ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<SHAMD5HMACPPKeyGenerate>:
  endbr64
  mov    %edi,%r10d
  lea    0x118(%rdi),%edi
  mov    %rdx,%r9
  movslq %edi,%rdi
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rdi),%rax
  test   $0x8,%al
  je     L37
  movslq %r10d,%rax
  mov    %rax,%r11
  lea    0x40(%rax),%rcx
  mov    %rax,%rdx
  neg    %r11
  shl    $0x2,%r11
  lea    (%rsi,%r11,1),%r8
  nopw   0x0(%rax,%rax,1)
L7:
  movslq (%r8,%rdx,4),%rsi
  add    $0x4,%rdx
  mov    %rsi,-0x4(%rdx)
  cmp    %rcx,%rdx
  jne    L7
  lea    0x44(%r10),%edx
  add    $0x48,%r10d
  movslq %edx,%rdx
  movslq %r10d,%r10
  mov    (%rdx),%rsi
  or     $0x20,%rsi
  mov    %rsi,(%rdx)
  movq   $0x0,(%r10)
L0:
  mov    (%rdi),%rdx
  and    $0x1,%edx
  je     L0
  lea    (%r9,%r11,1),%rsi
  nopl   0x0(%rax)
L39:
  mov    (%rax),%rdx
  mov    %edx,(%rsi,%rax,4)
  add    $0x4,%rax
  cmp    %rcx,%rax
  jne    L39
  ret
```

assistant: ```c
void SHAMD5HMACPPKeyGenerate(uint32_t ui32Base, uint8_t *pui8Key, uint8_t *pui8PPKey) {
  uint32_t ui32Index;
  ;
  while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000008) == 0) {
  }
  for (ui32Index = 0; ui32Index < 64; ui32Index += 4) {
    (*((volatile unsigned long *)(ui32Base + 0x00000000 + ui32Index))) = *((uint32_t *)(pui8Key + ui32Index));
  }
  (*((volatile unsigned long *)(ui32Base + 0x00000044))) |= 0x00000020;
  (*((volatile unsigned long *)(ui32Base + 0x00000048))) = 0;
  while (((*((volatile unsigned long *)(ui32Base + 0x00000118))) & 0x00000001) == 0) {
  }
  for (ui32Index = 0; ui32Index < 64; ui32Index += 4) {
    *((uint32_t *)(pui8PPKey + ui32Index)) = (*((volatile unsigned long *)(ui32Base + 0x00000000 + ui32Index)));
  }
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<find_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  cmpl   $0x0,-0x28(%rbp)
  je     L46
  mov    $0x0,%eax
  jmp    L42
L38:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L68
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  jmp    L42
L68:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x2e,%al
  jne    L62
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x4(%rbp),%eax
  jmp    L42
L62:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5c,%al
  je     L21
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x3a,%al
  jne    L32
L21:
  mov    $0x0,%eax
  jmp    L42
L32:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x4(%rbp),%edx
  movslq %edx,%rcx
  mov    -0x20(%rbp),%rdx
  add    %rcx,%rdx
  movzbl (%rax),%eax
  mov    %al,(%rdx)
  addl   $0x1,-0x4(%rbp)
L46:
  mov    -0x4(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L38
  mov    $0x0,%eax
L42:
  pop    %rbp
  ret
```

assistant: ```c
int find_file(const char *path, char *buf, int length, int is_dir) {
  int i = 0;
  if (is_dir)
    return 0;
  while (i < length) {
    if (path[i] == 0) {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '.') {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '\\' || path[i] == ':')
      return 0;
    buf[i] = path[i];
    ++i;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<find_file>:
  endbr64
  mov    $0x0,%r9d
  test   %ecx,%ecx
  jne    L25
  test   %edx,%edx
  jle    L53
  mov    %edx,%edx
  mov    $0x0,%eax
L97:
  mov    %eax,%r9d
  movzbl (%rdi,%rax,1),%r8d
  test   %r8b,%r8b
  je     L17
  cmp    $0x2e,%r8b
  je     L98
  cmp    $0x5c,%r8b
  je     L109
  cmp    $0x3a,%r8b
  je     L109
  mov    %r8b,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  jne    L97
  mov    %ecx,%r9d
