ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D15(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %eax,%eax
  je     L16
  lea    0x20(%rsp),%rax
  lea    0x18(%rsp),%r15
  mov    %rax,(%rsp)
  lea    0x28(%rsp),%rax
  lea    0x1b4(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    D8(%rip),%r13
L10:
  mov    %rbx,%rdi
  mov    %r15,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  xor    %eax,%eax
  mov    $0x33,%ecx
  rep stos %rax,%es:(%rdi)
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L7
  xor    %r14d,%r14d
  lea    0x1c(%rsp),%rbp
  nopl   0x0(%rax,%rax,1)
L27:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <scanf@plt>
  movslq 0x1c(%rsp),%rax
  movl   $0x1,0x20(%rsp,%rax,4)
  cmp    %r14d,0x18(%rsp)
  jg     L27
  mov    0x24(%rsp),%edx
L2:
  mov    0x8(%rsp),%rax
  xor    %esi,%esi
  jmp    L35
  nopl   0x0(%rax,%rax,1)
L44:
  mov    (%rax),%edx
  add    $0x4,%rax
L35:
  cmp    $0x1,%edx
  sbb    $0xffffffff,%esi
  cmp    %r12,%rax
  jne    L44
  mov    %r13,%rdi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %eax,%eax
  jne    L10
L16:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L73
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L7:
  xor    %edx,%edx
  jmp    L2
L73:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: data_tag: D15
data_type: string
name: retrieve_data
arguments: data_tag: D8
data_type: string

tool: D15: %d

tool: D8: %d


assistant: ```c
int main() {
  int t;
  int n, i, j, ele, count;
  scanf("%d", &t);
  while (t--) {
    count = 0;
    scanf("%d", &n);
    int arr[102] = {0};
    for (i = 0; i < n; ++i) {
      scanf("%d", &ele);
      arr[ele] = 1;
    }
    for (i = 1; i <= 100; i++)
      if (arr[i] != 0)
        count++;
    printf("%d\n", count);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<main>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    D19(%rip),%rbx
  mov    %rbx,%rdi
  sub    $0x1c8,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x1b8(%rsp)
  xor    %eax,%eax
  lea    0x14(%rsp),%rsi
  call   <scanf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%edx
  mov    %edx,0x14(%rsp)
  test   %eax,%eax
  je     L34
  lea    0x20(%rsp),%rax
  lea    0x18(%rsp),%r15
  mov    %rax,(%rsp)
  lea    0x24(%rsp),%rax
  lea    0x1b4(%rsp),%r12
  mov    %rax,0x8(%rsp)
  lea    D14(%rip),%r13
L15:
  mov    %rbx,%rdi
  mov    %r15,%rsi
  call   <scanf@plt>
  mov    (%rsp),%rdi
  xor    %eax,%eax
  mov    $0x33,%ecx
  rep stos %rax,%es:(%rdi)
  mov    0x18(%rsp),%eax
  test   %eax,%eax
  jle    L30
  xor    %r14d,%r14d
  lea    0x1c(%rsp),%rbp
  nop
L14:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  add    $0x1,%r14d
  call   <scanf@plt>
  movslq 0x1c(%rsp),%rax
  movl   $0x1,0x20(%rsp,%rax,4)
  cmp    %r14d,0x18(%rsp)
  jg     L14
L30:
  pxor   %xmm1,%xmm1
  mov    0x8(%rsp),%rax
  movdqa %xmm1,%xmm2
L4:
  movdqu (%rax),%xmm0
  add    $0x10,%rax
  pcmpeqd %xmm2,%xmm0
  pcmpeqd %xmm2,%xmm0
  psubd  %xmm0,%xmm1
  cmp    %rax,%r12
  jne    L4
  movdqa %xmm1,%xmm0
  mov    %r13,%rdi
  psrldq $0x8,%xmm0
  paddd  %xmm0,%xmm1
  movdqa %xmm1,%xmm0
  psrldq $0x4,%xmm0
  paddd  %xmm0,%xmm1
  movd   %xmm1,%esi
  call   <printf@plt>
  mov    0x14(%rsp),%eax
  lea    -0x1(%rax),%ecx
  mov    %ecx,0x14(%rsp)
  test   %eax,%eax
  jne    L15
L34:
  mov    0x1b8(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L57
  add    $0x1c8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L57:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: unpack_data
arguments: data_tag: D19
data_type: string
name: unpack_data
arguments: data_tag: D14
data_type: string

