ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<sysfs_cpufreq_read_file>:
  endbr64
  push   %r13
  mov    %rsi,%r8
  mov    $0xff,%esi
  push   %r12
  mov    %rcx,%r12
  mov    %edi,%ecx
  push   %rbp
  mov    %rdx,%rbp
  lea    D4(%rip),%rdx
  sub    $0x110,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x108(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r13
  mov    %r13,%rdi
  call   <snprintf@plt>
  mov    %r12,%rdx
  mov    %rbp,%rsi
  mov    %r13,%rdi
  call   <sysfs_read_file@plt>
  mov    0x108(%rsp),%rdx
  sub    %fs:0x28,%rdx
  jne    L5
  add    $0x110,%rsp
  pop    %rbp
  pop    %r12
  pop    %r13
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D4
datatype: string

tool: D4: /sys/devices/system/cpu/cpu%u/cpufreq/%s

assistant: ```c
unsigned int sysfs_cpufreq_read_file(unsigned int cpu, const char *fname, char *buf, size_t buflen) {
  char path[255];
  snprintf(path, sizeof(path),
           "/sys/devices/system/cpu/"
           "cpu%u/cpufreq/%s",
           cpu, fname);
  return sysfs_read_file(path, buf, buflen);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<transfer_YUV161616_to_YUV422>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    %edx,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L17
  mov    -0x10(%rbp),%rax
  add    $0x4,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x1,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  add    $0x8,%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x3,%rax
  mov    %dl,(%rax)
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  mov    %dl,(%rax)
  jmp    L13
L17:
  mov    -0x10(%rbp),%rax
  mov    (%rax),%eax
  sar    $0x8,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  add    $0x2,%rax
  mov    %dl,(%rax)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  lea    0x4(%rax),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
L13:
  nop
  pop    %rbp
  ret
```

assistant: ```c
void transfer_YUV161616_to_YUV422(unsigned char *(*output), uint16_t *input, int j) {
  if (!(j & 1)) {
    (*output)[1] = input[1] >> 8;
    (*output)[3] = input[2] >> 8;
    (*output)[0] = input[0] >> 8;
  } else {
    (*output)[2] = input[0] >> 8;
    (*output) += 4;
  }
}
```
user: What is the c source code of the assembly code below?

```asm
<transfer_YUV161616_to_YUV422>:
  endbr64
  test   $0x1,%dl
  jne    L0
  mov    (%rdi),%rax
  mov    0x4(%rsi),%edx
  movzbl %dh,%ecx
  mov    %cl,0x1(%rax)
  mov    (%rdi),%rax
  mov    0x8(%rsi),%edx
  movzbl %dh,%ecx
  mov    %cl,0x3(%rax)
  mov    (%rdi),%rax
  mov    (%rsi),%edx
  movzbl %dh,%ecx
  mov    %cl,(%rax)
  ret
L0:
  mov    (%rdi),%rax
  mov    (%rsi),%edx
  movzbl %dh,%ecx
  mov    %cl,0x2(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void transfer_YUV161616_to_YUV422(unsigned char *(*output), uint16_t *input, int j) {
  if (!(j & 1)) {
    (*output)[1] = input[1] >> 8;
    (*output)[3] = input[2] >> 8;
    (*output)[0] = input[0] >> 8;
  } else {
    (*output)[2] = input[0] >> 8;
    (*output) += 4;
  }
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<transfer_YUV161616_to_YUV422>:
  endbr64
  and    $0x1,%edx
  mov    (%rdi),%rax
  jne    L6
  mov    0x4(%rsi),%edx
  mov    %dh,0x1(%rax)
  mov    (%rdi),%rax
  mov    0x8(%rsi),%edx
  mov    %dh,0x3(%rax)
  mov    (%rdi),%rax
  mov    (%rsi),%edx
  mov    %dh,(%rax)
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  mov    (%rsi),%edx
  mov    %dh,0x2(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void transfer_YUV161616_to_YUV422(unsigned char *(*output), uint16_t *input, int j) {
  if (!(j & 1)) {
    (*output)[1] = input[1] >> 8;
    (*output)[3] = input[2] >> 8;
    (*output)[0] = input[0] >> 8;
  } else {
    (*output)[2] = input[0] >> 8;
    (*output) += 4;
  }
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<transfer_YUV161616_to_YUV422>:
  endbr64
  and    $0x1,%edx
  mov    (%rdi),%rax
  jne    L9
  mov    0x4(%rsi),%edx
  mov    %dh,0x1(%rax)
  mov    (%rdi),%rax
  mov    0x8(%rsi),%edx
  mov    %dh,0x3(%rax)
  mov    (%rdi),%rax
  mov    (%rsi),%edx
  mov    %dh,(%rax)
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  mov    (%rsi),%edx
  mov    %dh,0x2(%rax)
  addq   $0x4,(%rdi)
  ret
```

