ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<test_2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  cmpl   $0x5,-0x14(%rbp)
  jle    L25
  cmpl   $0x0,-0x18(%rbp)
  je     L21
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  jmp    L25
L21:
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
L25:
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  cmpl   $0x6,-0x14(%rbp)
  jle    L2
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
L2:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int test_2(int a, int b) {
  void *p;
  if (a > 5)
    if (b)
      p = malloc(16);
    else
      p = malloc(32);
  __analyzer_dump_exploded_nodes(0);
  if (a > 6) {
    free(p);
    __analyzer_dump_exploded_nodes(0);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<test_2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  cmp    $0x5,%edi
  jle    L40
  test   %esi,%esi
  je     L13
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
L40:
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  cmp    $0x6,%ebx
  jg     L38
L7:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L13:
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L40
L38:
  mov    %rbp,%rdi
  call   <free@plt>
  mov    $0x0,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  jmp    L7
```

assistant: ```c
int test_2(int a, int b) {
  void *p;
  if (a > 5)
    if (b)
      p = malloc(16);
    else
      p = malloc(32);
  __analyzer_dump_exploded_nodes(0);
  if (a > 6) {
    free(p);
    __analyzer_dump_exploded_nodes(0);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<test_2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x5,%edi
  jle    L23
  mov    %edi,%ebx
  test   %esi,%esi
  jne    L22
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
L9:
  xor    %edi,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  cmp    $0x6,%ebx
  je     L1
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  xor    %edi,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
L1:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L22:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L9
```

assistant: ```c
int test_2(int a, int b) {
  void *p;
  if (a > 5)
    if (b)
      p = malloc(16);
    else
      p = malloc(32);
  __analyzer_dump_exploded_nodes(0);
  if (a > 6) {
    free(p);
    __analyzer_dump_exploded_nodes(0);
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<test_2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  cmp    $0x5,%edi
  jle    L25
  mov    %edi,%ebx
  test   %esi,%esi
  jne    L24
  mov    $0x20,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
L36:
  xor    %edi,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  cmp    $0x6,%ebx
  je     L5
  mov    %rbp,%rdi
  call   <free@plt>
  xor    %edi,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  cs nopw 0x0(%rax,%rax,1)
L25:
  xor    %edi,%edi
  call   <__analyzer_dump_exploded_nodes@plt>
L5:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L24:
  mov    $0x10,%edi
  call   <malloc@plt>
  mov    %rax,%rbp
  jmp    L36
```

assistant: ```c
int test_2(int a, int b) {
  void *p;
  if (a > 5)
    if (b)
      p = malloc(16);
    else
      p = malloc(32);
  __analyzer_dump_exploded_nodes(0);
  if (a > 6) {
    free(p);
    __analyzer_dump_exploded_nodes(0);
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<word_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%eax
  mov    %al,-0x1c(%rbp)
  movq   $0x1,-0x8(%rbp)
  jmp    L15
L29:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,-0x1c(%rbp)
  jne    L16
  addq   $0x1,-0x8(%rbp)
L16:
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %rax,-0x18(%rbp)
L15:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L29
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int word_count(char *input, char delimiter) {
  size_t count = 1;
  while (*input != '\0') {
    if (*input == delimiter) {
      count++;
    }
    *input++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<word_count>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  mov    $0x1,%eax
L10:
  cmp    %dl,%sil
  sete   %dl
  movzbl %dl,%edx
  add    %rdx,%rax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L10
  ret
L5:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int word_count(char *input, char delimiter) {
  size_t count = 1;
  while (*input != '\0') {
    if (*input == delimiter) {
      count++;
    }
    *input++;
  }
  return count;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<word_count>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L0
  mov    $0x1,%eax
L9:
  cmp    %dl,%sil
  sete   %dl
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L9
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int word_count(char *input, char delimiter) {
  size_t count = 1;
  while (*input != '\0') {
    if (*input == delimiter) {
      count++;
    }
    *input++;
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<word_count>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L2
  mov    $0x1,%eax
L4:
  cmp    %sil,%dl
  sete   %dl
  add    $0x1,%rdi
  movzbl %dl,%edx
  add    %rdx,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L4
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  mov    $0x1,%eax
  ret
```

