ylfeng/ReF-Decompile-dataset huggingface dataset:
user: What would the C source look like for the assembly code provided here:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,-0x20(%rbp)
  mov    -0x1c(%rbp),%edx
  mov    -0x20(%rbp),%eax
  add    %edx,%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  lea    0x1(%rax),%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <find_kth_element@plt>
  movq   %xmm0,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L5
  movsd  -0x8(%rbp),%xmm0
  jmp    L17
L5:
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  shr    $0x1f,%edx
  add    %edx,%eax
  sar    %eax
  mov    %eax,%edi
  mov    -0x20(%rbp),%ecx
  mov    -0x28(%rbp),%rdx
  mov    -0x1c(%rbp),%esi
  mov    -0x18(%rbp),%rax
  mov    %edi,%r8d
  mov    %rax,%rdi
  call   <find_kth_element@plt>
  movsd  -0x8(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  movsd  -0x8(%rbp),%xmm0
  movsd  D6(%rip),%xmm1
  divsd  %xmm1,%xmm0
L17:
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: parse_data
arguments: label: D6
datatype: f64

tool: D6: 2

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1_size, int *nums2, int nums2_size) {
  int nums_size = nums1_size + nums2_size;
  double result = find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2 + 1);
  if (nums_size & 1)
    return result;
  result += find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2);
  return result / 2.0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %esi,%ebp
  mov    %rdx,%r14
  mov    %ecx,%r12d
  lea    (%rsi,%rcx,1),%r15d
  mov    %r15d,%ebx
  shr    $0x1f,%ebx
  add    %r15d,%ebx
  sar    %ebx
  lea    0x1(%rbx),%r8d
  call   <find_kth_element@plt>
  movsd  %xmm0,0x8(%rsp)
  test   $0x1,%r15b
  je     L4
L15:
  movsd  0x8(%rsp),%xmm0
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L4:
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  call   <find_kth_element@plt>
  addsd  0x8(%rsp),%xmm0
  mulsd  D9(%rip),%xmm0
  movsd  %xmm0,0x8(%rsp)
  jmp    L15
```

tool_calls: name: read_data
arguments: data_label: D9
datatype: byte[8]

tool: {"D9": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1_size, int *nums2, int nums2_size) {
  int nums_size = nums1_size + nums2_size;
  double result = find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2 + 1);
  if (nums_size & 1)
    return result;
  result += find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2);
  return result / 2.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r15
  lea    (%rsi,%rcx,1),%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r15d,%ebx
  shr    $0x1f,%ebx
  add    %r15d,%ebx
  sar    %ebx
  sub    $0x18,%rsp
  lea    0x1(%rbx),%r8d
  call   <find_kth_element@plt>
  and    $0x1,%r15d
  movapd %xmm0,%xmm1
  jne    L4
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <find_kth_element@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  mulsd  D8(%rip),%xmm1
L4:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D8
type_guessed: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1_size, int *nums2, int nums2_size) {
  int nums_size = nums1_size + nums2_size;
  double result = find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2 + 1);
  if (nums_size & 1)
    return result;
  result += find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2);
  return result / 2.0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<findMedianSortedArrays>:
  endbr64
  push   %r15
  lea    (%rsi,%rcx,1),%r15d
  push   %r14
  mov    %rdx,%r14
  push   %r13
  mov    %rdi,%r13
  push   %r12
  mov    %ecx,%r12d
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %r15d,%ebx
  shr    $0x1f,%ebx
  add    %r15d,%ebx
  sar    %ebx
  sub    $0x18,%rsp
  lea    0x1(%rbx),%r8d
