ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0xa,%ebx
L135:
  mov    $0x0,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L135
  mov    $0xa,%ebx
L61:
  mov    $0x0,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L61
  mov    $0xa,%ebx
L124:
  mov    $0x0,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L124
  mov    $0xa,%ebx
L113:
  mov    $0x0,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L113
  mov    $0xa,%ebx
L69:
  mov    $0x0,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L69
  mov    $0xa,%ebx
L45:
  mov    $0x0,%eax
  call   <gang@plt>
  sub    $0x1,%ebx
  jne    L45
  mov    $0xa,%ebx
L117:
  mov    $0x0,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L117
  mov    $0xa,%ebx
L94:
  mov    $0x0,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L94
  mov    $0xa,%ebx
L26:
  mov    $0x0,%eax
  call   <worker@plt>
  sub    $0x1,%ebx
  jne    L26
  mov    $0xa,%ebx
L76:
  mov    $0x0,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L76
  mov    $0xa,%ebx
L102:
  mov    $0x0,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L102
  mov    $0xa,%ebx
L138:
  mov    $0x0,%eax
  call   <vector@plt>
  sub    $0x1,%ebx
  jne    L138
  mov    $0xa,%ebx
L77:
  mov    $0x0,%eax
  call   <seq@plt>
  sub    $0x1,%ebx
  jne    L77
  mov    $0xa,%ebx
L68:
  mov    $0x0,%eax
  call   <seq@plt>
  sub    $0x1,%ebx
  jne    L68
  mov    $0xa,%ebx
L73:
  mov    $0x0,%eax
  call   <seq@plt>
  sub    $0x1,%ebx
  jne    L73
  mov    $0x0,%eax
  pop    %rbx
  ret
```

assistant: ```c
int main() {
  int red = 0;
#pragma acc parallel copy(red)
  {
#pragma acc loop reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += gang();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += worker();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += vector();
#pragma acc loop gang reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += seq();
#pragma acc loop worker reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += seq();
#pragma acc loop vector reduction(+ : red)
    for (int i = 0; i < 10; i++)
      red += seq();
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<test_placement>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %ecx,%eax
  mov    %edi,%ecx
  mov    %cl,-0x4(%rbp)
  mov    %esi,%ecx
  mov    %cl,-0x8(%rbp)
  mov    %dl,-0xc(%rbp)
  mov    %al,-0x10(%rbp)
  lea    -0x8(%rbp),%rcx
  lea    -0x4(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L29
  lea    -0x10(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L46
L29:
  mov    $0x1,%eax
  jmp    L20
L46:
  movzbl -0x4(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x4(%rbp)
  movzbl -0x8(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x8(%rbp)
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0xc(%rbp)
  movzbl -0x10(%rbp),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <toupper@plt>
  mov    %al,-0x10(%rbp)
  lea    -0x8(%rbp),%rcx
  lea    -0x4(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L34
  lea    -0x10(%rbp),%rcx
  lea    -0xc(%rbp),%rax
  mov    $0x1,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L34
  mov    $0x0,%eax
  jmp    L20
L34:
  mov    $0x1,%eax
L20:
  leave
  ret
```

assistant: ```c
int test_placement(char up, char down, char left, char right) {
  if (!strncmp(&up, &down, 1) || !strncmp(&left, &right, 1))
    return 1;
  up = toupper(up);
  down = toupper(down);
  left = toupper(left);
  right = toupper(right);
  if (!strncmp(&up, &down, 1) && !strncmp(&left, &right, 1))
    return 0;
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<test_placement>:
  endbr64
  sub    $0x18,%rsp
  mov    %dil,0xc(%rsp)
  mov    %sil,0x8(%rsp)
  mov    %dl,0x4(%rsp)
  mov    %cl,(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    $0x1,%edx
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L37
L26:
  add    $0x18,%rsp
  ret
L37:
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  je     L26
  movsbl 0xc(%rsp),%edi
