user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D46(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x4,%edx
  mov    $0x3,%esi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L50
L33:
  movl   $0x0,-0x74(%rbp)
  jmp    L79
L16:
  lea    -0x70(%rbp),%rdx
  mov    -0x74(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x78(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rcx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    %rax,%rsi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  addl   $0x1,-0x74(%rbp)
L79:
  cmpl   $0x3,-0x74(%rbp)
  jle    L16
  addl   $0x1,-0x78(%rbp)
L50:
  cmpl   $0x2,-0x78(%rbp)
  jle    L33
  movl   $0x0,-0x78(%rbp)
  jmp    L28
L98:
  movl   $0x0,-0x74(%rbp)
  jmp    L5
L6:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x78(%rbp),%eax
  cltq
  shl    $0x2,%rax
  add    %rdx,%rax
  mov    -0x70(%rbp,%rax,4),%edx
  mov    -0x78(%rbp),%eax
  movslq %eax,%rsi
  mov    -0x74(%rbp),%eax
  movslq %eax,%rcx
  mov    %rcx,%rax
  add    %rax,%rax
  add    %rcx,%rax
  add    %rsi,%rax
  mov    %edx,-0x40(%rbp,%rax,4)
  addl   $0x1,-0x74(%rbp)
L5:
  cmpl   $0x3,-0x74(%rbp)
  jle    L6
  addl   $0x1,-0x78(%rbp)
L28:
  cmpl   $0x2,-0x78(%rbp)
  jle    L98
  lea    D36(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x3,%edx
  mov    $0x4,%esi
  lea    D34(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  movl   $0x0,-0x78(%rbp)
  jmp    L56
L57:
  movl   $0x0,-0x74(%rbp)
  jmp    L68
L59:
  mov    -0x74(%rbp),%eax
  movslq %eax,%rcx
  mov    -0x78(%rbp),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  add    %rax,%rax
  add    %rdx,%rax
  add    %rcx,%rax
  mov    -0x40(%rbp,%rax,4),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x74(%rbp)
L68:
  cmpl   $0x2,-0x74(%rbp)
  jle    L59
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x78(%rbp)
L56:
  cmpl   $0x3,-0x78(%rbp)
  jle    L57
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D46
data_type: string
name: retrieve_data
arguments: tag: D23
data_type: string
name: retrieve_data
arguments: tag: D6
data_type: string
name: retrieve_data
arguments: tag: D36
data_type: string
name: retrieve_data
arguments: tag: D34
data_type: string
name: retrieve_data
arguments: tag: D7
data_type: string

tool: D46: Enter elements of the matrixA,

tool: D23: %d*%d:


tool: D6: %d

tool: D36: MatrixB,

tool: D34: %d*%d


tool: D7: %8d

assistant: ```c
main() {
  int matrixA[3][4], matrixB[4][3];
  int i, j;
  printf("Enter elements of the matrixA,");
  printf("%d*%d:\n", 3, 4);
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      scanf("%d", &matrixA[i][j]);
    }
  }
  for (i = 0; i < 3; i++) {
    for (j = 0; j < 4; j++) {
      matrixB[j][i] = matrixA[i][j];
    }
  }
  printf("MatrixB,");
  printf("%d*%d\n", 4, 3);
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 3; j++) {
      printf("%8d", matrixB[i][j]);
    }
    printf("\n");
  }
}
```