ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 请将以下的汇编代码转换成C语言代码：

```asm
<ft_str_len>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
L59:
  mov    -0x8(%rbp),%rax
  mov    (%rax),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  movzbl %al,%eax
  test   %eax,%eax
  jne    L49
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  jmp    L44
L49:
  mov    -0xc(%rbp),%eax
  and    $0xff00,%eax
  test   %eax,%eax
  jne    L54
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x1,%rax
  jmp    L44
L54:
  mov    -0xc(%rbp),%eax
  and    $0xff0000,%eax
  test   %eax,%eax
  jne    L62
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x2,%rax
  jmp    L44
L62:
  mov    -0xc(%rbp),%eax
  and    $0xff000000,%eax
  test   %eax,%eax
  jne    L28
  mov    -0x8(%rbp),%rax
  sub    -0x18(%rbp),%rax
  add    $0x3,%rax
  jmp    L44
L28:
  addq   $0x4,-0x8(%rbp)
  jmp    L59
L44:
  pop    %rbp
  ret
```

assistant: ```c
unsigned long ft_str_len(const void *s) {
  unsigned x;
  char *buf;
  buf = (char *)s;
  while (1) {
    x = *(unsigned *)buf;
    if (!(x & 0xFF))
      return (buf - (char *)s);
    if (!(x & 0xFF00))
      return (buf - (char *)s + 1);
    if (!(x & 0xFF0000))
      return (buf - (char *)s + 2);
    if (!(x & 0xFF000000))
      return (buf - (char *)s + 3);
    buf += 4;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_str_len>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L9
L3:
  test   $0xff,%dh
  je     L46
  test   $0xff0000,%edx
  je     L41
  test   $0xff000000,%edx
  je     L24
  add    $0x4,%rax
  mov    (%rax),%edx
  test   %dl,%dl
  jne    L3
L9:
  sub    %rdi,%rax
  ret
L46:
  sub    %rdi,%rax
  add    $0x1,%rax
  ret
L41:
  sub    %rdi,%rax
  add    $0x2,%rax
  ret
L24:
  sub    %rdi,%rax
  add    $0x3,%rax
  ret
```

assistant: ```c
unsigned long ft_str_len(const void *s) {
  unsigned x;
  char *buf;
  buf = (char *)s;
  while (1) {
    x = *(unsigned *)buf;
    if (!(x & 0xFF))
      return (buf - (char *)s);
    if (!(x & 0xFF00))
      return (buf - (char *)s + 1);
    if (!(x & 0xFF0000))
      return (buf - (char *)s + 2);
    if (!(x & 0xFF000000))
      return (buf - (char *)s + 3);
    buf += 4;
  }
}
```
user: Translate the below assembly code into C programming language:

```asm
<ft_str_len>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L18
  jmp    L59
  nop
L3:
  test   $0xff0000,%edx
  je     L9
  and    $0xff000000,%edx
  je     L23
  mov    0x4(%rax),%edx
  add    $0x4,%rax
  test   %dl,%dl
  je     L20
L18:
  test   $0xff,%dh
  jne    L3
  sub    %rdi,%rax
  add    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L9:
  sub    %rdi,%rax
  add    $0x2,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  sub    %rdi,%rax
  add    $0x3,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L20:
  sub    %rdi,%rax
  ret
L59:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long ft_str_len(const void *s) {
  unsigned x;
  char *buf;
  buf = (char *)s;
  while (1) {
    x = *(unsigned *)buf;
    if (!(x & 0xFF))
      return (buf - (char *)s);
    if (!(x & 0xFF00))
      return (buf - (char *)s + 1);
    if (!(x & 0xFF0000))
      return (buf - (char *)s + 2);
