ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<uninitvar_fpclassify>:
  endbr64
  sub    $0x18,%rsp
  fldz
  fstpt  (%rsp)
  call   <fpclassify@plt>
  fldz
  lea    -0x10(%rsp),%rsp
  fstpt  (%rsp)
  call   <fpclassify@plt>
  add    $0x20,%rsp
  push   $0x0
  push   $0x0
  call   <fpclassify@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void uninitvar_fpclassify(void) {
  float f;
  (void)fpclassify(f);
  double d;
  (void)fpclassify(d);
  long double ld;
  (void)fpclassify(ld);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uninitvar_fpclassify>:
  endbr64
  sub    $0x18,%rsp
  fldz
  fstpt  (%rsp)
  call   <fpclassify@plt>
  sub    $0x10,%rsp
  fldz
  fstpt  (%rsp)
  call   <fpclassify@plt>
  add    $0x20,%rsp
  push   $0x0
  push   $0x0
  call   <fpclassify@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void uninitvar_fpclassify(void) {
  float f;
  (void)fpclassify(f);
  double d;
  (void)fpclassify(d);
  long double ld;
  (void)fpclassify(ld);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<uninitvar_fpclassify>:
  endbr64
  sub    $0x18,%rsp
  fldz
  fstpt  (%rsp)
  call   <fpclassify@plt>
  sub    $0x10,%rsp
  fldz
  fstpt  (%rsp)
  call   <fpclassify@plt>
  add    $0x20,%rsp
  push   $0x0
  push   $0x0
  call   <fpclassify@plt>
  add    $0x18,%rsp
  ret
```

assistant: ```c
void uninitvar_fpclassify(void) {
  float f;
  (void)fpclassify(f);
  double d;
  (void)fpclassify(d);
  long double ld;
  (void)fpclassify(ld);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ReadUINT>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  cmpq   $0x0,-0x18(%rbp)
  je     L6
  cmpq   $0x0,-0x20(%rbp)
  jne    L5
L6:
  mov    $0x0,%eax
  jmp    L49
L5:
  mov    -0x20(%rbp),%rdx
  lea    -0xc(%rbp),%rax
  mov    %rdx,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <fread@plt>
  cmp    $0x1,%eax
  je     L12
  mov    $0x0,%eax
  jmp    L49
L12:
  movzbl -0x9(%rbp),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  mov    %eax,%edx
  movzbl -0xa(%rbp),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  or     %eax,%edx
  movzbl -0xb(%rbp),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  or     %eax,%edx
  movzbl -0xc(%rbp),%eax
  movzbl %al,%eax
  or     %edx,%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,(%rax)
  mov    $0x1,%eax
L49:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

assistant: ```c
int ReadUINT(unsigned long int *x, FILE *f) {
  unsigned char little[4];
  if (x == NULL || f == NULL) {
    return 0;
  }
  if (fread(little, 4, 1, f) != 1) {
    return 0;
  }
  *x = (little[3] << 24 | little[2] << 16 | little[1] << 8 | little[0]);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ReadUINT>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L32
  mov    %rdi,%rbx
  test   %rsi,%rsi
  je     L32
  lea    0x4(%rsp),%rdi
  mov    %rsi,%rcx
  mov    $0x1,%edx
  mov    $0x4,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  jne    L17
  movzbl 0x7(%rsp),%edx
  shl    $0x18,%edx
  movzbl 0x6(%rsp),%ecx
  shl    $0x10,%ecx
  or     %ecx,%edx
  movzbl 0x4(%rsp),%ecx
  or     %ecx,%edx
  movzbl 0x5(%rsp),%ecx
  shl    $0x8,%ecx
  or     %ecx,%edx
  movslq %edx,%rdx
  mov    %rdx,(%rbx)
  jmp    L22
L32:
  mov    $0x0,%eax
L22:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L16
  add    $0x10,%rsp
  pop    %rbx
  ret
L17:
  mov    $0x0,%eax
  jmp    L22
L16:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadUINT(unsigned long int *x, FILE *f) {
  unsigned char little[4];
  if (x == NULL || f == NULL) {
    return 0;
  }
  if (fread(little, 4, 1, f) != 1) {
    return 0;
  }
  *x = (little[3] << 24 | little[2] << 16 | little[1] << 8 | little[0]);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ReadUINT>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L4
  mov    %rsi,%rcx
  test   %rsi,%rsi
  je     L4
  mov    %rdi,%rbx
  mov    $0x1,%edx
  lea    0x4(%rsp),%rdi
  mov    $0x4,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  jne    L4
  movslq 0x4(%rsp),%rdx
  mov    %rdx,(%rbx)
  jmp    L41
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
L41:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L35
  add    $0x10,%rsp
  pop    %rbx
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadUINT(unsigned long int *x, FILE *f) {
  unsigned char little[4];
  if (x == NULL || f == NULL) {
    return 0;
  }
  if (fread(little, 4, 1, f) != 1) {
    return 0;
  }
  *x = (little[3] << 24 | little[2] << 16 | little[1] << 8 | little[0]);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<ReadUINT>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L40
  mov    %rsi,%rcx
  test   %rsi,%rsi
  je     L40
  mov    %rdi,%rbx
  mov    $0x1,%edx
  lea    0x4(%rsp),%rdi
  mov    $0x4,%esi
  call   <fread@plt>
  cmp    $0x1,%eax
  jne    L40
  movslq 0x4(%rsp),%rdx
  mov    %rdx,(%rbx)
  jmp    L29
  nopl   0x0(%rax)
L40:
  xor    %eax,%eax
L29:
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L25
  add    $0x10,%rsp
  pop    %rbx
  ret
L25:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int ReadUINT(unsigned long int *x, FILE *f) {
  unsigned char little[4];
  if (x == NULL || f == NULL) {
    return 0;
  }
  if (fread(little, 4, 1, f) != 1) {
    return 0;
  }
  *x = (little[3] << 24 | little[2] << 16 | little[1] << 8 | little[0]);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<default_mutex_create>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    -0x8(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  movl   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void default_mutex_create(void **mutex) {
  *mutex = malloc(sizeof(int));
  *(int *)*mutex = 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<default_mutex_create>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movl   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void default_mutex_create(void **mutex) {
  *mutex = malloc(sizeof(int));
  *(int *)*mutex = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<default_mutex_create>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movl   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void default_mutex_create(void **mutex) {
  *mutex = malloc(sizeof(int));
  *(int *)*mutex = 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<default_mutex_create>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <malloc@plt>
  mov    %rax,(%rbx)
  movl   $0x0,(%rax)
  pop    %rbx
  ret
```

