ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<find_xor8_mask>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %rdx,-0x38(%rbp)
  mov    %rcx,-0x40(%rbp)
  cmpq   $0x0,-0x30(%rbp)
  je     L57
  mov    -0x30(%rbp),%rax
  cmp    -0x40(%rbp),%rax
  jae    L47
L57:
  mov    $0xffffffff,%eax
  jmp    L127
L47:
  cmpq   $0x0,-0x40(%rbp)
  jne    L156
  mov    $0xfffffffe,%eax
  jmp    L127
L156:
  mov    -0x38(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x17(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  cmpq   $0x1,-0x40(%rbp)
  jne    L78
  cmpq   $0x1,-0x30(%rbp)
  jne    L103
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x17(%rbp),%al
  movzbl %al,%eax
  jmp    L127
L103:
  mov    $0xfffffffe,%eax
  jmp    L127
L78:
  mov    -0x38(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%eax
  mov    %al,-0x16(%rbp)
  movl   $0xffffffff,-0x14(%rbp)
  mov    -0x30(%rbp),%rax
  sub    -0x40(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  jmp    L153
L67:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  xor    -0x17(%rbp),%al
  mov    %al,-0x15(%rbp)
  mov    -0x10(%rbp),%rax
  add    $0x1,%rax
  movzbl (%rax),%edx
  movzbl -0x16(%rbp),%eax
  xor    -0x15(%rbp),%al
  cmp    %al,%dl
  jne    L89
  movzbl -0x15(%rbp),%ecx
  mov    -0x40(%rbp),%rdx
  mov    -0x38(%rbp),%rsi
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <memcmp_xor8@plt>
  test   %rax,%rax
  jne    L89
  cmpl   $0xffffffff,-0x14(%rbp)
  jne    L137
  movzbl -0x15(%rbp),%eax
  mov    %eax,-0x14(%rbp)
  jmp    L89
L137:
  mov    $0xfffffffe,%eax
  jmp    L127
L89:
  addq   $0x1,-0x10(%rbp)
L153:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jbe    L67
  mov    -0x14(%rbp),%eax
L127:
  leave
  ret
```

assistant: ```c
int find_xor8_mask(const void *haystack, size_t hlen, const void *needle, size_t nlen) {
  const unsigned char *p, *q;
  int r;
  unsigned char n0, n1, x;
  if (hlen == 0 || hlen < nlen)
    return -1;
  if (nlen == 0)
    return -2;
  n0 = *(const unsigned char *)needle;
  p = (const unsigned char *)haystack;
  if (nlen == 1)
    return (hlen == 1) ? *p ^ n0 : -2;
  n1 = *((const unsigned char *)needle + 1);
  for (r = -1, q = p + hlen - nlen; p <= q; p++) {
    x = *p ^ n0;
    if (*(p + 1) == (n1 ^ x) && memcmp_xor8(p, needle, nlen, x) == 0) {
      if (r == -1)
        r = x;
      else
        return -2;
    }
  }
  return r;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<find_xor8_mask>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L133
  mov    %rdi,%rbx
  mov    %rsi,%r12
  mov    %rdx,%r15
  mov    %rcx,%r14
  cmp    %rcx,%rsi
  jb     L133
  test   %rcx,%rcx
  je     L10
  movzbl (%rdx),%r13d
  cmp    $0x1,%rcx
  je     L82
  movzbl 0x1(%rdx),%eax
  mov    %al,0xb(%rsp)
  sub    %rcx,%r12
  add    %rdi,%r12
  jb     L19
  movl   $0xffffffff,0xc(%rsp)
  jmp    L102
L82:
  movl   $0xfffffffe,0xc(%rsp)
  cmp    $0x1,%rsi
  je     L50
L61:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L50:
  xor    (%rdi),%r13b
  movzbl %r13b,%eax
  mov    %eax,0xc(%rsp)
  jmp    L61
L0:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jb     L61
L102:
  mov    %r13d,%ebp
  xor    (%rbx),%bpl
  movzbl 0xb(%rsp),%eax
  xor    %ebp,%eax
  cmp    %al,0x1(%rbx)
  jne    L0
