ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xe0(%rbp),%rax
  mov    %rax,%rsi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0xed(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0xec(%rbp),%rax
  mov    %rax,%rsi
  lea    D58(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D37(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    -0x70(%rbp),%rsi
  lea    -0xe0(%rbp),%rax
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    %rax,%rdi
  call   <check_substr@plt>
  mov    %eax,-0xe8(%rbp)
  mov    -0xec(%rbp),%edx
  movzbl -0xed(%rbp),%eax
  movsbl %al,%esi
  lea    -0xe0(%rbp),%rax
  mov    %edx,%ecx
  mov    $0x64,%edx
  mov    %rax,%rdi
  call   <c_less_n@plt>
  mov    %eax,-0xe4(%rbp)
  cmpl   $0x1,-0xe8(%rbp)
  jne    L12
  cmpl   $0x0,-0xe4(%rbp)
  je     L36
L12:
  cmpl   $0x0,-0xe8(%rbp)
  jne    L10
  cmpl   $0x1,-0xe4(%rbp)
  jne    L10
L36:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L10:
  lea    D49(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L47:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L54
  call   <__stack_chk_fail@plt>
L54:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: label: D20
datatype: string
name: retrieve_data
arguments: label: D4
datatype: string
name: retrieve_data
arguments: label: D58
datatype: string
name: retrieve_data
arguments: label: D37
datatype: string
name: retrieve_data
arguments: label: D14
datatype: string
name: retrieve_data
arguments: label: D49
datatype: string

tool: D20: %s 

tool: D4: %c

tool: D58: %d

tool: D37: %s

tool: D14: YES

tool: D49: NO

assistant: ```c
int main() {
  char s1[100], s2[100], ch;
  int n, i, j;
  scanf("%s ", s1);
  scanf("%c", &ch);
  scanf("%d", &n);
  scanf("%s", s2);
  i = check_substr(s1, s2, 100, 100);
  j = c_less_n(s1, ch, 100, n);
  if ((i == 1 && j == 0) || (i == 0 && j == 1))
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xf8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    %rbp,%rsi
  lea    D56(%rip),%rdi
  call   <scanf@plt>
  lea    0xb(%rsp),%rsi
  lea    D40(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D48(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  lea    0x80(%rsp),%rbx
  mov    %rbx,%rsi
  lea    D46(%rip),%rdi
  mov    $0x0,%eax
  call   <scanf@plt>
  mov    $0x64,%ecx
  mov    $0x64,%edx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <check_substr@plt>
  mov    %eax,%ebx
  movsbl 0xb(%rsp),%esi
  mov    0xc(%rsp),%ecx
  mov    $0x64,%edx
  mov    %rbp,%rdi
  call   <c_less_n@plt>
  cmp    $0x1,%ebx
  jne    L22
  test   %eax,%eax
  je     L46
L22:
  test   %ebx,%ebx
  jne    L43
  cmp    $0x1,%eax
  jne    L43
L46:
  lea    D5(%rip),%rdi
  call   <printf@plt>
L52:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0xf8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L43:
  lea    D4(%rip),%rdi
  call   <printf@plt>
  jmp    L52
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D56
data_type: string
name: parse_data
arguments: data_label: D40
data_type: string
name: parse_data
arguments: data_label: D48
data_type: string
name: parse_data
arguments: data_label: D46
data_type: string
name: parse_data
arguments: data_label: D5
data_type: string
name: parse_data
arguments: data_label: D4
data_type: string

