ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_boolean_option>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x148,%rsp
  mov    %rdi,-0x138(%rbp)
  mov    %esi,-0x13c(%rbp)
  mov    %rdx,-0x148(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movq   $0x0,-0x120(%rbp)
  movq   $0x0,-0x118(%rbp)
  lea    -0x110(%rbp),%rdx
  mov    $0x0,%eax
  mov    $0x1d,%ecx
  mov    %rdx,%rdi
  rep stos %rax,%es:(%rdi)
  mov    %rdi,%rdx
  mov    %eax,(%rdx)
  add    $0x4,%rdx
  mov    %ax,(%rdx)
  add    $0x2,%rdx
  mov    %al,(%rdx)
  add    $0x1,%rdx
  cmpq   $0x0,-0x138(%rbp)
  jne    L67
  mov    $0x0,%eax
  jmp    L63
L67:
  lea    -0x120(%rbp),%rax
  mov    $0xfe,%edx
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x138(%rbp),%rcx
  lea    -0x120(%rbp),%rax
  mov    $0xfe,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncat@plt>
  movl   $0x0,-0x124(%rbp)
  jmp    L44
L62:
  mov    -0x124(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x148(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    -0x120(%rbp),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L40
  mov    -0x124(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x148(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rbx
  lea    -0x120(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jmp    L63
L40:
  addl   $0x1,-0x124(%rbp)
L44:
  mov    -0x124(%rbp),%eax
  cmp    -0x13c(%rbp),%eax
  jl     L62
  mov    $0x0,%eax
L63:
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L31
  call   <__stack_chk_fail@plt>
L31:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D1
type_infered: string

tool: D1: --

assistant: ```c
char *get_boolean_option(const char *option, const int argc, char **argv) {
  int a;
  char temp[255] = "";
  if (option == NULL) {
    return NULL;
  }
  strncpy(temp, "--", sizeof(temp) - 1);
  strncat(temp, option, sizeof(temp) - 1);
  for (a = 0; a < argc; a++) {
    if (strcmp(argv[a], temp) == 0) {
      return (argv[a] + strlen(temp));
    }
  }
  return NULL;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<get_boolean_option>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %rdi,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  lea    0x10(%rsp),%rdi
  mov    $0x1d,%ecx
  rep stos %rax,%es:(%rdi)
  movl   $0x0,(%rdi)
  movw   $0x0,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  test   %rbx,%rbx
  je     L23
  mov    %esi,%ebp
  mov    %rdx,%r12
  mov    %rsp,%r13
  mov    $0xfe,%edx
  lea    D6(%rip),%rsi
  mov    %r13,%rdi
  call   <strncpy@plt>
  mov    $0xfe,%edx
  mov    %rbx,%rsi
  mov    %r13,%rdi
  call   <strncat@plt>
  test   %ebp,%ebp
  jle    L49
  mov    %r12,%rbx
  lea    -0x1(%rbp),%eax
  lea    0x8(%r12,%rax,8),%r13
  mov    %rsp,%rbp
L35:
  mov    %rbp,%rsi
  mov    (%rbx),%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L34
  add    $0x8,%rbx
  cmp    %r13,%rbx
  jne    L35
  mov    $0x0,%eax
  jmp    L5
L34:
  mov    (%rbx),%rbx
  mov    %rsp,%rdi
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
L5:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L74
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L23:
  mov    %rbx,%rax
  jmp    L5
L49:
  mov    $0x0,%eax
  jmp    L5
L74:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D6
type_guessed: string

tool: D6: --

assistant: ```c
char *get_boolean_option(const char *option, const int argc, char **argv) {
  int a;
  char temp[255] = "";
  if (option == NULL) {
    return NULL;
  }
  strncpy(temp, "--", sizeof(temp) - 1);
  strncat(temp, option, sizeof(temp) - 1);
  for (a = 0; a < argc; a++) {
    if (strcmp(argv[a], temp) == 0) {
      return (argv[a] + strlen(temp));
    }
  }
  return NULL;
}
```
user: What is the c source code of the assembly code below?

