ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 这段汇编代码用C语言表示是什么样的?

```asm
<HashGen>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L13
L19:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x8,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x2(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x10,%eax
  xor    %eax,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x3(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  shl    $0x18,%eax
  xor    %eax,-0x8(%rbp)
  addl   $0x1,-0x4(%rbp)
L13:
  mov    -0x1c(%rbp),%eax
  lea    -0x4(%rax),%edx
  mov    -0x4(%rbp),%eax
  cmp    %eax,%edx
  ja     L19
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
unsigned int HashGen(unsigned char *file, unsigned int size) {
  unsigned int HASH = 0;
  int i;
  for (i = 0; i < size - 4; i++) {
    HASH ^= file[i];
    HASH ^= file[i + 1] << 8;
    HASH ^= file[i + 2] << 16;
    HASH ^= file[i + 3] << 24;
  }
  return HASH;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<HashGen>:
  endbr64
  cmp    $0x4,%esi
  je     L2
  mov    %rdi,%rdx
  lea    -0x5(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%r8
  mov    $0x0,%esi
L10:
  movzbl 0x1(%rdx),%eax
  shl    $0x8,%eax
  movzbl 0x2(%rdx),%ecx
  shl    $0x10,%ecx
  xor    %ecx,%eax
  movzbl 0x3(%rdx),%ecx
  shl    $0x18,%ecx
  movzbl (%rdx),%edi
  xor    %edi,%ecx
  xor    %ecx,%eax
  xor    %eax,%esi
  add    $0x1,%rdx
  cmp    %r8,%rdx
  jne    L10
L24:
  mov    %esi,%eax
  ret
L2:
  mov    $0x0,%esi
  jmp    L24
```

assistant: ```c
unsigned int HashGen(unsigned char *file, unsigned int size) {
  unsigned int HASH = 0;
  int i;
  for (i = 0; i < size - 4; i++) {
    HASH ^= file[i];
    HASH ^= file[i + 1] << 8;
    HASH ^= file[i + 2] << 16;
    HASH ^= file[i + 3] << 24;
  }
  return HASH;
}
```
user: What is the c source code of the assembly code below?