    if (!(x & 0xFF000000))
      return (buf - (char *)s + 3);
    buf += 4;
  }
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<ft_str_len>:
  endbr64
  mov    (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  jne    L0
  jmp    L43
  nop
L56:
  test   $0xff0000,%edx
  je     L12
  and    $0xff000000,%edx
  je     L51
  mov    0x4(%rax),%edx
  add    $0x4,%rax
  test   %dl,%dl
  je     L23
L0:
  test   $0xff,%dh
  jne    L56
  sub    %rdi,%rax
  add    $0x1,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L12:
  sub    %rdi,%rax
  add    $0x2,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L51:
  sub    %rdi,%rax
  add    $0x3,%rax
  ret
  nopl   0x0(%rax,%rax,1)
L23:
  sub    %rdi,%rax
  ret
L43:
  xor    %eax,%eax
  ret
```

assistant: ```c
unsigned long ft_str_len(const void *s) {
  unsigned x;
  char *buf;
  buf = (char *)s;
  while (1) {
    x = *(unsigned *)buf;
    if (!(x & 0xFF))
      return (buf - (char *)s);
    if (!(x & 0xFF00))
      return (buf - (char *)s + 1);
    if (!(x & 0xFF0000))
      return (buf - (char *)s + 2);
    if (!(x & 0xFF000000))
      return (buf - (char *)s + 3);
    buf += 4;
  }
}
```
user: What is the c source code of the assembly code below:

```asm
<move_l>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x8(%rbp)
  mov    %rsi,-0x10(%rbp)
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shr    $0x9,%rax
  and    $0x7000,%eax
  mov    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shr    $0xc,%rax
  and    $0x7,%eax
  or     %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shl    $0x9,%rax
  and    $0xe00,%eax
  or     %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  shl    $0xc,%rax
  and    $0xe00000,%eax
  or     %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    (%rax),%rax
  and    $0x1f81f8,%eax
  or     %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rdx,(%rax)
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  shr    $0x6,%ax
  movzwl %ax,%eax
  and    $0x300,%eax
  lea    0x200(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    $0x7,%eax
  mov    %ecx,%esi
  sar    $0x1f,%esi
  sub    %esi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x8,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%esi
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  shr    $0x8,%ax
  movzwl %ax,%eax
  and    $0x3,%eax
  lea    0x1(%rax),%edx
  movslq %edx,%rax
  imul   $0x55555556,%rax,%rax
  shr    $0x20,%rax
  mov    %edx,%ecx
  sar    $0x1f,%ecx
  sub    %ecx,%eax
  mov    %eax,%ecx
  add    %ecx,%ecx
  add    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  or     %eax,%esi
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shl    $0x6,%eax
  movzbl %al,%eax
  lea    0x80(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    $0x5,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0x6,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  movzwl %ax,%eax
  shl    $0x8,%eax
  and    $0xc000,%eax
  lea    0x4000(%rax),%ecx
  movslq %ecx,%rax
  imul   $0x2aaaaaab,%rax,%rax
  shr    $0x20,%rax
  sar    $0xd,%eax
  mov    %ecx,%edi
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edx
  mov    %edx,%eax
