ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D4(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rdx
  call   <scanf@plt>
  mov    (%rsp),%esi
  mov    0x4(%rsp),%r10d
  cmp    %r10d,%esi
  jg     L73
  cmp    $0x2,%esi
  jle    L145
  xor    %r9d,%r9d
L20:
  xor    %edi,%edi
  mov    $0x1,%r8d
  nopl   (%rax)
L108:
  mov    $0x2,%ecx
  nopl   (%rax)
L5:
  mov    %esi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  cmove  %r8d,%edi
  add    $0x1,%ecx
  cmp    %ecx,%esi
  jg     L5
  cmp    $0x1,%edi
  adc    $0x0,%r9d
  add    $0x1,%esi
  cmp    %esi,%r10d
  jge    L108
L2:
  mov    %r9d,%esi
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L157
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L145:
  mov    $0x2,%edx
  mov    $0x1,%ecx
  cmp    %edx,%r10d
  cmovle %r10d,%edx
  mov    %edx,%eax
  sub    %esi,%eax
  cmp    %edx,%esi
  lea    0x1(%rax),%edi
  cmovg  %ecx,%edi
  jg     L101
  cmp    $0x3,%eax
  jbe    L101
  movdqa D2(%rip),%xmm2
  movd   %esi,%xmm6
  mov    %edi,%ecx
  xor    %eax,%eax
  pshufd $0x0,%xmm6,%xmm1
  movdqa D15(%rip),%xmm5
  movdqa D14(%rip),%xmm4
  shr    $0x2,%ecx
  paddd  %xmm2,%xmm1
L15:
  movdqa %xmm2,%xmm0
  movdqa %xmm1,%xmm3
  paddd  %xmm5,%xmm2
  add    $0x1,%eax
  paddd  %xmm5,%xmm1
  paddd  %xmm4,%xmm0
  paddd  %xmm4,%xmm3
  cmp    %ecx,%eax
  jne    L15
  mov    %edi,%eax
  pshufd $0xff,%xmm3,%xmm3
  pshufd $0xff,%xmm0,%xmm0
  and    $0xfffffffc,%eax
  movd   %xmm0,%r9d
  lea    (%rsi,%rax,1),%ecx
  movd   %xmm3,%esi
  cmp    %eax,%edi
  je     L84
L62:
  lea    0x1(%rcx),%esi
  lea    0x1(%rax),%r9d
  cmp    %edx,%esi
  jg     L84
  lea    0x2(%rcx),%esi
  lea    0x2(%rax),%r9d
  cmp    %edx,%esi
  jg     L84
  lea    0x3(%rcx),%esi
  lea    0x3(%rax),%r9d
  cmp    %edx,%esi
  jg     L84
  lea    0x4(%rax),%r9d
  lea    0x4(%rcx),%esi
L84:
  cmp    %esi,%r10d
  jge    L20
  jmp    L2
L73:
  xor    %r9d,%r9d
  jmp    L2
L101:
  mov    %esi,%ecx
  xor    %eax,%eax
  jmp    L62
L157:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
type: string
name: parse_data
arguments: label: D16
type: string
name: parse_data
arguments: label: D2
type: byte[16]
name: parse_data
arguments: label: D15
type: byte[16]
name: parse_data
arguments: label: D14
type: byte[16]

