ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<solcon_quaddobl_multi_affinization>:
  endbr64
  sub    $0x28,%rsp
  xor    %r8d,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rcx
  mov    %edi,0x10(%rsp)
  mov    $0x393,%edi
  mov    %esi,0x14(%rsp)
  lea    0x10(%rsp),%rsi
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_quaddobl_multi_affinization(int n, int m, int *z) {
  int fail;
  int pars[2];
  double c;
  pars[0] = n;
  pars[1] = m;
  fail = _ada_use_c2phc4c(915, pars, z, &c, 0);
  return fail;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<solcon_quaddobl_multi_affinization>:
  endbr64
  sub    $0x28,%rsp
  movd   %edi,%xmm0
  movd   %esi,%xmm1
  xor    %r8d,%r8d
  punpckldq %xmm1,%xmm0
  lea    0x8(%rsp),%rcx
  lea    0x10(%rsp),%rsi
  mov    $0x393,%edi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movq   %xmm0,0x10(%rsp)
  call   <_ada_use_c2phc4c@plt>
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int solcon_quaddobl_multi_affinization(int n, int m, int *z) {
  int fail;
  int pars[2];
  double c;
  pars[0] = n;
  pars[1] = m;
  fail = _ada_use_c2phc4c(915, pars, z, &c, 0);
  return fail;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<_dgr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %ecx,-0x20(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jns    L81
  cmpl   $0x0,-0x1c(%rbp)
  js     L81
  mov    $0x0,%eax
  jmp    L68
L81:
  cmpl   $0x0,-0x14(%rbp)
  js     L49
  cmpl   $0x0,-0x1c(%rbp)
  jns    L49
  mov    $0x1,%eax
  jmp    L68
L49:
  cmpl   $0x0,-0x14(%rbp)
  jns    L16
  mov    -0x14(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  and    $0x7fffffff,%eax
  mov    %eax,-0x1c(%rbp)
  mov    -0x18(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  mov    %eax,-0x18(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L16:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jge    L116
  mov    $0x0,%eax
  jmp    L68
L116:
  mov    -0x14(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L140
  mov    $0x1,%eax
  jmp    L68
L140:
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jae    L108
  mov    $0x0,%eax
  jmp    L68
L108:
  mov    -0x18(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jbe    L14
  mov    $0x1,%eax
  jmp    L68
L14:
  mov    $0x0,%eax
L68:
  pop    %rbp
  ret
```

assistant: ```c
int _dgr(int bh, unsigned int bl, int ch, unsigned int cl) {
  if (bh < 0 && ch >= 0)
    return 0;
  else if (bh >= 0 && ch < 0)
    return 1;
  else if (bh < 0) {
    int temp = bh;
    bh = ch & 0x7fffffff;
    ch = temp & 0x7fffffff;
    temp = bl;
    bl = cl;
    cl = temp;
  }
  if (bh < ch)
    return 0;
  else if (bh > ch)
    return 1;
  else if (bl < cl)
    return 0;
  else if (bl > cl)
    return 1;
  else
    return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<_dgr>:
  endbr64
  mov    %edx,%r8d
  not    %r8d
  mov    $0x0,%eax
  test   %r8d,%edi
  js     L7
  mov    $0x1,%eax
  or     %edi,%r8d
  jns    L7
  test   %edi,%edi
  js     L50
L59:
  mov    $0x0,%eax
  cmp    %edx,%edi
  jl     L7
  mov    $0x1,%eax
  jg     L7
  cmp    %ecx,%esi
  seta   %al
  movzbl %al,%eax
L7:
  ret
L50:
  mov    %edx,%eax
  and    $0x7fffffff,%eax
  mov    %edi,%edx
  and    $0x7fffffff,%edx
  mov    %esi,%edi
  mov    %ecx,%esi
  mov    %edi,%ecx
  mov    %eax,%edi
  jmp    L59
```

assistant: ```c
int _dgr(int bh, unsigned int bl, int ch, unsigned int cl) {
  if (bh < 0 && ch >= 0)
    return 0;
  else if (bh >= 0 && ch < 0)
    return 1;
