ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 下面的汇编指令对应的C源代码是什么：

```asm
<internal_fiat_poly1305_carry>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  mov    %rsi,%rbp
  mov    $0x8,%esi
  push   %rbx
  mov    %rdi,%rbx
  mov    %ebp,%edi
  sub    $0x8,%rsp
  call   <_br2_load@plt>
  lea    0x8(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r12
  call   <_br2_load@plt>
  lea    0x10(%rbp),%edi
  mov    $0x8,%esi
  mov    %rax,%r13
  call   <_br2_load@plt>
  mov    %r12,%rdx
  mov    %ebx,%edi
  shr    $0x2c,%rdx
  mov    %rax,%r8
  add    %r13,%rdx
  movabs $0x7ffffffffff,%r13
  mov    %rdx,%rax
  and    %r13,%rdx
  shr    $0x2b,%rax
  add    %r8,%rax
  mov    %rax,%rcx
  and    %r13,%rax
  shr    $0x2b,%rcx
  lea    (%rcx,%rcx,4),%rsi
  movabs $0xfffffffffff,%rcx
  and    %rcx,%r12
  add    %r12,%rsi
  mov    %rsi,%rbp
  and    %rcx,%rsi
  shr    $0x2c,%rbp
  add    %rdx,%rbp
  mov    $0x8,%edx
  mov    %rbp,%r12
  shr    $0x2b,%r12
  add    %rax,%r12
  call   <_br2_store@plt>
  mov    %rbp,%rsi
  lea    0x8(%rbx),%edi
  mov    $0x8,%edx
  and    %r13,%rsi
  call   <_br2_store@plt>
  add    $0x8,%rsp
  lea    0x10(%rbx),%edi
  mov    %r12,%rsi
  pop    %rbx
  mov    $0x8,%edx
  pop    %rbp
  pop    %r12
  pop    %r13
  jmp    1060 <_br2_store@plt>
```

assistant: ```c
void internal_fiat_poly1305_carry(uintptr_t out0, uintptr_t in0) {
  uintptr_t x0, x1, x2, x3, x4, x6, x7, x5, x8, x9, x10, x11, x12, x13;
  x0 = _br2_load((in0) + ((uintptr_t)0ULL), sizeof(uintptr_t));
  x1 = _br2_load((in0) + ((uintptr_t)8ULL), sizeof(uintptr_t));
  x2 = _br2_load((in0) + ((uintptr_t)16ULL), sizeof(uintptr_t));
  x3 = x0;
  x4 = ((x3) >> ((uintptr_t)44ULL)) + (x1);
  x5 = ((x4) >> ((uintptr_t)43ULL)) + (x2);
  x6 = ((x3) & ((uintptr_t)17592186044415ULL)) + (((x5) >> ((uintptr_t)43ULL)) * ((uintptr_t)5ULL));
  x7 = ((x6) >> ((uintptr_t)44ULL)) + ((x4) & ((uintptr_t)8796093022207ULL));
  x8 = (x6) & ((uintptr_t)17592186044415ULL);
  x9 = (x7) & ((uintptr_t)8796093022207ULL);
  x10 = ((x7) >> ((uintptr_t)43ULL)) + ((x5) & ((uintptr_t)8796093022207ULL));
  x11 = x8;
  x12 = x9;
  x13 = x10;
  _br2_store((out0) + ((uintptr_t)0ULL), x11, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)8ULL), x12, sizeof(uintptr_t));
  _br2_store((out0) + ((uintptr_t)16ULL), x13, sizeof(uintptr_t));
  return;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x38,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x18(%rbp)
  xor    %eax,%eax
  movl   $0x1,-0x38(%rbp)
  movl   $0x0,-0x34(%rbp)
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movzbl -0x20(%rbp),%eax
  movsbl %al,%eax
  lea    -0x30(%rax),%ebx
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <CheckISBN@plt>
  movsbl %al,%eax
  cmp    %eax,%ebx
  je     L55
  movl   $0x5,-0x38(%rbp)
L55:
  lea    -0x30(%rbp),%rax
  mov    $0x4,%edx
  lea    D19(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L30
  lea    -0x30(%rbp),%rax
  mov    $0x4,%edx
  lea    D13(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L30
  movl   $0x0,-0x38(%rbp)
L30:
  movl   $0x0,-0x3c(%rbp)
  jmp    L2
L76:
  mov    -0x3c(%rbp),%eax
  cltq
  movzbl -0x30(%rbp,%rax,1),%eax
  cmp    $0x2d,%al
  je     L11
  addl   $0x1,-0x34(%rbp)
L11:
  addl   $0x1,-0x3c(%rbp)
L2:
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  cmp    %eax,-0x3c(%rbp)
  jl     L76
  cmpl   $0xd,-0x34(%rbp)
  je     L38
  movl   $0x0,-0x38(%rbp)
L38:
  mov    -0x38(%rbp),%eax
  mov    %eax,%esi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  cmpl   $0x1,-0x38(%rbp)
  jne    L62
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <CheckBrand@plt>
L62:
  mov    $0x0,%eax
  mov    -0x18(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L20
  call   <__stack_chk_fail@plt>
L20:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D14
type_infered: string
name: retrieve_data
arguments: tag: D19
type_infered: string
name: retrieve_data
arguments: tag: D13
type_infered: string
name: retrieve_data
arguments: tag: D17
type_infered: string

