ylfeng/ReF-Decompile-dataset huggingface dataset:
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<main>:
  endbr64
  push   %rbp
  lea    D1(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D15(%rip),%rdi
  call   <scanf@plt>
  lea    D10(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <first_single@plt>
  test   %al,%al
  je     L24
  movsbl %al,%esi
  lea    D39(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L4:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L18
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L24:
  lea    D14(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L4
L18:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: read_data
arguments: label: D1
type: string
name: read_data
arguments: label: D15
type: string
name: read_data
arguments: label: D10
type: string
name: read_data
arguments: label: D39
type: string
name: read_data
arguments: label: D14
type: string

tool: D1: Please input string:

tool: D15: %s

tool: D10: get the string:%s


tool: D39: The first single char is %c


tool: D14: no result!

assistant: ```c
int main(void) {
  char first;
  char string[100];
  printf("Please input string:");
  scanf("%s", string);
  printf("get the string:%s\n", string);
  first = first_single(string);
  if (first)
    printf("The first single char is %c\n", first);
  else
    printf("no result!");
  return 0;
}
```
user: 这段汇编代码用C语言表示是什么样的？

```asm
<main>:
  endbr64
  push   %rbp
  lea    D16(%rip),%rdi
  sub    $0x70,%rsp
  mov    %fs:0x28,%rax
  mov    %rax,0x68(%rsp)
  xor    %eax,%eax
  mov    %rsp,%rbp
  call   <printf@plt>
  mov    %rbp,%rsi
  lea    D10(%rip),%rdi
  call   <scanf@plt>
  lea    D41(%rip),%rdi
  xor    %eax,%eax
  mov    %rbp,%rsi
  call   <printf@plt>
  mov    %rbp,%rdi
  call   <first_single@plt>
  test   %al,%al
  je     L23
  movsbl %al,%esi
  lea    D30(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
L15:
  mov    0x68(%rsp),%rax
  sub    %fs:0x28,%rax
  jne    L24
  add    $0x70,%rsp
  xor    %eax,%eax
  pop    %rbp
  ret
L23:
  lea    D12(%rip),%rdi
  xor    %eax,%eax
  call   <printf@plt>
  jmp    L15
L24:
  call   <__stack_chk_fail@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D16
type: string
name: disassemble_data
arguments: tag: D10
type: string
name: disassemble_data
arguments: tag: D41
type: string
name: disassemble_data
arguments: tag: D30
type: string
name: disassemble_data
arguments: tag: D12
type: string

tool: D16: Please input string:

tool: D10: %s

tool: D41: get the string:%s


tool: D30: The first single char is %c


tool: D12: no result!

assistant: ```c
int main(void) {
  char first;
  char string[100];
  printf("Please input string:");
  scanf("%s", string);
  printf("get the string:%s\n", string);
  first = first_single(string);
  if (first)
    printf("The first single char is %c\n", first);
  else
    printf("no result!");
  return 0;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_deposit_info>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x10,%rsp
  mov    %edi,-0x4(%rbp)
  mov    %esi,-0x8(%rbp)
  mov    -0x4(%rbp),%eax
  mov    %eax,%esi
  lea    D9(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  mov    -0x8(%rbp),%eax
  mov    %eax,%esi
  lea    D14(%rip),%rax
  mov    %rax,%rdi
  call   <printf@plt>
  nop
  leave
  ret
```

tool_calls: name: retrieve_data
arguments: data_label: D9
datatype: string
name: retrieve_data
arguments: data_label: D14
datatype: string

tool: D9: Depositing %d dollars.


tool: D14: Current balance %d dollars.


assistant: ```c
void print_deposit_info(int amount, int balance) {
  printf("Depositing %d dollars.\n", amount);
  printf("Current balance %d dollars.\n", balance);
}
```
user: 提供的汇编代码用C语言表示会是什么样子:

```asm
<print_deposit_info>:
  endbr64
  push   %rbx
  mov    %esi,%ebx
  mov    %edi,%esi
  lea    D6(%rip),%rdi
  call   <printf@plt>
  mov    %ebx,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  pop    %rbx
  ret
```

tool_calls: name: unpack_data
arguments: label: D6
type: string
name: unpack_data
arguments: label: D8
type: string

tool: D6: Depositing %d dollars.