  else if (bh < 0) {
    int temp = bh;
    bh = ch & 0x7fffffff;
    ch = temp & 0x7fffffff;
    temp = bl;
    bl = cl;
    cl = temp;
  }
  if (bh < ch)
    return 0;
  else if (bh > ch)
    return 1;
  else if (bl < cl)
    return 0;
  else if (bl > cl)
    return 1;
  else
    return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<_dgr>:
  endbr64
  mov    %edx,%r8d
  xor    %eax,%eax
  not    %r8d
  test   %r8d,%edi
  js     L44
  or     %edi,%r8d
  mov    $0x1,%eax
  jns    L44
  test   %edi,%edi
  jns    L8
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %esi,%edi
  mov    %ecx,%esi
  and    $0x7fffffff,%eax
  mov    %edi,%ecx
  and    $0x7fffffff,%edx
  mov    %eax,%edi
L8:
  xor    %eax,%eax
  cmp    %edx,%edi
  jl     L44
  mov    $0x1,%eax
  jg     L44
  xor    %eax,%eax
  cmp    %ecx,%esi
  seta   %al
L44:
  ret
```

assistant: ```c
int _dgr(int bh, unsigned int bl, int ch, unsigned int cl) {
  if (bh < 0 && ch >= 0)
    return 0;
  else if (bh >= 0 && ch < 0)
    return 1;
  else if (bh < 0) {
    int temp = bh;
    bh = ch & 0x7fffffff;
    ch = temp & 0x7fffffff;
    temp = bl;
    bl = cl;
    cl = temp;
  }
  if (bh < ch)
    return 0;
  else if (bh > ch)
    return 1;
  else if (bl < cl)
    return 0;
  else if (bl > cl)
    return 1;
  else
    return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<_dgr>:
  endbr64
  mov    %edx,%r8d
  xor    %eax,%eax
  not    %r8d
  test   %r8d,%edi
  js     L11
  or     %edi,%r8d
  mov    $0x1,%eax
  jns    L11
  test   %edi,%edi
  jns    L19
  mov    %edx,%eax
  mov    %edi,%edx
  mov    %esi,%edi
  mov    %ecx,%esi
  and    $0x7fffffff,%eax
  mov    %edi,%ecx
  and    $0x7fffffff,%edx
  mov    %eax,%edi
L19:
  xor    %eax,%eax
  cmp    %edx,%edi
  jl     L11
  mov    $0x1,%eax
  jg     L11
  xor    %eax,%eax
  cmp    %ecx,%esi
  seta   %al
L11:
  ret
```

assistant: ```c
int _dgr(int bh, unsigned int bl, int ch, unsigned int cl) {
  if (bh < 0 && ch >= 0)
    return 0;
  else if (bh >= 0 && ch < 0)
    return 1;
  else if (bh < 0) {
    int temp = bh;
    bh = ch & 0x7fffffff;
    ch = temp & 0x7fffffff;
    temp = bl;
    bl = cl;
    cl = temp;
  }
  if (bh < ch)
    return 0;
  else if (bh > ch)
    return 1;
  else if (bl < cl)
    return 0;
  else if (bl > cl)
    return 1;
  else
    return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<workout_bytes_per_sample>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movl   $0x1,-0x4(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L40
  addl   $0x2,-0x4(%rbp)
L40:
  movzbl -0x14(%rbp),%eax
  and    $0x30,%eax
  test   %eax,%eax
  je     L19
  movzbl -0x14(%rbp),%eax
  and    $0x2,%eax
  test   %eax,%eax
  je     L48
  subl   $0x1,-0x4(%rbp)
L48:
  addl   $0x2,-0x4(%rbp)
  movzbl -0x14(%rbp),%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L15
  addl   $0x4,-0x4(%rbp)
L15:
  movzbl -0x14(%rbp),%eax
  and    $0x4,%eax
  test   %eax,%eax
  je     L19
  addl   $0x1,-0x4(%rbp)
L19:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int workout_bytes_per_sample(unsigned char bt) {
  int recsiz = 1;
  if ((((bt)&2) != 0))
    recsiz += 2;
  if ((((bt) & (16 | 32)) != 0)) {
    if ((((bt)&2) != 0))
      recsiz -= 1;
    recsiz += 2;
    if ((((bt)&8) != 0))
      recsiz += 4;
    if ((((bt)&4) != 0))
      recsiz += 1;
  }
  return recsiz;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<workout_bytes_per_sample>:
  endbr64
  test   $0x2,%dil
  jne    L33
  test   $0x30,%dil
  jne    L5
  mov    $0x1,%eax
  ret
