ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<sum_num_down>:
  endbr64
  mov    %rdi,%r10
  lea    -0x40(%rdi),%r9
  xor    %r11d,%r11d
L7:
  mov    %r10,%rax
  mov    $0x3,%r8d
  movslq %r11d,%rcx
L17:
  mov    0x30(%rax),%esi
  test   %esi,%esi
  je     L66
  movslq %r8d,%rdx
  movl   $0x0,0x30(%rax)
  sub    $0x1,%r8d
  shl    $0x4,%rdx
  add    %rdi,%rdx
  mov    %esi,(%rdx,%rcx,4)
L66:
  sub    $0x10,%rax
  cmp    %r9,%rax
  jne    L17
  mov    $0x3,%edx
  nopw   0x0(%rax,%rax,1)
L6:
  movslq %edx,%rax
  shl    $0x4,%rax
  lea    (%rdi,%rax,1),%r8
  lea    -0x10(%rdi,%rax,1),%rax
  mov    (%r8,%rcx,4),%esi
  cmp    (%rax,%rcx,4),%esi
  jne    L55
  add    %esi,%esi
  sub    $0x1,%edx
  mov    %esi,(%r8,%rcx,4)
  movl   $0x0,(%rax,%rcx,4)
L55:
  sub    $0x1,%edx
  test   %edx,%edx
  jg     L6
  lea    0x30(%r10),%rax
  mov    $0x3,%r8d
L30:
  mov    (%rax),%esi
  test   %esi,%esi
  je     L18
  movslq %r8d,%rdx
  movl   $0x0,(%rax)
  sub    $0x1,%r8d
  shl    $0x4,%rdx
  add    %rdi,%rdx
  mov    %esi,(%rdx,%rcx,4)
L18:
  sub    $0x10,%rax
  cmp    %r10,%rax
  jne    L30
  add    $0x1,%r11d
  lea    0x4(%rax),%r10
  add    $0x4,%r9
  cmp    $0x4,%r11d
  jne    L7
  ret
```

assistant: ```c
void sum_num_down(int num[4][4]) {
  int i;
  int j;
  int p;
  int temp;
  for (j = 0; j < 4; j++) {
    for (p = i = 4 - 1; i >= 0; i--) {
      if (num[i][j] != 0) {
        temp = num[i][j];
        num[i][j] = 0;
        num[p][j] = temp;
        p--;
      }
    }
    for (i = 4 - 1; i > 0; i--) {
      if (num[i][j] == num[i - 1][j]) {
        num[i][j] = num[i][j] * 2;
        num[i - 1][j] = 0;
        i--;
      }
    }
    for (p = i = 4 - 1; i > 0; i--) {
      if (num[i][j] != 0) {
        temp = num[i][j];
        num[i][j] = 0;
        num[p][j] = temp;
        p--;
      }
    }
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<sum_num_down>:
  endbr64
  mov    %rdi,%r9
  xor    %r10d,%r10d
L84:
  cmpl   $0x1,0x30(%r9)
  mov    0x20(%r9),%r8d
  movslq %r10d,%rcx
  sbb    %rsi,%rsi
  and    $0x10,%esi
  mov    %rsi,%rdx
  mov    %rsi,%rax
  add    $0x10,%rdx
  add    $0x20,%rax
  test   %r8d,%r8d
  je     L78
  lea    (%rdi,%rcx,4),%r11
  movl   $0x0,0x20(%r9)
  mov    %r8d,(%r11,%rax,1)
  mov    %rdx,%rax
  mov    %rsi,%rdx
L78:
  mov    0x10(%r9),%esi
  test   %esi,%esi
  je     L8
  lea    (%rdi,%rcx,4),%r8
  movl   $0x0,0x10(%r9)
  mov    %esi,(%r8,%rax,1)
  mov    %rdx,%rax
L8:
  mov    (%r9),%edx
  test   %edx,%edx
  je     L64
  lea    (%rdi,%rcx,4),%rsi
  movl   $0x0,(%r9)
  mov    %edx,(%rsi,%rax,1)
L64:
  mov    $0x3,%edx
  nopw   0x0(%rax,%rax,1)
L28:
  movslq %edx,%rax
  shl    $0x4,%rax
  lea    (%rdi,%rax,1),%r8
  lea    -0x10(%rdi,%rax,1),%rax
  mov    (%r8,%rcx,4),%esi
  cmp    (%rax,%rcx,4),%esi
  je     L43
  sub    $0x1,%edx
  jne    L28
L81:
  cmpl   $0x1,0x30(%r9)
  mov    0x20(%r9),%esi
  sbb    %rdx,%rdx
  and    $0x10,%edx
  add    $0x10,%rdx
  cmpl   $0x1,0x30(%r9)
  sbb    %rax,%rax
  and    $0x10,%eax
  add    $0x20,%rax
  test   %esi,%esi
  je     L88
  lea    (%rdi,%rcx,4),%r8
  movl   $0x0,0x20(%r9)
  mov    %esi,(%r8,%rax,1)
  mov    %rdx,%rax
L88:
  mov    0x10(%r9),%edx
  test   %edx,%edx
  je     L70
  lea    (%rdi,%rcx,4),%rcx
  movl   $0x0,0x10(%r9)
  mov    %edx,(%rcx,%rax,1)
L70:
  add    $0x1,%r10d
  add    $0x4,%r9
  cmp    $0x4,%r10d
  jne    L84
  ret
  nopl   0x0(%rax)
L43:
  add    %esi,%esi
  mov    %esi,(%r8,%rcx,4)
  movl   $0x0,(%rax,%rcx,4)
  cmp    $0x3,%edx
  jne    L81
  mov    $0x1,%edx
  jmp    L28
```

