ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<purge>:
  endbr64
  sub    $0x8,%rsp
  jmp    L16
  nopw   0x0(%rax,%rax,1)
L8:
  mov    D8(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L9
L16:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L8
L9:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void purge(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    ;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<purge>:
  endbr64
  sub    $0x8,%rsp
  jmp    L4
  nopw   0x0(%rax,%rax,1)
L7:
  mov    D3(%rip),%rdx
  cmp    %eax,(%rdx)
  je     L22
L4:
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0xa,%eax
  jne    L7
L22:
  add    $0x8,%rsp
  ret
```

assistant: ```c
void purge(void) {
  int c;
  while ((c = getchar()) != '\n' && c != EOF) {
    ;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x4,-0x50(%rbp)
  movl   $0xfffffffd,-0x4c(%rbp)
  movl   $0x6,-0x48(%rbp)
  movl   $0x8,-0x44(%rbp)
  movl   $0x2,-0x40(%rbp)
  movl   $0x7,-0x3c(%rbp)
  lea    -0x50(%rbp),%rax
  mov    $0x6,%esi
  mov    %rax,%rdi
  call   <test@plt>
  movl   $0x576,-0x30(%rbp)
  movl   $0xfffffffa,-0x2c(%rbp)
  movl   $0x18,-0x28(%rbp)
  movl   $0xffffffff,-0x24(%rbp)
  movl   $0xd,-0x20(%rbp)
  movl   $0x41,-0x1c(%rbp)
  movl   $0x18,-0x18(%rbp)
  movl   $0xfffffe16,-0x14(%rbp)
  movl   $0xfffff830,-0x10(%rbp)
  lea    -0x30(%rbp),%rax
  mov    $0x9,%esi
  mov    %rax,%rdi
  call   <test@plt>
  mov    D13(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x58(%rbp)
  mov    D2(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x54(%rbp)
  lea    -0x58(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <test@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
int main(void) {
  int a1[] = {4, -3, 6, 8, 2, 7};
  test(a1, (sizeof(a1) / sizeof(a1[0])));
  int a2[] = {1398, -6, 24, -1, 13, 65, 24, -490, -2000};
  test(a2, (sizeof(a2) / sizeof(a2[0])));
  int a3[] = {INT_MAX, INT_MIN};
  test(a3, (sizeof(a3) / sizeof(a3[0])));
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movl   $0x4,0x10(%rsp)
  movl   $0xfffffffd,0x14(%rsp)
  movl   $0x6,0x18(%rsp)
  movl   $0x8,0x1c(%rsp)
  movl   $0x2,0x20(%rsp)
  movl   $0x7,0x24(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x6,%esi
  call   <test@plt>
  movl   $0x576,0x30(%rsp)
  movl   $0xfffffffa,0x34(%rsp)
  movl   $0x18,0x38(%rsp)
  movl   $0xffffffff,0x3c(%rsp)
  movl   $0xd,0x40(%rsp)
  movl   $0x41,0x44(%rsp)
  movl   $0x18,0x48(%rsp)
  movl   $0xfffffe16,0x4c(%rsp)
  movl   $0xfffff830,0x50(%rsp)
  lea    0x30(%rsp),%rdi
  mov    $0x9,%esi
  call   <test@plt>
  mov    D17(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  mov    D7(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  lea    0x8(%rsp),%rdi
  mov    $0x2,%esi
  call   <test@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x68,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a1[] = {4, -3, 6, 8, 2, 7};
  test(a1, (sizeof(a1) / sizeof(a1[0])));
  int a2[] = {1398, -6, 24, -1, 13, 65, 24, -490, -2000};
  test(a2, (sizeof(a2) / sizeof(a2[0])));
  int a3[] = {INT_MAX, INT_MIN};
  test(a3, (sizeof(a3) / sizeof(a3[0])));
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x68,%rsp
  mov    $0x6,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  movabs $0xfffffffd00000004,%rax
  lea    0x10(%rsp),%rdi
  mov    %rax,0x10(%rsp)
  movabs $0x800000006,%rax
  mov    %rax,0x18(%rsp)
  movabs $0x700000002,%rax
  mov    %rax,0x20(%rsp)
  call   <test@plt>
  lea    0x30(%rsp),%rdi
  movabs $0xfffffffa00000576,%rax
  mov    $0x9,%esi
  mov    %rax,0x30(%rsp)
  movabs $0xffffffff00000018,%rax
  mov    %rax,0x38(%rsp)
  movabs $0x410000000d,%rax
  mov    %rax,0x40(%rsp)
  movabs $0xfffffe1600000018,%rax
  mov    %rax,0x48(%rsp)
  movl   $0xfffff830,0x50(%rsp)
  call   <test@plt>
  lea    0x8(%rsp),%rdi
  mov    $0x2,%esi
