ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<imcomm_simplify_sn>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  mov    $0x0,%ebx
  mov    $0x0,%r13d
  jmp    L22
L17:
  add    $0x1,%rbx
L22:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jle    L27
  movzbl (%r12,%rbx,1),%edi
  cmp    $0x20,%dil
  je     L17
  movslq %r13d,%rbp
  add    %r14,%rbp
  movsbl %dil,%edi
  call   <tolower@plt>
  mov    %al,0x0(%rbp)
  add    $0x1,%r13d
  jmp    L17
L27:
  lea    0x1(%r13),%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  movslq %r13d,%r13
  movb   $0x0,(%rax,%r13,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *imcomm_simplify_sn(const char *sn) {
  char *temp;
  int x, count;
  temp = malloc(strlen(sn) + 1);
  for (x = 0, count = 0; x < (int)strlen(sn); x++) {
    if (sn[x] == ' ')
      continue;
    temp[count] = tolower(sn[x]);
    count++;
  }
  temp = realloc(temp, count + 1);
  temp[count] = 0;
  return temp;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<imcomm_simplify_sn>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  jmp    L25
  nopl   0x0(%rax)
L9:
  movsbl (%r12,%rbx,1),%edi
  cmp    $0x20,%dil
  je     L6
  call   <tolower@plt>
  add    %r14,%rbp
  mov    %al,0x0(%rbp)
  movslq %r13d,%rbp
  add    $0x1,%r13d
L6:
  add    $0x1,%rbx
L25:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L9
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  movb   $0x0,(%rax,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *imcomm_simplify_sn(const char *sn) {
  char *temp;
  int x, count;
  temp = malloc(strlen(sn) + 1);
  for (x = 0, count = 0; x < (int)strlen(sn); x++) {
    if (sn[x] == ' ')
      continue;
    temp[count] = tolower(sn[x]);
    count++;
  }
  temp = realloc(temp, count + 1);
  temp[count] = 0;
  return temp;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<imcomm_simplify_sn>:
  endbr64
  push   %r14
  push   %r13
  mov    $0x1,%r13d
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  xor    %ebp,%ebp
  push   %rbx
  xor    %ebx,%ebx
  call   <strlen@plt>
  lea    0x1(%rax),%rdi
  call   <malloc@plt>
  mov    %rax,%r14
  jmp    L19
  nopl   0x0(%rax)
L5:
  movsbl (%r12,%rbx,1),%edi
  cmp    $0x20,%dil
  je     L15
  call   <tolower@plt>
  add    %r14,%rbp
  mov    %al,0x0(%rbp)
  movslq %r13d,%rbp
  add    $0x1,%r13d
L15:
  add    $0x1,%rbx
L19:
  mov    %r12,%rdi
  call   <strlen@plt>
  cmp    %ebx,%eax
  jg     L5
  mov    %r13d,%esi
  mov    %r14,%rdi
  call   <realloc@plt>
  movb   $0x0,(%rax,%rbp,1)
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
char *imcomm_simplify_sn(const char *sn) {
  char *temp;
  int x, count;
  temp = malloc(strlen(sn) + 1);
  for (x = 0, count = 0; x < (int)strlen(sn); x++) {
    if (sn[x] == ' ')
      continue;
    temp[count] = tolower(sn[x]);
    count++;
  }
  temp = realloc(temp, count + 1);
  temp[count] = 0;
  return temp;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<inet_print_iphdr>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  add    $0x4,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,%edx
  lea    D8(%rip),%rax
  mov    %rax,%rsi
  mov    $0x8,%edi
  call   <jlog@plt>
  nop
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: label: D8
data_type: string

tool: D8: inet]> iphdr len: %i

assistant: ```c
void inet_print_iphdr(void *data) {
  struct ip *iph;
  iph = data + sizeof(struct ether_header);
  jlog(0x08, "inet]> iphdr len: %i", iph->ip_len);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<inet_print_iphdr>:
  endbr64
  sub    $0x8,%rsp
  mov    0x4(%rdi),%edx
  lea    D4(%rip),%rsi
  mov    $0x8,%edi
  call   <jlog@plt>
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: data_tag: D4
type: string

