,%esi
  mov    %r12d,%edi
  call   <evaluate_sin_of_distance@plt>
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x130,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L27:
  lea    D20(%rip),%rax
  lea    0x18(%rsp),%rdx
  mov    $0x1,%ecx
  mov    %r13,%rsi
  mov    $0x2,%edi
  mov    %rax,0x18(%rsp)
  call   <log_message@plt>
  movsd  0x8(%rsp),%xmm0
  jmp    L33
  nopl   0x0(%rax,%rax,1)
L29:
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L55
  add    $0x130,%rsp
  mov    %ebp,%esi
  mov    %r12d,%edi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    10c0 <fetch_sin_of_distance@plt>
L55:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
datatype: f64
name: parse_data
arguments: tag: D4
datatype: string
name: parse_data
arguments: tag: D20
datatype: string

tool: D8: 50

tool: D4: Failed to fetch (%d, %d) from the cache.

tool: D20: GEOMETRY_CACHE_MISS

assistant: ```c
double sin_of_distance(int x, int y, double wavelength) {
  x = abs(x);
  y = abs(y);
  if (wavelength == 50.0 && x <= 500 && y <= 500) {
    return fetch_sin_of_distance(x, y);
  } else {
    char message[256];
    if (sprintf(message, "Failed to fetch (%d, %d) from the cache.", x, y) > 0) {
      char *tags[] = {"GEOMETRY_CACHE_MISS"};
      log_message(2, message, tags, 1);
    }
    return evaluate_sin_of_distance(x, y, wavelength);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<measure_tsc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  lea    -0x30(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,-0x28(%rbp)
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    -0x2c(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,-0x20(%rbp)
  mov    -0x28(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jge    L5
  mov    -0x20(%rbp),%rax
  sub    -0x28(%rbp),%rax
  mov    %rax,%rbx
  jmp    L17
L5:
  mov    -0x28(%rbp),%rax
  sub    -0x20(%rbp),%rax
  mov    %rax,%rbx
L17:
  lea    -0x2c(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <ts_delta@plt>
  mov    %rax,%rcx
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movq   %xmm0,%rax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L28
  call   <__stack_chk_fail@plt>
L28:
  movq   %rax,%xmm0
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
double measure_tsc() {
  struct timeval t1, t2;
  gettimeofday(&t1, 0);
  uint64_t tsc1 = rdtsc();
  sleep(1);
  gettimeofday(&t2, 0);
  uint64_t tsc2 = rdtsc();
  return (tsc1 < tsc2 ? (tsc2 - tsc1) : (tsc1 - tsc2)) / ts_delta(&t1, &t2);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<measure_tsc>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,%rbp
  mov    $0x1,%edi
  call   <sleep@plt>
  lea    0x4(%rsp),%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  mov    $0x0,%eax
  call   <rdtsc@plt>
  mov    %rax,%rdx
  sub    %rbp,%rdx
  mov    %rbp,%rbx
  sub    %rax,%rbx
  cmp    %rax,%rbp
  cmovl  %rdx,%rbx
  lea    0x4(%rsp),%rsi
  mov    %rsp,%rdi
  call   <ts_delta@plt>
  mov    %rax,%rcx
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double measure_tsc() {
  struct timeval t1, t2;
  gettimeofday(&t1, 0);
  uint64_t tsc1 = rdtsc();
  sleep(1);
  gettimeofday(&t2, 0);
  uint64_t tsc2 = rdtsc();
  return (tsc1 < tsc2 ? (tsc2 - tsc1) : (tsc1 - tsc2)) / ts_delta(&t1, &t2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<measure_tsc>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4(%rsp),%r13
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    $0x1,%edi
  mov    %rax,%rbp
  call   <sleep@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rbp,%rbx
  call   <gettimeofday@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
  sub    %rbp,%rdx
  cmp    %rax,%rbp
  cmovl  %rdx,%rbx
  call   <ts_delta@plt>
  pxor   %xmm0,%xmm0
  mov    %rax,%r8
  mov    %rbx,%rax
  cqto
  idiv   %r8
  cvtsi2sd %rax,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double measure_tsc() {
