ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<print_number>:
  endbr64
  test   %rdi,%rdi
  je     L2
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  lea    (%rsi,%rdi,1),%rbp
  push   %rbx
  mov    %rsi,%rbx
  nopl   0x0(%rax,%rax,1)
L14:
  movzbl (%rbx),%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L14
  pop    %rbx
  mov    $0xa,%edi
  pop    %rbp
  pop    %r12
  jmp    1060 <putchar@plt>
  nopl   0x0(%rax)
L2:
  mov    $0xa,%edi
  jmp    1060 <putchar@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D5
data_type: string

tool: D5: %02X 

assistant: ```c
void print_number(size_t len, unsigned char *data) {
  for (size_t i = 0; i < len; i++) {
    printf("%02X ", data[i]);
  }
  printf("\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x1,-0xc(%rbp)
  jmp    L15
L0:
  mov    -0x8(%rbp),%rax
  lea    D7(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strtok@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <data_to_address@plt>
  addl   $0x1,-0xc(%rbp)
L15:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <read_address@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L0
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D7
type_infered: string

tool: D7: 


assistant: ```c
void read_all(void) {
  char *line;
  int ctr;
  ctr = 1;
  while ((line = read_address(ctr)) != NULL) {
    strtok(line, "\n");
    ;
    data_to_address(ctr);
    ctr++;
  }
  free(line);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<read_all>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebx
  lea    D4(%rip),%rbp
  jmp    L19
L0:
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %ebx,%edi
  call   <data_to_address@plt>
  add    $0x1,%ebx
L19:
  mov    %ebx,%edi
  call   <read_address@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L0
  call   <free@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D4
type: string

tool: D4: 


assistant: ```c
void read_all(void) {
  char *line;
  int ctr;
  ctr = 1;
  while ((line = read_address(ctr)) != NULL) {
    strtok(line, "\n");
    ;
    data_to_address(ctr);
    ctr++;
  }
  free(line);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<read_all>:
  endbr64
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L13
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <data_to_address@plt>
L13:
  mov    %ebx,%edi
  call   <read_address@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <free@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D4
datatype: string

tool: D4: 


assistant: ```c
void read_all(void) {
  char *line;
  int ctr;
  ctr = 1;
  while ((line = read_address(ctr)) != NULL) {
    strtok(line, "\n");
    ;
    data_to_address(ctr);
    ctr++;
  }
  free(line);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<read_all>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x8,%rsp
  jmp    L0
  nopl   0x0(%rax,%rax,1)
L11:
  mov    %rbp,%rsi
  call   <strtok@plt>
  mov    %ebx,%edi
  add    $0x1,%ebx
  call   <data_to_address@plt>
L0:
  mov    %ebx,%edi
  call   <read_address@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  jmp    1080 <free@plt>
```

tool_calls: name: read_data
arguments: label: D1
type_guessed: string

tool: D1: 


assistant: ```c
void read_all(void) {
  char *line;
  int ctr;
  ctr = 1;
  while ((line = read_address(ctr)) != NULL) {
    strtok(line, "\n");
    ;
    data_to_address(ctr);
    ctr++;
  }
  free(line);
}
```
user: What is the c source code of the assembly code below?

```asm
<strlwr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L28
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L3
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    -0x8(%rbp),%rdx
  mov    %al,(%rdx)
L3:
  addq   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L27
  mov    -0x18(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p;
  for (p = s; *p; p++) {
    if (isalpha(*p))
      *p = toupper(*p);
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlwr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  movzbl (%rdi),%edi
  test   %dil,%dil
  je     L39
  mov    %rbp,%rbx
  jmp    L36
L10:
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L39
L36:
  movsbl %dil,%edi
  call   <isalpha@plt>
  test   %rax,%rax
  je     L10
  movsbl (%rbx),%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  jmp    L10
L39:
  mov    %rbp,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p;
  for (p = s; *p; p++) {
    if (isalpha(*p))
      *p = toupper(*p);
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L36
  mov    %r12,%rbx
  jmp    L17
  nopl   0x0(%rax,%rax,1)
L43:
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  je     L36
L17:
  call   <isalpha@plt>
  test   %rax,%rax
  je     L43
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L17
L36:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p;
  for (p = s; *p; p++) {
    if (isalpha(*p))
      *p = toupper(*p);
  }
  return s;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<strlwr>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbx
  sub    $0x8,%rsp
  movsbl (%rdi),%edi
  test   %dil,%dil
  je     L37
  mov    %r12,%rbx
  nopl   0x0(%rax)
L26:
  call   <isalpha@plt>
  test   %rax,%rax
  jne    L35
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L26
L37:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L35:
  movsbl (%rbx),%edi
  add    $0x1,%rbx
  call   <toupper@plt>
  mov    %al,-0x1(%rbx)
  movsbl (%rbx),%edi
  test   %dil,%dil
  jne    L26
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %r12
  ret
```