tool: D56: %s 

tool: D40: %c

tool: D48: %d

tool: D46: %s

tool: D5: YES

tool: D4: NO

assistant: ```c
int main() {
  char s1[100], s2[100], ch;
  int n, i, j;
  scanf("%s ", s1);
  scanf("%c", &ch);
  scanf("%d", &n);
  scanf("%s", s2);
  i = check_substr(s1, s2, 100, 100);
  j = c_less_n(s1, ch, 100, n);
  if ((i == 1 && j == 0) || (i == 0 && j == 1))
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %r12
  lea    D16(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x80(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  lea    0xb(%rsp),%rsi
  lea    D32(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D44(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D29(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0x64,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x64,%edx
  call   <check_substr@plt>
  movsbl 0xb(%rsp),%esi
  mov    0xc(%rsp),%ecx
  mov    %rbp,%rdi
  mov    %eax,%ebx
  mov    $0x64,%edx
  call   <c_less_n@plt>
  cmp    $0x1,%ebx
  jne    L37
  test   %eax,%eax
  je     L4
L37:
  test   %ebx,%ebx
  jne    L5
  sub    $0x1,%eax
  jne    L5
L4:
  lea    D36(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  add    $0xf0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L5:
  lea    D45(%rip),%rdi
  call   <printf@plt>
  jmp    L42
L34:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_label: D16
data_type: string
name: read_data
arguments: data_label: D32
data_type: string
name: read_data
arguments: data_label: D44
data_type: string
name: read_data
arguments: data_label: D29
data_type: string
name: read_data
arguments: data_label: D36
data_type: string
name: read_data
arguments: data_label: D45
data_type: string

tool: D16: %s 

tool: D32: %c

tool: D44: %d

tool: D29: %s

tool: D36: YES

tool: D45: NO

assistant: ```c
int main() {
  char s1[100], s2[100], ch;
  int n, i, j;
  scanf("%s ", s1);
  scanf("%c", &ch);
  scanf("%d", &n);
  scanf("%s", s2);
  i = check_substr(s1, s2, 100, 100);
  j = c_less_n(s1, ch, 100, n);
  if ((i == 1 && j == 0) || (i == 0 && j == 1))
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D30(%rip),%rdi
  push   %rbp
  push   %rbx
  sub    $0xf0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xe8(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  lea    0x80(%rsp),%r12
  mov    %rbp,%rsi
  call   <scanf@plt>
  lea    0xb(%rsp),%rsi
  lea    D57(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    0xc(%rsp),%rsi
  lea    D0(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r12,%rsi
  lea    D8(%rip),%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    $0x64,%ecx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    $0x64,%edx
  call   <check_substr@plt>
  movsbl 0xb(%rsp),%esi
  mov    0xc(%rsp),%ecx
  mov    %rbp,%rdi
  mov    %eax,%ebx
  mov    $0x64,%edx
  call   <c_less_n@plt>
  cmp    $0x1,%ebx
  jne    L7
  test   %eax,%eax
  je     L6
L7:
  test   %ebx,%ebx
  jne    L42
  sub    $0x1,%eax
  jne    L42
L6:
  lea    D9(%rip),%rdi
  call   <printf@plt>
L39:
  mov    0xe8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0xf0,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L42:
  lea    D34(%rip),%rdi
  call   <printf@plt>
  jmp    L39
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D30
type_infered: string
name: parse_data
arguments: label: D57
type_infered: string
name: parse_data
arguments: label: D0
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D9
type_infered: string
name: parse_data
arguments: label: D34
type_infered: string