```asm
<get_boolean_option>:
  endbr64
  push   %r13
  mov    $0x1d,%ecx
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %ax,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  test   %r12,%r12
  je     L15
  mov    %rsp,%rbp
  mov    %esi,%r13d
  lea    D8(%rip),%rsi
  mov    %rdx,%rbx
  mov    %rbp,%rdi
  mov    $0xfe,%edx
  call   <strncpy@plt>
  mov    $0xfe,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  test   %r13d,%r13d
  jle    L15
  lea    -0x1(%r13),%eax
  lea    0x8(%rbx,%rax,8),%r12
  jmp    L41
  xchg   %ax,%ax
L48:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L15
L41:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L48
  mov    %rbp,%rdi
  mov    (%rbx),%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jmp    L47
  nopl   0x0(%rax,%rax,1)
L15:
  xor    %eax,%eax
L47:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L38
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D8
type: string

tool: D8: --

assistant: ```c
char *get_boolean_option(const char *option, const int argc, char **argv) {
  int a;
  char temp[255] = "";
  if (option == NULL) {
    return NULL;
  }
  strncpy(temp, "--", sizeof(temp) - 1);
  strncat(temp, option, sizeof(temp) - 1);
  for (a = 0; a < argc; a++) {
    if (strcmp(argv[a], temp) == 0) {
      return (argv[a] + strlen(temp));
    }
  }
  return NULL;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<get_boolean_option>:
  endbr64
  push   %r13
  mov    $0x1d,%ecx
  pxor   %xmm0,%xmm0
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x118,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rdi
  movaps %xmm0,(%rsp)
  rep stos %rax,%es:(%rdi)
  xor    %eax,%eax
  movl   $0x0,(%rdi)
  mov    %ax,0x4(%rdi)
  movb   $0x0,0x6(%rdi)
  test   %r12,%r12
  je     L52
  mov    %rsp,%rbp
  mov    %esi,%r13d
  lea    D8(%rip),%rsi
  mov    %rdx,%rbx
  mov    %rbp,%rdi
  mov    $0xfe,%edx
  call   <strncpy@plt>
  mov    $0xfe,%edx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strncat@plt>
  test   %r13d,%r13d
  jle    L52
  lea    -0x1(%r13),%eax
  lea    0x8(%rbx,%rax,8),%r12
  jmp    L43
  xchg   %ax,%ax
L32:
  add    $0x8,%rbx
  cmp    %r12,%rbx
  je     L52
L43:
  mov    (%rbx),%rdi
  mov    %rbp,%rsi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L32
  mov    %rbp,%rdi
  mov    (%rbx),%rbx
  call   <strlen@plt>
  cltq
  add    %rbx,%rax
  jmp    L60
  nopl   0x0(%rax,%rax,1)
L52:
  xor    %eax,%eax
L60:
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L57
  add    $0x118,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D8
data_type: string

tool: D8: --

assistant: ```c
char *get_boolean_option(const char *option, const int argc, char **argv) {
  int a;
  char temp[255] = "";
  if (option == NULL) {
    return NULL;
  }
  strncpy(temp, "--", sizeof(temp) - 1);
  strncat(temp, option, sizeof(temp) - 1);
  for (a = 0; a < argc; a++) {
    if (strcmp(argv[a], temp) == 0) {
      return (argv[a] + strlen(temp));
    }
  }
  return NULL;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<show>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    $0x7b,%edi
  call   <putchar@plt>
  jmp    L7
L5:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x4(%rbp)
  jae    L4
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L4:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L5
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D29
datatype: string
name: extract_symbolic_data
arguments: label: D16
datatype: string
name: extract_symbolic_data
arguments: label: D19
datatype: string

