ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<substr>:
  endbr64
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  sub    $0x148,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x138(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  cmp    %esi,%ebx
  jg     L14
  mov    %esi,%r8d
  mov    %esi,%ebp
  lea    (%rdx,%rbx,1),%rsi
  mov    %rsp,%rdi
  sub    %ebx,%r8d
  lea    0x1(%rbp),%ebx
  add    $0x1,%r8
  mov    %r8,%rdx
  call   <memcpy@plt>
  mov    %rax,%rdi
L14:
  call   <strdup@plt>
  movslq %ebx,%rbx
  movb   $0x0,(%rax,%rbx,1)
  mov    0x138(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L1
  add    $0x148,%rsp
  pop    %rbx
  pop    %rbp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
char *substr(int start, int end, char *str) {
  int i = start;
  int newStrIndex = 0;
  char newStr[300];
  for (; i < end + 1; i++) {
    newStr[newStrIndex] = str[i];
    newStrIndex++;
  }
  char *ret = strdup(newStr);
  ret[i] = '\0';
  return ret;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<check_responses>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x70,%rsp
  mov    %edi,-0x64(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D40(%rip),%rax
  mov    %rax,-0x40(%rbp)
  movl   $0x2000,-0x38(%rbp)
  lea    -0x54(%rbp),%rax
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    D8(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x54(%rbp)
  lea    -0x54(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  movl   $0x4,-0x28(%rbp)
  movl   $0x1,-0x24(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  movq   $0x0,-0x18(%rbp)
  lea    -0x40(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  lea    -0x30(%rbp),%rcx
  mov    -0x64(%rbp),%eax
  mov    $0x0,%edx
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <recvmsg@plt>
  mov    %rax,-0x50(%rbp)
  cmpq   $0x0,-0x50(%rbp)
  jg     L20
  mov    $0x0,%eax
  jmp    L66
L20:
  lea    D40(%rip),%rax
  mov    %rax,-0x48(%rbp)
  mov    -0x50(%rbp),%rdx
  mov    -0x48(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <NLMSG_OK@plt>
  test   %rax,%rax
  je     L43
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    D33(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L43
  mov    -0x48(%rbp),%rax
  mov    (%rax),%rdx
  mov    D44(%rip),%rax
  mov    (%rax),%rax
  cmp    %rax,%rdx
  je     L43
  mov    $0x1,%eax
  jmp    L66
L43:
  mov    $0x0,%eax
L66:
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L60
  call   <__stack_chk_fail@plt>
L60:
  leave
  ret
```

assistant: ```c
int check_responses(const int fd) {
  static char buf[8192];
  struct sockaddr_nl nladdr;
  struct iovec iov = {.iov_base = buf, .iov_len = sizeof(buf)};
  memset(&nladdr, 0, sizeof(nladdr));
  nladdr.nl_family = AF_NETLINK;
  struct msghdr msg = {.msg_name = (void *)&nladdr, .msg_namelen = sizeof(nladdr), .msg_iov = &iov, .msg_iovlen = 1, .msg_control = NULL, .msg_controllen = 0, .msg_flags = 0};
  ssize_t ret = recvmsg(fd, &msg, 0);
  if (ret <= 0)
    return 0;
  struct nlmsghdr *h = (struct nlmsghdr *)buf;
  return (NLMSG_OK(h, ret) && h->nlmsg_type != NLMSG_ERROR && h->nlmsg_type != NLMSG_DONE) ? 1 : 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<check_responses>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x58,%rsp
  mov    %edi,%ebx
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rax
  mov    %rax,0x10(%rsp)
  movl   $0x2000,0x18(%rsp)
  lea    0xc(%rsp),%rbp
  mov    $0x4,%edx
  mov    $0x0,%esi
  mov    %rbp,%rdi
  call   <memset@plt>
  mov    D1(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,0xc(%rsp)
  mov    %rbp,0x20(%rsp)
  movl   $0x4,0x28(%rsp)
  movl   $0x1,0x2c(%rsp)
  movl   $0x0,0x30(%rsp)
  movl   $0x0,0x34(%rsp)
  movq   $0x0,0x38(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,0x40(%rsp)