tool: D14: %s

tool: D19: 978-

tool: D13: 979-

tool: D17: %d

assistant: ```c
int main() {
  int i, end = 1, shit = 0;
  char a[20];
  scanf("%s", a);
  if ((a[16] - '0') != CheckISBN(a))
    end = 5;
  if (strncmp(a, "978-", 4) != 0 && strncmp(a, "979-", 4) != 0)
    end = 0;
  for (i = 0; i < strlen(a); i++)
    if (a[i] != '-')
      shit++;
  if (shit != 13)
    end = 0;
  printf("%d", end);
  if (end == 1)
    CheckBrand(a);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%ebx
  sub    $0x30,%ebx
  mov    %rbp,%rdi
  call   <CheckISBN@plt>
  movsbl %al,%eax
  cmp    %eax,%ebx
  setne  %r13b
  movzbl %r13b,%r13d
  lea    0x1(,%r13,4),%r13d
  mov    %rsp,%rdi
  mov    $0x4,%edx
  lea    D35(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L8
L33:
  mov    $0x0,%ebx
  mov    $0x0,%ebp
  mov    %rsp,%r12
  jmp    L51
L8:
  mov    %rsp,%rdi
  mov    $0x4,%edx
  lea    D24(%rip),%rsi
  call   <strncmp@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %eax,%r13d
  jmp    L33
L7:
  cmpb   $0x2d,(%rbx,%r12,1)
  setne  %al
  movzbl %al,%eax
  add    %eax,%ebp
  add    $0x1,%rbx
L51:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  cmp    $0xd,%ebp
  je     L35
  mov    $0x0,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
L42:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L38
  mov    $0x0,%eax
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L35:
  mov    %r13d,%esi
  lea    D29(%rip),%rdi
  call   <printf@plt>
  cmp    $0x1,%r13d
  jne    L42
  mov    %rsp,%rdi
  call   <CheckBrand@plt>
  jmp    L42
L38:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D8
type_infered: string
name: retrieve_data
arguments: label: D35
type_infered: string
name: retrieve_data
arguments: label: D24
type_infered: string
name: retrieve_data
arguments: label: D29
type_infered: string

