ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<JimSqliteQuoteString>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %rdx,%rbp
  test   %esi,%esi
  jle    L38
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edx
  lea    0x1(%rdi,%rdx,1),%rsi
  mov    $0x0,%edx
L34:
  cmpb   $0x27,(%rax)
  sete   %cl
  movzbl %cl,%ecx
  add    %ecx,%edx
  add    $0x1,%rax
  cmp    %rsi,%rax
  jne    L34
  lea    (%rdx,%r13,1),%r12d
  mov    %r12d,%edi
  call   <Jim_Alloc@plt>
  lea    -0x1(%r13),%edx
L45:
  mov    %edx,%edx
  lea    0x1(%rbx,%rdx,1),%rdi
  mov    %rax,%rcx
  jmp    L5
L38:
  mov    %esi,%edi
  call   <Jim_Alloc@plt>
  test   %r13d,%r13d
  jne    L52
  mov    %r13d,%r12d
L69:
  mov    %r12d,0x0(%rbp)
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L52:
  lea    -0x1(%r13),%edx
  mov    %r13d,%r12d
  jmp    L45
L43:
  add    $0x1,%rbx
  lea    0x1(%rdx),%rcx
  movzbl -0x1(%rbx),%esi
  mov    %sil,(%rdx)
  cmp    %rdi,%rbx
  je     L69
L5:
  mov    %rcx,%rdx
  cmpb   $0x27,(%rbx)
  jne    L43
  lea    0x1(%rcx),%rdx
  movb   $0x27,(%rcx)
  jmp    L43
```

assistant: ```c
char *JimSqliteQuoteString(const char *str, int len, int *newLenPtr) {
  int i, newLen, c = 0;
  const char *s;
  char *d, *buf;
  for (i = 0; i < len; i++)
    if (str[i] == '\'')
      c++;
  newLen = len + c;
  s = str;
  d = buf = Jim_Alloc(newLen);
  while (len--) {
    if (*s == '\'')
      *d++ = '\'';
    *d++ = *s++;
  }
  *newLenPtr = newLen;
  return buf;
}
```
user: What is the c source code of the assembly code below?

```asm
<JimSqliteQuoteString>:
  endbr64
  push   %r14
  push   %r13
  mov    %rdx,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x10,%rsp
  test   %esi,%esi
  jle    L4
  lea    0x1(%rdi),%rbx
  mov    %rdi,%rax
  lea    -0x1(%rsi),%edi
  xor    %edx,%edx
  mov    %rdi,%r14
  add    %rbx,%rdi
L64:
  xor    %ecx,%ecx
  cmpb   $0x27,(%rax)
  sete   %cl
  add    $0x1,%rax
  add    %ecx,%edx
  cmp    %rdi,%rax
  jne    L64
  lea    (%rdx,%rsi,1),%r12d
  mov    %r12d,%edi
  call   <Jim_Alloc@plt>
L23:
  lea    0x1(%rbp,%r14,1),%rdi
  mov    %rax,%rsi
  jmp    L74
  nopl   0x0(%rax)
L35:
  add    $0x1,%rbx
L74:
  movzbl 0x0(%rbp),%ecx
  mov    %rsi,%rdx
  cmp    $0x27,%cl
  jne    L0
  movb   $0x27,(%rsi)
  movzbl 0x0(%rbp),%ecx
  add    $0x1,%rdx
L0:
  mov    %cl,(%rdx)
  mov    %rbx,%rbp
  lea    0x1(%rdx),%rsi
  cmp    %rdi,%rbx
  jne    L35
L2:
  mov    %r12d,0x0(%r13)
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopw   0x0(%rax,%rax,1)
L4:
  mov    %esi,%edi
  mov    %esi,0xc(%rsp)
  call   <Jim_Alloc@plt>
  mov    0xc(%rsp),%esi
  test   %esi,%esi
  jne    L75
  xor    %r12d,%r12d
  jmp    L2
L75:
  mov    %esi,%r12d
  lea    0x1(%rbp),%rbx
  lea    -0x1(%rsi),%r14d
  jmp    L23
```