  call   <find_kth_element@plt>
  and    $0x1,%r15d
  movapd %xmm0,%xmm1
  jne    L1
  mov    %ebx,%r8d
  mov    %r12d,%ecx
  mov    %r14,%rdx
  mov    %ebp,%esi
  mov    %r13,%rdi
  movsd  %xmm0,0x8(%rsp)
  call   <find_kth_element@plt>
  movsd  0x8(%rsp),%xmm1
  addsd  %xmm0,%xmm1
  mulsd  D8(%rip),%xmm1
L1:
  add    $0x18,%rsp
  movapd %xmm1,%xmm0
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
datatype: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double findMedianSortedArrays(int *nums1, int nums1_size, int *nums2, int nums2_size) {
  int nums_size = nums1_size + nums2_size;
  double result = find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2 + 1);
  if (nums_size & 1)
    return result;
  result += find_kth_element(nums1, nums1_size, nums2, nums2_size, nums_size / 2);
  return result / 2.0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<__ip__>:
  endbr64
  mov    %rsi,%r8
  mov    %edx,%r9d
  and    $0x7,%r9d
  sar    $0x3,%edx
  je     L27
  mov    %rdi,%rax
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%esi
  shl    $0x6,%rsi
  lea    0x40(%rdi,%rsi,1),%rsi
  pxor   %xmm0,%xmm0
L6:
  movsd  (%rax),%xmm1
  mulsd  (%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x8(%rax),%xmm0
  mulsd  0x8(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x10(%rax),%xmm1
  mulsd  0x10(%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x18(%rax),%xmm0
  mulsd  0x18(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x20(%rax),%xmm1
  mulsd  0x20(%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x28(%rax),%xmm0
  mulsd  0x28(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  0x30(%rax),%xmm1
  mulsd  0x30(%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  0x38(%rax),%xmm0
  mulsd  0x38(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  add    $0x40,%rax
  add    $0x40,%rcx
  cmp    %rsi,%rax
  jne    L6
  shl    $0x3,%edx
L17:
  mov    %r9d,%eax
  lea    D4(%rip),%rcx
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
L27:
  pxor   %xmm0,%xmm0
  jmp    L17
  movslq %edx,%rax
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%edx
  movslq %edx,%rax
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%edx
  movslq %edx,%rax
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%edx
  movslq %edx,%rax
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%edx
  movslq %edx,%rax
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%edx
  movslq %edx,%rax
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  add    $0x1,%edx
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm1
  mulsd  (%r8,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int j, k;
  register int i;
  register double sum;
  sum = 0.0;
  i = len >> 3;
  j = 0;
  k = len & 7;
  while (i--) {
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
  }
  switch (k) {
  case 7:
    sum += dp1[j] * dp2[j];
    j++;
  case 6:
    sum += dp1[j] * dp2[j];
    j++;
  case 5:
    sum += dp1[j] * dp2[j];
    j++;
  case 4:
    sum += dp1[j] * dp2[j];
    j++;
  case 3:
    sum += dp1[j] * dp2[j];
    j++;
  case 2:
    sum += dp1[j] * dp2[j];
    j++;
  case 1:
    sum += dp1[j] * dp2[j];
    j++;
  }
  return sum;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<__ip__>:
  endbr64
  mov    %edx,%r9d
  mov    %rsi,%r8
  and    $0x7,%r9d
  sar    $0x3,%edx
  je     L25
  mov    %rsi,%rcx
  lea    -0x1(%rdx),%esi
  pxor   %xmm0,%xmm0
  mov    %rdi,%rax
  shl    $0x6,%rsi
  lea    0x40(%rdi,%rsi,1),%rsi
  nopl   (%rax)
L2:
  movsd  (%rax),%xmm1
  mulsd  (%rcx),%xmm1
  add    $0x40,%rax
  add    $0x40,%rcx
  addsd  %xmm0,%xmm1
  movsd  -0x38(%rax),%xmm0
  mulsd  -0x38(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x30(%rax),%xmm1