assistant: ```c
void sum_num_down(int num[4][4]) {
  int i;
  int j;
  int p;
  int temp;
  for (j = 0; j < 4; j++) {
    for (p = i = 4 - 1; i >= 0; i--) {
      if (num[i][j] != 0) {
        temp = num[i][j];
        num[i][j] = 0;
        num[p][j] = temp;
        p--;
      }
    }
    for (i = 4 - 1; i > 0; i--) {
      if (num[i][j] == num[i - 1][j]) {
        num[i][j] = num[i][j] * 2;
        num[i - 1][j] = 0;
        i--;
      }
    }
    for (p = i = 4 - 1; i > 0; i--) {
      if (num[i][j] != 0) {
        temp = num[i][j];
        num[i][j] = 0;
        num[p][j] = temp;
        p--;
      }
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xd8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xc8(%rsp)
  xor    %eax,%eax
  lea    0x1c(%rsp),%rsi
  lea    D55(%rip),%rdi
  call   <scanf@plt>
  mov    0x1c(%rsp),%eax
  test   %eax,%eax
  je     L68
  lea    0x20(%rsp),%rbp
  mov    $0x0,%ebx
  lea    D55(%rip),%r12
L59:
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x0(%rbp),%eax
  mov    %eax,0x70(%rsp,%rbx,4)
  lea    0x1(%rbx),%eax
  add    $0x1,%rbx
  add    $0x4,%rbp
  cmp    %ebx,0x1c(%rsp)
  jne    L59
L68:
  movl   $0x0,0x20(%rsp)
  cltq
  movl   $0x0,0x20(%rsp,%rax,4)
  movl   $0x0,0x70(%rsp)
  movl   $0x0,0x70(%rsp,%rax,4)
  movl   $0x3e8,0xc(%rsp)
  lea    D48(%rip),%r13
  lea    D11(%rip),%r15
L57:
  cmpl   $0x0,0x1c(%rsp)
  je     L43
  mov    $0x0,%ebx
  mov    $0x1,%r12d
  lea    0x20(%rsp),%rbp
  mov    $0x0,%r14d
  jmp    L46
L58:
  cmpl   $0x1,0x0(%rbp,%rbx,4)
  je     L81
L136:
  add    $0x1,%rbx
  cmp    %ebx,0x1c(%rsp)
  je     L71
L46:
  cmpl   $0x0,0x0(%rbp,%rbx,4)
  jne    L58
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L58
L81:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14d,%r12d
  jmp    L136
L71:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x70(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  mov    0x1c(%rsp),%edx
  call   <next_generation@plt>
  cmp    $0x1,%r12d
  jne    L138
L3:
  mov    0xc8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0xd8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L138:
  subl   $0x1,0xc(%rsp)
  jne    L57
  jmp    L3
L43:
  lea    D13(%rip),%rdi
  call   <printf@plt>
  lea    0x70(%rsp),%rsi
  lea    0x20(%rsp),%rdi
  mov    0x1c(%rsp),%edx
  call   <next_generation@plt>
  jmp    L3
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D55
data_type: string
name: read_data
arguments: data_tag: D48
data_type: string
name: read_data
arguments: data_tag: D11
data_type: string
name: read_data
arguments: data_tag: D13
data_type: string

