ylfeng/ReF-Decompile-dataset huggingface dataset:
user: Demonstrate the C code that generates the assembly output below:

```asm
<norm>:
  endbr64
  test   %edx,%edx
  jle    L57
  mov    %rdi,%r10
  mov    %esi,%r9d
  pxor   %xmm4,%xmm4
  push   %rbx
  movq   D0(%rip),%xmm5
  mov    %edx,%r8d
  xor    %edi,%edi
  xor    %esi,%esi
  movapd %xmm4,%xmm2
  movapd %xmm4,%xmm1
  lea    -0x1(%r9),%ebx
  lea    0x8(%r10),%r11
  cs nopw 0x0(%rax,%rax,1)
L11:
  test   %r9d,%r9d
  jle    L40
  movslq %edi,%rdx
  movapd %xmm1,%xmm3
  lea    (%r10,%rdx,8),%rax
  add    %rbx,%rdx
  lea    (%r11,%rdx,8),%rdx
  jmp    L45
  nopl   0x0(%rax)
L29:
  movapd %xmm1,%xmm3
L45:
  movsd  (%rax),%xmm0
  comisd %xmm4,%xmm0
  jae    L18
  xorpd  %xmm5,%xmm0
L18:
  subsd  %xmm2,%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  subsd  %xmm0,%xmm2
  cmp    %rdx,%rax
  jne    L29
L40:
  add    $0x1,%esi
  add    %ecx,%edi
  cmp    %esi,%r8d
  jne    L11
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
L57:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: extract_symbolic_data
arguments: data_tag: D0
type_infered: f32[2]

tool: {"D0": [0.0,-0.0]}

assistant: ```c
double norm(const double *src, int nrows, int ncols, int ld) {
  int i, j;
  double result = 0, comp = 0;
  for (i = 0; i < ncols; ++i) {
    for (j = 0; j < nrows; ++j) {
      const int k = i * ld + j;
      const double v = src[k], a = (0 <= v ? v : -v) - comp, b = result + a;
      comp = (b - result) - a;
      result = b;
    }
  }
  return result;
}
```
user: Translate the below assembly code into C programming language:

```asm
<norm>:
  endbr64
  test   %edx,%edx
  jle    L47
  mov    %rdi,%r10
  mov    %esi,%r9d
  pxor   %xmm4,%xmm4
  push   %rbx
  movq   D2(%rip),%xmm5
  mov    %edx,%r8d
  xor    %edi,%edi
  xor    %esi,%esi
  movapd %xmm4,%xmm2
  movapd %xmm4,%xmm1
  lea    -0x1(%r9),%ebx
  lea    0x8(%r10),%r11
  cs nopw 0x0(%rax,%rax,1)
L22:
  test   %r9d,%r9d
  jle    L37
  movslq %edi,%rdx
  movapd %xmm1,%xmm3
  lea    (%r10,%rdx,8),%rax
  add    %rbx,%rdx
  lea    (%r11,%rdx,8),%rdx
  jmp    L1
  nopl   0x0(%rax)
L19:
  movapd %xmm1,%xmm3
L1:
  movsd  (%rax),%xmm0
  comisd %xmm4,%xmm0
  jae    L42
  xorpd  %xmm5,%xmm0
L42:
  subsd  %xmm2,%xmm0
  add    $0x8,%rax
  addsd  %xmm0,%xmm1
  movapd %xmm1,%xmm2
  subsd  %xmm3,%xmm2
  subsd  %xmm0,%xmm2
  cmp    %rax,%rdx
  jne    L19
L37:
  add    $0x1,%esi
  add    %ecx,%edi
  cmp    %esi,%r8d
  jne    L22
  movapd %xmm1,%xmm0
  pop    %rbx
  ret
L47:
  pxor   %xmm1,%xmm1
  movapd %xmm1,%xmm0
  ret
```

tool_calls: name: disassemble_data
arguments: tag: D2
type_guessed: f32[2]