  jmp    L25
L17:
  movb   $0x0,(%rsi,%rax,1)
L25:
  mov    %r9d,%eax
  ret
L98:
  movb   $0x0,(%rsi,%rax,1)
  jmp    L25
L53:
  mov    %ecx,%r9d
  jmp    L25
L109:
  mov    %ecx,%r9d
  jmp    L25
```

assistant: ```c
int find_file(const char *path, char *buf, int length, int is_dir) {
  int i = 0;
  if (is_dir)
    return 0;
  while (i < length) {
    if (path[i] == 0) {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '.') {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '\\' || path[i] == ':')
      return 0;
    buf[i] = path[i];
    ++i;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<find_file>:
  endbr64
  test   %ecx,%ecx
  jne    L20
  test   %edx,%edx
  jle    L20
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L67
  nopl   0x0(%rax,%rax,1)
L40:
  cmp    $0x2e,%cl
  je     L56
  cmp    $0x5c,%cl
  je     L20
  cmp    $0x3a,%cl
  je     L20
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L20
L67:
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%r8d
  test   %cl,%cl
  jne    L40
L56:
  movb   $0x0,(%rsi,%rax,1)
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L20:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_file(const char *path, char *buf, int length, int is_dir) {
  int i = 0;
  if (is_dir)
    return 0;
  while (i < length) {
    if (path[i] == 0) {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '.') {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '\\' || path[i] == ':')
      return 0;
    buf[i] = path[i];
    ++i;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<find_file>:
  endbr64
  test   %ecx,%ecx
  jne    L66
  test   %edx,%edx
  jle    L66
  movslq %edx,%rdx
  xor    %eax,%eax
  jmp    L12
  nopl   0x0(%rax,%rax,1)
L65:
  cmp    $0x2e,%cl
  je     L48
  cmp    $0x5c,%cl
  je     L66
  cmp    $0x3a,%cl
  je     L66
  mov    %cl,(%rsi,%rax,1)
  add    $0x1,%rax
  cmp    %rdx,%rax
  je     L66
L12:
  movzbl (%rdi,%rax,1),%ecx
  mov    %eax,%r8d
  test   %cl,%cl
  jne    L65
L48:
  movb   $0x0,(%rsi,%rax,1)
  mov    %r8d,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L66:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
int find_file(const char *path, char *buf, int length, int is_dir) {
  int i = 0;
  if (is_dir)
    return 0;
  while (i < length) {
    if (path[i] == 0) {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '.') {
      buf[i] = 0;
      return i;
    }
    if (path[i] == '\\' || path[i] == ':')
      return 0;
    buf[i] = path[i];
    ++i;
  }
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<read_line>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movl   $0x50,-0x10(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    $0x50,%edi
  call   <zmalloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L64
  movl   $0x1,-0xc(%rbp)
  jmp    L64
L17:
  mov    -0x8(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x10(%rbp)
  jg     L90
  mov    -0x10(%rbp),%eax
  add    %eax,%eax
  add    $0x1,%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    -0x10(%rbp),%edx
  mov    %edx,%esi
  mov    %rax,%rdi
  call   <zrealloc@plt>
  mov    -0x20(%rbp),%rdx
  mov    %rax,(%rdx)
L90:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rcx
  mov    -0x8(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x8(%rbp)
  cltq
  add    %rcx,%rax
  mov    -0x4(%rbp),%edx
  mov    %dl,(%rax)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <getc@plt>
  mov    %eax,-0x4(%rbp)
  mov    D6(%rip),%rax
  mov    (%rax),%eax
  cmp    %eax,-0x4(%rbp)