  struct timeval t1, t2;
  gettimeofday(&t1, 0);
  uint64_t tsc1 = rdtsc();
  sleep(1);
  gettimeofday(&t2, 0);
  uint64_t tsc2 = rdtsc();
  return (tsc1 < tsc2 ? (tsc2 - tsc1) : (tsc1 - tsc2)) / ts_delta(&t1, &t2);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<measure_tsc>:
  endbr64
  push   %r13
  xor    %esi,%esi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x4(%rsp),%r13
  mov    %r12,%rdi
  call   <gettimeofday@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    $0x1,%edi
  mov    %rax,%rbp
  call   <sleep@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  mov    %rbp,%rbx
  call   <gettimeofday@plt>
  xor    %eax,%eax
  call   <rdtsc@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    %rax,%rdx
  sub    %rax,%rbx
  sub    %rbp,%rdx
  cmp    %rax,%rbp
  cmovl  %rdx,%rbx
  call   <ts_delta@plt>
  pxor   %xmm0,%xmm0
  mov    %rax,%r8
  mov    %rbx,%rax
  cqto
  idiv   %r8
  cvtsi2sd %rax,%xmm0
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
double measure_tsc() {
  struct timeval t1, t2;
  gettimeofday(&t1, 0);
  uint64_t tsc1 = rdtsc();
  sleep(1);
  gettimeofday(&t2, 0);
  uint64_t tsc2 = rdtsc();
  return (tsc1 < tsc2 ? (tsc2 - tsc1) : (tsc1 - tsc2)) / ts_delta(&t1, &t2);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xrop3_115_0_1>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%edx
  mov    %esi,%eax
  mov    %dl,-0x24(%rbp)
  mov    %al,-0x28(%rbp)
  movl   $0xff,-0x18(%rbp)
  movzbl -0x24(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x24(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x14(%rbp)
  movzbl -0x28(%rbp),%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzbl -0x28(%rbp),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  or     -0xc(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  notl   -0x4(%rbp)
  mov    -0x10(%rbp),%eax
  not    %eax
  or     -0x14(%rbp),%eax
  and    -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  not    %eax
  and    -0x10(%rbp),%eax
  and    -0x18(%rbp),%eax
  or     %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned xrop3_115_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<xrop3_115_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%edx
  or     $0xff,%dl
  and    %edi,%edx
  or     %edi,%eax
  not    %edx
  and    %edx,%eax
  not    %edi
  and    %esi,%edi
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_115_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xrop3_115_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%edx
  or     %edi,%eax
  or     $0xff,%dl
  and    %edi,%edx
  not    %edi
  not    %edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_115_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xrop3_115_0_1>:
  endbr64
  movzbl %dil,%eax
  mov    %eax,%edi
  shl    $0x8,%edi
  or     %eax,%edi
  movzbl %sil,%eax
  mov    %eax,%esi
  shl    $0x8,%esi
  or     %eax,%esi
  mov    %esi,%eax
  not    %eax
  mov    %eax,%edx
  or     %edi,%eax
  or     $0xff,%dl
  and    %edi,%edx
  not    %edi
  not    %edx
  and    %esi,%edi
  and    %edx,%eax
  movzbl %dil,%edi
  or     %edi,%eax
  ret
```

assistant: ```c
unsigned xrop3_115_0_1(unsigned char s, unsigned char t) {
  unsigned D = 0x00ff;
  unsigned S = ((unsigned)s << 8) | s;
  unsigned T = ((unsigned)t << 8) | t;
  unsigned stk1;
  unsigned stk2;
  unsigned stk3;
  stk3 = ~T;
  stk2 = D | stk3;
  stk1 = S & stk2;
  stk1 = ~stk1;
  return (stk1 & S) | (stk1 & (~T)) | (T & (~S) & D);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<char_needs_escaping>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  js     L43
  cmpl   $0x1f,-0x4(%rbp)
  jle    L10
  cmpl   $0x22,-0x4(%rbp)
  je     L10
  cmpl   $0x5c,-0x4(%rbp)
  jne    L43
L10:
  mov    $0x1,%eax
  jmp    L47
L43:
  mov    $0x0,%eax
L47:
  pop    %rbp
  ret
```