tool: D55: %d

tool: D48: .

tool: D11: *

tool: D13: 


assistant: ```c
int main(void) {
  int old_cells[20];
  int new_cells[20];
  int limiter;
  int counter;
  int generation_counter = 0;
  int deadflag = 1;
  scanf("%d", &limiter);
  counter = 0;
  while (counter != limiter) {
    scanf("%d", &old_cells[counter]);
    new_cells[counter] = old_cells[counter];
    counter++;
  }
  old_cells[0] = 0;
  old_cells[counter] = 0;
  new_cells[0] = 0;
  new_cells[counter] = 0;
  while (generation_counter != 1000) {
    counter = 0;
    while (counter != limiter) {
      if (old_cells[counter] == 0) {
        printf(".");
      }
      if (old_cells[counter] == 1) {
        printf("*");
        deadflag = 0;
      }
      counter++;
    }
    printf("\n");
    next_generation(old_cells, new_cells, limiter);
    generation_counter++;
    if (deadflag == 1) {
      return 0;
    }
    deadflag = 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<check_length>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L41
L27:
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isdigit@plt>
  test   %rax,%rax
  je     L29
  addl   $0x1,-0x8(%rbp)
L29:
  addl   $0x1,-0xc(%rbp)
L41:
  mov    -0xc(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L27
  cmpl   $0xd,-0x8(%rbp)
  jne    L13
  mov    $0x1,%eax
  jmp    L19
L13:
  mov    $0x0,%eax
L19:
  leave
  ret
```

assistant: ```c
int check_length(char data[20]) {
  int i;
  int length = strlen(data);
  int num_digits = 0;
  for (i = 0; i < length; i++)
    if (isdigit(data[i])) {
      num_digits++;
    }
  if (num_digits == 13)
    return 1;
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  call   <strlen@plt>
  test   %eax,%eax
  jle    L26
  mov    %rbp,%rbx
  lea    -0x1(%rax),%eax
  lea    0x1(%rbp,%rax,1),%r12
  mov    $0x0,%ebp
L18:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L18
L15:
  cmp    $0xd,%ebp
  sete   %al
  movzbl %al,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    $0x0,%ebp
  jmp    L15
```