tool: D19: %d

tool: D14: %d


assistant: ```c
int main() {
  int t;
  int n, i, j, ele, count;
  scanf("%d", &t);
  while (t--) {
    count = 0;
    scanf("%d", &n);
    int arr[102] = {0};
    for (i = 0; i < n; ++i) {
      scanf("%d", &ele);
      arr[ele] = 1;
    }
    for (i = 1; i <= 100; i++)
      if (arr[i] != 0)
        count++;
    printf("%d\n", count);
  }
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<erealloc>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x10(%rbp),%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <realloc@plt>
  mov    %rax,-0x8(%rbp)
  cmpq   $0x0,-0x8(%rbp)
  jne    L1
  lea    D7(%rip),%rax
  mov    %rax,%rsi
  mov    $0x1,%edi
  call   <die@plt>
L1:
  mov    -0x8(%rbp),%rax
  leave
  ret
```

tool_calls: name: read_data
arguments: data_tag: D7
type_guessed: string

tool: D7: realloc:

assistant: ```c
void *erealloc(void *p, size_t size) {
  if (!(p = realloc(p, size)))
    die(1, "realloc:");
  return p;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<erealloc>:
  endbr64
  push   %rbx
  call   <realloc@plt>
  mov    %rax,%rbx
  test   %rax,%rax
  je     L16
L11:
  mov    %rbx,%rax
  pop    %rbx
  ret
L16:
  lea    D1(%rip),%rsi
  mov    $0x1,%edi
  call   <die@plt>
  jmp    L11
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D1
type_infered: string

tool: D1: realloc:

assistant: ```c
void *erealloc(void *p, size_t size) {
  if (!(p = realloc(p, size)))
    die(1, "realloc:");
  return p;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<erealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L19
L15:
  mov    %r12,%rax
  pop    %r12
  ret
L19:
  lea    D5(%rip),%rsi
  mov    $0x1,%edi
  call   <die@plt>
  jmp    L15
```

tool_calls: name: disassemble_data
arguments: tag: D5
type_guessed: string

tool: D5: realloc:

assistant: ```c
void *erealloc(void *p, size_t size) {
  if (!(p = realloc(p, size)))
    die(1, "realloc:");
  return p;
}
```
user: Translate the below assembly code into C programming language:

```asm
<erealloc>:
  endbr64
  push   %r12
  call   <realloc@plt>
  mov    %rax,%r12
  test   %rax,%rax
  je     L15
L19:
  mov    %r12,%rax
  pop    %r12
  ret
L15:
  lea    D9(%rip),%rsi
  mov    $0x1,%edi
  call   <die@plt>
  jmp    L19
```

tool_calls: name: parse_data
arguments: label: D9
type_guessed: string

tool: D9: realloc:

assistant: ```c
void *erealloc(void *p, size_t size) {
  if (!(p = realloc(p, size)))
    die(1, "realloc:");
  return p;
}
```
user: What is the c source code of the assembly code below?

```asm
<stampa_quaterna_se_idonea>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %edx,-0x20(%rbp)
  movl   $0x0,-0x4(%rbp)
  mov    -0x1c(%rbp),%eax
  cmp    -0x20(%rbp),%eax
  jge    L8
  mov    $0x4,%edi
  call   <messaggi@plt>
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <stampa_quaterne@plt>
  movl   $0x1,-0x4(%rbp)
L8:
  mov    -0x4(%rbp),%eax
  leave
  ret
```

