ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What is the c source code of the assembly code below?

```asm
<inotify_watch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <inotify_backend_watch@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jle    L6
  mov    -0x18(%rbp),%rdx
  mov    -0x4(%rbp),%eax
  mov    %rdx,%rsi
  mov    %eax,%edi
  call   <inotify_map@plt>
L6:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int inotify_watch(const char *path) {
  int wd = inotify_backend_watch(path);
  if (wd > 0)
    inotify_map(wd, path);
  return wd;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<inotify_watch>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  call   <inotify_backend_watch@plt>
  mov    %eax,%ebx
  test   %eax,%eax
  jg     L6
L15:
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L6:
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <inotify_map@plt>
  jmp    L15
```

assistant: ```c
int inotify_watch(const char *path) {
  int wd = inotify_backend_watch(path);
  if (wd > 0)
    inotify_map(wd, path);
  return wd;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<inotify_watch>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <inotify_backend_watch@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L3
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <inotify_map@plt>
L3:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int inotify_watch(const char *path) {
  int wd = inotify_backend_watch(path);
  if (wd > 0)
    inotify_map(wd, path);
  return wd;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<inotify_watch>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  sub    $0x8,%rsp
  call   <inotify_backend_watch@plt>
  mov    %eax,%r12d
  test   %eax,%eax
  jle    L2
  mov    %rbp,%rsi
  mov    %eax,%edi
  call   <inotify_map@plt>
L2:
  add    $0x8,%rsp
  mov    %r12d,%eax
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
int inotify_watch(const char *path) {
  int wd = inotify_backend_watch(path);
  if (wd > 0)
    inotify_map(wd, path);
  return wd;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minstack_print_message>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D0
data_type: string

tool: D0: %s


assistant: ```c
void minstack_print_message(void *message) {
  char *char_message = message;
  printf("%s\n", char_message);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minstack_print_message>:
  endbr64
  sub    $0x8,%rsp
  mov    %rdi,%rsi
  lea    D5(%rip),%rdi
  call   <printf@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: tag: D5
datatype: string

tool: D5: %s


assistant: ```c
void minstack_print_message(void *message) {
  char *char_message = message;
  printf("%s\n", char_message);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<minstack_print_message>:
  endbr64
  mov    %rdi,%rsi
  lea    D4(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: read_data
arguments: data_tag: D4
type_guessed: string

tool: D4: %s


assistant: ```c
void minstack_print_message(void *message) {
  char *char_message = message;
  printf("%s\n", char_message);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<minstack_print_message>:
  endbr64
  mov    %rdi,%rsi
  lea    D0(%rip),%rdi
  jmp    1050 <printf@plt>
```

tool_calls: name: unpack_data
arguments: tag: D0
type: string

tool: D0: %s


assistant: ```c
void minstack_print_message(void *message) {
  char *char_message = message;
  printf("%s\n", char_message);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<lltos>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %esi,-0xc(%rbp)
  mov    $0x38,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  mov    $0x30,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    $0x28,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    $0x20,%edx
  mov    -0xc(%rbp),%eax
  mov    %edx,%ecx
  sar    %cl,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x18,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x4,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x10,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x5,%rax
  mov    %dl,(%rax)
  mov    -0xc(%rbp),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  add    $0x6,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  add    $0x7,%rax
  mov    -0xc(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void lltos(char *str, uint64_t value) {
  str[0] = value >> 56;
  str[1] = value >> 48;
  str[2] = value >> 40;
  str[3] = value >> 32;
  str[4] = value >> 24;
  str[5] = value >> 16;
  str[6] = value >> 8;
  str[7] = value;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<lltos>:
  endbr64
  mov    %esi,%eax
  mov    %esi,%edx
  mov    $0x38,%ecx
  sar    %cl,%edx
  mov    %dl,(%rdi)
  mov    %esi,%edx
  mov    $0x30,%ecx
  sar    %cl,%edx
  mov    %dl,0x1(%rdi)
  mov    %esi,%edx
  mov    $0x28,%ecx
  sar    %cl,%edx
  mov    %dl,0x2(%rdi)
  mov    %esi,%edx
  mov    $0x20,%ecx
  sar    %cl,%edx
  mov    %dl,0x3(%rdi)
  mov    %esi,%edx
  sar    $0x18,%edx
  mov    %dl,0x4(%rdi)
  mov    %esi,%edx
  sar    $0x10,%edx
  mov    %dl,0x5(%rdi)
  movzbl %ah,%ecx
  mov    %cl,0x6(%rdi)
  mov    %sil,0x7(%rdi)
  ret
```

assistant: ```c
void lltos(char *str, uint64_t value) {
  str[0] = value >> 56;
  str[1] = value >> 48;
  str[2] = value >> 40;
  str[3] = value >> 32;
  str[4] = value >> 24;
  str[5] = value >> 16;
  str[6] = value >> 8;
  str[7] = value;
}
```
user: Translate the below assembly code into C programming language:

```asm
<lltos>:
  endbr64
  mov    %esi,%eax
  mov    $0x38,%ecx
  sar    %cl,%eax
  mov    $0x30,%ecx
  mov    %al,(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x28,%ecx
  mov    %al,0x1(%rdi)
  mov    %esi,%eax
  sar    %cl,%eax
  mov    $0x20,%ecx
  mov    %al,0x2(%rdi)
  mov    %esi,%eax
  bswap  %esi
  sar    %cl,%eax
  mov    %esi,0x4(%rdi)
  mov    %al,0x3(%rdi)
  ret
```

assistant: ```c
void lltos(char *str, uint64_t value) {
  str[0] = value >> 56;
  str[1] = value >> 48;
  str[2] = value >> 40;
  str[3] = value >> 32;
  str[4] = value >> 24;
  str[5] = value >> 16;
  str[6] = value >> 8;
  str[7] = value;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<lltos>:
  endbr64
  mov    %esi,%edx
  mov    $0x38,%ecx
  mov    %esi,%eax
  push   %r14
  sar    %cl,%edx
  mov    $0x30,%ecx
  push   %rbx
  mov    %esi,%ebx
  sar    %cl,%eax
  sar    $0x8,%ebx
  mov    %esi,%r8d
  mov    %esi,%r9d
  mov    %eax,%r14d
  movzbl %sil,%eax
  mov    %esi,%r10d
  mov    %esi,%r11d
  shl    $0x8,%rax
  movzbl %bl,%esi
  sar    $0x10,%r11d
  mov    $0x28,%ecx
  or     %rsi,%rax
  movzbl %r11b,%esi
  sar    $0x18,%r10d
  movzbl %dl,%edx
  shl    $0x8,%rax
  sar    %cl,%r8d
  mov    $0x20,%ecx
  pop    %rbx
  or     %rsi,%rax
  movzbl %r10b,%esi
  sar    %cl,%r9d
  movzbl %r14b,%ecx
  shl    $0x8,%rax
  pop    %r14
  or     %rsi,%rax
  movzbl %r9b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  movzbl %r8b,%esi
  shl    $0x8,%rax
  or     %rsi,%rax
  shl    $0x8,%rax
  or     %rcx,%rax
  shl    $0x8,%rax
  or     %rdx,%rax
  mov    %rax,(%rdi)
  ret
```

assistant: ```c
void lltos(char *str, uint64_t value) {
  str[0] = value >> 56;
  str[1] = value >> 48;
  str[2] = value >> 40;
  str[3] = value >> 32;
  str[4] = value >> 24;
  str[5] = value >> 16;
  str[6] = value >> 8;
  str[7] = value;
}
```
user: What is the c source code of the assembly code below?

