ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here?

```asm
<write_block>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x4b0,%esi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %ecx,%edx
  lea    0x80(%rbx),%r13
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  movl   $0xffffffff,0x4(%rsp)
  mov    %r15,%rcx
  call   <write_bits@plt>
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %r14,%rdi
  mov    $0x258,%esi
  mov    %rax,%rbp
  call   <write_bits@plt>
  movzbl %r12b,%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  add    %rax,%rbp
  xor    %r12d,%r12d
  call   <write_byte@plt>
  add    %rax,%rbp
  xchg   %ax,%ax
L19:
  movzbl (%rbx),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  add    $0x1,%rbx
  add    %esi,%r12d
  call   <write_byte@plt>
  add    %rax,%rbp
  cmp    %r13,%rbx
  jne    L19
  movzbl %r12b,%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  call   <write_byte@plt>
  add    %rbp,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L11
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long write_block(FILE *out, int block, unsigned char *buf, int sync_bits) {
  int a;
  int sync = -1;
  long flen = 0;
  unsigned char crc = 0;
  flen += write_bits(out, (1200), sync_bits, &sync);
  flen += write_bits(out, (600), 1, &sync);
  flen += write_byte(out, block, &sync);
  for (a = 0; a < 128; a++) {
    crc += buf[a];
    flen += write_byte(out, buf[a], &sync);
  }
  flen += write_byte(out, crc, &sync);
  return flen;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<write_block>:
  endbr64
  push   %r15
  push   %r14
  mov    %rdi,%r14
  push   %r13
  push   %r12
  mov    %esi,%r12d
  mov    $0x4b0,%esi
  push   %rbp
  push   %rbx
  mov    %rdx,%rbx
  mov    %ecx,%edx
  lea    0x80(%rbx),%r13
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r15
  movl   $0xffffffff,0x4(%rsp)
  mov    %r15,%rcx
  call   <write_bits@plt>
  mov    %r15,%rcx
  mov    $0x1,%edx
  mov    %r14,%rdi
  mov    $0x258,%esi
  mov    %rax,%rbp
  call   <write_bits@plt>
  movzbl %r12b,%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  add    %rax,%rbp
  xor    %r12d,%r12d
  call   <write_byte@plt>
  add    %rax,%rbp
  xchg   %ax,%ax
L3:
  movzbl (%rbx),%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  add    $0x1,%rbx
  add    %esi,%r12d
  call   <write_byte@plt>
  add    %rax,%rbp
  cmp    %r13,%rbx
  jne    L3
  movzbl %r12b,%esi
  mov    %r15,%rdx
  mov    %r14,%rdi
  call   <write_byte@plt>
  add    %rbp,%rax
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long write_block(FILE *out, int block, unsigned char *buf, int sync_bits) {
  int a;
  int sync = -1;
  long flen = 0;
  unsigned char crc = 0;
  flen += write_bits(out, (1200), sync_bits, &sync);
  flen += write_bits(out, (600), 1, &sync);
  flen += write_byte(out, block, &sync);
  for (a = 0; a < 128; a++) {
    crc += buf[a];
    flen += write_byte(out, buf[a], &sync);
  }
  flen += write_byte(out, crc, &sync);
  return flen;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<m_burn>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  je     L19
  jmp    L21
L12:
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x8(%rbp)
  movb   $0x0,(%rax)
L21:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L12
  jmp    L10
L19:
  nop
L10:
  pop    %rbp
  ret
```

assistant: ```c
void m_burn(void *data, unsigned int len) {
  volatile char *p = data;
  if (data == NULL)
    return;
  while (len--) {
    *p++ = 0x0;
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<m_burn>:
  endbr64
  test   %rdi,%rdi
  je     L10
  lea    -0x1(%rsi),%eax
  test   %esi,%esi
  je     L10
  mov    %eax,%eax
  lea    0x1(%rdi,%rax,1),%rdx
L21:
  mov    %rdi,%rax
  add    $0x1,%rdi
  movb   $0x0,(%rax)
  cmp    %rdi,%rdx
  jne    L21
L10:
  ret
```

assistant: ```c
void m_burn(void *data, unsigned int len) {
  volatile char *p = data;
  if (data == NULL)
    return;
  while (len--) {
