ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<__bound_memset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    %rdx,-0x18(%rbp)
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <__bound_check@plt>
  mov    -0x18(%rbp),%rdx
  mov    -0xc(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  leave
  ret
```

assistant: ```c
void *__bound_memset(void *dst, int c, size_t size) {
  __bound_check(dst, size);
  return memset(dst, c, size);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__bound_memset>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%r12d
  mov    %rdx,%rbp
  mov    %rdx,%rsi
  call   <__bound_check@plt>
  mov    %rbp,%rdx
  mov    %r12d,%esi
  mov    %rbx,%rdi
  call   <memset@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
void *__bound_memset(void *dst, int c, size_t size) {
  __bound_check(dst, size);
  return memset(dst, c, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<__bound_memset>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <__bound_check@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <memset@plt>
```

assistant: ```c
void *__bound_memset(void *dst, int c, size_t size) {
  __bound_check(dst, size);
  return memset(dst, c, size);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__bound_memset>:
  endbr64
  push   %r13
  mov    %esi,%r13d
  mov    %rdx,%rsi
  push   %r12
  mov    %rdx,%r12
  push   %rbp
  mov    %rdi,%rbp
  call   <__bound_check@plt>
  mov    %r12,%rdx
  mov    %r13d,%esi
  mov    %rbp,%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <memset@plt>
```

assistant: ```c
void *__bound_memset(void *dst, int c, size_t size) {
  __bound_check(dst, size);
  return memset(dst, c, size);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<allocmat>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %edi,-0x34(%rbp)
  mov    %esi,-0x38(%rbp)
  mov    %edx,-0x3c(%rbp)
  mov    -0x34(%rbp),%eax
  cltq
  shl    $0x3,%eax
  add    $0x4,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x20(%rbp)
  cmpq   $0x0,-0x20(%rbp)
  jne    L13
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <fail@plt>
L13:
  mov    -0x20(%rbp),%rax
  mov    -0x34(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x20(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L27
L31:
  mov    -0x24(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rbx
  mov    -0x3c(%rbp),%edx
  mov    -0x38(%rbp),%eax
  mov    %edx,%esi
  mov    %eax,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  mov    (%rbx),%rax
  test   %rax,%rax
  jne    L35
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <fail@plt>
L35:
  addl   $0x1,-0x24(%rbp)
L27:
  mov    -0x24(%rbp),%eax
  cmp    -0x34(%rbp),%eax
  jl     L31
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D7
type_infered: string
name: parse_data
arguments: label: D11
type_infered: string

tool: D7: allocmat: malloc [] failed!

tool: D11: allocmat: malloc [][] failed!

assistant: ```c
void *allocmat(int rows, int columns, int size) {
  int i;
  void **p, *rp;
  rp = malloc(rows * sizeof(void *) + sizeof(int));
  if (rp == NULL)
    fail("allocmat: malloc [] failed!");
  *((int *)rp) = rows;
  p = rp + sizeof(int);
  for (i = 0; i < rows; i++)
    if ((p[i] = calloc(columns, size)) == NULL)
      fail("allocmat: malloc [][] failed!");
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<allocmat>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%r15d
  mov    %esi,%ebp
  mov    %edx,%r12d
  lea    0x4(,%rdi,8),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  test   %rax,%rax
  je     L3
L46:
  mov    %r15d,0x0(%r13)
  lea    0x4(%r13),%r14
  test   %r15d,%r15d
  jle    L19
  mov    %r14,%rbx
  lea    -0x1(%r15),%eax
  lea    0xc(%r13,%rax,8),%r13
  lea    D13(%rip),%r15
  jmp    L14
L3:
  lea    D10(%rip),%rdi
  call   <fail@plt>
  jmp    L46
L58:
  add    $0x8,%rbx
  cmp    %r13,%rbx
  je     L19
L14:
  mov    %r12d,%esi
  mov    %ebp,%edi
  call   <calloc@plt>
  mov    %rax,(%rbx)
  test   %rax,%rax
  jne    L58
  mov    %r15,%rdi
  call   <fail@plt>
  jmp    L58
L19:
  mov    %r14,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D13
type: string
name: disassemble_data
arguments: data_tag: D10
type: string

tool: D13: allocmat: malloc [][] failed!

tool: D10: allocmat: malloc [] failed!

assistant: ```c
void *allocmat(int rows, int columns, int size) {
  int i;
  void **p, *rp;
  rp = malloc(rows * sizeof(void *) + sizeof(int));
  if (rp == NULL)
    fail("allocmat: malloc [] failed!");
  *((int *)rp) = rows;
  p = rp + sizeof(int);
  for (i = 0; i < rows; i++)
    if ((p[i] = calloc(columns, size)) == NULL)
      fail("allocmat: malloc [][] failed!");
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<allocmat>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  lea    0x4(,%rdi,8),%edi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L55
L63:
  mov    %r14d,(%r12)
  lea    0x4(%r12),%r13
  test   %r14d,%r14d
  jle    L25
  lea    -0x1(%r14),%eax
  mov    %r13,%r15
  lea    D9(%rip),%r14
  lea    0xc(%r12,%rax,8),%r12
  jmp    L20
L19:
  add    $0x8,%r15
  cmp    %r12,%r15
  je     L25
L20:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,(%r15)
  test   %rax,%rax
  jne    L19
  mov    %r14,%rdi
  add    $0x8,%r15
  call   <fail@plt>
  cmp    %r12,%r15
  jne    L20
L25:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L55:
  lea    D12(%rip),%rdi
  call   <fail@plt>
  jmp    L63
```

