ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Translate the below assembly code into C programming language:

```asm
<ish_builtin_pwd>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <getcwd@plt>
  lea    D3(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

tool_calls: name: unpack_data
arguments: label: D3
data_type: string

tool: D3: %s


assistant: ```c
void ish_builtin_pwd(struct ish_shell_t *shell __attribute__((unused)), char **args __attribute__((unused))) {
  char *pwd = getcwd(NULL, 0);
  printf("%s\n", pwd);
  free(pwd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ish_builtin_pwd>:
  endbr64
  push   %rbp
  xor    %esi,%esi
  xor    %edi,%edi
  call   <getcwd@plt>
  lea    D7(%rip),%rdi
  mov    %rax,%rbp
  mov    %rax,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <free@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: %s


assistant: ```c
void ish_builtin_pwd(struct ish_shell_t *shell __attribute__((unused)), char **args __attribute__((unused))) {
  char *pwd = getcwd(NULL, 0);
  printf("%s\n", pwd);
  free(pwd);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x2,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  jmp    L12
L2:
  mov    -0x8(%rbp),%eax
  add    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L12:
  cmpl   $0x1dcd64ff,-0x8(%rbp)
  jle    L2
  mov    -0x4(%rbp),%eax
  sub    $0x6605cd81,%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: %d


assistant: ```c
int main() {
  int i = 2;
  int j = i;
  for (; i < 500000000; ++i)
    j += i;
  printf("%d\n", j - 1711656321);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x2,%eax
L4:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    $0x1dcd6500,%eax
  jne    L4
  lea    -0x6605cd81(%rdx),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type: string

tool: D8: %d


assistant: ```c
int main() {
  int i = 2;
  int j = i;
  for (; i < 500000000; ++i)
    j += i;
  printf("%d\n", j - 1711656321);
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x2,%edx
  mov    $0x2,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  add    %eax,%edx
  add    $0x1,%eax
  cmp    $0x1dcd6500,%eax
  jne    L6
  lea    -0x6605cd81(%rdx),%esi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %d


assistant: ```c
int main() {
  int i = 2;
  int j = i;
  for (; i < 500000000; ++i)
    j += i;
  printf("%d\n", j - 1711656321);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movdqa D20(%rip),%xmm0
  xor    %eax,%eax
  pxor   %xmm1,%xmm1
  movdqa D18(%rip),%xmm3
  xchg   %ax,%ax
L0:
  movdqa %xmm0,%xmm2
  add    $0x1,%eax
  paddd  %xmm3,%xmm0
  paddd  %xmm2,%xmm1
  cmp    $0x773593f,%eax
  jne    L0
  movdqa %xmm1,%xmm0
  lea    D28(%rip),%rdi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%esi
  sub    $0x2a6b0382,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D20
datatype: byte[16]
name: read_data
arguments: data_tag: D18
datatype: byte[16]
name: read_data
arguments: data_tag: D28
datatype: string

tool: {"D20": [0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D18": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D28: %d


assistant: ```c
int main() {
  int i = 2;
  int j = i;
  for (; i < 500000000; ++i)
    j += i;
  printf("%d\n", j - 1711656321);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x14(%rbp)
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L28
  movq   $0x1,-0x10(%rbp)
  jmp    L1
L23:
  mov    -0x14(%rbp),%eax
  cltq
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  imul   %edx,%eax
  mov    %eax,-0x14(%rbp)
  addq   $0x1,-0x10(%rbp)
L1:
  mov    -0x18(%rbp),%eax
  cltq
  cmp    %rax,-0x10(%rbp)
  jbe    L23
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L49
L28:
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
L49:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L33
  call   <__stack_chk_fail@plt>
L33:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D34
type_guessed: string
name: read_data
arguments: label: D24
type_guessed: string
name: read_data
arguments: label: D11
type_guessed: string
name: read_data
arguments: label: D26
type_guessed: string

tool: D34: Enter a number: 

tool: D24: %d

tool: D11: The factorial is %d 

tool: D26: Please enter appropriate input!