assistant: ```c
int word_count(char *input, char delimiter) {
  size_t count = 1;
  while (*input != '\0') {
    if (*input == delimiter) {
      count++;
    }
    *input++;
  }
  return count;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  movl   $0x2,-0x10(%rbp)
  movl   $0xffffffff,-0xc(%rbp)
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movl   $0x1,-0x14(%rbp)
  jmp    L15
L13:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x14(%rbp),%xmm1
  pxor   %xmm0,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x28(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edi
  call   <fat@plt>
  imul   -0xc(%rbp),%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  movsd  -0x28(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  addl   $0x2,-0x10(%rbp)
  negl   -0xc(%rbp)
  addl   $0x1,-0x14(%rbp)
L15:
  cmpl   $0x4,-0x14(%rbp)
  jle    L13
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D6
datatype: string

tool: D6: %lf

assistant: ```c
int main() {
  int i, p = 2, sinal = -1;
  double soma = 0.0;
  for (i = 1; i <= 4; i++) {
    soma = soma + (i + 0.0) / (fat(p) * sinal);
    p = p + 2;
    sinal *= -1;
  }
  printf("%lf", soma);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r14
  push   %rbp
  push   %rbx
  pxor   %xmm4,%xmm4
  movq   %xmm4,%r14
  mov    $0xffffffff,%ebp
  mov    $0x1,%ebx
L0:
  lea    (%rbx,%rbx,1),%edi
  call   <fat@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  pxor   %xmm2,%xmm2
  addsd  %xmm2,%xmm0
  imul   %ebp,%eax
  pxor   %xmm1,%xmm1
  cvtsi2sd %eax,%xmm1
  divsd  %xmm1,%xmm0
  movq   %r14,%xmm3
  addsd  %xmm3,%xmm0
  movq   %xmm0,%r14
  neg    %ebp
  add    $0x1,%ebx
  cmp    $0x5,%ebx
  jne    L0
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbx
  pop    %rbp
  pop    %r14
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D7
type_guessed: string

tool: D7: %lf

assistant: ```c
int main() {
  int i, p = 2, sinal = -1;
  double soma = 0.0;
  for (i = 1; i <= 4; i++) {
    soma = soma + (i + 0.0) / (fat(p) * sinal);
    p = p + 2;
    sinal *= -1;
  }
  printf("%lf", soma);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L2:
  lea    (%rbx,%rbx,1),%edi
  movsd  %xmm1,0x8(%rsp)
  call   <fat@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sd %ebx,%xmm0
  movsd  0x8(%rsp),%xmm1
  add    $0x1,%ebx
  imul   %ebp,%eax
  neg    %ebp
  cvtsi2sd %eax,%xmm2
  addsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0x5,%ebx
  jne    L2
  movapd %xmm1,%xmm0
  lea    D9(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
datatype: string

tool: D9: %lf

assistant: ```c
int main() {
  int i, p = 2, sinal = -1;
  double soma = 0.0;
  for (i = 1; i <= 4; i++) {
    soma = soma + (i + 0.0) / (fat(p) * sinal);
    p = p + 2;
    sinal *= -1;
  }
  printf("%lf", soma);
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  push   %rbp
  pxor   %xmm1,%xmm1
  mov    $0xffffffff,%ebp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x18,%rsp
L1:
  lea    (%rbx,%rbx,1),%edi
  movsd  %xmm1,0x8(%rsp)
  call   <fat@plt>
  pxor   %xmm0,%xmm0
  pxor   %xmm2,%xmm2
  pxor   %xmm3,%xmm3
  cvtsi2sd %ebx,%xmm0
  movsd  0x8(%rsp),%xmm1
  add    $0x1,%ebx
  imul   %ebp,%eax
  neg    %ebp
  cvtsi2sd %eax,%xmm2
  addsd  %xmm3,%xmm0
  divsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  cmp    $0x5,%ebx
  jne    L1
  movapd %xmm1,%xmm0
  lea    D8(%rip),%rdi
  call   <printf@plt>
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: parse_data
arguments: tag: D8
type_guessed: string