  movzbl %bpl,%ebp
  mov    %ebp,%ecx
  mov    %r14,%rdx
  mov    %r15,%rsi
  mov    %rbx,%rdi
  call   <memcmp_xor8@plt>
  test   %rax,%rax
  jne    L0
  cmpl   $0xffffffff,0xc(%rsp)
  jne    L37
  mov    %ebp,0xc(%rsp)
  jmp    L0
L133:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L61
L10:
  movl   $0xfffffffe,0xc(%rsp)
  jmp    L61
L19:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L61
L37:
  movl   $0xfffffffe,0xc(%rsp)
  jmp    L61
```

assistant: ```c
int find_xor8_mask(const void *haystack, size_t hlen, const void *needle, size_t nlen) {
  const unsigned char *p, *q;
  int r;
  unsigned char n0, n1, x;
  if (hlen == 0 || hlen < nlen)
    return -1;
  if (nlen == 0)
    return -2;
  n0 = *(const unsigned char *)needle;
  p = (const unsigned char *)haystack;
  if (nlen == 1)
    return (hlen == 1) ? *p ^ n0 : -2;
  n1 = *((const unsigned char *)needle + 1);
  for (r = -1, q = p + hlen - nlen; p <= q; p++) {
    x = *p ^ n0;
    if (*(p + 1) == (n1 ^ x) && memcmp_xor8(p, needle, nlen, x) == 0) {
      if (r == -1)
        r = x;
      else
        return -2;
    }
  }
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<find_xor8_mask>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L73
  mov    %rsi,%r12
  mov    %rcx,%r8
  cmp    %rcx,%rsi
  jb     L73
  test   %rcx,%rcx
  je     L132
  movzbl (%rdx),%r14d
  mov    %rdi,%rbx
  mov    %rdx,%r13
  cmp    $0x1,%rcx
  je     L29
  sub    %rcx,%r12
  movl   $0xffffffff,0xc(%rsp)
  movzbl 0x1(%rdx),%r15d
  add    %rdi,%r12
  jae    L22
  jmp    L67
  nopw   0x0(%rax,%rax,1)
L31:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jb     L67
L22:
  movzbl (%rbx),%eax
  mov    %r15d,%edx
  xor    %r14d,%eax
  xor    %eax,%edx
  cmp    %dl,0x1(%rbx)
  jne    L31
  movzbl %al,%ebp
  mov    %r8,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    %ebp,%ecx
  mov    %r8,(%rsp)
  call   <memcmp_xor8@plt>
  mov    (%rsp),%r8
  test   %rax,%rax
  jne    L31
  cmpl   $0xffffffff,0xc(%rsp)
  jne    L132
  add    $0x1,%rbx
  mov    %ebp,0xc(%rsp)
  cmp    %rbx,%r12
  jae    L22
L67:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L29:
  cmp    $0x1,%rsi
  je     L148
L132:
  movl   $0xfffffffe,0xc(%rsp)
  jmp    L67
L148:
  xor    (%rdi),%r14b
  movzbl %r14b,%eax
  mov    %eax,0xc(%rsp)
  jmp    L67
L73:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L67
```

assistant: ```c
int find_xor8_mask(const void *haystack, size_t hlen, const void *needle, size_t nlen) {
  const unsigned char *p, *q;
  int r;
  unsigned char n0, n1, x;
  if (hlen == 0 || hlen < nlen)
    return -1;
  if (nlen == 0)
    return -2;
  n0 = *(const unsigned char *)needle;
  p = (const unsigned char *)haystack;
  if (nlen == 1)
    return (hlen == 1) ? *p ^ n0 : -2;
  n1 = *((const unsigned char *)needle + 1);
  for (r = -1, q = p + hlen - nlen; p <= q; p++) {
    x = *p ^ n0;
    if (*(p + 1) == (n1 ^ x) && memcmp_xor8(p, needle, nlen, x) == 0) {
      if (r == -1)
        r = x;
      else
        return -2;
    }
  }
  return r;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_xor8_mask>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  test   %rsi,%rsi
  je     L96
  mov    %rsi,%r12
  mov    %rcx,%r8
  cmp    %rcx,%rsi
  jb     L96
  test   %rcx,%rcx
