ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  lea    D11(%rip),%rdi
  call   <puts@plt>
  mov    %rsp,%rbx
  mov    $0x64,%esi
  mov    %rbx,%rdi
  call   <getline@plt>
  lea    D4(%rip),%rdi
  call   <puts@plt>
  lea    0x70(%rsp),%rbp
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <getline@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <strcaat@plt>
  mov    %rbx,%rsi
  lea    D0(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  call   <getchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L3
  mov    $0x0,%eax
  add    $0xe8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L3:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D11
datatype: string
name: unpack_data
arguments: label: D4
datatype: string
name: unpack_data
arguments: label: D0
datatype: string

tool: D11: Enter first string

tool: D4: Enter second string

tool: D0: %s

assistant: ```c
int main() {
  char a[100];
  char b[100];
  printf("Enter first string\n");
  getline(a, 100);
  printf("Enter second string\n");
  getline(b, 100);
  strcaat(a, b);
  printf("%s", a);
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D1(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <getline@plt>
  lea    D12(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcaat@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L2
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L2:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D1
type: string
name: retrieve_data
arguments: tag: D12
type: string
name: retrieve_data
arguments: tag: D15
type: string

tool: D1: Enter first string

tool: D12: Enter second string

tool: D15: %s

assistant: ```c
int main() {
  char a[100];
  char b[100];
  printf("Enter first string\n");
  getline(a, 100);
  printf("Enter second string\n");
  getline(b, 100);
  strcaat(a, b);
  printf("%s", a);
  getchar();
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D9(%rip),%rdi
  push   %rbp
  sub    $0xe8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0xd8(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  lea    0x70(%rsp),%r12
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %rbp,%rdi
  call   <getline@plt>
  lea    D24(%rip),%rdi
  call   <puts@plt>
  mov    $0x64,%esi
  mov    %r12,%rdi
  call   <getline@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <strcaat@plt>
  xor    %eax,%eax
  mov    %rbp,%rsi
  lea    D20(%rip),%rdi
  call   <printf@plt>
  xor    %eax,%eax
  call   <getchar@plt>
  mov    0xd8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0xe8,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D9
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D24
type_guessed: string
name: extract_symbolic_data
arguments: data_tag: D20
type_guessed: string