tool_calls: name: read_data
arguments: data_label: D9
type: string
name: read_data
arguments: data_label: D12
type: string

tool: D9: allocmat: malloc [][] failed!

tool: D12: allocmat: malloc [] failed!

assistant: ```c
void *allocmat(int rows, int columns, int size) {
  int i;
  void **p, *rp;
  rp = malloc(rows * sizeof(void *) + sizeof(int));
  if (rp == NULL)
    fail("allocmat: malloc [] failed!");
  *((int *)rp) = rows;
  p = rp + sizeof(int);
  for (i = 0; i < rows; i++)
    if ((p[i] = calloc(columns, size)) == NULL)
      fail("allocmat: malloc [][] failed!");
  return p;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<allocmat>:
  endbr64
  push   %r15
  push   %r14
  mov    %edi,%r14d
  lea    0x4(,%rdi,8),%edi
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  call   <malloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L62
L39:
  mov    %r14d,(%r12)
  lea    0x4(%r12),%r13
  test   %r14d,%r14d
  jle    L7
  lea    -0x1(%r14),%eax
  mov    %r13,%r15
  lea    D15(%rip),%r14
  lea    0xc(%r12,%rax,8),%r12
  jmp    L38
L43:
  add    $0x8,%r15
  cmp    %r12,%r15
  je     L7
L38:
  mov    %ebp,%esi
  mov    %ebx,%edi
  call   <calloc@plt>
  mov    %rax,(%r15)
  test   %rax,%rax
  jne    L43
  mov    %r14,%rdi
  add    $0x8,%r15
  call   <fail@plt>
  cmp    %r12,%r15
  jne    L38
L7:
  add    $0x8,%rsp
  mov    %r13,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L62:
  lea    D11(%rip),%rdi
  call   <fail@plt>
  jmp    L39
```

tool_calls: name: disassemble_data
arguments: data_label: D15
type_guessed: string
name: disassemble_data
arguments: data_label: D11
type_guessed: string

tool: D15: allocmat: malloc [][] failed!

tool: D11: allocmat: malloc [] failed!

assistant: ```c
void *allocmat(int rows, int columns, int size) {
  int i;
  void **p, *rp;
  rp = malloc(rows * sizeof(void *) + sizeof(int));
  if (rp == NULL)
    fail("allocmat: malloc [] failed!");
  *((int *)rp) = rows;
  p = rp + sizeof(int);
  for (i = 0; i < rows; i++)
    if ((p[i] = calloc(columns, size)) == NULL)
      fail("allocmat: malloc [][] failed!");
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D45(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D14
type: string
name: disassemble_data
arguments: tag: D12
type: string
name: disassemble_data
arguments: tag: D45
type: string

tool: D14: %p


tool: D12: %d

tool: D45: d=%d


assistant: ```c
int main() {
  int d;
  char *p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
  scanf("%d", &d);
  printf("d=%d\n", d);
  p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,%rsi
  lea    D9(%rip),%rbx
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D5(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rax,%rsi
  mov    %rbx,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  mov    $0x0,%eax
  add    $0x10,%rsp
  pop    %rbx
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D9
datatype: string
name: extract_symbolic_data
arguments: data_label: D5
datatype: string
name: extract_symbolic_data
arguments: data_label: D3
datatype: string

tool: D9: %p


tool: D5: %d

tool: D3: d=%d


assistant: ```c
int main() {
  int d;
  char *p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
  scanf("%d", &d);
  printf("d=%d\n", d);
  p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  lea    D10(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D0(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D27(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
type: string
name: extract_symbolic_data
arguments: tag: D0
type: string
name: extract_symbolic_data
arguments: tag: D27
type: string

tool: D10: %p


tool: D0: %d

tool: D27: d=%d


assistant: ```c
int main() {
  int d;
  char *p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
  scanf("%d", &d);
  printf("d=%d\n", d);
  p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x4,%edi
  lea    D8(%rip),%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%esi
  lea    D21(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    $0x4,%edi
  call   <sbrk@plt>
  mov    %rbp,%rdi
  mov    %rax,%rsi
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
datatype: string
name: extract_symbolic_data
arguments: data_tag: D1
datatype: string
name: extract_symbolic_data
arguments: data_tag: D21
datatype: string

tool: D8: %p


tool: D1: %d

tool: D21: d=%d


assistant: ```c
int main() {
  int d;
  char *p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
  scanf("%d", &d);
  printf("d=%d\n", d);
  p = sbrk(4);
  printf("%p\n", p);
  p = sbrk(4);
  printf("%p\n", p);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<lmc_file_size>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xc(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  jne    L7
  mov    $0x0,%eax
  jmp    L6
L7:
  mov    -0xc(%rbp),%eax
L6:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L26
  call   <__stack_chk_fail@plt>
L26:
  leave
  ret
```