tool: D8: Current balance %d dollars.


assistant: ```c
void print_deposit_info(int amount, int balance) {
  printf("Depositing %d dollars.\n", amount);
  printf("Current balance %d dollars.\n", balance);
}
```
user: 请将以下的汇编代码转换成C语言代码:

```asm
<print_deposit_info>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  lea    D8(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D19(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: tag: D8
data_type: string
name: disassemble_data
arguments: tag: D19
data_type: string

tool: D8: Depositing %d dollars.


tool: D19: Current balance %d dollars.


assistant: ```c
void print_deposit_info(int amount, int balance) {
  printf("Depositing %d dollars.\n", amount);
  printf("Current balance %d dollars.\n", balance);
}
```
user: Translate the below assembly code into C programming language:

```asm
<print_deposit_info>:
  endbr64
  push   %rbp
  mov    %esi,%ebp
  mov    %edi,%esi
  lea    D12(%rip),%rdi
  call   <printf@plt>
  mov    %ebp,%esi
  lea    D4(%rip),%rdi
  pop    %rbp
  jmp    1050 <printf@plt>
```

tool_calls: name: disassemble_data
arguments: label: D12
type_infered: string
name: disassemble_data
arguments: label: D4
type_infered: string

tool: D12: Depositing %d dollars.


tool: D4: Current balance %d dollars.


assistant: ```c
void print_deposit_info(int amount, int balance) {
  printf("Depositing %d dollars.\n", amount);
  printf("Current balance %d dollars.\n", balance);
}
```
user: Demonstrate the C code that generates the assembly output below:

```asm
<print_human_readable_size>:
  endbr64
  sub    $0x8,%rsp
  cmp    $0x3ff,%rsi
  jbe    L57
  mov    %rsi,%rdx
  mov    $0x0,%eax
L45:
  shr    $0xa,%rdx
  add    $0x1,%rax
  cmp    $0x3ff,%rdx
  ja     L45
  lea    D28(%rip),%rcx
  movzbl (%rcx,%rax,1),%r8d
  lea    (%rax,%rax,4),%ecx
  add    %ecx,%ecx
  mov    $0x1,%eax
  shl    %cl,%rax
  lea    -0x1(%rax),%rcx
  and    %rsi,%rcx
  js     L65
  pxor   %xmm0,%xmm0
  cvtsi2sd %rcx,%xmm0
L126:
  cmp    $0x400,%rax
  jbe    L101
  movsd  D70(%rip),%xmm1
L75:
  mulsd  %xmm1,%xmm0
  shr    $0xa,%rax
  cmp    $0x400,%rax
  ja     L75
L101:
  mulsd  D23(%rip),%xmm0
  addsd  D53(%rip),%xmm0
  comisd D47(%rip),%xmm0
  jae    L42
  cvttsd2si %xmm0,%rcx
L110:
  cmp    $0x3e8,%rcx
  je     L6
L37:
  cmp    $0x20,%r8b
  je     L34
  movsbl %r8b,%r8d
  lea    D50(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
L72:
  mov    $0x0,%eax
  add    $0x8,%rsp
  ret
L65:
  mov    %rcx,%rsi
  shr    %rsi
  and    $0x1,%ecx
  or     %rcx,%rsi
  pxor   %xmm0,%xmm0
  cvtsi2sd %rsi,%xmm0
  addsd  %xmm0,%xmm0
  jmp    L126
L42:
  subsd  D47(%rip),%xmm0
  cvttsd2si %xmm0,%rcx
  btc    $0x3f,%rcx
  jmp    L110
L6:
  add    $0x1,%rdx
  mov    $0x0,%ecx
  jmp    L37
L57:
  mov    %rsi,%rdx
  mov    $0x20,%r8d
  mov    $0x0,%ecx
  jmp    L37
L34:
  lea    D74(%rip),%rsi
  mov    $0x0,%eax
  call   <fprintf@plt>
  jmp    L72
```