  add    %eax,%eax
  add    %edx,%eax
  shl    $0xe,%eax
  sub    %eax,%ecx
  mov    %ecx,%edx
  mov    %edx,%eax
  or     %eax,%esi
  mov    %esi,%edx
  mov    -0x10(%rbp),%rax
  movzwl (%rax),%eax
  and    $0x3c3c,%ax
  or     %edx,%eax
  mov    %eax,%edx
  mov    -0x10(%rbp),%rax
  mov    %dx,(%rax)
  nop
  pop    %rbp
  ret
```

assistant: ```c
void move_l(unsigned long *p, unsigned short *o) {
  *p = (((*p) >> 9) & 070000) | (((*p) >> 12) & 07) | (((*p) << 9) & 07000) | (((*p) << 12) & 070000000) | ((*p) & 07700770);
  *o = (((((*o) >> 6) & 0x300) + 0x200) % 0x300) | (((((*o) >> 8) & 0x3) + 0x1) % 0x3) | (((((*o) << 6) & 0xc0) + 0x80) % 0xc0) | (((((*o) << 8) & 0xc000) + 0x4000) % 0xc000) | ((*o) & 0x3c3c);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<move_l>:
  endbr64
  mov    %rsi,%rcx
  mov    (%rdi),%rdx
  mov    %rdx,%rax
  shr    $0x9,%rax
  and    $0x7000,%eax
  mov    %rdx,%rsi
  shr    $0xc,%rsi
  and    $0x7,%esi
  or     %rsi,%rax
  mov    %rdx,%rsi
  and    $0x1f81f8,%esi
  or     %rsi,%rax
  mov    %rdx,%rsi
  shl    $0x9,%rsi
  and    $0xe00,%esi
  or     %rsi,%rax
  shl    $0xc,%rdx
  and    $0xe00000,%edx
  or     %rdx,%rax
  mov    %rax,(%rdi)
  movzwl (%rcx),%esi
  movzwl %si,%edx
  mov    %esi,%eax
  shr    $0x6,%ax
  and    $0x300,%eax
  lea    0x200(%rax),%eax
  movslq %eax,%rdi
  imul   $0x2aaaaaab,%rdi,%rdi
  sar    $0x27,%rdi
  lea    (%rdi,%rdi,2),%edi
  shl    $0x8,%edi
  sub    %edi,%eax
  mov    %esi,%edi
  shr    $0x8,%di
  and    $0x3,%edi
  lea    0x1(%rdi),%r8d
  movslq %r8d,%rdi
  imul   $0x55555556,%rdi,%rdi
  shr    $0x20,%rdi
  lea    (%rdi,%rdi,2),%edi
  sub    %edi,%r8d
  or     %r8d,%eax
  and    $0x3c3c,%si
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x6,%esi
  movzbl %sil,%esi
  sub    $0xffffff80,%esi
  movslq %esi,%rdi
  imul   $0x2aaaaaab,%rdi,%rdi
  sar    $0x25,%rdi
  lea    (%rdi,%rdi,2),%edi
  shl    $0x6,%edi
  sub    %edi,%esi
  or     %esi,%eax
  shl    $0x8,%edx
  and    $0xc000,%edx
  add    $0x4000,%edx
  movslq %edx,%rsi
  imul   $0x2aaaaaab,%rsi,%rsi
  sar    $0x2d,%rsi
  lea    (%rsi,%rsi,2),%esi
  shl    $0xe,%esi
  sub    %esi,%edx
  or     %edx,%eax
  mov    %ax,(%rcx)
  ret
```

assistant: ```c
void move_l(unsigned long *p, unsigned short *o) {
  *p = (((*p) >> 9) & 070000) | (((*p) >> 12) & 07) | (((*p) << 9) & 07000) | (((*p) << 12) & 070000000) | ((*p) & 07700770);
  *o = (((((*o) >> 6) & 0x300) + 0x200) % 0x300) | (((((*o) >> 8) & 0x3) + 0x1) % 0x3) | (((((*o) << 6) & 0xc0) + 0x80) % 0xc0) | (((((*o) << 8) & 0xc000) + 0x4000) % 0xc000) | ((*o) & 0x3c3c);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<move_l>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  mov    %rdx,%rax
  mov    %rdx,%rsi
  shr    $0x9,%rax
  shr    $0xc,%rsi
  and    $0x7,%esi
  and    $0x7000,%eax
  or     %rsi,%rax
  mov    %rdx,%rsi
  and    $0x1f81f8,%esi
  or     %rsi,%rax
  mov    %rdx,%rsi
  shl    $0xc,%rdx
  shl    $0x9,%rsi
  and    $0xe00000,%edx
  and    $0xe00,%esi
  or     %rsi,%rax
  or     %rdx,%rax
  movzwl (%rcx),%edx
  mov    %rax,(%rdi)
  mov    $0xaaaaaaab,%edi
  mov    %edx,%eax
  mov    %edx,%esi
  shr    $0x6,%ax
  and    $0x3c3c,%si
