ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<ex3>:
  endbr64
  push   %rbx
  lea    D39(%rip),%rbx
  mov    %rbx,%rdi
  call   <print@plt>
  lea    D0(%rip),%rdi
  call   <print@plt>
  lea    D17(%rip),%rdi
  call   <print@plt>
  lea    D54(%rip),%rdi
  call   <print@plt>
  lea    D41(%rip),%rdi
  call   <print@plt>
  lea    D31(%rip),%rdi
  call   <print@plt>
  mov    %rbx,%rdi
  call   <print@plt>
  pop    %rbx
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D39
data_type: string
name: extract_symbolic_data
arguments: label: D0
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D54
data_type: string
name: extract_symbolic_data
arguments: label: D41
data_type: string
name: extract_symbolic_data
arguments: label: D31
data_type: string

tool: D39: 
------------------------------


tool: D0: Indique, para cada expressao logica abaixo, se ela retornara um valor TRUE ou FALSE.

tool: D17: [1 > 3 || (! (5 <= 8)) && 6 == 7] e FALSE.

tool: D54: [!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e TRUE.

tool: D41: [7%4 == 3 && !(20/5 == 5)] e TRUE.

tool: D31: [(23.1 >= 64/3) || ('b' == 'a')] e TRUE.

assistant: ```c
void ex3() {
  print("\n------------------------------\n");
  print("Indique, para cada expressao logica abaixo, se ela retornara um valor TRUE ou FALSE.");
  if (1 > 3 || (!(5 <= 8)) && 6 == 7) {
    print("[1 > 3 || (! (5 <= 8)) && 6 == 7] e TRUE.");
  } else {
    print("[1 > 3 || (! (5 <= 8)) && 6 == 7] e FALSE.");
  }
  if (!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))) {
    print("[!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e TRUE.");
  } else {
    print("[!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e FALSE.");
  }
  if (7 % 4 == 3 && !(20 / 5 == 5)) {
    print("[7%4 == 3 && !(20/5 == 5)] e TRUE.");
  } else {
    print("[7%4 == 3 && !(20/5 == 5)] e FALSE.");
  }
  if ((23.1 >= 64 / 3) || ('b' == 'a')) {
    print("[(23.1 >= 64/3) || ('b' == 'a')] e TRUE.");
  } else {
    print("[(23.1 >= 64/3) || ('b' == 'a')] e FALSE.");
  }
  print("\n------------------------------\n");
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ex3>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rbp
  mov    %rbp,%rdi
  call   <print@plt>
  lea    D36(%rip),%rdi
  call   <print@plt>
  lea    D23(%rip),%rdi
  call   <print@plt>
  lea    D21(%rip),%rdi
  call   <print@plt>
  lea    D56(%rip),%rdi
  call   <print@plt>
  lea    D32(%rip),%rdi
  call   <print@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <print@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
type: string
name: read_data
arguments: data_label: D36
type: string
name: read_data
arguments: data_label: D23
type: string
name: read_data
arguments: data_label: D21
type: string
name: read_data
arguments: data_label: D56
type: string
name: read_data
arguments: data_label: D32
type: string

tool: D16: 
------------------------------


tool: D36: Indique, para cada expressao logica abaixo, se ela retornara um valor TRUE ou FALSE.

tool: D23: [1 > 3 || (! (5 <= 8)) && 6 == 7] e FALSE.

tool: D21: [!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e TRUE.

tool: D56: [7%4 == 3 && !(20/5 == 5)] e TRUE.

tool: D32: [(23.1 >= 64/3) || ('b' == 'a')] e TRUE.