tool_calls: name: unpack_data
arguments: label: D28
type_infered: string
name: unpack_data
arguments: label: D70
type_infered: f32[2]
name: unpack_data
arguments: label: D23
type_infered: f64
name: unpack_data
arguments: label: D53
type_infered: f64
name: unpack_data
arguments: label: D47
type_infered: f32
name: unpack_data
arguments: label: D50
type_infered: string
name: unpack_data
arguments: label: D74
type_infered: string

tool: D28:  KMGTPEZY

tool: {"D70": [0.0,0.8125]}

tool: D23: 0.9765625

tool: D53: 0.5

tool: D47: 0

tool: D50: %zu.%03zu %ciB

tool: D74: %zu B

assistant: ```c
int print_human_readable_size(FILE *stream, size_t size) {
  static const char *prefixes = " KMGTPEZY";
  size_t order = 0;
  size_t hr_size = size;
  size_t hr_fraction = 0;
  double double_fraction = 0;
  char prefix = '\0';
  while (hr_size > 1023) {
    hr_size = hr_size >> 10;
    ++order;
  }
  prefix = prefixes[order];
  order = (size_t)(1) << (10 * order);
  hr_fraction = size % order;
  double_fraction = (double)(hr_fraction);
  while (order > 1024) {
    double_fraction = double_fraction / 1024;
    order = order >> 10;
  }
  hr_fraction = (size_t)(0.5 + double_fraction * 0.9765625);
  if (hr_fraction == 1000) {
    ++hr_size;
    hr_fraction = 0;
  }
  if (prefix == ' ') {
    fprintf(stream, "%zu B", hr_size);
  } else {
    fprintf(stream, "%zu.%03zu %ciB", hr_size, hr_fraction, prefix);
  }
  return (0);
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<print_human_readable_size>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  cmp    $0x3ff,%rsi
  jbe    L75
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L68:
  shr    $0xa,%rdx
  add    $0x1,%rax
  cmp    $0x3ff,%rdx
  ja     L68
  lea    D14(%rip),%rcx
  pxor   %xmm0,%xmm0
  movsbl (%rcx,%rax,1),%r8d
  lea    (%rax,%rax,4),%ecx
  mov    $0x1,%eax
  add    %ecx,%ecx
  shl    %cl,%rax
  lea    -0x1(%rax),%rcx
  and    %rsi,%rcx
  cvtsi2sd %rcx,%xmm0
  cmp    $0x400,%rax
  jbe    L7
  movsd  D66(%rip),%xmm1
  nopw   0x0(%rax,%rax,1)
L27:
  mulsd  %xmm1,%xmm0
  shr    $0xa,%rax
  cmp    $0x400,%rax
  ja     L27
L7:
  mulsd  D27(%rip),%xmm0
  movsd  D20(%rip),%xmm1
  addsd  D47(%rip),%xmm0
  comisd %xmm1,%xmm0
  jae    L28
  cvttsd2si %xmm0,%rcx
L13:
  cmp    $0x3e8,%rcx
  jne    L6
  add    $0x1,%rdx
  xor    %ecx,%ecx
L6:
  cmp    $0x20,%r8b
  je     L75
  lea    D22(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L28:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rcx
  btc    $0x3f,%rcx
  jmp    L13
L75:
  lea    D65(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: read_data
arguments: data_label: D14
type_guessed: string
name: read_data
arguments: data_label: D66
type_guessed: f32[2]
name: read_data
arguments: data_label: D27
type_guessed: f64
name: read_data
arguments: data_label: D20
type_guessed: f32[2]
name: read_data
arguments: data_label: D47
type_guessed: f64
name: read_data
arguments: data_label: D22
type_guessed: string
name: read_data
arguments: data_label: D65
type_guessed: string