```asm
<Hash_Key>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L12
L10:
  mov    -0x4(%rbp),%eax
  lea    0x0(,%rax,8),%edx
  mov    -0x4(%rbp),%eax
  shr    $0x1c,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  add    %edx,%eax
  add    %eax,-0x4(%rbp)
  addq   $0x1,-0x18(%rbp)
L12:
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L10
  mov    -0x4(%rbp),%eax
  mov    $0x0,%edx
  divl   -0x1c(%rbp)
  mov    %edx,%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int Hash_Key(const char *name, unsigned int modulus) {
  unsigned int key;
  for (key = 0; *name; name++)
    key += ((key << 3) + (key >> 28) + *name);
  return (key % modulus);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<Hash_Key>:
  endbr64
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L5
  mov    $0x0,%eax
L19:
  mov    %eax,%ecx
  shr    $0x1c,%ecx
  movsbl %dl,%edx
  lea    (%rdx,%rax,8),%edx
  add    %edx,%eax
  add    %ecx,%eax
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L19
L14:
  mov    $0x0,%edx
  div    %esi
  mov    %edx,%eax
  ret
L5:
  mov    $0x0,%eax
  jmp    L14
```

assistant: ```c
unsigned int Hash_Key(const char *name, unsigned int modulus) {
  unsigned int key;
  for (key = 0; *name; name++)
    key += ((key << 3) + (key >> 28) + *name);
  return (key % modulus);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<Hash_Key>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L3
  xor    %eax,%eax
  nopl   (%rax)
L14:
  lea    (%rdx,%rax,8),%edx
  add    $0x1,%rdi
  mov    %eax,%ecx
  add    %edx,%eax
  movsbl (%rdi),%edx
  shr    $0x1c,%ecx
  add    %ecx,%eax
  test   %dl,%dl
  jne    L14
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L3:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int Hash_Key(const char *name, unsigned int modulus) {
  unsigned int key;
  for (key = 0; *name; name++)
    key += ((key << 3) + (key >> 28) + *name);
  return (key % modulus);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<Hash_Key>:
  endbr64
  movsbl (%rdi),%edx
  test   %dl,%dl
  je     L6
  xor    %eax,%eax
  nopl   (%rax)
L5:
  lea    (%rdx,%rax,8),%edx
  add    $0x1,%rdi
  mov    %eax,%ecx
  add    %edx,%eax
  movsbl (%rdi),%edx
  shr    $0x1c,%ecx
  add    %ecx,%eax
  test   %dl,%dl
  jne    L5
  xor    %edx,%edx
  div    %esi
  mov    %edx,%r8d
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L6:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int Hash_Key(const char *name, unsigned int modulus) {
  unsigned int key;
  for (key = 0; *name; name++)
    key += ((key << 3) + (key >> 28) + *name);
  return (key % modulus);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<log1minusbetai>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  movq   %xmm0,%rbx
  movsd  %xmm2,0x8(%rsp)
  pxor   %xmm0,%xmm0
  comisd %xmm2,%xmm0
  ja     L57
  movq   %xmm1,%rbp
  comisd D11(%rip),%xmm2
  ja     L41
  ucomisd %xmm0,%xmm2
  setnp  %al
  mov    $0x0,%edx
  cmovne %edx,%eax
  test   %al,%al
  jne    L38
  ucomisd D11(%rip),%xmm2
  setnp  %al
  cmovne %edx,%eax
  test   %al,%al
  je     L69
L38:
  mov    D66(%rip),%r12
L71:
  movq   %rbx,%xmm0
  movq   %rbp,%xmm5
  addsd  %xmm5,%xmm0
  addsd  D48(%rip),%xmm0
  movq   %rbx,%xmm1
  addsd  D11(%rip),%xmm1
  divsd  %xmm0,%xmm1
  comisd 0x8(%rsp),%xmm1
  jbe    L37
  movq   %r12,%xmm0
  call   <exp@plt>
  movq   %xmm0,%r12
  movsd  0x8(%rsp),%xmm2
  movq   %rbp,%xmm1
  movq   %rbx,%xmm0
  call   <betacf@plt>
  movq   %r12,%xmm6
  mulsd  %xmm0,%xmm6
  movapd %xmm6,%xmm0
  movq   %rbx,%xmm7
  divsd  %xmm7,%xmm0
  movsd  D11(%rip),%xmm1
  subsd  %xmm0,%xmm1
  movapd %xmm1,%xmm0
  call   <log@plt>
  jmp    L41
L69:
  movq   %rbx,%xmm0
  addsd  %xmm1,%xmm0
  call   <gammln@plt>
  movq   %xmm0,%r12
  movq   %rbx,%xmm0
  call   <gammln@plt>
  movq   %r12,%xmm4
  subsd  %xmm0,%xmm4
