ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码:

```asm
<content_type>:
  endbr64
  push   %r12
  mov    %rdi,%rsi
  push   %rbp
  lea    D12(%rip),%rbp
  sub    $0x818,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x808(%rsp)
  xor    %eax,%eax
  lea    0x400(%rsp),%r12
  mov    %r12,%rdi
  call   <strcpy@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strtok@plt>
  xor    %edi,%edi
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %rsp,%rdi
  mov    %rax,%rsi
  call   <strcpy@plt>
  cmpl   $0x6c6d7468,(%rsp)
  je     L23
L0:
  cmpl   $0x6d7468,(%rsp)
  lea    D14(%rip),%rax
  lea    D11(%rip),%rdx
  cmove  %rdx,%rax
L5:
  mov    0x808(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L21
  add    $0x818,%rsp
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  cmpb   $0x0,0x4(%rsp)
  lea    D11(%rip),%rax
  je     L5
  jmp    L0
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D14
data_type: string
name: disassemble_data
arguments: data_tag: D11
data_type: string

tool: D12: .

tool: D14: text/plain

tool: D11: text/html

assistant: ```c
char *content_type(char *file) {
  char extension[1024];
  char file_name[1024];
  strcpy(file_name, file);
  strtok(file_name, ".");
  strcpy(extension, strtok(NULL, "."));
  if (!strcmp(extension, "html") || !strcmp(extension, "htm"))
    return "text/html";
  else
    return "text/plain";
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<testTrueAndEquals>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <cu_success_assertation@plt>
  mov    $0x0,%eax
  call   <cu_success_assertation@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void testTrueAndEquals(void) {
  if ((1)) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 50,
                        "1"
                        " is not true");
  };
  if (((1)) == ((1))) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 54,
                        "1"
                        " not equals "
                        "1");
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<testTrueAndEquals>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <cu_success_assertation@plt>
  mov    $0x0,%eax
  call   <cu_success_assertation@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void testTrueAndEquals(void) {
  if ((1)) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 50,
                        "1"
                        " is not true");
  };
  if (((1)) == ((1))) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 54,
                        "1"
                        " not equals "
                        "1");
  };
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<testTrueAndEquals>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cu_success_assertation@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <cu_success_assertation@plt>
```

assistant: ```c
void testTrueAndEquals(void) {
  if ((1)) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 50,
                        "1"
                        " is not true");
  };
  if (((1)) == ((1))) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 54,
                        "1"
                        " not equals "
                        "1");
  };
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<testTrueAndEquals>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <cu_success_assertation@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1050 <cu_success_assertation@plt>
```

assistant: ```c
void testTrueAndEquals(void) {
  if ((1)) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 50,
                        "1"
                        " is not true");
  };
  if (((1)) == ((1))) {
    cu_success_assertation();
  } else {
    cu_fail_assertation("/scratch/repos/new/home/jordi_armengol_estape/c-scraper/outputs/2022-01-22/02-19-57/repos/esromneb/embedded-c-unit-test/refs/heads/master/demo/tests.c", 54,
                        "1"
                        " not equals "
                        "1");
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<gcd>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  jne    L1
  mov    -0x8(%rbp),%rax
  jmp    L8
L1:
  mov    -0x8(%rbp),%rax
  cqto
  idivq  -0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <gcd>
L8:
  leave
  ret
```

