ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<_prtl8>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%rcx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  movb   $0x0,0xc(%rsp)
  lea    0xd(%rsp),%r8
  lea    0x18(%rsp),%rsi
  mov    %r8,%rax
  nopl   (%rax)
L61:
  mov    %edi,%edx
  add    $0x1,%rax
  sar    $0x3,%rdi
  and    $0x7,%edx
  add    $0x30,%edx
  mov    %dl,-0x1(%rax)
  cmp    %rsi,%rax
  jne    L61
  movzbl 0x17(%rsp),%esi
  and    $0x33,%esi
  cmp    $0x30,%sil
  jne    L55
  mov    $0xa,%eax
  nopl   0x0(%rax,%rax,1)
L46:
  mov    %eax,%edx
  sub    $0x1,%rax
  cmpb   $0x30,(%r8,%rax,1)
  je     L46
  test   %edx,%edx
  jne    L10
  movzbl 0xd(%rsp),%esi
  mov    $0x1,%edx
  mov    $0x1,%eax
L12:
  add    $0x1,%edx
  lea    0xc(%rsp,%rax,1),%rax
  movslq %edx,%rdx
  add    %rcx,%rdx
  jmp    L36
L51:
  movzbl (%rax),%esi
L36:
  add    $0x1,%rcx
  sub    $0x1,%rax
  mov    %sil,-0x1(%rcx)
  cmp    %rdx,%rcx
  jne    L51
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L86
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
  nopl   0x0(%rax,%rax,1)
L10:
  movslq %edx,%rax
  movzbl 0xc(%rsp,%rax,1),%esi
  jmp    L12
L55:
  mov    $0xb,%edx
  mov    $0xb,%eax
  jmp    L12
L86:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
_prtl8(num, str) long num;
char *str;
{
  int i;
  char c, temp[12];
  temp[0] = '\0';
  for (i = 1; i <= 11; i++) {
    temp[i] = (num & 07) + '0';
    num = num >> 3;
  }
  temp[11] &= '3';
  for (i = 11; temp[i] == '0'; i--)
    ;
  if (i == 0)
    i++;
  while (i >= 0)
    *str++ = temp[i--];
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<print16>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    $0x30,%edi
  call   <putchar@plt>
  movl   $0x0,-0x4(%rbp)
  jmp    L1
L14:
  mov    -0x4(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  mov    -0x4(%rbp),%edx
  mov    %eax,%esi
  lea    D6(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  addl   $0x1,-0x4(%rbp)
L1:
  cmpl   $0xf,-0x4(%rbp)
  jle    L14
  nop
  nop
  leave
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
datatype: string

tool: D6: +%u*256^%d

assistant: ```c
void print16(const unsigned char *k) {
  int i;
  printf("0");
  for (i = 0; i < 16; ++i)
    printf("+%u*256^%d", 255 & (int)k[i], i);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<print16>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbp
  mov    $0x30,%edi
  call   <putchar@plt>
  mov    $0x0,%ebx
  lea    D5(%rip),%r12
L3:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  add    $0x1,%rbx
  cmp    $0x10,%rbx
  jne    L3
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D5
datatype: string

tool: D5: +%u*256^%d

assistant: ```c
void print16(const unsigned char *k) {
  int i;
  printf("0");
  for (i = 0; i < 16; ++i)
    printf("+%u*256^%d", 255 & (int)k[i], i);
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<print16>:
  endbr64
  push   %r12
  lea    D8(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x30,%edi
  push   %rbx
  xor    %ebx,%ebx
  call   <putchar@plt>
  xchg   %ax,%ax
L7:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x10,%rbx
  jne    L7
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D8
type: string

tool: D8: +%u*256^%d

assistant: ```c
void print16(const unsigned char *k) {
  int i;
  printf("0");
  for (i = 0; i < 16; ++i)
    printf("+%u*256^%d", 255 & (int)k[i], i);
}
```
user: What is the c source code of the assembly code below?