  and    $0x300,%eax
  lea    0x200(%rax),%r8d
  mov    %r8,%rax
  imul   %rdi,%r8
  shr    $0x29,%r8
  lea    (%r8,%r8,2),%r8d
  shl    $0x8,%r8d
  sub    %r8d,%eax
  mov    %edx,%r8d
  shr    $0x8,%r8w
  and    $0x3,%r8d
  add    $0x1,%r8d
  mov    %r8,%r9
  imul   %rdi,%r8
  shr    $0x21,%r8
  lea    (%r8,%r8,2),%r8d
  sub    %r8d,%r9d
  or     %r9d,%eax
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x6,%esi
  movzbl %sil,%esi
  lea    0x80(%rsi),%r8d
  mov    %r8,%rsi
  imul   %rdi,%r8
  shr    $0x27,%r8
  lea    (%r8,%r8,2),%r8d
  shl    $0x6,%r8d
  sub    %r8d,%esi
  shl    $0x8,%edx
  and    $0xc000,%edx
  or     %esi,%eax
  lea    0x4000(%rdx),%esi
  mov    %rsi,%rdx
  imul   %rdi,%rsi
  shr    $0x2f,%rsi
  lea    (%rsi,%rsi,2),%esi
  shl    $0xe,%esi
  sub    %esi,%edx
  or     %edx,%eax
  mov    %ax,(%rcx)
  ret
```

assistant: ```c
void move_l(unsigned long *p, unsigned short *o) {
  *p = (((*p) >> 9) & 070000) | (((*p) >> 12) & 07) | (((*p) << 9) & 07000) | (((*p) << 12) & 070000000) | ((*p) & 07700770);
  *o = (((((*o) >> 6) & 0x300) + 0x200) % 0x300) | (((((*o) >> 8) & 0x3) + 0x1) % 0x3) | (((((*o) << 6) & 0xc0) + 0x80) % 0xc0) | (((((*o) << 8) & 0xc000) + 0x4000) % 0xc000) | ((*o) & 0x3c3c);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<move_l>:
  endbr64
  mov    (%rdi),%rdx
  mov    %rsi,%rcx
  mov    %rdx,%rax
  mov    %rdx,%rsi
  shr    $0x9,%rax
  shr    $0xc,%rsi
  and    $0x7,%esi
  and    $0x7000,%eax
  or     %rsi,%rax
  mov    %rdx,%rsi
  and    $0x1f81f8,%esi
  or     %rsi,%rax
  mov    %rdx,%rsi
  shl    $0xc,%rdx
  shl    $0x9,%rsi
  and    $0xe00000,%edx
  and    $0xe00,%esi
  or     %rsi,%rax
  or     %rdx,%rax
  movzwl (%rcx),%edx
  mov    %rax,(%rdi)
  mov    $0xaaaaaaab,%edi
  mov    %edx,%eax
  mov    %edx,%esi
  shr    $0x6,%ax
  and    $0x3c3c,%si
  and    $0x300,%eax
  lea    0x200(%rax),%r8d
  mov    %r8,%rax
  imul   %rdi,%r8
  shr    $0x29,%r8
  lea    (%r8,%r8,2),%r8d
  shl    $0x8,%r8d
  sub    %r8d,%eax
  mov    %edx,%r8d
  shr    $0x8,%r8w
  and    $0x3,%r8d
  add    $0x1,%r8d
  mov    %r8,%r9
  imul   %rdi,%r8
  shr    $0x21,%r8
  lea    (%r8,%r8,2),%r8d
  sub    %r8d,%r9d
  or     %r9d,%eax
  or     %esi,%eax
  mov    %edx,%esi
  shl    $0x6,%esi
  movzbl %sil,%esi
  lea    0x80(%rsi),%r8d
  mov    %r8,%rsi
  imul   %rdi,%r8
  shr    $0x27,%r8
  lea    (%r8,%r8,2),%r8d
  shl    $0x6,%r8d
  sub    %r8d,%esi
  shl    $0x8,%edx
  and    $0xc000,%edx
  or     %esi,%eax
  lea    0x4000(%rdx),%esi
  mov    %rsi,%rdx
  imul   %rdi,%rsi
  shr    $0x2f,%rsi
  lea    (%rsi,%rsi,2),%esi
  shl    $0xe,%esi
  sub    %esi,%edx
  or     %edx,%eax
  mov    %ax,(%rcx)
  ret
```

assistant: ```c
void move_l(unsigned long *p, unsigned short *o) {
  *p = (((*p) >> 9) & 070000) | (((*p) >> 12) & 07) | (((*p) << 9) & 07000) | (((*p) << 12) & 070000000) | ((*p) & 07700770);
  *o = (((((*o) >> 6) & 0x300) + 0x200) % 0x300) | (((((*o) >> 8) & 0x3) + 0x1) % 0x3) | (((((*o) << 6) & 0xc0) + 0x80) % 0xc0) | (((((*o) << 8) & 0xc000) + 0x4000) % 0xc000) | ((*o) & 0x3c3c);
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<catfil>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %edi,-0x14(%rbp)