  call   <toupper@plt>
  mov    %al,0xc(%rsp)
  movsbl 0x8(%rsp),%edi
  call   <toupper@plt>
  mov    %al,0x8(%rsp)
  movsbl 0x4(%rsp),%edi
  call   <toupper@plt>
  mov    %al,0x4(%rsp)
  movsbl (%rsp),%edi
  call   <toupper@plt>
  mov    %al,(%rsp)
  lea    0x8(%rsp),%rsi
  lea    0xc(%rsp),%rdi
  mov    $0x1,%edx
  call   <strncmp@plt>
  mov    %eax,%edx
  mov    $0x1,%eax
  test   %edx,%edx
  jne    L26
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdi
  mov    $0x1,%edx
  call   <strncmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L26
```

assistant: ```c
int test_placement(char up, char down, char left, char right) {
  if (!strncmp(&up, &down, 1) || !strncmp(&left, &right, 1))
    return 1;
  up = toupper(up);
  down = toupper(down);
  left = toupper(left);
  right = toupper(right);
  if (!strncmp(&up, &down, 1) && !strncmp(&left, &right, 1))
    return 0;
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<test_placement>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%rbp
  mov    %dil,0xc(%rsp)
  mov    %sil,0x8(%rsp)
  mov    %rbp,%rdi
  mov    %r12,%rsi
  mov    %dl,0x4(%rsp)
  mov    $0x1,%edx
  mov    %cl,(%rsp)
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L8
L4:
  mov    $0x1,%eax
L31:
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L8:
  mov    %rsp,%r14
  lea    0x4(%rsp),%r13
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L4
  movsbl 0xc(%rsp),%edi
  call   <toupper@plt>
  movsbl 0x8(%rsp),%edi
  mov    %al,0xc(%rsp)
  call   <toupper@plt>
  movsbl 0x4(%rsp),%edi
  mov    %al,0x8(%rsp)
  call   <toupper@plt>
  movsbl (%rsp),%edi
  mov    %al,0x4(%rsp)
  call   <toupper@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %al,(%rsp)
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L4
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L31
```

assistant: ```c
int test_placement(char up, char down, char left, char right) {
  if (!strncmp(&up, &down, 1) || !strncmp(&left, &right, 1))
    return 1;
  up = toupper(up);
  down = toupper(down);
  left = toupper(left);
  right = toupper(right);
  if (!strncmp(&up, &down, 1) && !strncmp(&left, &right, 1))
    return 0;
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<test_placement>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  sub    $0x18,%rsp
  lea    0x8(%rsp),%r12
  lea    0xc(%rsp),%rbp
  mov    %dil,0xc(%rsp)
  mov    %sil,0x8(%rsp)
  mov    %rbp,%rdi
  mov    %r12,%rsi
  mov    %dl,0x4(%rsp)
  mov    $0x1,%edx
  mov    %cl,(%rsp)
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L17
L29:
  mov    $0x1,%eax
L34:
  add    $0x18,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nop
L17:
  mov    %rsp,%r14
  lea    0x4(%rsp),%r13
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  je     L29
  movsbl 0xc(%rsp),%edi
  call   <toupper@plt>
  movsbl 0x8(%rsp),%edi
  mov    %al,0xc(%rsp)
  call   <toupper@plt>
  movsbl 0x4(%rsp),%edi
  mov    %al,0x8(%rsp)
  call   <toupper@plt>
  movsbl (%rsp),%edi
  mov    %al,0x4(%rsp)
  call   <toupper@plt>
  mov    $0x1,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %al,(%rsp)
  call   <strncmp@plt>
  test   %eax,%eax
  jne    L29
  mov    $0x1,%edx
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <strncmp@plt>
  test   %eax,%eax
  setne  %al
  movzbl %al,%eax
  jmp    L34
```

assistant: ```c
int test_placement(char up, char down, char left, char right) {
  if (!strncmp(&up, &down, 1) || !strncmp(&left, &right, 1))
    return 1;
  up = toupper(up);
  down = toupper(down);
  left = toupper(left);
  right = toupper(right);
  if (!strncmp(&up, &down, 1) && !strncmp(&left, &right, 1))
    return 0;
  return 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<err_out>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <perror@plt>
  mov    $0x1,%eax
  leave
  ret
```

assistant: ```c
int err_out(const char *msg) {