assistant: ```c
char *JimSqliteQuoteString(const char *str, int len, int *newLenPtr) {
  int i, newLen, c = 0;
  const char *s;
  char *d, *buf;
  for (i = 0; i < len; i++)
    if (str[i] == '\'')
      c++;
  newLen = len + c;
  s = str;
  d = buf = Jim_Alloc(newLen);
  while (len--) {
    if (*s == '\'')
      *d++ = '\'';
    *d++ = *s++;
  }
  *newLenPtr = newLen;
  return buf;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<start_timeout_timer>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x24(%rbp),%eax
  mov    %eax,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x24(%rbp),%edx
  mov    %edx,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x20,%rax
  shr    $0x6,%eax
  imul   $0x3e8,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  imul   $0x3e8,%eax,%eax
  mov    %eax,-0xc(%rbp)
  movq   $0x0,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  lea    -0x20(%rbp),%rcx
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <setitimer@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
void start_timeout_timer(unsigned int msecs) {
  struct itimerval ival;
  ival.it_value.tv_sec = msecs / 1000;
  ival.it_value.tv_usec = (msecs % 1000) * 1000;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<start_timeout_timer>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,0x10(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  imul   $0x3e8,%edi,%edi
  mov    %edi,0x14(%rsp)
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  mov    %rsp,%rsi
  mov    $0x0,%edx
  mov    D9(%rip),%rax
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  add    $0x28,%rsp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void start_timeout_timer(unsigned int msecs) {
  struct itimerval ival;
  ival.it_value.tv_sec = msecs / 1000;
  ival.it_value.tv_usec = (msecs % 1000) * 1000;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<start_timeout_timer>:
  endbr64
  sub    $0x28,%rsp
  xor    %edx,%edx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  mov    %rsp,%rsi
  movq   $0x0,(%rsp)
  movq   $0x0,0x8(%rsp)
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  mov    %eax,0x10(%rsp)
  imul   $0x3e8,%eax,%eax
  sub    %eax,%edi
  mov    D7(%rip),%rax
  imul   $0x3e8,%edi,%edi
  mov    %edi,0x14(%rsp)
  mov    (%rax),%edi
  call   <setitimer@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  add    $0x28,%rsp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void start_timeout_timer(unsigned int msecs) {
  struct itimerval ival;
  ival.it_value.tv_sec = msecs / 1000;
  ival.it_value.tv_usec = (msecs % 1000) * 1000;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<start_timeout_timer>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %edi,%eax
  mov    %rsp,%rsi
  imul   $0x10624dd3,%rax,%rax
  shr    $0x26,%rax
  imul   $0x3e8,%eax,%edx
  movd   %eax,%xmm0
  mov    D1(%rip),%rax
  sub    %edx,%edi
  xor    %edx,%edx
  imul   $0x3e8,%edi,%edi
  movd   %edi,%xmm1
  mov    (%rax),%edi
  punpckldq %xmm1,%xmm0
  movq   %xmm0,0x10(%rsp)
  pxor   %xmm0,%xmm0
  movaps %xmm0,(%rsp)
  call   <setitimer@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L8
  add    $0x28,%rsp
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void start_timeout_timer(unsigned int msecs) {
  struct itimerval ival;
  ival.it_value.tv_sec = msecs / 1000;
  ival.it_value.tv_usec = (msecs % 1000) * 1000;
  ival.it_interval.tv_sec = ival.it_interval.tv_usec = 0;
  setitimer(ITIMER_REAL, &ival, NULL);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0xb4,-0x10(%rbp)
  lea    D11(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x14(%rbp),%rdx
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  mov    -0x18(%rbp),%edx
  mov    -0x14(%rbp),%eax
  add    %eax,%edx
  mov    -0x10(%rbp),%eax
  sub    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x18(%rbp),%eax
  cmp    $0x5a,%eax
  jg     L42
  mov    -0x14(%rbp),%eax
  cmp    $0x5a,%eax
  jg     L42
  cmpl   $0x5a,-0xc(%rbp)
  jle    L66
L42:
  lea    D24(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L66:
  mov    -0x18(%rbp),%eax
  cmp    $0x5a,%eax
  je     L60
  mov    -0x14(%rbp),%eax
  cmp    $0x5a,%eax
  je     L60
  cmpl   $0x5a,-0xc(%rbp)
  jne    L27
L60:
  lea    D41(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L47
L27:
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L47:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L30
  call   <__stack_chk_fail@plt>
L30:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D11
type_infered: string
name: unpack_data
arguments: data_tag: D25
type_infered: string
name: unpack_data
arguments: data_tag: D24
type_infered: string
name: unpack_data
arguments: data_tag: D41
type_infered: string
name: unpack_data
arguments: data_tag: D29
type_infered: string

tool: D11: Iki adet aci giriniz...