  je     L128
  movzbl (%rdx),%r14d
  mov    %rdi,%rbx
  mov    %rdx,%r13
  cmp    $0x1,%rcx
  je     L71
  sub    %rcx,%r12
  movl   $0xffffffff,0xc(%rsp)
  movzbl 0x1(%rdx),%r15d
  add    %rdi,%r12
  jae    L93
  jmp    L72
  nopw   0x0(%rax,%rax,1)
L83:
  add    $0x1,%rbx
  cmp    %rbx,%r12
  jb     L72
L93:
  movzbl (%rbx),%eax
  mov    %r15d,%edx
  xor    %r14d,%eax
  xor    %eax,%edx
  cmp    %dl,0x1(%rbx)
  jne    L83
  movzbl %al,%ebp
  mov    %r8,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  mov    %ebp,%ecx
  mov    %r8,(%rsp)
  call   <memcmp_xor8@plt>
  mov    (%rsp),%r8
  test   %rax,%rax
  jne    L83
  cmpl   $0xffffffff,0xc(%rsp)
  jne    L128
  add    $0x1,%rbx
  mov    %ebp,0xc(%rsp)
  cmp    %rbx,%r12
  jae    L93
L72:
  mov    0xc(%rsp),%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L71:
  cmp    $0x1,%rsi
  je     L54
L128:
  movl   $0xfffffffe,0xc(%rsp)
  jmp    L72
L54:
  xor    (%rdi),%r14b
  movzbl %r14b,%eax
  mov    %eax,0xc(%rsp)
  jmp    L72
L96:
  movl   $0xffffffff,0xc(%rsp)
  jmp    L72
```

assistant: ```c
int find_xor8_mask(const void *haystack, size_t hlen, const void *needle, size_t nlen) {
  const unsigned char *p, *q;
  int r;
  unsigned char n0, n1, x;
  if (hlen == 0 || hlen < nlen)
    return -1;
  if (nlen == 0)
    return -2;
  n0 = *(const unsigned char *)needle;
  p = (const unsigned char *)haystack;
  if (nlen == 1)
    return (hlen == 1) ? *p ^ n0 : -2;
  n1 = *((const unsigned char *)needle + 1);
  for (r = -1, q = p + hlen - nlen; p <= q; p++) {
    x = *p ^ n0;
    if (*(p + 1) == (n1 ^ x) && memcmp_xor8(p, needle, nlen, x) == 0) {
      if (r == -1)
        r = x;
      else
        return -2;
    }
  }
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0xc0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0xb0(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0xd,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  movl   $0x0,-0xb4(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,%rdi
  call   <gets@plt>
  jmp    L7
L24:
  mov    -0xb4(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  movsbl %al,%eax
  sub    $0x61,%eax
  movslq %eax,%rdx
  mov    -0xb0(%rbp,%rdx,4),%edx
  add    $0x1,%edx
  cltq
  mov    %edx,-0xb0(%rbp,%rax,4)
  addl   $0x1,-0xb4(%rbp)
L7:
  mov    -0xb4(%rbp),%eax
  cltq
  movzbl -0x40(%rbp,%rax,1),%eax
  test   %al,%al
  jne    L24
  movl   $0x0,-0xb4(%rbp)
  jmp    L12
L20:
  mov    -0xb4(%rbp),%eax
  cltq
  mov    -0xb0(%rbp,%rax,4),%eax
  mov    -0xb4(%rbp),%edx
  add    $0x61,%edx
  mov    %eax,%esi
  mov    %edx,%edi
  call   <print@plt>
  addl   $0x1,-0xb4(%rbp)
L12:
  cmpl   $0x19,-0xb4(%rbp)
  jle    L20
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void main() {
  char str[50];
  int arr[26] = {0};
  int i = 0;
  gets(str);
  while (str[i] != '\0') {
    arr[str[i] - 'a']++;
    i++;
  }
  for (i = 0; i < 26; i++) {
    print(i + 'a', arr[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x70(%rsp),%rdi
  call   <gets@plt>
  movzbl 0x70(%rsp),%eax
  test   %al,%al
  je     L25
  lea    0x71(%rsp),%rdx
L33:
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  addl   $0x1,(%rsp,%rax,4)
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L33
L25:
  mov    %rsp,%rbx
  lea    0x68(%rsp),%r12