tool: {"D2": [0.0,-0.0]}

assistant: ```c
double norm(const double *src, int nrows, int ncols, int ld) {
  int i, j;
  double result = 0, comp = 0;
  for (i = 0; i < ncols; ++i) {
    for (j = 0; j < nrows; ++j) {
      const int k = i * ld + j;
      const double v = src[k], a = (0 <= v ? v : -v) - comp, b = result + a;
      comp = (b - result) - a;
      result = b;
    }
  }
  return result;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<removeDuplicates>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  cmpl   $0x1,-0x1c(%rbp)
  jg     L29
  mov    -0x1c(%rbp),%eax
  jmp    L0
L29:
  movl   $0x1,-0x4(%rbp)
  movl   $0x1,-0x8(%rbp)
  jmp    L49
L8:
  mov    -0x8(%rbp),%eax
  cltq
  shl    $0x2,%rax
  lea    -0x4(%rax),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%edx
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rcx
  mov    -0x18(%rbp),%rax
  add    %rcx,%rax
  mov    (%rax),%eax
  cmp    %eax,%edx
  je     L43
  mov    -0x8(%rbp),%eax
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  lea    (%rdx,%rax,1),%rcx
  mov    -0x4(%rbp),%eax
  lea    0x1(%rax),%edx
  mov    %edx,-0x4(%rbp)
  cltq
  lea    0x0(,%rax,4),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    (%rcx),%eax
  mov    %eax,(%rdx)
L43:
  addl   $0x1,-0x8(%rbp)
L49:
  mov    -0x8(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L8
  mov    -0x4(%rbp),%eax
L0:
  pop    %rbp
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return numsSize;
  }
  int i, count = 1;
  for (i = 1; i < numsSize; i++) {
    if (nums[i - 1] != nums[i]) {
      nums[count++] = nums[i];
    }
  }
  return count;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<removeDuplicates>:
  endbr64
  mov    %esi,%ecx
  cmp    $0x1,%esi
  jle    L32
  mov    %rdi,%rax
  lea    -0x2(%rsi),%edx
  lea    0x4(%rdi,%rdx,4),%r8
  mov    $0x1,%ecx
  jmp    L22
L28:
  add    $0x4,%rax
  cmp    %r8,%rax
  je     L32
L22:
  mov    0x4(%rax),%edx
  cmp    %edx,(%rax)
  je     L28
  movslq %ecx,%rsi
  mov    %edx,(%rdi,%rsi,4)
  lea    0x1(%rcx),%ecx
  jmp    L28
L32:
  mov    %ecx,%eax
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return numsSize;
  }
  int i, count = 1;
  for (i = 1; i < numsSize; i++) {
    if (nums[i - 1] != nums[i]) {
      nums[count++] = nums[i];
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeDuplicates>:
  endbr64
  mov    %esi,%eax
  cmp    $0x1,%esi
  jle    L27
  sub    $0x2,%eax
  mov    %rdi,%rdx
  lea    0x4(%rdi,%rax,4),%r8
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L18:
  mov    0x4(%rdx),%ecx
  cmp    %ecx,(%rdx)
  je     L19
  movslq %eax,%rsi
  add    $0x1,%eax
  mov    %ecx,(%rdi,%rsi,4)
L19:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L18
L27:
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return numsSize;
  }
  int i, count = 1;
  for (i = 1; i < numsSize; i++) {
    if (nums[i - 1] != nums[i]) {
      nums[count++] = nums[i];
    }
  }
  return count;
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<removeDuplicates>:
  endbr64
  mov    %esi,%eax
  cmp    $0x1,%esi
  jle    L28
  sub    $0x2,%eax
  mov    %rdi,%rdx
  lea    0x4(%rdi,%rax,4),%r8
  mov    $0x1,%eax
  nopl   0x0(%rax,%rax,1)
L22:
  mov    0x4(%rdx),%ecx
  cmp    %ecx,(%rdx)
  je     L16
  movslq %eax,%rsi
  add    $0x1,%eax
  mov    %ecx,(%rdi,%rsi,4)
L16:
  add    $0x4,%rdx
  cmp    %r8,%rdx
  jne    L22
L28:
  ret
```

assistant: ```c
int removeDuplicates(int *nums, int numsSize) {
  if (numsSize <= 1) {
    return numsSize;
  }
  int i, count = 1;
  for (i = 1; i < numsSize; i++) {
    if (nums[i - 1] != nums[i]) {
      nums[count++] = nums[i];
    }
  }
  return count;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<mklower>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,-0x8(%rbp)
  jmp    L2
L8:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x40,%al
  jle    L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  cmp    $0x5a,%al
  jg     L13
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  add    $0x20,%eax
  mov    %eax,%edx
  mov    -0x8(%rbp),%rax
  mov    %dl,(%rax)
L13:
  addq   $0x1,-0x8(%rbp)
L2:
  mov    -0x8(%rbp),%rax
  movzbl (%rax),%eax
  test   %al,%al
  jne    L8
  mov    -0x18(%rbp),%rax
  pop    %rbp
  ret
```