```asm
<print16>:
  endbr64
  push   %r12
  lea    D2(%rip),%r12
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x30,%edi
  push   %rbx
  xor    %ebx,%ebx
  call   <putchar@plt>
  xchg   %ax,%ax
L2:
  movzbl 0x0(%rbp,%rbx,1),%esi
  mov    %ebx,%edx
  mov    %r12,%rdi
  xor    %eax,%eax
  add    $0x1,%rbx
  call   <printf@plt>
  cmp    $0x10,%rbx
  jne    L2
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

tool_calls: name: unpack_data
arguments: label: D2
type_guessed: string

tool: D2: +%u*256^%d

assistant: ```c
void print16(const unsigned char *k) {
  int i;
  printf("0");
  for (i = 0; i < 16; ++i)
    printf("+%u*256^%d", 255 & (int)k[i], i);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<my_puts>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    $0xa,%edi
  call   <outChar1@plt>
  mov    $0xd,%edi
  call   <outChar1@plt>
  jmp    L11
L14:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  movsbl %al,%eax
  mov    %eax,%edi
  call   <outChar1@plt>
  addq   $0x1,-0x8(%rbp)
L11:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L14
  nop
  nop
  leave
  ret
```

assistant: ```c
void my_puts(char *str) {
  outChar1('\n');
  outChar1('\r');
  while (*str) {
    outChar1(*str);
    str++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<my_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <outChar1@plt>
  mov    $0xd,%edi
  call   <outChar1@plt>
  movzbl (%rbx),%edi
  test   %dil,%dil
  je     L4
L3:
  movsbl %dil,%edi
  call   <outChar1@plt>
  add    $0x1,%rbx
  movzbl (%rbx),%edi
  test   %dil,%dil
  jne    L3
L4:
  pop    %rbx
  ret
```

assistant: ```c
void my_puts(char *str) {
  outChar1('\n');
  outChar1('\r');
  while (*str) {
    outChar1(*str);
    str++;
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<my_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <outChar1@plt>
  mov    $0xd,%edi
  call   <outChar1@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L3
  nopl   0x0(%rax)
L14:
  call   <outChar1@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L14
L3:
  pop    %rbx
  ret
```

assistant: ```c
void my_puts(char *str) {
  outChar1('\n');
  outChar1('\r');
  while (*str) {
    outChar1(*str);
    str++;
  }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<my_puts>:
  endbr64
  push   %rbx
  mov    %rdi,%rbx
  mov    $0xa,%edi
  call   <outChar1@plt>
  mov    $0xd,%edi
  call   <outChar1@plt>
  movsbl (%rbx),%edi
  test   %dil,%dil
  je     L14
  nopl   0x0(%rax)
L9:
  call   <outChar1@plt>
  movsbl 0x1(%rbx),%edi
  add    $0x1,%rbx
  test   %dil,%dil
  jne    L9
L14:
  pop    %rbx
  ret
```