assistant: ```c
int stampa_quaterna_se_idonea(int quaterna[], int prodotto_quaterna, int media_elementi_vettore) {
  int esito = 0;
  if (prodotto_quaterna < media_elementi_vettore) {
    messaggi(4);
    stampa_quaterne(quaterna);
    esito = 1;
  }
  return (esito);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<stampa_quaterna_se_idonea>:
  endbr64
  mov    $0x0,%eax
  cmp    %edx,%esi
  jl     L6
  ret
L6:
  push   %rbx
  mov    %rdi,%rbx
  mov    $0x4,%edi
  call   <messaggi@plt>
  mov    %rbx,%rdi
  call   <stampa_quaterne@plt>
  mov    $0x1,%eax
  pop    %rbx
  ret
```

assistant: ```c
int stampa_quaterna_se_idonea(int quaterna[], int prodotto_quaterna, int media_elementi_vettore) {
  int esito = 0;
  if (prodotto_quaterna < media_elementi_vettore) {
    messaggi(4);
    stampa_quaterne(quaterna);
    esito = 1;
  }
  return (esito);
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<stampa_quaterna_se_idonea>:
  endbr64
  cmp    %edx,%esi
  jl     L6
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L6:
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <messaggi@plt>
  mov    %rbp,%rdi
  call   <stampa_quaterne@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stampa_quaterna_se_idonea(int quaterna[], int prodotto_quaterna, int media_elementi_vettore) {
  int esito = 0;
  if (prodotto_quaterna < media_elementi_vettore) {
    messaggi(4);
    stampa_quaterne(quaterna);
    esito = 1;
  }
  return (esito);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<stampa_quaterna_se_idonea>:
  endbr64
  cmp    %edx,%esi
  jl     L2
  xor    %eax,%eax
  ret
  nopl   0x0(%rax,%rax,1)
L2:
  push   %rbp
  mov    %rdi,%rbp
  mov    $0x4,%edi
  call   <messaggi@plt>
  mov    %rbp,%rdi
  call   <stampa_quaterne@plt>
  mov    $0x1,%eax
  pop    %rbp
  ret
```

