ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<table>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movsd  %xmm0,(%rsp)
  movsd  %xmm1,0x8(%rsp)
  test   %edi,%edi
  je     L11
  mov    %edi,%ebp
  mov    %rsi,%r12
  mov    $0x0,%ebx
  lea    D9(%rip),%r13
L16:
  mov    %ebx,%eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %rax,%xmm0
  mulsd  0x8(%rsp),%xmm0
  addsd  (%rsp),%xmm0
  movq   %xmm0,%r14
  call   *%r12
  movapd %xmm0,%xmm1
  movq   %r14,%xmm0
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L16
L11:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D9
datatype: string

tool: D9: %g:  %g


assistant: ```c
void table(double x0, double deltaX, unsigned rows, double (*f)(double x)) {
  unsigned r = 0;
  for (r; r < rows; r++) {
    double x = x0 + r * deltaX;
    double y = (*f)(x);
    printf("%g:  %g\n", x, y);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<table>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  test   %edi,%edi
  je     L19
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    D9(%rip),%r12
  xor    %r13d,%r13d
  nopl   (%rax)
L12:
  mov    %r13d,%eax
  pxor   %xmm2,%xmm2
  add    $0x1,%r13d
  cvtsi2sd %rax,%xmm2
  mulsd  0x18(%rsp),%xmm2
  addsd  0x10(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rbp
  movsd  0x8(%rsp),%xmm2
  mov    %r12,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L12
L19:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D9
type: string

tool: D9: %g:  %g


assistant: ```c
void table(double x0, double deltaX, unsigned rows, double (*f)(double x)) {
  unsigned r = 0;
  for (r; r < rows; r++) {
    double x = x0 + r * deltaX;
    double y = (*f)(x);
    printf("%g:  %g\n", x, y);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<table>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x28,%rsp
  movsd  %xmm0,0x10(%rsp)
  movsd  %xmm1,0x18(%rsp)
  test   %edi,%edi
  je     L5
  mov    %edi,%ebx
  mov    %rsi,%rbp
  lea    D5(%rip),%r12
  xor    %r13d,%r13d
  nopl   (%rax)
L8:
  mov    %r13d,%eax
  pxor   %xmm2,%xmm2
  add    $0x1,%r13d
  cvtsi2sd %rax,%xmm2
  mulsd  0x18(%rsp),%xmm2
  addsd  0x10(%rsp),%xmm2
  movapd %xmm2,%xmm0
  movsd  %xmm2,0x8(%rsp)
  call   *%rbp
  movsd  0x8(%rsp),%xmm2
  mov    %r12,%rdi
  movapd %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  cmp    %r13d,%ebx
  jne    L8
L5:
  add    $0x28,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D5
datatype: string

tool: D5: %g:  %g


assistant: ```c
void table(double x0, double deltaX, unsigned rows, double (*f)(double x)) {
  unsigned r = 0;
  for (r; r < rows; r++) {
    double x = x0 + r * deltaX;
    double y = (*f)(x);
    printf("%g:  %g\n", x, y);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<str_map>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,%edi
  call   <str_new@plt>
  mov    %rax,-0x18(%rbp)
  movq   $0x0,-0x20(%rbp)
  jmp    L9
L16:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rdx
  lea    (%rcx,%rdx,1),%rbx
  mov    -0x30(%rbp),%rdx
  mov    %eax,%edi
  call   *%rdx
  mov    %al,(%rbx)
  addq   $0x1,-0x20(%rbp)
  addq   $0x1,-0x20(%rbp)
L9:
  mov    -0x28(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  mov    -0x18(%rbp),%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
char *str_map(char *const s, char (*f)(char)) {
  char *new = str_new(strlen(s));
  for (size_t i = 0; s[i] != '\0'; i++) {
    new[i] = f(s[i]);
    i++;
  }
  return (new);
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<str_map>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %eax,%edi
  call   <str_new@plt>
  mov    %rax,%r12
  movzbl 0x0(%rbp),%edi
  test   %dil,%dil
  je     L17
  mov    $0x0,%ebx
L11:
  movsbl %dil,%edi
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x2,%rbx
  movzbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L11
L17:
  mov    %r12,%rax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *str_map(char *const s, char (*f)(char)) {
  char *new = str_new(strlen(s));
  for (size_t i = 0; s[i] != '\0'; i++) {
    new[i] = f(s[i]);
    i++;
  }
  return (new);
}
```
user: Translate the below assembly code into C programming language:

```asm
<str_map>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  call   <str_new@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L12
  xor    %ebx,%ebx
  xchg   %ax,%ax
L6:
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x2,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L6
L12:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *str_map(char *const s, char (*f)(char)) {
  char *new = str_new(strlen(s));
  for (size_t i = 0; s[i] != '\0'; i++) {
    new[i] = f(s[i]);
    i++;
  }
  return (new);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str_map>:
  endbr64
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  mov    %eax,%edi
  call   <str_new@plt>
  movsbl 0x0(%rbp),%edi
  mov    %rax,%r12
  test   %dil,%dil
  je     L4
  xor    %ebx,%ebx
  xchg   %ax,%ax
L18:
  call   *%r13
  mov    %al,(%r12,%rbx,1)
  add    $0x2,%rbx
  movsbl 0x0(%rbp,%rbx,1),%edi
  test   %dil,%dil
  jne    L18
L4:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

assistant: ```c
char *str_map(char *const s, char (*f)(char)) {
  char *new = str_new(strlen(s));
  for (size_t i = 0; s[i] != '\0'; i++) {
    new[i] = f(s[i]);
    i++;
  }
  return (new);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inComment>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L14
L18:
  mov    -0x4(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,-0x4(%rbp)
L14:
  cmpl   $0x2a,-0x8(%rbp)
  jne    L18
  cmpl   $0x2f,-0x4(%rbp)
  jne    L18
  nop
  nop
  leave
  ret
```

assistant: ```c
void inComment() {
  int c, d;
  c = getchar();
  d = getchar();
  while (c != '*' || d != '/') {
    c = d;
    d = getchar();
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inComment>:
  endbr64
  push   %rbx
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x2a,%ebx
  jne    L15
  cmp    $0x2f,%eax
  je     L9
L15:
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <getchar@plt>
  cmp    $0x2a,%ebx
  jne    L15
  cmp    $0x2f,%eax
  jne    L15
L9:
  pop    %rbx
  ret
```

assistant: ```c
void inComment() {
  int c, d;
  c = getchar();
  d = getchar();
  while (c != '*' || d != '/') {
    c = d;
    d = getchar();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<inComment>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  nopl   0x0(%rax)
L12:
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x2a,%ebx
  jne    L12
  cmp    $0x2f,%eax
  jne    L12
  pop    %rbx
  ret
```

assistant: ```c
void inComment() {
  int c, d;
  c = getchar();
  d = getchar();
  while (c != '*' || d != '/') {
    c = d;
    d = getchar();
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<inComment>:
  endbr64
  push   %rbx
  xor    %eax,%eax
  call   <getchar@plt>
  nopl   0x0(%rax)
L15:
  mov    %eax,%ebx
  xor    %eax,%eax
  call   <getchar@plt>
  cmp    $0x2a,%ebx
  jne    L15
  cmp    $0x2f,%eax
  jne    L15
  pop    %rbx
  ret
```