tool: D25: %d%d

tool: D24: Bu ucgen genis acilidir...


tool: D41: Bu ucgen dik acilidir...


tool: D29: Bu ucgen dar acilidir...


assistant: ```c
int main() {
  int aci1, aci2;
  int ucgen = 180;
  printf("Iki adet aci giriniz...\n");
  scanf("%d%d", &aci1, &aci2);
  int aci3 = ucgen - (aci1 + aci2);
  if (aci1 > 90 || aci2 > 90 || aci3 > 90) {
    printf("Bu ucgen genis acilidir...\n");
  } else if (aci1 == 90 || aci2 == 90 || aci3 == 90) {
    printf("Bu ucgen dik acilidir...\n");
  } else {
    printf("Bu ucgen dar acilidir...\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D42(%rip),%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D17(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%ecx
  lea    (%rdx,%rcx,1),%esi
  mov    $0xb4,%eax
  sub    %esi,%eax
  cmp    $0x5a,%ecx
  setg   %sil
  cmp    $0x5a,%edx
  setg   %dil
  or     %dil,%sil
  jne    L3
  cmp    $0x5a,%eax
  jle    L1
L3:
  lea    D31(%rip),%rdi
  call   <printf@plt>
L64:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L48
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L1:
  cmp    $0x5a,%ecx
  sete   %cl
  cmp    $0x5a,%edx
  sete   %dl
  or     %dl,%cl
  jne    L16
  cmp    $0x5a,%eax
  jne    L20
L16:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L20:
  lea    D6(%rip),%rdi
  call   <printf@plt>
  jmp    L64
L48:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D42
data_type: string
name: disassemble_data
arguments: data_tag: D17
data_type: string
name: disassemble_data
arguments: data_tag: D31
data_type: string
name: disassemble_data
arguments: data_tag: D12
data_type: string
name: disassemble_data
arguments: data_tag: D6
data_type: string

tool: D42: Iki adet aci giriniz...


tool: D17: %d%d

tool: D31: Bu ucgen genis acilidir...


tool: D12: Bu ucgen dik acilidir...


tool: D6: Bu ucgen dar acilidir...


assistant: ```c
int main() {
  int aci1, aci2;
  int ucgen = 180;
  printf("Iki adet aci giriniz...\n");
  scanf("%d%d", &aci1, &aci2);
  int aci3 = ucgen - (aci1 + aci2);
  if (aci1 > 90 || aci2 > 90 || aci3 > 90) {
    printf("Bu ucgen genis acilidir...\n");
  } else if (aci1 == 90 || aci2 == 90 || aci3 == 90) {
    printf("Bu ucgen dik acilidir...\n");
  } else {
    printf("Bu ucgen dar acilidir...\n");
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D41(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%ecx
  mov    $0xb4,%eax
  lea    (%rdx,%rcx,1),%esi
  sub    %esi,%eax
  cmp    $0x5a,%edx
  setg   %sil
  cmp    $0x5a,%ecx
  setg   %dil
  or     %dil,%sil
  jne    L61
  cmp    $0x5a,%eax
  jle    L38
L61:
  lea    D26(%rip),%rdi
  call   <printf@plt>
L50:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L60
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L38:
  cmp    $0x5a,%ecx
  sete   %cl
  cmp    $0x5a,%edx
  sete   %dl
  or     %dl,%cl
  jne    L65
  cmp    $0x5a,%eax
  jne    L27
L65:
  lea    D36(%rip),%rdi
  call   <printf@plt>
  jmp    L50
L27:
  lea    D31(%rip),%rdi
  call   <printf@plt>
  jmp    L50
L60:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_label: D41
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string
name: retrieve_data
arguments: data_label: D26
type_guessed: string
name: retrieve_data
arguments: data_label: D36
type_guessed: string
name: retrieve_data
arguments: data_label: D31
type_guessed: string

tool: D41: Iki adet aci giriniz...


tool: D15: %d%d

tool: D26: Bu ucgen genis acilidir...


tool: D36: Bu ucgen dik acilidir...


tool: D31: Bu ucgen dar acilidir...