assistant: ```c
int gcd(long int x, long int y) {
  if (y == 0)
    return x;
  return gcd(y, x % y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L5
  ret
L5:
  sub    $0x8,%rsp
  mov    %rsi,%rdi
  cqto
  idiv   %rsi
  mov    %rdx,%rsi
  call   <gcd>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gcd(long int x, long int y) {
  if (y == 0)
    return x;
  return gcd(y, x % y);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L27
  jmp    L1
  xchg   %ax,%ax
L28:
  mov    %rdx,%rsi
L27:
  cqto
  idiv   %rsi
  mov    %rsi,%rax
  test   %rdx,%rdx
  jne    L28
  mov    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L1:
  mov    %rdi,%rsi
  mov    %esi,%eax
  ret
```

assistant: ```c
int gcd(long int x, long int y) {
  if (y == 0)
    return x;
  return gcd(y, x % y);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gcd>:
  endbr64
  mov    %rdi,%rax
  test   %rsi,%rsi
  jne    L15
  jmp    L27
  xchg   %ax,%ax
L8:
  mov    %rdx,%rsi
L15:
  cqto
  idiv   %rsi
  mov    %rsi,%rax
  test   %rdx,%rdx
  jne    L8
  mov    %esi,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rdi,%rsi
  mov    %esi,%eax
  ret
```

assistant: ```c
int gcd(long int x, long int y) {
  if (y == 0)
    return x;
  return gcd(y, x % y);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<serialize_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    %ecx,(%rdx)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x8,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    %ecx,(%rdx)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x10,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    %ecx,(%rdx)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %esi,%edx
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%esi
  mov    -0x18(%rbp),%rax
  mov    (%rax),%eax
  lea    0x1(%rax),%ecx
  mov    -0x18(%rbp),%rdx
  mov    %ecx,(%rdx)
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  mov    %esi,%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void serialize_int(unsigned char *outputBlockData, unsigned int value, unsigned int *count) {
  outputBlockData[(*count)++] = value;
  outputBlockData[(*count)++] = value >> 8;
  outputBlockData[(*count)++] = value >> 16;
  outputBlockData[(*count)++] = value >> 24;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<serialize_int>:
  endbr64
  push   %rbx
  mov    %rdi,%rcx
  mov    %esi,%eax
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %esi,%esi
  mov    %al,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %esi,%esi
  movzbl %ah,%ebx
  mov    %bl,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %esi,%esi
  mov    %eax,%edi
  shr    $0x10,%edi
  mov    %dil,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %esi,%esi
  shr    $0x18,%eax
  mov    %al,(%rcx,%rsi,1)
  pop    %rbx
  ret
```

assistant: ```c
void serialize_int(unsigned char *outputBlockData, unsigned int value, unsigned int *count) {
  outputBlockData[(*count)++] = value;
  outputBlockData[(*count)++] = value >> 8;
  outputBlockData[(*count)++] = value >> 16;
  outputBlockData[(*count)++] = value >> 24;
}
```
user: What is the c source code of the assembly code below?

```asm
<serialize_int>:
  endbr64
  mov    %esi,%eax
  mov    (%rdx),%esi
  mov    %rdi,%rcx
  push   %rbx
  pop    %rbx
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %al,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %ah,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %eax,%edi
  shr    $0x18,%eax
  shr    $0x10,%edi
  mov    %dil,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %al,(%rcx,%rsi,1)
  ret
```

assistant: ```c
void serialize_int(unsigned char *outputBlockData, unsigned int value, unsigned int *count) {
  outputBlockData[(*count)++] = value;
  outputBlockData[(*count)++] = value >> 8;
  outputBlockData[(*count)++] = value >> 16;
  outputBlockData[(*count)++] = value >> 24;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<serialize_int>:
  endbr64
  mov    %esi,%eax
  mov    (%rdx),%esi
  mov    %rdi,%rcx
  push   %rbx
  pop    %rbx
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %al,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %ah,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %eax,%edi
  shr    $0x18,%eax
  shr    $0x10,%edi
  mov    %dil,(%rcx,%rsi,1)
  mov    (%rdx),%esi
  lea    0x1(%rsi),%edi
  mov    %edi,(%rdx)
  mov    %al,(%rcx,%rsi,1)
  ret
```

assistant: ```c
void serialize_int(unsigned char *outputBlockData, unsigned int value, unsigned int *count) {
  outputBlockData[(*count)++] = value;
  outputBlockData[(*count)++] = value >> 8;
  outputBlockData[(*count)++] = value >> 16;
  outputBlockData[(*count)++] = value >> 24;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jle    L9
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L9:
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D0
data_type: string

tool: D0: parent PID: %d


assistant: ```c
int main(void) {
  pid_t a;
  a = fork();
  if (a > 0)
    printf("parent PID: %d\n", getpid());
  else
    printf("");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <fork@plt>
  test   %rax,%rax
  jg     L10
L7:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L10:
  mov    $0x0,%eax
  call   <getpid@plt>
  mov    %eax,%esi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L7
```