assistant: ```c
char *strlwr(char *s) {
  char *p;
  for (p = s; *p; p++) {
    if (isalpha(*p))
      *p = toupper(*p);
  }
  return s;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x7,%rax
  mov    %rax,%rdx
  movabs $0x1b4334b500,%rax
  and    %rdx,%rax
  mov    %rax,-0x10(%rbp)
  movq   $0x0,-0x18(%rbp)
  jmp    L13
L17:
  mov    -0x10(%rbp),%rax
  cmp    %rax,-0x18(%rbp)
  jae    L25
  mov    -0x10(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    -0x10(%rbp,%rax,8),%rax
  shr    %rax
  and    $0x6,%eax
  or     $0x1,%eax
  mov    %eax,%ecx
  shl    %cl,%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,-0x10(%rbp,%rax,8)
  jmp    L18
L25:
  lea    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  lea    -0x10(%rbp),%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  lea    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    -0x1c(%rbp),%edx
  mov    %edx,(%rax)
L18:
  addq   $0x1,-0x18(%rbp)
L13:
  mov    -0x28(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x18(%rbp)
  jb     L17
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  movabs $0x149154248,%rax
  and    %rax,%rdx
  mov    -0x30(%rbp),%rax
  mov    %rdx,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy11 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy11;
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 690137161UL) << 3UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdi),%rax
  shl    $0x7,%rax
  movabs $0x1b4334b500,%rcx
  and    %rcx,%rax
  mov    %rax,(%rsp)
  mov    0x8(%rdi),%rdi
  test   %rdi,%rdi
  je     L16
  mov    $0x0,%eax
L48:
  mov    (%rsp),%rsi
  cmp    %rax,%rsi
  jbe    L38
  mov    %rsi,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rsi
  mov    %rsi,(%rsp,%rax,8)
L43:
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L48
L16:
  mov    (%rsp),%rax
  shl    $0x3,%rax
  movabs $0x149154248,%rcx
  and    %rcx,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x18,%rsp
  ret
L38:
  mov    (%rsp),%ecx
  mov    0x4(%rsp),%esi
  mov    %esi,(%rsp)
  mov    %ecx,0x4(%rsp)
  jmp    L43
L12:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy11 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy11;
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 690137161UL) << 3UL;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<RandomFunc>:
  endbr64
  movabs $0x1b4334b500,%rdx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  mov    0x8(%rdi),%rdi
  shl    $0x7,%rax
  and    %rdx,%rax
  mov    %rax,(%rsp)
  test   %rdi,%rdi
  je     L15
  xor    %edx,%edx
L6:
  cmp    %rax,%rdx
  jae    L39
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,(%rsp,%rdx,8)
L32:
  add    $0x1,%rdx
  cmp    %rdi,%rdx
  jne    L6
L15:
  movabs $0x149154248,%rdx
  shl    $0x3,%rax
  and    %rdx,%rax
  mov    %rax,(%rsi)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L17
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L39:
  mov    (%rsp),%eax
  mov    0x4(%rsp),%ecx
  mov    %eax,0x4(%rsp)
  mov    %ecx,(%rsp)
  mov    (%rsp),%rax
  jmp    L32
L17:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy11 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy11;
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 690137161UL) << 3UL;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<RandomFunc>:
  endbr64
  sub    $0x18,%rsp
  mov    %rsi,%rdx
  mov    0x8(%rdi),%rsi
  movabs $0x1b4334b500,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdi),%rax
  shl    $0x7,%rax
  and    %rcx,%rax
  movq   %rax,%xmm1
  pshufd $0xe1,%xmm1,%xmm0
  test   %rsi,%rsi
  je     L89
  test   %rax,%rax
  je     L15