  cmpl   $0x0,-0x14(%rbp)
  jne    L8
  lea    D18(%rip),%rax
  jmp    L12
L8:
  lea    D29(%rip),%rax
  mov    %rax,-0x8(%rbp)
  movl   $0x0,-0x10(%rbp)
  jmp    L18
L20:
  mov    -0x14(%rbp),%eax
  mov    %eax,-0xc(%rbp)
  mov    -0x14(%rbp),%eax
  movslq %eax,%rdx
  imul   $0x66666667,%rdx,%rdx
  shr    $0x20,%rdx
  sar    $0x2,%edx
  sar    $0x1f,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  mov    %eax,-0x14(%rbp)
  subq   $0x1,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,%edx
  mov    -0x14(%rbp),%eax
  mov    %eax,%ecx
  mov    %ecx,%eax
  shl    $0x2,%eax
  add    %ecx,%eax
  add    %eax,%eax
  mov    %eax,%ecx
  mov    %edx,%eax
  sub    %ecx,%eax
  add    $0x30,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
  addl   $0x1,-0x10(%rbp)
L18:
  cmpl   $0x5,-0x10(%rbp)
  jle    L20
  lea    D6(%rip),%rax
L12:
  pop    %rbp
  ret
```

assistant: ```c
char *catfil(num)
int num;
{
  static char catdir[] = {"/catalog/catdir.cat"};
  static char catent[] = {"/catalog/c000000.cat"};
  char *cfield;
  int k, iq;
  if (num == 0)
    return catdir;
  cfield = &catent[16];
  for (k = 0; k < 6; ++k) {
    iq = num;
    num = num / 10;
    --cfield;
    *cfield = (char)('0' + (iq - num * 10));
  }
  return catent;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<catfil>:
  endbr64
  lea    D20(%rip),%rax
  test   %edi,%edi
  je     L11
  lea    D6(%rip),%rcx
  lea    -0x6(%rcx),%rsi
L6:
  mov    %edi,%edx
  movslq %edi,%rax
  imul   $0x66666667,%rax,%rax
  sar    $0x22,%rax
  sar    $0x1f,%edi
  sub    %edi,%eax
  mov    %eax,%edi
  sub    $0x1,%rcx
  add    $0x30,%edx
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  mov    %dl,(%rcx)
  cmp    %rsi,%rcx
  jne    L6
  lea    D18(%rip),%rax
L11:
  ret
```

assistant: ```c
char *catfil(num)
int num;
{
  static char catdir[] = {"/catalog/catdir.cat"};
  static char catent[] = {"/catalog/c000000.cat"};
  char *cfield;
  int k, iq;
  if (num == 0)
    return catdir;
  cfield = &catent[16];
  for (k = 0; k < 6; ++k) {
    iq = num;
    num = num / 10;
    --cfield;
    *cfield = (char)('0' + (iq - num * 10));
  }
  return catent;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<catfil>:
  endbr64
  lea    D26(%rip),%rax
  test   %edi,%edi
  je     L1
  lea    D0(%rip),%rdx
  lea    -0x6(%rdx),%rsi
  nopw   0x0(%rax,%rax,1)
L19:
  movslq %edi,%rdi
  sub    $0x1,%rdx
  mov    %rdi,%rax
  imul   $0x66666667,%rdi,%rdi
  mov    %eax,%ecx
  add    $0x30,%eax
  sar    $0x1f,%ecx
  sar    $0x22,%rdi
  sub    %ecx,%edi
  lea    (%rdi,%rdi,4),%ecx
  add    %ecx,%ecx
  sub    %ecx,%eax
  mov    %al,(%rdx)
  cmp    %rsi,%rdx
  jne    L19
  lea    D19(%rip),%rax
L1:
  ret
```

assistant: ```c
char *catfil(num)
int num;
{
  static char catdir[] = {"/catalog/catdir.cat"};
  static char catent[] = {"/catalog/c000000.cat"};
  char *cfield;
  int k, iq;
  if (num == 0)
    return catdir;
  cfield = &catent[16];
  for (k = 0; k < 6; ++k) {
    iq = num;
    num = num / 10;
    --cfield;
    *cfield = (char)('0' + (iq - num * 10));
  }
  return catent;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<catfil>:
  endbr64
  test   %edi,%edi
  je     L1
  movslq %edi,%rax
  mov    %edi,%esi