tool: D14:  KMGTPEZY

tool: {"D66": [0.0,0.8125]}

tool: D27: 0.9765625

tool: {"D20": [0.0,448.0]}

tool: D47: 0.5

tool: D22: %zu.%03zu %ciB

tool: D65: %zu B

assistant: ```c
int print_human_readable_size(FILE *stream, size_t size) {
  static const char *prefixes = " KMGTPEZY";
  size_t order = 0;
  size_t hr_size = size;
  size_t hr_fraction = 0;
  double double_fraction = 0;
  char prefix = '\0';
  while (hr_size > 1023) {
    hr_size = hr_size >> 10;
    ++order;
  }
  prefix = prefixes[order];
  order = (size_t)(1) << (10 * order);
  hr_fraction = size % order;
  double_fraction = (double)(hr_fraction);
  while (order > 1024) {
    double_fraction = double_fraction / 1024;
    order = order >> 10;
  }
  hr_fraction = (size_t)(0.5 + double_fraction * 0.9765625);
  if (hr_fraction == 1000) {
    ++hr_size;
    hr_fraction = 0;
  }
  if (prefix == ' ') {
    fprintf(stream, "%zu B", hr_size);
  } else {
    fprintf(stream, "%zu.%03zu %ciB", hr_size, hr_fraction, prefix);
  }
  return (0);
}
```
user: What is the c source code of the assembly code below:

```asm
<print_human_readable_size>:
  endbr64
  sub    $0x8,%rsp
  mov    %rsi,%rdx
  cmp    $0x3ff,%rsi
  jbe    L21
  xor    %eax,%eax
  nopw   0x0(%rax,%rax,1)
L6:
  shr    $0xa,%rdx
  add    $0x1,%rax
  cmp    $0x3ff,%rdx
  ja     L6
  lea    D9(%rip),%rcx
  pxor   %xmm0,%xmm0
  movsbl (%rcx,%rax,1),%r8d
  lea    (%rax,%rax,4),%ecx
  mov    $0x1,%eax
  add    %ecx,%ecx
  shl    %cl,%rax
  lea    -0x1(%rax),%rcx
  and    %rsi,%rcx
  cvtsi2sd %rcx,%xmm0
  cmp    $0x400,%rax
  jbe    L8
  movsd  D4(%rip),%xmm1
  nopw   0x0(%rax,%rax,1)
L16:
  mulsd  %xmm1,%xmm0
  shr    $0xa,%rax
  cmp    $0x400,%rax
  ja     L16
L8:
  mulsd  D16(%rip),%xmm0
  movsd  D33(%rip),%xmm1
  addsd  D40(%rip),%xmm0
  comisd %xmm1,%xmm0
  jae    L22
  cvttsd2si %xmm0,%rcx
L64:
  cmp    $0x3e8,%rcx
  jne    L7
  add    $0x1,%rdx
  xor    %ecx,%ecx
L7:
  cmp    $0x20,%r8b
  je     L21
  lea    D48(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
  nopl   (%rax)
L22:
  subsd  %xmm1,%xmm0
  cvttsd2si %xmm0,%rcx
  btc    $0x3f,%rcx
  jmp    L64
L21:
  lea    D3(%rip),%rsi
  xor    %eax,%eax
  call   <fprintf@plt>
  xor    %eax,%eax
  add    $0x8,%rsp
  ret
```

tool_calls: name: parse_data
arguments: data_label: D9
type_infered: string
name: parse_data
arguments: data_label: D4
type_infered: f32[2]
name: parse_data
arguments: data_label: D16
type_infered: f64
name: parse_data
arguments: data_label: D33
type_infered: f32[2]
name: parse_data
arguments: data_label: D40
type_infered: f64
name: parse_data
arguments: data_label: D48
type_infered: string
name: parse_data
arguments: data_label: D3
type_infered: string

