ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Converte this assembly snippet into its equivalent C code:

```asm
<qstat_strnstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  je     L88
  lea    0x1(%rsi),%r13
  mov    %rdx,%r14
  mov    %r13,%rdi
  lea    -0x1(%r14),%rbx
  call   <strlen@plt>
  mov    %rax,%r15
  test   %r14,%r14
  jne    L61
  nopl   0x0(%rax,%rax,1)
L86:
  xor    %r12d,%r12d
L88:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L19:
  cmp    %rbx,%r15
  ja     L86
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L25
L63:
  sub    $0x1,%rbx
  jb     L86
L61:
  mov    %r12,%r14
  movzbl (%r12),%eax
  add    $0x1,%r12
  test   %al,%al
  je     L86
  cmp    %al,%bpl
  jne    L63
  jmp    L19
L25:
  mov    %r14,%r12
  jmp    L88
```

assistant: ```c
char *qstat_strnstr(const char *s, const char *find, size_t slen) {
  char c, sc;
  size_t len;
  if ((c = *find++) != '\0') {
    len = strlen(find);
    do {
      do {
        if ((slen-- < 1) || ((sc = *s++) == '\0')) {
          return (NULL);
        }
      } while (sc != c);
      if (len > slen) {
        return (NULL);
      }
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<qstat_strnstr>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  movzbl (%rsi),%ebp
  test   %bpl,%bpl
  je     L73
  lea    0x1(%rsi),%r13
  mov    %rdx,%r14
  mov    %r13,%rdi
  lea    -0x1(%r14),%rbx
  call   <strlen@plt>
  mov    %rax,%r15
  test   %r14,%r14
  jne    L20
  nopl   0x0(%rax,%rax,1)
L55:
  xor    %r12d,%r12d
L73:
  add    $0x8,%rsp
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
  nopl   (%rax)
L86:
  cmp    %rbx,%r15
  ja     L55
  mov    %r15,%rdx
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <strncmp@plt>
  test   %rax,%rax
  je     L64
L45:
  sub    $0x1,%rbx
  jb     L55
L20:
  mov    %r12,%r14
  movzbl (%r12),%eax
  add    $0x1,%r12
  test   %al,%al
  je     L55
  cmp    %al,%bpl
  jne    L45
  jmp    L86
L64:
  mov    %r14,%r12
  jmp    L73
```

assistant: ```c
char *qstat_strnstr(const char *s, const char *find, size_t slen) {
  char c, sc;
  size_t len;
  if ((c = *find++) != '\0') {
    len = strlen(find);
    do {
      do {
        if ((slen-- < 1) || ((sc = *s++) == '\0')) {
          return (NULL);
        }
      } while (sc != c);
      if (len > slen) {
        return (NULL);
      }
    } while (strncmp(s, find, len) != 0);
    s--;
  }
  return ((char *)s);
}
```
user: Translate the below assembly code into C programming language:

```asm
<Tcl_ConvertElement>:
  endbr64
  mov    %edx,%eax
  and    $0x3,%eax
  cmp    $0x2,%eax
  je     L104
  movzbl (%rdi),%ecx
  test   %cl,%cl
  jne    L162
  movb   $0x5c,(%rsi)
  movb   $0x30,0x1(%rsi)
  lea    0x2(%rsi),%rax
  jmp    L248
L104:
  movb   $0x7b,(%rsi)
  lea    0x1(%rsi),%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L194