assistant: ```c
int check_length(char data[20]) {
  int i;
  int length = strlen(data);
  int num_digits = 0;
  for (i = 0; i < length; i++)
    if (isdigit(data[i])) {
      num_digits++;
    }
  if (num_digits == 13)
    return 1;
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L12
  sub    $0x1,%eax
  xor    %ebp,%ebp
  lea    0x1(%rbx,%rax,1),%r12
  xchg   %ax,%ax
L1:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jne    L1
  xor    %eax,%eax
  cmp    $0xd,%ebp
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
  nopl   (%rax)
L12:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_length(char data[20]) {
  int i;
  int length = strlen(data);
  int num_digits = 0;
  for (i = 0; i < length; i++)
    if (isdigit(data[i])) {
      num_digits++;
    }
  if (num_digits == 13)
    return 1;
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<check_length>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L7
  sub    $0x1,%eax
  xor    %ebp,%ebp
  lea    0x1(%rbx,%rax,1),%r12
  xchg   %ax,%ax
L11:
  movsbl (%rbx),%edi
  call   <isdigit@plt>
  cmp    $0x1,%rax
  sbb    $0xffffffff,%ebp
  add    $0x1,%rbx
  cmp    %r12,%rbx
  jne    L11
  xor    %eax,%eax
  cmp    $0xd,%ebp
  pop    %rbx
  pop    %rbp
  sete   %al
  pop    %r12
  ret
  nopl   (%rax)
L7:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_length(char data[20]) {
  int i;
  int length = strlen(data);
  int num_digits = 0;
  for (i = 0; i < length; i++)
    if (isdigit(data[i])) {
      num_digits++;
    }
  if (num_digits == 13)
    return 1;
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<getByte>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x18(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  movzbl %al,%eax
  pop    %rbp
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int shift = n << 3;
  return (x >> shift) & 0xff;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<getByte>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int shift = n << 3;
  return (x >> shift) & 0xff;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<getByte>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int shift = n << 3;
  return (x >> shift) & 0xff;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<getByte>:
  endbr64
  lea    0x0(,%rsi,8),%ecx
  sar    %cl,%edi
  movzbl %dil,%eax
  ret
```

assistant: ```c
int getByte(int x, int n) {
  int shift = n << 3;
  return (x >> shift) & 0xff;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    $0x0,%eax
  call   <ich_liebe_dich@plt>
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  leave
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  ich_liebe_dich();
  return EXIT_SUCCESS;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <ich_liebe_dich@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  ich_liebe_dich();
  return EXIT_SUCCESS;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ich_liebe_dich@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  ich_liebe_dich();
  return EXIT_SUCCESS;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <ich_liebe_dich@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int main(int argc, char *argv[]) {
  ich_liebe_dich();
  return EXIT_SUCCESS;
}
```
user: Translate the below assembly code into C programming language:

```asm
<translate_bool_to_ascii>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  test   %eax,%eax
  je     L6
  cmp    $0x1,%eax
  jne    L10
  mov    $0x31,%eax
  jmp    L17
L6:
  mov    $0x30,%eax
  jmp    L17
L10:
  mov    $0x3f,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
char translate_bool_to_ascii(char value) {
  switch (value) {
  case 0x01:
    return '1';
  case 0x00:
    return '0';
  }
  return '?';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<translate_bool_to_ascii>:
  endbr64
  mov    $0x30,%eax
  test   %dil,%dil
  je     L9
  cmp    $0x1,%dil
  mov    $0x3f,%eax
  mov    $0x31,%edx
  cmove  %edx,%eax
L9:
  ret
```

assistant: ```c
char translate_bool_to_ascii(char value) {
  switch (value) {
  case 0x01:
    return '1';
  case 0x00:
    return '0';
  }
  return '?';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<translate_bool_to_ascii>:
  endbr64
  mov    $0x30,%eax
  test   %dil,%dil
  je     L5
  cmp    $0x1,%dil
  mov    $0x3f,%eax
  mov    $0x31,%edx
  cmove  %edx,%eax
L5:
  ret
```

assistant: ```c
char translate_bool_to_ascii(char value) {
  switch (value) {
  case 0x01:
    return '1';
  case 0x00:
    return '0';
  }
  return '?';
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<translate_bool_to_ascii>:
  endbr64
  mov    $0x30,%eax
  test   %dil,%dil
  je     L7
  cmp    $0x1,%dil
  mov    $0x3f,%eax
  mov    $0x31,%edx
  cmove  %edx,%eax
L7:
  ret
```