tool: D8: %s

tool: D35: 978-

tool: D24: 979-

tool: D29: %d

assistant: ```c
int main() {
  int i, end = 1, shit = 0;
  char a[20];
  scanf("%s", a);
  if ((a[16] - '0') != CheckISBN(a))
    end = 5;
  if (strncmp(a, "978-", 4) != 0 && strncmp(a, "979-", 4) != 0)
    end = 0;
  for (i = 0; i < strlen(a); i++)
    if (a[i] != '-')
      shit++;
  if (shit != 13)
    end = 0;
  printf("%d", end);
  if (end == 1)
    CheckBrand(a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D18(%rip),%rdi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%ebx
  mov    %rbp,%rdi
  call   <CheckISBN@plt>
  mov    $0x4,%edx
  lea    D19(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x30,%ebx
  movsbl %al,%eax
  cmp    %eax,%ebx
  setne  %r13b
  lea    0x1(,%r13,4),%r13d
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L44
L19:
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L78
  nopl   0x0(%rax)
L53:
  xor    %eax,%eax
  cmpb   $0x2d,0x0(%rbp,%rbx,1)
  setne  %al
  add    $0x1,%rbx
  add    %eax,%r12d
L78:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L53
  cmp    $0xd,%r12d
  je     L74
  xor    %esi,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
L75:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L41
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L74:
  mov    %r13d,%esi
  lea    D39(%rip),%rdi
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L75
  mov    %rbp,%rdi
  call   <CheckBrand@plt>
  jmp    L75
L44:
  mov    $0x4,%edx
  lea    D27(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %eax,%r13d
  jmp    L19
L41:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D18
data_type: string
name: read_data
arguments: data_tag: D19
data_type: string
name: read_data
arguments: data_tag: D39
data_type: string
name: read_data
arguments: data_tag: D27
data_type: string

tool: D18: %s

tool: D19: 978-

tool: D39: %d

tool: D27: 979-

assistant: ```c
int main() {
  int i, end = 1, shit = 0;
  char a[20];
  scanf("%s", a);
  if ((a[16] - '0') != CheckISBN(a))
    end = 5;
  if (strncmp(a, "978-", 4) != 0 && strncmp(a, "979-", 4) != 0)
    end = 0;
  for (i = 0; i < strlen(a); i++)
    if (a[i] != '-')
      shit++;
  if (shit != 13)
    end = 0;
  printf("%d", end);
  if (end == 1)
    CheckBrand(a);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  lea    D34(%rip),%rdi
  xor    %r13d,%r13d
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  call   <scanf@plt>
  movsbl 0x10(%rsp),%ebx
  mov    %rbp,%rdi
  call   <CheckISBN@plt>
  mov    $0x4,%edx
  lea    D36(%rip),%rsi
  mov    %rbp,%rdi
  sub    $0x30,%ebx
  movsbl %al,%eax
  cmp    %eax,%ebx
  setne  %r13b
  lea    0x1(,%r13,4),%r13d
  call   <strncmp@plt>
  test   %rax,%rax
  jne    L37
L30:
  xor    %ebx,%ebx
  xor    %r12d,%r12d
  jmp    L61
  nopl   0x0(%rax)
L7:
  xor    %eax,%eax
  cmpb   $0x2d,0x0(%rbp,%rbx,1)
  setne  %al
  add    $0x1,%rbx
  add    %eax,%r12d
L61:
  mov    %rbp,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L7
  cmp    $0xd,%r12d
  je     L71
  xor    %esi,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
L63:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L71:
  mov    %r13d,%esi
  lea    D3(%rip),%rdi
  call   <printf@plt>
  sub    $0x1,%r13d
  jne    L63
  mov    %rbp,%rdi
  call   <CheckBrand@plt>
  jmp    L63
L37:
  mov    $0x4,%edx
  lea    D42(%rip),%rsi
  mov    %rbp,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  mov    $0x0,%eax
  cmovne %eax,%r13d
  jmp    L30
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D34
datatype: string
name: unpack_data
arguments: label: D36
datatype: string
name: unpack_data
arguments: label: D3
datatype: string
name: unpack_data
arguments: label: D42
datatype: string