assistant: ```c
void my_puts(char *str) {
  outChar1('\n');
  outChar1('\r');
  while (*str) {
    outChar1(*str);
    str++;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<CriticalPart2>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x24(%rbp)
  movsd  %xmm0,-0x30(%rbp)
  movsd  %xmm1,-0x38(%rbp)
  movsd  %xmm2,-0x40(%rbp)
  movsd  %xmm3,-0x48(%rbp)
  cmpl   $0x1,-0x24(%rbp)
  jne    L30
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movapd %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  D12(%rip),%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm3,%xmm2
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  movsd  %xmm1,-0x50(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm4
  subsd  -0x38(%rbp),%xmm4
  movq   %xmm4,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm5
  mulsd  -0x48(%rbp),%xmm5
  movapd %xmm5,%xmm1
  movsd  -0x50(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x8(%rbp)
  mov    -0x8(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L36
L30:
  cmpl   $0x2,-0x24(%rbp)
  jne    L6
  mov    -0x30(%rbp),%rax
  movq   %rax,%xmm0
  call   <log@plt>
  movq   %xmm0,%rax
  movq   D21(%rip),%xmm0
  movq   %rax,%xmm1
  xorpd  %xmm0,%xmm1
  movsd  -0x48(%rbp),%xmm0
  mulsd  %xmm0,%xmm0
  movsd  D12(%rip),%xmm3
  movapd %xmm0,%xmm2
  divsd  %xmm3,%xmm2
  movsd  -0x40(%rbp),%xmm0
  subsd  -0x38(%rbp),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  movsd  %xmm1,-0x50(%rbp)
  movsd  -0x40(%rbp),%xmm0
  movapd %xmm0,%xmm6
  subsd  -0x38(%rbp),%xmm6
  movq   %xmm6,%rax
  movq   %rax,%xmm0
  call   <sqrt@plt>
  movq   %xmm0,%rax
  movq   %rax,%xmm7
  mulsd  -0x48(%rbp),%xmm7
  movapd %xmm7,%xmm1
  movsd  -0x50(%rbp),%xmm0
  divsd  %xmm1,%xmm0
  movsd  %xmm0,-0x10(%rbp)
  mov    -0x10(%rbp),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  movsd  %xmm0,-0x18(%rbp)
  jmp    L36
L6:
  call   <abort@plt>
L36:
  movsd  -0x18(%rbp),%xmm0
  movq   %xmm0,%rax
  movq   %rax,%xmm0
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: tag: D12
type_guessed: f64
name: extract_symbolic_data
arguments: tag: D21
type_guessed: byte[8]

tool: D12: 2

tool: {"D21": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80]}

assistant: ```c
double CriticalPart2(int id, double I, double t1, double T2, double v) {
  double result;
  if (id == 1) {
    const double z1 = (log(I) + ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = cnd(z1);
  } else if (id == 2) {
    const double z2 = (-log(I) - ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = -cnd(z2);
  } else
    abort();
  return result;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<CriticalPart2>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x18,%rsp
  movq   %xmm1,%rbp
  movq   %xmm2,%rbx
  movsd  %xmm3,0x8(%rsp)
  cmp    $0x1,%edi
  je     L58
  cmp    $0x2,%edi
  jne    L41
  call   <log@plt>
  movq   %rbx,%xmm2
  movq   %rbp,%xmm5
  subsd  %xmm5,%xmm2
  xorpd  D25(%rip),%xmm0
  movsd  0x8(%rsp),%xmm4
  movapd %xmm4,%xmm1
  mulsd  %xmm4,%xmm1
  mulsd  D16(%rip),%xmm1
  mulsd  %xmm2,%xmm1
  subsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L56
  sqrtsd %xmm2,%xmm2
L22:
  movsd  0x8(%rsp),%xmm1
  mulsd  %xmm2,%xmm1
  movq   %rbx,%xmm0
  divsd  %xmm1,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  neg    %eax
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
L66:
  add    $0x18,%rsp
  pop    %rbx
  pop    %rbp
  ret
L58:
  call   <log@plt>
  movapd %xmm0,%xmm1
  movq   %rbx,%xmm2
  movq   %rbp,%xmm7
  subsd  %xmm7,%xmm2
  movsd  0x8(%rsp),%xmm6
  movapd %xmm6,%xmm0
  mulsd  %xmm6,%xmm0
  mulsd  D16(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm1,%xmm0
  movq   %xmm0,%rbx
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L36
  sqrtsd %xmm2,%xmm2
L59:
  mulsd  0x8(%rsp),%xmm2
  movq   %rbx,%xmm0
  divsd  %xmm2,%xmm0
  mov    $0x1,%eax
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  cvtsi2sd %eax,%xmm0
  jmp    L66
L36:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L59
L56:
  movapd %xmm2,%xmm0
  call   <sqrt@plt>
  movapd %xmm0,%xmm2
  jmp    L22
L41:
  call   <abort@plt>
```

tool_calls: name: disassemble_data
arguments: data_label: D25
data_type: byte[16]
name: disassemble_data
arguments: data_label: D16
data_type: byte[8]

tool: {"D25": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D16": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double CriticalPart2(int id, double I, double t1, double T2, double v) {
  double result;
  if (id == 1) {
    const double z1 = (log(I) + ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = cnd(z1);
  } else if (id == 2) {
    const double z2 = (-log(I) - ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = -cnd(z2);
  } else
    abort();
  return result;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<CriticalPart2>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  cmp    $0x1,%edi
  je     L39
  cmp    $0x2,%edi
  jne    10c0 <CriticalPart2.cold>
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm2
  xorpd  D23(%rip),%xmm1
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  D22(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L10
  sqrtsd %xmm2,%xmm2
L36:
  mulsd  %xmm2,%xmm3
  mov    $0x1,%eax
  divsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  add    $0x28,%rsp
  neg    %eax
  cvtsi2sd %eax,%xmm0
  ret
  xchg   %ax,%ax
L39:
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm2
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  D22(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L48
  sqrtsd %xmm2,%xmm2
L2:
  mulsd  %xmm3,%xmm2
  mov    $0x1,%eax
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  add    $0x28,%rsp
  cvtsi2sd %eax,%xmm0
  ret
L10:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L36
L48:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L2
```