  mov    $0x61,%ebp
L4:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  call   <print@plt>
  add    $0x4,%rbx
  add    $0x1,%ebp
  cmp    %r12,%rbx
  jne    L4
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L32
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L32:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str[50];
  int arr[26] = {0};
  int i = 0;
  gets(str);
  while (str[i] != '\0') {
    arr[str[i] - 'a']++;
    i++;
  }
  for (i = 0; i < 26; i++) {
    print(i + 'a', arr[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xd,%ecx
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    0x70(%rsp),%rdi
  call   <gets@plt>
  movsbl 0x70(%rsp),%eax
  test   %al,%al
  je     L38
  lea    0x71(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L15:
  sub    $0x61,%eax
  add    $0x1,%rdx
  cltq
  addl   $0x1,(%rsp,%rax,4)
  movsbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L15
L38:
  lea    0x68(%rsp),%r12
  mov    $0x61,%ebp
  nop
L8:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  add    $0x4,%rbx
  add    $0x1,%ebp
  call   <print@plt>
  cmp    %r12,%rbx
  jne    L8
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L26:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str[50];
  int arr[26] = {0};
  int i = 0;
  gets(str);
  while (str[i] != '\0') {
    arr[str[i] - 'a']++;
    i++;
  }
  for (i = 0; i < 26; i++) {
    print(i + 'a', arr[i]);
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %r12
  mov    $0xd,%ecx
  push   %rbp
  push   %rbx
  sub    $0xb0,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xa8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbx
  mov    %rbx,%rdi
  rep stos %rax,%es:(%rdi)
  lea    0x70(%rsp),%rdi
  call   <gets@plt>
  movsbl 0x70(%rsp),%eax
  test   %al,%al
  je     L8
  lea    0x71(%rsp),%rdx
  nopl   0x0(%rax,%rax,1)
L18:
  sub    $0x61,%eax
  add    $0x1,%rdx
  cltq
  addl   $0x1,(%rsp,%rax,4)
  movsbl -0x1(%rdx),%eax
  test   %al,%al
  jne    L18
L8:
  lea    0x68(%rsp),%r12
  mov    $0x61,%ebp
  nop
L33:
  mov    (%rbx),%esi
  mov    %ebp,%edi
  add    $0x4,%rbx
  add    $0x1,%ebp
  call   <print@plt>
  cmp    %rbx,%r12
  jne    L33
  mov    0xa8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  add    $0xb0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void main() {
  char str[50];
  int arr[26] = {0};
  int i = 0;
  gets(str);
  while (str[i] != '\0') {
    arr[str[i] - 'a']++;
    i++;
  }
  for (i = 0; i < 26; i++) {
    print(i + 'a', arr[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<unpack_tagcls>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,%eax
  mov    %al,-0x24(%rbp)
  movzbl -0x24(%rbp),%eax
  and    $0x1f,%eax
  mov    %al,-0x2(%rbp)
  movzbl -0x24(%rbp),%eax
  and    $0xffffffe0,%eax
  mov    %al,-0x1(%rbp)
  movzbl -0x1(%rbp),%ecx
  movzbl -0x2(%rbp),%edx
  mov    -0x20(%rbp),%rsi
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <unpack_long_tag_and_class@plt>
  leave
  ret
```

assistant: ```c
int unpack_tagcls(unsigned char **p, unsigned char **e, unsigned char tagcls) {
  uint newtag = (tagcls & 0x1f);
  uint newcls = (tagcls & 0xe0);
  return unpack_long_tag_and_class(p, e, newtag, newcls);
}
```
user: What is the c source code of the assembly code below?