L41:
  mov    %dl,(%rax)
  add    $0x1,%rdi
  add    $0x1,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  jne    L41
L194:
  movb   $0x7d,(%rax)
  add    $0x1,%rax
L248:
  movb   $0x0,(%rax)
  sub    %esi,%eax
  ret
L162:
  mov    %rsi,%rax
  and    $0x4,%edx
  mov    $0x1,%r10d
  movabs $0x800001500000000,%r9
  jmp    L138
L83:
  cmp    $0x9,%cl
  jne    L182
  movb   $0x5c,(%rax)
  movb   $0x74,0x1(%rax)
  add    $0x2,%rax
  jmp    L244
L198:
  mov    %r10,%r8
  shl    %cl,%r8
  test   %r9,%r8
  jne    L43
  cmp    $0xd,%cl
  je     L199
  cmp    $0xc,%cl
  je     L21
L182:
  movzbl (%rdi),%ecx
  mov    %cl,(%rax)
  add    $0x1,%rax
L244:
  add    $0x1,%rdi
  movzbl (%rdi),%ecx
  test   %cl,%cl
  je     L248
L138:
  cmp    $0x3b,%cl
  jg     L249
  cmp    $0xb,%cl
  jg     L198
  cmp    $0xa,%cl
  je     L78
  cmp    $0xb,%cl
  jne    L83
  movb   $0x5c,(%rax)
  movb   $0x76,0x1(%rax)
  add    $0x2,%rax
  jmp    L244
L249:
  cmp    $0x7b,%cl
  je     L254
  jle    L230
  cmp    $0x7d,%cl
  jne    L182
L254:
  test   %edx,%edx
  je     L182
  movb   $0x5c,(%rax)
  add    $0x1,%rax
  jmp    L182
L230:
  sub    $0x5b,%ecx
  cmp    $0x2,%cl
  ja     L182
L43:
  movb   $0x5c,(%rax)
  add    $0x1,%rax
  jmp    L182
L21:
  movb   $0x5c,(%rax)
  movb   $0x66,0x1(%rax)
  add    $0x2,%rax
  jmp    L244
L78:
  movb   $0x5c,(%rax)
  movb   $0x6e,0x1(%rax)
  add    $0x2,%rax
  jmp    L244
L199:
  movb   $0x5c,(%rax)
  movb   $0x72,0x1(%rax)
  add    $0x2,%rax
  jmp    L244
```

assistant: ```c
int Tcl_ConvertElement(src, dst, flags)
register char *src;
char *dst;
int flags;
{
  register char *p = dst;
  if ((flags & 2) && !(flags & 1)) {
    *p = '{';
    p++;
    for (; *src != 0; src++, p++) {
      *p = *src;
    }
    *p = '}';
    p++;
  } else if (*src == 0) {
    p[0] = '\\';
    p[1] = '0';
    p += 2;
  } else {
    for (; *src != 0; src++) {
      switch (*src) {
      case ']':
      case '[':
      case '$':
      case ';':
      case ' ':
      case '\\':
      case '"':
        *p = '\\';
        p++;
        break;
      case '{':
      case '}':
        if (flags & 4) {
          *p = '\\';
          p++;
        }
        break;
      case '\f':
        *p = '\\';
        p++;
        *p = 'f';
        p++;
        continue;
      case '\n':
        *p = '\\';
        p++;
        *p = 'n';
        p++;
        continue;
      case '\r':
        *p = '\\';
        p++;
        *p = 'r';
        p++;
        continue;
      case '\t':
        *p = '\\';
        p++;
        *p = 't';
        p++;
        continue;
      case '\v':
        *p = '\\';
        p++;
        *p = 'v';
        p++;
        continue;
      }
      *p = *src;
      p++;
    }
  }
  *p = '\0';
  return p - dst;
}
```
user: What is the c source code of the assembly code below?

