ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
  mov    $0x0,%r13d
  lea    D15(%rip),%r12
L25:
  lea    -0x10(%rbp),%rbx
L27:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  add    $0x4,%rbx
  cmp    %rbp,%rbx
  jne    L27
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x4,%r13
  add    $0x10,%rbp
  cmp    $0x10,%r13
  jne    L25
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    $0x4,%esi
  call   <transpose@plt>
  mov    %rax,%r14
  mov    %rax,%r13
  lea    0x20(%rax),%r15
  lea    D2(%rip),%r12
L36:
  mov    %r13,%rbp
  mov    $0x0,%ebx
L22:
  mov    0x0(%rbp),%rax
  mov    (%rax,%rbx,1),%esi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x4,%rbx
  cmp    $0x10,%rbx
  jne    L22
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x8,%r13
  cmp    %r13,%r15
  jne    L36
  mov    %r14,%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x1,%eax
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D15
type: string
name: unpack_data
arguments: label: D2
type: string

tool: D15: %d

tool: D2:  %4d 

assistant: ```c
int main() {
  int i = 0, j = 0;
  int matrix[4][4];
  for (; i < 4; i++) {
    for (j = 0; j < 4; j++)
      scanf("%d", &matrix[i][j]);
    printf("\n");
  }
  int **a = (int(**))transpose(&matrix[0][0], 4, 4);
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++)
      printf(" %4d ", a[i][j]);
    printf("\n");
  }
  free(a);
  return 1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D7(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
L33:
  lea    -0x10(%rbp),%rbx
L36:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L36
  mov    $0xa,%edi
  add    $0x4,%r13
  lea    0x10(%rbx),%rbp
  call   <putchar@plt>
  cmp    $0x10,%r13
  jne    L33
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    $0x4,%esi
  call   <transpose@plt>
  lea    D8(%rip),%rbp
  mov    %rax,%r12
  mov    %rax,%r14
  lea    0x20(%rax),%r13
L32:
  xor    %ebx,%ebx
L34:
  mov    (%r14),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x10,%rbx
  jne    L34
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r14,%r13
  jne    L32
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L42
  add    $0x50,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L42:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D7
data_type: string
name: unpack_data
arguments: data_label: D8
data_type: string

tool: D7: %d

tool: D8:  %4d 

assistant: ```c
int main() {
  int i = 0, j = 0;
  int matrix[4][4];
  for (; i < 4; i++) {
    for (j = 0; j < 4; j++)
      scanf("%d", &matrix[i][j]);
    printf("\n");
  }
  int **a = (int(**))transpose(&matrix[0][0], 4, 4);
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++)
      printf(" %4d ", a[i][j]);
    printf("\n");
  }
  free(a);
  return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %r14
  push   %r13
  xor    %r13d,%r13d
  push   %r12
  lea    D3(%rip),%r12
  push   %rbp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rbp
L25:
  lea    -0x10(%rbp),%rbx
L11:
  mov    %rbx,%rsi
  mov    %r12,%rdi
  add    $0x4,%rbx
  call   <scanf@plt>
  cmp    %rbp,%rbx
  jne    L11
  mov    $0xa,%edi
  add    $0x4,%r13
  lea    0x10(%rbx),%rbp
  call   <putchar@plt>
  cmp    $0x10,%r13
  jne    L25
  mov    %rsp,%rdi
  mov    $0x4,%edx
  mov    $0x4,%esi
  call   <transpose@plt>
  lea    D10(%rip),%rbp
  mov    %rax,%r12
  mov    %rax,%r14
  lea    0x20(%rax),%r13
L36:
  xor    %ebx,%ebx
L14:
  mov    (%r14),%rax
  mov    %rbp,%rdi
  mov    (%rax,%rbx,1),%esi
  xor    %eax,%eax
  add    $0x4,%rbx
  call   <printf@plt>
  cmp    $0x10,%rbx
  jne    L14
  mov    $0xa,%edi
  add    $0x8,%r14
  call   <putchar@plt>
  cmp    %r14,%r13
  jne    L36
  mov    %r12,%rdi
  call   <free@plt>
  mov    0x48(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L20
  add    $0x50,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L20:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: tag: D3
type_guessed: string
name: unpack_data
arguments: tag: D10
type_guessed: string