tool: D4: inet]> iphdr len: %i

assistant: ```c
void inet_print_iphdr(void *data) {
  struct ip *iph;
  iph = data + sizeof(struct ether_header);
  jlog(0x08, "inet]> iphdr len: %i", iph->ip_len);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<inet_print_iphdr>:
  endbr64
  mov    0x4(%rdi),%edx
  lea    D5(%rip),%rsi
  mov    $0x8,%edi
  jmp    1050 <jlog@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D5
type: string

tool: D5: inet]> iphdr len: %i

assistant: ```c
void inet_print_iphdr(void *data) {
  struct ip *iph;
  iph = data + sizeof(struct ether_header);
  jlog(0x08, "inet]> iphdr len: %i", iph->ip_len);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<inet_print_iphdr>:
  endbr64
  mov    0x4(%rdi),%edx
  lea    D6(%rip),%rsi
  mov    $0x8,%edi
  jmp    1050 <jlog@plt>
```

tool_calls: name: parse_data
arguments: data_label: D6
type_infered: string

tool: D6: inet]> iphdr len: %i

assistant: ```c
void inet_print_iphdr(void *data) {
  struct ip *iph;
  iph = data + sizeof(struct ether_header);
  jlog(0x08, "inet]> iphdr len: %i", iph->ip_len);
}
```
user: What is the c source code of the assembly code below?

```asm
<strend>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  jmp    L55
L17:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L35
  addq   $0x1,-0x8(%rbp)
L55:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jne    L17
  jmp    L58
L35:
  nop
  jmp    L58
L14:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L72
  addq   $0x1,-0x8(%rbp)
  addq   $0x1,-0x10(%rbp)
L58:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  je     L14
  jmp    L30
L72:
  nop
L30:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L52
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  je     L7
L52:
  mov    $0x0,%eax
  jmp    L93
L7:
  mov    $0x1,%eax
L93:
  pop    %rbp
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  for (; *s != *t; s++)
    if (*s == '\0')
      break;
  for (; *s == *t; s++, t++)
    if (*t == '\0')
      break;
  if (*s || *t)
    return 0;
  else
    return 1;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<strend>:
  endbr64
  movzbl (%rdi),%edx
  movzbl (%rsi),%eax
  test   %dl,%dl
  je     L19
  cmp    %al,%dl
  je     L19
L22:
  add    $0x1,%rdi
  movzbl (%rdi),%edx
  cmp    %al,%dl
  je     L19
  test   %dl,%dl
  jne    L22
L19:
  movzbl (%rdi),%ecx
  test   %al,%al
  je     L24
  cmp    %al,%cl
  jne    L24
  mov    $0x1,%edx
L49:
  movzbl (%rdi,%rdx,1),%ecx
  movzbl (%rsi,%rdx,1),%eax
  add    $0x1,%rdx
  test   %al,%al
  je     L24
  cmp    %al,%cl
  je     L49
L24:
  or     %al,%cl
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  for (; *s != *t; s++)
    if (*s == '\0')
      break;
  for (; *s == *t; s++, t++)
    if (*t == '\0')
      break;
  if (*s || *t)
    return 0;
  else
    return 1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<strend>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  test   %al,%al
  jne    L41
  jmp    L53
L74:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L53
L41:
  cmp    %al,%dl
  jne    L74
L85:
  mov    %eax,%ecx
  mov    $0x1,%edx
  jmp    L34
  nopl   0x0(%rax)
L73:
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jne    L47
L34:
  test   %cl,%cl
  jne    L73
L1:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L53:
  cmp    %al,%dl
  je     L85
  or     %edx,%eax
  jmp    L1
  nopl   0x0(%rax,%rax,1)
L47:
  or     %ecx,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  for (; *s != *t; s++)
    if (*s == '\0')
      break;
  for (; *s == *t; s++, t++)
    if (*t == '\0')
      break;
  if (*s || *t)
    return 0;
  else
    return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<strend>:
  endbr64
  movzbl (%rdi),%eax
  movzbl (%rsi),%edx
  test   %al,%al
  jne    L4
  jmp    L8
L77:
  movzbl 0x1(%rdi),%eax
  add    $0x1,%rdi
  test   %al,%al
  je     L8
L4:
  cmp    %al,%dl
  jne    L77
L22:
  mov    %eax,%ecx
  mov    $0x1,%edx
  jmp    L55
  nopl   0x0(%rax)
L47:
  movzbl (%rdi,%rdx,1),%eax
  add    $0x1,%rdx
  movzbl -0x1(%rsi,%rdx,1),%ecx
  cmp    %cl,%al
  jne    L85
L55:
  test   %cl,%cl
  jne    L47
L59:
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
  xchg   %ax,%ax
L8:
  cmp    %al,%dl
  je     L22
  or     %edx,%eax
  jmp    L59
  nopl   0x0(%rax,%rax,1)
L85:
  or     %ecx,%eax
  test   %al,%al
  sete   %al
  movzbl %al,%eax
  ret
```