tool_calls: name: unpack_data
arguments: data_tag: D23
type_infered: byte[16]
name: unpack_data
arguments: data_tag: D22
type_infered: byte[8]

tool: {"D23": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double CriticalPart2(int id, double I, double t1, double T2, double v) {
  double result;
  if (id == 1) {
    const double z1 = (log(I) + ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = cnd(z1);
  } else if (id == 2) {
    const double z2 = (-log(I) - ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = -cnd(z2);
  } else
    abort();
  return result;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<CriticalPart2>:
  endbr64
  sub    $0x28,%rsp
  movsd  %xmm1,0x8(%rsp)
  movsd  %xmm3,0x18(%rsp)
  movsd  %xmm2,0x10(%rsp)
  cmp    $0x1,%edi
  je     L41
  cmp    $0x2,%edi
  jne    10c0 <CriticalPart2.cold>
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm2
  xorpd  D8(%rip),%xmm1
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  D22(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  subsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L31
  sqrtsd %xmm2,%xmm2
L24:
  mulsd  %xmm2,%xmm3
  mov    $0x1,%eax
  divsd  %xmm3,%xmm1
  movapd %xmm1,%xmm0
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  add    $0x28,%rsp
  neg    %eax
  cvtsi2sd %eax,%xmm0
  ret
  xchg   %ax,%ax
L41:
  call   <log@plt>
  movsd  0x18(%rsp),%xmm3
  movsd  0x10(%rsp),%xmm2
  movapd %xmm0,%xmm1
  subsd  0x8(%rsp),%xmm2
  movapd %xmm3,%xmm0
  mulsd  %xmm3,%xmm0
  mulsd  D22(%rip),%xmm0
  mulsd  %xmm2,%xmm0
  addsd  %xmm0,%xmm1
  pxor   %xmm0,%xmm0
  ucomisd %xmm2,%xmm0
  ja     L22
  sqrtsd %xmm2,%xmm2
L19:
  mulsd  %xmm3,%xmm2
  mov    $0x1,%eax
  divsd  %xmm2,%xmm1
  movapd %xmm1,%xmm0
  call   <cnd@plt>
  pxor   %xmm0,%xmm0
  add    $0x28,%rsp
  cvtsi2sd %eax,%xmm0
  ret
L31:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L24
L22:
  movapd %xmm2,%xmm0
  movsd  %xmm3,0x10(%rsp)
  movsd  %xmm1,0x8(%rsp)
  call   <sqrt@plt>
  movsd  0x10(%rsp),%xmm3
  movsd  0x8(%rsp),%xmm1
  movapd %xmm0,%xmm2
  jmp    L19
```

tool_calls: name: extract_symbolic_data
arguments: label: D8
data_type: byte[16]
name: extract_symbolic_data
arguments: label: D22
data_type: byte[8]

tool: {"D8": [0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: {"D22": [0x00,0x00,0x00,0x00,0x00,0x00,0xe0,0x3f]}

assistant: ```c
double CriticalPart2(int id, double I, double t1, double T2, double v) {
  double result;
  if (id == 1) {
    const double z1 = (log(I) + ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = cnd(z1);
  } else if (id == 2) {
    const double z2 = (-log(I) - ((v) * (v)) / 2.0 * (T2 - t1)) / (v * sqrt(T2 - t1));
    result = -cnd(z2);
  } else
    abort();
  return result;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  movl   $0x5,-0x14(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,-0x10(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rcx
  mov    $0xffffffffffffffff,%rax
  mov    $0x0,%edx
  div    %rcx
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x10(%rbp),%rax
  mov    %rax,%rsi
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    -0x10(%rbp),%rax
  cmp    -0x8(%rbp),%rax
  je     L9
  mov    $0x1,%esi
  lea    D18(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  mov    $0x1,%edi
  call   <exit@plt>
