ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    D47(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  pxor   %xmm0,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  movl   $0x1,-0x1c(%rbp)
L19:
  lea    D48(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x18(%rbp),%rax
  mov    %rax,%rsi
  lea    D40(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movsd  -0x18(%rbp),%xmm0
  movsd  D50(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  jp     L33
  movsd  D50(%rip),%xmm1
  ucomisd %xmm1,%xmm0
  je     L29
L33:
  movsd  -0x18(%rbp),%xmm0
  movsd  -0x10(%rbp),%xmm1
  addsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  addl   $0x1,-0x1c(%rbp)
  cmpl   $0x9,-0x1c(%rbp)
  jle    L19
  jmp    L25
L29:
  nop
L25:
  pxor   %xmm1,%xmm1
  cvtsi2sdl -0x1c(%rbp),%xmm1
  movsd  -0x10(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  mov    -0x10(%rbp),%rax
  movapd %xmm0,%xmm1
  movq   %rax,%xmm0
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L11
  call   <__stack_chk_fail@plt>
L11:
  leave
  ret
```

tool_calls: name: parse_data
arguments: data_label: D47
data_type: string
name: parse_data
arguments: data_label: D48
data_type: string
name: parse_data
arguments: data_label: D40
data_type: string
name: parse_data
arguments: data_label: D50
data_type: f32[2]
name: parse_data
arguments: data_label: D22
data_type: string

tool: D47: do-while Loop Example 3


tool: D48: Enter a value: 

tool: D40: %lf

tool: {"D50": [0.0,-1.875]}

tool: D22: 
The sum is %2.2lf and the avg is %2.2lf.



assistant: ```c
int main() {
  int counter;
  double numEntered, sum;
  printf("do-while Loop Example 3\n\n");
  sum = 0.0;
  counter = 1;
  do {
    printf("Enter a value: ");
    scanf("%lf", &numEntered);
    if (numEntered == -1.0)
      break;
    sum = sum + numEntered;
    counter++;
  } while (counter < 10);
  printf("\nThe sum is %2.2lf and the avg is %2.2lf.\n\n", sum, sum / counter);
  return 0;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<main>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D25(%rip),%rdi
  call   <puts@plt>
  pxor   %xmm4,%xmm4
  movsd  %xmm4,0x8(%rsp)
  mov    $0x1,%ebx
  lea    D22(%rip),%r12
  lea    D44(%rip),%rbp
L28:
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    0x10(%rsp),%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  ucomisd D4(%rip),%xmm0
  jp     L13
  je     L0
L13:
  addsd  0x8(%rsp),%xmm0
  movsd  %xmm0,0x8(%rsp)
  add    $0x1,%ebx
  cmp    $0xa,%ebx
  jne    L28
L0:
  pxor   %xmm0,%xmm0
  cvtsi2sd %ebx,%xmm0
  movsd  0x8(%rsp),%xmm3
  movapd %xmm3,%xmm1
  divsd  %xmm0,%xmm1
  movapd %xmm3,%xmm0
  lea    D17(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  mov    $0x0,%eax
  add    $0x20,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D25
type: string
name: parse_data
arguments: label: D22
type: string
name: parse_data
arguments: label: D44
type: string
name: parse_data
arguments: label: D4
type: f32[2]
name: parse_data
arguments: label: D17
type: string

tool: D25: do-while Loop Example 3


tool: D22: Enter a value: 

tool: D44: %lf

tool: {"D4": [0.0,-1.875]}

tool: D17: 
The sum is %2.2lf and the avg is %2.2lf.