L5:
  mov    $0x1,%eax
  jmp    L22
L16:
  mov    $0x2,%eax
L22:
  lea    0x2(%rax),%edx
  add    $0x6,%eax
  test   $0x8,%dil
  cmove  %edx,%eax
  and    $0x4,%edi
  cmp    $0x1,%dil
  sbb    $0xffffffff,%eax
  ret
L33:
  test   $0x30,%dil
  jne    L16
  mov    $0x3,%eax
  ret
```

assistant: ```c
int workout_bytes_per_sample(unsigned char bt) {
  int recsiz = 1;
  if ((((bt)&2) != 0))
    recsiz += 2;
  if ((((bt) & (16 | 32)) != 0)) {
    if ((((bt)&2) != 0))
      recsiz -= 1;
    recsiz += 2;
    if ((((bt)&8) != 0))
      recsiz += 4;
    if ((((bt)&4) != 0))
      recsiz += 1;
  }
  return recsiz;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<workout_bytes_per_sample>:
  endbr64
  mov    %edi,%eax
  and    $0x30,%eax
  test   $0x2,%dil
  je     L28
  test   %al,%al
  je     L4
  mov    $0x4,%eax
  mov    $0x2,%edx
  jmp    L27
  nop
L28:
  test   %al,%al
  je     L16
  mov    $0x3,%eax
  mov    $0x1,%edx
L27:
  add    $0x6,%edx
  test   $0x8,%dil
  cmovne %edx,%eax
  and    $0x4,%edi
  cmp    $0x1,%dil
  sbb    $0xffffffff,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  mov    $0x1,%eax
  ret
  xchg   %ax,%ax
L4:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int workout_bytes_per_sample(unsigned char bt) {
  int recsiz = 1;
  if ((((bt)&2) != 0))
    recsiz += 2;
  if ((((bt) & (16 | 32)) != 0)) {
    if ((((bt)&2) != 0))
      recsiz -= 1;
    recsiz += 2;
    if ((((bt)&8) != 0))
      recsiz += 4;
    if ((((bt)&4) != 0))
      recsiz += 1;
  }
  return recsiz;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<workout_bytes_per_sample>:
  endbr64
  mov    %edi,%eax
  and    $0x30,%eax
  test   $0x2,%dil
  je     L16
  test   %al,%al
  je     L4
  mov    $0x8,%eax
  mov    $0x4,%edx
  jmp    L34
  nop
L16:
  test   %al,%al
  je     L26
  mov    $0x7,%eax
  mov    $0x3,%edx
L34:
  test   $0x8,%dil
  cmove  %edx,%eax
  and    $0x4,%edi
  cmp    $0x1,%dil
  sbb    $0xffffffff,%eax
  ret
L26:
  mov    $0x1,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  mov    $0x3,%eax
  ret
```

assistant: ```c
int workout_bytes_per_sample(unsigned char bt) {
  int recsiz = 1;
  if ((((bt)&2) != 0))
    recsiz += 2;
  if ((((bt) & (16 | 32)) != 0)) {
    if ((((bt)&2) != 0))
      recsiz -= 1;
    recsiz += 2;
    if ((((bt)&8) != 0))
      recsiz += 4;
    if ((((bt)&4) != 0))
      recsiz += 1;
  }
  return recsiz;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<is_operator>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x14(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L12
L27:
  lea    D8(%rip),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x14(%rbp)
  jne    L15
  mov    $0x1,%eax
  jmp    L11
L15:
  addq   $0x1,-0x8(%rbp)
L12:
  mov    D0(%rip),%rax
  cmp    %rax,-0x8(%rbp)
  jb     L27
  mov    $0x0,%eax
L11:
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string
name: disassemble_data
arguments: tag: D0
type_guessed: byte[8]

tool: D8: |<>

tool: {"D0": [0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
bool is_operator(const char c) {
  static const char operators[] = "|<>";
  static const size_t num_ops = sizeof(operators) / sizeof(operators[0]) - 1;
  for (size_t i = 0; i < num_ops; ++i) {
    if (c == operators[i]) {
      return true;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<is_operator>:
  endbr64
  cmp    $0x7c,%dil
  je     L0
  cmp    $0x3c,%dil
  je     L6
  cmp    $0x3e,%dil
  sete   %al
  movzbl %al,%eax
  ret
L0:
  mov    $0x1,%eax
  ret
