ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<_fds_check2>:
  endbr64
  test   %edx,%edx
  jle    L10
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L20
  xchg   %ax,%ax
L5:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L2
L20:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L5
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L5
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L2:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  xor    %eax,%eax
  ret
```

assistant: ```c
int _fds_check2(fd_set *fds, fd_set *chk, int nfds) {
  int fd;
  for (fd = 0; fd < nfds; fd++) {
    if (FD_ISSET(fd, chk) && FD_ISSET(fd, fds)) {
      return 1;
    }
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<_fds_check2>:
  endbr64
  test   %edx,%edx
  jle    L6
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  jmp    L27
  xchg   %ax,%ax
L41:
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  je     L25
L27:
  mov    %r12,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L41
  mov    %r13,%rsi
  mov    %ebx,%edi
  call   <FD_ISSET@plt>
  test   %rax,%rax
  je     L41
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   (%rax)
L25:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L6:
  xor    %eax,%eax
  ret
```

assistant: ```c
int _fds_check2(fd_set *fds, fd_set *chk, int nfds) {
  int fd;
  for (fd = 0; fd < nfds; fd++) {
    if (FD_ISSET(fd, chk) && FD_ISSET(fd, fds)) {
      return 1;
    }
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <getpgid@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setpgid@plt>
  mov    D0(%rip),%rax
  mov    (%rax),%eax
  mov    -0x8(%rbp),%edx
  neg    %edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <kill@plt>
  jmp    L33
L34:
  cmpl   $0x0,-0x4(%rbp)
  jne    L33
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setpgid@plt>
L33:
  call   <fork@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xffffffff,-0x4(%rbp)
  jne    L34
  jmp    L33
```

assistant: ```c
int main() {
  pid_t pid;
  pid_t pgid = getpgid(0);
  setpgid(0, 0);
  kill(-1 * pgid, SIGKILL);
  while (1) {
    while ((pid = fork()) != -1) {
      if (pid == 0) {
        setpgid(0, 0);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbx
  mov    $0x0,%edi
  call   <getpgid@plt>
  mov    %eax,%ebx
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setpgid@plt>
  neg    %ebx
  mov    %ebx,%edi
  mov    D2(%rip),%rax
  mov    (%rax),%esi
  call   <kill@plt>
L14:
  call   <fork@plt>
  test   %eax,%eax
  jne    L14
  mov    $0x0,%esi
  mov    $0x0,%edi
  call   <setpgid@plt>
  jmp    L14
```

assistant: ```c
int main() {
  pid_t pid;
  pid_t pgid = getpgid(0);
  setpgid(0, 0);
  kill(-1 * pgid, SIGKILL);
  while (1) {
    while ((pid = fork()) != -1) {
      if (pid == 0) {
        setpgid(0, 0);
      }
    }
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  call   <getpgid@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <setpgid@plt>
  mov    D6(%rip),%rax
  neg    %ebx
  mov    %ebx,%edi
  mov    (%rax),%esi
  call   <kill@plt>
  nopl   0x0(%rax)
L6:
  call   <fork@plt>
  test   %eax,%eax
  jne    L6
  xor    %esi,%esi
  xor    %edi,%edi
  call   <setpgid@plt>
  jmp    L6
```

assistant: ```c
int main() {
  pid_t pid;
  pid_t pgid = getpgid(0);
  setpgid(0, 0);
  kill(-1 * pgid, SIGKILL);
  while (1) {
    while ((pid = fork()) != -1) {
      if (pid == 0) {
        setpgid(0, 0);
      }
    }
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbx
  xor    %edi,%edi
  call   <getpgid@plt>
  xor    %esi,%esi
  xor    %edi,%edi
  mov    %eax,%ebx
  call   <setpgid@plt>
  mov    D2(%rip),%rax
  neg    %ebx
  mov    %ebx,%edi
  mov    (%rax),%esi
  call   <kill@plt>
  nopl   0x0(%rax)
L11:
  call   <fork@plt>
  test   %eax,%eax
  jne    L11
  xor    %esi,%esi
  xor    %edi,%edi
  call   <setpgid@plt>
  jmp    L11
```