assistant: ```c
void default_mutex_create(void **mutex) {
  *mutex = malloc(sizeof(int));
  *(int *)*mutex = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_empty_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x1c0,%esi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <make_dir@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <is_dir@plt>
  mov    %eax,%ecx
  mov    $0x35,%edx
  lea    D6(%rip),%rax
  mov    %rax,%rsi
  mov    %ecx,%edi
  mov    $0x0,%eax
  call   <seatest_assert_true@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D6
data_type: string

tool: D6: create_empty_dir

assistant: ```c
void create_empty_dir(const char dir[]) {
  make_dir(dir, 0700);
  do {
    seatest_assert_true(is_dir(dir), __FUNCTION__, 53);
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_empty_dir>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x1c0,%esi
  mov    $0x0,%eax
  call   <make_dir@plt>
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <is_dir@plt>
  mov    %eax,%edi
  mov    $0x35,%edx
  lea    D5(%rip),%rsi
  mov    $0x0,%eax
  call   <seatest_assert_true@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
data_type: string

tool: D5: create_empty_dir

assistant: ```c
void create_empty_dir(const char dir[]) {
  make_dir(dir, 0700);
  do {
    seatest_assert_true(is_dir(dir), __FUNCTION__, 53);
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<create_empty_dir>:
  endbr64
  push   %rbp
  mov    $0x1c0,%esi
  mov    %rdi,%rbp
  xor    %eax,%eax
  call   <make_dir@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <is_dir@plt>
  mov    $0x35,%edx
  lea    D1(%rip),%rsi
  pop    %rbp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1090 <seatest_assert_true@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: create_empty_dir

assistant: ```c
void create_empty_dir(const char dir[]) {
  make_dir(dir, 0700);
  do {
    seatest_assert_true(is_dir(dir), __FUNCTION__, 53);
  } while (0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<create_empty_dir>:
  endbr64
  push   %rbp
  mov    $0x1c0,%esi
  mov    %rdi,%rbp
  xor    %eax,%eax
  call   <make_dir@plt>
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <is_dir@plt>
  mov    $0x35,%edx
  lea    D3(%rip),%rsi
  pop    %rbp
  mov    %eax,%edi
  xor    %eax,%eax
  jmp    1090 <seatest_assert_true@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
type_infered: string

