ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<autohelperowl_attackpat206>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %esi,-0x2c(%rbp)
  mov    %edx,-0x30(%rbp)
  mov    %ecx,-0x34(%rbp)
  mov    %r8d,-0x38(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x14(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,-0x8(%rbp)
  mov    -0x2c(%rbp),%edx
  mov    -0x30(%rbp),%eax
  mov    %edx,%ecx
  mov    %eax,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jg     L61
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L51
L61:
  mov    -0x4(%rbp),%edx
  mov    -0x34(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  jne    L45
  mov    $0x3,%eax
  sub    -0x34(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  jne    L45
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jns    L51
L45:
  mov    -0x8(%rbp),%edi
  mov    -0xc(%rbp),%esi
  mov    -0x30(%rbp),%edx
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%ecx
  push   %rcx
  mov    -0x30(%rbp),%ecx
  push   %rcx
  mov    %edi,%r9d
  mov    %esi,%r8d
  mov    %edx,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <play_attack_defend2_n@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  jne    L51
  mov    $0x1,%eax
  jmp    L3
L51:
  mov    $0x0,%eax
L3:
  leave
  ret
```

assistant: ```c
int autohelperowl_attackpat206(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D, E;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 1, move, transformation);
  c = offset(1, 0, move, transformation);
  D = offset(1, -1, move, transformation);
  E = offset(0, 1, move, transformation);
  return (owl_escape_value(a) > 0 || owl_escape_value(b) > 0) && ((somewhere(color, 0, E) || somewhere((1 + 2 - (color)), 0, E)) || owl_escape_value(a) < 0) && !play_attack_defend2_n(color, 1, 3, move, c, D, move, D);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<autohelperowl_attackpat206>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %esi,%ebp
  mov    %edx,%ebx
  mov    %ecx,%r12d
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%r14d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,0xc(%rsp)
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x0,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%r15d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  call   <offset@plt>
  mov    %eax,%r13d
  mov    %ebp,%ecx
  mov    %ebx,%edx
  mov    $0x1,%esi
  mov    $0x0,%edi
  call   <offset@plt>
  mov    %eax,%ebp
  mov    %r14d,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L11
L9:
  mov    %ebp,%edx
  mov    $0x0,%esi
  mov    %r12d,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  jne    L53
  mov    $0x3,%edi
  sub    %r12d,%edi
  mov    %ebp,%edx
  mov    $0x0,%esi
  call   <somewhere@plt>
  test   %rax,%rax
  je     L67
L53:
  push   %r13
  push   %rbx
  mov    %r13d,%r9d
  mov    %r15d,%r8d
  mov    %ebx,%ecx
  mov    $0x3,%edx
  mov    $0x1,%esi
  mov    %r12d,%edi
  call   <play_attack_defend2_n@plt>
  add    $0x10,%rsp
  test   %eax,%eax
  sete   %al
  movzbl %al,%eax
L28:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  mov    0xc(%rsp),%edi
  call   <owl_escape_value@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jg     L9
  jmp    L28
L67:
  mov    %r14d,%edi
  call   <owl_escape_value@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  jns    L28
  jmp    L53
```