assistant: ```c
void inComment() {
  int c, d;
  c = getchar();
  d = getchar();
  while (c != '*' || d != '/') {
    c = d;
    d = getchar();
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Vector3SubtractFromSelf>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  movss  (%rax),%xmm1
  subss  %xmm1,%xmm0
  mov    -0x8(%rbp),%rax
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm0
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  movss  (%rax),%xmm1
  mov    -0x8(%rbp),%rax
  add    $0x8,%rax
  subss  %xmm1,%xmm0
  movss  %xmm0,(%rax)
  mov    -0x8(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
float *Vector3SubtractFromSelf(float v1[3], const float v2[3]) {
  v1[0] -= v2[0];
  v1[1] -= v2[1];
  v1[2] -= v2[2];
  return v1;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<Vector3SubtractFromSelf>:
  endbr64
  mov    %rdi,%rax
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *Vector3SubtractFromSelf(float v1[3], const float v2[3]) {
  v1[0] -= v2[0];
  v1[1] -= v2[1];
  v1[2] -= v2[2];
  return v1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<Vector3SubtractFromSelf>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *Vector3SubtractFromSelf(float v1[3], const float v2[3]) {
  v1[0] -= v2[0];
  v1[1] -= v2[1];
  v1[2] -= v2[2];
  return v1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Vector3SubtractFromSelf>:
  endbr64
  movss  (%rdi),%xmm0
  subss  (%rsi),%xmm0
  mov    %rdi,%rax
  movss  %xmm0,(%rdi)
  movss  0x4(%rdi),%xmm0
  subss  0x4(%rsi),%xmm0
  movss  %xmm0,0x4(%rdi)
  movss  0x8(%rdi),%xmm0
  subss  0x8(%rsi),%xmm0
  movss  %xmm0,0x8(%rdi)
  ret
```

assistant: ```c
float *Vector3SubtractFromSelf(float v1[3], const float v2[3]) {
  v1[0] -= v2[0];
  v1[1] -= v2[1];
  v1[2] -= v2[2];
  return v1;
}
```
user: What is the c source code of the assembly code below:

```asm
<xmodem_crc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movw   $0x0,-0x6(%rbp)
  jmp    L30
L8:
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x18(%rbp)
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  mov    %eax,%edx
  movzwl -0x6(%rbp),%eax
  xor    %edx,%eax
  mov    %ax,-0x6(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L47
L35:
  movzwl -0x6(%rbp),%eax
  test   %ax,%ax
  jns    L29
  movzwl -0x6(%rbp),%eax
  add    %eax,%eax
  xor    $0x1021,%ax
  mov    %ax,-0x6(%rbp)
  jmp    L9
L29:
  shlw   -0x6(%rbp)
L9:
  addl   $0x1,-0x4(%rbp)
L47:
  cmpl   $0x7,-0x4(%rbp)
  jle    L35
L30:
  mov    -0x1c(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,-0x1c(%rbp)
  test   %eax,%eax
  jne    L8
  movzwl -0x6(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int xmodem_crc(unsigned char *p, int len) {
  int i;
  unsigned short crc = 0;
  while (len--) {
    crc = crc ^ (unsigned short)*p++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return crc;
}
```
user: What is the c source code of the assembly code below?

```asm
<xmodem_crc>:
  endbr64
  test   %esi,%esi
  je     L20
  mov    %esi,%esi
  lea    (%rdi,%rsi,1),%r8
  mov    $0x0,%eax
  jmp    L14
L41:
  cmp    %r8,%rdi
  je     L29
L14:
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%edx
  shl    $0x8,%edx
  xor    %edx,%eax
  mov    $0x8,%ecx
L26:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  lea    (%rax,%rax,1),%esi
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%ecx
  jne    L26
  jmp    L41
L20:
  mov    $0x0,%eax
L29:
  movzwl %ax,%eax
  ret
```