assistant: ```c
int main() {
  int counter;
  double numEntered, sum;
  printf("do-while Loop Example 3\n\n");
  sum = 0.0;
  counter = 1;
  do {
    printf("Enter a value: ");
    scanf("%lf", &numEntered);
    if (numEntered == -1.0)
      break;
    sum = sum + numEntered;
    counter++;
  } while (counter < 10);
  printf("\nThe sum is %2.2lf and the avg is %2.2lf.\n\n", sum, sum / counter);
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  push   %r13
  lea    D13(%rip),%rdi
  lea    D7(%rip),%r13
  push   %r12
  push   %rbp
  lea    D47(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L13:
  mov    %r13,%rdi
  xor    %eax,%eax
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  ucomisd D42(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  jp     L16
  je     L32
L16:
  add    $0x1,%ebx
  addsd  %xmm0,%xmm2
  cmp    $0xa,%ebx
  jne    L13
L32:
  pxor   %xmm0,%xmm0
  movapd %xmm2,%xmm1
  mov    $0x2,%eax
  cvtsi2sd %ebx,%xmm0
  lea    D9(%rip),%rdi
  divsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_label: D13
type_guessed: string
name: unpack_data
arguments: data_label: D7
type_guessed: string
name: unpack_data
arguments: data_label: D47
type_guessed: string
name: unpack_data
arguments: data_label: D42
type_guessed: f32[2]
name: unpack_data
arguments: data_label: D9
type_guessed: string

tool: D13: do-while Loop Example 3


tool: D7: Enter a value: 

tool: D47: %lf

tool: {"D42": [0.0,-1.875]}

tool: D9: 
The sum is %2.2lf and the avg is %2.2lf.



assistant: ```c
int main() {
  int counter;
  double numEntered, sum;
  printf("do-while Loop Example 3\n\n");
  sum = 0.0;
  counter = 1;
  do {
    printf("Enter a value: ");
    scanf("%lf", &numEntered);
    if (numEntered == -1.0)
      break;
    sum = sum + numEntered;
    counter++;
  } while (counter < 10);
  printf("\nThe sum is %2.2lf and the avg is %2.2lf.\n\n", sum, sum / counter);
  return 0;
}
```
user: What is the c source code of the assembly code below:

```asm
<main>:
  endbr64
  push   %r13
  lea    D31(%rip),%rdi
  lea    D15(%rip),%r13
  push   %r12
  push   %rbp
  lea    D48(%rip),%rbp
  push   %rbx
  mov    $0x1,%ebx
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%r12
  call   <puts@plt>
  pxor   %xmm2,%xmm2
  cs nopw 0x0(%rax,%rax,1)
L0:
  mov    %r13,%rdi
  xor    %eax,%eax
  movsd  %xmm2,0x8(%rsp)
  call   <printf@plt>
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <scanf@plt>
  movsd  0x10(%rsp),%xmm0
  ucomisd D35(%rip),%xmm0
  movsd  0x8(%rsp),%xmm2
  jp     L13
  je     L21
L13:
  add    $0x1,%ebx
  addsd  %xmm0,%xmm2
  cmp    $0xa,%ebx
  jne    L0
L21:
  pxor   %xmm0,%xmm0
  movapd %xmm2,%xmm1
  mov    $0x2,%eax
  cvtsi2sd %ebx,%xmm0
  lea    D18(%rip),%rdi
  divsd  %xmm0,%xmm1
  movapd %xmm2,%xmm0
  call   <printf@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L11
  add    $0x28,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L11:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: tag: D31
type_guessed: string
name: retrieve_data
arguments: tag: D15
type_guessed: string
name: retrieve_data
arguments: tag: D48
type_guessed: string
name: retrieve_data
arguments: tag: D35
type_guessed: f32[2]
name: retrieve_data
arguments: tag: D18
type_guessed: string

tool: D31: do-while Loop Example 3


tool: D15: Enter a value: 

tool: D48: %lf

tool: {"D35": [0.0,-1.875]}

tool: D18: 
The sum is %2.2lf and the avg is %2.2lf.