  lea    0x20(%rsp),%rsi
  mov    $0x0,%edx
  mov    %ebx,%edi
  call   <recvmsg@plt>
  mov    %rax,%rsi
  mov    $0x0,%eax
  test   %rsi,%rsi
  jle    L24
  lea    D10(%rip),%rdi
  call   <NLMSG_OK@plt>
  mov    %rax,%rdx
  mov    $0x0,%eax
  test   %rdx,%rdx
  je     L24
  mov    D10(%rip),%rdx
  mov    D15(%rip),%rcx
  cmp    (%rcx),%rdx
  je     L24
  mov    D37(%rip),%rax
  cmp    %rdx,(%rax)
  setne  %al
  movzbl %al,%eax
L24:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L23
  add    $0x58,%rsp
  pop    %rbx
  pop    %rbp
  ret
L23:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_responses(const int fd) {
  static char buf[8192];
  struct sockaddr_nl nladdr;
  struct iovec iov = {.iov_base = buf, .iov_len = sizeof(buf)};
  memset(&nladdr, 0, sizeof(nladdr));
  nladdr.nl_family = AF_NETLINK;
  struct msghdr msg = {.msg_name = (void *)&nladdr, .msg_namelen = sizeof(nladdr), .msg_iov = &iov, .msg_iovlen = 1, .msg_control = NULL, .msg_controllen = 0, .msg_flags = 0};
  ssize_t ret = recvmsg(fd, &msg, 0);
  if (ret <= 0)
    return 0;
  struct nlmsghdr *h = (struct nlmsghdr *)buf;
  return (NLMSG_OK(h, ret) && h->nlmsg_type != NLMSG_ERROR && h->nlmsg_type != NLMSG_DONE) ? 1 : 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<check_responses>:
  endbr64
  push   %r12
  xor    %esi,%esi
  mov    $0x4,%edx
  lea    D5(%rip),%r12
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  sub    $0x50,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x48(%rsp)
  xor    %eax,%eax
  lea    0xc(%rsp),%rbx
  mov    %r12,0x10(%rsp)
  mov    %rbx,%rdi
  movl   $0x2000,0x18(%rsp)
  call   <memset@plt>
  mov    D16(%rip),%rax
  xor    %edx,%edx
  mov    %ebp,%edi
  lea    0x20(%rsp),%rsi
  mov    %rbx,0x20(%rsp)
  movq   $0x0,0x30(%rsp)
  mov    (%rax),%eax
  movq   $0x0,0x38(%rsp)
  mov    %eax,0xc(%rsp)
  movabs $0x100000004,%rax
  mov    %rax,0x28(%rsp)
  lea    0x10(%rsp),%rax
  mov    %rax,0x40(%rsp)
  call   <recvmsg@plt>
  test   %rax,%rax
  jle    L21
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <NLMSG_OK@plt>
  test   %rax,%rax
  jne    L27
L21:
  xor    %eax,%eax
L13:
  mov    0x48(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L48
  add    $0x50,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax)
L27:
  mov    D29(%rip),%rax
  mov    D5(%rip),%rdx
  cmp    (%rax),%rdx
  je     L21
  mov    D1(%rip),%rcx
  mov    $0x1,%eax
  cmp    (%rcx),%rdx
  jne    L13
  jmp    L21
L48:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int check_responses(const int fd) {
  static char buf[8192];
  struct sockaddr_nl nladdr;
  struct iovec iov = {.iov_base = buf, .iov_len = sizeof(buf)};
  memset(&nladdr, 0, sizeof(nladdr));
  nladdr.nl_family = AF_NETLINK;
  struct msghdr msg = {.msg_name = (void *)&nladdr, .msg_namelen = sizeof(nladdr), .msg_iov = &iov, .msg_iovlen = 1, .msg_control = NULL, .msg_controllen = 0, .msg_flags = 0};
  ssize_t ret = recvmsg(fd, &msg, 0);
  if (ret <= 0)
    return 0;
  struct nlmsghdr *h = (struct nlmsghdr *)buf;
  return (NLMSG_OK(h, ret) && h->nlmsg_type != NLMSG_ERROR && h->nlmsg_type != NLMSG_DONE) ? 1 : 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<gen_scalar_derefs>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <scalar_derefs@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int gen_scalar_derefs(char *dirname) {
  scalar_derefs(dirname);
  return (0);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<gen_scalar_derefs>:
  endbr64
  sub    $0x8,%rsp
  call   <scalar_derefs@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_scalar_derefs(char *dirname) {
  scalar_derefs(dirname);
  return (0);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<gen_scalar_derefs>:
  endbr64
  sub    $0x8,%rsp