    *p++ = 0x0;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<m_burn>:
  endbr64
  test   %rdi,%rdi
  je     L26
  test   %esi,%esi
  je     L26
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rax
  nopl   0x0(%rax,%rax,1)
L20:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  movb   $0x0,(%rdx)
  cmp    %rdi,%rax
  jne    L20
L26:
  ret
```

assistant: ```c
void m_burn(void *data, unsigned int len) {
  volatile char *p = data;
  if (data == NULL)
    return;
  while (len--) {
    *p++ = 0x0;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<m_burn>:
  endbr64
  test   %rdi,%rdi
  je     L27
  test   %esi,%esi
  je     L27
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%rax
  nopl   0x0(%rax,%rax,1)
L14:
  mov    %rdi,%rdx
  add    $0x1,%rdi
  movb   $0x0,(%rdx)
  cmp    %rdi,%rax
  jne    L14
L27:
  ret
```

assistant: ```c
void m_burn(void *data, unsigned int len) {
  volatile char *p = data;
  if (data == NULL)
    return;
  while (len--) {
    *p++ = 0x0;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<write_partition_physical_disk_drive_id_fat16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movb   $0x80,-0x9(%rbp)
  lea    -0x9(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    $0x1,%ecx
  mov    $0x24,%esi
  mov    %rax,%rdi
  call   <write_data@plt>
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L9
  call   <__stack_chk_fail@plt>
L9:
  leave
  ret
```

assistant: ```c
int write_partition_physical_disk_drive_id_fat16(FILE *fp) {
  unsigned char ucId = 0x80;
  return write_data(fp, 0x24, &ucId, 1);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_partition_physical_disk_drive_id_fat16>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  movb   $0x80,0x7(%rsp)
  lea    0x7(%rsp),%rdx
  mov    $0x1,%ecx
  mov    $0x24,%esi
  call   <write_data@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_partition_physical_disk_drive_id_fat16(FILE *fp) {
  unsigned char ucId = 0x80;
  return write_data(fp, 0x24, &ucId, 1);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<write_partition_physical_disk_drive_id_fat16>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%ecx
  mov    $0x24,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdx
  movb   $0x80,0x7(%rsp)
  call   <write_data@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_partition_physical_disk_drive_id_fat16(FILE *fp) {
  unsigned char ucId = 0x80;
  return write_data(fp, 0x24, &ucId, 1);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<write_partition_physical_disk_drive_id_fat16>:
  endbr64
  sub    $0x18,%rsp
  mov    $0x1,%ecx
  mov    $0x24,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x7(%rsp),%rdx
  movb   $0x80,0x7(%rsp)
  call   <write_data@plt>
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L2
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int write_partition_physical_disk_drive_id_fat16(FILE *fp) {
  unsigned char ucId = 0x80;
  return write_data(fp, 0x24, &ucId, 1);
}
```
user: What is the c source code of the assembly code below:

```asm
<rbits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L3
L5:
  mov    $0x0,%eax
  call   <unif_rand@plt>
  shl    $0x10,%eax
  mov    %eax,%edi
  call   <floor@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  shl    $0x10,%eax
  mov    %eax,%edx
  mov    -0x4(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  addl   $0x10,-0x8(%rbp)
L3:
  mov    -0x8(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jle    L5
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x14(%rbp),%eax
  mov    $0x1,%esi
  mov    %eax,%ecx
  shl    %cl,%rsi
  mov    %rsi,%rax
  sub    $0x1,%rax
  and    %rdx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

assistant: ```c
double rbits(int bits) {
  int_least64_t v = 0;
  for (int n = 0; n <= bits; n += 16) {
    int v1 = (int)floor(unif_rand() * 65536);
    v = 65536 * v + v1;
  }
  return (double)(v & ((1L << bits) - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<rbits>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edi,%r12d