```asm
<HashGen>:
  endbr64
  cmp    $0x4,%esi
  je     L19
  lea    -0x5(%rsi),%eax
  xor    %r8d,%r8d
  lea    0x1(%rdi,%rax,1),%rsi
  nopl   0x0(%rax)
L12:
  movzbl 0x1(%rdi),%eax
  movzbl 0x2(%rdi),%edx
  add    $0x1,%rdi
  movzbl -0x1(%rdi),%ecx
  shl    $0x10,%edx
  shl    $0x8,%eax
  xor    %edx,%eax
  movzbl 0x2(%rdi),%edx
  shl    $0x18,%edx
  xor    %ecx,%edx
  xor    %edx,%eax
  xor    %eax,%r8d
  cmp    %rdi,%rsi
  jne    L12
  mov    %r8d,%eax
  ret
  nopw   0x0(%rax,%rax,1)
L19:
  xor    %r8d,%r8d
  mov    %r8d,%eax
  ret
```

assistant: ```c
unsigned int HashGen(unsigned char *file, unsigned int size) {
  unsigned int HASH = 0;
  int i;
  for (i = 0; i < size - 4; i++) {
    HASH ^= file[i];
    HASH ^= file[i + 1] << 8;
    HASH ^= file[i + 2] << 16;
    HASH ^= file[i + 3] << 24;
  }
  return HASH;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<sam_print>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L5:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  mov    -0x4(%rbp),%eax
  movq   %rdx,%xmm0
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L5
  nop
  nop
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
datatype: string

tool: D9: mu%d=%f, 

assistant: ```c
void sam_print(const double *mu, const int N) {
  for (int i = 0; i < N; ++i) {
    printf("mu%d=%f, ", i, mu[i]);
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<sam_print>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%r12
  mov    %esi,%ebp
  mov    $0x0,%ebx
  lea    D0(%rip),%r13
L11:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r13,%rdi
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L11
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L15:
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D0
type: string

tool: D0: mu%d=%f, 

assistant: ```c
void sam_print(const double *mu, const int N) {
  for (int i = 0; i < N; ++i) {
    printf("mu%d=%f, ", i, mu[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sam_print>:
  endbr64
  test   %esi,%esi
  jle    L15
  push   %r13
  lea    D0(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L7:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbp,%rbx
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L15:
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D0
datatype: string

tool: D0: mu%d=%f, 

assistant: ```c
void sam_print(const double *mu, const int N) {
  for (int i = 0; i < N; ++i) {
    printf("mu%d=%f, ", i, mu[i]);
  }
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<sam_print>:
  endbr64
  test   %esi,%esi
  jle    L0
  push   %r13
  lea    D2(%rip),%r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  movslq %esi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L14:
  movsd  (%r12,%rbx,8),%xmm0
  mov    %ebx,%esi
  mov    %r13,%rdi
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    %rbx,%rbp
  jne    L14
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
  nopl   0x0(%rax)
L0:
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type: string

tool: D2: mu%d=%f, 

assistant: ```c
void sam_print(const double *mu, const int N) {
  for (int i = 0; i < N; ++i) {
    printf("mu%d=%f, ", i, mu[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<hostx_calculate_color_shift>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  movl   $0x1,-0x4(%rbp)
  jmp    L9
L16:
  addl   $0x1,-0x4(%rbp)
L9:
  shrq   -0x18(%rbp)
  cmpq   $0x0,-0x18(%rbp)
  jne    L16
  mov    -0x4(%rbp),%eax
  sub    $0x8,%eax
  mov    %eax,-0x4(%rbp)
  cmpl   $0x0,-0x4(%rbp)
  jns    L23
  movl   $0x0,-0x4(%rbp)
L23:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int hostx_calculate_color_shift(unsigned long mask) {
  int shift = 1;
  while ((mask = (mask >> 1)))
    shift++;
  shift = shift - sizeof(unsigned char) * 8;
  if (shift < 0)
    shift = 0;
  return shift;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<hostx_calculate_color_shift>:
  endbr64
  shr    %rdi
  je     L0
  mov    $0x1,%eax
L9:
  add    $0x1,%eax
  shr    %rdi
  jne    L9
L28:
  sub    $0x8,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  ret
L0:
  mov    $0x1,%eax
  jmp    L28
```

assistant: ```c
int hostx_calculate_color_shift(unsigned long mask) {
  int shift = 1;
  while ((mask = (mask >> 1)))
    shift++;
  shift = shift - sizeof(unsigned char) * 8;
  if (shift < 0)
    shift = 0;
  return shift;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<hostx_calculate_color_shift>:
  endbr64
  shr    %rdi
  je     L4
  mov    $0x1,%edx
  xchg   %ax,%ax
L6:
  mov    %edx,%eax
  add    $0x1,%edx
  shr    %rdi
  jne    L6
  sub    $0x7,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L4:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hostx_calculate_color_shift(unsigned long mask) {
  int shift = 1;
  while ((mask = (mask >> 1)))
    shift++;
  shift = shift - sizeof(unsigned char) * 8;
  if (shift < 0)
    shift = 0;
  return shift;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<hostx_calculate_color_shift>:
  endbr64
  shr    %rdi
  je     L17
  mov    $0x1,%edx
  xchg   %ax,%ax
L2:
  mov    %edx,%eax
  add    $0x1,%edx
  shr    %rdi
  jne    L2
  sub    $0x7,%eax
  mov    $0x0,%edx
  cmovs  %edx,%eax
  ret
  cs nopw 0x0(%rax,%rax,1)
L17:
  xor    %eax,%eax
  ret
```

assistant: ```c
int hostx_calculate_color_shift(unsigned long mask) {
  int shift = 1;
  while ((mask = (mask >> 1)))
    shift++;
  shift = shift - sizeof(unsigned char) * 8;
  if (shift < 0)
    shift = 0;
  return shift;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<explode>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x20(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <count_delim@plt>
  mov    %eax,-0x4(%rbp)
  mov    -0x28(%rbp),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x4(%rbp),%edx
  mov    -0x20(%rbp),%rcx
  mov    -0x18(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <array_of_segments@plt>
  leave
  ret
```

assistant: ```c
char **explode(char *buf, char *dl, int *acp) {
  int i = count_delim(buf, dl);
  *acp = i;
  return array_of_segments(buf, dl, i);
}
```
user: Translate the below assembly code into C programming language:

```asm
<explode>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  call   <count_delim@plt>
  mov    %eax,%edx
  mov    %eax,(%r12)
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <array_of_segments@plt>
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char **explode(char *buf, char *dl, int *acp) {
  int i = count_delim(buf, dl);
  *acp = i;
  return array_of_segments(buf, dl, i);
}
```
user: What is the c source code of the assembly code below?