assistant: ```c
void transfer_YUV161616_to_YUV422(unsigned char *(*output), uint16_t *input, int j) {
  if (!(j & 1)) {
    (*output)[1] = input[1] >> 8;
    (*output)[3] = input[2] >> 8;
    (*output)[0] = input[0] >> 8;
  } else {
    (*output)[2] = input[0] >> 8;
    (*output) += 4;
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<other_function>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  movl   $0x1,-0x4(%rbp)
  addl   $0x1,-0x4(%rbp)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void other_function(void) {
  int i = 1;
  i++;
}
```
user: Translate the below assembly code into C programming language:

```asm
<other_function>:
  endbr64
  ret
```

assistant: ```c
void other_function(void) {
  int i = 1;
  i++;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<other_function>:
  endbr64
  ret
```

assistant: ```c
void other_function(void) {
  int i = 1;
  i++;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<other_function>:
  endbr64
  ret
```

assistant: ```c
void other_function(void) {
  int i = 1;
  i++;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<substr_count>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,%eax
  mov    %al,-0x20(%rbp)
  movl   $0x0,-0x8(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L7
L23:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  cmp    %al,-0x20(%rbp)
  jne    L22
  addl   $0x1,-0x8(%rbp)
L22:
  addl   $0x1,-0x4(%rbp)
L7:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L23
  mov    -0x8(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
int substr_count(char *haystack, int len, char needle) {
  int count = 0;
  for (int i = 0; i < len; i++) {
    if (haystack[i] == needle)
      count++;
  }
  return count;
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<substr_count>:
  endbr64
  test   %esi,%esi
  jle    L22
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x1(%rdi,%rcx,1),%rdi
  mov    $0x0,%ecx
L27:
  cmp    %dl,(%rax)
  sete   %sil
  movzbl %sil,%esi
  add    %esi,%ecx
  add    $0x1,%rax
  cmp    %rdi,%rax
  jne    L27
L1:
  mov    %ecx,%eax
  ret
L22:
  mov    $0x0,%ecx
  jmp    L1
```

assistant: ```c
int substr_count(char *haystack, int len, char needle) {
  int count = 0;
  for (int i = 0; i < len; i++) {
    if (haystack[i] == needle)
      count++;
  }
  return count;
}
```
user: Translate the below assembly code into C programming language:

```asm
<substr_count>:
  endbr64
  test   %esi,%esi
  jle    L0
  lea    -0x1(%rsi),%eax
  lea    0x1(%rdi,%rax,1),%rsi
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L15:
  xor    %ecx,%ecx
  cmp    %dl,(%rdi)
  sete   %cl
  add    $0x1,%rdi
  add    %ecx,%eax
  cmp    %rsi,%rdi
  jne    L15
  ret
  nopl   0x0(%rax,%rax,1)
L0:
  xor    %eax,%eax
  ret
```

assistant: ```c
int substr_count(char *haystack, int len, char needle) {
  int count = 0;
  for (int i = 0; i < len; i++) {
    if (haystack[i] == needle)
      count++;
  }
  return count;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    D9(%rip),%rax
  mov    %rax,%rsi
  lea    D15(%rip),%rax
  mov    %rax,%rdi
  call   <minDistance@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  pop    %rbp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D9
data_type: string
name: extract_symbolic_data
arguments: label: D15
data_type: string
name: extract_symbolic_data
arguments: label: D2
data_type: string

tool: D9: ALTRUISTIC

tool: D15: ALGORITHM

tool: D2: %d


assistant: ```c
int main() {
  printf("%d\n", minDistance("ALGORITHM", "ALTRUISTIC"));
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D26(%rip),%rsi
  lea    D10(%rip),%rdi
  call   <minDistance@plt>
  mov    %eax,%esi
  lea    D2(%rip),%rdi
  call   <printf@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_label: D26
type_infered: string
name: extract_symbolic_data
arguments: data_label: D10
type_infered: string
name: extract_symbolic_data
arguments: data_label: D2
type_infered: string

tool: D26: ALTRUISTIC

tool: D10: ALGORITHM

tool: D2: %d


assistant: ```c
int main() {
  printf("%d\n", minDistance("ALGORITHM", "ALTRUISTIC"));
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D20(%rip),%rsi
  lea    D2(%rip),%rdi
  call   <minDistance@plt>
  lea    D23(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: retrieve_data
arguments: label: D20
datatype: string
name: retrieve_data
arguments: label: D2
datatype: string
name: retrieve_data
arguments: label: D23
datatype: string

tool: D20: ALTRUISTIC

tool: D2: ALGORITHM

tool: D23: %d


assistant: ```c
int main() {
  printf("%d\n", minDistance("ALGORITHM", "ALTRUISTIC"));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  lea    D22(%rip),%rsi
  lea    D0(%rip),%rdi
  call   <minDistance@plt>
  lea    D28(%rip),%rdi
  mov    %eax,%esi
  call   <printf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D22
datatype: string
name: disassemble_data
arguments: data_tag: D0
datatype: string
name: disassemble_data
arguments: data_tag: D28
datatype: string

tool: D22: ALTRUISTIC

tool: D0: ALGORITHM

tool: D28: %d


assistant: ```c
int main() {
  printf("%d\n", minDistance("ALGORITHM", "ALTRUISTIC"));
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<minipack_pack_str32>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  push   %rbx
  sub    $0x28,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  movq   $0x5,(%rax)
  mov    -0x18(%rbp),%rax
  movl   $0xdb,(%rax)
  mov    -0x18(%rbp),%rax
  lea    0x1(%rax),%rbx
  mov    -0x1c(%rbp),%eax
  mov    %eax,%edi
  call   <htonl@plt>
  mov    %eax,(%rbx)
  nop
  mov    -0x8(%rbp),%rbx
  leave
  ret
```

