ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<distance_l2_m128d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r12
  mov    %rsi,%r13
  mov    %edx,%r14d
  mov    %edx,%r15d
  shr    $0x1f,%r15d
  add    %edx,%r15d
  sar    %r15d
  cmp    $0x1,%edx
  jle    L17
  mov    $0x0,%ebx
  mov    $0x0,%ebp
L67:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    (%r12,%rbx,8),%rdi
  call   <_mm_sub_pd@plt>
  mov    %rax,%rdi
  mov    %rax,%rsi
  call   <_mm_mul_pd@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  call   <_mm_add_pd@plt>
  mov    %rax,%rbp
  add    $0x1,%rbx
  cmp    %ebx,%r15d
  jg     L67
  test   %r15d,%r15d
  mov    $0x1,%eax
  cmovle %eax,%r15d
L14:
  movsd  0x0(%rbp),%xmm0
  addsd  0x8(%rbp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    %r15d,%r15d
  cmp    %r15d,%r14d
  jle    L28
  movslq %r15d,%rbx
  sub    $0x1,%r14d
  sub    %r15d,%r14d
  lea    0x1(%rbx,%r14,1),%rbp
L46:
  movsd  (%r12,%rbx,8),%xmm0
  subsd  0x0(%r13,%rbx,8),%xmm0
  mov    $0x2,%edi
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L46
L28:
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm2
  ucomisd %xmm2,%xmm0
  ja     L20
  sqrtsd %xmm2,%xmm2
  movapd %xmm2,%xmm0
L4:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L17:
  mov    $0x0,%r15d
  mov    $0x0,%ebp
  jmp    L14
L20:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L4
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  ret = sum[0] + sum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<distance_l2_m128d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x18,%rsp
  cmp    $0x1,%edx
  jle    10e0 <distance_l2_m128d.cold>
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %edx,%r12d
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L41:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    (%r15,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <_mm_sub_pd@plt>
  mov    %rax,%rdi
  mov    %rax,%rsi
  call   <_mm_mul_pd@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <_mm_add_pd@plt>
  mov    %rax,%r14
  cmp    %ebx,%ebp
  jg     L41
  test   %ebp,%ebp
  mov    $0x1,%eax
  movsd  (%r14),%xmm1
  addsd  0x8(%r14),%xmm1
  cmovle %eax,%ebp
  add    %ebp,%ebp
  cmp    %ebp,%r12d
  jle    L40
  movslq %ebp,%rax
  sub    $0x1,%r12d
  sub    %ebp,%r12d
  lea    0x1(%rax),%rbx
  add    %rbx,%r12
  jmp    L7
  nopl   (%rax)
L48:
  add    $0x1,%rbx
L7:
  movsd  (%r15,%rax,8),%xmm0
  subsd  0x0(%r13,%rax,8),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  mov    %rbx,%rax
  addsd  %xmm0,%xmm1
  cmp    %rbx,%r12
  jne    L48
L40:
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L18
  sqrtsd %xmm1,%xmm1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm1,%xmm0
  pop    %r14
  pop    %r15
  ret
L18:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <sqrt@plt>
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  ret = sum[0] + sum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<distance_l2_m128d>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  shr    $0x1f,%ebp
  add    %edx,%ebp
  sar    %ebp
  sub    $0x18,%rsp
  cmp    $0x1,%edx
  jle    10e0 <distance_l2_m128d.cold>
  mov    %rdi,%r15
  mov    %rsi,%r13
  mov    %edx,%r12d
  xor    %ebx,%ebx
  xor    %r14d,%r14d
  nopw   0x0(%rax,%rax,1)
L19:
  mov    0x0(%r13,%rbx,8),%rsi
  mov    (%r15,%rbx,8),%rdi
  add    $0x1,%rbx
  call   <_mm_sub_pd@plt>
  mov    %rax,%rdi
  mov    %rax,%rsi
  call   <_mm_mul_pd@plt>
  mov    %r14,%rdi
  mov    %eax,%esi
  call   <_mm_add_pd@plt>
  mov    %rax,%r14
  cmp    %ebx,%ebp
  jg     L19
  test   %ebp,%ebp
  mov    $0x1,%eax
  movsd  (%r14),%xmm1
  addsd  0x8(%r14),%xmm1
  cmovle %eax,%ebp
  add    %ebp,%ebp
  cmp    %ebp,%r12d
  jle    L3
  movslq %ebp,%rax
  sub    $0x1,%r12d
  sub    %ebp,%r12d
  lea    0x1(%rax),%rbx
  add    %rbx,%r12
  jmp    L27
  nopl   (%rax)
L5:
  add    $0x1,%rbx
L27:
  movsd  (%r15,%rax,8),%xmm0
  subsd  0x0(%r13,%rax,8),%xmm0
  mov    $0x2,%edi
  movsd  %xmm1,0x8(%rsp)
  call   <pow@plt>
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm1
  cvtsi2sd %rax,%xmm0
  mov    %rbx,%rax
  addsd  %xmm0,%xmm1
  cmp    %rbx,%r12
  jne    L5
L3:
  pxor   %xmm0,%xmm0
  ucomisd %xmm1,%xmm0
  ja     L21
  sqrtsd %xmm1,%xmm1
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  movapd %xmm1,%xmm0
  pop    %r14
  pop    %r15
  ret
L21:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1090 <sqrt@plt>
