ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的：

```asm
<recursedigit>:
  endbr64
  test   %edi,%edi
  je     L29
  push   %rbx
  mov    %edi,%ebx
  shr    $0x1f,%edi
  add    %ebx,%edi
  sar    %edi
  call   <recursedigit>
  test   $0x1,%bl
  je     L5
  lea    D0(%rip),%rdi
  call   <printf@plt>
  jmp    L12
L5:
  lea    D6(%rip),%rdi
  call   <printf@plt>
L12:
  pop    %rbx
  ret
L29:
  ret
```

tool_calls: name: read_data
arguments: data_label: D0
type_infered: string
name: read_data
arguments: data_label: D6
type_infered: string

tool: D0: 1

tool: D6: 0

assistant: ```c
void recursedigit(int n) {
  int on;
  if (0 == n) {
    return;
  }
  on = 0;
  if (0 != (n - ((n / 2) * 2))) {
    on = 1;
  }
  recursedigit(n / 2);
  if (0 == on) {
    printf("0");
  }
  if (1 == on) {
    printf("1");
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<recursedigit>:
  endbr64
  test   %edi,%edi
  je     L204
  mov    %edi,%edx
  mov    %edi,%eax
  push   %r14
  shr    $0x1f,%edx
  push   %r13
  add    %edi,%edx
  push   %r12
  sar    %edx
  push   %rbp
  push   %rbx
  test   $0x1,%al
  jne    L85
  xor    %ebx,%ebx
  test   %edx,%edx
  je     L134
L68:
  test   %eax,%eax
  lea    0x3(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x2,%ecx
  and    $0x1,%edx
  je     L72
  mov    $0x1,%ebp
  test   %ecx,%ecx
  je     L209
L11:
  test   %eax,%eax
  lea    0x7(%rax),%edx
  cmovns %eax,%edx
  sar    $0x3,%edx
  and    $0x1,%ecx
  jne    L188
  xor    %r12d,%r12d
  test   %edx,%edx
  je     L6
L161:
  test   %eax,%eax
  lea    0xf(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x4,%ecx
  and    $0x1,%edx
  je     L230
  mov    $0x1,%r13d
  test   %ecx,%ecx
  je     L275
L280:
  test   %eax,%eax
  lea    0x1f(%rax),%edx
  cmovns %eax,%edx
  sar    $0x5,%edx
  and    $0x1,%ecx
  je     L169
  mov    $0x1,%r14d
  test   %edx,%edx
  je     L120
L62:
  test   %eax,%eax
  lea    0x3f(%rax),%edi
  cmovns %eax,%edi
  sar    $0x6,%edi
  and    $0x1,%edx
  jne    L221
  call   <recursedigit>
  lea    D5(%rip),%rdi
  call   <printf@plt>
L227:
  test   %r14d,%r14d
  jne    L120
L71:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L60
  nopl   0x0(%rax)
L85:
  mov    $0x1,%ebx
  test   %edx,%edx
  jne    L68
L18:
  pop    %rbx
  lea    D10(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L120:
  lea    D10(%rip),%rdi
  call   <printf@plt>
L60:
  test   %r13d,%r13d
  je     L98
L275:
  lea    D10(%rip),%rdi
  call   <printf@plt>
L222:
  test   %r12d,%r12d
  je     L6
L119:
  lea    D10(%rip),%rdi
  call   <printf@plt>
L198:
  test   %ebp,%ebp
  je     L288
L209:
  lea    D10(%rip),%rdi
  call   <printf@plt>
L241:
  test   %ebx,%ebx
  jne    L18
L134:
  pop    %rbx
  lea    D5(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L204:
  ret
  nopl   0x0(%rax)
L72:
  xor    %ebp,%ebp
  test   %ecx,%ecx
  jne    L11
L288:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L241
  nopl   0x0(%rax,%rax,1)
L188:
  mov    $0x1,%r12d
  test   %edx,%edx
  jne    L161
  jmp    L119
L6:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L198
  xchg   %ax,%ax
L230:
  xor    %r13d,%r13d
  test   %ecx,%ecx
  jne    L280
L98:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  jmp    L222