assistant: ```c
int main() {
  int counter;
  double numEntered, sum;
  printf("do-while Loop Example 3\n\n");
  sum = 0.0;
  counter = 1;
  do {
    printf("Enter a value: ");
    scanf("%lf", &numEntered);
    if (numEntered == -1.0)
      break;
    sum = sum + numEntered;
    counter++;
  } while (counter < 10);
  printf("\nThe sum is %2.2lf and the avg is %2.2lf.\n\n", sum, sum / counter);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<is_exist_dir>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  movq   $0x0,-0x8(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <opendir@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L4
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x0,%eax
  jmp    L13
L4:
  mov    -0x8(%rbp),%rax
  mov    %rax,%rdi
  call   <closedir@plt>
  mov    $0x1,%eax
L13:
  leave
  ret
```

assistant: ```c
int is_exist_dir(char *_dir) {
  DIR *dir = NULL;
  dir = opendir(_dir);
  if (dir == NULL) {
    closedir(dir);
    return 0;
  } else {
    closedir(dir);
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_exist_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <opendir@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L3
  call   <closedir@plt>
  mov    $0x1,%eax
L0:
  add    $0x8,%rsp
  ret
L3:
  call   <closedir@plt>
  mov    $0x0,%eax
  jmp    L0
```

assistant: ```c
int is_exist_dir(char *_dir) {
  DIR *dir = NULL;
  dir = opendir(_dir);
  if (dir == NULL) {
    closedir(dir);
    return 0;
  } else {
    closedir(dir);
    return 1;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<is_exist_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <opendir@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L2
  call   <closedir@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L2:
  call   <closedir@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_exist_dir(char *_dir) {
  DIR *dir = NULL;
  dir = opendir(_dir);
  if (dir == NULL) {
    closedir(dir);
    return 0;
  } else {
    closedir(dir);
    return 1;
  }
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<is_exist_dir>:
  endbr64
  sub    $0x8,%rsp
  call   <opendir@plt>
  mov    %rax,%rdi
  test   %rax,%rax
  je     L3
  call   <closedir@plt>
  mov    $0x1,%eax
  add    $0x8,%rsp
  ret
  nopl   0x0(%rax)
L3:
  call   <closedir@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

assistant: ```c
int is_exist_dir(char *_dir) {
  DIR *dir = NULL;
  dir = opendir(_dir);
  if (dir == NULL) {
    closedir(dir);
    return 0;
  } else {
    closedir(dir);
    return 1;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    %rsi,-0x30(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0x10(%rbp)
  mov    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <strlen@plt>
  mov    %eax,-0xc(%rbp)
  movl   $0x0,-0x14(%rbp)
  jmp    L16
L39:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %eax,%edx
  mov    -0x14(%rbp),%ecx
  mov    -0x28(%rbp),%rax
  mov    %ecx,%esi
  mov    %rax,%rdi
  call   <subsequence@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x30(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L4
  mov    -0x14(%rbp),%eax
  jmp    L30
L4:
  addl   $0x1,-0x14(%rbp)
L16:
  mov    -0x14(%rbp),%edx
  mov    -0xc(%rbp),%eax
  add    %edx,%eax
  cmp    %eax,-0x10(%rbp)
  jge    L39
  mov    $0xffffffff,%eax
L30:
  leave
  ret
```

assistant: ```c
int contains(char string[], char substring[]) {
  int master_len = strlen(string);
  int slave_len = strlen(substring);
  int index = 0;
  char *sub;
  while (index + slave_len <= master_len) {
    sub = subsequence(string, index, index + slave_len);
    if (!strcmp(sub, substring))
      return index;
    index++;
  }