assistant: ```c
void minipack_pack_str32(void *ptr, uint32_t length, size_t *sz) {
  *sz = 5;
  *((uint8_t *)ptr) = 0xDB;
  *((uint32_t *)(ptr + 1)) = htonl(length);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<minipack_pack_str32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  movq   $0x5,(%rdx)
  movl   $0xdb,(%rbx)
  call   <htonl@plt>
  mov    %eax,0x1(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void minipack_pack_str32(void *ptr, uint32_t length, size_t *sz) {
  *sz = 5;
  *((uint8_t *)ptr) = 0xDB;
  *((uint32_t *)(ptr + 1)) = htonl(length);
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<minipack_pack_str32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  movq   $0x5,(%rdx)
  movl   $0xdb,(%rbx)
  call   <htonl@plt>
  mov    %eax,0x1(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void minipack_pack_str32(void *ptr, uint32_t length, size_t *sz) {
  *sz = 5;
  *((uint8_t *)ptr) = 0xDB;
  *((uint32_t *)(ptr + 1)) = htonl(length);
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<minipack_pack_str32>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    %esi,%edi
  movq   $0x5,(%rdx)
  movl   $0xdb,(%rbx)
  call   <htonl@plt>
  mov    %eax,0x1(%rbx)
  pop    %rbx
  ret
```

assistant: ```c
void minipack_pack_str32(void *ptr, uint32_t length, size_t *sz) {
  *sz = 5;
  *((uint8_t *)ptr) = 0xDB;
  *((uint32_t *)(ptr + 1)) = htonl(length);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  add    $0xffffffffffffff80,%rsp
  mov    %edi,-0x74(%rbp)
  mov    %rsi,-0x80(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0x372b38382a393939,%rax
  mov    $0x36362d37,%edx
  mov    %rax,-0x60(%rbp)
  mov    %rdx,-0x58(%rbp)
  movq   $0x0,-0x50(%rbp)
  movq   $0x0,-0x48(%rbp)
  movq   $0x0,-0x40(%rbp)
  lea    -0x60(%rbp),%rax
  mov    %rax,%rsi
  lea    D22(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movq   $0x0,-0x30(%rbp)
  movq   $0x0,-0x28(%rbp)
  movq   $0x0,-0x20(%rbp)
  movq   $0x0,-0x18(%rbp)
  movq   $0x0,-0x10(%rbp)
  lea    -0x30(%rbp),%rdx
  lea    -0x60(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <convertToPostfix@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rsi
  lea    D25(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    -0x30(%rbp),%rax
  mov    %rax,%rdi
  call   <evaluatePostfixExpression@plt>
  mov    %eax,-0x64(%rbp)
  mov    -0x64(%rbp),%eax
  mov    %eax,%edx
  lea    D21(%rip),%rax
  mov    %rax,%rsi
  lea    D17(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L8
  call   <__stack_chk_fail@plt>
L8:
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D22
type_guessed: string
name: read_data
arguments: data_tag: D25
type_guessed: string
name: read_data
arguments: data_tag: D21
type_guessed: string
name: read_data
arguments: data_tag: D17
type_guessed: string

tool: D22: %s

tool: D25: %s


tool: D21: result=

tool: D17: %s%d


assistant: ```c
int main(int argc, char const *argv[]) {
  char infix[40] = "999*88+77-66";
  scanf("%s", infix);
  char postfix[40] = "";
  char c;
  int result;
  convertToPostfix(infix, postfix);
  printf("%s\n", postfix);
  result = evaluatePostfixExpression(postfix);
  printf("%s%d\n", "result=", result);
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x68,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  movabs $0x372b38382a393939,%rax
  mov    $0x36362d37,%edx
  mov    %rax,(%rsp)
  mov    %rdx,0x8(%rsp)
  movq   $0x0,0x10(%rsp)
  movq   $0x0,0x18(%rsp)
  movq   $0x0,0x20(%rsp)
  mov    %rsp,%rbp
  mov    %rbp,%rsi
  lea    D1(%rip),%rdi
  call   <scanf@plt>
  movq   $0x0,0x30(%rsp)
  movq   $0x0,0x38(%rsp)
  movq   $0x0,0x40(%rsp)
  movq   $0x0,0x48(%rsp)
  movq   $0x0,0x50(%rsp)
  lea    0x30(%rsp),%rbx
  mov    %rbx,%rsi
  mov    %rbp,%rdi
  call   <convertToPostfix@plt>
  mov    %rbx,%rsi
  lea    D12(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    %rbx,%rdi
  call   <evaluatePostfixExpression@plt>
  mov    %eax,%edx
  lea    D15(%rip),%rsi
  lea    D32(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  mov    $0x0,%eax
  add    $0x68,%rsp
  pop    %rbx
  pop    %rbp
  ret
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: tag: D1
type: string
name: read_data
arguments: tag: D12
type: string
name: read_data
arguments: tag: D15
type: string
name: read_data
arguments: tag: D32
type: string

tool: D1: %s

tool: D12: %s


tool: D15: result=

tool: D32: %s%d


assistant: ```c
int main(int argc, char const *argv[]) {
  char infix[40] = "999*88+77-66";
  scanf("%s", infix);
  char postfix[40] = "";
  char c;
  int result;
  convertToPostfix(infix, postfix);
  printf("%s\n", postfix);
  result = evaluatePostfixExpression(postfix);
  printf("%s%d\n", "result=", result);
  return 0;
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<main>:
  endbr64
  push   %r12
  lea    D37(%rip),%rdi
  push   %rbp
  sub    $0x68,%rsp
  movdqa D41(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%rbp
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,(%rsp)
  mov    %r12,%rsi
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  call   <convertToPostfix@plt>
  mov    %rbp,%rsi
  lea    D3(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <evaluatePostfixExpression@plt>
  lea    D32(%rip),%rsi
  lea    D24(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L5
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L5:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: tag: D37
data_type: string
name: extract_symbolic_data
arguments: tag: D41
data_type: byte[16]
name: extract_symbolic_data
arguments: tag: D3
data_type: string
name: extract_symbolic_data
arguments: tag: D32
data_type: string
name: extract_symbolic_data
arguments: tag: D24
data_type: string

tool: D37: %s

tool: {"D41": [0x39,0x39,0x39,0x2a,0x38,0x38,0x2b,0x37,0x37,0x2d,0x36,0x36,0x00,0x00,0x00,0x00]}

tool: D3: %s


tool: D32: result=

tool: D24: %s%d


assistant: ```c
int main(int argc, char const *argv[]) {
  char infix[40] = "999*88+77-66";
  scanf("%s", infix);
  char postfix[40] = "";
  char c;
  int result;
  convertToPostfix(infix, postfix);
  printf("%s\n", postfix);
  result = evaluatePostfixExpression(postfix);
  printf("%s%d\n", "result=", result);
  return 0;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %r12
  lea    D28(%rip),%rdi
  push   %rbp
  sub    $0x68,%rsp
  movdqa D38(%rip),%xmm0
  mov    %fs:0x28,%rax
  mov    %rax,0x58(%rsp)
  xor    %eax,%eax
  mov    %rsp,%r12
  lea    0x30(%rsp),%rbp
  movq   $0x0,0x20(%rsp)
  movaps %xmm0,(%rsp)
  mov    %r12,%rsi
  pxor   %xmm0,%xmm0
  movaps %xmm0,0x10(%rsp)
  call   <scanf@plt>
  pxor   %xmm0,%xmm0
  mov    %rbp,%rsi
  mov    %r12,%rdi
  movaps %xmm0,0x30(%rsp)
  movaps %xmm0,0x40(%rsp)
  movq   $0x0,0x50(%rsp)
  call   <convertToPostfix@plt>
  mov    %rbp,%rsi
  lea    D49(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <evaluatePostfixExpression@plt>
  lea    D19(%rip),%rsi
  lea    D16(%rip),%rdi
  mov    %eax,%edx
  xor    %eax,%eax
  call   <printf@plt>
  mov    0x58(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  add    $0x68,%rsp
  xor    %eax,%eax
  pop    %rbp
  pop    %r12
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_tag: D28
data_type: string
name: parse_data
arguments: data_tag: D38
data_type: byte[16]
name: parse_data
arguments: data_tag: D49
data_type: string
name: parse_data
arguments: data_tag: D19
data_type: string
name: parse_data
arguments: data_tag: D16
data_type: string

tool: D28: %s

tool: {"D38": [0x39,0x39,0x39,0x2a,0x38,0x38,0x2b,0x37,0x37,0x2d,0x36,0x36,0x00,0x00,0x00,0x00]}

tool: D49: %s


tool: D19: result=

tool: D16: %s%d


assistant: ```c
int main(int argc, char const *argv[]) {
  char infix[40] = "999*88+77-66";
  scanf("%s", infix);
  char postfix[40] = "";
  char c;
  int result;
  convertToPostfix(infix, postfix);
  printf("%s\n", postfix);
  result = evaluatePostfixExpression(postfix);
  printf("%s%d\n", "result=", result);
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jg     L59
  mov    $0xffffffff,%eax
  jmp    L41
L59:
  movl   $0x2,-0x4(%rbp)
  jmp    L68
L25:
  mov    -0x14(%rbp),%eax
  cltd
  idivl  -0x4(%rbp)
  mov    %edx,%eax
  test   %eax,%eax
  jne    L5
  cmpl   $0x2,-0x14(%rbp)
  jne    L47
  mov    $0x1,%eax
  jmp    L41
L47:
  mov    $0x0,%eax
  jmp    L41
L5:
  addl   $0x1,-0x4(%rbp)
L68:
  mov    -0x4(%rbp),%eax
  cmp    -0x14(%rbp),%eax
  jl     L25
  mov    $0x1,%eax
L41:
  pop    %rbp
  ret
```