assistant: ```c
int autohelperowl_attackpat206(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D, E;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 1, move, transformation);
  c = offset(1, 0, move, transformation);
  D = offset(1, -1, move, transformation);
  E = offset(0, 1, move, transformation);
  return (owl_escape_value(a) > 0 || owl_escape_value(b) > 0) && ((somewhere(color, 0, E) || somewhere((1 + 2 - (color)), 0, E)) || owl_escape_value(a) < 0) && !play_attack_defend2_n(color, 1, 3, move, c, D, move, D);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<autohelperowl_attackpat206>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  push   %rbx
  sub    $0x18,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    %eax,%r14d
  call   <offset@plt>
  mov    %r13d,%ecx
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    $0x1,%edi
  mov    %eax,0xc(%rsp)
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <offset@plt>
  xor    %edi,%edi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L31
L9:
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %ebp,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  je     L14
L1:
  push   %rbx
  mov    %r12d,%ecx
  mov    %ebx,%r9d
  mov    %r15d,%r8d
  push   %r12
  mov    $0x3,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <play_attack_defend2_n@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  sete   %al
  add    $0x18,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L14:
  mov    $0x3,%edi
  xor    %esi,%esi
  mov    %r13d,%edx
  sub    %ebp,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  jne    L1
  mov    %r14d,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  js     L1
  xor    %eax,%eax
L27:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L31:
  mov    0xc(%rsp),%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jg     L9
  xor    %eax,%eax
  jmp    L27
```

assistant: ```c
int autohelperowl_attackpat206(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D, E;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 1, move, transformation);
  c = offset(1, 0, move, transformation);
  D = offset(1, -1, move, transformation);
  E = offset(0, 1, move, transformation);
  return (owl_escape_value(a) > 0 || owl_escape_value(b) > 0) && ((somewhere(color, 0, E) || somewhere((1 + 2 - (color)), 0, E)) || owl_escape_value(a) < 0) && !play_attack_defend2_n(color, 1, 3, move, c, D, move, D);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<autohelperowl_attackpat206>:
  endbr64
  push   %r15
  xor    %edi,%edi
  push   %r14
  push   %r13
  mov    %esi,%r13d
  push   %r12
  mov    %edx,%r12d
  push   %rbp
  mov    %ecx,%ebp
  mov    %esi,%ecx
  mov    $0xffffffff,%esi
  push   %rbx
  sub    $0x18,%rsp
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    $0x1,%edi
  mov    %eax,%r14d
  call   <offset@plt>
  mov    %r13d,%ecx
  xor    %esi,%esi
  mov    %r12d,%edx
  mov    $0x1,%edi
  mov    %eax,0xc(%rsp)
  call   <offset@plt>
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0xffffffff,%esi
  mov    $0x1,%edi
  mov    %eax,%r15d
  call   <offset@plt>
  xor    %edi,%edi
  mov    %r13d,%ecx
  mov    %r12d,%edx
  mov    $0x1,%esi
  mov    %eax,%ebx
  call   <offset@plt>
  mov    %r14d,%edi
  mov    %eax,%r13d
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jle    L40
L10:
  xor    %esi,%esi
  mov    %r13d,%edx
  mov    %ebp,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  je     L38
L22:
  push   %rbx
  mov    %r12d,%ecx
  mov    %ebx,%r9d
  mov    %r15d,%r8d
  push   %r12
  mov    $0x3,%edx
  mov    %ebp,%edi
  mov    $0x1,%esi
  call   <play_attack_defend2_n@plt>
  pop    %rdx
  pop    %rcx
  test   %eax,%eax
  sete   %al
  add    $0x18,%rsp
  pop    %rbx
  movzbl %al,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L38:
  mov    $0x3,%edi
  xor    %esi,%esi
  mov    %r13d,%edx
  sub    %ebp,%edi
  call   <somewhere@plt>
  test   %rax,%rax
  jne    L22
  mov    %r14d,%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  js     L22
  xor    %eax,%eax
L46:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax)
L40:
  mov    0xc(%rsp),%edi
  call   <owl_escape_value@plt>
  test   %rax,%rax
  jg     L10
  xor    %eax,%eax
  jmp    L46
```

assistant: ```c
int autohelperowl_attackpat206(struct pattern *patt, int transformation, int move, int color, int action) {
  int a, b, c, D, E;
  (void)patt;
  (void)color;
  (void)action;
  a = offset(0, -1, move, transformation);
  b = offset(1, 1, move, transformation);
  c = offset(1, 0, move, transformation);
  D = offset(1, -1, move, transformation);
  E = offset(0, 1, move, transformation);
  return (owl_escape_value(a) > 0 || owl_escape_value(b) > 0) && ((somewhere(color, 0, E) || somewhere((1 + 2 - (color)), 0, E)) || owl_escape_value(a) < 0) && !play_attack_defend2_n(color, 1, 3, move, c, D, move, D);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<showAllLeapYearInAge>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x14(%rbp),%eax
  imul   $0x64,%eax,%eax
  sub    $0x63,%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x4(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%edi
  call   <startShowAllLeapYear@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
data_type: string

tool: D8: 
***SHOWING ALL LEAP YEAR ON %d AGE.


