ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<mrb_get_line>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  mov    %esi,%ebp
  jmp    L3
L11:
  mov    %ebp,%edi
  call   <m_putc@plt>
L3:
  mov    %rbx,%rdi
  call   <mrb_get@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  je     L21
  cmp    $0xa,%esi
  jne    L11
  mov    $0x0,%esi
  mov    %ebp,%edi
  call   <m_putc@plt>
  mov    $0x1,%eax
  jmp    L4
L21:
  mov    $0x0,%eax
L4:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mrb_get_line(struct mrb *q, int line) {
  int ch, found = 0;
  while ((ch = mrb_get(q)) != -1)
    if (ch == 10) {
      m_putc(line, 0);
      found = 1;
      break;
    } else
      m_putc(line, ch);
  return found;
}
```
user: Translate the below assembly code into C programming language:

```asm
<mrb_get_line>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L16
  nopl   0x0(%rax)
L6:
  cmp    $0xa,%esi
  je     L27
  mov    %ebp,%edi
  call   <m_putc@plt>
L16:
  mov    %rbx,%rdi
  call   <mrb_get@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  jne    L6
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L27:
  mov    %ebp,%edi
  xor    %esi,%esi
  call   <m_putc@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mrb_get_line(struct mrb *q, int line) {
  int ch, found = 0;
  while ((ch = mrb_get(q)) != -1)
    if (ch == 10) {
      m_putc(line, 0);
      found = 1;
      break;
    } else
      m_putc(line, ch);
  return found;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<mrb_get_line>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  jmp    L29
  nopl   0x0(%rax)
L7:
  cmp    $0xa,%esi
  je     L13
  mov    %ebp,%edi
  call   <m_putc@plt>
L29:
  mov    %rbx,%rdi
  call   <mrb_get@plt>
  mov    %eax,%esi
  cmp    $0xffffffff,%eax
  jne    L7
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax)
L13:
  mov    %ebp,%edi
  xor    %esi,%esi
  call   <m_putc@plt>
  add    $0x8,%rsp
  mov    $0x1,%eax
  pop    %rbx
  pop    %rbp
  ret
```

assistant: ```c
int mrb_get_line(struct mrb *q, int line) {
  int ch, found = 0;
  while ((ch = mrb_get(q)) != -1)
    if (ch == 10) {
      m_putc(line, 0);
      found = 1;
      break;
    } else
      m_putc(line, ch);
  return found;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<splitNames>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L11
L37:
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L13
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L34
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x1(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    $0x27,%al
  jne    L13
L34:
  mov    -0x8(%rbp),%eax
  lea    -0x1(%rax),%edx
  mov    -0x18(%rbp),%rcx
  mov    -0x20(%rbp),%rax
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <strncpy@plt>
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcpy@plt>
L13:
  addl   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%eax
  cmp    -0x4(%rbp),%eax
  jle    L37
  nop
  nop
  leave
  ret
```

assistant: ```c
void splitNames(char string[], char *firstName, char *lastName) {
  int i = 0, strLen = strlen(string);
  for (i = 0; i <= strLen; i++) {
    if (isupper(string[i]) && (isupper(string[i + 1]) || string[i + 1] == '\'')) {
      strncpy(firstName, string, i - 1);
      firstName[i] = '\0';
      strcpy(lastName, &string[i]);
    }
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<splitNames>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbp
  mov    %rsi,%r14
  mov    %rdx,%r15
  call   <strlen@plt>
  test   %eax,%eax
  js     L60
  mov    %eax,%r12d
  mov    $0x0,%ebx
  jmp    L68
L63:
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r13,%rsi
  mov    %r15,%rdi
  call   <strcpy@plt>
L42:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L60
L68:
  lea    0x0(%rbp,%rbx,1),%r13
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  test   %rax,%rax
  je     L42
  movsbl 0x1(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L63
  cmpb   $0x27,0x1(%rbp,%rbx,1)