assistant: ```c
int lmc_file_size(const char *fn) {
  struct stat st;
  if (stat(fn, &st) == -1)
    return 0;
  return st.st_size;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<lmc_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lmc_file_size(const char *fn) {
  struct stat st;
  if (stat(fn, &st) == -1)
    return 0;
  return st.st_size;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<lmc_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lmc_file_size(const char *fn) {
  struct stat st;
  if (stat(fn, &st) == -1)
    return 0;
  return st.st_size;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<lmc_file_size>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rsi
  call   <stat@plt>
  cmp    $0xffffffff,%eax
  mov    $0x0,%eax
  cmovne 0x4(%rsp),%eax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x18,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int lmc_file_size(const char *fn) {
  struct stat st;
  if (stat(fn, &st) == -1)
    return 0;
  return st.st_size;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<phy_reset>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x8000,%esi
  mov    $0x0,%edi
  call   <phy_write@plt>
  nop
L5:
  mov    $0x0,%edi
  call   <phy_read@plt>
  and    $0x8000,%eax
  test   %eax,%eax
  jne    L5
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void phy_reset() {
  phy_write(0, 0x8000);
  while (phy_read(0) & 0x8000)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<phy_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8000,%esi
  mov    $0x0,%edi
  call   <phy_write@plt>
L5:
  mov    $0x0,%edi
  call   <phy_read@plt>
  test   $0x80,%ah
  jne    L5
  add    $0x8,%rsp
  ret
```

assistant: ```c
void phy_reset() {
  phy_write(0, 0x8000);
  while (phy_read(0) & 0x8000)
    ;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<phy_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8000,%esi
  xor    %edi,%edi
  call   <phy_write@plt>
  nopl   0x0(%rax)
L4:
  xor    %edi,%edi
  call   <phy_read@plt>
  test   $0x80,%ah
  jne    L4
  add    $0x8,%rsp
  ret
```

assistant: ```c
void phy_reset() {
  phy_write(0, 0x8000);
  while (phy_read(0) & 0x8000)
    ;
}
```
user: Translate the below assembly code into C programming language:

```asm
<phy_reset>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x8000,%esi
  xor    %edi,%edi
  call   <phy_write@plt>
  nopl   0x0(%rax)
L1:
  xor    %edi,%edi
  call   <phy_read@plt>
  test   $0x80,%ah
  jne    L1
  add    $0x8,%rsp
  ret
```

assistant: ```c
void phy_reset() {
  phy_write(0, 0x8000);
  while (phy_read(0) & 0x8000)
    ;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<colorize>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  lea    D21(%rip),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    $0x80,%edx
  mov    %rax,%rsi
  lea    D21(%rip),%rax
  mov    %rax,%rdi
  call   <strlcpy@plt>
  jmp    L3
L15:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movzbl (%rax),%edx
  add    $0xffffff80,%edx
  mov    %dl,(%rax)
L3:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L15
  lea    D21(%rip),%rax
  leave
  ret
```