  mulsd  -0x30(%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x28(%rax),%xmm0
  mulsd  -0x28(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x20(%rax),%xmm1
  mulsd  -0x20(%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x18(%rax),%xmm0
  mulsd  -0x18(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  movsd  -0x10(%rax),%xmm1
  mulsd  -0x10(%rcx),%xmm1
  addsd  %xmm0,%xmm1
  movsd  -0x8(%rax),%xmm0
  mulsd  -0x8(%rcx),%xmm0
  addsd  %xmm1,%xmm0
  cmp    %rax,%rsi
  jne    L2
  shl    $0x3,%edx
L12:
  lea    D5(%rip),%rcx
  mov    %r9d,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%rdi,%rax,8),%xmm1
  mulsd  (%r8,%rax,8),%xmm1
  addsd  %xmm1,%xmm0
  movslq %edx,%rdx
  movsd  (%rdi,%rdx,8),%xmm1
  mulsd  (%r8,%rdx,8),%xmm1
  addsd  %xmm1,%xmm0
  ret
  nopl   0x0(%rax)
L25:
  pxor   %xmm0,%xmm0
  jmp    L12
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int j, k;
  register int i;
  register double sum;
  sum = 0.0;
  i = len >> 3;
  j = 0;
  k = len & 7;
  while (i--) {
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
  }
  switch (k) {
  case 7:
    sum += dp1[j] * dp2[j];
    j++;
  case 6:
    sum += dp1[j] * dp2[j];
    j++;
  case 5:
    sum += dp1[j] * dp2[j];
    j++;
  case 4:
    sum += dp1[j] * dp2[j];
    j++;
  case 3:
    sum += dp1[j] * dp2[j];
    j++;
  case 2:
    sum += dp1[j] * dp2[j];
    j++;
  case 1:
    sum += dp1[j] * dp2[j];
    j++;
  }
  return sum;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<__ip__>:
  endbr64
  mov    %edx,%r9d
  mov    %rdi,%r8
  mov    %rsi,%rdi
  and    $0x7,%r9d
  sar    $0x3,%edx
  je     L5
  mov    %rsi,%rax
  lea    -0x1(%rdx),%esi
  pxor   %xmm3,%xmm3
  mov    %r8,%rcx
  shl    $0x6,%rsi
  lea    0x40(%rdi,%rsi,1),%rsi
L29:
  movupd (%rcx),%xmm6
  movupd (%rax),%xmm2
  add    $0x40,%rax
  add    $0x40,%rcx
  movupd -0x30(%rcx),%xmm7
  movupd -0x30(%rax),%xmm1
  mulpd  %xmm6,%xmm2
  movupd -0x20(%rax),%xmm0
  movupd -0x20(%rcx),%xmm6
  mulpd  %xmm7,%xmm1
  movupd -0x10(%rax),%xmm4
  movupd -0x10(%rcx),%xmm7
  mulpd  %xmm6,%xmm0
  mulpd  %xmm7,%xmm4
  movapd %xmm2,%xmm5
  unpckhpd %xmm2,%xmm2
  addsd  %xmm3,%xmm5
  movapd %xmm4,%xmm3
  unpckhpd %xmm4,%xmm4
  addsd  %xmm5,%xmm2
  addsd  %xmm1,%xmm2
  unpckhpd %xmm1,%xmm1
  addsd  %xmm2,%xmm1
  addsd  %xmm0,%xmm1
  unpckhpd %xmm0,%xmm0
  addsd  %xmm1,%xmm0
  addsd  %xmm0,%xmm3
  addsd  %xmm4,%xmm3
  cmp    %rax,%rsi
  jne    L29
  shl    $0x3,%edx
L11:
  lea    D9(%rip),%rcx
  mov    %r9d,%eax
  movslq (%rcx,%rax,4),%rax
  add    %rcx,%rax
  notrack jmp *%rax
  nopw   0x0(%rax,%rax,1)
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm3
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm3
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm3
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm3
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm3
  movslq %edx,%rax
  add    $0x1,%edx
  movsd  (%r8,%rax,8),%xmm0
  mulsd  (%rdi,%rax,8),%xmm0
  addsd  %xmm0,%xmm3
  movslq %edx,%rdx
  movsd  (%r8,%rdx,8),%xmm0
  mulsd  (%rdi,%rdx,8),%xmm0
  addsd  %xmm0,%xmm3
  movapd %xmm3,%xmm0
  ret
  nopl   (%rax)
L5:
  pxor   %xmm3,%xmm3
  jmp    L11
```

assistant: ```c
double __ip__(dp1, dp2, len)
register double *dp1, *dp2;
int len;
{
  register int j, k;
  register int i;
  register double sum;
  sum = 0.0;
  i = len >> 3;
  j = 0;
  k = len & 7;
  while (i--) {
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
    sum += dp1[j] * dp2[j];
    j++;
  }
  switch (k) {
  case 7:
    sum += dp1[j] * dp2[j];
    j++;
  case 6:
    sum += dp1[j] * dp2[j];
    j++;
  case 5:
    sum += dp1[j] * dp2[j];
    j++;
  case 4:
    sum += dp1[j] * dp2[j];
    j++;
  case 3:
    sum += dp1[j] * dp2[j];
    j++;
  case 2:
    sum += dp1[j] * dp2[j];
    j++;
  case 1:
    sum += dp1[j] * dp2[j];
    j++;
  }
  return sum;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<chop_newline>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L27
L16:
  addq   $0x1,-0x8(%rbp)
L27:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L16
  jmp    L44
L17:
  subq   $0x1,-0x8(%rbp)
L44:
  mov    -0x8(%rbp),%rax
  cmp    -0x18(%rbp),%rax
  jb     L68
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xd,%al
  je     L17
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0xa,%al
  je     L17
L68:
  mov    -0x8(%rbp),%rax
  add    $0x1,%rax
  movb   $0x0,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void chop_newline(char *s) {
  char *t;
  for (t = s; *t != 0; t++)
    ;
  for (; t >= s && (*t == 0 || *t == '\r' || *t == '\n'); t--)
    ;
  *(t + 1) = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chop_newline>:
  endbr64
  cmpb   $0x0,(%rdi)
  je     L23
  mov    %rdi,%rax
L61:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L61
  cmp    %rax,%rdi
  ja     L5
L62:
  mov    $0x2401,%ecx
  jmp    L8
L23:
  mov    %rdi,%rax
  jmp    L62
L71:
  bt     %rdx,%rcx
  jae    L5
  sub    $0x1,%rax
  cmp    %rax,%rdi
  ja     L5
L8:
  movzbl (%rax),%edx
  cmp    $0xd,%dl
  jbe    L71
L5:
  movb   $0x0,0x1(%rax)
  ret
```

assistant: ```c
void chop_newline(char *s) {
  char *t;
  for (t = s; *t != 0; t++)
    ;
  for (; t >= s && (*t == 0 || *t == '\r' || *t == '\n'); t--)
    ;
  *(t + 1) = 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<chop_newline>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L52
  nopl   0x0(%rax)
L14:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L14
L52:
  xor    %edx,%edx
  mov    $0xffffffffffffdbfe,%rcx
  nopw   0x0(%rax,%rax,1)
L24:
  cmp    $0xd,%dl
  jbe    L22
L45:
  movb   $0x0,0x1(%rax)
  ret
  nopw   0x0(%rax,%rax,1)
L22:
  bt     %rdx,%rcx
  jb     L45
  sub    $0x1,%rax
  cmp    %rax,%rdi
  ja     L45
  movzbl (%rax),%edx
  jmp    L24
```

assistant: ```c
void chop_newline(char *s) {
  char *t;
  for (t = s; *t != 0; t++)
    ;
  for (; t >= s && (*t == 0 || *t == '\r' || *t == '\n'); t--)
    ;
  *(t + 1) = 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<chop_newline>:
  endbr64
  cmpb   $0x0,(%rdi)
  mov    %rdi,%rax
  je     L15
  nopl   0x0(%rax)
L24:
  add    $0x1,%rax
  cmpb   $0x0,(%rax)
  jne    L24
L15:
  mov    $0xffffffffffffdbfe,%rcx
L42:
  movzbl (%rax),%edx
  cmp    $0xd,%dl
  jbe    L49
L19:
  movb   $0x0,0x1(%rax)
  ret
  nopl   (%rax)
L49:
  bt     %rdx,%rcx
  jb     L19
  sub    $0x1,%rax
  cmp    %rax,%rdi
  jbe    L42
  movb   $0x0,0x1(%rax)
  ret
```

assistant: ```c
void chop_newline(char *s) {
  char *t;
  for (t = s; *t != 0; t++)
    ;
  for (; t >= s && (*t == 0 || *t == '\r' || *t == '\n'); t--)
    ;
  *(t + 1) = 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <readLine@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D10(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  mov    %rax,%rdi
  call   <free@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <system@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L2
  call   <__stack_chk_fail@plt>
L2:
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D10
type_infered: string
name: unpack_data
arguments: label: D3
type_infered: string

tool: D10: Your string: %s


tool: D3: PAUSE

assistant: ```c
int main() {
  char *str;
  readLine(&str);
  printf("Your string: %s\n", str);
  free(str);
  system("PAUSE");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <readLine@plt>
  mov    (%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  lea    D16(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  mov    $0x0,%eax