```asm
<rop3_34_0_0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,%ecx
  mov    %edx,%eax
  mov    %ecx,%edx
  mov    %dl,-0x1c(%rbp)
  mov    %al,-0x20(%rbp)
  movzbl -0x1c(%rbp),%eax
  not    %eax
  mov    %al,-0x2(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl (%rax),%eax
  and    -0x2(%rbp),%al
  mov    %al,-0x1(%rbp)
  mov    -0x18(%rbp),%rax
  movzbl -0x1(%rbp),%edx
  mov    %dl,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void rop3_34_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<rop3_34_0_0>:
  endbr64
  not    %esi
  and    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_34_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<rop3_34_0_0>:
  endbr64
  not    %esi
  and    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_34_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<rop3_34_0_0>:
  endbr64
  not    %esi
  and    %sil,(%rdi)
  ret
```

assistant: ```c
void rop3_34_0_0(unsigned char *D, unsigned char S, unsigned char T) {
  unsigned char stk1;
  unsigned char stk2;
  stk2 = ~S;
  stk1 = *D & stk2;
  *D = stk1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<write_file>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x24(%rbp)
  mov    %ecx,-0x28(%rbp)
  mov    -0x18(%rbp),%rax
  lea    D3(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fopen@plt>
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L29
L21:
  movl   $0x0,-0xc(%rbp)
  jmp    L30
L4:
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D23(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addq   $0x8,-0x20(%rbp)
  addl   $0x1,-0xc(%rbp)
L30:
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  cmp    %eax,-0x28(%rbp)
  jg     L4
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rdx
  mov    -0x8(%rbp),%rax
  movq   %rdx,%xmm0
  lea    D9(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fprintf@plt>
  addq   $0x8,-0x20(%rbp)
  addl   $0x1,-0x10(%rbp)
L29:
  mov    -0x10(%rbp),%eax
  cmp    -0x24(%rbp),%eax
  jl     L21
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <fclose@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D3
type_guessed: string
name: retrieve_data
arguments: data_tag: D23
type_guessed: string
name: retrieve_data
arguments: data_tag: D9
type_guessed: string

tool: D3: wt

tool: D23: %3.4f	

tool: D9: %.6g


assistant: ```c
void write_file(char const *fn, double *buf, int nrow, int ncol) {
  FILE *fp = fopen(fn, "wt");
  for (int i = 0; i < nrow; ++i) {
    for (int j = 0; j + 1 < ncol; ++j) {
      fprintf(fp, "%3.4f\t", *buf);
      ++buf;
    }
    fprintf(fp, "%.6g\n", *buf);
    ++buf;
  }
  fclose(fp);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<write_file>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rsi,%rbx
  mov    %edx,%r15d
  mov    %ecx,%r14d
  mov    %ecx,0x4(%rsp)
  lea    D10(%rip),%rsi
  call   <fopen@plt>
  mov    %rax,%r12
  test   %r15d,%r15d
  jle    L23
  lea    -0x2(%r14),%eax
  lea    0x8(,%rax,8),%rax
  mov    %rax,0x8(%rsp)
  mov    $0x0,%r14d
  lea    D29(%rip),%r13
  jmp    L29
L1:
  movsd  (%rbx),%xmm0
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  add    $0x8,%rbx
  cmp    %rbp,%rbx
  jne    L1
L51:
  movsd  0x0(%rbp),%xmm0
  lea    D22(%rip),%rsi
  mov    %r12,%rdi
  call   <fprintf@plt>
  lea    0x8(%rbp),%rbx
  add    $0x1,%r14d
  cmp    %r14d,%r15d
  je     L23
L29:
  mov    0x8(%rsp),%rax
  lea    (%rbx,%rax,1),%rbp
  cmpl   $0x1,0x4(%rsp)
  jg     L1
  mov    %rbx,%rbp
  jmp    L51
L23:
  mov    %r12,%rdi
  call   <fclose@plt>
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
data_type: string
name: unpack_data
arguments: label: D29
data_type: string
name: unpack_data
arguments: label: D22
data_type: string

tool: D10: wt

tool: D29: %3.4f	