```

assistant: ```c
double distance_l2_m128d(__m128d *p1, __m128d *p2, int len) {
  double ret = 0;
  __m128d sum = {0, 0};
  int i = 0;
  for (i = 0; i < len / 2; i++) {
    __m128d diff;
    diff = _mm_sub_pd(p1[i], p2[i]);
    sum = _mm_add_pd(sum, _mm_mul_pd(diff, diff));
  }
  ret = sum[0] + sum[1];
  for (i *= 2; i < len; i++) {
    ret += pow(((double *)p1)[i] - ((double *)p2)[i], 2);
  }
  return sqrt(ret);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<AND_zp>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <c64_memZero@plt>
  mov    $0x0,%eax
  call   <AND_@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AND_zp(void) {
  c64_memZero();
  AND_();
}
```
user: Translate the below assembly code into C programming language:

```asm
<AND_zp>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <c64_memZero@plt>
  mov    $0x0,%eax
  call   <AND_@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void AND_zp(void) {
  c64_memZero();
  AND_();
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<AND_zp>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memZero@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <AND_@plt>
```

assistant: ```c
void AND_zp(void) {
  c64_memZero();
  AND_();
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<AND_zp>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <c64_memZero@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <AND_@plt>
```

assistant: ```c
void AND_zp(void) {
  c64_memZero();
  AND_();
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D20(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  shl    $0x2,%eax
  mov    %eax,%edi
  call   <malloc@plt>
  mov    %rax,-0x10(%rbp)
  lea    D35(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L2
L8:
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L2:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L8
  lea    D31(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  movl   $0x0,-0x1c(%rbp)
  jmp    L32
L6:
  lea    D43(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x10(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D52(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x1c(%rbp)
L32:
  mov    -0x20(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jl     L6
  mov    -0x20(%rbp),%edx
  mov    -0x10(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <produto_escalar@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L45
  call   <__stack_chk_fail@plt>
L45:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D20
data_type: string
name: retrieve_data
arguments: data_tag: D52
data_type: string
name: retrieve_data
arguments: data_tag: D35
data_type: string
name: retrieve_data
arguments: data_tag: D11
data_type: string
name: retrieve_data
arguments: data_tag: D31
data_type: string
name: retrieve_data
arguments: data_tag: D43
data_type: string

tool: D20: Digite o tamanho do vetor


tool: D52: %d

tool: D35: primeiro vetor


tool: D11: digite o valor  


tool: D31: segundo vetor


tool: D43: digite o valor


assistant: ```c
int main(int argc, const char *argv[]) {
  int *x, *y, tamanho, i;
  printf("Digite o tamanho do vetor\n");
  scanf("%d", &tamanho);
  x = (int *)malloc(sizeof(int) * tamanho);
  y = (int *)malloc(sizeof(int) * tamanho);
  printf("primeiro vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor  \n");
    scanf("%d", &x[i]);
  }
  printf("segundo vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor\n");
    scanf("%d", &y[i]);
  }
  produto_escalar(x, y, tamanho);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D29(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r12
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  lea    D46(%rip),%rdi
  call   <printf@plt>
  cmpl   $0x0,0x4(%rsp)
  jle    L22
  mov    %r12,%rbp
  mov    $0x0,%ebx
  lea    D13(%rip),%r15
  lea    D10(%rip),%r14
L43:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  add    $0x4,%rbp
  cmp    %ebx,0x4(%rsp)
  jg     L43
L22:
  lea    D23(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L0
  mov    %r13,%rbp
  mov    $0x0,%ebx
  lea    D49(%rip),%r15
  lea    D10(%rip),%r14
L16:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <scanf@plt>
  add    $0x1,%ebx
  mov    0x4(%rsp),%edx
  add    $0x4,%rbp
  cmp    %ebx,%edx
  jg     L16
L0:
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <produto_escalar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D29