assistant: ```c
void showAllLeapYearInAge(int age) {
  int count = 0, i;
  int start = (100 * age) - 99;
  printf("\n***SHOWING ALL LEAP YEAR ON %d AGE.\n", age);
  startShowAllLeapYear(start, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<showAllLeapYearInAge>:
  endbr64
  push   %rbx
  mov    %edi,%ebx
  mov    %edi,%esi
  lea    D4(%rip),%rdi
  call   <printf@plt>
  imul   $0x64,%ebx,%edi
  sub    $0x63,%edi
  mov    $0x1,%esi
  call   <startShowAllLeapYear@plt>
  pop    %rbx
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type_infered: string

tool: D4: 
***SHOWING ALL LEAP YEAR ON %d AGE.


assistant: ```c
void showAllLeapYearInAge(int age) {
  int count = 0, i;
  int start = (100 * age) - 99;
  printf("\n***SHOWING ALL LEAP YEAR ON %d AGE.\n", age);
  startShowAllLeapYear(start, 1);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<showAllLeapYearInAge>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  lea    D5(%rip),%rdi
  call   <printf@plt>
  imul   $0x64,%ebx,%edi
  mov    $0x1,%esi
  pop    %rbx
  sub    $0x63,%edi
  jmp    1070 <startShowAllLeapYear@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: 
***SHOWING ALL LEAP YEAR ON %d AGE.


assistant: ```c
void showAllLeapYearInAge(int age) {
  int count = 0, i;
  int start = (100 * age) - 99;
  printf("\n***SHOWING ALL LEAP YEAR ON %d AGE.\n", age);
  startShowAllLeapYear(start, 1);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<showAllLeapYearInAge>:
  endbr64
  push   %rbx
  mov    %edi,%esi
  mov    %edi,%ebx
  lea    D3(%rip),%rdi
  call   <printf@plt>
  imul   $0x64,%ebx,%edi
  mov    $0x1,%esi
  pop    %rbx
  sub    $0x63,%edi
  jmp    1070 <startShowAllLeapYear@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_infered: string

tool: D3: 
***SHOWING ALL LEAP YEAR ON %d AGE.


assistant: ```c
void showAllLeapYearInAge(int age) {
  int count = 0, i;
  int start = (100 * age) - 99;
  printf("\n***SHOWING ALL LEAP YEAR ON %d AGE.\n", age);
  startShowAllLeapYear(start, 1);
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %rsi,-0x10(%rbp)
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
datatype: string

tool: D7: Hello World!!!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!!!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_infered: string

tool: D5: Hello World!!!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!!!\n");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D0(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D0
data_type: string

tool: D0: Hello World!!!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!!!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D8
type_infered: string

tool: D8: Hello World!!!


assistant: ```c
int main(int argc, char *argv[]) {
  printf("Hello World!!!\n");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<multiple>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L10
L38:
  mov    -0x14(%rbp),%eax
  and    -0x8(%rbp),%eax
  test   %eax,%eax
  je     L27
  movl   $0x0,-0x4(%rbp)
  jmp    L32
L27:
  addl   $0x1,-0xc(%rbp)
  shll   -0x8(%rbp)
L10:
  cmpl   $0xa,-0xc(%rbp)
  jle    L38
L32:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int multiple(int num) {
  int i, mask = 1, mult = 1;
  for (i = 1; i <= 10; i++, mask <<= 1)
    if ((num & mask) != 0) {
      mult = 0;
      break;
    }
  return mult;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<multiple>:
  endbr64
  mov    %edi,%ecx
  and    $0x1,%ecx
  jne    L9
  mov    $0x9,%edx
  mov    $0x2,%eax
L36:
  test   %eax,%edi
  jne    L18
  add    %eax,%eax
  sub    $0x1,%edx
  jne    L36
  mov    $0x1,%ecx
L18:
  mov    %ecx,%eax
  ret
L9:
  mov    $0x0,%ecx
  jmp    L18
```

assistant: ```c
int multiple(int num) {
  int i, mask = 1, mult = 1;
  for (i = 1; i <= 10; i++, mask <<= 1)
    if ((num & mask) != 0) {
      mult = 0;
      break;
    }
  return mult;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<multiple>:
  endbr64
  mov    $0xa,%edx
  mov    $0x1,%eax
  xchg   %ax,%ax
L17:
  test   %eax,%edi
  jne    L2
  add    %eax,%eax
  sub    $0x1,%edx
  jne    L17
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L2:
  xor    %eax,%eax
  ret
```