  test   %edi,%edi
  js     L23
  mov    $0x0,%ebp
  mov    $0x0,%ebx
L5:
  mov    $0x0,%eax
  call   <unif_rand@plt>
  shl    $0x10,%eax
  mov    %eax,%edi
  call   <floor@plt>
  shl    $0x10,%ebx
  add    %eax,%ebx
  add    $0x10,%ebp
  cmp    %ebp,%r12d
  jge    L5
L17:
  mov    $0x1,%eax
  mov    %r12d,%ecx
  shl    %cl,%rax
  sub    $0x1,%rax
  movslq %ebx,%rbx
  and    %rbx,%rax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L23:
  mov    $0x0,%ebx
  jmp    L17
```

assistant: ```c
double rbits(int bits) {
  int_least64_t v = 0;
  for (int n = 0; n <= bits; n += 16) {
    int v1 = (int)floor(unif_rand() * 65536);
    v = 65536 * v + v1;
  }
  return (double)(v & ((1L << bits) - 1));
}
```
user: Translate the below assembly code into C programming language:

```asm
<rbits>:
  endbr64
  push   %r13
  mov    %edi,%ecx
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  shl    %cl,%r12
  push   %rbx
  sub    $0x1,%r12
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L0
  mov    %edi,%r13d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L1:
  xor    %eax,%eax
  shl    $0x10,%ebx
  add    $0x10,%ebp
  call   <unif_rand@plt>
  shl    $0x10,%eax
  mov    %eax,%edi
  call   <floor@plt>
  add    %eax,%ebx
  cmp    %ebp,%r13d
  jge    L1
  movslq %ebx,%rbx
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  and    %r12,%rbx
  cvtsi2sd %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double rbits(int bits) {
  int_least64_t v = 0;
  for (int n = 0; n <= bits; n += 16) {
    int v1 = (int)floor(unif_rand() * 65536);
    v = 65536 * v + v1;
  }
  return (double)(v & ((1L << bits) - 1));
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<rbits>:
  endbr64
  push   %r13
  mov    %edi,%ecx
  push   %r12
  mov    $0x1,%r12d
  push   %rbp
  shl    %cl,%r12
  push   %rbx
  sub    $0x1,%r12
  sub    $0x8,%rsp
  test   %edi,%edi
  js     L2
  mov    %edi,%r13d
  xor    %ebp,%ebp
  xor    %ebx,%ebx
  nopl   0x0(%rax,%rax,1)
L12:
  xor    %eax,%eax
  shl    $0x10,%ebx
  add    $0x10,%ebp
  call   <unif_rand@plt>
  shl    $0x10,%eax
  mov    %eax,%edi
  call   <floor@plt>
  add    %eax,%ebx
  cmp    %ebp,%r13d
  jge    L12
  movslq %ebx,%rbx
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  and    %r12,%rbx
  cvtsi2sd %rbx,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  add    $0x8,%rsp
  pxor   %xmm0,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
double rbits(int bits) {
  int_least64_t v = 0;
  for (int n = 0; n <= bits; n += 16) {
    int v1 = (int)floor(unif_rand() * 65536);
    v = 65536 * v + v1;
  }
  return (double)(v & ((1L << bits) - 1));
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<seatest_assert_string_contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x18000(%rsp),%r11
L10:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L10
  sub    $0x6d0,%rsp
  mov    %rdi,-0x186b8(%rbp)
  mov    %rsi,-0x186c0(%rbp)
  mov    %rdx,-0x186c8(%rbp)
  mov    %ecx,-0x186cc(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x186c0(%rbp),%rcx
  mov    -0x186b8(%rbp),%rdx
  lea    -0x186b0(%rbp),%rax
  lea    D7(%rip),%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  mov    -0x186b8(%rbp),%rdx
  mov    -0x186c0(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %al
  movzbl %al,%eax
  mov    -0x186cc(%rbp),%ecx
  mov    -0x186c8(%rbp),%rdx
  lea    -0x186b0(%rbp),%rsi
  mov    %eax,%edi
  call   <seatest_simple_test_result@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L12
  call   <__stack_chk_fail@plt>
L12:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D7
type: string

tool: D7: Expected "%s" to be in "%s"

assistant: ```c
void seatest_assert_string_contains(const char *expected, const char *actual, const char *function, unsigned int line) {
  char s[100000];
  sprintf(s, "Expected \"%s\" to be in \"%s\"", expected, actual);