assistant: ```c
int main(void) {
  int num, fact = 1;
  printf("Enter a number: ");
  if (scanf("%d", &num) != 0) {
    for (size_t i = 1; i <= num; i++) {
      fact *= i;
    }
    printf("The factorial is %d ", fact);
  } else {
    printf("Please enter appropriate input!");
    goto end;
  }
end:
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D22(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L4
  movslq 0x4(%rsp),%rdx
  test   %rdx,%rdx
  je     L8
  mov    $0x1,%eax
  mov    $0x1,%esi
L48:
  imul   %eax,%esi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jbe    L48
L57:
  lea    D6(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L2:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L27
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L8:
  mov    $0x1,%esi
  jmp    L57
L4:
  lea    D27(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L2
L27:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D22
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D1
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D27
type_guessed: string

tool: D22: Enter a number: 

tool: D1: %d

tool: D6: The factorial is %d 

tool: D27: Please enter appropriate input!

assistant: ```c
int main(void) {
  int num, fact = 1;
  printf("Enter a number: ");
  if (scanf("%d", &num) != 0) {
    for (size_t i = 1; i <= num; i++) {
      fact *= i;
    }
    printf("The factorial is %d ", fact);
  } else {
    printf("Please enter appropriate input!");
    goto end;
  }
end:
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D39(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D27(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L23
  movslq 0x4(%rsp),%rdx
  test   %rdx,%rdx
  je     L47
  mov    $0x1,%eax
  mov    $0x1,%esi
  xchg   %ax,%ax
L9:
  imul   %eax,%esi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jbe    L9
L27:
  lea    D17(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L3:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L23:
  lea    D35(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L3
L47:
  mov    $0x1,%esi
  jmp    L27
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D39
data_type: string
name: unpack_data
arguments: data_tag: D27
data_type: string
name: unpack_data
arguments: data_tag: D17
data_type: string
name: unpack_data
arguments: data_tag: D35
data_type: string

tool: D39: Enter a number: 

tool: D27: %d

tool: D17: The factorial is %d 

tool: D35: Please enter appropriate input!

assistant: ```c
int main(void) {
  int num, fact = 1;
  printf("Enter a number: ");
  if (scanf("%d", &num) != 0) {
    for (size_t i = 1; i <= num; i++) {
      fact *= i;
    }
    printf("The factorial is %d ", fact);
  } else {
    printf("Please enter appropriate input!");
    goto end;
  }
end:
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D34(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D37(%rip),%rdi
  call   <scanf@plt>
  test   %rax,%rax
  je     L15
  movslq 0x4(%rsp),%rdx
  test   %rdx,%rdx
  je     L13
  mov    $0x1,%eax
  mov    $0x1,%esi
  xchg   %ax,%ax
L25:
  imul   %eax,%esi
  add    $0x1,%rax
  cmp    %rdx,%rax
  jbe    L25
L4:
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L58:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L43
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L15:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L58
L13:
  mov    $0x1,%esi
  jmp    L4
L43:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D34
data_type: string
name: extract_symbolic_data
arguments: tag: D37
data_type: string
name: extract_symbolic_data
arguments: tag: D39
data_type: string
name: extract_symbolic_data
arguments: tag: D12
data_type: string

tool: D34: Enter a number: 

tool: D37: %d

tool: D39: The factorial is %d 

tool: D12: Please enter appropriate input!