assistant: ```c
int xmodem_crc(unsigned char *p, int len) {
  int i;
  unsigned short crc = 0;
  while (len--) {
    crc = crc ^ (unsigned short)*p++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return crc;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<xmodem_crc>:
  endbr64
  test   %esi,%esi
  je     L4
  mov    %esi,%esi
  xor    %eax,%eax
  lea    (%rdi,%rsi,1),%r8
L10:
  movzbl (%rdi),%edx
  add    $0x1,%rdi
  mov    $0x8,%ecx
  shl    $0x8,%edx
  xor    %edx,%eax
  nopl   0x0(%rax)
L22:
  lea    (%rax,%rax,1),%edx
  lea    (%rax,%rax,1),%esi
  xor    $0x1021,%dx
  test   %ax,%ax
  mov    %edx,%eax
  cmovns %esi,%eax
  sub    $0x1,%ecx
  jne    L22
  cmp    %rdi,%r8
  jne    L10
  movzwl %ax,%eax
  ret
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xmodem_crc(unsigned char *p, int len) {
  int i;
  unsigned short crc = 0;
  while (len--) {
    crc = crc ^ (unsigned short)*p++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return crc;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<xmodem_crc>:
  endbr64
  mov    %rdi,%rcx
  test   %esi,%esi
  je     L95
  mov    %esi,%esi
  xor    %eax,%eax
  add    %rdi,%rsi
  jmp    L162
  nopl   0x0(%rax,%rax,1)
L53:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L87
L125:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L166
L3:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L62
L137:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L109
L106:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L119
L14:
  add    %eax,%eax
  mov    %eax,%edx
  test   %dx,%dx
  js     L18
L127:
  add    %eax,%eax
  mov    %eax,%edx
L104:
  lea    (%rax,%rax,1),%edi
  mov    %edi,%eax
  xor    $0x1021,%ax
  test   %dx,%dx
  cmovns %edi,%eax
  cmp    %rcx,%rsi
  je     L144
L162:
  movzbl (%rcx),%edx
  add    $0x1,%rcx
  shl    $0x8,%edx
  xor    %dx,%ax
  jns    L53
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L125
L87:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L3
L166:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L137
L62:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L106
L109:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L14
L119:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  test   %dx,%dx
  jns    L127
L18:
  lea    (%rax,%rax,1),%edx
  xor    $0x1021,%dx
  mov    %edx,%eax
  jmp    L104
  xchg   %ax,%ax
L144:
  movzwl %ax,%eax
  ret
L95:
  xor    %eax,%eax
  ret
```

assistant: ```c
int xmodem_crc(unsigned char *p, int len) {
  int i;
  unsigned short crc = 0;
  while (len--) {
    crc = crc ^ (unsigned short)*p++ << 8;
    for (i = 0; i < 8; i++) {
      if (crc & 0x8000)
        crc = crc << 1 ^ 0x1021;
      else
        crc = crc << 1;
    }
  }
  return crc;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubsort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0xc(%rbp)
  jmp    L48
L38:
  movl   $0x0,-0x8(%rbp)
  jmp    L26
L21:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  jge    L3
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x8(%rbp),%edx
  add    $0x1,%edx
  mov    %edx,%edx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x8(%rbp),%eax
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
L3:
  addl   $0x1,-0x8(%rbp)
L26:
  mov    -0x1c(%rbp),%eax
  sub    -0xc(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x8(%rbp)
  jb     L21
  addl   $0x1,-0xc(%rbp)
L48:
  mov    -0xc(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jb     L38
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
int *bubsort(int *arr, unsigned n) {
  unsigned i, j;
  int temp;
  for (i = 0; i < n; ++i)
    for (j = 0; j < n - i - 1; ++j)
      if (arr[j + 1] < arr[j]) {
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  return arr;
}
```
user: Translate the below assembly code into C programming language:

```asm
<bubsort>:
  endbr64
  test   %esi,%esi
  je     L37
  lea    -0x1(%rsi),%r8d
  lea    0x4(%rdi),%r9
  jmp    L55
L17:
  add    $0x4,%rax
  cmp    %rax,%rsi
  je     L20
L31:
  mov    0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jge    L17
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
  jmp    L17
L20:
  sub    $0x1,%r8d
L55:
  test   %r8d,%r8d
  je     L37
  mov    %rdi,%rax
  lea    -0x1(%r8),%edx
  lea    (%r9,%rdx,4),%rsi
  jmp    L31
L37:
  mov    %rdi,%rax
  ret
```