tool: D3: create_empty_dir

assistant: ```c
void create_empty_dir(const char dir[]) {
  make_dir(dir, 0700);
  do {
    seatest_assert_true(is_dir(dir), __FUNCTION__, 53);
  } while (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<PinLock>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    $0x400,%eax
  mov    (%rax),%rax
  and    $0xfffe,%eax
  test   %rax,%rax
  je     L0
  mov    $0x4402e190,%edx
  mov    -0x8(%rbp),%rax
  not    %rax
  mov    %rax,(%rdx)
  mov    $0x4402e16c,%eax
  mov    (%rax),%rax
  mov    $0x4402e16c,%edx
  or     $0x3000000,%rax
  mov    %rax,(%rdx)
L0:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void PinLock(unsigned long ulOutEnable) {
  if (((*((volatile unsigned long *)(0x00000400))) & 0xFFFF) >= 2) {
    (*((volatile unsigned long *)(0x4402E000 + 0x00000190))) = ~ulOutEnable;
    (*((volatile unsigned long *)(0x4402E000 + 0x0000016C))) |= (3 << 24);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<PinLock>:
  endbr64
  mov    0x400,%rax
  test   $0xfffe,%eax
  je     L6
  not    %rdi
  mov    %rdi,0x4402e190
  mov    0x4402e16c,%rax
  or     $0x3000000,%rax
  mov    %rax,0x4402e16c
L6:
  ret
```

assistant: ```c
void PinLock(unsigned long ulOutEnable) {
  if (((*((volatile unsigned long *)(0x00000400))) & 0xFFFF) >= 2) {
    (*((volatile unsigned long *)(0x4402E000 + 0x00000190))) = ~ulOutEnable;
    (*((volatile unsigned long *)(0x4402E000 + 0x0000016C))) |= (3 << 24);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<PinLock>:
  endbr64
  mov    0x400,%rax
  test   $0xfffe,%eax
  je     L4
  not    %rdi
  mov    %rdi,0x4402e190
  mov    0x4402e16c,%rax
  or     $0x3000000,%rax
  mov    %rax,0x4402e16c
L4:
  ret
```

assistant: ```c
void PinLock(unsigned long ulOutEnable) {
  if (((*((volatile unsigned long *)(0x00000400))) & 0xFFFF) >= 2) {
    (*((volatile unsigned long *)(0x4402E000 + 0x00000190))) = ~ulOutEnable;
    (*((volatile unsigned long *)(0x4402E000 + 0x0000016C))) |= (3 << 24);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<PinLock>:
  endbr64
  mov    0x400,%rax
  test   $0xfffe,%eax
  je     L8
  not    %rdi
  mov    %rdi,0x4402e190
  mov    0x4402e16c,%rax
  or     $0x3000000,%rax
  mov    %rax,0x4402e16c
L8:
  ret
```

assistant: ```c
void PinLock(unsigned long ulOutEnable) {
  if (((*((volatile unsigned long *)(0x00000400))) & 0xFFFF) >= 2) {
    (*((volatile unsigned long *)(0x4402E000 + 0x00000190))) = ~ulOutEnable;
    (*((volatile unsigned long *)(0x4402E000 + 0x0000016C))) |= (3 << 24);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<ccAddInclude>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <BASM_PP_AddIncludePathFront@plt>
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D7
type_guessed: string

tool: D7: Add include '%s'


assistant: ```c
void ccAddInclude(char *path) {
  int i;
  printf("Add include '%s'\n", path);
  BASM_PP_AddIncludePathFront(path);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ccAddInclude>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <BASM_PP_AddIncludePathFront@plt>
  pop    %rbx
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
type_infered: string

tool: D0: Add include '%s'


assistant: ```c
void ccAddInclude(char *path) {
  int i;
  printf("Add include '%s'\n", path);
  BASM_PP_AddIncludePathFront(path);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ccAddInclude>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <BASM_PP_AddIncludePathFront@plt>
```

tool_calls: name: read_data
arguments: data_tag: D5
type: string

tool: D5: Add include '%s'