assistant: ```c
int char_needs_escaping(int c) {
  if ((c >= 0) && (c < 0x20 || c == 0x22 || c == 0x5c)) {
    return 1;
  }
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<char_needs_escaping>:
  endbr64
  mov    $0x0,%eax
  test   %edi,%edi
  js     L7
  cmp    $0x1f,%edi
  setle  %al
  cmp    $0x22,%edi
  sete   %dl
  or     %edx,%eax
  cmp    $0x5c,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int char_needs_escaping(int c) {
  if ((c >= 0) && (c < 0x20 || c == 0x22 || c == 0x5c)) {
    return 1;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<char_needs_escaping>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L3
  cmp    $0x1f,%edi
  setle  %al
  cmp    $0x22,%edi
  sete   %dl
  or     %edx,%eax
  cmp    $0x5c,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L3:
  ret
```

assistant: ```c
int char_needs_escaping(int c) {
  if ((c >= 0) && (c < 0x20 || c == 0x22 || c == 0x5c)) {
    return 1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<char_needs_escaping>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  js     L7
  cmp    $0x1f,%edi
  setle  %al
  cmp    $0x22,%edi
  sete   %dl
  or     %edx,%eax
  cmp    $0x5c,%edi
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
L7:
  ret
```

assistant: ```c
int char_needs_escaping(int c) {
  if ((c >= 0) && (c < 0x20 || c == 0x22 || c == 0x5c)) {
    return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <test_queue_array_pos@plt>
  mov    $0x0,%eax
  call   <test_queue_internals@plt>
  mov    $0x0,%eax
  call   <test_queue@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main() {
  test_queue_array_pos();
  test_queue_internals();
  test_queue();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <test_queue_array_pos@plt>
  mov    $0x0,%eax
  call   <test_queue_internals@plt>
  mov    $0x0,%eax
  call   <test_queue@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_queue_array_pos();
  test_queue_internals();
  test_queue();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_queue_array_pos@plt>
  xor    %eax,%eax
  call   <test_queue_internals@plt>
  xor    %eax,%eax
  call   <test_queue@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_queue_array_pos();
  test_queue_internals();
  test_queue();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <test_queue_array_pos@plt>
  xor    %eax,%eax
  call   <test_queue_internals@plt>
  xor    %eax,%eax
  call   <test_queue@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main() {
  test_queue_array_pos();
  test_queue_internals();
  test_queue();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fftBRInit>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    -0x38(%rbp),%rax
  mov    %rax,%rdx
  shr    $0x3f,%rdx
  add    %rdx,%rax
  sar    %rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movq   $0x0,-0x30(%rbp)
  jmp    L44
L30:
  movq   $0x0,-0x28(%rbp)
  movq   $0x1,-0x20(%rbp)
  movq   $0x1,-0x18(%rbp)
  jmp    L25
L4:
  mov    -0x30(%rbp),%rax
  and    -0x20(%rbp),%rax
  test   %rax,%rax
  je     L37
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  sar    %cl,%rax
  add    %rax,-0x28(%rbp)
L37:
  shlq   -0x20(%rbp)
  addq   $0x1,-0x18(%rbp)
L25:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jle    L4
  mov    -0x30(%rbp),%rax
  lea    (%rax,%rax,1),%rdx
  mov    -0x40(%rbp),%rax
  add    %rdx,%rax
  mov    -0x28(%rbp),%rdx
  mov    %dx,(%rax)
  addq   $0x1,-0x30(%rbp)
L44:
  mov    -0x30(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jl     L30
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void fftBRInit(long M, short *BRLow) {
  long Mroot_1 = M / 2 - 1;
  long Nroot_1 = ((unsigned long)1 << (Mroot_1));
  long i1;
  long bitsum;
  long bitmask;
  long bit;
  for (i1 = 0; i1 < Nroot_1; i1++) {
    bitsum = 0;
    bitmask = 1;
    for (bit = 1; bit <= Mroot_1; bitmask <<= 1, bit++)
      if (i1 & bitmask)
        bitsum = bitsum + (Nroot_1 >> bit);
    BRLow[i1] = bitsum;
  };
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<fftBRInit>:
  endbr64
  push   %rbx
  mov    %rsi,%r10
  mov    %rdi,%rax
  shr    $0x3f,%rax
  lea    (%rax,%rdi,1),%r9
  sar    %r9
  lea    -0x1(%r9),%r11
  mov    $0x1,%r8d
  mov    %r11d,%ecx
  shl    %cl,%r8
  mov    $0x0,%edi
  mov    $0x0,%ebx
  test   %r8,%r8
  jg     L18
L36:
  pop    %rbx
  ret
L48:
  mov    %r8,%rax
  sar    %cl,%rax
  add    %rdx,%rax
  test   %rsi,%rdi
  cmovne %rax,%rdx
  add    %rsi,%rsi
  add    $0x1,%rcx
  cmp    %rcx,%r9
  jne    L48
L7:
  mov    %dx,(%r10,%rdi,2)
  add    $0x1,%rdi
  cmp    %rdi,%r8
  je     L36
L18:
  mov    $0x1,%ecx
  mov    $0x1,%esi
  mov    %rbx,%rdx
  test   %r11,%r11
  jg     L48
  jmp    L7
```

assistant: ```c
void fftBRInit(long M, short *BRLow) {
  long Mroot_1 = M / 2 - 1;
  long Nroot_1 = ((unsigned long)1 << (Mroot_1));
  long i1;
  long bitsum;
  long bitmask;
  long bit;
  for (i1 = 0; i1 < Nroot_1; i1++) {
    bitsum = 0;
    bitmask = 1;
    for (bit = 1; bit <= Mroot_1; bitmask <<= 1, bit++)
      if (i1 & bitmask)
        bitsum = bitsum + (Nroot_1 >> bit);
    BRLow[i1] = bitsum;
  };
}
```