ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<getDirname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L40
L53:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <is_slash@plt>
  test   %rax,%rax
  jne    L8
  subl   $0x1,-0x4(%rbp)
L40:
  cmpl   $0x0,-0x4(%rbp)
  jns    L53
  jmp    L28
L8:
  nop
L28:
  cmpl   $0x0,-0x4(%rbp)
  js     L11
  mov    -0x4(%rbp),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x2f,(%rax)
  jmp    L49
L11:
  movl   $0xffffffff,-0x4(%rbp)
L49:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  nop
  leave
  ret
```

assistant: ```c
void getDirname(char *fname, char *dirname) {
  int i;
  for (i = (int)strlen(fname) - 1; i >= 0; i--) {
    if (is_slash(fname[i]))
      break;
  }
  if (i >= 0) {
    strncpy(dirname, fname, i);
    dirname[i] = '/';
  } else
    i = -1;
  dirname[i + 1] = '\0';
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<getDirname>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r12
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L14
  movslq %eax,%rbx
L1:
  mov    %ebx,%r13d
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <is_slash@plt>
  test   %rax,%rax
  jne    L4
  sub    $0x1,%rbx
  test   %ebx,%ebx
  jns    L1
L14:
  mov    $0xffffffff,%r13d
L17:
  movslq %r13d,%r13
  movb   $0x0,0x1(%r12,%r13,1)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  test   %ebx,%ebx
  js     L43
  mov    %ebx,%edx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <strncpy@plt>
  movslq %ebx,%rax
  movb   $0x2f,(%r12,%rax,1)
  jmp    L17
L43:
  mov    $0xffffffff,%r13d
  jmp    L17
```

assistant: ```c
void getDirname(char *fname, char *dirname) {
  int i;
  for (i = (int)strlen(fname) - 1; i >= 0; i--) {
    if (is_slash(fname[i]))
      break;
  }
  if (i >= 0) {
    strncpy(dirname, fname, i);
    dirname[i] = '/';
  } else
    i = -1;
  dirname[i + 1] = '\0';
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<getDirname>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L5
  movslq %eax,%rbx
  jmp    L22
  nopl   0x0(%rax,%rax,1)
L17:
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  je     L5
L22:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r12d
  call   <is_slash@plt>
  test   %rax,%rax
  je     L17
  add    $0x1,%r12d
  mov    %r13,%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movslq %r12d,%r12
  movb   $0x2f,0x0(%r13,%rbx,1)
  add    %r12,%r13
L5:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void getDirname(char *fname, char *dirname) {
  int i;
  for (i = (int)strlen(fname) - 1; i >= 0; i--) {
    if (is_slash(fname[i]))
      break;
  }
  if (i >= 0) {
    strncpy(dirname, fname, i);
    dirname[i] = '/';
  } else
    i = -1;
  dirname[i + 1] = '\0';
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<getDirname>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  sub    $0x1,%eax
  js     L38
  movslq %eax,%rbx
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L6:
  sub    $0x1,%rbx
  cmp    $0xffffffff,%ebx
  je     L38
L1:
  movsbl 0x0(%rbp,%rbx,1),%edi
  mov    %ebx,%r12d
  call   <is_slash@plt>
  test   %rax,%rax
  je     L6
  add    $0x1,%r12d
  mov    %r13,%rdi
  mov    %ebx,%edx
  mov    %rbp,%rsi
  call   <strncpy@plt>
  movslq %r12d,%r12
  movb   $0x2f,0x0(%r13,%rbx,1)
  add    %r12,%r13
L38:
  movb   $0x0,0x0(%r13)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
void getDirname(char *fname, char *dirname) {
  int i;
  for (i = (int)strlen(fname) - 1; i >= 0; i--) {
    if (is_slash(fname[i]))
      break;
  }
  if (i >= 0) {
    strncpy(dirname, fname, i);
    dirname[i] = '/';
  } else
    i = -1;
  dirname[i + 1] = '\0';
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x20(%rbp)
  movl   $0x2,-0x1c(%rbp)
  movl   $0x3,-0x18(%rbp)
  movl   $0x4,-0x14(%rbp)
  lea    -0x24(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x24(%rbp),%edx
  lea    -0x20(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <buscaSequencial@plt>
  test   %eax,%eax
  jne    L23
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <mostrarVetorInteiros@plt>
  jmp    L24
L23:
  mov    -0x24(%rbp),%eax
  mov    %eax,%esi
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    $0x4,%esi
  mov    %rax,%rdi
  call   <mostrarVetorInteiros@plt>
L24:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: tag: D12
type_guessed: string
name: extract_symbolic_data
arguments: tag: D20
type_guessed: string