tool: D4: %d%d

tool: D16: %d

tool: {"D2": [0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00]}

tool: {"D15": [0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: {"D14": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int main() {
  int start, end, i, flag = 0, x;
  int count = 0;
  scanf("%d%d", &start, &end);
  for (i = start; i <= end; i++) {
    for (x = 2; x < i; x++) {
      if (i % x == 0) {
        flag = 1;
      }
    }
    if (flag == 0)
      count++;
  }
  printf("%d", count);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<settings_setString>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <stmt_set@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L28
  mov    $0xffffffff,%eax
  jmp    L25
L28:
  mov    D8(%rip),%rax
  mov    (%rax),%ecx
  mov    -0x20(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%r8d
  mov    $0xffffffff,%ecx
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <sqlite3_bind_text@plt>
  mov    D19(%rip),%rdx
  mov    (%rdx),%rdx
  cmp    %rdx,%rax
  je     L14
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlite3_finalize@plt>
  mov    $0xffffffff,%eax
  jmp    L25
L14:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlite3_step@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <sqlite3_finalize@plt>
  mov    $0x0,%eax
L25:
  leave
  ret
```

assistant: ```c
int settings_setString(char *name, char *value) {
  sqlite3_stmt *stmt = stmt_set(name);
  if (stmt == NULL)
    return -1;
  if (sqlite3_bind_text(stmt, 2, value, -1, SQLITE_STATIC) != SQLITE_OK) {
    sqlite3_finalize(stmt);
    return -1;
  }
  sqlite3_step(stmt);
  sqlite3_finalize(stmt);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<settings_setString>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  call   <stmt_set@plt>
  test   %rax,%rax
  je     L12
  mov    %rax,%rbx
  mov    D10(%rip),%rax
  mov    (%rax),%r8d
  mov    $0xffffffff,%ecx
  mov    %rbp,%rdx
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <sqlite3_bind_text@plt>
  mov    D12(%rip),%rdx
  cmp    (%rdx),%rax
  jne    L24
  mov    %rbx,%rdi
  call   <sqlite3_step@plt>
  mov    %rbx,%rdi
  call   <sqlite3_finalize@plt>
  mov    $0x0,%eax
L31:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    %rbx,%rdi
  call   <sqlite3_finalize@plt>
  mov    $0xffffffff,%eax
  jmp    L31
L12:
  mov    $0xffffffff,%eax
  jmp    L31
```

assistant: ```c
int settings_setString(char *name, char *value) {
  sqlite3_stmt *stmt = stmt_set(name);
  if (stmt == NULL)
    return -1;
  if (sqlite3_bind_text(stmt, 2, value, -1, SQLITE_STATIC) != SQLITE_OK) {
    sqlite3_finalize(stmt);
    return -1;
  }
  sqlite3_step(stmt);
  sqlite3_finalize(stmt);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<settings_setString>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <stmt_set@plt>
  test   %rax,%rax
  je     L32
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    $0xffffffff,%ecx
  mov    $0x2,%esi
  mov    D18(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%r8d
  call   <sqlite3_bind_text@plt>
  mov    D14(%rip),%rdx
  mov    %rbp,%rdi
  cmp    (%rdx),%rax
  jne    L37
  call   <sqlite3_step@plt>
  mov    %rbp,%rdi
  call   <sqlite3_finalize@plt>
  xor    %eax,%eax
L2:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L37:
  call   <sqlite3_finalize@plt>
  mov    $0xffffffff,%eax
  jmp    L2
L32:
  mov    $0xffffffff,%eax
  jmp    L2
```

assistant: ```c
int settings_setString(char *name, char *value) {
  sqlite3_stmt *stmt = stmt_set(name);
  if (stmt == NULL)
    return -1;
  if (sqlite3_bind_text(stmt, 2, value, -1, SQLITE_STATIC) != SQLITE_OK) {
    sqlite3_finalize(stmt);
    return -1;
  }
  sqlite3_step(stmt);
  sqlite3_finalize(stmt);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<settings_setString>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <stmt_set@plt>
  test   %rax,%rax
  je     L17
  mov    %rax,%rbp
  mov    %r12,%rdx
  mov    $0xffffffff,%ecx
  mov    $0x2,%esi
  mov    D18(%rip),%rax
  mov    %rbp,%rdi
  mov    (%rax),%r8d
  call   <sqlite3_bind_text@plt>
  mov    D1(%rip),%rdx
  mov    %rbp,%rdi
  cmp    (%rdx),%rax
  jne    L32
  call   <sqlite3_step@plt>
  mov    %rbp,%rdi
  call   <sqlite3_finalize@plt>
  xor    %eax,%eax
L16:
  add    $0x8,%rsp
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <sqlite3_finalize@plt>
  mov    $0xffffffff,%eax
  jmp    L16
L17:
  mov    $0xffffffff,%eax
  jmp    L16
```