assistant: ```c
void ex3() {
  print("\n------------------------------\n");
  print("Indique, para cada expressao logica abaixo, se ela retornara um valor TRUE ou FALSE.");
  if (1 > 3 || (!(5 <= 8)) && 6 == 7) {
    print("[1 > 3 || (! (5 <= 8)) && 6 == 7] e TRUE.");
  } else {
    print("[1 > 3 || (! (5 <= 8)) && 6 == 7] e FALSE.");
  }
  if (!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))) {
    print("[!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e TRUE.");
  } else {
    print("[!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e FALSE.");
  }
  if (7 % 4 == 3 && !(20 / 5 == 5)) {
    print("[7%4 == 3 && !(20/5 == 5)] e TRUE.");
  } else {
    print("[7%4 == 3 && !(20/5 == 5)] e FALSE.");
  }
  if ((23.1 >= 64 / 3) || ('b' == 'a')) {
    print("[(23.1 >= 64/3) || ('b' == 'a')] e TRUE.");
  } else {
    print("[(23.1 >= 64/3) || ('b' == 'a')] e FALSE.");
  }
  print("\n------------------------------\n");
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ex3>:
  endbr64
  push   %rbp
  lea    D14(%rip),%rbp
  mov    %rbp,%rdi
  call   <print@plt>
  lea    D45(%rip),%rdi
  call   <print@plt>
  lea    D2(%rip),%rdi
  call   <print@plt>
  lea    D46(%rip),%rdi
  call   <print@plt>
  lea    D49(%rip),%rdi
  call   <print@plt>
  lea    D33(%rip),%rdi
  call   <print@plt>
  mov    %rbp,%rdi
  pop    %rbp
  jmp    1050 <print@plt>
```

tool_calls: name: read_data
arguments: tag: D14
type_infered: string
name: read_data
arguments: tag: D45
type_infered: string
name: read_data
arguments: tag: D2
type_infered: string
name: read_data
arguments: tag: D46
type_infered: string
name: read_data
arguments: tag: D49
type_infered: string
name: read_data
arguments: tag: D33
type_infered: string

tool: D14: 
------------------------------


tool: D45: Indique, para cada expressao logica abaixo, se ela retornara um valor TRUE ou FALSE.

tool: D2: [1 > 3 || (! (5 <= 8)) && 6 == 7] e FALSE.

tool: D46: [!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e TRUE.

tool: D49: [7%4 == 3 && !(20/5 == 5)] e TRUE.

tool: D33: [(23.1 >= 64/3) || ('b' == 'a')] e TRUE.

assistant: ```c
void ex3() {
  print("\n------------------------------\n");
  print("Indique, para cada expressao logica abaixo, se ela retornara um valor TRUE ou FALSE.");
  if (1 > 3 || (!(5 <= 8)) && 6 == 7) {
    print("[1 > 3 || (! (5 <= 8)) && 6 == 7] e TRUE.");
  } else {
    print("[1 > 3 || (! (5 <= 8)) && 6 == 7] e FALSE.");
  }
  if (!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))) {
    print("[!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e TRUE.");
  } else {
    print("[!((2 >= 5) && (5 <= 8) || ((4 + 3) > 7))] e FALSE.");
  }
  if (7 % 4 == 3 && !(20 / 5 == 5)) {
    print("[7%4 == 3 && !(20/5 == 5)] e TRUE.");
  } else {
    print("[7%4 == 3 && !(20/5 == 5)] e FALSE.");
  }
  if ((23.1 >= 64 / 3) || ('b' == 'a')) {
    print("[(23.1 >= 64/3) || ('b' == 'a')] e TRUE.");
  } else {
    print("[(23.1 >= 64/3) || ('b' == 'a')] e FALSE.");
  }
  print("\n------------------------------\n");
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<skipSpaces>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L26
L18:
  addq   $0x1,-0x8(%rbp)
L26:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L18
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L18
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
const char *skipSpaces(const char *p) {
  while (*p == ' ' || *p == '\t')
    p++;
  return p;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skipSpaces>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L27
  cmp    $0x9,%dl
  jne    L19
L27:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L27
  cmp    $0x9,%dl
  je     L27
L19:
  ret
```

assistant: ```c
const char *skipSpaces(const char *p) {
  while (*p == ' ' || *p == '\t')
    p++;
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<skipSpaces>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L10
  nop
L17:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L17
L10:
  cmp    $0x9,%dl
  je     L17
  ret
```

assistant: ```c
const char *skipSpaces(const char *p) {
  while (*p == ' ' || *p == '\t')
    p++;
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<skipSpaces>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L6
  nop
L1:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L1
L6:
  cmp    $0x9,%dl
  je     L1
  ret
```