assistant: ```c
int stampa_quaterna_se_idonea(int quaterna[], int prodotto_quaterna, int media_elementi_vettore) {
  int esito = 0;
  if (prodotto_quaterna < media_elementi_vettore) {
    messaggi(4);
    stampa_quaterne(quaterna);
    esito = 1;
  }
  return (esito);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  movabs $0xfffffff800000000,%rax
  mov    %rax,-0x20(%rbp)
  lea    D4(%rip),%rax
  mov    %rax,%rdi
  call   <sys_puts@plt>
  mov    -0x20(%rbp),%rcx
  lea    -0x12(%rbp),%rax
  mov    $0xa,%edx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <memcpy@plt>
  lea    D13(%rip),%rax
  mov    %rax,%rdi
  call   <sys_puts@plt>
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L5
  call   <__stack_chk_fail@plt>
L5:
  leave
  ret
```

tool_calls: name: read_data
arguments: tag: D4
type: string
name: read_data
arguments: tag: D13
type: string

tool: D4: before read


tool: D13: after read

assistant: ```c
int main(void) {
  char *kernel = (char *)0xFFFFFFF800000000;
  char buffer[10];
  sys_puts("before read\n");
  memcpy(buffer, kernel, sizeof(buffer));
  sys_puts("after read");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    D10(%rip),%rdi
  call   <sys_puts@plt>
  lea    0xe(%rsp),%rdi
  mov    $0xa,%edx
  movabs $0xfffffff800000000,%rsi
  call   <memcpy@plt>
  lea    D2(%rip),%rdi
  call   <sys_puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L9
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L9:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D10
data_type: string
name: read_data
arguments: label: D2
data_type: string

tool: D10: before read


tool: D2: after read

assistant: ```c
int main(void) {
  char *kernel = (char *)0xFFFFFFF800000000;
  char buffer[10];
  sys_puts("before read\n");
  memcpy(buffer, kernel, sizeof(buffer));
  sys_puts("after read");
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D15(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <sys_puts@plt>
  lea    0xe(%rsp),%rdi
  mov    $0xa,%edx
  movabs $0xfffffff800000000,%rsi
  call   <memcpy@plt>
  lea    D16(%rip),%rdi
  call   <sys_puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L7
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L7:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D15
datatype: string
name: retrieve_data
arguments: label: D16
datatype: string

tool: D15: before read


tool: D16: after read

assistant: ```c
int main(void) {
  char *kernel = (char *)0xFFFFFFF800000000;
  char buffer[10];
  sys_puts("before read\n");
  memcpy(buffer, kernel, sizeof(buffer));
  sys_puts("after read");
  return 0;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D19(%rip),%rdi
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  call   <sys_puts@plt>
  lea    0xe(%rsp),%rdi
  mov    $0xa,%edx
  movabs $0xfffffff800000000,%rsi
  call   <memcpy@plt>
  lea    D7(%rip),%rdi
  call   <sys_puts@plt>
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L4
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L4:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: data_tag: D19
datatype: string
name: read_data
arguments: data_tag: D7
datatype: string

tool: D19: before read


tool: D7: after read

assistant: ```c
int main(void) {
  char *kernel = (char *)0xFFFFFFF800000000;
  char buffer[10];
  sys_puts("before read\n");
  memcpy(buffer, kernel, sizeof(buffer));
  sys_puts("after read");
  return 0;
}
```
user: Translate the below assembly code into C programming language:

```asm
<post2dictionary_fetch>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  lea    -0x20000(%rsp),%r11
L27:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L27
  sub    $0x30,%rsp
  mov    %rdi,-0x20018(%rbp)
  mov    %rsi,-0x20020(%rbp)
  mov    %rdx,-0x20028(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  mov    -0x20018(%rbp),%rax
  movb   $0x0,(%rax)
  jmp    L64
L23:
  mov    -0x20028(%rbp),%rdx
  lea    -0x20010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <timlib_strncmp@plt>
  test   %rax,%rax
  je     L87
  movzbl -0x20010(%rbp),%eax
  test   %al,%al
  jne    L22
  jmp    L64
L22:
  lea    -0x20010(%rbp),%rax
  lea    D4(%rip),%rdx
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  jne    L48
  jmp    L64
L48:
  lea    -0x20010(%rbp),%rdx
  mov    -0x20018(%rbp),%rax
  lea    D1(%rip),%rcx
  mov    %rcx,%rsi
  mov    %rax,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,-0x20018(%rbp)
L64:
  mov    -0x20020(%rbp),%rdx
  lea    -0x20010(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  jne    L23
  jmp    L29
L87:
  nop
L29:
  nop
  mov    -0x8(%rbp),%rax
  sub    %fs:0x28,%rax
  je     L57
  call   <__stack_chk_fail@plt>
L57:
  leave
  ret
```

tool_calls: name: extract_symbolic_data
arguments: label: D4
type: string
name: extract_symbolic_data
arguments: label: D1
type: string

tool: D4: select

tool: D1: %s

assistant: ```c
void post2dictionary_fetch(char *destination, FILE *input_stream, char *post_key) {
  char input_buffer[131072];
  *destination = '\0';
  while (get_line(input_buffer, input_stream)) {
    if (timlib_strncmp(input_buffer, post_key) == 0)
      break;
    if (!*input_buffer)
      continue;
    if (strcmp(input_buffer, "select") == 0)
      continue;
    destination += sprintf(destination, "%s", input_buffer);
  }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<post2dictionary_fetch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L62:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L62
  sub    $0x18,%rsp
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rdi)
  lea    D17(%rip),%r14
  mov    %rsp,%rbx
  lea    D0(%rip),%r15
L57:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  je     L67
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <timlib_strncmp@plt>
  test   %rax,%rax
  je     L67
  cmpb   $0x0,(%rsp)
  je     L57
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L57
  mov    %rbx,%rdx
  mov    %r15,%rsi
  mov    %r13,%rdi
  call   <sprintf@plt>
  cltq
  add    %rax,%r13
  jmp    L57
L67:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L68
  add    $0x20018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L68:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: tag: D17
type: string
name: parse_data
arguments: tag: D0
type: string