  call   <scalar_derefs@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int gen_scalar_derefs(char *dirname) {
  scalar_derefs(dirname);
  return (0);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<AYSoundHQ>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x1,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x2,%edi
  call   <DoAYSQHQ@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void AYSoundHQ(void) {
  DoAYSQHQ(0);
  DoAYSQHQ(1);
  DoAYSQHQ(2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AYSoundHQ>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x1,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x2,%edi
  call   <DoAYSQHQ@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void AYSoundHQ(void) {
  DoAYSQHQ(0);
  DoAYSQHQ(1);
  DoAYSQHQ(2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<AYSoundHQ>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x1,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1050 <DoAYSQHQ@plt>
```

assistant: ```c
void AYSoundHQ(void) {
  DoAYSQHQ(0);
  DoAYSQHQ(1);
  DoAYSQHQ(2);
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<AYSoundHQ>:
  endbr64
  sub    $0x8,%rsp
  xor    %edi,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x1,%edi
  call   <DoAYSQHQ@plt>
  mov    $0x2,%edi
  add    $0x8,%rsp
  jmp    1050 <DoAYSQHQ@plt>
```

assistant: ```c
void AYSoundHQ(void) {
  DoAYSQHQ(0);
  DoAYSQHQ(1);
  DoAYSQHQ(2);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f4>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x48(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x38(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x30(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x20(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x18(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x48(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void f4(void *const **bar) {
  const void ***p9 = (const void ***)bar;
  void *const **p11 = (void *const **)bar;
  void **const *p13 = (void **const *)bar;
  const void *const **p15 = (const void *const **)bar;
  const void **const *p17 = (const void **const *)bar;
  void *const *const *p19 = (void *const *const *)bar;
  const void *const *const *p21 = (const void *const *const *)bar;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void *const **bar) {
  const void ***p9 = (const void ***)bar;
  void *const **p11 = (void *const **)bar;
  void **const *p13 = (void **const *)bar;
  const void *const **p15 = (const void *const **)bar;
  const void **const *p17 = (const void **const *)bar;
  void *const *const *p19 = (void *const *const *)bar;
  const void *const *const *p21 = (const void *const *const *)bar;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void *const **bar) {
  const void ***p9 = (const void ***)bar;
  void *const **p11 = (void *const **)bar;
  void **const *p13 = (void **const *)bar;
  const void *const **p15 = (const void *const **)bar;
  const void **const *p17 = (const void **const *)bar;
  void *const *const *p19 = (void *const *const *)bar;
  const void *const *const *p21 = (const void *const *const *)bar;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<f4>:
  endbr64
  ret
```

assistant: ```c
void f4(void *const **bar) {
  const void ***p9 = (const void ***)bar;
  void *const **p11 = (void *const **)bar;
  void **const *p13 = (void **const *)bar;
  const void *const **p15 = (const void *const **)bar;
  const void **const *p17 = (const void **const *)bar;
  void *const *const *p19 = (void *const *const *)bar;
  const void *const *const *p21 = (const void *const *const *)bar;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<certificate_type_exists>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  cmpq   $0x0,-0x28(%rbp)
  jne    L37
  cmpq   $0x0,-0x20(%rbp)
  jne    L37