tool: D0: %d

tool: D12: O numero %d NAO esta no vetor 

tool: D20: O numero %d esta no vetor 

assistant: ```c
int main() {
  int v[] = {1, 2, 3, 4};
  int k;
  scanf("%d", &k);
  if (!buscaSequencial(v, 4, k)) {
    printf("O numero %d NAO esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  } else {
    printf("O numero %d esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  movl   $0x1,0x10(%rsp)
  movl   $0x2,0x14(%rsp)
  movl   $0x3,0x18(%rsp)
  movl   $0x4,0x1c(%rsp)
  lea    0xc(%rsp),%rsi
  lea    D4(%rip),%rdi
  call   <scanf@plt>
  lea    0x10(%rsp),%rdi
  mov    0xc(%rsp),%edx
  mov    $0x4,%esi
  call   <buscaSequencial@plt>
  test   %eax,%eax
  jne    L14
  mov    0xc(%rsp),%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x4,%esi
  call   <mostrarVetorInteiros@plt>
L18:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  mov    $0x0,%eax
  add    $0x38,%rsp
  ret
L14:
  mov    0xc(%rsp),%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x10(%rsp),%rdi
  mov    $0x4,%esi
  call   <mostrarVetorInteiros@plt>
  jmp    L18
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D4
datatype: string
name: parse_data
arguments: label: D8
datatype: string
name: parse_data
arguments: label: D6
datatype: string

tool: D4: %d

tool: D8: O numero %d NAO esta no vetor 

tool: D6: O numero %d esta no vetor 

assistant: ```c
int main() {
  int v[] = {1, 2, 3, 4};
  int k;
  scanf("%d", &k);
  if (!buscaSequencial(v, 4, k)) {
    printf("O numero %d NAO esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  } else {
    printf("O numero %d esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rdi
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  movabs $0x200000001,%rax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  mov    %rax,0x10(%rsp)
  movabs $0x400000003,%rax
  mov    %rax,0x18(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <buscaSequencial@plt>
  mov    0xc(%rsp),%esi
  test   %eax,%eax
  jne    L13
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <mostrarVetorInteiros@plt>
L3:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L13:
  lea    D24(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <mostrarVetorInteiros@plt>
  jmp    L3
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D7
type: string
name: retrieve_data
arguments: tag: D5
type: string
name: retrieve_data
arguments: tag: D24
type: string

tool: D7: %d

tool: D5: O numero %d NAO esta no vetor 

tool: D24: O numero %d esta no vetor 

assistant: ```c
int main() {
  int v[] = {1, 2, 3, 4};
  int k;
  scanf("%d", &k);
  if (!buscaSequencial(v, 4, k)) {
    printf("O numero %d NAO esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  } else {
    printf("O numero %d esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D39(%rip),%rdi
  sub    $0x30,%rsp
  movdqa D28(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x28(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    0x10(%rsp),%rbp
  movaps %xmm0,0x10(%rsp)
  call   <scanf@plt>
  mov    0xc(%rsp),%edx
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <buscaSequencial@plt>
  mov    0xc(%rsp),%esi
  test   %eax,%eax
  jne    L3
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <mostrarVetorInteiros@plt>
L20:
  mov    0x28(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x30,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L3:
  lea    D16(%rip),%rdi
  call   <printf@plt>
  mov    $0x4,%esi
  mov    %rbp,%rdi
  call   <mostrarVetorInteiros@plt>
  jmp    L20
L10:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D39
type_guessed: string
name: read_data
arguments: data_tag: D28
type_guessed: byte[16]
name: read_data
arguments: data_tag: D19
type_guessed: string
name: read_data
arguments: data_tag: D16
type_guessed: string

tool: D39: %d

tool: {"D28": [0x01,0x00,0x00,0x00,0x02,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x04,0x00,0x00,0x00]}