data_type: string
name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D46
data_type: string
name: unpack_data
arguments: label: D13
data_type: string
name: unpack_data
arguments: label: D23
data_type: string
name: unpack_data
arguments: label: D49
data_type: string

tool: D29: Digite o tamanho do vetor


tool: D10: %d

tool: D46: primeiro vetor


tool: D13: digite o valor  


tool: D23: segundo vetor


tool: D49: digite o valor


assistant: ```c
int main(int argc, const char *argv[]) {
  int *x, *y, tamanho, i;
  printf("Digite o tamanho do vetor\n");
  scanf("%d", &tamanho);
  x = (int *)malloc(sizeof(int) * tamanho);
  y = (int *)malloc(sizeof(int) * tamanho);
  printf("primeiro vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor  \n");
    scanf("%d", &x[i]);
  }
  printf("segundo vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor\n");
    scanf("%d", &y[i]);
  }
  produto_escalar(x, y, tamanho);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  lea    D43(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D46(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D37(%rip),%rdi
  mov    %rax,%r14
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L47
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D41(%rip),%r15
  nopl   0x0(%rax,%rax,1)
L7:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L7
L47:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L32
  mov    %r14,%rbp
  xor    %ebx,%ebx
  lea    D1(%rip),%r15
L34:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L34
L32:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <produto_escalar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D43
type_infered: string
name: parse_data
arguments: tag: D46
type_infered: string
name: parse_data
arguments: tag: D37
type_infered: string
name: parse_data
arguments: tag: D41
type_infered: string
name: parse_data
arguments: tag: D12
type_infered: string
name: parse_data
arguments: tag: D1
type_infered: string

tool: D43: Digite o tamanho do vetor


tool: D46: %d

tool: D37: primeiro vetor


tool: D41: digite o valor  


tool: D12: segundo vetor


tool: D1: digite o valor


assistant: ```c
int main(int argc, const char *argv[]) {
  int *x, *y, tamanho, i;
  printf("Digite o tamanho do vetor\n");
  scanf("%d", &tamanho);
  x = (int *)malloc(sizeof(int) * tamanho);
  y = (int *)malloc(sizeof(int) * tamanho);
  printf("primeiro vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor  \n");
    scanf("%d", &x[i]);
  }
  printf("segundo vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor\n");
    scanf("%d", &y[i]);
  }
  produto_escalar(x, y, tamanho);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %r15
  lea    D48(%rip),%rdi
  push   %r14
  push   %r13
  push   %r12
  lea    D10(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  mov    %rax,%r13
  mov    0x4(%rsp),%eax
  lea    0x0(,%rax,4),%edi
  call   <malloc@plt>
  lea    D40(%rip),%rdi
  mov    %rax,%r14
  call   <printf@plt>
  mov    0x4(%rsp),%eax
  test   %eax,%eax
  jle    L35
  mov    %r13,%rbp
  xor    %ebx,%ebx
  lea    D31(%rip),%r15
  nopl   0x0(%rax,%rax,1)
L18:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  cmp    %ebx,0x4(%rsp)
  jg     L18
L35:
  lea    D28(%rip),%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edx
  test   %edx,%edx
  jle    L41
  mov    %r14,%rbp
  xor    %ebx,%ebx
  lea    D57(%rip),%r15
L23:
  mov    %r15,%rdi
  add    $0x1,%ebx
  call   <printf@plt>
  mov    %rbp,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbp
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  cmp    %ebx,%edx
  jg     L23
L41:
  mov    %r14,%rsi
  mov    %r13,%rdi
  call   <produto_escalar@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D48
datatype: string
name: extract_symbolic_data
arguments: data_label: D10
datatype: string
name: extract_symbolic_data
arguments: data_label: D40
datatype: string
name: extract_symbolic_data
arguments: data_label: D31
datatype: string
name: extract_symbolic_data
arguments: data_label: D28
datatype: string
name: extract_symbolic_data
arguments: data_label: D57
datatype: string

tool: D48: Digite o tamanho do vetor


tool: D10: %d

tool: D40: primeiro vetor


tool: D31: digite o valor  


tool: D28: segundo vetor


tool: D57: digite o valor


assistant: ```c
int main(int argc, const char *argv[]) {
  int *x, *y, tamanho, i;
  printf("Digite o tamanho do vetor\n");