assistant: ```c
char *mklower(str)
char *str;
{
  char *sp;
  sp = str;
  while (*sp) {
    if ('A' <= *sp && *sp <= 'Z')
      *sp += 'a' - 'A';
    ++sp;
  }
  return (str);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<mklower>:
  endbr64
  mov    %rdi,%rax
  movzbl (%rdi),%edx
  test   %dl,%dl
  je     L9
  mov    %rdi,%rcx
  jmp    L34
L4:
  add    $0x1,%rcx
  movzbl (%rcx),%edx
  test   %dl,%dl
  je     L9
L34:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L4
  add    $0x20,%edx
  mov    %dl,(%rcx)
  jmp    L4
L9:
  ret
```

assistant: ```c
char *mklower(str)
char *str;
{
  char *sp;
  sp = str;
  while (*sp) {
    if ('A' <= *sp && *sp <= 'Z')
      *sp += 'a' - 'A';
    ++sp;
  }
  return (str);
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<mklower>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L10
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L19:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L25
  add    $0x20,%edx
  mov    %dl,(%rcx)
L25:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L19
L10:
  ret
```

assistant: ```c
char *mklower(str)
char *str;
{
  char *sp;
  sp = str;
  while (*sp) {
    if ('A' <= *sp && *sp <= 'Z')
      *sp += 'a' - 'A';
    ++sp;
  }
  return (str);
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<mklower>:
  endbr64
  movzbl (%rdi),%edx
  mov    %rdi,%rax
  test   %dl,%dl
  je     L13
  mov    %rdi,%rcx
  nopl   0x0(%rax)
L18:
  lea    -0x41(%rdx),%esi
  cmp    $0x19,%sil
  ja     L29
  add    $0x20,%edx
  add    $0x1,%rcx
  mov    %dl,-0x1(%rcx)
  movzbl (%rcx),%edx
  test   %dl,%dl
  jne    L18
  ret
  nopl   0x0(%rax,%rax,1)
L29:
  movzbl 0x1(%rcx),%edx
  add    $0x1,%rcx
  test   %dl,%dl
  jne    L18
L13:
  ret
```

assistant: ```c
char *mklower(str)
char *str;
{
  char *sp;
  sp = str;
  while (*sp) {
    if ('A' <= *sp && *sp <= 'Z')
      *sp += 'a' - 'A';
    ++sp;
  }
  return (str);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,-0x8(%rbp)
  xor    %eax,%eax
  lea    -0x14(%rbp),%rsi
  lea    -0x18(%rbp),%rcx
  lea    -0x1c(%rbp),%rdx
  lea    -0x20(%rbp),%rax
  mov    %rsi,%r8
  mov    %rax,%rsi
  lea    D0(%rip),%rax
  mov    %rax,%rdi
  call   <scanf@plt>
  movss  -0x20(%rbp),%xmm1
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x1c(%rbp),%xmm2
  movss  -0x18(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L30
  ucomiss %xmm1,%xmm0
  jne    L30
  lea    D28(%rip),%rax
  mov    %rax,%rdi
  mov    $0x0,%eax
  call   <printf@plt>
  jmp    L19
L30:
  movss  -0x20(%rbp),%xmm0
  movss  -0x18(%rbp),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x1c(%rbp),%xmm3
  movss  -0x18(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0x10(%rbp)
  movss  -0x1c(%rbp),%xmm0
  movss  -0x14(%rbp),%xmm2
  movaps %xmm0,%xmm1
  subss  %xmm2,%xmm1
  movss  -0x20(%rbp),%xmm2
  movss  -0x18(%rbp),%xmm0
  mulss  %xmm2,%xmm0
  mulss  %xmm1,%xmm0
  movss  -0x20(%rbp),%xmm2
  movss  -0x14(%rbp),%xmm1
  mulss  %xmm2,%xmm1
  movss  -0x18(%rbp),%xmm3
  movss  -0x1c(%rbp),%xmm2
  mulss  %xmm3,%xmm2
  subss  %xmm2,%xmm1
  divss  %xmm1,%xmm0
  movss  %xmm0,-0xc(%rbp)
  pxor   %xmm2,%xmm2
  cvtss2sd -0x10(%rbp),%xmm2
  movss  -0xc(%rbp),%xmm0
  movss  D20(%rip),%xmm1
  xorps  %xmm1,%xmm0
  pxor   %xmm4,%xmm4
  cvtss2sd %xmm0,%xmm4
  movq   %xmm4,%rax
  movapd %xmm2,%xmm1
  movq   %rax,%xmm0
  lea    D29(%rip),%rax
  mov    %rax,%rdi
  mov    $0x2,%eax
  call   <printf@plt>
L19:
  mov    $0x0,%eax
  mov    -0x8(%rbp),%rdx
  sub    %fs:0x28,%rdx
  je     L23
  call   <__stack_chk_fail@plt>
L23:
  leave
  ret
```