  jne    L42
  jmp    L63
L60:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void splitNames(char string[], char *firstName, char *lastName) {
  int i = 0, strLen = strlen(string);
  for (i = 0; i <= strLen; i++) {
    if (isupper(string[i]) && (isupper(string[i + 1]) || string[i + 1] == '\'')) {
      strncpy(firstName, string, i - 1);
      firstName[i] = '\0';
      strcpy(lastName, &string[i]);
    }
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<splitNames>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  js     L54
  mov    %eax,%r12d
  xor    %ebx,%ebx
  jmp    L68
  nopl   0x0(%rax,%rax,1)
L33:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L54
L68:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r13
  call   <isupper@plt>
  test   %rax,%rax
  je     L33
  movsbl 0x1(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L13
  cmpb   $0x27,0x1(%rbp,%rbx,1)
  jne    L33
L13:
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x1,%rbx
  call   <strcpy@plt>
  cmp    %ebx,%r12d
  jge    L68
L54:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void splitNames(char string[], char *firstName, char *lastName) {
  int i = 0, strLen = strlen(string);
  for (i = 0; i <= strLen; i++) {
    if (isupper(string[i]) && (isupper(string[i + 1]) || string[i + 1] == '\'')) {
      strncpy(firstName, string, i - 1);
      firstName[i] = '\0';
      strcpy(lastName, &string[i]);
    }
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<splitNames>:
  endbr64
  push   %r15
  mov    %rdx,%r15
  push   %r14
  mov    %rsi,%r14
  push   %r13
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  sub    $0x8,%rsp
  call   <strlen@plt>
  test   %eax,%eax
  js     L18
  mov    %eax,%r12d
  xor    %ebx,%ebx
  jmp    L10
  nopl   0x0(%rax,%rax,1)
L50:
  add    $0x1,%rbx
  cmp    %ebx,%r12d
  jl     L18
L10:
  movsbl 0x0(%rbp,%rbx,1),%edi
  lea    0x0(%rbp,%rbx,1),%r13
  call   <isupper@plt>
  test   %rax,%rax
  je     L50
  movsbl 0x1(%rbp,%rbx,1),%edi
  call   <isupper@plt>
  test   %rax,%rax
  jne    L14
  cmpb   $0x27,0x1(%rbp,%rbx,1)
  jne    L50
L14:
  lea    -0x1(%rbx),%edx
  mov    %rbp,%rsi
  mov    %r14,%rdi
  call   <strncpy@plt>
  movb   $0x0,(%r14,%rbx,1)
  mov    %r13,%rsi
  mov    %r15,%rdi
  add    $0x1,%rbx
  call   <strcpy@plt>
  cmp    %ebx,%r12d
  jge    L10
L18:
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
```

assistant: ```c
void splitNames(char string[], char *firstName, char *lastName) {
  int i = 0, strLen = strlen(string);
  for (i = 0; i <= strLen; i++) {
    if (isupper(string[i]) && (isupper(string[i + 1]) || string[i + 1] == '\'')) {
      strncpy(firstName, string, i - 1);
      firstName[i] = '\0';
      strcpy(lastName, &string[i]);
    }
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<opentab>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %edx,-0x18(%rbp)
  cmpl   $0x72,-0x18(%rbp)
  je     L33
  cmpl   $0x77,-0x18(%rbp)
  je     L53
  jmp    L38
L33:
  mov    D10(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x10(%rbp)
  jmp    L55
L53:
  mov    D62(%rip),%rax
  mov    (%rax),%edx
  mov    D27(%rip),%rax
  mov    (%rax),%eax
  or     %eax,%edx
  mov    D50(%rip),%rax
  mov    (%rax),%eax
  or     %edx,%eax
  mov    %eax,-0x10(%rbp)
  jmp    L55
L38:
  mov    D60(%rip),%rax
  mov    (%rax),%edx
  mov    D30(%rip),%rax
  mov    %edx,(%rax)
  mov    $0xffffffff,%eax
  jmp    L9
L55:
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  mov    %eax,%edi
  call   <seteuid@plt>
  mov    -0x10(%rbp),%ecx
  mov    -0x20(%rbp),%rax
  mov    $0x1b6,%edx
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <open@plt>
  mov    %eax,-0x8(%rbp)
  mov    D30(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <seteuid@plt>
  mov    D30(%rip),%rax
  mov    -0x4(%rbp),%edx
  mov    %edx,(%rax)
  mov    -0x8(%rbp),%eax
L9:
  leave
  ret
```

assistant: ```c
int opentab(int uid, char *file, int how) {
  uid_t safe_uid;
  int flags, r, err;
  switch (how) {
  case 'r':