tool: D9: Enter first string

tool: D24: Enter second string

tool: D20: %s

assistant: ```c
int main() {
  char a[100];
  char b[100];
  printf("Enter first string\n");
  getline(a, 100);
  printf("Enter second string\n");
  getline(b, 100);
  strcaat(a, b);
  printf("%s", a);
  getchar();
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<uu_decode_word24>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movl   $0x0,-0x10(%rbp)
  jmp    L11
L29:
  mov    -0x10(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <uu_decode_char8@plt>
  mov    -0x10(%rbp),%edx
  movslq %edx,%rdx
  mov    %al,-0xc(%rbp,%rdx,1)
  addl   $0x1,-0x10(%rbp)
L11:
  cmpl   $0x3,-0x10(%rbp)
  jle    L29
  movzbl -0xc(%rbp),%eax
  movsbl %al,%eax
  shl    $0x2,%eax
  mov    %eax,%edx
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  sar    $0x4,%eax
  and    $0x3,%eax
  add    %edx,%eax
  mov    %eax,%edx
  mov    -0x18(%rbp),%rax
  mov    %dl,(%rax)
  movzbl -0xb(%rbp),%eax
  movsbl %al,%eax
  shl    $0x4,%eax
  mov    %eax,%edx
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  sar    $0x2,%eax
  and    $0xf,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  movzbl -0xa(%rbp),%eax
  movsbl %al,%eax
  shl    $0x6,%eax
  mov    %eax,%edx
  movzbl -0x9(%rbp),%eax
  and    $0x3f,%eax
  add    %eax,%edx
  mov    -0x18(%rbp),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L1
  call   <__stack_chk_fail@plt>
L1:
  leave
  ret
```

assistant: ```c
void uu_decode_word24(char *dest, char *src_uu) {
  uint8_t i;
  char uu_dec[4];
  ;
  for (i = 0; i < 4; i++)
    uu_dec[i] = uu_decode_char8(src_uu[i]);
  ;
  dest[0] = ((uu_dec[0] & 0x3F) << 2) + ((uu_dec[1] & 0x30) >> 4);
  dest[1] = ((uu_dec[1] & 0x0F) << 4) + ((uu_dec[2] & 0x3C) >> 2);
  dest[2] = ((uu_dec[2] & 0x03) << 6) + (uu_dec[3] & 0x3F);
  ;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<uu_decode_word24>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x10,%rsp
  mov    %rdi,%r12
  mov    %rsi,%rbp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  mov    $0x0,%ebx
L19:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <uu_decode_char8@plt>
  mov    %al,0x4(%rsp,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L19
  movsbl 0x5(%rsp),%ecx
  movsbl 0x4(%rsp),%eax
  mov    %ecx,%edx
  sar    $0x4,%edx
  and    $0x3,%edx
  lea    (%rdx,%rax,4),%eax
  mov    %al,(%r12)
  movsbl 0x6(%rsp),%edx
  mov    %edx,%eax
  sar    $0x2,%eax
  and    $0xf,%eax
  shl    $0x4,%ecx
  add    %ecx,%eax
  mov    %al,0x1(%r12)
  movzbl 0x7(%rsp),%eax
  and    $0x3f,%eax
  shl    $0x6,%edx
  add    %edx,%eax
  mov    %al,0x2(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L14
  add    $0x10,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L14:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uu_decode_word24(char *dest, char *src_uu) {
  uint8_t i;
  char uu_dec[4];
  ;
  for (i = 0; i < 4; i++)
    uu_dec[i] = uu_decode_char8(src_uu[i]);
  ;
  dest[0] = ((uu_dec[0] & 0x3F) << 2) + ((uu_dec[1] & 0x30) >> 4);
  dest[1] = ((uu_dec[1] & 0x0F) << 4) + ((uu_dec[2] & 0x3C) >> 2);
  dest[2] = ((uu_dec[2] & 0x03) << 6) + (uu_dec[3] & 0x3F);
  ;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<uu_decode_word24>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
L18:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <uu_decode_char8@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L18
  movsbl 0x5(%rsp),%ecx
  movsbl 0x4(%rsp),%eax
  mov    %ecx,%edx
  shl    $0x4,%ecx
  sar    $0x4,%edx
  and    $0x3,%edx
  lea    (%rdx,%rax,4),%eax
  movsbl 0x6(%rsp),%edx
  mov    %al,(%r12)
  mov    %edx,%eax
  shl    $0x6,%edx
  sar    $0x2,%eax
  and    $0xf,%eax
  add    %ecx,%eax
  mov    %al,0x1(%r12)
  movzbl 0x7(%rsp),%eax
  and    $0x3f,%eax
  add    %edx,%eax
  mov    %al,0x2(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uu_decode_word24(char *dest, char *src_uu) {
  uint8_t i;
  char uu_dec[4];
  ;
  for (i = 0; i < 4; i++)
    uu_dec[i] = uu_decode_char8(src_uu[i]);
  ;
  dest[0] = ((uu_dec[0] & 0x3F) << 2) + ((uu_dec[1] & 0x30) >> 4);
  dest[1] = ((uu_dec[1] & 0x0F) << 4) + ((uu_dec[2] & 0x3C) >> 2);