tool: D3: %d

tool: D10:  %4d 

assistant: ```c
int main() {
  int i = 0, j = 0;
  int matrix[4][4];
  for (; i < 4; i++) {
    for (j = 0; j < 4; j++)
      scanf("%d", &matrix[i][j]);
    printf("\n");
  }
  int **a = (int(**))transpose(&matrix[0][0], 4, 4);
  for (i = 0; i < 4; i++) {
    for (j = 0; j < 4; j++)
      printf(" %4d ", a[i][j]);
    printf("\n");
  }
  free(a);
  return 1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D3
type_guessed: string

tool: D3: NHDP compiled!

assistant: ```c
int main(void) {
  printf("NHDP compiled!");
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D8: NHDP compiled!

assistant: ```c
int main(void) {
  printf("NHDP compiled!");
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D5
type_infered: string

tool: D5: NHDP compiled!

assistant: ```c
int main(void) {
  printf("NHDP compiled!");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D4(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: tag: D4
type: string

tool: D4: NHDP compiled!

assistant: ```c
int main(void) {
  printf("NHDP compiled!");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_microseconds>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  je     L10
  mov    $0x0,%eax
  call   <abort@plt>
L10:
  mov    -0x18(%rbp),%rax
  imul   $0xf4240,%rax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

assistant: ```c
long long get_microseconds(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    abort();
  return ((long long)tv.tv_sec) * 1000000LL + (long long)tv.tv_usec;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<get_microseconds>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  test   %rax,%rax
  jne    L18
L16:
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L18:
  mov    $0x0,%eax
  call   <abort@plt>
  jmp    L16
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_microseconds(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    abort();
  return ((long long)tv.tv_sec) * 1000000LL + (long long)tv.tv_usec;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<get_microseconds>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  jne    L4
L15:
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L3
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L4:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L15
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_microseconds(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    abort();
  return ((long long)tv.tv_sec) * 1000000LL + (long long)tv.tv_usec;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<get_microseconds>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  test   %rax,%rax
  jne    L5
L6:
  imul   $0xf4240,0x8(%rsp),%rax
  add    (%rsp),%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L15
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax)
L5:
  xor    %eax,%eax
  call   <abort@plt>
  jmp    L6
L15:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long get_microseconds(void) {
  struct timeval tv;
  if (gettimeofday(&tv, NULL) != 0)
    abort();
  return ((long long)tv.tv_sec) * 1000000LL + (long long)tv.tv_usec;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rotateL_fun_int32_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x8(%rbp),%eax
  cltd
  shr    $0x1b,%edx
  add    %edx,%eax
  and    $0x1f,%eax
  sub    %edx,%eax
  mov    %eax,-0x8(%rbp)
  cmpl   $0x0,-0x8(%rbp)
  jne    L18
  mov    -0x4(%rbp),%eax
  jmp    L5
L18:
  mov    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %edx,%esi
  mov    %eax,%ecx
  shl    %cl,%esi
  mov    $0x1f,%eax
  sub    -0x8(%rbp),%eax
  mov    $0x7fffffff,%edx
  mov    %edx,%edi
  mov    %eax,%ecx
  sar    %cl,%edi
  mov    $0x20,%eax
  sub    -0x8(%rbp),%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    %edi,%eax
  or     %esi,%eax
L5:
  pop    %rbp
  ret
```

assistant: ```c
int32_t rotateL_fun_int32_t(int32_t x, int32_t i) {
  if ((i %= 32) == 0)
    return x;
  return (x << i) | ((0x7fffffff >> (31 - i)) & (x >> (32 - i)));
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rotateL_fun_int32_t>:
  endbr64
  mov    %edi,%edx
  mov    %edi,%eax
  test   $0x1f,%sil
  je     L4
  mov    %esi,%eax
  sar    $0x1f,%eax
  shr    $0x1b,%eax
  lea    (%rsi,%rax,1),%edi
  and    $0x1f,%edi
  sub    %eax,%edi
  mov    $0x1f,%ecx
  sub    %edi,%ecx
  mov    $0x7fffffff,%eax
  sar    %cl,%eax
  mov    $0x20,%ecx
  sub    %edi,%ecx
  mov    %edx,%edi
  sar    %cl,%edi
  and    %edi,%eax
  mov    %esi,%ecx
  shl    %cl,%edx
  or     %edx,%eax
L4:
  ret
```