    flags = O_RDONLY;
    break;
  case 'w':
    flags = O_WRONLY | O_CREAT | O_TRUNC;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  safe_uid = geteuid();
  seteuid(uid);
  r = open(file, flags, 0666);
  err = errno;
  seteuid(safe_uid);
  errno = err;
  return r;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<opentab>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    %rsi,%rbx
  cmp    $0x72,%edx
  je     L7
  cmp    $0x77,%edx
  je     L9
  mov    D64(%rip),%rax
  mov    (%rax),%ebp
  mov    $0xffffffff,%ebx
  jmp    L16
L7:
  mov    D26(%rip),%rax
  mov    (%rax),%r13d
L23:
  mov    $0x0,%eax
  call   <geteuid@plt>
  mov    %eax,%r12d
  mov    %ebp,%edi
  call   <seteuid@plt>
  mov    $0x1b6,%edx
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <open@plt>
  mov    %eax,%ebx
  mov    D12(%rip),%rax
  mov    (%rax),%ebp
  mov    %r12d,%edi
  call   <seteuid@plt>
L16:
  mov    D12(%rip),%rax
  mov    %ebp,(%rax)
  mov    %ebx,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L9:
  mov    D13(%rip),%rax
  mov    (%rax),%r13d
  mov    D42(%rip),%rax
  or     (%rax),%r13d
  mov    D0(%rip),%rax
  or     (%rax),%r13d
  jmp    L23
```

assistant: ```c
int opentab(int uid, char *file, int how) {
  uid_t safe_uid;
  int flags, r, err;
  switch (how) {
  case 'r':
    flags = O_RDONLY;
    break;
  case 'w':
    flags = O_WRONLY | O_CREAT | O_TRUNC;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  safe_uid = geteuid();
  seteuid(uid);
  r = open(file, flags, 0666);
  err = errno;
  seteuid(safe_uid);
  errno = err;
  return r;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<opentab>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x72,%edx
  je     L1
  cmp    $0x77,%edx
  je     L16
  mov    D22(%rip),%rax
  mov    D27(%rip),%rbx
  mov    $0xffffffff,%r12d
  mov    (%rax),%r13d
  mov    %r12d,%eax
  mov    %r13d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L1:
  mov    D6(%rip),%rax
  mov    (%rax),%r12d
L6:
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %r14d,%edi
  mov    %eax,%ebp
  call   <seteuid@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x1b6,%edx
  call   <open@plt>
  mov    D27(%rip),%rbx
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    (%rbx),%r13d
  call   <seteuid@plt>
  mov    %r12d,%eax
  mov    %r13d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L16:
  mov    D39(%rip),%rax
  mov    (%rax),%r12d
  mov    D5(%rip),%rax
  or     (%rax),%r12d
  mov    D52(%rip),%rax
  or     (%rax),%r12d
  jmp    L6
```

assistant: ```c
int opentab(int uid, char *file, int how) {
  uid_t safe_uid;
  int flags, r, err;
  switch (how) {
  case 'r':
    flags = O_RDONLY;
    break;
  case 'w':
    flags = O_WRONLY | O_CREAT | O_TRUNC;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  safe_uid = geteuid();
  seteuid(uid);
  r = open(file, flags, 0666);
  err = errno;
  seteuid(safe_uid);
  errno = err;
  return r;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<opentab>:
  endbr64
  push   %r14
  mov    %edi,%r14d
  push   %r13
  mov    %rsi,%r13
  push   %r12
  push   %rbp
  push   %rbx
  cmp    $0x72,%edx
  je     L23
  cmp    $0x77,%edx
  je     L12
  mov    D66(%rip),%rax
  mov    D41(%rip),%rbx
  mov    $0xffffffff,%r12d
  mov    (%rax),%r13d
  mov    %r12d,%eax
  mov    %r13d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  cs nopw 0x0(%rax,%rax,1)
L23:
  mov    D46(%rip),%rax
  mov    (%rax),%r12d
L13:
  xor    %eax,%eax
  call   <geteuid@plt>
  mov    %r14d,%edi
  mov    %eax,%ebp
  call   <seteuid@plt>
  mov    %r12d,%esi
  mov    %r13,%rdi
  mov    $0x1b6,%edx
  call   <open@plt>
  mov    D41(%rip),%rbx
  mov    %ebp,%edi
  mov    %eax,%r12d
  mov    (%rbx),%r13d
  call   <seteuid@plt>
  mov    %r12d,%eax
  mov    %r13d,(%rbx)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  xchg   %ax,%ax
L12:
  mov    D56(%rip),%rax
  mov    (%rax),%r12d
  mov    D14(%rip),%rax
  or     (%rax),%r12d
  mov    D60(%rip),%rax
  or     (%rax),%r12d
  jmp    L13
```