  dest[2] = ((uu_dec[2] & 0x03) << 6) + (uu_dec[3] & 0x3F);
  ;
}
```
user: 这段汇编代码用C语言表示是什么样的:

```asm
<uu_decode_word24>:
  endbr64
  push   %r13
  push   %r12
  mov    %rdi,%r12
  push   %rbp
  mov    %rsi,%rbp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%r13
L8:
  movsbl 0x0(%rbp,%rbx,1),%edi
  call   <uu_decode_char8@plt>
  mov    %al,0x0(%r13,%rbx,1)
  add    $0x1,%rbx
  cmp    $0x4,%rbx
  jne    L8
  movsbl 0x5(%rsp),%ecx
  movsbl 0x4(%rsp),%eax
  mov    %ecx,%edx
  shl    $0x4,%ecx
  sar    $0x4,%edx
  and    $0x3,%edx
  lea    (%rdx,%rax,4),%eax
  movsbl 0x6(%rsp),%edx
  mov    %al,(%r12)
  mov    %edx,%eax
  shl    $0x6,%edx
  sar    $0x2,%eax
  and    $0xf,%eax
  add    %ecx,%eax
  mov    %al,0x1(%r12)
  movzbl 0x7(%rsp),%eax
  and    $0x3f,%eax
  add    %edx,%eax
  mov    %al,0x2(%r12)
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L10
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L10:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
void uu_decode_word24(char *dest, char *src_uu) {
  uint8_t i;
  char uu_dec[4];
  ;
  for (i = 0; i < 4; i++)
    uu_dec[i] = uu_decode_char8(src_uu[i]);
  ;
  dest[0] = ((uu_dec[0] & 0x3F) << 2) + ((uu_dec[1] & 0x30) >> 4);
  dest[1] = ((uu_dec[1] & 0x0F) << 4) + ((uu_dec[2] & 0x3C) >> 2);
  dest[2] = ((uu_dec[2] & 0x03) << 6) + (uu_dec[3] & 0x3F);
  ;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D57(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  jmp    L17
L19:
  lea    D5(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <print_binary@plt>
  lea    D3(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0xc(%rbp),%eax
  mov    %eax,%edi
  call   <swap_pairs@plt>
  mov    %eax,%edi
  call   <print_binary@plt>
  lea    D7(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
L17:
  lea    -0xc(%rbp),%rax
  mov    %rax,%rsi
  lea    D33(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L19
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L0
  call   <__stack_chk_fail@plt>
L0:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_tag: D57
type: string
name: parse_data
arguments: data_tag: D7
type: string
name: parse_data
arguments: data_tag: D5
type: string
name: parse_data
arguments: data_tag: D3
type: string
name: parse_data
arguments: data_tag: D33
type: string

tool: D57: Enter a number for the Flip Bit to Win game


tool: D7: > 

tool: D5: Input:	

tool: D3: Output:	

tool: D33: %u

assistant: ```c
int main(void) {
  printf("Enter a number for the Flip Bit to Win game\n");
  printf("> ");
  unsigned n;
  while (scanf("%u", &n) == 1) {
    printf("Input:\t");
    print_binary(n);
    printf("Output:\t");
    print_binary(swap_pairs(n));
    printf("> ");
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    D34(%rip),%rdi
  call   <printf@plt>
  lea    D48(%rip),%rdi
  call   <printf@plt>
  lea    D37(%rip),%rbx
  lea    D58(%rip),%r13
  lea    D44(%rip),%r12
  lea    D48(%rip),%rbp
  jmp    L3
L24:
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <print_binary@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <swap_pairs@plt>
  mov    %eax,%edi
  call   <print_binary@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
L3:
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L24
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D34
data_type: string
name: disassemble_data
arguments: label: D48
data_type: string
name: disassemble_data
arguments: label: D37
data_type: string
name: disassemble_data
arguments: label: D58
data_type: string
name: disassemble_data
arguments: label: D44
data_type: string

tool: D34: Enter a number for the Flip Bit to Win game


tool: D48: > 

tool: D37: %u

tool: D58: Input:	

tool: D44: Output:	

assistant: ```c
int main(void) {
  printf("Enter a number for the Flip Bit to Win game\n");
  printf("> ");
  unsigned n;
  while (scanf("%u", &n) == 1) {
    printf("Input:\t");
    print_binary(n);
    printf("Output:\t");
    print_binary(swap_pairs(n));
    printf("> ");
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r14
  lea    D29(%rip),%rdi
  lea    D23(%rip),%r14