assistant: ```c
int main() {
  pid_t pid;
  pid_t pgid = getpgid(0);
  setpgid(0, 0);
  kill(-1 * pgid, SIGKILL);
  while (1) {
    while ((pid = fork()) != -1) {
      if (pid == 0) {
        setpgid(0, 0);
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<closedirp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  test   %rax,%rax
  je     L1
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
L1:
  nop
  leave
  ret
```

assistant: ```c
void closedirp(DIR **d) {
  if (*d)
    closedir(*d);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<closedirp>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <closedir@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
void closedirp(DIR **d) {
  if (*d)
    closedir(*d);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<closedirp>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  jmp    1050 <closedir@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void closedirp(DIR **d) {
  if (*d)
    closedir(*d);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<closedirp>:
  endbr64
  mov    (%rdi),%rdi
  test   %rdi,%rdi
  je     L9
  jmp    1050 <closedir@plt>
  nopl   0x0(%rax)
L9:
  ret
```

assistant: ```c
void closedirp(DIR **d) {
  if (*d)
    closedir(*d);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<ojp_ntohl>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x34(%rbp),%rcx
  lea    -0x30(%rbp),%rax
  mov    $0x4,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  mov    -0x18(%rbp),%rax
  mov    %eax,%edx
  mov    -0x20(%rbp),%rax
  shl    $0x8,%eax
  or     %eax,%edx
  mov    -0x28(%rbp),%rax
  shl    $0x10,%eax
  or     %eax,%edx
  mov    -0x30(%rbp),%rax
  shl    $0x18,%eax
  or     %edx,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
uint32_t ojp_ntohl(uint32_t val) {
  uint8_t bytes[4] = {0};
  memcpy(&bytes, &val, 4);
  return ((uint32_t)bytes[3] << 0) | ((uint32_t)bytes[2] << 8) | ((uint32_t)bytes[1] << 16) | ((uint32_t)bytes[0] << 24);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<ojp_ntohl>:
  endbr64
  sub    $0x48,%rsp
  mov    %edi,0xc(%rsp)
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  movq   $0x0,0x28(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    $0x4,%edx
  call   <memcpy@plt>
  mov    0x20(%rsp),%eax
  shl    $0x8,%eax
  mov    0x18(%rsp),%edx
  shl    $0x10,%edx
  or     %edx,%eax
  or     0x28(%rsp),%eax
  mov    0x10(%rsp),%edx
  shl    $0x18,%edx
  or     %edx,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x48,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t ojp_ntohl(uint32_t val) {
  uint8_t bytes[4] = {0};
  memcpy(&bytes, &val, 4);
  return ((uint32_t)bytes[3] << 0) | ((uint32_t)bytes[2] << 8) | ((uint32_t)bytes[1] << 16) | ((uint32_t)bytes[0] << 24);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ojp_ntohl>:
  endbr64
  sub    $0x48,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x4,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <memcpy@plt>
  mov    0x20(%rsp),%eax
  mov    0x18(%rsp),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    0x10(%rsp),%edx
  or     0x28(%rsp),%eax
  shl    $0x18,%edx
  or     %edx,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x48,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t ojp_ntohl(uint32_t val) {
  uint8_t bytes[4] = {0};
  memcpy(&bytes, &val, 4);
  return ((uint32_t)bytes[3] << 0) | ((uint32_t)bytes[2] << 8) | ((uint32_t)bytes[1] << 16) | ((uint32_t)bytes[0] << 24);
}
```
user: What is the c source code of the assembly code below?