tool: D9:  KMGTPEZY

tool: {"D4": [0.0,0.8125]}

tool: D16: 0.9765625

tool: {"D33": [0.0,448.0]}

tool: D40: 0.5

tool: D48: %zu.%03zu %ciB

tool: D3: %zu B

assistant: ```c
int print_human_readable_size(FILE *stream, size_t size) {
  static const char *prefixes = " KMGTPEZY";
  size_t order = 0;
  size_t hr_size = size;
  size_t hr_fraction = 0;
  double double_fraction = 0;
  char prefix = '\0';
  while (hr_size > 1023) {
    hr_size = hr_size >> 10;
    ++order;
  }
  prefix = prefixes[order];
  order = (size_t)(1) << (10 * order);
  hr_fraction = size % order;
  double_fraction = (double)(hr_fraction);
  while (order > 1024) {
    double_fraction = double_fraction / 1024;
    order = order >> 10;
  }
  hr_fraction = (size_t)(0.5 + double_fraction * 0.9765625);
  if (hr_fraction == 1000) {
    ++hr_size;
    hr_fraction = 0;
  }
  if (prefix == ' ') {
    fprintf(stream, "%zu B", hr_size);
  } else {
    fprintf(stream, "%zu.%03zu %ciB", hr_size, hr_fraction, prefix);
  }
  return (0);
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<induceSAl0>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  sub    $0x40,%rsp
  mov    %rdi,-0x18(%rbp)
  mov    %rsi,-0x20(%rbp)
  mov    %rdx,-0x28(%rbp)
  mov    %rcx,-0x30(%rbp)
  mov    %r8,-0x38(%rbp)
  mov    %r9d,%eax
  mov    %al,-0x3c(%rbp)
  mov    -0x38(%rbp),%rcx
  mov    -0x30(%rbp),%rdx
  mov    -0x28(%rbp),%rsi
  mov    -0x20(%rbp),%rax
  mov    $0x0,%r8d
  mov    %rax,%rdi
  call   <getBuckets@plt>
  mov    -0x28(%rbp),%rax
  mov    (%rax),%rax
  lea    0x1(%rax),%rdx
  mov    -0x28(%rbp),%rax
  mov    %rdx,(%rax)
  movq   $0x0,-0x10(%rbp)
  jmp    L4
L20:
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  test   %rax,%rax
  jle    L30
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  sub    $0x1,%rax
  mov    %rax,-0x8(%rbp)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%edx
  mov    -0x8(%rbp),%rax
  lea    0x1(%rax),%rcx
  mov    -0x20(%rbp),%rax
  add    %rcx,%rax
  movzbl (%rax),%eax
  cmp    %al,%dl
  jb     L30
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rax,%rdx
  mov    -0x8(%rbp),%rax
  mov    %rax,(%rdx)
  mov    -0x8(%rbp),%rdx
  mov    -0x20(%rbp),%rax
  add    %rdx,%rax
  movzbl (%rax),%eax
  movzbl %al,%eax
  lea    0x0(,%rax,8),%rdx
  mov    -0x28(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rdx
  add    $0x1,%rdx
  mov    %rdx,(%rax)
  cmpb   $0x0,-0x3c(%rbp)
  jne    L30
  cmpq   $0x0,-0x10(%rbp)
  jle    L30
  mov    -0x10(%rbp),%rax
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  movq   $0x0,(%rax)
L30:
  addq   $0x1,-0x10(%rbp)
L4:
  mov    -0x10(%rbp),%rax
  cmp    -0x30(%rbp),%rax
  jl     L20
  nop
  nop
  leave
  ret
```