  nopl   0x0(%rax)
L169:
  xor    %r14d,%r14d
  test   %edx,%edx
  jne    L62
  jmp    L71
L221:
  call   <recursedigit>
  lea    D10(%rip),%rdi
  call   <printf@plt>
  jmp    L227
```

tool_calls: name: parse_data
arguments: tag: D5
type: string
name: parse_data
arguments: tag: D10
type: string

tool: D5: 0

tool: D10: 1

assistant: ```c
void recursedigit(int n) {
  int on;
  if (0 == n) {
    return;
  }
  on = 0;
  if (0 != (n - ((n / 2) * 2))) {
    on = 1;
  }
  recursedigit(n / 2);
  if (0 == on) {
    printf("0");
  }
  if (1 == on) {
    printf("1");
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<recursedigit>:
  endbr64
  test   %edi,%edi
  je     L85
  mov    %edi,%edx
  mov    %edi,%eax
  push   %r14
  shr    $0x1f,%edx
  push   %r13
  add    %edi,%edx
  push   %r12
  sar    %edx
  push   %rbp
  push   %rbx
  test   $0x1,%al
  jne    L240
  xor    %ebx,%ebx
  test   %edx,%edx
  je     L253
L76:
  test   %eax,%eax
  lea    0x3(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x2,%ecx
  and    $0x1,%edx
  je     L185
  mov    $0x1,%ebp
  test   %ecx,%ecx
  je     L80
L273:
  test   %eax,%eax
  lea    0x7(%rax),%edx
  cmovns %eax,%edx
  sar    $0x3,%edx
  and    $0x1,%ecx
  jne    L138
  xor    %r12d,%r12d
  test   %edx,%edx
  je     L5
L141:
  test   %eax,%eax
  lea    0xf(%rax),%ecx
  cmovns %eax,%ecx
  sar    $0x4,%ecx
  and    $0x1,%edx
  je     L272
  mov    $0x1,%r13d
  test   %ecx,%ecx
  je     L10
L279:
  test   %eax,%eax
  lea    0x1f(%rax),%edx
  cmovns %eax,%edx
  sar    $0x5,%edx
  and    $0x1,%ecx
  je     L284
  mov    $0x1,%r14d
  test   %edx,%edx
  je     L32
L263:
  test   %eax,%eax
  lea    0x3f(%rax),%edi
  cmovns %eax,%edi
  sar    $0x6,%edi
  and    $0x1,%edx
  jne    L48
  call   <recursedigit>
  lea    D19(%rip),%rdi
  call   <printf@plt>
L200:
  test   %r14d,%r14d
  jne    L32
L95:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L255
  nopl   0x0(%rax)
L240:
  mov    $0x1,%ebx
  test   %edx,%edx
  jne    L76
L184:
  pop    %rbx
  lea    D75(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopl   0x0(%rax)
L32:
  lea    D75(%rip),%rdi
  call   <printf@plt>
L255:
  test   %r13d,%r13d
  je     L77
L10:
  lea    D75(%rip),%rdi
  call   <printf@plt>
L54:
  test   %r12d,%r12d
  je     L5
L212:
  lea    D75(%rip),%rdi
  call   <printf@plt>
L35:
  test   %ebp,%ebp
  je     L116
L80:
  lea    D75(%rip),%rdi
  call   <printf@plt>
L260:
  test   %ebx,%ebx
  jne    L184
L253:
  pop    %rbx
  lea    D19(%rip),%rdi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  jmp    1050 <printf@plt>
  nopw   0x0(%rax,%rax,1)
L85:
  ret
  nopl   0x0(%rax)
L185:
  xor    %ebp,%ebp
  test   %ecx,%ecx
  jne    L273
L116:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L260
  nopl   0x0(%rax,%rax,1)
L138:
  mov    $0x1,%r12d
  test   %edx,%edx
  jne    L141
  jmp    L212
L5:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L35
  xchg   %ax,%ax
L272:
  xor    %r13d,%r13d
  test   %ecx,%ecx
  jne    L279
L77:
  lea    D19(%rip),%rdi
  call   <printf@plt>
  jmp    L54
  nopl   0x0(%rax)
L284:
  xor    %r14d,%r14d
  test   %edx,%edx
  jne    L263
  jmp    L95
L48:
  call   <recursedigit>
  lea    D75(%rip),%rdi
  call   <printf@plt>
  jmp    L200
```