  jne    L64
  movl   $0x1,-0xc(%rbp)
L64:
  cmpl   $0xa,-0x4(%rbp)
  je     L24
  cmpl   $0x0,-0xc(%rbp)
  je     L17
L24:
  cmpl   $0x0,-0xc(%rbp)
  je     L81
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rdi
  call   <free@plt>
  mov    -0x20(%rbp),%rax
  movq   $0x0,(%rax)
  mov    $0x0,%eax
  jmp    L98
L67:
  subl   $0x1,-0x8(%rbp)
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L28
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%eax
  cltq
  add    %rdx,%rax
  movb   $0x0,(%rax)
L81:
  cmpl   $0x1,-0x8(%rbp)
  jg     L67
  jmp    L91
L28:
  nop
L91:
  mov    $0x1,%eax
L98:
  leave
  ret
```

assistant: ```c
int read_line(FILE *fp, char **buffer) {
  int buffer_size = (80);
  int eof = 0;
  int position = 0;
  int c;
  *buffer = zmalloc((80));
  (*buffer)[0] = '\0';
  if ((c = getc(fp)) == EOF)
    eof = 1;
  while (c != '\n' && !eof) {
    if (position + 1 >= buffer_size) {
      buffer_size = buffer_size * 2 + 1;
      *buffer = zrealloc(*buffer, buffer_size);
    }
    (*buffer)[position++] = c;
    (*buffer)[position] = '\0';
    c = getc(fp);
    if (c == EOF)
      eof = 1;
  }
  if (eof) {
    free(*buffer);
    *buffer = NULL;
    return 0;
  }
  while (position > 1) {
    position--;
    if (!isspace((*buffer)[position]))
      break;
    (*buffer)[position] = '\0';
  }
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<read_line>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r15
  mov    %rsi,%r12
  mov    $0x50,%edi
  call   <zmalloc@plt>
  mov    %rax,(%r12)
  movb   $0x0,(%rax)
  mov    %r15,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  cmp    $0xa,%ebx
  je     L37
  mov    $0x1,%ebp
  mov    $0x50,%r14d
  cmp    %ebx,%eax
  jne    L42
L37:
  cmp    %ebx,%eax
  jne    L118
L61:
  mov    (%r12),%rdi
  call   <free@plt>
  movq   $0x0,(%r12)
  mov    $0x0,%eax
  jmp    L80
L19:
  add    $0x1,%rbp
L42:
  mov    %ebp,%r13d
  mov    %ebp,0xc(%rsp)
  mov    (%r12),%rax
  mov    %bl,-0x1(%rax,%rbp,1)
  mov    (%r12),%rax
  movb   $0x0,(%rax,%rbp,1)
  mov    %r15,%rdi
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D4(%rip),%rax
  cmp    %ebx,(%rax)
  je     L61
  cmp    $0xa,%ebx
  je     L100
  add    $0x1,%r13d
  cmp    %r13d,%r14d
  jg     L19
  lea    0x1(%r14,%r14,1),%r14d
  mov    %r14d,%esi
  mov    (%r12),%rdi
  call   <zrealloc@plt>
  mov    %rax,(%r12)
  jmp    L19
L122:
  mov    $0x1,%eax
L80:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L118:
  mov    $0x1,%eax
  jmp    L80
L100:
  cmpl   $0x1,0xc(%rsp)
  jle    L11
  movslq 0xc(%rsp),%rax
  lea    -0x1(%rax),%rbx
  sub    $0x2,%rax
  lea    -0x2(%rbp),%edx
  sub    %rdx,%rax
  mov    %rax,%rbp
L124:
  mov    (%r12),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  je     L122
  mov    (%r12),%rax
  movb   $0x0,(%rax,%rbx,1)
  sub    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L124
  mov    $0x1,%eax
  jmp    L80
L11:
  mov    $0x1,%eax
  jmp    L80
```

assistant: ```c
int read_line(FILE *fp, char **buffer) {
  int buffer_size = (80);
  int eof = 0;
  int position = 0;
  int c;
  *buffer = zmalloc((80));
  (*buffer)[0] = '\0';
  if ((c = getc(fp)) == EOF)
    eof = 1;
  while (c != '\n' && !eof) {
    if (position + 1 >= buffer_size) {
      buffer_size = buffer_size * 2 + 1;
      *buffer = zrealloc(*buffer, buffer_size);
    }
    (*buffer)[position++] = c;
    (*buffer)[position] = '\0';
    c = getc(fp);
    if (c == EOF)
      eof = 1;
  }
  if (eof) {
    free(*buffer);
    *buffer = NULL;
    return 0;
  }