```asm
<ojp_ntohl>:
  endbr64
  sub    $0x48,%rsp
  pxor   %xmm0,%xmm0
  mov    $0x4,%edx
  mov    %edi,0xc(%rsp)
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x38(%rsp)
  xor    %eax,%eax
  movaps %xmm0,0x10(%rsp)
  movaps %xmm0,0x20(%rsp)
  call   <memcpy@plt>
  mov    0x20(%rsp),%eax
  mov    0x18(%rsp),%edx
  shl    $0x8,%eax
  shl    $0x10,%edx
  or     %edx,%eax
  mov    0x10(%rsp),%edx
  or     0x28(%rsp),%eax
  shl    $0x18,%edx
  or     %edx,%eax
  mov    0x38(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x48,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
uint32_t ojp_ntohl(uint32_t val) {
  uint8_t bytes[4] = {0};
  memcpy(&bytes, &val, 4);
  return ((uint32_t)bytes[3] << 0) | ((uint32_t)bytes[2] << 8) | ((uint32_t)bytes[1] << 16) | ((uint32_t)bytes[0] << 24);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<serial_write_int>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,%eax
  mov    %ax,-0x18(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L20
L3:
  nop
L11:
  movzwl -0x18(%rbp),%eax
  mov    %eax,%edi
  call   <serial_is_transmit_empty@plt>
  test   %rax,%rax
  je     L11
  mov    $0x3,%eax
  sub    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  shr    %cl,%edx
  mov    %edx,%eax
  movzbl %al,%edx
  movzwl -0x18(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <outb@plt>
  addl   $0x1,-0x4(%rbp)
L20:
  cmpl   $0x3,-0x4(%rbp)
  jbe    L3
  nop
  nop
  leave
  ret
```

assistant: ```c
void serial_write_int(unsigned int i, const unsigned short com) {
  unsigned int k = 0;
  for (; k < 4; ++k) {
    while (serial_is_transmit_empty(com) == 0)
      ;
    outb(com, (i >> (3 - k)) & 0xFF);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<serial_write_int>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x3,%ebp
  movzwl %si,%ebx
L16:
  mov    %ebx,%edi
  call   <serial_is_transmit_empty@plt>
  test   %rax,%rax
  je     L16
  mov    %r12d,%esi
  mov    %ebp,%ecx
  shr    %cl,%esi
  movzbl %sil,%esi
  mov    %ebx,%edi
  call   <outb@plt>
  sub    $0x1,%ebp
  cmp    $0xffffffff,%ebp
  jne    L16
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void serial_write_int(unsigned int i, const unsigned short com) {
  unsigned int k = 0;
  for (; k < 4; ++k) {
    while (serial_is_transmit_empty(com) == 0)
      ;
    outb(com, (i >> (3 - k)) & 0xFF);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<serial_write_int>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  movzwl %si,%ebx
  nopl   0x0(%rax,%rax,1)
L8:
  mov    %ebx,%edi
  call   <serial_is_transmit_empty@plt>
  test   %rax,%rax
  je     L8
  mov    %ebp,%ecx
  mov    %r12d,%esi
  mov    %ebx,%edi
  shr    %cl,%esi
  movzbl %sil,%esi
  call   <outb@plt>
  sub    $0x1,%ebp
  jae    L8
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void serial_write_int(unsigned int i, const unsigned short com) {
  unsigned int k = 0;
  for (; k < 4; ++k) {
    while (serial_is_transmit_empty(com) == 0)
      ;
    outb(com, (i >> (3 - k)) & 0xFF);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<serial_write_int>:
  endbr64
  push   %r12
  mov    %edi,%r12d
  push   %rbp
  mov    $0x3,%ebp
  push   %rbx
  movzwl %si,%ebx
  nopl   0x0(%rax,%rax,1)
L3:
  mov    %ebx,%edi
  call   <serial_is_transmit_empty@plt>
  test   %rax,%rax
  je     L3
  mov    %ebp,%ecx
  mov    %r12d,%esi
  mov    %ebx,%edi
  shr    %cl,%esi
  movzbl %sil,%esi
  call   <outb@plt>
  sub    $0x1,%ebp
  jae    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void serial_write_int(unsigned int i, const unsigned short com) {
  unsigned int k = 0;
  for (; k < 4; ++k) {
    while (serial_is_transmit_empty(com) == 0)
      ;
    outb(com, (i >> (3 - k)) & 0xFF);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<invMixColumns>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L7
L15:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <invMixColumn@plt>
  addq   $0x4,-0x8(%rbp)
  addl   $0x1,-0xc(%rbp)
L7:
  cmpl   $0x3,-0xc(%rbp)
  jle    L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void invMixColumns(unsigned char *const block) {
  int i;
  unsigned char *temp = block;
  for (i = 0; i < 4; i++) {
    invMixColumn(temp);
    temp += 4;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<invMixColumns>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    0x10(%rdi),%rbp
L1:
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <invMixColumn@plt>
  add    $0x4,%rbx
  cmp    %rbx,%rbp
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void invMixColumns(unsigned char *const block) {
  int i;
  unsigned char *temp = block;
  for (i = 0; i < 4; i++) {
    invMixColumn(temp);
    temp += 4;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<invMixColumns>:
  endbr64
  push   %rbp
  lea    0x10(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L9:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <invMixColumn@plt>
  cmp    %rbx,%rbp
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void invMixColumns(unsigned char *const block) {
  int i;
  unsigned char *temp = block;
  for (i = 0; i < 4; i++) {
    invMixColumn(temp);
    temp += 4;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<invMixColumns>:
  endbr64
  push   %rbp
  lea    0x10(%rdi),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
L5:
  mov    %rbx,%rdi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <invMixColumn@plt>
  cmp    %rbp,%rbx
  jne    L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void invMixColumns(unsigned char *const block) {
  int i;
  unsigned char *temp = block;
  for (i = 0; i < 4; i++) {
    invMixColumn(temp);
    temp += 4;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Cyc_is_other_special>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    %al,-0x5(%rbp)
  movsbl -0x5(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x5e,-0x4(%rbp)
  jg     L34
  cmpl   $0x9,-0x4(%rbp)
  jl     L4
  mov    -0x4(%rbp),%eax
  sub    $0x9,%eax
  cmp    $0x55,%eax
  ja     L4
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D10(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D10(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
L34:
  cmpl   $0x7c,-0x4(%rbp)
  je     L20
  jmp    L4
  nop
  nop
  nop
  nop
L20:
  nop
  nop
  nop
  nop
  nop
  mov    $0x1,%eax
  jmp    L14
L4:
  mov    $0x0,%eax
L14:
  pop    %rbp
  ret
```