```asm
<explode>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <count_delim@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  mov    %eax,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <array_of_segments@plt>
```

assistant: ```c
char **explode(char *buf, char *dl, int *acp) {
  int i = count_delim(buf, dl);
  *acp = i;
  return array_of_segments(buf, dl, i);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<explode>:
  endbr64
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  mov    %rdx,%rbx
  call   <count_delim@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  mov    %eax,(%rbx)
  mov    %eax,%edx
  pop    %rbx
  pop    %rbp
  pop    %r12
  jmp    1070 <array_of_segments@plt>
```

assistant: ```c
char **explode(char *buf, char *dl, int *acp) {
  int i = count_delim(buf, dl);
  *acp = i;
  return array_of_segments(buf, dl, i);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x18,%rsp
  movsd  %xmm0,-0x18(%rbp)
  movsd  D2(%rip),%xmm2
  movsd  %xmm2,-0x20(%rbp)
  movsd  D6(%rip),%xmm0
  comisd -0x18(%rbp),%xmm0
  jbe    L53
  mov    $0x0,%eax
  jmp    L45
L53:
  movsd  -0x18(%rbp),%xmm0
  ucomisd D6(%rip),%xmm0
  jp     L1
  movsd  -0x18(%rbp),%xmm0
  ucomisd D6(%rip),%xmm0
  jne    L1
  mov    $0x1,%eax
  jmp    L45
L1:
  movsd  D6(%rip),%xmm0
  mov    -0x18(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  call   <remainder@plt>
  test   %eax,%eax
  jne    L43
  mov    $0x0,%eax
  jmp    L45
L43:
  mov    -0x18(%rbp),%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  cvttsd2si %xmm0,%ebx
  jmp    L3
L17:
  mov    -0x18(%rbp),%rax
  movsd  -0x20(%rbp),%xmm1
  movq   %rax,%xmm0
  call   <remainder@plt>
  test   %eax,%eax
  jne    L22
  mov    $0x0,%eax
  jmp    L45
L22:
  movsd  D6(%rip),%xmm0
  addsd  -0x20(%rbp),%xmm0
  movsd  %xmm0,-0x20(%rbp)
L3:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  comisd -0x20(%rbp),%xmm0
  jae    L17
  mov    $0x1,%eax
L45:
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D2
data_type: f64
name: retrieve_data
arguments: data_label: D6
data_type: byte[8]