  mov    $0x1,%eax
  jmp    L58
L37:
  movq   $0x0,-0x8(%rbp)
  jmp    L56
L52:
  mov    -0x8(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L21
  mov    $0x1,%eax
  jmp    L58
L21:
  addq   $0x1,-0x8(%rbp)
L56:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L52
  mov    $0x0,%eax
L58:
  pop    %rbp
  ret
```

assistant: ```c
int certificate_type_exists(uint8_t *list, size_t count, uint8_t desired_type) {
  if (desired_type == 0 && count == 0)
    return 1;
  for (size_t i = 0; i < count; i++) {
    if (list[i] == desired_type)
      return 1;
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<certificate_type_exists>:
  endbr64
  mov    $0x1,%eax
  mov    %rsi,%rcx
  or     %rdx,%rcx
  je     L25
  test   %rsi,%rsi
  je     L6
  mov    $0x0,%eax
L4:
  cmp    %rdx,(%rdi,%rax,8)
  je     L37
  add    $0x1,%rax
  cmp    %rax,%rsi
  jne    L4
  mov    $0x0,%eax
  ret
L6:
  mov    $0x0,%eax
  ret
L37:
  mov    $0x1,%eax
L25:
  ret
```

assistant: ```c
int certificate_type_exists(uint8_t *list, size_t count, uint8_t desired_type) {
  if (desired_type == 0 && count == 0)
    return 1;
  for (size_t i = 0; i < count; i++) {
    if (list[i] == desired_type)
      return 1;
  }
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<certificate_type_exists>:
  endbr64
  mov    %rsi,%rcx
  mov    $0x1,%eax
  or     %rdx,%rcx
  je     L33
  test   %rsi,%rsi
  je     L35
  xor    %eax,%eax
  jmp    L47
  nopw   0x0(%rax,%rax,1)
L41:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L35
L47:
  cmp    %rdx,(%rdi,%rax,8)
  jne    L41
  mov    $0x1,%eax
L33:
  ret
  nopl   (%rax)
L35:
  xor    %eax,%eax
  ret
```

assistant: ```c
int certificate_type_exists(uint8_t *list, size_t count, uint8_t desired_type) {
  if (desired_type == 0 && count == 0)
    return 1;
  for (size_t i = 0; i < count; i++) {
    if (list[i] == desired_type)
      return 1;
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<certificate_type_exists>:
  endbr64
  mov    %rsi,%rcx
  mov    $0x1,%eax
  or     %rdx,%rcx
  je     L1
  test   %rsi,%rsi
  je     L42
  xor    %eax,%eax
  jmp    L48
  nopw   0x0(%rax,%rax,1)
L19:
  add    $0x1,%rax
  cmp    %rax,%rsi
  je     L42
L48:
  cmp    %rdx,(%rdi,%rax,8)
  jne    L19
  mov    $0x1,%eax
L1:
  ret
  nopl   (%rax)
L42:
  xor    %eax,%eax
  ret
```

assistant: ```c
int certificate_type_exists(uint8_t *list, size_t count, uint8_t desired_type) {
  if (desired_type == 0 && count == 0)
    return 1;
  for (size_t i = 0; i < count; i++) {
    if (list[i] == desired_type)
      return 1;
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<xfrd_read_time_t>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <xfrd_read_token@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L18
  mov    $0x0,%eax
  jmp    L17
L18:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <atol@plt>
  mov    -0x20(%rbp),%rdx
  mov    %eax,(%rdx)
  mov    $0x1,%eax
L17:
  leave
  ret
```

assistant: ```c
int xfrd_read_time_t(FILE *in, time_t *v) {
  char *p = xfrd_read_token(in);
  if (!p)
    return 0;
  *v = atol(p);
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<xfrd_read_time_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <xfrd_read_token@plt>
  mov    %rax,%rdi
  mov    $0x0,%eax
  test   %rdi,%rdi
  je     L6
  call   <atol@plt>
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L6:
  pop    %rbx
  ret
```

assistant: ```c
int xfrd_read_time_t(FILE *in, time_t *v) {
  char *p = xfrd_read_token(in);
  if (!p)
    return 0;
  *v = atol(p);
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<xfrd_read_time_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <xfrd_read_token@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L0
  call   <atol@plt>
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L0:
  pop    %rbx
  ret
```

assistant: ```c
int xfrd_read_time_t(FILE *in, time_t *v) {
  char *p = xfrd_read_token(in);
  if (!p)
    return 0;
  *v = atol(p);
  return 1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<xfrd_read_time_t>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  call   <xfrd_read_token@plt>
  mov    %rax,%rdi
  xor    %eax,%eax
  test   %rdi,%rdi
  je     L3
  call   <atol@plt>
  mov    %eax,(%rbx)
  mov    $0x1,%eax
L3:
  pop    %rbx
  ret
```

assistant: ```c
int xfrd_read_time_t(FILE *in, time_t *v) {
  char *p = xfrd_read_token(in);
  if (!p)
    return 0;
  *v = atol(p);
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<strtohex>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,%eax
  mov    %al,-0x4(%rbp)
  cmpb   $0x39,-0x4(%rbp)
  jg     L5
  movzbl -0x4(%rbp),%eax
  sub    $0x30,%eax
  jmp    L28
L5:
  cmpb   $0x46,-0x4(%rbp)
  jg     L8
  movzbl -0x4(%rbp),%eax
  sub    $0x37,%eax
  jmp    L28
L8:
  cmpb   $0x66,-0x4(%rbp)
  jg     L57
  movzbl -0x4(%rbp),%eax
  sub    $0x57,%eax
  jmp    L28
L57:
  mov    $0xffffffff,%eax
L28:
  pop    %rbp
  ret
```

assistant: ```c
uint8_t strtohex(uint8_t x) {
  if (x <= '9')
    return x - '0';
  else if (x <= 'F')
    return x - 'A' + 10;
  else if (x <= 'f')
    return x - 'a' + 10;
  return 0xFF;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<strtohex>:
  endbr64
  cmp    $0x39,%dil
  jle    L17
  cmp    $0x46,%dil
  jle    L0
  lea    -0x57(%rdi),%eax
  cmp    $0x67,%dil
  mov    $0xffffffff,%edi
  cmovge %edi,%eax
  ret
L17:
  lea    -0x30(%rdi),%eax
  ret
L0:
  lea    -0x37(%rdi),%eax
  ret
```

assistant: ```c
uint8_t strtohex(uint8_t x) {
  if (x <= '9')
    return x - '0';
  else if (x <= 'F')
    return x - 'A' + 10;
  else if (x <= 'f')
    return x - 'a' + 10;
  return 0xFF;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strtohex>:
  endbr64
  cmp    $0x39,%dil
  jle    L12
  cmp    $0x46,%dil
  jle    L7
  cmp    $0x67,%dil
  lea    -0x57(%rdi),%eax
  mov    $0xffffffff,%edi
  cmovge %edi,%eax
  ret
L7:
  lea    -0x37(%rdi),%eax
  ret
  nopl   0x0(%rax)
L12:
  lea    -0x30(%rdi),%eax
  ret
```

assistant: ```c
uint8_t strtohex(uint8_t x) {
  if (x <= '9')
    return x - '0';
  else if (x <= 'F')
    return x - 'A' + 10;
  else if (x <= 'f')
    return x - 'a' + 10;
  return 0xFF;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<strtohex>:
  endbr64
  cmp    $0x39,%dil
  jle    L2
  cmp    $0x46,%dil
  jle    L17
  cmp    $0x67,%dil
  lea    -0x57(%rdi),%eax
  mov    $0xffffffff,%edi
  cmovge %edi,%eax
  ret
L17:
  lea    -0x37(%rdi),%eax
  ret
  nopl   0x0(%rax)
L2:
  lea    -0x30(%rdi),%eax
  ret
```

assistant: ```c
uint8_t strtohex(uint8_t x) {
  if (x <= '9')
    return x - '0';
  else if (x <= 'F')
    return x - 'A' + 10;
  else if (x <= 'f')
    return x - 'a' + 10;
  return 0xFF;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<ft_putnbr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x24(%rbp)
  movq   $0x1,-0x18(%rbp)
  mov    -0x24(%rbp),%eax
  cltq
  mov    %rax,-0x10(%rbp)
  jmp    L31
L14:
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,-0x18(%rbp)
L31:
  mov    -0x18(%rbp),%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  add    %rax,%rax
  mov    %rax,%rsi
  mov    -0x10(%rbp),%rax
  cqto
  idiv   %rsi
  test   %rax,%rax
  jne    L14
  cmpq   $0x0,-0x10(%rbp)
  jns    L19
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  negq   -0x10(%rbp)
  jmp    L19
L1:
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  add    $0x30,%rax
  mov    %rax,%rdi
  call   <ft_putchar@plt>
  mov    -0x10(%rbp),%rax
  cqto
  idivq  -0x18(%rbp)
  mov    %rdx,-0x10(%rbp)
  mov    -0x18(%rbp),%rcx
  movabs $0x6666666666666667,%rdx
  mov    %rcx,%rax
  imul   %rdx
  mov    %rdx,%rax
  sar    $0x2,%rax