tool_calls: name: unpack_data
arguments: label: D0
data_type: string

tool: D0: parent PID: %d


assistant: ```c
int main(void) {
  pid_t a;
  a = fork();
  if (a > 0)
    printf("parent PID: %d\n", getpid());
  else
    printf("");
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jle    L0
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D5(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: label: D5
type_guessed: string

tool: D5: parent PID: %d


assistant: ```c
int main(void) {
  pid_t a;
  a = fork();
  if (a > 0)
    printf("parent PID: %d\n", getpid());
  else
    printf("");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <fork@plt>
  test   %rax,%rax
  jle    L0
  xor    %eax,%eax
  call   <getpid@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
L0:
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_infered: string

tool: D8: parent PID: %d


assistant: ```c
int main(void) {
  pid_t a;
  a = fork();
  if (a > 0)
    printf("parent PID: %d\n", getpid());
  else
    printf("");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <findMaxConsecutiveOnes@plt>
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: %d


assistant: ```c
int main() {
  int array[2] = {1, 1};
  printf("%d\n", findMaxConsecutiveOnes(array, 2));
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x1,(%rsp)
  movl   $0x1,0x4(%rsp)
  mov    %rsp,%rdi
  mov    $0x2,%esi
  call   <findMaxConsecutiveOnes@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main() {
  int array[2] = {1, 1};
  printf("%d\n", findMaxConsecutiveOnes(array, 2));
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000001,%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <findMaxConsecutiveOnes@plt>
  lea    D2(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D2
type_guessed: string

tool: D2: %d


assistant: ```c
int main() {
  int array[2] = {1, 1};
  printf("%d\n", findMaxConsecutiveOnes(array, 2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x2,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D11(%rip),%rax
  mov    %rsp,%rdi
  mov    %rax,(%rsp)
  call   <findMaxConsecutiveOnes@plt>
  lea    D8(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D11
type_infered: byte[8]
name: read_data
arguments: data_tag: D8
type_infered: string