tool_calls: name: read_data
arguments: label: D0
data_type: string
name: read_data
arguments: label: D28
data_type: string
name: read_data
arguments: label: D20
data_type: byte[4]
name: read_data
arguments: label: D29
data_type: string

tool: D0: %f %f %f %f

tool: D28: INF

tool: {"D20": [0x00,0x00,0x00,0x80]}

tool: D29: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x, y;
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    y = ((a1 - a2) * (b1 * b2)) / ((a1 * b2) - (b1 * a2));
    x = ((b1 - b2) * (a1 * a2)) / ((a1 * b2) - (a2 * b1));
    printf("(%.3f,%.3f)", -x, y);
  }
  return 0;
}
```
user: What is the c source code of the assembly code below?

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  lea    D9(%rip),%rdi
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm3
  movss  0x14(%rsp),%xmm6
  movaps %xmm3,%xmm2
  mulss  %xmm6,%xmm2
  movss  0xc(%rsp),%xmm0
  movss  0x10(%rsp),%xmm5
  movaps %xmm0,%xmm4
  mulss  %xmm5,%xmm4
  ucomiss %xmm4,%xmm2
  jp     L19
  jne    L19
  lea    D4(%rip),%rdi
  mov    $0x0,%eax
  call   <printf@plt>
L24:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L23
  mov    $0x0,%eax
  add    $0x28,%rsp
  ret
L19:
  subss  %xmm4,%xmm2
  movaps %xmm3,%xmm1
  subss  %xmm5,%xmm1
  movaps %xmm6,%xmm4
  mulss  %xmm0,%xmm4
  mulss  %xmm4,%xmm1
  divss  %xmm2,%xmm1
  subss  %xmm6,%xmm0
  mulss  %xmm5,%xmm3
  mulss  %xmm3,%xmm0
  divss  %xmm2,%xmm0
  xorps  D10(%rip),%xmm0
  cvtss2sd %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  lea    D31(%rip),%rdi
  mov    $0x2,%eax
  call   <printf@plt>
  jmp    L24
L23:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: data_tag: D9
type: string
name: disassemble_data
arguments: data_tag: D4
type: string
name: disassemble_data
arguments: data_tag: D10
type: byte[16]
name: disassemble_data
arguments: data_tag: D31
type: string

tool: D9: %f %f %f %f

tool: D4: INF

tool: {"D10": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

tool: D31: (%.3f,%.3f)

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x, y;
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    y = ((a1 - a2) * (b1 * b2)) / ((a1 * b2) - (b1 * a2));
    x = ((b1 - b2) * (a1 * a2)) / ((a1 * b2) - (a2 * b1));
    printf("(%.3f,%.3f)", -x, y);
  }
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D25(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm2
  movss  0x14(%rsp),%xmm5
  movss  0x10(%rsp),%xmm4
  movaps %xmm3,%xmm0
  movaps %xmm2,%xmm1
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L33
  jne    L33
  lea    D24(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L2:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L0
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L33:
  movaps %xmm5,%xmm6
  subss  %xmm1,%xmm0
  movaps %xmm3,%xmm1
  mov    $0x2,%eax
  mulss  %xmm2,%xmm6
  subss  %xmm4,%xmm1
  subss  %xmm5,%xmm2
  mulss  %xmm4,%xmm3
  lea    D19(%rip),%rdi
  mulss  %xmm6,%xmm1
  mulss  %xmm3,%xmm2
  divss  %xmm0,%xmm1
  divss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  xorps  D8(%rip),%xmm2
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  jmp    L2
L0:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: parse_data
arguments: label: D25
datatype: string
name: parse_data
arguments: label: D24
datatype: string