  return -1;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<contains>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  mov    %rsi,%r13
  call   <strlen@plt>
  mov    %eax,%r14d
  mov    %r13,%rdi
  call   <strlen@plt>
  cmp    %eax,%r14d
  jl     L10
  mov    %eax,%ebx
  mov    $0x0,%ebp
L36:
  mov    %ebx,%edx
  mov    %ebp,%esi
  mov    %r12,%rdi
  call   <subsequence@plt>
  mov    %rax,%rdi
  mov    %r13,%rsi
  call   <strcmp@plt>
  test   %eax,%eax
  je     L13
  add    $0x1,%ebp
  add    $0x1,%ebx
  cmp    %ebx,%r14d
  jge    L36
  mov    $0xffffffff,%ebp
L13:
  mov    %ebp,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
L10:
  mov    $0xffffffff,%ebp
  jmp    L13
```

assistant: ```c
int contains(char string[], char substring[]) {
  int master_len = strlen(string);
  int slave_len = strlen(substring);
  int index = 0;
  char *sub;
  while (index + slave_len <= master_len) {
    sub = subsequence(string, index, index + slave_len);
    if (!strcmp(sub, substring))
      return index;
    index++;
  }
  return -1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<contains>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jl     L20
  mov    %eax,%ebx
  xor    %r14d,%r14d
  jmp    L10
  xchg   %ax,%ax
L15:
  add    $0x1,%ebx
  add    $0x1,%r14d
  cmp    %ebx,%r13d
  jl     L20
L10:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %ebx,%edx
  call   <subsequence@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L15
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L20:
  mov    $0xffffffff,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int contains(char string[], char substring[]) {
  int master_len = strlen(string);
  int slave_len = strlen(substring);
  int index = 0;
  char *sub;
  while (index + slave_len <= master_len) {
    sub = subsequence(string, index, index + slave_len);
    if (!strcmp(sub, substring))
      return index;
    index++;
  }
  return -1;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<contains>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  mov    %rsi,%r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <strlen@plt>
  mov    %r12,%rdi
  mov    %eax,%r13d
  call   <strlen@plt>
  cmp    %eax,%r13d
  jl     L31
  mov    %eax,%ebx
  xor    %r14d,%r14d
  jmp    L21
  xchg   %ax,%ax
L25:
  add    $0x1,%ebx
  add    $0x1,%r14d
  cmp    %ebx,%r13d
  jl     L31
L21:
  mov    %r14d,%esi
  mov    %rbp,%rdi
  mov    %ebx,%edx
  call   <subsequence@plt>
  mov    %r12,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %eax,%eax
  jne    L25
  pop    %rbx
  mov    %r14d,%eax
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
  nopl   0x0(%rax)
L31:
  mov    $0xffffffff,%r14d
  pop    %rbx
  pop    %rbp
  mov    %r14d,%eax
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
int contains(char string[], char substring[]) {
  int master_len = strlen(string);
  int slave_len = strlen(substring);
  int index = 0;
  char *sub;
  while (index + slave_len <= master_len) {
    sub = subsequence(string, index, index + slave_len);
    if (!strcmp(sub, substring))
      return index;
    index++;
  }
  return -1;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpl   $0x270f,0x4(%rsp)
  je     L115
  lea    D13(%rip),%r12
  lea    D76(%rip),%rbp
  lea    D43(%rip),%rbx
  lea    D23(%rip),%r13
  jmp    L27
L37:
  lea    D71(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L24:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L82
L17:
  test   %eax,%eax
  jne    L16
  lea    D71(%rip),%rdi
  call   <printf@plt>
L82:
  lea    D0(%rip),%rdi
  call   <printf@plt>
  lea    D63(%rip),%rdi
  call   <system@plt>
  lea    D94(%rip),%rdi
  call   <system@plt>
  cmpl   $0x270f,0x4(%rsp)