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0x8(%rsp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  call   <test@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x68,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  int a1[] = {4, -3, 6, 8, 2, 7};
  test(a1, (sizeof(a1) / sizeof(a1[0])));
  int a2[] = {1398, -6, 24, -1, 13, 65, 24, -490, -2000};
  test(a2, (sizeof(a2) / sizeof(a2[0])));
  int a3[] = {INT_MAX, INT_MIN};
  test(a3, (sizeof(a3) / sizeof(a3[0])));
}
```
user: Translate the below assembly code into C programming language:

```asm
<tmr_set_prescaler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  shl    $0x3,%eax
  mov    %eax,-0x4(%rbp)
  andl   $0xff,-0x18(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  js     L16
  cmpl   $0x3,-0x14(%rbp)
  jle    L2
L16:
  mov    $0xffffffff,%eax
  jmp    L17
L2:
  mov    $0x1d50000,%eax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%eax
  mov    $0xff,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  not    %eax
  mov    $0x1d50000,%edx
  and    %esi,%eax
  mov    %eax,(%rdx)
  mov    $0x1d50000,%eax
  mov    (%rax),%esi
  mov    -0x4(%rbp),%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  mov    $0x1d50000,%edx
  or     %esi,%eax
  mov    %eax,(%rdx)
  mov    $0x0,%eax
L17:
  pop    %rbp
  ret
```

assistant: ```c
int tmr_set_prescaler(int p, int value) {
  int offset = p * 8;
  value &= 0xFF;
  if (p < 0 || p > 3)
    return -1;
  (*(volatile unsigned *)0x1d50000) &= ~(0xFF << offset);
  (*(volatile unsigned *)0x1d50000) |= (value << offset);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tmr_set_prescaler>:
  endbr64
  lea    0x0(,%rdi,8),%ecx
  movzbl %sil,%esi
  cmp    $0x3,%edi
  ja     L5
  mov    0x1d50000,%edx
  mov    $0xff,%eax
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,0x1d50000
  mov    0x1d50000,%eax
  shl    %cl,%esi
  or     %eax,%esi
  mov    %esi,0x1d50000
  mov    $0x0,%eax
  ret
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int tmr_set_prescaler(int p, int value) {
  int offset = p * 8;
  value &= 0xFF;
  if (p < 0 || p > 3)
    return -1;
  (*(volatile unsigned *)0x1d50000) &= ~(0xFF << offset);
  (*(volatile unsigned *)0x1d50000) |= (value << offset);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<tmr_set_prescaler>:
  endbr64
  lea    0x0(,%rdi,8),%ecx
  movzbl %sil,%esi
  cmp    $0x3,%edi
  ja     L5
  mov    $0xff,%eax
  mov    0x1d50000,%edx
  shl    %cl,%esi
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,0x1d50000
  mov    0x1d50000,%eax
  or     %eax,%esi
  xor    %eax,%eax
  mov    %esi,0x1d50000
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int tmr_set_prescaler(int p, int value) {
  int offset = p * 8;
  value &= 0xFF;
  if (p < 0 || p > 3)
    return -1;
  (*(volatile unsigned *)0x1d50000) &= ~(0xFF << offset);
  (*(volatile unsigned *)0x1d50000) |= (value << offset);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<tmr_set_prescaler>:
  endbr64
  lea    0x0(,%rdi,8),%ecx
  movzbl %sil,%esi
  cmp    $0x3,%edi
  ja     L5
  mov    $0xff,%eax
  mov    0x1d50000,%edx
  shl    %cl,%esi
  shl    %cl,%eax
  not    %eax
  and    %edx,%eax
  mov    %eax,0x1d50000
  mov    0x1d50000,%eax
  or     %eax,%esi
  xor    %eax,%eax
  mov    %esi,0x1d50000
  ret
  nopw   0x0(%rax,%rax,1)
L5:
  mov    $0xffffffff,%eax
  ret
```

assistant: ```c
int tmr_set_prescaler(int p, int value) {
  int offset = p * 8;
  value &= 0xFF;
  if (p < 0 || p > 3)
    return -1;
  (*(volatile unsigned *)0x1d50000) &= ~(0xFF << offset);
  (*(volatile unsigned *)0x1d50000) |= (value << offset);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<RandomFunc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  sub    $0x4d,%eax
  mov    %al,-0x9(%rbp)
  movb   $0x0,-0xa(%rbp)
  jmp    L38
L47:
  movzbl -0x9(%rbp),%eax
  add    %eax,%eax
  mov    %al,-0x9(%rbp)
  movzbl -0x9(%rbp),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L38:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L47
  movb   $0x0,-0xa(%rbp)
  jmp    L19
L8:
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %edx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0x9(%rbp),%ecx
  movzbl -0xa(%rbp),%eax
  cltq
  movzbl -0x9(%rbp,%rax,1),%edx
  movzbl -0xa(%rbp),%eax
  add    %ecx,%edx
  cltq
  mov    %dl,-0x9(%rbp,%rax,1)
  movzbl -0xa(%rbp),%eax
  add    $0x1,%eax
  mov    %al,-0xa(%rbp)
L19:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  cmp    %al,-0xa(%rbp)
  jb     L8
  movzbl -0x9(%rbp),%eax
  lea    -0x12(%rax),%edx
  mov    -0x20(%rbp),%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L43
  call   <__stack_chk_fail@plt>
L43:
  leave
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] += state[0UL];
      state[local1] = state[0UL] + state[0UL];
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      state[local1] = state[0UL] + state[local1];
      local1++;
    }
    output[0UL] = state[0UL] - 681723154UL;
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  sub    $0x4d,%eax
  movzbl 0x1(%rdi),%ecx
  test   %cl,%cl
  je     L29
  mov    $0x0,%edx
L14:
  shl    $0x2,%eax
  add    $0x1,%edx
  cmp    %cl,%dl
  jne    L14
  mov    $0x0,%edx
L0:
  shl    $0x2,%eax
  add    $0x1,%edx
  cmp    %cl,%dl
  jne    L0
L29:
  sub    $0x12,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] += state[0UL];
      state[local1] = state[0UL] + state[0UL];
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      state[local1] = state[0UL] + state[local1];
      local1++;
    }
    output[0UL] = state[0UL] - 681723154UL;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<RandomFunc>:
  endbr64
  movzbl (%rdi),%eax
  movzbl 0x1(%rdi),%ecx
  sub    $0x4d,%eax
  test   %cl,%cl
  je     L25
  xor    %edx,%edx
  nopl   0x0(%rax)
L27:
  add    $0x1,%edx
  shl    $0x2,%eax
  cmp    %cl,%dl
  jne    L27
  xor    %edx,%edx
  nopl   0x0(%rax)
L19:
  add    $0x1,%edx
  shl    $0x2,%eax
  cmp    %cl,%dl
  jne    L19
L25:
  sub    $0x12,%eax
  mov    %al,(%rsi)
  ret
```

assistant: ```c
void RandomFunc(unsigned char input[1], unsigned char output[1]) {
  unsigned char state[1];
  unsigned char local1;
  {
    state[0UL] = (input[0UL] + 914778474UL) - (unsigned char)183;
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[0UL] += state[0UL];
      state[local1] = state[0UL] + state[0UL];
      local1++;
    }
    local1 = 0UL;
    while (local1 < input[1UL]) {
      state[local1] += state[local1];
      state[local1] = state[0UL] + state[local1];
      local1++;
    }
    output[0UL] = state[0UL] - 681723154UL;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<BKDRHash>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x83,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L14:
  mov    -0xc(%rbp),%eax
  imul   -0x4(%rbp),%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addq   $0x1,-0x18(%rbp)
  addl   $0x1,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L14
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int BKDRHash(const char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<BKDRHash>:
  endbr64
  test   %esi,%esi
  je     L13
  mov    %esi,%eax
  lea    (%rdi,%rax,1),%rcx
  mov    $0x0,%eax
L5:
  imul   $0x83,%eax,%eax
  movsbl (%rdi),%edx
  add    %edx,%eax
  add    $0x1,%rdi
  cmp    %rcx,%rdi
  jne    L5
  ret
L13:
  mov    %esi,%eax
  ret
```

assistant: ```c
unsigned int BKDRHash(const char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<BKDRHash>:
  endbr64
  test   %esi,%esi
  je     L9
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L15:
  imul   $0x83,%eax,%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L15
  ret
  nopl   (%rax)
L9:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int BKDRHash(const char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: What is the c source code of the assembly code below:

```asm
<BKDRHash>:
  endbr64
  test   %esi,%esi
  je     L5
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%rcx
L9:
  imul   $0x83,%eax,%eax
  movsbl (%rdi),%edx
  add    $0x1,%rdi