  perror(msg);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<err_out>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err_out(const char *msg) {
  perror(msg);
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<err_out>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err_out(const char *msg) {
  perror(msg);
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<err_out>:
  endbr64
  sub    $0x8,%rsp
  call   <perror@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int err_out(const char *msg) {
  perror(msg);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fs_exec>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  je     L4
  movq   $0xe000,-0x8(%rbp)
L4:
  jmp    *-0x8(%rbp)
```

assistant: ```c
int fs_exec(int ino) {
  void *src = 0;
  if (ino)
    src = (void *)0xe000;
  goto *src;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fs_exec>:
  endbr64
  neg    %edi
  sbb    %rax,%rax
  and    $0xe000,%eax
  jmp    *%rax
```

assistant: ```c
int fs_exec(int ino) {
  void *src = 0;
  if (ino)
    src = (void *)0xe000;
  goto *src;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<fs_exec>:
  endbr64
  neg    %edi
  sbb    %rax,%rax
  and    $0xe000,%eax
  jmp    *%rax
```

assistant: ```c
int fs_exec(int ino) {
  void *src = 0;
  if (ino)
    src = (void *)0xe000;
  goto *src;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fs_exec>:
  endbr64
  neg    %edi
  sbb    %rax,%rax
  and    $0xe000,%eax
  jmp    *%rax
```

assistant: ```c
int fs_exec(int ino) {
  void *src = 0;
  if (ino)
    src = (void *)0xe000;
  goto *src;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strncmp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L32
L38:
  mov    -0x10(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x10(%rbp)
  movzbl (%rax),%eax
  mov    %al,-0x15(%rbp)
  movzbl -0x15(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%edx
  mov    %ecx,%eax
  sub    %edx,%eax
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L24
  cmpb   $0x0,-0x15(%rbp)
  je     L24
L32:
  mov    -0x38(%rbp),%rax
  lea    -0x1(%rax),%rdx
  mov    %rdx,-0x38(%rbp)
  test   %rax,%rax
  jne    L38
L24:
  mov    -0x14(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  const unsigned char *c1 = (const unsigned char *)s1;
  const unsigned char *c2 = (const unsigned char *)s2;
  unsigned char ch;
  int d = 0;
  while (n--) {
    d = (int)(ch = *c1++) - (int)*c2++;
    if (d || !ch)
      break;
  }
  return d;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<strncmp>:
  endbr64
  mov    $0x0,%ecx
L29:
  cmp    %rcx,%rdx
  je     L19
  movzbl (%rdi,%rcx,1),%r9d
  movzbl %r9b,%eax
  movzbl (%rsi,%rcx,1),%r8d
  add    $0x1,%rcx
  sub    %r8d,%eax
  jne    L24
  test   %r9b,%r9b
  jne    L29
  jmp    L24
L19:
  mov    $0x0,%eax
L24:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  const unsigned char *c1 = (const unsigned char *)s1;
  const unsigned char *c2 = (const unsigned char *)s2;
  unsigned char ch;
  int d = 0;
  while (n--) {
    d = (int)(ch = *c1++) - (int)*c2++;
    if (d || !ch)
      break;
  }
  return d;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<strncmp>:
  endbr64
  xor    %ecx,%ecx
  jmp    L19
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  add    $0x1,%rcx
  mov    %eax,%r9d
  sub    %r8d,%eax
  jne    L15
  test   %r9b,%r9b
  je     L15
L19:
  cmp    %rcx,%rdx
  jne    L29
  xor    %eax,%eax
L15:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  const unsigned char *c1 = (const unsigned char *)s1;
  const unsigned char *c2 = (const unsigned char *)s2;
  unsigned char ch;
  int d = 0;
  while (n--) {
    d = (int)(ch = *c1++) - (int)*c2++;
    if (d || !ch)
      break;
  }
  return d;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strncmp>:
  endbr64
  xor    %ecx,%ecx
  jmp    L23
  nopl   0x0(%rax,%rax,1)
L22:
  movzbl (%rdi,%rcx,1),%eax
  movzbl (%rsi,%rcx,1),%r8d
  add    $0x1,%rcx
  mov    %eax,%r9d
  sub    %r8d,%eax
  jne    L30
  test   %r9b,%r9b
  je     L30
L23:
  cmp    %rcx,%rdx
  jne    L22
  xor    %eax,%eax
L30:
  ret
```

assistant: ```c
int strncmp(const char *s1, const char *s2, size_t n) {
  const unsigned char *c1 = (const unsigned char *)s1;
  const unsigned char *c2 = (const unsigned char *)s2;
  unsigned char ch;
  int d = 0;
  while (n--) {
    d = (int)(ch = *c1++) - (int)*c2++;
    if (d || !ch)
      break;
  }
  return d;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x7,-0x30(%rbp)
  movl   $0x9,-0x2c(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x3,-0x24(%rbp)
  movl   $0x6,-0x20(%rbp)
  movl   $0x1,-0x1c(%rbp)
  movl   $0x12,-0x18(%rbp)
  movl   $0x2,-0x14(%rbp)
  movl   $0xa,-0x10(%rbp)
  movl   $0x5,-0xc(%rbp)
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <printVet@plt>
  lea    -0x30(%rbp),%rax
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <quickSort@plt>
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <printVet@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D1
type_infered: string
name: read_data
arguments: data_tag: D6
type_infered: string

tool: D1: Vetor desordenado:


tool: D6: Vetor ordenado:


assistant: ```c
int main() {
  int vet[10] = {7, 9, 4, 3, 6, 1, 18, 2, 10, 5};
  int i;
  printf("Vetor desordenado:\n");
  printVet(vet);
  quickSort(vet, 0, 9);
  printf("Vetor ordenado:\n");
  printVet(vet);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x7,(%rsp)
  movl   $0x9,0x4(%rsp)
  movl   $0x4,0x8(%rsp)
  movl   $0x3,0xc(%rsp)
  movl   $0x6,0x10(%rsp)
  movl   $0x1,0x14(%rsp)
  movl   $0x12,0x18(%rsp)
  movl   $0x2,0x1c(%rsp)
  movl   $0xa,0x20(%rsp)
  movl   $0x5,0x24(%rsp)
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  call   <printVet@plt>
  mov    $0x9,%edx
  mov    $0x0,%esi
  mov    %rbx,%rdi
  call   <quickSort@plt>
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <printVet@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x30,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D10
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D3
type_guessed: string

tool: D10: Vetor desordenado:


tool: D3: Vetor ordenado:


assistant: ```c
int main() {
  int vet[10] = {7, 9, 4, 3, 6, 1, 18, 2, 10, 5};
  int i;
  printf("Vetor desordenado:\n");
  printVet(vet);
  quickSort(vet, 0, 9);
  printf("Vetor ordenado:\n");
  printVet(vet);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x900000007,%rax
  mov    %rsp,%rbp
  mov    %rax,(%rsp)
  movabs $0x300000004,%rax
  mov    %rax,0x8(%rsp)
  movabs $0x100000006,%rax
  mov    %rax,0x10(%rsp)
  movabs $0x200000012,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x50000000a,%rax
  mov    %rax,0x20(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printVet@plt>
  xor    %esi,%esi
  mov    $0x9,%edx
  mov    %rbp,%rdi
  call   <quickSort@plt>
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printVet@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D7
type_guessed: string
name: disassemble_data
arguments: label: D8
type_guessed: string

tool: D7: Vetor desordenado:


tool: D8: Vetor ordenado:


assistant: ```c
int main() {
  int vet[10] = {7, 9, 4, 3, 6, 1, 18, 2, 10, 5};
  int i;
  printf("Vetor desordenado:\n");
  printVet(vet);
  quickSort(vet, 0, 9);
  printf("Vetor ordenado:\n");
  printVet(vet);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D10(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D28(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  mov    D1(%rip),%rax
  mov    %rsp,%rbp
  movaps %xmm0,(%rsp)
  movdqa D45(%rip),%xmm0
  mov    %rax,0x20(%rsp)
  movaps %xmm0,0x10(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printVet@plt>
  xor    %esi,%esi
  mov    $0x9,%edx
  mov    %rbp,%rdi
  call   <quickSort@plt>
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printVet@plt>
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D10
datatype: string
name: unpack_data
arguments: label: D28
datatype: byte[16]
name: unpack_data
arguments: label: D1