assistant: ```c
int32_t rotateL_fun_int32_t(int32_t x, int32_t i) {
  if ((i %= 32) == 0)
    return x;
  return (x << i) | ((0x7fffffff >> (31 - i)) & (x >> (32 - i)));
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<rotateL_fun_int32_t>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  and    $0x1f,%edi
  je     L3
  mov    %esi,%edx
  mov    $0x1f,%ecx
  sar    $0x1f,%edx
  shr    $0x1b,%edx
  add    %edx,%esi
  and    $0x1f,%esi
  sub    %edx,%esi
  mov    $0x7fffffff,%edx
  sub    %esi,%ecx
  sar    %cl,%edx
  mov    $0x20,%ecx
  sub    %esi,%ecx
  mov    %eax,%esi
  sar    %cl,%esi
  mov    %edi,%ecx
  and    %esi,%edx
  shl    %cl,%eax
  or     %edx,%eax
L3:
  ret
```

assistant: ```c
int32_t rotateL_fun_int32_t(int32_t x, int32_t i) {
  if ((i %= 32) == 0)
    return x;
  return (x << i) | ((0x7fffffff >> (31 - i)) & (x >> (32 - i)));
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<rotateL_fun_int32_t>:
  endbr64
  mov    %edi,%eax
  mov    %esi,%edi
  and    $0x1f,%edi
  je     L1
  mov    %esi,%edx
  mov    $0x1f,%ecx
  sar    $0x1f,%edx
  shr    $0x1b,%edx
  add    %edx,%esi
  and    $0x1f,%esi
  sub    %edx,%esi
  mov    $0x7fffffff,%edx
  sub    %esi,%ecx
  sar    %cl,%edx
  mov    $0x20,%ecx
  sub    %esi,%ecx
  mov    %eax,%esi
  sar    %cl,%esi
  mov    %edi,%ecx
  and    %esi,%edx
  shl    %cl,%eax
  or     %edx,%eax
L1:
  ret
```