  movq   %xmm4,%r12
  movq   %rbp,%xmm0
  call   <gammln@plt>
  movq   %xmm0,%r14
  movsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movq   %xmm0,%r13
  movsd  D11(%rip),%xmm0
  subsd  0x8(%rsp),%xmm0
  call   <log@plt>
  movq   %r12,%xmm1
  movq   %r14,%xmm7
  subsd  %xmm7,%xmm1
  movq   %r13,%xmm2
  movq   %rbx,%xmm6
  mulsd  %xmm6,%xmm2
  addsd  %xmm2,%xmm1
  movq   %rbp,%xmm5
  mulsd  %xmm5,%xmm0
  addsd  %xmm0,%xmm1
  movq   %xmm1,%r12
  jmp    L71
L37:
  movsd  D11(%rip),%xmm2
  subsd  0x8(%rsp),%xmm2
  movq   %rbx,%xmm1
  movq   %rbp,%xmm0
  call   <lbetacf@plt>
  movq   %xmm0,%rbx
  movq   %rbp,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm0
  movq   %r12,%xmm6
  addsd  %xmm6,%xmm0
  subsd  %xmm1,%xmm0
  jmp    L41
L57:
  pxor   %xmm0,%xmm0
L41:
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

tool_calls: name: read_data
arguments: label: D11
datatype: f64[2]
name: read_data
arguments: label: D66
datatype: f64
name: read_data
arguments: label: D48
datatype: f64

tool: {"D11": [1.0,2.0]}

tool: D66: 0

tool: D48: 2

assistant: ```c
double log1minusbetai(double a, double b, double x) {
  double bt;
  if (x < 0.0 || x > 1.0)
    return 0.;
  if (x == 0.0 || x == 1.0)
    bt = 0.0;
  else
    bt = gammln(a + b) - gammln(a) - gammln(b) + a * log(x) + b * log(1.0 - x);
  if (x < (a + 1.0) / (a + b + 2.0))
    return log(1. - exp(bt) * betacf(a, b, x) / a);
  else
    return bt + lbetacf(b, a, 1.0 - x) - log(b);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<ifrac>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  push   0x18(%rbp)
  push   0x10(%rbp)
  call   <floorl@plt>
  add    $0x10,%rsp
  fstpt  -0x20(%rbp)
  fldt   0xeb3(%rip)        # 2010 <_fini+0xe28>
  fldt   -0x20(%rbp)
  fcomip %st(1),%st
  fstp   %st(0)
  jae    L14
  fldt   -0x20(%rbp)
  fnstcw -0x32(%rbp)
  movzwl -0x32(%rbp),%eax
  or     $0xc,%ah
  mov    %ax,-0x34(%rbp)
  fldcw  -0x34(%rbp)
  fistpll -0x28(%rbp)
  fldcw  -0x32(%rbp)
  jmp    L19
L14:
  fldt   -0x20(%rbp)
  fldt   0xe85(%rip)        # 2010 <_fini+0xe28>
  fsubrp %st,%st(1)
  fnstcw -0x32(%rbp)
  movzwl -0x32(%rbp),%eax
  or     $0xc,%ah
  mov    %ax,-0x34(%rbp)
  fldcw  -0x34(%rbp)
  fistpll -0x28(%rbp)
  fldcw  -0x32(%rbp)
  movabs $0x8000000000000000,%rax
  xor    %rax,-0x28(%rbp)
L19:
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  fldt   0x10(%rbp)
  fldt   -0x20(%rbp)
  fsubrp %st,%st(1)
  fstpt  -0x10(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rsi
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  fldt   -0x10(%rbp)
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D7
type: string

tool: D7:  int = %lx


assistant: ```c
long double ifrac(x)
long double x;
{
  unsigned long lx;
  long double y, z;
  z = floorl(x);
  lx = z;
  y = x - z;
  printf(" int = %lx\n", lx);
  return (y);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<ifrac>:
  endbr64
  sub    $0x28,%rsp
  fnstcw 0x1e(%rsp)
  movzwl 0x1e(%rsp),%eax
  and    $0xf3,%ah
  or     $0x4,%ah
  mov    %ax,0x1a(%rsp)
  fldt   0x30(%rsp)
  fldcw  0x1a(%rsp)
  frndint
  fldcw  0x1e(%rsp)
  fld    %st(0)
  fstpt  (%rsp)
  flds   0xebe(%rip)        # 200c <_fini+0xe44>
  fxch   %st(1)
  fcomi  %st(1),%st
  fstp   %st(1)
  jae    L5
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fldcw  0x1c(%rsp)
  fistpll 0x10(%rsp)
  fldcw  0x1e(%rsp)
  mov    0x10(%rsp),%rsi
L6:
  lea    D1(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  fldt   (%rsp)
  fldt   0x30(%rsp)
  fsubp  %st,%st(1)
  add    $0x28,%rsp
  ret
L5:
  fstp   %st(0)
  fnstcw 0x1e(%rsp)
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fldt   (%rsp)
  fsubs  0xe5d(%rip)        # 200c <_fini+0xe44>
  fldcw  0x1c(%rsp)
  fistpll 0x10(%rsp)
  fldcw  0x1e(%rsp)
  mov    0x10(%rsp),%rsi
  btc    $0x3f,%rsi
  jmp    L6
```