tool: D2: 3

tool: {"D6": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

assistant: ```c
int prime(double n) {
  double sqrt(double x);
  register double d = 3;
  register rt;
  if (n < 2)
    return 0;
  if (n == 2)
    return 1;
  if (!(remainder((n), (2))))
    return 0;
  rt = sqrt(n);
  while (d <= rt) {
    if (!(remainder((n), (d))))
      return 0;
    d += 2;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prime>:
  endbr64
  push   %rbx
  sub    $0x10,%rsp
  movapd %xmm0,%xmm3
  movsd  %xmm0,0x8(%rsp)
  mov    $0x0,%eax
  movsd  D5(%rip),%xmm0
  comisd %xmm3,%xmm0
  ja     L71
  ucomisd %xmm0,%xmm3
  jp     L61
  mov    $0x1,%eax
  jne    L61
L71:
  add    $0x10,%rsp
  pop    %rbx
  ret
L61:
  movsd  D5(%rip),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <remainder@plt>
  test   %eax,%eax
  je     L71
  pxor   %xmm0,%xmm0
  movsd  0x8(%rsp),%xmm5
  ucomisd %xmm5,%xmm0
  ja     L14
  sqrtsd %xmm5,%xmm5
  movapd %xmm5,%xmm0
L38:
  cvttsd2si %xmm0,%eax
  pxor   %xmm6,%xmm6
  cvtsi2sd %eax,%xmm6
  movq   %xmm6,%rbx
  cmp    $0x2,%eax
  jle    L105
  movsd  D8(%rip),%xmm7
  movsd  %xmm7,(%rsp)
L62:
  movsd  (%rsp),%xmm1
  movsd  0x8(%rsp),%xmm0
  call   <remainder@plt>
  test   %eax,%eax
  je     L71
  movsd  (%rsp),%xmm2
  addsd  D5(%rip),%xmm2
  movsd  %xmm2,(%rsp)
  movq   %rbx,%xmm4
  comisd %xmm2,%xmm4
  jae    L62
  mov    $0x1,%eax
  jmp    L71
L14:
  movsd  0x8(%rsp),%xmm0
  call   <sqrt@plt>
  jmp    L38
L105:
  mov    $0x1,%eax
  jmp    L71
```

tool_calls: name: parse_data
arguments: data_label: D5
datatype: byte[8]
name: parse_data
arguments: data_label: D8
datatype: f64

tool: {"D5": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D8: 3

assistant: ```c
int prime(double n) {
  double sqrt(double x);
  register double d = 3;
  register rt;
  if (n < 2)
    return 0;
  if (n == 2)
    return 1;
  if (!(remainder((n), (2))))
    return 0;
  rt = sqrt(n);
  while (d <= rt) {
    if (!(remainder((n), (d))))
      return 0;
    d += 2;
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<prime>:
  endbr64
  movsd  D16(%rip),%xmm4
  comisd %xmm0,%xmm4
  ja     L86
  ucomisd %xmm4,%xmm0
  movapd %xmm0,%xmm2
  jp     L9
  jne    L9
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L9:
  push   %rbx
  movapd %xmm2,%xmm0
  sub    $0x10,%rsp
  mov    D16(%rip),%rax
  movsd  %xmm2,(%rsp)
  movq   %rax,%xmm1
  call   <remainder@plt>
  test   %eax,%eax
  jne    L75
L25:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L86:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L75:
  movsd  (%rsp),%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  movapd %xmm2,%xmm0
  ja     L59
  sqrtsd %xmm0,%xmm0
L8:
  cvttsd2si %xmm0,%eax
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm5
  movq   %xmm5,%rbx
  cmp    $0x2,%eax
  jle    L38
  movsd  D25(%rip),%xmm1
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L87:
  movsd  0x8(%rsp),%xmm1
  movq   %rbx,%xmm3
  movsd  (%rsp),%xmm2
  addsd  D16(%rip),%xmm1
  comisd %xmm1,%xmm3
  jb     L38
L69:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <remainder@plt>
  test   %eax,%eax
  jne    L87
  jmp    L25
  nopl   0x0(%rax,%rax,1)
L38:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
L59:
  movsd  %xmm2,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm2
  jmp    L8
```

tool_calls: name: parse_data
arguments: data_label: D16
datatype: byte[8]
name: parse_data
arguments: data_label: D25
datatype: f64