  je     L115
L27:
  mov    %r12,%rdi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <printf@plt>
  lea    0x4(%rsp),%rsi
  mov    %rbx,%rdi
  call   <scanf@plt>
  mov    0x4(%rsp),%edx
  movslq %edx,%rax
  imul   $0x51eb851f,%rax,%rax
  sar    $0x27,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   $0x3,%dl
  jne    L17
  movslq %edx,%rcx
  imul   $0x51eb851f,%rcx,%rcx
  sar    $0x25,%rcx
  mov    %edx,%esi
  sar    $0x1f,%esi
  sub    %esi,%ecx
  imul   $0x64,%ecx,%ecx
  cmp    %ecx,%edx
  jne    L37
  test   %eax,%eax
  jne    L24
  lea    D71(%rip),%rdi
  call   <printf@plt>
  jmp    L82
L16:
  mov    %r13,%rdi
  call   <printf@plt>
  jmp    L82
L115:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L103
  mov    $0x0,%eax
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L103:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: label: D13
type_infered: string
name: unpack_data
arguments: label: D76
type_infered: string
name: unpack_data
arguments: label: D43
type_infered: string
name: unpack_data
arguments: label: D23
type_infered: string
name: unpack_data
arguments: label: D71
type_infered: string
name: unpack_data
arguments: label: D0
type_infered: string
name: unpack_data
arguments: label: D63
type_infered: string
name: unpack_data
arguments: label: D94
type_infered: string

tool: D13: VERIFICADOR DE ANO BISSEXTO



tool: D76: Insira o ano com 4 digitos (9999 para sair): 

tool: D43: %d

tool: D23: O ano NAO e Bissexto

tool: D71: Ano Bissexto

tool: D0: 



tool: D63: PAUSE

tool: D94: cls

assistant: ```c
main() {
  int ano, div4, div100, div400;
  while (ano != 9999) {
    printf("VERIFICADOR DE ANO BISSEXTO\n\n");
    printf("Insira o ano com 4 digitos (9999 para sair): ");
    scanf("%d", &ano);
    div4 = ano % 4;
    div100 = ano % 100;
    div400 = ano % 400;
    if (div4 == 0) {
      if (div100 != 0) {
        printf("Ano Bissexto");
      } else {
        if (div400 == 0) {
          printf("Ano Bissexto");
        } else {
          printf("O ano NAO e Bissexto");
        }
      }
    } else {
      if (div400 == 0) {
        printf("Ano Bissexto");
      } else {
        printf("O ano NAO e Bissexto");
      }
    }
    printf("\n\n");
    system("PAUSE");
    system("cls");
  }
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpl   $0x270f,0x4(%rsp)
  je     L54
  lea    D71(%rip),%r15
  lea    D36(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D34(%rip),%r12
  lea    D13(%rip),%rbp
  lea    D41(%rip),%rbx
  jmp    L69
  nopw   0x0(%rax,%rax,1)
L79:
  lea    D10(%rip),%rdi
  call   <printf@plt>
L49:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  lea    D5(%rip),%rdi
  call   <system@plt>
  cmpl   $0x270f,0x4(%rsp)
  je     L54
L69:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x27,%rax
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   $0x3,%dl
  jne    L29
  imul   $0xc28f5c29,%edx,%edx
  add    $0x51eb850,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L21
L29:
  test   %eax,%eax
  jne    L79
L21:
  lea    D62(%rip),%rdi
  call   <printf@plt>
  jmp    L49
  cs nopw 0x0(%rax,%rax,1)
L54:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L19
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L19:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D71
type: string
name: parse_data
arguments: label: D36
type: string
name: parse_data
arguments: label: D34
type: string
name: parse_data
arguments: label: D13
type: string
name: parse_data
arguments: label: D41
type: string
name: parse_data
arguments: label: D10
type: string
name: parse_data
arguments: label: D5
type: string
name: parse_data
arguments: label: D62
type: string

tool: D71: VERIFICADOR DE ANO BISSEXTO