assistant: ```c
int settings_setString(char *name, char *value) {
  sqlite3_stmt *stmt = stmt_set(name);
  if (stmt == NULL)
    return -1;
  if (sqlite3_bind_text(stmt, 2, value, -1, SQLITE_STATIC) != SQLITE_OK) {
    sqlite3_finalize(stmt);
    return -1;
  }
  sqlite3_step(stmt);
  sqlite3_finalize(stmt);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  je     L65
  mov    %rdi,%rbp
  mov    %rsi,%r15
  mov    %rdx,%r14
  test   %rdi,%rdi
  je     L65
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  mov    %eax,0xc(%rsp)
  test   %eax,%eax
  je     L87
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L64
  test   %r14,%r14
  lea    D3(%rip),%rax
  cmovne %r14,%rax
  mov    %rax,0x10(%rsp)
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,0x18(%rsp)
  mov    $0x0,%r12d
  movslq %ebx,%r14
  jmp    L73
L68:
  lea    (%rbx,%r14,1),%r13
  add    $0x1,%r12d
L73:
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <strstr@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  jne    L68
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    %eax,%edx
  mov    0x18(%rsp),%eax
  sub    0xc(%rsp),%eax
  imul   %r12d,%eax
  lea    0x1(%rax,%rdx,1),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L88
  test   %r12d,%r12d
  je     L44
  mov    %rax,%r14
  movslq 0x18(%rsp),%rax
  mov    %rax,0x18(%rsp)
L39:
  mov    %r15,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  sub    %rbp,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rdx
  lea    (%rax,%rdx,1),%rdi
  mov    0x10(%rsp),%rsi
  call   <strcpy@plt>
  mov    0x18(%rsp),%rcx
  lea    (%rax,%rcx,1),%r14
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  add    %rbx,%rbp
  sub    $0x1,%r12d
  jne    L39
L32:
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strcpy@plt>
L64:
  mov    %r13,%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  mov    %rax,%r14
  jmp    L32
L65:
  mov    $0x0,%r13d
  jmp    L64
L87:
  mov    $0x0,%r13d
  jmp    L64
L88:
  mov    %rbx,%r13
  jmp    L64
```

tool_calls: name: extract_symbolic_data
arguments: label: D3
data_type: string

tool: 

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep || !(len_rep = strlen(rep)))
    return NULL;
  if (!(ins = strstr(orig, rep)))
    return NULL;
  if (!with)
    with = "";
  len_with = strlen(with);
  for (count = 0; tmp = strstr(ins, rep); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = (char *)malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  je     L48
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L48
  mov    %rsi,%rdi
  mov    %rsi,%r12
  mov    %rdx,%r13
  call   <strlen@plt>
  movslq %eax,%r15
  mov    %r15d,0xc(%rsp)
  test   %r15d,%r15d
  je     L48
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L48
  test   %r13,%r13
  lea    D4(%rip),%rax
  cmove  %rax,%r13
  xor    %ebx,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,0x10(%rsp)
  jmp    L49
  nopl   0x0(%rax,%rax,1)
L94:
  lea    (%rax,%r15,1),%r14
  add    $0x1,%ebx
L49:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L94
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%r15d
  mov    %eax,%r8d
  mov    %r15d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r8,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L48
  lea    -0x1(%rbx),%r14d
  test   %ebx,%ebx
  je     L60
  movslq %r15d,%rax
  mov    %rcx,%r15
  mov    %rax,0x10(%rsp)
  nop
L72:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  sub    %rbp,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r13,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r15
  add    %rbx,%rbp
  sub    $0x1,%r14d
  jae    L72
L42:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L45
  nopl   0x0(%rax,%rax,1)
L48:
  movq   $0x0,0x18(%rsp)
L45:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L60:
  mov    0x18(%rsp),%r15
  jmp    L42
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string

tool: 

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep || !(len_rep = strlen(rep)))
    return NULL;
  if (!(ins = strstr(orig, rep)))
    return NULL;
  if (!with)
    with = "";
  len_with = strlen(with);
  for (count = 0; tmp = strstr(ins, rep); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = (char *)malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<str_replace>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  test   %rsi,%rsi
  je     L81
  mov    %rdi,%rbp
  test   %rdi,%rdi
  je     L81
  mov    %rsi,%rdi
  mov    %rsi,%r12
  mov    %rdx,%r13
  call   <strlen@plt>
  movslq %eax,%r15
  mov    %r15d,0xc(%rsp)
  test   %r15d,%r15d
  je     L81
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  mov    %rax,%r14
  test   %rax,%rax
  je     L81
  test   %r13,%r13
  lea    D8(%rip),%rax
  cmove  %rax,%r13
  xor    %ebx,%ebx
  mov    %r13,%rdi
  call   <strlen@plt>
  mov    %eax,0x10(%rsp)
  jmp    L56
  nopl   0x0(%rax,%rax,1)
L53:
  lea    (%rax,%r15,1),%r14
  add    $0x1,%ebx
L56:
  mov    %r12,%rsi
  mov    %r14,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  jne    L53
  mov    %rbp,%rdi
  call   <strlen@plt>
  mov    0x10(%rsp),%r15d
  mov    %eax,%r8d
  mov    %r15d,%eax
  sub    0xc(%rsp),%eax
  imul   %ebx,%eax
  lea    0x1(%rax,%r8,1),%edi
  call   <malloc@plt>
  mov    %rax,0x18(%rsp)
  mov    %rax,%rcx
  test   %rax,%rax
  je     L81
  lea    -0x1(%rbx),%r14d
  test   %ebx,%ebx
  je     L44
  movslq %r15d,%rax
  mov    %rcx,%r15
  mov    %rax,0x10(%rsp)
  nop
L9:
  mov    %rbp,%rdi
  mov    %r12,%rsi
  call   <strstr@plt>
  mov    %rbp,%rsi
  mov    %r15,%rdi
  sub    %rbp,%rax
  mov    %rax,%rbx
  mov    %eax,%edx
  call   <strncpy@plt>
  movslq %ebx,%rdx
  mov    %r13,%rsi
  lea    (%rax,%rdx,1),%rdi
  call   <strcpy@plt>
  mov    0x10(%rsp),%rcx
  add    0xc(%rsp),%ebx
  movslq %ebx,%rbx
  lea    (%rax,%rcx,1),%r15
  add    %rbx,%rbp
  sub    $0x1,%r14d
  jae    L9
L17:
  mov    %rbp,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
  jmp    L27
  nopl   0x0(%rax,%rax,1)
L81:
  movq   $0x0,0x18(%rsp)
L27:
  mov    0x18(%rsp),%rax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L44:
  mov    %rax,%r15
  jmp    L17
```