assistant: ```c
int strend(char *s, char *t) {
  for (; *s != *t; s++)
    if (*s == '\0')
      break;
  for (; *s == *t; s++, t++)
    if (*t == '\0')
      break;
  if (*s || *t)
    return 0;
  else
    return 1;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<uart_write_chars>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  movq   $0x0,-0x8(%rbp)
  jmp    L13
L15:
  mov    -0x18(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    %eax,%edi
  call   <uart_write_char@plt>
  addq   $0x1,-0x8(%rbp)
L13:
  mov    -0x8(%rbp),%rax
  cmp    -0x20(%rbp),%rax
  jb     L15
  nop
  nop
  leave
  ret
```

assistant: ```c
void uart_write_chars(const unsigned char *buffer, size_t size) {
  for (size_t i = 0; i < size; i++) {
    uart_write_char(buffer[i]);
  }
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<uart_write_chars>:
  endbr64
  test   %rsi,%rsi
  je     L15
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    %rdi,%rbx
  lea    (%rdi,%rsi,1),%rbp
L3:
  movzbl (%rbx),%edi
  call   <uart_write_char@plt>
  add    $0x1,%rbx
  cmp    %rbp,%rbx
  jne    L3
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L15:
  ret
```

assistant: ```c
void uart_write_chars(const unsigned char *buffer, size_t size) {
  for (size_t i = 0; i < size; i++) {
    uart_write_char(buffer[i]);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<uart_write_chars>:
  endbr64
  test   %rsi,%rsi
  je     L16
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L19:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  call   <uart_write_char@plt>
  cmp    %rbp,%rbx
  jne    L19
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L16:
  ret
```

assistant: ```c
void uart_write_chars(const unsigned char *buffer, size_t size) {
  for (size_t i = 0; i < size; i++) {
    uart_write_char(buffer[i]);
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uart_write_chars>:
  endbr64
  test   %rsi,%rsi
  je     L15
  push   %rbp
  lea    (%rdi,%rsi,1),%rbp
  push   %rbx
  mov    %rdi,%rbx
  sub    $0x8,%rsp
  cs nopw 0x0(%rax,%rax,1)
L13:
  movzbl (%rbx),%edi
  add    $0x1,%rbx
  call   <uart_write_char@plt>
  cmp    %rbp,%rbx
  jne    L13
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
  nopl   0x0(%rax,%rax,1)
L15:
  ret
```