assistant: ```c
int main() {
  int aci1, aci2;
  int ucgen = 180;
  printf("Iki adet aci giriniz...\n");
  scanf("%d%d", &aci1, &aci2);
  int aci3 = ucgen - (aci1 + aci2);
  if (aci1 > 90 || aci2 > 90 || aci3 > 90) {
    printf("Bu ucgen genis acilidir...\n");
  } else if (aci1 == 90 || aci2 == 90 || aci3 == 90) {
    printf("Bu ucgen dik acilidir...\n");
  } else {
    printf("Bu ucgen dar acilidir...\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  lea    D20(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  call   <printf@plt>
  lea    0x4(%rsp),%rdx
  mov    %rsp,%rsi
  lea    D44(%rip),%rdi
  call   <scanf@plt>
  mov    (%rsp),%edx
  mov    0x4(%rsp),%ecx
  mov    $0xb4,%eax
  lea    (%rdx,%rcx,1),%esi
  sub    %esi,%eax
  cmp    $0x5a,%edx
  setg   %sil
  cmp    $0x5a,%ecx
  setg   %dil
  or     %dil,%sil
  jne    L55
  cmp    $0x5a,%eax
  jle    L24
L55:
  lea    D23(%rip),%rdi
  call   <printf@plt>
L48:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L28
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L24:
  cmp    $0x5a,%ecx
  sete   %cl
  cmp    $0x5a,%edx
  sete   %dl
  or     %dl,%cl
  jne    L35
  cmp    $0x5a,%eax
  jne    L23
L35:
  lea    D12(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L23:
  lea    D8(%rip),%rdi
  call   <printf@plt>
  jmp    L48
L28:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D20
datatype: string
name: disassemble_data
arguments: tag: D44
datatype: string
name: disassemble_data
arguments: tag: D23
datatype: string
name: disassemble_data
arguments: tag: D12
datatype: string
name: disassemble_data
arguments: tag: D8
datatype: string

tool: D20: Iki adet aci giriniz...


tool: D44: %d%d

tool: D23: Bu ucgen genis acilidir...


tool: D12: Bu ucgen dik acilidir...


tool: D8: Bu ucgen dar acilidir...


assistant: ```c
int main() {
  int aci1, aci2;
  int ucgen = 180;
  printf("Iki adet aci giriniz...\n");
  scanf("%d%d", &aci1, &aci2);
  int aci3 = ucgen - (aci1 + aci2);
  if (aci1 > 90 || aci2 > 90 || aci3 > 90) {
    printf("Bu ucgen genis acilidir...\n");
  } else if (aci1 == 90 || aci2 == 90 || aci3 == 90) {
    printf("Bu ucgen dik acilidir...\n");
  } else {
    printf("Bu ucgen dar acilidir...\n");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<TEST_should_push_and_pop_three_integers_to_integer_stack>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x3,%edi
  call   <init_integer_stack@plt>
  mov    %rax,-0x8(%rbp)
  lea    D30(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x1,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x2,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    $0x3,%esi
  mov    %rax,%rdi
  call   <push@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <pop@plt>
  mov    %eax,%esi
  lea    D19(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D30
datatype: string
name: retrieve_data
arguments: data_label: D19
datatype: string

tool: D30: 
Running: TEST_should_push_and_pop_three_integers_to_integer_stack.

tool: D19: 
Stack pop: %d,

assistant: ```c
void TEST_should_push_and_pop_three_integers_to_integer_stack() {
  struct integer_stack_head *integer_stack = init_integer_stack(3);
  printf("\nRunning: TEST_should_push_and_pop_three_integers_to_integer_stack.");
  push(integer_stack, 1);
  push(integer_stack, 2);
  push(integer_stack, 3);
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<TEST_should_push_and_pop_three_integers_to_integer_stack>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x3,%edi
  call   <init_integer_stack@plt>
  mov    %rax,%rbx
  lea    D9(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x2,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    $0x3,%esi
  mov    %rbx,%rdi
  call   <push@plt>
  mov    %rbx,%rdi
  call   <pop@plt>
  mov    %eax,%esi
  lea    D12(%rip),%rbp
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <pop@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <pop@plt>
  mov    %eax,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

tool_calls: name: read_data
arguments: data_label: D9
type_infered: string
name: read_data
arguments: data_label: D12
type_infered: string

tool: D9: 
Running: TEST_should_push_and_pop_three_integers_to_integer_stack.

tool: D12: 
Stack pop: %d,

assistant: ```c
void TEST_should_push_and_pop_three_integers_to_integer_stack() {
  struct integer_stack_head *integer_stack = init_integer_stack(3);
  printf("\nRunning: TEST_should_push_and_pop_three_integers_to_integer_stack.");
  push(integer_stack, 1);
  push(integer_stack, 2);
  push(integer_stack, 3);
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
}
```
user: What is the c source code of the assembly code below?