tool: D8: %lf

assistant: ```c
int main() {
  int i, p = 2, sinal = -1;
  double soma = 0.0;
  for (i = 1; i <= 4; i++) {
    soma = soma + (i + 0.0) / (fat(p) * sinal);
    p = p + 2;
    sinal *= -1;
  }
  printf("%lf", soma);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x130,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x128(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rsi
  lea    D8(%rip),%rdi
  call   <scanf@plt>
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L63
  lea    D24(%rip),%r12
  lea    0x10(%rsp),%rbx
  mov    $0x0,%ebp
  jmp    L115
L107:
  add    $0x1,%rdx
  movzbl -0x1(%rdx),%eax
  test   %al,%al
  je     L28
L123:
  lea    -0x61(%rax),%ecx
  cmp    $0x19,%cl
  ja     L107
  movsbl %al,%eax
  sub    $0x61,%eax
  cltq
  addl   $0x1,0x10(%rsp,%rax,4)
  jmp    L107
L28:
  mov    $0x0,%ecx
  jmp    L131
L144:
  add    (%rbx,%rax,4),%edx
L75:
  add    $0x1,%rax
  cmp    $0x1a,%rax
  je     L87
L41:
  cmp    %ecx,%eax
  jne    L144
  jmp    L75
L87:
  mov    %edx,0x80(%rsp,%rcx,4)
L15:
  add    $0x1,%rcx
  cmp    $0x1a,%rcx
  je     L135
L131:
  cmpl   $0x0,(%rbx,%rcx,4)
  je     L15
  mov    $0x0,%eax
  mov    %ebp,%edx
  jmp    L41
L135:
  mov    $0x0,%eax
  jmp    L200
L99:
  add    $0x4,%rax
  cmp    $0x68,%rax
  je     L20
L200:
  mov    0x80(%rsp,%rax,1),%edx
  test   %edx,%edx
  je     L99
  cmp    (%rax,%rbx,1),%edx
  jne    L99
  lea    D17(%rip),%rdi
  call   <printf@plt>
  jmp    L138
L63:
  mov    0x128(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L192
  mov    $0x0,%eax
  add    $0x130,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L20:
  lea    D16(%rip),%rdi
  call   <printf@plt>
L138:
  mov    0xc(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0xc(%rsp)
  test   %eax,%eax
  je     L63
L115:
  lea    0x10(%rsp),%rdi
  mov    $0x0,%eax
  mov    $0xd,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0x80(%rsp),%rdi
  mov    $0xe,%ecx
  rep stos %rax,%es:(%rdi)
  lea    0xf0(%rsp),%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movzbl 0xf0(%rsp),%eax
  test   %al,%al
  je     L28
  lea    0xf1(%rsp),%rdx
  jmp    L123
L192:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D8
type: string
name: parse_data
arguments: data_label: D24
type: string
name: parse_data
arguments: data_label: D17
type: string
name: parse_data
arguments: data_label: D16
type: string

tool: D8: %d

tool: D24: %s

tool: D17: YES


tool: D16: NO


assistant: ```c
int main() {
  int t;
  scanf("%d", &t);
  while (t--) {
    char string[52];
    int c = 0, count[26] = {0}, k[28] = {0}, i, j, p = 0;
    scanf("%s", string);
    while (string[c] != '\0') {
      if (string[c] >= 'a' && string[c] <= 'z')
        count[string[c] - 'a']++;
      c++;
    }
    for (i = 0; i < 26; i++) {
      int s = 0;
      if (count[i] != 0) {
        for (j = 0; j < 26; j++) {
          if (i != j && count[j] != 0)
            s = s + count[j];
        }
        k[i] = s;
      }
    }
    for (i = 0; i < 26; i++) {
      if (k[i] != 0 && (count[i] == k[i])) {
        p = 1;
        break;
      }
    }
    if (p == 1)
      printf("YES\n");
    else
      printf("NO\n");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<change_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <chdir@plt>
  test   %eax,%eax
  je     L1
  lea    D8(%rip),%rax
  mov    %rax,%rdi
  call   <perror@plt>
L1:
  nop
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D8
type: string