assistant: ```c
const char *skipSpaces(const char *p) {
  while (*p == ' ' || *p == '\t')
    p++;
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<pathname_concat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9,-0x40(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x40(%rbp),%rax
  add    %rax,%rdx
  mov    0x18(%rbp),%rax
  add    %rdx,%rax
  add    $0x1,%rax
  cmp    %rax,-0x20(%rbp)
  jae    L12
  mov    $0xffffffff,%eax
  jmp    L17
L12:
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x30(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rcx
  mov    -0x8(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x40(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x2e,(%rax)
  mov    0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    0x10(%rbp),%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    0x18(%rbp),%rax
  add    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
  mov    $0x0,%eax
L17:
  leave
  ret
```

assistant: ```c
int pathname_concat(char *pathname_out, size_t pathname_out_len, const char *pathname_lib, const size_t pathname_lib_len, const char *pathname_module, const size_t pathname_module_len, const char *pathname_ext, const size_t pathname_ext_len) {
  char *pathname_out_p = pathname_out;
  if (pathname_lib_len + pathname_module_len + pathname_ext_len + 1 > pathname_out_len) {
    return -1;
  }
  pathname_out_p = pathname_out;
  memcpy(pathname_out_p, pathname_lib, pathname_lib_len);
  pathname_out_p += pathname_lib_len;
  memcpy(pathname_out_p, pathname_module, pathname_module_len);
  pathname_out_p += pathname_module_len;
  *pathname_out_p++ = '.';
  memcpy(pathname_out_p, pathname_ext, pathname_ext_len);
  pathname_out_p += pathname_ext_len;
  *pathname_out_p++ = '\0';
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<pathname_concat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    0x38(%rsp),%r13
  lea    0x1(%r9,%r13,1),%rax
  add    %rcx,%rax
  cmp    %rsi,%rax
  ja     L15
  mov    %rdx,%rsi
  mov    %rcx,%r12
  mov    %r8,%r14
  mov    %r9,%rbp
  mov    %rcx,%rdx
  call   <memcpy@plt>
  add    %r12,%rbx
  mov    %rbp,%rdx
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <memcpy@plt>
  add    %rbp,%rbx
  lea    0x1(%rbx),%rdi
  movb   $0x2e,(%rbx)
  mov    %r13,%rdx
  mov    0x30(%rsp),%rsi
  call   <memcpy@plt>
  movb   $0x0,0x1(%rbx,%r13,1)
  mov    $0x0,%eax
L6:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L15:
  mov    $0xffffffff,%eax
  jmp    L6
```

assistant: ```c
int pathname_concat(char *pathname_out, size_t pathname_out_len, const char *pathname_lib, const size_t pathname_lib_len, const char *pathname_module, const size_t pathname_module_len, const char *pathname_ext, const size_t pathname_ext_len) {
  char *pathname_out_p = pathname_out;
  if (pathname_lib_len + pathname_module_len + pathname_ext_len + 1 > pathname_out_len) {
    return -1;
  }
  pathname_out_p = pathname_out;
  memcpy(pathname_out_p, pathname_lib, pathname_lib_len);
  pathname_out_p += pathname_lib_len;
  memcpy(pathname_out_p, pathname_module, pathname_module_len);
  pathname_out_p += pathname_module_len;
  *pathname_out_p++ = '.';
  memcpy(pathname_out_p, pathname_ext, pathname_ext_len);
  pathname_out_p += pathname_ext_len;
  *pathname_out_p++ = '\0';
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<pathname_concat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r13
  lea    0x1(%r9,%r13,1),%rax
  add    %rcx,%rax
  cmp    %rsi,%rax
  ja     L15
  mov    %rcx,%r12
  mov    %rdi,%rbx
  mov    %r9,%rbp
  mov    %r8,%r14
  mov    %rdx,%rsi
  add    %r12,%rbx
  mov    %rcx,%rdx
  call   <memcpy@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rdx
  add    %rbp,%rbx
  mov    %r14,%rsi
  call   <memcpy@plt>
  movb   $0x2e,(%rbx)
  mov    0x30(%rsp),%rsi
  mov    %r13,%rdx
  lea    0x1(%rbx),%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%rbx,%r13,1)
  xor    %eax,%eax
L19:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L15:
  mov    $0xffffffff,%eax
  jmp    L19
```

assistant: ```c
int pathname_concat(char *pathname_out, size_t pathname_out_len, const char *pathname_lib, const size_t pathname_lib_len, const char *pathname_module, const size_t pathname_module_len, const char *pathname_ext, const size_t pathname_ext_len) {
  char *pathname_out_p = pathname_out;
  if (pathname_lib_len + pathname_module_len + pathname_ext_len + 1 > pathname_out_len) {
    return -1;
  }
  pathname_out_p = pathname_out;
  memcpy(pathname_out_p, pathname_lib, pathname_lib_len);
  pathname_out_p += pathname_lib_len;
  memcpy(pathname_out_p, pathname_module, pathname_module_len);
  pathname_out_p += pathname_module_len;
  *pathname_out_p++ = '.';
  memcpy(pathname_out_p, pathname_ext, pathname_ext_len);
  pathname_out_p += pathname_ext_len;
  *pathname_out_p++ = '\0';
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<pathname_concat>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    0x38(%rsp),%r13
  lea    0x1(%r9,%r13,1),%rax
  add    %rcx,%rax
  cmp    %rsi,%rax
  ja     L7
  mov    %rcx,%r12
  mov    %rdi,%rbx
  mov    %r9,%rbp
  mov    %r8,%r14
  mov    %rdx,%rsi
  add    %r12,%rbx
  mov    %rcx,%rdx
  call   <memcpy@plt>
  mov    %rbx,%rdi
  mov    %rbp,%rdx
  add    %rbp,%rbx
  mov    %r14,%rsi
  call   <memcpy@plt>
  movb   $0x2e,(%rbx)
  mov    0x30(%rsp),%rsi
  mov    %r13,%rdx
  lea    0x1(%rbx),%rdi
  call   <memcpy@plt>
  movb   $0x0,0x1(%rbx,%r13,1)
  xor    %eax,%eax
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L7:
  mov    $0xffffffff,%eax
  jmp    L11
```