  while (position > 1) {
    position--;
    if (!isspace((*buffer)[position]))
      break;
    (*buffer)[position] = '\0';
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_line>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  mov    $0x50,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <zmalloc@plt>
  mov    %r14,%rdi
  mov    %rax,(%r15)
  movb   $0x0,(%rax)
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    %ebx,%eax
  je     L55
  mov    $0x1,%r12d
  mov    $0x50,%r13d
  cmp    $0xa,%ebx
  jne    L16
  jmp    L25
  nopl   (%rax)
L0:
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jg     L4
  mov    (%r15),%rdi
  lea    0x1(%r13,%r13,1),%r13d
  mov    %r13d,%esi
  call   <zrealloc@plt>
  mov    %rax,(%r15)
L4:
  add    $0x1,%r12
L16:
  mov    (%r15),%rax
  mov    %r14,%rdi
  mov    %r12d,0xc(%rsp)
  mov    %r12d,%ebp
  mov    %bl,-0x1(%rax,%r12,1)
  mov    (%r15),%rax
  movb   $0x0,(%rax,%r12,1)
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D18(%rip),%rax
  mov    (%rax),%eax
  cmp    $0xa,%ebx
  je     L18
  cmp    %ebx,%eax
  jne    L0
L55:
  mov    (%r15),%rdi
  call   <free@plt>
  movq   $0x0,(%r15)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L18:
  cmp    %ebx,%eax
  je     L55
  cmpl   $0x1,0xc(%rsp)
  je     L112
  movslq 0xc(%rsp),%r12
  lea    -0x2(%rbp),%eax
  lea    -0x1(%r12),%rbx
  sub    $0x2,%r12
  sub    %rax,%r12
  jmp    L60
  nopl   0x0(%rax)
L42:
  mov    (%r15),%rax
  movb   $0x0,(%rax,%rbx,1)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  je     L112
L60:
  mov    (%r15),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L42
L112:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L25:
  cmp    %ebx,%eax
  jne    L112
  jmp    L55
```

assistant: ```c
int read_line(FILE *fp, char **buffer) {
  int buffer_size = (80);
  int eof = 0;
  int position = 0;
  int c;
  *buffer = zmalloc((80));
  (*buffer)[0] = '\0';
  if ((c = getc(fp)) == EOF)
    eof = 1;
  while (c != '\n' && !eof) {
    if (position + 1 >= buffer_size) {
      buffer_size = buffer_size * 2 + 1;
      *buffer = zrealloc(*buffer, buffer_size);
    }
    (*buffer)[position++] = c;
    (*buffer)[position] = '\0';
    c = getc(fp);
    if (c == EOF)
      eof = 1;
  }
  if (eof) {
    free(*buffer);
    *buffer = NULL;
    return 0;
  }
  while (position > 1) {
    position--;
    if (!isspace((*buffer)[position]))
      break;
    (*buffer)[position] = '\0';
  }
  return 1;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<read_line>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  push   %r14
  mov    %rdi,%r14
  mov    $0x50,%edi
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  call   <zmalloc@plt>
  mov    %r14,%rdi
  mov    %rax,(%r15)
  movb   $0x0,(%rax)
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    %ebx,%eax
  je     L3
  mov    $0x1,%r12d
  mov    $0x50,%r13d
  cmp    $0xa,%ebx
  jne    L122
  jmp    L124
  nopl   (%rax)
L5:
  add    $0x1,%ebp
  cmp    %ebp,%r13d
  jg     L123
  mov    (%r15),%rdi
  lea    0x1(%r13,%r13,1),%r13d
  mov    %r13d,%esi
  call   <zrealloc@plt>
  mov    %rax,(%r15)
L123:
  add    $0x1,%r12
L122:
  mov    (%r15),%rax
  mov    %r14,%rdi
  mov    %r12d,0xc(%rsp)
  mov    %r12d,%ebp
  mov    %bl,-0x1(%rax,%r12,1)
  mov    (%r15),%rax
  movb   $0x0,(%rax,%r12,1)
  call   <getc@plt>
  mov    %eax,%ebx
  mov    D9(%rip),%rax
  mov    (%rax),%eax
  cmp    $0xa,%ebx
  je     L99
  cmp    %ebx,%eax
  jne    L5
L3:
  mov    (%r15),%rdi
  call   <free@plt>
  movq   $0x0,(%r15)