tool_calls: name: retrieve_data
arguments: label: D8
datatype: string

tool: 

assistant: ```c
char *str_replace(char *orig, char *rep, char *with) {
  char *result;
  char *ins;
  char *tmp;
  int len_rep;
  int len_with;
  int len_front;
  int count;
  if (!orig)
    return NULL;
  if (!rep || !(len_rep = strlen(rep)))
    return NULL;
  if (!(ins = strstr(orig, rep)))
    return NULL;
  if (!with)
    with = "";
  len_with = strlen(with);
  for (count = 0; tmp = strstr(ins, rep); ++count) {
    ins = tmp + len_rep;
  }
  tmp = result = (char *)malloc(strlen(orig) + (len_with - len_rep) * count + 1);
  if (!result)
    return NULL;
  while (count--) {
    ins = strstr(orig, rep);
    len_front = ins - orig;
    tmp = strncpy(tmp, orig, len_front) + len_front;
    tmp = strcpy(tmp, with) + len_with;
    orig += len_front + len_rep;
  }
  strcpy(tmp, orig);
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movl   $0x0,-0x14(%rbp)
  jmp    L8
L15:
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %eax,%ebx
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %ebx,%ecx
  mov    %eax,%esi
  lea    D1(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x14(%rbp)
L8:
  cmpl   $0x9,-0x14(%rbp)
  jle    L15
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: %d %d %d


assistant: ```c
main() {
  for (int i = 0; i < 10; ++i) {
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    $0x0,%ebx
  lea    D2(%rip),%r12
L2:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %eax,%ebp
  mov    %ebx,%esi
  mov    $0x2,%edi
  call   <power@plt>
  mov    %eax,%edx
  mov    %ebp,%ecx
  mov    %ebx,%esi
  mov    %r12,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L2
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: retrieve_data
arguments: label: D2
type_guessed: string

tool: D2: %d %d %d


assistant: ```c
main() {
  for (int i = 0; i < 10; ++i) {
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L4:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <power@plt>
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L4
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: tag: D4
datatype: string

tool: D4: %d %d %d


assistant: ```c
main() {
  for (int i = 0; i < 10; ++i) {
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D1(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  nopl   0x0(%rax)
L2:
  mov    %ebx,%esi
  mov    $0xfffffffd,%edi
  call   <power@plt>
  mov    %ebx,%esi
  mov    $0x2,%edi
  mov    %eax,%r12d
  call   <power@plt>
  mov    %ebx,%esi
  mov    %r12d,%ecx
  mov    %rbp,%rdi
  mov    %eax,%edx
  add    $0x1,%ebx
  call   <printf@plt>
  cmp    $0xa,%ebx
  jne    L2
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: parse_data
arguments: data_label: D1
type: string