assistant: ```c
int Cyc_is_other_special(char c) {
  char _T0;
  int _T1;
  _T0 = c;
  _T1 = (int)_T0;
  switch (_T1) {
  case 92:
    goto _LL4;
  case 34:
  _LL4:
    goto _LL6;
  case 59:
  _LL6:
    goto _LL8;
  case 38:
  _LL8:
    goto _LLA;
  case 40:
  _LLA:
    goto _LLC;
  case 41:
  _LLC:
    goto _LLE;
  case 124:
  _LLE:
    goto _LL10;
  case 94:
  _LL10:
    goto _LL12;
  case 60:
  _LL12:
    goto _LL14;
  case 62:
  _LL14:
    goto _LL16;
  case 10:
  _LL16:
    goto _LL18;
  case 9:
  _LL18:
    return 1;
  default:
    return 0;
  };
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Cyc_is_other_special>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3c,%dil
  jg     L15
  cmp    $0x8,%dil
  jle    L7
  movabs $0x1800034400000600,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L15:
  sub    $0x3e,%ecx
  movabs $0x4000000140000001,%rdx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  cmp    $0x3f,%cl
  mov    $0x0,%eax
  cmovb  %edx,%eax
  ret
```

assistant: ```c
int Cyc_is_other_special(char c) {
  char _T0;
  int _T1;
  _T0 = c;
  _T1 = (int)_T0;
  switch (_T1) {
  case 92:
    goto _LL4;
  case 34:
  _LL4:
    goto _LL6;
  case 59:
  _LL6:
    goto _LL8;
  case 38:
  _LL8:
    goto _LLA;
  case 40:
  _LLA:
    goto _LLC;
  case 41:
  _LLC:
    goto _LLE;
  case 124:
  _LLE:
    goto _LL10;
  case 94:
  _LL10:
    goto _LL12;
  case 60:
  _LL12:
    goto _LL14;
  case 62:
  _LL14:
    goto _LL16;
  case 10:
  _LL16:
    goto _LL18;
  case 9:
  _LL18:
    return 1;
  default:
    return 0;
  };
}
```
user: What is the c source code of the assembly code below:

```asm
<Cyc_is_other_special>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3c,%dil
  jg     L3
  cmp    $0x8,%dil
  jle    L4
  movabs $0x1800034400000600,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L3:
  movabs $0x4000000140000001,%rdx
  sub    $0x3e,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x3f,%cl
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Cyc_is_other_special(char c) {
  char _T0;
  int _T1;
  _T0 = c;
  _T1 = (int)_T0;
  switch (_T1) {
  case 92:
    goto _LL4;
  case 34:
  _LL4:
    goto _LL6;
  case 59:
  _LL6:
    goto _LL8;
  case 38:
  _LL8:
    goto _LLA;
  case 40:
  _LLA:
    goto _LLC;
  case 41:
  _LLC:
    goto _LLE;
  case 124:
  _LLE:
    goto _LL10;
  case 94:
  _LL10:
    goto _LL12;
  case 60:
  _LL12:
    goto _LL14;
  case 62:
  _LL14:
    goto _LL16;
  case 10:
  _LL16:
    goto _LL18;
  case 9:
  _LL18:
    return 1;
  default:
    return 0;
  };
}
```
user: Translate the below assembly code into C programming language:

```asm
<Cyc_is_other_special>:
  endbr64
  mov    %edi,%ecx
  cmp    $0x3c,%dil
  jg     L14
  cmp    $0x8,%dil
  jle    L0
  movabs $0x1800034400000600,%rax
  shr    %cl,%rax
  and    $0x1,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L14:
  movabs $0x4000000140000001,%rdx
  sub    $0x3e,%ecx
  shr    %cl,%rdx
  mov    %edx,%eax
  and    $0x1,%eax
  mov    %eax,%edx
  xor    %eax,%eax
  cmp    $0x3f,%cl
  cmovb  %edx,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int Cyc_is_other_special(char c) {
  char _T0;
  int _T1;
  _T0 = c;
  _T1 = (int)_T0;
  switch (_T1) {
  case 92:
    goto _LL4;
  case 34:
  _LL4:
    goto _LL6;
  case 59:
  _LL6:
    goto _LL8;
  case 38:
  _LL8:
    goto _LLA;
  case 40:
  _LLA:
    goto _LLC;
  case 41:
  _LLC:
    goto _LLE;
  case 124:
  _LLE:
    goto _LL10;
  case 94:
  _LL10:
    goto _LL12;
  case 60:
  _LL12:
    goto _LL14;
  case 62:
  _LL14:
    goto _LL16;
  case 10:
  _LL16:
    goto _LL18;
  case 9:
  _LL18:
    return 1;
  default:
    return 0;
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<mmio_writew>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    $0x0,%eax
  call   <sync_primitive@plt>
  nop
  leave
  ret
```