tool: {"D11": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

tool: D8: %d


assistant: ```c
int main() {
  int array[2] = {1, 1};
  printf("%d\n", findMaxConsecutiveOnes(array, 2));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smprintf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xe0,%rsp
  mov    %rdi,-0xd8(%rbp)
  mov    %rsi,-0xa8(%rbp)
  mov    %rdx,-0xa0(%rbp)
  mov    %rcx,-0x98(%rbp)
  mov    %r8,-0x90(%rbp)
  mov    %r9,-0x88(%rbp)
  test   %al,%al
  je     L6
  movaps %xmm0,-0x80(%rbp)
  movaps %xmm1,-0x70(%rbp)
  movaps %xmm2,-0x60(%rbp)
  movaps %xmm3,-0x50(%rbp)
  movaps %xmm4,-0x40(%rbp)
  movaps %xmm5,-0x30(%rbp)
  movaps %xmm6,-0x20(%rbp)
  movaps %xmm7,-0x10(%rbp)
L6:
  mov    %fs:0x28,%rax
  mov    %rax,-0xb8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0xc0(%rbp)
  mov    -0xd8(%rbp),%rdx
  mov    -0xc4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <va_start@plt>
  mov    -0xc4(%rbp),%edx
  mov    -0xd8(%rbp),%rcx
  lea    -0xc0(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <vasprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L8
  movq   $0x0,-0xc0(%rbp)
L8:
  mov    -0xc4(%rbp),%eax
  mov    %eax,%edi
  call   <va_end@plt>
  mov    -0xc0(%rbp),%rax
  mov    -0xb8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L4
  call   <__stack_chk_fail@plt>
L4:
  leave
  ret
```

assistant: ```c
char *smprintf(char *fmt, ...) {
  va_list fmtargs;
  char *buf = NULL;
  va_start(fmtargs, fmt);
  if (vasprintf(&buf, fmt, fmtargs) == -1)
    buf = NULL;
  va_end(fmtargs);
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<smprintf>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  mov    %rdi,%rsi
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  cmp    $0xffffffff,%eax
  je     L4
L15:
  mov    $0x0,%ebx
  mov    %ebx,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L4:
  movq   $0x0,(%rsp)
  jmp    L15
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *smprintf(char *fmt, ...) {
  va_list fmtargs;
  char *buf = NULL;
  va_start(fmtargs, fmt);
  if (vasprintf(&buf, fmt, fmtargs) == -1)
    buf = NULL;
  va_end(fmtargs);
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<smprintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L13
  movq   $0x0,(%rsp)
L13:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L12
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *smprintf(char *fmt, ...) {
  va_list fmtargs;
  char *buf = NULL;
  va_start(fmtargs, fmt);
  if (vasprintf(&buf, fmt, fmtargs) == -1)
    buf = NULL;
  va_end(fmtargs);
  return buf;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<smprintf>:
  endbr64
  push   %r12
  xor    %r12d,%r12d
  mov    %rdi,%rsi
  push   %rbp
  mov    %rdi,%rbp
  mov    %r12d,%edi
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  call   <va_start@plt>
  mov    %rsp,%rdi
  mov    %r12d,%edx
  mov    %rbp,%rsi
  call   <vasprintf@plt>
  cmp    $0xffffffff,%eax
  jne    L10
  movq   $0x0,(%rsp)
L10:
  xor    %edi,%edi
  call   <va_end@plt>
  mov    (%rsp),%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *smprintf(char *fmt, ...) {
  va_list fmtargs;
  char *buf = NULL;
  va_start(fmtargs, fmt);
  if (vasprintf(&buf, fmt, fmtargs) == -1)
    buf = NULL;
  va_end(fmtargs);
  return buf;
}
```
user: What is the c source code of the assembly code below:

```asm
<test_onepath>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <read_quaddobl_target_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <read_quaddobl_start_system@plt>
  mov    %eax,-0xc(%rbp)
  mov    $0x0,%eax
  call   <copy_quaddobl_start_solutions_to_container@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <solcon_number_of_quaddobl_solutions@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    D35(%rip),%rax
  pxor   %xmm1,%xmm1
  movq   %rax,%xmm0
  mov    $0x1,%edi
  call   <ade_onepath_qd@plt>
  mov    %eax,-0xc(%rbp)
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%eax
  call   <solcon_write_quaddobl_solutions@plt>
  mov    %eax,-0xc(%rbp)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
type_guessed: string
name: extract_symbolic_data
arguments: tag: D10
type_guessed: string
name: extract_symbolic_data
arguments: tag: D35
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D17
type_guessed: string

tool: D2: 
Tracking one solution path ...

tool: D10: The solution container has size %d.


tool: D35: 1

tool: D17: The solutions after Newton's method :

assistant: ```c
void test_onepath(void) {
  int fail, len;
  printf("\nTracking one solution path ...\n");
  fail = read_quaddobl_target_system();
  fail = read_quaddobl_start_system();
  fail = copy_quaddobl_start_solutions_to_container();
  fail = solcon_number_of_quaddobl_solutions(&len);
  printf("The solution container has size %d.\n", len);
  fail = ade_onepath_qd(1, 1.0, 0.0);
  printf("The solutions after Newton's method :\n");
  fail = solcon_write_quaddobl_solutions();
}
```