L6:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool is_operator(const char c) {
  static const char operators[] = "|<>";
  static const size_t num_ops = sizeof(operators) / sizeof(operators[0]) - 1;
  for (size_t i = 0; i < num_ops; ++i) {
    if (c == operators[i]) {
      return true;
    }
  }
  return false;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_operator>:
  endbr64
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x3c,%al
  sete   %al
  cmp    $0x7c,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_operator(const char c) {
  static const char operators[] = "|<>";
  static const size_t num_ops = sizeof(operators) / sizeof(operators[0]) - 1;
  for (size_t i = 0; i < num_ops; ++i) {
    if (c == operators[i]) {
      return true;
    }
  }
  return false;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<is_operator>:
  endbr64
  mov    %edi,%eax
  and    $0xfffffffd,%eax
  cmp    $0x3c,%al
  sete   %al
  cmp    $0x7c,%dil
  sete   %dl
  or     %edx,%eax
  movzbl %al,%eax
  ret
```

assistant: ```c
bool is_operator(const char c) {
  static const char operators[] = "|<>";
  static const size_t num_ops = sizeof(operators) / sizeof(operators[0]) - 1;
  for (size_t i = 0; i < num_ops; ++i) {
    if (c == operators[i]) {
      return true;
    }
  }
  return false;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<bogoSort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  jmp    L13
L4:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <shuffle@plt>
L13:
  mov    -0xc(%rbp),%edx
  mov    -0x8(%rbp),%rax
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <isOrdered@plt>
  test   %eax,%eax
  je     L4
  nop
  nop
  leave
  ret
```

assistant: ```c
void bogoSort(int A[], int length) {
  while (!isOrdered(A, length)) {
    shuffle(A, length);
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<bogoSort>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%ebx
  jmp    L10
L6:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <shuffle@plt>
L10:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <isOrdered@plt>
  test   %eax,%eax
  je     L6
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bogoSort(int A[], int length) {
  while (!isOrdered(A, length)) {
    shuffle(A, length);
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bogoSort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L8
  nopl   0x0(%rax)
L5:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <shuffle@plt>
L8:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <isOrdered@plt>
  test   %eax,%eax
  je     L5
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bogoSort(int A[], int length) {
  while (!isOrdered(A, length)) {
    shuffle(A, length);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bogoSort>:
  endbr64
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L12
  nopl   0x0(%rax)
L19:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <shuffle@plt>
L12:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <isOrdered@plt>
  test   %eax,%eax
  je     L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
void bogoSort(int A[], int length) {
  while (!isOrdered(A, length)) {
    shuffle(A, length);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<fixDown>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  jmp    L46
L31:
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jge    L23
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  add    $0x1,%rax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L23
  addl   $0x1,-0x4(%rbp)