  sar    $0x3f,%rcx
  mov    %rcx,%rdx
  sub    %rdx,%rax
  mov    %rax,-0x18(%rbp)
L19:
  cmpq   $0x0,-0x18(%rbp)
  jg     L1
  nop
  nop
  leave
  ret
```

assistant: ```c
void ft_putnbr(int nb) {
  long int del;
  long int tmp;
  long int nb_m;
  del = 1;
  nb_m = nb;
  while (nb_m / (del * 10) != 0) {
    del = del * 10;
  }
  if (nb_m < 0) {
    ft_putchar('-');
    nb_m *= -1;
  }
  while (del >= 1) {
    tmp = nb_m / del;
    ft_putchar(tmp + 48);
    nb_m = nb_m % del;
    del /= 10;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<ft_putnbr>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  movslq %edi,%rbx
  mov    $0x1,%ecx
L22:
  mov    %rcx,%rbp
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rcx
  mov    %rbx,%rax
  cqto
  idiv   %rcx
  test   %rax,%rax
  jne    L22
  test   %rbx,%rbx
  js     L6
L2:
  test   %rbp,%rbp
  jle    L1
  movabs $0x6666666666666667,%r12
L47:
  mov    %rbx,%rax
  cqto
  idiv   %rbp
  mov    %rdx,%rbx
  lea    0x30(%rax),%rdi
  call   <ft_putchar@plt>
  mov    %rbp,%rcx
  mov    %rbp,%rax
  imul   %r12
  sar    $0x2,%rdx
  mov    %rbp,%rax
  sar    $0x3f,%rax
  sub    %rax,%rdx
  mov    %rdx,%rbp
  cmp    $0x9,%rcx
  jg     L47
L1:
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L6:
  mov    $0x2d,%edi
  call   <ft_putchar@plt>
  neg    %rbx
  jmp    L2
```

assistant: ```c
void ft_putnbr(int nb) {
  long int del;
  long int tmp;
  long int nb_m;
  del = 1;
  nb_m = nb;
  while (nb_m / (del * 10) != 0) {
    del = del * 10;
  }
  if (nb_m < 0) {
    ft_putchar('-');
    nb_m *= -1;
  }
  while (del >= 1) {
    tmp = nb_m / del;
    ft_putchar(tmp + 48);
    nb_m = nb_m % del;
    del /= 10;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_putnbr>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
L12:
  mov    %rbp,%rax
  mov    %rcx,%rbx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rcx
  cqto
  idiv   %rcx
  test   %rax,%rax
  jne    L12
  test   %rbp,%rbp
  js     L25
L2:
  movabs $0xcccccccccccccccd,%r12
  cs nopw 0x0(%rax,%rax,1)
L21:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  lea    0x30(%rax),%rdi
  mov    %rdx,%rbp
  call   <ft_putchar@plt>
  mov    %rbx,%rax
  mul    %r12
  mov    %rdx,%rbx
  shr    $0x3,%rbx
  jne    L21
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L25:
  mov    $0x2d,%edi
  neg    %rbp
  call   <ft_putchar@plt>
  jmp    L2
```

assistant: ```c
void ft_putnbr(int nb) {
  long int del;
  long int tmp;
  long int nb_m;
  del = 1;
  nb_m = nb;
  while (nb_m / (del * 10) != 0) {
    del = del * 10;
  }
  if (nb_m < 0) {
    ft_putchar('-');
    nb_m *= -1;
  }
  while (del >= 1) {
    tmp = nb_m / del;
    ft_putchar(tmp + 48);
    nb_m = nb_m % del;
    del /= 10;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<ft_putnbr>:
  endbr64
  push   %r12
  mov    $0x1,%ecx
  push   %rbp
  movslq %edi,%rbp
  push   %rbx
L15:
  mov    %rbp,%rax
  mov    %rcx,%rbx
  lea    (%rcx,%rcx,4),%rcx
  add    %rcx,%rcx
  cqto
  idiv   %rcx
  test   %rax,%rax
  jne    L15
  test   %rbp,%rbp
  js     L29
L26:
  movabs $0xcccccccccccccccd,%r12
  cs nopw 0x0(%rax,%rax,1)
L7:
  mov    %rbp,%rax
  cqto
  idiv   %rbx
  lea    0x30(%rax),%rdi
  mov    %rdx,%rbp
  call   <ft_putchar@plt>
  mov    %rbx,%rax
  mul    %r12
  mov    %rdx,%rbx
  shr    $0x3,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  mov    $0x2d,%edi
  neg    %rbp
  call   <ft_putchar@plt>
  jmp    L26
```

assistant: ```c
void ft_putnbr(int nb) {
  long int del;
  long int tmp;
  long int nb_m;
  del = 1;
  nb_m = nb;
  while (nb_m / (del * 10) != 0) {
    del = del * 10;
  }
  if (nb_m < 0) {
    ft_putchar('-');
    nb_m *= -1;
  }
  while (del >= 1) {
    tmp = nb_m / del;
    ft_putchar(tmp + 48);
    nb_m = nb_m % del;
    del /= 10;
  }
}
```