  seatest_simple_test_result(strstr(actual, expected) != 0, s, function, line);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<seatest_assert_string_contains>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x18000(%rsp),%r11
L11:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L11
  sub    $0x6b0,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%rbx
  mov    %rdx,%r12
  mov    %ecx,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r14
  mov    %rsi,%rcx
  mov    %rdi,%rdx
  lea    D6(%rip),%rsi
  mov    %r14,%rdi
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strstr@plt>
  test   %rax,%rax
  setne  %dil
  movzbl %dil,%edi
  mov    %r13d,%ecx
  mov    %r12,%rdx
  mov    %r14,%rsi
  call   <seatest_simple_test_result@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x186b0,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: Expected "%s" to be in "%s"

assistant: ```c
void seatest_assert_string_contains(const char *expected, const char *actual, const char *function, unsigned int line) {
  char s[100000];
  sprintf(s, "Expected \"%s\" to be in \"%s\"", expected, actual);
  seatest_simple_test_result(strstr(actual, expected) != 0, s, function, line);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<seatest_assert_string_contains>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x18000(%rsp),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0x6b0,%rsp
  mov    %rsp,%r15
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  mov    %ecx,%r14d
  mov    %r15,%rdi
  mov    %rsi,%rcx
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  xor    %edi,%edi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  test   %rax,%rax
  mov    %r15,%rsi
  setne  %dil
  call   <seatest_simple_test_result@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x186b0,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D0
type_infered: string

tool: D0: Expected "%s" to be in "%s"

assistant: ```c
void seatest_assert_string_contains(const char *expected, const char *actual, const char *function, unsigned int line) {
  char s[100000];
  sprintf(s, "Expected \"%s\" to be in \"%s\"", expected, actual);
  seatest_simple_test_result(strstr(actual, expected) != 0, s, function, line);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<seatest_assert_string_contains>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  lea    -0x18000(%rsp),%r11
L13:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L13
  sub    $0x6b0,%rsp
  mov    %rsp,%r15
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %rdx,%r13
  mov    %fs:0x28,%rax
  mov    %rax,0x186a8(%rsp)
  xor    %eax,%eax
  mov    %rdi,%rdx
  mov    %ecx,%r14d
  mov    %r15,%rdi
  mov    %rsi,%rcx
  lea    D0(%rip),%rsi
  call   <sprintf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strstr@plt>
  xor    %edi,%edi
  mov    %r14d,%ecx
  mov    %r13,%rdx
  test   %rax,%rax
  mov    %r15,%rsi
  setne  %dil
  call   <seatest_simple_test_result@plt>
  mov    0x186a8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x186b0,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L14:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D0
type_infered: string

tool: D0: Expected "%s" to be in "%s"

assistant: ```c
void seatest_assert_string_contains(const char *expected, const char *actual, const char *function, unsigned int line) {
  char s[100000];
  sprintf(s, "Expected \"%s\" to be in \"%s\"", expected, actual);
  seatest_simple_test_result(strstr(actual, expected) != 0, s, function, line);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<string_reduce>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L78
L14:
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L26
L64:
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  mov    %al,-0x19(%rbp)
  cmpb   $0x24,-0x19(%rbp)
  je     L65
  mov    -0x18(%rbp),%eax
  lea    0x1(%rax),%edx
  movsbl -0x19(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <matching_char_position@plt>
  mov    %eax,-0xc(%rbp)
  cmpl   $0xffffffff,-0xc(%rbp)