tool: D22: %.6g


assistant: ```c
void write_file(char const *fn, double *buf, int nrow, int ncol) {
  FILE *fp = fopen(fn, "wt");
  for (int i = 0; i < nrow; ++i) {
    for (int j = 0; j + 1 < ncol; ++j) {
      fprintf(fp, "%3.4f\t", *buf);
      ++buf;
    }
    fprintf(fp, "%.6g\n", *buf);
    ++buf;
  }
  fclose(fp);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<write_file>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  lea    D12(%rip),%rsi
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %edx,(%rsp)
  mov    %ecx,0x4(%rsp)
  call   <fopen@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L29
  lea    -0x2(%r14),%eax
  xor    %r12d,%r12d
  lea    D22(%rip),%r14
  lea    0x8(,%rax,8),%rax
  lea    D17(%rip),%rbp
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L26:
  mov    0x8(%rsp),%rax
  cmpl   $0x1,0x4(%rsp)
  lea    (%r15,%rax,1),%rbx
  jle    L44
L19:
  movsd  (%r15),%xmm0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x8,%r15
  call   <fprintf@plt>
  cmp    %rbx,%r15
  jne    L19
L16:
  movsd  (%rbx),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  lea    0x8(%rbx),%r15
  add    $0x1,%r12d
  call   <fprintf@plt>
  cmp    %r12d,(%rsp)
  jne    L26
L29:
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <fclose@plt>
  nopl   0x0(%rax)
L44:
  mov    %r15,%rbx
  jmp    L16
```

tool_calls: name: read_data
arguments: data_label: D12
data_type: string
name: read_data
arguments: data_label: D22
data_type: string
name: read_data
arguments: data_label: D17
data_type: string

tool: D12: wt

tool: D22: %.6g


tool: D17: %3.4f	

assistant: ```c
void write_file(char const *fn, double *buf, int nrow, int ncol) {
  FILE *fp = fopen(fn, "wt");
  for (int i = 0; i < nrow; ++i) {
    for (int j = 0; j + 1 < ncol; ++j) {
      fprintf(fp, "%3.4f\t", *buf);
      ++buf;
    }
    fprintf(fp, "%.6g\n", *buf);
    ++buf;
  }
  fclose(fp);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<write_file>:
  endbr64
  push   %r15
  mov    %rsi,%r15
  lea    D28(%rip),%rsi
  push   %r14
  mov    %ecx,%r14d
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %edx,%ebx
  sub    $0x18,%rsp
  mov    %edx,(%rsp)
  mov    %ecx,0x4(%rsp)
  call   <fopen@plt>
  mov    %rax,%r13
  test   %ebx,%ebx
  jle    L18
  lea    -0x2(%r14),%eax
  xor    %r12d,%r12d
  lea    D25(%rip),%r14
  lea    0x8(,%rax,8),%rax
  lea    D6(%rip),%rbp
  mov    %rax,0x8(%rsp)
  cs nopw 0x0(%rax,%rax,1)
L34:
  mov    0x8(%rsp),%rax
  cmpl   $0x1,0x4(%rsp)
  lea    (%r15,%rax,1),%rbx
  jle    L23
L28:
  movsd  (%r15),%xmm0
  mov    %rbp,%rsi
  mov    %r13,%rdi
  add    $0x8,%r15
  call   <fprintf@plt>
  cmp    %rbx,%r15
  jne    L28
L17:
  movsd  (%rbx),%xmm0
  mov    %r14,%rsi
  mov    %r13,%rdi
  lea    0x8(%rbx),%r15
  add    $0x1,%r12d
  call   <fprintf@plt>
  cmp    %r12d,(%rsp)
  jne    L34
L18:
  add    $0x18,%rsp
  mov    %r13,%rdi
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1070 <fclose@plt>
  nopl   0x0(%rax)
L23:
  mov    %r15,%rbx
  jmp    L17
```

tool_calls: name: unpack_data
arguments: data_tag: D28
type: string
name: unpack_data
arguments: data_tag: D25
type: string
name: unpack_data
arguments: data_tag: D6
type: string

tool: D28: wt

tool: D25: %.6g


tool: D6: %3.4f	

assistant: ```c
void write_file(char const *fn, double *buf, int nrow, int ncol) {
  FILE *fp = fopen(fn, "wt");
  for (int i = 0; i < nrow; ++i) {
    for (int j = 0; j + 1 < ncol; ++j) {
      fprintf(fp, "%3.4f\t", *buf);
      ++buf;
    }
    fprintf(fp, "%.6g\n", *buf);
    ++buf;
  }
  fclose(fp);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<search_sort_test>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <bsearch_test@plt>
  mov    $0x0,%eax
  call   <qsort_test@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