assistant: ```c
void induceSAl0(long *SA, unsigned char *s, long *bkt, long n, long K, char suffix) {
  long i, j;
  getBuckets(s, bkt, n, K, 0);
  bkt[0]++;
  for (i = 0; i < n; i++)
    if (SA[i] > 0) {
      j = SA[i] - 1;
      if (s[j] >= s[j + 1]) {
        SA[bkt[s[j]]] = j;
        bkt[s[j]]++;
        if (!suffix && i > 0)
          SA[i] = 0;
      }
    }
}
```
user: What is the c source code of the assembly code below:

```asm
<induceSAl0>:
  endbr64
  push   %r14
  push   %r13
  push   %r12
  push   %rbp
  push   %rbx
  mov    %rdi,%rbx
  mov    %rsi,%rbp
  mov    %rdx,%r12
  mov    %rcx,%r13
  mov    %r8,%rcx
  mov    %r9d,%r14d
  mov    $0x0,%r8d
  mov    %r13,%rdx
  mov    %r12,%rsi
  mov    %rbp,%rdi
  call   <getBuckets@plt>
  addq   $0x1,(%r12)
  test   %r13,%r13
  jle    L51
  mov    $0x0,%eax
  jmp    L38
L5:
  add    $0x1,%rax
  cmp    %rax,%r13
  je     L51
L38:
  mov    (%rbx,%rax,8),%rdx
  test   %rdx,%rdx
  jle    L5
  lea    -0x1(%rdx),%rdi
  lea    0x0(%rbp,%rdi,1),%rsi
  movzbl (%rsi),%ecx
  cmp    0x0(%rbp,%rdx,1),%cl
  jb     L5
  movzbl %cl,%ecx
  mov    (%r12,%rcx,8),%rdx
  mov    %rdi,(%rbx,%rdx,8)
  movzbl (%rsi),%edx
  addq   $0x1,(%r12,%rdx,8)
  test   %r14b,%r14b
  jne    L5
  test   %rax,%rax
  jle    L5
  movq   $0x0,(%rbx,%rax,8)
  jmp    L5
L51:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void induceSAl0(long *SA, unsigned char *s, long *bkt, long n, long K, char suffix) {
  long i, j;
  getBuckets(s, bkt, n, K, 0);
  bkt[0]++;
  for (i = 0; i < n; i++)
    if (SA[i] > 0) {
      j = SA[i] - 1;
      if (s[j] >= s[j + 1]) {
        SA[bkt[s[j]]] = j;
        bkt[s[j]]++;
        if (!suffix && i > 0)
          SA[i] = 0;
      }
    }
}
```
user: Converte this assembly snippet into its equivalent C code:

```asm
<induceSAl0>:
  endbr64
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %rcx,%r13
  mov    %r8,%rcx
  xor    %r8d,%r8d
  push   %r12
  mov    %rdx,%r12
  mov    %r13,%rdx
  push   %rbp
  mov    %rsi,%rbp
  mov    %r12,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  call   <getBuckets@plt>
  addq   $0x1,(%r12)
  test   %r13,%r13
  jle    L16
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L37:
  mov    (%rbx,%rax,8),%rdx
  test   %rdx,%rdx
  jle    L26
  lea    -0x1(%rdx),%rdi
  lea    0x0(%rbp,%rdi,1),%rsi
  movzbl (%rsi),%ecx
  cmp    0x0(%rbp,%rdx,1),%cl
  jb     L26
  mov    (%r12,%rcx,8),%rdx
  mov    %rdi,(%rbx,%rdx,8)
  movzbl (%rsi),%edx
  addq   $0x1,(%r12,%rdx,8)
  test   %r14b,%r14b
  jne    L26
  test   %rax,%rax
  jle    L26
  movq   $0x0,(%rbx,%rax,8)
  nopl   (%rax)
L26:
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L37
L16:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void induceSAl0(long *SA, unsigned char *s, long *bkt, long n, long K, char suffix) {
  long i, j;
  getBuckets(s, bkt, n, K, 0);
  bkt[0]++;
  for (i = 0; i < n; i++)
    if (SA[i] > 0) {
      j = SA[i] - 1;
      if (s[j] >= s[j + 1]) {
        SA[bkt[s[j]]] = j;
        bkt[s[j]]++;
        if (!suffix && i > 0)
          SA[i] = 0;
      }
    }
}
```
user: 请显示与下面列出的汇编代码相匹配的C语言实现：