assistant: ```c
void ccAddInclude(char *path) {
  int i;
  printf("Add include '%s'\n", path);
  BASM_PP_AddIncludePathFront(path);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ccAddInclude>:
  endbr64
  push   %rbp
  mov    %rdi,%rsi
  mov    %rdi,%rbp
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1070 <BASM_PP_AddIncludePathFront@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type_infered: string

tool: D7: Add include '%s'


assistant: ```c
void ccAddInclude(char *path) {
  int i;
  printf("Add include '%s'\n", path);
  BASM_PP_AddIncludePathFront(path);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strlen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L18
L12:
  addq   $0x1,-0x18(%rbp)
L18:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L12
  mov    -0x18(%rbp),%rax
  sub    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int strlen(const char *p) {
  const char *q = p;
  while (*p)
    p++;
  return p - q;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L16
  mov    %rdi,%rax
L0:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L0
L4:
  sub    %edi,%eax
  ret
L16:
  mov    %rdi,%rax
  jmp    L4
```

assistant: ```c
int strlen(const char *p) {
  const char *q = p;
  while (*p)
    p++;
  return p - q;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L3
  mov    %rdi,%rax
  nopl   0x0(%rax)
L16:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L16
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L3:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strlen(const char *p) {
  const char *q = p;
  while (*p)
    p++;
  return p - q;
}
```
user: What is the c source code of the assembly code below?

```asm
<strlen>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L5
  mov    %rdi,%rax
  nopl   0x0(%rax)
L19:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L19
  sub    %edi,%eax
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
int strlen(const char *p) {
  const char *q = p;
  while (*p)
    p++;
  return p - q;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<duffs_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  shr    $0x1d,%edx
  add    %edx,%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  ja     L2
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D8(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D8(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L21:
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  jmp    L26
  nop
L26:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L21
L2:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void duffs_loop(int n) {
  int i = 0;
  switch (n % 8) {
  case 7:
    while (i < n) {
      i++;
    case 6:
      i++;
    case 5:
      i++;
    case 4:
      i++;
    case 3:
      i++;
    case 2:
      i++;
    case 1:
      i++;
    case 0:
      i++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<duffs_loop>:
  endbr64
  mov    %edi,%ecx
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  mov    %eax,%edx
  cmp    $0x7,%eax
  ja     L66
  mov    %eax,%eax
  lea    D8(%rip),%rsi
  movslq (%rsi,%rax,4),%rax
  add    %rsi,%rax
  notrack jmp *%rax
L22:
  add    $0x1,%edx
  jmp    L77
  mov    $0x0,%edx
L77:
  add    $0x1,%edx
L5:
  add    $0x1,%edx
L21:
  add    $0x1,%edx
L70:
  add    $0x1,%edx
L58:
  add    $0x1,%edx
L86:
  add    $0x1,%edx
  add    $0x1,%edx
  jmp    L65
  mov    $0x0,%edx
  jmp    L5
  mov    $0x0,%edx
  jmp    L21
  mov    $0x0,%edx
  jmp    L70
  mov    $0x0,%edx
  jmp    L58
  mov    $0x0,%edx
  jmp    L86
  mov    $0x0,%edx
L65:
  cmp    %ecx,%edx
  jl     L22
L66:
  ret
```