assistant: ```c
int opentab(int uid, char *file, int how) {
  uid_t safe_uid;
  int flags, r, err;
  switch (how) {
  case 'r':
    flags = O_RDONLY;
    break;
  case 'w':
    flags = O_WRONLY | O_CREAT | O_TRUNC;
    break;
  default:
    errno = EINVAL;
    return -1;
  }
  safe_uid = geteuid();
  seteuid(uid);
  r = open(file, flags, 0666);
  err = errno;
  seteuid(safe_uid);
  errno = err;
  return r;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<wrong3>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L4
L19:
  mov    -0x4(%rbp),%eax
  mov    $0x0,%esi
  mov    %eax,%edi
  call   <work@plt>
  addl   $0x1,-0x4(%rbp)
L4:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L19
  nop
  nop
  leave
  ret
```

assistant: ```c
void wrong3(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
#pragma omp single
      work(i, 0);
    }
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<wrong3>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %edi,%ebp
  mov    $0x0,%ebx
L7:
  mov    $0x0,%esi
  mov    %ebx,%edi
  call   <work@plt>
  add    $0x1,%ebx
  cmp    %ebx,%ebp
  jne    L7
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  ret
```

assistant: ```c
void wrong3(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
#pragma omp single
      work(i, 0);
    }
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<wrong3>:
  endbr64
  test   %edi,%edi
  jle    L3
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L17:
  mov    %ebx,%edi
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <work@plt>
  cmp    %ebx,%ebp
  jne    L17
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L3:
  ret
```

assistant: ```c
void wrong3(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
#pragma omp single
      work(i, 0);
    }
  }
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<wrong3>:
  endbr64
  test   %edi,%edi
  jle    L8
  push   %rbp
  mov    %edi,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopw   0x0(%rax,%rax,1)
L10:
  mov    %ebx,%edi
  xor    %esi,%esi
  add    $0x1,%ebx
  call   <work@plt>
  cmp    %ebx,%ebp
  jne    L10
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nop
L8:
  ret
```

assistant: ```c
void wrong3(int n) {
#pragma omp parallel default(shared)
  {
    int i;
#pragma omp for
    for (i = 0; i < n; i++) {
#pragma omp single
      work(i, 0);
    }
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<fig07_10>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x6574436152614863,%rax
  movabs $0x2420646e61207372,%rdx
  mov    %rax,-0x20(%rbp)
  mov    %rdx,-0x18(%rbp)
  movl   $0x392e3233,-0x10(%rbp)
  movw   $0x38,-0xc(%rbp)
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rdi
  call   <convertToUppercase@plt>
  lea    -0x20(%rbp),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D13
type_guessed: string
name: retrieve_data
arguments: data_label: D15
type_guessed: string

tool: D13: The string before conversion is: %s

tool: D15: 
The string after conversion is: %s


assistant: ```c
void fig07_10() {
  char string[] = "cHaRaCters and $32.98";
  printf("The string before conversion is: %s", string);
  convertToUppercase(string);
  printf("\nThe string after conversion is: %s\n", string);
}
```
user: Translate the below assembly code into C programming language:

```asm
<fig07_10>:
  endbr64
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movabs $0x6574436152614863,%rax
  movabs $0x2420646e61207372,%rdx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movl   $0x392e3233,0x10(%rsp)
  movw   $0x38,0x14(%rsp)
  mov    %rsp,%rbx
  mov    %rbx,%rsi
  lea    D7(%rip),%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <convertToUppercase@plt>
  mov    %rbx,%rsi
  lea    D17(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbx
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D7
data_type: string
name: extract_symbolic_data
arguments: label: D17
data_type: string

tool: D7: The string before conversion is: %s

tool: D17: 
The string after conversion is: %s


