user: 这段汇编代码用C语言表示是什么样的:

```asm
<print_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x48,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  lea    D84(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  movl   $0x74786554,-0x34(%rbp)
  movw   $0x31,-0x30(%rbp)
  movl   $0x74786554,-0x2e(%rbp)
  movw   $0x32,-0x2a(%rbp)
  lea    D113(%rip),%rax
  mov    %rax,-0x60(%rbp)
  mov    $0x6,%edi
  call   <malloc@plt>
  mov    %rax,-0x58(%rbp)
  mov    -0x58(%rbp),%rax
  lea    D42(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
  lea    D87(%rip),%rax
  mov    %rax,-0x50(%rbp)
  lea    D103(%rip),%rax
  mov    %rax,-0x48(%rbp)
  lea    D48(%rip),%rax
  mov    %rax,-0x40(%rbp)
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r13d
  mov    -0x60(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%r12d
  lea    -0x2e(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%ebx
  lea    -0x34(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %r13d,%r8d
  mov    %r12d,%ecx
  mov    %ebx,%edx
  mov    %eax,%esi
  lea    D80(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x34(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x2e(%rbp),%rax
  mov    %rax,%rsi
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D39(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rsi
  lea    D89(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x40(%rbp),%rcx
  mov    -0x48(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rax,%rsi
  lea    D90(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x58(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  nop
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  add    $0x48,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
```

tool_calls: name: unpack_data
arguments: label: D84
type_infered: string
name: unpack_data
arguments: label: D113
type_infered: string
name: unpack_data
arguments: label: D42
type_infered: string
name: unpack_data
arguments: label: D87
type_infered: string
name: unpack_data
arguments: label: D103
type_infered: string
name: unpack_data
arguments: label: D48
type_infered: string
name: unpack_data
arguments: label: D80
type_infered: string
name: unpack_data
arguments: label: D25
type_infered: string
name: unpack_data
arguments: label: D16
type_infered: string
name: unpack_data
arguments: label: D39
type_infered: string
name: unpack_data
arguments: label: D89
type_infered: string
name: unpack_data
arguments: label: D90
type_infered: string

tool: D84: Regular Chars

tool: D113: Text3

tool: D42: Text4

tool: D87: Test

tool: D103: Some

tool: D48: Strings

tool: D80: String c lengths %i %i %i %i


tool: D25: String c1 %s


tool: D16: String c2 %s


tool: D39: String c3 %s


tool: D89: String c4 %s


tool: D90: %s %s %s


assistant: ```c
void print_chars() {
  printf("Regular Chars\n");
  char c1[] = {'T', 'e', 'x', 't', '1', '\0'};
  char c2[] = "Text2";
  char *c3 = "Text3";
  char *c4 = (char *)malloc(6 * sizeof(char));
  strcpy(c4, "Text4");
  char *c5[] = {"Test", "Some", "Strings"};
  printf("String c lengths %i %i %i %i\n", strlen(c1), strlen(c2), strlen(c3), strlen(c4));
  printf("String c1 %s\n", c1);
  printf("String c2 %s\n", c2);
  printf("String c3 %s\n", c3);
  printf("String c4 %s\n", c4);
  printf("%s %s %s\n", c5[0], c5[1], c5[2]);
  free(c4);
}
```