assistant: ```c
int *bubsort(int *arr, unsigned n) {
  unsigned i, j;
  int temp;
  for (i = 0; i < n; ++i)
    for (j = 0; j < n - i - 1; ++j)
      if (arr[j + 1] < arr[j]) {
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  return arr;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<bubsort>:
  endbr64
  mov    %rdi,%r9
  test   %esi,%esi
  je     L35
  lea    -0x1(%rsi),%edx
  lea    0x4(%rdi),%rdi
  test   %edx,%edx
  je     L35
  cs nopw 0x0(%rax,%rax,1)
L47:
  sub    $0x1,%edx
  mov    %r9,%rax
  mov    %rdx,%r8
  lea    (%rdi,%rdx,4),%rsi
  nopl   (%rax)
L49:
  mov    0x4(%rax),%edx
  mov    (%rax),%ecx
  cmp    %ecx,%edx
  jge    L21
  mov    %ecx,0x4(%rax)
  mov    %edx,(%rax)
L21:
  add    $0x4,%rax
  cmp    %rax,%rsi
  jne    L49
  mov    %r8d,%edx
  test   %edx,%edx
  jne    L47
L35:
  mov    %r9,%rax
  ret
```

assistant: ```c
int *bubsort(int *arr, unsigned n) {
  unsigned i, j;
  int temp;
  for (i = 0; i < n; ++i)
    for (j = 0; j < n - i - 1; ++j)
      if (arr[j + 1] < arr[j]) {
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  return arr;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<bubsort>:
  endbr64
  mov    %rdi,%r9
  test   %esi,%esi
  je     L17
  lea    -0x1(%rsi),%eax
  lea    0x4(%rdi),%rdi
  test   %eax,%eax
  je     L17
  cs nopw 0x0(%rax,%rax,1)
L44:
  sub    $0x1,%eax
  mov    %r9,%rdx
  mov    %rax,%r8
  lea    (%rdi,%rax,4),%rsi
  nopl   (%rax)
L22:
  movq   (%rdx),%xmm0
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm0,%ecx
  movd   %xmm2,%eax
  pshufd $0xe1,%xmm0,%xmm1
  cmp    %eax,%ecx
  jle    L6
  movq   %xmm1,(%rdx)
L6:
  add    $0x4,%rdx
  cmp    %rsi,%rdx
  jne    L22
  mov    %r8d,%eax
  test   %eax,%eax
  jne    L44
L17:
  mov    %r9,%rax
  ret
```

assistant: ```c
int *bubsort(int *arr, unsigned n) {
  unsigned i, j;
  int temp;
  for (i = 0; i < n; ++i)
    for (j = 0; j < n - i - 1; ++j)
      if (arr[j + 1] < arr[j]) {
        temp = arr[j + 1];
        arr[j + 1] = arr[j];
        arr[j] = temp;
      }
  return arr;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<now>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <gettimeofday@plt>
  mov    -0x20(%rbp),%rax
  imul   $0x3e8,%rax,%rcx
  mov    -0x18(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x6,%edx
  sar    $0x1f,%eax
  mov    %eax,%esi
  mov    %edx,%eax
  sub    %esi,%eax
  cltq
  add    %rcx,%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L3
  call   <__stack_chk_fail@plt>
L3:
  leave
  ret
```

assistant: ```c
long long now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long long ms = (tv.tv_sec * 1000LL) + (tv.tv_usec / 1000);
  return ms;
}
```
user: What is the c source code of the assembly code below?

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  mov    $0x0,%esi
  call   <gettimeofday@plt>
  imul   $0x3e8,(%rsp),%rax
  mov    0x8(%rsp),%ecx
  movslq %ecx,%rdx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x26,%rdx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L9
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long long ms = (tv.tv_sec * 1000LL) + (tv.tv_usec / 1000);
  return ms;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L6
  add    $0x28,%rsp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long long ms = (tv.tv_sec * 1000LL) + (tv.tv_usec / 1000);
  return ms;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<now>:
  endbr64
  sub    $0x28,%rsp
  xor    %esi,%esi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <gettimeofday@plt>
  movslq 0x8(%rsp),%rdx
  imul   $0x3e8,(%rsp),%rax
  mov    %rdx,%rcx
  imul   $0x10624dd3,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x26,%rdx
  sub    %ecx,%edx
  movslq %edx,%rdx
  add    %rdx,%rax
  mov    0x18(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x28,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
long long now() {
  struct timeval tv;
  gettimeofday(&tv, NULL);
  long long ms = (tv.tv_sec * 1000LL) + (tv.tv_usec / 1000);
  return ms;
}
```