  push   %rbx
  xor    %ebx,%ebx
  imul   $0x51eb851f,%rax,%rcx
  sar    $0x1f,%esi
  imul   $0x66666667,%rax,%r8
  sar    $0x25,%rcx
  sub    %esi,%ecx
  sar    $0x22,%r8
  sub    %esi,%r8d
  lea    (%rcx,%rcx,4),%r9d
  add    $0x30,%ecx
  lea    0x30(%r8),%edx
  add    %r9d,%r9d
  lea    (%r8,%r8,4),%r8d
  sub    %r9d,%edx
  add    %r8d,%r8d
  mov    %dl,%bl
  lea    0x30(%rdi),%edx
  sub    %r8d,%edx
  mov    %dl,%bh
  imul   $0x10624dd3,%rax,%rdx
  mov    %bx,D19(%rip)
  pop    %rbx
  sar    $0x26,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edi
  add    $0x30,%edx
  add    %edi,%edi
  sub    %edi,%ecx
  mov    %cl,D31(%rip)
  imul   $0x68db8bad,%rax,%rcx
  sar    $0x2c,%rcx
  sub    %esi,%ecx
  lea    (%rcx,%rcx,4),%edi
  add    $0x30,%ecx
  add    %edi,%edi
  sub    %edi,%edx
  mov    %dl,D37(%rip)
  imul   $0x14f8b589,%rax,%rdx
  imul   $0x431bde83,%rax,%rax
  sar    $0x2d,%rdx
  sub    %esi,%edx
  lea    (%rdx,%rdx,4),%edi
  add    $0x30,%edx
  add    %edi,%edi
  sub    %edi,%ecx
  sar    $0x32,%rax
  sub    %esi,%eax
  mov    %cl,D53(%rip)
  lea    (%rax,%rax,4),%eax
  add    %eax,%eax
  sub    %eax,%edx
  lea    D43(%rip),%rax
  mov    %dl,D14(%rip)
  ret
  nopl   (%rax)
L1:
  lea    D6(%rip),%rax
  ret
```

assistant: ```c
char *catfil(num)
int num;
{
  static char catdir[] = {"/catalog/catdir.cat"};
  static char catent[] = {"/catalog/c000000.cat"};
  char *cfield;
  int k, iq;
  if (num == 0)
    return catdir;
  cfield = &catent[16];
  for (k = 0; k < 6; ++k) {
    iq = num;
    num = num / 10;
    --cfield;
    *cfield = (char)('0' + (iq - num * 10));
  }
  return catent;
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现:

```asm
<itoa>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x50,%rsp
  mov    %edi,-0x44(%rbp)
  mov    %rsi,-0x50(%rbp)
  mov    %edx,-0x48(%rbp)
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x20(%rbp),%rax
  mov    %rax,-0x28(%rbp)
  movl   $0x0,-0x38(%rbp)
  jmp    L38
L101:
  mov    -0x38(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x50(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x38(%rbp),%eax
  cltq
  movb   $0x0,-0x20(%rbp,%rax,1)
  addl   $0x1,-0x38(%rbp)
L38:
  cmpl   $0xf,-0x38(%rbp)
  jle    L101
  cmpl   $0xa,-0x48(%rbp)
  jne    L87
  cmpl   $0x0,-0x44(%rbp)
  jns    L87
  mov    $0x1,%eax
  jmp    L48
L87:
  mov    $0x0,%eax
L48:
  mov    %eax,-0x30(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L30
  mov    -0x44(%rbp),%eax
  neg    %eax
  mov    %eax,-0x3c(%rbp)
  jmp    L45
L30:
  mov    -0x44(%rbp),%eax
  mov    %eax,-0x3c(%rbp)
  jmp    L45
L99:
  mov    -0x48(%rbp),%ecx
  mov    -0x3c(%rbp),%eax
  mov    $0x0,%edx
  div    %ecx
  mov    %edx,%eax
  mov    %eax,-0x2c(%rbp)
  mov    -0x48(%rbp),%esi
  mov    -0x3c(%rbp),%eax
  mov    $0x0,%edx
  div    %esi
  mov    %eax,-0x3c(%rbp)
  cmpl   $0x9,-0x2c(%rbp)
  jg     L154
  mov    -0x2c(%rbp),%eax
  lea    0x30(%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
  jmp    L45
L154:
  mov    -0x2c(%rbp),%eax
  lea    0x57(%rax),%ecx
  mov    -0x28(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x28(%rbp)
  mov    %ecx,%edx
  mov    %dl,(%rax)
L45:
  cmpl   $0x0,-0x3c(%rbp)