  push   %r13
  lea    D14(%rip),%r13
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D27(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L15
  nopw   0x0(%rax,%rax,1)
L8:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <print_binary@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <swap_pairs@plt>
  mov    %eax,%edi
  call   <print_binary@plt>
  mov    %r12,%rdi
  call   <printf@plt>
L15:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L8
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L29
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L29:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D29
type_infered: string
name: parse_data
arguments: label: D23
type_infered: string
name: parse_data
arguments: label: D14
type_infered: string
name: parse_data
arguments: label: D8
type_infered: string
name: parse_data
arguments: label: D27
type_infered: string

tool: D29: Enter a number for the Flip Bit to Win game


tool: D23: Input:	

tool: D14: Output:	

tool: D8: > 

tool: D27: %u

assistant: ```c
int main(void) {
  printf("Enter a number for the Flip Bit to Win game\n");
  printf("> ");
  unsigned n;
  while (scanf("%u", &n) == 1) {
    printf("Input:\t");
    print_binary(n);
    printf("Output:\t");
    print_binary(swap_pairs(n));
    printf("> ");
  }
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r14
  lea    D33(%rip),%rdi
  lea    D31(%rip),%r14
  push   %r13
  lea    D7(%rip),%r13
  push   %r12
  lea    D17(%rip),%r12
  push   %rbp
  push   %rbx
  lea    D49(%rip),%rbx
  sub    $0x10,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  lea    0x4(%rsp),%rbp
  call   <printf@plt>
  mov    %r12,%rdi
  call   <printf@plt>
  jmp    L28
  nopw   0x0(%rax,%rax,1)
L13:
  mov    %r14,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <print_binary@plt>
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x4(%rsp),%edi
  call   <swap_pairs@plt>
  mov    %eax,%edi
  call   <print_binary@plt>
  mov    %r12,%rdi
  call   <printf@plt>
L28:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  cmp    $0x1,%eax
  je     L13
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L26
  add    $0x10,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L26:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D33
type: string
name: disassemble_data
arguments: data_label: D31
type: string
name: disassemble_data
arguments: data_label: D7
type: string
name: disassemble_data
arguments: data_label: D17
type: string
name: disassemble_data
arguments: data_label: D49
type: string

tool: D33: Enter a number for the Flip Bit to Win game


tool: D31: Input:	

tool: D7: Output:	

tool: D17: > 

tool: D49: %u

assistant: ```c
int main(void) {
  printf("Enter a number for the Flip Bit to Win game\n");
  printf("> ");
  unsigned n;
  while (scanf("%u", &n) == 1) {
    printf("Input:\t");
    print_binary(n);
    printf("Output:\t");
    print_binary(swap_pairs(n));
    printf("> ");
  }
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<divide_ceiling>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %eax,-0x4(%rbp)
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x18(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  je     L6
  addl   $0x1,-0x4(%rbp)
L6:
  mov    -0x4(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint32_t divide_ceiling(uint32_t a, uint32_t b) {
  uint32_t ret = a / b;
  if (a % b)
    ret += 1;
  return ret;
}
```
user: Translate the below assembly code into C programming language:

```asm
<divide_ceiling>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
uint32_t divide_ceiling(uint32_t a, uint32_t b) {
  uint32_t ret = a / b;
  if (a % b)
    ret += 1;
  return ret;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<divide_ceiling>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
uint32_t divide_ceiling(uint32_t a, uint32_t b) {
  uint32_t ret = a / b;
  if (a % b)
    ret += 1;
  return ret;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<divide_ceiling>:
  endbr64
  mov    %edi,%eax
  cltd
  idiv   %esi
  cmp    $0x1,%edx
  sbb    $0xffffffff,%eax
  ret
```