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,(%rsp)
  cmp    $0x1,%rsi
  je     L89
L82:
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,0x8(%rsp)
L48:
  cmp    $0x2,%rsi
  jbe    L89
  mov    $0x2,%edi
L17:
  cmp    %rax,%rdi
  jae    L109
  mov    %rax,%rcx
  shr    %rcx
  and    $0x6,%ecx
  or     $0x1,%ecx
  shl    %cl,%rax
  mov    %rax,(%rsp,%rdi,8)
L18:
  add    $0x1,%rdi
  cmp    %rsi,%rdi
  jne    L17
  cs nopw 0x0(%rax,%rax,1)
L89:
  movabs $0x149154248,%rcx
  shl    $0x3,%rax
  and    %rcx,%rax
  mov    %rax,(%rdx)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L40
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax)
L15:
  movq   %xmm0,(%rsp)
  movq   %xmm0,%rax
  cmp    $0x1,%rsi
  je     L89
  cmp    $0x1,%rax
  ja     L82
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rsp)
  movq   %xmm0,%rax
  jmp    L48
  xchg   %ax,%ax
L109:
  movq   (%rsp),%xmm0
  pshufd $0xe1,%xmm0,%xmm0
  movq   %xmm0,(%rsp)
  movq   %xmm0,%rax
  jmp    L18
L40:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void RandomFunc(unsigned long input[1], unsigned long output[1]) {
  unsigned long state[1];
  unsigned long local1;
  unsigned int copy11;
  {
    state[0UL] = (input[0UL] & 914778474UL) << 7UL;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      if (state[0UL] > local1) {
        state[local1] = state[0UL] << (((state[local1] >> 1UL) & 7UL) | 1UL);
      } else {
        copy11 = *((unsigned int *)(&state[0UL]) + 0);
        *((unsigned int *)(&state[0UL]) + 0) = *((unsigned int *)(&state[0UL]) + 1);
        *((unsigned int *)(&state[0UL]) + 1) = copy11;
      }
      local1++;
    }
    output[0UL] = (state[0UL] & 690137161UL) << 3UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <myFunction@plt>
  mov    $0x0,%eax
  call   <anotherFunction@plt>
  mov    $0x0,%eax
  call   <stillmore@plt>
  mov    $0x0,%eax
  call   <andagain@plt>
  mov    $0x0,%eax
  call   <multiplyfive@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int main(void) {
  myFunction();
  anotherFunction();
  stillmore();
  andagain();
  multiplyfive();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <myFunction@plt>
  mov    $0x0,%eax
  call   <anotherFunction@plt>
  mov    $0x0,%eax
  call   <stillmore@plt>
  mov    $0x0,%eax
  call   <andagain@plt>
  mov    $0x0,%eax
  call   <multiplyfive@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  myFunction();
  anotherFunction();
  stillmore();
  andagain();
  multiplyfive();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <myFunction@plt>
  xor    %eax,%eax
  call   <anotherFunction@plt>
  xor    %eax,%eax
  call   <stillmore@plt>
  xor    %eax,%eax
  call   <andagain@plt>
  xor    %eax,%eax
  call   <multiplyfive@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  myFunction();
  anotherFunction();
  stillmore();
  andagain();
  multiplyfive();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <myFunction@plt>
  xor    %eax,%eax
  call   <anotherFunction@plt>
  xor    %eax,%eax
  call   <stillmore@plt>
  xor    %eax,%eax
  call   <andagain@plt>
  xor    %eax,%eax
  call   <multiplyfive@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(void) {
  myFunction();
  anotherFunction();
  stillmore();
  andagain();
  multiplyfive();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<initDlgFunction>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  lea    D26(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <fwrite@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D15
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string
name: extract_symbolic_data
arguments: label: D19
type_guessed: string