assistant: ```c
void duffs_loop(int n) {
  int i = 0;
  switch (n % 8) {
  case 7:
    while (i < n) {
      i++;
    case 6:
      i++;
    case 5:
      i++;
    case 4:
      i++;
    case 3:
      i++;
    case 2:
      i++;
    case 1:
      i++;
    case 0:
      i++;
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<duffs_loop>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  ja     L62
  lea    D8(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0x7,%eax
  nopl   (%rax)
L67:
  cmp    %edi,%eax
  jge    L62
L99:
  add    $0x8,%eax
  cmp    %edi,%eax
  jl     L99
L62:
  ret
  nopl   0x0(%rax)
  xor    %eax,%eax
  jmp    L67
  nopl   0x0(%rax)
  mov    $0x1,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
  mov    $0x5,%eax
  jmp    L67
  nopw   0x0(%rax,%rax,1)
  mov    $0x6,%eax
  jmp    L67
```

assistant: ```c
void duffs_loop(int n) {
  int i = 0;
  switch (n % 8) {
  case 7:
    while (i < n) {
      i++;
    case 6:
      i++;
    case 5:
      i++;
    case 4:
      i++;
    case 3:
      i++;
    case 2:
      i++;
    case 1:
      i++;
    case 0:
      i++;
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<duffs_loop>:
  endbr64
  mov    %edi,%edx
  sar    $0x1f,%edx
  shr    $0x1d,%edx
  lea    (%rdi,%rdx,1),%eax
  and    $0x7,%eax
  sub    %edx,%eax
  cmp    $0x7,%eax
  ja     L67
  lea    D9(%rip),%rdx
  movslq (%rdx,%rax,4),%rax
  add    %rdx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  mov    $0x7,%eax
  nopl   (%rax)
L66:
  cmp    %edi,%eax
  jge    L67
L0:
  add    $0x8,%eax
  cmp    %edi,%eax
  jl     L0
L67:
  ret
  nopl   0x0(%rax)
  xor    %eax,%eax
  jmp    L66
  nopl   0x0(%rax)
  mov    $0x1,%eax
  jmp    L66
  nopw   0x0(%rax,%rax,1)
  mov    $0x2,%eax
  jmp    L66
  nopw   0x0(%rax,%rax,1)
  mov    $0x3,%eax
  jmp    L66
  nopw   0x0(%rax,%rax,1)
  mov    $0x4,%eax
  jmp    L66
  nopw   0x0(%rax,%rax,1)
  mov    $0x5,%eax
  jmp    L66
  nopw   0x0(%rax,%rax,1)
  mov    $0x6,%eax
  jmp    L66
```

assistant: ```c
void duffs_loop(int n) {
  int i = 0;
  switch (n % 8) {
  case 7:
    while (i < n) {
      i++;
    case 6:
      i++;
    case 5:
      i++;
    case 4:
      i++;
    case 3:
      i++;
    case 2:
      i++;
    case 1:
      i++;
    case 0:
      i++;
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adb_command>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <adb_connect@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L31
  mov    $0xffffffff,%eax
  jmp    L7
L31:
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <adb_status@plt>
  test   %rax,%rax
  je     L5
  mov    -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <adb_close@plt>
  mov    $0xffffffff,%eax
  jmp    L7
L5:
  mov    $0x0,%eax
L7:
  leave
  ret
```

assistant: ```c
int adb_command(const char *service) {
  int fd = adb_connect(service);
  if (fd < 0) {
    return -1;
  }
  if (adb_status(fd)) {
    adb_close(fd);
    return -1;
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<adb_command>:
  endbr64
  push   %rbx
  call   <adb_connect@plt>
  test   %eax,%eax
  js     L18
  mov    %eax,%ebx
  mov    %eax,%edi
  call   <adb_status@plt>
  test   %rax,%rax
  jne    L29
  mov    $0x0,%eax
L23:
  pop    %rbx
  ret
L29:
  mov    %ebx,%edi
  call   <adb_close@plt>
  mov    $0xffffffff,%eax
  jmp    L23
L18:
  mov    $0xffffffff,%eax
  jmp    L23
```

assistant: ```c
int adb_command(const char *service) {
  int fd = adb_connect(service);
  if (fd < 0) {
    return -1;
  }
  if (adb_status(fd)) {
    adb_close(fd);
    return -1;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<adb_command>:
  endbr64
  push   %rbp
  call   <adb_connect@plt>
  test   %eax,%eax
  js     L10
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <adb_status@plt>
  test   %rax,%rax
  jne    L0
  xor    %eax,%eax
  pop    %rbp
  ret
L10:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L0:
  mov    %ebp,%edi
  call   <adb_close@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int adb_command(const char *service) {
  int fd = adb_connect(service);
  if (fd < 0) {
    return -1;
  }
  if (adb_status(fd)) {
    adb_close(fd);
    return -1;
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<adb_command>:
  endbr64
  push   %rbp
  call   <adb_connect@plt>
  test   %eax,%eax
  js     L16
  mov    %eax,%edi
  mov    %eax,%ebp
  call   <adb_status@plt>
  test   %rax,%rax
  jne    L2
  xor    %eax,%eax
  pop    %rbp
  ret
L16:
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
L2:
  mov    %ebp,%edi
  call   <adb_close@plt>
  mov    $0xffffffff,%eax
  pop    %rbp
  ret
```

assistant: ```c
int adb_command(const char *service) {
  int fd = adb_connect(service);
  if (fd < 0) {
    return -1;
  }
  if (adb_status(fd)) {
    adb_close(fd);
    return -1;
  }
  return 0;
}
```