L9:
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  leave
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D4
type_infered: string
name: disassemble_data
arguments: tag: D18
type_infered: string
name: disassemble_data
arguments: tag: D14
type_infered: string

tool: D4: Result is %ld. Correct=%ld


tool: D18: Error %d


tool: D14: Success

assistant: ```c
int main() {
  int base = 5;
  unsigned long max_over_base = (unsigned long)-1 / base;
  unsigned long correct = ((unsigned long)-1) / base;
  printf("Result is %ld. Correct=%ld\n", max_over_base, correct);
  if (max_over_base != correct) {
    printf("Error %d\n", (int)1);
    exit(1);
  };
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<main>:
  endbr64
  sub    $0x8,%rsp
  movabs $0x3333333333333333,%rsi
  mov    %rsi,%rdx
  lea    D3(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  lea    D8(%rip),%rdi
  call   <puts@plt>
  mov    $0x0,%edi
  call   <exit@plt>
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D3
type_guessed: string
name: disassemble_data
arguments: tag: D8
type_guessed: string

tool: D3: Result is %ld. Correct=%ld


tool: D8: Success

assistant: ```c
int main() {
  int base = 5;
  unsigned long max_over_base = (unsigned long)-1 / base;
  unsigned long correct = ((unsigned long)-1) / base;
  printf("Result is %ld. Correct=%ld\n", max_over_base, correct);
  if (max_over_base != correct) {
    printf("Error %d\n", (int)1);
    exit(1);
  };
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  movabs $0x3333333333333333,%rsi
  sub    $0x8,%rsp
  lea    D16(%rip),%rdi
  xor    %eax,%eax
  mov    %rsi,%rdx
  call   <printf@plt>
  lea    D14(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D16
type: string
name: parse_data
arguments: data_label: D14
type: string

tool: D16: Result is %ld. Correct=%ld


tool: D14: Success

assistant: ```c
int main() {
  int base = 5;
  unsigned long max_over_base = (unsigned long)-1 / base;
  unsigned long correct = ((unsigned long)-1) / base;
  printf("Result is %ld. Correct=%ld\n", max_over_base, correct);
  if (max_over_base != correct) {
    printf("Error %d\n", (int)1);
    exit(1);
  };
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<main>:
  endbr64
  movabs $0x3333333333333333,%rsi
  sub    $0x8,%rsp
  lea    D2(%rip),%rdi
  xor    %eax,%eax
  mov    %rsi,%rdx
  call   <printf@plt>
  lea    D17(%rip),%rdi
  call   <puts@plt>
  xor    %edi,%edi
  call   <exit@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: disassemble_data
arguments: data_tag: D2
datatype: string
name: disassemble_data
arguments: data_tag: D17
datatype: string

tool: D2: Result is %ld. Correct=%ld


tool: D17: Success

assistant: ```c
int main() {
  int base = 5;
  unsigned long max_over_base = (unsigned long)-1 / base;
  unsigned long correct = ((unsigned long)-1) / base;
  printf("Result is %ld. Correct=%ld\n", max_over_base, correct);
  if (max_over_base != correct) {
    printf("Error %d\n", (int)1);
    exit(1);
  };
  {
    printf("Success\n");
    exit(0);
  };
}
```
user: 请将这段汇编代码片段转换成等效的C代码：

```asm
<secreteLibSSLError>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    D4(%rip),%rax
  mov    (%rax),%eax
  mov    %eax,%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  nop
  pop    %rbp
  ret
```