tool: D17: select

tool: D0: %s

assistant: ```c
void post2dictionary_fetch(char *destination, FILE *input_stream, char *post_key) {
  char input_buffer[131072];
  *destination = '\0';
  while (get_line(input_buffer, input_stream)) {
    if (timlib_strncmp(input_buffer, post_key) == 0)
      break;
    if (!*input_buffer)
      continue;
    if (strcmp(input_buffer, "select") == 0)
      continue;
    destination += sprintf(destination, "%s", input_buffer);
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<post2dictionary_fetch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L52:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L52
  sub    $0x18,%rsp
  lea    D7(%rip),%r14
  lea    D2(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rdi)
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rsp,%rbx
  nopl   0x0(%rax,%rax,1)
L28:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  je     L35
L12:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <timlib_strncmp@plt>
  test   %rax,%rax
  je     L35
  cmpb   $0x0,(%rsp)
  je     L28
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L28
  mov    %r13,%rdi
  mov    %r15,%rsi
  mov    %rbx,%rdx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  cltq
  add    %rax,%r13
  call   <get_line@plt>
  test   %rax,%rax
  jne    L12
  nopl   0x0(%rax)
L35:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L21
  add    $0x20018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L21:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: data_label: D7
type: string
name: parse_data
arguments: data_label: D2
type: string

tool: D7: select

tool: D2: %s

assistant: ```c
void post2dictionary_fetch(char *destination, FILE *input_stream, char *post_key) {
  char input_buffer[131072];
  *destination = '\0';
  while (get_line(input_buffer, input_stream)) {
    if (timlib_strncmp(input_buffer, post_key) == 0)
      break;
    if (!*input_buffer)
      continue;
    if (strcmp(input_buffer, "select") == 0)
      continue;
    destination += sprintf(destination, "%s", input_buffer);
  }
}
```
user: What would the C source look like for the assembly code provided here?

```asm
<post2dictionary_fetch>:
  endbr64
  push   %r15
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  lea    -0x20000(%rsp),%r11
L68:
  sub    $0x1000,%rsp
  orq    $0x0,(%rsp)
  cmp    %r11,%rsp
  jne    L68
  sub    $0x18,%rsp
  lea    D14(%rip),%r14
  lea    D10(%rip),%r15
  mov    %fs:0x28,%rax
  mov    %rax,0x20008(%rsp)
  xor    %eax,%eax
  movb   $0x0,(%rdi)
  mov    %rdi,%r13
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rsp,%rbx
  nopl   0x0(%rax,%rax,1)
L44:
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  call   <get_line@plt>
  test   %rax,%rax
  je     L10
L38:
  mov    %r12,%rsi
  mov    %rbx,%rdi
  call   <timlib_strncmp@plt>
  test   %rax,%rax
  je     L10
  cmpb   $0x0,(%rsp)
  je     L44
  mov    %r14,%rsi
  mov    %rbx,%rdi
  call   <strcmp@plt>
  test   %rax,%rax
  je     L44
  mov    %r13,%rdi
  mov    %r15,%rsi
  mov    %rbx,%rdx
  call   <sprintf@plt>
  mov    %rbp,%rsi
  mov    %rbx,%rdi
  cltq
  add    %rax,%r13
  call   <get_line@plt>
  test   %rax,%rax
  jne    L38
  nopl   0x0(%rax)
L10:
  mov    0x20008(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L12
  add    $0x20018,%rsp
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  pop    %r15
  ret
L12:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: retrieve_data
arguments: label: D14
data_type: string
name: retrieve_data
arguments: label: D10
data_type: string