tool: D29: %lf

tool: D16: , 

tool: D19: }

assistant: ```c
void show(const double a[], unsigned elements) {
  unsigned i = 0;
  printf("{");
  for (i; i < elements; ++i) {
    printf("%lf", a[i]);
    if (i < elements - 1)
      printf(", ");
  }
  printf("}\n");
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<show>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x7b,%edi
  call   <putchar@plt>
  test   %ebp,%ebp
  je     L17
  lea    -0x1(%rbp),%r14d
  mov    %ebp,%ebp
  mov    $0x0,%ebx
  lea    D5(%rip),%r13
  lea    D19(%rip),%r15
  jmp    L22
L38:
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  je     L17
L22:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %r13,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebx,%r14d
  jbe    L38
  mov    %r15,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L38
L17:
  lea    D3(%rip),%rdi
  call   <puts@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
data_type: string
name: extract_symbolic_data
arguments: data_tag: D19
data_type: string
name: extract_symbolic_data
arguments: data_tag: D3
data_type: string

tool: D5: %lf

tool: D19: , 

tool: D3: }

assistant: ```c
void show(const double a[], unsigned elements) {
  unsigned i = 0;
  printf("{");
  for (i; i < elements; ++i) {
    printf("%lf", a[i]);
    if (i < elements - 1)
      printf(", ");
  }
  printf("}\n");
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<show>:
  endbr64
  push   %r15
  lea    D18(%rip),%r15
  push   %r14
  push   %r13
  push   %r12
  lea    D23(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x7b,%edi
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %esi,0xc(%rsp)
  call   <putchar@plt>
  mov    0xc(%rsp),%r13d
  lea    -0x1(%r13),%r14d
  test   %r13d,%r13d
  je     L13
  nopl   0x0(%rax)
L17:
  movsd  0x0(%rbp,%rbx,8),%xmm0
  mov    %r12,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  cmp    %ebx,%r14d
  jbe    L3
  mov    %r15,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L3:
  add    $0x1,%rbx
  cmp    %r13,%rbx
  jne    L17
L13:
  add    $0x18,%rsp
  lea    D2(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D18
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D23
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D2
type_guessed: string