assistant: ```c
char *colorize(char *str) {
  static char ret[128];
  char *c = ret;
  strlcpy(ret, str, sizeof(ret));
  while (*c)
    *c++ += 128;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<colorize>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  mov    $0x80,%edx
  lea    D18(%rip),%rdi
  call   <strlcpy@plt>
  movzbl D18(%rip),%eax
  test   %al,%al
  je     L13
  lea    D18(%rip),%rdx
L3:
  add    $0x1,%rdx
  add    $0xffffff80,%eax
  mov    %al,-0x1(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L3
L13:
  lea    D18(%rip),%rax
  add    $0x8,%rsp
  ret
```

assistant: ```c
char *colorize(char *str) {
  static char ret[128];
  char *c = ret;
  strlcpy(ret, str, sizeof(ret));
  while (*c)
    *c++ += 128;
  return ret;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<colorize>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  mov    %rdi,%rsi
  mov    $0x80,%edx
  mov    %r12,%rdi
  call   <strlcpy@plt>
  movzbl D5(%rip),%eax
  test   %al,%al
  je     L1
  mov    %r12,%rdx
  nopl   0x0(%rax,%rax,1)
L7:
  add    $0x1,%rdx
  add    $0xffffff80,%eax
  mov    %al,-0x1(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L7
L1:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *colorize(char *str) {
  static char ret[128];
  char *c = ret;
  strlcpy(ret, str, sizeof(ret));
  while (*c)
    *c++ += 128;
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<colorize>:
  endbr64
  push   %r12
  lea    D11(%rip),%r12
  mov    %rdi,%rsi
  mov    $0x80,%edx
  mov    %r12,%rdi
  call   <strlcpy@plt>
  movzbl D11(%rip),%eax
  test   %al,%al
  je     L4
  mov    %r12,%rdx
  nopl   0x0(%rax,%rax,1)
L8:
  add    $0x1,%rdx
  add    $0xffffff80,%eax
  mov    %al,-0x1(%rdx)
  movzbl (%rdx),%eax
  test   %al,%al
  jne    L8
L4:
  mov    %r12,%rax
  pop    %r12
  ret
```

assistant: ```c
char *colorize(char *str) {
  static char ret[128];
  char *c = ret;
  strlcpy(ret, str, sizeof(ret));
  while (*c)
    *c++ += 128;
  return ret;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x4(%rbp)
  jmp    L2
L19:
  call   <fork@plt>
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L2:
  cmpl   $0x1,-0x4(%rbp)
  jle    L19
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string

tool: D0: -


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 2; ++i) {
    fork();
    printf("-\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbx
  call   <fork@plt>
  lea    D8(%rip),%rbx
  mov    %rbx,%rdi
  call   <printf@plt>
  call   <fork@plt>
  mov    %rbx,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
datatype: string

tool: D8: -


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 2; ++i) {
    fork();
    printf("-\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  lea    D8(%rip),%rbp
  call   <fork@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  call   <fork@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D8
type: string

tool: D8: -


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 2; ++i) {
    fork();
    printf("-\n");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D7(%rip),%rbp
  call   <fork@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  call   <fork@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  xor    %eax,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: -


assistant: ```c
int main() {
  int i;
  for (i = 0; i < 2; ++i) {
    fork();
    printf("-\n");
  }
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<_str_free_mem>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L7
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
L7:
  nop
  leave
  ret
```

assistant: ```c
void _str_free_mem(void *ptr) {
  if (ptr != (void *)NULL) {
    free(ptr);
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_str_free_mem>:
  endbr64
  test   %rdi,%rdi
  je     L3
  sub    $0x8,%rsp
  call   <free@plt>
  add    $0x8,%rsp
  ret
L3:
  ret
```

assistant: ```c
void _str_free_mem(void *ptr) {
  if (ptr != (void *)NULL) {
    free(ptr);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_str_free_mem>:
  endbr64
  test   %rdi,%rdi
  je     L6
  jmp    1050 <free@plt>
  xchg   %ax,%ax
L6:
  ret
```

assistant: ```c
void _str_free_mem(void *ptr) {
  if (ptr != (void *)NULL) {
    free(ptr);
  }
}
```