assistant: ```c
void uart_write_chars(const unsigned char *buffer, size_t size) {
  for (size_t i = 0; i < size; i++) {
    uart_write_char(buffer[i]);
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<even_old_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  push   %r12
  push   %rbx
  sub    $0x18,%rsp
  mov    %rdi,%rbx
  mov    %esi,%r13d
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rcx
  and    $0xfffffffffffffff0,%rcx
  and    $0xfffffffffffff000,%rax
  mov    %rsp,%rdx
  sub    %rax,%rdx
L65:
  cmp    %rdx,%rsp
  je     L59
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  jmp    L65
L59:
  mov    %rcx,%rax
  and    $0xfff,%eax
  sub    %rax,%rsp
  test   %rax,%rax
  je     L123
  orq    $0x0,-0x8(%rsp,%rax,1)
L123:
  mov    %rsp,%r12
  mov    %r13d,%esi
  mov    %rbx,%rdi
  call   <select_sort@plt>
  test   %r13d,%r13d
  jle    L10
  mov    %rbx,%rdx
  lea    -0x1(%r13),%eax
  lea    0x4(%rbx,%rax,4),%rdi
  mov    %rbx,%rax
  mov    %r12,%rcx
  jmp    L19
L18:
  add    $0x4,%rax
  cmp    %rdi,%rax
  je     L16
L19:
  mov    (%rax),%esi
  test   $0x1,%sil
  je     L18
  mov    %esi,(%rcx)
  add    $0x4,%rcx
  jmp    L18
L49:
  add    $0x4,%rdx
  cmp    %rdi,%rdx
  je     L120
L16:
  mov    (%rdx),%eax
  test   $0x1,%al
  jne    L49
  mov    %eax,(%rcx)
  add    $0x4,%rcx
  jmp    L49
L120:
  mov    %r13d,%r13d
  mov    $0x0,%eax
L101:
  mov    (%r12,%rax,4),%edx
  mov    %edx,(%rbx,%rax,4)
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L101
L10:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L35
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L35:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void even_old_sort(int *p, int size) {
  int temp[size];
  int *q = temp;
  int i;
  select_sort(p, size);
  for (i = 0; i < size; i++) {
    if (p[i] % 2 != 0) {
      *q = p[i];
      q++;
    }
  }
  for (i = 0; i < size; i++) {
    if (p[i] % 2 == 0) {
      *q = p[i];
      q++;
    }
  }
  q = temp;
  for (i = 0; i < size; i++) {
    p[i] = q[i];
  }
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<even_old_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L71
L89:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L89
L71:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L66
L63:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %rsp,%r12
  call   <select_sort@plt>
  test   %ebx,%ebx
  jle    L60
  lea    -0x1(%rbx),%eax
  mov    %r13,%rcx
  mov    %r12,%rsi
  lea    0x4(%r13,%rax,4),%r8
  mov    %r13,%rax
  nopl   0x0(%rax)
L92:
  mov    (%rax),%edi
  test   $0x1,%dil
  je     L98
  mov    %edi,(%rsi)
  add    $0x4,%rsi
L98:
  add    $0x4,%rax
  cmp    %r8,%rax
  jne    L92
  nop
L84:
  mov    (%rcx),%eax
  test   $0x1,%al
  jne    L6
  mov    %eax,(%rsi)
  add    $0x4,%rsi
L6:
  add    $0x4,%rcx
  cmp    %r8,%rcx
  jne    L84
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L60:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L33