assistant: ```c
int multiple(int num) {
  int i, mask = 1, mult = 1;
  for (i = 1; i <= 10; i++, mask <<= 1)
    if ((num & mask) != 0) {
      mult = 0;
      break;
    }
  return mult;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<multiple>:
  endbr64
  xor    %eax,%eax
  and    $0x3ff,%edi
  sete   %al
  ret
```

assistant: ```c
int multiple(int num) {
  int i, mask = 1, mult = 1;
  for (i = 1; i <= 10; i++, mask <<= 1)
    if ((num & mask) != 0) {
      mult = 0;
      break;
    }
  return mult;
}
```
user: Translate the below assembly code into C programming language:

```asm
<Timeval_add>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  mov    %edi,%ecx
  mov    %rsi,%rax
  mov    %rax,%rbx
  mov    %rcx,-0x50(%rbp)
  mov    %rbx,-0x48(%rbp)
  mov    %rdx,-0x58(%rbp)
  movq   $0xf4240,-0x38(%rbp)
  mov    -0x50(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x58(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x30(%rbp),%rax
  cqto
  idivq  -0x38(%rbp)
  mov    %rax,-0x28(%rbp)
  mov    -0x30(%rbp),%rax
  cqto
  idivq  -0x38(%rbp)
  mov    %rdx,-0x30(%rbp)
  mov    -0x48(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  cltq
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %eax,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    -0x18(%rbp),%rdx
  mov    %rax,%rcx
  mov    %rdx,%rbx
  mov    %ecx,%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
struct timeval Timeval_add(const struct timeval x, long long usec_delta) {
  struct timeval retval;
  long long sec_delta, usec;
  const long long K = (1000LL * 1000LL);
  usec = usec_delta + (long long)x.tv_usec;
  sec_delta = usec / K;
  usec %= K;
  retval.tv_sec = x.tv_sec + (int)sec_delta;
  retval.tv_usec = (int)usec;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Timeval_add>:
  endbr64
  movslq %edi,%rdi
  add    %rdx,%rdi
  movabs $0x431bde82d7b634db,%rdx
  mov    %rdi,%rax
  imul   %rdx
  sar    $0x12,%rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  movslq %edx,%rcx
  add    %rsi,%rcx
  imul   $0xf4240,%rdx,%rdx
  mov    %edi,%eax
  sub    %edx,%eax
  mov    %rcx,%rdx
  ret
```