tool: D34: %s

tool: D36: 978-

tool: D3: %d

tool: D42: 979-

assistant: ```c
int main() {
  int i, end = 1, shit = 0;
  char a[20];
  scanf("%s", a);
  if ((a[16] - '0') != CheckISBN(a))
    end = 5;
  if (strncmp(a, "978-", 4) != 0 && strncmp(a, "979-", 4) != 0)
    end = 0;
  for (i = 0; i < strlen(a); i++)
    if (a[i] != '-')
      shit++;
  if (shit != 13)
    end = 0;
  printf("%d", end);
  if (end == 1)
    CheckBrand(a);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<compute_row_thresholds>:
  endbr64
  test   %ecx,%ecx
  jle    L27
  push   %rbp
  push   %rbx
  mov    %rdx,%r9
  add    $0x1,%rdi
  mov    %ecx,%ecx
  lea    (%rsi,%rcx,2),%rcx
  jmp    L4
L43:
  mov    %r11b,-0x1(%rdi)
  add    $0x1,%rdi
  cmp    %rcx,%rsi
  je     L0
L4:
  movzbl 0x2(%rsi),%edx
  movzbl (%rsi),%eax
  cmp    %al,%dl
  cmova  %eax,%edx
  movzbl 0x3(%rsi),%eax
  movzbl 0x1(%rsi),%r10d
  cmp    %r10b,%al
  cmovb  %r10d,%eax
  add    $0x2,%rsi
  movzbl (%r9),%ebp
  movzbl 0x1(%r9),%r11d
  movzbl 0x2(%r9),%ebx
  movzbl 0x3(%r9),%r10d
  add    $0x2,%r9
  cmp    %bpl,%dl
  cmova  %ebp,%edx
  cmp    %bl,%dl
  cmova  %ebx,%edx
  movzbl %dl,%edx
  cmp    %r11b,%al
  cmovb  %r11d,%eax
  cmp    %r10b,%al
  cmovb  %r10d,%eax
  movzbl %al,%eax
  lea    (%rdx,%rax,1),%r10d
  sar    %r10d
  mov    %r10d,%r11d
  sub    %edx,%eax
  cmp    %r8d,%eax
  jge    L43
  cmp    $0x7e,%r10b
  setbe  %r11b
  neg    %r11d
  jmp    L43
L0:
  pop    %rbx
  pop    %rbp
  ret
L27:
  ret
```

assistant: ```c
void compute_row_thresholds(unsigned char *thresholds_dest, const unsigned char *min_max_a, const unsigned char *min_max_b, int count, int contrast_threshold) {
  int i;
  unsigned char min_a, max_a, min_b, max_b;
  unsigned char test_threshold;
  for (i = count; i > 0; --i) {
    min_a = min_max_a[0];
    max_a = min_max_a[1];
    if (min_max_a[2] < min_a)
      min_a = min_max_a[2];
    if (min_max_a[3] > max_a)
      max_a = min_max_a[3];
    min_max_a += 2;
    min_b = min_max_b[0];
    max_b = min_max_b[1];
    if (min_max_b[2] < min_b)
      min_b = min_max_b[2];
    if (min_max_b[3] > max_b)
      max_b = min_max_b[3];
    min_max_b += 2;
    if (min_b < min_a)
      min_a = min_b;
    if (max_b > max_a)
      max_a = max_b;
    test_threshold = (unsigned char)((min_a + max_a) / 2);
    if ((max_a - min_a) < contrast_threshold) {
      if (test_threshold < 127)
        *thresholds_dest++ = ((unsigned char)255);
      else
        *thresholds_dest++ = ((unsigned char)0);
    } else {
      *thresholds_dest++ = test_threshold;
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<compute_row_thresholds>:
  endbr64
  movslq %ecx,%r10
  add    %rdi,%r10
  test   %ecx,%ecx
  jle    L23
  push   %rbp
  mov    %rdx,%r9
  push   %rbx
  nopw   0x0(%rax,%rax,1)
L4:
  movzbl (%rsi),%eax
  movzbl 0x2(%rsi),%edx
  movzbl 0x1(%rsi),%ecx
  movzbl (%r9),%ebp
  cmp    %al,%dl
  movzbl 0x1(%r9),%r11d
  movzbl 0x2(%r9),%ebx
  cmova  %eax,%edx
  movzbl 0x3(%rsi),%eax
  cmp    %cl,%al
  cmovb  %ecx,%eax
  movzbl 0x3(%r9),%ecx
  add    $0x2,%rsi
  add    $0x2,%r9
  cmp    %bpl,%dl
  cmova  %ebp,%edx
  cmp    %bl,%dl
  cmova  %ebx,%edx
  cmp    %r11b,%al
  cmovb  %r11d,%eax
  cmp    %cl,%al
  cmovb  %ecx,%eax
  add    $0x1,%rdi
  lea    (%rdx,%rax,1),%ecx
  sub    %edx,%eax
  sar    %ecx
  mov    %ecx,%edx
  cmp    %r8d,%eax
  jge    L5
  cmp    $0x7e,%ecx
  setle  %dl
  neg    %edx
L5:
  mov    %dl,-0x1(%rdi)
  cmp    %rdi,%r10
  jne    L4
  pop    %rbx
  pop    %rbp
  ret
L23:
  ret
```