L23:
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L14
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <swap@plt>
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x20(%rbp)
L46:
  mov    -0x20(%rbp),%eax
  add    %eax,%eax
  cmp    %eax,-0x1c(%rbp)
  jg     L31
  jmp    L22
L14:
  nop
L22:
  nop
  leave
  ret
```

assistant: ```c
void fixDown(int *a, int size, int k) {
  int j;
  while (2 * k < size) {
    j = 2 * k;
    if (j < size - 1 && a[j] < a[j + 1])
      j++;
    if (a[k] >= a[j])
      break;
    swap(a + k, a + j), k = j;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<fixDown>:
  endbr64
  lea    (%rdx,%rdx,1),%eax
  cmp    %eax,%esi
  jle    L24
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %esi,%r12d
  lea    -0x1(%rsi),%r13d
  jmp    L55
L18:
  movslq %edx,%rdx
  lea    0x0(%rbp,%rdx,4),%rdi
  movslq %ebx,%rax
  lea    0x0(%rbp,%rax,4),%rsi
  mov    (%rsi),%eax
  cmp    %eax,(%rdi)
  jge    L26
  mov    $0x0,%eax
  call   <swap@plt>
  lea    (%rbx,%rbx,1),%eax
  cmp    %r12d,%eax
  jge    L26
  mov    %ebx,%edx
L55:
  mov    %eax,%ebx
  cmp    %eax,%r13d
  jle    L18
  movslq %eax,%rcx
  mov    0x4(%rbp,%rcx,4),%esi
  cmp    %esi,0x0(%rbp,%rcx,4)
  jge    L18
  lea    0x1(%rax),%ebx
  jmp    L18
L26:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L24:
  ret
```

assistant: ```c
void fixDown(int *a, int size, int k) {
  int j;
  while (2 * k < size) {
    j = 2 * k;
    if (j < size - 1 && a[j] < a[j + 1])
      j++;
    if (a[k] >= a[j])
      break;
    swap(a + k, a + j), k = j;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<fixDown>:
  endbr64
  lea    (%rdx,%rdx,1),%ecx
  cmp    %ecx,%esi
  jle    L32
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L17
  nop
L4:
  xor    %eax,%eax
  call   <swap@plt>
  lea    (%r12,%r12,1),%ecx
  cmp    %ebx,%ecx
  jge    L39
  mov    %r12d,%edx
L17:
  movslq %ecx,%rax
  mov    %ecx,%r12d
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rsi
  mov    (%rsi),%r8d
  cmp    %ebp,%ecx
  jge    L31
  lea    0x4(%r13,%rax,1),%rax
  mov    (%rax),%ecx
  cmp    %r8d,%ecx
  jle    L31
  add    $0x1,%r12d
  mov    %ecx,%r8d
  mov    %rax,%rsi
L31:
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rdi
  cmp    %r8d,(%rdi)
  jl     L4
L39:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L32:
  ret
```

assistant: ```c
void fixDown(int *a, int size, int k) {
  int j;
  while (2 * k < size) {
    j = 2 * k;
    if (j < size - 1 && a[j] < a[j + 1])
      j++;
    if (a[k] >= a[j])
      break;
    swap(a + k, a + j), k = j;
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<fixDown>:
  endbr64
  lea    (%rdx,%rdx,1),%ecx
  cmp    %ecx,%esi
  jle    L47
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbp
  lea    -0x1(%rsi),%ebp
  push   %rbx
  mov    %esi,%ebx
  sub    $0x8,%rsp
  jmp    L38
  nop
L4:
  xor    %eax,%eax
  call   <swap@plt>
  lea    (%r12,%r12,1),%ecx
  cmp    %ebx,%ecx
  jge    L56
  mov    %r12d,%edx
L38:
  movslq %ecx,%rax
  mov    %ecx,%r12d
  shl    $0x2,%rax
  lea    0x0(%r13,%rax,1),%rsi
  mov    (%rsi),%r8d
  cmp    %ebp,%ecx
  jge    L55
  lea    0x4(%r13,%rax,1),%rax
  mov    (%rax),%ecx
  cmp    %r8d,%ecx
  jle    L55
  add    $0x1,%r12d
  mov    %ecx,%r8d
  mov    %rax,%rsi
L55:
  movslq %edx,%rdx
  lea    0x0(%r13,%rdx,4),%rdi
  cmp    %r8d,(%rdi)
  jl     L4
L56:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L47:
  ret
```

assistant: ```c
void fixDown(int *a, int size, int k) {
  int j;
  while (2 * k < size) {