```asm
<unpack_tagcls>:
  endbr64
  sub    $0x8,%rsp
  mov    %edx,%ecx
  and    $0xe0,%ecx
  and    $0x1f,%edx
  call   <unpack_long_tag_and_class@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
int unpack_tagcls(unsigned char **p, unsigned char **e, unsigned char tagcls) {
  uint newtag = (tagcls & 0x1f);
  uint newcls = (tagcls & 0xe0);
  return unpack_long_tag_and_class(p, e, newtag, newcls);
}
```
user: Translate the below assembly code into C programming language:

```asm
<unpack_tagcls>:
  endbr64
  mov    %edx,%ecx
  and    $0x1f,%edx
  and    $0xe0,%ecx
  jmp    1050 <unpack_long_tag_and_class@plt>
```

assistant: ```c
int unpack_tagcls(unsigned char **p, unsigned char **e, unsigned char tagcls) {
  uint newtag = (tagcls & 0x1f);
  uint newcls = (tagcls & 0xe0);
  return unpack_long_tag_and_class(p, e, newtag, newcls);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<unpack_tagcls>:
  endbr64
  mov    %edx,%ecx
  and    $0x1f,%edx
  and    $0xe0,%ecx
  jmp    1050 <unpack_long_tag_and_class@plt>
```

assistant: ```c
int unpack_tagcls(unsigned char **p, unsigned char **e, unsigned char tagcls) {
  uint newtag = (tagcls & 0x1f);
  uint newcls = (tagcls & 0xe0);
  return unpack_long_tag_and_class(p, e, newtag, newcls);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<old_str_str>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %rax,-0x10(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L3
  mov    -0x18(%rbp),%rax
  jmp    L4
L31:
  subq   $0x1,-0x10(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L2
  mov    -0x18(%rbp),%rax
  jmp    L4
L2:
  addq   $0x1,-0x18(%rbp)
L3:
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  jae    L31
  mov    $0x0,%eax
L4:
  leave
  ret
```

assistant: ```c
char *old_str_str(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  l1 = strlen(s1);
  if (!l2)
    return (char *)s1;
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2))
      return (char *)s1;
    s1++;
  }
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<old_str_str>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %rsi,%rdi
  call   <strlen@plt>
  mov    %r12,%rbx
  test   %rax,%rax
  je     L41
  mov    %rax,%rbp
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %rax,%rbp
  ja     L33
  add    %rax,%r12
L43:
  mov    %rbp,%rdx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  je     L41
  add    $0x1,%rbx
  mov    %r12,%rax
  sub    %rbx,%rax
  cmp    %rax,%rbp
  jbe    L43
  mov    $0x0,%ebx
L41:
  mov    %rbx,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L33:
  mov    $0x0,%ebx
  jmp    L41
```

assistant: ```c
char *old_str_str(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  l1 = strlen(s1);
  if (!l2)
    return (char *)s1;
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2))
      return (char *)s1;
    s1++;
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<old_str_str>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L49
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r13
  cmp    %rax,%rbx
  jbe    L35
  jmp    L33
  nopw   0x0(%rax,%rax,1)
L13:
  add    $0x1,%r12
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rbx,%rax
  jb     L33
L35:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L13
L49:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L33:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *old_str_str(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  l1 = strlen(s1);
  if (!l2)
    return (char *)s1;
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2))
      return (char *)s1;
    s1++;
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<old_str_str>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  mov    %rsi,%rdi
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %rax,%rax
  je     L20
  mov    %r12,%rdi