datatype: byte[8]
name: unpack_data
arguments: label: D45
datatype: byte[16]
name: unpack_data
arguments: label: D16
datatype: string

tool: D10: Vetor desordenado:


tool: {"D28": [0x07,0x00,0x00,0x00,0x09,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D1": [0x0a,0x00,0x00,0x00,0x05,0x00,0x00,0x00]}

tool: {"D45": [0x06,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x12,0x00,0x00,0x00,0x02,0x00,0x00,0x00]}

tool: D16: Vetor ordenado:


assistant: ```c
int main() {
  int vet[10] = {7, 9, 4, 3, 6, 1, 18, 2, 10, 5};
  int i;
  printf("Vetor desordenado:\n");
  printVet(vet);
  quickSort(vet, 0, 9);
  printf("Vetor ordenado:\n");
  printVet(vet);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x756e696c,-0xd(%rbp)
  movb   $0x78,-0x9(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jg     L39
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L39:
  cmpl   $0x2,-0x24(%rbp)
  jle    L99
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L99:
  mov    -0x30(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%rax
  lea    -0xd(%rbp),%rcx
  mov    $0x5,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  mov    %eax,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jle    L54
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L54:
  cmpl   $0x0,-0x14(%rbp)
  jns    L26
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L35
L26:
  cmpl   $0x0,-0x14(%rbp)
  jne    L35
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
L35:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L47
  call   <__stack_chk_fail@plt>
L47:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D6
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D40
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D16
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_label: D17
type_guessed: string

tool: D6: MOAR!


tool: D40: LESS!


tool: D16: TOO SPICEY!


tool: D18: TOO SOUR!


tool: D17: Just right!


assistant: ```c
void main(int argc, char *argv[]) {
  char answer[5] = "linux";
  if (argc < 2) {
    printf("MOAR!\n");
    return;
  }
  if (argc > 2) {
    printf("LESS!\n");
    return;
  }
  int comp = (memcmp(argv[1], answer, sizeof(answer)));
  if (comp > 0) {
    printf("TOO SPICEY!\n");
    return;
  }
  if (comp < 0) {
    printf("TOO SOUR!\n");
    return;
  }
  if (comp == 0) {
    printf("Just right!\n");
    return;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movl   $0x756e696c,0x3(%rsp)
  movb   $0x78,0x7(%rsp)
  cmp    $0x1,%edi
  jle    L72
  cmp    $0x2,%edi
  jg     L13
  lea    0x3(%rsp),%rax
  mov    0x8(%rsi),%rdi
  mov    $0x5,%edx
  mov    %rax,%rsi
  call   <memcmp@plt>
  test   %eax,%eax
  jg     L3
  js     L38
  lea    D40(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L72:
  lea    D33(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L13:
  lea    D42(%rip),%rdi
  call   <printf@plt>
L26:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  ret
L3:
  lea    D21(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L38:
  lea    D7(%rip),%rdi
  call   <printf@plt>
  jmp    L26
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D40
datatype: string
name: unpack_data
arguments: data_label: D33
datatype: string
name: unpack_data
arguments: data_label: D42
datatype: string
name: unpack_data
arguments: data_label: D21
datatype: string
name: unpack_data
arguments: data_label: D7
datatype: string

tool: D40: Just right!


tool: D33: MOAR!


tool: D42: LESS!


tool: D21: TOO SPICEY!


tool: D7: TOO SOUR!


assistant: ```c
void main(int argc, char *argv[]) {
  char answer[5] = "linux";
  if (argc < 2) {
    printf("MOAR!\n");
    return;
  }
  if (argc > 2) {
    printf("LESS!\n");
    return;
  }
  int comp = (memcmp(argv[1], answer, sizeof(answer)));
  if (comp > 0) {
    printf("TOO SPICEY!\n");
    return;
  }
  if (comp < 0) {
    printf("TOO SOUR!\n");
    return;
  }
  if (comp == 0) {
    printf("Just right!\n");
    return;
  }
}
```