```asm
<TEST_should_push_and_pop_three_integers_to_integer_stack>:
  endbr64
  push   %r12
  mov    $0x3,%edi
  lea    D9(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <init_integer_stack@plt>
  lea    D5(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <push@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <push@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  mov    %eax,%esi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1090 <printf@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
type_infered: string
name: extract_symbolic_data
arguments: label: D5
type_infered: string

tool: D9: 
Stack pop: %d,

tool: D5: 
Running: TEST_should_push_and_pop_three_integers_to_integer_stack.

assistant: ```c
void TEST_should_push_and_pop_three_integers_to_integer_stack() {
  struct integer_stack_head *integer_stack = init_integer_stack(3);
  printf("\nRunning: TEST_should_push_and_pop_three_integers_to_integer_stack.");
  push(integer_stack, 1);
  push(integer_stack, 2);
  push(integer_stack, 3);
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<TEST_should_push_and_pop_three_integers_to_integer_stack>:
  endbr64
  push   %r12
  mov    $0x3,%edi
  lea    D13(%rip),%r12
  push   %rbp
  sub    $0x8,%rsp
  call   <init_integer_stack@plt>
  lea    D17(%rip),%rdi
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  mov    $0x1,%esi
  call   <push@plt>
  mov    %rbp,%rdi
  mov    $0x2,%esi
  call   <push@plt>
  mov    $0x3,%esi
  mov    %rbp,%rdi
  call   <push@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  mov    %r12,%rdi
  mov    %eax,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <pop@plt>
  add    $0x8,%rsp
  mov    %r12,%rdi
  mov    %eax,%esi
  pop    %rbp
  xor    %eax,%eax
  pop    %r12
  jmp    1090 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D13
data_type: string
name: disassemble_data
arguments: data_label: D17
data_type: string

tool: D13: 
Stack pop: %d,

tool: D17: 
Running: TEST_should_push_and_pop_three_integers_to_integer_stack.

assistant: ```c
void TEST_should_push_and_pop_three_integers_to_integer_stack() {
  struct integer_stack_head *integer_stack = init_integer_stack(3);
  printf("\nRunning: TEST_should_push_and_pop_three_integers_to_integer_stack.");
  push(integer_stack, 1);
  push(integer_stack, 2);
  push(integer_stack, 3);
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
  printf("\nStack pop: %d,", pop(integer_stack));
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<get_free_list>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x200,-0x4(%rbp)
  jmp    L18
L19:
  mov    -0x8(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,-0x4(%rbp)
L18:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jne    L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int get_free_list(int size) {
  int index = 0, current_size = 512;
  while (current_size != size) {
    index = 2 * index + 1;
    current_size = current_size / 2;
  }
  return index;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<get_free_list>:
  endbr64
  cmp    $0x200,%edi
  je     L28
  mov    $0x200,%edx
  mov    $0x0,%ecx
L16:
  lea    0x1(%rcx,%rcx,1),%ecx
  mov    %edx,%eax
  shr    $0x1f,%eax
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edx
  cmp    %eax,%edi
  jne    L16
L18:
  mov    %ecx,%eax
  ret
L28:
  mov    $0x0,%ecx
  jmp    L18
```

assistant: ```c
int get_free_list(int size) {
  int index = 0, current_size = 512;
  while (current_size != size) {
    index = 2 * index + 1;
    current_size = current_size / 2;
  }
  return index;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<get_free_list>:
  endbr64
  cmp    $0x200,%edi
  je     L4
  mov    $0x200,%eax
  xor    %r8d,%r8d
  nopl   0x0(%rax)
L18:
  mov    %eax,%edx
  lea    0x1(%r8,%r8,1),%r8d
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,%edi
  jne    L18
  mov    %r8d,%eax
  ret
  xchg   %ax,%ax
L4:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int get_free_list(int size) {
  int index = 0, current_size = 512;
  while (current_size != size) {
    index = 2 * index + 1;
    current_size = current_size / 2;
  }
  return index;
}
```