assistant: ```c
int search_sort_test() {
  bsearch_test();
  qsort_test();
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<search_sort_test>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <bsearch_test@plt>
  mov    $0x0,%eax
  call   <qsort_test@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int search_sort_test() {
  bsearch_test();
  qsort_test();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<search_sort_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bsearch_test@plt>
  xor    %eax,%eax
  call   <qsort_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int search_sort_test() {
  bsearch_test();
  qsort_test();
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<search_sort_test>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <bsearch_test@plt>
  xor    %eax,%eax
  call   <qsort_test@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int search_sort_test() {
  bsearch_test();
  qsort_test();
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<Xgetsockname>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x28(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  lea    -0x10(%rbp),%rdx
  mov    -0x20(%rbp),%rcx
  mov    -0x14(%rbp),%eax
  mov    %rcx,%rsi
  mov    %eax,%edi
  call   <getsockname@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x10(%rbp),%eax
  mov    %eax,%edx
  mov    -0x28(%rbp),%rax
  mov    %edx,(%rax)
  mov    -0xc(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L6
  call   <__stack_chk_fail@plt>
L6:
  leave
  ret
```

assistant: ```c
int Xgetsockname(int s, struct sockaddr *a, int *l) {
  unsigned int rl;
  int code;
  rl = *l;
  code = getsockname(s, a, &rl);
  *l = rl;
  return code;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<Xgetsockname>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdx,%rbx
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    (%rdx),%eax
  mov    %eax,0x4(%rsp)
  lea    0x4(%rsp),%rdx
  call   <getsockname@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L8
  add    $0x10,%rsp
  pop    %rbx
  ret
L8:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Xgetsockname(int s, struct sockaddr *a, int *l) {
  unsigned int rl;
  int code;
  rl = *l;
  code = getsockname(s, a, &rl);
  *l = rl;
  return code;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<Xgetsockname>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdx),%eax
  lea    0x4(%rsp),%rdx
  mov    %eax,0x4(%rsp)
  call   <getsockname@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L7
  add    $0x10,%rsp
  pop    %rbx
  ret
L7:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Xgetsockname(int s, struct sockaddr *a, int *l) {
  unsigned int rl;
  int code;
  rl = *l;
  code = getsockname(s, a, &rl);
  *l = rl;
  return code;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<Xgetsockname>:
  endbr64
  push   %rbx
  mov    %rdx,%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  mov    (%rdx),%eax
  lea    0x4(%rsp),%rdx
  mov    %eax,0x4(%rsp)
  call   <getsockname@plt>
  mov    0x4(%rsp),%edx
  mov    %edx,(%rbx)
  mov    0x8(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L0
  add    $0x10,%rsp
  pop    %rbx
  ret
L0:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int Xgetsockname(int s, struct sockaddr *a, int *l) {
  unsigned int rl;
  int code;
  rl = *l;
  code = getsockname(s, a, &rl);
  *l = rl;
  return code;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<logit_1_clamped>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movss  %xmm0,-0x4(%rbp)
  movss  %xmm1,-0x8(%rbp)
  movss  %xmm2,-0xc(%rbp)
  mov    -0x4(%rbp),%eax
  movd   %eax,%xmm0
  call   <logit_1@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x4(%rbp)