tool_calls: name: parse_data
arguments: data_label: D19
type_infered: string
name: parse_data
arguments: data_label: D75
type_infered: string

tool: D19: 0

tool: D75: 1

assistant: ```c
void recursedigit(int n) {
  int on;
  if (0 == n) {
    return;
  }
  on = 0;
  if (0 != (n - ((n / 2) * 2))) {
    on = 1;
  }
  recursedigit(n / 2);
  if (0 == on) {
    printf("0");
  }
  if (1 == on) {
    printf("1");
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  movl   $0x0,-0xc(%rbp)
  jmp    L1
L2:
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D23(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  call   <print_results@plt>
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%esi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0xc(%rbp)
L1:
  cmpl   $0x2,-0xc(%rbp)
  jle    L2
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D9
data_type: string
name: read_data
arguments: label: D23
data_type: string
name: read_data
arguments: label: D10
data_type: string

tool: D9: rsqrtf

tool: D23: # c::native::%s


tool: D10: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "rsqrtf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <print_version@plt>
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
  lea    D16(%rip),%r12
  lea    D1(%rip),%rbp
L1:
  mov    %r13,%rsi
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  add    $0x1,%ebx
  mov    %ebx,%esi
  mov    %rbp,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L1
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D16
type_infered: string
name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D0: rsqrtf

tool: D16: # c::native::%s


tool: D1: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "rsqrtf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D5(%rip),%r13
  push   %r12
  lea    D9(%rip),%r12
  push   %rbp
  lea    D7(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L5:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L5
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: tag: D5
type_guessed: string
name: read_data
arguments: tag: D9
type_guessed: string
name: read_data
arguments: tag: D7
type_guessed: string

tool: D5: rsqrtf

tool: D9: # c::native::%s


tool: D7: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "rsqrtf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %r13
  xor    %edi,%edi
  lea    D0(%rip),%r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  lea    D26(%rip),%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %eax,%edi
  call   <srand@plt>
  xor    %eax,%eax
  call   <print_version@plt>
L4:
  mov    %r13,%rsi
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%ebx
  call   <printf@plt>
  xor    %eax,%eax
  call   <benchmark@plt>
  call   <print_results@plt>
  xor    %eax,%eax
  mov    %ebx,%esi
  mov    %rbp,%rdi
  call   <printf@plt>
  cmp    $0x3,%ebx
  jne    L4
  mov    $0x3,%esi
  mov    $0x3,%edi
  call   <print_summary@plt>
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
```

tool_calls: name: read_data
arguments: data_tag: D0
datatype: string
name: read_data
arguments: data_tag: D17
datatype: string
name: read_data
arguments: data_tag: D26
datatype: string

tool: D0: rsqrtf

tool: D17: # c::native::%s


tool: D26: ok %d benchmark finished


assistant: ```c
int main(void) {
  double elapsed;
  int i;
  srand(time(NULL));
  print_version();
  for (i = 0; i < 3; i++) {
    printf("# c::native::%s\n", "rsqrtf");
    elapsed = benchmark();
    print_results(elapsed);
    printf("ok %d benchmark finished\n", i + 1);
  }
  print_summary(3, 3);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<__hexfloattofloatintpart>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x28(%rbp)
  movl   $0x0,-0x14(%rbp)
  mov    -0x28(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2d,%al
  jne    L11
  movl   $0x1,-0x14(%rbp)
L11:
  fldz
  fstpt  -0x10(%rbp)
  movl   $0x0,-0x1c(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    $0x1,%eax
  mov    %eax,-0x18(%rbp)
  jmp    L12
L35:
  cmpl   $0x0,-0x1c(%rbp)
  je     L40
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get_digit@plt>
  fstpt  -0x40(%rbp)
  mov    -0x1c(%rbp),%eax
  mov    %eax,%esi
  mov    $0x10,%edi
  call   <powl@plt>
  fldt   -0x40(%rbp)
  fmulp  %st,%st(1)
  fldt   -0x10(%rbp)
  faddp  %st,%st(1)
  fstpt  -0x10(%rbp)
  jmp    L38
L40:
  mov    -0x18(%rbp),%edx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <get_digit@plt>
  fstpt  -0x10(%rbp)
L38:
  addl   $0x1,-0x1c(%rbp)
  subl   $0x1,-0x18(%rbp)
L12:
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  sub    -0x14(%rbp),%eax
  cmp    %eax,-0x1c(%rbp)
  jb     L35
  fldt   -0x10(%rbp)
  leave
  ret
```