name: parse_data
arguments: label: D19
datatype: string
name: parse_data
arguments: label: D8
datatype: byte[16]

tool: D25: %f %f %f %f

tool: D24: INF

tool: D19: (%.3f,%.3f)

tool: {"D8": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x, y;
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    y = ((a1 - a2) * (b1 * b2)) / ((a1 * b2) - (b1 * a2));
    x = ((b1 - b2) * (a1 * a2)) / ((a1 * b2) - (a2 * b1));
    printf("(%.3f,%.3f)", -x, y);
  }
  return 0;
}
```
user: What would the C source look like for the assembly code provided here:

```asm
<main>:
  endbr64
  sub    $0x28,%rsp
  lea    D31(%rip),%rdi
  lea    0x10(%rsp),%rcx
  lea    0xc(%rsp),%rdx
  mov    %fs:0x28,%rax
  mov    %rax,0x18(%rsp)
  xor    %eax,%eax
  lea    0x8(%rsp),%rsi
  lea    0x14(%rsp),%r8
  call   <scanf@plt>
  movss  0x8(%rsp),%xmm3
  movss  0xc(%rsp),%xmm2
  movss  0x14(%rsp),%xmm5
  movss  0x10(%rsp),%xmm4
  movaps %xmm3,%xmm0
  movaps %xmm2,%xmm1
  mulss  %xmm5,%xmm0
  mulss  %xmm4,%xmm1
  ucomiss %xmm1,%xmm0
  jp     L9
  jne    L9
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L36:
  mov    0x18(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L30
  xor    %eax,%eax
  add    $0x28,%rsp
  ret
L9:
  movaps %xmm5,%xmm6
  subss  %xmm1,%xmm0
  movaps %xmm3,%xmm1
  mov    $0x2,%eax
  mulss  %xmm2,%xmm6
  subss  %xmm4,%xmm1
  subss  %xmm5,%xmm2
  mulss  %xmm4,%xmm3
  lea    D33(%rip),%rdi
  mulss  %xmm6,%xmm1
  mulss  %xmm3,%xmm2
  divss  %xmm0,%xmm1
  divss  %xmm0,%xmm2
  pxor   %xmm0,%xmm0
  cvtss2sd %xmm1,%xmm1
  xorps  D39(%rip),%xmm2
  cvtss2sd %xmm2,%xmm0
  call   <printf@plt>
  jmp    L36
L30:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: extract_symbolic_data
arguments: label: D31
datatype: string
name: extract_symbolic_data
arguments: label: D30
datatype: string
name: extract_symbolic_data
arguments: label: D33
datatype: string
name: extract_symbolic_data
arguments: label: D39
datatype: byte[16]

tool: D31: %f %f %f %f

tool: D30: INF

tool: D33: (%.3f,%.3f)

tool: {"D39": [0x00,0x00,0x00,0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00]}

assistant: ```c
int main() {
  float a1, b1, a2, b2;
  scanf("%f %f %f %f", &a1, &b1, &a2, &b2);
  float x, y;
  if (a1 * b2 == b1 * a2) {
    printf("INF");
  } else {
    y = ((a1 - a2) * (b1 * b2)) / ((a1 * b2) - (b1 * a2));
    x = ((b1 - b2) * (a1 * a2)) / ((a1 * b2) - (a2 * b1));
    printf("(%.3f,%.3f)", -x, y);
  }
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<main>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  movl   $0x0,-0x10(%rbp)
  movl   $0x1,-0xc(%rbp)
  jmp    L51
L63:
  mov    -0x10(%rbp),%eax
  mov    %eax,-0x8(%rbp)
  mov    -0xc(%rbp),%eax
  mov    %eax,-0x4(%rbp)
  mov    $0x0,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L44
  cmpl   $0x1f,-0x8(%rbp)
  jg     L18
  addl   $0x2,-0x8(%rbp)
  addl   $0x2,-0x4(%rbp)
  jmp    L44
L18:
  addl   $0x1,-0x8(%rbp)
  jmp    L4
L44:
  mov    -0x8(%rbp),%eax
  mov    %eax,-0x10(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,-0xc(%rbp)
L51:
  mov    $0x0,%eax
  call   <nd@plt>
  test   %rax,%rax
  jne    L63
L4:
  mov    -0x10(%rbp),%eax
  cmp    -0xc(%rbp),%eax
  jle    L12
  mov    $0x0,%eax
  call   <__VERIFIER_error@plt>
L12:
  mov    $0x0,%eax
  leave
  ret
```