assistant: ```c
int main(void) {
  int num, fact = 1;
  printf("Enter a number: ");
  if (scanf("%d", &num) != 0) {
    for (size_t i = 1; i <= num; i++) {
      fact *= i;
    }
    printf("The factorial is %d ", fact);
  } else {
    printf("Please enter appropriate input!");
    goto end;
  }
end:
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<getline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x14(%rbp)
  movb   $0x0,-0x1d(%rbp)
  jmp    L14
L39:
  addl   $0x1,-0x18(%rbp)
L14:
  cmpl   $0x4f,-0x1c(%rbp)
  jg     L26
  mov    -0x1c(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,(%rbx)
  movzbl (%rbx),%eax
  cmp    $0xa,%al
  jne    L39
L26:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  jne    L38
  movl   $0x1,-0x14(%rbp)
L38:
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int getline(char strng[]) {
  int i = 0, count = 0, emptyStr = 0;
  char c = 0;
  while (i < (81 - 1) && (strng[i++] = getchar()) != '\n')
    count++;
  strng[i] = '\0';
  if (strng[0] == ' ') {
    emptyStr = 1;
  }
  return (emptyStr);
}
```
user: What is the c source code of the assembly code below:

```asm
<getline>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x1,%ebx
L5:
  mov    %ebx,%r12d
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %al,-0x1(%rbp,%rbx,1)
  cmp    $0xa,%al
  je     L17
  add    $0x1,%rbx
  cmp    $0x51,%rbx
  jne    L5
L17:
  movslq %r12d,%r12
  movb   $0x0,0x0(%rbp,%r12,1)
  cmpb   $0x20,0x0(%rbp)
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int getline(char strng[]) {
  int i = 0, count = 0, emptyStr = 0;
  char c = 0;
  while (i < (81 - 1) && (strng[i++] = getchar()) != '\n')
    count++;
  strng[i] = '\0';
  if (strng[0] == ' ') {
    emptyStr = 1;
  }
  return (emptyStr);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<getline>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L27:
  add    $0x1,%rbx
  cmp    $0x51,%rbx
  je     L36
L25:
  xor    %eax,%eax
  movslq %ebx,%r12
  call   <getchar@plt>
  mov    %al,-0x1(%rbp,%rbx,1)
  cmp    $0xa,%al
  jne    L27
L19:
  movb   $0x0,0x0(%rbp,%r12,1)
  xor    %eax,%eax
  cmpb   $0x20,0x0(%rbp)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L36:
  mov    $0x50,%r12d
  jmp    L19
```

assistant: ```c
int getline(char strng[]) {
  int i = 0, count = 0, emptyStr = 0;
  char c = 0;
  while (i < (81 - 1) && (strng[i++] = getchar()) != '\n')
    count++;
  strng[i] = '\0';
  if (strng[0] == ' ') {
    emptyStr = 1;
  }
  return (emptyStr);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getline>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    $0x1,%ebx
  jmp    L25
  nopw   0x0(%rax,%rax,1)
L11:
  add    $0x1,%rbx
  cmp    $0x51,%rbx
  je     L2
L25:
  xor    %eax,%eax
  movslq %ebx,%r12
  call   <getchar@plt>
  mov    %al,-0x1(%rbp,%rbx,1)
  cmp    $0xa,%al
  jne    L11
L12:
  movb   $0x0,0x0(%rbp,%r12,1)
  xor    %eax,%eax
  cmpb   $0x20,0x0(%rbp)
  pop    %rbx
  sete   %al
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x50,%r12d
  jmp    L12
```

assistant: ```c
int getline(char strng[]) {
  int i = 0, count = 0, emptyStr = 0;
  char c = 0;
  while (i < (81 - 1) && (strng[i++] = getchar()) != '\n')
    count++;
  strng[i] = '\0';
  if (strng[0] == ' ') {
    emptyStr = 1;
  }
  return (emptyStr);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hexencodemap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x220,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x214(%rbp)
  jmp    L12
L13:
  mov    -0x214(%rbp),%eax
  sar    $0x4,%eax
  cltq
  lea    D16(%rip),%rdx
  movzbl (%rax,%rdx,1),%edx
  mov    -0x214(%rbp),%eax
  cltq
  mov    %dl,-0x210(%rbp,%rax,1)
  mov    -0x214(%rbp),%eax
  and    $0xf,%eax
  cltq
  lea    D16(%rip),%rdx
  movzbl (%rax,%rdx,1),%edx
  mov    -0x214(%rbp),%eax
  cltq
  mov    %dl,-0x110(%rbp,%rax,1)
  addl   $0x1,-0x214(%rbp)
L12:
  cmpl   $0xff,-0x214(%rbp)
  jle    L13
  lea    -0x210(%rbp),%rax