assistant: ```c
long double __hexfloattofloatintpart(const char *buffer) {
  unsigned int c, i, pad;
  long double res;
  pad = 0;
  if (buffer[0] == '-') {
    pad = 1;
  }
  res = 0.0;
  for (c = 0, i = strlen(buffer) - 1; c < strlen(buffer) - pad; c++, i--) {
    if (!c == 0) {
      res = res + (get_digit(buffer[i]) * powl(16, c));
    } else {
      res = get_digit(buffer[i]);
    }
  }
  return res;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<__hexfloattofloatintpart>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %rdi,%r12
  cmpb   $0x2d,(%rdi)
  sete   %r14b
  movzbl %r14b,%r14d
  call   <strlen@plt>
  lea    -0x1(%rax),%r13d
  fldz
  fstpt  (%rsp)
  mov    $0x0,%ebx
  jmp    L25
L14:
  mov    %ebp,%ebp
  movsbl (%r12,%rbp,1),%edi
  call   <get_digit@plt>
  fstpt  (%rsp)
L31:
  add    $0x1,%ebx
L25:
  mov    %r13d,%ebp
  sub    %ebx,%ebp
  mov    %r12,%rdi
  call   <strlen@plt>
  sub    %r14d,%eax
  cmp    %ebx,%eax
  jbe    L38
  test   %ebx,%ebx
  je     L14
  mov    %ebp,%ebp
  movsbl (%r12,%rbp,1),%edi
  call   <get_digit@plt>
  fstpt  0x10(%rsp)
  mov    %ebx,%esi
  mov    $0x10,%edi
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fldt   (%rsp)
  faddp  %st,%st(1)
  fstpt  (%rsp)
  jmp    L31
L38:
  fldt   (%rsp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long double __hexfloattofloatintpart(const char *buffer) {
  unsigned int c, i, pad;
  long double res;
  pad = 0;
  if (buffer[0] == '-') {
    pad = 1;
  }
  res = 0.0;
  for (c = 0, i = strlen(buffer) - 1; c < strlen(buffer) - pad; c++, i--) {
    if (!c == 0) {
      res = res + (get_digit(buffer[i]) * powl(16, c));
    } else {
      res = get_digit(buffer[i]);
    }
  }
  return res;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<__hexfloattofloatintpart>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  cmpb   $0x2d,(%rdi)
  sete   %r14b
  xor    %ebx,%ebx
  call   <strlen@plt>
  fldz
  lea    -0x1(%rax),%r13d
  fstpt  (%rsp)
  jmp    L35
  nop
L23:
  call   <get_digit@plt>
  mov    %ebx,%esi
  mov    $0x10,%edi
  fstpt  0x10(%rsp)
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fldt   (%rsp)