assistant: ```c
void fig07_10() {
  char string[] = "cHaRaCters and $32.98";
  printf("The string before conversion is: %s", string);
  convertToUppercase(string);
  printf("\nThe string after conversion is: %s\n", string);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<fig07_10>:
  endbr64
  push   %rbp
  lea    D13(%rip),%rdi
  sub    $0x20,%rsp
  movdqa D4(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x38,%eax
  movl   $0x392e3233,0x10(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  mov    %ax,0x14(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <convertToUppercase@plt>
  mov    %rbp,%rsi
  lea    D21(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L6
  add    $0x20,%rsp
  pop    %rbp
  ret
L6:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D13
datatype: string
name: extract_symbolic_data
arguments: data_label: D4
datatype: byte[16]
name: extract_symbolic_data
arguments: data_label: D21
datatype: string

tool: D13: The string before conversion is: %s

tool: {"D4": [0x63,0x48,0x61,0x52,0x61,0x43,0x74,0x65,0x72,0x73,0x20,0x61,0x6e,0x64,0x20,0x24]}

tool: D21: 
The string after conversion is: %s


assistant: ```c
void fig07_10() {
  char string[] = "cHaRaCters and $32.98";
  printf("The string before conversion is: %s", string);
  convertToUppercase(string);
  printf("\nThe string after conversion is: %s\n", string);
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<fig07_10>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  sub    $0x20,%rsp
  movdqa D29(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  mov    $0x38,%eax
  movl   $0x392e3233,0x10(%rsp)
  mov    %rbp,%rsi
  movaps %xmm0,(%rsp)
  mov    %ax,0x14(%rsp)
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <convertToUppercase@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0x20,%rsp
  pop    %rbp
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D16
type: string
name: retrieve_data
arguments: data_tag: D29
type: byte[16]
name: retrieve_data
arguments: data_tag: D10
type: string

tool: D16: The string before conversion is: %s

tool: {"D29": [0x63,0x48,0x61,0x52,0x61,0x43,0x74,0x65,0x72,0x73,0x20,0x61,0x6e,0x64,0x20,0x24]}

tool: D10: 
The string after conversion is: %s


assistant: ```c
void fig07_10() {
  char string[] = "cHaRaCters and $32.98";
  printf("The string before conversion is: %s", string);
  convertToUppercase(string);
  printf("\nThe string after conversion is: %s\n", string);
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<scan_quote>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,-0x4(%rbp)
  addq   $0x1,-0x20(%rbp)
  jmp    L69
L49:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  movzbl %al,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  and    $0x20,%eax
  test   %eax,%eax
  je     L11
  addq   $0x1,-0x20(%rbp)
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  movzbl %al,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  and    $0x8,%eax
  test   %eax,%eax
  je     L11
  mov    -0x20(%rbp),%rax
  jmp    L3
L11:
  addq   $0x1,-0x20(%rbp)
L69:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbq %al,%rax
  movzbl %al,%eax
  lea    (%rax,%rax,1),%rdx
  mov    -0x18(%rbp),%rax
  mov    (%rax),%rax
  add    %rdx,%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  and    $0x8,%eax
  test   %eax,%eax
  jne    L22
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L49
L22:
  mov    -0x20(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  cmp    %eax,-0x4(%rbp)
  jne    L29
  addq   $0x1,-0x20(%rbp)
L29:
  mov    -0x20(%rbp),%rax
L3:
  pop    %rbp
  ret
```

assistant: ```c
char *scan_quote(CONF *conf, char *p) {
  int q = *p;
  p++;
  while (!((((unsigned short *)((conf)->meth_data))[(*p) & 0xff] & 8)) && (*p != q)) {
    if ((((unsigned short *)((conf)->meth_data))[(*p) & 0xff] & 32)) {
      p++;
      if ((((unsigned short *)((conf)->meth_data))[(*p) & 0xff] & 8))
        return (p);
    }
    p++;
  }
  if (*p == q)
    p++;
  return (p);
}
```