assistant: ```c
int main() {
  int x = 0;
  int y = 1;
  while (nd()) {
    int nx = x;
    int ny = y;
    if (nd()) {
      if (nx < 32) {
        nx += 2;
        ny += 2;
      } else {
        nx++;
        break;
      }
    }
    x = nx;
    y = ny;
  }
  if (!(x <= y)) {
    __VERIFIER_error();
  };
  return 0;
}
```
user: 下面的汇编指令对应的C源代码是什么：

```asm
<main>:
  endbr64
  push   %rbp
  push   %rbx
  sub    $0x8,%rsp
  mov    $0x1,%ebp
  mov    $0x0,%ebx
  jmp    L52
L3:
  add    $0x2,%ebx
  add    $0x2,%ebp
L52:
  mov    $0x0,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L51
  mov    $0x0,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L52
  cmp    $0x1f,%ebx
  jle    L3
L51:
  cmp    %ebp,%ebx
  jg     L59
L57:
  mov    $0x0,%eax
  add    $0x8,%rsp
  pop    %rbx
  pop    %rbp
  ret
L59:
  mov    $0x0,%eax
  call   <__VERIFIER_error@plt>
  jmp    L57
```

assistant: ```c
int main() {
  int x = 0;
  int y = 1;
  while (nd()) {
    int nx = x;
    int ny = y;
    if (nd()) {
      if (nx < 32) {
        nx += 2;
        ny += 2;
      } else {
        nx++;
        break;
      }
    }
    x = nx;
    y = ny;
  }
  if (!(x <= y)) {
    __VERIFIER_error();
  };
  return 0;
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L53:
  xor    %eax,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L49
L59:
  xor    %eax,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L53
  cmp    $0x1f,%ebx
  jg     L49
  xor    %eax,%eax
  add    $0x2,%ebx
  add    $0x2,%ebp
  call   <nd@plt>
  test   %rax,%rax
  jne    L59
L49:
  cmp    %ebp,%ebx
  jg     L20
L7:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L20:
  xor    %eax,%eax
  call   <__VERIFIER_error@plt>
  jmp    L7
```

assistant: ```c
int main() {
  int x = 0;
  int y = 1;
  while (nd()) {
    int nx = x;
    int ny = y;
    if (nd()) {
      if (nx < 32) {
        nx += 2;
        ny += 2;
      } else {
        nx++;
        break;
      }
    }
    x = nx;
    y = ny;
  }
  if (!(x <= y)) {
    __VERIFIER_error();
  };
  return 0;
}
```
user: 请将以下的汇编代码转换成C语言代码：