tool: D1: %d %d %d


assistant: ```c
main() {
  for (int i = 0; i < 10; ++i) {
    printf("%d %d %d\n", i, power(2, i), power(-3, i));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<send_all>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0xc(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %eax,-0x8(%rbp)
  movl   $0xffffffff,-0x4(%rbp)
  jmp    L42
L18:
  mov    D7(%rip),%rax
  mov    (%rax),%ecx
  mov    -0xc(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x20(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x8(%rbp),%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <send@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L53
  mov    $0xfffffff3,%eax
  jmp    L34
L53:
  cmpl   $0x0,-0x4(%rbp)
  jne    L32
  mov    $0xffffffe9,%eax
  jmp    L34
L32:
  mov    -0x4(%rbp),%eax
  sub    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  add    %eax,-0xc(%rbp)
L42:
  cmpl   $0x0,-0x8(%rbp)
  jg     L18
  mov    $0x0,%eax
L34:
  leave
  ret
```

assistant: ```c
int send_all(int tofd, uint8_t *b, size_t len) {
  int nsent;
  int nleft;
  int ret;
  nsent = 0;
  nleft = len;
  ret = -1;
  while (0 < nleft) {
    if (-1 == (ret = send(tofd, (void *)(b + nsent), nleft, MSG_NOSIGNAL))) {
      return -13;
    } else if (0 == ret) {
      return -23;
    }
    nleft -= ret;
    nsent += ret;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<send_all>:
  endbr64
  test   %edx,%edx
  jle    L51
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    %rsi,%r13
  mov    %edx,%ebx
  mov    $0x0,%ebp
  mov    D3(%rip),%r14
L24:
  movslq %ebp,%rax
  lea    0x0(%r13,%rax,4),%rsi
  mov    (%r14),%ecx
  mov    %ebx,%edx
  mov    %r12d,%edi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  je     L2
  test   %eax,%eax
  je     L21
  sub    %eax,%ebx
  add    %eax,%ebp
  test   %ebx,%ebx
  jg     L24
  mov    $0x0,%eax
  jmp    L13
L51:
  mov    $0x0,%eax
  ret
L2:
  mov    $0xfffffff3,%eax
L13:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L21:
  mov    $0xffffffe9,%eax
  jmp    L13
```

assistant: ```c
int send_all(int tofd, uint8_t *b, size_t len) {
  int nsent;
  int nleft;
  int ret;
  nsent = 0;
  nleft = len;
  ret = -1;
  while (0 < nleft) {
    if (-1 == (ret = send(tofd, (void *)(b + nsent), nleft, MSG_NOSIGNAL))) {
      return -13;
    } else if (0 == ret) {
      return -23;
    }
    nleft -= ret;
    nsent += ret;
  }
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<send_all>:
  endbr64
  test   %edx,%edx
  jle    L46
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  mov    D6(%rip),%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  mov    %edx,%ebx
  jmp    L26
  nopl   0x0(%rax,%rax,1)
L12:
  test   %eax,%eax
  je     L43
  sub    %eax,%ebx
  add    %eax,%r14d
  test   %ebx,%ebx
  jle    L3
L26:
  movslq %r14d,%rax
  mov    0x0(%r13),%ecx
  mov    %ebx,%edx
  mov    %ebp,%edi
  lea    (%r12,%rax,4),%rsi
  call   <send@plt>
  cmp    $0xffffffff,%eax
  jne    L12
  pop    %rbx
  mov    $0xfffffff3,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L3:
  pop    %rbx
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax,%rax,1)
L43:
  pop    %rbx
  mov    $0xffffffe9,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L46:
  xor    %eax,%eax
  ret
```

assistant: ```c
int send_all(int tofd, uint8_t *b, size_t len) {
  int nsent;
  int nleft;
  int ret;
  nsent = 0;
  nleft = len;
  ret = -1;
  while (0 < nleft) {
    if (-1 == (ret = send(tofd, (void *)(b + nsent), nleft, MSG_NOSIGNAL))) {
      return -13;
    } else if (0 == ret) {
      return -23;
    }
    nleft -= ret;
    nsent += ret;
  }
  return 0;
}
```