assistant: ```c
void compute_row_thresholds(unsigned char *thresholds_dest, const unsigned char *min_max_a, const unsigned char *min_max_b, int count, int contrast_threshold) {
  int i;
  unsigned char min_a, max_a, min_b, max_b;
  unsigned char test_threshold;
  for (i = count; i > 0; --i) {
    min_a = min_max_a[0];
    max_a = min_max_a[1];
    if (min_max_a[2] < min_a)
      min_a = min_max_a[2];
    if (min_max_a[3] > max_a)
      max_a = min_max_a[3];
    min_max_a += 2;
    min_b = min_max_b[0];
    max_b = min_max_b[1];
    if (min_max_b[2] < min_b)
      min_b = min_max_b[2];
    if (min_max_b[3] > max_b)
      max_b = min_max_b[3];
    min_max_b += 2;
    if (min_b < min_a)
      min_a = min_b;
    if (max_b > max_a)
      max_a = max_b;
    test_threshold = (unsigned char)((min_a + max_a) / 2);
    if ((max_a - min_a) < contrast_threshold) {
      if (test_threshold < 127)
        *thresholds_dest++ = ((unsigned char)255);
      else
        *thresholds_dest++ = ((unsigned char)0);
    } else {
      *thresholds_dest++ = test_threshold;
    }
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<show_handler>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%esi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L9
L4:
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  addl   $0x1,-0x4(%rbp)
L9:
  cmpl   $0x4,-0x4(%rbp)
  jle    L4
  nop
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D15
type_infered: string
name: parse_data
arguments: label: D4
type_infered: string

tool: D15: %d


tool: D4: i = %d


assistant: ```c
void show_handler(int s) {
  printf("%d\n", s);
  int i;
  for (i = 0; i < 5; i++) {
    printf("i = %d\n", i);
    sleep(1);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<show_handler>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%esi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%ebx
  lea    D13(%rip),%rbp
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D17
data_type: string
name: extract_symbolic_data
arguments: label: D13
data_type: string

tool: D17: %d


tool: D13: i = %d


assistant: ```c
void show_handler(int s) {
  printf("%d\n", s);
  int i;
  for (i = 0; i < 5; i++) {
    printf("i = %d\n", i);
    sleep(1);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<show_handler>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  lea    D14(%rip),%rdi
  lea    D2(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L1:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x5,%ebx
  jne    L1
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D2
data_type: string

tool: D14: %d


tool: D2: i = %d


assistant: ```c
void show_handler(int s) {
  printf("%d\n", s);
  int i;
  for (i = 0; i < 5; i++) {
    printf("i = %d\n", i);
    sleep(1);
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<show_handler>:
  endbr64
  push   %rbp
  mov    %edi,%esi
  lea    D2(%rip),%rdi
  lea    D13(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <printf@plt>
L9:
  mov    %ebx,%esi
  mov    %rbp,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  cmp    $0x5,%ebx
  jne    L9
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_tag: D2
datatype: string
name: read_data
arguments: data_tag: D13
datatype: string