  jne    L99
  lea    -0x20(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  je     L99
  lea    -0x20(%rbp),%rdx
  mov    -0x28(%rbp),%rax
  sub    %rdx,%rax
  mov    %eax,-0x34(%rbp)
  cmpl   $0x0,-0x30(%rbp)
  je     L42
  mov    -0x50(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x50(%rbp)
  movb   $0x2d,(%rax)
  addl   $0x1,-0x34(%rbp)
  jmp    L42
L78:
  subq   $0x1,-0x28(%rbp)
  mov    -0x50(%rbp),%rax
  lea    0x1(%rax),%rdx
  mov    %rdx,-0x50(%rbp)
  mov    -0x28(%rbp),%rdx
  movzbl (%rdx),%edx
  mov    %dl,(%rax)
L42:
  lea    -0x20(%rbp),%rax
  cmp    %rax,-0x28(%rbp)
  ja     L78
  mov    -0x34(%rbp),%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L97
  call   <__stack_chk_fail@plt>
L97:
  leave
  ret
```

assistant: ```c
int itoa(int value, char *sp, int radix) {
  char tmp[16];
  char *tp = tmp;
  int i;
  unsigned v;
  for (int i = 0; i < 16; i++) {
    sp[i] = '\0';
    tmp[i] = '\0';
  }
  int sign = (radix == 10 && value < 0);
  if (sign)
    v = -value;
  else
    v = (unsigned)value;
  while (v || tp == tmp) {
    i = v % radix;
    v /= radix;
    if (i < 10)
      *tp++ = i + '0';
    else
      *tp++ = i + 'a' - 10;
  }
  int len = tp - tmp;
  if (sign) {
    *sp++ = '-';
    len++;
  }
  while (tp > tmp)
    *sp++ = *--tp;
  return len;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<itoa>:
  endbr64
  sub    $0x28,%rsp
  mov    %rsi,%r9
  mov    %edx,%r8d
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  mov    $0x0,%edx
L57:
  movb   $0x0,(%r9,%rdx,1)
  movb   $0x0,(%rsp,%rdx,1)
  add    $0x1,%rdx
  cmp    $0x10,%rdx
  jne    L57
  cmp    $0xa,%r8d
  sete   %cl
  mov    %edi,%edx
  shr    $0x1f,%edx
  mov    %edi,%eax
  neg    %eax
  and    %dl,%cl
  mov    %ecx,%r11d
  cmove  %edi,%eax
  lea    0x1(%rsp),%rcx
  mov    %rsp,%r10
L30:
  mov    %eax,%edi
  mov    $0x0,%edx
  div    %r8d
  cmp    $0x9,%edx
  jg     L5
  mov    %rcx,%rsi
  add    $0x30,%edx
L86:
  mov    %dl,-0x1(%rcx)
  add    $0x1,%rcx
  cmp    %r10,%rsi
  je     L30
  cmp    %edi,%r8d
  jbe    L30
  mov    %rsp,%rdx
  mov    %rsi,%rax
  sub    %rdx,%rax
  mov    %eax,%ecx
  test   %r11b,%r11b
  je     L14
  movb   $0x2d,(%r9)
  lea    0x1(%rax),%ecx
  lea    0x1(%r9),%r9
L14:
  mov    %rsp,%rax
  mov    %rsp,%rdx
  cmp    %rax,%rsi
  jbe    L24
L39:
  sub    $0x1,%rsi
  add    $0x1,%r9
  movzbl (%rsi),%eax
  mov    %al,-0x1(%r9)
  cmp    %rdx,%rsi
  jne    L39
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L34
  mov    %ecx,%eax
  add    $0x28,%rsp
  ret
L5:
  mov    %rcx,%rsi
  add    $0x57,%edx
  jmp    L86
L34:
  call   <__stack_chk_fail@plt>
```

assistant: ```c
int itoa(int value, char *sp, int radix) {
  char tmp[16];
  char *tp = tmp;
  int i;
  unsigned v;
  for (int i = 0; i < 16; i++) {
    sp[i] = '\0';
    tmp[i] = '\0';
  }
  int sign = (radix == 10 && value < 0);
  if (sign)
    v = -value;
  else
    v = (unsigned)value;
  while (v || tp == tmp) {
    i = v % radix;
    v /= radix;
    if (i < 10)
      *tp++ = i + '0';
    else
      *tp++ = i + 'a' - 10;
  }
  int len = tp - tmp;
  if (sign) {
    *sp++ = '-';
    len++;
  }
  while (tp > tmp)
    *sp++ = *--tp;
  return len;
}
```