  add    %edx,%eax
  cmp    %rdi,%rcx
  jne    L9
  ret
  nopl   (%rax)
L5:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned int BKDRHash(const char *str, unsigned int len) {
  unsigned int seed = 131;
  unsigned int hash = 0;
  unsigned int i = 0;
  for (i = 0; i < len; str++, i++) {
    hash = (hash * seed) + (*str);
  }
  return hash;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<xmms_strlist_copy>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <xmms_strlist_len@plt>
  add    $0x1,%eax
  cltq
  shl    $0x3,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L14
L13:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,8),%rcx
  mov    -0x18(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    %rax,%rdi
  call   <strdup@plt>
  mov    %rax,(%rbx)
  addl   $0x1,-0x1c(%rbp)
L14:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jne    L13
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char **xmms_strlist_copy(char **strlist) {
  char **ret;
  int i;
  ret = malloc((xmms_strlist_len(strlist) + 1) * sizeof(char *));
  for (i = 0; strlist[i] != NULL; i++) {
    ret[i] = strdup(strlist[i]);
  }
  ret[i] = NULL;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmms_strlist_copy>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <xmms_strlist_len@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  mov    (%r12),%rdi
  test   %rdi,%rdi
  je     L26
  mov    $0x0,%ebx
L22:
  call   <strdup@plt>
  mov    %rax,0x0(%rbp,%rbx,1)
  add    $0x8,%rbx
  mov    (%r12,%rbx,1),%rdi
  test   %rdi,%rdi
  jne    L22
L9:
  movq   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  mov    $0x0,%ebx
  jmp    L9
```

assistant: ```c
char **xmms_strlist_copy(char **strlist) {
  char **ret;
  int i;
  ret = malloc((xmms_strlist_len(strlist) + 1) * sizeof(char *));
  for (i = 0; strlist[i] != NULL; i++) {
    ret[i] = strdup(strlist[i]);
  }
  ret[i] = NULL;
  return ret;
}
```
user: What is the c source code of the assembly code below:

```asm
<xmms_strlist_copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <xmms_strlist_len@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdi
  mov    %rax,%r12
  test   %rdi,%rdi
  je     L10
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L0:
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,1)
  add    $0x8,%rbx
  mov    0x0(%rbp,%rbx,1),%rdi
  test   %rdi,%rdi
  jne    L0
  add    %r12,%rbx
  mov    %r12,%rax
  movq   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L10:
  mov    %rax,%rbx
  mov    %r12,%rax
  movq   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **xmms_strlist_copy(char **strlist) {
  char **ret;
  int i;
  ret = malloc((xmms_strlist_len(strlist) + 1) * sizeof(char *));
  for (i = 0; strlist[i] != NULL; i++) {
    ret[i] = strdup(strlist[i]);
  }
  ret[i] = NULL;
  return ret;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<xmms_strlist_copy>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <xmms_strlist_len@plt>
  lea    0x8(,%rax,8),%edi
  call   <malloc@plt>
  mov    0x0(%rbp),%rdi
  mov    %rax,%r12
  test   %rdi,%rdi
  je     L9
  xor    %ebx,%ebx
  nopw   0x0(%rax,%rax,1)
L7:
  call   <strdup@plt>
  mov    %rax,(%r12,%rbx,1)
  add    $0x8,%rbx
  mov    0x0(%rbp,%rbx,1),%rdi
  test   %rdi,%rdi
  jne    L7
  add    %r12,%rbx
  mov    %r12,%rax
  movq   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L9:
  mov    %rax,%rbx
  mov    %r12,%rax
  movq   $0x0,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **xmms_strlist_copy(char **strlist) {
  char **ret;
  int i;
  ret = malloc((xmms_strlist_len(strlist) + 1) * sizeof(char *));
  for (i = 0; strlist[i] != NULL; i++) {
    ret[i] = strdup(strlist[i]);
  }
  ret[i] = NULL;
  return ret;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x616e65646163,%rax
  mov    %rax,-0x1e(%rbp)
  movw   $0x0,-0x16(%rbp)
  movb   $0x0,-0x14(%rbp)
  movl   $0x0,-0x24(%rbp)
  jmp    L26
L2:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x1e(%rbp,%rax,1),%edx