tool: D2: %d


tool: D13: i = %d


assistant: ```c
void show_handler(int s) {
  printf("%d\n", s);
  int i;
  for (i = 0; i < 5; i++) {
    printf("i = %d\n", i);
    sleep(1);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x10(%rbp),%rcx
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L130
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jl     L143
L130:
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L147
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L147
L143:
  mov    -0x18(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L147:
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L112
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jl     L104
L112:
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jge    L60
  mov    -0x14(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L60
L104:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  jmp    L1
L60:
  mov    -0x18(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L109
  mov    -0x10(%rbp),%edx
  mov    -0x14(%rbp),%eax
  cmp    %eax,%edx
  jl     L43
L109:
  mov    -0x14(%rbp),%edx
  mov    -0x10(%rbp),%eax
  cmp    %eax,%edx
  jge    L1
  mov    -0x10(%rbp),%edx
  mov    -0x18(%rbp),%eax
  cmp    %eax,%edx
  jge    L1
L43:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L1:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D26(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L139
  call   <__stack_chk_fail@plt>
L139:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D6
type_guessed: string
name: extract_symbolic_data
arguments: label: D3
type_guessed: string
name: extract_symbolic_data
arguments: label: D26
type_guessed: string

tool: D6: Please enter 3 numbers separated by spaces > 

tool: D3: %d%d%d

tool: D26: %d is the median


assistant: ```c
int main() {
  int a, b, c, z;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if ((b < a && a < c) || (c < a && a < b))
    z = a;
  else if ((a < b && b < c) || (c < b && b < a))
    z = b;
  else if ((a < c && c < b) || (b < c && c < a))
    z = c;
  printf("%d is the median\n", z);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D4(%rip),%rdi
  call   <printf@plt>
  lea    0x14(%rsp),%rcx
  lea    0x10(%rsp),%rdx
  lea    0xc(%rsp),%rsi
  lea    D21(%rip),%rdi
  call   <scanf@plt>
  mov    0x10(%rsp),%eax
  mov    0xc(%rsp),%esi
  cmp    %esi,%eax
  jge    L108
  mov    0x14(%rsp),%edx
  cmp    %edx,%esi
  jl     L104
  setg   %dil
  cmp    %edx,%eax
  setl   %r8b
  setg   %cl
  cmp    %esi,%eax
  jge    L124
  test   %cl,%cl
  je     L124
  mov    %eax,%esi
  jmp    L104
L108:
  mov    0x14(%rsp),%edx
  setg   %cl
  cmp    %edx,%esi
  setg   %dil
  test   %cl,%cl
  je     L152
  test   %dil,%dil
  je     L152
L104:
  lea    D2(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L22:
  mov    %edx,%esi
  jmp    L104
L35:
  cmp    %edx,%eax
  setg   %cl
L124:
  cmp    %edx,%esi
  jge    L146
  test   %cl,%cl
  jne    L22
L146:
  test   %r8b,%r8b
  je     L104
  test   %dil,%dil
  cmovne %edx,%esi
  jmp    L104
L152:
  cmp    %edx,%eax
  setl   %r8b
  test   %cl,%cl
  je     L35
  test   %r8b,%r8b
  je     L35
  mov    %eax,%esi
  jmp    L104
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string
name: retrieve_data
arguments: data_tag: D21
type: string
name: retrieve_data
arguments: data_tag: D2
type: string

tool: D4: Please enter 3 numbers separated by spaces > 

tool: D21: %d%d%d

tool: D2: %d is the median


assistant: ```c
int main() {
  int a, b, c, z;
  printf("Please enter 3 numbers separated by spaces > ");
  scanf("%d%d%d", &a, &b, &c);
  if ((b < a && a < c) || (c < a && a < b))
    z = a;
  else if ((a < b && b < c) || (c < b && b < a))
    z = b;
  else if ((a < c && c < b) || (b < c && c < a))
    z = c;
  printf("%d is the median\n", z);
  return 0;
}
```