  lea    D0(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <char_array_to_c@plt>
  lea    -0x110(%rbp),%rax
  lea    D25(%rip),%rdx
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <char_array_to_c@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L21
  call   <__stack_chk_fail@plt>
L21:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D16
data_type: string
name: disassemble_data
arguments: data_label: D0
data_type: string
name: disassemble_data
arguments: data_label: D25
data_type: string

tool: D16: 0123456789ABCDEF

tool: D0: gsHexEncodeMap1

tool: D25: gsHexEncodeMap2

assistant: ```c
void hexencodemap() {
  static const char sHexChars[] = "0123456789ABCDEF";
  int i;
  char hexEncode1[256];
  char hexEncode2[256];
  for (i = 0; i < 256; ++i) {
    hexEncode1[i] = sHexChars[i >> 4];
    hexEncode2[i] = sHexChars[i & 0x0f];
  }
  char_array_to_c(hexEncode1, 256, "gsHexEncodeMap1");
  char_array_to_c(hexEncode2, 256, "gsHexEncodeMap2");
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<hexencodemap>:
  endbr64
  sub    $0x218,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  lea    D9(%rip),%rcx
L18:
  mov    %eax,%edx
  sar    $0x4,%edx
  movslq %edx,%rdx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rsp,%rax,1)
  mov    %rax,%rdx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,0x100(%rsp,%rax,1)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L18
  mov    %rsp,%rdi
  lea    D19(%rip),%rdx
  mov    $0x100,%esi
  call   <char_array_to_c@plt>
  lea    0x100(%rsp),%rdi
  lea    D8(%rip),%rdx
  mov    $0x100,%esi
  call   <char_array_to_c@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x218,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string
name: retrieve_data
arguments: data_tag: D19
type: string
name: retrieve_data
arguments: data_tag: D8
type: string

tool: D9: 0123456789ABCDEF

tool: D19: gsHexEncodeMap1

tool: D8: gsHexEncodeMap2

assistant: ```c
void hexencodemap() {
  static const char sHexChars[] = "0123456789ABCDEF";
  int i;
  char hexEncode1[256];
  char hexEncode2[256];
  for (i = 0; i < 256; ++i) {
    hexEncode1[i] = sHexChars[i >> 4];
    hexEncode2[i] = sHexChars[i & 0x0f];
  }
  char_array_to_c(hexEncode1, 256, "gsHexEncodeMap1");
  char_array_to_c(hexEncode2, 256, "gsHexEncodeMap2");
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<hexencodemap>:
  endbr64
  sub    $0x218,%rsp
  mov    $0x30,%edx
  mov    $0x30,%ecx
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  mov    $0x1,%eax
  lea    -0x1(%rsp),%r8
  lea    0xff(%rsp),%rdi
  lea    D4(%rip),%rsi
  jmp    L8
  nopl   0x0(%rax)
L9:
  mov    %edx,%ecx
  and    $0xf,%edx
  sar    $0x4,%ecx
  movzbl (%rsi,%rdx,1),%edx
  movslq %ecx,%rcx
  movzbl (%rsi,%rcx,1),%ecx
L8:
  mov    %dl,(%rdi,%rax,1)
  mov    %eax,%edx
  mov    %cl,(%r8,%rax,1)
  add    $0x1,%rax
  cmp    $0x101,%rax
  jne    L9
  lea    D29(%rip),%rdx
  mov    $0x100,%esi
  mov    %rsp,%rdi
  call   <char_array_to_c@plt>
  lea    D6(%rip),%rdx
  mov    $0x100,%esi
  lea    0x100(%rsp),%rdi
  call   <char_array_to_c@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x218,%rsp
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type_infered: string
name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D6
type_infered: string

tool: D4: 0123456789ABCDEF

tool: D29: gsHexEncodeMap1

tool: D6: gsHexEncodeMap2

assistant: ```c
void hexencodemap() {
  static const char sHexChars[] = "0123456789ABCDEF";
  int i;
  char hexEncode1[256];
  char hexEncode2[256];
  for (i = 0; i < 256; ++i) {
    hexEncode1[i] = sHexChars[i >> 4];
    hexEncode2[i] = sHexChars[i & 0x0f];
  }
  char_array_to_c(hexEncode1, 256, "gsHexEncodeMap1");
  char_array_to_c(hexEncode2, 256, "gsHexEncodeMap2");
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<hexencodemap>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rcx
  sub    $0x210,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x208(%rsp)