assistant: ```c
int32_t rotateL_fun_int32_t(int32_t x, int32_t i) {
  if ((i %= 32) == 0)
    return x;
  return (x << i) | ((0x7fffffff >> (31 - i)) & (x >> (32 - i)));
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__iintsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  cmpl   $0x1,-0x44(%rbp)
  jle    L59
  mov    -0x44(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  mov    %rax,-0x38(%rbp)
  cmpl   $0x0,-0x44(%rbp)
  jle    L61
  mov    -0x38(%rbp),%rdx
  mov    -0x50(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <iiqst@plt>
  mov    -0x50(%rbp),%rax
  lea    0x4(%rax),%r12
  jmp    L141
L61:
  mov    -0x38(%rbp),%r12
L141:
  mov    -0x50(%rbp),%rbx
  mov    %rbx,%r13
  jmp    L134
L62:
  mov    0x0(%r13),%edx
  mov    (%rbx),%eax
  cmp    %eax,%edx
  jle    L134
  mov    %rbx,%r13
L134:
  mov    %rbx,%rax
  lea    0x4(%rax),%rbx
  cmp    %rax,%r12
  ja     L62
  cmp    -0x50(%rbp),%r13
  je     L25
  mov    -0x50(%rbp),%rax
  mov    (%rax),%r15d
  mov    0x0(%r13),%edx
  mov    -0x50(%rbp),%rax
  mov    %edx,(%rax)
  mov    %r15d,0x0(%r13)
L25:
  mov    -0x50(%rbp),%r14
  jmp    L29
L107:
  nop
L98:
  sub    $0x4,%r12
  mov    (%r12),%edx
  mov    (%r14),%eax
  cmp    %eax,%edx
  jg     L98
  add    $0x4,%r12
  cmp    %r14,%r12
  je     L29
  lea    0x4(%r14),%rbx
  jmp    L70
L9:
  mov    (%rbx),%r15d
  mov    %rbx,%r13
  mov    %r13,%rcx
  jmp    L65
L129:
  mov    0x0(%r13),%eax
  mov    %eax,(%rcx)
  mov    %r13,%rcx
L65:
  sub    $0x4,%r13
  cmp    %r12,%r13
  jae    L129
  mov    %rcx,%rax
  mov    %r15d,(%rax)
L70:
  sub    $0x4,%rbx
  cmp    %r14,%rbx
  jae    L9
L29:
  add    $0x4,%r14
  mov    %r14,%r12
  cmp    -0x38(%rbp),%r12
  jb     L107
  jmp    L150
L59:
  nop
L150:
  add    $0x28,%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  pop    %rbp
  ret
```

assistant: ```c
void __iintsort(int n, int *base) {
  register int *i;
  register int *j;
  register int *lo;
  register int *hi;
  register int *min;
  register int c;
  int *max;
  if (n <= 1)
    return;
  max = base + n;
  if (n >= 1) {
    iiqst(base, max);
    hi = base + 1;
  } else
    hi = max;
  for (j = lo = base; lo++ < hi;) {
    if (*j > *lo)
      j = lo;
  }
  if (j != base) {
    c = *base;
    *base = *j;
    *j = c;
  }
  for (min = base; (hi = min += 1) < max;) {
    while (*(--hi) > *min)
      ;
    if ((hi += 1) != min) {
      for (lo = min + 1; --lo >= min;) {
        c = *lo;
        for (i = j = lo; (j -= 1) >= hi; i = j)
          *i = *j;
        *i = c;
      }
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__iintsort>:
  endbr64
  cmp    $0x1,%edi
  jle    L39
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rsi,%rbp
  movslq %edi,%rdi
  lea    (%rsi,%rdi,4),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <iiqst@plt>
  lea    0x4(%rbp),%rsi
  mov    0x0(%rbp),%eax
  cmp    0x4(%rbp),%eax
  jle    L47
  mov    0x4(%rbp),%edx
  mov    %edx,0x0(%rbp)
  mov    %eax,0x4(%rbp)
L47:
  cmp    %rsi,%rbx
  ja     L70
L57:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L28:
  add    $0x4,%rsi
  cmp    %rsi,%rbx
  jbe    L57
L70:
  mov    (%rsi),%ecx
  mov    %rsi,%rax
L78:
  mov    %rax,%rdx
  sub    $0x4,%rax
  cmp    %ecx,(%rax)
  jg     L78
  cmp    %rsi,%rdx
  je     L28
  lea    -0x4(%rsi),%r8
  sub    %rdx,%r8
  mov    %rsi,%rdi
L0:
  mov    (%rdi),%r9d
  mov    %rdi,%rax
  sub    $0x4,%rdi
  cmp    %rdi,%rdx
  ja     L50
  mov    %rdi,%rax
L46:
  mov    (%rax),%ecx
  mov    %ecx,0x4(%rax)
  sub    $0x4,%rax
  cmp    %rax,%rdx
  jbe    L46
  mov    %r8,%rcx
  and    $0xfffffffffffffffc,%rcx
  mov    %rdi,%rax
  sub    %rcx,%rax
L50:
  mov    %r9d,(%rax)
  sub    $0x4,%r8
  cmp    %rsi,%rdi
  jae    L0
  jmp    L28
L39:
  ret
```