assistant: ```c
void mmio_writew(uint16_t val, void *addr) {
  *(volatile uint16_t *)addr = val;
  sync_primitive();
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mmio_writew>:
  endbr64
  sub    $0x8,%rsp
  mov    %edi,(%rsi)
  mov    $0x0,%eax
  call   <sync_primitive@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void mmio_writew(uint16_t val, void *addr) {
  *(volatile uint16_t *)addr = val;
  sync_primitive();
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<mmio_writew>:
  endbr64
  mov    %edi,(%rsi)
  xor    %eax,%eax
  jmp    1050 <sync_primitive@plt>
```

assistant: ```c
void mmio_writew(uint16_t val, void *addr) {
  *(volatile uint16_t *)addr = val;
  sync_primitive();
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<mmio_writew>:
  endbr64
  mov    %edi,(%rsi)
  xor    %eax,%eax
  jmp    1050 <sync_primitive@plt>
```

assistant: ```c
void mmio_writew(uint16_t val, void *addr) {
  *(volatile uint16_t *)addr = val;
  sync_primitive();
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<jours_depuis_debut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x640,-0x8(%rbp)
  jmp    L20
L26:
  mov    -0x8(%rbp),%eax
  mov    %eax,%edi
  call   <jours_par_an@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L20:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L26
  movl   $0x1,-0x8(%rbp)
  jmp    L27
L24:
  mov    -0x1c(%rbp),%edx
  mov    -0x8(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <jours_par_mois@plt>
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0x4(%rbp)
  addl   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jl     L24
  mov    -0x4(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %edx,%eax
  sub    $0x1,%eax
  leave
  ret
```

assistant: ```c
int jours_depuis_debut(int jour, int mois, int annee) {
  int i, total = 0;
  for (i = 1600; i < annee; i++)
    total += jours_par_an(i);
  for (i = 1; i < mois; i++)
    total += jours_par_mois(i, annee);
  return total + jour - 1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<jours_depuis_debut>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r14d
  mov    %esi,%r13d
  mov    %edx,%r12d
  cmp    $0x640,%edx
  jle    L25
  mov    $0x0,%ebx
  mov    $0x640,%ebp
L22:
  mov    %ebp,%edi
  call   <jours_par_an@plt>
  add    %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r12d
  jne    L22
L19:
  cmp    $0x1,%r13d
  jle    L47
  mov    $0x1,%ebp
L9:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <jours_par_mois@plt>
  add    %eax,%ebx
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jne    L9
L47:
  lea    -0x1(%rbx,%r14,1),%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L25:
  mov    $0x0,%ebx
  jmp    L19
```

assistant: ```c
int jours_depuis_debut(int jour, int mois, int annee) {
  int i, total = 0;
  for (i = 1600; i < annee; i++)
    total += jours_par_an(i);
  for (i = 1; i < mois; i++)
    total += jours_par_mois(i, annee);
  return total + jour - 1;
}
```