ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<strstr>:
  endbr64
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  movzbl (%rsi),%r13d
  test   %r13b,%r13b
  je     L10
  mov    %rsi,%rbp
  mov    %rdi,%rbx
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  add    $0x1,%r12
  sub    %rax,%r12
  lea    (%r14,%r12,1),%rsi
  cmp    %rsi,%r14
  jb     L25
  jmp    L50
L71:
  add    $0x1,%rbx
  cmp    %rbx,%rsi
  je     L50
L25:
  cmp    (%rbx),%r13b
  jne    L71
  mov    $0x1,%eax
  jmp    L38
  nopl   (%rax)
L61:
  movzbl (%rbx,%rax,1),%ecx
  add    $0x1,%rax
  cmp    %cl,%dl
  jne    L71
L38:
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L61
  mov    %rbx,%r14
L10:
  pop    %rbx
  mov    %r14,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L50:
  xor    %r14d,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14,%rax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  const char *hend;
  const char *a, *b;
  if (*needle == 0)
    return (char *)haystack;
  hend = haystack + strlen(haystack) - strlen(needle) + 1;
  while (haystack < hend) {
    if (*haystack == *needle) {
      a = haystack;
      b = needle;
      for (;;) {
        if (*b == 0)
          return (char *)haystack;
        if (*a++ != *b++) {
          break;
        }
      }
    }
    haystack++;
  }
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<strstr>:
  endbr64
  push   %r13
  mov    %rdi,%rax
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%r13d
  test   %r13b,%r13b
  je     L35
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  call   <strlen@plt>
  add    $0x1,%r12
  sub    %rax,%r12
  lea    (%rbx,%r12,1),%rcx
  cmp    %rcx,%rbx
  jb     L26
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L41:
  add    $0x1,%rbx
  cmp    %rbx,%rcx
  je     L8
L26:
  cmp    (%rbx),%r13b
  jne    L41
  mov    %r13d,%edx
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L50:
  cmp    %dl,(%rbx,%rax,1)
  jne    L41
  add    $0x1,%rax
  movzbl 0x0(%rbp,%rax,1),%edx
  test   %dl,%dl
  jne    L50
  mov    %rbx,%rax
L35:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L8:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *strstr(const char *haystack, const char *needle) {
  const char *hend;
  const char *a, *b;
  if (*needle == 0)
    return (char *)haystack;
  hend = haystack + strlen(haystack) - strlen(needle) + 1;
  while (haystack < hend) {
    if (*haystack == *needle) {
      a = haystack;
      b = needle;
      for (;;) {
        if (*b == 0)
          return (char *)haystack;
        if (*a++ != *b++) {
          break;
        }
      }
    }
    haystack++;
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <check_ISBN_validity@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D2
datatype: string

tool: D2: %s

assistant: ```c
int main() {
  char ISBN[20];
  scanf("%s", ISBN);
  check_ISBN_validity(ISBN);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  mov    %rbx,%rdi
  call   <check_ISBN_validity@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D9
data_type: string

tool: D9: %s

assistant: ```c
int main() {
  char ISBN[20];
  scanf("%s", ISBN);
  check_ISBN_validity(ISBN);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D3(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <check_ISBN_validity@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D3
type_infered: string

tool: D3: %s

assistant: ```c
int main() {
  char ISBN[20];
  scanf("%s", ISBN);
  check_ISBN_validity(ISBN);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D2(%rip),%rdi
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  mov    %rbp,%rdi
  call   <check_ISBN_validity@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x20,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D2
data_type: string

tool: D2: %s

assistant: ```c
int main() {
  char ISBN[20];
  scanf("%s", ISBN);
  check_ISBN_validity(ISBN);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<parse_dpms_capabilities>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movzbl -0x4(%rbp),%eax
  test   %al,%al
  jns    L25
  lea    D7(%rip),%rcx
  jmp    L55
L25:
  lea    D13(%rip),%rcx
L55:
  movzbl -0x4(%rbp),%eax
  and    $0x40,%eax
  test   %eax,%eax
  je     L24
  lea    D7(%rip),%rdx
  jmp    L1
L24:
  lea    D13(%rip),%rdx
L1:
  movzbl -0x4(%rbp),%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L41
  lea    D7(%rip),%rax
  jmp    L14
L41:
  lea    D13(%rip),%rax
L14:
  mov    %rcx,%r8
  mov    %rdx,%rcx
  mov    %rax,%rdx
  lea    D32(%rip),%rax
  mov    %rax,%rsi
  lea    D59(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D7
type_guessed: string
name: read_data
arguments: data_label: D13
type_guessed: string
name: read_data
arguments: data_label: D32
type_guessed: string
name: read_data
arguments: data_label: D59
type_guessed: string