```asm
<induceSAl0>:
  endbr64
  push   %r14
  mov    %r9d,%r14d
  push   %r13
  mov    %rcx,%r13
  mov    %r8,%rcx
  xor    %r8d,%r8d
  push   %r12
  mov    %rdx,%r12
  mov    %r13,%rdx
  push   %rbp
  mov    %rsi,%rbp
  mov    %r12,%rsi
  push   %rbx
  mov    %rdi,%rbx
  mov    %rbp,%rdi
  call   <getBuckets@plt>
  addq   $0x1,(%r12)
  test   %r13,%r13
  jle    L11
  xor    %eax,%eax
  nopl   0x0(%rax,%rax,1)
L21:
  mov    (%rbx,%rax,8),%rdx
  test   %rdx,%rdx
  jle    L31
  lea    -0x1(%rdx),%rdi
  lea    0x0(%rbp,%rdi,1),%rsi
  movzbl (%rsi),%ecx
  cmp    0x0(%rbp,%rdx,1),%cl
  jb     L31
  mov    (%r12,%rcx,8),%rdx
  mov    %rdi,(%rbx,%rdx,8)
  movzbl (%rsi),%edx
  addq   $0x1,(%r12,%rdx,8)
  test   %r14b,%r14b
  jne    L31
  test   %rax,%rax
  jle    L31
  movq   $0x0,(%rbx,%rax,8)
  nopl   (%rax)
L31:
  add    $0x1,%rax
  cmp    %rax,%r13
  jne    L21
L11:
  pop    %rbx
  pop    %rbp
  pop    %r12
  pop    %r13
  pop    %r14
  ret
```

assistant: ```c
void induceSAl0(long *SA, unsigned char *s, long *bkt, long n, long K, char suffix) {
  long i, j;
  getBuckets(s, bkt, n, K, 0);
  bkt[0]++;
  for (i = 0; i < n; i++)
    if (SA[i] > 0) {
      j = SA[i] - 1;
      if (s[j] >= s[j + 1]) {
        SA[bkt[s[j]]] = j;
        bkt[s[j]]++;
        if (!suffix && i > 0)
          SA[i] = 0;
      }
    }
}
```
user: What is the c source code of the assembly code below?

```asm
<arr_contains>:
  endbr64
  push   %rbp
  mov    %rsp,%rbp
  mov    %rdi,-0x18(%rbp)
  mov    %esi,-0x1c(%rbp)
  mov    %rdx,-0x28(%rbp)
  movl   $0x0,-0x4(%rbp)
  jmp    L14
L33:
  mov    -0x4(%rbp),%eax
  cltq
  lea    0x0(,%rax,8),%rdx
  mov    -0x18(%rbp),%rax
  add    %rdx,%rax
  mov    (%rax),%rax
  cmp    %rax,-0x28(%rbp)
  jne    L39
  mov    $0x1,%eax
  jmp    L36
L39:
  addl   $0x1,-0x4(%rbp)
L14:
  mov    -0x4(%rbp),%eax
  cmp    -0x1c(%rbp),%eax
  jl     L33
  mov    $0x0,%eax
L36:
  pop    %rbp
  ret
```

assistant: ```c
bool arr_contains(char **arr, int arr_len, char *ptr) {
  for (int i = 0; i < arr_len; i++) {
    if (arr[i] == ptr) {
      return true;
    }
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码：

```asm
<arr_contains>:
  endbr64
  test   %esi,%esi
  jle    L7
  mov    %rdi,%rax
  lea    -0x1(%rsi),%ecx
  lea    0x8(%rdi,%rcx,8),%rcx
L8:
  cmp    %rdx,(%rax)
  je     L23
  add    $0x8,%rax
  cmp    %rcx,%rax
  jne    L8
  mov    $0x0,%eax
  ret
L7:
  mov    $0x0,%eax
  ret
L23:
  mov    $0x1,%eax
  ret
```

assistant: ```c
bool arr_contains(char **arr, int arr_len, char *ptr) {
  for (int i = 0; i < arr_len; i++) {
    if (arr[i] == ptr) {
      return true;
    }
  }
  return false;
}
```
user: 提供的汇编代码用C语言表示会是什么样子：

```asm
<arr_contains>:
  endbr64
  test   %esi,%esi
  jle    L36
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  jmp    L2
  nopw   0x0(%rax,%rax,1)
L37:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L36
L2:
  cmp    %rdx,(%rdi)
  jne    L37
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L36:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool arr_contains(char **arr, int arr_len, char *ptr) {
  for (int i = 0; i < arr_len; i++) {
    if (arr[i] == ptr) {
      return true;
    }
  }
  return false;
}
```
user: 请从给定的汇编指令推导出C源代码:

```asm
<arr_contains>:
  endbr64
  test   %esi,%esi
  jle    L32
  lea    -0x1(%rsi),%eax
  lea    0x8(%rdi,%rax,8),%rax
  jmp    L17
  nopw   0x0(%rax,%rax,1)
L22:
  add    $0x8,%rdi
  cmp    %rax,%rdi
  je     L32
L17:
  cmp    %rdx,(%rdi)
  jne    L22
  mov    $0x1,%eax
  ret
  nopl   0x0(%rax)
L32:
  xor    %eax,%eax
  ret
```

assistant: ```c
bool arr_contains(char **arr, int arr_len, char *ptr) {
  for (int i = 0; i < arr_len; i++) {
    if (arr[i] == ptr) {
      return true;
    }
  }
  return false;
}
```