assistant: ```c
void secreteLibSSLError(void) {
  ERR_print_errors_fp(stderr);
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<secreteLibSSLError>:
  endbr64
  sub    $0x8,%rsp
  mov    D2(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  mov    $0x0,%eax
  call   <abort@plt>
  add    $0x8,%rsp
  ret
```

assistant: ```c
void secreteLibSSLError(void) {
  ERR_print_errors_fp(stderr);
  abort();
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<secreteLibSSLError>:
  endbr64
  sub    $0x8,%rsp
  mov    D7(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

assistant: ```c
void secreteLibSSLError(void) {
  ERR_print_errors_fp(stderr);
  abort();
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<secreteLibSSLError>:
  endbr64
  sub    $0x8,%rsp
  mov    D3(%rip),%rax
  mov    (%rax),%edi
  call   <ERR_print_errors_fp@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  jmp    1060 <abort@plt>
```

assistant: ```c
void secreteLibSSLError(void) {
  ERR_print_errors_fp(stderr);
  abort();
}
```
user: What is the c source code of the assembly code below:

```asm
<swap>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  je     L4
  mov    -0x1c(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%eax
  mov    %eax,-0x4(%rbp)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    -0x1c(%rbp),%edx
  movslq %edx,%rdx
  lea    0x0(,%rdx,4),%rcx
  mov    -0x18(%rbp),%rdx
  add    %rcx,%rdx
  mov    (%rax),%eax
  mov    %eax,(%rdx)
  mov    -0x20(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x4(%rbp),%eax
  mov    %eax,(%rdx)
  jmp    L14
L4:
  nop
L14:
  pop    %rbp
  ret
```

assistant: ```c
void swap(int nums[], int a, int b) {
  if (a == b)
    return;
  int tmp = nums[a];
  nums[a] = nums[b];
  nums[b] = tmp;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<swap>:
  endbr64
  cmp    %edx,%esi
  je     L1
  movslq %esi,%rsi
  lea    (%rdi,%rsi,4),%rcx
  mov    (%rcx),%esi
  movslq %edx,%rdx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
L1:
  ret
```

assistant: ```c
void swap(int nums[], int a, int b) {
  if (a == b)
    return;
  int tmp = nums[a];
  nums[a] = nums[b];
  nums[b] = tmp;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<swap>:
  endbr64
  cmp    %edx,%esi
  je     L0
  movslq %esi,%rsi
  movslq %edx,%rdx
  lea    (%rdi,%rsi,4),%rcx
  lea    (%rdi,%rdx,4),%rax
  mov    (%rcx),%esi
  mov    (%rax),%edx
  mov    %edx,(%rcx)
  mov    %esi,(%rax)
L0:
  ret
```

assistant: ```c
void swap(int nums[], int a, int b) {
  if (a == b)
    return;
  int tmp = nums[a];
  nums[a] = nums[b];
  nums[b] = tmp;
}
```