user: 请从给定的汇编指令推导出C源代码:

```asm
<test>:
  endbr64
  push   %r15
  lea    D4(%rip),%r15
  push   %r14
  lea    D15(%rip),%r14
  push   %r13
  mov    %r14,%rdi
  lea    D171(%rip),%r13
  push   %r12
  lea    D32(%rip),%r12
  push   %rbp
  lea    D64(%rip),%rbp
  push   %rbx
  lea    D174(%rip),%rbx
  sub    $0x8,%rsp
  mov    D175(%rip),%rax
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  mov    %r13,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  mov    %r12,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  mov    %rbp,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  lea    D84(%rip),%r9
  mov    %r9,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  lea    D137(%rip),%r8
  mov    %r8,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  mov    %rbx,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  mov    D175(%rip),%rax
  mov    %r15,%rdi
  movq   %rax,%xmm0
  mov    $0x1,%eax
  call   <printf@plt>
  xor    %esi,%esi
  mov    %r14,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %esi,%esi
  mov    %r13,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %esi,%esi
  mov    %r12,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  xor    %esi,%esi
  mov    %rbp,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  lea    D84(%rip),%r9
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %r9,%rdi
  call   <scanf@plt>
  lea    D137(%rip),%r8
  xor    %esi,%esi
  xor    %eax,%eax
  mov    %r8,%rdi
  call   <scanf@plt>
  xor    %esi,%esi
  mov    %rbx,%rdi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r15,%rdi
  xor    %esi,%esi
  xor    %eax,%eax
  call   <scanf@plt>
  mov    %r14,%rdi
  mov    $0x2a,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r13,%rdi
  mov    $0x2a,%esi
  xor    %eax,%eax
  call   <printf@plt>
  mov    %r12,%rdi
  mov    $0x2a,%esi
  xor    %eax,%eax
  call   <printf@plt>
  add    $0x8,%rsp
  mov    %rbp,%rdi
  xor    %eax,%eax
  pop    %rbx
  mov    $0x2a,%esi
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  jmp    1060 <printf@plt>
```

tool_calls: name: read_data
arguments: tag: D4
type_infered: string
name: read_data
arguments: tag: D15
type_infered: string
name: read_data
arguments: tag: D171
type_infered: string
name: read_data
arguments: tag: D32
type_infered: string
name: read_data
arguments: tag: D64
type_infered: string
name: read_data
arguments: tag: D174
type_infered: string
name: read_data
arguments: tag: D175
type_infered: f64
name: read_data
arguments: tag: D84
type_infered: string
name: read_data
arguments: tag: D137
type_infered: string

tool: D4: %C

tool: D15: %jd

tool: D171: %ju

tool: D32: %zu

tool: D64: %td

tool: D174: %S

tool: D175: 42

tool: D84: %lc

tool: D137: %ls

assistant: ```c
void test(void) {
  printf("%jd", 42.0);
  printf("%ju", 42.0);
  printf("%zu", 42.0);
  printf("%td", 42.0);
  printf("%lc", 42.0);
  printf("%ls", 42.0);
  printf("%S", 42.0);
  printf("%C", 42.0);
  scanf("%jd", 0);
  scanf("%ju", 0);
  scanf("%zu", 0);
  scanf("%td", 0);
  scanf("%lc", 0);
  scanf("%ls", 0);
  scanf("%S", 0);
  scanf("%C", 0);
  typedef void *size_t;
  typedef void *intmax_t;
  typedef void *uintmax_t;
  typedef void *ptrdiff_t;
  printf("%jd", (intmax_t)42);
  printf("%ju", (uintmax_t)42);
  printf("%zu", (size_t)42);
  printf("%td", (ptrdiff_t)42);
}
```