tool: D7: yes

tool: D13: no

tool: D32: parse_dpms_capabilities

tool: D59: [EDID] %s: # DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s



assistant: ```c
int parse_dpms_capabilities(unsigned char flags) {
  printf("[EDID] %s: "
         "# DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s\n\n",
         __FUNCTION__, (flags & (1 << 5)) ? "yes" : "no", (flags & (1 << 6)) ? "yes" : "no", (flags & (1 << 7)) ? "yes" : "no");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_dpms_capabilities>:
  endbr64
  sub    $0x8,%rsp
  test   %dil,%dil
  lea    D36(%rip),%r8
  lea    D1(%rip),%rax
  cmovns %rax,%r8
  test   $0x40,%dil
  lea    D36(%rip),%rcx
  cmove  %rax,%rcx
  test   $0x20,%dil
  lea    D36(%rip),%rdx
  cmove  %rax,%rdx
  lea    D52(%rip),%rsi
  lea    D17(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D36
type_guessed: string
name: read_data
arguments: tag: D1
type_guessed: string
name: read_data
arguments: tag: D52
type_guessed: string
name: read_data
arguments: tag: D17
type_guessed: string

tool: D36: yes

tool: D1: no

tool: D52: parse_dpms_capabilities

tool: D17: [EDID] %s: # DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s



assistant: ```c
int parse_dpms_capabilities(unsigned char flags) {
  printf("[EDID] %s: "
         "# DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s\n\n",
         __FUNCTION__, (flags & (1 << 5)) ? "yes" : "no", (flags & (1 << 6)) ? "yes" : "no", (flags & (1 << 7)) ? "yes" : "no");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<parse_dpms_capabilities>:
  endbr64
  lea    D25(%rip),%rax
  sub    $0x8,%rsp
  lea    D0(%rip),%rdx
  test   %dil,%dil
  mov    %rax,%r8
  mov    %rax,%rcx
  lea    D8(%rip),%rsi
  cmovs  %rdx,%r8
  test   $0x40,%dil
  cmovne %rdx,%rcx
  and    $0x20,%edi
  cmove  %rax,%rdx
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D25
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D0
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D8
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D11
type_guessed: string

tool: D25: no

tool: D0: yes

tool: D8: parse_dpms_capabilities

tool: D11: [EDID] %s: # DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s



assistant: ```c
int parse_dpms_capabilities(unsigned char flags) {
  printf("[EDID] %s: "
         "# DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s\n\n",
         __FUNCTION__, (flags & (1 << 5)) ? "yes" : "no", (flags & (1 << 6)) ? "yes" : "no", (flags & (1 << 7)) ? "yes" : "no");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<parse_dpms_capabilities>:
  endbr64
  lea    D11(%rip),%rax
  sub    $0x8,%rsp
  lea    D12(%rip),%rdx
  test   %dil,%dil
  mov    %rax,%r8
  mov    %rax,%rcx
  lea    D3(%rip),%rsi
  cmovs  %rdx,%r8
  test   $0x40,%dil
  cmovne %rdx,%rcx
  and    $0x20,%edi
  cmove  %rax,%rdx
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D11
data_type: string
name: retrieve_data
arguments: tag: D12
data_type: string
name: retrieve_data
arguments: tag: D3
data_type: string
name: retrieve_data
arguments: tag: D27
data_type: string