tool: D15: 



tool: D26: static HWND create_dlg_%s 
	(
	HINSTANCE hInst, HWND hParent, HWND *hFocus
	)


tool: D19: {


assistant: ```c
void initDlgFunction(FILE *dst, const char *dlgName) {
  fprintf(dst, "\n\n");
  fprintf(dst, "static HWND create_dlg_%s \n\t(\n\tHINSTANCE hInst, HWND hParent, HWND *hFocus\n\t)\n", dlgName);
  fprintf(dst, "{\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<initDlgFunction>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdi,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D5(%rip),%rdi
  call   <fwrite@plt>
  mov    %rbp,%rdx
  lea    D29(%rip),%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <fprintf@plt>
  mov    %rbx,%rcx
  mov    $0x2,%edx
  mov    $0x1,%esi
  lea    D1(%rip),%rdi
  call   <fwrite@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D5
type_infered: string
name: parse_data
arguments: tag: D29
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string

tool: D5: 



tool: D29: static HWND create_dlg_%s 
	(
	HINSTANCE hInst, HWND hParent, HWND *hFocus
	)


tool: D1: {


assistant: ```c
void initDlgFunction(FILE *dst, const char *dlgName) {
  fprintf(dst, "\n\n");
  fprintf(dst, "static HWND create_dlg_%s \n\t(\n\tHINSTANCE hInst, HWND hParent, HWND *hFocus\n\t)\n", dlgName);
  fprintf(dst, "{\n");
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<initDlgFunction>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  mov    %rsi,%r13
  mov    $0x2,%edx
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  lea    D24(%rip),%rdi
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D19(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    $0x2,%edx
  pop    %r12
  mov    $0x1,%esi
  lea    D26(%rip),%rdi
  pop    %r13
  jmp    1070 <fwrite@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D24
type_guessed: string
name: disassemble_data
arguments: data_tag: D19
type_guessed: string
name: disassemble_data
arguments: data_tag: D26
type_guessed: string

tool: D24: 



tool: D19: static HWND create_dlg_%s 
	(
	HINSTANCE hInst, HWND hParent, HWND *hFocus
	)


tool: D26: {


assistant: ```c
void initDlgFunction(FILE *dst, const char *dlgName) {
  fprintf(dst, "\n\n");
  fprintf(dst, "static HWND create_dlg_%s \n\t(\n\tHINSTANCE hInst, HWND hParent, HWND *hFocus\n\t)\n", dlgName);
  fprintf(dst, "{\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<initDlgFunction>:
  endbr64
  push   %r13
  mov    %rdi,%rcx
  mov    %rsi,%r13
  mov    $0x2,%edx
  push   %r12
  mov    $0x1,%esi
  mov    %rdi,%r12
  lea    D21(%rip),%rdi
  sub    $0x8,%rsp
  call   <fwrite@plt>
  mov    %r13,%rdx
  mov    %r12,%rdi
  xor    %eax,%eax
  lea    D0(%rip),%rsi
  call   <fprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rcx
  mov    $0x2,%edx
  pop    %r12
  mov    $0x1,%esi
  lea    D23(%rip),%rdi
  pop    %r13
  jmp    1070 <fwrite@plt>
```

tool_calls: name: retrieve_data
arguments: label: D21
type_guessed: string
name: retrieve_data
arguments: label: D0
type_guessed: string
name: retrieve_data
arguments: label: D23
type_guessed: string

tool: D21: 



tool: D0: static HWND create_dlg_%s 
	(
	HINSTANCE hInst, HWND hParent, HWND *hFocus
	)


tool: D23: {


assistant: ```c
void initDlgFunction(FILE *dst, const char *dlgName) {
  fprintf(dst, "\n\n");
  fprintf(dst, "static HWND create_dlg_%s \n\t(\n\tHINSTANCE hInst, HWND hParent, HWND *hFocus\n\t)\n", dlgName);
  fprintf(dst, "{\n");
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<get_serial_lines>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    D0(%rip),%rax
  mov    (%rax),%ecx
  lea    -0xc(%rbp),%rdx
  mov    -0x14(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ioctl@plt>
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L7
  call   <__stack_chk_fail@plt>
L7:
  leave
  ret
```

assistant: ```c
int get_serial_lines(int fd) {
  int modem_lines;
  ioctl(fd, TIOCMGET, &modem_lines);
  return modem_lines;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<get_serial_lines>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rdx
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_serial_lines(int fd) {
  int modem_lines;
  ioctl(fd, TIOCMGET, &modem_lines);
  return modem_lines;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_serial_lines>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D8(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x18,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_serial_lines(int fd) {
  int modem_lines;
  ioctl(fd, TIOCMGET, &modem_lines);
  return modem_lines;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_serial_lines>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    D5(%rip),%rax
  lea    0x4(%rsp),%rdx
  mov    (%rax),%esi
  call   <ioctl@plt>
  mov    0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int get_serial_lines(int fd) {
  int modem_lines;
  ioctl(fd, TIOCMGET, &modem_lines);
  return modem_lines;
}
```