assistant: ```c
int is_prime(int a) {
  if (a < 1)
    return -1;
  int i;
  for (i = 2; i < a; i++) {
    if (a % i == 0) {
      if (a == 2)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<is_prime>:
  endbr64
  mov    $0xffffffff,%eax
  test   %edi,%edi
  jle    L47
  cmp    $0x2,%edi
  jle    L18
  test   $0x1,%dil
  je     L38
  mov    $0x2,%ecx
L56:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  je     L8
  mov    %edi,%eax
  cltd
  idiv   %ecx
  mov    %edx,%eax
  test   %edx,%edx
  jne    L56
L47:
  ret
L8:
  mov    $0x1,%eax
  ret
L18:
  mov    $0x1,%eax
  ret
L38:
  mov    $0x0,%eax
  jmp    L47
```

assistant: ```c
int is_prime(int a) {
  if (a < 1)
    return -1;
  int i;
  for (i = 2; i < a; i++) {
    if (a % i == 0) {
      if (a == 2)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<is_prime>:
  endbr64
  mov    $0xffffffff,%edx
  test   %edi,%edi
  jle    L44
  cmp    $0x2,%edi
  jle    L13
  test   $0x1,%dil
  je     L65
  mov    $0x2,%ecx
  jmp    L49
  nop
L46:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L44
L49:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L46
L13:
  mov    $0x1,%edx
L44:
  mov    %edx,%eax
  ret
L65:
  xor    %edx,%edx
  jmp    L44
```