assistant: ```c
int pathname_concat(char *pathname_out, size_t pathname_out_len, const char *pathname_lib, const size_t pathname_lib_len, const char *pathname_module, const size_t pathname_module_len, const char *pathname_ext, const size_t pathname_ext_len) {
  char *pathname_out_p = pathname_out;
  if (pathname_lib_len + pathname_module_len + pathname_ext_len + 1 > pathname_out_len) {
    return -1;
  }
  pathname_out_p = pathname_out;
  memcpy(pathname_out_p, pathname_lib, pathname_lib_len);
  pathname_out_p += pathname_lib_len;
  memcpy(pathname_out_p, pathname_module, pathname_module_len);
  pathname_out_p += pathname_module_len;
  *pathname_out_p++ = '.';
  memcpy(pathname_out_p, pathname_ext, pathname_ext_len);
  pathname_out_p += pathname_ext_len;
  *pathname_out_p++ = '\0';
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strlen0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L8:
  addl   $0x1,-0x4(%rbp)
L9:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strlen0(char *str) {
  int count = 0;
  while (str[count] != '\0')
    ++count;
  return count;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<strlen0>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L15
  mov    $0x1,%eax
L8:
  mov    %eax,%edx
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L8
L12:
  mov    %edx,%eax
  ret
L15:
  mov    $0x0,%edx
  jmp    L12
```

assistant: ```c
int strlen0(char *str) {
  int count = 0;
  while (str[count] != '\0')
    ++count;
  return count;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strlen0>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L14
  mov    $0x1,%eax
  xchg   %ax,%ax
L13:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L14:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen0(char *str) {
  int count = 0;
  while (str[count] != '\0')
    ++count;
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<strlen0>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L9
  mov    $0x1,%eax
  xchg   %ax,%ax
L13:
  mov    %eax,%r8d
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rdi,%rax,1)
  jne    L13
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L9:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int strlen0(char *str) {
  int count = 0;
  while (str[count] != '\0')
    ++count;
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<nm_pos_geomean>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %esi,-0x28(%rbp)
  movsd  D0(%rip),%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x28(%rbp),%eax
  sub    -0x24(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L18
L16:
  pxor   %xmm0,%xmm0
  cvtsi2sdl -0x14(%rbp),%xmm0
  movsd  -0x8(%rbp),%xmm1
  mulsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x1,-0x14(%rbp)
L18:
  mov    -0x14(%rbp),%eax
  cmp    -0x28(%rbp),%eax
  jle    L16
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x10(%rbp),%xmm1
  movsd  D0(%rip),%xmm0
  divsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%edi
  movq   %rax,%xmm0
  call   <pow@plt>
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: f64

tool: D0: 1

assistant: ```c
int nm_pos_geomean(int l, int u) {
  int i;
  int n;
  double tmp;
  int pos;
  tmp = 1;
  n = u - l + 1;
  for (i = l; i <= u; i++)
    tmp *= i;
  pos = floor(pow(tmp, 1. / n));
  return pos;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<nm_pos_geomean>:
  endbr64
  sub    $0x8,%rsp
  mov    %esi,%eax
  sub    %edi,%eax
  add    $0x1,%eax
  cmp    %edi,%esi
  jl     L23
  add    $0x1,%esi
  movsd  D23(%rip),%xmm0
L2:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  mulsd  %xmm1,%xmm0
  add    $0x1,%edi
  cmp    %esi,%edi
  jne    L2
L20:
  pxor   %xmm2,%xmm2
  cvtsi2sd %eax,%xmm2
  movsd  D23(%rip),%xmm1
  divsd  %xmm2,%xmm1
  cvttsd2si %xmm1,%edi
  call   <pow@plt>
  mov    %eax,%edi
  call   <floor@plt>
  add    $0x8,%rsp
  ret
L23:
  movsd  D23(%rip),%xmm0
  jmp    L20
```