  movss  -0xc(%rbp),%xmm0
  subss  -0x8(%rbp),%xmm0
  mulss  -0x4(%rbp),%xmm0
  movss  -0x8(%rbp),%xmm1
  addss  %xmm1,%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x4(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float logit_1_clamped(float a, float min, float max) {
  a = logit_1(a);
  a = min + (max - min) * a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<logit_1_clamped>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0x8(%rsp)
  movss  %xmm2,0xc(%rsp)
  call   <logit_1@plt>
  movaps %xmm0,%xmm1
  movss  0xc(%rsp),%xmm0
  movss  0x8(%rsp),%xmm3
  subss  %xmm3,%xmm0
  mulss  %xmm1,%xmm0
  addss  %xmm3,%xmm0
  add    $0x18,%rsp
  ret
```

assistant: ```c
float logit_1_clamped(float a, float min, float max) {
  a = logit_1(a);
  a = min + (max - min) * a;
  return a;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<logit_1_clamped>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <logit_1@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  subss  %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float logit_1_clamped(float a, float min, float max) {
  a = logit_1(a);
  a = min + (max - min) * a;
  return a;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<logit_1_clamped>:
  endbr64
  sub    $0x18,%rsp
  movss  %xmm1,0xc(%rsp)
  movss  %xmm2,0x8(%rsp)
  call   <logit_1@plt>
  movss  0xc(%rsp),%xmm1
  movss  0x8(%rsp),%xmm2
  add    $0x18,%rsp
  subss  %xmm1,%xmm2
  mulss  %xmm0,%xmm2
  addss  %xmm1,%xmm2
  movaps %xmm2,%xmm0
  ret
```

assistant: ```c
float logit_1_clamped(float a, float min, float max) {
  a = logit_1(a);
  a = min + (max - min) * a;
  return a;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<skip_to_next_directive>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L132
L73:
  cmpl   $0x20,-0x4(%rbp)
  je     L38
  cmpl   $0x9,-0x4(%rbp)
  jne    L20
L38:
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L132
L20:
  cmpl   $0xa,-0x4(%rbp)
  jne    L193
  movl   $0x0,-0x8(%rbp)
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L132
L193:
  cmpl   $0x2f,-0x4(%rbp)
  jne    L8
  movl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0x2a,-0x4(%rbp)
  jne    L132
  mov    $0x0,%eax
  call   <skip_comment@plt>
  test   %rax,%rax
  jne    L139
  mov    $0x0,%eax
  jmp    L95
L139:
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L132
L8:
  cmpl   $0x5c,-0x4(%rbp)
  jne    L76
  movl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xd,-0x4(%rbp)
  jne    L163
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  cmpl   $0xa,-0x4(%rbp)
  jne    L132
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L132
L163:
  cmpl   $0x0,-0x4(%rbp)
  je     L132
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
  jmp    L132
L76:
  cmpl   $0x23,-0x4(%rbp)
  jne    L82
  cmpl   $0x0,-0x8(%rbp)
  je     L103
L82:
  movl   $0x1,-0x8(%rbp)
  mov    $0x0,%eax
  call   <input@plt>
  mov    %eax,-0x4(%rbp)
L132:
  cmpl   $0x0,-0x4(%rbp)
  jne    L73
L103:
  mov    -0x4(%rbp),%eax
L95:
  leave
  ret
```

assistant: ```c
int skip_to_next_directive() {
  int state = 0;
  int c;
  c = input();
  while (c != 0) {
    if (c == ' ' || c == '\t') {
      c = input();
    } else if (c == '\n') {
      state = 0;
      c = input();
    } else if (c == '/') {
      state = 1;
      if ((c = input()) == '*') {
        if (skip_comment() == 0) {
          return 0;
        }
        c = input();
      }
    } else if (c == '\\') {
      state = 1;
      if ((c = input()) == '\r') {
        if ((c = input()) == '\n') {
          c = input();
        }
      } else if (c != 0) {
        c = input();
      }
    } else if (c != '#' || state != 0) {
      state = 1;
      c = input();
    } else {
      break;
    }
  }
  return c;
}
```