assistant: ```c
struct timeval Timeval_add(const struct timeval x, long long usec_delta) {
  struct timeval retval;
  long long sec_delta, usec;
  const long long K = (1000LL * 1000LL);
  usec = usec_delta + (long long)x.tv_usec;
  sec_delta = usec / K;
  usec %= K;
  retval.tv_sec = x.tv_sec + (int)sec_delta;
  retval.tv_usec = (int)usec;
  return retval;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Timeval_add>:
  endbr64
  movslq %edi,%rdi
  add    %rdx,%rdi
  movabs $0x431bde82d7b634db,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  mov    %edi,%eax
  movslq %edx,%r8
  imul   $0xf4240,%rdx,%rdx
  add    %rsi,%r8
  sub    %edx,%eax
  mov    %r8,%rdx
  ret
```

assistant: ```c
struct timeval Timeval_add(const struct timeval x, long long usec_delta) {
  struct timeval retval;
  long long sec_delta, usec;
  const long long K = (1000LL * 1000LL);
  usec = usec_delta + (long long)x.tv_usec;
  sec_delta = usec / K;
  usec %= K;
  retval.tv_sec = x.tv_sec + (int)sec_delta;
  retval.tv_usec = (int)usec;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<Timeval_add>:
  endbr64
  movslq %edi,%rdi
  add    %rdx,%rdi
  movabs $0x431bde82d7b634db,%rdx
  mov    %rdi,%rax
  imul   %rdx
  mov    %rdi,%rax
  sar    $0x3f,%rax
  sar    $0x12,%rdx
  sub    %rax,%rdx
  mov    %edi,%eax
  movslq %edx,%r8
  imul   $0xf4240,%rdx,%rdx
  add    %rsi,%r8
  sub    %edx,%eax
  mov    %r8,%rdx
  ret
```

assistant: ```c
struct timeval Timeval_add(const struct timeval x, long long usec_delta) {
  struct timeval retval;
  long long sec_delta, usec;
  const long long K = (1000LL * 1000LL);
  usec = usec_delta + (long long)x.tv_usec;
  sec_delta = usec / K;
  usec %= K;
  retval.tv_sec = x.tv_sec + (int)sec_delta;
  retval.tv_usec = (int)usec;
  return retval;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divide_by_zero_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  nop
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D8
data_type: string

tool: D8: 
 #####> Exiting on divide by zero !!


assistant: ```c
void divide_by_zero_handler() {
  printf("\n #####> Exiting on divide by zero !!\n");
  exit(-1);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<divide_by_zero_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  call   <exit@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D6
type_guessed: string

tool: D6: 
 #####> Exiting on divide by zero !!


assistant: ```c
void divide_by_zero_handler() {
  printf("\n #####> Exiting on divide by zero !!\n");
  exit(-1);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<divide_by_zero_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D5
data_type: string

tool: D5: 
 #####> Exiting on divide by zero !!


assistant: ```c
void divide_by_zero_handler() {
  printf("\n #####> Exiting on divide by zero !!\n");
  exit(-1);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<divide_by_zero_handler>:
  endbr64
  sub    $0x8,%rsp
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0xffffffff,%edi
  add    $0x8,%rsp
  jmp    1070 <exit@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D6
type: string

tool: D6: 
 #####> Exiting on divide by zero !!


assistant: ```c
void divide_by_zero_handler() {
  printf("\n #####> Exiting on divide by zero !!\n");
  exit(-1);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<cmdWho>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x120,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x110(%rbp),%rax
  mov    $0x100,%esi
  mov    %rax,%rdi
  call   <identify2@plt>
  mov    %eax,-0x114(%rbp)
  cmpl   $0x0,-0x114(%rbp)
  je     L29
  mov    -0x114(%rbp),%eax
  mov    %eax,%esi
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L8
L29:
  lea    -0x110(%rbp),%rax
  mov    %rax,%rdi
  call   <puts@plt>
L8:
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L19
  call   <__stack_chk_fail@plt>
L19:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: tag: D8
type_guessed: string

tool: D8: Erro: %d


assistant: ```c
void cmdWho(void) {
  char name[256];
  int err = identify2(name, 256);
  if (err) {
    printf("Erro: %d\n", err);
    return;
  }
  printf("%s\n", name);
}
```
user: Translate the below assembly code into C programming language:

```asm
<cmdWho>:
  endbr64
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x100,%esi
  call   <identify2@plt>
  test   %eax,%eax
  jne    L12
  mov    %rsp,%rdi
  call   <puts@plt>
L24:
  mov    0x108(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x118,%rsp
  ret
L12:
  mov    %eax,%esi
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L24
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Erro: %d


assistant: ```c
void cmdWho(void) {
  char name[256];
  int err = identify2(name, 256);
  if (err) {
    printf("Erro: %d\n", err);
    return;
  }
  printf("%s\n", name);
}
```