  xor    %eax,%eax
  movb   $0x30,(%rsp)
  mov    $0x1,%eax
  mov    %rsp,%rdi
  movb   $0x30,0x100(%rsp)
  lea    0x100(%rsp),%rbp
  nopw   0x0(%rax,%rax,1)
L16:
  mov    %rax,%rdx
  and    $0xf,%edx
  movzbl (%rcx,%rdx,1),%esi
  mov    %eax,%edx
  sar    $0x4,%edx
  movslq %edx,%rdx
  mov    %sil,0x0(%rbp,%rax,1)
  movzbl (%rcx,%rdx,1),%edx
  mov    %dl,(%rdi,%rax,1)
  add    $0x1,%rax
  cmp    $0x100,%rax
  jne    L16
  lea    D7(%rip),%rdx
  mov    $0x100,%esi
  call   <char_array_to_c@plt>
  lea    D11(%rip),%rdx
  mov    $0x100,%esi
  mov    %rbp,%rdi
  call   <char_array_to_c@plt>
  mov    0x208(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x210,%rsp
  pop    %rbp
  ret
L17:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D13
data_type: string
name: retrieve_data
arguments: label: D7
data_type: string
name: retrieve_data
arguments: label: D11
data_type: string

tool: D13: 0123456789ABCDEF

tool: D7: gsHexEncodeMap1

tool: D11: gsHexEncodeMap2

assistant: ```c
void hexencodemap() {
  static const char sHexChars[] = "0123456789ABCDEF";
  int i;
  char hexEncode1[256];
  char hexEncode2[256];
  for (i = 0; i < 256; ++i) {
    hexEncode1[i] = sHexChars[i >> 4];
    hexEncode2[i] = sHexChars[i & 0x0f];
  }
  char_array_to_c(hexEncode1, 256, "gsHexEncodeMap1");
  char_array_to_c(hexEncode2, 256, "gsHexEncodeMap2");
}
```
user: What is the c source code of the assembly code below:

```asm
<_assert>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void _assert(char const *s1, int l, char const *s2) {
  (void)(s1);
  (void)(l);
  (void)(s2);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<_assert>:
  endbr64
  ret
```

assistant: ```c
void _assert(char const *s1, int l, char const *s2) {
  (void)(s1);
  (void)(l);
  (void)(s2);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<_assert>:
  endbr64
  ret
```

assistant: ```c
void _assert(char const *s1, int l, char const *s2) {
  (void)(s1);
  (void)(l);
  (void)(s2);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<_assert>:
  endbr64
  ret
```

assistant: ```c
void _assert(char const *s1, int l, char const *s2) {
  (void)(s1);
  (void)(l);
  (void)(s2);
}
```
user: Translate the below assembly code into C programming language:

```asm
<init_prng>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x12345,-0x30(%rbp)
  movq   $0x23456,-0x28(%rbp)
  movq   $0x34567,-0x20(%rbp)
  movq   $0x45678,-0x18(%rbp)
  movq   $0x4,-0x38(%rbp)
  mov    -0x38(%rbp),%rdx
  lea    -0x30(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <init_by_array64@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
void init_prng(void) {
  unsigned long long init[4] = {0x12345ULL, 0x23456ULL, 0x34567ULL, 0x45678ULL}, length = 4;
  init_by_array64(init, length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<init_prng>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movq   $0x12345,(%rsp)
  movq   $0x23456,0x8(%rsp)
  movq   $0x34567,0x10(%rsp)
  movq   $0x45678,0x18(%rsp)
  mov    %rsp,%rdi
  mov    $0x4,%esi
  call   <init_by_array64@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x38,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void init_prng(void) {
  unsigned long long init[4] = {0x12345ULL, 0x23456ULL, 0x34567ULL, 0x45678ULL}, length = 4;
  init_by_array64(init, length);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<init_prng>:
  endbr64
  sub    $0x38,%rsp
  mov    $0x4,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  movq   $0x12345,(%rsp)
  movq   $0x23456,0x8(%rsp)
  movq   $0x34567,0x10(%rsp)
  movq   $0x45678,0x18(%rsp)
  call   <init_by_array64@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x38,%rsp
  ret
L5:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void init_prng(void) {
  unsigned long long init[4] = {0x12345ULL, 0x23456ULL, 0x34567ULL, 0x45678ULL}, length = 4;
  init_by_array64(init, length);
}
```