tool: D30: %s 

tool: D57: %c

tool: D0: %d

tool: D8: %s

tool: D9: YES

tool: D34: NO

assistant: ```c
int main() {
  char s1[100], s2[100], ch;
  int n, i, j;
  scanf("%s ", s1);
  scanf("%c", &ch);
  scanf("%d", &n);
  scanf("%s", s2);
  i = check_substr(s1, s2, 100, 100);
  j = c_less_n(s1, ch, 100, n);
  if ((i == 1 && j == 0) || (i == 0 && j == 1))
    printf("YES");
  else
    printf("NO");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_cmd_string>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L0:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%rax
  mov    -0x20(%rbp),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L13
  mov    $0x0,%eax
  jmp    L33
L13:
  addl   $0x1,-0x4(%rbp)
L32:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L0
  mov    $0xffffffff,%eax
L33:
  leave
  ret
```

assistant: ```c
int check_cmd_string(char **args, const char *str2, int count) {
  int i = 0;
  while (i < count) {
    if ((strncmp(args[i], str2, strlen(args[i]))) == 0) {
      return 0;
    }
    i++;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<check_cmd_string>:
  endbr64
  test   %edx,%edx
  jle    L5
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  lea    -0x1(%rdx),%eax
  lea    0x8(%rdi,%rax,8),%r12
L33:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L17
  add    $0x8,%rbx
  cmp    %r12,%rbx
  jne    L33
  mov    $0xffffffff,%eax
  jmp    L15
L5:
  mov    $0xffffffff,%eax
  ret
L17:
  mov    $0x0,%eax
L15:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int check_cmd_string(char **args, const char *str2, int count) {
  int i = 0;
  while (i < count) {
    if ((strncmp(args[i], str2, strlen(args[i]))) == 0) {
      return 0;
    }
    i++;
  }
  return -1;
}
```
user: What is the c source code of the assembly code below?

```asm
<check_cmd_string>:
  endbr64
  test   %edx,%edx
  jle    L34
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L8
  nopl   0x0(%rax)
L3:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L31
L8:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L3
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L31:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
L34:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int check_cmd_string(char **args, const char *str2, int count) {
  int i = 0;
  while (i < count) {
    if ((strncmp(args[i], str2, strlen(args[i]))) == 0) {
      return 0;
    }
    i++;
  }
  return -1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<check_cmd_string>:
  endbr64
  test   %edx,%edx
  jle    L8
  lea    -0x1(%rdx),%eax
  push   %r12
  lea    0x8(%rdi,%rax,8),%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  mov    %rdi,%rbx
  jmp    L26
  nopl   0x0(%rax)
L7:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L25
L26:
  mov    (%rbx),%rdi
  call   <strlen@plt>
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  mov    %eax,%edx
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L7
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
  nopw   0x0(%rax,%rax,1)
L25:
  pop    %rbx
  mov    $0xffffffff,%eax
  pop    %rbp
  pop    %r12
  ret
L8:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int check_cmd_string(char **args, const char *str2, int count) {
  int i = 0;
  while (i < count) {
    if ((strncmp(args[i], str2, strlen(args[i]))) == 0) {
      return 0;
    }
    i++;
  }
  return -1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<disasm_mem_operand>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    $0x9,%edi
  call   <xmalloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%ecx
  lea    D2(%rip),%rdx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D2: [0x%X]

assistant: ```c
const char *disasm_mem_operand(unsigned int operand) {
  char *ret;
  ret = xmalloc(9);
  snprintf(ret, 9, "[0x%X]", operand);
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<disasm_mem_operand>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x9,%edi
  call   <xmalloc@plt>
  mov    %rax,%rbx
  mov    %ebp,%ecx
  lea    D3(%rip),%rdx
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <snprintf@plt>
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type: string

tool: D3: [0x%X]

assistant: ```c
const char *disasm_mem_operand(unsigned int operand) {
  char *ret;
  ret = xmalloc(9);
  snprintf(ret, 9, "[0x%X]", operand);
  return ret;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<disasm_mem_operand>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x9,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <xmalloc@plt>
  mov    %r13d,%ecx
  mov    $0x9,%esi
  lea    D4(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: label: D4
type: string

tool: D4: [0x%X]

assistant: ```c
const char *disasm_mem_operand(unsigned int operand) {
  char *ret;
  ret = xmalloc(9);
  snprintf(ret, 9, "[0x%X]", operand);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<disasm_mem_operand>:
  endbr64
  push   %r13
  mov    %edi,%r13d
  mov    $0x9,%edi
  push   %r12
  sub    $0x8,%rsp
  call   <xmalloc@plt>
  mov    %r13d,%ecx
  mov    $0x9,%esi
  lea    D6(%rip),%rdx
  mov    %rax,%rdi
  mov    %rax,%r12
  call   <snprintf@plt>
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type: string

tool: D6: [0x%X]

assistant: ```c
const char *disasm_mem_operand(unsigned int operand) {
  char *ret;
  ret = xmalloc(9);
  snprintf(ret, 9, "[0x%X]", operand);
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <my_add@plt>
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D1
type: string

tool: D1: 5 + 7: %i


assistant: ```c
int main(void) {
  printf("5 + 7: %i\n", my_add(5, 7));
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <my_add@plt>
  mov    %eax,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
type_infered: string

tool: D6: 5 + 7: %i


assistant: ```c
int main(void) {
  printf("5 + 7: %i\n", my_add(5, 7));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <my_add@plt>
  lea    D4(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: label: D4
type_infered: string

tool: D4: 5 + 7: %i


assistant: ```c
int main(void) {
  printf("5 + 7: %i\n", my_add(5, 7));
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x7,%esi
  mov    $0x5,%edi
  call   <my_add@plt>
  lea    D3(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
type_infered: string

tool: D3: 5 + 7: %i


assistant: ```c
int main(void) {
  printf("5 + 7: %i\n", my_add(5, 7));
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_matrix>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %rdx,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L34
L25:
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,%esi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L12:
  mov    -0x4(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L7
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  addl   $0x1,-0x8(%rbp)
L34:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
  nop
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D16
type_infered: string
name: disassemble_data
arguments: data_tag: D8
type_infered: string

tool: D16: %5d 

tool: 

assistant: ```c
void print_matrix(int n, int p, int **m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++)
      printf("%5d ", m[i][j]);
    puts("");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<print_matrix>:
  endbr64
  test   %edi,%edi
  jle    L43
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %esi,%r14d
  mov    %rdx,%rbp
  lea    -0x1(%rdi),%eax
  lea    0x8(%rdx,%rax,8),%r15
  lea    -0x1(%rsi),%eax
  lea    0x4(,%rax,4),%r13
  lea    D10(%rip),%r12
  jmp    L22
L42:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    %r13,%rbx
  jne    L42
L2:
  lea    D16(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rbp
  cmp    %r15,%rbp
  je     L19
L22:
  mov    $0x0,%ebx
  test   %r14d,%r14d
  jg     L42
  jmp    L2
L19:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L43:
  ret
```