tool_calls: name: parse_data
arguments: data_label: D23
type: f64

tool: D23: 1

assistant: ```c
int nm_pos_geomean(int l, int u) {
  int i;
  int n;
  double tmp;
  int pos;
  tmp = 1;
  n = u - l + 1;
  for (i = l; i <= u; i++)
    tmp *= i;
  pos = floor(pow(tmp, 1. / n));
  return pos;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<nm_pos_geomean>:
  endbr64
  mov    %esi,%eax
  sub    $0x8,%rsp
  sub    %edi,%eax
  add    $0x1,%eax
  cmp    %edi,%esi
  jl     L21
  movsd  D18(%rip),%xmm2
  add    $0x1,%esi
  movapd %xmm2,%xmm0
  nopw   0x0(%rax,%rax,1)
L15:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  add    $0x1,%edi
  mulsd  %xmm1,%xmm0
  cmp    %esi,%edi
  jne    L15
L5:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%edi
  call   <pow@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <floor@plt>
  nopl   0x0(%rax,%rax,1)
L21:
  movsd  D18(%rip),%xmm2
  movapd %xmm2,%xmm0
  jmp    L5
```

tool_calls: name: disassemble_data
arguments: data_tag: D18
type_infered: f64

tool: D18: 1

assistant: ```c
int nm_pos_geomean(int l, int u) {
  int i;
  int n;
  double tmp;
  int pos;
  tmp = 1;
  n = u - l + 1;
  for (i = l; i <= u; i++)
    tmp *= i;
  pos = floor(pow(tmp, 1. / n));
  return pos;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<nm_pos_geomean>:
  endbr64
  mov    %esi,%eax
  sub    $0x8,%rsp
  sub    %edi,%eax
  add    $0x1,%eax
  cmp    %edi,%esi
  jl     L8
  movsd  D0(%rip),%xmm2
  add    $0x1,%esi
  movapd %xmm2,%xmm0
  nopw   0x0(%rax,%rax,1)
L12:
  pxor   %xmm1,%xmm1
  cvtsi2sd %edi,%xmm1
  add    $0x1,%edi
  mulsd  %xmm1,%xmm0
  cmp    %edi,%esi
  jne    L12
L4:
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm2
  cvttsd2si %xmm2,%edi
  call   <pow@plt>
  add    $0x8,%rsp
  mov    %eax,%edi
  jmp    1060 <floor@plt>
  nopl   0x0(%rax,%rax,1)
L8:
  movsd  D0(%rip),%xmm2
  movapd %xmm2,%xmm0
  jmp    L4
```

tool_calls: name: read_data
arguments: data_label: D0
data_type: f64

tool: D0: 1

assistant: ```c
int nm_pos_geomean(int l, int u) {
  int i;
  int n;
  double tmp;
  int pos;
  tmp = 1;
  n = u - l + 1;
  for (i = l; i <= u; i++)
    tmp *= i;
  pos = floor(pow(tmp, 1. / n));
  return pos;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  nop
  pop    %rbp
  ret
```

assistant: ```c
int swap(int *data, int r, int s) {
  int temp = *(data + r);
  *(data + r) = *(data + s);
  *(data + s) = temp;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
int swap(int *data, int r, int s) {
  int temp = *(data + r);
  *(data + r) = *(data + s);
  *(data + s) = temp;
}
```
user: Translate the below assembly code into C programming language:

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
int swap(int *data, int r, int s) {
  int temp = *(data + r);
  *(data + r) = *(data + s);
  *(data + s) = temp;
}
```
user: What is the c source code of the assembly code below?

```asm
<swap>:
  endbr64
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
  ret
```

assistant: ```c
int swap(int *data, int r, int s) {
  int temp = *(data + r);
  *(data + r) = *(data + s);
  *(data + s) = temp;
}
```