tool: D8: cd

assistant: ```c
void change_dir(char *dir) {
  if ((!chdir(dir)) == 0) {
    perror("cd");
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<change_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <chdir@plt>
  test   %eax,%eax
  jne    L6
L9:
  add    $0x8,%rsp
  ret
L6:
  lea    D8(%rip),%rdi
  call   <perror@plt>
  jmp    L9
```

tool_calls: name: unpack_data
arguments: data_tag: D8
type_infered: string

tool: D8: cd

assistant: ```c
void change_dir(char *dir) {
  if ((!chdir(dir)) == 0) {
    perror("cd");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<change_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <chdir@plt>
  test   %eax,%eax
  jne    L0
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L0:
  lea    D6(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perror@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D6
data_type: string

tool: D6: cd

assistant: ```c
void change_dir(char *dir) {
  if ((!chdir(dir)) == 0) {
    perror("cd");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<change_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <chdir@plt>
  test   %eax,%eax
  jne    L2
  add    $0x8,%rsp
  ret
  cs nopw 0x0(%rax,%rax,1)
L2:
  lea    D1(%rip),%rdi
  add    $0x8,%rsp
  jmp    1070 <perror@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
data_type: string

tool: D1: cd

assistant: ```c
void change_dir(char *dir) {
  if ((!chdir(dir)) == 0) {
    perror("cd");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<ltoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x38(%rbp)
  mov    %rsi,-0x40(%rbp)
  mov    %edx,%eax
  mov    %ax,-0x44(%rbp)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x40(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x40(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  cmpw   $0x1,-0x44(%rbp)
  jbe    L63
  cmpw   $0x24,-0x44(%rbp)
  jbe    L80
L63:
  mov    -0x40(%rbp),%rax
  jmp    L48
L80:
  cmpq   $0x0,-0x38(%rbp)
  jns    L95
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  movb   $0x2d,(%rax)
  addq   $0x1,-0x18(%rbp)
  mov    -0x38(%rbp),%rax
  neg    %rax
  mov    %rax,-0x8(%rbp)
  jmp    L38
L95:
  mov    -0x38(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L38:
  movl   $0x0,-0x24(%rbp)
L33:
  movzwl -0x44(%rbp),%ecx
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rcx
  mov    %rdx,%rax
  mov    %eax,-0x24(%rbp)
  cmpl   $0x9,-0x24(%rbp)
  jg     L86
  mov    -0x24(%rbp),%eax
  add    $0x30,%eax
  mov    %eax,%ecx
  jmp    L98
L86:
  mov    -0x24(%rbp),%eax
  add    $0x57,%eax
  mov    %eax,%ecx
L98:
  mov    -0x20(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x20(%rbp)
  mov    %cl,(%rax)
  movzwl -0x44(%rbp),%esi
  mov    -0x8(%rbp),%rax
  cqto
  idiv   %rsi
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L33
  mov    -0x20(%rbp),%rax
  movb   $0x0,(%rax)
  mov    -0x20(%rbp),%rax
  sub    $0x1,%rax
  mov    %rax,-0x10(%rbp)
  jmp    L36
L45:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  mov    %al,-0x25(%rbp)
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  movzbl -0x25(%rbp),%edx
  mov    %dl,(%rax)
  addq   $0x1,-0x18(%rbp)
  subq   $0x1,-0x10(%rbp)
L36:
  mov    -0x18(%rbp),%rax
  cmp    -0x10(%rbp),%rax
  jb     L45
  mov    -0x40(%rbp),%rax
L48:
  pop    %rbp
  ret
```