```asm
<main>:
  endbr64
  push   %rbp
  mov    $0x1,%ebp
  push   %rbx
  xor    %ebx,%ebx
  sub    $0x8,%rsp
  nopl   0x0(%rax)
L15:
  xor    %eax,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L4
L17:
  xor    %eax,%eax
  call   <nd@plt>
  test   %rax,%rax
  je     L15
  cmp    $0x1f,%ebx
  jg     L4
  xor    %eax,%eax
  add    $0x2,%ebx
  add    $0x2,%ebp
  call   <nd@plt>
  test   %rax,%rax
  jne    L17
L4:
  cmp    %ebp,%ebx
  jg     L43
L32:
  add    $0x8,%rsp
  xor    %eax,%eax
  pop    %rbx
  pop    %rbp
  ret
L43:
  xor    %eax,%eax
  call   <__VERIFIER_error@plt>
  jmp    L32
```

assistant: ```c
int main() {
  int x = 0;
  int y = 1;
  while (nd()) {
    int nx = x;
    int ny = y;
    if (nd()) {
      if (nx < 32) {
        nx += 2;
        ny += 2;
      } else {
        nx++;
        break;
      }
    }
    x = nx;
    y = ny;
  }
  if (!(x <= y)) {
    __VERIFIER_error();
  };
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的：

```asm
<url_full_path>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x20,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    -0x18(%rbp),%rax
  mov    %rax,%rdi
  call   <full_path_length@plt>
  mov    %eax,-0xc(%rbp)
  mov    -0xc(%rbp),%eax
  add    $0x1,%eax
  mov    %eax,%edi
  call   <checking_malloc@plt>
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x18(%rbp),%rax
  mov    %rdx,%rsi
  mov    %rax,%rdi
  call   <full_path_write@plt>
  mov    -0xc(%rbp),%eax
  movslq %eax,%rdx
  mov    -0x8(%rbp),%rax
  add    %rdx,%rax
  movb   $0x0,(%rax)
  mov    -0x8(%rbp),%rax
  leave
  ret
```

assistant: ```c
char *url_full_path(const struct url *url) {
  int length = full_path_length(url);
  char *full_path = checking_malloc(length + 1);
  full_path_write(url, full_path);
  full_path[length] = '\0';
  return full_path;
}
```
user: Please show me the C implementation that matches the assembly code listed below:

```asm
<url_full_path>:
  endbr64
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%r12
  call   <full_path_length@plt>
  mov    %eax,%ebx
  lea    0x1(%rax),%edi
  call   <checking_malloc@plt>
  mov    %rax,%rbp
  mov    %rax,%rsi
  mov    %r12,%rdi
  call   <full_path_write@plt>
  movslq %ebx,%rbx
  movb   $0x0,0x0(%rbp,%rbx,1)
  mov    %rbp,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *url_full_path(const struct url *url) {
  int length = full_path_length(url);
  char *full_path = checking_malloc(length + 1);
  full_path_write(url, full_path);
  full_path[length] = '\0';
  return full_path;
}
```
user: 下面的汇编指令对应的C源代码是什么:

```asm
<url_full_path>:
  endbr64
  push   %r12
  push   %rbp
  mov    %rdi,%rbp
  push   %rbx
  call   <full_path_length@plt>
  movslq %eax,%rbx
  lea    0x1(%rbx),%edi
  call   <checking_malloc@plt>
  mov    %rbp,%rdi
  mov    %rax,%r12
  mov    %rax,%rsi
  call   <full_path_write@plt>
  movb   $0x0,(%r12,%rbx,1)
  mov    %r12,%rax
  pop    %rbx
  pop    %rbp
  pop    %r12
  ret
```

assistant: ```c
char *url_full_path(const struct url *url) {
  int length = full_path_length(url);
  char *full_path = checking_malloc(length + 1);
  full_path_write(url, full_path);
  full_path[length] = '\0';
  return full_path;
}
```