tool_calls: name: parse_data
arguments: data_label: D10
type_infered: string
name: parse_data
arguments: data_label: D16
type_infered: string

tool: D10: %5d 

tool: 

assistant: ```c
void print_matrix(int n, int p, int **m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++)
      printf("%5d ", m[i][j]);
    puts("");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<print_matrix>:
  endbr64
  test   %edi,%edi
  jle    L33
  push   %r15
  lea    -0x1(%rdi),%eax
  mov    %rdx,%r15
  push   %r14
  lea    0x8(%rdx,%rax,8),%rax
  lea    D13(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  lea    D18(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x4(,%rax,4),%r12
  cs nopw 0x0(%rax,%rax,1)
L36:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L14
  nopw   0x0(%rax,%rax,1)
L29:
  mov    (%r15),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L29
L14:
  mov    %r14,%rdi
  add    $0x8,%r15
  call   <puts@plt>
  cmp    0x8(%rsp),%r15
  jne    L36
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L33:
  ret
```

tool_calls: name: unpack_data
arguments: label: D13
datatype: string
name: unpack_data
arguments: label: D18
datatype: string

tool: 

tool: D18: %5d 

assistant: ```c
void print_matrix(int n, int p, int **m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++)
      printf("%5d ", m[i][j]);
    puts("");
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_matrix>:
  endbr64
  test   %edi,%edi
  jle    L38
  push   %r15
  lea    -0x1(%rdi),%eax
  mov    %rdx,%r15
  push   %r14
  lea    0x8(%rdx,%rax,8),%rax
  lea    D11(%rip),%r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,0x8(%rsp)
  lea    -0x1(%rsi),%eax
  lea    0x4(,%rax,4),%r12
  cs nopw 0x0(%rax,%rax,1)
L13:
  xor    %ebx,%ebx
  test   %r13d,%r13d
  jle    L0
  nopw   0x0(%rax,%rax,1)
L21:
  mov    (%r15),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    %rbx,%r12
  jne    L21
L0:
  mov    %r14,%rdi
  add    $0x8,%r15
  call   <puts@plt>
  cmp    0x8(%rsp),%r15
  jne    L13
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L38:
  ret
```