assistant: ```c
uint32_t divide_ceiling(uint32_t a, uint32_t b) {
  uint32_t ret = a / b;
  if (a % b)
    ret += 1;
  return ret;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<closed_loop>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    $0x0,%eax
  call   <double_matrix_multiplication@plt>
  mov    $0x0,%eax
  call   <double_sub_matrix@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void closed_loop(void) {
  double_matrix_multiplication();
  double_sub_matrix();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<closed_loop>:
  endbr64
  sub    $0x8,%rsp
  mov    $0x0,%eax
  call   <double_matrix_multiplication@plt>
  mov    $0x0,%eax
  call   <double_sub_matrix@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void closed_loop(void) {
  double_matrix_multiplication();
  double_sub_matrix();
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<closed_loop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <double_matrix_multiplication@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <double_sub_matrix@plt>
```

assistant: ```c
void closed_loop(void) {
  double_matrix_multiplication();
  double_sub_matrix();
}
```
user: What is the c source code of the assembly code below?

```asm
<closed_loop>:
  endbr64
  sub    $0x8,%rsp
  xor    %eax,%eax
  call   <double_matrix_multiplication@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1070 <double_sub_matrix@plt>
```

assistant: ```c
void closed_loop(void) {
  double_matrix_multiplication();
  double_sub_matrix();
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<skips>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L19
  mov    $0x0,%eax
  jmp    L29
L19:
  movl   $0x1,-0x4(%rbp)
  jmp    L14
L39:
  subl   $0x1,-0x14(%rbp)
  mov    -0x4(%rbp),%eax
  imul   $0x1a,%eax,%eax
  mov    %eax,-0x4(%rbp)
L14:
  cmpl   $0x0,-0x14(%rbp)
  jg     L39
  mov    -0x4(%rbp),%eax
  sub    $0x1,%eax
L29:
  pop    %rbp
  ret
```

assistant: ```c
int skips(int lvl) {
  if (lvl == 0)
    return 0;
  int i = 1;
  while (lvl > 0) {
    lvl--;
    i *= 26;
  }
  return i - 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<skips>:
  endbr64
  mov    %edi,%eax
  test   %edi,%edi
  je     L12
  jle    L29
  mov    $0x1,%eax
L4:
  imul   $0x1a,%eax,%eax
  sub    $0x1,%edi
  jne    L4
L16:
  sub    $0x1,%eax
L12:
  ret
L29:
  mov    $0x1,%eax
  jmp    L16
```

assistant: ```c
int skips(int lvl) {
  if (lvl == 0)
    return 0;
  int i = 1;
  while (lvl > 0) {
    lvl--;
    i *= 26;
  }
  return i - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skips>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L22
  jle    L22
  mov    $0x1,%eax
  nopl   0x0(%rax)
L26:
  imul   $0x1a,%eax,%eax
  sub    $0x1,%edi
  jne    L26
  sub    $0x1,%eax
L22:
  ret
```

assistant: ```c
int skips(int lvl) {
  if (lvl == 0)
    return 0;
  int i = 1;
  while (lvl > 0) {
    lvl--;
    i *= 26;
  }
  return i - 1;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<skips>:
  endbr64
  xor    %eax,%eax
  test   %edi,%edi
  je     L40
  jle    L40
  mov    %edi,%ecx
  cmp    $0x1,%edi
  je     L33
  movq   D0(%rip),%xmm0
  mov    %edi,%edx
  shr    %edx
  nop
L24:
  movdqa %xmm0,%xmm1
  add    $0x1,%eax
  pslld  $0x1,%xmm1
  paddd  %xmm0,%xmm1
  pslld  $0x2,%xmm1
  paddd  %xmm1,%xmm0
  pslld  $0x1,%xmm0
  cmp    %eax,%edx
  jne    L24
  movd   %xmm0,%edi
  pshufd $0xe5,%xmm0,%xmm2
  movd   %xmm2,%eax
  imul   %eax,%edi
  and    $0x1,%ecx
  je     L30
L33:
  imul   $0x1a,%edi,%edi
L30:
  lea    -0x1(%rdi),%eax
L40:
  ret
```

tool_calls: name: read_data
arguments: label: D0
type: byte[8]

tool: {"D0": [0x01,0x00,0x00,0x00,0x01,0x00,0x00,0x00]}

assistant: ```c
int skips(int lvl) {
  if (lvl == 0)
    return 0;
  int i = 1;
  while (lvl > 0) {
    lvl--;
    i *= 26;
  }
  return i - 1;
}
```