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D25: 3

assistant: ```c
int prime(double n) {
  double sqrt(double x);
  register double d = 3;
  register rt;
  if (n < 2)
    return 0;
  if (n == 2)
    return 1;
  if (!(remainder((n), (2))))
    return 0;
  rt = sqrt(n);
  while (d <= rt) {
    if (!(remainder((n), (d))))
      return 0;
    d += 2;
  }
  return 1;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<prime>:
  endbr64
  movsd  D7(%rip),%xmm4
  comisd %xmm0,%xmm4
  ja     L34
  ucomisd %xmm4,%xmm0
  movapd %xmm0,%xmm2
  jp     L33
  jne    L33
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L33:
  push   %rbx
  movapd %xmm2,%xmm0
  sub    $0x10,%rsp
  mov    D7(%rip),%rax
  movsd  %xmm2,(%rsp)
  movq   %rax,%xmm1
  call   <remainder@plt>
  test   %eax,%eax
  jne    L8
L11:
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  ret
  nopl   0x0(%rax,%rax,1)
L34:
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L8:
  movsd  (%rsp),%xmm2
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  movapd %xmm2,%xmm0
  ja     L15
  sqrtsd %xmm0,%xmm0
L9:
  cvttsd2si %xmm0,%eax
  pxor   %xmm5,%xmm5
  cvtsi2sd %eax,%xmm5
  movq   %xmm5,%rbx
  cmp    $0x2,%eax
  jle    L26
  movsd  D22(%rip),%xmm1
  jmp    L49
  nopw   0x0(%rax,%rax,1)
L86:
  movsd  0x8(%rsp),%xmm1
  movq   %rbx,%xmm3
  movsd  (%rsp),%xmm2
  addsd  D7(%rip),%xmm1
  comisd %xmm1,%xmm3
  jb     L26
L49:
  movapd %xmm2,%xmm0
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm2,(%rsp)
  call   <remainder@plt>
  test   %eax,%eax
  jne    L86
  jmp    L11
  nopl   0x0(%rax,%rax,1)
L26:
  add    $0x10,%rsp
  mov    $0x1,%eax
  pop    %rbx
  ret
L15:
  movsd  %xmm2,(%rsp)
  call   <sqrt@plt>
  movsd  (%rsp),%xmm2
  jmp    L9
```

tool_calls: name: disassemble_data
arguments: tag: D7
type_guessed: byte[8]
name: disassemble_data
arguments: tag: D22
type_guessed: f64

tool: {"D7": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x40]}

tool: D22: 3

assistant: ```c
int prime(double n) {
  double sqrt(double x);
  register double d = 3;
  register rt;
  if (n < 2)
    return 0;
  if (n == 2)
    return 1;
  if (!(remainder((n), (2))))
    return 0;
  rt = sqrt(n);
  while (d <= rt) {
    if (!(remainder((n), (d))))
      return 0;
    d += 2;
  }
  return 1;
}
```
user: What is the c source code of the assembly code below?

```asm
<math_clamp_float>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movss  %xmm0,-0x14(%rbp)
  movss  %xmm1,-0x18(%rbp)
  movss  %xmm2,-0x1c(%rbp)
  mov    %edi,-0x20(%rbp)
  movss  -0x14(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  cmpl   $0x1,-0x20(%rbp)
  jne    L49
  movss  -0x1c(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x4(%rbp)
  movss  -0x18(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L40
  movss  -0x18(%rbp),%xmm0
  movaps %xmm0,%xmm1
  subss  -0x8(%rbp),%xmm1
  movss  -0x1c(%rbp),%xmm0
  subss  %xmm1,%xmm0
  movd   %xmm0,%eax
  movss  -0x4(%rbp),%xmm0
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fmodf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L55
L40:
  movss  -0x8(%rbp),%xmm0
  subss  -0x18(%rbp),%xmm0
  addss  -0x18(%rbp),%xmm0
  movd   %xmm0,%eax
  movss  -0x4(%rbp),%xmm0
  movaps %xmm0,%xmm1
  movd   %eax,%xmm0
  call   <fmodf@plt>
  movd   %xmm0,%eax
  mov    %eax,-0x8(%rbp)
  jmp    L55
L49:
  movss  -0x18(%rbp),%xmm0
  comiss -0x8(%rbp),%xmm0
  jbe    L17
  movss  -0x18(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
  jmp    L55
L17:
  movss  -0x8(%rbp),%xmm0
  comiss -0x1c(%rbp),%xmm0
  jbe    L55
  movss  -0x1c(%rbp),%xmm0
  movss  %xmm0,-0x8(%rbp)
L55:
  movss  -0x8(%rbp),%xmm0
  leave
  ret
```