tool_calls: name: disassemble_data
arguments: data_tag: D1
datatype: string

tool: D1:  int = %lx


assistant: ```c
long double ifrac(x)
long double x;
{
  unsigned long lx;
  long double y, z;
  z = floorl(x);
  lx = z;
  y = x - z;
  printf(" int = %lx\n", lx);
  return (y);
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<ifrac>:
  endbr64
  sub    $0x28,%rsp
  fnstcw 0x1e(%rsp)
  fldt   0x30(%rsp)
  movzwl 0x1e(%rsp),%eax
  and    $0xf3,%ah
  or     $0x4,%ah
  mov    %ax,0x1a(%rsp)
  fldcw  0x1a(%rsp)
  frndint
  fldcw  0x1e(%rsp)
  flds   0xebc(%rip)        # 200c <_fini+0xe48>
  fxch   %st(1)
  fcomi  %st(1),%st
  jae    L14
  fstp   %st(1)
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fld    %st(0)
  fldcw  0x1c(%rsp)
  fistpll (%rsp)
  fldcw  0x1e(%rsp)
  mov    (%rsp),%rsi
L8:
  lea    D6(%rip),%rdi
  xor    %eax,%eax
  fstpt  (%rsp)
  call   <printf@plt>
  fldt   0x30(%rsp)
  fldt   (%rsp)
  add    $0x28,%rsp
  fsubrp %st,%st(1)
  ret
  nopl   (%rax)
L14:
  fnstcw 0x1e(%rsp)
  fsub   %st,%st(1)
  fxch   %st(1)
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fldcw  0x1c(%rsp)
  fistpll (%rsp)
  fldcw  0x1e(%rsp)
  mov    (%rsp),%rsi
  btc    $0x3f,%rsi
  jmp    L8
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D6
data_type: string

tool: D6:  int = %lx


assistant: ```c
long double ifrac(x)
long double x;
{
  unsigned long lx;
  long double y, z;
  z = floorl(x);
  lx = z;
  y = x - z;
  printf(" int = %lx\n", lx);
  return (y);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ifrac>:
  endbr64
  sub    $0x28,%rsp
  fnstcw 0x1e(%rsp)
  fldt   0x30(%rsp)
  movzwl 0x1e(%rsp),%eax
  and    $0xf3,%ah
  or     $0x4,%ah
  mov    %ax,0x1a(%rsp)
  fldcw  0x1a(%rsp)
  frndint
  fldcw  0x1e(%rsp)
  flds   0xebc(%rip)        # 200c <_fini+0xe48>
  fxch   %st(1)
  fcomi  %st(1),%st
  jae    L9
  fstp   %st(1)
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fld    %st(0)
  fldcw  0x1c(%rsp)
  fistpll (%rsp)
  fldcw  0x1e(%rsp)
  mov    (%rsp),%rsi
L14:
  lea    D5(%rip),%rdi
  xor    %eax,%eax
  fstpt  (%rsp)
  call   <printf@plt>
  fldt   0x30(%rsp)
  fldt   (%rsp)
  add    $0x28,%rsp
  fsubrp %st,%st(1)
  ret
  nopl   (%rax)
L9:
  fnstcw 0x1e(%rsp)
  fsub   %st,%st(1)
  fxch   %st(1)
  movzwl 0x1e(%rsp),%eax
  or     $0xc,%ah
  mov    %ax,0x1c(%rsp)
  fldcw  0x1c(%rsp)
  fistpll (%rsp)
  fldcw  0x1e(%rsp)
  mov    (%rsp),%rsi
  btc    $0x3f,%rsi
  jmp    L14
```

tool_calls: name: read_data
arguments: tag: D5
type: string

tool: D5:  int = %lx


assistant: ```c
long double ifrac(x)
long double x;
{
  unsigned long lx;
  long double y, z;
  z = floorl(x);
  lx = z;
  y = x - z;
  printf(" int = %lx\n", lx);
  return (y);
}
```
user: Translate the below assembly code into C programming language:

```asm
<display>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,%eax
  mov    %esi,-0x18(%rbp)
  mov    %edx,-0x1c(%rbp)
  mov    %al,-0x14(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L25
L37:
  movl   $0x1,-0x4(%rbp)
  jmp    L29
L13:
  movsbl -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <putchar@plt>
  addl   $0x1,-0x4(%rbp)
L29:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jle    L13
  mov    $0xa,%edi
  call   <putchar@plt>
  addl   $0x1,-0x8(%rbp)
L25:
  mov    -0x8(%rbp),%eax
  cmp    -0x18(%rbp),%eax
  jle    L37
  nop
  nop
  leave
  ret
```