assistant: ```c
char *ltoa(long int num, char *buf, unsigned short int base) {
  char *p = buf;
  char *p1, *p2;
  long int ud = 0;
  *buf = '\0';
  p1 = buf;
  if (base < 2 || base > 36) {
    return buf;
  }
  if (num < 0) {
    *(p++) = '-';
    p1++;
    ud = -num;
  } else {
    ud = num;
  }
  int remainder = 0;
  do {
    remainder = ud % base;
    *(p++) = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
  } while (ud /= base);
  *p = '\0';
  p2 = p - 1;
  char tmp;
  while (p1 < p2) {
    tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return buf;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ltoa>:
  endbr64
  mov    %rsi,%r10
  mov    %edx,%r8d
  movb   $0x0,(%rsi)
  sub    $0x2,%edx
  cmp    $0x22,%dx
  ja     L24
  test   %rdi,%rdi
  js     L21
L27:
  mov    %rsi,%rcx
  movzwl %r8w,%r8d
  jmp    L25
L21:
  lea    0x1(%rsi),%rsi
  movb   $0x2d,(%r10)
  neg    %rdi
  jmp    L27
L60:
  mov    %r9,%rcx
L25:
  mov    %rdi,%rax
  cqto
  idiv   %r8
  lea    0x30(%rdx),%r9d
  lea    0x57(%rdx),%eax
  cmp    $0x9,%edx
  cmovle %r9d,%eax
  lea    0x1(%rcx),%r9
  mov    %al,-0x1(%r9)
  mov    %rdi,%rax
  cqto
  idiv   %r8
  mov    %rax,%rdi
  test   %rax,%rax
  jne    L60
  movb   $0x0,(%r9)
  cmp    %rcx,%rsi
  jae    L24
L16:
  movzbl (%rsi),%eax
  movzbl (%rcx),%edx
  mov    %dl,(%rsi)
  mov    %al,(%rcx)
  add    $0x1,%rsi
  sub    $0x1,%rcx
  cmp    %rcx,%rsi
  jb     L16
L24:
  mov    %r10,%rax
  ret
```

assistant: ```c
char *ltoa(long int num, char *buf, unsigned short int base) {
  char *p = buf;
  char *p1, *p2;
  long int ud = 0;
  *buf = '\0';
  p1 = buf;
  if (base < 2 || base > 36) {
    return buf;
  }
  if (num < 0) {
    *(p++) = '-';
    p1++;
    ud = -num;
  } else {
    ud = num;
  }
  int remainder = 0;
  do {
    remainder = ud % base;
    *(p++) = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
  } while (ud /= base);
  *p = '\0';
  p2 = p - 1;
  char tmp;
  while (p1 < p2) {
    tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return buf;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<ltoa>:
  endbr64
  lea    -0x2(%rdx),%ecx
  movb   $0x0,(%rsi)
  mov    %rdi,%rax
  mov    %rsi,%r10
  cmp    $0x22,%cx
  ja     L21
  mov    %rsi,%rdi
  test   %rax,%rax
  js     L6
L14:
  movzwl %dx,%r8d
  mov    %rdi,%rcx
  jmp    L32
  nopw   0x0(%rax,%rax,1)
L76:
  mov    %rsi,%rcx
L32:
  cqto
  idiv   %r8
  lea    0x30(%rdx),%r9d
  lea    0x57(%rdx),%esi
  cmp    $0x9,%rdx
  mov    %r9d,%edx
  cmovg  %esi,%edx
  lea    0x1(%rcx),%rsi
  mov    %dl,-0x1(%rsi)
  test   %rax,%rax
  jne    L76
  movb   $0x0,(%rsi)
  cmp    %rcx,%rdi
  jb     L73
  jmp    L21
  nop
L36:
  movzbl (%rcx),%edx
L73:
  movzbl (%rdi),%eax
  sub    $0x1,%rcx
  mov    %dl,(%rdi)
  add    $0x1,%rdi
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rdi
  jb     L36
L21:
  mov    %r10,%rax
  ret
  nopl   0x0(%rax)
L6:
  movb   $0x2d,(%rsi)
  lea    0x1(%rsi),%rdi
  neg    %rax
  jmp    L14
```