tool: D11: no

tool: D12: yes

tool: D3: parse_dpms_capabilities

tool: D27: [EDID] %s: # DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s



assistant: ```c
int parse_dpms_capabilities(unsigned char flags) {
  printf("[EDID] %s: "
         "# DPMS capabilities: Active off:%s  Suspend:%s  Standby:%s\n\n",
         __FUNCTION__, (flags & (1 << 5)) ? "yes" : "no", (flags & (1 << 6)) ? "yes" : "no", (flags & (1 << 7)) ? "yes" : "no");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<str_rcut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <str_endwith@plt>
  test   %rax,%rax
  je     L4
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,%rbx
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    %rax,%rbx
  mov    %rbx,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
L4:
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *str_rcut(char *haystack, const char *word) {
  if (str_endwith(haystack, word)) {
    haystack[strlen(haystack) - strlen(word)] = '\0';
  }
  return haystack;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<str_rcut>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  call   <str_endwith@plt>
  test   %rax,%rax
  je     L5
  mov    %rbx,%rdi
  call   <strlen@plt>
  mov    %rax,%r12
  mov    %rbp,%rdi
  call   <strlen@plt>
  sub    %rax,%r12
  movb   $0x0,(%rbx,%r12,1)
L5:
  mov    %rbx,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rcut(char *haystack, const char *word) {
  if (str_endwith(haystack, word)) {
    haystack[strlen(haystack) - strlen(word)] = '\0';
  }
  return haystack;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<str_rcut>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <str_endwith@plt>
  test   %rax,%rax
  je     L3
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  sub    %rax,%rbx
  movb   $0x0,(%r12,%rbx,1)
L3:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rcut(char *haystack, const char *word) {
  if (str_endwith(haystack, word)) {
    haystack[strlen(haystack) - strlen(word)] = '\0';
  }
  return haystack;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<str_rcut>:
  endbr64
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  call   <str_endwith@plt>
  test   %rax,%rax
  je     L1
  mov    %r12,%rdi
  call   <strlen@plt>
  mov    %rbp,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  sub    %rax,%rbx
  movb   $0x0,(%r12,%rbx,1)
L1:
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *str_rcut(char *haystack, const char *word) {
  if (str_endwith(haystack, word)) {
    haystack[strlen(haystack) - strlen(word)] = '\0';
  }
  return haystack;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    $0x0,%eax
  movsbl %al,%eax
  mov    %eax,-0xc(%rbp)
  cmpl   $0x1,-0xc(%rbp)
  je     L36
  movl   $0x1,-0xc(%rbp)
L36:
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L39
L10:
  cmpq   $0x0,-0x8(%rbp)
  je     L24
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L24:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x10(%rbp)
  addl   $0x1,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L39:
  cmpl   $0x9,-0x10(%rbp)
  jg     L10
  mov    -0x14(%rbp),%edx
  mov    -0x8(%rbp),%rax
  lea    D3(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D3: %d

assistant: ```c
char *itoa(int i) {
  char *a;
  int b = i;
  int c = ""[0];
  if (c != 1)
    c = 1;
  a = malloc(1);
  while (b > 9) {
    if (a != NULL)
      free(a);
    b /= 10;
    c += 1;
    a = malloc(c + 1);
  }
  sprintf(a, "%d", i);
  return a;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<itoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  mov    $0x1,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  cmp    $0x9,%r12d
  jle    L36
  mov    %r12d,%ebx
  mov    $0x3,%ebp
  jmp    L37
L24:
  movslq %ebx,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  mov    %ebx,%edx
  sar    $0x1f,%edx
  sub    %edx,%eax
  mov    %eax,%r13d
  mov    %ebp,%edi
  call   <malloc@plt>
  mov    %rax,%r14
  add    $0x1,%ebp
  cmp    $0x63,%ebx
  jle    L36
  mov    %r13d,%ebx
L37:
  test   %r14,%r14
  je     L24
  mov    %r14,%rdi
  call   <free@plt>
  jmp    L24
L36:
  mov    %r12d,%edx
  lea    D0(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %r14,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
data_type: string

tool: D0: %d

assistant: ```c
char *itoa(int i) {
  char *a;
  int b = i;
  int c = ""[0];
  if (c != 1)
    c = 1;
  a = malloc(1);
  while (b > 9) {
    if (a != NULL)
      free(a);
    b /= 10;
    c += 1;
    a = malloc(c + 1);
  }
  sprintf(a, "%d", i);
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<itoa>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %edi,%r12d
  mov    $0x1,%edi
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    $0x9,%r12d
  jle    L18
  mov    %r12d,%ebx
  mov    $0x3,%r14d
  mov    $0xcccccccd,%ebp
  jmp    L5
  cs nopw 0x0(%rax,%rax,1)
L2:
  mov    %r13d,%ebx
L5:
  test   %rdi,%rdi
  je     L36
  call   <free@plt>
L36:
  mov    %ebx,%eax
  mov    %r14d,%edi
  add    $0x1,%r14d
  imul   %rbp,%rax
  shr    $0x23,%rax
  mov    %rax,%r13
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    $0x63,%ebx
  jg     L2
L18:
  mov    %r12d,%edx
  lea    D7(%rip),%rsi
  mov    %rdi,0x8(%rsp)
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D7
type_infered: string

tool: D7: %d

assistant: ```c
char *itoa(int i) {
  char *a;
  int b = i;
  int c = ""[0];
  if (c != 1)
    c = 1;
  a = malloc(1);
  while (b > 9) {
    if (a != NULL)
      free(a);
    b /= 10;
    c += 1;
    a = malloc(c + 1);
  }
  sprintf(a, "%d", i);
  return a;
}
```
user: What is the c source code of the assembly code below:

```asm
<itoa>:
  endbr64
  push   %r14
  push   %r13
  mov    %edi,%r13d
  mov    $0x1,%edi
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  call   <malloc@plt>
  mov    %rax,%rdi
  cmp    $0x9,%r13d
  jle    L21
  mov    %r13d,%ebp
  mov    $0x3,%r14d
  mov    $0xcccccccd,%r12d
  jmp    L8
  nopw   0x0(%rax,%rax,1)
L30:
  mov    %ebx,%ebp
L8:
  test   %rdi,%rdi
  je     L28
  call   <free@plt>
L28:
  mov    %ebp,%ebx
  mov    %r14d,%edi
  add    $0x1,%r14d
  call   <malloc@plt>
  imul   %r12,%rbx
  mov    %rax,%rdi
  shr    $0x23,%rbx
  cmp    $0x63,%ebp
  jg     L30
L21:
  mov    %r13d,%edx
  lea    D9(%rip),%rsi
  mov    %rdi,0x8(%rsp)
  call   <sprintf@plt>
  mov    0x8(%rsp),%rax
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
datatype: string

tool: D9: %d

assistant: ```c
char *itoa(int i) {
  char *a;
  int b = i;
  int c = ""[0];
  if (c != 1)
    c = 1;
  a = malloc(1);
  while (b > 9) {
    if (a != NULL)
      free(a);
    b /= 10;
    c += 1;
    a = malloc(c + 1);
  }
  sprintf(a, "%d", i);
  return a;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0xa,-0x4(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_label: D6
data_type: string

tool: D6: I am %d years old


assistant: ```c
int main() {
  int age = 10;
  printf("I am %d years old\n", age);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D6
type: string

tool: D6: I am %d years old


assistant: ```c
int main() {
  int age = 10;
  printf("I am %d years old\n", age);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D0
type: string

tool: D0: I am %d years old


assistant: ```c
int main() {
  int age = 10;
  printf("I am %d years old\n", age);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0xa,%esi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
data_type: string

tool: D5: I am %d years old


assistant: ```c
int main() {
  int age = 10;
  printf("I am %d years old\n", age);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<partition>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    %r8d,-0x2c(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L24
L18:
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0xc(%rbp),%eax
  cltq
  add    %rax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0xc(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0xc(%rbp)
L24:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L18
  subl   $0x1,-0x20(%rbp)
  addl   $0x1,-0x2c(%rbp)
L32:
  addl   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   *%rdx
  test   %eax,%eax
  js     L32
L56:
  subl   $0x1,-0x2c(%rbp)
  mov    -0x2c(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x8(%rbp),%rax
  mov    -0x28(%rbp),%rdx
  mov    %rax,%rsi
  mov    %rcx,%rdi
  call   *%rdx
  test   %eax,%eax
  jg     L56
  mov    -0x20(%rbp),%eax
  cmp    -0x2c(%rbp),%eax
  jge    L29
  mov    -0x2c(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rsi
  mov    -0x20(%rbp),%eax
  imul   -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edx
  mov    %rcx,%rdi
  call   <swap@plt>
  jmp    L32
L29:
  mov    -0x2c(%rbp),%eax
  leave
  ret
```

assistant: ```c
int partition(void *base, int size, int (*compare)(const void *, const void *), int low, int high) {
  void *pivot = malloc(size);
  int i;
  for (i = 0; i < size; i++)
    *((char *)pivot + i) = *((char *)base + low * size + i);
  low--;
  high++;
  while (1) {
    do {
      low++;
    } while (compare(((char *)base) + low * size, pivot) < 0);
    do {
      high--;
    } while (compare(((char *)base) + high * size, pivot) > 0);
    if (low < high) {
      swap(((char *)base) + low * size, ((char *)base) + high * size, size);
    } else
      return high;
  }
  free(pivot);
}
```