    j = 2 * k;
    if (j < size - 1 && a[j] < a[j + 1])
      j++;
    if (a[k] >= a[j])
      break;
    swap(a + k, a + j), k = j;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<chomp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  jmp    L1
L12:
  addq   $0x1,-0x8(%rbp)
L1:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L23
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  jne    L12
L23:
  mov    -0x8(%rbp),%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r')
    s++;
  *s = 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L39
  mov    $0x2401,%edx
  bt     %rax,%rdx
  jb     L2
L39:
  mov    $0x2401,%edx
L29:
  add    $0x1,%rdi
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L29
  bt     %rax,%rdx
  jae    L29
L2:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r')
    s++;
  *s = 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L12
  mov    $0xffffffffffffdbfe,%rdx
  bt     %rax,%rdx
  jae    L21
L12:
  mov    $0xffffffffffffdbfe,%rdx
  nop
L8:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0xd,%al
  ja     L8
  bt     %rax,%rdx
  jb     L8
L21:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r')
    s++;
  *s = 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<chomp>:
  endbr64
  movzbl (%rdi),%eax
  cmp    $0xd,%al
  ja     L4
  mov    $0xffffffffffffdbfe,%rdx
  bt     %rax,%rdx
  jae    L26
L4:
  mov    $0xffffffffffffdbfe,%rdx
  nop
L22:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  cmp    $0xd,%al
  ja     L22
  bt     %rax,%rdx
  jb     L22
L26:
  movb   $0x0,(%rdi)
  ret
```

assistant: ```c
void chomp(char *s) {
  while (*s && *s != '\n' && *s != '\r')
    s++;
  *s = 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<mv_ut>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L22
L1:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  pxor   %xmm0,%xmm0
  movsd  %xmm0,(%rax)
  movl   $0x0,-0x8(%rbp)
  jmp    L28
L29:
  mov    -0x28(%rbp),%rax
  lea    0x8(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  movsd  (%rax),%xmm1
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x30(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mulsd  %xmm0,%xmm1
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movsd  (%rax),%xmm0
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  addsd  %xmm1,%xmm0
  movsd  %xmm0,(%rax)
  addl   $0x1,-0x8(%rbp)
L28:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jbe    L29
  addl   $0x1,-0x4(%rbp)
L22:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L1
  nop
  nop
  pop    %rbp
  ret
```

assistant: ```c
void mv_ut(double *y, unsigned int n, const double *U, const double *x) {
  unsigned int i, j;
  for (j = 0; j < n; ++j) {
    y[j] = 0;
    for (i = 0; i <= j; ++i)
      y[i] += (*U++) * x[j];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mv_ut>:
  endbr64
  mov    %rdi,%r8
  test   %esi,%esi
  je     L4
  mov    %esi,%r9d
  mov    $0x0,%edi
L24:
  movq   $0x0,(%r8,%rdi,8)
  mov    $0x0,%eax
L26:
  add    $0x8,%rdx
  mov    %eax,%esi
  lea    (%r8,%rsi,8),%rsi
  movsd  -0x8(%rdx),%xmm0
  mulsd  (%rcx),%xmm0
  addsd  (%rsi),%xmm0
  movsd  %xmm0,(%rsi)
  add    $0x1,%eax
  cmp    %edi,%eax
  jbe    L26
  add    $0x1,%rdi
  add    $0x8,%rcx
  cmp    %r9,%rdi
  jne    L24
L4:
  ret
```

assistant: ```c
void mv_ut(double *y, unsigned int n, const double *U, const double *x) {
  unsigned int i, j;
  for (j = 0; j < n; ++j) {
    y[j] = 0;
    for (i = 0; i <= j; ++i)
      y[i] += (*U++) * x[j];
  }
}
```