  faddp  %st,%st(1)
  fstpt  (%rsp)
L7:
  add    $0x1,%ebx
L35:
  mov    %r12,%rdi
  mov    %r13d,%ebp
  call   <strlen@plt>
  sub    %ebx,%ebp
  sub    %r14d,%eax
  cmp    %ebx,%eax
  jbe    L18
  movsbl (%r12,%rbp,1),%edi
  test   %ebx,%ebx
  jne    L23
  call   <get_digit@plt>
  fstpt  (%rsp)
  jmp    L7
  nopl   (%rax)
L18:
  fldt   (%rsp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long double __hexfloattofloatintpart(const char *buffer) {
  unsigned int c, i, pad;
  long double res;
  pad = 0;
  if (buffer[0] == '-') {
    pad = 1;
  }
  res = 0.0;
  for (c = 0, i = strlen(buffer) - 1; c < strlen(buffer) - pad; c++, i--) {
    if (!c == 0) {
      res = res + (get_digit(buffer[i]) * powl(16, c));
    } else {
      res = get_digit(buffer[i]);
    }
  }
  return res;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__hexfloattofloatintpart>:
  endbr64
  push   %r14
  xor    %r14d,%r14d
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  cmpb   $0x2d,(%rdi)
  sete   %r14b
  xor    %ebx,%ebx
  call   <strlen@plt>
  fldz
  lea    -0x1(%rax),%r13d
  fstpt  (%rsp)
  jmp    L37
  nop
L13:
  call   <get_digit@plt>
  mov    %ebx,%esi
  mov    $0x10,%edi
  fstpt  0x10(%rsp)
  call   <powl@plt>
  fldt   0x10(%rsp)
  fmulp  %st,%st(1)
  fldt   (%rsp)
  faddp  %st,%st(1)
  fstpt  (%rsp)
L0:
  add    $0x1,%ebx
L37:
  mov    %r12,%rdi
  mov    %r13d,%ebp
  call   <strlen@plt>
  sub    %ebx,%ebp
  sub    %r14d,%eax
  cmp    %ebx,%eax
  jbe    L19
  movsbl (%r12,%rbp,1),%edi
  test   %ebx,%ebx
  jne    L13
  call   <get_digit@plt>
  fstpt  (%rsp)
  jmp    L0
  nopl   (%rax)
L19:
  fldt   (%rsp)
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
long double __hexfloattofloatintpart(const char *buffer) {
  unsigned int c, i, pad;
  long double res;
  pad = 0;
  if (buffer[0] == '-') {
    pad = 1;
  }
  res = 0.0;
  for (c = 0, i = strlen(buffer) - 1; c < strlen(buffer) - pad; c++, i--) {
    if (!c == 0) {
      res = res + (get_digit(buffer[i]) * powl(16, c));
    } else {
      res = get_digit(buffer[i]);
    }
  }
  return res;
}
```
user: Translate the below assembly code into C programming language:

```asm
<argvpos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <argvarg@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  je     L14
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  sar    $0x3,%rax
  jmp    L10
L14:
  mov    $0xffffffff,%eax
L10:
  leave
  ret
```

assistant: ```c
int argvpos(char const *const *argv, char const *arg) {
  char **a = argvarg(argv, arg);
  if (a)
    return a - (char **)argv;
  else
    return -1;
}
```
user: Translate the below assembly code into C programming language:

```asm
<argvpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <argvarg@plt>
  test   %rax,%rax
  je     L2
  sub    %rbx,%rax
  sar    $0x3,%rax
L0:
  pop    %rbx
  ret
L2:
  mov    $0xffffffff,%eax
  jmp    L0
```

assistant: ```c
int argvpos(char const *const *argv, char const *arg) {
  char **a = argvarg(argv, arg);
  if (a)
    return a - (char **)argv;
  else
    return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<argvpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <argvarg@plt>
  test   %rax,%rax
  je     L9
  sub    %rbx,%rax
  pop    %rbx
  sar    $0x3,%rax
  ret
L9:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int argvpos(char const *const *argv, char const *arg) {
  char **a = argvarg(argv, arg);
  if (a)
    return a - (char **)argv;
  else
    return -1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<argvpos>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  call   <argvarg@plt>
  test   %rax,%rax
  je     L4
  sub    %rbx,%rax
  pop    %rbx
  sar    $0x3,%rax
  ret
L4:
  mov    $0xffffffff,%eax
  pop    %rbx
  ret
```

assistant: ```c
int argvpos(char const *const *argv, char const *arg) {
  char **a = argvarg(argv, arg);
  if (a)
    return a - (char **)argv;
  else
    return -1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x3,-0x4(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x18(%rbp)
  jmp    L63
L112:
  movl   $0x0,-0x14(%rbp)
  jmp    L53
L137:
  movl   $0x0,-0x10(%rbp)
  jmp    L10
L41:
  cmpl   $0x1,-0x18(%rbp)
  jne    L85
  cmpl   $0x1,-0x14(%rbp)
  jne    L85
  cmpl   $0x1,-0x10(%rbp)
  jne    L85
  movl   $0x1,-0x8(%rbp)
  jmp    L91
L85:
  addl   $0x1,-0xc(%rbp)
  addl   $0x1,-0x10(%rbp)
L10:
  mov    -0x10(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L41
L91:
  cmpl   $0x0,-0x8(%rbp)
  jne    L22
  addl   $0x1,-0x14(%rbp)
L53:
  mov    -0x14(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L137
  jmp    L64
L22:
  nop
L64:
  cmpl   $0x0,-0x8(%rbp)
  jne    L5
  addl   $0x1,-0x18(%rbp)
L63:
  mov    -0x18(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jl     L112
  jmp    L71
L5:
  nop
L71:
  mov    -0xc(%rbp),%eax
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_label: D2
type_guessed: string

tool: D2: Count = %d



assistant: ```c
int main() {
  int i, j, k, n = 3, count = 0, breakIt = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        if (i == 1 && j == 1 && k == 1) {
          breakIt = 1;
          break;
        }
        count++;
      }
      if (breakIt)
        break;
    }
    if (breakIt)
      break;
  }
  printf("Count = %d\n\n", count);
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%esi
  mov    $0x0,%edx
  jmp    L59
L8:
  lea    0x3(%rcx),%esi
  add    $0x1,%eax
  cmp    $0x3,%eax
  je     L1
L54:
  mov    %esi,%ecx
  add    $0x1,%esi
  cmp    $0x1,%edx
  jne    L8
  cmp    $0x1,%eax
  jne    L8
L42:
  lea    D3(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L1:
  add    $0x1,%edx
  cmp    $0x3,%edx
  je     L42
L59:
  mov    $0x0,%eax
  jmp    L54
```

tool_calls: name: disassemble_data
arguments: data_tag: D3
type_guessed: string

tool: D3: Count = %d



assistant: ```c
int main() {
  int i, j, k, n = 3, count = 0, breakIt = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        if (i == 1 && j == 1 && k == 1) {
          breakIt = 1;
          break;
        }
        count++;
      }
      if (breakIt)
        break;
    }
    if (breakIt)
      break;
  }
  printf("Count = %d\n\n", count);
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  xor    %esi,%esi
  xor    %edx,%edx
L24:
  xor    %eax,%eax
L40:
  mov    %esi,%ecx
  add    $0x1,%esi
  cmp    $0x1,%eax
  jne    L0
  cmp    $0x1,%edx
  jne    L0
L41:
  lea    D5(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
L0:
  add    $0x1,%eax
  lea    0x3(%rcx),%esi
  cmp    $0x3,%eax
  jne    L40
  add    $0x1,%edx
  cmp    $0x3,%edx
  jne    L24
  jmp    L41
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type_guessed: string

tool: D5: Count = %d



assistant: ```c
int main() {
  int i, j, k, n = 3, count = 0, breakIt = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++) {
      for (k = 0; k < n; k++) {
        if (i == 1 && j == 1 && k == 1) {
          breakIt = 1;
          break;
        }
        count++;
      }
      if (breakIt)
        break;
    }
    if (breakIt)
      break;
  }
  printf("Count = %d\n\n", count);
  return 0;
}
```