assistant: ```c
float math_clamp_float(const float value, const float min, const float max, const int wrap) {
  float wrapped_value = value;
  if (wrap == 1) {
    const float range = max - min;
    if (wrapped_value < min) {
      wrapped_value = fmodf(max - (min - wrapped_value), range);
    } else {
      wrapped_value = fmodf(min + (wrapped_value - min), range);
    }
  } else {
    if (wrapped_value < min) {
      wrapped_value = min;
    } else if (wrapped_value > max) {
      wrapped_value = max;
    }
  }
  return wrapped_value;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<math_clamp_float>:
  endbr64
  movaps %xmm1,%xmm3
  cmp    $0x1,%edi
  je     L12
  comiss %xmm0,%xmm1
  ja     L37
  minss  %xmm0,%xmm2
  movaps %xmm2,%xmm1
L37:
  movaps %xmm1,%xmm0
  ret
L12:
  sub    $0x8,%rsp
  movaps %xmm2,%xmm1
  subss  %xmm3,%xmm1
  comiss %xmm0,%xmm3
  jbe    L3
  subss  %xmm0,%xmm3
  subss  %xmm3,%xmm2
  movaps %xmm2,%xmm0
  call   <fmodf@plt>
  movaps %xmm0,%xmm1
L36:
  movaps %xmm1,%xmm0
  add    $0x8,%rsp
  ret
L3:
  subss  %xmm3,%xmm0
  addss  %xmm3,%xmm0
  call   <fmodf@plt>
  movaps %xmm0,%xmm1
  jmp    L36
```

assistant: ```c
float math_clamp_float(const float value, const float min, const float max, const int wrap) {
  float wrapped_value = value;
  if (wrap == 1) {
    const float range = max - min;
    if (wrapped_value < min) {
      wrapped_value = fmodf(max - (min - wrapped_value), range);
    } else {
      wrapped_value = fmodf(min + (wrapped_value - min), range);
    }
  } else {
    if (wrapped_value < min) {
      wrapped_value = min;
    } else if (wrapped_value > max) {
      wrapped_value = max;
    }
  }
  return wrapped_value;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<math_clamp_float>:
  endbr64
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm3
  cmp    $0x1,%edi
  je     L9
  comiss %xmm4,%xmm1
  movaps %xmm1,%xmm0
  jbe    L0
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  minss  %xmm4,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  comiss %xmm0,%xmm3
  movaps %xmm2,%xmm1
  subss  %xmm3,%xmm1
  jbe    L20
  subss  %xmm0,%xmm3
  subss  %xmm3,%xmm2
  movaps %xmm2,%xmm0
  jmp    1050 <fmodf@plt>
  nopl   0x0(%rax)
L20:
  subss  %xmm3,%xmm4
  addss  %xmm3,%xmm4
  movaps %xmm4,%xmm0
  jmp    1050 <fmodf@plt>
```

assistant: ```c
float math_clamp_float(const float value, const float min, const float max, const int wrap) {
  float wrapped_value = value;
  if (wrap == 1) {
    const float range = max - min;
    if (wrapped_value < min) {
      wrapped_value = fmodf(max - (min - wrapped_value), range);
    } else {
      wrapped_value = fmodf(min + (wrapped_value - min), range);
    }
  } else {
    if (wrapped_value < min) {
      wrapped_value = min;
    } else if (wrapped_value > max) {
      wrapped_value = max;
    }
  }
  return wrapped_value;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<math_clamp_float>:
  endbr64
  movaps %xmm0,%xmm4
  movaps %xmm1,%xmm3
  cmp    $0x1,%edi
  je     L27
  comiss %xmm4,%xmm1
  movaps %xmm1,%xmm0
  jbe    L17
  ret
  nopl   0x0(%rax,%rax,1)
L17:
  minss  %xmm4,%xmm2
  movaps %xmm2,%xmm0
  ret
  nopl   0x0(%rax,%rax,1)
L27:
  comiss %xmm0,%xmm3
  movaps %xmm2,%xmm1
  subss  %xmm3,%xmm1
  jbe    L8
  subss  %xmm0,%xmm3
  subss  %xmm3,%xmm2
  movaps %xmm2,%xmm0
  jmp    1050 <fmodf@plt>
  nopl   0x0(%rax)
L8:
  subss  %xmm3,%xmm4
  addss  %xmm3,%xmm4
  movaps %xmm4,%xmm0
  jmp    1050 <fmodf@plt>
```

assistant: ```c
float math_clamp_float(const float value, const float min, const float max, const int wrap) {
  float wrapped_value = value;
  if (wrap == 1) {
    const float range = max - min;
    if (wrapped_value < min) {
      wrapped_value = fmodf(max - (min - wrapped_value), range);
    } else {
      wrapped_value = fmodf(min + (wrapped_value - min), range);
    }
  } else {
    if (wrapped_value < min) {
      wrapped_value = min;
    } else if (wrapped_value > max) {
      wrapped_value = max;
    }
  }
  return wrapped_value;
}
```