assistant: ```c
void __iintsort(int n, int *base) {
  register int *i;
  register int *j;
  register int *lo;
  register int *hi;
  register int *min;
  register int c;
  int *max;
  if (n <= 1)
    return;
  max = base + n;
  if (n >= 1) {
    iiqst(base, max);
    hi = base + 1;
  } else
    hi = max;
  for (j = lo = base; lo++ < hi;) {
    if (*j > *lo)
      j = lo;
  }
  if (j != base) {
    c = *base;
    *base = *j;
    *j = c;
  }
  for (min = base; (hi = min += 1) < max;) {
    while (*(--hi) > *min)
      ;
    if ((hi += 1) != min) {
      for (lo = min + 1; --lo >= min;) {
        c = *lo;
        for (i = j = lo; (j -= 1) >= hi; i = j)
          *i = *j;
        *i = c;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<__iintsort>:
  endbr64
  cmp    $0x1,%edi
  jle    L21
  push   %r13
  movslq %edi,%rdi
  push   %r12
  lea    (%rsi,%rdi,4),%r13
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  lea    0x4(%rbx),%rbp
  sub    $0x8,%rsp
  call   <iiqst@plt>
  mov    (%rbx),%eax
  mov    0x4(%rbx),%edx
  cmp    %edx,%eax
  jg     L19
L94:
  cmp    %rbp,%r13
  jbe    L88
  xchg   %ax,%ax
L33:
  mov    0x0(%rbp),%ebx
  mov    %rbp,%rax
  cs nopw 0x0(%rax,%rax,1)
L95:
  mov    %rax,%rdx
  sub    $0x4,%rax
  cmp    %ebx,(%rax)
  jg     L95
  cmp    %rbp,%rdx
  jne    L64
L1:
  add    $0x4,%rbp
  cmp    %rbp,%r13
  ja     L33
L88:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L64:
  lea    -0x4(%rbp),%rax
  cmp    %rax,%rdx
  ja     L35
  mov    %rax,%rcx
  sub    %rdx,%rcx
  shr    $0x2,%rcx
  mov    %rcx,%rdi
  lea    0x4(,%rcx,4),%rdx
  neg    %rdi
  shl    $0x2,%rdi
  lea    (%rax,%rdi,1),%r12
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <memmove@plt>
L37:
  mov    %ebx,(%r12)
  jmp    L1
L19:
  mov    %edx,(%rbx)
  mov    %eax,0x4(%rbx)
  jmp    L94
L21:
  ret
L35:
  mov    %rbp,%r12
  jmp    L37
```

assistant: ```c
void __iintsort(int n, int *base) {
  register int *i;
  register int *j;
  register int *lo;
  register int *hi;
  register int *min;
  register int c;
  int *max;
  if (n <= 1)
    return;
  max = base + n;
  if (n >= 1) {
    iiqst(base, max);
    hi = base + 1;
  } else
    hi = max;
  for (j = lo = base; lo++ < hi;) {
    if (*j > *lo)
      j = lo;
  }
  if (j != base) {
    c = *base;
    *base = *j;
    *j = c;
  }
  for (min = base; (hi = min += 1) < max;) {
    while (*(--hi) > *min)
      ;
    if ((hi += 1) != min) {
      for (lo = min + 1; --lo >= min;) {
        c = *lo;
        for (i = j = lo; (j -= 1) >= hi; i = j)
          *i = *j;
        *i = c;
      }
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__iintsort>:
  endbr64
  cmp    $0x1,%edi
  jle    L33
  push   %r13
  movslq %edi,%rdi
  push   %r12
  lea    (%rsi,%rdi,4),%r13
  push   %rbp
  push   %rbx
  mov    %rsi,%rbx
  mov    %r13,%rsi
  mov    %rbx,%rdi
  lea    0x4(%rbx),%rbp
  sub    $0x8,%rsp
  call   <iiqst@plt>
  movq   (%rbx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%edx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%edx
  jg     L30
L28:
  cmp    %rbp,%r13
  jbe    L54
  nop
L18:
  mov    0x0(%rbp),%ebx
  mov    %rbp,%rax
  cs nopw 0x0(%rax,%rax,1)
L46:
  mov    %rax,%rdx
  sub    $0x4,%rax
  cmp    %ebx,(%rax)
  jg     L46
  cmp    %rbp,%rdx
  jne    L45
L44:
  add    $0x4,%rbp
  cmp    %rbp,%r13
  ja     L18
L54:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L45:
  lea    -0x4(%rbp),%rax
  cmp    %rax,%rdx
  ja     L94
  mov    %rax,%rcx
  sub    %rdx,%rcx
  shr    $0x2,%rcx
  mov    %rcx,%rdi
  lea    0x4(,%rcx,4),%rdx
  neg    %rdi
  shl    $0x2,%rdi
  lea    (%rax,%rdi,1),%r12
  add    %rbp,%rdi
  mov    %r12,%rsi
  call   <memmove@plt>
L42:
  mov    %ebx,(%r12)
  jmp    L44
L30:
  movq   %xmm1,(%rbx)
  jmp    L28
L33:
  ret
L94:
  mov    %rbp,%r12
  jmp    L42
```