  scanf("%d", &tamanho);
  x = (int *)malloc(sizeof(int) * tamanho);
  y = (int *)malloc(sizeof(int) * tamanho);
  printf("primeiro vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor  \n");
    scanf("%d", &x[i]);
  }
  printf("segundo vetor\n");
  for (i = 0; i < tamanho; i++) {
    printf("digite o valor\n");
    scanf("%d", &y[i]);
  }
  produto_escalar(x, y, tamanho);
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0xc(%rbp),%xmm0
  cvtss2sd %xmm0,%xmm0
  movsd  D38(%rip),%xmm1
  divsd  %xmm1,%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  lea    D16(%rip),%rax
  mov    %rax,%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D4
type_guessed: string
name: unpack_data
arguments: label: D15
type_guessed: string
name: unpack_data
arguments: label: D38
type_guessed: f64
name: unpack_data
arguments: label: D16
type_guessed: string

tool: D4: km/h: 

tool: D15: %f

tool: D38: 3.6

tool: D16: m/s: %.2f

assistant: ```c
int main() {
  float velocidade;
  printf("km/h: ");
  scanf("%f", &velocidade);
  printf("m/s: %.2f", velocidade / 3.6);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D6(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  lea    D2(%rip),%rdi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  cvtss2sd 0x4(%rsp),%xmm0
  divsd  D0(%rip),%xmm0
  lea    D17(%rip),%rdi
  mov    $0x1,%eax
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D2
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D0
type_infered: f64
name: extract_symbolic_data
arguments: data_tag: D17
type_infered: string

tool: D6: km/h: 

tool: D2: %f

tool: D0: 3.6

tool: D17: m/s: %.2f

assistant: ```c
int main() {
  float velocidade;
  printf("km/h: ");
  scanf("%f", &velocidade);
  printf("m/s: %.2f", velocidade / 3.6);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D18(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D6(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D29(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  divsd  D26(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D18
data_type: string
name: unpack_data
arguments: tag: D6
data_type: string
name: unpack_data
arguments: tag: D29
data_type: string
name: unpack_data
arguments: tag: D26
data_type: f64

tool: D18: km/h: 

tool: D6: %f

tool: D29: m/s: %.2f

tool: D26: 3.6

assistant: ```c
int main() {
  float velocidade;
  printf("km/h: ");
  scanf("%f", &velocidade);
  printf("m/s: %.2f", velocidade / 3.6);
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D14(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    D2(%rip),%rdi
  lea    0x4(%rsp),%rsi
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    $0x1,%eax
  lea    D32(%rip),%rdi
  cvtss2sd 0x4(%rsp),%xmm0
  divsd  D4(%rip),%xmm0
  call   <printf@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D14
data_type: string
name: unpack_data
arguments: tag: D2
data_type: string
name: unpack_data
arguments: tag: D32
data_type: string
name: unpack_data
arguments: tag: D4
data_type: f64

tool: D14: km/h: 

tool: D2: %f

tool: D32: m/s: %.2f

tool: D4: 3.6

assistant: ```c
int main() {
  float velocidade;
  printf("km/h: ");
  scanf("%f", &velocidade);
  printf("m/s: %.2f", velocidade / 3.6);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rdx
  lea    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <f@plt>
  test   %rax,%rax
  je     L4
  mov    $0x0,%eax
  call   <abort@plt>
L4:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L15
  call   <__stack_chk_fail@plt>
L15:
  leave
  ret
```

assistant: ```c
int main() {
  union {
    long l;
    int i;
  } a;
  if (f(&a.i, &a.l) != 0)
    abort();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rdi,%rsi
  call   <f@plt>
  test   %rax,%rax
  jne    L25
L22:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L25:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L22
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  union {
    long l;
    int i;
  } a;
  if (f(&a.i, &a.l) != 0)
    abort();
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    %rdi,%rsi
  call   <f@plt>
  test   %rax,%rax
  jne    L29
L9:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L29:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L9
L2:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int main() {
  union {
    long l;
    int i;
  } a;
  if (f(&a.i, &a.l) != 0)
    abort();
  return 0;
}
```