assistant: ```c
char *ltoa(long int num, char *buf, unsigned short int base) {
  char *p = buf;
  char *p1, *p2;
  long int ud = 0;
  *buf = '\0';
  p1 = buf;
  if (base < 2 || base > 36) {
    return buf;
  }
  if (num < 0) {
    *(p++) = '-';
    p1++;
    ud = -num;
  } else {
    ud = num;
  }
  int remainder = 0;
  do {
    remainder = ud % base;
    *(p++) = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
  } while (ud /= base);
  *p = '\0';
  p2 = p - 1;
  char tmp;
  while (p1 < p2) {
    tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return buf;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<ltoa>:
  endbr64
  lea    -0x2(%rdx),%ecx
  movb   $0x0,(%rsi)
  mov    %rdi,%rax
  mov    %rsi,%r9
  cmp    $0x22,%cx
  ja     L46
  test   %rdi,%rdi
  js     L11
L81:
  movzwl %dx,%r8d
  mov    %rsi,%rcx
  jmp    L13
  nopl   0x0(%rax)
L74:
  add    $0x30,%edx
  mov    %dl,-0x1(%rdi)
  test   %rax,%rax
  je     L79
L45:
  mov    %rdi,%rcx
L13:
  cqto
  lea    0x1(%rcx),%rdi
  idiv   %r8
  cmp    $0x9,%rdx
  jle    L74
  add    $0x57,%edx
  mov    %dl,-0x1(%rdi)
  test   %rax,%rax
  jne    L45
L79:
  movb   $0x0,(%rdi)
  cmp    %rcx,%rsi
  jae    L46
  nopl   0x0(%rax,%rax,1)
L41:
  movzbl (%rsi),%eax
  movzbl (%rcx),%edx
  add    $0x1,%rsi
  sub    $0x1,%rcx
  mov    %dl,-0x1(%rsi)
  mov    %al,0x1(%rcx)
  cmp    %rcx,%rsi
  jb     L41
L46:
  mov    %r9,%rax
  ret
  nopl   (%rax)
L11:
  movb   $0x2d,(%r9)
  lea    0x1(%rsi),%rsi
  neg    %rax
  jmp    L81
```

assistant: ```c
char *ltoa(long int num, char *buf, unsigned short int base) {
  char *p = buf;
  char *p1, *p2;
  long int ud = 0;
  *buf = '\0';
  p1 = buf;
  if (base < 2 || base > 36) {
    return buf;
  }
  if (num < 0) {
    *(p++) = '-';
    p1++;
    ud = -num;
  } else {
    ud = num;
  }
  int remainder = 0;
  do {
    remainder = ud % base;
    *(p++) = (remainder < 10) ? remainder + '0' : remainder + 'a' - 10;
  } while (ud /= base);
  *p = '\0';
  p2 = p - 1;
  char tmp;
  while (p1 < p2) {
    tmp = *p1;
    *p1 = *p2;
    *p2 = tmp;
    p1++;
    p2--;
  }
  return buf;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<parseFileChar>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  movsbl -0x4(%rbp),%eax
  mov    %eax,%edi
  call   <tolower@plt>
  sub    $0x61,%eax
  cmp    $0x7,%eax
  ja     L37
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  lea    D7(%rip),%rax
  mov    (%rdx,%rax,1),%eax
  cltq
  lea    D7(%rip),%rdx
  add    %rdx,%rax
  notrack jmp *%rax
  mov    $0x0,%eax
  jmp    L5
  mov    $0x1,%eax
  jmp    L5
  mov    $0x2,%eax
  jmp    L5
  mov    $0x3,%eax
  jmp    L5
  mov    $0x4,%eax
  jmp    L5
  mov    $0x5,%eax
  jmp    L5
  mov    $0x6,%eax
  jmp    L5
  mov    $0x7,%eax
  jmp    L5
L37:
  mov    $0x8,%eax
L5:
  leave
  ret
```

assistant: ```c
int parseFileChar(const char c) {
  switch (tolower(c)) {
  case 'a':
    return 0;
  case 'b':
    return 1;
  case 'c':
    return 2;
  case 'd':
    return 3;
  case 'e':
    return 4;
  case 'f':
    return 5;
  case 'g':
    return 6;
  case 'h':
    return 7;
  default:
    return 8;
  }
}
```