tool: D19: O numero %d NAO esta no vetor 

tool: D16: O numero %d esta no vetor 

assistant: ```c
int main() {
  int v[] = {1, 2, 3, 4};
  int k;
  scanf("%d", &k);
  if (!buscaSequencial(v, 4, k)) {
    printf("O numero %d NAO esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  } else {
    printf("O numero %d esta no vetor ", k);
    mostrarVetorInteiros(v, 4);
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rtrim>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  jmp    L14
L7:
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  subl   $0x1,-0x8(%rbp)
L14:
  cmpl   $0x0,-0x8(%rbp)
  jle    L4
  mov    -0x8(%rbp),%eax
  cltq
  lea    -0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L7
L4:
  mov    -0x4(%rbp),%eax
  sub    -0x8(%rbp),%eax
  leave
  ret
```

assistant: ```c
unsigned int rtrim(char *s) {
  int n = strlen(s);
  int i;
  for (i = n; i > 0 && s[i - 1] == ' '; --i)
    s[i - 1] = 0;
  return n - i;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L36
  movslq %eax,%rdx
  lea    -0x1(%rbx,%rdx,1),%rdx
  mov    %eax,%ecx
L39:
  cmpb   $0x20,(%rdx)
  jne    L24
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  sub    $0x1,%ecx
  jne    L39
L24:
  sub    %ecx,%eax
  pop    %rbx
  ret
L36:
  mov    %eax,%ecx
  jmp    L24
```

assistant: ```c
unsigned int rtrim(char *s) {
  int n = strlen(s);
  int i;
  for (i = n; i > 0 && s[i - 1] == ' '; --i)
    s[i - 1] = 0;
  return n - i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L16
  movslq %eax,%rdx
  mov    %eax,%ecx
  lea    -0x1(%rbx,%rdx,1),%rdx
  jmp    L7
  nopl   (%rax)
L17:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  sub    $0x1,%ecx
  je     L15
L7:
  cmpb   $0x20,(%rdx)
  je     L17
  sub    %ecx,%eax
L15:
  pop    %rbx
  ret
L16:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int rtrim(char *s) {
  int n = strlen(s);
  int i;
  for (i = n; i > 0 && s[i - 1] == ' '; --i)
    s[i - 1] = 0;
  return n - i;
}
```
user: What is the c source code of the assembly code below?

```asm
<rtrim>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <strlen@plt>
  test   %eax,%eax
  jle    L9
  movslq %eax,%rdx
  mov    %eax,%ecx
  lea    -0x1(%rbx,%rdx,1),%rdx
  jmp    L15
  nopl   (%rax)
L31:
  movb   $0x0,(%rdx)
  sub    $0x1,%rdx
  sub    $0x1,%ecx
  je     L26
L15:
  cmpb   $0x20,(%rdx)
  je     L31
  sub    %ecx,%eax
L26:
  pop    %rbx
  ret
L9:
  xor    %eax,%eax
  pop    %rbx
  ret
```

assistant: ```c
unsigned int rtrim(char *s) {
  int n = strlen(s);
  int i;
  for (i = n; i > 0 && s[i - 1] == ' '; --i)
    s[i - 1] = 0;
  return n - i;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<xTrimLeft>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L9
L22:
  addq   $0x1,-0x8(%rbp)
L9:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x20,%al
  je     L22
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x9,%al
  je     L22
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *xTrimLeft(char *buffer) {
  while (*buffer == ' ' || *buffer == '\t')
    buffer++;
  return (buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xTrimLeft>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  cmp    $0x20,%dl
  je     L3
  cmp    $0x9,%dl
  jne    L0
L3:
  add    $0x1,%rax
  movzbl (%rax),%edx
  cmp    $0x20,%dl
  je     L3
  cmp    $0x9,%dl
  je     L3
L0:
  ret
```

assistant: ```c
char *xTrimLeft(char *buffer) {
  while (*buffer == ' ' || *buffer == '\t')
    buffer++;
  return (buffer);
}
```
user: Translate the below assembly code into C programming language:

```asm
<xTrimLeft>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L29
  nop
L25:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L25
L29:
  cmp    $0x9,%dl
  je     L25
  ret
```

assistant: ```c
char *xTrimLeft(char *buffer) {
  while (*buffer == ' ' || *buffer == '\t')
    buffer++;
  return (buffer);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<xTrimLeft>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  cmp    $0x20,%dl
  jne    L21
  nop
L29:
  movzbl 0x1(%rax),%edx
  add    $0x1,%rax
  cmp    $0x20,%dl
  je     L29
L21:
  cmp    $0x9,%dl
  je     L29
  ret
```

assistant: ```c
char *xTrimLeft(char *buffer) {
  while (*buffer == ' ' || *buffer == '\t')
    buffer++;
  return (buffer);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_u32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  shr    $0x18,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    %ecx,%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl %cl,%edx
  mov    %edx,(%rax)
  mov    -0x14(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%ecx
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl %cl,%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%rax
  lea    0x4(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  mov    -0x14(%rbp),%edx
  movzbl %dl,%edx
  mov    %edx,(%rax)
  cmpq   $0x0,-0x10(%rbp)
  je     L6
  mov    -0x10(%rbp),%rax
  mov    (%rax),%rax
  lea    -0x4(%rax),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,(%rax)
L6:
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
uint8_t *write_u32(uint8_t *p, size_t *s, const uint32_t v) {
  *p++ = (v >> 24) & 0xFF;
  *p++ = (v >> 16) & 0xFF;
  *p++ = (v >> 8) & 0xFF;
  *p++ = (v >> 0) & 0xFF;
  if (s != NULL)
    *s -= 4;
  return (p);
}
```
user: Translate the below assembly code into C programming language:

```asm
<write_u32>:
  endbr64
  mov    %edx,%eax
  shr    $0x18,%eax
  mov    %eax,(%rdi)
  mov    %edx,%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,0x4(%rdi)
  movzbl %dh,%eax
  mov    %eax,0x8(%rdi)
  lea    0x10(%rdi),%rax
  and    $0xff,%edx
  mov    %edx,0xc(%rdi)
  test   %rsi,%rsi
  je     L8
  subq   $0x4,(%rsi)
L8:
  ret
```

assistant: ```c
uint8_t *write_u32(uint8_t *p, size_t *s, const uint32_t v) {
  *p++ = (v >> 24) & 0xFF;
  *p++ = (v >> 16) & 0xFF;
  *p++ = (v >> 8) & 0xFF;
  *p++ = (v >> 0) & 0xFF;
  if (s != NULL)
    *s -= 4;
  return (p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_u32>:
  endbr64
  mov    %edx,%eax
  shr    $0x18,%eax
  mov    %eax,(%rdi)
  mov    %edx,%eax
  sar    $0x10,%eax
  and    $0xff,%eax
  mov    %eax,0x4(%rdi)
  movzbl %dh,%eax
  and    $0xff,%edx
  mov    %eax,0x8(%rdi)
  lea    0x10(%rdi),%rax
  mov    %edx,0xc(%rdi)
  test   %rsi,%rsi
  je     L4
  subq   $0x4,(%rsi)
L4:
  ret
```

assistant: ```c
uint8_t *write_u32(uint8_t *p, size_t *s, const uint32_t v) {
  *p++ = (v >> 24) & 0xFF;
  *p++ = (v >> 16) & 0xFF;
  *p++ = (v >> 8) & 0xFF;
  *p++ = (v >> 0) & 0xFF;
  if (s != NULL)
    *s -= 4;
  return (p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_u32>:
  endbr64
  mov    %edx,%eax
  movzbl %dh,%ecx
  lea    0x10(%rdi),%r8
  shr    $0x18,%eax
  movd   %ecx,%xmm1
  movd   %eax,%xmm0
  mov    %edx,%eax
  movzbl %dl,%edx
  sar    $0x10,%eax
  movd   %edx,%xmm2
  movzbl %al,%eax
  punpckldq %xmm2,%xmm1
  movd   %eax,%xmm3
  punpckldq %xmm3,%xmm0
  punpcklqdq %xmm1,%xmm0
  movups %xmm0,(%rdi)
  test   %rsi,%rsi
  je     L2
  subq   $0x4,(%rsi)
L2:
  mov    %r8,%rax
  ret
```

assistant: ```c
uint8_t *write_u32(uint8_t *p, size_t *s, const uint32_t v) {
  *p++ = (v >> 24) & 0xFF;
  *p++ = (v >> 16) & 0xFF;
  *p++ = (v >> 8) & 0xFF;
  *p++ = (v >> 0) & 0xFF;
  if (s != NULL)
    *s -= 4;
  return (p);
}
```
user: What is the c source code of the assembly code below:

```asm
<bubble_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L24:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x4(%rbp)
  jmp    L28
L5:
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jle    L29
  mov    -0x4(%rbp),%edx
  mov    -0x8(%rbp),%ecx
  mov    -0x18(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <swap@plt>
L29:
  addl   $0x1,-0x4(%rbp)
L28:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  addl   $0x1,-0x8(%rbp)
L7:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L24
  nop
  nop
  leave
  ret
```