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   0x0(%rax,%rax,1)
L99:
  cmp    %ebx,%eax
  je     L3
  cmpl   $0x1,0xc(%rsp)
  je     L35
  movslq 0xc(%rsp),%r12
  lea    -0x2(%rbp),%eax
  lea    -0x1(%r12),%rbx
  sub    $0x2,%r12
  sub    %rax,%r12
  jmp    L23
  nopl   0x0(%rax)
L73:
  mov    (%r15),%rax
  movb   $0x0,(%rax,%rbx,1)
  sub    $0x1,%rbx
  cmp    %r12,%rbx
  je     L35
L23:
  mov    (%r15),%rax
  movsbl (%rax,%rbx,1),%edi
  call   <isspace@plt>
  test   %eax,%eax
  jne    L73
L35:
  add    $0x18,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L124:
  cmp    %ebx,%eax
  jne    L35
  jmp    L3
```

assistant: ```c
int read_line(FILE *fp, char **buffer) {
  int buffer_size = (80);
  int eof = 0;
  int position = 0;
  int c;
  *buffer = zmalloc((80));
  (*buffer)[0] = '\0';
  if ((c = getc(fp)) == EOF)
    eof = 1;
  while (c != '\n' && !eof) {
    if (position + 1 >= buffer_size) {
      buffer_size = buffer_size * 2 + 1;
      *buffer = zrealloc(*buffer, buffer_size);
    }
    (*buffer)[position++] = c;
    (*buffer)[position] = '\0';
    c = getc(fp);
    if (c == EOF)
      eof = 1;
  }
  if (eof) {
    free(*buffer);
    *buffer = NULL;
    return 0;
  }
  while (position > 1) {
    position--;
    if (!isspace((*buffer)[position]))
      break;
    (*buffer)[position] = '\0';
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<rand_pos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %edi,-0x24(%rbp)
  mov    $0x0,%edi
  call   <time@plt>
  mov    %eax,%ebx
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x5,%edx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%ecx
  sub    %ecx,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %ebx,%eax
  mov    %eax,%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
  jmp    L36
L28:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idivl  -0x24(%rbp)
  mov    %edx,%eax
  add    $0x1,%eax
  mov    %eax,-0x14(%rbp)
L36:
  mov    -0x14(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  je     L28
  mov    -0x24(%rbp),%eax
  sub    $0x1,%eax
  cmp    %eax,-0x14(%rbp)
  je     L28
  cmpl   $0x0,-0x14(%rbp)
  je     L28
  mov    -0x14(%rbp),%eax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
int rand_pos(int max) {
  int b;
  srand((unsigned int)(time(NULL) + (rand() % 100)));
  b = (rand() % max) + 1;
  while (b == max || b == max - 1 || b == 0)
    b = (rand() % max) + 1;
  return b;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<rand_pos>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebx
  mov    $0x0,%edi
  call   <time@plt>
  mov    %rax,%rbp
  mov    $0x0,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x25,%rdx
  mov    %eax,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  lea    (%rax,%rbp,1),%edi
  call   <srand@plt>
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  add    $0x1,%edx
  lea    -0x1(%rbx),%ebp
  jmp    L33
L19:
  mov    $0x0,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  add    $0x1,%edx
L33:
  cmp    %ebx,%edx
  je     L19
  cmp    %edx,%ebp
  je     L19
  test   %edx,%edx
  je     L19
  mov    %edx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rand_pos(int max) {
  int b;
  srand((unsigned int)(time(NULL) + (rand() % 100)));
  b = (rand() % max) + 1;
  while (b == max || b == max - 1 || b == 0)
    b = (rand() % max) + 1;
  return b;
}
```
user: Translate the below assembly code into C programming language:

```asm
<rand_pos>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  lea    (%rax,%rbp,1),%edi