tool: D36: Insira o ano com 4 digitos (9999 para sair): 

tool: D34: %d

tool: D13: 



tool: D41: PAUSE

tool: D10: O ano NAO e Bissexto

tool: D5: cls

tool: D62: Ano Bissexto

assistant: ```c
main() {
  int ano, div4, div100, div400;
  while (ano != 9999) {
    printf("VERIFICADOR DE ANO BISSEXTO\n\n");
    printf("Insira o ano com 4 digitos (9999 para sair): ");
    scanf("%d", &ano);
    div4 = ano % 4;
    div100 = ano % 100;
    div400 = ano % 400;
    if (div4 == 0) {
      if (div100 != 0) {
        printf("Ano Bissexto");
      } else {
        if (div400 == 0) {
          printf("Ano Bissexto");
        } else {
          printf("O ano NAO e Bissexto");
        }
      }
    } else {
      if (div400 == 0) {
        printf("Ano Bissexto");
      } else {
        printf("O ano NAO e Bissexto");
      }
    }
    printf("\n\n");
    system("PAUSE");
    system("cls");
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x8(%rsp)
  xor    %eax,%eax
  cmpl   $0x270f,0x4(%rsp)
  je     L70
  lea    D31(%rip),%r15
  lea    D70(%rip),%r14
  lea    0x4(%rsp),%r13
  lea    D27(%rip),%r12
  lea    D78(%rip),%rbp
  lea    D22(%rip),%rbx
  jmp    L77
  nopw   0x0(%rax,%rax,1)
L73:
  lea    D72(%rip),%rdi
  call   <printf@plt>
L67:
  mov    %rbp,%rdi
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <system@plt>
  lea    D24(%rip),%rdi
  call   <system@plt>
  cmpl   $0x270f,0x4(%rsp)
  je     L70
L77:
  mov    %r15,%rdi
  call   <printf@plt>
  mov    %r14,%rdi
  call   <printf@plt>
  mov    %r13,%rsi
  mov    %r12,%rdi
  call   <scanf@plt>
  movslq 0x4(%rsp),%rax
  mov    %rax,%rdx
  imul   $0x51eb851f,%rax,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sar    $0x27,%rax
  sub    %ecx,%eax
  imul   $0x190,%eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  test   $0x3,%dl
  jne    L49
  imul   $0xc28f5c29,%edx,%edx
  add    $0x51eb850,%edx
  ror    $0x2,%edx
  cmp    $0x28f5c28,%edx
  ja     L39
L49:
  test   %eax,%eax
  jne    L73
L39:
  lea    D25(%rip),%rdi
  call   <printf@plt>
  jmp    L67
  cs nopw 0x0(%rax,%rax,1)
L70:
  mov    0x8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L37
  add    $0x18,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L37:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: label: D31
data_type: string
name: disassemble_data
arguments: label: D70
data_type: string
name: disassemble_data
arguments: label: D27
data_type: string
name: disassemble_data
arguments: label: D78
data_type: string
name: disassemble_data
arguments: label: D22
data_type: string
name: disassemble_data
arguments: label: D72
data_type: string
name: disassemble_data
arguments: label: D24
data_type: string
name: disassemble_data
arguments: label: D25
data_type: string

tool: D31: VERIFICADOR DE ANO BISSEXTO



tool: D70: Insira o ano com 4 digitos (9999 para sair): 

tool: D27: %d

tool: D78: 



tool: D22: PAUSE

tool: D72: O ano NAO e Bissexto

tool: D24: cls

tool: D25: Ano Bissexto

assistant: ```c
main() {
  int ano, div4, div100, div400;
  while (ano != 9999) {
    printf("VERIFICADOR DE ANO BISSEXTO\n\n");
    printf("Insira o ano com 4 digitos (9999 para sair): ");
    scanf("%d", &ano);
    div4 = ano % 4;
    div100 = ano % 100;
    div400 = ano % 400;
    if (div4 == 0) {
      if (div100 != 0) {
        printf("Ano Bissexto");
      } else {
        if (div400 == 0) {
          printf("Ano Bissexto");
        } else {
          printf("O ano NAO e Bissexto");
        }
      }
    } else {
      if (div400 == 0) {
        printf("Ano Bissexto");
      } else {
        printf("O ano NAO e Bissexto");
      }
    }
    printf("\n\n");
    system("PAUSE");
    system("cls");
  }
}
```