assistant: ```c
void __iintsort(int n, int *base) {
  register int *i;
  register int *j;
  register int *lo;
  register int *hi;
  register int *min;
  register int c;
  int *max;
  if (n <= 1)
    return;
  max = base + n;
  if (n >= 1) {
    iiqst(base, max);
    hi = base + 1;
  } else
    hi = max;
  for (j = lo = base; lo++ < hi;) {
    if (*j > *lo)
      j = lo;
  }
  if (j != base) {
    c = *base;
    *base = *j;
    *j = c;
  }
  for (min = base; (hi = min += 1) < max;) {
    while (*(--hi) > *min)
      ;
    if ((hi += 1) != min) {
      for (lo = min + 1; --lo >= min;) {
        c = *lo;
        for (i = j = lo; (j -= 1) >= hi; i = j)
          *i = *j;
        *i = c;
      }
    }
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<writeGenerationalSolutionsBest>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %ax,-0x4(%rbp)
  cmpw   $0x0,-0x4(%rbp)
  je     L15
  mov    $0x0,%eax
  call   <writeGenerationalSolutionsBestFinal@plt>
  jmp    L4
L15:
  mov    $0x0,%eax
  call   <writeGenerationalSolutionsBestNotFinal@plt>
L4:
  nop
  leave
  ret
```

assistant: ```c
void writeGenerationalSolutionsBest(short final) {
  if (final)
    writeGenerationalSolutionsBestFinal();
  else
    writeGenerationalSolutionsBestNotFinal();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<writeGenerationalSolutionsBest>:
  endbr64
  sub    $0x8,%rsp
  test   %di,%di
  je     L8
  mov    $0x0,%eax
  call   <writeGenerationalSolutionsBestFinal@plt>
L1:
  add    $0x8,%rsp
  ret
L8:
  mov    $0x0,%eax
  call   <writeGenerationalSolutionsBestNotFinal@plt>
  jmp    L1
```

assistant: ```c
void writeGenerationalSolutionsBest(short final) {
  if (final)
    writeGenerationalSolutionsBestFinal();
  else
    writeGenerationalSolutionsBestNotFinal();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<writeGenerationalSolutionsBest>:
  endbr64
  xor    %eax,%eax
  test   %di,%di
  je     L2
  jmp    1060 <writeGenerationalSolutionsBestFinal@plt>
L2:
  jmp    1070 <writeGenerationalSolutionsBestNotFinal@plt>
```

assistant: ```c
void writeGenerationalSolutionsBest(short final) {
  if (final)
    writeGenerationalSolutionsBestFinal();
  else
    writeGenerationalSolutionsBestNotFinal();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<writeGenerationalSolutionsBest>:
  endbr64
  xor    %eax,%eax
  test   %di,%di
  je     L9
  jmp    1060 <writeGenerationalSolutionsBestFinal@plt>
L9:
  jmp    1070 <writeGenerationalSolutionsBestNotFinal@plt>
```

assistant: ```c
void writeGenerationalSolutionsBest(short final) {
  if (final)
    writeGenerationalSolutionsBestFinal();
  else
    writeGenerationalSolutionsBestNotFinal();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<is_marc_genre>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <marc_find_genre@plt>
  cmp    $0xffffffff,%eax
  je     L18
  mov    $0x1,%eax
  jmp    L6
L18:
  mov    $0x0,%eax
L6:
  leave
  ret
```

assistant: ```c
int is_marc_genre(const char *query) {
  if (marc_find_genre(query) != -1)
    return 1;
  else
    return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<is_marc_genre>:
  endbr64
  sub    $0x8,%rsp
  call   <marc_find_genre@plt>
  cmp    $0xffffffff,%eax
  setne  %al
  movzbl %al,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_marc_genre(const char *query) {
  if (marc_find_genre(query) != -1)
    return 1;
  else
    return 0;
}
```