tool: D18: , 

tool: D23: %lf

tool: D2: }

assistant: ```c
void show(const double a[], unsigned elements) {
  unsigned i = 0;
  printf("{");
  for (i; i < elements; ++i) {
    printf("%lf", a[i]);
    if (i < elements - 1)
      printf(", ");
  }
  printf("}\n");
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<show>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  mov    %rdi,%r13
  mov    $0x7b,%edi
  push   %r12
  mov    %esi,%r12d
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <putchar@plt>
  test   %r12d,%r12d
  je     L31
  mov    %r12d,%ebx
  sub    $0x1,%ebx
  jne    L19
  lea    D18(%rip),%rbp
  cs nopw 0x0(%rax,%rax,1)
L18:
  mov    %ebx,%eax
  mov    %rbp,%rdi
  add    $0x1,%ebx
  movsd  0x0(%r13,%rax,8),%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
L32:
  cmp    %ebx,%r12d
  ja     L18
L31:
  add    $0x18,%rsp
  lea    D1(%rip),%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1080 <puts@plt>
  nopl   0x0(%rax,%rax,1)
L19:
  cmp    %ebx,%r12d
  mov    %r13,%r15
  lea    D18(%rip),%rbp
  cmovbe %r12d,%ebx
  lea    D5(%rip),%r14
  mov    %ebx,0xc(%rsp)
  xor    %ebx,%ebx
  xchg   %ax,%ax
L14:
  movsd  (%r15),%xmm0
  mov    %rbp,%rdi
  mov    $0x1,%eax
  add    $0x1,%ebx
  add    $0x8,%r15
  call   <printf@plt>
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <printf@plt>
  cmp    0xc(%rsp),%ebx
  jb     L14
  jmp    L32
```

tool_calls: name: read_data
arguments: data_tag: D18
datatype: string
name: read_data
arguments: data_tag: D1
datatype: string
name: read_data
arguments: data_tag: D5
datatype: string

tool: D18: %lf

tool: D1: }

tool: D5: , 

assistant: ```c
void show(const double a[], unsigned elements) {
  unsigned i = 0;
  printf("{");
  for (i; i < elements; ++i) {
    printf("%lf", a[i]);
    if (i < elements - 1)
      printf(", ");
  }
  printf("}\n");
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x74(%rbp)
L21:
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x70(%rbp),%eax
  cmp    $0x53,%al
  jne    L22
  movzbl -0x6f(%rbp),%eax
  cmp    $0x54,%al
  jne    L22
  movzbl -0x6e(%rbp),%eax
  cmp    $0x4f,%al
  jne    L22
  movzbl -0x6d(%rbp),%eax
  cmp    $0x50,%al
  je     L47
L22:
  movl   $0x0,-0x78(%rbp)
  jmp    L29
L55:
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x60,%al
  jle    L11
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  cmp    $0x7a,%al
  jg     L11
  mov    -0x78(%rbp),%eax
  cltq
  movzbl -0x70(%rbp,%rax,1),%eax
  sub    $0x20,%eax
  mov    %eax,%edx
  mov    -0x78(%rbp),%eax
  cltq
  mov    %dl,-0x70(%rbp,%rax,1)
L11:
  addl   $0x1,-0x78(%rbp)
L29:
  cmpl   $0x63,-0x78(%rbp)
  jle    L55
  lea    -0x70(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L21
L47:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L82
  call   <__stack_chk_fail@plt>
L82:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D4
type: string

tool: D4: 
%s

assistant: ```c
int main() {
  char words[100];
  int i = 0;
  do {
    scanf("\n%s", words);
    if (words[0] == 'S' && words[1] == 'T' && words[2] == 'O' && words[3] == 'P') {
      break;
    } else {
      int f = 0;
      for (; f < 100; f++) {
        if (words[f] >= 'a' && words[f] <= 'z') {
          words[f] -= 32;
        }
      }
      printf("\n%s", words);
    }
  } while (1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  lea    D1(%rip),%rbx
  jmp    L84
L24:
  cmpb   $0x54,0x1(%rsp)
  jne    L94
  cmpb   $0x4f,0x2(%rsp)
  jne    L94
  cmpb   $0x50,0x3(%rsp)
  jne    L94
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L54
  mov    $0x0,%eax
  add    $0x70,%rsp
  pop    %rbx
  ret
L42:
  add    $0x1,%rax
  cmp    %rsi,%rax
  je     L28
L98:
  movzbl (%rax),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L42
  sub    $0x20,%edx
  mov    %dl,(%rax)
  jmp    L42
L28:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <printf@plt>
L84:
  mov    %rsp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmpb   $0x53,(%rsp)
  je     L24
L94:
  mov    %rsp,%rax
  lea    0x64(%rsp),%rsi
  jmp    L98
L54:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D1
type_guessed: string

tool: D1: 
%s

assistant: ```c
int main() {
  char words[100];
  int i = 0;
  do {
    scanf("\n%s", words);
    if (words[0] == 'S' && words[1] == 'T' && words[2] == 'O' && words[3] == 'P') {
      break;
    } else {
      int f = 0;
      for (; f < 100; f++) {
        if (words[f] >= 'a' && words[f] <= 'z') {
          words[f] -= 32;
        }
      }
      printf("\n%s", words);
    }
  } while (1);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x64(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L13:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movzbl (%rsp),%edx
  cmp    $0x53,%dl
  je     L22
L50:
  mov    %r12,%rax
  jmp    L51
  nopl   0x0(%rax)
L57:
  movzbl (%rax),%edx
L51:
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L8
  sub    $0x20,%edx
  mov    %dl,(%rax)
L8:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L57
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L13