  add    $0x18,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
datatype: string
name: read_data
arguments: label: D16
datatype: string

tool: D10: Your string: %s


tool: D16: PAUSE

assistant: ```c
int main() {
  char *str;
  readLine(&str);
  printf("Your string: %s\n", str);
  free(str);
  system("PAUSE");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <readLine@plt>
  mov    (%rsp),%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  lea    D2(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D10
datatype: string
name: extract_symbolic_data
arguments: tag: D2
datatype: string

tool: D10: Your string: %s


tool: D2: PAUSE

assistant: ```c
int main() {
  char *str;
  readLine(&str);
  printf("Your string: %s\n", str);
  free(str);
  system("PAUSE");
  return 0;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rdi
  call   <readLine@plt>
  mov    (%rsp),%rsi
  lea    D19(%rip),%rdi
  call   <printf@plt>
  mov    (%rsp),%rdi
  call   <free@plt>
  lea    D10(%rip),%rdi
  call   <system@plt>
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L1
  xor    %eax,%eax
  add    $0x18,%rsp
  ret
L1:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D19
type_guessed: string
name: retrieve_data
arguments: data_tag: D10
type_guessed: string

tool: D19: Your string: %s


tool: D10: PAUSE

assistant: ```c
int main() {
  char *str;
  readLine(&str);
  printf("Your string: %s\n", str);
  free(str);
  system("PAUSE");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<tablenameid>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    D15(%rip),%eax
  add    $0x1,%eax
  mov    %eax,D70(%rip)
  mov    D70(%rip),%eax
  cltd
  shr    $0x1e,%edx
  add    %edx,%eax
  and    $0x3,%eax
  sub    %edx,%eax
  mov    %eax,D70(%rip)
  mov    D70(%rip),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    D70(%rip),%rdx
  add    %rdx,%rax
  mov    %rax,-0x18(%rbp)
  movl   $0x0,-0x20(%rbp)
  movl   $0x0,-0x1c(%rbp)
  jmp    L25
L17:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x5f,%al
  jne    L22
  addl   $0x1,-0x1c(%rbp)
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L46
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%edx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%ecx
  mov    %ecx,-0x20(%rbp)
  movslq %eax,%rcx
  mov    -0x18(%rbp),%rax
  lea    (%rcx,%rax,1),%rbx
  mov    %edx,%edi
  call   <toupper@plt>
  mov    %al,(%rbx)
  jmp    L20
L22:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x20(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x20(%rbp)
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  movzbl (%rcx),%eax
  mov    %al,(%rdx)
L20:
  addl   $0x1,-0x1c(%rbp)
L25:
  mov    -0x1c(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L17
  jmp    L49
L46:
  nop
L49:
  mov    -0x20(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x18(%rbp),%rax
  lea    D33(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcat@plt>
  mov    D70(%rip),%eax
  movslq %eax,%rdx
  mov    %rdx,%rax
  shl    $0x2,%rax
  add    %rdx,%rax
  lea    0x0(,%rax,4),%rdx
  add    %rdx,%rax
  shl    $0x2,%rax
  lea    D70(%rip),%rdx
  add    %rdx,%rax
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: unpack_data
arguments: data_tag: D33
type_infered: string

tool: D33: Id

assistant: ```c
const char *tablenameid(const char *tablename) {
  static char buf[4][100];
  static int s = 0;
  ++s, s %= 4;
  char *result = buf[s];
  int c = 0;
  for (int i = 0; tablename[i] != '\0'; ++i) {
    if (tablename[i] == '_') {
      if (tablename[++i] == '\0') {
        break;
      }
      result[c++] = (toupper((int)(tablename[i])));
    } else {
      result[c++] = tablename[i];
    }
  }
  result[c] = 0;
  strcat(result, "Id");
  return buf[s];
}
```