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L66:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L63
L33:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void even_old_sort(int *p, int size) {
  int temp[size];
  int *q = temp;
  int i;
  select_sort(p, size);
  for (i = 0; i < size; i++) {
    if (p[i] % 2 != 0) {
      *q = p[i];
      q++;
    }
  }
  for (i = 0; i < size; i++) {
    if (p[i] % 2 == 0) {
      *q = p[i];
      q++;
    }
  }
  q = temp;
  for (i = 0; i < size; i++) {
    p[i] = q[i];
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<even_old_sort>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %r13
  mov    %rdi,%r13
  push   %r12
  push   %rbx
  mov    %esi,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x28(%rbp)
  xor    %eax,%eax
  movslq %esi,%rax
  mov    %rsp,%rcx
  lea    0xf(,%rax,4),%rax
  mov    %rax,%rdx
  and    $0xfffffffffffff000,%rax
  sub    %rax,%rcx
  and    $0xfffffffffffffff0,%rdx
  cmp    %rcx,%rsp
  je     L85
L54:
  sub    $0x1000,%rsp
  orq    $0x0,0xff8(%rsp)
  cmp    %rcx,%rsp
  jne    L54
L85:
  and    $0xfff,%edx
  sub    %rdx,%rsp
  test   %rdx,%rdx
  jne    L87
L37:
  mov    %ebx,%esi
  mov    %r13,%rdi
  mov    %rsp,%r12
  call   <select_sort@plt>
  test   %ebx,%ebx
  jle    L72
  lea    -0x1(%rbx),%eax
  mov    %r13,%rcx
  mov    %r12,%rsi
  lea    0x4(%r13,%rax,4),%r8
  mov    %r13,%rax
  nopl   0x0(%rax)
L89:
  mov    (%rax),%edi
  test   $0x1,%dil
  je     L3
  mov    %edi,(%rsi)
  add    $0x4,%rsi
L3:
  add    $0x4,%rax
  cmp    %rax,%r8
  jne    L89
  nop
L82:
  mov    (%rcx),%eax
  test   $0x1,%al
  jne    L73
  mov    %eax,(%rsi)
  add    $0x4,%rsi
L73:
  add    $0x4,%rcx
  cmp    %rcx,%r8
  jne    L82
  mov    %ebx,%edx
  mov    %r12,%rsi
  mov    %r13,%rdi
  shl    $0x2,%rdx
  call   <memcpy@plt>
L72:
  mov    -0x28(%rbp),%rax
  sub    %fs:0x28,%rax
  jne    L81
  lea    -0x18(%rbp),%rsp
  pop    %rbx
  pop    %r12
  pop    %r13
  pop    %rbp
  ret
L87:
  orq    $0x0,-0x8(%rsp,%rdx,1)
  jmp    L37
L81:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void even_old_sort(int *p, int size) {
  int temp[size];
  int *q = temp;
  int i;
  select_sort(p, size);
  for (i = 0; i < size; i++) {
    if (p[i] % 2 != 0) {
      *q = p[i];
      q++;
    }
  }
  for (i = 0; i < size; i++) {
    if (p[i] % 2 == 0) {
      *q = p[i];
      q++;
    }
  }
  q = temp;
  for (i = 0; i < size; i++) {
    p[i] = q[i];
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %edi,-0x14(%rbp)
  mov    %rsi,-0x20(%rbp)
  cmpl   $0x1,-0x14(%rbp)
  jg     L6
  mov    -0x20(%rbp),%rax
  mov    (%rax),%rax
  mov    %rax,%rsi
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L6:
  mov    -0x20(%rbp),%rax
  mov    0x8(%rax),%rax
  mov    %rax,-0x10(%rbp)
  mov    -0x20(%rbp),%rax
  mov    0x10(%rax),%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <fs_server_1@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D3
type_infered: string