  lea    -0x1(%rbx),%ebp
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  lea    0x1(%rdx),%eax
  jmp    L26
  nopl   0x0(%rax)
L30:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  lea    0x1(%rdx),%eax
L26:
  cmp    %ebx,%eax
  je     L30
  test   %eax,%eax
  je     L30
  cmp    %ebp,%eax
  je     L30
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rand_pos(int max) {
  int b;
  srand((unsigned int)(time(NULL) + (rand() % 100)));
  b = (rand() % max) + 1;
  while (b == max || b == max - 1 || b == 0)
    b = (rand() % max) + 1;
  return b;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rand_pos>:
  endbr64
  push   %rbp
  push   %rbx
  mov    %edi,%ebx
  xor    %edi,%edi
  sub    $0x8,%rsp
  call   <time@plt>
  mov    %rax,%rbp
  xor    %eax,%eax
  call   <rand@plt>
  movslq %eax,%rdx
  mov    %eax,%ecx
  imul   $0x51eb851f,%rdx,%rdx
  sar    $0x1f,%ecx
  sar    $0x25,%rdx
  sub    %ecx,%edx
  imul   $0x64,%edx,%edx
  sub    %edx,%eax
  lea    (%rax,%rbp,1),%edi
  lea    -0x1(%rbx),%ebp
  call   <srand@plt>
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  lea    0x1(%rdx),%eax
  jmp    L14
  nopl   0x0(%rax)
L38:
  xor    %eax,%eax
  call   <rand@plt>
  cltd
  idiv   %ebx
  lea    0x1(%rdx),%eax
L14:
  cmp    %ebx,%eax
  je     L38
  test   %eax,%eax
  je     L38
  cmp    %ebp,%eax
  je     L38
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int rand_pos(int max) {
  int b;
  srand((unsigned int)(time(NULL) + (rand() % 100)));
  b = (rand() % max) + 1;
  while (b == max || b == max - 1 || b == 0)
    b = (rand() % max) + 1;
  return b;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x9000(%rsp),%r11
L101:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L101
  sub    $0xc60,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x9c54(%rbp)
  movl   $0x0,-0x9c5c(%rbp)
  jmp    L8
L77:
  mov    -0x9c5c(%rbp),%eax
  cltq
  movl   $0x1,-0x9c50(%rbp,%rax,4)
  addl   $0x1,-0x9c5c(%rbp)
L8:
  cmpl   $0x270f,-0x9c5c(%rbp)
  jle    L77
  movl   $0x3e8,-0x9c58(%rbp)
  jmp    L32
L36:
  movl   $0x1,-0x9c5c(%rbp)
  jmp    L2
L68:
  mov    -0x9c58(%rbp),%eax
  cltd
  idivl  -0x9c5c(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L24
  mov    -0x9c58(%rbp),%eax
  cltd
  idivl  -0x9c5c(%rbp)
  mov    %eax,%ecx
  mov    -0x9c58(%rbp),%edx
  mov    -0x9c5c(%rbp),%eax
  mov    %ecx,%esi
  mov    %eax,%edi
  call   <ispan@plt>
  test   %rax,%rax
  je     L24
  mov    -0x9c58(%rbp),%eax
  cltq
  mov    -0x9c50(%rbp,%rax,4),%eax
  test   %eax,%eax
  je     L24
  mov    -0x9c58(%rbp),%eax
  add    %eax,-0x9c54(%rbp)
  mov    -0x9c58(%rbp),%eax
  cltq
  movl   $0x0,-0x9c50(%rbp,%rax,4)
L24:
  addl   $0x1,-0x9c5c(%rbp)
L2:
  mov    -0x9c58(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  cmp    %eax,-0x9c5c(%rbp)
  jl     L68
  addl   $0x1,-0x9c58(%rbp)
L32:
  cmpl   $0x270f,-0x9c58(%rbp)
  jle    L36
  mov    -0x9c54(%rbp),%eax
  mov    %eax,%esi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L40
  call   <__stack_chk_fail@plt>
L40:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D7
type_infered: string

tool: D7: %d


assistant: ```c
int main() {
  int i, n;
  int sum = 0;
  int arr[10000];
  for (i = 0; i < 10000; i++)
    arr[i] = 1;
  for (n = 1000; n < 10000; n++) {
    for (i = 1; i < n / 2; i++) {
      if (!(n % i)) {
        if (ispan(i, n / i, n)) {
          if (arr[n]) {
            sum += n;
            arr[n] = 0;
          }
        }
      }
    }
  }
  printf("%d\n", sum);
  return 0;
}
```