  mov    %rax,%rbx
  call   <strlen@plt>
  lea    (%r12,%rax,1),%r13
  cmp    %rax,%rbx
  jbe    L3
  jmp    L10
  nopw   0x0(%rax,%rax,1)
L35:
  add    $0x1,%r12
  mov    %r13,%rax
  sub    %r12,%rax
  cmp    %rbx,%rax
  jb     L10
L3:
  mov    %rbx,%rdx
  mov    %rbp,%rsi
  mov    %r12,%rdi
  call   <memcmp@plt>
  test   %eax,%eax
  jne    L35
L20:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nop
L10:
  add    $0x8,%rsp
  xor    %r12d,%r12d
  pop    %rbx
  mov    %r12,%rax
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *old_str_str(const char *s1, const char *s2) {
  size_t l1, l2;
  l2 = strlen(s2);
  l1 = strlen(s1);
  if (!l2)
    return (char *)s1;
  while (l1 >= l2) {
    l1--;
    if (!memcmp(s1, s2, l2))
      return (char *)s1;
    s1++;
  }
  return NULL;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__divdi3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x10(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jns    L14
  notq   -0x10(%rbp)
  negq   -0x18(%rbp)
L14:
  cmpq   $0x0,-0x20(%rbp)
  jns    L3
  notq   -0x10(%rbp)
  negq   -0x20(%rbp)
L3:
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <__udivmoddi4@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x10(%rbp)
  je     L17
  negq   -0x8(%rbp)
L17:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
long long __divdi3(long long u, long long v) {
  long c = 0;
  long long w;
  if (u < 0) {
    c = ~c;
    u = -u;
  }
  if (v < 0) {
    c = ~c;
    v = -v;
  }
  w = __udivmoddi4(u, v, 0);
  if (c)
    w = -w;
  return w;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__divdi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L42
  test   %rsi,%rsi
  js     L36
  mov    $0x0,%edx
  call   <__udivmoddi4@plt>
  jmp    L41
L42:
  neg    %rdi
  test   %rsi,%rsi
  js     L3
  mov    $0x0,%edx
  call   <__udivmoddi4@plt>
L8:
  neg    %rax
L41:
  add    $0x8,%rsp
  ret
L36:
  neg    %rsi
  mov    $0x0,%edx
  call   <__udivmoddi4@plt>
  jmp    L8
L3:
  neg    %rsi
  mov    $0x0,%edx
  call   <__udivmoddi4@plt>
  jmp    L41
```

assistant: ```c
long long __divdi3(long long u, long long v) {
  long c = 0;
  long long w;
  if (u < 0) {
    c = ~c;
    u = -u;
  }
  if (v < 0) {
    c = ~c;
    v = -v;
  }
  w = __udivmoddi4(u, v, 0);
  if (c)
    w = -w;
  return w;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<__divdi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L10
  test   %rsi,%rsi
  js     L1
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <__udivmoddi4@plt>
  nopl   (%rax)
L1:
  neg    %rsi
L0:
  xor    %edx,%edx
  call   <__udivmoddi4@plt>
  add    $0x8,%rsp
  neg    %rax
  ret
  nopw   0x0(%rax,%rax,1)
L10:
  neg    %rdi
  test   %rsi,%rsi
  jns    L0
  neg    %rsi
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <__udivmoddi4@plt>
```

assistant: ```c
long long __divdi3(long long u, long long v) {
  long c = 0;
  long long w;
  if (u < 0) {
    c = ~c;
    u = -u;
  }
  if (v < 0) {
    c = ~c;
    v = -v;
  }
  w = __udivmoddi4(u, v, 0);
  if (c)
    w = -w;
  return w;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<__divdi3>:
  endbr64
  sub    $0x8,%rsp
  test   %rdi,%rdi
  js     L13
  test   %rsi,%rsi
  js     L19
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <__udivmoddi4@plt>
  nopl   (%rax)
L19:
  neg    %rsi
L16:
  xor    %edx,%edx
  call   <__udivmoddi4@plt>
  add    $0x8,%rsp
  neg    %rax
  ret
  nopw   0x0(%rax,%rax,1)
L13:
  neg    %rdi
  test   %rsi,%rsi
  jns    L16
  neg    %rsi
  xor    %edx,%edx
  add    $0x8,%rsp
  jmp    1050 <__udivmoddi4@plt>
```

assistant: ```c
long long __divdi3(long long u, long long v) {
  long c = 0;
  long long w;
  if (u < 0) {
    c = ~c;
    u = -u;
  }
  if (v < 0) {
    c = ~c;
    v = -v;
  }
  w = __udivmoddi4(u, v, 0);
  if (c)
    w = -w;
  return w;
}
```