tool_calls: name: retrieve_data
arguments: label: D11
type_guessed: string
name: retrieve_data
arguments: label: D7
type_guessed: string

tool: 

tool: D7: %5d 

assistant: ```c
void print_matrix(int n, int p, int **m) {
  int i, j;
  for (i = 0; i < n; i++) {
    for (j = 0; j < p; j++)
      printf("%5d ", m[i][j]);
    puts("");
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<fast_sqrt>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x40000000,-0x8(%rbp)
  jmp    L27
L19:
  sarl   $0x2,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jg     L19
  jmp    L18
L2:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L40
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x14(%rbp)
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    %eax,-0xc(%rbp)
L40:
  sarl   -0xc(%rbp)
  sarl   $0x2,-0x8(%rbp)
L18:
  cmpl   $0x0,-0x8(%rbp)
  jne    L2
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int fast_sqrt(int x) {
  int res = 0;
  int one = 1 << 30;
  int resone;
  while (one > x)
    one >>= 2;
  while (one != 0) {
    resone = res + one;
    if (x >= resone) {
      x -= resone;
      res += one << 1;
    }
    res >>= 1;
    one >>= 2;
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<fast_sqrt>:
  endbr64
  cmp    $0x3fffffff,%edi
  jg     L4
  mov    $0x40000000,%eax
L13:
  sar    $0x2,%eax
  cmp    %eax,%edi
  jl     L13
  test   %eax,%eax
  je     L37
L67:
  mov    $0x0,%edx
  jmp    L33
L4:
  mov    $0x40000000,%eax
  jmp    L67
L62:
  sar    %edx
  sar    $0x2,%eax
  je     L17
L33:
  lea    (%rdx,%rax,1),%ecx
  cmp    %edi,%ecx
  jg     L62
  sub    %ecx,%edi
  lea    (%rdx,%rax,2),%edx
  jmp    L62
L37:
  mov    %eax,%edx
L17:
  mov    %edx,%eax
  ret
```

assistant: ```c
int fast_sqrt(int x) {
  int res = 0;
  int one = 1 << 30;
  int resone;
  while (one > x)
    one >>= 2;
  while (one != 0) {
    resone = res + one;
    if (x >= resone) {
      x -= resone;
      res += one << 1;
    }
    res >>= 1;
    one >>= 2;
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<fast_sqrt>:
  endbr64
  mov    $0x40000000,%eax
  cmp    $0x3fffffff,%edi
  jg     L49
  nopl   0x0(%rax)
L4:
  sar    $0x2,%eax
  cmp    %eax,%edi
  jl     L4
  test   %eax,%eax
  je     L40
L49:
  xor    %r8d,%r8d
  cs nopw 0x0(%rax,%rax,1)
L10:
  lea    (%r8,%rax,1),%edx
  cmp    %edi,%edx
  jg     L24
  sub    %edx,%edi
  lea    (%r8,%rax,2),%r8d
L24:
  sar    %r8d
  sar    $0x2,%eax
  jne    L10
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L40:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int fast_sqrt(int x) {
  int res = 0;
  int one = 1 << 30;
  int resone;
  while (one > x)
    one >>= 2;
  while (one != 0) {
    resone = res + one;
    if (x >= resone) {
      x -= resone;
      res += one << 1;
    }
    res >>= 1;
    one >>= 2;
  }
  return res;
}
```