tool: D3: usage: %s server_host remote_file


assistant: ```c
int main(int argc, char *argv[]) {
  char *host;
  char *remote;
  if (argc < 2) {
    printf("usage: %s server_host remote_file\n", argv[0]);
    exit(1);
  }
  host = argv[1];
  remote = argv[2];
  fs_server_1(host, remote);
  exit(0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L19
L4:
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <fs_server_1@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  pop    %rbx
  ret
L19:
  mov    (%rsi),%rsi
  lea    D1(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L4
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D1
data_type: string

tool: D1: usage: %s server_host remote_file


assistant: ```c
int main(int argc, char *argv[]) {
  char *host;
  char *remote;
  if (argc < 2) {
    printf("usage: %s server_host remote_file\n", argv[0]);
    exit(1);
  }
  host = argv[1];
  remote = argv[2];
  fs_server_1(host, remote);
  exit(0);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L3
L2:
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <fs_server_1@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L3:
  mov    (%rsi),%rsi
  lea    D0(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: parse_data
arguments: label: D0
data_type: string

tool: D0: usage: %s server_host remote_file


assistant: ```c
int main(int argc, char *argv[]) {
  char *host;
  char *remote;
  if (argc < 2) {
    printf("usage: %s server_host remote_file\n", argv[0]);
    exit(1);
  }
  host = argv[1];
  remote = argv[2];
  fs_server_1(host, remote);
  exit(0);
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbx
  mov    %rsi,%rbx
  cmp    $0x1,%edi
  jle    L16
L2:
  mov    0x10(%rbx),%rsi
  mov    0x8(%rbx),%rdi
  call   <fs_server_1@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  pop    %rbx
  ret
L16:
  mov    (%rsi),%rsi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
  jmp    L2
```

tool_calls: name: read_data
arguments: tag: D6
data_type: string

tool: D6: usage: %s server_host remote_file


assistant: ```c
int main(int argc, char *argv[]) {
  char *host;
  char *remote;
  if (argc < 2) {
    printf("usage: %s server_host remote_file\n", argv[0]);
    exit(1);
  }
  host = argv[1];
  remote = argv[2];
  fs_server_1(host, remote);
  exit(0);
}
```
user: What is the c source code of the assembly code below:

```asm
<ldiv>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    -0x18(%rbp),%rax
  cqto
  idivq  -0x20(%rbp)
  mov    %rax,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  imul   -0x20(%rbp),%rax
  mov    %rax,%rdx
  mov    -0x18(%rbp),%rax
  sub    %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x10(%rbp),%rax
  mov    -0x8(%rbp),%rdx
  pop    %rbp
  ret
```

assistant: ```c
ldiv_t ldiv(long numerator, long denominator) {
  ldiv_t x;
  x.quot = numerator / denominator;
  x.rem = numerator - x.quot * denominator;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
ldiv_t ldiv(long numerator, long denominator) {
  ldiv_t x;
  x.quot = numerator / denominator;
  x.rem = numerator - x.quot * denominator;
  return x;
}
```
user: Translate the below assembly code into C programming language:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
ldiv_t ldiv(long numerator, long denominator) {
  ldiv_t x;
  x.quot = numerator / denominator;
  x.rem = numerator - x.quot * denominator;
  return x;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<ldiv>:
  endbr64
  mov    %rdi,%rax
  cqto
  idiv   %rsi
  ret
```

assistant: ```c
ldiv_t ldiv(long numerator, long denominator) {
  ldiv_t x;
  x.quot = numerator / denominator;
  x.rem = numerator - x.quot * denominator;
  return x;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<thread_main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  mov    $0x400,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
void *thread_main(void *arg) {
  int *ptr;
  ptr = malloc(1024);
  memset(ptr, 5, 1024);
  sleep(1);
  return NULL;
}
```
user: What is the c source code of the assembly code below:

```asm
<thread_main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    %rax,%rdi
  mov    $0x400,%edx
  mov    $0x5,%esi
  call   <memset@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_main(void *arg) {
  int *ptr;
  ptr = malloc(1024);
  memset(ptr, 5, 1024);
  sleep(1);
  return NULL;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<thread_main>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x400,%edi
  call   <malloc@plt>
  mov    $0x400,%edx
  mov    $0x5,%esi
  mov    %rax,%rdi
  call   <memset@plt>
  mov    $0x1,%edi
  call   <sleep@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
void *thread_main(void *arg) {
  int *ptr;
  ptr = malloc(1024);
  memset(ptr, 5, 1024);
  sleep(1);
  return NULL;
}
```