assistant: ```c
int is_prime(int a) {
  if (a < 1)
    return -1;
  int i;
  for (i = 2; i < a; i++) {
    if (a % i == 0) {
      if (a == 2)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<is_prime>:
  endbr64
  mov    $0xffffffff,%edx
  test   %edi,%edi
  jle    L6
  cmp    $0x2,%edi
  jle    L10
  test   $0x1,%dil
  je     L22
  mov    $0x2,%ecx
  jmp    L60
  nop
L16:
  mov    %edi,%eax
  cltd
  idiv   %ecx
  test   %edx,%edx
  je     L6
L60:
  add    $0x1,%ecx
  cmp    %ecx,%edi
  jne    L16
L10:
  mov    $0x1,%edx
L6:
  mov    %edx,%eax
  ret
L22:
  xor    %edx,%edx
  jmp    L6
```

assistant: ```c
int is_prime(int a) {
  if (a < 1)
    return -1;
  int i;
  for (i = 2; i < a; i++) {
    if (a % i == 0) {
      if (a == 2)
        return 1;
      else
        return 0;
    }
  }
  return 1;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<str2ip>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x30,%rsp
  mov    %rdi,-0x28(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,%rdi
  call   <isIP@plt>
  test   %eax,%eax
  jne    L41
  mov    $0x0,%eax
  jmp    L66
L41:
  movq   $0x0,-0x8(%rbp)
  movb   $0x0,-0x11(%rbp)
  mov    -0x28(%rbp),%rax
  mov    %rax,-0x10(%rbp)
  jmp    L57
L19:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x2f,%al
  jle    L51
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x39,%al
  jg     L51
  movzbl -0x11(%rbp),%edx
  mov    %edx,%eax
  shl    $0x2,%eax
  add    %edx,%eax
  add    %eax,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  add    %edx,%eax
  sub    $0x30,%eax
  mov    %al,-0x11(%rbp)
  jmp    L37
L51:
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  movb   $0x0,-0x11(%rbp)
L37:
  addq   $0x1,-0x10(%rbp)
L57:
  mov    -0x10(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L19
  mov    -0x8(%rbp),%rax
  shl    $0x8,%rax
  mov    %rax,%rdx
  movzbl -0x11(%rbp),%eax
  or     %rdx,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
L66:
  leave
  ret
```

assistant: ```c
unsigned long str2ip(char *str) {
  char *c;
  unsigned long res;
  unsigned char n;
  if (!isIP(str))
    return 0;
  res = 0;
  n = 0;
  c = str;
  while (*c) {
    if ((*c >= '0') && (*c <= '9'))
      n = n * 10 + (*c - '0');
    else {
      res = (res << 8) | n;
      n = 0;
    }
    c++;
  }
  res = (res << 8) | n;
  return res;
}
```