assistant: ```c
char translate_bool_to_ascii(char value) {
  switch (value) {
  case 0x01:
    return '1';
  case 0x00:
    return '0';
  }
  return '?';
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ft_strstr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <ft_strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L32
  mov    -0x18(%rbp),%rax
  jmp    L79
L31:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L60
  addq   $0x1,-0x10(%rbp)
  jmp    L29
L60:
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L62
  jmp    L38
L25:
  subq   $0x1,-0x18(%rbp)
L38:
  mov    -0x8(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  test   %rax,%rax
  jne    L25
  addq   $0x1,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  jmp    L79
L62:
  addq   $0x1,-0x18(%rbp)
L32:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L22
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L31
L22:
  mov    $0x0,%eax
L79:
  leave
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  const char *cp_s2;
  unsigned long ct_s2;
  cp_s2 = s2;
  ct_s2 = ft_strlen(s2);
  if (!*s2)
    return ((char *)s1);
  while (*s1 && *s2) {
    if (*s1 == *cp_s2)
      cp_s2++;
    else
      cp_s2 = s2;
    if (!*cp_s2) {
      while (ct_s2--)
        s1--;
      return ((char *)++s1);
    }
    s1++;
  }
  return (NULL);
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_strstr>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rsi,%rdi
  call   <ft_strlen@plt>
  mov    %rbx,%rdx
  cmpb   $0x0,0x0(%rbp)
  je     L45
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L109
  mov    %rbp,%rcx
  jmp    L12
L78:
  lea    0x1(%rcx),%rdx
  cmpb   $0x0,0x1(%rcx)
  je     L99
  mov    %rdx,%rcx
L106:
  add    $0x1,%rbx
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L102
L12:
  cmp    %dl,(%rcx)
  je     L78
  mov    %rbp,%rcx
  jmp    L106
L99:
  lea    -0x1(%rax),%rdx
  test   %rax,%rax
  je     L53
L31:
  sub    $0x1,%rdx
  cmp    $0xffffffffffffffff,%rdx
  jne    L31
  sub    %rax,%rbx
L53:
  lea    0x1(%rbx),%rdx
L45:
  mov    %rdx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L102:
  mov    $0x0,%edx
  jmp    L45
L109:
  mov    $0x0,%edx
  jmp    L45
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  const char *cp_s2;
  unsigned long ct_s2;
  cp_s2 = s2;
  ct_s2 = ft_strlen(s2);
  if (!*s2)
    return ((char *)s1);
  while (*s1 && *s2) {
    if (*s1 == *cp_s2)
      cp_s2++;
    else
      cp_s2 = s2;
    if (!*cp_s2) {
      while (ct_s2--)
        s1--;
      return ((char *)++s1);
    }
    s1++;
  }
  return (NULL);
}
```
user: What is the c source code of the assembly code below:

```asm
<ft_strstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  movzbl 0x0(%rbp),%edi
  mov    %rbx,%r8
  test   %dil,%dil
  je     L60
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L47
  mov    %rbp,%rcx
  jmp    L41
L20:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  mov    %rbp,%rcx
  test   %dl,%dl
  je     L47
L52:
  movzbl (%rcx),%edi
L41:
  cmp    %dl,%dil
  jne    L20
  cmpb   $0x0,0x1(%rcx)
  lea    0x1(%rcx),%rdx
  je     L43
  add    $0x1,%rbx
  mov    %rdx,%rcx
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L52
L47:
  xor    %r8d,%r8d
L60:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L43:
  mov    %rbx,%rdx
  add    $0x1,%rbx
  sub    %rax,%rdx
  test   %rax,%rax
  lea    0x1(%rdx),%r8
  cmove  %rbx,%r8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  const char *cp_s2;
  unsigned long ct_s2;
  cp_s2 = s2;
  ct_s2 = ft_strlen(s2);
  if (!*s2)
    return ((char *)s1);
  while (*s1 && *s2) {
    if (*s1 == *cp_s2)
      cp_s2++;
    else
      cp_s2 = s2;
    if (!*cp_s2) {
      while (ct_s2--)
        s1--;
      return ((char *)++s1);
    }
    s1++;
  }
  return (NULL);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<ft_strstr>:
  endbr64
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rdi
  sub    $0x8,%rsp
  call   <ft_strlen@plt>
  movzbl 0x0(%rbp),%esi
  mov    %rbx,%r8
  test   %sil,%sil
  je     L34
  movzbl (%rbx),%edx
  test   %dl,%dl
  je     L21
  mov    %esi,%ecx
  mov    %rbp,%rdi
  jmp    L42
  nopw   0x0(%rax,%rax,1)
L14:
  movzbl 0x1(%rbx),%edx
  add    $0x1,%rbx
  mov    %esi,%ecx
  mov    %rbp,%rdi
  test   %dl,%dl
  je     L21
L42:
  cmp    %dl,%cl
  jne    L14
  movzbl 0x1(%rdi),%ecx
  lea    0x1(%rdi),%rdx
  test   %cl,%cl
  je     L9
  add    $0x1,%rbx
  mov    %rdx,%rdi
  movzbl (%rbx),%edx
  test   %dl,%dl
  jne    L42
L21:
  xor    %r8d,%r8d
L34:
  add    $0x8,%rsp
  mov    %r8,%rax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L9:
  mov    %rbx,%rdx
  add    $0x1,%rbx
  sub    %rax,%rdx
  test   %rax,%rax
  lea    0x1(%rdx),%r8
  cmove  %rbx,%r8
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  mov    %r8,%rax
  ret
```

assistant: ```c
char *ft_strstr(const char *s1, const char *s2) {
  const char *cp_s2;
  unsigned long ct_s2;
  cp_s2 = s2;
  ct_s2 = ft_strlen(s2);
  if (!*s2)
    return ((char *)s1);
  while (*s1 && *s2) {
    if (*s1 == *cp_s2)
      cp_s2++;
    else
      cp_s2 = s2;
    if (!*cp_s2) {
      while (ct_s2--)
        s1--;
      return ((char *)++s1);
    }
    s1++;
  }
  return (NULL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<NextSlashOrNull>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L20
L14:
  addq   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  je     L1
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
L1:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *NextSlashOrNull(char *p) {
  while (*p != '/' && *p != '\0') {
    p++;
  }
  return p;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<NextSlashOrNull>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x2f,%dl
  je     L32
  test   %dl,%dl
  je     L32
L22:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x2f,%dl
  je     L32
  test   %dl,%dl
  jne    L22
L32:
  ret
```

assistant: ```c
char *NextSlashOrNull(char *p) {
  while (*p != '/' && *p != '\0') {
    p++;
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<NextSlashOrNull>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x2f,%dl
  jne    L7
  jmp    L38
  nopl   0x0(%rax)
L16:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x2f,%dl
  je     L38
L7:
  test   %dl,%dl
  jne    L16
L38:
  ret
```

assistant: ```c
char *NextSlashOrNull(char *p) {
  while (*p != '/' && *p != '\0') {
    p++;
  }
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<NextSlashOrNull>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x2f,%dl
  jne    L36
  jmp    L38
  nopl   0x0(%rax)
L6:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x2f,%dl
  je     L38
L36:
  test   %dl,%dl
  jne    L6
L38:
  ret
```

assistant: ```c
char *NextSlashOrNull(char *p) {
  while (*p != '/' && *p != '\0') {
    p++;
  }
  return p;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x0,%eax
  call   <start_watchdog@plt>
  lea    -0x10(%rbp),%rax
  mov    $0xffffffff,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sem_init@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x0,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <sem_init@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x55,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_wait@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_post@plt>
  mov    %eax,-0xc(%rbp)
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <sem_destroy@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
int main(void) {
  int r __attribute__((unused));
  sem_t s1;
  start_watchdog();
  r = sem_init(&s1, 0, ~0);
  r = sem_init(&s1, 0, 0);
  memset(&s1, 0x55, sizeof(s1));
  r = sem_wait(&s1);
  r = sem_post(&s1);
  sem_destroy(&s1);
  return 0;
}
```