tool: D14: select

tool: D10: %s

assistant: ```c
void post2dictionary_fetch(char *destination, FILE *input_stream, char *post_key) {
  char input_buffer[131072];
  *destination = '\0';
  while (get_line(input_buffer, input_stream)) {
    if (timlib_strncmp(input_buffer, post_key) == 0)
      break;
    if (!*input_buffer)
      continue;
    if (strcmp(input_buffer, "select") == 0)
      continue;
    destination += sprintf(destination, "%s", input_buffer);
  }
}
```
user: 请将这段汇编代码片段转换成等效的C代码:

```asm
<distribute_bits>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  mov    %esi,-0x18(%rbp)
  movl   $0x0,-0xc(%rbp)
  movl   $0x0,-0x4(%rbp)
  movl   $0x0,-0x8(%rbp)
  jmp    L7
L14:
  mov    -0x4(%rbp),%eax
  mov    -0x14(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  jne    L18
  mov    -0x8(%rbp),%eax
  mov    -0x18(%rbp),%edx
  mov    %eax,%ecx
  sar    %cl,%edx
  mov    %edx,%eax
  and    $0x1,%eax
  test   %eax,%eax
  je     L15
  mov    -0x4(%rbp),%eax
  mov    $0x1,%edx
  mov    %eax,%ecx
  shl    %cl,%edx
  mov    %edx,%eax
  or     %eax,-0xc(%rbp)
L15:
  addl   $0x1,-0x8(%rbp)
L18:
  addl   $0x1,-0x4(%rbp)
L7:
  cmpl   $0xf,-0x4(%rbp)
  jle    L14
  mov    -0xc(%rbp),%eax
  pop    %rbp
  ret
```

assistant: ```c
uint16_t distribute_bits(uint16_t d, uint16_t n) {
  uint16_t res = 0;
  int in, id;
  for (id = 0, in = 0; id < 16; id++) {
    if (0 == (d & (1 << id))) {
      if (n & (1 << in))
        res |= 1 << id;
      in++;
    }
  }
  return res;
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<distribute_bits>:
  endbr64
  mov    $0x0,%ecx
  mov    $0x0,%eax
  mov    $0x0,%edx
  mov    $0x1,%r9d
  jmp    L44
L24:
  add    $0x1,%eax
L43:
  add    $0x1,%ecx
  cmp    $0x10,%ecx
  je     L8
L44:
  bt     %ecx,%edi
  jb     L43
  bt     %eax,%esi
  jae    L24
  mov    %r9d,%r8d
  shl    %cl,%r8d
  or     %r8d,%edx
  jmp    L24
L8:
  mov    %edx,%eax
  ret
```

assistant: ```c
uint16_t distribute_bits(uint16_t d, uint16_t n) {
  uint16_t res = 0;
  int in, id;
  for (id = 0, in = 0; id < 16; id++) {
    if (0 == (d & (1 << id))) {
      if (n & (1 << in))
        res |= 1 << id;
      in++;
    }
  }
  return res;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<distribute_bits>:
  endbr64
  xor    %ecx,%ecx
  xor    %eax,%eax
  xor    %r8d,%r8d
  mov    $0x1,%r9d
  nopl   0x0(%rax)
L7:
  bt     %ecx,%edi
  jb     L8
  bt     %eax,%esi
  jae    L10
  mov    %r9d,%edx
  shl    %cl,%edx
  or     %edx,%r8d
L10:
  add    $0x1,%eax
L8:
  add    $0x1,%ecx
  cmp    $0x10,%ecx
  jne    L7
  mov    %r8d,%eax
  ret
```

assistant: ```c
uint16_t distribute_bits(uint16_t d, uint16_t n) {
  uint16_t res = 0;
  int in, id;
  for (id = 0, in = 0; id < 16; id++) {
    if (0 == (d & (1 << id))) {
      if (n & (1 << in))
        res |= 1 << id;
      in++;
    }
  }
  return res;
}
```