  mov    -0x24(%rbp),%eax
  cltq
  mov    %dl,-0x13(%rbp,%rax,1)
  addl   $0x1,-0x24(%rbp)
L26:
  mov    -0x24(%rbp),%eax
  cltq
  movzbl -0x1e(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L2
  mov    -0x24(%rbp),%eax
  cltq
  movb   $0x0,-0x13(%rbp,%rax,1)
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L27
  call   <__stack_chk_fail@plt>
L27:
  leave
  ret
```

assistant: ```c
int main(void) {
  char original[10 + 1] = "cadena";
  char copia[10 + 1];
  int i;
  for (i = 0; original[i] != '\0'; i++) {
    copia[i] = original[i];
  }
  copia[i] = '\0';
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x616e65646163,%rax
  mov    %rax,0xd(%rsp)
  movw   $0x0,0x15(%rsp)
  movb   $0x0,0x17(%rsp)
  test   %al,%al
  je     L17
  lea    0xe(%rsp),%rax
L7:
  add    $0x1,%rax
  cmpb   $0x0,-0x1(%rax)
  jne    L7
L17:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main(void) {
  char original[10 + 1] = "cadena";
  char copia[10 + 1];
  int i;
  for (i = 0; original[i] != '\0'; i++) {
    copia[i] = original[i];
  }
  copia[i] = '\0';
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char original[10 + 1] = "cadena";
  char copia[10 + 1];
  int i;
  for (i = 0; original[i] != '\0'; i++) {
    copia[i] = original[i];
  }
  copia[i] = '\0';
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  xor    %eax,%eax
  ret
```

assistant: ```c
int main(void) {
  char original[10 + 1] = "cadena";
  char copia[10 + 1];
  int i;
  for (i = 0; original[i] != '\0'; i++) {
    copia[i] = original[i];
  }
  copia[i] = '\0';
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<lcd_showvalue>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movb   $0x0,-0x3(%rbp)
  movb   $0x0,-0x2(%rbp)
  movb   $0x0,-0x1(%rbp)
  movzbl -0x14(%rbp),%eax
  mov    $0x29,%edx
  mul    %dl
  shr    $0x8,%ax
  shr    $0x4,%al
  mov    %al,-0x3(%rbp)
  movzbl -0x14(%rbp),%edx
  movzbl -0x3(%rbp),%eax
  imul   $0xffffff9c,%eax,%eax
  add    %edx,%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x3(%rbp),%eax
  mov    $0xffffff9c,%edx
  imul   %edx,%eax
  mov    %eax,%edx
  movzbl -0x2(%rbp),%eax
  mov    $0xfffffff6,%ecx
  imul   %ecx,%eax
  add    %eax,%edx
  movzbl -0x14(%rbp),%eax
  add    %edx,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x3(%rbp),%eax
  add    $0x30,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <lcd_char@plt>
  movzbl -0x2(%rbp),%eax
  add    $0x30,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <lcd_char@plt>
  movzbl -0x1(%rbp),%eax
  add    $0x30,%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <lcd_char@plt>
  nop
  leave
  ret
```

assistant: ```c
void lcd_showvalue(unsigned char num) {
  unsigned char H = 0, T = 0, O = 0;
  H = num / 100;
  T = (num - (H * 100)) / 10;
  O = (num - (H * 100) - (T * 10));
  lcd_char(H + 48);
  lcd_char(T + 48);
  lcd_char(O + 48);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<lcd_showvalue>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ecx
  mov    $0x29,%edi
  mov    %edi,%eax
  mul    %cl
  mov    %eax,%edi
  shr    $0xc,%di
  movzbl %dil,%edx
  imul   $0xffffff9c,%edx,%edx
  movzbl %cl,%eax
  add    %eax,%edx
  movslq %edx,%rbx
  imul   $0x66666667,%rbx,%rbx
  sar    $0x22,%rbx
  sar    $0x1f,%edx
  sub    %edx,%ebx
  mov    $0xffffff9c,%ebp
  mov    %ebp,%eax
  imul   %edi,%eax
  mov    %eax,%ebp
  lea    0x30(%rbp,%rcx,1),%ebp
  add    $0x30,%edi
  movzbl %dil,%edi
  call   <lcd_char@plt>
  lea    0x30(%rbx),%edi
  movzbl %dil,%edi
  call   <lcd_char@plt>
  mov    $0xfffffff6,%edi
  mov    %edi,%eax
  imul   %ebx,%eax
  mov    %eax,%edi
  add    %ebp,%edi
  movzbl %dil,%edi
  call   <lcd_char@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void lcd_showvalue(unsigned char num) {
  unsigned char H = 0, T = 0, O = 0;
  H = num / 100;
  T = (num - (H * 100)) / 10;
  O = (num - (H * 100) - (T * 10));
  lcd_char(H + 48);
  lcd_char(T + 48);
  lcd_char(O + 48);
}
```