  je     L2
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x24,(%rax)
  mov    -0x18(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x8(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  movl   $0x1,-0x14(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L26
L2:
  addl   $0x1,-0x18(%rbp)
  jmp    L26
L65:
  addl   $0x1,-0x18(%rbp)
L26:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x18(%rbp)
  jl     L64
L78:
  cmpl   $0x1,-0x14(%rbp)
  je     L14
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <compress_string@plt>
  leave
  ret
```

assistant: ```c
int string_reduce(char *string) {
  char *iter = string;
  int i = 0, j = 0;
  int found = 1;
  while (found == 1) {
    found = 0;
    iter = string;
    i = 0;
    while (i < strlen(string)) {
      char c = iter[i];
      if (c != '$') {
        int j = matching_char_position(string, c, i + 1);
        if (j != -1) {
          iter[i] = iter[j] = '$';
          found = 1;
          i = j + 1;
        } else
          i++;
      } else
        i++;
    }
  }
  return compress_string(string);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<string_reduce>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    $0x1,%r14d
  jmp    L5
L7:
  add    $0x1,%ebx
  movsbl %sil,%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  call   <matching_char_position@plt>
  cmp    $0xffffffff,%eax
  je     L30
  movslq %eax,%rdx
  movb   $0x24,(%r12,%rdx,1)
  movb   $0x24,0x0(%rbp)
  lea    0x1(%rax),%ebx
  mov    %r14d,%r13d
L30:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L64
  movslq %ebx,%rbp
  add    %r12,%rbp
  movzbl 0x0(%rbp),%esi
  cmp    $0x24,%sil
  jne    L7
  add    $0x1,%ebx
  jmp    L30
L64:
  cmp    $0x1,%r13d
  jne    L17
L5:
  mov    $0x0,%r13d
  mov    $0x0,%ebx
  jmp    L30
L17:
  mov    %r12,%rdi
  call   <compress_string@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int string_reduce(char *string) {
  char *iter = string;
  int i = 0, j = 0;
  int found = 1;
  while (found == 1) {
    found = 0;
    iter = string;
    i = 0;
    while (i < strlen(string)) {
      char c = iter[i];
      if (c != '$') {
        int j = matching_char_position(string, c, i + 1);
        if (j != -1) {
          iter[i] = iter[j] = '$';
          found = 1;
          i = j + 1;
        } else
          i++;
      } else
        i++;
    }
  }
  return compress_string(string);
}
```
user: What is the c source code of the assembly code below:

```asm
<string_reduce>:
  endbr64
  push   %r13
  mov    %rdi,%r13
  push   %r12
  xor    %r12d,%r12d
  push   %rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L36:
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L44
L61:
  movslq %ebx,%rbp
  add    $0x1,%ebx
  add    %r13,%rbp
  movsbl 0x0(%rbp),%esi
  cmp    $0x24,%sil
  je     L36
  mov    %ebx,%edx
  mov    %r13,%rdi
  call   <matching_char_position@plt>
  cmp    $0xffffffff,%eax
  je     L36
  movslq %eax,%rdx
  mov    %r13,%rdi
  lea    0x1(%rax),%ebx
  mov    $0x1,%r12d
  movb   $0x24,0x0(%r13,%rdx,1)
  movb   $0x24,0x0(%rbp)
  call   <strlen@plt>
  cmp    %eax,%ebx
  jl     L61
L30:
  mov    %r13,%rdi
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  call   <strlen@plt>
  test   %eax,%eax
  jg     L61
L39:
  add    $0x8,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1070 <compress_string@plt>
  nopl   0x0(%rax,%rax,1)
L44:
  cmp    $0x1,%r12d
  je     L30
  jmp    L39
```

assistant: ```c
int string_reduce(char *string) {
  char *iter = string;
  int i = 0, j = 0;
  int found = 1;
  while (found == 1) {
    found = 0;
    iter = string;
    i = 0;
    while (i < strlen(string)) {
      char c = iter[i];
      if (c != '$') {
        int j = matching_char_position(string, c, i + 1);
        if (j != -1) {
          iter[i] = iter[j] = '$';
          found = 1;
          i = j + 1;
        } else
          i++;
      } else
        i++;
    }
  }
  return compress_string(string);
}
```