L22:
  cmpb   $0x54,0x1(%rsp)
  jne    L50
  cmpb   $0x4f,0x2(%rsp)
  jne    L50
  cmpb   $0x50,0x3(%rsp)
  jne    L50
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D4
type_infered: string

tool: D4: 
%s

assistant: ```c
int main() {
  char words[100];
  int i = 0;
  do {
    scanf("\n%s", words);
    if (words[0] == 'S' && words[1] == 'T' && words[2] == 'O' && words[3] == 'P') {
      break;
    } else {
      int f = 0;
      for (; f < 100; f++) {
        if (words[f] >= 'a' && words[f] <= 'z') {
          words[f] -= 32;
        }
      }
      printf("\n%s", words);
    }
  } while (1);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  lea    D4(%rip),%rbp
  push   %rbx
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x64(%rsp),%rbx
  nopl   0x0(%rax,%rax,1)
L71:
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  cmpb   $0x53,(%rsp)
  je     L50
L28:
  mov    %r12,%rax
  nopl   0x0(%rax)
L37:
  movzbl (%rax),%edx
  lea    -0x61(%rdx),%ecx
  cmp    $0x19,%cl
  ja     L1
  sub    $0x20,%edx
  mov    %dl,(%rax)
L1:
  add    $0x1,%rax
  cmp    %rbx,%rax
  jne    L37
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <printf@plt>
  jmp    L71
L50:
  cmpb   $0x54,0x1(%rsp)
  jne    L28
  cmpb   $0x4f,0x2(%rsp)
  jne    L28
  cmpb   $0x50,0x3(%rsp)
  jne    L28
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D4
type_infered: string

tool: D4: 
%s

assistant: ```c
int main() {
  char words[100];
  int i = 0;
  do {
    scanf("\n%s", words);
    if (words[0] == 'S' && words[1] == 'T' && words[2] == 'O' && words[3] == 'P') {
      break;
    } else {
      int f = 0;
      for (; f < 100; f++) {
        if (words[f] >= 'a' && words[f] <= 'z') {
          words[f] -= 32;
        }
      }
      printf("\n%s", words);
    }
  } while (1);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0xc(%rbp)
  lea    -0x14(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
L0:
  lea    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x10(%rbp),%eax
  test   %eax,%eax
  je     L47
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  sete   %al
  movzbl %al,%eax
  add    %eax,-0xc(%rbp)
  jmp    L0
L47:
  nop
  cmpl   $0x0,-0xc(%rbp)
  je     L18
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L5
L18:
  lea    D12(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L5:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L41
  call   <__stack_chk_fail@plt>
L41:
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: data_label: D9
type_infered: string
name: disassemble_data
arguments: data_label: D12
type_infered: string

tool: D9: %d

tool: D12: None

assistant: ```c
int main() {
  int target, in, sum = 0;
  scanf("%d", &target);
  while (1) {
    scanf("%d", &in);
    if (!in) {
      break;
    }
    sum += (target == in) ? 1 : 0;
  }
  if (sum) {
    printf("%d", sum);
  } else {
    printf("None");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    D33(%rip),%rdi
  call   <scanf@plt>
  mov    $0x0,%ebx
  lea    D33(%rip),%rbp
  jmp    L28
L15:
  cmp    %eax,(%rsp)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebx
L28:
  lea    0x4(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L15
  test   %ebx,%ebx
  je     L39
  mov    %ebx,%esi
  lea    D33(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L12:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L39:
  lea    D34(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L12
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D33
type: string
name: disassemble_data
arguments: tag: D34
type: string

tool: D33: %d

tool: D34: None

assistant: ```c
int main() {
  int target, in, sum = 0;
  scanf("%d", &target);
  while (1) {
    scanf("%d", &in);
    if (!in) {
      break;
    }
    sum += (target == in) ? 1 : 0;
  }
  if (sum) {
    printf("%d", sum);
  } else {
    printf("None");
  }
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %r12
  lea    D5(%rip),%r12
  push   %rbp
  mov    %r12,%rdi
  xor    %ebp,%ebp
  push   %rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rsi
  lea    0x4(%rsp),%rbx
  call   <scanf@plt>
  jmp    L27
  nopw   0x0(%rax,%rax,1)
L41:
  cmp    %eax,(%rsp)
  sete   %al
  movzbl %al,%eax
  add    %eax,%ebp
L27:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jne    L41
  test   %ebp,%ebp
  je     L35
  mov    %ebp,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <printf@plt>
L15:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L35:
  lea    D11(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L15
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D5
type_infered: string
name: extract_symbolic_data
arguments: data_label: D11
type_infered: string

tool: D5: %d

tool: D11: None

assistant: ```c
int main() {
  int target, in, sum = 0;
  scanf("%d", &target);
  while (1) {
    scanf("%d", &in);
    if (!in) {
      break;
    }
    sum += (target == in) ? 1 : 0;
  }
  if (sum) {
    printf("%d", sum);
  } else {
    printf("None");
  }
  return 0;
}
```