assistant: ```c
void display(char cr, int lines, int width) {
  int row, col;
  for (row = 1; row <= lines; row++) {
    for (col = 1; col <= width; col++)
      putchar(cr);
    putchar('\n');
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<display>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %esi,%r13d
  mov    %edx,%ebp
  mov    $0x1,%r14d
  movsbl %dil,%r12d
  test   %esi,%esi
  jg     L12
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L40:
  mov    %r12d,%edi
  call   <putchar@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jge    L40
L41:
  mov    $0xa,%edi
  call   <putchar@plt>
  add    $0x1,%r14d
  cmp    %r14d,%r13d
  jl     L16
L12:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jg     L40
  jmp    L41
```

assistant: ```c
void display(char cr, int lines, int width) {
  int row, col;
  for (row = 1; row <= lines; row++) {
    for (col = 1; col <= width; col++)
      putchar(cr);
    putchar('\n');
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L33
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  nop
L19:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L38
  nopl   0x0(%rax)
L27:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L27
L38:
  mov    $0xa,%edi
  add    $0x1,%r14d
  call   <putchar@plt>
  cmp    %r14d,%r13d
  jge    L19
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L33:
  ret
```

assistant: ```c
void display(char cr, int lines, int width) {
  int row, col;
  for (row = 1; row <= lines; row++) {
    for (col = 1; col <= width; col++)
      putchar(cr);
    putchar('\n');
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<display>:
  endbr64
  test   %esi,%esi
  jle    L12
  push   %r14
  mov    $0x1,%r14d
  push   %r13
  mov    %esi,%r13d
  push   %r12
  movsbl %dil,%r12d
  push   %rbp
  mov    %edx,%ebp
  push   %rbx
  nop
L39:
  mov    $0x1,%ebx
  test   %ebp,%ebp
  jle    L38
  nopl   0x0(%rax)
L2:
  mov    %r12d,%edi
  add    $0x1,%ebx
  call   <putchar@plt>
  cmp    %ebx,%ebp
  jge    L2
L38:
  mov    $0xa,%edi
  add    $0x1,%r14d
  call   <putchar@plt>
  cmp    %r14d,%r13d
  jge    L39
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L12:
  ret
```

assistant: ```c
void display(char cr, int lines, int width) {
  int row, col;
  for (row = 1; row <= lines; row++) {
    for (col = 1; col <= width; col++)
      putchar(cr);
    putchar('\n');
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    $0xfa0,%edi
  call   <malloc@plt>
  mov    %rax,-0x18(%rbp)
  mov    $0x80000000,%eax
  mov    %rax,-0x10(%rbp)
  mov    $0x80000001,%eax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L24
L32:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x1c(%rbp),%eax
  mov    %eax,(%rdx)
  addl   $0x1,-0x1c(%rbp)
L24:
  cmpl   $0x3e7,-0x1c(%rbp)
  jle    L32
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x1c(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L8
L30:
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  neg    %edx
  mov    %edx,(%rax)
  addl   $0x1,-0x1c(%rbp)
L8:
  cmpl   $0x3e7,-0x1c(%rbp)
  jle    L30
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D7
type: string
name: read_data
arguments: tag: D13
type: string

tool: D7: finish setting H label!


tool: D13: finish setting L label!


assistant: ```c
int main() {
  int i;
  int *buffer;
  buffer = (int *)malloc(sizeof(int) * 1000);
  int *set_label_l = (int *)0x80000000;
  int *set_label_h = (int *)0x80000001;
  i = *set_label_h;
  for (i = 0; i < 1000; i++)
    buffer[i] = i;
  printf("finish setting H label!\n");
  i = *set_label_l;
  for (i = 0; i < 1000; i++)
    buffer[i] = -i;
  printf("finish setting L label!\n");
  return 0;
}
```