assistant: ```c
void bubble_sort(int *arr, int length) {
  for (int i = 0; i < length; i++)
    for (int j = i + 1; j < length; j++)
      if (arr[i] > arr[j])
        swap(arr, i, j);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubble_sort>:
  endbr64
  test   %esi,%esi
  jle    L35
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbp
  lea    -0x1(%rsi),%eax
  mov    %rax,(%rsp)
  mov    $0x0,%r12d
  lea    -0x2(%rsi),%eax
  mov    %eax,0xc(%rsp)
  jmp    L12
L55:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  je     L6
L64:
  mov    %ebx,%edx
  mov    0x0(%rbp,%rbx,4),%eax
  cmp    %eax,0x0(%rbp,%r12,4)
  jle    L55
  mov    %r14d,%esi
  mov    %rbp,%rdi
  call   <swap@plt>
  jmp    L55
L6:
  mov    %r15,%r12
L12:
  mov    %r12d,%r14d
  cmp    (%rsp),%r12
  je     L47
  lea    0x1(%r12),%r15
  mov    0xc(%rsp),%eax
  sub    %r12d,%eax
  lea    0x2(%r12,%rax,1),%r13
  mov    %r15,%rbx
  jmp    L64
L47:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L35:
  ret
```

assistant: ```c
void bubble_sort(int *arr, int length) {
  for (int i = 0; i < length; i++)
    for (int j = i + 1; j < length; j++)
      if (arr[i] > arr[j])
        swap(arr, i, j);
}
```
user: What is the c source code of the assembly code below?

```asm
<bubble_sort>:
  endbr64
  test   %esi,%esi
  jle    L20
  push   %r15
  lea    -0x1(%rsi),%eax
  push   %r14
  push   %r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  mov    %r12d,%r14d
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rax,(%rsp)
  lea    -0x2(%rsi),%eax
  mov    %eax,0xc(%rsp)
  cmp    (%rsp),%r12
  je     L21
  nopw   0x0(%rax,%rax,1)
L18:
  mov    0xc(%rsp),%eax
  lea    0x1(%r12),%r13
  mov    %r13,%rbx
  sub    %r12d,%eax
  lea    0x2(%r12,%rax,1),%r15
  jmp    L25
  cs nopw 0x0(%rax,%rax,1)
L0:
  add    $0x1,%rbx
  cmp    %r15,%rbx
  je     L19
L25:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%edx
  cmp    %eax,0x0(%rbp,%r12,4)
  jle    L0
  mov    %r14d,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %r15,%rbx
  jne    L25
L19:
  mov    %r13,%r12
  mov    %r12d,%r14d
  cmp    (%rsp),%r12
  jne    L18
L21:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L20:
  ret
```

assistant: ```c
void bubble_sort(int *arr, int length) {
  for (int i = 0; i < length; i++)
    for (int j = i + 1; j < length; j++)
      if (arr[i] > arr[j])
        swap(arr, i, j);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<bubble_sort>:
  endbr64
  cmp    $0x1,%esi
  jle    L56
  push   %r15
  mov    %esi,%r15d
  push   %r14
  movslq %esi,%r14
  push   %r13
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L46:
  lea    -0x1(%r12),%r13d
  mov    %r12,%rbx
  jmp    L19
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jle    L54
L19:
  mov    0x0(%rbp,%rbx,4),%eax
  mov    %ebx,%edx
  cmp    %eax,-0x4(%rbp,%r12,4)
  jle    L31
  mov    %r13d,%esi
  mov    %rbp,%rdi
  add    $0x1,%rbx
  call   <swap@plt>
  cmp    %ebx,%r15d
  jg     L19
L54:
  add    $0x1,%r12
  cmp    %r14,%r12
  jne    L46
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L56:
  ret
```

assistant: ```c
void bubble_sort(int *arr, int length) {
  for (int i = 0; i < length; i++)
    for (int j = i + 1; j < length; j++)
      if (arr[i] > arr[j])
        swap(arr, i, j);
}
```